Datasets:

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target-benchmark

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spider-queries-train

like 0

department_management

How many heads of the departments are older than 56 ?

SELECT count(*) FROM head WHERE age > 56

easy

department_management

List the name, born state and age of the heads of departments ordered by age.

SELECT name , born_state , age FROM head ORDER BY age

medium

department_management

List the creation year, name and budget of each department.

SELECT creation , name , budget_in_billions FROM department

medium

department_management

What are the maximum and minimum budget of the departments?

SELECT max(budget_in_billions) , min(budget_in_billions) FROM department

medium

department_management

What is the average number of employees of the departments whose rank is between 10 and 15?

SELECT avg(num_employees) FROM department WHERE ranking BETWEEN 10 AND 15

easy

department_management

What are the names of the heads who are born outside the California state?

SELECT name FROM head WHERE born_state != 'California'

easy

department_management

What are the distinct creation years of the departments managed by a secretary born in state 'Alabama'?

SELECT DISTINCT T1.creation FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T3.born_state = 'Alabama'

hard

department_management

What are the names of the states where at least 3 heads were born?

SELECT born_state FROM head GROUP BY born_state HAVING count(*) >= 3

easy

department_management

In which year were most departments established?

SELECT creation FROM department GROUP BY creation ORDER BY count(*) DESC LIMIT 1

hard

department_management

Show the name and number of employees for the departments managed by heads whose temporary acting value is 'Yes'?

SELECT T1.name , T1.num_employees FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id WHERE T2.temporary_acting = 'Yes'

medium

department_management

How many acting statuses are there?

SELECT count(DISTINCT temporary_acting) FROM management

easy

department_management

How many departments are led by heads who are not mentioned?

SELECT count(*) FROM department WHERE department_id NOT IN (SELECT department_id FROM management);

extra

department_management

What are the distinct ages of the heads who are acting?

SELECT DISTINCT T1.age FROM management AS T2 JOIN head AS T1 ON T1.head_id = T2.head_id WHERE T2.temporary_acting = 'Yes'

medium

department_management

List the states where both the secretary of 'Treasury' department and the secretary of 'Homeland Security' were born.

SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = 'Treasury' INTERSECT SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = 'Homeland Security'

extra

department_management

Which department has more than 1 head at a time? List the id, name and the number of heads.

SELECT T1.department_id , T1.name , count(*) FROM management AS T2 JOIN department AS T1 ON T1.department_id = T2.department_id GROUP BY T1.department_id HAVING count(*) > 1

medium

department_management

Which head's name has the substring 'Ha'? List the id and name.

SELECT head_id , name FROM head WHERE name LIKE '%Ha%'

medium

farm

How many farms are there?

SELECT count(*) FROM farm

easy

farm

Count the number of farms.

SELECT count(*) FROM farm

easy

farm

List the total number of horses on farms in ascending order.

SELECT Total_Horses FROM farm ORDER BY Total_Horses ASC

easy

farm

What is the total horses record for each farm, sorted ascending?

SELECT Total_Horses FROM farm ORDER BY Total_Horses ASC

easy

farm

What are the hosts of competitions whose theme is not "Aliens"?

SELECT Hosts FROM farm_competition WHERE Theme != 'Aliens'

easy

farm

Return the hosts of competitions for which the theme is not Aliens?

SELECT Hosts FROM farm_competition WHERE Theme != 'Aliens'

easy

farm

What are the themes of farm competitions sorted by year in ascending order?

SELECT Theme FROM farm_competition ORDER BY YEAR ASC

easy

farm

Return the themes of farm competitions, sorted by year ascending.

SELECT Theme FROM farm_competition ORDER BY YEAR ASC

easy

farm

What is the average number of working horses of farms with more than 5000 total number of horses?

SELECT avg(Working_Horses) FROM farm WHERE Total_Horses > 5000

easy

farm

Give the average number of working horses on farms with more than 5000 total horses.

SELECT avg(Working_Horses) FROM farm WHERE Total_Horses > 5000

easy

farm

What are the maximum and minimum number of cows across all farms.

SELECT max(Cows) , min(Cows) FROM farm

medium

farm

Return the maximum and minimum number of cows across all farms.

SELECT max(Cows) , min(Cows) FROM farm

medium

farm

How many different statuses do cities have?

SELECT count(DISTINCT Status) FROM city

easy

farm

Count the number of different statuses.

SELECT count(DISTINCT Status) FROM city

easy

farm

List official names of cities in descending order of population.

SELECT Official_Name FROM city ORDER BY Population DESC

easy

farm

What are the official names of cities, ordered descending by population?

SELECT Official_Name FROM city ORDER BY Population DESC

easy

farm

List the official name and status of the city with the largest population.

SELECT Official_Name , Status FROM city ORDER BY Population DESC LIMIT 1

medium

farm

What is the official name and status of the city with the most residents?

SELECT Official_Name , Status FROM city ORDER BY Population DESC LIMIT 1

medium

farm

Show the years and the official names of the host cities of competitions.

SELECT T2.Year , T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID

medium

farm

Give the years and official names of the cities of each competition.

SELECT T2.Year , T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID

medium

farm

Show the official names of the cities that have hosted more than one competition.

SELECT T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID HAVING COUNT(*) > 1

medium

farm

What are the official names of cities that have hosted more than one competition?

SELECT T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID HAVING COUNT(*) > 1

medium

farm

Show the status of the city that has hosted the greatest number of competitions.

SELECT T1.Status FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID ORDER BY COUNT(*) DESC LIMIT 1

extra

farm

What is the status of the city that has hosted the most competitions?

SELECT T1.Status FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID ORDER BY COUNT(*) DESC LIMIT 1

extra

farm

Please show the themes of competitions with host cities having populations larger than 1000.

SELECT T2.Theme FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID WHERE T1.Population > 1000

medium

farm

What are the themes of competitions that have corresponding host cities with more than 1000 residents?

SELECT T2.Theme FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID WHERE T1.Population > 1000

medium

farm

Please show the different statuses of cities and the average population of cities with each status.

SELECT Status , avg(Population) FROM city GROUP BY Status

medium

farm

What are the statuses and average populations of each city?

SELECT Status , avg(Population) FROM city GROUP BY Status

medium

farm

Please show the different statuses, ordered by the number of cities that have each.

SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) ASC

medium

farm

Return the different statuses of cities, ascending by frequency.

SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) ASC

medium

farm

List the most common type of Status across cities.

SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) DESC LIMIT 1

hard

farm

What is the most common status across all cities?

SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) DESC LIMIT 1

hard

farm

List the official names of cities that have not held any competition.

SELECT Official_Name FROM city WHERE City_ID NOT IN (SELECT Host_city_ID FROM farm_competition)

hard

farm

What are the official names of cities that have not hosted a farm competition?

SELECT Official_Name FROM city WHERE City_ID NOT IN (SELECT Host_city_ID FROM farm_competition)

hard

farm

Show the status shared by cities with population bigger than 1500 and smaller than 500.

SELECT Status FROM city WHERE Population > 1500 INTERSECT SELECT Status FROM city WHERE Population < 500

hard

farm

Which statuses correspond to both cities that have a population over 1500 and cities that have a population lower than 500?

SELECT Status FROM city WHERE Population > 1500 INTERSECT SELECT Status FROM city WHERE Population < 500

hard

farm

Find the official names of cities with population bigger than 1500 or smaller than 500.

SELECT Official_Name FROM city WHERE Population > 1500 OR Population < 500

medium

farm

What are the official names of cities that have population over 1500 or less than 500?

SELECT Official_Name FROM city WHERE Population > 1500 OR Population < 500

medium

farm

Show the census ranking of cities whose status are not "Village".

SELECT Census_Ranking FROM city WHERE Status != "Village"

easy

farm

What are the census rankings of cities that do not have the status "Village"?

SELECT Census_Ranking FROM city WHERE Status != "Village"

easy

student_assessment

which course has most number of registered students?

SELECT T1.course_name FROM courses AS T1 JOIN student_course_registrations AS T2 ON T1.course_id = T2.course_Id GROUP BY T1.course_id ORDER BY count(*) DESC LIMIT 1

extra

student_assessment

What is the name of the course with the most registered students?

SELECT T1.course_name FROM courses AS T1 JOIN student_course_registrations AS T2 ON T1.course_id = T2.course_Id GROUP BY T1.course_id ORDER BY count(*) DESC LIMIT 1

extra

student_assessment

what is id of students who registered some courses but the least number of courses in these students?

SELECT student_id FROM student_course_registrations GROUP BY student_id ORDER BY count(*) LIMIT 1

hard

student_assessment

What are the ids of the students who registered for some courses but had the least number of courses for all students?

SELECT student_id FROM student_course_registrations GROUP BY student_id ORDER BY count(*) LIMIT 1

hard

student_assessment

what are the first name and last name of all candidates?

SELECT T2.first_name , T2.last_name FROM candidates AS T1 JOIN people AS T2 ON T1.candidate_id = T2.person_id

medium

student_assessment

What are the first and last names of all the candidates?

SELECT T2.first_name , T2.last_name FROM candidates AS T1 JOIN people AS T2 ON T1.candidate_id = T2.person_id

medium

student_assessment

List the id of students who never attends courses?

SELECT student_id FROM students WHERE student_id NOT IN (SELECT student_id FROM student_course_attendance)

hard

student_assessment

What are the ids of every student who has never attended a course?

SELECT student_id FROM students WHERE student_id NOT IN (SELECT student_id FROM student_course_attendance)

hard

student_assessment

List the id of students who attended some courses?

SELECT student_id FROM student_course_attendance

easy

student_assessment

What are the ids of all students who have attended at least one course?

SELECT student_id FROM student_course_attendance

easy

student_assessment

What are the ids of all students for courses and what are the names of those courses?

SELECT T1.student_id , T2.course_name FROM student_course_registrations AS T1 JOIN courses AS T2 ON T1.course_id = T2.course_id

medium

student_assessment

What is detail of the student who most recently registered course?

SELECT T2.student_details FROM student_course_registrations AS T1 JOIN students AS T2 ON T1.student_id = T2.student_id ORDER BY T1.registration_date DESC LIMIT 1

hard

student_assessment

What details do we have on the students who registered for courses most recently?

SELECT T2.student_details FROM student_course_registrations AS T1 JOIN students AS T2 ON T1.student_id = T2.student_id ORDER BY T1.registration_date DESC LIMIT 1

hard

student_assessment

How many students attend course English?

SELECT count(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "English"

medium

student_assessment

How many students are attending English courses?

SELECT count(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "English"

medium

student_assessment

How many courses do the student whose id is 171 attend?

SELECT count(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T2.student_id = 171

medium

student_assessment

How many courses does the student with id 171 actually attend?

SELECT count(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T2.student_id = 171

medium

student_assessment

Find id of the candidate whose email is [email protected]?

SELECT T2.candidate_id FROM people AS T1 JOIN candidates AS T2 ON T1.person_id = T2.candidate_id WHERE T1.email_address = "[email protected]"

medium

student_assessment

What is the id of the candidate whose email is [email protected]?

SELECT T2.candidate_id FROM people AS T1 JOIN candidates AS T2 ON T1.person_id = T2.candidate_id WHERE T1.email_address = "[email protected]"

medium

student_assessment

Find id of the candidate who most recently accessed the course?

SELECT candidate_id FROM candidate_assessments ORDER BY assessment_date DESC LIMIT 1

medium

student_assessment

What is the id of the candidate who most recently accessed the course?

SELECT candidate_id FROM candidate_assessments ORDER BY assessment_date DESC LIMIT 1

medium

student_assessment

What is detail of the student who registered the most number of courses?

SELECT T1.student_details FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1

extra

student_assessment

What are the details of the student who registered for the most number of courses?

SELECT T1.student_details FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1

extra

student_assessment

List the id of students who registered some courses and the number of their registered courses?

SELECT T1.student_id , count(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id

medium

student_assessment

For every student who is registered for some course, how many courses are they registered for?

SELECT T1.student_id , count(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id

medium

student_assessment

How many registed students do each course have? List course name and the number of their registered students?

SELECT T3.course_name , count(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id JOIN courses AS T3 ON T2.course_id = T3.course_id GROUP BY T2.course_id

hard

student_assessment

For each course id, how many students are registered and what are the course names?

SELECT T3.course_name , count(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id JOIN courses AS T3 ON T2.course_id = T3.course_id GROUP BY T2.course_id

hard

student_assessment

Find id of candidates whose assessment code is "Pass"?

SELECT candidate_id FROM candidate_assessments WHERE asessment_outcome_code = "Pass"

easy

student_assessment

What are the ids of the candidates that have an outcome code of Pass?

SELECT candidate_id FROM candidate_assessments WHERE asessment_outcome_code = "Pass"

easy

student_assessment

Find the cell mobile number of the candidates whose assessment code is "Fail"?

SELECT T3.cell_mobile_number FROM candidates AS T1 JOIN candidate_assessments AS T2 ON T1.candidate_id = T2.candidate_id JOIN people AS T3 ON T1.candidate_id = T3.person_id WHERE T2.asessment_outcome_code = "Fail"

hard

student_assessment

What are the cell phone numbers of the candidates that received an assessment code of "Fail"?

SELECT T3.cell_mobile_number FROM candidates AS T1 JOIN candidate_assessments AS T2 ON T1.candidate_id = T2.candidate_id JOIN people AS T3 ON T1.candidate_id = T3.person_id WHERE T2.asessment_outcome_code = "Fail"

hard

student_assessment

What are the id of students who registered course 301?

SELECT student_id FROM student_course_attendance WHERE course_id = 301

easy

student_assessment

What are the ids of the students who registered for course 301?

SELECT student_id FROM student_course_attendance WHERE course_id = 301

easy

student_assessment

What is the id of the student who most recently registered course 301?

SELECT student_id FROM student_course_attendance WHERE course_id = 301 ORDER BY date_of_attendance DESC LIMIT 1

hard

student_assessment

What are the ids of the students who registered for course 301 most recently?

SELECT student_id FROM student_course_attendance WHERE course_id = 301 ORDER BY date_of_attendance DESC LIMIT 1

hard

student_assessment

Find distinct cities of addresses of people?

SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id

easy

student_assessment

What are the different cities where people live?

SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id

easy

student_assessment

Find distinct cities of address of students?

SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id JOIN students AS T3 ON T2.person_id = T3.student_id

medium

student_assessment

What are the different cities where students live?

SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id JOIN students AS T3 ON T2.person_id = T3.student_id

medium

student_assessment

List the names of courses in alphabetical order?

SELECT course_name FROM courses ORDER BY course_name

easy

student_assessment

What are the names of the courses in alphabetical order?

SELECT course_name FROM courses ORDER BY course_name

easy

student_assessment

List the first names of people in alphabetical order?

SELECT first_name FROM people ORDER BY first_name

easy

student_assessment

What are the first names of the people in alphabetical order?

SELECT first_name FROM people ORDER BY first_name

easy

student_assessment

What are the id of students who registered courses or attended courses?

SELECT student_id FROM student_course_registrations UNION SELECT student_id FROM student_course_attendance

hard