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The dataset generation failed because of a cast error
Error code:   DatasetGenerationCastError
Exception:    DatasetGenerationCastError
Message:      An error occurred while generating the dataset

All the data files must have the same columns, but at some point there are 2 new columns ({'Java', 'Cpp'}) and 7 missing columns ({'Kuin', 'Ruby', 'Go', 'C++', 'Python', 'Crystal', 'Rust'}).

This happened while the json dataset builder was generating data using

hf://datasets/puwaer/puwaer_code_translation/kyopro_codes_cpp_java.json (at revision 36699897bb89deae6ba5dff622d167b37730d160)

Please either edit the data files to have matching columns, or separate them into different configurations (see docs at https://hf.co/docs/hub/datasets-manual-configuration#multiple-configurations)
Traceback:    Traceback (most recent call last):
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 1871, in _prepare_split_single
                  writer.write_table(table)
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/arrow_writer.py", line 623, in write_table
                  pa_table = table_cast(pa_table, self._schema)
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/table.py", line 2293, in table_cast
                  return cast_table_to_schema(table, schema)
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/table.py", line 2241, in cast_table_to_schema
                  raise CastError(
              datasets.table.CastError: Couldn't cast
              id: int64
              name: string
              Cpp: string
              Java: string
              -- schema metadata --
              pandas: '{"index_columns": [], "column_indexes": [], "columns": [{"name":' + 534
              to
              {'id': Value(dtype='int64', id=None), 'name': Value(dtype='string', id=None), 'C++': Value(dtype='string', id=None), 'Crystal': Value(dtype='string', id=None), 'Python': Value(dtype='string', id=None), 'Go': Value(dtype='string', id=None), 'Rust': Value(dtype='string', id=None), 'Kuin': Value(dtype='string', id=None), 'Ruby': Value(dtype='string', id=None)}
              because column names don't match
              
              During handling of the above exception, another exception occurred:
              
              Traceback (most recent call last):
                File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1438, in compute_config_parquet_and_info_response
                  parquet_operations = convert_to_parquet(builder)
                File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1050, in convert_to_parquet
                  builder.download_and_prepare(
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 925, in download_and_prepare
                  self._download_and_prepare(
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 1001, in _download_and_prepare
                  self._prepare_split(split_generator, **prepare_split_kwargs)
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 1742, in _prepare_split
                  for job_id, done, content in self._prepare_split_single(
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 1873, in _prepare_split_single
                  raise DatasetGenerationCastError.from_cast_error(
              datasets.exceptions.DatasetGenerationCastError: An error occurred while generating the dataset
              
              All the data files must have the same columns, but at some point there are 2 new columns ({'Java', 'Cpp'}) and 7 missing columns ({'Kuin', 'Ruby', 'Go', 'C++', 'Python', 'Crystal', 'Rust'}).
              
              This happened while the json dataset builder was generating data using
              
              hf://datasets/puwaer/puwaer_code_translation/kyopro_codes_cpp_java.json (at revision 36699897bb89deae6ba5dff622d167b37730d160)
              
              Please either edit the data files to have matching columns, or separate them into different configurations (see docs at https://hf.co/docs/hub/datasets-manual-configuration#multiple-configurations)

Need help to make the dataset viewer work? Make sure to review how to configure the dataset viewer, and open a discussion for direct support.

id
int64
name
string
C++
string
Crystal
string
Python
string
Go
string
Rust
string
Kuin
string
Ruby
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#include <iostream> using namespace std; long long N, K, L; long long A[1 << 18]; bool solve(long long M) { long long cnt = 0, pre = 0; for (int i = 1; i <= N; i++) { if (A[i] - pre >= M && L - A[i] >= M) { cnt += 1; pre = A[i]; } } if (cnt >= K) return true; return false; } int main() { // Step #1. “ü—Í cin >> N >> L; cin >> K; for (int i = 1; i <= N; i++) { cin >> A[i]; } // Step #2. “š‚¦‚Å“ñ•ª’T�õ�i‚ß‚®‚é�®“ñ•ª’T�õ–@�j // https://qiita.com/drken/items/97e37dd6143e33a64c8c long long left = -1; long long right = L + 1; while (right - left > 1) { long long mid = left + (right - left) / 2; if (solve(mid) == false) right = mid; else left = mid; } cout << left << endl; return 0; }
_, l = read_line.split.map(&.to_i) k = read_line.to_i a = read_line.split.map(&.to_i) + [l] puts (1..10**9).bsearch { |len| last, cnt = 0, 0 a.each do |i| if i - last >= len cnt += 1 last = i end end cnt < k + 1 }.not_nil! - 1
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#include <iostream> using namespace std; long long N, K, L; long long A[1 << 18]; bool solve(long long M) { long long cnt = 0, pre = 0; for (int i = 1; i <= N; i++) { if (A[i] - pre >= M && L - A[i] >= M) { cnt += 1; pre = A[i]; } } if (cnt >= K) return true; return false; } int main() { // Step #1. “ü—Í cin >> N >> L; cin >> K; for (int i = 1; i <= N; i++) { cin >> A[i]; } // Step #2. “š‚¦‚Å“ñ•ª’T�õ�i‚ß‚®‚é�®“ñ•ª’T�õ–@�j // https://qiita.com/drken/items/97e37dd6143e33a64c8c long long left = -1; long long right = L + 1; while (right - left > 1) { long long mid = left + (right - left) / 2; if (solve(mid) == false) right = mid; else left = mid; } cout << left << endl; return 0; }
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n, l = map(int,input().split()) k = int(input()) a = list(map(int,input().split())) a.append(l) dif = [a[0]] # 切り口の差を計算 for i in range(n): dif.append(a[i + 1] - a[i]) def is_ok(x): length = 0 cnt = 0 for i in dif: length += i if length >= x: length = 0 cnt += 1 return cnt # 分割する領域の個数 def meguru_bisect(ng, ok): while ng - ok > 1: mid = (ng + ok) // 2 if is_ok(mid) >= k + 1: # まだまだ大きくできる ok = mid else: ng = mid # 小さくしなければいけない return ok print(meguru_bisect(l + 1, -1))
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001
#include <iostream> using namespace std; long long N, K, L; long long A[1 << 18]; bool solve(long long M) { long long cnt = 0, pre = 0; for (int i = 1; i <= N; i++) { if (A[i] - pre >= M && L - A[i] >= M) { cnt += 1; pre = A[i]; } } if (cnt >= K) return true; return false; } int main() { // Step #1. “ü—Í cin >> N >> L; cin >> K; for (int i = 1; i <= N; i++) { cin >> A[i]; } // Step #2. “š‚¦‚Å“ñ•ª’T�õ�i‚ß‚®‚é�®“ñ•ª’T�õ–@�j // https://qiita.com/drken/items/97e37dd6143e33a64c8c long long left = -1; long long right = L + 1; while (right - left > 1) { long long mid = left + (right - left) / 2; if (solve(mid) == false) right = mid; else left = mid; } cout << left << endl; return 0; }
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package main import ( "bufio" "fmt" "os" "strconv" ) var sc = bufio.NewScanner(os.Stdin) func main() { buf := make([]byte, 1024*1024) sc.Buffer(buf, bufio.MaxScanTokenSize) sc.Split(bufio.ScanWords) n, l := ScanInt(), ScanInt() k := ScanInt() a := ScanIntSlice(n) ok, ng := 0, l check := func(x int) bool { preAi := 0 cnt := 0 for i := 0; i < n; i++ { if a[i]-preAi >= x && l-a[i] >= x { cnt++ preAi = a[i] } } return cnt >= k } for ng-ok > 1 { c := (ng + ok) / 2 if check(c) { ok = c } else { ng = c } } fmt.Println(ok) } func ScanInt() int { sc.Scan() i, err := strconv.Atoi(sc.Text()) if err != nil { panic(err) } return i } func ScanIntSlice(n int) []int { s := make([]int, n) for i := range s { s[i] = ScanInt() } return s }
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#include <iostream> using namespace std; long long N, K, L; long long A[1 << 18]; bool solve(long long M) { long long cnt = 0, pre = 0; for (int i = 1; i <= N; i++) { if (A[i] - pre >= M && L - A[i] >= M) { cnt += 1; pre = A[i]; } } if (cnt >= K) return true; return false; } int main() { // Step #1. “ü—Í cin >> N >> L; cin >> K; for (int i = 1; i <= N; i++) { cin >> A[i]; } // Step #2. “š‚¦‚Å“ñ•ª’T�õ�i‚ß‚®‚é�®“ñ•ª’T�õ–@�j // https://qiita.com/drken/items/97e37dd6143e33a64c8c long long left = -1; long long right = L + 1; while (right - left > 1) { long long mid = left + (right - left) / 2; if (solve(mid) == false) right = mid; else left = mid; } cout << left << endl; return 0; }
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fn main() { proconio::input! { n: isize, l: isize, k: isize, mut a: [isize; n] } a.sort(); let mut ok = 0; let mut ng = l + 1; while (ng - ok).abs() > 1 { let mid = (ok + ng) / 2; if is_ok(&a, l, k, mid) { ok = mid; } else { ng = mid; } } println!("{}", ok); } fn is_ok(a: &Vec<isize>, l: isize, k: isize, mid: isize) -> bool { let mut x = 0; let mut y = 0; for i in a { if i - x >= mid && l - i >= mid { x = *i; y += 1; } } y >= k }
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#include <iostream> using namespace std; long long N, K, L; long long A[1 << 18]; bool solve(long long M) { long long cnt = 0, pre = 0; for (int i = 1; i <= N; i++) { if (A[i] - pre >= M && L - A[i] >= M) { cnt += 1; pre = A[i]; } } if (cnt >= K) return true; return false; } int main() { // Step #1. “ü—Í cin >> N >> L; cin >> K; for (int i = 1; i <= N; i++) { cin >> A[i]; } // Step #2. “š‚¦‚Å“ñ•ª’T�õ�i‚ß‚®‚é�®“ñ•ª’T�õ–@�j // https://qiita.com/drken/items/97e37dd6143e33a64c8c long long left = -1; long long right = L + 1; while (right - left > 1) { long long mid = left + (right - left) / 2; if (solve(mid) == false) right = mid; else left = mid; } cout << left << endl; return 0; }
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func main() var n: int :: cui@inputInt() var l: int :: cui@inputInt() var k: int :: cui@inputInt() var a: []int :: #[n + 1]int for i(0, n - 1) do a[i] :: cui@inputInt() end for do a[n] :: l var ok: int :: 0 var ng: int :: l + 1 while((ok - ng).abs() > 1) var mid: int :: (ok + ng) / 2 var prev: int :: 0 var cnt: int :: 0 for i(0, n) if(a[i] - prev >= mid) do cnt :+ 1 do prev :: a[i] end if end for var isOk: bool :: cnt >= k + 1 if(isOk) do ok :: mid else do ng :: mid end if end while var ans: int :: ok do cui@print("\{ans}\n") end func
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_, l = read_line.split.map(&.to_i) k = read_line.to_i a = read_line.split.map(&.to_i) + [l] puts (1..10**9).bsearch { |len| last, cnt = 0, 0 a.each do |i| if i - last >= len cnt += 1 last = i end end cnt < k + 1 }.not_nil! - 1
n, l = map(int,input().split()) k = int(input()) a = list(map(int,input().split())) a.append(l) dif = [a[0]] # 切り口の差を計算 for i in range(n): dif.append(a[i + 1] - a[i]) def is_ok(x): length = 0 cnt = 0 for i in dif: length += i if length >= x: length = 0 cnt += 1 return cnt # 分割する領域の個数 def meguru_bisect(ng, ok): while ng - ok > 1: mid = (ng + ok) // 2 if is_ok(mid) >= k + 1: # まだまだ大きくできる ok = mid else: ng = mid # 小さくしなければいけない return ok print(meguru_bisect(l + 1, -1))
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7
001
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_, l = read_line.split.map(&.to_i) k = read_line.to_i a = read_line.split.map(&.to_i) + [l] puts (1..10**9).bsearch { |len| last, cnt = 0, 0 a.each do |i| if i - last >= len cnt += 1 last = i end end cnt < k + 1 }.not_nil! - 1
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package main import ( "bufio" "fmt" "os" "strconv" ) var sc = bufio.NewScanner(os.Stdin) func main() { buf := make([]byte, 1024*1024) sc.Buffer(buf, bufio.MaxScanTokenSize) sc.Split(bufio.ScanWords) n, l := ScanInt(), ScanInt() k := ScanInt() a := ScanIntSlice(n) ok, ng := 0, l check := func(x int) bool { preAi := 0 cnt := 0 for i := 0; i < n; i++ { if a[i]-preAi >= x && l-a[i] >= x { cnt++ preAi = a[i] } } return cnt >= k } for ng-ok > 1 { c := (ng + ok) / 2 if check(c) { ok = c } else { ng = c } } fmt.Println(ok) } func ScanInt() int { sc.Scan() i, err := strconv.Atoi(sc.Text()) if err != nil { panic(err) } return i } func ScanIntSlice(n int) []int { s := make([]int, n) for i := range s { s[i] = ScanInt() } return s }
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_, l = read_line.split.map(&.to_i) k = read_line.to_i a = read_line.split.map(&.to_i) + [l] puts (1..10**9).bsearch { |len| last, cnt = 0, 0 a.each do |i| if i - last >= len cnt += 1 last = i end end cnt < k + 1 }.not_nil! - 1
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fn main() { proconio::input! { n: isize, l: isize, k: isize, mut a: [isize; n] } a.sort(); let mut ok = 0; let mut ng = l + 1; while (ng - ok).abs() > 1 { let mid = (ok + ng) / 2; if is_ok(&a, l, k, mid) { ok = mid; } else { ng = mid; } } println!("{}", ok); } fn is_ok(a: &Vec<isize>, l: isize, k: isize, mid: isize) -> bool { let mut x = 0; let mut y = 0; for i in a { if i - x >= mid && l - i >= mid { x = *i; y += 1; } } y >= k }
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_, l = read_line.split.map(&.to_i) k = read_line.to_i a = read_line.split.map(&.to_i) + [l] puts (1..10**9).bsearch { |len| last, cnt = 0, 0 a.each do |i| if i - last >= len cnt += 1 last = i end end cnt < k + 1 }.not_nil! - 1
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func main() var n: int :: cui@inputInt() var l: int :: cui@inputInt() var k: int :: cui@inputInt() var a: []int :: #[n + 1]int for i(0, n - 1) do a[i] :: cui@inputInt() end for do a[n] :: l var ok: int :: 0 var ng: int :: l + 1 while((ok - ng).abs() > 1) var mid: int :: (ok + ng) / 2 var prev: int :: 0 var cnt: int :: 0 for i(0, n) if(a[i] - prev >= mid) do cnt :+ 1 do prev :: a[i] end if end for var isOk: bool :: cnt >= k + 1 if(isOk) do ok :: mid else do ng :: mid end if end while var ans: int :: ok do cui@print("\{ans}\n") end func
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n, l = map(int,input().split()) k = int(input()) a = list(map(int,input().split())) a.append(l) dif = [a[0]] # 切り口の差を計算 for i in range(n): dif.append(a[i + 1] - a[i]) def is_ok(x): length = 0 cnt = 0 for i in dif: length += i if length >= x: length = 0 cnt += 1 return cnt # 分割する領域の個数 def meguru_bisect(ng, ok): while ng - ok > 1: mid = (ng + ok) // 2 if is_ok(mid) >= k + 1: # まだまだ大きくできる ok = mid else: ng = mid # 小さくしなければいけない return ok print(meguru_bisect(l + 1, -1))
package main import ( "bufio" "fmt" "os" "strconv" ) var sc = bufio.NewScanner(os.Stdin) func main() { buf := make([]byte, 1024*1024) sc.Buffer(buf, bufio.MaxScanTokenSize) sc.Split(bufio.ScanWords) n, l := ScanInt(), ScanInt() k := ScanInt() a := ScanIntSlice(n) ok, ng := 0, l check := func(x int) bool { preAi := 0 cnt := 0 for i := 0; i < n; i++ { if a[i]-preAi >= x && l-a[i] >= x { cnt++ preAi = a[i] } } return cnt >= k } for ng-ok > 1 { c := (ng + ok) / 2 if check(c) { ok = c } else { ng = c } } fmt.Println(ok) } func ScanInt() int { sc.Scan() i, err := strconv.Atoi(sc.Text()) if err != nil { panic(err) } return i } func ScanIntSlice(n int) []int { s := make([]int, n) for i := range s { s[i] = ScanInt() } return s }
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n, l = map(int,input().split()) k = int(input()) a = list(map(int,input().split())) a.append(l) dif = [a[0]] # 切り口の差を計算 for i in range(n): dif.append(a[i + 1] - a[i]) def is_ok(x): length = 0 cnt = 0 for i in dif: length += i if length >= x: length = 0 cnt += 1 return cnt # 分割する領域の個数 def meguru_bisect(ng, ok): while ng - ok > 1: mid = (ng + ok) // 2 if is_ok(mid) >= k + 1: # まだまだ大きくできる ok = mid else: ng = mid # 小さくしなければいけない return ok print(meguru_bisect(l + 1, -1))
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fn main() { proconio::input! { n: isize, l: isize, k: isize, mut a: [isize; n] } a.sort(); let mut ok = 0; let mut ng = l + 1; while (ng - ok).abs() > 1 { let mid = (ok + ng) / 2; if is_ok(&a, l, k, mid) { ok = mid; } else { ng = mid; } } println!("{}", ok); } fn is_ok(a: &Vec<isize>, l: isize, k: isize, mid: isize) -> bool { let mut x = 0; let mut y = 0; for i in a { if i - x >= mid && l - i >= mid { x = *i; y += 1; } } y >= k }
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001
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n, l = map(int,input().split()) k = int(input()) a = list(map(int,input().split())) a.append(l) dif = [a[0]] # 切り口の差を計算 for i in range(n): dif.append(a[i + 1] - a[i]) def is_ok(x): length = 0 cnt = 0 for i in dif: length += i if length >= x: length = 0 cnt += 1 return cnt # 分割する領域の個数 def meguru_bisect(ng, ok): while ng - ok > 1: mid = (ng + ok) // 2 if is_ok(mid) >= k + 1: # まだまだ大きくできる ok = mid else: ng = mid # 小さくしなければいけない return ok print(meguru_bisect(l + 1, -1))
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func main() var n: int :: cui@inputInt() var l: int :: cui@inputInt() var k: int :: cui@inputInt() var a: []int :: #[n + 1]int for i(0, n - 1) do a[i] :: cui@inputInt() end for do a[n] :: l var ok: int :: 0 var ng: int :: l + 1 while((ok - ng).abs() > 1) var mid: int :: (ok + ng) / 2 var prev: int :: 0 var cnt: int :: 0 for i(0, n) if(a[i] - prev >= mid) do cnt :+ 1 do prev :: a[i] end if end for var isOk: bool :: cnt >= k + 1 if(isOk) do ok :: mid else do ng :: mid end if end while var ans: int :: ok do cui@print("\{ans}\n") end func
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001
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package main import ( "bufio" "fmt" "os" "strconv" ) var sc = bufio.NewScanner(os.Stdin) func main() { buf := make([]byte, 1024*1024) sc.Buffer(buf, bufio.MaxScanTokenSize) sc.Split(bufio.ScanWords) n, l := ScanInt(), ScanInt() k := ScanInt() a := ScanIntSlice(n) ok, ng := 0, l check := func(x int) bool { preAi := 0 cnt := 0 for i := 0; i < n; i++ { if a[i]-preAi >= x && l-a[i] >= x { cnt++ preAi = a[i] } } return cnt >= k } for ng-ok > 1 { c := (ng + ok) / 2 if check(c) { ok = c } else { ng = c } } fmt.Println(ok) } func ScanInt() int { sc.Scan() i, err := strconv.Atoi(sc.Text()) if err != nil { panic(err) } return i } func ScanIntSlice(n int) []int { s := make([]int, n) for i := range s { s[i] = ScanInt() } return s }
fn main() { proconio::input! { n: isize, l: isize, k: isize, mut a: [isize; n] } a.sort(); let mut ok = 0; let mut ng = l + 1; while (ng - ok).abs() > 1 { let mid = (ok + ng) / 2; if is_ok(&a, l, k, mid) { ok = mid; } else { ng = mid; } } println!("{}", ok); } fn is_ok(a: &Vec<isize>, l: isize, k: isize, mid: isize) -> bool { let mut x = 0; let mut y = 0; for i in a { if i - x >= mid && l - i >= mid { x = *i; y += 1; } } y >= k }
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001
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package main import ( "bufio" "fmt" "os" "strconv" ) var sc = bufio.NewScanner(os.Stdin) func main() { buf := make([]byte, 1024*1024) sc.Buffer(buf, bufio.MaxScanTokenSize) sc.Split(bufio.ScanWords) n, l := ScanInt(), ScanInt() k := ScanInt() a := ScanIntSlice(n) ok, ng := 0, l check := func(x int) bool { preAi := 0 cnt := 0 for i := 0; i < n; i++ { if a[i]-preAi >= x && l-a[i] >= x { cnt++ preAi = a[i] } } return cnt >= k } for ng-ok > 1 { c := (ng + ok) / 2 if check(c) { ok = c } else { ng = c } } fmt.Println(ok) } func ScanInt() int { sc.Scan() i, err := strconv.Atoi(sc.Text()) if err != nil { panic(err) } return i } func ScanIntSlice(n int) []int { s := make([]int, n) for i := range s { s[i] = ScanInt() } return s }
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func main() var n: int :: cui@inputInt() var l: int :: cui@inputInt() var k: int :: cui@inputInt() var a: []int :: #[n + 1]int for i(0, n - 1) do a[i] :: cui@inputInt() end for do a[n] :: l var ok: int :: 0 var ng: int :: l + 1 while((ok - ng).abs() > 1) var mid: int :: (ok + ng) / 2 var prev: int :: 0 var cnt: int :: 0 for i(0, n) if(a[i] - prev >= mid) do cnt :+ 1 do prev :: a[i] end if end for var isOk: bool :: cnt >= k + 1 if(isOk) do ok :: mid else do ng :: mid end if end while var ans: int :: ok do cui@print("\{ans}\n") end func
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15
001
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fn main() { proconio::input! { n: isize, l: isize, k: isize, mut a: [isize; n] } a.sort(); let mut ok = 0; let mut ng = l + 1; while (ng - ok).abs() > 1 { let mid = (ok + ng) / 2; if is_ok(&a, l, k, mid) { ok = mid; } else { ng = mid; } } println!("{}", ok); } fn is_ok(a: &Vec<isize>, l: isize, k: isize, mid: isize) -> bool { let mut x = 0; let mut y = 0; for i in a { if i - x >= mid && l - i >= mid { x = *i; y += 1; } } y >= k }
func main() var n: int :: cui@inputInt() var l: int :: cui@inputInt() var k: int :: cui@inputInt() var a: []int :: #[n + 1]int for i(0, n - 1) do a[i] :: cui@inputInt() end for do a[n] :: l var ok: int :: 0 var ng: int :: l + 1 while((ok - ng).abs() > 1) var mid: int :: (ok + ng) / 2 var prev: int :: 0 var cnt: int :: 0 for i(0, n) if(a[i] - prev >= mid) do cnt :+ 1 do prev :: a[i] end if end for var isOk: bool :: cnt >= k + 1 if(isOk) do ok :: mid else do ng :: mid end if end while var ans: int :: ok do cui@print("\{ans}\n") end func
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// this problem was so fun :) #include <bits/stdc++.h> #include <atcoder/all> using namespace std; using namespace atcoder; #define fs(n) fixed << setprecision(n); #define mp(a, b) make_pair(a, b); using ll = long long; using ld = long double; int n; int l = 0, r = 0; vector<string> anslist; /* if X is correct brackets string then: (define length of X = L) * L is even number * from 1st to nth chars, * the count of "(" is greater than or equal to the count of ")" (1 ~ n ~ L - 1) * the total count of "(" is equal to the total count of ")" is equal to L / 2 */ void dfs(string s){ if(s.length() == n){ // should consist l = r = n / 2 anslist.emplace_back(s); return; }else{ if(r < n / 2){ r++; dfs(s + "("); r--; } if(l < n / 2 && r > l){ l++; dfs(s + ")"); l--; } } } int main(){ // amount of "(" is equal to amount of ")" is equal to n / 2 cin >> n; if(n % 2) cout << endl; else{ // generate from 2nd char by dfs r = 1; dfs("("); } // sort by lexical order ('(' < ')') sort(anslist.begin(), anslist.end()); for(auto itr = anslist.begin(); itr != anslist.end(); itr++){ cout << *itr << endl; } }
n = read_line.to_i ['(', ')'].each_repeated_permutation(n, true) { |s| a = s.reduce([0]) { |acc, c| acc << acc[-1] + (c == '(' ? 1 : -1) } if a[-1] == 0 && a.all? { |i| i >= 0 } puts s.join end }
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// this problem was so fun :) #include <bits/stdc++.h> #include <atcoder/all> using namespace std; using namespace atcoder; #define fs(n) fixed << setprecision(n); #define mp(a, b) make_pair(a, b); using ll = long long; using ld = long double; int n; int l = 0, r = 0; vector<string> anslist; /* if X is correct brackets string then: (define length of X = L) * L is even number * from 1st to nth chars, * the count of "(" is greater than or equal to the count of ")" (1 ~ n ~ L - 1) * the total count of "(" is equal to the total count of ")" is equal to L / 2 */ void dfs(string s){ if(s.length() == n){ // should consist l = r = n / 2 anslist.emplace_back(s); return; }else{ if(r < n / 2){ r++; dfs(s + "("); r--; } if(l < n / 2 && r > l){ l++; dfs(s + ")"); l--; } } } int main(){ // amount of "(" is equal to amount of ")" is equal to n / 2 cin >> n; if(n % 2) cout << endl; else{ // generate from 2nd char by dfs r = 1; dfs("("); } // sort by lexical order ('(' < ')') sort(anslist.begin(), anslist.end()); for(auto itr = anslist.begin(); itr != anslist.end(); itr++){ cout << *itr << endl; } }
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from itertools import product n = int(input()) ans = [] if n % 2 == 0: # 奇数のときは正しいカッコ列を生成できない for i in product([0, 1], repeat = n): # 0 -> ( , 1 -> ) if i.count(1) == n // 2: # 0, 1の個数が同じ時に判定を始める zero_count = 0 Bool = True word = "" for j in range(len(i)): if i[j] == 0: zero_count += 1 elif i[j] == 1: if zero_count >= 1: # 0の個数が1個以上ないと正しい文字列にならない zero_count -= 1 else: Bool = False word += str(i[j]) if Bool: x = word.replace("0", "(") y = x.replace("1", ")") ans.append(y) ans.sort() print(*ans ,sep = "\n")
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// this problem was so fun :) #include <bits/stdc++.h> #include <atcoder/all> using namespace std; using namespace atcoder; #define fs(n) fixed << setprecision(n); #define mp(a, b) make_pair(a, b); using ll = long long; using ld = long double; int n; int l = 0, r = 0; vector<string> anslist; /* if X is correct brackets string then: (define length of X = L) * L is even number * from 1st to nth chars, * the count of "(" is greater than or equal to the count of ")" (1 ~ n ~ L - 1) * the total count of "(" is equal to the total count of ")" is equal to L / 2 */ void dfs(string s){ if(s.length() == n){ // should consist l = r = n / 2 anslist.emplace_back(s); return; }else{ if(r < n / 2){ r++; dfs(s + "("); r--; } if(l < n / 2 && r > l){ l++; dfs(s + ")"); l--; } } } int main(){ // amount of "(" is equal to amount of ")" is equal to n / 2 cin >> n; if(n % 2) cout << endl; else{ // generate from 2nd char by dfs r = 1; dfs("("); } // sort by lexical order ('(' < ')') sort(anslist.begin(), anslist.end()); for(auto itr = anslist.begin(); itr != anslist.end(); itr++){ cout << *itr << endl; } }
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// this problem was so fun :) #include <bits/stdc++.h> #include <atcoder/all> using namespace std; using namespace atcoder; #define fs(n) fixed << setprecision(n); #define mp(a, b) make_pair(a, b); using ll = long long; using ld = long double; int n; int l = 0, r = 0; vector<string> anslist; /* if X is correct brackets string then: (define length of X = L) * L is even number * from 1st to nth chars, * the count of "(" is greater than or equal to the count of ")" (1 ~ n ~ L - 1) * the total count of "(" is equal to the total count of ")" is equal to L / 2 */ void dfs(string s){ if(s.length() == n){ // should consist l = r = n / 2 anslist.emplace_back(s); return; }else{ if(r < n / 2){ r++; dfs(s + "("); r--; } if(l < n / 2 && r > l){ l++; dfs(s + ")"); l--; } } } int main(){ // amount of "(" is equal to amount of ")" is equal to n / 2 cin >> n; if(n % 2) cout << endl; else{ // generate from 2nd char by dfs r = 1; dfs("("); } // sort by lexical order ('(' < ')') sort(anslist.begin(), anslist.end()); for(auto itr = anslist.begin(); itr != anslist.end(); itr++){ cout << *itr << endl; } }
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func main() var n: int :: cui@inputInt() if(n % 2 <> 0) do cui@print("\n") ret end if for i(0, 2 ^ n - 1) var id: int :: i var cntOpen: int :: 0 var cntClose: int :: 0 var a: []bool :: #[n]bool for j(0, n - 1) do a[j] :: id % 2 = 1 if(a[j]) do cntOpen :+ 1 if(cntOpen > n / 2) skip i end if else do cntClose :+ 1 if(cntClose > cntOpen) skip i end if end if do id :/ 2 end for for j(n - 1, 0, -1) do cui@print(a[j] ?(")", "(")) end for do cui@print("\n") end for end func
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n = read_line.to_i ['(', ')'].each_repeated_permutation(n, true) { |s| a = s.reduce([0]) { |acc, c| acc << acc[-1] + (c == '(' ? 1 : -1) } if a[-1] == 0 && a.all? { |i| i >= 0 } puts s.join end }
from itertools import product n = int(input()) ans = [] if n % 2 == 0: # 奇数のときは正しいカッコ列を生成できない for i in product([0, 1], repeat = n): # 0 -> ( , 1 -> ) if i.count(1) == n // 2: # 0, 1の個数が同じ時に判定を始める zero_count = 0 Bool = True word = "" for j in range(len(i)): if i[j] == 0: zero_count += 1 elif i[j] == 1: if zero_count >= 1: # 0の個数が1個以上ないと正しい文字列にならない zero_count -= 1 else: Bool = False word += str(i[j]) if Bool: x = word.replace("0", "(") y = x.replace("1", ")") ans.append(y) ans.sort() print(*ans ,sep = "\n")
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n = read_line.to_i ['(', ')'].each_repeated_permutation(n, true) { |s| a = s.reduce([0]) { |acc, c| acc << acc[-1] + (c == '(' ? 1 : -1) } if a[-1] == 0 && a.all? { |i| i >= 0 } puts s.join end }
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n = read_line.to_i ['(', ')'].each_repeated_permutation(n, true) { |s| a = s.reduce([0]) { |acc, c| acc << acc[-1] + (c == '(' ? 1 : -1) } if a[-1] == 0 && a.all? { |i| i >= 0 } puts s.join end }
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func main() var n: int :: cui@inputInt() if(n % 2 <> 0) do cui@print("\n") ret end if for i(0, 2 ^ n - 1) var id: int :: i var cntOpen: int :: 0 var cntClose: int :: 0 var a: []bool :: #[n]bool for j(0, n - 1) do a[j] :: id % 2 = 1 if(a[j]) do cntOpen :+ 1 if(cntOpen > n / 2) skip i end if else do cntClose :+ 1 if(cntClose > cntOpen) skip i end if end if do id :/ 2 end for for j(n - 1, 0, -1) do cui@print(a[j] ?(")", "(")) end for do cui@print("\n") end for end func
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from itertools import product n = int(input()) ans = [] if n % 2 == 0: # 奇数のときは正しいカッコ列を生成できない for i in product([0, 1], repeat = n): # 0 -> ( , 1 -> ) if i.count(1) == n // 2: # 0, 1の個数が同じ時に判定を始める zero_count = 0 Bool = True word = "" for j in range(len(i)): if i[j] == 0: zero_count += 1 elif i[j] == 1: if zero_count >= 1: # 0の個数が1個以上ないと正しい文字列にならない zero_count -= 1 else: Bool = False word += str(i[j]) if Bool: x = word.replace("0", "(") y = x.replace("1", ")") ans.append(y) ans.sort() print(*ans ,sep = "\n")
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from itertools import product n = int(input()) ans = [] if n % 2 == 0: # 奇数のときは正しいカッコ列を生成できない for i in product([0, 1], repeat = n): # 0 -> ( , 1 -> ) if i.count(1) == n // 2: # 0, 1の個数が同じ時に判定を始める zero_count = 0 Bool = True word = "" for j in range(len(i)): if i[j] == 0: zero_count += 1 elif i[j] == 1: if zero_count >= 1: # 0の個数が1個以上ないと正しい文字列にならない zero_count -= 1 else: Bool = False word += str(i[j]) if Bool: x = word.replace("0", "(") y = x.replace("1", ")") ans.append(y) ans.sort() print(*ans ,sep = "\n")
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func main() var n: int :: cui@inputInt() if(n % 2 <> 0) do cui@print("\n") ret end if for i(0, 2 ^ n - 1) var id: int :: i var cntOpen: int :: 0 var cntClose: int :: 0 var a: []bool :: #[n]bool for j(0, n - 1) do a[j] :: id % 2 = 1 if(a[j]) do cntOpen :+ 1 if(cntOpen > n / 2) skip i end if else do cntClose :+ 1 if(cntClose > cntOpen) skip i end if end if do id :/ 2 end for for j(n - 1, 0, -1) do cui@print(a[j] ?(")", "(")) end for do cui@print("\n") end for end func
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func main() var n: int :: cui@inputInt() if(n % 2 <> 0) do cui@print("\n") ret end if for i(0, 2 ^ n - 1) var id: int :: i var cntOpen: int :: 0 var cntClose: int :: 0 var a: []bool :: #[n]bool for j(0, n - 1) do a[j] :: id % 2 = 1 if(a[j]) do cntOpen :+ 1 if(cntOpen > n / 2) skip i end if else do cntClose :+ 1 if(cntClose > cntOpen) skip i end if end if do id :/ 2 end for for j(n - 1, 0, -1) do cui@print(a[j] ?(")", "(")) end for do cui@print("\n") end for end func
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#include <iostream> #include <vector> #include <queue> using namespace std; // 入力 int N; int A[1 << 18], B[1 << 18]; // グラフ const int INF = (1 << 29); vector<int> G[1 << 18]; int dist[1 << 18]; void getdist(int start) { // 幅優先探索(BFS)により、最短距離を計算 for (int i = 1; i <= N; i++) dist[i] = INF; queue<int> Q; Q.push(start); dist[start] = 0; while (!Q.empty()) { int pos = Q.front(); Q.pop(); for (int to : G[pos]) { if (dist[to] == INF) { dist[to] = dist[pos] + 1; Q.push(to); } } } } int main() { // Step #1. 入力 cin >> N; for (int i = 1; i <= N - 1; i++) { cin >> A[i] >> B[i]; G[A[i]].push_back(B[i]); G[B[i]].push_back(A[i]); } // Step #2. 頂点 1 からの最短距離を求める // maxid1: 頂点 1 から最も離れている(最短距離が長い)頂点 getdist(1); int maxn1 = -1, maxid1 = -1; for (int i = 1; i <= N; i++) { if (maxn1 < dist[i]) { maxn1 = dist[i]; maxid1 = i; } } // Step #3. 頂点 maxid1 からの最短距離を求める // maxn2: 木の直径(最短距離の最大値) getdist(maxid1); int maxn2 = -1; for (int i = 1; i <= N; i++) { maxn2 = max(maxn2, dist[i]); } // Step #4. 出力 cout << maxn2 + 1 << endl; return 0; }
class UnweightedGraph getter graph : Array(Array(Int32)) def initialize(size : Int) @graph = Array.new(size) { Array(Int32).new } end def add_edge(v, u) @graph[v] << u @graph[u] << v end delegate size, to: @graph delegate :[], to: @graph private def tree_depth_dfs(v : Int32, p : Int32, dist : Int32, a : Array(Int32)) a[v] = dist self[v].each do |u| tree_depth_dfs(u, v, dist + 1, a) if u != p end end def tree_depth(root : Int32) a = Array.new(size, 0) tree_depth_dfs(root, -1, 0, a) a end end n = read_line.to_i graph = UnweightedGraph.new(n) n.pred.times do a, b = read_line.split.map(&.to_i.pred) graph.add_edge(a, b) end _, v = graph.tree_depth(0).each_with_index.max dist, _ = graph.tree_depth(v).each_with_index.max puts dist + 1
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#include <iostream> #include <vector> #include <queue> using namespace std; // 入力 int N; int A[1 << 18], B[1 << 18]; // グラフ const int INF = (1 << 29); vector<int> G[1 << 18]; int dist[1 << 18]; void getdist(int start) { // 幅優先探索(BFS)により、最短距離を計算 for (int i = 1; i <= N; i++) dist[i] = INF; queue<int> Q; Q.push(start); dist[start] = 0; while (!Q.empty()) { int pos = Q.front(); Q.pop(); for (int to : G[pos]) { if (dist[to] == INF) { dist[to] = dist[pos] + 1; Q.push(to); } } } } int main() { // Step #1. 入力 cin >> N; for (int i = 1; i <= N - 1; i++) { cin >> A[i] >> B[i]; G[A[i]].push_back(B[i]); G[B[i]].push_back(A[i]); } // Step #2. 頂点 1 からの最短距離を求める // maxid1: 頂点 1 から最も離れている(最短距離が長い)頂点 getdist(1); int maxn1 = -1, maxid1 = -1; for (int i = 1; i <= N; i++) { if (maxn1 < dist[i]) { maxn1 = dist[i]; maxid1 = i; } } // Step #3. 頂点 maxid1 からの最短距離を求める // maxn2: 木の直径(最短距離の最大値) getdist(maxid1); int maxn2 = -1; for (int i = 1; i <= N; i++) { maxn2 = max(maxn2, dist[i]); } // Step #4. 出力 cout << maxn2 + 1 << endl; return 0; }
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) import sys sys.setrecursionlimit(10**6) N = int(input()) G = [[] for _ in range(N)] for _ in range(N - 1): a, b = map(int, input().split()) a, b = a - 1, b - 1 G[a].append(b) G[b].append(a) def dfs(s): D = [-1] * N D[s] = 0 stk = [s] push, pop = stk.append, stk.pop while stk: v = pop() nd = D[v] + 1 for nv in G[v]: if D[nv] >= 0: continue D[nv] = nd push(nv) return D D0 = dfs(0) mxi = max(enumerate(D0), key=lambda x: x[1])[0] Dmx = dfs(mxi) print(max(Dmx) + 1)
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#include <iostream> #include <vector> #include <queue> using namespace std; // 入力 int N; int A[1 << 18], B[1 << 18]; // グラフ const int INF = (1 << 29); vector<int> G[1 << 18]; int dist[1 << 18]; void getdist(int start) { // 幅優先探索(BFS)により、最短距離を計算 for (int i = 1; i <= N; i++) dist[i] = INF; queue<int> Q; Q.push(start); dist[start] = 0; while (!Q.empty()) { int pos = Q.front(); Q.pop(); for (int to : G[pos]) { if (dist[to] == INF) { dist[to] = dist[pos] + 1; Q.push(to); } } } } int main() { // Step #1. 入力 cin >> N; for (int i = 1; i <= N - 1; i++) { cin >> A[i] >> B[i]; G[A[i]].push_back(B[i]); G[B[i]].push_back(A[i]); } // Step #2. 頂点 1 からの最短距離を求める // maxid1: 頂点 1 から最も離れている(最短距離が長い)頂点 getdist(1); int maxn1 = -1, maxid1 = -1; for (int i = 1; i <= N; i++) { if (maxn1 < dist[i]) { maxn1 = dist[i]; maxid1 = i; } } // Step #3. 頂点 maxid1 からの最短距離を求める // maxn2: 木の直径(最短距離の最大値) getdist(maxid1); int maxn2 = -1; for (int i = 1; i <= N; i++) { maxn2 = max(maxn2, dist[i]); } // Step #4. 出力 cout << maxn2 + 1 << endl; return 0; }
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#include <iostream> #include <vector> #include <queue> using namespace std; // 入力 int N; int A[1 << 18], B[1 << 18]; // グラフ const int INF = (1 << 29); vector<int> G[1 << 18]; int dist[1 << 18]; void getdist(int start) { // 幅優先探索(BFS)により、最短距離を計算 for (int i = 1; i <= N; i++) dist[i] = INF; queue<int> Q; Q.push(start); dist[start] = 0; while (!Q.empty()) { int pos = Q.front(); Q.pop(); for (int to : G[pos]) { if (dist[to] == INF) { dist[to] = dist[pos] + 1; Q.push(to); } } } } int main() { // Step #1. 入力 cin >> N; for (int i = 1; i <= N - 1; i++) { cin >> A[i] >> B[i]; G[A[i]].push_back(B[i]); G[B[i]].push_back(A[i]); } // Step #2. 頂点 1 からの最短距離を求める // maxid1: 頂点 1 から最も離れている(最短距離が長い)頂点 getdist(1); int maxn1 = -1, maxid1 = -1; for (int i = 1; i <= N; i++) { if (maxn1 < dist[i]) { maxn1 = dist[i]; maxid1 = i; } } // Step #3. 頂点 maxid1 からの最短距離を求める // maxn2: 木の直径(最短距離の最大値) getdist(maxid1); int maxn2 = -1; for (int i = 1; i <= N; i++) { maxn2 = max(maxn2, dist[i]); } // Step #4. 出力 cout << maxn2 + 1 << endl; return 0; }
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use proconio::{input,marker::Usize1}; use std::collections::VecDeque; fn main(){ input!{n:usize} let mut g=vec![vec![];n]; for _ in 1..n{ input!{x:Usize1,y:Usize1} g[x].push(y); g[y].push(x); } let mut d=vec![1<<30;n]; bfs(&g,&mut d,0usize); let mut u:usize=0; let m=d.iter().max().unwrap(); for i in 0..n{ if &d[i]==m {u=i} } let mut d=vec![1<<30;n]; bfs(&g,&mut d,u); println!("{}",1+d.iter().max().unwrap()); } fn bfs(g:&Vec<Vec<usize>>,d:&mut Vec<isize>,s:usize){ let mut q:VecDeque<usize>=VecDeque::new(); d[s]=0; q.push_back(s); while q.len()>0{ let i=q.pop_front().unwrap(); for j in g[i].iter(){ if d[*j]==1<<30{ q.push_back(*j); d[*j]=d[i]+1; } } } }
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#include <iostream> #include <vector> #include <queue> using namespace std; // 入力 int N; int A[1 << 18], B[1 << 18]; // グラフ const int INF = (1 << 29); vector<int> G[1 << 18]; int dist[1 << 18]; void getdist(int start) { // 幅優先探索(BFS)により、最短距離を計算 for (int i = 1; i <= N; i++) dist[i] = INF; queue<int> Q; Q.push(start); dist[start] = 0; while (!Q.empty()) { int pos = Q.front(); Q.pop(); for (int to : G[pos]) { if (dist[to] == INF) { dist[to] = dist[pos] + 1; Q.push(to); } } } } int main() { // Step #1. 入力 cin >> N; for (int i = 1; i <= N - 1; i++) { cin >> A[i] >> B[i]; G[A[i]].push_back(B[i]); G[B[i]].push_back(A[i]); } // Step #2. 頂点 1 からの最短距離を求める // maxid1: 頂点 1 から最も離れている(最短距離が長い)頂点 getdist(1); int maxn1 = -1, maxid1 = -1; for (int i = 1; i <= N; i++) { if (maxn1 < dist[i]) { maxn1 = dist[i]; maxid1 = i; } } // Step #3. 頂点 maxid1 からの最短距離を求める // maxn2: 木の直径(最短距離の最大値) getdist(maxid1); int maxn2 = -1; for (int i = 1; i <= N; i++) { maxn2 = max(maxn2, dist[i]); } // Step #4. 出力 cout << maxn2 + 1 << endl; return 0; }
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func main() var n: int :: cui@inputInt() var graph: []list<int> :: #[n]list<int> for i(0, n - 1) do graph[i] :: #list<int> end for for i(0, n - 2) var a: int :: cui@inputInt() - 1 var b: int :: cui@inputInt() - 1 do graph[a].add(b) do graph[b].add(a) end for var ans: int :: treeDiameter(graph) + 1 do cui@print("\{ans}\n") func treeDiameter(graph: []list<int>): int var pos: int :: 0 do treeDiameterSub(graph, &pos, -1) ret treeDiameterSub(graph, &pos, -1) func treeDiameterSub(graph: []list<int>, pos: &int, p: int): int var u: int :: pos var res: int :: 0 do graph[u].head() while(!graph[u].term()) var x: int :: graph[u].get() if(x <> p) var dist: int :: treeDiameterSub(graph, &x, u) + 1 if(dist > res) do res :: dist do pos :: x end if end if do graph[u].next() end while ret res end func end func end func
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class UnweightedGraph getter graph : Array(Array(Int32)) def initialize(size : Int) @graph = Array.new(size) { Array(Int32).new } end def add_edge(v, u) @graph[v] << u @graph[u] << v end delegate size, to: @graph delegate :[], to: @graph private def tree_depth_dfs(v : Int32, p : Int32, dist : Int32, a : Array(Int32)) a[v] = dist self[v].each do |u| tree_depth_dfs(u, v, dist + 1, a) if u != p end end def tree_depth(root : Int32) a = Array.new(size, 0) tree_depth_dfs(root, -1, 0, a) a end end n = read_line.to_i graph = UnweightedGraph.new(n) n.pred.times do a, b = read_line.split.map(&.to_i.pred) graph.add_edge(a, b) end _, v = graph.tree_depth(0).each_with_index.max dist, _ = graph.tree_depth(v).each_with_index.max puts dist + 1
# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) import sys sys.setrecursionlimit(10**6) N = int(input()) G = [[] for _ in range(N)] for _ in range(N - 1): a, b = map(int, input().split()) a, b = a - 1, b - 1 G[a].append(b) G[b].append(a) def dfs(s): D = [-1] * N D[s] = 0 stk = [s] push, pop = stk.append, stk.pop while stk: v = pop() nd = D[v] + 1 for nv in G[v]: if D[nv] >= 0: continue D[nv] = nd push(nv) return D D0 = dfs(0) mxi = max(enumerate(D0), key=lambda x: x[1])[0] Dmx = dfs(mxi) print(max(Dmx) + 1)
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class UnweightedGraph getter graph : Array(Array(Int32)) def initialize(size : Int) @graph = Array.new(size) { Array(Int32).new } end def add_edge(v, u) @graph[v] << u @graph[u] << v end delegate size, to: @graph delegate :[], to: @graph private def tree_depth_dfs(v : Int32, p : Int32, dist : Int32, a : Array(Int32)) a[v] = dist self[v].each do |u| tree_depth_dfs(u, v, dist + 1, a) if u != p end end def tree_depth(root : Int32) a = Array.new(size, 0) tree_depth_dfs(root, -1, 0, a) a end end n = read_line.to_i graph = UnweightedGraph.new(n) n.pred.times do a, b = read_line.split.map(&.to_i.pred) graph.add_edge(a, b) end _, v = graph.tree_depth(0).each_with_index.max dist, _ = graph.tree_depth(v).each_with_index.max puts dist + 1
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class UnweightedGraph getter graph : Array(Array(Int32)) def initialize(size : Int) @graph = Array.new(size) { Array(Int32).new } end def add_edge(v, u) @graph[v] << u @graph[u] << v end delegate size, to: @graph delegate :[], to: @graph private def tree_depth_dfs(v : Int32, p : Int32, dist : Int32, a : Array(Int32)) a[v] = dist self[v].each do |u| tree_depth_dfs(u, v, dist + 1, a) if u != p end end def tree_depth(root : Int32) a = Array.new(size, 0) tree_depth_dfs(root, -1, 0, a) a end end n = read_line.to_i graph = UnweightedGraph.new(n) n.pred.times do a, b = read_line.split.map(&.to_i.pred) graph.add_edge(a, b) end _, v = graph.tree_depth(0).each_with_index.max dist, _ = graph.tree_depth(v).each_with_index.max puts dist + 1
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use proconio::{input,marker::Usize1}; use std::collections::VecDeque; fn main(){ input!{n:usize} let mut g=vec![vec![];n]; for _ in 1..n{ input!{x:Usize1,y:Usize1} g[x].push(y); g[y].push(x); } let mut d=vec![1<<30;n]; bfs(&g,&mut d,0usize); let mut u:usize=0; let m=d.iter().max().unwrap(); for i in 0..n{ if &d[i]==m {u=i} } let mut d=vec![1<<30;n]; bfs(&g,&mut d,u); println!("{}",1+d.iter().max().unwrap()); } fn bfs(g:&Vec<Vec<usize>>,d:&mut Vec<isize>,s:usize){ let mut q:VecDeque<usize>=VecDeque::new(); d[s]=0; q.push_back(s); while q.len()>0{ let i=q.pop_front().unwrap(); for j in g[i].iter(){ if d[*j]==1<<30{ q.push_back(*j); d[*j]=d[i]+1; } } } }
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class UnweightedGraph getter graph : Array(Array(Int32)) def initialize(size : Int) @graph = Array.new(size) { Array(Int32).new } end def add_edge(v, u) @graph[v] << u @graph[u] << v end delegate size, to: @graph delegate :[], to: @graph private def tree_depth_dfs(v : Int32, p : Int32, dist : Int32, a : Array(Int32)) a[v] = dist self[v].each do |u| tree_depth_dfs(u, v, dist + 1, a) if u != p end end def tree_depth(root : Int32) a = Array.new(size, 0) tree_depth_dfs(root, -1, 0, a) a end end n = read_line.to_i graph = UnweightedGraph.new(n) n.pred.times do a, b = read_line.split.map(&.to_i.pred) graph.add_edge(a, b) end _, v = graph.tree_depth(0).each_with_index.max dist, _ = graph.tree_depth(v).each_with_index.max puts dist + 1
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func main() var n: int :: cui@inputInt() var graph: []list<int> :: #[n]list<int> for i(0, n - 1) do graph[i] :: #list<int> end for for i(0, n - 2) var a: int :: cui@inputInt() - 1 var b: int :: cui@inputInt() - 1 do graph[a].add(b) do graph[b].add(a) end for var ans: int :: treeDiameter(graph) + 1 do cui@print("\{ans}\n") func treeDiameter(graph: []list<int>): int var pos: int :: 0 do treeDiameterSub(graph, &pos, -1) ret treeDiameterSub(graph, &pos, -1) func treeDiameterSub(graph: []list<int>, pos: &int, p: int): int var u: int :: pos var res: int :: 0 do graph[u].head() while(!graph[u].term()) var x: int :: graph[u].get() if(x <> p) var dist: int :: treeDiameterSub(graph, &x, u) + 1 if(dist > res) do res :: dist do pos :: x end if end if do graph[u].next() end while ret res end func end func end func
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) import sys sys.setrecursionlimit(10**6) N = int(input()) G = [[] for _ in range(N)] for _ in range(N - 1): a, b = map(int, input().split()) a, b = a - 1, b - 1 G[a].append(b) G[b].append(a) def dfs(s): D = [-1] * N D[s] = 0 stk = [s] push, pop = stk.append, stk.pop while stk: v = pop() nd = D[v] + 1 for nv in G[v]: if D[nv] >= 0: continue D[nv] = nd push(nv) return D D0 = dfs(0) mxi = max(enumerate(D0), key=lambda x: x[1])[0] Dmx = dfs(mxi) print(max(Dmx) + 1)
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) import sys sys.setrecursionlimit(10**6) N = int(input()) G = [[] for _ in range(N)] for _ in range(N - 1): a, b = map(int, input().split()) a, b = a - 1, b - 1 G[a].append(b) G[b].append(a) def dfs(s): D = [-1] * N D[s] = 0 stk = [s] push, pop = stk.append, stk.pop while stk: v = pop() nd = D[v] + 1 for nv in G[v]: if D[nv] >= 0: continue D[nv] = nd push(nv) return D D0 = dfs(0) mxi = max(enumerate(D0), key=lambda x: x[1])[0] Dmx = dfs(mxi) print(max(Dmx) + 1)
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use proconio::{input,marker::Usize1}; use std::collections::VecDeque; fn main(){ input!{n:usize} let mut g=vec![vec![];n]; for _ in 1..n{ input!{x:Usize1,y:Usize1} g[x].push(y); g[y].push(x); } let mut d=vec![1<<30;n]; bfs(&g,&mut d,0usize); let mut u:usize=0; let m=d.iter().max().unwrap(); for i in 0..n{ if &d[i]==m {u=i} } let mut d=vec![1<<30;n]; bfs(&g,&mut d,u); println!("{}",1+d.iter().max().unwrap()); } fn bfs(g:&Vec<Vec<usize>>,d:&mut Vec<isize>,s:usize){ let mut q:VecDeque<usize>=VecDeque::new(); d[s]=0; q.push_back(s); while q.len()>0{ let i=q.pop_front().unwrap(); for j in g[i].iter(){ if d[*j]==1<<30{ q.push_back(*j); d[*j]=d[i]+1; } } } }
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) import sys sys.setrecursionlimit(10**6) N = int(input()) G = [[] for _ in range(N)] for _ in range(N - 1): a, b = map(int, input().split()) a, b = a - 1, b - 1 G[a].append(b) G[b].append(a) def dfs(s): D = [-1] * N D[s] = 0 stk = [s] push, pop = stk.append, stk.pop while stk: v = pop() nd = D[v] + 1 for nv in G[v]: if D[nv] >= 0: continue D[nv] = nd push(nv) return D D0 = dfs(0) mxi = max(enumerate(D0), key=lambda x: x[1])[0] Dmx = dfs(mxi) print(max(Dmx) + 1)
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func main() var n: int :: cui@inputInt() var graph: []list<int> :: #[n]list<int> for i(0, n - 1) do graph[i] :: #list<int> end for for i(0, n - 2) var a: int :: cui@inputInt() - 1 var b: int :: cui@inputInt() - 1 do graph[a].add(b) do graph[b].add(a) end for var ans: int :: treeDiameter(graph) + 1 do cui@print("\{ans}\n") func treeDiameter(graph: []list<int>): int var pos: int :: 0 do treeDiameterSub(graph, &pos, -1) ret treeDiameterSub(graph, &pos, -1) func treeDiameterSub(graph: []list<int>, pos: &int, p: int): int var u: int :: pos var res: int :: 0 do graph[u].head() while(!graph[u].term()) var x: int :: graph[u].get() if(x <> p) var dist: int :: treeDiameterSub(graph, &x, u) + 1 if(dist > res) do res :: dist do pos :: x end if end if do graph[u].next() end while ret res end func end func end func
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use proconio::{input,marker::Usize1}; use std::collections::VecDeque; fn main(){ input!{n:usize} let mut g=vec![vec![];n]; for _ in 1..n{ input!{x:Usize1,y:Usize1} g[x].push(y); g[y].push(x); } let mut d=vec![1<<30;n]; bfs(&g,&mut d,0usize); let mut u:usize=0; let m=d.iter().max().unwrap(); for i in 0..n{ if &d[i]==m {u=i} } let mut d=vec![1<<30;n]; bfs(&g,&mut d,u); println!("{}",1+d.iter().max().unwrap()); } fn bfs(g:&Vec<Vec<usize>>,d:&mut Vec<isize>,s:usize){ let mut q:VecDeque<usize>=VecDeque::new(); d[s]=0; q.push_back(s); while q.len()>0{ let i=q.pop_front().unwrap(); for j in g[i].iter(){ if d[*j]==1<<30{ q.push_back(*j); d[*j]=d[i]+1; } } } }
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func main() var n: int :: cui@inputInt() var graph: []list<int> :: #[n]list<int> for i(0, n - 1) do graph[i] :: #list<int> end for for i(0, n - 2) var a: int :: cui@inputInt() - 1 var b: int :: cui@inputInt() - 1 do graph[a].add(b) do graph[b].add(a) end for var ans: int :: treeDiameter(graph) + 1 do cui@print("\{ans}\n") func treeDiameter(graph: []list<int>): int var pos: int :: 0 do treeDiameterSub(graph, &pos, -1) ret treeDiameterSub(graph, &pos, -1) func treeDiameterSub(graph: []list<int>, pos: &int, p: int): int var u: int :: pos var res: int :: 0 do graph[u].head() while(!graph[u].term()) var x: int :: graph[u].get() if(x <> p) var dist: int :: treeDiameterSub(graph, &x, u) + 1 if(dist > res) do res :: dist do pos :: x end if end if do graph[u].next() end while ret res end func end func end func
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use proconio::{input,marker::Usize1}; use std::collections::VecDeque; fn main(){ input!{n:usize} let mut g=vec![vec![];n]; for _ in 1..n{ input!{x:Usize1,y:Usize1} g[x].push(y); g[y].push(x); } let mut d=vec![1<<30;n]; bfs(&g,&mut d,0usize); let mut u:usize=0; let m=d.iter().max().unwrap(); for i in 0..n{ if &d[i]==m {u=i} } let mut d=vec![1<<30;n]; bfs(&g,&mut d,u); println!("{}",1+d.iter().max().unwrap()); } fn bfs(g:&Vec<Vec<usize>>,d:&mut Vec<isize>,s:usize){ let mut q:VecDeque<usize>=VecDeque::new(); d[s]=0; q.push_back(s); while q.len()>0{ let i=q.pop_front().unwrap(); for j in g[i].iter(){ if d[*j]==1<<30{ q.push_back(*j); d[*j]=d[i]+1; } } } }
func main() var n: int :: cui@inputInt() var graph: []list<int> :: #[n]list<int> for i(0, n - 1) do graph[i] :: #list<int> end for for i(0, n - 2) var a: int :: cui@inputInt() - 1 var b: int :: cui@inputInt() - 1 do graph[a].add(b) do graph[b].add(a) end for var ans: int :: treeDiameter(graph) + 1 do cui@print("\{ans}\n") func treeDiameter(graph: []list<int>): int var pos: int :: 0 do treeDiameterSub(graph, &pos, -1) ret treeDiameterSub(graph, &pos, -1) func treeDiameterSub(graph: []list<int>, pos: &int, p: int): int var u: int :: pos var res: int :: 0 do graph[u].head() while(!graph[u].term()) var x: int :: graph[u].get() if(x <> p) var dist: int :: treeDiameterSub(graph, &x, u) + 1 if(dist > res) do res :: dist do pos :: x end if end if do graph[u].next() end while ret res end func end func end func
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#include <iostream> using namespace std; #pragma warning (disable: 4996) int H, W; int A[2009][2009]; int Row[2009], Column[2009]; int Answer[2009][2009]; int main() { // Step #1. “ü—Í cin >> H >> W; for (int i = 1; i <= H; i++) { for (int j = 1; j <= W; j++) { scanf("%d", &A[i][j]); } } // Step #2. ‘OŒvŽZ for (int i = 1; i <= H; i++) { for (int j = 1; j <= W; j++) { Row[i] += A[i][j]; Column[j] += A[i][j]; } } // Step #3. “š‚¦‚ÌŒvŽZ for (int i = 1; i <= H; i++) { for (int j = 1; j <= W; j++) { Answer[i][j] = Row[i] + Column[j] - A[i][j]; } } // Step #4. �o—Í for (int i = 1; i <= H; i++) { for (int j = 1; j <= W; j++) { if (j >= 2) printf(" "); printf("%d", Answer[i][j]); } printf("\n"); } return 0; }
h, w = read_line.split.map(&.to_i) a = (1..h).map { read_line.split.map(&.to_i) } row_sum = a.map(&.sum) column_sum = a.transpose.map(&.sum) (0...h).each do |i| puts (0...w).join(' ') { |j| row_sum[i] + column_sum[j] - a[i][j] } end
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h, w = read_line.split.map(&.to_i) a = (1..h).map { read_line.split.map(&.to_i) } row_sum = a.map(&.sum) column_sum = a.transpose.map(&.sum) (0...h).each do |i| puts (0...w).join(' ') { |j| row_sum[i] + column_sum[j] - a[i][j] } end
# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) import sys def main(): input = sys.stdin.readline H, W = map(int, input().split()) A = [tuple(map(int, input().split())) for _ in range(H)] R = [sum(A[i]) for i in range(H)] C = [sum(A[i][j] for i in range(H)) for j in range(W)] ans = [[R[i] + C[j] - A[i][j] for j in range(W)] for i in range(H)] for a in ans: print(*a) if __name__ == '__main__': main()
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h, w = read_line.split.map(&.to_i) a = (1..h).map { read_line.split.map(&.to_i) } row_sum = a.map(&.sum) column_sum = a.transpose.map(&.sum) (0...h).each do |i| puts (0...w).join(' ') { |j| row_sum[i] + column_sum[j] - a[i][j] } end
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h, w = read_line.split.map(&.to_i) a = (1..h).map { read_line.split.map(&.to_i) } row_sum = a.map(&.sum) column_sum = a.transpose.map(&.sum) (0...h).each do |i| puts (0...w).join(' ') { |j| row_sum[i] + column_sum[j] - a[i][j] } end
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func main() var h: int :: cui@inputInt() var w: int :: cui@inputInt() do cui@delimiter("") var s: []char :: cui@inputStr() var idx: int :: 0 var a: [][]int :: #[h, w]int var row: []int :: #[h]int var col: []int :: #[w]int for y(0, h - 1) for x(0, w - 1) var v: int :: 0 while('0' <= s[idx]) do v :* 10 do v :+ s[idx] $ int - '0' $ int do idx :+ 1 end while do idx :+ 1 do a[y][x] :: v do row[y] :+ v do col[x] :+ v end for end for for y(0, h - 1) for x(0, w - 1) do a[y][x] :: row[y] + col[x] - a[y][x] end for end for for y(0, h - 1) do cui@print(a[y].join(" ")) do cui@print("\n") end for end func
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#include <iostream> using namespace std; #pragma warning (disable: 4996) int H, W; int A[2009][2009]; int Row[2009], Column[2009]; int Answer[2009][2009]; int main() { // Step #1. “ü—Í cin >> H >> W; for (int i = 1; i <= H; i++) { for (int j = 1; j <= W; j++) { scanf("%d", &A[i][j]); } } // Step #2. ‘OŒvŽZ for (int i = 1; i <= H; i++) { for (int j = 1; j <= W; j++) { Row[i] += A[i][j]; Column[j] += A[i][j]; } } // Step #3. “š‚¦‚ÌŒvŽZ for (int i = 1; i <= H; i++) { for (int j = 1; j <= W; j++) { Answer[i][j] = Row[i] + Column[j] - A[i][j]; } } // Step #4. �o—Í for (int i = 1; i <= H; i++) { for (int j = 1; j <= W; j++) { if (j >= 2) printf(" "); printf("%d", Answer[i][j]); } printf("\n"); } return 0; }
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) import sys def main(): input = sys.stdin.readline H, W = map(int, input().split()) A = [tuple(map(int, input().split())) for _ in range(H)] R = [sum(A[i]) for i in range(H)] C = [sum(A[i][j] for i in range(H)) for j in range(W)] ans = [[R[i] + C[j] - A[i][j] for j in range(W)] for i in range(H)] for a in ans: print(*a) if __name__ == '__main__': main()
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#include <iostream> using namespace std; #pragma warning (disable: 4996) int H, W; int A[2009][2009]; int Row[2009], Column[2009]; int Answer[2009][2009]; int main() { // Step #1. “ü—Í cin >> H >> W; for (int i = 1; i <= H; i++) { for (int j = 1; j <= W; j++) { scanf("%d", &A[i][j]); } } // Step #2. ‘OŒvŽZ for (int i = 1; i <= H; i++) { for (int j = 1; j <= W; j++) { Row[i] += A[i][j]; Column[j] += A[i][j]; } } // Step #3. “š‚¦‚ÌŒvŽZ for (int i = 1; i <= H; i++) { for (int j = 1; j <= W; j++) { Answer[i][j] = Row[i] + Column[j] - A[i][j]; } } // Step #4. �o—Í for (int i = 1; i <= H; i++) { for (int j = 1; j <= W; j++) { if (j >= 2) printf(" "); printf("%d", Answer[i][j]); } printf("\n"); } return 0; }
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#include <iostream> using namespace std; #pragma warning (disable: 4996) int H, W; int A[2009][2009]; int Row[2009], Column[2009]; int Answer[2009][2009]; int main() { // Step #1. “ü—Í cin >> H >> W; for (int i = 1; i <= H; i++) { for (int j = 1; j <= W; j++) { scanf("%d", &A[i][j]); } } // Step #2. ‘OŒvŽZ for (int i = 1; i <= H; i++) { for (int j = 1; j <= W; j++) { Row[i] += A[i][j]; Column[j] += A[i][j]; } } // Step #3. “š‚¦‚ÌŒvŽZ for (int i = 1; i <= H; i++) { for (int j = 1; j <= W; j++) { Answer[i][j] = Row[i] + Column[j] - A[i][j]; } } // Step #4. �o—Í for (int i = 1; i <= H; i++) { for (int j = 1; j <= W; j++) { if (j >= 2) printf(" "); printf("%d", Answer[i][j]); } printf("\n"); } return 0; }
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func main() var h: int :: cui@inputInt() var w: int :: cui@inputInt() do cui@delimiter("") var s: []char :: cui@inputStr() var idx: int :: 0 var a: [][]int :: #[h, w]int var row: []int :: #[h]int var col: []int :: #[w]int for y(0, h - 1) for x(0, w - 1) var v: int :: 0 while('0' <= s[idx]) do v :* 10 do v :+ s[idx] $ int - '0' $ int do idx :+ 1 end while do idx :+ 1 do a[y][x] :: v do row[y] :+ v do col[x] :+ v end for end for for y(0, h - 1) for x(0, w - 1) do a[y][x] :: row[y] + col[x] - a[y][x] end for end for for y(0, h - 1) do cui@print(a[y].join(" ")) do cui@print("\n") end for end func
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) import sys def main(): input = sys.stdin.readline H, W = map(int, input().split()) A = [tuple(map(int, input().split())) for _ in range(H)] R = [sum(A[i]) for i in range(H)] C = [sum(A[i][j] for i in range(H)) for j in range(W)] ans = [[R[i] + C[j] - A[i][j] for j in range(W)] for i in range(H)] for a in ans: print(*a) if __name__ == '__main__': main()
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) import sys def main(): input = sys.stdin.readline H, W = map(int, input().split()) A = [tuple(map(int, input().split())) for _ in range(H)] R = [sum(A[i]) for i in range(H)] C = [sum(A[i][j] for i in range(H)) for j in range(W)] ans = [[R[i] + C[j] - A[i][j] for j in range(W)] for i in range(H)] for a in ans: print(*a) if __name__ == '__main__': main()
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func main() var h: int :: cui@inputInt() var w: int :: cui@inputInt() do cui@delimiter("") var s: []char :: cui@inputStr() var idx: int :: 0 var a: [][]int :: #[h, w]int var row: []int :: #[h]int var col: []int :: #[w]int for y(0, h - 1) for x(0, w - 1) var v: int :: 0 while('0' <= s[idx]) do v :* 10 do v :+ s[idx] $ int - '0' $ int do idx :+ 1 end while do idx :+ 1 do a[y][x] :: v do row[y] :+ v do col[x] :+ v end for end for for y(0, h - 1) for x(0, w - 1) do a[y][x] :: row[y] + col[x] - a[y][x] end for end for for y(0, h - 1) do cui@print(a[y].join(" ")) do cui@print("\n") end for end func
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func main() var h: int :: cui@inputInt() var w: int :: cui@inputInt() do cui@delimiter("") var s: []char :: cui@inputStr() var idx: int :: 0 var a: [][]int :: #[h, w]int var row: []int :: #[h]int var col: []int :: #[w]int for y(0, h - 1) for x(0, w - 1) var v: int :: 0 while('0' <= s[idx]) do v :* 10 do v :+ s[idx] $ int - '0' $ int do idx :+ 1 end while do idx :+ 1 do a[y][x] :: v do row[y] :+ v do col[x] :+ v end for end for for y(0, h - 1) for x(0, w - 1) do a[y][x] :: row[y] + col[x] - a[y][x] end for end for for y(0, h - 1) do cui@print(a[y].join(" ")) do cui@print("\n") end for end func
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#include <iostream> using namespace std; long long modpow(long long a, long long b, long long m) { long long p = 1, q = a; for (int i = 0; i < 63; i++) { if ((b & (1LL << i)) != 0) { p *= q; p %= m; } q *= q; q %= m; } return p; } const long long mod = 1000000007; // 入力 long long N, B, K; long long C[11]; // その他の変数 long long power10[64]; long long DP[64][1009]; long long Answer[64][1009]; int main() { // Step #1. 入力 cin >> N >> B >> K; for (int i = 1; i <= K; i++) cin >> C[i]; // Step #2. 前計算 for (int i = 0; i <= 62; i++) { power10[i] = modpow(10LL, (1LL << i), B); } // Step #3. dp[1][i] を求める for (int i = 1; i <= K; i++) { DP[0][C[i] % B] += 1; } // Step #4. dp[1][i], dp[2][i], ..., dp[2^n][i] を求める for (int i = 0; i < 62; i++) { for (int j = 0; j < B; j++) { for (int k = 0; k < B; k++) { int nex = (j * power10[i] + k) % B; DP[i + 1][nex] += DP[i][j] * DP[i][k]; DP[i + 1][nex] %= mod; } } } // Step #5. 繰り返し二乗法により dp[N][i] を求める Answer[0][0] = 1; for (int i = 0; i < 62; i++) { if ((N & (1LL << i)) != 0LL) { for (int j = 0; j < B; j++) { for (int k = 0; k < B; k++) { int nex = (j * power10[i] + k) % B; Answer[i + 1][nex] += Answer[i][j] * DP[i][k]; Answer[i + 1][nex] %= mod; } } } else { for (int j = 0; j < B; j++) Answer[i + 1][j] = Answer[i][j]; } } // Step #6. 出力 cout << Answer[62][0] << endl; return 0; }
struct Mint MOD = 1000000007i64 def self.zero new end def self.raw(value : Int64) result = new result.value = value result end @value : Int64 def initialize @value = 0i64 end def initialize(value) @value = value.to_i64 % MOD end def initialize(m : self) @value = m.value end protected def value=(value : Int64) @value = value end getter value : Int64 def + : self self end def - : self Mint.raw(value != 0 ? MOD &- value : 0i64) end def +(v) self + v.to_m end def +(m : self) x = value &+ m.value x &-= MOD if x >= MOD Mint.raw(x) end def -(v) self - v.to_m end def -(m : self) x = value &- m.value x &+= MOD if x < 0 Mint.raw(x) end def *(v) self * v.to_m end def *(m : self) Mint.new(value &* m.value) end def /(v) self / v.to_m end def /(m : self) raise DivisionByZeroError.new if m.value == 0 a, b, u, v = m.to_i64, MOD, 1i64, 0i64 while b != 0 t = a // b a &-= t &* b a, b = b, a u &-= t &* v u, v = v, u end Mint.new(value &* u) end def //(v) self / v end def **(exponent : Int) t, res = self, Mint.raw(1i64) while exponent > 0 res *= t if exponent & 1 == 1 t *= t exponent >>= 1 end res end def ==(m : self) value == m.value end def ==(m : Int) raise NotImplementedError.new("==") end def succ Mint.raw(value != MOD &- 1 ? value &+ 1 : 0i64) end def pred Mint.raw(value != 0 ? value &- 1 : MOD &- 1) end def abs self end def to_i64 : Int64 value end delegate to_s, to: @value delegate inspect, to: @value end struct Int {% for op in %w[+ - * / //] %} def {{op.id}}(value : Mint) to_m {{op.id}} value end {% end %} def to_m : Mint Mint.new(self) end end class String def to_m : Mint Mint.new(self) end end struct Int def powmod(exp : T, mod : self) forall T n = self % mod res = typeof(self).new(1) while exp > 0 res = res * n % mod if exp.odd? n = n * n % mod exp >>= 1 end res end end n, b, k = read_line.split.try { |(n, b, k)| {n.to_i64, b.to_i, k.to_i} } a = read_line.split.map(&.to_i) m = Math.log2(n).ceil.to_i + 1 dp_marge = ->(dp1 : Array(Mint), digit : Int64, dp2 : Array(Mint)) { dp_res = Array.new(b, Mint.zero) pow10 = 10.powmod(digit, b) (0...b).each do |i| (0...b).each do |j| dp_res[(i * pow10 + j) % b] += dp1[i] * dp2[j] end end dp_res } doubling = Array.new(1) { [Mint.zero] * b } a.each { |j| doubling[0][j % b] += 1 } (1..m).each { |i| doubling << dp_marge.call(doubling[-1], 2i64**i.pred, doubling[-1]) } dp = [Mint.zero] * b dp[0] = 1.to_m (0..m).select { |i| n.bit(i) == 1 }.each do |i| dp = dp_marge.call(dp, 2i64**i, doubling[i]) end puts dp[0]
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#include <iostream> using namespace std; long long modpow(long long a, long long b, long long m) { long long p = 1, q = a; for (int i = 0; i < 63; i++) { if ((b & (1LL << i)) != 0) { p *= q; p %= m; } q *= q; q %= m; } return p; } const long long mod = 1000000007; // 入力 long long N, B, K; long long C[11]; // その他の変数 long long power10[64]; long long DP[64][1009]; long long Answer[64][1009]; int main() { // Step #1. 入力 cin >> N >> B >> K; for (int i = 1; i <= K; i++) cin >> C[i]; // Step #2. 前計算 for (int i = 0; i <= 62; i++) { power10[i] = modpow(10LL, (1LL << i), B); } // Step #3. dp[1][i] を求める for (int i = 1; i <= K; i++) { DP[0][C[i] % B] += 1; } // Step #4. dp[1][i], dp[2][i], ..., dp[2^n][i] を求める for (int i = 0; i < 62; i++) { for (int j = 0; j < B; j++) { for (int k = 0; k < B; k++) { int nex = (j * power10[i] + k) % B; DP[i + 1][nex] += DP[i][j] * DP[i][k]; DP[i + 1][nex] %= mod; } } } // Step #5. 繰り返し二乗法により dp[N][i] を求める Answer[0][0] = 1; for (int i = 0; i < 62; i++) { if ((N & (1LL << i)) != 0LL) { for (int j = 0; j < B; j++) { for (int k = 0; k < B; k++) { int nex = (j * power10[i] + k) % B; Answer[i + 1][nex] += Answer[i][j] * DP[i][k]; Answer[i + 1][nex] %= mod; } } } else { for (int j = 0; j < B; j++) Answer[i + 1][j] = Answer[i][j]; } } // Step #6. 出力 cout << Answer[62][0] << endl; return 0; }
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) import sys MOD = 10**9 + 7 def main(): input = sys.stdin.readline N, B, K = map(int, input().split()) *C, = map(int, input().split()) def f(left, right, shift): res = [0] * B for lm in range(B): for rm in range(B): nm = (lm * shift + rm) % B res[nm] = (res[nm] + left[lm] * right[rm]) % MOD return res t = [0] * B # 1桁のとき for c in C: t[c % B] += 1 ans = [0] * B ans[0] = 1 shift = 1 for i in range(N.bit_length()): shift = pow(10, 1 << i, B) if N & (1 << i): ans = f(ans, t, shift) t = f(t, t, shift) print(ans[0]) if __name__ == '__main__': main()
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#include <iostream> using namespace std; long long modpow(long long a, long long b, long long m) { long long p = 1, q = a; for (int i = 0; i < 63; i++) { if ((b & (1LL << i)) != 0) { p *= q; p %= m; } q *= q; q %= m; } return p; } const long long mod = 1000000007; // 入力 long long N, B, K; long long C[11]; // その他の変数 long long power10[64]; long long DP[64][1009]; long long Answer[64][1009]; int main() { // Step #1. 入力 cin >> N >> B >> K; for (int i = 1; i <= K; i++) cin >> C[i]; // Step #2. 前計算 for (int i = 0; i <= 62; i++) { power10[i] = modpow(10LL, (1LL << i), B); } // Step #3. dp[1][i] を求める for (int i = 1; i <= K; i++) { DP[0][C[i] % B] += 1; } // Step #4. dp[1][i], dp[2][i], ..., dp[2^n][i] を求める for (int i = 0; i < 62; i++) { for (int j = 0; j < B; j++) { for (int k = 0; k < B; k++) { int nex = (j * power10[i] + k) % B; DP[i + 1][nex] += DP[i][j] * DP[i][k]; DP[i + 1][nex] %= mod; } } } // Step #5. 繰り返し二乗法により dp[N][i] を求める Answer[0][0] = 1; for (int i = 0; i < 62; i++) { if ((N & (1LL << i)) != 0LL) { for (int j = 0; j < B; j++) { for (int k = 0; k < B; k++) { int nex = (j * power10[i] + k) % B; Answer[i + 1][nex] += Answer[i][j] * DP[i][k]; Answer[i + 1][nex] %= mod; } } } else { for (int j = 0; j < B; j++) Answer[i + 1][j] = Answer[i][j]; } } // Step #6. 出力 cout << Answer[62][0] << endl; return 0; }
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func main() const mod: int :: 1000000007 var n: int :: cui@inputInt() var b: int :: cui@inputInt() var k: int :: cui@inputInt() var dp: []int :: #[b]int for i(0, k - 1) var c: int :: cui@inputInt() do dp[c % b] :+ 1 end for var ans: []int :: #[b]int var pow10: int :: 10 % b do ans[0] :: 1 while(n > 0) if(n % 2 = 1) var ansNext: []int :: #[b]int for i(0, b - 1) for j(0, b - 1) do ansNext[(i * pow10 + j) % b] :+ ans[i] * dp[j] do ansNext[(i * pow10 + j) % b] :% mod end for end for do ans :: ansNext end if block var dpNext: []int :: #[b]int for i(0, b - 1) for j(0, b - 1) do dpNext[(i * pow10 + j) % b] :+ dp[i] * dp[j] do dpNext[(i * pow10 + j) % b] :% mod end for end for do dp :: dpNext end block do pow10 :: (pow10 ^ 2) % b do n :/ 2 end while do cui@print("\{ans[0]}\n") end func
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struct Mint MOD = 1000000007i64 def self.zero new end def self.raw(value : Int64) result = new result.value = value result end @value : Int64 def initialize @value = 0i64 end def initialize(value) @value = value.to_i64 % MOD end def initialize(m : self) @value = m.value end protected def value=(value : Int64) @value = value end getter value : Int64 def + : self self end def - : self Mint.raw(value != 0 ? MOD &- value : 0i64) end def +(v) self + v.to_m end def +(m : self) x = value &+ m.value x &-= MOD if x >= MOD Mint.raw(x) end def -(v) self - v.to_m end def -(m : self) x = value &- m.value x &+= MOD if x < 0 Mint.raw(x) end def *(v) self * v.to_m end def *(m : self) Mint.new(value &* m.value) end def /(v) self / v.to_m end def /(m : self) raise DivisionByZeroError.new if m.value == 0 a, b, u, v = m.to_i64, MOD, 1i64, 0i64 while b != 0 t = a // b a &-= t &* b a, b = b, a u &-= t &* v u, v = v, u end Mint.new(value &* u) end def //(v) self / v end def **(exponent : Int) t, res = self, Mint.raw(1i64) while exponent > 0 res *= t if exponent & 1 == 1 t *= t exponent >>= 1 end res end def ==(m : self) value == m.value end def ==(m : Int) raise NotImplementedError.new("==") end def succ Mint.raw(value != MOD &- 1 ? value &+ 1 : 0i64) end def pred Mint.raw(value != 0 ? value &- 1 : MOD &- 1) end def abs self end def to_i64 : Int64 value end delegate to_s, to: @value delegate inspect, to: @value end struct Int {% for op in %w[+ - * / //] %} def {{op.id}}(value : Mint) to_m {{op.id}} value end {% end %} def to_m : Mint Mint.new(self) end end class String def to_m : Mint Mint.new(self) end end struct Int def powmod(exp : T, mod : self) forall T n = self % mod res = typeof(self).new(1) while exp > 0 res = res * n % mod if exp.odd? n = n * n % mod exp >>= 1 end res end end n, b, k = read_line.split.try { |(n, b, k)| {n.to_i64, b.to_i, k.to_i} } a = read_line.split.map(&.to_i) m = Math.log2(n).ceil.to_i + 1 dp_marge = ->(dp1 : Array(Mint), digit : Int64, dp2 : Array(Mint)) { dp_res = Array.new(b, Mint.zero) pow10 = 10.powmod(digit, b) (0...b).each do |i| (0...b).each do |j| dp_res[(i * pow10 + j) % b] += dp1[i] * dp2[j] end end dp_res } doubling = Array.new(1) { [Mint.zero] * b } a.each { |j| doubling[0][j % b] += 1 } (1..m).each { |i| doubling << dp_marge.call(doubling[-1], 2i64**i.pred, doubling[-1]) } dp = [Mint.zero] * b dp[0] = 1.to_m (0..m).select { |i| n.bit(i) == 1 }.each do |i| dp = dp_marge.call(dp, 2i64**i, doubling[i]) end puts dp[0]
# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) import sys MOD = 10**9 + 7 def main(): input = sys.stdin.readline N, B, K = map(int, input().split()) *C, = map(int, input().split()) def f(left, right, shift): res = [0] * B for lm in range(B): for rm in range(B): nm = (lm * shift + rm) % B res[nm] = (res[nm] + left[lm] * right[rm]) % MOD return res t = [0] * B # 1桁のとき for c in C: t[c % B] += 1 ans = [0] * B ans[0] = 1 shift = 1 for i in range(N.bit_length()): shift = pow(10, 1 << i, B) if N & (1 << i): ans = f(ans, t, shift) t = f(t, t, shift) print(ans[0]) if __name__ == '__main__': main()
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struct Mint MOD = 1000000007i64 def self.zero new end def self.raw(value : Int64) result = new result.value = value result end @value : Int64 def initialize @value = 0i64 end def initialize(value) @value = value.to_i64 % MOD end def initialize(m : self) @value = m.value end protected def value=(value : Int64) @value = value end getter value : Int64 def + : self self end def - : self Mint.raw(value != 0 ? MOD &- value : 0i64) end def +(v) self + v.to_m end def +(m : self) x = value &+ m.value x &-= MOD if x >= MOD Mint.raw(x) end def -(v) self - v.to_m end def -(m : self) x = value &- m.value x &+= MOD if x < 0 Mint.raw(x) end def *(v) self * v.to_m end def *(m : self) Mint.new(value &* m.value) end def /(v) self / v.to_m end def /(m : self) raise DivisionByZeroError.new if m.value == 0 a, b, u, v = m.to_i64, MOD, 1i64, 0i64 while b != 0 t = a // b a &-= t &* b a, b = b, a u &-= t &* v u, v = v, u end Mint.new(value &* u) end def //(v) self / v end def **(exponent : Int) t, res = self, Mint.raw(1i64) while exponent > 0 res *= t if exponent & 1 == 1 t *= t exponent >>= 1 end res end def ==(m : self) value == m.value end def ==(m : Int) raise NotImplementedError.new("==") end def succ Mint.raw(value != MOD &- 1 ? value &+ 1 : 0i64) end def pred Mint.raw(value != 0 ? value &- 1 : MOD &- 1) end def abs self end def to_i64 : Int64 value end delegate to_s, to: @value delegate inspect, to: @value end struct Int {% for op in %w[+ - * / //] %} def {{op.id}}(value : Mint) to_m {{op.id}} value end {% end %} def to_m : Mint Mint.new(self) end end class String def to_m : Mint Mint.new(self) end end struct Int def powmod(exp : T, mod : self) forall T n = self % mod res = typeof(self).new(1) while exp > 0 res = res * n % mod if exp.odd? n = n * n % mod exp >>= 1 end res end end n, b, k = read_line.split.try { |(n, b, k)| {n.to_i64, b.to_i, k.to_i} } a = read_line.split.map(&.to_i) m = Math.log2(n).ceil.to_i + 1 dp_marge = ->(dp1 : Array(Mint), digit : Int64, dp2 : Array(Mint)) { dp_res = Array.new(b, Mint.zero) pow10 = 10.powmod(digit, b) (0...b).each do |i| (0...b).each do |j| dp_res[(i * pow10 + j) % b] += dp1[i] * dp2[j] end end dp_res } doubling = Array.new(1) { [Mint.zero] * b } a.each { |j| doubling[0][j % b] += 1 } (1..m).each { |i| doubling << dp_marge.call(doubling[-1], 2i64**i.pred, doubling[-1]) } dp = [Mint.zero] * b dp[0] = 1.to_m (0..m).select { |i| n.bit(i) == 1 }.each do |i| dp = dp_marge.call(dp, 2i64**i, doubling[i]) end puts dp[0]
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func main() const mod: int :: 1000000007 var n: int :: cui@inputInt() var b: int :: cui@inputInt() var k: int :: cui@inputInt() var dp: []int :: #[b]int for i(0, k - 1) var c: int :: cui@inputInt() do dp[c % b] :+ 1 end for var ans: []int :: #[b]int var pow10: int :: 10 % b do ans[0] :: 1 while(n > 0) if(n % 2 = 1) var ansNext: []int :: #[b]int for i(0, b - 1) for j(0, b - 1) do ansNext[(i * pow10 + j) % b] :+ ans[i] * dp[j] do ansNext[(i * pow10 + j) % b] :% mod end for end for do ans :: ansNext end if block var dpNext: []int :: #[b]int for i(0, b - 1) for j(0, b - 1) do dpNext[(i * pow10 + j) % b] :+ dp[i] * dp[j] do dpNext[(i * pow10 + j) % b] :% mod end for end for do dp :: dpNext end block do pow10 :: (pow10 ^ 2) % b do n :/ 2 end while do cui@print("\{ans[0]}\n") end func
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) import sys MOD = 10**9 + 7 def main(): input = sys.stdin.readline N, B, K = map(int, input().split()) *C, = map(int, input().split()) def f(left, right, shift): res = [0] * B for lm in range(B): for rm in range(B): nm = (lm * shift + rm) % B res[nm] = (res[nm] + left[lm] * right[rm]) % MOD return res t = [0] * B # 1桁のとき for c in C: t[c % B] += 1 ans = [0] * B ans[0] = 1 shift = 1 for i in range(N.bit_length()): shift = pow(10, 1 << i, B) if N & (1 << i): ans = f(ans, t, shift) t = f(t, t, shift) print(ans[0]) if __name__ == '__main__': main()
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func main() const mod: int :: 1000000007 var n: int :: cui@inputInt() var b: int :: cui@inputInt() var k: int :: cui@inputInt() var dp: []int :: #[b]int for i(0, k - 1) var c: int :: cui@inputInt() do dp[c % b] :+ 1 end for var ans: []int :: #[b]int var pow10: int :: 10 % b do ans[0] :: 1 while(n > 0) if(n % 2 = 1) var ansNext: []int :: #[b]int for i(0, b - 1) for j(0, b - 1) do ansNext[(i * pow10 + j) % b] :+ ans[i] * dp[j] do ansNext[(i * pow10 + j) % b] :% mod end for end for do ans :: ansNext end if block var dpNext: []int :: #[b]int for i(0, b - 1) for j(0, b - 1) do dpNext[(i * pow10 + j) % b] :+ dp[i] * dp[j] do dpNext[(i * pow10 + j) % b] :% mod end for end for do dp :: dpNext end block do pow10 :: (pow10 ^ 2) % b do n :/ 2 end while do cui@print("\{ans[0]}\n") end func
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/* 競プロ典型90問 第6問 s https://atcoder.jp/contests/typical90/submissions/23191468 */ #include <iostream> #include <algorithm> #include <vector> #include <queue> using namespace std; typedef long long ll; typedef pair<char, int> P; int N, K; string s; int main() { cin >> N >> K; cin >> s; priority_queue<P, vector<P>, greater<P>> pq; //前からN - K + 1個をまず入れる。 for (int i = 0; i < N - K + 1; i++) pq.push(make_pair(s[i], i)); string ans = ""; int topIdx = -1; for (int i = 0; i < K; i++) { P top; while (true) { top = pq.top(); pq.pop(); if (top.second > topIdx) break; } ans += top.first; topIdx = top.second; pq.push(make_pair(s[N - K + 1 + i], N - K + 1 + i)); } cout << ans << endl; return 0; }
n, k = read_line.split.map(&.to_i) s = read_line next_index = ('a'..'z').map { |c| prev_index = n (0...n).reverse_each.map { |i| if s[i] == c prev_index = i else prev_index end }.to_a.reverse } index = 0 puts (1..k).join { |size| ('a'..'z').find { |char| next_index[char - 'a'][index] <= n - (k - size + 1) }.not_nil!.tap { |char| index = next_index[char - 'a'][index] + 1 } }
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n, k = read_line.split.map(&.to_i) s = read_line next_index = ('a'..'z').map { |c| prev_index = n (0...n).reverse_each.map { |i| if s[i] == c prev_index = i else prev_index end }.to_a.reverse } index = 0 puts (1..k).join { |size| ('a'..'z').find { |char| next_index[char - 'a'][index] <= n - (k - size + 1) }.not_nil!.tap { |char| index = next_index[char - 'a'][index] + 1 } }
# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) def main(): N, K = map(int, input().split()) S = input() a = ord('a') st = SegmentTree( f=min, identity_factory=lambda: ( 27, len(S)), initial_values=[ (ord(s) - a, i) for i, s in enumerate(S)]) ans = [] l = 0 r = len(S) - K for _ in range(K): mn = st.query(l, r + 1) ans.append(mn[0]) l = mn[1] + 1 r += 1 print(''.join(map(lambda x: chr(x + a), ans))) class SegmentTree: __slots__ = ('__n', '__d', '__f', '__e') def __init__(self, n=None, f=max, identity_factory=int, initial_values=None): assert(n or initial_values) size = n if n else len(initial_values) d = [identity_factory() for _ in range(2 * size + 1)] self.__n, self.__d, self.__f, self.__e = size, d, f, identity_factory if initial_values: for i, v in enumerate(initial_values): d[size + i] = v for i in range(size - 1, 0, -1): d[i] = f(d[i << 1], d[i << 1 | 1]) def get_at(self, index): return self.__d[index + self.__n] def set_at(self, index, new_value): i, d, f = index + self.__n, self.__d, self.__f if d[i] == new_value: return d[i], i = new_value, i >> 1 while i: d[i], i = f(d[i << 1], d[i << 1 | 1]), i >> 1 def modify_at(self, index, value): self.set_at(index, self.__f(self.__d[index + self.__n], value)) def query(self, from_inclusive, to_exclusive): ans = self.__e() if to_exclusive <= from_inclusive: return ans l, r, d, f = from_inclusive + self.__n, to_exclusive + self.__n, self.__d, self.__f while l < r: if l & 1: ans, l = f(ans, d[l]), l + 1 if r & 1: ans, r = f(d[r - 1], ans), r - 1 l, r = l >> 1, r >> 1 return ans def query_all(self): return self.__d[1] def bisect_left(self, func, from_inclusive=None, to_exclusive=None): '''func()がTrueになるもっとも左のindexを探す ''' n, f, d, v = self.__n, self.__f, self.__d, self.__e() l = (from_inclusive if from_inclusive else 0) + n r = (to_exclusive if to_exclusive else n) + n h = 0 while l < r: if l & 1: nv = f(v, d[l]) if func(nv): return self.__single_bisect_left(func, l, v) v, l = nv, l + 1 l, r, h = l >> 1, r >> 1, h + 1 if r == 0: return n for i in range(h, 0, -1): if ((r + 1) << i <= n + n): nv = f(v, d[r]) if func(nv): return self.__single_bisect_left(func, r, v) v, r = nv, r + 1 r <<= 1 return n def __single_bisect_left(self, func, root, left_val): n, f, d = self.__n, self.__f, self.__d i, v = root, left_val while i < n: i <<= 1 nv = f(v, d[i]) if not func(nv): i, v = i + 1, nv return i - n if __name__ == '__main__': main()
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n, k = read_line.split.map(&.to_i) s = read_line next_index = ('a'..'z').map { |c| prev_index = n (0...n).reverse_each.map { |i| if s[i] == c prev_index = i else prev_index end }.to_a.reverse } index = 0 puts (1..k).join { |size| ('a'..'z').find { |char| next_index[char - 'a'][index] <= n - (k - size + 1) }.not_nil!.tap { |char| index = next_index[char - 'a'][index] + 1 } }
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func main() var n: int :: cui@inputInt() var k: int :: cui@inputInt() var s: []char :: cui@input() var nextPos: [][]int :: #[n, 26]int var pos: []int :: [n].repeat(26) for i(n - 1, 0, -1) do pos[s[i] $ int - 'a' $ int] :: i for j(0, 25) do nextPos[i][j] :: pos[j] end for end for var p: int :: 0 var ans: []char :: #[k]char for i(0, k - 1) for j(0, 25) var remains: int :: n - 1 - nextPos[p][j] if(remains >= k - 1 - i) do ans[i] :: 'a'.offset(j) do p :: nextPos[p][j] + 1 break j end if end for end for do cui@print("\{ans}\n") end func
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/* 競プロ典型90問 第6問 s https://atcoder.jp/contests/typical90/submissions/23191468 */ #include <iostream> #include <algorithm> #include <vector> #include <queue> using namespace std; typedef long long ll; typedef pair<char, int> P; int N, K; string s; int main() { cin >> N >> K; cin >> s; priority_queue<P, vector<P>, greater<P>> pq; //前からN - K + 1個をまず入れる。 for (int i = 0; i < N - K + 1; i++) pq.push(make_pair(s[i], i)); string ans = ""; int topIdx = -1; for (int i = 0; i < K; i++) { P top; while (true) { top = pq.top(); pq.pop(); if (top.second > topIdx) break; } ans += top.first; topIdx = top.second; pq.push(make_pair(s[N - K + 1 + i], N - K + 1 + i)); } cout << ans << endl; return 0; }
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) def main(): N, K = map(int, input().split()) S = input() a = ord('a') st = SegmentTree( f=min, identity_factory=lambda: ( 27, len(S)), initial_values=[ (ord(s) - a, i) for i, s in enumerate(S)]) ans = [] l = 0 r = len(S) - K for _ in range(K): mn = st.query(l, r + 1) ans.append(mn[0]) l = mn[1] + 1 r += 1 print(''.join(map(lambda x: chr(x + a), ans))) class SegmentTree: __slots__ = ('__n', '__d', '__f', '__e') def __init__(self, n=None, f=max, identity_factory=int, initial_values=None): assert(n or initial_values) size = n if n else len(initial_values) d = [identity_factory() for _ in range(2 * size + 1)] self.__n, self.__d, self.__f, self.__e = size, d, f, identity_factory if initial_values: for i, v in enumerate(initial_values): d[size + i] = v for i in range(size - 1, 0, -1): d[i] = f(d[i << 1], d[i << 1 | 1]) def get_at(self, index): return self.__d[index + self.__n] def set_at(self, index, new_value): i, d, f = index + self.__n, self.__d, self.__f if d[i] == new_value: return d[i], i = new_value, i >> 1 while i: d[i], i = f(d[i << 1], d[i << 1 | 1]), i >> 1 def modify_at(self, index, value): self.set_at(index, self.__f(self.__d[index + self.__n], value)) def query(self, from_inclusive, to_exclusive): ans = self.__e() if to_exclusive <= from_inclusive: return ans l, r, d, f = from_inclusive + self.__n, to_exclusive + self.__n, self.__d, self.__f while l < r: if l & 1: ans, l = f(ans, d[l]), l + 1 if r & 1: ans, r = f(d[r - 1], ans), r - 1 l, r = l >> 1, r >> 1 return ans def query_all(self): return self.__d[1] def bisect_left(self, func, from_inclusive=None, to_exclusive=None): '''func()がTrueになるもっとも左のindexを探す ''' n, f, d, v = self.__n, self.__f, self.__d, self.__e() l = (from_inclusive if from_inclusive else 0) + n r = (to_exclusive if to_exclusive else n) + n h = 0 while l < r: if l & 1: nv = f(v, d[l]) if func(nv): return self.__single_bisect_left(func, l, v) v, l = nv, l + 1 l, r, h = l >> 1, r >> 1, h + 1 if r == 0: return n for i in range(h, 0, -1): if ((r + 1) << i <= n + n): nv = f(v, d[r]) if func(nv): return self.__single_bisect_left(func, r, v) v, r = nv, r + 1 r <<= 1 return n def __single_bisect_left(self, func, root, left_val): n, f, d = self.__n, self.__f, self.__d i, v = root, left_val while i < n: i <<= 1 nv = f(v, d[i]) if not func(nv): i, v = i + 1, nv return i - n if __name__ == '__main__': main()
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/* 競プロ典型90問 第6問 s https://atcoder.jp/contests/typical90/submissions/23191468 */ #include <iostream> #include <algorithm> #include <vector> #include <queue> using namespace std; typedef long long ll; typedef pair<char, int> P; int N, K; string s; int main() { cin >> N >> K; cin >> s; priority_queue<P, vector<P>, greater<P>> pq; //前からN - K + 1個をまず入れる。 for (int i = 0; i < N - K + 1; i++) pq.push(make_pair(s[i], i)); string ans = ""; int topIdx = -1; for (int i = 0; i < K; i++) { P top; while (true) { top = pq.top(); pq.pop(); if (top.second > topIdx) break; } ans += top.first; topIdx = top.second; pq.push(make_pair(s[N - K + 1 + i], N - K + 1 + i)); } cout << ans << endl; return 0; }
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func main() var n: int :: cui@inputInt() var k: int :: cui@inputInt() var s: []char :: cui@input() var nextPos: [][]int :: #[n, 26]int var pos: []int :: [n].repeat(26) for i(n - 1, 0, -1) do pos[s[i] $ int - 'a' $ int] :: i for j(0, 25) do nextPos[i][j] :: pos[j] end for end for var p: int :: 0 var ans: []char :: #[k]char for i(0, k - 1) for j(0, 25) var remains: int :: n - 1 - nextPos[p][j] if(remains >= k - 1 - i) do ans[i] :: 'a'.offset(j) do p :: nextPos[p][j] + 1 break j end if end for end for do cui@print("\{ans}\n") end func
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) def main(): N, K = map(int, input().split()) S = input() a = ord('a') st = SegmentTree( f=min, identity_factory=lambda: ( 27, len(S)), initial_values=[ (ord(s) - a, i) for i, s in enumerate(S)]) ans = [] l = 0 r = len(S) - K for _ in range(K): mn = st.query(l, r + 1) ans.append(mn[0]) l = mn[1] + 1 r += 1 print(''.join(map(lambda x: chr(x + a), ans))) class SegmentTree: __slots__ = ('__n', '__d', '__f', '__e') def __init__(self, n=None, f=max, identity_factory=int, initial_values=None): assert(n or initial_values) size = n if n else len(initial_values) d = [identity_factory() for _ in range(2 * size + 1)] self.__n, self.__d, self.__f, self.__e = size, d, f, identity_factory if initial_values: for i, v in enumerate(initial_values): d[size + i] = v for i in range(size - 1, 0, -1): d[i] = f(d[i << 1], d[i << 1 | 1]) def get_at(self, index): return self.__d[index + self.__n] def set_at(self, index, new_value): i, d, f = index + self.__n, self.__d, self.__f if d[i] == new_value: return d[i], i = new_value, i >> 1 while i: d[i], i = f(d[i << 1], d[i << 1 | 1]), i >> 1 def modify_at(self, index, value): self.set_at(index, self.__f(self.__d[index + self.__n], value)) def query(self, from_inclusive, to_exclusive): ans = self.__e() if to_exclusive <= from_inclusive: return ans l, r, d, f = from_inclusive + self.__n, to_exclusive + self.__n, self.__d, self.__f while l < r: if l & 1: ans, l = f(ans, d[l]), l + 1 if r & 1: ans, r = f(d[r - 1], ans), r - 1 l, r = l >> 1, r >> 1 return ans def query_all(self): return self.__d[1] def bisect_left(self, func, from_inclusive=None, to_exclusive=None): '''func()がTrueになるもっとも左のindexを探す ''' n, f, d, v = self.__n, self.__f, self.__d, self.__e() l = (from_inclusive if from_inclusive else 0) + n r = (to_exclusive if to_exclusive else n) + n h = 0 while l < r: if l & 1: nv = f(v, d[l]) if func(nv): return self.__single_bisect_left(func, l, v) v, l = nv, l + 1 l, r, h = l >> 1, r >> 1, h + 1 if r == 0: return n for i in range(h, 0, -1): if ((r + 1) << i <= n + n): nv = f(v, d[r]) if func(nv): return self.__single_bisect_left(func, r, v) v, r = nv, r + 1 r <<= 1 return n def __single_bisect_left(self, func, root, left_val): n, f, d = self.__n, self.__f, self.__d i, v = root, left_val while i < n: i <<= 1 nv = f(v, d[i]) if not func(nv): i, v = i + 1, nv return i - n if __name__ == '__main__': main()
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func main() var n: int :: cui@inputInt() var k: int :: cui@inputInt() var s: []char :: cui@input() var nextPos: [][]int :: #[n, 26]int var pos: []int :: [n].repeat(26) for i(n - 1, 0, -1) do pos[s[i] $ int - 'a' $ int] :: i for j(0, 25) do nextPos[i][j] :: pos[j] end for end for var p: int :: 0 var ans: []char :: #[k]char for i(0, k - 1) for j(0, 25) var remains: int :: n - 1 - nextPos[p][j] if(remains >= k - 1 - i) do ans[i] :: 'a'.offset(j) do p :: nextPos[p][j] + 1 break j end if end for end for do cui@print("\{ans}\n") end func
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#include <iostream> #include <algorithm> #include <cmath> using namespace std; const int INF = 2000000000; int N; int A[300009]; int Q; int B[300009]; int main() { // Step #1. Input cin >> N; for (int i = 1; i <= N; i++) cin >> A[i]; cin >> Q; for (int i = 1; i <= Q; i++) cin >> B[i]; // Step #2. Sorting sort(A + 1, A + N + 1); // Step #3. Binary Search for (int i = 1; i <= Q; i++) { int pos1 = lower_bound(A + 1, A + N + 1, B[i]) - A; int Diff1 = INF, Diff2 = INF; if (pos1 <= N) Diff1 = abs(B[i] - A[pos1]); if (pos1 >= 2) Diff2 = abs(B[i] - A[pos1 - 1]); cout << min(Diff1, Diff2) << endl; } return 0; }
read_line a = [-2*10**9] + read_line.split.map(&.to_i).sort + [2*10**9] read_line.to_i.times do b = read_line.to_i i = a.bsearch_index { |x| x > b }.not_nil! puts a[i - 1..i + 1].min_of { |x| (b - x).abs } end
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#include <iostream> #include <algorithm> #include <cmath> using namespace std; const int INF = 2000000000; int N; int A[300009]; int Q; int B[300009]; int main() { // Step #1. Input cin >> N; for (int i = 1; i <= N; i++) cin >> A[i]; cin >> Q; for (int i = 1; i <= Q; i++) cin >> B[i]; // Step #2. Sorting sort(A + 1, A + N + 1); // Step #3. Binary Search for (int i = 1; i <= Q; i++) { int pos1 = lower_bound(A + 1, A + N + 1, B[i]) - A; int Diff1 = INF, Diff2 = INF; if (pos1 <= N) Diff1 = abs(B[i] - A[pos1]); if (pos1 >= 2) Diff2 = abs(B[i] - A[pos1 - 1]); cout << min(Diff1, Diff2) << endl; } return 0; }
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) from bisect import bisect_left N = int(input()) *A, = map(int, input().split()) Q = int(input()) A.sort() for _ in range(Q): b = int(input()) i = bisect_left(A, b) u = 10**18 if i < N: u = min(u, abs(A[i] - b)) if i > 0: u = min(u, abs(A[i - 1] - b)) print(u)
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#include <iostream> #include <algorithm> #include <cmath> using namespace std; const int INF = 2000000000; int N; int A[300009]; int Q; int B[300009]; int main() { // Step #1. Input cin >> N; for (int i = 1; i <= N; i++) cin >> A[i]; cin >> Q; for (int i = 1; i <= Q; i++) cin >> B[i]; // Step #2. Sorting sort(A + 1, A + N + 1); // Step #3. Binary Search for (int i = 1; i <= Q; i++) { int pos1 = lower_bound(A + 1, A + N + 1, B[i]) - A; int Diff1 = INF, Diff2 = INF; if (pos1 <= N) Diff1 = abs(B[i] - A[pos1]); if (pos1 >= 2) Diff2 = abs(B[i] - A[pos1 - 1]); cout << min(Diff1, Diff2) << endl; } return 0; }
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func main() var n: int :: cui@inputInt() var a: []int :: #[n]int for i(0, n - 1) do a[i] :: cui@inputInt() end for do a.sort() var q: int :: cui@inputInt() for(1, q) var b: int :: cui@inputInt() var ok: int :: 0 var ng: int :: n while((ok - ng).abs() > 1) var mid: int :: (ok + ng) / 2 if(a[mid] <= b) do ok :: mid else do ng :: mid end if end while var ans: int :: (b - a[ok]).abs() if(ok <> n - 1) do ans :: [ans, a[ok + 1] - b].min() end if do cui@print("\{ans}\n") end for end func
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read_line a = [-2*10**9] + read_line.split.map(&.to_i).sort + [2*10**9] read_line.to_i.times do b = read_line.to_i i = a.bsearch_index { |x| x > b }.not_nil! puts a[i - 1..i + 1].min_of { |x| (b - x).abs } end
# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) from bisect import bisect_left N = int(input()) *A, = map(int, input().split()) Q = int(input()) A.sort() for _ in range(Q): b = int(input()) i = bisect_left(A, b) u = 10**18 if i < N: u = min(u, abs(A[i] - b)) if i > 0: u = min(u, abs(A[i - 1] - b)) print(u)
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read_line a = [-2*10**9] + read_line.split.map(&.to_i).sort + [2*10**9] read_line.to_i.times do b = read_line.to_i i = a.bsearch_index { |x| x > b }.not_nil! puts a[i - 1..i + 1].min_of { |x| (b - x).abs } end
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func main() var n: int :: cui@inputInt() var a: []int :: #[n]int for i(0, n - 1) do a[i] :: cui@inputInt() end for do a.sort() var q: int :: cui@inputInt() for(1, q) var b: int :: cui@inputInt() var ok: int :: 0 var ng: int :: n while((ok - ng).abs() > 1) var mid: int :: (ok + ng) / 2 if(a[mid] <= b) do ok :: mid else do ng :: mid end if end while var ans: int :: (b - a[ok]).abs() if(ok <> n - 1) do ans :: [ans, a[ok + 1] - b].min() end if do cui@print("\{ans}\n") end for end func
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) from bisect import bisect_left N = int(input()) *A, = map(int, input().split()) Q = int(input()) A.sort() for _ in range(Q): b = int(input()) i = bisect_left(A, b) u = 10**18 if i < N: u = min(u, abs(A[i] - b)) if i > 0: u = min(u, abs(A[i - 1] - b)) print(u)
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func main() var n: int :: cui@inputInt() var a: []int :: #[n]int for i(0, n - 1) do a[i] :: cui@inputInt() end for do a.sort() var q: int :: cui@inputInt() for(1, q) var b: int :: cui@inputInt() var ok: int :: 0 var ng: int :: n while((ok - ng).abs() > 1) var mid: int :: (ok + ng) / 2 if(a[mid] <= b) do ok :: mid else do ng :: mid end if end while var ans: int :: (b - a[ok]).abs() if(ok <> n - 1) do ans :: [ans, a[ok + 1] - b].min() end if do cui@print("\{ans}\n") end for end func
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#include <iostream> #include <string> #include <vector> #define mod 1000000007 using namespace std; //19[ms] string t = "atcoder"; int main(){ int n; string s; cin >> n >> s; vector<vector<int>> dp(8, vector<int>(n + 1)); for(int i = 0; i <= n; i++) dp[0][i] = 1; for(int i = 0; i < 7; i++){ for(int j = 0; j < n; j++){ if(t[i] == s[j]){ dp[i + 1][j + 1] += dp[i][j]; dp[i + 1][j + 1] %= mod; } dp[i + 1][j + 1] += dp[i + 1][j]; dp[i + 1][j + 1] %= mod; } } cout << dp[7][n] << "\n"; }
read_line s = read_line atcoder = "?atcoder" m = atcoder.size puts s.chars.each_with_object([1] + [0] * m.pred) { |c, dp| if i = atcoder.index(c) dp[i] = (dp[i] + dp[i - 1]) % (10**9 + 7) end }.last
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#include <iostream> #include <string> #include <vector> #define mod 1000000007 using namespace std; //19[ms] string t = "atcoder"; int main(){ int n; string s; cin >> n >> s; vector<vector<int>> dp(8, vector<int>(n + 1)); for(int i = 0; i <= n; i++) dp[0][i] = 1; for(int i = 0; i < 7; i++){ for(int j = 0; j < n; j++){ if(t[i] == s[j]){ dp[i + 1][j + 1] += dp[i][j]; dp[i + 1][j + 1] %= mod; } dp[i + 1][j + 1] += dp[i + 1][j]; dp[i + 1][j + 1] %= mod; } } cout << dp[7][n] << "\n"; }
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) from collections import defaultdict MOD = 10**9 + 7 N = int(input()) S = input() C = defaultdict(int) ATCODER = 'atcoder' dp = [0] * len(ATCODER) for s in S[::-1]: if s in ATCODER: i = ATCODER.index(s) if i == len(ATCODER) - 1: dp[i] += 1 else: dp[i] = (dp[i] + dp[i + 1]) % MOD print(dp[0])
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#include <iostream> #include <string> #include <vector> #define mod 1000000007 using namespace std; //19[ms] string t = "atcoder"; int main(){ int n; string s; cin >> n >> s; vector<vector<int>> dp(8, vector<int>(n + 1)); for(int i = 0; i <= n; i++) dp[0][i] = 1; for(int i = 0; i < 7; i++){ for(int j = 0; j < n; j++){ if(t[i] == s[j]){ dp[i + 1][j + 1] += dp[i][j]; dp[i + 1][j + 1] %= mod; } dp[i + 1][j + 1] += dp[i + 1][j]; dp[i + 1][j + 1] %= mod; } } cout << dp[7][n] << "\n"; }
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func main() var n: int :: cui@inputInt() var s: []char :: cui@input() var atcoder: []char :: "atcoder" var dp: []int :: #[^atcoder + 1]int do dp[0] :: 1 for i(0, n - 1) for j(0, ^atcoder - 1) if(s[i] = atcoder[j]) do dp[j + 1] :+ dp[j] do dp[j + 1] :% 10 ^ 9 + 7 end if end for end for var ans: int :: dp[^atcoder] do cui@print("\{ans}\n") end func
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read_line s = read_line atcoder = "?atcoder" m = atcoder.size puts s.chars.each_with_object([1] + [0] * m.pred) { |c, dp| if i = atcoder.index(c) dp[i] = (dp[i] + dp[i - 1]) % (10**9 + 7) end }.last
# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) from collections import defaultdict MOD = 10**9 + 7 N = int(input()) S = input() C = defaultdict(int) ATCODER = 'atcoder' dp = [0] * len(ATCODER) for s in S[::-1]: if s in ATCODER: i = ATCODER.index(s) if i == len(ATCODER) - 1: dp[i] += 1 else: dp[i] = (dp[i] + dp[i + 1]) % MOD print(dp[0])
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read_line s = read_line atcoder = "?atcoder" m = atcoder.size puts s.chars.each_with_object([1] + [0] * m.pred) { |c, dp| if i = atcoder.index(c) dp[i] = (dp[i] + dp[i - 1]) % (10**9 + 7) end }.last
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func main() var n: int :: cui@inputInt() var s: []char :: cui@input() var atcoder: []char :: "atcoder" var dp: []int :: #[^atcoder + 1]int do dp[0] :: 1 for i(0, n - 1) for j(0, ^atcoder - 1) if(s[i] = atcoder[j]) do dp[j + 1] :+ dp[j] do dp[j + 1] :% 10 ^ 9 + 7 end if end for end for var ans: int :: dp[^atcoder] do cui@print("\{ans}\n") end func
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) from collections import defaultdict MOD = 10**9 + 7 N = int(input()) S = input() C = defaultdict(int) ATCODER = 'atcoder' dp = [0] * len(ATCODER) for s in S[::-1]: if s in ATCODER: i = ATCODER.index(s) if i == len(ATCODER) - 1: dp[i] += 1 else: dp[i] = (dp[i] + dp[i + 1]) % MOD print(dp[0])
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func main() var n: int :: cui@inputInt() var s: []char :: cui@input() var atcoder: []char :: "atcoder" var dp: []int :: #[^atcoder + 1]int do dp[0] :: 1 for i(0, n - 1) for j(0, ^atcoder - 1) if(s[i] = atcoder[j]) do dp[j + 1] :+ dp[j] do dp[j + 1] :% 10 ^ 9 + 7 end if end for end for var ans: int :: dp[^atcoder] do cui@print("\{ans}\n") end func
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#include <iostream> #include <cmath> #include <vector> #include <algorithm> using namespace std; struct Point { double px, py; }; Point operator-(const Point& a1, const Point& a2) { return Point{ a1.px - a2.px, a1.py - a2.py }; } double getangle(Point G) { // 点 G の偏角を求める if (G.py >= 0.0) { double I = G.px / sqrt(G.px * G.px + G.py * G.py); double kaku = acos(I) * 180.0 / 3.14159265358979; return kaku; } else { double I = G.px / sqrt(G.px * G.px + G.py * G.py); double kaku = acos(I) * 180.0 / 3.14159265358979; return 360.0 - kaku; } } double getangle2(double I1, double I2) { // [偏角 I1] - [原点] - [偏角 I2] のなす角度を求める // 例えば I1 = 240°、I2 = 30°のとき、求める角度は 150° double res = abs(I1 - I2); if (res >= 180.0) return 360.0 - res; return res; } int N; Point G[2009]; double solve(int pos) { // 最初に偏角の昇順にソートする vector<double> vec; for (int i = 1; i <= N; i++) { if (i == pos) continue; Point SA = G[i] - G[pos]; double angle = getangle(SA); vec.push_back(angle); } sort(vec.begin(), vec.end()); // 点 A を全探索して、最も偏角の大きくなる点 C を二分探索(std::lower_bound)で求める double ret = 0.0; for (int i = 0; i < vec.size(); i++) { double target = vec[i] + 180.0; if (target >= 360.0) target -= 360.0; int pos1 = lower_bound(vec.begin(), vec.end(), target) - vec.begin(); // 点 C の候補は高々 2 つに絞れる int CandIdx1 = pos1 % vec.size(); int CandIdx2 = (pos1 + vec.size() - 1) % vec.size(); double Candidate1 = getangle2(vec[i], vec[CandIdx1]); double Candidate2 = getangle2(vec[i], vec[CandIdx2]); ret = max({ ret, Candidate1, Candidate2 }); } return ret; } // O(N^3) のアルゴリズム(点 A, B, C を全探索) double solve_Slow() { double Answer = 0.0; for (int i = 1; i <= N; i++) { for (int j = 1; j <= N; j++) { for (int k = 1; k <= N; k++) { if (i == j || i == k || j == k) continue; double I1 = getangle(G[i] - G[j]); double I2 = getangle(G[k] - G[j]); Answer = max(Answer, getangle2(I1, I2)); } } } return Answer; } // O(N^2 log N) のアルゴリズム double solve_Fast() { // 点 B を全探索 double Answer = 0.0; for (int i = 1; i <= N; i++) { double ret = solve(i); Answer = max(Answer, ret); } return Answer; } int main() { // Step #1. 入力 cin >> N; for (int i = 1; i <= N; i++) { cin >> G[i].px >> G[i].py; } // Step #2. 出力 double FinalAns = solve_Fast(); printf("%.12lf\n", FinalAns); return 0; }
# 0.36.0 以降は Math::TAU があります TAU = Math::PI * 2 n = read_line.to_i xy = (1..n).map { {Int32, Int32}.from read_line.split.map(&.to_i) } puts (0...n).max_of { |i| angle = (0...n).select { |j| i != j }.map { |j| Math.atan2(xy[j][1] - xy[i][1], xy[j][0] - xy[i][0]) } angles = angle.flat_map { |a| [a, a + Math::PI * 2] }.sort angle.max_of { |a| index = angles.bsearch_index { |b| b >= a + Math::PI }.not_nil! {angles[index - 1], angles[index]}.max_of { |b| res = (b - a) % TAU res > Math::PI ? Math::PI - res : res } } } * 360 / TAU
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#include <iostream> #include <cmath> #include <vector> #include <algorithm> using namespace std; struct Point { double px, py; }; Point operator-(const Point& a1, const Point& a2) { return Point{ a1.px - a2.px, a1.py - a2.py }; } double getangle(Point G) { // 点 G の偏角を求める if (G.py >= 0.0) { double I = G.px / sqrt(G.px * G.px + G.py * G.py); double kaku = acos(I) * 180.0 / 3.14159265358979; return kaku; } else { double I = G.px / sqrt(G.px * G.px + G.py * G.py); double kaku = acos(I) * 180.0 / 3.14159265358979; return 360.0 - kaku; } } double getangle2(double I1, double I2) { // [偏角 I1] - [原点] - [偏角 I2] のなす角度を求める // 例えば I1 = 240°、I2 = 30°のとき、求める角度は 150° double res = abs(I1 - I2); if (res >= 180.0) return 360.0 - res; return res; } int N; Point G[2009]; double solve(int pos) { // 最初に偏角の昇順にソートする vector<double> vec; for (int i = 1; i <= N; i++) { if (i == pos) continue; Point SA = G[i] - G[pos]; double angle = getangle(SA); vec.push_back(angle); } sort(vec.begin(), vec.end()); // 点 A を全探索して、最も偏角の大きくなる点 C を二分探索(std::lower_bound)で求める double ret = 0.0; for (int i = 0; i < vec.size(); i++) { double target = vec[i] + 180.0; if (target >= 360.0) target -= 360.0; int pos1 = lower_bound(vec.begin(), vec.end(), target) - vec.begin(); // 点 C の候補は高々 2 つに絞れる int CandIdx1 = pos1 % vec.size(); int CandIdx2 = (pos1 + vec.size() - 1) % vec.size(); double Candidate1 = getangle2(vec[i], vec[CandIdx1]); double Candidate2 = getangle2(vec[i], vec[CandIdx2]); ret = max({ ret, Candidate1, Candidate2 }); } return ret; } // O(N^3) のアルゴリズム(点 A, B, C を全探索) double solve_Slow() { double Answer = 0.0; for (int i = 1; i <= N; i++) { for (int j = 1; j <= N; j++) { for (int k = 1; k <= N; k++) { if (i == j || i == k || j == k) continue; double I1 = getangle(G[i] - G[j]); double I2 = getangle(G[k] - G[j]); Answer = max(Answer, getangle2(I1, I2)); } } } return Answer; } // O(N^2 log N) のアルゴリズム double solve_Fast() { // 点 B を全探索 double Answer = 0.0; for (int i = 1; i <= N; i++) { double ret = solve(i); Answer = max(Answer, ret); } return Answer; } int main() { // Step #1. 入力 cin >> N; for (int i = 1; i <= N; i++) { cin >> G[i].px >> G[i].py; } // Step #2. 出力 double FinalAns = solve_Fast(); printf("%.12lf\n", FinalAns); return 0; }
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) from bisect import bisect_left from cmath import phase, pi from typing import List C = 2 * pi N = int(input()) P: List[complex] = [] for _ in range(N): x, y = map(int, input().split()) P.append(x + y * 1j) ans = 0 for i in range(N): A = sorted((phase(P[j] - P[i]) + pi) * 360 / C for j in range(N) if i != j) now = 0 for Aj in A: k = bisect_left(A, Aj + 180) r = A[k % len(A)] - Aj if r < 0: r += 360 if r > 180: r = 360 - r l = A[k % len(A) - 1] - Aj if l < 0: l += 360 if l > 180: l = 360 - l now = max(now, l, r) ans = max(ans, now) print(ans)
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#include <iostream> #include <cmath> #include <vector> #include <algorithm> using namespace std; struct Point { double px, py; }; Point operator-(const Point& a1, const Point& a2) { return Point{ a1.px - a2.px, a1.py - a2.py }; } double getangle(Point G) { // 点 G の偏角を求める if (G.py >= 0.0) { double I = G.px / sqrt(G.px * G.px + G.py * G.py); double kaku = acos(I) * 180.0 / 3.14159265358979; return kaku; } else { double I = G.px / sqrt(G.px * G.px + G.py * G.py); double kaku = acos(I) * 180.0 / 3.14159265358979; return 360.0 - kaku; } } double getangle2(double I1, double I2) { // [偏角 I1] - [原点] - [偏角 I2] のなす角度を求める // 例えば I1 = 240°、I2 = 30°のとき、求める角度は 150° double res = abs(I1 - I2); if (res >= 180.0) return 360.0 - res; return res; } int N; Point G[2009]; double solve(int pos) { // 最初に偏角の昇順にソートする vector<double> vec; for (int i = 1; i <= N; i++) { if (i == pos) continue; Point SA = G[i] - G[pos]; double angle = getangle(SA); vec.push_back(angle); } sort(vec.begin(), vec.end()); // 点 A を全探索して、最も偏角の大きくなる点 C を二分探索(std::lower_bound)で求める double ret = 0.0; for (int i = 0; i < vec.size(); i++) { double target = vec[i] + 180.0; if (target >= 360.0) target -= 360.0; int pos1 = lower_bound(vec.begin(), vec.end(), target) - vec.begin(); // 点 C の候補は高々 2 つに絞れる int CandIdx1 = pos1 % vec.size(); int CandIdx2 = (pos1 + vec.size() - 1) % vec.size(); double Candidate1 = getangle2(vec[i], vec[CandIdx1]); double Candidate2 = getangle2(vec[i], vec[CandIdx2]); ret = max({ ret, Candidate1, Candidate2 }); } return ret; } // O(N^3) のアルゴリズム(点 A, B, C を全探索) double solve_Slow() { double Answer = 0.0; for (int i = 1; i <= N; i++) { for (int j = 1; j <= N; j++) { for (int k = 1; k <= N; k++) { if (i == j || i == k || j == k) continue; double I1 = getangle(G[i] - G[j]); double I2 = getangle(G[k] - G[j]); Answer = max(Answer, getangle2(I1, I2)); } } } return Answer; } // O(N^2 log N) のアルゴリズム double solve_Fast() { // 点 B を全探索 double Answer = 0.0; for (int i = 1; i <= N; i++) { double ret = solve(i); Answer = max(Answer, ret); } return Answer; } int main() { // Step #1. 入力 cin >> N; for (int i = 1; i <= N; i++) { cin >> G[i].px >> G[i].py; } // Step #2. 出力 double FinalAns = solve_Fast(); printf("%.12lf\n", FinalAns); return 0; }
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#include <iostream> #include <cmath> #include <vector> #include <algorithm> using namespace std; struct Point { double px, py; }; Point operator-(const Point& a1, const Point& a2) { return Point{ a1.px - a2.px, a1.py - a2.py }; } double getangle(Point G) { // 点 G の偏角を求める if (G.py >= 0.0) { double I = G.px / sqrt(G.px * G.px + G.py * G.py); double kaku = acos(I) * 180.0 / 3.14159265358979; return kaku; } else { double I = G.px / sqrt(G.px * G.px + G.py * G.py); double kaku = acos(I) * 180.0 / 3.14159265358979; return 360.0 - kaku; } } double getangle2(double I1, double I2) { // [偏角 I1] - [原点] - [偏角 I2] のなす角度を求める // 例えば I1 = 240°、I2 = 30°のとき、求める角度は 150° double res = abs(I1 - I2); if (res >= 180.0) return 360.0 - res; return res; } int N; Point G[2009]; double solve(int pos) { // 最初に偏角の昇順にソートする vector<double> vec; for (int i = 1; i <= N; i++) { if (i == pos) continue; Point SA = G[i] - G[pos]; double angle = getangle(SA); vec.push_back(angle); } sort(vec.begin(), vec.end()); // 点 A を全探索して、最も偏角の大きくなる点 C を二分探索(std::lower_bound)で求める double ret = 0.0; for (int i = 0; i < vec.size(); i++) { double target = vec[i] + 180.0; if (target >= 360.0) target -= 360.0; int pos1 = lower_bound(vec.begin(), vec.end(), target) - vec.begin(); // 点 C の候補は高々 2 つに絞れる int CandIdx1 = pos1 % vec.size(); int CandIdx2 = (pos1 + vec.size() - 1) % vec.size(); double Candidate1 = getangle2(vec[i], vec[CandIdx1]); double Candidate2 = getangle2(vec[i], vec[CandIdx2]); ret = max({ ret, Candidate1, Candidate2 }); } return ret; } // O(N^3) のアルゴリズム(点 A, B, C を全探索) double solve_Slow() { double Answer = 0.0; for (int i = 1; i <= N; i++) { for (int j = 1; j <= N; j++) { for (int k = 1; k <= N; k++) { if (i == j || i == k || j == k) continue; double I1 = getangle(G[i] - G[j]); double I2 = getangle(G[k] - G[j]); Answer = max(Answer, getangle2(I1, I2)); } } } return Answer; } // O(N^2 log N) のアルゴリズム double solve_Fast() { // 点 B を全探索 double Answer = 0.0; for (int i = 1; i <= N; i++) { double ret = solve(i); Answer = max(Answer, ret); } return Answer; } int main() { // Step #1. 入力 cin >> N; for (int i = 1; i <= N; i++) { cin >> G[i].px >> G[i].py; } // Step #2. 出力 double FinalAns = solve_Fast(); printf("%.12lf\n", FinalAns); return 0; }
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func main() var n: int :: cui@inputInt() var x: []float :: #[n]float var y: []float :: #[n]float for i(0, n - 1) do x[i] :: cui@inputFloat() do y[i] :: cui@inputFloat() end for var ans: float :: 0.0 for i(0, n - 1) var rots: []float :: #[n]float for j(0, n - 1) if(i = j) if(i = 0) do rots[j] :: lib@invRot(x[j + 1], y[j + 1], x[i], y[i]) else do rots[j] :: lib@invRot(x[j - 1], y[j - 1], x[i], y[i]) end if else do rots[j] :: lib@invRot(x[j], y[j], x[i], y[i]) end if end for do rots.sort() var rots2: []float :: #[2 * n]float for j(0, n - 1) do rots2[j] :: rots[j] end for for j(n, 2 * n - 1) do rots2[j] :: rots[j - n] + 2.0 * lib@pi end for for j(0, n - 1) var target: float :: rots[j] + lib@pi var ok: int :: j var ng: int :: j + n while((ok - ng).abs() > 1) var mid: int :: (ok + ng) / 2 if(rots2[mid] <= target) do ok :: mid else do ng :: mid end if end while do ans :: [ans, f(rots2[ok] - rots[j])].max() do ans :: [ans, f(rots2[ok + 1] - rots[j])].max() end for end for do cui@print("\{lib@toDegree(ans)}\n") func f(t: float): float if(t > lib@pi) do t :: 2.0 * lib@pi - t end if ret t end func end func
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# 0.36.0 以降は Math::TAU があります TAU = Math::PI * 2 n = read_line.to_i xy = (1..n).map { {Int32, Int32}.from read_line.split.map(&.to_i) } puts (0...n).max_of { |i| angle = (0...n).select { |j| i != j }.map { |j| Math.atan2(xy[j][1] - xy[i][1], xy[j][0] - xy[i][0]) } angles = angle.flat_map { |a| [a, a + Math::PI * 2] }.sort angle.max_of { |a| index = angles.bsearch_index { |b| b >= a + Math::PI }.not_nil! {angles[index - 1], angles[index]}.max_of { |b| res = (b - a) % TAU res > Math::PI ? Math::PI - res : res } } } * 360 / TAU
# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) from bisect import bisect_left from cmath import phase, pi from typing import List C = 2 * pi N = int(input()) P: List[complex] = [] for _ in range(N): x, y = map(int, input().split()) P.append(x + y * 1j) ans = 0 for i in range(N): A = sorted((phase(P[j] - P[i]) + pi) * 360 / C for j in range(N) if i != j) now = 0 for Aj in A: k = bisect_left(A, Aj + 180) r = A[k % len(A)] - Aj if r < 0: r += 360 if r > 180: r = 360 - r l = A[k % len(A) - 1] - Aj if l < 0: l += 360 if l > 180: l = 360 - l now = max(now, l, r) ans = max(ans, now) print(ans)
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# 0.36.0 以降は Math::TAU があります TAU = Math::PI * 2 n = read_line.to_i xy = (1..n).map { {Int32, Int32}.from read_line.split.map(&.to_i) } puts (0...n).max_of { |i| angle = (0...n).select { |j| i != j }.map { |j| Math.atan2(xy[j][1] - xy[i][1], xy[j][0] - xy[i][0]) } angles = angle.flat_map { |a| [a, a + Math::PI * 2] }.sort angle.max_of { |a| index = angles.bsearch_index { |b| b >= a + Math::PI }.not_nil! {angles[index - 1], angles[index]}.max_of { |b| res = (b - a) % TAU res > Math::PI ? Math::PI - res : res } } } * 360 / TAU
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# 0.36.0 以降は Math::TAU があります TAU = Math::PI * 2 n = read_line.to_i xy = (1..n).map { {Int32, Int32}.from read_line.split.map(&.to_i) } puts (0...n).max_of { |i| angle = (0...n).select { |j| i != j }.map { |j| Math.atan2(xy[j][1] - xy[i][1], xy[j][0] - xy[i][0]) } angles = angle.flat_map { |a| [a, a + Math::PI * 2] }.sort angle.max_of { |a| index = angles.bsearch_index { |b| b >= a + Math::PI }.not_nil! {angles[index - 1], angles[index]}.max_of { |b| res = (b - a) % TAU res > Math::PI ? Math::PI - res : res } } } * 360 / TAU
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func main() var n: int :: cui@inputInt() var x: []float :: #[n]float var y: []float :: #[n]float for i(0, n - 1) do x[i] :: cui@inputFloat() do y[i] :: cui@inputFloat() end for var ans: float :: 0.0 for i(0, n - 1) var rots: []float :: #[n]float for j(0, n - 1) if(i = j) if(i = 0) do rots[j] :: lib@invRot(x[j + 1], y[j + 1], x[i], y[i]) else do rots[j] :: lib@invRot(x[j - 1], y[j - 1], x[i], y[i]) end if else do rots[j] :: lib@invRot(x[j], y[j], x[i], y[i]) end if end for do rots.sort() var rots2: []float :: #[2 * n]float for j(0, n - 1) do rots2[j] :: rots[j] end for for j(n, 2 * n - 1) do rots2[j] :: rots[j - n] + 2.0 * lib@pi end for for j(0, n - 1) var target: float :: rots[j] + lib@pi var ok: int :: j var ng: int :: j + n while((ok - ng).abs() > 1) var mid: int :: (ok + ng) / 2 if(rots2[mid] <= target) do ok :: mid else do ng :: mid end if end while do ans :: [ans, f(rots2[ok] - rots[j])].max() do ans :: [ans, f(rots2[ok + 1] - rots[j])].max() end for end for do cui@print("\{lib@toDegree(ans)}\n") func f(t: float): float if(t > lib@pi) do t :: 2.0 * lib@pi - t end if ret t end func end func
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) from bisect import bisect_left from cmath import phase, pi from typing import List C = 2 * pi N = int(input()) P: List[complex] = [] for _ in range(N): x, y = map(int, input().split()) P.append(x + y * 1j) ans = 0 for i in range(N): A = sorted((phase(P[j] - P[i]) + pi) * 360 / C for j in range(N) if i != j) now = 0 for Aj in A: k = bisect_left(A, Aj + 180) r = A[k % len(A)] - Aj if r < 0: r += 360 if r > 180: r = 360 - r l = A[k % len(A) - 1] - Aj if l < 0: l += 360 if l > 180: l = 360 - l now = max(now, l, r) ans = max(ans, now) print(ans)
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) from bisect import bisect_left from cmath import phase, pi from typing import List C = 2 * pi N = int(input()) P: List[complex] = [] for _ in range(N): x, y = map(int, input().split()) P.append(x + y * 1j) ans = 0 for i in range(N): A = sorted((phase(P[j] - P[i]) + pi) * 360 / C for j in range(N) if i != j) now = 0 for Aj in A: k = bisect_left(A, Aj + 180) r = A[k % len(A)] - Aj if r < 0: r += 360 if r > 180: r = 360 - r l = A[k % len(A) - 1] - Aj if l < 0: l += 360 if l > 180: l = 360 - l now = max(now, l, r) ans = max(ans, now) print(ans)
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func main() var n: int :: cui@inputInt() var x: []float :: #[n]float var y: []float :: #[n]float for i(0, n - 1) do x[i] :: cui@inputFloat() do y[i] :: cui@inputFloat() end for var ans: float :: 0.0 for i(0, n - 1) var rots: []float :: #[n]float for j(0, n - 1) if(i = j) if(i = 0) do rots[j] :: lib@invRot(x[j + 1], y[j + 1], x[i], y[i]) else do rots[j] :: lib@invRot(x[j - 1], y[j - 1], x[i], y[i]) end if else do rots[j] :: lib@invRot(x[j], y[j], x[i], y[i]) end if end for do rots.sort() var rots2: []float :: #[2 * n]float for j(0, n - 1) do rots2[j] :: rots[j] end for for j(n, 2 * n - 1) do rots2[j] :: rots[j - n] + 2.0 * lib@pi end for for j(0, n - 1) var target: float :: rots[j] + lib@pi var ok: int :: j var ng: int :: j + n while((ok - ng).abs() > 1) var mid: int :: (ok + ng) / 2 if(rots2[mid] <= target) do ok :: mid else do ng :: mid end if end while do ans :: [ans, f(rots2[ok] - rots[j])].max() do ans :: [ans, f(rots2[ok + 1] - rots[j])].max() end for end for do cui@print("\{lib@toDegree(ans)}\n") func f(t: float): float if(t > lib@pi) do t :: 2.0 * lib@pi - t end if ret t end func end func
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func main() var n: int :: cui@inputInt() var x: []float :: #[n]float var y: []float :: #[n]float for i(0, n - 1) do x[i] :: cui@inputFloat() do y[i] :: cui@inputFloat() end for var ans: float :: 0.0 for i(0, n - 1) var rots: []float :: #[n]float for j(0, n - 1) if(i = j) if(i = 0) do rots[j] :: lib@invRot(x[j + 1], y[j + 1], x[i], y[i]) else do rots[j] :: lib@invRot(x[j - 1], y[j - 1], x[i], y[i]) end if else do rots[j] :: lib@invRot(x[j], y[j], x[i], y[i]) end if end for do rots.sort() var rots2: []float :: #[2 * n]float for j(0, n - 1) do rots2[j] :: rots[j] end for for j(n, 2 * n - 1) do rots2[j] :: rots[j - n] + 2.0 * lib@pi end for for j(0, n - 1) var target: float :: rots[j] + lib@pi var ok: int :: j var ng: int :: j + n while((ok - ng).abs() > 1) var mid: int :: (ok + ng) / 2 if(rots2[mid] <= target) do ok :: mid else do ng :: mid end if end while do ans :: [ans, f(rots2[ok] - rots[j])].max() do ans :: [ans, f(rots2[ok + 1] - rots[j])].max() end for end for do cui@print("\{lib@toDegree(ans)}\n") func f(t: float): float if(t > lib@pi) do t :: 2.0 * lib@pi - t end if ret t end func end func
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#include <iostream> using namespace std; // 入力 int N; int C[100009], P[100009]; int Q; int L[100009], R[100009]; // 累積和 int Sum1[100009]; int Sum2[100009]; int main() { // Step #1. 入力 cin >> N; for (int i = 1; i <= N; i++) cin >> C[i] >> P[i]; cin >> Q; for (int i = 1; i <= Q; i++) cin >> L[i] >> R[i]; // Step #2. 1 組・2 組それぞれの累積和を取る for (int i = 1; i <= N; i++) { Sum1[i] = Sum1[i - 1]; Sum2[i] = Sum2[i - 1]; if (C[i] == 1) Sum1[i] += P[i]; if (C[i] == 2) Sum2[i] += P[i]; } // Step #3. クエリに答える for (int i = 1; i <= Q; i++) { int Answer1 = Sum1[R[i]] - Sum1[L[i] - 1]; int Answer2 = Sum2[R[i]] - Sum2[L[i] - 1]; cout << Answer1 << " " << Answer2 << endl; } return 0; }
n = read_line.to_i sums = {0, 1}.map { [0] * n.succ } n.times do |i| c, p = read_line.split.map(&.to_i) sums.each { |sum| sum[i + 1] += sum[i] } sums[c - 1][i + 1] += p end read_line.to_i.times do l, r = read_line.split.map(&.to_i) puts sums.join(' ') { |sum| sum[r] - sum[l - 1] } end
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#include <iostream> using namespace std; // 入力 int N; int C[100009], P[100009]; int Q; int L[100009], R[100009]; // 累積和 int Sum1[100009]; int Sum2[100009]; int main() { // Step #1. 入力 cin >> N; for (int i = 1; i <= N; i++) cin >> C[i] >> P[i]; cin >> Q; for (int i = 1; i <= Q; i++) cin >> L[i] >> R[i]; // Step #2. 1 組・2 組それぞれの累積和を取る for (int i = 1; i <= N; i++) { Sum1[i] = Sum1[i - 1]; Sum2[i] = Sum2[i - 1]; if (C[i] == 1) Sum1[i] += P[i]; if (C[i] == 2) Sum2[i] += P[i]; } // Step #3. クエリに答える for (int i = 1; i <= Q; i++) { int Answer1 = Sum1[R[i]] - Sum1[L[i] - 1]; int Answer2 = Sum2[R[i]] - Sum2[L[i] - 1]; cout << Answer1 << " " << Answer2 << endl; } return 0; }
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) N = int(input()) S = [[0] * (N + 1) for _ in range(2)] for i in range(N): c, p = map(int, input().split()) S[c - 1][i + 1] = p for i in range(N): for j in range(2): S[j][i + 1] += S[j][i] Q = int(input()) LR = [tuple(map(int, input().split())) for _ in range(Q)] for l, r in LR: print(S[0][r] - S[0][l - 1], S[1][r] - S[1][l - 1])
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#include <iostream> using namespace std; // 入力 int N; int C[100009], P[100009]; int Q; int L[100009], R[100009]; // 累積和 int Sum1[100009]; int Sum2[100009]; int main() { // Step #1. 入力 cin >> N; for (int i = 1; i <= N; i++) cin >> C[i] >> P[i]; cin >> Q; for (int i = 1; i <= Q; i++) cin >> L[i] >> R[i]; // Step #2. 1 組・2 組それぞれの累積和を取る for (int i = 1; i <= N; i++) { Sum1[i] = Sum1[i - 1]; Sum2[i] = Sum2[i - 1]; if (C[i] == 1) Sum1[i] += P[i]; if (C[i] == 2) Sum2[i] += P[i]; } // Step #3. クエリに答える for (int i = 1; i <= Q; i++) { int Answer1 = Sum1[R[i]] - Sum1[L[i] - 1]; int Answer2 = Sum2[R[i]] - Sum2[L[i] - 1]; cout << Answer1 << " " << Answer2 << endl; } return 0; }
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func main() var n: int :: cui@inputInt() var cum1: []int :: #[n + 1]int var cum2: []int :: #[n + 1]int for i(0, n - 1) var c: int :: cui@inputInt() var p: int :: cui@inputInt() do cum1[i + 1] :: cum1[i] do cum2[i + 1] :: cum2[i] if(c = 1) do cum1[i + 1] :+ p else do cum2[i + 1] :+ p end if end for var q: int :: cui@inputInt() for(1, q) var l: int :: cui@inputInt() - 1 var r: int :: cui@inputInt() do cui@print("\{cum1[r] - cum1[l]} \{cum2[r] - cum2[l]}\n") end for end func
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n = read_line.to_i sums = {0, 1}.map { [0] * n.succ } n.times do |i| c, p = read_line.split.map(&.to_i) sums.each { |sum| sum[i + 1] += sum[i] } sums[c - 1][i + 1] += p end read_line.to_i.times do l, r = read_line.split.map(&.to_i) puts sums.join(' ') { |sum| sum[r] - sum[l - 1] } end
# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) N = int(input()) S = [[0] * (N + 1) for _ in range(2)] for i in range(N): c, p = map(int, input().split()) S[c - 1][i + 1] = p for i in range(N): for j in range(2): S[j][i + 1] += S[j][i] Q = int(input()) LR = [tuple(map(int, input().split())) for _ in range(Q)] for l, r in LR: print(S[0][r] - S[0][l - 1], S[1][r] - S[1][l - 1])
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n = read_line.to_i sums = {0, 1}.map { [0] * n.succ } n.times do |i| c, p = read_line.split.map(&.to_i) sums.each { |sum| sum[i + 1] += sum[i] } sums[c - 1][i + 1] += p end read_line.to_i.times do l, r = read_line.split.map(&.to_i) puts sums.join(' ') { |sum| sum[r] - sum[l - 1] } end
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func main() var n: int :: cui@inputInt() var cum1: []int :: #[n + 1]int var cum2: []int :: #[n + 1]int for i(0, n - 1) var c: int :: cui@inputInt() var p: int :: cui@inputInt() do cum1[i + 1] :: cum1[i] do cum2[i + 1] :: cum2[i] if(c = 1) do cum1[i + 1] :+ p else do cum2[i + 1] :+ p end if end for var q: int :: cui@inputInt() for(1, q) var l: int :: cui@inputInt() - 1 var r: int :: cui@inputInt() do cui@print("\{cum1[r] - cum1[l]} \{cum2[r] - cum2[l]}\n") end for end func
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) N = int(input()) S = [[0] * (N + 1) for _ in range(2)] for i in range(N): c, p = map(int, input().split()) S[c - 1][i + 1] = p for i in range(N): for j in range(2): S[j][i + 1] += S[j][i] Q = int(input()) LR = [tuple(map(int, input().split())) for _ in range(Q)] for l, r in LR: print(S[0][r] - S[0][l - 1], S[1][r] - S[1][l - 1])
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func main() var n: int :: cui@inputInt() var cum1: []int :: #[n + 1]int var cum2: []int :: #[n + 1]int for i(0, n - 1) var c: int :: cui@inputInt() var p: int :: cui@inputInt() do cum1[i + 1] :: cum1[i] do cum2[i + 1] :: cum2[i] if(c = 1) do cum1[i + 1] :+ p else do cum2[i + 1] :+ p end if end for var q: int :: cui@inputInt() for(1, q) var l: int :: cui@inputInt() - 1 var r: int :: cui@inputInt() do cui@print("\{cum1[r] - cum1[l]} \{cum2[r] - cum2[l]}\n") end for end func
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#include <iostream> #include <vector> #include <algorithm> #include <tuple> using ll = long long; using namespace std; template<class T, class U> T &chmax(T &a, const U &b){ if(a < b) a = b; return a; } //43[ms] int main(){ int n; cin >> n; vector<tuple<int,int,int>> v(n); for(int i = 0; i < n; i++){ int d,c,s; cin >> d >> c >> s; v[i] = {d,c,s}; } sort(v.begin(), v.end()); vector<ll> cur(5001), next(5001); for(int i = 0; i < n; i++){ int d,c,s; tie(d,c,s) = v[i]; for(int j = 0; j <= 5000; j++){ next[j] = cur[j]; if(j > d || j < c) continue; chmax(next[j], cur[j - c] + s); } swap(cur, next); } ll ans = 0; for(int i = 0; i <= 5000; i++) chmax(ans, cur[i]); cout << ans << "\n"; }
n = read_line.to_i dcs = (1..n).map { read_line.split.try { |(d, c, s)| {d.to_i, c.to_i, s.to_i64} } }.sort day = dcs.max_of { |(d, c, s)| d } puts dcs.each_with_object([0i64] * day.succ) { |(d, c, s), dp| (c..d).reverse_each do |i| dp[i] = {dp[i], dp[i - c] + s}.max end (0...day).each do |i| dp[i + 1] = {dp[i + 1], dp[i]}.max end }.max
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#include <iostream> #include <vector> #include <algorithm> #include <tuple> using ll = long long; using namespace std; template<class T, class U> T &chmax(T &a, const U &b){ if(a < b) a = b; return a; } //43[ms] int main(){ int n; cin >> n; vector<tuple<int,int,int>> v(n); for(int i = 0; i < n; i++){ int d,c,s; cin >> d >> c >> s; v[i] = {d,c,s}; } sort(v.begin(), v.end()); vector<ll> cur(5001), next(5001); for(int i = 0; i < n; i++){ int d,c,s; tie(d,c,s) = v[i]; for(int j = 0; j <= 5000; j++){ next[j] = cur[j]; if(j > d || j < c) continue; chmax(next[j], cur[j - c] + s); } swap(cur, next); } ll ans = 0; for(int i = 0; i <= 5000; i++) chmax(ans, cur[i]); cout << ans << "\n"; }
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) import sys def main(): input = sys.stdin.readline N = int(input()) DCS = sorted([tuple(map(int, input().split())) for _ in range(N)], key=lambda x: x[0]) M = max(d for d, c, s in DCS) dp = [[0] * (M + 1) for _ in range(N + 1)] for i in range(N): d, c, s = DCS[i] for j in range(M + 1): dp[i + 1][j] = max(dp[i + 1][j], dp[i][j]) if j + c > d: continue dp[i + 1][j + c] = max(dp[i + 1][j + c], dp[i][j] + s) print(max(dp[N])) if __name__ == '__main__': main()
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#include <iostream> #include <vector> #include <algorithm> #include <tuple> using ll = long long; using namespace std; template<class T, class U> T &chmax(T &a, const U &b){ if(a < b) a = b; return a; } //43[ms] int main(){ int n; cin >> n; vector<tuple<int,int,int>> v(n); for(int i = 0; i < n; i++){ int d,c,s; cin >> d >> c >> s; v[i] = {d,c,s}; } sort(v.begin(), v.end()); vector<ll> cur(5001), next(5001); for(int i = 0; i < n; i++){ int d,c,s; tie(d,c,s) = v[i]; for(int j = 0; j <= 5000; j++){ next[j] = cur[j]; if(j > d || j < c) continue; chmax(next[j], cur[j - c] + s); } swap(cur, next); } ll ans = 0; for(int i = 0; i <= 5000; i++) chmax(ans, cur[i]); cout << ans << "\n"; }
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#include <iostream> #include <vector> #include <algorithm> #include <tuple> using ll = long long; using namespace std; template<class T, class U> T &chmax(T &a, const U &b){ if(a < b) a = b; return a; } //43[ms] int main(){ int n; cin >> n; vector<tuple<int,int,int>> v(n); for(int i = 0; i < n; i++){ int d,c,s; cin >> d >> c >> s; v[i] = {d,c,s}; } sort(v.begin(), v.end()); vector<ll> cur(5001), next(5001); for(int i = 0; i < n; i++){ int d,c,s; tie(d,c,s) = v[i]; for(int j = 0; j <= 5000; j++){ next[j] = cur[j]; if(j > d || j < c) continue; chmax(next[j], cur[j - c] + s); } swap(cur, next); } ll ans = 0; for(int i = 0; i <= 5000; i++) chmax(ans, cur[i]); cout << ans << "\n"; }
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func main() var n: int :: cui@inputInt() var works: []Work :: #[n]Work var dMax: int :: 0 for i(0, n - 1) var d: int :: cui@inputInt() var c: int :: cui@inputInt() var s: int :: cui@inputInt() do works[i] :: (#Work).init(d, c, s) do dMax :: [dMax, d].max() end for do works.sort() ; dp[仕事番号][合計仕事時間] = 合計金額 var dp: [][]int :: #[n + 1, dMax + 1]int ; 初期化する代わりに、最初の所持金を1円として「最終的な金額 - 1」を答えとする。 do dp[0][0] :: 1 for i(0, n - 1) for j(0, dMax) var d: int :: works[i].d var c: int :: works[i].c var s: int :: works[i].s if(j + c <= d) do dp[i + 1][j + c] :: [dp[i + 1][j + c], dp[i][j] + s].max() end if do dp[i + 1][j] :: [dp[i + 1][j], dp[i][j]].max() end for end for var ans: int :: 0 for j(0, dMax) do ans :: [ans, dp[n][j]].max() end for do ans :- 1 do cui@print("\{ans}\n") class Work() +var d: int +var c: int +var s: int +func init(d: int, c: int, s: int): Work do me.d :: d do me.c :: c do me.s :: s ret me end func +*func cmp(t: kuin@Class): int if(me.d < (t $ Work).d) ret - 1 elif(me.d > (t $ Work).d) ret 1 end if ret 0 end func end class end func
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n = read_line.to_i dcs = (1..n).map { read_line.split.try { |(d, c, s)| {d.to_i, c.to_i, s.to_i64} } }.sort day = dcs.max_of { |(d, c, s)| d } puts dcs.each_with_object([0i64] * day.succ) { |(d, c, s), dp| (c..d).reverse_each do |i| dp[i] = {dp[i], dp[i - c] + s}.max end (0...day).each do |i| dp[i + 1] = {dp[i + 1], dp[i]}.max end }.max
# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) import sys def main(): input = sys.stdin.readline N = int(input()) DCS = sorted([tuple(map(int, input().split())) for _ in range(N)], key=lambda x: x[0]) M = max(d for d, c, s in DCS) dp = [[0] * (M + 1) for _ in range(N + 1)] for i in range(N): d, c, s = DCS[i] for j in range(M + 1): dp[i + 1][j] = max(dp[i + 1][j], dp[i][j]) if j + c > d: continue dp[i + 1][j + c] = max(dp[i + 1][j + c], dp[i][j] + s) print(max(dp[N])) if __name__ == '__main__': main()
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n = read_line.to_i dcs = (1..n).map { read_line.split.try { |(d, c, s)| {d.to_i, c.to_i, s.to_i64} } }.sort day = dcs.max_of { |(d, c, s)| d } puts dcs.each_with_object([0i64] * day.succ) { |(d, c, s), dp| (c..d).reverse_each do |i| dp[i] = {dp[i], dp[i - c] + s}.max end (0...day).each do |i| dp[i + 1] = {dp[i + 1], dp[i]}.max end }.max
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n = read_line.to_i dcs = (1..n).map { read_line.split.try { |(d, c, s)| {d.to_i, c.to_i, s.to_i64} } }.sort day = dcs.max_of { |(d, c, s)| d } puts dcs.each_with_object([0i64] * day.succ) { |(d, c, s), dp| (c..d).reverse_each do |i| dp[i] = {dp[i], dp[i - c] + s}.max end (0...day).each do |i| dp[i + 1] = {dp[i + 1], dp[i]}.max end }.max
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func main() var n: int :: cui@inputInt() var works: []Work :: #[n]Work var dMax: int :: 0 for i(0, n - 1) var d: int :: cui@inputInt() var c: int :: cui@inputInt() var s: int :: cui@inputInt() do works[i] :: (#Work).init(d, c, s) do dMax :: [dMax, d].max() end for do works.sort() ; dp[仕事番号][合計仕事時間] = 合計金額 var dp: [][]int :: #[n + 1, dMax + 1]int ; 初期化する代わりに、最初の所持金を1円として「最終的な金額 - 1」を答えとする。 do dp[0][0] :: 1 for i(0, n - 1) for j(0, dMax) var d: int :: works[i].d var c: int :: works[i].c var s: int :: works[i].s if(j + c <= d) do dp[i + 1][j + c] :: [dp[i + 1][j + c], dp[i][j] + s].max() end if do dp[i + 1][j] :: [dp[i + 1][j], dp[i][j]].max() end for end for var ans: int :: 0 for j(0, dMax) do ans :: [ans, dp[n][j]].max() end for do ans :- 1 do cui@print("\{ans}\n") class Work() +var d: int +var c: int +var s: int +func init(d: int, c: int, s: int): Work do me.d :: d do me.c :: c do me.s :: s ret me end func +*func cmp(t: kuin@Class): int if(me.d < (t $ Work).d) ret - 1 elif(me.d > (t $ Work).d) ret 1 end if ret 0 end func end class end func
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) import sys def main(): input = sys.stdin.readline N = int(input()) DCS = sorted([tuple(map(int, input().split())) for _ in range(N)], key=lambda x: x[0]) M = max(d for d, c, s in DCS) dp = [[0] * (M + 1) for _ in range(N + 1)] for i in range(N): d, c, s = DCS[i] for j in range(M + 1): dp[i + 1][j] = max(dp[i + 1][j], dp[i][j]) if j + c > d: continue dp[i + 1][j + c] = max(dp[i + 1][j + c], dp[i][j] + s) print(max(dp[N])) if __name__ == '__main__': main()
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# でつoO(YOU PLAY WITH THE CARDS YOU'RE DEALT..) import sys def main(): input = sys.stdin.readline N = int(input()) DCS = sorted([tuple(map(int, input().split())) for _ in range(N)], key=lambda x: x[0]) M = max(d for d, c, s in DCS) dp = [[0] * (M + 1) for _ in range(N + 1)] for i in range(N): d, c, s = DCS[i] for j in range(M + 1): dp[i + 1][j] = max(dp[i + 1][j], dp[i][j]) if j + c > d: continue dp[i + 1][j + c] = max(dp[i + 1][j + c], dp[i][j] + s) print(max(dp[N])) if __name__ == '__main__': main()
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func main() var n: int :: cui@inputInt() var works: []Work :: #[n]Work var dMax: int :: 0 for i(0, n - 1) var d: int :: cui@inputInt() var c: int :: cui@inputInt() var s: int :: cui@inputInt() do works[i] :: (#Work).init(d, c, s) do dMax :: [dMax, d].max() end for do works.sort() ; dp[仕事番号][合計仕事時間] = 合計金額 var dp: [][]int :: #[n + 1, dMax + 1]int ; 初期化する代わりに、最初の所持金を1円として「最終的な金額 - 1」を答えとする。 do dp[0][0] :: 1 for i(0, n - 1) for j(0, dMax) var d: int :: works[i].d var c: int :: works[i].c var s: int :: works[i].s if(j + c <= d) do dp[i + 1][j + c] :: [dp[i + 1][j + c], dp[i][j] + s].max() end if do dp[i + 1][j] :: [dp[i + 1][j], dp[i][j]].max() end for end for var ans: int :: 0 for j(0, dMax) do ans :: [ans, dp[n][j]].max() end for do ans :- 1 do cui@print("\{ans}\n") class Work() +var d: int +var c: int +var s: int +func init(d: int, c: int, s: int): Work do me.d :: d do me.c :: c do me.s :: s ret me end func +*func cmp(t: kuin@Class): int if(me.d < (t $ Work).d) ret - 1 elif(me.d > (t $ Work).d) ret 1 end if ret 0 end func end class end func
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func main() var n: int :: cui@inputInt() var works: []Work :: #[n]Work var dMax: int :: 0 for i(0, n - 1) var d: int :: cui@inputInt() var c: int :: cui@inputInt() var s: int :: cui@inputInt() do works[i] :: (#Work).init(d, c, s) do dMax :: [dMax, d].max() end for do works.sort() ; dp[仕事番号][合計仕事時間] = 合計金額 var dp: [][]int :: #[n + 1, dMax + 1]int ; 初期化する代わりに、最初の所持金を1円として「最終的な金額 - 1」を答えとする。 do dp[0][0] :: 1 for i(0, n - 1) for j(0, dMax) var d: int :: works[i].d var c: int :: works[i].c var s: int :: works[i].s if(j + c <= d) do dp[i + 1][j + c] :: [dp[i + 1][j + c], dp[i][j] + s].max() end if do dp[i + 1][j] :: [dp[i + 1][j], dp[i][j]].max() end for end for var ans: int :: 0 for j(0, dMax) do ans :: [ans, dp[n][j]].max() end for do ans :- 1 do cui@print("\{ans}\n") class Work() +var d: int +var c: int +var s: int +func init(d: int, c: int, s: int): Work do me.d :: d do me.c :: c do me.s :: s ret me end func +*func cmp(t: kuin@Class): int if(me.d < (t $ Work).d) ret - 1 elif(me.d > (t $ Work).d) ret 1 end if ret 0 end func end class end func
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