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At Sparrowtown Consulting, the head of human resources examined how the number of employees with health care benefits varied in response to policy changes. According to the table, what was the rate of change between 2011 and 2012? | null | 27 | employees per year | Employees with health care benefits | Year | Employees
2009 | 48
2010 | 41
2011 | 6
2012 | 33
2013 | 25 | {
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"41",
"6",
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"Name": null,
"Number of apples": null,
"Number of bottles": null,
"Number of branches": null,
"Number of buckets": null,
"Number of cans of food": null,
"Number of clubs": null,
"Number of cows": null,
"Number of cupcakes": null,
"Number of cups": null,
"Number of fan letters": null,
"Number of fields": null,
"Number of gym lockers": null,
"Number of pairs of shorts": null,
"Number of pink highlighters": null,
"Number of practices": null,
"Number of red blocks": null,
"Number of respondents": null,
"Number of shells": null,
"Number of soccer fields": null,
"Number of students": null,
"Number of tables": null,
"Number of tickets": null,
"Number of times": null,
"Number of trips": null,
"Number of vans": null,
"Number of watermelons": null,
"Number spun": null,
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"Quantity supplied": null,
"Record time (minutes)": null,
"Score": null,
"Stem": null,
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"Thursday": null,
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"Type": null,
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"Year": [
"2009",
"2010",
"2011",
"2012",
"2013"
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"y": null
} | 6 | 2 | Plug the numbers into the formula for rate of change and simplify.
Rate of change
= \frac{change in value}{change in time}
= \frac{33 employees - 6 employees}{2012 - 2011}
= \frac{33 employees - 6 employees}{1 year}
= \frac{27 employees}{1 year}
= 27 employees per year
The rate of change between 2011 and 2012 was 27 employees per year. | free_text | integer_number | 7 | train |
What is the total cost for 2+1/4 pounds of oranges? | null | 6.75 | $ | null | oranges | $3/pound
limes | $1/pound
tangerines | $4/pound
pineapples | $4/pound | {
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"pineapples"
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"Year": null,
"x": null,
"y": null
} | 4 | 2 | Find the cost of the oranges. Multiply the price per pound by the number of pounds.
$3 × 2\frac{1}{4} = $3 × 2.25 = $6.75
The total cost is $6.75. | free_text | decimal_number | 6 | train |
Lillian's class recorded how many cans of food each student collected for their canned food drive. Who collected the most cans? | [
"Lillian",
"Bryan",
"Jeanette",
"Kari"
] | Bryan | null | Cans of food collected | Name | Number of cans of food
Lillian | 662
Bryan | 698
Jeanette | 678
Kari | 679 | {
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"698",
"678",
"679"
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"x": null,
"y": null
} | 5 | 2 | Find the greatest number in the table. Remember to compare the numbers starting with the highest place value. The greatest number is 698.
Now find the corresponding name. Bryan corresponds to 698. | multi_choice | extractive_text | 2 | train |
Roxanne spent a week at the beach and recorded the number of shells she found each day. According to the table, what was the rate of change between Wednesday and Thursday? | null | -2 | shells per day | Shells Roxanne found | Day | Number of shells
Tuesday | 6
Wednesday | 4
Thursday | 2
Friday | 5
Saturday | 0 | {
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"Number of cupcakes": null,
"Number of cups": null,
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"Number of gym lockers": null,
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"Number of shells": [
"6",
"4",
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"y": null
} | 6 | 2 | Plug the numbers into the formula for rate of change and simplify.
Rate of change
= \frac{change in value}{change in time}
= \frac{2 shells - 4 shells}{1 day}
= \frac{-2 shells}{1 day}
= -2 shells per day
The rate of change between Wednesday and Thursday was - 2 shells per day. | free_text | integer_number | 8 | train |
How much money does Lena need to buy a pink flamingo pen, a tiny bottle of sand, and a souvenir cup? | null | 2.23 | $ | null | souvenir cup | $0.78
sand castle magnet | $0.99
pink flamingo pen | $0.92
whale keychain | $0.44
tiny bottle of sand | $0.53
souvenir spoon | $0.96 | {
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"Column 1": [
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"sand castle magnet",
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"Number of cups": null,
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"Number of pink highlighters": null,
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"Number of respondents": null,
"Number of shells": null,
"Number of soccer fields": null,
"Number of students": null,
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"Wednesday": null,
"Year": null,
"x": null,
"y": null
} | 6 | 2 | Find the total cost of a pink flamingo pen, a tiny bottle of sand, and a souvenir cup.
$0.92 + $0.53 + $0.78 = $2.23
Lena needs $2.23. | free_text | decimal_number | 5 | train |
Three friends went on a road trip and kept track of how long each of them spent driving. What fraction of the driving was done by Ronald? Simplify your answer. | null | 79/180 | null | Road trip driving times | Name | Minutes spent driving
Ronald | 790
Clare | 410
Hansen | 600 | {
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"410",
"600"
],
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"Number of cups": null,
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"x": null,
"y": null
} | 4 | 2 | Find how many minutes Ronald spent driving.
790
Find how many minutes were spent driving in total.
790 + 410 + 600 = 1,800
Divide 790 by1,800.
\frac{790}{1,800}
Reduce the fraction.
\frac{790}{1,800} → \frac{79}{180}
\frac{79}{180} of minutes Ronald spent driving. | free_text | decimal_number | 7 | train |
A candy dispenser put various numbers of orange candies into bags. How many bags had exactly 90 orange candies? | null | 4 | bags | Orange candies per bag | Stem | Leaf
3 | 4
4 | 1, 4, 4, 6
5 | 6
6 | 3, 3, 4, 5, 6
7 | 0, 2, 5, 5
8 | 1, 1
9 | 0, 0, 0, 0 | {
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"7",
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"9"
],
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"Wednesday": null,
"Year": null,
"x": null,
"y": null
} | 8 | 2 | For the number 90, the stem is 9, and the leaf is 0. Find the row where the stem is 9. In that row, count all the leaves equal to 0.
You counted 4 leaves, which are blue in the stem-and-leaf plot above. 4 bags had exactly 90 orange candies. | free_text | integer_number | 5 | train |
Each field has 2 cows. How many cows are in 3 fields? | null | 6 | null | null | Number of fields | Number of cows
1 | 2
2 | 4
3 | ? | {
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"4",
"?"
],
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"2",
"3"
],
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} | 4 | 2 | Count by twos. Use the chart: there are 6 cows in 3 fields. | free_text | integer_number | 2 | train |
Look at the following schedule. Naomi just missed the 9.45 A.M. train at Richmond. What time is the next train? | [
"9:45 A.M.",
"11:45 A.M.",
"4:15 P.M.",
"10:00 A.M."
] | 10:00 A.M. | null | Train schedule | Richmond | 9:00 A.M. | 9:45 A.M. | 10:00 A.M. | 10:30 A.M.
Kingwood | 10:45 A.M. | 11:30 A.M. | 11:45 A.M. | 12:15 P.M.
Seaside | 11:15 A.M. | 12:00 P.M. | 12:15 P.M. | 12:45 P.M.
Westminster | 12:45 P.M. | 1:30 P.M. | 1:45 P.M. | 2:15 P.M.
Washington | 2:45 P.M. | 3:30 P.M. | 3:45 P.M. | 4:15 P.M.
Oakland | 3:15 P.M. | 4:00 P.M. | 4:15 P.M. | 4:45 P.M. | {
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"12:45 P.M.",
"2:15 P.M.",
"4:15 P.M.",
"4:45 P.M."
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"Number of cups": null,
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"Number of soccer fields": null,
"Number of students": null,
"Number of tables": null,
"Number of tickets": null,
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"Number of watermelons": null,
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"Price": null,
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"Quantity supplied": null,
"Record time (minutes)": null,
"Score": null,
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"Teacher": null,
"Thursday": null,
"Times eaten": null,
"Type": null,
"Vertically": null,
"Wednesday": null,
"Year": null,
"x": null,
"y": null
} | 6 | 5 | Find 9:45 A. M. in the row for Richmond.
Look for the next train in that row.
The next train is at 10:00 A. M. | multi_choice | extractive_text | 4 | train |
Employees at Layla's Movies tracked the number of movies that customers rented last month. How many customers rented a movie fewer than 3 times? | null | 30 | null | Renting movies last month | Number of times | Frequency
0 | 5
1 | 6
2 | 19
3 | 10
4 | 3 | {
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"Number of respondents": null,
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"Number of tables": null,
"Number of tickets": null,
"Number of times": [
"0",
"1",
"2",
"3",
"4"
],
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"Number of watermelons": null,
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"Wednesday": null,
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"x": null,
"y": null
} | 6 | 2 | Find the rows for 0, 1, and 2 times. Add the frequencies for these rows.
Add:
5 + 6 + 19 = 30
30 customers rented a movie fewer than 3 times. | free_text | integer_number | 7 | train |
Look at the following schedule. When does the badminton event begin? | [
"3:55 P.M.",
"2:55 P.M.",
"3:00 P.M.",
"1:20 P.M."
] | 1:20 P.M. | null | Summer Olympics schedule | Event | Begin | End
wrestling | 10:15 A.M. | 2:15 P.M.
track and field | 12:45 P.M. | 3:00 P.M.
badminton | 1:20 P.M. | 3:55 P.M.
volleyball | 2:55 P.M. | 5:15 P.M.
archery | 3:45 P.M. | 6:00 P.M. | {
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"y": null
} | 6 | 3 | Find the badminton event on the schedule. Find the beginning time for the badminton event.
badminton: 1:20 P. M. | multi_choice | extractive_text | 3 | train |
While writing a paper on making decisions in groups, Bridgette researched the size of a number of committees. What is the size of the largest committee? | null | 89 | members | Committee sizes (number of members) | Stem | Leaf
4 | 0, 1, 1, 3, 4, 8, 8
5 | 1, 3, 4
6 | 0, 1, 2, 2, 4, 5, 5, 7
7 | 8
8 | 3, 3, 3, 8, 9 | {
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"6",
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"y": null
} | 6 | 2 | Look at the last row of the stem-and-leaf plot. The last row has the highest stem. The stem for the last row is 8.
Now find the highest leaf in the last row. The highest leaf is 9.
The size of the largest committee has a stem of 8 and a leaf of 9. Write the stem first, then the leaf: 89.
The size of the largest committee is 89 members. | free_text | integer_number | 5 | train |
Liam's class paid attention to how many bottles each student collected for their recycling project. What is the range of the numbers? | null | 15 | null | Bottles collected | Name | Number of bottles
Liam | 100
Zeke | 86
Josiah | 97
Brooke | 85
Pablo | 95
Regan | 92 | {
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"Thursday": null,
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"Wednesday": null,
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"x": null,
"y": null
} | 7 | 2 | Read the numbers from the table.
100, 86, 97, 85, 95, 92
First, find the greatest number. The greatest number is 100.
Next, find the least number. The least number is 85.
Subtract the least number from the greatest number:
100 − 85 = 15
The range is 15. | free_text | integer_number | 5 | train |
An Italian restaurant monitored the number of times its regular customers ate pizza last month. How many customers ate pizza at least 1 time? | null | 65 | null | Eating pizza last month | Times eaten | Frequency
0 | 1
1 | 14
2 | 13
3 | 12
4 | 8
5 | 18 | {
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"1",
"2",
"3",
"4",
"5"
],
"Type": null,
"Vertically": null,
"Wednesday": null,
"Year": null,
"x": null,
"y": null
} | 7 | 2 | Find the rows for 1, 2, 3, 4, and 5 times. Add the frequencies for these rows.
Add:
14 + 13 + 12 + 8 + 18 = 65
65 customers ate pizza at least 1 time. | free_text | integer_number | 8 | train |
Look at the following schedule. When does family ice skating begin? | [
"2:20 P.M.",
"9:50 A.M.",
"1:20 P.M.",
"3:30 P.M."
] | 1:20 P.M. | null | Winter lodge schedule | Activity | Begin | End
advanced ski class | 8:40 A.M. | 9:45 A.M.
figure skating | 9:50 A.M. | 11:15 A.M.
beginning ski class | 11:20 A.M. | 12:45 P.M.
family ice skating | 1:20 P.M. | 2:15 P.M.
cross-country ski tour | 2:20 P.M. | 2:55 P.M.
intermediate ski class | 3:30 P.M. | 4:45 P.M. | {
"": null,
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"advanced ski class",
"figure skating",
"beginning ski class",
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"cross-country ski tour",
"intermediate ski class"
],
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"Number of students": null,
"Number of tables": null,
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"Type": null,
"Vertically": null,
"Wednesday": null,
"Year": null,
"x": null,
"y": null
} | 7 | 3 | Find family ice skating on the schedule. Find the beginning time for family ice skating.
family ice skating: 1:20 P. M. | multi_choice | extractive_text | 3 | train |
Mrs. McKenzie, the science teacher, informed her students of their scores on Monday's test. What is the lowest score? | null | 13 | points | Science test scores | Stem | Leaf
1 | 3, 4, 5
2 | 9
3 | 2, 6
4 | 6, 9
5 | 1, 9
6 | 2, 3, 5, 9
7 | 0, 3, 9
8 | 0, 4, 5, 6, 9
9 | 0 | {
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"6, 9",
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"2",
"3",
"4",
"5",
"6",
"7",
"8",
"9"
],
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"x": null,
"y": null
} | 10 | 2 | Look at the first row of the stem-and-leaf plot. The first row has the lowest stem. The stem for the first row is 1.
Now find the lowest leaf in the first row. The lowest leaf is 3.
The lowest score has a stem of 1 and a leaf of 3. Write the stem first, then the leaf: 13.
The lowest score is 13 points. | free_text | integer_number | 5 | train |
Look at the following schedule. Which event ends at 4.30 P.M.? | [
"javelin throw",
"steeplechase",
"men's relay",
"pole vault"
] | steeplechase | null | Track meet schedule | Event | Begin | End
hurdles | 11:20 A.M. | 11:35 A.M.
javelin throw | 11:45 A.M. | 12:35 P.M.
triple jump | 12:50 P.M. | 1:25 P.M.
long jump | 1:30 P.M. | 2:05 P.M.
shot put | 2:20 P.M. | 3:00 P.M.
men's relay | 3:10 P.M. | 3:30 P.M.
pole vault | 3:40 P.M. | 3:50 P.M.
steeplechase | 4:05 P.M. | 4:30 P.M.
women's relay | 4:35 P.M. | 5:35 P.M.
high jump | 5:45 P.M. | 6:25 P.M. | {
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} | 11 | 3 | Find 4:30 P. M. on the schedule. The steeplechase ends at 4:30 P. M. | multi_choice | extractive_text | 3 | train |
How much money does Beth need to buy 5 scuba-diving adventure packages? | null | 3,705 | $ | null | deep-sea fishing package | $858.00
scuba-diving adventure package | $741.00
ski trip package | $646.00
surfing adventure package | $275.00 | {
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} | 4 | 2 | Find the total cost of 5 scuba-diving adventure packages by multiplying 5 times the price of a scuba-diving adventure package.
$741.00 × 5 = $3,705.00
Beth needs $3,705.00. | free_text | integer_number | 8 | train |
Some students compared how many clubs they belong to. What is the mode of the numbers? | null | 8 | null | Clubs | Name | Number of clubs
Diana | 8
Jaden | 8
Oliver | 10
Heather | 8
Bryan | 10
Marco | 5 | {
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} | 7 | 2 | Read the numbers from the table.
8, 8, 10, 8, 10, 5
First, arrange the numbers from least to greatest:
5, 8, 8, 8, 10, 10
Now count how many times each number appears.
5 appears 1 time.
8 appears 3 times.
10 appears 2 times.
The number that appears most often is 8.
The mode is 8. | free_text | integer_number | 7 | train |
A flight attendant was counting the number of passengers present to see if any upgrades could be offered. The flight attendant's list contained passengers' Frequent Flyer status as well as number of bags checked. What is the probability that a randomly selected passenger has silver status and 1 checked bag? Simplify any fractions. | null | 3/16 | null | null | | 0 checked bags | 1 checked bag
Bronze status | 3 | 7
Silver status | 3 | 3 | {
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} | 3 | 3 | Let A be the event "the passenger has silver status" and B be the event "the passenger has 1 checked bag".
To find the probability that a passenger has silver status and 1 checked bag, first identify the sample space and the event.
The outcomes in the sample space are the different passengers. Each passenger is equally likely to be selected, so this is a uniform probability model.
The event is A and B, "the passenger has silver status and 1 checked bag".
Since this is a uniform probability model, count the number of outcomes in the event A and B and count the total number of outcomes. Then, divide them to compute the probability.
Find the number of outcomes in the event A and B.
A and B is the event "the passenger has silver status and 1 checked bag", so look at the table to see how many passengers have silver status and 1 checked bag.
The number of passengers who have silver status and 1 checked bag is 3.
Find the total number of outcomes.
Add all the numbers in the table to find the total number of passengers.
3 + 3 + 7 + 3 = 16
Find P(A and B).
Since all outcomes are equally likely, the probability of event A and B is the number of outcomes in event A and B divided by the total number of outcomes.
P(A and B) = \frac{# of outcomes in A and B}{total # of outcomes}
= \frac{3}{16}
The probability that a passenger has silver status and 1 checked bag is \frac{3}{16}. | free_text | decimal_number | 8 | train |
A survey was conducted to learn people's chocolate preferences. What fraction of the respondents preferred white chocolate? Simplify your answer. | null | 29/43 | null | Chocolate preferences | Type | Number of respondents
White chocolate | 870
Milk chocolate | 280
Dark chocolate | 140 | {
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} | 4 | 2 | Find how many respondents preferred white chocolate.
870
Find how many people responded in total.
870 + 280 + 140 = 1,290
Divide 870 by1,290.
\frac{870}{1,290}
Reduce the fraction.
\frac{870}{1,290} → \frac{29}{43}
\frac{29}{43} of respondents preferred white chocolate. | free_text | decimal_number | 7 | train |
The parks department compared how many soccer fields there are at each park. What is the mean of the numbers? | null | 5 | null | Soccer fields | Park | Number of soccer fields
Juniper Park | 8
Windy Hill Park | 4
Middle Park | 4
Crane Park | 5
Elmhurst Park | 7
Lighthouse Park | 2 | {
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} | 7 | 2 | Read the numbers from the table.
8, 4, 4, 5, 7, 2
First, count how many numbers are in the group.
There are 6 numbers.
Now add all the numbers together:
8 + 4 + 4 + 5 + 7 + 2 = 30
Now divide the sum by the number of numbers:
30 ÷ 6 = 5
The mean is 5. | free_text | integer_number | 5 | train |
An employee at the craft store counted the number of red buttons in each bag of mixed buttons. How many bags had at least 36 red buttons? | null | 21 | bags | Red buttons per bag | Stem | Leaf
3 | 0, 1, 7, 7
4 | 3, 8
5 | 4, 5, 9
6 | 0, 3, 8
7 | 3, 5, 6, 7, 7
8 | 0, 1, 5, 7
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} | 8 | 2 | Find the row with stem 3. Count all the leaves greater than or equal to 6.
Count all the leaves in the rows with stems 4, 5, 6, 7, 8, and 9.
You counted 21 leaves, which are blue in the stem-and-leaf plots above. 21 bags had at least 36 red buttons. | free_text | integer_number | 7 | train |
A stock broker followed the stock prices of a certain set of companies. How much did Watson and Partners's stock cost on Thursday? | null | 4 | $ | Stock prices | Company | Wednesday | Thursday
Watson and Partners | $1 | $4
Thompson Corporation | $12 | $3
Computer Data Company | $15 | $20 | {
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} | 4 | 3 | First, find the row for Watson and Partners. Then find the number in the Thursday column.
This number is $4.00. Watson and Partners's stock cost $4 on Thursday. | free_text | integer_number | 5 | train |
How much more does a motorcycle cost than a kayak? | null | 175 | $ | null | sailboat | $904.00
kayak | $470.00
snowmobile | $898.00
motorcycle | $645.00 | {
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} | 4 | 2 | Subtract the price of a kayak from the price of a motorcycle.
$645.00 - $470.00 = $175.00
A motorcycle costs $175.00 more than a kayak. | free_text | integer_number | 4 | train |
Jon just returned from a spring break volunteer trip. He is shopping for a photo album that will showcase his photos from the trip. The albums range in photo capacity and orientation. What is the probability that a randomly selected photo album holds exactly 50 photos and is oriented horizontally? Simplify any fractions. | null | 1/5 | null | null | | Horizontally | Vertically
50 photos | 2 | 4
100 photos | 2 | 2 | {
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} | 3 | 3 | Let A be the event "the photo album holds exactly 50 photos" and B be the event "the photo album is oriented horizontally".
To find the probability that a photo album holds exactly 50 photos and is oriented horizontally, first identify the sample space and the event.
The outcomes in the sample space are the different photo albums. Each photo album is equally likely to be selected, so this is a uniform probability model.
The event is A and B, "the photo album holds exactly 50 photos and is oriented horizontally".
Since this is a uniform probability model, count the number of outcomes in the event A and B and count the total number of outcomes. Then, divide them to compute the probability.
Find the number of outcomes in the event A and B.
A and B is the event "the photo album holds exactly 50 photos and is oriented horizontally", so look at the table to see how many photo albums hold exactly 50 photos and are oriented horizontally.
The number of photo albums that hold exactly 50 photos and are oriented horizontally is 2.
Find the total number of outcomes.
Add all the numbers in the table to find the total number of photo albums.
2 + 2 + 4 + 2 = 10
Find P(A and B).
Since all outcomes are equally likely, the probability of event A and B is the number of outcomes in event A and B divided by the total number of outcomes.
P(A and B) = \frac{# of outcomes in A and B}{total # of outcomes}
= \frac{2}{10}
= \frac{1}{5}
The probability that a photo album holds exactly 50 photos and is oriented horizontally is \frac{1}{5}. | free_text | decimal_number | 8 | train |
A bakery recorded how many cupcakes it sold in the past 6 days. What is the range of the numbers? | null | 6 | null | Cupcakes sold | Day | Number of cupcakes
Monday | 92
Tuesday | 92
Wednesday | 96
Thursday | 93
Friday | 90
Saturday | 91 | {
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} | 7 | 2 | Read the numbers from the table.
92, 92, 96, 93, 90, 91
First, find the greatest number. The greatest number is 96.
Next, find the least number. The least number is 90.
Subtract the least number from the greatest number:
96 − 90 = 6
The range is 6. | free_text | integer_number | 5 | train |
Each branch has 10 apples. How many apples are on 6 branches? | null | 60 | apples | null | Number of branches | Number of apples
1 | 10
2 | 20
3 | 30
4 | 40
5 | 50
6 | ? | {
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} | 7 | 2 | Count by tens. Use the chart: there are 60 apples on 6 branches. | free_text | integer_number | 1 | train |
An actor was informed how many fan letters he received each day. On which day were the fewest fan letters received? | [
"Monday",
"Tuesday",
"Wednesday",
"Thursday"
] | Thursday | null | Fan letters received | Day | Number of fan letters
Monday | 58
Tuesday | 56
Wednesday | 59
Thursday | 51 | {
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} | 5 | 2 | Find the least number in the table. Remember to compare the numbers starting with the highest place value. The least number is 51.
Now find the corresponding day. Thursday corresponds to 51. | multi_choice | extractive_text | 2 | train |
Desmond bought 2 pounds of beef sauce and 5 pounds of marinara sauce. How much did he spend? | null | 49 | $ | null | tomato sauce | $4 per pound
marinara sauce | $7 per pound
alfredo sauce | $6 per pound
pesto sauce | $5 per pound
chicken sauce | $6 per pound
beef sauce | $7 per pound | {
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} | 6 | 2 | Find the cost of the beef sauce. Multiply:
$7 × 2 = $14
Find the cost of the marinara sauce. Multiply:
$7 × 5 = $35
Now find the total cost by adding:
$14 + $35 = $49
He spent $49. | free_text | integer_number | 7 | train |
How much more does a box of tissues cost than a box of breath mints? | null | 0.19 | $ | null | box of breath mints | $0.77
barrette | $0.83
lip balm | $0.87
nail file | $0.85
box of tissues | $0.96 | {
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} | 5 | 2 | Subtract the price of a box of breath mints from the price of a box of tissues.
$0.96 - $0.77 = $0.19
A box of tissues costs $0.19 more than a box of breath mints. | free_text | decimal_number | 5 | train |
A game show viewer monitors how often a wheel numbered 1 through 5 stops at each number. Which number was spun the fewest times? | null | 3 | null | Spinning a wheel numbered 1 through 5 | Number spun | Frequency
1 | 3
2 | 9
3 | 0
4 | 1
5 | 13 | {
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} | 6 | 2 | Look at the frequency column. Find the least frequency. The least frequency is 0, which is in the row for 3. 3 was spun the fewest times. | free_text | integer_number | 8 | train |
Melissa buys 4 pounds of Anaheim peppers. How much does she spend? | null | 5.52 | $ | null | chili peppers | $1.10 per pound
purple bell peppers | $2.31 per pound
Anaheim peppers | $1.38 per pound
habanero peppers | $2.10 per pound | {
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} | 4 | 2 | Find the cost of the Anaheim peppers. Multiply the price per pound by the number of pounds.
$1.38 × 4 = $5.52
She spends $5.52. | free_text | decimal_number | 7 | train |
A coffee shop monitored the number of cups of coffee sold each day. What is the mean of the numbers? | null | 18 | null | Cups of coffee sold | Day | Number of cups
Saturday | 16
Sunday | 14
Monday | 16
Tuesday | 21
Wednesday | 23 | {
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} | 6 | 2 | Read the numbers from the table.
16, 14, 16, 21, 23
First, count how many numbers are in the group.
There are 5 numbers.
Now add all the numbers together:
16 + 14 + 16 + 21 + 23 = 90
Now divide the sum by the number of numbers:
90 ÷ 5 = 18
The mean is 18. | free_text | integer_number | 5 | train |
Kathleen counted all the beads in each necklace at the jewelry store where she works. What is the smallest number of beads? | null | 10 | beads | Beads per necklace | Stem | Leaf
1 | 0
2 | 2, 3
3 | 5
4 | 1, 2, 3, 7
5 | 1, 4, 6, 7
6 | 5
7 |
8 | 6
9 | 0 | {
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"4",
"5",
"6",
"7",
"8",
"9"
],
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"y": null
} | 10 | 2 | Look at the first row of the stem-and-leaf plot. The first row has the lowest stem. The stem for the first row is 1.
Now find the lowest leaf in the first row. The lowest leaf is 0.
The smallest number of beads has a stem of 1 and a leaf of 0. Write the stem first, then the leaf: 10.
The smallest number of beads is 10 beads. | free_text | integer_number | 8 | train |
How much more does a colorful pinwheel cost than a small teddy bear? | null | 0.71 | $ | null | red kazoo | $0.27
small teddy bear | $0.25
colorful pinwheel | $0.96
plastic horse | $0.18
tiny doll | $0.32 | {
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"Wednesday": null,
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"x": null,
"y": null
} | 5 | 2 | Subtract the price of a small teddy bear from the price of a colorful pinwheel.
$0.96 - $0.25 = $0.71
A colorful pinwheel costs $0.71 more than a small teddy bear. | free_text | decimal_number | 7 | train |
Each year the Oakland School District publishes its annual budget, which includes information on the sports program's per-student spending. According to the table, what was the rate of change between 2010 and 2011? | null | 2 | $, per year | Oakland School District sports budget | Year | Per-student budget
2010 | $34
2011 | $36
2012 | $31
2013 | $28
2014 | $26 | {
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"$31",
"$28",
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],
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"Year": [
"2010",
"2011",
"2012",
"2013",
"2014"
],
"x": null,
"y": null
} | 6 | 2 | Plug the numbers into the formula for rate of change and simplify.
Rate of change
= \frac{change in value}{change in time}
= \frac{$36 - $34}{2011 - 2010}
= \frac{$36 - $34}{1 year}
= \frac{$2}{1 year}
= $2 per year
The rate of change between 2010 and 2011 was $2 per year. | free_text | integer_number | 7 | train |
A game show program recorded the scores of its contestants. Which score did the fewest people receive? | null | 9 | null | Scores on a quiz show | Score | Frequency
5 | 17
6 | 14
7 | 3
8 | 10
9 | 1
10 | 8 | {
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"9",
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"Thursday": null,
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"Type": null,
"Vertically": null,
"Wednesday": null,
"Year": null,
"x": null,
"y": null
} | 7 | 2 | Look at the frequency column. Find the least frequency. The least frequency is 1, which is in the row for 9. The fewest people scored 9. | free_text | integer_number | 8 | train |
Spencer buys 1/2 of a pound of dark chocolate chips. How much does he spend? | null | 2 | $ | null | peanut butter chips | $8/pound
milk chocolate chips | $7/pound
dark chocolate chips | $4/pound
white chocolate chips | $6/pound | {
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"x": null,
"y": null
} | 4 | 2 | Find the cost of the dark chocolate chips. Multiply the price per pound by the number of pounds.
$4 × \frac{1}{2} = $4 × 0.5 = $2
He spends $2. | free_text | integer_number | 6 | train |
Each van has 2 students. How many students are in 4 vans? | null | 8 | students | null | Number of vans | Number of students
1 | 2
2 | 4
3 | 6
4 | ? | {
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"4",
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"?"
],
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"Number of vans": [
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"2",
"3",
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"x": null,
"y": null
} | 5 | 2 | Count by twos. Use the chart: there are 8 students in 4 vans. | free_text | integer_number | 1 | train |
How much more does a can of pears cost than a can of cranberry sauce? | null | 0.01 | $ | null | can of cranberry sauce | $0.95
can of corn | $0.96
can of pears | $0.96
can of peaches | $0.55
can of tuna fish | $0.46 | {
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"Wednesday": null,
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"x": null,
"y": null
} | 5 | 2 | Subtract the price of a can of cranberry sauce from the price of a can of pears.
$0.96 - $0.95 = $0.01
A can of pears costs $0.01 more than a can of cranberry sauce. | free_text | decimal_number | 7 | train |
Look at the following schedule. Which activity begins at 8.35 P.M.? | [
"dog show",
"livestock exhibition",
"cooking demonstration",
"milking demonstration"
] | dog show | null | County fair schedule | Activity | Begin | End
rodeo competition | 7:05 A.M. | 12:05 P.M.
livestock exhibition | 11:55 A.M. | 4:15 P.M.
milking demonstration | 3:50 P.M. | 7:20 P.M.
cooking demonstration | 6:40 P.M. | 9:15 P.M.
dog show | 8:35 P.M. | 10:50 P.M. | {
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],
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"x": null,
"y": null
} | 6 | 3 | Find 8:35 P. M. on the schedule. The dog show begins at 8:35 P. M. | multi_choice | extractive_text | 3 | train |
A sports fan decided to examine the pattern of medals won by certain countries at several Olympic games. In 2008, which of the countries shown won the most medals? | [
"Sweden",
"Brazil",
"Romania"
] | Brazil | null | Olympic medals | Country | 2004 | 2008
Brazil | 10 | 15
Romania | 19 | 8
Sweden | 7 | 5 | {
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"x": null,
"y": null
} | 4 | 3 | Look at the numbers in the 2008 column. Find the greatest number in this column.
The greatest number is 15, which is in the Brazil row. In 2008, Brazil won the most medals. | multi_choice | extractive_text | 5 | train |
Scott has $0.09. Does he have enough to buy a peppermint candy and a sour apple candy? | [
"yes",
"no"
] | no | null | null | peppermint candy | $0.03
gum drop | $0.05
cinnamon candy | $0.08
sour apple candy | $0.07
gummy bear | $0.05 | {
"": null,
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"Column 1": [
"peppermint candy",
"gum drop",
"cinnamon candy",
"sour apple candy",
"gummy bear"
],
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"$0.05"
],
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"x": null,
"y": null
} | 5 | 2 | Add the price of a peppermint candy and the price of a sour apple candy:
$0.03 + $0.07 = $0.10
$0.10 is more than $0.09. Scott does not have enough money. | multi_choice | boolean_text | 3 | train |
In hopes of raising more funds for arts education, some parents in the Yardley School District publicized the current per-student arts education budget. According to the table, what was the rate of change between 2019 and 2020? | null | 11 | $, per year | Yardley arts education budget | Year | Per-student budget
2017 | $24
2018 | $33
2019 | $24
2020 | $35
2021 | $33 | {
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} | 6 | 2 | Plug the numbers into the formula for rate of change and simplify.
Rate of change
= \frac{change in value}{change in time}
= \frac{$35 - $24}{2020 - 2019}
= \frac{$35 - $24}{1 year}
= \frac{$11}{1 year}
= $11 per year
The rate of change between 2019 and 2020 was $11 per year. | free_text | integer_number | 7 | train |
Each bucket has 2 red blocks. How many red blocks are in 5 buckets? | null | 10 | null | null | Number of buckets | Number of red blocks
1 | 2
2 | 4
3 | 6
4 | 8
5 | ? | {
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} | 6 | 2 | Count by twos. Use the chart: there are 10 red blocks in 5 buckets. | free_text | integer_number | 2 | train |
Rosanne kept a tally of the number of emails she received each day for a week. According to the table, what was the rate of change between Friday and Saturday? | null | -1 | emails per day | Emails Rosanne received | Day | Emails
Tuesday | 3
Wednesday | 3
Thursday | 7
Friday | 10
Saturday | 9 | {
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} | 6 | 2 | Plug the numbers into the formula for rate of change and simplify.
Rate of change
= \frac{change in value}{change in time}
= \frac{9 emails - 10 emails}{1 day}
= \frac{-1 emails}{1 day}
= -1 emails per day
The rate of change between Friday and Saturday was - 1 emails per day. | free_text | integer_number | 7 | train |
The transportation company tracked the number of train tickets sold in the past 3 days. How many more tickets were sold on Tuesday than on Wednesday? | null | 353 | tickets | Train tickets sold | Day | Number of tickets
Monday | 877
Tuesday | 659
Wednesday | 306 | {
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"659",
"306"
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"y": null
} | 4 | 2 | Find the numbers in the table.
Tuesday: 659
Wednesday: 306
Now subtract: 659 - 306 = 353.
353 more tickets were sold on Tuesday | free_text | integer_number | 3 | train |
A farmer recalled how many watermelons were harvested in the past 4 days. On which day were the fewest watermelons harvested? | [
"Friday",
"Saturday",
"Sunday",
"Monday"
] | Monday | null | Watermelons harvested | Day | Number of watermelons
Friday | 34
Saturday | 38
Sunday | 32
Monday | 31 | {
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} | 5 | 2 | Find the least number in the table. Remember to compare the numbers starting with the highest place value. The least number is 31.
Now find the corresponding day. Monday corresponds to 31. | multi_choice | extractive_text | 2 | train |
A theme park developer recorded the number of people who visited the local water park last summer. How many people went to the water park fewer than 4 times? | null | 23 | null | Going to the water park last summer | Number of trips | Frequency
1 | 11
2 | 4
3 | 8
4 | 12
5 | 14 | {
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} | 6 | 2 | Find the rows for 1, 2, and 3 times. Add the frequencies for these rows.
Add:
11 + 4 + 8 = 23
23 people went to the water park fewer than 4 times. | free_text | integer_number | 8 | train |
An actor was informed how many fan letters he received each day. What is the range of the numbers? | null | 6 | null | Fan letters received | Day | Number of fan letters
Saturday | 3
Monday | 8
Tuesday | 4
Wednesday | 3
Thursday | 9 | {
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} | 6 | 2 | Read the numbers from the table.
3, 8, 4, 3, 9
First, find the greatest number. The greatest number is 9.
Next, find the least number. The least number is 3.
Subtract the least number from the greatest number:
9 − 3 = 6
The range is 6. | free_text | integer_number | 8 | train |
If Lamar buys 4 pounds of nails, how much will he spend? | null | 5.80 | $ | null | standard washers | $4.64/lb
rivets | $1.42/lb
nuts | $1.13/lb
nails | $1.45/lb | {
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"y": null
} | 4 | 2 | Find the cost of the nails. Multiply the price per pound by the number of pounds.
$1.45 × 4 = $5.80
He will spend $5.80. | free_text | decimal_number | 8 | train |
How much more does a photo album cost than a scrapbook? | null | 3 | $ | null | dog calendar | $14
math book | $17
photo album | $14
scrapbook | $11 | {
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"y": null
} | 4 | 2 | Subtract the price of a scrapbook from the price of a photo album.
$14 - $11 = $3
A photo album costs $3 more than a scrapbook. | free_text | integer_number | 4 | train |
Each gym locker has 10 pairs of shorts. How many pairs of shorts are in 5 gym lockers? | null | 50 | pairs of shorts | null | Number of gym lockers | Number of pairs of shorts
1 | 10
2 | 20
3 | 30
4 | 40
5 | ? | {
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} | 6 | 2 | Count by tens. Use the chart: there are 50 pairs of shorts in 5 gym lockers. | free_text | integer_number | 1 | train |
Elena purchased 3+1/2 pounds of blueberry muffin mix. What was the total cost? | null | 7 | $ | null | apple muffin mix | $1/pound
blueberry muffin mix | $2/pound
chocolate chip muffin mix | $2/pound
pumpkin muffin mix | $1/pound
bran muffin mix | $2/pound
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} | 6 | 2 | Find the cost of the blueberry muffin mix. Multiply the price per pound by the number of pounds.
$2 × 3\frac{1}{2} = $2 × 3.5 = $7
The total cost was $7. | free_text | integer_number | 6 | train |
Middletown will decide whether to extend its public pool's hours by looking at the number of times its residents visited the pool last month. How many people went swimming more than 3 times? | null | 11 | null | Going swimming last month | Number of times | Frequency
1 | 6
2 | 13
3 | 12
4 | 7
5 | 4 | {
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} | 6 | 2 | Find the rows for 4 and 5 times. Add the frequencies for these rows.
Add:
7 + 4 = 11
11 people went swimming more than 3 times. | free_text | integer_number | 7 | train |
At a candy factory, butterscotch candies were packaged into bags of different sizes. How many bags had fewer than 60 butterscotch candies? | null | 14 | bags | Butterscotch candies per bag | Stem | Leaf
1 | 5, 7, 8, 8
2 | 1, 4, 9
3 | 9
4 | 2
5 | 1, 2, 3, 3, 5
6 | 1, 3, 3, 3, 4, 5, 6, 6, 7, 9 | {
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} | 7 | 2 | Count all the leaves in the rows with stems 1, 2, 3, 4, and 5.
You counted 14 leaves, which are blue in the stem-and-leaf plot above. 14 bags had fewer than 60 butterscotch candies. | free_text | integer_number | 8 | train |
Jonah has $14,197. Does he have enough to buy a peanut cart and a pretzel stand? | [
"yes",
"no"
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funnel cake stand | $5,385
popsicle stand | $5,384
shaved ice cart | $9,831
peanut cart | $5,199
pretzel stand | $9,745 | {
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} | 6 | 2 | Add the price of a peanut cart and the price of a pretzel stand:
$5,199 + $9,745 = $14,944
$14,944 is more than $14,197. Jonah does not have enough money. | multi_choice | boolean_text | 4 | train |
Troy wrote down how many minutes of TV he watched over the past 5 days. How many minutes in total did Troy watch on Monday and Thursday? | null | 287 | minutes | Minutes of TV watched | Day | Minutes
Monday | 131
Tuesday | 135
Wednesday | 113
Thursday | 156
Friday | 156 | {
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} | 6 | 2 | Find the numbers in the table.
Monday: 131
Thursday: 156
Now add: 131 + 156 = 287.
Troy watched 287 minutes of TV on Monday and Thursday. | free_text | integer_number | 3 | train |
Employees at Elise's Movies tracked the number of movies that customers rented last month. How many customers rented a movie at least 2 times? | null | 11 | null | Renting movies last month | Number of times | Frequency
0 | 16
1 | 18
2 | 9
3 | 2 | {
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} | 5 | 2 | Find the rows for 2 and 3 times. Add the frequencies for these rows.
Add:
9 + 2 = 11
11 customers rented a movie at least 2 times. | free_text | integer_number | 8 | train |
Dale wants to save up some money to buy a new smartphone, so he babysits on the weekends. There is a proportional relationship between the time Dale spends babysitting (in hours), x, and the amount of money he earns babysitting (in dollars), y. What is the constant of proportionality? Write your answer as a whole number or decimal. | null | 5 | dollars per hour | x (hours) y (dollars) | 1 | $5
2 | $10
3 | $15
4 | $20 | {
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} | 4 | 2 | To find the constant of proportionality, calculate the ratio of y to x.
5 / 1 = 5
10 / 2 = 5
15 / 3 = 5
20 / 4 = 5
The ratio for each pair of x- and y-values is 5. So, the variables have a proportional relationship.
So, the constant of proportionality is 5 dollars per hour. | free_text | integer_number | 7 | train |
Each year, the campers at Meg's summer camp try to set that summer's record for finishing the obstacle course as quickly as possible. According to the table, what was the rate of change between 2019 and 2020? | null | 5 | minutes per year | Record obstacle course completion times | Year | Record time (minutes)
2016 | 21
2017 | 21
2018 | 22
2019 | 23
2020 | 28 | {
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} | 6 | 2 | Plug the numbers into the formula for rate of change and simplify.
Rate of change
= \frac{change in value}{change in time}
= \frac{28 minutes - 23 minutes}{2020 - 2019}
= \frac{28 minutes - 23 minutes}{1 year}
= \frac{5 minutes}{1 year}
= 5 minutes per year
The rate of change between 2019 and 2020 was 5 minutes per year. | free_text | integer_number | 8 | train |
The table shows a function. Is the function linear or nonlinear? | [
"linear",
"nonlinear"
] | linear | null | null | x | y
8 | 0
9 | 8
10 | 16 | {
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"10"
],
"y": [
"0",
"8",
"16"
]
} | 4 | 2 | To determine whether the function is linear or nonlinear, see whether it has a constant rate of change.
Pick the points in any two rows of the table and calculate the rate of change between them. The first two rows are a good place to start.
Call the values in the first row x1 and y1. Call the values in the second row x2 and y2.
Rate of change = \frac{y2 - y1}{x2 - x1}
= \frac{8 - 0}{9 - 8}
= \frac{8}{1}
= 8
Now pick any other two rows and calculate the rate of change between them.
Call the values in the second row x1 and y1. Call the values in the third row x2 and y2.
Rate of change = \frac{y2 - y1}{x2 - x1}
= \frac{16 - 8}{10 - 9}
= \frac{8}{1}
= 8
The two rates of change are the same.
If you checked the rate of change between rows 1 and 3, you would find that it is also 8.
This means the rate of change is the same for each pair of points. So, the function has a constant rate of change.
The function is linear. | multi_choice | boolean_text | 8 | train |
A girl compared the ages of her cousins. What is the median of the numbers? | null | 12 | null | Ages of cousins | Name | Age (years)
Fernando | 10
Ken | 6
Camilla | 15
Riley | 9
Herman | 13
Joe | 12
Bonnie | 19 | {
"": null,
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"10",
"6",
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"19"
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"Thursday": null,
"Times eaten": null,
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"Wednesday": null,
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"x": null,
"y": null
} | 8 | 2 | Read the numbers from the table.
10, 6, 15, 9, 13, 12, 19
First, arrange the numbers from least to greatest:
6, 9, 10, 12, 13, 15, 19
Now find the number in the middle.
6, 9, 10, 12, 13, 15, 19
The number in the middle is 12.
The median is 12. | free_text | integer_number | 5 | train |
Look at the following schedule. Which event ends at 4.20 P.M.? | [
"men's volleyball game",
"women's basketball game",
"women's volleyball game",
"rugby match"
] | women's volleyball game | null | University sports schedule | Event | Begin | End
men's volleyball game | 12:45 P.M. | 2:05 P.M.
women's basketball game | 1:05 P.M. | 3:45 P.M.
women's volleyball game | 3:10 P.M. | 4:20 P.M.
diving meet | 3:40 P.M. | 5:05 P.M.
swim meet | 4:55 P.M. | 6:30 P.M.
rugby match | 5:55 P.M. | 9:15 P.M. | {
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"April": null,
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"12:45 P.M.",
"1:05 P.M.",
"3:10 P.M.",
"3:40 P.M.",
"4:55 P.M.",
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"Type": null,
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"Wednesday": null,
"Year": null,
"x": null,
"y": null
} | 7 | 3 | Find 4:20 P. M. on the schedule. The women's volleyball game ends at 4:20 P. M. | multi_choice | extractive_text | 3 | train |
The parks department compared how many soccer fields there are at each park. What is the range of the numbers? | null | 9 | null | Soccer fields | Park | Number of soccer fields
Middle Park | 1
Windy Hill Park | 2
Juniper Park | 4
Canyon Park | 8
Elmhurst Park | 5
Madison Park | 7
Moon Park | 10
Crane Park | 8 | {
"": null,
"Activity": null,
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"Number of shells": null,
"Number of soccer fields": [
"1",
"2",
"4",
"8",
"5",
"7",
"10",
"8"
],
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"Number of tickets": null,
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"Number of watermelons": null,
"Number spun": null,
"Park": [
"Middle Park",
"Windy Hill Park",
"Juniper Park",
"Canyon Park",
"Elmhurst Park",
"Madison Park",
"Moon Park",
"Crane Park"
],
"Pay period": null,
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"Thursday": null,
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"Wednesday": null,
"Year": null,
"x": null,
"y": null
} | 9 | 2 | Read the numbers from the table.
1, 2, 4, 8, 5, 7, 10, 8
First, find the greatest number. The greatest number is 10.
Next, find the least number. The least number is 1.
Subtract the least number from the greatest number:
10 − 1 = 9
The range is 9. | free_text | integer_number | 5 | train |
A county agency recorded the money donated to several charitable causes over time. How much money was raised for parks in April? | null | 4 | $ | Donations received | Cause | March | April
Education | $12 | $7
Parks | $11 | $4
Hunger | $8 | $17 | {
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"April": [
"$7",
"$4",
"$17"
],
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"Education",
"Parks",
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],
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],
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"Number of pink highlighters": null,
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"Number of red blocks": null,
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"Thursday": null,
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"Wednesday": null,
"Year": null,
"x": null,
"y": null
} | 4 | 3 | First, find the row for parks. Then find the number in the April column.
This number is $4.00. $4 was raised for parks in April. | free_text | integer_number | 5 | train |
Look at the table. Then answer the question. At a price of $755, is there a shortage or a surplus? | [
"shortage",
"surplus"
] | shortage | null | null | Price | Quantity demanded | Quantity supplied
$615 | 17,000 | 8,800
$685 | 13,900 | 9,400
$755 | 10,800 | 10,000
$825 | 7,700 | 10,600
$895 | 4,600 | 11,200 | {
"": null,
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"Price": [
"$615",
"$685",
"$755",
"$825",
"$895"
],
"Quantity demanded": [
"17,000",
"13,900",
"10,800",
"7,700",
"4,600"
],
"Quantity supplied": [
"8,800",
"9,400",
"10,000",
"10,600",
"11,200"
],
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"x": null,
"y": null
} | 6 | 3 | At the price of $755, the quantity demanded is greater than the quantity supplied. There is not enough of the good or service for sale at that price. So, there is a shortage.
| multi_choice | boolean_text | 5 | train |
Some teachers compared how many students are in their classes. What is the mode of the numbers? | null | 30 | null | Class size | Teacher | Number of students
Mrs. King | 30
Miss Jones | 29
Mr. Clay | 29
Mrs. Novak | 30
Mrs. Truman | 30 | {
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"Number of cups": null,
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"Number of red blocks": null,
"Number of respondents": null,
"Number of shells": null,
"Number of soccer fields": null,
"Number of students": [
"30",
"29",
"29",
"30",
"30"
],
"Number of tables": null,
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"Record time (minutes)": null,
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"Teacher": [
"Mrs. King",
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"Mr. Clay",
"Mrs. Novak",
"Mrs. Truman"
],
"Thursday": null,
"Times eaten": null,
"Type": null,
"Vertically": null,
"Wednesday": null,
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"x": null,
"y": null
} | 6 | 2 | Read the numbers from the table.
30, 29, 29, 30, 30
First, arrange the numbers from least to greatest:
29, 29, 30, 30, 30
Now count how many times each number appears.
29 appears 2 times.
30 appears 3 times.
The number that appears most often is 30.
The mode is 30. | free_text | integer_number | 5 | train |
While looking through an almanac at the library, Destiny noticed some data showing the population density of various states. In 1990, which had fewer people per square mile, North Dakota or Montana? | [
"North Dakota",
"Montana"
] | Montana | null | Population per square mile | State | 1990 | 2000
Montana | 5 | 6
Nevada | 10 | 18
South Dakota | 9 | 10
New Mexico | 12 | 15
North Dakota | 9 | 9 | {
"": null,
"Activity": null,
"Age (years)": null,
"April": null,
"Arrive": null,
"Begin": null,
"Cause": null,
"Column 1": [
"State",
"Montana",
"Nevada",
"South Dakota",
"New Mexico",
"North Dakota"
],
"Column 2": [
"1990",
"5",
"10",
"9",
"12",
"9"
],
"Column 3": [
"2000",
"6",
"18",
"10",
"15",
"9"
],
"Column 4": null,
"Column 5": null,
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"Day": null,
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"Number of cans of food": null,
"Number of clubs": null,
"Number of cows": null,
"Number of cupcakes": null,
"Number of cups": null,
"Number of fan letters": null,
"Number of fields": null,
"Number of gym lockers": null,
"Number of pairs of shorts": null,
"Number of pink highlighters": null,
"Number of practices": null,
"Number of red blocks": null,
"Number of respondents": null,
"Number of shells": null,
"Number of soccer fields": null,
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"Wednesday": null,
"Year": null,
"x": null,
"y": null
} | 6 | 3 | Find the 1990 column. Compare the numbers in this column for North Dakota and Montana.
5 is less than 9. Montana had fewer people per square mile in 1990. | multi_choice | extractive_text | 4 | train |
Anthony has $9. Does he have enough to buy pasta with white sauce and steamed broccoli? | [
"yes",
"no"
] | no | null | null | pasta with white sauce | $9
pasta with tomato sauce | $7
steamed broccoli | $2
grilled eggplant | $6 | {
"": null,
"Activity": null,
"Age (years)": null,
"April": null,
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"Begin": null,
"Cause": null,
"Column 1": [
"pasta with white sauce",
"pasta with tomato sauce",
"steamed broccoli",
"grilled eggplant"
],
"Column 2": [
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"$2",
"$6"
],
"Column 3": null,
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"Thursday": null,
"Times eaten": null,
"Type": null,
"Vertically": null,
"Wednesday": null,
"Year": null,
"x": null,
"y": null
} | 4 | 2 | Add the price of pasta with white sauce and the price of steamed broccoli:
$9 + $2 = $11
$11 is more than $9. Anthony does not have enough money. | multi_choice | boolean_text | 3 | train |
Dr. Morrison, a pediatrician, weighed all the children who recently visited her office. How many children weighed exactly 41 pounds? | null | 1 | children | Children's weights (lbs) | Stem | Leaf
2 | 2, 5
3 | 4
4 | 1
5 | 0, 6 | {
"": null,
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],
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"Quantity supplied": null,
"Record time (minutes)": null,
"Score": null,
"Stem": [
"2",
"3",
"4",
"5"
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"Thursday": null,
"Times eaten": null,
"Type": null,
"Vertically": null,
"Wednesday": null,
"Year": null,
"x": null,
"y": null
} | 5 | 2 | For the number 41, the stem is 4, and the leaf is 1. Find the row where the stem is 4. In that row, count all the leaves equal to 1.
You counted 1 leaf, which is blue in the stem-and-leaf plot above. 1 child weighed exactly 41 pounds. | free_text | integer_number | 5 | train |
Alvin recalled how many minutes he had spent at theater rehearsal in the past 4 days. On which day did Alvin rehearse the least? | [
"Saturday",
"Sunday",
"Monday",
"Tuesday"
] | Tuesday | null | Minutes spent rehearsing | Day | Minutes
Saturday | 151
Sunday | 135
Monday | 153
Tuesday | 112 | {
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"153",
"112"
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"y": null
} | 5 | 2 | Find the least number in the table. Remember to compare the numbers starting with the highest place value. The least number is 112.
Now find the corresponding day. Tuesday corresponds to 112. | multi_choice | extractive_text | 2 | train |
Look at the table. Then answer the question. At a price of $1,020, is there a shortage or a surplus? | [
"shortage",
"surplus"
] | surplus | null | null | Price | Quantity demanded | Quantity supplied
$420 | 14,000 | 8,200
$620 | 11,200 | 9,800
$820 | 8,400 | 11,400
$1,020 | 5,600 | 13,000
$1,220 | 2,800 | 14,600 | {
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"Price": [
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"$820",
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"$1,220"
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"2,800"
],
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"y": null
} | 6 | 3 | At the price of $1,020, the quantity demanded is less than the quantity supplied. There is too much of the good or service for sale at that price. So, there is a surplus.
| multi_choice | boolean_text | 5 | train |
Malia looked over her calendar to see how many times she had soccer practice each month. What is the range of the numbers? | null | 6 | null | Soccer practice | Month | Number of practices
May | 5
June | 6
July | 9
August | 5
September | 9
October | 11
November | 10
March | 10 | {
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} | 9 | 2 | Read the numbers from the table.
5, 6, 9, 5, 9, 11, 10, 10
First, find the greatest number. The greatest number is 11.
Next, find the least number. The least number is 5.
Subtract the least number from the greatest number:
11 − 5 = 6
The range is 6. | free_text | integer_number | 5 | train |
Look at this table. Is this relation a function? | [
"yes",
"no"
] | no | null | null | x | y
18 | 18
19 | 3
18 | 5 | {
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"x": [
"18",
"19",
"18"
],
"y": [
"18",
"3",
"5"
]
} | 4 | 2 | Look at the x-values in the table.
The x-value 18 is paired with multiple y-values, so the relation is not a function. | multi_choice | boolean_text | 8 | train |
How much more does a silver necklace cost than a sapphire pendant? | null | 59 | $ | null | sapphire pendant | $815.00
emerald ring | $626.00
silver necklace | $874.00
sapphire ring | $782.00
topaz pendant | $950.00 | {
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"y": null
} | 5 | 2 | Subtract the price of a sapphire pendant from the price of a silver necklace.
$874.00 - $815.00 = $59.00
A silver necklace costs $59.00 more than a sapphire pendant. | free_text | integer_number | 5 | train |
The players on a quiz show received the following scores. Who had the lowest score? | [
"Bridgette",
"Darren",
"Emma",
"Jenna"
] | Bridgette | null | Quiz show scores | Name | Score
Bridgette | 41
Darren | 48
Emma | 42
Jenna | 49 | {
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"49"
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"y": null
} | 5 | 2 | Find the least number in the table. Remember to compare the numbers starting with the highest place value. The least number is 41.
Now find the corresponding name. Bridgette corresponds to 41. | multi_choice | extractive_text | 2 | train |
David owns five dogs and monitors how much food they eat in a month. What fraction of the food was eaten by Snowball? Simplify your answer. | null | 15/49 | null | Dog food consumption | Dog | Kilograms of food
Snowball | 45
Sparky | 20
Peanut | 45
Cocoa | 19
Blue | 18 | {
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} | 6 | 2 | Find how many kilograms of food were eaten by Snowball.
45
Find how many kilograms of food the dogs ate in total.
45 + 20 + 45 + 19 + 18 = 147
Divide 45 by147.
\frac{45}{147}
Reduce the fraction.
\frac{45}{147} → \frac{15}{49}
\frac{15}{49} of kilograms of food were eaten by Snowball. | free_text | decimal_number | 7 | train |
Michael entered his sister into their town's Smelly Shoe Competition. Michael observed contestants of all ages proudly strutting around wearing different kinds of smelly shoes. What is the probability that a randomly selected contestant is wearing tennis shoes and is 13 to 30 years old? Simplify any fractions. | null | 4/13 | null | null | | Under age 12 | 13 to 30 years old
Tennis shoes | 3 | 4
High heels | 3 | 3 | {
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} | 3 | 3 | Let A be the event "the contestant is wearing tennis shoes" and B be the event "the contestant is 13 to 30 years old".
To find the probability that a contestant is wearing tennis shoes and is 13 to 30 years old, first identify the sample space and the event.
The outcomes in the sample space are the different contestants. Each contestant is equally likely to be selected, so this is a uniform probability model.
The event is A and B, "the contestant is wearing tennis shoes and is 13 to 30 years old".
Since this is a uniform probability model, count the number of outcomes in the event A and B and count the total number of outcomes. Then, divide them to compute the probability.
Find the number of outcomes in the event A and B.
A and B is the event "the contestant is wearing tennis shoes and is 13 to 30 years old", so look at the table to see how many contestants are wearing tennis shoes and are 13 to 30 years old.
The number of contestants who are wearing tennis shoes and are 13 to 30 years old is 4.
Find the total number of outcomes.
Add all the numbers in the table to find the total number of contestants.
3 + 3 + 4 + 3 = 13
Find P(A and B).
Since all outcomes are equally likely, the probability of event A and B is the number of outcomes in event A and B divided by the total number of outcomes.
P(A and B) = \frac{# of outcomes in A and B}{total # of outcomes}
= \frac{4}{13}
The probability that a contestant is wearing tennis shoes and is 13 to 30 years old is \frac{4}{13}. | free_text | decimal_number | 8 | train |
Ms. Wong reported her students' scores on the most recent quiz. How many students scored at least 83 points? | null | 2 | students | Quiz scores | Stem | Leaf
2 | 0, 0, 1, 2, 2, 3, 8
3 | 1, 5, 6, 7
4 | 6
5 | 1, 7, 9
6 | 0, 8, 8
7 | 0, 0, 0
8 | 5
9 | 0 | {
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"Minutes spent driving": null,
"Month": null,
"Name": null,
"Number of apples": null,
"Number of bottles": null,
"Number of branches": null,
"Number of buckets": null,
"Number of cans of food": null,
"Number of clubs": null,
"Number of cows": null,
"Number of cupcakes": null,
"Number of cups": null,
"Number of fan letters": null,
"Number of fields": null,
"Number of gym lockers": null,
"Number of pairs of shorts": null,
"Number of pink highlighters": null,
"Number of practices": null,
"Number of red blocks": null,
"Number of respondents": null,
"Number of shells": null,
"Number of soccer fields": null,
"Number of students": null,
"Number of tables": null,
"Number of tickets": null,
"Number of times": null,
"Number of trips": null,
"Number of vans": null,
"Number of watermelons": null,
"Number spun": null,
"Park": null,
"Pay period": null,
"Per-student budget": null,
"Price": null,
"Quantity demanded": null,
"Quantity supplied": null,
"Record time (minutes)": null,
"Score": null,
"Stem": [
"2",
"3",
"4",
"5",
"6",
"7",
"8",
"9"
],
"Teacher": null,
"Thursday": null,
"Times eaten": null,
"Type": null,
"Vertically": null,
"Wednesday": null,
"Year": null,
"x": null,
"y": null
} | 9 | 2 | Find the row with stem 8. Count all the leaves greater than or equal to 3.
Count all the leaves in the row with stem 9.
You counted 2 leaves, which are blue in the stem-and-leaf plots above. 2 students scored at least 83 points. | free_text | integer_number | 6 | train |
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