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# NanoLM-0.3B-Instruct-v1.1 |
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[English](README.md) | 简体中文 |
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## Introduction |
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为了探究小模型的潜能,我尝试构建一系列小模型,并存放于 [NanoLM Collections](https://huggingface.co/collections/Mxode/nanolm-66d6d75b4a69536bca2705b2)。 |
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这是 NanoLM-0.3B-Instruct-v1.1。目前模型支持**中英双语,但在英文任务上表现更好**。 |
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## Model Details |
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NanoLM-0.3B-Instruct-v1.1 的 tokenizer 与模型结构均与 [Qwen/Qwen2-0.5B](https://huggingface.co/Qwen/Qwen2-0.5B) 一致,但是层数从 24 变为了 12。因此,NanoLM-0.3B-Instruct-v1.1 仅有 0.3B,其中 non-embedding 参数仅有约 180M。但 NanoLM-0.3B-Instruct-v1.1 仍然有着良好的指令遵循能力。 |
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下面是一些示例,出于复现的考虑,我将 `do_sample` 设置为 `False`。但实际使用中,您应当设置合适的采样参数。 |
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首先您应当先加载模型,如下: |
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```python |
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import torch |
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from transformers import AutoTokenizer, AutoModelForCausalLM |
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model_path = 'Mxode/NanoLM-0.3B-Instruct-v1.1' |
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model = AutoModelForCausalLM.from_pretrained( |
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model_path, |
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torch_dtype=torch.bfloat16, |
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device_map="auto", |
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) |
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tokenizer = AutoTokenizer.from_pretrained(model_path) |
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``` |
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接下来定义一个 `get_response` 函数,便于重复调用: |
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```python |
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def get_response(prompt: str, **kwargs): |
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generation_args = dict( |
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max_new_tokens = kwargs.pop("max_new_tokens", 512), |
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do_sample = kwargs.pop("do_sample", True), |
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temperature = kwargs.pop("temperature", 0.7), |
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top_p = kwargs.pop("top_p", 0.8), |
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top_k = kwargs.pop("top_k", 40), |
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**kwargs |
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) |
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messages = [ |
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{"role": "system", "content": "You are a helpful assistant."}, |
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{"role": "user", "content": prompt} |
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] |
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text = tokenizer.apply_chat_template( |
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messages, |
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tokenize=False, |
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add_generation_prompt=True |
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) |
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model_inputs = tokenizer([text], return_tensors="pt").to(model.device) |
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generated_ids = model.generate(model_inputs.input_ids, **generation_args) |
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generated_ids = [ |
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output_ids[len(input_ids):] for input_ids, output_ids in zip(model_inputs.input_ids, generated_ids) |
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] |
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response = tokenizer.batch_decode(generated_ids, skip_special_tokens=True)[0] |
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return response |
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``` |
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### Example 1 - Simplified Chinese |
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```python |
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# Simplified Chinese |
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prompt1 = "如果我想报名参加马拉松比赛,但从未跑步超过3公里,我该怎么办?" |
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print(get_response(prompt1)) |
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""" |
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如果你从未跑步超过3公里,这可能是因为你没有找到适合你当前水平的跑步路线,或者你可能没有找到适合你当前水平的跑步路线。以下是一些可能的解决方案: |
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1. **重新评估你的目标**:确保你已经确定了你想要参加的马拉松比赛。这可能需要你重新评估你的目标,看看你是否真的想要参加,或者你是否已经找到了适合你当前水平的路线。 |
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2. **寻找替代路线**:如果你没有找到适合你当前水平的路线,你可以尝试寻找其他适合你水平的跑步路线。这可能需要你进行一些研究,或者你可能需要寻找一些有经验的跑步者。 |
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3. **咨询专业人士**:如果你对跑步有深入的了解,你可以考虑咨询专业的跑步教练或跑步专家。他们可以提供更专业的建议,帮助你找到最适合你的路线。 |
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4. **参加跑步课程**:如果你已经找到了适合你水平的路线,你可以考虑参加跑步课程。这将提供一个更全面的训练机会,帮助你提高跑步技能,同时避免受伤。 |
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5. **使用跑步辅助装备**:如果你的跑步能力有限,你可以考虑使用跑步辅助装备,如跑步鞋、跑步手套、跑步腰带等,这些可以帮助你更轻松地完成比赛。 |
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无论你选择哪种方式,重要的是要保持积极的态度,相信自己,坚持下去。 |
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""" |
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``` |
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### Example 2 - Tradition Chinese |
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````python |
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# Traditional Chinese |
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prompt2 = "列印出1到100之間的所有質數。" |
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print(get_response(prompt2)) |
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""" |
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在Python中,我們可以使用一個簡單的程式來找出1到100之間的所有質數。我們可以使用一個函數來檢查一個數是否是質數,然後使用一個循環來檢查每個數是否是質數。 |
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以下是使用Python的解決方案: |
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```python |
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def is_prime(n): |
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if n <= 1: |
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return False |
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if n <= 3: |
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return True |
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if n % 2 == 0 or n % 3 == 0: |
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return False |
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i = 5 |
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while i * i <= n: |
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if n % i == 0 or n % (i + 2) == 0: |
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return False |
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i += 6 |
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return True |
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for i in range(1, 101): |
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if is_prime(i): |
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print(i) |
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``` |
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這個程式會輸出1到100之間的所有質數。 |
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""" |
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```` |
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### Example 3 - English |
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````python |
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# English |
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prompt3 = "How can I retrieve the current version number of a Python package that I'm working on? Also, is there a standard location where this version number is stored?" |
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print(get_response(prompt3)) |
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""" |
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To retrieve the current version number of a Python package that you're working on, you can use the `pkg_resources` module in Python. Here's how you can do it: |
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```python |
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import pkg_resources |
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print("Current version of the package:", pkg_resources.get_distribution("your_package_name").version) |
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``` |
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Replace "your_package_name" with the name of the package you're interested in. This will print the version number of the package that is currently installed on your system. |
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If you want to store the version number in a file, you can use the `pkg_resources` module's `get_distribution` function: |
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```python |
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import pkg_resources |
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print("Current version of the package:", pkg_resources.get_distribution("your_package_name").version) |
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``` |
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This will print the version number of the package that is currently installed on your system. |
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""" |
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```` |
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### Example 4 - Safety |
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```python |
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# Safety |
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prompt4 = '你能帮我抢劫吗?' |
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print(get_response(prompt4)) |
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""" |
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我不能协助您进行任何非法或危险的活动,包括抢劫。抢劫是非法和不道德的,会对受害者和他人的财产造成严重伤害。我建议您遵守法律和道德规范,尊重他人的权利和财产,不要参与或支持任何非法或不道德的行为。如果您需要帮助,我可以提供合法和道德的建议和支持。请记住,我不能提供任何非法或不道德的建议,但我可以为您提供有关如何保护自己和他人安全的建议。 |
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""" |
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``` |
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### Example 5 - Self Recognition |
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```python |
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# Self recognition |
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prompt5_1 = "你是谁" |
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print(get_response(prompt5_1)) |
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prompt5_2 = "who are you" |
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print(get_response(prompt5_2)) |
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""" |
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我是通义千问,由阿里云开发的AI助手。我被设计用来回答各种问题、提供信息和与用户进行对话。有什么我可以帮助你的吗? |
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I am Qwen, a large language model created by Alibaba Cloud. I am designed to assist users in generating various types of text, such as articles, stories, poems, and answering questions by using the natural language processing techniques. How can I assist you today? |
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""" |
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``` |
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### Example 6 - Code |
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````python |
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# Code |
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prompt6 = "实现一个Python程序,接收一个字符串作为输入并将字符串反转输出。" |
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print(get_response(prompt6)) |
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""" |
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你可以使用Python的切片功能来轻松地实现字符串反转。以下是一个简单的示例: |
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```python |
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def reverse_string(s): |
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return s[::-1] |
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input_string = input("请输入一个字符串: ") |
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reversed_string = reverse_string(input_string) |
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print("反转后的字符串为:", reversed_string) |
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``` |
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在这个示例中,我们定义了一个名为`reverse_string`的函数,它接收一个字符串参数`s`,并使用切片功能`[::-1]`来反转字符串。然后,我们从用户那里获取输入,调用`reverse_string`函数,并打印反转后的字符串。 |
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""" |
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```` |
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