instagram-R-api / app.py
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Create app.py
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from fastapi import FastAPI, HTTPException, Query
from fastapi.responses import FileResponse
import os
from yt_dlp import YoutubeDL
# Define the FastAPI app
app = FastAPI()
# Directory to save downloaded videos
DOWNLOAD_DIR = "downloads"
os.makedirs(DOWNLOAD_DIR, exist_ok=True)
@app.get("/")
def read_root():
return {"message": "Welcome to the Instagram Reel Downloader API"}
@app.get("/download/")
def download_instagram_reel(
reel_url: str = Query(..., description="The URL of the Instagram Reel to download"),
):
"""
Download an Instagram Reel using yt-dlp.
Args:
reel_url (str): The URL of the Instagram Reel.
Returns:
FileResponse: The path to the downloaded file.
"""
if not reel_url:
raise HTTPException(status_code=400, detail="The 'reel_url' parameter is required.")
# Define yt-dlp options
ydl_opts = {
"outtmpl": os.path.join(DOWNLOAD_DIR, "%(title)s.%(ext)s"),
"quiet": True, # Suppress yt-dlp's output
"merge_output_format": "mp4",
}
try:
with YoutubeDL(ydl_opts) as ydl:
info = ydl.extract_info(reel_url, download=True)
filename = ydl.prepare_filename(info)
if not os.path.exists(filename):
raise HTTPException(status_code=500, detail="Failed to download the Reel.")
return FileResponse(
path=filename,
filename=os.path.basename(filename),
media_type="video/mp4"
)
except Exception as e:
raise HTTPException(status_code=500, detail=f"An error occurred: {str(e)}")