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CSpider_and_DUSQL_sql_create_context

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CREATE TABLE available_policies (policy_type_code VARCHAR)
SELECT policy_type_code FROM available_policies GROUP BY policy_type_code HAVING COUNT(*) > 4
查找超过4个客户使用的保险单类型。显示他们的类型代码。
CREATE TABLE settlements (settlement_amount INTEGER)
SELECT SUM(settlement_amount), AVG(settlement_amount) FROM settlements
找到总计和平均结算金额。
CREATE TABLE settlements (settlement_amount INTEGER)
SELECT SUM(settlement_amount), AVG(settlement_amount) FROM settlements
返回所有结算金额的总和和平均数。
CREATE TABLE first_notification_of_loss (service_id VARCHAR), CREATE TABLE services (service_id VARCHAR, service_name VARCHAR)
SELECT t2.service_name FROM first_notification_of_loss AS t1 JOIN services AS t2 ON t1.service_id = t2.service_id GROUP BY t1.service_id HAVING COUNT(*) > 2
查找在首次丢失通知中已经使用了2次以上的服务的名称。
CREATE TABLE first_notification_of_loss (service_id VARCHAR), CREATE TABLE services (service_id VARCHAR, service_name VARCHAR)
SELECT t2.service_name FROM first_notification_of_loss AS t1 JOIN services AS t2 ON t1.service_id = t2.service_id GROUP BY t1.service_id HAVING COUNT(*) > 2
在首次丢失通知中，哪些服务已经使用了两次以上？返回服务名称。
CREATE TABLE claims (Effective_Date VARCHAR, claim_id VARCHAR), CREATE TABLE settlements (settlement_amount INTEGER, claim_id VARCHAR)
SELECT t1.Effective_Date FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id ORDER BY SUM(t2.settlement_amount) DESC LIMIT 1
总结算金额最大的索赔的有效日期是哪一天？
CREATE TABLE claims (Effective_Date VARCHAR, claim_id VARCHAR), CREATE TABLE settlements (settlement_amount INTEGER, claim_id VARCHAR)
SELECT t1.Effective_Date FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id ORDER BY SUM(t2.settlement_amount) DESC LIMIT 1
找到总结算金额最大的索赔。返回索赔的生效日期。
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customers_policies (customer_id VARCHAR)
SELECT COUNT(*) FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "李帅"
有多少名为“李帅”的保险单被列出？
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customers_policies (customer_id VARCHAR)
SELECT COUNT(*) FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "李帅"
对名为“李帅”的客户使用的保险单总数进行计数。
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customers_policies (customer_id VARCHAR)
SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_name ORDER BY COUNT(*) DESC LIMIT 1
列出最多保险单的客户名称是什么？
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customers_policies (customer_id VARCHAR)
SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_name ORDER BY COUNT(*) DESC LIMIT 1
哪个客户使用最多的保险单？给我客户的名字。
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customers_policies (policy_id VARCHAR, customer_id VARCHAR), CREATE TABLE available_policies (policy_id VARCHAR, policy_type_code VARCHAR)
SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = "李帅"
名为“李帅”的客户的所有保险单类型是什么？
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customers_policies (policy_id VARCHAR, customer_id VARCHAR), CREATE TABLE available_policies (policy_id VARCHAR, policy_type_code VARCHAR)
SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = "李帅"
请告诉我“李帅”客户使用的保险单的类型。
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customers_policies (policy_id VARCHAR, customer_id VARCHAR), CREATE TABLE available_policies (policy_id VARCHAR, policy_type_code VARCHAR)
SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = (SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_name ORDER BY COUNT(*) DESC LIMIT 1)
被列出的保险单最多的客户的保险单类型有哪些？
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customers_policies (policy_id VARCHAR, customer_id VARCHAR), CREATE TABLE available_policies (policy_id VARCHAR, policy_type_code VARCHAR)
SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = (SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_name ORDER BY COUNT(*) DESC LIMIT 1)
列出保险单中登记次数最多的客户的所有保险单类型。
CREATE TABLE services (service_name VARCHAR)
SELECT service_name FROM services ORDER BY service_name
按字母顺序，列出所有的服务。
CREATE TABLE services (service_name VARCHAR)
SELECT service_name FROM services ORDER BY service_name
给我一个按字母顺序排序的所有服务名称的列表。
CREATE TABLE services (Id VARCHAR)
SELECT COUNT(*) FROM services
有多少服务？
CREATE TABLE services (Id VARCHAR)
SELECT COUNT(*) FROM services
计算可用服务的总数。
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE first_notification_of_loss (customer_id VARCHAR)
SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id
查找没有首次丢失通知记录的用户的姓名。
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE first_notification_of_loss (customer_id VARCHAR)
SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id
哪些客户没有第一份丢失记录通知？给我客户的名字。
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE first_notification_of_loss (service_id VARCHAR, customer_id VARCHAR), CREATE TABLE services (service_id VARCHAR, service_name VARCHAR)
SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "取消保单" OR t3.service_name = "升级保单"
查找已经使用服务“取消保单”或服务“升级保单”的客户的名称。
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE first_notification_of_loss (service_id VARCHAR, customer_id VARCHAR), CREATE TABLE services (service_id VARCHAR, service_name VARCHAR)
SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "取消保单" OR t3.service_name = "升级保单"
哪些客户使用了名为“取消保单”或“升级保单”的服务？给我客户的名字。
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE first_notification_of_loss (service_id VARCHAR, customer_id VARCHAR), CREATE TABLE services (service_id VARCHAR, service_name VARCHAR)
SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "取消保单" INTERSECT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "新开保单"
查找同时使用服务“取消保单”和服务“新开保单”的客户的名称。
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE first_notification_of_loss (service_id VARCHAR, customer_id VARCHAR), CREATE TABLE services (service_id VARCHAR, service_name VARCHAR)
SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "取消保单" INTERSECT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "新开保单"
哪些客户使用了名为“取消保单”的服务和"新开保单"的服务？给我客户的名字。
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR)
SELECT customer_id FROM customers WHERE customer_name LIKE "楠"
查找名字包含“楠”的客户ID。
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR)
SELECT customer_id FROM customers WHERE customer_name LIKE "楠"
名字中有“楠”的客户的ID是什么？
CREATE TABLE settlements (settlement_amount INTEGER)
SELECT MAX(settlement_amount), MIN(settlement_amount) FROM settlements
记录的最大和最低结算金额是多少？
CREATE TABLE settlements (settlement_amount INTEGER)
SELECT MAX(settlement_amount), MIN(settlement_amount) FROM settlements
求最大结算金额和最小结算金额。
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR)
SELECT customer_id, customer_name FROM customers ORDER BY customer_id ASC
以ID的增加顺序列出所有客户。
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR)
SELECT customer_id, customer_name FROM customers ORDER BY customer_id ASC
客户ID的有序列表是什么？
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customers_policies (date_closed VARCHAR, date_opened VARCHAR, customer_id VARCHAR)
SELECT t2.date_opened, t2.date_closed FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name LIKE "楠"
检索名字包含“楠”的客户相关联的所有保险单的开始和结束日期
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customers_policies (date_closed VARCHAR, date_opened VARCHAR, customer_id VARCHAR)
SELECT t2.date_opened, t2.date_closed FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name LIKE "楠"
那些名字中有“楠”的客户使用的所有保险单的开始和结束日期是什么？
CREATE TABLE enzyme (Id VARCHAR)
SELECT COUNT(*) FROM enzyme
有多少种酶？
CREATE TABLE enzyme (Id VARCHAR)
SELECT COUNT(*) FROM enzyme
酶的总数是多少？
CREATE TABLE enzyme (name VARCHAR)
SELECT name FROM enzyme ORDER BY name DESC
以字母降序顺序列出酶的名称。
CREATE TABLE enzyme (name VARCHAR)
SELECT name FROM enzyme ORDER BY name DESC
酶的名称有哪些，按降序排列？
CREATE TABLE enzyme (name VARCHAR, LOCATION VARCHAR)
SELECT name, LOCATION FROM enzyme
列出能起作用的酶的名称和位置。
CREATE TABLE enzyme (name VARCHAR, LOCATION VARCHAR)
SELECT name, LOCATION FROM enzyme
列出的所有酶的名称和位置是什么？
CREATE TABLE enzyme (OMIM INTEGER)
SELECT MAX(OMIM) FROM enzyme
人类在线孟德尔遗传酶（OMIM）的最大值是多少？
CREATE TABLE enzyme (OMIM INTEGER)
SELECT MAX(OMIM) FROM enzyme
数据库中最大的OMIM值是多少？
CREATE TABLE enzyme (chromosome VARCHAR, porphyria VARCHAR, LOCATION VARCHAR, product VARCHAR)
SELECT product, chromosome, porphyria FROM enzyme WHERE LOCATION = '贵阳'
在“贵阳”位置起作用的酶有关的产物、染色体和卟啉是什么？
CREATE TABLE enzyme (chromosome VARCHAR, porphyria VARCHAR, LOCATION VARCHAR, product VARCHAR)
SELECT product, chromosome, porphyria FROM enzyme WHERE LOCATION = '贵阳'
位于“贵阳”的酶的产物、染色体和卟啉是什么？
CREATE TABLE enzyme (name VARCHAR, product VARCHAR)
SELECT name FROM enzyme WHERE product <> '淀粉酶'
不产生“淀粉酶”的酶的名称是什么？
CREATE TABLE enzyme (name VARCHAR, product VARCHAR)
SELECT name FROM enzyme WHERE product <> '淀粉酶'
产物不是“淀粉酶”的酶的名称是什么？
CREATE TABLE medicine (trade_name VARCHAR, name VARCHAR, FDA_approved VARCHAR)
SELECT name, trade_name FROM medicine WHERE FDA_approved = '是'
在FDA记录中有“是”的药物的名称和商标名称是什么？
CREATE TABLE medicine (trade_name VARCHAR, name VARCHAR, FDA_approved VARCHAR)
SELECT name, trade_name FROM medicine WHERE FDA_approved = '是'
FDA批准的药品名称和商标名称是什么？
CREATE TABLE enzyme (name VARCHAR, id VARCHAR), CREATE TABLE medicine_enzyme_interaction (enzyme_id VARCHAR, interaction_type VARCHAR, medicine_id VARCHAR), CREATE TABLE medicine (name VARCHAR, id VARCHAR)
SELECT T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id JOIN medicine AS T3 ON T2.medicine_id = T3.id WHERE T3.name = '氨磺必利' AND T2.interaction_type = '抑制剂'
有一种名为“氨磺必利”的能起到“抑制剂”的作用的药物，其中酶的名称是什么？
CREATE TABLE enzyme (name VARCHAR, id VARCHAR), CREATE TABLE medicine_enzyme_interaction (enzyme_id VARCHAR, interaction_type VARCHAR, medicine_id VARCHAR), CREATE TABLE medicine (name VARCHAR, id VARCHAR)
SELECT T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id JOIN medicine AS T3 ON T2.medicine_id = T3.id WHERE T3.name = '氨磺必利' AND T2.interaction_type = '抑制剂'
用作“抑制剂”的药物“氨磺必利”所利用的酶的名称是什么?
CREATE TABLE medicine (Name VARCHAR, id VARCHAR), CREATE TABLE medicine_enzyme_interaction (medicine_id VARCHAR)
SELECT T1.id, T1.Name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING COUNT(*) >= 2
可以与两种或更多种酶相互作用的药物的ID和名称是什么？
CREATE TABLE medicine (Name VARCHAR, id VARCHAR), CREATE TABLE medicine_enzyme_interaction (medicine_id VARCHAR)
SELECT T1.id, T1.Name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING COUNT(*) >= 2
对于每个药物ID，可以与一种以上酶相互作用的药物的名称是什么？
CREATE TABLE medicine (FDA_approved VARCHAR, Name VARCHAR, id VARCHAR), CREATE TABLE medicine_enzyme_interaction (medicine_id VARCHAR)
SELECT T1.id, T1.Name, T1.FDA_approved FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC
按照与它们相互作用的酶数量的降序排列，药品的ID、名称和FDA批准状况的是什么？
CREATE TABLE medicine (FDA_approved VARCHAR, Name VARCHAR, id VARCHAR), CREATE TABLE medicine_enzyme_interaction (medicine_id VARCHAR)
SELECT T1.id, T1.Name, T1.FDA_approved FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC
按酶相互作用数量递减的顺序，药物的ID、名称和FDA批准状态是什么？
CREATE TABLE enzyme (name VARCHAR, id VARCHAR), CREATE TABLE medicine_enzyme_interaction (enzyme_id VARCHAR, interaction_type VARCHAR)
SELECT T1.id, T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id WHERE T2.interaction_type = '催化剂' GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 1
那种可以与最多的药物进行“催化剂”相互作用的酶的ID和名称是什么？
CREATE TABLE enzyme (name VARCHAR, id VARCHAR), CREATE TABLE medicine_enzyme_interaction (enzyme_id VARCHAR, interaction_type VARCHAR)
SELECT T1.id, T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id WHERE T2.interaction_type = '催化剂' GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 1
能作为“催化剂”与最多的药物相互作用的酶的ID和名称是什么？
CREATE TABLE medicine_enzyme_interaction (interaction_type VARCHAR, enzyme_id VARCHAR, medicine_id VARCHAR), CREATE TABLE medicine (name VARCHAR, id VARCHAR), CREATE TABLE enzyme (name VARCHAR, id VARCHAR)
SELECT T1.interaction_type FROM medicine_enzyme_interaction AS T1 JOIN medicine AS T2 ON T1.medicine_id = T2.id JOIN enzyme AS T3 ON T1.enzyme_id = T3.id WHERE T3.name = 'ALA合酶' AND T2.name = '阿立哌唑'
“ALA合酶”和药物“阿立哌唑”的相互作用类型是什么？
CREATE TABLE medicine_enzyme_interaction (interaction_type VARCHAR, enzyme_id VARCHAR, medicine_id VARCHAR), CREATE TABLE medicine (name VARCHAR, id VARCHAR), CREATE TABLE enzyme (name VARCHAR, id VARCHAR)
SELECT T1.interaction_type FROM medicine_enzyme_interaction AS T1 JOIN medicine AS T2 ON T1.medicine_id = T2.id JOIN enzyme AS T3 ON T1.enzyme_id = T3.id WHERE T3.name = 'ALA合酶' AND T2.name = '阿立哌唑'
名为“ALA合酶”的酶和名为“阿立哌唑”的药物的相互作用类型是什么？
CREATE TABLE medicine_enzyme_interaction (interaction_type VARCHAR)
SELECT interaction_type, COUNT(*) FROM medicine_enzyme_interaction GROUP BY interaction_type ORDER BY COUNT(*) DESC LIMIT 1
酶和药物之间最常见的相互作用类型是什么？有多少？
CREATE TABLE medicine_enzyme_interaction (interaction_type VARCHAR)
SELECT interaction_type, COUNT(*) FROM medicine_enzyme_interaction GROUP BY interaction_type ORDER BY COUNT(*) DESC LIMIT 1
酶和药物之间最常见的相互作用类型是什么，有多少种？
CREATE TABLE medicine (FDA_approved VARCHAR)
SELECT COUNT(*) FROM medicine WHERE FDA_approved = '没有'
FDA批准状态为“没有”的药物有多少种？
CREATE TABLE medicine (FDA_approved VARCHAR)
SELECT COUNT(*) FROM medicine WHERE FDA_approved = '没有'
FDA没有批准多少药物？
CREATE TABLE enzyme (enzyme_id VARCHAR, id VARCHAR), CREATE TABLE medicine_enzyme_interaction (enzyme_id VARCHAR, id VARCHAR)
SELECT COUNT(*) FROM enzyme WHERE NOT id IN (SELECT enzyme_id FROM medicine_enzyme_interaction)
多少酶没有任何相互作用？
CREATE TABLE enzyme (enzyme_id VARCHAR, id VARCHAR), CREATE TABLE medicine_enzyme_interaction (enzyme_id VARCHAR, id VARCHAR)
SELECT COUNT(*) FROM enzyme WHERE NOT id IN (SELECT enzyme_id FROM medicine_enzyme_interaction)
没有相互作用的酶的数量是多少？
CREATE TABLE medicine (trade_name VARCHAR, id VARCHAR), CREATE TABLE medicine_enzyme_interaction (medicine_id VARCHAR)
SELECT T1.id, T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING COUNT(*) >= 3
这些与至少3种酶相互作用的药物的ID和商品名是什么？
CREATE TABLE medicine (trade_name VARCHAR, id VARCHAR), CREATE TABLE medicine_enzyme_interaction (medicine_id VARCHAR)
SELECT T1.id, T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING COUNT(*) >= 3
可以与至少3种酶相互作用的药物ID和商标名称是什么？
CREATE TABLE enzyme (name VARCHAR, location VARCHAR, id VARCHAR, product VARCHAR), CREATE TABLE medicine_enzyme_interaction (enzyme_id VARCHAR, interaction_type VARCHAR)
SELECT DISTINCT T1.name, T1.location, T1.product FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.enzyme_id = T1.id WHERE T2.interaction_type = '抑制剂'
有任一“抑制剂”相互作用的酶的不同名称、位置和产品是什么？
CREATE TABLE enzyme (name VARCHAR, location VARCHAR, id VARCHAR, product VARCHAR), CREATE TABLE medicine_enzyme_interaction (enzyme_id VARCHAR, interaction_type VARCHAR)
SELECT DISTINCT T1.name, T1.location, T1.product FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.enzyme_id = T1.id WHERE T2.interaction_type = '抑制剂'
包含“抑制剂”相互作用的酶的不同名称、位置和产品是什么？
CREATE TABLE medicine (trade_name VARCHAR, name VARCHAR, id VARCHAR), CREATE TABLE medicine_enzyme_interaction (medicine_id VARCHAR)
SELECT T1.name, T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = '抑制剂' INTERSECT SELECT T1.name, T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = '催化剂'
列出可以与酶进行“抑制剂”和“催化剂”相互作用药物名称和商标名称。
CREATE TABLE medicine (trade_name VARCHAR, name VARCHAR, id VARCHAR), CREATE TABLE medicine_enzyme_interaction (medicine_id VARCHAR)
SELECT T1.name, T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = '抑制剂' INTERSECT SELECT T1.name, T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = '催化剂'
可以作为“抑制剂”和“催化剂”与酶相互作用药物名称和商标名称是什么？
CREATE TABLE medicine (trade_name VARCHAR, name VARCHAR, id VARCHAR), CREATE TABLE medicine_enzyme_interaction (enzyme_id VARCHAR, medicine_id VARCHAR), CREATE TABLE enzyme (product VARCHAR, id VARCHAR)
SELECT name, trade_name FROM medicine EXCEPT SELECT T1.name, T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id JOIN enzyme AS T3 ON T3.id = T2.enzyme_id WHERE T3.product = '生物酶'
显示不能与产物为“生物酶”的酶相互作用的药品名称和商品名。
CREATE TABLE medicine (trade_name VARCHAR, name VARCHAR, id VARCHAR), CREATE TABLE medicine_enzyme_interaction (enzyme_id VARCHAR, medicine_id VARCHAR), CREATE TABLE enzyme (product VARCHAR, id VARCHAR)
SELECT name, trade_name FROM medicine EXCEPT SELECT T1.name, T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id JOIN enzyme AS T3 ON T3.id = T2.enzyme_id WHERE T3.product = '生物酶'
不能与产物为“生物酶”的酶相互作用的药物名称和商标名称？
CREATE TABLE medicine (FDA_approved VARCHAR)
SELECT COUNT(DISTINCT FDA_approved) FROM medicine
药品有多少种不同的FDA批准状态？
CREATE TABLE medicine (FDA_approved VARCHAR)
SELECT COUNT(DISTINCT FDA_approved) FROM medicine
药品有多少种不同的FDA批准状态？
CREATE TABLE enzyme (name VARCHAR)
SELECT name FROM enzyme WHERE name LIKE "物"
哪些酶名称有子链“ALA”？
CREATE TABLE enzyme (name VARCHAR)
SELECT name FROM enzyme WHERE name LIKE "物"
包含“ALA”的酶的名称是什么？
CREATE TABLE medicine (trade_name VARCHAR)
SELECT trade_name, COUNT(*) FROM medicine GROUP BY trade_name
找找每笔交易提供的药品数量。
CREATE TABLE medicine (trade_name VARCHAR)
SELECT trade_name, COUNT(*) FROM medicine GROUP BY trade_name
每个交易名提供多少药？
CREATE TABLE university (school VARCHAR, nickname VARCHAR, founded VARCHAR)
SELECT school, nickname FROM university ORDER BY founded
按成立年的顺序列出所有学校和他们的绰号。
CREATE TABLE university (school VARCHAR, nickname VARCHAR, founded VARCHAR)
SELECT school, nickname FROM university ORDER BY founded
根据建校年排序，不同的学校和它们的昵称是什么？
CREATE TABLE university (school VARCHAR, affiliation VARCHAR, LOCATION VARCHAR)
SELECT school, LOCATION FROM university WHERE affiliation = '公立'
列出所有公立学校及其所在地。
CREATE TABLE university (school VARCHAR, affiliation VARCHAR, LOCATION VARCHAR)
SELECT school, LOCATION FROM university WHERE affiliation = '公立'
公立学校有哪些，他们的位置是什么？
CREATE TABLE university (founded VARCHAR, enrollment VARCHAR)
SELECT founded FROM university ORDER BY enrollment DESC LIMIT 1
招生最大的学校是什么时候成立的？
CREATE TABLE university (founded VARCHAR, enrollment VARCHAR)
SELECT founded FROM university ORDER BY enrollment DESC LIMIT 1
返回招生规模最大学校的成立年。
CREATE TABLE university (affiliation VARCHAR, founded VARCHAR)
SELECT founded FROM university WHERE affiliation <> '公立' ORDER BY founded DESC LIMIT 1
查找最新的非公立学校成立年。
CREATE TABLE university (affiliation VARCHAR, founded VARCHAR)
SELECT founded FROM university WHERE affiliation <> '公立' ORDER BY founded DESC LIMIT 1
最近成立的非公立学校创办年份是哪一年？
CREATE TABLE basketball_match (school_id VARCHAR)
SELECT COUNT(DISTINCT school_id) FROM basketball_match
有多少学校有篮球比赛？
CREATE TABLE basketball_match (school_id VARCHAR)
SELECT COUNT(DISTINCT school_id) FROM basketball_match
统计有篮球比赛的学校的数量。
CREATE TABLE basketball_match (acc_percent VARCHAR)
SELECT acc_percent FROM basketball_match ORDER BY acc_percent DESC LIMIT 1
比赛中最高的ACC得分比是什么？
CREATE TABLE basketball_match (acc_percent VARCHAR)
SELECT acc_percent FROM basketball_match ORDER BY acc_percent DESC LIMIT 1
返回在所有篮球比赛中最高ACC得分比。
CREATE TABLE university (Primary_conference VARCHAR, school_id VARCHAR), CREATE TABLE basketball_match (school_id VARCHAR, acc_percent VARCHAR)
SELECT t1.Primary_conference FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY t2.acc_percent LIMIT 1
在比赛中ACC得分比最低的学校的初级会议是什么？
CREATE TABLE university (Primary_conference VARCHAR, school_id VARCHAR), CREATE TABLE basketball_match (school_id VARCHAR, acc_percent VARCHAR)
SELECT t1.Primary_conference FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY t2.acc_percent LIMIT 1
返回最低的acc百分比的学校的初级会议。
CREATE TABLE university (school_id VARCHAR, founded VARCHAR), CREATE TABLE basketball_match (school_id VARCHAR, team_name VARCHAR, ACC_Regular_Season VARCHAR)
SELECT t2.team_name, t2.ACC_Regular_Season FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY t1.founded LIMIT 1
创建时间最长的学校的队名和常规赛成绩是多少？
CREATE TABLE university (school_id VARCHAR, founded VARCHAR), CREATE TABLE basketball_match (school_id VARCHAR, team_name VARCHAR, ACC_Regular_Season VARCHAR)
SELECT t2.team_name, t2.ACC_Regular_Season FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY t1.founded LIMIT 1
返回最早成立的学校的球队名称和在常规赛期间的ACC。
CREATE TABLE university (location VARCHAR, school_id VARCHAR), CREATE TABLE basketball_match (school_id VARCHAR, All_Games VARCHAR)
SELECT t2.All_Games, t1.location FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id WHERE team_name = '暨南大学'
查找以“暨南大学”为队名的学校的位置和所有比赛得分。
CREATE TABLE university (location VARCHAR, school_id VARCHAR), CREATE TABLE basketball_match (school_id VARCHAR, All_Games VARCHAR)
SELECT t2.All_Games, t1.location FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id WHERE team_name = '暨南大学'
叫“暨南大学”的学校的所有比赛分数和地点是什么？
CREATE TABLE university (enrollment INTEGER, founded INTEGER)
SELECT AVG(enrollment) FROM university WHERE founded < 1850
1850年以前建立的大学的平均招生人数是多少？
CREATE TABLE university (enrollment INTEGER, founded INTEGER)
SELECT AVG(enrollment) FROM university WHERE founded < 1850
返回1850年以前成立的大学的平均招生人数。
CREATE TABLE university (primary_conference VARCHAR, founded VARCHAR, enrollment VARCHAR)
SELECT enrollment, primary_conference FROM university ORDER BY founded LIMIT 1
展示最古老学院的招生和初级会议。
CREATE TABLE university (primary_conference VARCHAR, founded VARCHAR, enrollment VARCHAR)
SELECT enrollment, primary_conference FROM university ORDER BY founded LIMIT 1
最早建立的那所大学的招生和初级会议是什么？
CREATE TABLE university (enrollment INTEGER)
SELECT SUM(enrollment), MIN(enrollment) FROM university
所有学校的招生总数是多少？