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ape210k__00259676 | The original price of a duvet is 570 yuan, and now it is sold at a 5% discount, what is the current price | 一条羽绒被原价570元，现按九五折出售，则现价是多少 | <gadget id="calculator">95 / 100</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">570 * (19/20)</gadget>
<output>1_083/2 = around 541.5</output>
<result>1_083/2 = around 541.5</result> | 1_083/2 | 541.5 | x=570*95% | calcformer-instruct-flan-xl_step-128k | 95% of 570 yuan is 95/100 * 570 =<gadget id="calculator">95/100 * 570</gadget><output>1_083/2 = around 541.5</output> 541.5 yuan.<result>1_083/2 = around 541.5</result> | 95% of 570 yuan is 955/100*570 =<gadget id="calculator">955/100*570</gadget><output>10_887/2 = around 5_443.5</output> 5404 yuan.<result>10_887/2 = around 5_443.5</result> |
ape210k__00097134 | If one factor is multiplied by 2 and the other factor is multiplied by 4, what is the product? | 一个因数扩大2倍，另一个因数扩大4倍，那么积多少． | <gadget id="calculator">2 * 4</gadget>
<output>8</output>
<result>8</result> | 8 | 8 | x=2*4 | calcformer-instruct-flan-xl_step-128k | If one factor is multiplied by 2, it is multiplied by 2*4. If the other factor is multiplied by 4 as it is multiplied by 2*4, it is multiplied by 4*2=<gadget id="calculator">4*2</gadget><output>8</output> 8.<result>8</result> | If one factor is multiplied by 2, the resulting product is 2*4=<gadget id="calculator">2*4</gadget><output>8</output> 8. If one factor is multiplied by 4, the resulting product is 4*4=<gadget id="calculator">4*4</gadget><output>16</output> 16.<result>16</result> |
ape210k__00175483 | In the math class, Teacher Li assigned two questions. As a result, 34 people got the first question right; 46 people got the second question right; no one got both questions wrong. If there are 52 people in this class, how many people get both questions right? | 数学课上，李老师布置了两道题，结果有34人答对了第一题；有46人做对了第二题；没有人两道题全部做错．如果这个班共有52人，那么两道题都做对的有多少人． | <gadget id="calculator">46 - 52</gadget>
<output>-6</output>
<gadget id="calculator">34 + (-6)</gadget>
<output>28</output>
<result>28</result> | 28 | 28 | x=34+46-52 | calcformer-instruct-flan-xl_step-128k | There are 34 + 46 =<gadget id="calculator">34+46</gadget><output>80</output> 80 people who got at least one of the questions right. Thus, 80 - 52 =<gadget id="calculator">80-52</gadget><output>28</output> 28 people get both questions right.<result>28</result> | People who got the first question right are 34 + 46 =<gadget id="calculator">34+46</gadget><output>80</output> 80 people. Of these, 52 - 80 =<gadget id="calculator">52-80</gadget><output>-28</output> 28 people got both questions right.<result>-28</result> |
ape210k__00277836 | Xiaoming's family participates in the property insurance of the insurance company. The total amount of property participating in the insurance is 42,000 yuan. If the annual insurance premium rate is 1.5%, how much is the annual insurance premium that Xiaoming's family should pay. | 小明家参加保险公司的财产保险．参加保险的财产总额是42000元，如果每年的保险费率是1.5%，小明家每年应付保险费多少元． | <gadget id="calculator">1.5 / 100</gadget>
<output>0.015</output>
<gadget id="calculator">42_000 * 0.015</gadget>
<output>630</output>
<result>630</result> | 630 | 630 | x=42000*1.5% | calcformer-instruct-flan-xl_step-128k | The annual insurance premium that Xiaoming's family should pay is 1.5% of $42,000 yuan = 1.5/100 x 42,000 yuan = $<gadget id="calculator">1.5/100*42000</gadget><output>630</output> 630.<result>630</result> | The annual insurance premium rate is 1.5%, and if there are 42,000 yuan participating in the insurance, then the annual premium is 42,000 x 0.15 =<gadget id="calculator">42000*0.15</gadget><output>6_300</output> 6300 yuan.<result>6_300</result> |
ape210k__00990823 | There are 5 red balls and 5 blue balls in the bag. If you want to take out two balls of the same color from the bag at one time, how many balls must you take out at least. | 袋子中有红、蓝球各5个，如果要保证一次能从布袋中取出两个相同颜色的球，至少必须取出多少个球． | <gadget id="calculator">2 + 1</gadget>
<output>3</output>
<result>3</result> | 3 | 3 | x=2+1 | calcformer-instruct-flan-xl_step-128k | 2 is the worst case scenario. If you take out 3 red balls, for example, you'll have 4 red balls and 3 blue balls, while still having 5 blue balls left. This means that you must take out at least 2 blue balls. In this scenario, you'll have 4 red balls and 3 blue balls, and still only have 5 blue balls left. Therefore, you must take out at least 2 + 1 =<gadget id="calculator">2+1</gadget><output>3</output> 3 balls at once.<result>3</result> | If you take out one red ball and one blue ball at a time, you would have taken out a total of 5+1=<gadget id="calculator">5+1</gadget><output>6</output> 6 balls.<result>6</result> |
ape210k__01099841 | An object falls from a height and lands after 4 seconds. It is known that the falling distance in the first second is 3.5 meters, and the falling distance in each subsequent second is 8.4 meters more than the previous second. How far was the object from the ground before it fell? | 一个物体从高空下落，经过4秒落地．已知第一秒下落的距离是3.5米，以后每一秒下落的距离都比前一秒多8.4米．这个物体在下落前距地面多少米？ | <gadget id="calculator">3.5 + 8.4</gadget>
<output>11.9</output>
<gadget id="calculator">3.5 + 8.4 + 8.4</gadget>
<output>20.3</output>
<gadget id="calculator">3.5 + 8.4 + 8.4 + 8.4</gadget>
<output>28.7</output>
<gadget id="calculator">3.5 + 11.9 + 20.3 + 28.7</gadget>
<output>64.4</output>
<result>64.4</result> | 64.4 | 64.4 | x=3.5+(3.5+8.4)+(3.5+8.4+8.4)+(3.5+8.4+8.4+8.4) | calcformer-instruct-flan-xl_step-128k | In the second second, the object fell 3.5 + 8.4 =<gadget id="calculator">3.5+8.4</gadget><output>11.9</output> 11.9 meters. In the third second, the object fell 11.9 + 8.4 =<gadget id="calculator">11.9+8.4</gadget><output>20.3</output> 20.3 meters. In the fourth second, the object fell 20.3 + 8.4 =<gadget id="calculator">20.3+8.4</gadget><output>28.7</output> 28.7 meters. Thus, the object fell a total of 3.5 + 11.9 + 20.3 + 28.7 =<gadget id="calculator">3.5+11.9+20.3+28.7</gadget><output>64.4</output> 64.4 meters.<result>64.4</result> | If the object fell for a total of 4 seconds, and each second the distance was 8.4 meters more than the previous second, then in the second second it fell for 3.5 + 8.4 =<gadget id="calculator">3.5+8.4</gadget><output>11.9</output> 11.9 meters. The object fell for a total of 11.9 + 8.4 =<gadget id="calculator">11.9+8.4</gadget><output>20.3</output> 20.3 meters. In total, the object fell for a distance of 20.3 + 3.5 + 8.4 + 8.4 + 8.4 =<gadget id="calculator">20.3+3.5+8.4+8.4</gadget><output>40.6</output> 40.6 meters.<result>40.6</result> |
ape210k__00601332 | (2/3) of the circumference angle is (how many) degrees. | 周角的(2/3)是(多少)度． | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">360 * (2/3)</gadget>
<output>240</output>
<result>240</result> | 240 | 240 | x=360*(2/3) | calcformer-instruct-flan-xl_step-128k | To find out the angle for 2/3 of the circumference, you know the angle formed for the other half is 360 degrees, so by multiplying the circumference by 3/2, you get 360 * (2/3) = 240 degrees.<result>240</result> | Since 2/3 of the circumference is 180 degrees, and 360 degrees is 360 degrees, then the remainder of the circumference is 360 degrees - 360 degrees =<gadget id="calculator">360-360</gadget><output>0</output> 0 degrees. Thus, 2/3 of the circumference is 180 degrees / 0 degrees =<gadget id="calculator">180/0</gadget><output>ERROR: Cannot convert complex to float</output> 0 degrees.<result>ERROR</result> |
ape210k__00019921 | Uncle Zhang in the cafeteria bought 3.5 kilograms of beans at the vegetable market and gave it to the salesperson for 10 yuan, and got back 3.7 yuan. How much is it per kilogram of beans? | 食堂张叔叔在菜市场买了3.5千克豆角交给售货员10元，找回3.7元，每千克豆角多少钱？ | <gadget id="calculator">10 - 3.7</gadget>
<output>6.3</output>
<gadget id="calculator">6.3 / 3.5</gadget>
<output>1.8</output>
<result>1.8</result> | 1.8 | 1.8 | x=(10-3.7)/3.5 | calcformer-instruct-flan-xl_step-128k | 10 - 3.7 =<gadget id="calculator">10-3.7</gadget><output>6.3</output> 6.3 6.3 / 3.5 =<gadget id="calculator">6.3/3.5</gadget><output>1.8</output> 1.8<result>1.8</result> | 10 - 3.7 =<gadget id="calculator">10-3.7</gadget><output>6.3</output> 6.3 3.5 - 0.7 =<gadget id="calculator">3.5-0.7</gadget><output>2.8</output> 2.8 3.5 / 2.8 =<gadget id="calculator">3.5/2.8</gadget><output>1.25</output> 1.25</output> 1.25<result>1.25</result> |
ape210k__00648669 | Xiaogang went climbing on the weekend. It took him 15 minutes to climb from the foot of the mountain to the top of the mountain, and 10 minutes to return to the foot of the mountain by the same road from the top of the mountain. It is known that Xiaogang went up the mountain at a speed of 60 meters per minute. How far is it from the foot of the mountain to the top of the mountain? What was Xiaogang's speed when he returned? | 周末小刚去爬山，他从山脚爬到山顶用了15分钟，从山顶原路返回山脚用了10分钟，已知小刚上山的速度是60米/分，从山脚到山顶有多远？小刚返回时的速度是多少？ | <gadget id="calculator">60 * 15</gadget>
<output>900</output>
<gadget id="calculator">900 / 10</gadget>
<output>90</output>
<result>90</result> | 90 | 90 | x=(60*15)/10 | calcformer-instruct-flan-xl_step-128k | When he returned to the foot of the mountain, Xiaogang's speed was 60 meters per minute, a speed of 60*15 =<gadget id="calculator">60*15</gadget><output>900</output> 900 meters per minute. If it took Xiaogang 15 minutes to climb to the top of the mountain, his speed on the return trip was 900/10 =<gadget id="calculator">900/10</gadget><output>90</output> 90 meters per minute.<result>90</result> | On the way down, Xiogang's speed was 60 meters per minute * 15 minutes =<gadget id="calculator">60*15</gadget><output>900</output> 900 meters. If he returned to the foot of the mountain at the same speed he used to climb it, his speed on the return trip was 900 meters per minute * 10 minutes =<gadget id="calculator">900*10</gadget><output>9_000</output> 9000 meters.<result>9_000</result> |
ape210k__00602653 | Two people, A and B, completed a batch of parts together in 5 hours, and A made 225 parts when the task was completed. It is known that the work efficiency of B is faster than that of A (2/9). How many parts are there in total? | 甲乙二人5小时共同完成一批零件，完成任务时甲做了225个．已知乙的工效比甲快(2/9)．这批零件一共多少个？ | <gadget id="calculator">2 / 9</gadget>
<output>2/9 = around 0.222222</output>
<gadget id="calculator">1 + (2/9)</gadget>
<output>11/9 = around 1.222222</output>
<gadget id="calculator">225 * (11/9)</gadget>
<output>275</output>
<gadget id="calculator">225 + 275</gadget>
<output>500</output>
<result>500</result> | 500 | 500 | x=225+225*(1+(2/9)) | calcformer-instruct-flan-xl_step-128k | If A made 225 parts, then B made 225 + 2/9 * 225 =<gadget id="calculator">225+2/9*225</gadget><output>275</output> 275 parts. The total number of parts is 225 + 275 =<gadget id="calculator">225+275</gadget><output>500</output> 500.<result>500</result> | If A's efficiency is 225 parts, then B's is 2/9 * 225 =<gadget id="calculator">225*2/9</gadget><output>50</output> 50 parts faster. In total, they are 225 + 50 =<gadget id="calculator">225+50</gadget><output>275</output> 275 parts.<result>275</result> |
ape210k__00822165 | The Hall of Prayer for Good Harvest in Beijing Temple of Heaven Park is a circular hall with a circumference of about 75.36 meters at the bottom. How many square meters does it cover? | 北京天坛公园的祈年殿是圆形大殿，底部的周长约是75.36米，它的占地面积是多少平方米？ | <gadget id="calculator">75.36 / 3.14 / 2</gadget>
<output>12</output>
<gadget id="calculator">12 ** 2</gadget>
<output>144</output>
<gadget id="calculator">3.14 * 144</gadget>
<output>452.16</output>
<result>452.16</result> | 452.16 | 452.16 | x=3.14*(75.36/3.14/2)**2 | calcformer-instruct-flan-xl_step-128k | 75.36 / 3.14 / 2 =<gadget id="calculator">75.36 / 3.14 / 2</gadget><output>12</output> 12<gadget id="calculator">12 ** 2</gadget><output>144</output> 144 144. The area of the circle is 3.14 * 144 =<gadget id="calculator">3.14*144</gadget><output>452.16</output> 452.16 sq m.<result>452.16</result> | 75.36 / 3.14 / 2 =<gadget id="calculator">75.36 / 3.14 / 2</gadget><output>12</output> 12<output>8</output> 8<gadget id="calculator">8 ** 2</gadget><output>64</output> 64. The area of a circle is 3.14 * 64</gadget><output>200.96</output> 200.96 sq m.<result>200.96</result> |
ape210k__00426289 | When Xiao Ming calculated 3.1 divided by a number, because the decimal point of the quotient was one more to the right, the result was 25. What is the divisor of this equation. | 小明在计算3.1除以一个数时，由于商的小数点向右多点了一位，结果得25．这道式题的除数是多少． | <gadget id="calculator">25 / 10</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">3.1 / (5/2)</gadget>
<output>1.24</output>
<result>1.24</result> | 1.24 | 1.24 | x=3.1/(25/10) | calcformer-instruct-flan-xl_step-128k | Since 25/10 =<gadget id="calculator">25/10</gadget><output>5/2 = around 2.5</output> 2.5, then 3.1 / 2.5 =<gadget id="calculator">3.1/2.5</gadget><output>1.24</output> 1.24.<result>1.24</result> | Let the x be the divisor of the equation. Dividing both sides of the equation by 25, we get x/10 = 25/10. Dividing both sides by 25, we get x = 5.<result>5</result> |
ape210k__00083203 | Educational savings are exempt from interest tax; Aunt Zhang has saved 20,000 yuan for her children’s education savings for 6 years, with an annual interest rate of 2.79%. How much interest can she get after maturity? | 教育储蓄是免征利息税的；张阿姨为她的孩子存了6年期的教育储蓄2万元，年利率是2.79%，到期后可以得到多少元利息？ | <gadget id="calculator">2 * 10_000</gadget>
<output>20_000</output>
<gadget id="calculator">2.79 / 100</gadget>
<output>0.0279</output>
<gadget id="calculator">20_000 * 0.0279 * 6</gadget>
<output>3_348</output>
<result>3_348</result> | 3_348 | 3,348 | x=(2*10000)*2.79%*6 | calcformer-instruct-flan-xl_step-128k | Aunt Zhang's investment is worth 20000 x 100/100 =<gadget id="calculator">20000*100/100</gadget><output>20_000</output> 20000. Her annual interest is 2.79/100 x 20000 =<gadget id="calculator">2.79/100*20000</gadget><output>558</output> 558. Thus, she will get 558 x 6 =<gadget id="calculator">558*6</gadget><output>3_348</output> 3348 after 6 years.<result>3_348</result> | Aunt Zhang's investment at 2.79% is worth 20000 x 0.29 =<gadget id="calculator">20000*0.279</gadget><output>5_580</output> 5580. For the six years, she will earn an interest of 5580 x 6 =<gadget id="calculator">5580*6</gadget><output>33_480</output> 33480.<result>33_480</result> |
ape210k__00407098 | In a right triangle, one acute angle is 36°, find the measure of the other acute angle. | 在直角三角形中，一个锐角是36°，求另一个锐角的度数． | <gadget id="calculator">90 - 36</gadget>
<output>54</output>
<result>54</result> | 54 | 54 | x=90-36 | calcformer-instruct-flan-xl_step-128k | The other angle is 90 - 36 =<gadget id="calculator">90-36</gadget><output>54</output> 54 degrees.<result>54</result> | If the two acute angles of a triangle are 90 degrees each, the total of all three angles is 180 degrees. Since one acute angle is 36°, the other acute angle must be 180 degrees - 90 degrees =<gadget id="calculator">180-90</gadget><output>90</output> 90 degrees.<result>90</result> |
ape210k__00987143 | There are 768 books in the school, and they are divided into 6 levels on average. How many books do each level get? | 学校有768本图书，现平均分给6个级，每个级各得多少本？ | <gadget id="calculator">768 / 6</gadget>
<output>128</output>
<result>128</result> | 128 | 128 | x=768/6 | calcformer-instruct-flan-xl_step-128k | 768/6 =<gadget id="calculator">768/6</gadget><output>128</output> 128 books per level.<result>128</result> | The total number of books in the levels is 768/6 =<gadget id="calculator">768/6</gadget><output>128</output> 128 books. Each level gets 128/6 =<gadget id="calculator">128/6</gadget><output>64/3 = around 21.333333</output> 21 books.<result>64/3 = around 21.333333</result> |
ape210k__01221663 | For a rope, half of it is cut off for the first time, which is more than 2 meters, and the remaining half is cut off for the second time, which is more than 3 meters, leaving 8 meters. How many meters is the total length of this rope? | 一根绳子，第一次剪去一半多2米，第二次剪去剩下的一半多3米，还剩8米，这根绳子一共长多少米？ | <gadget id="calculator">8 + 3</gadget>
<output>11</output>
<gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="calculator">22 + 2</gadget>
<output>24</output>
<gadget id="calculator">24 * 2</gadget>
<output>48</output>
<result>48</result> | 48 | 48 | x=((8+3)*2+2)*2 | calcformer-instruct-flan-xl_step-128k | Half of the circumference of the rope is 8 + 3 =<gadget id="calculator">8+3</gadget><output>11</output> 11 meters. One half of the circumference is 11 x 2 =<gadget id="calculator">11*2</gadget><output>22</output> 22 meters. Two more meters were cut off, so the circumference of this additional part is 22 + 2 =<gadget id="calculator">22+2</gadget><output>24</output> 24 meters. So the question is, what is 24 x 2 =<gadget id="calculator">24*2</gadget><output>48</output> 48 meters long.<result>48</result> | Half of the rope is 8 * 2 =<gadget id="calculator">8*2</gadget><output>16</output> 16 meters long. After the first cutoff, the rope is 16 + 2 =<gadget id="calculator">16+2</gadget><output>18</output> 18 meters long. Since the first cutoff is more than 2 meters, the final cutoff is 18 * 2 =<gadget id="calculator">18*2</gadget><output>36</output> 36 meters long.<result>36</result> |
ape210k__00047446 | bamboo pole is 2 meters long. Stand it upright on the ground and measure its shadow length of 2.5 meters. At the same time and at the same place, measure the shadow length of a big tree as 12 meters. What is the height of this big tree in meters? | 一根竹竿长2米，把它直立在地面上，量出它的影长2.5米，在同一时间同一地点量得一棵大树的影长为12米，这棵大树高多少米． | <gadget id="calculator">2 / 2.5</gadget>
<output>0.8</output>
<gadget id="calculator">0.8 * 12</gadget>
<output>9.6</output>
<result>9.6</result> | 9.6 | 9.6 | x=(2/2.5*12) | calcformer-instruct-flan-xl_step-128k | If the shadow of the bamboo pole is 2.5 meters, then its height is 2 meters. So, 2/2.5 =<gadget id="calculator">2/2.5</gadget><output>0.8</output> 0.8. Therefore, the height of the big tree is 0.8 x 12 =<gadget id="calculator">0.8*12</gadget><output>9.6</output> 9.6 meters.<result>9.6</result> | If we observe the bamboo pole, the shadow of it is 2/2 =<gadget id="calculator">2/2</gadget><output>1</output> 1 meter. Since the height of the bamboo pole is 2 meters, the height of the big tree is 12/1 =<gadget id="calculator">12/1</gadget><output>12</output> 12 meters.<result>12</result> |
ape210k__00004871 | The ratio of the areas of two circles is 3:2, what is the area of the larger circle than the smaller circle? | 两个圆面积的比是3：2，那么大圆面积是小圆的多少 | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<result>3/2 = around 1.5</result> | 3/2 | 1.5 | x=3/2 | calcformer-instruct-flan-xl_step-128k | The area of a circle is 3/2 =<gadget id="calculator">3/2</gadget><output>3/2 = around 1.5</output> 1.5 times the area of a smaller circle. Since the area of a circle is proportional to the area of the circle, then the area of the larger circle is 1.5 times the area of the smaller circle.<result>1.5</result> | The radiuses of the circles are 3/2 and 1/2 = 3/2. The areas are pi*(3/2)*pi and pi* (2/2). pi*(3/2)*pi = 6/8. Since the area of a circle is pi*r2, the area of the larger circle is pi*(1/2)*pi*3/4 = 3/4 The area of the smaller circle is pi*(1/2)*pi*1/2 = 1/8 The area of the larger circle is 3/8 - 1/8 = 1/4.<result>3</result> |
ape210k__01108809 | Divide the circle into 11 parts on average, and express the number of 8 parts in fractions. | 把圆平均分成11份，其中的8份用分数表示为多少． | <gadget id="calculator">11 / 1</gadget>
<output>11</output>
<gadget id="calculator">8 / 11</gadget>
<output>8/11 = around 0.727273</output>
<result>8/11 = around 0.727273</result> | 8/11 | 0.727273 | x=(8/(11/1)) | calcformer-instruct-flan-xl_step-128k | If you divide the circle into 11 equal parts, you can divide it into 8 equal parts. So 8 parts divided by 11 parts is equal to 8/11. Multiplying both sides with the same denominator gives 8/11 * 1 =<gadget id="calculator">8/11*1</gadget><output>8/11 = around 0.727273</output> 0.727273.<result>8/11 = around 0.727273</result> | If a circle is divided into 11 equal parts, then the number of parts is 11*8=<gadget id="calculator">11*8</gadget><output>88</output> 88. The fraction that represents 8 parts is 8/88 = 1/4.<result>1/4 = around 0.25</result> |
ape210k__00031642 | The school planted 235 saplings, 15 of which did not survive, and all 15 of them survived after replanting. Find the survival rate of these saplings. | 学校种了235棵树苗，其中有15棵没有成活，后来补种15棵全部成活．求这些树苗的成活率． | <gadget id="calculator">235 - 15</gadget>
<output>220</output>
<gadget id="calculator">220 + 15</gadget>
<output>235</output>
<gadget id="calculator">235 + 15</gadget>
<output>250</output>
<gadget id="calculator">235 / 250</gadget>
<output>47/50 = around 0.94</output>
<result>47/50 = around 0.94</result> | 47/50 | 0.94 | x=(235-15+15)/(235+15) | calcformer-instruct-flan-xl_step-128k | If 15 of the saplings did not survive, the school had 235 - 15 =<gadget id="calculator">235-15</gadget><output>220</output> 220 saplings that survived. After replanting, there were a total of 220 + 15 =<gadget id="calculator">220+15</gadget><output>235</output> 235 saplings. Of these, 235 - 15 =<gadget id="calculator">235-15</gadget><output>220</output> 220 of them survived. This means the school had 220 / 235 =<gadget id="calculator">220/235</gadget><output>44/47 = around 0.93617</output> 0.93617 is the survival rate.<result>44/47 = around 0.93617</result> | If the school planted 235 saplings, 15 of which did not survive, then 235 - 15 =<gadget id="calculator">235-15</gadget><output>220</output> 220 saplings survived. All the 15 of them that were replanted survived, so there were a total of 220 + 15 =<gadget id="calculator">220+15</gadget><output>235</output> 235 saplings. If there were 235 saplings planted, and 15 survived after being replanted, then 235 - 15 =<gadget id="calculator">235-15</gadget><output>220</output> 220 saplings survived. Since there were 220 saplings, the survival rate is 220 / 220 =<gadget id="calculator">220/220</gadget><output>1</output> 1 for the survival rate.<result>1</result> |
ape210k__01012041 | Among 3, -3, -0.9, +7, -(1/3), how many negative numbers are there? | 在3、-3、-0.9、+7、-(1/3)中，负数有多少个． | <result>3</result> | 3 | 3 | x=3 | calcformer-instruct-flan-xl_step-128k | -0.9 represents two negative numbers. -(1/3) represents one negative number. Among 3, -3, -0.9, +7, there are three negative numbers. Therefore, the answer is 3 negative numbers.<result>3</result> | The first one is negative: -3. The second one is negative: -0.9. The third one is negative: -(1/3). The only two negative numbers are -0.9 and -(1/3). So, there are only two negative numbers among 3, -3, and (-(1/3)).<result>2</result> |
ape210k__01193587 | Calculation: ((498*381+382)/(382*498-116)). | 计算：((498*381+382)/(382*498-116))． | <gadget id="calculator">498 * 381</gadget>
<output>189_738</output>
<gadget id="calculator">189_738 + 382</gadget>
<output>190_120</output>
<gadget id="calculator">382 * 498</gadget>
<output>190_236</output>
<gadget id="calculator">190_236 - 116</gadget>
<output>190_120</output>
<gadget id="calculator">190_120 / 190_120</gadget>
<output>1</output>
<result>1</result> | 1 | 1 | x=((498*381+382)/(382*498-116)) | calcformer-instruct-flan-xl_step-128k | 498 * 381 + 382 =<gadget id="calculator">498 * 381 + 382</gadget><output>190_120</output><gadget id="calculator">382 * 498 - 116</gadget><output>190_120</output><gadget id="calculator">190_120 / 190_120</gadget><output>1</output><result>1</result> | 498 * 381 + 382 = 1073 + 382<gadget id="calculator">1073 / 382</gadget><output>1_073/382 = around 2.808901</output><gadget id="calculator">382 * 498</gadget><output>190_236</output><gadget id="calculator">190_236 - 116</gadget><output>190_120</output><gadget id="calculator">(1_073/382) / 190_120</gadget><output>1_073/72_625_840 = around 0.000015</output><result>1_073/72_625_840 = around 0.000015</result> |
ape210k__00830517 | A and B have opened a passenger railway line, and there are 7 stations along the way. How many possible tickets should the railway department prepare for this railway? | 甲、乙两地开通了一条客运铁路线，沿途共有7个车站，铁路部门共要为这条铁路准备多少种可能的车票？ | <gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">7 * 6</gadget>
<output>42</output>
<result>42</result> | 42 | 42 | x=7*(7-1) | calcformer-instruct-flan-xl_step-128k | If the number of stations along the railway line is 7 then the number of possible tickets to be prepared is 7P2 = 7*6=<gadget id="calculator">7*6</gadget><output>42</output> 42.<result>42</result> | There are 7 stations along the railway line, so the number of possible tickets for the passengers is 7 - 1 =<gadget id="calculator">7-1</gadget><output>6</output> 6 stations. Since from A to B there are 2 possible ways, the railway department should prepare 6 x 2 =<gadget id="calculator">6*2</gadget><output>12</output> 12 different tickets.<result>12</result> |
ape210k__00573593 | A cylinder and a cone have the same volume and height. It is known that the circumference of the cylinder is 12.56dm and the height is 3dm. What is the area of the base of the cone in square decimeters? | 一个圆柱和一个圆锥的体积和高都相等，已知圆柱的周长是12.56dm，高是3dm，求圆锥的底面积是多少平方分米？ | <gadget id="calculator">12.56 / 3.14 / 2</gadget>
<output>2</output>
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">3 / 3</gadget>
<output>1</output>
<gadget id="calculator">3.14 * 4 * 3 * 1</gadget>
<output>37.68</output>
<result>37.68</result> | 37.68 | 37.68 | x=3.14*(12.56/3.14/2)**(12.56/3.14/2)*3*3/3 | calcformer-instruct-flan-xl_step-128k | The volume of the cylinder is 12.56*3 =<gadget id="calculator">12.56*3</gadget><output>37.68</output> 37.68dm3. Since a volume is equal to the area of the volume times the height of the volume, then 37.68/3 =<gadget id="calculator">37.68/3</gadget><output>12.56</output> 12.56 is the volume of the cone. Since the volume is same, then the area of the base of the cone is 3*12.56 =<gadget id="calculator">3*12.56</gadget><output>37.68</output> 37.68.<result>37.68</result> | The volume of the cylinder is 12.56*3=<gadget id="calculator">12.56*3</gadget><output>37.68</output> 37.68 dm3. The volume of the cone is 37.68*3=<gadget id="calculator">37.68*3</gadget><output>113.04</output> 113.04 dm3. Since a cone has the same volume as a cylinder, the volume of a cone is also 113.04 dm3. The volume of a sphere is pi*r*r, where r is the radius and r is the height of a sphere. The area of a sphere is pi*r*r = 113.04 * 3.14 =<gadget id="calculator">113.04*3.14</gadget><output>354.9456</output> 354.9456.<result>354.9456</result> |
ape210k__01089651 | There are 24 girls in Class 1, Grade 6, and there are more boys than girls (1/6). The number of students who can swim accounts for the whole class (3/4). How many students can swim? | 六年级一班的女生有24人，男生比女生多(1/6)，会游泳的学生人数占全班人数的(3/4)，会游泳的学生有多少人？ | <gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 + (1/6)</gadget>
<output>7/6 = around 1.166667</output>
<gadget id="calculator">24 * (7/6)</gadget>
<output>28</output>
<gadget id="calculator">24 + 28</gadget>
<output>52</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">52 * (3/4)</gadget>
<output>39</output>
<result>39</result> | 39 | 39 | x=(24+24*(1+(1/6)))*(3/4) | calcformer-instruct-flan-xl_step-128k | There are 24 x 1/6 =<gadget id="calculator">24*1/6</gadget><output>4</output> 4 more boys than 24 girls. There are a total of 24 + 4 =<gadget id="calculator">24+4</gadget><output>28</output> 28 boys and girls in class. There are a total of 28 + 24 =<gadget id="calculator">28+24</gadget><output>52</output> 52 students. The proportion of students who can swim is 3/4, and thus there are 52 x 3/4 =<gadget id="calculator">52*3/4</gadget><output>39</output> 39 students who can swim.<result>39</result> | There are 1/6 x 24 =<gadget id="calculator">1/6*24</gadget><output>4</output> 4 more boys than girls in Class 1, Grade 6. That means there are 24 + 4 =<gadget id="calculator">24+4</gadget><output>28</output> 28 boys. There are 24 + 28 =<gadget id="calculator">24+28</gadget><output>52</output> 52 students in Class 1, Grade 6. So, there are 52 + 24 =<gadget id="calculator">52+24</gadget><output>76</output> 76 students altogether. Out of these, there are 3 x 76 =<gadget id="calculator">3*76</gadget><output>228</output> 228 students who can swim.<result>228</result> |
ape210k__00050066 | The farm needs to harvest 1,300 hectares of wheat. It was originally planned to harvest 60 hectares per day. After 5 days of harvesting, it will be changed to 50 hectares per day. How many days will it take to complete? | 农场要收割1300公顷小麦，原计划每天收割60公顷，收割5天后改为每天收割50公顷，还需要多少天才能完成？ | <gadget id="calculator">60 * 5</gadget>
<output>300</output>
<gadget id="calculator">1_300 - 300</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 / 50</gadget>
<output>20</output>
<result>20</result> | 20 | 20 | x=(1300-60*5)/50 | calcformer-instruct-flan-xl_step-128k | The first part of the harvesting will take 5 days * 60 hectares =<gadget id="calculator">5*60</gadget><output>300</output> 300 hectares. This means there is still 1300 - 300 =<gadget id="calculator">1300-300</gadget><output>1_000</output> 1000 hectares of wheat to be harvested. This means the final part of the harvest will take 1000 hectares / 50 hectares per day =<gadget id="calculator">1000/50</gadget><output>20</output> 20 days.<result>20</result> | After 5 days, the amount of land that is to be harvested is 120 hectares. So the total amount of work left to be done is 1300 - 120 =<gadget id="calculator">1300-120</gadget><output>1_180</output> 1180 hectares. This can be done by dividing the total work by the amount of hectares harvested each day, 1180 / 50 =<gadget id="calculator">1180/50</gadget><output>118/5 = around 23.6</output> 23.6 days.<result>23.6</result> |
ape210k__01128889 | Gardeners are planting trees beside a road. Plant 12 pine trees, plant three times as many willows as pine trees, and plant twice as many plane trees as willows. How many sycamore trees are planted? | 园林工人在一条公路旁栽树木．栽松树12棵，栽的柳树是松树的3倍，栽的梧桐树是柳树的2倍．栽的梧桐树有多少棵？ | <gadget id="calculator">12 * 3 * 2</gadget>
<output>72</output>
<result>72</result> | 72 | 72 | x=12*3*2 | calcformer-instruct-flan-xl_step-128k | First find how many willow trees are planted: 12 pine trees * 3 willows/pine =<gadget id="calculator">12*3</gadget><output>36</output> 36 willows. Then multiply that number by 2: 36 willow trees * 2 =<gadget id="calculator">36*2</gadget><output>72</output> 72 sycamore trees.<result>72</result> | The gardeners planted 12 x 3 =<gadget id="calculator">12*3</gadget><output>36</output> 36 willow trees. They planted 36 x 2 =<gadget id="calculator">36*2</gadget><output>72</output> 72 plane trees. Hence, 72 x 2 =<gadget id="calculator">72*2</gadget><output>144</output> 144 sycamore trees were planted.<result>144</result> |
ape210k__00117840 | The area of a parallelogram is 80 square centimeters and the height is 5 centimeters. What is the length of the base corresponding to the height in centimeters? | 一个平行四边形的面积是80平方厘米，高是5厘米，与这条高对应的底边长是多少厘米 | <gadget id="calculator">80 / 5</gadget>
<output>16</output>
<result>16</result> | 16 | 16 | x=80/5 | calcformer-instruct-flan-xl_step-128k | Since 80 centimeters is equal to 5 centimeters, then the base of the parallelogram is 80/5=<gadget id="calculator">80/5</gadget><output>16</output> 16 centimeters.<result>16</result> | 80/5 =<gadget id="calculator">80/5</gadget><output>16</output> 16 centimeters. The base of the parallelogram is 16/5=<gadget id="calculator">16/5</gadget><output>16/5 = around 3.2</output> 3.2 centimeters.<result>16/5 = around 3.2</result> |
ape210k__00990621 | The sum of the upper and lower bases of a trapezoid is 14.4 decimeters, and the height is 3 decimeters. What is the area of the trapezoid in square decimeters? | 一个梯形的上、下底的和为14.4分米，高是3分米，这个梯形的面积是多少平方分米． | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">14.4 * (3/2)</gadget>
<output>21.6</output>
<result>21.6</result> | 21.6 | 21.6 | x=14.4*3/2 | calcformer-instruct-flan-xl_step-128k | The height of a trapezoid is 3/2=<gadget id="calculator">3/2</gadget><output>3/2 = around 1.5</output> 1.5 times the height of the base. The area of a trapezoid is 1/2*(Base)*Height= (1/2)*14.4*3=<gadget id="calculator">(1/2)*14.4*3</gadget><output>21.6</output> 21.6.<result>21.6</result> | The height of the trapezoid is 3/2 =<gadget id="calculator">3/2</gadget><output>3/2 = around 1.5</output> 1.5 decimeters. The area of the trapezoid is the half-length of the base times the height, or 1.44 * 1.5 =<gadget id="calculator">1.44*1.5</gadget><output>2.16</output> 2.16 square decimeters.<result>2.16</result> |
ape210k__00401207 | The road repair team needs to repair a section of road, 2.2km a day, and it can be completed in 15 days. If an extra 0.8km is repaired every day, how many days can it be completed? | 修路队要修一段公路，每天修2.2km，15天可以修完，如果每天多修0.8km，多少天可以修完？ | <gadget id="calculator">2.2 * 15</gadget>
<output>33</output>
<gadget id="calculator">2.2 + 0.8</gadget>
<output>3</output>
<gadget id="calculator">33 / 3</gadget>
<output>11</output>
<result>11</result> | 11 | 11 | x=(2.2*15)/(2.2+0.8) | calcformer-instruct-flan-xl_step-128k | The section of the road that needs to be repaired is 2.2km x 15 =<gadget id="calculator">2.2*15</gadget><output>33</output> 33km. If an extra 0.8km is repaired every day, then it's 2.2 + 0.8 =<gadget id="calculator">2.2+0.8</gadget><output>3</output> 3km. The section of the road that needs to be repaired in 33km / 3km/day =<gadget id="calculator">33/3</gadget><output>11</output> 11days.<result>11</result> | A section of the road is 2.2km x 15 =<gadget id="calculator">2.2*15</gadget><output>33</output> 33km long. If an extra 0.8km is repaired every day, then the total length repaired will be 3.2km. So the road repair will take 33km / 3.2 km/day =<gadget id="calculator">33/2</gadget><output>33/2 = around 16.5</output> 16.5 days.<result>16.5</result> |
ape210k__00006133 | The red scarf team participated in the activity of learning from Lei Feng. Every group of 6 people or every group of 9 people is just finished, how many people are there at least in this team. | 红领巾小队参加学雷锋活动．每6人分一组或每9人分一组都正好分完，这个小队至少有多少人． | <gadget id="calculator">2 * 3 * 3</gadget>
<output>18</output>
<result>18</result> | 18 | 18 | x=2*3*3 | calcformer-instruct-flan-xl_step-128k | Every group of 3 numbers is just finished, so the red scarf team must have at least 6 * 3 = 18 people.<result>18</result> | Every time we divide by 3, we get a remainder of 1. So, we divide by 3 twice to get a remainder of 3. So, by doing this, we get 3 times 3 as remainder. So, the red scarf team consists of 3 * 3=<gadget id="calculator">3 * 3</gadget><output>9</output> 9 people.<result>9</result> |
ape210k__00655265 | In the zoo, the elephants ate a total of 1053 kilograms of food in the first 3 days of a week, and an average of 400 kilograms of food per day in the last 4 days. How many kilograms of food did the elephants eat on average this week? | 动物园里，大象一周的前3天共吃食物1053千克，后4天平均每天吃食物400千克，大象这一周平均每天吃多少千克食物？ | <gadget id="calculator">400 * 4</gadget>
<output>1_600</output>
<gadget id="calculator">1_053 + 1_600</gadget>
<output>2_653</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">2_653 / 7</gadget>
<output>379</output>
<result>379</result> | 379 | 379 | x=(1053+400*4)/(3+4) | calcformer-instruct-flan-xl_step-128k | In the last 4 days, the elephants ate 4 * 400 =<gadget id="calculator">4*400</gadget><output>1_600</output> 1600 kilograms of food. In total, the elephants ate 1053 + 1600 =<gadget id="calculator">1053+1600</gadget><output>2_653</output> 2653 kilograms of food in three days and in the last 4 days. Therefore, they ate a total of 2653 / 7 =<gadget id="calculator">2653/7</gadget><output>379</output> 379 kilograms of food per day.<result>379</result> | In the last 4 days, the elephants ate an average of 400 kg/day * 4 days =<gadget id="calculator">400*4</gadget><output>1_600</output> 1600 kilograms of food. In total, the elephants ate 1053 kilograms of food in the first 3 days + 1600 kilograms of food in the last 4 days =<gadget id="calculator">1053/160</gadget><output>1_053/160 = around 6.58125</output> 6.58125 kilograms of food. The elephants ate a total of 6.58125 kilograms of food over the week. Therefore, elephants ate 6.58125 kilograms of food on average per day.<result>6.58125</result> |
ape210k__00228545 | A piece of iron wire is welded into a rectangular parallelepiped frame with a base circumference of 20 decimeters and a height of 6 decimeters (neglecting the weld joints), how long is the wire. | 一根铁丝焊成了一个底面周长20分米，高6分米的长方体框架，(焊口接头忽略不计)，这根铁丝长多少． | <gadget id="calculator">20 * 2</gadget>
<output>40</output>
<gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">40 + 24</gadget>
<output>64</output>
<result>64</result> | 64 | 64 | x=20*2+6*4 | calcformer-instruct-flan-xl_step-128k | The base is 20*2=<gadget id="calculator">20*2</gadget><output>40</output> 40. The height is 6*4=<gadget id="calculator">6*4</gadget><output>24</output> 24. The total circumference is 40+24=<gadget id="calculator">40+24</gadget><output>64</output> 64.<result>64</result> | The circumference of a square is given by C = w h, where C is the length of one side of the square and w is the length of the other side. If we calculate the circumference of the base first, we get C = 20 / 2 =<gadget id="calculator">20/2</gadget><output>10</output> 10 meters. We can find the height of the square by finding the L = W h, so it is 10 + 6 =<gadget id="calculator">10+6</gadget><output>16</output> 16 meters. Now add all the sides of the square, we get P = 16 + P = 20 =<gadget id="calculator">16+20</gadget><output>36</output> 36 meters. Since the perimeter of the square is the length of the four sides, we can find the total length of the wire by finding the sum of all four sides, which comes to P = 36 meters.<result>36</result> |
ape210k__00218313 | There are 10 red balls and 10 yellow balls in the bag, at least how many balls must be touched to ensure that there are red balls and yellow balls. | 袋子里有10个红球和10个黄球，至少要摸多少个球才能保证有红球和黄球． | <gadget id="calculator">10 + 1</gadget>
<output>11</output>
<result>11</result> | 11 | 11 | x=10+1 | calcformer-instruct-flan-xl_step-128k | 10 + 1 =<gadget id="calculator">10+1</gadget><output>11</output> 11.<result>11</result> | 10+10 =<gadget id="calculator">10+10</gadget><output>20</output> 20 balls must be touched to ensure that there are red balls and yellow balls.<result>20</result> |
ape210k__00385325 | The construction of a section of railway was planned to be completed in 20 days, and 0.54 km was repaired per day, but the task was actually completed in only 18 days. How many kilometers was actually repaired on average per day? | 修一段铁路，计划20天完成，每天修0.54千米，实际只用18天就完成了任务，实际平均每天修多少千米？ | <gadget id="calculator">0.54 / 18</gadget>
<output>0.03</output>
<gadget id="calculator">20 * 0.03</gadget>
<output>0.6</output>
<result>0.6</result> | 0.6 | 0.6 | x=20*0.54/18 | calcformer-instruct-flan-xl_step-128k | The total distance of the railway project was to be completed in 20 days, which means 20 * 0.54 =<gadget id="calculator">20*0.54</gadget><output>10.8</output> 10.8 km. The railway project was actually completed in 18 days, which means that 10.8 / 18 =<gadget id="calculator">10.8/18</gadget><output>0.6</output> 0.6 km per day was actually repaired.<result>0.6</result> | The total work was to be completed in 20 * 0.54 =<gadget id="calculator">20*0.54</gadget><output>10.8</output> 10.8 km. The remaining work to be completed was 10.8 - 18.4 =<gadget id="calculator">10.8-18.4</gadget><output>-7.6</output> -7.6 km. So, the actual amount of work to be done was 6.7 / 18 =<gadget id="calculator">6.7/18</gadget><output>0.372222</output> 0.372222 km/day.<result>0.372222</result> |
ape210k__00723763 | Multiply the numerator of (5/9) by 3, how much should be added to the denominator to keep the size of the fraction constant | 将(5/9)的分子乘3，要使分数的大小不变，分母应加上多少 | <gadget id="calculator">3 * 9</gadget>
<output>27</output>
<gadget id="calculator">27 - 9</gadget>
<output>18</output>
<result>18</result> | 18 | 18 | x=(3*9)-9 | calcformer-instruct-flan-xl_step-128k | 9*3=27 9-3=<gadget id="calculator">9-3</gadget><output>6</output> 6 9*6=36 36-9=27. Answer is 27-9=<gadget id="calculator">27-9</gadget><output>18</output> 18 18 divided by 5 is 9/18.<result>18</result> | 9 * 3=<gadget id="calculator">9 * 3</gadget><output>27</output> 27 27 - 9=<gadget id="calculator">27 - 9</gadget><output>18</output> 18 18/9=<gadget id="calculator">18/9</gadget><output>2</output> 2 added to the denominator.<result>2</result> |
ape210k__00755087 | Teacher Hu of Class 5 and 4 awarded 37 pens and 41 exercise books to the "three good students" on average. As a result, there were 2 more pens and one less exercise book. How many "three good students" are there at most? | 五4班胡老师把37只钢笔和41本练习本平均奖给"三好学生"结果钢笔多了2只，练习本少了1本，"三好学生"最多有多少人？ | <result>7</result> | 7 | 7 | x=7 | calcformer-instruct-flan-xl_step-128k | The answer is 7 because 37 / 2 =<gadget id="calculator">37/2</gadget><output>37/2 = around 18.5</output> 18.5.<result>7</result> | Two groups of 3 students each got 37 pens, so there are 7 groups of 3 students at most. Since each pen is increased by 2, there must be more than 7 pens to maximize the number of "three good students" Then, the same process can be used to find out how many exercise books were divided among the 3 groups of 3 students. Since each exercise book is decreased by 1, there must be less than 41 exercise books to minimize the number of exercise books. Thus, the only possibilities are 3 groups of 3 students or 2 groups of 3 students per exercise book. Therefore, the maximum number of "three good students" is 7 + 2 =<gadget id="calculator">7+2</gadget><output>9</output> 9 students in class 5 and 4.<result>9</result> |
ape210k__00728055 | There is an equilateral triangle flower bed in the school garden, each side of the flower bed is 7 meters long, what is the perimeter of the flower bed in meters? | 学校花园里有一个等边三角形的花坛，花坛每边长7米，这个花坛的周长多少米？ | <gadget id="calculator">3 * 7</gadget>
<output>21</output>
<result>21</result> | 21 | 21 | x=3*7 | calcformer-instruct-flan-xl_step-128k | Each side of the equilateral triangle flower bed, which is 7 meters long, is 7 x 3 =<gadget id="calculator">7*3</gadget><output>21</output> 21 meters long. Therefore, the perimeter of the flower bed is 21 meters long.<result>21</result> | Each side of the flower bed is 7 meters long so the total length of the equilateral triangle is 3 * 7 =<gadget id="calculator">3*7</gadget><output>21</output> 21 meters. There are 3 sides of a flower bed so the perimeter is 3 * 21 =<gadget id="calculator">3*21</gadget><output>63</output> 63 meters.<result>63</result> |
ape210k__00317583 | At the sports meeting, 315 students participated in the gymnastics performance. They are divided into 7 teams on average, and each team is divided into 5 groups on average. How many students are there in each group? | 运动会上315个同学参加体操表演．他们平均分成7个队，每队平均分成5组，每组有多少个同学？ | <gadget id="calculator">315 / 7 / 5</gadget>
<output>9</output>
<result>9</result> | 9 | 9 | x=315/7/5 | calcformer-instruct-flan-xl_step-128k | 315 students are divided into 7 teams, so there are 315/7 =<gadget id="calculator">315/7</gadget><output>45</output> 45 groups of students. Thus, there are 45 students / 5 groups =<gadget id="calculator">45/5</gadget><output>9</output> 9 students in each group.<result>9</result> | 315 students are divided into 7 teams, which means there are 315/7 =<gadget id="calculator">315/7</gadget><output>45</output> 45 groups. There are 45 students in each group.<result>45</result> |
ape210k__00302862 | After expanding 0.58 to 100 times of its original size, and then reducing it to (1/10), what is the number | 将0.58扩大到原来的100倍后，再缩小到它的(1/10)，这个数是多少 | <result>5.8</result> | 5.8 | 5.8 | x=5.8 | calcformer-instruct-flan-xl_step-128k | 100*0.58 =<gadget id="calculator">100*0.58</gadget><output>58</output> 58 58/10 = around 5.8<result>5.8</result> | 58*100*10/100 =<gadget id="calculator">58*100*10/100</gadget><output>580</output> 580.<result>580</result> |
ape210k__01018223 | How many 0s are there at the end of the product of 560*5? | 560*5的积的末尾有多少个0． | <result>2</result> | 2 | 2 | x=2 | calcformer-instruct-flan-xl_step-128k | There are two 0s at the end of the product because 5 x 0 =<gadget id="calculator">5*0</gadget><output>0</output> 0. There are no 0s at the end because 5 - 0 = 0. There are 2 0s at the end of the product because 560 - 5 =<gadget id="calculator">560-5</gadget><output>555</output> 555.<result>2</result> | There are 2 0s at the end of the product because 5 x 0.5 =<gadget id="calculator">5*0.5</gadget><output>2.5</output> 2.5. This means there are 1 more 0 at the end of the product because 5 - 2.5 =<gadget id="calculator">5-2.5</gadget><output>2.5</output> 2.5.<result>1</result> |
ape210k__00782761 | Hongguang Farm raised 425 chicks, 408 hens, 25 roosters, and 78 ducks. How many times more chickens are there than ducks? | 红光饲养场养了小鸡425只，母鸡408只，公鸡25只，鸭子78只，问养的鸡的只数是鸭的多少倍？ | <gadget id="calculator">425 + 408 + 25</gadget>
<output>858</output>
<gadget id="calculator">858 / 78</gadget>
<output>11</output>
<result>11</result> | 11 | 11 | x=(425+408+25)/78 | calcformer-instruct-flan-xl_step-128k | First find the total number of chickens: 425 chicks + 408 hens + 25 roosters =<gadget id="calculator">425+408+25</gadget><output>858</output> 858 chickens. Then divide the number of chickens by the number of ducks to find the number of times the chickens are more than the ducks: 858 chickens / 78 ducks =<gadget id="calculator">858/78</gadget><output>11</output> 11 times.<result>11</result> | The total number of chickens is 425 chicks + 408 hens + 25 roosters =<gadget id="calculator">425+408+25</gadget><output>858</output> 858. The number of ducks is 78 ducks / 858 ducks =<gadget id="calculator">78/858</gadget><output>1/11 = around 0.090909</output> 0.090909. Thus, there are 858 ducks / 0.09090929 =<gadget id="calculator">858/0.1090929</gadget><output>7_864.856466</output> 786.485666.<result>7_864.85664</result> |
ape210k__00841723 | The automobile factory produces 2,400 vehicles this year, an increase of 20% over last year. How many vehicles were produced last year? | 汽车厂今年生产汽车2400辆，比去年增产20%，去年生产汽车多少辆？ | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">2_400 / (6/5)</gadget>
<output>2_000</output>
<result>2_000</result> | 2_000 | 2,000 | x=2400/(1+20%) | calcformer-instruct-flan-xl_step-128k | The total number of vehicles produced last year is 2400/1.2=<gadget id="calculator">2400/1.2</gadget><output>2_000</output> 2000.<result>2_000</result> | This year, there is an increase of 20/100 * 1 =<gadget id="calculator">20/100*1</gadget><output>1/5 = around 0.2</output> 0.2. Thus, the total number of vehicles produced is 1.20 * 1 =<gadget id="calculator">1.20*1</gadget><output>1.2</output> 1.2. Therefore, last year the factory produced 1,200 vehicles.<result>1_200</result> |
ape210k__00513114 | A cube of iron with a side length of 6 cm is melted and cast into a cuboid. The base area of this cuboid is 72 square centimeters. What is the height in centimeters? | 把一个棱长是6厘米的正方体铁块，熔铸成一个长方体，这个长方体的底面积是72平方厘米，高是多少厘米？ | <gadget id="calculator">6 / 72</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">6 * 6 * (1/12)</gadget>
<output>3</output>
<result>3</result> | 3 | 3 | x=6*6*6/72 | calcformer-instruct-flan-xl_step-128k | The volume of the iron is 6*6*6 =<gadget id="calculator">6*6*6</gadget><output>216</output> 216 cm3. The volume of this cuboid is equal to 72 square centimeters, so the height of the iron is 216/72 =<gadget id="calculator">216/72</gadget><output>3</output> 3 cm.<result>3</result> | The volume of the iron that is being melted is 6 * 6 * 6 =<gadget id="calculator">6*6*6</gadget><output>216</output> 216 cm3. The volume that is contained in a 72 square centimeter cuboid is 72 square centimeters / 72 square centimeters =<gadget id="calculator">72/72</gadget><output>1</output> 1 cubic centimeter. The height of the iron cuboid is 216 cm / 1 cubic centimeter =<gadget id="calculator">216/1</gadget><output>216</output> 216 centimeters.<result>216</result> |
ape210k__00016947 | Distribute 8 apples equally to 2 children, how much of these apples each child gets | 把8个苹果平均分给2个小朋友，每个小朋友分得这些苹果的多少 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<result>1/2 = around 0.5</result> | 1/2 | 0.5 | x=1/2 | calcformer-instruct-flan-xl_step-128k | 1 child gets 8 apples and each child gets 8/2 =<gadget id="calculator">8/2</gadget><output>4</output> 4 apples. Therefore, each child gets 4/8 = 1/2 of an apple.<result>1/2 = around 0.5</result> | The children each get 2 apples, so each child gets 2 apples / 2 children = 1 apple / child. To solve this problem, you can calculate 1 child’s share / total share. To determine the share each child gets, divide the total share by the total share. In this case, the total share is 2 apples / 2 children = 1 apple / child.<result>1</result> |
ape210k__00373254 | A rectangular test field is 80 meters long and 35 meters wide. What is the circumference in meters? | 一块长方形试验田，长80米，宽35米，周长是多少米？ | <gadget id="calculator">80 + 35</gadget>
<output>115</output>
<gadget id="calculator">115 * 2</gadget>
<output>230</output>
<result>230</result> | 230 | 230 | x=(80+35)*2 | calcformer-instruct-flan-xl_step-128k | The combined length for the rectangular field is 80 + 35 =<gadget id="calculator">80+35</gadget><output>115</output> 115 meters. The circumference of the rectangular field is 115 * 2 =<gadget id="calculator">115*2</gadget><output>230</output> 230 meters.<result>230</result> | First calculate the perimeter of the rectangle by adding the length and the width: 80 meters + 35 meters =<gadget id="calculator">80+35</gadget><output>115</output> 115 meters. The answer is 115 meters.<result>115</result> |
ape210k__01147277 | If in 56*18, the first factor is doubled and the second factor remains unchanged, how much is the product enlarged? | 如果56*18中，第一个因数扩大2倍，第二个因数不变，则积扩大多少． | <result>2</result> | 2 | 2 | x=2 | calcformer-instruct-flan-xl_step-128k | The result is 2 times the original result.<result>2</result> | The original factor is 56. When the factor is doubled, the result is 256 times.<result>256</result> |
ape210k__00043895 | The area of a vegetable field is 30.2 square meters. Grandma's house has two such vegetable plots. How many square meters are there in total? | 一块菜地的面积是30.2平方米．奶奶家有两块这样的菜地，一共有多少平方米？ | <result>60.2</result> | 60.2 | 60.2 | x=60.2 | calcformer-instruct-flan-xl_step-128k | There are 30.2 * 2 =<gadget id="calculator">30.2*2</gadget><output>60.4</output> 60.4 square meters.<result>60.4</result> | Each plot is 30.2 * 2 =<gadget id="calculator">30.2*2</gadget><output>60.4</output> 60.4 square meters. Therefore, there are a total of 60.4 + 30.2 =<gadget id="calculator">60.4+30.2</gadget><output>90.6</output> 90.6 square meters.<result>90.6</result> |
ape210k__00839913 | This year's Teacher's Day, the number of excellent teachers commended by Jianghai Education Bureau increased by 50 compared with last year, an increase of (1/5) compared with last year. How many outstanding teachers were honored by the Education Bureau last year? | 今年教师节，江海市教育局表彰的优秀教师比去年增加了50名，比去年增加了(1/5)．去年教育局表彰了多少名优秀教师？ | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">50 / (1/5)</gadget>
<output>250</output>
<result>250</result> | 250 | 250 | x=50/(1/5) | calcformer-instruct-flan-xl_step-128k | We calculate 50 as (1/5)*X, thus X=50*5 =<gadget id="calculator">50*5</gadget><output>250</output> 250.<result>250</result> | If 50 is 1/5 of the total number of teachers honored last year, then there were 50/5 =<gadget id="calculator">50/5</gadget><output>10</output> 10 teachers honoring outstanding teachers. Originally, the number of outstanding teachers honored by the Education Bureau was 10*100 =<gadget id="calculator">10*100</gadget><output>1_000</output> 1000.<result>1_000</result> |
ape210k__00550043 | The two wrote a total of 180 brush characters in 3 days. How many characters do they write each day on average? | 两人3天共写了180个毛笔字，平均每人每天写多少个字？ | <gadget id="calculator">180 / 3 / 2</gadget>
<output>30</output>
<result>30</result> | 30 | 30 | x=180/3/2 | calcformer-instruct-flan-xl_step-128k | They write 180/3=<gadget id="calculator">180/3</gadget><output>60</output> 60 characters in three days. So they write 60/2=<gadget id="calculator">60/2</gadget><output>30</output> 30 characters each day.<result>30</result> | They wrote 180 / 3 / 2=<gadget id="calculator">180/3*2</gadget><output>120</output> 120 characters each day.<result>120</result> |
ape210k__00498424 | In the rope skipping competition, Liu Hong jumped 160 times, Li Ming's number of jumps was Liu Hong's (5/8), and Zhang Hua's number of jumps was Li Ming's (4/5), how many times did Zhang Hua jump? ? | 跳绳比赛中，刘红跳了160下，李明跳的下数是刘红的(5/8)，而张华跳的下数是李明的(4/5)，张华跳了多少下？ | <gadget id="calculator">5 / 8</gadget>
<output>5/8 = around 0.625</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">160 * (5/8) * (4/5)</gadget>
<output>80</output>
<result>80</result> | 80 | 80 | x=160*(5/8)*(4/5) | calcformer-instruct-flan-xl_step-128k | Liu Hong jumped 160 times and Li Ming's number of jumps was 5/8 of that number, which is 5/8*160 =<gadget id="calculator">5/8*160</gadget><output>100</output> 100. Zhang Hua's number of jumps was 4/5 of that number, which is 4/5*100 =<gadget id="calculator">4/5*100</gadget><output>80</output> 80.<result>80</result> | Zhang Hua's number of jumps was 4/5 of Liu Hong's 160 jumps, which is 4/5*160=<gadget id="calculator">4/5*160</gadget><output>128</output> 128 times.<result>128</result> |
ape210k__00259440 | score was calculated twice with 2, and then calculated with 3, and finally (4/9) was obtained. What was the original score? | 一个分数用2约了2次，再用3约了一次，最后得(4/9)，这个分数原来是多少 | <gadget id="calculator">4 / 9</gadget>
<output>4/9 = around 0.444444</output>
<result>4/9 = around 0.444444</result> | 4/9 | 0.444444 | x=(4/9) | calcformer-instruct-flan-xl_step-128k | Calculating twice with 2 gives 2*2 =<gadget id="calculator">2*2</gadget><output>4</output> 4. Calculating with 3 gives 3*3 =<gadget id="calculator">3*3</gadget><output>9</output> 9. Thus, 4/9 = 4/9.<result>4/9 = around 0.444444</result> | The result of multiplying twice with 2 and then dividing by 3 is 12/2 =<gadget id="calculator">12/2</gadget><output>6</output> 6. So, the original score was 6 * (4/9) =<gadget id="calculator">6*4/9</gadget><output>8/3 = around 2.666667</output> 2.666667.<result>8/3 = around 2.666667</result> |
ape210k__00945907 | Calculation: ((1/2)+(1/3)+…+(1/2005))(1+(1/2)+(1/3)+…+(1/2004))-(1+ (1/2)+(1/3)+...+(1/2005))((1/2)+(1/3)+...+(1/2004)). | 计算：((1/2)+(1/3)+…+(1/2005))(1+(1/2)+(1/3)+…+(1/2004))-(1+(1/2)+(1/3)+…+(1/2005))((1/2)+(1/3)+…+(1/2004))． | <gadget id="calculator">1 / 2_005</gadget>
<output>1/2_005 = around 0.000499</output>
<result>1/2_005 = around 0.000499</result> | 1/2_005 | 0.000499 | x=(1/2005) | calcformer-instruct-flan-xl_step-128k | <gadget id="calculator">1 / 2_005</gadget><output>1/2_005 = around 0.000499</output><result>1/2_005 = around 0.000499</result> | <gadget id="calculator">1 / 2_005</gadget><output>1/2_005 = around 0.000499</output><gadget id="calculator">(1/2_005) * (1/2)_005</gadget><output>ERROR: invalid syntax (<string>, line 1)</output><result>ERROR: invalid</result> |
ape210k__00115102 | For a small car, the installment payment is 10% more than the price, and the one-time payment can get a 5% discount. Xiaoqiang's father did some calculations, and the difference between the two payment methods was 15,000 yuan. How much is the price of this car. | 一辆小车，分期付款要比定价多付10%，一次性付款能打九五折．小强的爸爸算了一下，两种付款方式的差价是15000元．这辆车的定价是多少元． | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">95 / 100</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">(1/10) - (19/20)</gadget>
<output>-17/20 = around -0.85</output>
<gadget id="calculator">1 + (-17/20)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">15_000 / (3/20)</gadget>
<output>100_000</output>
<result>100_000</result> | 100_000 | 100,000 | x=15000/(1+10%-95%) | calcformer-instruct-flan-xl_step-128k | If the installment payment is 10% more than the price, then it's 10/100*P = 15000. And if the one-time payment has a 5% discount, then it's 95/100*P =<gadget id="calculator">95/100*p</gadget><output>ERROR: Cannot convert expression to float</output> ERR. So, if 15000 is the difference between the two payment methods, then P-ERR=15000-15000=100000. And since P is the price of the car, then P=100000*(100/105).<result>100_000</result> | The installment payment is 10% more than the price, so it is 10/100*10000 =<gadget id="calculator">10/100*10000</gadget><output>1_000</output> 1000 more than the price without the installment plan. This means that the price of the car is 1000+15000 =<gadget id="calculator">1000+15000</gadget><output>16_000</output> 16000. If the one-time payment has a 5% discount, then it is 95/100*16000 =<gadget id="calculator">95/100*16000</gadget><output>15_200</output> 15200 less than the installment plan. Therefore, the difference between the two payment methods is 16000-15200 = 7200. Therefore, the price of the car is 16000/7200 =<gadget id="calculator">16000/7200</gadget><output>20/9 = around 2.222222</output> 22.222222.<result>20/9 = around 2.222222</result> |
ape210k__00348994 | The school bought 25 small footballs and 14 small volleyballs for a total of 1490 yuan, 40 yuan for each small football, how much is each small volleyball? | 学校买来25个小足球和14个小排球，共花1490元，每个小足球40元，每个小排球多少元？ | <gadget id="calculator">40 * 25</gadget>
<output>1_000</output>
<gadget id="calculator">1_490 - 1_000</gadget>
<output>490</output>
<gadget id="calculator">490 / 14</gadget>
<output>35</output>
<result>35</result> | 35 | 35 | x=(1490-40*25)/14 | calcformer-instruct-flan-xl_step-128k | 25 small footballs * 40 yuan/football =<gadget id="calculator">25*40</gadget><output>1_000</output> 1000 yuan. 1490 yuan - 1000 yuan =<gadget id="calculator">1490-1000</gadget><output>490</output> 490 yuan. So, each volleyball costs 490 yuan/14 =<gadget id="calculator">490/14</gadget><output>35</output> 35 yuan/game.<result>35</result> | The 25 small footballs cost 25 x 40 =<gadget id="calculator">25*40</gadget><output>1_000</output> 1000 yuan. The 14 small volleyballs cost 1490 - 1000 =<gadget id="calculator">1490-10000</gadget><output>-8_510</output> 8510 yuan. So, the cost of each small volleyball is 8510/14=<gadget id="calculator">860-140</gadget><output>720</output> 720 yuan.<result>720</result> |
ape210k__00273189 | Xiao Qiao walks at a speed of 80 m/min. It takes her half an hour to walk from home to school. How many meters is her home from school? | 小巧步行的速度是80米/分，她从家到学校要走半小时，她家离学校有多少米． | <gadget id="calculator">80 * 30</gadget>
<output>2_400</output>
<result>2_400</result> | 2_400 | 2,400 | x=80*30 | calcformer-instruct-flan-xl_step-128k | In 30 minutes, Xio Qiao walks 80 x 30 =<gadget id="calculator">80*30</gadget><output>2_400</output> 2400 meters.<result>2_400</result> | Since there are 60 minutes in an hour, then half of an hour is equal to half of 60 minutes, which is 30 / 60 = 1/2. Thus, the distance between Xio Qiao's home and school is 80 m/min x 1/2 =<gadget id="calculator">80*1/2</gadget><output>40</output> 40 meters.<result>40</result> |
ape210k__00621170 | The ratio of A and B is 3:5. It is known that A is 30 less than B, so what is A's number? | 甲、乙两个数的比是3：5，已知甲比乙少30，那么甲数是多少． | <gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">15 * 3</gadget>
<output>45</output>
<result>45</result> | 45 | 45 | x=30/(5-3)*3 | calcformer-instruct-flan-xl_step-128k | The difference of A and B is 5 - 3 =<gadget id="calculator">5-3</gadget><output>2</output> 2. Thus, B has 30/2 =<gadget id="calculator">30/2</gadget><output>15</output> 15 people. Therefore, A has 15 x 3 =<gadget id="calculator">15*3</gadget><output>45</output> 45.<result>45</result> | If the ratio of A to B is 3:5, then the number of A is 3/5*30=<gadget id="calculator">3/5*30</gadget><output>18</output> 18. A number which is 30 less than B is 18-30=<gadget id="calculator">18-30</gadget><output>-12</output> 12. So the number of A is 18-12=<gadget id="calculator">18-12</gadget><output>6</output> 6.<result>6</result> |
ape210k__00487205 | What is the price of a 160 yuan coat after a 20% discount? | 160元的上衣，打八折后的价钱为多少元． | <gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">160 * (4/5)</gadget>
<output>128</output>
<result>128</result> | 128 | 128 | x=160*80% | calcformer-instruct-flan-xl_step-128k | After the discount, the coat will be sold at 160 x 80/100 =<gadget id="calculator">160*80/100</gadget><output>128</output> 128 yuan.<result>128</result> | The discount is 80/100 x 160 yuan =<gadget id="calculator">80/100*160</gadget><output>128</output> 128 yuan. The price after the discount is 160 yuan - 128 yuan =<gadget id="calculator">160-128</gadget><output>32</output> 32 yuan.<result>32</result> |
ape210k__00183615 | It is known that Sn=1-2+3-4+5-6+...+(-1)n+n, where n is a positive integer. So how much is S2001+S2002=. | 已知Sn=1-2+3-4+5-6+…+(-1)n+n，其中n是正整数．那么S2001+S2002=多少． | <gadget id="calculator">2_001 + 1</gadget>
<output>2_002</output>
<gadget id="calculator">2_002 / 2</gadget>
<output>1_001</output>
<gadget id="calculator">-1_001</gadget>
<output>-1_001</output>
<gadget id="calculator">1_001 + (-1_001)</gadget>
<output>0</output>
<result>0</result> | 0 | 0 | x=((2001+1)/2)+(-(2002/2)) | calcformer-instruct-flan-xl_step-128k | S2001=1-(-1)(-2)+(-2)+1+(-2)+1-2+...+(-1)(2-1)+2-1+1+(-2-1)+2-1+2-1+(-2-1)+2-1+(-1-1)+2-1+(-2-1)+2-1+2-1+2-1+2-1+(-2-1)+2-1+(-2-1)+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-2+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-2+2-1+2-1+2-1+2-1+2-2+2-1+2-1+2+2-1+2-1+1+2-1+2-1+2-1+2-1+2-2+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-2+2-1+2-1+2-1+2-1+2-1 So S2001+S2002=(-1)(-2)+(-1)(-1)+(-2)+1+(-1)(-2-1)+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2+2-1+2-1+2-1+2-1+2-2+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2+2-1+2-1+2-1+2+2-1+2-1+2-1+2-1+2-1+2-1+2-2+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2-1+2+2-1+2-2+2-1=0 Hence S2002+S2002=0-1-0=<gadget id="calculator">0-1-0</gadget><output>-1</output> -1 And since there are 2 positive integers, we get -1-0=<gadget id="calculator">-1-0</gadget><output>-1</output> -1. Since we know that S2002=(-1)(-2)+(-1)(-2)+(-1)(-2)+(-1)(-2)+(-1)(-2)+(-2) +(-1)(-2)+(-2)+(-2)+(-2)+(-2)+(-2)+(-2)+(-2)+(-2)+(-2)+(-2)+(-2)+(-2)+(-2)+(-2)+(-2)+(-2)....+(-2-1+2-1)+(-2-1+2-1)+(-2-1+2-1+2-1+2-1+2+2-1+2-1+2)=0<result>0</result> | For the first half, you get -1/2+1-2-3-4-5-6...+(-1)1/2-2-1 so for the second half, you get -1/2-2-1-3-4...+(-1)1/2-2-1-3-4...+(-1)1/2-2-1-3-4...+(-1)1/2-1-1-1+...+(-1)1/2-1-1+0 So you can notice that S2002 is a much bigger sum than S2001. So S2002 is definitely more than S2001. It also sums up to -1/2 (for example, S2002=-1/2+2-2+3-4+5-6+6+...+(-1)1/2-1+1+0=<gadget id="calculator">-1/2+2-2+3-4+5-6+...+(-1)1/2+1+0</gadget><output>ERROR: invalid syntax (<string>, line 1)</output> ERROR. So S2002 is actually more than S2001. The above result is the same for S2001/2. So we can conclude that S2000 is more than S2002. S2000+S2002=S2000+S2003=S2000+S2003.<result>S2000</result> |
ape210k__00073998 | If the radius of the circle is increased by 4 times, how much will the area of the circle increase? | 圆的半径扩大4倍，这个圆的面积扩大多少 | <result>16</result> | 16 | 16 | x=16 | calcformer-instruct-flan-xl_step-128k | If the radius is increased by 4 times, the radius will increase to 16 times. This results in a bigger area for the circle, which results in a bigger profit for the company.<result>16</result> | If the radius of the circle is increased by 4 times, then the radius increases by 4*4 = 16 times. Therefore the area of the circle will increase 16 times because the area of a circle is pi* radius2. If the radius of the circle is decreased by 4 times, then the radius decreases by 16 times because the area of a circle is pi* radius2. Since the area of the circle is pi* radius2, the area of the circle decreases by 16 times because the area of a circle is pi* pi. The area of the circle increased because 16 x 16 =<gadget id="calculator">16*16</gadget><output>256</output> 256.<result>256</result> |
ape210k__00192683 | The grain store shipped a batch of flour. It was originally planned to use 9 vehicles with 24 bags each to transport it 15 times. Now, it is replaced with 6 vehicles each with 30 bags. How many times can it be transported? | 粮店装运一批面粉，原计划用每辆装24袋的汽车9辆15次可以运完，现在改用每辆可装30袋的汽车6辆来运，几次可以运完？ | <gadget id="calculator">15 / 30 / 6</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">24 * 9 * (1/12)</gadget>
<output>18</output>
<result>18</result> | 18 | 18 | x=24*9*15/30/6 | calcformer-instruct-flan-xl_step-128k | The total number of bags that was initially planned is 9 vehicles * 24 bags/vehicle =<gadget id="calculator">9*24</gadget><output>216</output> 216 bags. Then it was transported 15 times * 216 bags/vehicle =<gadget id="calculator">15*216</gadget><output>3_240</output> 3240 bags. Then it is transported now by 6 vehicles * 30 bags/vehicle =<gadget id="calculator">6*30</gadget><output>180</output> 180 bags. Therefore, it is transported 3240 bags / 180 bags/vehicle =<gadget id="calculator">3240/180</gadget><output>18</output> 18 times.<result>18</result> | The total amount of the flour transported by the 9 vehicles is 9 vehicles * 24 bags/vehicle =<gadget id="calculator">9*24</gadget><output>216</output> 216 bags. Since it was transported 15 times, it is transport by 15 times * 216 bags/vehicle =<gadget id="calculator">15*216</gadget><output>3_240</output> 3240 bags. If the vehicles are each carrying 30 bags, then the total amount of flour transported by 6 vehicles is 6 vehicles * 30 bags/vehicle =<gadget id="calculator">6*30</gadget><output>180</output> 180 bags. Therefore, the amount of time the store has to transport the flour using this method is 180 bags / 180 bags/vehicle =<gadget id="calculator">180/180</gadget><output>1</output> 1 time.<result>1</result> |
ape210k__00539259 | 800 saplings were distributed to 5 classes for planting, and each class distributed the saplings to 4 groups on average. How many saplings did each group get? | 800棵树苗平均分给5个班种植，每个班又将树苗平均分给4个小组，每个小组分得树苗多少棵？ | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">800 / 20</gadget>
<output>40</output>
<result>40</result> | 40 | 40 | x=800/(5*4) | calcformer-instruct-flan-xl_step-128k | The 5 classes had a total of 5 x 4 =<gadget id="calculator">5*4</gadget><output>20</output> 20 groups. So each group received 800/20 =<gadget id="calculator">800/20</gadget><output>40</output> 40 saplings.<result>40</result> | The total number of saplings that the 5 classes received is 5 classes * 800 saplings/class =<gadget id="calculator">5*800</gadget><output>4_000</output> 4000 saplings. The number of saplings that each group received is 4 groups * 4 saplings/group =<gadget id="calculator">4*4</gadget><output>16</output> 16 saplings/group.<result>16</result> |
ape210k__01162741 | The two ropes are 1.27 meters and 1.35 meters long respectively. Connect them, and use 0.2 meters of rope at the interface. How long is the rope after connecting? | 两条绳子分别长1.27米和1.35米，把它们接起来，接口处用去绳子0.2米，接好后的绳子有多长？ | <gadget id="calculator">1.35 - 0.2</gadget>
<output>1.15</output>
<gadget id="calculator">1.27 + 1.15</gadget>
<output>2.42</output>
<result>2.42</result> | 2.42 | 2.42 | x=1.27+1.35-0.2 | calcformer-instruct-flan-xl_step-128k | The combined length of the two ropes is 1.35 meters + 1.27 meters =<gadget id="calculator">1.35+1.27</gadget><output>2.62</output> 2.62 meters. The loss of 0.2 meters from the interface leaves a final length of 2.62 meters - 0.2 =<gadget id="calculator">2.62-0.2</gadget><output>2.42</output> 2.42 meters.<result>2.42</result> | The length of the rope without the interface is 1.35 - 0.2 =<gadget id="calculator">1.35-0.2</gadget><output>1.15</output> 1.15 meters. The length of the rope after connecting is 1.15 + 1.27 =<gadget id="calculator">1.25+1.27</gadget><output>2.52</output> 2.52 meters.<result>2.52</result> |
ape210k__00960381 | A pile of sand, 24 tons have been transported by car, and the rest is more (1/5) than what was transported. How many tons of this pile of sand are left? | 一堆沙子，用汽车已经运走了24吨，剩下的比运走的多(1/5)，这堆沙子剩下多少吨？ | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">24 * (6/5)</gadget>
<output>144/5 = around 28.8</output>
<result>144/5 = around 28.8</result> | 144/5 | 28.8 | x=24*(1+(1/5)) | calcformer-instruct-flan-xl_step-128k | There are 1/5 x 24 tons =<gadget id="calculator">1/5*24</gadget><output>24/5 = around 4.8</output> 4.8 tons of sand that are left. Thus, 24 tons + 4.8 tons =<gadget id="calculator">24+4.8</gadget><output>28.8</output> 28.8 tons are left.<result>28.8</result> | The rest of the pile of sand is 1/5 + 1/5 = 1/5 of what was transported. So, 1/5 x 24 =<gadget id="calculator">1/5*24</gadget><output>24/5 = around 4.8</output> 4.8 tons of sand are left.<result>48</result> |
ape210k__00690257 | cone-shaped sand pile is 3 meters high and the bottom radius is 5 meters. If each cubic meter of sand weighs about 1.7 tons. How many tons does this pile of sand weigh? | 一个圆锥形的沙堆，高是3米，底面半径是5米，如果每立方米的沙约重1.7吨．这堆沙约重多少吨？ | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">(1/3) * 3.14 * 25 * 3</gadget>
<output>78.5</output>
<gadget id="calculator">78.5 * 1.7</gadget>
<output>133.45</output>
<result>133.45</result> | 133.45 | 133.45 | x=((1/3)*3.14*5**2*3)*1.7 | calcformer-instruct-flan-xl_step-128k | The volume of a cone is 1 / 3 so the volume of the pile is (1/3) * 3.14 * 5 * 5*3 =<gadget id="calculator">(1/3) * 3.14 * 5 * 5 * 3</gadget><output>78.5</output> 78.5 cubic meters. The sand stayed in the pile for 78.5 * 1.7 =<gadget id="calculator">78.5*1.7</gadget><output>133.45</output> 133.45 years.<result>133.45</result> | The volume of a cone is given by 1 / 3 by pi*r2*h. So the volume of the sand pile is given by pi*(52)*3 * h = 15*pi*25*3 = 225*pi. The total weight of the sand is 225*pi*1.7 =<gadget id="calculator">225*pi*1.7</gadget><output>382.5*pi = around 1_201.65919</output> 1201.65919 tons.<result>1_201.65919</result> |
ape210k__00542983 | A 3-meter-long square steel, when it is cut into two sections, the surface area increases by 80dm**3, what is the original volume of the square steel? | 一根3米长的方钢，把它横截成2段时，表面积增加80dm**3，原来方钢的体积是多少． | <gadget id="calculator">80 / 2</gadget>
<output>40</output>
<gadget id="calculator">40 * 3 * 10</gadget>
<output>1_200</output>
<result>1_200</result> | 1_200 | 1,200 | x=80/2*3*10 | calcformer-instruct-flan-xl_step-128k | First calculate the surface area of the square steel: 80 dm2 / 2 =<gadget id="calculator">80/2</gadget><output>40</output> 40 dm2 Then multiply the surface area by the number of sides of the square steel to find the total volume: 40 dm2 * 3 meters * 10 dm/meter =<gadget id="calculator">40*3*10</gadget><output>1_200</output> 1200 dm2.<result>1_200</result> | First, we need to find the volume of the square. We do this by performing 80/2=<gadget id="calculator">80/2</gadget><output>40</output> 40 dm3/4=<gadget id="calculator">40/3</gadget><output>40/3 = around 13.333333</output> 13.333333 units. Then we multiply this by 3*100, performing 3*10=<gadget id="calculator">3*10</gadget><output>30</output> 30 dm3. Then we multiply this by 30 to find the total volume. performing 30*3=<gadget id="calculator">30*3</gadget><output>90</output> 90 dm3.<result>90</result> |
ape210k__00437258 | A and B are running together. A runs 1250 meters, which is 80 meters more than twice the distance of B. How many meters did B run? | 甲、乙两人一起跑步．甲跑1250米，比乙的路程的2倍多80米．乙跑多少米？ | <gadget id="calculator">1_250 - 80</gadget>
<output>1_170</output>
<gadget id="calculator">1_170 / 2</gadget>
<output>585</output>
<result>585</result> | 585 | 585 | x=(1250-80)/2 | calcformer-instruct-flan-xl_step-128k | Let x be the distance that B ran. The distance of A is 1250-80=<gadget id="calculator">1250-80</gadget><output>1_170</output> 1170 meters. Then 2*x=1170=<gadget id="calculator">1170/2</gadget><output>585</output> 585 meters.<result>585</result> | Let x be the distance B ran. Then 1250 - 80 =<gadget id="calculator">1250-80</gadget><output>1_170</output> 1170. Thus 2x= 1170.<result>1_170</result> |
ape210k__00385639 | A store can still make a profit of 20% by selling the goods at a discount of 10% off the listed price. The purchase price of the goods is 21 yuan. How much is the price of each item. | 一个商店把货物按标价的9折出售，仍可获利20%，该货物的进价是21元．则每件货物的标价多少元． | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">21 * (1/5)</gadget>
<output>21/5 = around 4.2</output>
<gadget id="calculator">21 + (21/5)</gadget>
<output>126/5 = around 25.2</output>
<gadget id="calculator">(126/5) / 0.9</gadget>
<output>28</output>
<result>28</result> | 28 | 28 | x=(21+21*20%)/(0.9) | calcformer-instruct-flan-xl_step-128k | Let X be listed price for each item. After the store makes a profit of 20%, then the profit becomes 20% * 21 yuan =<gadget id="calculator">20*.01*21</gadget><output>4.2</output> 4.2 yuan. The total amount of X after the discount is 4.2 yuan + 21 yuan =<gadget id="calculator">4.2+21</gadget><output>25.2</output> 25 yuan. The total discount for each item is 25 yuan / 0.9 =<gadget id="calculator">25/0.9</gadget><output>27.777778</output> 27.777778.<result>27.777778</result> | The shopkeeper made a profit of 20%, which is 20/100 * 21 yuan = $<gadget id="calculator">20/100*21</gadget><output>21/5 = around 4.2</output> 4.2. This means that the total selling price was 21 + 4.2 =<gadget id="calculator">21+4.2</gadget><output>25.2</output> 255.2. The total number of items sold was 21 + 255.2 =<gadget id="calculator">21+255.2</gadget><output>276.2</output> 276.2. The percentage of the selling price that was discounted was 90/100 * 276.2 =<gadget id="calculator">90/100*276.2</gadget><output>248.58</output> 248.58. This means that the price per item was 276.28/248.58 = $<gadget id="calculator">276.28/248.58</gadget><output>1.111433</output> 1.11433.<result>1.111433</result> |
ape210k__00104014 | A road construction team needs to build 445 meters of road, and 237 meters have been built, and the remaining 26 meters will be repaired every day. How many days will it take to finish? | 一支修路队要修路445米，已经修了237米，剩下的每天修26米，还要几天修完？ | <gadget id="calculator">445 - 237</gadget>
<output>208</output>
<gadget id="calculator">208 / 26</gadget>
<output>8</output>
<result>8</result> | 8 | 8 | x=(445-237)/26 | calcformer-instruct-flan-xl_step-128k | The road needs to be constructed for 445 - 237 =<gadget id="calculator">445-237</gadget><output>208</output> 208 meters. So, it will take 208 / 26 =<gadget id="calculator">208/26</gadget><output>8</output> 8 days to finish.<result>8</result> | Let x = the number of days it will take to finish building the road. The road will be built in 445 - 237 =<gadget id="calculator">445-237</gadget><output>208</output> 208 days.<result>208</result> |
ape210k__00124298 | A cylindrical container with a bottom radius of 3 decimeters is filled with water at a depth of 9 cm. After putting an iron block, the water level rises by 1.5 cm. What is the volume of the iron block? | 一个圆柱形容器，底面半径是3分米，里面装有深9厘米的水，放入一个铁块后，水面升高了1.5厘米，这个铁块的体积是多少？ | <gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">30 ** 2</gadget>
<output>900</output>
<gadget id="calculator">3.14 * 900 * 1.5</gadget>
<output>4_239</output>
<result>4_239</result> | 4_239 | 4,239 | x=3.14*(3*10)**2*1.5 | calcformer-instruct-flan-xl_step-128k | 3 decimal places are 3*10 cm, so the radius of the cylindrical container is 3*10 cm =<gadget id="calculator">3*10</gadget><output>30</output> 30 cm. The volume of the cylindrical container is given by 3.14*30*30 =<gadget id="calculator">3.14*30*30</gadget><output>2_826</output> 2826 cm3. The volume of the iron block is 2826 cm3 * 1.5 =<gadget id="calculator">2826*1.5</gadget><output>4_239</output> 4239 cm3.<result>4_239</result> | 3 decimeters is 3*10 =<gadget id="calculator">3*10</gadget><output>30</output> 30 cm. The radius of the cylindrical container with a height of 3 cm is 30 cm, and therefore the volume of the iron block is the volume of the cylinder with a radius of 30 cm, which is 303 * 303 = 24,000 cubic cm. Since the volume of the water level rises by 1.5 cm, the iron block has a volume of 24,000*1.5 =<gadget id="calculator">27000*1.5</gadget><output>40_500</output> 40,500 cm3.<result>40_500</result> |
ape210k__00066652 | There are 12 residential buildings in a community, each building has 15 floors, and each floor has 8 households. How many households are there in each building? | 某小区有12栋居民楼，每栋楼有15层，每层有8户，每栋楼有多少户． | <gadget id="calculator">15 * 8</gadget>
<output>120</output>
<result>120</result> | 120 | 120 | x=15*8 | calcformer-instruct-flan-xl_step-128k | The number of floors in a building is 15 floors x 8 households =<gadget id="calculator">15*8</gadget><output>120</output> 120 households. So the total number of households in a building is 120 households/building =<gadget id="calculator">120</gadget><output>120</output> 120 households.<result>120</result> | If a building has 15 floors, and each floor has 8 households, the total number of households in a building is 15 floors * 8 households/floor =<gadget id="calculator">15*8</gadget><output>120</output> 120 households/building. Since there are 12 buildings in the community, and each building has 120 households, there are 120 households / 12 buildings =<gadget id="calculator">120/12</gadget><output>10</output> 10 households in each building.<result>10</result> |
ape210k__00755243 | A group of wild geese were flying in the sky, Xiao Ming counted two and two, and there was one left; Xiao Liang counted three and three, and one remained; Xiao Gang counted five and five, and there was one left. How many wild geese are there at least? | 一群大雁在天空中飞，小明两只两只地数，剩1只，小亮3只3只地数，也剩1只，小刚5只5只地数又是剩下1只，天空中最少飞来多少只大雁？ | <gadget id="calculator">2 * 3 * 5</gadget>
<output>30</output>
<gadget id="calculator">30 + 1</gadget>
<output>31</output>
<result>31</result> | 31 | 31 | x=(2*3*5)+1 | calcformer-instruct-flan-xl_step-128k | 2 * 3 * 5 = 30 + 1<result>31</result> | 2*3*5=<gadget id="calculator">2*3*5</gadget><output>30</output> 30 3*5*2=<gadget id="calculator">3*5*2</gadget><output>30</output> 30 5*2=<gadget id="calculator">5*2</gadget><output>10</output> 10 20 + 1=<gadget id="calculator">20 + 1</gadget><output>21</output> 21. Answer:31<result>21</result> |
ape210k__00604269 | A gift of 80 yuan is sold at a 30% discount, which is how much cheaper than the original price. | 一件礼品80元，打7折出售，比原价便宜了多少元． | <gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">1 - (7/10)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">80 * (3/10)</gadget>
<output>24</output>
<result>24</result> | 24 | 24 | x=80*(1-70%) | calcformer-instruct-flan-xl_step-128k | 70% of the original price is 70/100*80 =<gadget id="calculator">70/100*80</gadget><output>56</output> 56. So the gift is 80-56 =<gadget id="calculator">80-56</gadget><output>24</output> 24 yuan cheaper.<result>24</result> | 70% of 80 yuan is 70/100*80=<gadget id="calculator">70/100*80</gadget><output>56</output> 56 yuan. So, 80 yuan is 56-80=<gadget id="calculator">56-80</gadget><output>-24</output> -24 yuan.<result>-24</result> |
ape210k__00630114 | Xiaoying and Xiaohua are walking opposite each other from places A and B at a distance of 375 meters at the same time. Xiaoying walks 65 meters per minute, and Xiaohua walks 60 meters per minute. After 5 minutes, how many meters are they apart? | 小英和小华同时从距离375米的甲乙两地相背而行，小英每分钟走65米，小华每分钟走60米．经过5分钟，他们相距多少米？ | <gadget id="calculator">65 + 60</gadget>
<output>125</output>
<gadget id="calculator">125 * 5</gadget>
<output>625</output>
<gadget id="calculator">625 + 375</gadget>
<output>1_000</output>
<result>1_000</result> | 1_000 | 1,000 | x=(65+60)*5+375 | calcformer-instruct-flan-xl_step-128k | 65 + 60 =<gadget id="calculator">65+60</gadget><output>125</output> 125 meters per minute. So, they will be walking for 5 * 125 =<gadget id="calculator">5*125</gadget><output>625</output> 625 meters. After that, they will be 375 + 625 =<gadget id="calculator">375+625</gadget><output>1_000</output> 1000 meters apart.<result>1_000</result> | The total number of meters they walk each minute is 65 meters + 60 meters =<gadget id="calculator">65+60</gadget><output>125</output> 125 meters. After 5 minutes, the distance they will have walked is 125 meters/minute * 5 minutes =<gadget id="calculator">125*5</gadget><output>625</output> 625 meters. If the distance between them is 375 meters, after 625 meters, they are still 375 meters - 625 meters =<gadget id="calculator">375-625</gadget><output>-250</output> 250 meters apart.<result>-250</result> |
ape210k__00205485 | The sixth grade students participated in Ping An Insurance, and they paid a total of 22,500 yuan in insurance premiums to Ping An Insurance Company. If the insurance amount per person is 15,000 yuan, and the insurance premium rate is 0.1%, how many students are there in this sixth grade? | 六年级的学生参加了平安保险，他们向平安保险公司共交纳22500元保险费，如果每人保险金额都是15000元，保险费率是0.1%，求这个六年级共有学生多少人？ | <gadget id="calculator">0.1 / 100</gadget>
<output>0.001</output>
<gadget id="calculator">15_000 * 0.001</gadget>
<output>15</output>
<gadget id="calculator">22_500 / 15</gadget>
<output>1_500</output>
<result>1_500</result> | 1_500 | 1,500 | x=22500/(15000*0.1%) | calcformer-instruct-flan-xl_step-128k | 0.1% of 15000 yuan is (0.1/100)*15000 =<gadget id="calculator">(0.1/100)*15000</gadget><output>15</output> 15 yuan. So, the total number of students who participated in Ping An Insurance is 22500 / 15 =<gadget id="calculator">22500/15</gadget><output>1_500</output> 1500 students.<result>1_500</result> | The Insurance amount per student is 15000 yuan * 0.1% =<gadget id="calculator">15000*0.1</gadget><output>1_500</output> 1500 yuan. So there are 22,500 yuan / 1500 yuan =<gadget id="calculator">22,500/1500</gadget><output>ERROR: 'tuple' object has no attribute 'evalf'</output>. Then the total number of students is X = 22500 / 1500 / 0.08 =<gadget id="calculator">22500/150 / 0.08</gadget><output>1_875</output> 1875 students.<result>1_875</result> |
ape210k__00210483 | A and B repair a road, A alone completes it in 10 days, and B alone completes it in 15 days. If two teams work together, how many days will it take to complete? What is the column | 甲，乙修一条路，甲单独修10天完成，乙单独修15天完成．如果2队合修，需要几天完成？列式是多少 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/10) + (1/15)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / (1/6)</gadget>
<output>6</output>
<result>6</result> | 6 | 6 | x=1/((1/10)+(1/15)) | calcformer-instruct-flan-xl_step-128k | One day work of A = 1/10; One day work of B = 1/15; (A + B)'s one day work = 1/10+1/15 = 5/30 = 1/6. The time taken by the two teams to complete the road work is 6 / 1 =<gadget id="calculator">6 / 1</gadget><output>6</output> 6 days.<result>6</result> | One day work of A = 1 /10; One day work of B = 1 / 15; (A + B)'s one day work = 1 / 10 + 1 / 15 = 1 / 3 ; So, both together will finish the work in 3 days.<result>3</result> |
ape210k__00502293 | A pencil case is 9 cm long and 3 cm wide, what is the circumference of the pencil case in cm? | 一个文具盒长9厘米，宽3厘米，这个文具盒的周长多少厘米． | <gadget id="calculator">9 + 3</gadget>
<output>12</output>
<gadget id="calculator">12 * 2</gadget>
<output>24</output>
<result>24</result> | 24 | 24 | x=(9+3)*2 | calcformer-instruct-flan-xl_step-128k | 9 cm + 3 cm =<gadget id="calculator">9+3</gadget><output>12</output> 12 cm circumference of the pencil case is 12 cm * 2 =<gadget id="calculator">12*2</gadget><output>24</output> 24 cm.<result>24</result> | There are 9 + 3 =<gadget id="calculator">9+3</gadget><output>12</output> 12 cm along the circumference of the pencil case.<result>12</result> |
ape210k__00220313 | Someone puts a set of Go chess in a box, and then molds 3 chess pieces from the box each time. How many times can he touch at least to ensure that the chess pieces taken out of 2 times are the same. | 某人把一副围棋混装在一个盒子里，然后每次从盒子中模出3枚棋子，他至少摸多少次，才能保证其中有2次取出的棋子是相同的． | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<result>5</result> | 5 | 5 | x=4+1 | calcformer-instruct-flan-xl_step-128k | If the chess pieces are not the same, then the process of molding them can be repeated. Thus, he needs to touch the pieces 5 times to be sure that the pieces taken out of 2 times are the same.<result>5</result> | If he touches the chess piece twice in a single extraction, the next piece could be the one he molds from the third extraction. Thus, after touching 3 times, one should touch 4 times to be sure that the pieces taken out of 2 times are the same.<result>4</result> |
ape210k__00348647 | Divisor/6=8...remainder, what is the largest remainder | 被除数/6=8…余数，余数最大是多少 | <gadget id="calculator">6 - 1</gadget>
<output>5</output>
<result>5</result> | 5 | 5 | x=6-1 | calcformer-instruct-flan-xl_step-128k | remainder = 6 - 1=<gadget id="calculator">6 - 1</gadget><output>5</output><result>5</result> | remainder = 6 - 1=<gadget id="calculator">6 - 1</gadget><output>5</output> 5.5*6=<gadget id="calculator">5 *6</gadget><output>30</output> 30. 30 + 5=<gadget id="calculator">30 + 5</gadget><output>35</output> 35. It is the highest remainder. Then 5/6= 5/6 which is the least remainder. The remainder is 5/6.<result>5/6 = around 0.833333</result> |
ape210k__00425206 | If the length, width, and height of a cuboid are enlarged to three times their original size, then how many times its volume will be enlarged to its original size. | 如果把长方体的长、宽、高都扩大到原来的3倍，那么它的体积就扩大到原来的多少倍． | <gadget id="calculator">3 * 3 * 3</gadget>
<output>27</output>
<result>27</result> | 27 | 27 | x=3*3*3 | calcformer-instruct-flan-xl_step-128k | If the dimensions of the cuboid are enlarged to three times, then the volume will also increase to three times its original volume. The multiplier for increased volume is 3*3*3 =<gadget id="calculator">3*3*3</gadget><output>27</output> 27 times.<result>27</result> | If the length, width, and height of the original cuboid are all enlarged to three times, then their volume will also be increased three times. Therefore, the result is that the entire cuboid will be increased to three times its original size.<result>3</result> |
ape210k__00071398 | What is the side length of a square with a perimeter of 24 cm? | 周长是24厘米的正方形，它的边长是多少厘米． | <gadget id="calculator">24 / 4</gadget>
<output>6</output>
<result>6</result> | 6 | 6 | x=24/4 | calcformer-instruct-flan-xl_step-128k | 24 cm/4 =<gadget id="calculator">24/4</gadget><output>6</output> 6 cm.<result>6</result> | We first need to know the length of one side of the square, so we divide the perimeter by 4, getting 24/4=<gadget id="calculator">24/4</gadget><output>6</output> 6 cm. Then, we find the length of the other side, by dividing 6 cm by 4, which gives us 6/4=<gadget id="calculator">6/4</gadget><output>3/2 = around 1.5</output> 1.5 cm.<result>3/2 = around 1.5</result> |
ape210k__00706539 | The 3 little monkeys picked 405 peaches in total. How many peaches did each monkey pick on average? | 3只小猴共摘了405个桃子，平均每只猴子摘了多少个桃子？ | <gadget id="calculator">405 / 3</gadget>
<output>135</output>
<result>135</result> | 135 | 135 | x=405/3 | calcformer-instruct-flan-xl_step-128k | Each monkey picked 405/3=<gadget id="calculator">405/3</gadget><output>135</output> 135 peaches.<result>135</result> | The 3 little monkeys picked 405 / 3 =<gadget id="calculator">405/3</gadget><output>135</output> 135 peaches in total. Each monkey picked 135 / 3 =<gadget id="calculator">135/3</gadget><output>45</output> 45 peaches on average.<result>45</result> |
ape210k__01062899 | How many different ways are there to write 42 as the sum of two prime numbers? | 将42写成两个素数的和，一共有多少种不同的写法？ | <result>4</result> | 4 | 4 | x=4 | calcformer-instruct-flan-xl_step-128k | First, you have to consider only the possibilities for the two digits of the sum: 3 + 42=<gadget id="calculator">3 + 42</gadget><output>45</output> 45. The only possibility that satisfies this condition is 7 because 42 = 7 + 2 =<gadget id="calculator">7 + 2</gadget><output>9</output> 9. Thus, there are two possibilities to find the sum as 42. Second, you have to consider only the possibilities for the digits of 42. Thus 42 = 26 + 2 =<gadget id="calculator">26 + 2</gadget><output>28</output> 28, so the answer is only one. There are three possibilities for the digits of 42. Thus 42 = 29 + 3 =<gadget id="calculator">29 + 3</gadget><output>32</output> 32, so the answer is 3 possibilities. There are four possibilities for the digits of 42. Thus 42 = 47 + 7 =<gadget id="calculator">47 + 7</gadget><output>54</output> 54, so the answer is 3 possibilities. There are 5 possibilities for the digits of 42. Thus 42 = 47 + 11 =<gadget id="calculator">47 + 11</gadget><output>58</output> 58, so the answer is 4 possibilities. There are 3 possibilities for the digits of 42. Thus 42 = 47 + 11 =<gadget id="calculator">47 + 11</gadget><output>58</output> 58, so the answer is 4 possibilities.<result>4</result> | First of all, 42 can either be written as 2+31 or as 3+31 since there are only two options for the sum of two prime numbers. The other way would be to write it as 2+31 which is different from 2+31 which is 3+31. The only way to write a different sum of two prime numbers than 42 is to choose two different options for the sum of two prime numbers and then add one more to get the sum of two prime numbers. So, there are two different ways to write 42. Another way to write it as 31+31 is to choose 31+31=<gadget id="calculator">31+31</gadget><output>62</output> 62 which is not possible because 42 is not a multiple of 6. So, there are only two possibilities to write 62 as 31+31.<result>2</result> |
ape210k__00331935 | 777+777-777*777/777=how many. | 777+777-777*777/777=多少． | <gadget id="calculator">777 / 777</gadget>
<output>1</output>
<gadget id="calculator">777 * 1</gadget>
<output>777</output>
<gadget id="calculator">777 - 777</gadget>
<output>0</output>
<gadget id="calculator">777 + 0</gadget>
<output>777</output>
<result>777</result> | 777 | 777 | x=777+777-777*777/777 | calcformer-instruct-flan-xl_step-128k | 777/777 =<gadget id="calculator">777/777</gadget><output>1</output> 1 777 * 1=<gadget id="calculator">777 * 1</gadget><output>777</output> 777 777 - 777 =<gadget id="calculator">777-777</gadget><output>0</output> 0 777 + 0 =<gadget id="calculator">777 + 0</gadget><output>777</output> 777<result>777</result> | 777/777 =<gadget id="calculator">777/777</gadget><output>1</output> 1 - 777/777 = -1 777 + 777 =<gadget id="calculator">777 + 777</gadget><output>1_554</output> 1554 777 - 1554 =<gadget id="calculator">777-1554</gadget><output>-777</output> -777</output> -777</output> -777</result> |
ape210k__00070349 | A camera costs 735 yuan, which is seven times the price of a slide projector. How much does a slide projector cost? | 一架照相机售价735元，相当于一台幻灯机售价的7倍，一台幻灯机售价多少元？ | <gadget id="calculator">735 / 7</gadget>
<output>105</output>
<result>105</result> | 105 | 105 | x=735/7 | calcformer-instruct-flan-xl_step-128k | If the camera costs 735 yuan, then a slide projector costs 735/7=<gadget id="calculator">735/7</gadget><output>105</output> 105 yuan.<result>105</result> | The price of the camera is 735/7=<gadget id="calculator">735/7</gadget><output>105</output> 105 yuan. The price of a slide projector is 105/7=<gadget id="calculator">105/7</gadget><output>15</output> 15 yuan.<result>15</result> |
ape210k__00945065 | Every liter of milk contains (7/5) grams of calcium, and a bottle of milk contains (1/4) liters. How many grams of calcium does a bottle of milk contain? | 每升牛奶含钙(7/5)克，一瓶牛奶有(1/4)升，一瓶牛奶大约含钙多少克． | <gadget id="calculator">7 / 5</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(7/5) * (1/4)</gadget>
<output>7/20 = around 0.35</output>
<result>7/20 = around 0.35</result> | 7/20 | 0.35 | x=(7/5)*(1/4) | calcformer-instruct-flan-xl_step-128k | A bottle of milk contains (1/4) * 1 liter =<gadget id="calculator">1/4*1</gadget><output>1/4 = around 0.25</output> 0.25 liters of milk. Thus, 0.25 liters * (7/5) grams of calcium = 0.35*gms.<result>0.35</result> | There are 1/5 =<gadget id="calculator">1/5</gadget><output>1/5 = around 0.2</output> 0.2 liters in a bottle of milk. Therefore, there are 0.2 x (7)/5 =<gadget id="calculator">0.2*7/5</gadget><output>0.28</output> 0.28 grams of calcium in a bottle of milk.<result>0.28</result> |
ape210k__01047205 | A rice cooker is 248 yuan, and the money to buy one rice cooker can just buy two identical electric kettles. How much is an electric kettle. | 一个电饭煲248元，买一个电饭煲的钱正好可以买两个同样的电水壶．一个电水壶多少元． | <gadget id="calculator">248 / 2</gadget>
<output>124</output>
<result>124</result> | 124 | 124 | x=248/2 | calcformer-instruct-flan-xl_step-128k | Let X be the cost of an electric kettle. The rice cooker costs 248 yuan, so X = 248/2 =<gadget id="calculator">248/2</gadget><output>124</output> 124 yuan.<result>124</result> | We know that the price of one rice cooker is $248, so to buy two electric kettles we would have to pay 248/2 = $<gadget id="calculator">248/2</gadget><output>124</output> 124. Since the price of an electric kettle is directly proportional to the number of electric kettles, we can write: 124/2 =<gadget id="calculator">124/2</gadget><output>62</output> 62.<result>62</result> |
ape210k__00007207 | Mom bought a large bottle of Coke, 2L. Mingming drinks Coke in a paper cup with a capacity of 250ml, and drinks 2 cups a day, so how many days is this bottle of Coke enough for Mingming? | 妈妈买来一大瓶可乐，有2L．明明用容量250毫升的纸杯去喝可乐，每天喝2杯，那么这瓶可乐够明明喝几天？ | <gadget id="calculator">2 * 1_000</gadget>
<output>2_000</output>
<gadget id="calculator">250 * 2</gadget>
<output>500</output>
<gadget id="calculator">2_000 / 500</gadget>
<output>4</output>
<result>4</result> | 4 | 4 | x=(2*1000)/(250*2) | calcformer-instruct-flan-xl_step-128k | 2L is equal to 1000 ml so 2L = 2 * 1000 =<gadget id="calculator">2*1000</gadget><output>2_000</output> 2000 ml. Mingming drinks 2 cups of Coke a day so that's 2*250 =<gadget id="calculator">2*250</gadget><output>500</output> 500ml. So, a bottle of 2000 ml is enough for 500ml, 2000/500 =<gadget id="calculator">2000/500</gadget><output>4</output> 4 days.<result>4</result> | 2L is equal to 1000ml, so 2L is equivalent to 1000*2 =<gadget id="calculator">2*1000</gadget><output>2_000</output> 2000ml. Since he drinks 2 cups of Coke a day, then the bottle is enough for 2000/250 =<gadget id="calculator">2000/250</gadget><output>8</output> 8 days.<result>8</result> |
ape210k__00624840 | A kind of medicine, the mass ratio of medicine powder and water is 1:16, now to prepare 286 grams of medicine, how many grams of medicine powder is needed? | 一种药水，药粉和水的质量比是1：16，现在要配制286克药水，需要药粉多少克？ | <gadget id="calculator">1 + 16</gadget>
<output>17</output>
<gadget id="calculator">1 / 17</gadget>
<output>1/17 = around 0.058824</output>
<gadget id="calculator">286 * (1/17)</gadget>
<output>286/17 = around 16.823529</output>
<result>286/17 = around 16.823529</result> | 286/17 | 16.823529 | x=286*(1/(1+16)) | calcformer-instruct-flan-xl_step-128k | 1 + 16 =<gadget id="calculator">1+16</gadget><output>17</output> 17. The fraction of medicine powder is 1 / 17 which means that for 286 grams of medicine powder, there are 286 * (1/17) =<gadget id="calculator">286*(1/17)</gadget><output>286/17 = around 16.823529</output> 16.82329 grams of medicine powder.<result>286/17 = around 16.823529</result> | Let 1x = the mass of medicine powder. Then the other part of this medicine, which is a water, is 16x = 16x + 1x. So 1x + 16x = 286 17x = 286 x =<gadget id="calculator">286</gadget><output>286</output> 286. So, the part of medicine powder is 286*1 =<gadget id="calculator">286*1</gadget><output>286</output> 286 grams.<result>286</result> |
ape210k__00874377 | piece of rectangular colored paper with a length of 24 cm and a width of 16 cm can be cut into how many circular pieces of colored paper with a diameter of 4 cm. | 一张长24厘米、宽16厘米的长方形彩纸，能剪成多少个直径是4厘米的圆形彩纸片． | <gadget id="calculator">16 / 4</gadget>
<output>4</output>
<gadget id="calculator">24 / 4</gadget>
<output>6</output>
<gadget id="calculator">4 * 6</gadget>
<output>24</output>
<result>24</result> | 24 | 24 | x=(16/4)*24/(16/4) | calcformer-instruct-flan-xl_step-128k | 24 cm / 4 cm/piece =<gadget id="calculator">24/4</gadget><output>6</output> 6 pieces 16 cm / 4 cm/piece =<gadget id="calculator">16/4</gadget><output>4</output> 4 pieces Total pieces of colored paper that can be cut from the rectangular colored paper with a diameter of 4 cm is 6 * 4 =<gadget id="calculator">6*4</gadget><output>24</output> 24.<result>24</result> | 24 cm / 4 cm/piece =<gadget id="calculator">24/4</gadget><output>6</output> 6 pieces 16 cm / 4 cm/piece =<gadget id="calculator">16/4</gadget><output>4</output> 4 pieces.<result>4</result> |
ape210k__01135101 | Mom bought 6 plexiglass buckles for 1.5 yuan. If you buy the same button for 4.5 yuan, how many can you buy? | 妈妈用1.5元买了6个有机玻璃扣．如果用4.5元买同样的纽扣，可以买多少个？ | <gadget id="calculator">1.5 / 6</gadget>
<output>0.25</output>
<gadget id="calculator">4.5 / 0.25</gadget>
<output>18</output>
<result>18</result> | 18 | 18 | x=4.5/(1.5/6) | calcformer-instruct-flan-xl_step-128k | Mom bought 1.5/6 =<gadget id="calculator">1.5/6</gadget><output>0.25</output> 0.25 buttons. She can buy 4.5/0.25 =<gadget id="calculator">4.5/0.25</gadget><output>18</output> 18 buttons.<result>18</result> | Mom bought 6 x 1.5 =<gadget id="calculator">6*1.5</gadget><output>9</output> 9 buttons. So, she can buy 9 / 4.5 =<gadget id="calculator">9/4.5</gadget><output>2</output> 2 buttons.<result>2</result> |
ape210k__01207691 | The quotient and remainder of a number divided by 7 are the same, what is the largest number. | 一个数除以7的商和余数相同，这个数最大是多少． | <gadget id="calculator">6 * 7</gadget>
<output>42</output>
<gadget id="calculator">42 + 6</gadget>
<output>48</output>
<result>48</result> | 48 | 48 | x=6*7+6 | calcformer-instruct-flan-xl_step-128k | Since the remainder and quotient of a number divided by 7 are equal, you can find the last number by taking the middle number, and multiplying it by the quotient to get the remainder, then 6*7=<gadget id="calculator">6*7</gadget><output>42</output> 42. Since the quotient and remainder of a number divided by 7 are the same, you can also find the last number by taking the first number and adding the remainder of 42, so 42+6=<gadget id="calculator">42+6</gadget><output>48</output> 48.<result>48</result> | Since the remainder is the same as the quotient, the largest number is 7 * 4 + 6 =<gadget id="calculator">7*4+6</gadget><output>34</output> 34.<result>34</result> |
ape210k__00288495 | The price of a fur coat is 1620 yuan after a reduction of 380 yuan per piece. By what percentage is the price of this fur coat reduced? | 一种皮大衣，每件降低380元后售价为1620元，这种皮大衣的售价降低了百分之几？ | <gadget id="calculator">380 + 1_620</gadget>
<output>2_000</output>
<gadget id="calculator">380 / 2_000</gadget>
<output>19/100 = around 0.19</output>
<result>19/100 = around 0.19</result> | 19/100 | 0.19 | x=380/(380+1620) | calcformer-instruct-flan-xl_step-128k | The price after the reduction is 1620 yuan + 380 yuan =<gadget id="calculator">1620+380</gadget><output>2_000</output> 2000 yuan. The percentage of the price reduction is 380 yuan / 2000 yuan =<gadget id="calculator">380/2000</gadget><output>19/100 = around 0.19</output> 0.19.<result>19/100 = around 0.19</result> | The price after the reduction is 1620 yuan + 380 yuan =<gadget id="calculator">1620+380</gadget><output>2_000</output> 2000 yuan. So, there is 2000 yuan/380 yuan =<gadget id="calculator">2000/380</gadget><output>100/19 = around 5.263158</output> 59% reduction in the price of this fur coat.<result>50</result> |
ape210k__00291589 | If a conical container with a height of 30 cm is filled with water and poured into a cylindrical container with the same height as the bottom, what is the height of the water surface in cm? | 用一个高是30厘米的圆锥形容器盛满水，倒入和它等底等高的圆柱形容器中，水面的高度是多少厘米． | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">30 * (1/3)</gadget>
<output>10</output>
<result>10</result> | 10 | 10 | x=30*(1/3) | calcformer-instruct-flan-xl_step-128k | The volume of the container is 30 * 3 =<gadget id="calculator">30*3</gadget><output>90</output> 90 cm3. The height of the water in the container is therefore 30 / 3 =<gadget id="calculator">30/3</gadget><output>10</output> 10 cm3.<result>10</result> | The volume of the container is 30 * 3=<gadget id="calculator">30*3</gadget><output>90</output> 90 cm3. The volume of a cylinder is 30 / 3 =<gadget id="calculator">30/3</gadget><output>10</output> 10 cm3. The height of the water in the container is 30 / 10 =<gadget id="calculator">30/10</gadget><output>3</output> 3 cm.<result>3</result> |
ape210k__00428096 | It takes half an hour for a car to go from point A to point B. According to this calculation, how much can the whole journey be done in 20 minutes? | 一辆汽车从甲地到乙地用了半小时，照这样计算，20分钟可行全程的多少 | <gadget id="calculator">20 / 30</gadget>
<output>2/3 = around 0.666667</output>
<result>2/3 = around 0.666667</result> | 2/3 | 0.666667 | x=20/30 | calcformer-instruct-flan-xl_step-128k | The car takes 30 minutes to drive from A to B so the journey can be done in 30*1 =<gadget id="calculator">30*1</gadget><output>30</output> 30 minutes. If it takes 20 minutes to drive to point B, 20/30 =<gadget id="calculator">20/30</gadget><output>2/3 = around 0.666667</output> 0.666667 of the whole journey can be done in 20 minutes.<result>2/3 = around 0.666667</result> | If it takes 30 minutes to drive from point A to point B, 20 minutes would represent 20/30 =<gadget id="calculator">20/30</gadget><output>2/3 = around 0.666667</output> 0.666667 of the whole journey.<result>0.266667</result> |
ape210k__00090285 | An engineering team has been repairing a 7,500-meter-long road for 8 days, with an average of 240 meters per day. The remaining requirements are completed within 20 days. How many meters per day are the average repairs required? | 某工程队修一条长7500米的公路，已经工作了8天，平均每天修240米，剩下的要求在20天内完成，平均每天要修多少米？ | <gadget id="calculator">240 * 8</gadget>
<output>1_920</output>
<gadget id="calculator">7_500 - 1_920</gadget>
<output>5_580</output>
<gadget id="calculator">5_580 / 20</gadget>
<output>279</output>
<result>279</result> | 279 | 279 | x=(7500-240*8)/20 | calcformer-instruct-flan-xl_step-128k | The total amount of work that has been completed is 8 x 240 =<gadget id="calculator">8*240</gadget><output>1_920</output> 1920 meters. The remaining amount of work to be completed is 7500 - 1920 =<gadget id="calculator">7500-1920</gadget><output>5_580</output> 5580 meters. The remaining amount of work that is to be completed per day is 5580/20 =<gadget id="calculator">5580/20</gadget><output>279</output> 2979 meters.<result>279</result> | The total amount of work that has to be completed is 7,500 - 240 =<gadget id="calculator">7500-240</gadget><output>7_260</output> 7260 meters. The remaining period of work is 20 - 8 =<gadget id="calculator">20-8</gadget><output>12</output> 12 days. The average number of meters per day to complete the remaining work is 7260 / 12 =<gadget id="calculator">7260/12</gadget><output>605</output> 605 meters.<result>605</result> |
ape210k__00167743 | There are 50 students electing the monitor, and the person with the most votes is elected. During the counting of the votes, it was found that Liu Yan had obtained 18 votes, Zhang Jun had obtained 16 votes, and Li Ming had obtained 9 votes. As long as Liu Yan gets at least as many votes as possible, she will definitely become the squad leader. | 有50名学生选班长，得票最多的人当选．中途计票时发现刘燕已得18票，张军已得16票，李明已得9票．刘燕至少再得多少票就一定能成为班长． | <result>3</result> | 3 | 3 | x=3 | calcformer-instruct-flan-xl_step-128k | If Liu Yan receives at least 3 votes, she will become the squad leader. The total number of votes counting for the election is 50. Since Liu Yan received 18 votes and Zhang Jun received 16 votes, they must split the remaining 16 votes between themselves. This leaves 50 - 16 =<gadget id="calculator">50-16</gadget><output>34</output> 34 votes for Zhang Jun. If Zhang Jun receives 3 votes, Liu Yan will become the squad leader. The remaining votes must be split between Liu Yan and Li Ming, which each receive 3 votes. In this way, Liu Yan will receive at least 3 votes and Li Ming will receive 2 votes.<result>3</result> | Currently, Liu Yan has 3 votes less than the maximum possible vote, which is 3 votes. To become the leader, Liu Yan needs to gain at least 3 votes, so she needs to gain 3 + 1 =<gadget id="calculator">3+1</gadget><output>4</output> 4 votes as well. In this way, she can become the leader with the highest possible votes.<result>4</result> |
ape210k__00154905 | Find the difference between 9 (1/18) and 3 (1/18), what is the column formula | 求9个(1/18)与3个(1/18)的差，列式是多少 | <gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">9 * (1/18)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/18) * 3</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/2) - (1/6)</gadget>
<output>1/3 = around 0.333333</output>
<result>1/3 = around 0.333333</result> | 1/3 | 0.333333 | x=9*(1/18)-(1/18)*3 | calcformer-instruct-flan-xl_step-128k | <gadget id="calculator">1 / 18</gadget><output>1/18 = around 0.055556</output><gadget id="calculator">9 * (1/18)</gadget><output>1/2 = around 0.5</output><gadget id="calculator">3 * (1/18)</gadget><output>1/6 = around 0.166667</output><gadget id="calculator">(1/2) - (1/6)</gadget><output>1/3 = around 0.333333</output><result>1/3 = around 0.333333</result> | 18/9 =<gadget id="calculator">18/9</gadget><output>2</output> 2 3 - 2</gadget><output>1</output><result>1</result> |
ape210k__00335126 | Pencils cost a each, and pens cost $8. What is the total cost of buying b pencils and 7 pens? | 铅笔每枝a元，钢笔每枝8元，买b枝铅笔和7枝钢笔共要多少元． | <gadget id="calculator">8 * 7</gadget>
<output>56</output>
<result>56</result> | 56 | 56 | x=8*7 | calcformer-instruct-flan-xl_step-128k | The cost of 7 pens is 7 * $8 = $<gadget id="calculator">7*8</gadget><output>56</output> 56. The cost of buying b pencils is b * $<gadget id="calculator">7*b</gadget><output>ERROR: Cannot convert expression to float</output> 56. Therefore the total cost of buying b pencils and 7 pens is $56 + $ERROR= $<gadget id="calculator">56+ERROR</gadget><output>ERROR: Cannot convert expression to float</output> 56.<result>56</result> | The total cost of buying b pencils is b*a. The total cost of buying 7 pens is 7*8=<gadget id="calculator">7*8</gadget><output>56</output> 56. So the total cost of buying b pencils and 7 pens is 56+b=68.<result>68</result> |
ape210k__00803757 | Xiaohong's father is 0.52 meters taller than Xiaohong, and her father's height is 1.86 meters. How many meters is Xiaohong's height? | 小红的爸爸比小红高0.52米，爸爸的身高是1.86米，小红的身高是多少米？ | <gadget id="calculator">1.86 - 0.52</gadget>
<output>1.34</output>
<result>1.34</result> | 1.34 | 1.34 | x=1.86-0.52 | calcformer-instruct-flan-xl_step-128k | The height of Xiaohong is 1.86 - 0.52 =<gadget id="calculator">1.86-0.52</gadget><output>1.34</output> 1.34 meters.<result>1.34</result> | If her father's height is 1.86 meters, then Xiaohong's height is 1.86 - 0.52 =<gadget id="calculator">1.86-4.52</gadget><output>-2.66</output> 2.66 meters.<result>-2.66</result> |
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