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spider-syn

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SpiderSynQuestion
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Show the name, location, and number of platforms for all stations.
SELECT name , LOCATION , number_of_platforms FROM station
Show the name, city, and number of platforms for all terminals.
train_station
What are all locations of train stations?
SELECT DISTINCT LOCATION FROM station
What are all cities of train terminals?
train_station
Show the names and total passengers for all train stations not in London.
SELECT name , total_passengers FROM station WHERE LOCATION != 'London'
Show the names and total passengers for all train terminals not in London.
train_station
Show the names and main services for train stations that have the top three total number of passengers.
SELECT name , main_services FROM station ORDER BY total_passengers DESC LIMIT 3
Show the names and main services for train terminals that have the top three total number of passengers.
train_station
What is the average and maximum number of total passengers for train stations in London or Glasgow?
SELECT avg(total_passengers) , max(total_passengers) FROM station WHERE LOCATION = 'London' OR LOCATION = 'Glasgow'
What is the average and maximum number of total passengers for train terminals in London or Glasgow?
train_station
Show all locations and the total number of platforms and passengers for all train stations in each location.
SELECT LOCATION , sum(number_of_platforms) , sum(total_passengers) FROM station GROUP BY LOCATION
Show all cities and the total number of platforms and passengers for all train terminals in each city.
train_station
Show all locations that have train stations with at least 15 platforms and train stations with more than 25 total passengers.
SELECT DISTINCT LOCATION FROM station WHERE number_of_platforms >= 15 AND total_passengers > 25
Show all cities that have train terminals with at least 15 platforms and train terminals with more than 25 total passengers.
train_station
Show all locations which don't have a train station with at least 15 platforms.
SELECT LOCATION FROM station EXCEPT SELECT LOCATION FROM station WHERE number_of_platforms >= 15
Show all cities which don't have a train terminal with at least 15 platforms.
train_station
Show the location with most number of train stations.
SELECT LOCATION FROM station GROUP BY LOCATION ORDER BY count(*) DESC LIMIT 1
Show the city with most number of train terminals.
train_station
Show the name, time, and service for all trains.
SELECT name , TIME , service FROM train
Show the name, time, and service for all trains.
train_station
Show the number of trains
SELECT count(*) FROM train
Show the number of trains
train_station
Show the name and service for all trains in order by time.
SELECT name , service FROM train ORDER BY TIME
Show the name and service for all trains in order by time.
train_station
Show the station name and number of trains in each station.
SELECT T2.name , count(*) FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id GROUP BY T1.station_id
Show the terminal name and number of trains in each terminal.
train_station
show the train name and station name for each train.
SELECT T2.name , T3.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id
show the train name and terminal name for each train.
train_station
Show all train names and times in stations in London in descending order by train time.
SELECT T3.name , T3.time FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id WHERE T2.location = 'London' ORDER BY T3.time DESC
Show all train names and times in terminals in London in descending order by train time.
train_station
Show the station name with greatest number of trains.
SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id GROUP BY T1.station_id ORDER BY count(*) DESC LIMIT 1
Show the terminal name with greatest number of trains.
train_station
Show the station name with at least two trains.
SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id GROUP BY T1.station_id HAVING count(*) >= 2
Show the terminal name with at least two trains.
train_station
Show all locations with only 1 station.
SELECT LOCATION FROM station GROUP BY LOCATION HAVING count(*) = 1
Show all cities with only 1 station.
train_station
Show station names without any trains.
SELECT name FROM station WHERE station_id NOT IN (SELECT station_id FROM train_station)
Show terminal names without any trains.
train_station
What are the names of the stations which serve both "Ananthapuri Express" and "Guruvayur Express" trains?
SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id WHERE T3.Name = "Ananthapuri Express" INTERSECT SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id WHERE T3.Name = "Guruvayur Express"
What are the names of the terminals which serve both "Ananthapuri Express" and "Guruvayur Express" trains?
train_station
Find the names of the trains that do not pass any station located in London.
SELECT T2.name FROM train_station AS T1 JOIN train AS T2 ON T1.train_id = T2.train_id WHERE T1.station_id NOT IN (SELECT T4.station_id FROM train_station AS T3 JOIN station AS T4 ON T3.station_id = T4.station_id WHERE t4.location = "London")
Find the names of the trains that do not pass any terminal located in London.
train_station
List the names and locations of all stations ordered by their yearly entry exit and interchange amounts.
SELECT name , LOCATION FROM station ORDER BY Annual_entry_exit , Annual_interchanges
List the names and cities of all stations ordered by their yearly entry exit and interchange amounts.
train_station
List all vehicle id
SELECT vehicle_id FROM Vehicles;
List all vehicle id
driving_school
What are the ids of all vehicles?
SELECT vehicle_id FROM Vehicles;
What are the ids of all vehicles?
driving_school
How many vehicle in total?
SELECT count(*) FROM Vehicles;
How many vehicle in total?
driving_school
How many vehicles exist?
SELECT count(*) FROM Vehicles;
How many vehicles exist?
driving_school
Show the detail of vehicle with id 1.
SELECT vehicle_details FROM Vehicles WHERE vehicle_id = 1;
Show the information of vehicle with id 1.
driving_school
What are the details of the car with id 1?
SELECT vehicle_details FROM Vehicles WHERE vehicle_id = 1;
What are the information of the car with id 1?
driving_school
List the first name middle name and last name of all staff.
SELECT first_name , middle_name , last_name FROM Staff;
List the forename middle name and family name of all staff.
driving_school
What are the first, middle, and last names of all staff?
SELECT first_name , middle_name , last_name FROM Staff;
What are the forename, middle name, and surname of all staff?
driving_school
What is the birthday of the staff member with first name as Janessa and last name as Sawayn?
SELECT date_of_birth FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
What is the birthday of the staff member with first name as Janessa and last name as Sawayn?
driving_school
What is the date of birth for the staff member named Janessa Sawayn?
SELECT date_of_birth FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
What is the birthday for the staff member named Janessa Sawayn?
driving_school
When did the staff member with first name as Janessa and last name as Sawayn join the company?
SELECT date_joined_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
When did the employee member with first name as Janessa and last name as Sawayn join the company?
driving_school
When did the staff member named Janessa Sawayn join the company?
SELECT date_joined_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
When did the employee member named Janessa Sawayn join the company?
driving_school
When did the staff member with first name as Janessa and last name as Sawayn leave the company?
SELECT date_left_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
When did the employee member with first name as Janessa and last name as Sawayn leave the company?
driving_school
When did the staff member Janessa Sawayn leave the company?
SELECT date_left_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
When did the employee member Janessa Sawayn leave the company?
driving_school
How many staff have the first name Ludie?
SELECT count(*) FROM Staff WHERE first_name = "Ludie";
How many employee have the forename Ludie?
driving_school
How many employees have a first name of Ludie?
SELECT count(*) FROM Staff WHERE first_name = "Ludie";
How many employees have a first name of Ludie?
driving_school
What is the nickname of staff with first name as Janessa and last name as Sawayn?
SELECT nickname FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
What is the monicker of employee with first name as Janessa and last name as Sawayn?
driving_school
What is the nickname of the employee named Janessa Sawayn?
SELECT nickname FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
What is the monicker of the employee named Janessa Sawayn?
driving_school
How many staff in total?
SELECT count(*) FROM Staff;
How many employee in total?
driving_school
How many employees are there?
SELECT count(*) FROM Staff;
How many employees are there?
driving_school
Which city does staff with first name as Janessa and last name as Sawayn live?
SELECT T1.city FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
Which city does employee with first name as Janessa and last name as Sawayn live?
driving_school
In what city does Janessa Sawayn live?
SELECT T1.city FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
In what city does Janessa Sawayn live?
driving_school
Which country and state does staff with first name as Janessa and last name as Sawayn lived?
SELECT T1.country , T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
Which nation and state does staff with first name as Janessa and last name as Sawayn lived?
driving_school
In which country and state does Janessa Sawayn live?
SELECT T1.country , T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
In which nation and state does Janessa Sawayn live?
driving_school
How long is the total lesson time took by customer with first name as Rylan and last name as Goodwin?
SELECT sum(T1.lesson_time) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin";
How long is the total class time took by customer with first name as Rylan and last name as Goodwin?
driving_school
How long is the total lesson time took by the customer named Rylan Goodwin?
SELECT sum(T1.lesson_time) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin";
How long is the total class time took by the customer named Rylan Goodwin?
driving_school
What is the zip code of staff with first name as Janessa and last name as Sawayn lived?
SELECT T1.zip_postcode FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
What is the postal code of employee with first name as Janessa and last name as Sawayn lived?
driving_school
What is the zip code of the hosue of the employee named Janessa Sawayn?
SELECT T1.zip_postcode FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
What is the postal code of the hosue of the employee named Janessa Sawayn?
driving_school
How many staff live in state Georgia?
SELECT count(*) FROM Addresses WHERE state_province_county = "Georgia";
How many employee live in state Georgia?
driving_school
How many employees live in Georgia?
SELECT count(*) FROM Addresses WHERE state_province_county = "Georgia";
How many employees live in Georgia?
driving_school
Find out the first name and last name of staff lived in city Damianfort.
SELECT T2.first_name , T2.last_name FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T1.city = "Damianfort";
Find out the full name of staff lived in city Damianfort.
driving_school
What is the first and last name of all employees who live in the city Damianfort?
SELECT T2.first_name , T2.last_name FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T1.city = "Damianfort";
What is the forename and surname of all employees who live in the city Damianfort?
driving_school
Which city lives most of staffs? List the city name and number of staffs.
SELECT T1.city , count(*) FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.city ORDER BY count(*) DESC LIMIT 1;
Which city lives most of employees? List the city name and number of employees.
driving_school
In which city do the most employees live and how many of them live there?
SELECT T1.city , count(*) FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.city ORDER BY count(*) DESC LIMIT 1;
In which city do the most employees live and how many of them live there?
driving_school
List the states which have between 2 to 4 staffs living there.
SELECT T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.state_province_county HAVING count(*) BETWEEN 2 AND 4;
List the states which have between 2 to 4 employees living there.
driving_school
What are the names of the states that have 2 to 4 employees living there?
SELECT T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.state_province_county HAVING count(*) BETWEEN 2 AND 4;
What are the names of the states that have 2 to 4 employees living there?
driving_school
List the first name and last name of all customers.
SELECT first_name , last_name FROM Customers;
List the forename and family name of all customers.
driving_school
What are the first and last names for all customers?
SELECT first_name , last_name FROM Customers;
What are the forename and family names for all customers?
driving_school
List email address and birthday of customer whose first name as Carole.
SELECT email_address , date_of_birth FROM Customers WHERE first_name = "Carole"
List email address and birthday of customer whose first name as Carole.
driving_school
What are the email addresses and date of births for all customers who have a first name of Carole?
SELECT email_address , date_of_birth FROM Customers WHERE first_name = "Carole"
What are the email addresses and birthdays for all customers who have a first name of Carole?
driving_school
List phone number and email address of customer with more than 2000 outstanding balance.
SELECT phone_number , email_address FROM Customers WHERE amount_outstanding > 2000;
List telephone number and email address of client with more than 2000 outstanding balance.
driving_school
What are the phone numbers and email addresses of all customers who have an outstanding balance of more than 2000?
SELECT phone_number , email_address FROM Customers WHERE amount_outstanding > 2000;
What are the telephone numbers and email addresses of all clients who have an outstanding balance of more than 2000?
driving_school
What is the status code, mobile phone number and email address of customer with last name as Kohler or first name as Marina?
SELECT customer_status_code , cell_mobile_phone_number , email_address FROM Customers WHERE first_name = "Marina" OR last_name = "Kohler"
What is the status code, cellphone number and email address of client with last name as Kohler or first name as Marina?
driving_school
What is the status code, phone number, and email address of the customer whose last name is Kohler or whose first name is Marina?
SELECT customer_status_code , cell_mobile_phone_number , email_address FROM Customers WHERE first_name = "Marina" OR last_name = "Kohler"
What is the status code, telephone number, and email address of the client whose last name is Kohler or whose first name is Marina?
driving_school
When are the birthdays of customer who are classified as 'Good Customer' status?
SELECT date_of_birth FROM Customers WHERE customer_status_code = 'Good Customer'
When are the birthdays of customer who are classified as 'Good Customer' status?
driving_school
What is the date of birth of every customer whose status code is 'Good Customer'?
SELECT date_of_birth FROM Customers WHERE customer_status_code = 'Good Customer'
What is the birthday of every customer whose status code is 'Good Customer'?
driving_school
When did customer with first name as Carole and last name as Bernhard became a customer?
SELECT date_became_customer FROM Customers WHERE first_name = "Carole" AND last_name = "Bernhard";
When did client with first name as Carole and last name as Bernhard became a client?
driving_school
When did Carole Bernhard first become a customer?
SELECT date_became_customer FROM Customers WHERE first_name = "Carole" AND last_name = "Bernhard";
When did Carole Bernhard first become a client?
driving_school
How many customers in total?
SELECT count(*) FROM Customers;
How many clients in total?
driving_school
How many customers are there?
SELECT count(*) FROM Customers;
How many clients are there?
driving_school
List all customer status codes and the number of customers having each status code.
SELECT customer_status_code , count(*) FROM Customers GROUP BY customer_status_code;
List all client status codes and the number of clients having each status code.
driving_school
For each customer status code, how many customers are classified that way?
SELECT customer_status_code , count(*) FROM Customers GROUP BY customer_status_code;
For each client status code, how many clients are classified that way?
driving_school
Which customer status code has least number of customers?
SELECT customer_status_code FROM Customers GROUP BY customer_status_code ORDER BY count(*) ASC LIMIT 1;
Which client status code has least number of clients?
driving_school
What is the status code with the least number of customers?
SELECT customer_status_code FROM Customers GROUP BY customer_status_code ORDER BY count(*) ASC LIMIT 1;
What is the status code with the least number of clients?
driving_school
How many lessons taken by customer with first name as Rylan and last name as Goodwin were completed?
SELECT count(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin" AND T1.lesson_status_code = "Completed";
How many classes taken by customer with first name as Rylan and last name as Goodwin were completed?
driving_school
How many lessons did the customer Ryan Goodwin complete?
SELECT count(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin" AND T1.lesson_status_code = "Completed";
How many classes did the customer Ryan Goodwin complete?
driving_school
What is maximum, minimum and average amount of outstanding of customer?
SELECT max(amount_outstanding) , min(amount_outstanding) , avg(amount_outstanding) FROM Customers;
What is maximum, minimum and average amount of outstanding of client?
driving_school
What is the maximum, minimum, and average amount of money outsanding for all customers?
SELECT max(amount_outstanding) , min(amount_outstanding) , avg(amount_outstanding) FROM Customers;
What is the maximum, minimum, and average amount of money outsanding for all clients?
driving_school
List the first name and last name of customers have the amount of outstanding between 1000 and 3000.
SELECT first_name , last_name FROM Customers WHERE amount_outstanding BETWEEN 1000 AND 3000;
List the forename and surname of customers have the amount of outstanding between 1000 and 3000.
driving_school
What are the first and last names of all customers with between 1000 and 3000 dollars outstanding?
SELECT first_name , last_name FROM Customers WHERE amount_outstanding BETWEEN 1000 AND 3000;
What are the full names of all customers with between 1000 and 3000 dollars outstanding?
driving_school
List first name and last name of customers lived in city Lockmanfurt.
SELECT T1.first_name , T1.last_name FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T2.city = "Lockmanfurt";
List forename and family name of customers lived in city Lockmanfurt.
driving_school
What are the first and last names of all customers who lived in Lockmanfurt?
SELECT T1.first_name , T1.last_name FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T2.city = "Lockmanfurt";
What are the forename and family names of all customers who lived in Lockmanfurt?
driving_school
Which country does customer with first name as Carole and last name as Bernhard lived in?
SELECT T2.country FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
Which nation does client with first name as Carole and last name as Bernhard lived in?
driving_school
What is the country in which the customer Carole Bernhard lived?
SELECT T2.country FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
What is the nation in which the client Carole Bernhard lived?
driving_school
What is zip code of customer with first name as Carole and last name as Bernhard?
SELECT T2.zip_postcode FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
What is postal code of client with first name as Carole and last name as Bernhard?
driving_school
What is the zip code of the customer Carole Bernhard?
SELECT T2.zip_postcode FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
What is the postal code of the client Carole Bernhard?
driving_school
Which city does has most number of customers?
SELECT T2.city FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id GROUP BY T2.city ORDER BY count(*) DESC LIMIT 1;
Which city does has most number of clients?
driving_school
What is the city with the most customers?
SELECT T2.city FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id GROUP BY T2.city ORDER BY count(*) DESC LIMIT 1;
What is the city with the most clients?
driving_school
How much in total does customer with first name as Carole and last name as Bernhard paid?
SELECT sum(T1.amount_payment) FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Carole" AND T2.last_name = "Bernhard"
How much in total does client with first name as Carole and last name as Bernhard paid?
driving_school
What is the total amount of moeny paid by the customer Carole Bernhard?
SELECT sum(T1.amount_payment) FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Carole" AND T2.last_name = "Bernhard"
What is the total quantity of moeny paid by the client Carole Bernhard?
driving_school
List the number of customers that did not have any payment history.
SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_Payments );
List the number of clients that did not have any payment history.
driving_school
How many customers have no payment histories?
SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_Payments );
How many clients have no payment histories?
driving_school
List first name and last name of customers that have more than 2 payments.
SELECT T2.first_name , T2.last_name FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) > 2;
List forename and family name of customers that have more than 2 payments.
driving_school
What are the first and last names of all customers with more than 2 payments?
SELECT T2.first_name , T2.last_name FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) > 2;
What are the full names of all customers with more than 2 payments?
driving_school
List all payment methods and number of payments using each payment methods.
SELECT payment_method_code , count(*) FROM Customer_Payments GROUP BY payment_method_code;
List all payment types and number of payments using each payment types.
driving_school
For each payment method, how many payments were made?
SELECT payment_method_code , count(*) FROM Customer_Payments GROUP BY payment_method_code;
For each payment type, how many payments were made?
driving_school
How many lessons were in cancelled state?
SELECT count(*) FROM Lessons WHERE lesson_status_code = "Cancelled";
How many classes were in cancelled state?
driving_school
How many lessons have been cancelled?
SELECT count(*) FROM Lessons WHERE lesson_status_code = "Cancelled";
How many classes have been cancelled?
driving_school