Datasets:
HusnaManakkot
/
updated-dataset

Dataset card Data Studio Files Community
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manufactory_1
SELECT name FROM manufacturers WHERE revenue > (SELECT avg(revenue) FROM manufacturers)
Find the name of companies whose revenue is greater than the average revenue of all companies.
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manufactory_1
SELECT name FROM manufacturers WHERE revenue > (SELECT avg(revenue) FROM manufacturers)
What are the names of manufacturers with revenue greater than the average of all revenues?
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manufactory_1
SELECT name FROM manufacturers WHERE revenue < (SELECT min(revenue) FROM manufacturers WHERE headquarter = 'Austin')
Find the name of companies whose revenue is smaller than the revenue of all companies based in Austin.
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manufactory_1
SELECT name FROM manufacturers WHERE revenue < (SELECT min(revenue) FROM manufacturers WHERE headquarter = 'Austin')
What are the names of companies with revenue less than the lowest revenue of any manufacturer in Austin?
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manufactory_1
SELECT sum(revenue) FROM manufacturers WHERE revenue > (SELECT min(revenue) FROM manufacturers WHERE headquarter = 'Austin')
Find the total revenue of companies whose revenue is larger than the revenue of some companies based in Austin.
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manufactory_1
SELECT sum(revenue) FROM manufacturers WHERE revenue > (SELECT min(revenue) FROM manufacturers WHERE headquarter = 'Austin')
What is the total revenue of companies with revenue greater than the lowest revenue of any manufacturer in Austin?
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manufactory_1
SELECT sum(revenue) , founder FROM manufacturers GROUP BY founder
Find the total revenue of companies of each founder.
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manufactory_1
SELECT sum(revenue) , founder FROM manufacturers GROUP BY founder
What is the total revenue of companies started by founder?
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manufactory_1
SELECT name , max(revenue) , Headquarter FROM manufacturers GROUP BY Headquarter
Find the name and revenue of the company that earns the highest revenue in each city.
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manufactory_1
SELECT name , max(revenue) , Headquarter FROM manufacturers GROUP BY Headquarter
What are the names and revenues of the companies with the highest revenues in each headquarter city?
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manufactory_1
SELECT sum(revenue) , name FROM manufacturers GROUP BY name
Find the total revenue for each manufacturer.
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manufactory_1
SELECT sum(revenue) , name FROM manufacturers GROUP BY name
What is the total revenue of each manufacturer?
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manufactory_1
SELECT avg(T1.price) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name
Find the average prices of all products from each manufacture, and list each company's name.
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manufactory_1
SELECT avg(T1.price) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name
What are the average prices of products for each manufacturer?
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manufactory_1
SELECT count(DISTINCT T1.name) , T2.Headquarter FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.Headquarter
Find the number of different products that are produced by companies at different headquarter cities.
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manufactory_1
SELECT count(DISTINCT T1.name) , T2.Headquarter FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.Headquarter
How many different products are produced in each headquarter city?
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manufactory_1
SELECT count(DISTINCT name) FROM products WHERE name NOT IN (SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Sony')
Find number of products which Sony does not make.
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manufactory_1
SELECT count(DISTINCT name) FROM products WHERE name NOT IN (SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Sony')
How many products are not made by Sony?
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manufactory_1
SELECT name FROM manufacturers EXCEPT SELECT T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T1.name = 'DVD drive'
Find the name of companies that do not make DVD drive.
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manufactory_1
SELECT name FROM manufacturers EXCEPT SELECT T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T1.name = 'DVD drive'
What are the names of companies that do not make DVD drives?
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manufactory_1
SELECT count(*) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name
Find the number of products for each manufacturer, showing the name of each company.
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manufactory_1
SELECT count(*) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name
How many products are there for each manufacturer?
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manufactory_1
SELECT Name FROM Products
Select the names of all the products in the store.
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manufactory_1
SELECT Name FROM Products
What are the names of all products?
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manufactory_1
SELECT name , price FROM products
Select the names and the prices of all the products in the store.
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manufactory_1
SELECT name , price FROM products
What are the names and prices of all products in the store?
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manufactory_1
SELECT name FROM products WHERE price <= 200
Select the name of the products with a price less than or equal to $200.
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manufactory_1
SELECT name FROM products WHERE price <= 200
What are the names of products with price at most 200?
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manufactory_1
SELECT * FROM products WHERE price BETWEEN 60 AND 120
Find all information of all the products with a price between $60 and $120.
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manufactory_1
SELECT * FROM products WHERE price BETWEEN 60 AND 120
What is all the information of all the products that have a price between 60 and 120?
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manufactory_1
SELECT avg(price) FROM products
Compute the average price of all the products.
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manufactory_1
SELECT avg(price) FROM products
What is the average price across all products?
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manufactory_1
SELECT avg(price) FROM products WHERE Manufacturer = 2
Compute the average price of all products with manufacturer code equal to 2.
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manufactory_1
SELECT avg(price) FROM products WHERE Manufacturer = 2
What is the average price of products with manufacturer codes equal to 2?
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manufactory_1
SELECT count(*) FROM products WHERE price >= 180
Compute the number of products with a price larger than or equal to $180.
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manufactory_1
SELECT count(*) FROM products WHERE price >= 180
How many products have prices of at least 180?
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manufactory_1
SELECT name , price FROM products WHERE price >= 180 ORDER BY price DESC , name ASC
Select the name and price of all products with a price larger than or equal to $180, and sort first by price (in descending order), and then by name (in ascending order).
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manufactory_1
SELECT name , price FROM products WHERE price >= 180 ORDER BY price DESC , name ASC
What are the names and prices of products that cost at least 180, sorted by price decreasing and name ascending?
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manufactory_1
SELECT * FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code
Select all the data from the products and each product's manufacturer.
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[ "Select", "all", "the", "data", "from", "the", "products", "and", "each", "product", "'s", "manufacturer", "." ]
manufactory_1
SELECT * FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code
What is all the product data, as well as each product's manufacturer?
[ "SELECT", "*", "FROM", "products", "AS", "T1", "JOIN", "Manufacturers", "AS", "T2", "ON", "T1.manufacturer", "=", "T2.code" ]
[ "select", "*", "from", "products", "as", "t1", "join", "manufacturers", "as", "t2", "on", "t1", ".", "manufacturer", "=", "t2", ".", "code" ]
[ "What", "is", "all", "the", "product", "data", ",", "as", "well", "as", "each", "product", "'s", "manufacturer", "?" ]
manufactory_1
SELECT AVG(Price) , Manufacturer FROM Products GROUP BY Manufacturer
Select the average price of each manufacturer's products, showing only the manufacturer's code.
[ "SELECT", "AVG", "(", "Price", ")", ",", "Manufacturer", "FROM", "Products", "GROUP", "BY", "Manufacturer" ]
[ "select", "avg", "(", "price", ")", ",", "manufacturer", "from", "products", "group", "by", "manufacturer" ]
[ "Select", "the", "average", "price", "of", "each", "manufacturer", "'s", "products", ",", "showing", "only", "the", "manufacturer", "'s", "code", "." ]
manufactory_1
SELECT AVG(Price) , Manufacturer FROM Products GROUP BY Manufacturer
What are the average prices of products, grouped by manufacturer code?
[ "SELECT", "AVG", "(", "Price", ")", ",", "Manufacturer", "FROM", "Products", "GROUP", "BY", "Manufacturer" ]
[ "select", "avg", "(", "price", ")", ",", "manufacturer", "from", "products", "group", "by", "manufacturer" ]
[ "What", "are", "the", "average", "prices", "of", "products", ",", "grouped", "by", "manufacturer", "code", "?" ]
manufactory_1
SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name
Select the average price of each manufacturer's products, showing the manufacturer's name.
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[ "Select", "the", "average", "price", "of", "each", "manufacturer", "'s", "products", ",", "showing", "the", "manufacturer", "'s", "name", "." ]
manufactory_1
SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name
What are the average prices of products, grouped by manufacturer name?
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[ "select", "avg", "(", "t1", ".", "price", ")", ",", "t2", ".", "name", "from", "products", "as", "t1", "join", "manufacturers", "as", "t2", "on", "t1", ".", "manufacturer", "=", "t2", ".", "code", "group", "by", "t2", ".", "name" ]
[ "What", "are", "the", "average", "prices", "of", "products", ",", "grouped", "by", "manufacturer", "name", "?" ]
manufactory_1
SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name HAVING avg(T1.price) >= 150
Select the names of manufacturer whose products have an average price higher than or equal to $150.
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[ "Select", "the", "names", "of", "manufacturer", "whose", "products", "have", "an", "average", "price", "higher", "than", "or", "equal", "to", "$", "150", "." ]
manufactory_1
SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name HAVING avg(T1.price) >= 150
What are the names and average prices of products for manufacturers whose products cost on average 150 or more?
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[ "What", "are", "the", "names", "and", "average", "prices", "of", "products", "for", "manufacturers", "whose", "products", "cost", "on", "average", "150", "or", "more", "?" ]
manufactory_1
SELECT name , price FROM Products ORDER BY price ASC LIMIT 1
Select the name and price of the cheapest product.
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[ "select", "name", ",", "price", "from", "products", "order", "by", "price", "asc", "limit", "value" ]
[ "Select", "the", "name", "and", "price", "of", "the", "cheapest", "product", "." ]
manufactory_1
SELECT name , price FROM Products ORDER BY price ASC LIMIT 1
What is the name and price of the cheapest product?
[ "SELECT", "name", ",", "price", "FROM", "Products", "ORDER", "BY", "price", "ASC", "LIMIT", "1" ]
[ "select", "name", ",", "price", "from", "products", "order", "by", "price", "asc", "limit", "value" ]
[ "What", "is", "the", "name", "and", "price", "of", "the", "cheapest", "product", "?" ]
manufactory_1
SELECT T1.Name , max(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name
Select the name of each manufacturer along with the name and price of its most expensive product.
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[ "Select", "the", "name", "of", "each", "manufacturer", "along", "with", "the", "name", "and", "price", "of", "its", "most", "expensive", "product", "." ]
manufactory_1
SELECT T1.Name , max(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name
For each manufacturer name, what are the names and prices of their most expensive product?
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[ "For", "each", "manufacturer", "name", ",", "what", "are", "the", "names", "and", "prices", "of", "their", "most", "expensive", "product", "?" ]
manufactory_1
SELECT code , name , min(price) FROM products GROUP BY name
Select the code of the product that is cheapest in each product category.
[ "SELECT", "code", ",", "name", ",", "min", "(", "price", ")", "FROM", "products", "GROUP", "BY", "name" ]
[ "select", "code", ",", "name", ",", "min", "(", "price", ")", "from", "products", "group", "by", "name" ]
[ "Select", "the", "code", "of", "the", "product", "that", "is", "cheapest", "in", "each", "product", "category", "." ]
manufactory_1
SELECT code , name , min(price) FROM products GROUP BY name
What are the codes and names of the cheapest products in each category?
[ "SELECT", "code", ",", "name", ",", "min", "(", "price", ")", "FROM", "products", "GROUP", "BY", "name" ]
[ "select", "code", ",", "name", ",", "min", "(", "price", ")", "from", "products", "group", "by", "name" ]
[ "What", "are", "the", "codes", "and", "names", "of", "the", "cheapest", "products", "in", "each", "category", "?" ]
tracking_software_problems
SELECT problem_log_id FROM problem_log ORDER BY log_entry_date DESC LIMIT 1
What is the id of the problem log that is created most recently?
[ "SELECT", "problem_log_id", "FROM", "problem_log", "ORDER", "BY", "log_entry_date", "DESC", "LIMIT", "1" ]
[ "select", "problem_log_id", "from", "problem_log", "order", "by", "log_entry_date", "desc", "limit", "value" ]
[ "What", "is", "the", "id", "of", "the", "problem", "log", "that", "is", "created", "most", "recently", "?" ]
tracking_software_problems
SELECT problem_log_id FROM problem_log ORDER BY log_entry_date DESC LIMIT 1
Which problem log was created most recently? Give me the log id.
[ "SELECT", "problem_log_id", "FROM", "problem_log", "ORDER", "BY", "log_entry_date", "DESC", "LIMIT", "1" ]
[ "select", "problem_log_id", "from", "problem_log", "order", "by", "log_entry_date", "desc", "limit", "value" ]
[ "Which", "problem", "log", "was", "created", "most", "recently", "?", "Give", "me", "the", "log", "id", "." ]
tracking_software_problems
SELECT problem_log_id , problem_id FROM problem_log ORDER BY log_entry_date LIMIT 1
What is the oldest log id and its corresponding problem id?
[ "SELECT", "problem_log_id", ",", "problem_id", "FROM", "problem_log", "ORDER", "BY", "log_entry_date", "LIMIT", "1" ]
[ "select", "problem_log_id", ",", "problem_id", "from", "problem_log", "order", "by", "log_entry_date", "limit", "value" ]
[ "What", "is", "the", "oldest", "log", "id", "and", "its", "corresponding", "problem", "id", "?" ]
tracking_software_problems
SELECT problem_log_id , problem_id FROM problem_log ORDER BY log_entry_date LIMIT 1
Find the oldest log id and its corresponding problem id.
[ "SELECT", "problem_log_id", ",", "problem_id", "FROM", "problem_log", "ORDER", "BY", "log_entry_date", "LIMIT", "1" ]
[ "select", "problem_log_id", ",", "problem_id", "from", "problem_log", "order", "by", "log_entry_date", "limit", "value" ]
[ "Find", "the", "oldest", "log", "id", "and", "its", "corresponding", "problem", "id", "." ]
tracking_software_problems
SELECT problem_log_id , log_entry_date FROM problem_log WHERE problem_id = 10
Find all the ids and dates of the logs for the problem whose id is 10.
[ "SELECT", "problem_log_id", ",", "log_entry_date", "FROM", "problem_log", "WHERE", "problem_id", "=", "10" ]
[ "select", "problem_log_id", ",", "log_entry_date", "from", "problem_log", "where", "problem_id", "=", "value" ]
[ "Find", "all", "the", "ids", "and", "dates", "of", "the", "logs", "for", "the", "problem", "whose", "id", "is", "10", "." ]
tracking_software_problems
SELECT problem_log_id , log_entry_date FROM problem_log WHERE problem_id = 10
For the problem with id 10, return the ids and dates of its problem logs.
[ "SELECT", "problem_log_id", ",", "log_entry_date", "FROM", "problem_log", "WHERE", "problem_id", "=", "10" ]
[ "select", "problem_log_id", ",", "log_entry_date", "from", "problem_log", "where", "problem_id", "=", "value" ]
[ "For", "the", "problem", "with", "id", "10", ",", "return", "the", "ids", "and", "dates", "of", "its", "problem", "logs", "." ]
tracking_software_problems
SELECT problem_log_id , log_entry_description FROM problem_log
List all the log ids and their descriptions from the problem logs.
[ "SELECT", "problem_log_id", ",", "log_entry_description", "FROM", "problem_log" ]
[ "select", "problem_log_id", ",", "log_entry_description", "from", "problem_log" ]
[ "List", "all", "the", "log", "ids", "and", "their", "descriptions", "from", "the", "problem", "logs", "." ]
tracking_software_problems
SELECT problem_log_id , log_entry_description FROM problem_log
What are the log id and entry description of each problem?
[ "SELECT", "problem_log_id", ",", "log_entry_description", "FROM", "problem_log" ]
[ "select", "problem_log_id", ",", "log_entry_description", "from", "problem_log" ]
[ "What", "are", "the", "log", "id", "and", "entry", "description", "of", "each", "problem", "?" ]
tracking_software_problems
SELECT DISTINCT staff_first_name , staff_last_name FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T2.problem_id = 1
List the first and last names of all distinct staff members who are assigned to the problem whose id is 1.
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[ "select", "distinct", "staff_first_name", ",", "staff_last_name", "from", "staff", "as", "t1", "join", "problem_log", "as", "t2", "on", "t1", ".", "staff_id", "=", "t2", ".", "assigned_to_staff_id", "where", "t2", ".", "problem_id", "=", "value" ]
[ "List", "the", "first", "and", "last", "names", "of", "all", "distinct", "staff", "members", "who", "are", "assigned", "to", "the", "problem", "whose", "id", "is", "1", "." ]
tracking_software_problems
SELECT DISTINCT staff_first_name , staff_last_name FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T2.problem_id = 1
Which staff members are assigned to the problem with id 1? Give me their first and last names.
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[ "select", "distinct", "staff_first_name", ",", "staff_last_name", "from", "staff", "as", "t1", "join", "problem_log", "as", "t2", "on", "t1", ".", "staff_id", "=", "t2", ".", "assigned_to_staff_id", "where", "t2", ".", "problem_id", "=", "value" ]
[ "Which", "staff", "members", "are", "assigned", "to", "the", "problem", "with", "id", "1", "?", "Give", "me", "their", "first", "and", "last", "names", "." ]
tracking_software_problems
SELECT DISTINCT T2.problem_id , T2.problem_log_id FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T1.staff_first_name = "Rylan" AND T1.staff_last_name = "Homenick"
List the problem id and log id which are assigned to the staff named Rylan Homenick.
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[ "List", "the", "problem", "id", "and", "log", "id", "which", "are", "assigned", "to", "the", "staff", "named", "Rylan", "Homenick", "." ]
tracking_software_problems
SELECT DISTINCT T2.problem_id , T2.problem_log_id FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T1.staff_first_name = "Rylan" AND T1.staff_last_name = "Homenick"
Which problem id and log id are assigned to the staff named Rylan Homenick?
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[ "Which", "problem", "id", "and", "log", "id", "are", "assigned", "to", "the", "staff", "named", "Rylan", "Homenick", "?" ]
tracking_software_problems
SELECT count(*) FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id WHERE T1.product_name = "voluptatem"
How many problems are there for product voluptatem?
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[ "select", "count", "(", "*", ")", "from", "product", "as", "t1", "join", "problems", "as", "t2", "on", "t1", ".", "product_id", "=", "t2", ".", "product_id", "where", "t1", ".", "product_name", "=", "value" ]
[ "How", "many", "problems", "are", "there", "for", "product", "voluptatem", "?" ]
tracking_software_problems
SELECT count(*) FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id WHERE T1.product_name = "voluptatem"
How many problems did the product called "voluptatem" have in record?
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[ "How", "many", "problems", "did", "the", "product", "called", "``", "voluptatem", "''", "have", "in", "record", "?" ]
tracking_software_problems
SELECT count(*) , T1.product_name FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_name ORDER BY count(*) DESC LIMIT 1
How many problems does the product with the most problems have? List the number of the problems and product name.
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[ "How", "many", "problems", "does", "the", "product", "with", "the", "most", "problems", "have", "?", "List", "the", "number", "of", "the", "problems", "and", "product", "name", "." ]
tracking_software_problems
SELECT count(*) , T1.product_name FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_name ORDER BY count(*) DESC LIMIT 1
Which product has the most problems? Give me the number of problems and the product name.
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[ "Which", "product", "has", "the", "most", "problems", "?", "Give", "me", "the", "number", "of", "problems", "and", "the", "product", "name", "." ]
tracking_software_problems
SELECT T1.problem_description FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop"
Give me a list of descriptions of the problems that are reported by the staff whose first name is Christop.
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[ "Give", "me", "a", "list", "of", "descriptions", "of", "the", "problems", "that", "are", "reported", "by", "the", "staff", "whose", "first", "name", "is", "Christop", "." ]
tracking_software_problems
SELECT T1.problem_description FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop"
Which problems are reported by the staff with first name "Christop"? Show the descriptions of the problems.
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[ "select", "t1", ".", "problem_description", "from", "problems", "as", "t1", "join", "staff", "as", "t2", "on", "t1", ".", "reported_by_staff_id", "=", "t2", ".", "staff_id", "where", "t2", ".", "staff_first_name", "=", "value" ]
[ "Which", "problems", "are", "reported", "by", "the", "staff", "with", "first", "name", "``", "Christop", "''", "?", "Show", "the", "descriptions", "of", "the", "problems", "." ]
tracking_software_problems
SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_last_name = "Bosco"
Find the ids of the problems that are reported by the staff whose last name is Bosco.
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[ "Find", "the", "ids", "of", "the", "problems", "that", "are", "reported", "by", "the", "staff", "whose", "last", "name", "is", "Bosco", "." ]
tracking_software_problems
SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_last_name = "Bosco"
Which problems are reported by the staff with last name "Bosco"? Show the ids of the problems.
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[ "Which", "problems", "are", "reported", "by", "the", "staff", "with", "last", "name", "``", "Bosco", "''", "?", "Show", "the", "ids", "of", "the", "problems", "." ]
tracking_software_problems
SELECT problem_id FROM problems WHERE date_problem_reported > "1978-06-26"
What are the ids of the problems which are reported after 1978-06-26?
[ "SELECT", "problem_id", "FROM", "problems", "WHERE", "date_problem_reported", ">", "``", "1978-06-26", "''" ]
[ "select", "problem_id", "from", "problems", "where", "date_problem_reported", ">", "value" ]
[ "What", "are", "the", "ids", "of", "the", "problems", "which", "are", "reported", "after", "1978-06-26", "?" ]
tracking_software_problems
SELECT problem_id FROM problems WHERE date_problem_reported > "1978-06-26"
Find the ids of the problems reported after 1978-06-26.
[ "SELECT", "problem_id", "FROM", "problems", "WHERE", "date_problem_reported", ">", "``", "1978-06-26", "''" ]
[ "select", "problem_id", "from", "problems", "where", "date_problem_reported", ">", "value" ]
[ "Find", "the", "ids", "of", "the", "problems", "reported", "after", "1978-06-26", "." ]
tracking_software_problems
SELECT problem_id FROM problems WHERE date_problem_reported < "1978-06-26"
What are the ids of the problems which are reported before 1978-06-26?
[ "SELECT", "problem_id", "FROM", "problems", "WHERE", "date_problem_reported", "<", "``", "1978-06-26", "''" ]
[ "select", "problem_id", "from", "problems", "where", "date_problem_reported", "<", "value" ]
[ "What", "are", "the", "ids", "of", "the", "problems", "which", "are", "reported", "before", "1978-06-26", "?" ]
tracking_software_problems
SELECT problem_id FROM problems WHERE date_problem_reported < "1978-06-26"
Which problems are reported before 1978-06-26? Give me the ids of the problems.
[ "SELECT", "problem_id", "FROM", "problems", "WHERE", "date_problem_reported", "<", "``", "1978-06-26", "''" ]
[ "select", "problem_id", "from", "problems", "where", "date_problem_reported", "<", "value" ]
[ "Which", "problems", "are", "reported", "before", "1978-06-26", "?", "Give", "me", "the", "ids", "of", "the", "problems", "." ]
tracking_software_problems
SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_id
For each product which has problems, what are the number of problems and the product id?
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[ "For", "each", "product", "which", "has", "problems", ",", "what", "are", "the", "number", "of", "problems", "and", "the", "product", "id", "?" ]
tracking_software_problems
SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_id
For each product with some problems, list the count of problems and the product id.
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[ "select", "count", "(", "*", ")", ",", "t2", ".", "product_id", "from", "problems", "as", "t1", "join", "product", "as", "t2", "on", "t1", ".", "product_id", "=", "t2", ".", "product_id", "group", "by", "t2", ".", "product_id" ]
[ "For", "each", "product", "with", "some", "problems", ",", "list", "the", "count", "of", "problems", "and", "the", "product", "id", "." ]
tracking_software_problems
SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T1.date_problem_reported > "1986-11-13" GROUP BY T2.product_id
For each product that has problems, find the number of problems reported after 1986-11-13 and the product id?
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[ "For", "each", "product", "that", "has", "problems", ",", "find", "the", "number", "of", "problems", "reported", "after", "1986-11-13", "and", "the", "product", "id", "?" ]
tracking_software_problems
SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T1.date_problem_reported > "1986-11-13" GROUP BY T2.product_id
What are the products that have problems reported after 1986-11-13? Give me the product id and the count of problems reported after 1986-11-13.
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[ "select", "count", "(", "*", ")", ",", "t2", ".", "product_id", "from", "problems", "as", "t1", "join", "product", "as", "t2", "on", "t1", ".", "product_id", "=", "t2", ".", "product_id", "where", "t1", ".", "date_problem_reported", ">", "value", "group", "by", "t2", ".", "product_id" ]
[ "What", "are", "the", "products", "that", "have", "problems", "reported", "after", "1986-11-13", "?", "Give", "me", "the", "product", "id", "and", "the", "count", "of", "problems", "reported", "after", "1986-11-13", "." ]
tracking_software_problems
SELECT DISTINCT product_name FROM product ORDER BY product_name
List the names of all the distinct product names in alphabetical order?
[ "SELECT", "DISTINCT", "product_name", "FROM", "product", "ORDER", "BY", "product_name" ]
[ "select", "distinct", "product_name", "from", "product", "order", "by", "product_name" ]
[ "List", "the", "names", "of", "all", "the", "distinct", "product", "names", "in", "alphabetical", "order", "?" ]
tracking_software_problems
SELECT DISTINCT product_name FROM product ORDER BY product_name
Sort all the distinct product names in alphabetical order.
[ "SELECT", "DISTINCT", "product_name", "FROM", "product", "ORDER", "BY", "product_name" ]
[ "select", "distinct", "product_name", "from", "product", "order", "by", "product_name" ]
[ "Sort", "all", "the", "distinct", "product", "names", "in", "alphabetical", "order", "." ]
tracking_software_problems
SELECT DISTINCT product_name FROM product ORDER BY product_id
List all the distinct product names ordered by product id?
[ "SELECT", "DISTINCT", "product_name", "FROM", "product", "ORDER", "BY", "product_id" ]
[ "select", "distinct", "product_name", "from", "product", "order", "by", "product_id" ]
[ "List", "all", "the", "distinct", "product", "names", "ordered", "by", "product", "id", "?" ]
tracking_software_problems
SELECT DISTINCT product_name FROM product ORDER BY product_id
What is the list of distinct product names sorted by product id?
[ "SELECT", "DISTINCT", "product_name", "FROM", "product", "ORDER", "BY", "product_id" ]
[ "select", "distinct", "product_name", "from", "product", "order", "by", "product_id" ]
[ "What", "is", "the", "list", "of", "distinct", "product", "names", "sorted", "by", "product", "id", "?" ]
tracking_software_problems
SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Dameon" AND T2.staff_last_name = "Frami" UNION SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Jolie" AND T2.staff_last_name = "Weber"
What are the id of problems reported by the staff named Dameon Frami or Jolie Weber?
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[ "select", "product_id", "from", "problems", "as", "t1", "join", "staff", "as", "t2", "on", "t1", ".", "reported_by_staff_id", "=", "t2", ".", "staff_id", "where", "t2", ".", "staff_first_name", "=", "value", "and", "t2", ".", "staff_last_name", "=", "value", "union", "select", "product_id", "from", "problems", "as", "t1", "join", "staff", "as", "t2", "on", "t1", ".", "reported_by_staff_id", "=", "t2", ".", "staff_id", "where", "t2", ".", "staff_first_name", "=", "value", "and", "t2", ".", "staff_last_name", "=", "value" ]
[ "What", "are", "the", "id", "of", "problems", "reported", "by", "the", "staff", "named", "Dameon", "Frami", "or", "Jolie", "Weber", "?" ]
tracking_software_problems
SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Dameon" AND T2.staff_last_name = "Frami" UNION SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Jolie" AND T2.staff_last_name = "Weber"
Which problems were reported by the staff named Dameon Frami or Jolie Weber? Give me the ids of the problems.
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[ "Which", "problems", "were", "reported", "by", "the", "staff", "named", "Dameon", "Frami", "or", "Jolie", "Weber", "?", "Give", "me", "the", "ids", "of", "the", "problems", "." ]
tracking_software_problems
SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop" AND T2.staff_last_name = "Berge" INTERSECT SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.closure_authorised_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Ashley" AND T2.staff_last_name = "Medhurst"
What are the product ids for the problems reported by Christop Berge with closure authorised by Ashley Medhurst?
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[ "What", "are", "the", "product", "ids", "for", "the", "problems", "reported", "by", "Christop", "Berge", "with", "closure", "authorised", "by", "Ashley", "Medhurst", "?" ]
tracking_software_problems
SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop" AND T2.staff_last_name = "Berge" INTERSECT SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.closure_authorised_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Ashley" AND T2.staff_last_name = "Medhurst"
For which product was there a problem reported by Christop Berge, with closure authorised by Ashley Medhurst? Return the product ids.
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[ "For", "which", "product", "was", "there", "a", "problem", "reported", "by", "Christop", "Berge", ",", "with", "closure", "authorised", "by", "Ashley", "Medhurst", "?", "Return", "the", "product", "ids", "." ]
tracking_software_problems
SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported < ( SELECT min(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Lysanne" AND T4.staff_last_name = "Turcotte" )
What are the ids of the problems reported before the date of any problem reported by Lysanne Turcotte?
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[ "What", "are", "the", "ids", "of", "the", "problems", "reported", "before", "the", "date", "of", "any", "problem", "reported", "by", "Lysanne", "Turcotte", "?" ]
tracking_software_problems
SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported < ( SELECT min(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Lysanne" AND T4.staff_last_name = "Turcotte" )
Which problems were reported before the date of any problem reported by the staff Lysanne Turcotte? Give me the ids of the problems.
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[ "Which", "problems", "were", "reported", "before", "the", "date", "of", "any", "problem", "reported", "by", "the", "staff", "Lysanne", "Turcotte", "?", "Give", "me", "the", "ids", "of", "the", "problems", "." ]
tracking_software_problems
SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported > ( SELECT max(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Rylan" AND T4.staff_last_name = "Homenick" )
What are the ids of the problems reported after the date of any problems reported by Rylan Homenick?
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[ "What", "are", "the", "ids", "of", "the", "problems", "reported", "after", "the", "date", "of", "any", "problems", "reported", "by", "Rylan", "Homenick", "?" ]
tracking_software_problems
SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported > ( SELECT max(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Rylan" AND T4.staff_last_name = "Homenick" )
Find the ids of the problems reported after the date of any problems reported by the staff Rylan Homenick.
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[ "Find", "the", "ids", "of", "the", "problems", "reported", "after", "the", "date", "of", "any", "problems", "reported", "by", "the", "staff", "Rylan", "Homenick", "." ]
tracking_software_problems
SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY count(*) DESC LIMIT 3
Find the top 3 products which have the largest number of problems?
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[ "Find", "the", "top", "3", "products", "which", "have", "the", "largest", "number", "of", "problems", "?" ]
tracking_software_problems
SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY count(*) DESC LIMIT 3
What are the three products that have the most problems?s
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[ "What", "are", "the", "three", "products", "that", "have", "the", "most", "problems", "?", "s" ]
tracking_software_problems
SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "voluptatem" AND T1.date_problem_reported > "1995"
List the ids of the problems from the product "voluptatem" that are reported after 1995?
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[ "List", "the", "ids", "of", "the", "problems", "from", "the", "product", "``", "voluptatem", "''", "that", "are", "reported", "after", "1995", "?" ]
tracking_software_problems
SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "voluptatem" AND T1.date_problem_reported > "1995"
What are the ids of the problems that are from the product "voluptatem" and are reported after 1995?
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[ "What", "are", "the", "ids", "of", "the", "problems", "that", "are", "from", "the", "product", "``", "voluptatem", "''", "and", "are", "reported", "after", "1995", "?" ]
tracking_software_problems
SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "rem" EXCEPT SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "aut"
Find the first and last name of the staff members who reported problems from the product "rem" but not "aut"?
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[ "Find", "the", "first", "and", "last", "name", "of", "the", "staff", "members", "who", "reported", "problems", "from", "the", "product", "``", "rem", "''", "but", "not", "``", "aut", "''", "?" ]
tracking_software_problems
SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "rem" EXCEPT SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "aut"
Which staff members who reported problems from the product "rem" but not "aut"? Give me their first and last names.
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[ "Which", "staff", "members", "who", "reported", "problems", "from", "the", "product", "``", "rem", "''", "but", "not", "``", "aut", "''", "?", "Give", "me", "their", "first", "and", "last", "names", "." ]
tracking_software_problems
SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Lacey" AND T3.staff_last_name = "Bosco" INTERSECT SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Kenton" AND T3.staff_last_name = "Champlin"
Find the products which have problems reported by both Lacey Bosco and Kenton Champlin?
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[ "Find", "the", "products", "which", "have", "problems", "reported", "by", "both", "Lacey", "Bosco", "and", "Kenton", "Champlin", "?" ]
tracking_software_problems
SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Lacey" AND T3.staff_last_name = "Bosco" INTERSECT SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Kenton" AND T3.staff_last_name = "Champlin"
Which products have problems reported by both the staff named Lacey Bosco and the staff named Kenton Champlin?
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