// #pragma GCC optimize("Ofast,unroll-loops") // #pragma GCC target("avx,avx2,fma") #include using namespace std; #define ll long long #define ull unsigned long long #define dd double #define ld long double #define sl(n) scanf("%lld", &n) #define si(n) scanf("%d", &n) #define sd(n) scanf("%lf", &n) #define pll pair #define pii pair #define mp make_pair #define pb push_back #define all(v) v.begin(), v.end() #define inf (1LL << 62) #define loop(i, start, stop, inc) for(ll i = start; i <= stop; i += inc) #define for1(i, stop) for(ll i = 1; i <= stop; ++i) #define for0(i, stop) for(ll i = 0; i < stop; ++i) #define rep1(i, start) for(ll i = start; i >= 1; --i) #define rep0(i, start) for(ll i = (start-1); i >= 0; --i) #define ms(n, i) memset(n, i, sizeof(n)) #define casep(n) printf("Case %lld:", ++n) #define pn printf("\n") #define pf printf #define EL '\n' #define fastio std::ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL); const ll sz = 5e4 + 10; pii ara[sz], lst[sz]; ll pnt[sz], dp[sz]; struct Line { ll m, c; } tree[4*sz]; bool exist[4*sz]; inline ll f(Line &line, ll x) { return line.m*x + line.c; } void add(ll lo, ll hi, Line line, ll node) { exist[node] = 1; if(lo == hi) { if(f(line, pnt[lo]) < f(tree[node], pnt[lo])) tree[node] = line; return; } ll mid = lo+hi >> 1; bool l = f(line, pnt[lo]) < f(tree[node], pnt[lo]); bool m = f(line, pnt[mid]) < f(tree[node], pnt[mid]); if(m) swap(tree[node], line); if(l != m) add(lo, mid, line, node<<1); else add(mid +1, hi, line, node<<1|1); } ll query(ll lo, ll hi, ll idx, ll node) { if(lo == hi) return f(tree[node], pnt[idx]); ll mid = lo+hi >> 1, ret = f(tree[node], pnt[idx]); if(idx <= mid && exist[node<<1]) ret = min(ret, query(lo, mid, idx, node<<1)); else if(idx > mid && exist[node<<1|1]) ret = min(ret, query(mid+1, hi, idx, node<<1|1)); return ret; } int main() { ll n; cin >> n; for1(i, n) { si(ara[i].first), si(ara[i].second); } sort(ara+1, ara+n+1); ll mxw = 0, idx = 0; rep1(i, n) { if(ara[i].second > mxw) lst[++idx] = ara[i]; mxw = max(mxw, (ll)ara[i].second); } reverse(lst+1, lst+idx+1); for1(i, idx) pnt[i] = lst[i].first; for0(i, 4*sz) tree[i] = {0, inf}; for1(i, idx) { add(1, idx, {lst[i].second, dp[i-1]}, 1); dp[i] = query(1, idx, i, 1); } cout << dp[idx] << EL; return 0;