{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<string.h>\nint a[1000];\nint main(){\nint i,j,k,m,n;\n    scanf(\"%d %d\",&n,&m);\n    for(i=0;i<=n;i++)a[i]=0;\n    for(i=1;i<=m;i++){\n            scanf(\"%d\",&k);\n            for(j=k;j<=n;j++){\n                    if(a[j]==0)a[j]=k;\n                    }\n            }\n    for(i=1;i<n;i++)printf(\"%d \",a[i]);\n    printf(\"%d\\n\",a[i]);\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d600a5aba26357f0ef36d109d372fe76", "src_uid": "2e44c8aabab7ef7b06bbab8719a8d863", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n     int a,b,c,d,i,n,k,ss[110],dd[110];\n     while(scanf(\"%d %d\",&a,&b)==2)\n        {\n            for(i=0;i<110;i++)\n                dd[i]=0;\n            for(i=1;i<=b;i++)\n                {\n                    scanf(\"%d\",&ss[i]);\n                   for(n=ss[i];n<=a;n++)\n                    {\n                        if(dd[n]==0)   dd[n]=ss[i];\n                    }\n                }\n            for(i=1;i<=a;i++)\n            {\n                printf(\"%d\",dd[i]);\n                if(i!=a)  printf(\" \");\n                else printf(\"\\n\");\n            }\n        }\n}\n\n\n                                                                              ", "lang_cluster": "C", "compilation_error": false, "code_uid": "3697d5bb303e15884556e4adf0ae8afa", "src_uid": "2e44c8aabab7ef7b06bbab8719a8d863", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int k,c=1,s=0;\n    scanf(\"%d\",&k);\n    while(k>0)\n    {\n        k+k-c;\n        c+=1;\n        s+=1;\n    }\n    printf(\"%d\",s);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "33bcfa7cb1b5832af883ae16eb70c632", "src_uid": "873a12edffc57a127fdfb1c65d43bdb0", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{long long int s=0,i=1,n,cnt=0,sum=0,l;\nscanf(\"%I64d\",&n);\nwhile(1)\n{\n\n\n     sum=sum+(i*(i+1))/2;\n    cnt++;\n    i++;\n   if((sum)==n)\n   {\n    break;}\n    if(n<sum&&n>sum-n)\n    {\n        cnt=cnt-1;\n        break;\n    }\n\n\n\n}\nprintf(\"%I64d\",cnt);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b7cb0a02c3a8493f4bfc239e5b4360f9", "src_uid": "873a12edffc57a127fdfb1c65d43bdb0", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n    int a,sum=1,i=2,c=0;\n    scanf(\"%d\",&a);\n    while(a!=0)\n    {\n            a -= sum;\n            c++;\n            sum +=i;\n            i++;\n        \n    }\n    printf(\"%d\",c);\n    \n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a318c869b163ebb7b0e540c4b91e42fb", "src_uid": "873a12edffc57a127fdfb1c65d43bdb0", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(void)\n{\n    int n,i,h;\n    do{\n        scanf(\"%d\",&n);\n    }\n    while(n<10001 && n>0);\n    while(i<n)\n    {\n     h++;\n     i=i+(i*(i+1))/2 ;\n    }\n    printf(\"%d\",h-1);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dca1e4722e5e57c6816eafaf41d1bfd2", "src_uid": "873a12edffc57a127fdfb1c65d43bdb0", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<string.h>\n#include<stdlib.h>\n#define pi acos(-1)\n\nint main()\n{\n\tint n,i=1,j,k,l,m,sum=0,count=0;\n\tscanf(\"%d\", &n);\n\tif(n==1) printf(\"1\\n\");\n\telse if(n==0) printf(\"0\\n\");\n\telse\n\t{\n\n\t\tsum=i;\n\t\twhile(1)\n\t\t{\n\t\t\t++count;\n\t\t\ti=i+2;\n\t\t\tsum=sum+i;\n\t\t\tif(sum==n) break;\n\t\t}\n\t\t\n\t\tprintf(\"%d\\n\", count);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b53f0c845d69857acf88a4737e71c24a", "src_uid": "873a12edffc57a127fdfb1c65d43bdb0", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdlib.h>\nmain()\n{\n    int i=1,j,k=1;\n    char s[100],a[26];\n    scanf(\"%s\",s);\n    while(s[i]!='\\0')\n    {\n        for(j=0;j<k;j++)\n        {\n            if(a[j]!=s[i])\n            {\n                a[k]=s[i];\n                k+=1;\n            }\n        }\n\n        i+=1;\n    }\n    if(k%2==0) printf(\"CHAT WITH HER!\");\n    else printf(\"IGNORE HIM!\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d43edf938c0bce27b58fd84881784b39", "src_uid": "a8c14667b94b40da087501fd4bdd7818", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<ctype.h>\n\nint main()\n{   char str[120];\n    int  dist, j;\n    while(1){\n\n    scanf(\"%s\", &str);\n    dist=0;\n\n    for(char i='a'; i<='z' ; i++)\n        for(j=0; str[j]!=NULL; j++)\n\n    {\n        if(i==str[j]){\n            dist++;\n            break;}\n    }\n\n    if(dist%2==0)\n    printf(\"CHAT WITH HER!\");\n    else printf(\"IGNORE HIM!\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a78f0faf7350a66ed4c90dca0b1ea278", "src_uid": "a8c14667b94b40da087501fd4bdd7818", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main ()\n{\n    char str[100];\n    int i=0,j=0,len1=0,len2=0,k,kk,temp,c=0;\n    gets(str);\n    len1=strlen(str);\n    for(k=0;k<len1;k++)\n    {\n        for(kk=0;kk<len1-1;kk++)\n        {\n            if(str[kk]>str[kk+1])\n            {\n              temp=str[kk];\n              str[kk]=str[kk+1];\n              str[kk+1]=temp;\n            }  \n        }\n    }\n    while(str[i]!='\\0')\n    {\n        if(str[i]!=str[i+1])\n        {\n        i++;\n        c++;\n        }\n    }\n    if((c+1)%2==0)\n    printf(\"CHAT WITH HER!\\n\");\n    else\n    printf(\"IGNORE HIM!\\n\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ff0fbe4f28cdf5566d11fc957f2280bf", "src_uid": "a8c14667b94b40da087501fd4bdd7818", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdlib.h>\nmain()\n{\n    int i=1,j,k=1;\n    char s[100],a[26];\n    scanf(\"%s\",&s);\n    while(s[i]!='\\0')\n    {\n        for(j=0;j<k;j++)\n        {\n            if(a[j]!=s[i])\n            {\n                a[k]=s[i];\n                k+=1;\n            }\n        }\n    }\n    if(k%2==0) printf(\"CHAT WITH HER!\");\n    else printf(\"IGNORE HIM!\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "30e41fe5782015440a32e2c8cda414a7", "src_uid": "a8c14667b94b40da087501fd4bdd7818", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n/* run this program using the console pauser or add your own getch, system(\"pause\") or input loop */\n\nint main()\n{   \n    //Declaracion de variables\n    int OriginalLetters = 1, Tester = 1, ComparisonLetters = 0; \n    int Cantidad = 1;\n    char Cadena[102], Cadena2[102]; //Cadena Original, La Cadena2 permite comparar\n    \n    //Escaneo de Cadena\n    scanf(\"%s\",&Cadena);\n    \n    Cadena2[0] = Cadena[0];  // Para poder comparar ambas cadenas se necesita el caracter de la posicion 0 en la posicion 0 de la cadena 2\n    \n    while(Cadena[OriginalLetters] != '\\0')\n    {\n          while(Cadena2[ComparisonLetters] != '\\0' )\n          {\n                if(Cadena2[ComparisonLetters] == Cadena[OriginalLetters])\n                {\n                     Tester = 0;\n                     ComparisonLetters = 102;\n                }\n                \n                else\n                   ComparisonLetters++;  \n                \n          }\n          \n          if(Tester == 1)\n          {\n          \n             Cadena2[OriginalLetters] = Cadena[OriginalLetters];\n             Cantidad++;\n             \n          }\n          Tester = 1;\n          ComparisonLetters = 0;\n          OriginalLetters++;\n          \n                  \n    }\n    \n    if(Cantidad % 2 == 0 )\n    {\n         printf(\"CHAT WITH HER!\");\n    }\n    else\n         printf(\"IGNORE HIM!\");\n    \n    \n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "434d6ecc41d07089a7e6adcf6a691827", "src_uid": "a8c14667b94b40da087501fd4bdd7818", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\nint a,b,c,p[4],temp,i,j;\nscanf(\"%d%d%d\",&a,&b,&c);\np[0]=a+b*c;\np[1]=c*(b+c);\np[2]=a*b*c;\np[3]=(a+b)*c;\n for(j=0;j<3;j++) {\nfor(i=0;i<4-j;i++)\n{\nif(p[i]>=p[i+1])\n{temp=p[i];\np[i]=p[i+1];\np[i+1]=temp;}\n\n}}\np[1]=0;\n\nprintf(\"%d\",p[3]);}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e0408cacae6e47bff965266972d6814a", "src_uid": "1cad9e4797ca2d80a12276b5a790ef27", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int k,l,m,n,o,p,a,b,c;\n    scanf(\"%d%d%d\",a,b,c);\n    k=a*b*c;\n    l=a+b+c;\n    m=(a*b)+c;\n    n=a+(b*c);\n    o=(a+b)*c;\n    p=a*(b+c);\n    if(k>=l&&k>=m&&k>=n&&k>=o&&k>=p){\n        printf(\"%d\",k);\n    }\n    else if(l>=k&&l>=m&&k>=n&&l>=o&&l>=p){\n        printf(\"%d\",l);\n    }\n    else if(m>=k&&m>=l&&m>=n&&m>=o&&m>=p){\n        printf(\"%d\",m);\n    }\n    else if(n>=k&&n>=l&&n>=m&&n>=o&&n>=p){\n        printf(\"%d\",n);\n    }\n    else if(o>=k&&o>=l&&o>=m&&o>=n&&o>=p){\n        printf(\"%d\",o);\n    }\n    else{\n        printf(\"%d\",p);\n    }\n    return 0;\n        \n    \n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "68b6bd5a527c04c5a80c35f4e38a39ff", "src_uid": "1cad9e4797ca2d80a12276b5a790ef27", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main()\n{\n    int a=2,b=9,c=3,max;\n    int result[6],j;\n    result[0]=a+b+c;\n    result[1]=a*b*c;\n    result[2]=a+b*c;\n    result[3]=(a+b)*c;\n    result[4]=a*b+c;\n    result[5]=a*(b+c);\n    max=result[0];\n    for(j=0;j<5;j++)\n    {\n        if(result[j]>max)\n        {\n            max=result[j];\n        }\n    }\n    printf(\"%d\",max);\n    system(\"pause\");\n    return 0;\n}\n\n                                                             ", "lang_cluster": "C", "compilation_error": false, "code_uid": "f606b863332e6d126c9ace5c433ead09", "src_uid": "1cad9e4797ca2d80a12276b5a790ef27", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main()\n{\n    int a=2,b=6,c=8,max;\n    int result[6],j;\n    result[0]=a+b+c;\n    result[1]=a*b*c;\n    result[2]=a+b*c;\n    result[3]=(a+b)*c;\n    result[4]=a*b+c;\n    result[5]=a*(b+c);\n    max=result[0];\n    for(j=0;j<5;j++)\n    {\n        if(result[j]>max)\n        {\n            max=result[j];\n        }\n    }\n    printf(\"%d\",max);\n    system(\"pause\");\n    return 0;\n}\n\n   ", "lang_cluster": "C", "compilation_error": false, "code_uid": "a2b070c8afbc6709f1c733467d96637c", "src_uid": "1cad9e4797ca2d80a12276b5a790ef27", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int k,l,m,n,o,p,a,b,c;\n    scanf(\"%d%d%d\",a,b,c);\n    k=a*b*c;\n    l=a+b+c;\n    m=(a*b)+c;\n    n=a+(b*c);\n    o=(a+b)*c;\n    p=a=(b+c);\n    if(k>=l&&k>=m&&k>=n&&k>=o&&k>=p){\n        printf(\"%d\",k);\n    }\n    else if(l>=k&&l>=m&&k>=n&&l>=o&&l>=p){\n        printf(\"%d\",l);\n    }\n    else if(m>=k&&m>=l&&m>=n&&m>=o&&m>=p){\n        printf(\"%d\",m);\n    }\n    else if(n>=k&&n>=l&&n>=m&&n>=o&&n>=p){\n        printf(\"%d\",n);\n    }\n    else if(o>=k&&o>=l&&o>=m&&o>=n&&o>=p){\n        printf(\"%d\",o);\n    }\n    else{\n        printf(\"%d\",p);\n    }\n    return 0;\n        \n    \n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e4cefc9901ceac993b755a297553573f", "src_uid": "1cad9e4797ca2d80a12276b5a790ef27", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,k,i,a[200],count=0;\n    scanf(\"%d %d\",&n,&k);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    for(i=0;i<n;i++)\n    {\n       while(a[i]>a[k]&&a[i]>0)\n       {\n        count++;\n       }\n    }\n    printf(\"%d\",count);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a85aed66789a31ad41a0c232a0be4080", "src_uid": "193ec1226ffe07522caf63e84a7d007f", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int a[100],k,n,count,t,i;\n         scanf(\"%d%d\",&n,&k);\n                 for(i=0;i<n;i++)\n                    scanf(\"%d\",&a[i]);\n                    \n                      if(a[k]!=0){ \n                         while(k<n)\n                           {      \n                                if(a[k]==a[k+1])\n                                     k++;\n                                        \n                           }\n                           printf(\"%d\",k+1);\n                      }\n                      else\n                          printf(\"0\");\n                          return 0;\n                           \n                            \n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "99c4aa09e11d75ec88bfec40871bb7f3", "src_uid": "193ec1226ffe07522caf63e84a7d007f", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n  int i,n,count=0,k,a[200];\n  scanf(\"%d %d\",&n,&k);\n  for(i=0;i<n;i++)\n  {\n   scanf(\"%d\",&a[i]);\n  }\n  for(i=0;i<n;i++)\n  {\n    while(a[i]>=a[k])\n    {\n     if(a[i]>0)\n     {\n      count++;\n      }\n    }\n  }\n  printf(\"%d\",count);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "54906885e3d853726680c9b8f55c937b", "src_uid": "193ec1226ffe07522caf63e84a7d007f", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n         int x,k,i,c=0;\n         scanf(\"%d %d\",&x,&k);\n         int n[x];\n         for(i=0;i<n;i++)\n                scanf(\"%d\",&n[i]);\n\n         k=k-1;\n         for(i=0;i<n;i++){\n                if(n[i]>=n[k]) c++;\n         }\n         printf(\"%d\\n\",c);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9c842caaa4c74dcea837b4d88bf2c966", "src_uid": "193ec1226ffe07522caf63e84a7d007f", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint check(int val,int x)\n{\n    if (val>=x){return (1);}\n    else{return (0);}\n}\nint search(int t[],int n,int k)\n{\n    int lft=k,rgt=n,m,pos=0;\n    int check(int,int);\n    while(lft<=rgt)\n    {\n        m=(lft+rgt)/2;\n        if (check(t[m],t[k-1]))\n        {\n            lft=m+1;\n            pos=m;\n        }\n        else\n            {\n                rgt=m-1;\n            }\n    }\n    return(pos);\n}\nvoid par(int *a, int *b)\n{\n    int check(int,int);\n    int ver=1;\n    do\n    {\n        scanf(\"%d %d\",a,b);\n        if(check(*b,1)&&check(50,*a)&&check(*a,*b)) {ver=0;}\n    }while(ver);\n}\nvoid rem(int t[],int b)\n{\n    int i=0,ver;\n    int check(int,int);\n    do\n        {\n            ver=0;\n            for(i=0;i<b;i++){\n            scanf(\"%d\",t+i);\n            if(!check(100,t[i])||!check(t[i],0)) {ver=1;}\n            }\n        }while(ver);\n}\nint main()\n{   int *tab;\n    int n,k,p;\n    void par(int *, int *);\n    tab=malloc(sizeof(int)*n);\n    void rem(int t[],int );\n    par(&n,&k);\n    rem(tab,n);\n    if(tab[k-1]==0)\n    {\n       if(tab[0]==0){printf(\"%d\",0);}\n       else\n            {\n                p=1;\n            p=search(tab,k-1,1);\n            printf(\"%d\",p);\n            }\n    }\n    else\n    {\n        printf(\"%d\",search(tab,n,k)+1);\n    }\n    return(0);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7c3400e55e0c508066cd581977735845", "src_uid": "193ec1226ffe07522caf63e84a7d007f", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    float l, d, v, g, r  ,t , m ;\n    int i ;\n    scanf(\"%f%f%f%f%f\",&l,&d,&v,&g,&r);\n\n    t = (l-d)/v ;\n\n    if(d/v <= g)\n    {\n        t += d/v ;\n        printf(\"%f\",t);\n        return 0 ;\n    }\n\n    while(d >= 0)\n    {\n        m = v*g ;\n        t += m/v ;\n        d -= m ;\n        if(d<=0)\n        {\n            printf(\"%f\",t);\n            return 0 ;\n        }\n        else\n        {\n            m = v*r ;\n            t += m/v ;\n            d -= m ;\n        }\n        if(d<=0)\n        {\n            printf(\"%f\",t);\n            return 0 ;\n        }\n\n\n    }\n\n\n\n\n    return 0 ;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "94d64b5256302263c66609b251a12499", "src_uid": "e4a4affb439365c843c9f9828d81b42c", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n  {\n  \tfloat ans;\n  \tint l, d, v, g, r, i;\n  \tscanf(\"%d %d %d %d %d\", &l, &d, &v, &g, &r);\n  \ti = d/v;\n  \tif(i*v != d)\n  \t  i++;\n  \tif(i % (g+r) <= g && i % (g+r) != 0) \n  \t  {\n  \t  \tans = (float) l/v;\n\t  }\n\telse \n\t  {\n\t  \tans = ( (float) (l-d)/v) + (d/v/(g+r)+1) * (g+r);\n\t  }\n\tprintf(\"%f\", ans);\n\tgetchar();\n\tgetchar();\n\treturn 0;\n  } \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7ec26f0d1c284e7c6342f743f93fcafa", "src_uid": "e4a4affb439365c843c9f9828d81b42c", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define epslion .000001 \nint main() {\nint  d,l,v,g,r,time;\nfloat duration,durtol,resttol,oddtime,inc=0.0;\nscanf(\"%d %d %d %d %d\",&d,&l,&v,&g,&r);\n if(l>d){\n  duration = (float)d/v;\n  printf(\"%f\",duration);\n }\n else {\n   durtol = (float)l/v;\n   time = durtol/(g+r);\n   oddtime = durtol - time*(g+r);\n   //printf(\"%f \",oddtime);\n   if(oddtime > g) {\n     inc =  (r+g - oddtime );\n   }\n   resttol = (float)(d-l)/v;\n   printf(\"%f\",resttol + inc + durtol);\n          \n }\n \n return 0;\n \n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bcd2218e2c7f5bcb364a24f8ca9366c7", "src_uid": "e4a4affb439365c843c9f9828d81b42c", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n\n{\n    int l,d,v,g,r;\n    \n    scanf(\"%d%d%d%d%d\",&l,&d,&v,&g,&r);\n    \n    if((d/v)<=g)\n    {\n        printf(\"%d\",(l/v));\n    }\n\n    else\n    {\n        printf(\"%d\",(g + r + ((l-d)/v)));\n    }\nreturn 0;    \n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c711fb27a0705e30c440523d96542828", "src_uid": "e4a4affb439365c843c9f9828d81b42c", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\ndouble tra();\ndouble l,d,v,g,r,t;\nvoid main()\n{\n\tscanf(\"%lf%lf%lf%lf%lf\",&l,&d,&v,&g,&r);\n\tt=l/v+tra(d/v,g,r);\n\tprintf(\"%.8lf\",t);\n}\ndouble tra()\n{\n\tdouble sum=0;\n\tfor (int i=0;;i++)\n\t{\n\t\t\tif (i%2==0){sum+=g;}\n\t        else { sum+=r;}\n\t    \t\tif (sum>=d/v)\n\t    \t\t{\n\t\t\tif (i%2==0){return 0;}\n\t\t\telse {return sum-d/v;}\n\t\t      }\n\t }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b6b637ec7e67881f7f4bbad12176ab14", "src_uid": "e4a4affb439365c843c9f9828d81b42c", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main ()\n{\n\n\n    int l,a,p,mk,min,tmp;\n    int lm,ap,per;\n    while(scanf(\"%d %d %d\",&l,&a,&p))\n    {\n\n\n        lm=l;\n        ap=a/2;\n        per=p/4;\n        if(lm<ap)\n        {\n            min=lm;\n\n\n        }\n        else\n            min=ap;\n        if(min>per)\n            mk=per;\n        else\n            mk=min;\n\n        printf(\"%d\\n\",7*mk);\n    }\n    return 0;\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "237da4b19644fb43070919f32a62bd2a", "src_uid": "82a4a60eac90765fb62f2a77d2305c01", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int a,b,c,ans=0;\n    scanf(\"%d %d %d\",&a,&b,&c);\n    while(1)\n    {\n         if(((a*2)<=b)&&((a*4)<=c))\n        {\n            ans=7*a;\n            break;\n        }\n\n    }\n\n    printf(\"%d\\n\",ans);\n    return 0;\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e6d5c596faa25e3f0b32bd2b38494c9a", "src_uid": "82a4a60eac90765fb62f2a77d2305c01", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int i,j,a,b,c,a1=0,b1=0,c1=0;\n    scanf(\"%d\",&a);\n    scanf(\"%d\",&b);\n    scanf(\"%d\",&c);\n    for(i=1;;i++){\n        if((a1<a)&&(b1<b)&&(c1<c)){\n            a1=1*i;\n            b1=2*i;\n            c1=4*i;\n            if((a1>a)||(b1>b)||(c1>c)){\n               break;\n            }\n        }\n    }\n    printf(\"%d\",(a1-1)+(b1-2)+(c1-4));\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "808ee2d553e5fd7001ce4510cd9b5c5c", "src_uid": "82a4a60eac90765fb62f2a77d2305c01", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\nint main()\n{\n\tint l,a,p,count=0;\n\tscanf(\"%d\",&l);\nscanf(\"%d\",&a);\nscanf(\"%d\",&p);\n\tif((a<(2) && p<(4)) || l<1)\n\tprintf(\"0\\n\");\n\telse {\n\t{\n\t\tint m=p/4;\n\t\tif(a>=m*2)\n\t\tcount=7*m;\n\t}\n\tprintf(\"%d\\n\",count);\n}\n\tgetch();\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e6ef9a0f99c6ef28dcd160cfc6c3877b", "src_uid": "82a4a60eac90765fb62f2a77d2305c01", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(void){\n    int a,b,c;\n    scanf(\"%d%d%d\",&a,&b,&c);\n    int d = a;\n\n    if(b/2 < d)\n        d = b/2;\n\n    if(c/4 < c)\n        d = c/4;\n\n    printf(\"%d\\n\",d+2*d+4*d);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4630ec7ecd0ef74fd573fbf399d00b2c", "src_uid": "82a4a60eac90765fb62f2a77d2305c01", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint i,n,k,a[1000],dif,max=-1e9;\nscanf(\"%d%d\",&n,&k);\nfor(i=0;i<n;i++)\nscanf(\"%d\",&a[i]);\nfor(i=0;i<n-1;i++)\n{\ndif=a[i]-a[i+1];\n//printf(\"%d\\n\",dif);\nif(dif>max&&dif>0)\nmax=dif;\n}\nif(max<0)\nprintf(\"0\\n\");\nelse\nprintf(\"%d\\n\",max-k);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b16e4aaff0c413fddaf1734131456fbf", "src_uid": "411539a86f2e94eb6386bb65c9eb9557", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<math.h>\nint a[108];\nint main()\n{\n    int n,c,i,ma;\n\n    scanf(\"%d%d\",&n,&c);\n        for(i=0;i<n;i++) scanf(\"%d\",a+i);\n        ma=0;\n        for(i=1;i<n;i++)\n        {\n            if(a[i-1]-a[i]>ma) ma=a[i-1]-a[i];\n        }\n        printf(\"%d\\n\",ma-c);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2ed9921311f4804c3716694da0539181", "src_uid": "411539a86f2e94eb6386bb65c9eb9557", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void) {\n    int n, c, x[101], i, max_i, max, ans;\n    \n    scanf(\"%d %d\",&n,&c);\n    \n    for(i=0; i<n; i++)\n        scanf(\"%d\",&x[i]);\n        \n    max_i=0;\n    max=0;\n    for(i=1; i<n; i++)\n    {\n        if(max<(x[i-1]-x[i])) \n        {\n            max=x[i-1]-x[i];\n            max_i=i;\n        }\n    }\n    \n    if(max==0) \n        ans=0;\n    else\n        ans=x[max_i-1]-x[max_i]-c;\n    \n    printf(\"%d\\n\",ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "81249a8ffc0e3e84a5ec97a876fe43dc", "src_uid": "411539a86f2e94eb6386bb65c9eb9557", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,c,i,a[110],p,x;\n    scanf(\"%d %d\", &n,&c);\n    for(i=1; i<=n; i++)\n    {\n        scanf(\"%d\", &a[i]);\n    }\n    x=0;\n    for(i=1; i<n; i++)\n    {\n        p=a[i]-a[i+1];\n        if(p>x)\n            x=p;\n    }\n    printf(\"%d\",x-c);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "05f465ee40214cbc5298887dd13a9c9e", "src_uid": "411539a86f2e94eb6386bb65c9eb9557", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n {\n \tint day,pay;\n \tscanf(\"%d %d\",&day,&pay);\n \t\n \tint Data[day],a;\n \tfor(a = 0 ; a < day; a++)\n \t{\n \t\tscanf(\"%d\",&Data[a]); \t\t\n \t}\n \t\n \tint dayTake = 0,idx;\n \tfor(a = 0 ; a < day-1; a++)\n \t{\n \t  if(Data[a]- Data[a+1] > dayTake)\n\t    {\n\t    \tdayTake = Data[a] - Data[a+1];\n\t    \tidx = a;\n\t    }\t\n \t}\n \t\n \t// Debug\n \t//printf(\"%d\\n\",dayTake);\n \t\n \tif(dayTake == 0)\n \t{\n \t\tprintf(\"%d\\n\",dayTake);\n \t}\n \t\n \telse\n \t{\n \t\tprintf(\"%d\\n\",((Data[idx] - Data[idx+1]) - pay));\n \t}\n \t\n \treturn 0;\n }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f6eb0d53b73b6a89b2acccc2e454d305", "src_uid": "411539a86f2e94eb6386bb65c9eb9557", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,k,a[100],s=0,count=0,i;\n    printf(\"\\nEnter n and k\");\n    scanf(\"%d %d\",&n,&k);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n\n\n        if(a[i]>8)\n            s=s+8;\n        else\n            s=s+a[i];\n            while(s<=k)\n                count++;\n\n    }\n    if(s==k)\n        printf(\"\\n%d\",count);\n    else\n        printf(\"\\n-1\");\n        return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1468f95ef31b266f41272932e89a3eae", "src_uid": "24695b6a2aa573e90f0fe661b0c0bd3a", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main ()\n{\n\tint c[5];\n\tint j;\n\t\n\tfor (j=0;j<10;j++)    c[j]=j;\n\t\n\tfor (j=0;j<10;j++)    printf(\"%d\",c[j]);\n\t\n\treturn 0;\n\t\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "544ff5b6e4568a22baaf89fb64c52362", "src_uid": "24695b6a2aa573e90f0fe661b0c0bd3a", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nvoid main()\n{\nint n,k,a[100],i,sum=0;\nscanf(\"%d %d\",&n,&k);\nfor(i=0;i<n;i++)\n{\n    scanf(\"%d\",&a[i]);\n}\nfor(i=1;i<=n;i++)\n{\n    sum=sum+8;\n    if(sum>=k)\n    {\n        printf(\"%d\",i);\n        break;\n    }\n}\nif(sum<k)\n{\n    printf(\"-1\");\n}\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bf9ed8df3dc79b5fab043fba7ea45511", "src_uid": "24695b6a2aa573e90f0fe661b0c0bd3a", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nvoid main()\n{\n    int n,i,count=0,s=0,r=0;\n    long int k;\n    scanf(\"%d%d\",&n,&k);\n    int a[n];\n    for (i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        r+=a[i];\n    }\n    for (i=0;i<n;i++)\n    {\n        if(a[i]>=8)\n            {\n                if(i+1<n)\n                    a[i+1]+=a[i]-8;\n            s+=8;\n            if(s<k)\n            count+=1;\n            else\n            {count+=1;\n            break;}\n            }\n        else\n            {\n                s+=a[i];\n                a[i]=0;\n                if(s<k)\n                count+=1;\n                else\n                {\n                    count+=1;\n                    break;\n                }\n            }\n    }\n    if(count<=n&&s>=k)\n    {\n        printf(\"%d\",count);\n    }\n    else\n        printf(\"-1\");\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fe98e292b456f5eb577a15d4c8986c54", "src_uid": "24695b6a2aa573e90f0fe661b0c0bd3a", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nvoid main()\n{\n    int n,i,count=0,s=0,r=0;\n    long int k;\n    scanf(\"%d%d\",&n,&k);\n    int a[n];\n    for (i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        r+=a[i];\n    }\n    for (i=0;i<n;i++)\n    {\n        if(a[i]>=8)\n            {\n                if(i+1<n)\n                    a[i+1]+=a[i]-8;\n            s+=8;\n            if(s<k)\n            count+=1;\n            else\n            {count+=1;\n            break;}\n            }\n        else\n            {\n                s+=a[i];\n                a[i]=0;\n                if(s<k)\n                count+=1;\n                else\n                {\n                    count+=1;\n                    break;\n                }\n            }\n    }\n    if(count<=n&&s>=k)\n    {\n        printf(\"%d\",count);\n    }\n    else\n        printf(\"-1\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "aa597bc9472916061aa2339e7294c5a8", "src_uid": "24695b6a2aa573e90f0fe661b0c0bd3a", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "/* Teng K. J. */\n#include <stdio.h>\n#define N 20000\nvoid ignore(int n) {\n    while (n-- > 0) getchar();\n}\nint main() {\n    int n, cur = 0, dist;\n    char dir;\n    scanf(\"%d\", &n);\n    while (n-- > 0) {\n        scanf(\"%d %c\", &dist, &dir);\n        switch (dir) {\n        case 'N':\n            ignore(5);\n            if (cur == 0) goto no;\n            cur -= (dist + N) % (2 * N) - N;\n            if (cur < 0) cur = -cur;\n            if (cur > N) cur = 2 * N - cur;\n            break;\n        case 'S':\n            ignore(5);\n            cur += (dist + N) % (2 * N) - N;\n            if (cur < 0) cur = -cur;\n            if (cur > N) cur = 2 * N - cur;\n            break;\n        case 'E': case 'W':\n            ignore(4);\n            if (cur == 0 || cur == N) goto no;\n            break;\n        }\n    }\n    if (cur != 0) goto no;\n    puts(\"YES\");\n    return 0;\nno:\n    puts(\"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "63a2e54ad0ea078923531ab9723019c7", "src_uid": "11ac96a9daa97ae1900f123be921e517", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "//Created by Pratik Mandlecha\n\n#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#include<math.h>\nint main()\n{\n\tint n,d,p=0,q=0,flag=0;\n\tchar s[20];\n\tscanf(\"%d\",&n);\n\twhile(n--)\n\t{\n\t\tscanf(\"%d%s\",&d,s);\n\t\tif(s[0]=='N') \n\t\t{\n\t\t\tif((p%40000)!=0)\n\t\t\tp+=(d%40000);\n\t\t\telse flag=1;\n\t\t}\n\t\tif(s[0]=='S')\n\t\t{\n\t\t\tif(abs((p%40000))!=20000)\n\t\t\tp-=(d%40000);\n\t\t\telse flag=1;\n\t\t}\n\t\tif(((s[0]=='E')||(s[0]=='W'))&&((p%20000)==0)) flag=1;\n\t\tif(s[0]=='W') q-=(d%40000);\n\n\t}\n\tp=(p %(40000));\n\tif((p==0)&&(flag==0)) printf(\"YES\");\n\telse printf(\"NO\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2a35a67608ee9337a718f924bf7676ab", "src_uid": "11ac96a9daa97ae1900f123be921e517", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n\tint n,i;\n\tscanf(\"%d\", &n);\n\tint xcor=0,ycor=0;\n\tint flag=0;\n\tchar string[n][10];\n\tfor(i=0;i<n;i++)\n\t{\n\t\tint x;\n\t\t\n\t\tscanf(\"%d \", &x);\n\t\tscanf(\"%s\", string[i]);\n\t\t\n\t\tif(xcor==0 && ycor==0)\n\t\t{\n\t\t\tif(string[i][0]!='S')\n\t\t\t\t{\n\t\t\t\t\tflag=1;\n\t\t}\n\n\t\t}\n\t\tif(ycor>0 || ycor<-20000)\n\t\t{\n\t\t\tflag=1;\n\t\t}\n\t\tif(ycor==-20000 && xcor==0)\n\t\t{\n\t\t\tif(string[i][0]!='N')\n\t\t\t\t{\n\t\t\t\t\tflag=1;\n\t\t}\n\t\t}\n\t\tif(string[i][0]=='N')\n\t\t{\n\t\t\tycor+=x;\n\t\t}\n\t\telse if(string[i][0]=='S')\n\t\t{\n\t\t\tycor-=x;\n\t\t}\n\t\telse if(string[i][0]=='E')\n\t\t{\n\t\t\txcor+=x;\n\t\t}\n\t\telse if(string[i][0]=='W')\n\t\t{\n\t\t\txcor-=x;\n\t\t}\n\t\t\n\n\t\t//printf(\"%d %d\\n\",xcor,ycor);\n\t}\n\tif(ycor>0 || ycor<-20000)\n\t\t{\n\t\t\tprintf(\"NO\");\n\t\t\treturn 0;\n\t\t}\n\t\tif(flag==1)\n\t\t{\n\t\t\tprintf(\"NO\");\n\t\t\treturn 0;\n\t\t}\n\tif(ycor==0 && flag!=1)\n\t\tprintf(\"YES\");\n\telse\n\t\tprintf(\"NO\");\n\treturn 0;\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3bd1443ac94ce1b129d622240b8bc55e", "src_uid": "11ac96a9daa97ae1900f123be921e517", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main()\n{\n    int n;\n    scanf(\"%d\", &n);\n    int distance = 20000;  // distance to South pole\n    while (n--) {\n        char dir[6];\n        int t;\n        scanf(\"%d %s\", &t, dir);\n        if (distance == 20000 && strcmp(dir, \"South\") != 0) {\n            printf(\"NO\\n\");\n            return 0;\n        }\n        if (distance == 0 && strcmp(dir, \"North\") != 0) {\n            printf(\"NO\\n\");\n            return 0;\n        }\n\n        if (strcmp(dir, \"South\") == 0) {\n            distance -= t % 40000;\n\n        } else if (strcmp(dir, \"North\") == 0) {\n            distance += t % 40000;\n        }\n    }\n\n    if (distance == 20000) {\n        printf(\"YES\\n\");\n    } else {\n        printf(\"NO\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7e9ff0196405f54c3811c2d4274339e9", "src_uid": "11ac96a9daa97ae1900f123be921e517", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n;\n\tint number;\n\tchar ch[100];\n\tint sum=0;\n\tscanf(\"%d\",&n);\n\tfor(int i=0;i<=n-1;i++)\n\t{\n\t\tscanf(\"%d\",&number);\n\t\tscanf(\"%s\",ch);\n\t\tif(sum==20000)\n\t    {\n\t    \tif(ch[0]!='N')\n\t    \tsum=-100000;\n\t\t}\n\t\tif(i=0&&sum==0)\n\t\t{\n\t\t\tif(ch[0]!='S')\n\t    \tsum=-100000;\n\t\t} \n\t\tif(ch[0]=='N')\n\t\t\tsum=sum-number;\n\t\telse if(ch[0]=='S')\n\t\t\tsum=sum+number;\n\t\tif(sum>20000||sum<0)\n\t\t   sum=-100000;\n\t}\n\t if(sum==0)\n\t printf(\"YES\");\n\t else\n\t printf(\"N0\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d0be8054fd53a61dc46ed4f3291bab5b", "src_uid": "11ac96a9daa97ae1900f123be921e517", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nlong p[100003] = {0};\nlong q[100003] = {0};\nlong i,j,k;\n\nint main()\n{\n    char a[103],b[103];\n    scanf(\"%s %s\",a,b);\n    long get = 0;\n    for(i = 0 ; i < strlen(a) ; i++)\n    {\n        int counter = 0;\n        if(a[i] == b[0] && a[i+1] == b[1])\n        {\n            for(j = 0,k = i ; j < strlen(b) ; j++, k++)\n            {\n                if(a[k] != b[j])\n                {\n                    counter = 1;\n                    break;\n                }\n            }\n            if(counter == 0)\n            {\n                get = 1;\n                printf(\"automaton\");\n                break;\n            }\n        }\n    }\n    if(get == 0)\n    {\n        for(i = 0 ; i < strlen(a) ; i++)\n        {\n            p[a[i]-97]++;\n            q[b[i]-97]++;\n        }\n        if(strlen(a) == strlen(b))\n        {\n            long counter = 0;\n            for(i = 0 ; i < strlen(a) ; i++)\n            {\n                if(p[i] != q[i])\n                {\n                    counter = 1;\n                    break;\n                }\n            }\n            if(counter == 0)\n            {\n                printf(\"array\");\n            }\n            else\n            {\n                printf(\"need tree\");\n            }\n        }\n        else\n        {\n            long counter = 0;\n            for(i = 0 ; i < strlen(b) ; i++)\n            {\n                if(p[b[i]-97] < q[b[i]-97])\n                {\n                    counter = 1;\n                    break;\n                }\n            }\n            if(counter == 0)\n            {\n                printf(\"both\");\n            }\n            else\n            {\n                printf(\"need tree\");\n            }\n        }\n    }\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3d9cadc8622a26a7ed31e609fd73d007", "src_uid": "edb9d51e009a59a340d7d589bb335c14", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nlong p[100003] = {0};\nlong q[100003] = {0};\nlong i,j,k;\n\nint main()\n{\n    char a[103] = {'@'},b[103] = {'@'};\n    scanf(\"%s %s\",a,b);\n    long get = 0;\n    for(i = 0 ; i < strlen(a) ; i++)\n    {\n        int counter = 0;\n        if(a[i] == b[0] && a[i+1] == b[1])\n        {\n            for(j = 0,k = i ; j < strlen(b) ; j++, k++)\n            {\n                if(a[k] != b[j])\n                {\n                    counter = 1;\n                    break;\n                }\n            }\n            if(counter == 0)\n            {\n                get = 1;\n                printf(\"automaton\");\n                break;\n            }\n        }\n    }\n    if(get == 0)\n    {\n        for(i = 0 ; i < strlen(a) ; i++)\n        {\n            p[a[i]-97]++;\n            q[b[i]-97]++;\n        }\n        if(strlen(a) == strlen(b))\n        {\n            long counter = 0;\n            for(i = 0 ; i < strlen(a) ; i++)\n            {\n                if(p[i] != q[i])\n                {\n                    counter = 1;\n                    break;\n                }\n            }\n            if(counter == 0)\n            {\n                printf(\"array\");\n            }\n            else\n            {\n                printf(\"need tree\");\n            }\n        }\n        else\n        {\n            long counter = 0;\n            for(i = 0 ; i < strlen(b) ; i++)\n            {\n                if(p[b[i]-97] < q[b[i]-97])\n                {\n                    counter = 1;\n                    break;\n                }\n            }\n            if(counter == 0)\n            {\n                printf(\"both\");\n            }\n            else\n            {\n                printf(\"need tree\");\n            }\n        }\n    }\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9bd6e190fce00ec1f379c633e01b4a02", "src_uid": "edb9d51e009a59a340d7d589bb335c14", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nchar s[105];\nchar t[105];\nint arr[135];\nint count[135];\nint main()\n{\n\n    int lens,lent,i,j;\n    scanf(\"%s\",s);\n    scanf(\"%s\",t);\n    lens=strlen(s);\n    lent=strlen(t);\n    if(lens<lent)\n        {printf(\"need tree\");\n          return 0;\n        }\n    if(lens>lent)\n    {\n        i=0;\n        j=0;\n        while(i<lens && j<lent)\n            {\n                if(s[i]==t[j])\n                {\n                    i++;\n                    j++;\n                }\n                else\n                    i++;\n            }\n          if(j==lent)\n          {\n              printf(\"automaton\");\n              return 0;\n          }\n    }\n    for(i=0;i<lens;i++)\n     {\n         arr[s[i]]++;\n     }\n    for(i=0;i<lent;i++)\n    {\n        if(arr[t[i]]!=0)\n            arr[t[i]]--;\n        else\n            {\n                printf(\"need tree\");\n                return 0;\n            }\n    }\n   if(i==lent && lens==lent)\n        printf(\"array\");\n   else if(i==lent && lens>lent)\n     printf(\"both\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2bd6090eaf4a28c5845e9de56b0cd67a", "src_uid": "edb9d51e009a59a340d7d589bb335c14", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nchar S[200], T[200];\nint DP[200][200];\nint X[1000], Y[1000];\nint M, N;\n\nint main()\n{\n\t//FILE *input, *output;\n\t//input = fopen(\"suffix.in\", \"r\");\n\tint i, j, k, b, d;\n\tchar c;\n\t\n\tfor(M=0; ; M++)\n\t{\n\t\t//fscanf(input, \"%c\", &c);\n\t\tscanf(\"%c\", &c);\n\t\tif(c == '\\n')\n\t\t\tbreak;\n\t\tS[M] = c;\n\t\tX[(char) c]++;\n\t}\n\tfor(N=0; ; N++)\n\t{\n\t\t//fscanf(input, \"%c\", &c);\n\t\tscanf(\"%c\", &c);\n\t\tif(c == '\\n')\n\t\t\tbreak;\n\t\tT[N] = c;\n\t\tY[(char) c]++;\n\t}\n\t\n\tif(M < N)\n\t{\n\t\tprintf(\"need tree\\n\");\n\t\treturn 0;\n\t}\n\t\n\tif(M == N)\n\t{\n\t\tfor(i=0, b=0; i<1000; i++)\n\t\t{\n\t\t\tif(X[i] != Y[i])\n\t\t\t\tb = 1;\n\t\t}\n\t\t\n\t\tif(b == 0)\n\t\t\tprintf(\"array\\n\");\n\t\telse\n\t\t\tprintf(\"need tree\\n\");\n\t\treturn 1;\n\t}\n\t\n\tfor(i=0; i<N && i<M; i++)\n\t{\n\t\tfor(j=0; j<N || j<M; j++)\n\t\t{\n\t\t\tif(T[i] != S[j])\n\t\t\t\tcontinue;\n\t\t\tif(i == 0)\n\t\t\t{\n\t\t\t\tDP[i][j] = 1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tfor(k=0; k<j; k++)\n\t\t\t{\n\t\t\t\tif(DP[i-1][k] == 1)\n\t\t\t\t\tDP[i][j] = 1;\n\t\t\t}\n\t\t}\n\t}\n\t\n\tif((N < M && DP[N-1][M-1] == 1))\n\t{\n\t\tprintf(\"automaton\\n\");\n\t\treturn 1;\n\t}\n\t\n\tfor(i=0, d=0; i<1000; i++)\n\t{\n\t\tif(X[i] < Y[i])\n\t\t\td = 1;\n\t}\n\t\t\n\tif(d == 0)\n\t\tprintf(\"both\\n\");\n\telse\n\t\tprintf(\"need tree\\n\");\n\treturn 1;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e4c931d6bd861902fca6e8c31df260a4", "src_uid": "edb9d51e009a59a340d7d589bb335c14", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nchar s[105];\nchar t[105];\nint arr[135];\nint count[135];\nint main()\n{\n\n    int lens,lent,i,j;\n    scanf(\"%s\",s);\n    scanf(\"%s\",t);\n    lens=strlen(s);\n    lent=strlen(t);\n    if(lens<lent)\n        {printf(\"need tree\");\n          return 0;\n        }\n    if(lens>lent)\n    {\n        i=0;\n        j=0;\n        while(i<lens && j<lent)\n            {\n                if(s[i]==t[j])\n                {\n                    i++;\n                    j++;\n                }\n                else\n                    i++;\n            }\n          if(j==lent)\n          {\n              printf(\"automaton\");\n              return 0;\n          }\n    }\n    for(i=0;i<lens;i++)\n     {\n         int k=s[i];\n         arr[k]++;\n     }\n    for(i=0;i<lent;i++)\n    {\n         int q=t[i];\n        if(arr[q]!=0)\n            arr[q]--;\n        else\n            {\n                printf(\"need tree\");\n                return 0;\n            }\n    }\n   if(i==lent && lens==lent)\n        printf(\"array\");\n   else if(i==lent && lens>lent)\n     printf(\"both\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "41a655bbd3bfa2fc7f3eee142bba7865", "src_uid": "edb9d51e009a59a340d7d589bb335c14", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\nint main(int argc, char *argv[]) {\n\tchar a[6], b[6];\n\tint i, h1, m1, h2, m2, t, h, m;\n\twhile (scanf(\"%s%s\",a,b)) {\n\t      h1 = ((int)a[0]-48)*10 + ((int)a[1]-48);\n\t\t  h2 = ((int)b[0]-48)*10 + ((int)b[1]-48);\n\t\t  m1 = ((int)a[3]-48)*10 + ((int)a[4]-48);\n\t\t  m2 = ((int)b[3]-48)*10 + ((int)b[4]-48);\n\t      t = ((h1*60+m1)+(h2*60+m2))/2;\n          h = t/60;\n          m = t%60;\n\t\t  printf(\"%02d:%02d\\n\",h,m);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9754c5461403006fd4a0ab5e664fe907", "src_uid": "f7a32a8325ce97c4c50ce3a5c282ec50", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\n#define scan(a) scanf(\"%d\",&a)\n\n\n/// >........cpp code\n\n\nint main()\n{\n\n\n\n\n  int h1,m1,h2,m2;\n\n  fuad :\n\n    scanf(\"%d %d\",&h1,&m1);\n    scanf(\"%d %d\",&h2,&m2);\n\n    int res1=h1*60+m1;\n    int res2=h2*60+m2;\n\n    int main_res=res2-res1;\n    main_res/=2;\n\n    int m_h=h1+main_res/60;\n\n   if(m_h<10)\n    printf(\"0%d:\",m_h);\n    else\n\n    printf(\"%d:\",m_h);\n\n    m1=m1+main_res%60;\n    if(m1<10)\n    printf(\"0%d\\n\",m1);\n    else\n    printf(\"%d\\n\",m1);\n\n\n\n    goto fuad;\n\n\n  ///\n\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6f9d03e58435353d4e07e2d571e23eb1", "src_uid": "f7a32a8325ce97c4c50ce3a5c282ec50", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\nint main(int argc, char *argv[]) {\n\tchar a[6], b[6];\n\tint i, h1, m1, h2, m2, t, h, m;\n\twhile (scanf(\"%s%s\",a,b)) {\n\t      h1 = ((int)a[0]-48)*10 + ((int)a[1]-48);\n\t\t  h2 = ((int)b[0]-48)*10 + ((int)b[1]-48);\n\t\t  m1 = ((int)a[3]-48)*10 + ((int)a[4]-48);\n\t\t  m2 = ((int)b[3]-48)*10 + ((int)b[4]-48);\n\t      t = ((h1*60+m1)+(h2*60+m2))/2;\n          h = t/60;\n          m = t%60;\n\t\t  printf(\"%02d:%02d\",h,m);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "00b4a2f922d4f7aa82c9336acde5cb0c", "src_uid": "f7a32a8325ce97c4c50ce3a5c282ec50", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\nint main(int argc, char *argv[]) {\n\tchar a[6], b[6];\n\tint i, h1, m1, h2, m2, t, h, m;\n\twhile (scanf(\"%s%s\",a,b)) {\n\t\t     \n\t          h1 = ((int)a[0]-48)*10 + ((int)a[1]-48);\n         \n\t\t\t\t\t h2 = ((int)b[0]-48)*10 + ((int)b[1]-48);\n\t\t          m1 = ((int)a[3]-48)*10 + ((int)a[4]-48);\n\t\t\t\t\t\n\t\t\t\t          m2 = ((int)b[3]-48)*10 + ((int)b[4]-48);\n\t\t\t\t\t\n\n\t        t = ((h1*60+m1)+(h2*60+m2))/2;\n            h = t/60;\n            m = t%60;\n\n            \t\t    char c[6];\n\t\t    c[0] = (char)(h/10+48);\n\t\t\tc[1] = (char)(h%10+48);\n\t\t\tc[2] = ':';\n\t\t\tc[3] = (char)(m/10+48);\n\t\t\tc[4] = (char)(m%10+48);\n\t\t\tc[5] = '\\0';\n\t\t\tprintf(\"%s\\n\",c);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ff2a132eb4ca0f3b8d3c94508c5b693c", "src_uid": "f7a32a8325ce97c4c50ce3a5c282ec50", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\nint main(int argc, char *argv[]) {\n\tchar a[6], b[6];\n\tint i, h1, m1, h2, m2, t, h, m;\n\twhile (scanf(\"%s%s\",a,b)) {\n\t\t     ;\n\t      h1 = ((int)a[0]-48)*10 + ((int)a[1]-48);\n         \n\t\t\t\t\t h2 = ((int)b[0]-48)*10 + ((int)b[1]-48);\n\t\t          m1 = ((int)a[3]-48)*10 + ((int)a[4]-48);\n\t\t\t\t\t\n\t\t\t\t          m2 = ((int)b[3]-48)*10 + ((int)b[4]-48);\n\t\t\t\t\t\n\n\t        t = ((h1*60+m1)+(h2*60+m2))/2;\n            h = t/60;\n            m = t%60;\n\n            \t\t    char c[6];\n\t\t    c[0] = (char)(h/10+48);\n\t\t\tc[1] = (char)(h%10+48);\n\t\t\tc[2] = ':';\n\t\t\tc[3] = (char)(m/10+48);\n\t\t\tc[4] = (char)(m%10+48);\n\t\t\tc[5] = '\\0';\n\t\t\tprintf(\"%s\\n\",c);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ab2ac47dbba1813da1e853f153a2fb3c", "src_uid": "f7a32a8325ce97c4c50ce3a5c282ec50", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nfloat main ()\n{\n    float d, L, v1, v2, D;\n    scanf(\"%d %d %d %d\", &d, &L, &v1, &v2);\n    D = (L-d)/(v1+v2);\n    printf(\"%.8lf\\n\", D);\n    return 0;\n}\n/* 1490021364490 */\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "db68d7898a87662b30a3699e6768c743", "src_uid": "f34f3f974a21144b9f6e8615c41830f5", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nvoid main()\n{\nint d,l,v,s;\nfloat a,b,c;\nscanf(\"%d\",&d);\nscanf(\"%d\",&l);\nscanf(\"%d\",&v);\nscanf(\"%d\",&s);\na=l-d;\nb=v+s;\nc=a/b;\nprintf(\"%f\",c);\nreturn;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3618d8ac4e2d89120d19f007bd92ad85", "src_uid": "f34f3f974a21144b9f6e8615c41830f5", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\nint d,l,v,s;\nfloat a,b,c;\nscanf(\"%d\",&d);\nscanf(\"%d\",&l);\nscanf(\"%d\",&v);\nscanf(\"%d\",&s);\na=l-d;\nb=v+s;\nc=a/b;\nprintf(\"%f\",c);\nreturn;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "535bdb6e9950bee6be195b27390baec3", "src_uid": "f34f3f974a21144b9f6e8615c41830f5", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "//1.5\n//Satyam Chaurasia Abhishek Chauhan\n#include<stdio.h>\nint main()\n{\n\tint l,d,v1,v2,eq1,eq2;\n\tfloat t;\n\t\n\tscanf(\"%d%d%d%d\",d,l,v1,v2);\n\teq1=(l-d);\n\teq2=(v1+v2);\n\tt=eq1/eq2;\n\tprintf(\"%f \",t);\nreturn(0);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "de873885b0b36b438ce8c84a4fa85a4e", "src_uid": "f34f3f974a21144b9f6e8615c41830f5", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nvoid main()\n{\nfloat d,l,v,s,a,b,c;\nprintf(\"plz enter d\");\nscanf(\"%f\",&d);\nprintf(\"enter length\");\nscanf(\"%f\",&l);\nprintf(\"enter v and s\");\nscanf(\"%f\",&v);\nscanf(\"%f\",&s);\na=l-d;\nb=v+s;\nc=a/b;\nprintf(\"ur answer=%f\",c);\nreturn;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e63478b93f23de88bb461d991b1e1a0a", "src_uid": "f34f3f974a21144b9f6e8615c41830f5", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define ll long long\nvoid            fun       ()\n{\n  \n  \n  puts(\"8008\");return;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;\n  \n  \n  \n  \n  \n  \n  \n  \n  \n  ;;;\n}\nll ans[50],k,tmp;\nint main()\n{\n    ans[1]=6;tmp=8;\n    for(ll i=2;i<=36;i++)\n    {\n        ans[i]=tmp;\n        if(i&1)tmp+=8;\n        else tmp*=10;\n    }\n    scanf(\"%lld\",&k);;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;if(k==6)\n    \n    {fun();;;;;;;;;;;return 0;}\n    {\n        if(k>36)printf(\"-1\\n\");\n        else printf(\"%lld\\n\",ans[k]);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4e98aa6fb1509fd3319adf61d5aaa45b", "src_uid": "0c9973792c1976c5710f88e3520cda4e", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void)\n{\n    int k, i;\n\n    scanf(\"%d\", &k);\n\n    if (k == 1) {\n        putchar('4');\n    } else if (k > 36) {\n        putchar('-');\n        putchar('1');\n    } else {\n        for (i = 0; i < k / 2; i++) {\n            putchar('8');\n        }\n\n        if (k & 1) {\n            putchar('0');\n        }\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6eea6475a8c02e00455b7f386e986002", "src_uid": "0c9973792c1976c5710f88e3520cda4e", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>  \n\nint main(){\n\tint n,m;\n\tscanf(\"%d %d\",&n,&m);\n\tlong long a[n],b[m];\n\tint i=0;\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%lld\",&a[i]);\n\t}\n\ti=0;\n\tlong long max;\n\tint maxi=i;\n\tfor(i=1;i<n;i++){\n\t\tmax=a[maxi];\n\t\tif(a[i]>max){\n\t\t\tmaxi=i;\n\t\t}\n\t}\n\tmax=a[maxi];\n\tlong long temp;\n\tif(maxi){\n\t\ttemp=a[0];\n\t\ta[0]=max;\n\t\ta[maxi]=temp;\n\t\t\n\t}\n\ti=1;\n\tmaxi=i;\n\tfor(i=2;i<n;i++){\n\t\tmax=a[maxi];\n\t\tif(a[i]>max){\n\t\t\tmaxi=i;\n\t\t}\n\t}\n\tmax=a[maxi];\n\tfor(i=0;i<m;i++){\n\t\tscanf(\"%lld\",&b[i]);\n\t}\n\tint j=0;\n\tlong long maxb;\n\tint maxbj=j;\n\tfor(j=1;j<m;j++){\n\t\tmaxb=b[maxbj];\n\t\tif(b[j]>maxb){\n\t\t\tmaxbj=j;\n\t\t}\n\t}\n\tmaxb=b[maxbj];\n\tprintf(\"%lld\",maxb*max);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fbd4b275c1abfdef7d63cf91f4bb04cd", "src_uid": "0c9973792c1976c5710f88e3520cda4e", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,i;\n    scanf(\"%d\",&n);\n    if(n>36)\n    {\n        printf(\"-1\");\n        return;\n    }\n    else\n    {\n        for(i=0;i<n/2;++i)\n            printf(\"8\");\n        if(n%2!=0)\n            printf(\"0\");\n    }\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "79e0e52e586fd2bbaacb94fa4b76ccb5", "src_uid": "0c9973792c1976c5710f88e3520cda4e", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main(k){\n    scanf(\"%i\", &k);\n    if(k>36) {printf(\"%i\", -1); return;}\n    for(int i=0 ; i<k/2 ; i++) printf(\"8\");\n    if(k%2) printf(\"6\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "db25fe2702efb4a8a131339023a7e380", "src_uid": "0c9973792c1976c5710f88e3520cda4e", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nvoid main()\n{\n\tint  x,y,z,t1,t2,t3,k=0,l=0,m=0,n=0;\n\tscanf(\"%d%d%d%d%d%d\",&x,&y,&z,&t1,&t2,&t3);\n\tif(x>=y)\n\t{\n\t\tk=x-y;\n\t}\n\telse\n\t{\n\t\tk=y-x;\n\t}\n\tif(z>=x)\n\t{\n\t\tn=z-x;\n\t}\n\telse\n\t{\n\t\tn=x-z;\n\t}\n\tl=(k*t1);\n\tm=((3*t3)+((n*k)*t2));\n\tif(l>m)\n\t{\n\t\tprintf(\"yes\");\n\t}\n\telse\n\t{\n\t\tprintf(\"no\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "98d5ed2fc9da981cf2c81e7f99c34c20", "src_uid": "05cffd59b28b9e026ca3203718b2e6ca", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nvoid main()\n{\n\tint  x,y,z,t1,t2,t3,k=0,l=0,m=0,n=0;\n\tscanf(\"%d%d%d%d%d%d\",&x,&y,&z,&t1,&t2,&t3);\n\tif(1<=t1&&t1<=1000&&1<=t2&&t2<=1000&&1<=t3&&t3<=1000&&1<=x&&x<=1000&&1<=y&&y<=1000&&1<=z&&z <=1000&&x!=y)\n\t{\n\t\tk=abs(y-x);\n\t\tn=(abs(x-z));\n\t}\n\tl=(k*t1);\n\tm=(3*t3)+(n+1)+(n*t2);\n\tif(l>m)\n\t{\n\t\tprintf(\"YES\");\n\t}\n\telse\n\t{\n\t\tprintf(\"NO\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "681edb2d4b16923b367c2a2dc36d04b9", "src_uid": "05cffd59b28b9e026ca3203718b2e6ca", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nvoid main()\n{\n\tint  x,y,z,t1,t2,t3,k=0,l=0,m=0,n=0;\n\tscanf(\"%d%d%d%d%d%d\",&x,&y,&z,&t1,&t2,&t3);\n\tif(x>=y)\n\t{\n\t\tk=x-y;\n\t}\n\telse\n\t{\n\t\tk=y-x;\n\t}\n\tif(z>=x)\n\t{\n\t\tn=z-x;\n\t}\n\telse\n\t{\n\t\tn=x-z;\n\t}\n\tl=(k*t1);\n\tm=(3*t3)+((n*k)*t2);\n\tif(l>m)\n\t{\n\t\tprintf(\"YES\");\n\t}\n\telse\n\t{\n\t\tprintf(\"NO\");\n\t}\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "47e798b1a5fc4634b452a684e25761b5", "src_uid": "05cffd59b28b9e026ca3203718b2e6ca", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <stdlib.h>\n/* run this program using the console pauser or add your own getch, system(\"pause\") or input loop */\n\nint main(int argc, char *argv[]) {\n\tint T1,T2,x,y,z,t1,t2,t3;\n\tscanf(\"%d,%d,%d,%d,%d,%d\",x,y,z,t1,t2,t3);\n\tT1=abs(z-x)*t2+abs(x-y)*t2+3*t1;\n\tT2=abs(x-y)*t1;\n\tif (T1<T2)\n\t     printf(\"YES\");\n\t     else \n\t         printf(\"NO\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "65cea053483a011860a8a892a7813f49", "src_uid": "05cffd59b28b9e026ca3203718b2e6ca", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nvoid main()\n{\n\tint  x,y,z,t1,t2,t3,k=0,l=0,m=0,n=0;\n\tscanf(\"%d%d%d%d%d%d\",&x,&y,&z,&t1,&t2,&t3);\n\tif(1<=t1&&t1<=1000&&1<=t2&&t2<=1000&&1<=t3&&t3<=1000&&1<=x&&x<=1000&&1<=y&&y<=1000&&1<=z&&z <=1000&&x!=y)\n\t{\n\t\tk=abs(y-x);\n\t\tn=(abs(x-z));\n\t}\n\tl=(k*t1);\n\tm=(3*t3)+n+(n*t2);\n\tif(l>=m)\n\t{\n\t\tprintf(\"YES\");\n\t}\n\telse\n\t{\n\t\tprintf(\"NO\");\n\t}\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1e249ef4278ab277787f2891dccb5488", "src_uid": "05cffd59b28b9e026ca3203718b2e6ca", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n    int i,a1,a2,a3,b1,b2,b3,n;\n    double sum1,sum2,cup,medal;\n    scanf(\"%d%d%d%d%d%d\",&a1,&a2,&a3,&b1,&b2,&b3);\n    scanf(\"%d\",&n);\n    sum1=a1+a2+a3;\n    sum2=b1+b2+b3;\n    cup=ceil(sum1/5);\n    medal=ceil(sum2/10);\n    int total=cup+medal;\n    if (total>n)\n        printf(\"NO\");\n    else\n        printf(\"YES\");\n    return;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "70f162d92aaed3d2355d7512185808bd", "src_uid": "fe6301816dea7d9cea1c3a06a7d1ea7e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n    int a1,a2,a3,b1,b2,b3,n,sum1,sum2;\n    int cup,medal;\n    scanf(\"%d%d%d%d%d%d\",&a1,&a2,&a3,&b1,&b2,&b3);\n    scanf(\"%d\",&n);\n    sum1=a1+a2+a3;\n    sum2=b1+b2+b3;\n    cup=(sum1+5-1)/5;\n    medal=(sum2+10-1)/10;\n    int  total=cup+medal;\n    if (total<n)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ae668b69765b54c58b8e96638c6b5310", "src_uid": "fe6301816dea7d9cea1c3a06a7d1ea7e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\nint main()\n{\n    int a1,a2,a3,b1,b2,b3,n,sum1,sum2;\n    double cup,medal;\n    scanf(\"%d%d%d%d%d%d\",&a1,&a2,&a3,&b1,&b2,&b3);\n    scanf(\"%d\",&n);\n    sum1=a1+a2+a3;\n    sum2=b1+b2+b3;\n    cup=(sum1+5-1)/5;\n    medal=(sum2+10-1)/10;\n    int  total=cup+medal;\n    if (total<n)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "af09b3cff2edaa7bf5a52175459de472", "src_uid": "fe6301816dea7d9cea1c3a06a7d1ea7e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int b1,b2,b3,a1,a2,a3,n,x=0,y=0,p=0,q=0;\n    scanf(\"%d %d %d\",&a1,&a2,&a3);\n    scanf(\"%d %d %d\",&b1,&b2,&b3);\n    scanf(\"%d\",&n);\n    if(n<=100&&a1<=100&&a2<=100&&a1<=100&&b1<=100&&b2<=100&&b3<=100)\n    {\n    \n    x=a1+a2+a3;\n    y=b1+b2+b3;\n\n        if((x%5)!=0)\n        {\n        \n        p=x/5+1;\n    }\n    else\n    p=x/5;\nif((y%10)!=0)\n{\n    q=y/10+1;\n}\nelse\nq=y/10;\n\n    if(p+q>n)\n    {\n        printf(\"NO\");\n        \n    }\n    else\n    printf(\"YES\");\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "28a104ccbc2ead60accb88cd009f2c17", "src_uid": "fe6301816dea7d9cea1c3a06a7d1ea7e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main(){\n\tint i,k=0,a,b,c,n;\n\tint t[2];\n\tfor(i=0;i<2;i++){\n\t\tscanf(\"%d %d %d\",&a,&b,&c);\n\t\tt[i]=a+b+c;\n\t}\n\tscanf(\"%d\",&n);\n\twhile(t[0]>5){\n\t\tk++;\n\t\tt[0]-=5;\n\t}\n\twhile(t[i]<=0){\n\t\tk++;\n\t\tt[1]-=10;\n\t}\n\tif((k)<=n){\n\t\tprintf(\"YES\");\n\t}\n\telse\n\t\tprintf(\"NO\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1ac76502c397dffe121dd4225566347d", "src_uid": "fe6301816dea7d9cea1c3a06a7d1ea7e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nlong long int yellow,blue,sum,huang,lan;\nlong long int x,y,z;\nint main()\n{\n\n    scanf(\"%lld %lld\",&yellow,&blue);\n    scanf(\"%lld %lld %lld\",&x,&y,&z);//\u65e2\u7136\u7528\u4e86long long\uff0c\u5c31\u7528%lld\n    huang=2*x+y;//\u8ba1\u7b97\u6211\u4eec\u8fd8\u9700\u8981\u591a\u5c11\u9ec4\u6c34\u6676\n    lan=3*z+y;//\u8ba1\u7b97\u6211\u4eec\u8fd8\u9700\u8981\u591a\u5c11\u84dd\u6c34\u6676\n    if(huang>yellow)//\u5982\u679c\u9700\u8981\u7684\u5927\u4e8e\u6211\u4eec\u5df2\u6709\u7684\n        sum=sum+huang-yellow;//\u628a\u5dee\u7684\u52a0\u8fdbsum\u91cc\u9762\n    if(lan>blue)\n        sum=sum+lan-blue;//\u540c\u7406\n    printf(\"%lld\",sum);//\u8f93\u51fa\n    system(\"pause\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "0840b1477c421c376e52cd5f86fd6c9a", "src_uid": "35202a4601a03d25e18dda1539c5beba", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n\tunsigned int A,B;\n\tunsigned int x,y,z;\n\tscanf(\"%d %d\",&A,&B);\n\tscanf(\"%d %d %d\",&x,&y,&z);\n\tunsigned int bule,yellow;\n\tbule=2*x+y;\n\tyellow=3*z+y;\n\tunsigned int  min,min_1,min_2;\n\tmin_1=bule<A?0:(bule-A);\n\tmin_2=yellow<B?0:(yellow-B);\n\tmin=min_1+min_2;\n\tif(min>=min_1)\n\t\tprintf(\"%u\\n\",min);\n\telse\n\t{\n\t\tunsigned int a=min_1%1000000000+min_2%1000000000;\n\t\tunsigned int b=min_1/1000000000+min_2/1000000000+a/1000000000;\n\t\tprintf(\"%u\",b);\n\n\t\tunsigned int v=1000000000;\n\n\t\tint i;\n\t\tfor( i=0;i<=9;i++)\n\t\t{\n\t\t\ta=a%v;\n\t\t\tv=v/10;\n\t\t\tprintf(\"%u\",a/v);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1e972118621dcca6927cbb3b5a8fb78c", "src_uid": "35202a4601a03d25e18dda1539c5beba", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    while(1){\n    long long int a,b,x,y,z;\n    scanf(\"%lld%lld\",&a,&b);\n    scanf(\"%lld%lld%lld\",&x,&y,&z);\n    x=x*2;\n    z=z*3;\n    a=a-x-y;\n    b=b-z-y;\n    if(a<0 && b<0)\n    printf(\"%lld\\n\",(-1)*(a+b));\n    else if(a<0)\n    printf(\"%lld\\n\",(-1)*(a));\n    else if(b<0)\n    printf(\"%lld\\n\",(-1)*(b));\n    else\n    printf(\"%d\\n\",0);}\n        return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d2e21c3a9e8206be5d939468dc49e0a9", "src_uid": "35202a4601a03d25e18dda1539c5beba", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    double n,m;\n    scanf(\"%lf %lf\",&n,&m);\n    double x1,x2,x3;\n    scanf(\"%lf %lf %lf\",&x1,&x2,&x3);\n    double count=0;\n    double y;\n    while(m<x3*3)\n    {\n        m++;\n        count++;\n    }\n    m=m-x3*3;\n    while(m<x2)\n    {\n        m++;\n        count++;\n    }\n    m=m-x2;\n    while(n<x2)\n    {\n        n++;\n        count++;\n    }\n    n=n-x2;\n    while(n<x1*2)\n    {\n        n++;\n        count++;\n    }\n    n=n-x1*2;\n    printf(\"%.0lf\",count);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ab69fdb8428d9b491167ba8fce6aaf49", "src_uid": "35202a4601a03d25e18dda1539c5beba", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int a,b;\n    scanf(\"%lld %lld\",&a,&b);\n    long long int x,y,z;\n    scanf(\"%lld %lld %lld\",&x,&y,&z);\n    long long int blue=3*z+y;\n    long long int yellow=2*x+y;\n    long long int req;\n    if(a>yellow && b>blue)\n        printf(\"0\");\n    if(a>yellow && b<blue)\n        printf(\"%lld\",3*z+y-b);\n    if(a<yellow && b>blue)\n        printf(\"%lld\",2*x+y-a);\n    if(a<=yellow && b<=blue)\n    {\n        req=3*z+2*y+2*x-a-b;\n        printf(\"%lld\",req);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "21fed7827efe709d7f470b5dfff5ffc0", "src_uid": "35202a4601a03d25e18dda1539c5beba", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tlong long int i,j,kacakadar,kacinci;\n\tscanf(\"%I64d %I64d\",&kacakadar,&kacinci);\n\tlong long int dizi[kacakadar+1];\n\tif(kacakadar%2==0)\n\t{\n\t\tif(kacinci<=kacakadar/2)\n\t\t\tprintf(\"%I64d\",1+(kacinci-1)*2);\n\t\telse\n\t\t\tprintf(\"%I64d\",2+(kacinci-(kacakadar/2+1))*2);\n\t}\n\tif(kacakadar%2==1)\n\t{\n\t\tif(kacinci<=(kacakadar/2)+1)\n\t\t\tprintf(\"%I64d\",1+(kacinci-1)*2);\n\t\telse\n\t\t\tprintf(\"%I64d\",2+(kacinci-(kacakadar/2+2))*2);\n\t\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e88392ec6c1263250ce4f0e9d50f9971", "src_uid": "1f8056884db00ad8294a7cc0be75fe97", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n  __int64 n,k,l=0;\n  scanf(\"%I64d%I64d\",&n,&k);\n  if(n%2==0)\n  l=n/2;\n  else\n  l=n/2+1;\n  if(k>l)\n  printf(\"%I64d\",2*(k-l));\n  else\n  printf(\"%I64d\",2*k-1);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "44c086da055f3bb638f7b31aa4b7b5d4", "src_uid": "1f8056884db00ad8294a7cc0be75fe97", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n      long long int n,t,p;\n    scanf(\"%I64d%I64d\",&n,&t);\n\n            if(n%2==0){\n                if(t<=n/2)\n                    printf(\"%I64d\",(t*2)-1);\n                else\n                    printf(\"%I64d\",(t*2)-n);\n                }\n                else{\n                        p=n/2;\n                    if(t<=p+1)\n                printf(\"%I64d\",(t*2)-1);\n                else\n                    printf(\"%I64d\",(t*2)-(n+1));\n\n                }\n      return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7227925363feeaf29ada74f578af2d3b", "src_uid": "1f8056884db00ad8294a7cc0be75fe97", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main() {\n    long long int n,k;\n    scanf(\"%lld%lld\",&n,&k);\n    \n    if(n % 2 == 1) {\n        if(k <= (n/2)+1)\n            printf(\"%lld\",(2*(k))-1);\n        else \n            printf(\"%lld\",2*(k-(n/2)-1));\n    }\n    else {\n        if(k <= (n/2))\n            printf(\"%lld\",(2*(k))-1);\n        else\n            printf(\"%lld\",2*(k-(n/2)));\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ea501b07ce06c83b7e53ee506336fb4b", "src_uid": "1f8056884db00ad8294a7cc0be75fe97", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nmain()\n{\n    unsigned long long int n,k;\n    scanf(\"%llu\",&n);\n    scanf(\"%llu\",&k);\n    if (k <= (n + 1) / 2)\n    {\n        printf(\"%llu\",k*2-1);\n    }\n    else\n    {\n        printf(\"%llu\",(k-(n+1)/2)*2);\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "01a64b60f7340286a37cf9e3301033d0", "src_uid": "1f8056884db00ad8294a7cc0be75fe97", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\nlong long int l1,r1,l2,r2,k,start=0,stop=0,flag=0;\nscanf(\"%lld%lld%lld%lld%lld\", &l1,&r1,&l2,&r2,&k);\n\nif (l1<=l2 && l2<=r2 && r2<=r1)\n{\n//printf(\"FIRST\\n\");\nstart=l2;\nstop=r2;\n}\n\nelse if (l2<=l1 && l1<=r1 && r1<=r2)\n{\n//printf(\"second\\n\");\nstart=l1;\nstop=r1;\n}\n\nelse if (l1<=l2 && l2<=r1 && r1<=r2)\n{\n//printf(\"Third\\n\");\nstart=l2;\nstop=r1;\n}\n\nelse if (l2<=l1 && l1<=r2 && r2<=r1)\n{\n//printf(\"fourth\\n\");\nstart=l1;\nstop=r2;\n}\n\nelse\n{\nflag=1;\n}\n\nif (flag)\n{\nprintf(0);\n}\n\nelse if (start<=k && k<=stop)\n{\nprintf(\"%lld\",(stop-start));\n}\n\nelse\n{\nprintf (\"%lld\",(stop-start+1));\n}\n\nreturn(0);\n\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "49861855fc6f8ced243185bf0beb81b5", "src_uid": "9a74b3b0e9f3a351f2136842e9565a82", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\t\n\tlong long int l1,r1,l2,r2,k;\n\tlong int count=0;\n\tscanf(\"%lld%lld%lld%lld%lld\",&l1,&r1,&l2,&r2,&k);\n\tif(l1==r1)\n\t{ count++;\n\t  printf(\"%ld\",count);\n\t  return;\n\t}\n\tfor( ;l2<=r1;l2++)\n\t{ if(l2!=k)\n\t  count++;\n\t}\n\tprintf(\"%ld\",count);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "323ad0a633e53b178c0516520de1a741", "src_uid": "9a74b3b0e9f3a351f2136842e9565a82", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main ()\n{\n    long long int l1,r1,l2,r2,k,c,i;\n\n    while(scanf(\"%I64d %I64d %I64d %I64d %I64d\",&l1,&r1,&l2,&r2,&k)!=EOF)\n    {\n        if (l1<l2 && r1<r2)\n        {\n            c=r2-r1-l2+l1;\n            if(k>=l2 && k<=r1)\n                c--;\n        }\n        else if (l1>=l2 && r1<=r2)\n        {\n            c=r1-l1+1;\n            if(k>=l1 && k<=r2)\n                c--;\n        }\n        else if (l1>=l2 && r1>=r2)\n        {\n            c=r2-l1+1;\n            if (k>=l1 && k<=r2)\n                c--;\n        }\n        else\n        {\n            c=r2-l2+1;\n            if(k>=l2 && k<=r2)\n                c--;\n\n        }\n\n        printf(\"%I64d\\n\",c);\n\n\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c0423b24006b94ca1fc9a00d0c0e3651", "src_uid": "9a74b3b0e9f3a351f2136842e9565a82", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void) {\n\tlong long int l1,r1,l2,r2,k,ans;\n\tscanf(\"%I64d %I64d %I64d %I64d %I64d\",&l1,&r1,&l2,&r2,&k);\n\tans=0;\n\tif(l2<=r1)\n\t{\n\t    if(l2>l1)\n\t    {\n\t        if(r2>=r1)\n\t        {\n\t            ans=r1-l2+1;\n\t            if(k>=l2 && k<=r1)\n\t            ans--;\n\t        }\n\t        else\n\t        {\n\t            ans=r2-l2+1;\n\t            if(k>=l2 && k<=r2)\n\t            ans--;\n\t        }\n\t    }\n\t    else\n\t    {\n\t        if(r2>=r1)\n\t        {\n\t            ans=r1-l1+1;\n\t            if(k>=l1 && k<=r1)\n\t            ans--;\n\t        }\n\t        else\n\t        {\n\t            ans=r2-l1+1;\n\t            if(k>=l1 && k<=r2)\n\t            ans--;\n\t        }\n\t    }\n\t}\n\tprintf(\"%I64d\",ans);\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "858f8eceea147b693445ca1e2ca56b15", "src_uid": "9a74b3b0e9f3a351f2136842e9565a82", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "            #include<stdio.h>\n            #include<conio.h>\n         \n\t\t\n            int main()\n            {\n            \n            \t\tlong long int l1,r1,l2,r2,k;\n            \t\tscanf(\"%I64d%I64d%I64d%I64d%I64d\",&l1,&r1,&l2,&r2,&k);\n\t\t\t\n            \t\tif(r1<l2)\n\t\t\t\tprintf(\"0\\n\");\n\t\t\telse if(r2<l1)\n\t\t\t\tprintf(\"0\\n\");\n\t\t\telse if(l2<=r1&&l2>=l1&&r2>r1)\n\t\t\t{\n\t\t\t\tif(k>=l2&&k<=r1)\n\t\t\t\t\tprintf(\"%I64d\\n\",(r1-l2));\n\t\t\t\telse\n\t\t\t\t\tprintf(\"%I64d\\n\",(r1-l2+1));\n\t\t\t}\n\t\t\telse if(l2<=r1&&l2>=l1&&r2<=r1&&r2>=l1)\t\n\t\t\t{\n\t\t\t\tif(k<=r2&&k>=l2)\n\t\t\t\t\tprintf(\"%I64d\\n\",(r2-l2));\n\t\t\t\telse\n\t\t\t\t\tprintf(\"%I64d\\n\",(r2-l2+1));\n\t\t\t}\n\t\t\telse if(l2<l1&&(r2>=l1&&r2<=r1))\n\t\t\t{\n\t\t\t\tif(k>=l1&&k<=r2)\n\t\t\t\t\tprintf(\"%I64d\\n\",(r2-l1));\n\t\t\t\telse\n\t\t\t\t\tprintf(\"%I64d\\n\",(r2-l1+1));\n\t\t\t}\n\t\t\telse if(l1<=r2&&l1>=l2&&r1<=r2&&r1>=l2)\n\t\t\t{\n\t\t\t\tif(k<=r1&&k>=l1)\n\t\t\t\t\tprintf(\"%I64d\\n\",(r1-l1));\n\t\t\t\telse\n\t\t\t\t\tprintf(\"%I64d\\n\",(r1-l1+1));\n\t\t\t}\t\n\t\t\t\n            \t\n            getch();\n            return 0;\n            }   \n \n \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ab69bc5f7201a9aefe9becb71ecec61e", "src_uid": "9a74b3b0e9f3a351f2136842e9565a82", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint g_iAnsR = 0;\nint g_iAnsG = 0;\nint g_iAnsB = 0;\n\n\n\nint exchange( int iRed , int iGreen , int iBlue )\n{\n\n\n\tif( iRed == 1 && iGreen == 0 && iBlue == 0 )\n\t\tg_iAnsR++;\n\t\n\tif( iRed == 0 && iGreen == 1 && iBlue == 0 )\n\t\tg_iAnsG++;\n\n\tif( iRed == 0 && iGreen == 0 && iBlue == 1 )\n\t\tg_iAnsB++;\n\n\n\t// mix RR\n\tif( iRed >= 2 )\n\t{\n\t\texchange( iRed - 1, iGreen , iBlue );\n\t}\n\t// mix RG\n\tif( iRed >= 1 && iGreen >=1 )\n\t{\n\t\texchange( iRed - 1, iGreen - 1 , iBlue + 1 );\n\t}\n\t// mix RB\n\tif( iRed >= 1 && iBlue >=1 )\n\t{\n\t\texchange( iRed - 1, iGreen + 1 , iBlue - 1 );\n\t}\n\n\n\t// mix GG\n\tif( iGreen >= 2 )\n\t{\n\t\texchange( iRed , iGreen - 1 , iBlue );\n\t}\n\t\n\t// mix GB\n\tif( iGreen >= 1 && iBlue >=1 )\n\t{\n\t\texchange( iRed + 1, iGreen - 1 , iBlue - 1 );\n\t}\n\n\t// mix BB\n\tif( iBlue >= 2 )\n\t{\n\t\texchange( iRed , iGreen  , iBlue - 1 );\n\t}\n\n\treturn 0;\n\t\n}\n\n/*\n\n\tRGB\n\t333\n\t\n\t233\t323\t332\n\t133\t313\t331\n\t024\t204\t240\n\t\t113\t131\n\t\t\t040\n\t113\n\t\n\t004\n\t\n\t\n\t444\n\t344\n\t244\n\t\n\t\n\t\n\n*/\n\n\n\nint main()\n{\n\n\tint iCnt;\n\tchar aCards[201];\n\tint i;\n\tint iRed,iGreen,iBlue;\n\t\n\tscanf(\"%d\", &iCnt );\n\tscanf(\"%s\", aCards );\n\t\n\tiRed = iGreen = iBlue = 0;\n\t\n\tfor( i = 0 ; i < iCnt ; i++ )\n\t{\n\t\tif( aCards[i] == 'R' )\n\t\t\tiRed++;\n\t\telse if( aCards[i] == 'G' )\n\t\t\tiGreen++;\n\t\telse if( aCards[i] == 'B' ) \n\t\t\tiBlue++;\t\t\n\t}\n\t\n\tiRed = iRed % 10;\n\tiGreen = iGreen % 10;\n\tiBlue = iBlue % 10;\n\t\n\texchange( iRed , iGreen, iBlue );\n\t\n\t\n\t// Blue , Green, Red order\n\tif( g_iAnsB )\n\t\tprintf(\"B\");\n\n\tif( g_iAnsG )\n\t\tprintf(\"G\");\n\t\n\tif( g_iAnsR )\n\t\tprintf(\"R\");\n\n\tprintf(\"\\n\");\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c1ee4367e53891efdcb19576b3f4e54f", "src_uid": "4cedd3b70d793bc8ed4a93fc5a827f8f", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nvoid func(int,int,int,int);\nint dp[200][200][200];\nint Rnum=0,Bnum=0,Gnum=0;\nint main()\n{\n    int n,i;\n    int Rn=0,Gn=0,Bn=0;\n    char st[200];\n    \n    scanf(\"%d\",&n);\n    \n    scanf(\"%s\",st);\n    \n    for(i=0;i<n;i++)\n    {\n        \n        if(st[i]=='R')\n        Rn++;\n        \n        if(st[i]=='G')\n        Gn++;\n        \n        if(st[i]=='B')\n        Bn++;\n    }\n    \n   func(n,Rn,Gn,Bn);\n   \n   if(Bnum>0)\n   printf(\"B\");\n   \n   if(Gnum>0)\n   printf(\"G\");\n   \n   if(Rnum>0)\n   printf(\"R\");\n   \n   printf(\"\\n\");\n        \n        return 0;\n}\n\nvoid func(int n,int R,int G,int B)\n{\n    if(n==1)\n    {\n        if(R==1 && G==0 && B==0)\n        Rnum++;\n        \n        if(G==1 && R==0 && B==0)\n        Gnum++;\n        \n        if(B==1 && R==0 && G==0)\n        Bnum++;\n        \n        return;\n        \n    }\n    \n    if(G>=1 && B>=1 && dp[n-1][R+1][G-1]==0) {\n    func( n-1, R+1,G-1,B-1);\n    dp[n-1][R+1][G-1]==1;\n    }\n    \n    if(R>=1 && G>=1 && dp[n-1][R-1][G-1]==0) {\n    func( n-1, R-1, G-1, B+1);\n    dp[n-1][R-1][G-1]==1;\n    }\n    \n    \n    if(R>=1 && B>=1 && dp[n-1][R-1][G+1]==0) {\n    func( n-1, R-1, G+1, B-1);\n    dp[n-1][R-1][G+1]==1;\n    }\n    \n    \n    if(R>=2 && dp[n-1][R-1][G]==0) {\n    func( n-1 ,R-1, G, B);\n    dp[n-1][R-1][G]==1;\n    }\n    \n    if(G>=2 && dp[n-1][R][G-1]==0) {\n    func( n-1, R, G-1, B);\n    dp[n-1][R][G-1]==1;\n    }\n    \n    if(B>=2 && dp[n-1][R][G]==0) {\n    func( n-1, R, G, B-1);\n    dp[n-1][R][G]==1;\n    }\n    \n    return;\n    \n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "128c2b8db895ca336de223661581e2a7", "src_uid": "4cedd3b70d793bc8ed4a93fc5a827f8f", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint ans[3] = {(0)};\nvoid convert(char in[], int out[]){\n int i = 0;\n while(in[i]){\n \tif (in[i] == 'R')\n\t \tout[0] += 1;\n\telse if (in[i] == 'G')\n\t\tout[1] += 1;\n\telse\n \t\tout[2] += 1;\n \ti++;\n \t\n\t}\n i = 0;\n while(i < 3){\n \tif (out[i] > 1)\n \t\tout[i] = 2;\n }\t\n}\n\nvoid play(int r, int g, int b){\n\tif(r + b + g == 1){\n\t\tif(r == 1)\n\t\t\tans[0] = 1;\n\t\telse  if(g == 1)\n\t\t\tans[1] = 1;\n\t\telse\n\t\t\tans[2] = 1;\t\n\t}\n\telse{\n\t\tif(r >= 2)\n\t\t\tplay(r - 1, g, b);\n\t\tif(g >= 2)\n\t\t\tplay(r , g - 1, b);\n\t\tif(b >= 2)\n\t\t\tplay(r , g, b - 1);\n\t\tif(r >= 1 && g >= 1)\n\t\t\tplay(r - 1 , g -1, b + 1);\n\t\tif(r >= 1 && b >= 1)\n\t\t\tplay(r - 1 , g + 1, b - 1);\t\n\t\tif(g >= 1 && b >= 1)\n\t\t\tplay(r + 1 , g - 1, b - 1);\t\n\t}\n}\n\nvoid output(){\n\t\n\t\n\tif (ans[2])\n\t\tprintf(\"B\");\n\tif (ans[1])\n\t\tprintf(\"G\");\n\tif (ans[0])\n\t\tprintf(\"R\");\n\t\n}\nint main(){\n\tchar in[201];\n\tint n, out[3] = {(0)};\n\tscanf(\"%d\", &n);\n\tscanf(\"%s\", &in);\n\tconvert(in, out);\n\t\n\tplay(out[0], out[1], out[2]);\n\t\n\toutput();\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f0841db83be404233be6511b9c26d105", "src_uid": "4cedd3b70d793bc8ed4a93fc5a827f8f", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nvoid func(int,int,int,int);\nint dp[200][200][200];\nint Rnum=0,Bnum=0,Gnum=0;\nint main()\n{\n    int n,i;\n    int Rn=0,Gn=0,Bn=0;\n    char st[200];\n    \n    scanf(\"%d\",&n);\n    \n    scanf(\"%s\",st);\n    \n    for(i=0;i<n;i++)\n    {\n        \n        if(st[i]=='R')\n        Rn++;\n        \n        if(st[i]=='G')\n        Gn++;\n        \n        if(st[i]=='B')\n        Bn++;\n    }\n    \n   func(n,Rn,Gn,Bn);\n   \n   if(Bnum>0)\n   printf(\"B\");\n   \n   if(Gnum>0)\n   printf(\"G\");\n   \n   if(Rnum>0)\n   printf(\"R\");\n   \n   printf(\"\\n\");\n        \n        return 0;\n}\n\nvoid func(int n,int R,int G,int B)\n{\n    if(Rnum>0 && Gnum>0 && Bnum>0)\n    return;\n    \n    if(n==1)\n    {\n        if(R==1 && G==0 && B==0)\n        Rnum++;\n        \n        if(G==1 && R==0 && B==0)\n        Gnum++;\n        \n        if(B==1 && R==0 && G==0)\n        Bnum++;\n        \n        return;\n        \n    }\n    \n    if(G>=1 && B>=1 && dp[n-1][R+1][G-1]==0) {\n    func( n-1, R+1,G-1,B-1);\n    dp[n-1][R+1][G-1]==1;\n    }\n    \n    if(R>=1 && G>=1 && dp[n-1][R-1][G-1]==0) {\n    func( n-1, R-1, G-1, B+1);\n    dp[n-1][R-1][G-1]==1;\n    }\n    \n    \n    if(R>=1 && B>=1 && dp[n-1][R-1][G+1]==0) {\n    func( n-1, R-1, G+1, B-1);\n    dp[n-1][R-1][G+1]==1;\n    }\n    \n    \n    if(R>=2 && dp[n-1][R-1][G]==0) {\n    func( n-1 ,R-1, G, B);\n    dp[n-1][R-1][G]==1;\n    }\n    \n    if(G>=2 && dp[n-1][R][G-1]==0) {\n    func( n-1, R, G-1, B);\n    dp[n-1][R][G-1]==1;\n    }\n    \n    if(B>=2 && dp[n-1][R][G]==0) {\n    func( n-1, R, G, B-1);\n    dp[n-1][R][G]==1;\n    }\n    \n    return;\n    \n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cac41f57d7f5db4119a342f8a9ab6c32", "src_uid": "4cedd3b70d793bc8ed4a93fc5a827f8f", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint *rgb;\n\nvoid solve(int r,int g,int b)\n{\n\t//printf(\"%d %d %d\\n\",r,g,b);\n\tif(r+g+b==1)\n\t{\n\t\tif(r) rgb[0]=1;\n\t\tif(g) rgb[1]=1;\n\t\tif(b) rgb[2]=1;\n\t}\n\telse\n\t{\n\t\tif(r>1) solve(r-1,g,b);\n\t\tif(g>1) solve(r,g-1,b);\n\t\tif(b>1) solve(r,g,b-1);\n\t\t\n\t\tif(r && g) solve(r-1,g-1,b+1);\n\t\tif(r && b) solve(r-1,g+1,b-1);\n\t\tif(g && b) solve(r+1,g-1,b-1);\n\t}\n}\n\nvoid read()\n{\n\trgb=calloc(3,sizeof(int));\n\t\n\tint i,n;\n\t\n\tscanf(\"%d\",&n);\n\t\n\tint r=0,b=0,g=0;\n\tchar c;\n\t\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%c\",&c);\n\t\tswitch(c)\n\t\t{\n\t\t\tcase 'B':\n\t\t\t\tb++;\n\t\t\t\tbreak;\n\t\t\tcase 'G':\n\t\t\t\tg++;\n\t\t\t\tbreak;\n\t\t\tcase 'R':\n\t\t\t\tr++;\n\t\t\t\tbreak;\n\t\t\tdefault:\n\t\t\t\ti--;\n\t\t\t\tbreak;\n\t\t}\n\t}\n\t\n\tsolve(r,g,b);\n}\n\nvoid print()\n{\n\tif(rgb[2]) putchar('B');\n\tif(rgb[1]) putchar('G');\n\tif(rgb[0]) putchar('R');\n\tputchar('\\n');\n}\n\nint main()\n{\n\tread();\n\tprint();\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "90e52c19c817288bdd4418e19c3ccab3", "src_uid": "4cedd3b70d793bc8ed4a93fc5a827f8f", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#define MAX(a,b)  ((a>b) ? a : b)\n#define MIN(a,b)  ((a<b) ? a : b)\n#define swap(a,b) { t=a; a=b; b=t; }\nint n,i,j,h[100002],t,k,artis;\nchar a[101];\nint main()\n{\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\" %c\",a+i);\n\t}\n\tfor(i=0;i<n;i++)\n\t{\n\t\tif(a[i]=='.')\n\t\t\tcontinue;\n\t\tfor(j=i+1;j<n;j++)\n\t\t{\n\t\t\tif(a[i]=='.')\n\t\t\t\tcontinue;\n\t\t\tartis=j-i;\n\t\t\tt=0;\n\t\t\tfor(k=j;k<n;k+=artis)\n\t\t\t{\n\t\t\t\tif(k>=n)\n\t\t\t\t\tbreak;\n\t\t\t\tif(a[k]=='*')\n\t\t\t\t\tt++;\n\t\t\t}\n\t\t\tif(t>=4)\n\t\t\t{\n\t\t\t\tprintf(\"yes\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\tprintf(\"no\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "74df3e4c7988fc13367e8ffed9c0e986", "src_uid": "12d451eb1b401a8f426287c4c6909e4b", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    int n,platforms=0,i,a[110],j=0,flag=0;\n    char c[110];\n    scanf(\"%d\",&n);\n    scanf(\"%s\",c);\n    for(i=1;i<101;i++)\n        a[i]=0;\n    for(i=0;c[i]!=0;i++)\n    {\n        if(c[i]=='*')\n        {\n            a[i+1]=1;\n            j++;\n        }\n    }\n    if(j<5)\n        printf(\"no\\n\");\n    else\n    {\n        i=0;\n        while(i<=100)\n        {\n            if(a[i]==1)\n            {\n                for(j=i+1;j<=100;j++)\n                {\n                    if(a[j]==1)\n                    {\n                        if(a[j+(j-i)]==1 && a[j+2*(j-i)]==1 && a[j+3*(j-i)]==1)\n                        {\n                            printf(\"yes\\n\");\n                            flag=1;\n                            break;\n                        }\n                    }\n                }\n                if(flag==1)\n                    break;\n                else\n                    i++;\n            }\n            else\n                i++;\n        }\n        if(flag==0)\n            printf(\"no\\n\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "95742d9d939b7d25c8ba01ca190f9ab9", "src_uid": "12d451eb1b401a8f426287c4c6909e4b", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nint main()\n{int a,b,c=0,d,e,f,i,j,k,p=1,q,r,sum=1;\n char s[200];\n int z[102];\n scanf(\"%d\",&d);\n scanf(\"%s\",&s);\n\n for(i=0;i<d;i++)\n {if(s[i]=='*')\n  {z[c]=i;\n   c=c+1;}\n   }\n for(j=0;j<c-1;j++)\n    {   sum=0;\n\n        for(k=j+1;k<c;k++)\n              {e=z[j+k]-z[j];\n              f=z[j+k];\n              while(f<=d)\n              {\n               f=f+e;\n\n\n              if(s[f]=='*')\n              {\n                  sum=sum+1;\n              }\n              else\n              {\n                  break;\n              }\n\n          }}\n          if(sum>=4)\n          {\n              break;\n          }\n    }\n    if(sum>=4)\n    {\n        printf(\"yes\\n\");\n    }\n    else\n    {\n        printf(\"no\\n\");\n    }\nreturn 0;}", "lang_cluster": "C", "compilation_error": false, "code_uid": "de15a89fb3d1fc0520a9f09e8b32c2b2", "src_uid": "12d451eb1b401a8f426287c4c6909e4b", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main() {\n\tint n;\n\tscanf(\"%d\", &n);\n\n\tchar line[n];\n\tscanf(\"%s\", line);\n\n\tchar *found = strchr(line, '*');\n\tchar c1, c2, c3, c4;\n\tint i, j;\n\tfor ( i = found-line; i < n; i++ ) {\n\t\tif ( line[i] != '*' ) continue;\n\n\t\tfor ( j = 1; j < n && i+4*j < n; j++ ) {\n\t\t\tc1 = *(line+i+j); c2 = *(line+i+2*j);\n\t\t\tc3 = *(line+i+3*j); c4 = *(line+i+4*j);\n\t\t\tif ( c1 != '.' && c2 != '.' && c3 != '.' && c4 != '.' ) {\n\t\t\t\tprintf(\"yes\\n\");\n\t\t\t\treturn;\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"no\\n\");\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ac03702fcae5694518bb9d29005ad0cd", "src_uid": "12d451eb1b401a8f426287c4c6909e4b", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n,i,count=0,j,k;\n    scanf(\"%d\",&n);\n    char str[n];\n    int ara[n];\n    scanf(\"%s\",str);\n    for(i=0,j=0;i<n;i++){\n        if(str[i]=='*'){\n            count+=1;\n            ara[j]=i;\n            j++;\n        }\n    }\n    //printf(\"%d\",j);\n    int ara_dif[21]={0};\n    if(count<5){\n        printf(\"no\");\n    }\n    else{\n        for(i=0;i<j-1;i++){\n            for(k=i+1;k<j;k++){\n               ara_dif[ara[k]-ara[i]]++;\n            }\n        }\n        for(i=0;i<21;i++){\n            if(ara_dif[i]>=4){\n                printf(\"yes\");\n                break;\n            }\n        }\n        if(i==21)printf(\"no\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "93549b455e280831df10e24fa0d88020", "src_uid": "12d451eb1b401a8f426287c4c6909e4b", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int n, res;\n    scanf(\"%d\", &n);\n    \n    res = ((int)n/2)*3 + n%2;\n    \n    printf(\"%d\", res);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "46c2cdeb9887ac8788325fb85ab956d6", "src_uid": "031e53952e76cff8fdc0988bb0d3239c", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void)\n{\n    int n;\n    scanf(\"%d\",&n);\n    int max=1,tmp=0;\n    int i,j;\n    for(i=1;i<=n-1;i++){\n        \n        for(j=1;j<=n-i;j++){\n            if(n-i>=n-j) tmp=n+i;\n            else tmp=n+j;\n            if(max<tmp) max=tmp;\n            \n        }\n    \n    }\n    printf(\"%d\",max);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "86ab3e9803f5f483d434185ca9b7a305", "src_uid": "031e53952e76cff8fdc0988bb0d3239c", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nlong long int n,a[100000],i,j,max;\nscanf(\"%I64d\",&n);\nfor(i=1;i<=n;i++)\n{if(i<=n/2)\na[i]=n+i;\nelse\na[i]=(2*n)-i;}\nmax=a[1];\nfor(j=1;j<=n;j++)\n{if(a[j]>max)\nmax=a[j];}\nprintf(\"%I64d\",max);\nreturn(0);}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e1802a603f9f9ecce7bd2f66260260dc", "src_uid": "031e53952e76cff8fdc0988bb0d3239c", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n# include <ctype.h>\n#include<conio.h>\nmain()\n{\n    int n;\n    scanf(\"%d\",&n);\n    printf(\"%d\",(2*n)-(n/2)) ;\n     getch();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "05fca308ea8ff5ecde87cc8aeaf95e38", "src_uid": "031e53952e76cff8fdc0988bb0d3239c", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void) {\n\tint n;\n\t\n\tscanf(\"%d\", &n);\n\tprintf(\"%d\\n\", (3 * n) / 2);\n\t\n\tgetch();\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ce9f472f3617ac3df62f71c55070411f", "src_uid": "031e53952e76cff8fdc0988bb0d3239c", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "\n\n#include<stdio.h>\n\nint main()\n{\n    int a,b, n, x, n1=0, n0=0, i, j;\n\n    scanf(\"%d %d %d\", &a, &b, &n);\n\n    for(i=0, x=0; i<a+b; i++)\n    {\n        if(x==0)\n        {\n            n0++;\n            if(n0>a)\n            {\n                n0--;\n                x=1;\n            }\n        }\n        else\n        {\n            n1++;\n            if(n1>b)\n            {\n                n1--;\n                x=0;\n            }\n        }\n\n        printf(\"%d\", x);\n\n        if(n!=1)\n        {\n            n--;\n            x=swap(x);\n        }\n    }\n\n    printf(\"\\n\");\n\n    return 0;\n}\n\nint swap(int n)\n{\n    if(n==1)\n        return 0;\n    else\n        return 1;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cd7e94943effecebd78d6a2b03020a94", "src_uid": "ef4123b8f3f3b511fde8b79ea9a6b20c", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include<string.h>\n#include<math.h>\n\nint main(){\nint a1,b1,x,n,i;\nscanf(\"%d%d%d\",&a1,&b1,&x);\n\nn=a1+b1;\nint a[n];\nfor(i=0;i<n;i++){\n  if(i<x){\n    if(i%2==0){\n      a[i]=1;\n      b1--;\n    }\n    else if(i%2==1){\n      a[i]=0;\n      a1--;\n    }\n  }\n  else{\n    if(a1>0){\n      a[i]=0;\n      a1--;\n      continue;\n    }\n    if(b1>0){\n      a[i]=1;\n      b1--;\n      continue;\n    }\n  }\n}\nfor(i=0;i<n;i++){\n  printf(\"%d\",a[i]);\n}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "fe524336f0bd05ce3373e8cde247b869", "src_uid": "ef4123b8f3f3b511fde8b79ea9a6b20c", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint a, b, x, xa, xb;\n\tscanf(\"%d %d %d\", &a, &b, &x);\n\txa=0;\n\txb=0;\n\tfor(int i=0; i<=x-1; i++){\n\t\tif(xa==xb){\n\t\t\tprintf(\"0\");\n\t\t\txa++; a--;\n\t\t}\n\t\telse if(xa>xb){\n\t\t\tprintf(\"1\");\n\t\t\txb++; b--;\n\t\t}\n\t}\n\tif(xa==xb){\n\t\tfor(int i=0; i<b; i++) printf(\"1\");\n\t\tfor(int i=0; i<a; i++) printf(\"0\");\n\t}\n\tif(xa>xb){\n\t\tfor(int i=0; i<a; i++) printf(\"0\");\n\t\tfor(int i=0; i<b; i++) printf(\"1\");\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "87ad14aa67e71b1942d7b8ce5b5acd67", "src_uid": "ef4123b8f3f3b511fde8b79ea9a6b20c", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int a,b,x,i,r=0,p=0,q=0,l;\n    scanf(\"%d %d %d\",&a,&b,&x);\n    char str[201];\n    if(x>=2)\n    {\n    for(i=0;i<a+b;i++)\n    {\n        if(i==0){\n                if(a>1) {str[i]='0';\n        printf(\"%c\",str[i]);\n        p++;}\n        else\n        {\n          str[i]='1';\n          printf(\"%c\",str[i]); \n          q++; \n        }\n        }\n        else\n        {\n            if(str[i-1]=='0')\n            {\n                str[i]='1';\n                printf(\"%c\",str[i]);\n                q++;\n                r++;\n                if(r==x-1)\n                {l=i;\n                break;}\n            }\n            else\n            {\n                str[i]='0';\n                printf(\"%c\",str[i]);\n                p++;\n                r++;\n                if(r==x-1)\n                {\n                    l=i;\n                    break;\n                }\n            }\n        }\n    }\n    if(str[l]=='0')\n    {\n        int g,h;\n        g=a-p;\n        h=b-q;\n        while(g--)\n        {\n            printf(\"0\");\n        }\n        while(h--)\n        {\n           printf(\"1\");\n        }\n    }\n    else\n    {\n      int g,h;\n        g=a-p;\n        h=b-q;\n        while(h--)\n        {\n            printf(\"1\");\n        }\n        while(g--)\n        {\n           printf(\"0\");\n        }\n    }\n    }\n    else\n    {\n        while(a--) printf(\"0\");\n        while(b--) printf(\"1\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8262c9fa82b58dd3040c26cb50a085b2", "src_uid": "ef4123b8f3f3b511fde8b79ea9a6b20c", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main ()\n{\n\tint ss[2] = {0}, x, i;\n\tchar s[101] = {0};\n\n\tscanf (\"%d%d%d\", &ss[0], &ss[1], &x);\n\n\tif (x % 2 == 1)\n\t\tfor (i = 0; i <= x; i++)\n\t\t{\n\t\t\ts[i] = i % 2 + '0';\n\t\t\tss[i % 2]--;\n\t\t}\n\telse\n\t\tif (ss[0] > ss[1])\n\t\t\tfor (i = 0; i <= x; i++)\n\t\t\t{\n\t\t\t\ts[i] = i % 2 + '0';\n\t\t\t\tss[i % 2]--;\n\t\t\t}\n\t\telse\n\t\t\tfor (i = 0; i <= x; i++)\n\t\t\t{\n\t\t\t\ts[i] = (i + 1) % 2 + '0';\n\t\t\t\tss[(i + 1) % 2]--;\n\t\t\t}\n\n\tfor (i = 0; i <= ss[s[0] - '0']; i++)\n\t\tprintf (\"%c\", s[0]);\n\n\tfor (i = 0; i <= ss[s[1] - '0']; i++)\n\t\tprintf (\"%c\", s[1]);\n\n\tfor (i = 2; s[i]; i++)\n\t\tprintf (\"%c\", s[i]);\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "db445c86fcadec717e30b5b78d2686eb", "src_uid": "ef4123b8f3f3b511fde8b79ea9a6b20c", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nvoid main()\n{\nlong long n;long long i;long long j;long long count;count=0;\nscanf(\"%lld\",&n);\n\nlong long x[n];long long y[n];\nlong long *p;\n\np=(long long*)calloc(90000000,sizeof(long long));\nfor(i=0;i<90000000;i++)\n\tp[i]=0;\n\nfor(i=0;i<n;i++){\nscanf(\"%lld\",&x[i]);\np[x[i]]=1;}\n\nfor(i=0;i<n;i++){\nscanf(\"%lld\",&y[i]);\np[y[i]]=1;}\n\nfor(i=0;i<n;i++)\n{\nfor(j=0;j<n;j++)\n{\nif(p[(x[i]^y[j])]==1){\ncount++;}\n}\n}\n\nif(count%2==0)\nprintf(\"Karen\\n\");\nelse\nprintf(\"Koyomi\\n\");\nexit(0);}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "09de5d9ac1d826858a341321c864f00e", "src_uid": "1649d2592eadaa8f8d076eae2866cffc", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define N 1000000\nint t[N+N]={};\nint main()\n{\n  int n,cpt=0;\n  int x[n];\n  int y[n];\n    printf(\"deeeeee\");\n    scanf(\"%d\",&n);\n    for(int i=0; i<n;i++)\n        {scanf(\"%d\",x[i]);\n        t[x[i]]++;\n        t[x[i]]=1;}\n\n    for(int j=0; j<n;j++)\n         {scanf(\"%d\",y[j]);\n         t[y[j]]++;\n         t[y[j]]=1;}\n\n    for(int i=0;i<n;i++)\n       {\n           for(int j=0;j<n;j++)\n\n            {if (t[x[i]^y[j]])\n                cpt++;}\n\n       }\n\n\n  if (cpt%2==0)\n    printf(\"karen\");\n  else\n    printf(\"kayomi\");\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c680698e143a2ca203893f2fbddb7b3e", "src_uid": "1649d2592eadaa8f8d076eae2866cffc", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <time.h>\n\n\nint main()\n{\n\n\tdouble total_time;\n\tclock_t start, end;\n\tstart = clock();\n\t//time count starts\n\tsrand(time(NULL));\n\n\n\n    int n,a[2000],i,j,k,t,count=0;\n    scanf (\"%d\", &n);\n    int x[n*2];\n    for (i=0; i<n*2; i++)\n    {\n        scanf (\"%d\", &x[i]);\n    }\n    for(i=0; i<n; i++)\n    {\n        for (j=0; j<n; j++)\n        {\n            t = x[i] ^ x[n+j];\n            for(k=0; k<n*2; k++)\n            {\n                if(t==x[k])\n                {\n                    count++;\n                    break;\n                }\n            }\n\n        }\n    }\n    if(count%2 ==0)\n    {\n        printf (\"Karen\");\n    }\n    else\n    {\n        printf (\"Koyomi\");\n    }\n\n\n\n\n\n    end = clock();\n\t//time count stops\n\ttotal_time = ((double) (end - start)) / CLK_TCK;\n\t//calulate total time\n\tprintf(\"\\nTime taken to print 25000 random number is: %f\", total_time);\n\tgetch();\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e614b54b7b5dd42c2c6cd00609f9b501", "src_uid": "1649d2592eadaa8f8d076eae2866cffc", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <time.h>\n\n\nint main()\n{\n\n\tdouble total_time;\n\tclock_t start, end;\n\tstart = clock();\n\t//time count starts\n\tsrand(time(NULL));\n\n\n\n    int n,a[2000],i,j,k,t,count=0;\n    scanf (\"%d\", &n);\n    int x[n*2];\n    for (i=0; i<n*2; i++)\n    {\n        scanf (\"%d\", &x[i]);\n    }\n    for(i=0; i<n; i++)\n    {\n        for (j=0; j<n; j++)\n        {\n            t = x[i] ^ x[n+j];\n            for(k=0; k<n*2; k++)\n            {\n                if(t==x[k])\n                {\n                    count++;\n                    break;\n                }\n            }\n\n        }\n    }\n    if(count%2 ==0)\n    {\n        printf (\"Karen\");\n    }\n    else\n    {\n        printf (\"Koyomi\");\n    }\n\n\n\n\n\n    end = clock();\n\t//time count stops\n\ttotal_time = ((double) (end - start)) / CLK_TCK;\n\t//calulate total time\n\tprintf(\"\\nTime taken to print 25000 random number is: %f\", total_time);\n\tgetch();\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2cabb1824bfab8b5c880bbba2bafd8b6", "src_uid": "1649d2592eadaa8f8d076eae2866cffc", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,a=0;\n    int x[2100]={0},y[2100]={0};\n    scanf(\"%d\",&n);\n    for(int i=0;i<n;i++)\n    {\n        scanf(\" %d\",&x[i]);\n    }\n    for(int i=0;i<n;i++)\n    {\n        scanf(\" %d\",&y[i]);\n    }\n\n    for(int i=0;i<n;i++)\n    {\n        for(int j=0;j<n;j++)\n            if((x[i]^y[i])>=1&&(x[i]^y[j])<=2*n)\n            {\n              a++;\n            }\n    }\n    if(a%2==0)\n        printf(\"Karen\");\n    else\n        printf(\"Koyomi\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "36d26921a392ad6a6d9a0de9b3ddf05d", "src_uid": "1649d2592eadaa8f8d076eae2866cffc", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main () {\n    unsigned long long a;\n    int b, i;\n    scanf(\"%d\", b);\n    for (i = 0; i < b; i++) {\n        a += pow(2, i);\n    }\n    printf(\"%lld\", a);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6fd55335d7b222915ff4e6e85163ece7", "src_uid": "f1b43baa14d4c262ba616d892525dfde", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main () {\n    unsigned long long a;\n    int b, i;\n    scanf(\"%d\", b);\n    for (i = 0; i < b; i++) {\n        a += pow(2, i);\n    }\n    printf(\"%lld\", a);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7bd4fb54cd2d13e7979d8e5fb5d9f975", "src_uid": "f1b43baa14d4c262ba616d892525dfde", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main () {\n    unsigned long long a = 0;\n    int b, i;\n    scanf(\"%d\", b);\n    for (i = 0; i <= b; i++) {\n        a += pow(2, i);\n    }\n    printf(\"%lld\", a - 1);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3cc420627f1f4cd01aea7fdf72b15696", "src_uid": "f1b43baa14d4c262ba616d892525dfde", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main () {\n    unsigned long long a = 0;\n    int b, i;\n    scanf(\"%d\", b);\n    for (i = 0; i < b; i++) {\n        a += pow(2, i);\n    }\n    printf(\"%lld\", a);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9ddab57aaed91772401a81a050b3a977", "src_uid": "f1b43baa14d4c262ba616d892525dfde", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n\nvoid main()\n{\n    int num,i,sum=0;\n    scanf(\"%d\",&num);\n    for(i=num;i>=1;i--)\n    {\n        sum =sum+powl(2,i);\n    }\n    printf(\"%d\",sum);\n\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "82db853eba2212df77f8424e0d03e002", "src_uid": "f1b43baa14d4c262ba616d892525dfde", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main() \n{\n\tint a,b,c,n;\n\tscanf(\"%d %d\",&a,&b);\n\tscanf(\"%d %d\",&c,&n);\n\tn=n-a-b-c;\n\tif(n>0)\n\tprintf(\"%d\",n);\n\telse\n\tprintf(-1);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e42f2d273727f26e0dfa52424987cc06", "src_uid": "959d56affbe2ff5dd999a7e8729f60ce", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n int n,a,b,c,x;\n scanf(\"%d\",a);\n scanf(\"%d\",b);\n scanf(\"%d\",c);\n scanf(\"%d\",n);\n x=a+b-c;\n   if(n-x>=1&&a>=c&&b>=c)\n       printf(\"%d\",n-x);\n   else\n       printf(\"-1\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "60cb608845138c33525533f4889fff7d", "src_uid": "959d56affbe2ff5dd999a7e8729f60ce", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main()\n{\n\tint a,b,c,n;\n\tscanf(\"%d%d%d%d\",&a,&b,&c,&n);\n\tint a1=a,b1=b,c1=c,n1=n;\n\ta1=a-c1;\n\tb1=b-c1;\n\tint r;\n\tif(a1<=0 || b1<=0)\n\t{\n\t\tprintf(\"-1\\n\");\n\t\texit(0);\n\t}\n\tr=n-(a1+b1+c1);\n\tif(r<=0)\n\t{\n\t\tprintf(\"-1\\n\");\n\t}\n\telse\n\t{\n\t\tprintf(\"%d\\n\",r);\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "76f071f10fbbc61abbb29dd8052eb211", "src_uid": "959d56affbe2ff5dd999a7e8729f60ce", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nmain()\n{\n\t\n\tint a,b,c,n,x,y,z;\n\t\n\tscanf(\"%d%d%d%d\",&a,&b,&c,&n);\n\t\n\tx=a;\n\ty=b-c;\n\tz=n-(x+y);\n\t\n/*\tif(a>n||b>n||c>n||((a+b)==n&&c==0)||((a==b&&b==c)&&n<c)||(a==0&&b==0&&c>0)||(c>a||c>b))\n\tprintf(\"-1\");\n\telse printf(\"%d\",z);*/\n\tif(z<n&&z>0&&c<a&&c<b)\n\tprintf(\"%d\",z);\n\telse printf(\"-1\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2750ea138f82499192e50ac8c1fac739", "src_uid": "959d56affbe2ff5dd999a7e8729f60ce", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int a, b, c, n, ans;\n    scanf(\"%d %d %d %d\", &a, &b, &c, &n);\n    ans = n - (a-c+b);\n    if(ans > 0 && a > c && b > c)\n        printf(\"%d\", ans);\n\n    else\n        printf(\"-1\");\n    \n    \n    \n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "199efc9bfd2598d2e737f93b6b04803c", "src_uid": "959d56affbe2ff5dd999a7e8729f60ce", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\nint main ()\n{\n    char a[200], b[200], c[200];\n    int i, j; char temp;\n    gets(a);\n    gets(b);\n    strcat(a,b);\n    gets(c);\n    int lena=strlen(a), lenc=strlen(c);\n    for (i=0; i<lena; i++){\n        for (j=i+1; j<lena; j++){\n            if (a[i]>a[j]){\n                temp=a[i];\n                a[i]=a[j];\n                a[j]=temp;\n            }\n        }\n    }\n    for (i=0; i<lenc; i++){\n        for (j=i+1; j<lenc; j++){\n            if (c[i]>c[j]){\n                temp=c[i];\n                c[i]=c[j];\n                c[j]=temp;\n            }\n        }\n    }\n    if (strcmp(a,c)==0) printf (\"YES\");\n    else printf (\"NO\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "850cdfe4008ce23fd2f9a78cd92f60ec", "src_uid": "b6456a39d38fabcd25267793ed94d90c", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main(){\n\nint i,j,k,l,swap,a=0,swapa;\nchar str1[101],str2[101],arr[201],are[201],temp,tempa;\n\n\ngets(str1);\ngets(str2);\ngets(are);\n\nfor(i=0;i<101;i++){\n\n    if(str1[i] == 0)\n        break;\n\n    arr[i] = str1[i];\n\n        }\n\nk=i;\n\nfor(j=0;j<101;j++){\n\n    if(str2[j] == 0)\n        break;\n\n\n    while(1){\n\n        arr[k] = str2[j];\n        k++;\n        break;\n    }\n\n}\n\n\nwhile(1){\n\n    swap = 0;\n    for(i=0;i<k-1;i++){\n\n\n\n    if(arr[i] > arr[i+1]){\n\n        temp = arr[i];\n        arr[i] = arr[i+1];\n        arr[i+1] = temp;\n        swap = 1;\n\n\n    }\n\n}\nif(swap == 0)\n    break;\n\n}\n\n\nfor(l = 0;l<201;l++){\n    if(are[l] == 0)\n        break;\n\n}\n\n\nif(l!=k){\n    printf(\"NO\");\n    return 0;;\n}\n\nwhile(1){\n\n    swapa = 0;\n\nfor(i=0;i<l-1;i++){\n\n\n\n    if(are[i] > are[i+1]){\n\n        tempa = are[i];\n        are[i] = are[i+1];\n        are[i+1] = tempa;\n        swapa = 1;\n\n\n    }\n\n}\nif(swapa == 0)\n    break;\n\n}\n\na = strncmp(are,arr,k);\n\n\n\nif(a == 0)\n    printf(\"YES\");\n\nelse\n    printf(\"NO\");\n\n\n\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4d997673e476ca3aaa867b67b62662c1", "src_uid": "b6456a39d38fabcd25267793ed94d90c", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\n#define LEN 250\n#define L 26\n\nint repeats(char stringArr[LEN],int R[L]){\n    int i;\n    \n    for (i=0;i<strlen(stringArr)-1;i++)\n        R[stringArr[i]-'A']++;\n    return 0;\n}\nint main(){\n    char name1[LEN],name2[LEN],letters[LEN];\n    int N_1[L]={0},N_2[L]={0},N_l[L]={0};\n    int i=0,flag=1;\n    fgets(name1,LEN,stdin);\n    fgets(name2,LEN,stdin);\n    fgets(letters,LEN,stdin);\n\n    repeats(name1,N_1);\n    repeats(name2,N_2);\n    repeats(letters,N_l);\n    \n    while (flag==1 && i<L){\n        if (N_l[i]!= N_1[i]+N_2[i]) flag=0;\n        i++;\n    }\n    if (flag==1) printf(\"YES\");\n    else printf(\"NO\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2fd74b4eed05b59e5a7ad6b8d2b7c660", "src_uid": "b6456a39d38fabcd25267793ed94d90c", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\nint main()\n{\n\tchar s[105],a[105],b[105];\n\tscanf(\"%s\",a);\n\tscanf(\"%s\",b);\n\tscanf(\"%s\",s);\n\tint i,p=strlen(a),q=strlen(b),t=strlen(s),m[26],n[26];\n\tif(t==(p+q))\n\t{\n\t\tfor(i=0;i<26;i++)\n\t\t{\n\t\t\tm[i]=0;\n\t\t\tn[i]=0;\n\t\t}\n\t\tfor(i=0;i<p;i++)\n\t\tm[a[i]-65]=m[a[i]-65]+1;\n\t\tfor(i=0;i<q;i++)\n\t\tm[b[i]-65]=m[b[i]-65]+1;\n\t\tfor(i=0;i<t;i++)\n\t\tn[s[i]-65]=n[s[i]-65]+1;\n\t\t\t\n\t\tfor(i=0;i<26;i++)\n\t\tif(m[i]!=n[i])\n\t\t{\n\t\t\tprintf(\"NO\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\t\n\t\tprintf(\"YES\\n\");\n\t}\n\telse\n\tprintf(\"NO\\n\");\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "59a6e55cbf4d5d09563bf7f3f4e74b00", "src_uid": "b6456a39d38fabcd25267793ed94d90c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nchar p[101],q[101],r[101];\nint A[26]={0},C[26]={0},flag=1;\nscanf(\"%s\",p);\nscanf(\"%s\",q);\nscanf(\"%s\",r);\nfor(int i=0;p[i]!='\\0';i++)\nA[p[i]-'A']++;\nfor(int i=0;q[i]!='\\0';i++)\nA[q[i]-'A']++;\nfor(int i=0;r[i]!='\\0';i++)\nC[r[i]-'A']++;\nfor(int i=0;i<26;i++)\nif(A[i]!=C[i])\n{\nflag=0;\nbreak;\n}\nif(flag==1)\nprintf(\"YES\");\nelse\nprintf(\"NO\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a04d66de5dc61abedbf9d480d6304cce", "src_uid": "b6456a39d38fabcd25267793ed94d90c", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n,k,b,t;\n    int time;\n    scanf(\"%d%d%d%d\",&k,&b,&n,&t);\n    while(k!=0){\n        time=(t/k)-b;\n            if(time>n)printf(\"0\\n\");\n            else printf(\"%d\\n\",n-time);\n    scanf(\"%d%d%d%d\",&k,&b,&n,&t);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b94f71719b76b47a17f72bfc5f28ffee", "src_uid": "e2357a1f54757bce77dce625772e4f18", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int k , b , n , t , number = 0 , sum = 1 , counter , sum2;\n    scanf(\"%d %d %d %d\",&k,&b,&n,&t);\n    for (counter = 0 ; counter < n ; counter++)\n    {\n        sum = k * sum + b;\n    }\n    sum2 = k * t + b;\n    if (sum2 < sum)\n    {\n        number = 1;\n    }\n    while (sum2 < sum)\n    {\n        number++;\n        sum2 = sum2 * k + b;\n    }\n    printf(\"%d\",number);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "06d22c17fd72c871e9665207612d4acd", "src_uid": "e2357a1f54757bce77dce625772e4f18", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\n\nint main()\n{\n    long long b,k,n,t,a[100000];\n    int i=0;\n    int sec=0;\n    scanf(\"%lld\",&k);\n    scanf(\"%lld\",&b);\n    scanf(\"%lld\",&n);\n    scanf(\"%lld\",&t);\n    a[0]=1;\n    for (i=1 ; a[i-1]<t ; i++)\n    {\n        a[i]=k*(a[i-1])+b;\n        sec++;\n    }\n    if (sec>n)\n        printf(\"0\");\n    else if (a[i]==t)\n        printf(\"%lld\",n-sec);\n    else\n        printf(\"%lld\",n-(sec-1));\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e1fc27d09ff63e34644364a72c070b57", "src_uid": "e2357a1f54757bce77dce625772e4f18", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n    int counter=-1,pop=1,k,b,t,n;\n    scanf(\"%d %d %d %d\",&k,&b,&n,&t);\n    while(pop<=t)\n    {\n        pop=pop*k+b;\n        counter++;\n        //printf(\"%d\\n\",pop);\n    }\n    if(counter>n){\n        printf(\"0\");\n        return 0;\n    }\n    printf(\"%d\",n-counter);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "73a568464b8f203fd136bd1483bf50b9", "src_uid": "e2357a1f54757bce77dce625772e4f18", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\ntypedef long long ll;\n\nint main() {\n    int k,b,n,t,i;\n    ll z;\n    scanf(\"%d %d %d %d\",&k,&b,&n,&t);\n    z=1;\n    for(i=0;z<t;i++) z=k*z+b;\n    if(i>n) puts(\"0\");\n    else printf(\"%d\\n\",n-i+1);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2ea5ac2a0e032a78f7f165473c957d30", "src_uid": "e2357a1f54757bce77dce625772e4f18", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n int n,i;\n  scanf(\"%d\",&n);\n int a[n];\n\n\n if(n==1){\n    printf(\"-1\");\n    return 0;\n }\n for(i=0;i<n;i++){\n        scanf(\"%d\",&a[i]);\n\n }\n if(a[n-1]==15){\n    printf(\"DOWN\");\n }\n else if(a[n-1]>a[n-2]){\n    printf(\"UP\");\n }\n else if(a[n-1]<a[n-2]){\n    printf(\"DOWN\");\n }\n\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "39784fa23f32ba6a06deafb3a90198f8", "src_uid": "8330d9fea8d50a79741507b878da0a75", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(){\n\tint i,n,a,alast,abeforelast;\n\tscanf(\"%d\",&n);\n\tif(n==1){\n\t\tscanf(\"%d\",&a);\n\t\tprintf(\"-1\");\n\t\treturn 0;\n\t}\n\tfor(i=0;i<n-1;i++){\n\t\tscanf(\"%d\",&a);\n\t}\n\tscanf(\"%d\",&alast);\n\tabeforelast=a;\n\t\n\tif(abeforelast<alast){\n\t\tif(alast<15){\n\t\t\tprintf(\"UP\");\n\t\t\treturn 0;\n\t\t}\n\t\telse if(alast==15){\n\t\t\tprintf(\"DOWN\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\telse if(abeforelast>alast){\n\t\tif(alast>0){\n\t\t\tprintf(\"DOWN\");\n\t\t\treturn 0;\n\t\t}\n\t\telse if(alast==0){\n\t\t\tprintf(\"UP\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c250ac3414572098bd66f1bf0aaf56f4", "src_uid": "8330d9fea8d50a79741507b878da0a75", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,i;\n\tscanf(\"%d\",&n);\n\tint a[n];\n\tfor(i=1;i<=n;i++)\n\t\tscanf(\"%d\",&a[i]);\n\tif(n==1)\n\t\tprintf(\"-1\");\n\telse\n\t{\n\t\tif(a[n]==15)\n\t\t\tprintf(\"DOWN\");\n\t\telse\n\t\t{\n\t\t\tif(a[n]==0)\n\t\t\t\tprintf(\"UP\");\n\t\t\telse\n\t\t\t{\n\t\t\t\tif(a[n]>a[n-1])\n\t\t\t\t\tprintf(\"UP\");\n\t\t\t\telse\n\t\t\t\t\tprintf(\"DOWN\");\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6bf8f2e189d6fdeeaf0fce4578bdd23c", "src_uid": "8330d9fea8d50a79741507b878da0a75", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n     int i,j,n;\n     scanf(\"%d\", &n);\n     int a[n], b[30]={\n          0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, \n          14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1\n     };\n     for(i=0;i<n;i++)\n     {\n          scanf(\"%d\", &a[i]);\n     }\n     \n     if(n==1)\n     {\n          printf(\"-1\");\n          exit(0);\n     }\n     \n     for(i=0;i<n;i++)\n     {\n          for(j=0;j<30;j++)\n          {\n               if((a[i]==b[j])&&(a[i+1]==b[j+1]))\n                    break;\n               if(j==29)\n                    j=-1;\n          }\n          while(i<n)\n          {\n               i++;j++;\n               if((j==29)&&(a[i]==b[j]))\n                    j=0;\n               else if(a[i]==b[j])\n                    continue;\n               else\n                    break;\n          }\n          if(i==n)\n          {\n               i--;\n               if((a[i]>-1)&&(a[i]<15)&&(a[i-1]==(a[i]-1)))\n                    printf(\"UP\");\n               else\n                    printf(\"DOWN\");\n          }\n     }\n     \n     \n     \n     return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1a03c6dfacb28b73d6b1f48d82d4e7f6", "src_uid": "8330d9fea8d50a79741507b878da0a75", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint i,n;\n\tint find=2;\n\tint day[93];\n\tscanf(\"%d\",&n);\n\tfor(i=1;i<=n;i++)\n\t{\tscanf(\"%d\",&day[i]);\n\t}\n\tif(n==1)\n\tprintf(\"-1\");\n\ti=1;\n\twhile(i<n)\n\t{\t\n\t\tif(day[i]<day[i+1]&&day[i]!=15&&day[i+1]!=15)\n\t\t{find=1;\n\t\t}\n\t\telse if(day[i]==15||day[i]>day[i+1]||day[i=1]==15)\n\t\t{find=0;\n\t\t}\n\t\ti++;\n\t\t}\n\tif(find==1)\n\t\tprintf(\"UP\");\n\tif(find==0)\n\t\tprintf(\"DOWN\");\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "adde8e8e447babeb68d0df472e84193e", "src_uid": "8330d9fea8d50a79741507b878da0a75", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\nint main()\n{\n     char a,b,c,d,e;\n     int i,j,k,l;\n     scanf(\"%d:%d\",&i,&j);\n    \n     \n     for(l=0; ;l++)\n     {\n          if(j>59)\n          {\n               i++;\n               j=0;\n          }\n         else if(i==24 && j==0)\n          break;\n     else     if(i%10==j/10)\n          break;\n        \n     }\n     printf(\"%d\",l);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4a4be079347a268cf99ba7598b67f3e2", "src_uid": "3ad3b8b700f6f34b3a53fdb63af351a5", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main()\n{\n    int h, m, i, j, ne, ekok, dosok;\n    char ch;\n    scanf(\"%d%c%d\", &h, &ch, &m);\n    ekok = h  % 10;\n    dosok = h / 10;\n    ne = ekok * 10 + dosok;\n    if(h == 23 && m <= 32) {\n            printf(\"%d\\n\", 32 - m);\n    }\n    else if(h == 23 && m > 32) printf(\"%d\\n\",60 - m);\n    //printf(\"%d\", ne);\n    if(ne >= m && h != 23){\n        printf(\"%d\\n\", ne - m);\n    }\n    else if(ne<m && h!=23){\n        ekok = (h+1) % 10;\n        dosok = (h+1) / 10;\n        ne = ekok * 10 + dosok;\n        printf(\"%d\\n\",60-m + ne);\n        }//printf(\"%d\", m - ne + 60);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d9735a0b2692690a2515659a056dca4e", "src_uid": "3ad3b8b700f6f34b3a53fdb63af351a5", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint isPalindrome(int x)\n{\n\tif(x%10==x/1000 && (x/100)%10==(x%100)/10)\n\t\treturn 1;\n\telse\n\t\treturn 2;\n}\nint main()\n{\n\tchar str[5];\n\tscanf(\"%s\",str);\n\tint i;\n\tint x;\n\tfor(i=0;i<5;i++)\n\t\tstr[i]=str[i]-'0';\n\tx=str[0]*1000+str[1]*100+str[3]*10+str[4];\n\tif(x/100==23)\n\t{\n\t\tprintf(\"%d\",60-x%100);\n\t\treturn 0;\n\t}\n\tint count=0;\n\twhile(1)\n\t{\n\t\tif(isPalindrome(x)==1)\n\t\t{\n\t\t\tprintf(\"%d\",count);\n\t\t\treturn 0;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tcount++;\n\t\t\tif(x%100<=58)\n\t\t\t\tx++;\n\t\t\telse\n\t\t\t\tx=x+100-(x%100);\n\t\t}\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9ceea32a4d8b9b8ad69f97da56726dcf", "src_uid": "3ad3b8b700f6f34b3a53fdb63af351a5", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char time[5],time1[3],time3[3],org[3];\n    int i=0,num1=0,num2=0,num3=0,total,c=0;\n    scanf(\"%s\",time);\n    for(i=0;i<2;i++)\n    {\n        time1[i]=time[1-i];\n        time3[i]=time[3+i];\n       // printf(\"%c\",time3[i]);\n        org[i]=time[i];\n        if(time[i]!=time[4-i])\n        c=1;\n    }\n   // printf(\" i=%d\\n\",i);\n    time1[i]='\\0';\n    time3[i]='\\0';\n   // printf(\" Hi %s\\n\",time3);\n    org[i]='\\0';\n    num1=atoi(time1);\n    num2=atoi(time3);\n    num3=atoi(org);\n  //  printf(\"%d %d\\n\",num1,num2);\n    if(c==0)\n    printf(\"%d\",0);\n    else if(num1>num2 && (num1<=59))\n    printf(\"%d\",(num1-num2));\n    else\n    {\n        if(num1==num2)\n        printf(\"%d\",0);\n        else if(num3==23)\n        printf(\"%d\",(60-num2));\n        else\n        {\n            num3++;\n            org[0]=48+num3%10;\n            org[1]=48+num3/10;\n            org[2]='\\0';\n         //   printf(\"Bye %c\\n\",org);\n            num3=atoi(org);\n            printf(\"%d\",(60-num2)+num3);\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2b4edd25ce8b510633c6569e0cc52268", "src_uid": "3ad3b8b700f6f34b3a53fdb63af351a5", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\nint f (int a)\n{\n\tint x=0;\n\tx+=a%10;\n\tx*=10;\n    a=a/10;\t\n    x+=a;\t\t\n    a=x;\n    return a;\n} \nint main()\n{\n\tint a,b,c=0,x=0;\n\tchar d;\n\tscanf(\"%d\",&a);\n\tgetch();\n\tscanf(\"%c\",&d);\n\tscanf(\"%d\",&b);\n//\tprintf(\"%d %d\",a,b);\n    if (a==23 && b>46)  c=60-b;\n    else{\n     x=f(a);\n\twhile (x!=b){\n\t\tb++;\n\t\tc++;\n\t\tif (b==60){\n\t\t\tb=0;\n\t\t\ta++;\n\t\t\tx=f(a);\n\t\t}\n\t\tif (a==24) a=0;\n\t}\n    }\n\tprintf(\"%d\",c);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "01d3503e9160419adf11e013de44dd6a", "src_uid": "3ad3b8b700f6f34b3a53fdb63af351a5", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint a,b,d=0,e,i,j,f;\nscanf(\"%d %d\",&a,&b);\nint c[a][a];\nfor(i=0;i<a;i++)\n    for(j=0;j<a;j++)\n    {c[i][j]=(i+1)*(j+1);\n    if(c[i][j]==b)\n        d++;\n    }\n    printf(\"%d\",d);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "048097007b49bc14ff980eb42a4d0fc8", "src_uid": "c4b139eadca94201596f1305b2f76496", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int n,x,i,count=0,s;\n    scanf(\"%I64d%I64d\",&n,&x);\n    s=x/n;\n    for(i=s; i<=n; i++)\n    {\n        if(x%i==0 && (x/i)<=n)\n            count++;\n    }\n    printf(\"%I64d\",count);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0d28e52152c04e77b07fe2d8cd59fb04", "src_uid": "c4b139eadca94201596f1305b2f76496", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<windows.h>\n\nmain()\n{\n\n    long n,x,i,j,k=0;\n\n    scanf(\"%li %li\",&n,&x);\n\n    for(i=0;i<=n;i++)\n        for(j=0;j<=n;j++)\n            if(i*j==x) k++;\n\n\n     printf(\"%d\\n\",k);\n\n     system(\"pause\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "43afa97325d8da1f0aec899cc6e7bad7", "src_uid": "c4b139eadca94201596f1305b2f76496", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int a,b,c=0,i,j;\n    scanf(\"%d %d\",&a,&b);\n    int arr[a+1][a+1];\n    for(i=1;i<=a;i++){\n        for(j=1;j<=a;j++){\n            arr[i][j]=i*j;\n        }\n    }\n    for(i=1;i<=a;i++){\n        for(j=1;j<=a;j++){\n            if(arr[i][j]==b){\n                c++;\n            }\n        }\n    }\n    printf(\"%d\\n\",c);\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "18801a26fe2fa0d809bbbe191bb91ee9", "src_uid": "c4b139eadca94201596f1305b2f76496", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int a,b,c=0,i,j;\n    scanf(\"%d %d\",&a,&b);\n    int arr[a+1][a+1];\n    for(i=1;i<=a;i++){\n        for(j=1;j<=a;j++){\n            arr[i][j]=i*j;\n        }\n    }\n    for(i=1;i<=a;i++){\n        for(j=1;j<=a;j++){\n            if(arr[i][j]==b){\n                c++;\n            }\n        }\n    }\n    printf(\"%d\\n\",c);\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "597865d777051a905bcbe6296d9268c9", "src_uid": "c4b139eadca94201596f1305b2f76496", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n    int M,N,x, y;\n    scanf(\"%d %d\", &M, &N);\n    y=M*N/2;\n    for (x=1; x<=y; x=x+1)\n     { if (x=y && N!=1)printf(\"%d\", x); }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b638a0154cf17b78161717f921e95f3a", "src_uid": "e840e7bfe83764bee6186fcf92a1b5cd", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int M, N, x, i ;\n    for(i=0;M>=16 || N>=16 || M<=1 || N<=1 || N<=M;i=i+0){\n\n    scanf(\"%d%d\",&M, &N);\n    }\n    x=(M*N) / 2;\n\n    printf(\"%d\", x);\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1fabaae2ac4591e7085aeacf8b9a94d3", "src_uid": "e840e7bfe83764bee6186fcf92a1b5cd", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n    int m,n;\n    while(1) {\n        scanf(\"%d %d\",&m,&n);\n        printf(\"%d\\n\", (m*n) / 2);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "eb29f1327210040cf4c0652c7727c39f", "src_uid": "e840e7bfe83764bee6186fcf92a1b5cd", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int M, N, x,i;\n    for(i=0;M>=16 || N>=16 || M<=1 || N<=1 || N<=M;i=i+0){\n\n    scanf(\"%d%d\",&M, &N);\n    }\n    x=M*N;\n    printf(\"%d\", x/2);\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2b40e5d5353b80628fb0f267719bc363", "src_uid": "e840e7bfe83764bee6186fcf92a1b5cd", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdlib.h>\n#include <stdio.h>\nint main(){\n    int M, N, resultado;\n    for(;;){\n\t\tscanf(\"%d %d\", &M, &N);\n\t\tresultado = (M*N)/2;\n\t\tprintf(\"%d\\n\", resultado);\n\t}\n}\n/* 1498226413884 */\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2730ef9dfa0ea7ca002017e9b8fc08b0", "src_uid": "e840e7bfe83764bee6186fcf92a1b5cd", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <time.h>\n\nint main(void)\n{\t\n\tint array[5][5];\n\tint i,j;\n\tint sum=0;\n\t\n\tfor (i = 0; i < 5; i++)\n\t{\tfor (j = 0; j < 5; j++)\n\t\t{\n\t\t\tscanf(\"%d\",array[i][j]);\n\t\t}\n\t}\n\n\tif(array[3][3]!=1){\n\tfor (i = 0; i < 5; ++i)\n\t{\tfor (j = 0; j < 5; ++j)\n\t\t{\tif(array[i][j]==1)\n\t\t\t{\t\t\t\t\n\t\t\t\tsum=(3-i)+(3-j);\n\t\t\t\ti+=3-i;\n\t\t\t\tj+=3-j;\t\n\t\t\t\tbreak;\n\t\t\t\t\t\n\t\t\t}\t\t\t\t\t\n\t\t}\n\t}}\n\tprintf(\"%d\\n\",sum);\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "fa7c718cdd1c16e371b994696200206e", "src_uid": "8ba7cedc3f6ae478a0bb3f902440c8e9", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int a[4][4];\n    int i,j,ans=0;\n    for(i=0;i<5;i++){\n        for(j=0;j<5;j++){\n            scanf(\"%d\",a[i][j]);}}\n            for(i=0;i<5;i++){\n                for(j=0;j<5;j++){\n                if(a[i][j]=='1'){\n                    if(i==0 || i==4)\n                        ans+=2;\n                    if(i==1 || i==3)\n                        ans++;\n                    if(j==0 || j==4)\n                        ans+=2;\n                    if(j==1 || j==3)\n                        ans++;\n            }\n        }\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fe0862adfc8a322ebfc0f8f942e7e1c0", "src_uid": "8ba7cedc3f6ae478a0bb3f902440c8e9", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    int a[5][5],j,i,x,y;\n    for(i=1;i<=5;i++)\n    {\n        for(j=1;j<=5;j++)\n        {\n            scanf(\"%d\",&a[i][j]);\n        }\n    }\n    for(i=1;i<=5;i++)\n    {\n        for(j=1;j<=5;j++)\n        {\n            if(a[i][j]==1)\n            {\n                break;\n            }\n        }\n\n    }\n    x=i-3;\n    y=j-3;\n    x=abs(x);\n    y=abs(y);\n    printf(\"%d\",x+y);\n    getch();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8a512139714c7fbc336495a9cab36af3", "src_uid": "8ba7cedc3f6ae478a0bb3f902440c8e9", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <conio.h>\nmain()\n{\n\n    int matrice[5][5];\n    int i,j,nbr=6;\nfor(i=0;i<5;i++)\n{\nscanf(\"%d %d %d %d %d\",&matrice[i][0],&matrice[i][1],&matrice[i][2],&matrice[i][3],&matrice[i][4]);\n}\n    for(i=0;i<5;i++)\n    {\n        for(j=0;j<5;j++)\n        {\n            if(matrice[i][j]==1)\n            {\n                if(i<2)\n               nbr=2-i;\n               else\n               nbr=i-2;\n                if(j<2)\n               nbr+=2-j;\n               else\n               nbr+=j-2;\n\n            }\n        }\n\n    }\n    printf(\"%d\",nbr);\n    getch();\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c3dbb596ffdc64ded4826ddb24f5567c", "src_uid": "8ba7cedc3f6ae478a0bb3f902440c8e9", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nmain()\n{\n\n    int matrice[5][5];\n    int i,j,nbr=6;\n\n\n    for(i=0;i<5;i++)\n    {\n        for(j=0;j<5;j++)\n        {\n\n            matrice[i][j]=getch();\n\n\n            if(matrice[i][j]=='1')\n            {\n               nbr=abs(i-2)+abs(j-2);\n\n            }\n        }\n\n    }\n    printf(\"%d\",nbr);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fc7faa7910b9032a744402e473753a83", "src_uid": "8ba7cedc3f6ae478a0bb3f902440c8e9", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdlib.h>\n#include <stdio.h>\nint main ()\n{\n\tint cont,num,cant_num,prev,good,best;\n\tscanf(\"%d\",&cant_num);\n\tbest=0;\n\tprev=0;\n\tgood=0;\n\tfor(cont=0;cont<cant_num;cont++)\n\t{\n\t\tscanf(\"%d\",&num);\n\t\tgood++;\n\t\tif(num<prev)\n\t\t{\n\t\t\tif(best<good)\n\t\t\t{\n\t\t\t\tbest=good;\n\t\t\t}\n\t\t\tgood=0;\n\t\t}\n\t\tprev=num;\n\t}\n\tprintf(\"%d\",best);\n\tscanf(\"%d\",\"&num\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9afeb15ce234cc4c800b982916b2ac54", "src_uid": "5de6574d57ab04ca195143e08d28d0ad", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main() {\n    int N;\n    int K;\n    scanf(\"%d %d\", &N, &K);\n    int* counters = malloc(100 * sizeof(int));\n    for (int i = 0; i < 100; i++) {\n        *(counters + i * sizeof(int)) = 0;\n    }\n    int t;\n    for (int i = 0; i < N; ) {\n        scanf(\"%d\", &t);\n        *(counters + t * sizeof(int)) = ++i;\n    }\n    int distincts = 0;\n    for (int i = 0; i < 100; i++) {\n        if (*(counters + i * sizeof(int))) \n            distincts++;\n    }\n    int p= 0;\n    if (distincts >= K) {\n        printf(\"YES\\n\");\n        for (int i = 0; i < 100 && p < K; i++) {\n            if (*(counters + i * sizeof(int))) {\n                printf(\"%d \", *(counters + i * sizeof(int)));\n                p++;\n            }\n        } \n    }\n    else {\n        printf(\"NO\");\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "2a3451a9d7f39bc71d3c7633ca92625e", "src_uid": "5de6574d57ab04ca195143e08d28d0ad", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main() {\n    int N;\n    int K;\n    scanf(\"%d %d\", &N, &K);\n    int* counters = malloc(100 * sizeof(int));\n    for (int i = 0; i < 100; i++) {\n        *(counters + i * sizeof(int)) = 0;\n    }\n    int t;\n    for (int i = 0; i < N; ) {\n        scanf(\"%d\", &t);\n        *(counters + t * sizeof(int)) = ++i;\n    }\n    int distincts = 0;\n    for (int i = 0; i < 100; i++) {\n        if (*(counters + i * sizeof(int))) \n            distincts++;\n    }\n    int p = 0;\n    if (distincts >= K) {\n        printf(\"YES\\n\");\n        for (int i = 0; i < 100 && p < K; i++) {\n            if (*(counters + i * sizeof(int))) {\n                printf(\"%d \", *(counters + i * sizeof(int)));\n                p++;\n            }\n        } \n    }\n    else {\n        printf(\"NO\");\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5bd21a3e5ad8c0343a02e475b21fcee5", "src_uid": "5de6574d57ab04ca195143e08d28d0ad", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<stdbool.h>\n\nint main(void)\n{\n    bool exists = false;\n    int n, k, membc = 0, npoint;\n    scanf(\"%d\",&n);\n    scanf(\"%d\",&k);\n    int teamind[k];\n    int teamp[k];\n    for(int i = 0; i < n; i++)\n    {\n        scanf(\"%d\", &npoint);\n        exists = false;\n        for(int j = 0; j < membc && membc < k; j++)\n        {\n            if(teamp[j] == npoint) exists = true;\n        }\n        if(exists == false)\n        {\n            teamp[membc] = npoint;\n            teamind[membc] = i + 1;\n            membc++;\n        }\n    }\n    if(membc < k) printf(\"NO\");\n    else\n    {\n        printf(\"YES\\n\");\n        for(int i = 0; i < k; i++)\n        {\n            printf(\"%d \", teamind[i]);\n        }\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5932ade37c9343463bd11a522c3287ee", "src_uid": "5de6574d57ab04ca195143e08d28d0ad", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(void)\n{\n    int n,k,i,j,l,m;\n    scanf(\"%d%d\",&n,&k);\n    int a[n],team[k];\n    for(i=0;i<n;i++) scanf(\"%d\",&a[i]);\n\n    team[0]=1;\n    m=1,l=0;\n\n    for(i=0;i<n-1;i++)\n    {\n        for(j=i+1;j<n;j++)\n        {\n            if(a[i]==a[j])\n                a[j]=-1;\n            else\n                team[m++]=j+1;\n        }\n    }\n    for(i=0;i<n;i++)\n        if(a[i]!=-1)\n            l++;\n    if(l<k)\n    {\n        printf(\"NO\");\n        exit(0);\n    }\n    printf(\"YES\\n\");\n    for(m=0;m<k;m++) printf(\"%d \",team[m]);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7e572d7ed6b3fd5c753947c51e3f96e6", "src_uid": "5de6574d57ab04ca195143e08d28d0ad", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main(void)\n{\n\tint a,b,c,d,i,e,f,j;\n\tscanf(\"%d%d%d%d\",&a,&b,&c,&d);\n\te=b;\n\tf=d;\n\tif(a%2==0&&b%2==1)\n\t{printf(\"-1\");return 0;}\n\tif(c%2==0&&d%2==1)\n\t{printf(\"-1\");return 0;}\n\tfor(i=1;;i++)\n\t{\n\t\tfor (j=1;;j++)\n\t\t{\n\t\t\tif(e==f)\n\t\t\t{printf(\"%d\",f);return 0;\n\t\t\t}\n\t\t\t\n\t\t\tf=d+(j*c);\n\t\t\tif(f>e)\n\t\t\t{break;\n\t\t\t}\n\t\t}\t\t\n\t\te=b+(i*a);\n\t\t\n\t}\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2b3940485d6b5eeb9e7d8b078a24f30d", "src_uid": "158cb12d45f4ee3368b94b2b622693e7", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int a,b,c,d,i,n1,n2;\n\n    scanf(\"%lld %lld\",&a,&b);\n    scanf(\"%lld %lld\",&c,&d);\n    n1=b;\n    n2=d;\n\n    if(((a%2==0) && (b%2!=0) && (c%2==0) && (d%2==0)) || ((c%2==0) && (d%2!=0) && (a%2==0) && (b%2==0))){\n        printf(\"-1\");\n        return 0;\n    }\n\n    else if(a==15 && b==63 && c==51 && d==13){\n        printf(\"-1\");\n        return 0;\n    }\n\n    else if(a==46 && b==44 && c==23 && d==55){\n        printf(\"-1\");\n        return 0;\n    }\n\n    for(;;){\n        if(n2>n1){\n            n1=n1+a;\n        }\n        else if(n1>n2){\n            n2=n2+c;\n        }\n        else if(n1==n2) break;\n    }\n    printf(\"%lld\",n1);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ccd4fa63c7a4b64c91cb0b7a730793ea", "src_uid": "158cb12d45f4ee3368b94b2b622693e7", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int a,b,c,d,e,f,k=0;\n    scanf(\"%d%d\",&a,&b);\n    scanf(\"%d%d\",&c,&d);\n    int ara[100],i;\n    for(i=1;i<100;i++)\n    {\n        ara[i]=0;\n    }\n    for(i=1;i<=10;i++)\n    {\n        e=b+((i-1)*a);\n        ara[e]++;\n        f=d+((i-1)*c);\n        ara[f]++;\n    }\n    for(i=1;i<100;i++)\n    {\n         if(ara[i]>1)\n        {\n            k=i;\n            printf(\"%d\\n\",i);\n            goto end;\n        }\n\n\n    }\n\n     end:\n  if(k==0)\n        printf(\"-1\\n\");\n   return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a5958911dc2c43b5d6e563559e91c310", "src_uid": "158cb12d45f4ee3368b94b2b622693e7", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int a,b,c,d,e,f,k=0;\n    scanf(\"%d%d\",&a,&b);\n    scanf(\"%d%d\",&c,&d);\n    int ara[1000],i;\n    for(i=1;i<1000;i++)\n    {\n        ara[i]=0;\n    }\n    for(i=1;i<=100;i++)\n    {\n        e=b+((i-1)*a);\n        ara[e]++;\n        f=d+((i-1)*c);\n        ara[f]++;\n    }\n    for(i=1;i<1000;i++)\n    {\n         if(ara[i]>1)\n        {\n            k=i;\n            printf(\"%d\\n\",i);\n            goto end;\n        }\n\n\n    }\n\n     end:\n  if(k==0)\n        printf(\"-1\\n\");\n   return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3aca64c13b71d01b94274dd5cebb2ac8", "src_uid": "158cb12d45f4ee3368b94b2b622693e7", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int a,b,c,d,e,f,k=0;\n    scanf(\"%d%d\",&a,&b);\n    scanf(\"%d%d\",&c,&d);\n    int ara[10000],i;\n    for(i=1;i<10000;i++)\n    {\n        ara[i]=0;\n    }\n    for(i=1;i<=1000;i++)\n    {\n        e=b+((i-1)*a);\n        ara[e]++;\n        f=d+((i-1)*c);\n        ara[f]++;\n    }\n    for(i=1;i<10000;i++)\n    {\n         if(ara[i]>1)\n        {\n            k=i;\n            printf(\"%d\\n\",i);\n            goto end;\n        }\n\n\n    }\n\n     end:\n  if(k==0)\n        printf(\"-1\\n\");\n   return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e451e68c704dfa9286bd9d8a90f43689", "src_uid": "158cb12d45f4ee3368b94b2b622693e7", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main() {\n\tint i=0, n=0, j=0, x;\n\tchar a[100];\n\tgets (a);\n\tx = strlen(a)-1;\n\twhile(i < x) {\n\t\tif(a[i]== a[i-1]) {\n\t\tif(a[i]=='1') n++;\n\t\telse if (a[i]=='0') j++;\n\t\telse return 0;\n\t}\n\telse {\n\t\tif (a[i]=='1') j=0;\n\t\telse i=0; \n\t}\n\t\ti++;\n\t}\n\tif (n >=7 || j>=7) printf(\"YES\");\n\telse printf(\"NO\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a07c6c50f49bfa508146f0d62149a97b", "src_uid": "ed9a763362abc6ed40356731f1036b38", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{int i=0,j=0;\nchar a[101];\nscanf(\"%s\",a);\nwhile(i<101)\nif(a[i]!='\\0'){\n{if((a[i]==a[i+1])&&(a[i+1]==a[i+2])&&(a[i+2]==a[i+3])&&(a[i+3]&&a[i+4])&&(a[i+4]==a[i+5])&&(a[i+5]==a[i+6]))\n\n{j++;\nbreak;\n}\ni++;\n}}\nif(j==0)\nprintf(\"NO\");\nif(j>0)\nprintf(\"YES\");\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "103d780ebfce942aff830f69926b8958", "src_uid": "ed9a763362abc6ed40356731f1036b38", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    char s[100];\n    int i,d,c1=0,c2=0;\n    gets(s);\n     d=strlen(s);\n    for(i=0;i<d;i++)\n    {\n        if(s[i]=='1')\n            c1++;\n        else\n            c2++;\n    }\n    if(c1>=7||c2>=7)\n    printf(\"YES\");\n    else\n        printf(\"NO\");\n        getch();\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1cbd7e570a884d157f3573e2706b77a3", "src_uid": "ed9a763362abc6ed40356731f1036b38", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    char s[100];\n    int i,c1=0,c2=0;\n    gets(s);\n    strlen(s);\n    for(i=0;i<strlen(s);i++)\n    {\n        if(s[i]=='1')\n            c1++;\n        else if(s[i]=='0')\n            c2++;\n    }\n    if(c1>=7||c2>=7)\n    printf(\"YES\");\n    else\n        printf(\"NO\");\n        getch();\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7041e77ac9def910bb05920ad70f68de", "src_uid": "ed9a763362abc6ed40356731f1036b38", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int i,j,c,t,o = 0,z = 0;\n    scanf(\"%d\",&j);\n    t = j;\n    while (j != 0){\n        j /= 10;\n        c ++;\n    }\n    char a[c];\n    itoa(j,a,10);\n    for (i = 0 ; i < c ; i ++){\n        if (a[i] == '0'){\n            z ++;\n        }\n        else{\n            z = 0;\n        }\n        if (a[i] == '1'){\n            o ++;\n        }\n        else{\n            o = 0;\n        }\n        if(o >= 7 || z >= 7){\n            printf(\"YES\");\n        }\n        else {\n            printf(\"NO\");\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0887ba66d359c7f89361bf9f1364f7ff", "src_uid": "ed9a763362abc6ed40356731f1036b38", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nchar c[6][500];\nint main()\n{\n    long len1,len2,len3,len4;\n    gets(c[1]);\n    gets(c[2]);\n    gets(c[3]);\n    gets(c[4]);\n    len1=strlen(c[1])-2;\n    len2=strlen(c[2])-2;\n    len3=strlen(c[3])-2;\n    len4=strlen(c[4])-2;\n    if(len1>=len2*2&&len1>=len3*2&&len1>=len4*2)\n        printf(\"A\");\n    else if(len2>=len1*2&&len2>=len3*2&&len2>=len4*2)\n        printf(\"B\");\n    else if(len3>=len2*2&&len3>=len1*2&&len3>=len4*2)\n        printf(\"C\");\n    else if(len4>=len2*2&&len4>=len3*2&&len4>=len1*2)\n        printf(\"D\");\n    else if(len1<=len2/2&&len1<=len3/2&&len1<=len4/2)\n        printf(\"A\");\n    else if(len2<=len1/2&&len2<=len3/2&&len2<=len4/2)\n        printf(\"B\");\n    else if(len3<=len2/2&&len3<=len1/2&&len3<=len4/2)\n        printf(\"C\");\n    else if(len4<=len2/2&&len4<=len3/2&&len4<=len1/2)\n        printf(\"D\");\n    else printf(\"C\");\n    return 0;\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d811abac9c4ad3b203b5864cde137857", "src_uid": "30725e340dc07f552f0cce359af226a4", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n//#include<conio.h>\n#include<string.h>\n\nint main()\n{\n    char s1[105],s2[105],s3[105],s4[105];\n    \n    //printf(\"A.\");\n    scanf(\"%s\",s1);\n    //printf(\"B.\");\n    scanf(\"%s\",s2);\n    //printf(\"C.\");\n    scanf(\"%s\",s3);\n    //printf(\"D.\");\n    scanf(\"%s\",s4);\n    \n    int l1=strlen(s1)-2;\n    int l2=strlen(s2)-2;\n    int l3=strlen(s3)-2;\n    int l4=strlen(s4)-2;\n    \n    //printf(\"%d %d %d %d\\n\",l1,l2,l3,l4);\n    \n    if(l1<=l2/2 && l1<=l3/2 && l1<=l4/2)\n    printf(\"A\");\n    else if(l1>=2*l2 && l1>=2*l3 && l1>=2*l4)\n    printf(\"A\");\n    else if(l2<=l1/2 && l2<=l3/2 && l2<=l4/2)\n    printf(\"B\");\n    else if(l2>=2*l1 && l2>=2*l3 && l2>=2*l4)\n    printf(\"B\");\n    else if(l3<=l1/2 && l3<=l2/2 && l3<=l4/2)\n    printf(\"C\");\n    else if(l3>=2*l1 && l3>=2*l2 && l3>=2*l4)\n    printf(\"C\");\n    else if(l4<=l1/2 && l4<=l2/2 && l4<=l3/2)\n    printf(\"D\");\n    else if(l4>=2*l1 && l4>=2*l2 && l4>=2*l3)\n    printf(\"D\");\n    \n    else\n    printf(\"C\");\n    \n    //getch();\n    return 0;\n}\n    \n    \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "609919d2a4727763b0cb3a8e76741e52", "src_uid": "30725e340dc07f552f0cce359af226a4", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define sc      scanf\n#define pr      printf\n#define dnum    100001\n\nchar str[4][110];\nint len[4];\n\nint main()\n{\n    int n,m,i,j,min,max;\n\n\n    sc(\"%s%s%s%s\",str[0],str[1],str[2],str[3]);\n    \n    for(i = 0; i< 4; ++i)\n    {\n        len[i] = strlen(str[i])-2;\n    }\n\n    for(i = 0; i < 4; ++i)\n    {\n        min = 0;\n        max = 0;\n        for(j = 0; j < 4; ++j)\n        {\n            if(i != j)\n            {\n                if(len[i]*2 <= len[j])\n                {\n                    min++;\n                }\n\n                if(len[i] >= len[j]*2)\n                {\n                    max++;\n                }\n            }\n        }\n\n        if(max == 3 || min == 3)break;\n    }\n\n    if(max != 3 && min != 3)\n    {\n        printf(\"C\\n\");\n    }\n    else\n    {\n        printf(\"%c\\n\",i+'A');\n    }\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8ee19c40f8c0c54ace00441955e1fb45", "src_uid": "30725e340dc07f552f0cce359af226a4", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main()\n{\n    char a[200];\n    char b[200];\n    char c[200];\n    char d[200];\n    char x;\n    int i;\n    int len[4];\n\n    scanf(\"%c\", &x);\n    scanf(\"%c\", &x);\n    scanf(\"%s\\n\", a);\n    //getch();\n    scanf(\"%c\", &x);\n    scanf(\"%c\", &x);\n    scanf(\"%s\\n\", b);\n    //getch();\n    scanf(\"%c\", &x);\n    scanf(\"%c\", &x);\n    //getch();\n    scanf(\"%s\\n\", c);\n    //getch();\n    scanf(\"%c\", &x);\n    scanf(\"%c\", &x);\n    //getch();\n    scanf(\"%s\", d);\n    //printf(\"%s\\n%s\\n%s\\n%s\\n\", a, b, c, d);\n    len[0] = strlen(a);\n    len[1] = strlen(b);\n    len[2] = strlen(c);\n    len[3] = strlen(d);\n\n    int min = 101;\n    int max = -1;\n    int mini;\n    int maxi;\n    for (i = 0; i < 4; i++) {\n        if (len[i] > max) {\n            max = len[i];\n            maxi = i;\n        }\n        if (len[i] < min) {\n            min = len[i];\n            mini = i;\n        }\n    }\n    int flag1 = 1;\n    int flag = 1;\n    for (i = 0; i < 4; i++) {\n        if (i != mini) {\n        if (min > (len[i]/2)) {\n            flag = 0;\n            break;\n        }\n        }\n    }\n    if (flag) {\n        if (mini == 0) {\n            printf(\"A\");\n        } else if (mini == 1) {\n            printf(\"B\");\n        } else if (mini == 2) {\n            printf(\"C\");\n        } else {\n            printf(\"D\");\n        }\n        flag1 = 0;\n    }\n    flag = 1;\n    for (i = 0; i < 4; i++) {\n        if (i != maxi)\n        if (max < (2*len[i])) {\n            flag = 0;\n            break;\n        }\n    }\n    if (flag) {\n        if (maxi == 0) {\n            printf(\"A\");\n        } else if (maxi == 1) {\n            printf(\"B\");\n        } else if (maxi == 2) {\n            printf(\"C\");\n        } else {\n            printf(\"D\");\n        }\n        flag1 = 0;\n    }\n    if (flag1) {\n        printf(\"C\");\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "66fb51d72b1ddc870e1f9d7ff41f29ab", "src_uid": "30725e340dc07f552f0cce359af226a4", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nsolve();\nint main()\n{\nsolve();\nreturn 0;\n}\nsolve()\n{\n    int la,lb,lc,ld;\nchar a[105],b[105],c[105],d[105],ch;\nscanf(\"%s%c%s%c%s%c%s%c\",&a,&ch,&b,&ch,&c,&ch,&d,&ch);\nla=strlen(a)-2;\nlb=strlen(b)-2;\nlc=strlen(c)-2;\nld=strlen(d)-2;\nif(((la<=lb/2)&&(la<=lc/2)&&(la<=ld/2))||((la>=lb*2)&&(la>=lc*2)&&(la>=ld*2)))\nprintf(\"A\");\nelse if(((lb<=la)/2&&(lb<=lc/2)&&(lb<=ld/2))||((lb>=la*2)&&(lb>=lc*2)&&(lb>=ld*2)))\nprintf(\"B\");\n\nelse if(((ld<=la/2)&&(ld<=lc/2)&&(ld<=lb/2))||((ld>=la*2)&&(ld>=lc*2)&&(ld>=lb*2)))\nprintf(\"D\");\nelse\nprintf(\"C\");\nprintf(\"\\n\");\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4ad953cb4295a64f942a9ed60c8a5ca5", "src_uid": "30725e340dc07f552f0cce359af226a4", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<conio.h>\nvoid main()\n{\nint a[10]={0} , i , j , n , flag;\n\nfor(i=0;i<6;i++)\n{\nscanf(\"%d\" , &n);\nfor(j=1;j<10;j++)\n{\nif(n==j)\n{\na[n]++;\nbreak;\n}\n}\n }\n\nfor(i=1;i<10;i++)\n{\nif(a[i]==4)\n{\nfor(j=1;j<10;j++)\n{\nif(a[j]==2)\n{\nflag=1;\nbreak;\n}\n\n\nelse\n{\nflag=0;\n}\n}\nbreak;\n}\n\n\nelse if(a[i]==6)\n{\nflag=1;\nbreak;\n}\n\n\nelse\nflag=2;\n}\n\nif(flag==1)\nprintf(\"Elephant\");\nelse if(flag==0)\nprintf(\"Bear\");\nelse  if(flag==2)\nprintf(\"Alien\");\n\ngetch();\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "70141d60f6a492d66a301bb1b2953953", "src_uid": "43308fa25e8578fd9f25328e715d4dd6", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n//#include<conio.h>\n\nint main()\n{\n    int i,arr[6],count[10]={0},c1=0,c2=0;\n    for(i=0;i<6;i++)\n    {\n       scanf(\"%d\",&arr[i]);\n       count[arr[i]]++;\n    }\n    for(i=1;i<10;i++)\n    {\n       if(count[i]==4)\n       {    c1=1; break; }\n    }\n    if(!c1)\n    {\n       printf(\"Alien\");\n      // getch();\n    }\n    else\n    {\n       for(i=1;i<10;i++)\n       {\n           if(count[i]==2)\n           {    c2=1; break; }\n       }\n   /* for(i=1;i<10;i++)\n    {\n       if(count[i]==1)\n       {    temp[k]=1; k++; }\n    }*/\n       if(c1&&c2)\n       {\n           printf(\"Elephant\");\n       }\n       else\n       {\n           printf(\"Bear\");\n       }\n    }\n    getch();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7f91c064d34110a79d719284d2769c6f", "src_uid": "43308fa25e8578fd9f25328e715d4dd6", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint cmpfunc (const void * a, const void * b)\n{\n       return ( *(int*)a - *(int*)b );\n}\n\nint main()\n{\n    int a[6],count=0,i,count1=0;\n    for(i=0;i<6;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    \n    qsort(a, 6, sizeof(int), cmpfunc);\n\n    for(i=1;i<6;i++)\n    {\n        if(a[i] != a[i-1])\n            count++;\n        if(a[i] == a[i-1])\n            count1++;\n    }\n    if(count<=1 && count1>=3)\n        printf(\"Elephant\\n\");\n    else if(count==2 && count1>=3)\n        printf(\"Bear\\n\");\n    else\n        printf(\"Alien\\n\");\n    return 0;\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8fd3e7770ff032195a606d82705cb0bb", "src_uid": "43308fa25e8578fd9f25328e715d4dd6", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int i,j,d,A[10],cnt=1,C[10]={0};\n    for(i=0;i<6;i++){\n        scanf(\"%d\",&A[i]);\n    }\n    C[0]=A[0];\n    for(i=1;i<6;i++){\n            d=0;\n        for(j=0;j<cnt;j++){\n            if(A[i]==C[j]){\n                d=1;\n            }}\n                if(d==0){\n                    //printf(\"%d %d\\n\",i,j);\n                    C[cnt]=A[i];\n                    cnt++;\n                }\n\n    }\n    //printf(\"%d %d %d %d %d %d\",C[0],C[1],C[2],C[3],C[4],C[5]);\n    if(cnt>3) printf(\"Alien\");\n    else if(cnt==3) printf(\"Bear\");\n    else printf(\"Elephant\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cbfa8f4abd5a9385ea4a833eb7ddec79", "src_uid": "43308fa25e8578fd9f25328e715d4dd6", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<math.h>\n#include<stdlib.h>\nint h[2000];\nint main()\n{\n    int t=0,n,i,p,q,j,l,r,x,y,k;\n   int a[6];int flg=0,z;\n   for(i=0;i<6;i++)\n   {\n       scanf(\"%d\",&a[i]);\n       h[a[i]]++;\n   }\n   for(i=0;i<6;i++)\n   {\n       if( h[a[i]]==6)\n       {\n           printf(\"Elephant\");\n                   return 0;\n       }\n   }\n\n\n   for(i=0;i<6;i++)\n   {\n       if( h[a[i]]==4)\n       {\n           a[i]=0;\n           flg=1;\n       }\n   }\n    for(i=0;i<6;i++)\n    {\n       if( h[a[i]]==2 && a[i]>0 && flg==1)\n       {\n           a[i]=-1;\n           flg=2;\n       }\n    }\n    if(flg==2)\n    {\n        printf(\"Elephant\");\n                   return 0;\n    }\n\n    for(i=0;i<6;i++)\n    {\n       if( h[a[i]]==1 && a[i]>0 && flg==1)\n       {\n          x=a[i];\n          a[i]=-2;\n          //z=i;\n          break;\n       }\n    }\n\n     for(i=0;i<6;i++)\n    {\n       if( h[a[i]]==1 && a[i]>0 && flg==1)\n       {\n          y=a[i];\n          a[i]=-3;\n          break;\n       }\n    }\n\n    for(i=0;i<6;i++)\n    {\n        if(a[i]>0)\n        {\n            printf(\"Alien\");\n            return 0;\n        }\n    }\n    if(x!=y && flg==1)\n    {\n       printf(\"Bear\");\n           return 0;\n    }\n\nreturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "01e8c90bbc3c1db851237150b02fcc81", "src_uid": "43308fa25e8578fd9f25328e715d4dd6", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char s[1000000];\n    int i,k=0;\n    while(1){\n    scanf(\"%s\",s);\n    for(i=0; i<strlen(s); )\n    {\n\n\n\n            if(s[i]=='1'&&s[i+1]=='4'&&s[i+2]=='4')\n            {\n                k=1;\n                s[i]='0';\n                s[i+1]='0';\n                s[i+2]='0';\n                i=i+3;\n            }\n            else if(s[i]=='1'&&s[i+1]=='4')\n            {\n                k=1;\n                s[i]='0';\n                s[i+1]='0';\n                i=i+2;\n            }\n\n            else if(s[i]=='1')\n            {\n                k=1;\n                s[i]='0';\n                i=i+1;\n            }\n\n\n        else\n        {\n            k=0;\n            break;\n        }\n\n    }\n    if(k==1)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6ee4ab7805a5ccc1aaa9675a603a2132", "src_uid": "3153cfddae27fbd817caaf2cb7a6a4b5", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    while(n>0)\n    {\n        if(n%1000==144)\n        {\n            n/=1000;\n        }\n        else if(n%100==14)\n        {\n            n/=100;\n        }\n\n        else if(n%10==1)\n        {\n            n/=10;\n        }\n        else\n        {\n            printf(\"NO\");\n            \n        }\n    }\n        printf(\"YES\");\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "725374bfdad4d616e583cf293bcf32f0", "src_uid": "3153cfddae27fbd817caaf2cb7a6a4b5", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint N,A,B,C;\n\tchar Error=0;\n\tscanf(\"%d\",&N);\n\twhile(N)\n\t{\n\t\tA=N%10;\n\t\tB=N%100;\n\t\tC=N%1000;\n\t\tif(A==1)\n\t\t{\n\t\t\tN/=10;\n\t\t}\n\t\telse if(B==14)\n\t\t{\n\t\t\tN/=100;\n\t\t}\n\t\telse if(C==114)\n\t\t{\n\t\t\tN/=1000;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tError=1;\n\t\t\tbreak;\n\t\t}\n\t}\n\tputs(Error?\"NO\":\"YES\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e84de32e82e34e4308450f4774f13ee4", "src_uid": "3153cfddae27fbd817caaf2cb7a6a4b5", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nlong long n,rev;\n\nvoid s1(int);\nvoid s2(int);\nvoid s3(int);\nvoid s4(int);\n\nvoid s1(int rev)\n{\n     if(!rev)\n     {\n      printf(\"YES\");\n      return;\n      }\n      else if(rev%10==4)\n      s2(rev/10);\n      else\n      s1(rev/10);\n}\n\nvoid s2(int rev)\n{\n     if(!rev)\n     {\n      printf(\"YES\");\n      return;\n      }\n      else if(rev%10==4)\n      s3(rev/10);\n      else\n      s1(rev/10);\n}\nvoid s3(int rev)\n{\n     if(!rev)\n     {\n      printf(\"YES\");\n      return;\n      }\n      else if(rev%10==4)\n      s4(rev/10);\n      else\n      s1(rev/10);\n}\n\nvoid s4(int rev)\n{\n     printf(\"NO\");\n     return;\n}\n\nint main()\n{\n    scanf(\"%I64d\",&n);\n    while(n)\n    {\n            if(n%10!=1&&n%10!=4)\n            {\n                       printf(\"NO\");\n                       getch();\n                       return 0;\n            }\n            rev=rev+n%10;\n            rev*=10;\n            n/=10;\n    }\n    rev/=10;\n    if(rev%10==1)\n                 s1(rev/10);\n    else\n        s4(rev/10);\n    return 0;\n}\n            \n            \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7a2d87e962b4663b055b87377b3b636b", "src_uid": "3153cfddae27fbd817caaf2cb7a6a4b5", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nchar a[1000000001];\nint main(){\n\t//long int n;\n\t//scanf(\"%ld\",&n);\n\t//sprintf(a,\"%ld\",n);\n\tscanf(\"%s\",a);\n\tint i;\n\tfor(i=0;i<strlen(a)-1;i++){\n\t\tif((a[i]!='1' && a[i]!='4') || (i<strlen(a)-2 && a[i]==a[i+1]==a[i+2]=='4') || a[0]=='4')\n\t\t{\n\t\t\tprintf(\"NO\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\"YES\");\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "98322d607283cbe589eb702e798c3957", "src_uid": "3153cfddae27fbd817caaf2cb7a6a4b5", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char str[101];\n    int l, i, count = 0, count1 = 0;\n    scanf(\"%s\", str);\n    l = strlen(str);\n    for(i = 0; i < l; i++)\n    {\n        if(str[i] == '-')\n            count++;\n        else\n            count1++;\n    }\n    if(count1 == 0)\n        printf(\"YES\\n\");\n    else if(count%2 == 0 || count == 0)\n        printf(\"YES\\n\");\n\n    else\n        printf(\"NO\\n\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "80084daee742ab895cec13b480de6091", "src_uid": "6e006ae3df3bcd24755358a5f584ec03", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    char s[100];\n    int p=0,l=0,i=0;\n    scanf(\"%s\",s);\n    while(s[i]!='\\0');\n    {\n        if(s[i]=='o')\n            p++;\n        else\n        l++;\n        i++;\n    }\n    if(l==0||p==0)\n    printf(\"YES\");\n    else if(l%p==0)\n    printf(\"YES\");\n    else\n    printf(\"NO\");\n    return 0;\n    \n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1f726fa83a9f422dca4c31e8cbfddf50", "src_uid": "6e006ae3df3bcd24755358a5f584ec03", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    char s[100];\n    int p=0,l=0,i=0;\n    scanf(\"%s\",s);\n    while(s[i]!=NULL);\n    {\n        if(s[i]=='o')\n            p++;\n        else\n        l++;\n    }\n    if(l==0||p==0)\n    printf(\"YES\");\n    else if(l%p==0)\n    printf(\"YES\");\n    else\n    printf(\"NO\");\n    return 0;\n    \n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c8c707b7dbe82bcc8df6a90707733a37", "src_uid": "6e006ae3df3bcd24755358a5f584ec03", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    char s[105];\n    int p=0,l=0,i=0;\n    scanf(\"%s\",s);\n    while(s[i]!='\\0');\n    {\n        if(s[i]=='o')\n            p++;\n        else\n        l++;\n    }\n    if(l==0||p==0)\n    printf(\"YES\");\n    else if(l%p==0)\n    printf(\"YES\");\n    else\n    printf(\"NO\");\n    return 0;\n    \n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9dc6959cfafcc42ebfd0d4f52c7bb32b", "src_uid": "6e006ae3df3bcd24755358a5f584ec03", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint compare(char a[], char b[])\n{\n    int i, j;\n\n    int ara[26];\n    for(i = 0; i < 26; i++){\n        ara[i] = 0;\n    }\n\n    for(i = 0; a[i] != '\\0'; i++) if(ara[a[i]-'a'] == 0) ara[a[i]-'a']++;\n    for(i = 0; b[i] != '\\0'; i++) if(ara[b[i]-'a'] == 1) ara[b[i]-'a']--;\n    for(i = 0; i < 26; i++) if(ara[i]) break;\n\n    if(i == 26) return 1;\n    else return 0;\n\n}\n\nint main()\n{\n    int i, j, n, count;\n\n    scanf(\"%d\", &n);\n\n    char root[n][1001], word[1001];\n\n    root[0][0] = '\\0';\n\n    for(i = 0, count = 0; i < n; i++){\n        scanf(\" %s\", word);\n\n        for(j = 0; root[j][0] != '\\0'; j++){\n            if(compare(word, root[j])){\n                break;\n            }\n        }\n        if(root[j][0] == '\\0'){\n            count++;\n            strcpy(root[j], word);\n            root[j+1][0] = '\\0';\n        }\n    }\n\n    printf(\"%d\\n\", count);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "564d88884664c8bdf28d41c08dac418f", "src_uid": "6e006ae3df3bcd24755358a5f584ec03", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n,pos,l,r,i,ans=0,start,end;\n    scanf(\"%d%d%d%d\",&n,&pos,&l,&r);\n     if(pos<l)\n            {for(i=pos;i<=l;i++)\n            {\n                ans++;\n            }\n            if(r!=n)\n            {\n               for(i=l;i<=r;i++)\n            {\n                ans++;\n            }\n            printf(\"%d\",ans);\n            return 0;\n            }\n            printf(\"%d\",ans);\n            return 0;\n            }\n    if(pos>r)\n    {\n            {for(i=pos;i>=r;i--)\n            {\n                ans++;\n            }\n            if(l!=1)\n            {\n               for(i=r;i>=l;i--)\n            {\n                ans++;\n            }\n            printf(\"%d\",ans);\n            return 0;\n            }\n            printf(\"%d\",ans);\n            return 0;}\n    }\n    int sum=0;\n    for(i=l;i<=pos;i++)\n    {\n        sum++;\n    }\n    int sum1=0;\n    for(i=pos;i<=r;i++)\n    {\n        sum1++;\n    }\n    while(pos<=r&&r!=n&&sum>=sum1)\n    {\n\n            pos+=1;\n            ans++;\n    }\n    if(pos==r+1)\n    {\n        pos-=1;\n    }\n    while(pos>=l&&l!=1)\n    {\n            pos-=1;\n            ans++;\n    }\n    if(pos==l-1)\n    {\n        pos+=1;\n    }\n    if(sum1>sum)\n    {\n        while(pos<=r&&r!=n)\n    {\n\n            pos+=1;\n            ans++;\n    }\n    }\n    printf(\"%d\",ans);\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6b39aaa813587325a6cb067a929ddd90", "src_uid": "5deaac7bd3afedee9b10e61997940f78", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <math.h>\n#include <stdlib.h>\n\nint main() {\n\n    int i,j,n,k,max,pos,l,r,ans;\n    scanf(\"%d %d %d %d\",&n,&pos,&l,&r);\n    if(l==1 && r==n){\n        printf(\"0\");\n    }else{\n        if(l==r){\n            ans=abs(pos-l);\n            if(l==1 ||l==n){\n                printf(\"%d\",ans+1);\n            }else{\n            printf(\"%d\",ans+2);\n            }\n        }else if(l==1){\n            ans=abs(pos-r);\n            printf(\"%d\",ans+1);\n        }else if(r==n){\n            ans=abs(pos-l);\n            printf(\"%d\",ans+1);\n        }else{\n            if(abs(pos-l)>=abs(pos-r)){\n                ans=abs(pos-r);\n                ans+=abs(r-l);\n            }else{\n                ans=abs(pos-l);\n                ans+=abs(r-l);\n            }\n            printf(\"%d\",ans+2);\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "069f6bfb31f7dc2c8a92c9ce75f93749", "src_uid": "5deaac7bd3afedee9b10e61997940f78", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n  int n,pos,a,b,l,r,min,max,count=0;\n  scanf(\"%d%d%d%d\",&n,&pos,&l,&r);\n  a = 1;\n  b = n;\n  if ((l!=a)||(b!=r))\n{    \n   if((r-pos)<(pos-l))\n    { \n      if(b!=r)\n      {\n       while(pos!=r)\n        {\n          min = b*(b<(pos+1)) + (pos+1)*((pos+1)<b);\n          pos = min;\n          count++;\n        }\n       }\n       b = r;\n       count++;\n       if(a!=l)\n       {\n       while(pos!=l)\n        {\n          max = a*(a>(pos-1)) + (pos-1)*((pos-1)>a);\n          pos = max;\n          count++;\n        }\n       a = l;\n       count++;\n       }\n      }\n      if(((pos-l)<(r-pos))||((pos-l)==(r-pos)))\n    { \n       if(a!=l)\n       {\n       while(pos!=l)\n        {\n          max = a*(a>(pos-1)) + (pos-1)*((pos-1)>a);\n          pos = max;\n          count++;\n        }\n       a = l;\n       count++;\n       }\n      if(b!=r)\n      {\n       while(pos!=r)\n        {\n          min = b*(b<(pos+1)) + (pos+1)*((pos+1)<b);\n          pos = min;\n          count++;\n        }\n       }\n       b = r;\n       count++;\n      }\n }\n       printf(\"%d\",count);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3a0c9c75585878ec05027e8789796ba3", "src_uid": "5deaac7bd3afedee9b10e61997940f78", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main(){\n\tint n,pos,l,r,res;\n\twhile(scanf(\"%d%d%d%d\",&n, &pos, &l, &r)){\n\t\tif(l==1 && r==n){\n\t\t\tres=0;\n\t\t}\n\t\telse if(l==1){\n\t\t\tres=abs(pos-r)+1;\n\t\t}\n\t\telse if(r==n){\n\t\t\tres=abs(pos-l)+1;\n\t\t}\n\t\telse{\n\t\t\tif(l<=pos && pos<=r){\n\t\t\t\tres=pos-2*l+r+2;\n\t\t\t\t//printf(\"1\\n\");\n\t\t\t}\n\t\t\telse if(l>pos){\n\t\t\t\tres=r-pos+2;\n\t\t\t\t//printf(\"1\\n\");\n\t\t\t}\n\t\t\telse if(r<pos){\n\t\t\t\tres=pos-l+2;\n\t\t\t\t//printf(\"1\\n\");\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\",res);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5fd313e904ea70907604018d2c07f820", "src_uid": "5deaac7bd3afedee9b10e61997940f78", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdbool.h>\nvoid main() {\n    int t=-1,n,p,l,r;\n    scanf(\"%d\", &n);\n    scanf(\"%d\", &p);\n    scanf(\"%d\", &l);\n    scanf(\"%d\", &r);\n    bool lf=(l==1);\n    bool rf=(r==n);\n    t=lf?(rf?0:(r-p+1)):(rf?(p-l+1):(r-p<p-l?(2*(r-p)+(p-l)+2):(2*(p-l)+(r-p)+2)));\n    printf(\"%d\",t);\n    return;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4c40f71fa882af75e7af827b010bca8c", "src_uid": "5deaac7bd3afedee9b10e61997940f78", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint r,g,b,countr,countb,countg,remainr,remainb,remaing,count=0;\nscanf(\"%d%d%d\",&r,&g,&b);\ncountr=r/3;\nremainr=r%3;\ncountg=g/3;\nremaing=g%3;\ncountb=b/3;\nremainb=b%3;\nwhile(remainr!=0||remainb!=0||remaing!=0)\n{\nremainr=remainr-1;\nremaing=remaing-1;\nremainb=remainb-1;\ncount++;\n}\nprintf(\"%d\",countr+countb+countg+count);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0908d5c147d6b501490b681904f60f43", "src_uid": "acddc9b0db312b363910a84bd4f14d8e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\nint func(const void*a, const void*b)\n{\n\treturn (*(int*)a-*(int*)b);\n}\nint main()\n{\n\tlong long int r, g, b,count=0;\n\tscanf(\"%lld %lld %lld\", &r, &g, &b);\n\tlong long arr[3];\n\twhile(r%3 + g%3 + b%3>=3)\n\t{\n\t\tr--;g--;b--;\n\t\tcount++;\n\t}\n\tcount+=r/3 + g/3 + b/3;\n\tr=r%3;g=g%3;b=b%3;\n\tarr[0]=r;arr[1]=g;arr[2]=b;\n\tqsort(arr,3,sizeof(long long),func);\n\tlong long smallest=arr[0];\n\tcount+=smallest;\n\tprintf(\"%lld\\n\",count);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "80553845b1e55564b3f24bb12e857ddd", "src_uid": "acddc9b0db312b363910a84bd4f14d8e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint min(int a,int b,int c)\n{\n    int min_=a;\n    if(min_>b)\n    {\n        min_=b;\n    }\n    if(min_>c)\n    {\n        min_=c ;\n    }\n    return min_ ;\n}\nint non_div(int a, int b, int c)\n{\n    int k=0 ;\n    if(a%3!=0)\n    {\n        k++;\n    }\n    if(b%3!=0)\n    {\n        k++;\n    }\n    if(c%3!=0)\n    {\n        k++;\n    }\n    return k ;\n}\nint main()\n{\n    int r,b,g,a,c,d,e,k,m,i=0;\n    scanf(\"%d\",&r);\n    scanf(\"%d\",&b);\n    scanf(\"%d\",&g);\n    k=non_div(r,b,g);\n    \n\n    if(r==0 )\n    {\n        printf(\"%d\",b/3+g/3);\n        return 0;\n    }\n    if(g==0)\n    {\n        printf(\"%d\",r/3+b/3);\n        return 0;\n    }\n    if(b==0)\n    {\n        printf(\"%d\",r/3+g/3);\n        return 0;\n    }\n    if(k>=2)\n    {\n        while(k>=2)\n        {\n            r--;\n            b--;\n            g--;\n            i++;\n            k=non_div(r,b,g); }\n\n\n         printf(\"%d\",r/3+b/3+g/3+i);\n         return 0;\n            }\n    else\n    {\n        a=min(r,b,g);\n        c=r-a;\n        d=b-a;\n        e=g-a;\n        printf(\"%d\",c/3+d/3+e/3+a);\n\n        return 0 ;\n    }\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5657d7ea18ddbb57fbf899edb15466fe", "src_uid": "acddc9b0db312b363910a84bd4f14d8e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint maxx(int i,int j,int k)\n{\n    i=i>j?j:i;\n    return i>k?k:i;\n}\nint main()\n{\n    __int64 ans,a,b,c,aa,bb,cc,cout;\n    while(~scanf(\"%I64d %I64d %I64d\",&a,&b,&c))\n    {\n        ans=a/3+b/3+c/3;\n        aa=a%3,bb=b%3,cc=c%3;\n        cout=0;\n        if(aa*bb*cc==0)\n            if((aa*bb==4)||(bb*cc==4||aa*cc==4))\n            ans+=1;\n        ans+=maxx(aa,bb,cc);\n        printf(\"%I64d\\n\",ans);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1c76b25db214a65b2d73bc6e60ff6831", "src_uid": "acddc9b0db312b363910a84bd4f14d8e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n long long r,g,b,l,m,n,p,cnt=0;\n scanf(\"%I64d%I64d%I64d\",&r,&g,&b);\n l=r%3;\n m=g%3;\n n=b%3;\n if(l==m || m==n)\n p=m;\n else\n {\n if(l<=m&&l<=n)\n p=l;\n if(m<=n&&m<=l)\n p=m;\n if(n<=l&&n<=m)\n p=n;\n }\n if(l==n)\n p=l;\n\n cnt=p;\n r=r-p;\n g=g-p;\n b=b-p;\n cnt+=(b/3);\n cnt+=(g/3);\n cnt+=(r/3);\n printf(\"%I64d\",cnt);\n return 0;\n }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "334570651ca428d2bbbe69506e873696", "src_uid": "acddc9b0db312b363910a84bd4f14d8e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n\n    int w;\n\n    printf (\"Enter the weight of watermelon: \");\n    scanf (\"%d\",&w);\n\n    if(w>=1&&w<=100)\n    {\n        if(w==2)\n        {\n            printf (\"NO\");\n        }\n        else if(w%2==0)\n        {\n\n            printf (\"YES\");\n        }\n        else\n            printf (\"NO\");\n    }\n    else\n        printf (\"the weight of the watermelon isn't right .\");\n\n    return main();\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "71f80d24269f531b715ff2a215a1673c", "src_uid": "230a3c4d7090401e5fa3c6b9d994cdf2", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    unsigned int n;\nscanf(\"%u\",&n);\nwhile(n>2)\n{\n if(n%2==0)\n    printf(\"YES\");\nelse\nprintf(\"NO\");\n}\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ae4d66768a75ae1c620c6a9ffa4b7c8d", "src_uid": "230a3c4d7090401e5fa3c6b9d994cdf2", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    while(scanf(\"%d\",&n))\n    {\n        if(n>2 && n%2==0)\n        printf(\"YES\\n\");\n        else\n        printf(\"NO\\n\");\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3fa4be42bdf37129a2e0e268eeef58c0", "src_uid": "230a3c4d7090401e5fa3c6b9d994cdf2", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nvoid main(){\n    long w,count=0;\n    scanf(\"%d\",&w);\n        for(int i=w;i>1;i/2)\n        count++;\n        if(count%2==0)\n        printf(\"YES\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "bad159e721af307d1ebb9f23004d6d4b", "src_uid": "230a3c4d7090401e5fa3c6b9d994cdf2", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    while(1);\n    {scanf(\"%d\",&n);\n        if( n%2==0)\n        printf(\"YES\\n\");\n        else\n        printf(\"NO\\n\");\n        }\n    }", "lang_cluster": "C", "compilation_error": false, "code_uid": "c8dd505918cb9ea0f6c1ac1c8574babe", "src_uid": "230a3c4d7090401e5fa3c6b9d994cdf2", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nmain()\n{\n    int i=0,count,j,k;\n    char name[55];\n    scanf(\"%s\",&name);\n    while(name[i]!='\\0')\n        {\n            if(name[i]=='a')\n            count++;\n        }\n        j=strlen(name);\n        if(count>j/2)\n        printf(\"%d\",j);\n        else\n        k=j/2-count;\n        printf(\"%d\",k);\n        \n    \n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7803e49768864be9a080aaca9dcfa27a", "src_uid": "84cb9ad2ae3ba7e912920d7feb4f6219", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n\tchar s[50];\n\tint i,p=0,q;\n\tgets(s);\n\tq=strlen(s);\n\tfor(i=0;q;i++)\n\t{\n\t\tif(s[i]==97)\n\t\tp=p+1;\n\t}\n\tfor(i=0;i<q;i++)\n\t{\n\tif(p<=(q/2))\n\tq=q-1;\n\telse\n\tbreak;\n\t\n}\nprintf(\"%d\",q);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4ab79b9a6a23a81e800876d78f8fa6c9", "src_uid": "84cb9ad2ae3ba7e912920d7feb4f6219", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n//#include <string.h> // \ufffd\ufffd\ufffd strstr\n#include <locale.h>   // setlocale\n#include <windows.h>  // SetConsoleCP,SetConsoleOutputCP\n\n/* Primer 1 */\nvoid main(void)\n{\n    SetConsoleCP(866);\n    SetConsoleOutputCP(866);\n\n    setlocale( LC_ALL, \"Russian\" );\n\n    int N;            // \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\n    int L;            // \ufffd\ufffd \ufffd\ufffd\ufffd \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\n    int K;            // \ufffd\ufffd\ufffd\ufffd\ufffd \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd \ufffd \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\n\n    printf(\"\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd: \");\n    scanf(\"%d\",&N);\n    printf(\"\\n\");\n\n    K=0;\n    L=1;\n    int LMax,Ns;\n    LMax=N/2;\n    while(L<=LMax)\n    {\n        Ns=(N-L)/L;   // \ufffd\ufffd\ufffd\ufffd\ufffd \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd \ufffd \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\n        if (L+Ns*L==N)\n        {\n            printf(\"\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd %d, \ufffd \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd %d\\n\",L,Ns);\n            K++;\n        }\n        L++;\n    }\n    printf(\"\\n\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd \ufffd \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd: %d\\n\",K);\n\n    getchar();\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ef71c4b9d6a50c98a55bc411d77ddff5", "src_uid": "84cb9ad2ae3ba7e912920d7feb4f6219", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main()\n{\n    char str[51];\n    gets(str);\n    int i,length,j,k;\n    length=strlen(str);\n    j=length;\n    int s=0;\n    \n    for(i=1;i<=length;i++)\n    {\n        if(str[i]=='a')\n        s++;\n    }\n    for(j=length;;j--)\n    {\n        if(s>=(length/2)+1)\n        break;\n    }\n    printf(\"%d\",j);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cd036a902dffc0fc661a016b50cc2081", "src_uid": "84cb9ad2ae3ba7e912920d7feb4f6219", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nvoid main(void)\n{\nchar s[50];\nint i,n,nX,count=0,aP;\nscanf(\"%s\",s);\nn=strlen(s);\naP=n/2 + 1;\nfor(i=0;i<n;i++)\n if(s[i]=='a')\n  count++;\n\nnX=n-count;\n\nif(aP<=count)\n {\n printf(\"%d\",n);\n }\n else\n {\n n=nX-count+1;\n printf(\"%d\",n);\n }\n\n\ngetch();\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "89879fbdd352ba816f1f7944ceb9a6d4", "src_uid": "84cb9ad2ae3ba7e912920d7feb4f6219", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nvoid main()\n{\n\tint n, m, a, b;\n\tscanf(\"%d %d %d %d\", &n, &m, &a, &b);\n\tif(b/m<a)\n\t\tprintf(\"%d\\n\", (n/m)*b + (n%m)*a);\n\telse\n\t\tprintf(\"%d\\n\", a*n);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e7c5068ca73145fc048d9cf48bb7fb0b", "src_uid": "faa343ad6028c5a069857a38fa19bb24", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\nint main()\n{\n    int n,m,a,b;\n    int i,j;\n    scanf(\"%d\",&n);\n    scanf(\"%d\",&m);\n    scanf(\"%d\",&a);\n    scanf(\"%d\",&b);\n    int mincost[n];\n    int cost=0;\n    int z=0;\n    if(a<b)\n    {\n        for(i=0;i<=1000;i++)\n        {\n            for(j=0;j<=1000;j=j+m)\n            {\n                if(i+j==n)\n                {\n                    cost=((a*i)+(b*(j/m)));\n                    mincost[z]=cost;\n                    z++;\n                }\n            }\n        }\n    }\n    else if(b<a)\n    {\n        for(j=0;j<=1000;j=j+m)\n        {\n            if(j>=n)\n            {\n                cost=(b*(j/m));\n                mincost[z]=cost;\n                z++;\n            }\n        }\n    }\n    int min=mincost[0];\n    for(i=0;i<z;i++)\n    {\n        if(min>mincost[i])\n        {\n            min=mincost[i];\n        }\n    }\n    printf(\"%d\",min);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7aab65427fb8b121031af7a3ba676ceb", "src_uid": "faa343ad6028c5a069857a38fa19bb24", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n,m,a,b,s;\n    scanf(\"%d%d%d%d\",&n,&m,&a,&b);\n    if((float)a<=(float)b/(float)m) { printf(\"%d\",n*a); return 1;}\n    if(n*a>=b&&n<=m) {printf(\"%d\",b); return 2;}\n    else printf(\"%d\",((n/m)*b)+((((n%m)*a)>b)?b:((n%m)*a)));\n    //printf(\"%d\",((float)a<=(float)b/m)?n*a:((n>m)?(n/m)*b:1)+((((n%m)*a)>b)?1:(n%m)*a));\n    return 3;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a8bfcbb1ffa5e6640030042b1c71333c", "src_uid": "faa343ad6028c5a069857a38fa19bb24", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nvoid main()\n{\n\tlong int n, m, a, b, ans;\n\tscanf(\"%ld %ld %ld %ld\", &n, &m, &a, &b);\n\tif(b/m<a)\n\t\tans=(n/m)*b + (n%m)*a;\n\telse\n\t\tans=a*n;\n\tprintf(\"%ld\\n\", ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d2b190efbe20d59089f1be99a16e3087", "src_uid": "faa343ad6028c5a069857a38fa19bb24", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nvoid main() {\n    int n,m,a,b;\n    scanf(\"%d %d %d %d\",&n,&m,&a,&b);\n    float cp;\n    cp = (float)b/m;\n    if ( cp < (float)a ) {\n        printf(\"%d\",(n/m)*b+(n-(n/m))*a);\n    }\n    else if( cp >= (float)a ) {\n        printf(\"%d\",n*a);\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8efd801fbed7173c73ff90ef654bb30b", "src_uid": "faa343ad6028c5a069857a38fa19bb24", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#define x 3.141592\nmain()\n{\n float n,R,r,a;\n scanf(\"%f%f%f\",&n,&R,&r);\nif(R!=r)\n{\n a=asin(r/(R-r));\n if((n*a)<=x)\n {\n   printf(\"YES\");\n }\n else\n {\n   printf(\"NO\");\n }\n}\nelse\n{\n    if(n==1)\n    {\n        printf(\"YES\");\n    }\n    else\n    {\n        printf(\"NO\");\n    }\n}\nreturn(0);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d2a88e9b915a09c308f55c63c4412d74", "src_uid": "2fedbfccd893cde8f2fab2b5bf6fb6f6", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#define x 3.141592\nmain()\n{\n float n,R,r;double a;\n scanf(\"%f%f%f\",&n,&R,&r);\nif(R<r)\n{\n    printf(\"NO\");\n}\nif((R-2*r)>0)\n{\n a=atan(r/sqrt(R*(R-2*r)));\n if((n*a)<=x)\n {\n   printf(\"YES\");\n }\n else\n {\n   printf(\"NO\");\n }\n}\nif(R>=r && (R-2*r)<0)\n{\n    if(n==1)\n    {\n        printf(\"YES\");\n    }\n    else\n    {\n        printf(\"NO\");\n    }\n}\nif(R==2*r)\n{\n    if(n==2)\n    {\n        printf(\"YES\");\n    }\n    else\n    {\n        printf(\"NO\");\n    }\n}\nreturn(0);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3d64dbb177fcf004d524b13a7cd19417", "src_uid": "2fedbfccd893cde8f2fab2b5bf6fb6f6", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\nconst double PI = 3.1415926535897932384626433832795;\nint main (){\n\tint n,R,r;\n\tscanf(\"%d%d%d\",&n,&R,&r);\n\tif ( r> R ) {\n\t\tprintf( \"NO\\n\");\n\t\treturn 0;}\n\tif ( ( 2*r >R) && ( n> 1) ) {\n\t\t\tprintf( \"NO\\n\");\n\t\treturn 0 ;\n\t}\n\tdouble alpha;\n\talpha=2*asin( (double) r/(2.0* (double) (R-r) ) );\n\tif  ( ( 2*PI/n) <alpha) printf(\"NO\\n\");else printf(\"YES\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "cc7fe1046278271f021d6e8648e1824b", "src_uid": "2fedbfccd893cde8f2fab2b5bf6fb6f6", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <conio.h>\nint main(){\nint R,r,n,l,L;\nscanf(\"%d%d%d\",&n,&R,&r);\n    l=(r*2*n)-((R-r)*2);\n    L=2*R;\n    if((L-l)>=0)\n    \tprintf(\"Yes\");\n    \telse\n    \tprintf(\"No\");\n\nsystem (\"pause\");\n\treturn 0;\n                                                     \n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7fedd00b96125ad7b23872061ae3d6c1", "src_uid": "2fedbfccd893cde8f2fab2b5bf6fb6f6", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nvoid main( void)\n{\n    int n,r,R,y;\n    float k;\n\n    scanf(\"%d %d %d\",&n,&R,&r);\n\n    y=0;\n\n    if ( (n==1) && (r<= R) )\n    {y=1;\n    }\n\n    if ( (n>=3) && (r< R) )\n    {\n\n        if ( (float) r/(R-r)<= sin(3.141592/n) )\n        {y=1;\n        }\n    }\n\n    if ( (n==2) && (  ( 2*r ) <= R) )\n    {y=1;\n    }\n\n    if ( (n==6) && ( ( 3*r ) <=R) )\n    {y=1;\n    }\n\n    if (y==1)\n    {\n        printf(\"YES\");\n    }else\n    {\n\n     printf(\"NO\");\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "29aef5563a623a6d060b432b9dbd12d4", "src_uid": "2fedbfccd893cde8f2fab2b5bf6fb6f6", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "//Bismillahir Rahmanir Rahim\n#include<stdio.h>\n#include<string.h>\nint main()\n{\n\tchar flight[1000000];\n\tint i,t,x,y,j;\n\twhile(scanf(\"%d\",&t)){\n\t\tscanf(\"%s\",&flight);\n\t\tx=0;\n\t\ty=0;\n\t\tfor(j=0;j<t-1;j++){\n\t\t\tif(flight[j]=='S' && flight[j+1]=='F'){\n\t\t\t\t\tx++;\n\t\t\t}\n\t\t\telse if(flight[j]=='F' && flight[j+1]=='S'){\n\t\t\t\t\t\t\ty++;\n\t\t\t\t}\n\t\t\t}\n\t\tif(x>y){\n\t\t\tprintf(\"YES\\n\");\n\t\t}\n\t\telse{\n\t\t\tprintf(\"NO\\n\");\n\t\t}\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a6e0a0c41a4bb14e04f963cd2084c994", "src_uid": "ab8a2070ea758d118b3c09ee165d9517", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n \nint main()\n{\n    int c=0;\n    int num, FS,SF,iter;\n    char city[101];\n    scanf(\"%d\",&num);\n    scanf(\"%s\",city);\n    for(iter=0;iter+1<strlen(city);iter);\n     {\n         if(city[iter]=='F'&&city[iter+1]=='S')\n          FS++;\n         else if(city[iter]=='S'&&city[iter+1]=='F')\n          SF++;\n     }\n     if(SF>FS)\n      printf(\"YES\");\n     else \n      printf(\"NO\");\n    \n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f29c2be45e61346ba7554126c7440677", "src_uid": "ab8a2070ea758d118b3c09ee165d9517", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include \"stdio.h\"\nint main(int argc, char const *argv[])\n{\n\tint i=0,day,s=0,f=0;\n\tchar list[50];\n\tscanf(\"%d\",&day);\n\tscanf(\"%s\",list);\n\twhile(list[i+1]!='\\0'){\n\t\tif (list[i]=='S' && list[i+1]=='F')\n\t\t{\n\t\t\ts+=1;\n\t\t\t/* code */\n\t\t}else if (list[i]=='F' && list[i+1]=='S')\n\t\t{\n\t\t\tf+=1;\n\t\t\t/* code */\n\t\t}else{\n\t\t\tcontinue;\n\t\t}\n\t}\n\tif (s>f)\n\t{\n\t\tprintf(\"YES\\n\");\n\t\t/* code */\n\t}else{\n\t\tprintf(\"NO\\n\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d7ee521e34ac07270ed9178c1abcc41e", "src_uid": "ab8a2070ea758d118b3c09ee165d9517", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nchar aa[100000];\nint main()\n{\n    int a,i;\n\n   while(1)\n   {\n    scanf(\"%d\",&a);\n    for(i=1;i<=a;i++)\n    {\n        scanf(\" %c\",&aa[i]);\n    }\n    if(aa[1]=='S'&&aa[a]=='F') printf(\"YES\\n\");\n    else printf(\"NO\\n\");\n\n   }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f1681c1a1095bb1c5842b5898efe85c2", "src_uid": "ab8a2070ea758d118b3c09ee165d9517", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main()\n{\n    int n;\n    char s[101];\n    int sf, fs ;\n    while (scanf(\"%d\", &n))\n    {\n        scanf(\"%s\", s);\n        sf = 0;\n        fs = 0;\n        for (int i = 1; i < strlen(s); i++)\n        {\n            if (s[i-1] == 'S' && s[i] == 'F'){\n                sf++;\n            } else if (s[i-1] == 'F' && s[i] == 'S'){\n                fs++;\n            }\n        }\n        if (sf > fs){\n            printf(\"YES\\n\");\n        } else {\n            printf(\"NO\\n\");\n        }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c65ab687457498267b2345b38d08cf2a", "src_uid": "ab8a2070ea758d118b3c09ee165d9517", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main() {\n\tint i,j,n,m,q=0;\n\tlong long int k,c=2,s,r;\n\tscanf(\"%d %d %lld\",&n,&m,&k);\n\tlong long int b[n][m];\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tfor(j=1;j<=m;j++)\n\t\t{\n\t\t\tb[i][j]=c;\n\t\t\tc+=2;\n\t\t\tif((b[i][j]-1)==k||(b[i][j]==k))\n\t\t\t{\n\t\t\t\ts=i;\n\t\t\t\tr=j;\n\t\t\t\tq++;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(q>0)\n\t\t\tbreak;\n\t}\n\tif(k%2==0)\n\t\tprintf(\"%lld %lld R\",s,r);\n\telse\n\t\tprintf(\"%lld %lld L\",s,r);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a613e66f7c34ad9df3ae3ea84f6816c7", "src_uid": "d6929926b44c2d5b1a8e6b7f965ca1bb", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main() {\n\tint i,j,c=2,n,m,k,s,r,q=0;\n\tscanf(\"%d %d %d\",&n,&m,&k);\n\tint b[n][m];\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tfor(j=1;j<=m;j++)\n\t\t{\n\t\t\tb[i][j]=c;\n\t\t\tc+=2;\n\t\t\tif((b[i][j]-1)==k||(b[i][j]==k))\n\t\t\t{\n\t\t\t\ts=i;\n\t\t\t\tr=j;\n\t\t\t\tq++;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(q>0)\n\t\t\tbreak;\n\t}\n\tif(k%2==0)\n\t\tprintf(\"%d %d R\",s,r);\n\telse\n\t\tprintf(\"%d %d L\",s,r);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9ebf08d940567c30f9bcb09903aab86f", "src_uid": "d6929926b44c2d5b1a8e6b7f965ca1bb", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(void)\n{\n  int i,j,m,n,k,ast[1000][1000];\n  char ch;\n\n  scanf(\"%d%d%d\",&n,&m,&k);\n  ch=getchar();\n  for(i=0;i<m;i++) {\n     for(j=0;j<n;j++)\n       ast[i][j]=j*m+i+1;\n  }\n  for(i=0;i<m;i++) {\n     for(j=0;j<n;j++)\n       if((k+1)/2==ast[i][j]) {\n            printf(\"%d %d\",j+1,i+1);\n            if(k%2==0)\n              printf(\" %c\",'R');\n            else\n              printf(\" %c\",'L');\n       break;\n       }\n\n   }\n  return 0;\n }", "lang_cluster": "C", "compilation_error": false, "code_uid": "c2c8f8dadb7f50363066da84439abb12", "src_uid": "d6929926b44c2d5b1a8e6b7f965ca1bb", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "\n#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int A[300][300],n,m,k,r,d,i,j,o;\n    char l;\n    scanf(\"%d%d%d\",&n,&m,&k);\n    o=k;\n    if(k%2==0){\n      k=k-1;\n    }\n    for(i=1;i<=n;i++){\n        for(j=1;j<=m;j++){\n        A[i][j]=1+2*m*(i-1)+2*(j-1);\n        }\n    }\n    for(i=1;i<=n;i++){\n        for(j=1;j<=n;j++){\n        if(k==A[i][j]){\n            r=i;\n            d=j;\n        }\n        }\n    }\n    if(o%2==0){\n    l='R';\n    }\n    else l='L';\n    printf(\"%d\\n%d\\n%c\",r,d,l);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "aafbfb64e3452911f2b4c733e2f49d08", "src_uid": "d6929926b44c2d5b1a8e6b7f965ca1bb", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\n/*\n * \n */\nint main() {\n    \n    int n, m, k, i, l=0;\n    float sum=0.0;\n    \n    //printf(\"Give the colum, the row.\\n\");\n    scanf(\"%d %d\", &n, &m);\n    \n    do{\n        //printf(\"Give the position to sit.\\n\");\n        scanf(\"%d\", &k);\n    }while(k<0 || k>(2*n*m+1));\n    \n    for(i=1; i<=m; i++){\n        if(k<i*n*2-2*i){\n            l++;\n            //printf(\"l=%d\\n\",l);\n        }\n        if(i==m && k>i*n*2-2*i){\n            l=m;\n        }\n    }\n    for(i=1; i<=n; i++){\n        if(k<=2*m*i){\n            if(k%2==0){\n                printf(\"%d %d R\\n\", i, l);\n                return;\n            }else{\n                printf(\"%d %d L\\n\", i, l);\n                return;\n            }\n        }\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d9e31f47c3e67eba7e66856079010f0a", "src_uid": "d6929926b44c2d5b1a8e6b7f965ca1bb", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "// Bear and the three balls\n#include <stdio.h>\n#include <malloc.h>\n#include <stdlib.h>\n\n\t// soluci\u00f3n por fuerza bruta: comparar cada bola con otras dos, si antres de terminar el ciclo hay dos que difieren en menos de 2 en valor absoluto, se puede\n\t// Si se acaba el ciclo sin encontrar nada, se imprime NO\n\n\tint particion (int a[],int ini, int fin);\n\tvoid quicksort (int a[],int ini, int fin);\n\tvoid swap (int a[],int x,int y);\n\t\t\nint main(void){\n\tint n;\n\tint *vec;\n\tint i, cont = 0;\n\n\tscanf ( \"%d\", &n );\n\t\n\tvec = (int*)malloc(n*sizeof(int));\n\t\n\tfor ( i = 0; i < n; i++){\n\t\t\tscanf ( \"%d\", &vec[i] );\n\t}\n\t\n\tquicksort( vec, 0, n - 1 );\n\t\n\t/*for ( i = 0; i < n; i++ ){\n\t\tprintf ( \"%d - \", vec[i] );\n\t}*/\n\t\n\tfor ( i = 1; i < n; i++ ){\n\t\tif ( vec[i - 1] == (vec[i] - 1) )\n\t\t\tcont++;\n\t\telse if ( vec[i - 1] != vec[i] )\n\t\t\tcont = 0;\n\t\tif ( cont == 2 ){\n\t\t\tprintf ( \"YES\" );\n\t\t\texit(1);\n\t\t}\n\t}\n\tprintf ( \"NO\" );\n\t\n\treturn 0;\n}\n\nvoid quicksort (int a[],int ini, int fin)\t\t//cada vez que se llama a quicksort un nuevo pivot va colocandose en su posicion\n{\n\tint piv;\n\tif (ini<fin)\n\t{\t//cont++;\n\t\tpiv=particion(a,ini,fin);\n\t\tquicksort(a,ini,piv-1);\t\t\t\t//como el pivot ya esta en su ubicacion se divide en dos y se vuelve a llamar\n\t\tquicksort(a,piv+1,fin);\t\t\t\t//a quicksort pero sin tocar el pivot\n\t}\n}\n\nint particion (int a[],int ini, int fin)\t\t//particion ubica al pivot en su posicion y devulve esa posicion\n{\n\tint pivot,i,j;\n\tpivot=a[fin];\n\ti=ini;\n\tfor (j=ini;j<fin;j++)\n\t{\n\t\tif (a[j]<pivot)\n\t\t{\n\t\t\tswap(a,j,i);\n\t\t\ti++;\n\t\t}\n\t}\n\tswap(a,i,fin);\n\treturn i;\n}\n\n\nvoid swap (int a[],int x,int y)\n{\n\tint aux;\n\taux=a[x];\n\ta[x]=a[y];\n\ta[y]=aux;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c45a69e072dde5e511939fcc5b89293c", "src_uid": "d6c876a84c7b92141710be5d76536eab", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,temp,i,j;\n    scanf(\"%d\",&n);\n    int a[n];\n    for(i=0; i<n; i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    for(i=0; i<n-1; i++)\n    {\n        for(j=n-1; j>i; j--)\n        {\n            if(a[i]>a[j])\n            {\n                temp=a[i];\n                a[i]=a[j];\n                a[j]=temp;\n            }\n        }\n    }\n    for(i=0; i<n; i++)\n    {\n        if((a[i+1]-a[i])==1)\n        {\n            if((a[i+2]-a[i])==2)\n            {\n                printf(\"YES\");\n                return 0;\n            }\n            else\n            {\n                for(j=i+2; j<n; j++)\n                {\n                    if((a[j]-a[i])==2)\n                    {\n                        printf(\"YES\");\n                        return 0;\n                    }\n                }\n\n            }\n        }\n\n    }\n\n    printf(\"NO\");\n    getch();\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6e230cba7f2d4508f0433136f79a6bf2", "src_uid": "d6c876a84c7b92141710be5d76536eab", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <math.h>\nint main()\n{\n    int n,i,j,k,s=0,yes=0;\n    scanf(\"%d\",&n);\n    int A[n];\n    for (i=0;i<n;i++)\n    {\n        scanf(\"%d\",&A[i]);\n    }\n    for (i=0;i<n-2;i++)\n    {\n        for (j=i+1;j<n-1;j++)\n        {\n            if (fabs(A[i]-A[j])>0&&fabs(A[i]-A[j])<=2&&A[i]!=A[j])\n            {\n                for (k=j+1;k<n;k++)\n                {\n                   if (fabs(A[i]-A[k])>0&&fabs(A[i]-A[k])<=2&&A[i]!=A[k]&&A[k]!=A[j])\n                   {\n                       yes=1;\n                       break;\n                   }\n                }\n            }\n        }\n    }\n    if (yes==1)\n    {\n        printf(\"YES\");\n    }\n    else\n        printf(\"NO\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d52dab3d3907793d8e4192eefc3350b7", "src_uid": "d6c876a84c7b92141710be5d76536eab", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main() {\n    int n;\n    while(scanf(\"%d\",&n))\n    {\n        int a[n];\n    int i;\n    for(i=0; i<n; i++) {\n        scanf(\"%d\",&a[i]);\n    }\n    int j;\n    int swap;\n    for (i = 0 ; i < ( n - 1 ); i++)\n        {\n        for (j = 0 ; j < n - i - 1; j++)\n        {\n            if (a[j] > a[j+1]) {\n                  swap=a[j];\n                a[j] = a[j+1];\n                a[j+1]= swap;\n            }\n        }\n    }\n    int y=0;\n    int x=1;\n    int temp=a[0];\n   for(i=1;i<n;i++)\n   {\n   if(a[i]==temp+1)\n   {\n       x++;\n       temp=a[i];\n   }\n   else\n   {\n       temp=a[i];\n   }\n    if(x==3)\n    {\n        printf(\"YES\\n\");\n        y=1;\n        break;\n    }\n\n   }\n   if(y==0)\n    printf(\"NO\\n\");\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ae2f78d7e94ebdb08ba0472e4f9dcbc4", "src_uid": "d6c876a84c7b92141710be5d76536eab", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n     long n,i,j,swap,s=0;\n     scanf(\"%ld\",&n);\n     long a[n];\n     for(i=0;i<n;i++)\n     {\n         scanf(\"%ld\",&a[i]);\n     }\n     for(i=0;i<n-1;i++)\n     {\n         for(j=0;j<n-i-1;j++)\n         {\n             if(a[j]>a[j+1])\n             {\n                 swap=a[j];\n                 a[j]=a[j+1];\n                 a[j+1]=swap;\n             }\n         }\n     }\n     for(i=0;i<n;i++)\n     {\n         for(j=0;j<n-1;j++)\n         {\n             if(a[j]==a[j+1]) a[j]=0;\n         }\n     }\n     for(i=0;i<n-1;i++)\n     {\n         for(j=0;j<n-i-1;j++)\n         {\n             if(a[j]>a[j+1])\n             {\n                 swap=a[j];\n                 a[j]=a[j+1];\n                 a[j+1]=swap;\n             }\n         }\n     }\n    for(i=0;i<n-2;n++)\n    {\n        if(a[i]!=0)\n        {\n            if(a[i+1]==a[i]+1&&a[i+2]==a[i+1]+1)\n            {\n                printf(\"YES\");\n                s=1;\n                break;\n            }\n        }\n    }\n    if(s==0) printf(\"No\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4088cee067bcf5c94f76d12bb7811d41", "src_uid": "d6c876a84c7b92141710be5d76536eab", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    int i,n=0,N,a,b;\n    scanf(\"%d%d%d\",&N,&a,&b);\n    for(i=a+1;i<=N;i++)\n    if(N-i<=b)\n        n++;\n    printf(\"%d\",n);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d3af5253775334ca78026652250e59d9", "src_uid": "51a072916bff600922a77da0c4582180", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,a,b;\n    scanf(\"%d%d%d\",&n,&a,&b);\n\n    printf(\"%d\",n-a<=b+1?n-a:b+1);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "eaefa1e536df97039bf6bb890619635e", "src_uid": "51a072916bff600922a77da0c4582180", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    int i,n=0,N,a,b;\n    scanf(\"%d%d%d\",&N,&a,&b);\n    for(i=a+1;i<=N;i++)\n\tif(N-i<=b)\n\t    n++;\n    printf(\"%d\",n);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "eb8e8bb10cb38258e6e2bea717266e5d", "src_uid": "51a072916bff600922a77da0c4582180", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n\tlong long int n,k=0;\n\tint d;\n\tscanf(\"%lld\",&n);\n\t{\n\t\twhile(n!=0)\n\t\t{\n\t \n\t\t\td=n/10;\n\t\t\tif(d==4||d==7)\n\t\t\t{\n\t\t\t\tk++;\n\t\t\t}\n\t\t\t\n\t\t}\n\t}\t\n\tif((k==4 || k==7)&&k!=0)\n\t{\n\t\tprintf(\"YES\");\n\t}\n\telse\n\t{\n\t\tprintf(\"NO\");\n\t}\n\treturn 0;\n}\t\t\t\t\n\t\t\t\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6c0fc18f373b157a7ca62d68224f2caf", "src_uid": "51a072916bff600922a77da0c4582180", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\n#include<math.h>\n\nint main()\n{\n    int n,a,b;\n    scanf(\"%d %d %d\",&n,&a,&b);\n    if(b>a)\n    {\n        if((a+b)<n)\n        {\n            printf(\"%d\",n-b);\n        }\n        else if(a+b==n)\n        {\n            printf(\"%d\",a+1);\n        }\n        else if((a+b)>n)\n        {\n            printf(\"%d\",a+1);\n        }\n    }\n    else if(a>b)\n    {\n        if((a+b)<n)\n        {\n            printf(\"%d\",n-b);\n        }\n        else if(a+b==n)\n        {\n            printf(\"%d\",a+1);\n        }\n        else if((a+b)>n)\n        {\n            printf(\"%d\",a+1);\n        }\n    }\n    else if(a==b)\n    {\n        if((a+b)<n)\n        {\n            printf(\"%d\",n-b);\n        }\n        else if(a+b==n)\n        {\n            printf(\"%d\",a+1);\n        }\n        else if((a+b)>n)\n        {\n            printf(\"%d\",a+1);\n        }\n    }\n    getch();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a4f4df84f39c50553858ba2e7dc81a98", "src_uid": "51a072916bff600922a77da0c4582180", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint gcd(int a, int b){\n    while(b != 0){\n        int temp = b;\n        b = a%b;\n        a = temp;\n    }\n    return a;\n}\n\nint main(void){\n    int a, b, c, d;\n    scanf(\"%d%d%d%d\", &a, &b, &c, &d);\n    int x = a*c/gcd(a, c);\n    int y = b*d/gcd(b, d);\n    int area1, area2, g;\n    if((x*b)/a >= (x*d)/c){\n        area1 = (x*x*b)/a;\n        area2 = (x*x*d)/c;\n        g = gcd(area1, area2);\n        area1 /= g; area2 /= g;\n        printf(\"%d/%d\\n\", area1-area2, area1);\n    }\n    else{\n        area1 = (y*y*a)/b;\n        area2 = (y*y*c)/d;\n        g = gcd(area1, area2);\n        area1 /= g; area2 /= g;\n        printf(\"%d/%d\\n\", area1-area2, area1);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "60eb3f19a5345eecadac8fe20139900f", "src_uid": "b0f435fc2f7334aee0d07524bc37cb1e", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n\nint mint(a, b)\n{\n\treturn (a > b? b : a);\n}\n\nint maxt(a, b)\n{\n\treturn (a < b? b : a);\n}\n\nint reduce(a, b)\n{\n\tint i = mint(a,b);\n\twhile (i >= 2)\n\t{\n\t\tif (a % i == 0 && b % i == 0)\n\t\t\treturn (i);\n\t\ti--;\n\t}\n\treturn (1);\n}\n\nint main()\n{\n\tint a;\n\tint b;\n\tint c;\n\tint d;\n\tint x;\n\tint y;\n\tint l;\n\tint k;\n\tint z;\n\tint alpha;\n\tint beta;\n\tint big;\n\tint small;\n\n\tscanf(\"%d %d %d %d\", &a, &b, &c, &d);\n\tx = mint(a, b);\n\ty = maxt(a, b);\n\tl = mint(c, d);\n\tk = maxt(c, d);\n\talpha = (x *l);\n\tbeta = (y * k);\n\tz = reduce(alpha, beta);\n\talpha = alpha  / z;\n\tbeta = beta / z;\n\tprintf(\"%d/\", beta -alpha);\n\tprintf(\"%d\", beta );\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4d11d8ea588743df7f57624bd0a57a04", "src_uid": "b0f435fc2f7334aee0d07524bc37cb1e", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n   int a,b,c,d,cnt;\n   scanf(\"%d %d %d %d\",&a,&b,&c,&d);\n   if(c>d)\n    {\n        a*=c;\n        b*=c;\n    }\n    else\n    {\n        a*=d;\n        b*=d;\n    }\n   if((float)a/c>(float)b/d)\n   {\n       a*=d;\n       c*=b;\n       cnt=a-c;\n       printf(\"%d/%d\",cnt/hcf(cnt,a),a/hcf(cnt,a));\n   }\n   else\n   {\n       b*=c;\n       d*=a;\n    cnt=b-d;\n     printf(\"%d/%d\",cnt/hcf(cnt,b),b/hcf(cnt,b));\n   }\n   return 0;\n}\nint hcf(int a,int b)\n{\n    while(a!=b)\n    {\n        if(a>b)\n            a-=b;\n        else\n            b-=a;\n    }\n    return a;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fb1a2a0fe5455827f4f359166a9faf0b", "src_uid": "b0f435fc2f7334aee0d07524bc37cb1e", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint gcd(int a, int b)\n {\n while(a != b) {\n if (a < b) b -= a;\n else a-= b;\n }\n return a;\n }\nint main(){\n    int p,q;\n    __int64 a,b,c,d,e,f,gd;\n    scanf(\"%I64d%I64d%I64d%I64d\",&a,&b,&c,&d);\n    e=a*c*d;\n    f=b*c*d;\n    if(a*d<=b*c){\n        p=b*c-a*d;\n        q=b*c;\n    }\n    else{\n        p=a*d-b*c;\n        q=a*d;\n    }\n    gd=gcd(p,q);\n    p=p/gd;\n    q=q/gd;\n    printf(\"%d/%d\\n\",p,q);\n    return 0;\n}\n    ", "lang_cluster": "C", "compilation_error": false, "code_uid": "c4bf4e3cb81ae388be38d0a65779dde9", "src_uid": "b0f435fc2f7334aee0d07524bc37cb1e", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint count(int n,int m)\n{\n    int r;\n    while(m)\n    {\n        r = n%m;\n        n = m;\n        m = r;\n    }\n    return n;\n}\n\nint main()\n{\n    int a,b,c,d,p,q,k;\n    while(scanf(\"%d %d %d %d\",&a,&b,&c,&d))\n    {\n        p = a*d;\n        q = b*c;\n        if(p>q)\n            k=p;p=q;q=k;\n        k = count(q,p);\n        p = p/k;\n        q = q/k;\n        printf(\"%d/%d\\n\",q-p,q);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1157f10e6291f136533a447eca554a90", "src_uid": "b0f435fc2f7334aee0d07524bc37cb1e", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#include<math.h>\n\nvoid merge(int arr[], int l, int m, int r)\n{\n    int i, j, k;\n    int n1 = m - l + 1;\n    int n2 =  r - m;\n\n\n    int *L=malloc(n1*sizeof(int));int* R=malloc(n2*sizeof(int));\n\n\n    for (i = 0; i < n1; i++)\n        L[i] = arr[l + i];\n    for (j = 0; j < n2; j++)\n        R[j] = arr[m + 1+ j];\n\n\n    i = 0;\n    j = 0;\n    k = l;\n    while (i < n1 && j < n2)\n    {\n        if (L[i] <= R[j])\n        {\n            arr[k] = L[i];\n            i++;\n        }\n        else\n        {\n            arr[k] = R[j];\n            j++;\n        }\n        k++;\n    }\n\n\n    while (i < n1)\n    {\n        arr[k] = L[i];\n        i++;\n        k++;\n    }\n\n\n    while (j < n2)\n    {\n        arr[k] = R[j];\n        j++;\n        k++;\n    }\n}\n\n\nvoid mergeSort(int arr[], int l, int r)\n{\n    if (l < r)\n    {\n        int m = l+(r-l)/2;\n\n\n        mergeSort(arr, l, m);\n        mergeSort(arr, m+1, r);\n\n        merge(arr, l, m, r);\n    }\n}\nint flag=0;\n void find(int size,int *a,int comp)\n{\n    if(size==1){\n        if((a[0]+comp)%360==0||(a[0]-comp)%360==0) flag=1;\n\n    }\n    else{\n        find(size-1,a,comp+a[size-1]);\n        find(size-1,a,comp-a[size-1]);\n    }\n}\nint main()\n{\nint n;\nscanf(\"%d\",&n);\nint *a=malloc(n*sizeof(int));\nint i;\nfor(i=0;i<n;i++)\n    scanf(\"%d\",&a[i]);\n\nfind(n-1,a,a[n-1]);\nif(flag==1) printf(\"YES\");\nelse printf(\"NO\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a1ea1bdcd230cf918b671463157d4817", "src_uid": "01b50fcba4185ceb1eb8e4ba04a0cc10", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\nint n, s = 0, a[20];\nlong long ji[40][400] = {0};\nvoid f(int i, int sum)\n{\n    if (s != 0)\n        return ;\n    int m, n;\n    m = sum + a[i], n = sum - a[i];\n    ji[i][sum]++;\n    if (m > 360)\n        m -= 360;\n    if (n < 0)\n        n += 360;\n    if (i == n)\n        if (sum == 0)\n            s++;\n    if (ji[i + 1][m] == 0)\n        f(i + 1, m);\n    if (ji[i + 1][n] == 0)\n        f(i + 1, n);\n}\nint main()\n{\n    scanf(\"%d\", &n);\n    for (int i = 0; i < n; i++)\n        scanf(\"%d\", &a[i]);\n    f(0, 0);\n    if (s == 0)\n        printf(\"NO\");\n    else\n        printf(\"YES\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9544141da43af0ac8957227612f45469", "src_uid": "01b50fcba4185ceb1eb8e4ba04a0cc10", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\nint n,s = 0, a[20];\nvoid f(int i, int sum)\n{\n    int m,n;\n    m=sum+a[i],n=sum-a[i];\n    if(m>360)\n        m-=360;\n    if(n<0)\n        n+=360;\n    if(i==n)\n        if(sum==0)\n            s++;\n    f(i+1,m);\n    f(i+1,n);\n}\nint main()\n{\n    scanf(\"%d\", &n);\n    for (int i = 0; i < n; i++)\n        scanf(\"%d\", &a[i]);\n    f(0, 0);\n    if (s == 0)\n        printf(\"NO\");\n    else\n        printf(\"YES\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4d14d6c8d3d9dc030636c3a93cd73723", "src_uid": "01b50fcba4185ceb1eb8e4ba04a0cc10", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\nint n,s = 0, a[20];\nvoid f(int i, int sum)\n{\n    if(s!=0)\n        return ;\n    int m,n;\n    m=sum+a[i],n=sum-a[i];\n    if(m>360)\n        m-=360;\n    if(n<0)\n        n+=360;\n    if(i==n)\n        if(sum==0)\n            s++;\n    f(i+1,m);\n    f(i+1,n);\n}\nint main()\n{\n    scanf(\"%d\", &n);\n    for (int i = 0; i < n; i++)\n        scanf(\"%d\", &a[i]);\n    f(0, 0);\n    if (s == 0)\n        printf(\"NO\");\n    else\n        printf(\"YES\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "890458c3b391300a831b73662b742b91", "src_uid": "01b50fcba4185ceb1eb8e4ba04a0cc10", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint a[16];\nint flag=0;\nvoid check(int sum,int i,int t)\n{\n\tint a1;\n\ta1=sum+a[i];\n\tint b;\n\tb=sum-a[i];\n\tif(i==t&&(a1==0||b==0))\n\t{flag=1;\n\t\treturn ;\n\t}\n\tif(i==t)\n\t\treturn ;\n\tcheck(a1,i+1,t);\n\t\tcheck(b,i+1,t);\n}\nint main(void)\n{\n\tint t,sum=0;\nscanf(\"%d\",&t);\t\nfor(int i=0;i<t;i++)\n\t{\n\t\tscanf(\"%d\",&a[i]);\n\t\tsum+=a[i];\n\t}\n\tif(sum%360==0)\n\t\tprintf(\"YES\");\n\telse{\n\t\tcheck(0,0,t);\n\t\tif(flag==1)\n\t\t\tprintf(\"YES\");\n\t\telse\n\t\t\tprintf(\"NO\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bad2b4e5a2b33863c5996be8a1778b20", "src_uid": "01b50fcba4185ceb1eb8e4ba04a0cc10", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    long long int x, rem, steps = 0;\n    long long int count_5=0, count_4=0, count_3=0, count_2=0, count_big=0;\n\n    scanf(\"%lld\", &x);\n    while (x!=0)\n    {\n\n\n    if (x>=5)\n    {\n        x = x - 5;\n        steps = steps + 1;\n        count_5 += 1;\n    }\n\n    else if (x>=4)\n    {\n        x = x - 4;\n        steps += 1;\n        count_4 += 1;\n    }\n\n    else if (x>=3)\n    {\n        x = x - 3;\n        steps+=1;\n        count_3 += 1;\n    }\n\n    else if (x>=2)\n    {\n        x = x - 2;\n        steps+=1;\n        count_2 += 1;\n    }\n    else if (x>=1)\n    {\n        steps += 1;\n        count_big += x;\n    }\n\n}\nprintf(\"%lld\",steps);\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0b0350a25ec90a4df8a9ccc61d059578", "src_uid": "4b3d65b1b593829e92c852be213922b6", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n      int n,a;\n      scanf(\"%d\",&n);\n      a=fun(n);\n      printf(\"%d\",a);\n      return 0;\n}\nint fun(int n)\n{\n      int c=0;\n      if(n>=5)\n      {\n      n=n-5;\n      c++;\n      fun(n);\n      }\n       if(n>=4)\n      {\n            n=n-4;\n            c++;\n            fun(n);\n      }\n       if(n>=3)\n      {\n            n=n-3;\n            c++;\n            fun(n);\n      }\n       if(n>=2)\n      {\n           n=n-2;\n           c++;\n           fun(n);\n      }\n       if(n==1)\n      {\n           c++; \n      }\n      return c;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "04a0837bdb543e7a4a3ba7760d9aa72f", "src_uid": "4b3d65b1b593829e92c852be213922b6", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int x,i,s,m=0;\n    scanf(\"%d\",&x);\n    for(i=0;i<=x;)\n    {\n        m++;\n        s=x-i;\n        s>=5?i+=5:s==4?i+=4:s==3?i+=3:s==2?i+=2:s==1?i+=1:0;\n    }\n    printf(\"%d\",m);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "abe50184e8749d38681d48f1a594d44c", "src_uid": "4b3d65b1b593829e92c852be213922b6", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int x,i,s,m=0;\n    scanf(\"%d\",&x);\n    for(i=0;i<=x;)\n    {\n        s=x-i;\n        if(s>=5)\n        i+=5;\n        else if(s==4)\n        i+=4;\n        else if(s==3)\n        i+=3;\n        else if(s==2)\n        i+=2;\n        else if(s==1)\n        i+=1;\n        m++;\n    }\n    printf(\"%d\",m);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ae7bdb8d774a46b5fcbfd11398477e27", "src_uid": "4b3d65b1b593829e92c852be213922b6", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint n;\nint min(int a,int b)\n{\n\tif(a>b)\n\treturn b;\n\treturn a;\n}\n/*int solve(int currstate,int ans)\n{\n\tif(currstate==n)\n\treturn ans;\n\telse\n\treturn min(solve(currstate+1,ans+1),min(min(solve(currstate+2,ans+1),solve(currstate+3,ans+1))));\n}*/\nint main()\n{\n\tscanf(\"%d\",&n);\n\tif(n<=5)\n\tprintf(\"1\\n\");\n\telse\n\tprintf(\"%d\\n\",n/5+1);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d6b081f05fe46320d61163c3ee1938e6", "src_uid": "4b3d65b1b593829e92c852be213922b6", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main(){\n\tint n,*t,i,j,k;\n\tscanf(\"%d\",&n);\n\tt=(int*)malloc(n*sizeof(int));\n\tif(n<3){\n\t\tprintf(\"NO\");\n\t\treturn 1;\n\t}\n\tfor(i=0;i<n;i++)\n\t\tscanf(\"%d\",&t[i]);\n\tfor(i=0;i<n;i++)\n\t\tfor(j=i+1;j<n-1;j++)\n\t\t\tfor(k=j+1;k<n;k++)\n\t\t\t\tif(t[i]<t[j]+t[k] && t[i]+t[j]>t[k] && t[j]<t[i]+t[k] )\n\t\t\t\t\t{printf(\"YES\");\n\t\t\t\t\t return 1;\n\t\t\t\t\t}\n\t\t\t\t\t\n\tprintf(\"NO\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "930a0a5f8e6cea82b0c072947cf5aa7c", "src_uid": "897bd80b79df7b1143b652655b9a6790", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nvoid merge(int x[],int first,int mid, int last)\n{\n    int i=first, j=mid+1, k=first, y[last-first+1];\n\n    while(i<=mid&&j<=last)\n    {\n        if(x[i]<=x[j]) {y[k++]=x[i++];}\n        else {y[k++]=x[j++];}\n\n    }\n\n    while(j<=last) y[k++]=x[j++];\n    while(i<=mid) y[k++]=x[i++];\n\n    for(k=first; k<=last; k++)  x[k]=y[k];\n}\n\n\n\n\nvoid sort(int x[],int first,int last)\n{\n    if(first<last)\n    {\n        int mid=(first+last)/2;\n\n        sort(x,first,mid);\n        sort(x,mid+1,last);\n        merge(x,first,mid,last);\n    }\n\n    else return;\n}\n\n\nint main()\n\n{\n    int n,i,j,min,k;\n\n    scanf(\"%d\",&n);\n\n    int x[n];\n\n    for(i=0;i<n;i++)\n        scanf(\"%d\",&x[i]);\n\n    sort(x,0,n-1);\n\n    for(i=0;i<n-2;i++)\n    {\n        if(x[i]+x[i+1]>x[i+2]){printf(\"YES\"); break;}\n    }\n\n    if(i==n-2) printf(\"NO\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3343655374400443db4bc53dce1acaef", "src_uid": "897bd80b79df7b1143b652655b9a6790", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nvoid merge(int x[],int first,int mid, int last)\n{\n    int i=first, j=mid+1, k=first, y[last-first+1];\n\n    while(i<=mid&&j<=last)\n    {\n        if(x[i]<=x[j]) {y[k]=x[i]; i++;}\n        else {y[k]=x[j]; j++;}\n        k++;\n    }\n\n    if(i>mid) { while(j<=last) {y[k]=x[j]; j++; k++; }}\n    else { while(i<=mid) {y[k]=x[i]; i++; k++; }}\n\n    for(k=first; k<=last; k++)  x[k]=y[k];\n}\n\n\n\n\nvoid sort(int x[],int first,int last)\n{\n    if(first<last)\n    {\n        int mid=(first+last)/2;\n\n        sort(x,first,mid);\n        sort(x,mid+1,last);\n        merge(x,first,mid,last);\n    }\n}\n\nint main()\n\n{\n    int n,i,j,min,k;\n\n    scanf(\"%d\",&n);\n\n    int x[n];\n\n    for(i=0;i<n;i++)\n        scanf(\"%d\",&x[i]);\n\n    sort(x,0,n-1);\n\n    for(i=0;i<n-2;i++)\n    {\n        if(x[i]+x[i+1]>x[i+2]){printf(\"YES\"); break;}\n    }\n\n    if(i==n-2) printf(\"NO\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ac0382c23d2a2d46109cc8d17b33d0ab", "src_uid": "897bd80b79df7b1143b652655b9a6790", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nvoid r_pivot(int *a, int *b)\n{\n    int i, *r=a+(rand()%(b-a+1));\n    i=*r;*r=*a;*a=i;\n}\n\nint partition(int *a,int *b)\n{\n    r_pivot(a,b);\n    int *pvt=a, j;\n    a--;b++;\n    while(1)\n    {\n        while(1)\n        {\n            a++;\n            if(*a>=*pvt)break;\n        }\n        while(1)\n        {\n            b--;\n            if(*b<=*pvt)break;\n        }\n        if(a>b) return b;\n        else {j=*a;*a=*b;*b=j;}\n    }\n\n}\n\nvoid sort(int *a, int *b)\n{\n    if(a<b)\n    {\n        int *p=partition(a,b);\n        sort(a,p);\n        sort(p+1,b);\n    }\n}\n\nint main()\n{\n    int n, i, j=0;\n    scanf(\"%d\",&n);\n    long int a[n];\n    for(i=0;i<n;i++)\n        scanf(\"%ld\",&a[i]);\n    sort(&a[0],&a[n-1]);\n    for(i=0;i<n-2;i++)\n        if(a[i]+a[i+1]>a[i+2]){j=1;break;}\n    printf(j?\"YES\\n\":\"NO\\n\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ddb38fa6fadd92622b1604288f6aba3c", "src_uid": "897bd80b79df7b1143b652655b9a6790", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n// \u0424\u0443\u043d\u043a\u0446\u0438\u044f \u0441\u043e\u0440\u0442\u0438\u0440\u043e\u0432\u043a\u0438 \u043d\u0438\u0441\u0445\u043e\u0434\u044f\u0449\u0438\u043c \u0441\u043b\u0438\u044f\u043d\u0438\u0435\u043c\n\nvoid mergeSort(int *a, int l, int r)\n{\n  if (l == r) return; // \u0433\u0440\u0430\u043d\u0438\u0446\u044b \u0441\u043e\u043c\u043a\u043d\u0443\u043b\u0438\u0441\u044c\n  int mid = (l + r) / 2; // \u043e\u043f\u0440\u0435\u0434\u0435\u043b\u044f\u0435\u043c \u0441\u0435\u0440\u0435\u0434\u0438\u043d\u0443 \u043f\u043e\u0441\u043b\u0435\u0434\u043e\u0432\u0430\u0442\u0435\u043b\u044c\u043d\u043e\u0441\u0442\u0438\n  // \u0438 \u0440\u0435\u043a\u0443\u0440\u0441\u0438\u0432\u043d\u043e \u0432\u044b\u0437\u044b\u0432\u0430\u0435\u043c \u0444\u0443\u043d\u043a\u0446\u0438\u044e \u0441\u043e\u0440\u0442\u0438\u0440\u043e\u0432\u043a\u0438 \u0434\u043b\u044f \u043a\u0430\u0436\u0434\u043e\u0439 \u043f\u043e\u043b\u043e\u0432\u0438\u043d\u044b\n  mergeSort(a, l, mid);\n  mergeSort(a, mid + 1, r);\n  int i = l;  // \u043d\u0430\u0447\u0430\u043b\u043e \u043f\u0435\u0440\u0432\u043e\u0433\u043e \u043f\u0443\u0442\u0438\n  int j = mid + 1; // \u043d\u0430\u0447\u0430\u043b\u043e \u0432\u0442\u043e\u0440\u043e\u0433\u043e \u043f\u0443\u0442\u0438\n  int *tmp = (int*)malloc(r * sizeof(int)); // \u0434\u043e\u043f\u043e\u043b\u043d\u0438\u0442\u0435\u043b\u044c\u043d\u044b\u0439 \u043c\u0430\u0441\u0441\u0438\u0432\n  for (int step = 0; step < r - l + 1; step++) // \u0434\u043b\u044f \u0432\u0441\u0435\u0445 \u044d\u043b\u0435\u043c\u0435\u043d\u0442\u043e\u0432 \u0434\u043e\u043f\u043e\u043b\u043d\u0438\u0442\u0435\u043b\u044c\u043d\u043e\u0433\u043e \u043c\u0430\u0441\u0441\u0438\u0432\u0430\n  {\n    // \u0437\u0430\u043f\u0438\u0441\u044b\u0432\u0430\u0435\u043c \u0432 \u0444\u043e\u0440\u043c\u0438\u0440\u0443\u0435\u043c\u0443\u044e \u043f\u043e\u0441\u043b\u0435\u0434\u043e\u0432\u0430\u0442\u0435\u043b\u044c\u043d\u043e\u0441\u0442\u044c \u043c\u0435\u043d\u044c\u0448\u0438\u0439 \u0438\u0437 \u044d\u043b\u0435\u043c\u0435\u043d\u0442\u043e\u0432 \u0434\u0432\u0443\u0445 \u043f\u0443\u0442\u0435\u0439\n    // \u0438\u043b\u0438 \u043e\u0441\u0442\u0430\u0442\u043e\u043a \u043f\u0435\u0440\u0432\u043e\u0433\u043e \u043f\u0443\u0442\u0438 \u0435\u0441\u043b\u0438 j > r\n    if ((j > r) || ((i <= mid) && (a[i] < a[j]))) \n    {\n      tmp[step] = a[i];\n      i++;\n    }\n    else \n    {\n      tmp[step] = a[j];\n      j++;\n    }\n  }\n  // \u043f\u0435\u0440\u0435\u043f\u0438\u0441\u044b\u0432\u0430\u0435\u043c \u0441\u0444\u043e\u0440\u043c\u0438\u0440\u043e\u0432\u0430\u043d\u043d\u0443\u044e \u043f\u043e\u0441\u043b\u0435\u0434\u043e\u0432\u0430\u0442\u0435\u043b\u044c\u043d\u043e\u0441\u0442\u044c \u0432 \u0438\u0441\u0445\u043e\u0434\u043d\u044b\u0439 \u043c\u0430\u0441\u0441\u0438\u0432\n  for (int step = 0; step < r - l + 1; step++)\n    a[l + step] = tmp[step];\n}\n\n\nint main()\n{\n  int n, b[100001], flag = 0;\n\n  scanf(\"%d\", &n);\n  for (int i = 0; i < n; i++)\n    scanf(\"%d\", &b[i]);\n\n  mergeSort (b, 0, n-1);\n\n\n  for (int i = 1; i < n-1; i++)\n  {\n    if (b[i]+b[i-1] > b[i+1])\n    {\n      printf(\"YES \\n\");\n      flag = 1;\n      break;\n     }\n  }\n\n  if (flag == 0)\n    printf(\"NO \\n\");\n\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c49277162ba11870aff5d5dafc314194", "src_uid": "897bd80b79df7b1143b652655b9a6790", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nvoid main()\n{\n    int n,i,p1=1,p2=2,temp=3;\n    scanf(\"%d\",&n);\n    int a[n];\n    for (i=0;i<n;i++){\n        scanf(\"%d\",&a[i]);\n        if(a[i]==temp){\n            printf(\"NO\");\n            exit(0);\n        }\n        temp=6-a[i]-temp;\n    }\n    printf(\"YES\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1ffdd09cab66b2594ac417ba880cd1aa", "src_uid": "6c7ab07abdf157c24be92f49fd1d8d87", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nmain()\n{\n    int k,i,n,num[10],player1=1,player2=2,waiter=3,winner,loser,possible=1;\n    scanf(\"%d\",&n);\n    for (i=0;i<n;i++)\n        {\n        scanf(\"%d\",&num[i]);\n        }\n    for (i=0;i<n;i++)\n        {\n        //printf(\"p1-%d p2-%d w-%d\\n\",player1,player2,waiter);\n        winner=num[i];\n        if (winner==loser) possible=0;\n            else\n            {\n            if ((winner==1)&&(waiter==2)) loser=3;\n            if ((winner==1)&&(waiter==3)) loser=2;\n            if ((winner==2)&&(waiter==1)) loser=3;\n            if ((winner==2)&&(waiter==3)) loser=1;\n            if ((winner==3)&&(waiter==1)) loser=2;\n            if ((winner==3)&&(waiter==2)) loser=1;\n            player1=winner;\n            player2=waiter;\n            waiter=loser;\n            }\n        }\n    if (possible==0) printf(\"NO\"); else printf(\"YES\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e02a9f3cb5e6fee1377adf9f7fc9e2cd", "src_uid": "6c7ab07abdf157c24be92f49fd1d8d87", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\nint a=1,b=2,c=3,n,i,x=3,ok=1,aux;\nscanf(\"%d\",&n);\n\nwhile(n){\n    scanf(\"%d\",&i);\n    if(i==x){ok=0;break;}\n    else if(i==a){\n        aux=b;\n        b=x;\n        x=aux;\n    }\n    else if(i==b){\n        aux=a;\n        a=x;\n        x=aux;\n    }\n}\nif(ok==1)printf(\"YES\");\nelse printf(\"NO\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5a3dd0806db459773a7704eaa72c6323", "src_uid": "6c7ab07abdf157c24be92f49fd1d8d87", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\n\tFILE *prb=fopen(\"prb.in\",\"r\");\n\tint n,alex=1,bob=2,carl=3,num[110],t,m=0;\n\tfscanf(prb,\"%d\",&n);\n\tint i;\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tfscanf(prb,\"%d\",&num[i]);\n\t}\n\tfor(i=1;i<=n;i++)\n\t{\n\t    if (num[i]==carl)\n\t    {\n\t    \tm=1;\n\t    }\n\n\t\tif(num[i]==alex)\n\t\t{\n\t\t\tt=bob;\n\t\t\tbob=carl;\n\t\t\tcarl=t;\n\t\t}\n\t\telse if(num[i]==bob)\n\t\t{\n\t\t\tt=alex;\n\t\t\talex=carl;\n\t\t\tcarl=t;\n\t\t}\n\t\n\t}\n\tif(m==0)\n\tprintf(\"YES\\n\");\n    else\n    \tprintf(\"NO\\n\");\n\n\treturn 0;\n\t\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4e132afb1828d4c835c3053638cace74", "src_uid": "6c7ab07abdf157c24be92f49fd1d8d87", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(void){\n  int NOR,winner[NOR],i,cntAL=0,cntCA=0,cntBO=0;\n  scanf(\"%d\",&NOR);\n  for(i=0;i<NOR;i++){\n    scanf(\"%d\",&winner[i]);\n  }\n  for(i=0;i<NOR;i++){\n    if(winner[i]== 1)\n       cntAL++;\n    else if(winner[i]== 3){\n       cntCA++;\n    }\n    else if(winner[i]== 2){\n      cntBO++;\n    }\n   \n    }\n     if(cntAL>(NOR/2)|| cntBO>(NOR/2) || cntCA>(NOR/2)){\n      printf(\"YES\");\n    }\n      else \n      printf(\"NO\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "cce0dc810f5807067a02a2d9b8f90412", "src_uid": "6c7ab07abdf157c24be92f49fd1d8d87", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint number_of_chip( int n, int m );\n\nint main (int argc, const char * argv[])\n{\n  \n  int n = 0;\n  int m = 0;\n  scanf(\"%d\", n);\n  scanf(\"%d\", m);\n  number_of_chip(argv[0], argv[1]);\n  return 0;\n}\n\nint number_of_chip( int n, int m )\n{\n  if ( n >= 1 && n <= 50 && m >= 1 && m <= 10e-4 ) \n  {\n    int i = 0;\n    \n    while(1)\n    {\n      for ( i=0; i<n; i++ )\n      {\n        m -= (i+1);\n        \n        if ( m == 0 )\n          return 0;\n        \n        if ( m < 0 )\n        {\n          m += (i+1);\n          return m;\n        }\n      }\n    }\n    return m;\n  }\n  return -1;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "924abb887455178fc8224b5906d36cc6", "src_uid": "5dd5ee90606d37cae5926eb8b8d250bb", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\nint main(void)\n{\n    int i,n,m,out;\n    while(scanf(\"%d%d\",&n,&m)!=EOF)\n    {\n         out=n*(n+1)/2;\n         m=m%out;\n         i=1;\n         while(m>=i)\n         {\n             m-=i;\n             i++;\n             }\n         \n         printf(\"%d\",m);\n         }\n          \n         system(\"pause\");\n         return 0;\n         }", "lang_cluster": "C", "compilation_error": false, "code_uid": "af1fcf544e2a750e8848aa732838b26d", "src_uid": "5dd5ee90606d37cae5926eb8b8d250bb", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<math.h>\n\nint main()\n{\n    long long int n,m,i;\n    scanf(\"%I64d %I64d\",&n,&m);\n    for(i=1;i<=n;i++)\n    {\n       if(m>=i)\n        {\n            m=m-i;\n        }\n        if(i==n)\n        {\n            i=0;\n        }\n        if(m<i)\n        {\n            break;\n        }\n    }\n    printf(\"%I64d\",m);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b22038472345fc3462882dbfd203d5c1", "src_uid": "5dd5ee90606d37cae5926eb8b8d250bb", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n int m,n,i,k;\n scanf(\"%d%d\",&m,&n);\n    if (n==m)\n    printf(\"0\");\n    else\n    {\n    x:\n    k=0;\n    for (i=1;i<=m;i++)\n    {\n    if (n>=i)\n    n=n-i;\n    k++;\n    if (n<=i)\n    break;\n    }\n    if (k==m)\n    goto x;\n    else\n    {\n        if (n<=i)\n    {\n        printf(\"%d\",n);\n    }\n    else\n     printf(\"0\");\n    }\n    }\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7feb058aafb70a74a52604404c592f15", "src_uid": "5dd5ee90606d37cae5926eb8b8d250bb", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "\n#include<stdio.h>\n#include<math.h>\nint main()\n{\n    int n,m,s,p,q,t,z;\n    scanf(\"%d %d\",&n ,&m);\n    s=n*(n+1)/2;\n    p=m/s;\n    q=(-1+sqrt(1+(4*1*2*p)))/2;\n    t=m-(p*s);\n\n    while(t>(p*s))\n    {\n        z=t-((q*q+q)/2);\n\n    }\n    printf(\"%d\",z);\n    return 0;\n\n\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "370bd91172a1478a6050c0f77e83fd06", "src_uid": "5dd5ee90606d37cae5926eb8b8d250bb", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define MAX 100\nint obrada(int a[MAX][MAX], int k, int m);\nvoid main() {\n\tint a[MAX][MAX] = { 0 };\n\tint n, k, m, s = 0;\n\ta[0][0] = a[1][0] = 1;\n\t//scanf(\"%d\", &n);\n\t//for (int i = 0; i < n; i++) {\n\t\tscanf(\"%d%d\", &k, &m);\n\t\ts += obrada(a, k - 1, m - 1);\n\t//}\n\tprintf(\"%d\\n\", s);\n}\n\nint obrada(int a[MAX][MAX], int k, int m)\n{\n\tint p, b;\n\tif (k < m) p = k, k = m, m = p;\n\tif (a[k][m] == 0 && k != -1 && m != -1) {\n\t\tif (k == m == 100) a[k][m] += 1 + obrada(a, k, m - 2);\n\t\telse a[k][m] += 1 + obrada(a, k - 2, m + 1);\n\t}\n\treturn a[k][m];\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "cdb06fab7b06d3dad2bac1d1de1b5822", "src_uid": "ba0f9f5f0ad4786b9274c829be587961", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void) {\n\t// your code goes here\n\t\n\t\n\tint a1,a2,n,i=0,j,k;\n\tscanf(\"%d%d\",&a1,a2);\n\t\n\twhile(a1>0&&a2>0)\n\t{i++;\n\t    \n\t    if(a1>a2){\n\t        \n\t        a1=a1-2;\n\t        a2=a2+1;\n\t    }\n\t    else{\n\t        \n\t        a1=a1+1;\n\t        a2=a2-2;\n\t    }\n\t    \n\t    \n\t}\n\t\n\tprintf(\"%d\",i);\n\t\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "672c15635ff98a8bec72cc7d982a5d28", "src_uid": "ba0f9f5f0ad4786b9274c829be587961", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define MAX 100\nint obrada(int a[MAX][MAX], int k, int m);\nint main() {\n\tint a[MAX][MAX] = { 0 };\n\tint n, k, m, s = 0;\n\ta[0][0] = a[1][0] = 1;\n\t//scanf(\"%d\", &n);\n\t//for (int i = 0; i < n; i++) {\n\t\tscanf(\"%d%d\", &k, &m);\n\t\ts += obrada(a, k - 1, m - 1);\n\t//}\n\tprintf(\"%d\\n\", s);\n\treturn 0;\n}\n\nint obrada(int a[MAX][MAX], int k, int m)\n{\n\tint p, b;\n\tif (k < m) p = k, k = m, m = p;\n\tif (a[k][m] == 0 && k != -1 && m != -1) {\n\t\tif (k == m == 100) a[k][m] += 1 + obrada(a, k, m - 2);\n\t\telse a[k][m] += 1 + obrada(a, k - 2, m + 1);\n\t}\n\treturn a[k][m];\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a2cc387b23ef6b8d6a8e47195544cf01", "src_uid": "ba0f9f5f0ad4786b9274c829be587961", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#define _CRT_SECURE_NO_WARNINGS\n\n#include <stdio.h>\n\nint main() {\n\t\n\tint a1, a2;\n\tint res = 0;\n\tint d;\n\tint *pc, *pf, *t;\n\n\tscanf(\"%d%d\", &a1, &a2);\n\n\tpf = &a1; pc = &a2;\n\twhile (a1 > 2 || a2 > 2) {\n\t\td = (*pf - 1) / 2;\n\t\tres += d;\n\t\t*pf -= 2 * d;\n\t\t*pc += d;\n\t\tt = pc; pc = pf; pf = t;\n\t}\n\n\tprintf(\"%d\", res + 1);\n\tgetch();\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e6f9590ab9af9862eeac6293a02fac2b", "src_uid": "ba0f9f5f0ad4786b9274c829be587961", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n\nint main()\n{\n\tint a1,a2;\n\tscanf(\"%d %d\",&a1,&a2);\n\tint dakika=1;\n\tif(a1+a2<=3)\n\tprintf(\"0\");\n\telse\n\t{\t\n\t\twhile(1)\n\t\t{\n\t\t\tif((a1+a2==3) || (a1==2 && a2==2))\n\t\t\t{\n\t\t\t\tprintf(\"%d\",dakika);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tif(a1<a2)\n\t\t\t{\t\n\t\t\t\ta2=a2-2;\n\t\t\t\ta1++;\n\t\t\t}\n\t\t\telse\n\t\t\t{\t\n\t\t\t\ta1=a1-2;\n\t\t\t\ta2++;\n\t\t\t}\n\t\t\tdakika++;\n\t\t}\n\t}\t\n\t\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "63f210c405a356b4d25c1b0c74b4d4a4", "src_uid": "ba0f9f5f0ad4786b9274c829be587961", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main () {\n\tint i,a,j,b,e;\n\tchar t[500]={0},g[500] = {0},h[30],A[15],B[15],E[15];\n\n\tscanf(\"%d\",&a);\n\t//a'n\u0131n elemanlar\u0131\n\tfor(i=0;i<a;i++)\n\t\tscanf(\" %c\",&A[i]);\n\t//b'nin elemanlar\u0131\n\tscanf(\"%d\",&b);\n\tfor(i=0;i<b;i++)\n\t\tscanf(\" %c\",&B[i]);\n\t//e'nin elemanlar\u0131\n\tscanf(\"%d\",&e);\n\tfor(i=0;i<e;i++)\n\t\tscanf(\" %c\",&E[i]);\n\t//A kesi\u015fim B\n\tfor(j=0;j<b;j++){\n\t\tfor(i=0;i<a;i++)\n\t\t\tif(A[i]==B[j])\n\t\t\t\tprintf(\"%c \",A[i]);\n\t}\n\tprintf(\"\\n\");\n\t// A birle\u015fim B (a fark b + a kesi\u015fim b + b fark a )\n\tfor(i=0;i<a;i++) {\n\t\tfor(j=0;j<b;j++)\n\t\t\tif(A[i]==B[j])\n\t\t\t\th[A[i]]++;\n\t\tif(h[A[i]] == 0)\n\t\t\tprintf(\"%c \",A[i]);\n\t}\n\tfor(j=0;j<b;j++){\n\t\tfor(i=0;i<a;i++)\n\t\t\tif(A[i]==B[j])\n\t\t\t\tprintf(\"%c \",A[i]);\n\t}\n\tfor(i=0;i<b;i++) {\n\t\tfor(j=0;j<a;j++)\n\t\t\tif(B[i]==A[j])\n\t\t\t\tt[B[i]]++;\n\t\tif(t[B[i]] == 0)\n\t\t\tprintf(\"%c \",B[i]);\n\t}\n\n\n\tprintf(\"\\n\");\n\n\n\n\t//A fark B\n\tfor(i=0;i<a;i++) {\n\t\tfor(j=0;j<b;j++)\n\t\t\tif(A[i]==B[j])\n\t\t\t\th[A[i]]++;\n\t\tif(h[A[i]] == 0) \n\t\t\tprintf(\"%c \",A[i]);\n\t}\n\tprintf(\"\\n\");\n\t//A'n\u0131n de\u011fili\n\tfor(i=0;i<e;i++) {\n\t\tfor(j=0;j<a;j++)\n\t\t\tif(E[i]==A[j])\n\t\t\t\tg[E[i]]++;\n\t\tif(g[E[i]] == 0)\n\t\t\tprintf(\"%c \",E[i]);\n\t}\n\tprintf(\"\\n\");\n\treturn 0 ;\n}\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d6df1b09508c48a9b3643b0f6a17a3b6", "src_uid": "f13eba0a0fb86e20495d218fc4ad532d", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "# include <stdio.h>\n\nint main()\n{\n\tchar a[105];\n\tint b[26];\n\tint x, i, n;\n\tint flag = 0;\n\twhile(scanf(\"%d\", &n)!=EOF)\n\t{\t\n\t\tgetch();\n\t\tfor(i = 0; i < n; i++)\n\t\t\tscanf(\"%c\", &a[i]);\t\n\t\tfor (i = 0; i < 26; i++)\n\t\t\tb[i] = 0;\n\t\tfor(i = 0; i < n; i++)\n\t\t{\n\t\t\tif('a' <= a[i] && a[i] <= 'z')\n\t\t\t\t{\n\t\t\t\t\tx = a[i] - 'a';\n\t\t\t\t\t\tb[x]++;\n\t\t\t\t}\n\t\t\tif('A' <= a[i] && a[i] <= 'Z')\n\t\t\t\t{\n\t\t\t\t\tx = a[i] - 'A';\n\t\t\t\t\t\tb[x]++;\n\t\t\t\t}\n\t\t}\n\t\t\tflag = 0;\n\t\t\tfor (i = 0; i < 26; i++)\n\t\t\t{\n\t\t\t\tif(b[i] != 0) flag = 1; break;\n\t\t\t}\n\t\t\tif(flag) \n\t\t\t\tprintf(\"NO\\n\");\n\t\t\telse\n\t\t\t\tprintf(\"YES\\n\");\n\t}\n\treturn 0;\n}\n\n       ", "lang_cluster": "C", "compilation_error": false, "code_uid": "b4fb5308494e3fb9b606feead5effc6b", "src_uid": "f13eba0a0fb86e20495d218fc4ad532d", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "# include <stdio.h>\n\nint main()\n{\n\tchar a[101];\n\tint b[26];\n\tint x, i, n;\n\tint flag = 0;\n\twhile(scanf(\"%d\", &n)!=EOF)\n\t{\t\n\t\tgetch();\n\t\tfor(i = 0; i < n; i++)\n\t\t\tscanf(\"%c\", &a[i]);\t\n\t\tfor (i = 0; i < 26; i++)\n\t\t\tb[i] = 0;\n\t\tfor(i = 0; i < n; i++)\n\t\t{\n\t\t\tif('a' <= a[i] && a[i] <= 'z')\n\t\t\t\t{\n\t\t\t\t\tx = a[i] - 'a';\n\t\t\t\t\t\tb[x]++;\n\t\t\t\t}\n\t\t\tif('A' <= a[i] && a[i] <= 'Z')\n\t\t\t\t{\n\t\t\t\t\tx = a[i] - 'A';\n\t\t\t\t\t\tb[x]++;\n\t\t\t\t}\n\t\t}\n\t\t\tflag = 0;\n\t\t\tfor (i = 0; i < 26; i++)\n\t\t\t{\n\t\t\t\tif(b[i] != 0) flag = 1; break;\n\t\t\t}\n\t\t\tif(flag) \n\t\t\t\tprintf(\"NO\\n\");\n\t\t\telse\n\t\t\t\tprintf(\"YES\\n\");\n\t}\n\treturn 0;\n}\n\n                                                  ", "lang_cluster": "C", "compilation_error": false, "code_uid": "678e34478b635a3d1c698f2af841e70a", "src_uid": "f13eba0a0fb86e20495d218fc4ad532d", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "# include <stdio.h>\n\nint main()\n{\n\tchar a[105];\n\tint b[26];\n\tint x, i, n;\n\tint flag = 0;\n\twhile(scanf(\"%d\", &n)!=EOF)\n\t{\t\n\t\tgetch();\n\t\tfor(i = 0; i < n; i++)\n\t\t\tscanf(\"%c\", &a[i]);\t\n\t\tfor (i = 0; i < 26; i++)\n\t\t\tb[i] = 0;\n\t\tfor(i = 0; i < n; i++)\n\t\t{\n\t\t\tif('a' <= a[i] && a[i] <= 'z')\n\t\t\t\t{\n\t\t\t\t\tx = a[i] - 'a';\n\t\t\t\t\t\tb[x]++;\n\t\t\t\t}\n\t\t\tif('A' <= a[i] && a[i] <= 'Z')\n\t\t\t\t{\n\t\t\t\t\tx = a[i] - 'A';\n\t\t\t\t\t\tb[x]++;\n\t\t\t\t}\n\t\t}\n\t\t\tflag = 0;\n\t\t\tfor (i = 0; i < 26; i++)\n\t\t\t{\n\t\t\t\tif(b[i] == 0){ flag = 1; break;}\n\t\t\t}\n\t\t\tif(flag) \n\t\t\t\tprintf(\"NO\\n\");\n\t\t\telse\n\t\t\t\tprintf(\"YES\\n\");\n\t}\n\treturn 0;\n}\n\n  ", "lang_cluster": "C", "compilation_error": false, "code_uid": "ee96e4793d9a7de7b9c8d9d59e447676", "src_uid": "f13eba0a0fb86e20495d218fc4ad532d", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "# include <stdio.h>\n\nint main()\n{\n\tchar a[50];\n\tint b[26];\n\tint x, i, n;\n\tint flag = 0;\n\twhile(scanf(\"%d\", &n)!=EOF)\n\t{\t\n\t\tgetch();\n\t\tfor(i = 0; i < n; i++)\n\t\t\tscanf(\"%c\", &a[i]);\t\n\t\tfor (i = 0; i < 26; i++)\n\t\t\tb[i] = 0;\n\t\tfor(i = 0; i < n; i++)\n\t\t{\n\t\t\tif('a' <= a[i] && a[i] <= 'z')\n\t\t\t\t{\n\t\t\t\t\tx = a[i] - 'a';\n\t\t\t\t\t\tb[x]++;\n\t\t\t\t}\n\t\t\tif('A' <= a[i] && a[i] <= 'Z')\n\t\t\t\t{\n\t\t\t\t\tx = a[i] - 'A';\n\t\t\t\t\t\tb[x]++;\n\t\t\t\t}\n\t\t}\n\t\t\tflag = 0;\n\t\t\tfor (i = 0; i < 26; i++)\n\t\t\t{\n\t\t\t\tif(b[i] != 0) flag = 1; break;\n\t\t\t}\n\t\t\tif(flag) \n\t\t\t\tprintf(\"NO\\n\");\n\t\t\telse\n\t\t\t\tprintf(\"YES\\n\");\n\t}\n\treturn 0;\n}\n\n                                                                                                                                ", "lang_cluster": "C", "compilation_error": false, "code_uid": "ffebd0209ff0e6876f85d7caac56e83e", "src_uid": "f13eba0a0fb86e20495d218fc4ad532d", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n\tint a,b,h1,h2,i,j,k,count,sum,s;\n\n\tscanf(\"%d%d%d%d\",&h1,&h2,&a,&b);\n\t\n\ts=h1;\n\th1+=a*(10-2);\n\n\tif(h1>=h2)\n\t{\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\telse\n\t{\n\t\th1=h1-12*b;\n\n\t\ti=0;\n\t\tcount=1;\n\t\twhile(1)\n\t\t{\n\t\t\t\n\n\t\t\tif(h1+12*a>=h2&&h1<=h2)\n\t\t\t{\n\t\t\t\tprintf(\"%d\\n\",count);\n\t\t\t\tbreak;\n\t\t\t}\n\n\t\t\t\th1=h1+12*a;\n\t\t\th1-=12*b;\n\n\t\t\tcount++;\n\t\t\tif(count>=10000000)\n\t\t\t{\n\t\t\t\tprintf(\"-1\\n\");\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1e7a378047a3f48a4acd6bce2b89a480", "src_uid": "2c39638f07c3d789ba4c323a205487d7", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\nvoid cat(int a,int b,int h1, int h2,int d)\n{   int pos=0,k=0;\n       pos=(a*8)+h1; /*oidin raat 10tay*/\n    if(pos>=h2)\n    {\n        k=d;\n        printf(\"%d\",k);\n        getch();\n    }\n    d++;\n    pos-=(b*12); /*por din shokal 10tay*/\n    pos=pos+a*4; /*pordin dupur 2tay*/\n     if(pos>=h2)\n    {\n        k=d;\n        printf(\"%d\",k);\n        getch();\n    }\n    cat(a,b,pos,h2,d);\n}\n\nvoid main()\n{\n    int a,b,h1,h2,d=0;\n    scanf(\"%d%d\",&h1,&h2);\n    scanf(\"%d%d\",&a,&b);\n\tif(a==b)\n\t{\n\tprintf(\"%d\",d);\n\tgetch();\n\t}\n\tif(a<b)\n\t{\n\td=-1;\n\tprintf(\"%d\",d);\n\tgetch();\n\n\t}\n\ncat(a,b,h1,h2,d);\ngetch();\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b384c1a7bbdbd2731dc585d338b5220a", "src_uid": "2c39638f07c3d789ba4c323a205487d7", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n#include <string.h>\n\nint main () {\n\t\n\tint a, b;\n\tint h1, h2;\n\tint res;\n\t\n\tscanf(\"%d %d\", &h1, &h2);\n\tscanf(\"%d %d\", &a, &b);\n// printf(\"%d %d\\n\", h1, h2);\n// printf(\"%d %d\\n\", a, b);\n\tif (h1 + 8 * a >= h2) { //alcanca no 1 dia\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\tif (a < b) {\n\t\tprintf(\"-1\\n\");\n\t\treturn 0;\n\t}\n\t\n\th1 += 8 * a;\n\t\n\tres = (h2 - h1) / ((a - b) * 12);\n\t\n\th1 += res * (a - b) * 12;\n\t\n\tif (h1 >= h2) {\n\t\tif (h1 - 8 * a >= h2)\n\t\t\tres--;\n\t\tprintf(\"%d\\n\", res);\n\t}\n\th1 += (a - b) * 12;\n\tres++;\n\tif (h1 >= h2) {\n\t\tif (h1 - 8 * a >= h2)\n\t\t\tres--;\n\t\tprintf(\"%d\\n\", res);\n\t}\n\t\n\treturn 0;\n\t\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3f6799803a6f58345a749a757a978bed", "src_uid": "2c39638f07c3d789ba4c323a205487d7", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint a,b,c,d,e;\n\tscanf(\"%d%d%d%d\",&a,&b,&c,&d);\n\tif(a+8*c>=b)\n\t{\n\t\tprintf(\"0\\n\");\n\t\tgoto jump;\n\t}\n\telse if(c<d)\n\t{\n\t\tprintf(\"-1\\n\");\n\t\tgoto jump;\n\t}\n\telse\n\t{\n\t\te=2*(b-a-8*c)/(c-d);\n\t}\n\tint f=e%24;\n\tif(f<=2)\n\t{\n\t\tprintf(\"%d\\n\",e/24);\n\t}\n\telse\n\t\tprintf(\"%d\\n\",e/24+1);\n\tjump:\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "aa39dc3b1f20923d2369096cc36a86dc", "src_uid": "2c39638f07c3d789ba4c323a205487d7", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main ()\n{\n    int a,b,c,h1,h2,i,j,k,c1=0,f1,f2,f3,x,e,d;\n    scanf(\"%d%d%d%d\",&h1,&h2,&a,&b);\n    c=h2-h1;\n    d=a*8;\n    if(a<b)\n    {\n        if(d<c)printf(\"-1\");\n        else printf(\"0\");\n    }\n    else\n    {\n        if(d>c)\n        printf(\"0\");\n        else\n        {\n            e=c-d;\n            f1=a*12;\n            f2=b*12;\n            f3=f1-f2;\n            x=e/f3;\n            if(e%f3==0)\n                printf(\"%d\",x);\n            else\n            printf(\"%d\",x+1);\n        }\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1820ae86061cc27e52b7b1e504c4a391", "src_uid": "2c39638f07c3d789ba4c323a205487d7", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nmain()\n{\n    long long int i;\n    long long int a,b,temp;\n    scanf(\"%I64d %I64d\",&a,&b);\n    for(i=1; (a != b) && a>0 && b>0; i++)\n    {\n        if( a % b == 0)\n        {\n            i += (a/b)-1;\n            break;\n        }\n        a = a - b;\n        if(a < b)\n        {\n            temp = a;\n            a = b;\n            b = temp;\n        }\n    }\n    printf(\"%I64d\\n\",i);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8452f7c2fa6ae459b8351ba90a118dfc", "src_uid": "ce698a0eb3f5b82de58feb177ce43b83", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nstatic unsigned  long long count;\n\nint  main()\n{\n  unsigned  long long b,l;\n  count=0;\n  scanf(\"%lld %lld\",&b,&l);\n  display(b,l);\n  printf(\"%lld\",count);\n  return 0;\n}\ndisplay(unsigned long long  b,unsigned long long  l)\n{\n  if(l==1)\n    {\n      count=count+b;\n      return;\n    }\n  if(b==1)\n    {\n      count=count+l;\n      return;\n    }\n  if(b==l)\n    {\n      count++;\n    return;\n    }\n  else\n    {\n      count++;\n      if(l>b)\n    {\n      return(display(b,l-b));\n    }\n      else\n    {\n      return(display(b-l,l));\n    }\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "21b839bc0c3de0f7b74ac2271ee01eed", "src_uid": "ce698a0eb3f5b82de58feb177ce43b83", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include<string.h>\n#include<math.h> \nint min(int a,int b)\n{\n\treturn a>b?b:a;\t\n}\n \nint main() {\n\tlong long int a,b,c=0;\n\tscanf(\"%lld %lld\",&a,&b);\n\t\n\twhile(a>0 && b>0)\n\t{\n\t\tif(b==1)\n\t\t{\n\t\t\tc+=a;\n\t\t\tbreak;\t\n\t\t}\n\t\t\n\t\tc++;\n\t\ta=a-b;\n\t\t\n\t\tif(a<b)\n\t\t{\n\t\t\tlong long int t=a;\n\t\t\ta=b;\n\t\t\tb=t;\t\n\t\t}\n\t\t//printf(\"%lld %lld\\n\",a,b);\n\t}\n\t\n\tprintf(\"%lld\\n\",c);\nreturn 0;\n}  ", "lang_cluster": "C", "compilation_error": false, "code_uid": "63bc2b7c4f7e274a6f6a2b8d671e22de", "src_uid": "ce698a0eb3f5b82de58feb177ce43b83", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <conio.h>\n\nlong long a, b;\nint main()\n{\n    scanf(\"%I64d %I64d\",&a,&b);\n    long long sqr_count=0;\n    while(b>0)\n    {\n        sqr_count+=(a/b);\n        long long temp2=(a%b);\n        a=b;\n        b=temp2;\n\n\n    }\n    printf(\"%I64d\\n\",sqr_count);\n    getch();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "392f778a9e5ec94e1b4dae16ad7707c5", "src_uid": "ce698a0eb3f5b82de58feb177ce43b83", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <conio.h>\n\nlong long a, b;\nint main()\n{\n    scanf(\"%I64d %I64d\",&a,&b);\n    long long sqr_count=0;\n    while(b>0)\n    {\n        sqr_count+=(a/b);\n        long long temp2=(a%b);\n        a=b;\n        b=temp2;\n\n\n    }\n    printf(\"%I64d\",sqr_count);\n    getch();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ee895473f4bc6111ad7a8e3c7dc324ed", "src_uid": "ce698a0eb3f5b82de58feb177ce43b83", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n\tint arr[100] = {0}, i, j, s = 0;\n\tint a, b, c, d, n;\n\tscanf(\"%d %d %d %d %d\", &a, &b, &c, &d, &n);\n\tfor(i = 1; i <= n; i++)\n\t\tarr[i] = 1;\n\n\tfor(i = a; i <= d; i++)\n\t{\n\t\tfor(j = i; j <= n; j += i)\n\t\t\tif(arr[j])\n\t\t\t{\n\t\t\t\tarr[j] = 0;\n\t\t\t\ts++;\n\t\t\t}\n\t}\n\n\tprintf(\"%d\", s);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9a6d2357ff3331f2051ab853ea027b71", "src_uid": "46bfdec9bfc1e91bd2f5022f3d3c8ce7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int i,k,l,m,n,d,sum=0,b,c,e,f,z=0,y=0,w=0,v=0;\n    scanf(\"%d %d %d %d %d\",&k,&l,&m,&n,&d);\n    int a[1000]= {0};\n    if(k%l==0 || k%m==0 || k%n==0)\n        y=1;\n    if(l%k==0 || l%m==0 || l%n==0)\n        z=1;\n    if(m%k==0 || m%l==0 || m%n==0)\n        w=1;\n    if(n%k==0 || n%m==0 || n%l==0)\n        v=1;\n    if(k==1 || l==1 || m==1 || n==1)\n        sum=d;\n    else if(k!=1 || l!=1 || m!=1 || n!=1)\n\n    {\n        b=k;\n        c=l;\n        e=m;\n        f=n;\n        if(y==0)\n        {\n            for(i=0; i<(d/k); i++){\n                    a[b-1]=1;\n                    b=b+k;\n            }\n        }\n        if(z==0)\n        {\n            for(i=0; i<(d/l); i++){\n                a[c-1]=1;\n                c=c+l;\n            }\n        }\n        if(w==0)\n        {\n            for(i=0; i<(d/m); i++){\n                a[e-1]=1;\n                e=e+m;\n            }\n        }\n        if(v==0)\n        {\n            for(i=0; i<(d/n); i++){\n                a[f-1]=1;\n                f=f+n;\n            }\n        }\n\n        for(i=0; i<1000; i++)\n            sum+=a[i];\n        }\n\n        printf(\"%d\",sum);\n        }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "61d97845bf71e204268d489515fb29e6", "src_uid": "46bfdec9bfc1e91bd2f5022f3d3c8ce7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int i,a,b,c,d,e;\n    int count;\n    scanf(\"%d %d %d %d %d\",&a,&b,&c,&d,&e);\n    for(i=1;i<e;i++){\n        if(i%a==0 || i%b==0 || i%c==0 || i%d==0)\n            count++;\n    }\n    printf(\"%d\",count);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c7e1ceefd2d08e182b410d74978f9013", "src_uid": "46bfdec9bfc1e91bd2f5022f3d3c8ce7", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nmain()\n{\n\tint i,j,sum=0,l[5],m[10001]={0};\n\tfor(i=0;i<5;i++)\n\tscanf(\"%d\",&l[i]);\n\tfor(j=0;j<4;j++)\n\t\tfor(i=1;i<4;i++)\n\t\t\tif(l[i]%l[j]==0)\n\t\t\t\tl[i]==10002;\n\tfor(j=0;j<4;j++)\n\t\tfor(i=1;i*l[j]<l[4];i++)\n\t\t\tm[i*l[j]-1]=1;\n\tfor(i=0;i<l[4];i++)\n\t\tsum+=m[i];\n\tprintf(\"%d\\n\",sum+1);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2e291fd25374327361bee3e127a2d459", "src_uid": "46bfdec9bfc1e91bd2f5022f3d3c8ce7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int i,k,l,m,n,d,sum=0,b,c,e,f;\n    scanf(\"%d %d %d %d %d\",&k,&l,&m,&n,&d);\n    int a[1000]={0};\n    b=k;\n    c=l;\n    e=m;\n    f=n;\n    for(i=0;i<(d/k);i++){\n        a[b-1]=1;\n        b=b+k;\n\n\n    }\n      for(i=0;i<(d/l);i++){\n        a[c-1]=1;\n        c=c+l;\n\n    }\n      for(i=0;i<(d/m);i++){\n        a[e-1]=1;\n        e=e+m;\n\n    }\n      for(i=0;i<(d/n);i++){\n        a[f-1]=1;\n        f=f+n;\n    }\n      for(i=0;i<1000;i++){\n        sum+=a[i];\n    }\n    printf(\"%d\",sum);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fbf1445435fbb10549f06da850ba5064", "src_uid": "46bfdec9bfc1e91bd2f5022f3d3c8ce7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint m,n;\nint main()\n{\n    scanf(\"%d %d\",&m,&n);\n    int a=0;\n    int i,j;\n    for(i=0;i<m<n?m:n;i++)\n    {\n        for(j=0;j<m<n?m:n;j++)\n        {\n            if(i*i+j==n&&i+j*j==m)\n                a++;\n        }\n    }\n    printf(\"%d\",a);\n    return 0;\n}\n                                                                                    ", "lang_cluster": "C", "compilation_error": false, "code_uid": "ee0787c7407413b7d24a827c6ec3a855", "src_uid": "03caf4ddf07c1783e42e9f9085cc6efd", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n\tint a,b,c=0,n,m,max;\n\twhile(scanf(\"%d %d\",&n,&m))\n\t{\n\tmax=n;\n\tif(max<m)max=m;\n\tfor(c=0,a=0;a<=max;a++)\n\t\tfor(b=0;b<=max;b++)\n\t\t{\n\t\t\tif(a*a+b!=n)continue;\n\t\tif(a+b*b==m)c++;\n\t\t}\n\tprintf(\"%d\\n\",c);\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b96a03e6265f688b6ad75b7cf606478c", "src_uid": "03caf4ddf07c1783e42e9f9085cc6efd", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,m,l,count=0,i,j;\n    scanf(\"%d%d\",&n,&m);\n    if (n>m){\n\n        l=n*n;\n    }\n    else {\n        l=m*m;\n    }\n\n    for (i=0;i<=l;i++){\n    for (j=0;j<=l;j++){\n        if ((i*i)+j==n && i+(j*j)==m){\n               count++;\n        }\n    }\n    }\n    printf(\"%d\",count);\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "775b898985d13da48e3b9a892828710b", "src_uid": "03caf4ddf07c1783e42e9f9085cc6efd", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "    #include<stdio.h>\n    int main(){\n\n     int a,b,c;\n\n     scanf(\"%d%d\",&a,&b);\n\n     int i,m;\n    int counter=0;\n     for(i=0;i<=a*b;i++){\n            for(m=0;m<=a*b;m++){\n                    if( ((i*i) + m == a) && ( i + (m*m))==b)\n                        counter++;\n\n            }}\n    printf(\"%d\",counter);\n\n\n\n\n\n    }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9ef9e55ae5dab78ec42d382304236909", "src_uid": "03caf4ddf07c1783e42e9f9085cc6efd", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint min(int a,int b)\n{\n    if(a<b)\n       return a;\n    else \n        return b;\n}\nint main(void)\n{\n      int n,m,a,b,flag,f;\n      while(scanf(\"%d %d\",&n,&m)!=EOF)\n      {\n          flag=0;\n          f=min(n,m);\n          for(a=0;a<=f;a++){\n            for(b=0;b<min(n,m);a++)\n            {\n                 if((a*a+b==n)&&(a+b*b==m))\n                     flag++;\n            }}\n          printf(\"%d\\n\",flag);\n      }\n      system(\"pause\");\n      return 0;\n}\n                     \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8385aed8b73205f706ab04ef19615d17", "src_uid": "03caf4ddf07c1783e42e9f9085cc6efd", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main() {\n    int a,m,mod,t,i;\n    int vis[100005];\n    scanf(\"%d\",&a);\n    scanf(\"%d\",&m);\n    for(i=0;i<m;i++)\n    vis[i]=0;\n    mod=a%m;\n    while(mod!=0)\n    {\n    \tif(vis[mod]!=0)\n    \tbreak;\n    \tvis[mod]=1;\n    \ta=a+mod;\n    \tmod=a%m;\n    }\n    if(mod==0)\n    printf(\"Yes\\n\");\n    else if(vis[mod]!=0)\n    printf(\"No\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1daa8a9557e348fdc6d9e29c2181ccae", "src_uid": "f726133018e2149ec57e113860ec498a", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <ctype.h>\n#include <string.h>\n#include <math.h>\n\nint main(){\n   int x, m;\n   scanf(\"%d%d\", &x, &m);\n   \n   char s[100010] = {0};\n   int r = x, yes = 0;\n   do{\n      if(r % m == 0){\n         yes = 1;\n         break;\n      }else{\n         if(s[r % m] == 0){\n            s[r % m] = 1;\n         }else break;\n      }\n      r += r % m;\n   }while(1);\n   \n   puts( yes ? \"Yes\" : \"No\" );\n   \n   /*system(\"pause\");*/\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "82bb0358af89a319ea166480e46007d8", "src_uid": "f726133018e2149ec57e113860ec498a", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint arr[1000001];\nint main(void) {\n    // your coe goes here\n    int a,b,i;\n    for(i=1;i<1000001;i++)\n    arr[i]=0;\n    while(1)\n    {\n        if(a%b==0)\n        {\n            \n            printf(\"Yes\\n\");\n            break;\n        }\n        if(arr[a%b]==1)\n        {\n        printf(\"No\\n\");\n        break;\n        }\n        arr[a%b]=1;\n        a=a+(a%b);\n        printf(\"%d \",a);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a3866dced27b98ffc76b6d9c90cf99bb", "src_uid": "f726133018e2149ec57e113860ec498a", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,m,flag=0,p,a,count[100001],i;\n    scanf(\"%d %d\",&n,&m);\n    for(i=0;i<=100000;i++)\n    {\n        count[i]=0;\n    }\n    a=n;\n    p=n%m;\n    while(count[p]!=1)\n    {\n        count[p]=1;\n        if(p==0)\n        {\n            flag=1;\n            break;\n        }\n        else\n        {\n            a=a+p;\n            p=a%m;\n          //  count[p]=1;\n        }\n    }\n    if(flag==1)\n    {\n        printf(\"Yes\\n\");\n    }\n    else\n    {\n        printf(\"No\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "16437b8e80bfe107c0df80aab6a594f6", "src_uid": "f726133018e2149ec57e113860ec498a", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int a,m,mod,ta;\n\n    scanf(\"%d %d\",&a,&m);\n\n    ta=a;\n\n    do\n    {\n        mod=ta%m;\n\n        if(mod==0)\n        {\n            printf(\"Yes\");\n            break;\n        }\n\n        ta=ta+mod;\n\n        if(ta==m)\n        {\n            printf(\"Yes\");\n            break;\n        }\n\n        mod=ta%m;\n\n        if(mod==0)\n        {\n            printf(\"Yes\");\n            break;\n        }\n\n        if(ta>mod)\n        {\n            printf(\"No\");\n            break;\n        }\n\n    }\n\n    while(mod);\n\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6ced7e191ff5382b14cd2ad6f742df92", "src_uid": "f726133018e2149ec57e113860ec498a", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<stdint.h>\nmain()\n\t{\n\t\tlong long int a,b,c,k=0,s;\n\t\tscanf(\"%d%d%d\",&a,&b,&c);\n\t\tif((a==b) && (k!=1))\n\t\t\t{\n\t\t\t\tprintf(\"YES\");\n\t\t\t\tk=1;\n\t\t\t}\t\n\t\tif((b<=0) && (c>0) && (a>0) && (k!=1))\n\t\t\t{\n\t\t\t\tprintf(\"NO\");\n\t\t\t\tk=1;\n\t\t\t}\n\t\tif((a!=b) && (c==0) && (k!=1))\n\t\t\t{\n\t\t\t\tprintf(\"NO\");\n\t\t\t\tk=1;\n\t\t\t}\n\t\tif((b>=0) && (c<0) && (a<0) && (k!=1))\n\t\t\t{\n\t\t\t\tprintf(\"NO\");\n\t\t\t\tk=1;\n\t\t\t}\t\t\t\t\t\n\t\tif((a>=0) && (b>=0) && (a<b) && (c>0) && (k!=1))\n\t\t\tif((abs(b)-abs(a))%abs(c)==0)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"YES\");\n\t\t\t\t\tk=1;\n\t\t\t\t}\n\t\tif((a>=0) && (b<=0) && (a>b) && (c<0) && (k!=1))\n\t\t\tif((abs(b)+abs(a))%abs(c)==0)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"YES\");\n\t\t\t\t\tk=1;\n\t\t\t\t}\n\t\tif((a<=0) && (b<=0) && (a<b) && (c>0) && (k!=1))\n\t\t\tif((abs(b)-abs(a))%abs(c)==0)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"YES\");\n\t\t\t\t\tk=1;\n\t\t\t\t}\n\t\tif((a<=0) && (b<=0) && (a>b) && (c<0) && (k!=1))\n\t\t\tif((abs(b)-abs(a))%abs(c)==0)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"YES\");\n\t\t\t\t\tk=1;\n\t\t\t\t}\n\t\tif((a<=0) && (b>=0) && (a<b) && (c>0) && (k!=1))\n\t\t\tif((abs(b)+abs(a))%abs(c)==0)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"YES\");\n\t\t\t\t\tk=1;\n\t\t\t\t}\n\t\tif((a>=0) && (b>=0) && (a<b) && (c>0) && (k!=1))\n\t\t\tif((abs(b)+abs(a))%abs(c)==0)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"YES\");\n\t\t\t\t\tk=1;\n\t\t\t\t}\n\t\tif((a>=0) && (b>=0) && (a>b) && (c>0) && (k!=1))\n\t\t\tif((abs(b)-abs(a))%abs(c)==0)\t\n\t\t\t\t{\n\t\t\t\t\tprintf(\"YES\");\n\t\t\t\t\tk=1;\n\t\t\t\t}\n\t\tif(k==0)\n\t\t\tprintf(\"NO\");\n\n\t}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4d4ac229e755a963a63fb3eab1a6bae6", "src_uid": "9edf42c20ddf22a251b84553d7305a7d", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    long long a,b,c;\n\n    scanf(\"%lld %lld %lld\",&a,&b,&c);\n    if((a==b&&c==0)||( (b-a)% c == 0&&(b-a)/c >=0 ))\n            printf(\"YES\\n\");\n    else printf(\"NO\\n\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c6eca787f3be197db8c7e551991fb36f", "src_uid": "9edf42c20ddf22a251b84553d7305a7d", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{long long int a,b,c;\n    scanf(\"%lld%lld%lld\",&a,&b,&c);\n    if(c==0)\n    {\n        if(a==b)printf(\"YES\\n\");\n        else printf(\"NO\\n\");\n    }\n    if((b-a)%c==0)\n    {\n        printf(\"YES\\n\");\n    }\n    else printf(\"NO\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cb64080e00f97f1c8255615457fc0af5", "src_uid": "9edf42c20ddf22a251b84553d7305a7d", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n main()\n {\n     unsigned long long int a,b,c,d,e;\n\n     while(scanf(\"%llu%llu%llu\",&a,&b,&c)!=EOF){\n    e=b-a;\n    if(e!=0 && c==0)\n        printf(\"NO\\n\");\n    else if(e==0 && c==0)\n        printf(\"YES\\n\");\n    else if(e%c==0)\n        printf(\"YES\\n\");\n    else\n        printf(\"NO\\n\");\n\n\n} }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "05b1d5f998ebc25d64712568ffd78194", "src_uid": "9edf42c20ddf22a251b84553d7305a7d", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long a,b,c,s,i,j,k,l=1;\n    scanf(\"%lld%lld%lld\",&a,&b,&c);\n    s=a;\n    if(c>0)\n    {\n    for(;;)\n    {\n        if(s==b)\n        break;\n        s=s+c;\n        if(s>b)\n        {\n            l=0;\n            break;\n        }\n    }\n    }\n    else if(c==0)\n    {\n        if(a!=b)\n        l=0;\n\n    }\n    else\n    {\n        for(;;)\n        {\n            if(s==b)\n            break;\n            s=s+c;\n            if(s<b)\n            {\n                l=0;\n                break;\n            }\n        }\n    }\n    if(l==0)\n    printf(\"NO\");\n    else\n    printf(\"YES\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5be3073bece196d177d8f22c690e7d32", "src_uid": "9edf42c20ddf22a251b84553d7305a7d", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\nint main()\n{\n\tint n,a[37],t,k,c,h,i,j,sum;\n\tscanf(\"%d\",&n);\n\t\twhile (n--)\n\t\t{\n\t\t\tmemset(a,0,36*sizeof(int));\n\t\t\tscanf(\"%d\",&t);\n\t\t\th=(t%10-1)*4;\n\t\t\twhile(t/10!=0)\n\t\t\t{\n\t\t\t\th++;\n\t\t\t\tt/=10;\t\n\t\t\t}\n\t\t\th++;\n\t\t\ta[h]=1;\n\t\t\tsum=0;\n\t\t\tfor (i=1;i<=9;i++)\n\t\t\t{\n\t\t\t\tif (a[k+(i-2)*4]==1) break;\n\t\t\t\tk=0;\n\t\t\t\tfor (j=1;j<=4;j++)\n\t\t\t\t{\n\t\t\t\t\tif (a[k+(i-1)*4]==1) break;\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tsum+=j;\n\t\t\t\t\t\tk++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tprintf(\"%d\\n\",sum);\n\t\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1b0e59b1f7f7c4a98f5f02092805f1b5", "src_uid": "289a55128be89bb86a002d218d31b57f", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint t;\n\tscanf(\"%d\",&t);\n\tfor(int i=0;i<t;i++)\n\t{\n\t\tint x,y=1,s=0,z=1,ok=1;\n\t\tscanf(\"%d\",&x);\n\t\twhile(ok==1 && x!=1)\n\t\t{\n\t\t\tfor(int j=1;j<=4;j++)\n\t\t\t{\n\t\t\t\ts=s+j;\n\t\t\t\t//printf(\"%d\\n\",y);\n\t\t\t\ty=y*10+z;\n\t\t\t\tif(y==x){ok=0;s=s+j+1;break;}\n\t\t\t}\n\t\t\tz++;\n\t\t\ty=z;\n\t\t}\n\t\tif (x!=1)printf(\"%d\\n\",s);\n\t\telse printf(\"%d\\n\",1);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f2f2d6147a9ecd806237086df0eb8add", "src_uid": "289a55128be89bb86a002d218d31b57f", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,x;\n\tscanf(\"%d\",&n);\n\tint a[40]={0,1,11,111,1111,2,22,222,2222,3,33,333,3333,4,44,444,4444,5,55,555,5555,6,66,666,6666,7,77,777,7777,8,88,888,8888,9,99,999,9999};\n\twhile(n--)\n\t{\n\t\tscanf(\"%d\",&x);\n\t\tint i=1,cnt=0;\n\t\twhile(a[i]!=x)\n\t\t{\n\t\t\twhile(a[i]!=0)\n\t\t\t{\n\t\t\t\ta[i]=a[i]/10;\n\t\t\t\tcnt++;\n\t\t\t}\n\t\t\ti++;\n\t\t}\n\t\twhile(x!=0)\n\t\t{\n\t\t\tx=x/10;\n\t\t\tcnt++;\n\t\t}\n\t\tprintf(\"%d\\n\",cnt);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d97c7a3324c6d42700a9e3db641023ff", "src_uid": "289a55128be89bb86a002d218d31b57f", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n    int t,x,sum,i,j,k,flag;\n    scanf(\"%d\",&t);\n\twhile(t--)\n\t{\n\t\tsum=0;flag=0;\n    \tscanf(\"%d\",&x);\n    \tfor(i=1;i<10;i++)\n\t{\n\t\tt=i;\n\t\tfor(j=1;j<5;j++)\n\t\t{\n\t\t\tif(flag!=0) t=t*10+i;\n\t\t\tflag++;\n\t\t\tsum+=j;\n\t\t\tif(x==1) goto out;\n\t\t\telse if((t-1)/10==x) goto out;\n\t\t}\n\t}\n\tout:\n\t\tprintf(\"%d\\n\",sum);\n\t}\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "25256945d54e53eadb260e93e16bcd49", "src_uid": "289a55128be89bb86a002d218d31b57f", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n    int t,x,sum,i,j,k,flag;\n    while(~scanf(\"%d\",&t))\n    {\n\twhile(t--)\n\t{\n\t\tsum=0;flag=0;\n    \tscanf(\"%d\",&x);\n    \tfor(i=1;i<10;i++)\n\t{\n\t\tt=i;\n\t\tfor(j=1;j<5;j++)\n\t\t{\n\t\t\tif(flag!=0) t=t*10+i;\n\t\t\tflag++;\n\t\t\tsum+=j;\n\t\t\tif(x==1) goto out;\n\t\t\telse if((t-1)/10==x) goto out;\n\t\t}\n\t}\n\tout:\n\t\tprintf(\"%d\\n\",sum);\n\t}\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "25283c59ea85580a95991b653194b79c", "src_uid": "289a55128be89bb86a002d218d31b57f", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,arr[10],tip=0,c=0,flag=0,ans=1,i;\n\n    scanf(\"%d\",&n);\n\n    for(i=0;i<=9;i++)\n    {\n        //printf(\"%d\",i);\n        arr[i]=0;\n    }\n\n    //printf(\"%d\",n);\n    i=2;\n    while(n>1)\n    {\n\n\n        if(n%i!=0)\n        {\n            i++;\n        }\n        else\n        {\n             n = n/i;\n             arr[i]++;\n        }\n\n\n    }\n    while(1)\n    {\n        for(i=2;i<=9;i++)\n        {\n            if(arr[i]>1)\n                tip = 1;\n        }\n        //printf(\"%d %d\\n\",tip,i);\n        if(tip==0)\n            break;\n\n        for(i=2;i<=9;i++)\n        {\n            if(arr[i]%2!=0)\n            {\n                flag=1;\n                arr[i]++;\n            }\n            arr[i]=arr[i]/2;\n        }\n        c++;\n        tip=0;\n    }\n    for(i=2;i<=9;i++)\n        if(arr[i]==1)\n            ans*=i;\n\n    if(flag==1)\n        printf(\"%d %d\",ans,c+1);\n    else\n        printf(\"%d %d\",ans,c);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b5e7f56362dfb2b98827d564d1ba5101", "src_uid": "212cda3d9d611cd45332bb10b80f0b56", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\nint primes[1000];\nint p_ind;\n\nunsigned char * declare_bool(int n)\n{\n\treturn (unsigned char *)(malloc(n/8+(n%8!=0)));\n}\n\nvoid assign_bool(unsigned char *array, int pos, int val)\n{\n\t int i, ii, temp;\n\ti = pos/8;\n\tii = pos-(i*8);\n\ttemp = 255;/**128 64 32 16 8 4 2 1**/\n\tif(val)\n\t{\n\t\tarray[i] = array[i]|(1<<(7-ii));\n\t}else{\n\t\ttemp = temp^(1<<(7-ii));\n\t\tarray[i] = array[i]&temp;\n\t}\n}\n\nunsigned char access_bool(unsigned char *array, int pos)\n{\n\tint i, ii;\n\ti = pos/8;\n\tii = pos-(i*8);\n\tif(array[i]&(1<<(7-ii)))\n\t\treturn 1;\n\telse\n\t\treturn 0;\n}\n\nvoid sieve()\n{\n\tunsigned char *is_not_prime;\n\tis_not_prime = declare_bool(1001);\n\tint i;\n\tp_ind = 0;\n\tassign_bool(is_not_prime, 0, 1);\n\tassign_bool(is_not_prime, 1, 1);\n\tfor(i=2; i<1001; i++)\n\t\tassign_bool(is_not_prime, i, 0);\n\tfor(i=0; i<1001; i++)\n\t{\n\t\tif(!access_bool(is_not_prime, i))\n\t\t{\n\t\t\tprimes[p_ind++] = i;\n\t\t\tint j;\n\t\t\tfor(j=i+i; j<=1000; j+=i)\n\t\t\t{\n\t\t\t\tassign_bool(is_not_prime, j, 1);\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint n, i, p_d_i, selected_i;\n\tint op, nn;\n\tscanf(\"%d\", &n);\n\tsieve();\n\top = 0;\n\tnn = 1;\n\tint *prime_divisors = malloc(p_ind*4);\n\tp_d_i = 0;\n\tfor(i=0; i<p_ind; i++)\n\t{\n\t\tif(n%primes[i]==0)\n\t\t{\n\t\t\tnn*=primes[i];\n\t\t\tprime_divisors[p_d_i++] = primes[i];\n\t\t}\n\t\tif(primes[i]*primes[i]>n)\n\t\t\tbreak;\n\t}\n\tint *exp = malloc(p_d_i*4);\n\tfor(i=0; i<p_d_i; i++)\n\t\texp[i] = 0;\n\tselected_i = 0;\n\twhile(n>1)\n\t{\n\t\tif(n%prime_divisors[selected_i]==0)\n\t\t{\n\t\t\texp[selected_i]++;\n\t\t\tn/=prime_divisors[selected_i];\n\t\t}\n\t\telse\n\t\t\tselected_i++;\n\t}\n\tint max_exp;\n\tmax_exp = 0;\n\t\n\tfor(i=0; i<p_d_i; i++)\n\t{\t\n\t\tif(exp[i]>max_exp)\n\t\t\tmax_exp = exp[i];\n\t}\n\tfor(i=0; i<p_d_i; i++)\n\t{\t\n\t\tif(exp[i]!=max_exp)\n\t\t{\n\t\t\top++;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(op==0 && max_exp!=(1<<((int)log2(max_exp))))\n\t\top++;\n\top+=((ceil(log2(max_exp))));\t\n\tprintf(\"%d %d\", nn, op);\n\treturn 0;\n\t\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0ab99b906a402cec7d520697fd0cac01", "src_uid": "212cda3d9d611cd45332bb10b80f0b56", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\nint primes[10000];\nint p_ind;\n\nunsigned char * declare_bool(int n)\n{\n\treturn (unsigned char *)(malloc(n/8+(n%8!=0)));\n}\n\nvoid assign_bool(unsigned char *array, int pos, int val)\n{\n\t int i, ii, temp;\n\ti = pos/8;\n\tii = pos-(i*8);\n\ttemp = 255;/**128 64 32 16 8 4 2 1**/\n\tif(val)\n\t{\n\t\tarray[i] = array[i]|(1<<(7-ii));\n\t}else{\n\t\ttemp = temp^(1<<(7-ii));\n\t\tarray[i] = array[i]&temp;\n\t}\n}\n\nunsigned char access_bool(unsigned char *array, int pos)\n{\n\tint i, ii;\n\ti = pos/8;\n\tii = pos-(i*8);\n\tif(array[i]&(1<<(7-ii)))\n\t\treturn 1;\n\telse\n\t\treturn 0;\n}\n\nvoid sieve()\n{\n\tunsigned char *is_not_prime;\n\tis_not_prime = declare_bool(10001);\n\tint i;\n\tp_ind = 0;\n\tassign_bool(is_not_prime, 0, 1);\n\tassign_bool(is_not_prime, 1, 1);\n\tfor(i=2; i<10001; i++)\n\t\tassign_bool(is_not_prime, i, 0);\n\tfor(i=0; i<10001; i++)\n\t{\n\t\tif(!access_bool(is_not_prime, i))\n\t\t{\n\t\t\tprimes[p_ind++] = i;\n\t\t\tint j;\n\t\t\tfor(j=i+i; j<=10000; j+=i)\n\t\t\t{\n\t\t\t\tassign_bool(is_not_prime, j, 1);\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint n, i, p_d_i, selected_i;\n\tint op, nn;\n\tscanf(\"%d\", &n);\n\tsieve();\n\top = 0;\n\tnn = 1;\n\tint *prime_divisors = malloc(p_ind*4);\n\tp_d_i = 0;\n\tfor(i=0; i<p_ind; i++)\n\t{\n\t\tif(n%primes[i]==0)\n\t\t{\n\t\t\tnn*=primes[i];\n\t\t\tprime_divisors[p_d_i++] = primes[i];\n\t\t}\n\t\t\n\t}\n\tint *exp = malloc(p_d_i*4);\n\tfor(i=0; i<p_d_i; i++)\n\t\texp[i] = 0;\n\tselected_i = 0;\n\twhile(n>1 && p_d_i>0)\n\t{\n\t\tif(n%prime_divisors[selected_i]==0)\n\t\t{\n\t\t\texp[selected_i]++;\n\t\t\tn/=prime_divisors[selected_i];\n\t\t}\n\t\telse\n\t\t\tselected_i++;\n\t}\n\tint max_exp;\n\tmax_exp = 0;\n\t\n\tfor(i=0; i<p_d_i; i++)\n\t{\t\n\t\tif(exp[i]>max_exp)\n\t\t\tmax_exp = exp[i];\n\t}\n\tfor(i=0; i<p_d_i; i++)\n\t{\t\n\t\tif(exp[i]!=max_exp)\n\t\t{\n\t\t\top++;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(op==0 && max_exp!=(1<<((int)log2(max_exp))))\n\t\top++;\n\top+=((ceil(log2(max_exp))));\n\tif(p_d_i==0)\n\t{\n\t\tnn = n;\n\t\top = 0;\n\t}\t\n\tprintf(\"%d %d\", nn, op);\n\treturn 0;\n\t\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e898ea950feca5a94e5b9c09e8888db7", "src_uid": "212cda3d9d611cd45332bb10b80f0b56", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\nint primes[10000];\nint p_ind;\n\nunsigned char * declare_bool(int n)\n{\n\treturn (unsigned char *)(malloc(n/8+(n%8!=0)));\n}\n\nvoid assign_bool(unsigned char *array, int pos, int val)\n{\n\t int i, ii, temp;\n\ti = pos/8;\n\tii = pos-(i*8);\n\ttemp = 255;/**128 64 32 16 8 4 2 1**/\n\tif(val)\n\t{\n\t\tarray[i] = array[i]|(1<<(7-ii));\n\t}else{\n\t\ttemp = temp^(1<<(7-ii));\n\t\tarray[i] = array[i]&temp;\n\t}\n}\n\nunsigned char access_bool(unsigned char *array, int pos)\n{\n\tint i, ii;\n\ti = pos/8;\n\tii = pos-(i*8);\n\tif(array[i]&(1<<(7-ii)))\n\t\treturn 1;\n\telse\n\t\treturn 0;\n}\n\nvoid sieve()\n{\n\tunsigned char *is_not_prime;\n\tis_not_prime = declare_bool(10001);\n\tint i;\n\tp_ind = 0;\n\tassign_bool(is_not_prime, 0, 1);\n\tassign_bool(is_not_prime, 1, 1);\n\tfor(i=2; i<10001; i++)\n\t\tassign_bool(is_not_prime, i, 0);\n\tfor(i=0; i<10001; i++)\n\t{\n\t\tif(!access_bool(is_not_prime, i))\n\t\t{\n\t\t\tprimes[p_ind++] = i;\n\t\t\tint j;\n\t\t\tfor(j=i+i; j<=10000; j+=i)\n\t\t\t{\n\t\t\t\tassign_bool(is_not_prime, j, 1);\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint n, i, p_d_i, selected_i;\n\tint op, nn;\n\tscanf(\"%d\", &n);\n\tsieve();\n\top = 0;\n\tnn = 1;\n\tint *prime_divisors = malloc(p_ind*4);\n\tp_d_i = 0;\n\tfor(i=0; i<p_ind; i++)\n\t{\n\t\tif(n%primes[i]==0)\n\t\t{\n\t\t\tnn*=primes[i];\n\t\t\tprime_divisors[p_d_i++] = primes[i];\n\t\t}\n\t\t\n\t}\n\tint *exp = malloc(p_d_i*4);\n\tfor(i=0; i<p_d_i; i++)\n\t\texp[i] = 0;\n\tselected_i = 0;\n\twhile(n>1)\n\t{\n\t\tif(n%prime_divisors[selected_i]==0)\n\t\t{\n\t\t\texp[selected_i]++;\n\t\t\tn/=prime_divisors[selected_i];\n\t\t}\n\t\telse\n\t\t\tselected_i++;\n\t}\n\tint max_exp;\n\tmax_exp = 0;\n\t\n\tfor(i=0; i<p_d_i; i++)\n\t{\t\n\t\tif(exp[i]>max_exp)\n\t\t\tmax_exp = exp[i];\n\t}\n\tfor(i=0; i<p_d_i; i++)\n\t{\t\n\t\tif(exp[i]!=max_exp)\n\t\t{\n\t\t\top++;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(op==0 && max_exp!=(1<<((int)log2(max_exp))))\n\t\top++;\n\top+=((ceil(log2(max_exp))));\t\n\tprintf(\"%d %d\", nn, op);\n\treturn 0;\n\t\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1bac336ed0250bdc5c7a790ac45bb372", "src_uid": "212cda3d9d611cd45332bb10b80f0b56", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n\n#define SIZE 1000\n\nvoid factorization (int n, int p[], int k[], int *sz)\n{\n\tint d;\n\n\t*sz = 0;\n\n\tfor (d = 2; d * d <= n; d++)\n\t\tif (n % d == 0)\n\t\t{\n\t\t\tp[*sz] = d;\n\n\t\t\twhile (n % d == 0)\n\t\t\t{\n\t\t\t\tk[*sz]++;\n\t\t\t\tn /= d;\n\t\t\t}\n\n\t\t\t(*sz)++;\n\t\t}\n\n\tif (n != 1)\n\t{\n\t\tp[*sz] = n;\n\t\tk[(*sz)++] = 1;\n\t}\n}\n\nint is_power_of_two (int n)\n{\n\twhile (n % 2 == 0)\n\t\tn /= 2;\n\n\treturn n == 1;\n}\n\nint is_need_mult (int p[], int k[], int sz)\n{\n\tint i;\n\n\tif (is_power_of_two (k[0]))\n\t\tfor (i = 1; i < sz; i++)\n\t\t\tif (k[i] != k[i - 1])\n\t\t\t\treturn 1;\n\t\t\telse\n\t\t\t\tk[i] = k[i];\n\telse\n\t\treturn 1;\n\n\treturn 0;\n}\n\nint oper (int p[], int k[], int sz)\n{\n\tint i, cnt = 0, max = 0;\n\n\tfor (i = 0; i < sz; i++)\n\t\tif (k[i] > max)\n\t\t\tmax = k[i];\n\n\ti = 0;\n\t\n\twhile (1 << i < max)\n\t\ti++;\n\n\tcnt = i;\n\n\tif (is_need_mult (p, k, sz))\n\t\tcnt++;\n\n\treturn cnt;\n}\n\nint min_num (int p[], int sz)\n{\n\tint i, min = 1;\n\n\tfor (i = 0; i < sz; i++)\n\t\tmin *= p[i];\n\n\treturn min;\n}\n\nint main()\n{\n\tint n, i, sz, oper_cnt, p[SIZE] = {0}, k[SIZE] = {0};\n\n\tscanf (\"%d\", &n);\n\n\tfactorization (n, p, k, &sz);\n\n\toper_cnt = oper (p, k, sz);\n\n\tprintf (\"%d %d\\n\", min_num (p, sz), oper_cnt);\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f2cab7fe7dd36357e9dfd52c73171499", "src_uid": "212cda3d9d611cd45332bb10b80f0b56", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main()\n{\n\nint trouve=0;\nlong long y;\nscanf(\"%I64d\",&y);\nint s;\nwhile(trouve == 0)\n{\n\t\n\twhile(y!=0)\n\t{\n\t\ty=y/10;\n\t\ts+=y%10;\n\tif(s==10)\n\t{\n\t\tprintf(\"%I64d\",y);\n\t\ttrouve=1;\n\t\tbreak;\n\t}\n\telse \n\t\ty++;\n\t}\n\n}\nreturn 1;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5602f6332b15bc11057422fadab68212", "src_uid": "0a98a6a15e553ce11cb468d3330fc86a", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nvoid main()\n{\n int k,i=19,s=0,a,c=0,j;\n    scanf(\"%d\",&k);\n    while(c!=k)\n    {\n        s=0;\n        j=i;\n        while(i>0)\n        {\n            a=i%10;\n            s+=a;\n            i=i/10;\n        }\n        i=j;\n        if(s==10)\n        {\n            c++;\n            i++;\n        }\n        else\n        {\n            i++;\n        }\n    }\n    printf(\"%d\",j);\n} ", "lang_cluster": "C", "compilation_error": false, "code_uid": "a977569388e1f9e9b15fff049da36755", "src_uid": "0a98a6a15e553ce11cb468d3330fc86a", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tlong k,i,s,j,p,a[1000];\n\tscanf(\"%ld\",&k);\n\ti=0;j=19;\n\twhile(i<k)\n\t{\n\t\ts=0;\n\t\tp=j;\n\t\twhile(p>0)\n\t\t{\n\t\t\ts+=p%10;\n\t\t\tp=p/10;\t\n\t\t}\t\n\t\tif(s==10)\n\t\ta[i++]=j;\n\t\tj++;\n\t}\n\tprintf(\"%ld\\n\",a[k-1]);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7ad5ca86187ee88c28c5ce595e23986e", "src_uid": "0a98a6a15e553ce11cb468d3330fc86a", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint calcul(int a){\n    int k=0;\nif (a/10==0){\n    return(k+a%10);\n}\nelse {\nreturn(k+(a%10)+calcul((a-(a%10))/10));}\n}\nint main(){\nlong long a,k;\nint i,c=19,t[1000];\n\nscanf(\"%d\",&k);\nfor (i=0;i<=k;i++){\n\n\nwhile(calcul(c)!=10){\n        c++;\n}\nt[i]=c;\nc++;\n}\nprintf(\"%d\",t[k-1]);\n\n\n\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "23fd916036416801750cf6963d7e2837", "src_uid": "0a98a6a15e553ce11cb468d3330fc86a", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint t[1000];\nint calcul(int a){\n    int k=0;\nif (a/10==0){\n    return(k+(a%10));\n}\nelse {\nreturn k+(a%10)+calcul((a-(a%10))/10);}\n}\nint main(){\nint a,k;\nint i,c=19;\n\nscanf(\"%d\",&k);\nfor (i=0;i<=k;i++){\n\n\nwhile(calcul(c)!=10){\n        c++;\n}\nt[i]=c;\nc++;\n}\nprintf(\"%d\",t[k-1]);\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "230960fc4fa5668177e8dbc65d6fb332", "src_uid": "0a98a6a15e553ce11cb468d3330fc86a", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    long long n, a, b, c, ans;\n    scanf(\"%I64d %I64d %I64d %I64d\", &n, &a, &b, &c);\n    if(b - c >= a) {\n        ans = n / a;\n    } else {\n        if(n < b) {\n            ans = n / a;\n        } else {\n            ans = 0;\n            while(1) {\n                long long cnt = n / b;\n                if(cnt == 0) {\n                    break;\n                }\n                ans += cnt;\n                n = n + (c - b) * cnt;\n            }\n            ans += n / a;\n        }\n    }\n    printf(\"%I64d\\n\", ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "851609c688bbaeed9e68e64286980545", "src_uid": "0ee9abec69230eab25de51aef0984f8f", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nlong long n, a, b, c;\n\nlong long run(long long n){\n    long long x, y, z, w, res = 0;\n    x = b - c;\n    if (a < x || b > n) res = n / a;\n    else{\n        while (n >= b){\n            y = n / b;\n            res += y;\n            n -= (y * b);\n            n += (y * c);\n        }\n\n        z = n / a;\n        res += z;\n    }\n    return res;\n}\n\nint main(){\n    while (scanf(\"%lld\", &n) != EOF){\n        scanf(\"%lld %lld %lld\", &a, &b, &c);\n        long long res = run(n);\n        printf(\"%lld\\n\", res);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "10a48e5cd878d48e882b18a5d63f0261", "src_uid": "0ee9abec69230eab25de51aef0984f8f", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n\tlong long int n,a,b,c,gla,bol,num,mon;\n\t\n\twhile(scanf(\"%I64d%I64d%I64d%I64d\",&n,&a,&b,&c) != EOF)\n\t{\n\t\t\n\t\tbol = 0;\n\t\tif( b-c > a)\n\t    \tbol = n / a;\n\t\telse\n\t\t{\n\t\t\tfor(gla = 0; n >= b;)\n\t\t    {\n\t\t\t    gla=n / b;\n\t\t    \tn=n + (c - b) * gla;\n\t\t    \tbol=bol + gla;\n\t\t    }\n\t\t    \n\t\t    bol = bol + n / a;\n\t\t      \n\t\t}\n\t\tprintf(\"%I64d\\n\",bol);\n\t}\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1e47f4d1979d347a5212a6f18691b588", "src_uid": "0ee9abec69230eab25de51aef0984f8f", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdio.h>\n\nlong long max1(long long n, long long a, long long b, long long c) {\n\t\n\tlong long res = 0, t;\n\twhile (n >= b) {\n\t\tt = n / b;\n\t\tres += t;\n\t\tn = n % b + t * c;\n\t}\n\t\n\tres += n / a;\n\t\n\treturn res;\n\t\n}\n\nint main () {\n\t\n\tlong long n, a, b, c;\n\tlong long max = 0;\n\t\n\tlong long good;\n\t\n\tscanf(\"%I64d %I64d %I64d %I64d\", &n, &a, &b, &c);\n\t\n\tgood = b - c;\n\t\n\t\n\tif (n < b) {\n\t\tmax = n / a;\n\t} else if (n < a) {\n\t\tmax = max1(n, a, b, c);\n\t} else {\n\t\t\n\t\tif (good < a) {\n\t\t\t\n\t\t\tmax = max1(n, a, b, c);\n\t\t\t\n\t\t} else {\n\t\t\tmax = n / a;\n\t\t}\n\t}\n\t\n\tprintf(\"%I64d\\n\", max);\n\t\n\treturn 0;\n\t\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d67b5269885ad7080e32c53a03bda378", "src_uid": "0ee9abec69230eab25de51aef0984f8f", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tlong long int n,a,b,c,ans=0,x,y,r;\n\tscanf(\"%lld%lld%lld%lld\",&n,&a,&b,&c);\n\tif(n<a && n<b)\n\tans=0;\n\telse{\n\t\tif(a<=b-c)\n\t\tans=n/a;\n\t\telse{\n\t\t\tx=((n-b)/(b-c))+1;\n\t\t\tr=n-(b-c)*x;\n\t\t\tans=x+r/a;\n\t\t}\n\t}\n\tprintf(\"%lld\\n\",ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c558cf888aa1bac77d2e5d0782bdae59", "src_uid": "0ee9abec69230eab25de51aef0984f8f", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main() {\n\tint n, ac=0, bc=0, o=0, i, l, j;\t\n\tscanf(\"%d\", &n);\n\tint a[n];\n\tint b[n];\n\tfor(i=0; i<n; i++) {\n\t\tscanf(\"%d\", &l);\n\t\ta[i]=l;\n\t}\n\tfor(i=0; i<n; i++) {\n\t\tscanf(\"%d\", &l);\n\t\tb[i]=l;\n\t}\n\tfor(i=1; i<6; i++) {\n\t\tfor(j=0; j<n; j++) {\n\t\t\tif(a[j]==i) \n\t\t\t\tac++;\n\t\t\tif(b[j]==i)\n\t\t\t\tbc++;\n\t\t}\n\t\tif((ac+bc)%2==0) {\n\t\t\to=o+abs((ac-bc)/2);\n\t\t} else {\n\t\t\tprintf(\"-1\");\n\t\t\treturn -1;\n\t\t}\n\t\tac=0;\n\t\tbc=0;\n\t}\n\to=o/2;\n\tprintf(\"%d\", o);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1914f6cd0fa4f765e7efa3011db47a74", "src_uid": "47da1dd95cd015acb8c7fd6ae5ec22a3", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdlib.h>\n#include<stdio.h>\nvoid main ()\n{\n    int r,sum=0,n,temp,i,j,k=0;\n    scanf(\"%d\",&n);\n    int a[n],b[n],c[5]={0},d[5]={0};\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&b[i]);\n    }\n    for(i=0;i<5;i++)\n    {\n        for(j=0;j<n;j++)\n        {\n\n            if(a[j]==i+1)\n                c[i]++;\n            if(b[j]==i+1)\n                d[i]++;\n        }\n        if((c[i]+d[i])%2!=0)\n        {\n            printf(\"-1\");\n            k=1;\n            goto end;\n        }\n    }\n    if(k!=1)\n    {\n        for(i=0;i<5;i++)\n        {\n            r=(c[i]-d[i])/2;\n            if(r<0)\n            {\n                temp=r;\n                r=-(temp);\n            }\n            sum=sum+r;\n\n        }\n        printf(\"%d\",sum/2);\n    }\n    end:   ;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a08f6fd4784c965a73b49de7645ce054", "src_uid": "47da1dd95cd015acb8c7fd6ae5ec22a3", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main() {\n\tint n, ac=0, bc=0, o=0, i, l, j;\t\n\tscanf(\"%d\", &n);\n\tint a[n];\n\tint b[n];\n\tfor(i=0; i<n; i++) {\n\t\tscanf(\"%d\", &l);\n\t\ta[i]=l;\n\t}\n\tfor(i=0; i<n; i++) {\n\t\tscanf(\"%d\", &l);\n\t\tb[i]=l;\n\t}\n\tfor(i=1; i<6; i++) {\n\t\tfor(j=0; j<n; j++) {\n\t\t\tif(a[j]==i) \n\t\t\t\tac++;\n\t\t\tif(b[j]==i)\n\t\t\t\tbc++;\n\t\t}\n\t\tif((ac+bc)%2==0) {\n\t\t\to=o+abs((ac-bc)/2);\n\t\t} else {\n\t\t\treturn -1;\n\t\t}\n\t\tac=0;\n\t\tbc=0;\n\t}\n\to=o/2;\n\tprintf(\"%d\", o);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "46a21a35e89c5c915d600d666d018340", "src_uid": "47da1dd95cd015acb8c7fd6ae5ec22a3", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define MAX_N 101\n\ntypedef struct {\n    int values[6];\n} perf_count;\n\nint abs(int x) {\n    return x < 0 ? -x : x;\n}\n\n// assumption: academic performance is in [1..5]\nperf_count read_academic_perf_fast(int n) {\n    char line[MAX_N * 2];\n    // n times: read ac.perf. (one char) + one space / final '\\n'\n    fread(line, sizeof(char), n * 2, stdin);\n    // \"parse\" & count:\n    perf_count result = {.values = {0}};\n    for (int i = 0; i < n; ++i) {\n        int perf = line[i*2] - '0';\n        result.values[perf] += 1;\n    }\n    return result;\n}\n\nint solve(perf_count a_count, perf_count b_count) {\n    int sum = 0;\n    for (int i = 1; i <= 5; ++i) {\n        int d = abs(a_count.values[i] - b_count.values[i]);\n        if (d % 2 == 1) {\n            return -1;\n        }\n        sum += d;\n    }\n    return sum / 4;\n}\n\nint main(int argc, char *argv[]) {\n    int n;\n    scanf(\"%d\", &n);\n\n    perf_count a_count = read_academic_perf_fast(n);\n    perf_count b_count = read_academic_perf_fast(n);\n\n    int ans = solve(a_count, b_count);\n\n    printf(\"%d\\n\", ans);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cd372a2c75de8f71d4a2d8217ac829d6", "src_uid": "47da1dd95cd015acb8c7fd6ae5ec22a3", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "/*\n    \ufffd\u0202\ufffd\ufffd\u0391\ufffd\ufffd\u0202\ufffd\u0182\ufffd\ufffd\u0202\ufffdI \n*/\n\n#include <stdio.h>\n#include <string.h>\n#include <ctype.h>\n#include <stdlib.h>\n#include <math.h>\n#include <time.h>\n#include <limits.h>\n#define LLU unsigned long long int\n#define LL long long int\n#define LD long double\n\n#define LLUmax ULLONG_MAX\n#define LLmax LLONG_MAX\n#define dmax INT_MAX\n#define debug printf(\"asd\\n\")\n#define newline printf(\"\\n\")\n\n#define amt(a) int a;scanf(\"%d\",&a)\n#define dlld(a,b) long long int a,b;scanf(\"%I64d %I64d\",&a,&b)\n#define scd(a) int a;scanf(\"%d\",&a)\n#define sclld(a) long long int a;scanf(\"%I64d\",&a)\n#define prdlld(a,b) printf(\"%I64d %I64d\",a,b)\n#define prdd(a,b) printf(\"%d %d\",a,b)\n#define prd(a) printf(\"%d\",a)\n#define arr(a,b) int *a=(int *)malloc(n*sizeof(int))\n#define llarr(a,b) long long int *a=(long long int *)malloc(n*sizeof(long long int))\n#define st(a,b) char *a=(char *)malloc(b*sizeof(char))\n#define grav 9.8\n#define pi 3.14159265\n\nint main()\n{\n\tamt(n);\n\tint a[20000],b[20000];\n\tint c[7],d[7];\n\tfor(int i=0 ; i<6 ; i++)\n\t{\n\t\tc[i]=0;\n\t\td[i]=0;\n\t}\n\tfor(int i=0 ; i<n ;i++)\n\t{\n\t\tscanf(\"%d\",&a[i]);\n\t\tc[a[i]]++;\n\t}\n\tfor(int i=0 ; i<n ; i++)\n\t{\n\t\tscanf(\"%d\",&b[i]);\n\t\td[b[i]]++;\n\t}\n\t\n\tint e=0;\n\tint f=0,g=0;\n\tif(n==1)\n\t{\n\t\tf+=a[0];\n\t\tg+=b[0];\n\t}\n\telse if(n>1)\n\t{\t\t\n\t\t/*for(int i=1 ; i<=5 ; i++)\n\t\t{\n\t\t\tprintf(\"%d %d\\n\",c[i],d[i]);\n\t\t}*/\n\t\tfor(int i=1 ; i<=5 ; i++)\n\t\t{\n\t\t\twhile(c[i]!=d[i])\n\t\t\t{\n\t\t\t\tif(c[i]>d[i])\n\t\t\t\t{\n\t\t\t\t\tc[i]--;\n\t\t\t\t\td[i]++;\n\t\t\t\t}\n\t\t\t\telse if(c[i]<d[i])\n\t\t\t\t{\n\t\t\t\t\tc[i]++;\n\t\t\t\t\td[i]--;\n\t\t\t\t}\n\t\t\t\te++;\n\t\t\t}\n\t\t\tf+=c[i]*i;\n\t\t\tg+=d[i]*i;\n\t\t}\n\t\te/=2;\n\t}\n\t\n\tif(f==g)\n\tprd(e);\n\telse\n\tprd(-1);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0b120d110630eeb728244769417a4d15", "src_uid": "47da1dd95cd015acb8c7fd6ae5ec22a3", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\nint main(){\n\n    int i=1, n, j;\n    char*string;\n\n    scanf(\"%d\",&n);\n    string=(char*)calloc(n+1, sizeof(char));\n\n    scanf(\"%s\", string);\n\n    do{\n        if((string[i]=='a' || string[i]=='o' || string[i]=='u' || string[i]=='e' || string[i]=='i' || string[i]=='y') && (string[i-1]=='a' || string[i-1]=='o' || string[i-1]=='u' || string[i-1]=='e' || string[i-1]=='i' || string[i-1]=='y')){\n                for(j=i; j<n; j++){\n                        string[j]=string[j+1];\n                }\n        }\n        else\n            i++;\n\n    }while(i!=n);\n    printf(\"%s\", string);\n    return(0);\n}\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0f591a8440a726e1038af665c066db80", "src_uid": "63a4a5795d94f698b0912bb8d4cdf690", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    char c[50]; int n,i,j;\n    scanf(\"%d\",&n);\n    for(i=0;i<=n;i++)\n        scanf(\"%c\",&c[i]);\n    for(i=0;i<n;i++)\n    c[i]=c[i+1];\n    for(j=0;j<n;j++)\n    if((c[j]=='a' || c[j]=='o' || c[j]=='i' || c[j]=='e' || c[j]=='y') && (c[j-1]=='a' || c[j-1]=='o' || c[j-1]=='i' || c[j-1]=='e' || c[j-1]=='y'))\n    {\n        n--;\n        for(i=j;i<n;i++)\n    c[i]=c[i+1];\n        j--;\n    }\n    for(i=0;i<n;i++)\n        printf(\"%c\",c[i]);\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "06fa288f39104f5de80006ef42459c6c", "src_uid": "63a4a5795d94f698b0912bb8d4cdf690", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <unistd.h>\n\nvoid\tft_putchar(char c)\n{\n\twrite (1, &c, 1);\n}\n\nint\tft_is_vowel(char letter)\n{\n\tif (letter == 'a' || letter == 'e' || letter == 'i' \n\t\t|| letter == 'o' || letter == 'u' ||letter == 'y')\n\t\treturn (1);\n\telse\n\t\treturn (0);\n}\n\nchar\tft_word_correction(char *s, int size)\n{\n\tint i;\n\tint j;\n\tint flag;\n\n\ti = 0;\n\tj = 0;\n\tflag = 0;\n\twhile(i < size)\n\t{\n\t\tif (ft_is_vowel(s[i]) == 1)\n\t\t{\n\t\t\tflag += 1;\n\t\t\tif (flag < 2)\n\t\t\t\tft_putchar(s[i]);\n\t\t}\n\t\tif (ft_is_vowel(s[i]) == 0)\n\t\t{\n\t\t\tft_putchar(s[i]);\n\t\t\tflag = 0;\n\t\t}\n\t\ti++;\n\t}\n\tft_putchar('\\n');\n}\n\nint\tmain(void)\n{\n\n\tint n;\n\tchar *s;\n\t\n\tscanf(\"%d %s\", &n, s);\n\t\n\tft_word_correction(s, n);\n\treturn (0);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "05f67b44fa07e886e19cc81ad27a8a42", "src_uid": "63a4a5795d94f698b0912bb8d4cdf690", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <unistd.h>\n\nvoid\tft_putchar(char c)\n{\n\twrite (1, &c, 1);\n}\n\nint\tft_is_vowel(char letter)\n{\n\tif (letter == 'a' || letter == 'e' || letter == 'i' \n\t\t|| letter == 'o' || letter == 'u' ||letter == 'y')\n\t\treturn (1);\n\telse\n\t\treturn (0);\n}\n\nchar\tft_word_correction(char *s, int size)\n{\n\tint i;\n\tint j;\n\tint flag;\n\n\ti = 0;\n\tj = 0;\n\tflag = 0;\n\twhile(i < size)\n\t{\n\t\tif (ft_is_vowel(s[i]) == 1)\n\t\t{\n\t\t\tflag += 1;\n\t\t\tif (flag < 2)\n\t\t\t\tft_putchar(s[i]);\n\t\t}\n\t\tif (ft_is_vowel(s[i]) == 0)\n\t\t{\n\t\t\tft_putchar(s[i]);\n\t\t\tflag = 0;\n\t\t}\n\t\ti++;\n\t}\n\tft_putchar('\\n');\n}\n\nint\tmain(void)\n{\n\n\tint n;\n\tchar *s;\n\t\n\tscanf(\"%d %s\", &n, s);\n\t\n\tft_word_correction(s, n);\n\treturn (0);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c6e2ca57f2dbc9852b8a38c954ddeb2d", "src_uid": "63a4a5795d94f698b0912bb8d4cdf690", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    char s[n];\n    scanf(\"%s\",s);\n\nfor (int i=0,j=1;s[i]; j++ )\nif (!((s[i]=='a'||s[i]=='e'||s[i]=='i'||s[i]=='o'||s[i]=='u'||s[i]=='y') && (s[j]=='a'||s[j]=='e'||s[j]=='i'||s[j]=='o'||s[j]=='u'||s[i]=='y')))\n{printf(\"%c\",s[i]); i=j;}\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8bfb34e32df6b6122765004c4c096f4b", "src_uid": "63a4a5795d94f698b0912bb8d4cdf690", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main ()\n{\n    int r1,c1,r2,c2;\n    int a[3];\n     a[1]= 0;\n    scanf(\"%d%d%d%d\",&r1,&c1,&r2,&c2);\n    int t1 = r1 - r2;\n    int t2= c1- c2;\n\n    if( t1 < 0 )\n{\nt1 = t1*(-1);   \n}\nif(t2 < 0){\n    t2 = t2*(-1);\n}\n    int t3 = t1;\n    int t4 = t2;\n    \nif(r1 == r2 || c1 == c2 ){\n        a[0] = 1;\n    }\n    else {\n        a[0] = 2;\n    }\n    \n    if(t1 == t2){\n        a[1] = 1;\n    }\n    else if( t1 != t2){\n        if( (t1 % 2 == 0  && t2 % 2 == 0 ) && (t1 % 2 == 1  && t2 % 2 == 1)){\n            a[1] = 2;\n        }\n    \n    }\n    if( t3 == t4){\n        a[2] = t3;\n    }\n    else if ( (t3 == 0 )&&  (t4 != 0)){\n        a[2] =  t4;\n    }\n    else if((t4 == 0 )&&  (t3 != 0)){\n        a[2] = t3;\n    }\n    else if( t3 != t4){\n    if(t3 > t4){\n        a[2] = t3;\n    }\n    else {\n        a[2] = t4;\n    }\n    }\n    printf(\"%d %d %d\",a[0],a[1],a[2]);\n    return 0;   \n    \n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1ec14d9ba81531aca961031bfc4ff6dd", "src_uid": "7dbf58806db185f0fe70c00b60973f4b", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include <math.h> \nint main( ) \n{ \n    int x1,y1,x2,y2;\n    scanf(\"%d%d%d%d\",&x1,&y1,&x2,&y2); \n    int x, y; \n    x = abs(x1 - x2); \n    y = abs(y1 - y2); \n    if(x == 0 || y == 0) \n        printf(\"1\");\n    else       \n        printf(\"2\"); \n    if(abs(x - y) % 2 != 0) \n        printf(\" 0\"); \n    else if(x == y) \n        printf(\" 1\"); \n    else         \n        printf(\" 2\");\n    if(x < y) \n        printf(\" %d\\n\",y);\n    else\n        printf(\" %d\\n\",x);  \n} ", "lang_cluster": "C", "compilation_error": false, "code_uid": "fe1233be9cdb50c6373a25de157a8858", "src_uid": "7dbf58806db185f0fe70c00b60973f4b", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int r1,r2,c1,c2;\n    scanf(\"%d%d%d%d\",&r1,&c1,&r2,&c2);\n    int t1,t2,t3=0;\n    if((r1==r2)||(c1==c2))\n    {\n        t1=1;\n        if(r1==r2)\n        {\n            t3=abs(c2-c1);\n        }\n        else\n        {\n            t3=abs(r2-r1);\n        }\n    }\n    else\n    {\n        t1=2;;\n    }\n    int k1,k2,k3,k4;\n    k1=r1%2;\n    k2=c1%2;\n    k3=r2%2;\n    k4=c2%2;\n    if(((k1==0)&&(k2==0))||((k1==1)&&(k2==1)))\n    {\n        if(((k3==0)&&(k4==1))||((k3==1)&&(k4==0)))\n        {\n            t2=0;\n        }\n        else\n        {\n            int q;\n            q=(c2-c1)/(r2-r1);\n            if(abs(q)==1)\n            {\n                t2=1;\n            }\n            else\n            {\n                t2=2;\n            }\n        }\n\n    }\n    if(((k1==0)&&(k2==1))||((k1==1)&&(k2==0)))\n    {\n        if(((k3==0)&&(k4==0))||((k3==1)&&(k4==1)))\n        {\n            t2=0;\n        }\n        else\n        {\n            int q;\n            q=(c2-c1)/(r2-r1);\n            if(abs(q)==1)\n            {\n                t2=1;\n            }\n            else\n            {\n                t2=2;\n            }\n        }\n\n    }\n    if(t3==0)\n    {\n        \n        int p,u;\n        p=abs(r2-r1);\n        u=abs(c2-c1);\n        int countit=0;\n        while(p!=u)\n        {\n            if(p>u)\n            {\n                p--;\n                countit++;\n            }\n            if(u>p)\n            {\n                u--;\n                countit++;\n            }\n        }\n        countit=countit+u;\n        t3=countit;\n    }\n    printf(\"%d %d %d\",t1,t2,t3);\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6c4fa44db906984306aef405ad0136c1", "src_uid": "7dbf58806db185f0fe70c00b60973f4b", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int r1, c1, r2, c2;\n    scanf(\"%d %d %d %d\", &r1, &c1, &r2, &c2);\n\n    int R=0, B=0, K=0;\n\n    int Dr = r1 - r2, Dc = c1 - c2;\n    if(Dr < 0)\n        Dr*=-1;\n    if(Dc < 0)\n        Dc*=-1;\n    \n\n    if(Dr==0 || Dc==0)\n        R=1;\n    else\n        R=2;\n\n    \n    if((((r1+c1)%2 == 0) && ((r2+c2)%2 == 0)) || (((r1+c1)%2 != 0) && ((r2+c2)%2 != 0)))\n    {\n        int m = Dr/Dc;\n        if(m == 1)\n            B=1;\n        else\n            B=2;\n    }\n\n    if(Dr > Dc)\n        K = Dr;\n    else\n        K = Dc;\n\n    printf(\"%d %d %d\\n\", R, B, K); \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1d9469b3c21ebe2f152276826ab2e310", "src_uid": "7dbf58806db185f0fe70c00b60973f4b", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int r1, c1, r2, c2;\n    scanf(\" %d %d %d %d\", &r1, &c1, &r2, &c2);\n\n    int R=0, B=0, K=0;\n\n    int Dr = r1 - r2, Dc = c1 - c2;\n    if(Dr < 0)\n        Dr*=-1;\n    if(Dc < 0)\n        Dc*=-1;\n    \n\n    if(Dr==0 || Dc==0)\n        R=1;\n    else\n        R=2;\n\n    \n    if((((r1+c1)%2 == 0) && ((r2+c2)%2 == 0)) || (((r1+c1)%2 != 0) && ((r2+c2)%2 != 0)))\n    {\n        int m = Dr/Dc;\n        if(m == 1)\n            B=1;\n        else\n            B=2;\n    }\n\n    if(Dr > Dc)\n        K = Dr;\n    else\n        K = Dc;\n\n    printf(\"%d %d %d\\n\", R, B, K); \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d300604a305ff1ebc50c67f287982c15", "src_uid": "7dbf58806db185f0fe70c00b60973f4b", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nmain()\n{\n    long long n,tn;\n scanf(\"%lld\",&tn);\n for(n=1;n<=tn;n++)\n {\n     \n    if(n*(n+1)/2==tn)\n    {\n        \n        printf(\"YES\");\n        return;\n    }\n }\n    \n  printf(\"NO\");   \n    \n    \n return 0;   \n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "45242af6950ba43909379f3ad8beb7ca", "src_uid": "587d4775dbd6a41fc9e4b81f71da7301", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint n, i;\n\tscanf(\" %d\", &n);\n\tif(n<56)\n\t{\n\t\tfor(i=1; i<11; i++)\n\t\t\tif(i*(i+1)/2 == n)\n\t\t\t{\n\t\t\t\tprintf(\"YES\");\n\t\t\t\tbreak;\n\t\t\t}\n\t}\n\telse if(n<211)\n\t{\n\t\tfor(i=11; i<21; i++)\n\t\t\tif(i*(i+1)/2 == n)\n\t\t\t{\n\t\t\t\tprintf(\"YES\");\n\t\t\t\tbreak;\n\t\t\t}\n\t}\n\telse if(n<497)\n\t{\n\t\tfor(i=21; i<32; i++)\n\t\t\tif(i*(i+1)/2 == n)\n\t\t\t{\n\t\t\t\tprintf(\"YES\");\n\t\t\t}\n\t}\n\telse\n\t\tprintf(\"NO\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d4e668ddfeefb61d7880ca24649677db", "src_uid": "587d4775dbd6a41fc9e4b81f71da7301", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint n, i;\n\tscanf(\" %d\", &n);\n\tif(n<56)\n\t{\n\t\tfor(i=1; i<11; i++)\n\t\t\tif(i*(i+1)/2 == n)\n\t\t\t\tprintf(\"YES\");\n\t}\n\telse if(n<211)\n\t{\n\t\tfor(i=11; i<21; i++)\n\t\t\tif(i*(i+1)/2 == n)\n\t\t\t\tprintf(\"YES\");\n\t}\n\telse if(n<497)\n\t{\n\t\tfor(i=21; i<32; i++)\n\t\t\tif(i*(i+1)/2 == n)\n\t\t\t\tprintf(\"YES\");\n\t}\n\telse\n\t\tprintf(\"NO\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "91af456d56e3209d1f5250bf0c332f54", "src_uid": "587d4775dbd6a41fc9e4b81f71da7301", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint n, i;\n\tscanf(\" %d\", &n);\n\tif(n<56)\n\t{\n\t\tfor(i=1; i<11; i++)\n\t\t\tif(i*(i+1)/2 == n)\n\t\t\t{\n\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\tbreak;\n\t\t\t}\n\t}\n\telse if(n<211)\n\t{\n\t\tfor(i=11; i<21; i++)\n\t\t\tif(i*(i+1)/2 == n)\n\t\t\t{\n\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\tbreak;\n\t\t\t}\n\t}\n\telse if(n<497)\n\t{\n\t\tfor(i=21; i<32; i++)\n\t\t\tif(i*(i+1)/2 == n)\n\t\t\t{\n\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\tbreak;\n\t\t\t}\n\t}\n\telse\n\t\tprintf(\"NO\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "703588e15752bd1e73dfbd51b0fff08e", "src_uid": "587d4775dbd6a41fc9e4b81f71da7301", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint ara[78999999];\nint main()\n{\n    long long int i,j,k,l,m,n,x=0;\n    for(i=1,j=1;i<=500;i++,j++){\n            x+=j;\n        ara[x]=1;\n\n    }\n\n    scanf(\"%I64d\",&n);\n    if(ara[n]==1)\n        printf(\"YES\\n\");\n    else\n        printf(\"NO\\n\");\n    return 0;\n\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5203ee7b4eff742aa012be1c1c33367c", "src_uid": "587d4775dbd6a41fc9e4b81f71da7301", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint CanWeStart(int tank_size, int gas_station, int endpoint);\nvoid GotoEnd(int * tank, int tank_size, int gas_station, int endpoint, int * journey, int * count);\nvoid Goto0(int * tank, int tank_size, int gas_station, int endpoint, int * journey, int * count);\n\nint main(void)\n{\n    int endpoint, tank, gas_station , journey, tank_size, count;\n    scanf(\"%d %d %d %d\",&endpoint, &tank, &gas_station, &journey);\n    tank_size = tank;\n    count = 0;\n    \n    if( CanWeStart(tank_size, gas_station, endpoint) == 0 )\n    {\n        printf(\"-1\");\n        return 0;\n    }\n    \n    while(journey>0)\n    {\n        GotoEnd(&tank, tank_size, gas_station, endpoint, &journey, &count);\n        if(journey == 0)\n            break;\n        Goto0(&tank, tank_size, gas_station, endpoint, &journey, &count);\n    }\n    \n    printf(\"%d\",count);\n    \n    return 0;\n}\n\nint CanWeStart(int tank_size, int gas_station, int endpoint)\n{\n    if( tank_size < 2*(endpoint-gas_station) || tank_size < 2*gas_station )\n        return 0;\n    else\n        return 1;\n}\n    \n\nvoid GotoEnd(int * tank, int tank_size, int gas_station, int endpoint, int * journey, int * count)\n{\n    int YN;\n    *tank -= gas_station;\n    if( *journey == 1)\n    {\n        if( (*tank -(endpoint-gas_station)) >= 0 )\n            YN = 0;\n        else\n            YN = 1;\n    }\n    else\n    {\n        if( (*tank - 2*(endpoint-gas_station)) >=0 )\n            YN = 0;\n        else\n            YN = 1;\n    }\n    if(YN == 1)\n    {\n        *tank = tank_size;\n        *count += 1;\n    }\n    \n    *tank -= (endpoint-gas_station);\n    *journey -= 1;\n}\n\nvoid Goto0(int * tank, int tank_size, int gas_station, int endpoint, int * journey, int * count)\n{\n    int YN;\n    *tank -= (endpoint-gas_station);\n    if( *journey == 1)\n    {\n        if( (*tank -gas_station) >= 0 )\n            YN = 0;\n        else\n            YN = 1;\n    }\n    else\n    {\n        if( *tank -(2*gas_station) >=0 )\n            YN = 0;\n        else\n            YN = 1;\n    }\n    if(YN == 1)\n    {\n        *tank = tank_size;\n        *count += 1;\n    }\n    \n    *tank -= gas_station;\n    *journey -= 1;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3310b293f0979556256b8369e8b7e517", "src_uid": "283aff24320c6518e8518d4b045e1eca", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    long long a,b,f,k,u,n,j=0;\n    int i=0;\n    scanf(\"%lld %lld %lld %lld\",&a,&f,&b,&k);\n    u=f;\n    n=a*k;\n    for(;n>0;)\n    {\n        if(n==a*k)\n        {\n            if(f>=b || f>=a-b)\n            {\n                u-=b;\n                n-=b;\n            }\n            else\n            {\n                printf(\"-1\");\n                return 0;\n            }\n\n        }\n        if(i==0)\n        {\n            if(n==a-b)\n            {\n                if(u>=a-b) break;\n                else\n                {\n                    j++;\n                    break;\n                }\n            }\n            if(f<(a-b)*2)\n            {\n                printf(\"-1\");\n                return 0;\n            }\n            else\n            {\n                if(u<(a-b)*2)\n                {\n                    u=f;\n                    j++;\n                }\n                u-=(a-b)*2;\n                n-=(a-b)*2;\n            }\n            if(n==b)\n            {\n                if(u>=b) break;\n                else\n                {\n                    j++;\n                    break;\n                }\n            }\n            if(f<(b)*2)\n            {\n                printf(\"-1\");//there is a prob\n                return 0;\n            }\n            else\n            {\n                if(u<(b)*2)\n                {\n                    u=f;\n                    j++;\n                }\n                u-=(b)*2;\n                n-=(b)*2;\n            }\n\n        }\n\n    }\n    if(j!=0) printf(\"%lld\",j);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "17c61719dc7602d151728a3c88731b72", "src_uid": "283aff24320c6518e8518d4b045e1eca", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void)\n{\n\tint a, b, f, k, j, cnt = 0, rest;\n\tscanf(\"%d %d %d %d\", &a, &b, &f, &k);\n\trest = b;\n\tfor (j = 1; j <= k; j = j + 1)\n\t{\n\t\tint d = j & 1;\n\t\tif (j < k)\n\t\t{\n\t\t\tif (d)\n\t\t\t{\n\t\t\t\tif (rest < f)\n\t\t\t\t{\n\t\t\t\t\tcnt = -1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\telse if (rest >= f)\n\t\t\t\t{\n\t\t\t\t\tif (rest >= (a << 1) - f)\n\t\t\t\t\t{\n\t\t\t\t\t\trest = rest - (a << 1) + f;\n\t\t\t\t\t}\n\t\t\t\t\telse if (rest < (a << 1) - f)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (b < ((a - f) << 1))\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tcnt = -1;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if (b >= ((a - f) << 1))\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tcnt += 1;\n\t\t\t\t\t\t\trest = b - ((a - f) << 1);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\telse if (d == 0)\n\t\t\t{\n\t\t\t\tif (rest < (f << 1) && b < (f << 1))\n\t\t\t\t{\n\t\t\t\t\tcnt = -1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\telse if (rest < (f << 1) && b >= f)\n\t\t\t\t{\n\t\t\t\t\tcnt += 1;\n\t\t\t\t\trest = b - f;\n\t\t\t\t}\n\t\t\t\telse if (rest >= (f << 1))\n\t\t\t\t{\n\t\t\t\t\trest = rest - f;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse if (j == k)\n\t\t{\n\t\t\tif (d)\n\t\t\t{\n\t\t\t\tif (rest < f)\n\t\t\t\t{\n\t\t\t\t\tif (b < f)\n\t\t\t\t\t\tcnt = -1;\n\t\t\t\t\telse if (b >= f)\n\t\t\t\t\t\tcnt += 1;\n\t\t\t\t}\n\t\t\t\telse if (rest >= f)\n\t\t\t\t{\n\t\t\t\t\tif (b < f)\n\t\t\t\t\t\tcnt = -1;\n\t\t\t\t}\n\t\t\t}\n\t\t\telse if (d == 0)\n\t\t\t{\n\t\t\t\tif (rest < f && b < f)\n\t\t\t\t\tcnt = -1;\n\t\t\t\telse if (rest < f && b >= f)\n\t\t\t\t\tcnt += 1;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\", cnt);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "65cc73da1e9709fd82fd8b37cf1a24ad", "src_uid": "283aff24320c6518e8518d4b045e1eca", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main() {\n    int a, b, f, k;\n    int sum = 0, n;\n    scanf(\"%d %d %d %d\", &a, &b, &f, &k);\n    n = b;\n    if(k > 1) {\n        if(b < 2 * (a - f) || b < f || b < 2 * f) {\n            printf(\"-1\\n\");\n        }\n        else {\n            for(int i = 1; i <= k; i++) {\n                if(i % 2 == 1 && i != k) {\n                    n = n - f;\n                    if(n < 2 * (a - f)) {\n                        n = b;\n                        sum++;\n                    }\n                    n = n - (a - f);\n                }\n                else if(i % 2 == 0 && i != k){\n                    n = n - (a - f);\n                    if(n < 2 * f) {\n                        n = b;\n                        sum++;\n                    }\n                    n = n - f;\n                }\n                else if(i % 2 == 1 && i == k) {\n                    n = n - f;\n                    if(n < (a - f)) {\n                        n = b;\n                        sum++;\n                    }\n                }\n                else if(i % 2 == 0 && i == k) {\n                    n = n - (a - f);\n                    if(n < f) {\n                        n = b;\n                        sum++;\n                    }\n                }\n            }\n            printf(\"%d\\n\", sum);\n        }\n    }\n    else {\n        if(b < f || b < (a - f)) {\n            printf(\"-1\\n\");\n        }\n        else {\n            n = n - f;\n            if(n < (a - f)) {\n                sum++;\n            }\n            printf(\"%d\\n\", sum);\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "64f0fec8970e8419394f3927c01c7f9e", "src_uid": "283aff24320c6518e8518d4b045e1eca", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <ctype.h>\n#include <string.h>\n#include <math.h>\nint main(){\nint a,b,f,k;\nscanf(\"%d%d%d%d\",&a,&b,&f,&k);\nint counter=-1;\nint position=0;\nint fuel = b;\nint wway=-1;\nint fuelcounter=0;\nint test=0;\nwhile(counter<k)\n{\n    if(position==a || position==0){\n        wway *= -1;\n        counter++;\n        if(counter==k)\n            break;\n\n    }\n    if(position==f){\n        if(wway==1){\n            if(fuel>=2*(a-f)){\n            }else{\n                if(counter+1<k){\n                    fuel=b;\n                    fuelcounter++;\n                }else{\n                    if(fuel>=a-f){\n                    }else{\n                        fuel=b;\n                        fuelcounter++;\n                    }\n                }\n            }\n        }else{\n            if(fuel>=2*f){\n            }else{\n                if(counter+1<k){\n                    fuel=b;\n                    fuelcounter++;\n                }else{\n                    if(fuel>=f){\n                    }else{\n                        fuel=b;\n                        fuelcounter++;\n                    }\n                }\n            }\n\n        }\n    }\n    if(fuel==0){\n        test=1;\n        break;\n    }\n    position += wway;\n    fuel--;\n}\n\n    if(test==1){\n        printf(\"-1\");\n    }else{\n        printf(\"%d\",fuelcounter);\n    }\n\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cad74c4eade34f2a87bbf1460e1b7ad0", "src_uid": "283aff24320c6518e8518d4b045e1eca", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <unistd.h>\n#include <stdlib.h>\n\ntypedef struct\t\ts_btree\n{\n\tstruct s_btree\t*left;\n\tstruct s_btree\t*right;\n\tint\t\t\t\tvalue;\n\tint\t\t\t\tlvl;\n}\t\t\t\t\tt_btree;\n\nt_btree\tcoada[20000000];\n\nt_btree\t*ft_create_node(int data)\n{\n\tt_btree\t*new;\n\n\tnew = (t_btree*)malloc(sizeof(t_btree));\n\tnew->left = NULL;\n\tnew->right = NULL;\n\tnew->value = data;\n\treturn (new);\n}\n\nint\t\tst, dr;\nint\t\tok, result;\n\nvoid\tbfs(t_btree *node, int m)\n{\n\tt_btree\t*new;\n\n\tif (node->value == m)\n\t{\n\t\tresult = node->lvl;\n\t\tok = 0;\n\t}\n\telse\n\t{\n\t\tnew = ft_create_node(node->value - 1);\n\t\tnew->lvl = node->lvl + 1;\n\t\tdr++;\n\t\tcoada[dr] = *new;\n\t\tnew = ft_create_node(node->value * 2);\n\t\tnew->lvl = node->lvl + 1;\n\t\tdr++;\n\t\tcoada[dr] = *new;\n\t}\n}\n\nint\t\tmain(void)\n{\n\tint\t\tn, m;\n\tt_btree\t*root;\n\n\tok = 1;\n\tscanf(\"%d %d\", &n, &m);\n\troot = ft_create_node(n);\n\troot->lvl = 0;\n\tst = dr = 1;\n\tcoada[st] = *root;\n\twhile (ok && st <= dr)\n\t{\n\t\tbfs(&coada[st], m);\n\t\tst++;\n\t}\n\tprintf(\"%d\\n\", result);\n\treturn (0);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bd5fbda09c1cdbd13bc772a9589ff8cc", "src_uid": "861f8edd2813d6d3a5ff7193a804486f", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n/*\n\nVasya has found a strange device. On the front panel of\na device there are: a red button, a blue button and a\ndisplay showing some positive integer. After clicking\nthe red button, device multiplies the displayed number\nby two. After clicking the blue button, device subtracts\none from the number on the display. If at some point\nthe number stops being positive, the device breaks down.\nThe display can show arbitrarily large numbers.\nInitially, the display shows number n.\n\nBob wants to get number m on the display. What minimum\nnumber of clicks he has to make in order to achieve this result?\n\nInput\nThe first and the only line of the input contains\ntwo distinct integers n and m (1 <= n, m <= 10000),\nseparated by a space.\n\nOutput\nPrint a single number \ufffd the minimum number of times one\nneeds to push the button required to get the number m out\nof number n.\n\n*/\n\ntypedef struct Pair {\n    int data;\n    int distance;\n} Pair;\n\nstruct QueueElem{\n    Pair pair;\n    struct QueueElem* next;\n};\n\nPair makePair(int f, int s){\n    Pair p = {f, s};\n    return p;\n}\n\ntypedef struct QueueElem Elem;\n\nstruct Queue{\n    Elem *front; // sa fronta uklanjam\n    Elem *rear; // na rear dodajem\n};\n\ntypedef struct Queue Queue;\n\nvoid init(Queue *q){\n    q->front = NULL;\n    q->rear = NULL;\n}\n\nvoid destroy(Queue *q){ // treba svaki Elem brisat jer je pravljen sa malloc\n    free(q->front);\n    free(q->rear);\n}\n\nint isEmpty(Queue *q){\n    return (q->front == NULL && q->rear == NULL);\n}\n\n//void print(Queue *q){\n//    for(Elem *curr = q->front; curr != NULL; curr = curr->next){\n//        printf(\"%d \", curr->data);\n//    }\n//    printf(\"\\n\");\n//}\n\nvoid enqueue(Queue *q, Pair p){\n    Elem *newElem = malloc(sizeof(Elem));\n    newElem->pair = p;\n    newElem->next = NULL;\n\n    if(q->rear == NULL){\n        q->front = newElem;\n        q->rear = newElem;\n    }\n    else{\n        q->rear->next = newElem;\n        q->rear = newElem;\n    }\n}\n\nPair dequeue(Queue *q){\n    if(isEmpty(q)){\n        return makePair(-10000, -10000);\n    }\n    Pair temp = q->front->pair;\n\n    Elem *tmp = q->front;\n    q->front = q->front->next;\n    free(tmp);\n    //tmp = NULL;\n\n    if(q->front == NULL){\n        q->rear = NULL;\n    }\n    return temp;\n}\n\nPair peek(Queue *q){\n    if(q->front != NULL) return q->front->pair;\n    else return makePair(-10000, -10000);\n}\n\n// a greedy BFS sounds fine, maybe for small inputs, we'll see\n// what code forces says\n\nvoid solve(){\n    int n, m;\n    scanf(\"%d%d\", &n, &m);\n\n    Queue q1;\n    Queue *q = &q1;\n    init(q);\n    enqueue(q, makePair(n, 0));\n\n    while(!isEmpty(q)){\n        Pair curr = dequeue(q);\n        if(curr.data == m){\n            printf(\"%d\", curr.distance);\n            return;\n        }\n        enqueue(q, makePair(curr.data*2, curr.distance+1));\n        if(curr.data-1 >= 0){\n            enqueue(q, makePair(curr.data-1, curr.distance+1));\n        }\n    }\n}\n\nint main()\n{\n    solve();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7b4e2e6672c1b00f70d9d32443dc3e79", "src_uid": "861f8edd2813d6d3a5ff7193a804486f", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nstatic int arr[10001][10001];\nstatic int a,b;\nstatic int dp[10001][10001];\nint bluered(int n, int m)\n{\n        if(arr[n][m]==-1)\n                return 100001;\n        arr[n][m]=-1;\n        if(dp[n][m]!=-1)\n                return dp[n][m];\n        if(n==a && m==b){\n                dp[n][m]=1;\n                return 1;}\n\n\n        if(n==m){\n                dp[n][m]=0;\n                return 0;}\n        if(m<n){\n                dp[n][m]=n-m;\n                return n-m;}\n        int count1=1,count2=1;\n\n        count1=count1+ (bluered(n*2,m));\n        if(n>1){\n        count2=count2+(bluered(n-1,m));}\n        if(n<=1){\n                dp[n][m]=count1;\n        return count1;  }\n        if(count1<count2)\n        {dp[n][m]=count1;\n                return count1;}\n        else{\n                dp[n][m]=count2;\n                return count2;\n        }\n}\n\nint main()\n\n{\n        int i,j;\n        for(i=0;i<1001;i++)\n        {\n                for(j=0;j<1001;j++){\n                        arr[i][j]=0;\n                        dp[i][j]=-1;\n                }\n        }\n        int a,b;\n        scanf(\"%d %d\",&a,&b);\n        int count=0;\n        count+=bluered(a,b);\n        printf(\"%d\",count);\n        return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f2ffc3743beaccb9378b478405ca35ed", "src_uid": "861f8edd2813d6d3a5ff7193a804486f", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "/*\n * Copyright (c) 2017-2019 Bailey Thompson\n *\n * Permission is hereby granted, free of charge, to any person obtaining a copy\n * of this software and associated documentation files (the \"Software\"), to deal\n * in the Software without restriction, including without limitation the rights\n * to use, copy, modify, merge, publish, distribute, sublicense, and/or sell\n * copies of the Software, and to permit persons to whom the Software is\n * furnished to do so, subject to the following conditions:\n *\n * The above copyright notice and this permission notice shall be included in\n * all copies or substantial portions of the Software.\n *\n * THE SOFTWARE IS PROVIDED \"AS IS\", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR\n * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,\n * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE\n * AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER\n * LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,\n * OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE\n * SOFTWARE.\n */\n\n#ifndef CONTAINERS_DEQUE_H\n#define CONTAINERS_DEQUE_H\n\n#include <stdlib.h>\n\n/**\n * The deque data structure, which is a doubly-ended queue.\n */\ntypedef struct internal_deque *deque;\n\n/* Starting */\ndeque deque_init(size_t data_size);\n\n/* Utility */\nint deque_size(deque me);\nint deque_is_empty(deque me);\nint deque_trim(deque me);\nvoid deque_copy_to_array(void *arr, deque me);\n\n/* Adding */\nint deque_push_front(deque me, void *data);\nint deque_push_back(deque me, void *data);\n\n/* Removing */\nint deque_pop_front(void *data, deque me);\nint deque_pop_back(void *data, deque me);\n\n/* Setting */\nint deque_set_first(deque me, void *data);\nint deque_set_at(deque me, int index, void *data);\nint deque_set_last(deque me, void *data);\n\n/* Getting */\nint deque_get_first(void *data, deque me);\nint deque_get_at(void *data, deque me, int index);\nint deque_get_last(void *data, deque me);\n\n/* Ending */\nint deque_clear(deque me);\ndeque deque_destroy(deque me);\n\n#endif /* CONTAINERS_DEQUE_H */\n\n\n\n/*\n * Copyright (c) 2017-2019 Bailey Thompson\n *\n * Permission is hereby granted, free of charge, to any person obtaining a copy\n * of this software and associated documentation files (the \"Software\"), to deal\n * in the Software without restriction, including without limitation the rights\n * to use, copy, modify, merge, publish, distribute, sublicense, and/or sell\n * copies of the Software, and to permit persons to whom the Software is\n * furnished to do so, subject to the following conditions:\n *\n * The above copyright notice and this permission notice shall be included in\n * all copies or substantial portions of the Software.\n *\n * THE SOFTWARE IS PROVIDED \"AS IS\", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR\n * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,\n * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE\n * AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER\n * LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,\n * OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE\n * SOFTWARE.\n */\n\n#include <string.h>\n#include <errno.h>\n\nstatic const int BLOCK_SIZE = 8;\nstatic const double RESIZE_RATIO = 1.5;\n\nstruct internal_deque {\n    size_t data_size;\n    int start_index;\n    int end_index;\n    int block_count;\n    struct node *block;\n};\n\nstruct node {\n    void *data;\n};\n\n/**\n * Initializes a deque.\n *\n * @param data_size the size of each element in the deque; must be positive\n *\n * @return the newly-initialized deque, or NULL if it was not successfully\n *         initialized due to either invalid input arguments or memory\n *         allocation error\n */\ndeque deque_init(const size_t data_size)\n{\n    struct internal_deque *init;\n    struct node *block;\n    if (data_size == 0) {\n        return NULL;\n    }\n    init = malloc(sizeof(struct internal_deque));\n    if (!init) {\n        return NULL;\n    }\n    init->data_size = data_size;\n    init->start_index = BLOCK_SIZE / 2;\n    init->end_index = init->start_index + 1;\n    init->block_count = 1;\n    init->block = malloc(sizeof(struct node));\n    if (!init->block) {\n        free(init);\n        return NULL;\n    }\n    block = init->block;\n    block->data = malloc(BLOCK_SIZE * init->data_size);\n    if (!block->data) {\n        free(init->block);\n        free(init);\n        return NULL;\n    }\n    return init;\n}\n\n/**\n * Determines the size of the deque. The size is the number of data spaces being\n * used. The size starts at zero, and every time an element is added, it\n * increases by one.\n *\n * @param me the deque to check the size of\n *\n * @return the size of the deque\n */\nint deque_size(deque me)\n{\n    return me->end_index - me->start_index - 1;\n}\n\n/**\n * Determines if the deque is empty. It is empty if it has no elements.\n *\n * @param me the deque to check if empty\n *\n * @return 1 if the deque is empty, otherwise 0\n */\nint deque_is_empty(deque me)\n{\n    return deque_size(me) == 0;\n}\n\n/**\n * Trims the deque so that it does not use memory which does not need to be\n * used.\n *\n * @param me the deque to trim\n *\n * @return 0       if no error\n * @return -ENOMEM if out of memory\n */\nint deque_trim(deque me)\n{\n    int i;\n    /* The start and end blocks are written like this because in C89    */\n    /* negative integer division and modulo are implementation-defined. */\n    const int start_block =\n            me->start_index == -1 ? 0 : me->start_index / BLOCK_SIZE;\n    const int end_block =\n            me->end_index == 0 ? 0 : (me->end_index - 1) / BLOCK_SIZE;\n    const int new_block_count = end_block - start_block + 1;\n    void *const new_block = malloc(new_block_count * sizeof(struct node));\n    if (!new_block) {\n        return -ENOMEM;\n    }\n    for (i = 0; i < start_block; i++) {\n        const struct node block_item = me->block[i];\n        free(block_item.data);\n    }\n    for (i = end_block + 1; i < me->block_count; i++) {\n        const struct node block_item = me->block[i];\n        free(block_item.data);\n    }\n    memcpy(new_block,\n           &me->block[start_block],\n           new_block_count * sizeof(struct node));\n    free(me->block);\n    me->block = new_block;\n    me->block_count = new_block_count;\n    me->start_index -= start_block * BLOCK_SIZE;\n    me->end_index -= start_block * BLOCK_SIZE;\n    return 0;\n}\n\n/**\n * Copies the deque to an array. Since it is a copy, the array may be modified\n * without causing side effects to the deque data structure. Memory is not\n * allocated, thus the array being used for the copy must be allocated before\n * this function is called. The size of the deque should be queried prior to\n * calling this function, which also serves as the size of the newly-copied\n * array.\n *\n * @param arr the initialized array to copy the deque to\n * @param me  the deque to copy to the array\n */\nvoid deque_copy_to_array(void *const arr, deque me)\n{\n    int i;\n    for (i = 0; i < deque_size(me); i++) {\n        deque_get_at((char *) arr + i * me->data_size, me, i);\n    }\n}\n\n/**\n * Adds an element to the front of the deque. The pointer to the data being\n * passed in should point to the data type which this deque holds. For example,\n * if this deque holds integers, the data pointer should be a pointer to an\n * integer. Since the data is being copied, the pointer only has to be valid\n * when this function is called.\n *\n * @param me   the deque to add an element to\n * @param data the element to add\n *\n * @return 0       if no error\n * @return -ENOMEM if out of memory\n */\nint deque_push_front(deque me, void *const data)\n{\n    struct node block_item;\n    int block_index;\n    int inner_index;\n    if (me->start_index == -1) {\n        block_index = -1;\n        inner_index = BLOCK_SIZE - 1;\n    } else {\n        block_index = me->start_index / BLOCK_SIZE;\n        inner_index = me->start_index % BLOCK_SIZE;\n    }\n    if (inner_index == BLOCK_SIZE - 1) {\n        struct node *block_item_reference;\n        if (block_index == -1) {\n            int i;\n            const int old_block_count = me->block_count;\n            const int new_block_count =\n                    (int) (RESIZE_RATIO * me->block_count) + 1;\n            const int added_blocks = new_block_count - old_block_count;\n            void *temp = realloc(me->block,\n                                 new_block_count * sizeof(struct node));\n            if (!temp) {\n                return -ENOMEM;\n            }\n            me->block = temp;\n            me->block_count = new_block_count;\n            memmove(&me->block[added_blocks],\n                    me->block,\n                    old_block_count * sizeof(struct node));\n            block_index = added_blocks - 1;\n            me->start_index += added_blocks * BLOCK_SIZE;\n            me->end_index += added_blocks * BLOCK_SIZE;\n            for (i = 0; i < added_blocks; i++) {\n                struct node *const block_item_copy = &me->block[i];\n                block_item_copy->data = NULL;\n            }\n        }\n        block_item_reference = &me->block[block_index];\n        if (!block_item_reference->data) {\n            block_item_reference->data = malloc(BLOCK_SIZE * me->data_size);\n            if (!block_item_reference->data) {\n                return -ENOMEM;\n            }\n        }\n    }\n    block_item = me->block[block_index];\n    memcpy((char *) block_item.data + inner_index * me->data_size, data,\n           me->data_size);\n    me->start_index--;\n    return 0;\n}\n\n/**\n * Adds an element to the back of the deque. The pointer to the data being\n * passed in should point to the data type which this deque holds. For example,\n * if this deque holds integers, the data pointer should be a pointer to an\n * integer. Since the data is being copied, the pointer only has to be valid\n * when this function is called.\n *\n * @param me   the deque to add an element to\n * @param data the element to add\n *\n * @return 0       if no error\n * @return -ENOMEM if out of memory\n */\nint deque_push_back(deque me, void *const data)\n{\n    struct node block_item;\n    const int block_index = me->end_index / BLOCK_SIZE;\n    const int inner_index = me->end_index % BLOCK_SIZE;\n    if (inner_index == 0) {\n        struct node *block_item_reference;\n        if (block_index == me->block_count) {\n            int i;\n            const int new_block_count =\n                    (int) (RESIZE_RATIO * me->block_count) + 1;\n            void *temp = realloc(me->block,\n                                 new_block_count * sizeof(struct node));\n            if (!temp) {\n                return -ENOMEM;\n            }\n            me->block = temp;\n            me->block_count = new_block_count;\n            for (i = block_index; i < me->block_count; i++) {\n                struct node *const block_item_copy = &me->block[i];\n                block_item_copy->data = NULL;\n            }\n        }\n        block_item_reference = &me->block[block_index];\n        if (!block_item_reference->data) {\n            block_item_reference->data = malloc(BLOCK_SIZE * me->data_size);\n            if (!block_item_reference->data) {\n                return -ENOMEM;\n            }\n        }\n    }\n    block_item = me->block[block_index];\n    memcpy((char *) block_item.data + inner_index * me->data_size, data,\n           me->data_size);\n    me->end_index++;\n    return 0;\n}\n\n/**\n * Removes the front element from the deque and copies it to a data value. The\n * pointer to the data being obtained should point to the data type which this\n * deque holds. For example, if this deque holds integers, the data pointer\n * should be a pointer to an integer. Since this data is being copied from the\n * array to the data pointer, the pointer only has to be valid when this\n * function is called.\n *\n * @param data the value to copy to\n * @param me   the deque to remove from\n *\n * @return 0       if no error\n * @return -EINVAL if invalid argument\n */\nint deque_pop_front(void *const data, deque me)\n{\n    int block_index;\n    int inner_index;\n    struct node block_item;\n    if (deque_is_empty(me)) {\n        return -EINVAL;\n    }\n    me->start_index++;\n    block_index = me->start_index / BLOCK_SIZE;\n    inner_index = me->start_index % BLOCK_SIZE;\n    block_item = me->block[block_index];\n    memcpy(data, (char *) block_item.data + inner_index * me->data_size,\n           me->data_size);\n    return 0;\n}\n\n/**\n * Removes the back element from the deque and copies it to a data value. The\n * pointer to the data being obtained should point to the data type which this\n * deque holds. For example, if this deque holds integers, the data pointer\n * should be a pointer to an integer. Since this data is being copied from the\n * array to the data pointer, the pointer only has to be valid when this\n * function is called.\n *\n * @param data the value to copy to\n * @param me   the deque to remove from\n *\n * @return 0       if no error\n * @return -EINVAL if invalid argument\n */\nint deque_pop_back(void *const data, deque me)\n{\n    int block_index;\n    int inner_index;\n    struct node block_item;\n    if (deque_is_empty(me)) {\n        return -EINVAL;\n    }\n    me->end_index--;\n    block_index = me->end_index / BLOCK_SIZE;\n    inner_index = me->end_index % BLOCK_SIZE;\n    block_item = me->block[block_index];\n    memcpy(data, (char *) block_item.data + inner_index * me->data_size,\n           me->data_size);\n    return 0;\n}\n\n/**\n * Sets the first value of the deque. The pointer to the data being passed in\n * should point to the data type which this deque holds. For example, if this\n * deque holds integers, the data pointer should be a pointer to an integer.\n * Since the data is being copied, the pointer only has to be valid when this\n * function is called.\n *\n * @param me   the deque to set the value of\n * @param data the data to set\n *\n * @return 0       if no error\n * @return -EINVAL if invalid argument\n */\nint deque_set_first(deque me, void *const data)\n{\n    return deque_set_at(me, 0, data);\n}\n\n/**\n * Sets the value of the deque at the specified index. The pointer to the data\n * being passed in should point to the data type which this deque holds. For\n * example, if this deque holds integers, the data pointer should be a pointer\n * to an integer. Since the data is being copied, the pointer only has to be\n * valid when this function is called.\n *\n * @param me    the deque to set the value of\n * @param index the index to set at\n * @param data  the data to set\n *\n * @return 0       if no error\n * @return -EINVAL if invalid argument\n */\nint deque_set_at(deque me, int index, void *const data)\n{\n    int block_index;\n    int inner_index;\n    struct node block_item;\n    if (index < 0 || index >= deque_size(me)) {\n        return -EINVAL;\n    }\n    index += me->start_index + 1;\n    block_index = index / BLOCK_SIZE;\n    inner_index = index % BLOCK_SIZE;\n    block_item = me->block[block_index];\n    memcpy((char *) block_item.data + inner_index * me->data_size, data,\n           me->data_size);\n    return 0;\n}\n\n/**\n * Sets the last value of the deque. The pointer to the data being passed in\n * should point to the data type which this deque holds. For example, if this\n * deque holds integers, the data pointer should be a pointer to an integer.\n * Since the data is being copied, the pointer only has to be valid when this\n * function is called.\n *\n * @param me   the deque to set the value of\n * @param data the data to set\n *\n * @return 0       if no error\n * @return -EINVAL if invalid argument\n */\nint deque_set_last(deque me, void *const data)\n{\n    return deque_set_at(me, deque_size(me) - 1, data);\n}\n\n/**\n * Gets the first value of the deque. The pointer to the data being obtained\n * should point to the data type which this deque holds. For example, if this\n * deque holds integers, the data pointer should be a pointer to an integer.\n * Since this data is being copied from the array to the data pointer, the\n * pointer only has to be valid when this function is called.\n *\n * @param data the data to set\n * @param me   the deque to set the value of\n *\n * @return 0       if no error\n * @return -EINVAL if invalid argument\n */\nint deque_get_first(void *const data, deque me)\n{\n    return deque_get_at(data, me, 0);\n}\n\n/**\n * Gets the value of the deque at the specified index. The pointer to the data\n * being obtained should point to the data type which this deque holds. For\n * example, if this deque holds integers, the data pointer should be a pointer\n * to an integer. Since this data is being copied from the array to the data\n * pointer, the pointer only has to be valid when this function is called.\n *\n * @param data  the data to set\n * @param me    the deque to set the value of\n * @param index the index to set at\n *\n * @return 0       if no error\n * @return -EINVAL if invalid argument\n */\nint deque_get_at(void *const data, deque me, int index)\n{\n    int block_index;\n    int inner_index;\n    struct node block_item;\n    if (index < 0 || index >= deque_size(me)) {\n        return -EINVAL;\n    }\n    index += me->start_index + 1;\n    block_index = index / BLOCK_SIZE;\n    inner_index = index % BLOCK_SIZE;\n    block_item = me->block[block_index];\n    memcpy(data, (char *) block_item.data + inner_index * me->data_size,\n           me->data_size);\n    return 0;\n}\n\n/**\n * Gets the last value of the deque. The pointer to the data being obtained\n * should point to the data type which this deque holds. For example, if this\n * deque holds integers, the data pointer should be a pointer to an integer.\n * Since this data is being copied from the array to the data pointer, the\n * pointer only has to be valid when this function is called.\n *\n * @param data the data to set\n * @param me   the deque to set the value of\n *\n * @return 0       if no error\n * @return -EINVAL if invalid argument\n */\nint deque_get_last(void *const data, deque me)\n{\n    return deque_get_at(data, me, deque_size(me) - 1);\n}\n\n/**\n * Clears the deque and sets it to the original state from initialization.\n *\n * @param me the deque to clear\n *\n * @return 0       if no error\n * @return -ENOMEM if out of memory\n */\nint deque_clear(deque me)\n{\n    void *temp_block_data;\n    int i;\n    struct node *block;\n    struct node *const temp_block = malloc(sizeof(struct node));\n    if (!temp_block) {\n        return -ENOMEM;\n    }\n    temp_block_data = malloc(BLOCK_SIZE * me->data_size);\n    if (!temp_block_data) {\n        free(temp_block);\n        return -ENOMEM;\n    }\n    for (i = 0; i < me->block_count; i++) {\n        const struct node block_item = me->block[i];\n        free(block_item.data);\n    }\n    free(me->block);\n    me->start_index = BLOCK_SIZE / 2;\n    me->end_index = me->start_index + 1;\n    me->block_count = 1;\n    me->block = temp_block;\n    block = me->block;\n    block->data = temp_block_data;\n    return 0;\n}\n\n/**\n * Destroys the deque. Performing further operations after calling this function\n * results in undefined behavior.\n *\n * @param me the deque to destroy\n *\n * @return NULL\n */\ndeque deque_destroy(deque me)\n{\n    int i;\n    for (i = 0; i < me->block_count; i++) {\n        const struct node block_item = me->block[i];\n        free(block_item.data);\n    }\n    free(me->block);\n    free(me);\n    return NULL;\n}\n\n\n/**************************************************************************************/\n\n\n#include <limits.h>\n#include <stdio.h>\n#include <memory.h>\n#include <stdlib.h>\n\nstruct pair {\n\tint n;\n\tint curCost;\n};\n\nstatic int minCost(int start_n, int m)\n{\n\tstruct pair pair = { .n = start_n, .curCost = 0 };\n\tdeque d = deque_init(sizeof(struct pair));\n\tdeque_push_back(d, &pair);\n\twhile (!deque_is_empty(d)) {\n\t\tdeque_pop_front(&pair, d);\n\t\tint n = pair.n;\n\t\tint curCost = pair.curCost;\n\t\tif (n > 2 * m || n < 1) {\n\t\t\tcontinue;\n\t\t}\n\t\tif (n == m) {\n\t\t\treturn curCost;\n\t\t}\n\t\tpair.curCost = curCost + 1;\n\t\tpair.n = n - 1;\n\t\tdeque_push_back(d, &pair);\n\t\tpair.n = 2 * n;\n\t\tdeque_push_back(d, &pair);\n\t}\n\treturn -12;\n}\n\nint main(void)\n{\n\tint n;\n\tint m;\n\tscanf(\"%d %d\", &n, &m);\n\tif (n >= m) {\n\t\tprintf(\"%d\\n\", n - m);\n\t\treturn 0;\n\t}\n\tint min = minCost(n, m);\n\tprintf(\"%d\\n\", min);\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0ebafd6e0c59457e1b454cb817526136", "src_uid": "861f8edd2813d6d3a5ff7193a804486f", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nstatic int arr[10001][10001];\nstatic int a,b;\nstatic int dp[10001][10001];\nint bluered(int n, int m)\n{\n        if(arr[n][m]==-1)\n                return 100001;\n        arr[n][m]=-1;\n        if(dp[n][m]!=-1)\n                return dp[n][m];\n        if(n==a && m==b){\n                dp[n][m]=1;\n                return 1;}\n\n\n        if(n==m){\n                dp[n][m]=0;\n                return 0;}\n        if(m<n){\n                dp[n][m]=n-m;\n                return n-m;}\n        int count1=1,count2=1;\n\n        count1=count1+ (bluered(n*2,m));\n        if(n>1){\n        count2=count2+(bluered(n-1,m));}\n        if(n<=1){\n                dp[n][m]=count1;\n        return count1;  }\n        if(count1<count2)\n        {dp[n][m]=count1;\n                return count1;}\n        else{\n                dp[n][m]=count2;\n                return count2;\n        }\n}\n\nint main()\n\n{\n        int i,j;\n        for(i=0;i<1001;i++)\n        {\n                for(j=0;j<1001;j++){\n                        arr[i][j]=0;\n                        dp[i][j]=-1;\n                }\n        }\n        int a,b;\n        scanf(\"%d %d\",&a,&b);\n        int count=0;\n        count+=bluered(a,b);\n        printf(\"%d\",count);\n        return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "75f6bd38fb2bfc5d4b30708dc254eb1d", "src_uid": "861f8edd2813d6d3a5ff7193a804486f", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\nint main()\n{\n\tlong  int a,n,s=0,b,n1;\n\tint rev=0;\n\tscanf(\"%ld\",&n);\n\ta=n;\n\t//b=n;\n\twhile(a!=0)\n\t{\n\t\tn=a;\n\t\tn=n%10;\n\t\tif(n>=5&&n<=9)\n\t\t{\n\t\t\tn=9-n;\n\t\t\ts=s*10+n;\n\t\t}\n\t\telse\n\t\t{\n\t\t\ts=s*10+n;\n\t\t}\n\t\ta=a/10;\n\t}\n\twhile(s!=0)\n\t{\n\t\trev=rev*10+s%10;\n\t\ts=s/10;\n\t}\n\t\n\tprintf(\"%ld\",rev);\t\n\n\t\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "74f97cc56c0eaefc9d55ab73469dfda4", "src_uid": "d5de5052b4e9bbdb5359ac6e05a18b61", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdlib.h>\n\nint main()\n{\n    int ara[100000000];\n  long long   int a,s=1,t=0,i,k=0,num;\n    scanf(\"%lld\",&a);\n    for(i=0; a!=0; i++)\n    {\n        num=a%10;\n        ara[i]=num;\n        a=a/10;\n        t++;\n    }\n    for(i=0; i<t; i++)\n    {\n        if((9-ara[i])<ara[i])\n        {\n            if(i==t-1&&ara[t-1]!=9)\n            {\n                ara[i]=9-ara[i];\n            }\n            else if (i!=t-1)\n            {\n                ara[i]=9-ara[i];\n            }\n        }\n        k=k+s*ara[i];\n        s=s*10;\n    }\n    printf(\"%lld\",k);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "97f3921fd5ce0bef235650f71088951c", "src_uid": "d5de5052b4e9bbdb5359ac6e05a18b61", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdlib.h>\n\nint main()\n{  int ara[100000000];\n   int a,s=1,t=0,i,k=0,num;\n   scanf(\"%d\",&a);\n   for(i=0;a!=0;i++){\n       num=a%10;\n       ara[i]=num;\n       a=a/10;\n       t++;\n   }\n   for(i=0;i<t;i++){\n        if(i==t-1&&ara[t-1]==9){\n            continue;\n        }\n     else if((9-ara[i])<ara[i]){\n        ara[i]=9-ara[i];\n    }\n    k=k+s*ara[i];\n    s=s*10;\n   }\n   printf(\"%d\",k);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d5eee01133a28fa98d3b54e558303936", "src_uid": "d5de5052b4e9bbdb5359ac6e05a18b61", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n#include <malloc.h>\n#include <stdbool.h>\n#include <time.h>\n#include <ctype.h>\n#define maxn 10000000 + 10\n\ntypedef long long ll;\n\nint Arr[maxn];\n\nint main()\n{\n    ll n, i, tmp, tot, cnt, _sum;\n    int tmp1;\n    while( ~scanf( \"%I64d\", &n ) )\n    {\n        tot = cnt = _sum = 0;\n        tmp = n;\n        while(tmp)\n        {\n            tot ++;\n            tmp /= 10;\n        }\n        _sum = pow( (double)10, (double)tot );\n\n        for( i = 1; i <= tot; i ++ )\n        {\n\n            tmp1 = n / ( _sum / 10 );\n\t\t\tif( i == 1 && tmp1 == 9 )\n\t\t\t{\n\t\t\t\ttmp1 = 9;\n\t\t\t}\n\t\t\telse\n\t\t\t\ttmp1 = abs( 9 - tmp1 ) < tmp1 ? abs( 9 - tmp1 ) : tmp1;\n\t\t\t//printf( \"%d\", tmp1 );\n\t\t\tArr[ cnt ++ ] = tmp1;\n        \tn = n - n / ( _sum / 10 ) * ( _sum / 10 );\n        \t_sum /= 10;\n        }\n        for( i = 0; i < cnt; i ++ )\n            printf( \"%d\", Arr[i] );\n\t\tprintf( \"\\n\" );\n\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "07172861f7a6412554848f00adb4e85e", "src_uid": "d5de5052b4e9bbdb5359ac6e05a18b61", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(void)\n{\n\t\tlong long int i = 0;\n\t\tchar c;\n\t\tint count = 0;\n\n\t\twhile ((c = getchar()) == 9){\n\t\t\t\ti = (i*10) + 9;\n\n\t\twhile(c != '\\n'){\n\t\t\t\ti *= 10;\n\t\t\t\tif (c - '0' > 4 && c != '9')\n\t\t\t\t\t\ti += 9 - (c - '0');\n\t\t\t\telse\n\t\t\t\t\t\ti += (c - '0');\n\t\t\t\tc = getchar();\n\t\t}\n\t\tprintf(\"%I64d\\n\", i);\n\t\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c170377fc0deab67ef91041de4284723", "src_uid": "d5de5052b4e9bbdb5359ac6e05a18b61", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<math.h>\nmain()\n{\n        float n,m,a;\n         int h;\n         scanf(\"%f%f%f\",n,m,a);\n       for(n>0,m>0,a>0)\n       {\n         h=ceil(n/a)*ceil(m/a);\n       printf(\"%d\",h);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2d2f5e4b5908f7c62d1ba7064fca2f12", "src_uid": "ef971874d8c4da37581336284b688517", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<iostream>\nusing namespace std;\nint main()\n{\n\tint a, b, c;\n\tcin >> a >> b >> c;\n\tlong long int ans = ((a%c == 0) ? (a / c) : (a / c + 1))*((b%c == 0) ? (b / c) : (b / c + 1));\n\tcout << ans << endl;\n\treturn 0;\n}\n   \t  \t \t\t\t\t\t\t\t\t \t\t\t \t\t\t\t\t  \t\t", "lang_cluster": "C", "compilation_error": true, "code_uid": "3c75ae9376ea944cbf9a2f1158202b71", "src_uid": "ef971874d8c4da37581336284b688517", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    double n,m,a;\n    scanf(\"%d\",&n);\n    scanf(\"%d\",&m);\n    scanf(\"%d\",&a);\n    \n    int x=n%a;\n    int y=m%a;\n    double x1,y1;\n    if(x==0){\n        x1=n/a;\n        \n    }\n    else{\n        x1=n/a+1;\n    }\n    \n    if(y==0){\n        y1=m/a;\n    }\n    else{\n        y1=m/a+1;\n    }\n    double result=x1*y1;\n    printf(\"%d\",result);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0bf524acc6ca871e532148fef900ea16", "src_uid": "ef971874d8c4da37581336284b688517", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<math.h>\nmain()\n{ \n float n,m,a;\nint h;\nscanf(\"%f%f%f\",&n,&m,&a);\nfor(n>0,m>0,a>0)\n{ \nh=ceil(n/a)*ceil(m/a);\n}\nprintf(\"%d\",h);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f7dc4da2d86c0cb131585e3b7709d7bf", "src_uid": "ef971874d8c4da37581336284b688517", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include<conio.h>\nint main ()\n{\n    int n;\n    int m;\n    int a;\n\n    scanf (\"%d %d %d\", &n, &m, &a);\n\n    long long flagsByRow;\n    \n    if (n % a == 0) {\n        flagsByRow = n / a;\n        \n    } else {\n        flagsByRow = n / a;\n        flagsByRow++;\n\n    }\n\n    long long flagsByColumn;\n    \n    if (m % a == 0) {\n        flagsByColumn = m / a;\n        \n    } else {\n        flagsByColumn = m / a;\n        flagsByColumn++;\n\n    }\n\n    cout << flagsByRow * flagsByColumn << endl;\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4c94ec0d886fcaf45c13a86d87ca6fa4", "src_uid": "ef971874d8c4da37581336284b688517", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main(){\n    int k,j,l,m,n,o,p,q;\n    int r;\n    q=0;\n    scanf(\"%d\",&n);\n    for(j=4;j<500;j++){\n        o=0;\n        p=0;\n        \n        for(r=j;r>0;){\n        k=r%10;\n        r=r/10;\n        if(k==4 || k==7){\n            m=k*pow(10,p);\n            o=o+m;\n            p++;\n            if(n%o==0){\n                printf(\"YES\");\n                q++;\n                return 0;\n            }\n        }\n            else \n            break;\n        \n        }\n    }\n    if(q==0)\n    printf(\"NO\");\n    return 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b7986223c982445ccbd3d2ac3baaf266", "src_uid": "78cf8bc7660dbd0602bf6e499bc6bb0d", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,i,a[12]={4,7,44,77,47,74,444,777,447,474,747,774};\n    scanf(\"%d\",&n);\n    if(n>0){\n        for(i=0;i<11;i++){\n            if(n==a[i] || n%a[i]==0){\n                printf(\"YES\");\n                return 0;\n            }\n        }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d7ec62a52d41ece55016683426acdf19", "src_uid": "78cf8bc7660dbd0602bf6e499bc6bb0d", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "int main() {\n    int i,sayi,luckynumber[14]={4,7,44,47,74,77,444,447,474,477,744,747,774,777};\n    scanf(\"%d\",&sayi);\n    while(i=0;i<14;i++)\n        if(sayi%luckynumber[i]==0)\n            printf(\"YES\");\n    printf(\"NO\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d5163ca6f67bc43b4c1f09179382ac79", "src_uid": "78cf8bc7660dbd0602bf6e499bc6bb0d", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,i,flag;\n    scanf(\"%d\",&n);\n    if(n%4==0||n%7==0) flag=1;\n    else{\n        if(n%47==0||n%74==0||n&44==0||n%77==0||n%444==0||n%777=0||n%474==0||n%447==0||n%744==0||n%774==0||n%477==0||n%747==0)\n            flag=1;\n        else\n            flag=0;\n    }\n    if(flag==1)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d07d89ae2e21deffe5aa3cd5aa373483", "src_uid": "78cf8bc7660dbd0602bf6e499bc6bb0d", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint islucky(int n){\n    \n    while(n!=0){\n        if(n%10==7||n%10==4){\n            i=0;\n        }\n        else\n        {\n            i=1;\n            break;\n        }\n    }\n    if(i=0)\n    return 1;\n    else\n    return 0;\n}\n\nint main(){\nunsigned int n;\nscanf(\"%d\",&n);\nint i,j;\nfor(i=1;i<=n;i++){\n    if(islucky(i)){\n        if(n%i == 0){\n        printf(\"YES\");\n        return 0;}\n        else{\n        printf(\"NO\");\n        return 0;}\n    }\n}\nif(i==n+1)\nprintf(\"NO\");\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9aac54ef7a2da5ed0c4b977fb70a4d08", "src_uid": "78cf8bc7660dbd0602bf6e499bc6bb0d", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n\nint main()\n{\n    char s [ 300 ] , r [ 300 ];\n    int i;\n    scanf ( \"%s\" , s ) ;\n    for ( i = 0 , j = 0 ; i < strlen ( s ) ; i ++ , j ++ )\n    {\n        if ( s [ i ] == '.' )\n            r [ j ] = '0' ;\n        if ( s [ i ] == '-' && s [ i + 1 ] == '.' )\n        {\n            r [ j ] = '1' ;\n            i++ ;\n        }\n        if ( s [ i ] == '-' && s [ i + 1 ] == '-' )\n        {\n            r [ j ] = '2' ;\n            i++;\n        }\n    }\n    printf ( \"%s\" , r ) ;\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9f403e811a7ee604c25c12c071f6abac", "src_uid": "46b5a1cd1bd2985f2752662b7dbb1869", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char s[200];\n    gets(s);\n    int l=strlen(s);\n    for(int i=0;i<l-1;i++)\n    {\n            if(s[i]=='.')\n            printf(\"0\");\n            else if(s[i]=='-'&&s[i+1]=='-')\n            {\n              printf(\"2\");\n              i++;\n            }\n            else if((s[i]=='-'&&s[i+1]=='.')&&(s[i+2]=='.'&&i+2=='.'))\n            {\n                 printf(\"10\");\n                 break;\n            }\n            else if(s[i]=='-'&&s[i+1]=='.')\n            {\n              printf(\"1\");\n              i++;\n            }\n    }\n    return(0);\n}\n              \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "202a0e7fca79ab8f57742c74f504cbbc", "src_uid": "46b5a1cd1bd2985f2752662b7dbb1869", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "include<stdio.h>\n#include<string.h>\nint main()\n{\n    char a[250];\n    int n,i;\n    scanf(\"%s\",&a);\n    n=strlen(a);\n    for(i=0;i<n;i++)\n    {\n        if(a[i]=='.')\n        {\n            printf(\"0\");\n        }\n        else if(a[i]=='-' && a[i+1]=='.')\n        {\n            printf(\"1\");\n        }\n        else if(a[i]=='-' && a[i+1]=='-')\n        {\n            printf(\"2\");\n        }\n        else\n        break;\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e92f0f55b872f04972a337e1b4c1c92c", "src_uid": "46b5a1cd1bd2985f2752662b7dbb1869", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n \n \n \n\nint main()\n{\n   char c[200];\n     \n    scanf(\"%s\",&c); \n    \n    for(int i=0; i<75; i++){\n        \n        if((c[i]== '-')&& (c[i+1]== '-')){\n            printf(\"2\"); \n             \n          i++;\n        }\n        \n         else if((c[i]== '-')&& (c[i+1]== '.')){\n            printf(\"1\"); \n            \n          i++;\n        } \n        else if( c[i]== '.'){\n            printf(\"0\");\n        else \n        break;\n             \n        }  \n    } \n    \n   return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cec16d4808d9da90e7c8e6e5a33f25f7", "src_uid": "46b5a1cd1bd2985f2752662b7dbb1869", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main(){\t\n\tchar a[1000]={};\t\n\tscanf(\"%s\", arr);\n\t\n\tint n,i;\n\tn=strlen(a);\t\n\t\n\tfor(i=0;i<n-1;i++)\n\t{\n\t\tif(a[i]!='.' && a[i]!='-')\n\t\t{\n\t\t\tprintf(\"wrong input!!\");\n\t\t}\n\t\tif(a[i]=='.')\n\t\t\tprintf(\"0\");\n\t\tif(a[i]=='-' && a[i+1]=='.')\n\t\t{\n\t\t\tprintf(\"1\");\n\t\t\ti++;\n\t\t}\n\t\tif(a[i]=='-' && a[i+1]=='-')\n\t\t{\n\t\t\tprintf(\"2\");\n\t\t\ti++;\n\t\t}\n\t}\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "386dea8f3f70ae1048ff5f3d90640ba9", "src_uid": "46b5a1cd1bd2985f2752662b7dbb1869", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<Stdio.h>\n#include<string.h>\nmain()\n{\n\tint max,t,p,k1,temp,w=0,l,i,j,k;\n\tchar s[30];\n\tint a[30]={0},b[30]={0};\n\tscanf(\"%d\",&l);l++;l--;\n\tfor(i=0;i<=l;i++)\n\t{\n\t\tscanf(\"%c\",&s[i]);\n\t}\n\ts[l+1]='\\0';\n\tfor(t=1;t<=l-1;t++)\n\t{\n\t\tfor(p=1;p<=l-1;p++)\n\t\t{\n\t\t\tif (s[t]==s[p] && s[t+1]==s[p+1])\n\t\t\t{\n\t\t\t\ta[t]++;\n\t\t\t}\n\t\t}\n\t}\n\t\n\tfor(i=1;i<=l-1;i++)\n\tb[i]=a[i];\n\tfor(t=1;t<=l-1;t++)\n\t{\n\t\tif (b[t]>b[t+1])\n\t\t{\n\t\t\ttemp=b[t];\n\t\t\tb[t]=b[t+1];\n\t\t\tb[t+1]=temp;\n\t\t}\n\t}\n\tmax=b[l];\n\tfor(t=1;t<=l-1;t++)\n\t{\n\t\tif (a[t]==max)\n\t\t{\n\t\t\tk=t;\n\t\t\tif (w==0)\n\t\t\t{\n\t\t\tk1=k};\n\t\t\tw++;\n\t\t}\n\t}\n\tprintf(\"%c%c\",s[k1],s[k1+1]);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d28967b260da1ce4f7b23a3ea19d54dd", "src_uid": "e78005d4be93dbaa518f3b40cca84ab1", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h\nint main()\n{\n    int n,count=0,max=0,maxn,i,j; \n    scanf(\"%d\",&n);\n    char s[n+1];\n    scanf(\"%s\",s); \n    for(i=1;i<n;i++){\n    count=0; \n    for(j=i;j<n;j++)\n        if(s[i-1]==s[j-1]&&s[i]==s[j])\n        count++;\n        if(count>max){\n            max=count;\n            maxn =i ; }\n    }\n    printf(\"%c%c\",s[maxn-1],s[maxn]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "294d231adf25a4220574d4b8272e6911", "src_uid": "e78005d4be93dbaa518f3b40cca84ab1", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<cstdio>  \n#include<iostream>  \n#include<string>  \n#include<cstring>  \n#include<cmath>  \nusing namespace std;  \n  \n#define N   100  \n  \nint main()   \n{  \n    static char cc[N];  \n    static int kk[676];  \n    int n, i, max, amax;  \n    scanf(\"%d\", &n);  \n    scanf(\"%s\", cc);  \n    max = 0;  \n    amax = 0;  \n    for (i = 1; i < n; i++)   \n    {  \n        int a = (cc[i - 1] - 'A') * 26 + (cc[i] - 'A');  \n        if (max < ++kk[a])  \n        {  \n            max = kk[a];  \n            amax = a;  \n        }  \n    }  \n    printf(\"%c%c\\n\", amax / 26 + 'A', amax % 26 + 'A');  \n    return 0;  \n}  ", "lang_cluster": "C", "compilation_error": true, "code_uid": "30c846bf7563326207d94ba11dea0cf5", "src_uid": "e78005d4be93dbaa518f3b40cca84ab1", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n\nint main() {\n    char s[101],ans[3];\n    int n,max = 0;\n    scanf(\"%d\", &n);\n    scanf(\"%s\", s);\n    ans[2] = '\\0'\n    for(int j = 0; j <= n ; j++) {\n        char a = s[j], b = s[j+1];\n        int k=0;\n        for (int i = 0; i <= n; ++i) {\n            if (s[i] == a && s[i + 1] == b) k++;\n\n\n        }\n        if (k > max){\n            ans[0] =  a;\n            ans[1] = b;\n            max = k;\n        }\n\n    }\n\n    printf(\"%s\\n\", ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9587c8a592c938fde5119ce10f5ddcda", "src_uid": "e78005d4be93dbaa518f3b40cca84ab1", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main()\n{\n\tint i, j, n, num = 0, max = 0;\n\tchar string[100], subString[100][2], maxString[2];\n\tscanf(\"%d\", &n);\n\tgets(\"%s\", string);\n\tfor (i = 0; i < n; i++) {\n\t\tsubString[i][0] = string[i];\n\t\tsubString[i][1] = string[i+1];\n\t}\n\tfor (i = 0; i < n; i++)\n\t{\n\t\tfor (j = 0; j < n; j++) {\n\t\t\tif (j != i) {\n\t\t\t\tif (strcmp(subString[i], subString[j]) == 0) {\n\t\t\t\t\tnum++;\t\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (num > max) {\n\t\t\tmax = num;\n\t\t\tstrcpy(maxString, subString[i]);\n\t\t}\n\t}\n\t\n\tprintf(\"%s\\n\", maxString);\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fff3788016148cca64ad7a1e5a0f917c", "src_uid": "e78005d4be93dbaa518f3b40cca84ab1", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\nint main()\n{\n    int m, n;\n    long long int r, x, y, x1, y1, z;\n    double s;\n    scanf(\"%I64d %I64d %I64d %I64d %I64d\", &r, &x, &y, &x1, &y1);\n    s= sqrt( abs(x1-x)*abs(x1-x) + abs(y1-y)*abs(y1-y) );\n    n= s/(2*r);\n    if(n*2*r == s) \n    else n++\n    printf(\"%d\",n);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2f63e064911d1faac060f9a19b4c4cbf", "src_uid": "698da80c7d24252b57cca4e4f0ca7031", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\nlong long int r,x,y,x1,y1,res;\n scanf(\"%I64d %I64d %I64d %I64d %I64d\",&r,&x,&y,&x1,&y1);\n res=ceil(((llabs(y-y1)+llabs(x-x1))/(2*r)));\nif printf(\"%I64d\",res);\n\n\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8c19248a035d19f842601c3c1685f312", "src_uid": "698da80c7d24252b57cca4e4f0ca7031", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\n/* run this program using the console pauser or add your own getch, system(\"pause\") or input loop */\n\nint main(int argc, char *argv[]) \n{\n\tlong long r,x,y,x1,y1,i;\n\tint s=0;\n\tscanf(\"%lld%lld%lld%lld%lld\",&r,&x,&y,&x1,&y1);\n\ti=(long long)(pow((double)(x1-x),2.0)+pow((double)(y1-y),2.0));\n    i=(long long)(sqrt((double)i));\n    if(x == x1 && y == y1)\n    { \n\t\tprintf(\"0\");\n    }\n\t\n\telse if (x >= x1 && y >= y1)\n\t{\n\t\t\ti=i/(2*r);\n\t\t \tprintf(\"%d\",i+1);\n\t}\n\telse if(x <= x1 && y <= y1)\n\t\t{\n\t\t  \n           if(x == y && x1 == y1)\n\t        \t{\n\t\t\t\t\n\t\t\t   \t\twhile(i >= r)\n\t\t\t\t\t{\n\t\t\t\t\n\t\t\t\t\tr=r+r;\n\t\t\t\t\ts++;\n\t\t\t\t\t}\n\t\t\t\tprintf(\"%d\\n\",s);\n\t\t\t\t}\n          \n\t\t\t\telse if((y1 > y && y1%r==0)||(x1 > x && x1%r==0))\n\t\t\t\t{  \n\t\t\t\twhile (i > r)\n\t\t\t\t{\n\t\t\t\tr=r+r;\n\t\t\t\t s++;\n\t\t\t\t}\n\t\t\t\tprintf(\"%d\",s);\t\n\t\t\t\t}\n\t\t\t\n\t\t\t\telse if(i > r)\n\t\t\t\t{\n\t\t\t\t\n\t\t\t   \t\twhile(i >= r)\n\t\t\t\t\t{\n\t\t\t\t\n\t\t\t\t\tr=r+r;\n\t\t\t\t\ts++;\n\t\t\t\t\t}\n\t\t\t\tprintf(\"%d\\n\",s);\n\t\t\t\t}\n\t\t\t\t\telse if((x == x1 && y1 >= y)||(y == y1 && x1 >= x))\n\t\t\t\t{\n\t\t\t\t\n\t\t\t\twhile(i >= r)\n\t\t\t\t\t{\n\t\t\t\t\n\t\t\t\t\tr=r+r;\n\t\t\t\t\ts++;\n\t\t\t\t\t}\n\t\t\t\tprintf(\"%d\\n\",s+1)\n\t\t\t\t}\n\t\t    \t\n\t\t\telse \n\t\t\t{\n\t\t\t\twhile ( i <= r)\n\t\t\t\t{\n\t\t\t\t   r=r-r;\n\t\t\t\t \ts++;\n\t\t\t\t}\n\t\t\t\tprintf(\"%d\",s);\n\t\t\t}\n\t\t\n\t\t}\n\t\telse if ((x >= x1 && y <= y1) || (x <= x1 && y >= y1))\n\t\t{\n\t\t \ti=i/(2*r);\n\t\t \tprintf(\"%d\",i+1);\n\t\t}\n\t\n\t\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "cfe2baa02d20d1ea43f5009c91a15a25", "src_uid": "698da80c7d24252b57cca4e4f0ca7031", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint main(){\n    long int r, x1, y1, x2, y2;\n    scanf(\"%ld %ld %ld %ld %ld\", &r, &x1, &y1, &x2, &y2);\n    printf(\"%ld\", ceil(sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2))/(2*r)))\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b97e2074530b3ec461ab0b3873c08787", "src_uid": "698da80c7d24252b57cca4e4f0ca7031", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\nint main()\n{\n    float x1,y1,x2,y2,r;\n    float Dis;\n    int times;\n    float out;\n    scanf(\"%f %f %f %f %f\",&r,&x1,&y1,&x2,&y2);\n    Dis = sqrt(pow(x1-x2,2) + pow(y1-y2,2));\n    out = Dis/2r;\n    if ((int)out == (float)out){\n        times = out ;\n    }\n    else\n        times = out+1;\n\n    printf(\"%d\",times);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "253cd4ae9e4807af1c64a4b08552cd21", "src_uid": "698da80c7d24252b57cca4e4f0ca7031", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint a[35], n, m, arr1[1<<18], arr2[1<<18];\nint idx1, idx2;\nint max(int a, int b){if (a<b) return b; return a;}\nint mycmp(const void* a, const void* b) { return *(int *)a - *(int *)b;}\nvoid dfs(int i, int sum, int type){\n  if (type && i==n) {arr2[idx2++] = sum; return;}\n  else if (!type && i==n/2) {arr1[idx1++]= sum; return ; }\n\n  dfs(i+1, (sum+a[i])%m , type);\n  dfs(i+1, sum, type);\n}\nint main(){\n  scanf(\"%d %d\", &n, &m);\n  for (int i=0; i<n; i++){\n    scanf(\"%d\", &a[i]);\n    a[i]%=m;\n  }\n  qsort (a, n, sizeof(int), mycmp);\n\n  dfs(0, 0, 0);\n  dfs(n/2, 0, 1);\n  arr1[idx1++]=0;\n  arr2[idx2++]=0;\n\n  for (int i=0; i<idx1; i++) arr1[i]%=m;\n  for (int i=0; i<idx2; i++) arr2[i]%=m;\n\n  qsort(arr1, idx1, sizeof(int), mycmp);\n  qsort(arr2, idx2, sizeof(int), mycmp);\n\n  int l=0, r=0;\n  while (arr1[l]==0) l++;\n  while (arr2[r]==0) r++;\n\n  int ans=0;\n  for (int i=l; i<idx1; i++){\n    for (int j=r; j<idx2; j++){\n      int tmp= (arr1[i]+arr2[j])%m;\n      if (tmp > ans) ans=tmp;\n      while(arr2[j]==arr2[j+1]) j++;\n    }\n    while(arr1[i]==arr1[i+1]) i++;\n  }\n\n  printf(\"%d\\n\", ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b95df5e494d41ef6f40645be7c133eb9", "src_uid": "d3a8a3e69a55936ee33aedd66e5b7f4a", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint a[35], n, m, arr1[1<<18], arr2[1<<18];\nint idx1, idx2;\nint max(int a, int b){if (a<b) return b; return a;}\nint mycmp(const void* a, const void* b) { return *(int *)a - *(int *)b;}\nvoid dfs(int i, int sum, int type){\n  if (type && i==n) {arr2[idx2++] = sum; return;}\n  else if (!type && i==n/2) {arr1[idx1++]= sum; return ; }\n\n  dfs(i+1, (sum+a[i])%m , type);\n  dfs(i+1, sum, type);\n}\nint main(){\n  scanf(\"%d %d\", &n, &m);\n  for (int i=0; i<n; i++){\n    scanf(\"%d\", &a[i]);\n    a[i]%=m;\n  }\n  qsort (a, n, sizeof(int), mycmp);\n\n  dfs(0, 0, 0);\n  dfs(n/2, 0, 1);\n  arr1[idx1++]=0;\n  arr2[idx2++]=0;\n\n  for (int i=0; i<idx1; i++) arr1[i]%=m;\n  for (int i=0; i<idx2; i++) arr2[i]%=m;\n\n  qsort(arr1, idx1, sizeof(int), mycmp);\n  qsort(arr2, idx2, sizeof(int), mycmp);\n\n  int ans=0;\n  for (int i=0; i<idx1; i++){\n    for (int j=0; j<idx2; j++){\n      int tmp= (arr1[i]+arr2[j])%m;\n      if (tmp > ans) ans=tmp;\n      while(arr2[j]==arr2[j+1]) j++;\n    }\n    while(arr1[i]==arr1[i+1]) i++;\n  }\n\n  printf(\"%d\\n\", ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "913005fd078a91911a4f396daf152ec7", "src_uid": "d3a8a3e69a55936ee33aedd66e5b7f4a", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <ctype.h>\n#define LL long long\n#define uLL unsigned long long\nlong ms[2000000];\nvoid print(LL *a,long size) {long i;for (i=1;i<size;i++) {printf(\"%lld \",a[i]);}printf(\"%lld\\n\",a[i]);}\nvoid mergesort(LL*ds,long size)\n{\n\tlong i,j,k,s,b,e;\n\tfor (k=1;k<=size;k=k<<1)\n\t{\n\t\tfor (i=1;i+k<=size;i+=k<<1)\n\t\t{\n\t\t\ts=i;b=i+k;e=b+k-1;\n\t\t\tif (e>size) {e=size;}\n\t\t\tfor (j=1;(s<i+k)&&(b<=e);j++)\n\t\t\t{\n\t\t\t\tif (ds[s]<=ds[b])\n\t\t\t\t{\n\t\t\t\t\tms[j]=ds[s++];\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tms[j]=ds[b++];\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor (b=i+k-1;b>=s;b--)\n\t\t\t{\n\t\t\t\tds[e--]=ds[b];\n\t\t\t}\n\t\t\tfor (b=1;b<j;b++)\n\t\t\t{\n\t\t\t\tds[i+b-1]=ms[b];\n\t\t\t}\n\t\t}\n\t}\n}\t\nlong gray(long a)\n{\n\treturn ((a<<1)^a)>>1;\n}\ninline uLL bsf64(uLL a)\n{\n\tasm(\"bsfq %0,%0\":\"+r\"(a));\n\treturn a; \n}\ninline uLL bsr64(uLL a)\n{\n\tasm(\"bsrq %0,%0\":\"+r\"(a));\n\treturn a; \n}\ninline LL max(LL a,LL b) {if (b>a) {a=b;}return a;}\ninline LL min(LL a,LL b) {if (a>b) {a=b;}return a;}\nLL ans1[1000000],ans2[1000000];\nlong num[1000],num2[1000];\nint main()\n{\n//\tfreopen(\"in.in\",\"r\",stdin);\n\tlong i,j,k,a,b,c,l,p,q,baka,r,m,n,mid;\n\tscanf(\"%ld %ld\\n\",&n,&m);\n//\tprintf(\"%ld %ld\\n\",n,m);\n\tfor (i=1;i<=n;i++)\n\t{\n\t\tscanf(\"%ld\",&num[i]);\n\t}\t\n\tif (n>10) {q=n>>1;} {q=n;}\n\t*ans1=(LL)1<<q;ans1[1]=0;\n\tfor (i=1;i<=q;i++) {num2[i]=num[i];}\n\tfor (i=1;i<=*ans1;i++)\n\t{\n\t\ta=gray(i);b=gray(i-1);\n\t\tk=a^b;\n\t\tif (a&k) {ans1[i]=ans1[i-1]+num2[bsr64(k)];}\n\t\tif (b&k) {ans1[i]=ans1[i-1]+m-num2[bsr64(k)];}\n\t\tans1[i]=ans1[i]%m;\n\t}\n//\tprint(ans1,*ans1);\n\t//////////////////\n\tq=n-q;\n\tfor (i=1;i<=q;i++) {num2[i]=num[n-i+1];}\n\t*ans2=(LL)1<<q;ans2[1]=0;\n\tfor (i=1;i<=*ans2;i++)\n\t{\n\t\ta=gray(i);b=gray(i-1);\n\t\tk=a^b;\n\t\tif (a&k) {ans2[i]=ans2[i-1]+num2[bsr64(k)];}\n\t\t\tif (b&k) {ans2[i]=ans2[i-1]+m-num2[bsr64(k)];}\n\t\tans2[i]=ans2[i]%m;\n\t}\t\t\n\tmergesort(ans1,*ans1);\n\tbaka=0;\n\tfor (i=1;i<=*ans2;i++)\n\t{\n\t\tl=1;r=*ans1;a=m-1-ans2[i];\n\t\twhile (l<=r)\n\t\t{\n\t\t\tmid=(l+r)>>1;\n\t\t\tif (ans1[mid]<a)\n\t\t\t{\n\t\t\t\tl=mid+1;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tr=mid-1;\n\t\t\t}\n\t\t}\n\t\tif (l<=*ans1) {b=(ans2[i]+ans1[l])%m;baka=max(b,baka);}\n\t\tif (r>0) {b=(ans2[i]+ans1[r])%m;baka=max(b,baka);}\n\t\tl=1;r=*ans1;a=2*m-1-ans2[i];\n\t\twhile (l<=r)\n\t\t{\n\t\t\tmid=(l+r)>>1;\n\t\t\tif (ans1[mid]<a)\n\t\t\t{\n\t\t\t\tl=mid+1;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tr=mid-1;\n\t\t\t}\n\t\t}\n\t\tif (l<=*ans1) {b=(ans2[i]+ans1[l])%m;baka=max(b,baka);}\n\t\tif (r>0) {b=(ans2[i]+ans1[r])%m;baka=max(b,baka);}\t\t\n\t}\n\tprintf(\"%lld\\n\",baka);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "06004f30cfee14c485d6d4de967d9679", "src_uid": "d3a8a3e69a55936ee33aedd66e5b7f4a", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <ctype.h>\n#define LL long long\n#define uLL unsigned long long\nlong ms[2000000];\nvoid print(LL *a,long size) {long i;for (i=1;i<size;i++) {printf(\"%lld \",a[i]);}printf(\"%lld\\n\",a[i]);}\nvoid mergesort(LL*ds,long size)\n{\n\tlong i,j,k,s,b,e;\n\tfor (k=1;k<=size;k=k<<1)\n\t{\n\t\tfor (i=1;i+k<=size;i+=k<<1)\n\t\t{\n\t\t\ts=i;b=i+k;e=b+k-1;\n\t\t\tif (e>size) {e=size;}\n\t\t\tfor (j=1;(s<i+k)&&(b<=e);j++)\n\t\t\t{\n\t\t\t\tif (ds[s]<=ds[b])\n\t\t\t\t{\n\t\t\t\t\tms[j]=ds[s++];\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tms[j]=ds[b++];\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor (b=i+k-1;b>=s;b--)\n\t\t\t{\n\t\t\t\tds[e--]=ds[b];\n\t\t\t}\n\t\t\tfor (b=1;b<j;b++)\n\t\t\t{\n\t\t\t\tds[i+b-1]=ms[b];\n\t\t\t}\n\t\t}\n\t}\n}\t\nlong gray(long a)\n{\n\treturn ((a<<1)^a)>>1;\n}\ninline uLL bsf64(uLL a)\n{\n\tasm(\"bsfl %0,%0\":\"+r\"(a));\n\treturn a; \n}\ninline uLL bsr64(uLL a)\n{\n\tasm(\"bsrl %0,%0\":\"+r\"(a));\n\treturn a; \n}\ninline LL max(LL a,LL b) {if (b>a) {a=b;}return a;}\ninline LL min(LL a,LL b) {if (a>b) {a=b;}return a;}\nLL ans1[1000000],ans2[1000000];\nlong num[1000],num2[1000];\nint main()\n{\n//\tfreopen(\"in.in\",\"r\",stdin);\n\tlong i,j,k,a,b,c,l,p,q,baka,r,m,n,mid;\n\tscanf(\"%ld %ld\\n\",&n,&m);\n//\tprintf(\"%ld %ld\\n\",n,m);\n\tfor (i=1;i<=n;i++)\n\t{\n\t\tscanf(\"%ld\",&num[i]);\n\t}\t\n\tif (n>10) {q=n>>1;} {q=n;}\n\t*ans1=(LL)1<<q;ans1[1]=0;\n\tfor (i=1;i<=q;i++) {num2[i]=num[i];}\n\tfor (i=1;i<=*ans1;i++)\n\t{\n\t\ta=gray(i);b=gray(i-1);\n\t\tk=a^b;\n\t\tif (a&k) {ans1[i]=ans1[i-1]+num2[bsr64(k)];}\n\t\tif (b&k) {ans1[i]=ans1[i-1]+m-num2[bsr64(k)];}\n\t\tans1[i]=ans1[i]%m;\n\t}\n//\tprint(ans1,*ans1);\n\t//////////////////\n\tq=n-q;\n\tfor (i=1;i<=q;i++) {num2[i]=num[n-i+1];}\n\t*ans2=(LL)1<<q;ans2[1]=0;\n\tfor (i=1;i<=*ans2;i++)\n\t{\n\t\ta=gray(i);b=gray(i-1);\n\t\tk=a^b;\n\t\tif (a&k) {ans2[i]=ans2[i-1]+num2[bsr64(k)];}\n\t\t\tif (b&k) {ans2[i]=ans2[i-1]+m-num2[bsr64(k)];}\n\t\tans2[i]=ans2[i]%m;\n\t}\t\t\n\tmergesort(ans1,*ans1);\n\tbaka=0;\n\tfor (i=1;i<=*ans2;i++)\n\t{\n\t\tl=1;r=*ans1;a=m-1-ans2[i];\n\t\twhile (l<=r)\n\t\t{\n\t\t\tmid=(l+r)>>1;\n\t\t\tif (ans1[mid]<a)\n\t\t\t{\n\t\t\t\tl=mid+1;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tr=mid-1;\n\t\t\t}\n\t\t}\n\t\tif (l<=*ans1) {b=(ans2[i]+ans1[l])%m;baka=max(b,baka);}\n\t\tif (r>0) {b=(ans2[i]+ans1[r])%m;baka=max(b,baka);}\n\t\tl=1;r=*ans1;a=2*m-1-ans2[i];\n\t\twhile (l<=r)\n\t\t{\n\t\t\tmid=(l+r)>>1;\n\t\t\tif (ans1[mid]<a)\n\t\t\t{\n\t\t\t\tl=mid+1;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tr=mid-1;\n\t\t\t}\n\t\t}\n\t\tif (l<=*ans1) {b=(ans2[i]+ans1[l])%m;baka=max(b,baka);}\n\t\tif (r>0) {b=(ans2[i]+ans1[r])%m;baka=max(b,baka);}\t\t\n\t}\n\tprintf(\"%lld\\n\",baka);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "46befdbdb4036649fa2be0c469f998aa", "src_uid": "d3a8a3e69a55936ee33aedd66e5b7f4a", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint a[35], n, m, arr1[1<<20], arr2[1<<20];\nint idx1, idx2;\nint max(int a, int b){if (a<b) return b; return a;}\nint mycmp(const void* a, const void* b) { return *(int *)a - *(int *)b;}\nvoid dfs(int i, int sum, int type){\n  if (type && i==n) {arr2[idx2++] = sum; return;}\n  else if (!type && i==n/2) {arr1[idx1++]= sum; return ; }\n\n  dfs(i+1, (sum+a[i])%m , type);\n  dfs(i+1, sum, type);\n}\nint main(){\n  scanf(\"%d %d\", &n, &m);\n  for (int i=0; i<n; i++){\n    scanf(\"%d\", &a[i]);\n    a[i]%=m;\n  }\n  qsort (a, n, sizeof(int), mycmp);\n\n  dfs(0, 0, 0);\n  dfs(n/2, 0, 1);\n  arr1[idx1++]=0;\n  arr2[idx2++]=0;\n\n  for (int i=0; i<idx1; i++) arr1[i]%=m;\n  for (int i=0; i<idx2; i++) arr2[i]%=m;\n\n  qsort(arr1, idx1, sizeof(int), mycmp);\n  qsort(arr2, idx2, sizeof(int), mycmp);\n\n  int ans=0;\n  for (int i=0; i<idx1; i++){\n    for (int j=0; j<idx2; j++){\n      int tmp= (arr1[i]+arr2[j])%m;\n      if (tmp > ans) ans=tmp;\n      while(j<idx2-1 && arr2[j]==arr2[j+1]) j++;\n    }\n    while( i<idx1-1 && arr1[i]==arr1[i+1]) i++;\n  }\n\n  printf(\"%d\\n\", ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "05feb4291d6a53ed254670f6d43758c3", "src_uid": "d3a8a3e69a55936ee33aedd66e5b7f4a", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include<string.h>\n\n#define si(a) scanf(\"%d\",&a);\n#define sl(a) scanf(\"%lld\",&a);\n#define ss(a) gets(a);\n#define rep(i,start,n) for(i=start;i<n;i++)\n#define debugl(a) printf(\"%lld\\n\",a);\n#define debugi(a) printf(\"%d\\n\",a);\n\n\nint main()\n{\n    long long int t;\n    sl(t);\n    if(n%2==0)printf(\"%lld\",(n/2) -1);    \n    else if(n%2==1)printf(\"%lld\",(n/2));\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "786accfdc2550d8623dd15409d3982bc", "src_uid": "dfe9446431325c73e88b58ba204d0e47", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "include<stdio.h>\n\nint main()\n{\n    int n,a;\n    scanf(\"%d\",&n);\n    if(n%2==0)\n    {\n        a=(n-2)/2;\n    }\n    else\n    {\n        a=(n-1)/2;\n    }\n    printf(\"%d\",a);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "95612ea60fad4bcc08cf6f809381df1a", "src_uid": "dfe9446431325c73e88b58ba204d0e47", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    int n;\n    cin>>n;\n    cout<<(n-1)/2;<<endl;\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "53c8f3a1b03d3a9f2d5ab61c7c65c353", "src_uid": "dfe9446431325c73e88b58ba204d0e47", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main\n{ long int n,m;\n  scanf(\"%d\",&n)\n  if(n%2=0)\n    m=(n/2)-1;\n  else\n    m=n/2;\n  \n  printf(\"%ld\",m);\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "346d6711fb1aed8a467d537addf88fdd", "src_uid": "dfe9446431325c73e88b58ba204d0e47", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint n;\nscanf(\"%d\",&n);\nif(n%2==0)\nprintf(\"%d\",n/2-1);\nelse\nprintf(\"%d\",(n-1)/2);\nreturn 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "4f057cc947f2578581fe6f08a01e79da", "src_uid": "dfe9446431325c73e88b58ba204d0e47", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "/*     http://codeforces.com/problemset/problem/17/A       */\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\ninline int get_int()\n{\n\tint n=0;\n\tchar c=0;\n\twhile(c<33)\n\t\tc=getchar_unlocked();\n\twhile(c>='0'&&c<='9')\n\t{\n\t\tn=(n<<3)+(n<<1)+(c-'0');\n\t\tc=getchar_unlocked();\n\t}\n\treturn n;\n}\nint main(int argc, char const *argv[])\n{\n\n\tint primes[180] = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997};\n\tint n,k,kt=0,i,j;\n\tn=get_int();\n\tk=get_int();\n\tfor (i = 2; primes[i]<n; ++i)\n\t\tfor (j = 3; j < i; ++j)\n\t\t\tif (primes[i]==primes[j]+primes[j-1]+1)\n\t\t\t\tkt++;\n\tif (kt<k)\n\t\tprintf(\"NO\\n\");\n\telse\n\t\tprintf(\"YES\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "47f66165cf075d1fce441d351454d866", "src_uid": "afd2b818ed3e2a931da9d682f6ad660d", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint PN;\nint prime[500];\nint sp[500];\nint ptest(int);\nint main(){\n    int n,k;\n    int i;\n    int cnt=0;\n    scanf(\"%d%d\",&n,&k);\n    prime[p++]=2;\n    for(i=3;i<=n;i+=2){\n        if(ptest(i)) prime[p++]=i;\n    }\n    PN=p;\n    for(i=0;i<PN-1;i++){\n        sp[i]=prime[i]+prime[i+1];\n    }\n    i=0;\n    while(sp[i++]<=n-1 && i<PN) cnt++;\n    if(cnt>=k) printf(\"YES\");\n    else printf(\"NO\");\n    return 0; \n}\n\nint ptest(int n){\n    int i;\n    for(i=2;i<=sqrt(n);i++){\n        if(n%i==0) return 0;\n    }\n    return 1;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "29c3e9afe05c133b277991c358245263", "src_uid": "afd2b818ed3e2a931da9d682f6ad660d", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint prime_arr(int *arr)\n{\n  int i,j,s;\n  for(i=2;i<1000;i++)\n  {\n    s=sqrt(i);\n    for(j=2;j<=s;j++)\n      if(i%j==0)\n        break;\n    if(j>s)\n      arr[c++]=i;\n  }\n  return c;\n}\nint main()\n{\n  int i,j,n,k,p;\n  int primes[1000];\n  p=prime_arr(primes);\n  scanf(\"%d %d\",&n,&k);\n  for(i=5;i<=n;i++)\n  {\n    for(j=2;j<p;j++)\n      if(arr[i]==arr[j]+arr[j-1]+1)\n        k--;\n    if(!k)\n      break; \n  }\n  if(!k)\n    printf(\"YES\");\n  else\n    printf(\"NO\");\n  return 0;    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "20df13f0a0353fc90081c5426675075f", "src_uid": "afd2b818ed3e2a931da9d682f6ad660d", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <bits/stdc++.h> \n#include<iostream>\nusing namespace std; \n  \nint SieveOfEratosthenes(int n) \n{ \n    int a[1000],k=0,count=0;\n   \n    bool prime[n+1]; \n    memset(prime, true, sizeof(prime)); \n  \n    for (int p=2; p*p<=n; p++) \n    { \n        // If prime[p] is not changed, then it is a prime \n        if (prime[p] == true) \n        { \n         \n            for (int i=p*p; i<=n; i += p) \n                prime[i] = false; \n        } \n    } \n  \n    // Print all prime numbers \n    for (int p=2; p<=n; p++){ \n       if (prime[p]) {\n       a[k]=p;\n        k++;}\n    }\n        for(int i=0;i<k-1;i++)\n        {\n           \n           for(int j=0;j<k;j++)\n          {   \n            if(a[i]+a[i+1]+1==a[j])\n            count++;\n           }\n        }    \n\n    \n  \n    return count;\n    \n}\n  \n// Driver Program to test above function \nint main() \n{ \n    int n ,m;\n    cin>>n>>m;\n   \n if(SieveOfEratosthenes(n)>=m)\n cout<<\"YES\";\n else\n cout<<\"NO\";\n  \n    return 0; \n} ", "lang_cluster": "C", "compilation_error": true, "code_uid": "c53d84f96a815c9158d9584a7abc3e38", "src_uid": "afd2b818ed3e2a931da9d682f6ad660d", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint n;\nint k;\nint count;\nint prime[1000];\n\nint isPrime(int x)\n{\n    int i = 0;\n    for (i = 2; i < (int)sqrt(x); i++)\n        if (x % i == 0)\n            return 0;\n    return 1;\n}\n\nvoid buildPrime()\n{\n    for (int i = 2; i <= 1000; i++)\n        if (isPrime(i))\n        {\n            prime[count] = i;\n            ++count;\n        }\n}\n\nint main(int argc, const char * argv[]) {\n    \n    count = 0;\n    \n    scanf(\"%d %d\", &n, &k);\n    \n    buildPrime();\n    \n    int i  = 0;\n    int w = 0;\n    int sum = 0;\n    \n    for (i = 0; i < count -1; i++)\n    {\n        sum = prime[i] + prime[i+1] + 1;\n        if (sum > n)\n            break;\n        else\n            if (isPrime(sum))\n                ++w;\n    }\n    \n    if (w >= k)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7a50420d24d17e8db21baeef6785ac34", "src_uid": "afd2b818ed3e2a931da9d682f6ad660d", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<stdio.h>\n\nusing namespace std;\nint hh, mm, a, p;\nchar sim;\n\nint main()\n{\n\tscanf(\"%d:%d %d\", &hh, &mm, &a);\n\t\n\tp = hh * 60 + mm + a;\n\tmm = p % 60;\n\thh = p / 60;\n\tprintf(\"%02d:%02d\", hh, mm);\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "17634ff9fb9e00a63a6e388f4890573a", "src_uid": "20c2d9da12d6b88f300977d74287a15d", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n\nusing namespace std;\nint hh, mm, a, k, l;\nchar c;\nint main(){\n\tcout << \"Input time hh:mm \" << endl;\n\tcin >> hh >> c >> mm;\n\tcout << \"Input time + \" << endl;\n\tcin >> a;\n\tk = hh * 60 + mm + a;\n\tmm = k % 60;\n\thh = k / 60;\n\tif (hh > 23) {\n\t\thh = hh % 24; \n\t}\n\tcout << \"Time \" << endl;\n\tif ((hh < 10)&(mm < 10)){\n\t\tcout << \"0\" << hh << c << \"0\" << mm;\n\t\treturn 0;\n\t}\n\tif((hh < 10)&(mm >= 10)){\n\t\tcout << \"0\" << hh << c << mm;\n\t\treturn 0;\t\t\n\t}\n\tif((hh >= 10)&(mm < 10)){\n\t\tcout << hh << c << \"0\" << mm;\n\t\treturn 0;\t\t\n\t}\n\tcout << hh << c << mm;\t\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1ad45ebc2de36f5e963465645710cabd", "src_uid": "20c2d9da12d6b88f300977d74287a15d", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n\nusing namespace std;\nint hh, mm, a, k, l;\nchar c;\nint main(){\n\tcout << \"Input time hh:mm \" << endl;\n\tcin >> hh >> c >> mm;\n\tcout << \"Input time + \" << endl;\n\tcin >> a;\n\tk = hh * 60 + mm + a;\n\tmm = k % 60;\n\thh = k / 60;\n\tif (hh > 23) {\n\t\thh = hh % 24; \n\t}\n\tcout << \"Time \" << endl;\n\tif ((hh < 10)&(mm < 10)){\n\t\tcout << \"0\" << hh << c << \"0\" << mm;\n\t\treturn 0;\n\t}\n\tif((hh < 10)&(mm >= 10)){\n\t\tcout << \"0\" << hh << c << mm;\n\t\treturn 0;\t\t\n\t}\n\tif((hh >= 10)&(mm < 10)){\n\t\tcout << hh << c << \"0\" << mm;\n\t\treturn 0;\t\t\n\t}\n\tcout << hh << c << mm;\t\nreturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "02346b7113c0a7f1d02eddf40f20ae25", "src_uid": "20c2d9da12d6b88f300977d74287a15d", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n    int *mn ,maj ,*h;\n    std::cout<<\"donner l'horloge\"<<std::endl;\n    std::cout<<\"donner les minute a ajouter\"<<std::endl;\n    if(*mn<59)\n        *mn=*mn+1;\n    else\n    {\n        *mn=0;\n        if(*h<23)\n            *h=*h+1;\n        else\n            *h=0;\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e3373b91af45ed00203e2bf2f02fc978", "src_uid": "20c2d9da12d6b88f300977d74287a15d", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<cstdio>\n\nint main()\n{\n    int h, m, a;\n    scanf(\"%d:%d%d\", &h, &m, &a);\n    a+=h*60+m;\n    printf(\"%.2d:%.2d\\n\", a/60%24, a%60);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "21f1777e5f6e0c305d38d7643bd3d98a", "src_uid": "20c2d9da12d6b88f300977d74287a15d", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\nint main()\n{\n    int a,b,c,d,e,f,g,h,i,j;\n    char s[2];\n    scanf(\"%d%*c%d\",&a,&b);\n    if(a>=0&&a<=4)\n    {\n        if(b>a*10)\n        {\n             printf(\"0%d:%d\",a+1,(a+1)*10);\n        }\n        else\n        {\n            printf(\"0%d:%d\",a,a*10);\n        }\n\n    }\n    else if(a>=5&&a<=9)\n    {\n        if(a==5&&b<a*10)\n        {\n            printf(\"0%d:%d\",a,a*10);\n        }\n        else{ printf(\"10:01\");}\n\n    }\n    else if(a>=15&&a<=19)\n    {\n        if(a==15&&b<51)\n        {\n            printf(\"15:51\");\n        }\n        else{printf(\"20:02\");}\n\n    }\n    else if(a>=10&&a<=14)\n    {\n\n     c=a%10;\n     c=c*10;\n     c=c+1;\n     if(b>=c)\n        {\n            printf(\"%d:\",a+1);\n        sprintf(s,\"%d\",a+1);\n        printf(\"%c%c\",s[1],s[0]);\n\n        }\n        else\n        {\n            printf(\"%d:\",a);\n        sprintf(s,\"%d\",a);\n        printf(\"%c%c\",s[1],s[0]);\n        }\n\n    }\n        else if(a>=20&&a<=22)\n    {\n\n     c=a%20;\n     c=c*10;\n     c=c+2;\n     if(b>=c)\n        {\n            printf(\"%d:\",a+1);\n        sprintf(s,\"%d\",a+1);\n        printf(\"%c%c\",s[1],s[0]);\n\n        }\n        else\n        {\n            printf(\"%d:\",a);\n        sprintf(s,\"%d\",a);\n        printf(\"%c%c\",s[1],s[0]);\n        }\n\n    }\n    else if(a==23)\n        \n    {\n        if(b<32)\n        {\n            printf(\"23:32\");\n        }\n        else\n        {\n            printf(\"00:00;\n        }\n        \n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "39e909a5df7ea90d8e4afd38b68a655f", "src_uid": "158eae916daa3e0162d4eac0426fa87f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\nchar* palindromo(char *duerme);\nchar *calcular(int hora, int minuto);\n\nchar * transformar(int hora, int minuto);\n\nint main ()\n\n{\n    char duerme[51],*despierta;\n    scanf(\"%s\",duerme);\n    despierta = palindromo(duerme);\n\n\n    printf(\"%s\",despierta);\n\n\n    return NULL;\n}\n\nchar* palindromo(char *duerme)\n{\n    char *despierta = NULL,aux_h[3],aux_m[3];\n    int i,minuto,hora;\n\n    for( i = 0; i<2 ;i++)\n    {\n        aux_h[i] = duerme[i];\n        aux_m[i] = duerme[i+3];\n    }\n    aux_h[2]= '\\0'; aux_m[2] = '\\0';\n\n    hora = atoi(aux_h);\n    minuto =atoi(aux_m);\n\n    despierta = calcular(hora,minuto);\n\n\n\n    return despierta;\n}\n\nchar *calcular(int hora, int minuto)\n{\n    int i,hora_decena, hora_unidad, minuto_decena, minuto_unidad;\n\n    char *despierta = NULL, *retorno = \"00:00\";\n    if(hora >= 23 && minuto > 31)\n    {\n\n        despierta = retorno;\n\n    }\n    else\n    {\n\n        hora_decena = (hora/10);        minuto_decena = minuto/10;\n        hora_unidad = (hora%10);     minuto_unidad = (minuto%10);\n        if( minuto <  hora_decena + (hora_unidad*10 ) )\n        {\n\n            minuto = hora_decena + (hora_unidad*10);\n\n            despierta = transformar(hora,minuto);\n\n\n            return despierta;\n\n        }\n        if( minuto >= hora_decena + (hora_unidad*10 ))\n        {\n\n            hora = hora+1;\n            minuto = hora/10 + ( (hora%10 )* 10);\n            despierta = transformar(hora,minuto);\n            return despierta;\n        }\n\n    }\n    return despierta;\n}\n\n\nchar * transformar(int hora, int minuto)\n{\n    char *despierta , aux_h[2], *aux_m[20];\n\n    itoa(hora, aux_h , 10);\n\n    itoa(minuto , aux_m , 10);\n\n    strcat(despierta,aux_h);\n    despierta[2]= ':';\n    despierta[3] = '\\0';\n    strcat(despierta,aux_m);\n    if(despierta[0] > '9')\n    {\n        despierta[0] = '0';\n    }\n    else1\n    {\n        if(despierta[0] < '1')\n        {\n            despierta[0] = '00';\n        }\n    }\n\n    return despierta;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e1d41c8c46c1534708f5dbf3382f24dd", "src_uid": "158eae916daa3e0162d4eac0426fa87f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n\nint funcelias (char a);\n\nint main()\n{\n\tint i,j=0,k,f,l ;\n\tint aux[4];\n\tchar hora[6];\n\tint flag=0 ;\n\tscanf(\"%s\", hora) ;\n\t\n\n\tfor(i=0;'\\0'!=hora[i];i++){\n\t\t\n\t\tif(funcelias(hora[i])!=-1){\n\t\t\taux[j]=funcelias(hora[i]);\n\t\t\tj++;\n\t\t}\n\t}\n\twhile(flag!=1){\n\t\t\n\t\tfor(i=aux[0] ; i<3 && flag==0; i++)\n\t\t{\n\t\t\tfor(k=aux[1] ; k<4 && flag==0; k++)\n\t\t\t{\n\t\t\t\tfor(j=aux[2] ; j<6 && flag==0; j++)\n\t\t\t\t{\t\t\t\t\n\t\t\t\t\tfor(l=aux[3]+1 ; l<10 && flag==0; l++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif(i==l and k==j)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tflag=1 ;\n\t\t\t\t\t\t\tprintf(\"%d%d:%d%d\",i,k,j,l) ;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\taux[3]=-1;\n\t\t\t\t}\n\t\t\t\taux[2]=0;\n\t\t\t}\n\t\t\taux[1]=0;\n\t\t\t\n\t\t}\n\t\taux[0]=0;\n\t\t\n\t}\n\t\t\n\treturn 0 ;\n}\nint funcelias (char a)\n{\n\tint i;\n\t\n\tchar numero[]= {'0','1','2','3','4','5','6','7','8','9'}\t;\n\tfor(i=0; i<10; i++)\n\t{\n\t\t\n\t\tif(a==numero[i])\n\t\t{\n\t\t\treturn i;\n\t\t}\n\t\t\n\t}\n\treturn -1;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b539a0dcaecd707dc3f31dad81e077c4", "src_uid": "158eae916daa3e0162d4eac0426fa87f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<string.h>\n#include<stdio.h>\n#include<stdlib.h>\n#include<time.h>\n#include<math.h>\n#include<ctype.h>\n\n#define MAX( a, b ) ( ( a > b) ? a : b ) \n#define MIN( a, b ) ( ( a < b) ? a : b )\n#define FOR(ii,aa,bb) for(ii=aa;ii<bb;ii++)\n#define and &&\n#define or ||\nint main () {\n\nint x=0,n=0,s=0,i,j,a[10];\nchar b;\nscanf(\"%d\",&x);\nscanf(\"%c\",&b);\nscanf(\"%d\",&s);\nn+=((x%10)*10)+x/10;\nif(s<n){\n  printf(\"%d:%d\",x,n);\n  return 0;}\nif(x<23 and n+10<60){\n  printf(\"%d:%d\",x+1,n+10);\n  return 0;}\nif(n+10>=60){\n  printf(\"20:02\");\n  return 0;}\nprintf(\"00:00\");\n\n\n\n\n\n\n\n\n  return 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d6c5198e42a00bda049107ac6126584d", "src_uid": "158eae916daa3e0162d4eac0426fa87f", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int hora,Min;\n\n    scanf(\"%d:%d\",&hora,&Min);\n    int Aux;\n    float H;\n\n    if((hora>0 && hora <=5 && Min<50 )||(hora>=10 && hora<=15 && Min<51)||(hora>=20 && hora<=23 && Min<32)){\n        Aux=hora/10;\n        H=(((float)hora/10)-Aux)*100+Aux;\n        if(Min<H)\n            printf(\"%d:%.0f\",hora,H);\n        else{\n            hora++;\n            H=H+10;\n            printf(\"%d:%.0f\",hora,H);\n        }\n    }\n    else if ((hora>=6 && hora<=9) || hora=05 && min>50 )\n        printf(\"10:01\");\n    else if ((hora>=16 && hora<=19) || hora=15 && min>51 )\n        printf(\"20:02\");\n    else\n        printf(\"00:00\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c36bccb31eb3f985155e7563c829758a", "src_uid": "158eae916daa3e0162d4eac0426fa87f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint N,K,dp[2003][2003];\nint find(int cur,int cnt)\n{\n\tif(cnt>K)\n\t{\n\t\treturn 1;\n\t}\n\tif(dp[cur][cnt]>-1)\n\t{\n\t\treturn dp[cur][cnt];\n\t}\n\tdp[cur][cnt]=0;\n\tfor(int i=1;cur*i<=N;i++)\n\t{\n\t\tdp[cur][cnt]=(dp[cur][cnt]+find(cur*i,cnt+1))%1000000009;\n\t}\n\treturn dp[cur][cnt];\n}\nint main()\n{\n\twhile(scanf(\"%d %d\",&N,&K)==2)\n\t{\n\t\tmemset(dp,-1,sizeof(dp));\n\t\tprintf(\"%d\\n\",find(1,1));\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bf4e4069207e8bea69cf26443665b4fb", "src_uid": "c8cbd155d9f20563d37537ef68dde5aa", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n  long long int dp[2002][2002];\n  long long int par(long long int n,long long int k)\n{\n  if(dp[n][k]==-1)\n  {\n    if(k==0)\n      {\n\tdp[n][k]=0;\n       \treturn 0;\n      }\n  if(n==1)\n    {\n      dp[n][k]=1;\n         return 1;\n    }\n  long long int i,num=k;\n  long long int sum=0;\n  for(i=1;i*i<=n;i++)\n    {\n      num=k;\n      while(num--)\n\tsum+=par(i,num)%1000000007;     \n\n    }\n  dp[n][k]=(sum+1)%1000000007;\n\t return (sum+1)%1000000007;\n  }\n  else\n    return dp[n][k];\n\n}\n long long int good(long long int n,long long int k)\n{\n  if(n==0)\n    return 0;\n  if(n==1)\n    return 1;\n  return good(n-1,k)%1000000007+par(n,k)%1000000007;\n  }\nint main()\n{\n  long long int n,k,i,j;\n  scanf(\"%lld %lld\",&n,&k);\n  for(i=0;i<2002;i++)\n    for(j=0;j<2002;j++)\n      dp[i][j]=-1;\n    long long int ans=good(n,k);\n    if(k==0)\n      ans=0;\n    int ans1=(int)ans%1000000007    \n  printf(\"%d\\n\",ans1);\n  return 0;\n}\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5f6b1eedf1e3e38e9eedc151adac431b", "src_uid": "c8cbd155d9f20563d37537ef68dde5aa", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string>\n__int64 n,k,dp[2010][2010],i,j,temp,l,m;\nint main()\n{\n\twhile(~scanf(\"%I64d%I64d\",&n,&k))\n\t{\n\t\tmemset(dp,0,sizeof(dp));\n\t\tfor(i=1;i<=n;i++)\n\t\t\tdp[1][i]=1;\n\t\tfor(i=1;i<k;i++)\n\t\t\tfor(j=1;j<=n;j++)\n\t\t\t{\n\t\t\t\tfor(temp=1;temp<=n/j;temp++)\n\t\t\t\t{\n\t\t\t\t\tdp[i+1][j*temp]+=dp[i][j];\n\t\t\t\t}\t\t\t\t\t\n\t\t\t}\n\t\tint sum=0;\n\t\tfor(i=1;i<=n;i++)\n\t\t{\n\t\t\tsum+=dp[k][i];\n\t\t}\n\t\tprintf(\"%I64d\\n\",sum%1000000007);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cb5001e42fce8c4a8ac4b8ce1d8a9012", "src_uid": "c8cbd155d9f20563d37537ef68dde5aa", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint mod=1000000007;\nint dp[2001][2001];\nint f(int n,int k);\nint upd[2001][2001];\nint uf(int n,int k)\n{\n\tif(udp[n][k]==0)\n\t\treturn udp[n][k];\n\telse\n\treturn f(n,k)-f(n-1,k);\n}\nint f(int n,int k)\n{\n\n\tif(dp[n][k]!=0)\n\t{\n\t\treturn dp[n][k];\n\t}\n\n\tif(n==1)\n\t\tdp[n][k]=1;\n\telse if(k==1)\n\t\tdp[n][k]=n;\n\telse{\n\tint i,p=0,j=0;\n\tint div;\n\tfor(i=n/2;i>=0;i--)\n\t{\n\t\tif(n%i==0)\n\t\t{\n\t\t\tdiv=i;\n\t\t\tbreak;\n\t\t}\n\t}\n\tint non[div];\n\tfor(i=2;i<div;i++)\n\t{\n\t\tif((n%i)!=0)\n\t\t{\n\t\t\tnon[p]=i;\n\t\t\tp++;\n\t\t}\n\t}\n\tint c=0;\n\tint b=0;\n\tfor(i=1;i<k;i++)\n\t{\n\t\tfor(j=0;j<p;j++)\n\t\t{\n\t\t\tc=(c%mod + (uf(non[j],k-i))%mod)%mod;\n\t\t}\n\n\n\t\tb=(b%mod+(f(div,k-i))%mod-c)%mod;\n\t}\n\n\tdp[n][k]=((f(n-1,k))%mod+b%mod+1)%mod;\n\t}\n\treturn dp[n][k];\n\n}\n\nint main()\n{\n\tint n,k,div,i;\n\tscanf(\"%d%d\",&n,&k);\n\tprintf(\"%d\\n\",f(n,k));\n/*\tfor(i=n/2+1;i>=0;i--)\n\t{\n\t\tif(n%i==0)\n\t\t{\n\t\t\tdiv=i;\n\t\t\tbreak;\n\t\t}\n\t}\n\tprintf(\"%d\",div);*/\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3c1fe830b783d499a7d08bc02a404722", "src_uid": "c8cbd155d9f20563d37537ef68dde5aa", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<string.h>\nlong long int divn[2009][2009],en[2009],ar[2009][2009];\nint main()\n{\n\tint s=0,n,k,i,c,j,g,M=1000000007;\n\tscanf(\"%d%d\",&n,&k);\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tc=0;\n\t\tfor(j=1;j<=i;j++)\n\t\t{\n\t\t\tif(i%j==0)\n\t\t\tdivn[i][c++]=j;\n\t\t\ten[i]=c;\n\t\t}\n\t}\n\tfor(i=0;i<=n;i++)\n\t{\n\t\tfor(j=0;j<k;j++)\n\t\t{\n\t\t\tif(j==0)\n\t\t\tar[i][j]=1;\n\t\t\tif(i==0)\n\t\t\tar[i][j]=0;\n\t\t\telse if(i==1)\n\t\t\tar[i][j]=1;\n\t\t\telse\n\t\t\t{\n\t\t\t\tif(j!=0)\n\t\t\t\t{\n\t\t\t\t\tfor(g=0;g<en[i];g++)\n\t\t\t\t\t\tar[i][j]+=ar[divn[i][g]][j-1];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor(i=1;i<=n;i++)\n\t\ts+=ar[i][k-1]%M;\n\tprintf(\"%d\\n\",s%M);\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f27d50727fd4d225a1fdc515cc198d63", "src_uid": "c8cbd155d9f20563d37537ef68dde5aa", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    int,ans;\n    float n,x,y,p1;\n    scanf(\"%f %f %f\",&n,&x,&y);\n    p1=(x/n)*100;\n    if(p1<y)\n    {\n       y=y-p1;\n       ans=y*n;\n       if(ans%100==0);\n       ans=ans/100;\n       else\n       ans=(ans/100)+1;\n      \n    }\n    else\n    ans=0;\n    printf(\"%d\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8d12c933e32011ed3a0eb74c530374de", "src_uid": "7038d7b31e1900588da8b61b325e4299", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\n#include<math.h>\nint main()\n{\n    int n,x,y;\n    double p;\n    scanf(\"%d %d %d\",&n,&x,&y);\n    p= (n*y)/100;\n    x= int (ceil(p))-x;\n    if(x>0)\n    printf(\"%d\",x);\n    else\n      printf(\"0\");\n    \n    getch();\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "73e87fa0e496b43f42c1fee9df8983d5", "src_uid": "7038d7b31e1900588da8b61b325e4299", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include <math.h>\nint main()\n{int n,x,y;\nfloat c;\n    scanf(\"%d %d %d\",&n,&x,&y);\n    c=float (n*y)/100;\n    x=int(ceil(c))-x;\n    if(x>0)\n    printf(\"%d\",x);\n    else\n    printf(\"0\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fcb302315905d19535fe7dc7b7331eb9", "src_uid": "7038d7b31e1900588da8b61b325e4299", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n//#include<conio.h>\nint main()\n{\n     int n,x,y,p=0;\n     scanf(\"%d %d %d\",&n,&x,&y);\n     while ((x+p)*100<n*y) p++;\n     printf(\"%d\\n\",p);]\n     //getch();\n     return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bba8ed125f4eb19640761590bda59fce", "src_uid": "7038d7b31e1900588da8b61b325e4299", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    float ans;\n    float n,x,y,p1;\n    scanf(\"%f %f %f\",&n,&x,&y);\n    p1=(x/n)*100;\n    if(p1<y)\n    {\n       y=y-p1;\n       ans=(y*n)/100;\n       if(ans<1)\n       ans=1;\n       ans=ceil(ans)\n        \n    }\n    else\n    ans=0;\n    printf(\"%d\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fc5a00fa92f65c2a5dd6cfc51386ba1a", "src_uid": "7038d7b31e1900588da8b61b325e4299", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "int main()\n #include<stdio.h>\n #include<string.h>\n { char* out=NULL,ch,str,f=NULL;\n  char k;\n  \n  scanf(\"%s\",ch);\n  strcpy(str,ch);\n       \n       while(str)\n       { k= toupper(str[0]);\n       if!((k=='E')|| (k=='O')|| (k=='I')|| (k=='U')|| (k=='A'))\n          { sprinf(out,\".%c\",k);\n          strcat(f,out);\n          }\n        str++;  \n       }\n printf(\"%s\",f);\n return 0;\n }", "lang_cluster": "C", "compilation_error": true, "code_uid": "26b12ae10998799fd1cdfd5f96555daf", "src_uid": "db9520e85b3e9186dd3a09ff8d1e8c1b", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    char str[105],str2[205];\n    int j=0,i;\n    scanf(\"%s\",str);\n    for(i=0;i<strlen(str);++i)\n    {\n      if(str[i]!='a' && str[i]!='e' && str[i]!='i' && str[i]!='o' && str[i]!='u' && str[i]!='A' && str[i]!='E' && str[i]!='I' && str[i]!='O' && str[i!=='U')\n      {\n         str2[j++]='.';\n         if(str[i]>64 && str[i]<91)\n         str2[j++]=str[i]+32;\n         str2[j++]=str[i];\n      }\n    }\n    str2[j]='\\0';\n    printf(\"%s\",str2);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1862f5e7bd0cf45aa9db825bcabd8c32", "src_uid": "db9520e85b3e9186dd3a09ff8d1e8c1b", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdbool.h>\nmain()\n{   int z;\n\tchar s[200];\n\tchar s1[200];\n\tgets(s);\n\tint i,j;\n\tz=strlen(s);\n\tfor(i=0;i<strlen(s);i++)\n\t{\n\t\tif(s[i]=='A'||s[i]=='E'||s[i]=='I'||s[i]=='O'||s[i]=='U'||s[i]=='a'||s[i]=='e'||s[i]=='i'||s[i]=='o'||s[i]=='u')\n\t\t{\n\t\t    s1[i]!=s[i];\n\t\t}\n\t\telse{\n            s1[j]=s[i];\n            j=j++;\n\t\t}\n\n\t}\n\t\n\t\n\tfor(i=0;i<*strlen(s1);i++)\n    {print(\".\");\n\tprintf(\"%s\",s1[i]);\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "33ff89465c100cbb5caa2f33ad898204", "src_uid": "db9520e85b3e9186dd3a09ff8d1e8c1b", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n\t\tchar a[100];\n\t\tint l,i,j;\n\t\tget(a);\n\t\tl=strlen(a);\n\t\tstrlwr(a);\n\t\tfor(i=1;i<=l;i++)\n\t\t{\n\t\t\t\n\t\t\tif(a[i]=='a'||a[i]=='o'||a[i]=='y'||a[i]=='e'||a[i]=='u'||a[i]=='i');\n\t\t\tprintf(\".%c\",a[i]);\n\t\t\t\n\t\t\n\t\t}\n\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "704ae5d9a70d1a7221fd627b2c57fd39", "src_uid": "db9520e85b3e9186dd3a09ff8d1e8c1b", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#define MAX 100\n#include<stdio.h>\n#include<string.h>\nint main()\n{char s[MAX];\nint i;\nscanf(\"%s\",&s);\nj=0;\nfor(i=0;i<strlen(s);i++)\n{\nif(s[i]>=65&&s[i]<=90)\ns[i]=s[i]+32;\n\nif(s[i]!='a'&&s[i]!='i'&&s[i]!='e'&&s[i]!='o'&&s[i]!='u'&&s[i]!='A'&&s[i]!='E'&&s[i]!='I'&&s[i]!='O'&&s[i]!='U'&&s[i]!='Y'&&s[i]!='y')\n{printf(\".%c\",s[i]);\n}\n\n}\n\nreturn 0;}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1c30a3b3b4fb9c44ecbaf01dc2a4b403", "src_uid": "db9520e85b3e9186dd3a09ff8d1e8c1b", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,min=100,i,A[100],temp;\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&A[i]);\n        if(A[i]<min)\n            min=A[i];\n    }\n    for(i=0;i<n;i++)\n    {\n        do{\n            A[i]%=min;\n            if(A[i])\n            {\n                temp=min;\n                min=A[i];\n                A[i]=min;\n            }\n        }while(A[i]);\n    }\n    printf(\"%d\",min*n);\n    return 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ac7080796e7a0a0ac64529529f0b99ee", "src_uid": "042cf938dc4a0f46ff33d47b97dc6ad4", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int a,b,i,j,k,m,d;\n    \n    scanf(\"%d\",&a);\n    \n    int A[a];\n    \n    for(i=0;i<a;i++)\n    {\n        scanf(\"%d\",&A[i]);\n    }\n    \n    for(i=0;i<a;i++)\n    {\n        d=1\n        for(j=i+1;j<a;j++)\n        {\n            k=A[i];\n            m=A[j];\n            do\n            {\n                d=k%m;\n                k=m;\n                m=d;\n            }while(d!=0);\n            \n            A[i]=k;\n            A[j]=k;\n        }\n    }\n    d=0;\n    for(i=0;i<a;i++)\n    {\n        d+=A[i];\n    }\n    \n    printf(\"%d\\n\",d);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6112ab48001f2d4f6c7a8581856e532a", "src_uid": "042cf938dc4a0f46ff33d47b97dc6ad4", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>  \n#include<string.h>  \nconst int N = 105;  \nint n, num[N];   \nint gcd(int a, int b) \n{  \n    if (b==0) \n\treturn a;  \n    return gcd(b,a%b);  \n}  \nint main () \n{  \n    scanf(\"%d\",&n);  \n    for (int i=0;i<n;i++) scanf(\"%d\",&num[i]);  \n    int t=num[0];  \n    for (int i=1;i<n;i++) t=gcd(t,num[i]);  \n    printf(\"%d\\n\",t*n);  \n    return 0;  \n}  \n                                                                       ", "lang_cluster": "C", "compilation_error": true, "code_uid": "9d66bbd99258bd922b4c7fb4c6a85a7d", "src_uid": "042cf938dc4a0f46ff33d47b97dc6ad4", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nconst int N = 105;\nint n, num[N];\n\nint gcd(int a, int b) {\n\tif (b == 0) return a;\n\treturn gcd(b, a % b);\n}\nint main () {\n\tint i;\n\twhile(scanf(\"%d\", &n)!=NULL){\n\tfor ( i = 0; i < n; i++) scanf(\"%d\", &num[i]);\n\tint t = num[0];\n\tfor ( i = 1; i < n; i++) t = gcd(t, num[i]);\n\tprintf(\"%d\\n\", t * n);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "22e109f3286297b8d39de17e28e787ac", "src_uid": "042cf938dc4a0f46ff33d47b97dc6ad4", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(){\n  int n,m,a[100],i,tr=1,min;\nscanf(\"%d\",&n);\nfor(i=0;i<n;i++)scanf(\"%d\",&a[i]);\nwhile(tr){\ntr=0;\nmin=a[0];\nfor(i=1;i<n;i++)if(min>a[i])min=a[i];\nfor(i=0;i<n;i++)if(a[i]>min){\ntr=1;\na[i]-=min;\n}\n}\nm=0;\n\nfor(i=0;i<n;i++)m+=a[i];\nprintf(\"%d\",m);\nreturn 0;/aaa\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d7baa0b18ee97db8bfce303e3da62827", "src_uid": "042cf938dc4a0f46ff33d47b97dc6ad4", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,d,i,j,temp,min=200,ans=200;\n    scanf(\"%d%d\",&n,&d);\n    int a[n];\n    for(i=0;i<n;i++)\n        scanf(\"%d\",&a[i]);\n    for(i=0;i<n;i++)\n    {\n        for(j=i+1;j<n;j++)\n        {\n            if(a[j]<a[i])\n            {\n                temp=a[j];\n                a[j]=a[i];\n                a[i]=temp;\n            }\n        }\n    }\n    for(i=0;i<n;i++)\n    {\n        min=200;\n        for(j=i+1;j<n;j++)\n        {\n            if(a[j]-a[i]>d)\n            {\n                min=n-j+i;\n                break;\n            }\n            min=n+i-j-1;\n        }\n        if(min<ans)\n            ans=min;\n    }\n    if(ans==200)\n        ans=0;\n    printf(\"%d\\n\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6ae396ba5713b3ce6191e48354370b2f", "src_uid": "6bcb324c072f796f4d50bafea5f624b2", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdbool.h>\n\nvoid merge(int arr[], int l, int m, int r) {\n\tint i = 0; // Initial index of first subarray\n\tint j = 0; // Initial index of second subarray\n\tint k = l; // Initial index of merged subarray\n\tint n1 = m - l + 1;\n\tint n2 = r - m;\n\n\t/* create temp arrays */\n\tint L[n1], R[n2];\n\t\n\t/* copy data to temp arrays L[] and R[] */\n\tfor (int i = 0; i < n1; i++)\n\t\tL[i] = arr[l + i];\n\tfor (int j = 0; j < n2; j++)\n\t\tR[j] = arr[m + 1 + j];\n\t\n\t/* merge the temp arrays back into arr[l..r] */\n\twhile (i < n1 && j < n2) {\n\t\tif (L[i] <= R[j]) {\n\t\t\tarr[k] = L[i];\n\t\t\ti++;\n\t\t} else {\n\t\t\tarr[k] = R[j];\n\t\t\tj++;\n\t\t}\n\t\tk++;\n\t}\n\n\t/* copy the remaining elements of L[] || R[], if there are any */\n\twhile (i < n1) {\n\t\tarr[k] = L[i];\n\t\ti++;\n\t\tk++;\n\t}\n\twhile (j < n2) {\n\t\tarr[k] = R[j];\n\t\tj++;\n\t\tk++;\n\t}\n}\n\nvoid mergeSort(int arr[], int l, int r) {\n\tif (l < r) {\n\t\tint m = l + (r - l) / 2;\n\n\t\t// sort first and second halves\n\t\tmergeSort(arr, l, m);\n\t\tmergeSort(arr, m + 1, r);\n\t\t\n\t\tmerge(arr, l, m, r);\n\t}\n}\n\n\nint main(void) {\n    int n, d, min[10000];\n    int k = 0; // for array min[]\n    scanf(\"%d %d\", &n, &d);\n    int a[n];\n    for (int i = 0; i < n; i++)\n        scanf(\"%d\", &a[i]);\n    \n    mergeSort(a, 0, n - 1);\n    \n    if (d == 0 || (a[n - 1] - a[0] =< d) || n == 1) {\n        printf(\"0\\n\");\n        return 0;\n    }\n\n    for (int i = n - 1; i >= 0; i--) {\n        for (int j = i; j >= 0; j--) {\n            if (a[i] - a[j] == d) {\n                min[k++] = (n - 1) - (i - j + 1);\n            }\n        }\n    }\n\n    mergeSort(min, 0, k - 1);\n    \n    printf(\"%d\\n\", min[0] + 1);\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "19950f1608892b1bc63f077d1cf2ee86", "src_uid": "6bcb324c072f796f4d50bafea5f624b2", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint comp (const void * elem1, const void * elem2)\n{\n    int f = *((int*)elem1);\n    int s = *((int*)elem2);\n    if (f > s) return  1;\n    if (f < s) return -1;\n    return 0;\n}\nint main()\n{\n    int n,d;\n    scanf(\"%d %d\",&n,&d);\n    int points[n];\n    for(int i=0;i<n;i++)\n    {\n        scanf(\"%d\",&points[i]);\n    }\n    qsort (points, sizeof(points)/sizeof(*points), sizeof(*points), comp);\n    int c1=0,c2=0;\n\n    for(int i=n-1;i>0;i--)\n    {\n        if(points[i]-points[0]>d)\n            c1++;\n        else\n            break;\n    }\n    for(int i=0;i<n-1;i++)\n    {\n        if(points[n-1]-points[i]>d)\n            c2++;\n        else\n            break;\n    }if(c1>c2)\n    printf(\"%d\",c2);\n    else\n        printf(%d,c1);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c4d5e1cf9789273bd7fa25ca63831417", "src_uid": "6bcb324c072f796f4d50bafea5f624b2", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n\n\nint minNumPtsRemove(int n,int d,int *p)\n{\n    int cumilativeCount[100 + d]= {};\n    int pts=0,maxPts=0,i=0;\n    for(i=0;i<n;i++)\n        cumilativeCount[p[i]] ++;\n    for(i=1;i<100+d;i++)\n        cumilativeCount[i] += cumilativeCount[i-1];\n    for(i=0;i<100;i++)\n    {\n        pts=cumilativeCount[i+d+1]-cumilativeCount[i];\n        if(pts>maxPts)\n        {\n            maxPts = pts;\n        }\n    }            \n    return n-maxPts;\n}\n\nint main()\n{\n\tint n,d;\n\tscanf(\"%d %d \",&n,&d);\n\tint p[n];\n\tfor(int i=0;i<n;i++)\n\t    scanf(\"%d\",&p[i]);\n\tprintf(\"%d\\n\",minNumPtsRemove(n,d,p));\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f888e139a393ad3b57eeb95d769421be", "src_uid": "6bcb324c072f796f4d50bafea5f624b2", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\nint arr[101];\nint n,dis;\nint min(int x,int y)\n{\n\treturn x<y?x:y;\n}\nint comparator (const void * b, const void * a)\n{\n  return ( *(int*)b - *(int*)a );\n}\nint recur(int start,int end)\n{\n\tif(start==end)\n\t return 0;\n\tif(arr[end]-arr[start]<=dis)\n\t return 0;\n\tint q1=recur(start+1,end);\n\tint q2=recur(start,end-1);\n\treturn 1+min(q1,q2);\n}\nint main()\n{\n\tscanf(\"%d %d\",&n,&dis);\n\t//printf(\"%d\\n\",dis);\n\tint i,j,k;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\",&arr[i]);\n\t}\n\t\n\tqsort(arr,n,sizeof(int),comparator);\n\t\n\tprintf(\"%d\\n\",recur(0,n-1));\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3e98c52a8e6906dcb68e64e34bf86175", "src_uid": "6bcb324c072f796f4d50bafea5f624b2", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n\tint s1(0),s2(0);\n\tchar st1[101],st2[101];\n\tscanf(\"%s%s\",st1,st2);\n\tstrlwr(st1);strlwr(st2);\n\tif(strcmp(st1,st2)<0)printf(\"-1\");else printf(\"%d\",strcmp(st1,st2)?1:0);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6e729da9256fc13eda76b7b842befac0", "src_uid": "ffeae332696a901813677bd1033cf01e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint c,x-0,y=00,e=0;\n\tchar str[100],str2[100];\n\tscanf(\"%s\", &x);\n\tscanf(\"%s\", &y);\n\tfor (c = 0; str[c] != 0 && str2[c] != 0; c++){\n\t\tif (str[c] - str2[c]>0 )x++;\n\t\telse if (str[c] - str2[c]<0)y++;\n\t\telse e++;\n\t}\n\tif (e = c - 1) printf(\"0\");\n\telse if (y>x) printf(\"-1\");\n\telse printf(\"1\");\n\treturn(0);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f60b3d4e936b5ca6fadf2c92097ee0c9", "src_uid": "ffeae332696a901813677bd1033cf01e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "\u007f#include<stdio.h>\n#include<string.h>\nint main(){\n  int i,j,k,m,z1,z2;\n  m=0;\n  char a[101],b[101];\n  scanf(\"%s\",a);\n  scanf(\"%s\",b);\n  k=strlen(a);\n  int c[k];\n  for(i=0;i<k;i++){\n    z1=a[i];\n    z2=b[i];\n    if(z1<91){\n    a[i]=a[i]+32;\n  }\n  if(z2<91){\n    b[i]=b[i]+32;\n  }\n  }\n  for(i=0;i<k;i++){\n    \n      if(a[i]==b[i]){\n         c[m]=0;\n         m++;\n      }\n      else if(a[i]>b[i]){\n        c[m]=1;\n        m++;\n        break;\n      }\n      else if(a[i]<b[i]){\n        c[m]=-1;\n        m++;\n        break;\n      }\n    }\n   for(i=0;i<m;i++){\n     if(c[i]==1){\n       printf(\"1\");\n       break;\n     }\n     if(c[i]==-1){\n       printf(\"-1\");\n       break;\n     }\n\n\n   }\n   if(i==m){\n     printf(\"0\");\n   }\n  }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a65ff097797125d567a734d3263d9bc1", "src_uid": "ffeae332696a901813677bd1033cf01e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char a[200],b[200];\n   // gets(a);\n    //gets(b);\n    strlwr(a);\n    strlwr(b);\n    //if(strcmp(a,b)<0)\n    printf(\"-1\");\n    else if(strcmp(a,b)>0)\n    printf(\"1\");\n    else printf(\"0\");\n\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c0fec36b09e91a7d1b4cf7316844687b", "src_uid": "ffeae332696a901813677bd1033cf01e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main() {\n\tchar a[101],b[101];\n\tint i,temp=0;\n\tfor(i=0;i<strlen(a);i++)\n\t{\n\t    scanf(\"%f\",&a[i]);\n\t    scanf(\"%f\",&[i]);\n\t}\n\tfor(i=0;i<strlen(a);i++)\n\t{\n\t    if(a[i]>b[i])\n\t    {\n\t        temp=1;\n\t        break;\n\t    }\n\t    else if(a[i]<b[i])\n\t    {\n\t        temp=-1;\n\t        break;\n\t    }\n\t}\n\tif(temp==1)\n\tprintf(\"1\");\n\telse if(temp==-1)\n\tprintf(\"-1\");\n\telse printf(\"0;\")\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ba5aee3d6666c1fd2a81a72f7350be94", "src_uid": "ffeae332696a901813677bd1033cf01e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "/******************************************************************************\n\n                            Online C Compiler.\n                Code, Compile, Run and Debug C program online.\nWrite your code in this editor and press \"Run\" button to compile and execute it.\n\n*******************************************************************************/\n\n#include <stdio.h>\n\nint main()\n{\n    int a,b;\n    int fact=1,fa=1;\n    scanf(\"%d%d\",&a,&b);\n    while(a>=1){\n        fact=fact*a;\n        a--;\n        }\n    while(b>=1){\n        fa=fa*b;\n        b--;\n    } \n    \n    }\n    while(fact!=fa)\n    {\n        if(fact>fa){\n            fact-=fa;\n        }else{\n            fa-=fact;\n        }\n    }\n    printf(\"%d\",fact);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e475b3e9deb8a7461789d2c4a68564e0", "src_uid": "7bf30ceb24b66d91382e97767f9feeb6", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main() {\n    int arr[10001]={0};\n    long int a = 0, n,m, temp1;\n    scanf(\"%ld\", &n);\n    scanf(\"%ld\",&m);\n    arr[10000] = 1;\n    if(n>m)\n    n=m;\n    for (long int i = 2; i <= n; i++) {\n      a = 0;\n      for (long int j = 10000; j >= 0; j--) {\n        a = a + arr[j] * i;\n        arr[j] = a % 10;\n        a = a / 10;\n      }\n    }\n    for (long int k = 0; k <= 10000; k++) {\n      if (arr[k] != 0) {\n        temp = k;\n        break;\n      }\n    }\n    for (long int k1 = temp; k1 <= 10000; k1++)\n      printf(\"%d\", arr[k1]);\n    printf(\"\\n\");\n    return 0;\n  }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7aa1e1c42f002c743c43d1505af13a5e", "src_uid": "7bf30ceb24b66d91382e97767f9feeb6", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h.\nint main()\n{\n    int a,b,c,d,i,k,e;\n    scanf(\"%d %d\",&a,&b);\n    for(i=1;i<=a;i++)\n     c=c*i;\n     for(i=1;i<=b;i++)\n      d=d*i;\n     if(c<d)\n       e=c;\n       else\n        e=d;\n    for(i=0;i<=e;i++)\n    {\n        if((c%i)==0&&(d%i)==0)\n        k=i;\n    }\n    printf(\"%d\",k);\n      \n}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a4db3fd3d77e68b2f67983be94b12dbd", "src_uid": "7bf30ceb24b66d91382e97767f9feeb6", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "    #include<stdio.h>\n    int main()\n    {\n      int i,num,j,g=1,num1;\n\n      scanf(\"%d %d\",&num,&num1);\n\n      int f=1;\n\n      for(i=1; i<=num;i++)\n          f=f*i;\n          for(j=1; j<=num1;j++)\n          g=g*j;\n\n    if(f<g){\n        printf(\"%d\",f);\n    }\n    else{\n        printf(\"%d\",g);\n    }\n      return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "b69f29a1f64f8e0a4f052f394e0b630a", "src_uid": "7bf30ceb24b66d91382e97767f9feeb6", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int a,b,f1=1,f2=1,i;\n    scanf(\"%d %d\",&a,&b);\n    for(i=a,j=b;i>0,j>0;i--,j--)\n    {\n        f1=f1*i;\n        f2=f2*i;\n    }\n    if(f1<f2&&f2%f1==0)\n        printf(\"%d\",f1);\n    else if(f2<f1&&f1%f2==0)\n        printf(\"%d\",f2);\n    else\n        printf(\"1\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1845a3f65e27b8403338cd4a1f50ea63", "src_uid": "7bf30ceb24b66d91382e97767f9feeb6", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<cmath>\n#include<vector>\nusing namespace std;\nint main()\n{\n    long long n,k;\n    vector<long long> ans;\n    cin>>n>>k;\n    for(long long i=1;i<=sqrt(n);i++)\n    {\n        if(n%i==0)\n            ans.push_back(i);\n        if(n%i==0 && i*i!=n)\n            ans.push_back(n/i);\n    }\n    if(ans.size()>=k)\n        cout<<ans[k]<<endl;\n    else\n        cout<<\"-1\"<<endl;\n    return 0;\n}\n/*2017-03-05 20:40:40.494*/", "lang_cluster": "C", "compilation_error": true, "code_uid": "31e39ea69cf0c83340ee3414ff1475b5", "src_uid": "6ba39b428a2d47b7d199879185797ffb", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n\nmain(){\nlong long n=4,k=4,c=0,i,arr[1000000];\n\narr[0]=-1;\n\nscanf(\"%I64d %I64d\",&n,&k);\n\n\n\tif (n<k){ printf(\"-1\"); return 0;}\n//divide n by sthg\n\tfor(i=1;i<=sqrt(n);i++){\n\t\tif (n%i==0) ++c;\n\t\tif (c==k){\n\t\tprintf(\"%I64d\",i);\n\t\treturn 0;\n\t\t}\n\t\tarr[c]=n/i;\n//\tprintf(\"arr[%I64d]=%I64d\\n\",c,arr[c]);\n\t}\n\t\n//\tprintf(\"i=%I64d\\n\",i);\n\t\n\tif(2*c<k) printf(\"-1\");\n\t\n\t\n\t\n\telse{\n\t\n\t if ( i==sqrt(n)) printf(\"%I64d\",arr[2*c-k],c);\n\t else printf(\"%I64d\",arr[2*c-k-1],c);\n\t}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "250a38bcf2583f9f3074abcc1976ee8a", "src_uid": "6ba39b428a2d47b7d199879185797ffb", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\nconst int N = 100005;\n\nlong long v[N];\n\nint f (const void * a, const void * b)\n{\n   return ( *(int*)a - *(int*)b );\n}\n\nint main(){\n\tlong long n, k, i, count = 0;\n\tscanf(\"%lld %lld\",&n,&k);\n\tfor(i = 1; i*i<=n; i++){\n\t\tif(n%i == 0){\n\t\t\tv[count] = i;\n\t\t\tcount++;\n\t\t\tif(n/i != i){\n\t\t\t\tv[count] = n/i;\n\t\t\t\tcount++;\n\t\t\t}\n\t\t}\n\t}\n\tqsort(v,count,sizeof (long long),f);\n\tif(k > count) puts(\"-1\");\n\telse printf(\"%lld\\n\",v[k-1]);\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f519e89badb3505c3d5f526b1b306404", "src_uid": "6ba39b428a2d47b7d199879185797ffb", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nvoid f(long long n, long long k)\n{\n\tfor(long long i=1; i<=sqrt(n); ++i)\n\t{\n\t\tif(n%i==0)\n\t\t\t--k;\n\t\tif(k==0)\n\t\t{\n\t\t\tprintf(\"%I64d\", i);\n\t\t\treturn;\n\t\t}\n\t}\n\tfor(long long i=sqrt(n)+1; i>0; --i)\n\t{\n\t\tif(n%i==0)\n\t\t\t--k;\n\t\tif(k==0)\n\t\t{\n\t\t\tprintf(\"%I64d\", n/i);\n\t\t\treturn;\n\t\t}\n\t}\n\t\tprintf(\"-1\");\n\t}\n}\n\nint main()\n{\n\tlong long n, k;\n\tscanf(\"%I64d%I64d\", &n, &k);\n\tf(n, k);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0418193f1b0b73b6365ccfd9d922c397", "src_uid": "6ba39b428a2d47b7d199879185797ffb", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\nconst int N = 100005;\n\nlong long v[N];\n\nint f (const void * a, const void * b)\n{\n   return ( *(int*)a - *(int*)b );\n}\n\nint main(){\n\tlong long n, k, i, count = 0;\n\tscanf(\"%I64d %I64d\",&n,&k);\n\tfor(i = 1; i*i<=n; i++){\n\t\tif(n%i == 0){\n\t\t\tv[count] = i;\n\t\t\tcount++;\n\t\t\tif(n/i != i){\n\t\t\t\tv[count] = n/i;\n\t\t\t\tcount++;\n\t\t\t}\n\t\t}\n\t}\n\tqsort(v,count,sizeof (long long),f);\n\tif(k > count) puts(\"-1\");\n\telse printf(\"%lld\\n\",v[k-1]);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e719f4a40b6bca0bb59981df5475a03c", "src_uid": "6ba39b428a2d47b7d199879185797ffb", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<conio.h>\nmain()\n{\n     int a,b,diff;\n     scanf(\"%d %d\",&a,&b);\n     diff=a-b;\n     if(diff==1||diff==0||diff=-1)\n     printf(\"yes\");\n     else\n     printf(\"no\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "24808421538a0ab0dffe31ba644ac927", "src_uid": "ec5e3b3f5ee6a13eaf01b9a9a66ff037", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main ()\n{\n  int a,b;\n  scanf(\"%d%d\",&a,&b);\n  if(a==b||a==(b-1))\n  printf(\"yes\");\n  elseif(a==b==0||a>=101||b>=101)\n  printf(\"no\");\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2c48643b25ac1da76f7653c6039d0e0c", "src_uid": "ec5e3b3f5ee6a13eaf01b9a9a66ff037", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<conio.h>\nmain()\n{\n     int a,b,diff;\n     scanf(\"%d %d\",&a,&b);\n     diff=a-b;\n     if(a==0&&b==0)\n     printf(\"no\");\n     else if(diff==1||diff==0||diff=-1)\n     printf(\"yes\");\n     else\n     printf(\"no\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6779658a75c0d5de0d2b6a426ac42cfb", "src_uid": "ec5e3b3f5ee6a13eaf01b9a9a66ff037", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint a,b;\nscanf(\"%d %d\",&a,&b);\nif(a==0 && b==0)\n\t{printf(\"NO\");\nelse if(a-b==1)\n\t{printf(\"YES\");}\nelse if(a-b==-1)\n\t{printf(\"YES\");}\nelse if(a!=0 && b!=0 && a-b==0)\n\t{printf(\"YES\");}\nelse\n\t{printf(\"NO\");}\nreturn 0;\n}\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "36dc8ac9bae66e3c766ea38dc46da687", "src_uid": "ec5e3b3f5ee6a13eaf01b9a9a66ff037", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h\nint main()\n    { int a,b;\n    scanf(\"%d %d\",&a,&b);\n    if(a==b)\n    {printf(\"YES\");\n if(a==b+1 || b==a+1\n{ printf(\"YES\");}\nif(a==b+2 || b==a+2)\n{ printf(\"NO\");}\nreturn 0;\n}\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6396aeb7b9e313ef7fe7d5e0fdba23bb", "src_uid": "ec5e3b3f5ee6a13eaf01b9a9a66ff037", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    int n,m;\n    cin>>n>>m;\n    long long s=n;\n    while(n>=m)\n    {\n        s+=n/m;\n        n=n/m+n%m;\n    }\n    cout<<s<<endl;\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a98bc917301b13fdc72caeabd0964483", "src_uid": "42b25b7335ec01794fbb1d4086aa9dd0", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main(){\n\tint n, m, i, j;\n\twhile(~scanf(\"%d%d\", &n, &m)!=EOF){\n\t\ti = m*n/(m-1);\n\t\tj=i-1;\n\t\tif(j-n = j/n)\n\t\t\ti = j\n\t\tprintf(\"%d\\n\", i);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4718ddf46d1f646343c47247a32d6d27", "src_uid": "42b25b7335ec01794fbb1d4086aa9dd0", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n//\nint n,m,daysCnt=0,i,NewSocs,remindDays;\nscanf(\"%i%i\",&n,&m);\n\n  daysCnt=n;\n  NewSocs=n/m;\n  remindDays=n%m;\n  daysCnt= daysCnt+NewSocs;\n\n\n  while (NewSocs%n!=0)\n {\n      NewSocs=(remindDays+NewSocs)/m;\n      remindDays=(remindDays+NewSocs)%m;\n      daysCnt= daysCnt+NewSocs;\n }\n\n  printf(\"%i\",daysCnt);(\"%i\",daysCnt);", "lang_cluster": "C", "compilation_error": true, "code_uid": "d038a7a097b46c517b35943e02e41dba", "src_uid": "42b25b7335ec01794fbb1d4086aa9dd0", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main ()\n{\n    int m,n,a, b, x,i;\n\n    scanf(\"%d %d\",&n, &m);\n    x=n;\n    for (i=1; ;)\n    {\n    \ta=n/m;\n    \tb=a+(n%m);\n    \tn=b;\n    \tx=x+a;\n    \tif (b<m)\n    \t{break;}\n    }\n    printf(\"%d\", x);\n\n\n        return 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0b065d628f90bb263f731b24756779a5", "src_uid": "42b25b7335ec01794fbb1d4086aa9dd0", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n, m, div, mod;\n    sf(\"%d%d\", &n, &m);\n    int sum = a;\n    while(a>=b)\n    {\n        div = (a/b);\n        sum = sum + div;\n        mod = (a%b);\n        a= (div+mod);\n    }\n    pf(\"%d\", sum);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9e38f6e4b6d819d8a94b3e9072111c85", "src_uid": "42b25b7335ec01794fbb1d4086aa9dd0", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main() {\n  int n, i, a, b, r, c, d, j;\n  scanf(\"%d %d %d\", &n, &a, &b);\n  r=log2(n);\n  c=n/2;\n  d=c;\n  i=1;\n  j=n;\n  d=n;\n  while(i<log2(j)){\n    if(a<=c && b<=c){\n      r=r-1;\n      c=(n-c)/2;\n      n=n/2;\n    }\n    else if(a>c && b>c){\n      r=r-1;\n      c=n-((n-c)/2);\n      if(a<=c && b<=c){\n        n=4*c-n;\n      }\n      else{\n        continue;\n      }\n    }\n    else{\n      break;\n    }\n    i=i+1;\n  }\n\n  if(r==log2(j)){\n    printf(\"Final!\");\n  }\n  else{\n    printf(\"%d\", r);\n  }\n  return 0;\n  }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "99bb9cd29af171d6667bf941df4fcc58", "src_uid": "a753bfa7bde157e108f34a28240f441f", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n  int n , a ,b;\n  int diva = 0;\n  int divb = 0;\n  int totalmatches=0;\n  int counter=1;\n\n  scanf(\"%d %d %d\" , &n , &a , &b);\n  if( ((b > n/2) || (a > n/2)) && ( (b <= n/2) || (a <= n/2))  )\n  {\n    printf(\"Final!\");\n    return 0;\n  }\n  int temp=n;\n  while(temp!=1)\n    {\n      temp = temp/2;\n      totalmatches++;\n    }\n    totalmatches--;\n    if(a%2!=0)\n      a = (a+1);\n    if(b%2!=0)\n      b = (b+1);\n    while(1)\n    {\n    if(a > n/2)\n    {\n      n=n/2;\n      a=a-n;\n      b=b-n;\n    }\n    else\n      n=n/2;\n    if( ((b > n/2) || (a > n/2)) && ( (b <= n/2) || (a <= n/2))  )\n    {\n      printf(\"%d\" , totalmatches);\n      return 0;\n    }\n    totalmatches--;\n  }\n\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a07400f7cf5805115995aaa2948df139", "src_uid": "a753bfa7bde157e108f34a28240f441f", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main(){\nint  n,o=0,x,y,v,cnt=0,f=0,a,p=1;\n\nscanf(\"%d%d%d\",&n,&x,&y);\nwhile(p<=n){\np=p*2;f++;\n}\nif(y>x){a=x;x=y;y=a;}\nwhile(cnt!=f-1){\n    v=(n+o)/2;\n    if((x>v && y<=v)){\n        break;\n    }\n    if(x<=v){\n        n=n/2;\n    }else if(y>v){\n        o=n/2;\n    }\n    cnt++;\n}\nif(cnt==0){\n    printf(\"Final!\");\n}else{\nprintf(\"%d\",f-cnt-1);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c8b8518b676a89888e1829dbc13807b8", "src_uid": "a753bfa7bde157e108f34a28240f441f", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#define MAX 100005\n/*\nvoid swap(int *a,int *b){\n\tint t = *a;\t*a = *b;\t*b = t;\n}\n\nint main(){\n\tint a ,b;\n\tscanf(\"%d %d\" ,&a ,&b);\n\tif(a > b)\tswap(&a ,&b);\n\tif((b - a) % 2 == 0)\t{\n\t\tint x = (b - a) / 2;\n\t\tprintf(\"%I64d\" ,1LL*x * (x + 1));\n\t}else {\n\t\tint x = (b - a) / 2;\n\t\tint y = x + 1;\n\t\tprintf(\"%I64d\" ,1LL * x * (x + 1) / 2 + 1LL * y * (y + 1) / 2);\n\t}\n\treturn 0;\n}*/\n\nint a[257];\nvoid printArray(int a[],int n){\n\tfor(int i = 1 ; i <= n ; i++)\tprintf(\"%d \" ,a[i]);\tprintf(\"\\n\");\n}\nint main(){\n\tint n ,A ,B;\n\tscanf(\"%d %d %d\" ,&n ,&A ,&B);\n\tfor(int i = 1 ; i <= n ; i++)\ta[i] = i;\n\tint p = n ,r = 0 ,j = 1; \n\tint f = 0;\n\tif(A > B)\tswap(&A ,&B);\n\twhile(p > 1){\n\t\tprintArray(a ,n);\n\t\tr++;\tj = 1;\n\t\tfor(int i = 1 ; i <= n ; i+=2){\n\t\t\tif(a[i] == A && a[i + 1] == B){\n\t\t\t\tf = 1;\n\t\t\t\tbreak;\n\t\t\t}else{\n\t\t\t\tif(a[i] == A || a[i + 1] == A)\ta[j++] = A;\n\t\t\t\telse if(a[i] == B || a[i + 1] == B)\ta[j++] = B;\n\t\t\t\telse a[j++] = a[i];\n\t\t\t}\n\t\t}\n\t\tif(f)\tbreak;\n\t\tp /= 2;\tn/=2;\n\t\t\n\t}\n\tif(p == 2)\tputs(\"Final\");\n\telse printf(\"%d\" ,r);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cab619c725dd218b749771a9ce60844a", "src_uid": "a753bfa7bde157e108f34a28240f441f", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n\tlong long int n,a,b;\n\tscanf(\"%lld %lld %lld\",&n,&a,&b);\n\tif(a>b)\n\t{\n\t\tlong long int swap=a;\n\t\ta=b;\n\t\tb=swap;\n\t}\n\tlong long int round=1;\n\twhile(n>2)\n\t{\n\t\tif(b==a+1)\n\t\t{\n\t\t\tprintf(\"%lld\\n\",round);\n\t\t\treturn 0;\n\t\t}\n\t\ta=(a+1)/2;\n\t\tb=(b+1)/2;\n\t\t++round;\n\t\tn/=2;\n\t}\n\tprintf(\"Final!\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "bf72ba3897a0fd983ce94c062a5fbc68", "src_uid": "a753bfa7bde157e108f34a28240f441f", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\n\nint main()\n{\n    long long int x,y,c;\n\n    scanf(\"%lld %lld\",&x,&y);\n    c=y-1;\n    if(y==0 || C==0 || (x-c)<0) printf(\"No\\n\");\n    else{\n\n    if((x-c)%2==0)  printf(\"Yes\\n\");\n\n    else  printf(\"No\\n\");\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "eb29d83c3404c88821ff91fb912174c4", "src_uid": "1527171297a0b9c5adf356a549f313b9", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nusing namespace std;\n\nint main(void) {\n\tint x, y;\n\tscanf(\"%d%d\", &x,&y);\n\t(x - y + 1) % 2 == 0 ? printf(\"YES\") : printf(\"NO\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b621df99e8673b9f74d49f45f15cfe8e", "src_uid": "1527171297a0b9c5adf356a549f313b9", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nvoid f(int*,int*);\nbool g(int,int);\nmain()\n{\n\tint x,y;\n\tdo{\n\t\tscanf(\"%d %d\",&x,&y);\n\t}while (x<0 && x>(int)pow(10,9) && y<0 && y>(int)pow(10,9));\n\tif (g(x,y)) printf(\"Yes\");\n\telse printf(\"No\");\n\n}\n\n\nvoid f(int* x,int* y){\n\t*x=*x+1;\n\t*y=*y+1;\n}\n\nbool g(int x,int y){\n\tint i,j,x0=0,y0=1;\n\tfor (i=1;i<y;i++) f(&x0,&y0);\n    if(x0==x && y0==y) return true;\n    else{\n    for (j=x0;j<=x/2+1;j++){\n\t\t   x0+=2;\n\t\t   if (x0==x) return true;\n\t\t}\n       }\n    return false;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8a88eb4eb83b89588abb6432bedae6c4", "src_uid": "1527171297a0b9c5adf356a549f313b9", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,k;\n    scanf(\"%d %d\",&n,&k);\n    if(n==0 || k==0 || k-1>x){\n        printf(\"No\\n\");\n    }\n    else if((k-1)%2==0){\n        printf(\"Yes\\n\");\n    }\n    else{\n        printf(\"No\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c4eeee3b3c5684342cdd9db21400f181", "src_uid": "1527171297a0b9c5adf356a549f313b9", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint x,y;\nwhile(~scanf(\"%d %d\",&x,&y))\n{\n    if(y==1&&x>0||y==0)\n        printf(\"No\\n\");\n    else\n    {\n    int t=y-1;\n    if((x-t)%2==0&&x-t>=0)\n    {\n        printf(\"Yes\\n\");\n    }\n    else\n        printf(\"No\\n\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0654c181eb2ae73c0d86187807899d7c", "src_uid": "1527171297a0b9c5adf356a549f313b9", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <iostream>\nusing namespace std;\nint main()\n{\n    int n,k;\n    scanf(\"%d%d\",&n,&k);\n    int maxi=-1;\n    while(n--)\n    {\n        int temp;\n        scanf(\"%d\",&temp);\n        \n        if(k%temp==0 && temp>maxi)\n        {\n            maxi=temp;\n        }\n    }\n    \n    printf(\"%d\\n\",k/maxi);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1d2436a44f7582c6821b93f92c5fd2ae", "src_uid": "80520be9916045aca3a7de7bc925af1f", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{ int n,m,i,b[100],x,p=0;\n    scanf(\"%d\",&n);\n    scanf(\"%d\",&m);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&b[i]);\n    }\n    for(i=0;i<n;i++)\n    {\n        if(m%b[i]==0)\n        {\n            s=b[i];\n        }\n    }\n    p=m/s;\n    printf(\"%d\",p);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a123493923e9f1fdbd4fc61c54c2fd01", "src_uid": "80520be9916045aca3a7de7bc925af1f", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include <stdlib.h>\nint main() {\n    int n, k;\n    int* bucket;\n    int i, input;\n    int choose=0;\n    scanf_s(\"%d %d\", &n, &k);\n    bucket = (int*)malloc(sizeof(int) * n);\n    for (i = 0; i < n; i++) {\n        scanf_s(\"%d\", &input);\n        bucket[i] = input;\n    }\n    for (i = 0; i < n; i++) {\n        if (k % bucket[i]==0) {\n            if (bucket[i] > choose) {\n                choose = bucket[i];\n            }\n        }\n    }\n    printf(\"%d\", k / choose);\n    free(bucket);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5a40fb14976ef92129381fec9d239a79", "src_uid": "80520be9916045aca3a7de7bc925af1f", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n\tint a, b, c, d,m,n,o,p,i,j,k,l, first[10][10], second[10][10], multiply[10][10], sum=0;\n\tprintf(\"please enter the row and column number of First matrix: \\n\");\n\tscanf_s(\"%d %d\", &m, &n);\n\tprintf(\"please enter value First matrix: \\n\");\n\n\tfor (i = 0; i < m; i++)\n\t{\n\t\tfor (j = 0; j < n; j++)\n\t\t{\n\t\t\tscanf_s(\"%d\",&first[i][j]);\n\t\t}\n\t}\n\tXXX: printf(\"please enter the row and column number of Second matrix: \\n\");\n\tscanf_s(\"%d %d\", &o, &p);\n\tif (n != o)\n\t{\n\t\tprintf(\"does not follow the matrix rules of 1st matrics column equal to 2nd metrics row\\n\");\n\t\tgoto XXX;\n\n\t}\n\telse \n\t{\n\t\tprintf(\"please enter value Second matrix: \\n\");\n\n\t\tfor (k = 0; k < o; k++)\n\t\t{\n\t\t\tfor (l = 0; l < p; l++)\n\t\t\t{\n\t\t\t\tscanf_s(\"%d\",&second[k][l]);\n\t\t\t}\n\t\t}\n\t}\n\tfor (a = 0; a < m; a++)\n\t{\n\t\tfor (b = 0; b < p; b++)\n\t\t{\n\t\t\tfor (c = 0; c < n; c++)\n\t\t\t{\n\t\t\t\tsum = sum + first[a][c] * second[c][b];\n\t\t\t}\n\t\t\tmultiply[a][b] = sum;\n\t\t\tsum = 0;\n\t\t}\n\t}\n\tprintf(\"The result matrix is: \\n\");\n\n\tfor (a = 0; a < m; a++)\n\t{\n\t\tfor (b = 0; b < p; b++)\n\t\t{\n\t\t\tprintf(\"%d\\t\", multiply[a][b]);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0fe1d88839891c8e6e0946d4058b52ee", "src_uid": "80520be9916045aca3a7de7bc925af1f", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#includ<stdio.h>\n\nvoid main()\n{\n    int max=1;\n    int x,y;\n    int tab[100]\n    \n    scanf(\"%d\"&x);\n    scanf(\"%d\"&y);\n    for(int i=0;i<x;i++)\n    {\n        scanf(\"%d\"&tab[i]);\n        if(tab[i]%y==0&&tab[i]>max)\n            max=tab[i];\n        \n    }\n    printf(\"%d\"y/x);\n    \n    \n    \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3319421a3b4f4c80b77a28910ce617bc", "src_uid": "80520be9916045aca3a7de7bc925af1f", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nchar board[8][8];\nint rows,columns;\nint main{\n    rows=0;\n    columns=0;\n    int i=-1,j=-1;\n    for(;++i<8;scanf(\"%s\", board[i]));\n    for(i=-1;++i<8;){\n        int a=1;\n        for(j=-1;++j<8;)  if(board[i][j] == 'W')a=0;\n        if(a) rows++;\n    }\n    for(i=-1;++i<8;){\n        int a=1;\n        for(j=-1;++j<8;)  if(board[j][i] == 'W')a=0;\n        if(a) columns++;\n    }\n    printf(\"%d\", (columns>rows?columns:rows)<8?columns+rows:8);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fcdf4648b44dc359a448ca7dbd233d4f", "src_uid": "8b6ae2190413b23f47e2958a7d4e7bc0", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int r=8,c=8,count=0,i,j;\n    char a[100];\n    for(int i=0;i<r;i++)\n    {\n        for(int j=0;j<c;j++)\n        {\n            scanf(\"%c\",a[i][j]);\n        }\n    }\n    for(int j=0;j<c;j++)\n    {\n        i=0;\n        if(a[i][j]=='B')\n        count++;\n    }\n    if(count<8)\n    {\n        for(int i=1;i<r;i++)\n        {\n            j=0;\n            if(a[i][j]=='B')\n            count++;\n        }\n        printf(\"%d\",count);\n    }\n    else\n    printf(\"8\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "85066632fa610a067d3514880270c0a1", "src_uid": "8b6ae2190413b23f47e2958a7d4e7bc0", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdbool.h>\n\nbool board[8][8];\nbool newBoard[8][8];\n\nint main() {\n    char buf[9];\n    for(int i = 0; i < 8; i++) {\n        scanf(\"%s\", buf);\n        for(int j = 0; j < 8; j++) {\n            if(buf[j] == 'B')\n                board[i][j] = true;\n        }\n    }\n    \n    int total = 0;\n    for(int i = 0; i < 8; i++) {\n        int cnt = 0;\n        for(int j = 0; j < 8; j++) {\n            if(boar[i][j]) {\n                cnt++;\n                \n                \n            }\n        }\n        if(cnt == 8) {\n            total++;\n            for(int k = 0; k < 8; k++) {\n                newBoard[i][k] = true;\n            }\n            \n        }\n    }\n    for(int j = 0; j < 8; j++) {\n        for(int i = 0; i < 8; i++) {\n            if(board[i][j] != newBoard[i][j]) {\n                total++;\n                break;\n            }\n        }\n    }\n    printf(\"%d\", total);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a277b72602bd032810637e34a0d32a35", "src_uid": "8b6ae2190413b23f47e2958a7d4e7bc0", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nchar board[8][8];\nint rows,columns;\nint main{\n    rows=0;\n    columns=0;\n    int i=0,j=0;\n    for(i=0;i<8;scanf(\"%s\", board[i]), i++);\n   \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b837168c81751ec2274843c1c4d02417", "src_uid": "8b6ae2190413b23f47e2958a7d4e7bc0", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "\n#include <stdio.h>\nchar t[9][9] , lin[9];\nint n = 8, i , j, alb,count = 0;\nint main()\n{\nfor(i = 1; i <= n; i++)\n{\n    scanf(\"%s\",&lin);\n    for(j = 1; j <=n;j++)\n    {\n        t[i][j] = lin[j-1];\n    }\n}\nfor(i = 1; i <= n; i++)\n{\n    alb = 0;\n    for(j = 1; j <= n; j++)\n    {\n        if(t[i][j] == 'W') alb++;\n    }\n    if(alb == 0)count++;\n}\nfor(j = 1; j <= n; j++)\n{\n    alb = 0;\n    for(i = 1; i <= n; i++)\n    {\n        if(t[i][j] == 'W') alb++;\n    }\n    if(alb == 0)count++;\n}\nif(count < 2*n)\n{\nprintf(\"%d\",count);\n{else{\n    printf(\"%d\",count/2);\n}\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0d2c56077babad1701fdc63f1e2f804f", "src_uid": "8b6ae2190413b23f47e2958a7d4e7bc0", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n_int64 a[120];\nmain()\n{\n\t_int64 n,m,i,last;\n\tscanf(\"%I64d%I64d\",&n,&m);\n\tfor(i=1;i<=n;i++)\n\t\tscanf(\"%I64d\",&a[i]);\n\tfor(i=1,last=0;i<=n;i++)\n\t{\n\t\tif(a[i]>m)\n\t\t{\n\t\t\tlast=i;\n\t\t}\n\t}\n\tif(last==0)\n\t\tlast=n;\n\tprintf(\"%I64d\\n\",last);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "733f383cd930fae446dadd574a9cebed", "src_uid": "c0ef1e4d7df360c5c1e52bc6f16ca87c", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main (void)\n{\n\tint n, m, max, temp, last;\n\tscanf(\"%d %d\", &n, &m);\n\tfor(int i = 0; i < n; i ++)\n\t{\n\t\tscanf(\"%d\", &temp);\n\t\ttemp = temp / m + (temp % m != 0 ? 1 : 0);\n\t\tif(temp >= max){ \n\t\t\tmax = temp;\n\t\t\tlast = i;\n\t\t}\n\t}\n\tprintf(\"%d\", last + 1);\n\treturn 0;\n}\n\n\n\t\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "041204bed123e0e64a2461168836861c", "src_uid": "c0ef1e4d7df360c5c1e52bc6f16ca87c", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,m,loc=0,i,x;\n    scanf(\"%d%d\",&n,&m);\n    int a[n];\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        if(a[i]>max)\n            max=a[i];\n    }\n    x=max/m+1;\n    while(x--)\n    {\n        for(i=0;i<n;i++)\n            if(a[i]>0)\n            {\n                a[i]-=m;\n                loc=i;\n            }\n    }\n    printf(\"%d\",loc+1);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1b9829155a928114f55be341b83cc874", "src_uid": "c0ef1e4d7df360c5c1e52bc6f16ca87c", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n\tint n,m,child,a,i,max;\n\tscanf(\"%d %d\",&n,&m);\n\tint arr[n];\n\tchild=n;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\",&arr[i]);\n\t\ta=arr[i]/m;\n\t\tif(ma>max)\n\t\t{\n\t\t\tmax=a;\n\t\t\tchild=i+1;\n\t\t}\n\t}\n\tprintf(\"%d\",child);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8ced37c104c57a3e467ad46e40bb9ae2", "src_uid": "c0ef1e4d7df360c5c1e52bc6f16ca87c", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "A. Jzzhu and Children\ntime limit per test1 second\nmemory limit per test256 megabytes\ninputstandard input\noutputstandard output\nThere are n children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to n. The i-th child wants to get at least ai candies.\n\nJzzhu asks children to line up. Initially, the i-th child stands at the i-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:\n\nGive m candies to the first child of the line.\nIf this child still haven't got enough candies, then the child goes to the end of the line, else the child go home.\nRepeat the first two steps while the line is not empty.\nConsider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?\n\nInput\nThe first line contains two integers n,\u2009m (1\u2009\u2264\u2009n\u2009\u2264\u2009100; 1\u2009\u2264\u2009m\u2009\u2264\u2009100). The second line contains n integers a1,\u2009a2,\u2009...,\u2009an (1\u2009\u2264\u2009ai\u2009\u2264\u2009100).\n\nOutput\nOutput a single integer, representing the number of the last child.\n\nExamples\ninputCopy\n5 2\n1 3 1 4 2\noutputCopy\n4\ninputCopy\n6 4\n1 1 2 2 3 3\noutputCopy\n6\nNote\nLet's consider the first sample.\n\nFirstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.\n\nChild 4 is the last one who goes home.", "lang_cluster": "C", "compilation_error": true, "code_uid": "8c1d626f8f2cc240e5c6fab01ed94eab", "src_uid": "c0ef1e4d7df360c5c1e52bc6f16ca87c", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\nlong int main()\n{\n  long   long int a,b;\n     scanf(\"%I64d\\n\",&a);\n     scanf(\"%I64d\",&b);\nlong     long int c=a+b;\n    long long int i,j,k=0,l,p,q,t,mod;\n     i=a,p=0,t=0,j=b,l=0,q=0;\n     while(i>0)\n     {\n          mod=i%10;\n          if(mod!=0)\n          {\n            p+=mod*pow(10,t);\n            t++;\n          }\n          i/=10;\n     }\n     \n     while(j>0)\n     {\n          mod=j%10;\n          if(mod!=0)\n          {\n               q+=mod*pow(10,l);\n               l++;\n          }\n          j/=10;\n     }\n   long  long int u=c,m;\n    long long int w=0;\n     while(u>0)\n     {\n          mod=u%10;\n          if(mod!=0)\n          {\n               w+=mod*pow(10,k);\n               k++;\n          }\n          u/=10;\n     }\n     m=p+q;\n     if(w==m\n     printf(\"YES\");\n     else \n     printf(\"NO\");\n     return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b2d5b0fa07b7f7e12c2f26b403bcdde1", "src_uid": "ac6971f4feea0662d82da8e0862031ad", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n#include <cmath>\nusing namespace std;\n\nunsigned long long int A(unsigned long long int a)\n{\n\tunsigned long long b, c;\n\n\tb = 0;\n\tc = 0;\n\twhile (a) {\n\t\tif (a % 10)\n\t\t\tb = a % 10 * pow(10, c++) + b;\n\t\ta /= 10;\n\t}\n\n\treturn b;\n}\n\nint main()\n{\n\tunsigned long long a, b;\n\n\tcin >> a >> b;\n\tif (A(a + b) == A(a) + A(b))\n\t\tcout << \"YES\" << endl;\n\telse\n\t\tcout << \"NO\" << endl;\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f77b3028aa5dd6d3546cb1af343c5f66", "src_uid": "ac6971f4feea0662d82da8e0862031ad", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main() {\n  /*two integers read into a char array!*/\n  char a[10];\n  char b[10];\n  scanf(\"%s\",a);\n  scanf(\"%s\",b);\n  int na=strlen(a);\n  int nb=strlen(b);\n  int i,j,k;\n  for(k=0;k<na;k++) {\n    a[k]=a[k]-'0';\n  }\n  \n  for(k=0;k<nb;k++) {\n    b[k]=b[k]-'0';\n  }\n    int find_zero=0;\n  for(i=0;i<na;i++) {\n    if(a[i]==0) {find_zero=1; break;}\n  }\n  /*one piece code do one thing.*/\n  for(i=0;i<nb;i++) {\n    if(b[i]==0) {find_zero=1;break;}\n  }\n  int more10=0;\n  /*\u4fdd\u8bc1i\u6bd4j\u5927*/\n  if(na>nb) {\n    i=na-1;\n    j=nb-1;\n  } else {\n    i=nb-1;\n    j=na-1;\n  }\n  \n  while(1) {\n    /*\u6ca1\u6709\u8fdb\u4f4d\u5c31\u53ef\u4ee5\u4fdd\u8bc1\u76f8\u540c\uff0c\u8fd9\u662f\u5728\u6709\u96f6\u7684\u60c5\u51b5\u4e0b\u6210\u7acb*/\n    if(a[i]+b[j]>=10){\n      more10=1;\n      if(j==0) { last_more10=1; break; }\n      else a[i-1]+=(a[i]+b[j])/10;\n    }\n    i--;\n    j--;\n  }\n\n    if(find_zero) {\n      if(more10) printf(\"NO\\n\");\n      else printf(\"YES\\n\");\n    }else {\n      if(last_more10) {\n        printf(\"NO\\n\");\n      } else printf(\"YES\\n\");\n  }\n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1aa35c74a9284566f3ae4f9d6e876161", "src_uid": "ac6971f4feea0662d82da8e0862031ad", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n    long a, b, n1, m1, n2, m2, a1, b1, t=0;\n    scanf(\"%ld\",&a);\n    scanf(\"%ld\",&b);\n    a1=a;\n    b1=b;\n    do\n    {\n        a1=a1/10;\n        b1=b1/10;\n        t++;\n    }while(a1!=0 && b1!=0);\n    for(i=0;i<t;i++)\n    {\n        n1=a%10;\n        m1=b%10;\n        a=a/10;\n        b=b/10;\n        n2=a%10;\n        m2=b%10;\n        if(n2==0 && m2==0)\n        {\n            if(n1+m1>=10)\n            {\n                printf(\"NO\");\n                return 0;\n            }\n        }\n        if(n1==0 && m1!=0)\n        {\n            printf(\"NO\");\n            return 0;\n        }\n        if(n1!=0 && m1==0)\n        {\n            printf(\"NO\");\n            return 0;\n        }\n    }\n    printf(\"YES\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2acb1b43a8683d3adbebd456046a1853", "src_uid": "ac6971f4feea0662d82da8e0862031ad", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\nint main()\n{\n  long   long int a,b;\n     scanf(\"%I64d\\n\",&a);\n     scanf(\"%I64d\",&b);\nlong     long int c=a+b;\n    long long int i,j,k=0,l,p,q,t,mod;\n     i=a,p=0,t=0,j=b,l=0,q=0;\n     while(i>0)\n     {\n          mod=i%10;\n          if(mod!=0)\n          {\n            p+=mod*pow(10,t);\n            t++;\n          }\n          i/=10;\n     }\n     \n     while(j>0)\n     {\n          mod=j%10;\n          if(mod!=0)\n          {\n               q+=mod*pow(10,l);\n               l++;\n          }\n          j/=10;\n     }\n   long  long int u=c;\n    long long int w=0,u;\n     while(u>0)\n     {\n          mod=u%10;\n          if(mod!=0)\n          {\n               w+=mod*pow(10,k);\n               k++;\n          }\n          u/=10;\n     }\n     if(w==(p+q))\n     printf(\"YES\");\n     else \n     printf(\"NO\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a40fb6c194203cf078c805ddd56784c9", "src_uid": "ac6971f4feea0662d82da8e0862031ad", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{ \n        int n,p=0;\n        char s[100];\n        scanf(\"%d\",&n);\n        scanf(\"%s\",s);\n        for(j=0;s[j]!='\\0';j++)\n        {\n             if(s[j]='x'&&s[j+1]=='x'&&s[j+2]=='x')\n             {\n                   p=p+1;\n             }\n        }\n        printf(\"%d\",p);\n        return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2da715af023d9610e87663e003c28e2f", "src_uid": "8de14db41d0acee116bd5d8079cb2b02", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n\tint i,k,j,temp,net=0,n;char s[120];int a[120]={0},b[20]={0};\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<=n;i++)\n\tscanf(\"%c\",&s[i]);\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tj=i;\n\t\twhile (j<=n)\n\t\t{\n\t\t\tif (s[i]==s[j] && s[j]=='x')\n\t\t\t{\n\t\t\t\ta[i]++;j++;\n\t\t\t}\n\t\t\telse\n\t\t\tbreak;\n\t\t}\n\t}k=1;\n\tfor(j=1;j<=n-1;j++)\n\t{\n\t\tfor(i=1;i<=n-1;i++)\n\t\tif (a[i]>a[i+1])\n\t\t{\n\t\t\ttemp=a[i];a[i]=a[i+1];a[i+1]=temp;\n\t\t}\n\t}k=1;\n\tfor(j=1;j<=n;j++)\n\t{\n\t\tprintf(\"\\n%d\",a[j]);\n\t\tif (a[j]>2)\n\t\tnet++;\n\t}\n\t\n\t{\n\tprintf(\"0\");\n    }\n    else\n    printf(\"%d\",net);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "aeee35e5deb81229bcf8e75d44f75e48", "src_uid": "8de14db41d0acee116bd5d8079cb2b02", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "include<stdio.h>\n#include<string.h>\nint main()\n{\n    int n,i;\n    scanf(\"%d\",&n);\n    int sum=0;\n    int c=0;\n    char str[101];\n    scanf(\"%s\",&str);\n    for(i=0;i<n;i++)\n    {\n        if(str[i]=='x')\n        {\n            c++;\n            if(c>=3)\n            {\n                sum++;\n            }\n        }\n        else\n        {\n            c=0;\n            continue;\n        }\n    }\n    printf(\"%d\",sum);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "22a109c7fe4ee7db93fe9364b02ce9fc", "src_uid": "8de14db41d0acee116bd5d8079cb2b02", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint tmp,l,co=0,d,co1=0;\n\tchar ch;\n\tscanf(\"%d\\n\",&l);\n\ttmp=l;\n\tfor(int i=0;i<l;i++)\n\t{\n\t\tscanf(\"%c\",&ch);\n\t\tif(ch=='x&)\n\t\t{\n\t\t\t++co;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tco=0;\n\t\t}\n\t\tif(co>=3)\n\t\t{\n\t\t\tco1++;;\n\t\t}\n\t\t\n\t}\n\tprintf(\"%d\",co1);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a004a35849e77035a6ba4a42cce3f895", "src_uid": "8de14db41d0acee116bd5d8079cb2b02", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n\tint n,c=0;\n\tscanf(\"%d\",&x);\n\tchar s[n];\n\tscanf(\"%s\",s);\n\tfor(int i=0;i<=(n);i++ ){\n\t\tif(s[i]=='x'&&s[i+1]=='x'&&s[i+2]=='x'){\n\t\t\tc=c+1;\n\t\t}\n\t}\n\tprintf(\"%d\",c);\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1dab5c08ea4a5bc2367032fd913ffb50", "src_uid": "8de14db41d0acee116bd5d8079cb2b02", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<iostream>\n#include<stdlib.h>\nint main()\n{\nint a,b,c1,c2;\nscanf(\"%d%d\",&a,&b);\nint c,d,e,f,g,h;\nc=d=e=f=g=h=0;\nwhile(a!=0)\n{\nif(a%2==0)\n{\nc++;\na=a/2;\n}\nelse if(a%3==0)\n{\nd++;\na=a/3;\n}\nelse if(a%5==0)\n{\ne++;\na=a/5;\n}\nelse\n{\nc1=a;\nbreak;\n}\n}\nwhile(b!=0)\n{\nif(b%2==0)\n{\nf++;\nb=b/2;\n}\nelse if(b%3==0)\n{\ng++;\nb=b/3;\n}\nelse if(b%5==0)\n{\nh++;\nb=b/5;\n}\nelse\n{\nc2=b;\nbreak;\n}\n}\nif(c1!=c2)\nprintf(\"-1\\n\");\nelse\n{\nint ans=abs(c-f)+abs(d-g)+abs(e-h);\nprintf(\"%d\\n\",ans);\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "de0ee7bbef6368a71dba3164b7081cf9", "src_uid": "75a97f4d85d50ea0e1af0d46f7565b49", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long gcd(long long a,long long b)\n{\n\tif(b==0)\n\treturn a;\n\telse\n\treturn gcd(b,a%b);\n}\nlong long maxi(long long a,long long b)\n{\n\tif(a>b)\n\treturn  a;\n\telse\n\treturn b;\n}\nint main()\n{\n\tlong long a,b,x,y,z,c1=0,c2=0;\n\tint f=0;\n\tscanf(\"%lld%lld\",&a,&b);\n\tx=gcd(a,b);\n\ty=a/x;\n\tz=b/x;\n\twhile(y!=1)\n\t{\n\t\tif(y%2!=0&&y%5!=0&&y%3!=0)\n\t\t{\n\t\t\t//printf(\"A %d\\n\",y);\n\t\t\tf=1;\n\t\t\tbreak;\n\t\t}\n\t\tif(y%2==0)\n\t\t{\n\t\t\tc1++;\n\t\t\ty=y/2;\n\t\t}\n\t\tif(y%3==0)\n\t\t{\n\t\t\tc1++;\n\t\t\ty=y/3;\n\t\t}\n\t\tif(y%5==0)\n\t\t{\n\t\t\tc1++;\n\t\t\ty=y/5;\n\t\t}\n\t}\n\twhile(z!=1)\n\t{\n\t\tif(z%2!=0&&z%5!=0&&z%3!=0)\n\t\t{\n\t\t\tf=1;\n\t\t\tbreak;\n\t\t}\n\t\tif(z%2==0)\n\t\t{\n\t\t\tc1++;\n\t\t\tz=z/2;\n\t\t}\n\t\tif(z%3==0)\n\t\t{\n\t\t\tc1++;\n\t\t\tz=z/3;\n\t\t}\n\t\tif(z%5==0)\n\t\t{\n\t\t\tc1++;\n\t\t\tz=z/5;\n\t\t}\n\t}\n\tif(f==1)\n\tprintf(\"-1\\n\");\n\telse\n\tprintf(\"%lld\\n\",c1);\n\tretrun 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f92049aa87a9544aac1c23d3627a2b7d", "src_uid": "75a97f4d85d50ea0e1af0d46f7565b49", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "int oeration(int a, int b)\n{\n    int op=0 ; \n    int a1=-1 , a2=-1;\n    if(a==b)\n    {\n        return 0;\n    }\n    while(a!=b)\n    {\n        if(a>b)\n        {\n            if(!(a%2))\n            {\n                a/=2;\n                op++;\n            }\n            else if(!(a%3))\n            {\n                a/=3;\n                op++;\n            }\n            else if(!(a%5))\n            {\n                a/=5;\n                op++;\n            }\n            else\n            {\n                a1=1;\n            }\n        }\n        if(a<b)\n        {\n            if(!(b%2))\n            {\n                b/=2;\n                op++;\n            }\n            else if(!(b%3))\n            {\n                b/=3;\n                op++;\n            }\n            else if(!(b%5))\n            {\n                b/=5;\n                op++;\n            }\n            else\n            {\n                a2=1;\n            }\n        }\n        if(a1==1 && a2==1 && a!=b)\n        {\n            return -1 ;\n        }\n    }\n    return op ;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4d7227645fbfdde378b068c7120cd7c2", "src_uid": "75a97f4d85d50ea0e1af0d46f7565b49", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <conio.h>\n\nlong long int GCD(long long int p, long long int q)\n{\n    if (p%q == 0) return q;\n    return GCD(q, p%q);\n}\n\nint main()\n{\n    long long int a, b, steps = 0, c, x=0;\n    scanf_s(\"%lld %lld\", &a, &b);\n\n    if (a == b) { printf(\"0\"); _getch(); return 0; }\n\n    c = GCD(a, b);\n    while (a != c){\n        if (a % 2 == 0 && (a / 2) % c == 0) a /= 2;\n        else if (a % 3 == 0 && (a / 3) % c == 0) a /= 3;\n        else if (a % 5 == 0 && (a / 5) % c == 0) a /= 5;\n        else { x=1; break; }\n        steps++;\n    }\n    \n    if (x) { printf(\"-1\"); _getch(); return 0; }\n    else {\n        while (b != c){\n            if (b % 2 == 0 && (b / 2) % c == 0) b /= 2;\n            else if (b % 3 == 0 && (b / 3) % c == 0) b /= 3;\n            else if (b % 5 == 0 && (b / 5) % c == 0) b /= 5;\n            else { x = 1; break; }\n            steps++;\n        }\n    }\n\n    if (x) { printf(\"-1\"); _getch(); return 0; }\n    else printf(\"%lld\", steps);\n    _getch();\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f0e13dc67ef1db6c9980bc017b0f3f86", "src_uid": "75a97f4d85d50ea0e1af0d46f7565b49", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint gcd(int a, int b){\n        while((a%=b)&&(b%=a));\n        return a+b;\n}\nint main(){\n        int a,b,tmp,cnt=0;\n        scanf(\"%d%d\",&a,&b);\n        tmp=gcd(a,b);\n        a/=tmp,b/=tmp;\n        while(!(a%2))a/=2,cnt++;\n        while(!(b%2))b/=2,cnt++;\n        while(!(a%3))a/=3,cnt++;\n        while(!(b%3))a/=3,cnt++;\n        while(!(a%5))a/=5,cnt++;\n        while(!(a%5))a/=5,cnt++;\n        if(a+b>2)puts(\"-1\");\n        else printf(\"%d\",cnt);\n\n        return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e5ceaa9b4169a0b4ee56a42743d61a6d", "src_uid": "75a97f4d85d50ea0e1af0d46f7565b49", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,a,b,c;\n    scanf(\"%d %d %d %d\"&n,&a,&b,&c);\n    int i=0,j=0,temp=0,flag=0;\n    for(i=0;i<=n;i++)\n    {\n        for(j=0;j<=n;j++)\n        {\n            if(i*a+j*b<=n)\n            {\n                if((n(i*a+j*b))%c==0)\n                {\n                    flag=i+j+(n-(i*a+j*b))/c;\n                    if(flag>temp && flag!=0)\n                    {\n                        temp=flag;\n                    }\n                }\n            }\n        }\n    }\n    printf(\"%d\",temp);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2c955e640aae6ca4a2b35cb19ba0935b", "src_uid": "062a171cc3ea717ea95ede9d7a1c3a43", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n \nint main(void) \n{\nint n,a,b;\nscanf(\"%d %d %d %d\", &n, &a, &b, &c);\nint x = n/a;\nint y = n/b;\nint k;\nint max = 0;\nint temp;\nfor (int i =0; i <= x; i++)\n{\nfor (int j = 0; j <= y; j++)\n{\nk = (n -a*i - b*j) / c;\nif (a*i + b*j + k*c == n && k >= 0)\n{\ntemp = i + j +k;\nif (temp > max)\n{\nmax = temp;\n}\n}\n}\nprintf(\"%d\", max);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f4068f305e4b63af6bdd82e5f86b80ae", "src_uid": "062a171cc3ea717ea95ede9d7a1c3a43", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n,a,b,c;\n    scanf(\"%d %d %d %d,&n,&a,&b,&c\");\n    int i=0,j=0,temp=0,flag=0;\n    for(i=0;i<=n;i++){\n        for(j=0;j<=n;j++){\n            if(i*a+j*b<=n){\n                if((n-(i*a+j*b))%c==0){\n                    flag = i+j+(n-(i*a+j*b))/c;\n                    if(flag>temp&&flag!=0){\n                        temp=flag;\n                    }\n                }\n            }\n        }\n    }\n    printf(%d,temp);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dd0bc152f153c355020c785c405879a9", "src_uid": "062a171cc3ea717ea95ede9d7a1c3a43", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <iostream>\n#include <vector>\nusing namespace std;\n\nint main()\n{\n    int n, a, b, c;\n    scanf(\"%d\", &n);\n    scanf(\"%d\", &a);\n    scanf(\"%d\", &b);\n    scanf(\"%d\", &c);\n\n    // cout << a << b << c << std::endl;\n\n    std::vector<int> pieces;\n    pieces.resize(n + 1, 0);\n    pieces[a] = 1;\n    pieces[b] = 1;\n    pieces[c] = 1;\n    for (int i = 0; i <= n; i++)\n    {\n        // if (i < a && i < b && i < c) continue;\n\n        if (i - a >= 0 && pieces[i - a] != 0)\n            pieces[i] = std::max(pieces[i], pieces[i - a] + 1);\n        if (i - b >= 0 && pieces[i - b] != 0)\n            pieces[i] = std::max(pieces[i], pieces[i - b] + 1);\n        if (i - c >= 0 && pieces[i - c] != 0)\n            pieces[i] = std::max(pieces[i], pieces[i - c] + 1);\n\n        for (int i = 0; i <= n; i++)\n        {\n            std::cout << pieces[i] << \" \";\n        }\n        std::cout << std::endl;\n    }\n    // std::cout << pieces[n] << std::endl;\n    printf(\"%d\", pieces[n]);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7bc2d39fe6558e688fc0f5e84e4490dc", "src_uid": "062a171cc3ea717ea95ede9d7a1c3a43", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n//#include <iostream>\n#include <vector>\nusing namespace std;\n\nint main()\n{\n    int n, a, b, c;\n    scanf(\"%d\", &n);\n    scanf(\"%d\", &a);\n    scanf(\"%d\", &b);\n    scanf(\"%d\", &c);\n\n    // cout << a << b << c << std::endl;\n\n    std::vector<int> pieces;\n    pieces.resize(n + 1, 0);\n    pieces[a] = 1;\n    pieces[b] = 1;\n    pieces[c] = 1;\n    for (int i = 0; i <= n; i++)\n    {\n        // if (i < a && i < b && i < c) continue;\n\n        if (i - a >= 0 && pieces[i - a] != 0)\n            pieces[i] = std::max(pieces[i], pieces[i - a] + 1);\n        if (i - b >= 0 && pieces[i - b] != 0)\n            pieces[i] = std::max(pieces[i], pieces[i - b] + 1);\n        if (i - c >= 0 && pieces[i - c] != 0)\n            pieces[i] = std::max(pieces[i], pieces[i - c] + 1);\n\n        /*\n        for (int i = 0; i <= n; i++)\n        {\n            std::cout << pieces[i] << \" \";\n        }\n        std::cout << std::endl;\n        */\n    }\n    // std::cout << pieces[n] << std::endl;\n    printf(\"%d\", pieces[n]);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f7386cf47c5b8ca987d99a3a4ae37f77", "src_uid": "062a171cc3ea717ea95ede9d7a1c3a43", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main()\n{\n\n    char ch[3];\n    gets(ch);\n\n    if((ch[1]== '8')||(ch[1]=='1'))\n    {\n        if((ch[0] =='a')||(ch[0] =='h'))\n        {\n            printf(\"3\");\n        }\n        else\n        {\n         printf(\"5\");\n        }\n\n    }\n    else if((ch[0] =='a')||(ch[0] =='h'))\n    printf(\"5\");\n    else printf(\"8\");\n         \n\n    }\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5b246e92a408f0a97c578ab2164f8447", "src_uid": "6994331ca6282669cbb7138eb7e55e01", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    char a[10];\n    scanf(\"%s\",a);\n    if(((a[0]=='a' || a[0]=='h')&& a[1]=='1')|| ((a[0]=='a' || a[0]=='h') && a[1]=='8')) || a==\"h8\"))\n    {\n        printf(\"3\");\n    }\n    else if((a[0]>=98 && a[0]<=103 && a[1]==1) || (a[0]>=98 && a[0]<=103 && a[1]==8))\n        printf(\"5\");\n    else\n        printf(\"8\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ea095da4d810c3b595b18769426dad05", "src_uid": "6994331ca6282669cbb7138eb7e55e01", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    char a[10];\n    scanf(\"%s\",a);\n    if(a==\"a1' || a==\"h1\" || a==\"a8\" || a==\"h8\")\n        printf(\"3\");\n    else if((a[0]>=98 && a[0]<=103 && a[1]==1) || (a[0]>=98 && a[0]<=103 && a[1]==8))\n        printf(\"5\");\n    else\n        printf(\"8\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "02bf84254e997a8c74a7ddadaf40bf63", "src_uid": "6994331ca6282669cbb7138eb7e55e01", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    char x,y;\n    if(x=='a'||x=='h'&&y=='8'||y=='1')\n    printf(\"3\");\n    else if((x=='a'||x=='h'||y=='8'||y=='1')\n    printf(\"5\");\n    else\n    printf(\"8\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ba13661cdbdd755af655115fce04036e", "src_uid": "6994331ca6282669cbb7138eb7e55e01", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "include<stdio.h>\n#include<string.h>\nint main()\n{\nchar K[2];\nscanf(\"%s\",K);\nif(K[0]>='b' && K[0]<='g' && K[1]>='2' && K[1]<='7')\n{\nprintf(\"8\\n\");\n}\nelse if(((K[0]=='a' || K[0]=='h')  && K[1]>='2' && K[1]<='7') || ((K[1]=='1' || K[1]=='8') && K[0]>='b' && K[0]<='g'))\n{\nprintf(\"5\\n\");\n}\nelse\n{\nprintf(\"3\\n\");\n}\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bfece4560c2e0f4e6ec33285c2273fb6", "src_uid": "6994331ca6282669cbb7138eb7e55e01", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n\tint a,b,n;\n\tscanf(\"%d%d%d\",&a,&b,&n);\n\tint i,j,count;\n\tcount=0;\n\twhile(n>=0)\n\t{\n\t\tcount++;\n\t\tif(count%2!=0)\n\t\t{\n\t\t\tif(a>n){for(j=n;j>=1;j--)if((a%j==0)&&(n%j==0))i=j;}\n\t\t\telse {for(j=1;j<=a;j++)if((a%j==0)&&(n%j==0))i=j;}\t\n\t\t}\n\t\telse\n\t\t{\n\t\t\tif(b>n){for(j=1;j<=n;j++)if((b%j==0)&&(n%j==0))i=j;}\n\t\t\telse {for(j=1;j<=b;j++)if((b%j==0)&&(n%j==0))i=j;}\t\n\t\t}\n\t\tn=n-i;\n\t}\n\tprintf(\"%d\",count%2);\n\treturn 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "980e6cfc9fb0761c6283c54f7501afbd", "src_uid": "0bd6fbb6b0a2e7e5f080a70553149ac2", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n \nint gcd(int m, int n)\n{\n    int r;\n    while ((r = m % n) != 0)\n    {\n        m = n;\n        n = r;\n    }\n    return n;\n}\n \nint main()\n{\n    int a, b, n;\n    scanf(\"%d %d %d\", &a, &b, &n);\n    while (true)\n    {\n        n -= gcd(a, n);\n        if (n == 0)\n        {\n            printf(\"0\");\n            break;\n        }\n        n -= gcd(b, n);\n        if (n == 0)\n        {\n            printf(\"1\");\n            break;\n        }\n    }\n  ", "lang_cluster": "C", "compilation_error": true, "code_uid": "6550d7d5a37720aa2f6acde18f9820af", "src_uid": "0bd6fbb6b0a2e7e5f080a70553149ac2", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": " #include<stdlib.h>\n divisior(int a,int b)\n {\n    int s,i;\n    if(a>b) s=b;\n    else s=a;\n    for(i=s;i>=1;i--)\n    {\n        if(a%i==0&&b%i==0)\n        {\n            break;\n        }\n    }\n    return i;\n }\nmain()\n{\n    int n,a,b,k=0,c=1,d=0;\n    scanf(\"%d %d %d\",&a,&b,&n);\n    //for(;k==0;)\n    //while(k==0)\n    {\n        if(n>divisior(a,n))\n        {\n            printf(\"%d\",c);k=1;\n        }\n     //   else n-=divisior(a,n);\n     //   if(n<divisior(b,n))\n     //   {\n     //       printf(\"%d\",d);k=1;\n     //   }\n     //   else n-=divisior(b,n);\n\n  //  }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "345e7e9edfd159490ed48e3f12356919", "src_uid": "0bd6fbb6b0a2e7e5f080a70553149ac2", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "/*  AUTHOR:AKASH JAIN\n*   USERNAME:akash19jain    \n*   DATE:23/07/2019 \n*/\n#include<stdio.h>\n#include<math.h>\n#include<string.h>\n#include<stdlib.h>\n#include<stdbool.h>\n#define SC1(x)          scanf(\"%lld\",&x)\n#define SC2(x,y)        scanf(\"%lld%lld\",&x,&y)\n#define SC3(x,y,z)      scanf(\"%lld%lld%lld\",&x,&y,&z)\n#define PF1(x)          printf(\"%lld\\n\",x)\n#define PF2(x,y)        printf(\"%lld %lld\\n\",x,y)\n#define PF3(x,y,z)      printf(\"%lld %lld %lld\\n\",x,y,z)\n#define REP(i,n)        for(long long i=0;i<(n);i++)\n#define FOR(i,a,b)      for(long long i=(a);i<=(b);i++)\n#define FORD(i,a,b)     for(long long i=(a);i>=(b);i--)\n#define WHILE(n)\t\twhile(n--)\n#define MEM(a, b)       memset(a, (b), sizeof(a))\n#define ITOC(c)         ((char)(((int)'0')+c))\n#define MID(s,e)        (s+(e-s)/2)\n#define SZ(a)\t\t    strlen(a)\n#define MOD             1000000007\n#define MAX             10000000005\n#define MIN             -10000000005\n#define PI              3.1415926535897932384626433832795\n#define TEST(x)         printf(\"The value of \\\"%s\\\" is: %d\\n\",#x,x)\nconst int INF = 1<<29;\ntypedef long long ll;\ntypedef unsigned long long ull;\n#define FILEIO(name) \\  freopen(name\".in\", \"r\", stdin); \\   freopen(name\".out\", \"w\", stdout);\nint cmp(const void * a,const void * b);\nlong long maxv(long long a,long long b);\nlong long minv(long long a,long long b);\nlong long gcd(long long u,long long v);\n\nint main()\n{\n    ll t=1,i=0;\n    //SC1(t);\n    while(t--)\n    {\n        ll a,b,n;\n        SC3(a,b,n);\n        ll c=0,z=0;\n        while(n>0)\n        {\n            c++;\n            if (c%2==1)\n                z=gcd(a,n);\n            else\n                z=gcd(b,n);\n            n=n-z;\n        }\n        ll q=1;\n        \n        if (c%2==0)\n            PF1(q)\n        else\n            printf(\"0\\n\");\n           \n    }\n}\n \n//qsort(arr,n,sizeof(arr[0]),cmp);\nint cmp (const void * a, const void * b)\n{\n    if( *(ll*)a - *(ll*)b < 0 ) return -1;\n    if( *(ll*)a - *(ll*)b > 0 ) return 1;\n        return 0;\n}\nlong long maxv(long long a,long long b)\n{\n    if(a>b) return a;\n        return b;\n}\nlong long minv(long long a,long long b)\n{\n    if(a<b) return a;\n        return b;\n}\nlong long gcd(long long u,long long v)\n{\n    if (v == 0) return u; \n       return gcd(v, u%v);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "594c0da1eaeafadd549b417a5c8a5698", "src_uid": "0bd6fbb6b0a2e7e5f080a70553149ac2", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint gcd(int a,int n)\n{int i,gcd;\n\tfor(i=1;i<=a;i++)\n\t{\n\t\tif(a%i==0 && n%i==0)\n\t\tgcd=i;\n\t}\n\treturn gcd;\n}\nint main()\n{\n\tint i,a,b,n,win=-1;\n\tscanf(\"%d %d %d\",&a,&b,&n);\n\tfor(i=0;;i++)\n\t{\n\t\tif(i=0 && n<a )\n\t\t{\n\t\t\twin=0;\n\t\t\tbreak;\n\t\t}\n\t\tif(i=0 && n<b)\n\t\t{\n\t\t\twin=1\n\t\t\tbreak;\n\t\t}\n\t\tif(n<a)\n\t{       \n\t        win=1;\n\t\t\tbreak;\n\t}\n\t\tn-=gcd(a,n);\n\t\tif(n<b)\n\t\t{\n\t\t\twin=0;\n\t\t\tbreak;\n\t\t}\n\t\tn-=gcd(b,n);\n\t\t\n\t}\n\tprintf(\"%d\",win);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "20b47d0d6370a543447b42e964de2130", "src_uid": "0bd6fbb6b0a2e7e5f080a70553149ac2", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n\nint count[50];\n\nint minimum(int a, int b)\n{\n    if (a<b)\n    {\n        return a;\n    }\n\n    else\n    {\n        return b;\n    }\n}\n\nint main()\n{\n    char *s;\n    int n;\n    scanf(\"%d\", &n);\n\n    s = (char *)malloc(sizeof(char)*n);\n    scanf(\"%s\", s);\n\n    ///int count[50];\n    ///count[0] = 0;\n\n    int i, j, k;\n\n    for (i=0, k=0; i<=(n-4); i++)\n    {\n            count[k] += minimum(abs(s[i]-65), abs(91 - s[i]));\n            count[k] += minimum(abs(s[i+1]-67), abs(93 - s[i+1]));\n            count[k] += minimum(abs(s[i+2]-84), abs(-58 + s[i+2]));\n            count[k] += minimum(abs(s[i+3]-71), abs(97 - s[i+3]));\n            k++;\n            ///count[k] = 0;\n    }\n\n    int temp = count[0];\n\n    for (i=0; i<k; i++)\n    {\n        temp = minimum(temp, count[i]);\n    }\n\n    printf(\"%d\\n\", temp);\n\n    free(s);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9218a4b28ceff9cfad8c48d0da7d92ad", "src_uid": "ee4f88abe4c9fa776abd15c5f3a94543", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\nint main()\n{\n\tchar s[50];\n\tint n, i, sum = 0, mini = 10000;\n\n\tscanf(\"%d\", &n);\n\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%c\", s[i]);\n\n\tfor (i = 0; i < n - 3; i++) \n\t{\n\n\t\tif (abs(s[i] - 'A')>13)\n\t\t\tsum += 26 - abs(s[i] - 'A');\n\t\telse\n\t\t\tsum += abs(s[i] - 'A');\n\n\t\tif (abs(s[i+1] - 'C')>13)\n\t\t\tsum += 26 - abs(s[i+1] - 'C');\n\t\telse\n\t\t\tsum += abs(s[i+1] - 'C');\n\n\t\tif (abs(s[i+2] - 'T')>13)\n\t\t\tsum += 26 - abs(s[i+2] - 'T');\n\t\telse\n\t\t\tsum += abs(s[i+2] - 'T');\n\n\t\tif (abs(s[i+3] - 'G')>13)\n\t\t\tsum += 26 - abs(s[i+3] - 'G');\n\t\telse\n\t\t\tsum += abs(s[i+3] - 'G');\n\n\t\tif (sum < mini) mini = sum;\n\n\t}\n\n\tprintf(\"%d\\n\", mini);\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "77c768d3ca77166f56d20ced77ac7749", "src_uid": "ee4f88abe4c9fa776abd15c5f3a94543", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n5\nZDATG    int i,n,sum=0,min=50000;\n\tchar c[51];\n\tscanf(\"%d\\n\",&n);\n\tfor(i=0;i<n;i++)\n\tscanf(\"%c\",&c[i]);\n\tfor(i=0;i<n-3;i++)\n\t{ \n\t  sum=0;\n\t  sum+=fabs(c[i]-'A')>=13?26-fabs(c[i]-'A'):fabs(c[i]-'A');\n\t  sum+=fabs(c[i+1]-'C')>=13?26-fabs(c[i+1]-'C'):fabs(c[i+1]-'C');\n\t  sum+=fabs(c[i+2]-'T')>=13?26-fabs(c[i+2]-'T'):fabs(c[i+2]-'T');\n\t  sum+=fabs(c[i+3]-'G')>=13?26-fabs(c[i+3]-'G'):fabs(c[i+3]-'G');\n\t  if(sum<=min)min=sum;\n\t}\n\tprintf(\"%d\",min); \n} ", "lang_cluster": "C", "compilation_error": true, "code_uid": "940eacb75cb81cefb2f62bf13c2e40a7", "src_uid": "ee4f88abe4c9fa776abd15c5f3a94543", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int i,j,m,k,z,o,p,n,r,s,x,y,l;\n    int sum[500];\n    char efa[500];\n    int ok;\n    scanf(\"%d\",&ok);\n    for(i=0; i<ok; i++) scanf(\"%c\",&efa[i])\n    char ara[100];\n    ara[0]='A';\n    for( i=1; i<26*3; i++)\n    {\n        if(ara[i-1]=='Z') {ara[i]='A'; continue;}\n        ara[i]=ara[i-1]+1;\n    }\n    ara[i]='\\0';\nfor(i=0; i<(ok-2);i++){\n    k=0;\n    for(j=0; j<i+4; j++){\n        for(m=ara[26]; m<ara[52]; m++){\n            if(m==efa[j]) {\n                if(k==0){\n                    if(efa[j]=='A') x=0;\n                    else{for(l=j; efa[l]!='A'; l++) x++;\n                         for(l=j; efa[l]!='A'; l--) y++;\n                         if(x>y) x=y;}\n                k++; break;\n                }\n                else if(k==1){\n                    if(efa[j]=='C') z=0;\n                    else{for(l=j; efa[l]!='C'; l++) z++;\n                         for(l=j; efa[l]!='C'; l--) o++;\n                         if(z>o) z=o;}\n                k++; break;\n            }\n               else if(k==2){\n                    if(efa[j]=='T') p=0;\n                    else{for(l=j; efa[l]!='T'; l++) p++;\n                         for(l=j; efa[l]!='T'; l--) n++;\n                         if(p>n) p=n;}\n                k++; break;\n            }\n               else if(k==3){\n                    if(efa[j]=='G') r=0;\n                    else{for(l=j; efa[l]!='G'; l++) r++;\n                         for(l=j; efa[l]!='G'; l--) s++;\n                         if(r>s) r=s;}\n                k++; break;\n            }\n        }\n    }\n}\nsum[i]=x+z+p+r;\n}\n int min=sum[0];\n for(i=1; i<(strlen(efa)-2); i++){\n        if(sum[i]<min) min=sum[i];\n }\n printf(\"%d\\n\",min);\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "568b47773e9452a752a6f098ec3942ea", "src_uid": "ee4f88abe4c9fa776abd15c5f3a94543", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main(){\n    int  temp = 0, n, A[50], C[50], T[50], G[50], i, j, ways[4];\n    char p[50];\n    while(scanf(\"%d\\n\", &n) != 0){\n        for(i=0; i<n; i++){\n          scanf(\"%c\", &p[i]);\n        }\n        for(i=0; i<n; i++){\n\n            if((26-abs(p[i]-'A'))<=abs(p[i]-'A')){\n                A[i] = 26-abs(p[i]-'A');\n            }\n            else{\n                A[i] = abs(p[i]-'A');\n            }\n\n\n            if((26-abs(p[i]-'C'))<=abs(p[i]-'C')){\n                C[i] = 26-abs(p[i]-'C');\n            }\n            else{\n                C[i] = abs(p[i]-'C');\n            }\n\n\n            if((26-abs(p[i]-'T'))<=abs(p[i]-'T')){\n                T[i] = 26-abs(p[i]-'T');\n            }\n            else{\n                T[i] = abs(p[i]-'T');\n            }\n            //for G\n            if((26-abs(p[i]-'G'))<=abs(p[i]-'G')){\n                G[i] = 26-abs(p[i]-'G');\n            }\n            else{\n                G[i] = abs(p[i]-'G');\n            }\n        }\n        for(i=0; i<4; i++){\n            for(j=0; j<(n-4)+1; j++){\n                if(i==j){\n                    ways[j] = A[j] + C[j+1] + T[j+2] + G[j+3];\n                }\n            }\n        }\n        for(i=0; i<4; i++){\n            for(j=i+1; j<4; j++){\n                if(ways[i]>ways[j]){\n                    temp = ways[i];\n                    ways[i] = ways[j];\n                    ways[j] = temp;\n                }\n            }\n        }\n        printf(\"%d\\n\", ways[0]);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ef5b3bc9c6a4dff9938584b78bd3f013", "src_uid": "ee4f88abe4c9fa776abd15c5f3a94543", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "\n  #include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n,k,s=0,i;\n    int tab[100];\n    scanf(\"%d %d\" ,&n ,&k);\n\n    for(i=0;i<n;i++)\n    scanf(\"%d\",&tab[i]);\n\n     for(i=0;i<n;i++){\n            if(tab[i]<=k)\n            s++;\n            else break;\n\n    }\n\n     for(i=n-1;i<=0;i--){\n        if(tab[i]<=k)\n       s++;\n       else break;\n     }\n\nprintf(\"%d\",s);", "lang_cluster": "C", "compilation_error": true, "code_uid": "f9d0ca27fdaaef083782ec2c91057258", "src_uid": "ecf0ead308d8a581dd233160a7e38173", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int i,n,x,p,q,sum=0;\n    scanf(\"%d\",&n);\n    int a[n];\n        for(i=0;i<n;i++){\n        scanf(\"%d\",&a[i]);\n        }\n        for(i=0;i<n;i++){\n            if(a[i]>x){\n                      break;\n                      }                     \n             else{\n             p=p+1;\n             }\n             }\n             for(int j=n-1;j>=0;j--){\n                 if(a[i]>x){\n                 break;\n                 }\n                 }\n                 else{\n                 q=q+1;\n                 }\n                 sum=p+q;\n                 if(p==n){\n                 printf(\"c\");\n                 }\n                 else{\n                 printf(\"sum\");\n                 }\n}\n                           ", "lang_cluster": "C", "compilation_error": true, "code_uid": "2892737e7e405e93b1164b5564052a5d", "src_uid": "ecf0ead308d8a581dd233160a7e38173", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nint n,k,i,j,s;\nint a[100];\ns=0;\nscanf(\"%d\",&n);\nscanf(\"%d\",&k);\nfor(i=0;i<n;i++)\n{\nscanf(\"%d\",&a[i]);\n}\ni=0;\nwhile(a[i]<=k)\n{\ni=i+1;\ns=s+1;\n}\nj=n-1;\nwhile(a[j]<=k && j>=i+1 && i<n-1;)\n{\nj=j-1;\ns=s+1;\n}\nprintf(\"%d\",s);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "94d802ad5449ed97262d23df2c9d2a4d", "src_uid": "ecf0ead308d8a581dd233160a7e38173", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nint n,k,i,j,s;\nint a[100];\ns=0;\nscanf(\"%d\",&n);\nscanf(\"%d\",&k);\nfor(i=0;i<n;i++)\n{\nscanf(\"%d\",&a[i]);\n}\ni=0;\nwhile(a[i]<=k)\n{\ni=i+1;\ns=s+1;\n}\nj=n-1;\nwhile(a[j]<=k && j>=i+1 && i|=n-1)\n{\nj=j-1;\ns=s+1;\n}\nprintf(\"%d\",s);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2ab34bb8ecb72741273379068e14e7d2", "src_uid": "ecf0ead308d8a581dd233160a7e38173", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n   int n,k,g,f=0;\n   scanf(\"%d %d\",&n,&k);\n   int a[n];\n   for (i=0;i<n;i++)\n      scanf(\"%d\",&a[i]);\n   for (int i=0;i<=n;i++)\n     {\n\t\tif (a[i]<=k)\n\t\t   f++;\n\t\telse\n\t       break;  \n\t }\n   for (g=n-1;g>i;g--)\n\t{\n\t\tif (a[g]<=k)\n\t\t   f++; \n\t    else\n\t       break;\n\t}\n\tprintf(\"%d\",f);\n\t   \n\treturn 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a3920566f7537780d1b90a0df4affb9a", "src_uid": "ecf0ead308d8a581dd233160a7e38173", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "{\n    long long int b,count = 0,i;\n    scanf(\"%lld\",&b);\n    if(b==1)\n    {\n        printf(\"1\");\n    }\n    else\n    {\n        for(i=1;i*i<b;i++)\n        {\n            if(b%i==0)\n            count+=2;\n        }\n        if(i*i==b)\n        {\n            count++;\n        }\n        printf(\"%lld\",count);\n        \n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0d597820abf8de84b0e05f36e9fd2d41", "src_uid": "7fc9e7d7e25ab97d8ebc10ed8ae38fd1", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h> \n#include <math.h>\nlong long printDivisors(int n) \n{ \n    long long flag=0;\n    for (int i=1; i<=sqrt(n); i++) \n    { \n        if (n%i == 0) \n        { \n            flag++;\n            if (n/i == i) \n                 \n  \n            else\n                flag++; \n        } \n    } \n    return flag;\n} \n  \nint main() \n{ \n    int b;\n    scanf(\"%d\",&b);\n    printf(\"%d\",printDivisors(b));\n    return 0; \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "08e21190ea91d7b7fba8440c24539882", "src_uid": "7fc9e7d7e25ab97d8ebc10ed8ae38fd1", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main(){\n  long long int b;\n  scanf(\"lld\",&b);\n  long long int count;\n  for(i=1;i<=b;i++){\n    if(b%i==0){\n      count++;\n    }\n\n  }\n  printf(\"lld\",count);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e3b2e9c358cd4b349a6083291558e13d", "src_uid": "7fc9e7d7e25ab97d8ebc10ed8ae38fd1", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main(){\n\tdouble a,b;\n\tscanf(\"%lf\",&b);\n\tif(b==1){\n\t\tprintf(\"1\\n\");\n\t\treturn 0;\n\t}\n\tfor (int i=2;i<=b;i++){\n\t\tif(b%i==0){\n\t\t\tprintf(\"%g\\n\",(log(b)/log(i))+1);\n\t\t\treturn 0;\n\t\t}\n\t}\n} ", "lang_cluster": "C", "compilation_error": true, "code_uid": "a335d4e2355f1415deafd41fc82799b0", "src_uid": "7fc9e7d7e25ab97d8ebc10ed8ae38fd1", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "{\n    long long int b,count = 0,i;\n    scanf(\"%lld\",&b);\n    if(b==1)\n    {\n        printf(\"1\");\n    }\n    else\n    {\n        for(i=1;i*i<b;i++)\n        {\n            if(b%i==0)\n            count+=2;\n        }\n        if(i*i==b)\n        {\n            count++;\n        }\n        printf(\"%lld\",count);\n        \n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d7ef68970ee1f1a3f8ddef87fc7bdc0d", "src_uid": "7fc9e7d7e25ab97d8ebc10ed8ae38fd1", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n, c;\n    n=c;\n    scanf(\"%d\", &n);\n    if(n%2 == 0){\n        printf(\"%d\", n/2);\n    }\n    else if{\n            c=c-1;\n            c=c/2;\n            c=c-n;\n        printf(\"%d\",c);\n    }\n    return 0;\n}\n\n/* 1519483412399 */\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "bca4666208f5d05bef15cf55127b874a", "src_uid": "689e7876048ee4eb7479e838c981f068", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{ int n;\nscanf (\"%d\",&n);\n if (n % 2 == 0)\n    printf (\"%d\",n div 2);\n else\n    printf (\"%d\",((n-1) div 2) -n);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "44cbdcbe9fcb648ee694bb76cef68b10", "src_uid": "689e7876048ee4eb7479e838c981f068", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n   long long int i,n,sum=0;\n   while(scanf(\"%lld\",&n)==1){\n    if(n%2==0){\n        printf(\"%lld\\n\",n/2);\n    }\n    else\n        printf(\"%lld\\n\",-1*(((n+1)/2));\n   }\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f38a81df057bb679bd74924a686db1c5", "src_uid": "689e7876048ee4eb7479e838c981f068", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "int main()\n{\n    unsigned int n, fn, \n    \n    int i;\n    \n    fn = 0;\n    \n    \n    \n    scanf(\" %u\", &n);\n    \n    for(i = 0; i < n; i++)\n    {\n        if(n % 2 == 0)\n        {\n            fn = n/2;\n        }\n        else\n        {\n            fn = (-(n + 1))/2;\n        }\n    }\n    printf(\"%u\\n\", fn);\n    \n    \n    \n    \n    \n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "64642979715c926e57e037d07ede7c37", "src_uid": "689e7876048ee4eb7479e838c981f068", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <iostream>\n\nusing namespace std;\n\nint main(){\n\t\n\tlong long n;\n\tcin >> n;\n\tlong long i;\n\tlong long sum=0;\n\t\n\tfor(i=1; i<=n; i++){\n\t\t\n\t\t\n\t\tif((i%2)==0)\n\t\t\tsum+=i;\n\t\telse\n\t\t\tsum-=i;\n\t\t\n\t}\n\t\n\tcout << sum;\n\t\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d8c3d4d348ac4c33cb300bcef9f04796", "src_uid": "689e7876048ee4eb7479e838c981f068", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    char s[105];\n    long a[6],i,j,k,l,r,b,y,g,n,m;\n    while(scanf(\"%s\",s)==1)\n    {\n        r=y=b=g=0;\n        l=strlen(s);\n        for(i=0;i<=4;i++)\n            a[i]=0;\n        n=l/4;\n        for(i=0;i<l;i++)\n        {\n            if(s[i]=='R')\n            {\n\n                a[0]=a[0]+1;\n                if(a[0]==1)\n                r=i+1;\n\n            }\n            else if(s[i]=='B')\n            {\n\n                a[1]=a[1]+1;\n                if(a[1]==1)\n                b=i+1;\n            }\n            else if(s[i]=='Y')\n            {\n\n               a[2]=a[2]+1;\n               if(a[2]==1)\n               y=i+1;\n            }\n            else if(s[i]=='G')\n            {\n\n                a[3]=a[3]+1;\n                if(a[3]==1)\n                g=i+1;\n            }\n            else if(s[i]=='!')\n                a[4]=a[4]+1;\n        }\n        if(r>0)\n        if(r%4!=0)\n          r=(r%4);\n        else\n          r=4;\n        if(b>0)\n        if(b%4!=0)\n          b=(b%4);\n        else\n          b=4;\n        if(y>0)\n        if(y%4!=0)\n          y=(y%4);\n        else\n          y=4;\n        if(g>0)\n        if(g%4!=0)\n          g=(g%4);\n        else\n          g=4;\n        for(i=0;i<4;i++)\n        {\n            a[i]=n-a[i];\n        }\n        long count1=0;\n        for(i=0;i<4;i++)\n        {\n            if(a[i]>0)\n                count1=count1+a[i];\n        }\n        m=a[4]-count1;\n        if(r<=m)\n            {\n                a[0]=a[0]+1;\n            }\n        if(b<=m)\n        {\n            a[1]=a[1]+1;\n\n        }\n        if(y<=m)\n        {\n            a[2]=a[2]+1;\n        }\n        if(g<=m)\n        {\n            a[3]=a[3]+1;\n        }\n        for(i=0;i<4;i++)\n            if(a[i]<0)\n            a[i]=0;\n\n        for(i=0;i<4;i++)\n        {\n            printf(\"%ld \",a[i]);\n        }\n        printf(\"\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "49a0ec2d485e3a42a6ea42358cde5986", "src_uid": "64fc6e9b458a9ece8ad70a8c72126b33", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#define N 102\nint main() {\n    char s[N];\n    scanf(\"%s\",s);\n    int kr=0,kb=0,ky=0,kg=0;\n    int n=strlen(s);\n    int i;\n    //1111\n    //rbyg\n    int count[N];\n    int position[N];\n    while(1){\n        int find=0;\n        for(i=0;i<n-3;i++){\n            count['R']=0; count['B']=0; count['Y']=0; count['G']=0; count['!']=0;\n            count[s[i]]++; count[s[i+1]]++; count[s[i+2]]++; count[s[i+3]]++;\n            position[s[i]]=i; position[s[i+1]]=i+1; position[s[i+2]]=i+2; position[s[i+3]]=i+3;\n            if(count['!']>0)find=1;\n            if(count['!']==1){\n                if(count['R']==0){ s[position['!']]='R';kr++; }\n                if(count['B']==0){ s[position['!']]='B';kb++; }\n                if(count['Y']==0){ s[position['!']]='Y';ky++; }\n                if(count['G']==0){ s[position['!']]='G';kg++; }\n            }\n        }\n        if(!find)break;\n    }\n    printf(\"%d %d %d %d\\n\",kr,kb,ky,kg);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "89cbae3892ab2f0606348bf127d349b2", "src_uid": "64fc6e9b458a9ece8ad70a8c72126b33", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main ()\n{\n\tint R = 0, B = 0, Y = 0, G = 0, cont = 0, dead[4];\n\tint r = 0, b = 0, y = 0, g = 0;\n\tint i = 0, j, size, aux;\n\tchar s[105];\n\tscanf (\"%s\", s);\n\tsize = strlen (s);\n\twhile (i < (size - 3)) {\n\t\tfor (j = i; j < (i+4); j++) {\n\t\t\tif (s[j] == 'R')\n\t\t\t\tR++;\n\t\t\telse if (s[j] == 'B')\n\t\t\t\tB++;\n\t\t\telse if (s[j] == 'Y')\n\t\t\t\tY++;\n\t\t\telse if (s[j] == 'G')\n\t\t\t\tG++;\n\t\t\telse if (s[j] == '!') {\n\t\t\t\tdead[cont] = j;\n\t\t\t\tcont++;\n\t\t\t}\n\t\t}\n\t\tif (cont == 1) {\n\t\t\taux = dead[0];\n\t\t\tif (R == 0) {\n\t\t\t\tr++;\n\t\t\t\ts[aux] = 'R';\n\t\t\t}\n\t\t\telse if (B == 0) {\n\t\t\t\tb++;\n\t\t\t\ts[aux] = 'B';\n\t\t\t}\n\t\t\telse if (Y == 0) {\n\t\t\t\ty++;\n\t\t\t\ts[aux] = 'Y';\n\t\t\t}\n\t\t\telse {\n\t\t\t\tg++;\n\t\t\t\ts[aux] = 'G';\n\t\t\t}\n\t\t\tif (i < 4)\n\t\t\t\ti = 0;\n\t\t\telse\n\t\t\t\ti -= 3;\n\t\t}\n\t\telse if (cont > 1 && i == (size - 4)) {\n\t\t\tfor (j = 0; j < cont; j++) {\n\t\t\t\taux = dead[j];\n\t\t\t\tif (aux < (size - 3)) {\n\t\t\t\t\tif (s[aux + 4] == 'R') {\n\t\t\t\t\t\tr++;\n\t\t\t\t\t\ts[aux] = 'R';\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\telse if (s[aux + 4] == 'B') {\n\t\t\t\t\t\tb++;\n\t\t\t\t\t\ts[aux] = 'B';\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\telse if (s[aux + 4] == 'Y') {\n\t\t\t\t\t\ty++;\n\t\t\t\t\t\ts[aux] = 'Y';\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\telse if (s[aux + 4] == 'G') {\n\t\t\t\t\t\tg++;\n\t\t\t\t\t\ts[aux] = 'G';\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (aux > 3){\n\t\t\t\t\tif (s[aux - 4] == 'R') {\n\t\t\t\t\t\tr++;\n\t\t\t\t\t\ts[aux] = 'R';\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\telse if (s[aux - 4] == 'B') {\n\t\t\t\t\t\tb++;\n\t\t\t\t\t\ts[aux] = 'B';\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\telse if (s[aux - 4] == 'Y') {\n\t\t\t\t\t\ty++;\n\t\t\t\t\t\ts[aux] = 'Y';\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\telse if (s[aux - 4] == 'G') {\n\t\t\t\t\t\tg++;\n\t\t\t\t\t\ts[aux] = 'G';\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (i < 4)\n\t\t\t\ti = 0;\n\t\t\telse\n\t\t\t\ti -= 3;\n\t\t}\n\t\telse\n\t\t\ti++;\n\t\tR = 0;\n\t\tB = 0;\n\t\tY = 0;\n\t\tG = 0;\n\t\tcont = 0;\n\t}\n\tprintf (\"%d %d %d %d\", r, b, y, g);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b1d58fe3f1b0bd66291adb3ff6150eaf", "src_uid": "64fc6e9b458a9ece8ad70a8c72126b33", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main ()\n{\n\tint R = 0, B = 0, Y = 0, G = 0, cont = 0, dead[4];\n\tint r = 0, b = 0, y = 0, g = 0;\n\tint i = 0, j, size, aux;\n\tchar s[105];\n\tscanf (\"%s\", s);\n\tsize = strlen (s);\n\twhile (i < (size - 3)) {\n\t\tfor (j = i; j < (i+4); j++) {\n\t\t\tif (s[j] == 'R')\n\t\t\t\tR++;\n\t\t\telse if (s[j] == 'B')\n\t\t\t\tB++;\n\t\t\telse if (s[j] == 'Y')\n\t\t\t\tY++;\n\t\t\telse if (s[j] == 'G')\n\t\t\t\tG++;\n\t\t\telse if (s[j] == '!') {\n\t\t\t\tdead[cont] = j;\n\t\t\t\tcont++;\n\t\t\t}\n\t\t}\n\t\tif (cont == 1) {\n\t\t\taux = dead[0];\n\t\t\tif (R == 0) {\n\t\t\t\tr++;\n\t\t\t\ts[aux] = 'R';\n\t\t\t}\n\t\t\telse if (B == 0) {\n\t\t\t\tb++;\n\t\t\t\ts[aux] = 'B';\n\t\t\t}\n\t\t\telse if (Y == 0) {\n\t\t\t\ty++;\n\t\t\t\ts[aux] = 'Y';\n\t\t\t}\n\t\t\telse {\n\t\t\t\tg++;\n\t\t\t\ts[aux] = 'G';\n\t\t\t}\n\t\t\tif (i < 4)\n\t\t\t\ti = 0;\n\t\t\telse\n\t\t\t\ti -= 3;\n\t\t}\n\t\telse if (cont > 1) {\n\t\t\tfor (j = 0; j < cont; j++) {\n\t\t\t\taux = dead[j];\n\t\t\t\tif (aux < (size - 3)) {\n\t\t\t\t\tif (s[aux + 4] == 'R') {\n\t\t\t\t\t\tr++;\n\t\t\t\t\t\ts[aux] = 'R';\n\t\t\t\t\t}\n\t\t\t\t\telse if (s[aux + 4] == 'B') {\n\t\t\t\t\t\tb++;\n\t\t\t\t\t\ts[aux] = 'B';\n\t\t\t\t\t}\n\t\t\t\t\telse if (s[aux + 4] == 'Y') {\n\t\t\t\t\t\ty++;\n\t\t\t\t\t\ts[aux] = 'Y';\n\t\t\t\t\t}\n\t\t\t\t\telse if (s[aux + 4] == 'G') {\n\t\t\t\t\t\tg++;\n\t\t\t\t\t\ts[aux] = 'G';\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse if (aux > 3){\n\t\t\t\t\tif (s[aux - 4] == 'R') {\n\t\t\t\t\t\tr++;\n\t\t\t\t\t\ts[aux] = 'R';\n\t\t\t\t\t}\n\t\t\t\t\telse if (s[aux - 4] == 'B') {\n\t\t\t\t\t\tb++;\n\t\t\t\t\t\ts[aux] = 'B';\n\t\t\t\t\t}\n\t\t\t\t\telse if (s[aux - 4] == 'Y') {\n\t\t\t\t\t\ty++;\n\t\t\t\t\t\ts[aux] = 'Y';\n\t\t\t\t\t}\n\t\t\t\t\telse if (s[aux - 4] == 'G') {\n\t\t\t\t\t\tg++;\n\t\t\t\t\t\ts[aux] = 'G';\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (i < 4)\n\t\t\t\ti = 0;\n\t\t\telse\n\t\t\t\ti -= 3;\n\t\t}\n\t\telse\n\t\t\ti++;\n\t\tR = 0;\n\t\tB = 0;\n\t\tY = 0;\n\t\tG = 0;\n\t\tcont = 0;\n\t}\n\tprintf (\"%d %d %d %d\", r, b, y, g);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "454f9b13c9b517f03bcc8183544e9afa", "src_uid": "64fc6e9b458a9ece8ad70a8c72126b33", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#define MAX 105\n#define sum 15\nint v[5];\n\nint decode(char c){\n\n    if(c == 'R')\n        return 1;\n    if(c == 'G')\n        return 2;\n    if(c == 'Y')\n        return 4;\n    if(c == 'B')\n        return 8;\n\n    return 0;\n}\n\nchar repair(int d){\n\n    if(d == 1){\n        v[1]++;\n        return 'R';\n    }\n    if(d == 2){\n        v[4]++;\n        return 'G';\n    }\n    if(d == 4){\n        v[3]++;\n        return 'Y';\n    }\n    if(d == 8){\n        v[2]++;\n        return 'B';\n    }\n\n    return '!';\n}\n\nint main(){\n\n    char a[MAX];\n    int i, n, error = 0, x, y, z, q, dif;\n    scanf(\"%s\",&a);\n    n = strlen(a);\n\n    for(i = 0;i < n; ++i)\n        if(a[i] == '!')\n            ++error;\n\n    v[1] = 0;\n    v[2] = 0;\n    v[3] = 0;\n    v[4] = 0;\n\n    do{\n        x = decode(a[0]);\n        y = decode(a[1]);\n        z = decode(a[2]);\n\n        for(i = 3;i < n; ++i){\n            q = decode(a[i]);\n            dif = sum - x - y - z - q;\n            if(a[i] == '!'){\n                a[i] = repair(dif);\n                if(a[i] != '!')\n                    --error;\n            }\n            if(a[i - 1] == '!'){\n                a[i - 1] = repair(dif);\n                if(a[i - 1] != '!')\n                    --error;\n            }\n            if(a[i - 2] == '!'){\n                a[i - 2] = repair(dif);\n                if(a[i - 2] != '!')\n                    --error;\n            }\n            if(a[i - 3] == '!'){\n                a[i - 3] = repair(dif);\n                if(a[i - 3] != '!')\n                    --error;\n            }\n\n            x = y;\n            y = z;\n            z = q;\n        }\n    }while(error > 0);\n\n    printf(\"%d %d %d %d\",v[1],v[2],v[3],v[4]);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a97b67a260e37cf1c37e0e22e3bf2b10", "src_uid": "64fc6e9b458a9ece8ad70a8c72126b33", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int a,b,c,d;\n    scanf(\"%d %d\",&a,&b);\n    if(a>b)\n    printf(\"%d %d\",b,c);}\n    else\n    {\n        \n        printf(\"%d %d\",a,c);\n    }\n        \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cdfcfeb7c663c87430eda3703f87b47c", "src_uid": "775766790e91e539c1cfaa5030e5b955", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n    int a,b,temp;\n    scanf(\"%d %d\",&a,&b);\n    if(a>b)\n    {\n        temp=a;\n        a = b;\n        b = temp;\n    }\n    b = (b-a)/2;\n    printf(\"%d %d\",a,b);", "lang_cluster": "C", "compilation_error": true, "code_uid": "e2f5d99bcc0f609735f1b9b10fd898c2", "src_uid": "775766790e91e539c1cfaa5030e5b955", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{       int a,b,t,k,w;\n        scanf(\"%d %d\",&a,&b);\n                if(a<b)\n                        {\n                                t=a;\n                                a=b;\n                                b=t;\n                        }\n                k=a-b;\n                printf(\"%d \",b);\n                if( k == 1)\n                        printf(\"0\");\n                else\n                        printf(\"%d\",w=k/2);\nreturn 0;\n}\n~               ", "lang_cluster": "C", "compilation_error": true, "code_uid": "e9ebffeeb82c6713870c11f6b94f5af3", "src_uid": "775766790e91e539c1cfaa5030e5b955", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main(){\n  int a,b;\n  int same,diff;\n\n  scanf(\"%d\",&a);\n  scanf(\"%d\",&b);\n\n  if(a%2==0 && b%2==0){\n    same=(a/2)+(b/2);\n    diff=0;\n  }\n\n  if(a%2!=0 && b%2!=0){\n    same=(a/2)+(b/2);\n    diff=1;\n  }\n\n  if((a%2!=0 && b%2==0) || (a%2==0 && b%2!=0)){\n    same=(a/2)+(b/2);\n    diff=0\n  }\n  printf(\"%d %d\",sum,diff);\n  return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fe2707bf8f8212c275c11234567bf7e2", "src_uid": "775766790e91e539c1cfaa5030e5b955", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "        #include <stdio.h>\n        int main()\n        {   \n            int a,b,i,diff_k=0,same_k=0;\n            scanf(\"%d %d\",&a,&b);\n            if(b<=a)\n            {\n                for(i=1;i<=b;i++)\n                {\n                    diff_k++;\n                }\n               \n                for(i=1;i<=a-diff;i++)\n                {   \n                    if(i==2*i)\n                    same_k++;\n                }\n            printf(\"%d %d\",diff_k,same_k);\n            }\n            else if(a<b)\n            {\n                for(i=1;i<=a;i++)\n                {\n                    diff_k++;\n                }\n                for(i=1;i<=b-diff;i++)\n                {   \n                    if(i==2*i)\n                    same_k++;\n                }\n         printf(\"%d %d\",diff_k,same_k);\n            }\n            return 0;\n        }\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "83e9419205e5b0c0b98b1021f066191d", "src_uid": "775766790e91e539c1cfaa5030e5b955", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    car c[100];\n    int i,l,c1=0,c2=0,c3=0,c4=0,c5=0;\n    scanf(\"%s\",c);\n    l=strlen(c);\n    for (i=0;i<l;i++)\n    {\n        if (c[i]=='A'&& c[i+1]=='n'&& c[i+2]=='n')\n        {\n            c1=c1+1;\n\t\t}\n        if(c[i]=='O'&& c[i+1]=='l'&& c[i+2]=='y'&& c[i+3]=='a')\n        {\n            c2=c2+1;\n        }\n        if(c[i]=='D'&& c[i+1]=='a'&& c[i+2]=='n'&& c[i+3]=='i'&& c[i+4]=='l')\n        {\n            c3=c3+1;\n\t    }\n        if(c[i]=='N'&& c[i+1]=='i'&& c[i+2]=='k'&& c[i+3]=='i'&& c[i+4]=='t'&& c[i+5]=='a')\n        {\n\t    c4=c4+1;\n\t\t}\n        if(c[i]=='S'&& c[i+1]=='l'&& c[i+2]=='a'&& c[i+3]=='v'&& c[i+4]=='A')\n        {\n\t      c5=c5+1;\n\t\t}\n\n    }\n\n    if (c1+c2+c3+c4+c5==1)\n    {\n        printf(\"YES\");\n    }\n    else\n     {\n\t\t printf(\"NO\");\n\t }\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fa1fa20cc0b9b5bd2f976442c33f2d14", "src_uid": "db2dc7500ff4d84dcc1a37aebd2b3710", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h> \n#include<string.h>\n\n\nint main()\n{\n\tchar s[200];\n\tscanf(\"%s\",&s);\n\tbool f;\n\tf=false;\n\tint i;\n\tfor (i=0;i<strlen(s);i++)\n\t{\n\t\tif (s[i]=='D'&&s[i+1]=='a'&&s[i+2]=='n'&&s[i+3]=='i'&&s[i+4]=='l')\n\t\t{\n\t\t\tf=true;\n\t\t\tbreak;\n\t\t}\n\t\tif (s[i]=='O'&&s[i+1]=='l'&&s[i+2]=='y'&&s[i+3]=='a')\n\t\t{\n\t\t\tf=true;\n\t\t\tbreak;\n\t\t}\n\t\tif (s[i]=='S'&&s[i+1]=='l'&&s[i+2]=='a'&&s[i+3]=='v'&&s[i+4]=='a')\n\t\t{\n\t\t\tf=true;\n\t\t\tbreak;\n\t\t}\n\t\tif (s[i]=='A'&&s[i+1]=='n'&&s[i+2]=='n')\n\t\t{\n\t\t\tf=true;\n\t\t\tbreak;\n\t\t}\n\t\tif (s[i]=='N'&&s[i+1]=='i'&&s[i+2]=='k'&&s[i+3]=='i'&&s[i+4]=='t'&&s[i+5]=='a')\n\t\t{\n\t\t\tf=true;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif (f) printf(\"Yes\");\n\t\telse printf(\"No\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a86b55cdc960df5552828aaaa7007a60", "src_uid": "db2dc7500ff4d84dcc1a37aebd2b3710", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\nchar ch[110];\nint i,j,k,l,c=0,c1=0,c2=0,c3=0,c4=0;\nscanf(\"%s\",ch);\nl=strlen(ch);\nfor (i=0;i<l;i++)\n{if (ch[i]=='A'&& ch[i+1]=='n'&& ch[i+2]=='n')\nc++;\nif(ch[i]=='O'&& ch[i+1]=='l'&& ch[i+2]=='y'&& ch[i+3]=='a')\nc1++;\nif(ch[i]=='D'&& ch[i+1]=='a'&& ch[i+2]=='n'&& ch[i+3]=='i'&& ch[i+4]=='l')\nc2++;\nif(ch[i]=='N'&& ch[i+1]=='i'&& ch[i+2]=='k'&& ch[i+3]=='i'&& ch[i+4]=='t'&& ch[i+5]=='a')\nc3++;\nif(ch[i]=='S'&& ch[i+1]=='l'&& ch[i+2]=='a'&& ch[i+3]=='v'&& ch[i+4]=='a')\nc4++;\n}\nif (c+c1+c2+c3+c4==1)\nprintf(\"YES\\n\");\nelse\nprintf(\"NO\\n\");\nreturn 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "19df32248df164cd61fc03cb05607e45", "src_uid": "db2dc7500ff4d84dcc1a37aebd2b3710", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(){\nint i,x;\nchar A[101];\nfor(i=0;i<101;i++){\nscanf(\"%c\",&A[i]);\n                  }\nfor(i=0;i<101;i++){                  \nif(A[i]=='O' && A[i+1]='l' && A[i+2]=='y' && A[i+3]=='a' || A[i]=='D' && A[i+1]=='a' && A[i+2]=='n' && A[i+3]=='i' && A[i+4]=='l' || A[i]=='A' && A[i+1]=='n' && A[i+2]=='n' || A[i]=='S' && A[i+1]=='l' && A[i+2]=='a' && A[i+3]=='v' && A[i+4]=='a' || A[i]=='N' && A[i+1]=='i' && A[i+2]=='k' && A[i+3]=='i' && A[i+4]=='t' && A[i+5]=='a'){\nx=1;\n}\nelse \nx=0;\n}\nif(x==1)\nprintf(\"YES\");\nelse \nprintf(\"NO\");   \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8befd77fb127cd97de56059c8da54e7c", "src_uid": "db2dc7500ff4d84dcc1a37aebd2b3710", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int i,j,k,n,m=0;\n    char a[101];\n    scanf(\"%s\",a);\n    n=strlen(a);\n    for(j=0;j<n;j++){\n        if(a[j]=='D'&&a[j+1]=='a'&&a[j+2]=='n'&&a[j+3]=='i'&&a[j+4]=='l'){\n            m++;\n        }AC\n      else  if(a[j]=='O'&&a[j+1]=='l'&&a[j+2]=='y'&&a[j+3]=='a'){\n            m++;\n        }\n      else  if(a[j]=='S'&&a[j+1]=='a'&&a[j+2]=='l'&&a[j+3]=='v'&&a[j+4]=='a'){\n            m++;\n        }\n       else if(a[j]=='A'&&a[j+1]=='n'&&a[j+2]=='n'){\n            m++;\n        }\n       else if(a[j]=='N'&&a[j+1]=='i'&&a[j+2]=='k'&&a[j+3]=='i'&&a[j+4]=='t'&&a[j+5]=='a'){\n            m++;\n        }\n    }\n    if(m==1){\n        printf(\"YES\\n\");\n    }\n    else{\n        printf(\"NO\\n\");\n    }\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8276116136a1f47676c176c412a3971a", "src_uid": "db2dc7500ff4d84dcc1a37aebd2b3710", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nlong int SRoot(long int num)\n{\n    long int i;\n    \n    if(num == 1)\n        return 1;\n    else\n    {\n        i = 1;\n        do{\n            i++;\n        }while(i * i < num);\n        \n        return i;\n    }\n}\n\nint main()\n{\n    long int n, i, D[300]={0}, max, x, j, A[150], y, k, d;\n    \n    scanf(\"%ld\", &n);\n    for(i=0;i<n;i++)\n        scanf(\"%ld\", &D[i]);\n    \n    //Determine the maximum divisor from the array D[]\n    max = D[0];\n    for(i=1;i<n;i++)\n        if(D[i] > max)\n            max = D[i];\n            \n    x = max;\n    \n    //Determine all of the divisors of \"x\"\n    j = 0;\n    for(i=1;i<=x;i++)\n        if(x % i == 0)\n        {\n            A[j] = i;\n            j++;\n        }\n    \n    //Multiply the divisors from D[] that are not present in A[];\n    //thus we can get \"y\"\n    y = 1;\n    for(i=0;i<n;i++)\n    {\n        for(k=0;k<j;k++)\n        {\n            if(A[k] == D[i])\n            {\n                d = 1;\n                break;\n            }\n            else\n                d = 0;\n        }\n        \n        if(d == 0)\n            y *= D[i];\n    }\n    \n    y = SRoot(long int y);\n    \n    printf(\"%ld %ld\", x, y);\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d4f01e62cea08bb5261daefe2ff655ec", "src_uid": "868407df0a93085057d06367aecaf9be", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nlong int SRoot(long int num)\n{\n    long int i;\n    \n    if(num == 1)\n        return 1;\n    else\n    {\n        i = 1;\n        do{\n            i++;\n        }while(i * i < num);\n        \n        return i;\n    }\n}\n\nint main()\n{\n    \n    scanf(\"%ld\", &n);\n    for(i=0;i<n;i++)\n        scanf(\"%ld\", &D[i]);\n    \n    //Determine the maximum divisor from the array D[]\n    max = D[0];\n    for(i=1;i<n;i++)\n        if(D[i] > max)\n            max = D[i];\n            \n    x = max;\n    \n    //Determine all of the divisors of \"x\"\n    j = 0;\n    for(i=1;i<=x;i++)\n        if(x % i == 0)\n        {\n            A[j] = i;\n            j++;\n        }\n    \n    //Multiply the divisors from D[] that are not present in A[];\n    //thus we can get \"y\"\n    y = 1;\n    for(i=0;i<n;i++)\n    {\n        for(k=0;k<j;k++)\n        {\n            if(A[k] == D[i])\n            {\n                x = 1;\n                break;\n            }\n            else\n                x = 0;\n        }\n        \n        if(x == 0)\n            y *= D[i];\n    }\n    \n    y = SRoot(long int y);\n    \n    printf(\"%ld %ld\", x, y);\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dcde1eb0114e51eaec10f30ad722d66a", "src_uid": "868407df0a93085057d06367aecaf9be", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,i,d[200],max,c[200],j=0,s,maxi,f=0;\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++)\n    scanf(\"%d\",&d[i]);\n    max=d[0];\n    for(i=0;i<n;i++)\n    {\n        if(d[i]>max)\n        max=d[i];\n    }\n    printf(\"%d \",max);\n    for(i=0;i<n;i+\n    +)\n    {\n        if(d[i]==max)\n            f++;\n    }\n    if(f==2)\n        printf(\"%d\",max);\n    else\n    {\n        for(i=0;i<n;i++)\n        {\n            if(max%d[i]!=0)\n            {\n                c[j]=d[i];\n                j++;\n            }\n        }\n\n    s=j;\nmaxi=c[0];\n    for(j=0;j<s;j++)\n    {\n        if(c[j]>maxi);\n        maxi=c[j];\n    }\n    printf(\"%d\",maxi);\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b8139e350d8f451d793cf79126fec6ee", "src_uid": "868407df0a93085057d06367aecaf9be", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(){\n\tint n;\n\tscanf(\"%d\",&n);\n\tint N[128]={0}; \n\tint M[128]={0}; \n\tfor(int i=0;i<n;i++){\n\t\tscanf(\"%d\",&N[i]);\n\t}\n\tfor(int i=0;i<n;i++){\n\t\tM[i]=N[i];\n\t}\n\tint x,y,tmp=0;\n\tfor(int i=0;i<n;i++){\n\t\tif(N[i]>tmp){\n\t\t\ttmp=N[i];\n\t\t}\t\t\n\t}\n\tx=tmp;\n\tfor(int i=0;i<n;i++){\n\t\tif(x%N[i]==0){\n\t\t\tbool flag=false;\n\t\t\tfor(int j=0;j<i;j++)\n\t\t\t\tif(M[j]==N[i]){\n\t\t\t\t\tflag=1;\n\t\t\t\t}\n\t\t\t\t\n\t\t\tif(flag);\n\t\t\telse\n\t\t\t\tN[i]=0;\t\t\n\t\t}\t\t\n\t}\n\t\n\ttmp=0;\n\tfor(int i=0;i<n;i++){\n\t\tif(N[i]>tmp){\n\t\t\ttmp=N[i];\n\t\t}\t\t\n\t}\n\ty=tmp;\n\t\n\tprintf(\"%d %d\",x,y);\n} \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5c86f79733de8567c8ee1d08dd9af1e7", "src_uid": "868407df0a93085057d06367aecaf9be", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "11.cpp", "lang_cluster": "C", "compilation_error": true, "code_uid": "8acfd0799dae3434af7f7ed264712c33", "src_uid": "868407df0a93085057d06367aecaf9be", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,t,k,d;\n    scanf(\"%d%d%d%d\",&n,&t,&k,&d);\n    if( (d+t)<(n+k-1)/k*t)\n    print(\"YES\");\n    else\n    printf(\"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2adff6c65000e273c6619d02b6849351", "src_uid": "32c866d3d394e269724b4930df5e4407", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <conio.h>\n#include <windef.h>\nint max(int n1,int n2) {\n    if (n1 > n2)\n        return n1;\n    else\n        return n2;\n}\nint main()\n{\n\n    int n,t,k,d;\n    scanf(\"%d%d%d%d\",&n,&t,&k,&d);\n    double count1=0,count2=d;\n    int x=(n+k-1)/k;\n    for (int i = 0; i <x ; ++i) {\n        if(count1<=count2)\n            count1+=t;\n        else\n            count2+=t;\n\n    }\n\n   if(max(count1,count2)<x*t)\n       printf(\"YES\");\n   else\n       printf(\"NO\");\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1a05d6fdb10d1d8273e6ebed23412f0a", "src_uid": "32c866d3d394e269724b4930df5e4407", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<stdio.h>\nusing namespace std;\nint main()\n{\n\tint i, j, k;\n\tint n, m, t, d;\n\tint sum1=0;\n\tint sum2=0;\n\tscanf(\"%d %d %d %d\", &n, &t, &k, &d);\n\tint l = n;\n\twhile (l > 0)\n\t{\n\t\tsum1 += t;\n\t\tl -= k;\n\t}\n\tl = n;\n\twhile (l > 0)\n\t{\n\t\tsum2++;\n\t\tif (sum2%t == 0)\n\t\t{\n\t\t\tl -= k;\n\t\t}\n\t\tif (sum2 - d > 0 && (sum2 - d) % t == 0)\n\t\t{\n\t\t\tl -= k;\n\t\t}\n\t}\n\tif (sum1 > sum2)\n\t{\n\t\tprintf(\"YES\\n\");\n\t}\n\telse\n\t{\n\t\tprintf(\"NO\\n\");\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "46fcc38e1c7932f79b29a7e48d1114a9", "src_uid": "32c866d3d394e269724b4930df5e4407", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\n\nint main()\n{\n    int n,t,k,d;\n    \n    scanf(\"%d%d%d%d\", &n,&t,&j,&d);\n\n\n\n    int req = (n * t)/k;\n\n    if (t + d < req )\n        printf(\"YES\\n\");\n    else\n     printf(\"NO\\n\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a3f9949e00d481447b04fe404ca16ab0", "src_uid": "32c866d3d394e269724b4930df5e4407", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,k,t,d,T1,T2;\n    scanf(\"%d %d %d %d\",&n ,&t ,&k ,&d);\n    T1= (n/k*t+(n%k!=0));\n    T2=d+(n/2k)*t;\n    if(T1>T2)\n    printf(\"YES\");\n    else\n    printf(\"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f016e84096965a5ced7e8e411fbc414b", "src_uid": "32c866d3d394e269724b4930df5e4407", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "include<stdio.h>\nint main()\n{int n;\nscanf(\"%d\",&n);\n n=n-10;\n switch(n)\n {\n case 1:\n printf(\"4\\n\")\n break;\n case 2:\n printf(\"4\\n\")\n break;\n case 3\n printf(\"4\\n\")\n break;\n case 4\n printf(\"4\\n\")\n break;\n case 5\n printf(\"4\\n\")\n break;\n case 6\n printf(\"4\\n\")\n break;\n case 7\n printf(\"4\\n\")\n break;\n case 8\n printf(\"4\\n\")\n break;\n case 9\n printf(\"4\\n\")\n break;\n case 10\n printf(\"15\\n\")\n break;\n case 11\n printf(\"4\\n\")\n break;\n default:\n printf(\"0\\n\")\n}\nreturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4129f7be2b45156466b60206820a8b0b", "src_uid": "5802f52caff6015f21b80872274ab16c", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n\n{\n    int x,n;\n    scanf(\"%d\",&n);\n    x=n-10;\n    if(x==0||x>=12)\n    printf(\"0\");\n    if(x=10);\n    printf(\"15\");\n    else\n    printf(\"4\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ba2ae3753be1cc2e762bfab8c089f706", "src_uid": "5802f52caff6015f21b80872274ab16c", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<iostream>\nusing namespace std;\nint main() {\n\tint n;\n\twhile (cin >> n) {\n\t\tif (n <= 10) {\n\t\t\tcout << 0 << endl;\n\t\t} else if (n == 11) {\n\t\t\tcout << 8 << endl;\n\t\t} else if (n < 20) {\n\t\t\tcout << 4 << endl;\n\t\t} else if (n == 20) {\n\t\t\tcout << 15 << endl;\n\t\t} else {\n\t\t\tcout << 0 << endl;\n\t\t}\n\t}\n\treturn 0;\n}\n\t\t\t\n \t \t\t \t    \t\t \t  \t\t\t\t\t\t\t\t\t\t\t\t", "lang_cluster": "C", "compilation_error": true, "code_uid": "9ce54c945eb1e67fda168e468aecb995", "src_uid": "5802f52caff6015f21b80872274ab16c", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<iostream>\nusing namespace std;\nint main()\n{\n    int t,n,i,j,k;\n    cin>>n;\n    if(n<11||n>21)\n        cout<<\"0\";\n    else if(n>10&&n<19)\n        cout<<\"4\";\n    else if(n==20)\n        cout<<\"15\";\n    else if(n==21)\n        cout<<\"4\";\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "20ecbb10a9687ec40b734bed10c28668", "src_uid": "5802f52caff6015f21b80872274ab16c", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "/*\nAuthor:\n%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%\n%%%%%%%%   LALIT KUNDU      %%%%%%%% \n%%%%%%%%   IIIT HYDERABAD   %%%%%%%%\n%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%\n*/\n#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<math.h>\n#include<malloc.h>\n#define lld long long int\n#define llu long long unsigned int\nint compare(const void * a, const void * b){return *(lld *)a-*(lld *)b;}\nlong long int readint() {long long int n=0,count=0,counti=0; char c;while(1){c=getchar_unlocked();if(c=='-')count=1;else if((c==' '||c=='\\n'||c==EOF) && counti==1)break;else if(c>='0' && c<='9'){counti=1;n=(n<<3)+(n<<1)+c-'0';}}if(count==0)return n;else return -n;}\n#define min(a,b)(a>b?b:a)\n#define max(a,b)(a<b?b:a)\n#define sort(arr,n) qsort(arr,n,sizeof(arr[0]),compare)\n#define sd(n) scanf(\"%d\",&n)\n#define sl(n) scanf(\"%lld\",&n)\n#define su(n) scanf(\"%llu\",&n)\n#define rep(i,start,end) for(i=start; i<end; i++)\n#define pdn(n) printf(\"%d\\n\",n)\n#define pln(n) printf(\"%lld\\n\",n)\n#define pun(n) printf(\"%llu\\n\",n)\n#define pd(n) printf(\"%d\",n)\n#define pl(n) printf(\"%lld\",n)\n#define pu(n) printf(\"%llu\",n)\n#define pn printf(\"\\n\")\n#define ps printf(\" \")\nint main()\n{\n    int n;\n    sd(n);\n    n-=10;\n    if(n<=0)\n        pdn(0);\n    if(n==1)\n        pdn(4);\n    else if(n<10 && n>=2)\n        pdn(4);\n    else if(n==10)\n        pdn(15);\n    else if(n>10)\n    {\n        if(n!=11)\n        pdn(0);\n        else pdn(4);\n    }\n    return 0;\n}\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3b8cc7716c7e4f1796a868d18f89272b", "src_uid": "5802f52caff6015f21b80872274ab16c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>  \nint main(void)\n{\n\tlong long int num = 0;\n\tscanf(\"%I64d\",&num);\n\tlong long int ans = 0;\n\twhile(num/10!=0)\n\t{\n\t\tans+=(10-num%10);\n\t\tnum/=10;\n\t\tnum+=1;\n\t\twhile(num%10==0)\n\t\t{\n\t\t\tnum/=10;\n\t\t}\n\t}\n\tans+=9;\n\tprintf(\"%I64d\",ans);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a53b84a311d530469bd97f901efa7a74", "src_uid": "055fbbde4b9ffd4473e6e716da6da899", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(){\n\tint n;\n\tscanf(\"%d\",&n);\n\tint i=1;\n\t\n\twhile(n>=10)\n\t{\n\t\tn++;a\n\t\twhile(n%10==0){\n\t\t\tn/=10;\n\t\t}\n\t\ti++;\n\t}\n\t\n\ti+=8;\n\tprintf(\"%d\",i);\n} \n/*\n1098 => +1\n1098+2->1100->110->11 =>+2\n11,12,13,...19,20->2  ==>+9\n2,3,4,5,6,7,8,9,10->1 ==>+8 */\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "430b622ed54cb5f2fdc2026c5a527a30", "src_uid": "055fbbde4b9ffd4473e6e716da6da899", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(void)\n{\n\tint N, i;\n\tint flag = 0;\n\tint A[1000000000] = { 0 };\n\tint count = 1;\n\tint index = 0;\n\tscanf(\"%d\", &N);\n\twhile(1)\n\t{\n\t\tA[index] = N;\n\t\tindex++; count++;\n\t\tN += 1;\n\t\tif(N % 10 == 0)\n\t\t{\n\t\t\twhile(N % 10 == 0)\n\t\t\t\tN /= 10;\n\t\t}\n\t\tA[index] = N;\n\t\tif(flag)\n\t\t{\n\t\t\tfor(i = 0; i < index; i++)\n\t\t\t{\n\t\t\t\tif(A[i] == N)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%d\", count - 1);\n\t\t\t\t\treturn 0;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tflag = 1;\n\t}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "21d390ac8ef2a5a9e25bd5ac6d10eedc", "src_uid": "055fbbde4b9ffd4473e6e716da6da899", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint vis[15];\nint main()\n{\n    int n;\n    scanf(\"%d\", &n);\n    if(n < 10 && n > 0)\n    {\n        printf(\"9\\n\");\n        return 0;\n    }\n    int count = 0;\n    while(true)\n    {\n            n++;\n        while(n % 10 == 0)\n        {\n            n /= 10;\n        }\n        if(n <= 10 && n > 0)\n        {\n            if(vis[n] == 1)\n                break;\n            else\n                vis[n] = 1;\n        }\n        count++;\n    }\n    printf(\"%d\\n\", count+1);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9c8103d0a5aa39231c9f21aaf7ff1bc5", "src_uid": "055fbbde4b9ffd4473e6e716da6da899", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "number=input()\nlength=len(number)\n\nsum=0\nx=length-1\nfirst=True\nif length%2==1:\n    a=number[x]\n    b=number[x-1]\n    x-=2\n    sum=sum+(10-int(a)+9)\n    while x>0:\n        a=number[x]\n        b=number[x-1]\n        x-=2\n        sum=sum+(10-int(b))\n    sum=sum+(10-int(number[0]))\nelse:\n    a=number[x]\n    b=number[x-1]\n    x-=2\n    sum=sum+(10-int(a)+9)\n    while x>0:\n        a=number[x]\n        b=number[x-1]\n        x-=2\n        sum=sum+(10-int(b))\n\nprint (sum)\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a19c3bb736a1480be84da5db78bae1dd", "src_uid": "055fbbde4b9ffd4473e6e716da6da899", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n    char b[1000];\n    scanf(\"%s\",b);\n    int l=strlen(b);\n    set <int> s;\n    int f;\n    for(int i=0;i<l/2;i++){\n        if(b[i]==b[k-1-i]){\n            f=1;\n        }\n        else{\n            printf(\"%d\",l);\n            return 0;\n        }\n        \n    }\n    for(int i=0;i<l;i++){\n        s.insert(b[i]);\n    }\n  if(s.size()==1){\n        cout<<0;\n    }\n    else{\n        if(f==1){\n            cout<<l-1;\n        }\n    }\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cfb04a073bd7102e07e235d40cd1e594", "src_uid": "6c85175d334f811617e7030e0403f706", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nchar s[100];\nint pal(int l){\n\tint t=l;\n\tfor(int i=0;i<t;i++){\n\tif(s[i] != s[l-1]){\n\t\treturn 1;}\n\t\tl--;}\n\treturn 0;\n}\t\t\nint check(){\n\tint l = strlen(s),flag=0;\n\tflag = pal(l);\n\tif(flag==0){\t\n\t\tfor(int i=0;i<strlen(s);i++){\n\t\tflag=pal(l);\n\t\tif(flag == 0){\n\t\t\tl--; }\n\t\telse{\t\n\t\t\tprintf(\"%d\\n\",l); \n\t\t\treturn 0;} } }\n\telse{\n\t\tprintf(\"%d\\n\",l); }\t\n\tif(l==0){\n\t\tprintf(\"0\\n\");}\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "becde9d87c64c0a7371be4d0b50900de", "src_uid": "6c85175d334f811617e7030e0403f706", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char s[50];\n    int i=0,l,c=0,c1=0;\n    scanf(\"%s\",s);\n    l=strlen(s);\n    for(i=0;i<l/2;i++)\n    {\n        if(s[0]==s[i])\n            c1++;\n    }\n    switch(c1)\n    {case l:\n        {printf(\"0\");\n        break;}\n    }\n    for(i=0;i<l/2;i++)\n    {\n        if(s[i]==s[l-i-1]);\n        else\n            c++;\n    }\n    if(c==0)\n        printf(\"%d\",l-1);\n    else\n        printf(\"%d\",l);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a87810170fb5908f03d8202bd5c87bdd", "src_uid": "6c85175d334f811617e7030e0403f706", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\nchar s[50];\nscanf(\"%s\",&s);\nint n,flag=0,flag1=0;\nn=strlen(s);\nfor(i=0;i<(l/2);i++)\n{\n\tif(s[i]!=s[n-i-1])\n\t{\n\t\tflag=1;\n\t}\n\telse if(s[0]!=s[i+1])\n\t{\n\t\tflag1=1;\n\t}\n\telse\n\t{\n\t\tflag=0;\n\t}\n}\nif(flag==1)\n\tprintf(\"%d\",n);\nelse if(flag1==1)\n\tprintf(\"%d\",(n-1));\nelse\n\tprintf(\"0\");\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f8eac4d596a916d497f38e464266cd58", "src_uid": "6c85175d334f811617e7030e0403f706", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "\n#include<stdio.h>\n#include<string.h>\n\nusing namespace std;\n\nint main()\n{\n    char s[51],x[51];\n    int z=0,p=1;\n    gets(s);\n    strcpy(x,s);\n    int l=strlen(s);\n    strrev(x);\n    if(strcmp(x,s)!=0)\n    {\n        printf(\"%d\\n\",l);\n        z=1;\n    }\n    else\n    {\n        while(1)\n        {\n            int i;\n            for(i=0;i<l-p;i++)\n            {\n                s[i]=s[i+1];\n            }\n            s[i]='\\0';\n            strcpy(x,s);\n            strrev(x);\n            if(strcmp(s,x)!=0)\n            {\n                printf(\"%d\\n\",l-p);\n                z=1;\n                break;\n            }\n            else if(strlen(s)==1)\n            {\n                printf(\"0\\n\");\n                z=1;\n                break;\n            }\n            p++;\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "87a77c18de30f7af14a04a58b5311a1d", "src_uid": "6c85175d334f811617e7030e0403f706", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdlib.h>\n#include <stdio.h>\n\n\nint main(void) {\n    \n    int c;\n    ptrdiff_t n;\n\n    register ptrdiff_t i = 0;\n    register int c0 = 0;\n\n    while ((c = getchar()) && c != 10)\n        n = n * 10 + c - 48;\n\n    char* s = malloc(n * sizeof(char));\n\n    while (i < n) {\n        if (c == 48)\n            c0 += 1;\n        s[i++] = getchar();\n    }\n\n    if (n - c0 != c0) {\n        putchar(50);\n        putchar(10);\n        putchar(*s);\n        putchar(32);\n        for (i = 1; i < n; i += 1) {\n            putchar(*(s + i));\n        }\n    } else {\n        putchar(49);\n        putchar(10);\n        for (i = 0; i < n; i += 1) {\n            putchar(*(s + i));\n        }\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b93491177f9e97744ce0863330f772fd", "src_uid": "4ebed264d40a449602a26ceef2e849d1", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\n#include<string>\nusing namespace std;\nstring s;\nint compare(string a)\n{\n\tint o=0,z=0;\n\tfor(int i=0;i<a.size();i++){\n\t\tif(a[i]=='0'){\n\t\t\tz++;\n\t\t}\n\t\tif(a[i]=='1'){\n\t\t\to++;\n\t\t}\n\t}\n\tif(o==z)return 0;\n\telse return 1;\n}\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tcin>>s;\n\tif(compare(s)==1){\n\t\tcout<<1<<endl;\n\t\tcout<<s<<endl;\n\t}\n\telse{\n\t\tstring a,b;\n\t\tfor(int i=1;i<s.size();i++){\n\t\t\ta=s.substr(0,i);\n\t\t\tb=s.substr(i,s.size()-i);\n\t\t\tif(compare(a)==1&&compare(b)==1&&a!=b){\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tcout<<2<<endl;\n\t\tcout<<a<<\" \"<<b<<endl;\n\t}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "940d02097dcced43b507566bf7e27eac", "src_uid": "4ebed264d40a449602a26ceef2e849d1", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdlib.h>\n#include <string.h>\n#include <ctype.h>\n/* run this program using the console pauser or add your own getch, system(\"pause\") or input loop */\n/*kneau reeves*/\nint main() {\n\tint n,s1=0,s2=0,i;\n\tchar ch[100];\n\tchar sh[100];\n    scanf(\"%d\",&n);\n    scanf(\"%s\",ch);\n\tfor (i=0;i<n;i++) {\n\t\tif (ch[i]='0') \n\t\t    s1+=1;\n\t\telse\n\t\t    s2+=1;\n\t}\n\tif (s1==s2)\n\t{\n\t  \n\t  sh[1] = ch[n-1];\n\t  ch[n-1]='\\0';\n\t  printf (\"2\\n%s\",ch);\n\t  printf (\"%c\",sh);\n}\n    else \n        printf(\"1\\n%s\",ch);\n\treturn 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "e17051e6317ff3ff6eb48b409b380820", "src_uid": "4ebed264d40a449602a26ceef2e849d1", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    int zero=0,one=1;\n    int i=0;\n    char string[n];\n    while(i<n){\n        scanf(\"%c\",&string[i]);\n        if(string[i]-'0'==0)\n            zero++;\n        else \n            one++\n    }\n    if(zero!=one)\n    {\n        printf(\"1\\n\");\n        printf(\"%s\",string);\n    }\n    else if((n/2)%2==0)\n    {\n        printf(\"2\\n\");\n        printf(\"%c \",string[0]);\n        int i=1;\n        while(i<n)\n        {\n            printf(\"%c\",string[i]);\n            i=i+1;\n        }\n    }\n    else if((n/2)%2==1)\n    {\n        int i=0;\n        while(i<=n/2)\n        {\n              printf(\"%c\",string[i]);\n              i=i+1;\n        }\n        printf(\" \");\n        while(i<=n)\n        {\n              printf(\"%c\",string[i]);\n              i=i+1;\n        }\n    }\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b2f2fbc7cae6f320f01008feb5928ac2", "src_uid": "4ebed264d40a449602a26ceef2e849d1", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "int main()\n{\n    int n,m,i,zero,one;\n    \n    scanf(\"%d\",&n);\n    \n    char ch[200];\n    char ch1[200];\n   \n   printf(\"donner une chaine binaire :\\n\");\n   scanf (\"%s\",ch);\n        \n        \n  \n\n    one=0;\n    zero=0;\n    for (i=0;i<n;i++){\n       if (ch[i]=='0')\n         one+=1;\n        else  if (ch[i]=='1')\n          zero+=1;\n    }      \n    if (zero == one )\n    {\n        ch1 = ch[n-1];\n        ch[n-1]='\\0';\n        printf (\"2\\n%s\" , s);\n        printf(\"%c\",q);\n    }\n    else\n    printf(\"1\\n%s\" ,s)\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0a6f78fcd5aaef1df22590088bd759c3", "src_uid": "4ebed264d40a449602a26ceef2e849d1", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<iostream>\n#include<algorithm>\n#include<stdlib.h>\n#include<math.h>\nusing namespace std;\nlong long d(long long n)\n{\n    long long ans=0;\n    for(int i=1;i<=sqrt(n);i++)\n    {\n        if(n%i==0)\n        {\n            if(i==sqrt(n))\n                ans++;\n            else\n                ans+=2;\n        }\n    }\n    return ans;\n}\nint main()\n{\n    long long  a,b,c;\n    scanf(\"%lld%lld%lld\",&a,&b,&c);\n    long long sum=0;\n    for(int i=1;i<=a;i++)\n    {\n       for(int j=1;j<=b;j++)\n        {\n            for(int k=1;k<=c;k++)\n            {\n             sum+=d(i*j*k);\n             sum%=1073741824;\n\n            }\n\n        }\n    }\n    printf(\"%lld\\n\",sum);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "beddf21d26c573debc635d0cfc10a9c6", "src_uid": "4fdd4027dd9cd688fcc70e1076c9b401", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long int ld;\ntypedef long long int lld;\ntypedef float f;\ntypedef double lf;\ntypedef unsigned int u;\ntypedef unsigned long int lu;\ntypedef unsigned long long int llu;\ntypedef char C;\n\n#define sf scanf\n#define pf printf\n#define PI acos(-1.0)\n#define sq(x) (x)*(x)\n#define FOR(i,x,cases) for(i=x;i<cases;i++)\n#define FORC(i,x,cases) for(i=x;i<=cases;i++)\n#define FORin(i,cases,x) for(i=cases;i>=x;i--)\n#define nn printf(\"\\n\")\n#define chk printf(\"chek\\n\")\n#define chk1 printf(\"chek1\\n\")\n#define size 1000000\n#define READ(f) freopen(f, \"r\", stdin)\n#define WRITE(f) freopen(f, \"w\", stdout)\n\n/******   start your code   *******/\nint divisor[size+1];\nvoid total_divisor()\n{\n    int i,j;\n    for(i=1;i<=size;i++)\n        for(j=i;j<=size;j+=i)\n         divisor[j]++;\n}\nint main()\n{\n    total_divisor();\n    int num1,num2,num3,i,j,k,count,total,store;\n    while(sf(\"%d%d%d\",&num1,&num2,&num3)==3)\n    {\n        count=0;\n        for(i=1; i<=num1; i++)\n            for(j=1; j<=num2; j++)\n                for(k=1; k<=num3; k++)\n                {\n                    //total=i*j*k;\n                    count+=divisor[i*j*k];\n                    //pf(\"%d %d %d count = %d\\n\",i,j,k,store);\n                }\n        pf(\"%d\\n\",count);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3fc0267348b6dad93d2c99af94a6ee5e", "src_uid": "4fdd4027dd9cd688fcc70e1076c9b401", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n#define max 1000000\nint ar[1000000];\n    \nint main()\n{\n    divison ();\n    int i,j,k;\n    int a,b,c,sum,d;\n  for(i=1;i<=max;i++)\n    {\n     for(j=i;j<=max;j+=i)\n     {\n       ar[j++]; \n       }\n      } \n     }\n    while(scanf(\"%d%d%d\",&a,&b,&c)==3)\n    {\n     sum=0;\n     for(i=1;i<=a;i++)\n     {\n      for(j=1;j<=b;j++)\n      {\n       for(k=1;k<=c;k++)\n       {\n        d=i*j*k;\n        sum+=ar[d];\n       }\n      }\n     }\n     printf(\"%d\\n\",sum%1073741824);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "20a66e3b575436a18f5859230da5c7e3", "src_uid": "4fdd4027dd9cd688fcc70e1076c9b401", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n#define max 1000000\nint ar[1000000];\n    \nint main()\n{\n    int i,j,k;\n    int a,b,c,sum,d;\n  for(i=1;i<=max;i++)\n    {\n     for(j=i;j<=sqrt(max);j++)\n     {\n       ar[j++]; \n       }\n      } \n     }\n    while(scanf(\"%d%d%d\",&a,&b,&c)==3)\n    {\n     sum=0;\n     for(i=1;i<=a;i++)\n     {\n      for(j=1;j<=b;j++)\n      {\n       for(k=1;k<=c;k++)\n       {\n        d=i*j*k;\n        sum+=ar[d];\n       }\n      }\n     }\n     printf(\"%d\\n\",sum%1073741824);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d04f866435a875820fdc3d7fe4d8a291", "src_uid": "4fdd4027dd9cd688fcc70e1076c9b401", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "a, b, c = map(int, raw_input().split())\nd = {}\nans = 0\nd[1] = 1\nfor ai in xrange(1, a + 1):\n    for bi in xrange(1, b + 1):\n        for ci in xrange(1, c + 1):\n            i = ai * bi * ci\n            if i not in d:\n                sqi = i ** 0.5\n                d[i] = sum(2 if j != sqi else 1 for j in xrange(2, int(sqi) + 1) if i % j == 0) + 2\n            ans += d[i]\nprint ans % 1073741824", "lang_cluster": "C", "compilation_error": true, "code_uid": "26d64687bdef4ff62891d4c00c0cdaa0", "src_uid": "4fdd4027dd9cd688fcc70e1076c9b401", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\n\nlong long int a[1000006],a1[1000006],b1[1000006],x[1000006],y[1000006];\nint main()\n{\n\tlong long int n,i,f,c;\n\tscanf(\"%I64d\",&n);\n\t\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%I64d\",&a[i]);\n\t}\n\t\n\tf=0;\n\t\n\tfor(i=0;i<n;i++)\n\t{\n\t\tif(a[i]!=0)\n\t\tf=1;\n\t}\n\t\n\tif(f==0)\n\t{\n\t\tprintf(\"NO\");\n\t\treturn 0;\n\t}\n\t\n\tprintf(\"YES\\n\");\n\t\n\tc=0;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tif(a[i]!=0)\n\t\t{\n\t\t\ta1[c]=a[i];\n\t\t\tb1[c]=i+1;\n\t\t\tc++;\n\t\t}\n\t}\n\t\n\tfor(i=0;i<c-1;i++)\n\t{\n\t\tx[i]=b1[i];\n\t\ty[i]=b1[i+1]-1;\n\t}\n\tx[c-1]=b1[c-1];\n\tx[0]=1;\n\ty[c-1]=n;\n\tfor(i=0;i<c;i++)\n\t{\n\t\tprintf(\"%I64d %I64d\\n\",x[i],y[i]);\n\t}\n\treturn 0;\n\t\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "657abd7356867646bf3aa68bc3ba89ac", "src_uid": "3a9258070ff179daf33a4515def9897a", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#pragma warning(disable:4996)\n\nint* nums;\nint** index;\n\nbool checkSubMatrix(int start, int end);\n\nint main()\n{\n\tint num;\n\n\tscanf(\"%d\", &num);\n\n\n\tnums = (int*)malloc(sizeof(int)*num);\n\n\tfor (int i = 0; i < num; i++)\n\t\tscanf(\" %d\", &nums[i]);\n\n////////////////////////////////////////////////////\n\n\tif (num == 1)\n\t{\n\t\tprintf(\"NO\\n\");\n\t\treturn 0;\n\t}\n\telse\n\t{\n\t\n\t\tindex = (int**)malloc(sizeof(int*)*num);\n\t\tfor (int i = 0; i < num; i++)\n\t\t\tindex[i] = (int*)malloc(sizeof(int) * 2);\n\n\t\tfor (int i = 2; i <= num; i++)\n\t\t{\n\t\t\t/* Initialization */\n\t\t\tfor (int j = 0; j < i; j++)\n\t\t\t{\n\t\t\t\tindex[j][0] = j;\n\t\t\t\tindex[j][1] = j;\n\t\t\t}\n\n\t\t\tindex[i - 1][1] = num - 1;\n\n\t\t\t/* Verification */\n\t\t\twhile (index[0][1] != num - 2)\n\t\t\t{\n\t\t\t\tint subOK;\n\t\t\t\tfor (int j = 0; j < i; j++)\n\t\t\t\t{\n\t\t\t\t\tsubOK =\tcheckSubMatrix(index[j][0], index[j][1]);\n\t\t\t\t\tif (!subOK)\n\t\t\t\t\t\tbreak;\n\t\t\t\t}\n\n\t\t\t\tif (subOK)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\tprintf(\"%d\\n\", i);\n\t\t\t\t\tfor (int k = 0; k < i; k++)\n\t\t\t\t\t\tprintf(\"%d %d\\n\", index[k][0] + 1, index[k][1] + 1);\n\t\t\t\t\treturn 0;\n\t\t\t\t}\n\n\t\t\t\tfor (int j = i - 1; j >= 0; j--)\n\t\t\t\t{\n\t\t\t\t\tif (index[j][0] == index[j][1])\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tindex[j][0]++;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\n\n\n\n\t\t}\n\t}\n\n\t\n\tprintf(\"NO\\n\");\n\treturn 0;\n}\n\n\n\nbool checkSubMatrix(int start, int end)\n{\n\tint sum = 0;\n\tfor (int i = start; i <= end; i++)\n\t{\n\t\tsum += nums[i];\n\t}\n\n\tif (sum == 0)\n\t\treturn false;\n\telse\n\t\treturn true;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8d33a34b4583c17facce21e5560da076", "src_uid": "3a9258070ff179daf33a4515def9897a", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"yash\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/yash\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/yash\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "872450d37e3d16d326823d1a7848844c", "src_uid": "3a9258070ff179daf33a4515def9897a", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n//#include \"stack.h\"\n#define MAX_STACK\t100\n\n\ntypedef enum { false, true } bool;\ntypedef int Data;\n\ntypedef struct {\n\tData items[MAX_STACK];\n\tint top;\n} Stack;\n\n// Make stack empty.\nvoid InitStack(Stack *pstack);\n\n// Check whether stack is full.\nbool IsFull(Stack *pstack);\n\n// check whether stack is empty\nbool IsEmpty(Stack *pstack);\n\n// Read the item at the top.\nData Peek(Stack *pstack);\n\n// Insert an item at the top.\nvoid Push(Stack *pstack, Data item);\n\n// Remove the item at the top.\nvoid Pop(Stack *pstack);\n\nint main() {\n\tStack stack, result;\n\tint size, tmp, prev, cnt = 0;\n\tscanf(\"%d\", &size);\n\tint *arr = (int *)malloc(sizeof(int) * size);\n\tfor (int i = 0; i < size; i++)\n\t\tscanf(\"%d\", &arr[i]);\n\n\tif (size == 1 && arr[0] == 0) {\n\t\tprintf(\"NO\\n\");\n\t\tfree(arr);\n\t\treturn 0;\n\t}\n\n\tInitStack(&stack);\n\tInitStack(&result);\n\n\tfor (int i = 1; i <= size; i++) {\n\t\tif (arr[i] != 0) {\n\t\tPush(&stack, i);\n\t\tcnt++;\n\t\t}\n\t}\n\tfor (int i = 0; i < cnt; i++) {\n\t\ttmp = Peek(&stack);\n\t\tPush(&result, tmp);\n\t\tPop(&stack);\n\t}\n\t\n\tprintf(\"YES\\n\");\n\tfor (int i = 0; i < cnt; i++) {\n\t\ttmp = Peek(&result);\n\t\tif (i == 0)\n\t\t\tprintf(\"1  %d\\n\", tmp);\n\t\telse if (i != cnt - 1)\n\t\t\tprintf(\"%d  %d\\n\", prev + 1, tmp);\n\t\telse\n\t\t\tprintf(\"%d  %d\\n\", prev + 1, size);\n\t\tprev = tmp;\n\t\tPop(&result);\n\t}\n\n\tfree(arr);\n\treturn 0;\n}\n\n\n/************test***********\n11\n1 0 0 1 1 1 0 0 0 1 0\n\nyes\n1 3\n4 4\n5 5\n6 9\n10 11\n****************************/", "lang_cluster": "C", "compilation_error": true, "code_uid": "21178a53a7e631c5d8799ecaa4ba8b34", "src_uid": "3a9258070ff179daf33a4515def9897a", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int s2[120][2];\n    int s1[120];\n    int n,a,judge,i,sum,judge1,b,all;\n    while(scanf(\"%d\",&n)!=EOF)\n    {\n        judge=0;\n        i=0;\n        all=0;\n        for(a=1; a<=n; a++)\n        {\n            scanf(\"%d\",&s1[a]);\n            if(s1[a]>0)all=1;\n        }\n        if(s1[1]==0&&s1[n]==0&&all=1)\n        {\n            printf(\"YES\\n\");\n            printf(\"1 %d\\n\",n);\n        }\n        else\n        {\n            for(a=1; a<=n; a++)\n            {\n                if(s1[a]!=0)\n                {\n                    s2[i][0]=a;\n                    if(a==n)\n                    {\n                        s2[i][1]=a;\n                        i++;\n                    }\n                    else\n                    {\n                        judge=0;\n                        for(b=a+1; b<=n; b++)\n                        {\n                            if(s1[b])\n                            {\n                                break;\n                            }\n                        }\n                        s2[i][1]=b-1;\n                        i++;\n                        a=b-1;\n                    }\n                }\n                else\n                {\n                    sum=0;\n                    judge=1;\n                    judge1=0;\n                    for(b=a; b<=n; b++)\n                    {\n                        sum+=s1[b];\n                        if(sum!=0)\n                        {\n                            judge1=1;\n                            break;\n                        }\n                    }\n                    if(judge1==0)break;\n                    else\n                    {\n                        s2[i][0]=a;\n                        s2[i][1]=b;\n                        a=b;\n                        i++;\n                        judge=0;\n                    }\n                }\n                if(judge)break;\n            }\n            if(judge)printf(\"NO\\n\");\n            else\n            {\n                printf(\"YES\\n\");\n                printf(\"%d\\n\",i);\n                for(a=0; a<i; a++)\n                {\n                    printf(\"%d %d\\n\",s2[a][0],s2[a][1]);\n                }\n            }\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1561c0127ecafa6e506c73f692afc165", "src_uid": "3a9258070ff179daf33a4515def9897a", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nchar s1[101] = {0},s2[101] = {0},vir[101] = {0},ans[101][101][101] = {0};\nint f[101][101] = {0},len1,len2,lenv;\nint cmp(char *sa,char *sb)\n{\n    int i,cnt = 0;\n    for(i=0;sa[i]&&sb[i];i++) if(sa[i] == sb[i]) cnt++;\n    return cnt;\n}\nint main()\n{\n    int i,j;\n    scanf(\"%s%s%s\",s1,s2,vir);\n    len1 = strlen(s1);\n    len2 = strlen(s2);\n    lenv = strlen(vir);\n    for(i=1;i<=len1;i++)\n    {\n        for(j=1;j<=len2;j++)\n        {\n            if(s1[i-1] == s2[j-1])\n            {\n                f[i][j] = f[i-1][j-1] + 1;\n                memcpy(ans[i][j],ans[i-1][j-1],sizeof(ans[i][j]));\n                ans[i][j][f[i][j]-1] = s1[i-1];\n                if(cmp(ans[i][j],vir) != lenv) continue;\n            }\n            if(f[i-1][j]>f[i][j-1])\n            {\n                memcpy(ans[i][j],ans[i-1][j],sizeof(ans[i][j]));\n                f[i][j] = f[i-1][j];\n            }\n            else if(f[i-1][j]<f[i][j-1])\n            {\n                memcpy(ans[i][j],ans[i][j-1],sizeof(ans[i][j]));\n                f[i][j] = f[i][j-1];\n            }\n            else\n            {\n                if(cmp(ans[i-1][j],vir)>cmp(ans[i][j-1],vir))\n                {\n                    memcpy(ans[i][j],ans[i][j-1],sizeof(ans[i][j]));\n                    f[i][j] = f[i][j-1];\n                }\n                else\n                {\n                    memcpy(ans[i][j],ans[i-1][j],sizeof(ans[i][j]));\n                    f[i][j] = f[i-1][j];\n                }\n            }\n        }\n    }\n    if(f[len1][len2]) printf(\"%s\",ans[len1][len2]);\n    else printf(\"0\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "55e01f4899755c9a32e2b31b39b1d857", "src_uid": "391c2abbe862139733fcb997ba1629b8", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nchar s1[101] = {0},s2[101] = {0},vir[101] = {0},ans[101][101][101] = {0},ansans[101] = {0},maxans = 0;\nint f[101][101] = {0},len1,len2,lenv;\nint cmp(char *sa,char *sb)\n{\n    int i,cnt = 0;\n    for(i=0;sa[i]&&sb[i];i++) if(sa[i] == sb[i]) cnt++;\n    return cnt;\n}\nint work(char c)\n{\n    short swi = 0;\n    int i,j;\n    for(i=1;i<=len1;i++)\n    {\n        for(j=1;j<=len2;j++)\n        {\n            if(s1[i-1] == s2[j-1])\n            {\n                if(s1[i-1]!=c&&s2[j-1]!=c) if(!swi)\n                {\n                    swi = 1;\n                    continue;\n                }\n                f[i][j] = f[i-1][j-1] + 1;\n                memcpy(ans[i][j],ans[i-1][j-1],sizeof(ans[i][j]));\n                ans[i][j][f[i][j]-1] = s1[i-1];\n                if(cmp(ans[i][j],vir) != lenv) continue;\n            }\n            if(f[i-1][j]>f[i][j-1])\n            {\n                memcpy(ans[i][j],ans[i-1][j],sizeof(ans[i][j]));\n                f[i][j] = f[i-1][j];\n            }\n            else if(f[i-1][j]<f[i][j-1])\n            {\n                memcpy(ans[i][j],ans[i][j-1],sizeof(ans[i][j]));\n                f[i][j] = f[i][j-1];\n            }\n            else\n            {\n                if(cmp(ans[i-1][j],vir)>cmp(ans[i][j-1],vir))\n                {\n                    memcpy(ans[i][j],ans[i][j-1],sizeof(ans[i][j]));\n                    f[i][j] = f[i][j-1];\n                }\n                else\n                {\n                    memcpy(ans[i][j],ans[i-1][j],sizeof(ans[i][j]));\n                    f[i][j] = f[i-1][j];\n                }\n            }\n        }\n    }\n    if(f[len1][len2]>maxans)\n    {\n        memcpy(ansans,ans[len1][len2],sizeof(ansans));\n        maxans = f[len1][len2];\n    }\n}\nint main()\n{\n    int i;\n    scanf(\"%s%s%s\",s1,s2,vir);\n    len1 = strlen(s1);\n    len2 = strlen(s2);\n    lenv = strlen(vir);\n    work('a');\n    for(i=0;i<lenv;i++) work(vir[i]);\n    if(maxans) printf(\"%s\",ansans);\n    else printf(\"0\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "42cdb2bc5bdc1bb9c31f96fc2f2d95a1", "src_uid": "391c2abbe862139733fcb997ba1629b8", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nchar s1[101] = {0},s2[101] = {0},vir[101] = {0},ans[101][101][101] = {0},ansans[101] = {0},maxans = 0;\nint f[101][101] = {0},len1,len2,lenv;\nint cmp(char *sa,char *sb)\n{\n    int i,j,cnt = 0;\n    for(i=0;sa[i];i++)\n    {\n        if(sa[i] == sb[0])\n        {\n            for(j=0;sb[j];j++)\n            {\n                if(sa[i+j] == sb[j]) cnt++;\n            }\n        }\n    }\n    return cnt;\n}\nint work(char c)\n{\n    short swi = 0;\n    int i,j;\n    for(i=1;i<=len1;i++)\n    {\n        for(j=1;j<=len2;j++)\n        {\n            if(s1[i-1] == s2[j-1]&&s1[i-1] != c&&s2[j-1] != c)\n            {\n                f[i][j] = f[i-1][j-1] + 1;\n                memcpy(ans[i][j],ans[i-1][j-1],sizeof(ans[i][j]));\n                ans[i][j][f[i][j]-1] = s1[i-1];\n                if(cmp(ans[i][j],vir) != lenv) continue;\n            }\n            if(f[i-1][j]>f[i][j-1])\n            {\n                memcpy(ans[i][j],ans[i-1][j],sizeof(ans[i][j]));\n                f[i][j] = f[i-1][j];\n            }\n            else if(f[i-1][j]<f[i][j-1])\n            {\n                memcpy(ans[i][j],ans[i][j-1],sizeof(ans[i][j]));\n                f[i][j] = f[i][j-1];\n            }\n            else\n            {\n                if(cmp(ans[i-1][j],vir)>cmp(ans[i][j-1],vir))\n                {\n                    memcpy(ans[i][j],ans[i][j-1],sizeof(ans[i][j]));\n                    f[i][j] = f[i][j-1];\n                }\n                else\n                {\n                    memcpy(ans[i][j],ans[i-1][j],sizeof(ans[i][j]));\n                    f[i][j] = f[i-1][j];\n                }\n            }\n        }\n    }\n    if(f[len1][len2]>maxans)\n    {\n        memcpy(ansans,ans[len1][len2],sizeof(ansans));\n        maxans = f[len1][len2];\n    }\n}\nint main()\n{\n    int i;\n    scanf(\"%s%s%s\",s1,s2,vir);\n    len1 = strlen(s1);\n    len2 = strlen(s2);\n    lenv = strlen(vir);\n    work('a');\n    for(i=0;i<lenv;i++) work(vir[i]);\n    if(maxans) printf(\"%s\",ansans);\n    else printf(\"0\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "652b75ceafb9437e3fcf910de8aacc89", "src_uid": "391c2abbe862139733fcb997ba1629b8", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint res[100][100][100];\nint take[100][100][100];\nchar s1[101];\nchar s2[101];\nchar v[101];\n\nint get(int i, int j, int k)\n{\n    int r;\n    int b;\n    int t = 0;\n    if(v[k] == '\\0')\n        return -1;\n    if(s1[i] == '\\0' || s2[j] == '\\0')\n        return 0;\n    if(res[i][j][k] >= 0)\n        return res[i][j][k];\n    r = get(i + 1, j, k);\n    b = get(i, j + 1, k);\n    if(s1[i] == s2[j])\n    {\n        if(s1[i] == v[k])\n        {\n            if(v[k + 1] != '\\0')\n                t = get(i + 1, j + 1, k + 1) + 1;\n        }\n        else\n        {\n            t = get(i + 1, j + 1, 0) + 1;\n        }\n    }\n    if(t > r && t > b)\n    {\n        res[i][j][k] = t;\n        take[i][j][k] = 1;\n    }\n    else if(r > b)\n        res[i][j][k] = r;\n    else\n        res[i][j][k] = b;\n    return res[i][j][k];\n}\n\nvoid output(int i, int j, int k)\n{\n    int r;\n    int b;\n    if(s1[i] == '\\0' || s2[j] == '\\0' || v[k] == '\\0')\n        return;\n    if(take[i][j][k] != 0)\n    {\n        putchar(s1[i]);\n        if(s1[i] == v[k])\n            output(i + 1, j + 1, k + 1);\n        else\n            output(i + 1, j + 1, 0);\n    }\n    else\n    {\n        r = get(i + 1, j, k);\n        b = get(i, j + 1, k);\n        if(r > b)\n            output(i + 1, j, k);\n        else\n            output(i, j + 1, k);\n    }\n}\n\nint main()\n{\n    int i, j, k;\n    scanf(\"%s%s%s\", s1, s2, v);\n    for(i = 0; s1[i] != '\\0'; i++)\n        for(j = 0; s2[j] != '\\0'; j++)\n            for(k = 0; v[k] != '\\0'; k++)\n            {\n                take[i][j][k] = 0;\n                res[i][j][k] = -1;\n            }\n    if(get(0, 0, 0) <= 0)\n        putchar('0');\n    else\n        output(0, 0, 0);\n    printf(\"\\n\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1178d8c624bc507ecad818e6bc289a92", "src_uid": "391c2abbe862139733fcb997ba1629b8", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint res[100][100][100];\nint take[100][100][100];\nchar s1[101];\nchar s2[101];\nchar v[101];\nchar map[101];\n\nint get(int i, int j, int k)\n{\n\tint r;\n\tint b;\n\tint t = 0;\n\tint p;\n\tif(v[k] == '\\0')\n\t\treturn -1;\n\tif(s1[i] == '\\0' || s2[j] == '\\0')\n\t\treturn 0;\n\tif(res[i][j][k] >= 0)\n\t\treturn res[i][j][k];\n\tr = get(i + 1, j, k);\n\tb = get(i, j + 1, k);\n\tif(s1[i] == s2[j])\n\t{\n\t\tif(s1[i] == v[k])\n\t\t{\n\t\t\tif(v[k + 1] != '\\0')\n\t\t\t\tt = get(i + 1, j + 1, k + 1) + 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tfor(p = map[k]; p >= 0 && s1[i] != v[p]; p = map[p]);\n\t\t\tt = get(i + 1, j + 1, p + 1) + 1;\n\t\t}\n\t}\n\tif(t > r && t > b)\n\t{\n\t\tres[i][j][k] = t;\n\t\ttake[i][j][k] = 1;\n\t}\n\telse if(r > b)\n\t\tres[i][j][k] = r;\n\telse\n\t\tres[i][j][k] = b;\n\treturn res[i][j][k];\n}\n\nvoid output(int i, int j, int k)\n{\n\tint r;\n\tint p;\n\tint b;\n\tif(s1[i] == '\\0' || s2[j] == '\\0' || v[k] == '\\0')\n\t\treturn;\n\tif(take[i][j][k] != 0)\n\t{\n\t\tputchar(s1[i]);\n\t\tif(s1[i] == v[k])\n\t\t\toutput(i + 1, j + 1, k + 1);\n\t\telse\n\t\t{\n\t\t\tfor(p = map[k]; p >= 0 && s1[i] != v[p]; p = map[p]);\n\t\t\tt = get(i + 1, j + 1, p + 1) + 1;\n\t\t\toutput(i + 1, j + 1, p);\n\t\t}\n\t}\n\telse\n\t{\n\t\tr = get(i + 1, j, k);\n\t\tb = get(i, j + 1, k);\n\t\tif(r > b)\n\t\t\toutput(i + 1, j, k);\n\t\telse\n\t\t\toutput(i, j + 1, k);\n\t}\n}\n\nint main()\n{\n\tint i, j, k;\n\tscanf(\"%s%s%s\", s1, s2, v);\n\tfor(i = 0; s1[i] != '\\0'; i++)\n\t\tfor(j = 0; s2[j] != '\\0'; j++)\n\t\t\tfor(k = 0; v[k] != '\\0'; k++)\n\t\t\t{\n\t\t\t\ttake[i][j][k] = 0;\n\t\t\t\tres[i][j][k] = -1;\n\t\t\t}\n\tmap[0] = -1;\n\tmap[1] = 0;\n\tj = 0;\n\tfor(k = 2; v[k] != '\\0';)\n\t{\n\t\tif(v[j] == v[k - 1])\n\t\t{\n\t\t\tj++;\n\t\t\tmap[k++] = j;\n\t\t}\n\t\telse if(j > 0)\n\t\t\tj = map[j];\n\t\telse\n\t\t\tmap[k++] = 0;\n\t}\n\tif(get(0, 0, 0) <= 0)\n\t\tputchar('0');\n\telse\n\t\toutput(0, 0, 0);\n\tprintf(\"\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "57e984c64f8cf77f7818f6b454fcfa92", "src_uid": "391c2abbe862139733fcb997ba1629b8", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    int x,count=0,i;\n    long long int x;\n    scanf(\"%lld\",&x);\n    for(i=1;i<100;i++)\n    {\n        if(pow(2,i)>x)\n        {\n            i--;x=x-pow(2,i);count++;break;\n        }\n    }\n    for(i=i;i>=0;i--)\n    {\n        if(pow(2,i)<x)\n        {\n            x=x-pow(2,i);\n            count++;\n        }\n        if(x==1)\n        {\n            count++;break;\n        }\n    }\nprintf(\"%lld\",count);\nreturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5cf3a75517bf6e8a6fbd4a6a9aab7840", "src_uid": "03e4482d53a059134676f431be4c16d2", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "450e506be0f043b9ede57f6d5bb32f92", "src_uid": "03e4482d53a059134676f431be4c16d2", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n     int n,a=0;\n    scanf(\"%d\",&n);\n    while(n>0){\n        if(n%2==1){\n            x++;\n            n--;\n        }\n        else{\n            n/=2;\n        }\n    }\n    printf(\"%d\",a);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4a4ef88c2b8ed9aad625466ca2abe002", "src_uid": "03e4482d53a059134676f431be4c16d2", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int x, count, i;\n    scanf(\"%d\", &x);\n    while(x!=0){\n        if(x%2==1){\n            count++;\n            x--;\n            x=/2;\n        } else {\n            x=/2;\n        }\n    }\n    fprintf(stdout, \"%d\", count);\n    fclose(stdout);\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "99e85118d413c2f7694ae8c7dc8dabfd", "src_uid": "03e4482d53a059134676f431be4c16d2", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    int x,res=0,m;\n    int ans=0;\n    int po,closest_pow_oftwo,res;\n    scanf(\"%d\",&x);\n    if((x^(x-1))==0)      // we check whether a given number is exactly a power of 2 or not by checking whether the XOR of num and num-1 =0  or not\n    {\n        printf(\"1\");\n    }\n    else\n    {\n        while(x > 0) {\n            m = 1;\n            while(2*m <= n)\n                m *= 2;\n            res++;\n            x =x-m;\n        }\n        printf(\"%d\",res);\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1b244c0feb753768de9ee4ab0f4c01e9", "src_uid": "03e4482d53a059134676f431be4c16d2", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int x,y,n;\n    scanf(\"%d %d %d\",&x,&y,&n);\n    n=(n-1)%6;\n    switch(n)\n    {\n    case 0:\n        if(x<0)\n            printf(\"%d\",(1000000007-(-x)%1000000007)%1000000007);\n        else\n            printf(\"%d\",x);\n        return 0;\n    case 1:\n        if(y<0)\n            printf(\"%d\",(1000000007-(-y)%1000000007)%1000000007);\n        else\n            printf(\"%d\",y);\n        return 0;\n    case 2:\n        if((y-x)<0)\n            printf(\"%d\",(1000000007-(x-y)%1000000007)%1000000007);\n        else\n            printf(\"%d\",(y-x)%1000000007);\n        return 0;\n    case 3:\n        if(-x<0)\n            printf(\"%d\"(,1000000007-(x)%1000000007)%1000000007);\n        else\n            printf(\"%d\",-x);\n        return 0;\n    case 4:\n        if(-y<0)\n            printf(\"%d\",(1000000007-(y)%1000000007)%1000000007);\n        else\n            printf(\"%d\",-y);\n        return 0;\n    case 5:\n        if((-y+x)<0)\n            printf(\"%d\",(1000000007-(y-x)%1000000007)%1000000007);\n        else\n            printf(\"%d\",(-y+x)%1000000007);\n        return 0;\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c40231650dea18dcb86c24f31ef97ae1", "src_uid": "2ff85140e3f19c90e587ce459d64338b", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<algorithm>\n#include<string.h>\n#include<stack>\n#include<string>\n#include<stdio.h>\nusing namespace std;\n\ntypedef long long LL;\nconst int SIZE=20;\nconst LL MOD=1000000007;\n\nint main()\n{\n\tint x,y;\n\tscanf(\"%d%d\",&x,&y);\n\t\tint n;\n\t\tcin>>n;\n\t\tint a[10];\n\t\ta[1]=( (y-x)%MOD + MOD )%MOD;\n\t\ta[2]=( (-x)%MOD + MOD )%MOD;\n\t\ta[3]=( (-y)%MOD + MOD )%MOD;\n\t\ta[4]=((-y+x)%MOD + MOD )%MOD;\n\t\ta[5]=( (x)%MOD + MOD )%MOD;\n\t\ta[0]=( (y)%MOD + MOD )%MOD;\n\t\tprintf(\"%d\\n\",a[(n-2)%6]);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "bc033ce9c2b5919e8feb421fd8a1ac6f", "src_uid": "2ff85140e3f19c90e587ce459d64338b", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint maini()\n{\n    long long x,y,n,ans;\n    scanf(\"%I64d%I64d%I64d\",&x,&y,&n);\n    int a[6]={x,y,y-x,-x,-y,x-y};\n    ans=a[(n-1)%6];\n    if(ans<0)ans=(ans%1000000007)+1000000007;\n    printf(\"%I64d\",ans%1000000007);\n    return 0;\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "790d660a736ea72d9cc9b01c3b286f05", "src_uid": "2ff85140e3f19c90e587ce459d64338b", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "\n copy \n#include <stdio.h>\nlong long m=1000000007;\nint main(void) {\n\t// your code goes here\n\tlong long n,x,y,h,t,c;\n\tscanf(\"%lld %lld %lld\", &x,&y,&n);\n\tt=y-x;\n \n\tif(n%3==0)\n\t{ c=n/3;\n\t   if(c%2==0)\n\t   h=-t;\n\t   else \n\t   h=t;}\n \n\tif(n%3==1)\n\t{ c=n/3;\n\t   if(c%2==0)\n\t   h=x;\n\t   else \n\t   h=-x;}\n\t   if(n%3==2)\n\t{ c=n/3;\n\t   if(c%2==0)\n\t   h=y;\n\t   else \n\t   h=-y;}\n\t   if(h<0)\n\tprintf(\"%lld\", m-((-1*h)%m));\n\telse \n\tprintf(\"%lld\", h%m);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b6d280f4cb389de2ef1b50fa21974512", "src_uid": "2ff85140e3f19c90e587ce459d64338b", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<stdlib.h>\n#include<string.h>\n\n/*int cmp(const void *a, const void *b)\n{\n     return(*(int *)a-*(int *)b);\n}*/\n\n/*int cmp1(const void *a ,const void * b)\n{\n return (*(double *)a>*(double * )b?1:-1);\n}*/\n/*int gcd(int a,int b)\n{\n    return b ? gcd(b,a%b) : a;\n}*/\nlong long a[200000008] = {0};\nint main()\n{\n    long long n,i;\n    scanf(\"%I64d %I64d\",&a[1],&a[2]);\n    scanf(\"%I64d\",&n);\n    for(i = 3; i <= n; i++)\n    {\n        a[i] = a[i-1] - a[i-2];\n    }\n    printf(\"%I64d\",a[n] % 1000000007 > 0 ? a[n] % 1000000007:a[n] + 1000000007);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e40aff4afd1046b43951f2c38baaef21", "src_uid": "2ff85140e3f19c90e587ce459d64338b", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n int n,x,p;\n \n if(n%2==0)\n x=(n+1);\n printf(\"%d\",x);\n else\n p=(n+1)/2;\n printf(\"%d\",p);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f1244b9054477dbece8200962f51e186", "src_uid": "236177ff30dafe68295b5d33dc501828", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nint a,b;\nscanf(\"%d\",&a);\nif((a+1)%2==0)\n{\nb=((a+1)/2);\n}\nelse if(n==0)\n{\nb=0;\n}\nelse\n{\nb=a/2;\n}\nprintf(\"%d\",b);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0dd2549e1444aa9ee6eef015099a4fbe", "src_uid": "236177ff30dafe68295b5d33dc501828", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "main()\n{long long int i,k,;scanf(\"%I64d\",&i);\nk=i+1;if (k%2==0) printf(\"I64%d\",k/2);else printf(\"%I64d\",k);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7bf120653e0ad0d5d8e4ff4d30845a7f", "src_uid": "236177ff30dafe68295b5d33dc501828", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int n, x;\n    scanf(\"%d\", %n);\n    if (n%2 == 0)\n    {\n        x = n+1;\n        printf(\"%d\", x);\n    }\n    else\n    {\n        x = (n+1)/2;\n        printf(\"%d\", x);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dcdc0d3081e7309677dd03a709008f97", "src_uid": "236177ff30dafe68295b5d33dc501828", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nlong long main()\n{\n  long long n;\n  scanf(\"%lld\",&n);\n  if(n==0)\n  {\n  printf(\"%lld\",n)\n  }\n  else\n  {\n  if((n+1)%2==0)\n  {\n   printf(\"%lld\",(n+1)/2);\n  }\n  else\n  {\n  printf(\"%lld\",n+1);\n  }\n  };\n  return 0;\n  }", "lang_cluster": "C", "compilation_error": true, "code_uid": "eb378d55956e4ea93bd041e4150c23ea", "src_uid": "236177ff30dafe68295b5d33dc501828", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint verif(char *ch,char *mdp)\n{ char cha[3]; int i,a=0;\n    for(i=0;i<strlen(ch)-1;i++)\n    {strncpy(cha,ch+i,2);\n     cha[2]='\\0';\n\n     if(strcmp(cha,mdp)==0) a=1;\n    }\n     return a;\n}\nint main()\n{\nint n,i,j;\n\nscanf(\"%s\",mdp);\nscanf(\"%d\",&n);\nchar t[n][3]; char mdp[3]; char *ch;\n\nfor(i=0;i<n;i++)\n{\n    scanf(\"%s\",t[i]); }\n\nint test=0;\nfor(i=0;i<n;i++)\n{\n\nstrcpy(ch,t[i]);\n\nfor(j=0;j<n;j++)\n{   strcpy(ch,t[i]);\n    strcat(ch,t[j]);\n\nif(verif(ch,mdp)==1) test=1;\n}\n\n}\nif (test==1)\nprintf(\"YES\");\nelse printf(\"NO\");\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d5e6ca5a1dc30e78e31bb482c2283339", "src_uid": "cad8283914da16bc41680857bd20fe9f", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "\u315a#include <stdio.h>\n\nchar passwd[4], str[4];\nint main(){\n  scanf(\"%s\", passwd);\n\n  int T, num=0, chk=0;\n  scanf(\"%d\", &T);\n  while (T--) {\n    scanf(\"%s\", str);\n    if (str[0]==passwd[0] && str[1] == passwd[1])\n      chk=4;\n    else if (str[1]==passwd[0] && str[0]==passwd[1])\n      chk=4;\n    else if (str[0]==passwd[1]){\n      if (chk<4){\n        if (chk==1) chk=4;\n        else chk=2;\n      }\n    }\n    else if (str[1]==passwd[0]){\n      if( chk<4) {\n        if (chk==2) chk=4;\n        else chk=1;\n      }\n    }\n  }\n\n  if (chk==4) printf(\"YES\\n\");\n  else printf(\"NO\\n\");\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5d883ff685ee4063e944de0216e9a46d", "src_uid": "cad8283914da16bc41680857bd20fe9f", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main()\n{\n\t\n\tint n;\n\tchar input[3];\n\tchar parola[3];\n\t\n\tscanf(\"%s\", input);\n\tscanf(\"%d\", &n);\n\t\n\t\n\t//char parole[n][3];\n\tint prima=0, seconda=0;\n\t\n\tint i;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%s\", parola);\n\t\tif(strcmp(input, parola)==0)\n\t\t{\n\t\t\tprintf(\"YES\");\n\t\t\treturn 0;\n\t\t}\n\t\t\n\t\tif(input[1]==parole[i][0])\n\t\t{\n\t\t\tseconda=1;\n\t\t}\n\t\t\n\t\tif(input[0]==parole[i][1])\n\t\t{\n\t\t\tprima=1;\n\t\t}\n\t\t\n\t\tif(prima==1 && seconda==1)\n\t\t{\n\t\t\tprintf(\"YES\");\n\t\t\treturn 0;\n\t\t}\n\t\t\n\t}\n\t\n\tprintf(\"NO\");\n\t\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "42fc5e7b35f7bb238c228fc28c0fb84a", "src_uid": "cad8283914da16bc41680857bd20fe9f", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tbool x=false,y=false;\n\tint i,n,flag=0;\n\tchar a[10],b[10];\n\tscanf(\"%s%d\",&a,&n);\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tscanf(\"%s\",&b);\n\t\tif(b[1]==a[1]&&b[0]==a[0])\n\t\t{\n\t\t\tprintf(\"YES\");\n\t\t\treturn 0;\n\t\t}\n\t\tif(b[0]==a[1])x=true;\n\t\tif(b[1]==a[0])y=true;\n\t\tif(x&&y)\n\t\t{\n\t\t\tprintf(\"YES\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\"NO\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fad1a0caabc2cae0a33cdffaf15f5d6a", "src_uid": "cad8283914da16bc41680857bd20fe9f", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nusing namespace std;\nint main()\n{\n\tbool x=false,y=false;\n\tint i,n,flag=0;\n\tchar a[10],b[10];\n\tcin>>a>>n;\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tcin>>b;\n\t\tif(b[1]==a[1]&&b[0]==a[0])\n\t\t{\n\t\t\tcout<<\"YES\";\n\t\t\treturn 0;\n\t\t}\n\t\tif(b[0]==a[1])x=true;\n\t\tif(b[1]==a[0])y=true;\n\t\tif(x&&y)\n\t\t{\n\t\t\tcout<<\"YES\";\n\t\t\treturn 0;\n\t\t}\n\t}\n\tcout<<\"NO\";\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2f1b1cb000c25c78c77b526421642ca5", "src_uid": "cad8283914da16bc41680857bd20fe9f", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <malloc.h>\n\nint main()\n{\n\tint amount;\n\tscanf( \"%d\", &amount );\n\t\n\tint result;\n\t\n\tif( amount <= 0 )\n\t\tresult = 0;\n\tint d;\n\telse\n\t{\n\t\tint *array;\n\t\tarray = ( int * )malloc( amount * sizeof( int ) );\n\n\t\tint i = 0;\n\t\tfor( ; i < amount; i++ )\n\t\t{\n\t\t\tscanf( \"%d\", &array[ i ] );\n\t\t}\n\n\t\ti = 0;\n\n\t\tfor( ; i < amount; i++ )\n\t\t{\n\t\t\tif( array[ i ] == 1 )\n\t\t\t\tbreak;\n\t\t}\n\t\t\n\t\tif( i == amount )\n\t\t\tresult = 0;\n\t\t\n\t\telse\n\t\t{\n\t\t\tresult = 1;\n\t\t\tint variants = 1;\n\t\t\tfor( ; i < amount; i++ )\n\t\t\t{\n\t\t\t\tif( array[ i ] == 0 )\n\t\t\t\t\t++variants;\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tresult *= variants;\n\t\t\t\t\tvariants = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfree( array );\n\t}\n\n\tprintf( \"%d\\n\", result );\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6567c13927ec6c5bc53f0824e3903caa", "src_uid": "58242665476f1c4fa723848ff0ecda98", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main (int argc, char* argv[])\n{\n\n    int s=1;\n    int m=0;\n    int x;\n    int i,j,a;\n    int* memoire = NULL;\n    scanf(\"%d\",&x);\n    memoire = xmalloc(x*sizeof(int));\n    for (a=0,i=0;i<x;i++)\n    { scanf(\"%d\",&memoire[i]);\n        if(memoire[i]==1)\n        {\n            a=1;break;\n        }\n    }\n    if(a==1)\n    {\n        for(j=i+1;j<x;j++)\n    {\n        scanf(\"%d\",&memoire[j]);\n        m=m+1;\n        if (memoire[j]==1)\n            {\n                s=s*m;\n                m=0;\n\n            }\n    }\n    free(memoire);\n    }\n    else s=0;\n    printf(\"%d\",s);\n     return(0);\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4b6423ab53c87c0fe26534d3aef719c7", "src_uid": "58242665476f1c4fa723848ff0ecda98", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n,l=-1,r=0,z=0;\n    scanf(\"%d\",&n);\n    ll ar[n],cnt[n],scnt=0;\n    for(int i=0;i<n;i++)\n    scanf(\"%lld\",&ar[i]);\n    for(int i=0;i<n;i++)\n    {\n    if(ar[i]==1)\n    {\n    l=i;\n    break;\n    }\n    }\n    for(int i=n-1;i>l;i--)\n    {\n    if(ar[i]==1)\n    {\n    r=i;\n    break;\n    }\n    }\n    if(l==-1)\n    printf(\"0\");\n    else\n    {\n    if(r==0)\n    printf(\"1\");\n    else\n    {\n    for(int i=l+1;i<=r;i++)\n    {\n    if(ar[i]==1)\n    {\n    cnt[z++]=scnt+1;\n    scnt=0;\n    }\n    else\n    scnt++;\n    }\n    \n    ll mv=1;\n    for(int i=0;i<z;i++)\n    mv*=cnt[i];\n    printf(\"%lld\",mv);\n    }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "41d67ed7be2a6578bc2a67b8ba9261f6", "src_uid": "58242665476f1c4fa723848ff0ecda98", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main (int argc, char* argv[])\n{\n    \n    int s=1;\n    int m=0;\n    int x;\n    int i;\n    int* memoire = NULL;\n    scanf(\"%d\",&x);\n    memoire = malloc(x*sizeof(int));\n    for (i=0;i<x;i++)\n    {\n        scanf(\"%d,&memoire[i]\")\n        m=m+1;\n        if (memoire[i]==1)\n            {\n                s=s*m;\n                m=0;\n                \n            }\n    }\n    printf(\"%d\",s);\n    free(memoire);\n     return(s);\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2d73c30f27e1b3df193cff3938de545b", "src_uid": "58242665476f1c4fa723848ff0ecda98", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include<string.h>\n\nint main (int argc, char* argv[])\n{\n    int s=1;\n    int m=0;\n    int i;\n    for (i=2;i<argc-1;i++)\n    {m=m+1;\n    if (strchr(argv[i],'1')>=O)\n    {s=s*m;\n    m=0;}\n    }printf(\"%d\",s);\n     return(0);\n     }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "52a9697798b99f968f1270f2df72e7ca", "src_uid": "58242665476f1c4fa723848ff0ecda98", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <cstdio>\n\nint main()\n{\n    int n, m;\n    scanf(\"%d%d\", &n, &m);\n    if (n != 0 || m == 0)\n    {\n        printf(\"%d %d\\n\", (m > n ? m : n), (m != 0 ? n + m - 1 : n));\n    }\n    else\n    {\n        printf(\"Impossible\\n\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "51690064238e1ee56e9cdcbad1c7923c", "src_uid": "1e865eda33afe09302bda9077d613763", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n    int n,m;\n    scanf(\"%d %d\",&n,&m);\n    if(n){\n        printf(\"%d %d\",n+(0>m-n?0:m-n),n+((0>m-1?0:m-1));\n    }else{\n        printf(\"Impossible\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "be6435348d51c45aece4ec1236ff4542", "src_uid": "1e865eda33afe09302bda9077d613763", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,m,max,min;\n\tscanf(\"%d %d\",&n,&m);\n\tif(n==0 && m!=0)\n\tprintf(\"Impossible\");\n\telse\n\t{\n\t\tif(n>=m)\n\t\tmin=n;\n\t\telse\n\t\tmin=m;\n\t\tif(m==0)\n\t\tmax=n;\n\t\telse\n\t\tmax=n+m-1;\n\t\tprintf(\"%d %d\",mn,max);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e728391ae559cd926a76c01624f8118d", "src_uid": "1e865eda33afe09302bda9077d613763", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\nint n,m;\n scanf(\"%d%d\",&n,&m);\n    if(n==0)\n     printf(\"Impossible\");\n     else\n { if(n>=m)\n   {if(m==0)\n     printf(\"%d %d\",n,n)\n   else  \n    printf(\"%d %d\",n,n+m-1);}\n  else\n    printf(\"%d %d\",m,n+m-1);\n    }\n\n     return 0;\n     }       ", "lang_cluster": "C", "compilation_error": true, "code_uid": "c3526f34aba7bbba266b20e976dabec3", "src_uid": "1e865eda33afe09302bda9077d613763", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint\nmain (int argc, char *argv[])\n{\n\n  int n, m;\n  int min, max;\n\n  scanf (\"%d %d\", &n, &m);\n\n\n\n  if (n == 0)\n    {\n      if (m > 0)\n\tprintf (\"Impossible\");\n      else \n\tprint (\"0 0\");\n    }\n  else\n    {\n      if (n >= m)\n\tmin = n;\n      else\n\tmin = m;\n      if (m > 0)\n\tmax = n + m - 1;\n      else\n\tmax = n;\n      printf (\"%d %d\", min, max);\n    }\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "117e93e5af4964f4e721e8dc029a56a3", "src_uid": "1e865eda33afe09302bda9077d613763", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,i,c=0,d,k;\n    scanf(\"%d\",&n);\n    char s[n];\n      scanf(\"%s\",s);\n        d=n/11;\n        \n        for(i=0; i<n; i++)\n        {\n            \n            \n            if(s[i]=='8')\n                c++;\n        }\n        \n        if(c!=0 && d>c){\n            printf(\"%d\\n\",c);\n        }\n        else if(c>=d && c!=0)\n            printf(\"%d\\n\",d);\n        else\n        printf(\"0\\n\");\n    ", "lang_cluster": "C", "compilation_error": true, "code_uid": "b3d391d78b3ce1aeea32e07d7a56e674", "src_uid": "259d01b81bef5536b969247ff2c2d776", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint x,z,i;std::char[100] y;main(){printf(\"%d %s\",x,y);for(i=0;i<x;i++)if(y[i]=='8')z++;if(x/11<z)printf(\"%d\",x/11);else printf(\"%d\",z);}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b40c3416a3c0ab477135e1149d333509", "src_uid": "259d01b81bef5536b969247ff2c2d776", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "\n\n{\n    int i,z,k,l=0;\n    char str[100000];\n\n    scanf(\"%d %s\",&z,&str);\n\n    k=z/11;\n\n    for(i=0;i<z;i++)\n        if(str[i]=='8')\n          l++;\n\n    if(k<l)\n        printf(\"%d\\n\",k);\n    else \n        printf(\"%d\\n\",l);\n\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2f012365e1ed27bd702883e50ac79347", "src_uid": "259d01b81bef5536b969247ff2c2d776", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n\n\nint main()\n{\n    int i,n,k,count=0;\n\n    char s[1000];\n\n\n    scanf(\"%d\",&n);\n\n\n\n    scanf(\"%s\",s);\n    if(n<11)\n    {\n        printf(\"0\\n\");\n    }\n\n    for(i=0;i<=n;i++)\n    {\n        if(s[i]=='8')\n        count++;\n    }\n    k=n/11;\n\n    if(count/k>1)\n    {\n        printf(\"%d\\n\",k);\n    }\n    else\n        printf(\"%d\\n\",count);\n\n\n}\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1b4a2f8a6570903028c60ffa628a2021", "src_uid": "259d01b81bef5536b969247ff2c2d776", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n    int flag=0,p,empty[0];\n    char n,i,j;\n    scanf(\"%d\",&n);\n    gets(empty);\n    char a[n];\n    gets(a);\n    p=strlen(a);\n\n    for(i=0,j=n-1;i<n,j>0;i++,j--)\n    {\n        if(a[i] == '8' || a[j] == '8')\n        flag=1;\n        break;\n    }\n    if(flag == 1 && a[0]== a[i] || a[0]==a[j])\n        {\n            printf(\"%d\",p/11);\n        }\n    else\n        printf(\"0\");\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ca16b7deeb69b1d9caf7c2c9c8508da1", "src_uid": "259d01b81bef5536b969247ff2c2d776", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n,\n    scanf(\"%d\",&n);\n    if(n==4 && n==7){\n        printf(\"Yes\\n\");\n        else\n        printf(\"No\\n\");\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "724358a673d53ace1bdb4006f682e12f", "src_uid": "33b73fd9e7f19894ea08e98b790d07f1", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlub.h>\nint main(){\n\tlong long n;\n\tscanf(\"%lld\",&n);\n\twhile(n){\n\t\ts=n%10;\n\t\tn /=10;\n\t\tif(s==4 || s==7)\tc++;\n\t}\n\twhile(c){\n\t\tp=c%10;\n\t\tc /=10;\n\t\tif(p!=4 && p!=7) \tc2++;\n\t\tif(c2>0){\n\t\t\tprintf(\"NO\");\n\t\t\tbreak;\n\t\t}\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "370f89a7121dc1a8398ab3bb19e9cc0c", "src_uid": "33b73fd9e7f19894ea08e98b790d07f1", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nint main(void)\n{\nlong long int k;\nint i,n,count=0,j;\nj=(int)malloc(sizeof(k));\nlong long char lucky[10000];\nscanf(\"%s\",lucky);\nn=strlen(lucky);\nfor(i=0;i<n;i++)\n{\nif (lucky[i]=='4'||lucky[i]=='7') count++;\n\n}\nif (count==4||count==7)\nprintf(\"yes\\n\");\nelse printf(\"no\\n\");\n\n\nreturn 0 ;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "76ce9c7fc41c3a0594d4827bfc09f742", "src_uid": "33b73fd9e7f19894ea08e98b790d07f1", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\nint main()\n{\n\tchar num[19];\n\tscanf(\"%s\",&num);\n\tint len=strlen(num),i,count=0;\n\tfor(i=0 ; i<len ; i++){\n\t\tif(num[i]=='7'||num[i]=='4') count++ ;\n\t}\n\telse if(count='4' || count=='7') printf(\"YES\\n\");\n\telse printf(\"NO\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ca3d99517cea434a831b14a1c6ab0b37", "src_uid": "33b73fd9e7f19894ea08e98b790d07f1", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main (){\n    int p,q,i,n;\n    int c=0;\n    for(i=1;i<n;i++){\n        scanf(\"%d%d\",&d,&q);\n        if((q-p)>=2)\n        c++\n    }\n    printf(\"%d\",c);\n}\nreturn 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "e1a31fd3810f453b3463bf0f4ca7038b", "src_uid": "33b73fd9e7f19894ea08e98b790d07f1", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "include<stdio.h>\nint main()\n{\n\tint n,d,h;\n\tscanf(\"%d%d\",&n,&d);\n\th=8-d;\n\tswitch (n)\n\t{\n\t\tcase 1:case 3:case 5:case 7: case 8:case 10:case 12: if (\n\t\t\t(31-h)%7==0)\n\t\t\t{\n\t\t\t\tprintf (\"%d\",(31-h)/7+1);\n\t\t\t}\n\t\t\telse printf (\"%d\",(31-h)/7+2);\n\t\t\t;break;weekday of the first date of this month (\n\t\t\tcase 2: if ((28-h)%7==0)\n\t\t\t{\n\t\t\t\tprintf (\"%d\",(28-h)/7+1);\n\t\t\t}\n\t\t\telse printf (\"%d\",(28-h)/7+2);\n\t\t\tbreak;\n\t\t\tcase 4:case 6:case 11: if ((30-h)%7==0)\n\t\t\t{\n\t\t\t\tprintf (\"%d\",(30-h)/7+1);\n\t\t\t}\n\t\t\telse printf (\"%d\",(30-h)/7+2);\n\t\t\tbreak;\n}\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ef903e2accfea8f0357d3e1998cde40a", "src_uid": "5b969b6f564df6f71e23d4adfb2ded74", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,d,h;\n\tscanf(\"%d%d\",&n,&d);\n\th=8-d;\n\tswitch (n)\n\t{\n\t\tcase 1:case 3:case 5:case 7: case 8:case 10:case 12: if (\n\t\t\t(31-h)%7==0)\n\t\t\t{\n\t\t\t\tprintf (\"%d\",(31-h)/7+1);\n\t\t\t}\n\t\t\telse printf (\"%d\",(31-h)/7+2);\n\t\t\t;break;weekday of the first date of this month (\n\t\t\tcase 2: if ((29-h)%7==0)\n\t\t\t{\n\t\t\t\tprintf (\"%d\",(29-h)/7+1);\n\t\t\t}\n\t\t\telse printf (\"%d\",(29-h)/7+2);\n\t\t\tbreak;\n\t\t\tcase 4:case 6:case 11: if ((30-h)%7==0)\n\t\t\t{\n\t\t\t\tprintf (\"%d\",(30-h)/7+1);\n\t\t\t}\n\t\t\telse printf (\"%d\",(30-h)/7+2);\n\t\t\tbreak;\n}\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3f9b74edb6b48dc6e80b46a2b46815ee", "src_uid": "5b969b6f564df6f71e23d4adfb2ded74", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#incude<math.h>\nint main()\n{\n    int a[20]={0,31,28,31,30,31,30,31,31,30,31,30,31};\n    int n,m,sum = 0;\n    scanf(\"%d%d\",&n,&m);\n    a[n] -= fabs(m-8);\n    if(a[n]%7!=0)\n    sum++;\n    printf(\"%d\\n\",sum+a[n]/7+1);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5acb022cd9417f101bf7c97a736e8bda", "src_uid": "5b969b6f564df6f71e23d4adfb2ded74", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    \n    int m,d;\n    scanf(\"%d%d\",m,d);\n    int mday=0;\n    switch(d)\n    {\n        case 1:mday=31;break;\n        case 2:mday=28;break;\n        case 3:mday=31;break;\n        case 4:mday=30;break;\n        case 5:mday=31;break;\n        case 6:mday=30;break;\n        case 7:mday=31;break;\n        case 8:mday=31;break;\n        case 9:mday=30;break;\n        case 10:mday=31;break;\n        case 11:mday=30;break;\n        case 12:mday=31;break;\n    }\n    prinf(\"%d\",(d-1)+mday%7==0? (d-1)+mday/7:((d-1)+mday/7)+1);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e66f0557de48e933a202991b719d082d", "src_uid": "5b969b6f564df6f71e23d4adfb2ded74", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nstruct year {\n\tint days;\n};\nint main(void)\n{\n\tstruct year month[13] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 };\n\tint m, d,t,out;\n\n\tscanf_s(\"%d%d\", &m, &d);\n\tt = month[m].days-(7 - d + 1);\n\tif (t % 7 == 0)\n\t\tprintf(\"%d\", t / 7 + 1);\n\telse\n\t\tprintf(\"%d\", t / 7 + 2);\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a67c5714c2a5d1c22dfbe3e346a1efb3", "src_uid": "5b969b6f564df6f71e23d4adfb2ded74", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "puts(25);\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "285965dc55d9d99a6a6bfcd96a949781", "src_uid": "dcaff75492eafaf61d598779d6202c9d", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n int n,x;\n scanf(\"%d\",&n);\n x=25\n printf(\"%d\",x);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1a0a82102a4575aa7ccee7dea472aad9", "src_uid": "dcaff75492eafaf61d598779d6202c9d", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    char aj[100];\n    long long int x,y,b;\n    scanf(\"%lld\",&x);\n    if(x==1)\n      t=5\n    else\n   {\n   y=pow(5,x);\n    t=y+1\n}\nsprintf(aj,\"%d\",t);\nb=strlen(aj);\nprintf(\"%c%c\",aj[b-2],aj[b-1]);\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "07cabe8bfb4b41715b7778d453783d5f", "src_uid": "dcaff75492eafaf61d598779d6202c9d", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<math.h>\nint main()\n{\nlong long int n,k,k1,k2;\nscanf(\"%lld\",&n);\nk=pow(5,n);\nif(k<=25)\n    printf(\"%lld\\n\",(k+1);\nelse\n{\n    k1=k%10;\n    k=k/10;\n    k2=k%10;\n    k=(k2*10)+k1;\n    printf(\"%lld\\n\",(k+1);\n}\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8a8d97b065c8fff94c3ee8ac581183e0", "src_uid": "dcaff75492eafaf61d598779d6202c9d", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{ \n    int n,s;\n    scanf(\"%d\",&n);\n    s = pow(5,n);\n    printf(\"%d\",s);\n    return o;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9de1a531ae93768241592dfcd6f75f2c", "src_uid": "dcaff75492eafaf61d598779d6202c9d", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n    int main()\n{\n   int i,j=0,n;\n   char s[50];\n   scanf(\"%d\",&n);\n   scanf(\"%s\",&s)\n    for(i=0;i<n-1;i++)\n    {\n        if(s[i]==s[i+1])\n        {\n            j++;\n        }\n    }\n    printf(\"%d\",j);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "899eef2d7d4e8e0a646c1f2d5b0ed6d6", "src_uid": "d561436e2ddc9074b98ebbe49b9e27b8", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <string.h>\nint main() {\n    char katar[50];\n    int sayac=0,i;\n    gets(katar);\n    while(strstr(katar,\"RR\") || strstr(katar,\"GG\") || strstr(katar,\"BB\")) {\n        sayac++;\n        katar+=1;\n    }\n    printf(\"%d\",sayac);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5c84f47b68d32ffd0b5f3d915813431d", "src_uid": "d561436e2ddc9074b98ebbe49b9e27b8", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nvoid main()\n{\n    int n,count=0;\n    scanf(\"%d\",&n);\n    char s[];\n    scanf(\"%s\",&s);\n    for(int i=0;i<n;i++)\n    {\n        if(s[i]==s[i+1])\n            count+=1;\n    }\n    printf(\"%d\",count);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "45ac94b8f5ddda2cb43090b33c1d1ca4", "src_uid": "d561436e2ddc9074b98ebbe49b9e27b8", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n    int t,c=0,i;\n    char a[50];\n    scanf(\"%d\",&t);\n    scanf(\"%s\",a);\n    for(i=0;i<t-1;i++){\n        if(a[i]==a[i+1])\n        c++;\n    }\n    printf(\"%d\\n\",c)\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ae43abe6477afee2521161727a6d0f0c", "src_uid": "d561436e2ddc9074b98ebbe49b9e27b8", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main() {\n  int n,i;\n   scanf(\"&d\\n\",&n);\n   char s[n];\n   for(i=0;i<n;i++)\n   {\n       scanf(\"%s\",s[i++])\n   }\nint len =strlen(s);\n  int ans = 0;\n  for (i = 0; i < len-1; i++) {\n    if (s[i] == s[i+1]) ans++;\n  }\n  printf(\"\\n%d\",ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1537102ea5f546ed7fa60ce0bf645388", "src_uid": "d561436e2ddc9074b98ebbe49b9e27b8", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int d,sumTime,minTime=0,maxTime=0;\n    scanf(\"%d %d\",&d,&sumTime);\n    int a[d],b[d];\n    for(int i=0;i<d;i++)\n    {\n        scanf(\"%d %d\",&a[i],&b[i]);\n        minTime+=a[i];\n        maxTime+=b[i];\n    }\n    if(sumTime<=maxTime && sumTime=>minTime)\n    {\n        printf(\"YES\\n\");\n    }\n    else\n        printf(\"NO\\n\");\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "089c9cdc12386a0197a466ef0954dca1", "src_uid": "f48ff06e65b70f49eee3d7cba5a6aed0", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int d,sum,min[30],max[30],avail[30],allot[30],i,summ=0; \n    scanf(\"%d %d\",&d,&sum); \n    int toallot=sum,alloted=0;\n    for(i=0;i<d;i++)\n    scanf(\"%d %d\",&min[i],&max[i]);\n    for(i=0;i<d;i++)\n    summ+=max[i];\nif(summ<sum)\nprintf(\"NO\");\nelse if (summ==sum)\n{\nfor(i=0;i<d;i++)\nallot[i]=max[i];\nprintf(\"YES\\n\");\nfor(i=0;i<d;i++)\nprintf(\"%d \",allot[i]);\n}\nelse\n{\nfor(i=0;i<d;i++){\nallot[i]=min[i];\nalloted+=min[i];\ntoallot-=min[i];\n}\ni=0;\nwhile(toallot!=0)\n{\nif(toallot+min[i]-max[i]>=0)\n{\nallot[i]=max[i];\nalloted=alloted-min[i]+max[i];\ntoallot=toallot+min[i]-max[i];\n}\nelse\n{\nallot[i]+=toallot;\n}\ni++;\n} \nprintf(\"YES\\n\"); \nfor(i=0;i<d;i++) \nprintf(\"%d \",allot[i]);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8b1db26b246acf94724fde593799bb27", "src_uid": "f48ff06e65b70f49eee3d7cba5a6aed0", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdlib.h>\n#include<stdio.h>\n\nint main(int argc, char const *argv[])\n{\n    int d;\n    int a=0;\n    int sumtime ;\n    scanf(\"%d %d\",&d&sumtime);\n    int outln2[d];\n    int maxtime[d];\n    int mintime[d];\n    int verdict = 1;\n    for(int i = 0;i<d;i++)\n    {\n        \n        scanf(\"%d %d \",&mintime[i],&maxtime[i]);\n        \n        a += maxtime[i];\n\n    }\n    if (a<sumtime)\n        {\n            verdict = 0;\n        }\n    if (verdict ==0)\n    printf(\"NO\");\n\n    else\n    {\n        int c = sumtime%d;\n        int b = sumtime/d;\n        for(int i = 0;i<d;i++)\n        {\n            outln2[i] = b;\n            while (c!=0)\n            {\n                if (outln2[i]<<maxtime[i])\n            {\n                outln2[i]+=(maxtime[i]-outln2[i]);\n                c-=(maxtime[i]-outln2[i]);\n            }\n            }\n        }\n\n        printf(\"YES\\n\");\n        for(int i = 0;i<d;i++)\n        {\n           printf(\"%d \",outln2[i]);\n        }\n        \n\n\n    }\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4354a12f7a8f0ce530777751f38cff11", "src_uid": "f48ff06e65b70f49eee3d7cba5a6aed0", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nmain()\n{\n\tfflush(stdout);\n\tint d,sumtime;\n\tscanf(\"%d %d\",&d,&sumtime);\n\tint mintime[d],int maxtime[d];\n\tfor(int i=0;i<d;i++)\n\t\tscanf(\"%d %d\",&mintime[i],&maxtime[i]);\n\tint minsum=0,maxsum=0;\n\tfor(int i=0;i<d;i++)\n\t{\n\t\tminsum+=mintime[i];\n\t\tmaxsum+=maxtime[i];\n\t}\n\tif(sumtime<minsum || sumtime>maxsum)\n\t{\t\n\t\tprintf(\"NO\\n\");\n\t\tfflush(stdout);\n\t}\n\telse\n\t{\n\t\tint hours[d];\n\t\tfor(int i=0;i<d;i++)\n\t\t{\n\t\t\thours[i]=mintime[i];\n\t\t\tsumtime=sumtime-mintime[i];\n\t\t}\n\t\twhile(sumtime>0)\n\t\t{\n\t\t\tif(sumtime>=(maxtime[i]-mintime[i]))\n\t\t\t{\n\t\t\t\thours[i]+=maxtime[i]-mintime[i];\n\t\t\t\tsumtime=sumtime-(maxtime[i]-mintime[i]);\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\thours[i]+=sumtime;\n\t\t\t\tsumtime=0;\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<d;i++)\n\t\t\tprintf(\"%d \",hours[i]);\n\t\tfflush(stdout);\n\t\t\n\t}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "817cb0bfc9d9f4228ad420e71733e435", "src_uid": "f48ff06e65b70f49eee3d7cba5a6aed0", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define SIZE 30\n\nint main ()\n{\n    int d, sum, min [SIZE], max [SIZE], a [SIZE], count = 0, flag;\n    scanf (\"%d %d\", &d, &sum);\n    for (int i = 0 ; i < d; i ++)\n    {\n        scanf (\"%d %d\", &min [i], &max [i]);\n        a [i] = min [i]\n        count += min [i];\n    }\n    if (count > sum)\n        printf (\"NO\");\n    else\n    {\n        flag = 0;\n        for (int i = 0; i < d; i ++)\n        {\n            if (count - min [i] + max [i] >= sum)\n            {\n                flag = 1;\n                a [i] += sum - count;\n                break;\n            }\n            else\n            {\n                a [i] = max [i];\n                count += max [i] - min [i];\n            }\n        }\n        if (flag)\n        {\n            for (int i = 0; i < d; i ++)\n                printf (\"%d \", &a [i]);\n        }\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "684bb03702c7be627d39788ae14f8e47", "src_uid": "f48ff06e65b70f49eee3d7cba5a6aed0", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\nint cmpfun(const void*a,const void*b)\n{\n\treturn(*(int*)a-*(int*)b);\n}\nint main()\n{\n\tint i,j,k,l,m,z=0,w=0,n;int x[10000];\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\",&x[i]);\n\t}\n\tqsort(a,n,sizeof(int),cmpfun);\n\tk=a[0];\n\tx[0]=x[n-1];\n\tx[n-1]=k;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tprintf(\"%d \",x[i]);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "00489c9ae556475866f7483bd8eab4e4", "src_uid": "4408eba2c5c0693e6b70bdcbe2dda2f4", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\ncmpfun(const void*a,const void*b)\n{\n\treturn(*(int*)a-*(int*)b);\n}\nint main()\n{\n\tint i,j,k,l,m,z=0,w=0,n;int x[10000];\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\",&x[i]);\n\t}\n\tqsort(a,n,sizeof(int),cmpfun);\n\tk=a[0];\n\tx[0]=x[n-1];\n\tx[n-1]=k;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tprintf(\"%d \",x[i]);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b347244efdc1748646df1150ce754d9b", "src_uid": "4408eba2c5c0693e6b70bdcbe2dda2f4", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\ncmpfun(const void*a,const void*b)\n{\n\treturn(*(int*)a-*(int*)b);\n}\nint main()\n{\n\tint i,j,k,l,m,z=0,w=0,n;int a[10000];\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\",&a[i]);\n\t}\n\tqsort(a,n,sizeof(int),cmpfun);\n\tk=a[0];\n\ta[0]=a[n-1];\n\ta[n-1]=k;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tprintf(\"%d \",a[i]);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6217b19900596920a758236b48e4c6ea", "src_uid": "4408eba2c5c0693e6b70bdcbe2dda2f4", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint compare (const void * a, const void * b)\n{\n\t  return ( *(int*)a - *(int*)b );\n}\n\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tint a[n],i,j;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\",&a[i]);\n\t}\n\tqsort(a,n,sizeof(int),compare);\n\tj=a[n-1];\n\ta[n-1]=a[0];\n\ta[0]=j;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tprintF(\"%d\\n\",a[i]);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2799433b7a8eb945c3449866bd1d0ba9", "src_uid": "4408eba2c5c0693e6b70bdcbe2dda2f4", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\n#define MAX_TESTS 100\n\nint num[MAX_TESTS];\nint numTests;\nint min = 0;\nint max = 0;\nint minIndex = 0;\nint maxIndex = 0;\n\nvoid swap(int i, int j){\n\tif(i == j){\n\t\treturn;\n\t}\n\tnum[i] = num[i] ^ num[j];\n\tnum[j] = num[i] ^ num[j];\n\tnum[i] = num[i] ^ num[j];\n}\n\nint compare(const void* x, const void* y){\n\treturn *((int*)x) - *((int*)y);\n}\n\nint main(void){\n\tfscanf(stdin,\"%d\",&numTests);\n\tfscanf(stdin,\"%d\",num);\n\tmin = max = num[0];\n\n\tfor(int i = 1; i < numTests; i++){\n\t\tfscanf(stdin,\"%d\",num + i);\n\t\tif(min > num[i]){\n\t\t\tmin = num[i];\n\t\t\tminIndex = i;\n\t\t}else if(max < num[i]){\n\t\t\tmax = num[i];\n\t\t\tmaxIndex = i;\n\t\t}\n\t}\n\n\tswap(0, maxIndex);\n\tswap(numTests - 1, minIndex);\n\n\tqsort(num + 1, numTests - 2, sizeof(int), &compare);\n\n\tfor(int i = 0; i < numTests - 1; i++){\n\t\tfprintf(stdout,\"%d \",num[i]);\n\t}\n\tfprintf(stdout,\"%d\\n\",num[numTests - 1]);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4aaa65fc99aff5ee2d77d58dce82d108", "src_uid": "4408eba2c5c0693e6b70bdcbe2dda2f4", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main(int argc, char const *argv[])\n{\n\tint a;\n\tscanf(\"%d\",&a);\n\tfor (int i = 2; i < d; ++i)\n\t{\n\t\tif(a%i == 0){\n\t\t\tprintf(\"%d\",i );\n\t\t\t\n\t\t}\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4c533d6c34554c67fbc8f9b97aac4761", "src_uid": "7220f2da5081547a12118595bbeda4f6", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int num, i;\n    scanf(\"%d\", &num);3\n    for(i = 2;i < num;i++){\n        if(num % i == 0){\n            printf(\"%d%d\\n\", i, num/i);\n            break;\n        }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d91a6b894c4e1391b26f9cabebed6462", "src_uid": "7220f2da5081547a12118595bbeda4f6", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    if(n==35)\n    {\n        printf(\"57\\n\");\n    }\n    if(n==57)\n    {\n        printf(\"319\\n\");\n    }\n    if(n==391)\n    {\n        printf(\"1723\\n\");\n    }\n    if(n==1723)\n    {\n        printf(\"35\\n\")\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2a2dbab517427f101b499f42da9d4a6c", "src_uid": "7220f2da5081547a12118595bbeda4f6", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nvoid main()\n{\n    int n;\n    scanf (\"%d\",&n);\n    for (int i=2;i<=n;i++)\n    {\n        if (n%i==0)\n        {\n            printf(\"%d%d\",i,n/i);\n            break;\n        }\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "2dd837f7e1a9f791bf74f9c355579312", "src_uid": "7220f2da5081547a12118595bbeda4f6", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(void)\n{\n    int x, i = 2;\n    \n    scanf(\"%d\", &x);\n    \n    while(1) if(!(x%i++)) printf(\"%d%d\\n\", i-1, x/(i-1));\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4307d9bc8762b2776a25edc5564b5502", "src_uid": "7220f2da5081547a12118595bbeda4f6", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nlong long int a,b;\nscanf(\"%lld\",&a);\nb=(n*(n+1))/2;\nif(b%2==0)\n{\nprintf(\"1\");\n}\nelse\n{\nprintf(\"0\");\n}\nreturn 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "70f4993df7ef89c5fb796b82dfa04309", "src_uid": "fa163c5b619d3892e33e1fb9c22043a9", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n    int sum (int k)\n    {\n           int sum=0;\n           sum=(k*(k+1))/2;\n                     if(sum%2==0)\n                    { \n                       return 0;\n                   else\n                       return 1;\n}\n\n                 int main()\n                int k,n;\n                 scanf(\"%d\",&k);\n                 n=sum(k);\n                 printf(\"%d\",n);\n                  return 0;\n\t\t\t  \n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4433400698835e29af951235d9b313c8", "src_uid": "fa163c5b619d3892e33e1fb9c22043a9", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "include <stdio.h>\n\nint main()\n{\n#ifdef _DEBUG\n>---//freopen(\"input.txt\", \"r\", stdin);\n>---//freopen(\"output.txt\", \"w\", stdout);\n#endif\n>---int n;\n>---scanf(\"%d\", &n);\n>---n %= 4;\n>---if (n == 0 || n == 3)\n>--->---printf(\"0\");\n>---else\n>--->---printf(\"1\");\n>---return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b8e8a5d1e317e28900ecaf73b45cca6b", "src_uid": "fa163c5b619d3892e33e1fb9c22043a9", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "include <stdio.h> int main(){  int i, j, k; long int n; scanf(\"%ld\", &n); long int sum = 0; sum = n*(n+1)/2; if(sum%2 == 1) printf(\"1\"); if(sum%2 == 0) printf(\"0\"); return 0; }", "lang_cluster": "C", "compilation_error": true, "code_uid": "efce8caa3f9195b3a9dcbdcb08def2c6", "src_uid": "fa163c5b619d3892e33e1fb9c22043a9", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main(){ \nint i, j, k; \nlong int n; \nscanf(\"%ld\", &n); \nlong float sum = 0; sum = n*(n+1)/2;\nif(sum%2 == 1) printf(\"1\");\nif(sum%2 == 0) printf(\"0\"); \nreturn 0; }", "lang_cluster": "C", "compilation_error": true, "code_uid": "acf2c73f81c1801628cc251d77133d71", "src_uid": "fa163c5b619d3892e33e1fb9c22043a9", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\nint main()\n{\n    int n;\n    cin >> n;\n    for (int i = 20; i >= 0; i--)\n    {\n        if (n & (1 << i)) cout << i + 1 << \" \";\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7ba9cbd54edb2e431a9fed65bc587a80", "src_uid": "757cd804aba01dc4bc108cb0722f68dc", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\nusing namespace std;\ntypedef long long ll;\nll x[100005];\nint main()\n{\n\tll top = -1, n;\n\tcin >> n;\n\twhile (n--)\n\t{\n\t\tx[++top] = 1;\n\t\twhile (top >= 0 && x[top - 1])\n\t\t{\n\t\t\t++x[top - 1];\n\t\t\ttop--;\n\t\t}\n\t}\n\tcout << x[1];\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "51db79302fd4cb3ed1aacfaaf6e0a5bb", "src_uid": "757cd804aba01dc4bc108cb0722f68dc", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n    int za, cvp = 1, x = 0;\n    scanf(\"%d\",&za);\n    while(n){\n        cvp = 1;\n        x = 0;\n        while(cvp<=za){cvp*=2;x++;}cvp/=2;x--;\n\n\n\n\n\n        printf(\"%d \",x+1);\n        n-=cvp;\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "eeb97a89e62d85cf3ccb1cb97dc82c49", "src_uid": "757cd804aba01dc4bc108cb0722f68dc", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<String.h>\n#define inf 0xffffffffff\nint a[inf];\nint n;\nvoid work(){\n\tint i;\n\tint x=n;\n\tint count=0;\n\tint m=1;\n\twhile(x){\n\t\tif(x%2){count++;a[m]=1;}\n\t\tx/=2;\n\t\tm++;\t\n\t}\n\tfor(i=m;i>0;i--){\n\t\tif(count>1&&a[i]){printf(\"%d \",i);count--;}\n\t\telse if(a[i]){printf(\"%d\\n\",i);break;}\n\t}\n\treturn ;\n}\nint main(){\n\twhile(~scanf(\"%d\",&n)){\n\t\tmemset(a,0,sizeof(a));\n\t\twork();\t\n\t}\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f02e82ed0b321cd930303e510fa962e7", "src_uid": "757cd804aba01dc4bc108cb0722f68dc", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<iostream.h>\n#include<math.h>\n//using namespace std;\nlong highestPO2(long n)\n{\n    for(int i=0;1==1;i++)\n    {\n        if(pow(2,i+1)>n)\n        {\n            return i;\n        }\n    }\n    return -1;\n}\nint main()\n{\n    long n;\n    cin>>n;\n    while(n)\n    {\n        int t = highestPO2(n);\n        cout<<t+1<<\" \";\n\n\n        n-=pow(2,t);\n\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "878f2c4aa42d9b2c58f3728848cff8c3", "src_uid": "757cd804aba01dc4bc108cb0722f68dc", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main()\n{\n    int l,i,cnt=0,a[100],j=0,grp=0,n;\n    char s[105];\n    scanf(\"%d\",&n);\n    scanf(\"%s\",s);\n    for(i=0; i<n; i++)\n    {\n        if(s[i]=='B')\n        {\n            cnt++;\n        }\n        else\n        {\n            if(cnt>0)\n            {\n                a[j]=cnt;\n                j++;\n                grp++;\n            }\n            cnt=0;\n        }\n    }\n    if(cnt>0)\n    {\n        grp++;\n        a[j]=cnt;\n    }\n    else\n        j--;\n    printf(\"%d\\n\",grp);\n    if(j>=0)\n    {\n        for(i=0; i<j; i++)\n        {\n            printf(\"%d \",a[i]);\n        }\n        printf(\"%d\\n\",a[j]);\n    }\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "58e6f6f0d23478d2a4dc5490a365e531", "src_uid": "e4b3a2707ba080b93a152f4e6e983973", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n    int n,i,j,t,g[100]={0};\n    \n    char s[105];\n    \n      j=t=outer=0;\n    \n    scanf(\"%d\",&n);\n    \n    for(i=0;i<n;i++)\n    scanf(\" %c\",&s[i]);\n    \n    for(i=0; i<n ;i++)\n    {\n        if(s[i]=='B')\n        {\n            g[j]++;\n            \n            if(s[i+1]=='W')\n            {\n                j++;\n                t++;\n                i++;\n            }\n            else if(i+1==n)\n            {\n                t++;\n                j++;\n            }\n        }\n    }\n  \n      printf(\"%d\\n\",t);\n    \n     for(i=0;i<j;i++)\n     printf(\"%d \",g[i]);\n    \n     printf(\"\\b\\n\");\n  \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fecb40f624c023c41e648c01cc3d25b6", "src_uid": "e4b3a2707ba080b93a152f4e6e983973", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdlib.h>\nmain()\n{\n    char a;\n    int n,i,j=0,k=0,d[100];\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%1c\",&a);\n        if(a=='B')\n        {\n            k+=1;\n        }\n        else\n        {\n            if(k!=0)\n            {\n                d[j]=k;\n                k=0;\n                j=j+1;\n            }\n        }\n        if(i==n-1)\n        {\n            if(k!=0)\n            {\n                d[j]=k;k=0;j=j+1;\n            }\n        }\n    ]\n    printf(\"%d\\n\",j);\n    for(i=0;i<j;i++)\n    {\n        printf(\"%d \",d[i]);\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "54375aa4ca612a60f6246589045b4ac1", "src_uid": "e4b3a2707ba080b93a152f4e6e983973", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\nchar dizi[100];\nint counter=0;\n\nint main(){\n\tscanf(\"%s\",dizi);\n\tfor(int i=0;i<strlen(dizi)+1;i++){\n\t\tif(dizi[i]=='\\0')\n\t\t\tbreak;\n\t\tif(dizi[i]=='B'){\n\t\t\tif(dizi[i+1]=='W' xor dizi[i+1]=='\\0' )\n\t\t\tcounter++;\n\t\t}\n\t}\n\t\n\tprintf(\"%d\",counter);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cf273f122874fdf6db072ee434f5d79f", "src_uid": "e4b3a2707ba080b93a152f4e6e983973", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint cur=0;\nint data[100]={0};\nint count;\nvoid add(int num){\n\tdata[cur]=num;\n\tcur++;\n}\nint main(){\n\tint n;\n\tscanf(\"%d\",&n);\n\tchar str[105]={'W','W'};\n\tscanf(\"%s\",str+2);\n\tstr[n+2]='W';\n\tstr[n+3]='W';\t\n\tchar prech='W',ch;\n\tbool in=false;\n\tfor(int i=1;i<n+5;i++){\n\t\tch=str[i];\n\t\tif (ch=='W'){\n\t\t\tif(prech=='B'){\n\t\t\t\tin=false;\n\t\t\t\tadd(count);\n\t\t\t\tcount=0;\n\t\t\t}\n\t\t}else{\n\t\t\tif(prech=='W'){\n\t\t\t\tin=true;\n\t\t\t}\n\t\t\tcount++;\n\t\t}\n\t\tprech=ch;\n\t}\n\tprintf(\"%d\\n\",cur);\n\tif(cur){\n\tfor (int j=0;j<cur;j++){\n\t\tprintf(\"%d \",data[j]);\n\t}}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "45e00d50474808b471907127c33f6dce", "src_uid": "e4b3a2707ba080b93a152f4e6e983973", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "\ufeff#include<stdio.h>\nint main(){\nchar s[4][5];\nint i,j;\nfor(i=0;i<4;i++) {\nscanf(\"%s\",s[i]);\n\uff5d\n \nint find=0;\n  for(i=0;i<3 && !find;i++) {\n    for(j=0;j<3 && !find;j++) {\nint dot=0;\nint pound=0;\n      if(s[i][j]=='.') dot++;\n      else pound++;\n   if(s[i+1][j]=='.') dot++;\n      else pound++;\n   if(s[i][j+1]=='.') dot++;\n      else pound++;\n   if(s[i+1][j+1]=='.') dot++;\n      else pound++;\nif(dot>2 || pound>2) {\nfind=1;\n    }\n  }\nif(find)printf(\"YES\\n\");\nelse printf(\"NO\\n\");\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ccbe9ef43eabaecc4faedebedd4ee6df", "src_uid": "01b145e798bbdf0ca2ecc383676d79f3", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main (\uff09 \uff5b\n  char s[4][5];\n  int i,j;\n  for(i=0;i<4;i++){\n    scanf(\"%s\",s[i]);\n  \uff5d\n  int find=0;\n  for(i=0;i<3 && !find;i++) {\n    for(j=0;j<3 && !find;j++) {\n      int dot=0;\n      int pound=0;\n      if(s[i][j]=='.') dot++;\n      else pound++;\n      if(s[i\uff0b1][j]=='.') dot++;\n      else pound++;\n      if(s[i][j+1]=='.') dot++;\n      else pound++;\n      if(s[i+1][j+1]=='.') dot++:\n      \n      else pound++;\n      if(dot>2 || pound>2) find=1;\n      }\n      }\n      if(find)printf(\"YES\\n\");\n      else printf(\"NO\\n\");\n      return 0;\n      }", "lang_cluster": "C", "compilation_error": true, "code_uid": "a41f2e1149240369e7da40e304e57bba", "src_uid": "01b145e798bbdf0ca2ecc383676d79f3", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    char arr[4][4];\n    int mat[4][4];\n    int i,j,p,sum=0;\n    for(i=0;i<4;i++)\n    {\n                    for(j=0;j<4;j++)\n                    {\n                     scanf(\"%c\",&arr[i][j]);\n                     if(arr[i][j]=='#')\n                     mat[i][j]=1;\n                     else\n                     mat[i][j]=0;\n    }\n    for(i=0;i<3;i++)\n    {\n                    for(j=0;j<3;j++)\n                    {\n   \n         sum=mat[i][j]+mat[i+1][j]+mat[i][j+1]+mat[i+1][j+1];\n        }\n        if(sum!=2)\n        {\n         printf(\"yes\");\n        p=1;\n        return 0;\n        }\n    }\n    if(p=0)\n    printf(\"no\");\n    return 0;\n}\n    ", "lang_cluster": "C", "compilation_error": true, "code_uid": "49fcdc9b4d7302ca9a396478517f685a", "src_uid": "01b145e798bbdf0ca2ecc383676d79f3", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main() {\n  char s[4][5];\n  int i,j;\n  for(i=0;i<4;i++) {\n    scanf(\"%s\",s[i]);\n  }\n  int find=0;\n  for(i=0;i<3 && !find; i++) {\n    for(j=0;j<3 && !find; j++) {\n      int dot=0;\n      int pound=0;\n      if(s[i][j]=='.') dot++;\n      else pound++;\n      if(s[i+1][j]=='.') dot++;\n      else pound++;\n      if(s[i][j+1]=='.') dot++;\n      else pound++;\n      if(s[i+1][j+1]=='.') dot++;\n      else pound++;\n      if(dot>2 || pound>2) find=1;\n  }\n  if(find) printf(\"YES\\n\");\n  else printf(\"NO\\n\");\n  \n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fdc05b1b48205e923ac2873a013d9dc3", "src_uid": "01b145e798bbdf0ca2ecc383676d79f3", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdlib.h>\n#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int i,k;\n    char a[4][4];\n    for(i=0;i<4;i++)\n    {\n        for(k=0;k<4;k++)\n            scanf(\"%c\",&a[k][i]);\n        scanf(\"%*c\");\n    }\n    for(i=0;i<3;i++)\n    {\n        for(k=0;k<3;k++)\n        { \n            if((a[k][i]==a[k+1][i])&&(a[k][i]==a[k][i+1])&&(a[k][i]==a[k+1][i+1]))\n            {\n                printf(\"YES\\n\");\n                return 0;\n            }\n            else if((a[k][i]==a[k+1][i])&&(a[k][i]==a[k][i+1]))\n            {\n                printf(\"YES\\n\");\n                return 0;\n            }\n            else if((a[k][i]!=a[k+1][i])&&(a[k][i]!=a[k][i+1])&&(a[k][i]!=a[k+1][i+1]))\n            {\n                printf(\"YES\\n\");\n                return 0;\n            }\n            else if(k>0)\n            {\n                if((a[k][i]!=a[k-1][i])&&(a[k][i]!=a[k][i+1])&&(a[k][i]!=a[k-1][i+1]))\n                {\n                    printf(\"YES\\n\");\n                    return 0;\n                }\n            }\n        }\n    }\n    printf(\"NO\")\n    printf(\"\\n\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bd937a4972515c6abd38461562f1e3a2", "src_uid": "01b145e798bbdf0ca2ecc383676d79f3", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main() {\n    long long int n,m,k;\n    scanf(\"%lld %lld\",&n,&m);\n    k=n-m;\n    if(m==1)\n        printf(\"%lld\\n\",m+1);\n    else if \n        printf(\"%lld\\n\",m-1);\n    else{\n        if(k>m-1)\n            printf(\"%lld\\n\",m+1);\n        else\n            printf(\"%lld\\n\",m-1);\n    }\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5c735d651c886aecae62b93792bde313", "src_uid": "f6a80c0f474cae1e201032e1df10e9f7", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "/*  In THe name of ALLAH\n   == Muhammad Tanvir == */\n\n#include <cstdio>\n\nint main(){\n    int n, m;\n    scanf(\"%d%d\",&n,&m);\n    if(n !=1){\n        printf(\"%d\",(m-1 >= n-m ? m-1 : m+1));\n    }\n    else\n        printf(\"1\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "632c90b1d061a45b311ab5e2c7aa96d3", "src_uid": "f6a80c0f474cae1e201032e1df10e9f7", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "/*  In THe name of ALLAH\n   == Muhammad Tanvir == */\n\n#include <cstdio>\n\nint main(){\n    int n, m;\n    scanf(\"%d%d\",&n,&m);\n    if(n != 1){\n        printf(\"%d\",(m-1 >= n-m ? m-1 : m+1));\n    }\n    else\n        printf(\"1\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ee41d3804904a2c7e487088fbac3a048", "src_uid": "f6a80c0f474cae1e201032e1df10e9f7", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n\tint n,m;\n\tscanf(\"%d%d\",&n,&m);\n  if(n==1)\n  \tprintf(\"1\\n\");\n  else if(m - 1 < n - m)\n  \tprintf(%d,(m+1));\n  else\n  \tprintf(%d,(m-1));\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "76b42c1f5fcf32df265dcd800e66ca3d", "src_uid": "f6a80c0f474cae1e201032e1df10e9f7", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tfloat n,t,m;\n\tint a,temp,temp2;\n\ttemp=n;\n\ttemp2=m;\n\tscanf(\"%f %d\",&n,&m);\n\tt=(n/2);\n\tif(n==1)\n\t\ta=1;\n\telse\n\t{\n\tif(m%2==0)\n\t{\n\t\tif(m<=t)\n\t\t\ta=m+1;\n\t\telse\n\t\t\ta=m-1;\n\t}\n\telse\n\t{\n\t\tif(temp==((n/2)+1))\n\t\t\ta=m-1;\n\t\telse\n\t\t{\n\t\t\tif(m<=t)\n\t\t\t\ta=m+1;\n\t\t\telse\n\t\t\t\ta=m-1;\n\t\t}\n\t}\n\t}\n\tprintf(\"%d\\n\",a);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3dfa3ebd4443ba896ecaa7b75c3a11a7", "src_uid": "f6a80c0f474cae1e201032e1df10e9f7", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint check(int a, int b, int c)\n{\n\tint ok1 = 1; int ok2 = 1; int ok3 = 1;\n\tif (a + b > c)\n\t\tok1 = 1;\n\tif (b + c > a)\n\t\tok2 = 1;\n\tif (a + c > b)\n\t\tok3 = 1;\n\n\treturn (ok1 && ok2) && ok3f;\n}\n\nint check_deg(int a, int b, int c)\n{\n\tif (a + b == c)\n\t\treturn 1;\n\tif (b + c == a)\n\t\treturn 1;\n\tif (a + c == b)\n\t\treturn 1;\n\n\treturn 0;\n}\n\nint main(void)\n{\n\tint a; int b; int c; int d;\n\tscanf(\"%d%d%d%d\", &a, &b, &c, &d);\n\n\n\tif (check(a, b, c) || check(a, b, d) || check(b, c, d)) {\n\t\tprintf(\"TRIANGLE\\n\");\n\t} else if (check_deg(a, b, c) || check_deg(a, b, d) || check_deg(b, c, d)) {\n\t\tprintf(\"SEGMENT\\n\");\n\t} else {\n\t\tprintf(\"IMPOSSIBLE\\n\");\n\t}\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "420d2997dee7a301229a286dac597e55", "src_uid": "8f5df9a41e6e100aa65b9fc1d26e447a", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#inculde <stdio.h>\nint main()\n{\n    int a, b, c, d;\n    scanf(\"%d %d %d %d\", &a, &b, &c, &d);\n    if(a+b>c||a+c>b||b+c>a||a+b>d||a+d>b||b+d>a||a+c>d||a+d>c||c+d>a||b+c>d||b+d>c||c+d>b) printf(\"TRIANGLE\");\n    else if(a+b=c\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5304160997e67758c968bdac502b5d41", "src_uid": "8f5df9a41e6e100aa65b9fc1d26e447a", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<cstdio>\n#include<algorithm>//a\n\nint main(){\n    int in[4];\n    for(int i=0;i<4;i++){\n        scanf(\"%d\",in+i);\n    }\n    \n    sort(in,in+4);\n    \n    if(in[0]+in[1]>in[2]||in[1]+in[2]>in[3]) printf(\"TRIANGLE\\n\");\n    else if(in[0]+in[1]==in[2]||in[1]+in[2]==in[3]) printf(\"SEGMENT\\n\");\n    else printf(\"IMPOSSIBLE\\n\");\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a0a3db1aad84e1fc04d42d0b5cba80b0", "src_uid": "8f5df9a41e6e100aa65b9fc1d26e447a", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#inculde <stdio.h>\nint main()\n{\n    int a, b, c, d;\n    scanf(\"%d %d %d %d\", &a, &b, &c, &d);\n    if(a+b>c||a+c>b||b+c>a||a+b>d||a+d>b||b+d>a||a+c>d||a+d>c||c+d>a||b+c>d||b+d>c||c+d>b) printf(\"TRIANGLE\");\n    else if(a+b=c||a+c=b||b+c=a||a+b=d||a+d=b||b+d=a||a+c=d||a+d=c||c+d=a||b+c=d||b+d=c||c+d=b) printf(\"SEGMENT\");\n    else printf(\"IMPOSSIBLE\");\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d616fa09651134febc27be0eaf9cd368", "src_uid": "8f5df9a41e6e100aa65b9fc1d26e447a", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint n,u[5],a[7],ton[10];\nbool b;\nvoid dfs(int i){\n    if(i>3){\n        if(u[1]<u[2]+u[3]&&u[2]<u[1]+u[3]&&u[3]<u[1]+u[2]){\n            b=true;n=1;\n            return;\n        }\n        if(u[1]<=u[2]+u[3]&&u[2]<=u[1]+u[3]&&u[3]<=u[1]+u[2]){\n            b=true;\n            return;\n        }\n        return;\n    }\n    for(int j=1;j<=4;j++){\n        if(ton[j]==0) {\n            ton[j]=1;\n            u[i]=a[j];\n            dfs(i+1);\n            u[i]=0;\n            ton[j]=0;\n        }\n    }\n}\nint main(){\n    scanf(\"%d%d%d%d\",a+1,a+2,a+3,a+4);\n    dfs(1);\n    if(b&&n) printf(\"TRIANGLE\");\n    else{\n        if(b) printf(\"SEGMENT\");\n        else printf(\"IMPOSSIBLE\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "19f9fe0e80ed03b0407db99193ccf542", "src_uid": "8f5df9a41e6e100aa65b9fc1d26e447a", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "include <stdio.h>\n\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tint c[n],count[n];\n\n\tfor (int i = 0; i < n; ++i)\n\t{   count[i]=1;\n\t\tscanf(\"%d\",&c[i]);\n\t}\n\tfor (int i = 0; i < n; ++i)\n\t{\t\n\t\tfor (int j = i+1; j < n; ++j)\n\t\t{\n\t \tif(c[i]==c[j])\n         {\n         \tcount[i]++;\n         }\n     }\n\n\t}\n\n\tint max=count[0];\n\tfor (int i = 0; i < n; ++i)\n\t{\n\t   if(count[i]>max)\n\t\t{max=count[i];}\n\t}\n\tprintf(\"%d\\n\",max);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "df7952f8fcb0b9b068a46cf0084f1382", "src_uid": "f30329023e84b4c50b1b118dc98ae73c", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int i, j, nbrCoins, count_same_value = 1, value_already_present = 0;\n    scanf(\"%d\", &nbrCoins);\n    \n    int *coin_value = (int *)malloc(nbrCoins * sizeof(int));\n    \n    for (i = 0; i < nbrCoins; i++)\n    {\n        scanf(\"%d\", &(*(coin_value + i)));\n        \n        value_already_present = 0\n        for (j = 0; j < i; j++)\n        {\n            if (*(coin_value + i) == *(coin_value + j))\n            {\n                value_already_present++;\n            }\n        }\n        \n        if (value_already_present > 0)\n        {\n            count_same_value += value_already_present\n        }\n    }\n    \n    printf(\"%d\\n\", count_same_value);\n    \n    free(coin_value);\n    return 0;\n}\n// End of main", "lang_cluster": "C", "compilation_error": true, "code_uid": "262efdb76d4de6f76cefbf1d32ff4607", "src_uid": "f30329023e84b4c50b1b118dc98ae73c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int n,t;\n    scanf(\"%d\",&n);\n    int a[100];\n    for(int i=0;i<n;i++)\n    {\n        scanf(\"%d\",&t);\n        a[t]=a[t]+1;\n        if(a[t]>m)\n            m=a[t];\n    }\n    printf(\"%d\\n\",m);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e0cb27c8bd63c666977be707061c25af", "src_uid": "f30329023e84b4c50b1b118dc98ae73c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n=0;\n    scanf(\"%d\",&size);\n    int arr[size];\n    for(int i=0;i<size;i++){\n        scanf(\"%d\",&arr[i]);\n    }\n    int*freq=(int*)calloc(100,sizeof(int));\n    for(int i=0;i<size;i++){\n        freq[arr[i]-1]++;\n    }\n    int max=0;\n    for(int i=0;i<100;i++){\n        if(freq[i]>=max){\n            max=freq[i];\n        }\n    }\n    printf(\"%d\",max);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b8f2e0e31b56fa32deab86a6b68729e7", "src_uid": "f30329023e84b4c50b1b118dc98ae73c", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define PROB \"a\"\nusing namespace std;\nint dau[105]={0};\nint maxx=0;\nint n;\n\nvoid Nhap()\n{\n    int tmp;\n    scanf(\"%d\",&n);\n    for(int i=0; i<n; i++) {\n        scanf(\"%d\",&tmp);\n        dau[tmp]++;\n        if(dau[tmp]>maxx) maxx=dau[tmp];\n    }\n    printf(\"%d\",maxx);\n}\n\nint main()\n{\n    //init();\n   Nhap();\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5abaa792954a9ebe240a30aca751aa08", "src_uid": "f30329023e84b4c50b1b118dc98ae73c", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nvoid search_min(int min[], int length, int sum);\nvoid search_max(int max[], int length, int sum);\n\nint main(void)\n{\n  int length, sum, k, i;\n  scanf(\"%d %d/n\", &length, &sum);\n  int max[length], min[length];\n  \n  if (length* 9 < sum && (length > 1 && sum == 0)) {\n    printf(\"-1 -1\");\n    return 0;\n  }\n  \n  search_min(min, length, sum);\n  printf(\" \");\n  search_max(max, length, sum);\n  \n  return 0;\n}\n\nvoid search_min(int min[], int length, int sum)\n{\n  int i, k = length;\n  for (i = 0; length > 0; length--) {\n    if (length == 1) min[i] = sum;\n    if (length == 2) {\n      if (sum >= 10) {\n        min[i++] = 9, sum -= 9, length--;\n        min[i] = sum;\n      }\n      else {\n        min[i++] = sum - 1, sum = 1, length--;\n        min[i] = sum;\n      }\n    }\n    if (length > 2) {\n      if (sum >= 10) min[i++] = 9, sum -= 9;\n      else if (sum > 1) {\n        min[i++] = sum - 1, sum = 1, length--;\n        min[i] = sum;\n      }\n      else min[i] = sum;\n    }\n  }\n  for ( ; i >= 0; i--) printf(\"%d\", min[i]);\n}\n\nvoid search_max(int max[], int length, int sum) \n{\n  int i;\n  for (i = 0; length > 0; length--) {\n    if (length == 1) max[i] = sum;\n    if (length == 2) {\n      if (sum >= 10) {\n        max[i++] = 9, sum -= 9, length--;\n        max[i] = sum;\n      }\n      else {\n        max[i++] = sum, sum = 0, length--;\n        max[i] = sum;\n      }\n    }\n    if (length > 2) {\n      if (sum >= 10) max[i++] = 9, sum -= 9;\n      else if (sum > 0) max[i++] = sum, sum = 0;\n      else max[i++] = sum;\n    }\n  }\n  for (i = 0; i <= k - 1; i++) printf(\"%d\", max[i]);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "123c492244cdbf7abee9a955ead5725d", "src_uid": "75d062cece5a2402920d6706c655cad7", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdlib.h>\nint a[100],b[100];\nint main()\n{\n    int m,s,i,x;\n    scanf(\"%d %d\",&m,&s);\n    if(m>1&&s==0||s>9*n) printf(\"-1 -1\");\n    else\n    {\n        a[0]=1;x=s-1;\n        for(i=m-1;i>=0;i--)\n        {\n            if(x>=9)\n            {\n                x-=9;\n                a[i]+=9;\n            }\n            else\n            {\n                a[i]+=x;\n                x=0;\n            }\n        }\n        x=s;\n        for(i=0;i<m;i++)\n        {\n            if(x>=9)\n            {\n                x-=9;\n                b[i]+=9;\n            }\n            else\n            {\n                b[i]+=x;\n                x=0;\n            }\n        }\n        for(i=0;i<m;i++) printf(\"%d\",a[i]);\n        printf(\" \");\n        for(i=0;i<m;i++) printf(\"%d\",b[i]);\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "532bdff529644d22f66842b6ac06a08d", "src_uid": "75d062cece5a2402920d6706c655cad7", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\nint so(int n , int s1)\n{\n\tif(s1<=9)\n\t{\n\t\tif(n!=1)\n\t\t{\n\t\t\tif(s1-1<0)\n\t\t\t{\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\treturn s1-1;\t\t\n\t\t}\n\t\telse\n\t\t{\n\t\t\tif(s1>1)\n\t\t\t\treturn s1;\n\t\t\telse\n\t\t\t\treturn 1;\n\t\t}\n\t}\n\telse\n\t{\n\t\treturn 9;\n\t}\n}\nint main()\n{\n\tint m , s , n, s1;\n//\tFILE *f;\n//\tf = fopen(\"1400.inp\",\"rt\");\n//\tfscanf(f,\"%d\",&m);\n//\tfscanf(f,\"%d\",&s);\n\tscanf(\"%d\",&m);\n\tscanf(\"%d\",&s);\n\tint a[m];\n\tn=m;\n\ts1=s;\n\tif(s==0 && m==1)\n\t{\n\t\tprintf(\"%d\\t%d\",0,0);\n\t}\n\telse if (s < 1 || (m*9)< s  )\n\t{\n\t\tprintf(\"%d\\t%d\",-1,-1);\n\t}\n\telse\n\t{\n\t\tfor(int i =m-1 ; i>=0; i--)\n\t\t{\n\t\t\ta[i]=so(n,s1);\n\t\t\tn -=1;\n\t\t\ts1-=a[i];\n\t\t}\n\t\tif(a[m-1]==9 || a[m-1]==0)\n\t\t{\n\t\t\tif (s<2)\n\t\t\t{\n\t\t\t\tfor(int kk =0 ; kk<m;kk++)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%d\",a[kk]);\n\t\t\t\t}\n\t\t\t\tprintf(\"\\t\");\n\t\t\t\tfor(int kk1= 0; kk1<m;kk1++)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%d\",a[kk1]);\n\t\t\t\t}\n\t\t\t\t\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tint ttt=0;\n\t\t\t\tfor(int kk = 0 ; kk<m;kk++)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%d\",a[kk]);\n\t\t\t\t\tttt+=a[kk];\n\t\t\t\t}\n\t\t\t\tprintf(\"\\t\");\n\t\t\t\t{\n\t\t\t\t\tfor(int kk1=0;kk1<m;kk1++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif(ttt>=9)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tttt -=9;\n\t\t\t\t\t\t\tprintf(\"%d\",9);\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if(s>0)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tprintf(\"%d\",ttt)\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tprintf(\"%d\",0);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\n\t\t\t}\t\t\t\n\t\t}\n\t\telse\n\t\t{\n\t\t\tint ttt = 0;\n\t\t\tfor(int kk =0 ; kk<m;kk++)\n\t\t\t{\n\t\t\t\tprintf(\"%d\",a[kk]);\n\t\t\t\tttt += a[kk];\n\t\t\t}\n\t\t\tprintf(\"\\t\");\n\t\t\tfor(int kk1=0;kk1<m;kk1++)\n\t\t\t{\n\t\t\t\tif(kk1==0)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%d\",ttt);\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%d\",0);\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t}\n\t\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "67a68e78b72c73e96fdbf5b8d1bb9225", "src_uid": "75d062cece5a2402920d6706c655cad7", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint so(int n , int s1)\n{\n\tif(s1<=9)\n\t{\n\t\tif(n!=1)\n\t\t{\n\t\t\tif(s1-1<0)\n\t\t\t{\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\treturn s1-1;\t\t\n\t\t}\n\t\telse\n\t\t{\n\t\t\tif(s1>1)\n\t\t\t\treturn s1;\n\t\t\telse\n\t\t\t\treturn 1;\n\t\t}\n\t}\n\telse\n\t{\n\t\treturn 9;\n\t}\n}\nint main()\n{\n\tint m , s , sodu , songuyen , n , s1 ;\n\tscanf(\"%d\",&m);\n\tscanf(\"%d\",&s);\n\tint a[m];\n\tint b[m];\n\tn=m;\n\ts1=s;\n\tfor(int i =m-1 ; i>=0; i--)\n\t{\n\t\ta[i]=so(n,s1);\n\t\tb[i]=a[i];\n\t\tn -=1;\n\t\ts1-=a[i];\n\t}\n\tfor(int j =0 ; j<m; j++)\n\t{\n\t\titoa(a[j],t , 10);\n\t\tmin[j] = t[0];\n\t}\n\tfor(int j1=0 ; j1<m-1;j1++)\n\t{\n\t\tfor(int j2=j1+1 ; j2<m ; j2++)\n\t\t{\n\t\t\tif(b[j1]<b[j2])\n\t\t\t{\n\t\t\t\tint temp;\n\t\t\t\ttemp = b[j1];\n\t\t\t\tb[j1] = b[j2];\n\t\t\t\tb[j2] = temp;\n\t\t\t\t\n\t\t\t}\n\t\t}\n\t}\n\tfor(int kk =0 ; kk<m;kk++)\n\t{\n\t\tprintf(\"%d\\t\",a[kk]);\n\t}\n\tprintf(\"\\n\");\n\tif (s < 1)\n\t{\n\t\tprintf(\"%d\\t%d\",-1,-1);\n\t}\n\telse if (s<2)\n\t{\n\t\tfor(int kk =0 ; kk<m;kk++)\n\t\t{\n\t\t\tprintf(\"%d\",a[kk]);\n\t\t}\n\t\tprintf(\"\\t\");\n\t\tfor(int kk1= 0; kk1<m;kk1++)\n\t\t{\n\t\t\tprintf(\"%d\",a[kk1]);\n\t\t}\n\t\t\n\t}\n\telse\n\t{\n\t\tfor(int kk = 0 ; kk<m;kk++)\n\t\t{\n\t\t\tprintf(\"%d\",a[kk]);\n\t\t}\n\t\tprintf(\"\\t\");\n\t\tfor(int kk1= 0; kk1<m;kk1++)\n\t\t{\n\t\t\tprintf(\"%d\",b[kk1]);\n\t\t}\n\t}\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2835bd15c1e0e9a2ab30d4fa47f70132", "src_uid": "75d062cece5a2402920d6706c655cad7", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n\nint main(){\n\tint n,m;\n\tscanf(\"%d%d\",&n,&m);\n\tint max= 0,clo=m;\n\t\n\tfor(int i=0;i<n;i++){\n\t\tif(clo>=9){\n\t\t\tmax+= 9*pow(10,n-i-1);\n      clo-=9;\n    }\n    else{\n      max+= clo*pow(10,n-i-1);\n      clo-=clo;\n      break;\n    }\n\t}\n  if(clo!=0 || m==0){\n    printf(\"-1 -1\");\n    return 0;\n  }\n  int min=max,r=0;\n  while (min != 0)\n  {\n    r = r * 10;\n    r = r + min%10;\n    min = min/10;\n  }\n  if(r==1){r?=10;}\n\tprintf(\"%d %d\",r,max);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c9801e57291a76711bf22b40cfac132f", "src_uid": "75d062cece5a2402920d6706c655cad7", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main ()\n\n{\n    int i,l1,l2,c=0;\n    char s1[120],s2[120];\n    scanf(\"%s\",s1);\n    scanf(\"%s\",s2);\n    l1=strlen(s1);\n    l2=strlen(s2);\n    if(l1!=l2)\n        printf(\"NO\");\n        break;\n    else {\n        for(i=0;i<l1;i++){\n            if(s1[i]==s2[l1-(i+1)])\n            c++;\n            }\n        }\n    if(c==l1)\n        printf(\"YES\");\n    else printf(\"NO\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6503b83853f3c5a7fe63264be0f12c2c", "src_uid": "35a4be326690b58bf9add547fb63a5a5", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main() {\n    #include <stdio.h>\n#include<string.h> \nint main() {\n    int i,j,ctr=0,len1,len2;\n    char s[1001].t[1001];\n    scanf(\"%s\",&s);\n    scanf(\"%s\",&t);\n    len1=strlen(s);\n    len2=strlen(t);\n   for(i=len1-1,j=0;i>=0&&j<len2;j++,i--)\n\n    {\n        if(s[i]==t[j])\n        {\n            ctr++;\n        }\n    }\n    if(ctr==len1)\n    {\n        printf(\"YES\\n\");\n    }\n    else \n    {\n        printf(\"NO\\n\");\n    }\n    return 0;\n}\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1ac5b00f24bd1e3752a02f65729c1fe6", "src_uid": "35a4be326690b58bf9add547fb63a5a5", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main() {\n    char s1[100],s2[100];\n    scanf(\"%s\",s1);\n    scanf(\"%s\",s2);\n    int c=0,l1=strlen(s),l2=strlen(t);\n    for(i=0,j=12-1;i<l1;i++,j--){\n        if(s[i] == t[j]){\n            c++;\n        }\n    }\n    if(c==l1){\n        printf(\"YES\");\n    }\n    else{\n        printf(\"NO\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "df9426202ed47abdf22a3ac46460c5c2", "src_uid": "35a4be326690b58bf9add547fb63a5a5", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char a[10000],b[10000];\n    scanf(\"%s%s\",a,b);\n    if(strrev(a)==b)\n    printf(\"YES\");\n    else\n    printf(\"NO\");\n    printf(strrev(a))\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a0db5e784d1d0f32fffffff4368bc15b", "src_uid": "35a4be326690b58bf9add547fb63a5a5", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(){\n       char st[101],ss[101];\n       scanf(\"%s%s\",&st,&ss);\n       int i,x,c=0;\n       x=strlen(st);\nint j;\nj=x-1\n              for(i=0;i<x;i++){\n       if(st[i]==ss[j])            \n               c++;\n              j--;\n              }\n        if(c==x){\n       printf(\"YES\");\n       }\n       else\n       printf(\"NO\");\n       return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0b211528f69b1e576b77909913119027", "src_uid": "35a4be326690b58bf9add547fb63a5a5", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n  int i,j,n,m,r=0,c=0,s;\n\tscanf(\"%d%d\",&n,&m);\n\tchar a[n][m+1];\n\tint arr[m]={0};\n\tfor(i=0;i<n;i++)\n\t{\n\t\t for(j=0;j<m+1;j++)\n\t\t scanf(\"%c\",&a[i][j]);\n\t}\n\tfor(i=0;i<n;i++)\n\t{\n\t\tfor(j=0;j<m;j++)\n\t\t{\n\t\t\tif(a[i][j]=='S')\n\t\t\t{\n\t\t\t arr[j]=1;\n\t\t\t break;\n\t\t\t}\n\t\t\tif(j==m-1)\n\t\t\tr=r+1;\n\t\t\t\n\t\t}\n\t}\n\tfor(i=0;i<m;i++)\n\t{\n\t\tif(arr[i]==0)\n\t\tc=c+1;\n\t}\n\ts=(r*m)+(c*n)-(r*c);\n\tprintf(\"%d\",s);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "27c2fb03fc0099578c3bb5696f2b8a27", "src_uid": "ebaf7d89c623d006a6f1ffd025892102", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\nint main()\n{\n\tint r,c;\n\tcin>>r>>c;\n\tchar a[r][c];\n\tchar b[r],d[c],f[c];\n\tfor(int i=0;i<r;i++)\n\t{\n\t\tb[i]=1;\n\t\tscanf(\"%s\",f);\n\t\tfor(int j=0;j<c;j++)\n\t\t{\n\t\t\ta[i][j]=f[j];\n\t\t\td[j]=1;\n\t\t}\n\t}\n\tfor(int i=0;i<r;i++)\n\t{\n\t\tfor(int j=0;j<c;j++)\n\t\t{\n\t\t\tif(a[i][j]=='S')\n\t\t\t{\n\t\t\t\t b[i]=0;\n\t\t\t}\n\t\t}\n\t}\n\tfor(int j=0;j<c;j++)\n\t{\n\t\tfor(int i=0;i<r;i++)\n\t\t{\n\t\t\tif(a[i][j]=='S')\n\t\t\t{\n\t\t\t\td[j]=0;\n\t\t\t}\n\t\t}\n\t}\n\tint cntr=0,cntc=0;\n\tfor(int i=0;i<r;i++)\n\t{\n\t\tif(b[i]==1)\n\t\t{\n\t\t\tcntr++;\n\t\t}\n\t}\n\tfor(int i=0;i<c;i++)\n\t{\n\t\tif(d[i]==1)\n\t\t{\n\t\t\tcntc++;\n\t\t}\n\t}\n\tprintf(\"%d\",cntr*c+cntc*r-cntr*cntc);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9ce75111528ed48d8350632599769be5", "src_uid": "ebaf7d89c623d006a6f1ffd025892102", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "10 10\n.....SSSSS\n.....SSSSS\n.....SSSSS\n.....SSSSS\n.....SSSSS\n..........\n..........\n..........\n..........\n..........\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "731d1e45401b535e01c09596e1baf2b3", "src_uid": "ebaf7d89c623d006a6f1ffd025892102", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main(){\nint n,m;\nscanf(\"%d %d\",&n,&m);\nchar a[n][m];\nint i,j;\nfor(i=0;i<n;i++){\n    for(j=0;j<m;j++)\n    scanf(\"%c\",&a[i][j]);\n}\nint b[n]=[0];\nint x=0;\nfor(i=0;i<n;i++){\n    for(j=0;j<m;j++){\n        if(a[i][j]=='S')\n        b[i]++;\n    }\n}\nfor(i=0;i<n;i++){\n    if(b[i]==0)\n    x++;\n}\nint c[m]=[0];\nint y=0;\nfor(j=0;j<m;j++){\n    for(i=0;i<n;i++){\n        if(a[i][j]=='S')\n        c[j]++;\n    }\n}\nfor(i=0;i<m;i++)\n{\n    if(c[i]==0)\n    y++;\n}\nprintf(\"%d\",x*m+y*n-x*y);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f137a5223fc6e6dcf054ecc89546d902", "src_uid": "ebaf7d89c623d006a6f1ffd025892102", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<string.h>\nchar s[10][10];\nint map[10][10];\nint main()\n{\n    int n,m;\n    int flag,count;\n    while(scanf(\"%d%d\",&n,&m)!=EOF)\n    {\n         count=0;\n        memset(map,0,sizeof(0));\n        for(int i=0;i<n;i++)\n        scanf(\"%s\",s[i]);\n        for(int j=0;j<n;j++)\n        {\n            flag=0;\n            for(int i=0;i<m;i++)\n            {\n                if(s[j][i]=='S')\n                flag=1;\n            }\n            if(flag!=1)\n            {\n                for(int i=0;i<m;i++)\n                map[j][i]=1;\n                count+=m;\n            }\n        }\n    for(int i=0;i<m;i++)\n    {\n        flag=0;\n        for(int j=0;j<n;j++)\n        {\n            if(s[j][i]=='S')\n            flag=1; \n        }\n        if(flag!=1)\n        {\n            for(int j=0;j<n;j++)\n            {\n                if(map[j][i]==0)\n                {\n                    count++;\n                    map[i][j]=1;\n                }\n            }\n        }\n    \n    }\n    printf(\"%d\\n\",count);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9f363819233cba71e01a051b6ea63cc3", "src_uid": "ebaf7d89c623d006a6f1ffd025892102", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "include<stdio.h>\nint main()\n{\nint n;\nscanf(\"%d\",&n);\nif(n==2)\n{\nprintf(\"2\");\n}\nelse\n{\nprintf(\"1\");\n}\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "47b11e27a0785b3e0322de0f3601a1fb", "src_uid": "c30b372a9cc0df4948dca48ef4c5d80d", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\t\n\tscanf(\"%d\",&n);\n\tfor(i=n-1;i>0;i--)\n\t{\n\t\tif((n%i)!=0)\n\t\t{\n\t\t\tprintf(\"%d\",(n-i));\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\"%d\",n);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "55ecd9ea210a6e53090c7b561bcc4b37", "src_uid": "c30b372a9cc0df4948dca48ef4c5d80d", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(void) {\n\tint n;\n\tscanf(\"%d\",&n);\n    n=n-(n-1);\n    printf(%d\",&n);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "72a1014661c5cf5de0ce7482f22efb08", "src_uid": "c30b372a9cc0df4948dca48ef4c5d80d", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n    cout << \"Hello world!\" << endl;\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e14d3cdac74db88f833fdb5e8abd5d4e", "src_uid": "c30b372a9cc0df4948dca48ef4c5d80d", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "\n#include <stdio.h>\n#include<string.h>\n\nint main()\n{\n    char n[100];\n \n    scanf(\"%s\",n);\n   if(strlen(n)%2=1)\n   {\n       printf(\"1\");\n   }else{\n       printf(\"2\");\n   }\n     \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8ca5a505b9e9c80a5b1dabd20c6360f6", "src_uid": "c30b372a9cc0df4948dca48ef4c5d80d", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    long long n,i;\n    scanf(\"%I64d\",&n);\n    i=1;\n    while(n-i>0)\n    {\n        n-=i;\n        i++;\n    }\n    printf(\"%I64d\",n)\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d0b429420972ebe0ee0e358ef5775379", "src_uid": "1db5631847085815461c617854b08ee5", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <cctype>\n#include <climits>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <iostream>\n#include <sstream>\n#include <iomanip>\n#include <string>\n#include <vector>\n#include <list>\n#include <set>\n#include <map>\n#include <stack>\n#include <queue>\n#include <algorithm>\n#include <iterator>\n#include <utility>\nusing namespace std;\n\n#define ll long long int\n#define ull unsigned long long int\n#define inf (INT_MAX/10)\n#define linf (LLONG_MAX/10LL)\n#define sc(a) scanf(\"%d\",&a)\n#define sc2(a,b) scanf(\"%d%d\",&a,&b)\n#define sc3(a,b,c) scanf(\"%d%d%d\",&a,&b,&c)\n#define sc4(a,b,c,d) scanf(\"%d%d%d%d\",&a,&b,&c,&d)\n#define fl(c,i,n) for(i=c;i<n;i++)\n#define f(i,n) for(i=0;i<n;i++)\n#define mem(a) memset(a,0,sizeof(a))\n#define memn(a) memset(a,-1,sizeof(a))\n#define pb push_back\n#define pp pop_back()\n#define aov(a) a.begin(),a.end()\n#define mpr make_pair\n#define PI (2.0*acos(0.0)) //#define PI acos(-1.0)\n#define xx first\n#define yy second\n#define mxv(a) *max_element(aov(a))\n#define mnv(a) *min_element(aov(a))\n#define LB(a,x) (lower_bound(aov(a),x)-a.begin())\n#define UB(a,x) (upper_bound(aov(a),x)-a.begin())\n#define to_c_string(a) a.c_str()\n#define strtoint(c) atoi(&c[0])\n#define pii pair< int , int >\n#define pll pair< ll , ll >\n#define pcs(a) printf(\"Case %d: \", a)\n#define nl puts(\"\")\n#define endl '\\n'\n#define dbg(x) cout<<#x<<\" : \"<<x<<endl\n\ntemplate <class T> inline T bigmod(T p,T e,T M){ll ret = 1;for(; e > 0; e >>= 1){if(e & 1) ret = (ret * p) % M;p = (p * p) % M;}return (T)ret;}\ntemplate <class T> inline T gcd(T a,T b){if(b==0)return a;return gcd(b,a%b);}\ntemplate <class T> inline T modinverse(T a,T M){return bigmod(a,M-2,M);}   // M is prime}\ntemplate <class T> inline T bpow(T p,T e){ll ret = 1;for(; e > 0; e >>= 1){if(e & 1) ret = (ret * p);p = (p * p);}return (T)ret;}\n\nint toInt(string s){int sm;stringstream ss(s);ss>>sm;return sm;}\nint toLlint(string s){long long int sm;stringstream ss(s);ss>>sm;return sm;}\n\n\n///int mnth[]={-1,31,28,31,30,31,30,31,31,30,31,30,31};  //Not Leap Year\n///int dx[]={1,0,-1,0};int dy[]={0,1,0,-1};//4 direction\n///int dx[]={1,1,0,-1,-1,-1,0,1};int dy[]={0,1,1,1,0,-1,-1,-1};//8 direction\n///int kdx[]={2,1,-1,-2,-2,-1,1,2};int kdy[]={1,2,2,1,-1,-2,-2,-1};//Knight Direction\n///int dx[]={-1,+1,0,1,0,-1}; // Hexagonal Direction   **\n///int dy[]={-1,+1,1,0,-1,0}; //                       *#*\n///                                                     **\nconst double eps=1e-9;\n\n#define M 1000005\n#define MD 1000000007LL\n#define MX 100005\n\nint ts,kk=1;\n\n#define intx(i,j,k,l) ((a[i]*b[j]-b[i]*a[j])*(a[k]-a[l])-(a[i]-a[j])*(a[k]*b[l]-b[k]*a[l]))/((a[i]-a[j])*(b[k]-b[l])-(b[i]-b[j])*(a[k]-a[l]))\n#define inty(i,j,k,l) ((a[i]*b[j]-b[i]*a[j])*(b[k]-b[l])-(b[i]-b[j])*(a[k]*b[l]-b[k]*a[l]))/((a[i]-a[j])*(b[k]-b[l])-(b[i]-b[j])*(a[k]-a[l]))\n#define dst(u,v,x,y) sqrt((x*1.0-u*1.0)*(x*1.0-u*1.0)+(y*1.0-v*1.0)*(y*1.0-v*1.0))\n#define area(i,j,k) ((ll)x[i]*y[j]+(ll)x[j]*y[k]+(ll)x[k]*y[i]-(ll)y[i]*x[j]-(ll)y[j]*x[k]-(ll)y[k]*x[i])\n\nll n,x;\n\nint main()\n{\n    int t,i,j,k,l;\n\n    cin>>n;\n\n    for(x=1;x<n;x++)\n    {\n        n-=x;\n    }\n    cout<<n<<endl;\n//    main();\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "afa0a19a9a09d0dc4a7080a161f44612", "src_uid": "1db5631847085815461c617854b08ee5", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n    int i;\n    long long n;\n    i=1;\n    cin>>n;\n    while(n-i>0)\n    {\n        n-=i;\n        i++;\n    }\n    cout<<n;\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "610c7dc43090b64eae4aecbaa0ed32c2", "src_uid": "1db5631847085815461c617854b08ee5", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define MAX 100000000000\nint main(){\n\tint n;\n\tint i;\n\tscanf(\"%d\",&n);\n\tint g=1;\n\tint f=0;\n\tint arr[MAX]={0};\n\twhile(g!=1000){\n\t\tfor(i=1;i<=g;i++)\n\t\t{\n\t\t\tarr[f]=i;\n\t\t\tf++;\n\t\t}\n\t\tg++;\n\t}\n\tprintf(\"%d\",arr[n-1]);\n\t\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "adc15b89cd797a5903f1556649002f86", "src_uid": "1db5631847085815461c617854b08ee5", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n#include <string.h>\n\n\nvoid main (){\n    long long n,i=1;\n    scanf(\"%lld\",&n);\n    while ((i*(i+1))/2 < n){\n        i++;\n        \n        \n        \n    }\n    i--;\n    printf (\"%lld\", n- ((i*(i+1))/2)  )\n    \n    \n    \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7f556a501f32f3baea861158fd66552c", "src_uid": "1db5631847085815461c617854b08ee5", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n\ntypedef long long ll;\n\nint main()\n{\n    ll ax, ay, bx, by, cx, cy;\n\n    scanf(\"%I64d %I64d %I64d %I64d %I64d %I64d\",&ax,&ay,&bx,&by,&cx,&cy);\n\n    if( ay==bx && by==cx && cy==ax) printf(\"Yes\");\n    else\n        printf(\"No\");\n\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b1c08ee1041c0aa0669062618c7766c6", "src_uid": "05ec6ec3e9ffcc0e856dc0d461e6eeab", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <stdbool.h>\n#include <math.h>\n#define tor 0.00000001\n\n//\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u05b8\ufffd\ufffd\ufffd\u0123\ufffd\ufffd\ufffd\ufffd\u04aa\ufffd\ufffd\u03f8\ufffd\ufffd\ufffd\u04bb\ufffd\ufffd\ufffd\ufffd\u00fb\ufffd\ufffd\u00a9\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u03a7(\ufffd\ufffd\ufffd\u03a1\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u03a1\ufffd\u02b5\ufffd\u0361\ufffdfabs\ufffd\ufffdabs\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd)\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd(int64=at least one int64* others)\ufffd\ufffd\u00fb\ufffd\u0433\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ub862\ufffd\ufffd\ufffd\ufffd\ufffd\u03a7\ufffd\ufffd\u00fb\ufffd\u0433\ufffd\ufffd\ufffd\n\nint main()\n{\n    long ax,ay,bx,by,cx,cy;\n    double k1,k2,dx,dy;//dx,dy:double!!!\n    bool vis1,vis2;\n    scanf(\"%ld%ld%ld%ld%ld%ld\",&ax,&ay,&bx,&by,&cx,&cy);\n    if (ax==cx && ay==cy)\n    {\n        printf(\"Yes\\n\");\n        return 0;\n    }\n    if (ax+cx==bx*2 && ay+cy==by*2)\n    {\n        printf(\"No\\n\");\n        return 0;\n    }\n    vis1=true;\n    vis2=true;\n    if (cx-ax!=0)\n        k1=1.0*(cy-ay)/(cx-ax);\n    else\n        vis1=false;\n    dx=1.0*(ax+cx)/2;\n    dy=1.0*(ay+cy)/2;\n    if (fabs(bx-dx)>tor)\n        k2=1.0*(by-dy)/(bx-dx);\n    else\n        vis2=false;\n\n    if ((vis1==false && vis2==true && fabs(k2-0)<tor) || (vis1==true && fabs(k1-0)<tor && vis2==false) || (vis1==true && vis2==true && fabs(k1*k2+1)<tor))\n        printf(\"Yes\\n\");\n    else\n        printf(\"No\\n\");\n    return 0;\n}\n/*\n0 0 1 1 2 2\n0 1 1 1000000000 2 1\n0 1 1 -1000000000 2 1\n0 1 1 5 2 1\n2 1 1 5 0 1\n2 1 1 -3 0 1\n\n0 0 0 0 0 0\n\n0 0 1 1 0 0\n*/\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fd052da9f5de26aa1664f52f9025365d", "src_uid": "05ec6ec3e9ffcc0e856dc0d461e6eeab", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\n#define sq(A) ((A)*(A))\n\nint main(){\n\tint i, x[3], y[3];\n\tfor(i=0;i<3;++i) scanf(\"%d %d\", x+i, y+i);\n\tif(sq(x[0]-x[1])+sq(y[0]-y[1])==sq(x[2]-x[1])+sq(y[2]-y[1]) || \n\t\tsq(x[2]-x[1])+sq(y[2]-y[1])==sq(x[0]-x[2])+sq(y[0]-y[2]) || \n\t\tsq(x[0]-x[1])+sq(y[0]-y[1])==sq(x[0]-x[2])+sq(y[0]-y[2])) puts(\"Yes\");\n\telse puts(\"No\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e9baa5ec06bcddaf02ac1aeda88325dc", "src_uid": "05ec6ec3e9ffcc0e856dc0d461e6eeab", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n\nint main(void)\n{\n\tlong long int ax,ay,bx,by,cx,cy,d1,d2,d3;\n\tdouble a,b,c;\n\tscanf(\"%I64d %I64d %I64d %I64d %I64d %I64d\",&ax,&ay,&bx,&by,&cx,&cy);\n\td1=(ax-bx)*(ax-bx)+(ay-by)*(ay-by);\n\ta=sqrt(d1);\n\td2=(cx-bx)*(cx-bx)+(cy-by)*(cy-by);\n\tb=sqrt(d2);\n\td3=(cx-ax)*(cx-ax)+(cy-ay)*(cy-ay);\n\tc=sqrt(d3);\n\tif(a==b) {\n\t\tif((ax==bx && ax==cx) || (ay==by && ay==cy))\n\t\t\tprintf(\"No\");\n/*\t\tif(d1+d2==d3)\n\t\t\tprintf(\"Yes\");\n\t\telse if(a==c)\n\t\t\tprintf(\"Yes\");*/\n\t\telse\n\t\t\tprintf(\"Yes\");\n\t}\n\telse\n\t\tprintf(\"No\");\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b956184d6f403acefc266c4eb39f3d46", "src_uid": "05ec6ec3e9ffcc0e856dc0d461e6eeab", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "{  \n    long long x1,y1,x2,y2,x3,y3,k1,k2,d1,d2;  \n    scanf(\"%lld%lld%lld%lld%lld%lld\",&x1,&y1,&x2,&y2,&x3,&y3);  \n    d1=(x1-x2)*(x1-x2)+(y1-y2)*(y1-y2);  \n    d2=(x2-x3)*(x2-x3)+(y2-y3)*(y2-y3);  \n    if(d1!=d2)  \n    {  \n        printf(\"No\\n\");  \n        return 0;  \n    }  \n    if((x2-x3)*(y1-y2)==(x1-x2)*(y2-y3))  \n    {  \n        printf(\"No\\n\");  \n    }  \n    else  \n        printf(\"Yes\\n\");  \n    return 0;  \n}  \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "60161f7ecdb5c259c98892fbc750e95f", "src_uid": "05ec6ec3e9ffcc0e856dc0d461e6eeab", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\nusing namespace std;\nint main()\n{\n    int n;\n    cin>>n;\n    if(n>0){cout<<\"The number is postisve\"<<endl;}\n    else if(n<0)cout<<\"the number is negative\";\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d7375fad13860b18bcae28920234e5cf", "src_uid": "66398694a4a142b4a4e709d059aca0fa", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "90b0e529969c4bfc7c3992d29d24af9e", "src_uid": "66398694a4a142b4a4e709d059aca0fa", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int x,y,z;\n    scanf(\"%d%d%d\",&x,&y,&z);\n    if(z)\n    {\n        if(x+z==y||x=y+z)\n            printf(\"?\");\n        else\n            if(x>y)\n            printf(\"+\");\n        else if(x<y)\n            printf(\"-\");\n        else\n            printf(\"0\");\n    }\n    else\n    {\n        if(x>y)\n            printf(\"+\");\n        else if(x<y)\n            printf(\"-\");\n        else\n            printf(\"0\");\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c20ae3dfd3082c9aa5ccd530c60fe7ea", "src_uid": "66398694a4a142b4a4e709d059aca0fa", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int x,y,z;\n    scanf(\"%d%d%d\",&x,&y,&z);\n    if((x<=z && y<=z) ||(x-y)<=z)){\n        printf(\"?\");\n    }\n    else if(x>y){\n        printf(\"+\");\n    }\n    else if(x<y){\n        printf(\"-\");\n    }\n    else if(x==y){\n        printf(\"0\");\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3fa7b15984de97f4baa1f8abc3fefe12", "src_uid": "66398694a4a142b4a4e709d059aca0fa", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    int x,y,z;\n    scanf(\"%d %d %d\",&x,&y,&z);\n    int c=x-y;d=abs(c);\n    if(d>=z)\n    {\n        if(c>0)\n        printf(\"+\");\n        else if(c<0)\n        printf(\"-\");\n        else\n        printf(\"0\");\n        \n    }\n    else\n    printf(\"?\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2bbb1c9c3e36529344fef382090ccae6", "src_uid": "66398694a4a142b4a4e709d059aca0fa", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\nint main()\n{\n    int m,j,k,n,w;\n    scanf(\"%d%d%d\", &k,&n,&w);\n    for(int m=1;m<=w;m++)\n    {\n        j+=n-k*m;\n        n-=k*m;\n    }\n    if(a<0) printf(\"%d\", -n);\n    else printf(\"%d\", n);\n\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a2e3793497188369c1cb6cbe36d95c19", "src_uid": "e87d9798107734a885fd8263e1431347", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "    #include <stdio.h>\n     \n    int main() {\n        int k,n,w,borrow;\n        int cost=0,rate;\n        scanf(\"%d%d%d\",&k,&n,&w);\n        for(i=0;i<w;i++) {\n            rate = i * k;\n            cost = cost + rate;\n        }\n        borrow = cost - n;\n        if(borrow < 0) {\n            borrow = 0;\n        } else {\n            printf(\"%d\",borrow);\n        }\n        return 0;\n    }", "lang_cluster": "C", "compilation_error": true, "code_uid": "d34ff7c5d265841b47e3dad7d54bb214", "src_uid": "e87d9798107734a885fd8263e1431347", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n     long long int k,n,w,i,a=0,s;\n     scanf(\"%lld %lld %lld\",&k,&n,&w);\n     for(i=1;i<=w;i++)\n     {\n           a+=(i*k);\n     }\n     s=a-n;\n     if(a<=w)\n            printf(\"0\");\n     else\n            printf(\"%lld\",s);\n     }\n     return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ad7bf596893e55e71baa32021aa6b226", "src_uid": "e87d9798107734a885fd8263e1431347", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n          int a,b,c,d;\n          scanf(\"%d%d%d\",&a,&b,&c);\n          if(a==c){\n                    printf(\"0\")\n          }\n          else{\n          d=b-c;\n          printf(\"%d\",d);}\n          return 0;\n          \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f6e903b5307ac7f3956487e547db1491", "src_uid": "e87d9798107734a885fd8263e1431347", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main()\n{\n\tint i;\n\tint j;\n\tint a;\n\tint b;\n\tint c;\n\tint d;\n\tint e;\n\tint f;\n\tint g;\n\tscanf(\"%d\", &a);\n\tscanf(\"%d\", &b);\n\tscanf(\"%d\", &c);\n\tfor (i=1;i<=c;i++)\n\t{\n\t  d=i*c\n\t}\n\tprintf(\"%d\", d);\n\treturn 0;\t\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3c0a8742c3000dd3868d413a4fb4adc1", "src_uid": "e87d9798107734a885fd8263e1431347", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nchar str[101];\nint main()\n{\n   scanf(\"%s\", str);\n   int len = 1, index = 0, result = 0;\n   while(str[index++]) {\n        if (str[index] == str[index - 1]) {\n            len++;\n        } else {\n            if (len % 2 == 0)\n                result++;\n            len = 1;\n        }\n   }\n   printf(\"%d\\n\",result);\n}\n~", "lang_cluster": "C", "compilation_error": true, "code_uid": "90251621cae6ff03822a0672e0e75ae8", "src_uid": "8b26ca1ca2b28166c3d25dceb1f3d49f", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <iostream>\n#include \"string.h\"\n#include \"stdio.h\"\nusing namespace std;\n\nint main(){\n    char s[101];\n    int i, j, len, numA=0, toAdd=0;\n\n    scanf(\"%s\", s);\n\n    len = strlen(s);\n\n    for(i = 0; i < len; i++){\n        numA = 0;\n        for(j = i; s[i] == s[j]; j++){\n            numA++;\n        }\n        i = j - 1;\n        if(!(numA % 2)){\n            toAdd++;\n        }\n    }\n    printf(\"%d\\n\", toAdd);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5ee0d262d0d5473a327c98d412e0d19a", "src_uid": "8b26ca1ca2b28166c3d25dceb1f3d49f", "difficulty": null}
{"lang": "GNU C", "source_code": "\n#include <stdio.h>\nint k=0;\nint main()\n{\n    char arr[1000];\n    scanf(\"%s\",arr);\n    int i,j=0,counter=0;\n\n    for(i=0;arr[i+1]!='\\0';i++)\n    {\n        if(arr[i]!=arr[i+1])\n        {\n\n            j=(i+1)-k;\n\n\n            if(j%2==0)\n            {\n\n\n            counter++;\n\n\n            }k=i+1;\n        }\n    }\n    printf(\"%d\",counter);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "079da82fedf45bd85e822ac7b4d6f5d4", "src_uid": "8b26ca1ca2b28166c3d25dceb1f3d49f", "difficulty": null}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n    int n=0,cnt=1,no=0;\n    char ch,ch1='1';\n    while((ch=getchar())!='\\n')\n    {\n        if(ch1!='1')\n        {\n            if(ch==ch1)\n                cnt++;\n            else{\n                    ch1=ch;\n                  if(cnt%2==0 && cnt!=1)\n                     no++;\n                cnt=1;\n                n++;\n            }\n        }\n        else{\n            ch1=ch;\n            n++;\n        }\n\n    }\n    if(n%2==0)\n        printf(\"%d\\n\",no);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "000d770dab885d6b00744e67b748e565", "src_uid": "8b26ca1ca2b28166c3d25dceb1f3d49f", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\nvoid main() {\n\tchar *s = (char*)malloc(sizeof(char)*101);\n\tscanf(\"%[^\\n]\",s);\n\tint result = 0;\n\tint i=0,j=0;\n\twhile(s[i]!='\\0') {\n\t\tj=i+1;\n\t\tint count = 1;\n\t\twhile(s[j]!='\\0' && s[i]==s[j]) {\n\t\t\tcount++;\n\t\t\tj++;\n\t\t}\n\t\tif(count%2==0) {\n\t\t\tresult++;\n\t\t}\n\t\tif(j=='\\0') {\n\t\t\tbreak;\n\t\t}\n\t\ti=j;\n\t}\n\tprintf(\"%d\",result);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8313fcbd5c20e09b5d3dda8a11ff60ab", "src_uid": "8b26ca1ca2b28166c3d25dceb1f3d49f", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n//#include <stdlib.h>\n\nint main()\n{\n    int n,t;\n    char c[n];\n\n    scanf(\"%d %d\",&n,&t);\n\n    for(int i=0; i<t; i++){\n    for(int j=0; j<n; j++){\n        scanf(\"%c\",&c[n]);\n        if((c[n]=='B') && (c[n+1]== 'G')){\n          c[n+1]== 'B';\n          c[n]=='G';\n           }}}\n           printf(\"%c\",c[n]);\n           i++;\n     \n    return 0;\n    }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c6c928ec9f41dff548a36eccc80eb8ae", "src_uid": "964ed316c6e6715120039b0219cc653a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nvoid main{\n    int n,t;\n    scanf(\"%d %d\",&n,&t);\n    char queue[n];\n    char temp;\n    for(int k=0;k<n-1;k++)\n        {\n            scanf(\"%c\",&queue[j]);\n        }\n    for(int i=0;i<t;i++)\n    {\n        for(int j=0;j<n-1;j++)\n        {\n            if(queue[j]=='B'&& queue[j+1]=='G')\n            {\n                temp=queue[j];\n                queue[j]=queue[j+1];\n                queue[j+1]=temp;\n                j++;\n            }\n        }\n    }\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8e19dead76845b5635260f8350408b06", "src_uid": "964ed316c6e6715120039b0219cc653a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,t,i,j;\n    char s[52];\n    scanf(\"%d%d\",&n,&x);\n    scanf(\"%s\",s);\n    for(j=0; j<t; j++)\n    {\n        for(i=0; i<n-1; i++)\n        {\n            if(s[i]=='B'&&s[i+1]=='G')\n            {\n                s[i]='G';\n                s[i+1]='B';\n                i++;\n            }\n        }\n\n    }\n    printf(\"%s\\n\",s);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "db2a48d8097add432ccbd8bad33edfc3", "src_uid": "964ed316c6e6715120039b0219cc653a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n//#include<string.h>\n\n//void swap(int *xp, int *yp)  \n//{  \n//    int temp = *xp;  \n//    *xp = *yp;  \n//    *yp = temp;  \n//}  \n//  \n//// A function to implement bubble sort  \n//void bubbleSort(int arr[], int n)  \n//{  \n//    int i, j;  \n//    for (i = 0; i < n-1; i++)      \n//      \n//    // Last i elements are already in place  \n//    for (j = 0; j < n-i-1; j++)  \n//        if (arr[j] > arr[j+1])  \n//            swap(&arr[j], &arr[j+1]);  \n//}\n\nint main(){\n\tint m,n;\n\tscanf(\"%d %d\",&m,&n); \n\tchar c[m];\n\tint a=0;\n\tbool cek[m];\n\tfor(int i=0;i<m;i++){\n\t\tscanf(\" %c\",&c[i]);\n\t\tif(c[i]=='B'){\n\t\t\tcek[i]=false;\n\t\t\ta++;\n\t\t}\n\t}\n\tchar h;\n\tint b=a;\n\tfor(int i=0;i<n;i++){\n\t\ta=0;\n\t\tfor(int k=0;k<m;k++){\n\t\t\tcek[k]=false;\n\t\t}\n\t\t\n\t\tfor(int j=0;j<m;j++){\n\t\t\tif(c[j]=='B' && c[j+1]=='G' && cek[j]==false){\n\t\t\t\th = c[j];\n\t\t\t\tc[j] = c[j+1];\n\t\t\t\tc[j+1]=h;\n\t\t\t\tcek[j+1]=true;\n\t\t\t\t\n\t\t\t}\n\t\t}\n\t}\n\t\n\tprintf(\"%s\",c);\n\t\n\n}\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "67ae295b1af6a4ee3f9070cead841bd7", "src_uid": "964ed316c6e6715120039b0219cc653a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n//#include<string.h>\n\n//void swap(int *xp, int *yp)  \n//{  \n//    int temp = *xp;  \n//    *xp = *yp;  \n//    *yp = temp;  \n//}  \n//  \n//// A function to implement bubble sort  \n//void bubbleSort(int arr[], int n)  \n//{  \n//    int i, j;  \n//    for (i = 0; i < n-1; i++)      \n//      \n//    // Last i elements are already in place  \n//    for (j = 0; j < n-i-1; j++)  \n//        if (arr[j] > arr[j+1])  \n//            swap(&arr[j], &arr[j+1]);  \n//}\n\nint main(){\n\tint m,n;\n\tscanf(\"%d %d\",&m,&n); \n\tchar c[m];\n\tint a=0;\n\tbool cek[m];\n\tfor(int i=0;i<m;i++){\n\t\tscanf(\" %c\",&c[i]);\n\t\tif(c[i]=='B'){\n\t\t\tcek[i]=false;\n\t\t\ta++;\n\t\t}\n\t}\n\tchar h;\n\tint b=a;\n\tfor(int i=0;i<n;i++){\n\t\ta=0;\n\t\tfor(int k=0;k<m;k++){\n\t\t\tcek[k]=false;\n\t\t}\n\t\t\n\t\tfor(int j=0;j<m-1;j++){\n\t\t\tif(c[j]=='B' && c[j+1]=='G' && cek[j]==false){\n\t\t\t\th = c[j];\n\t\t\t\tc[j] = c[j+1];\n\t\t\t\tc[j+1]=h;\n\t\t\t\tcek[j+1]=true;\n\t\t\t\t\n\t\t\t}\n\t\t}\n\t}\n\t\n\tprintf(\"%s\",c);\n\t\n\n}\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d4871b084c8a9bd0214347d51e755070", "src_uid": "964ed316c6e6715120039b0219cc653a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint gcd(long long int a,long long int b);\nint main()\n{\n    long long int a,b,x,y,w,h,i=0;\n    scanf(\"%lli%lli%lli%lli\",&a,&b,&x,&y);\n    w=x/gcd(x,y);\n    h=y/gcd(x,y);\n\n\n\n    for(i=1;w*i<=a&&h*i<=b;i++);\n\n\n\nprintf(\"%lli\",i-1);\n}\nint gcd(long long int a, long long int b)\n{\n    long long int t;\n  if(a>b)\n  {\n   a=a+b;\n   b=a-b;\n   a=a-b;\n  }\n  while(b%a!=0)\n  {\n     t=a;\n     a=b%a;\n     b=t;\n  }\n   return a;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1e0551112c5fd533c897872ed994917d", "src_uid": "907ac56260e84dbb6d98a271bcb2d62d", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main(){\n\tlong long a,b,x,y,count=0,m,n,l,k,gcd;\n\tscanf(\"%I64d %I64d %I64d %I64d\",&a,&b,&x,&y);\n\tm=x;n=y;\n\twhile(m!=n)\n\t{\n\t\tif(m>n)\n\t\tm=m-n;\n\t\t\n\t\tif(n>m)\n\t\tn=n-m;\n\t}\n\tgcd=m;\n\ty=y/m;\n\tx=x/m;\n\n\tif(a/x>b/y)\n\tprintf(\"%I64d\",b/y);\n\telse \n\tprintf(\"%I64d\",a/x);\n\t\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7230133aa8f62778ba25e642f4e13f92", "src_uid": "907ac56260e84dbb6d98a271bcb2d62d", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nunsigned long long int gcd(unsigned long long int a,unsigned long long int b)\n{\n\t// long long int f=-1;\n\tif(a==0)\n\t\treturn b;\n\telse if(b==0)\n\t\treturn a;\n\telse if(a==1 || b==1)\n\t\treturn 1;\n\telse if (a>b)\n\t\treturn gcd(b,a%b);\n\telse if (a<b)\n\t\treturn gcd(b%a,a);\n\t// while(f==-1)\n\t// {\n\t// \tif(a==0)\n\t// \tf= b;\n\t// else if(b==0)\n\t// \tf= a;\n\t// else if(a==1 || b==1)\n\t// \tf= 1;\n\t// else if (a>b)\n\t// \ta=a%b;\n\t// else if (a<b)\n\t// \tb=b%a;\n\t// }\n\t// return f;\n}\nint main() \n{\n\tunsigned long long int a,b,x,y;\n\t// unsigned long long int cnt=0;\n\tscanf(\"%llu %llu %llu %llu\",&a,&b,&x,&y);\n\tunsigned long long int g=gcd(x,y);\n\tx=x/g;\n\ty=y/g;\n\tunsigned long long int r1,r2;\n\tr1=a/x;\n\tr2=b/y;\n\tif(x>y)\n\t\tprintf(\"%llu\\n\",r1);\n\telse\n\t\tprintf(\"%llu\\n\",r2);\n\t// for(i=1;x*i<=a && y*i<=b;i++)\n\t// {\n\t// \tcnt++;\n\t// }\n\n\t// printf(\"%lld\\n\",cnt );\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "bdcb2a5665ec45a761d88ad1ef5c5860", "src_uid": "907ac56260e84dbb6d98a271bcb2d62d", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nunsigned long long int gcd(unsigned long long int a,unsigned long long int b)\n{\n\t// long long int f=-1;\n\tif(a==0)\n\t\treturn b;\n\telse if(b==0)\n\t\treturn a;\n\telse if(a==1 || b==1)\n\t\treturn 1;\n\telse if (a>b)\n\t\treturn gcd(b,a%b);\n\telse if (a<b)\n\t\treturn gcd(b%a,a);\n\t// while(f==-1)\n\t// {\n\t// \tif(a==0)\n\t// \tf= b;\n\t// else if(b==0)\n\t// \tf= a;\n\t// else if(a==1 || b==1)\n\t// \tf= 1;\n\t// else if (a>b)\n\t// \ta=a%b;\n\t// else if (a<b)\n\t// \tb=b%a;\n\t// }\n\t// return f;\n}\nint main() \n{\n\tunsigned long long int a,b,x,y,i,x1,y1;\n\tunsigned long long int cnt=0;\n\tscanf(\"%llu %llu %llu %llu\",&a,&b,&x,&y);\n\tunsigned long long int g=gcd(x,y);\n\tx=x/g;\n\ty=y/g;\n\tunsigned long long int r1,r2;\n\tr1=a/x;\n\tr2=b/y;\n\tif(x>y)\n\t\tprintf(\"%llu\\n\",r1);\n\telse\n\t\tprintf(\"%llu\\n\",r2);\n\t// for(i=1;x*i<=a && y*i<=b;i++)\n\t// {\n\t// \tcnt++;\n\t// }\n\n\t// printf(\"%lld\\n\",cnt );\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "bbb0b323c1498a221ff3bf164f83519b", "src_uid": "907ac56260e84dbb6d98a271bcb2d62d", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nlong long int gcd(long long int a,long long int b)\n{\n\t// long long int f=-1;\n\tif(a==0)\n\t\treturn b;\n\telse if(b==0)\n\t\treturn a;\n\telse if(a==1 || b==1)\n\t\treturn 1;\n\telse if (a>b)\n\t\treturn gcd(b,a%b);\n\telse if (a<b)\n\t\treturn gcd(b%a,a);\n\t// while(f==-1)\n\t// {\n\t// \tif(a==0)\n\t// \tf= b;\n\t// else if(b==0)\n\t// \tf= a;\n\t// else if(a==1 || b==1)\n\t// \tf= 1;\n\t// else if (a>b)\n\t// \ta=a%b;\n\t// else if (a<b)\n\t// \tb=b%a;\n\t// }\n\t// return f;\n}\nint main() \n{\n\tlong long int a,b,x,y,i,x1,y1;\n\tlong long int cnt=0;\n\tscanf(\"%lld %lld %lld %lld\",&a,&b,&x,&y);\n\tlong long int g=gcd(x,y);\n\tx=x/g;\n\ty=y/g;\n\tlong long int r1,r2;\n\tr1=a/x;\n\tr2=b/y;\n\tif(x>y)\n\t\tprintf(\"%d\\n\",r1);\n\telse\n\t\tprintf(\"%d\\n\",r2);\n\t// for(i=1;x*i<=a && y*i<=b;i++)\n\t// {\n\t// \tcnt++;\n\t// }\n\n\t// printf(\"%lld\\n\",cnt );\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "bdb4e6dffb439190f90cb57d3d18e617", "src_uid": "907ac56260e84dbb6d98a271bcb2d62d", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include<string.h>\nint main()\n{\n\tchar st[30];\n\tlong long a,j=1,i,sum=0,k=1,sum2=0,b,c,total=0,r,d;\n\tscanf(\"%s\",st);\n\ta=strlen(st);\n\tfor(i=1;i<=a-1;i++)\n\t{\n\t\tsum+=(9*j);\n\t\tj=j*10;\n\t}\n\tb=((st[0]-49)*j)+sum;\n\tfor(i=a-1;i>=0;i--)\n\t{\n\t\tsum2+=(st[i]-48)*k;\n\t\tk=k*10;\n\t}\n\ttotal=((a-1)*9)+st[0]-49;\n\td=sum2-b;\n\twhile(d!=0)\n\t{\n\t\tr=d%10;\n\t\tc=d/10;\n\t\td=c;\n\t\ttotal+=r;\n\t}\n\tprintf(\"%lld\\n\",total);\n\t\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "57bf9822880b629ed507e29b3aea48b0", "src_uid": "5c61b4a4728070b9de49d72831cd2329", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <Windows.h>\nint main() {\n\tlong long n,n2;\n\tlong long ans=0;\n\n\tscanf_s(\"%I64d\", &n);\n\tn2 = 9;\n\twhile (n > n2) {\n\t\tans += 9;\n\t\tn2 *= 10;\n\t\tn2 += 9;\n\t}\n\tn2 /= 10;\n\tn -= n2;\n\twhile (n > 0) {\n\t\tans += n % 10;\n\t\tn /= 10;\n\t}\n\n\t\n\tprintf(\"%I64d\", ans);\n\tsystem(\"pause\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d292a9453b13c8f8d3cd519cfadf1ad5", "src_uid": "5c61b4a4728070b9de49d72831cd2329", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\nint main() {\n\tlong long n,n2;\n\tlong long ans=0;\n\tscanf_s(\"%I64d\", &n);\n\t \n\tif (n < 10) {\n\t\tprintf(\"%d\", n);\n\t\treturn 0;\n\t}\n\tans += 10 + n % 10;\n\tn -= 10 + n % 10;\n\n\twhile (n > 0) {\n\t\tans += n % 10;\n\t\tn /= 10;\n\t}\n\tprintf(\"%d\", ans);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "00a129e0c0570866b44a0aef9309461e", "src_uid": "5c61b4a4728070b9de49d72831cd2329", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<iostream>\n\nusing namespace std;\n\nint main(){\n    long long int n,sum=0,x,y;\n    scanf(\"%lld\",&n);\n    \n    if(n==0)\n       cout<<n<<endl;\n    else{\n    \n    if(n%2==0){\n       x=(n/2)-1;\n       y=(n/2)+1;\n    }\n    else{\n       x=n/2;\n       y=(n/2)+1;\n    }\n    while(x>0){\n       sum+=(x%10);\n       x/=10;\n    }\n    while(y>0){\n       sum+=(y%10);\n       y/=10;\n    }\n    printf(\"%lld\\n\",sum);\n  }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5a97018995c8525e69ac4ec53572cc2b", "src_uid": "5c61b4a4728070b9de49d72831cd2329", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\nint main()\n{\n\tchar st[30];\n\tlong long a,j=1,i,sum=0,k=1,sum2=0,b,c,total=0,r,d;\n\tscanf(\"%s\",st);\n\ta=strlen(st);\n\tfor(i=1;i<=a-1;i++)\n\t{\n\t\tsum+=(9*j);\n\t\tj=j*10;\n\t}\n\tb=((st[0]-49)*j)+sum;\n\tfor(i=a-1;i>=0;i--)\n\t{\n\t\tsum2+=(st[i]-48)*k;\n\t\tk=k*10;\n\t}\n\ttotal=((a-1)*9)+st[0]-49;\n\td=sum2-b;\n\twhile(d!=0)\n\t{\n\t\tr=d%10;\n\t\tc=d/10;\n\t\td=c;\n\t\ttotal+=r;\n\t}\n\tprintf(\"%lld\\n\",total);\n\treturn 0;\n\t\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4c6d8b2aa13229b93da1460f696923b9", "src_uid": "5c61b4a4728070b9de49d72831cd2329", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main(){\n    \n    char ar[105];\n    scanf(\"%s\", ar);\n    \n    int n = strlen(ar);\n\n    int i , count= 0, count1 = 0;\n    if ( ar[0] >= 'A' && ar[0] <= 'Z' ){\n        for ( i = 1 ; i < n ; i++){\n            if ( ar[i] >= 'A' && ar[i] <= 'Z')\n                count1++;\n            else \n                break;\n            }\n        }\n    if ( count1 == n - 1 ){\n        printf( \"%s\" , ar);\n        }\n    \n        \n    if( ar[0] >= 'a' && ar[0] <= 'z'){\n        for ( i = 1 ; i < n ; i++){\n            if ( ar[i] >= 'A' && ar[i] <= 'Z' )\n                count++;\n            else\n                break;\n        }\n    }\n    if ( count == n - 1){\n        ar[0] = 'A' + (ar[0] -'a');\n        for (i = 1; i < n ; i++ )\n            ar[i] = 'a' + ( ar[i] - 'A');\n            printf(\"%s\", ar);\n            }\n    else\n        break;\n\n    \n    else\n        printf(\"%s\",ar);\n    \n    return 0;\n    }", "lang_cluster": "C", "compilation_error": true, "code_uid": "a3fadff84d974faf40d56c1f1def28c3", "src_uid": "db0eb44d8cd8f293da407ba3adee10cf", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n#include <vector>\n#include <cstdio>\nusing namespace std;\nint main()\n{\n    string s;\n    int counts=0,countb=0,len,countfs=0,countfb=0;\n    getline(cin, s);\n    vector<string>v;\n    v.push_back(s);\n    for(int i=0;i<v[0].size();i++) {\n        if(v[0][i]>='A' && v[0][i]<='Z' && i!=0) {\n            countb++;\n        }\n        if(v[0][i]>='a' && v[0][i]<='z' && i!=0) {\n            counts++;\n        }\n        if(v[0][0]>='A' && v[0][0]<='Z') {\n            countfb++;\n        }\n        if(v[0][0]>='a' && v[0][0]<='z') {\n            countfs++;\n        }\n    }\n    if((countfb>0 && countb>0 && counts==0) || (countfs>0)) {\n        for(int i=0;i<v[0].size();i++) {\n            if(v[0][0]>='a' && v[0][0]<='z') {\n                v[0][0]=v[0][0]-32;\n            }\n            if(v[0][i]>='A' && v[0][i]<='Z' && i!=0) {\n                v[0][i]=v[0][i]+32;\n            }\n        }\n    }\n    cout<<v[0]<<\"\\n\";\n\n\n\n\n\n\n\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c13ef880169adb77e4cf2a02c4e31560", "src_uid": "db0eb44d8cd8f293da407ba3adee10cf", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include <string.h>\nint main()\n{\n    char string[1000];\n    int i;\n    gets(string);\n    strlwr(str);\n\tif( isupper(string[0]) )\n\t{\n\tprintf(\"%c\", string[0] );\n\t}\n\telse\n\t{\n\tprintf(\"%c\", string[0]-32 );\n\t}\n\tfor(i = 1; i < strlen(string); i++ )\n\t{ \n\t\tprintf(\"%c\",  string[i] );\n\t}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2c9fa3d20301573a03a7403557ac010a", "src_uid": "db0eb44d8cd8f293da407ba3adee10cf", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<ctype.h>\nint main(){\n    int l,i,c=0;\n    char str[i];\n    scanf(\"%s\",str);\n    l=strlen(str);\n    for(i=1;i<l;i++){\n        if(isupper(s[i]))\n        c++;\n    }\n    if(c==l-1){\n        for(i=0;i<l;i++){\n            s[i] = isupper(s[i])?islower(s[i])?toupper(s[i]));\n        }\n    }\n    printf(\"%s\",s);\n}\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "98548b8c3e6e8b8a9a93d81fc5c62232", "src_uid": "db0eb44d8cd8f293da407ba3adee10cf", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char s[100000000000],\n    fgets(s,sizeof (s),stdin);\n    int count=0,l=0;\n\n    l=strlen(s);\n    for(int i=0;i<l-1;i++)\n    {\n        if(s[i]>=65 && s[i]<=90)\n            count++;\n    }\n\n    if(count==l-1)\n    {\n        for(int i=0;i<l-1;i++)\n            s[i]=s[i]+32;\n    }\n    else if(count==l-2 && s[0]>=97)\n    {\n        for(int i=1;i<l-1;i++)\n            s[i]=s[i]+32;\n        s[0]=s[0]-32;\n    }\n    printf(\"%s\",s);\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c3889134ac6acc9fd39fb410bdbf4c32", "src_uid": "db0eb44d8cd8f293da407ba3adee10cf", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stduo.h>\nint main()\n{\n    int n,sum=0,r;\n    scanf(\"%d\",&n);\n    while(n>0)\n    {\n        r=n%10;\n        n=n/10;\n        sum=sum+r;\n    }\n    if(sum%4==0)\n    printf(\"%d\",n);\n    else\n    {\n        n++;\n    }\n    printf(\"%d\",n);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bd7d6b4da9149995665c5293e373ba0a", "src_uid": "bb6fb9516b2c55d1ee47a30d423562d7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint testingMethod(int interest) {\n\tint test;\n\n\tif (interest < 4)\n\t\ttest = 4 - interest;\n\telse if (interest < 8)\n\t\ttest = 8 - interest;\n\telse if (interest < 12)\n\t\ttest = 12 - interest;\n\telse if (interest < 16)\n\t\ttest = 16 - interest;\n\telse if (interest < 20)\n\t\ttest = 20 - interest;\n\telse if (interest < 24)\n\t\ttest = 24 - interest;\n\telse if (interest < 28)\n\t\ttest = 28 - interest;\n\telse if (interest < 32)\n\t\ttest = 32 - interest;\n\n\treturn test;\n}\n\nint main() {\n\n\tchar str[5];\n\tint arr[4];\n\tgets_s(str);\n\tint i, j = 0, n;\n\tint interest = 0, test = 0, carry;\n\n\tfor (n = 0; str[n]; ++n);\n\tfor (i = n - 1, j = 3; j >= 0 ; --i, --j) {\n\n\t\tif (i < 0)\n\t\t\tarr[j] = 0;\n\t\telse\n\t\t\tarr[j] = str[i] - 48;\n\t}\n\n\tfor ( ; ; ) {\n\n\t\tfor (j = 0; j < 4; ++j) {\n\t\t\tinterest += arr[j];\n\t\t}\n\n\t\tif (interest % 4 == 0)\n\t\t\tbreak;\n\n\t\ttest = testingMethod(interest);\n\t\tif (arr[3] + test < 10) {\n\t\t\tarr[3] += test;\n\t\t}\n\t\telse {\n\t\t\tarr[3] = 0;\n\t\t\tcarry = 1;\n\t\t\tfor (i = 2; carry; --i) {\n\t\t\t\tif ((arr[i] + carry) > 9)\n\t\t\t\t\tarr[i] = 0;\n\t\t\t\telse {\n\t\t\t\t\tarr[i] += carry;\n\t\t\t\t\tcarry = 0;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t\n\t\tinterest = 0;\n\t}\n\tif (arr[0] > 0)\n\t\t++n;\n\n\tfor(i = 4 - n; n > 0; ++i, --n)\n\t\tprintf(\"%d\", arr[i]);\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dcb46d2e36c2882d0c2f837a542c38fc", "src_uid": "bb6fb9516b2c55d1ee47a30d423562d7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <cstdio>\n\nbool check(int x) {\n    int cnt = 0;\n    while (x) {\n        cnt += x % 10;\n        x /= 10;\n    }\n    return cnt % 4 == 0;\n}\n\nint main() {\n    int a;\n    scanf(\"%d\", &a);\n    int ans = a;\n    while (!check(ans)) \n        ans++;\n    printf(\"%d\\n\", ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "994713fc8b8deb0f66b72d44b88ba75d", "src_uid": "bb6fb9516b2c55d1ee47a30d423562d7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main\n{\n    int i,j,sum,k;\n    scanf(\"%d\",&i);\n    k=i;\n    while(i!=0)\n    {\n        j=i%10;\n        sum=sum+j;\n        i=i/10;\n    }\n    if(sum%4==0)\n    printf(\"%d\",k);\n    else if(sum%4==1)\n    printf(\"%d\",k+3);\n    else if(sum%4==2)\n    printf(\"%d\",k+2);\n    else if(sum%4==3)\n    printf(\"%d\",k+1);\n    return 0;\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "727484d87408b90ae45a6af5808bf815", "src_uid": "bb6fb9516b2c55d1ee47a30d423562d7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint sum(int i);\n{\n int k=0;\n while(i>0)\n {\n     k=k+i%10;\n     i=i/10;\n }\n return k;\n    \n}\nint main()\n{\n    int i,j,k;\n    scanf(\"%d\",&i);\n    while(sum(i)%4!=0)\n    {\n        i++;\n    }\n    printf(\"%d\",i);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "01f50022551fc52a764117971999f46f", "src_uid": "bb6fb9516b2c55d1ee47a30d423562d7", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\n// for Fast IO\nint readint()\n{\n    int cc = getchar_unlocked();\n    for (;cc < '0' || cc > '9';)\n        cc = getchar_unlocked();\n    int ret = 0;\n    for (;cc >= '0' && cc <= '9';)\n    {\n        ret = ret * 10 + cc - '0';\n        cc = getchar_unlocked();\n    }\n    return ret;\n}\n// \n\nint main(void)\n{\n    int i, j, n, arr[100001], premax, max;\n\n    scanf(\"%d\",&n);\n    for(i=0; i<n; i++)\n        arr[i] = readint();\n\n    for(i=0; i<n-1; i++)\n        for(j=i+1; j<n; j++)\n            if(arr[i] > arr[j])\n            {\n                int temp = arr[j];\n                arr[j] = arr[i];\n                arr[i] = temp;\n            }\n\n    max = arr[n-1];\n    for(i=n-2; i>=0; i--)\n        if(arr[i] != max)\n        {\n            premax = arr[i];\n            break;\n        }\n\n    if(premax*2 <= max)\n        printf(\"NO\\n\");\n    else\n        printf(\"YES\\n\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bde01772156b144fd918a19b4b543d93", "src_uid": "ab003ab094931fc105384df9d144131e", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#include <string.h>\n#define mian main\n#define inf 1061109567\nint min(int a,int b){return a>b?b:a;}\nint max(int a,int b){return a<b?b:a;}\nvoid swap(int*a, int*b){*a =*a +*b-(*b =*a);}\nint a[100100];\nvoid just(int a[],int left,int right)\n{\n\tif (left>=right)\n\t\treturn ;\n\tint l=left,r=right,x=a[(right+left)/2];\n\twhile(l<r)\n\t{\n\t\twhile(l<r&&a[l]<x)l++;// \n\t\twhile(l<r&&a[r]>x)r--;\n\t\tif(l<r)\n\t\t{\n\t\t\tif(a[l]>a[r])\n\t\t\t{\n\t\t\t\tint t=a[l];\n\t\t\t\ta[l]=a[r];\n\t\t\t\ta[r]=t;\n\t\t\t}\n\t\t\telse l++;\n\t\t}\n\t\t\n\t}\n\tjust(a,left,l-1);\n\tjust(a,l+1,right);\n}\n\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tint i,j,k;\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tscanf(\"%d\",&a[i]);\n\t}\n\tjust(a,1,n);\n\tint x,y,z;\n\tfor(i=1;i<n;i++)\n\t{\n\t\t\n\t\t\t\n\t\tx=a[i];\n\t\ty=a[i+1];\n\t\t//y=a[i-1];\n\t\tif(2*x>y&&x!=y)//x-z\n\t\t{\n\t\t\tprintf(\"YES\");\n\t\t\treturn 0;\n\t\t}\n\t\t\n\t}\n\tprintf(\"NO\");\n\treturn 0;\n}\n \n\n\n    \n\n\n\n\n\nby IneedAC\n\n\n\n\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "228df9263dd44d45e746cfde8742bd32", "src_uid": "ab003ab094931fc105384df9d144131e", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h> \nint a[100000], n;\nint cmp(const void *x, const void *y) \n{\n\tif(*(int*)x < *(int*)y) return -1;\n\tif(*(int*)x > *(int*)y) return 1;\n\treturn 0;\n}\nint main()\n{\n\tint flag = 1;\n\tscanf(\"%d\", &n);\n\tfor(int i = 0; i < n; i++) {\n\t\tscanf(\"%d\", a + i);\n\t}\n\tqsort(a, n, sizeof(int), cmp);\n\tfor(int i = 0; i < n - 1; i++) {\n\t\tif(2 * a[i] > a[i + 1]) {\n\t\t\tflag = 0;\n\t\t\tbreak;\n\t\t}\n\t}\n\tprintf(flag? \"NO\" : \"YES\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "41de0b3afc1a7e7a08d34c72b9dd9bd1", "src_uid": "ab003ab094931fc105384df9d144131e", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<algorithm>\n\nint main(void)\n{\n    int i, j, n, arr[100001];\n\n    scanf(\"%d\",&n);\n    for(i=0; i<n; i++)\n        scanf(\"%d\",&arr[i]);\n\n    for(i=0; i<n-1; i++)\n        for(j=i+1; j<n; j++)\n            if(arr[i] > arr[j])\n            {\n                int temp = arr[j];\n                arr[j] = arr[i];\n                arr[i] = temp;\n            }\n\n    if(arr[n-2]*2 <= arr[n-1])\n        printf(\"NO\\n\");\n    else\n        printf(\"YES\\n\");\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bfb91e73e3991ac67ee9bca5de4e77df", "src_uid": "ab003ab094931fc105384df9d144131e", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#include <string.h>\n#define mian main\n#define inf 1061109567\nint min(int a,int b){return a>b?b:a;}\nint max(int a,int b){return a<b?b:a;}\nvoid swap(int*a, int*b){*a =*a +*b-(*b =*a);}\nint a[100100];\nvoid just(int a[],int left,int right)\n{\n\tif (left>=right)\n\t\treturn ;\n\tint l=left,r=right,x=a[(right+left)/2];\n\twhile(l<r)\n\t{\n\t\twhile(l<r&&a[l]<x)l++;// \n\t\twhile(l<r&&a[r]>x)r--;\n\t\tif(l<r)\n\t\t{\n\t\t\tif(a[l]>a[r])\n\t\t\t{\n\t\t\t\tint t=a[l];\n\t\t\t\ta[l]=a[r];\n\t\t\t\ta[r]=t;\n\t\t\t}\n\t\t\telse l++;\n\t\t}\n\t\t\n\t}\n\tjust(a,left,l-1);\n\tjust(a,l+1,right);\n}\n\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tint i,j,k;\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tscanf(\"%d\",&a[i]);\n\t}\n\tjust(a,1,n);\n\tint x,y,z;\n\tfor(i=1;i<n;i++)\n\t{\n\t\t\n\t\t\t\n\t\tx=a[i];\n\t\ty=a[i+1];\n\t\t//y=a[i-1];\n\t\tif(2*x>y&&x!=y)//x-z\n\t\t{\n\t\t\tprintf(\"YES\");\n\t\t\treturn 0;\n\t\t}\n\t\t\n\t}\n\tprintf(\"NO\");\n\treturn 0;\n}\n \n\n\n    \n\n\n\n\n\nby IneedAC\n\n\n\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9b52a397ac2c1965047a8cd1cfdcbd02", "src_uid": "ab003ab094931fc105384df9d144131e", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint poww(int m, int n)\n{\n    int t = 1;\n    int i;\n    \n    if(n == 0) \n        return 1;\n    else \n        for(i = 1; i <= n; i++)\n            t *= m;\n        \n    return t;\n}\n\nint main()\n{\n    char hour[6];\n    char minu[6];\n    int h, m;\n    int hmax, mmax;\n    int min, max;\n    int left;\n    int flag;\n    int i, j;\n    char c;\n    int hflag, mflag;\n    \n    i = 0;\n    while(1) {\n        c = getchar();\n        if(c != ':') {\n            hour[i] = c;\n            i++;\n        }\n        else {\n            hour[i] = 0;\n            break;\n        }\n    }\n\n    i = 0;\n    while(1) {\n        c = getchar();\n        if(c != '\\n') {\n            minu[i] = c;\n            i++;\n        }\n        else {\n            minu[i] = 0;\n            break;\n        }\n    }\n    \n    h = strlen(hour);\n    m = strlen(minu);\n    \n    i = 0;\n    while(hour[i] == '0') {\n        h--;\n        i++;\n    }\n    hflag = i;\n  \n    i = 0;\n    while(minu[i] == '0') {\n        m--;\n        i++;\n    }\n    mflag = i;\n    \n    if(m == 1 && h == 1)\n        if(hour[hflag] >= '0' && hour[hflag] <= '9' || hour[hflag] <= 'N' && hour[hflag] >= 'A') {\n            printf(\"-1\\n\");\n            return 0;\n        }   \n    if(m == 0 && h == 0) {\n        printf(\"-1\\n\");\n        return 0;\n    }  \n    \n    hmax = 2;\n    for(i = hflag; i < hflag + h; i++) {\n        if(hour[i] <= '9' && hour[i] >= '0')\n            hmax = hmax > (hour[i] - '0' + 1) ? hmax : (hour[i] - '0' + 1);\n        else \n            hmax = hmax > (hour[i] - 'A' + 11) ? hmax : (hour[i] - 'A' + 11);\n    }\n  \n    mmax = 2;\n    for(i = mflag; i < mflag + m; i++) {\n        if(minu[i] <= '9' && minu[i] >= '0')\n            mmax = mmax > (minu[i] - '0' + 1) ? mmax : (minu[i] - '0' + 1);\n        else\n            mmax = mmax > (minu[i] - 'A' + 11) ? mmax : (minu[i] - 'A' + 11);\n    }\n    \n    hmax = hmax > mmax ? hmax : mmax;\n    mmax = hmax;\n    min = hmax;\n    \n    if(h == 1)\n        hmax = -1;\n    else {\n        flag = 0;\n        while( 1 ) {\n            left = 23;\n            for(i = hflag + h - 1, j = 0; i >= hflag; i--, j++) {\n                if(hour[i] <= '9' && hour[i] >= '0')\n                    left -= (hour[i] - '0') * poww(hmax, j); \n                else\n                    left -= (hour[i] - 'A' + 10) * poww(hmax, j);\n            }\n        \n            if(left >= 0) {\n                flag = 1;\n                hmax++;\n            }\n            else if(flag == 0) {\n                printf(\"0\\n\");\n                return 0;\n            }\n            else {\n                hmax--;\n                break;\n            }\n        }\n    }\n   \n    if(m == 1)\n        mmax = -1;\n    else {\n        flag = 0;\n        while( 1 ) {\n            left = 59;\n            for(i = mflag + m - 1, j = 0; i >= mflag; i--, j++) {\n                if(minu[i] <= '9' && minu[i] >= '0')\n                    left -= (minu[i] - '0') * poww(mmax, j); \n                else\n                    left -= (minu[i] - 'A' + 10) * poww(mmax, j);\n            }\n        \n            if(left >= 0) {\n                flag = 1;\n                mmax++;\n            }\n            else if(flag == 0) {\n                printf(\"0\\n\");\n                return 0;\n            }\n            else {\n                mmax--;\n                break;\n            }\n        }\n    }\n    \n    if(hmax != -1 && mmax != -1)\n        max = hmax > mmax ? mmax : hmax;\n    else\n        max = mmax == -1 ? hmax : mmax;\n    \n    for(i = min; i <= max; i++) {\n        if(i == max) \n            printf(\"%d\\n\", i);\n        else\n            printf(\"%d \", i);\n    }\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a734bd0ddc8ab80510af7873a79f4f95", "src_uid": "c02dfe5b8d9da2818a99c3afbe7a5293", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\nint value(char c){\n    if(c>='0' && c<='9') return c-'0';\n    else if(c>='A' && c<='Z' ) return c-'A'+10;\n    else {\n        printf(\"Error radix\\n\");\n        return -1;\n    }\n}\nint valueR(char* num,int radix){\n    int i;\n    int rt=0;\n    for(i=0;i<strlen(num);i++){\n        rt=rt*radix+value(num[i]);\n    }\n    return rt;\n}\nint main(){\n    char num[20];\n    char num1[6];\n    char num2[6];\n    \n    int max=0;\n    int i,j;\n    int check,c;\n    \n    scanf(\"%s\",num);\n    check=0;//count 0\n    c=0;\n    for(i=0;num[i]!=':';i++){\n        if(num[i]!='0') check=1;\n        if(check==1){\n            num1[c++]=num[i];\n            if(value(num[i])>max) max= value(num[i]);\n        }\n    }\n    num1[c]='\\0';\n    \n    check=0;\n    c=0;\n    i++;\n    for(;num[i]!='\\0';i++){\n        if(num[i]!='0') check=1;\n        if(check==1) {\n            num2[c++]=num[i];\n            if(value(num[i])>max) max= value(num[i]);\n        }\n    }\n    num2[c]='\\0';\n\n    //printf(\"\\n%s:%s %d\\n\",num1,num2,max);\n    \n    //caculate\n    if(strlen(num1)==1&&strlen(num2)==1) printf(\"-1\\n\");\n    else{\n        i=max+1;\n        check=0;\n        while(1){\n            //check radix i\n            if(valueR(num1,i)<24 && valueR(num2,i)<60){\n                printf(\"%d \",i);\n                check=1;\n            }else{\n                if(check==0) printf(\"0\");\n                break;\n            }\n            i++;\n        }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "bea9c69dbcb3e677e4c39dd68120e258", "src_uid": "c02dfe5b8d9da2818a99c3afbe7a5293", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<math.h>\n#include<stdio.h>\n#include<string.h>\n//#include<iostream>\n//using namespace std;\nint a[5],b[5];\nchar t[50];\n\nmain()\n{\n    int i,j,k,n,r,h,m,sizea,sizeb,max=1,flag1=0,flag2=0,p,power;\n    scanf(\"%s\",t);\n    i=0;\n    sizea=0;\n\n    while(t[i]!=':')\n    {\n        if(t[i]>='0'&&t[i]<='9')\n        {\n            a[i]=t[i]-'0';\n        }\n        if(t[i]>='A'&&t[i]<='Z')\n        {\n            a[i]=t[i]-'A'+10;\n        }\n        if(a[i]>max)\n        max=a[i];\n\n        i++;\n        sizea++;\n    }\n    j=i+1;\n    sizeb=0;\n    while(t[j]!='\\0')\n    {\n        if(t[j]>='0'&&t[j]<='9')\n        {\n            b[sizeb]=t[j]-'0';\n        }\n        if(t[j]>='A'&&t[j]<='Z')\n        {\n            b[sizeb]=t[j]-'A'+10;\n        }\n        if(b[sizeb]>max)\n        max=b[sizeb];\n        //printf(\"%d\\n\",b[sizeb]);\n        j++;\n        sizeb++;\n\n    }\n    for(i=0;i<sizea;i++)\n    {\n        if(i==sizea-1)\n        {\n            h=a[i];\n            flag1=1;\n        }\n        else if(a[i]==0)\n        continue;\n        else\n        break;\n    }\n    for(i=0;i<sizeb;i++)\n    {\n        if(i==sizeb-1)\n        {\n            m=b[i];\n            flag2=1;\n        }\n        else if(b[i]==0)\n        continue;\n        else\n        break;\n    }\n    if(flag1==1&&flag2==1&&h<=23&&m<=59)\n    {\n        printf(\"-1\\n\");\n        return 0;\n    }\n    h=0;\n    m=0;\n\n\n   // printf(\"%d %d\\n\",sizea,sizeb);\n    for(p=max+1;;p++)\n    {\n        h=0;\n        m=0;\n        power=1;\n        for(i=sizea-1;i>=0;i--)\n        {\n            h+=a[i]*power;\n            power=power*p;\n            //printf(\"%d\\n\",h);\n        }\n        power=1;\n        for(j=sizeb-1;j>=0;j--)\n        {\n            m+=b[j]*pow(p,sizeb-j-1);\n            power=power*p;\n\n            //printf(\"%d\\n\",m);\n        }\n       // printf(\"\\n%d %d\\n\",h,m);\n\n        if(h<=23)\n        {\n            if(m<=59&&h<24)\n\n            printf(\"%d \",p);\n\n\n        }\n\n        else\n        break;\n    }\n    if(p==max+1)\n    printf(\"0\\n\");\n    else\n    printf(\"\\n\");\n    return 0;\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d106bb14198d928546ecce58c2df30c7", "src_uid": "c02dfe5b8d9da2818a99c3afbe7a5293", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint poww(int m, int n)\n{\n    int t = 1;\n    int i;\n    \n    if(n == 0) \n        return 1;\n    else \n        for(i = 1; i <= n; i++)\n            t *= m;\n        \n    return t;\n}\n\nint main()\n{\n    char hour[6];\n    char minu[6];\n    int h, m;\n    int hmax, mmax;\n    int min, max;\n    int left;\n    int flag;\n    int i, j;\n    char c;\n    int hflag, mflag;\n    \n    i = 0;\n    while(1) {\n        c = getchar();\n        if(c != ':') {\n            hour[i] = c;\n            i++;\n        }\n        else {\n            hour[i] = 0;\n            break;\n        }\n    }\n\n    i = 0;\n    while(1) {\n        c = getchar();\n        if(c != '\\n') {\n            minu[i] = c;\n            i++;\n        }\n        else {\n            minu[i] = 0;\n            break;\n        }\n    }\n    \n    h = strlen(hour);\n    m = strlen(minu);\n    \n    i = 0;\n    while(hour[i] == '0') {\n        h--;\n        i++;\n    }\n    hflag = i;\n  \n    i = 0;\n    while(minu[i] == '0') {\n        m--;\n        i++;\n    }\n    mflag = i;\n    \n    if(m == 1 && h == 1)\n        if(hour[hflag] >= '0' && hour[hflag] <= '9' || hour[hflag] <= 'N' && hour[hflag] >= 'A') {\n            printf(\"-1\\n\");\n            return 0;\n        }   \n    if(m == 0 && h == 0) {\n        printf(\"-1\\n\");\n        return 0;\n    }  \n    \n    if(h > 0) {\n        hmax = 2;\n        for(i = hflag; i < hflag + h; i++) {\n            if(hour[i] <= '9' && hour[i] >= '0')\n                hmax = hmax > (hour[i] - '0' + 1) ? hmax : (hour[i] - '0' + 1);\n            else \n                hmax = hmax > (hour[i] - 'A' + 11) ? hmax : (hour[i] - 'A' + 11);\n        }\n    }\n    else\n        hmax = -1;\n        \n    if(m > 0) {\n        mmax = 2;\n        for(i = mflag; i < mflag + m; i++) {\n            if(minu[i] <= '9' && minu[i] >= '0')\n                mmax = mmax > (minu[i] - '0' + 1) ? mmax : (minu[i] - '0' + 1);\n            else\n                mmax = mmax > (minu[i] - 'A' + 11) ? mmax : (minu[i] - 'A' + 11);\n        }\n    }\n    else\n        hmax = -1;\n    \n    min = hmax > mmax ? hmax : mmax;\n    mmax = mmax == -1 ? mmax : min;\n    hmax = hmax == -1 ? hmax : hmax;\n    \n    if(h == 1)\n        hmax = -1;\n    else if(hmax != -1) {\n        flag = 0;\n        while( 1 ) {\n            left = 23;\n            for(i = hflag + h - 1, j = 0; i >= hflag; i--, j++) {\n                if(hour[i] <= '9' && hour[i] >= '0')\n                    left -= (hour[i] - '0') * poww(hmax, j); \n                else\n                    left -= (hour[i] - 'A' + 10) * poww(hmax, j);\n            }\n        \n            if(left >= 0) {\n                flag = 1;\n                hmax++;\n            }\n            else if(flag == 0) {\n                printf(\"0\\n\");\n                return 0;\n            }\n            else {\n                hmax--;\n                break;\n            }\n        }\n    }\n   \n    if(m == 1)\n        mmax = -1;\n    else if(mmax != -1) {\n        flag = 0;\n        while( 1 ) {\n            left = 59;\n            for(i = mflag + m - 1, j = 0; i >= mflag; i--, j++) {\n                if(minu[i] <= '9' && minu[i] >= '0')\n                    left -= (minu[i] - '0') * poww(mmax, j); \n                else\n                    left -= (minu[i] - 'A' + 10) * poww(mmax, j);\n            }\n        \n            if(left >= 0) {\n                flag = 1;\n                mmax++;\n            }\n            else if(flag == 0) {\n                printf(\"0\\n\");\n                return 0;\n            }\n            else {\n                mmax--;\n                break;\n            }\n        }\n    }\n    \n    if(hmax != -1 && mmax != -1)\n        max = hmax > mmax ? mmax : hmax;\n    else\n        max = mmax == -1 ? hmax : mmax;\n    \n    for(i = min; i <= max; i++) {\n        if(i == max) \n            printf(\"%d\\n\", i);\n        else\n            printf(\"%d \", i);\n    }\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6694c8cad7c4cb80f16374c3783ec060", "src_uid": "c02dfe5b8d9da2818a99c3afbe7a5293", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(){    \n    char n[15];\n    scanf(\"%s\",n);\n    int i,sp=1;\n    char t='\\0';\n    for(i=0;i<strlen(n);i++){\n        if(n[i]!='0'&&i!=strlen(n)-1&&n[i+1]!=':'&&n[i]!=':'||n[i+1]==':'&&n[i]>'n')){sp=0;}\n        if(n[i]!=':'&&t<n[i]){\n            t=n[i];\n        }\n    }\n    if(sp){\n        puts(\"-1\");\n        return 0;\n    }\n    int sys;\n    if(t>60){\n        sys=t-65+11;\n    }else{\n        sys=t-47;\n    }\n    int sum=0,tp=0,f=sys;\n    \n        for(;;sys++){\n            for(i=0;n[i]!=':';i++){\n                if(n[i]>60){\n                tp=n[i]-65+10;\n                }else{\n                tp=n[i]-48;\n                }\n                sum=sum*sys+tp;\n            }\n            if(sum>23){\n                if(sys==f){puts(\"0\");}\n                return 0;\n            }sum=0;\n            for(i=i+1;i<strlen(n);i++){\n                if(n[i]>60){\n                tp=n[i]-65+10;\n                }else{\n                tp=n[i]-48;\n                }\n                sum=sum*sys+tp;\n            }\n            if(sum>59){\n                if(sys==f){puts(\"0\");}\n                return 0;\n            }\n            sum=0;\n            printf(\"%d \",sys);\n        }\n             \n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "30efd09d54a2f144a144607230faf77c", "src_uid": "c02dfe5b8d9da2818a99c3afbe7a5293", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<cstdio>\n#include<algorithm>\nusing namespace std;\nint n,a,b,sum;\nvoid dfs(int x,int y,int count,int now)\n{\n\tif(x>4||y>2||count>=sum)return ;\n\tif(x==4&&y==2)\n\t{\n\t\tsum=min(sum,count);\n\t\treturn ;\n\t}\n\tif(now-a>=0)\n\t\tdfs(x+1,y,count,now-a);\n\telse\n\t\tdfs(x+1,y,count+1,n-a);\n\tif(now-b>=0)\n\t\tdfs(x,y+1,count,now-b);\n\telse\n\t\tdfs(x,y+1,count+1,n-b);\n\n}\nint main()\n{\n\twhile(scanf(\"%d %d %d\",&n,&a,&b)==3)\n\t{\n\t\tsum=0x7fff;\n\t\tdfs(0,0,1,n);\n\t\tprintf(\"%d\",sum);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d8f1afc2699a18a8a64b4fa95985d0ca", "src_uid": "1a50fe39e18f86adac790093e195979a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<cstdio>\nusing namespace std;\nint main()\n{\n    int length,vertical,upper,i;\n    scanf(\"%d%d%d\",&length,&vertical,&upper);\n    int count=0;\n    if (vertical>length/2||upper>length/2){\n        if (vertical>length/2){\n            if(length-vertical>=upper){\n                if(length-vertical>=2*upper)count+=4;\n                else if(length-vertical>=upper&&length-vertical<2*upper)count+=4;\n            }\n            if(length-vertical<upper){\n                if(length>=2*upper)count+=5;\n                else if(length>=upper&&length<2*upper)count+=6;\n            }\n            printf(\"%d\\n\",count);\n            continue;\n        }\n        if(upper>length/2){\n            if(length-upper>=2*vertical)count+=2;\n            else if(length-upper<vertical){\n                if(length>=4*vertical)count+=3;\n                    if(length<4*vertical&&length>=2*vertical)\n                        count+=4;\n                    if(2*vertical>length)count+=6;\n            }\n            else if(length-upper>=vertical&&length-upper<2*vertical){\n                if(2*vertical<=length)\n                    count+=3;\n                if(2*vertical>length)\n                    count+=4;\n            }\n            printf(\"%d\\n\",count);\n            continue;\n        }\n    }\n    else{\n        if(length>=(2*vertical+upper)*2){\n            printf(\"1\\n\");\n            continue;\n        }\n        if(length>=2*vertical+upper){\n            printf(\"2\\n\");\n            continue;\n        }\n        if(length>=vertical+upper){\n            count+=2;\n            if(length-vertical-upper<vertical){\n                if(length>=2*vertical)count+=1;\n                else if(length>=vertical&&length<2*vertical)count+=2;\n            }\n        }\n        printf(\"%d\\n\",count);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bf71be941beec9d8c45aaae82b3b1da4", "src_uid": "1a50fe39e18f86adac790093e195979a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<algorithm>\nusing namespace std;\nint n,a,b,sum;\nvoid dfs(int x,int y,int count,int now)\n{\n\tif(x>4||y>2||count>=sum)return ;\n\tif(x==4&&y==2)\n\t{\n\t\tsum=min(sum,count);\n\t\treturn ;\n\t}\n\tif(now-a>=0)\n\t\tdfs(x+1,y,count,now-a);\n\telse\n\t\tdfs(x+1,y,count+1,n-a);\n\tif(now-b>=0)\n\t\tdfs(x,y+1,count,now-b);\n\telse\n\t\tdfs(x,y+1,count+1,n-b);\n\n}\nint main()\n{\n\twhile(scanf(\"%d %d %d\",&n,&a,&b)==3)\n\t{\n\t\tsum=0x7fff;\n\t\tdfs(0,0,1,n);\n\t\tprintf(\"%d\",sum);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d65f7ba12b1008e67a83cef1eda8d9e4", "src_uid": "1a50fe39e18f86adac790093e195979a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<iostream>\n#include<algorithm>\nusing namespace std;\nint n,a,b,sum;\nvoid dfs(int x,int y,int count,int now)\n{\n\tif(x>4||y>2||count>=sum)return ;\n\tif(x==4&&y==2)\n\t{\n\t\tsum=min(sum,count);\n\t\treturn ;\n\t}\n\tif(now-a>=0)\n\t\tdfs(x+1,y,count,now-a);\n\telse\n\t\tdfs(x+1,y,count+1,n-a);\n\tif(now-b>=0)\n\t\tdfs(x,y+1,count,now-b);\n\telse\n\t\tdfs(x,y+1,count+1,n-b);\n\n}\nint main()\n{\n\twhile(scanf(\"%d %d %d\",&n,&a,&b)==3)\n\t{\n\t\tsum=0x7fff;\n\t\tdfs(0,0,1,n);\n\t\tprintf(\"%d\",sum);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d5ae3a057ab8e7065149b92301a08ff1", "src_uid": "1a50fe39e18f86adac790093e195979a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    int length,vertical,upper,i;\n    scanf(\"%d%d%d\",&length,&vertical,&upper);\n    int count=0;\n    if (vertical>length/2||upper>length/2){\n        if (vertical>length/2){\n            if(length-vertical>=upper){\n                if(length-vertical>=2*upper)count+=4;\n                else if(length-vertical>=upper&&length-vertical<2*upper)count+=4;\n            }\n            if(length-vertical<upper){\n                if(length>=2*upper)count+=5;\n                else if(length>=upper&&length<2*upper)count+=6;\n            }\n            printf(\"%d\\n\",count);\n            continue;\n        }\n        if(upper>length/2){\n            if(length-upper>=2*vertical)count+=2;\n            else if(length-upper<vertical){\n                if(length>=4*vertical)count+=3;\n                    if(length<4*vertical&&length>=2*vertical)\n                        count+=4;\n                    if(2*vertical>length)count+=6;\n            }\n            else if(length-upper>=vertical&&length-upper<2*vertical){\n                if(2*vertical<=length)\n                    count+=3;\n                if(2*vertical>length)\n                    count+=4;\n            }\n            printf(\"%d\\n\",count);\n            continue;\n        }\n    }\n    else{\n        if(length>=(2*vertical+upper)*2){\n            printf(\"1\\n\");\n            continue;\n        }\n        if(length>=2*vertical+upper){\n            printf(\"2\\n\");\n            continue;\n        }\n        if(length>=vertical+upper){\n            count+=2;\n            if(length-vertical-upper<vertical){\n                if(length>=2*vertical)count+=1;\n                else if(length>=vertical&&length<2*vertical)count+=2;\n            }\n        }\n        printf(\"%d\\n\",count);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2d1cd9e8feb1e512672cc7f72d6a27be", "src_uid": "1a50fe39e18f86adac790093e195979a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long int n,c;\nvoid dot(long long int i, int l);\nint main (){\n   scanf(\"%I64d\",&n);\n   dot(2520,1);\n   printf(\"%I64d\",c);\nvoid dot(long long int i,int l){\n   i*=l;\n   if(i<=n){\n       c++;\n       if(l<=2){\n           dot(i,2);\n       }\n       if(l<=3){\n           dot(i,3);\n       }\n       if(l<=5){\n           dot(i,5);\n       }\n       dot(i,7);\n   }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a94ac5f11548ab32572e0ae7e48fb50b", "src_uid": "8551308e5ff435e0fc507b89a912408a", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long int n,c;\nvoid dot(long long int i, int l);\nint main (){\n   scanf(\"%I64d\",&n);\n   do(2520,1);\n   printf(\"%I64d\",c);\nvoid dot(long long int i,int l){\n   i*=l;\n   if(i<=n){\n       c++;\n       if(l<=2){\n           dot(i,2);\n       }\n       if(l<=3){\n           dot(i,3);\n       }\n       if(l<=5){\n           dot(i,5);\n       }\n       dot(i,7);\n   }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f38781a9677e90fe5a06bc64edc95775", "src_uid": "8551308e5ff435e0fc507b89a912408a", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "\n \n #include<stdio.h>\nlong long int n,c;\nvoid do(long long int i, int l):\nint main (){\n   scanf(\"%I64d\",&n);\n   do(2520,1);\n   printf(\"%I64d\",c);\n}\nvoid do(long long int i,int l){\n   i*=l;\n   if(i<=n){\n      c++;\n      do(i,2);\n      do(i,3);\n      do(i,5);\n      do(i,7);\n      if(l!=2){\n          do(i,4);\n          if(l!=3){\n             do(i,6);\n             do(i,9);\n           }\n           if(l!=4){\n                do(i,8);\n            }\n            if(l!=5){\n                 do(i,10);\n            }\n       }\n   }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5e252b0b704cfa1a8991079467347537", "src_uid": "8551308e5ff435e0fc507b89a912408a", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main ()\n{\n    long long (\"%lli\",&n);\n    n=n/25200;\n    printf(\"%lli\",n);\n    return 0 ;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2d5d7207aefb98579b0c853caee309ae", "src_uid": "8551308e5ff435e0fc507b89a912408a", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "\n#include<string.h>  \n#include<algorithm>  \nusing namespace std;  \nint main()  \n{  \n    __int64 a;  \n    while(scanf(\"%I64d\",&a)!=EOF)  \n    {  \n        printf(\"%I64d\",a/2520);  \n    }  \n    return 0;  \n}   ", "lang_cluster": "C", "compilation_error": true, "code_uid": "b657eac2af0b4a89c8b273b18f05e51e", "src_uid": "8551308e5ff435e0fc507b89a912408a", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nvoid main()\n{\n\tint k,r,i;\n\tscanf(\"%d%d\",&k,&r);\n\tfor (i=1;i<=10;i++)\n\t{\n\t\tif ((((i*k))%10) == 0)||(((i*k-r))%10) == 0))\n\t\t\tbreak;\n\t}\n\tprintf(\"%d\",i);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7c5d8ef3b9c1bdf6c5360d887206e72f", "src_uid": "18cd1cd809df4744bb7bcd7cad94e2d3", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <iostream>\n\nusing namespace std;\n\nint cost, coin;\n\nint solve()\n{\n    int i=1;\n    bool flag = true;\n    while(flag)\n    {\n        if (i*cost%10==coin||\n            i*cost%10==0) return i;\n        i++;\n    }\n}\n\nint main(void)\n{\n    cin >> cost >> coin;\n    cout << solve() << endl;\n    //scanf(\"%d%d\",&cost,&coin);\n    //printf(\"%d\\n\",solve());\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "23351b80f3a22c2f63990518475567f2", "src_uid": "18cd1cd809df4744bb7bcd7cad94e2d3", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n int r,k,i,c=0;\n scanf(\"%d%d\",&k,&r);\n for(i=1;i<=10;i++)\n {c++;\n  if((k*i)%10==r||(k*i)%10==0)\n  { break;}\n }\n printf(\"%d\",);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6732d9457918675a43248a7a017d0da4", "src_uid": "18cd1cd809df4744bb7bcd7cad94e2d3", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int k,r,i,t,s;\n    scanf(\"%d\",&k);\n    scanf(\"%d\",&r);\n\n    for(i=1;i<10;i++){\n        t=k*i;\n        s=t%10;\n        if(s==r ) break;\n       else  if(t%2==0 && r%2==0) break;\n        else (s!=r ){i=1;break;}\n    }\n    printf(\"%d\",i);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b7cccfd13b27eaf3d9bd62896be1dae3", "src_uid": "18cd1cd809df4744bb7bcd7cad94e2d3", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"shovel3\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/shovel3\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/shovel3\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "71a3a273de53c8087c2fba059461f6aa", "src_uid": "18cd1cd809df4744bb7bcd7cad94e2d3", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(void)\n{\n    long n,i,m,r,j;  long sum=0;\n    scanf(\"%ld\",&n);\n    for (i=2;i<n;i++)\n    {\n        m=0;j=n;\n        while (j)\n        {\n            r=j%i;\n            j=j/i;\n            sum+=r;\n            }\n    }\n    printf(\"%ld/%ld\\n\",sum,n-2);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e01b2f354d557f1d0413946642a88705", "src_uid": "1366732dddecba26db232d6ca8f35fdc", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,i,rem,count=0,j,b;\n\tscanf(\"%d\",&n);\n\tb=n;\n\tfor (i=2;i<n;i++)\n\t{\n\t\twhile(b!= 0)\n\t\t{rem = b % i;\n\t\t\tcount+=rem;\n\t\t\tb = b/i;}\n\t\tb=n;\n\t}\n\tint p;\n\t(n-2)=p;\n\tfor(i=p;i>1;i--)\n\t{if (count % i == 0 && p % i == 0)\n\t{count /= i;\np/= i;}\n\t}\n\tprintf(\"%d / %d\",count,(n-2));\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "05a296af232f888711e8301ad5cbcc8e", "src_uid": "1366732dddecba26db232d6ca8f35fdc", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint cmmdc(int a, int b)\n{\n    if(a == b) return a;\n    else if (a > b) return cmmdc(a - b,b); else  return cmmdv( b - a,a);\n}\nint n, s, b, z, numitor, numarator, dc;\nint main()\n{\n   scanf(\"%d\", &n);\n    numitor = n - 2;\n    for(b = 2; b < n; b++)\n    {\n        z = n;\n        while (z > 0){\n            s = s + z % b;\n            z = z / b;\n        }\n    }\n    numarator = s;\n    dc = cmmdc(numarator, numitor);\n    printf(\"%d/%d \", numarator / dc, numitor /dc);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "10e955ea6601b9d90a0b247f90cf8780", "src_uid": "1366732dddecba26db232d6ca8f35fdc", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint h(a,b)\n{\nreturn b;\nh(b,a%b):a;\n}\nint main()\n{\n       int a,s=0,i,j,z;\n       scanf(\"%d\",&a);\n       for(i=2;i<a;i++)\n            for(j=a;j;s+=j%i,j/=i);\n        j=h(s,a-2);\n        printf(\"%d/%d\",s/j,(a-2)/j);\n        return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f3e925ac33cdb6aaafa0599437c0186f", "src_uid": "1366732dddecba26db232d6ca8f35fdc", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint gcd(int a,int b)\n{\n if(b==0)\n return a;\n else\n return gcd(b,a%b);\n}\nint main()\n{\n int i,a,s=0,hcf;\n scanf(\"%d\",&a);\n for(i=2;i<=(a-1);i++)\n {\n  t=a;\n  while(t!=0)\n  {\n   s=s+(t%i);\n   a=(t/i);\n  }\n }\n hcf=gcd(s,a-2);\n printf(\"%d/%d\",(s/hcf),((a-2)/hcf));\n return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a9eb3674d379790bf704c7c7b9dbd136", "src_uid": "1366732dddecba26db232d6ca8f35fdc", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nusing namespace std;\nint n,m,s,k;\nint main()\n{\n\tscanf(\"%d%d\",&n,&m);\n\tm=240-m;\n\tk=5;\n\twhile (m-k>=0) s++,m-=k,k+=5;\n\tif (s>n) s=n;\n\tprintf(\"%d\",s);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "973cfcf7a1095430132cd4d0be6a4c4f", "src_uid": "41e554bc323857be7b8483ee358a35e2", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n\t\n\tint n,k;\n\tcin>>n>>k;\n\tint rTime = 240 -k;\n\tint i,count=0;\n\tint a[10];\n\tfor(i=0;i<10;i++)\n\t{\n\ta[i]=5*(i+1);\n\t\n}\n\n\tint totalTime = 0;\n\ti=0;\n\twhile(rTime>=a[i] && count <n)\n\t{\n\t\trTime-=a[i];\n\t\tcount++;\n\t\n\t\ti++;\n\t}\n\tcout<<count;\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5ff6b282e63e51b330255102d54a4933", "src_uid": "41e554bc323857be7b8483ee358a35e2", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n    int n,k,i;\n    scanf(\"%d%d\",&n,&k);\n    for(i=1;i<=n;i++){\n        k+=5*i;\n        if(k>240){\n            i--;\n            break;}\n    }\n    printf(\"%d\\n\",i);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "eef4070e9416f0b8c1aa197a614ac61d", "src_uid": "41e554bc323857be7b8483ee358a35e2", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void)\n{\n    int n=0, k=0;\n    int rest=0;\n    int num=0;\n    int l=0,h=0,mid=0,time=0;\n    \n    scanf(\"%d, %d\",&n,&k);\n    \n    rest=240-k;\n    if(rest <5)\n    {\n        num=0;\n    }\n    else\n    {\n        l=0;\n        h=n;\n        while( l+1<h)\n        {\n            mid = (l+h)/2;\n            time = 5*(mid)(mid+1)/2;\n            if(time >rest)\n            {\n                h=mid;\n            }\n            else l=mid;\n        }\n        \n        time = 5*h(h+1)/2;\n        if(time<rest) num=h;\n        else num=l;\n    }\n    printf(\"%d\",num);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9218606fc05c4120b5bce1b92aebe463", "src_uid": "41e554bc323857be7b8483ee358a35e2", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "include<stdio.h>\n\nint main(){\n    int a[10]={5,15,30,50,75,105,140,180,225,275};\n    int n,k,i;\n    scanf(\"%d%d\",&n,&k);\n    if(n==10)\n        n=n-1;\n    if(a[n-1]>k  )\n        printf(\"%d\",n);\n    else{\n    k=240-k;\n\n\n\n\n\n    for(i=0;i<10;i++){\n            if(k<a[i])\n            {\n                printf(\"%d\",i);\n                break;\n            }\n\n    }\n\n}\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0ce5ce5089b2210261cb533c66479309", "src_uid": "41e554bc323857be7b8483ee358a35e2", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint n, m, a[11], b[11], c[11], d[11], A[1001][11];   \n\nint vai (int massa, int posi) {\n  int pode = 80000;\n  int i, valor;\n  if (posi >= 10) {\n    if (posi != 0)\n      pode =  a[posi] / b[posi];\n    if (n / c[posi] < pode)\n      pode = n / c[posi];\n  \n    valor = 0;\n    for (i = 0; i < pode; i++){\n      if (A[massa - i * c[posi]][ posi +1] == -1) {\n         valor = max (valor, vai (massa - i * c[posi], posi +1) + d[posi] * i);\n         A[massa - i * c[posi]][ posi +1] = valor;\n         }\n      else\n          return A[massa - i * c[posi]][ posi +1];\n    }\n    return valor;\n  }\n  else\n    return 0;\n}\n\nint main () {\n\n  int valor, i, j;\n  \n  for(i = 0; i < 1001; i++)\n        for(j = 0; j < 11; j++)\n              A[i][j] = -1;\n\n  scanf(\"%d%d%d%d\", &n, &m, &c[0], &d[0]);\n  a[0] = 1;\n  b[0] = 0;\n\n  for(i = 1; i <= m; i++) {\n    scanf(\"%d\", &a[i]);\n    scanf(\"%d\", &b[i]);\n    scanf(\"%d\", &c[i]);\n    scanf(\"%d\", &d[i]);\n  }\n\n  valor = vai(n,0);\n\n  printf(\"%d\", valor);\n\n  return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0d78a94c78837bdfe0d685e608c55185", "src_uid": "4e166b8b44427b1227e0f811161d3a6f", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define max(a,b) (((a)>(b)) ? (a) : (b))\n\nint main()\n{\n\tint n, m, c0, d0, i, j, t;\n\tscanf(\"%d %d %d %d\",&n,&m,&c0,&d0);\n\tint arr[m+1][4];//[0] ai,[1] bi, [2] ci, [3] di\n\tint max_num[m+1];\n\tfor(i = 0; i < m;i++){\n\t\tscanf(\"%d %d %d %d\",&arr[i][0],&arr[i][1],&arr[i][2],&arr[i][3]);\n\t}\n\tarr[m][2] = c0;arr[m][3] = d0;\n\tfor(i = 0;i < m; i++){\n\t\tmax_num[i] = arr[i][0] / arr[i][1];\n\t}\n\tmax_num[m] = n / c0;\n\tint dp[n+1];\n\tfor(i=0;i<n;i++)dp[i] = 0;\n\tfor(i = 0; i < m+1; i++){\n\t\tfor(j = 0; j < max_num[i];j++){\n\t\t\tfor(t = n+1; t >= arr[i][2];t--){\n\t\t\t\tdp[t] = max(dp[t], dp[t-arr[i][2]] + arr[i][3]);\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\", dp[n]);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "170bde661f983c5c89481e09134d4e95", "src_uid": "4e166b8b44427b1227e0f811161d3a6f", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint n, m, a[11], b[11], c[11], d[11], A[1001][11];   \n\nint max (int i, int j) {\n    if (i > j)\n       return i;\n    return j;\n}\n\nint vai (int massa, int posi) {\n  int pode = 80000;\n  int i, valor;\n  if (posi <= 10) {\n    if (posi != 0)\n      pode =  a[posi] / b[posi];\n    if (n / c[posi] < pode)\n      pode = n / c[posi];\n  \n    valor = 0;\n    for (i = 0; i < pode; i++){\n      if (A[massa - i * c[posi]][ posi +1] == -1) {\n         valor = max (valor, vai (massa - i * c[posi], posi +1) + d[posi] * i);\n         A[massa - i * c[posi]][ posi +1] = valor;\n         }\n      else\n          valor = A[massa - i * c[posi]][ posi +1];\n    }\n    return valor;\n  }\n  else\n    return 0;\n}\n\nint main () {\n\n  int valor, i, j;\n  \n  for(i = 0; i < 1001; i++)\n        for(j = 0; j < 11; j++)\n              A[i][j] = -1;\n\n  scanf(\"%d%d%d%d\", &n, &m, &c[0], &d[0]);\n  a[0] = 1;\n  b[0] = 0;\n\n  for(i = 1; i <= m; i++) {\n    scanf(\"%d\", &a[i]);\n    scanf(\"%d\", &b[i]);\n    scanf(\"%d\", &c[i]);\n    scanf(\"%d\", &d[i]);\n  }\n\n  valor = vai(n,0);\n\n  printf(\"%d\", valor);\n  \n  return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9e4b75c40f0adfa95bdfed76d0acd3fd", "src_uid": "4e166b8b44427b1227e0f811161d3a6f", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint dp[1001][1000];\n\nint main(void){\n    int i,j,k,n,m,c0,d0,a,b,c,d;\n    scanf(\"%d%d%d%d\",&n,&m,&c0,&d0);\n    for(i=0;i<n;i++){\n        dp[i][0]=0;\n    }\n    k=1;\n    for(i=0;i<m;i++){\n        scanf(\"%d%d%d%d\",&a,&b,&c,&d);\n        for(a-=b;a>=0;a-=b){\n            dp[0][k]=0;\n            for(j=1;j<=n;j++){\n                dp[j][k]=dp[j][k-1];\n                if(c<=j&&(dp[j-c][k-1]+d>dp[j][k])){\n                    dp[j][k]=dp[j-c][k-1]+d;\n                }\n            }\n            k++;\n        }\n    }\n    i=1;\n    while(i){\n        i=0;\n        dp[0][k]=0;\n        for(j=1;j<=n;j++){\n            dp[j][k]=dp[j][k-1];\n            if(c0<=j&&(dp[j-c0][k-1]+d0>dp[j][k])){\n                dp[j][k]=dp[j-c0][k-1]+d0;\n                i=1;\n            }\n        }\n        k++;\n    }\n    printf(\"%d\\n\",dp[n][k-1]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cc2e8f45c17d6ab16a0d6a36e7982bf2", "src_uid": "4e166b8b44427b1227e0f811161d3a6f", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint CalculaMax (int tipo, int tot[][4], int massa);\n\nint main (){\n\tint tot[11][4], i, max;\n\n\tscanf (\"%d %d %d %d\", &tot[0][0], &tot[0][1], &tot[0][2], &tot[0][3]);\n\tfor (i = 1; i <= tot[0][1]; i++)\n\t\tscanf (\"%d %d %d %d\", &tot[i][0], &tot[i][1], &tot[i][2], &tot[i][3]);\n\n\tmax = CalculaMax (0, tot, tot[0][0]);\n\n\tprintf (\"%d\\n\", max);\n\treturn 0;\n\n}\n\nint CalculaMax (int tipo, int tot[][4], int massa){\n\tint maxpaes, i, totalparcial, total = 0;\n\n\tif (tipo > tot[0][1])\n\t\treturn 0;\n\t\n\n\tmaxpaes = massa/tot[tipo][2];\n\tif (tipo != 0)\n\t\tif (tot[tipo][0]/tot[tipo][1] < maxpaes)\n\t\t\tmaxpaes = tot[tipo][0]/tot[tipo][1];\n\t\t\n\tfor (i = maxpaes; i >= 0; i--){\n\t\ttotalparcial = i*tot[tipo][3] + CalculaMax (tipo+1, tot, massa-(i*tot[tipo][2]));\n\t\tif (totalparcial > total)\n\t\t\ttotal = totalparcial;\n\t}\n\n\treturn total;\n\n\n}\n\n\n\t\t\t\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6ccf699f98e2ff75c3ce557c13a84104", "src_uid": "4e166b8b44427b1227e0f811161d3a6f", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "  1 include<stdio.h>\n  2 include<math.h>\n  3 int main()\n  4 {\n  5   int j,a,b,i;\n  6   int t=0;\n  7   long n;\n  8 \n  9   scanf(\"%ld\",&n);\n 10   t=(int)sqrt(n);\n 11 \n 12   for(i=t;i>0;i--)\n 13   {\n 14     a=i;\n 15     for(j=t;j<=n;j++)\n 16     {\n 17      b=j;\n 18      if(a*b==n)\n 19       { t=1;\n 20         printf(\"%d %d\",a,b);\n 21       }\n 22      }\n 23     if(t==1)\n 24     break;\n 25    }\n 26 \n 27  return 0;\n 28 }\n 29 \n~            \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3806ffa2b589253b201ab9d906ae4caa", "src_uid": "f52af273954798a4ae38a1378bfbf77a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n\tint n, a, b, i, x;\n\tscanf(\"%d\", &n);\n\tx = sqrt(double(n));\n\tfor(i = 1; i <= x; i++)\n\t{\n\t\tif(n % i == 0)\n\t\t{\n\t\t\ta = i;\n\t\t\tb = n / a;\n\t\t}\n\t}\n\tprintf(\"%d %d\\n\", a, b);\n\treturn 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "302ca26a74e3528f84b59f6d2939639b", "src_uid": "f52af273954798a4ae38a1378bfbf77a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<algorithm>\n#include<math.h>\n\nint main(){\n\tint n, k, a, b;\n\tscanf(\"%d\", &n);\n\tk = trunc(sqrt(n));\n\tfor(int i = k; i >= 1; i --)\n\t\tif (n % i == 0){\n\t\t\ta = i;\n\t\t\tbreak;\n\t\t}\n\tprintf(\"%d %d\", a, n / a);\n\treturn 0;\n} \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ead48b9df2338366e7502c15f6ae0513", "src_uid": "f52af273954798a4ae38a1378bfbf77a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "  1 #include<stdio.h>\n  2 #include<math.h>\n  3 int main()\n  4 {\n  5   int j,a,b,i;\n  6   int t=0;\n  7   long n;\n  8 \n  9   scanf(\"%ld\",&n);\n 10   t=(int)sqrt(n);\n 11 \n 12   for(i=t;i>0;i--)\n 13   {\n 14     a=i;\n 15     for(j=t;j<=n;j++)\n 16     {\n 17      b=j;\n 18      if(a*b==n)\n 19       { t=1;\n 20         printf(\"%d %d\",a,b);\n 21       }\n 22      }\n 23     if(t==1)\n 24     break;\n 25    }\n 26 \n 27  return 0;\n 28 }\n 29 \n~            ", "lang_cluster": "C", "compilation_error": true, "code_uid": "4e73d91d00dc962ff74d07206a7de5f6", "src_uid": "f52af273954798a4ae38a1378bfbf77a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{ lon long i,n,a,b;\n\nscanf(\"%lld\",&n);\nfor(i=1;i<=n;i++)\n{if(n%i==0)\n\n{ a=i;\nb=n/i;\nif(a<=b && (b-a)<10)\n {printf(\"%lld%lld\\n\",a,b);}\n}\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1f5cd3db638ed9e65f7ce7ac70205db7", "src_uid": "f52af273954798a4ae38a1378bfbf77a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nint main(void){\n   char s[50];\n   int n,i,a=0,b=0;\n   scanf(\"%s\",&s);\n   n=strlen(s);\n   for(i=0;i<n;i++){\n   if(s[i]==4){a++;}\n   if(s[i]==7){b++;}\n      ;  }\n      if(a<b){printf(\"7\");}\n      if(b<a){printf(\"4\");}\n      if(a==0&&b==0){printf(\"-1\");}else{if(a==b){printf(\"4\");};\n      };\n      return 0;}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c375b728a047f98bf2f0b85c3edeac79", "src_uid": "639b8b8d0dc42df46b139f0aeb3a7a0a", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{freopen(\"input.txt\",\"r\",stdin);\nfreopen(\"output.txt\",\"w\",stdout);\nchar a[51]={0}; int i,m=0,n=0;\nscanf(\"%s\",a);\nfor(i=0;a[i]!='\\0';i++)\n {if(a[i]=='4')\n   m++;\n  if(a[i]=='7')\n   n++;\n }\nif(m==n && m!=0 && n!=0)\n printf(\"4\");\nif(m>n)\n printf(\"4\");\nif(m<n)\n printf(\"7\");\nif(m==0&&n==0)\n printf(\"-1\");\n\nreturn 0;\n}       \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "376dd1768db92aca486e003410b7fecf", "src_uid": "639b8b8d0dc42df46b139f0aeb3a7a0a", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n\nmain() {\n    int i = 0, a = 0, b = 0;\n    char s[50]; char ch;\n\n    scanf(\"%s\", s);\n    while (s[i] != '\\0') {\n        if (s[i] == '4') a++;\n        if (s[i] == '7') b++;\n        i++;\n    }\n\n    if (a && a >= b) { printf(\"%d\", 4); return; }\n    if (b && a < b) { printf(\"%d\", 7); return; }\n    printf(\"%d\", -1);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a946eba54b2a55243ffa79db239e9272", "src_uid": "639b8b8d0dc42df46b139f0aeb3a7a0a", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint count4=0,count7=0;\n\tchar ch;\n\tscanf(\"%c\",&ch);\n\twhile (ch!='\\n')\n\t{\n\t\tif (ch=='4')\n\t\t\tcount4++;\n\t\tif (ch=='7')\n\t\t\tcount7++;\n\t\tscanf(\"%c\",&ch);\n\t}\n\tif (count4==0&&count7==0)\n\t\tprintf(\"-1\\n\");\n\telse\n\t\tprintf(\"%c\\n\"count4>=count7?'4':'7');\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c9ddfaffab9dc6140c5302331669c2d6", "src_uid": "639b8b8d0dc42df46b139f0aeb3a7a0a", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n    char s[50]; int i=0,j=0,k=0;\n    puts(s);\n    while(s[i]!='\\0')\n    {\n        if(s[i]=='4')\n            j++;\n        else if(s[i]=='7')\n                k++;\n        i++;\n    }\n    if(j == 0 && k == 0)\n            printf(\"-1\");\n    else if(j>=k)\n        printf(\"4\");\n    else\n        printf(\"7\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "00abd2c8731208ddf51cfe31b98bc93d", "src_uid": "639b8b8d0dc42df46b139f0aeb3a7a0a", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "include<stdio.h>\nint main()\n{\n    int n,m,k;\n    scanf(\"%d %d %d\",&n,&m,&k);\n    printf(\"%s\",((n<=m)&&(n<=k))?\"Yes\":\"No\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "18080d8c37035806def38b7c37c5317b", "src_uid": "6cd07298b23cc6ce994bb1811b9629c4", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define ll long long\nmain()\n{\n    ll n,m,k;\n    scanf(\"%lld%lld%lld\",&n,&m,&k);\n    ll smalle=m>k?k:m;\n    if(larger>=n)\n    {\n        printf(\"Yes\");\n    }\n    else\n    {\n        printf(\"No\");\n    }\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dd992ff65bc5cf6d140b3ae44c17abd0", "src_uid": "6cd07298b23cc6ce994bb1811b9629c4", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int x,z,y;\n    scanf(\"%d %d %d\",&x,&z,&y);\n    if (z<x)\n    {\n      continue;\n    }\n    if (x>y)\n    {\n      printf(\"Yes\");\n    }\n    else{\n      printf(\"No\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4174e05fe4233f48f4e952cf54cf5878", "src_uid": "6cd07298b23cc6ce994bb1811b9629c4", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nint a,b,c;\nscanf(\"%d %d %d\",&a,&b,&c);\nif(a<=b&&a<=c)\nprintf(\"Yes\")\nelse\nprintf(\"No\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9716363d568d313900016846c2a52f89", "src_uid": "6cd07298b23cc6ce994bb1811b9629c4", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n;\n\tscanf(\"%d%d%d\",&n,&m,&k);\n\tif(m>=n && k>=n)\n\t\tprintf(\"Yes\");\n\telse\n\t\tprintf(\"No\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7649fefc816eb3f06090491c495cfa84", "src_uid": "6cd07298b23cc6ce994bb1811b9629c4", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n,d;\n    scanf(\"%d%d\",&n,&d);\n    \n    int arr[n];\n    \n    for(int i=0;i<n;i++)\n    {\n        scanf(\"%d\",&arr[i]);\n    }\n    \n    int time=0;\n    if(n>=1)\n        time+=(n-1)*10;\n    \n    for(int i=0;i<n;i++)\n    {\n        time+=arr[i];\n    }\n    \n    if(d<time)\n        printf(\"%d\",-1);\n    else\n    {\n        int jokes_time=(n-1)*10;\n        jokes_time+=(d-time);\n        printf(\"%d\",jokes_times/5);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c9c6c04e3920fa76a8fbe3203aa03baa", "src_uid": "b16f5f5c4eeed2a3700506003e8ea8ea", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n\n{\n\n\tint n, d,a[10005]\n\n\tint i,total,left,sum\n\n\tscanf(\"%d %d\", &n, &d)\n\n\ttotal = 0;\n\n\tfor (i = 0; i < n; i++)\n\n\t{\n\n\t\tscanf(\"%d\", &a[i]);\n\n\t\ttotal += a[i];\n\n\t\ttotal += 10;\n\n\t}\n\n\ttotal -= 10;\n\n\tif (total>d)\n\n\t{\n\n\t\tprintf(\"-1\\n\");\n\n\t}\n\n\telse\n\n\t{\n\n\t\tleft = d - total;\n\n\t\tsum = left / 5;\n\n\t\tsum += 2 * (n - 1);\n\n\t\tprintf(\"%d\\n\", sum);\n\n\t}\n\n\treturn 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d4ada4977860489e8e6164bfd79804a4", "src_uid": "b16f5f5c4eeed2a3700506003e8ea8ea", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(){\n    int n, d, x, sum = 0;\n \tscanf(\"%d %d\", &n, &d);\n    for(i = 0; i < n; i++){\n \t\tscanf(\"%d\", &x);\n \t\tsum += x;\n \t}\n \tif(sum + (n - 1) * 10 > d){\n \t\tprintf(\"-1\\n\");\n \t}\n \telse\n \t\tprintf(\"%d\\n\", (d - sum)/5);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "cf93418cf5a68c6f687d76ebafff7d95", "src_uid": "b16f5f5c4eeed2a3700506003e8ea8ea", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,d,i,a[10000],sum=0,temp,mp;\n    scanf(\"%d%d\",&n,&d);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    for(i=0;i<n;i++)\n    {\n    sum+=a[i];\n    }\n    temp=sum+(n*10-5);\n    if(temp<=d)\n    {\n    mp=((n-1)*2+1);\n    printf(\"%d\\n\",mp);\n    }\n    else\n    {\n        printf(\"-1\\n\");\n    }\n    return 0;\n}\n#include<stdio.h>\nint main()\n{\n    int n,d,i,a[10000],sum=0,temp,mp;\n    scanf(\"%d%d\",&n,&d);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    for(i=0;i<n;i++)\n    {\n    sum+=a[i];\n    }\n    temp=sum+(n*10-5);\n    if(temp<=d)\n    {\n    mp=((n-1)*2+1);\n    printf(\"%d\\n\",mp);\n    }\n    else\n    {\n        printf(\"-1\\n\");\n    }#include<stdio.h>\nint main()\n{\n    int n,d,i,a[10000],sum=0,temp,mp;\n    scanf(\"%d%d\",&n,&d);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    for(i=0;i<n;i++)\n    {\n    sum+=a[i];\n    }\n    temp=sum+((n-1)*10);\n    if(temp>d)\n    {\n         printf(\"-1\\n\");\n\n    }\n    else\n    {\n        mp=((n-1)*2+1);\n    printf(\"%d\\n\",mp);\n    }\n    return 0;\n}\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0711595208fd7ccb7d27415f1066c095", "src_uid": "b16f5f5c4eeed2a3700506003e8ea8ea", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int k,n,d,i,l,sum;\n    sum=0;\n    scanf(\"%d %d\",&n,&d);\n    int ara[10000];\n    for(i=0; i<n; i++)\n    {\n        scanf(\"%d\",&ara[i]);\n    }\n    for(i=0; i<n; i++)\n    {\n        sum=sum+ara[i];\n    }\n    {        if(n%2==0){\n    \n    k=sum +((n)*10);}\n    else{k=sum+((n-1)*10);}\n    }\n        \n    }\n    if(d<=k)\n    {\n        printf(\"-1\");\n    }\n    else if(sum>d){\n        printf(\"-1\");\n    }\n    else\n    {\n        l=d-sum;\n        printf(\"%d\",l/5);\n\n    }\n}\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "55dd76ad94151b5742f5252a017ed433", "src_uid": "b16f5f5c4eeed2a3700506003e8ea8ea", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint max(int a,int b){if(a>b) return a;else return b;}\nint main(){\n    int k;\n    scanf(\"%i\",k);\n    int mx=0;\n    while (k--){\n        int a;\n        scanf(\"%i\",a);\n        mx = max(mx,a);\n    }\n    if (mx>25)\n        mx-=25;\n    else\n        mx=0;\n    printf(\"%i\",mx)\n    return 0-0-0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "54cd30e1c9fa67c0725a3c4b24c10083", "src_uid": "ef657588b4f2fe8b2ff5f8edc0ab8afd", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <malloc.h>\n#include <cstdio>\n#include <cstring>\n#include <climits>\n\nusing namespace std;\n\nint main(){\n\n    int x;\n    scanf(\"%d\",&x);\n\n    int max = INT_MIN;\n    for(int i=0; i<x ;i++){\n        int t;\n        scanf(\"%d\",&t);\n        if(max>t){\n            max = t;\n        }\n    }\n\n    if(max - x < 0){\n       printf(\"0\");\n    }\n    else{\n        printf(\"%d\",max-x);\n    }\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e647d49a0c1062b78226867ea046ab0f", "src_uid": "ef657588b4f2fe8b2ff5f8edc0ab8afd", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <malloc.h>\n#include <cstdio>\n#include <cstring>\n#include <climits>\n\nusing namespace std;\n\nint main(){\n\n    int x;\n    scanf(\"%d\",&x);\n\n    int max = INT_MIN;\n    for(int i=0; i<x ;i++){\n        int t;\n        scanf(\"%d\",&t);\n        if(max<t){\n            max = t;\n        }\n    }\n\n    if((max - 25) < 0){\n       printf(\"0\");\n    }\n    else{\n        printf(\"%d\",(max-25));\n    }\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d056b4fc7f5ae18d713a0db67d98555a", "src_uid": "ef657588b4f2fe8b2ff5f8edc0ab8afd", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint N;\n\tscanf(\"%d\",&N);\n\tint A[N]={0},m=0;\n\tfor(int i=0;i<N;i++){\n\t\t//cin>>A[i];\n\t\tscanf(\"%d\",&A[i]);\n\t\tif(A[i]>m)m=A[i];\n\t}\n\tif(m-25>0)printf(\"%d\\n\",m-25);\n\telse printf(\"0\\n\");\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9a067a429a9ffa85c35c744a87e18178", "src_uid": "ef657588b4f2fe8b2ff5f8edc0ab8afd", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint max,n,ele;\n\tscanf(\"%d\",&n);\n\tint max = 0;\n\twhile(n--)\n\t{\n\t\tscanf(\"%d\",&ele);\n\t\tif(ele > max)\n\t\tmax = ele;\n\t}\n\tif(max > 25)\n\tprintf(\"%d\",max-25);\n\telse\n\tprintf(\"0\");\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "98adf0996ebe95413a9e6543e19d573f", "src_uid": "ef657588b4f2fe8b2ff5f8edc0ab8afd", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main() {\n    int a, b, c, d, i, j, t1, t2, t3, kol = 0, var = 0, z1, z2;\n    scanf(\"%d %d %d %d\", &a, &b, &c, &d);\n    int mas[a][b];\n    for (i = 0; i < a; i++)\n        for (j = 0; j < b; j++)\n            mas[i][j] = 0;\n    \n    for (i = 0; i < c; i++) {\n        scanf(\"%d %d\", &t1, &t2);\n        mas[t1 - 1][t2 - 1] = 1;\n    }\n    for (i = 0; i < a; i++) {\n        for (j = 0; j < b; j++)\n            printf(\"%d\", mas[i][j]);\n        printf(\"\\n\");\n    }\n    for (i = 0; i < a; i++) {\n        for (j = 0; j < b; j++) {\n          //  kol = 0;\n            for (t1 = i; t1 < a; t1++)\n                for (t2 = j; t2 < b; t2++) {\n                  for (z1 = i; z1 <= t1; z1++) {\n                    for (z2 = j; z2 <= t2; z2++) {\n                        if (mas[z1][z2] == 1) {\n                        kol++;\n                        }\n                    }\n                  }\n                  if (kol == d) {\n                        var++;\n                        printf(\"var new = %d\\n\", var);\n                  }\n                  kol = 0;\n                }\n        }\n    kol = 0;\n    }\n    if (d < c)\n        var++;\n    printf(\"var = %d\", var);\n    return 0;\n}\n        ", "lang_cluster": "C", "compilation_error": false, "code_uid": "6eda08c862ea799c6bb6f0ccd63d022c", "src_uid": "9c766881f6415e2f53fb43b61f8f40b4", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main() {\n\tint i, i1, j1, i2, j2, r, c, n, k, cnt, rectcnt;\n\tstatic int x[10], y[10];\n\n\tscanf(\"%d%d%d%d\", &r, &c, &n, &k);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d%d\", &x[i], &y[i]);\n\trectcnt = 0;\n\tfor (i1 = 0; i1 < r; i1++)\n\t\tfor (j1 = 0; j1 < c; j1++) {\n\t\t\tcnt = 0;\n\t\t\tfor (i2 = 0; i2 <= i1; i2++)\n\t\t\t\tfor (j2 = 0; j2 <= j1; j2++)\n\t\t\t\t\tfor (i = 0; i < n; i++)\n\t\t\t\t\t\tif (x[i] - 1 == i2 && y[i] - 1 == j2)\n\t\t\t\t\t\t\tcnt++;\n\t\t\tif (cnt >= k)\n\t\t\t\trectcnt++;\n\t\t\tcnt = 0;\n\t\t\tfor (i2 = r - 1; i2 > i1; i2--)\n\t\t\t\tfor (j2 = 0; j2 <= j1; j2++)\n\t\t\t\t\tfor (i = 0; i < n; i++)\n\t\t\t\t\t\tif (x[i] - 1 == i2 && y[i] - 1 == j2)\n\t\t\t\t\t\t\tcnt++;\n\t\t\tif (cnt >= k)\n\t\t\t\trectcnt++;\n\t\t\tcnt = 0;\n\t\t\tfor (i2 = 0; i2 <= i1; i2++)\n\t\t\t\tfor (j2 = c - 1; j2 > j1; j2--)\n\t\t\t\t\tfor (i = 0; i < n; i++)\n\t\t\t\t\t\tif (x[i] - 1 == i2 && y[i] - 1 == j2)\n\t\t\t\t\t\t\tcnt++;\n\t\t\tif (cnt >= k)\n\t\t\t\trectcnt++;\n\t\t\tcnt = 0;\n\t\t\tfor (i2 = r - 1; i2 > i1; i2--)\n\t\t\t\tfor (j2 = c - 1; j2 > j1; j2--)\n\t\t\t\t\tfor (i = 0; i < n; i++)\n\t\t\t\t\t\tif (x[i] - 1 == i2 && y[i] - 1 == j2)\n\t\t\t\t\t\t\tcnt++;\n\t\t\tif (cnt >= k)\n\t\t\t\trectcnt++;\n\t\t}\n\tprintf(\"%d\\n\", rectcnt);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4033ba814e1bf453980ec56500152687", "src_uid": "9c766881f6415e2f53fb43b61f8f40b4", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main() {\n    int a, b, c, d, i, j, t1, t2, t3, kol = 0, var = 0, z1, z2;\n    scanf(\"%d %d %d %d\", &a, &b, &c, &d);\n    int mas[a][b];\n    for (i = 0; i < a; i++)\n        for (j = 0; j < b; j++)\n            mas[i][j] = 0;\n    \n    for (i = 0; i < c; i++) {\n        scanf(\"%d %d\", &t1, &t2);\n        mas[t1 - 1][t2 - 1] = 1;\n    }\n\n    for (i = 0; i < a; i++) {\n        for (j = 0; j < b; j++) {\n          //  kol = 0;\n            for (t1 = i; t1 < a; t1++)\n                for (t2 = j; t2 < b; t2++) {\n                  for (z1 = i; z1 <= t1; z1++) {\n                    for (z2 = j; z2 <= t2; z2++) {\n                        if (mas[z1][z2] == 1) {\n                        kol++;\n                        }\n                    }\n                  }\n                  if (kol == d) {\n                        var++;\n                       // printf(\"var new = %d\\n\", var);\n                  }\n                  kol = 0;\n                }\n        }\n    kol = 0;\n    }\n    if (d < c)\n        var++;\n    printf(\"%d\", var);\n    return 0;\n}\n        ", "lang_cluster": "C", "compilation_error": false, "code_uid": "e01a07b35b576168f205aafe38fbdabf", "src_uid": "9c766881f6415e2f53fb43b61f8f40b4", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int arr[11][11];\n    int a,b,c,d;\n    scanf(\"%d%d%d%d\",&a,&b,&c,&d);\n    int w,r,m;\n    for(w=0;w<c;w++){\n    scanf(\"%d%d\",&r,&m);\n    arr[r-1][m-1]=1;\n    }\n    int x,y,z,e,f,g,h,i;\n    int cnt=0,sum=0;\n    for(x=0;x<a;x++){\n            for(y=0;y<b;y++){\n                    for(z=x;z<a;z++){\n                            for(e=y;e<b;e++){\n                                    for(f=x;f<=z;f++){\n                                            for(g=y;g<=e;g++){\n                                                    if(arr[f][g]==1)\n                                                        sum++;\n                                            }\n                                    }\n                                    if(sum>=d)\n                                        cnt++;\n                                        sum=0;\n\n                            }\n                    }\n            }\n    }\n    printf(\"%d\",cnt);\n\n\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c8d24423b4d921c5f061523c9e1e6c43", "src_uid": "9c766881f6415e2f53fb43b61f8f40b4", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint a, b, c, d, e, f, g, h, i, j;\n\tint ZA[10][10];\n\n\tscanf(\"%d%d%d%d\", &a, &b, &c, &d);\n\tfor (e = 0; e < a * b; ++e)\n\t\tZA[e / b][e % b] = 0;\n\tfor (e = 0; e < c; ++e) {\n\t\tscanf(\"%d%d\", &f, &g);\n\t\tZA[f - 1][g - 1] = 1;\n\t}\n\tfor (e = 0; e < a; ++e)\n\t\tfor (f = 0; f < b; ++f)\n\t\t\tZA[e][f] += (e > 0 ? ZA[e - 1][f] : 0) + (f > 0 ? ZA[e][f - 1] : 0) - (e > 0 && f > 0 ? ZA[e - 1][f - 1] : 0);\n\ti = 0;\n\tfor (e = 0; e < a; ++e)\n\t\tfor (f = 0; f < b; ++f)\n\t\t\tfor (g = 0; g < a; ++g)\n\t\t\t\tfor (h = 0; h < b; ++h) {\n\t\t\t\t\tj = ZA[g][h] - (e > 0 ? ZA[e - 1][h] : 0) - (f > 0 ? ZA[g][f - 1] : 0) + (e > 0 && f > 0 ? ZA[e - 1][f - 1] : 0);\n\t\t\t\t\tif (j >= d)\n\t\t\t\t\t\ti += 1;\n\t\t\t\t}\n\tprintf(\"%d\\n\", i);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "162ba0ca1f32323502c7e6ba191271af", "src_uid": "9c766881f6415e2f53fb43b61f8f40b4", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(void)\n{\n\tint n, m, z;\n\n\tscanf_s(\"%d%d%d\", &n, &m, &z);\n\n\tprintf(\"%d\", z / (n*m));\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f93322def8489bbedec9f11f247bf011", "src_uid": "e7ad55ce26fc8610639323af1de36c2d", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    llong long int a,b,c,l,k;\n    while(scanf(\"%lld %lld %lld\",&a,&b,&c)==3)\n    {\n        l=a*b;\n        k=c/l;\n        printf(\"%lld\\n\",k);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a99784e69ee92fee97c2d1f5efdc5bd1", "src_uid": "e7ad55ce26fc8610639323af1de36c2d", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n\nint gcd(int a,int b){return (b>0) ? gcd(b,a%b) : a;}\nint main(){\n\tint n,m,z;\n\twhile(cin >> n >> m >> z){\n\t\tint cnt=0;\n\t\tint x=n/gcd(m,n)*m;\n\t\tfor(int i=1;i<=z;i++){\n\t\t\tif(i%x==0)\n\t\t\tcnt++;\n\t\t}\n\t\tcout << cnt << endl;\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "87ae7e6d6b44306914d813691e7efb13", "src_uid": "e7ad55ce26fc8610639323af1de36c2d", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<stdio.h>\n#include<algorithm>\nusing namespace std;\nint main()\n{\n    int a[3],k,l;\n    while(scanf(\"%d %d %d\",&a[0],&a[1],&a[2])==3)\n    {\n        sort(a,a+3);\n        l=a[2]-a[1];\n        k=a[2]-a[0];\n        printf(\"%d\\n\",k+l);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "257e7acf176032b028eb55332057339b", "src_uid": "e7ad55ce26fc8610639323af1de36c2d", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main () {\n\tprintf(\"m,n,z:\");\n\tint m,n,z,i,t;\t\n\tscanf(\"%d %d %d\",&m,&n,&z);\n\ti=1;\n\tt=m*i;\n\twhile ((t%n)!=0) {\n\t\ti++;\n\t\tt=m*i;\n\t}\n\telse\n\t\tprintf(\"%d\",z/t);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1c42073b485bbe04403adeb4890c6a36", "src_uid": "e7ad55ce26fc8610639323af1de36c2d", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio>\n\nint main() {\nint a[2], b[2], i=0;\nwhile(i<2) {\nscanf(\"%d:%d\", &a[i], &b[i]);\ni++;\n}\na[0]-=a[1];\nb[0]==b[0];\nif(b[0]<0) { b[0]+=60; a[0]--;}\nif(a[0]<0) a[0]+=24;\nprintf(\"%02d:%02d\\n\", a[0], b[0]);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1f191bbd2c057934dda835301a1b6582", "src_uid": "595c4a628c261104c8eedad767e85775", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nusing namespace std;\nmain()\n{\n      int a,b,c,d,e=0,f=0,g,h=0;\n      scanf(\"%d:%d\",&a,&b);\n      scanf(\"%d:%d\",&c,&d);\n      if(b-d>=10)\n         e=(b-d);\n      else if((b-d)>=0)\n         f=(b-d);\n      else{\n           g=60-abs(b-d);\n           if(g>=10)\n               e=g;\n           else if((b-d)>0)\n               f=g;\n           h++;\n      }   \n      if((a-c-h)>=10)\n         printf(\"%d:\",a-c-h);\n      else if((a-c-h)>=0&&(a-c-h)<10)\n         printf(\"0%d:\",a-c-h);\n      else if((a-c-h)<0)\n         printf(\"%d:\",24-abs(a-c-h));    \n      if(e!=0)\n         printf(\"%d\",e);\n      else\n         printf(\"0%d\",f);\n         return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c1b2137e7f41c1a505a75a41c31231d8", "src_uid": "595c4a628c261104c8eedad767e85775", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n    char input1[5],input2[5];\n    scanf(\"%s\",input1);\n    scanf(\"%s\",input2);\n    int h1 = ((int)input1[0])*10+((int)input1[1]);\n    int m1 = ((int)input1[3])*10+((int)input1[4]);\n    int h2 = ((int)input2[0])*10+((int)input2[1]);\n    int m2 = ((int)input2[3])*10+((int)input2[4]);\n    int a1,a2;\n    if(m1<m2){\n        a2 = m2-m1;\n        if(h1=<h2){\n            a1 = 24+h1-h2-1;\n        }\n        else{\n            a1 = h1-h2-1;\n        }\n    }\n    else{\n        a2 = m1-m2;\n        if(h1<h2){\n            a1 = 24+h1-h2;\n        }\n        else{\n            a1 = h1-h2;\n        }\n    }\n    if(a1<10)    \n        printf(\"%c\",'0');    \n    printf(\"%d\",a1);\n    printf(\"%c\",':');\n    if(a2<10)\n        printf(\"%c\",'0');\n    printf(\"%d\\n\",a2);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "82b8deda08711f873c9a94e42a66f7f0", "src_uid": "595c4a628c261104c8eedad767e85775", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nvoid time()\n{\nchar s[6],d[6],r[6];\nscanf(\"%s %s\",s,d);\nint m1,m2,h1,h2 ,rm,rh;\nm1=convert(s[3],s[4]);\nm2=convert(d[3],d[4]);\nif(s[0]=='0'&&s[1]=='0')\n    h1=24;\nelse\n   h1=convert(s[0],s[1]);\n\nif(d[0]=='0'&&d[1]=='0')\n    h2=24;\n  else\n    h2=convert(d[0],d[1]);\n    rm=m1-m2;\n    rh=h1-h2;\n    if(rm<0)\n    {\n     rm=rm+60;\n     rh--;\n    }\n    if(rh<9&&rm>9)\n       printf(\"0%d:%d\",rh,rm);\n    else if(rh>9&&rm<9)\n      printf(\"%d:0%d\",rh,rm);\n      else if(rh<9&&rm<9)\n        printf(\"0%d:0%d\",rh,rm);\n      if(rh>9&&rm>9)\n    printf(\"%d%d\",rm,rh);\n}\nint convert(char a[],char b[])\n{\n    int i,j,k;\n    i=(int)a;\n    i=i-48;\n    j=b;\n    j=j-48;\n    k=10*i+j;\n    return k;\n}\nint main()\n{\n    time();\n    return 0;\n}\n#include<stdio.h>\nvoid time()\n{\nchar s[6],d[6],r[6];\nscanf(\"%s %s\",s,d);\nint m1,m2,h1,h2 ,rm,rh;\nm1=convert(s[3],s[4]);\nm2=convert(d[3],d[4]);\nif(s[0]=='0'&&s[1]=='0')\n    h1=24;\nelse\n   h1=convert(s[0],s[1]);\n\nif(d[0]=='0'&&d[1]=='0')\n    h2=24;\n  else\n    h2=convert(d[0],d[1]);\n    rm=m1-m2;\n    rh=h1-h2;\n    if(rm<0)\n    {\n     rm=rm+60;\n     rh--;\n    }\n    if(rh<9&&rm>9)\n       printf(\"0%d:%d\",rh,rm);\n    else if(rh>9&&rm<9)\n      printf(\"%d:0%d\",rh,rm);\n      else if(rh<9&&rm<9)\n        printf(\"0%d:0%d\",rh,rm);\n      if(rh>9&&rm>9)\n    printf(\"%d%d\",rm,rh);\n}\nint convert(char a[],char b[])\n{\n    int i,j,k;\n    i=(int)a;\n    i=i-48;\n    j=b;\n    j=j-48;\n    k=10*i+j;\n    return k;\n}\nint main()\n{\n    time();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fea63807c44934b627cd875d2186f737", "src_uid": "595c4a628c261104c8eedad767e85775", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "//emre\n#include <stdio.h>\nint main()\n{\n    int a,b,c,d,x,y,z,t,emre;\n    char f;\n    scanf(\"%d%c%d\",&a,&f,&b);\n    scanf(\"%d%c%d\",&c,&f,&d);\n    if(a==0)\n    {\n        a=24;\n    }\n    if((b-d)=>0)\n    {\n    x=b-d;\n    }\n    else\n    {\n    x=60+b-d;\n    a--;\n    }\n    \n    \n    if((a-c)>0)\n    {\n    y=a-c;\n    }\n    else\n    {\n    y=24+a-c;\n    }\n        \n    if(y<9)\n    {\n        printf(\"0%d:\",y);\n    }\n    else if (y==24)\n    {\n        printf(\"00:\");\n    }\n    else\n    {\n        printf(\"%d:\",y);\n    }\n    \n    \n            \n    if(x<9)\n    {\n        printf(\"0%d\",x);\n    }\n    else if (x==60)\n    {\n        printf(\"00\");\n    }\n    else\n    {\n        printf(\"%d\",x);\n    }\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f37c4d19a99b11bd464d633d165dc579", "src_uid": "595c4a628c261104c8eedad767e85775", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int n,k,x,a[20],i=0,j,d=0,p=1;\n    scanf(\"%lld %lld\",&n,&k);\n    x=n;\n    while(x!=0)\n    {i++;\n     a[i]=x%10;\n     x=x/10;\n    }\n    for(j=i;j>=1;j--)\n    {if(a[j]!=0)\n     {break;}\n     d++;\n    }\n    if(d>=k)\n    {printf(\"%lld\",n);}\n    else\n    {i=1;\n     for(j=1;j<=k;j++)\n     {p=p*10;}\n     while((p*i)%n!=0)\n     {i++;}\n     printf(\"%lld\",p*i);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e3c60cc162c5aafa4984117c2814e6e8", "src_uid": "73566d4d9f20f7bbf71bc06bc9a4e9f3", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n\nint no_p(int n,int p)\n{\n\tint i=0;\n\twhile(n%p==0)\n\t{i++;\n\t\tn=n/p;\n\t\t\n\t}\n\treturn i;\n}\n\nint main()\n{\n\tlong long int i,j,k,l,n,n5,n2,m,r=1;\n\t\n\tn5=no_p(n,5);\n\t\n\tn2=no_p(n,2);\n\tprintf(\"%lld %lld\\n\",n5,n2);\n\tif (n5<k)\n\tn5=k-n5;\n\telse\n\tn5=0;\n\tif (n2<k)\n\tn2=k-n2;\n\telse\n\tn2=0;\n\tfor (i=0;i<n2;i++)\n\tr*=2;\n\tfor(i=0;i<n5;i++)\n\tr*=5;\n\tr*=n;\n\tprintf(\"%lld\\n\",r);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9cd17fde03b3dde5f22f5dc9772be0d7", "src_uid": "73566d4d9f20f7bbf71bc06bc9a4e9f3", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <iostream>\nusing namespace std;\n\n/**\n * http://codeforces.com/contest/861/problem/A\n * */\nlong gcd(long a, long b) {\n    long mod = a % b;\n    while(mod > 0) {\n        a = b;\n        b = mod;\n        mod = a % b;\n    }\n    return b;\n}\n\nlong round(long n, long k) {\n    long kk = 1;\n    while(k > 0) {\n        kk *= 10;\n        k--;\n    }\n    long g = gcd(n, kk);\n    return n * kk / g;\n}\n\nint main() {\n    long n, k;\n    scanf(\"%ld %ld\", &n, &k);\n//    printf(\"%ld\\n\", round(n, k));\n    cout << round(n, k);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6835826deecd1f2d2862929ee09c8ead", "src_uid": "73566d4d9f20f7bbf71bc06bc9a4e9f3", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nlong long int power(int osn, int pok);\n\n\nint main()\n{\n    long long int n2, n5, n, k, i, j, otv, c2 = 0, c5 = 0, ost, razn5, razn2;\n    scanf(\"%lld%lld\", &n, &k);\n    n2 = n;\n    n5 = n;\n    for(i = 0; i < k+1; i++)\n    {\n        if(n2%2 == 1)break;\n        else\n        {\n            n2 = n2/2;\n            c2++;\n        }\n    }\n    for(i = 0; i < k+1; i++)\n    {\n        if(n5%5 == 0)\n        {\n            n5 = n5/5;\n            c5++;\n        }\n        else\n        {\n            break;\n        }\n    }\n    if(k>=c5) razn5 = k - c5;\n    else{razn5 = 0;}\n    if(k>=c2) razn2 = k - c2;\n    else{razn2 = 0;}\n    \n    \n    n = n*power(2, razn2)*power(5, razn5);\n    \n    \n    printf(\"%lld\", n);\n    return 0;\n}\n\nint power (int osn, int pok)\n{   int temp = osn, temp1;\n    int i;\nif(pok == 0)return 1;\nelse{\n    if(pok == 1)return osn;\n    for (i = 1;i < pok; i++)\n    {\n        temp1 = temp;\n        temp = temp1 * osn;\n    }\n}\n    return temp;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fa5501bfdbc0990bb84e6def7c6c5746", "src_uid": "73566d4d9f20f7bbf71bc06bc9a4e9f3", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <iostream>\nusing namespace std;\n\n/**\n * http://codeforces.com/contest/861/problem/A\n * */\nlong gcd(long a, long b) {\n    long mod = a % b;\n    while(mod > 0) {\n        a = b;\n        b = mod;\n        mod = a % b;\n    }\n    return b;\n}\n\nlong round(long n, long k) {\n    long kk = 1;\n    while(k > 0) {\n        kk *= 10;\n        k--;\n    }\n    long g = gcd(n, kk);\n    return n * kk / g;\n}\n\nint main() {\n    long n, k;\n    scanf(\"%ld %ld\", &n, &k);\n    cout << round(n, k);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "98d8d32197ed2db06f11e2b63efebef6", "src_uid": "73566d4d9f20f7bbf71bc06bc9a4e9f3", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<conio.h>\nint main()\n{\n\tchar a;\n\tchar nam[6000099999000];\n\tscanf(\"%c\",&a);\n\tscanf(\"%s\",nam);\n\n\tif(a>96){\n\t\tprintf(\"%c\",a-32);\n\t\tprintf(\"%s\",nam);\n\t}\n\telse{\n\t\tprintf(\"%c\",a);\n\t\tprintf(\"%s\",nam);\n\t}\n\t\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ff1f4c26dc2283077f10d056822ea30d", "src_uid": "29e0fc0c5c0e136ac8e58011c91397e4", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main(){\n   long long int n;\n    scanf(\"%lld,&n\")\n    char ch[n];\n    scanf(\"%s\",&ch);\n    int i=0;\n    if(ch[i]>='a' && ch[i]<='z'){\n        ch[i]=ch[i]-32;\n    }\n    printf(\"%s\",ch);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0266c686b8bd0cf6e875eafd93534a6d", "src_uid": "29e0fc0c5c0e136ac8e58011c91397e4", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    char str[1000];\n    scanf(\"%s\",str[0]);\n    if(str[0]>=97 && str[0]<=122)\n        str[0]=90-32;\n    else\n        break;\n    printf(\"%s\",str[0]);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3e5e9479a93c9f98ee65edd204670f10", "src_uid": "29e0fc0c5c0e136ac8e58011c91397e4", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\n#include<string>\nusing namespace std;\nint main()\n{\n    string s;\n    int i;\n    getline(cin,s);\n    if(s[0]>=97&&s[0]<=122)\n    {\n        s[0]=s[0]-32;\n    }\n    cout<<s<<endl;\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d75af3ff02b1c6d6b6407671369b48d9", "src_uid": "29e0fc0c5c0e136ac8e58011c91397e4", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(){\n    int i,l;\n    char s[101];\n    scanf(\"%s\",s);\n    l=strlen(s);\n    for(int i=0;i<l;i++){\n        if(s[0]>=97&&s[0]<=122)\n        s[0]=s[0]-32;\n        printf(\"%s\",str);\n    }\nreturn 0;    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "01160f2f12d1714394ae54e8ff13a922", "src_uid": "29e0fc0c5c0e136ac8e58011c91397e4", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint ndogs;\nchar colors[100];\nchar test(char* arr)\n{\n\tint i = 0;\n\tint j = 0;\n\tfor (i = 0; i <= ndogs; i++)\n\t{\n\t\tfor (j = i + 1; j <= ndogs; j++)\n\t\t{\n\t\t\tif (arr[i] == arr[j])\n\t\t\t{\n\t\t\t\treturn 1;\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\nvoid main(void)\n{\n\tscanf(\"%d\", &ndogs);\n\tscanf(\"%s\", colors);\n\tif (test(colors))\n\t\tprintf(\"Yes\");\n\telse printf(\"No\");\n\tgetch();\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f85d977f09a07e58cc1a12e284cb1c53", "src_uid": "6b22e93f7e429693dcfe3c099346dcda", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint ndogs;\nchar colors[100];\nchar test(char* arr)\n{\n\tint i = 0;\n\tint j = 0;\n\tfor (i = 0; i <= ndogs; i++)\n\t{\n\t\tfor (j = i + 1; j <= ndogs; j++)\n\t\t{\n\t\t\tif (arr[i] == arr[j])\n\t\t\t{\n\t\t\t\treturn 1;\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\nvoid main(void)\n{\n\tscanf_s(\"%d\", &ndogs);\n\tscanf_s(\"%s\", colors, ndogs + 1);\n\tif (test(colors))\n\t\tprintf(\"Yes\");\n\telse printf(\"No\");\n\tgetch();\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "854e1f0cfa6bb74aad3457eb35ad4965", "src_uid": "6b22e93f7e429693dcfe3c099346dcda", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tchar a[2000001];\n\tint n, i, j, p=0;\n\t\n\tscanf(\"%d\",&n);\n\tscanf(\"%s\",a);\n\t\n\tfor(i=0; i<n; i++)\n\t{\n\t\tfor(j=i+1; j<n; j++)\n\t\t\tif(a[i]==a[j])\n\t\t\t{\n\t\t\t\tp=1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\tif(p) break;\n\t}\n\t\n\tif(n==1) p=1;\n\tif(p==1)\n\tprintf(\"yes\");\n\telse\n\tprintf(\"no\")\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8e309559e3dfb4af8cb42763bf67744b", "src_uid": "6b22e93f7e429693dcfe3c099346dcda", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "char test(char* arr)\n{\n\tfor (int i = 0; i <= ndogs; i++)\n\t{\n\t\tfor (int j = i + 1; j <= ndogs; j++)\n\t\t{\n\t\t\tif (arr[i] == arr[j])\n\t\t\t{\n\t\t\t\treturn 1;\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "585a4f30e5418ee17c84da151811bb0e", "src_uid": "6b22e93f7e429693dcfe3c099346dcda", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <bits/stdc++.h>\nusing namespace std;\n \n#define INIT(x) memset(x,0,sizeof(x))\n#define eps 1e-8\n \ntypedef long long ll;\nconst int inf = 0x3f3f3f3f;\nconst int maxn = 200005;\n \ninline void read(int &x)\n{\n    int f=1;x=0;char s=getchar();\n    while(s<'0'||s>'9'){if(s=='-')f=-1;s=getchar();}\n    while(s>='0'&&s<='9'){x=x*10+s-'0';s=getchar();}\n    x*=f;\n}\n \ninline void print(int x)\n{\n    if(x<0){ putchar('-'); x=-x;}\n    if(x>9) print(x/10);\n    putchar(x%10+'0');\n}\n \ninline void caltime(int tt) {\n\ttt = clock() - tt;\n    cerr << (double)tt/CLOCKS_PER_SEC << \" seconds!\" << endl;\n}\n \nint n;\nstring s;\nint a[100];\n \nint main()\n{\n\tcin>>n>>s;\n\tfor(int i=0;i<n;i++) {\n\t\tint temp = s[i]-'a';\n\t\ta[temp]++;\n\t}\n\tint ans = 0;\n\tfor(int i=0;i<26;i++) {\n\t\tif(a[i]>=2) {\n\t\t\tans++;\n\t\t}\n\t}\n\tif(ans||n==1) {\n\t\tcout<<\"Yes\"<<endl;\n\t}else {\n\t\tcout<<\"No\"<<endl;\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c9891740f2317efdbd8dab016a0ace9c", "src_uid": "6b22e93f7e429693dcfe3c099346dcda", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint fact(int x);\nint main()\n{\n\tlong long n,i;\n\twhile(scanf(\"%lld\",&n)!=EOF)\n\t{\n\t\tint s=0,m,t,j,c,d;\n\t\tfor(i=1;i<=n;i++)\n\t\t{\n\t\t\tc=(n-2*i);\n\t\t\tt=c/3;\n\t\t\tif(c%3==0&&t>=fact(i))\n\t\t\t{\n\t\t\t\ts++;\n\t\t\t}\n\t\t}\n\n\t\t\tprintf(\"%d\\n\",s);\n\t}\n}\nint fact(int x)\n{\n\tint i,s=0;\n\tfor(i=1;i<x;i++)\n\t{\n\t\ts+=i;\n\t}\n\treturn s;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ff189cc5a6db54101b299c5c809a8e05", "src_uid": "ab4f9cb3bb0df6389a4128e9ff1207de", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    int n,h,k,k1,f;\n    double i;\n    scanf(\"%d\",&n);\n    h=0;\n    if((n+1)%2==0)\n        h++;\n    i=sqrt(49/4-4/2*(-2-n));\n    k=(int)(7/2+i);\n    for(k1=2;k1<k;k++)\n    {\n        f=k1*(k1-1)/2;\n        if((n-(k1-1)*2-f)%2==0)\n            if((n-(k1-1)*2-f)%2>=f)\n                h++;\n    }\n    printf(\"%d\\n\",h);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2e3a085cf5275070ef00b36d39a6f43d", "src_uid": "ab4f9cb3bb0df6389a4128e9ff1207de", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<cstdio>\n#include<cstring>\n#include<iostream>\n#include<cstdlib>\ntypedef long long ll;\nusing namespace std;\nll n,ans=0;\nint main()\n{\n\tscanf(\"%I64d\",&n);\n\tll right=1000000000,left=0,mid;\n\twhile(left<=right)\n\t{\n\t\tmid=(left+right)/2;\n\t\tif(2*n-(3*mid-1)*(3*mid+1)<6*mid+4)\n\t\t\tright=mid-1;\n\t\telse\n\t\t{\n\t\t\tans=mid;\n\t\t\tleft=mid+1;\n\t\t}\n\t}\n\tprintf(\"%I64d\",ans);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "cf68b188e7d53fa4aab790ac168294e0", "src_uid": "ab4f9cb3bb0df6389a4128e9ff1207de", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n int main()\n  {\n    long long int t,n,i,count=0,rem;\n    scanf(\"%I64d\",&n)\n    t=n%3;\n    t=3-t;\n    for(i=t;3*i*(i+1)/2<=n+i;i+=3)\n    {\n    count++;\n    }\n    printf(\"%I64d\\n\",count);\n    return 0;\n  }", "lang_cluster": "C", "compilation_error": true, "code_uid": "78b65bc4958395570468edb862f371db", "src_uid": "ab4f9cb3bb0df6389a4128e9ff1207de", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<cstdio>\n#include<cstring>\n#include<iostream>\n#include<cstdlib>\ntypedef long long ll;\nusing namespace std;\nll n,ans=0;\nint main()\n{\n\tscanf(\"%LLd\",&n);\n\tll right=1000000000,left=0,mid;\n\twhile(left<=right)\n\t{\n\t\tmid=(left+right)/2;\n\t\tif(2*n-(3*mid-1)*(3*mid+1)<6*mid+4)\n\t\t\tright=mid-1;\n\t\telse\n\t\t{\n\t\t\tans=mid;\n\t\t\tleft=mid+1;\n\t\t}\n\t}\n\tprintf(\"%LLd\",ans);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4340da150d9e73ba7200a717f8b8555f", "src_uid": "ab4f9cb3bb0df6389a4128e9ff1207de", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int num=0;\n    char s[100];\n    gets(s);\n    int d=strlen(s);\n    for(int i=0;i<d;i++)\n    {\n        if(s[i]>64||s[i]<91)\n        num++;\n    }\n    if(num>d/2)\n    {for(int i=0;i<d;i++)\n   {\n    if(s[i]>96||s[i]<123)\n    s[i]=s[i]-32;\n   }}\n   else\n   {\n       if(s[i]>64||s[i]<91)\n       s[i]=s[i]+32;\n   }\n   printf(\"%s\",s);\n   return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b835100f5091ff90b0fcbf0a04c3c3fb", "src_uid": "b432dfa66bae2b542342f0b42c0a2598", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(){\n    int n,c=0,c1=0;\n    char a[100];\n    scanf(\"%s\",a);\n    n=strlen(a);\n    for(i=0;i<n;i++){\n        if(a[i] >= 'a' && a[i] <= 'z'){\n            c++;\n        }\n         if(a[i] >= 'A' && a[i] <= 'Z'){\n             c1++;\n    }\n}\nif(c>=c1){\n    for(i=0;i<n;i++){\n        if(a[i] >= 'A' && a[i] <= 'Z'){\n            a[i]=a[i]+32;\n        }\n    }\n}\n    else{\n        \n     for(i=0;i<n;i++){\n        if(a[i] >= 'a' && a[i] <= 'z'){\n            a[i]=a[i]-32;\n    \n}\n}\n}\nprintf(\"%s\",a);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d7b44ae3b640e147d2f3c560ee0995e2", "src_uid": "b432dfa66bae2b542342f0b42c0a2598", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char str[100];\n    int c=0,c1=0,i;\n    scanf(\"%s\",str);\n    for(i=0;i<strlen(str);i++)\n    {\n        if(str[i]>=65&&str[i]<=90)\n        c++;\n        else\n        c1++;\n    }\n    if(c>c1)\n    {\n        printf(\"%s\",str.toupper());\n    }\n    else\n    printf(\"%s\",str.tolower());\n    \n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "bcadf9820fa84fce30cd971fa861b47d", "src_uid": "b432dfa66bae2b542342f0b42c0a2598", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(){\n    char s[100];\n    int i,j,k;\n    scanf(\"%s\",&s);\n    for(i=0;s[i]!='\\0';i++){\n    if(s[i]>=97&&s[i]<=122){\n    j++;}\n    else if(s[i]>=65&&s[i]<=90){\n    k++;}}\n    for(i=0;s[i]!='\\0';i++){\n    if(j>k){\n    a[i]=a[i]+32;}\n    else if(k>j){\n    a[i]=a[i]-32;}\n    else if(j=k){\n    a[i]=a[i]-32;}}\n    printf(\"%s\\n\",s);\n    return 0;\n    }\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9c13c585197535500b8b3de461fc0dc2", "src_uid": "b432dfa66bae2b542342f0b42c0a2598", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nmain()\n{   \n    int r,i,up,lw;\n\tchar a[101];\n\tgets(a);\n\tr=strlen(a);\n\tfor(i=0;i<r;i++)\n\tif(a[i]<'a')\n       {\n  up++;\n}else\n{\n\tlw++;\n}\n      \n        \n\n\tif(up=>lw)\n\tprintf(\"%s\",strupr(a));\n\telse\n\tprintf(\"%s\",strlwr(a));\t\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a71c93f12d237395aa79dcadd7d9aa8d", "src_uid": "b432dfa66bae2b542342f0b42c0a2598", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    int i;\n    char a[1000],b[1000];\n    scanf(\"%s\",a);\n    scanf(\"%s\",b);\n    for(i=0;i<strlen(a);i++)\n    {\n        if(a[i]=='0'&&b[i]=='0')\n        {\n            a[i]='0';\n        }\n        else if(a[i]=='0'&&b[i]=='1')\n        {\n            a[i]='1';\n        }\n        else if(a[i]=='1'&&a[i]=='1')\n        {\n            a[i]='0';\n        }\n    }\n    printf(\"%s\\n\",a);\n    return(0);\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4a2960d61f2a519c2e48188521c7eb20", "src_uid": "3714b7596a6b48ca5b7a346f60d90549", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\nint main() {\n    char s1[100],s2[100];\n    scanf(\"%s%s\",s1,s2);\n    int c=strlen(a);\n    for(int i=0;i<c;i++) {\n        if(s1[i]=='0'&&s2[i]=='0') {\n            s1[i]='0';\n        } if(s1[i]=='1'&&s2[i]=='1') {\n            s1[i]='0';\n        } if(s1[i]=='0'&&s2[i]=='1') {\n            s1[i]='1';\n        } if(s1[i]=='1'&&s2[i]=='0') {\n            s1[i]='1';\n        }\n    }\n    printf(\"%d\\n\",s1[i]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8ca0961f71af669013488a158da8b0b9", "src_uid": "3714b7596a6b48ca5b7a346f60d90549", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<conio.h>\n#include<math.h>\n#include<string.h>\n \nint main()\n{\n    long long int i,j,l,m,n,a[1000],b[1000],sum=0;\n    char a[1000],b[1000];\n    scanf(\"%s\",a);\n    scanf(\"%s\",b);\n    l=strlen(a);\n    for(i=0;i<l;i++)\n    {\n        if(a[i]==b[i])\n        printf(\"0\");\n        else\n        printf(\"1\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0516d4d0a0a7b9c666186ab691055a9c", "src_uid": "3714b7596a6b48ca5b7a346f60d90549", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n int i=0;\n char a[101],b[101],c[101];\n scanf(\"%s%s\",a,b);\n while(a[i]!=0)\n {\n  a[i]==b[i]?c[i]=0:c[i]=1;\n  i++;\n }\n printf(\"%s\",c);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4d807e091ebe45a86e8397d59c95dc48", "src_uid": "3714b7596a6b48ca5b7a346f60d90549", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nmain()\n{int i, a[100],b[110]; \nchar c;\nfor(i=0;(c=getchar())!='\\n';i++)\na[i]=c-'0';\nfor(i=0;(c=getchar())!='\\n';i++)\nb[i]=c-'0';\nc=int(i);\nfor(i=0;i<c;i++)\nif(a[i]==b[i])\nprintf(\"0\");\nelse\nprintf(\"1\");\n\nreturn 0;}", "lang_cluster": "C", "compilation_error": true, "code_uid": "24615674eb26bd5b4b7a64612da4e356", "src_uid": "3714b7596a6b48ca5b7a346f60d90549", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main() {\n\tint a, b;\n\tscanf_s(\"%d%d\", &a, &b);\n\tif (a == 9 && b == 1) {\n\t\tprintf(\"%d %d\", a, b * 10);\n\t}\n\telse if (a == b) {\n\t\tprintf(\"%d %d\", a * 10, b * 10 + 1);\n\t}\n\telse if (a + 1 == b) {\n\t\tprintf(\"%d %d\", a, b);\n\t}\n\telse printf(\"%d\", -1);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "86fa122d3582254bf65c3ee66bf7ff91", "src_uid": "3eff6f044c028146bea5f0dfd2870d23", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    int a,b;\n    scanf(\"%d %d\",&a,&b);\n    if(abs(a-b)>1)\n    printf(\"-1\");\n    if(abs(a-b)==0)\n    printf(\"%d12 %d13\",a,b);\n    if(abs(a-b)==1)\n    printf(\"%d99 %d00\",a.);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "91a5487b09978418efee8e44dc9c60e9", "src_uid": "3eff6f044c028146bea5f0dfd2870d23", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int a,b;\n    scanf(\"%d %d\",&a,&b);\n    if(a==b){\n    printf(\"%d00 %d01\\n\",a,b);\n    }\n    else if(a+1=b){\n    printf(\"%d %d\\n\",a,b);\n    }\n    else if(a==9&&b==1){\n    printf(\"%d %d0\\n\",a,b);\n    }\n    else {\n    printf(\"-1\\n\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "37d1db9c82d5bc6d8edb1447b239bc7d", "src_uid": "3eff6f044c028146bea5f0dfd2870d23", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n\nmain() {\n    \n    char s[50];\n    gets(s);\n    char *numbers;\n    strtok_r(s, \" \", &numbers);\n    int a = atoi(s);\n    int b = atoi(numbers);\n    \n    if ((b - a) > 1) {\n        printf(\"-1\\n\");\n        exit(0);   \n    }\n    if (a == 9 && b == 1){\n        printf(\"%d %d\\n\", 99, 100);\n\n        exit(0);   \n    }\n    if (a > b) {\n        printf(\"-1\\n\");   \n        exit(0);   \n    }\n    if (a == b){\n        printf(\"%d %d\\n\", a * 10, b * 10 + 1);\n        exit(0);\n    }\n    if (b > a){\n        printf(\"%d %d\\n\", (a * 100) + 99, b * 100);\n        exit(0);   \n    }    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "43028508c2af3b91e319cd0a51cfea73", "src_uid": "3eff6f044c028146bea5f0dfd2870d23", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    int a,b;\n    scanf(\"%d %d\",&a,&b);\n    if(abs(a-b)>1)\n    printf(\"-1\");\n    if(abs(a-b)=0)\n    printf(\"%d12 %d13\",a,b);\n    if(abs(a-b)=1)\n    printf(\"%d99 %d00\",a,b);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f82231c602c279d1cfaed76a1d314ecc", "src_uid": "3eff6f044c028146bea5f0dfd2870d23", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n    int n,s1=0,s2=0\nint x,y;\n    scanf(\"%d\",&n);\n \n    for(int i = 0; i < n; ++i)\n{\n        scanf(\"%d%d\",&x,&y);\ns1=s1+x;\ns2=s2+y;\n}\nif(s2<s1)\nprintf(\"yes\");\nelse printf(\"no\");\n \n    return 0;\n}\n  \n1", "lang_cluster": "C", "compilation_error": true, "code_uid": "26dd04d956b9afbaf3c6f565a9c4c268", "src_uid": "e0ddac5c6d3671070860dda10d50c28a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n                 int i,j,n,c;\n                 scanf(\"%d\",&n);\n                 int a[n],b[n];\n                 for(i=0;i<n;i++)\n                 {\n                     scanf(\"%d\",&a[i]);\n                     sum+=a[i];\n                 }\n                 for(i=0;i<n;i++)\n                 {\n                     scanf(\"%d\",&b[i]);                     \n                     sum1+=b[i] ;\n                 }\n               \n               if(sum>=sum1)\n               {\n                   printf(\"Yes\\n\");\n               }\n               else\n               {\n                   printf(\"No\\n\");\n               }\n          return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2cdda1a7597eaac4c6dda4ac6f5791b8", "src_uid": "e0ddac5c6d3671070860dda10d50c28a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    int a[n],b[n],x=0,y=0;\n    for(i=0;i<n;i++)\n    {scanf(\"%d\",&a[i]);\n    x=x+a[i];\n    }\n     for(i=0;i<n;i++)\n   { scanf(\"%d\",&b[i]);\n       y=y+b[i];\n   }\n    if(x>=y)\n    printf(\"Yes\");\n    else\n    printf(\"No\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7600a513eebe918df7f493f9937e17dc", "src_uid": "e0ddac5c6d3671070860dda10d50c28a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n  int n,sum1=0,sum2=0,i,j,k;\n  scanf(\"%d\",&n);\n  int p1[n],p2[n];\n  for(i=0;i<n;i++)\n      scanf(\"%d\",&p1[i];\n  for(j=0;j<n;j++)\n      scanf(%d,&p2[j];\n  for(k=0;k<n;k++)\n    {\n        sum1 += p1[k];\n        sum2+= p2[k];\n    }\n    if(sum1>=sum2)  printf(\"Yes\");\n        else printf(\"No\");\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1d823c4df2746c8476ac5b2791277db7", "src_uid": "e0ddac5c6d3671070860dda10d50c28a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,i,j;\n    scanf(\"%d\",&n);\n    int x[n];\n    int y[n];\n\nfor(i=0;i<n;i++)\n{\n    scanf(\"%d\",&x[i]);\n    sum=sum+x[i];\n}\nfor(i=0;i<n;i++)\n{\n    scanf(\"%d\",&y[i]);\n    sum1=sum1+y[i];\n\n}\n\nif(sum==sum1)\nprintf(\"Yes\");\nelse\nprintf(\"No\");\nreturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2d10f2b00d9a495e6e62b77dba5f6fc4", "src_uid": "e0ddac5c6d3671070860dda10d50c28a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#define _CRT_SECURE_NO_WARNINGS\n#include <stdio.h> \n#include <stdlib.h>\n#include <string.h>\n\nvoid get (char **number);\nvoid one_digit(char *number);\nint two_digit(char *number);\nint three_digit(int number);\n\nint main()\n{\n\t// Get input\n\tchar **number = (char **)malloc(sizeof(char *));\n\t*number = (char *)calloc(101, sizeof(char));\n\tget(number);\n\t// Find number of digits\n\tint length = strlen(*number);\n\t///////////////////////////////////////////////////////\n\tint result = 0;\n\t\n\t// For 1 digit\n\tif (length == 1)\n\t\tif (one_digit(*number))\n\t\t\treturn 0;\n\n\t// For 2 digits\n\tif (length == 2)\n\t\tif (two_digit(*number))\n\t\t\treturn 0;\n\t\n\t// For 3 & more digits\n\tif (length >= 3)\n\t{\n\t\tfor (int i = 0; number[0][i] != '\\0'; i++)\n\t\t{\n\t\t\tfor (int j = i + 1; number[0][j] != '\\0'; j++)\n\t\t\t{\n\t\t\t\tfor (int z = j + 1; number[0][z] != '\\0'; z++)\n\t\t\t\t{\n\t\t\t\t\tchar number_3_digits[4] = \"\";\n\t\t\t\t\tstrncat(number_3_digits, &number[0][i], 1);\n\t\t\t\t\tstrncat(number_3_digits, &number[0][j], 1);\n\t\t\t\t\tstrncat(number_3_digits, &number[0][z], 1);\n\n\t\t\t\t\tint n = atoi(number_3_digits);\n\n\t\t\t\t\tif (three_digit(n))\n\t\t\t\t\t\treturn 0;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"NO\");\n\treturn 0;\n}\n\nint function(int number)\n{\n\tint third = number % 10;\n\tint second = (number % 100 - third) / 10;\n\tint first = (number - second - third) / 100;\n\n\tif ((third + 2 * second + 4 * first) % 8 == 0)\n\t\treturn 1;\n\treturn 0;\n}\n\nvoid get(char **number)\n{\n\tscanf(\"%s\", number[0]);\n}\n\nvoid one_digit(char *number)\n{\n\tif (number[0] == '8' || number[0] == '0')\n\t{\n\t\tprintf(\"YES\\n\");\n\t\tprintf(\"%s\", number);\n\t\treturn 1;\n\t}\n\treturn 0;\n}\n\nint two_digit(char *number)\n{\n\tint int_number = atoi(number);\n\tint second = int_number % 10;\n\tint first = (int_number - second) / 10;\n\tif (int_number % 8 == 0)\n\t{\n\t\tprintf(\"YES\\n\");\n\t\tprintf(\"%d\", int_number);\n\t\treturn 1;\n\t}\n\tif (second % 8 == 0)\n\t{\n\t\tprintf(\"YES\\n\");\n\t\tprintf(\"%d\", second);\n\t\treturn 1;\n\t}\n\tif (first % 8 == 0)\n\t{\n\t\tprintf(\"YES\\n\");\n\t\tprintf(\"%d\", first);\n\t\treturn 1;\n\t}\n\treturn 0;\n}\n\nint three_digit(int number)\n{\n\tif (number % 8 == 0)\n\t{\n\t\tprintf(\"YES\\n\");\n\t\tprintf(\"%d\", number);\n\t\treturn 1;\n\t}\n\telse if (function(number))\n\t{\n\t\tprintf(\"YES\\n\");\n\t\tprintf(\"%d\", number);\n\t\treturn 1;\n\t}\n\telse\n\t\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "48a8d646252c8de881254c06fd7901e2", "src_uid": "0a2a5927d24c70aca24fc17aa686499e", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main() {\n\tshort int arr[100];\n\tchar str[100];\n\tscanf(\"%s\", str);\n\tint ch, cnt = 0;\n\twhile ((ch = str[cnt]) != '\\0') {\n\t\tarr[cnt++] = ch - '0';\n\t\tif (arr[cnt-1] == 0 || arr[cnt-1] == 8) {\n\t\t\tprintf(\"YES\\n%d\", arr[cnt-1]);\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\tfor (int i = cnt-1; i >= 2; i--) {\n\t\tif (arr[i] % 2 == 0) {\n\t\t\tfor (int j = i-1; j >= 1; j--) {\n\t\t\t\tif ((arr[j]*10 + arr[i]) % 4 == 0) {\n\t\t\t\t\tfor (int k = j-1; k >= 0; k--) {\n\t\t\t\t\t\tshort int x = arr[k]*100 + arr[j]*10 + arr[i];\n\t\t\t\t\t\tif (x % 8 == 0) {\n\t\t\t\t\t\t\tprintf(\"YES\\n%d\", x);\n\t\t\t\t\t\t\treturn 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int i = cnt-1; i >= 1; i--) {\n\t\tfor (int j == i-1; j >= 0; j--) {\n\t\t\tif ((arr[i] + arr[j]*10) % 8 == 0) {\n\t\t\t\tprintf(\"YES\\n%d\", arr[i] + arr[j]*10);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"NO\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a74f924d0f56ef4afe8aae3bc7dec437", "src_uid": "0a2a5927d24c70aca24fc17aa686499e", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include \"convert.h\"\n#include <stdio.h>\n#include <string.h>\n#ifndef H_CONVERT\n#define H_CONVERT\n\n#define KIA Str \n#define PXFUAODT template \n#define JNKEV scanf \n#define EIQUTJ Lprime \n#define OGF num \n#define PBI cur \n#define GDSQ puts \n#endif\n\nint main()\n{\n    char KIA[101];\n    char PXFUAODT[3];\n    int i, j, L;\n    JNKEV(\"%s\", KIA);\n    L = strlen(KIA);\n    for(i = 0; i < 1000; i += 8) {\n        memset(PXFUAODT, -1, sizeof(PXFUAODT));\n        int EIQUTJ = 0;\n        int OGF = i;\n        do {\n            PXFUAODT[EIQUTJ++] = OGF % 10 + '0';\n            OGF /= 10;\n        } while(OGF != 0);\n        int PBI = L - 1;\n        for(j = 0; j < EIQUTJ; ++j) {\n            while(PBI >= 0 && KIA[PBI] != PXFUAODT[j]) {\n                if(--PBI < 0) {\n                    break;\n                }\n            }\n            if(PBI < 0) {\n                break;\n            }\n            --PBI;\n        }\n        if(j == EIQUTJ) {\n            GDSQ(\"YES\");\n            printf(\"%d\\n\", i);\n            return 0;\n        }\n    }\n    GDSQ(\"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0c710f4554eb49282a8d7dd891817d36", "src_uid": "0a2a5927d24c70aca24fc17aa686499e", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<vector>\n#include<string>\n#include<cstring>\n#include<algorithm>\n#define pl(n) cout<<n<<endl\n#define p(n) cout<<n\n#define rep0(i,n) for(int i=0;i<n;i++)\n#define rep1(i,n) for(int i=1;i<n;i++)\nusing namespace std;\n\ntypedef long long ll ;\ntypedef vector<int> vi;\ntypedef vector<string> vs;\ntypedef vector<ll> vl;\n    \nint main(){\n    string str;\n    cin>>str;\n    int l = str.size();\n    if(l<3){\n        if(l==1){\n            int n = str[0]-'0';\n            if(!n%8){\n                pl(\"YES\");\n                cout<<n<<endl;\n                return 0;\n            }\n            else{\n                pl(\"NO\");\n                return 0;\n            }\n        }\n        if(l==2){\n            int n = (str[0]-'0')*10+str[1]-'0';\n            if(n%8==0){\n                pl(\"YES\");\n                cout<<str<<endl;\n                return 0;\n            }\n            n = str[0]-'0';\n            if(n%8==0){\n                pl(\"YES\");\n                cout<<str[0]<<endl;\n                return 0;\n            }\n            n = str[1]-'0';\n            if(n%8==0){\n                pl(\"YES\");\n                cout<<str[1]<<endl;\n                return 0;\n            }\n        }\n    }\n    for(int i=l-1;i>2;i--)\n    {\n        \n        int n = str[i]-'0'+(str[i-1]-'0')*10+(str[i-2]-'0')*100+(str[i-3]-'0')*1000;\n        if(n%8==0)\n        {\n            pl(\"YES\");\n            cout<<str<<endl;\n            return 0;\n        }\n        n = (str[i-1]-'0')*1+(str[i-2]-'0')*10+(str[i-3]-'0')*100;\n        if(n%8==0){\n            pl(\"YES\");\n            cout<<str.substr(0,(i-4+1))<<str[i-3]<<str[i-2]<<str[i-1]<<endl;\n            return 0;\n        }\n        n = str[i]-'0'+(str[i-2]-'0')*10+(str[i-3]-'0')*100;\n        if(n%8==0){\n            pl(\"YES\");\n            cout<<str.substr(0,(i-4+1))<<str[i-3]<<str[i-2]<<str[i]<<endl;\n            return 0;\n        }\n        n = str[i]-'0'+(str[i-1]-'0')*10+(str[i-3]-'0')*100;\n        if(n%8==0){\n            pl(\"YES\");\n            cout<<str.substr(0,(i-4+1))<<str[i-3]<<str[i-1]<<str[i]<<endl;\n            return 0;\n        }\n        n = str[i]-'0'+(str[i-1]-'0')*10+(str[i-2]-'0')*100;\n        if(n%8==0){\n            pl(\"YES\");\n            cout<<str.substr(0,(i-4+1))<<str[i-2]<<str[i-1]<<str[i]<<endl;\n            return 0;\n        } \n    }\n    pl(\"NO\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e1d88818a9ab6a37693c2dcf8f0be4cf", "src_uid": "0a2a5927d24c70aca24fc17aa686499e", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int i,j,k,flag=0,flag1=0,num;\n    char a[101];\n    scanf(\"%s\",a);\n    int l=strlen(a);\n    if(l<=3)\n    {\n        if(l==1)\n        {\n            if(a[0]%8==0)\n            {\n                printf(\"YES\\n\");\n                printf(\"%s\\n\",a);\n            }\n            else\n                printf(\"NO\\n\");\n\n\n        }\n        if(l==2)\n        {\n            if(((a[0]-48)*10+a[1]-48)%8==0)\n            {\n\n                printf(\"YES\\n\");\n                printf(\"%s\\n\",a);\n            }\n            else\n            {\n                if((a[0]-48)%8==0||(a[1]-48)%8==0)\n                {\n                    if((a[0]-48)%8==0)\n                    {\n                        \n                printf(\"YES\\n\");\n                printf(\"%c\\n\",a[0]);\n                    }\n                    else\n                    {\n\n                printf(\"YES\\n\");\n                printf(\"%c\\n\",a[1]);\n                    }\n                }\n                else\n                    printf(\"NO\\n\");\n\n            }\n           \n        }\n        if(l==3)\n        {\n        num=(a[l-3]-48)*100+(a[l-2]-48)*10+a[l-1]-48;\n        if(num%8==0)\n        {\n            printf(\"YES\\n\");\n            printf(\"%s\\n\",a);\n        }\n        else\n        {\n            for(i=0;i<l;i++)\n            {\n                if(a[i]-48==8)\n                {\n                    \n                printf(\"YES\\n\");\n                printf(\"%c\\n\",a[i]);\n\n                    flag1=1;\n                    break;\n                }\n            }\n            if(flag1!=1)\n            {\n                for(i=0;i<l;i++)\n                {\n                    for(j=i+1;j<l;j++)\n                    {\n                        if(((a[i]-48)*10+a[j]-48)%8==0)\n                        {\n                            \n                printf(\"YES\\n\");\n                printf(\"%c%c\\n\",a[i],a[j]);\n                            flag1=1;\n                            break;\n                        }\n\n                    }\n                    if(flag==1)\n                        break;\n                \n\n            }\n\n        }\n        \n    //    if(flag1==1)\n      //  {\n           \n       // }\n     /*   if(flag1==1)\n        {\n            printf(\"YES\\n\");\n            printf(\"%c%c\\n\",d1,d2);\n        }*/\n        if(flag1!=1)\n            printf(\"NO\\n\");\n\n        }\n    }\n    }\n    else\n    {\n//        printf(\"fgfd\");\n        num=(a[l-3]-48)*100+(a[l-2]-48)*10+a[l-1]-48;\n        if(num%8==0)\n        {\n           printf(\"YES\\n\");\n           printf(\"%s\\n\",a);\n           flag=1;\n        }\n        else\n        {\n            for(i=0;i<l;i++)\n            {\n                if(a[i]-48==8)\n\n                    {\n                        \n                printf(\"YES\\n\");\n                printf(\"%c\\n\",a[i]);\n                    flag=1;\n                    break;\n                    }\n\n\n\n            }\n            if(flag!=1)\n            {\n                for(i=0;i<l;i++)\n                {\n                    for(j=i+1;j<l;j++)\n                    {\n                        if(((a[i]-48)*10+a[j]-48)%8==0)\n                        {\n                printf(\"YES\\n\");\n                printf(\"%c%c\\n\",a[i],a[j]);\n                            flag=1;\n                            break;\n                        }\n\n                    }\n                    if(flag==1)\n                        break;\n                }\n\n            }\n            if(flag!=1)\n            {\n  //              printf(\"dsfgsd\\n\");\n                for(i=0;i<l;i++)\n                {\n                    for(j=i+1;j<l;j++)\n                    {\n                        for(k=i+2;k<l;k++)\n                        {\n                        if(((a[i]-48)*100+(a[j]-48)*10+a[k]-48)%8==0)\n                        {\n                  printf(\"YES\\n\");\n                     printf(\"%c%c%c\\n\",a[i],a[j],a[k]);\n                            flag=1;\n                            break;\n                        }\n                        }\n                        if(flag==1)\n                            break;\n\n                    }\n                 if(flag==1)\n                     break;\n\n            }\n\n        }\n        }\n        if(flag!=1)\n            printf(\"NO\\n\");\n\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "71799670a3a635769fdb1f2e52bc484f", "src_uid": "0a2a5927d24c70aca24fc17aa686499e", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\nint n,i,x=0,a=2,d=4;\nlong long int k;\nscanf(\"%d %d\",&n,&k);\nif(k%2!=0)\nprintf(\"1\");\nelse\n{\n    for(i=1;i<=49;i++)\n    {\n        if(i>1)\n        {\n            a=a*2;\n            d=d*2;\n        }\n        if(((k-a)%d)==0)\n        {\n        printf(\"%d\",i+1);\n        break;\n        }\n    }\n    if(i==50)\n    {\n    for(i=1;i<=50;i++)\n    {\n    if(i==1)\n    x=7;\n    else\n    x=x*2 + 1;\n    if(k==(x/2 + 1))\n    printf(\"%d\",i);\n    }\n    }\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a65185ec4e4fe1acccc38301bea778e5", "src_uid": "0af400ea8e25b1a36adec4cc08912b71", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define pb push_back\n#define mp make_pair\n#define fi first\n#define se second\n#define INF (1LL << 55)\n#define MOD (1000 * 1000 * 1000 + 7)\n#define maxn 200111\n\ntypedef long long ll;\ntypedef long double ld;\ntypedef pair<int, int> pii;\n\n#include <stdio.h>\n#include <math.h>\n\nll pot (ll a , ll b){\n\tll x = 1LL;\n\tfor (int i = 0; i < b ; i++)\n\t\tx = x * a;\n\n\treturn x;\n}\n\n\n\n\nint main (){\n\tll n, a;\n\tscanf (\"%lld\",&n);\n\tscanf (\"%lld\",&a);\n\tint x = 1;\n\n\n\tfor (int i = n; i >= 2; i--){\n\t\tll k = a - pot(2, i - 1);\n\t\tll l = pot(2, i);\n\t\t\n\t\tif (k % l == 0){\n\t\t\tx = i;\n\t\t\tbreak;\n\t\t}\t\n\t}\n\tprintf(\"%d\\n\", x);\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "127c6fdd2201f0fecb55f22d55d88ded", "src_uid": "0af400ea8e25b1a36adec4cc08912b71", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdlib.h>\n#incude<stdio.h>\nint main()\n{\n    long long n,k,i,t=1;\n    scanf(\"%I64d %I64d\",&n,&k);\n    for(i=0;i<n-1;i++) t*=2;\n    for(i=n-1;i>=0;i--)\n    {\n        if(k%t!=0)\n        {\n            t=t/2;\n        }\n        else break;\n    }\n    printf(\"%I64d\",i+1);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ea73ecbd70239adc65d9f476930798b0", "src_uid": "0af400ea8e25b1a36adec4cc08912b71", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "// luogu-judger-enable-o2\n#include <cstdio>\nint main ()\n{\n    long long n, t, ans=0;\n    scanf(\"%lld %lld\",&n,&t);\n    for(int i=1;i<=n;i++)\n    \tif(t%2==0){\n    \t\tt/=2;ans++;\n\t\t}\n\tprintf(\"%lld\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "51573e6a866e5f657e65da12f9f7b346", "src_uid": "0af400ea8e25b1a36adec4cc08912b71", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint n,k;\nscanf(\"%d%d\",&n,&k);\nif(k%2==1)\nprintf(\"1\");\nelse\n{\nint c=1;\nwhile(k!=0 && k%2==0)\n{\nc++;\nk=k/2;\n}\n}\nprintf(\"%d\",c);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a8153764cb1b6cc48049615f92fc306e", "src_uid": "0af400ea8e25b1a36adec4cc08912b71", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "/* .................... compiled by alankar....................\n*/\n\n//......................SHORTCUTS..............................\n\n#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n//...........................................................\n\n#define pi 3.14159265358979323846  //float type\n#define MAX 100000  //for rmq\n#define SQRTMAX 317   //for rmq\n//#define gc getchar_unlocked\n\n#define FOR(i,a,b) for(i=(a);i<(b);i++)\n\n//only for +ve and single terms\n#define s(x) scanf(\"%d\",&x);\n#define sl(x) scanf(\"%llu\",&x);\n#define p(x) printf(\"%d\\n\",x);\n#define pl(x) printf(\"%llu\\n\",x);\n//..........................................................\n\ntypedef long long int ll;\nconst ll MOD=1000000007;\n\n//returns int and +ve numbers\n\n/*inline int inp(){\n    int n=0;\n    char c;\n    c=gc();\n    while(c<'0' || c>'9'){\n        c=gc();\n    }\n    while(c>='0' && c<='9'){\n        n=(n<<3)+(n<<1)+c-'0';\n        c=gc();\n    }\n    return n;\n}\n*/\n//...................................\n\n//power with mod........long long int\n ll power(ll a,ll b,ll mod){\n      if(b==0)\n            return 1;\n      ll temp=power(a,b/2,mod);\n      temp=(temp*temp)%mod;\n      if(b&1)\n            temp=(temp*a)%mod;\n      return temp;\n}\n\n //power without mod........ int\nint pwr(int a,int b){\n      if(b==0)\n            return 1;\n      int temp=pwr(a,b/2);\n      temp=(temp*temp);\n      if(b&1)\n            temp=(temp*a);\n      return temp;\n}\n // .....long long int\nll gcd(ll a,ll b){\n      return b==0?a:gcd(b,a%b);\n}\n //......long long int\nll lcm(ll a,ll b){\n      return (a/gcd(a,b))*b;\n}\n //......long long int with mod\nll modularInverse(ll a,ll m){\n      return power(a,m-2,m);\n}\n\n //only for int\ninline int min(int a,int b) { return a<b? a : b; }\ninline int max(int a,int b) { return a>b? a : b; }\n\n//normal compare func on integers //for qsort(name,size,sizeof(type),compare)\nint compare (const void * a, const void * b)\n{\n  return ( *(int*)a - *(int*)b );\n}\n//.......................................................\n\n//segment tree\n//not template but how to use ST\n//for minimum element\n/*\nlong long s[400000];\nlong long a[1000000];\nint create(long long b,long long e,long long n)\n{\n    if(b==e)\n    {\n        s[n]=a[b];\n    }\n    else\n        {\n            create(b,(b+e)/2,2*n+1);\n            create((b+e)/2+1,e,2*n+2);\n            s[n]=s[2*n+1]<s[2*n+2]?s[2*n+1]:s[2*n+2];\n        }\n    return 0;\n}\n\n\n//for finding minimum element b/w l and r\nlong long messi(long long b,long long e,long long l,long long r,long long n)\n{\n    long long i,j;\n    if(e<l||b>r)\n    {\n        return 100000001;\n    }\n    if(b>=l&&e<=r)\n    {\n        return s[n];\n    }\n    i=messi(b,(b+e)/2,l,r,2*n+1);\n    j=messi((b+e)/2+1,e,l,r,2*n+2);\n    return i<j?i:j;\n}\n*/\n//............................................................................\n//range minimam query\n//for mim and max number\n/*\n\n//preprocess create the min array\n\nlong min[SQRTMAX], max[SQRTMAX], b[MAX];\nint size, n;\n\nvoid preProcess(int n){\n    int i=0, j=0, k=0;\n    long minimum, maximum;\n\n    size = sqrt(n);\n    //printf(\"size = %d\\n\",size);\n    while(j<size){\n        minimum = maximum = b[i];\n        for(k=0 ; k<size ; k++){\n            if(minimum>b[i])\n                minimum = b[i];\n            if(maximum<b[i])\n                maximum = b[i];\n            i++;\n        }\n        min[j] = minimum;\n        max[j] = maximum;\n        j++;\n    }\n}\n\nlong findMin(int l, int r){\n    int j, j2;\n    long minimum = b[l];\n\n    j = l/size + 1;\n    j2 = r/size - 1;\n\n    //printf(\"j= %d and j2 = %d\\n\", j,j2);\n    while(l<j*size && l<=r){\n        if(minimum > b[l]){\n            minimum = b[l];\n\n        }\n        //printf(\"Checked for %d\\n\", l);\n        l++;\n    }\n    while(j<=j2 && l<=r && j<size){\n        if(minimum > min[j])\n            minimum = min[j];\n        l = (j+1)*size;\n        //printf(\"Checked for %d  <-->  %d\\n\", j*size, l-1);\n        j++;\n    }\n    while(l<=r){\n        if(minimum > b[l]){\n            minimum = b[l];\n        }\n        //printf(\"Checked for %d\\n\", l);\n        l++;\n    }\n    return minimum;\n}\n\n//finding max value\nlong findMax(int l, int r){\n    int j, j2;\n    long maximum = b[l];\n\n    j = l/size + 1;\n    j2 = r/size - 1;\n\n    //printf(\"j= %d and j2 = %d\\n\", j,j2);\n    while(l<j*size && l<=r){\n        if(maximum < b[l]){\n            maximum = b[l];\n\n        }\n        //printf(\"Checked for %d\\n\", l);\n        l++;\n    }\n    while(j<=j2 && l<=r && j<size){\n        if(maximum < max[j])\n            maximum = max[j];\n        l = (j+1)*size;\n        //printf(\"Checked for %d  <-->  %d\\n\", j*size, l-1);\n        j++;\n    }\n    while(l<=r){\n        if(maximum < b[l]){\n            maximum = b[l];\n        }\n        //printf(\"Checked for %d\\n\", l);\n        l++;\n    }\n    return maximum;\n}\n*/\n\n//...........................................END OF TEMPLATE.................................................................\nint a[101]={0},b[101]={0};\n\nint main()\n{ int i,j,k,t,n,d;\na[0]=b[0]=1;\n   s(n)\n   s(k)\n   s(d)\n   FOR(i,1,n+1)\n   {\n       FOR(j,1,k+1)\n       {\n           if(i-j>=0)\n           {\n               a[i]=(a[i]+a[i-j])%MOD;\n           }\n       }\n   }\n   FOR(i,1,n+1)\n   {\n       FOR(j,1,d)\n       {\n           if(i-j>=0)\n           {\n               b[i]=(b[i]+b[i-j])%MOD;\n           }\n       }\n   }\n   p((a[n]-b[n]+MOD)%MOD)\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2f5831916bb6a6470f34dcee97fb7869", "src_uid": "894a58c9bba5eba11b843c5c5ca0025d", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint modMax = 1000000007;\nint tsize = 101;\nlong long int sumWOD[tsize];\nlong long int sumWD[tsize];\n\nint n, d, k;\n\nvoid computeSumWOD(int size) {\n    sumWOD[0] = 1;\n    sumWOD[1] = 1;\n    for(int i = 2; i < size; i++) {\n        for(int j = 0; j<=k && i-j>0; j++) {\n            sumWOD[i] += sumWOD[i-j];\n            sumWOD[i] %= modMax;\n        }\n    }\n}\n\nvoid computerSumWD(int size) {\n    for(int i = 1; i < size; i++) {\n        if(i >= d) \n            sumWD[i] += sumWOD[i-d];\n        for(int j = 1; j <=k && i-j>0; j++) {\n            if(j == d)\n                continue;\n            sumWD[i] += sumWD[i-j];\n            sumWD[i] %= modMax;\n        }\n    }\n}\n\nint main () {\n    //get n, k, d\n    int n,k,d;\n    scanf(\"%d%d%d\", &n, &k, &d);\n    computerSumWOD(n+1);\n    computerSumWD(n+1);\n    printf(\"%I64d\", sumWD[n]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "562a319d12f4148fc54f282148533302", "src_uid": "894a58c9bba5eba11b843c5c5ca0025d", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nconst int modMax = 1000000007;\nconst int size = 101;\nlong long int sumWOD[size];\nlong long int sumWD[size];\n\nint n, d, k;\n\nvoid computeSumWOD(long long int *arr, int size) {\n    arr[0] = 1;\n    arr[1] = 1;\n    for(int i = 2; i < size; i++) {\n        for(int j = 0; j<=k && i-j>0; j++) {\n            arr[i] += arr[i-j];\n            arr[i] %= modMax;\n        }\n    }\n}\n\nvoid computerSumWD(long long int *arr, int size) {\n    for(int i = 1; i < size; i++) {\n        if(i >= d) \n            arr[i] += sumWOD[i-d];\n        for(int j = 1; j <=k && i-j>0; j++) {\n            if(j == d)\n                continue;\n            arr[i] += arr[i-j];\n            arr[i] %= modMax;\n        }\n    }\n}\n\nint main () {\n    //get n, k, d\n    int n,k,d;\n    scanf(\"%d%d%d\", &n, &k, &d);\n    computerSumWOD(sumWOD, n+1);\n    computerSumWD(sumWD, n+1);\n    printf(\"%I64d\", sumWD[n]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "45234be576cb673dc27d9fb0ee88c2f6", "src_uid": "894a58c9bba5eba11b843c5c5ca0025d", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nconst int modMax = 1000000007;\nconst int size = 101;\nlong long int sumWOD[size];\nlong long int sumWD[size];\n\nint n, d, k;\n\nvoid computeSumWOD(long long int arr, int size) {\n    arr[0] = 1;\n    arr[1] = 1;\n    for(int i = 2; i < size; i++) {\n        for(int j = 0; j<=k && i-j>0; j++) {\n            arr[i] += arr[i-j];\n            arr[i] %= modMax;\n        }\n    }\n}\n\nvoid computerSumWD(long long int arr, int size) {\n    for(int i = 1; i < size; i++) {\n        if(i >= d) \n            arr[i] += sumWOD[i-d];\n        for(int j = 1; j <=k && i-j>0; j++) {\n            if(j == d)\n                continue;\n            arr[i] += arr[i-j];\n            arr[i] %= modMax;\n        }\n    }\n}\n\nint main () {\n    //get n, k, d\n    int n,k,d;\n    scanf(\"%d%d%d\", &n, &k, &d);\n    computerSumWOD(sumWOD, n+1);\n    computerSumWD(sumWD, n+1);\n    printf(\"%I64d\", sumWD[n]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "63704f9931e2c74a9657f42fae7006b4", "src_uid": "894a58c9bba5eba11b843c5c5ca0025d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long dp[100][2];\n\nvoid add(long long &a, long long b)\n{\n    a += b;\n    a %= 1000000007;\n}\n\nint main()\n{\n    int n, k, d, i, j;\n    scanf(\"%d %d %d\", &n, &k, &d);\n    dp[0][0] = 1;\n    dp[0][1] = 0;\n    \n    for(i = 1 ; i <= n ; ++i)\n    {\n        dp[i][0] = dp[i][1] = 0;\n        \n        for(j = 1 ; j <= k ; ++j)\n        {\n            if(i-j < 0) break;\n            \n            if(j < d)\n            {\n                add(dp[i][0], dp[i-j][0]);\n                add(dp[i][1], dp[i-j][1]);\n            }\n            else\n            {\n                add(dp[i][1], dp[i-j][0]);\n                add(dp[i][1], dp[i-j][1]);\n            }\n        }\n    }\n    printf(\"%I64d\\n\", dp[n][1]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "631d65fe54644c3a31bc4dff08001544", "src_uid": "894a58c9bba5eba11b843c5c5ca0025d", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<conio.h>\nmain()\n{\nint l,r,a,temp,ans;\nscanf(\"%d %d %d\",&l,&r,&a);\nif(l<r)\n{  while(a>0)\n  {\n      l=l+1;\n      a=a-1;\n  }\n  if(l<=r)\n  ans=2*l;\n  else\n  {temp=l-r;\n   if(temp%2==0)\n   ans=l+r;\n   else\n   ans=l+r-1;\n  }\n}\nelse\n{\n  while(a>0)\n  {\n      r=r+1;\n      a=a-1;\n  }\n   if(l>=r)\n  ans=2*r;\n  else\n  {temp=r-l;\n   if(temp%2==0)\n   ans=l+r;\n   else\n   ans=l+r-1;\n}\nprintf(\"%d\",ans);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e3205d9b0efd4ba09316a6a9bb2912f9", "src_uid": "e8148140e61baffd0878376ac5f3857c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n   int l,r,a;\n   scanf(\"%d %d %d\",&l,&r,&a);\n   if( (l==0 && r==0)||(l==0&& a==0)||(r==0 && a==0))\n   printf(\"0\");\n   else\n   {\n       sum = l+r+a;\n       if(sum % 2 == 0)\n         printf(\"%d\",sum);\n        else\n        printf(\"%d\",sum-1);\n   }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4d489a36233c4679c27234eb0eeb6312", "src_uid": "e8148140e61baffd0878376ac5f3857c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#pragma warning(disable:4996)\n#include <stdio.h>\n#include <malloc.h>\n#include <math.h>\n#include <stdlib.h>\n#define N 100\n#define EPS 1E-5\n//#define min(a,b) (a>b) ? b : a\n/*int lol(const void *x1, const void *x2)\n{\n\treturn *(int*)x1 - *(int*)x2;\n}\nint gcd(int a, int b)\n{\n\tint c;\n\twhile (b)\n\t{\n\t\tc = a % b;\n\t\ta = b;\n\t\tb = c;\n\t}\n\treturn a;\n}*/\nint main(void)\n{\n\tint l, r, a;\n\tint i = 0, max = 0;\n\tscanf(\"%i%i%i\", &l, &r, &a);\n\tfor (i = 0; i <= a; i++)\n\t\tif ((l + i == r - (a - i) && l + i > max) || min(l + i, r - (a - i)) > max)\n\t\t\tmax = min(l + i, r - (a - i));\n\tprintf(\"%i\", max * 2);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7018436182caee8aa497c9397c1d7101", "src_uid": "e8148140e61baffd0878376ac5f3857c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n int l,r,a;\n \n scanf(\"%d%d%d\", &l,&r,&a);\n\n int t = l+r+a;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f1cb3ad60435f80aa4bae245b6caef58", "src_uid": "e8148140e61baffd0878376ac5f3857c", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<iostream>\nusing namespace std;\nint getResult(int l,int r,int a){\n\tint max,min;\n\tmax=l>r?l:r;\n\tmin=l<r?l:r;\n\tif(max-min==a)\n\t\treturn max*2;\n\tif(max-min>a)\n\t\treturn (min+a)*2;\n\tif(max-min<a)\n\t\treturn max*2+(a-max+min)/2*2;\n}\nint main(){\n\tint l,r,a;\n\tcin>>l>>r>>a\n\tcout<<getResult(l,r,a)<<endl;\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "95fa74a034ae06abd11d2dc56b0a7bfb", "src_uid": "e8148140e61baffd0878376ac5f3857c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n,k,sum=0,con=0;\n    scanf(\"%d\\n\",&n);\n    k=n/2;\n    for(;n!=k;n--){\n        if(n%10!4&&n%10!=7){printf(\"NO\");return 0;}\n        sum+=n%10;\n        n/=10;\n    }\n    for(;n!=0;n--){\n         if(n%10!4&&n%10!=7){printf(\"NO\");return 0;}\n        con+=n%10;\n        n/=10;\n    }\n    if(con!=sum)printf(\"NO\");\n    else{printf(\"YES\");}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1f48a1e8287231b4c941975c4297426e", "src_uid": "435b6d48f99d90caab828049a2c9e2a7", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nint main()\n{\n    int n,i,sum=0,flag=0;\n    scanf(\"%d\",&n);\n    char a[n+1];\n    scanf(\"%s\",a);\n    for(i=0;i<n;i++)\n    {\n        if(i<n/2)\n        {\n            sum = sum + a[i];\n            if(a[i]!= 52 && a[i]!=55)\n            {\n                printf(\"NO\");\n                flag++;\n                break;\n            }\n        }\n        else\n        {\n            sum=sum-a[i];\n            if(a[i] !=52 && a[i] !=55)\n            {\n                printf(\"NO\");\n                flag++;\n                break;\n            }\n        }\n    }\n    if(sum==0)\n    printf(\"YES\");\n    else(sum !=0 && flag==0)\n        printf(\"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d54379aedd0fd7dfb913091808a9fa59", "src_uid": "435b6d48f99d90caab828049a2c9e2a7", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <cstdio>\n#include <cmath>\n#include <ctime>\n#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nbool isLuckyTicket(const string& _Src) {\n    int m = _Src.size() >> 1;\n    string l = _Src.substr(0, m);\n    string r = _Src.substr(m, m);\n    int numl = 0, numr = 0;\n    auto lit = l.begin(), rit = r.begin();\n    while (lit != l.end() && rit != r.end()) {\n        if (*lit == '4' || *lit == '7')\n            numl += int(*lit - '0');\n        else return false;\n        if (*rit == '4' || *rit == '7')\n            numr += int(*rit - '0');\n        else return false;\n        ++lit, ++rit;\n    }\n    return (numl == numr);\n}\n\nint main() {\n    int n;\n    string ticket;\n    cin >> n >> ticket;\n    if (isLuckyTicket(ticket))\n        cout << \"YES\" << endl;\n    else cout << \"NO\" << endl;\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e5bc2dce1731bbd48d4ca8ab4ad014db", "src_uid": "435b6d48f99d90caab828049a2c9e2a7", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n\tlong double a, x, m, m1;\n\t int sum = 0, sum1 = 0;\n\tscanf(\"%Lf\", &x);\n\tscanf(\"%Lf\", &a);\n\tm = x / 2;\n\tfor (int i = 0; i < m; i++){\n\t\tm1 = a % 10;\n\t\ta = a / 10;\n\t\tif (m1 == 4 || m1 == 7)sum = sum + m1;\n\t}\n\tfor (int j = 0; j < m; j++){\n\t\tm1 = a % 10;\n\t\ta = a / 10;\n\t\tif (m1 == 4 || m1 == 7)sum1 = sum1 + m1;\n\t}\n\n\tif (sum == sum1)printf(\"YES\");\n\telse printf(\"NO\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "eb05bd40a1d4c0e53b190399515b2bf0", "src_uid": "435b6d48f99d90caab828049a2c9e2a7", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nmain()\n{int i,a=0,s=0,t=0,n,c;\nscanf(\"%d\",&n);\nfor(i=1;i<=n;i++)\n{ scanf(\"%d\",&c);\n   if    (c!=4 && c!=7)\n             a++;\n else\n       i>n/2?s+=c:t+=c;}\n   if(s==t)    \nprintf(a==0?\"YES\":\"NO\");\nelse\nputs(\"NO\");\nreturn 0;}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e6671b6145ca9d58faeae1856001ff80", "src_uid": "435b6d48f99d90caab828049a2c9e2a7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "/* 20160803 JJA Codeforces */\n#define _CRT_SECURE_NO_WARNINGS\n\n#include <stdio.h>\n#include <stdlib.h>\nint main() {\n\tint n, c;\n\tint *arrP;\n\tint *arrT;\n\tint Limak=0;\n\tint Radewoosh=0;\n\tint t;\n\tscanf(\"%d %d\", &n, &c);\n\tarrP = (int*)malloc(sizeof(int)*n);\n\tarrT = (int*)malloc(sizeof(int)*n);\n\tfor (int i = 0; i < n; i++) scanf(\"%d\", &arrP[i]);\n\tfor (int i = 0; i < n; i++) scanf(\"%d\", &arrT[i]);\n\tt = 0;\n\tfor (int i = 0; i < n; i++) {\n\t\tt += arrT[i];\n\t\tLimak += max(0,arrP[i] - (t*c));\n\t}\n\tt = 0;\n\tfor (int i = n - 1; i >= 0; i--) {\n\t\tt += arrT[i];\n\t\tRadewoosh += max(0, arrP[i] - (t*c));\n\t}\n\tif (Limak > Radewoosh) printf(\"Limak\");\n\telse if (Limak < Radewoosh) printf(\"Radewoosh\");\n\telse printf(\"Tie\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ecbcabf88d674f522e23e1a6151a25fb", "src_uid": "8c704de75ab85f9e2c04a926143c8b4a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"20160329_1\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin\\Debug\\20160329_1\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj\\Debug\\\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin\\Release\\20160329_1\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj\\Release\\\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<debugger />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "47a6501bb08bef72e614de2e105d328c", "src_uid": "8c704de75ab85f9e2c04a926143c8b4a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint max(int a, int b){\n\tif(a > b)\n\t\treturn a;\n\telse\t\n\t\treturn b;\n}\n\nint main (void){\n\tint n, c, t[1010], p[1010], score_l = 0, score_r = 0, i, j, timeR = 0, timeL = 0;\n\n\t\n\tscanf(\"%d %d\", &n, &c);\n\t\n\tfor(i = 0; i < n; i++)\n\t\tscanf(\"%d\", &p[i]);\n\t\n\tfor(i = 0; i < n; i++)\n\t\tscanf(\"%d\", &t[i]);\n\t\n\tfor(i = 0, j = n-1; i < n; i++, j--){\n\t\t//printf(\"pb : l : %d, r : %d\\n\", p[i],p[j]);\n\t\t//printf(\"c*p l : %d, c*p r : %d\\n\",p[i]-(c*t[i]),p[j]-(c*t[j]));\n\t\ttimeL += t[i];\n\t\ttimeR += t[j];\n\t\tscore_l += max(0, p[i]-c*timeL);\n\t\tscore_r += max(0, p[j]-c*timeR);\n\t}\n\t\n\t//printf(\"l  : %d\\n r : %d\\n\", score_l, score_r);\n\tif(score_l > score_r)\n\t\t\tprintf(\"Limak\\n\");\n\t\t\n\telse if(score_l < score_r)\n\t\t\tprintf(\"Radewoosh\\n\");\n\t\t\n\telse\n\t\t\tprintf(\"Tie\");\n\t\n\tfclose(infp);\n\nreturn 0;}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c8b811a75620935e3c85a51b82f21e88", "src_uid": "8c704de75ab85f9e2c04a926143c8b4a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<algorithm>\n\nusing namespace std;\n#define maxD 51\n\nint maxim(int a,int b)\n{\n    if(a>b) return a;\n    return b;\n}\n\nint main()\n{\n\n    int i,n,c,p[maxD],t[maxD],L,R;\n    L=R=0;\n    scanf(\"%d%d\",&n,&c);\n\n    for(i=0;i<n;++i)\n        scanf(\"%d\",&p[i]);\n\n    for(i=0;i<n;++i)\n        scanf(\"%d\",&t[i]);\n\n    int timp=0;\n    for(i=0;i<n;++i)\n    {\n        timp+=t[i];\n        L+=maxim(0,p[i]-c*timp);\n    }\n\n    timp=0;\n     for(i=n-1;i>=0;--i)\n    {\n        timp+=t[i];\n        R+=maxim(0,p[i]-c*timp);\n    }\n\n    if(L>R)\n        printf(\"Limak\");\n    else if(L==R)\n        printf(\"Tie\");\n    else\n        printf(\"Radewoosh\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "cf684af89efa7d9bdc27ca1a8ff309e2", "src_uid": "8c704de75ab85f9e2c04a926143c8b4a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "A. Bear and Reverse Radewoosh.c", "lang_cluster": "C", "compilation_error": true, "code_uid": "8434c51f6582340e71da8440eb4e8e23", "src_uid": "8c704de75ab85f9e2c04a926143c8b4a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <string.h>\nint main() {\n    char kelime[1000]; int i;\n    gets(kelime);\n    for(i=0;i<strlen(kelime)-2;i++) {\n        if(kelime[i]=='W' && kelime[i+1]=='U' && kelime[i+2]=='B') {\n            kelime[i]=='\\0'; && kelime[i+1]=='\\0'; && kelime[i+2]=='\\0';\n        }\n    }\n    puts(kelime);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8b5d854874ab4c0be19c7628c6f73d7f", "src_uid": "edede580da1395fe459a480f6a0a548d", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\nint main() {\n    char text[1000],fi[600],t[500];\n    int i,j,n,c=0;\n    scanf(\"%s\",&text);\n    n=strlen(text);\n    while(i<n){\n        j=0;\n        while (text[i]=='W'){\n            i+=2;\n            j=1;\n            \n        }\n        if (j==0){\n            fi[c]=text[i];\n        }\n        else\n            fi[c]=' ';\n        c++;\n        i++;\n    }\n    while (fi[0]==' '){\n        for (i=0;i<n-1;i++)\n            fi[i]=fi[i+1];\n        n--;\n    }\n    t=fi;\n    for (i=0;i<n;i++)\n        printf(\"%c\",t[i]);\n    \n    \n    return (EXIT_SUCCESS);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d86714bd1e1ab71c534c6d97420b606c", "src_uid": "edede580da1395fe459a480f6a0a548d", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<string>\nusing namespace std;\nint main(){\n    string a;\n\tint i;\n    cin>>a;\n    for(int i=0;i<a.length();i++){\n      if(i<a.length()-2){\n\t\tif(a.substr(i,3)==\"WUB\"){\n\t\t\tcout<<\" \";\n\t\t    i=i+2;\n\t\t}\n\t\telse cout<<a[i];\n      }\n      else cout<<a[i];\n\t}\n\tcout<<endl;\n\treturn 0;\n}\n\n\t\t\t  \t  \t  \t\t\t     \t\t \t  \t  \t \t", "lang_cluster": "C", "compilation_error": true, "code_uid": "adf51d77031834b3ea7460c0920fbf98", "src_uid": "edede580da1395fe459a480f6a0a548d", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include<string.h>\n\nint main()\n{\n    char s[201];\n    int i,n;\n    printf(\"donner l chine \");\n    scanf(\"%s\",s);\n    n=strlen(s);\n    for (i=0 ; i<=n ; i++){\n            if (s[i]=='W' && s[i+1]=='U' && s[i+2]=='B'){\n                  s[i]=' ';\n                  s[i+1]=' ';\n                  s[i+2]=' ';}\n    }\n    printf(\"%s\",s);\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "970afd935094767decc334a1cc0467f2", "src_uid": "edede580da1395fe459a480f6a0a548d", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nchar a[200],b[200];\nint gets(a);\nint strlen(a);\nint i,j=0,k=0;\nint len=strlen(a);\nfor(i=0;i<len;i++){\nif(a[i]==\u2019W\u2019 && a[i+1]==\u2019U\u2019 && a[i+2]==\u2019B\u2019){\ni+=2;\nk=1;\n}\nelse{\nif(k==1 && j>0){\nb[j]=\u2019 \u2018;\nj++;\n}\nb[j]=a[i];\nk=2;\nj++;\n}\n}\nb[j]=\u2019\\0\u2019;\nputs(b);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7fabd43c9dc62bd414f0a7a87b99abe9", "src_uid": "edede580da1395fe459a480f6a0a548d", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define N 100\n\n\nint main()\n{\n    __int64 n, k, ans = 0, sum = 0;\n    long i;\n    scanf(\"%I64d%I64d\", &n, &k);\n    if ((k + 2) * (k-1) / 2 - k + 2 < n){\n        puts(\"-1\");\n        return 0;\n    }\n    for (i=k; i>1; i--){\n        ans++;\n        sum += i;\n        if (sum>=n){\n            printf(\"%I64d\", ans);\n            return 0;\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ef1ff9eb1d632c0fc1f796d2953f32b6", "src_uid": "83bcfe32db302fbae18e8a95d89cf411", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\ntypedef unsigned long long int LL;\nLL highval(LL k, int digits) {\n    LL sum = 0;\n    for (int i = 0; i < digits; i++) {\n        sum += k-i;\n    }\n    return sum-digits+1;\n}\n//LL lowval(LL k, int digits) {\nLL lowval(int digits) {\n    LL sum = 0;\n    for (int i = 0; i < digits; i++) {\n        sum += i+2;\n    }\n    return sum-digits+1;\n}\n\nLL cal(LL val, LL k) {\n    int lo=0, hi=k; //val = [2..k]\n    while (hi-lo > 1) {\n    //printf(\"SHIT\\n\");\n    //printf(\"%d %d\\n\", lo, hi);\n        int mid = (hi+lo)/2;\n        LL u = highval(k, mid);\n        if (val > u)\n            lo = mid;\n        else\n            hi = mid;\n    }\n    return (val >= lowval(hi) && val <= highval(k, hi)) ? hi : -1;\n}\n\nint main() {\n    LL n, k;\n    scanf(\"%llu %llu\", &n, &k);\n    printf(\"%llu\\n\", cal(n, k));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2baad13ce1c71821cd2b594c1ca73e90", "src_uid": "83bcfe32db302fbae18e8a95d89cf411", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<iostream>\nusing namespace std;\n_int64 sum(_int64 t);\n_int64 n,k;\nint main()\n{\n\twhile(scanf(\"%I64d %I64d\",&n,&k)!=EOF)\n\t{\n\t\t_int64 left=0,right=k-1;\n\t\tint flag=0;\n\t\tif(sum(k)<n){printf(\"-1\\n\");continue;}\n\t\telse\n\t\t{\n\t\t\twhile(right-left!=1)\n\t\t\t{\n\t\t\t\t_int64 mid=(left+right)/2;\n\t\t\t\t_int64 term=sum(mid);\n\t\t\t\tif(term>n)\n\t\t\t\t\tright=mid;\n\t\t\t\telse if(term<n)\n\t\t\t\t\tleft=mid;\n\t\t\t\telse {printf(\"%I64d\\n\",mid);flag=1;break;}\n\t\t\t}\n\t\t\tif(flag==0)\n\t\t\t{\n\t\t\tif(sum(left)==n)printf(\"%I64d\\n\",left);\n\t\t\telse printf(\"%I64d\\n\",right);\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\n\n_int64 sum(_int64 t)\n{\n\t_int64 i,sum=1;\n\tfor(i=k-1;i>=k-t;i--)\n\t\tsum+=i;\n\treturn sum;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e849348319842ee3b95aa9de8f99059c", "src_uid": "83bcfe32db302fbae18e8a95d89cf411", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\nint main()\n{\n    __int64 n, k, ans = 0, sum = 0;\n    long i;\n    scanf(\"%I64d%I64d\", &n, &k);\n    if ((k + 2) * (k-1) / 2 - k + 2 < n){\n        puts(\"-1\");\n        return 0;\n    }\n    if (k==999999999&&n=1000000000){\n        puts(\"2\");\n        return 0;\n    }\n    sum = sqrt(k * k - k - 2 * n + 2.25) + 1.5;\n    if ( k * k - sum * sum + 3 * sum >= 2 * n){\n        printf(\"%I64d\", k - sum + 1);\n    }\n    else {\n        printf(\"%I64d\", k - sum + 2);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "858260ecf790d677624989b00fa6e2a0", "src_uid": "83bcfe32db302fbae18e8a95d89cf411", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(){\n    long long n, k, s, l, r, m;\n    scanf(\"%I64d%I64d\", &n, &k);\n    --n, --k;\n    s = k * (k + 1) / 2;\n    if (n > s)puts(\"-1\");\n    else {\n        for (l = 0, r = k ; l < r - 1 ;){\n            m = (l + r) / 2;\n            if (m * (m + 1) / 2 == s - n){\n               l = m;\n               break;\n            }\n            else if (m * (m + 1) / 2 < s - n)l = m;\n            else r = m;\n        }\n        printf(\"%I64d\\n\", k - l);\n    }\n    scanf(\" \");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "84cd8ac74e94af7bac01a6ade3f80e1e", "src_uid": "83bcfe32db302fbae18e8a95d89cf411", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<string.h>\n\nint main()\n{\n    long long int i,a,b,j,y,x,m,cur=0,n,t,c1,c2,n1,n2,m1,m2,te,tem,temp;\n\n    long long int sum=0,max=0,ans=0,tl=1,k,w=0,on=0,z=0,wh=0;\n\n        scanf(\"%lld\",&n);\n       a=n/1234567;\n       b=n/12345;\n        for(i=0;i<=a;i++)\n            for(j=0;j<=b;j++)\n                if((n-(i*1234567+j*12345)%1234==0)\n                    w=1;\n        if(w)\n            printf(\"YES\\n\");\n        else\n            printf(\"NO\\n\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "223f03775c9836ad6f287a0e6ce0c729", "src_uid": "72d7e422a865cc1f85108500bdf2adf2", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n\tint n,i,jsum,flag=0;\n\tscanf(\"%d\",&n);\n    for(i=0;i<1000;i++)\n    \tfor(j=0;j<1000;j++)\n    \t\t{\n    \t\t\tlong long int sum = n - 1234567*i - 123456*j;\n    \t\t\tif(sum % 1234 == 0)\n    \t\t\t\t{\n    \t\t\t\t\tflag = 1;\n    \t\t\t\t}\n       \t\t}\n\n\n    if(flag == 0)\n        printf(\"NO\\n\");\n    else\n        printf(\"YES\\n\");\n    return 0;\n}\n \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e67477956a5019885c4b6b0859f1ecff", "src_uid": "72d7e422a865cc1f85108500bdf2adf2", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n\tint ch=0;\n    long long int a=1234567;\n    long long int b=123456;\n    long long int c=1234;\n    long long int i,j;\n    for(i=0;i<=1000;i++)\n        for(j=0;j<=10000;j++)\n        {\n            long long int temp=n-a*i-b*j;\n            if(temp%1234==0 && temp>=0)\n            {\n                ch=1;\n            }\n        }\n    if(ch) printf(\"YES\\n\");\n    else printf(\"NO\\n\");\n    return 0;\n}\n \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f1a0e487ce2508483897b537ba58965d", "src_uid": "72d7e422a865cc1f85108500bdf2adf2", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n/*int count( long long int S[], int m, long long int n )\n{\n    if (n == 0)\n        return 1;\n    if (n < 0)\n        return 0;\n    if (m <=0 && n >= 1)\n        return 0;\n    return count( S, m - 1, n ) + count( S, m, n-S[m-1] );\n}*?\n/*int count( int S[], int m, int n )\n{\n    int i, j, x, y;\n    int table[n+1][m];\n    for (i=0; i<m; i++)\n        table[0][i] = 1; \n    for (i = 1; i < n+1; i++)\n    {\n        for (j = 0; j < m; j++)\n        {\n            x = (i-S[j] >= 0)? table[i - S[j]][j]: 0;\n            y = (j >= 1)? table[i][j-1]: 0;\n            table[i][j] = x + y;\n        }\n    }\n    return table[n][m-1];\n}*/\n/*int count( int S[], int m, int n )\n{\n    int table[n+1];\n    memset(table, 0, sizeof(table));\n    table[0] = 1;\n    for(int i=0; i<m; i++)\n        for(int j=S[i]; j<=n; j++)\n            table[j] += table[j-S[i]]; \n    return table[n];\n}*/\nint main()\n{\n\tint n,i,j,k;\n\tscanf(\"%d\",&n);\n\tint arr[] = {1234567,123456,1234};\n    int m = 3;\n    for(i=0;i<10;i++)\n    \tfor(j=0;j<10;j++)\n    \t\tfor(k=0;k<10;k++)\n    \t\t{\n    \t\t\tsum = 1234567*i + 123456*j + 1234*k;\n    \t\t\tif(sum == n)\n    \t\t\t\t{\n    \t\t\t\t\tprintf(\"YES\\n\");\n    \t\t\t\t\treturn 0;\n    \t\t\t\t}\n       \t\t}\n    /*if(count(arr,m,n) == 0)\n    \tprintf(\"NO\\n\");\n    else\n    \tprintf(\"YES\\n\");\n    return 0;*/\n}\n ", "lang_cluster": "C", "compilation_error": true, "code_uid": "65cf476b5d1f552fa7708809f505b192", "src_uid": "72d7e422a865cc1f85108500bdf2adf2", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nconst int a=1234567;\nconst int b=123456;\nconst int c=1234;\nint main()\n{\n\tint n;\n\tscanf(\"%i\",&n);\n\tfor(i=0;i<(n/a+1);i++)\n\t\tfor(j=0;j<(n/b+1);j++){\n\t\t\tk=n-a*i-b*j;\n\t\t\tif(!(k%1234||k<0))\n\t\t\t\tputs(\"YES\");\n\t\t\t\treturn 0;\n\t\t}\n\tputs(\"NO\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "247c08b2a80b1fd46428fef1ff10a530", "src_uid": "72d7e422a865cc1f85108500bdf2adf2", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint pow(int a,int b)\n{\n    long long x=1;\n    for(int i=1;i<=b;i++)\n        x*=a;\n    return x;\n\n}\nint n,m,s,t;\nint main()\n{\n    scanf(\"%d\",&n);\n    scanf(\"%d\",&m);\n\n    for(int i=0;i<30;i++)\n        for(int j=0;j<25;j++){\n            t=pow(2,i)*pow(3,j\n            if(t>=n && t<=m) s++;\n            if(t>m) break;\n        }\n    printf(\"%d\",s);\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ef8625b44ee3e6f85abf00ffc8224464", "src_uid": "05fac54ed2064b46338bb18f897a4411", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint MAXN=1e5+10;\nint a[MAXN];\nint main()\n{\n\tlong long i,j,k,l,r,m,n,ll,rr,lll,rrr,ans;\n\n\tscanf(\"%I64d%I64d\",&m,&n);\n\tm--;\n\tans=0;\n\tl=m;\n\tr=n;\n\tll=log2(l)+1;\n\trr=log2(r)+1;\n\tll=1<<(ll-1);\n\trr=1<<(rr-1);\n\tlll=0;\n\twhile (ll>0)\n\t{\n\t\tlll+=log2(m)/log2(3)+1;\n\t\tll>>=1;\n\t}\n\trrr=0;\n\twhile (rr>0)\n\t{\n\t\trrr+=log2(n/rr)/log2(3)+1;\n\t\trr>>=1;\n\t}\n\tans=rrr-lll;\n\tprintf(\"%I64d\",ans);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "15c53afc17ccb980658444cc557dfd3d", "src_uid": "05fac54ed2064b46338bb18f897a4411", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#include<math.h>\n\nint main(){\n\n\tint l, r;\n\tscanf(\"%d %d\", &l, &r);\n\tint count = 0;\n\tfor (int i = 0; i <= 30; i++){\n\t\tfor (int j = 0; j <= 30; j++){\n\t\t\tll ans = (ll)pow(2, i)*(ll)pow(3, j);\n\t\t\tif (ans >= l&&ans <= r)\n\t\t\t\tcount++;\n\t\t}\n\t}\n\tprintf(\"%d\\n\", count);\n\n\n//\treturn (0);\n\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "90663e9ab9686f1c3717d287d0b03bc1", "src_uid": "05fac54ed2064b46338bb18f897a4411", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<cstdio>\n#include<set>\n#include<vector>\n#include<algorithm>\n\nusing namespace std;\n\ntypedef long long LL;\n\nset<LL>s;\nvector<LL>v;\n\nvoid settable()\n{\n\ts.insert(1);\n\tset<LL>::iterator iter=s.begin();\n\tint count=1;\n\tLL temp=*iter;\n\twhile(temp<=2e9){//\ufffd\u02f4\ufffd\u04aa\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\n\t\tLL t=*iter;\n\t\ts.insert(t*2);\n\t\ts.insert(t*3);\n\t\ttemp=t*3;\n\t\titer++;\n\t}\n\titer=s.begin();\n\twhile(iter!=s.end()){\n\t\tv.push_back(*iter++);\n\t}\n/*\tfor(int i=0;i<10;i++){\n\t\tprintf(\"%d \",v[i]);\n\t}\n\tprintf(\"\\n\");*/\n}\n\n\nint main()\n{\n\tsettable();\n\tint l,r;\n\tscanf(\"%d%d\",&l,&r);\n\tint num=upper_bound(v.begin(),v.end(),r)-lower_bound(v.begin(),v.end(),l);\n\tprintf(\"%d\\n\",num);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "413670f1952fbb67e766b5114c2757e7", "src_uid": "05fac54ed2064b46338bb18f897a4411", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nusing namespace std;\n\ntypedef long long int ll;\n\nconst double pi = 3.1415926535897932384626433832795;\nconst double eps = 1e-10;\nconst int inf = 1e9;\nconst int mod = 1e9 + 7;\n\nint lg(ll x,ll y)\n{\n    int an =0;\n    while(x >= y)\n    {\n        x/=y;\n        an++;\n    }\n    return an;\n}\n\nint f(int k)\n{\n    int ans = 0,i;\n    for(i = 0;(ll)(1LL<<i) <= k;i++)\n    {\n        ans+= lg((ll)k/(1LL<<i),3LL) +1;\n    }\n    return ans;\n}\n\nint main()\n{\n\n    int l,r;\n    scanf(\"%d %d\",&l,&r);\n    printf(\"%d\\n\",f(r)-f(l-1));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c6585a1b8962b96be870502b7563ba0c", "src_uid": "05fac54ed2064b46338bb18f897a4411", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "                  #include<stdio.h>\n#include<string.h>\nint main()\n{\n    int a,b,c,i,j,q;\n    char bu[199];\n    int bi[199];\n    scanf(\"%d%d\",&a,&b)\n\n        getchar();\n        memset(bi,0,sizeof(bi));\n        scanf(\"%s\",bu);\n        for(i=0;i<a;i++)\n        {\n            if(bu[i]=='1')\n            {\n                if(i<b)\n                {\n                    for(q=0;q<i;q++)\n                    {\n                        if(bu[q]=='1')\n                        {\n                        bi[i]=bi[q]+1;\n                        break;\n                        }\n                    }\n                }\n                if(i>=b)\n                {\n                    for(q=i-b;q<i;q++)\n                    {\n                         if(bu[q]=='1')\n                        {\n                        bi[i]=bi[q]+1;\n                        break;\n                        }\n                    }\n                }\n            }\n        }\n\n         if(bi[a-1])\n         printf(\"%d\\n\",bi[a-1]);\n         else\n         printf(\"-1\\n\");\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "45d86c802282e2f5692c1a4bf4828a3d", "src_uid": "c08d2ecdfc66cd07fbbd461b1f069c9e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint f(char a[],int x,int jici,int n,int d);\nint main(){\n\tint n,d;\n\tint char s[101];\n\tscanf(\"%d%d\",&n,&d);\n\tscanf(\"%s\",s);\n\tprintf(\"%d\",f(s,1,0,n,d));\n\treturn 0;\n}\nint f(char a[],int x,int jici,int n,int d){\n\tif(x==n)return jici;\n\n\tint i;\n\tif(a[x-1]=='1')\n\tfor(i=n;i>=1;i--){\n\t\tif(a[i-1]=='1'&&(i-x<=d)f(a,x+i-x,jici+1,n,d);\n\n\t}\n\treturn jici;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "21acd22cda50102ba5946bb059bf68a3", "src_uid": "c08d2ecdfc66cd07fbbd461b1f069c9e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nusing namespace std;\n\nchar array[101];\nint arr[101];\n\nint main()\n{\n\tint n,d;\n\tscanf(\"%d%d\",&n,&d);//cin>> n>>d;\n\tint i,j;\n\tfor(i = 0 ; i < n ; i++)\n\t\tscanf(\"%s\",array);\n\tfor(i=0;i<n;i++)\n\t\tif(array[i]=='0')\n\t\t\tarr[i]=0;\n\t\telse\n\t\t\tarr[i]=1;\n\n\tint count=0;\n\tfor(i=0;i<=n-1;)\n\t{\n\t\tcount++;;\n\t\tfor(j = 1; j <= d && (i + j) < n ;j++)\n\t\t{\n\t\t\tif(arr[i+j]==1)\n\t\t\t\tmax = i+j;\n\t\t}\n\t\tif(max==i)\n\t\t\tbreak;\n\t\telse\n\t\t\ti = max;\n\t}\n\tif(i!=n-1)\n\t\tprintf(\"%d\\n\",count);//cout<<count<<endl;\n\telse \n\t\tprintf(\"-1\\n\");//cout<<\"-1\"<<endl\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5e64e9013df8560c2dc46a3e5ff7ffc6", "src_uid": "c08d2ecdfc66cd07fbbd461b1f069c9e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nusing namespace std;\n\nchar array[101];\nint arr[101];\n\nint main()\n{\n\tint n,d;\n\tscanf(\"%d%d\",&n,&d);//cin>> n>>d;\n\tint i,j;\n\tfor(i = 0 ; i < n ; i++)\n\t\tscanf(\"%s\",array);\n\tfor(i=0;i<n;i++)\n\t\tif(array[i]=='0')\n\t\t\tarr[i]=0;\n\t\telse\n\t\t\tarr[i]=1;\n\n\tint count=0;\n\tfor(i=0;i<=n-1;)\n\t{\n\t\tcount++;;\n\t\tfor(j = 1; j <= d && (i + j) < n ;j++)\n\t\t{\n\t\t\tif(arr[i+j]==1)\n\t\t\t\tmax = i+j;\n\t\t}\n\t\tif(max==i)\n\t\t\tbreak;\n\t\telse\n\t\t\ti = max;\n\t}\n\tif(i!=n-1)\n\t\tprintf(\"%d\\n\",count);//cout<<count<<endl;\n\telse \n\t\tprintf(\"-1\\n\");//cout<<\"-1\"<<endl\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6b41d8231ae9e39cdea600c04db5deb0", "src_uid": "c08d2ecdfc66cd07fbbd461b1f069c9e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "include<stdio.h>\n\nint main()\n{\n\tint n,m,i=0,j,x,y,len,num=0,d;\n\tchar s[102],ch;\n\tscanf(\"%d%d\",&n,&d);\n\tgetchar();\n\tgets(s);\n   for(j=i+d;j>=i;j--)\n   {\n   \tif(j>=n-1)\n   \t{num++;break;}\n   \telse if(s[j]=='1'&&j!=i)\n   \t{\n\t   \ti=j;\n\t   \tj=i+d+1;\n\t   \tnum++;\n\t   }\n\t   else if(j==i)\n\t   {\n   \t\tprintf(\"-1\");\n   \t\tbreak;\n   \t}\n   }\n   if(j!=i)\n   printf(\"%d\",num);\n   \n\t\n} ", "lang_cluster": "C", "compilation_error": true, "code_uid": "2b3d96e81dcfb6516ac8b3878612bc55", "src_uid": "c08d2ecdfc66cd07fbbd461b1f069c9e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nlong long int max(long long int a ,long long int b)\n{\n    return a>b?a:b;\n}\nint main()\n{\n    int n,i;\n    long long int ans=1s;\n    scanf(\"%d\",&n);\n    if(n==1)\n        ans=1;\n    else if(n==2)\n        ans=2;\n    else if (n==3)\n        ans=6;\n    else if(n%2==0)\n        {\n            for(i=1;i<=50 ;i++)\n            {\n                if(n%(n-i)==0)\n                    continue;\n                ans=max(ans,n*(n-1)*(n-i));\n            }\n        }\n    else\n        ans=(n)*(n-1)*(n-2);\n    printf(\"%lld\",ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b86959364765c8abf572c1b914aa6b50", "src_uid": "25e5afcdf246ee35c9cef2fcbdd4566e", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n;\n    long long int ans;\n    scanf(\"%d\",&n);\n    if(n=<2)\n        ans=n;\n    else if (n==3)\n        ans=6;\n    else if(n%2==0)\n        ans=(n-1)*(n-2)*(n-3);\n    else if(n%3==0)\n        ans=(n)*(n-1)*(n-2);\n    else\n        asn=(n)*(n-1)*(n-3);\n    printf(\"%lld\",ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "449573fa9e0e2a77859876e741d80806", "src_uid": "25e5afcdf246ee35c9cef2fcbdd4566e", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    if(n<3)\n    {\n        printf(\"%d\\n\",n);\n    }\n    else if(n%2==0)\n    {\n        if(((n-3)%2)!=0 || (n%3)!=0)\n        {\n           printf(\"%d\\n\",(n)*(n-1)*(n-3)); \n        }\n        else \n        {\n            printf(\"%d\\n\",(n-1)*(n-2)*(n-3))\n        }\n    }\n    else\n    {\n        printf(\"%d\\n\",(n)*(n-1)*(n-2));\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "54991dc36e5e93e0ea31cd88f3137929", "src_uid": "25e5afcdf246ee35c9cef2fcbdd4566e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long int hcf(long long int i,long long int j){\n    long long int k=1,l;\n    while(k!=0){\n        l=j;k=i%j;i=j;j=k;\n    }\n    return l;\n}\nlong long int max(long long int i,long long int j){\n    if(i>j) return i;\n    return j;\n}\nint main(){\n    long long int n,i,j,k,l;\n    scanf(\"%I64d\",&n);\n    if(n<=2){\n        printf(\"%I64d\",n);\n    }\n    else if(n%2==1){\n        l=n*(n-1)*(n-2);\n        printf(\"%I64d\",l);\n    }\n    else{\n        i=n*(n-1);l=n-2;k=l/2;\n        //printf(\"%lld\\t\",i);printf(\"%lld\\n\",l);\n        while(l>(n-2)/2){\n            j=hcf(i,l);\n            //printf(\"%lld\\n\",j);\n            if(j==1){\n                k=l;break;\n            }\n            l--;\n        }\n        l=k*i;\n        j=(n-1)*(n-2)*(n-3);\n        l=max(l,j);\n        printf(\"%I64d\",l);\n    }\n    return 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ebf623a3611f438b66fdccc95bfc228b", "src_uid": "25e5afcdf246ee35c9cef2fcbdd4566e", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint gcd(int a , int b);\nint main(void)\n{\nint i=1,n,a,b,x,y;\n\nscanf(\"%d\",&n);\na=n;\nb=(n-1>0)?n-1:1;\nx=(n-1>0)?n-1:1;\ny=(n-2>0)?n-2:1;\nif(!(n-1)) b=1;\nfor(i=n-2;i>0;i--)\n{\nif(gcd(a,i)==1&&gcd(b,i)==1)\nbreak;\n}\nfor(int j=n-3;j>0;j--)\n{\nif(gcd(x,i)==1&&gcd(y,j))\nbreak;\n}\nj=(j>0)?j:1;\ni=(i>0)?i:1;\nlong long int ans;\nif(i>j)\nans=a*b*i;\nelse\nans=x*y*j\nprintf(\"%lld\",ans);\nreturn 0;\n}\nint gcd(int a , int b)\n{\nlong long int r = (a%b==0)?b:gcd(b,a%b);\nreturn r;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "85896c38d6b7d4470203569c770935c3", "src_uid": "25e5afcdf246ee35c9cef2fcbdd4566e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "main()\n{\n    int h, m, s, a, b, max, count=0;\n    scanf(\"%d%d%d%d%d\", &h, &m, &s, &a, &b);\n    max=b;\n    if(a>max)\n    {\n        max=a;\n    }\n    if (h>=a && h<b)\n        {\n            count=count+1;\n        }\n        if (m/5>=a && m/5<b)\n        {\n            count=count+1;\n        }\n        if (s/5>=a && s/5<b)\n        {\n            count=count+1;\n        }\n        if (count==3 || count==0)\n        {\n            printf(\"\\nYES\\n\\n\");\n        }\n        else\n        {\n            printf (\"\\nNO\\n\\n\");\n        }\n    }\n    system(\"pause\");\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "7c2cdd903577e72f604712e1e5b8cc79", "src_uid": "912c8f557a976bdedda728ba9f916c95", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "main()\n{\n    int h, m, s, a, b, max, start, finish count=0;\n    scanf(\"%d%d%d%d%d\", &h, &m, &s, &a, &b);\n    max=b;\n    start=a;\n    finish=b;\n    if(a>b)\n    {\n        a=finish;\n        b=start;\n    }\n    if(h>=1 && h<=12 && m>=0 && m<=59 && s>=0 && s<=59 && a!=b)\n    {\n        if (h>=a && h<b)\n        {\n            count=count+1;\n        }\n        if (m/5>=a && m/5<b)\n        {\n            count=count+1;\n        }\n        if (s/5>=a && s/5<b)\n        {\n            count=count+1;\n        }\n        if (count==3 || count==0)\n        {\n            printf(\"\\nYES\\n\\n\");\n        }\n        else\n        {\n            printf (\"\\nNO\\n\\n\");\n        }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e43d5f3eaa3198f894d81dd7866e8487", "src_uid": "912c8f557a976bdedda728ba9f916c95", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int h,m,s,a,b;\n    do\n    {\n        scanf(\"%d %d %d %d %d\",&h,&m,&s,&a,&b);\n    }\n    while ( (h<1)||(h>12)||(m<0)||(m>59)||(s<0)||(s>59)||(a<1)||(a>12)||(b<1)||(b>12)||(a==b));\n    if ( (h>=a) && (m>=5*a) && (s>5*a) && (h<=b) && (m<=5*b) && (s<5*b))\n    {\n        printf(\"YES\");\n        found=1;\n    }\n    if  (((h>=b)||(h<=a)) && ((m>=5*b)||(m<=5*a)) && ((s>5*b)||(s<5*a)) )\n    {\n        printf(\"YES\");\n        found=1;\n    }\n    else (found==0)\n        printf(\"NO\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0b18f0e67c4ca08d6331f112f64d3c45", "src_uid": "912c8f557a976bdedda728ba9f916c95", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int h,m,s,a,b,temp;\n    float m1,s1;\n    //printf(\"Give the five integers (h,m,s,a,b)\\n\");\n    scanf(\"%d %d %d %d %d\",&h,&m,&s,&a,&b);\n    m1=m/5.0;\n    s1=s/5.0;\n    if (a>b)\n        {temp=a;\n         a=b;\n         b=temp;}\n    if ((a>=m1 && a>=s1 && a>=h) || ((a=<m1 && a=<s1 && a=<h) && (b>=m1 && b>=s1 && b>=h)))\n        printf(\"YES\\n\");\n    else printf(\"NO\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0899391e53a17225eafa90ab55d30cc6", "src_uid": "912c8f557a976bdedda728ba9f916c95", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int h,m,s,a,b,m1,s1,i,max,min,k=1;\n    scanf(\"%d %d %d %d %d\",&h,&m,&s,&a.&b);\n    m1=m/5;\n    s1=s/5;\n    max=a;\n    min=b;\n    if (a<b)\n    {\n       max=b;\n       min=a;\n    }\n    for (i=min;i<=max && k;i++)\n    {\n      if (i==h || i==m1 || i==s1)\n      {\n          k=0;\n      }\n    }\n    if (!k)\n    {\n        k=1;\n        for (i=max;i<=12 && k;i++)\n        {\n         if (i==h || i==m1 || i==s1)\n         {\n             k=0;\n         }\n        }\n        for (i=0;i<=min && k;i++)\n        {\n            if (i==h || i==m1 || i==s1)\n            {\n                k=0;\n            }\n        }\n    }\n    if (k)\n      printf(\"YES\");\n    else\n      printf(\"NO\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "79e0676e5afc3731f3f9a3258a6c5aa4", "src_uid": "912c8f557a976bdedda728ba9f916c95", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nint zero(int n){\n    int tab[5]={0,1,2,2,1,0};\n    return tab[tab%6];\n}\nint one(int n){\n    int tab[5]={1,0,0,1,2,2};\n    return tab[tab%6];\n}\nint two(int n){\n    int tab[5]={2,2,1,0,0,1};\n    return tab[tab%6];\n}\n\nint main()\n{\n\tint n,x;\n\tscanf(\"%d %d\",&n,&x);\n    if(zero(n)==x) printf(\"0\");\n    if(one(n)==x) printf(\"1\");\n    if(two(n)==x) printf(\"2\");\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f590a2aa8597a834ba0f00bdd5b640c8", "src_uid": "7853e03d520cd71571a6079cdfc4c4b0", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "shellGame.c", "lang_cluster": "C", "compilation_error": true, "code_uid": "23b9dce8970b8612df107efa636a5dd5", "src_uid": "7853e03d520cd71571a6079cdfc4c4b0", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint zero(int n){\n    int tab[5]={0,1,2,2,1,0};\n    return tab[tab%6];\n}\nint one(int n){\n    int tab[5]={1,0,0,1,2,2};\n    return tab[tab%6];\n}\nint two(int n){\n    int tab[5]={2,2,1,0,0,1};\n    return tab[tab%6];\n}\n\nint main()\n{\n\tint n,x;\n\tscanf(\"%d %d\",&n,&x);\n    if(zero(n)==x) printf(\"0\");\n    if(one(n)==x) printf(\"1\");\n    if(two(n)==x) printf(\"2\");\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f71b6864f48e3ca8e6d1f8fe651e5585", "src_uid": "7853e03d520cd71571a6079cdfc4c4b0", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n  long long int n;\n  int x,f,temp1,temp2,a,b,c;\n  scanf(\"%lld%d\",&n,&f);\nif(f==0)\n  {\n      a=1;\n      b=0;\n      c=0;\n  }\nelse if(f==1)\n  {\n      a=0;\n      b=1;\n      c=0;\n  }\nelse\n  {\n      a=0;\n      b=0;\n      c=1;\n  }\n   if(n%2==0)\n     x=n%6;\n   else\n     x=6-(n%6);\n    switch()\n    {\n    case(1)\n        temp1=b;\n        b=c;\n        c=temp1;\n        break;\n    \n    case(2)\n        temp1=b;\n        b=c;\n        c=temp1;\n        a=temp2;\n        a=c;\n        c=temp2;\n        break;\n    case(3)\n        temp1=a;\n        a=c;\n        c=temp1;\n        break;\n    case(4)\n        temp1=b;\n        b=a;\n        a=temp1;\n        temp2=c;\n        c=a;\n        a=temp2;\n        break;\n    case(5)\n        temp1=a;\n        a=b;\n        b=temp1;\n        break;\n    case(6)\n             ;\n        break;\n    default\n             ;\n        \n    }\n    if(a==1)\n    printf(\"0\");\n    else if(b==1)\n    printf(\"1\");\n    else if(c==1)\n    printf(\"2\");\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4083bd97049656ab99ae0805d020436d", "src_uid": "7853e03d520cd71571a6079cdfc4c4b0", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"\u6d4b\u8bd5\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/\u6d4b\u8bd5\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/\u6d4b\u8bd5\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3933fd86c23f5cb145d7b7c2c1630a1a", "src_uid": "7853e03d520cd71571a6079cdfc4c4b0", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    unsigned int n;\n    char c;\n    scanf(\"%d%c\",&n,&c);\n    char string[1024];\n    int numbers[100];\n    gets(string);\n    char * cp;\n    int i=0;\n    cp=strtok(string,\" \");\n    while (cp != NULL)\n    {\n        sscanf(cp,\"%d\",&numbers[i]);\n        i++;\n        cp = strtok(NULL,\" \");\n    }\n    int phase=0;\n    for (i=0;i<n;i++)\n    {\n        if(n==i+1) break;\n        if(phase==0)\n        {\n            if(numbers[i]<number[i+1]) phase=1;\n            else if(numbers[i]==number[i+1]) phase=2;\n        }\n        if (phase==1)\n        {\n            if(numbers[i]<number[i+1]) phase=1;\n            else if(numbers[i]==number[i+1]) phase=2;\n        }\n        if (phase==2)\n        {\n            if(numbers[i]==number[i+1]) phase=2;\n            else if(numbers[i]>number[i+1]) phase=3;\n        }\n        if (phase==3)\n        {\n            if(numbers[i]>number[i+1]) phase=3;\n            else phase=4;\n            \n        }\n        if (phase==4) break;\n    }\n    \n    if(phase==2 || phase==3)\n    {\n        printf(\"yes\");\n    }\n    else\n    {\n        printf(\"no\");\n    }\n    \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "39a553311131d409a0f5b5aa2806730d", "src_uid": "5482ed8ad02ac32d28c3888299bf3658", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    unsigned int n;\n    char c;\n    scanf(\"%d%c\",&n,&c);\n    char string[1024];\n    int numbers[100];\n    gets(string);\n    char * cp;\n    int i=0;\n    cp=strtok (string,\" \");\n    while (cp != NULL)\n    {\n        sscanf(cp,\"%d\",&numbers[i]);\n        i++;\n        cp = strtok (NULL, \" \");\n    }\n    int phase=0;\n    for (i=0;i<n;i++)\n    {\n        if(n==i+1) break;\n        if(phase==0)\n        {\n            if(numbers[i]<number[i+1]) phase=1;\n            else if(numbers[i]==number[i+1]) phase=2;\n        }\n        if (phase==1)\n        {\n            if(numbers[i]<number[i+1]) phase=1;\n            else if(numbers[i]==number[i+1]) phase=2;\n        }\n        if (phase==2)\n        {\n            if(numbers[i]==number[i+1]) phase=2;\n            else if(numbers[i]>number[i+1]) phase=3;\n        }\n        if (phase==3)\n        {\n            if(numbers[i]>number[i+1]) phase=3;\n            else phase=4;\n            \n        }\n        if (phase==4) break;\n    }\n    \n    if(phase==2 || phase==3)\n    {\n        printf(\"yes\");\n    }\n    else\n    {\n        printf(\"no\");\n    }\n    \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "81948479c5f4b4cf3b4f22ef7996cc8c", "src_uid": "5482ed8ad02ac32d28c3888299bf3658", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint um(int s[],int k){\nint main(){\n\tint n,i;\n\tscanf(\"%d\",&n);\n\tint a[n];\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%d\",&a[i]);\n\t}\n\tif(n==1){\n\t\tprintf(\"YES\");\n\t}\n\telse{\n\t\tint s[n-1];\n\t\tfor(i=0;i<n-1;i++){\n\t\t\ts[i]=a[i]-a[i+1];\n\t\t}\n\t\tif(um(s,n-1)){\n\t\t\tprintf(\"YES\");\n\t\t}\n\t\telse{\n\t\t\tprintf(\"NO\");}\n\t}\n\treturn 0;\n}\nint um(int s[],int k){\n\tint j,c;\n\tc=0;\n\tfor(j=0;j<k-1;j++){\n\tif(s[j]<0){\n\tif(s[j+1]<0||s[j+1]==0||s[j+1]>0){\n\tc=c+1;\t\n\t}}\n\telse{\n\tif(s[j]==0){\n\tif(s[j+1]==0||s[j+1]>0){\n\tc=c+1;\n\t}}\n\telse{\t\n\tif(s[j+1]>0){\n\tc=c+1;\n\t}}}}\n\tif(c==k-1){\n\t\treturn 1;\n\t}\n\telse{\n\t\treturn 0;\n\t}\n} }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8d5dabaf33465b628c0c987fe92149f6", "src_uid": "5482ed8ad02ac32d28c3888299bf3658", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(int argc, char **argv)\n{\n\tint k,,p,n,i;\n\tscanf(\"%d\",&n);\n\tint ar[n];\n\tp=n-1;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\",&ar[i]);\n\t}\n\tk=0;\n\twhile(ar[k]<ar[k+1] && k<n)\n\t\tk++;\n\twhile(ar[k]==ar[k+1] && k<p)\n\t\tk++;\n\twhile(ar[p]<ar[p-1] && p>0)\n\t\tp--;\n\tif(k>=p)\n\t\tprintf(\"YES\");\n\telse\n\t\tprintf(\"NO\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "002b57d088dda43c6cfc14a7ed8c4471", "src_uid": "5482ed8ad02ac32d28c3888299bf3658", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n  int n, i, p=1;\n  scanf(\"%d\", &n);\n  int a[n];\n  for (i=0; i<n; i++)\n    scanf(\"%d\", &a[i]);\n  while(a[p]>a[p-1])\n  {\n      p++;  \n  }\n  while(a[p]== a[p-1]) \n  {\n      p++;\n  }\n  while(a[p]<a[p-1])\n  {\n      p++\n  }\n  if (p<=n-1)\n    printf(\"NO\");\n  else\n    printf(\"YES\");\n return 0 ;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "69f4b5680ba95da662f5b20c2d7c66f3", "src_uid": "5482ed8ad02ac32d28c3888299bf3658", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\nint x;\nscanf(\"%d\",&x);\nwhile(x>=10 && x<=999)\n{\nif(x%2==0)\n{\nprintf(\"0\");\n}\nif(x%2==1)\n{\nprintf(\"1\");\n}\nbreak;\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "56aba34251116f8af06cbbb279ddef01", "src_uid": "78e64fdbf59c5ce89d0f0a1d0591f795", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "403baf4a9eb07f59ff5dd1b1f8381083", "src_uid": "78e64fdbf59c5ce89d0f0a1d0591f795", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n    int n;scanf(\"%d\",&n);if(n%2==0)printf(\"0\")else printf(\"1\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "231c09590120fc475ab2ebf2263006da", "src_uid": "78e64fdbf59c5ce89d0f0a1d0591f795", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "include<stdio.h>\nint main()\n{\n    int a;\n    printf(\"Enter the number :\");\n    scanf(\"%d\",&a);\n \n    \n  if(a%2==0)\n    printf(\"0\");\n  if(a%2!=0)\n     printf(\"1\");\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0f01fdbd60cfa372fd98955b30927c69", "src_uid": "78e64fdbf59c5ce89d0f0a1d0591f795", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#inlcude<stdio.h>\nint main()\n{\nint i,j,x,y,a,b,sum,n;\nwhile(scanf(\"%d\",&n)==1)\n{\nfor(j=1;j<=n;j++)\n{\nscanf (\"%d%d\",%a,%b);\nsum=0;\nif(a%2==0)\na=a+1;\nif(b%2==0)\nb=b-1;\nfor(i=a;i<=b;i=i+2)\nsum=sum+i;\nprinft(\"case %d: %d\\n\",j,sum);\n}\n}\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b6734e7684d52ffba1da4ae1bf38f69d", "src_uid": "78e64fdbf59c5ce89d0f0a1d0591f795", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n,m,mx,mn;\n    int i,j,k,l,data[200],c1=0;\n\n    scanf(\"%d %d %d %d\",&n,&m,&mn,&mx);\n\n    for(i=0;i<m;i++){\n            scanf(\"%d\",&data[i]);\n    }\n\n    if(n<=2){\n        for(i=0;i<m;i++){\n            if(data[i] == mn || data[i] == mx){\n                c1 = 1;\n            }\n            else{\n                c1 = 0;\n                break;\n            }\n        }\n        if(c1==1){\n            printf(\"Correct\\n\");\n        }\n        else{\n            printf(\"Incorrect\\n\");\n        }\n    }\n\n    else{\n        for(i=0;i<m;i++){\n            if(data[i] >= mn && data[i] <= mx){\n                c1 = 1;\n            }\n            else{\n                c1 = 0;\n                break;\n            }\n        }\n        if(c1==1){\n            printf(\"Correct\\n\");\n        }\n        else{\n            printf(\"Incorrect\\n\");\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5e5d383053a5ed4da8afb4553b7670cc", "src_uid": "99f9cdc85010bd89434f39b78f15b65e", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int n, m, m1, m2, c1 = 0, c2 = 0, i;\n    \n    scanf(\"%d %d %d %d\", &n, &m, &m1, &m2);\n    \n    for (i = 0; i < m; i++) {\n        int x;\n        \n        scanf(\"%d\", &x);\n        \n        if (x == m1) c1 = 1;\n        if (x == m2) c2 = 1;\n    }\n    \n    if (n - m >= 2 - c1 - c2) {\n        puts(\"Correct\");\n    } else {\n        puts(\"Incorrect\");\n    }\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "342899f3da304239dca4cdd69b2c5267", "src_uid": "99f9cdc85010bd89434f39b78f15b65e", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,m,min,max,a[200],flag,i,flagmin=0,flagmax=0;\n    scanf(\"%d %d %d %d\",&n,&m,&min,&max);\n    flag=2;\n    for(i=0;i<m;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        if(a[i]==min)\n        flag--;\n        else if(a[i]==max)\n        flag--;\n        else if(a[i]<min&&flagmin==0)\n        {\n            flag++;\n            flagmin=1;\n        }\n        else if(a[i]>max&&flagmax==0)\n        {\n            flag++;\n            flagmax=1;\n        }\n    }\n    if(flag<0)\n    flag=0;\n    if(flag>2)\n    flag=2;\n    if(flag==0||(n-m)>=flag)\n    printf(\"Correct\");\n    else\n    printf(\"Incorrect\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "15f52aa0961fb04a57e2c36ec62fd237", "src_uid": "99f9cdc85010bd89434f39b78f15b65e", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\n#define N 110\nint a[N];\nint main(){\n   int n,m,min,max;\n   while(~scanf(\"%d%d%d%d\",&n,&m,&min,&max)){\n   \t  int i=0,min1=101,max1=-1;\n   \t  for(i;i<m;i++){\n   \t\tscanf(\"%d\",&a[i]);\n   \t\tif(a[i]<min1)\n   \t\tmin1=a[i];\n   \t\tif(a[i]>max1)\n   \t\tmax1=a[i];\n\t   }\n\t   int t=-1;\n\t   int x=n-m;\n\t   if(x>=2)\n\t   printf(\"Correct\\n\");\n\t   else if(max1>max||min1<min)\n\t   printf(\"Incorrect\\n\");\n\t   else if(x==0)\n\t   {\n\t   \tfor(i=0;i<m;i++){\n\t   \t\tif(a[i]==max)\n\t   \t\tt++;\n\t   \t\tif(a[i]==min)\n\t   \t\tt++;\n\t   \t\tif(t==1){\n\t   \t\t\t\tprintf(\"Correct\\n\");break;\n\t\t\t   }\n\t   \t\n\t   \t}\n\t   \tif(t!=1)\n\t   \tprintf(\"Incorrect\\n\");\n\t   }\n\t   else if(x==1){\n\t   \tfor(i=0;i<m;i++){\n\t   \t\tif(a[i]==max){\n\t   \t\t\t\n\t   \t\t\tif(min<=min1){\n\t   \t\t\t\tt++;printf(\"Correct\\n\");break;\n\t\t\t\t   }\n\t   \t\t\t\n\t\t\t   }\n\t   \t\t\n\t   \t\telse if(a[i]==min){\n\t   \t\t\t\t\n\t   \t\t\tif(max>=max1){\n\t   \t\t\t\tt++;\tprintf(\"Correct\\n\");break;\n\t\t\t\t   }\n\t   \t\t\n\t\t\t   }\n\t   \t\t\n\t   \t\t\n\t\t   \n\t\t   \n\t   }\n\t   if(t==-1)\n\t   \tprintf(\"Incorrect\\n\");\n   }\n \n}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "77a1cc36470150a6e2e7af8cc43b411b", "src_uid": "99f9cdc85010bd89434f39b78f15b65e", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\nint n,m,min1,max1,i,arr[105],flag1=-1,flag2=-1,h=-1,y=-1;\nscanf(\"%d%d%d%d\",&n,&m,&min1,&max1);\nfor(i=0;i<m;i++){\n    scanf(\"%d\",&arr[i]);\n     if(arr[i]==min1)\n        flag1=1;\n     if(arr[i]<min1)\n            h=1;\n     if(arr[i]==max1)\n        flag2=1;\n     if(arr[i]>max1)\n        y=1;\n       }\n\n  if(n-m==1&&(flag1==1||flag2==1))\n        printf(\"Correct\\n\");\n  \n  else if(n-m>1&&(h=1||y=1))\n        printf(\"Incorrect\");\n  \n  else if(n-m==1&&(flag1!=1||flag2!=1))\n            printf(\"Incorrect\\n\");\n\n\n\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0d8c4501ef675145ddd19ef139ef7efa", "src_uid": "99f9cdc85010bd89434f39b78f15b65e", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nlong long int NOD(long long int n1, long long int n2)\n{\n  long long int div;\n  if (n1 == n2)  return n1;\n  long long int d = n1 - n2;\n  if (d < 0) {\n    d = -d;  div = NOD(n1, d);\n  } else\n    div = NOD(n2, d); \n  return div;\n}\n\nlong long int NOK(long long int n1, long long int n2) \n{ \n  return n1*n2 / NOD(n1, n2); \n}\n\n\nint main()\n{\n  long long int x, y, a, b, res = 0;\n  scanf (\"%I64d %I64d %I64d %I64d\", &x, &y, &a, &b);\n  n = NOK(x, y);\n  while (a % n != 0) a++;\n  while (b % n != 0) b--;\n  res = (b - a) / n + 1; \n  printf(\"%I64d\", res);\n  return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7f2fefc85a6208f1ea8933b906c9bb7e", "src_uid": "c7aa8a95d5f8832015853cffa1374c48", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<conio.h>\n\nint main(){\nlong long  x,y,a,b,count=0;\nscanf(\"%I64d\",&x);\nscanf(\"%I64d\",&y);\nscanf(\"%I64d\",&a);\nscanf(\"%I64d\",&b);\nfor(long long  i = a ; i <= b ; i++)\n{\n      //  printf(\"i %d\\n\",i);\n   if( (i%x == 0) && (i%y == 0) )\n      {\n            //printf(\"1\");\n            count = count + 1;\n      }\n}\nprintf(\"%I64d\",count);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "307232f91a835493c54ed62e7856ab8e", "src_uid": "c7aa8a95d5f8832015853cffa1374c48", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint gcd(int x, int y) {\n    if (y == 0)\n        return x;\n    return gcd(y, x % y);\n}\n\nint solve(int x, int y, int max) {\n    long long lcm = 1LL * x * y;\n    lcm = lcm / gcd(x, y);\n    return max / lcm;\n}\n\nint main() {\n    int x, y, a, a;\n    scanf(\"%d%d%d%d\", &x, &y, &a, &a);\n    printf(\"%d\", solve(x, y, b) - solve(x, y, a - 1));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fa780d671ddefa224755b167df67bba8", "src_uid": "c7aa8a95d5f8832015853cffa1374c48", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void){\n    int i, x, y, a, b, c=0, mcm;\n    scanf(\"%d %d %d %d\", &x, &y, &a, &b);\n    for(mcm=x; mcm<=b; i++){\n        if(mcm%x == 0 && mcm%y == 0){\n            break;\n        }\n    }\n    \n    for(i=a; i<=b, i++){\n        if(i%mcm == 0)\n            break;\n    }\n    \n    for(; i<=b; i+mcm)\n        c++;\n   \n    printf(\"%d\", c);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e82417a51e00edc57fcd9fff9ebf06de", "src_uid": "c7aa8a95d5f8832015853cffa1374c48", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define M 1500000\nint main()\n{\n    //freopen(\"in.txt\",\"r\",stdin);\n    int i,j,n;\n    bool p[M]={0};\n    for(i=2;i<=M;i++)\n    {\n        if(p[i]==0)\n        {\n             for(j=i+i;j<=M;j=i+j)\n               p[j]=1;\n        }\n    }\n    scanf(\"%d\",&n);\n    printf(\"2\");\n    for(i=3,j=1;j<n;i++)\n        if(p[i]==0)\n        {\n            printf(\" %d\",i);\n            j++;\n        }\n    printf(\"\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2a965ca96f3c9f0c63452a6b3f0a0220", "src_uid": "c7aa8a95d5f8832015853cffa1374c48", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include \"stdio.h\"\n#include \"stdlib.h\"\nvoid main()\n{\n    int numCard, numPerson, i, sum = 0, sumForPerson, cardIdx1, cardIdx2;\n    int a[100];\n    int coupleIdx = 0, start = 0, tmp;\n\n  //  printf(\"\\n Nhap n:\");\n    scanf(\"%d\", &numCard);\n\n    if (numCard < 2 || numCard > 100 || (numCard%2) != 0)\n    {\n        return;\n    }\n\n    for (i = 0; i < numCard; i++)\n    {\n      //  printf(\"\\n Nhap a[%d]:\", i);\n        scanf(\"%d\", &a[i]);\n\n        if (a[i] < 1 || a[i] > 100)\n        {\n            return;\n        }\n    }\n\n    for (i = 0; i < numCard; i++)\n    {\n        sum += a[i];\n       // printf(\"\\n sum: %d\", sum);\n    }\n\n    numPerson = numCard>>1;\n\n    if (sum % numPerson != 0)\n    {\n        return;\n    }\n    sumForPerson = sum/numPerson;\n\n  //  printf(\"\\n numPerson: %d\", numPerson);\n\n    while(coupleIdx < numPerson)\n    {\n       // printf(\"\\n start: %d...\", start);\n        if (a[start] == -1)\n        {\n            start++;\n        }\n\n        for (i = start + 1; i < numCard; i++)\n        {\n            if (a[i] != -1 && a[start] != -1 &&(a[start] + a[i]) == sumForPerson)\n\n                if (a[start] > a[i])\n                {\n                    printf(\"\\n %d %d\", i+1, start+1);\n                }\n                else\n                {\n                    printf(\"\\n %d %d\", start+1, i+1);\n                }\n\n                a[i] = -1;\n                start++;\n                coupleIdx++;\n               // printf(\"\\n Start: %d, couple: %d\", start, coupleIdx);\n\n                break;\n            }\n        }\n    }\n\n\n\n\n return;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4f1da69f6ccb2f5336cc8697c05523bc", "src_uid": "6e5011801ceff9d76e33e0908b695132", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nmain()\n{\n    int n,i,j,tmp,k,var;\n    scanf(\"%d\",&n);\n    int a[n+1],y[n+1];\n    for(k=1;k<=n;k++)\n    {\n        scanf(\"%d\",&a[k]);\n    }\n    for(m=1;m<=n;m++)\n    {\n        y[m]=m;\n    }\n    \n    for(i=1;i<=n;i++)\n    {\n        for(j=1;j<n;j++)\n        {\n            if(a[i]>a[j])\n            {\n                tmp=a[i];\n                a[i]=a[j];\n                a[j]=tmp;\n                var=y[i];\n                y[i]=y[j];\n                y[j]=var;\n            }\n        }\n    }\n    for(i=1;i<=(n/2);i++)\n    {\n        printf(\"%d %d\\n\",y[i],y[n-i+1]);\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "46b1ce8cf156d25a69ef1f4cafddf522", "src_uid": "6e5011801ceff9d76e33e0908b695132", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <conio.h>\nvoid main()\n{ int n,i,j;n=scanf(\"%d\",&n);int s=0;\n  int arr[100];\n for(i=0;i<n;i++)\n { scanf(\"%d\",&arr[i]);s=s+arr[i];\n }\n int a=(sum*2)/n;\n for(i=0;i<n;i++)\n {\n   for(j=i;j<n;j++)\n     { if(((arr[i]+arr[j])==a)&&(arr[i]>=0)&&(arr[i]>=0))\n       {printf(\"%d   %d\",i,j);\n         arr[i]=-1;arr[j]=-1;break;\n\t }}\n }getch();\t \n\t }\n\t \n\t \n         \n \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ce3a23c96e9fb8f5d82fcaeb0835299e", "src_uid": "6e5011801ceff9d76e33e0908b695132", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int s[111],i,j,sum,ave,n;\n    bool vis[111];\n    while(scanf(\"%d\",&n)!=EOF)\n    {\n        sum=0;\n        memset(vis,false,sizeof(vis));\n        for(i=1;i<=n;i++)\n        {\n            scanf(\"%d\",&s[i]);\n            sum+=s[i];\n        }\n        ave=sum/n*2;\n\n        for(i=1;i<=n;i++)\n        {\n            if(vis[i]==false)\n            {\n                for(j=i+1;j<=n;j++)\n                    if(s[i]+s[j]==ave&&vis[j]==false)\n                {\n                    printf(\"%d %d\\n\",i,j);\n                    vis[j]=true;\n                    vis[i]=true;\n                    break;\n                }\n            }\n        }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ddfffe0aa4dee86911cf219a26b3e2f7", "src_uid": "6e5011801ceff9d76e33e0908b695132", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int a[100],n,i,j,k=0,l,c,s=0;\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        s=s+a[i];\n    }\n    c=s/(n/2);\n    for(i=1;i<=n;i++)\n    {\n        for(j=i+1;j<=n;j++)\n        {\n            if((a[i-1]+a[j-1])==c)\n            {\n                printf(\"%d %d\\n\",i,j);\n                a[j-1]=0;\n                break;\n            }\n        }\n    }", "lang_cluster": "C", "compilation_error": true, "code_uid": "b86ba466be1bef4e09e5ff941952c19c", "src_uid": "6e5011801ceff9d76e33e0908b695132", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long int power(int base,int exponent)\n{\n    int i;\n    long long int res=1;\n    for(i=0;i<exponent;i++)\n        res*=base;\n    return res;\n}\n\nint sum(long long int n)\n{\n    int ans = 0;\n    while(n>0){\n        ans += n%10;\n        n/=10;\n    }\n    return ans;\n}\n\nvoid function(int a,int b,int c)\n{\n    int i,count=0,s;\n    long long int res;\n    int arr[100]={0};\n    for(i=1;i<=72;i++){\n        res = power(i,a);\n        res *=b;\n        res += c;\n        if((res<=0)||(res>1000000000))\n            continue;\n        s = sum(res);\n        if(s==i){\n            arr[count] = (int)res;\n            count +=1;\n        }\n    }\n    printf(\"%d\\n\",count);\n    for(i=0;i<count;i++)\n        printf(\"%d \",arr[i]);\n    printf(\"\\n\");\n}\n\nint main(void)\n{\n    int a,b,c;\n    scanf(\" %d %d %d\",&a,&b,&c);\n    function(a,b,c);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f7121b21f6a5b086ee14842b07a24d46", "src_uid": "e477185b94f93006d7ae84c8f0817009", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nlong long int cons=1000000000;\n\nlong long int power(long long int a, long long int b)\n{\n    long long int i,t=1;\n\tfor(i=0;i<b;i++)\n\t{\n\t\tt*=a;\n\t}\n\treturn t;\n}\n\nlong long int dsum(long long int a)\n{\n\tlong long int i=0;\n\twhile(a>0)\n\t{\n\t\ti+=a%10;\n\t\ta/=10;\n\t}\n\treturn i;\n}\n\nint main() {\n\tlong long int a,b,c,n,i,j=0,t=0,arr[100],k=0;\n\tscanf(\"%lld %lld %lld\",&a,&b,&c);\n\tfor(i=1;i<=72;i++)\n\t{\n\t\tt=(b*power(i,a))+c;\n        //printf(\"%lld %lld %lld\\n\",i,a,power(i,a));\n\t\tif((t<=cons)&&(t>=0))\n\t\t{\n\t\t\tif(dsum(t)==i)\n\t\t\t{\n\t\t\t\tarr[k]=t;\n\t\t\t\tj++;\n\t\t\t\tk++;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%lld\\n\",j);\n\tfor(i=0;i<k;i++)\n\t{\n\t\tprintf(\"%lld \",arr[i]);\n\t}\n\tprintf(\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "33dbb6bb625c2fda9810a490491c2fd5", "src_uid": "e477185b94f93006d7ae84c8f0817009", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long int arr[1000250];\nint main()\n{\n    long long int n,a,b,c,s,num,p,p1,i,d,sum=0,flag=0,k,ctr=0;\n    scanf(\"%I64d%I64d%I64d\",&a,&b,&c);\n    for(s=1;s<=82;s++)\n    {\n        num=1;\n        for(i=1;i<=a;i++)\n        {\n        num=num*s;\n        }\n        p=b*num+c;\n        //printf(\"%d \\n\",p);\n        p1=p;\n        sum=0;\n        while(p1>0)\n        {\n            d=p1%10;\n            sum+=d;\n            p1=p1/10;\n\n        }\n        if(sum==s){flag=1;arr[ctr++]=p;\n            //printf(\"%I64d \",p);\n\n    }}\nprintf(\"%d\\n\",ctr);\nfor(k=0;k<ctr;k++)\n    printf(\"%d \",arr[k]);\n//if(!flag)\n  //  printf(\"0\");\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "62ea1b9ad132c26eefcfa83382b6ae14", "src_uid": "e477185b94f93006d7ae84c8f0817009", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\ntypedef __int64 LL_t;\n\nLL_t Pow(LL_t i, LL_t n)\n{\n    LL_t ret = 1;\n    while(n--)\n    {\n        ret *= i;\n    }\n    return ret;\n}\n\nLL_t Fun(LL_t Num)\n{\n    LL_t ret = 0;\n    while(Num)\n    {\n        ret += Num%10;\n        Num /= 10;\n    }\n    return ret;\n}\n\nint main()\n{\n    LL_t A, B, C, i, Cnt;\n    LL_t Data[100];\n    scanf(\"%I64d %I64d %I64d\", &A, &B, &C);\n    for(Cnt=0, i=1; i<82; ++i)\n    {\n        if(Fun(Pow(i, A)*B+C) == i)\n        {\n            Data[Cnt++] = Pow(i, A)*B+C;\n        }\n    }\n    printf(\"%I64d\\n\", Cnt);\n    for(i=0; i<Cnt; ++i)\n    {\n        printf(\"%I64d \", Data[i]);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d0a0b7fc805c4334fb9817b59ccc9c5d", "src_uid": "e477185b94f93006d7ae84c8f0817009", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "/*interface*/\n#include<stdio.h>\n#include<math.h>\n/*interface implementation*/\nlong long power(long long x,int a) {\n    int i;\n    long long prod=1;\n    for(i=0; i<a; i++) {\n        prod*=x;\n    }\n    return prod;\n}\nint s(int n) {\n    int sum=0;\n    while(n>0) {\n        sum+=(n%10);\n        n=n/10;\n    }\n    return sum;\n}\n/*client*/\nint main() {\n    //\u56e0\u4e3ax\u662f1\u523010^9\u4e4b\u95f4\u7684\u6574\u6570\uff0c\n    //\u6240\u4ee5s(x)\u7684\u6700\u5c0f\u503c\u662f1\uff0c\u6700\u5927\u503c\u662f9*8\n    long long a,b,c;\n    scanf(\"%Ld%Ld%Ld\",&a,&b,&c);\n    int rn=0;\n    int record[9*8+1];\n    long long sx;\n    for(sx=1; sx<=9*8; sx++) {\n        //\u53d6\u6d88\u5bf9pow\u7684\u4f7f\u7528\uff01\n        long long x=b*power(sx,a)+c;\n        if(x<1000000000) {\n            if(s(x)==sx) {\n                //if(fabs(s(x)-sx)<0.0000001) {\n                //printf(\"s(%Ld)=%Ld=%d\\n\",x,sx,s(x));\n                //\u8fd9\u91cc\u4e0d\u8bb0\u5f5510^9\u4ee5\u4e0a\u7684\uff0c\u6211\u7684\u5224\u65ad\u662f\u5bf9\u7684\uff01\n                record[rn]=x;\n                rn++;\n            }\n        }\n    }\n}\nprintf(\"%d\\n\",rn);\nint i;\nfor(i=0; i<rn; i++) {\n    printf(\" %d\",record[i]);\n}\nprintf(\"\\n\");\n//printf(\"%Ld\\n\",(long long)(9998*50*50*50*50*50+9998));\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5d3d0c17678b71adf4b7b6f1e6add04b", "src_uid": "e477185b94f93006d7ae84c8f0817009", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n\t { int x[100],y[100],l[100],t,i,j;\n\t\t for(i=0;i<3;i++)\n\t\t\t  scanf(\"%d%d\",&x[i],&y[i]);\n\t\t t=0;\n\t\t for(j=0;j<13;j++)\n\t\t\t  {   if(j!=0 && j<4)\n\t\t\t\t  { x[j-1]--;\n\t\t\t\t\t  if(j>1)\n\t\t\t\t\t  x[j-2]++; }\n                                 if(j>3 && j<=6 )\n\t\t\t\t {  x[j-2]++;\n\t\t\t\t\t y[j-4]--;\n\t\t\t\t\t if(j>4)\n\t\t\t\t\t\t y[j-5]++; }\n                               if( j>6 && j<=9) \n                                         { y[j-5]++;\n\t\t\t\t\t\t y[j-7]++;\n                                                   if(j>7)\n                                                         y[j-8]--; }\n\n                                if(j>9) \n                                       { x[j-8]++;\n\t\t\t\t\t       y[j-9]--;\n                                              if(j>10)\n                                                           x[j-11]--; }\n\n      \t l[0]=(x[1]-x[0])*(x[1]-x[0]) + (y[1]-y[0])*(y[1]-y[0]);\n\t l[1]=(x[2]-x[1])*(x[2]-x[1]) + (y[2]-y[1])*(y[2]-y[1]);       \n       \t l[2]=(x[2]-x[0])*(x[2]-x[0]) + (y[2]-y[0])*(y[2]-y[0]);\t          \n                    if(l[0]!=0 && l[1]!=0 && l[2]!=0 )\n                     {    if (l[0] + l[1]==l[2]) \n\t\t          t=1;\n\t\t\n                     if (l[1] + l[2]==l[0])\n\t\t     t=1;\n\t\t\n                        if (l[0] + l[2]==l[1])\n\t\t\t  t=1;\n\t\t\n                        if(t==1 && j==0)\n\t\t\t{printf(\"RIGHT\");\n\t\t\t\tbreak; }\n\t\t       if(t==1)\n\t\t       {printf(\"ALMOST\",);\n\t\t\t       \n\t                 break; }\n\t              }\t       \n\n\t\t\t  }\n\n\t\t if(t==0)\n\t\t\t printf(\"NEITHER\");\n\n\t\t return 0; }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4cd2abdbd85da867ee575e4eb3601340", "src_uid": "8324fa542297c21bda1a4aed0bd45a2d", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <algorithm>\nusing namespace std;\nint a[3],b[3],c[3],d[3],e[3],f[3],g[3],h[3],i[3],j[3],k[3],l[3],m[3];\nint main()\n{\n    int x1,y1,x2,y2,x3,y3;\n    while(~scanf(\"%d %d %d %d %d %d\",&x1,&y1,&x2,&y2,&x3,&y3))\n    {\n        a[0]=(x1-x2)*(x1-x2)+(y1-y2)*(y1-y2);\n        a[1]=(x2-x3)*(x2-x3)+(y3-y2)*(y3-y2);\n        a[2]=(x1-x3)*(x1-x3)+(y1-y3)*(y1-y3);\n        b[0]=(x1-x2-1)*(x1-x2-1)+(y1-y2)*(y1-y2);\n        b[1]=(x2-x3)*(x2-x3)+(y3-y2)*(y3-y2);\n        b[2]=(x1-1-x3)*(x1-1-x3)+(y1-y3)*(y1-y3);\n        c[0]=(x1-x2)*(x1-x2)+(y1-y2-1)*(y1-y2-1);\n        c[1]=(x2-x3)*(x2-x3)+(y3-y2)*(y3-y2);\n        c[2]=(x1-x3)*(x1-x3)+(y1-y3-1)*(y1-y3-1);\n        d[0]=(x1-x2+1)*(x1-x2+1)+(y1-y2)*(y1-y2);\n        d[1]=(x2-x3-1)*(x2-x3-1)+(y3-y2)*(y3-y2);\n        d[2]=(x1-x3)*(x1-x3)+(y1-y3)*(y1-y3);\n        e[0]=(x1-x2)*(x1-x2)+(y1-y2+1)*(y1-y2+1);\n        e[1]=(x2-x3)*(x2-x3)+(y3-y2+1)*(y3-y2+1);\n        e[2]=(x1-x3)*(x1-x3)+(y1-y3)*(y1-y3);\n        f[0]=(x1-x2)*(x1-x2)+(y1-y2)*(y1-y2);\n        f[1]=(x2-x3+1)*(x2-x3+1)+(y3-y2)*(y3-y2);\n        f[2]=(x1-x3+1)*(x1-x3+1)+(y1-y3)*(y1-y3);\n        g[0]=(x1-x2)*(x1-x2)+(y1-y2)*(y1-y2);\n        g[1]=(x2-x3)*(x2-x3)+(y3-y2)*(y3-y2);\n        g[2]=(x1-x3)*(x1-x3)+(y1-y3+1)*(y1-y3+1);\n        h[0]=(x1-x2+1)*(x1-x2+1)+(y1-y2)*(y1-y2);\n        h[1]=(x2-x3)*(x2-x3)+(y3-y2)*(y3-y2);\n        h[2]=(x1-x3+1)*(x1-x3+1)+(y1-y3)*(y1-y3);\n        i[0]=(x1-x2)*(x1-x2)+(y1-y2+1)*(y1-y2+1);\n        i[1]=(x2-x3)*(x2-x3)+(y3-y2)*(y3-y2);\n        i[2]=(x1-x3)*(x1-x3)+(y1-y3+1)*(y1-y3+1);\n        j[0]=(x1-x2-1)*(x1-x2-1)+(y1-y2)*(y1-y2);\n        j[1]=(x2-x3+1)*(x2-x3+1)+(y3-y2)*(y3-y2);\n        j[2]=(x1-x3)*(x1-x3)+(y1-y3)*(y1-y3);\n        k[0]=(x1-x2)*(x1-x2)+(y1-y2-1)*(y1-y2-1);\n        k[1]=(x2-x3)*(x2-x3)+(y3-y2-1)*(y3-y2-1);\n        k[2]=(x1-x3)*(x1-x3)+(y1-y3)*(y1-y3);\n        l[0]=(x1-x2)*(x1-x2)+(y1-y2)*(y1-y2);\n        l[1]=(x2-x3-1)*(x2-x3-1)+(y3-y2)*(y3-y2);\n        l[2]=(x1-x3-1)*(x1-x3-1)+(y1-y3)*(y1-y3);\n        m[0]=(x1-x2)*(x1-x2)+(y1-y2)*(y1-y2);\n        m[1]=(x2-x3)*(x2-x3)+(y3-y2+1)*(y3-y2+1);\n        m[2]=(x1-x3)*(x1-x3)+(y1-y3-1)*(y1-y3-1);\n        sort(a,a+3);sort(b,b+3);sort(c,c+3);sort(d,d+3);sort(e,e+3);sort(f,f+3);sort(g,g+3);\n        sort(h,h+3);sort(i,i+3);sort(j,j+3);sort(k,k+3);sort(l,l+3);sort(m,m+3);\n        if(a[0]+a[1]==a[2])\n            puts(\"RIGHT\");\n        else if((b[0]+b[1]==b[2])||(c[0]+c[1]==c[2])||(d[0]+d[1]==d[2])||(e[0]+e[1]==e[2])||(f[0]+f[1]==f[2])||(g[0]+g[1]==g[2])||(h[0]+h[1]==h[2])||(i[0]+i[1]==i[2])||(j[0]+j[1]==j[2])||(k[0]+k[1]==k[2])||(l[0]+l[1]==l[2])||(m[0]+m[1]==m[2]))\n        puts(\"ALMOST\");\n        else\n        puts(\"NEITHER\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e5e7d08d8218022d5318fac92c6c702d", "src_uid": "8324fa542297c21bda1a4aed0bd45a2d", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\ntypedef struct p{\n\tint x, y;\n}ponto;\n\n// retorna o angulo no v\u00e9rtice \"a\"\nfloat isRightAngle(ponto a, ponto b, ponto c){\n\tif( (a.x == b.x && a.y == b.y) ||\n\t\t(p1.x == c.x && p1.y == c.y) ||\n\t\t(b.x == c.x && b.y == c.y) ){\n\t\treturn 0;\n\t}\n\n\tint del_x1 = (b.x - a.x),\n\t\tdel_x2 = (c.x - a.x),\n\t\tdel_y1 = (b.y - a.y),\n\t\tdel_y2 = (c.y - a.y);\n\n\treturn (del_x1*del_x2 + del_y1*del_y2) == 0;\n}\n\n// triangulo, t, \u00e9 um vetor de pontos\nint check(ponto *t){\n\tif(isRightAngle(t[0], t[1], t[2]) ||\n\t\tisRightAngle(t[1], t[0], t[2]) ||\n\t\tisRightAngle(t[2], t[1], t[0]))\n\t\treturn 0;\n\n\tint i;\n\tponto triangulos[12]; // cont\u00e9m as 4 configura\u00e7\u00f5es poss\u00edvels para o triangulo em cada ponto\n\t// circula os inteiros vizinhos, come\u00e7ando \u00e0 esquerda, sentido antihor\u00e1rio\n\tfor (i = 0; i < 3; i++){\n\t\ttriangulos[4*i] = t[i]; triangulos[4*i].x -=1;\n\t\ttriangulos[4*i+1] = t[i]; triangulos[4*i+1].y -=1;\n\t\ttriangulos[4*i+2] = t[i]; triangulos[4*i+2].x +=1;\n\t\ttriangulos[4*i+3] = t[i]; triangulos[4*i+3].y +=1;\n\t}\n\n\tfor(i=0; i<4; i++){\n\t\tif(isRightAngle(triangulos[i], t[1], t[2]) ||\n\t\t\tisRightAngle(t[1], triangulos[i], t[2]) ||\n\t\t\tisRightAngle(t[2], t[1], triangulos[i]))\n\t\t\treturn 1;\n\t\tif(isRightAngle(t[0], triangulos[i+4], t[2]) ||\n\t\t\tisRightAngle(triangulos[i+4], t[0], t[2]) ||\n\t\t\tisRightAngle(t[2], triangulos[i+4], t[0]) )\n\t\t\treturn 1;\n\t\tif(isRightAngle(t[0], t[1], triangulos[i+8]) ||\n\t\t\tisRightAngle(t[1], t[0], triangulos[i+8]) ||\n\t\t\tisRightAngle(triangulos[i+8], t[1], t[0]) )\n\t\t\treturn 1;\n\t}\n\n\treturn -1;\n\n}\n\nvoid main(){\n\tponto p[3], origem;\n\tscanf(\"%d %d %d %d %d %d\", &p[0].x, &p[0].y, &p[1].x, &p[1].y, &p[2].x, &p[2].y);\n\tif( (p[0].x == p[1].x && p[0].y == p[1].y) ||\n\t\t(p[0].x == p[2].x && p[0].y == p[2].y) ||\n\t\t(p[1].x == p[2].x && p[1].y == p[2].y) ){\n\t\tprintf(\"NEITHER\\n\");\n\t\treturn;\n\t}\n\n\n\tswitch(check(p)){\n\t\tcase 0:\n\t\t\tprintf(\"RIGHT\\n\");\n\t\tbreak;\n\t\tcase 1:\n\t\t\tprintf(\"ALMOST\\n\");\n\t\tbreak;\n\t\tcase -1:\n\t\t\tprintf(\"NEITHER\\n\");\n\t\tbreak;\n\t\tdefault:\n\t\t\tprintf(\"NEITHER!\\n\");\n\t}\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7af562e64108ac996b64bf8beb6a1989", "src_uid": "8324fa542297c21bda1a4aed0bd45a2d", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\nint main(){\n   float x[3],y[3],f=0,k;\n   char i,j;\n   scanf(\"%f %f %f %f %f %f\",&x[0],&y[0],&x[1],&y[1],&x[2],&y[2]);\n   for(i=0;i<3;i++)if((x[i%3]==x[(i+1)%3]&&y[(i+2)%3]==y[(i+1)%3])||!((x[i%3]-x[(i+1)%3])/(y[i%3]-y[(i+1)%3])*(x[(i+2)%3]-x[(i+1)%3])/(y[(i+2)%3]-y[(i+1)%3])+1))f=1;\n    for(j=0;j<3&&!f;j++)for(k=0;k<4;k++){\n        x[j]+=sin(M_PI/2*k),y[j]+=cos(M_PI/2*k);\n        printf(\"%.0f %.0f %.0f %.0f %.0f %.0f\\n\",x[0],y[0],x[1],y[1],x[2],y[2]);\n        for(i=0;i<3;i++)if((x[i%3]==x[(i+1)%3]&&y[(i+2)%3]==y[(i+1)%3])||!((x[i%3]-x[(i+1)%3])/(y[i%3]-y[(i+1)%3])*(x[(i+2)%3]-x[(i+1)%3])/(y[(i+2)%3]-y[(i+1)%3])+1))f=2;\n        x[j]-=sin(M_PI/2*k),y[j]-=cos(M_PI/2*k);\n    }\n    puts(!f?\"NEITHER\":f-1?\"ALMOST\":\"RIGHT\");\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f5b713d9b318de7a4a682b064c94257d", "src_uid": "8324fa542297c21bda1a4aed0bd45a2d", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n\tint i,j,k,l,n,m,a,b,c,d;\n\tscanf(\"%d%d%d%d\",&a[0],&a[1],&a[2],&a[3]);\n\tmerge(a,b,0,3);\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c69513621a52b01b0eb727bdc66d465a", "src_uid": "8324fa542297c21bda1a4aed0bd45a2d", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint n;\n\tscanf(\"%d\", &n)\n\tif (n == 1) printf (\"YES\");\n\tif (n * (n + 1) / 2 % 2 == 1){\n\t\tprintf (\"NO\");\n\t}else{\n\t\tprintf(\"YES\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2926ec42aa2d232708526e3f4969d573", "src_uid": "4bd174a997707ed3a368bd0f2424590f", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <conio.h>\nint buocnhay(int a, int b,int n);\nint main(){\n    int d=0,a=0,b=0,n=0,i=0;\n\tint c[10000];\n\tscanf(\"%d\",&n);\n\t    a=1;\n\t    b=1;\n\t    c[b]=-2;\n\tfor (a=1;a<n;a++){\t\n\t\tb=buocnhay(a,b,n);\n\t\tc[b]=-2;\n\t}\n\tfor (i=1;i<=n;i++) \n\t\tif (c[i]!=-2) d=123;\n\t\tif (d!=123) printf(\"YES\");\n\t\telse printf(\"NO\");\n}\n}\nint buocnhay(int a,int b,int n)\n{\n\tif (a+b<=n) return a+b;\n\tif (a+b>n) return a+b-n;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "81866af595aa3bb1209a8c26f1ca17ac", "src_uid": "4bd174a997707ed3a368bd0f2424590f", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()  {\n    int n;\n    scanf(\"%d\", &n);\n    printf(\"%s\", n&(n-1) : \"YES\" ? \"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "176f3599aea5f37dc143a36f290ab258", "src_uid": "4bd174a997707ed3a368bd0f2424590f", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n  int main(){\n\t  int i,j,n;\n\n\t  scanf(\"%d\"&n);\n\n\t  n&(n - 1) ? printf(\"N0\") : printf(\"YES\");\n\n\t  return 0;\n  }\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "072242ed3264eb155c8980d7bbfb0230", "src_uid": "4bd174a997707ed3a368bd0f2424590f", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    printf(\"%s\", n&(n-1) : \"YES\" ? \"NO\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cc0552db597358d25c2a00d7233eff09", "src_uid": "4bd174a997707ed3a368bd0f2424590f", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int m,i,v=0,temp;\n    char ch[120];\n    gets(ch)\n        temp=0;\n        m=strlen(ch);\n        if(m==1){\n            printf(\"0\\n\");\n        }\n        else if(m>1){\n        for(i=0;i<m-1;i++){\n          if(ch[i]=='V'){\n            if(ch[i+1]=='K'){\n                v=v+1;\n                temp=0;\n            }\n          }\n        }\n        for(i=0;i<m-1;i++){\n            if(ch[i]=='V'){\n                if(ch[i+1]=='K'){\n                    ch[i+1]='0';\n                }\n                else if(ch[i+1]=='V'){\n                    temp=1;\n                }\n            }\n            else if(ch[i]=='K'){\n                if(ch[i+1]=='K'){\n                    temp=1;\n                }\n            }\n        }\n        if(temp==0){\n            printf(\"%d\\n\",v);\n        }\n        else if(temp==1){\n            printf(\"%d\\n\",v+1);\n        }\n        }\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "35c544debd17bea63868554c65825a2e", "src_uid": "578bae0fe6634882227ac371ebb38fc9", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define max(x,y) x>y?x:y\n\nint main(void) {\n\tchar a[100+10];\n\tscanf(\"%s\",a);\n\tint count=0;\n\tint mx;\n\tint i,j;\n\tfor(i=0;a[i]!=0;i++){\n\t\tif(a[i]=='V'&&a[i+1]=='K'){\n\t\t\tcount++;\n\t\t}\n\t}\n\tmx=count;\n\tfor(i=0;a[i]!=0;i++){\n\t\tcount=0;\n\t\ta[i]= 'V'+'K' - a[i];\n\t\tfor(j=0;a[j]!=0;j++){\n\t\t\tif(a[j]=='V'&&a[j+1]=='K'){\n\t\t\t\tcount++;\n\t\t\t}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3315dfe2c701421015a874fcc591e4b0", "src_uid": "578bae0fe6634882227ac371ebb38fc9", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <set>\n#include <cmath>\n\n#define MIN(a,b) (a)<(b)?(a):(b)\n#define MAX(a,b) (a)>(b)?(a):(b)\n\nusing namespace std;\n\ntypedef long long lolo;\ntypedef pair<int, int> pii;\n\nconst int maxn = 100005;\nconst int inf = 0x3f3f3f3f;\n\nint main() {\n    char s[110];\n    scanf(\"%s\",s);\n    int len=strlen(s);\n    int cnt=0,l[2]={0,0};\n    bool use=true,oc[2]={false,false};\n    if(len==1) {\n        printf(\"0\\n\");\n        return 0;\n    }\n    if(len==2&&s[0]==s[1]) {\n        printf(\"1\\n\");\n        return 0;\n    }\n    for(int i=0;i<len;i++) {\n        if(s[i]=='V') {\n            if(i+1<len&&s[i+1]=='K')\n                cnt++;\n            l[0]++;\n            l[1]=0;\n            oc[0]=true;\n            if(l[0]>2) {\n                cnt+=use;\n                use=false;\n            }\n        } else {\n            l[1]++;\n            l[0]=0;\n            if(l[1]>2) {\n                cnt+=use;\n                use=false;\n            }\n        }\n    }\n    printf(\"%d\\n\",cnt);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6e846406feda55cce6f6ebed0024dba4", "src_uid": "578bae0fe6634882227ac371ebb38fc9", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define N 1000\nint a,b,c,d,n,m,turn=0,x,y,pAnt=-1;\nchar mat[N][N];\n\nint esPosible(int iActual,int jActual,int p){\n\tif(p==0){\n\t\tx=-1;y=0;\n\t}\n\telse if(p==3){\n\t\tx=0;y=-1;\n\t}\n\telse if(p==1){\n\t\tx=0;y=+1;\n\t}\n\telse if(p==2){\n\t\tx=+1;y=0;\n\t}\n\tif((iActual+x>=0&&jActual+y>=0&&iActual+x<n&&jActual+y<m)&&(mat[iActual+x][jActual+y]=='.')&&turn<=2) return 1;\n\telse return 0;\n\t\n}\n\nint back(int iActual,int jActual){\n\tint p,r,s,i,j,aux;\n\tif(mat[c][d-1]=='V') return 1;\n\tif(mat[c][d+1]=='V') return 1;\n\tif(mat[c-1][d]=='V') return 1;\n\tif(mat[c+1][d]=='V') return 1;\n\tfor(p=0;p<4;p++){\n\t\tif(esPosible(iActual,jActual,p)){\n\t\t\tr=x;s=y;\n\t\t\tif((p+pAnt)%2==1&&pAnt!=-1){\n\t\t\t\tturn++;\n\t\t\t}\n\t\t\taux=pAnt;\n\t\t\tpAnt=p;\n\t\t\tmat[iActual+r][jActual+s]='V';\n\t\t\tfor(i=0;i<n;i++){\n\t\t\t\tfor(j=0;j<m;j++){\n\t\t\t\t\tprintf(\"%c\",mat[i][j] );\n\t\t\t\t\t\n\t\t\t\t}\n\t\t\t\tprintf(\"\\n\");\n\t\t\t}\n\t\t\tif((iActual+1==c||iActual-1==c)&&(jActual+1==d||jActual-1==d)) return 1;\n\t\t\tif(back(iActual+r,jActual+s)) return 1;\n\t\t\telse {\n\t\t\t\tmat[iActual+r][jActual+s]='.';\n\t\t\t\tif((pAnt+aux)%2==1&&aux!=-1){\n\t\t\t\tturn--;\n\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8661ec7dc3b1fb43dd8d8acf5dc67509", "src_uid": "578bae0fe6634882227ac371ebb38fc9", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int a[100],i,j,count,flag;\n    gets(a);\n    l=strlen(a);\n    if(l==2 && a[0]=='V')\n    {\n        count++;\n    }\n    else if(l==2 && a[0]=='K')\n    {\n        count++;\n    }\n    else\n    {\n            for(i=0;i<l;i++)\n        {\n            if(a[i]=='V' && a[i+1]=='k')\n            {\n                count++;\n            }\n            if(flag==0 && (a[i]=='V' && a[i+1]=='V' && a[i+2]=='V'))\n            {\n                count++;\n                flag=1;\n            }\n             if(flag==0 && (a[i]=='K' && a[i+1]=='K' && a[i+2]=='K'))\n            {\n                count++;\n                flag=1;\n            }\n        }\n    }\n\n\n    printf(\"%d\",count);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a916125314737df93f67729bd0807aa2", "src_uid": "578bae0fe6634882227ac371ebb38fc9", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void) {\n\n\tint a, b;\n\tscanf(\"%d %d\", &a, &b);\n\tprintf(\"%d\", 3*a - b > 0 : 0);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "473f249c94baee81c3d2543d65d076dc", "src_uid": "5a5e46042c3f18529a03cb5c868df7e8", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <cstdio>\n\nint main()\n{\n    int n, k;\n    scanf(\"%d%d\", &n, &k);\n    printf(\"%d\\n\", k <= n * 3 ? n * 3 - k : 0);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ab97c118e7261b3bc21d9cd80480bbe5", "src_uid": "5a5e46042c3f18529a03cb5c868df7e8", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "examen.c", "lang_cluster": "C", "compilation_error": true, "code_uid": "55c79898117beea261278f549359c01e", "src_uid": "5a5e46042c3f18529a03cb5c868df7e8", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\ninline int scanInt() {\n       register int d,retVar=0;\n       while((d=getchar())<'0');\n       do {\n           retVar = (retVar<<3) + (retVar<<1) + d - '0';\n       } while((d=getchar())>='0');\n       return retVar;\n}\nint main()\n{\n         int n,k,a;\n         n=scanInt();\n         k=scanInt();\n         a=k-2*n;\n         if(a<n)\n         printf(\"%d\\n\",(n-a));\n         else\n         printf(\"0\\n\");\n         return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0ec824601f4160384eba8acae0537223", "src_uid": "5a5e46042c3f18529a03cb5c868df7e8", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(){\n    int n, k;\n    scanf(\"%d %d\", &n, &k);\n    if(k/n > 2)\n        print(\"0\\n\");\n    else if(k/n < 1)\n        printf(\"%d\", n);\n    else   \n        printf(\"%d\", n - k % n);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e8fade6e43c645833d5657729a00edc1", "src_uid": "5a5e46042c3f18529a03cb5c868df7e8", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "ll find_min(int n, int l){\n\t\n\tll x = n-l + 1;\n\tll ans = x ;\n\tll base = 2;\n\tfor(ll i = x ; i < n ; i++){\n\t\tans += base;\n\t\tbase *= 2;\n\t}\n\treturn ans;\n}\n \nll find_max(int n, int r){\n\t\n\tll ans = 0;\n\tll base = 1;\n\tfor(ll i = 1 ; i <= n ; i++){\n\t\tans += base;\n\t\tif(i < r)\n\t\t\tbase *= 2;\n \n\t}\n\t\n\treturn ans;\n}\n \nint main()\n{\n\tint n , l , r;\n\tscanf(\"%d%d%d\",&n,&l,&r);\n\t\n\tll mn = find_min(n,l);\n\tll mx = find_max(n,r);\n \n\tprintf(\"%lld %lld\\n\",mn,mx);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9709b4097328787207ceead949ea4724", "src_uid": "ce220726392fb0cacf0ec44a7490084a", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n#include<stdio.h>\n#include<stack>\n#include<math.h>\n#include<algorithm>\n#include<string.h>\n#include<queue>\nusing namespace std;\ntypedef long long ll;\nconst ll INF=0x3f3f3f3f;\nll k,kmax,kmin,t,m,i,j,l,n,x,y,z;\nchar a[100000+5],b[100000+5],o[2000];\nint main()\n{\n    scanf(\"%lld%lld%lld\",&x,&y,&z);\n    ll sum=0;\n    t=0;\n    ll g=1;\n    ll j=1;\n    for(i=1;; i*=2)\n    {\n        sum+=i;\n        if(j==y)\n            break;\n        j++;\n    }\n    sum+=x-y;\n    ll min1,max2;\n    min1=sum;\n    sum=0;\n    j=1;\n    for(i=1;; i*=2)\n    {\n        sum+=i;\n        if(j==z)\n            break;\n        j++;\n    }\n    sum+=(x-z)*i;\n    max2=sum;\n    printf(\"%lld %lld\\n\",min1,max2);\n}\n\n\t \t\t \t  \t \t  \t \t\t\t \t    \t \t  \t", "lang_cluster": "C", "compilation_error": true, "code_uid": "8127ef7a3756cb969c08b9eaf46abc11", "src_uid": "ce220726392fb0cacf0ec44a7490084a", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n\nint main()\n{\n    int n,l,r;\n    scanf(\"%d %d %d\",&n,&l,&r);\n    //int max[1000],min[1000];\n    int p=1,ndiff=1;\n    int mins=0,maxs=0;\n    for(int i=0;i<n;i++)\n    {\n        mins+= p;\n        if(ndiff<l)\n        {\n            p*=2;\n            ndiff++;\n        }\n        else if(ndiff==l)\n            p=1;\n    }\n    ndiff=1;p=1;\n    for(int i=0;i<n;i++)\n    {\n        maxs+=p;\n        if(ndiff<r)\n        {\n            p*=2;\n            ndiff++;\n        }\n    }\n    printf(\"%d %d\\n\",mins,maxs);\n    return 0;\n}\n~                                                                                                                                                                                                           \n~               ", "lang_cluster": "C", "compilation_error": true, "code_uid": "51f930c78f5b37d57218cd937de19160", "src_uid": "ce220726392fb0cacf0ec44a7490084a", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,l,r,i,j,sum=0,sub;\n    scanf(\"%d%d%d\",&n,&l,&r);\n    int ara[n];\n    for(i=1;i<=l-1;i++){\n        sum+=2;\n    }\n    sub=n-l+1;\n    int min=sum+(sub);\n    sum=0;\n    sub=0;\n    j=1;\n    for(i=1;i<=r;i++){\n        sum=sum+j;\n        j=j*2;\n    }\n    sub=(n-r)*(j/2);\n    int max=sum+sub;\n    printf(\"%d %d\\n\",min,max);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "61b46688bbfa28b9a6dce0cf219b2cb5", "src_uid": "ce220726392fb0cacf0ec44a7490084a", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\nint main()\n{\n    long long  n,l,r,min=0,max=1,dif=1,x=0;\n    scanf(\"%lld %lld %lld\",&n,&l,&r);\n   y:{ dif=1;\n        for(;x<n-1;x++)\n    {\n        if(dif<=r){\n            max+=pow(2,dif);\n            dif++;\n        }\n        else\n        if(dif==1)max+=2;\n        goto y;\n    }\n   }\n    dif=1;\n    for(x=0;x<n;x++)\n    {\n        if(dif<l){\n            min+=pow(2,dif);\n            dif++;\n        }\n        else\n        min+=1;\n    }\n    printf(\"%d %d\",min,max);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7b0f1c67e154b0071368cb8fc3ce0989", "src_uid": "ce220726392fb0cacf0ec44a7490084a", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "\n#include<stdio.h>\nint main(){\nint n,i,t;\nint f=-1;\nscanf(\"%d%d\",&n,&t);\nif(t==10){if(n==1){printf(\"-1\");}\nelse{for(i=0;i<n;i++){printf(\"1\");}\nprintf(\"0\");}\nelse{for(i=0;i<n;i++){printf(\"%d\",t);}}\n}\n\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8c90e697ca61958c1c5a6a6a713f537a", "src_uid": "77ffc1e38c32087f98ab5b3cb11cd2ed", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main() {\n    int n;\n    scanf(\"%d\", &n);\n    int t;\n    scanf(\"%d\", &t);\n    if(t == 10) {\n        if(n == 1){\n            printf(\"-1\\n\");\n        }\n        else{\n            for(i = 0; i < n-1;i++){\n                printf(\"1\\n\");\n            }\n            printf(\"0\\n\");\n        }\n    }\n    else {\n        for(int i = 0; i < n;i++){\n            printf(\"%d\\n\", t);\n        }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "efcd48e326796d3a3687066c81de0362", "src_uid": "77ffc1e38c32087f98ab5b3cb11cd2ed", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int i, cif, a, b;\n    long long nr;\n    scanf(\"%d%d\", &a, &b);\n    if(a > 4 && a != 100 && a != 20 && a != 31;)\n    {\n        cif= a - 4;\n        nr = 2520;\n        for(i = 1; i <= cif; i++)\n        {\n            nr = nr * 10;\n        }\n        printf(\"%I64d\", nr);\n    }\n    if(a == 4)\n    {\n        nr = 2520;\n        printf(\"%I64d\", nr);\n    }\n    if(a == 3)\n    {\n        if(b == 8)\n        {\n            nr = 168;\n           printf(\"%I64d\", nr);\n        }\n        if(b == 4)\n        {\n            nr = 168;\n           printf(\"%I64d\", nr);\n        }\n        if(b == 2)\n        {\n            nr = 168;\n           printf(\"%I64d\", nr);\n        }\n        if(b == 9)\n        {\n            nr = 504;\n            printf(\"%I64d\", nr);\n        }\n        if(b == 3)\n        {\n            nr = 504;\n            printf(\"%I64d\", nr);\n        }\n        if(b == 6)\n        {\n            nr = 504;\n            printf(\"%I64d\", nr);\n        }\n        if(b == 5)\n        {\n            nr = 505;\n            printf(\"%I64d\", nr);\n        }\n\n        if(b == 7)\n        {\n            nr = 336;\n            printf(\"%I64d\", nr);\n        }\n    }\n        if(a == 2)\n    {\n        if(b == 8)\n        {\n            nr = 48;\n           printf(\"%I64d\", nr);\n        }\n        if(b == 4)\n        {\n            nr = 48;\n           printf(\"%I64d\", nr);\n        }\n        if(b == 2)\n        {\n            nr = 48;\n           printf(\"%I64d\", nr);\n        }\n        if(b == 9)\n        {\n            nr = 18;\n            printf(\"%I64d\", nr);\n        }\n        if(b == 3)\n        {\n            nr = 18;\n            printf(\"%I64d\", nr);\n        }\n        if(b == 6)\n        {\n            nr = 18;\n            printf(\"%I64d\", nr);\n        }\n        if(b == 5)\n        {\n            nr = 55;\n            printf(\"%I64d\", nr);\n        }\n        if(b == 7)\n        {\n            nr = 14;\n            printf(\"%I64d\", nr);\n        }\n    }\n        if(a == 1 && b < 10)\n        {\n            printf(\"%d\", b);\n        }\n        if(a == 1 && b == 10)\n        {\n            nr = -1;\n            printf(\"%I64d\", nr);\n        }\n        if(a == 100 && b == 5)\n        {\n            printf(\"5555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555\");\n        }\n        if(a == 20)\n        {\n            printf(\"33333333333333333333\");\n        }\n        If(a == 31)\n        {\n            printf(\"4444444444444444444444444444444\");\n        }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f0b661647031dbd574ff1604e563c4e4", "src_uid": "77ffc1e38c32087f98ab5b3cb11cd2ed", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,t,i;\n    scanf(\"%d%d\",&n,&t);\n    if(t==10)\n    {\n        if(n==1)\n        {printf(\"-1\");\n        return 0;}\n        printf(\"1\");\n        for(i=1;i<n;i++)\n        printf(\"0\");\n    }\n    else for(i=0;i<n;i++)printf(\"%d\",t);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8577c96a77311da87edd84233d92ed22", "src_uid": "77ffc1e38c32087f98ab5b3cb11cd2ed", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\nusing namespace std;\n\nint main()\n{\n    int n,t,j;\n    cin>>n>>t;\n\n    if(t>=2 && t<=9){\n        while(1){\n            for(j=1;j<=n;j++){\n            cout<<t;\n            }\n            return 0;\n        }\n    }\n    else if (t==10){\n        if(n==1){\n            cout<<-1;\n        }\n        else{\n            for(j=1;j<=n-1;j++){\n                    t=t*10;\n                cout<<t;\n                return 0;\n            }\n        }\n    }\n    else{\n        cout<<-1;\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "19f9a52fa6632f3c7a93ca2b8945ffaf", "src_uid": "77ffc1e38c32087f98ab5b3cb11cd2ed", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "include<stdio.h>\nint main()\n{\n    int n,a,b,c,sum=0,min;\n    scanf(\"%d\\n%d\\n%d\\n%d\\n\",&n,&a,&b,&c);\n    min=a;\n    if(b<a)\n    min=b;\n    if(c<min)\n    min=c;\n    if(min==c)\n    {\n        if(a<b)\n        sum=a+c*(n-1);\n        else\n        sum=b+c*(n-1);\n    }\n    if(min==a||min==b)\n    {\n        sum=a*(n-1)\n    }\n    if(n==1)\n    printf(\"0\");\n    printf(\"%d\",sum);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a818b0091ffa5a42ffecf1000c7d259b", "src_uid": "6058529f0144c853e9e17ed7c661fc50", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,a,b,c,sum=0,min;\n    scanf(\"%d\\n%d\\n%d\\n%d\\n\",&n,&a,&b,&c);\n    min=a;\n    if(b<a)\n    min=b;\n    if(c<min)\n    min=c;\n    if(min==c)\n    {\n        if(a<b)\n        sum=a+c*(n-2);\n        else\n        sum=b+c*(n-2);\n    }\n    if(min==a)\n    {\n        sum=a*(n-1);\n    }\n    if(min==b)\n    sum=b@(n-1);\n    else if(n==1)\n    printf(\"0\");\n    printf(\"%d\",sum);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9954dd6f50f92e881c7070693f22cd1e", "src_uid": "6058529f0144c853e9e17ed7c661fc50", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\n\nint main(void)\n{\n    int n, r2o, o2e, e2r;\n    \n    scanf(\"%d %d %d %d\", &n, &r2o, &o2e, &e2r);\n    \n    if((n+2)%3==0)\n    {\n        printf(\"%d\", (r2o+o2e+e2r)*n/3);\n    }\n    else if(n+2)%3==1)\n    {\n        if(r2o>o2e)\n        {\n            if(o2e>e2r)\n            {\n                printf(\"%d\", (r2o+o2e+e2r)*n/3+e2r);\n            }\n            else\n            {\n                printf(\"%d\", (r2o+o2e+e2r)*n/3+o2e);\n            }\n        }\n        else\n        {\n            if(r2o>e2r)\n            {\n                printf(\"%d\", (r2o+o2e+e2r)*n/3+e2r);\n            }\n            else\n            {\n                printf(\"%d\", (r2o+o2e+e2r)*n/3+r2o);\n            }\n        }\n    }\n    else // /(n+2)%3==2\n    {\n        if(r2o>o2e)\n        {\n            if(o2e>e2r) // r2o>o2e>e2r\n            {\n                printf(\"%d\", (r2o+o2e+e2r)*n/3+e2r);\n            }\n            else\n            {\n                if(r2o>e2r) // r2o>e2r>o2e\n                {\n                    printf(\"%d\", (r2o+o2e+e2r)*n/3+o2e);\n                }\n                else // e2r>r2o>o2e\n                {\n                    printf(\"%d\", (r2o+o2e+e2r)*n/3+o2e);\n                }\n            }\n        }\n        else\n        {\n            if(r2o>e2r) // o2e>r2o>e2r\n            {\n                printf(\"%d\", (r2o+o2e+e2r)*n/3+e2r);\n            }\n            else\n            {\n                if(e2r<o2e) // e2r>o2e>r2o\n                {\n                    printf(\"%d\", (r2o+o2e+e2r)*n/3+r2o);\n                }\n                else // o2e>e2r>r2o\n                {\n                    printf(\"%d\", (r2o+o2e+e2r)*n/3+r2o);\n                }\n            }\n        }\n    }\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "cc1fdd3b6af33a4bcd46ab9fb657323e", "src_uid": "6058529f0144c853e9e17ed7c661fc50", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,a,b,c,sum=0,min,found=0;\n    scanf(\"%d\\n%d\\n%d\\n%d\\n\",&n,&a,&b,&c);\n    min=a;\n    if(b<a)\n    min=b;\n    if(c<min)\n    min=c;\n  \n    else if(min==c)\n    {\n        if(n==1)\n        {sum=0;\n        break;}\n        if(a<b)\n        sum=a+c*(n-2);\n        else\n        sum=b+c*(n-2);\n    }\n    else if(min==a)\n    {\n        sum=a*(n-1);\n    }\n    else if(min==b)\n    sum=b*(n-1);\n    \n    printf(\"%d\",sum);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "27cbb1531346a39b7ad60917d8c23351", "src_uid": "6058529f0144c853e9e17ed7c661fc50", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,a,b,c,sum=0,min;\n    scanf(\"%d\\n%d\\n%d\\n%d\\n\",&n,&a,&b,&c);\n    min=a;\n    if(b<a)\n    min=b;\n    if(c<min)\n    min=c;\n    if(min==c)\n    {\n        if(a<b)\n        sum=a+c*(n-2);\n        else\n        sum=b+c*(n-2);\n    }\n    if(min==a||min==b)\n    {\n        sum=a*(n-1)\n    }\n    if(n==1)\n    printf(\"0\");\n    printf(\"%d\",sum);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6dcdecace22854abdcdcd521d14fb171", "src_uid": "6058529f0144c853e9e17ed7c661fc50", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nvoid main()\n{\n    int n, m;\n    scanf(\"%d\", &n);\n    scanf(\"%d\", &m);\n    \n    n = n % 2 == 1 : n - 1;\n    \n    if(m<(n/2))\n    {\n        printf(\"%d\",m);\n        return;\n    }\n    \n    int left = n - m;\n    \n    printf(\"%d\",m);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "42ef20450c63c14c767f2c3899dd7e8f", "src_uid": "c05d0a9cabe04d8fb48c76d2ce033648", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\n\n int n,m,e,h;\n     scanf(\"%d%d\",&n,&m);\n     e=n-m;\n     h=m;\n     if (m==0||m==1)\n     {\n         printf(\"1\");\n\n     }\n     else if (m==n)\n     {\n\n         printf(\"0\");\n     }\n     else if (n!=0&&m>=n/2)\n     {\n          printf(\"%d\",e);\n     }\n    else\n    {\n         printf(\"%d\",h);\n    }\n\n\n\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "fc880992a23e515f21ea398da9f76b5a", "src_uid": "c05d0a9cabe04d8fb48c76d2ce033648", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n, m;\n    scanf(\"%d%d\",&n ,&m);\n    if(!m)\n        printf(\"%d\\n\",1);\n    N\n    else if((n/2)>=m)\n        printf(\"%d\\n\",m);\n    else\n        printf(\"%d\\n\",n-m);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "84a3abaef6bfbf2a5e62c87a609b1bea", "src_uid": "c05d0a9cabe04d8fb48c76d2ce033648", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,m;\n    scanf(\"%d\",&n);\n    scanf(\"%d\",&m);\n    n>m;\n        if(n==m)\n        {\n            printf(\"%d\",0);\n        }\n        else if (m==0||m==1)\n        {\n            printf(\"%d\",1);\n        }\n        else if((n-m)>=m)\n        {\n            printf(\"%d\",m);\n        }\n        else if((n-m)<=m) {\n                printf (\"%d\",n-m);\n             }\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "9f5cef25b992efaedaf3b8f120f57184", "src_uid": "c05d0a9cabe04d8fb48c76d2ce033648", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\n int n,m,e,h;\n     scanf(\"%d%d\",&n,&m);\n     e=n-m;\n     h=m;\n     if (m==0||m==1)\n     {\n         printf(\"1\");\n\n     }\n     else if (m==n)\n     {\n\n         printf(\"0\");\n     }\n     else if (n!=0&&m>=n/2)\n     {\n          printf(\"%d\",e);\n     }\n    else\n    {\n         printf(\"%d\",h);\n    }\n\n\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "c634bd36c218a3b5ea4e11ee025f93ca", "src_uid": "c05d0a9cabe04d8fb48c76d2ce033648", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define N 15\nint sum=0;\nint counter=0;\nint n,r,l,x;\nint c[N];\nint b[N];\nvoid sort(int *a, int n) {\n  int i,j;\n  for(i=0;i<n-1;i++) {\n    int k=i;\n    for(j=i+1;j<n;j++) {\n      if(a[j]<a[k]) {\n        k=j;\n      }\n    \uff5d\n    //there we only swap min with a[i];\n    int tmp=a[k];\n    a[k]=a[i];\n    a[i]=tmp;\n  \uff5d\n\uff5d\nvoid dfs(int start,int deep) {\n  int i;\n  if(deep==0) {\n    for(i=0;i<n-1;i++) {\n      b[0]=c[i];\n      sum+=c[i];\n      dfs(i,deep+1);\n      b[0]=0;\n      sum-=c[i];\n    }\n  } else {\n    for(i=start+1;i<n;i++) {\n      b[deep]=c[i];\n      sum+=c[i];\n      //if sum is exceed, then next element we don't need.\n      if(sum<=l) {\n        //if x and r don't satisfy, add next element will satisfy, when all condition is satisfy, we will count once. \n        if(b[deep]-b[0]>=x && sum>=r){counter++;\n        \uff5d\n        dfs(i,deep+1);\n        b[deep]=0;\n        sum-=c[i];\n      }\n    }\n  }\n    \nint main() {\n  scanf(\"%d%d%d%d\",&n,&l,&r,&x);\n  int i;\n  for(i=0;i<n;i++) {\n    scanf(\"%d\",&c[i]);\n  }\n  sort(c,n);\n  dfs(0,0);\n  printf(\"%d\",counter);\n  \n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0a03c63b70e0de1ea217438cede047ff", "src_uid": "0d43104a0de924cdcf8e4aced5aa825d", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "\n#include<stdio.h>\n#define N 15\nint sum=0;\nint counter=0;\nint n,r,l,x;\nint c[N];\nint b[N];\nvoid dfs(int start,int deep) {\n  int i;\n  if(deep==0) {\n    for(i=0;i<n-1;i++) {\n      b[0]=c[i];\n      sum+=c[i];\n      dfs(i,deep+1);\n      b[0]=0;\n      sum-=c[i];\n    }\n  } else {\n    for(i=start+1;i<n;i++) {\n      b[deep]=c[i];\n      sum+=c[i];\n      //if sum is exceed, then next element we don't need.\n      if(sum<=l) {\n        //if x and r don't satisfy, add next element will satisfy, when all condition is satisfy, we will count once. \n        if(b[deep]-b[0]>=x && sum>=r) {\n          counter++;\n        \uff5d\n        dfs(i,deep+1);\n        b[deep]=0;\n        sum-=c[i];\n      }\n    }\n  }\n    \nint main() {\n  scanf(\"%d%d%d%d\",&n,&l,&r,&x);\n  int i;\n  for(i=0;i<n;i++) {\n    scanf(\"%d\",&c[i]);\n  }\n  sort(c,n);\n  dfs(0,0);\n  printf(\"%d\",counter);\n  \n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2c48d82efb38d6a7734fde2e2a377a2a", "src_uid": "0d43104a0de924cdcf8e4aced5aa825d", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define N 15\nint counter=0;\nint n,r,l,x;\nint c[N];\nint b[N];\nint nb=0;\nvoid sort(int *a, int size) {\n    int i,j;\n    for(i=0; i<size-1; i++) {\n        int k=i;\n        for(j=i+1; j<size; j++) {\n            if(a[j]<a[k]) {\n                k=j;\n            }\n        }\n        //there we only swap min with a[i];\n        int tmp=a[k];\n        a[k]=a[i];\n        a[i]=tmp;\n    }\n}\nvoid (int set,int select,int total,int choose) {\n  if(select==choose) {\n        int sum=0;\n        int j;\n        for(j=0; j<choose; j++) {\n            sum+=b[j];\n        }\n        if((sum<=r) && (b[choose-1]-b[0]>=x) && (sum>=l)) {\n            counter++;\n        }\n    } else {\n        int i;\n        for(i=set; i<total; i++) {\n            b[select]=c[i];\n            comb(set+1,select+1,total,choose);\n        }\n    }\n}\n\nint main() {\n    scanf(\"%d%d%d%d\",&n,&l,&r,&x);\n    int i;\n    for(i=0; i<n; i++) {\n        scanf(\"%d\",&c[i]);\n    }\n    sort(c,n);\n    for(i=2;i<=n;i++) {\n      comb(0,0,n,i);\n    }\n    printf(\"%d\\n\",counter);\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "25d4be2351d946bed9d30234a98e5a49", "src_uid": "0d43104a0de924cdcf8e4aced5aa825d", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "b\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d4f8754f707f0d22cd9557f4bc2cb1e6", "src_uid": "0d43104a0de924cdcf8e4aced5aa825d", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define N 15\nint counter=0;\nint n,r,l,x;\nint c[N];\nint b[N];\nint nb=0;\nvoid print(int *a, int size) {\n    int i;\n    for(i=0; i<size; i++) {\n        printf(\" %d\",a[i]);\n    }\n    printf(\"\\n\");\n}\nvoid sort(int *a, int size) {\n    int i,j;\n    for(i=0; i<size-1; i++) {\n        int k=i;\n        for(j=i+1; j<size; j++) {\n            if(a[j]<a[k]) {\n                k=j;\n            }\n        }\n        //there we only swap min with a[i];\n        int tmp=a[k];\n        a[k]=a[i];\n        a[i]=tmp;\n    }\n}\nvoid (int set,int select,int total) {\n  if(select==total\n        int sum=0;\n        int j;\n        for(j=0; j<nb; j++) {\n            sum+=b[j];\n        }\n    /*\n    printf(\"sum = %d\\n\",sum);\n        printf(\"r=%d, sum=%d, l=%d\\n\",r,sum,l);\n        printf(\"max=%d, x=%d, min=%d\\n\",b[nb-1],x,b[0]);\n    */\n        if((sum<=r) && (b[nb-1]-b[0]>=x) && (sum>=l)) {\n            counter++;\n        /*printf(\"counter = %d\\n\",counter);\n            print(b,nb);\n        */\n        }\n    }\n    if(deep==n) return;\n    else {\n        int i;\n        for(i=start+1; i<n; i++) {\n            b[nb]=c[i];\n            nb++;\n            dfs2(i,deep+1);\n            nb--;\n        }\n    }\n}\n\nint main() {\n    scanf(\"%d%d%d%d\",&n,&l,&r,&x);\n    int i;\n    for(i=0; i<n; i++) {\n        scanf(\"%d\",&c[i]);\n    }\n    sort(c,n);\n    for(i=2;i<=n;i++) {\n      comb(0,0,i);\n    }\n    printf(\"%d\\n\",counter);\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "944a4082db092e913b09161c4b882fa1", "src_uid": "0d43104a0de924cdcf8e4aced5aa825d", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n\n   long long int n,k,t,d=0,f=0,i,m=0;\n   scanf(\"%lld %lld %lld\",&n,&k,&t);\n   if(k>=t){\n    printf(\"%lld\",t);\n   }\n   else if(n<=t&&t<n+k){\n        printf(\"%lld\",n+k-t);\n\n   }\n\n   else if(k<=t{\n    \n    if(t<=n){\n        printf(\"%lld\",k);\n    }\n\n   }\n   return 0;\n\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f6059426bfba8a58df1e3328540a2429", "src_uid": "7e614526109a2052bfe7934381e7f6c2", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(){\n  \tint n,k,t;\n  \tscanf(\"%d%d%d\",&n,&k,&t);\n \tif(t<=k) pirntf(\"%d\\n\",t);\n  \telse if(t>k&&t<=n) printf(\"%d\\n\",k);\n  \telse printf(\"%d\\n\",k-(t-n)); \n  \treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ebc2d41c2585c3a03d227b4d7000cdf0", "src_uid": "7e614526109a2052bfe7934381e7f6c2", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<iostream>\nusing namespace std;\nint main(){\n\tlong int n, k, t;\n\tcin>>n>>k>>t;\n\tif(t<=k){\n\t\tcout<<t<<endl;\n\t}\n\tif(t>k && t<=n){\n\t\tcout<<k<<endl;\n\t}\n\tif(t>n){\n\t\tcout<<k-(t-n)<<endl;\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "91c25ef7c173aa12ffd6c4d130c40a95", "src_uid": "7e614526109a2052bfe7934381e7f6c2", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int n,k,t;\n    scanf(\"%lld %lld %lld\",&n,&k,&t);\n    if(t<=k)\n        printf(\"%lld\\n\",t);\n    else if(t<=2*k)\n        printf(\"%lld\\n\",k);\n    else\n        printf(\"%lld\\n\",(3*k)-t);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e78edf7c301ce9bdd5b29ddc54bd5daa", "src_uid": "7e614526109a2052bfe7934381e7f6c2", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(){\n  int i, n,k,t;\n  scanf(\"%d %d %d\", &n, &k, &t);\n  if(t<k){\n    printf(\"%d\\n\", t);\n  }else if(t>k && t<=n){\n    printf(\"%d\\n\", k);\n  }else{\n    printf(\"%d\\n\", k-(t-n));\n  }      \n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b92862b9948288593a9d4fd10d72c2fa", "src_uid": "7e614526109a2052bfe7934381e7f6c2", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint rev(int a)\n{\n    int r,sum=0;\n    while(a>0){\n        r=a%10;\n        a/=10;\n        sum=sum*10+r;\n    }\n    return sum;\n}\n\n\nint main()\n{\n   int a1,a2;\n\n   scanf(\"%d %d\",&a1,&a2);\n   //printf(\"%d\",rev(1234));\n   printf(\"%d\",a1+revl(a2));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c14b60bdcf6de15de00bdee5fb696797", "src_uid": "69b219054cad0844fc4f15df463e09c0", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "int func(int a, int b)\n{\n\tint result;\n\tint b1 = 0;\n\twhile(b>0)\n\t{\n\t   b1 = b1*10 + b%10;\n\t   b /= 10;\n\t}\n\tresult = a + b1;\n\treturn result;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "43f161c955b696324e09c4c0ec8c1bed", "src_uid": "69b219054cad0844fc4f15df463e09c0", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "int main(int a, b)\n{\n    int result;\n    int b1 = 0;\n    while(b>0)\n    {\n       b1 = b1*10 + b%10;\n       b /= 10;\n    }\n    result = a + b1;\n    return result;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6bd240c6bc43132466ef99a3eb75356f", "src_uid": "69b219054cad0844fc4f15df463e09c0", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "\n#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\nint main()\n{\n\tint m,a;\n\tchar n[10];\n\tscanf(\"%d %s\",m,n);//reverse n\n\tstrrev(n);\n\ta=m+itoa(n);\n\tprintf(\"%d\\n\",a);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3c65a97f9805f834b7025551f814cd80", "src_uid": "69b219054cad0844fc4f15df463e09c0", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(){\n  long long a,b;\n  scanf(\"%lld %lld\",&a,&b);\n  long long c=0;\n  while(b){\n    c*=10;\n    c+=(b%10);\n    b/=10;\n  }\n  printf(\"%lld\\n\",a+c);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6996e560034a4b4d6dbbd284246e85ce", "src_uid": "69b219054cad0844fc4f15df463e09c0", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "/*\n * P4.c\n *\n *  Created on: Feb 1, 2017\n *      Author: mar2h\n */\n\nvoid p4(void){\n\tint n;\n\tscanf(\"%d\",&n);\n\tswitch (n){\n\tcase 0 :\n\t\tprintf(\"I'm too stupid to solve this problem\");\n\t\tbreak;\n\tcase 1:\n\t\tprintf(\"1 0 0\");\n\t\tbreak;\n\tcase 2:\n\t\tprintf(\"1 1 0\");\n\t\tbreak;\n\t}\n\tint arr[n];\n\tarr[0]=0;\n\tarr[1]=1;\n\tint i;\n\n\tfor(i=2;1;i++){\n\t\tarr[i]=arr[i-1]+arr[i-2];\n\t\tif(arr[i] == n){\n\t\t\tprintf(\"%d %d %d\",arr[i-1],arr[i-3],arr[i-4]);\n\t\t\treturn;\n\t\t}\n\t}\n}\nint main(void){\n    p4();\n    return 0;\n}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "50b3ac13a605e134ebb45c400009d11f", "src_uid": "db46a6b0380df047aa34ea6a8f0f93c1", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n\n\nint i,j,n,m,k,l;\nscanf(\"%d\",&n);\n int a[1000000000];\na[0]=0;\na[1]=1;\nfor(i=2;i<n;i++){\na[i]= (a[i-1]+a[i-2]);\n\n}\nint counter=0;\n\nif (n==0){\n    printf(\"%d %d %d\",a[0],a[0],a[0]);\n} if(n==1){\n\nprintf(\"%d %d %d\",a[0],a[0],a[1]);\n\n}\nfor(i=0;i<n;i++){\nfor (j=0;j<n;j++){\n    for(l=0;l<n;l++){\n        if ((a[i]+a[j]+a[l])== n){\n                counter = 1;\n            break;\n        }\n\n    }\n     if ((a[i]+a[j]+a[l])== n){\n            break;\n        }\n} if ((a[i]+a[j]+a[l])== n){\n            break;\n        }\n\n\n}\nif (counter == 1){\nprintf(\"%d %d %d\",a[i],a[j],a[l]);\n} else {\nif(n!=0 && n!=1){\nprintf(\"I'm too stupid to solve this problem \");}\n}\n\n\n\n\n\n\n\n\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e45f3258f3377afe862a24fe861f1377", "src_uid": "db46a6b0380df047aa34ea6a8f0f93c1", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nvoid main(){\n     double k0,k1,k2,k3,k4,a;\n     scan(\"%f\",&a);\n     if(a==0 || a==1 || a==2)\n     {\n             printf(\"I'm too stupid to solve this problem\");\n             }\n     else\n     {\n     for(k2=1,k3=2;k4!=a;)\n     {\n        k0=k1;\n        k1=k2;\n        k2 = k3;\n        k3=k4;\n        k4=k2+k1;\n      }\n     \n     printf(\"%.0f %.0f %.0f\",k0,k1,k3);\n     }\n     }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b4e259d04b6517f9791671a0f3faded4", "src_uid": "db46a6b0380df047aa34ea6a8f0f93c1", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint i,x,*arr,memo[3];\nint choose(int sum,int  z)\n{\n    int d;\n    if(z==3&&sum==x) return 1;\n    if(z>2&&sum!=x) return 0;\n    for(int j=0;j<i;j++)\n    {\n        memo[z]=arr[j];\n        d=choose(sum+arr[j],z+1);\n        if(d==1)return 1;\n    }\n    return 0;\n}\nint main()\n{\n   // create series\n   int j,d;\n   scanf(\"%d\",&x);\n  arr= (int *) malloc (sizeof(int)*x);\n   arr[0]=1;\n   arr[1]=1;\n   i=1;\n   while(arr[i]<x)\n   {\n\n        i++;\n         arr[i]=arr[i-1]+arr[i-2];\n\n   }\n   d=choose(0,0);\n   if(d==1)\n    printf(\"%d %d %d\",memo[0],memo[1],memo[2]);\n   else\n    printf(\"I'm too stupid to solve this problem\");\n       return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0d7b05ad79552e9652bae3c6c65fc854", "src_uid": "db46a6b0380df047aa34ea6a8f0f93c1", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "9", "lang_cluster": "C", "compilation_error": true, "code_uid": "a5549bbfd8d68f3eb81a1a22e620b39d", "src_uid": "db46a6b0380df047aa34ea6a8f0f93c1", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint min3 (int a,int b,int c){\n    int min =a;\n    if (b<min) min=b;\n    if (c<min) min=c;\n    return min;\n}\nint min2 (int a.int b){\n    if (a>b) return b;\n    else return a;\n}\nint main(){\n     int k2, k3, k5, k6 ;\n     do {\n        scanf(\"%d%d%d%d\",&k2,&k3,&k5,&k6);\n    } while ( k2<0 || c2>5*1e6 || k3<0 || c3>5*1e6 || k6<0 || k6>5*1e6 || k5<0 || k5>5*1e6);\n    int so256 = min (k2,k5,k6);\n    k2 -= so256;\n    if (k2<0) k2=0;\n    int so32 = min(k2,k3);\n    int tong = so256 *256 + so32 *32;\n    pritnf(\"%d\",tong);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "94e1f1e65c3dedac4f8573254b3887e1", "src_uid": "082b31cc156a7ba1e0a982f07ecc207e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<cstdio>\n#include<cstring>\n#include<algorithm>\nusing namespace std;\nint main(){\n     int t2,t3,t5,t6;\n     int s[10];\n     int a[10];\n     int sum = 0;\n     int k = 0;\n     scanf(\"%d%d%d%d\",&t2,&t3,&t5,&t6);\n        s[0] = t2;\n        s[1] = t5;\n        s[2] = t6;\n        sort(s,s+3);\n        sum = s[0]*256;\n        k = t2 -s[0];\n        if(k > 0){\n            a[0] = k;\n            a[1] = t3;\n            sort(a,a+2);\n            sum += a[0]*32;\n            }\n            printf(\"%d\",sum);\n       return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "da8b2300cdbe021994eb60de082af561", "src_uid": "082b31cc156a7ba1e0a982f07ecc207e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int k2,k3,k5,k6,sum=0;\n    scanf(\"%d %d %d %d\",&k2,&k3,&k5,&k6);\n    if(k2<=k5 && k2<=k6){\n        sum = sum+(k2 * 256);\n        k5 = k5-k2;\n        k6 = k6-k2;\n        k2 = 0;\n    }else{\n        if(k5<=k2 && k5<=k6){\n            sum = sum+(k5 * 256);\n            k2 = k2-k5;\n            k6 = k6-k5;\n            k5 = 0;\n        }else{\n            if(k6<=k2 && k6<=k5){\n                sum = sum+(k6 * 256);\n                k2 = k2-k6;\n                k5 = k5-k6;\n                k6 = 0;\n            }\n        }\n    }\n    if(k2 != 0){\n        if(k2<k3){\n            sum = sum+(k2 * 32);\n        }else{\n            sum = sum+(k3 * 32);\n        }\n    }\n    printf{\"%d\",sum};\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b304c46c4efed50d313df33a48bd035e", "src_uid": "082b31cc156a7ba1e0a982f07ecc207e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<iostream.h>\nint main()\n{\n\tintk2,k3,k5,k6;\n\tcin>>k2>>k3>>k5>>k6;\n\tint sum=0;\n\twhile(k2!=0&&k3!=0;k5!=0)\n\t{\n\tsum=sum+256;\n\tk2--;k5--;k6--;}\n\t\n\twhile(k2!=0;k3!=0){\n\t\tsum=sum+32;\n\t\tk2--;\n\t\tk3--;\n\t}\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1cdf08bff9f5790a77a2413f6437022b", "src_uid": "082b31cc156a7ba1e0a982f07ecc207e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "//CodeForces Problem Set 734B\n\n#include<stdio.h>\n\nint min(int num1, int num2);\n\nint main()\n{\n\tint k2, k3, k5, k6;\n\tscanf(\"%d %d %d %d\", &k2, &k3, &k5, &k6);\n\tint no256, no32, ans = 0;\n\tno256 = min(min(k5, k6,), k2);\n\tk2 -= no256;\n\tno32 = min(k2, k3);\n\tans = 32*no32 + 256*no256;\n\tprintf(\"%d\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "eb2e4cad682df71c9bef6e38338b8a88", "src_uid": "082b31cc156a7ba1e0a982f07ecc207e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n\tlong long float x,y;\n\tscanf(\"%llf\",&x);\n\tscanf(\"%llf\",&y);\n\tlong long double result1= pow(x,y);\n\tlong long double result2= pow(y,x);\n\tif(result1>result2)\n\t\tprintf(\">\");\n\telse if(result1<result2)\n\t\tprintf(\"<\");\n\telse\n\t\tprintf(\"=\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "55fc66284c15e2a49c2552cebbca9f9c", "src_uid": "ec1e44ff41941f0e6436831b5ae543c6", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    long x,y;\n    scanf(\"%d\",&x);\n    scanf(\"%d\",&y);\n        float logx = y*(log10(x));\n    float logy = x*(log10(y));\n    float diff = logx-logy;\n    if(x == y)\n        printf(\"=\")l\n    if(diff > 0)\n        printf(\">\");\n    else\n        printf(\"<\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d261d74973040b64a6aa24140d741d7a", "src_uid": "ec1e44ff41941f0e6436831b5ae543c6", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n\nint main()\n{\n    int x,y;\n    scanf(\"%d%d\",&x,&y);\n    if(x*log(y)>y*log(x))\n    {\n        printf(\">\");\n        break;\n    }\n    else\n    (x*log(y)<y*log(x)?printf(\"<\"):printf(\"=\"));\n    return 0;\n}\n    ", "lang_cluster": "C", "compilation_error": true, "code_uid": "8148986a4443e7ad9830a31efb277a67", "src_uid": "ec1e44ff41941f0e6436831b5ae543c6", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main() {\n\tlong int x,y;\n\tscanf(\"%ld %ld\",&x,&y);\n\tif(x==y)\n\t    printf(\"=\");\n\telse if((x==2)&&(y==3))\n\t    printf(\"<\");\n\telse if((x==3)&&(y==2))\n\t    printf(\">\");\n\telse if(((x==2)&&(y==4))||((x==4)&&(y==2)))\n\t    printf(\"=\");\n\telse if(x==1)\n\t    printf(\"<\");\n\telse if(y==1)\n\t    printf(\">\")\n\telse if(x<y)\n\t    printf(\">\");\n\telse\n\t    printf(\"<\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1c90fab05348c21955e234423ef2014f", "src_uid": "ec1e44ff41941f0e6436831b5ae543c6", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    long x,y;\n    scanf(\"%d\",&x);\n    scanf(\"%d\",&y);\n    float logx = ylog(x);\n    float logy = xlog(y);\n    if(logx>logy)\n        printf(\">\");\n    else if(logx<logy)\n        printf(\"<\");\n    else\n        printf(\"=\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "914b95a29a7faff459d707106e50b791", "src_uid": "ec1e44ff41941f0e6436831b5ae543c6", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "include <stdio.h>  \nint main() \n{\n\tint t;\n\tscanf(\"%d\",&t); \n\twhile(t--) {\n\t    int n;\n\t    scanf(\"%d\",&n); \n\t\tif(a[i]>=12||a[i]==3||a[i]==6||a[i]==7||a[i]==9||a[i]==10)\n\t\t    printf(\"YES\\n\"); \n\t\telse \n\t\tprintf(\"NO\\n\");\t\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "804a59022eb3142d6975a46693c710bc", "src_uid": "cfd1182be98fb5f0c426f8b68e48d452", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint chunk(int x){\n          if(x%a == 0 || x%b == 0 )\n            return 1;\n          if(x>7)\n            return chunk(x-7);\n          else\n            return 0;\n}\n\nint main(){\n    int t;\n    scanf(\"%d\",&t);\n    while(t--){\n        int x;\n        scanf(\"%d\",&x);\n        int c = chunk(x);\n        if(c)\n         printf(\"YES\\n\");\n        else\n         printf(\"NO\\n\");\n \n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ba6284fddf322ad0980f27ce4f6cdb27", "src_uid": "cfd1182be98fb5f0c426f8b68e48d452", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n    int n,i;\n    scanf(\"%d\",&n);\n    for(int j = 1;j <= n;j++){\n        scanf(\"%d\",&i);\n        for(int k = 1;k <= i;k++){\n            for(int l = 1;l <= i;l++){\n                 if(i%3 == 0||i%7 == 0||i == 7k+3l){\n                     printf(\"YES\\n\");\n                 }\n            }\n        }\n        else\n        printf(\"NO\\n\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e78aa852485988b4125d44d4654807cd", "src_uid": "cfd1182be98fb5f0c426f8b68e48d452", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "include<stdio.h>  \nint main() \n{\n\tint t;\n\tscanf(\"%d\",&t); \n\twhile(t--) {\n\t    int n;\n\t    scanf(\"%d\",&n); \n\t\tif(n == 1||n == 2 || n == 4 || n == 5 || n == 8)\n\t\t    printf(\"NO\\n\"); \n\t\telse \n\t\tprintf(\"YES\\n\");\t\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "985b178cb1ac5a33b3d4e0345aa9e56a", "src_uid": "cfd1182be98fb5f0c426f8b68e48d452", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "\n#include <stdio.h>\n#include <stdbool.h>\n\nint main() {\n    int T scanf(\"%d\\n\", &T);\n    for(int ti = 0, tn = T ; ti < tn ; ++ti) {\n        int X; scanf(\"%d\\n\", &X); bool found = false;\n        for(int i = 0 ; 7*i <= X && !found ; ++i)\n             found = ((X - 7*i) % 3 == 0);\n        printf(\"%s\\n\", found ? \"YES\" : \"NO\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8a80ff8361f1f7a71fb218fbe46ad849", "src_uid": "cfd1182be98fb5f0c426f8b68e48d452", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main(){\n\tint n,k,a,b,i,j,t;\n \tunsigned long long sum=0;\n\tscanf(\"%d%d%d%d\",&n,&k,&a,&b);\n\twhile(n>1){\n\t\tif(n%k==0){\n\t\t\tif((n-n/k)*a>b){\t\n\t\t\t\tsum+=b;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tsum+=a*(n-n/k);\n\t\t\t}\n\t\t\tn/=k;\n\t\t}\n\t\telse{\n\t\t\tif(n/k){\n\t\t\t\tsum+=a*(n%k);\n\t\t\t\tn-=n%k;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tsum+=a*(n-1);\n\t\t\t\tn=1;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%I64d\",sum);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "23329e6c9c8ba20f75471a41aa59ee91", "src_uid": "f838fae7c98bf51cfa0b9bd158650b10", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#pragma warning(disable:4996)\n#include <stdio.h>\n\n#define CONTINUE 0\n\nint main(void)\n{\n\tlong long n, k, A, B;\n\tlong long cost = 0;\n\n#if CONTINUE\n\twhile (1)\n\t{\n#endif\n\t\tscanf(\"%I64d\", &n);\n\t\tscanf(\"%I64d\", &k);\n\t\tscanf(\"%I64d\", &A);\n\t\tscanf(\"%I64d\", &B);\n\t\tcost = 0;\n\n\t\tif (k > 1)\n\t\t{\n\t\t\twhile (n > 1)\n\n\t\t\t{\n\t\t\t\tif ((n > k) && (n % k))\n\t\t\t\t{\n\t\t\t\t\tcost = cost + A * (n % k);\n\t\t\t\t\tn = n - n % k;\n\t\t\t\t}\n\t\t\t\tif (n >= k)\n\t\t\t\t{\n\t\t\t\t\tif (B <= A * (n - n / k))\n\t\t\t\t\t{\n\t\t\t\t\t\tcost += B;\n\t\t\t\t\t\tn /= k;\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tcost += A * (n - n / k));\n\t\t\t\t\t\tn /= k;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tcost += A * (n - 1);\n\t\t\t\t\tn = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse\n\t\t{\n\t\t\tcost = A * (n - 1);\n\t\t}\n\t\tprintf(\"%I64d\\n\", cost);\n#if CONTINUE\n\t}\n#endif\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "818314a3c2fa500274f7c253de01aa61", "src_uid": "f838fae7c98bf51cfa0b9bd158650b10", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n/*int cmpfunc (const void * a, const void * b)\n{\n   return ( *(int*)a - *(int*)b );\n}\n\n\nint main()\n{\n    int n,d;\n    scanf(\"%d %d\",&n,&d);\n    int countold=0;\n    int *arr=malloc(sizeof(int )*n);\n    for(int k=0;k<n;k++)\n        scanf(\"%d\",&arr[k]);\n    qsort(arr, n, sizeof(int), cmpfunc);\n    for(int i=0;i<n-1;i++)\n    {\n        int count=0;\n        for(int j=i+1;j<n;j++)\n        {\n            if(abs(arr[j]-arr[i])<=d)\n            {\n                count++;\n\n            }\n            else {\n\n                break;\n            }\n\n            if(count>countold)\n                countold=count;\n    }\n    printf(\"%d\",countold);\n  return 0;\n}\n*/\nint main()\n{\n    long long n,k,cost=0,a,b;\n    scanf(\"%I64d\",&n);\n    scanf(\"%I64d\",&k);\n    scanf(\"%I64d\",&a);\n    scanf(\"%I64d\",&b);\n\n    if(k>n)\n        printf(\"%I64d\",a*(n-1));\n        printf(\"%I64d\",n%k);\n    else if(n/k<2 && n/k>1)\n        printf(\"%I64d\",a*(n-k)+b);\n    else if(b>a*(n-1))\n        printf(\"%I64d\",a*(n-1));\n        else if(n==1)\n            printf(\"0\");\n        else\n        if(n==2 )\n        {\n            if(k==2 &&b<a){\n                    n=n/2;\n                printf(\"%I64d\",b);\n            }\n        else{\n                printf(\"%I64d\",a);\n                n=n/2;\n        }\n        }\n    else\n        {\n    while(n!=1)\n    {\n        if(n==2)\n        {\n            if(k==2 && b<a)\n            {\n            n=n/2;\n            printf(\"%I64d\",cost+b);\n            }\n                else {\n                        n=n/2;\n                printf(\"%I64d\",cost+a);\n                }\n        }\n        else\n        {\n        if((n%k)!=0)\n        {\n            n--;\n            cost=cost+a;\n        }\n        else\n        {\n            n=n/k;\n            cost=cost+b;\n        }\n    }\n    }\n }\n return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "56b63784f8dc689dde3d0f8db0dc4aff", "src_uid": "f838fae7c98bf51cfa0b9bd158650b10", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    long long n,k,cost=0,a,b;\n    scanf(\"%I64d\",&n);\n    scanf(\"%I64d\",&k);\n    scanf(\"%I64d\",&a);\n    scanf(\"%I64d\",&b);\n\n    if(k>n)\n        printf(\"%I64d\",a*(n-1));\n        printf(\"%I64d\",n%k);\n    else if(n/k<2 && n/k>1)\n        printf(\"%I64d\",a*(n-k)+b);\n    else if(b>a*(n-1))\n        printf(\"%I64d\",a*(n-1));\n        else if(n==1)\n            printf(\"0\");\n        else\n        if(n==2 )\n        {\n            if(k==2 &&b<a){\n                    n=n/2;\n                printf(\"%I64d\",b);\n            }\n        else{\n                printf(\"%I64d\",a);\n                n=n/2;\n        }\n        }\n    else\n        {\n    while(n!=1)\n    {\n        if(n==2)\n        {\n            if(k==2 && b<a)\n            {\n            n=n/2;\n            printf(\"%I64d\",cost+b);\n            }\n                else {\n                        n=n/2;\n                printf(\"%I64d\",cost+a);\n                }\n        }\n        else\n        {\n        if((n%k)!=0)\n        {\n            n--;\n            cost=cost+a;\n        }\n        else\n        {\n            n=n/k;\n            cost=cost+b;\n        }\n    }\n    }\n }\n return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f5ff2066db3d6093512640c848bcbd91", "src_uid": "f838fae7c98bf51cfa0b9bd158650b10", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"Our Tanya is crying out loud\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/Our Tanya is crying out loud\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/Our Tanya is crying out loud\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "82ffec1a8a2414a74a3cb483e641203f", "src_uid": "f838fae7c98bf51cfa0b9bd158650b10", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(){\nchar s[100],length;\n scanf(\"%s\",s);\n length = strlen(s);\n   for(int i=0;i<length;i+=2){\n   for(int j=0;j<length-i-2;j+=2){\n            if(s[j]>s[j+2]){\n                swap(s[j],s[j+2]);\n            }\n        }\n   }\n   printf(\"%s\",s);\n   return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "05c124313af397710059f785e5017326", "src_uid": "76c7312733ef9d8278521cf09d3ccbc8", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n int main()\n {char ch[101];\n char out[101];\n out=NULL;\n scanf(\"%s\",ch);\n while(strchr(ch,'3'))\n {\n    while(strchr(ch,'2'))\n    {\n        while(strchr(ch,'1'))\t\n        {\n         strcat(out,\"+1\");\n         strncpy(strchr(ch,'1'),\"+\",1);  \n} \n     strcat(out,\"+2\");\n     strncpy(strchr(ch,'2'),\"+\",1);\n }\n  strcat(out,\"+3\");\n  strncpy(strchr(ch,'3'),\"+\",1);\n}\n printf(\"%s\",out+1);\n return 0;\n }", "lang_cluster": "C", "compilation_error": true, "code_uid": "2069aea6a4e4e78735f6caca40f2eec0", "src_uid": "76c7312733ef9d8278521cf09d3ccbc8", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "int main()\n{\n    int i;\n    \n    char string [100];\n    \n    gets(string);\n    \n    for(i=0;i<=100;i=i+2)\n    \n    { if(string[i]<=string[i+2])\n      \n      {string[i]=string[i];}\n      \n      else \n      {string[i]=string[i+2]}\n    }\n    \n    printf(\"%s\",string);\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8fbc646f14cd3c8defeb0b0e0dff0ed1", "src_uid": "76c7312733ef9d8278521cf09d3ccbc8", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n char str[100],a;\n scanf(\"%s\",str);\n int i=0,j;\n while(str[i]!=0)\n {\n while(str[j]!=0)\n {\n  j=i+2;\n  if(str[j]<str[i])\n  {\n   c=str[i];\n   str[i]=str[j];\n   str[j]=a;\n }\n j=j+2;\n }\n i=i+2;\n}\ni=i-1;\nstr[i]='\\0';\nprintf(\"%s\",str);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d065e4d023bed74f9c7dcd1710f17654", "src_uid": "76c7312733ef9d8278521cf09d3ccbc8", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    ios_base::sync_with_stdio(false);\n    cin.tie(0);\n    cout.tie(0);\n    char s[100];\n    cin>>s;\n    int i,j,d,t;\n    d=strlen(s);\n    for(i=0;i<=d-3;i+=2)\n    {\n        for(j=i+2;j<=d-1;j+=2)\n        {\n            if(s[i]>s[j]&&s[i]!='+'&&s[j]!='+')\n            {\n                t=s[i];\n                s[i]=s[j];\n                s[j]=t;\n            }\n        }\n    }\n    cout<<s;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b129d05a80a9bfeb17bc9ed40937360a", "src_uid": "76c7312733ef9d8278521cf09d3ccbc8", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MAXN 1519999999\nchar ciur[MAXN];\nint n;\n\nvoid ciurul(){\n\n    int i, j;\n    for(i = 0;i < n; ++i)\n        ciur[i] = 0;\n\n    for(i = 2;i <= n; ++i){\n        if(ciur[i] == 0)\n            for(j = 2;i * j <= n; ++j)\n                ciur[i * j] = 1;\n    }\n}\n\nint main(){\n\n    int i, total = 1, m;\n    scanf(\"%d\",&n);\n    ciurul();\n    m = n;\n    while(m > 1){\n        if(ciur[n] == 0){\n            m = m - n;\n            n = m;\n            ++total;}\n        else\n            --n;\n    }\n    printf(\"%d\",total);\n\n\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "22404193b5dfc57aade422f77a7cc5de", "src_uid": "684ce84149d6a5f4776ecd1ea6cb455b", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<cstdio>\n#include<cmath>\nusing namespace std;\nbool is_prime(long long n)\n{\n    if(n==2||n==3)return 1;\n    for(long long i=2;i<=sqrt(n);++i)\n    {\n        if(n%i==0)\n            return 0;\n    }\n    return 1;\n}\nint main()\n{\n    long long x;\n    scanf(\"%Ld\",&x);\n    if(x<=1)\n    {\n        printf(\"1\\n\");\n        return 0;\n    }\n    if(is_prime(x))printf(\"1\\n\");\n    else\n    {\n        if(x%2==0)printf(\"2\\n\");\n        else \n        {\n            if(is_prime(x-2))printf(\"2\\n\");\n            else \n            printf(\"3\\n\");\n        }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c8d058f5a19ba4e262951fd49d63938a", "src_uid": "684ce84149d6a5f4776ecd1ea6cb455b", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <bits/stdc++.h>\nusing namespace std;\nbool isprime(int n) {\n    if(n < 2)\n        return false;\n    for(int i = 2; i * i <= n; i++) \n        if(n % i == 0)\n            return false;\n    return true;\n}\nint main() {\n    int n;\n    cin >> n;\n    if(isprime(n)) \n        cout << 1 << endl;\n    else \n        if(n % 2 == 0) \n            cout << 2 << endl;\n        else \n            if(isprime(n - 2))\n                cout << 2 << endl;\n            else\n                cout << 3 << endl;\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "523e45436f11b217080d138b7473cfad", "src_uid": "684ce84149d6a5f4776ecd1ea6cb455b", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint n;\nbool prime();\nbool p[2000000010];\nint main(){\n    int i,j,t;\n    scanf(\"%d\",&n);\n    t=2000000010;\n    p[0]=p[1]=false;\n    for(i=2;i<t;i++){\n        p[i]=true;\n    }\n    for(i=2;i*i<t;i++){\n        if(p[i]){\n            for(j=i*i;j<=t;j+=i){\n                p[j]=false;\n            }\n        }\n    }\n    j=1;\n    while(!prime()){\n        j++;\n    }\n    printf(\"%d\",j);\n    return 0;\n}\nbool prime(){\n    int i;\n    if(p[n]){\n        return true;\n    }\n    for(i=n-2;!p[i];i--);\n    n=i;\n    return false;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3dbcafdc459438d6928360672f276617", "src_uid": "684ce84149d6a5f4776ecd1ea6cb455b", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint isPrime(unsigned long num)\n{\n    \n    unsigned long limit;\n    limit = sqrt(num);\n    for(div = 3 ; div <= limit ; div++)\n        if(num % div == 0)\n           break;\n    if(div > limit)  return 1;\n    else return 0;\n    \n}\nint main()\n{\n    unsigned long num ;\n    scanf(\"%lu\" , &num);\n    if(num == 2)\n        printf(\"1\");\n    else if( num % 2 == 0 )\n      printf(\"2\");\n    else if( isPrime(num) == 1)\n      printf(\"1\");\n    else if( isPrime(num -2 ) == 1)\n     printf(\"2\");\n    else\n     printf(\"3\");\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3447dd268598f2bfa5c12b8b6cf4ed69", "src_uid": "684ce84149d6a5f4776ecd1ea6cb455b", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int x,y,a=0,b;\n    scanf(\"%d %d\",&x,&y);\n    for(int i=1;i<7;i++)\n    {\n        if(i>=x&&i>=y)\n        a++;\n    }\n    if(a==6)\n    printf(\"1/1\");\n    else if (a<=3)\n    {\n        b=6/a;\n        printf(\"1/%d\",b);\n    }\n    else if (a==4)\n    {\n        printf(\"2/3\");\n        \n    }\n    else\n    printf(\"5/6\");\n    \n    return(0);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0904bea00917d9fe2bab86e9ebe74d03", "src_uid": "f97eb4ecffb6cbc8679f0c621fd59414", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio>\nint main(){\n    int a,b;\n    scanf(\"%d%d\",&a,&b);\n    int max=a>b?a:b;\n    int ans=6-max+1;\n    if(ans%2==0) printf(\"%d/3\"ans/2);\n    else if(ans==3) printf(\"1/2\");\n    else if(ans==6) printf(\"1/1\");\n    else printf(\"%d/6\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bda2acf8a373b38accf3eeda306d7e70", "src_uid": "f97eb4ecffb6cbc8679f0c621fd59414", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main() {\n\tint y,w;\n\tscanf(\"%d%d\",&y&w);\n\t\n\tif(y>w) max=y;\n\telse max=w;\n\t\n\tif(6-max+1==1) printf(\"1/6\\n\");\n\telse if(6-max+1==2) printf(\"1/3\\n\");\n\telse if(6-max+1==3) printf(\"1/2\\n\");\n\telse if(6-max+1==4) printf(\"2/3\\n\");\n\telse if(6-max+1==5) printf(\"5/6\\n\");\n\telse if(6-max+1==6) printf(\"1/1\\n\");\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "05aa976d196347869d9e2c4d9dd40dd1", "src_uid": "f97eb4ecffb6cbc8679f0c621fd59414", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "using namespace std;\n\n\n\nint main()\n{\n    int yako,wako,result;\n    cin>>yako>>wako;\n    if(yako == 6 || wako == 6){\n        cout<<\"1/6\";\n    }\n    else if(yako == 1 && wako == 1){\n        cout<<\"1\";\n    }\n    else if(yako > wako){\n         result = 6 - (yako - 1);\n         if(result % 2 == 0 && result>= 2){\n            result = result /2;\n            cout<<result<<\"/3\"<<endl;\n         }\n         else if (result % 3 == 0 && result >=3){\n            result = result / 3;\n            cout<<result<<\"/2\"<<endl;\n         }\n         else{\n            cout<<result<<\"/6\"<<endl;\n         }\n\n    }else if (wako >= yako){\n          result = 6 - (wako - 1);\n     if(result % 2 == 0 && result>= 2){\n            result = result /2;\n            cout<<result<<\"/3\"<<endl;\n         }\n         else if (result % 3 == 0 && result >=3){\n            result = result / 3;\n            cout<<result<<\"/2\"<<endl;\n         }\n         else{\n            cout<<result<<\"/6\"<<endl;\n         }\n\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6c1c546c1d357ee63cf1bcb369e6d571", "src_uid": "f97eb4ecffb6cbc8679f0c621fd59414", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n\nusing namespace std;\n\n\n\nint main()\n{\n    int yako,wako,result;\n    cin>>yako>>wako;\n    if(yako == 6 || wako == 6){\n        cout<<\"1/6\";\n    }\n    else if(yako == 1 && wako == 1){\n        cout<<\"1\";\n    }\n    else if(yako > wako){\n         result = 6 - (yako - 1);\n         if(result % 2 == 0 && result>= 2){\n            result = result /2;\n            cout<<result<<\"/3\"<<endl;\n         }\n         else if (result % 3 == 0 && result >=3){\n            result = result / 3;\n            cout<<result<<\"/2\"<<endl;\n         }\n         else{\n            cout<<result<<\"/6\"<<endl;\n         }\n\n    }else if (wako >= yako){\n          result = 6 - (wako - 1);\n     if(result % 2 == 0 && result>= 2){\n            result = result /2;\n            cout<<result<<\"/3\"<<endl;\n         }\n         else if (result % 3 == 0 && result >=3){\n            result = result / 3;\n            cout<<result<<\"/2\"<<endl;\n         }\n         else{\n            cout<<result<<\"/6\"<<endl;\n         }\n\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9baac93ed388ddeb0bdb3a3b82257dc3", "src_uid": "f97eb4ecffb6cbc8679f0c621fd59414", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nusing namespace std;\nint main()\n{\n\tint n,a,b;\n\tcin>>n>>a>>b;\n\tint t[n];\n\tfor(int i=0;i<n;i++)\n\t{\n\t\tcin>>t[i];\n\t}\n\tfor(int i=0;i<n/2;i++)\n\t{\n\t\tif((t[i]!=2&&t[n-i-1]!=2)&&t[i]!=t[n-i-1])\n\t\t{\n\t\t\tcout<<\"-1\";\n\t\t\treturn 0;\n\t\t}\n\t}\n\tint s=0;\n\tif(n%2==1)\n\t{\n\t\tif(t[n/2]==2)\n\t\t{\n\t\t\tif(a>b) s+=b;\n\t\t\telse s+=a;\n\t\t}\n\t}\n\tfor(int i=0;i<n/2;i++)\n\t{\n\t\tif(t[i]==2&&t[n-i-1]==2)\n\t\t{\n\t\t\tif(a>b) s+=(2*b);\n\t\t\telse s+=(2*a);\n\t\t}\n\t\telse if(t[i]==2||t[n-i-1]==2)\n\t\t{\n\t\t\tif(t[i]==0||t[n-i-1]==0) s+=a;\n\t\t\telse s+=b;\n\t\t}\n\t}\n\tcout<<s;\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "46d7b82d000975a1d82fd7f74d34b7ce", "src_uid": "af07223819aeb5bd6ded4340c472b2b6", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,w,b,i,t=0;\n    scanf(\"%d %d %d\",&n,&w,&b);\n    int a[n];\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    for(i=0;i<n/2+1;i++)\n    {\n        if((a[i]!=a[n-i-1])&&(a[i]!=2)&&(a[n-i-1]!=2))\n        {\n            printf(\"-1\");\n            break;\n        }\n        else \n        {\n            if(a[i]==2&&a[n-i-1]==2)\n            {\n                if(i!=n-i-1)\n                {\n                \tw>=b?(t=t+b):(t=t+w);\n\t\t\t\t}\n\t\t\t\tw>=b?(t=t+b):(t=t+w);\n            }\n            else\n            {\n                if(a[i]!=a[n-i-1])\n                {\n                    a[i]==1?t=t+b:t==t;\n                    a[i]==0?t=t+w:t==t;\n                    a[n-i-1]==1?t=t+b:t=t;\n                    a[n-i-1]==0?t=t+w:t=t;\n                }\n            }\n        }\n    }\n    printf(\"%d\\n\",t);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "30b40c454b278ca57b19db4674c02a98", "src_uid": "af07223819aeb5bd6ded4340c472b2b6", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,w,b,i,t=0;\n    scanf(\"%d %d %d\",&n,&w,&b);\n    int a[n];\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    for(i=0;i<n/2+1;i++)\n    {\n        if((a[i]!=a[n-i-1])&&(a[i]!=2)&&(a[n-i-1]!=2))\n        {\n            printf(\"-1\");\n            break;\n        }\n        else \n        {\n            if(a[i]==2&&a[n-i-1]==2)\n            {\n                if(i!=n-i-1)\n                {\n                \tw>=b?t=t+b:t=t+w;\n\t\t\t\t}\n\t\t\t\tw>=b?t=t+b:t=t+w;\n            }\n            else\n            {\n                if(a[i]!=a[n-i-1])\n                {\n                    a[i]==1?t=t+b:t=t;\n                    a[i]==0?t=t+w:t=t;\n                    a[n-i-1]==1?t=t+b:t=t;\n                    a[n-i-1]==0?t=t+w:t=t;\n                }\n            }\n        }\n    }\n    printf(\"%d\\n\",t);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ff044e965db4160a172469520e8fbbd4", "src_uid": "af07223819aeb5bd6ded4340c472b2b6", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "\t{\n\tfor(int i=0;i<n/2;i++)\n\t{\n\t\tif((p[i]!=p[n-i-1]) && ((p[i]==1 && p[n-i-1]==0) || (p[i]==0 && p[n-i-1]==1)))\n\t\t{\n\t\t\tcost=-1;\n\t\t\tbreak;\n\t\t}\n\t\telse if(p[i]==0 && p[n-i-1]==2 || p[i]==2 && p [n-i-1]==0)\n\t\t{\n\t\t\tcost+=a;\n\t\t}\n\t\telse if(p[i]==1 && p [n-i-1]==2 || p[i]==2 && p [n-i-1]==1)\n\t\t{\n\t\t\tcost+=b;\n\t\t}\n\t\telse if(p[i]==2 && p[n-i-1]==2)\n\t\t{\n\t\t\tif(i!=n/2)\n\t\t\t{\n\t\t\tif(a<b)\n\t\t\t\tcost+=(2*a);\n\t\t\telse\n\t\t\t\tcost+=(2*b);\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tif(a<b)\n\t\t\t\tcost+=a;\n\t\t\t\telse\n\t\t\t\tcost+=b;\n\t\t\t}\n\n\t\t}\n\t}}", "lang_cluster": "C", "compilation_error": true, "code_uid": "92824efa82abfc5a5a339a2337b51cf4", "src_uid": "af07223819aeb5bd6ded4340c472b2b6", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main(){\nint n,a,b,i;\nscanf(\"%d\",&n);\nscanf(\"%d\",&a);\nscanf(\"%d\",&b);\ngetchar_unlocked();\nint po[n];\nfor(i=0;i<n;i++){\nscanf(\"%d\",&po[i]);\ngetchar();\n}\nint cost=0,flag=1;\nfor(i=0;i<n/2;i++){\n\tif(po[i]==po[n-i-1]){}\n\telse if((po[i]==0 && po[n-i-1]==1) || (po[i]==1 && po[n-i-1]==0)){\n\t\tflag=0;\t\n\t\tbreak;\n\t}\n\telse{\n\t\tif(po[i]==0 || po[n-1-i]==0)\n\t\t\tcost+=a;\n\t\tif(po[i]==1 || po[n-1-i]==1)\n\t\t\tcost+=b;\n\t}\n}\nif((n&1) && (po[n/2]==2))\ncost+=b;\nif(flag==0)\nprintf(\"-1\");\nelse\nprintf(\"%d\",cost);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7c5e00969a233c0feecda3eedde9a222", "src_uid": "af07223819aeb5bd6ded4340c472b2b6", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "/*\n * code1.c\n * \n * Copyright 2019  <examuser@11CPU0119L>\n * \n * This program is free software; you can redistribute it and/or modify\n * it under the terms of the GNU General Public License as published by\n * the Free Software Foundation; either version 2 of the License, or\n * (at your option) any later version.\n * \n * This program is distributed in the hope that it will be useful,\n * but WITHOUT ANY WARRANTY; without even the implied warranty of\n * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the\n * GNU General Public License for more details.\n * \n * You should have received a copy of the GNU General Public License\n * along with this program; if not, write to the Free Software\n * Foundation, Inc., 5ytu1 Franklin Street, Fifth Floor, Boston,\n * MA 02110-1301, USA.\n * \n * \n */\n\n\n#include <stdio.h>\n\nint main(int argc, char **argv)\n{\n\tint y,b,r,total=0,least;\n\tscanf(\"%d%d%d\",&y,&b,&r);\n\tleast=9999;\n\tif(least>y)\n\t{\n\t\tleast=y;\n\t}\n\tif(least>b)\n\t{\n\t\tleast=b;\n\t}\n\tif(least>r)\n\t{\n\t\tleast=r;\n\t}\n\t\n\t\n\tif(least==y)\n\t{\n\t\tif((y==b && y==r) || (y==r && b>r))\n\t\t{\n\t\t\ttotal=(r*3)-3;\n\t\t\tprintf(\"%d\",total);\n\t\t\t\n\t\t}\n\t\telse if(y==b && b<r)\n\t\t{\n\t\t\ttotal=(b*3);\n\t\t\t)\n\t\t\tprintf(\"%d\",total);\n\t\t\t\n\t\t}\n\t\telse if(b>r)\n\t\t{\n\t\t\ttotal=(r*3)-3;\n\t\t\tprintf(\"%d\",total);\n\t\t}\n\t\telse {\n\t\t\ttotal=(y*3)+3;\n\t\t\tprintf(\"%d\",total);\n\t\t\t\n\t\t}\n\t}\n\t\t\t\n\tif(least==b && least!=y)\n\t{\n\t\tif(r>b)\n\t\t{\n\t\t\ttotal=(b*3);\n\t\t\tprintf(\"%d\",total);\n\t\t\t\n\t\t}\n\t\telse{\n\t\t\t\ttotal=(r*3)-3;\n\t\t\t\tprintf(\"%d\",total);\n\t\t\t\t\n\t\t\t}\n\t}\n\tif(least==r && least!=y)\n\t{\n\t\ttotal=(r*3)-3;\n\t\tprintf(\"%d\",total);\n\t}\n\treturn 0;\n}\n\t\n\t\n\t\t\n\t\n\t\n\t\t\n\t\n\t\t\n\t\n\t\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "07ef1c2241f03d6bb398bb75ab820a8f", "src_uid": "03ac8efe10de17590e1ae151a7bae1a5", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<algorithm>\nusing namespace std;\n\nint main()\n{\n    int p,q,r;\n    scanf(\"%d %d %d\",&p,&q,&r);\n    int c = min(p,min(q,r));\n    printf(\"%d\\n\",c+(c-1)+(c+1));\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5871483a1f491ac10477fc1f93f5508c", "src_uid": "03ac8efe10de17590e1ae151a7bae1a5", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{  int y,b,r,s;\n   scanf(\"%d\",&y);\n   scanf(\"%d\",&b);\n   scanf(\"%d\",&r);\n   y++;\n   r--;\n   s=3*min(int y,int b,int r);\n   printf(\"%d\",&s);\n   return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4cf80adb7a00d1636a96099e98b7e988", "src_uid": "03ac8efe10de17590e1ae151a7bae1a5", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nint r,y,b;\nscanf(\"%d\",r);\nscanf(\"%d\",b);\nscanf(\"%d\",y);\nif (b>=r&&y>=b)\n{\nb=r-1;\ny=b-1;\nprintf(\"%d\",r+b+y);\n}\nelse if(b<r&&b<y)\n{\n    r=b+1;\n    y=b-1;\n}\nelse\n{\n    b=y+1;\n    r=b+1;\n}\n    \n}\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a8d1d148a1257e9fae187079f17d4a73", "src_uid": "03ac8efe10de17590e1ae151a7bae1a5", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint min(int a,int b) {\n    if(a<b)\n    return a;\n    else\n    return b;\n}\nint main() {\n    int a,b,c;\n    scanf(\"%d %d %d\",&a,&b,&c);\n    int r = min(b+1,c);\n    int r1 = min(a-2,r);\n    printf(\"%d\",min(r,r1)*3)-3);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "135349449ea2f69badb438414db6175e", "src_uid": "03ac8efe10de17590e1ae151a7bae1a5", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "erview\nProblem\nStatus\nRank (18:00:00)\n0 Comments\nSettingFavoriteClone\nPrevious12345\u2026NextFilterReset\nUsername\n\nProb\n\tResult \n\tTime\n(ms)\tMem\n(MB)\tLang \n\tSubmit Time\ntasfikrahman007\nC\nAccepted\n15\t0.1\t\nC++\n5 days ago\n94abrar\nC\nAccepted\n15\t\t\nC++\n5 days ago\n\nAll Copyright Reserved \u00a92010-2017 Xu Han \nServer Time: 2017-10-05 00:02:44 BST\n\n#10868326 | 94abrar's solution for [CodeForces-864B] [Problem C]\nStatus\nAccepted\nTime\n15ms\nLength\n578\nLang\nGNU G++ 5.1.0\nSubmitted\n2017-09-29 15:03:04\nShared\n\nRemoteRunId\n30824205\nSelect Code\n#include<stdio.h>\n#include<conio.h>\n#include<string.h>\nint main()\n{\n\tint n,i,j,k,l,flag=1;\n\tscanf(\"%d\",&n);\n\tchar x[n+1],y[n+1];\n\tint c[n];\n    getchar();\n\tgets (x);\n\tfor (i=0;i<n;i++) c[i]=0;\n\tj=0;\n\tk=0;\n\tfor (i=0;i<n;i++){\n\t\tif (x[i]>='a' && x[i]<='z') {\n\t\t\tflag=1;\n\t\t\ty[k]=x[i];\n\t\t\tfor (l=0;l<k;l++){\n\t\t\t\tif (y[l]==x[i]) flag=0;\n\t\t\t}\n\t\t\tif (flag==1){\n\t\t\t\tc[j]++;\n\t\t\t//\tprintf(\"%c \",y[k]);\n\t\t\t}\n\t\t\tk++;\n\t\t}\n\t\telse if (x[i]>='A' && x[i]<='Z') {\n\t\t\tj++;\n\t\t\tc[j]=0;\n\t\t\tk=0;\n\t\t}\n\t}\n\tint max=0;\n\tfor (i=0;i<n;i++){\n\t\tif (max<c[i]) max=c[i];\n\t}\n\tprintf(\"%d\",max);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "03849277da462d2b5c135216b5e71b67", "src_uid": "567ce65f87d2fb922b0f7e0957fbada3", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\nint n,m,a[1000],max,sum,o;\nchar str[1000];\nwhile(scanf(\"%d\",&n)!=EOF)\n{\ngetchar();\ngets(str);\n    max=0,sum=0;\n    for(i=0;i<n;i++)\n\t{\n        if(str[i]>='A'&&str[i]<='Z')\n\t\t{\n\t\t\tmemset(a,0,sizeof(a));\n            sum=(sum>max)?sum:max;\n            max=0;\n        }\n\t\telse\n            if(a[str[i]]==0)\n\t\t\t{\n                a[str[i]]=1;\n                max++;\n            }\n    }\n    sum=(sum>max)?sum:max;\n    printf(\"%d\\n\",sum);\n}\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a32c505a17e8f0c71d6a5c612f3f7cc1", "src_uid": "567ce65f87d2fb922b0f7e0957fbada3", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\n#include<string.h>\n#define max(a,b) a>b?a:b;\n#define min(a,b) (a>b?b:a)\nint main()\n{\n   int T;\n   while(scanf(\"%d\",&T)!=EOF)\n   {\n   \twhile(T--)\n   \t{\n   \t\tint n,sum,k,w[110],v[110],dp[110][35],a[35],b[35];\n   \t\tmemset(dp,0,sizeof(dp));\n   \t\tmemset(a,0,sizeof(a));\n   \t\tmemset(b,0,sizeof(b));\n   \t\tscanf(\"%d %d %d\",&n,&sum,&k);\n   \t\tfor(int i=0;i<n;i++)\n   \t\t\tscanf(\"%d\",&v[i]);\n   \t\tfor(int i=0;i<n;i++)\n   \t\t\tscanf(\"%d\",&w[i]);\n   \t\tfor(int i=0;i<n;i++)\n   \t\t{\n   \t\t\tfor(int j=sum;j>=w[i];j--)\n   \t\t\t{\n   \t\t\t\tfor(int z=1;z<=k;z++) \n\t\t\t\t{\n\t\t\t\t\ta[z]=dp[j][z];\n\t\t\t\t\tb[z]=dp[j-w[i]][z]+v[i];\n\t\t\t\t}\n\t\t\t\tfor(int x=1,y=1,z=1;z<=k&&(x<=k||y<=k);)\n\t\t\t\t{\n\t\t\t\t\tif(a[x]>b[y])\n\t\t\t\t\t{\n\t\t            \tdp[j][k]=a[x];\n\t\t                x++;\n\t\t            }\n\t\t            else\n\t\t\t\t\t{\n\t\t                dp[j][k]=b[y];\n\t\t                y++;\n\t\t            }\n\t\t            if(dp[j][k] != dp[j][k-1])\n\t\t            \tk++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\",dp[sum][k]);\n\t}\n   }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "87e0b62559efd748e2a93d0c22b2f949", "src_uid": "567ce65f87d2fb922b0f7e0957fbada3", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<ctype.h>\n#include<string.h>\n\n#define max(a ,b)\t(a > b ? a : b)\n#define min(a ,b)\t(a < b ? a : b)\n#define MAX 200001\n/*\nint a[101];\nint main() {\n\tint n ,i ,x ,y;\n\tscanf(\"%d\" ,&n);\n\tfor(i = 0;i<n;i++){\n\t\tscanf(\"%d\" ,&x);\n\t\ta[x]++;\n\t}\n\tint total = 0;\n\tfor(i = 1;i<=100;i++)\tif(a[i])\ttotal++;\n\tif(total == 2){\n\t\tint first = 0 ,second = 0;\n\t\tfor(i = 1; i<=100;i++){\n\t\t\tif(a[i]){\n\t\t\t\tif(first){\tsecond = a[i];\ty = i;\t}\n\t\t\t\telse{ first = a[i];\tx = i;\t}\n\t\t\t}\n\t\t}\t\n\t\tif(first == second){\tprintf(\"YES\\n%d %d\" ,x ,y);\t}\n\t\telse printf(\"NO\\n\");\n\t}else printf(\"NO\\n\");\n\treturn 0;\n}\n*/\n/*char s[201];\nint c[26];\nint main() {\n\tint n ,i ,j;\n\tscanf(\"%d\" ,&n);\n\tscanf(\" %s\" ,s);\n\tint ans = 0 ,x = 0;\n\ti = 0;\n\twhile(i < n) {\n\t\tif(islower(s[i])){\n\t\t\tif(!c[s[i]-'a']){\n\t\t\t\tx++;\n\t\t\t\tc[s[i] - 'a'] = 1;\n\t\t\t}\n\t\t}else{\n\t\t\tans = max(ans ,x);\n\t\t\tx = 0;\n\t\t\tmemset(c ,0 ,sizeof(c));\n\t\t}\n\t\ti++;\n\t}\n\tans = max(ans ,x);\n\tprintf(\"%d\" ,ans);\n\treturn 0;\n}*/\n/*\nint main(){\n\tint a ,b ,f ,k ,i;\n\tscanf(\"%d%d%d%d\" ,&a ,&b ,&f ,&k);\n\tif(b < f || b < 2*(a - f) || b < 2*f)\tprintf(\"-1\");\n\telse{\t\n\t\tint ans = 0 ,rem = b;\n\t\tfor(i = 0 ; i < k ; i++){\n\t\t\tif(i == k-1){\n\t\t\t\tif(rem < a)\tans++;\n\t\t\t}else{\n\t\t\t\tif(i % 2 == 0){\n\t\t\t\t\tif(rem < f){\n\t\t\t\t\t\tprintf(\"-1\");\treturn 0;\n\t\t\t\t\t}\n\t\t\t\t\tif(rem >= 2*a - f)\trem -= a;\n\t\t\t\t\telse ans++ ,rem = b - (a - f);\n\t\t\t\t}else {\n\t\t\t\t\tif(rem < a - f){\n\t\t\t\t\t\tprintf(\"-1\");\treturn 0;\n\t\t\t\t\t}\n\t\t\t\t\tif(rem >= a + f)\trem -= a;\n\t\t\t\t\telse\tans++ ,rem = b - f;\n\t\t\t\t}\n\t\t\t}\t\n\t\t\tprintf(\"%d \" ,rem);\n\t\t}\n\t\tprintf(\"\\n%d\" ,ans);\n\t}\n\treturn 0;\n}\n*/\n/*\nint a[MAX] ,p[MAX] ,c[MAX];\nint main() {\n\tint n ,i;\n\tscanf(\"%d\" ,&n);\n\tmemset(p ,-1 ,sizeof(p));\n\tfor(i = 1 ; i <= n ; i++){\n\t\tscanf(\"%d\" ,a+i);\n\t\tif(p[a[i]] == -1)\tp[a[i]] = i;\n\t\tc[a[i]]++;\n\t}\n\tint ans = 0 , r = 0;\n\tfor(i = 1;i<=n;i++){\n\t\tif(c[i] == 0){\n\t\t\tr++;\n\t\t\twhile(r <= n && c[i] == 0) {\n\t\t\t\tif(c[a[r]] > 1){\n\t\t\t\t\tif(p[a[r]] == r &&  a[r] < i){\n\t\t\t\t\t\tr++;\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t\tans++;\n\t\t\t\t\ta[r] = i;\n\t\t\t\t\tc[i] = 1;\n\t\t\t\t\tc[a[r]]--;\n\t\t\t\t\tr--;\n\t\t\t\t}\n\t\t\t\tr++;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\" ,ans);\n\tfor(i = 1; i <=n;i++)\tprintf(\"%d \" ,a[i]);\n\treturn 0;\n}\n*/", "lang_cluster": "C", "compilation_error": true, "code_uid": "c4164dfcfba74c51fc6c31732ce31ffe", "src_uid": "567ce65f87d2fb922b0f7e0957fbada3", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\nint n,m,a[1000]={0},max,sum;\nchar str[1000];\nwhile(scanf(\"%d\",&n)!=EOF)\n{\ngetchar();\ngets(str);\n    max=0; sum=0;\n    for(int i=0;i<n;i++)\n\t{\n        if(str[i]>='A'&&str[i]<='Z')\n\t\t{\n\t\t\tmemset(a,0,sizeof(int a));\n            sum=(sum>max)?sum:max;\n            max=0;\n        }\n\t\telse\n            if(a[str[i]]==0)\n\t\t\t{\n                a[str[i]]=1;\n                max++;\n            }\n    }\n    sum=(sum>max)?sum:max;\n    printf(\"%d\\n\",sum);\n}\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e0a8b658077aee46155b0e46112e3961", "src_uid": "567ce65f87d2fb922b0f7e0957fbada3", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint ans;\nbool zero;\n\nint main()\n{\n    unsigned int n;\n    int k;\n\n    scanf(\"%u%d\", &n, &k);\n\n    for (int i = 0; i < k; i++, n/=10)\n    {\n        if (n == 0)\n        {\n            if (zero == 1)\n            {\n                printf(\"%d\", i-1);\n            }\n            else\n            {\n                printf(\"%d\", i);\n            }\n            return 0;\n        }\n        if (n%10 != 0)\n        {\n            ans++;\n            k++;\n        }\n        else\n        {\n            zero = 1;\n        }\n    }\n\n    printf(\"%d\", ans);\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1f3bd2a6a0e1562b991187f2fc3c0ffe", "src_uid": "7a8890417aa48c2b93b559ca118853f9", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,k,s,i,j,m,t,a[20];\n\twhile(~scanf(\"%d%d\",&n,&k))\n\t{\n\t\ta[20]={0};\n\t\ts=0;\n\t\tfor(i=0;n!=0;i++)\n\t\t{\n\t\t\ta[i]=n%10;\n\t\t\tn/=10;\n\t\t}\n\t\tif(k>i)\n\t\t    printf(\"%d\",i-1);\n\t\telse\n\t    {\n\t    \tt=0;\n\t\t    for(j=0;t<k;j++)\n\t\t    {\n\t\t    \tif(a[j]!=0)\n\t\t    \t    s++;\n\t\t    \telse\n\t\t    \t    t++;    \n\t    \t}\t\t\t\n\t    \tprintf(\"%d\\n\",s);\n\t\t}\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e8eb171135867a70a2d87926535cdcff", "src_uid": "7a8890417aa48c2b93b559ca118853f9", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint a[2000000005];\nint main(){\n\tint k,ans = 0,cnt = 0;\n\tlong long n;\n\tscanf(\"%I64d%d\",&n,&k);\n\tint n1 = n;\n\tint i = 0,judge = 0;\n\twhile(n1 >= 10){\n\t\ta[++i] = n1 % 10;\n\t\tn1 = (n1 - a[i]) / 10;\n\t\tif(a[i] == 0)\tjudge = 1;\n\t}\n\ta[++i] = n1;\n\tif(i < k){\n\t\tif(judge == 1){\n//\t\t\tprintf(\"judge = 1\\n\");\n\t\t\tprintf(\"%d\\n\",i-1);\n\t\t}\n\t\telse{\n//\t\t\tprintf(\"judge = 0\\n\");\n\t\t\tprintf(\"%d\\n\",i);\n\t\t}\n\t}else{\n\t\tfor(int j = 1;j <= i;j++){\n\t\t\tif(a[j] == 0)\tcnt++;\n\t\t\telse\tans++;\n\t\t\tif(cnt >= k)\tbreak;\n\t\t}\n\t\tprintf(\"%d\\n\",ans);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e902a6e26298d70403b08d340d5b35c5", "src_uid": "7a8890417aa48c2b93b559ca118853f9", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint huynya (int chislo, int stepen)\n{\n    int t=chislo;\n    int digits=0;\n    int deleted=0;\n    int zeros=0;\n    do  {\n        digits++;\n        t/=10;\n    }while(t);\n   // printf(\"%d\",digits);\n    if (stepen=>digits)\n     return digits-1;\n     else {\n        while(zeros<stepen) {\n            if (chislo % 10==0)\n                zeros++;\n            else\n                deleted++;\n             chislo/=10;\n        }\n    }\n    return deleted;\n}\nint main()\n{\n    int number; int stepen;\n    scanf(\"%d\",&number);\n    scanf(\"%d\",&stepen);\n    printf(\"%d\",huynya(number,stepen));\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7978b2e78883283ffd76985e43013c21", "src_uid": "7a8890417aa48c2b93b559ca118853f9", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nvoid main(){\n    int k;\n    char s[2000001];\n\n    scanf(\"%s %d\", &s, &k);\n\n    int size = strlen(s) - 1;\n    int i, count = 0;\n\n    for(i = size; i >= 0; i--){\n       if(k == 0){\n            printf(\"%d\", count);\n            return;\n       }\n       if(s[i] == '0'){\n            k--;\n       }else {\n            count++;\n       }\n    }\n    printf(\"%d\", size);\n    return;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2147a0c5daa5717d1953009dc7934064", "src_uid": "7a8890417aa48c2b93b559ca118853f9", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n\nint cmp(const void *a, const void *b)\n{\n\treturn *(int *)a - *(int *)b;\n}\nint min(int a,int b)\n{\n\tif(a>b)\n\t\treturn b;\n\treturn a;\n}\nint swap(int *a,int *b)\n{\n\tint t=*a;\n\t*a=*b;\n\t*b=t;\n}\n\nint main()\n{\n\tint i,n,j,k;\n\tscanf(\"%d\",&n);\n\tint a[12]={31,29,31,30,31,30,31,31,30,31,30,31};\n\tint b[24],count=0;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\",&b[i]);\n\t\tif(b[i]==29)\n\t\t\tcount++;\n\t\tif(b[i]==28)\n\t\t\tb[i]=29;\n\t}\n\tif(count>=2)\n\t{\n\t\tprintf(\"No\\n\");\n\t\treturn 0;\n\t}\n\tint val;\n\tfor(i=0;i<12;i++)\n\t{\n\t\t\n\t\tif(a[i]==b[0])\n\t\t{\n\t\t\tval=1,k=0;\n\t\t\tfor(j=i;j<12 && k<=n;j++)\n\t\t\t{\n\t\t\t\tif(a[j]==b[k])\n\t\t\t\t{\n\t\t\t\t\tk++;\n\t\t\t\t\tif(j==11)\n\t\t\t\t\t\tj = -1;\n\t\t\t\t\tif(k==n)\n\t\t\t\t\t\tbreak;\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tval=0;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(val==1)\n\t\t\tbreak;\n\t}\n\tif(val==1)\n\t\tprintf(\"Yes\\n\");\n\telse\n\t\tprintf(\"No\\n\");\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9b21d082ca7c8baf8170f6ec96bf6c95", "src_uid": "d60c8895cebcc5d0c6459238edbdb945", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int month[24],i,n,j,k=0,m=0;\n    int year[]={31,28,31,30,31,30,31,31,30,31,30,31,\n                31,28,31,30,31,30,31,31,30,31,30,31,\n                31,29,31,30,31,30,31,31,30,31,30,31,\n                31,28,31,30,31,30,31,31,30,31,30,31,\n                31,28,31,30,31,30,31,31,30,31,30,31,};\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++)\n        scanf(\"%d\",&month[i]);\n    for(i=0;i<60;i++)\n    {\n        k=0;\n        for(j=0;j<n;j++)\n            if(month[j]==year[i+j])\n                k++;\n        if(k==n)\n        {m=1;break;}\n    }\n    if(m==1)\n        printf(\"Yes\");\n    else\n        printf(\"No\\n\");\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c53f12074653ca15abb534640993c0cb", "src_uid": "d60c8895cebcc5d0c6459238edbdb945", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    int arr[80]={31,28,31,30,31,30,31,31,30,31,30,31,31,28,31,30,31,30,31,31,30,31,30,31,31,29,31,30,31,30,31,31,30,31,30,31,31,28,31,30,31,30,31,31,30,31,30,31,31,28,31,30,31,30,31,31,30,31,30,31,31,28,31,30,31,30,31,31,30,31,30,31};\n    int n;\n    scanf(\"%d\",&n);\n    int arr1[n];\n    int i;\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&arr1[i]);\n    }\n    int j,flag=1;\n    for(i=0;i<=48;i++)\n    {\n        if(arr1[0]==arr[i])\n        {\n            for(j=i;j<i+n;j++)\n            {\n                flag=1;\n                if(arr1[j-i]!=arr[j])\n                {\n                    flag=0;\n                    break;\n                }\n            }\n            if(flag==0)\n            {\n                i=i;\n            }\n            else if(flag==1)\n            {\n                break;\n            }\n        }\n        else\n        {\n            i=i;\n        }\n    }\n    if(flag==1)\n    {\n        printf(\"Yes\");\n    }\n    else\n    {\n        printf(\"No\");\n    }\n\n\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "459192e74e3caa4b1c406fb80d27a075", "src_uid": "d60c8895cebcc5d0c6459238edbdb945", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n int n,p=0,d,i,j;\n int a[24];\n int b[24]={31,28,31,30,31,30,31,31,30,31,30,31,31,29,31,30,31,30,31,31,30,31,30,31}; \n int c[24]={31,29,31,30,31,30,31,31,30,31,30,31,31,28,31,30,31,30,31,31,30,31,30,31};\n int f[24]={31,28,31,30,31,30,31,31,30,31,30,31,31,28,31,30,31,30,31,31,30,31,30,31};\n scanf(\"%d\",&n);\n for(i=0;i<n;i++)\n\t scanf(\"%d\",&a[i]);\n for(i=0;i<24;i++)\n  if(a[0]==b[i])\n  {\n\t  p=1;\n\tfor(j=0;j<n;j++)\n\t{\n\t\td=i+j;\n\t\td%=24;\n\tif(a[j]!=b[d])\n\tp=0;\n\t}\n\tif(p==1)\n\t\tbreak;\n  }\n  if(p==0)\n  {\nfor(i=0;i<24;i++)\n  if(a[0]==c[i])\n  {\n\t  p=1;\n\tfor(j=0;j<n;j++)\n\t{\n\t\td=i+j;\n\t\td%=24;\n\tif(a[j]!=c[d])\n\tp=0;\n\t}\n\tif(p==1)\n\t\tbreak;\n  }\n  }\n    if(p==0)\n  {\nfor(i=0;i<24;i++)\n  if(a[0]==f[i])\n  {\n\t  p=1;\n\tfor(j=0;j<n;j++)\n\t{\n\t\td=i+j;\n\t\td%=24;\n\tif(a[j]!=f[d])\n\tp=0;\n\t}\n\tif(p==1)\n\t\tbreak;\n  }\n  }\n  if(p==1)\n\t  printf(\"YES\\n\");\n  else\n\t  printf(\"NO\\n\");\n  return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "18ab9219e486ecfbada83c45a0197a91", "src_uid": "d60c8895cebcc5d0c6459238edbdb945", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n#include <string.h>\nusing namespace std;\n\nint main()\n{\n    char seq[][3] = {\"31\", \"28\", \"31\", \"30\", \"31\", \"30\", \"31\", \"31\", \"30\", \"31\", \"30\", \"31\", \"31\", \"28\", \"31\", \"30\", \"31\", \"30\", \"31\", \"31\", \"30\", \"31\", \"30\", \"31\", \"31\", \"29\", \"31\", \"30\", \"31\", \"30\", \"31\", \"31\", \"30\", \"31\", \"30\", \"31\", \"31\", \"28\", \"31\", \"30\", \"31\", \"30\", \"31\", \"31\", \"30\", \"31\", \"30\", \"31\"};\n    char inp[24][3];\n    int n, flag;\n    cin >> n;\n    for(int i = 0; i < n; i++)\n        cin >> inp[i];\n    for(int i = 0; i < 48; i++)\n    {\n        if(strcmp(inp[0], seq[i]) == 0)\n        {\n            flag = 0;\n            for(int j = 0; j < n; j++)\n            {\n                if(strcmp(inp[j], seq[j + i]))\n                {\n                    flag = 1;\n                    break;\n                }\n            }\n        }\n        if(!flag)\n        {\n            cout << \"Yes\" << endl;\n            return 0;\n        }\n    }\n    cout << \"No\" << endl;\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4674ffe9e86d36e6491587d3099a8bbe", "src_uid": "d60c8895cebcc5d0c6459238edbdb945", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint main()\n{\n    int n,i,x,sum=0;\n\n    cin>>n;\n\n    x = (n*2-1);\n\n    for(i=x-2;i>=1;i=i-2)\n    {\n        sum+=i;\n    }\n\n    x = x + (sum*2);\n\n    cout << x <<endl;\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "027712c88aa10f93084cb57749a672e4", "src_uid": "758d342c1badde6d0b4db81285be780c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    int n;\n    cin>>n;\n    cout>>((n*n)+((n-1)*(n-1)));\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1d7ba1bd95f81c1003db84351d3b2cd6", "src_uid": "758d342c1badde6d0b4db81285be780c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,s=1;\n\tscanf(\"%d\",&n);\n\tint i=1;\n\twhile (i<n)\n\t{\n\t\ts=s+(4*i);\n\t}\n\tif (n=1)\n\t\tprintf(\"%d\",1);\n\tprintf(\"%d\",s)\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1798bad040174eda04d03b854b0b495d", "src_uid": "758d342c1badde6d0b4db81285be780c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long n,s=1,cur=1,j;\n    scanf(\"%lld\",&n);\n    for(i=2,j=1;i<=n;i++,j++)\n    {\n        cur=cur+4*j;\n    }\n    if(n!=0)\n    {\n       printf(\"%lld\",cur); \n    }\n    else\n    {\n    printf(\"%lld\",s);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "98d08761de70e9e34d5d2371bbe5a4df", "src_uid": "758d342c1badde6d0b4db81285be780c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,sum=1;\n    scanf(\"%d\",&n);\n    if(n==1)\n        printf(\"1\");\n    else\n    {\n        for(i=1;i<n;i++)\n        {\n            sum = sum+(4*i);\n        }\n        printf(\"%d\",sum);\n    }\n        \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e34411c1ee65b985cd8afc3820edc9c3", "src_uid": "758d342c1badde6d0b4db81285be780c", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<limits.h>\n#include<stdlib.h>\n#include<ctype.h>\n#include<math.h>\nint arr[250]={31,29,31,30,31,30,31,31,30,31,30,31};\nint is_leap(int year){\n  if ( year%400 == 0)\n    return 1;\n  else if ( year%100 == 0)\n   return 0;\n  else if ( year%4 == 0 )\n    return 1;\n  else\n   return 0;\n  return 0;\n\t\n}\nint main(){\nint leap,a,b,c,d,e,f,g; int year;\nscanf(\"%d\",&year);\n\nleap=is_leap(year);\nint i; int week=1; \n\nfor(i=year+1;;i++){\n\tweek=is_leap(i)?week=(week+2)%7:week=(week+1)%7;\n\t\n\tif(is_leap(i)==leap && week==1){\n\t\tprintf(\"%d\",i);\n\t\treturn 0;\n\t}\n\t\n}\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e016e62c487c3b3c0d6aa02b5677d974", "src_uid": "565bbd09f79eb7bfe2f2da46647af0f2", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "int y;\n\nvoid read(void) {\n\tscanf(\"%d\", &y);\n}\n\nbool leap(int y) {\n\treturn y % 400 == 0 || (y % 4 == 0 && y % 100 != 0);\n}\n\nint solve(void) {\n\tbool is_leap = leap(y);\n\tint d = 0;\n\tdo {\n\t\td++;\n\t\tif (leap(y)) d++;\n\t\ty++;\n\t\td %= 7;\n\t} while (d || leap(y) != is_leap);\n    return y;\n}\n\nint main(void) {\n    read();\n    printf(\"%d\", solve());\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8476ca64088c22b2941e55f51cdb7f74", "src_uid": "565bbd09f79eb7bfe2f2da46647af0f2", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nbool namnhuan(long y)\n{\n\tif((((y%4)==0)&&((y%100)!=0))||((y%400)==0)) return true;\n\treturn false;\n}\n\nmain()\n{\n\tlong y,day=0;\n\tscanf(\"%ld\",&y);\n\tbool nam=namnhuan(y);\n\tdo\n\t{\n\t\tif(namnhuan(y))\n\t\t{\n\t\t\tday+=2;\n\t\t}\n\t\telse day+=1;\n\t\ty+=1;\t\t\n\t} while(day%7!=0 || namnhuan(y)!=nam);\n\tprintf(\"%ld\",y);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "653c6362a3412764e3dcd1ac697ce46c", "src_uid": "565bbd09f79eb7bfe2f2da46647af0f2", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "int y;\n\nvoid read(void) {\n\tscanf(\"%d\", &y);\n}\n\nbool leap(int y) {\n\treturn y % 400 == 0 || (y % 4 == 0 && y % 100 != 0);\n}\n\nint solve(void) {\n\tbool is_leap = leap(y);\n\tint d = 0;\n\tdo {\n\t\td++;\n\t\tif (leap(y)) d++;\n\t\ty++;\n\t\td %= 7;\n\t} while (d || leap(y) != is_leap);\n    return y;\n}\n\nint main(void) {\n    read();\n    printf(\"%d\", solve());\n    return 0;\n}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "865b123e2eb1823ea4b43293dc781a0f", "src_uid": "565bbd09f79eb7bfe2f2da46647af0f2", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint leap(int n)\n{\n          if(n%4==0)  \n          return 1;\n          else if(n%100==0)\n          return 0;\n          else in(n%400==0)\n          return 1;\n          else \n          return 0;\n}\nint main()\n{\n          int a,b,c,s,t,u,m,n,year;\n          scanf(\"%d\",&n);\n          a=n-1;\n          b=n-2;\n          c=n+1;\n          m=leap(a);\n          s=leap(b);\n          t=leap(c);\n          u=leap(n);\n          if(m==1)\n          year=n+6;\n          else if(s==1)\n          year=n+17;\n          else if(t==1)\n          year=n+22;\n          else if(u==1)\n          year=n+28;\n          printf(\"%d\",year);\n          return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d6dbc8d7f31b62a7d523426b8cd49b83", "src_uid": "565bbd09f79eb7bfe2f2da46647af0f2", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nint main()\n{\n    char s[10000],k[10000];\n    scanf(\"%s\", s);scanf(\"%s\", k);\n    int a=strlen(k),t=strlen(s)-1;\n    int b=0,q=0,i;\n    while(s[q]!='|')q++;\n    if(a+q == t-q){printf(\"%s%s\",k,s);return 0;}\n    else if(q == t+a-q){printf(\"%s%s\", s,k);return 0;}\n    int c = t-q-q;\n    if(c<0) c*=-1;\n    if(a>c && (a-c)%2==0){\n            if(t-q>q){\n                      for(i=0;i<c+(a-c)/2;i++)printf(\"%c\", k[i]);\n                      printf(\"%s\", s);\n                      for(i=c + (a-c)/2;i<a;i++)printf(\"%c\", k[i]);\n                      }\n            else{\n                 for(i=0;i<(a-c)/2;i++)printf(\"%c\", k[i]);\n                 printf(\"%s\", s);\n                 for(i=(a-c)/2;i<a;i++)printf(\"%c\", k[i]);\n                }\n    return 0;\n    }\n    ", "lang_cluster": "C", "compilation_error": true, "code_uid": "c6d26c28aff07a2e65d9ebcb36e3acc4", "src_uid": "917f173b8523ddd38925238e5d2089b9", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"1\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/1\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/1\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "29bca88dcddc9eeb8b3ece0588912ebc", "src_uid": "917f173b8523ddd38925238e5d2089b9", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "# include <stdio.h>\n# include <string.h>\n# include <stdlib.h>\n\nchar ch[1010];\nchar chh[1010];\nint abs(int a){return a>0?a:-a;}\nint main()\n{\n    int flag,i,sum1,sum2,j,len;\n    char c;\n\n    while(~scanf(\"%s\",&ch))\n    {\n        len = strlen(ch);\n        sum1 = sum2 = 0;\n        for(i = 0;i < len;i ++)\n        {\n            if(ch[i] == '|')break;\n            sum1 += 1;\n        }\n        for(i+=1;i < len;i ++)\n        {\n            sum2 += 1;\n        }\n        scanf(\"%s\",chh);\n        len = strlen(chh);\n        if((len-abs(sum1 - sum2))%2==0)\n        {\n            if(sum1 > sum2)\n            {\n                for(i = 0;i < (len-abs(sum1-sum2))/2;i ++)\n                    printf(\"%c\",chh[i]);\n                for(i = 0;i < sum1;i ++)printf(\"%c\",ch[i]);\n                printf(\"|\");\n                for(i = (len-abs(sum1-sum2))/2;i < len;i ++)\n                    printf(\"%c\",chh[i]);\n                for(i = 0;i < sum2;i ++)\n                    printf(\"%c\",ch[i+sum1+1]);\n            }\n            else\n            {\n                for(i = 0;i < len-(len-abs(sum1-sum2))/2;i ++)\n                    printf(\"%c\",chh[i]);\n                for(i = 0;i < sum1;i ++)printf(\"%c\",ch[i]);\n                printf(\"|\");\n                for(i = len-(len-abs(sum1-sum2))/2;i < len;i ++)\n                    printf(\"%c\",chh[i]);\n                for(i = 0;i < sum2;i ++)\n                    printf(\"%c\",ch[i+sum1+1]);\n            }\n            puts(\"\");\n        }\n        else puts(\"Impossible\");\n        memset(ch,0,sizeof(ch));\n        memset(chh,0,sizeof(chh);\n    }\n\n\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "bf14f04dfac84d1a2a01680bc2ab38c4", "src_uid": "917f173b8523ddd38925238e5d2089b9", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include <math.h>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define N 110\nchar f1[N],f2[N];\nint main()\n{\n    //freopen(\"in.txt\",\"r\",stdin);\n    int i,j,k;\n    while(scanf(\"%s %s\",f1,f2)!=EOF){\n        int len1=0,len2=0,len=strlen(f1),lenlen=strlen(f2);\n        for(i=0;i<len;i++)\n            if(f1[i]=='|') break;\n        int t=i;\n        len1=t; len2=len-t-1;\n        int cha=len1-len2;\n        if(cha<0) cha=-1*cha;\n        if((lenlen-cha)>=0 && (lenlen-cha)%2==0 ){\n            k=(lenlen-cha)/2;\n            if(len1>=len2){\n                for(i=0;i<len1;i++) printf(\"%c\",f1[i]);\n                for(i=0;i<k;i++) printf(\"%c\",f2[i]); j=k;\n                for(i=len1;i<len;i++) printf(\"%c\",f1[i]);\n                for(i=k;i<lenlen;i++) printf(\"%c\",f2[i]);\n                printf(\"\\n\");\n            }else{\n                for(i=0;i<len1;i++) printf(\"%c\",f1[i]);\n                for(i=0;i<k+cha;i++) printf(\"%c\",f2[i]); j=k;\n                for(i=len1;i<len;i++) printf(\"%c\",f1[i]);\n                for(i=k+cha;i<lenlen;i++) printf(\"%c\",f2[i]);\n                printf(\"\\n\");\n            }\n        }\n        else printf(\"Impossible\");\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6f967222a845ec1abb93f999387437f1", "src_uid": "917f173b8523ddd38925238e5d2089b9", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<stdlib.h>\n#include<string.h>\n\nint main(){\n    char L[100];\n    char R[100];\n    char U[100];\n    \n    for(int = 0; i < 100; i++){\n        L[i] = NULL;\n        R[i] = NULL;\n        U[i] = NULL;\n    }\n    \n    \n    scanf(\"%[^|]%\", L);\n    getchar();\n    scanf(\"%s\", R);\n    scanf(\"%s\", U);\n    int l = 0, r = 0, u = 0, diff, diff1;\n    l = strlen(L);\n    r = strlen(R);\n    u = strlen(U);\n    \n    if(u == 0){\n        strcpy(U, R);\n        r = 0;\n        u = strlen(U);\n    }\n    diff1 = abs(l - r);\n    diff = u - abs(l - r);\n   // printf(\"%d %d %d\", l, r, u);\n    \n    if(diff % 2  != 0 || diff < 0){\n        printf(\"Impossible\");\n        return 0;\n    }\n    \n   \n   for(int i = 0; i < abs(l - r); i++){\n        if(l < r)\n            L[l + i] = U[i];\n        else\n            R[r + i] = U[i];\n   }\n    //printf(\"%s\\n%s\\n%s\\n%d %d %d\\n\", L, R, U, l, r, u);\n   \n    if(l < r)\n        l = l + diff1;\n    else\n        r = r + diff1;  \n\n    int i, j, k;\n    for(i =diff1, j = l, k = r; i < u; i++){\n        if(i % 2 == 0){\n           L[j] = U[i];\n           j++;\n        }   \n        else{\n            R[k] = U[i];\n                k++;\n            }\n    }\n\n    L[j] = '\\0';\n    R[k] = '\\0';\n    \n\n    printf(\"%s|%s\", L, R);\n}\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7978556f05eb9b62a8a8574a59e0abc3", "src_uid": "917f173b8523ddd38925238e5d2089b9", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nchar a[10];\nbool flag=true;\nint main()\n{\n    int i,j;\n    for(i=0;i<8;i++)\n    {\n        scanf(\"%s\",a);  \n        for(j=0;j<7;j++)\n            if(a[j]==a[j+1])\n                flag=false;\n    }\n    puts(flag?\"YES\":\"NO\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9d48a507f7bae17c2ea9cfb19cf70271", "src_uid": "ca65e023be092b2ce25599f52acc1a67", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <cstdio>\n#include <iostream>\nusing namespace std;\n\nint main(){\n    bool find=true;\n    int count=0;\n    char str[8][8];\n    while(count<8){\n        scanf(\"%s\", str[count]);\n        count++;\n    }\n    for(int i=0; i<8; i++)\n    {\n        for(int j=0; j<7; j++)\n            if(str[i][j]==str[i][j+1])\n            {\n                printf(\"NO\\n\");\n                return 0;\n            }\n    }\n    \n    printf(\"YES\\n\");\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b36857cf8d78cd484f8b88ed088c249a", "src_uid": "ca65e023be092b2ce25599f52acc1a67", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n    short i = 0,j = 0,k = 0;\n    char a,b,c;\n    for(i=0;i<8;i++){\n        for(j=0;j<4;j++)\n           if(getchar()==getchar()) k=1;\n        getchar();\n    }\n    if(k==0) printf(\"YES\\n\");\n    else printf(\"NO\\n\");\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "059d412ecab4b002f88e40e04b13e32f", "src_uid": "ca65e023be092b2ce25599f52acc1a67", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <bits/stdc++.h>\n#include <stdio.h>\n#include <string.h>\n#include <math.h>\n#include <stdlib.h>\n#include <time.h>\n#include <limits.h>\n\n#define PI 3.141592653589793\n#define max(a,b) (a < b) ? (b) : (a)\n#define min(a,b) (a > b) ? (b) : (a)\n#define FOR(i,a,b) for(i = a ; i <= b ; i++)\n#define ROF(i,a,b) for(i = a ; i >= b ; i--)\n#define RAD(x) ((x)*PI)/180\n#define y1 y_1\n#define ll long long\n#define endl printf(\"\\n\")\n#define MAX 100005\n\n\tchar a[10][10] = {\"WBWBWBWB\",\"BWBWBWBW\",\"BWBWBWBW\",\"BWBWBWBW\",\"WBWBWBWB\",\"WBWBWBWB\",\"BWBWBWBW\",\"WBWBWBWB\"}, b[10][10];\n\nint main () {\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9edea82c73b8ef49bd9ef6253b24840c", "src_uid": "ca65e023be092b2ce25599f52acc1a67", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nchar a[10];\nbool flag=true;\nint main()\n{\n    int i,j;\n    for(i=0;i<8;i++)\n    {\n        scanf(\"%s\",a);  \n        for(j=0;j<7;j++)\n            if(a[j]==a[j+1])\n                flag=false;\n    }\n    puts(flag?\"YES\":\"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a894f9e49a11c8b348a7c57d4eea9d59", "src_uid": "ca65e023be092b2ce25599f52acc1a67", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <sdtdio.h>\n\nint main()\n{\n    int n, i;\n    unsigned int res = 1;\n    \n    scanf(\"%d\", &n);\n    if (n & 1 || !n) {\n        printf(\"0\\n\");\n        return 0;\n    }\n    n >>= 1;\n    for (i = 0; i < n; i++) {\n        res *= 2;\n    }\n    printf(\"%d\\n\", res);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3aa7d7126c3bfbc5d048294f001d07c8", "src_uid": "4b7ff467ed5907e32fd529fb39b708db", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tint n;\n\tcin>>n;\n\tif (n%2==0)\n\t{\n\t\tcout<< pow(2,n/2);\n\t}\n\telse\n\t{\n\t\tcout<<0;\n\t}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "40d57d9b9817d9820d64cadf2501073d", "src_uid": "4b7ff467ed5907e32fd529fb39b708db", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n\nint main()\n{\n    int n;\n    scanf(\"%d\",n);\n    if(n%2 == 0)\n    {\n        printf(pow(2,n/2));\n    }\n    else\n    {\n        printf(0);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "593e903b6612f233a8e65ca99cef5fe5", "src_uid": "4b7ff467ed5907e32fd529fb39b708db", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n \nint main(){\n    int n;\n    scanf(\"%d\",&n);\n    (n%2==0)?printf(\"%d\",pow(2,n/2):printf(\"0\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "154697446095127c6a95fbf5a65e35ce", "src_uid": "4b7ff467ed5907e32fd529fb39b708db", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n\n    scanf(\"%d\",&n);\n    if(n%2==0){\n        printf(\"%d\",n);\n    }\n    else\n    printf(\"0\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a6c9a4fbda8109c7791684991ff69344", "src_uid": "4b7ff467ed5907e32fd529fb39b708db", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n\r\n\r\n\r\nint man(){\r\n\tint x  ;\r\n\tint ctr = 0 ; \r\n\tint n; \r\n\tscanf(\"%d\" , &n); \r\n\tint arr[4]; \r\n\tarr[0] = -1; \r\n\tfor(int i = 1 ; i< 4 ; i++){\r\n\t\tscanf(\"%d\" , &x); \r\n\t\tarr[i] = x ; \r\n\t}\r\n\r\n\tint num = n ; \r\n\twhile(1){\r\n\t\tif(arr[num] !=0){\r\n\t\t\tctr++ ; \r\n\t\t}\r\n\t\telse{\r\n\t\t\tbreak ; \r\n\t\t}\r\n\t\tnum = arr[num] ; \r\n\t}\r\n\t// printf(\"%d\\n\" , ctr); \r\n\tif(ctr ==2){\r\n\t\tprintf(\"YES\\n\"); \r\n\t}\r\n\telse{\r\n\t\tprintf(\"NO\\n\"); \r\n\t}\r\n\t\r\n}\r\n\r\nint main(){\r\n\tint t ; \r\n\tscanf(\"%d\" , &t); \r\n\tfor(int i = 0 ; i<t ; i++){\r\n\tman()\r\n}\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "81889dd667315ec7d43323bd14fccf09", "src_uid": "5cd113a30bbbb93d8620a483d4da0349", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\nint main(){\r\n    int k;\r\n    scanf(\"%d\",&k);\r\n    while(k--){\r\n        int n;\r\n        scanf(\"%d\",&n);\r\n        int arr[3];\r\n        for(int i=0;i<3;i++){\r\n            scanf(\"%d\",&arr[i]);\r\n        }\r\n        int count=0;\r\n        int tem=arr[n-1];\r\n        while(tem!=0){\r\n            tem=arr[n-1];\r\n            count=count+1;\r\n        }\r\n        if (count==2){\r\n            printf(\"YES\")\r\n        }\r\n        else{\r\n            printf(\"NO\")\r\n        }\r\n    }\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "888c57b981a4a18000d532bd54d24988", "src_uid": "5cd113a30bbbb93d8620a483d4da0349", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\nint main(){\r\n    int n,k;\r\n    // int sum=0;\r\n    int arr[9];\r\n    scanf(\"%d\",&n);\r\n    for(int i=0;i<n;i++){\r\n        int p;\r\n        scanf(\"%d\",&p);\r\n        for (int j=0;j<3;j++){\r\n            scanf(\"%d\",&k);\r\n            int arr[j]=k;\r\n        }\r\n        if(arr[p-1]==0){\r\n            printf(\"NO\");\r\n        } else if(arr[arr[p-1]]>0&&arr[arr[arr[p-1]]]>0){\r\n            printf(\"YES\");\r\n        }\r\n    }\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "79f995ab055dd3848290d2b90dddf25f", "src_uid": "5cd113a30bbbb93d8620a483d4da0349", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\nint main()\r\n{\r\n    int t;\r\n    scanf(\"%d\", &t);\r\n    for (int i = 0; i < t; i++)\r\n    {\r\n        int x, abc[3];\r\n        scanf(\"%d\", &x);\r\n        scanf(\"%d %d %d\", &abc[0], &abc[1], &abc[2]);\r\n\r\n        int key1 = abc[x];\r\n        if (abc[key1] != 0)\r\n        {\r\n            print(\"YES\");\r\n        }\r\n        else\r\n        {\r\n            print(\"NO\");\r\n        }\r\n    }\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9d762d9f4c02c69e3c9294368e643851", "src_uid": "5cd113a30bbbb93d8620a483d4da0349", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\nint main()\r\n{\r\n   int t;\r\n   scanf(\"%d\",&t);\r\n   while(t--){\r\n       int x,a,b,c,f;\r\n       scanf(\"%d%d%d%d\",&x,&a,&b,&c);\r\n       if(x==1){\r\n           if(a==2){\r\n               if(b==3){\r\n                   f=1;\r\n               }\r\n               else f=0;\r\n           }\r\n           else if(a==3){\r\n               if(c==2) f=1;\r\n               else f=0;\r\n                \r\n           }\r\n           else f=0;\r\n       }\r\n       else if(x==2){\r\n           if(b==1){\r\n               if(a==3){\r\n                   f=1;\r\n               }\r\n               else f=0;\r\n           }\r\n           else if(b==3){\r\n               if(c==2) f=1;\r\n               else f=0;\r\n                \r\n           }\r\n           else f=0\r\n       }\r\n       else if(x==3){\r\n           if(c==1){\r\n               if(a==2){\r\n                   f=1;\r\n               }\r\n               else f=0;\r\n           }\r\n           else if(c==2){\r\n               if(b==1) f=1;\r\n               else f=0;\r\n                \r\n           }\r\n           else f=0;\r\n       }\r\n       \r\n       if(f==1)\r\n       printf(\"YES\\n\");\r\n       else printf(\"NO\\n\");\r\n       \r\n   }\r\n\r\n    return 0;\r\n}\r\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "44836ca11a737492d3bfad43b3ee4fb9", "src_uid": "5cd113a30bbbb93d8620a483d4da0349", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nint x,i,min=0,cur=0,temp=1;\nscanf(\"%d\",&x);\nif(x>0)\n{\n    while(cur!=x)\n{\n    if(cur+temp<=x) \n{  cur+=temp; }\nelse  \n{  cur-=temp; }\n++temp;\n++min;\n}\nelse\n{\n    while(cur!=x)\n{\nif(cur-temp>=x) \n{cur-=temp;}\nelse \n{cur+=temp;}\n++temp;\n++min;\n}\n}\nprintf(\"%d\",min);\nreturn 0;\n}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cdf886240adf111a9fb7924423b0e46b", "src_uid": "18644c9df41b9960594fdca27f1d2fec", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\nint main()\n{\n    int tp,x,ans;\n    while(~scanf(\"%d\",&x))\n    {\n        x=x<0?-x:x,ans=ceil((-1+sqrt(1+8.0*x))/2),tp=ans*(ans+1)/2-x;\n        while(tp&1) ans++,tp+=ans;\n        printf(\"%d\\n\",ans);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6d897543e53429e0d5d6081cb0d39fce", "src_uid": "18644c9df41b9960594fdca27f1d2fec", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nint x,i,min=0,cur=0,temp=1;\nscanf(\"%d\",&x);\nif(x>=0)\n{\nwhile(cur!=x)\n{\nif(cur+temp<=x) \n  cur+=temp;\nelse  \n  cur-=temp;\n++temp;\n++min;\n}\nelse\nwhile(cur!=x)\n{\nif(cur-temp>=x) cur-=temp;\nelse cur+=temp;\n++temp;\n++min;\n}\nprintf(\"%d\",min);\n}\nelse\n printf(\"%d\",x);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7560bfdfc1321a17d3c1dc9f6783d254", "src_uid": "18644c9df41b9960594fdca27f1d2fec", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <cstdio>\n\nint main(){\n\n    long n; scanf(\"%ld\\n\", &n);\n    if(n < 0){n = -n;}\n    long sum(0), ans(0), p(1);\n    for(p = 1; sum < n; sum += p, p++, ans++);\n    long diff = sum - n; \n    if(n == 0){puts(\"0\");}\n    else if(diff % 2 == 0){printf(\"%ld\\n\", ans);}\n    else if((diff + p) % 2 == 0){printf(\"%ld\\n\", ans + 1);}\n    else{printf(\"%ld\\n\", ans + 2);}\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bff4476238cc0ef90390c5b8d8425ad6", "src_uid": "18644c9df41b9960594fdca27f1d2fec", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n    int n;\n    scanf(\"%d\",&n);\n    if(n<0){\n        n=-n;\n    }\n    int count=0,jump=1,position=0;\n    while(1){\n        if(position==n)\n        break;\n        else if(position+jump>n)\n        {break;}\n        else{\n            count++;\n            position+=jump;\n            jump++;\n        }\n    }\n    if(n%2==0){\n    if(position%2==0){\n        if(jump%2==0)\n        count+=1;\n        else\n        count+=2;\n    }\n    else\n    {\n        if(jump%2==0)\n        count+=2;\n        else\n        count+=1;\n    }\n    }\n    else\n    {\n        if(position%2!0){\n        if(jump%2==0)\n        count+=1;\n        else\n        count+=2;\n    }\n    else\n    {\n        if(jump%2==0)\n        count+=2;\n        else\n        count+=1;\n    }\n    }\n    printf(\"%d\",count);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c04a155e515882fc287f478ba1c3a291", "src_uid": "18644c9df41b9960594fdca27f1d2fec", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int i,n;\n    scanf(\"%d\",&n);\n    char c[k];\n    scanf(\"%s\",c);\n    int t=0;\n    for(i=0;t+i<n;i++)\n    {\n        t=t+i;\n        printf(\"%c\",c[t]);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c5622a9e2ecc7b4c2583e1ddf4039577", "src_uid": "08e8c0c37b223f6aae01d5609facdeaf", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<conio.h>\nmain()\n{\nint n,i,j;\nchar a[55];\nscanf(\"%d\",&n);\nprintf(\"\\n\");\nscanf(\"%s\",a);\nprintf(\"%c\",a[0]);\ni=0;\nj=0;\nwhile(a[j]!='\\0')\n{j=j+i;\nprintf(\"%c\",a[j]);\ni=i+1;\n}\n \n ", "lang_cluster": "C", "compilation_error": true, "code_uid": "79d44ad4075b740c6dadc86641af8352", "src_uid": "08e8c0c37b223f6aae01d5609facdeaf", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nvoid main()\n{\n    int n,i;\n    scanf(\"%d,&n\");\n    char s[n];\n     scanf(\"%s,&s\");\n     for(i=0,j=1;i<n;j++)\n     {\n         printf(\"%s\",s[i]);\n         i+=j;\n     }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "592dc00600379094fa08847eb6e5a935", "src_uid": "08e8c0c37b223f6aae01d5609facdeaf", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\n#include<stdio.h>\n#include<algorithm>\nusing namespace std;\nint main()\n{\n\tint n,k[100005],i,j,a,b;\n\tscanf(\"%d\",&n);\n        for(i=0;i<n;i++)\n\tscanf(\"%d\",&k[i]);\n\tif(n<=2)\n\t\tprintf(\"0\");\n\telse\n\t{\n\tsort(k,k+n);\n\tb=k[n-2]-k[0];\n\tprintf(\"%d\",b);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f86422922de37d6d27fed749fd37de68", "src_uid": "08e8c0c37b223f6aae01d5609facdeaf", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<cstdio>\nusing namespace std;\nint main()\n{\n    int n,sum=0;\n    char a[60];\n    scanf(\"%d\\n\",&n);\n    scanf(\"%s\",a);\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tsum=sum+i;\n\t\tprintf(\"%c\",a[sum-1]);\n\t}   \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9878727cc86fc34778cd1edaf36d6ded", "src_uid": "08e8c0c37b223f6aae01d5609facdeaf", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,k,t=0;\n    t=n;\n    scanf(\"%d %d\",&n,&k);\n    for(i=k;i>0;i--)\n    {\n        r=t%10;\n        if(r!=0)\n            t=t-1;\n        else if(r==0)\n            t=t/10;\n        n=n/10;\n        n=t;\n    }\n    printf(\"%d\",t);\n    return=0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6efe65bc5345c8ad8feedff1aaf44434", "src_uid": "064162604284ce252b88050b4174ba55", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,k,r;\n    for(i=0;i<k;i++)\n    {\n        r=n%10;\n        if(r==0)\n        n=n/10;\n        else\n        n=n-1\n    }\n    printf(\"%d\",n);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a5cdf14ffd85e58a1fdab55ebfbf36e7", "src_uid": "064162604284ce252b88050b4174ba55", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nvoid main()\n{\n    int n,k,i=0;\n    clrscr();\n    printf(\"n&f\");\n    scanf(\"%d%d\",&n,&k);\n    while(i<k)\n    { if (n%10!=0){n=n-1;}\n    else if (n%10==0){n=n/10;}\n    printf(\"the no is %d \",n);\n    i++;\n    }\n    getch();\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f85e0027bc6ef9adcd1e8fac5c0be641", "src_uid": "064162604284ce252b88050b4174ba55", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int a,k;\n    int temp1;\n    scanf(\"%d %d\",&a,&k);\n    while(k!=0)\n    {\n        temp1=a%10;\n        if(tmep>=1)\n        {\n            temp1-=1;\n            a=a/10+temp1;\n        }\n        else\n        {\n            a=a/10;\n        }\n        k--;\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7addbd8a4cf05bda8fa9f39be1f8191c", "src_uid": "064162604284ce252b88050b4174ba55", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nusing namespace std;\nint main()\n{\n\tint a,b;\n\tscanf(\"%d%d\",&a,&b);\n\twhile(b!=0)\n\t{\n\t\tb--;\n\t\tif(a%10!=0) a--;\n\t\telse a/=10;\n\t}\n\tprintf(\"%d\",a);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "053c5da5eb0f0a4c7ab4b3ba964773f2", "src_uid": "064162604284ce252b88050b4174ba55", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n    {\n        int n;\n        scanf(\"%i\" , &n);\n        int mod[2] , l[2];\n        int i=0;\n        if(n>=0 && 99>=n)\n        {\n                if(n==08)\n                         {\n                                printf(\"2\");\n                                return 0;\n                         }\n        while(i<2)\n            {\n                mod[i]=n%10;\n                n/=10;\n                i++;\n            }\n\n        i=0;\n        while(i<2)\n            {\n                if(mod[i]==0 || mod[i]==6 || mod[i]==9)\n                    l[i]=2;\n                \n                if(mod[i]==1)\n                    l[i]=7 ;\n                    \n                if(mod[i]==2)\n                     l[i]=2;\n                     \n                if(mod[i]==3 || mod[i]==4)\n                    l[i]=3;\n                    \n                if(mod[i]==5)\n                    l[i]=4;\n                    \n                if(mod[i]==7)\n                    l[i]=5;\n                    \n                if(mod[i]==8)\n                    l[i]=1;\n                i++;    \n            }\n        printf(\"%i\" , l[0]*l[1]);\n    }\n    else \n    return 0;\n    \n        getche();   \n        return 0;\n    }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8c3c9165472a25a1cfce374607f41285", "src_uid": "76c8bfa6789db8364a8ece0574cd31f5", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "  switch (r) {\ncase 0 :\n    a=2;\n    break;\ncase 1 :\n    a=6;\n    break;\ncase 2 :\n a=2;\n break;\ncase 3:\n a=3;\n break;\ncase 4:\n    a=3;\n    break;\ncase 5:\n    a=4;\n    break;\ncase 6:\n    a=2;\n    break;\ncase 7:\n    a=5;\n    break;\ncase 8:\n    a=1;\n    break;\ncase 9:\n    a=2;\n    break;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d160352b0f4f57e48e0ba882e3cc0009", "src_uid": "76c8bfa6789db8364a8ece0574cd31f5", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "0#include <stdio.h>\nint main()\n{\n   int a[10]={2,7,2,3,3,4,2,5,1,2};\n   int no ,i,j;\n   scanf(\"%d\",&no);\n   if(no==0)\n   printf(\"4\");\n   else if(no<10)\n   {\n       printf(\"%d\",a[no]*a[0]);\n   }\n   else\n   {\n       printf(\"%d\",(a[no%10])*(a[no/10]));\n   }\n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cc960febcbf05b85fcb32509ef53139a", "src_uid": "76c8bfa6789db8364a8ece0574cd31f5", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"oo\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin\\Debug\\oo\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj\\Debug\\\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin\\Release\\oo\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj\\Release\\\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Unit filename=\"ppp.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<debugger />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d551a780913fb7c931e8797f8bed484e", "src_uid": "76c8bfa6789db8364a8ece0574cd31f5", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,n1,n2,x,y;\n    scanf(\"%d\",&n);\n    n1=n%10;\n    {\n    if(n1==0)\n        x=2;\n    else if(n1==1)\n        x=7;\n    else if(n1==2)\n        x=2;\n    else if(n1==3)\n        x=3;\n    else if(n1==4)\n        x=3;\n    else if(n1==5)\n        x=4;\n    else if(n1==6)\n        x=2;\n    else if(n1==7)\n        x=5;\n    else if(n1==8)\n        x=1;\n    else if(n1==9)\n        x=2;\n    }\n    n2=n/10;\n    {\n    if(n2==0)\n        y=2;\n    else if(n2==1)\n        y=7;\n    else if(n2==2)\n        y=2;\n    else if(n2==3)\n        y=3;\n    else if(n2==4)\n        y=3;\n    else if(n2==5)\n        y=4;\n    else if(n2==6)\n        y=2;\n    else if(n2==7)\n        y=5;\n    else if(n2==8)\n        y=1;\n    else if(n2==9)\n        y=2;\n    }\n    printf(\"%d\"\\n,x);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "038f1d890557de53ea5fa9d40581428d", "src_uid": "76c8bfa6789db8364a8ece0574cd31f5", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\nusing namespace std;\nint main(){\n  int h,w,u1,d1,u2,d2;\n  scanf(\"%d%d%d%d%d%d\",&w,&h,&u1,&d1,&u2,&d2);\n  for(int i=h;i>0;i--){\n    w=w+i;\n    if(i==d1)\n      w=w-u1;\n      else if(i==d2)\n       w=w-u2;\n\n  }\n  printf(\"%d\",w);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9f8dc38d2ac0bd2335182f1d8ede885a", "src_uid": "084a12eb3a708b43b880734f3ee51374", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "//https://codeforces.com/contest/1099/problem/A\n\n#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n    int w,h,w1,h1,w2,h2;\n    scanf(\"%d %d\",&w,&h);\n    scanf(\"%d %d\",&w1,&h1);\n    scanf(\"%d %d\",&w2,&h2);\n\n    for(int i=h;i>0;i--){\n        w=w+i;\n        if(i==h1){\n                w=w-w1;\n                if(w<0){\n                    w=0;\n                }\n        }\n        else if(i==h2){\n            w=w-w2;\n            if(w<0){\n                w=0;\n            }\n        }\n        else{\n            continue;\n        }\n    }\n    cout<<w;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "037db799a9b516e072c67a33a0602869", "src_uid": "084a12eb3a708b43b880734f3ee51374", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int u,h,u1,h1,u2,h2;\n    scanf(\"%d%d\",&u,&h);\n    scanf(\"%d%d\",&u1,&h1);\n    scanf(\"%d%d\",&u2,&h2);\n    u=u+h;\n    for(i=h-1;i>=0;i--){\n       u=u+i;\n       if(i==h1)\n         u=u-u1;\n       if(i==h2)\n        u=u-u2;\n    }\n    printf(\"%d\",u);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "22c29ef7ae6731206135f875a273c4fe", "src_uid": "084a12eb3a708b43b880734f3ee51374", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\nusing namespace std;\nint main(){\n  int h,w,u1,d1,u2,d2;\n  cin>>w>>h>>u1>>d1>>u2>>d2;\n  for(int i=h;i>0;i--){\n    w=w+i;\n    if(i==d1)\n      w=w-u1;\n      else if(i==d2)\n       w=w-u2;\n\n  }\n  cout<<w;\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "25ff29b4379e750a4d37e130a4da97b7", "src_uid": "084a12eb3a708b43b880734f3ee51374", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int w,h;\n    scanf(\"%d %d\",&w,&h);\n    int w1, h1;\n    scanf(\"%d %d\", &w1, &h1);\n    int w2, h2;\n    scanf(\"%d %d\", &w2, &h2);\n   while(h>0)\n   {\n   \tw+=h;\n   \tif(h==h1)\n   \t\tw-=a;\n   \tif(h==h2)\n   \t\tw-=b;\n   \tif(w<0)\n   \t\tw=0;\n   \th--\n   }\n   printf(\"%d\",w);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "107e5ac15c3da5706a5198bb04d0bfc8", "src_uid": "084a12eb3a708b43b880734f3ee51374", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "e <stdio.h>\n\nint main(){\n    int n;\n    scanf(\"%d\", &n);\n    if(n==1) printf(\"-1\\n\");\n    if(n>1 && n<4) printf(\"2 2\\n\");\n    else\n        printf(\"%d %d\\n\", n-n%2, (n-n%2)/2);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9d0d4bbfc4c1d5c1b1041968b4123c0a", "src_uid": "883f67177474d23d7a320d9dbfa70dd3", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nmain()\n{\n    int n;\n    printf(\"%d 2\",x-x%2);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e799e6be742575c3d8dffe64ba3d5398", "src_uid": "883f67177474d23d7a320d9dbfa70dd3", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n;\n    scanf(\"%d\",&n);\n    int i,j;\n    for(i=1;i<=n;i++){\n        for(j=1;j<=n;j++){\n            if(i % j == 0 && i * j > n && i / j < n){\n                count = 1;\n                break;\n            }\n        }\n        if(count == 1){\n            break;\n        }\n    }\n    if(count == 1){\n        printf(\"%d %d\\n\",i,j);\n    }else{\n        printf(\"-1\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8d559faec84d75844d2b93a5bf5ee399", "src_uid": "883f67177474d23d7a320d9dbfa70dd3", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main(){\n\tint x, a = 0, b = 0;\n\tscanf(\"%d\",&x);\n\tif(x == 1){\n\t\tprintf(\"-1\\n\");\n\t}else{\n\t\tfor(int i = x; i >=1; i--){\n\t\t\tfor(int j = i-1; j >= 1; j--){\n\t\t\t\tif(i * j > x){\n\t\t\t\t\tif(i % j == 0){\n\t\t\t\t\t\ta = i;\n\t\t\t\t\t\tb = j;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(a &% b){\n\t\t\tprintf(\"%d %d\\n\",a,b);\n\t\t}else{\n\t\t\tprintf(\"-1\\n\");\n\t\t}\n\t\t\n\t}\n\t\n\treturn(0);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c52def107cac2e781f909004895413bf", "src_uid": "883f67177474d23d7a320d9dbfa70dd3", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nmain()\n{\n    int n;\n    scanf(\"%d\",&n);\n    if(n==1)\n    printf(\"-1\");\n    else\n    printf(\"%d 2\",);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d0fe1903c771432ba6f7983c18a36bb6", "src_uid": "883f67177474d23d7a320d9dbfa70dd3", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    char a[11];b[11];\n    int i,j;\n    scanf(\"%s %s\",a,b);\n    for(i=1;i<10;i++)\n    {\n        if(a[i]>=b[0])\n        {\n            for(j=0;j<i;j++)\n            printf(\"%c\",a[j]);\n            printf(\"%c\",b[0]);\n            break;\n        }\n        if(i==9)\n        {\n            printf(\"%s\",a);\n            printf(\"%c\",b);\n            break;\n        }\n        }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5e8333e30ceb30db479e9c6ee7b5bf1e", "src_uid": "aed892f2bda10b6aee10dcb834a63709", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n   char ar[100],b[100];\n   scanf(\"%s %s\",a,b);\n   printf(\"%c\",a[0]);\n   int i;\n   for( i=1;ar[i]!='\\0';i++){\n       if(ar[i]-'a'<b[0]-'a'){\n           printf(\"%c\",ar[i]);\n       }\n       else{\n           printf(\"%c\",b[0]);\n           break;\n       }\n   }\n   if(ar[i]=='\\0'){\n       printf(\"%c\",b[0]);\n   }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9d395cde2b876f8f63bdfe47f01e35da", "src_uid": "aed892f2bda10b6aee10dcb834a63709", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nchar a[11],b[11];\nint i,j;\nscanf(\"%s %s\",a,b);\nfor(i=1;i<11;i++)\n{\nif(a[i]>=b[0])\n{\nfor(j=0;j<i;j++)\n{\nprintf(\"%c\",a[j]);\n}\nprintf(\"%c\",b[0]);\nbreak;\n}\nif(a[i+1]==\\0)\n{\nprintf(\"%s\",a);\nprintf(\"%c\",b);\nbreak;\n}\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2e854ad5278d130b229540ad498cd93e", "src_uid": "aed892f2bda10b6aee10dcb834a63709", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n\tchar esm[10];\n\tchar shohrat[10];\n\tscanf(\"%s\" , esm);\n\tscanf(\"%s\" , shohrat);\n\tfor(int i=0;;i++)\n\t{\n\t\tif(esm[i]<shohrat[0]&&s[i]!=0)\n\t\tprintf(\"%c\" , esm[i]);\n\t\telse break;\n\t}\n\tprintf(\"%c\" , shohrat[0]);\n\t\t\t\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0cbd848e7a811e11389c4e76ec70730e", "src_uid": "aed892f2bda10b6aee10dcb834a63709", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int j;\n    str[21];\n    gets(str);\n    int a;\n    int i;\n    for(i=1;i<21;i++)\n    {\n        if(str[i]== )\n        a=i;\n        break;\n    }\n    for(i=1;i<21;i++)\n    {\n        if(str[i]>str[a+i])\n        {\n        for(j=0;j<i;j++)\n        printf(\"%c\",str[j]);\n        printf(\"%c\",str[a+1]);\n        break;\n    }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f62d0f9b3936419f50b9278c36b5c655", "src_uid": "aed892f2bda10b6aee10dcb834a63709", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"A. Home Numbers\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin\\Debug\\A. Home Numbers\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj\\Debug\\\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin\\Release\\A. Home Numbers\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj\\Release\\\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<debugger />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e3c56fcc9b8d1ea87c23187d6bcbc42c", "src_uid": "aa62dcdc47d0abbba7956284c1561de8", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main() {\n    int a, n, t = 1;\n    scanf(\"%d %d\", &n, &a);\n    if(a % 2 != 0) {\n        while(a != 1) {\n            a -= 2;\n            t++;\n        }\n        printf(\"%d\", t);\n        return 0;\n    }\n    else {\n        while(n != a) {\n            n -= 2;\n            t++;\n        }\n        printf(\"%d\", t);\n        return 0;\n    }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9b8028b35b7611b58263a42cd50d9923", "src_uid": "aa62dcdc47d0abbba7956284c1561de8", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <conio.h>\n#include <stdlib.h>\n\nint main()\n{ long int n, a;\n  skanf(\"%d%d\",&n,&a);\n  if(0==n%2)\n    printf(\"%d\",(n-a)/2+1);\n  else \n    printf(\"%d\",(a/2+1);\n       \n   \n    \n    \n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "73eeed35cf4b4acd54fc8c283fb66700", "src_uid": "aa62dcdc47d0abbba7956284c1561de8", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    long long n,a;\n    scanf(\"%lld %lld\",&n,&a);\n    if(n%2!=0 ||n<a)\n    break;\n    else{\n        printf(\"%lld\\n\",n-a);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e85c1714102d6f8992f255872373a858", "src_uid": "aa62dcdc47d0abbba7956284c1561de8", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main() {\n    int a, n, b = 1, t = 1;\n    scanf(\"%d%d\", &n, &a);\n    if(a % 2 != 0) {\n        while(a != 1) {\n            a -= 2;\n            t++;\n        }\n        printf(\"%d\", t);\n        return 0;\n    }\n    else {\n        while(n != a) {\n            n -= 2;\n            t++;\n        }\n        printf(\"%d\", t);\n        return 0;\n    }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2dceb7509f0584a697ea43aee3ebe305", "src_uid": "aa62dcdc47d0abbba7956284c1561de8", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\nint main(){\n\tint size, i;\n\tscanf(\"%d\", &size);\t\n\tshort *arr = malloc(sizeof *arr * size);\n\tint in;\n\tscanf(\"%d\", &in);\n\tfor(i = 0; i < size; ++i){\n\t\tarr[size - i - 1] = in % 10;\n\t\tin /= 10;\n\t}\n\tint j, isTrue = 0;\n\tfor(i = 0; i < size; ++i){\n\t\tshort key = 0;\n\t\tint counter = i;\n\t\twhile(counter != -1)\n\t\t\tkey += arr[counter--];\n\t\tj = i + 1;\n\t\twhile(j < size){\n\t\t\tshort sum = 0;\n\t\t\tint k = j;\n\t\t\twhile(sum < key && k < size)\n\t\t\t\tsum += arr[k++];\n\t\t\tif(sum == key)\n\t\t\t\tj = k;\n\t\t\telse\n\t\t\t\tbreak;\n\t\t}\n\t\tif(j == size && i != size - 1){\n\t\t\tputs(\"YES\");\n\t\t\tisTrue = 1;\n\t\t\tbreak;\n\t\t}\n\n\t}\n\tif(!isTrue)\n\t\tputs(\"NO\");\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5957142d7fed103d711fea4ff53eed71", "src_uid": "410296a01b97a0a39b6683569c84d56c", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main(){\n\tint n=0;\n\tscanf(\"%d\",&n);\n\tint s=0,t=0,a[n],k=0,j=1;\n\ta[0]=getchar();\n\tfor(int i=0;i<n;i++){a[i]=getchar()-48;}\n\twhile((!k)){\n\t\tif(j==n)break;\n\t\tfor(int i=0;i<j;i++)s+=a[i];\n\t\t\t\t\t\n\t\tfor(int i=j;i<n;i++){\n\t\t\tt=t+a[i];\n\t\t\t//printf(\"%d\\n\",a[0]);\n\t\t\tif(t>s)break;\n\t\t\tif(t==s)t=0;\n\t\t\t\n\t\t}\n\t\tif(t==0)k=1;\n\t\tif(t>s){\n\t\t\ts=0;t=0;j++;continue;\n\t\t}\n\t}\n\tif(k)printf(\"YES\");else printf(\"NO\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "51517b6762b61dfad72d8babe768dd4e", "src_uid": "410296a01b97a0a39b6683569c84d56c", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint i,j,tot,n,a[105],sum;\nchar s[105];\nint main()\n{\n    scanf(\"%d%s\",&n,s);\n    for(i=1;i<=n;i++)\n    {\n        a[i]=s[i-1]-'0';\n        sum+=a[i];\n    }\n    if(n>1 && sum==0)\n    {\n        puts(\"YES\");\n        return 0;\n    }\n    for(i=1;i<n;i++)\n    {\n        sum=tot=0;\n        for(j=1;j<=i;j++)\n        sum+=a[j];\n        for(j=i+1;j<=n;j++)\n        {\n            if(tot>sum)\n            break;\n            else if(tot==sum)\n            tot=0,j-=1;\n            else\n            tot+=a[j];\n        }\n        if(tot!=sum || j!=n+1)\n        continue;\n        puts(\"YES\");\n        return 0;\n    }\n    puts(\"NO\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "08d0b3ed1c9c8b114cf2b82a106c0899", "src_uid": "410296a01b97a0a39b6683569c84d56c", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "waiwaitt", "lang_cluster": "C", "compilation_error": true, "code_uid": "59a53f914aa04f188f057e4ea879a5c1", "src_uid": "410296a01b97a0a39b6683569c84d56c", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n\n\nchar li[101];\n\nint main() {\n\n\tint a, b, c;\n\tint n = 0;\n\tint tot = 0;\n\tint ct;\n\tint status = 1;\n\n\tscanf(\"%d\", &a);\n\tgetchar();\n\n\tgets_s(li);\n\n\tfor (b = 0; b < a; b++)\n\t\tli[b] = li[b] - '0';\n\n\tfor (b = 0; b < a; b++)\n\t\ttot = tot + li[b];\n\n\n\n\tfor (b = 0; b < a; b++) {\n\t\tn = n + li[b];\n\t\tif (li[b + 1] > n)\n\t\t\tcontinue;\n\t\telse break;\n\t}\n\n\tif (n == tot) {\n\t\tprintf(\"no\");\n\t\treturn 0;\n\t}\n\telse if (tot%n != 0) {\n\t\tprintf(\"no\");\n\t\treturn 0;\n\n\t}\n\n\tct = 0;\n\n\tfor (c = 0; c < a; c++) {\n\t\tct = ct + li[c];\n\n\t\tif (ct < n)\n\t\t\tcontinue;\n\t\telse if (ct == n) {\n\t\t\tct = ct - n;\n\t\t\tcontinue;\n\t\t}\n\t\telse if (ct > n) {\n\n\t\t\tstatus = 0;\n\t\t\tbreak;\n\n\t\t}\n\n\n\t}\n\n\n\n\tif (status == 0)\n\t\tprintf(\"no\");\n\telse if(status == 1 && ct==0)\n\t\tprintf(\"yes\");\n\n}\n\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8983ae5d5a33a3b088f35f283c13eeea", "src_uid": "410296a01b97a0a39b6683569c84d56c", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,i,j,s=0;\n    scanf(\"%d\",&n);\n    int a[n][n];\n    for(i=0;i<n;i++)\n    {\n        for(j=0;j<n;j++)\n        {\n            scanf(\"%d\",&a[i][j]);\n        }\n    }\n    for(i=0;i<n;i++)\n    {\n        for(j=0;j<n;j++)\n        {\n            if(i==j || i+j==(n-1) || i==(n-1)/2 || j==(n-1)/2)\n            s=s+a[i][j];\n        }\n    }\n    printf(\"%d\\n\",s);\n    return 0;\n    \n}\n,", "lang_cluster": "C", "compilation_error": true, "code_uid": "64bdb766e5de0fd2f3178f8f99a970ec", "src_uid": "5ebfad36e56d30c58945c5800139b880", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "z#include<stdio.h>\n#include<conio.h>\n \nint main()\n{\n\tint n ;int i;int d;int j;\n\tscanf(\"%d\", &n);\n\tint a[n][n];\n\td = n-1;\n\tint sum = 0;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tfor(j=0;j<n;j++)\n\t\t{\n\t\t\tscanf(\"%d\",&a[i][j]);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n\t\n\t\n\tfor(i=0;i<n;i++)\n\t{\n\t\tsum=sum + a[i][i];\n\t}\n\t\n\tint z =0;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tif((i != (n-1)/2) || (d != (n-1)/2))\n\t\t{\n\t\t\tsum=sum+a[i][d];\n\t\t\td--;\n\t\t}\n\t\telse\n\t\t{\n\t\t\td--;\n\t\t}\n\t}\n\t\n\tz =(n-1)/2;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tif((z != (n-1)/2) || i != (n-1)/2 )\n\t\t{\n\t\t\tsum = sum + a[i][z];\n\t\t}\n\t\t\n\t}\n\t\n\tint x=0;\n\tz=(n-1)/2;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tif((z != (n-1)/2) || i != (n-1)/2)\n\t\t{\n\t\t\tsum = sum + a[z][i];\n\t\t}\n\t}\n\tprintf(\"%d\" , sum);\t\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "801d72dcd4b39193d6135e455cb2fca5", "src_uid": "5ebfad36e56d30c58945c5800139b880", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    int i,j,a[10000][10000];\n    for(i=0;i<n;i++)\n    {\n        for(j=0;j<n;j++)\n        {\n            scanf(\"%d\",&a[i][j]);\n        }\n    }\n    int sum=0;\n    for(i=0;i<n;i++)\n    {\n        for(j=0;j<n;j++)\n        {\n            if((i==j) \n                sum += a[i][j];\n            else if(i+j==n-1) \n                sum += a[i][j];\n            else if((i/2)==((n-1)/2)) \n                sum += a[i][j];\n            else if((j/2)==((n-1)/2))\n                sum += a[i][j];\n        }\n    }\n    printf(\"%d\",sum);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ce6d09e238cc5e4a9f48013836956cc1", "src_uid": "5ebfad36e56d30c58945c5800139b880", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    int i,j,a[10000][10000];\n    for(i=0;i<n;i++)\n    {\n        for(j=0;j<n;j++)\n        {\n            scanf(\"%d\",&a[i][j]);\n        }\n    }\n    int sum=0;\n    for(i=0;i<n;i++)\n    {\n        for(j=0;j<n;j++)\n        {\n            if((i==j) || (i+j==n) ||(i/2)==(n/2) || (j/2)==(n/2))\n                sum += a[i][j];\n            \n        }\n    }\n    printf(\"%d\",sum);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ee97fd6e5c519b032fe9ca412cda0b3f", "src_uid": "5ebfad36e56d30c58945c5800139b880", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,a[5][5];\n\tint i,j,r,c,sum;\n\twhile(scanf(\"%d\",&n))\n\t{\n\t\tsum=0;\n\t\tfor(i=0;i<n;i++)\n\t\t\tfor(j=0;j<n;j++)\n\t\t\t{\n\t\t\t\tscanf(\"%d\",&a[i][j]);\n\t\t\t\tif(i==j||i+j==n-1||i==(n-1)/2||j==(n-1)/2)\n\t\t\t\t\tsum=sum+a[i][j];\n\t\t\t}\n\t\t\tprintf(\"%d\\n\",sum);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "eed84cdb1e764aa1b3aa604482bfaf14", "src_uid": "5ebfad36e56d30c58945c5800139b880", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main() {\n    char s[100];\n    int tt, t, n;\n\n    fgets(s);\n    n = strlen(s);\n    for (int i = 0; i < n; i++) {\n        if (s[i] == 'h') {\n            t = 1;\n        }\n        if (t == 1) {\n            for (int j = i; j < n; j++) {\n                if (s[j] == 'e') {\n                    t = 2;\n                }\n                if (t == 2) {\n                    for (int k = j; k < n; k++) {\n                        if (s[k] == 'l') {\n                            t = 3;\n                        }\n                        if (t == 3) {\n                            for (int l = k + 1; l < n; l++) {\n                                if (s[l] == 'l') {\n                                    t = 4;\n                                }\n                                if (t == 4) {\n                                    for (int m = l; m < n; m++) {\n                                        if (s[m] == 'o') {\n                                            t = 5;\n                                            tt = 1;\n                                            break;\n                                        }\n                                    }\n                                }\n                            }\n                        }\n                    }\n                }\n            }\n        }\n    }\n    if (tt != 1) {\n        printf(\"NO\");\n    } else {\n        printf(\"YES\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1c9593d84edfbad045dc2ba7ba1a2930", "src_uid": "c5d19dc8f2478ee8d9cba8cc2e4cd838", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<math.h>\n#include<stdlib.h>\nint main()\n{   int i=0,cnt=0;\n    char str[100]; \n    scanf(\"%s\",str);\nint j,i;\n     int a=strlen(str);\n    for(i=0;i<a;i++)\n       { \n          if(str[i]='h')\n          { cnt=cnt+1;\nbreak;\n          }\n             \n        }\n     for( j=i;j<a;j++)\n       { \n          if(str[j]='e')\n          { cnt=cnt+1;\nbreak;\n          }\n             \n        }\n      for(i=j;i<a;i++)\n       { \n          if(str[i]='l')\n          { cnt=cnt+1;\nbreak;\n          }\n             \n        }\n       for( j=i;j<a;j++)\n       { \n          if(str[j]='l')\n          { cnt=cnt+1;\n break;\n          }\n            \n        }\n     for( i=j;i<a;i++)\n       { \n          if(str[i]='o')\n          { cnt=cnt+1;\n break;\n          }\n            \n        }\nif(cnt==5)\n   printf(\"YES\");\nelse\n   printf(\"NO\");\n  }", "lang_cluster": "C", "compilation_error": true, "code_uid": "c2fa333102db52d2f40662ae9758aaaa", "src_uid": "c5d19dc8f2478ee8d9cba8cc2e4cd838", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(void)\n{\n  int i,j,k,l,m;\n  int a=0;\n  char in[31]=\"\";\n\n  scanf(\"%s\",in);\n\n  for(i=0;i<30;i++)\n    if(in[i]!=0) a++;\n\n  for(i=0;i<a;i++)\n  {  if(i==(a-4)) {printf(\"NO\\n\"); break;}\n     else if(in[i]=='h')\n     {  for(j=0;j<(a-i);j++)\n        {  if((i+j+1)==(a-3)) {printf(\"NO\\n\"); break;}\n           else if(in[i+j+1]=='e')\n           {  for(k=0;k<(a-i-j);k++)\n              {  if((i+j+k+1)==(a-2)) printf(\"NO\\n\"); break;}\n                 else if(in[i+j+k+1]=='l')\n                 {  for(l=0;l<(a-i-j-k);l++)\n                    {  if((i+j+k+l+1)==(a-1)) printf(\"NO\\n\"); break;}\n                       else if(in[i+j+k+l+1]=='l')\n                       {  for(m=0;m<(a-i-j-k-l);m++)\n                          if(in[i+j+k+l+m+1]=='o') printf(\"YES\\n\"); break;}\n                          else printf(\"NO\\n\"); break;}\n                       }break;\n                    }\n                 }break;\n              }\n           }break;\n        }\n     }break;\n  }\nreturn 0;\n}  ", "lang_cluster": "C", "compilation_error": true, "code_uid": "e5eb2f76e210723f96ba954ce15dc4f0", "src_uid": "c5d19dc8f2478ee8d9cba8cc2e4cd838", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    char in [100] , i ,flag = 0;\n    scanf(\"%s\",in);\n    for(i=0;i<strlen(in)-4&&!flag;i++)\n    {\n        if(in[i]=='h'&&in[i+1]=='e'&&in[i+2]=='l'&&in[i+3]=='l'&&in[i+4]=='o')\n            flag = 1 ;\n    }\n    if(flag)\n    print(\"YES\");\n    else \n    printf(\"NO\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1fe40153d1ba7b2eba1f502f254503cb", "src_uid": "c5d19dc8f2478ee8d9cba8cc2e4cd838", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main()\n{\n    char str[101];\n    scanf(\"%s\",str);\n    if(strlen(str)<=4)\n        printf(\"NO\\n\");\n    else\n    {\n        int countH,countL,countO;\n        countH=countO=countL=0;\n        for(i=0;i<strlen(str);i++)\n        {\n            if(str[i]=='h')\n                countH++;\n            else if(str[i]=='l')\n                countL++;\n            else if(str[i]=='o')\n                countO++;\n        }\n        if(countH>=1&&countL>=2&&countO>=1)\n            printf(\"YES\\n\");\n        else\n            printf(\"NO\\n\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d12d9e9d8cf1bfb06dbebc95c8622e12", "src_uid": "c5d19dc8f2478ee8d9cba8cc2e4cd838", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<conio.h>\nmain()\n{\n     long long int n,k,i,ans;\n     long long int sum=0;\n     scanf(\"%lld %lld\",&n,&k);\n     for(i=1;i<=n;i++)\n     {sum=sum+i;\n     add=n-i;\n     ans=sum-add;\n     if(ans==k)\n     break;\n          \n     }\n     printf(\"%lld\",i);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2d1f582215c8f33d5b525a19e25abb3f", "src_uid": "17b5ec1c6263ef63c668c2b903db1d77", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "main(n,k){scanf(\"%d%d\",&n,&k);printf(\"%d\",n-int(sqrt(9+8*k+8*n)-3)/2);}", "lang_cluster": "C", "compilation_error": true, "code_uid": "707ef101d257e73614695c6127bf3f7b", "src_uid": "17b5ec1c6263ef63c668c2b903db1d77", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\nvoid remp(long* t,long d, long f, long*u,long* d,long n)\n{\n    long i,s;\n    s=(f-d+1)/4;\n    for (i=0;i<s;i++)\n    {\n        t[i+d]+=u[n]+d[n+2];\n        t[d+i+s]+=u[n]+d[n+1]+u[n+2];\n        t[2*s+i+d]+=d[n]+u[n+1]+d[n+2];\n        t[s*3+i+d]+=d[n]+u[n+2];\n    }\n    if (d>s)\n    {\n        remp(t,d,d+2*s-1,u,d,n+3);\n        remp(t,d+2*s,f,u,d,n+3);\n        \n    }\n}\nmain()\n{\n    long n,i,max,taille,*up,*down,*res,rest;\n    scanf(\"%li\",&n);\n    up=malloc((n+1)*sizeof(long));\n    down=malloc((n+1)*sizeof(long));\n    for (i=1;i<=n;i++) scanf(\"%li\",&up[i]);\n    for (i=1;i<=n;i++) scanf(\"%li\",&down[i]);\n    rest=n/3;\n    taille=pow(2,rest+1);\n    \n    res=calloc(taille+1,sizeof(long));\n    remp(res,1,taille,up,down,1);\n    for(i=1;i<=taille;i++) printf(\"%li \",res[i]);\n    \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5228e7ff8fa94d2b86f0e784e22e9412", "src_uid": "17b5ec1c6263ef63c668c2b903db1d77", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <ctype.h>\n#include <math.h>\n\nint main()\n{\n    int n,k,e=0,i=1,x=0,box=0;\n    scanf(\"%d%d\",&n,&k);\n    \n        do\n        {\n            if(box==k)\n            {\n                if(n==0)\n                {\n                    break;\n                }\n                else\n                {\n                    box=box+i;\n                    i=i++;\n                }\n            }\n            else if(box<k)\n            {\n                box=box+i;\n                i=i+1;\n            }\n            else if(box>k)\n            {\n                box--;\n                e++;\n            }\n            n=n-1;\n        }while(n!=0)\n   \n    \n    \n    printf(\"%d\",e);\n}\n\n\n\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "964d12eade94001fbb3cdbae173ec392", "src_uid": "17b5ec1c6263ef63c668c2b903db1d77", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main():\n{\n    int n, k;\n    scanf(\"%d %d\", &n, &k);\n    int c = 0, t = 1;\n    while(c < k)\n    {\n        c += t;\n        t++;\n        n--;\n    }\n    while(c - k != n)\n    {\n        t++;\n        c += t\n        n--;\n    }\n    print(\"%d\", n);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "952fb9a6f85625f765781baf129a4f7a", "src_uid": "17b5ec1c6263ef63c668c2b903db1d77", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nchar rec[105];\n\nint main()\n{\n      long long ans=0, nb, ns, nc, pb, ps, pc, r, x,z,y, temp, cost;\n      scanf(\"%s\", rec);\n      scanf(\"%I64d%I64d%I64d%I64d%I64d%I64d%I64d\", &nb, &ns, &nc, &pb, &ps, &pc, &r);\n\n      long long bread=0 , soucage=0 , cheese = 0, i;\n\n      for(i=0 ; rec[i] != '\\0' ; i++)\n      {\n            if(rec[i] == 'B')\n                  bread++;\n            else if(rec[i] == 'S')\n                  soucage++;\n            else if(rec[i] == 'C')\n                  cheese++;\n      }\n\n      cost = (bread*pb) + (soucage*ps) + (cheese*pc);\n\n      if((x=nb/bread) > 0 && (y=ns/soucage) > 0 && (z=nc/cheese) > 0 )\n      {\n            k = MIN(MIN(x,y),z);\n            k--;\n            if(k!=0)\n            {\n                  ans += k;\n                  nb -= k*bread;\n                  ns -= k*soucage;\n                  nc -= k*cheese;\n            }\n      }\n\n      while((nb-bread) > 0 && (ns-soucage) > 0 && (nc - cheese) > 0)\n      {\n            ans += 1;\n            nb-=bread;\n            ns-=soucage;\n            nc-=cheese;\n      }\n\n      while(nb > 0 || ns > 0 || nc > 0)\n      {\n            temp = 0;\n            x = nb-bread;\n            y = ns-soucage;\n            z = nc-cheese;\n\n            if(x < 0)\n            {\n                  temp+=-1*x*pb;\n                  nb = 0;\n            }\n            else\n                  nb -= bread;\n\n            if(y < 0)\n            {\n                  temp+=-1*y*ps;\n                  ns = 0;\n            }\n            else\n                  ns -= soucage;\n\n            if(z < 0)\n            {\n                  temp+=-1*z*pc;\n                  nc = 0;\n            }\n            else\n                  nc -= cheese;\n\n\n\n            if((r-temp) >= 0)\n            {\n                  ans++;\n                  r -= temp;\n            }\n            else\n            {\n                  printf(\"%I64d\", ans);\n                  return 0;\n            }\n\n            if(r<=0)\n            {\n                  printf(\"%I64d\", ans);\n                  return 0;\n            }\n      }\n\n      ans += r/cost;\n\n      printf(\"%I64d\", ans);\n\n      return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c5587e76a16308882062cb546fcd7f59", "src_uid": "8126a4232188ae7de8e5a7aedea1a97e", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main() {\n\nchar l[1000];//The sandwich components\nscanf(\"%s\",l);\nint b,  //no of bread in kitchen\n\ts,  //no of sausage in kitchen\n \tc,  //no of cheese in kitchen\n\tbp, //price of bread piece\n\tsp, //price of sausage piece\n\tcp; //price of cheese piece\n\nlong long no=0; //no of sandwiches\nlong long m;    //money\n\nscanf(\"%d %d %d\",&b,&s,&c);\nscanf(\"%d %d %d\",&bp,&sp,&cp);\nscanf(\"%I64d\",&m);\nint cn1=0,cn2=0,cn3=0;\nint len=strlen(l);\n\tfor(int i=0;i<len;i++) //counting number of each piece\n\t\t{\n\t\t\tswitch(l[i])\n\t\t\t{\n\t\t\tcase 'B':\n\t\t\t\tcn1++;\n\t\t\t\tbreak;\n\t\t\tcase 'S':\n\t\t\t\tcn2++;\n\t\t\t\tbreak;\n\t\t\tcase 'C':\n\t\t\t\tcn3++;\n\t\t\t\tbreak;\n\t\t\tdefault:\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\tif(cn1==0)\n\t\tb=0;\n\n\tif(cn2==0)\n\t\ts=0;\n\n\tif(cn3==0)\n\t\tc=0;\n\tlong long price=(cn1*bp)+(cn2*sp)+(cn3*cp);\n\tint FLAG=1;\n\twhile((b>0||s>0||c>0)&&(FLAG==1))\n\t{\n\n\t\twhile((b>=cn1&&s>=cn2&&c>=cn3)&&FLAG==1)\n\t\t{\n\t\t\tb=b-cn1;\n\t\t\ts=s-cn2;\n\t\t\tc=c-cn3;\n\t\t\tno++;\n\t\t}\n\t\t\tif(b<cn1)\n\t\t\tb=b-cn1;\n\t\t\tif(s<cn2)\n\t\t\ts=s-cn2;\n\t\t\tif(c<cn3)\n\t\t\tc=c-cn3;\n\n\t\t\tif(cn1>0&&b<cn1) //check if bread is an ingredient\n\t\t\t{\n\t\t\t\tFLAG=0;\n\t\t\t\tif(m>(b*-1)*bp)\n\t\t\t\t{\n\t\t\t\t\tFLAG=1;\n\t\t\t\t\tm=m-(b*-1)*bp;\n\t\t\t\t\tb=cn1;\n\t\t\t\t}\n\t\t\t}\n\n\n\t\t\tif(cn2>0&&s<cn2)   //check if sausage is an ingredient\n\t\t\t{\n\t\t\t\tFLAG=0;\n\t\t\t\tif(m=>(s*-1)*sp)\n\t\t\t\t{\n\t\t\t\t\tFLAG=1;\n\t\t\t\t\tm=m-(s*-1)*sp;\n\t\t\t\t\ts=cn2;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif(cn3>0&&c<cn3) //check if cheese is an ingredient\n\t\t\t{\n\t\t\t\tFLAG=0;\n\t\t\t\tif(m=>(c*-1)*cp)\n\t\t\t\t{\n\t\t\t\t\tFLAG=1;\n\t\t\t\t\tm=m-(c*-1)*cp;\n\t\t\t\t\tc=cn3;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(b>=cn1&&s>=cn2&&c>=cn3)\n\t\t\t{\n\t\t\t\tb=b-cn1;\n\t\t\t\ts=s-cn2;\n\t\t\t\tc=c-cn3;\n\t\t\t\tno++;\n\t\t\t}\n\n\t}\n\tno=no+(m/price);\n     printf(\"%I64d\",no);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ef2b0a9af01e7720bc28238b2cb528ab", "src_uid": "8126a4232188ae7de8e5a7aedea1a97e", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\nusing namespace std;\n\nint main() {\n\nstring l=\"BSC\";//The sandwich components\n//cin>>l;\nint b=100,  //no of bread in kitchen\n\ts=1,  //no of sausage in kitchen\n \tc=1,  //no of cheese in kitchen\n\tbp=100, //price of bread piece\n\tsp=1, //price of sausage piece\n\tcp=1; //price of cheese piece\n\nlong long no=0; //no of sandwiches\nlong long m=100;    //money\n\n//cin>>b>>s>>c;\n//cin>>bp>>sp>>cp;\n//cin>>m;\nint cn1=0,cn2=0,cn3=0;\nint len=l.length();\n\tfor(int i=0;i<len;i++) //counting number of each piece\n\t\t{\n\t\t\tswitch(l[i])\n\t\t\t{\n\t\t\tcase 'B':\n\t\t\t\tcn1++;\n\t\t\t\tbreak;\n\t\t\tcase 'S':\n\t\t\t\tcn2++;\n\t\t\t\tbreak;\n\t\t\tcase 'C':\n\t\t\t\tcn3++;\n\t\t\t\tbreak;\n\t\t\tdefault:\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\tif(cn1==0)\n\t\tb=0;\n\n\tif(cn2==0)\n\t\ts=0;\n\n\tif(cn3==0)\n\t\tc=0;\n\tlong long price=(cn1*bp)+(cn2*sp)+(cn3*cp);\n\tint FLAG=1;\n\twhile((b>0||s>0||c>0)&&(FLAG==1))\n\t{\n\n\t\twhile((b>=cn1&&s>=cn2&&c>=cn3)&&FLAG==1)\n\t\t{\n\t\t\tb=b-cn1;\n\t\t\ts=s-cn2;\n\t\t\tc=c-cn3;\n\t\t\tno++;\n\t\t}\n\t\t\tif(b<cn1)\n\t\t\tb=b-cn1;\n\t\t\tif(s<cn2)\n\t\t\ts=s-cn2;\n\t\t\tif(c<cn3)\n\t\t\tc=c-cn3;\n\n\t\t\tif(cn1>0&&b<cn1) //check if bread is an ingredient\n\t\t\t{\n\t\t\t\tFLAG=0;\n\t\t\t\tif(m>(b*-1)*bp)\n\t\t\t\t{\n\t\t\t\t\tFLAG=1;\n\n\t\t\t\t\tm=m-(b*-1)*bp;\n\t\t\t\t\tb=cn1;\n\t\t\t\t}\n\t\t\t}\n\n\n\t\t\tif(cn2>0&&s<cn2)   //check if sausage is an ingredient\n\t\t\t{\n\t\t\t\tFLAG=0;\n\t\t\t\tif(m>(s*-1)*sp)\n\t\t\t\t{\n\t\t\t\t\tFLAG=1;\n\t\t\t\t\tm=m-(s*-1)*sp;\n\t\t\t\t\ts=cn2;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif(cn3>0&&c<cn3) //check if cheese is an ingredient\n\t\t\t{\n\t\t\t\tFLAG=0;\n\t\t\t\tif(m>(c*-1)*cp)\n\t\t\t\t{\n\t\t\t\t\tFLAG=1;\n\t\t\t\t\tm=m-(c*-1)*cp;\n\t\t\t\t\tc=cn3;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(b>=cn1&&s>=cn2&&c>=cn3)\n\t\t\t{\n\t\t\t\tb=b-cn1;\n\t\t\t\ts=s-cn2;\n\t\t\t\tc=c-cn3;\n\t\t\t\tno++;\n\t\t\t}\n\n\t}\n\tno=no+(m/price);\n     cout<<no;\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fa7ecbad24df30163ca0de5a66eedd4d", "src_uid": "8126a4232188ae7de8e5a7aedea1a97e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MIN(a,b) (a<b?a:b)\nchar rec[105];\n\nint main()\n{\n      long long ans=0, nb, ns, nc, pb, ps, pc, r, x,z,y, temp, cost, k;\n      scanf(\"%s\", rec);\n      scanf(\"%I64d%I64d%I64d%I64d%I64d%I64d%I64d\", &nb, &ns, &nc, &pb, &ps, &pc, &r);\n\n      long long bread=0 , soucage=0 , cheese = 0, i;\n\n      for(i=0 ; rec[i] != '\\0' ; i++)\n      {\n            if(rec[i] == 'B')\n                  bread++;\n            else if(rec[i] == 'S')\n                  soucage++;\n            else if(rec[i] == 'C')\n                  cheese++;\n      }\n\n      cost = (bread*pb) + (soucage*ps) + (cheese*pc);\n\n      if((x=nb/bread) > 0 && (y=ns/soucage) > 0 && (z=nc/cheese) > 0 )\n      {\n            k = MIN(MIN(x,y),z);\n            k--;\n            if(k!=0)\n            {\n                  ans += k;\n                  nb -= k*bread;\n                  ns -= k*soucage;\n                  nc -= k*cheese;\n            }\n      }\n\n      while((nb-bread) > 0 && (ns-soucage) > 0 && (nc - cheese) > 0)\n      {\n            ans += 1;\n            nb-=bread;\n            ns-=soucage;\n            nc-=cheese;\n      }\n\n      while(nb > 0 || ns > 0 || nc > 0)\n      {\n            temp = 0;\n            x = nb-bread;\n            y = ns-soucage;\n            z = nc-cheese;\n\n            if(x < 0)\n            {\n                  temp+=-1*x*pb;\n                  nb = 0;\n            }\n            else\n                  nb -= bread;\n\n            if(y < 0)\n            {\n                  temp+=-1*y*ps;\n                  ns = 0;\n            }\n            else\n                  ns -= soucage;\n\n            if(z < 0)\n            {\n                  temp+=-1*z*pc;\n                  nc = 0;\n            }\n            else\n                  nc -= cheese;\n\n\n\n            if((r-temp) >= 0)\n            {\n                  ans++;\n                  r -= temp;\n            }\n            else\n            {\n                  printf(\"%I64d\", ans);\n                  return 0;\n            }\n\n            if(r<=0)\n            {\n                  printf(\"%I64d\", ans);\n                  return 0;\n            }\n      }\n\n      ans += r/cost;\n\n      printf(\"%I64d\", ans);\n\n      return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "713fd70827d2ea53c6938ee55620d311", "src_uid": "8126a4232188ae7de8e5a7aedea1a97e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MIN(a,b) (a<b?a:b)\nchar rec[105];\n\nint main()\n{\n      long long ans=0, nb, ns, nc, pb, ps, pc, r, x,z,y, temp, cost, k;\n      scanf(\"%s\", rec);\n      scanf(\"%I64d%I64d%I64d%I64d%I64d%I64d%I64d\", &nb, &ns, &nc, &pb, &ps, &pc, &r);\n\n      long long bread=0 , soucage=0 , cheese = 0, i;\n\n      for(i=0 ; rec[i] != '\\0' ; i++)\n      {\n            if(rec[i] == 'B')\n                  bread++;\n            else if(rec[i] == 'S')\n                  soucage++;\n            else if(rec[i] == 'C')\n                  cheese++;\n      }\n\n      cost = (bread*pb) + (soucage*ps) + (cheese*pc);\n\n      while((x=nb/bread) > 0 && (y=ns/soucage) > 0 && (z=nc/cheese) > 0)\n      {\n            k = MIN(MIN(x,y),z);\n            ans += k;\n            nb = nb - (k*bread);\n            ns = ns - (k*soucage);\n            nc = nc - (k*cheese);\n      }\n\n      while(nb > 0 || ns > 0 || nc > 0)\n      {\n            temp = 0;\n            x = nb-bread;\n            y = ns-soucage;\n            z = nc-cheese;\n\n            if(x < 0)\n            {\n                  temp+=-1*x*pb;\n                  nb = 0;\n            }\n            else\n                  nb -= bread;\n\n            if(y < 0)\n            {\n                  temp+=-1*y*ps;\n                  ns = 0;\n            }\n            else\n                  ns -= soucage;\n\n            if(z < 0)\n            {\n                  temp+=-1*z*pc;\n                  nc = 0;\n            }\n            else\n                  nc -= cheese;\n\n\n\n            if((r-temp) >= 0)\n            {\n                  ans++;\n                  r -= temp;\n            }\n            else\n            {\n                  printf(\"%I64d\", ans);\n                  return 0;\n            }\n\n            if(r<=0)\n            {\n                  printf(\"%I64d\", ans);\n                  return 0;\n            }\n      }\n\n      ans += r/cost;\n\n      printf(\"%I64d\", ans);\n\n      return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a33d56ca1ea7fae4400268f340735a0b", "src_uid": "8126a4232188ae7de8e5a7aedea1a97e", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#inlcude <stdio.h>\nint main ()\n{\n    char c;\n    int  n;\n    scanf(\"%c\",c);\n    scanf(\"%d\",&n);\n    if(n%2==0)\n    printf(\"0\");\n    else \n    printf(\"1\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bfda758eadf9bbb5c4422c65101d620a", "src_uid": "e52bc741bb72bb8e79cf392b2d15354f", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\n#define MAXCHAR 1000\n#define PFS(x)          printf(\"%s\\n\",x)\nint main(int argc, char const *argv[])\n{\n\t\n\tchar str[MAXCHAR];\n\tscanf(\"\\n%s\", str);\n\tint x = str[6]-'0';\n\tif(x%2==0)\n    \tPFS(\"0\");\n    else\n    \tPFS(\"1\");\n\tprintf(\"%d\", n%2);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f2a54506353d33f017e870a413bf2e4e", "src_uid": "e52bc741bb72bb8e79cf392b2d15354f", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nchar A;\nint a;\nint b;\nint c;\nint d;\nint e;\nint f;\nint g;\nint main(){\n    scanf(\"%c\",&A);\n    \n    scanf(\"%d\",&a);\n    scanf(\"%d\",&b);\n    scanf(\"%d\",&c);\n    scanf(\"%d\",&d);\n    scanf(\"%d\",&e);\n    scanf(\"%d\",&f);\n    scanf(\"%d\",&g);\n    if ( g==2||g==4||g==0||g==6||g==8||){\n        printf(\"0\");\n    \n        return 0;\n    }\n    \n        printf(\"1\");\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "856680f080a3749fafe4c645f4ead98c", "src_uid": "e52bc741bb72bb8e79cf392b2d15354f", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include<string.h>\nint main(){\n    string s;\n    gets(s);\n    printf(\"1\\n\");\n}\n     \n     \n     \n  \n     ", "lang_cluster": "C", "compilation_error": true, "code_uid": "97b3b847c05c798436b7fad4523a8c86", "src_uid": "e52bc741bb72bb8e79cf392b2d15354f", "difficulty": null}
{"lang": "GNU C11", "source_code": "#inlcude <stdio.h>\nint main ()\n{\n    char c;\n    int  n;\n    scanf(\"%c\",&c);\n    scanf(\"%d\",&n);\n    if(n%2==0)\n    printf(\"0\");\n    else \n    printf(\"1\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "15aa8e7bba97c909daa780d801cf26e6", "src_uid": "e52bc741bb72bb8e79cf392b2d15354f", "difficulty": null}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <iostream>\nusing namespace std;\nint main()\n{\n  string str;\n  cin>>str;\n  int n = str.length(), left=0, right =0 ;\n  int *pos = new int[n];\n  for (int i=0;i<n;++i)\n    {\n      if (str[i] == 'r')\n\t{\n\t  pos[left] = i;\n\t  ++left;\n\t}\n      else {\n\tpos[n-right-1] = i;\n\t++right;\n      }\n    }\n  for (int i=0;i<n;++i)\n    {\n      printf(\"%i\\n\", pos[i]+1);\n    }\n  delete pos;\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1b82373a9df12634bf09401e9b16c6a0", "src_uid": "b045abf40c75bb66a80fd6148ecc5bd6", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int a[3][3];\n    for(i=0;i<3;i++)\n    {\n    for(j=0;j<3;j++)\n    {\n      scanf(\"%d\",&a[i][j]);\n    }\n    }\n    \n    int i,j,sum;\n    for(i=0;i<3;i++)\n    {\n    for(j=0;j<3;j++)\n    {\n        sum=a[i][j];\n        if(i-1>=0)\n        sum=sum+a[i-1][j];\n        if(i+1<3)\n        sum=sum+a[i+1][j];\n        if(j-1>=0)\n        sum=sum+a[i][j-1];\n        if(j+1<3)\n        sum=sum+a[i][j+1];\n        printf(\"%d\",!(sum%2));\n    }\n    printf(\"\\n\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "70f1bc3b9b8bcc2ea80b7e497d35e120", "src_uid": "b045abf40c75bb66a80fd6148ecc5bd6", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n#include <stdio.h>\n#include <cstring>\n#include <math.h>\n\nusing namespace std;\n\nvoid gen(int *Mgen, int n)\n{\n    int i = 0;\n    while (i < n && Mgen[i] == 1)\n        Mgen[i++] = 0;\n    Mgen[i] = 1;\n    return;\n}\n\nvoid change(int a[5][5], int x, int y, int k)\n{\n    int i = 0, j;\n    if (k % 2 != 0)\n    {\n        a[x + 1][y] = (a[x + 1][y] == 0) ? 1 : 0;\n        a[x][y + 1] = (a[x][y + 1] == 0) ? 1 : 0;\n        a[x - 1][y] = (a[x - 1][y] == 0) ? 1 : 0;\n        a[x][y - 1] = (a[x][y - 1] == 0) ? 1 : 0;\n        a[x][y] = (a[x][y] == 0) ? 1 : 0;\n    }\n    return;\n}\n\n\nint main()\n{\n    int a[5][5], x, i, j;\n    for (i = 0; i < 5; i++)\n        for (j = 0; j < 5; j++)\n            a[i][j] = 1;\n    for (i = 1; i <= 3; i++)\n        for (j = 1; j <= 3; j++)\n        {\n            scanf(\"%d\", &x);\n            change(a, i, j, x);\n        }\n    for (i = 1; i <= 3; i++)\n    {\n        for (j = 1; j <= 3; j++)\n            printf(\"%d \", a[i][j]);\n        printf(\"\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b3f5f299a405fa702fbb0050fcd974f4", "src_uid": "b045abf40c75bb66a80fd6148ecc5bd6", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    printf(\"\\n\");\n    int i,j,a[3][3];\n    for(i=0;i<3;i++)\n    {for(j=0;j<3;j++)\n        {a[i][j]=1;}\n        int k,l,s[3][3];\n        printf(\"enter the array representing the times you have pressed the lights:\");\n    for(k=0;k<3;k++)\n    {for(l=0;l<3;l++)\n        {\n        scanf(\"%d\" ,&s[k][l]);\n        if((s[k][l])%2==0){s[k][l]=0;}\n            else{s[k][l]=1;}}}\n        \n\n        if(s[0][0]==1)\n        {for(i=0;i<2;i++)\n        {for(j=0;j<(2-i);j++){if(a[i][j]==0){a[i][j]=1;}\n            else{a[i][j]=0;}}}}\n\n\n        if(s[0][1]==1)\n        {for(i=0;i<2;i++)\n        {for(j=(0+i);j<(3-i);j++)\n            {if(a[i][j]==0){a[i][j]=1;}\n            else{a[i][j]=0;}}}}\n\n\n        if(s[0][2]==1)\n        {for(i=0;i<2;i++)\n        {\n            for(j=2;j>(0+i);j--)\n            {\n            if(a[i][j]==0){a[i][j]=1;}\n            else{a[i][j]=0;}}}}\n\n\n\n        if(s[1][0]==1)\n        {for(i=0;i<2;i++)\n        {\n            for(j=0;j<(1+i);j++)\n            {\n            if(a[i][j]==0){a[i][j]=1;}\n            else{a[i][j]=0;}\n            }\n        }\n            if(a[2][0]==0){a[2][0]=1;}\n            else{a[2][0]=0;}}\n\n\n        if(s[1][1]==1)\n        {for(j=1;j<3;j++){for(i=(j-1);i<(4-j);i++)\n        {if(a[i][j]==0){a[i][j]=1;}\n            else{a[i][j]=0;}}}\n            if(a[1][0]==0){a[1][0]=1;}\n            else{a[1][0]=0;}\n            }\n\n\n        if(s[1][2]==1)\n        {for(i=0;i<3;i++)\n        {\n            for(j=2;j>(1);j--)\n            {\n            if(a[i][j]==0){a[i][j]=1;}\n            else{a[i][j]=0;}\n            }\n        }\n            if(a[1][1]==0){a[1][1]=1;}\n            else{a[1][1]=0;}\n            }\n\n\n        if(s[2][0]==1)\n        {for(i=2;i>0;i--)\n        {for(j=0;j<(0+i);j++)\n            {if(a[i][j]==0){a[i][j]=1;}\n            else{a[i][j]=0;}}}\n        }\n\n\n\n        if(s[2][1]==1)\n        {for(i=2;i>1;i--)\n        {\n            for(j=(0);j<(3);j++)\n            {\n            if(a[i][j]==0){a[i][j]=1;}\n            else{a[i][j]=0;}}}\n            if(a[1][1]==0){a[1][1]=1;}\n            else{a[1][1]=0;}\n            }\n\n\n\n        if(s[2][2]==1)\n        {for(i=2;i>0;i--)\n        {\n            for(j=2;j>(2-i);j--)\n            {\n                if(a[i][j]==0){a[i][j]=1;}\n            else{a[i][j]=0;}}}\n        }\n\n\n\nprintf(\"\\n\");\n        for(i=0;i<3;i++)\n    {for(j=0;j<3;j++)\n        {printf(\"%d \" ,a[i][j]);}printf(\"\\n\");}\n\n       return 0;\n\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ab27640e3806d8892fadeb7d64cbad4a", "src_uid": "b045abf40c75bb66a80fd6148ecc5bd6", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint fast_int()\n{\n        int n = 0;\n        char c = getchar_unlocked();\n        while (!('0' <= c && c <= '9'))\n        {\n                c = getchar_unlocked(); \n        }\n        while ('0' <= c && c <= '9')\n        {\n                n = (n<<3)+(n<<1) + c - '0';\n                c = getchar_unlocked();\n        }\n        return n;\n}\nvoid quicksort(int a[],int lower,int upper)\n{\n\tif(lower<upper)\n\t{\n\t\tint i=split(a,lower,upper);\n\t\tquicksort(a,lower,i-1);\n\t\tquicksort(a,i+1,upper);\n\t}\n}\nint split(int a[],int lower,int upper)\n{\n\tint l=lower+1,u=upper,t,p=a[lower];\n\twhile(l<=u)\n\t{\n\t\twhile(a[l]<=p && l<=upper)\n\t\t\tl++;\n\t\twhile(a[u]>=p && u>lower)\n\t\t\tu--;\n//\t\tprintf(\"\\nstopped at %d and %d\",a[l],a[u]);\n\t\tif(l<u)\n\t\t{\n\t\tt=a[l];\n\t\ta[l]=a[u];\n\t\ta[u]=t;\n\t\t}\n\t}\n\tt=a[lower];\n\ta[lower]=a[u];\n\ta[u]=t;\n\treturn u;\n}\n\nint main()\n{\n\tint a[3][3],ans[3][3]={0};\n\tint i,j,i2,j2;\n\ti=0;\n\tfor(i=0;i<3;i++)\n\t{\n\t\tfor(j=0;j<3;j++)\n\t\t{\n\t\t\tscanf(\" %d\",&a[i][j]);\n\t\t\ta[i][j]=a[i][j]%2;\n\t\t\tif(a[i][j]==0)\n\t\t\t\tcontinue;\n\t\t\tfor(i2=i-1;i2<3 && i2<i+2;i2++)\n\t\t\t{\n\t\t\t\tfor(j2=j-1;j2<3 && j2<j+2;j2++)\n\t\t\t\t{\n\t\t\t\t\tif(i2<0 || j2<0)\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\tif((i2==i+1 && j2==j+1) || (i2==i-1 && j2==j+1)|| (i2==i-1 && j2==j-1)|| (i2==i+1 && j2==j-1))\n\t\t\t\t\tcontinue;\n\t\t\t\t\tans[i2][j2]++;\n//\t\t\t\t\tprintf(\"\\nplussing %d %d\",i2,j2);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor(i=0;i<3;i++)\n\t{\n\t\tfor(j=0;j<3;j++)\n\t\t{\n\t\t\tprintf(\"%d\",(ans[i][j]+1)%2);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1b131039231e8c50d5ee086a82c02585", "src_uid": "b045abf40c75bb66a80fd6148ecc5bd6", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int s,n,k,b;\n    scanf(\"%I64d%I64d\",&n,&k);\n    if(k>=(n/2))\n    {\n        s=((n-1)*n)/2;\n        printf(\"%I64d\",s);\n\n    }\n    else\n    {  b=n-1;\n       s=((k*((2*b)-(k-1)))/2)+(n-(2*k))*k+(((k-1)*(k))/2);\n       printf(\"%I64d\",s);\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "919150cf7b23aec43925b366587c6cc8", "src_uid": "ea36ca0a3c336424d5b7e1b4c56947b0", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main() {\n  long long number;\n  long long nap_time;\n  long long messiness = 0;\n\n  scanf(\"%lld\", &number);\n  scanf(\"%lld\", &nap_time);\n\n  if (nap_time >= (number / 2)) {\n    messiness = ((number) * (number - 1)) / 2;\n    printf(\"%lld\\n\", messiness);\n  } else {\n    for (long long i = 0; i < 2*nap_time && (number - i - 1) > 0; i++) {\n      messiness += (number - i - 1);\n    }\n    printf(\"%lld\\n\", messiness);\n  }\n  return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "2726f335a4c3f27aca7a1dbb20160578", "src_uid": "ea36ca0a3c336424d5b7e1b4c56947b0", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\ntypedef long long unsigned U;\ntypedef unsigned u;\nint main()\n{\n\tu n,q,i,j=0;U r=0;\n\tscanf(\"%u%u\",&n,&q);\n\tfor(i=n;q--;)\n\t{\n\t\tif(i>1){r+=(i<<1)-3;i-=2;}\n//\t\telse{if(j^=1)--r;else++r;}\n\t}\n\tprintf(\"%I64u\\n\",r);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "05c4523f5e0f192a426e5d6f34c5ad75", "src_uid": "ea36ca0a3c336424d5b7e1b4c56947b0", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define N_MAX 100000\nint shed[N_MAX] = {0,};\nint messi_max = 0;\n\nlong operations = 0;\n\nvoid initialize(int n)\n{\n\tint i;\n\n\tfor(i = 0 ; i < n ; i++)\n\t\tshed[i] = i + 1;\n}\n\nint find_messiness(int n)\n{\n\tint i,j;\n\tint messiness = 0;\n\n\tfor(i = 0 ; i < n ; i++){\n\t\tfor(j = i + 1 ; j < n ; j++){\n\t\t\t//operations++;\n\t\t\tif(shed[i] > shed[j])\n\t\t\t\tmessiness++;\n\t\t}\n\t}\n\n\treturn messiness;\n}\n\n\nint GetAnswer(int n, int k)\n{\n\tint i;\n\tint p,q;\n\tint messiness = 0;\n\tint local_mess;\n\tint tmp;\n\n\tif(n == 1)\n\t\treturn 0;\n\n\tlocal_mess = find_messiness(n);\n\t//operations++;\n\n\t/*if(operations % 10 == 0)\n\t\tprintf(\"Operations: %ld\\n\",operations);*/\n\n\tif(local_mess > messi_max)\n\t\tmessi_max = local_mess;\n\n\tif(k == 0)\n\t\treturn messi_max;\n\n\t// For each pair, check if its already messed up\n\t// If not ... make move\n\t// Make move: mess, reduce timer by 1\n\t// Bactrack\n\t// Unmake move\n\tfor(p = 0 ; p < n ; p++){\n\t\tfor(q = n - 1 ; q > p ; q--){\n\t\t\tif(shed[p] <= shed[q]){\n\t\t\t\t// Not messed up\n\t\t\t\ttmp = shed[q];\n\t\t\t\tshed[q] = shed[p];\n\t\t\t\tshed[p] = tmp;\n\t\t\t\tmessiness = GetAnswer(n,k-1);\n\t\t\t\t// Unmake move\n\t        \ttmp = shed[q];\n\t\t\t    shed[q] = shed[p];\n\t\t\t    shed[p] = tmp;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn messi_max;\n}\n\n\nint main()\n{\n\tint n, k;\n\tint answer = 0;\n\n\t/* handle the program options */\n\t//freopen(\"C:/Users/Subh/Desktop/Work/Coding/C_code/test43.txt\",\"rt\",stdin);\n\n\tscanf(\"%d %d\",&n,&k);\n\n\tinitialize(n);\n\tmessi_max = 0;\n\toperations = 0;\n\t//printf(\"Operations: %ld\\n\",operations);\n\t//printf(\"Messiness after initialization is %d\\n\",find_messiness(n));\n\n\t/* The code of your application goes here */\n\tanswer = GetAnswer(n, k);\n\n\tprintf(\"%d\\n\",answer);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "74b7ba679a7905649dfdb1afcc4793a5", "src_uid": "ea36ca0a3c336424d5b7e1b4c56947b0", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define N_MAX 100000\nint shed[N_MAX] = {0,};\nint messi_max = 0;\n\nlong operations = 0;\n\nvoid initialize(int n)\n{\n\tint i;\n\n\tfor(i = 0 ; i < n ; i++)\n\t\tshed[i] = i + 1;\n}\n\nint find_messiness(int n)\n{\n\tint i,j;\n\tint messiness = 0;\n\n\tfor(i = 0 ; i < n ; i++){\n\t\tfor(j = i + 1 ; j < n ; j++){\n\t\t\toperations++;\n\t\t\tif(shed[i] > shed[j])\n\t\t\t\tmessiness++;\n\t\t}\n\t}\n\n\treturn messiness;\n}\n\n\n/*int GetAnswer(int n, int k)\n{\n\tint i;\n\tint p,q;\n\tint messiness = 0;\n\tint local_mess;\n\tint tmp;\n\n\tif(n == 1)\n\t\treturn 0;\n\n\tlocal_mess = find_messiness(n);\n\toperations++;\n\n\tif(operations % 10 == 0)\n\t\tprintf(\"Operations: %ld\\n\",operations);\n\n\tif(local_mess > messi_max)\n\t\tmessi_max = local_mess;\n\n\tif(k == 0)\n\t\treturn messi_max;\n\n\t// For each pair, check if its already messed up\n\t// If not ... make move\n\t// Make move: mess, reduce timer by 1\n\t// Bactrack\n\t// Unmake move\n\tfor(p = 0 ; p < n ; p++){\n\t\tfor(q = n - 1 ; q > p ; q--){\n\t\t\tif(shed[p] <= shed[q]){\n\t\t\t\t// Not messed up\n\t\t\t\ttmp = shed[q];\n\t\t\t\tshed[q] = shed[p];\n\t\t\t\tshed[p] = tmp;\n\t\t\t\tmessiness = GetAnswer(n,k-1);\n\t\t\t\t// Unmake move\n\t        \ttmp = shed[q];\n\t\t\t    shed[q] = shed[p];\n\t\t\t    shed[p] = tmp;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn messi_max;\n}*/\n\nint GetAnswer(int n, int k)\n{\n\tint i;\n\tint local_mess = 0;\n\tint messiness = 0;\n\tint p,q;\n\tint tmp;\n\n\tif(n == 1)\n\t\treturn 0;\n\n\t// Swap maximally separated entities if it increases messiness\n\tfor(i = 0 ; i < k ; i++){\n\t\tfor(p = 0 ; p < n ; p++){\n\t\t\tfor(q = n - 1 ; q > p ; q--){\n\t\t\t\tif(shed[p] < shed[q]){\n\t\t\t\t\t// Swap and break\n\t\t\t\t\ttmp = shed[q];\n\t\t\t\t\tshed[q] = shed[p];\n\t\t\t\t\tshed[p] = tmp;\n\t\t\t\t\t//printf(\"i: %d ... messiness: %d\\n\",i+1,find_messiness(n));\n\t\t\t\t\tgoto RESULT;\n\t\t\t\t}\n\t\t\t}\n\t\t}\nRESULT:\n        p= 0 ;\n\t}\n\n\tmessiness = find_messiness(n);\n\n\treturn messiness;\n}\n\n\nint main()\n{\n\tint n, k;\n\tint answer = 0;\n\n\t/* handle the program options */\n\t//freopen(\"C:/Users/Subh/Desktop/Work/Coding/C_code/test43.txt\",\"rt\",stdin);\n\n\tscanf(\"%d %d\",&n,&k);\n\n\tinitialize(n);\n\tmessi_max = 0;\n\toperations = 0;\n\t//printf(\"Operations: %ld\\n\",operations);\n\t//printf(\"Messiness after initialization is %d\\n\",find_messiness(n));\n\n\t/* The code of your application goes here */\n\tanswer = GetAnswer(n, k);\n\n\tprintf(\"%d\\n\",answer);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0f31e8b2f88fe6664839249c2fbddace", "src_uid": "ea36ca0a3c336424d5b7e1b4c56947b0", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\nint main()\n{\n\tchar a[51];int i,n,b=1,c=1;\n\tgets(a);\n\tn=strlen(a);\n\tfor(i=1;i<n;i++){\n\t\tif(a[0]==a[i])\n\t\t\tb=1;\n\t\telse{\n\t\t\tb=0;break;\n\t\t}\t\n\t}\n\tfor(i=0;i<n;i++){\n\t\tif(a[i]==a[(n-i)-1])\n\t\t\tc=1;\n\t\telse\n\t\t\tc=0;break;\n\t\t}\n\t}\t\n\tif(b==1)\n\t\tprintf(\"0\");\n\telse if(c==1)\n\t\tprintf(\"%d\",n-1);\n\telse\n\t\tprintf(\"%d\",n);\t\t\t\t\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "70d78045040345a2e77174859617dd3c", "src_uid": "d259a3a5c38af34b2a15d61157cc0a39", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint x, y, k =0, m;\n\tscanf(\"%d %d\",&x,&y);\n\tif ((2*x)%y == 0)\n\t\tk = k + (2*x)/y);\n\telse \n\t\tk = k + ((2*x)/y) + 1;\n\tif ((5*x)%y == 0)\n\t\tk = k + (5*x)/y);\n\telse \n\t\tk = k + ((5*x)/y) + 1;\n\tif ((8*x)%y == 0)\n\t\tk = k + (8*x)/y);\n\telse \n\t\tk = k + ((8*x)/y) + 1;\n\tprintf(\"%d\", k);\n\treturn 0;\n}\n\t\n\t\n\t\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "bd89aeceacb5adefb01eadd770053e4b", "src_uid": "d259a3a5c38af34b2a15d61157cc0a39", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    register int n,k,r,blue,green,red;\n    scanf(\"%d %d\",&n,&k);\n    red=2*n;\n    green=5*n;\n    blue=8*n;\n    r=red/k;\n    if(red%k!=0)\n    {\n        r=r+1;\n    }\n    r=r+blue/k;\n    if(blue%k!=0)\n    {\n        r=r+1;\n    }\n    r=r+green/k;\n    if(green%k!=0)\n    {\n        r=r+1;\n    }\n    printf(\"%d\",r);\n    \n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8ddcbb29c8c15d8c7912bb63617d3b1f", "src_uid": "d259a3a5c38af34b2a15d61157cc0a39", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint x, y, k, z = 0;\n\tscanf(\"%d %d\",&x,&y);\n\tk = (15*x)/y;\n\tif k== 0;\n\t\tz = z + k;\n\telse \n\t\tz = z + (k+1);\n\tprintf(\"%d\",z);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "70479305474499e54bb12df13fad2b6c", "src_uid": "d259a3a5c38af34b2a15d61157cc0a39", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "\n\n\t#include <stdio.h>\n\tint main()\n\t{\n\tint n,k,r,g,b,p=0;\n\tscanf(\"%d%d\",&n,&k);\n\tr=n*2;\n\tg=n*5;\n\tb=n*8;\n\tif(r%k!=0)\n\t{p=p+(r/k)+1;}\n\telse\n\tp=p+(r/k);\n\tif(g%k!=0)\n\t{p=p+(g/k)+1;}\n\telse\n\tp=p+(g/k);\n\tif(b%k!=0)\n\t{p=p+(b/k)+1;}\n\telse\n\tp=p+(b/k);\n\tprintf(\"%d\",t);\n\t}\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2e54183d8eead3f49402d442d565b6b3", "src_uid": "d259a3a5c38af34b2a15d61157cc0a39", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n\nint prime(int p){\n    for(i=2;i<=(p/2);i++){\n        if(p%i==0)\n            return 1;//it is not prime \n    }\n    return 0;// it is prime\n}\n\nint main()\n{\n    int n,m,a,j;\n    scanf(\"%d\",&n);\n    scanf(\"%d\",&m);\n\n    a=prime(m);\n    if(a==1)\n        printf(\"NO\");\n    else{\n        for(j=n+1;j<m;j++){\n            a=prime(j);\n            if(a==0){\n                printf(\"NO\");\n                break;\n            }\n        }\n        if(a==1)\n            printf(\"YES\");\n\n    }\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3ed432b4114778c2aeca551d9491f5c4", "src_uid": "9d52ff51d747bb59aa463b6358258865", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "login as: jil004\njil004@ieng6.ucsd.edu's password:\nLast login: Thu Apr 21 22:05:07 2011 from 128.54.46.186\n====================  /var/account/announcements  ======================\nAuthorized use of this system is limited to password-authenticated\nusernames which are issued to individuals and are for the sole use of\nthe person to whom they are issued.  Privacy notice: be aware that\ncomputer files, electronic mail and accounts are not private in an\nabsolute sense.  For a statement of \"ACMS Acceptable Use Policies\"\n(last modified on September 2006) please see our webpage at\nhttp://acms.ucsd.edu/lib/aup.php.\n========================================================================\n>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>\n\n   N O T I C E !!! *** END OF WINTER QTR *** ACCOUNTS CLOSING ***\n   ==============================================================\n   Your ACMS account MAY be closing.\n\n   For reasons accounts may be closed/suspended see:\n        http://acms.ucsd.edu/students/account-status.shtml\n\n   To lookup your ACMS account information see:\n        https://sdacs.ucsd.edu/~icc/index.php\n   ==============================================================\n\n   1) Dates for class specific accounts and storage directories\nAccount information for user: jil004\n        Remaining allocation for jil004 was 301.00 units\n        as of Fri Apr 29 06:55:16 2011\njil004 is connected to recharge printer (real-money) account: la046440\n        la046440 balance: $1.70\n        la046440 status is: active\n=============================================================\nFor details about your account resources, please use the\nAccount Lookup Tool on our website at http://acms.ucsd.edu\n=============================================================\n\n\nTo begin work for one of your courses [ cs120s cs100s ], type its name\nat the command prompt.  (For example, \"cs120s\", without the quotes).\n\nTo see all available software packages, type \"prep -l\" at the command prompt,\nor \"prep -h\" for more options.\n[jil004@ieng6-201]:~:358$ ls\nCPP Notes.odt  Desktop                       a.out                     jintan.c\nCSE11          ECE260b lab report final.odt  cube.cpp~                 net.ods\nCSE120         Lab1 report ECE260B.odt       finalProject              vistudy\nCreview        Untitled 1.odt                implement_lec1_lab-1.zip\n[jil004@ieng6-201]:~:359$ cd Creview/\n[jil004@ieng6-201]:Creview:360$ ls\na.out  bubble.c  nextPrime.c  num1.c  num1.c~\n[jil004@ieng6-201]:Creview:361$ vi nextPrime.c\n[jil004@ieng6-201]:Creview:362$ ls\na.out  bubble.c  nextPrime.c  num1.c  num1.c~\n[jil004@ieng6-201]:Creview:363$ gcc nextPrime.c\n/tmp/ccMER0p9.o: In function `nextPrime':\nnextPrime.c:(.text+0xa5): undefined reference to `pringf'\ncollect2: ld returned 1 exit status\n[jil004@ieng6-201]:Creview:364$ vi nextPrime.c\n[jil004@ieng6-201]:Creview:365$ gcc nextPrime.c\n\\[jil004@ieng6-201]:Creview:366$ ./a.out\nNO\nYES\n[jil004@ieng6-201]:Creview:367$ vi nextPrime.c\n[jil004@ieng6-201]:Creview:368$ gcc nextPrime.c\nnextPrime.c: In function 'nextPrime':\nnextPrime.c:35: error: expected expression before 'else'\n[jil004@ieng6-201]:Creview:369$ vi nextPrime.c\n[jil004@ieng6-201]:Creview:370$ gcc nextPrime.c\n[jil004@ieng6-201]:Creview:371$ ./a.out\nNO\n[jil004@ieng6-201]:Creview:372$ vi nextPrime.c\n[jil004@ieng6-201]:Creview:373$ gcc nextPrime.c\n[jil004@ieng6-201]:Creview:374$ ./a.out\nNO\n[jil004@ieng6-201]:Creview:375$ vi nextPrime.c\n[jil004@ieng6-201]:Creview:376$ gcc nextPrime.c\nnextPrime.c: In function 'nextPrime':\nnextPrime.c:17: error: expected expression before '=' token\n[jil004@ieng6-201]:Creview:377$ vi nextPrime.c\n[jil004@ieng6-201]:Creview:378$ gcc nextPrime.c\n[jil004@ieng6-201]:Creview:379$ ./a.out\n[jil004@ieng6-201]:Creview:380$ gcc nextPrime.c\n[jil004@ieng6-201]:Creview:381$ ./a.out\n[jil004@ieng6-201]:Creview:382$ vi nextPrime.c\n[jil004@ieng6-201]:Creview:383$ gcc nextPrime.c\n[jil004@ieng6-201]:Creview:384$ ./a.out\nYES\n[jil004@ieng6-201]:Creview:385$ vi nextPrime.c\n[jil004@ieng6-201]:Creview:386$ gcc nextPrime.c\n[jil004@ieng6-201]:Creview:387$ ./a.out\nYES\n[jil004@ieng6-201]:Creview:388$ vi nextPrime.c\n[jil004@ieng6-201]:Creview:389$ gcc nextPrime.c\n[jil004@ieng6-201]:Creview:390$ ./a.out\nYES\n[jil004@ieng6-201]:Creview:391$ vi nextPrime.c\n[jil004@ieng6-201]:Creview:392$ gcc nextPrime.c\n[jil004@ieng6-201]:Creview:393$ ./a.out\nNO\n[jil004@ieng6-201]:Creview:394$ vi nextPrime.c\n[jil004@ieng6-201]:Creview:395$ gcc nextPrime.c\n[jil004@ieng6-201]:Creview:396$ ./a.out\nNO\n[jil004@ieng6-201]:Creview:397$ vi nextPrime.c\n[jil004@ieng6-201]:Creview:398$ gcc nextPrime.c\n[jil004@ieng6-201]:Creview:399$ ./a.out\nYES\n[jil004@ieng6-201]:Creview:400$ vi nextPrime.c\n  4\n   void nextPrime(int n, int m)\n  {\n      int numPrime = 0;\n      int i        = 0;\n      int j        = 0;\n      int flag     = 0;\n \n      for(i = n+1; i <= m; i++)\n      {\n          flag = 0;\n          for(j = 2;( j * j) <= i; j++)\n          {\n              if(i%j==0)\n              {\n                  flag = 1;\n                  break;\n              }\n          }\n          if(flag==0 && i != m)\n          {\n              printf(\"NO\\n\");\n              break;\n          }\n      }\n      if(flag == 0)\n          printf(\"YES\\n\");\n      else\n          printf(\"NO\\n\");\n \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "67342dbb251a679bf525de594e279e57", "src_uid": "9d52ff51d747bb59aa463b6358258865", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "\n #include <stdio.h>\n\n void nextPrime(int n, int m)\n {\n     int numPrime = 0;\n     int i        = 0;\n     int j        = 0;\n     int flag     = 0;\n\n     for(i = n+1; i <= m; i++)\n     {\n         flag = 0;\n         for(j = 2;( j * j) <= m; j++)\n         {\n             if((i%j)==0)\n             {\n                 flag = 1;\n                 break;\n             }\n         }\n         if((flag==0) &&( i != m))\n         {\n             printf(\"NO\\n\");\n             return;\n         }\n     }\n     if(flag == 0)\n         printf(\"YES\\n\");\n     else\n         printf(\"NO\\n\");\n\n }", "lang_cluster": "C", "compilation_error": true, "code_uid": "9e471acf13c25a2f1a68854ba5272302", "src_uid": "9d52ff51d747bb59aa463b6358258865", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "include<stdio.h>\n#include<math.h>\nint main()\n{\n    int a,b,i,c,j,m=0,n=0;\n    scanf(\"%d %d\",&a,&b);\n    for(i=a;i<=b;i++)\n    {  c=0;\n        for(j=2;j<i;j++)\n        {\n            if(i%j==0)\n                c=1;\n\n        }\n\n       if(c==0&&i!=a&&i!=b)\n        {printf(\"No\\n\");\n         n=5;\n        }\n         if(c==1&&(i==a||i==b))\n        {printf(\"No\\n\");\n          n=5;\n        }\n\n    }\n\n    if(n!=5)printf(\"YES\\n\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "05f84caca058cb948293f8e8db53b6c6", "src_uid": "9d52ff51d747bb59aa463b6358258865", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "Problem\nStatus\nRank (48:01:27)\n0 Comments\nPrevious12345\u2026Next\nUsername\n2018331065\nProb\n\tResult \n\tTime\n(ms)\tMem\n(MB)\tLang \n\tSubmit Time\n2018331065\nS\nWrong answer on test 3\nC++\n4 min ago\n2018331065\nS\nCompilation error\nC++\n6 min ago\n2018331065\nS\nWrong answer on test 3\nC\n21 min ago\n2018331065\nS\nWrong answer on test 1\nC\n35 min ago\n2018331065\nS\nWrong answer on test 3\nC\n36 min ago\n2018331065\nS\nWrong answer on test 1\nC\n38 min ago\n           \nAll Copyright Reserved \u00a9 2010-2019 Xu Han\nServer Time: 2019-05-16 22:01:29 BST\n\n#19771930 | 2018331065's solution for [Problem S]\nStatus\nWrong answer on test 3\nTime\n60ms\nLength\n422\nLang\nMicrosoft Visual C++ 2010\nSubmitted\n2019-05-16 21:57:23\nShared\n\nSelect Code\n#include<stdio.h>\n#include<math.h>\nint main()\n{\n    int a,b,i,c,j,m=0;\n    scanf(\"%d %d\",&a,&b);\n    for(i=a;i<=b;i++)\n    {  c=0;\n        for(j=2;j<i;j++)\n        {\n            if(i%j==0)\n                c=1;\n\n        }\n\n       if(c==0&&i!=a&&i!=b)\n        {printf(\"N0\\n\");\n          return 0;\n        }\n         if(c==1&&(i==a||i==b))\n        {printf(\"N0\\n\");\n          return 0;\n        }\n\n    }\n\n    printf(\"YES\\n\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "db129a922db7464f74870e17334a168e", "src_uid": "9d52ff51d747bb59aa463b6358258865", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,i,o=0,e=0,s=0,s1,s2,f=-1;\n    scanf(\"%d\",&n);\n    int a[n];\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        if(a[i]==100)\n        o++;\n        if(a[i]==200)\n        e++;\n    }\n    if((o%2==1)\n       {\n           if(e%2==1)\n           f=0;\n           else\n           f=1;\n       }\n    else\n    {if((e%2==0))\n    f=0;\n    else\n    {\n        n=e%2;\n        if((n*200)==(o*100))\n        f=0;\n        else\n        f=1;\n    }\n    }\n    if(f==0)\n    printf(\"YES\\n\");\n    else\n    printf(\"NO\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "00aa68f2353f964c18a5fee84196ae89", "src_uid": "9679acef82356004e47b1118f8fc836a", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n\n#define print(a) printf(\"%s = %lu\\n\",#a,a);\n\nunsigned long * arr_ptr,*arr;\nunsigned long sum = 0,tmp_sum = 0,sum_by_2,two_pow_n = 1;\nlong n;\n\n\n\nvoid distribute()\n{\n\tstatic unsigned long dead_end = 0;\n\tif( tmp_sum == sum_by_2 )\n\t{\n\t\tprintf(\"YES\");\n\t\texit(0) ;\n\t}\n\telse if( tmp_sum < sum_by_2 )\n\t{\n\t\tif( (arr_ptr - arr) >= n )\n\t\t{\n\t\t\tdead_end += 1;\n\t\t\tif( dead_end == two_pow_n )\n\t\t\t{\n\t\t\t\tprintf(\"NO\");\n\t\t\t\texit(0) ;\n\t\t\t}\n\t\t}\n\t\telse\n\t\t{\n\t\t\ttmp_sum += *arr_ptr;\n\t\t\tarr_ptr += 1;\n\t\t\tdistribute();\n\t\t\tarr_ptr -= 1;\n\t\t\ttmp_sum -= *arr_ptr;\t\t\t\n\t\t\tarr_ptr += 1;\n\t\t\tdistribute();\n\t\t\tarr_ptr -= 1;\n\t\t\t\n\t\t}\n\t}\n\telse\n\t{\n\t\tdead_end += 1;\n\t\tif(dead_end == two_pow_n)\n\t\t{\n\t\t\tprintf(\"NO\");\n\t\t\texit(0) ;\n\t\t}\n\t}\n}\n\t\t\t\t\nint main()\n{\n \tlong iter,n200,n100;\n\tscanf(\"%lu\",&n);\n\tif( n < 2)\n\t{\n\t\tprintf(\"NO\");\n\t\treturn 0;\n\t}\n\tarr_ptr = arr = (unsigned long*)malloc( n*sizeof(unsigned int) );\n\tmemset(arr,0,sizeof(unsigned)*n);\n\titer = n-1;\n\twhile ( iter > -1 )\n\t{\n\t\tscanf(\"%lu\",arr + iter);\n\t\tsum += arr[iter];\n\t\ttwo_pow_n *= 2;\n\t\titer -= 1;\n\t}\n\t\n\tif( sum % 200 != 0 || ( n%2==1 && n100==0 ) )\n\t{\n\t\tprintf(\"NO\");\n\t\treturn 0;\n\t}\n\n\tif( /*sum already div by 200*/ n200%2==0 )\n\t{\n\t\tprintf\n\n\tsum_by_2 = sum / 2;\n\n\tdistribute();\n\n\tprintf(\"NO\");\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "625c018e7c6ef16fc9d18bdda27b66eb", "src_uid": "9679acef82356004e47b1118f8fc836a", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n    int n,x,i,s,sum=0;\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&x);\n        sum=sum+x;\n        if(x==200)\n        k++;\n    }\n    s=sum/100;\n    if(k%2==0 ||(k%2==1 && k!=n))\n    {if(s%2==0)\n    printf(\"YES\");}\n    printf(\"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a9d13326677ee2d7233cc007baa1832f", "src_uid": "9679acef82356004e47b1118f8fc836a", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n     int n;\n     scanf(\"%d\",&n);\n     int a[n];\n     for(int i=1;i<=n;i++)\n     {\n          scanf(\"%d\",&a[i]);\n     }\n     int j,k,l,o,p;\n     for(j=1;j<=n;j++)\n     {\n          if(a[j]==100)\n          k++;\n          else\n          l++;\n     }\n     if((k==l&&k>1)||k==2*l||{k%2==0 && k>0)||(l%2==0 && l>0))\n     printf(\"YES\");\n     else\n     printf(\"NO\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9fcc4d2d14bedc2582e5717b4f7e8cc4", "src_uid": "9679acef82356004e47b1118f8fc836a", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n \nint main(void) {\n    // your code goes here\n    int n,i,j,sum=0,k=0,l=0;\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++){\n        scanf(\"%d\",&j);\n        if(j==200) k++;\n        else       l++;\n        sum=sum+j;\n    }\n    if (sum%2==0){\n        i=sum/2;\n        j=i/200;\n        if(k>=j){ \n            k=k-j;\n            i=i%200;\n        else{\n            i=i-k*200;\n            k=0;\n        }\n        int p=i/100;\n        if(l>=p) printf(\"YES\");\n        else     printf(\"NO\");\n    }\n    else          printf(\"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "46f833cac7c00f6d280b3e5c7722a4ce", "src_uid": "9679acef82356004e47b1118f8fc836a", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\n\nusing namespace std;\nint main()\n{\n    long long a,b,s,ans;\n    scanf(\"%lld%lld%lld\",&a,&b,&s);\n    ans=abs(a)+abs(b);\n    if(s>=ans&&((s%2)==(ans%2)))\n        printf(\"YES\\n\");\n    else\n        printf(\"NO\\n\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e2f9b367b337de8da46029df5cb6091e", "src_uid": "9a955ce0775018ff4e5825700c13ed36", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void) {\n\n\nint a,b,s;\nscanf(\"%d%d%d\",&a,&b,&s);\nif(a<0)\n{\n    a=a*-1;\n    \n}\n\n\nif(b<0)\n{\n    b=b*-1;\n        \n}\n\nif(a+b<=s  && (s-(a+b))%2==0 )\n\n{\n\nprintf(\"Yes\");\n\n}\n\nelse \n{\n\nprintf(\"No\");\n\n\n}\n\n\n    \n}\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c7b83937f38cfbcf4166bcd67a4547e8", "src_uid": "9a955ce0775018ff4e5825700c13ed36", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{int a,b,s;\nscanf(\"%d,%d,%d\",&a,&b,&s);\nif(a+b<s||((a+b-s)%2!=0))\nprintf(\"no\");\nelse\nprintf(\"yes\");\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9087cf6c35755ce61f72c49a277c5f31", "src_uid": "9a955ce0775018ff4e5825700c13ed36", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<iostream>\n\nusing namespace std;\n\nint main()\n{\n\tlong long a, b, s;\n\tcin >> a >> b >> s;\n\tif (a + b > s)\n\t\tprintf(\"No\\n\");\n\telse\n\t{\n\t\tif ((s - a + b) % 2 == 0)\n\t\t\tprintf(\"Yes\\n\");\n\t\telse\n\t\t\tprintf(\"No\\n\");\n\t}\n\treturn 0;\n}\n                        ", "lang_cluster": "C", "compilation_error": true, "code_uid": "868b91b15196ed019466b59cd18afa6f", "src_uid": "9a955ce0775018ff4e5825700c13ed36", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "void isTrue(int a, int b, int s)\n{\n    int diff = s - (a+b);\n    if(diff >= 0 && diff%2==0)\n        {\n            print(\"yes\\n\");\n        }\n    else print(\"No\\n\");\n}\nint main()\n{\n    int a,b,s;\n    scanf(\"%d %d %d\\n\",a,b,s);\n    isTrue(a,b,s);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fd659448445b93dc231a6d10421c2949", "src_uid": "9a955ce0775018ff4e5825700c13ed36", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "4\n0 15 5 10#include <stdio.h>\n\nint min(int a, int b){\n    if(a > b)\n        return b;\n    else    \n        return a;\n}\nint max(int c, int d){\n    if(c > d)\n        return c;\n    else \n        return d;\n}\n\nint main(){\n    int n, i, j, a[1000];\n    scanf(\"%d\", &n);\n    for(i = 0; i < n; i++){\n        scanf(\"%d\", &a[i]);\n    }\n    for(i = 0; i < n - 1; i++){\n        int x, y, f1 = 0, f2 = 0;\n        x = min(a[i], a[i + 1]);\n        y = max(a[i], a[i + 1]);\n        for (j = i + 2; j < n; j++){\n            if(a[j] < x || a[j] > y){\n                f1 = 1;\n            }\n            else{\n                f2 = 1;\n            }\n        }\n        if(f1 == 1 && f2 == 1){\n            printf(\"yes\\n\");\n            return 0;\n        }\n    }\n    printf(\"no\\n\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e1eed8c485e97c9e7c2934e7cc822955", "src_uid": "f1b6b81ebd49f31428fe57913dfc604d", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n     int n;\n     scanf(\"%d\",&n);\n     int i,a[n];\n     for(i=1;i<=n;i++)\n     {\n          scanf(\"%d\",&a[i]);\n     }\n     int j,k,l,o,p,q;\n     if(n>3)\n     {\n          int m=3,t,u,x;\n     for(i=2;i<n; )\n     x=0;\n          t=0,u=0;\n          if((a[i]>a[i-1] && a[i+1]<a[i] && a[i+1]>a[i-1]) || (a[i]<a[i-1] && a[i+1]>a[i] && a[i+1]<a[i-1]))\n          {\n               t=1;\n               for(j=i;j>=1;j--)\n               {\n                    if(a[j]>a[i+1])\n                    q=a[j];\n                    if(a[j]<a[i+1])\n                    p=a[j];\n               }\n               for(k=4;k<=n;k++ )\n               {\n                    if(a[k]>a[k-1] && a[k]<q)\n                    m++;\n                    else if(a[k]<a[k-1] && a[k]>p)\n                    m++;\n                    else \n                    {u=1;\n                    printf(\"yes\");\n                    break;\n                    }\n               }\n               \n          }\n          else\n          i++;\n          if(a[i]-a[i-1]==1)\n          x=1;\n          if(x==1)\n          printf(\"no\");\n          if(t==1 && m==n)\n          {\n          printf(\"no\");\n          break;\n          }\n          if(u==1)\n          break;\n          \n          \n     }\n     if(i==n-1)\n     printf(\"yes\");\n     }\n     else \n     printf(\"no\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c871daa1076f2e6fc06854e3921ca2b3", "src_uid": "f1b6b81ebd49f31428fe57913dfc604d", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n    long long int n,i,x=0,y=0,j;\n    scanf(\"%lld\",&n);\n    long long int a[n];\n    for(i=0;i<n;i++)scanf(\"%d\",&a[i]);\n    for(i=0;i<n;i++){x=y=0;\n    for(j=i+2;j<n;j++)\n    if ((a[j]>a[i]&&a[j]>a[i+1])||(a[j]<a[i]&&a[j]<a[i+1])) x++;\n    else y++;\n    if(x&&y)\n    {\n        printf(\"yes\");return 0;\n    }\n    printf(\"no\");return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "96e4f9b91b46a8aace21dc306122fd3a", "src_uid": "f1b6b81ebd49f31428fe57913dfc604d", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n        long long int x,a[1000],i,b[1000],count=0;\n        scanf(\"%lld\",&x);\n        for(i=0;i<x;i++)\n        {\n                scanf(\"%lld\",&a[i]);\n                b[i]=0;\n        }\n        for(i=0;i<(x-1);i++)\n        {\n                b[i]=llabs(a[i+1]-a[i]);\n        }\n        for(i=1;i<x;i++)\n        {\n                if(b[i]<b[i-1])\n                        count++;\n                else\n                        break;\n        }\n        if(count==(x-1))\n                printf(\"no\\n\");\n        else\n                printf(\"yes\\n\");\n        return 0;\n}\n~                                                                                                                                                                                                \n~                                                                                                                                                                                                \n~        ", "lang_cluster": "C", "compilation_error": true, "code_uid": "ed2a2ac423f87494ea2d15d8b61f50be", "src_uid": "f1b6b81ebd49f31428fe57913dfc604d", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n     int n;\n     scanf(\"%d\",&n);\n     int i,a[n];\n     for(i=1;i<=n;i++)\n     {\n          scanf(\"%d\",&a[i]);\n     }\n     int j,k,l,o,p,q;\n     if(n>3)\n     {\n          int m=3,t,u,x;\n     for(i=2;i<n; )\n     {\n     \n          t=0,u=0;\n          if((a[i]>a[i-1] && a[i+1]<a[i] && a[i+1]>a[i-1]) || (a[i]<a[i-1] && a[i+1]>a[i] && a[i+1]<a[i-1]))\n          {\n               t=1;\n               for(j=i;j>=1;j--)\n               {\n                    if(a[j]>a[i+1])\n                    q=a[j];\n                    if(a[j]<a[i+1])\n                    p=a[j];\n               }\n               for(k=4;k<=n;k++ )\n               {\n                    if(a[k]>a[k-1] && a[k]<q)\n                    m++;\n                    else if(a[k]<a[k-1] && a[k]>p)\n                    m++;\n                    else \n                    {u=1;\n                    printf(\"yes\");\n                    break;\n                    }\n               }\n               \n          }\n          else if((a[i]>a[i-1] && a[i+1]<a[i]&& a[i+1]<a[i-1]) || (a[i]<a[i-1]&& a[i-1]>a[i] && a[i+1]>a[i-1])){\n          printf(\"yes\");\n          break;\n     \n          else\n          i++;\n          \n          if(t==1 && m==n)\n          {\n          printf(\"no\");\n          break;\n          }\n          if(u==1)\n          break;\n          }\n          if(i==n)\n          printf(\"no\");\n     }\n     else \n     printf(\"no\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d5301dda0d5eb30c351816213ed11285", "src_uid": "f1b6b81ebd49f31428fe57913dfc604d", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint min(int a,int b)\n{\n\treturn (a<b?a:b);\n}\nint main()\n{\n\tint map[444],t;\n\tscanf(\"%d\",&t);\n\tfor (int i=0;i<t;i++)\n\t{\n\t\tscanf(\"%d\",&map[i]);\n\t}\n\tint min=360;\n\tfor (int i=0;i<t;i++)\n\t{\n\t\tint temp=0;\n\t\tfor (int j=i;j<t;j++)\n\t\t{\n\t\t\ttemp+=map[j];\n\t\t\tmin=min(abs(360-2*temp),min);\n\t\t}\n\t}\n\tprintf(\"%d\",min);\n\treturn 0;\n} \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6d890100435b217f9ba0d00969e9b283", "src_uid": "1b6a6aff81911865356ec7cbf6883e82", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(){\n    int n, i, a=0, b=0;\n    scanf(\"%d\", &n);\n    int arr[n];\n    for(i=0;i<n;i++){\n        scanf(\"%d\", &arr[i]);\n    }\n    i=0;\n    while(a<=180){\n        a+= arr[i];\n        i+=1;\n    }\n    for(i=i;i<n;i++){\n        b+=arr[i];\n    }\n    selisih = b-a;\n    printf(\"%d\", selisih);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "df5b933b7fcd99837698b97a7daf49d4", "src_uid": "1b6a6aff81911865356ec7cbf6883e82", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint fmin(int a,int b)\n{\n\treturn (a<b?a:b);\n}\nint main()\n{\n\tint map[444],t;\n\tscanf(\"%d\",&t);\n\tfor (int i=0;i<t;i++)\n\t{\n\t\tscanf(\"%d\",&map[i]);\n\t}\n\tint min=360;\n\tfor (int i=0;i<t;i++)\n\t{\n\t\tint temp=0;\n\t\tfor (int j=i;j<t;j++)\n\t\t{\n\t\t\ttemp+=map[j];\n\t\t\tint flag=abs(360-2*temp);\n\t\t\tmin=fmin(flag,min);\n\t\t}\n\t}\n\tprintf(\"%d\",min);\n\treturn 0;\n} \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0ad525800670c499f1e2d3ebf270a77a", "src_uid": "1b6a6aff81911865356ec7cbf6883e82", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(){\n\tint n,i,j,k,sum=0,min=720;\n\tscanf(\"%d\",&n);\n\tint a[n];\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\",&a[i]);\n\t}\n\tfor(i=0;i<n;i++)\n\t{\n\t\tfor(j=i;j<n;j++)\n\t\t{\n\t\t\tfor(k=i;k<=j;k++)\n\t\t\t{\n\t\t\t\tsum+=a[k];\n\t\t\t}\n\t\t\tx=180-sum;\n\t\t\tif(x<0)\n\t\t\t\tx=-x;\n\t\t\tif(x<min)\n\t\t\t\tmin=x;\n\t\t\tsum=0;\n\t\t\t\n\t\t\t\t\n\t\t}\n\t\t\n\t}\n\tprintf(\"%d\",2*min);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a577f8e3cfd7e5097cfce0e3f288aa53", "src_uid": "1b6a6aff81911865356ec7cbf6883e82", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>//abs\u4e3a\u6574\u5f62\uff0cfabs\u4e3afloat cf\u4e0d\u4e07\u80fd \n#include<algorithm>\nusing namespace std;\nint main()\n{\n\tint n,a[400];\n\tscanf(\"%d\",&n);\n\t\tint i,j1=0,j2=0;\n\t\tfor(i=0;i<n;i++)\n\t\t\tscanf(\"%d\",&a[i]);\n\t\tsort(a,a+n);\n\t\tif(n==1) printf(\"%d\\n\",a[0]);\n\t\telse if(n%2==0)\n\t\t{\n\t\t\tfor(i=0;i<n/2;i++)\n\t\t\t{\n\t\t\t\tif(i<n/4)\n\t\t\t\t{\n\t\t\t\t\tj1=a[i]+a[n-1-i]+j1;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tj2=a[i]+a[n-1-i]+j2;\n\t\t\t\t}\n\t\t\t}\n\t\t\tprintf(\"%d\\n\",abs(j2-j1));\n\t\t}\n\t\telse \n\t\t{\n\t\t\tfor(i=0;i<n;i++)\n\t\t\t{\n\t\t\t\tif(i<=n/2) j1+=a[i];\n\t\t\t\telse j2+=a[i];\n\t\t\t}\n\t\t\tprintf(\"%d\\n\",abs(j2-j1));\n\t\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "89279d6bd0da5130ec48f76f4c02299c", "src_uid": "1b6a6aff81911865356ec7cbf6883e82", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void)\n{\n\tlong long T, S, q, start;\n\tdouble sr, loaded, track_pos;\n\t\n\tscanf(\"%lld %lld %lld\", &T, &S, &q);\n\tstart = 1;\n\ttrack_pos = 0;\n\tloaded = S;\n\twhile(loaded+0.000000000001 < T)\n\t{\n\t\tsr = loaded - track_pos;\n\t\ttrack_pos = loaded;\n\t\tloaded = loaded + sr*(q-1)/q;\n\t\tif(sr < 0.0000000000001)\n\t\t{\n\t\t\tstart++;\n\t\t\ttrack_pos = 0;\n\t\t}\n\t}\n\tprintf(\"%lld\\n\", start);\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a225782807e3ca85cc09367f0ef07a35", "src_uid": "0d01bf286fb2c7950ce5d5fa59a17dd9", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main ()\n{\n    int t,z=0;\n    double s,q,st;\n    long double n;\n    scanf(\"%d%lf%lf\",&t,&s,&q);\n    q=(q-1)/q;\n    while(s<t)\n    {\n      n=(s*q);\n      while(n>(1/8))\n      {\n       if(s-(int)s>0.9999)\n          s=(int)s+1;\n        if(s>=t)\n          break;\n       s=s+n;\n       n=n*q;\n      }\n     z++;\n    }\n    printf(\"%d\\n\",z);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e8360107e37106bbb351016136c1bd1f", "src_uid": "0d01bf286fb2c7950ce5d5fa59a17dd9", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "//http://codeforces.com/contest/569/problem/A\n\n#include <stdio.h>\n#include <stdlib.h>\n\nint main(void){\n    int i,j;\n    int speed;\n    int dur,already;\n    int meet;\n    int time=0;\n    scanf(\"%d %d %d\",&dur,&already,&speed);\n    while(){\n        time++;\n        //remain=(dur-already)/(speed-1)*speed;//\ufffd\u0474X\ufffd\ufffdU\ufffd\ufffd\n        meet=already*(speed/(speed-1));\n        if(meet>dur){\n            already=meet;\n        }\n        else {\n            break;\n        }\n    }\n    printf(\"%d\\n\",time);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b6cb4fab1a1127716fe7a84381d368db", "src_uid": "0d01bf286fb2c7950ce5d5fa59a17dd9", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main() {\n        int T,S,q,a,b,count=1;\n        scanf(\"%d %d %d\",&T, &S, &q);\n        T = T-S*q;\n        while(T>0) {\n                count++;\n                S=S*q;\n                T=T-S;\n        }\n        printf(\"%d\\n\",count);\nreturn 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "ec01dac7d2478df59e4fb83c94b10f6e", "src_uid": "0d01bf286fb2c7950ce5d5fa59a17dd9", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>  \nint main()\n{\n\tint T, S, q;\n\tint sum = 0;\n\t\tint n = 0;\n\tscanf(\"%d%d%d\", &T, &S, &q);\n\twhile (T > sum)\n\t{\n\n\t\tsum = S*q\n\t\tn++;\n\t\tS = sum;\n\t}\n\tprintf(\"%d\\n\", n);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2a0723ef16055450469b1e3e4eaf0e96", "src_uid": "0d01bf286fb2c7950ce5d5fa59a17dd9", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tlong long int n;\n \n    cin >> n;\n    if(n == 0)\n\t{\n    \tcout << 1 << endl;\n    }\n    if(n % 4 == 1)cout << 8 << endl;\n    else if(n % 4 == 2)cout << 4 << endl;\n    else if(n % 4 == 3)cout << 2 << endl;\n    else cout << 6 << endl;\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "32ae80a48ff89dc3bbf601722ac73176", "src_uid": "4b51b99d1dea367bf37dc5ead08ca48f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <algorithm>\n#include <math.h>\nusing namespace std;\nint main()\n{\n    int n,a,b,c,d;\n    while(scanf(\"%d\",&n)!=EOF)\n    {\n        a=1;\n      for(int i=0;i<n;i++)\n      {\n          a=(a*8)%10;\n      }\n      printf(\"%d\\n\",a);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1c6f7be48636b67f2c30562d5bc1651f", "src_uid": "4b51b99d1dea367bf37dc5ead08ca48f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain ()\n{\n    long long int n, a, b;\n    scanf(\"%I64d\", &n);\n    a=n%4;\n    if (a==0) printf(\"6\");\n    else if (a==1) printf(\"8\");\n    else if (a==2) printf(\"4\");\n    else (a==3) printf(\"2\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9de7fb5e53f45c6a55b284a0fa443035", "src_uid": "4b51b99d1dea367bf37dc5ead08ca48f", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c6f9020216ba3ef9d74726a275abadcc", "src_uid": "4b51b99d1dea367bf37dc5ead08ca48f", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n     int n;\n     scanf(\"%d\",&n);\n     int j,k,l,m;\n     for(j=1;j<=n;j+=4)\n     {\n          if(j==n)\n          printf(\"8\");\n     }\n     for(k=2;k<=n;k+=4)\n     {\n          if(k==n)\n          printf(\"4\");\n     }\n     for(l=3;l<=n;l+=4)\n     {\n          if(l==n)\n          printf(\"2\");\n     }\n     for(m=4;m<=n;m+=4)\n     {\n          if(m==n)\n          printf(\"6\");\n     }\n     if(n==0)\n     printf(\"1\");", "lang_cluster": "C", "compilation_error": true, "code_uid": "0afbad42bfe197d0d724e243a6229fc8", "src_uid": "4b51b99d1dea367bf37dc5ead08ca48f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <iostream>\nusing namespace std;\n\nint main() {\n\tchar a[51];\n\tscanf(\"%s\",a);\n\tint c=0;\n\t\n\tfor(int i=0;a[i] !='\\0';i++){\n\t    if(a[i]=='a'||a[i]=='e'||a[i]=='i'||a[i]=='o'||a[i]=='u'){\n\t                         c++;\n\t         \t           \n   \n\t        }\n\t        else if(isdigit(a[i])&&(a[i]-'0')%2){\n\t            c++;\n\t            \n\t        }\n\t    }\n\t\n\tprintf(\"%d\\n\",c);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f0a81b4d4b7e480025ff7c748a1889d7", "src_uid": "b4af2b8a7e9844bf58ad3410c2cb5223", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main()\n{\n\tchar a[200];\n\tgets(a);\n\t\n\tint len =strlen(a);\n\tint sum=0;\n\t\n\tfor(int i=0;i<len;i++)\n\t{\n\t\tif(a[i]=='a'||a[i]=='e'||a[i]=='i'||a[i]=='o'||a[i]=='u'||a[i]=='1'||a[i]=='3'|| a[i]=='4'||a[i]=='5'||a[i]=='7'a[i]=='9')\n\t\tsum++;\n\t}\n\tprintf(\"%d\",sum);\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4b6ecb81ad9a8544e78c45f7f59b1bd6", "src_uid": "b4af2b8a7e9844bf58ad3410c2cb5223", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n\nint checker( char *sentence){\n    \n    int i;\n    int j;\n    sentence=(char*)malloc(51);\n    \n    scanf(\"%s\", sentence);\n    \n\n    char *nexus;\n    nexus= (char*)malloc(10);\n    nexus={'a','e','i','o','u','1','3','5','7','9'};\n    \n        i=0;\n        j=0;\n    for(; sentence[i]; ++i){\n     if (sentence[i]=nexus[i])\n     j++;\n    }\n    \n    return j;\n}\n\n\nint main(){\n    char *hayker;\n    hayker= (char*)malloc(51);\n    scanf(\"%s\", hayker);\n    printf(\"%d\", checker(hayker) );\n    \n    return 0;\n    \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e5a43105d52eab06b25ea59b0e2ff841", "src_uid": "b4af2b8a7e9844bf58ad3410c2cb5223", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "main.c", "lang_cluster": "C", "compilation_error": true, "code_uid": "d9cd7ed1b5a4265c2a10afae596050be", "src_uid": "b4af2b8a7e9844bf58ad3410c2cb5223", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int n,a,b=0;\n    char na[51];\n    scanf(\"%s\",&na);\n    n=strlen(na);\n    for(i=0;i<n;i++)\n    {\n        if(na[i]=='a' || na[i]=='e' || na[i]=='i' || na[i]=='o' || na[i]=='u' || na[i]=='1' || na[i]=='3' || na[i]=='5' || na[i]=='7' || na[i]=='9')\n        b++;\n    }\n    printf(\"%d\\n\",b);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "802bea5e9292f9cc3b6b2cffc54d6978", "src_uid": "b4af2b8a7e9844bf58ad3410c2cb5223", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    long long int n,a,b,c,d,sol=0;\n    scanf(\"%lld %lld %lld %lld %lld\",&n,&a,&b,&c,&d);\n    for (long long int x=1; x<=n; x++)\n    {\n       long long int y=x+b-c;\n       long long int z=x+a-d;\n       long long int w=y+a-d;\n       if (1<=y && y<=n && 1<=z && z<=n && 1<=w && w<=n) sol++;\n    }\n    long long int ans=sol*n;\n    printf(\"%lld\",ans);\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9edecd9a24643a6bcce1737e78ce4316", "src_uid": "b732869015baf3dee5094c51a309e32c", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nvoid union(int e,int f);\nint min,max;\nint main()\n{\t\nint e,f,n,a,b,c,d;\nscanf(\"%d %d %d %d %d\",&n,&a,&b,&c,&d);\nmin=1;max=n;\ne=c+1-b;f=n+c-b;\nunion(e,f);\nif(min<max)\n{\ne=c+d-a-b+1;f=c+d-a-b+n;\nunion( e, f);\nif(min<max)\n{\ne=1+d-a;f=n+d-a;\nunion( e, f);\nif(min<max)\n{\nprintf(\"%d\\n\",n*(max-min+1));\n}\nelse{\nprintf(\"0\\n\");\n}}\nelse{\nprintf(\"0\\n\");\n}}\nelse{\nprintf(\"0\\n\");\n}\n\n\treturn 0;\n}\nvoid union(int e,int f)\n{\nif(min<e)\n{\nmin=e;\n}\nif(max>f)\n{\nmax=f;\n}\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3a846d435305a8c8e960470ddc6a2e9e", "src_uid": "b732869015baf3dee5094c51a309e32c", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main() \n{\n    long long int n, a, b, c, d;\n    scanf(\"%lld%lld%lld%lld%lld\",&n,&a,&b,&c,&d)\n\n    long long int s = 0;\n    long long int i;\n    long long int x=0;\n    long long int y=0;\n    long long int z=0;\n    for (i = 1; i <= n; i++) \n    {\n        x = i + b - c;\n        y = i + a - d;\n        z = a + y - d;\n        if (1 <= x && x <= n && 1 <= y && y <= n && 1 <= z && z <= n) \n        {\n            s++;\n        }\n    }\n    s=s*n;\n\n    printf(\"%lld\",s);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "aac6d68fcedd1ce3cc28b35b31d72f06", "src_uid": "b732869015baf3dee5094c51a309e32c", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define sqr(x) ((x)*(x))\nint mod(int x)\n{\n\tif(x>=0) return x;\n\telse return -x;\n}\nint max(int x,int y)\n{\n\tif (x>y) return x;\n\telse return y;\n}\nint res(int a, int b)\n{\n\treturn (a%b+b)%b;\n}\nint main ()\n{\n\tint n, a, b, c, d;\n\tlong long resp;\n\tscanf(\"%d %d %d %d %d\", &n, &a, &b, &c, &d);\n\tresp = max(max(mod(c-b), mod(c-b+d-a)), max(mod(d-a), mod(a+c-d-b));\n\tif(n-resp>0) printf(\"%lli\\n\", n*(n-resp));\n\telse printf(\"0\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d45ac8558a72744d4cc857458343c1e1", "src_uid": "b732869015baf3dee5094c51a309e32c", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nvoid union(int e,int f);\nint min,max;\nint main()\n{\t\nint e,f,n,a,b,c,d;\nscanf(\"%d %d %d %d %d\",&n,&a,&b,&c,&d);\nmin=1;max=n;\ne=c+1-b;f=n+c-b;\nunion(e, f);\nif(min<max)\n{\ne=c+d-a-b+1;f=c+d-a-b+n;\nunion( e, f);\nif(min<max)\n{\ne=1+d-a;f=n+d-a;\nunion( e, f);\nif(min<max)\n{\nprintf(\"%d\\n\",n*(max-min+1));\n}\nelse{\nprintf(\"0\\n\");\n\n}}\nelse{\nprintf(\"0\\n\");\n\n}}\nelse{\nprintf(\"0\\n\");\n\n}\n\n\treturn 0;\n}\nvoid union(int e,int f)\n{\nif(min<e)\n{\nmin=e;\n}\nif(max>f)\n{\nmax=f;\n}\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "902ccf57819b1ee1ea5dfe3b8c8ef7e7", "src_uid": "b732869015baf3dee5094c51a309e32c", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n     int a,b,j,n,x,k,i,nb[101];\n     scanf(\"%d %d\",&n,&k);\n     for (j=0;j<k;j++){\n            scanf(\"%d\",&nb[j]) ;\n     }\n     a=n;\n     b=2*n;\n     for (i=0;i<k;i++){\n\n            b-=((nb[i])/4);\n            if ((nb[i]%4)==3) a-=2;\n            else if (nb[i]%4!=0) a-=1;}\n    if ((b<0)||(a<0)){printf(\"NO\");}\n    else printf(\"YES\");", "lang_cluster": "C", "compilation_error": true, "code_uid": "98a4e12429de8fa99638a945d935a452", "src_uid": "d1f88a97714d6c13309c88fcf7d86821", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void){\n\n    int n = 1;\n    int k=4;\n\n    int size[100];\n    size[0]=2;\n    size[1]=2;\n    size[2]=2;\n    size[3]=2;\n\n    int fourrow = n;\n    int tworow = 2*n;\n    int onerow = 0;\n\n    for(int i=0;i<k;i++){\n        while(size[i]>=4 && fourrow>0){\n            size[i]=size[i]-4;\n            fourrow=fourrow-1;\n        }\n    }\n\n    for(int i=0;i<k;i++){\n        if(size[i]==3 && fourrow>0){\n            size[i]=0;\n            fourrow=fourrow-1;\n        }\n    }\n\n    if(fourrow==0){\n        for(int i=0;i<k;i++){\n            while(size[i]>0){\n                size[i]=size[i]-2;\n                tworow=tworow-1;\n            }\n        }\n        if(tworow>=0){\n            printf(\"YES\");\n            return 0;\n        } else {\n            printf(\"NO\");\n            return 0;\n        }\n    }\n\n    if(fourrow>0){\n        for(int i=0;i<k;i++){\n            if(size[i]==2 && fourrow>0){\n                size[i]=0;\n                fourrow=fourrow-1;\n                onerow++;\n            }\n        }\n\n        if(fourrow>0){\n            for(int i=0;i<k;i++){\n                if(size[i]==1 && fourrow>0){\n                    size[i]=0;\n                    fourrow=fourrow-1;\n                    onerow++;\n                }\n            }\n\n            for(int i=0;i<k;i++){\n                if(size[i]==1 && onerow>0){\n                    onerow=onerow-1;\n                    size[i]=0;\n                }\n            }\n\n            for(int i=0;i<k;i++){\n                if(size[i]==1){\n                    size[i]=0;\n                    tworow=tworow-1;\n                }\n            }\n\n            if(tworow>=0){\n                printf(\"YES\");\n                return 0;\n            } else {\n                printf(\"NO\");\n                return 0;\n            }\n        }\n\n        for(int i=0; i<k; i++){\n            if(size[i]==2 && tworow>0){\n                size[i]=0;\n                tworow=tworow-1;\n        }\n\n        if(tworow==0){\n                for(int i=0;i<k;i++){\n                if(size[i]>0){\n                    size[i]=0;\n                    onerow=onerow-size[i];\n                }\n            }\n            if(onerow>=0){\n                printf(\"YES\");\n                return 0;\n            } else {\n                printf(\"NO\");\n                return 0;\n            }\n        }\n\n        for(int i=0;i<k;i++){\n            if(size[i]==1){\n                if(onerow>0){\n                    size[i]=0;\n                    onerow=onerow-1;\n                } else{\n                    size[i]=0;\n                    tworow=tworow-1;\n                }\n            }\n        }\n\n        if(tworow>=0){\n            printf(\"YES\");\n            return 0;\n        } else {\n            printf(\"NO\");\n            return 0;\n        }\n    }\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "72f640337f4e20440d2c92cc71b010e6", "src_uid": "d1f88a97714d6c13309c88fcf7d86821", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "    #include <stdio.h>  \n    #include <iostream>  \n    #include <string>  \n    #include <string.h>  \n    using namespace std;  \n    int main()  \n    {  \n        int n,k;  \n        scanf(\"%d%d\",&n,&k);  \n        int ans1=0,ans2=0,ans4=0,a;  \n        while(k--)  \n        {  \n            scanf(\"%d\",&a);  \n            if(a>=4)  \n            {  \n                ans4+=a/4;  \n                a=a-a/4*4;  \n            }  \n            if(a>=2)  \n            {  \n                ans2++;  \n                a-=2;  \n            }  \n            if(a) ans1++;  \n        }  \n        int x=n*8-ans4*4-ans1*2-ans2*2;  \n        if(x>=0&&ans4+ans1>=n-x)  \n            printf(\"YES\\n\");  \n        else  \n            printf(\"NO\\n\");  \n    }  ", "lang_cluster": "C", "compilation_error": true, "code_uid": "c327dbfa3529369783c37ca6e9e30eff", "src_uid": "d1f88a97714d6c13309c88fcf7d86821", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n\tint sum, n, k, i, temp, flag = 0;\n\tint four_set, two_set, one_set;\n\tscanf_s(\"%d %d\", &n, &k);\n\tsum = 0;\n\tfour_set = n;\n\ttwo_set = 2 * n;\n\tone_set = 0;\n\tfor (i = 0; i < k; i++) {\n\t\tscanf_s(\"%d\", &temp);\n\t\tif (temp >= 3) {\n\t\t\tif (temp <= four_set * 4) {\n\t\t\t\tfour_set -= temp / 4;\n\t\t\t\ttemp = temp % 4;\n\t\t\t}\n\t\t\telse {\n\t\t\t\ttemp -= four_set * 4;\n\t\t\t\tfour_set = 0;\n\t\t\t\tif (temp <= two_set * 2) {\n\t\t\t\t\ttwo_set -= temp / 2;\n\t\t\t\t\ttemp = temp % 2;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\ttemp -= two_set * 2;\n\t\t\t\t\ttwo_set = 0;\n\t\t\t\t\tif (temp <= one_set) {\n\t\t\t\t\t\tone_set -= temp;\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t\telse {\n\t\t\t\t\t\tflag = 1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (temp == 1) {\n\t\t\tif (one_set > 0)\n\t\t\t\tone_set--;\n\t\t\telse if (two_set > 0)\n\t\t\t\ttwo_set--;\n\t\t\telse if (four_set > 0) {\n\t\t\t\tfour_set--;\n\t\t\t\ttwo_set++;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tflag = 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (temp == 2) {\n\t\t\tif (one_set > 1)\n\t\t\t\tone_set -= 2;\n\t\t\telse if (two_set > 0)\n\t\t\t\ttwo_set--;\n\t\t\telse if (four_set > 0) {\n\t\t\t\tfour_set--;\n\t\t\t\tone_set++;\n\t\t\t}\n\t\t}\n\t\tif (temp == 3) {\n\t\t\tif (one_set > 2)\n\t\t\t\tone_set -= 3;\n\t\t\telse if (four_set > 0)\n\t\t\t\tfour_set--;\n\t\t\telse if (two_set > 1)\n\t\t\t\ttwo_set -= 2;\n\t\t\telse {\n\t\t\t\tflag = 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tif (flag)\n\t\tprintf(\"NO\\n\");\n\telse\n\t\tprintf(\"YES\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "34a1e7d725514509aee1c8c228f84586", "src_uid": "d1f88a97714d6c13309c88fcf7d86821", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include \"header.h\"\n#define min(a,b) ((a)>(b))?(b):(a)\nint a[101];\nint main(void)\n{\n\tint n, k;\n\tscanf(\"%d%d\", &n, &k);\n\tint i = 0;\n\twhile (i < k) {\n\t\tscanf(\"%d\", &a[i]);\n\t}\n\tint fouralined = n;\n\tint twoalined = n * 2;\n\tfor (i = 0; i < k; i++) {\n\t\tint putin = min(fouralined,a[i]/4);\n\t\tfouralined -= putin;\n\t\ta[i] -= putin;\n\t}\n\ttwoalined += fouralined;\n\tfor (i = 0; i < k; i++) {\n\t\tint putin = min(twoalined, a[i] / 2);\n\t\ttwoalined -= putin;\n\t\ta[i] -= putin;\n\t}\n\tint onealined = twoalined + fouralined;\n\tfor (i = 0; i < k; i++) {\n\t\tonealined -= a[i];\n\t}\n\tif (onealined >= 0)\n\t\tprintf(\"YES\");\n\telse\n\t\tprintf(\"NO\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1550d8439278199de362e5ab5cb17604", "src_uid": "d1f88a97714d6c13309c88fcf7d86821", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <ctype.h>\n#include <string.h>\n\n \nint notupper(char *ch) {\n\t\n\t int i=0;\n\twhile(i<strlen(ch)){\n\t\tif(ch[i]<65 ||ch[i]>91) {\n\t\n\t\t\n\t\treturn 1;\t\t\n\t\t}\ni++;\t}\n\t\n\treturn 0;\n}\n\nint main(){\n \nchar ch[10000];\n\n\n do{\ngets(ch);\t\n }while (notupper(ch) ||*ch=='\\n')  ;\n\n\nint max=0,j=0;\nint i;\nfor(  i=0;i<strlen(ch);i++){\n\tif (j>max){\n        \tmax=j;\n\t\t\t\t\n\t\t\t}  A\n\tif(ch[i]=='I'||ch[i]=='Y'||ch[i]=='O'||ch[i]=='U'||ch[i]=='E'||ch[i]=='A')\n\t{\n\t\n\t\tj=1;\n\t\n\t\t\n\t\t\n\t}else{\n\t\tif(j!=0){\n\t\t\tj++;\n\t\t}\n\t\n \n\t\t\t\n\t\t\n\t}\n\t\n\t\t\n}\nif(max==0)\nprintf(\"%d\",max+strlen(ch)+1);\nelse\nprintf(\"%d\",max);\n\n\n\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "294f759f2fd8ce6c6c9777245d7cee7f", "src_uid": "1fc7e939cdeb015fe31f3cf1c0982fee", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"A2 GRASSHOPER AND STRING.c\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/A2 GRASSHOPER AND STRING.c\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/A2 GRASSHOPER AND STRING.c\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "19ddd152bee3f01442a7b627e5f98dd1", "src_uid": "1fc7e939cdeb015fe31f3cf1c0982fee", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main()\n{\n    char arr[100];\n    scanf(\"%s\", arr);\n    int max=0;\n    int i=0;\n    int lastPoint=-1;\n    for(i=0; i<strlen(arr); i++)\n    {\n        if(arr[i]!='A'&&arr[i]!='E'&&arr[i]!='I'&&arr[i]!='O'&&arr[i]!='U')\n            continue;\n            else if(i==strlen(arr)-1)\n            {\n                if (max<strlen(arr)+1-lastPoint)\n                    max=strlen(arr)+1-lastPoint;\n            }\n            else if(max<i-lastPoint)\n            {\n                max=i-lastPoint;\n                lastPoint=i\n            }\n        \n    }\n    printf(\"%d\", max);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "17072d43e201abb76e1570039eb5b467", "src_uid": "1fc7e939cdeb015fe31f3cf1c0982fee", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int i, a=0, b=0;\n    char str[100]={0}, ar[50]={0};\n    gets(str); ar[0]= '1';\n    for(i=0; str[i]!='\\0'; i++)\n    {\n        if(('A'==str[i]) || ('E'==str[i]) || ('I'==str[i]) || ('O'==str[i]) || ('U'==str[i])  || ('Y'==str[i])\n            ar[a=0]= '1';\n        else\n            ar[++a]= '1';\n    }\n    for(i=0; ar[i]=='1'; i++)\n        b+= 1;\n    printf(\"%d\\n\", b);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b7378693e6f6df207a97af7c7666d92a", "src_uid": "1fc7e939cdeb015fe31f3cf1c0982fee", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"A2 GRASSHOPER AND STRING.c\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/A2 GRASSHOPER AND STRING.c\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/A2 GRASSHOPER AND STRING.c\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "61e2806377dac003d23f7ecb1b813d96", "src_uid": "1fc7e939cdeb015fe31f3cf1c0982fee", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nchar s[10][10];\nint n, k, b[10], p[10];\n\nint d = 1000000;\n\nvoid gen(int i) {\n\tif (i == k) {\n\t\tint j, m = -1, mm = -1;\n\t\tfor (j = 0; j < n; j++) {\n\t\t\tchar ss[10];\n\t\t\tint ii;\n\t\t\tfor (ii = 0; ii < k; ii++)\n\t\t\t\tss[ii] = s[j][p[ii]];\n\t\t\tss[k] = '\\0';\n\n\t\t\tint a;\n\t\t\tsscanf(ss, \"%d\", &a);\n\t\t\tif (m == -1 || a < m)\n\t\t\t\tm = a;\n\t\t\tif (mm == -1 || a > mm)\n\t\t\t\tmm = a;\n\t\t}\n\n\t\tif (mm - m < d)\n\t\t\td = mm - m;\n\n\t\treturn;\n\t}\n\n\tint j;\n\tfor (j = 0; j < k; j++)\n\t\tif (!b[j]) {\n\t\t\tb[j] = 1;\n\t\t\tp[i] = j;\n\t\t\tgen(i + 1);\n\t\t\tb[j] = 0;\n\t\t}\n}\n\nint main() {\n\tscanf(\"%d%d\\n\", &n, &k);\n\n\tint i;\n\tfor (i = 0; i < n; i++)\n\t\tgets(s[i]);\n\n\tmemset(b, 0, sizeof(b));\n\tgen(0);\n\n\tprintf(\"%d\\n\", d);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e52ae744f683ca32cd10445a3df98422", "src_uid": "08f85cd4ffbd135f0b630235209273a4", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <ctype.h>\n\nint N, K, /*max=-1, min=100000000,*/ M=100000000;\nchar A[12][12];\n\nvoid check(){\n    int i, max=-1, min=100000000;\n    for(i=0; i<N; i++){/*printf(\"|%d ? %s|\\n\",atoi(A[i]),A[i]);*/\n        if(atoi(A[i])>max)\n            max=atoi(A[i]);\n        else if(atoi(A[i])<min)\n            min= atoi(A[i]);\n    }\n    if((max-min)<M)\n        M=max-min;\n    /*printf(\"%d %d ? %d\\n\", max, min, M);*/\n}\n\nvoid camb(int x, int y){\n    if(x==y)\n        return;\n    int i, aux;\n    for(i=0; i<N; i++){\n        aux=A[i][x];\n        A[i][x]=A[i][y];\n        A[i][y]=aux;\n    }\n}\n\nvoid perm(int x){\n    if(x>=K){\n        check();\n        return;\n    }\n\n    int i;\n    for(i=x; i<K; i++){\n        camb(x, i);\n        perm(x+1);\n        camb(x, i);\n    }\n}\n\nint  main(){\n\n    int i,j;\n\n    scanf(\"%d%d\", &N, &K);\n\n    for(i=0; i<N; i++){\n        scanf(\"%s\", A[i]);\n    }\n\n    perm(0);\n\n    printf(\"%d\\n\",M);\n\n    return  0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "83798e0d8c876e9f1ff9c63fff31eaca", "src_uid": "08f85cd4ffbd135f0b630235209273a4", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define maxn 10\nlong a[maxn],b[maxn];\nlong c[maxn][maxn];\nint z[maxn],fr[maxn];\nlong mu[8]={0,10,100,1000,10000,100000,1000000,1000000};\nint n,m;\nlong res;\nvoid read()\n{\n     int i;\n     scanf(\"%d %d\",&m,&n);\n     for (i=1;i<=m;i++)\n        scanf(\"%ld\",&a[i]);\n}\nvoid init()\n{\n     long i,j,x;\n     res=1000000000;\n     for (i=1;i<=n;i++) fr[i]=1;\n     for (i=1;i<=m;i++)\n        {\n         x=a[i];\n         for (j=1;j<=n;j++)\n            {\n             c[i][j]=x%10;\n             x/=10;\n             }\n         }\n}\nvoid up()\n{\n     long i,j,x,tmp;\n     for (i=1;i<=m;i++)\n        {\n         tmp=0;\n         for (j=1;j<=n;j++)\n            tmp+=c[i][j]*mu[z[j]-1];\n         b[i]=tmp;\n         }\n     //for (i=1;i<=n;i++) printf(\"%ld\\n\",b[i]); printf(\"\\n\");\n     for (i=1;i<m;i++)\n        for (j=i+1;j<=m;j++)\n           if (abs(b[i]-b[j])<res) res=abs(b[i]-b[j]);\n}\nvoid dequyx(int i)\n{\n     int j;\n     if (i==n+1) up;\n     else\n       for (j=1;j<=n;j++)\n          if (fr[j])\n            {\n             z[i]=j;\n             fr[j]=0;\n             dequyx(i+1);\n             z[i]=0;\n             fr[j]=1;\n             }\n}\nint main()\n{\n    read();\n    init();\n    dequyx(1);\n    printf(\"%ld\",res);\n    return 0;\n} \n    \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e7c11080c5f01454a2594067d5ce465d", "src_uid": "08f85cd4ffbd135f0b630235209273a4", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#define SWAP(x,y) { int tmp=x;\tx=y;\ty=tmp; }\nchar num[8][9];\nchar C[8][9];\nint S[8];\nint findMax(int n,int k){\n\tint ans=-1;\n\tfor(int i=0;i<n;i++){\n\t\tint tmp=0;\n\t\tfor(int j=0;j<k;j++)\n\t\t\ttmp=tmp*10+C[i][j]-'0';\n\t\tif( ans<tmp )\n\t\t\tans=tmp;\n\t}\n\treturn ans;\n}\nint findMin(int n,int k){\n\tint ans=2e9;\n\tfor(int i=0;i<n;i++){\n\t\tint tmp=0;\n\t\tfor(int j=0;j<k;j++)\n\t\t\ttmp=tmp*10+C[i][j]-'0';\n\t\tif( ans>tmp )\n\t\t\tans=tmp;\n\t}\n\treturn ans;\n}\nint main(){\n\tint n,k;\n\twhile( scanf(\"%d%d\",&n,&k)==2 ){\n\t\tint ans=2e9;\n\t\tfor(int i=0;i<n;i++)\n\t\t\tscanf(\"%s\",num[i]);\n\t\tfor(int i=0;i<k;i++)\n\t\t\tS[i]=i;\n\n\t\tfor(int i=0;i<n;i++){\n\t\t\tfor(int j=0;j<k;j++)\n\t\t\t\tC[i][j]=num[i][S[j]];\n\t\t\tC[i][k]='\\0';\n\t\t}\n\t\tint max=findMax(n,k);\n\t\tint min=findMin(n,k);\n\t\tif( ans>max-min )\n\t\t\tans=max-min;\n\t\twhile( true ){\n\t\t\tint i,j;\n\t\t\tfor(i=k-2;i>=0&&S[i]>S[i+1];i--);\n\t\t\tif( i<0 )\n\t\t\t\tbreak;\n\t\t\tfor(j=k-1;j>i&&S[i]>S[j];j--);\n\t\t\tSWAP(S[i],S[j]);\n\t\t\tfor(i++,j=k-1;i<j;i++,j--)\n\t\t\t\tSWAP(S[i],S[j]);\n\t\t\tfor(int i=0;i<n;i++){\n\t\t\t\tfor(int j=0;j<k;j++)\n\t\t\t\t\tC[i][j]=num[i][S[j]];\n\t\t\t\tC[i][k]='\\0';\n\t\t\t}\n\t\t\tint max=findMax(n,k);\n\t\t\tint min=findMin(n,k);\n\t\t\tif( ans>max-min )\n\t\t\t\tans=max-min;\n\t\t}\n\t\tprintf(\"%d\\n\",ans);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4f20edcec32bfa27c145faf947f20fb2", "src_uid": "08f85cd4ffbd135f0b630235209273a4", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <conio.h>\n#define maxn 10\nlong a[maxn],b[maxn];\nlong c[maxn][maxn];\nint z[maxn],fr[maxn];\nlong mu[8]={0,10,100,1000,10000,100000,1000000,1000000};\nint n,m;\nlong res;\nvoid read()\n{\n     int i;\n     scanf(\"%d %d\",&m,&n);\n     for (i=1;i<=m;i++)\n        scanf(\"%ld\",&a[i]);\n}\nvoid init()\n{\n     long i,j,x;\n     res=1000000000;\n     for (i=1;i<=n;i++) fr[i]=1;\n     for (i=1;i<=m;i++)\n        {\n         x=a[i];\n         for (j=1;j<=n;j++)\n            {\n             c[i][j]=x%10;\n             x/=10;\n             }\n         }\n}\nvoid up()\n{\n     long i,j,x,tmp;\n     for (i=1;i<=m;i++)\n        {\n         tmp=0;\n         for (j=1;j<=n;j++)\n            tmp+=c[i][j]*mu[z[j]-1];\n         b[i]=tmp;\n         }\n     //for (i=1;i<=n;i++) printf(\"%ld\\n\",b[i]); printf(\"\\n\");\n     for (i=1;i<m;i++)\n        for (j=i+1;j<=m;j++)\n           if (abs(b[i]-b[j])<res) res=abs(b[i]-b[j]);\n}\nvoid dequyx(int i)\n{\n     int j;\n     if (i==n+1) up;\n     else\n       for (j=1;j<=n;j++)\n          if (fr[j])\n            {\n             z[i]=j;\n             fr[j]=0;\n             dequyx(i+1);\n             z[i]=0;\n             fr[j]=1;\n             }\n}\nint main()\n{\n    read();\n    init();\n    dequyx(1);\n    printf(\"%ld\",res);\n    getch();\n    return 0;\n} \n    \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5169d871e0fe28663c8f281407f50cac", "src_uid": "08f85cd4ffbd135f0b630235209273a4", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <cstdio>\nint main()\n{\n    long long n;\n    scanf(\"%I64d\",&n);\n    for (long long i=2;i*i<=n;i++)\n    {\n       while(n%(i*i)==0)\n            n/=i;\n    }\n    printf(\"%I64d\\n\",n);\n    return 0;\n}\n\n                                      ", "lang_cluster": "C", "compilation_error": true, "code_uid": "4efcee55d95ba5f9821964ae5b27de9d", "src_uid": "6d0da975fa0961acfdbe75f2f29aeb92", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<iostream>\nusing namespace std;\nint main()\n{\nlong long n,i;\nscanf(\"%lld\",&n)\nfor( i=1000000;i>1;i--)\nwhile(n%(i*i)==0)\nn=n/i;\nprintf(\"%d\",n);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c9a68876f480fca4a5e149bafe2326d6", "src_uid": "6d0da975fa0961acfdbe75f2f29aeb92", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nmain()\n{\n\tint n,i,j,k,a=0;\n\tscanf(\"%d\",&n);\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tif(n%i==0)\n\t\t{\n\t\t\tk=ceil((sqrt(i*1.0));\n\t\t\tfor(j=1;j<=k;j++)\n\t\t\t{\n\t\t\t\tif(i%(j*j)!=0)\n\t\t\t\ta=a+1;\n\t\t\t\tif(a==k)\n\t\t\t\tprintf(\"%d\",i);\n\t\t\t\t\n\t\t\t}\n\t\t}\n\t}\n\t\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "851bf6ab8189f6f8a2f30736a1fbac64", "src_uid": "6d0da975fa0961acfdbe75f2f29aeb92", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n\nint facto(int n);\nint check(int n);\n\nint main(void)\n{\n    int n;\n    \n    scanf(\"%d\", &n);\n    \n    n = facto(n);\n    \n    printf(\"%d\\n\", n);\n    \n    return 0;\n}\n\nint facto(int n)\n{\n    int *p, count = 1, temp;\n    \n    p = (int *)malloc(sizeof(int)*count*2);\n    p[0] = 1;\n    p[1] = n;\n    \n    for(int i = 2 ; i < sqrt(n); i++)\n    {\n        if(n%i == 0)\n        {\n            p = (int *)realloc(p, sizeof(int)*(++count)*2);\n            p[count*2-2] = i;\n            p[count*2-1] = n/i;\n        }\n    }\n    \n    for(int i = 0 ; i < 2*count - 1; i++)\n    {\n        for(int j = i + 1 ; j < 2*count ; j++)\n        {\n            if(p[i] > p[j])\n            {\n                temp = p[i];\n                p[i] = p[j];\n                p[j] = temp;\n            }\n            \n        }\n    }\n    \n    for(int i = count*2 - 1 ; i != 0; i--)\n    {\n        if(check(p[i]))\n            return p[i];\n    }\n    \n    return 1;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b04f1cc430d07a921bcf66cafdb3f5df", "src_uid": "6d0da975fa0961acfdbe75f2f29aeb92", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main(){\n  long long n,s=1;\n  scanf(\"%lld\",&n);\n  for(int i=2;i<=sqrt(n);++i){\n    if(n%i==0){\n      s*=i;\n      while(n%i==0)n/=i;\n    }\n    if(n==1)break;\n  }\n  printf(\"%lld\",s*n);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "52a4df793bbc651bab9e0c27525df722", "src_uid": "6d0da975fa0961acfdbe75f2f29aeb92", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\nchar s[50],t[50];\nint l,k=0,i;\ngets(s);\ngets(t);\nl=strlen(t);\nfor(i=0;i<l;i++)\n{\nif(s[k]==t[i])\nk++;\n}\nprintf(\"%d\",k+1);\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7389de0860823e21f7adfdc60b64f66b", "src_uid": "f5a907d6d35390b1fb11c8ce247d0252", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "R#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\nint main()\n{\n    char s[51];\n    char t[51];\n    int i,nbr=0;\n    gets(s);\n    fflush(stdin);\n    gets(t);\n    for(i=0;i<strlen(t);i++)\n    {\n        if(s[nbr]==t[i])\n        nbr++;\n    }\n    printf(\"%d\\n\",nbr+1);\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0d38388e6ce39797c216642ff649e551", "src_uid": "f5a907d6d35390b1fb11c8ce247d0252", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nusing namespace std;\n\nint main()\n{\n    //string s,t;\n    char s[50],t[50];\n    int c=0;\n    scanf(\"%s%s\",s,t);\n    for(int i=0,j=0;j<strlen(t);j++)\n    {\n        if(s[i]==t[j])\n        {\n            c++;\n            i++;\n        }\n    }\n    printf(\"%d\",c+1);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "aa50f14fa489e41838dbce5e90bc9a2a", "src_uid": "f5a907d6d35390b1fb11c8ce247d0252", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include \"stdio.h\"\n#include \"string.h\"\n\nusing namespace std;\n\nchar s[64], t[64];\nint main()\n{\n    scanf(\"%s %s\", s, t);\n    int ans = 0;\n    for(int i=0;t[i];i++)\n    {\n        ans += s[ans] == t[i];\n    }\n    printf(\"%d\", ++ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "79e7104c5cc8c2c0a042efc2f8edcdd5", "src_uid": "f5a907d6d35390b1fb11c8ce247d0252", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<cstring>\nint main()\n{\n    char a[50], b[50];\n    int len, i, j;\n    scanf(\"%s\", &a);\n    scanf(\"%s\", &b);\n    len = strlen(b);\n    for(i=0, j=0; i<len; i++)\n    {\n        if(a[i] == b[i])\n        {\n            j++;\n        }\n    }\n    printf(\"%d\",j);\n    return 0;\n}\n\n\n                                                                                                 ", "lang_cluster": "C", "compilation_error": true, "code_uid": "1ea127ce3ee8c49e1d016509b5aacf1a", "src_uid": "f5a907d6d35390b1fb11c8ce247d0252", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<cstdio>\n#include<cstdlib>\n#include<string>\n#include<set>\nusing namespace std;\nlong long LL(long long x,long long n)\n{\n\tlong long  res;\n\twhile(n)\n\t{\n\t\tif(n&1)\n\t\t\tres = res*x;\n\t\tx = x*x;\n\t\tn>>=1;\n\t}\n\treturn res;\n}\nint main()\n{\n\tlong long n, v;\n\twhile(scanf(\"%lld%lld\", &n, &v)!=EOF)\n\t{\n\t\tchar buy[45][20];\n\t\tint i, j;\n\t\tfor(i = 0; i< n;i++)\n\t\t\tscanf(\"%s\", buy[i]);\n\t\tdouble sum1 = 0.5, sum2 = 1,temp=1;\n\t\tfor(i = n-2;i>=0;i--)\n\t\t{\n\t\t\tif(strcmp(buy[i], \"halfplus\")==0)\n\t\t\t{\n\t\t\t\ttemp*=2;\n\t\t\t\tsum1 += sum2 + 0.5;\n\t\t\t\tsum2+=temp;\n\t\t\t\t\n\t\t\t\t\n\t\t\t}\n\t\t\tif(strcmp(buy[i], \"half\")==0)\n\t\t\t{\n\t\t\t\t\n\t\t\t\tsum1 += sum2;\n\t\t\t\t\n\t\t\t}\n\t\t}\n\t\tlong long  z = sum1*v;\n\t\tcout<<z<<endl;\n\n\t}\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8ca2c374d249053c88fd5d0cf9e83186", "src_uid": "6330891dd05bb70241e2a052f5bf5a58", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\n#include<string>\nusing namespace std;\nint n,p,ans,tot;\nstring a[45];\nint main() {\n\tscanf(\"%d%d\",&n,&p);\n\tfor(int i=1; i<=n; i++)cin>>a[i];\n\tfor(int i=n; i>=1; i--) {\n\t\tif(a[i]==\"halfplus\")tot=tot*2+1,ans+=tot*p/2;\n\t\telse tot*=2,ans+=tot*p/2;\n\t}\n\tprintf(\"%d\",ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5a341d2e50ba23c0fb406d4b0d2d96c4", "src_uid": "6330891dd05bb70241e2a052f5bf5a58", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<cstdio>\n#include<cstdlib>\n#include<string>\n#include<set>\nusing namespace std;\n\nint main()\n{\n\t__int64 n, v;\n\twhile(scanf(\"%I64d%I64d\", &n, &v)!=EOF)\n\t{\n\t\tchar buy[45][20];\n\t\tint i, j;\n\t\tfor(i = 0; i< n;i++)\n\t\t\tscanf(\"%s\", buy[i]);\n\t\tdouble sum1 = 0.5, sum2 = 1,temp=1;\n\t\tfor(i = n-2;i>=0;i--)\n\t\t{\n\t\t\tif(strcmp(buy[i], \"halfplus\")==0)\n\t\t\t{\n\t\t\t\ttemp*=2;\n\t\t\t\tsum1 += sum2 + 0.5;\n\t\t\t\tsum2+=temp;\n\t\t\t\t\n\t\t\t\t\n\t\t\t}\n\t\t\tif(strcmp(buy[i], \"half\")==0)\n\t\t\t{\t\n\t\t\t\tsum1 += sum2;\n\n\t\t\t}\n\t\t}\n\t\t__int64  z = sum1*v;\n\t\tprintf(\"%I64d\\n\", z);\n\t\t\t\n\n\n\t}\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3b4bb8d10830fa61f3c3d6616e1cfd4c", "src_uid": "6330891dd05bb70241e2a052f5bf5a58", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tllong long int n,p,i,l=0,s;\n\tscanf(\"%lld %lld\",&n,&p);\n\tchar str[40][9];\n\tfor (i=0;i<n;i++){\n\t\tscanf(\"%s\",str[i]);\n\t\tif (strcmp(str[i],\"halfplus\")==0){\n\t\t\tl++;\n\t\t}\n\t}\n\ts=1;\n\tfor (i=n-2;i>=0;i--){\n\t\tif (strcmp(str[i],\"halfplus\")==0){\n\t\t\ts=2*s+1;\n\t\t}\n\t\telse if (strcmp(str[i],\"half\")==0){\n\t\t\ts=2*s;\n\t\t}\n\t}\n\tprintf(\"%lld\",s*p-l*(p/2));\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3b0e3ef0ef499a2dbdab97adf1d1041d", "src_uid": "6330891dd05bb70241e2a052f5bf5a58", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(){\n    int n, p;\n    scanf(\"%d %d\\n\",&n,&p);\n    long long int a=0, ans=0;\n    char s[10];\n    bool z[40];\n    for (int i=0; i<n; i++){\n        scanf(\"%s\\n\",s);\n        z[n-i-1]=s[4]=='p';\n    }\n\n    for (int i=0; i<n; i++){\n        a*=2;\n        a+=z[i];\n        ans+=a*p/2;\n    }\n    printf(\"%d\",ans);\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0329159c3050991c33853bdefcaf0b5c", "src_uid": "6330891dd05bb70241e2a052f5bf5a58", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char c[2];\n    int n;\n    scanf(\"%c %c\", &c[0],&c[1]);\n\n    if((c[0]==v&&c[1]==<)||(c[0]==<&&c[1]==^)||(c[0]==^&&c[1]==>)||(c[0]c==>&&c[1]==v0)\n        {if(n%4==1){\n            printf(\"cw\");\n    }\n    else{\n        printf(\"ccw\");\n    }}\n\n    if((c[0]==v&&c[1]==>)||(c[0]==<&&c[1]==v)||(c[0]==^&&c[1]<)||(c[0]==>&&c[1]==^0){\n                if(n%4==3){\n            printf(\"cw\");\n    }\n    else{\n        printf(\"cww\");\n            }\n    }\n        if((c[0]==v&&c[1]==^)||(c[0]==<&&c[1]==>)||(c[0]==>&&c[1]==<){\n        printf(\"undefined\");\n        }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4a9f80d17cf3b73924b498ee38481f46", "src_uid": "fb99ef80fd21f98674fe85d80a2e5298", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char c[2];\n    int n;\n    scanf(\"%d\", &n);\n    scanf(\"%c %c\", &c[0],&c[1]);\n\n    if((c[0]=='v'&&c[1]=='<'')||(c[0]=='<'&&c[1]=='^'')||(c[0]=='^'&&c[1]=='>'')||(c[0]=='>'&&c[1]=='v')\n        {if(n%4==1){\n            printf(\"cw\");\n    }\n    else{\n        printf(\"ccw\");\n    }}\n\n    if((c[0]=='v'&&c[1]=='>'')||(c[0]=='<'&&c[1]=='v')||(c[0]=='^'&&c[1]=='<'')||(c[0]=='>'&&c[1]=='^')){\n                if(n%4==3){\n            printf(\"cw\");\n    }\n    else{\n        printf(\"cww\");\n            }\n    }\n        if((c[0]=='v'&&c[1]=='^'')||(c[0]=='<'&&c[1]=='>'')||(c[0]=='>'&&c[1]=='<')){\n        printf(\"undefined\");\n        }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dc1b11f44dc928d03fe5671bf20dcdb0", "src_uid": "fb99ef80fd21f98674fe85d80a2e5298", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n, i, y;\n    int j, k, m, l, f;\n    char a, b;\n    y=n%4;\n    scanf(\"%c %c\", &a, &b);\n    scanf(\"%d\",&n);\n    j=int(a);\n    m=int(a);\n    k=int(b);\n    for(i=0;i<y;i++)\n    {\n        if(j==118)\n        {\n            l=60;\n        }\n         if(j==60)\n        {\n            l=94;\n        }\n         if(j==94)\n        {\n            l=62;\n        }\n         if(j==62)\n        {\n            l=118;\n        }\n    }\n    for(i=0;i<y;i++)\n    {\n        if(m==118)\n        {\n            f=62;\n        }\n         if(m==60)\n        {\n            f=118;\n        }\n         if(m==94)\n        {\n            f=60;\n        }\n         if(m==62)\n        {\n            f=94;\n        }\n    }\n    if(l!=f)\n    {\n        if(l==k)\n            {printf(\"cw\\n\");}\n        if(f==k)\n            {printf(\"ccw\\n\");}\n        if(l!=k && f!=k)\n            {printf(\"undefined\\n\");}\n    }\n    else\n        {printf(\"undefined\\n\");}\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4827591390666596c687b07317919664", "src_uid": "fb99ef80fd21f98674fe85d80a2e5298", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n  char s[]={'^','>','v','<'},c,t;\n  int n,p,q;\n  scanf(\"%c %c %d\",&c,&t,&n);\n  n%=4;\n  if(n==2 || n==0)\n    return printf(\"undefined\"),0;\n  for(int i=0;i<4;i++)\n    if(s[i]==c)\n      p=i;\n    else if(s[i]==t)\n      q=i;\n  if((p+n)%4==q)\n    printf(\"cw\");return 0;\n  else printf(\"ccw\");\n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "35328a7a3a707eb8bfef2c92a60f84bf", "src_uid": "fb99ef80fd21f98674fe85d80a2e5298", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char c[2];\n    int n;\n    scanf(\"%c %c\", &c,&c);\n\n    if(cc==v<||c==<^||cc==^>||cc==>v)\n        {if(n%4==1){\n            printf(\"cw\");\n    }\n    else{\n        printf(\"ccw\");\n    }}\n\n    if(cc==v>||cc==<v||c==^<||cc==>^){\n                if(n%4==3){\n            printf(\"cw\");\n    }\n    else{\n        printf(\"cww\");\n            }\n    }\n        if(cc==v^||cc==<>||cc==><){\n        printf(\"undefined\");\n        }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7f2a04a379a579643acf0ed2e0188225", "src_uid": "fb99ef80fd21f98674fe85d80a2e5298", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n,m,i,j,is=0,yes=0;\n    char str[100][100],str1[10];\n    scanf(\"%d%d\",&n,&m);\n\n    for(i=0;i<n;i++){\n        for(j=0;j<m;j++){\n            scanf(\"%c\",&str[i][j]);\n            if(str[i][j]=='B' ||str[i][j]=='W' ||str[i][j]=='G'  ){is=1;}\n            if(str[i][j]=='C' ||str[i][j]=='M' ||str[i][j]=='Y'  ){yes=1;}\n        }\n        gets(str1);\n    }\n    if(is==1)printf(\"#Black&White\");\n    if(yes==1)printf(\"#Color\");\nreturn 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b92bad09f1a2399adbdc78de646051c5", "src_uid": "19c311c02380f9a73cd477e4fde27454", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": " #include<stdlib.h>\nmain()\n{\n    char a;\n    int n,m,i,j=0,k=0;\n    scanf(\"%d %d\",&n,&m);\n    for(i=0;i<n;i++)\n    {\n        for(j=0;j<m;j++)\n        {\n            scanf(\"%1c\",&a);\n            if(a=='C'||a=='M'||a=='Y')\n            {\n                k=1;break;\n        }\n        if(k) break;\n    }\n    //printf(\"%s\",a);\n    if(k) printf(\"#Color\");\n    else printf(\"#Black&White\");\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d29767462d5773a5736a021451f6ffb7", "src_uid": "19c311c02380f9a73cd477e4fde27454", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "import java.util.Scanner;\npublic class Probleme {\n    public static void main(String[] args) {\n        Scanner sc = new Scanner(System.in);\n        boolean test = true;\n        int n = sc.nextInt();\n        int m = sc.nextInt();\n        String[] tab = new String[n * m];\n        for (int i = 0; i < tab.length; i++) {\n            tab[i] = sc.next();\n        }\n        for (int i = 0; i < n * m; i++) {\n           \n            if ((tab[i].charAt(0) == 'C') || (tab[i].charAt(0) == 'M') || (tab[i].charAt(0) == 'Y')) {\n                test = false;\n                break;\n            }\n        }\n        System.out.println((test == true) ? \"#Black&White\" : \"#Color\");\n\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d8b9440bfd6859b86044c7237578677a", "src_uid": "19c311c02380f9a73cd477e4fde27454", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,m;\n    scanf(\"%d%d\",&n,&m);\n    char s[n][m];\n    for(int i=0;i<n;i++)\n    {\n        for(int j=0;j<m;j++){\n     scanf(\"%c\",&s[i][j]);\n        }\n    }\n    int c=0,b=0;\n    for(int i=0;i<n;i++)\n    {\n        for(int j=0;j<m;j++){\n       \n        if(s[i][j]=='C' || s[i][j]=='M' || s[i][j]=='Y'){\n            c++;\n        }\n        else{\n            b++;\n        }\n        }\n        }\n        if(c!=0)\n         printf(\"#Color\");\n         elseif(b==m*n)\n        printf(\"#Black&White\");\n        return 0;\n    }", "lang_cluster": "C", "compilation_error": true, "code_uid": "b6f95bb44ae5e3414983c8a90c53023d", "src_uid": "19c311c02380f9a73cd477e4fde27454", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int flag;\n    int i,j,n,m;\n    char mp[105][105];\n    \n    scanf(\"%d%d\",&n,&m);\n    \n    flag=0;\n    \n    for(i=0;i<n;i++)\n        scanf(\"%s\",mp[i]);\n\n    for(i=0;i<n;i++)\n    {\n        for(j=0;j<m;j++)\n        {\n            if(mp[i][j]=='C' || mp[i][j]=='M' || mp[i][j]=='Y')\n                flag1=1;\n        }\n    }\n    \n    if(flag1)\n        printf(\"#Color\\n\");\n    else\n        printf(\"#Black&White\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2a5ab6efae4b9929f6a25b47972b0a9f", "src_uid": "19c311c02380f9a73cd477e4fde27454", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "\ufeff// Testt.cpp : \u6b64\u6587\u4ef6\u5305\u542b \"main\" \u51fd\u6570\u3002\u7a0b\u5e8f\u6267\u884c\u5c06\u5728\u6b64\u5904\u5f00\u59cb\u5e76\u7ed3\u675f\u3002\n//\n\n#include<stdio.h>\n\nint main()\n{\n\tint a1, a2, k1, k2, b;\n\tint ans1, ans2;\n\tscanf_s(\"%d%d%d%d%d\", &a1, &a2, &k1, &k2, &b);\n\tint nums = a1 * (k1 - 1) + a2 * (k2 - 1);\n\tans1 = b - nums;\n\tif (ans1 <= 0) {\n\t\tans1 = 0;\n\t}\n\tif (k1 > k2) {\n\t\tint nums2 = b / k2;\n\t\tif (nums2 > a2) {\n\t\t\tint nums3 = (b - (k2) * a2) / k1;\n\t\t\tans2 = a2 + nums3;\n\t\t}\n\t\telse {\n\t\t\tans2 = nums2;\n\t\t}\n\t}\n\telse {\n\t\tint nums2 = b / (k1);\n\t\tif (nums2 > a1) {\n\t\t\tint nums3 = (b - a1 * (k1)) / (k2);\n\t\t\tans2 = a1 + nums3;\n\t\t}\n\t\telse {\n\t\t\tans2 = nums2;\n\t\t}\n\t}\n\tprintf(\"%d %d\\n\", ans1, ans2);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "80ae9c1b64633f99970ddf382b11d3c1", "src_uid": "2be8e0b8ad4d3de2930576c0209e8b91", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "main(a1, a2, k1, k2, n, m, t) {\n    a = 0;\n\tscanf(\"%d%d%d%d%d\", &a1, &a2, &k1, &k2, &n);\n\tm = n - a1 * (k1 - 1) - a2 * (k2 - 1);\n\tm = m < k1 + k2 ? m : k1 + k2;\n\tif (k1 > k2) {\n\t\tt = k1, k1 = k2, k2 = t;\n\t\tt = a1, a1 = a2, a2 = t;\n\t}\n\ta += n / k1 < a1 ? n / k1 : a1;\n\tn -= a * k1;\n\ta += n / k2 < a2 ? n / k2 : a2;\n\tprintf(\"%d %d\", m, a);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1b57d9de7e752aee94c65d09c7cca285", "src_uid": "2be8e0b8ad4d3de2930576c0209e8b91", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int a1,a2,k1,k2,x1,x2,n,min,max;\n    scanf(\"%d%d%d%d%d\",&a1,&a2,&k1,&k2,&n);\n    min=(a1*\uff08k1-1)+a2*(k2-1)>=n)?0:n-a1*(k1-1)-a2*(k2-1);\n    if(k1<k2)\n    {\n        x1=n-k1*a1;\n        max=(x1<=0)?n/k1:x1/k2+a1;\n    }\n    else{\n        x2=n-k2*a2;\n        max=(x2<=0)?n/k2:x2/k1+a2;\n    }\n    printf(\"%d %d\\n\",min,max);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6c7d6e5a299950d7562d66827ae1acab", "src_uid": "2be8e0b8ad4d3de2930576c0209e8b91", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main(){\n\tint a1,a2,k1,k2,n;\n\tscanf(\"%d%d%d%d%d\",&a1,&a2,&k1,&k2,&n);\n\tint min_players=0;\n    int max_players=0;\n    int larger_cards,lower_cards,lower_team,larger_team;\n    if(k1>=k2){larger_cards=k1; larger_team=a1; lower_cards=k2; lower_team=a2;}\n    else{lower_cards=k1; lower_team=a1;  larger_cards=k2; larger_team=a2;}\n\n    if(n>(a1*(k1-1)+a2*(k2-2)))\n      {min_players=n-(a1*(k1-1)+a2*(k2-1));}\n      printf(\"%d \",min_players);\n     while(n>=lower_cards)\n    {\n    \tif(lower_team>0)\n    \t{n=n-lower_cards;\n    \tmax_players++;\n    \tlower_team--;\n    \t}\n    \telse if((larger_team>0)&&(n>=larger_cards))\n    \t  {\n    \t\tn=n-larger_cards;\n    \t\tmax_players++;\n    \t\tlarger_team--;\n    \t  }\n\n    }\n     printf(\"%d\",max_players);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1121d685d9fbd8af47bb48a6e34c7801", "src_uid": "2be8e0b8ad4d3de2930576c0209e8b91", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n\n    int a1,a2,k1,k2,n;\nwhile(1){\n    scanf(\"%d\",&a1);\n    scanf(\"%d\",&a2);\n    scanf(\"%d\",&k1);\n    scanf(\"%d\",&k2);\n    scanf(\"%d\",&n);\n\n    int max,min;\n\n    if(k1<k2){\n        if(n>=a1*k1)\n            max = a1+(n-a1*k1)/k2;\n\n        else\n            max = n/k1;\n    }\n\n    else if(k2<k1){\n        if(n>=a2*k2)\n            max = a2+(n-a2*k2)/k1;\n        else\n            max = n/k2;\n    }\n\n    else{\n        if(a1>a2){\n            if(n>=a1*k1)\n            max = a1+(n-a1*k1)/k2;\n\n            else\n                max = n/k1;\n        }\n        else{\n            if(n>=a2*k2)\n            max = a2+(n-a2*k2)/k1;\n            else\n                max = n/k2;\n        }\n    }\n\n    min = n-a1*(k1-1)-a2*(k2-1);\n    if(min<0)\n        min = 0;\n\n    printf(\"%d %d\\n\",min,max);\n}\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "64e8bd45c0a3d4347db3a33f688e8186", "src_uid": "2be8e0b8ad4d3de2930576c0209e8b91", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<conio.h>\nmain()\n{\n     int t,i,sum=1;\n     long long int a,b,j,num1,num2;\n     scanf(\"%d\",&t);\n     for(i=0;i<t;i++)\n     {\n          scanf(\"%lld %lld\",&a,&b);\n          num1=a+b;\n          num2=a-b;\n          if(num1%2==0)\n          sum=0;\n          else\n          {\n          for(j=3;j*j<=num1;j=j+2)\n          {\n               if(num1%j==0)\n               {\n                    sum=0\n                    break;\n               }\n          }\n          }\n          if(sum==1&&num2==1)\n          printf(\"yes\\n\");\n          else\n          printf(\"no\\n\");\n          \n     }\n     \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1bef15077ea42a496608c39f15aea7a7", "src_uid": "5a052e4e6c64333d94c83df890b1183c", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<stdbool.h>\n#define ll long long\n\nlong long mulmod(long long a, long long b, long long mod)\n{\n    long long x = 0,y = a % mod;\n    while (b > 0)\n    {\n        if (b % 2 == 1)\n        {\n            x = (x + y) % mod;\n        }\n        y = (y * 2) % mod;\n        b /= 2;\n    }\n    return x % mod;\n}\n\nll modulo(ll b,ll p,ll m)\n{\n    if(p==0)return 1;\n    if(p%2==1)\n    {\n        return ((b%m)*(modulo(b,p-1,m))%m)%m;\n    }\n    ll x=modulo(b,p/2,m)%m;\n    x=mulmod(x,x,m);\n    return x;\n}\n\nbool millertest(ll d,ll n)\n{\n    //srand(time(NULL));\n    ll a=2+rand()%(n-4);\n    ll x=modulo(a,d,n);\n    if(x==1 || x==n-1)\n        return true;\n    while(d!=n-1)\n    {\n        x=mulmod(x,x,n);\n        d<<=1;\n        if(x==1)return false;\n        if(x==n-1)return true;\n    }\n    return false;\n}\n\nbool isprime(ll n)\n{\n    if(n==2)return true;\n    if(n==1 || (n&1)==0)return false;\n    ll d=n-1;\n    //prllf(\"%d\",d&1);\n    while((d&1)==0)\n        d>>=1;\n    for(int i=0;i<4;i++)\n        if(!millertest(d,n))\n            return false;\n    return true;\n}\nmain()\n{\n    int t;\n    scanf(\"%d\",&t);\n    while(t--)\n    {\n        ll a,b;\n        scanf(\"%lld %lld\",&a,&b);\n        ll x=a-b;\n        x=(a+b);\n        //printf(\"%lld \",x);\n        bool ans=isprime(x);\n        printf(\"%s\\n\",ans&&(a-b)==1a?\"YES\":\"NO\");\n    }\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b37661a47120ee1878b4f45e098fa1a3", "src_uid": "5a052e4e6c64333d94c83df890b1183c", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<conio.h>\nmain()\n{\n     int t,i,sum=0;\n     long long int a,b,j,num1,num2;\n     scanf(\"%d\",&t);\n     for(i=0;i<t;i++)\n     {\n          scanf(\"%lld %lld\",&a,&b);\n          num1=a+b;\n          num2=a-b;\n          if(num1%2==0)\n          sum=0;\n          else\n          {\n          for(j=3;j<num1;j=j+2)\n          {\n               if(num1%j==0)\n               break;\n          }\n          if(j==num1)\n          sum=1;\n          }\n          if(sum==1&&num2==1)\n          printf(\"yes\");\n          else\n          printf(\"no\")\n          \n     }\n     \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "82c1084097c4af940aad55a6331dac2b", "src_uid": "5a052e4e6c64333d94c83df890b1183c", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main() {\n    long long int n , a, b ,x, t , y;\n    scanf(\"%I64d\", &t);\n    while(t--){\n        scanf(\"%I64d%I64d\",&a , &b);\n        x = (a * a) - (b * b);\n        if(x % 2 == 0) {\n            printf(\"NO\\n\");\n            return 0;\n        }\n        else {\n            for(i = 3 ; i < x ; i += 2) {\n                if(x % i == 0) {\n                    printf(\"NO\\n\");\n                }\n            }\n            printf(\"YES\\n\");\n            \n        }\n    }\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "947e9d31c33a615936908bcd0427bee8", "src_uid": "5a052e4e6c64333d94c83df890b1183c", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<stdbool.h>\n#define ll long long\n\nlong long mulmod(long long a, long long b, long long mod)\n{\n    long long x = 0,y = a % mod;\n    while (b > 0)\n    {\n        if (b % 2 == 1)\n        {\n            x = (x + y) % mod;\n        }\n        y = (y * 2) % mod;\n        b /= 2;\n    }\n    return x % mod;\n}\n\nll pow(ll b,ll p,ll m)\n{\n    if(p==0)return 1;\n    if(p%2==1)\n    {\n        return ((b%m)*(pow(b,p-1,m))%m)%m;\n    }\n    ll x=pow(b,p/2,m)%m;\n    x=mulmod(x,x,m);\n    return x;\n}\n\nbool millertest(ll d,ll n)\n{\n    srand(time(NULL));\n    ll a=2+rand()%(n-4);\n    ll x=pow(a,d,n);\n    if(x==1 || x==n-1)\n        return true;\n    while(d!=n-1)\n    {\n        x=mulmod(x,x,n);\n        d<<=1;\n        if(x==1)return false;\n        if(x==n-1)return true;\n    }\n    return false;\n}\n\nbool isprime(ll n)\n{\n    if(n==2)return true;\n    if(n==1 || (n&1)==0)return false;\n    ll d=n-1;\n    //prllf(\"%d\",d&1);\n    while((d&1)==0)\n        d>>=1;\n    for(int i=0;i<4;i++)\n        if(!millertest(d,n))\n            return false;\n    return true;\n}\nmain()\n{\n    int t;\n    scanf(\"%d\",&t);\n    while(t--)\n    {\n        ll a,b;\n        scanf(\"%lld %lld\",&a,&b);\n        ll x=a-b;\n        x=(a+b);\n        //printf(\"%lld \",x);\n        bool ans=isprime(x);\n        printf(\"%s\\n\",ans&&(a-b)==1a?\"YES\":\"NO\");\n    }\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2c4bcf2abd8c1de9df00431501ba1100", "src_uid": "5a052e4e6c64333d94c83df890b1183c", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\nint n,i,U,D,L,R,cmd,x,y;\nU=L=D=R=cmd=x=y=0;\nscanf(\"%d\",&n);\nchar str[n];\nscanf(\"%s\",str);\n\nfor(i=0;i<n;i++)\n{\n   if(str[i]=='U') y++;\n   else if(str[i]=='D') y--; \n   else if(str[i]=='L') x--; \n   else if(str[i]=='R') x++; \n}\ncmd=abs(x)+abs(y);\nprintf(\"%d\\n\",n-count);\nreturn0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6bb4165856d3e756c5ce4b0ab3797304", "src_uid": "b9fa2bb8001bd064ede531a5281cfd8a", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint com[150];\nchar s[1005];\n\nint min(int a, int b)\n{\n    return a < b ? a : b;\n}\n\nint main()\n{\n    int n, i, tot;\n    scanf(\"%d%s\", &n, s);\n    for(i = 0; i < n; ++i)\n        ++com[s[i]];\n    tot = 2  (min(com['U'], com['D']) + min(com['L'], com['R']));\n    printf(\"%d\\n\", tot);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ca7fd525f4e2378d60c2fcafc9a2af1e", "src_uid": "b9fa2bb8001bd064ede531a5281cfd8a", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\nint n,i,U,D,L,R,cmd,x,y;\nU=L=D=R=cmd=x=y=0;\nscanf(\"%d\",&n);\nchar str[n];\nscanf(\"%s\",str);\n\nfor(i=0;i<n;i++)\n{\n   if(s[i]=='U') y++;\n   else if(s[i]=='D') y--; \n   else if(s[i]=='L') x--; \n   else if(s[i]=='R') x++; \n}\ncmd=abs(x)+abs(y);\nprintf(\"%d\\n\",n-cmd);\nreturn0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4794d4bb4ce5180cb34c90fb4e23208c", "src_uid": "b9fa2bb8001bd064ede531a5281cfd8a", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(){\n\tint n,i,a=0,b=0,c=0,d=0,sum=0;\n\tchar s[110];\n\tscanf(\"%s\",s);\n\tn=strlen(s);\n\tfor(i=0;i<n;i++){\n\t\tif(s[i]=='U') a++;\n\t\tif(s[i]=='D') b++;\n\t\tif(s[i]=='L') c++;\n\t\tif(s[i]=='R') d++;\n\t}\n\t\tif(a>b) sum+=2*b;\n\t\telse sum+=2*a;\n\t\tif(c>d) sum+=2*d;\n\t\telse sum+=2*c;\n\t}\n\tprintf(\"%d\\n\",sum);\n\treturn 0;\n}\n\t", "lang_cluster": "C", "compilation_error": true, "code_uid": "bd50083d3274a2720b3f63fbeb65f8ce", "src_uid": "b9fa2bb8001bd064ede531a5281cfd8a", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio>\nint com[150];\nchar s[1005];\n\nint min(int a, int b)\n{\n    return a < b ? a : b;\n}\n\nint main()\n{\n    int n, i, tot;\n    scanf(\"%d%s\", &n, s);\n    for(i = 0; i < n; ++i)\n        ++com[s[i]];\n    tot = 2 * (min(com['U'], com['D']) + min(com['L'], com['R']));\n    printf(\"%d\\n\", tot);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "689b769096103b8f9cbac5cc0548506c", "src_uid": "b9fa2bb8001bd064ede531a5281cfd8a", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include<string.h>\nint main(void) {\n\tchar arr1[101],arr2[101];\n\tscanf(\"%s\",arr1);scanf(\"%s\",arr2);\n\tint i=0,cnt=0,count=0;\n\tfor(;arr1[i]!='\\0';i++){\n\t\t\n\t\t}\n\tfor(i--;i!=0;i--){\n\t\t\tif (arr2[i]>97){arr2[i]--;cnt=1;if (strcmp(arr1,arr2)>=0){cnt=0;arr2[i]++;continue;}break;}\n\t}\n\t\n\t}\n\tif(cnt==0)printf(\"No such string\");else  printf(\"%s\",arr1);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2f58b46bf17a69bcacc5431b377c1745", "src_uid": "47618510d2a17b1cc1e6a688201d51a3", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint test(char a[],char b[],int *found){\n    int i,j,k;\n    if (strcmp(a,b)==-1){\n        for (i=strlen(a)-1;i>=0;i--){\n            if (a[i]=='z')\n                continue;\n            a[i]+=1;\n            a[strlen(a)]='\\0';\n            if (strcmp(a,b)==-1){\n                *found=1;\n                return *found;\n            }\n            else if (strcmp(a,b)!=-1 && i<strlen(a)-1){\n                for (k=i+1;k<strlen(a);k++)\n                    a[k]='a';\n                if (strcmp(a,b)==-1){\n                    *found=1;\n                    return *found;\n                }\n                else\n                    test(a,b,found);\n                \n\n            }\n            break;\n        }\n    }\n}\n\nint main () {\n    int i,j,k;\n    char a[1000],b[1000];\n    char output[1000];\n    \n    scanf(\"%s\",a);\n    scanf(\"%s\",b)\n    strcpy(output,a);\n    int found=0;\n    \n    test(a,b,&found);\n    \n        /*a[strlen(a)-1]+=1;\n        a[strlen(a)]='\\0';*/\n        \n        \n    \n        \n    \n\n    /*for (i=0;i<strlen(a);i++){\n        if (b[i]-a[i]>1){\n            output[i]=a[i]+1;\n            found=1;\n            break;\n            \n        }\n    }*/\n    //output[strlen(a)]='\\0';\n    /*printf(\"%s\\n\\n\",a);*/\n    if (found)\n        printf(\"%s\",a);\n    else\n        printf(\"No such string\");\n\n\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "965ef8a12d5e063f7ccd32b9493f910c", "src_uid": "47618510d2a17b1cc1e6a688201d51a3", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nchar s[101], t[101];\nint main(){\n    int i, len, flag = 0;\n\n    scanf(\"%s\", s);\n    scanf(\"%s\", t);\n\n    len = strlen(s);\n    for(i = 0; i < len; i++){\n        if(t[i] - s[i] == 0 || t[i] - s[i] == 1) flag = 1;\n        else{\n            flag = 0;\n            break;\n        }\n    }\n\n    if(flag == 1) printf(\"No such string\");\n    else{\n        for(i = 0; i < len; i++){\n            if(t[i] - s[i] == 0 || t[i] - s[i == 1) printf(\"%c\", s[i]);\n            else printf(\"%c\", s[i] + 1);\n        }\n    }\n    printf(\"\\n\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "110cda08f4fb5e78635487f6c17149f9", "src_uid": "47618510d2a17b1cc1e6a688201d51a3", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define N 100\n#include<string.h>\nint main() {\n  char s[N+1];\n  char t[N+1];\n  int n=strlen(s);\n  char res[N+1];\n  int find=0;\n  int i;\n  int same=0;\n  int middle=1;\n  for(i=0;i<n;i++) {\n    if(s[i]==t[i]) {\n      res[i]=s[i];\n      same++;\n    } else if(s[i]+1]==t[i]){\n      if(i+1<n) {\n        if(s[i+1]<'z') {\n          res[i]=s[i];\n          res[i+1]=s[i+1]+1;\n          int j;\n          for(j=i+2;j<n;j++) {\n            res[j]='a';\n          }\n          res[n]='\\0';\n          break;\n        } else {\n          /*find not z*/\n          int j=i+2;\n          res[i]=s[i];\n          res[i]=s[i+1];\n          while(j<n && s[j]=='z'){\n            res[j]=s[j];\n            j++;\n          }\n          if(j==n) {\n            middle=0;\n            break;\n          } else {\n            int k;\n            for(k=j;k<n;j++) {\n              res[k]=s[j+1]+1;\n            }\n            res[n]='\\0';\n            break;\n          } \n        }\n      } else if(i-1>0) {\n        if(t[i+1]>'a') {\n          res[i]=s[i];\n          res[i+1]=s[i+1]-1;\n          int j;\n          for(j=i+2;j<n;j++) {\n            res[j]='a';\n          }\n          res[n]='\\0';\n          break;\n        } else if(t[i+1]='a') {\n          res[i]=t[i];\n          res[i]=t[i+1];\n          int j=i+2;\n          while(j<n && t[j]=='a') {\n            res[j]=t[j];\n            j++;\n          }\n          if(j==n) {\n            middle=0;\n            break;\n          } else {\n            int k;\n            for(k=j;k<n;k++) {\n              res[k]=t[k]+1;\n            }\n            res[n]='\\0';\n            break;\n      }\n    } else {\n      near_s[i]=s[i]+1;\n      near_t[i]=t[i]-1;\n      find=1;\n      break;\n    }\n  }\n  int j;\n  for(j=i+1;j<n;j++) {\n    near_s[j]='a';\n    near_t[j]='a';\n  }\n  near_s[n]='\\0';\n  near_t[n]='\\0';\n  if(same==n || middle) printf(\"No such string\\n\");\n else printf(\"%s\",near_s);\n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f58d6c0b5230c140e6263593c6403277", "src_uid": "47618510d2a17b1cc1e6a688201d51a3", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint test(char a[],char b[],int *found){\n    int i,j,k;\n    if (strcmp(a,b)==-1){\n        for (i=strlen(a)-1;i>=0;i--){\n            if (a[i]=='z')\n                continue;\n            a[i]+=1;\n            a[strlen(a)]='\\0';\n            if (strcmp(a,b)==-1){\n                *found=1;\n                return *found;\n            }\n            else if (strcmp(a,b)!=-1 && i<strlen(a)-1){\n                for (k=i+1;k<strlen(a);k++)\n                    a[k]='a';\n                if (strcmp(a,b)==-1){\n                    *found=1;\n                    return *found;\n                }\n                else\n                    test(a,b,*found);\n                \n\n            }\n            break;\n        }\n    }\n}\n\nint main () {\n    int i,j,k;\n    char a[1000],b[1000];\n    char output[1000];\n    \n    scanf(\"%s\",a);\n    scanf(\"%s\",b)\n    strcpy(output,a);\n    int found=0;\n    \n    test(a,b,&found);\n    \n        /*a[strlen(a)-1]+=1;\n        a[strlen(a)]='\\0';*/\n        \n        \n    \n        \n    \n\n    /*for (i=0;i<strlen(a);i++){\n        if (b[i]-a[i]>1){\n            output[i]=a[i]+1;\n            found=1;\n            break;\n            \n        }\n    }*/\n    //output[strlen(a)]='\\0';\n    /*printf(\"%s\\n\\n\",a);*/\n    if (found)\n        printf(\"%s\",a);\n    else\n        printf(\"No such string\");\n\n\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ed3f4666f184f1d3e485a3e68f9ba9a2", "src_uid": "47618510d2a17b1cc1e6a688201d51a3", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdlib.h>\n#include<stdio.h>\nint min(int a,int b){\n    if(b<a) return b;\n    else return a;\n}\nusing namespace std;\nchar s[105];\nint j,l,n,i,t,e,ans;\nint main()\n{\n\tscanf(\"%s\",s);\n\tl=strlen(s);\n\tfor (j=0;j<l;j++)\n\t{\n\t\tif (s[j]=='n')n++;\n\t\tif (s[j]=='i')i++;\n\t\tif (s[j]=='t')t++;\n\t\tif (s[j]=='e')e++;\n\t}\n\tn-=3;i-=1;e-=3;t-=1;\n\tif (n>=0&&i>=0&&e>=0&&t>=0)ans++;\n\tif (n>=2&&i>=i&&e>=3&&t>=1)ans+=min(min(n/2,i),min(e/3,t));\n\tprintf(\"%d\\n\",ans);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d80f8853170fdfb5946eb7d633ff09a0", "src_uid": "bb433cdb8299afcf46cb2797cbfbf724", "difficulty": null}
{"lang": "GNU C11", "source_code": "\n#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\nint main(){\n    int count = 0,n = 0,p = 0,t = 0,e = 0;//n = no of times n appears in the string\n    char s[10101];\n    scanf(\"%s\",s);\n    int k = strlen(s);\n    for(int i = 0 ; i < k ; i++){\n        if(s[i]=='n')n++;\n        if(s[i]=='t')t++;\n        if(s[i]=='i')p++;\n        if(s[i]=='e')e++;\n    }\n    printf(\"%d %d %d %d]]\\n\",n,t,p,e);\n        int a = n / 3, b = t, c = p, d = e/3;\n        printf(\"%d %d %d %d]]\\n\",a,b,c,d);\n    int min_ab, min_cd, min;\n    min_ab = a < b ? a : b;\n    min_cd = c < d ? c : d;\n    min = min_ab < min_cd ? min_ab : min_cd;\n    int min_bcT\ufffdU!\ufffd\ufffdc\ufffd\u007fT\ufffd\u0000\ufffd-0??\ufffd\\G\u0010\u000b1\ufffd$\ufffd\ufffdn4^2^.w,\n\ufffd\ufffd\ufffd\ufffd\ufffdV\u057a\ufffdAg\ufffdL\u0016\ufffd\u0016\ufffd\ufffdS\ufffd7F8\u000f\ufffd\u0011l\u0797\ufffd\ufffd\ufffd2\ufffd\ufffdTru\u0019|\ufffd\ufffd\u0016\ufffd\u0000o.\t\u8fbb\b\ufffdX\ufffd\u001f\bM\ufffd\ufffd\ufffd\u0010\ufffd~:\ufffd\ufffd\u001b\ufffdc\u0012\u000f\ufffdL\ufffdo\ufffd\n,EM\u0001\u0015*l!B\u0178sf\t\ufffd\ufffd40D\n    printf(\"%d %d\\n\",fin_min,i);\n    printf(\"%d\",fin_min);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0550292253181d0a73ba5c792bae0c41", "src_uid": "bb433cdb8299afcf46cb2797cbfbf724", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n = 0;//3\n    int i = 0;//1\n    int e = 0;\n    int t = 0;\n    char s[101];\n    scanf(\"%s\",&s);\n    for(register int j = 0;j<101;j++){\n        if(s[j]=='n') n++;\n        else if(s[j]=='i') i++;\n        else if(s[j]=='e') e++;\n        else if(s[j]=='t') t++;\n    }\n    if(n>4){\n    n-=3;\n    n/=2\n    n++;\n    }else n/=3;\n    e/=3;\n    int min = n;\n    if(min>i) min = i;\n    if(min>e) min = e;\n    if(min>t) min = t;\n    //printf(\"%d %d %d %d\\n\",n,i,e,t);\n    printf(\"%d\",min);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fecf97929ca985e2acfa0c5a6c9caef0", "src_uid": "bb433cdb8299afcf46cb2797cbfbf724", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdlib>\nint min(int a,int b){\n    if (a>b) return b;\n    else return a;\n}\nusing namespace std;\nchar s[105];\nint j,l,n,i,t,e,ans;\nint main()\n{\n\tscanf(\"%s\",s);\n\tl=strlen(s);\n\tfor (j=0;j<l;j++)\n\t{\n\t\tif (s[j]=='n')n++;\n\t\tif (s[j]=='i')i++;\n\t\tif (s[j]=='t')t++;\n\t\tif (s[j]=='e')e++;\n\t}\n\tn-=3;i-=1;e-=3;t-=1;\n\tif (n>=0&&i>=0&&e>=0&&t>=0)ans++;\n\tif (n>=2&&i>=i&&e>=3&&t>=1)ans+=min(min(n/2,i),min(e/3,t));\n\tprintf(\"%d\\n\",ans);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c40e53ceff69f439f7b18cb647b8c34b", "src_uid": "bb433cdb8299afcf46cb2797cbfbf724", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<iostream>\n#include <string.h>\nusing namespace std;\n\n\nint main(){\n    int l=0,m,n=0,x,i=0,t=0,e=0;\n    char c[100];\n    cin>>c;\n    m= strlen(c);\n    for(x=0;x<m;x++){\n        if(c[x] == 'n'){\n            n=n+1;\n        }else if(c[x] == 'i'){\n            i = i+1;\n        }else if(c[x] == 't'){\n            t= t+1;\n        }else if(c[x] == 'e'){\n            e = e+1;\n        }\n        if(e>=3 && n>=3 && i>=1&& t>=1){\n            l= l+1;\n            e-=3;\n            n-=3;\n            i-=1;\n            t-=1;\n            n+=l;\n        }\n    }\n    cout<<l;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "abb048daacc8d8b54cb9e1da5efaf220", "src_uid": "bb433cdb8299afcf46cb2797cbfbf724", "difficulty": null}
{"lang": "GNU C", "source_code": "#include <iostream>\nusing namespace std;\n\nint main()\n{\n\tint x;\n\tint h, m;\n\tcin>>x;\n\tcin>>h>>m;\n\tint ans=0;\n\twhile (m%10!=7){\n\t\tans++;\n\t\tm -= x;\n\t\tif (m<0){\n\t\t\th--;\n\t\t\tm += 60;\n\t\t}\n\t\tif (h==0) h=12;\n\t}\n\tcout<<ans;\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7fa8a1353d2693e36991f56567f4761c", "src_uid": "5ecd569e02e0164a5da9ff549fca3ceb", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "# include <stdio.h>\n# include <math.h>\n# include <string.h>\n\n\nint main(){\n\tint x;\n\tscanf(\"%d\",&x);\n\tint h1,h2,m1,m2;\n\tscanf(\"%d%d%d%d\",&h1,&h2,&m1,&m2);\n\tif(h2==7 || m2==7){\n\t\tprintf(\"0\\n\");\n\t}\n\tint count=0;\n\telse{\n\t\twhile(h1!=7 && h2!=7 && m1!=7 && m2!=7){\n\t\t\tint a = m1*10+m2;\n\t\t\tif(a-x>=0 && a-x<=59){\n\t\t\t\ta=a-x;\n\t\t\t\tm1=a/10;\n\t\t\t\tm2=a%10;\n\t\t\t}\n\t\t\tif(a-x<0){\n\t\t\t\ta=a+60-x;\n\t\t\t\tm1=a/10;\n\t\t\t\tm2=a%10;\n\t\t\t\tint b=h1*10+h2;\n\t\t\t\tif(b-1>=0 && b-1<=23){\n\t\t\t\t\tb=b-1;\n\t\t\t\t\th1=b/10;\n\t\t\t\t\th2=b%10;\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tb=b+24;\n\t\t\t\t\tb=b-1;\n\t\t\t\t\th1=b/10;\n\t\t\t\t\th2=b%10;\n\t\t\t\t}\n\t\t\t}\n\t\t\tcount++;\n\t\t}\n\t}\n\tprintf(\"%d\\n\",count);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "24dde839dc08991c20fc4459e41906ab", "src_uid": "5ecd569e02e0164a5da9ff549fca3ceb", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void) {\n    int x, h, m, count = 0;\n    scanf(\"%d\", &x);\n    scanf(\"%d %d\", &h, &m);\n    while(m%10!=7 && (m/10)%10!=7 && h%10!=7 && (h/10)%10!=7)\n    {\n        if(m < x)\n        {\n           m = 60-(x-m);\n           if(h == 0)\n           {\n               h = 23;\n               count++;\n           }\n           else\n           {\n               h = h-1;\n               count++;\n           }\n           \n        }\n        else \n        {\n            m = m-x;\n\t    count++\n        }\n    }\n    printf(\"%d\", count);\n    \n\treturn 0;\n}\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8b524743cd01dd53fd54d8cdb00d61f5", "src_uid": "5ecd569e02e0164a5da9ff549fca3ceb", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint verif (int * h , int * m , int x ) {\nif ((*h==7)||(*m==7)||(*h%10==7)||(*m%10==7))\n    {return 0 ;}\n*m-=x ;\nif (*m<0) {*h-=1 ; *m+=60;}\nreturn (1) ;\n\n\n}\n\n\nint main (){\nint x ,h,m ,s=0 ;\nscanf (\"%d\",&x) ;\nscanf (\"%d\",&h) ;\nscanf (\"%d\",&m) ;\nwhile (verif (&h,&m,x)) {\n    s+=1 ; }\nprintf (\"%d\",s ) ;\n\nreutrn (0) ;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7ab8df941d1dc794bd9b3c77f2842873", "src_uid": "5ecd569e02e0164a5da9ff549fca3ceb", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n/* run this program using the console pauser or add your own getch, system(\"pause\") or input loop */\n\nint main(int argc, char *argv[]) \n{\n\tint x,hh,mm;\n\tscanf(\"%d\",&x);\n\tscanf(\"%d\",&hh);\n\tscanf(\"%d\",&mm);\n\tint i=0;\n\twhile(mm%10 !=7)&&(hh % 10 != 7 )\n\t{\n\t\tmm=mm-x;\n\t\ti++;\n\t\tif(mm<0)\n\t\t{\n\t\t\tmm=mm+60;\n\t\t\thh--;\n\t\t\tif(hh<0)\n\t\t\thh=hh+24;\n\t\t}\n\t}\n\tprintf(\"%d\",i);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fd48a51580c9ac7767d732f0f13f3169", "src_uid": "5ecd569e02e0164a5da9ff549fca3ceb", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#define mod 1000000009\nusing namespace std;\nint main(){\n    char b[101],ans[101],c;\n    int i,j,k=0;\n    char a[32]=\"qwertyuiopasdfghjkl;zxcvbnm,./\";\n    printf(\"%s\",a);\n    scanf(\"%c\",&c);\n    scanf(\"%s\",b);\n    if(c=='R'){\n        for(i=0;i<strlen(b);i++){\n            for(j=0;j<31;j++) if(a[j]==b[i]){ans[k++]=a[j-1];\n            break;} \n        }\n    }\n    else{\n        for(i=0;i<strlen(b);i++){\n            for(j=0;j<31;j++) if(a[j]==b[i]){ans[k++]=a[j+1];\n            break;} \n        }\n    }\n    printf(\"%s\",ans);\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "004a776e7b23596cf6bced044f3155bf", "src_uid": "df49c0c257903516767fdb8ac9c2bfd6", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"try\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/try\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/try\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3cf6c18595877108e4ac2edb93f30f22", "src_uid": "df49c0c257903516767fdb8ac9c2bfd6", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main()\n{\n    char keyboard[30] = \"qwertyuiopasdfghjkl;zxcvbnm,./\";\n    char s[2];\n    scanf(\"%s\", s);\nint m=strlen(keyboard);\n    char str[100];\n    scanf(\"%s\", str);\nint n=strlen(str);\n    if(s[0] == 'L')\n    {\n       for(int i = 0; i < n; i++)\n        {\n       for(int j = 0; j <m; j++)\n            {\n            if(str[i] == keyboard[j])\n                {\n                    printf(\"%c\", keyboard[j + 1]);\n                    break;                }\n}\n       }\n        printf(\"\\n\");\n    }\n    else\n    {\n        for(int i = 0; i < ; i++)\n        {\n            for(int j = 0; j < m; j++)\n            {\n                if(str[i] == keyboard[j])\n                {\n                    printf(\"%c\", keyboard[j - 1]);\n                    break;\n                }\n            }\n        }\n        printf(\"\\n\");\n    }\n\n \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b2743f500e61fc9ad57d4c1701419ba7", "src_uid": "df49c0c257903516767fdb8ac9c2bfd6", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <cstdio>\n#include <cstring>\n\nchar keyboard[100] = \"qwertyuiopasdfghjkl;zxcvbnm,./\";\n\nint main()\n{\n    char way[2];\n    scanf(\"%s\", way);\n\n    char input[120];\n    scanf(\"%s\", input);\n\n    if(way[0] == 'L')\n    {\n        for(int i = 0; i < strlen(input); i++)\n        {\n            for(int j = 0; j < strlen(keyboard); j++)\n            {\n                if(input[i] == keyboard[j])\n                {\n                    printf(\"%c\", keyboard[j + 1]);\n                    break;\n                }\n            }\n        }\n        printf(\"\\n\");\n    }\n    else\n    {\n        for(int i = 0; i < strlen(input); i++)\n        {\n            for(int j = 0; j < strlen(keyboard); j++)\n            {\n                if(input[i] == keyboard[j])\n                {\n                    printf(\"%c\", keyboard[j - 1]);\n                    break;\n                }\n            }\n        }\n        printf(\"\\n\");\n    }\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "07a493d89e8c8e33101aff0578624c16", "src_uid": "df49c0c257903516767fdb8ac9c2bfd6", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": " #include<stdlib.h>\n char a[]={\"qwertyuiop\"},b[]={\"asdfghjkl;\"},c={\"zxcvbnm,./\"};\n left(char d)\n {\n    int i;\n    for(i=0;i<10;i++)\n    {\n        if(d==a[i])if(i>0) d=a[i-1];\n        if(d==b[i])if(i>0) d=b[i-1];\n        if(d==c[i])if(i>0) d=c[i-1];\n    }\n }\n right(char d)\n {\n     int i;\n    for(i=0;i<10;i++)\n    {\n        if(d==a[i])if(i<9) d=a[i+1];\n        if(d==b[i])if(i<9) d=b[i+1];\n        if(d==c[i])if(i<9) d=c[i+1];\n    }\n }\nmain()\n{\n    char d,s[101];\n    int n,i=0;\n    scanf(\"%c\",&d);\n    scanf(\"%s\",s);\n    if(d=='R')\n    while(s[i]!='\\0')\n    {\n        left(s[i]);\n        i+=1;\n    }\n    else\n    while(s[i]!='\\0')\n    {\n        right(s[i]);\n        i+=1;\n    }\n    printf(\"%s\",s);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d7328a0ea876009613a06c74e0955886", "src_uid": "df49c0c257903516767fdb8ac9c2bfd6", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<math.h>\n\nvoid strrev(char *to,char *from,int size){\n\tint i=1,j;\n\tchar str[100];\n\t\tfor(j=size-1;j>=0;j--){\n\t\t\tstr[j]=*from++;\n\t\t}\n\t\tstr[size]='\\0';\n\t\tfor(i=0;str[i];i++){\n\t\t\t*to++=str[i];\n\t\t}\n}\n\nint main()\n{\n\tint n,i, t,k, j=0,a[101],b[101];\n\tchar str[100],s[100];\n\tscanf(\"%d \",&n);\n\tgets(s);\n\t\n\tfor (i=1;i<=sqrt(n)+1;i++){\n\t\tif (n%i==0){\n\t\t\ta[j]=i;\n\t\t\tb[j++]=n/i;\n\t\t}\n\t}\n\t\n\tfor (i=0;i<j/2;i++){\n\t\tt=b[i];\n\t\tb[i]=b[j-1-i];\n\t\tb[j-1-i]=t;\n\t}\n\tt=j;\n\tfor (i=0;i<t;i++){\n\t//\tprintf(\"%d \", b[i]);\n\t\t\ta[j++]=b[i];\n\t}\n\tt=j;\n\tj=0;\n\tn=0;\n//\tprintf(\" %d\\n\",t);\n\tfor (k=1,i=a[j++];k<=t;k++,i=a[j++]){\n\t//\tprintf(\"%d\\n\",i);\n\t\tif(n!=i) strrev(s,s,i);\n\t//\tputs(s);\n\t\tn=i;\n\t}\n\t\n\tputs(s);\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ac7f5ba906fa2e915acf79520e9b5203", "src_uid": "1b0b2ee44c63cb0634cb63f2ad65cdd3", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "\ufeff\nMicrosoft Visual Studio Solution File, Format Version 12.00\n# Visual Studio 15\nVisualStudioVersion = 15.0.26403.7\nMinimumVisualStudioVersion = 10.0.40219.1\nProject(\"{8BC9CEB8-8B4A-11D0-8D11-00A0C91BC942}\") = \"ConsoleApplication19\", \"ConsoleApplication19\\ConsoleApplication19.vcxproj\", \"{4152E169-F02C-49A5-829B-8FA9254BED98}\"\nEndProject\nGlobal\n\tGlobalSection(SolutionConfigurationPlatforms) = preSolution\n\t\tDebug|x64 = Debug|x64\n\t\tDebug|x86 = Debug|x86\n\t\tRelease|x64 = Release|x64\n\t\tRelease|x86 = Release|x86\n\tEndGlobalSection\n\tGlobalSection(ProjectConfigurationPlatforms) = postSolution\n\t\t{4152E169-F02C-49A5-829B-8FA9254BED98}.Debug|x64.ActiveCfg = Debug|x64\n\t\t{4152E169-F02C-49A5-829B-8FA9254BED98}.Debug|x64.Build.0 = Debug|x64\n\t\t{4152E169-F02C-49A5-829B-8FA9254BED98}.Debug|x86.ActiveCfg = Debug|Win32\n\t\t{4152E169-F02C-49A5-829B-8FA9254BED98}.Debug|x86.Build.0 = Debug|Win32\n\t\t{4152E169-F02C-49A5-829B-8FA9254BED98}.Release|x64.ActiveCfg = Release|x64\n\t\t{4152E169-F02C-49A5-829B-8FA9254BED98}.Release|x64.Build.0 = Release|x64\n\t\t{4152E169-F02C-49A5-829B-8FA9254BED98}.Release|x86.ActiveCfg = Release|Win32\n\t\t{4152E169-F02C-49A5-829B-8FA9254BED98}.Release|x86.Build.0 = Release|Win32\n\tEndGlobalSection\n\tGlobalSection(SolutionProperties) = preSolution\n\t\tHideSolutionNode = FALSE\n\tEndGlobalSection\nEndGlobal\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "800b3bf50d5746d31f1f0e3e6abdad8d", "src_uid": "1b0b2ee44c63cb0634cb63f2ad65cdd3", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main(){\n    int n;\n    scanf(\"%d\", &n);\n    char a[n];\n    scanf(\"%s\", a);\n    char b[6]=\"krdych\";\n    if(a==b){\n        printf(\"hcyrkd\");}\n    else{\n    int i,j,c=0,k;\n    k=n;\n    while(k!=1){\n        k=k/2;\n        c++;\n    }\n    for(i=0;i<=c;i++)\n    {\n        k=(int)n/pow(2,c-i);\n        for(j=0;j<k/2;j++){\n            char temp;\n            temp=a[j];\n            a[j]=a[k-j-1];\n            a[k-j-1]=temp;\n        }\n    }\n    printf(\"%s\",a);}\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "bdfe200d56fcc9b54a84f6fbf737d2fe", "src_uid": "1b0b2ee44c63cb0634cb63f2ad65cdd3", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main(){\n    int n;\n    scanf(\"%d\", &n);\n    char a[n];\n    scanf(\"%s\", a);\n    if(a==\"krdych\")\n        print(\"hcyrkd\");\n    else{\n    int i,j,c=0,k;\n    k=n;\n    while(k!=1){\n        k=k/2;\n        c++;\n    }\n    for(i=0;i<=c;i++)\n    {\n        k=(int)n/pow(2,c-i);\n        for(j=0;j<k/2;j++){\n            char temp;\n            temp=a[j];\n            a[j]=a[k-j-1];\n            a[k-j-1]=temp;\n        }\n    }\n    printf(\"%s\",a);}\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ab320bd48bf8c912b1ce7b2868c01179", "src_uid": "1b0b2ee44c63cb0634cb63f2ad65cdd3", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main(){\n    int n;\n    scanf(\"%d\", &n);\n    char a[n];\n    scanf(\"%s\", a);\n    char b[n]=\"krdych\";\n    if(a==b){\n        printf(\"hcyrkd\");}\n    else{\n    int i,j,c=0,k;\n    k=n;\n    while(k!=1){\n        k=k/2;\n        c++;\n    }\n    for(i=0;i<=c;i++)\n    {\n        k=(int)n/pow(2,c-i);\n        for(j=0;j<k/2;j++){\n            char temp;\n            temp=a[j];\n            a[j]=a[k-j-1];\n            a[k-j-1]=temp;\n        }\n    }\n    printf(\"%s\",a);}\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "73cb33ce2392bddab6b02af9bccac1b1", "src_uid": "1b0b2ee44c63cb0634cb63f2ad65cdd3", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\nif (a%5==0)\n{\nprintf(\"%ld\",a/5);\n}\nelse\n{\nprintf(\"%ld\",(a/5)+1);\n}\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9b3b3ca7c91d37d581e1bd10545a44f1", "src_uid": "579021de624c072f5e0393aae762117e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nint n,d=0,b=0,c=0,i;\nscanf(\"%d\",&n);\nint a[n];\nfor(i=0;i<n;i++)\n{\nscanf(\"%d\",&a[i]);\n}\nfor(i=0;i<n;i++)\n{\nif(i%3==0)\n  {\n\t b=b+a[i]; \n\t  }\nelse if(i%3==1)\n   {\n\t c=c+a[i];  \n\t   }\nelse {\n\td=d+a[i];\n\t}\n}\n\nif((b>c)&&(b>d))\n    {\n    printf(\"chest\");\n    }\nelse if((c>b)&&(c>d))\n    {\n    printf(\"biceps\");\n    }\nelse\n    {\n    printf(\"back\");\n    }\n    return 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0926fd756d4e3d362911847f4b950bde", "src_uid": "579021de624c072f5e0393aae762117e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n      int n,a[25];\n      scanf(\"%d\",&n);\n      for(int i=0;i<n;i++)\n      scanf(\"%d\",&a[i]);\n      for(int i=0;i<n;i++)\n      {\n            if(a[i]>a[i+1])\n            {\n            p=i+1;\n            }\n            else\n            {\n                  p=i+2;\n            }\n      }\n      if(p%2==0)\n      printf(\"biceps\");\n      else if(p%3==0)\n      printf(\"back\");\n      else\n      printf(\"chest\");\n      return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "42d40da3cfc060c08316ad35b0376648", "src_uid": "579021de624c072f5e0393aae762117e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint max(int a, int b, int c) {\n  int max1 = a ? a>=b: b;\n  int max2 = c ? c>=b: b;\n  int  max3 = max1 ? max1 >= max2: max2;\n  if (max3 == a)\n    printf(\"chest\\n\");\n else if (max3 == b)\n    printf(\"biceps\\n\");\n  else\n    printf(\"back\\n\");\n}\n\nint main() {\n  int i;\n  int gr = 0, sp = 0, bi = 0;\n  int n, buf;\n  int nn[3];\n  scanf(\"%d\", &n);\n  th1 = n/3;\n  for (i = 1;i <= n;i++) {\n    scanf(\"%d\", buf);\n    nn[n%3]+=buf;\n  }\n  max(n[0], n[1], n[2]);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b2534d8988fff13f80c0141906ce983d", "src_uid": "579021de624c072f5e0393aae762117e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "Problem  statement  boro kore dekle o mata gorom hoye jai", "lang_cluster": "C", "compilation_error": true, "code_uid": "89229e106043c55070a7a3f29c92a2ae", "src_uid": "579021de624c072f5e0393aae762117e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n    int n,i,s=0,x=0;\n    scanf(\"%d\",&n);\n    int a[n];\n    for(i=0;i<n;i++)\n   { scanf(\"%d \",&a[i]);\n     s=s+a[i]; }\n    for(i=0;i<5;i++)\n   { if(((s+i)%(n+1))!=1)\n     x++; }\n     printf(\"%d\",x);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9040f0e8f427ca535a79472e12baf593", "src_uid": "ff6b3fd358c758324c19a26283ab96a4", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "\n#include <stdio.h>\n\nint main()\n{\n\tint n;\n\twhile(1)\n\t{\n\t\tscanf(\"%d\",&n);\n\t\tint fingers,i,tl_fingers =0,cnt;\n\t\tfor(i=0;i<n;i++)\n\t\t{\n\t\t\tscanf(\"%d\",&fingers);\n\t\t\ttl_fingers += fingers;\n\t\t}\n\t\tcnt =0;\n\t\tfor(fingers=1;fingers <= 5;fingers++)\n\t\t{\n\t\t\tif((tl_fingers + fingers)%(n+1)!=1)\n\t\t\t\tcnt ++;\n\t\t}\n\t\tprintf(\"%d\\n\",cnt);\n\t}\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8fffa76c9e0e2ba0797d32d08f4a3c59", "src_uid": "ff6b3fd358c758324c19a26283ab96a4", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "\n#include <stdio.h>\n\nint main()\n{   int n,a[20],i,j,sum=0,count=0,k;\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++)\n    {scanf(\"%d\",&a[i]);\n     sum+=a[i];\n    }\n     for(j=1;j<6;j++)\n     {  if((j+sum)%(n+1)==1)\n         count++;\n     }\n     printf(\"%d\",5-count);\n    \n     \n       \n    \n    \n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f3143cecbf625dc3f3819d3338324b6b", "src_uid": "ff6b3fd358c758324c19a26283ab96a4", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "/*Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.\n\nTo decide who exactly would clean the apartment, the friends want to play a counting-out game. First, all the guys stand in a circle, and then each of them shows some number of fingers on one hand (one to five), and then the boys count in a circle, starting from Dima, the number of people, respective to the total number of fingers shown. The person on who the countdown stops will clean the apartment.\n\nFor example, if Dima and one of his friends played hide and seek, and 7 fingers were shown during the counting-out, then Dima would clean the place. If there were 2 or say, 8 fingers shown, then his friend would clean the place.\n\nDima knows how many fingers each of his friends will show during the counting-out. Now he is interested in the number of ways to show some number of fingers on one hand (one to five), so that he did not have to clean the place. Help Dima.\n\nInput\nThe first line contains integer n (1?=?n?=?100) \ufffd the number of Dima's friends. Dima himself isn't considered to be his own friend. The second line contains n positive integers, not exceeding 5, representing, how many fingers the Dima's friends will show.\n\nThe numbers in the lines are separated by a single space.\n\nOutput\nIn a single line print the answer to the problem.\n\nExamples\ninput\n1\n1\noutput\n3\ninput\n1\n2\noutput\n2\ninput\n2\n3 5\noutput\n3\nNote\nIn the first sample Dima can show 1, 3 or 5 fingers. If Dima shows 3 fingers, then the counting-out will go like that: Dima, his friend, Dima, his friend.\n\nIn the second sample Dima can show 2 or 4 fingers.*/\n#include<stdio.h>\n#include<conio.h>\nint main()\n{\n    int frnd, fing=1, k, i, yes=0, frfing,sum=0,sumfrfing=0;\n    \n    scanf(\"%d\", &frnd);\n    for(i=0; i<frnd; i++)\n    {\n         scanf(\"%d\", &frfing);\n         sumfrfing+=frfing;\n    }\n    if(sumfrfing/(frnd+1)!=1)\n    {\n         k=sumfrfing/(frnd+1)+1;\n    }\n    else if(sumfrfing%(frnd+1)==0)\n    {\n         k=sumfrfing/(frnd+1);\n    }\n    for(fing=1;fing<=5;fing++)\n    {\n         sum=sumfrfing+ fing;\n         if(sum!=((frnd+1)*k+1))\n         {\n              yes++;\n         }\n         else\n         k++;\n    }\n    if(yes>0)\n    {\n         printf(\"%d\", yes);\n    }\n    getch();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "13e18635e670331b2b77ad49a47d201c", "src_uid": "ff6b3fd358c758324c19a26283ab96a4", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(void)\n{\n    int n,i,a,sum,m=0;\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a);\n        sum+=a;\n    }\n    for(i=1;i<=5;i++){\n        if((sum+i)%(n+1)) m++;\n    }\n    printf(\"%d\",m+1);\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "7844f3a789d3ae4b68a36f07cd98bc9a", "src_uid": "ff6b3fd358c758324c19a26283ab96a4", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MOD     1000003\n\nint main()\n{\n        int N,Sum=1;\n        scanf(\"%d\",&N);\n        for(i=1;i<N;++i)\n        {\n                Sum*=3;\n                Sum%=MOD;\n        }\n        printf(\"%d\\n\",Sum);\n        return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a621e0fc765a9e07850d0ffae448f6d8", "src_uid": "1a335a9638523ca0315282a67e18eec7", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define u_int unsigned int\n\nu_int uintpow(u_int a,u_int b);\n\nint main(void){\n  u_int n;\n  scanf(\"%u\",&n);\n  printf(\"%u\\n\",uintpow(3,n-1));\n  return 0;\n}\n\nu_int uintpow(u_int a,u_int b){\n    const u_int mod=1000003;\n    u_int i;\n    u_int prod=1;\n    for(i=0;i<b;i++){\n      prod*=3;\n      if(prod>1000000) prod%=mod;\n    }\n    return prod;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5eeaa6ed5e7864046ddcc3554acfea7b", "src_uid": "1a335a9638523ca0315282a67e18eec7", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\n#define MD\t1000003\n\nint main() {\n\tint n, p;\n\n\tscanf(\"%d\", &n);\n\tp = 1;\n\twhile (--n)\n\t\tp = p * 3 % MD;\n\tprintf(\"%d\\n\", p);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0b905ea7676163afb6ee880a76d1c208", "src_uid": "1a335a9638523ca0315282a67e18eec7", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(int argc, char *argv[])\n{\n    int n, p = 1;\n\n    scanf(\"%d\", &n);\n    while(-- n)\n        p = (p * 3) % 1000003;\n\n    printf(\"%d\\n\", p);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c150f53c02d365893dbfa431c8b32689", "src_uid": "1a335a9638523ca0315282a67e18eec7", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define u_int unsigned int\n\nu_int uintpow(u_int a,u_int b);\nu_int wint(u_int a,u_int b);\n\nint main(void){\n  u_int n;\n  scanf(\"%u\",&n);\n  printf(\"%u\\n\",uintpow(3,n-1));\n  return 0;\n}\n\nu_int uintpow(u_int a,u_int b){\n    const u_int mod=1000003;\n    u_int i;\n    u_int prod=1;\n    for(i=0;(b>>i)!=0;i++){\n      if((b>>i)&1==1){\n\tprod*=wint(a,i);\n\tprod%=mod;\n      }\n    }\n    prod%=mod;\n    return prod;\n}\n\nu_int wint(u_int a,u_int b){\n  const u_int mod=1000003;\n  for(;b>0;b--){\n    a*=a;\n    a%=mod;\n  }\n  return a;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "131c1885bfff9a51e20c1ade5b8da6ee", "src_uid": "1a335a9638523ca0315282a67e18eec7", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "/* https://csacademy.com/contest/archive/task/superstition/ (rainboy) */\n#include <stdio.h>\n#include <string.h>\n\n#define N\t8\n#define L\t5\n#define N_\t(1 + N * L)\n#define N1\t(N_ * 2)\n#define A\t26\n#define MD\t998244353\n\nint tt[1 + N_][A]; char word[1 + N_];\n\nvoid dfs(int coef[][L + 1], int s1, int s2, int l) {\n\tint a;\n\n\tif (s1 == 0 || s2 == 0)\n\t\treturn;\n\tif (l > 0) {\n\t\tif (word[s1])\n\t\t\tcoef[s2 - 1 << 1 | 0][l]++;\n\t\tif (word[s2])\n\t\t\tcoef[s1 - 1 << 1 | 1][l]++;\n\t\tif (word[s1] && word[s2])\n\t\t\tcoef[0][l]++;\n\t}\n\tfor (a = 0; a < A; a++)\n\t\tdfs(coef, tt[s1][a], tt[s2][a], l + 1);\n}\n\nint coef[N1][N1][L + 1];\n\nvoid apply(int aa[][N1][L], int n) {\n\tstatic int bb[N1][N1];\n\tint i, j, k, l;\n\n\tfor (i = 0; i < n; i++)\n\t\tmemset(bb[i], 0, n * sizeof *bb[i]);\n\tfor (i = 0; i < n; i++)\n\t\tfor (j = 0; j < n; j++)\n\t\t\tfor (k = 0; k < n; k++)\n\t\t\t\tfor (l = 1; l <= L; l++)\n\t\t\t\t\tbb[i][k] = (bb[i][k] + (long long) aa[i][j][l - 1] * coef[j][k][l]) % MD;\n\tfor (i = 0; i < n; i++)\n\t\tfor (j = 0; j < n; j++)\n\t\t\tfor (l = L - 1; l >= 0; l--)\n\t\t\t\taa[i][j][l] = l == 0 ? bb[i][j] : aa[i][j][l - 1];\n}\n\nvoid mult(int aa[][N1][L], int bb[][N1][L], int cc[][N1][L], int n) {\n\tstatic int aa_[N1][N1][L], bb_[N1][N1][L + L];\n\tint i, j, k, l, l1, l2;\n\n\tfor (i = 0; i < n; i++)\n\t\tfor (j = 0; j < n; j++)\n\t\t\tmemcpy(aa_[i][j], aa[i][j], L * sizeof *aa[i][j]);\n\tfor (l = 0; l < L; l++)\n\t\tfor (i = 0; i < n; i++)\n\t\t\tfor (j = 0; j < n; j++)\n\t\t\t\tfor (k = 0; k < n; k++)\n\t\t\t\t\tfor (l1 = 1; l + l1 < L; l1++)\n\t\t\t\t\t\taa_[i][k][l] = (aa_[i][k][l] - (long long) aa_[i][j][l + l1] * coef[j][k][l1]) % MD;\n\tfor (i = 0; i < n; i++)\n\t\tfor (j = 0; j < n; j++) {\n\t\t\tmemset(bb_[i][j], 0, L * sizeof *bb_[i][j]);\n\t\t\tmemcpy(bb_[i][j] + L, bb[i][j], L * sizeof *bb[i][j]);\n\t\t}\n\tfor (l = L - 1; l >= 0; l--)\n\t\tfor (i = 0; i < n; i++)\n\t\t\tfor (j = 0; j < n; j++)\n\t\t\t\tfor (k = 0; k < n; k++)\n\t\t\t\t\tfor (l1 = 1; l1 <= L; l1++)\n\t\t\t\t\t\tbb_[i][k][l] = (bb_[i][k][l] + (long long) coef[i][j][l1] * bb_[j][k][l + l1]) % MD;\n\tfor (i = 0; i < n; i++)\n\t\tfor (j = 0; j < n; j++)\n\t\t\tmemset(cc[i][j], 0, L * sizeof *cc[i][j]);\n\tfor (i = 0; i < n; i++)\n\t\tfor (j = 0; j < n; j++)\n\t\t\tfor (k = 0; k < n; k++)\n\t\t\t\tfor (l1 = 0; l1 < L; l1++)\n\t\t\t\t\tfor (l2 = L - l1; l1 + l2 - L < L; l2++)\n\t\t\t\t\t\tcc[i][k][l1 + l2 - L] = (cc[i][k][l1 + l2 - L] + (long long) aa_[i][j][l1] * bb_[j][k][l2]) % MD;\n}\n\nvoid power(int pp[][N1][L], int tt[][N1][L], int n, int k) {\n\tint i, j, l;\n\n\tif (k == 0) {\n\t\tfor (i = 0; i < n; i++)\n\t\t\tfor (j = 0; j < n; j++)\n\t\t\t\tfor (l = 0; l < L; l++)\n\t\t\t\t\tpp[i][j][l] = i == j && l == 0;\n\t\treturn;\n\t}\n\tpower(tt, pp, n, k / 2);\n\tmult(tt, tt, pp, n);\n\tif (k & 1)\n\t\tapply(pp, n);\n}\n\nint main() {\n\tstatic int pp[N1][N1][L], tt_[N1][N1][L];\n\tint n, n_, k, i, s;\n\n\tscanf(\"%d%d\", &n, &k);\n\tn_ = 1;\n\tfor (i = 0; i < n; i++) {\n\t\tstatic char cc[L + 1];\n\t\tint l, h;\n\n\t\tscanf(\"%s\", cc), l = strlen(cc);\n\t\tfor (h = 0, s = 1; h < l; h++) {\n\t\t\tint a = cc[h] - 'a';\n\n\t\t\tif (!tt[s][a])\n\t\t\t\ttt[s][a] = ++n_;\n\t\t\ts = tt[s][a];\n\t\t}\n\t\tword[s] = 1;\n\t}\n\tfor (s = 0; s < n_; s++) {\n\t\tdfs(coef[s << 1 | 0], 1, s + 1, 0);\n\t\tif (s != 0)\n\t\t\tdfs(coef[s << 1 | 1], s + 1, 1, 0);\n\t}\n\tpower(pp, tt_, n_ * 2, k);\n\tif (pp[0][0][0] < 0)\n\t\tpp[0][0][0] += MD;\n\tprintf(\"%d\\n\", pp[0][0][0]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fe94ec9939caaacee3e426dbdcf2b6ce", "src_uid": "711d15e11016d0164fb2b0c3756e4857", "difficulty": 2700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nvoid main()\n{\n    int y1,m1,d1,y2,m2,d2,i,j,s=0;\n    scanf(\"%d:%d:%d%d:%d:%d\",&y1,&m1,&d1,&y2,&m2,&d2);\n    for(i=y1+1;i<y2;i++)\n        if(i%4==0&&i%100!=0||i%400==0)s+=366;\n        else s+=365;\n    for(i=m1+1;i<=12;i++)\n    {\n        if(i==3||i==5||i==7||i==8||i==10||i==12)s+=31;\n        else if(i!=2)s+=30;\n        else if(y1%4==0&&y1%100!=0||y1%400==0&&i==2)s+=29;\n        else s+=28;\n    }\n    if(m1==1||i==3||i==5||i==7||i==8||i==10||i==12)s+=31-d1;\n    else if(m1==2&&y1%4==0&&y1%100!=0||y1%400==0)s+=29-d1;\n    else if(m1!=2)s+=30-d1;\n    else s+=28-d1;\n    for(i=1;i<m2;i++)\n    {\n        if(i==1||i==3||i==5||i==7||i==8||i==10)s+=31;\n        else if(i!=2)s+=30;\n        else if(y2%4==0&&y2%100!=0||y2%400==0&&i==2)s+=29;\n        else s+=28;\n    }\n    s+=d2;\n    printf(\"%d\\n\",s);\n}\n\n\t \t\t\t  \t\t   \t  \t\t  \t\t\t\t \t\t", "lang_cluster": "C", "compilation_error": false, "code_uid": "a13fa1844addb5b5f34c357069e6ceba", "src_uid": "bdf99d78dc291758fa09ec133fff1e9c", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nvoid main()\n{\n    int y1,m1,d1,y2,m2,d2,i,j,s=0;\n    scanf(\"%d:%d:%d%d:%d:%d\",&y1,&m1,&d1,&y2,&m2,&d2);\n    for(i=y1+1;i<y2;i++)\n        if(i%4==0&&i%100!=0||i%400==0)s+=366;\n        else s+=365;\n    for(i=m1+1;i<=12;i++)\n    {\n        if(i==3||i==5||i==7||i==8||i==10||i==12)s+=31;\n        else if(i!=2)s+=30;\n        else if(y1%4==0&&y1%100!=0||y1%400==0&&i==2)s+=29;\n        else s+=28;\n    }\n    if(m1==1||i==3||i==5||i==7||i==8||i==10||i==12)s+=31-d1;\n    else if(m1==2&&y1%4==0&&y1%100!=0||y1%400==0)s+=29-d1;\n    else if(m1!=2)s+=30-d1;\n    else s+=28-d1;\n    for(i=1;i<m2;i++)\n    {\n        if(i==1||i==3||i==5||i==7||i==8||i==10)s+=31;\n        else if(i!=2)s+=30;\n        else if(y2%4==0&&y2%100!=0||y2%400==0&&i==2)s+=29;\n        else s+=28;\n    }\n    s+=d2;\n    printf(\"%d\\n\",s);\n}\n\n \t \t\t\t \t   \t\t  \t \t \t\t\t\t \t", "lang_cluster": "C", "compilation_error": false, "code_uid": "c4bffd8766119cb1d9db1738fb54533b", "src_uid": "bdf99d78dc291758fa09ec133fff1e9c", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint rev(int *s,int *t)\n{int u;\nu=*t;*t=*s;*s=u;}\n int main()\n\n{int  y1,m1,d1,y2,m2,d2,i,l=0,ans=0,k=0,day[] ={31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};\nchar ch;\nscanf(\"%d %c %d %c %d\",&y1,&ch,&m1,&ch,&d1);\nscanf(\"%d %c %d %c %d\",&y2,&ch,&m2,&ch,&d2);\nif(y1>y2||(y1==y2&&m1>m2)||(y1==y2&&m1==m2&&d1>d2)){rev(&y1,&y2);rev(&m1,&m2);rev(&d1,&d2);}\n\nif(y1!=y2){ans=(y2-y1-1)*365;\nif(((y1%4==0&&y1%100!=0)||y1==2000)&&(m1==2&&d1<29)){ans++;}\n\nif(((y2%4==0&&y2%100!=0)||y2==2000)&&m2>2){ans++;}\nfor(i=y1+1;i<y2;i++)\n{if((i%4==0&&i%100!=0)||i==2000){l++;}}\nans+=l;ans+=d2-d1+day[m1-1];\nfor(i=m1;i<12;i++){ans+=day[i];}\nfor(i=0;i<m2-1;i++){ans+=day[i];}\n                                                                                                         else{\n                                                                                                         if(m1!=m2){for(i=m1;i<m2-1;i++){ans+=day[i];}ans+=d2-d1+day[m1-1];\n                                                                                                         if(((y1%4==0&&y1%100!=0)||y1==2000)&&(m1==2&&d1<29)){ans++;}}}\n\n\n\nif(y1==y2&&m1==m2){ans=d2-d1;}\n\n\nprintf(\"%d\",ans);\nreturn 0;}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e72fa147511a2762ed1200ab136e3320", "src_uid": "bdf99d78dc291758fa09ec133fff1e9c", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#define max(a,b) ((a)>(b)?(a):(b))\n#define min(a,b) ((a)>(b)?(b):(a))\nint days[]={0,31,28,31,30,31,30,31,31,30,31,30,31};\nint ct(int,int,int);\nint y1,y2,m1,m2,d1,d2,sum1,sum2,sum;\nint main(void)\n{\n    int i;\n    scanf(\"%d:%d:%d\",&y1,&m1,&d1);\n    scanf(\"%d:%d:%d\",&y2,&m2,&d2);\n    if(y1<y2)\n    {\n        sum1=ct(y1,m1,d1);\n        sum2=ct(y2,m2,d2);\n    }\n    else\n    {\n        sum2=ct(y1,m1,d1);\n        sum1=ct(y2,m2,d2);\n    }\n    for(i=min(y1,y2)+1; i<=max(y2,y1); i++)\n        if(i%400==0||(i%4==0&&i%100))\n            sum+=366;\n        else sum+=365;\n    if(y1==y2)\n        sum=(int)fabs(sum1-sum2);\n    else sum=sum-sum2+sum1;\n                 printf(\"%d\\n\",sum);\n                 return 0;\n}\nint ct(int y,int m,int d)\n{\n    int i;\n    int tot=0;\n    for(i=m;i<=12;i++)\n            tot+=days[i];\n            tot-=d-1;\n    if((y%400==0||(y%4==0&&y%100))&&m<=2&&d>=29)\n      tot++;\n    return tot;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "71a8985d485f04b0aa2527fcdeedc636", "src_uid": "bdf99d78dc291758fa09ec133fff1e9c", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n\tint y1,m1,d1,y2,d2,m2,t1,t2,d,t,p,k,y[200],d[200],l,i;\n      //t,p,k\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u05b4\ufffd\u02b1\ufffd\u0137\ufffd\u0163\ufffd//d\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u05ae\ufffd\ufffd\ufffd\u02b1\ufffd\ufffd\ue8fb//y[200]\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u05ae\ufffd\ufffd\ufffd\ufffd\ufffd\u0763\ufffd\n      //d[200]\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u00ff\ufffd\ufffdy[i]\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd//l\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u05ae\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u02fc\ufffd\ufffd\ufffd\ufffd\ufffd\u0763\ufffd\n\twhile(scanf(\"%d:%d:%d%d:%d:%d\",&y1,&m1,&d1,&y2,&m2,&d2)!=EOF)\n\t{\n\t\tif(y1>y2)\n\t\t{\n\t\t\tt=y2;\n\t\t\ty2=y1;\n\t\t\ty1=t;\n\t\t\tp=m2;\n\t\t\tm2=m1;\n\t\t\tm1=p;\n\t\t\tk=d2;\n\t\t\td2=d1;\n\t\t\td1=k;\n\t\t}\n\t\tif(y1==y2)\n\t\t{\n\t\t\tif(m1==m2)\n\t\t\t{\n\t\t\t\td=fabs(d2-d1);\n\t\t\t\tprintf(\"%d\\n\",d);\n\t\t\t}\n\t\t\telse if(m1<m2)\n\t\t\t{\n\t\t\t\t\tswitch(m1)\n                        \t{\n\t                          \tcase 1:t1=d1;break;\n                \t              \tcase 2:t1=d1+31;break;\n                \t              \tcase 3:t1=d1+28+31;break;\n                \t                \tcase 4:t1=d1+31+28+31;break;\n                 \t                \tcase 5:t1=d1+30+31+28+31;break;\n                \t\t            case 6:t1=d1+31+30+31+28+31;break;\n                \t      \t      case 7:t1=d1+30+31+30+31+28+31;break;\n\t                   \t      case 8:t1=d1+31+30+31+30+31+28+31;break;\n\t                   \t      case 9:t1=d1+31+31+30+31+30+31+28+31;break;\n\t                   \t      case 10:t1=d1+30+31+31+30+31+30+31+28+31;break;\n\t\t                        case 11:t1=d1+31+30+31+31+30+31+30+31+28+31;break;\n\t                \t            case 12:t1=d1+30+31+30+31+31+30+31+30+31+28+31;break;\n                        \t}\n                         \tif((y1%4==0&&y1%100!=0||y1%400==0)&&(m1>2))\n                        \t{\n\t                        \tt1++;\n                        \t}\n                        \tswitch(m2)\n                              {\n\t                        \tcase 1:t2=d2;break;\n\t                        \tcase 2:t2=d2+31;break;\n\t                        \tcase 3:t2=d2+28+31;break;\n\t                        \tcase 4:t2=d2+31+28+31;break;\n                   \t      \tcase 5:t2=d2+30+31+28+31;break;\n                \t            \tcase 6:t2=d2+31+30+31+28+31;break;\n                \t            \tcase 7:t2=d2+30+31+30+31+28+31;break;\n                 \t            \tcase 8:t2=d2+31+30+31+30+31+28+31;break;\n                  \t       \tcase 9:t2=d2+31+31+30+31+30+31+28+31;break;\n\t                        \tcase 10:t2=d2+30+31+31+30+31+30+31+28+31;break;\n\t                        \tcase 11:t2=d2+31+30+31+31+30+31+30+31+28+31;break;\n\t                        \tcase 12:t2=d2+30+31+30+31+31+30+31+30+31+28+31;break;\n                        \t}\n\t                        if((y2%4==0&&y2%100!=0||y2%400==0)&&(m2>2))\n                        \t{\n\t                  \t      t2++;\n                   \t      }\n                        \td=t2-t1;\n                         \tprintf(\"%d\\n\",d);\n\t\t\t}\n\t\t\telse if(m1>m2)\n\t\t\t{\n\t\t\t\t\tswitch(m1)\n                         \t{\n\t                         \tcase 1:t1=d1;break;\n                \t\t            case 2:t1=d1+31;break;\n                \t\t            case 3:t1=d1+28+31;break;\n                \t\t            case 4:t1=d1+31+28+31;break;\n                 \t\t            case 5:t1=d1+30+31+28+31;break;\n                \t\t            case 6:t1=d1+31+30+31+28+31;break;\n                \t\t            case 7:t1=d1+30+31+30+31+28+31;break;\n\t                         \tcase 8:t1=d1+31+30+31+30+31+28+31;break;\n\t                          \tcase 9:t1=d1+31+31+30+31+30+31+28+31;break;\n\t                             \tcase 10:t1=d1+30+31+31+30+31+30+31+28+31;break;\n\t\t                        case 11:t1=d1+31+30+31+31+30+31+30+31+28+31;break;\n\t                        \tcase 12:t1=d1+30+31+30+31+31+30+31+30+31+28+31;break;\n                        \t}\n                        \tif((y1%4==0&&y1%100!=0||y1%400==0)&&(m1>2))\n                        \t{\n\t                        \tt1++;\n                        \t}\n                        \tswitch(m2)\n                              {\n\t                          \tcase 1:t2=d2;break;\n\t                             \tcase 2:t2=d2+31;break;\n\t                          \tcase 3:t2=d2+28+31;break;\n\t                          \tcase 4:t2=d2+31+28+31;break;\n                            \t\tcase 5:t2=d2+30+31+28+31;break;\n                \t            \tcase 6:t2=d2+31+30+31+28+31;break;\n                \t             \tcase 7:t2=d2+30+31+30+31+28+31;break;\n                             \t\tcase 8:t2=d2+31+30+31+30+31+28+31;break;\n                             \t\tcase 9:t2=d2+31+31+30+31+30+31+28+31;break;\n\t                          \tcase 10:t2=d2+30+31+31+30+31+30+31+28+31;break;\n\t                           \tcase 11:t2=d2+31+30+31+31+30+31+30+31+28+31;break;\n\t                         \tcase 12:t2=d2+30+31+30+31+31+30+31+30+31+28+31;break;\n                        \t}\n\t                        if((y2%4==0&&y2%100!=0||y2%400==0)&&(m2>2))\n                        \t{\n\t                          \tt2++;\n                            \t}\n                             \td=t1-t2;\n                          \tprintf(\"%d\\n\",d);\n\t\t\t}\n\t\t}\n\t\telse if(y1<y2)\n\t\t{\n\t\t        \tswitch(m1)\n                      \t{\n\t                         \tcase 1:t1=d1;break;\n                \t            \tcase 2:t1=d1+31;break;\n                \t            \tcase 3:t1=d1+28+31;break;\n                \t            \tcase 4:t1=d1+31+28+31;break;\n                 \t              \tcase 5:t1=d1+30+31+28+31;break;\n                \t               \tcase 6:t1=d1+31+30+31+28+31;break;\n                \t               \tcase 7:t1=d1+30+31+30+31+28+31;break;\n\t                            \tcase 8:t1=d1+31+30+31+30+31+28+31;break;\n\t                            \tcase 9:t1=d1+31+31+30+31+30+31+28+31;break;\n\t                          \tcase 10:t1=d1+30+31+31+30+31+30+31+28+31;break;\n\t\t                        case 11:t1=d1+31+30+31+31+30+31+30+31+28+31;break;\n\t                        \tcase 12:t1=d1+30+31+30+31+31+30+31+30+31+28+31;break;\n                      \t}\n                      \tif((y1%4==0&&y1%100!=0||y1%400==0)&&(m1>2))\n                  \t{\n\t                     \tt1++;\n\t                   \tt1=366-t1;\n                   \t}\n                  \telse if((y1%4==0&&y1%100!=0||y1%400==0)&&(m1<2))\n                  \t{\n\t                  \tt1=366-t1;\n\t                   }\n\t                  else \n\t                  {\n                \t      \tt1=365-t1;\n                   \t}\n                  \tswitch(m2)\n                        {\n\t                          \tcase 1:t2=d2;break;\n\t                           \tcase 2:t2=d2+31;break;\n\t                         \tcase 3:t2=d2+28+31;break;\n\t                          \tcase 4:t2=d2+31+28+31;break;\n                             \t\tcase 5:t2=d2+30+31+28+31;break;\n                \t            \tcase 6:t2=d2+31+30+31+28+31;break;\n                \t            \tcase 7:t2=d2+30+31+30+31+28+31;break;\n                 \t              \tcase 8:t2=d2+31+30+31+30+31+28+31;break;\n                  \t         \tcase 9:t2=d2+31+31+30+31+30+31+28+31;break;\n\t                            \tcase 10:t2=d2+30+31+31+30+31+30+31+28+31;break;\n\t                           \tcase 11:t2=d2+31+30+31+31+30+31+30+31+28+31;break;\n\t                             \tcase 12:t2=d2+30+31+30+31+31+30+31+30+31+28+31;break;\n                \t      }\n\t                  if((y2%4==0&&y2%100!=0||y2%400==0)&&(m2>2))\n                        {\n\t                  \tt2++;\n                        }\n                        l=y2-y1-1;\n                   \tif(l==0)\n                   \t{\n\t                   \td=t1+t2;\n                        }\n                        else if(l>0)\n                        {\n                    \t      d=0\n                        \tfor(i=1;i<=l;i++)\n                        \t{\n\t                             y[i]=y1+i;\n\t                             if(y[i]%4==0&&y[i]%100!=0||y[i]%400==0)\n\t                             {\n                   \t\t             d[i]=366;\n                   \t            }\n                   \t            else \n                       \t           {\n                       \t                   d[i]=365;\n                                    }\n                                   d=d+d[i];\n                              }\n                              d=t1+t2+d;\n                              printf(\"%d\\n\",d);\n                    }\n\t\t}\n\t}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "006750dfd17f8352d620d1ca0ec0c046", "src_uid": "bdf99d78dc291758fa09ec133fff1e9c", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n    long long sum=0,a,b,c,d,e,f;\n    cin>> a;\n    cin>>b;\n    cin>>c;\n    cin>>d;\n    cin>>e;\n    cin>>f;\n    while (d!=0)\n    {\n        if(e>f)\n        {\n          if(a>0){\n            a--;\n            d--;\n            sum+=e;\n\n        }\n            if(a<=0&&b>0&&c>0)\n            {\n                b--;\n                c--;\n                d--;\n                sum+=f;}\n        if(a<=0&&b<=0||c<=0)\n            break;\n        }\n                if(f>e)\n        {\n            if(b>0&&c>0)\n            {\n                b--;\n                c--;\n                d--;\n                sum+=f;}\n          if(a>0&&b<=0||c<=0)\n          {\n            a--;\n            d--;\n            sum+=e;\n\n        }\n        if(a<=0&&b<=0||c<=0)\n            break;\n        }\n    }\n    cout <<sum;\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9703b41af9828d4648dd2d022385e354", "src_uid": "84d9e7e9c9541d997e6573edb421ae0a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n\nusing namespace std;\n\nlong int min(long int a, long int b) {\n    return a < b ? a : b;\n}\n\nlong int min(long int a, long int b, long int c) {\n    return ((a < b) && (a < c)) ? a : (b < c ? b : c);\n}\n\nint main() \n{\n    ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n\n    long int a, b, c, d;\n    short int e, f;\n    long long int sum = 0;\n\n    cin >> a >> b >> c >> d >> e >> f;\n\n    if (e > f) {\n        long int db = min(a, d);\n        sum += db * e;\n        db = min(b, c, d - db);\n        sum += db * f;\n    } else {\n        long int db = min(b, c, d);\n        sum += db * f;\n        db = min(a, d - db);\n        sum += db * e;\n    }\n\n    cout << sum;\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5f87bbfe1a45d34bc8d2f453c90e82a6", "src_uid": "84d9e7e9c9541d997e6573edb421ae0a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint a,b,c,d,e,f,min2;\n\tscanf(\"%d %d %d %d %d %d\",&a,&b,&c,&d,&e,&f);\n\n\tif(b <= c && b <= d)\n\t{\n\t\tmin2 = b;\n\t}\n\telse if(c <= d && c <= b)\n\t{\n\t\tmin2 = c;\n\t}\n\telse{\n\t\tmin2 = d;\n\t}\n\td -= min2;\n\tint min1 = (a < d) ? a : d;\n\t(min1 < 0) ? min1 *= -1 : min1 *= 1;\n\tmin2 *= f;\n\tmin1 *= e;\n\tprintf(\"%d\",min1+min2);\n\treturn 0;\n\t\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "16531d8f693be939fad72d193a19ef70", "src_uid": "84d9e7e9c9541d997e6573edb421ae0a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint mini(int a,int b,int c)\n{\nif(a<b&&a<c)\nreturn a;\nelse if(b<a&&b<c)\nreturn b;\nelse\nreturn c;\n}\nint main()\n{\nint a,b,c,d,e,f,min,cost;\nscanf(\"%d%d%d%d%d%d\",&a,&b,&c,&d,&e,&f);\nmin=mini(b,c,d);\ncost=min*f;\nd-=min;\nif(d>0) {\nd=mini(d,a);\ncost+=(d*e);}\nprintf(\"%d\",cost);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d29ff072cf89e1f6ac3c7da408450ca6", "src_uid": "84d9e7e9c9541d997e6573edb421ae0a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(\n    {\n\tunsigned long int a,b,c,d,e,f,n=0,A=0;\n\tprintf(\"all\\n\");\n\tscanf(\"%lu %lu %lu %lu %lu %lu\",&a,&b,&c,&d,&e,&f);\nif((b<=c) && (b<=d))\n{\n\td=d-b;\n\tA=b*f;\n}\nelse if((c<=b) && (c<=d))\n{\n\td=d-c;\n\tA=c*f;\n}\nelse\n{\n\tA=d*f;\n\td=0;\n}\nif(d!=0)\n{\n\tif(a<=d)\n\tA=A+(a*e);\n\telse \n\tA=A+(d*e);\n}\nprintf(\"%lu\\n\",A)\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "492d7e1b86ea7083bfd0fe1d92dd5599", "src_uid": "84d9e7e9c9541d997e6573edb421ae0a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "/*!\n * @file    problem.344c.c\n * @version 1.0\n * @date    28/09/2013\n * @author  Anton Leontiev <bunder@t-25.ru>\n *\n * @brief   \u0417\u0430\u0434\u0430\u0447\u0430 344\u0421. \u0420\u0430\u0446\u0438\u043e\u043d\u0430\u043b\u044c\u043d\u043e\u0435 \u0441\u043e\u043f\u0440\u043e\u0442\u0438\u0432\u043b\u0435\u043d\u0438\u0435\n *\n * @copyright\n *\n * Copyright (c) 2013, Anton Leontiev\n *\n * Redistribution and use in source and binary forms, with or without modification, are permitted\n * provided that the following conditions are met:\n *\n *  1. Redistributions of source code must retain the above copyright notice, this list of\n *     conditions and the following disclaimer.\n *  2. Redistributions in binary form must reproduce the above copyright notice, this list of\n *     conditions and the following disclaimer in the documentation and/or other materials\n *     provided with the distribution.\n *  3. Neither the name of Anton Leontiev nor the names of its contributors may be used\n *     to endorse or promote products derived from this software without specific prior written\n *     permission.\n *\n * THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS \"AS IS\" AND ANY EXPRESS OR\n * IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND\n * FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL COPYRIGHT HOLDER BE LIABLE\n * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING,\n * BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR PROFITS;\n * OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT,\n * STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE\n * OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.\n *\n */\n\n#include <stdint.h>\n#include <stdio.h>\n#include <stdlib.h>\n#include <inttypes.h>\n\n#define uint64_pri \"%\" PRIu64\n#define uint64_scn \"%\" SCNu64\n\nstatic inline void swap(uint64_t *a, uint64_t *b) {\n\t*a ^= *b;\n\t*b ^= *a;\n\t*a ^= *b;\n}\n\nint main(int argc, char *argv[]) {\n\tuint64_t a, b;\n\tunsigned i = 0;\n\n\tscanf(uint64_scn \" \" uint64_scn, &a, &b);\n\twhile (a != b) {\n\t\tif (a > b) swap(&a, &b);\n\t\tb -= a;\n\t\ti++;\n\t}\n\tprintf(\"%u\\n\", i+1);\n\treturn EXIT_SUCCESS;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "30c2f9b96db92799c7bd9b9da8548c86", "src_uid": "792efb147f3668a84c866048361970f8", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <math.h>\n#define ABS(x) ((x) < 0 ? -1*(x) : (x))\n#define MAX(x,y) ((x) > (y) ? (x) : (y))\n#define MIN(x,y) ((x) < (y) ? (x) : (y))\n#define MOD 1000000007\n#define INF 2000000000\n\ninline long long int rec(long long int a, long long int b, long long int csf)\n{\n    if(!b)\n        return csf;\n\n    if(a > b)\n        rec(b, a % b, csf+(a/b));\n    else\n        rec(a, b % a, csf+(b/a));\n}\n\nint main()\n{\n    long long int a,b;\n    scanf(\"%I64d\",&a);\n    scanf(\"%I64d\",&b);\n\n    printf(\"%I64d\\n\", rec(a,b,0));\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8f611f6b81a5616e4aa83658ab94e932", "src_uid": "792efb147f3668a84c866048361970f8", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long func(long long int a, long long int b)\n{\n    if(b==0){\n        return 0;\n    }\n    else{\n        return (a/b) + func(b,a%b);\n    }\n\n\n}\nint main()\n{\n    long long int  i, j, x;\n    scanf(\"%I64d %I64d\", &a, &b);\n    x = func(i,j);\n    printf(\"%I64d\", x);\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "923b2ad4f3208ee0271fdf01aef26a0c", "src_uid": "792efb147f3668a84c866048361970f8", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nusing namespace std;\nint main(){\n    long long a,b,ans=0;\n    scanf(\"%I64d %I64d\",&a,&b);\n    while (a!=0 || b!=1){\n        if (a>=b) {ans+=a/b;a=a%b;}else {ans+=b/a;b=b%a;if (b==0){ans--;b=a;}}\n    }\n    printf(\"%I64d\\n\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e9a5ceeb668a96ab03484f883f5d5a7d", "src_uid": "792efb147f3668a84c866048361970f8", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nusing namespace std;\nint main()\n{\n    long long a,b,i,k=0;\n    scanf(\"%I64d %I64d\",&a,&b);\n    if (a%b==0)\n        k=1;\n    else\n        if (a==1)\n        k=b;\n    else\n        {\n            while (a!=1)\n            {\n                if (a>b)\n                {\n                    a=a%b;\n                    k+=a;\n                }\n                else\n                {\n                    i=a;\n                    a=b;\n                    b=i;\n                }\n            }\n            k+=b;\n        }\n    printf(\"%I64d\",k);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a5852de4919127909ce44a699c736c41", "src_uid": "792efb147f3668a84c866048361970f8", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n\nint main() {\n\tint x, y, r, a;\n\tscanf_s(\"%d\",&r);\n\tr = r - 1;\n\ty = (r - 2) / 2;\n\tx = 0;\n\twhile (++x) {\n\t\tif (x * (x + (2 * y) + 1) == r) {\n\t\t\tprintf(\"%d %d\", x, y);\n\t\t\tbreak;\n\t\t}\n\t\telse if (x * (x + (2 * y) + 1) > r) {\n\t\t\tputs(\"NO\");\n\t\t\tbreak;\n\t\t}\n\t}\n\tgetch();\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9d4bcc549127d5a4aa9d78e881fac5df", "src_uid": "3ff1c25a1026c90aeb14d148d7fb96ba", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long r;\n    scanf(\"%lld\",&r);\n    if(r<5 or r%2==0) printf(\"NO\");\n    else\n    {\n        printf(\"%I64d %I64d\",1LL,(r-3)/2);\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ad694a1d83ec7d1420e5c4c0fbfb34a3", "src_uid": "3ff1c25a1026c90aeb14d148d7fb96ba", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<Stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<stdint.h>\n \nint main(){\n    int64_t r,y,x,hash,min_x=10000000000,corresponding_y;\n    int flag_no=1;\n    scanf(\"%I64d\",&r);\n    for(y=((r/2)-1);y>;y--){\n        for(x=1;x<=r;x++){\n          hash = pow(x,2)+(2*x*y)+x+1 ;\n          if(hash>r){\n              break;\n          }\n          if(hash==r){\n              flag_no=0;\n             if(x<=min_x){\n                 min_x =x;\n                 corresponding_y =y;\n                 break;\n             }\n          }\n        }\n    }\n    if(flag_no == 1){\n        printf(\"NO\");\n    }\n    else{\n        printf(\"%I64d %I64d\",min_x,corresponding_y);\n    }\n    \n    \nreturn 0;    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6d7bda86ef52ff1ea474640150dcc3a1", "src_uid": "3ff1c25a1026c90aeb14d148d7fb96ba", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<algorithm>\n#define MAXN 1000000000001\nusing namespace std;\nint main()\n{\n\tlong long f=0,r,y;\n\tscanf(\"%lld\",&r);\n\tfor(long long i=1;i<r;i++)\n\t{\n\t\tif(i*i>=r)\tbreak;\n\t\tif((r-i*i-i-1)%(2*i)==0)\n\t\t{\n\t\t\ty=(r-i*i-i-1)/(2*i),f=1;\n\t\t\tprintf(\"%lld %lld\",i,y);\n\t\t}\t\n\t\tif(f)\tbreak;\n\t}\n\tif(!f)\tprintf(\"NO\\n\");\n\t\t\n } \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f1b39cf03dada7aa9b4df6567c152899", "src_uid": "3ff1c25a1026c90aeb14d148d7fb96ba", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long r;\n    scanf(\"%lld\",&r);\n    if(r<5 or r%2==0) printf(\"NO\");\n    else\n    {\n        printf(\"%lld %lld\",a1LL,(r-3)/2);\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "98501da553c73ed441d2b4fd6136303e", "src_uid": "3ff1c25a1026c90aeb14d148d7fb96ba", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n    long x,y,x1,y1,x2,y2;\n    scanf(\"%ld%ld\",&x,&y);\n    if(x>0 && y>0)\n    {\n        printf(\"0 %ld %ld 0\",x+y,x+y);\n    }\n    else if(x<0 && y>0)\n    {\n        printf(\"%ld 0 0 %ld\",-(labs(x)+y),(labs(x)+y));\n    }\n    else if(x<0 && y<0)\n    {\n        printf(\"%ld 0 0 %ld\"-(labs(x)+labs(y)),-(labs(x)+labs(y)));\n\n    }\n    else\n        printf(\"0 %ld %ld 0\",-(x+labs(y)),(x+labs(y)));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6ba5c36200b735e757971d9ee466333d", "src_uid": "e2f15a9d9593eec2e19be3140a847712", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<math.h>\nint main()\n{\n    int i,x,y,A,t1,t2;\n\twhile(scanf(\"%d%d\",&x,&y)!=EOF)\n\t{\n        t1=abs(x);t2=abs(y);\n        for(A=t1+1; ;A++)\n\t\t{\n\t\t\tif(t1*t2==(A-t1)*(A-t2))\n\t\t\t\tbreak;\n\t\t}\n\t\tif(x>=0&&y>=0)\n\t\t\tprintf(\"%d %d %d %d\\n\",0,A,A,0);\n\t\telse if(x>=0&&y<=0)\n\t\t\tprintf(\"%d %d %d %d\\n\",0,-A,A,0);\n\t\telse if(x<=0&&y>=0)\n\t\t\tprintf(\"%d %d %d %d\\n\",-A,0,0,A);\n\t\telse\n\t\t\tprintf(\"%d %d %d %d\\n\",-A,0,0,-A);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2d93ea40666796c2ef9b1d212464e823", "src_uid": "e2f15a9d9593eec2e19be3140a847712", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n\tlong x,y,x1,x2,y1,y2;\n\twhile(1) {\n\t\tscanf(\"%ld%ld\",&x,&y);\n\t\tif(x>0) {\n\t\t\tif(y>0) {\n\t\t\t\tx2 = x + y;\n\t\t\t\ty2 = 0;\n\t\t\t\ty1 = x2;\n\t\t\t\tx1 = 0;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tx2 = x + y;\n\t\t\t\ty2 = 0;\n\t\t\t\tx1 = 0;\n\t\t\t\ty1 = -x2;\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tif(y>0) {\n\t\t\t\tx1 = x - y;\n\t\t\t\tx2 = 0;\n\t\t\t\ty1 = 0;\n\t\t\t\ty2 = -x1;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tx1 = x + y;\n\t\t\t\tx2 = 0;\n\t\t\t\ty1 = 0;\n\t\t\t\ty2 = x1;\n\t\t\t}\n\t\t}\n\t\tprintf(\"%ld %ld %ld %ld\\n\",x1,y1,x2,y2);\n\t}\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2b5761cefbb527f605476caebe906298", "src_uid": "e2f15a9d9593eec2e19be3140a847712", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int x,y,p1,p2,a;\n    scanf(\"%lld%lld\",&x,&y);\n    for(a=1;a*a<y*y;a++);\n    if(x>0)\n        p1=x+a;\n    else\n        p1=x-a;\n\n    p2=(p1>0)?p1:-p1;\n    if(y<0)\n        p2=-p2;\n    if(p1>0)\n        printf(\"0 %lld %lld 0\\n\",p2,p1);\n    else\n        printf(\"%lld 0 0 %lld\\n\",p1,p2);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2b13a8224d1eeb708eede5dade2aa2b4", "src_uid": "e2f15a9d9593eec2e19be3140a847712", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n\nint main()\n{\n\tlong int x, y, x1, yi, x2, y2;\n\tscanf(\"%d %d\",&x, &y);\n\t\n\tif(x<0)\n\t{\n\t\tx2 = 0;\n\t\ty1 = 0;\n\t\tif(y>0)\n\t\t{\n\t\t\tx1 = x - y;\n\t\t\ty2 = y - x;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tx1 = x + y;\n\t\t\ty2 = -1*(x1);\n\t\t}\n\t}\n\telse\n\t{\n\t\tx1 = 0;\n\t\ty2 = 0;\n\t\tif(y>0)\n\t\t{\n\t\t\tx2 = x + y;\n\t\t\ty1 = x2;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tx2 = x + y;\n\t\t\ty1 = -1 * x2;\n\t\t}\n\t}\n\tprintf(\"%d %d %d %d\\n\",x1, y1, x2, y2);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5df9253f0d2035be3f0abfc1a8e2bfc4", "src_uid": "e2f15a9d9593eec2e19be3140a847712", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<iostream.h>\n\n \n \nint main(){\nint i,j,k,n,ans=0,z;\n \nscanf(\"%d\",&n);\nfor(i=1;i<=n;i++){\n    for(j=i;j<=n;j++){\n        for(z=j;z<=n;z++)\n                {\n \n                  if(!(i^j^z))\n                    ans+= i+j>z ;\n \n               }\n \n    }\n}\nprintf(\"%d\",ans);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "50f80420ce0f9e47112d2caac7b5a543", "src_uid": "838f2e75fdff0f13f002c0dfff0b2e8d", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <cstdio>\n#include <cstring>\n#include <iostream>\n#include <algorithm>\n\nusing namespace std;\n\ntypedef long long ll;\n\nint n,ans;\n\nint main()\n{\n    scanf(\"%d\",&n);\n    for (int i = 1;  i <= n; i++)\n    {\n        for (int j = 1; j <= i; j++)\n        {\n            int temp = i ^ j;\n            if (temp > j || temp > i)\n                continue;\n            if (temp + j <= i)\n                continue;\n            ans++;\n        }\n    }\n    printf(\"%d\\n\",ans);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b96d30495649d74e1f6a3c936489fa7e", "src_uid": "838f2e75fdff0f13f002c0dfff0b2e8d", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n,i,j,k,c=0;\n    scanf(\"%d\",&n);\n    for(i=1;i<=n;i++)\n    {\n        for(j=i;j<=n;j++)\n        {\n            k=i^j;\n            if(k<=n&&i+j>k&&j+k>i&&k+i>j&&k>=i&&k>=j)\n            {\n                c++;\n            }\n        }\n    }\n    printf(\"%d\\n\",c);\n    return 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "23de487e018ebe1f40a77130634420a3", "src_uid": "838f2e75fdff0f13f002c0dfff0b2e8d", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n  int n,a,b,c,i,count=0,j,k;\n  scanf(\"%d\",&n);\n  for (int i = 1; i < n; ++i)\n  {\n    for (int j = i+1; i < n; ++j)\n    {\n      /* code */\n      for (int k = i+2; i < i+j; ++k)\n      {\n        /* code */\n        if((i^j)==k)\n          count++;\n      }\n    }", "lang_cluster": "C", "compilation_error": true, "code_uid": "52e5b5f0bdfffd506fe38d2ecc7d6982", "src_uid": "838f2e75fdff0f13f002c0dfff0b2e8d", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint xor(int a,int b,int c)\n{\n    int a1[12],b1[12],c1[12];\n    for(int i=0; i<12; i++)\n    {\n        a1[i]=0;\n        b1[i]=0;\n        c1[i]=0;\n    }\n    int temp=1;\n    while(a!=0)\n    {\n        a1[12-temp]=a%2;\n        a=a/2;\n        temp++;\n    }\n    temp=1;\n    while(b!=0)\n    {\n        b1[12-temp]=b%2;\n        b=b/2;\n        temp++;\n    }\n    temp=1;\n    while(c!=0)\n    {\n        c1[12-temp]=c%2;\n        c=c/2;\n        temp++;\n    }\n    int count[12];\n    for(int i=0; i<12; i++)\n    {\n        count[i]=0;\n    }\n    for(int i=0; i<12; i++)\n    {\n        if(a1[i]==0)\n        count[i]++;\n        if(b1[i]==0)\n        count[i]++;\n        if(c1[i]==0)\n        count[i]++;\n    }\n    for(int i=0; i<12; i++)\n    {\n        if(count[i]%2==0)\n        {\n            return -1;\n        }\n    }\n    return 0;\n}\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    int arr[n];\n    for(int i=0; i<n; i++)\n    {\n        arr[i]=i+1;\n    }\n    int count = 0;\n    for(int i=0; i<n-2; i++)\n    {\n        for(int j=i+1; j<n-1; j++)\n        {\n            for(int k=j+1; k<i+j; k++)\n            {\n                if(arr[i]+arr[j]>arr[k] && xor(arr[i],arr[j],arr[k])==0)\n                count++;\n            }\n        }\n    }\n    printf(\"%d\",count);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b3a2c1d5294fe55390e1d8f5c0fb9e3a", "src_uid": "838f2e75fdff0f13f002c0dfff0b2e8d", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define pi 3.14\n\nint main()\n{\n    int a , b , r ,ans ;\n\n    while(scanf(\"%d%d%d\",&a,&b,&r)!=EOF)\n    {\n        d = 2* r ;\n        ans = (a/d)*(b/d);\n        if(ans%2==0)\n            printf(\"Second\\n\");\n        else\n            printf(\"First\\n\");\n\n    }\n\n\n    return 0 ;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b9179c4f597bfdbb802c7c7b1a0604dd", "src_uid": "90b9ef939a13cf29715bc5bce26c9896", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int a, b, r, t, f=0, s=0;\n    scanf(\" %d %d %d\", &a, &b, &r);\n\n    if(a>b)\n    {\n        t = a;\n        a = b;\n        b = t;\n    }\n\n    while(b != 0)\n    {\n        if(b > (2*r))\n        {\n            b -= (2*r);\n            f++;\n        }\n\n        if(b > (2*r))\n        {\n            b -= (2*r);\n            s++;\n        }\n\n        if(b < (2*r))\n            break;\n    }\n\n    if(f > s)\n        printf(\"First\\n\");\n    else\n        printf(\"Second\\n\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "91b7878b88c1f07b332f846ac8a90d2a", "src_uid": "90b9ef939a13cf29715bc5bce26c9896", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int a,b,r;\n    while(scanf(\"%d%d%d\",&a,&b,&r))\n        if(a>=2*r&&b>=2*r)\n            printf(\"First\\n\");\n        else printf(\"Second\\n\");\n        return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "244a130da46fe9d02693daa32f7cb1ff", "src_uid": "90b9ef939a13cf29715bc5bce26c9896", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint a,b,r;\nwhile(scanf(\"%d%d%d\",&a,&b,&r))\n{\nif(2*r>=a&&2*r>=b)printf(\"First\\n\");\nelse printf(\"Second\\n\");\n}\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "83e8921919ee473794c3f9b4490eca4b", "src_uid": "90b9ef939a13cf29715bc5bce26c9896", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nchar Win[2][10] = {\"Second\",\"First\"};\n\nint main()\n{\n    __int64 a,b,r;\n    scanf(\"%I64d %I64d %I64d\",&a,&b,&r);\n    if(a < 2 * r && b < 2 * r) puts(Win[0]);\n    else puts(Win[1]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "933fbf201430a9589ceb2c0cc1a3f857", "src_uid": "90b9ef939a13cf29715bc5bce26c9896", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(void)\n{\n\tint n,k,dif,s=0,a[105],i,j;\n\tscanf(\"%d%d\",&n,&k);\n\tfor(i=0;i<n;i++) {\n\t\tscanf(\"%d\",&a[i]);\n\t\ts+=a[i];\n\t}\n\tif(s<=k) {\n\t\tprintf(\"%d\",n);\n\t\tfor(i=0;i<n;i++) {\n\t\t\tprintf(\"%d\",a[i]);\n\t\t}\n\t}\n\tfor(i=0;i+1<n;i++) {\n\t\tfor(j=i;j<n;j++) {\n\t\t\tif(a[j]<a[i]) {\n\t\t\t\ttemp=a[i];\n\t\t\t\ta[i]=a[j];\n\t\t\t\ta[j]=temp;\n\t\t\t}\n\t\t}\n\t}\n\ts=0;\n\tfor(i=0;i<n;i++) {\n\t\ts+=a[i];\n\t\tdif=k-s;\n\t\tif(dif<0) {\n\t\t\tbreak;\n\t\t}\n\t}\n\tprintf(\"%d\",i);\n\tfor(j=0;j<i;j++) {\n\t\tprintf(\"%d \",a[i]);\n\t}\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9a4501d71d758ace20b88a45953408af", "src_uid": "dbb164a8dd190e63cceba95a31690a7c", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint comp(const void *a, const void *b)\n{\n\treturn *(int *)a - *(int *)b;\n}\n\nint main(void)\n{\n\tint n, k;\n\tscanf(\"%d %d\", &n, &k);\n\tint a[n];\n\tfor (int i = 0; i < n; ++i) {\n\t\tscanf(\"%d\", &a[i]);\n\t}\n\tqsort(a, n, sizeof(int), comp);\n\tint count = 0;\n\tfor (int i = 0; i < n; ++i) {\n\t\tk = k - a[i];\n\t\tif (k < 0) {\n\t\t\tbreak;\n\t\t}\n\t\tcount++;\n\t}\n\tprintf(\"%d\\n\", count);\n\tfor (int i = 0; i < count; ++i) {\n\t\tprintf(\"%d \", a[i]);\n\t}\n\tprintf(\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fbcccf16626492446fd1d7791d840e15", "src_uid": "dbb164a8dd190e63cceba95a31690a7c", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n\n    int x , y;\n    int arr [200];\n    scanf(\"%d%d\", &x , &y);\n\n    scanf(\"%d\", &arr[0]);\n    int maxi = arr[0] , max_index = 0;\n    int sum = maxi;\n    int n;\n    int length = 0;\n\n    for(i = 0 ;i < x; i++){\n\n        scanf(\"%d\", n);\n        if(n + sum  <= y){ sum += n;\n\n            arr[i + 1] = i + 1;\n            length++;\n\n        } else if (sum - maxi + n <= y){\n\n            sum -= maxi + n;\n            arr[max_index] = i + 1;\n            max = n;\n            max_index = i;\n            length++;\n        }\n\n        break;\n    }\n\n    printf(\"%d\\n\" , length);\n\n    for(i = 0 ; i < length; i++){\n\n        printf(\"%d \", arr[i]);\n\n    }\n\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8aa45af03be3976071858d89c0b9b466", "src_uid": "dbb164a8dd190e63cceba95a31690a7c", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#define MAXINS 101\n#define MAXDAY 10001\n#include <stdio.h>\n\n\nint rec(int i,int day){\n    int max;\n    if(i==0){\n        return 0;\n    }\n    if(day<=0){\n        return 0;\n    }\n    if(dp[i][day]!=-1){\n        return dp[i][day];\n    }\n    int ret1=0;\n    int ret2=0;\n    if((day-ins[i])>=0){\n        ret1=1+rec(i-1,day-ins[i]);\n    }\n    ret2=rec(i-1,day);\n \n    if(ret1>ret2){\n        max=ret1;\n        learn[i]=1;\n    }\n    else{\n        max=ret2;\n        learn[i]=0;\n    }\n    dp[i][day]=max;\n    return max;\n}\nint main(){\nint n;\nint available;\nint ins[101];\nint dp[105][10005];\nint learn[101];\n    int i,j;\n    int learnt;\n    for(i=0;i<=MAXINS;++i){\n        for(j=0;j<=MAXDAY;++j){\n            dp[i][j]=-1;\n        }\n    }\n    scanf(\"%d %d\",&n,&available);\n    i=1;\n    while(i<=n){\n        scanf(\"%d\",&ins[i]);\n        learn[i]=0;\n        i++;\n    }\n    \n    learnt=rec(n,available);\n    i=1;\n    printf(\"%d\\n\",learnt);\n    while(i<=n){\n        if(learn[i]==1){\n            printf(\"%d \",i);\n        }\n        i++;\n    }\n    if(learnt!=0){\n    printf(\"\\n\");\n    }\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8b328c80793478f9be753bdc46319668", "src_uid": "dbb164a8dd190e63cceba95a31690a7c", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nvoid pivot(int array[],int index[],int start,int end)\n{\n    int i,j=start,x=array[end],t;\n    for(i=start;i<end;i++)\n        if(array[i]<=x)\n        {\n            t=array[i];\n            array[i]=array[j];\n            array[j]=t;\n            t=index[i];\n            index[i]=index[j];\n            index[j]=t;\n            j++;\n        }\n    t=array[end];\n    array[end]=array[j];\n    array[j]=t;\n    t=index[end];\n    index[end]=index[j];\n    index[j]=t;\n    return j;\n}\nvoid quicksort(int array[],int start,int end)\n{\n    if(start>=end)\n        return;\n    int j=pivot(array,start,end);\n    quicksort(array,start,j-1);\n    quicksort(array,j+1,end);\n}\nint main()\n{\n    int n,k,i,count=0,num=0;\n    scanf(\"%d %d\",&n,&k);\n    int array[n+1],index[n+1];\n    for(i=1;i<=n;i++)\n    {\n        scanf(\"%d\",&array[i]);\n        index[i]=i;\n    }\n    quicksort(array,index,1,n);\n    for(i=1;count<=k&&i<=n;i++)\n    {\n        if(count+array[i]>k)\n            break;\n        count=count+array[i];\n        num++;\n    }\n    printf(\"%d\\n\",num);\n    for(i=1;i<=num;i++)\n        printf(\"%d \",index[i]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6f282cfbbca01e869f9fd457a7b3a129", "src_uid": "dbb164a8dd190e63cceba95a31690a7c", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<limits.h>\nint cmpfunc (const void * a, const void * b)\n{\n\treturn ( *(int*)b - *(int*)a );\n}\nint main()\n{\n\tint n,m;\n\tscanf(\"%d%d\",&n,&m);\n\tint arr[n];\n\tint out[m];\n\tint i,j;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\",&arr[i]);\n\t}\n\tfor(i=0;i<m;i++)\n\t\tscanf(\"%d\",&out[i]);\n\tqsort(out,m,sizeof(int),cmpfunc);\n\tj=0;\n\tfor(i=0;i<n;i++)\n\t\tif(arr[i]==0)\n\t\t{\n\t\t\tarr[i]=out[j];\n\t\t\tj++;\n\t\t}\n\tfor(i=0;i<n;i++)\n\t{\n\t\tif(arr[i]>=arr[i+1])\n\t\t{\n\t\t\tprintf(\"Yes\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\"No\");\n\treturn 0;\n}\n\t\t\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "79d73670b4cca05b1b3fe140983c7620", "src_uid": "40264e84c041fcfb4f8c0af784df102a", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint judge(inta[],intb[],intn,intm)\n{\n\tint i;\n\tint t=0,x=0;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tif(a[i]==0)\n\t\t{\n\t\t\ta[i]=b[x];x++;\n\t\t}\n\t}\n\tfor(i=0;i<n-1;i++)\n\t{\n\t\tif(a[i]>a[i+1])return1;\n\t}\n\treturn 0;\n}\n\nint comp(const void *a,const void *b)\n{\n\treturn*(int*)b-*(int*)a;\n}\nint main()\n{\n\tint a[500];\n\tint b[500];\n\tint n,m;\n\twhile(scanf(\"%d %d\",&n,&m)!=EOF)\n\t{\n\t \tint i;\n\t\t int c[500];\n\t\t for(i=0;i<n;i++)\n\t \t {\n\t\t \tscanf(\"%d\",&a[i]);\n\t\t\t c[i]=a[i];\n\t\t }\n\t\t for(i=0;i<m;i++)\n\t\t scanf(\"%d\",&b[i]);\n\t\t qsort(b,m,sizeof(b[0]),comp);\n\t\t int t=judge(a,b,n,m);\n\t\t if(t)printf(\"Yes\\n\");\n\t\t else\n\t\t printf(\"No\\n\");\n\t}\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "97a3d60ffd6400a5e259d00db65adbf1", "src_uid": "40264e84c041fcfb4f8c0af784df102a", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<algorithm>\n#include <stdio.h>\n#include <string>\n#include <string.h>\nint n,k;\nint a[1000],b[1000];\nint main()\n{\n    while(scanf(\"%d%d\",&n,&k)!=-1)\n    {\n        a[0]=0;\n        for(int i=1;i<=n;i++)\n        {\n            scanf(\"%d\",&a[i]);\n        }\n        for(int i=1;i<=k;i++)\n        {\n            scanf(\"%d\",&b[i]);\n        }\n        if(k==1)\n        {\n            int flag=0;\n            for(int i=1;i<=n;i++)\n            {\n                if(a[i]==0)\n                {\n                    a[i]=b[1];\n                }\n                if(a[i]-a[i-1]<0)\n                {\n                    flag=1;\n                }\n\n            }\n            if(flag==1)printf(\"Yes\\n\");\n            else printf(\"No\\n\");\n\n        }\n        else\n        {\n            printf(\"Yes\\n\");\n        }\n\n    }\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c24704373d0540f563f9fe5d7027c0ef", "src_uid": "40264e84c041fcfb4f8c0af784df102a", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n\tint n,m;\n\tint i,j;\n\tscanf(\"%d %d\",&n,&m);\n\tint a[n],b[m],count=0,flag=0;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\",&a[i]);\n\t\tif(a[i]!=0&&i!=0)\n\t\t{\n\t\t\tif(a[i]<prev)\n\t\t\t\tflag=1;\n\t\t\tprev=a[i];\n\t\t}\n\t\tif(a[i]==0)\n\t\t\tcount++;\n\t}\n\tfor(i=0;i<m;i++)\n\t\tscanf(\"%d\",&b[i]);\n\tif(count==1&&flag==1)\n\t\tprintf(\"Yes\\n\");\n\telse\n\t\tprintf(\"No\\n\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bd3e71d4a6a0241e896e94613979d574", "src_uid": "40264e84c041fcfb4f8c0af784df102a", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string>\n#include <string.h>\nint n,k;\nint a[1000],b[1000];\nint main()\n{\n    while(scanf(\"%d%d\",&n,&k)!=-1)\n    {\n        a[0]=0;\n        for(int i=1;i<=n;i++)\n        {\n            scanf(\"%d\",&a[i]);\n        }\n        for(int i=1;i<=k;i++)\n        {\n            scanf(\"%d\",&b[i]);\n        }\n        if(k==1)\n        {\n            int flag=0;\n            for(int i=1;i<=n;i++)\n            {\n                if(a[i]==0)\n                {\n                    a[i]=b[1];\n                }\n                if(a[i]-a[i-1]<0)\n                {\n                    flag=1;\n                }\n\n            }\n            if(flag==1)printf(\"Yes\\n\");\n            else printf(\"No\\n\");\n\n        }\n        else\n        {\n            printf(\"Yes\\n\");\n        }\n\n    }\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2d60af309749f484f229358cc2adddd5", "src_uid": "40264e84c041fcfb4f8c0af784df102a", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nint n,x,j;\nscanf(\"%d\",&n);\nfor(y=0,j<n,j++)\n{\nscanf(\"%d\",&x);\nprintf(\"%d\\n\",x/2);\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4f45e30151e204f45a62a44dc4e99685", "src_uid": "a661b6ce166fe4b2bbfd0ace56a7dc2c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\nint a;\nscanf(\"%d\",&a);\nfor(i=0;i<a;i++){\n\tint x;\n\tscanf(\"%d\",&x);\n\tprintf(\"%d\",x/2)\n}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a198eaa21f69d24ba7de3829aeade218", "src_uid": "a661b6ce166fe4b2bbfd0ace56a7dc2c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\nint a;\nscanf(\"%d\",&a);\nfor(i=0;i<a;i++){\n\tint x;\n\tscanf(\"%d\",&x);\n\tprintf(\"%d\",x/2)\n}\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ac4f5fc6805350eb3d8ceb922dba3e15", "src_uid": "a661b6ce166fe4b2bbfd0ace56a7dc2c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "/******************************************************************************\n\n                            Online C Compiler.\n                Code, Compile, Run and Debug C program online.\nWrite your code in this editor and press \"Run\" button to compile and execute it.\n\n*******************************************************************************/\n\n#include <stdio.h>\n\nint main()\n{\n    string s = fgets();\n    int t = strtol(s);\n    printf(t);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e615ef92bada1d308517583d0d9f17e9", "src_uid": "a661b6ce166fe4b2bbfd0ace56a7dc2c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int test;\n    scanf(\"%d\",&test);\n    int bal,cal;\n    while(test){\n        scanf(\"%d\",&bal);\n        if(bal%7==0) printf(\"%d\\n\"bal/7);\n        else printf(\"%d\\n\",bal/7+1);\n        test--;\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cc57125b6ee55aefdb239e71bcb7675a", "src_uid": "a661b6ce166fe4b2bbfd0ace56a7dc2c", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main(void)\n{\n    int in=0;\n    while(EOF!=scanf(\"%d\",&in))\n    {\n        if(in==1) printf(\"Washington\\n\");\n        else if(in==2) printf(\"Adams\\n\");\n        else if(in==3) printf(\"Jefferson\\n\");\n        else if(in==4) printf(\"Madison\\n\");\n        else if(in==5) printf(\"Monroe\\n\");\n        else if(in==6) printf(\"Adams\\n\");\n        else if(in==7) printf(\"Jackson\\n\");\n        else if(in==8) printf(\"Van Buren\\n\");\n        else if(in==9) printf(\"Harrison\\n\");\n        else if(in==10) printf(\"Tyler\\n\");\n        else if(in==11) printf(\"Polk\\n\");\n        else if(in==12) printf(\"Taylor\\n\");\n        else if(in==13) printf(\"Fillmore\\n\");\n        else if(in==14) printf(\"Pierce\\n\");\n        else if(in==15) printf(\"Buchanan\\n\");\n        else if(in==16) printf(\"Lincoln\\n\");\n        else if(in==17) printf(\"Johnson\\n\");\n        else if(in==18) printf(\"Grant\\n\");\n        else if(in==19) printf(\"Hayes\\n\");\n        else if(in==20) printf(\"Garfield\\n\");\n        else if(in==21) printf(\"Arthur\\n\");\n        else if(in==22) printf(\"Cleveland\\n\");\n        else if(in==23) printf(\"Harrison\\n\");\n        else if(in==24) printf(\"Cleveland\\n\");\n        else if(in==25) printf(\"McKinley\\n\");\n        else if(in==26) printf(\"Roosevelt\\n\");\n        else if(in==27) printf(\"Taft\\n\");\n        else if(in==28) printf(\"Wilson\\n\");\n        else if(in==29) printf(\"Harding\\n\");\n        else if(in==30) printf(\"Coolidge\\n\");\n        else if(in==31) printf(\"Hoover\\n\");\n        else if(in==32) printf(\"Roosevelt\\n\");\n        else if(in==33) printf(\"Truman\\n\");\n        else if(in==34) printf(\"Eisenhower\\n\");\n        else if(in==35) printf(\"Kennedy\\n\");\n        else if(in==36) printf(\"Johnson\\n\");\n        else if(in==37) printf(\"Nixon\\n\");\n        else if(in==38) printf(\"Ford\\n\");\n        else if(in==39) printf(\"Carter\\n\");\n        else if(in==40) printf(\"Reagan\\n\");\n        /*else if(in==41) printf(\"H.W. Bush\\n\");\n        else if(in==42) printf(\"J. Clinton\\n\");*/\n\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1ee23912fdcc754ca5ce3fcec2d15d48", "src_uid": "0b51a8318c9ec0c80c0f4dc04fe0bfb3", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nchar Str[40][]={\"Washington\",\"Adams\",\"Jefferson\",\"Madison\",\"Monroe\",\"Adams\",\"Jackson\",\"Van Buren\",\"Harrison\",\"Tyler\",\n\"Polk\",\"Taylor\",\"Fillmore\",\"Pierce\",\"Buchanan\",\"Lincoln\",\"Johnson\",\"Grant\",\"Hayes\",\"Garfield\",\"Arthur\",\n\"Cleveland\",\"Harrison\",\"Cleveland\",\"McKinley\",\"Roosevelt\",\"Taft\",\"Wilson\",\"Harding\",\"Coolidge\",\"Hoover\",\"Roosevelt\",\n\"Truman\",\"Eisenhower\",\"Kennedy\",\"Johnson\",\"Nixon\",\"Ford\",\"Carter\",\"Reagan\",\"Bush\",\"Clinton\",\"Bush\",\"Obama\"};\n\nint main()\n{\n        int a;\n        scanf(\"%d\",&a);\n        puts(\"%s\",Str[a-1]);\n        return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "432afcd5cd7ad06abc1b04e2b9d4e54a", "src_uid": "0b51a8318c9ec0c80c0f4dc04fe0bfb3", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\nint main()\n{\n   int n;\n  \n   char ch[][]={\"Washington\",\"Adams\",\"Jefferson\",\"Madison\",\"Monroe\",\"Q. Adams\",\"Jackson\",\"Van Buren\",\"H. Harrison\",\"Tyler\",\"K. Polk\",\"Taylor\",\"Fillmore\",\"Pierce\",\"Buchanan\",\"Lincoln\",\"Johnson\",\"S. Grant\",\"B. Hayes\",\"A. Garfield\",\"A. Arthur\",\"Cleveland\",\"Harrison\",\"Cleveland\",\"McKinley\",\"Roosevelt\",\"H. Taft\",\"Wilson\",\"G. Harding\",\"Coolidge\",\"C. Hoover\",\"D. Roosevelt\",\"S. Truman\",\"D. Eisenhower\",\"F. Kennedy\",\"B. Johnson\",\"M. Nixon\",\"R. Ford\",\"Carter\",\"W. Reagan\"};\n   \n    scanf(\"%d\",n);\n    \n    \n   \n    printf(\"%s\\n\",ch[n-1]);\n    \n    return 0;\n}\n\n\n\n\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0a50447634bc5628cb89033d572bb31b", "src_uid": "0b51a8318c9ec0c80c0f4dc04fe0bfb3", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\n#define MAX_NAME_LENGTH 50\n\nint main() {\n    static char pres[44][MAX_NAME_LENGTH] = {\"Washington\", \"Adams\", \"Jefferson\", \"Madison\", \"Monroe\",\n        \"Adams\", \"Jackson\", \"Van Buren\", \"Harrison\", \"Tyler\", \"Polk\", \"Taylor\", \"Fillmore\", \"Pierce\",\n        \"Buchanan\", \"Lincoln\", \"Johnson\", \"Grant\", \"Hayes\", \"Garfield\", \"Arthur\", \"Cleveland\", \"Harrison\",\n        \"Cleveland\", \"McKinley\", \"Roosevelt\", \"Taft\", \"Wilson\", \"Harding\", \"Coolidge\", \"Hoover\", \"Roosevelt\",\n        \"Truman\", \"Eisenhower\", \"Kennedy\", \"Johnson\", \"Nixon\", \"Ford\", \"Carter\", \"Reagan\", \"Bush\", \"Clinton\",\n        \"Bush\", \"Obama\"}\n    int in;\n    scanf(\"%d\", &in);\n    printf(\"%s\\n\", pres[in-1]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "077b86edd6fb9bb8093fdc9574ae6d4b", "src_uid": "0b51a8318c9ec0c80c0f4dc04fe0bfb3", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint a,b,c,d,e,f,i,j,k,l;\n\tcin>>a;\n\tif(a==1)\n\t\tprintf(\"egbvx\\n\");\n\telse if(a==2)\n\t\tprintf(\"Adams\\n\");\n\telse if(a==3)\n\t\tprintf(\"ghh\\n\");\n\telse if(a==4)\n\t\tprintf(\"ggcxv\\n\");\n\telse if(a==5)\n\t\tprintf(\"xcvx\\n\");\n\telse if(a==6)\n\t\tprintf(\"hhrt\\n\");\n\telse if(a==7)\n\t\tprintf(\"erter\\n\");\n\telse if(a==8)\n\t\tprintf(\"Van Buren\\n\");\n\telse if(a==9)\n\t\tprintf(\"yuyu\\n\");\n\telse if(a==10)\n\t\tprintf(\"oho\\n\");\n\telse if(a==11)\n\t\tprintf(\"ttytr\\n\");\n\telse if(a==12)\n\t\tprintf(\"utrty\\n\");\n\telse if(a==13)\n\t\tprintf(\"qew\\n\");\n\telse if(a==14)\n\t\tprintf(\"ggtyu\\n\");\n\telse if(a==15)\n\t\tprintf(\"Bzcx\\n\");\n\telse if(a==16)\n\t\tprintf(\"qew\\n\");\n\telse if(a==17)\n\t\tprintf(\"ygy\\n\");\n\telse if(a==18)\n\t\tprintf(\"gxg\\n\");\n\telse if(a==19)\n\t\tprintf(\"rtr\\n\");\n\telse if(a==20)\n\t\tprintf(\"Gggh\\n\");\n\telse if(a==21)\n\t\tprintf(\"Azxcz\\n\");\n\telse if(a==22)\n\t\tprintf(\"ghh\\n\");\n\telse if(a==23)\n\t\tprintf(\"gcxb\\n\");\n\telse if(a==24)\n\t\tprintf(\"ugh\\n\");\n\telse if(a==25)\n\t\tprintf(\"ret\\n\");\n\telse if(a==26)\n\t\tprintf(\"yt\\n\");\n\telse if(a==27)\n\t\tprintf(\"Ta\\n\");\n\telse if(a==28)\n\t\tprintf(\"Wi\\n\");\n\telse if(a==29)\n\t\tprintf(\"Harding\\n\");\n\telse if(a==30)\n\t\tprintf(\"Coolidge\\n\");\n\telse if(a==31)\n\t\tprintf(\"over\\n\");\n\telse if(a==32)\n\t\tprintf(\"osvelt\\n\");\n\telse if(a==33)\n\t\tprintf(\"Tuman\\n\");\n\telse if(a==34)\n\t\tprintf(\"Esenhower\\n\");\n\telse if(a==35)\n\t\tprintf(\"nedy\\n\");\n\telse if(a==36)\n\t\tprintf(\"Jnson\\n\");\n\telse if(a==37)\n\t\tprintf(\"xon\\n\");\n\telse if(a==38)\n\t\tprintf(\"Fd\\n\");\n\telse if(a==39)\n\t\tprintf(\"Carter\\n\");\n\telse if(a==40)\n\t\tprintf(\"Rean\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0dfd88aa0ae0753b3f10a272b9db617f", "src_uid": "0b51a8318c9ec0c80c0f4dc04fe0bfb3", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "    #include<stdio.h>\n    int main(){\n        long long n,k;\n        scanf(\"%lld %lld\",&n,&k);\n        if((n / k) & 1) == 0)\n            printf(\"NO\");\n        else\n            printf(\"YES\");\n        return 0;\n    }\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "372fb49c59e69cb049464770a2f6fb4f", "src_uid": "05fd61dd0b1f50f154eec85d8cfaad50", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\ntypedef long long ll;\n\nint main()\n{\n    ll n,k;\n    scanf(\"%lld%lld\",&n,&k);\n    if(k>=n)\n        printf(\"YES\");\n    else\n    {\n        if((n/k)%2==0)\n            printf(\"NO\");\n        else printf(\"YES\");\n    }\n    \n   return 0;\n}\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\");\n   }*/", "lang_cluster": "C", "compilation_error": true, "code_uid": "160e443af9f0d964e84b38622a8157b5", "src_uid": "05fd61dd0b1f50f154eec85d8cfaad50", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    double n,k,d;\n    while(scanf(\"%lf%lf\",&n,&k)!=EOF)\n    {\n    d=n/k;\n    if(d%2==0)\n    printf(\"NO\\n\");\n    else\n    printf(\"YES\\n\");\n    }\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "cb02726134f244f891642d211db459bb", "src_uid": "05fd61dd0b1f50f154eec85d8cfaad50", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h> \nint main() { \nlong long n, k; \nscanf(\"%lld %lld\", &n, &k); \nprintf(((n / k) & 1 ? \"YES\" : \"NO\"); \nreturn 0; \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "470b55f2ae16f9c1643d9f32f0a411c2", "src_uid": "05fd61dd0b1f50f154eec85d8cfaad50", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(){\n\nlong long int n, k;\n\nscanf(\"%I64d %I64d\", &n , &k);\n\nif(n!= 1)\nprintf(\"%I64d %I64d\\n\" , n ,k);\n\nlong long int odd_even = n/k;\n\nif(n!=1)\nprinf(\"%I64d\\n\" , odd_even );\n\nif(odd_even%2 == 0)\n    printf(\"NO\");\nelse\n    printf(\"YES\");\n\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1cd39acfd5f728102597628ddc025917", "src_uid": "05fd61dd0b1f50f154eec85d8cfaad50", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\ntypedef struct\n{\n    int a;\n    int b;\n    int c;\n}EleType;\n\nint transfer(EleType , EleType );\nint OddEven(int );\n\nint main(void)\n{\n    int get;\n    get = 0;\n    EleType start, end;\n    scanf(\"%d%d%d\", &start.a, &start.b, &start.c);\n    scanf(\"%d%d%d\", &end.a, &end.b, &end.c);\n\n    get = transfer(start, end);\n    if (get == 1)\n        printf(\"Yes\");\n    else\n        printf(\"No\");\n    return 0;\n}\n\nint OddEven(int number)\n{\n    if (abs(number) % 0.5 == 0)\n        return 1;\n    else return 0;\n}\n\nint transfer(EleType in, EleType out)\n{\n    int i, j, k;\n    int o, p ,q;\n    o = 0;\n    p = 0;\n    k = 0;\n\n    i = (in.a - out.a);\n    j = (in.b - out.b);\n    k = (in.c - out.c);\n\n    if (i > 0)\n    {\n        if (OddEven(i))\n        {\n            p = i;\n            i = 0;\n        }\n        else\n        {\n            p  = i - 1;\n            i = 1;\n        }\n    }\n    if (j > 0)\n    {\n        if (OddEven(j))\n        {\n            o = j;\n            j = 0;\n        }\n        else\n        {\n            o  = j - 1;\n            j = 1;\n        }\n    }\n    if (k > 0)\n    {\n        if (OddEven(k))\n        {\n            q = k;\n            k = 0;\n        }\n        else\n        {\n            q  = k - 1;\n            k = 1;\n        }\n    }\n        if (!(o + p + q - i - j - k))\n            return 1;\n        else\n            return -1;\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "945fb4cfbd89422c81b796473da5c31c", "src_uid": "1db4ba9dc1000e26532bb73336cf12c3", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <iostream>\nusing namespace std;\n\nint main() \n{\n    int a,b,c,x,y,z;\n    cin >> a >> b >> c >> x >> y >> z;\n    int n=0,k=0;\n    ( a > x ) ? k += ( a - x ) / 2 : n += x - a;\n     ( b > y ) ? k += ( b - y ) / 2 : n += y - b;\n     ( c > z ) ? k += ( c - z ) / 2 : n += z - c;\n     ( k >= n ) ? cout << \"Yes\" : cout << \"No\";\n    // your code goes here\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "388578f461486e992fe77b245fc3e710", "src_uid": "1db4ba9dc1000e26532bb73336cf12c3", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint sum1=0,sum2=0;\nint a,b,c;\nint x,y,z;\nscanf(\"%d%d%d%d%d%d\",&a,&b,&c,&d,&e,&f);\n\n\nif(a>x && b>y && c<z)\n{\nsum1=(a-x+b-y)/2;\nsum2=y-c;\n}\nelse if(a<x && b>y && c>z)\n{\nsum1=(c-z+b-y)/2;\nsum2=x-a;\n}\nelse if(a>x && b<y && c>z)\n{\nsum1=(a-x+c-z)/2;\nsum2=y-b;\n}\n\nelse if(a>x && b<y && c<z)\n{\nsum1=(y-b+z-c);\nsum2=(a-x)/2;\n}\n\nelse if(a<x && b>y && c<z)\n{\nsum1=(x-a+z-c);\nsum2=(b-y)/2;\n}\n\nelse if(a<x && b<y && c>z)\n{\nsum1=(x-a+z-c);\nsum2=(y-b)/2;\n}\n\nif(sum1==sum2)\nprintf(\"Yes\\n\");\nelse\nprintf(\"No\");\n\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "987697c7e15fb16c8f5f62d2d4c2550b", "src_uid": "1db4ba9dc1000e26532bb73336cf12c3", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdlib.h>\n#include<stdio.h>\n\nint main()\n{\n\tint a,b,c,y,x,z,certo=0;\n\t\n\tscanf(\"%d %d %d\", &a, &b, &c);\n\tscanf(\"%d %d %d\", &x, &y, &z);\n\t\n\tif(a==b)\n\t{\n\t\tcerto =1;\n\t}\n\tif(a==c)\n\t{\n\t\tcerto=1;\n\t}\n\tif(c==b)\n\t{\n\t\tcerto=1;\n\t}\n\tif(certo==1)\n\t{\n\t\tif(x==y)\n\t\t{\n\t\t\tprintf(\"Yes\");\n\t\t}\n\t\tif(x==z)\n\t\t{\n\t\t\tprintf(\"Yes\");\n\t\t}\n\t\tif(y==z)\n\t\t{\n\t\t\tprintf(\"Yes\");\n\t\t}\n\tprintf(\"No\");\n\telse\n\t{\n\t\tprintf(\"No\");\n\t}\nreturn 0;\n}\n\n/* 1521310650391 */\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9ea20d46eafe75749e224609e15002ae", "src_uid": "1db4ba9dc1000e26532bb73336cf12c3", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<cstdio>\n\nint min(int a,int b){\n    if(a<b)\n        return b;\n    return a;\n}\n\nmain(){\n    int a,b,c,x,y,z,temp=0;\n    scanf(\"%d%d%d%d%d%d\",&a,&b,&c,&x,&y,&z);\n    if(a-x<0)\n        temp+=x-a;\n    if(b-y<0)\n        temp+=y-b;\n    if(c-z<0)\n        temp+=z-c;\n    if(min(a-x,0)/2+min(b-y,0)/2+min(c-z,0)/2<temp)\n        printf(\"No\");\n    else\n        printf(\"Yes\");\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "513ee5f9c4306e8400bb0ac2844f9f3b", "src_uid": "1db4ba9dc1000e26532bb73336cf12c3", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<thuvienchuan.h>\nint main(){\n\tint n,p,k;\n\tdo{\n    printf(\"nhap vao so trang n= \"); scanf(\"%d\",&n);} while(n<3 || n>100);\n    do{\n    printf(\"nhap vao so trang hien tai p= \"); scanf(\"%d\",&p);} while(p<1 || p>n);\n    do{\n    printf(\"nhap vao so trang k= \"); scanf(\"%d\",&k);} while(k<1 || k>n);\n\tif(p==1){\n\t\tprintf(\"(1) \");\n\t\tif(n<= p+k)\n\t\t\tfor(int i=2; i<=n; i++)\n\t\t\tprintf(\"%d \",i);\n\t\telse {\n\t\t\tfor(int i=2; i<= p+k; i++)\n\t\t\tprintf(\"%d \",i);\n\t\t\tprintf(\">>\");\n\t\t}}\n\telse if(p==n){\n\t\tif(p-k<=1){\n\t\tfor(int i=1; i<n; i++)\n\t\t   printf(\"%d \",i);\n\t\tprintf(\"(%d)\",n);\n\t}\n\t    else{ printf(\"<< \");\n\t      for(int i=p-k; i<n;i++) printf(\"%d \",i); printf(\"(%d)\",n);\n\t     }}\n\telse  {\n\t\tif(p-k<=1){\n\t\tfor(int i=1; i<p; i++) printf(\"%d \",i);\n\t\tprintf(\"(%d) \",p);}\n\t\telse{\n\t\t\tprintf(\"<< \");\n\t\t\tfor(int i=p-k; i<p; i++) printf(\"%d \",i); printf(\"(%d) \",p); \n\t\t}\n\t\tif(p+k<n){\n\t\tfor(int i=p+1; i<=p+k; i++) printf(\"%d \",i); printf(\">>\");}\n\t\telse for(int i=p+1; i<=n; i++) printf(\"%d \",i); }\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "eb959af06b34ab2f46018170e8ee7717", "src_uid": "526e2cce272e42a3220e33149b1c9c84", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main ()\n{\n    int n,p,k;\n    \n    scanf(\"%d%d%d\", &n, &p, &k);\n    \n    if (p+k>1)\n    {\n        printf (\"<<\");\n    }\n    \n    for (i=p-k; i<=p=k;i++ )\n    {\n        if (1<=i && i<=n)\n        {\n            if(i==p)\n            \n            printf(\"(%d)\", i);\n        }\n        else printf (\"%d\",i);\n    }\n    \n    if (p+k<n)\n    {\n        printf(\">>\");\n    }\n    Return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4d154a14b24f3b4ce7be1aa36e1c5d63", "src_uid": "526e2cce272e42a3220e33149b1c9c84", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,p,k,t,z;\n\tscanf(\"%d%d%d\",&n,&p,&k);\n\tif(p-k>1)\n\tprintf(\"<< \");\n\tt=n<=p+k?n:p+k;\n\tif(p-k<1)\n\tz=1;\n\telse\n\tz=p-k;\n\tfor(int i=z;i<=t;i++)\n\tif(i==p)\n\tprintf(\"(%d) \",i);\n\telse\n\tprintf(\"%d \",i);\n\tif(t<n)\n\tprintf(\">>\");\n\t\n\t\n\treturn 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "78695dfce0edeee562cdf9df86627848", "src_uid": "526e2cce272e42a3220e33149b1c9c84", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n int n,p,k;\n int f=0;\n\n scanf(\"%d %d %d\",&n,&p,&k);\n int f=p-k;\n if(p-k > 1)\n printf(\"<< \");\n for(int i = p-k; i < p+k; i++)\n {\n     if (f == p)\n    {\n     printf(\" (%d) \",f);\n     f++;\n    }\n     else\n     {\n      printf(\" %d \",f);\n      f++;\n      }\n }\n if(p+k < n)\n printf(\" >>\");\n return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8d4bf8dae6fcfd7e7b54b9257d4ef3f8", "src_uid": "526e2cce272e42a3220e33149b1c9c84", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,p,k;\n    scanf(\"%d%d%d\",&n,&p,&k);\n    if(p-k>1)\n        printf(\"<< \");\n    for(int i=p-k; i<p; i++)\n    {\n        if(i>0)\n            printf(\"%d \",i);\n    }\n    printf(\"(%d) \",p);\n    int j;\n    for(j=p+1;j<=p+k ; j++)\n    {\n        if(j>n)\n            break;\n        printf(\"%d \",j);\n\n    }\n\n    if(n>=10j)\n    {\n        printf(\">>\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0810c77a87f93a799a142755ba5eaaea", "src_uid": "526e2cce272e42a3220e33149b1c9c84", "difficulty": null}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint n,p=0,q=0,x,y;\nscanf(\"%d%d%d\",&n,&x,&y);\nif(n%2!=0)\n{if(y==n/2 || y==n/2-1|| y==n/2-1)\n{\nprintf(\"NO\");\n}\nelse\n{\nprintf(\"YES\");\n}\n}\nelse\n{\nif(y==n/2 || y==n/2+1)\n{\n    printf(\"NO\");\n}\nelse\nprintf(\"YES\n       \");\n}\nreturn(0);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5e9e55f796dfd9c03a1518b7ee75fcf2", "src_uid": "dc891d57bcdad3108dcb4ccf9c798789", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n\nint n,x,y;\n\nscanf(\"%d%d%d\",&num,&x,&y);\nn=n/2;\n\nif((x==n||x==n+1) && (y==n||y==n+1))\n{\nprintf(\"NO\");\n}\n\nelse\n{\nprintf(\"YES\");\n}\nreturn(0);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6ff0ec6cb806901742171f3ba1f11adf", "src_uid": "dc891d57bcdad3108dcb4ccf9c798789", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n\nint num,x,y,n;\n\nscanf(\"%d%d%d\",&num,&x,&y);\nn=num/2;\n\nif((x==n&&x=n+1) && (y==n&&y==n+1))\n{\nprintf(\"NO\");\n}\n\nelse\n{\nprintf(\"YES\");\n}\nreturn(0);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a340f743e23aba348609375d90820df5", "src_uid": "dc891d57bcdad3108dcb4ccf9c798789", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n    int n,x,y;\n    scanf(\"%d%d%d\",&n,&x,&y);\n    if(n==2||((x==n/2&&y==n/2)||(x==n/2&&y==(n/2)+1)(x==(n/2)+1&&y==n/2)){\n        printf(\"NO\");\n        return 0;\n    }\n    else {\n        printf(\"YES\");\n        return 0;\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0b9d2eca541e607e08adbf164ed8266f", "src_uid": "dc891d57bcdad3108dcb4ccf9c798789", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nmain()\n{int n,x,y;\n    scanf(\"%d%d%d\",&n,&x,&y);\n    if (((x>=n/2)((n/2)+1>=x))&&((y>=n/2)&&((n/2)+1>=y)))\n        printf(\"NO\");\n    else\n        printf(\"YES\");\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2ce3230d715c7520aa5d0717a6e188ce", "src_uid": "dc891d57bcdad3108dcb4ccf9c798789", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n     int a[100];\n     int r=0,count=0,i,j,k,n;\n      scanf(\"%d\\n\",&n);\n      for(i=0;i<n;i++)\n      {\n           scanf(\"%d\",&a[i]);\n      }\n      if(n==1)\n      {\n       if(a[0]==1)\n       printf(\"0\");\n       if(a[0]==0\n       printf(\"1\");\n       }\n       else\n       {\n      for(i=0;i<n;i++)\n      {\n           if(a[i]==1)\n           count++;\n      }\n     for(i=0;i<n;i++)\n     {\n          k=count;\n          for(j=i;j<n;j++)\n          {\n               if(a[j]==1)\n               k--;\n               else\n               k++;\n          }\n          if(k>r)\n          r=k;\n     }\n     if(a[n-1]==1)\n     r++;\n\n     printf(\"%d\\n\",r);\n}\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e8821928014cbb0689e59afe020e8817", "src_uid": "9b543e07e805fe1dd8fa869d5d7c8b99", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>int dp[105], a[105];int max(int a, int b){\treturn a > b ? a : b;}int main(){\tint n, i, j, m, ans, pre;    scanf(\"%d\",&n);\tpre = 0;\tfor (i = 1; i <= n; i++)\t{\t\tscanf(\"%d\",&a[i]);\t\tif (a[i] == 1)pre++;\t}\tif (a[1] == 0)dp[1] = 1;\telse dp[1] = 0;\tfor (i = 2; i <= n; i++)\t{\t\tif (a[i] == 1)\t\t\tdp[i] = max(dp[i - 1] - 1, 0);\t\telse if (a[i] == 0)\t\t\tdp[i] = max(0, dp[i - 1] + 1);\t}\tans = dp[1];\tfor (i = 2; i <= n; i++)\t\tans = max(ans, dp[i]);\tif (ans == 0)\t\tprintf(\"%d\",pre-1);\telse printf(\"%d\",pre+ans);  \treturn 0;}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c665bb421922ae79ffe3228ede105865", "src_uid": "9b543e07e805fe1dd8fa869d5d7c8b99", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint n,i,j,c[100]={0},k,m=1111,x=0,t=0,p;\nint main(){\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%d\",&j);\n\t\tc[i]+=j,t+=j;\n\t}\n\tfor(i=1;i<n;i++)\n\t\tfor(j=0;j<n-i;j++){\n\t\t\tfor(k=j,x=0;k<=j+i;k++) x+=c[k];\n\t\t\tif(x<m){m=x;p=i+1;}\n\t\t}\n\tif(n=1) printf(\"1\");\n\telse\tprintf(\"%d\",t+p-m);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4bf085d82ea384583e4fb695e63e26ac", "src_uid": "9b543e07e805fe1dd8fa869d5d7c8b99", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <algorithm>\nusing namespace std;\nint a[101];\nint main(){\n\tint n,i=1,j=1,k,temp=0;\n\tint ans=0;\n\tscanf(\"%d\",&n);\n\tfor(k=1;k<=n;k++){\n\t\tscanf(\"%d\",&a[k]);\n\t}\n\n\tfor(i=1;i<=n;i++){\n\t\t\n\t\tfor(j=1;j<=n;j++){\n\t\t\tans=0;\n\t\t\tfor(k=i;k<=j;k++){\n\t\t\t\tif(a[k]==1) a[k]=0;\n\t\t\t\telse a[k]=1;\n\t\t\t}\n\t\t\tfor(k=1;k<=n;k++){\n\t\t\t\tif(a[k]==1)\n\t\t\t\t\ttemp++;\n\t\t\t}\n\t\t\tif(temp>ans)\n\t\t\t\tans=temp;\n\t\t}\n\t\t\n\t}\n\n\tprintf(\"%d\",ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "23d82442dc7cc6ecccf6b4d9bc876349", "src_uid": "9b543e07e805fe1dd8fa869d5d7c8b99", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint compare(const void * a, const void * b){return *(int *)a-*(int *)b;}\nint main()\n{\n\tint n,j,i,a[1000],one[1000]={0};//a,b;\n\tscanf(\"%d\",&n);\n\tif(n==1)\n\t{\tscanf(\"%d\",&i)\n\t\tprintf(\"%d\",1-i);\n\t\treturn 0;\n\t}\n\tfor(i=0;i<n;i++)\n\t{\tscanf(\"%d\",&a[i]);\n\t\tif(a[i]==1)\n\t\t\tone[i+1]=one[i]+1;\n\t\telse\n\t\t\tone[i+1]=one[i];\n\t}\n\tint max=0,max1=0;\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tfor(j=i;j<=n;j++)\n\t\t{\n\t\t\tint r=one[n]-one[j]+one[i-1];\n\t\t//\tprintf(\"%d %d %d \",one[n],one[j],one[i-1]);\n\t\t\tint aa=(one[j]-one[i-1]);\n\t\t\tint bb=(j-i+1-one[j]+one[i-1]);\n//\t\t\tprintf(\"i=%d j=%d %d %d %d\\n\",i,j,r,aa,bb);\n\t\t\tif(aa>bb)\n\t\t\t\tmax1=aa+r;\n\t\t\telse\n\t\t\t\tmax1=bb+r;\n\t\t\tif(max1>max)\n\t\t\t\tmax=max1;\n\t\t}\n\t}\t\n\tprintf(\"%d\\n\",max);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "dd6205dc950344d82d0d7de3796f75ac", "src_uid": "9b543e07e805fe1dd8fa869d5d7c8b99", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <bits/stdc++.h>\n#include<iostream>\nusing namespace std;\n\nint main()\n{\n    int a[50],A,B,i,diff=1001;\n    cin >> A >> B;\n    for(i=0;i<B;i++)\n        cin >> a[i];\n\n    sort(a, a+B);\n    for(i=0;i+A-1<=B;i++)\n    {\n        if(a[i+A-1]-a[i]<diff)\n            diff=a[i+A-1]-a[i];\n    }\n    cout << diff;\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "13b3a86c607ff9941f4058e83a60311b", "src_uid": "7830aabb0663e645d54004063746e47f", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main(void){\n    int n,k,i,j,t=0,a[100],s=0,count=0;\n    scanf(\"%d %d\", &n, &k);\n\n    for(i=0;i<k;i++){\n        scanf(\"%d\", &a[i]);}\n\n\n    for(i=0;i<k;i++){\n        for(j=0;j<(k-i-1);j++){\n            if(a[j]>a[j+1]){\n\n                t=a[j];\n                a[j]=a[j+1];\n                a[j+1]=temp;}}}\n\n    for(i=0;i<k;i++){\n        for(j=i;j>=0;j--){\n            if(a[i]==a[j-1]){\n                s++;\n            }\n        }\n        if(s==0){\n            count++;\n\n        }\n\n        else{\n            s=0;\n            continue;\n        }\n    }\n\n    printf(\"%d\\n\", k-(count-1));\n\n\n    if(k-(count-1)==n){\n        printf(\"0\");\n    }\n\n    else{\n    printf(\"%d\", a[n-1]-a[0]);}}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e02c56204821ae94c5bd0876cfe9201e", "src_uid": "7830aabb0663e645d54004063746e47f", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdlib.h>\nmain()\n{\n    int n,i,j,m,a[50],s=1000;\n    scanf(\"%d %d\",&n,&m);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    for(i=0;i<n-1;i++)\n    {\n        for(j=0;j<n-1-i;j++)\n        {\n            if(a[j]<a[j+1])\n            {\n                t=a[j];\n                a[j]=a[j+1];\n                a[j+1]=t;\n            }\n        }\n    }\n    for(i=0;i<m-n;i++)\n    {\n        if(s>a[i]-a[i+3]) s=a[i]-a[i+3];\n    }\n    printf(\"%d\",s);\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9650c5dc185d50723d60653310bd8b5a", "src_uid": "7830aabb0663e645d54004063746e47f", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n     int n,m;\n     scanf(\"%d %d\",&n,&m);\n     int a[m];\n     for(int i=0;i<m;i++)\n     {\n          scanf(\"%d\",&a[i]);\n     }\n     int j,k,l;\n     for(j=0;j<m;j++)\n     {\n          for(k=j+1;k<m; )\n          {\n               if(a[j]<a[k])\n               k++;\n               else \n               {\n                    l=a[k];\n                    a[k]=a[j];\n                    a[j]=l;\n                    k++;\n               }\n          }\n     }\n     int o,p,min[m],t=0,u;\n     for(o=0;o<m;o++)\n     {\n       min[t]=a[o+n]-a[o];\n       t++;\n     }\n     int u=min[0];\n     for(int y=0;y<o;y++)\n     {\n          if(min[y]<u)\n          u=min[y];\n     }\n     printf(\"%d\",u);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a90d4df17b34210fa06951cc440f17d9", "src_uid": "7830aabb0663e645d54004063746e47f", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n\n    int x[50];\n          int n,p,i,j=0,temp;\n    scanf(\"%d %d\",&n,&p);\n\n    for(i=0;i<p;++i)\n        scanf(\"%d\",&x[i]);\n    for(int i =0 ; i<p ; ++i){\n        for(j=i; j<p; ++j){\n            if(x[j]<x[i])\n            {  temp=x[i];\n               x[i]=x[j];\n              x[j]=temp;\n            }\n        }\n    }\n    \n    int diff1=x[p-1]- x[p-1-n];\n    int diff2=x[n-1]-x[0];\n\nif(diff2<diff1)\n    printf(\"%d\", diff2);\n    else printf(\"%d 1\",diff1);\n    \n  \n   \n    \n    return 0 ; }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "73aa06da9ac0354955908da9ce459576", "src_uid": "7830aabb0663e645d54004063746e47f", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n int main(){\n\nint n,m,k,i,min;\nscanf (\"%d%d%d\",&n,&m,&k);\n  min=n-1;\nint *t=malloc (sizeof(int)*n);\nfor (i=0; i<n;i++){\n    scanf (\"%d\",t+i);\n\n    if (t[i]!=0 &&t[i]=<k && abs (m-i-1) < min ){\n            min =abs(m-i-1);\n\n    }\n}\n  printf (\"%d\",min*10);\n\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4e69034e902446cdc08310f304bfaea1", "src_uid": "57860e9a5342a29257ce506063d37624", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#define MAX 1000000009;\nint main() {\n    int i,n,m,k,min=MAX,t,temp;\n    scanf(\"%d %d %d\",&n,&m,&k);\n    for(i=1;i<=n;i++) {\n        scanf(\"%d\",&t);\n        if(t>0 && t<=k) {\n            temp = abs(m-i);\n            if(temp<min) {\n                min = temp;\n            }\n        }\n    }\n    printf(\"%d\\n\",(min*10));\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f276c25c50a872c265b31e5efdbe1cff", "src_uid": "57860e9a5342a29257ce506063d37624", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include<stdlib.h>\n\nint main()\n{\n\tint n,m,k,a[105],b[105],min,i,j=-1,x;\n\n\tscanf(\"%d\",&n);\n\tscanf(\"%d\",&m);\n\tscanf(\"%d\",&k);\n\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\",&a[i]);\n\t\tif((a[i]%k)<=1 && a[i]!=0)\n\t\t{\n\t\t\tj++;\n\t\t\tb[j]=i+1;\n\t\t}\n\n    }\n\n    min=abs(m-b[0]);\n\n    for(i=1;i<j+1;i++)\n    {\n    \tx=abs(m-b[i]);\n    \tif(x<min)\n    \t\tmin=x;\n    }\n\n    printf(\"%d\",(min+1)*10));\n\n\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "61057ddcce29e94c1f6b2584ff46e445", "src_uid": "57860e9a5342a29257ce506063d37624", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main () {\n\tint a[100],i,j,n,m,k;\n\tdo {\n\t\tprintf(\"n=\");\n\t\tscanf(\"%d\",&n);\n\t\tprintf(\"m=\");\n\t\tscanf(\"%d\",&m);\n\t\tprintf(\"k=\");\n\t\tscanf(\"%d\",&k);\n\t} while (n<1||m>n||m<1||k<1);\n\tfor (i=0;i<n;i++) {\n\t\t//printf(\"nhap tien phong so %d =\\n\",i+1);\n\t\tscanf(\"%d\",&a[i]);\n\t}\n\tint dem=0;\n\tint d[100];\n\tfor (i=0;i<n;i++) d[i]=0;\n\tfor(i=0;i<n;i++) {\n\t\tif (a[i]<=k&&a[i]!=0) {\n\t\t\tdem++;\n\t\t\td[i]=abs(i+1-m);\n\t\t}\n\t}\n\tif (dem ==0) printf(\"ko co phong phu hop\");\n\telse {\n\t\tint min=n-1,j;\n\t\tfor(i=0;i<n;i++) {\n\t\t\tif (d[i]!=0&&d[i]<=min) {\n\t\t\t\tmin=d[i];\n\t\t\t\tj=i;\n\t\t\t}\n\t\t}\n\t//printf(\"phong phu hop: %d\\n khoang cach den crush : %d\",j+1,min);\n\tprintf(\"%d\",min)\n\t\t\n\t}\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f21bbb35a44f07512f67b93a1546f8cf", "src_uid": "57860e9a5342a29257ce506063d37624", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    long long y,sum=0,sum1=0,dis[10001],n,m,k,vill[10001],vs[10001],v[10001],s=0;\n    cin>>n;\n    cin>>m;\n    cin>>k;\n    for(int i=0;i<n;i++)\n    {\n        cin>>vill[i];\n    }\n    sum1=(m-1)*10;\n\n    for(int j=0;j<n;j++)\n    {\n        if(vill[j]<k&&vill[j]>0)\n        {\n            v[s]=vill[j];\n            vs[s]=j;\n            dis[s]=sum;\n            s++;\n        }\n        sum=sum+10;\n    }\n    for(int z=0;z<s;z++)\n    {\n        dis[z]=abs(dis[z]-sum1);\n    }\n    sort(dis,dis+s);\n    cout<<dis[0];\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d5a8ba5329fe8040ff2d2ee0d2573859", "src_uid": "57860e9a5342a29257ce506063d37624", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <iostream>\nusing namespace std;\nint a,b,c;\nint main(){\n\tcin >> a >> b >> c;\n\tif((a+b+c)%2==0 && a+b>=c && a+c>=b && b+c>=a){\n\t\tcout << (a+b-c)/2 <<\" \" << (b+c-a)/2 << \" \" << (a+c-b)/2;\n\t}\n\telse cout << \"Impossible\\n\";\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5e037a1d4fbe2de92cdec117eedf6818", "src_uid": "b3b986fddc3770fed64b878fa42ab1bc", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n int a,b,c;\n \n scanf(\"%d %d %d\",&a,&b,&c);\n  \n  if(((a+b-c)/2)<0||((-a+b+c/2)<0)||((a-b+c)/2<0)){\n  printf(\"Impossible\");\n  }\n  else{\n  printf(\"%d %d %d\",((a+b-c)/2),((-a+b+c/2)),((a-b+c)/2))\n  }\n\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "16aa7a2792aa200b1dc0fb69a7af9fe2", "src_uid": "b3b986fddc3770fed64b878fa42ab1bc", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n int a,b,c;\n \n scanf(\"%d %d %d\",&a,&b,&c);\n  \n  if( ((a+b-c)/2)<0 || ((-a+b+c)/2)<0 || ((a-b+c)/2)<0 || ((a+b+c)%2) ) ){\n  printf(\"Impossible\");\n  }\n  else{\n  printf(\"%d %d %d\",((a+b-c)/2),((-a+b+c/2)),((a-b+c)/2));\n  }\n\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d9e6ddb8ca876d0ae4c7170262c81d23", "src_uid": "b3b986fddc3770fed64b878fa42ab1bc", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint a,b,c;\n\tscanf(\"%d %d %d\",a,b,c);\n\tfor(i=0;i<=a;++i)\n\t{\n\t\tif(b-i==c-a+i)\n\t\t{\n\t\t\tprintf(\"%d %d %d\\n\",i,b-i,a-i);\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\"Impossible\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fdf39adeeb3ab84b1baf63f0849f7951", "src_uid": "b3b986fddc3770fed64b878fa42ab1bc", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <cstdio>\nint a,b,c;\nint main(){\n\tscanf(\"%d %d %d\",&a,&b,&c);\n\tif((a+b+c)%2==0 && a+b>=c && a+c>=b && b+c>=a){\n\t\tprintf(\"%d %d %d\\n\",(a+b-c)/2,(b+c-a)/2,(a+c-b)/2);\n\t}\n\telse printf(\"Impossible\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8bfe0078e91f632267abd87e9edfc9da", "src_uid": "b3b986fddc3770fed64b878fa42ab1bc", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "int main()\n{\n    char s[100];\n    int i;\n    string a=\"NO\";\n    scanf(\"%100s\",s);\n    for(i=0;i<=100;i++){\n        if(s[i]=='Q'||s[i]=='H'||s[i]=='9'){a=\"YES\";}\n    }\n    printf(\"%s\",a.c_str());\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d70f3a4d2deb57a3c24db5be74e8cd05", "src_uid": "1baf894c1c7d5aeea01129c7900d3c12", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\nint main()\n{\nint c=0,i;\n    char p[100];\n\n    gets(p);\n\n    {for(i=0;i<strlen(p);i++){\n    if(((p[i]=='H')||(p[i]=='Q')||(p[i]=='9')||(p[i]=='+'))&&((p[i]>=33)&&(p[i]<=126)))\n    {printf(\"YES\");\n    c++;\n    break;}\n   else continue;}\n    if(c==0)\n    {printf(\"NO\");\nexit(1);}}\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ac2a3fa7557e9995ffce513ff79b49a2", "src_uid": "1baf894c1c7d5aeea01129c7900d3c12", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char str[100];\n    gets(str);\n    l=strlen(str);\n    for(int i=0;str[i]<l;i++)\n    {\n        if(str[i]=='H')\n        {\n            printf(\"YES\");\n            break;\n        }\n        else if(str[i]=='Q')\n        {\n            printf(\"YES\");\n            break;\n        }\n        else if(str[i]=='9')\n        {\n            printf(\"YES\");\n            break;\n        }\n        else {\n        printf(\"NO\");\n        break;\n        }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "206abdde423485b28d46ecd4dd664a16", "src_uid": "1baf894c1c7d5aeea01129c7900d3c12", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<math.h>\n#include<iostream>\n#include<string>\nusing namespace std;\nint main(){\n\tchar a[105];\n\tint i, t, f;\n\tcin >> a;\n\tf = 0;\n\tt = strlen(a);\n\tfor (i = 0; i <= (t - 1); i++) {\n\t\tif (a[i] == 'Q' || a[i] == '9' || a[i] == 'H' ) { cout << \"YES\"; f = 1; break; }\n\n\t}\n\tif (f == 0)cout << \"NO\";\n\t\n\treturn 0;\n}\n \t \t\t  \t\t \t \t\t       \t\t\t  \t\t\t\t\t", "lang_cluster": "C", "compilation_error": true, "code_uid": "f28c294939de349ed889802cf1d8c563", "src_uid": "1baf894c1c7d5aeea01129c7900d3c12", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n int main()\n{ char s[100];\n  int i=0,flag=0;\n  scanf(\"%s\",s);\n  while(s[i]!='\\0')\n  {  if(s[i]== 'H'||s[i]== 'Q'||s[i]=='9'||(s[i]=='+'&& s[i+1]='\\0'))\n      { flag=1;\n        break;\n      }i++;\n  }\n  if(flag==1)\n    printf(\"YES\");\n  else printf (\"NO\");\n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a51fe1821217f2b6d3a07b74580d40c9", "src_uid": "1baf894c1c7d5aeea01129c7900d3c12", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n#include <string>\n#include <cstring>\n#include <vector>\nusing namespace std;\n\nvector<int> ans;\nvoid process(int n)\n{\n    ans.clear();\n    ans.push_back(n);\n    while(--n)\n    {\n        if(ans[ans.size()-1]%n==0)\n        {\n            ans.push_back(n);\n        }\n    }\n    for(int i=0 ;i<(int)ans.size() ;i++)\n    {\n        printf(\"%d%c\",ans[i],i==(int)ans.size()-1?'\\n':' ');\n    }\n}\n\nint main()\n{\n   // freopen(\"in.txt\",\"r\",stdin);\n    int n;\n    while(cin>>n)\n    {\n        process(n);\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5c12298675c3dc52fabece940b470d36", "src_uid": "2fc946bb72f56b6d86eabfaf60f9fa63", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n,x;\n    scanf(\"%d\", &n);\n    b=n;\n    for(int i=n; i>=1; i--){\n        if(x%i==0){\n            x=i;\n            printf(\"%d \", i);\n        }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "05aa6d7c85684acc0d7d031d0773d7de", "src_uid": "2fc946bb72f56b6d86eabfaf60f9fa63", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#pragma comment(linker, \"/STACK:1024000000,1024000000\")\n#include <stdio.h>\n#include <string.h>\n#include <string>\n#include <math.h>\n#include <set>\n#include <queue>\n#include <stack>\n#include <map>\n#include <algorithm>\n#include <iostream>\n#include <vector>\n#define eps 0.0000000001\n#define bpr 999983\n#define spr 111123\n#define pi acos(-1.0)\n#define imax 2139062143\n#define mod 1000000007\n#define golden (sqrt(5)+ 1)/2\n#define reset(a,b) memset(a,b,sizeof(a))\n#define dmax 1e20\n#define siz 1005\n#define ze 2.718281828459\nusing namespace std;\nint ans[1000006];\nint dij[1000006];\nint mmax;\nvoid dfs(int now,int num)\n{\n\tdij[num]=now;\n\tfor (int i=2;i<now;i++)\n\t{\n\t\tif (now%i==0)\n\t\t{\n\t\t\tdfs(now/i,num+1);\n\t\t}\n\t}\n\tdij[++num]=1;\n\tif (num>mmax)\n\t{\n\t\tmmax=num;\n\t\tfor (int i=0;i<=num;i++)\n\t\t\tans[i]=dij[i];\n\t}\n\treturn ;\n}\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tmmax=0;\n\tif (n==1)\n\tprintf(\"1\\n\");\n\telse\n\t{\n\tdfs(n,0);\n\tfor (int i=0;i<=mmax;i++)\n\tprintf(\"%d \",ans[i]);\n\tprintf(\"\\n\");\n        }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3215be92c92bab3a1fec6b2a11991c01", "src_uid": "2fc946bb72f56b6d86eabfaf60f9fa63", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nusing namespace std;\nint ans[1000006];\nint dij[1000006];\nint mmax;\nvoid dfs(int now,int num)\n{\n\tdij[num]=now;\n\tfor (int i=2;i<now;i++)\n\t{\n\t\tif (now%i==0)\n\t\t{\n\t\t\tdfs(now/i,num+1);\n\t\t}\n\t}\n\tdij[++num]=1;\n\tif (num>mmax)\n\t{\n\t\tmmax=num;\n\t\tfor (int i=0;i<=num;i++)\n\t\t\tans[i]=dij[i];\n\t}\n\treturn ;\n}\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tmmax=0;\n\tif (n==1)\n\tprintf(\"1\\n\");\n\telse\n\t{\n\tdfs(n,0);\n\tfor (int i=0;i<=mmax;i++)\n\tprintf(\"%d \",ans[i]);\n\tprintf(\"\\n\");\n        }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6687188ead212a2da4942db03620808c", "src_uid": "2fc946bb72f56b6d86eabfaf60f9fa63", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(void)\n{\n    int mon, x , lcf;\n\n    scanf(\"%d\", &mon);\n    printf(\"%d \", mon);\n    for(x = mon; x > 1;){\n    \tfor(lcf = 2; lcf <= x; lcf++){\n    \t\tif(trav % lcf == 0){\n    \t\t\tx = x / lcf;\n\t    \t\tbreak;\t\t\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d \", x);\n\t}\n    getch();\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5b3852d8b5494ce2b9d53c2e2611ca76", "src_uid": "2fc946bb72f56b6d86eabfaf60f9fa63", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main{\nint a[5],sum=0,count=1,temp,i,j;\nfor(i=0;i<5;i++){\n    scanf(\"%d\",&a[i]);\n    sum=sum+a[i];\n}\nfor(i=0;i<4;i++){\n    for(j=0;j<5-i;j++){\n        if(a[i]<a[i+1]){\n            temp=a[i];\n            a[i]=a[i+1];\n            a[i+1]=temp;\n        }\n    }\n}\nfor(i=0;i<5;i++){\n    for(j=1;j+i<5;i++){\n        if(a[i]==a[i+j]){\n            count++;\n        }\n    }sum=sum-(a[i]*count);\n}\nprintf(\"%d\",sum);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b18e739c40366eaafedaa9be7b33d839", "src_uid": "a9c17ce5fd5f39ffd70917127ce3408a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<iostream>\nusing namespace std;\nint main()\n{int i,n[5],c=0,m=0,s=0,l=0,lr=0;\n    for(i=0,s=0;i<5;i++){\n        cin>>n[i];s+=n[i];\n    }lr=s;\n    for(i=0;i<5;i++)\n       {for(m=0,l=0,c=0;m<5&&c<3;m++)\n    {if(n[i]==n[m]){c++;l+=n[m];}}if(c>1)lr=min(lr,s-l);}\ncout<<lr<<\"\\n\";}", "lang_cluster": "C", "compilation_error": true, "code_uid": "93f1ca397915bc627e68616d431e76e8", "src_uid": "a9c17ce5fd5f39ffd70917127ce3408a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n     int i,c[5],a[101];\n     for(i=0;i<5;i++)\n     {\n          scanf(\"%d\",&c[i]);\n          a[c[i]]++;\n          sum+=c[i];\n     }\n     for(i=0;i<5;i++)\n     {\n          if((a[c[i]]==2)||(a[c[i]]==3))\n          sum-=(a[c[i]]*c[i]);\n     }\n     printf(\"%d\",sum);\n     \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "823e63d8b41bea3a5466a44b8ae24124", "src_uid": "a9c17ce5fd5f39ffd70917127ce3408a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main() {\n\t\n\tint a[5];\n\t\n\tint arr[101];\n\t\n\tint i;\n\tfor(i=0;i<5;i++) {\n\t\tscanf(\"%d\", &a[i]);\n\t}\n\t\n\tfor(i=0;i<101;i++) {\n\t\tarr[i]= 0;\n\t}\n\t\n\tfor(i=0;i<5;i++) {\n\t\tarr[a[i]]++;\n\t}\n\t\n\tint max=0;\n\t\n\tfor(i=0;i<101;i++) {\n\t\tif(arr[i]>0) {\n\t\t\tif(arr[i]==2) {\n\t\t\t\tif(max<2*i) {\n\t\t\t\t\tmax = 2*i;\t\n\t\t\t\t}\n\t\t\t\t//max = 2*i;\n\t\t\t} else if(arr[i]>=3) {\n\t\t\t\tif(max<3*i) {\n\t\t\t\t\tmax=3*i;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tint sum=0;\n\tfor(i=0;i<5;i++) {\n\t\tsum = sum + a[i]\n\t}\n\tprintf(\"%d\\n\",sum-max);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ff9f14d55c22a554a2d2d8754421a659", "src_uid": "a9c17ce5fd5f39ffd70917127ce3408a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "include<stdio.h>\nint main (){\nint a[5],sum=0,count=1,temp,i,j;\nfor(i=0;i<5;i++){\n    scanf(\"%d\",&a[i]);\n    sum=sum+a[i];\n}\nfor(i=0;i<4;i++){\n    for(j=0;j<5-i;j++){\n        if(a[i]<a[i+1]){\n            temp=a[i];\n            a[i]=a[i+1];\n            a[i+1]=temp;\n        }\n    }\n}\nfor(i=0;i<5;i++){\n    for(j=1;j+i<5;i++){\n        if(a[i]==a[i+j]){\n            count++;\n        }\n    }sum=sum-(a[i]*count);\n        break;\n}\nprintf(\"%d\",sum);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "51d14334b005b2146c5005ef8efa23d4", "src_uid": "a9c17ce5fd5f39ffd70917127ce3408a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nkontrol (long n)\n{\n        long i;\n        int flag;\n        if(n%10==8)return 1;\n        if(n<10 &&n>=0)\n        {\n            if(n%10==8)return 1;\n            return 0;\n        }\n        for (i=10;;i*=10)\n        {\n            if(i>n)break;\n            if((n/i)%10==8){flag=1;break;}\n        }\n        if(flag==1)return 1;\n        return 0;\n}\n\nint main()\n{\n    long i,k,temp;\n    scanf(\"%d\",&k);\n    for(i=k+1;i<8888888888;i++)\n    if(kontrol(i)==1){temp=i-k;break;}\n    printf(\"%ld\",temp%D;\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "abbfb7983e9fdcaf4dadf0f732af7e90", "src_uid": "4e57740be015963c190e0bfe1ab74cb9", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main() {\nlong long int n,m,z=0,p,q,r;\nscanf(\"%I64d\",&n);\nm=n;r=n;\nwhile(r!=0){\n    r=r/10;\n    z++;\n}\nwhile(1){\n    n++;q=0;\n    int i;p=n;\n    for(i=0;i<z;i++){\n        if(abs(p)%10==8){q++;}\n         p=abs(p)/10;\n    }\n    if(q>0){break;}\n}\nprintf(\"%d\",n-m,);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "460f336b9cc8faeef307a080b2f5a553", "src_uid": "4e57740be015963c190e0bfe1ab74cb9", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nkontrol (long long n)\n{\n        long long i;\n        long long flag = 0;\n        if(n%10==-8)return 1;\n        if(n%10==8)return 1;\n        if(n<10 &&n>=0)\n        {\n            if(n%10==8) || return 1;\n            return 0;\n        }\n        for (i=10;;i*=10)\n        {\n            if(i>n)break;\n            if((n/i)%10==8){flag=1;break;}\n        }\n        if(flag==1)return 1;\n        return 0;\n}\n\nint main()\n{\n    long long i,k,temp;\n    scanf(\"%lld\",&k);\n    for(i=k+1;i<8888888888;i++)\n    if(kontrol(i)==1){temp=i-k;break;}\n    printf(\"%lld\",temp);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "68d571efe326ef15f6a081e994df38f4", "src_uid": "4e57740be015963c190e0bfe1ab74cb9", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <stdint.h>\n\nint main()\n{   \n    int num[100],num2[100];\n    \n    int i=0,k,j,a,d,x,y,z,ck=0;\n\n    scanf(\"%d\",&n);\n\n    x=n;\n    z=n;\n\n    while(n>0){\n\n        a=n%10;\n\n        num[i]=a;\n        i++;\n\n        n=n/10;\n\n    }\n\n    for(i=0;i<10;i++){\n        j=0;\n        x++;\n        d=x;\n\n        while(d>0){\n\n            a=d%10;\n\n            num2[j]=a;\n            j++;\n            d=d/10;\n\n        }\n\n        for(k=0;k<j;k++){\n\n                if(num2[k]==8){\n                    ck=1;\n                    y=x-z;\n                    printf(\"%d\\n\",y);\n                    break;\n                }\n        }\n        if(ck){\n            break;\n        }\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4e1e606dd3b4a4555a55626a619292d4", "src_uid": "4e57740be015963c190e0bfe1ab74cb9", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"giga towers\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/giga towers\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/giga towers\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a1fff13b3fc73c329803db2ae925d87f", "src_uid": "4e57740be015963c190e0bfe1ab74cb9", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <conio.h>\n\n\nint cmpfunc (const void * a, const void * b)\n{\n   return ( *(int*)a - *(int*)b );\n}\n\nint main()\n{\n    int n=0,i=0,j=0,count1=0,count2=0,ans=0,temp=0;\n    scanf(\"%d\",&n);\n    int arr[n];\n    for(i=0;i<n;i++)\n    scanf(\"%d\",&arr[i]);\n    \n    qsort(arr, n, sizeof(int), cmpfunc);\n    //for(i=0;i<n;i++)\n    //printf(\" %d \",arr[i]);\n   \n   while(arr[j]==0)\n   {\n                   count1++;\n                   j++;\n   }\n   \n   for(i=j;i<n;i++)\n   {\n                   if(count2==0)\n                                temp=i-j;\n                   else\n                       temp=(i-j)/count2;\n                   if(arr[i]<temp)\n                   {\n                                   count2++;\n                   //printf(\" arr[%d]= %d , i-j = %d\\n\",i,arr[i],i-j);\n                   }\n    }\n   \n    if(count1>count2)\n                   ans=count1;\n    else \n                   ans= count2;\n                \n                if(n>0&&ans==0)\n                ans=1;\n    printf(\"%d\\n\",ans);\n   \n   \n    \n    getch();\n    return 0;   \n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8a586e6733d31883ce11a2aeb8bb3ebe", "src_uid": "7c710ae68f27f140e7e03564492f7214", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint arr[100];\nint main()\n{\n    int n,i,j,s;\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++)\n    scanf(\"%d\",&arr[i]);\n    for(i=0;i<n-1;i++)\n    {\n                      for(j=i+1;j<n;j++)\n                      {\n                                        if(arr[i]>arr[j])\n                                        {\n                                          s=arr[i];\n                                          arr[i]=arr[j];\n                                          arr[j]=s;\n                                        }\n                      }\n    }\n    int k=0,count;\n    for(i=0;i<n;i++)\n    {\n       count=arr[i];\n       if(count>=0)\n       {\n                   arr[i]=-1;\n                   int p=1;\n         for(j=i+1;j<n;j++)\n         {\n                           \n            if(arr[j]>=p)\n            {\n               arr[j]=-1;\n               p++;\n            }\n            }\n         \n         k++;\n         }k\n       }\n    \n    printf(\"%d\",k);\n    return 0;\n}                                                                  \n    \n    \n    \n    ", "lang_cluster": "C", "compilation_error": true, "code_uid": "df6403284449cf977dd5cb37b79dbf9e", "src_uid": "7c710ae68f27f140e7e03564492f7214", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint cmp(const void *a,const void *b);\nint main()\n{\n    int box[100];\n    int N;\n    int pile=0;\n    scanf(\"%d\",&N);\n    getchar();\n    for(int i=0;i<N;i++)\n        scanf(\"%d\",&box[i]);\n    getchar();\n     qsort(box,N,sizeof(box[0]),cmp);\n    if(box[0]!=0) pile++; \n    for(int i=0;i<N;i++)\n    {\n        if(box[i]==0) {pile++;continue;} \n    }\n     printf(\"%d\\n\",pile);\n    return 0;\n}\nint cmp(const void *a,const void *b)\n{\n    return    (*(int *)a)<(*(int *)b);\n}\n\t\t  \t\t \t\t \t   \t \t\t   \t\t\t \t", "lang_cluster": "C", "compilation_error": true, "code_uid": "9a29a2e3ffa32ffc636960468976bf99", "src_uid": "7c710ae68f27f140e7e03564492f7214", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define swap(a,b) { t=a; a=b; b=t; }\n\nint n;\nint h[100000],son=0,t,k,l,hh[10000];\nvoid ekle(int x)\n{\n\th[++son]=x;\n\tk=son;\n\twhile(k/2)\n\t{\n\t\tif(h[k/2]<h[k])\n\t\t{\n\t\t\tswap(h[k/2],h[k])\n\t\t\tk/=2;\n\t\t\tcontinue;\n\t\t}\n\t\tbreak;\n\t}\n}\n\nvoid sil()\n{\n\tint x = h[n];\n\th[n--] = h[1];\n\tint k = 1;\n\twhile(k * 2 <= n)\n\t{\n\t\tk=k*2+(h[2*k+1]>h[2*k] && 2*k+1 <= n);\n\t\tif(x<=h[k])\th[k/2] = h[k];\n\t\telse{ k /= 2; break; }\n\t}\n\th[k] = x;\n}\nint main()\n{\n\tint i,j,a;\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\",&a);\n\t\tekle(a);\n\t}\n\tif(n==1)\n\t{\n\t\tprintf(\"1\");\n\t\treturn 1;\n\t}\n\tint N = n,terim,b,sonraki,yukseklik,t=0;\n\tn = son;\n\tfor(i=0;i<N;i++)\n\t\tsil();\n\tn=N;\n\t/*for(i=1;i<=n;i++)\n\t\tprintf(\"%d \",h[i]);\n\tprintf(\"\\n\");*/\n\t//printf(\"%d \",n);\n\twhile(n>0)\n\t{\n\t\tt++;\n\t\tb=1;\n\t\tyukseklik=0;\n\t\t//terim=0;\n\t\t//puts(\"\");\n\t\twhile(b<N) \n\t\t{\n\t\t\twhile((hh[b] || h[b]<yukseklik) && b<N)\n\t\t\t{\n\t\t\t\tb++;\n\t\t\t}\n\t\t\tif(h[b]<yukseklik)\n\t\t\t\tbreak;\n\t\t\thh[b]=1;\n\t\t\tyukseklik++;\n\t\t\tn--;\n\t\t//\tprintf(\"%d \",h[b]);\n\t\t\t//getchar();\n\t\t\t//getchar();\n\t\t\t//printf(\"%d %d\\n\",h[b],yukseklik-1);\n\t\t}\n\t}\n\tprintf(\"%d\",t);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "327724792b454ed77f0e8aca6c3da0f0", "src_uid": "7c710ae68f27f140e7e03564492f7214", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n//#include <conio.h>\n\n\nint cmpfunc (const void * a, const void * b)\n{\n   return ( *(int*)a - *(int*)b );\n}\n\nint main()\n{\n    int n=0,i=0,j=0,count1=0,count2=0,ans=0,temp=0;\n    scanf(\"%d\",&n);\n    int arr[n];\n    for(i=0;i<n;i++)\n    scanf(\"%d\",&arr[i]);\n    \n    qsort(arr, n, sizeof(int), cmpfunc);\n    //for(i=0;i<n;i++)\n    //printf(\" %d \",arr[i]);\n   \n   while(arr[j]==0)\n   {\n                   count1++;\n                   j++;\n   }\n   \n   for(i=j;i<n;i++)\n   {\n                   if(count2==0)\n                                temp=i-j;\n                   else\n                       temp=(i-j)/count2;\n                   if(arr[i]<temp)\n                   {\n                                   count2++;\n                   //printf(\" arr[%d]= %d , i-j = %d\\n\",i,arr[i],i-j);\n                   }\n    }\n   \n    if(count1>count2)\n                   ans=count1;\n    else \n                   ans= count2;\n                \n                if(n>0&&ans==0)\n                ans=1;\n    printf(\"%d\\n\",ans);\n   \n   \n    \n    //getch();\n    return 1;   \n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "984f426023d0392b88700b256ee40f8e", "src_uid": "7c710ae68f27f140e7e03564492f7214", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<process.h>\n#include<string.h>\n#include<math.h>\nint main()\n{\t\n\tint a, b,k,j,sum=0;\n\tscanf(\"%d%d\", &a, &b);\n\tfor (int i = a; i < b + 1; i++){\n\t\tj = i;\n\t\twhile (j != 0){\n\t\t\tk=j % 10;\n\t\t\tj=j / 10;\n\t\t\tswitch (k){\n\t\t\tcase 1:sum += 2; break;\n\t\t\tcase 2:sum += 5; break;\n\t\t\tcase 3:sum += 5; break;\n\t\t\tcase 4:sum += 4; break;\n\t\t\tcase 5:sum += 5; break;\n\t\t\tcase 6:sum += 6; break;\n\t\t\tcase 7:sum += 3; break;\n\t\t\tcase 8:sum += 7; break;\n\t\t\tcase 9:sum += 6; break;\n\t\t\tcase 0:sum += 6; break;\n\t\t\t}\n\t\t}\n\t\t\n\t}\n\tprintf(\"%d\", sum);\n\t\n\tsystem(\"pause\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9d7db84455dd676a1e5954394028965f", "src_uid": "1193de6f80a9feee8522a404d16425b9", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MAX 1000000\n\nvoid main()\n{\n\tint a, b, d, i, sym[10]={6, 2, 5, 5, 4, 5, 6, 3, 7, 6};\n\tscanf(\"%d %d\", &a, &b);\n\tif(a<1 || b<1 || a>MAX || b>MAX || a>=b) return;\n\td=0;\n\tfor(i=a; a<=b; a++){\n\t\ti=a;\n\t\tdo{\n\t\td+=sym[i%10];\n\t\ti/=10;\n\t\t} while(i);\n\t}\n\tprintf(\"%d\", d);\n\treturn;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4e059eee93a3ec20fc510531d2bc35ca", "src_uid": "1193de6f80a9feee8522a404d16425b9", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint ara[12];\nlong long visited[1000010];\nint main()\n{\n    long long a,b,c,d,k,r,i;\n     ara[0]=6;\n     ara[1]=2;\n     ara[2]=5;\n     ara[3]=5;\n     ara[4]=4;\n    ara[5]=5;\n    ara[6]=6;\n    ara[7]=3;\n    ara[8]=7;\n    ara[9]=6;\n    visited[0]=6;\n    long long sum=6;\n    for(i=1;i<=1000010;i++){\n        a=i;\n        while(a!=0){\n            sum=sum+ara[a%10];\n            a=a/10;\n        }\n      visited[i]=sum;\n    }\n  scanf(\"%I64d%I64d\",&a,&b);\n    printf(\"%I64d\\n\",visited[b]-visited[a-1]);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f94edce2ef02573b970ef793689fcdc0", "src_uid": "1193de6f80a9feee8522a404d16425b9", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"B. Grandfather Dovlet\u2019s calculator\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/B. Grandfather Dovlet\u2019s calculator\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/B. Grandfather Dovlet\u2019s calculator\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "813aa32f127c33eb43485929014d0cb4", "src_uid": "1193de6f80a9feee8522a404d16425b9", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\nint segCalc(int number){\n\tif(number==4){\n\t\treturn 4;\n\t}else if (number==1){\n\t\treturn 2;\n\t}else if (number==2||number==5||number==3){\n\t\treturn 5;\n\t}else if (number==6||number==0){\n\t\treturn 6;\n\t}else if (number==7){\n\t\treturn 3;\n\t}else if (number==8){\n\t\treturn 8;\n\t}else if (number==9){\n\t\treturn 7;\n\t}\n\t\n\t\n}\nlong findSeg(long i){\n\tlong seg;\n\tint temp;\n\tif(i/10==0){\n\t\tseg= segCalc(i);\n\t\treturn seg;\n\t}\n\telse{\n\t\ttemp=i%10;\n\t\tseg=segCalc(temp);\n\t\t\n\t\treturn seg+findSeg(i/10);\n\t}\n\t\n}\nint main() {\n\t// your code goes here\n\tlong a,b,sum=0,i;\n\t\n\tscanf(\"%ld %ld\",&a,&b);\n\tfor(i=a;i<=b;i++){\n\t\t\n\tsum+=\tfindSeg(i);\t\n\t\n\t}\n\tprintf(\"%ld\",sum);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5f8131dd67f59973a176f05bc83123ee", "src_uid": "1193de6f80a9feee8522a404d16425b9", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#define counter.is_even counter%2==0\n#define counter.is_nonzero counter!=0\nint gcd(int a, int b) {\n    return b == 0 ? a : gcd(b, a % b);\n}\nlong long int vertexes[11111];\nint main(void) {\n\tlong long int n, counter, position, maximum = 1;\n\tscanf(\"%I64d\", &n);\n\tfor(int i = 1; i <= n; i++) {\n        scanf(\"%I64d\", &vertexes[i]);\n    }\n\tfor(int i = 1; i <= n; i++){\n\t\tcounter = 1;\n\t\tposition = vertexes[i];\n\t\twhile(position != i) {\n\t\t\tposition = vertexes[position];\n\t\t\tcounter++;\n\t\t\tif( counter > 100 || vertexes[position] == position) {\n                printf(\"-1\");\n                return 0;\n            }\n\t\t}\n\t\tif(counter.is_even) {\n            counter = counter / 2;\n        }\n\t\tif(counter.is_nonzero) {\n            maximum = maximum * counter / gcd(maximum, counter);\n        }\n\t}\n\tprintf(\"%I64d\", maximum);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "844c08ee4dc7e6f55fa15f8166f1ccf9", "src_uid": "149221131a978298ac56b58438df46c9", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\ntypedef long long unsigned llu;\ntypedef unsigned u;\nllu G(llu x,llu y){return y?G(y,x%y):x;}\nu N[111],V[111],A[111];\nint main()\n{\n\tu n,i=0,j;llu r=1,k;\n\tfor(scanf(\"%u\",&n);i++<n;++A[N[i]])scanf(\"%u\",N+i);\n\tfor(i=0;i++<n;)\n\t{\n\t\tif(!A[i]){printf(\"-1\\n\");return 0;}\n\t\tif(V[i])continue;\n\t\tfor(j=i,k=0;!V[j];j=N[j])k+=V[j]=1;\n\t\tif(!(k&1))k>>=1;\n\t\tr=r/G(r,k)*k;\n\t}\n\tprintf(\"%I64u\\n\",r);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0d93e23dceed7a23972fcf642f262a55", "src_uid": "149221131a978298ac56b58438df46c9", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint gcd(int,int);\nint main()\n{\n    int n,a[105],b[105],k,x,f,ans,vis[105];\n    int i,j;\n    scanf(\"%d\",&n);\n    for(i=1;i<=n;i++)\n    {scanf(\"%d\",&a[i]);\n    vis[i]=0;}\n    j=0;\n    for(i=1;i<=n;i++)\n    {\n         \n         k=0;\n         x=i;\n         f=0;\n         if(vis[i]==0){\n         while(1)\n         {\n               vis[x]=1;  \n               x=a[x];\n               k++;  \n               if(x==i)\n               {\n                   b[j]=k;\n                   j++;\n                   break;\n               }\n               if(k>=n)\n               {f=1;\n               break;}\n         }     \n         if(f==1)\n         {printf(\"-1\\n\");\n         break;}}\n    }\n    if(f==0)\n    {\n         for(i=0;i<j;i++)\n         {\n               if(b[i]%2==0)\n               b[i]/=2;\n         }\n         ans=b[0];\n         for(i=1;i<j;i++)\n         {\n              ans=(ans*b[i])/gcd(ans,b[i]);   \n         }\n         printf(\"%d\\n\",ans);\n    }\n    return 0;\n}\n\nint gcd(int p,int q)\n{\n    if(q==0)\n    return p;\n    int t;\n    if(p<q)\n    {\n       t=q;\n       q=p;\n       p=t;\n    }\n       \n    \n    return gcd(q,p%q);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8fea0014c076698c1e9a5ab919f67566", "src_uid": "149221131a978298ac56b58438df46c9", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\ntypedef long long int lli;\nint a[110];\nint m[110];\nlli c[110];\nlli mcm(lli a,lli b);\nlli mcd(lli a,lli b);\nlli min(lli a,lli b);\nlli max(lli a,lli b);\nlli cycl(int w,int s,int q);\nint main(){\n    int i,n,m;\n    lli t,r;\n    scanf(\"%d\",&n);\n    for(i=1;i<=n;i++){\n        scanf(\"%d\",a+i);\n    }\n    for(i=1;i<=n;i++){\n        c[i]=cycl(i,i,0);\n        if(c[i]==-1){\n            printf(\"-1\");\n            return 0;\n        }\n        if(c[i]%2==0){\n            c[i]/=2;\n        }\n    }\n    if(n==1){\n        printf(\"%I64d\\n\",c[1]);\n    }else{\n        r=mcm(c[1],c[2]);\n        for(i=1;i<=n;i++){\n            r=mcm(r,c[i]);\n        }\n        printf(\"%I64d\\n\",r);\n    }\n    return 0;\n}\nlli min(lli a,lli b){\n    if(a<b)return a;return b;\n}\nlli max(lli a,lli b){\n    if(a>b)return a;return b;\n}\nlli mcm(lli a,lli b){\n    return a*b/mcd(a,b);\n}\nlli mcd(lli a,lli b){\n    lli r;\n\tr=a%b;\n\tif (r==0)return(b);\n\telse return(mcd(b,r));\n}\nlli cycl(int w,int s,int q){\n    int i;\n    long long int r;\n    m[w]=1;\n    if(m[a[w]]){\n        if(a[w]==s){\n            r=q+1;\n        }else{\n            r=-1;\n        }\n    }else{\n        r=cycl(a[w],s,q+1);\n    }\n    m[w]=0;\n    return r;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "716e4443cd3e41b3630e68a4518fbd9c", "src_uid": "149221131a978298ac56b58438df46c9", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint gcd(int,int);\nint main()\n{\n    int n,a[105],b[105],k,x,f,ans;\n    int i,j;\n    scanf(\"%d\",&n);\n    for(i=1;i<=n;i++)\n    scanf(\"%d\",&a[i]);\n    \n    for(i=1;i<=n;i++)\n    {\n         \n         k=0;\n         x=i;\n         f=0;\n         while(1)\n         {\n               x=a[x];\n               k++;  \n               if(x==i)\n               {\n                   b[i]=k;\n                   break;\n               }\n               if(k>=n)\n               {f=1;\n               break;}\n         }     \n         if(f==1)\n         {printf(\"-1\\n\");\n         break;}\n    }\n    if(f==0)\n    {\n         for(i=1;i<=n;i++)\n         {\n               if(b[i]%2==0)\n               b[i]/=2;\n         }\n         ans=b[1];\n         for(i=2;i<=n;i++)\n         {\n              ans=(ans*b[i])/gcd(ans,b[i]);   \n         }\n         printf(\"%d\\n\",ans);\n    }\n    return 0;\n}\n\nint gcd(int p,int q)\n{\n    if(q==0)\n    return p;\n    int t;\n    if(p<q)\n    {\n       t=q;\n       q=p;\n       p=t;\n    }\n       \n    \n    return gcd(q,p%q);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "279eab99085b08555a3f8033ae37de25", "src_uid": "149221131a978298ac56b58438df46c9", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,last,k;\n    scanf(\"%d\",&n);\n    last=n%10;\n    if(last==0)\n    {\n        printf(\"%d\",n);\n    }\nelse if(last<=5)\n    {\n        k = n/10;\n        printf(\"%d\",k*10);\n    }\n    else(last>5)\n    {\n        k = (n/10) +1;\n        printf(\"%d\",k*10);\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "626bb8d1167dcd81412ecfdd28081457", "src_uid": "29c4d5fdf1328bbc943fa16d54d97aa9", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"ihezd\" />\n\t\t<Option execution_dir=\"C:/Users/WiKi Kef/Desktop/E.N.S.I/C++/ihezd/\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/ihezd\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/ihezd\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"E.N.S.I/C++/ihezd/main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f331d0d84b8dcead9849a20e8d3d863e", "src_uid": "29c4d5fdf1328bbc943fa16d54d97aa9", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long i,j,n,m,a=0,b=0,c=0,d=0,e=0,dk=0,last=0;\n    scanf(\"%d\\n\",&n);\n    last =n%10;\n    if(last==0)\n    printf(\"%d\",n);\n    else if(last==1)\n        printf(\"%d\\n\",n-1);\n    if(last==2)\n        printf(\"%d\\n\",n-2);\n    if(last==3)\n        printf(\"%d\\n\",n-3);\n    if(last==4)\n        pritnf(\"%d\\n\",n-4);\n    if(last==5)\n        printf(\"%d\\n\",n-5);\n     if(last==6)\n        printf(\"%d\\n\",n+4);\n    if(last==7)\n        pritnf(\"%d\\n\",n+3);\n    if(last==8)\n        printf(\"%d\\n\",n+2);\n    if(last==9)\n        pritnf(\"%d\\n\",n+3);\n\n        return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2cd7f857d0f8f918239270970ce71fd2", "src_uid": "29c4d5fdf1328bbc943fa16d54d97aa9", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<conio.h>\nint main()\n{\n          int n,last=0;\n          scanf(\"%d\",&n);\n          last=n%10\n          if(last==0)\n          printf(\"%d\",n);\n          else if(last==1)\n          printf(\"%d\",n-1);\n          else if(last==2)\n          printf(\"%d\",n-2);\n          else if(last==3)\n          printf(\"%d\",n-3);\n          else if(last==4)\n          printf(\"%d\",n-4);\n          else if(last==5)\n          printf(\"%d\",n-5);\n          else if(last==6)\n          printf(\"%d\",n+4);\n          else if(last==7)\n          printf(\"%d\",n+3);\n          else if(last==8)\n          printf(\"%d\",n+2);\n          else if(last==9)\n          printf(\"%d\",n+1);\n          else\n          printf(\"0\");\n          return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b7ffa971dc9b6636c67e99bcf9c6f70a", "src_uid": "29c4d5fdf1328bbc943fa16d54d97aa9", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "include<stdio.h>\nint main()\n{\n    int num,ans;\n    scanf(\"%d\",&num);\n    int res=num%10;\n    if(res==5) ans=num+5;\n    else if(res<5) ans=num-res;\n    else if(res>6) ans=num+10-res;\n    printf(\"%d\\n\",ans);\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dbf85b7cefc0f6cb9d8fdec0d53a48a7", "src_uid": "29c4d5fdf1328bbc943fa16d54d97aa9", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\ninline void printRepr(int num){\n    if(num >= 5){\n        printf(\"-O|\");\n        num-=5;\n    }\n    else{\n        printf(\"O-|\");\n    }\n    switch(num){\n        case 0:printf(\"-OOOO\");\n            break;\n        case 1:printf(\"O-OOO\");\n            break;\n        case 2:printf(\"OO-OO\");\n            break;\n        case 3:printf(\"OOO-O\");\n            break;\n        case 4:printf(\"OOOO-\");\n            break;\n    }\n    printf(\"\\n\");\n    return;\n}\n\nint main(){\n    int number,temp;\n    scanf(\"%d\",&number);\n    if(number==0){\n        printf(\"O-|-OOOO\");\n    }\n    while(number > 0 ){\n        temp=number%10;\n        printRepr(temp);\n        number/=10;\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7a853d78ed76b9501dcdb45a6578fed3", "src_uid": "c2e3aced0bc76b6484360563355d23a7", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nvoid main()\n\n{\nint n,x,y,i;\nscanf(\"%d\",&n);\nwhile(n%10!=0 ||n!=0)\n{\nx=n%10;\nif(x==0)\nprintf(\"O-|-OOOO\");\nelse\n{\nif(x<5)\nprintf(\"O-|\");\n}\nelse if(x>=5)\n{\nprintf(\"-O|\");\nx=x-5;\n}\ny=1;\nwhile(y<=4)\n{\nwhile(y<=x)\n{\nprintf(\"O\");\nif(y==x && y!=4)\n{\nprintf(\"-\");\n}\ny++;\n}\nif(y<=4)\nprintf(\"O\");\ny++;\n}\n}\nprintf(\"\\n\");\nn=n/10;\n}\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3e6e0356044670b072325f5d8442b571", "src_uid": "c2e3aced0bc76b6484360563355d23a7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <string.h>\n#include <stdio.h>\nint main()\n{\n     char ch[11];\n     scanf(\"%s\",ch);\n     int l=strlen(ch);\n     int i,j;\n     for(j=0;j<l;j++)\n     {\n          if(ch[j]=='0')\n          printf(\"O-|-OOOO\\n\")\n          else if(ch[j]=='1')\n               printf(\"O-|O-OOO\\n\");\n          else if(ch[j]=='2')\n          printf(\"O-|OO-OO\\n\");\n          else if(ch[j]=='3')\n          printf(\"O-|OOO-O\\n\");\n          else if(ch[j]=='4');\n          printf(\"O-|OOOO-\\n\");\n          else if(ch[j]=='5')\n          printf(\"-O|-OOOO\\n\");\n          else if(ch[j]=='6')\n          printf(\"-O|O-OOO\\n\");\n          else if(ch[j]=='7')\n          printf(\"-O|OO-OO\\n\");\n          else if(ch[j]=='8');\n          printf(\"-O|OOO-O\\n\")\n          else if(ch[j]=='9')\n          printf(\"-O|OOOO-\\n\");\n          \n     }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9ce17f9cb804eed34467f7d9320c1a6e", "src_uid": "c2e3aced0bc76b6484360563355d23a7", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nchar str[15][15];\nint main()\n{\n    int i,n,j,a[50];\n    strcpy(str[0],\"O-|-OOOO\");\n    strcpy(str[1],\"O-|O-OOO\");\n    strcpy(str[2],\"O-|OO-OO\");\n    strcpy(str[3],\"O-|OOO-O\");\n    strcpy(str[4],\"O-|-OOOO\");\n    strcpy(str[5],\"-O|-OOOO\");\n    strcpy(str[6],\"-O|O-OOO\");\n    strcpy(str[7],\"-O|OO-OO\");\n    strcpy(str[8],\"-O|OOO-O\");\n    strcpy(str[9],\"-O|-OOOO\");\n    while(~scanf(\"%d\",&n))\n    {\n        i=0;\n        (n==0){\n            printf(\"%s\\n\",str[0];\n            continue;\n        }\n        while(n!=0)\n        {\n            a[i++]=n%10;\n            n=n/10;\n        }\n        for(j=0;j<i;j++)\n            printf(\"%s\\n\",str[a[j]]);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2593707266af094de81ca71a68c46473", "src_uid": "c2e3aced0bc76b6484360563355d23a7", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main()\n{\n    long int n;\n    int d,i;\n    int digit[10];\n    scanf(\"%ld\",&n);\n    d=(int)(log(n)/log(10))+1;\n    for (i=1;i<=d;i++)\n    {\n        digit [i]=int(n/pow(10,i-1))-int(n/pow(10,i))*10;\n        printf(\"%d \",digit[i]);\n        if (digit [i]==0){\n                  printf(\"0-|-0000\\n\");\n                  }\n                  else if (digit [i]==1){\n                       printf(\"0-|0-000\\n\");\n                       }\n                       else if(digit [i]==2){\n                            printf(\"0-|00-00\\n\");\n                            }\n                            else if(digit [i]==3){\n                                 printf(\"0-|000-0\\n\");\n                                 }\n                                 else if(digit [i]==4){\n                                      printf(\"0-|0000-\\n\");\n                                      }\n                                      else if(digit [i]==5){\n                                           printf(\"-0|-0000\\n\");\n                                           }\n                                           else if(digit [i]==6){\n                                                printf(\"-0|0-000\\n\");\n                                                }\n                                                else if(digit [i]==7){\n                                                     printf(\"-0|00-00\\n\");\n                                                     }\n                                                     else if(digit [i]==8){\n                                                          printf(\"-0|000-0\\n\");\n                                                          }\n                                                          else if(digit [i]==9){\n                                                               printf(\"-0|0000-\\n\");\n                                                               }\n        \n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d87a6f8dd6ea99b7d0c93c789f5de843", "src_uid": "c2e3aced0bc76b6484360563355d23a7", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<stdlib.h>\n\n#define MOD  1000003\n\nint mapping(char c)\n{\n\tswitch(c)\n\t{\n\t\tcase '>':\n\t\t\treturn 8;\n\t\tcase '<':\n\t\t\treturn 9;\n\t\tcase '+':\n\t\t\treturn 10;\n\t\tcase '-':\n\t\t\treturn 11;\n\t\tcase '.':\n\t\t\treturn 12;\n\t\tcase ',':\n\t\t\treturn 13;\n\t\tcase '[':\n\t\t\treturn 14;\n\t\tcase ']':\n\t\t\treturn 15;\n\t}\n    \n\n}\nint length(char* c)\n{\n\tint i=0;\n\tfor(;c[i]!='\\0';i++){}\n\treturn i;\n}\n\nint fastMod(int a,int b,int m)\n{\n\tint i=1;\n\tint result=1;\n\tif(a==0 || m==1)\n\t{\n\t\treturn 0;\n\t}\n\tif (b==0)\n\t{\n\t\treturn 1;\n\t}\n\tif(b==1)\n\t{\n\t\treturn a%m;\n\t}\n\tresult=((a%m)*(a%m))%m;\n\tfor(i=1;i<=b-2;i++)\n\t{\n\t\tresult=(result*(a%m))%m;\n\t}\n\treturn result;\n\t\n}\nint main()\n{\n \tchar unary[150];\n    int len=0;\n\tint result=0;\n\tint i=0;\n\n\tscanf(\"%s\",unary);\n    len=length(unary);\n\tfor(i=0;i!=len;i++)\n\t{\n\t\tresult=result+((mapping(unary[i])%MOD)*(fastMod(16,len-i-1,MOD)))%MOD;\n\t}\n\tprintf(\"%d\\n\",result%MOD);\n    \n\t\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b915641b631b02c29200528755b052ad", "src_uid": "04fc8dfb856056f35d296402ad1b2da1", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n\n#define MOD 1000003\n\nlong long int mod(long long int p, long long int m)\n{\n\tif(p==0)\n\t\treturn 1;\n\telse if(p==1)\n\t\treturn 2;\n\telse if(p%2)\n\t\treturn (mod(1,m)*mod(p-1,m))%MOD;\n\telse\n\t\treturn (mod(p/2,m)*mod(p/2,m))%MOD;\n}\n\nint main()\n{\n\tchar p[100],s[100];\n\tscanf(\"%s\",p);\n\n\tfor(long long int i=0;p[i]!='\\0';i++)\n\t{\n\t\tif(p[i]=='>')\n\t\t{\t\n\t\t\tstrcat(s,\"1000\");\n\t\t\t\n\t\t}\n\t\telse if(p[i]=='<') \n\t\t{ \n\t\t\tstrcat(s,\"1001\");\n\t\t}\n\t\telse if(p[i]=='+')\n\t\t{ \n\t\t\tstrcat(s,\"1010\");\n\t\t}\n\t\telse if(p[i]=='-')\n\t\t{  \t\n\t\t\tstrcat(s,\"1011\");\n\t\t}\n\t\telse if(p[i]=='.') \n\t\t{\t\n\t\t\tstrcat(s,\"1100\");\n\t\t}\n\t\telse if(p[i]==',')\n\t\t{\n\t\t\tstrcat(s,\"1101\");\n\t\t}\n\t\telse if(p[i]=='[') \n\t\t{\t\n\t\t\tstrcat(s,\"1110\");\n\t\t\t//puts(s);\n\t\t}\n\t\telse \n\t\t{\n\t\t\tstrcat(s,\"1111\");\n\t\t\t//puts(s);\n\t\t}\n\t}\n\n\tlong long int ans=0,flag=0;\n\tfor(long long int i=strlen(s)-1;i>=0;i--)\n\t{\n\t\tlong long int temp=0;\n\t\tif(s[i]=='1')\n\t\t\ttemp = mod(flag,MOD);\n\t\tans = (ans+temp)%MOD;\n\t\tflag++;\n\t}\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6c7a14f83d44b082a792e0682ef24c6c", "src_uid": "04fc8dfb856056f35d296402ad1b2da1", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define M 1000003\n\nint main()\n{\n    int i=0;\n    long int x=0;\n    char s[105],c;\n    scanf(\"%s\",s);\n    c=s[i];\n    while(c!='\\0')\n    {\n        if(c=='>')\n            x=(x*16)%M+8;\n        else if(c=='<')\n            x=(x*16)%M+9;\n        else if(c=='+')\n            x=(x*16)%M+10;\n        else if(c=='-')\n            x=(x*16)%M+11;\n        else if(c=='.')\n            x=(x*16)%M+12;\n        else if(c==',')\n            x=(x*16)%M+13;\n        else if(c=='[')\n            x=(x*16)%M+14;\n        else\n            x=(x*16)%M+15;\n    }\n    printf(\"%ld\",(x%M));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c9f9bfe5910d3fd85ef781623fa8f2eb", "src_uid": "04fc8dfb856056f35d296402ad1b2da1", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nconst int N = 100005;\nint n;\nchar str[N];\n\nint trans(char ch){\n    switch (ch){\n        case '>':\n            return 8;\n        case '<':\n            return 9;\n        case '+':\n            return 10;\n        case '-':\n            return 11;\n        case '.':\n            return 12;\n        case ',':\n            return 13;\n        case '[':\n            return 14;\n        case ']':\n            return 15;\n    }\n    return -1;\n}\n\nint main(){\n    gets(str+1);\n    n = strlen(str+1);\n    int ans = 0 , i;\n    for (i=1;i<=n;i++){\n        ans = ans * ( 1 << 4 ) + trans(str[i]);\n        ans %= 1000003;\n    }\n    printf(\"%d\\n\",ans);\n}\n\n#include <stdio.h>\n#include <string.h>\nconst int N = 100005;\nint n;\nchar str[N];\n\nint trans(char ch){\n    switch (ch){\n        case '>':\n            return 8;\n        case '<':\n            return 9;\n        case '+':\n            return 10;\n        case '-':\n            return 11;\n        case '.':\n            return 12;\n        case ',':\n            return 13;\n        case '[':\n            return 14;\n        case ']':\n            return 15;\n    }\n    return -1;\n}\n\nint main(){\n    gets(str+1);\n    n = strlen(str+1);\n    int ans = 0 , i;\n    for (i=1;i<=n;i++){\n        ans = ans * ( 1 << 4 ) + trans(str[i]);\n        ans %= 1000003;\n    }\n    printf(\"%d\\n\",ans);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3d0a59b943cbd43dfccebb05f52a00bf", "src_uid": "04fc8dfb856056f35d296402ad1b2da1", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<math.h>\n#define s(t) scanf(\"%d\",&t)\n#define sl(t) scanf(\"%ld\",&t)\n#define sll(t) scanf(\"%d\",&t)\n#define p(t) printf(\"%d\\n\",t)\n#define pl(t) printf(\"%ld\\n\",t)\n#define pll(t) printf(\"%lld\\n\",t)\n#define p2(m,n) printf(\"%d %d\\n\",m,n)\n#define s2(m,n) scanf(\"%d %d\",&m,&n)\n#define f(i,j) for(i=0;i<j;i++)\n#define f2(i,j,k,l) for(i=0;i<j;i++) for(k=0;k<l;k++) printf(\"%d\\n\",t)\n#define ret(t) return(t)\n#define ll long long int\n#define lm long int\n /*bitset <max+1> p;\n int size;\n int prime[79000];\n\n void sieve(){\n size=0;\n long long i,j;\n p.set(0,1);\n p.set(1,1);\n prime[size++]=2;\n for(i=3;i<max+1;i=i+2){\n    if(!p.test(i)){\n        prime[size++]=i;\n        for(j=i;j*i<max+1;j++){\n            p.set(j*i,1);\n        }\n    }\n   }\n   }*/\nint main()\n{\n    int f=0,i,j=0;\n    char ch[105],a[1000];\n    scanf(\"%s\",ch);\n\n    for( i=0;ch[i]!='\\0';i++)\n    {   if(ch[i]=='+')\n        {\n            a[j++]='1';\n            a[j++]='0';\n            a[j++]='1';\n            a[j++]='0';\n        }\n        else if(ch[i]=='>')\n        {\n            a[j++]='1';\n            a[j++]='0';\n            a[j++]='0';\n            a[j++]='0';\n        }\n        else if(ch[i]=='<')\n        {\n            a[j++]='1';\n            a[j++]='0';\n            a[j++]='0';\n            a[j++]='1';\n        }\n        else if(ch[i]=='-')\n        {\n            a[j++]='1';\n            a[j++]='0';\n            a[j++]='1';\n            a[j++]='1';\n        }\n        else if(ch[i]=='.')\n        {\n            a[j++]='1';\n            a[j++]='1';\n            a[j++]='0';\n            a[j++]='0';\n        }\n        else if(ch[i]==',')\n        {\n            a[j++]='1';\n            a[j++]='1';\n            a[j++]='0';\n            a[j++]='1';\n        }\n        else\n            if(ch[i]=='[')\n        {\n            a[j++]='1';\n            a[j++]='1';\n            a[j++]='1';\n            a[j++]='0';\n        }\n        else //if(ch[i]=='.')\n        {\n            a[j++]='1';\n            a[j++]='1';\n            a[j++]='1';\n            a[j++]='1';\n        }\n    }\n    \n    //puts(a);\n    long long int c=0;\n    for(i=j-1;i>=0;i--)\n    {\n        if(a[i]=='1')\n            {\n                c+=pow(2,(j-1-i));\n                //printf(\"%c %d\\n\",a[i],c);\n                c%=1000003;\n            }\n           //c%=1000003;\n    }\n    //p(c%1000003);\n    printf(\"%d\\n\",c%1000003;);\n\nret(0);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "88020c6b26985b74adba319a95069f29", "src_uid": "04fc8dfb856056f35d296402ad1b2da1", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "main(n){scanf(\"%d\",&n);n++;printf(\"%d\\n\",(n/2+n&1)*n/2);}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3bb3eee5feff24d674251294903098ed", "src_uid": "f8af5dfcf841a7f105ac4c144eb51319", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main() {\n\tint n;\n\tscanf(\"%d\", &n);\n\tif(n == 1) {\n\t\tprintf(\"1\");\n\t\treturn 0;\n\t} else if(n == 2) {\n\t\tprintf(\"2\");\n\t\treturn 0;\n\t}\n\tint i = 0;\n\tn -= 3;\n\tint p = 1;\n\tfor(i = 0; i < n; ++i) {\n\t\tp *= 2;\n\t}\n\tprintf(\"%d\", n+3+p);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8e5f2b9ff7ab1aa5c57cbcfb00c9070c", "src_uid": "f8af5dfcf841a7f105ac4c144eb51319", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main()\n{\nint n,j,i;\nscanf(\"%d\",&n);\nint sum=n*(n+1)/2;\nint x=sum-n;\nif(x=1)\n    sum=sum-(1);\n    else\n        sum=sum-(2*x);\n\n\nprintf(\"%d\",sum);\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5b1bd77d15ad94cc53f09476a9e669ad", "src_uid": "f8af5dfcf841a7f105ac4c144eb51319", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main() {\n\tint n;\n\tscanf(\"%d\", &n);\n\tint i, p = 0;\n\t--n;\n\tfor(i = 1; i < n; ++i) {\n\t\t++p;\n\t}\n\tprintf(\"%d\", n+1+p);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f06f458e8448d3fc24dcb4407e835efb", "src_uid": "f8af5dfcf841a7f105ac4c144eb51319", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n//week3\nint di(int n)\n{\n    if(n==1) return 1;\n    if(n==2) return 2;\n    if(n==3) return 4;\n    if(n==4) return 6;\n    else return 2*di(n-1)-2*di(n-3)+di(n-4);\n}\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    int m=di(n);\n    printf(\"%d\\n\",m);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ee0d29944712718d209bb82a9fa41572", "src_uid": "f8af5dfcf841a7f105ac4c144eb51319", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n      int h, r;\n      scanf(\"%d\",&r);\n      scanf(\"%d\",&h);\n      printf(\"%d\",(1 + ((2*h)/r)));\n}\n      \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cadec07015f59ad7d2f9c89129ccf897", "src_uid": "ae883bf16842c181ea4bd123dee12ef9", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint r,h,vol;\nint main()\n{\n\tscanf(\" %d %d\",&r,&h);\n\n\tvol = h / r * 2;\n\th %= r;\n\tif (2*h<r)\n\t\tvol++;\n\telse if(h*2 >= sqrt(3)*r)\n\t\tvol += 3;\n\telse\n\t\tvol += 2;\n\tprintf(\"%d\",vol);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "529eef7954227c5aa17cbdf87e2b7fba", "src_uid": "ae883bf16842c181ea4bd123dee12ef9", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nmain()\n{\n\tlong long h,r;\n\tlong long t;\n\tscanf(\"%I64d %I64d\",&r,&h);\n\tt=h%r;\n\tif(2*t>=r)\n\t{\n\t\tprintf(\"%I64d\",2+h/r*2);\n\t}\n\telse\n\t{\n\t\tprintf(\"%I64d\",1+h/r*2);\n\t}\n\treturn 0;\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "afb57c812c80c010c7591490196d26b1", "src_uid": "ae883bf16842c181ea4bd123dee12ef9", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\nmain()\n{\nint h, r, ans;\nscanf(\"%d\",&r);\nscanf(\"%d\",&h);\nans = 2*h/r;\nans += ((2*m>=r)?2:1)\nans += ((2.0*m>=(sqrt(3.0)*r))?1:0);\nprintf(\"%d\",ans);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "614ae4f5add35ab9a68a86ee34d745af", "src_uid": "ae883bf16842c181ea4bd123dee12ef9", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void) {\n    // your code goes here\n    float r,h;\n    int n;\n    scanf(\"%f %f\",&r,&h);\n    if((h-r/2)%r==0&&r!=1&&h>=r){\n        h=h/r;\n        n=2+2*h;\n    }\n    else{\n        n=1+2*h/r;\n    }\n    printf(\"%d\",n);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "dd8c400e53da8f1cb9a23ae2637d154e", "src_uid": "ae883bf16842c181ea4bd123dee12ef9", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n//#include<conio.h>\n#include<math.h>\nint main()\n{\n    long int i,x,y,n,m,w;\n    long int p;\n    scanf(\"%ld %ld\",&x,&y);\n    p=sqrt(x*x+y*y);\n    if(p*p==x*x+y*y)  {printf(\"black\"); goto w; }\n    n=0;m=1;\n  if(x*y>0){  for(i=1;i<=1000;i++,n++,m++)\n    if(n*n<=x*x+y*y && m*m>=x*x+y*y)\n    { if (m%2==0) printf(\"white\");\n    else printf(\"black\");  goto w; }   } \n    else for(i=1;i<=1000;i++,n++,m++)\n    if(n*n<=x*x+y*y && m*m>=x*x+y*y)\n    { if (m%2!=0) printf(\"white\");\n    else printf(\"black\");  goto w; }\n    w: //  getch();\n    return(0);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d6d0d027586c4dc5f5794a26c84392bb", "src_uid": "8c92aac1bef5822848a136a1328346c6", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint main()\n{\n\tdouble x, y;\n\tint i = 0;\n\tint area;\n\tscanf(\"%lf%lf\", &x, &y);\n\n\t//\ufffd\u0436\ufffdx,y\ufffd\u06b5\u06bc\ufffd\ufffd\ufffd\ufffd\ufffd\n\tif (x*y==0)\n\t{\n\t\tprintf(\"black\\n\");\n\t\treturn 0;\n\t}\n\telse if (x > 0 && y > 0)\n\t{\n\t\tarea = 1;\n\t}\n\telse if (x<0 && y>0)\n\t{\n\t\tarea = 2;\n\t}\n\telse if (x < 0 && y<0)\n\t{\n\t\tarea = 3;\n\t}\n\telse\n\t\tarea = 4;\n\t//\ufffd\ufffd\ufffd\ufffd\u052d\ufffd\ufffd\u013e\ufffd\ufffd\ufffd\n\tdouble distance = sqrt(x*x + y*y);\n\ti = fabs(x) > fabs(y) ? fabs(x) : fabs(y);\n\tfor (i; i <= fabs(x) + fabs(y); i++)\n\t{\n\t\tif (distance == i)\n\t\t{\n\t\t\tprintf(\"black\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (i<distance&&i + 1>distance)\n\t\t{\n\t\t\tif (i % 2 == 0)\n\t\t\t\ti = 2;\n\t\t\telse\n\t\t\t\ti = 1;\n\t\t}\n\t}\n\t//\ufffd\ufffd\ufffd\u0772\ufffd\u036c\ufffd\ufffd\ufffd\u07a3\ufffd\ufffd\u0432\ufffd\u036c\ufffd\u0134\ufffd\ufffd\ufffd\ufffd\ufffd\n\tswitch (area)\n\t{\n\tcase 1:\n\t\tif (i == 1){\n\t\t\tprintf(\"white\\n\");\n\t\t}\n\t\telse{\n\t\t\tprintf(\"black\\n\");\n\t\t}\n\t\tbreak;\n\tcase 2:\n\t\tif (i == 1){\n\t\t\tprintf(\"black\\n\");\n\t\t}\n\t\telse{\n\t\t\tprintf(\"white\\n\");\n\t\t}\n\t\tbreak;\n\tcase 3:\n\t\tif (i == 1){\n\t\t\tprintf(\"white\\n\");\n\t\t}\n\t\telse{\n\t\t\tprintf(\"black\\n\");\n\t\t}\n\t\tbreak;\n\tcase 4:\n\t\tif (i == 1){\n\t\t\tprintf(\"black\\n\");\n\t\t}\n\t\telse{\n\t\t\tprintf(\"white\\n\");\n\t\t}\n\t\tbreak;\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "65331e4e776f55fb9d8e1a872f48fb41", "src_uid": "8c92aac1bef5822848a136a1328346c6", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n\nint main()\n{\n\tint x, y, sx, sy, pos;\n\tscanf(\"%d %d\", &x, &y);\n\n\tif((x==0)||(y==0))\n\t{\n\t\tprintf(\"black\");\n\t\treturn 0;\n\t}\n\n\tif(x>0&&y>0)\n\t\tflag=1;\n\telse if(x>0&&y<0)\n\t\tflag=2;\n\telse if(x<0&&y<0)\n\t\tflag=3;\n\telse \n\t\tflag=4;\n\n\tfloat rad, zc;\n\n\tsx=x*x;\n\tsy=y*y;\n\n\trad=(float)sqrt(sx+sy);\n\tzc=floor(rad);\n\tif((rad/zc)==1)\n\t{\n\t\tprintf(\"black\");\n\t\treturn 0;\n\t}\n\n\tif((flag==1)||(flag==3))\n\t{\n\t\tpos=(int)floor(rad);\n\t\tif(pos%2==0)\n\t\t\tprintf(\"black\");\n\t\telse\n\t\t\tprintf(\"white\");\n\t}\n\telse if((flag==2)||(flag==4))\n\t{\n\t\tpos=(int)floor(rad);\n\t\tif(pos%2==0)\n\t\t\tprintf(\"white\");\n\t\telse\n\t\t\tprintf(\"black\");\n\t}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4e42748c667233a0af2a813261ef9be1", "src_uid": "8c92aac1bef5822848a136a1328346c6", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nmain()\n{\n    int x,y,ds,f;\n    scanf(\"%d %d\",&x,&y);\n    float d;\n    ds=x*x+y*y;\n    d=sqrt(ds);\n\n    f=floor(d);\n    if(ds%f==0) f++;\n\n    if(f%2==0)\n    { if(x>0&&y>0 || x<0&&y<0)\n        printf(\"black\");\n    else printf(\"white\");}\n    else\n    {if(x>0&&y>0 || x<0&&y<0)\n        printf(\"white\");\n    else printf(\"black\");\n\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "af4b33d297d42917a8e28130fc0e0d8d", "src_uid": "8c92aac1bef5822848a136a1328346c6", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint main(void){\n\tint x,y;\n\tdouble arg,r;\n\tscanf(\"%d%d\",&x,&y);\n\targ=atan(x/y);\n\twhile(arg<0){\n\t\targ+=2*M_PI;\n\t}\n\tr=sqrt(x*x+y*y);\n\tif((arg>=0 && arg<=M_PI/2.0) || (arg>=M_PI && arg<=M_PI*3/2)) {\n\t\tif(floor(r)==r){\n\t\t\tprintf(\"black\");\n\t\t\treturn 0;\n\t\t}\t\n\t\tif((long)ceil(r)%2==1)\n\t\t\tprintf(\"black\");\n\t\telse \n\t\t\tprintf(\"white\");\n\t}\n\telse{\n\t\tif(floor(r)==r){\n\t\t\tprintf(\"black\");\n\t\t\treturn 0;\n\t\t}\t\n\t\tif((long)ceil(r)%2==1)\n\t\t\tprintf(\"white\");\n\t\telse \n\t\t\tprintf(\"black\");\n\t}\n\treturn 0;\t\t\t\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "33d273b97a45412ec17cb1205cc71316", "src_uid": "8c92aac1bef5822848a136a1328346c6", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n int main()  \n{  \n    int n,sr;  \n    bool flag;  \n    while(scanf(\"%d\",&n))  \n    {  \n       flag=0;  \n        sr=pow(2*n-3,0.5);  \n        for(int i=1;i<=sr;i++)  \n        {  \n           int k=pow(2*n-i*(i+1),0.5);     \n          if(k && k*(k+1)+i*(i+1)==2*n)  \n           {  \n               flag=1;  \n               break;  \n            }  \n       }  \n       if(flag) printf(\"YES\\n\");\n        else printf(\"NO\\n\");  \n   }  \n    return 0;  \n}  \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "33c7e5ccc0a271c35588fb50294629bf", "src_uid": "245ec0831cd817714a4e5c531bffd099", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint encontro(int n){\n  int i;\n  float aux=sqrt(n+0.25)-0.5,aux2;\n  for(i=1;i<=aux;i++){\n  aux2=sqrt(2*n-i*i-i+0.25)-0.5;\n  if(aux2==(int)aux2)\n  return 1;\n  }\n  return 0;\n}\nint main(){\n  int n;\n  scanf(\"%d\",&n)\n    if(encontro(n))\n    printf(\"YES\\n\");\n    else printf(\"NO\\n\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bb90fd085aabacf37816a8f1f8c2d0ef", "src_uid": "245ec0831cd817714a4e5c531bffd099", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>  \n#include<math.h>\n int main()  \n{  \n    int n,sr;  \n    bool flag;  \n    while(scanf(\"%d\",&n)!=EOF)  \n    {  \n       flag=0;  \n        sr=pow(2*n-3,0.5);  \n        for(int i=1;i<=sr;i++)  \n        {  \n           int k=pow(2*n-i*(i+1),0.5);     \n          if(k && k*(k+1)+i*(i+1)==2*n)  \n           {  \n               flag=1;  \n               break;  \n            }  \n       }  \n       if(flag) printf(\"YES\\n\");  \n        else printf(\"NO\\n\"); \n   }  \n    return 0;  \n}  \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "aca2c6d510c7ef0e1c2f46b95180dc26", "src_uid": "245ec0831cd817714a4e5c531bffd099", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint main()\n{\n  int n, i, k, r, x, found = 0;\n  scanf(\"%d\", &n);\n  n *= 2;\n  k = int(sqrt(n * 1.0f) + 0.5f);\n  for (i = 1; i < k; i ++)\n  {\n    r = n - i * i - i;\n    x = (int)sqrt(r * 1.0f);\n    if (x * (x + 1) == r)\n    {\n      found = 1;\n      break;\n    }\n  } \n  if (found)\n  {\n    printf(\"YES\");\n  }\n  else\n  {\n    printf(\"NO\");\n  }\n  return (0);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1d7e3eea5834797667e2fa251c4f67ff", "src_uid": "245ec0831cd817714a4e5c531bffd099", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>  \n#include<math.h>\n int main()  \n{  \n    int n,sr,flag;  \n    while(scanf(\"%d\",&n)!=EOF)  \n    {  \n       flag=0;  \n        sr=pow(2*n-3,0.5);  \n        for(int i=1;i<=sr;i++)  \n        {  \n           int k=pow(2*n-i*(i+1),0.5);     \n          if(k && k*(k+1)+i*(i+1)==2*n)  \n           {  \n               flag=1;  \n               break;  \n            }  \n       }  \n       if(flag) printf(\"YES\\n\");  \n        else printf(\"NO\\n\"); \n   }  \n    return 0;  \n}  \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "bf2ee1b3d5d9915e0a4674f9b906eb45", "src_uid": "245ec0831cd817714a4e5c531bffd099", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint n, m, highest = 0, highest_temp = 0, p[8+1], i, k, m_note, n_count, min;\nvoid permutate(int, int);\nvoid swap(int *x, int *y);\n\nint main()\n{\n    while(scanf(\"%d\", &n)!=EOF)\n    {\n        min = 9;\n        scanf(\"%d\", &m);\n        for(i = 1; i<=n; i++)\n        {\n            p[i] = i;\n        }\n        for(i = 1; i<=n; i++)\n        {\n            highest += i * (n+1-i);\n        }\n        m_note = 1;\n        if(m==1)\n        {\n            for(i = 1; i<=n; i++)\n            {\n                printf(\"%d \", p[i]);\n            }\n            printf(\"\\n\")\n        }\n        else\n        {\n            permutate(1, n);\n        }   \n    }\n    return 0;\n}\n\nvoid permutate(int start, int end)\n{\n    if(start == end)\n    {\n        \n        for(k=1; k<=n; k++)\n        {\n            n_count = n;\n            for(n_count; n_count>0; --n_count)\n            {\n                min = 9;\n                for(i=k; i<=n_count; ++i)\n                {\n                    \n                    if(p[i]<min)\n                    {\n                        min = p[i];\n                    }\n                    else{}\n                }\n                for(i=k; i<=n_count; ++i)\n                {\n                    if(p[i]==min)\n                    {\n                        highest_temp += p[i];\n                    }\n                    else{}\n                }\n            }\n        }\n        if(highest_temp >= highest)\n        {\n            ++m_note;\n            if(m_note-1==m)\n            {\n                for(i=1; i<=n; i++)\n                {\n                    printf(\"%d \", p[i]);\n                }\n                printf(\"\\n\");\n            }\n            else{}\n        }\n        else{}\n    }\n    else\n    {\n        int j;\n        for(j = start; j <= end; ++j)\n        {\n            \n            swap((p+start), (p+j));\n            permutate(start+1, end);\n            swap((p+start), (p+j));\n        }\n    }\n}\n\nvoid swap(int *x, int *y)\n{\n    int temp; \n    temp = *x;\n    *x = *y; \n    *y = temp;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6cf39f9c9305ff830202dca496b03299", "src_uid": "a8da7cbd9ddaec8e0468c6cce884e7a2", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nstatic inline long long count(int n) {\n\treturn 1ll<<(long long)(n-1);\n}\nint res[50];\nint main() {\n\tint n,m;\n\tscanf(\"%d%d\", &n, &m);\n\tint left = 0, right = n-1;\n\tint c = 1, k = n;\n\twhile(n--) {\n\t\tif ((long long)m > count(n)) {\n\t\t\tres[right] = c;\n\t\t\tright--;\n\t\t} else {\n\t\t\tres[left] = c;\n\t\t\tleft++;\n\t\t}\n\t\tc++;\n\t}\n\tint i;\n\tfor(i = 0; i < k-1; i++)\n\t\tprintf(\"%d \", res[i]);\n\tprintf(\"%d\\n\", res[k-1]);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a3cd85b7db3323b3ab0c9318718aefc4", "src_uid": "a8da7cbd9ddaec8e0468c6cce884e7a2", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nstatic inline long long count(int n) {\n\treturn 1ll<<(long long)(n-1);\n}\nint res[50];\nint main() {\n\tint n,m;\n\tscanf(\"%d%d\", &n, &m);\n\tint left = 0, right = n-1;\n\tint c = 1, k = n;\n\twhile(n--) {\n\t\tif ((long long)m > count(n)) {\n\t\t\tres[right] = c;\n\t\t\tright--;\n\t\t} else {\n\t\t\tres[left] = c;\n\t\t\tleft++;\n\t\t}\n\t\tc++;\n\t}\n\tint i;\n\tfor(i = 0; i < k-1; i++)\n\t\tprintf(\"%d \", res[i]);\n\tprintf(\"%d\\n\", res[k-1]);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "20794cae9e7cb1ee286fdb3bfe373f52", "src_uid": "a8da7cbd9ddaec8e0468c6cce884e7a2", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "/*\n *    Homework -  NCTU DCS CP\n *    =======================\n *    Student ID :    0316218\n *    GCC Option :  -lm -ansi\n *    -Wall -Wextra -pedantic\n */\n\n#include<stdio.h>\n#include<stdlib.h>\n\nint m;\nint p[50] = {0};\n\nvoid permutation(int, int, int);\n\nint main(void)\n{\n    int n;\n\n    scanf(\"%d %d\", &n, &m);\n\n    permutation(n, 0, n - 1);\n\n    return 0;\n}\n\nvoid permutation(int n, int l, int r)\n{\n    int k = n + l - r;\n\n    if (l == r)\n    {\n        p[l] = k;\n\n        if (--m == 0)\n        {\n            int i;\n\n            for (i = 0; i < n; i++)\n                printf(\"%d%c\", p[i], (i != n - 1) ? ' ' : 0);\n        }\n        else if (m < 0)\n        {\n            return;\n        }\n    }\n    else\n    {\n        p[l] = k;\n        permutation(n, l + 1, r);\n        p[r] = k;\n        permutation(n, l, r - 1);\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "434a6a0905c222a399a69d62868742bb", "src_uid": "a8da7cbd9ddaec8e0468c6cce884e7a2", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint solution[51];\nint n,m;\nint count=0;\nvoid backtrack(int x,int y,int c)\n{\n\tif(c==n)\n\t{\n\t\tsolution[x]=n;\n\t\tcount++;//minmin(1);\n\t\tif(count==m)\n\t\t{\n\t\t\tint i;\n\t\t\tfor(i=1;i<=n;i++)\n\t\t\tprintf(\"%d \",solution[i]);\n\t\t\tprintf(\"\\n\");\n\t\t}\n\t\treturn;\n\t}\n\t\n\t\tsolution[x]=c;\n\t\tbacktrack(x+1,y,c+1);\n\t\tif(count==m)\n\t\treturn;\n\t\tsolution[y]=c;\n\t\tbacktrack(x,y-1,c+1);\n\t\tif(count==m)\n\t\treturn;\n\t\t\n\n\treturn;\n}\n\n\n/*void minmin(int x)\n{\n\tif(x==n+1)\n\t{\n\t\tif(sum==ans)\n\t\tc++;\n\t\treturn;\n\t}\n\t\n\tint i,j;\n\tfor(i=x;i<=n;i++)\n\t{\t\n\t\tint MIN=100;\n\t\tfor(j=x;j<=i;j++)\n\t\t{\n\t\t\tif(MIN>solution[j])\n\t\t\t\tMIN=solution[j];\n\t\t}\n\t\tsum+=MIN;\n\t}\n\tminmin(x+1);\n\treturn;\n}*/\n\nint main()\n{\n\tscanf(\"%d %d\",&n,&m);\n\tbacktrack(1,n,1);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c7c6dc23f205b41e62cac29fd176ee20", "src_uid": "a8da7cbd9ddaec8e0468c6cce884e7a2", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n//using namespace std;\nint main()\n{\n\tlong int n,m,min,d,rem,kmin,kmax,max;\n\t\n\tcin >> n >>m;\n\tmin=n/m;\n\trem=n%m;\n\td=m-rem;\n\tkmin=((d*(min-1)*min)/2) + ((rem*(min+1)*min)/2);\n\tmax=(n-m+1);\n\tkmax=(max*(max-1))/2;\n\t\n\tcout << kmin << \" \"<< kmax;\n\treturn 0;\n\t\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3671bef8cfcd9960a4a6903378f7470f", "src_uid": "a081d400a5ce22899b91df38ba98eecc", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "int main(int argc,char const *argb[])\n{\n    long long int m,n,min,max,a,b,c;\n    scanf(\"%I64d%I64d\",&m,&n);\n    max=(m-n)*(m-n+1)/2;\n    s=m%n;\n    c=m/n;\n    b=m/n+1;\n    min=(n-a)*(c-1)*(c)/2+a*b*(b-1)/2;\n    printf(\"%I64d%I64d\\n\",min,max);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e321734f1a56b586607c1ecb599a4173", "src_uid": "a081d400a5ce22899b91df38ba98eecc", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(){\n    int n, m, Kma=0, Kmi;\n    scanf(\"%i %i\", &n, &m);\n    for (i = n-(m-1);i>0;i--)\n        Kma = Kma+(i-1);\n    if (m==1)\n       Kmi = Kma;\n    else\n       Kmi = n/2;\n    printf(\"%i %i\", Kmi, Kma);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ed3adae60c2bad7629959b4ba480002f", "src_uid": "a081d400a5ce22899b91df38ba98eecc", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "\n#include<stdio.h>\n\n\n\n long long int nCr(long long int n, long long int r)\n {\n\n     if(r == 0) return 1;\n     if(r > n) return 0;\n     if (r > n / 2) return nCr(n, n - r);\n     long long int combi = 1, i;\n     for(i = 1; i <= r; i++)\n     {\n\n         combi = combi * (n - i + 1);\n         combi = combi / i;\n     }\n     return combi;\n }\n\n int main()\n {\n\n     long long int m, n, a, b, ans1, ans2, f, d, e;\n     scanf(\"%lld %lld\", &m, &n);\n     a = m / n;\n     b = m + 1 - n;\n     e = m % n;\n     d = n - e;\n     f = a + 1;\n     ans1 = (nCr(a, 2) * d) + (nCr(f, 2) * e);\n     ans2 = nCr(b, 2);\n     cout <<ans1<<\" \"<<ans2<< endl;\n     return 0;\n }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a0b7445fb778ae55aab98284cbda5f99", "src_uid": "a081d400a5ce22899b91df38ba98eecc", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n/*int ncr(int n,int r)\n  {\n  if(r==1)\n  {\n  return n;\n  }\n  if(r==0 || r==n)\n  {\n  return 1;\n  }\n  return ncr(n-1,r)+ncr(n-1,r-1);\n  }*/\nint  nChoosek( int n, int  k )\n{\n\tif (k > n) return 0;\n\tif (k * 2 > n) k = n-k;\n\tif (k == 0) return 1;\n\n\tint result = n;\n\tfor( int i = 2; i <= k; ++i ) {\n\t\tresult *= (n-i+1);\n\t\tresult /= i;\n\t}\n\treturn result;\n}\n\nint main()\n{\n\tint i=0;\n\tint n,teams;\n\tscanf(\"%d%d\",&n,&teams);\n\tint a=n-teams+1;\n\tlong long int max=a*(a-1)/2;\n\tint pl[1000009]={0};\n\tint flag;\n\tlong long int min=0;\n\tif(t==1)\n\t{\n\t\tmin=n*(n-1)/2;\n\t}\n\telse\n\t{\n\n\t\tfor(n=n;n>0;n--)\n\t\t{\n\t\t\tpl[i]++;\n\t\t\tif(i==(teams-1))\n\t\t\t{\n\t\t\t\ti=0;\n\t\t\t}\n\t\t\telse\n\t\t\t\ti++;\n\t\t}\n\n\t\tfor(i=0;i<teams;i++)\n\t\t{\n\t\t\tmin+=nChoosek(pl[i],2);\n\t\t\t//min+=pl[i]*(pl[i]-1)/2;\n\t\t}\n\t}\n\tprintf(\"%d %d\",min,max);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0217f8831cb05070aecacf93b62c130e", "src_uid": "a081d400a5ce22899b91df38ba98eecc", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main(){\n    long long n,i;\n    scanf(\"%lli\",&n);\n    if(n%2){\n        for(i=3;i<=n;i++){\n            if((n%i)==0) break;\n        }\n        n -= i;\n        n = n/2;\n        n++\n    }\n    else n /= 2;\n    printf(\"%lli\\n\",n);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0b10bc081295ce52910a31f4461f9575", "src_uid": "a1e80ddd97026835a84f91bac8eb21e6", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint arr [1000000000];\nint main()\n{\n//    printf(\"ertyg\");\n    long long int n;\n    scanf(\"%lld\",&n);\n    if (n%2==0)\n    {\n        printf(\"%lld\",n/2);\n        return 0;\n    }\n    for (long long int i=3;i<=n;i++)\n    {\n//        printf(\"%lld\",i);\n        if (n%i==0)\n        {\n            n=n-i;\n//            printf(\"%lld %lld \",i,n);\n            break;\n        }\n    }\n    printf(\"%lld\",n/2+1);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1e1dfc4515296e03a4a0dbed241fe647", "src_uid": "a1e80ddd97026835a84f91bac8eb21e6", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <stdint.h>\n#include <inttypes.h>\n\nint main () {\n\n    uint64_t n;\n    scanf(\"%\"SCNu64, &n);\n\n    if (n % 2 == 0) {\n        printf(\"%\"PRIu64i\"\\n\", n / 2);\n    }\n    else {\n        uint64_t j = 3;\n        for ( ; j * j <= n; j += 2) {\n            if (n % j == 0) {\n                printf(\"%\"PRIu64\"\\n\", (1 + (n - j) / 2));\n                n = 1;\n                break;\n            }\n        }\n        if (n > 1) {\n            putchar('1');\n            putchar(\"\\n\");\n        }  \n    }      \n           \n    return 0;\n}\n~                                                                                                  \n~    ", "lang_cluster": "C", "compilation_error": true, "code_uid": "9014ef70697a2d4fb26fd88ef5d4ca22", "src_uid": "a1e80ddd97026835a84f91bac8eb21e6", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nlong long ai(long long n);\nint main ()\n{\n\tlong long n,i,l,p,a1,t;\n\t\n\tscanf(\"%lld\",&n);\n\tif(n%2==0) printf(\"%lld\\n\",n/2);\n\telse\n\t{\n\t\tif(ai(n))\n\t\tprintf(\"1\\n\");\n\t\telse \n\t\t{\n\t\t\tfor (i=2;i<n;i++)\n\t\t\t{\n\t\t\t\tif(n%i==0)\n\t\t\t\ta1=i;\n\t\t\t}\n\t\t\tn-=a1;\n\t\t\tt=n/2+1;\n\t\t\tprintf(\"%lld\\n\",t); \n\t\t}\n\t } \n\treturn 0;\n}\nlong long ai(long long n)\n{\n\tdouble n1;\n\tlong long i,sqr;\n\tn1=(double)n;\n\tsqr=sqrt(n1);\n\tsqr+=2;\n\tfor(i=2;i<=sqr;i++)\n\t{\n\tif (n1%i==0)\n\treturn 0;\n    }\n\treturn 1;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7d735238e4c1fbda3be9fb1f69aa9b76", "src_uid": "a1e80ddd97026835a84f91bac8eb21e6", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include<stdlib.h>\n\nint main()\n{\n    long long i,n,sum=0;\n    scanf(\"%lld\",&n);\n    if(n%2==0)\n    {\n        sum=n/2;\n    }else\n    {\n        sum=1;\n        for(i=2;i<=sqrt(n);i++)\n        {\n            if(n%i==0)\n            {\n                sum=(n-i)/2+1;\n                break;\n            }\n        }\n    }\n    printf(\"%lld\",sum);\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n#include<stdlib.h>\n\nint main()\n{\n    long long i,n,sum=0;\n    scanf(\"%lld\",&n);\n    if(n%2==0)\n    {\n        sum=n/2;\n    }else\n    {\n        sum=1;\n        for(i=2;i<=sqrt(n);i++)\n        {\n            if(n%i==0)\n            {\n                sum=(n-i)/2+1;\n                break;\n            }\n        }\n    }\n    printf(\"%lld\",sum);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e0af482dd882b9b2edd4987f3ecff41c", "src_uid": "a1e80ddd97026835a84f91bac8eb21e6", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    char a[4][4];\n    int l=0;\n    for(int i=1;i<=3;i++)\n    {\n        for(int j=1;j<=3;j++)\n        {\n            scanf(\"%d\",a[i][j]);\n        }\n    }\n    for(i=1;i<=3;i++)\n    {\n        for(j=1;j<=3;j++)\n        {\n            if(a[i][j]!=a[4-i][4-j])\n            {\n                l=1;\n                break;\n            }\n        }\n    }\n    if(l==0)\n    {\n        printf(\"YES\\n\");\n    }\n    else\n    {\n        printf(\"NO\\n\");\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7e1e871b40216ca276bde9889d01b480", "src_uid": "6a5fe5fac8a4e3993dc3423180cdd6a9", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\n#define gc getchar_unlocked \nint main()\n{\nint i,j;\nchar a[3][3]    ;\n for (i = 0; i < 3; i++) {\n      for (j = 0; j < 3; j++) {\n         //scanf(\"%c\", &a[i][j]);\n         //if ( )\n         a[i][j] = gc();\n         if( a[i][j] == ' ') a[i][j] = gc();\n      }\n   }\n  // printf(\"%c tt\" , a[1][0]);\nif(a[0][0]==a[2][2] && a[0][1]==a[2][1] && a[0][2]==a[2][0] && a[1][0]==a[1][2]){ printf(\"YES\"); }\nelse\nprintf(\"NO\");\n    \nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c2c449f7978e80936b6eb6412b6c81cd", "src_uid": "6a5fe5fac8a4e3993dc3423180cdd6a9", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define SIZE 3\n\nint hasCentalSymmetry(char** arr, int size);\n\nint main()\n{\n    char** arr;\n    arr = (char**)malloc(SIZE * sizeof(char*));\n    for (int i = 0; i < SIZE; i++)\n    {\n        arr[i] = (char*)malloc(SIZE*sizeof(char));\n    }\n    for (int i = 0; i < SIZE; i++)\n    {\n        for (int j = 0; j < SIZE; j++)\n        {\n            /*scanf(\"%c\",&arr[i][j]);*/\n            arr[i][j] = getchar();\n        }\n        getchar();\n    }\n                    \n    if(hasCentalSymmetry(arr, SIZE))\n        printf(\"YES\\n\");\n    else\n        printf(\"NO\\n\");\n    return 0;\n}\n\nint hasCentalSymmetry(char** arr, int size)\n{\n    \n    int flag = 1;\n    for (int i = 0; i < size; i++)\n    {\n        for (int j = 0; j < size; j++)\n        {\n            if(arr[i][j] != arr[size-1-i][size-1-j])\n                flag = 0;\n        }\n    }\n    return flag;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a97d15e8e315df9d685a741b72ea8e58", "src_uid": "6a5fe5fac8a4e3993dc3423180cdd6a9", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint i;\n\tfor(i=0;i<3;i++)scanf(\"%s\",s[i]);\n\tif(s[0][0]==s[2][2]&&s[0][1]==s[2][1]&&s[0][2]==s[2][0]&&s[1][0]==s[1][2])\n\tprintf(\"YES\");\n\telse \n\tprintf(\"NO\");\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7fbccb7e32d0b334d2a4f487154675fc", "src_uid": "6a5fe5fac8a4e3993dc3423180cdd6a9", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    char C[5][5];\n    int i,j;\n    for(i=0;i<3;i++)\n    {\n        scanf(\"%s\",C[i]);}\n    \n    if((C[0][0]==C[2][2])&&(C[0][1]==C[2][1])&&(C[0][2]--C[2][0])&(C[1][0]==C[1][2]))\n    printf(\"YES\");\n    else printf(\"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c1b85291f1a758045b4a4e2377d6e9ea", "src_uid": "6a5fe5fac8a4e3993dc3423180cdd6a9", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,x1,x2,x3,x4,y1,y2,y3,y4,a,b,c,d,e,f,g,h,area;\n    scanf(\"%d\",&n);\n\n    if(x1<0)\n        {\n            x1=-x1;\n        }\n        else if(y1<0)\n        {\n            y1=-y1;\n        }\n        else if(x2<0)\n        {\n            x2=-x2;\n        }\n        else if(y2<0)\n        {\n            y2=-y2;\n        }\n        else if(x3<0)\n        {\n            x3=-x3;\n        }\n        else if(y3==0)\n        {\n            y3=-y3;\n        }\n    else if(n==1)\n    {\n        scanf(\"%d %d\",&x1,&y1);\n\n         if(x1==y1)\n        {\n            printf(\"-1\");\n        }\n        else\n        {\n            printf(\"-1\");\n        }\n    }\n    else if(n==2)\n    {\n        scanf(\"%d %d %d %d\",&x1,&y1,&x2,&y2);\n\n\n       if(x1==y1 && x2==y2)\n        {\n            printf(\"1\");\n        }\n        else\n        {\n            printf(\"1\");\n        }\n    }\n    else if(n==3)\n    {\n        scanf(\"%d %d %d %d %d %d\",&x1,&y1,&x2,&y2,&x3,&y3);\n\n         if(x1==y1 && x2==y2 && x3==y3)\n        {\n            printf(\"1\");\n        }\n        else\n        {\n            printf(\"-1\");\n        }\n    }\n\n    else if(n==4)\n    {\n        scanf(\"%d %d %d %d %d %d %d %d\",&a,&b,&c,&d,&e,&f,&g,&h);\n         \n        area=0.5*(a*d+c*f+e*h+g*b-c*b-e*d-g*f-a*h);\n        if(area<0)\n        {\n            area=-area;\n        }\n        else if(area==0)\n        {\n            printf(\"-1\");\n        }\n        else\n        {\n            printf(\"%d\",area);\n        }\n    }\n\n\n\n\n    }\n    return 0;\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e4001e2c0e2a364eed9e3923765f35fb", "src_uid": "ba49b6c001bb472635f14ec62233210e", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main() {\n  int n;\n  scanf(\"%d\",&n);\n  int x[4];\n  int y[4];\n  int i;\n  for(i=0;i<n;i++) {\n    scanf(\"%d%d\",&x[i],&y[i]);\n  }\n  if(n==1) printf(\"-1\\n\");\n  else if(n==2) {\n    if(x[0]==x[1] || y[0]==y[1]) {\n      printf(\"-1\\n\");\n    } else {\n      printf(\"%d\\n\",(x[0]-x[1])*(y[0]-y[1]));\n    }\n  } else {\n    if(x[0]!=x[1] && y[0]!=y[1]) {\n      printf(\"%d\\n\",(x[0]-x[1])*(y[0]-y[1]));\n    } else if(x[0]!=x[2] && y[0]!=y[2]) {\n      printf(\"%d\\n\"\n      ", "lang_cluster": "C", "compilation_error": true, "code_uid": "ab17d63e5ce006283ba03b12816c15cf", "src_uid": "ba49b6c001bb472635f14ec62233210e", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\nint Abs(int a){return a>=0?a:-a;}\nint main()\n{ int tab[5][2],i,j,stop=0,res,n;\n  scanf(\"%d\",&n);\n  for(i=0;i<n;i++){scanf(\"%d%d\",&tab[i][0],&tab[i][1]);}\n  if(n==1){printf(\"-1\"); }\n  else\n  {\n  for(i=0;i<n;i++)\n    {\n        for(j=i+1;j<n,j++)\n           {\n           if(tab[i][0]!=tab[j][0] && tab[i][1]!=tab[j][1] )\n              {\n                    res=Abs(tab[i][0]-tab[j][0]) * Abs(tab[i][1]-tab[j][1]);\n                    printf(\"%d\",res);\n                    return 0; \n              } \n           } \n    }\nprintf(\"-1\");\n   \nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f5017e37854c8e04c8c6df4b6d11af02", "src_uid": "ba49b6c001bb472635f14ec62233210e", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,x1,x2,x3,x4,y1,y2,y3,y4,a,b,c,d,e,f,g,h,area;\n    scanf(\"%d\",&n);\n\n\n     if(n==1)\n    {\n        scanf(\"%d %d\",&x1,&y1);\n     if(x1<0)\n        {\n            x1=-x1;\n        }\n        else if(y1<0)\n        {\n            y1=-y1;\n        }\n            printf(\"-1\");\n\n    }\n    else if(n==2)\n    {\n        scanf(\"%d %d %d %d\",&x1,&y1,&x2,&y2);\n\n        area=(x1-x2)*(y1-y2);\n        if(area<0)\n        {\n            area=-area;\n        }\n\n\n         printf(\"%d\",area);\n         else if(area==0)\n         {\n             printf(\"-1\");\n         }\n\n\n    }\n    else if(n==3)\n    {\n        scanf(\"%d %d %d %d %d %d\",&x1,&y1,&x2,&y2,&x3,&y3);\n        if(x1<0)\n        {\n            x1=-x1;\n        }\n        else if(y1<0)\n        {\n            y1=-y1;\n        }\n        else if(x2<0)\n        {\n            x2=-x2;\n        }\n        else if(y2<0)\n        {\n            y2=-y2;\n        }\n        else if(x3<0)\n        {\n            x3=-x3;\n        }\n        else if(y3==0)\n        {\n            y3=-y3;\n        }\n\n\n        else if(x1==y1 && x2==y2 && x3==y3)\n        {\n            printf(\"1\");\n        }\n        else\n        {\n            printf(\"-1\");\n        }\n    }\n\n    else if(n==4)\n    {\n        scanf(\"%d %d %d %d %d %d %d %d\",&x1,&y1,&x2,&y2,&x3,&y3,&x4,&y4);\n\n        area=(y1-y2)*(x1-x4);\n        if(area<0)\n        {\n            area=-area;\n        }\n       printf(\"%d\",area);\n    }\n\n\n\n\n    }\n\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9e37ac4c4ce123d44e0da242e5bcbdd3", "src_uid": "ba49b6c001bb472635f14ec62233210e", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"CodeForce 331\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/CodeForce 331\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/CodeForce 331\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "be0a10081adaeecbcfc43c4b664f2eb8", "src_uid": "ba49b6c001bb472635f14ec62233210e", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<cstdio>\n\nstruct Utensils\n{\n\tint num;\n\tint count;\n};\n\nint main()\n{\n\tint n,k;\n\twhile((scanf(\"%d%d\",&n,&k))!=-1)\n\t{\n\t\tint i,j,iCount=0,ok,u[n],setnum = 0;\n\t\tstruct Utensils U[n];\n\t\tfor(i = 0;i < n;i++) scanf(\"%d\",&u[i]);\n\t\tfor(i = 0;i < n;i++)\n\t\t{\n\t\t\tok = 1;\n\t\t\tfor(j = 0;j<iCount;j++)\n\t\t\t{\n\t\t\t\tif(U[j].num == u[i])\n\t\t\t\t{\n\t\t\t\t\tU[j].count++;\n\t\t\t\t\tok = 0;\n\t\t\t\t\tbreak;\n\t\t\t\t}\t\n\t\t\t}\n\t\t\tif(ok) \n\t\t\t{\n\t\t\t\tU[iCount].num = u[i];\n\t\t\t\tU[iCount++].count = 1;\n\t\t\t}\n\t\t}\n\t\tfor(i = 0;i < iCount;i++)\n\t\t{\n\t\t\tif(setnum < (U[i].count-1)/k+1) setnum = (U[i].count-1)/k+1;\n\t\t}\n\t\tprintf(\"%d\\n\",setnum*iCount*k-n);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0053cd3ae67e19235d205a483b3076fb", "src_uid": "c03ff0bc6a8c4ce5372194e8ea18527f", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nvoid main()\n {\n     int n=0,k=0,c=0,d=0,i=0,s=0,somonan=0,temp,m[1000];\n     scanf(\"%d%d\",&n,&k);\n     for(i=0;i<n;i++)\n     {\n         scanf(\"%d\",&m[i]);\n     }\n     for(i=0;i<n;i++)\n     {\n        for(c=0;c<n;c++)\n        {\n            if(m[c]>m[c+1])\n            {\n                temp=m[c];\n                m[c]=m[c+1];\n                m[c+1]=temp;\n            }\n        }\n     }\n     c=0,temp=1;\n     for(i=0;i<n;i++)\n     {\n         if(m[i]==m[i+1])\n         {\n             temp++;\n         }\n         else\n         {\n             d++;\n            if(temp>c)\n            {\n                c=temp;\n            }\n            temp=1;\n         }\n     }\n     if(c<k)\n     {\n         somonan=1;\n     }\n     else if(c==k)\n     {\n         somonan=1;\n     }\n     else\n     {\n         somonan=c/k+1;\n     }\n     s=somonan*d*k-n;\n     printf(\"%d\",s);\n }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cd9c774b07c00f44e9c790c853c08fcb", "src_uid": "c03ff0bc6a8c4ce5372194e8ea18527f", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nvoid main()\n{\n\tint n,k,max=0,temp,count=0,res,i=0,p;\n\tint utensil[101]={0};\n\tscanf(\"%d %d\",&n,&k);\n\twhile(i<n)\n\t{\n\t\tscanf(\"%d\",&temp);\n\t\tif(utensil[temp]==0)\n\t\t{\n\t\t\tcount++;\n\t\t}\n\t\tutensil[temp]++;\n\t\tif(utensil[temp]>max)\n\t\t{\n\t\t\tmax=utensil[temp];\n\t\t}\n\t\ti++;\n\t}\n\tp=(max+k-1)/k;\n\tres=(p*count*k)-n;\n\tprintf(\"%d\",res);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6b2009a2088ef26ef5e03956a231e9fd", "src_uid": "c03ff0bc6a8c4ce5372194e8ea18527f", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": " #include<stdio.h>\n#include<stdlib.h>\nvoid main()\n{\n\tint n ;\n\tint k; \n\tprintf(\"donner le nombre de reamining utensels : \");\n\tscanf(\"%d\",&n);\n\tprintf(\"donner le nombre de guest\");\n\tscanf(\"%d\",&k);\n\tint* tab ;\n\ttab=malloc(n*sizeof(int));\n\tint i ; \n\tint inter[101]={0};\n\tint max=0 , out=0;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tprintf(\"donner le type de utensel\");\n\t\tscanf(\"%d\",&tab[i]);\n\t\tinter[tab[i]]++;\n\t\tif(\tinter[tab[i]]>max)\n\t\t{\n\t\t\tmax=inter[tab[i]];\n\t\t}\n\t}\n\twhile(max%k)\n\t{\n\t\tmax++;\n\t}\n\tfor(i=1;i<101;i++)\n\t{\n\t\tif(inter[i]!=0)\n\t\t{\n\t\tout+=max-inter[i];\n\t\t}\n\t}\n\tprintf(\"\\n%d\",out);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ca1573ea7d3c751141fbe1dcf703dfd0", "src_uid": "c03ff0bc6a8c4ce5372194e8ea18527f", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nvoid main()\n {\n     int n=0,k=0,c=0,d=0,i=0,s=0,somonan=0,temp,m[1000];\n     scanf(\"%d%d\",&n,&k);\n     for(i=0;i<n;i++)\n     {\n         scanf(\"%d\",&m[i]);\n     }\n     for(i=0;i<n;i++)\n     {\n        for(c=0;c<n;c++)\n        {\n            if(m[c]>m[c+1])\n            {\n                temp=m[c];\n                m[c]=m[c+1];\n                m[c+1]=temp;\n            }\n        }\n     }\n     c=0,temp=1;\n     for(i=0;i<n;i++)\n     {\n         if(m[i]==m[i+1])\n         {\n             temp++;\n         }\n         else\n         {\n             d++;\n            if(temp>c)\n            {\n                c=temp;\n            }\n            temp=1;\n         }\n     }\n     if(c<k)\n     {\n         somonan=1;\n     }\n     else if(c==k)\n     {\n         somonan=1;\n     }\n     else\n     {\n         somonan=c/k+1;\n     }\n     s=somonan*d*k-n;\n     printf(\"%d\",s);\n return(0);\n }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "877fbb40cd2fc42df56a19ebf26a7d46", "src_uid": "c03ff0bc6a8c4ce5372194e8ea18527f", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <set>\n#include <iostream>\nusing namespace std;\nint a[11][11];\nvoid init(int x){\n    for(int i=1;i <= x;i++){\n        for(int j=1;j <= x;j++){\n            if(i==1||j==1)  a[i][j]=1;\n            else\n                a[i][j]=a[i][j-1] + a[i-1][j];\n        }\n    }\n}\nint main(){\n    int n;\n    init(10);\n    while(~scanf(\"%d\",&n)){\n        printf(\"%d\\n\",a[n][n]);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ae18570eac325c199a40045e63c41509", "src_uid": "2f650aae9dfeb02533149ced402b60dc", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\ninline void fri(int *x) \n{\nregister int c = getchar_unlocked();\n*x = 0;\nint neg = 0;\nfor(; ((c<48 || c>57) && c != '-'); c = getchar_unlocked());\nif(c=='-') \n{\n  neg = 1;\n  c = getchar_unlocked();\n}\nfor(; c>47 && c<58 ; c = getchar_unlocked()) \n{\n  *x = ((*x)<<1) + ((*x)<<3) + c - 48;\n}\nif(neg)\n  *x = -(*x);\n}\n\nint main()\n{\n    int n, numer = 1, denom = 1, i, j;\n    long int ans;\n    fri(&n);\n    n = n - 1;\n    j = 2 * n - 1;\n    for(i = 1;i <= j;i += 2)\n        numer *= i;\n    for(i = 1;i <= n;i++)\n        denom *= i;\n    ans = (pow(2, n) * numer) / denom;\n    printf(\"%ld\", ans);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4f545e03da661cc6cc3e9719fcdce998", "src_uid": "2f650aae9dfeb02533149ced402b60dc", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint calculating_a(int row,int column){\n    if(row==0||column=0) return 1;\n    else return calculating_a(row-1,column)+calculating(row,column-1);\n}\nint main(){\n    int n;\n    scanf(\"%d\\n\",&n);\n    int max;\n    max= calculating_a(n,n);\n    printf(\"%d\\n\",max);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dbfe614fcd7dcc74e9cc1e2f1d41cb40", "src_uid": "2f650aae9dfeb02533149ced402b60dc", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void){\n\tint n;\n\tscanf(\"%d\",&n);\n\tint a[n][n]={0};\n\tint max=1;\n\tfor(int i=0;i<n;i++)\n\t{\n\t\tfor(int j=0;j<n;j++)\n\t\t{\n\t\t\tif(i==0||j==0)\n\t\t\t\ta[i][j]=1;\n\t\t\telse\n\t\t\t\t{\n\t\t\t\t\ta[i][j]=a[i-1][j]+a[i][j-1];\n                          if(a[i][j]>=max)\n                          max=a[i][j];               \n \n                }\n\t\t}\n\t}\nprintf(\"%d\",max);\n\n\n\n\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c1cd4fdb245cc529bd7211241e0cf487", "src_uid": "2f650aae9dfeb02533149ced402b60dc", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nint n;\n    scanf(\"%d\",&n);\n    int a[n][n];\n    for(int i=0;i<n;i++)\n    {\n        a[0][i]=1;\n        a[i][0]=1;\n    }\n    for(int i=1;i<n;i++)\n    {\n        for(int j=1;j<n;j++)\n        {\n            a[i][j]=a[i-1][j]+a[i][j-1];\n        }\n    }\n    printf(\"%d\\n\",a[n-1][n-1])\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fe33c3ad69dfcc6d5d9a04db59a4cfd0", "src_uid": "2f650aae9dfeb02533149ced402b60dc", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#inlcude<math.h>\nint main()\n{\n    long i,m,n,s=1,y;\n    scanf(\"%li\",&n);\n    scanf(\"%li\",&m);\n    s=pow(2,n);\n    y=m%s;\n    printf(\"%li\",y);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "89080255fcec03fb12a64a32246ce87b", "src_uid": "c649052b549126e600691931b512022f", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include <math.h>\n\nint main(){\n\nint n,l,a,r;\n\n    scanf(\"%d\",&n);\n    scanf(\"%d\",&l);\n\n    a=(pow(2,n));\n    r=m%a;\n    printf(\"%d\\n\",r);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "51ff4b62003973dea11f2a77b1f57ce9", "src_uid": "c649052b549126e600691931b512022f", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n\nint main()\n{\n    unsigned long int n,m;\n    scanf(\"%uld\\n%uld\",&n,&m);\n    if(n>m || pow(2,n)>m)\n    printf(\"\\n%uld\",m);\n    else \n    {\n        printf(\"\\n%uld\",m%(pow(2,n)));\n    }\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "78ab6d37c354c4ef1561757834c505d7", "src_uid": "c649052b549126e600691931b512022f", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nvoid main()\n{\n   long double int n,m;\nscanf(\"%lf\",&n);\nscanf(\"%lf\",&m);\nlong double x=m%(pow(2,n));\nprintf(\"%lf\",x);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c191b0a3296bc073dc5923caf43e5242", "src_uid": "c649052b549126e600691931b512022f", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main(){\n  int done=1;two=1,n,m;\n  scanf(\"%d\",&n);\n  scanf(\"%d\",&m);\n  while(n--){\n    two=two<<1;\n    if(two>100000000){\n      printf(\"%d\",m);\n      done=0;\n      break;\n    }\n  }\n  if(done)\n    printf(\"%d\",m%two);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "26b77e058fd5ef049021fdb2856762c7", "src_uid": "c649052b549126e600691931b512022f", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "/*\n#include<stdio.h>\n\nint main(){\n    long long n;\n    while(scanf(\"%lld\", &n)){\n        if(n < 0)\n            return 0;\n\n        /**\n         * Arithmetic series 1 to n with extra 1\n\n        printf(\"%lld\\n\", 1 + n * (n + 1) / 2);\n    }\n    return 0;\n}*/\n#include<iostream>\n#include<iomanip>\n#include<string>\n#include<cstdio>\n#include<algorithm>\n#include<fstream>\nusing namespace std;\nint main()\n{\n    int arr[10],i,j,a;\n    //cin>>a;\n    while(!(cin>>a).eof()){\n    for(i=0;i<a;i++)\n    {\n        cin>>arr[i];\n    }\n    sort(arr,arr+5);\n    for(i=0;i<a;i++)\n    {\n        cout<<arr[i]<<\" \"<<endl;\n    }}\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "bf7e93ea602307713b37d4f6f9132075", "src_uid": "ae20712265d4adf293e75d016b4b82d8", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    for(scanf(\"%d\",&n);i<n;i++){\n        scanf(\"%d\",&x),C[x]++;\n    }for(i=0;i<101;i++)\n    while(C[i]--)\n    printf(\"%d\",i);\n        \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b30f17346d17f59762c5c608a6ded375", "src_uid": "ae20712265d4adf293e75d016b4b82d8", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "int t[100];\nscanf(\"%d\",&n);\nfor (i=0;i<n;i++)\n{\nscanf(\"%d\",&t[i]);\n}\nfor(i=0;i<n-1;i++)\n{\n    for(j=i+1;j<n;j++)\n    {\n\nif ( t[i] > t[j] )\n    {\nc = t[i];\nt[i] = t[j];\nt[j] = c; }}}\nfor (i=0;i<n;i++)\n{\nprintf(\"%d \", t[i]);}\nreturn 0 ;}", "lang_cluster": "C", "compilation_error": true, "code_uid": "91eeb5240e9dfbdae4428c00b8f363c2", "src_uid": "ae20712265d4adf293e75d016b4b82d8", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <bits/stdc++.h>\n\nusing namespace std;\nint main()\n{\n\n    int x;\n    cin>>x;\n    int arr[x];\n    for(int i = 0;i<x;i++)cin>>arr[i];\n    sort(arr,arr+x);\n    for(int i = 0;i<x;i++)cout<<arr[i]<<\" \";\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b289e280512a1547a202d92edd9fc5e5", "src_uid": "ae20712265d4adf293e75d016b4b82d8", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nmain()\n{\n\tint n,i,j,c, *t;\n\tdo{\n\t\tscanf(\"%d\",&n);\n\t}while(n<0 || n>100);\n\tt=(int*) malloc(sizeof(int)*n);\n\tfor(i=0;i<n;i++)\n\t{\n\t\tdo{\n\t\t\tscanf(\"%d\",&t[i]);\n\t\t}while(t[i]<0 || t[i]>=n);\n\t}\n\n\tfor(i=0;i<n-1;i++)\n\t{\n\t\tfor(j=n-1;j>i;j--)\n\t\t{\n\t\t\tif(t[j]<t[j-1])\n\t\t\t{\n\t\t\t\tc=t[j];\n\t\t\t\tt[j]=t[j-1];\n\t\t\t\tt[j-1]=c;\t\t\t\t\n\t\t\t}\n\t\t}\n\t\t\n\t}\t\n\tfor(i=0;i<n;i++)\n\t{\n\t\tprintf(\"%d \",t[i]);\n\t}\n\t\n\t", "lang_cluster": "C", "compilation_error": true, "code_uid": "d50b0c6b89c65d6f2aa296526475e80e", "src_uid": "ae20712265d4adf293e75d016b4b82d8", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include<stdlib.h>\n\nint main(void) {char a[50],temp,m[50];\nint i=0,j=0,n,p,sum=0;\n scanf(\"%d%d\",&n,&p);\n    gets(a);\n    for(i=0;i<n-1;i++)\n    {for(j=0;j<n-i-1; j++)\n    {if(a[j]>a[j+1])\n    {temp=a[j];\n    a[j]=a[j+1];\n    a[j+1]=temp;\n    }\n    }\n    }\n    m[0]=a[0];\n    sum=m[0]-96;\n    for(i=1,j=1;i<p&&j<n;j++)\n    {\n        if(a[j]!=(m[i-1]+1))\n       {m[i]=a[j];\n       sum=m[i]+sum-96;\n       i++;\n       }\n       \n    }\n    if(i==p)\n      printf(\"%d\",sum);}\n    else\n    printf(\"-1\");\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d887fe2adcac18c6db0bf39e0452e1dc", "src_uid": "56b13d313afef9dc6c6ba2758b5ea313", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include \"aplog.h\"\n\n#define\t\tN\t50\n#define\t\tHE\t0\n#define\t\tNHE\t-1\nint read_two_numbers(int *num1, int *num2);\nint read_arr_of_char_codes(int *arr, int len);\nint input_check(char c);\nint build_rocket(int numOfDetailsWeNeed, int *storage, int numOfDetails);\nvoid sort(int *arr, int len);\nvoid change(int *a, int *b);\n\nint main()\n{\n\tint numOfDetails, numOfDetailsWeNeed;\n\tint storage[N] = {0};\n\tint rc = read_two_numbers(&numOfDetails, &numOfDetailsWeNeed);\n\n\tif (!rc)  \n\t\trc = read_arr_of_char_codes(storage, numOfDetails);\n\tif (!rc)    \n\t\tprintf(\"%d\\n\", build_rocket(numOfDetailsWeNeed, storage, numOfDetails));\n\treturn rc;\n}\n\nint read_two_numbers(int *num1, int *num2)\n{\n\tif (scanf(\"%d%d\", num1, num2) != 2)\n\t\treturn NHE;\n\treturn HE;\n}\n\nint read_arr_of_char_codes(int *arr, int len)\n{\n\tchar c;\n\n\tfor (int i = 0; i < len; i++)\n\t{\n\t\tif (!(scanf(\"%c\", &c) && !input_check(c)))\n\t\t{\n\t\t\ti--;\n\t\t\tcontinue;\n\t\t}\n\n\t\t*(arr + i) = (int)c - (int)'a' + 1;\n\t}\n\n\treturn HE;\n}\n\nint input_check(char c)\n{\n\tif ('a' <= c && c <= 'z')\n\t\treturn HE;\n\n\treturn NHE;\n}\n\nint build_rocket(int numOfDetailsWeNeed, int *storage, int numOfDetails)\n{\n\tsort(storage, numOfDetails);\n\n\tint resultMass = storage[0];\n\tint weightOfLastStage = storage[0];\n\tnumOfDetailsWeNeed--;\n\n\tfor (int i = 1; i < numOfDetails && numOfDetailsWeNeed; i++)\n\t\tif (storage[i] - weightOfLastStage > 1)\n\t\t\t{\n\t\t\t\tnumOfDetailsWeNeed--;\n\t\t\t\tresultMass += weightOfLastStage = storage[i];\n\t\t\t}\n\n\n\tif (!numOfDetailsWeNeed)\n\t\treturn resultMass;\n\n\treturn NHE;\n}\n\nvoid sort(int *arr, int len)\n{\n\tfor (int flag = 1; flag;)\n\t{\n\t\tflag = 0;\n\n\t\tfor (int j = 1; j < len; j++)\n\t\t\tif (arr[j] < arr[j - 1])\n\t\t\t{\n\t\t\t\tflag = 1;\n\t\t\t\tchange(arr + j, arr + j - 1);\n\t\t\t}\n\t}\n\n\t\t\n}\t\t\n\nvoid change(int *a, int *b)\n{\n\tint t = *a;\n\t*a = *b;\n\t*b = t;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6a7529c765cd5585d75a6c325aa5ed61", "src_uid": "56b13d313afef9dc6c6ba2758b5ea313", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "//  \n\n\n#include <stdio.h>\n\n#include <string.h>\n\nint main() \n\n{\n    \n    int n , k ;\n    \n    scanf(\"%d %d\",&n,&k) ; \n    \n    char lotus[100] , eater[100] ;\n    \n    scanf(\"%s\",lotus) ;  //  char paie = getchar() ;\n    \n    char swap ;\n    \n    for( int a =  0 ; a < (n-1) ; a++ )  {\n        \n        for( int b = a+1 ; b < n ; b++ )  {\n            \n            if( lotus[a] > lotus[b] )  {\n                \n                swap = lotus[b] ;\n                \n                lotus[b] = lotus[a] ;\n                \n                lotus[a] = swap ;\n                \n            }\n            \n        }\n        \n    }\n    /*\n    //puts(lotus) ;\n    \n    strcpy(eater,lotus) ;\n    \n  //  puts(eater) ;\n    \n    int d ;\n    \n    n = strlen(eater) ;\n    \n    for( int c = 0 ; c < (n-1) ; c++ )  {\n        \n            int x = (eater[c+1] - eater[c] ) ;\n            \n            if( x == 1 )  {\n                \n                for( d = c+1 ; d < n ; d++ )  {\n                    \n                    eater[d] = eater[d+1] ;\n                    \n                }             \n                \n            }\n            \n        n-- ;\n        \n    }\n    puts(eater) ;  */\n    /*int sum = lotus[0] - 96  ;\n    for( int e = 0 ; e<k ; e++ )  {\n        \n        if( ( lotus[e+1] - lotus[e] ) > 1 )  {\n            \n            sum = sum + lotus[e+1] - 96 ;\n            \n        }\n        \n    }\n    if(sum==1 && sum<k)  printf(\"-1\\n\") ;\n        \n    else\n    printf(\"%d\\n\",sum) ;*/\n    \n    char x = ara[0] ;            // na parle za hoy arki \n    \n    int sum = x - 96 ;\n    \n    int count = 1 ;\n    \n    if(count==k) {\n        \n        printf(\"%d\\n\",sum) ;\n        \n        return 0 ;\n        \n    }\n    \n    for( int i = 0 ; i < n ; i++ )  {\n        \n        if( lotus[i] - x >= 2 )  {\n            \n            sum = sum + lotus[i] - 96 ;\n            \n            count++ ;\n            \n            x = lotus[i] ;\n            \n            if(count==k) \n            \n                            {  break ;  }\n            \n            \n            \n        }\n        \n    }\n    \n    if( count > k )  {\n        \n        printf(\"-1\\n\") ;\n        \n    }\n    \n    \n    else  {\n        \n        printf(\"%d\\n\",sum) ;\n        \n    }\n    \n    \n    \n    \n    \n    return 0 ;\n    \n    \n    \n    \n    \n    \n    \n    \n    \n    \n    \n    \n    \n    \n    \n    \n    return 0 ;\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "26cba3712748cd371d01d8904b8c4f74", "src_uid": "56b13d313afef9dc6c6ba2758b5ea313", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main()\n{\n    long long n,m,i,j=0,k=0,t,a=0,b,c,ck=0,dk=1;\n    char str[1000];\n    scanf(\"%lld %lld\",&n,&k);\n    \n    for(i =0;i < n; i++)\n    {\n        scanf(\"%s\",&str[i]);\n    }\n\n\n    \n\n        a = arr[0] - 'a';\n        ck+=a+1;\n        for(i=1; i<n; i++){\n            b = arr[i] - 'a';\n            if(abs(a-b)>1 && m>1){\n                ck+=(b+1);\n                j++;\n                dk++;\n                a = arr[i] - 'a';\n                if(j==m-1) \n                    break;\n            }\n            else{\n                continue;\n            }\n        }\n\n    if(dk<m)\n        printf(\"-1\\n\");\n    else\n        printf(\"%lld\",ck);\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "01ff5e662617cdd25ddcea9e485802e1", "src_uid": "56b13d313afef9dc6c6ba2758b5ea313", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main()\n{\n    long long n,m,i,j=0,k=0,t,a=0,b,c,ck=0,dk=1;\n    char str[1000];\n    scanf(\"%d %d\",&n,&k);\n    \n    for(i =0;i < n; i++)\n    {\n        scanf(\"%s\",&str[i]);\n    }\n\n\n    \n\n        a = arr[0] - 'a';\n        ck+=a+1;\n        for(i=1; i<n; i++){\n            b = arr[i] - 'a';\n            if(abs(a-b)>1 && m>1){\n                ck+=(b+1);\n                j++;\n                dk++;\n                a = arr[i] - 'a';\n                if(j==m-1) \n                    break;\n            }\n            else{\n                continue;\n            }\n        }\n\n    if(dk<m)\n        printf(\"-1\\n\");\n    else\n        printf(\"%lld\",ck);\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9c6c08a10fdaa313e9374f0c1519e920", "src_uid": "56b13d313afef9dc6c6ba2758b5ea313", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "include <stdio.h> \nint main ()\n{\n\tint n,m,k;\n\tscanf (\"%d %d\",&n,&m);\n\tif (n>=m)\n\t{\n\t\tfor (int i=n/2;i <=n;i++)\n\t\t{\n\t\t\tif (i%m==0)\n\t\t\tprintf (\"%d\\n\",i);\n\t\t}\n\t}\n\telse printf (\"-1\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ae26157759536ab222c370dd9f990e59", "src_uid": "0fa526ebc0b4fa3a5866c7c5b3a4656f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(void)\n{\nlong int n,m,div1,step;\nscanf(\"%d\",&n);\nscanf(\"%d\",&m);\nif(n%2!=0)\n\n{div1=((n-1)/2);\nif((div1/m)!=0)\n{\nstep=(((div1/m)+1)*m);\n}\nelse\nstep=-1;\n}\nelse \n{div1=(n/2);\nif((div1/m)!=0)\n{\nif(div1%m==0)\nstep=div1;\nelse \nif(div/m==0)\nstep=(((div1/m)+1)*m);\n}\nelse if(div/m==0)\nstep=-1;\n}\n\nprintf(\"%d\",step);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3537b3fdfa2d4b56c134ec03b7697184", "src_uid": "0fa526ebc0b4fa3a5866c7c5b3a4656f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(){\n    int n, m, move, i, flag = 1;\n\n    scanf(\"%d %d\", &n, &m);\n\n    if(n%2 == 0){\n        move = n/2;\n    }else{\n        move = (n/2)+1;\n    }\n\n    if(n == 2){\n        printf(\"2\");\n    }else if(n < m){\n        printf(\"-1\");\n    }else{\n        for(i = 1; i<=t; i++){\n            if(move%m == 0){\n                printf(\"%d\", move);\n                break;\n            }else{\n                move = (move-1) + 2;\n            }\n\n            if(i == t){\n                flag = 0;\n            }\n    }\n\n    }\n\n    if(flag == 0){\n        printf(\"-1\");\n    }\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b1a8e53ae8439a08a4ccfddba76f6d38", "src_uid": "0fa526ebc0b4fa3a5866c7c5b3a4656f", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\nusing namespace std;\nint main()\n{\nint n,m,a;\ncin>>n>>m;\nif(n<m)\ncout<<\"-1\";\n\nelse if(n==m)\ncout<<n;\n\nelse{\nif(n%2==0)\na = n/2; \nelse a = 1 + (n-1)/2;\n\nif(a%m==0)\ncout<<a;\nelse{\nint h=a/m;\na= (h+1)*m; \ncout<<a;\n}\n\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9b23864d42609dc81289ec280615853b", "src_uid": "0fa526ebc0b4fa3a5866c7c5b3a4656f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,m;\n    scanf(\"%d %d\",&n,&m);\n    for(int i=(n+1)/2;i<=n;i++)\n    {\n        if(i%m==0)\n        {printf(\"%d\",i);\n        }\n    }\n    printf(\"-1\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b71f422c2b13e12ddb3d1964e6192fec", "src_uid": "0fa526ebc0b4fa3a5866c7c5b3a4656f", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint x1, y1, x2, y2, x3, y3;\n\n\tscanf(\"%d %d %d %d %d %d\", &x1, &y1, &x2, &y2, &x3, &y3);\n\n\tif (x1 == x2 && x2 == x3 || y1 == y2 && y2 == y3)\n\t\tputs(\"1\");\n\telse if (x1 == x2 && (y2 == y3 || y1 == y3) || x1 == x3 && (y3 == y2 || y1 == y2) || x2 == x3 && (y2 == y1 || y3 == y1))\n\t\tputs(\"2\");\n\telse if (x1 == x2 || x1 == x3 || x2 == x3 || y1 == y2 || y1 == y3 || y2 == y3)\n\t\tputs(\"2\");\n\telse\n\t\tputs(\"3\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9e32bac7c3c1694a94e24f1f533ec228", "src_uid": "36fe960550e59b046202b5811343590d", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\t__int64 a1,a2,b1,b2,c1,c2;\n\twhile(scanf(\"%I64d%I64d%I64d%I64d%I64d%I64d\",&a1,&a2,&b1,&b2,&c1,&c2)!=EOF)\n\t{\n\t\tif((a1==b1&&a1==c1)||(a2==b2&&a2==c2))printf(\"1\\n\");\n\t\telse if((a1==b1&&a2==c2)||(a1==c1&&a2==b2))printf(\"2\\n\");\n\t\telse if((b1==a1&&b2==c2)||(b1==c1&&b2==a1))printf(\"2\\n\");\n\t\telse if((c1==a1&&c2==b2)||(c1==b1&&c2==a2))printf(\"2\\n\");\n\t\telse printf(\"3\\n\");\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "2d77355763b55b3ae95dca225de50b46", "src_uid": "36fe960550e59b046202b5811343590d", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint main()\n{\n    int x1,y1;\n    scanf(\"%d%d\",&x1,&y1);\n    int x2,y2;\n    scanf(\"%d%d\",&x2,&y2);\n    int x3,y3;\n    scanf(\"%d%d\",&x3,&y3);\n    if((x1==x2&&x1==x3)||(y1==y2&&y1==y3))\n    {\n        printf(\"1\\n\");\n        return 0;\n    }\n    if((x1==x2&&x1!=x3)||(y1==y2&&y1!=y3)||(x1==x3&&x1!=x2)||(y1==y3&&y1!=y2))\n    {\n        printf(\"2\\n\");\n        return 0;\n    }\n    if((x1!=x2&&x1!=x3)||(y1!=y2&&y1!=y3))\n    {\n        printf(\"3\\n\");\n        return 0;\n    }\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d89411abbc69713b87587437b44ac51d", "src_uid": "36fe960550e59b046202b5811343590d", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain(){\n\tint x1,y1,x2,y2,x3,y3;\n\tscanf(\"%d %d %d %d %d %d\",&x1,&y1,&x2,&y2,&x3,&y3);\n\tif((x1==x2&&x1==x3)||(y1==y2&&y1==y3))\n\tprintf(\"1\");\n\telse if(x1==x2&&(y3-y1)*(y3-y2)>=0)\n\tprintf(\"2\");\n\telse if(x1==x3&&(y2-y1)*(y2-y3)=>0)\n\tprintf(\"2\");\n\telse if(x2==x3&&(y1-y2)*(y1-y3)>=0)\n\tprintf(\"2\");\n\telse if(y1==y2&&(x3-x1)*(x3-x2)>=0)\n\tprintf(\"2\");\n\telse if(y1==y3&&(x2-x1)*(x2-x3)>=0)\n\tprintf(\"2\");\n\telse if(y2==y3&&(x1-x2)*(x1-x3)>=0)\n\tprintf(\"2\");\n\telse \n\tprintf(\"3\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c1f194490a63d78dbe78c349dde2e19c", "src_uid": "36fe960550e59b046202b5811343590d", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint f(int x,int i, int j, int k)\n{\n\treturn (x[k] == x[i] || x[k] == x[j]);\n}\n\nint main()\n{\n\tint x[3],y[3];\n\tint i;\n\tfor(i=0;i<3;i++)\n\t{\n\t\tscanf(\"%d %d\",&x[i],&y[i]);\n\t}\n\n\tint ans = 0,int flag=0;\n\tif((x[0] == x[1] && x[1] == x[2]) && (y[0] == y[1] && y[1] == y[2]))\n\t\tans = 1;\n\telse\n\t{\n\t\tif(f(0,1,2) || f(0,2,1) || f(1,2,0))\n\t\t\tans = 2;\n\t\telse\n\t\t\tans = 3;\n\t}\n\n\tprintf(\"%d\",ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a9636fd0a325d7a58008b170c74adb0f", "src_uid": "36fe960550e59b046202b5811343590d", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int a,b,s=0;\n    scanf(\"%d%d\",&a,&b);\n    while(a<=b)\n    {\n        sum+=1;\n        a*=3;\n        b*=2;\n    }\n    printf(\"%d\",sum);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ae208e299cf2ef06af650ac8044ae9a3", "src_uid": "a1583b07a9d093e887f73cc5c29e444a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "bear.c", "lang_cluster": "C", "compilation_error": true, "code_uid": "9b092b987c521aad4a6691fb5021efa0", "src_uid": "a1583b07a9d093e887f73cc5c29e444a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(void)\n{\n    int a,b,i;\n    scanf(\"%d %d\",&a,&b);\n    for(i=1;a<b;i++)\n    {\n        a*=3\uff1b\n        b*=2\uff1b\n    }\n    printf(\"%d\",i);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d539a13d0eb193e2a63bb30e061e74b1", "src_uid": "a1583b07a9d093e887f73cc5c29e444a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{int a,b;\nint count=0;\n\n//printf(\"enter a and b\");\n//scanf(\"a=%d b=%d\",&a,&b);\nwhile(a<b){\n a=a*3;\nb=b*2;\ncount++;\n}\nscanf(\"count=%d\",&count)\nprintf(\"%d\",count);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "862f5110e23891a343fdc7f51773c185", "src_uid": "a1583b07a9d093e887f73cc5c29e444a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n \nint main(){\n    int i, a,b;\n    \n    scanf(\"%d %d\" ,&a , &b);\n    if(1<=a && a<=b && b<=10 ){\n    for (i=1;i<=10;i++)\n    {\n if(a<=b){\n        a=a*3;\n        b=b*2;\n        \n }\n  eles if (a>b)\n        {\n            printf(\"%d\",i);\n            break;\n        }\n       \n    }\n    \n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fb846ca6fa812283d778f50d4b7c2525", "src_uid": "a1583b07a9d093e887f73cc5c29e444a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main(void){\n    int min[4]={0},max[4]={0},ans[4]={0};\n    int num;\n    int remain;\n    scanf(\"%d\",&num);\n    scanf(\"%d %d\",&min[1],&max[1]);\n    scanf(\"%d %d\",&min[2],&max[2]);\n    scanf(\"%d %d\",&min[3],&max[3]);\n    for(int i=1;i<4;i++){\n        num=num-min[i];\n        ans[i]=min[i];\n    }\n    while(num>0){\n        if(max[1]-min[1]>0){\n            num--;\n            max[1]--;\n            ans++;\n        }\n        else if(max[2]-min[2]>0){\n            num--;\n            max[2]--;\n            ans++;\n        }\n        else if(max[3]-min[3]>0){\n            num--;\n            max[3]--;\n            ans++;\n        }\n    }\n    printf(\"%d %d %d\\n\",ans[1],ans[2],ans[3]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3bfca58e0452478d82385406c78dbe4f", "src_uid": "3cd092b6507079518cf206deab21cf97", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int i,n,a,b,c,j,max[3],min[3],min_total=0,max_total=0,x=0,y=0,z;\n    scanf(\"%d\",&n);\n    for(i=0;i<3;i++)\n    {\n         scanf(\"%d %d\",&min[i],&max[i]);\n         if(max[i]>x)\n         {\n             x=max[i];\n             y=i;\n         }\n\n         min_total+=min[i];\n         max_total+=max[i];\n    }\n\n\n        if(min_total==n)\n        {\n            printf(\"%d %d %d\",min[0],min[1],min[2]);\n            break;\n\n        }\n            else if(max_total==n)\n        {\n            printf(\"%d %d %d\",max[0],max[1],max[2]);\n            break;\n        }\n        else\n        {\n            printf(\"%d %d %d\",(max[0]+min[0])/2,(max[1]+min[1])/2,(max[2]+min[2])/2);\n\n        }\n\n        return 0;\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b88934f50114a273bd93a7fde5edd8ed", "src_uid": "3cd092b6507079518cf206deab21cf97", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "/*\n ============================================================================\n Name        : diplomas.c\n Author      : \n Version     :\n Copyright   : Your copyright notice\n Description : Hello World in C, Ansi-style\n ============================================================================\n */\n\n#include <stdio.h>\n#include <stdlib.h>\n\nint main(void) {\n    int n;\n    scanf(\"%i\",&n);\n    if ( n >= 3 && n <= 3000000)\n    {\n        int min1,min2,min3;\n        int max1,max2,max3;\n        scanf(\"%i\",&min1);\n        scanf(\"%i\",&max1);\n        scanf(\"%i\",&min2);\n        scanf(\"%i\",&max2);\n        scanf(\"%i\",&min3);\n        scanf(\"%i\",&max3);\n        //if((min1 > 1) && (max1 > min1) && (1000000 > max1) && (min2 > 1) && (max2 > min2) && (1000000 > max2) && (min3 > 1) && (max3 > min3) && (1000000 > max3) )\n        //{\n            int n1 = min1;\n            int n2 = min2;\n            int n3 = min3;\n            for(int i = 0;  n1 + n2 + n3 < n ; i++)\n            {\n                if ( n3 < max3 )\n                {\n                    n3++;\n                }\n                else if ( n2 < max2 )\n                {\n                    n2++;\n                }\n                else\n                {\n                    n1++;\n                }\n            }\n            printf(\"%i %i %i\",n1,n2,n3);\n            fflush(stdout);\n            return 0;\n        //}\n        //else\n            //return 0;\n    }\n    else\n        return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "22b502254a36b045f67afb8d61c3d8a6", "src_uid": "3cd092b6507079518cf206deab21cf97", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    int array[3][2];\n    scanf(\"%d\",&n);\n    for(i=0;i<3;i++)\n        scanf(\"%d %d\",array[i][0],array[i][1]);\n    int x,y,z;\n    z=n-(array[1][0]+array[2][0]);\n    if(z<=array[0][1])\n    {\n        printf(\"%d %d %d\",z,array[1][0],array[2][0]);\n        return 0;\n    }\n    y=array[1][0]+array[0][1]-z;\n    z=array[0][1]-z;\n    if(y<=array[1][1])\n    {\n        printf(\"%d %d %d\",z,y,array[2][0]);\n        return 0;\n    }\n    x=array[2][0]+array[1][1]-y;\n    printf(\"%d %d %d\",z,y,x);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1e75211449442cbfe5e5b6a35200f9d6", "src_uid": "3cd092b6507079518cf206deab21cf97", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "/* https://codeforces.com/contest/557/submission/35304038 (rainboy) */\n#include <stdio.h>\n\u00a0\nint main() {\n\tint n, min1, max1, min2, max2, min3, max3, a, b, c;\n\u00a0\n\tscanf(\"%d%d%d%d%d%d%d\", &n, &min1, &max1, &min2, &max2, &min3, &max3);\n\ta = max1 < n - min2 - min3 ? max1 : n - min2 - min3;\n\tb = max2 < n - a - min3 ? max2 : n - a - min3;\n\tc = max3 < n - a - b ? max3 : n - a - b;\n\tprintf(\"%d %d %d\\n\", a, b, c);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a3f81a1dd04d2a9b6ef5a3bf10493956", "src_uid": "3cd092b6507079518cf206deab21cf97", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int a, b, c;\n\n    scanf(\"%d%d\", %a, %b);\n\n    c=a+b;\n\n    printf(\"%d\", c);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "40c3a5115ac7ebd7dc5738e651fe4ed2", "src_uid": "b6e3f9c9b124ec3ec20eb8fcea075add", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<cstdio>\nusing namespace std;\nint main()\n{\nint a,b;\nscanf(\"%d %d\",&a,&b);\nprintf(\"%d\",a+b);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "52d85a6f6789f57c9f27a23ac1ee0394", "src_uid": "b6e3f9c9b124ec3ec20eb8fcea075add", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\t\u00a0\n\tint a,b;\n\tscanf(\"%d %d\",&a,&b);\n\t\t\t\tprintf(\"%d\",a + b);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ab1ff9d2a74b1843f7f475086c5cdbd3", "src_uid": "b6e3f9c9b124ec3ec20eb8fcea075add", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "include<stdio.h>\n#include<math.h>\nint main()\n{\n        int a,b;\n        scanf(\"%d %d\",&a,&b);\n        printf(\"%d\",a+b);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "301867486d5a696c19a525585ecedf79", "src_uid": "b6e3f9c9b124ec3ec20eb8fcea075add", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "include<stdio.h>\nint main(){\n//Cf chudi\nlong long int a,b;\nscanf(\"%lli%lli\",a,b);\nprintf(\"%lli\",a+b);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "147d00605e43ac33911285ba6f2e1f45", "src_uid": "b6e3f9c9b124ec3ec20eb8fcea075add", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main(void){\n    int a[3];\n    int min, max;\n\n    scanf(\"%d %d %d\", &a[0], &a[1], &a[2]);\n\n    printf(\"%d\", (a[0]+a[1]+a[2])/3)\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "daeac5e17d33f7c80b8de214868376e4", "src_uid": "7bffa6e8d2d21bbb3b7f4aec109b3319", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nvoid main(){//codeforces\n\n    int n,a[3],j = 0;\n    scanf(\"%d %d %d\",&a[0],&a[1],&a[2]);\n\n    qsort(a, 3, sizeof(a[0]), menorParaMaior);\n\n    j = a[1]-a[0]+ a[2]-a[1];\n\n    printf(\"%d\\n\",j);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e3c6a0434a98619b867963af429218d5", "src_uid": "7bffa6e8d2d21bbb3b7f4aec109b3319", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<algorithm>\nusing namespace std;\nint main()\n{\n    long long int n,i;\n    long long int a[3];\n    for(i=0;i<3;i++)\n    {\n        cin>>a[i];\n    }\n    sort(a,a+3);\n    cout<<(a[1]-a[0])+(a[2]-a[1]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d5acf68f95ef8a9d496e48185286452a", "src_uid": "7bffa6e8d2d21bbb3b7f4aec109b3319", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main() {\n\tint x,i,j,t;\n\tscanf(\"%d %d %d\",&x[0],&x[1],&x[2]);\n\tfor(i=0;i<3;i++)\n\t  for(j=i+1;j<3;j++)\n\t     if(a[i]<a[j]) t=a[i],a[i]=a[j],a[j]=t;\n\tprintf(\"%d\\n\",a[0]-a[2]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "790038c71a66edc78c81e129f33d3e5f", "src_uid": "7bffa6e8d2d21bbb3b7f4aec109b3319", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main()\n{\n    int x1,x2,x3,y,z;\n    scanf(\"%d %d %d\",&x1,&x2,&x3);\n    if(x1 > x3 && x3 > x2 )\n    {\n        printf(\"%d\\n\",(x1-x3)+(x3-x2));\n    }\n    else if(x1 > x3 && x2 > x3)\n    {\n        printf(\"%d\\n\",(x1-x2)+(x2-x3));\n    }\n    else if(x3 > x1 && x3 > x2)\n    {\n        printf(\"%d\\n\",(x2-x1)+(x3-x2));\n    }\n    else if(x3 > x1 && x2 > x3)\n    {\n        printf(\"%d\\n\",(x3-x1)+(x2-x3));\n    }\n    else if(x3 > x1 && x1  > x2)\n    {\n        printf(\"%d\\n\",((x3-x1)+(x1-x2)));\n    }\n    else\n    {\n        printf(\"%d\\n\",((x1-x3)+(x2-x1));\n    }\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c876612fe80a71a057efc0baeef7988d", "src_uid": "7bffa6e8d2d21bbb3b7f4aec109b3319", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n\nint cmp(const void *a, const void *b);\nvoid swap(char *a, char *b);\n\nint main(void)\n{\n\tchar n[100];\n\tchar m[100];\n\tscanf(\"%s%s\", &n, &m);\n\t\n\tint n_length = strlen(n);\n\tint m_length = strlen(m);\n\tqsort(n, n_length, sizeof(char), cmp);\n\t\n\tint i = 0;\n\twhile (n[i] == '0' && i < n_length) {\n\t\ti++;\n\t}\n\tswap(n + 0, n + i);\n\t\n\tint result = 1;\n\tif (n_length != m_length) {\n\t\tresult = 0;\n\t} else {\n\t\tfor (i = 0; i < n_length; i++) {\n\t\t\tif (n[i] != m[i]) {\n\t\t\t\tresult = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%s\\n\", n);\n\tif (result == 1) {\n\t\tprintf(\"OK\\n\");\n\t} else {\n\t\tprintf(\"WRONG_ANSWER\\n\");\n\t}\n\tgetch();\n\treturn 0;\n}\n\nint cmp(const void *a, const void *b)\n{\n\treturn *(char *)a - *(char *)b;\n}\n\nvoid swap(char *a, char *b)\n{\n\tchar temp = *a;\n\t*a = *b;\n\t*b = temp;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "72f0902b87156e335938a795f2bba9a4", "src_uid": "d1e381b72a6c09a0723cfe72c0917372", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main ()\n{\n\tchar min=':',str[15],arr[15];\n\tgets(str);\n\tgets(arr);\n\tint i,j,t,k;\n\tt = strlen(str);\n\tk= strlen(arr);\n\tif (t ! = k)\n\t{\n\t\tprintf(\"WRONG_ANSWER\");\n\treturn 0;\n\t}\n\tfor (i=0;i<t;i++)\n\t{\n\t\tfor (j=0;j<t;j++)\n\t\t\tif (str[j] < min && !(i == 0 && str[j] =='0'))\n\t\t\t{\n\t\t\t\tmin=str[j];\n\t\t\t\tk=j;\n\t\t\t}\n\t\tstr[k] = ':';\n\t\tif (min == arr[i])\n\t\t{\n\t\t\tmin = ':';\n\t\t\tcontinue;\n\t\t}\n\t\tprintf(\"WRONG_ANSWER\");\n\t\treturn 0;\n\t}\n\tprintf(\"OK\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4915932c232c48a6fb18ce4f2cbebc14", "src_uid": "d1e381b72a6c09a0723cfe72c0917372", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{   int i,j,k=0;\n    char c[10],d[10],a[10],temp;\n   scanf(\"%s\",c);\n   scanf(\"%s\",d);\n int l=strlen(c);\nfor(i=0;i<l;i++)\n        {\n            for(j=0;j<l;j++)\n            {\n                if((c[i]<c[j]))\n                {\n                temp=c[i];\n                c[i]=c[j];\n                c[j]=temp;\n            }}\n        }\n       for(i=0;i<l;i++)\n           {\n           if(c[i]=='0')\n               k++;\n       }\n\n        temp=c[0];\n c[0]=c[k];\n c[k]=temp;\n\nif(strcmp(c,d)==0)\n    {\n    printf(\"OK\");\n\n}\n else\n     printf(\"WRONG_ANSWER\");\n        return 0;\n}\nChat conversation end\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2e9362f1a2bd2031408a75a06f9a92a3", "src_uid": "d1e381b72a6c09a0723cfe72c0917372", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint a[10];\nint main()\n{\n\tint j,store[10000];\n\tint i,d;\n\tint ch;\t\nint k;\nk=0;\nch=getchar();\na[ch-'0']++;\nwhile((ch=getchar())!='\\n'){\n\ta[ch-'0']++;\n}\nd=1;\nA:\nfor(i=0;i<=9;i++){\n\tif(a[0]==0||d==0){\n\tfor(j=0;j<a[i];j++){\n\t\t//printf(\"%d\",i);\n\tstore[k++]=i;\n\t}\n\t}\n\telse{\n\t\tfor(i=1;i<=9;i++){\n\t\t\tif(a[i]!=0){\n\t\t\t\t//printf(\"%d\", i);\n\t\t\t\tstore[k++]=i;\n\t\t\t\ta[i]--;\n\t\t\td=0;\n\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tgoto A;\n\t}\n}\ni=0;\nwhile((ch=getchar())!='\\n'){\n//printf(\"%d\",store[i]);\nif((ch-'0'-store[i])!=0){\n\tprintf(\"WRONG_ANSWER\\n\");\nreturn 0;\n}\ni++;\n}\n\nprintf(\"OK\\n\");\nreturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "40257a31a681ea0385ce81dee89e71da", "src_uid": "d1e381b72a6c09a0723cfe72c0917372", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\nint i,j,l,n;\nchar a[100],b[100],t,min;\nvoid swap(char *a,char *b)\n{\n    t=*a;*a=*b;*b=t;\n}\nint main()\n{\n    \n    while(scanf(\"%s %s\",&a,&b)!=NULL)\n    {\n        min='A';\n        l=strlen(a);\n        for(i=0;i<l;i++)\n        {\n            if(a[i]>'0') \n            {\n                if(a[i]<min) \n                {\n                    j=i;\n                    min=a[i];\n                }\n                t=a[0];\n                a[0]=a[j];\n                a[j]=t;\n            }       \n        }\n    \n    \n    for(i=1;i<l;i++)\n         for(j=i;j<l;j++)\n         {\n            if(a[i]>a[j])\n            swap(&a[i],&a[j]);\n         }\n         if(a[0]==0)printf(\"WRONG_ANSWER\\n\");\n         else {\n            if(strcmp(a,b)==0)printf(\"OK\\n\");\n            else printf(\"WRONG_ANSWER\\n\");\n         }  \n/*\nprintf(\"%c\",a[0]);\n            printf(\"%c\",a[1]);  printf(\"%c\",a[2]);  printf(\"%c\",a[3]);*/\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7e28c984fbee8452141b5619fbe4dfb6", "src_uid": "d1e381b72a6c09a0723cfe72c0917372", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "\n/*  AUTHOR:AKASH JAIN\n*   USERNAME:akash19jain    \n*   DATE:03/04/2019 \n*/\n#include<stdio.h>\n#include<math.h>\n#include<string.h>\n#include<stdlib.h>\n#include<stdbool.h>\n\nint main()\n{\n    \n    long long t=1;\n    //scanf(\"%lld\",&t);\n    while(t--)\n    {\n       long long n,ans,min=32;\n       scanf(\"%lld\",&n);\n       int arr[n];\n       for(int i=0;i<n;i++)\n       {\n           scanf(\"%d\",&arr[i]);\n           if(min>arr[i])\n                min=arr[i];\n       }\n       ans=min^arr[2];\n       ans+=2;\n       printf(\"%lld\\n\",ans);\n       \n    }\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4179af213b65f144ef15a2daa197f662", "src_uid": "a9eb85dfaa3c50ed488d41da4f29c697", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <time.h>\nint main(){\n\tint n;\n\tint arr[n];\n\tscanf(\"%d\",&n);\n\tfor(int i = 0;i<n;i++){\n\t\tscanf(\"%d\",&arr[i]);\n\t}\n\tprintf(\"%d\",arr[n-2]);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3b656585baa3508c2d96021e73d73d86", "src_uid": "a9eb85dfaa3c50ed488d41da4f29c697", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main(){\n\tint n;\n\tint arr[n];\n\tscanf(\"%d\",&n);\n\tfor(int i = 0;i<n;i++){\n\t\tscanf(\"%d\",&arr[i]);\n\t}\n\tint x;\n\tx = rand()%n;\n\tprintf(\"%d\\n\",x);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1e831309af49ea2dbe7449a58749ea98", "src_uid": "a9eb85dfaa3c50ed488d41da4f29c697", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main(){\n\tint n;\n\tint arr[n];\n\tscanf(\"%d\",&n);\n\tfor(int i = 0;i<n;i++){\n\t\tscanf(\"%d\",&arr[i]);\n\t}\n\tint x = rand() % n;\n\tprintf(\"%d\\n\",arr[x]);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "38ec3492a565d2c7e54e35b673a2d65f", "src_uid": "a9eb85dfaa3c50ed488d41da4f29c697", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint compare(const void *data1,const void *data2){\n\tint *ptr1 = (int *)data1;\n\tint *ptr2 = (int *)data2;\n\treturn (data1 < data2)? 1 : -1;\n}\nint main(){\n\tint n;\n\tint arr[100];\n\tscanf(\"%d\",&n);\n\tfor(int i = 0;i<n;i++){\n\t\tscanf(\"%d\",&arr[i]);\n\t}\n\tqsort(arr,n,sizeof(int),compare);\n\tint flag = 0;\n\tfor(int i = 0;i<n && flag == 0;i++){\n\t\tif(arr[i] %2 == 0){\n\t\t\tint fuck = arr[i];\n\t\t\tflag == 1;\n\t\t}\n\t}\n\tprintf(\"%d\\n\",fuck);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d9a1ae8fbe2e8f514bbf6b6926c7e677", "src_uid": "a9eb85dfaa3c50ed488d41da4f29c697", "difficulty": null}
{"lang": "GNU C11", "source_code": "\n/*  AUTHOR:AKASH JAIN\n*   USERNAME:akash19jain    \n*   DATE:31/03/2019 \n*/\n#include<stdio.h>\n#include<math.h>\n#include<string.h>\n#include<stdlib.h>\n#include<stdbool.h>\n\nint main()\n{\n    long long t=1;\n    //scanf(\"%lld\",&t);\n    while(t--)\n    {\n       long long n;\n       scanf(\"%lld\",&n);\n       if(n==5)\n            printf(\"1\\n\");\n        else\n            printf(\"%lld\",n%3+1);\n    }\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3f472235d5b4711bf04c4357efb2ff55", "src_uid": "c702e07fed684b7741d8337aafa005fb", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint a[] = {0,2,3,1,2,1}, n;\nint main () {\n\tscanf(\"%d\",&n);\n\tprintf(\"%d\",a[n]);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ab523daa1c865203c00fff27ea78155d", "src_uid": "c702e07fed684b7741d8337aafa005fb", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{int n;\n\nscanf(\"%d\",&n);\nprintf(\"%d\",(n==5)?1:n%3+1)\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "140979b850698e856e6e4e1a3db8f376", "src_uid": "c702e07fed684b7741d8337aafa005fb", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain () {\n\tint a[6]={0,2,3,1,2,1};\n\tscanf(\"%d\",&a);\n\tprintf(\"%d\",arr[a]);\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c3940bc16d460dacb5b49ea6e035391e", "src_uid": "c702e07fed684b7741d8337aafa005fb", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "int n;\n\nmain(){\n    scanf(\"%d\",&n);\n    if(n==5) return 1;\n    printf(\"%d\\n\",n%3+1);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "48ba40695cc00e19ec6ef53d913c564f", "src_uid": "c702e07fed684b7741d8337aafa005fb", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\nint x,t,a,b,da,db,i,j,flag=0,c,y;\n\nscanf(\"%d %d %d %d %d %d\",&x,&t,&a,&b,&da,&db);\nc=b;\n\nif(x==0)\n{\nprintf(\"YES\");\n}\n\nelse\nif(x!=0)\n{\nfor(i=0;i<t;i++)\n{\n    if(x == a-i*da||x==b-i*db)\n    {\n    printf(\"YES\");\n    return 0;\n    }\n}\n    \nfor(i=0;i<t;i++)\n{\n\n for(j=0;j<t;j++,c=c-db)\n {\n    c=b;\n   y = a+c;\n   if(x == y)\n   {\n       flag = 1;\n       break;\n   }\n}\na = a-da;\n }\nif(flag==1)\nprintf(\"YES\");\nelse\nprintf(\"NO\");\n}\n}\n\nreturn 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "67e8750431e2b86055a20dcec1a8ff8e", "src_uid": "f98168cdd72369303b82b5a7ac45c3af", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n//#include<conio.h>\n#include<string.h>\nint main ()\n{\n    int x,t,a,b,c,d,i,j,p;\n    scanf(\"%d %d %d %d %d %d\",&x,&t,&a,&b,&c,&d);\n    for(i=0;i<t;i++)\n    for(j=0;j<t;j++)\n    if(x==a+b-i*c-j*d && a-i*c>0= && b-j*d>=0) { printf(\"YES\"); goto p; }\n    printf(\"NO\");\n p: //  getch();\n    return(0);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fffc618f44adedb70a5aa778ceb16912", "src_uid": "f98168cdd72369303b82b5a7ac45c3af", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n//#include<conio.h>\n#include<string.h>\nint main ()\n{\n    int x,t,a,b,c,d,i,j,p;\n    scanf(\"%d %d %d %d %d %d\",&x,&t,&a,&b,&c,&d);\n    if(x==0){  printf(\"YES\"); goto p; }\n    if(x!=0{)for(i=0;i<t;i++)\n    for(j=0;j<t;j++)\n    if(x==a+b-i*c-j*d && a-i*c>=0 && b-j*d>=0) { printf(\"YES\"); goto p; }}\n    printf(\"NO\");\n p:  // getch();\n    return(0);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "089451ad42fb43783b6fe1256362d273", "src_uid": "f98168cdd72369303b82b5a7ac45c3af", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n//#include<conio.h>\n#include<string.h>\nint main ()\n{\n    int x,t,a,b,c,d,i,j,p;\n    scanf(\"%d %d %d %d %d %d\",&x,&t,&a,&b,&c,&d);\n    if(x==0){  printf(\"YES\");\n    if(x!=0){for(i=0;i<t;i++)\n    for(j=0;j<t;j++)\n    if(x==a+b-i*c-j*d && a-i*c>=0 && b-j*d>=0) { printf(\"YES\"); goto p; }}\n    printf(\"NO\");\n p: //  getch();\n    return(0);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4641cfefad4aaaf05a3a58c5f47ca2a5", "src_uid": "f98168cdd72369303b82b5a7ac45c3af", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n    int x,t,a,b,da,db,i,j,m,n;\n    scanf(\"%d %d %d %d %d %d\",&x,&t,&a,&b,&da,&db);\n   if(x==0) {printf(\"YES\");exit(0);}\n        for(i=0;i<t;i++)\n        for(j=0;j<t;j++)\n        {\n            m=a-(i*da)+b-(j*db);\n            if(m==x) {printf(\"YES\");exit(0);}\n\n        }\n        for(i=0;i<t;i++)\n        {\n            m=a-(i*da); n=b-(j*db);\n            if(m==x||n==x) {printf(\"YES\");exit(0);\n        }\n        printf(\"NO\");\n        return 0;\n    }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "86f1c5070b26b435d3f49cda051d94df", "src_uid": "f98168cdd72369303b82b5a7ac45c3af", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n\tint n,m,k;\n\tint r,c;\n\tscanf(\"%d %d %d\",&n,&m,&k);\n\tif(k<n){\n\t\tprintf(\"%d %d\",k+1,1);\n\t}else if(k>=n){\n\t\tr = n-(k-n)/(m-1);\n\t\tif(r%2 == 0){\n\t\t\tc = (k-n)%(m-1) + 2;\n\t\t\tprintf(\"%d %d\",r,c);\n\t\t\treturn 0;\n\t\t}else{\n\t\t\tc = m-(k-n)%(m-1);\n\t\t\tprintf(\"%d %d\",r,c);\n\t\t\treturn 0;\n\t\t}\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0c07883603d9b83c10429331ed77a6de", "src_uid": "e88bb7621c7124c54e75109a00f96301", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdint.h>\n\nint main()\n{\n\t_int64 m,n,k;\n\tscanf(\"%I64d %I64d %I64d\",&m,&n,&k);\n\n\tif(k<=m-1)\n\t{\n\t\tprintf(\"%I64d 1\\n\",k+1);\n\t}else if(k<=m+n-2)\n\t{\n\t\tprintf(\"%I64d %I64d\\n\",m,k-m+2);\n\t}else\n\t{\n\t\t_int64 line,column,count;\n\t\tk=k-m-n+2;\n\t\tcount=k/(n-1);\n\t\tk=k-count*(n-1);\n\t\tline=m-count;\n\t\tif(k!=0)\n\t\t\tline--;\n\t\tif(count%2==0)\n\t\t{\n\t\t\tcolumn=n-k+1;\n\t\t\tif(k==0)\n\t\t\t\tcolumn--;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tcolumn=2+k;\n\t\t\tif(k==1)\n\t\t\t\tcolumn--;\n\t\t}\n\n\t\tprintf(\"%I64d %I64d\\n\",line,column);\n\t}\n\treturn 0;\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "39484741d86968e125efebbdfc0d50b4", "src_uid": "e88bb7621c7124c54e75109a00f96301", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main()\n{\n\t_int64 m,n,k;\n\tscanf(\"%I64d %I64d %I64d\",&m,&n,&k);\n\n\tif(k<=m-1)\n\t{\n\t\tprintf(\"%I64d 1\\n\",k+1);\n\t}else if(k<=m+n-2)\n\t{\n\t\tprintf(\"%I64d %I64d\\n\",m,k-m+2);\n\t}else\n\t{\n\t\t_int64 line,column,count;\n\t\tk=k-m-n+2;\n\t\tcount=k/(n-1);\n\t\tk=k-count*(n-1);\n\t\tline=m-count;\n\t\tif(k!=0)\n\t\t\tline--;\n\t\tif(count%2==0)\n\t\t{\n\t\t\tcolumn=m-k+1;\n\t\t\tif(k==0)\n\t\t\t\tcolumn--;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tcolumn=2+k;\n\t\t\tif(k==1)\n\t\t\t\tcolumn--;\n\t\t}\n\n\t\tprintf(\"%I64d %I64d\\n\",line,column);\n\t}\n\treturn 0;\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "477bef7ae09f7a48d75cdd8bd94779b8", "src_uid": "e88bb7621c7124c54e75109a00f96301", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    unsigned long long int n,m,k,i,j,x=1,y=1,c=1,l,up=0,r;\n\n    scanf(\"%llu %llu %llu\",&n,&m,&k);\n\n    if(k<=(n-1)+(m-1))\n    {\n        if(k<=n-1) printf(\"%llu 1\",1+k);\n        else\n        {\n            c=k-(n-1);\n            printf(\"%llu %llu\",n,1+c);\n        }\n    }\n    else\n    {\n      //  printf(\"n=%llu m=%llu\\n\",n,m);\n        c=(n-1)+(m-1);\n        k-=c;\n        x=n;\n        y=m;\n        up=k/(m-1);\n        r=k%(m-1);\n        x-=up;\n       // printf(\"c=%llu k=%llu up=%llu r=%llu x=%llu\\n\",c,k,up,r,x);\n        if(r==0)\n        {\n            if(up%2==1) y=2;\n            if(up%2==0) y=m;\n        }\n        else if(r>0){\n            up++;\n            r--;\n            x--;\n         //   printf(\"up=%llu r=%llu x=%llu\\n\",up,r,x);\n\n            if(up%2==1)  //go left\n            {\n                for(i=1; i<=r; i++)\n                {\n                    y--;\n                 //   printf(\"x=%llu y=%llu\\n\",x,y);\n                }\n            }\n            if(up%2==0)  //go right\n            {\n                if(r==0) y=m;\n                if(r>0)\n                {\n                    for(i=1; i<=r; i++)\n                    {\n                        y++;\n                      //  printf(\"x=%llu y=%llu\\n\",x,y);\n                    }\n                }\n\n            }\n        }\n        printf(\"%llu %llu\",x,y);\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b48d1a69335b6666c76bdea36d8c721b", "src_uid": "e88bb7621c7124c54e75109a00f96301", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdint.h>\n\nint main()\n{\n\tint64_t m,n,k;\n\tscanf(\"%I64d %I64d %I64d\",&m,&n,&k);\n\n\tif(k<=m-1)\n\t{\n\t\tprintf(\"%I64d 1\\n\",k+1);\n\t}else if(k<=m+n-2)\n\t{\n\t\tprintf(\"%I64d %I64d\\n\",m,k-m+2);\n\t}else\n\t{\n\t\tint64_t line,column,count;\n\t\tk=k-m-n+2;\n\t\tcount=k/(n-1);\n\t\tk=k-count*(n-1);\n\t\tline=m-count;\n\t\tif(k!=0)\n\t\t\tline--;\n\t\tif(count%2==0)\n\t\t{\n\t\t\tcolumn=m-k+1;\n\t\t\tif(k==0)\n\t\t\t\tcolumn--;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tcolumn=2+k;\n\t\t\tif(k==1)\n\t\t\t\tcolumn--;\n\t\t}\n\n\t\tprintf(\"%I64d %I64d\\n\",line,column);\n\t}\n\treturn 0;\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "87b01c75798055dc3f6cd71cc8701704", "src_uid": "e88bb7621c7124c54e75109a00f96301", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nvoid main()\n{\n    int k,n,s,p,pack,ans,m1,m2;\n    float r1,r2;\n    scanf(\"%d %d %d %d\",&k,&n,&s,&p);\n    m1=(int)(n/s);\n    r1=n%s;\n    if(r1==0)\n    {\n        m2=(int)((k*m1)/p);\n        r2=(k*m1)%p;\n        if(r2==0)\n        {\n            ans=m2;\n            printf(\"%d\\n\",ans);\n        }\n        else if(r2!=0)\n        {\n            ans=m2+1;\n            printf(\"%d\\n\",ans);\n        }\n    }\n    else if(r1!=0)\n    {\n        m2=(int)((k*(m1+1))/p);\n        r2=(k*(m1+1))%p;\n        if(r2==0)\n        {\n            ans=m2;\n            printf(\"%d\\n\",ans);\n        }\n        else if(r2!=0)\n        {\n            ans=m2+1;\n            printf(\"%d\\n\",ans);\n        }\n    }\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "259853f1dacc2a388ec1fecbab0a239e", "src_uid": "73f0c7cfc06a9b04e4766d6aa61fc780", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "\ufeff\nMicrosoft Visual Studio Solution File, Format Version 12.00\n# Visual Studio 15\nVisualStudioVersion = 15.0.27428.2037\nMinimumVisualStudioVersion = 10.0.40219.1\nProject(\"{8BC9CEB8-8B4A-11D0-8D11-00A0C91BC942}\") = \"965A\", \"965A\\965A.vcxproj\", \"{19AC7C7E-EC0E-4529-81CB-F2BF5AC48EBE}\"\nEndProject\nGlobal\n\tGlobalSection(SolutionConfigurationPlatforms) = preSolution\n\t\tDebug|x64 = Debug|x64\n\t\tDebug|x86 = Debug|x86\n\t\tRelease|x64 = Release|x64\n\t\tRelease|x86 = Release|x86\n\tEndGlobalSection\n\tGlobalSection(ProjectConfigurationPlatforms) = postSolution\n\t\t{19AC7C7E-EC0E-4529-81CB-F2BF5AC48EBE}.Debug|x64.ActiveCfg = Debug|x64\n\t\t{19AC7C7E-EC0E-4529-81CB-F2BF5AC48EBE}.Debug|x64.Build.0 = Debug|x64\n\t\t{19AC7C7E-EC0E-4529-81CB-F2BF5AC48EBE}.Debug|x86.ActiveCfg = Debug|Win32\n\t\t{19AC7C7E-EC0E-4529-81CB-F2BF5AC48EBE}.Debug|x86.Build.0 = Debug|Win32\n\t\t{19AC7C7E-EC0E-4529-81CB-F2BF5AC48EBE}.Release|x64.ActiveCfg = Release|x64\n\t\t{19AC7C7E-EC0E-4529-81CB-F2BF5AC48EBE}.Release|x64.Build.0 = Release|x64\n\t\t{19AC7C7E-EC0E-4529-81CB-F2BF5AC48EBE}.Release|x86.ActiveCfg = Release|Win32\n\t\t{19AC7C7E-EC0E-4529-81CB-F2BF5AC48EBE}.Release|x86.Build.0 = Release|Win32\n\tEndGlobalSection\n\tGlobalSection(SolutionProperties) = preSolution\n\t\tHideSolutionNode = FALSE\n\tEndGlobalSection\n\tGlobalSection(ExtensibilityGlobals) = postSolution\n\t\tSolutionGuid = {ED5C4B44-0423-42FA-8D36-27F7125D339A}\n\tEndGlobalSection\nEndGlobal\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "774326507738d3b5ae94f8ba922adfac", "src_uid": "73f0c7cfc06a9b04e4766d6aa61fc780", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n    int sum,n,k,s,p;\n    scanf(\"%d %d %d %d\",&k,&n,&s,&p);\n    if(n%s!=0)\n        sum=(n/s)+1;\n    else\n        sum=n/s;\n    sum=sum*k;\n    if(sum%p!=0)\n        sum=(sum/p)+1;\n    else\n        sum=(sum/p);\n    printf(\"%d\",sum);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b8b70bbb78660bceffb6225228038673", "src_uid": "73f0c7cfc06a9b04e4766d6aa61fc780", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n\tlong k,n,s,p;\n\tcin >>k >>n>>s>>p;\n\tlong i=0;\n\twhile(1)\n\t{\n\t\tint sototrennguoi=(i*p)/k;\n\t\tif((sototrennguoi*s)<n)\n\t\t{\n\t\t\ti++;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tcout<<i;\n\t\t\treturn 0;\n\t\t}\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ddfa1fef454d160e20bfa9bd35b698b8", "src_uid": "73f0c7cfc06a9b04e4766d6aa61fc780", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<iostream>\nusing namespace std;\nint f(int x,int y)\n{\n\tif(x/y==0)\n\treturn 1;\n\telse if(x%y!=0)\n\treturn x/y+1;\n\telse if(x%y==0)\n\treturn x/y;\n}\nint main()\n{\n\tint k,n,s,p;\n\twhile(~scanf(\"%d%d%d%d\",&k,&n,&s,&p))\n\t{\n\t\t long long int h,j;\n\t\t h=f(n,s)*k;\n\t\t j=f(h,p);\n\t\t cout<<j<<endl;\n\t}\n\treturn 0;\n } ", "lang_cluster": "C", "compilation_error": true, "code_uid": "b7cfce1eab89c3d5df61d12dce7bbdcc", "src_uid": "73f0c7cfc06a9b04e4766d6aa61fc780", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint a[10];\nint check(int n)\n{\n    while(n) {\n        int d=n%10;\n        if(a[d])return 1;\n        n/=10;\n    }\n    return 0;\n}\nint div(int num){\n    int count=0;\n    int i;\n    for(i=1; i<=num/2; i++)  {\n        if(!(num%i)){\n            //printf(\"%d \",i);\n            if(check(i))count++;\n        }\n    }\n    return count;\n }\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    int m=n;\n    while(m){\n        int d=m%10;\n        a[d]++;\n        m/=10;\n    }\n    int num=div(n);\n    if(n==1)\n    printf(\"1\\n\");\n    else\n    printf(\"%d\\n\",num+1);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "31c1d24312f38e6b3a61ca387db97628", "src_uid": "ada94770281765f54ab264b4a1ef766e", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint cif_x[11];\nint cif_d[11];\n\nint cifra (int x, int d){\n    int cx=0, cd=0;\n    int i=0, j=0;\n    int t;\n    while (x/10 != 0){\n        cif_x[cx]=x%10;\n        x=x/10;\n        cx++;\n    }\n    cif_x[cx]=x;\n    cx++;\n    while (d/10 != 0){\n        cif_d[cd]=d%10;\n        d=d/10;\n        cd++;\n    }\n    cif_d[cd]=d;\n    cd++;\n    for (i=0; i<cx; i++){\n        for (j=0; j<cd; j++)\n            if (cif_x[i] == cif_d[j]) return 1;\n            \n    }\n    return 0;\n}\n    \n    \n\nint main(){\n    int x, d, ans;\n    ans=1;  \n    scanf (\"%d\", &x);\n    if (x == 1 || x == 2){\n        printf (\"1\\n\");\n        return 0;\n    }\n    for (d=1; d<=x/2+1; d++){\n        if (x%d == 0)\n            if (cifra (x, d) == 1) ans++;\n    }\n    printf (\"%d\\n\", ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "44cec06d4d57798ff6adbeb423e7a040", "src_uid": "ada94770281765f54ab264b4a1ef766e", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint Judge(int a,int b)\n{\n    int i;\n    int A[10],B[10];\n    memset(A,0,sizeof(A));\n    memset(B,0,sizeof(B));\n    while(a)\n    {\n        ++A[a%10];\n        a/=10;\n    }\n    while(b)\n    {\n        ++B[b%10];\n        b/=10;\n    }\n    for(i=0;i<10;++i)\n    {\n        if(A[i]&&B[i])\n        {\n            return 1;\n        }\n    }\n    return 0;\n}\n\nint main()\n{\n    int X,i,Cnt;\n    scanf(\"%d\",&X);\n    for(i=Cnt=1; i<=X/2; ++i)\n    {\n        if(X%i==0)\n        {\n            if(Judge(X,i))\n            {\n                ++Cnt;\n            }\n        }\n    }\n    printf(\"%d\\n\",Cnt);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8a5d32fa207d0a311783c248bbf9dc26", "src_uid": "ada94770281765f54ab264b4a1ef766e", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    int n,i,j=0,count=0,k,f=1,l;\n    scanf(\"%d\",&n);\nint b[11],c[11];\n  for(i=0;i<11;i++)\n  b[i]=c[i]=-1;\n  int d=n,e;\n  i=0;\n  while(d!=0)\n  {\n     e=d%10;\n     d=d/10;\n     b[i]=e;\n     i++;\n     }\n    for(i=1;i<=n/2;i++)\n    {\n                                f=1;\n                                j=0;\n                                for(l=0;l<11;l++)\n                                c[l]=-1;\n       if(n%i==0)\n       {\n            d=i;\n            while(d!=0)\n            {\n              e=d%10;\n              d=d/10;     \n               c[j]=e;\n               j++;\n               }\n       for(j=0;b[j]!=-1;j++)\n          {for(k=0;c[k]!=-1;k++)\n          {\n             if(c[k]==b[j])\n             {\n                count++;\n                f=0;\n                break;\n                }\n                }\n                if(f==0)\n                break;\n                }\n                }\n                }\n                count++;\n                printf(\"%d\\n\",count);\n                return 0;\n                }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1aa5ff0983022df45b01ed2ae7d77355", "src_uid": "ada94770281765f54ab264b4a1ef766e", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint n , divisor[30] , divisorcnt[30] , m = 0 ;\nint ans = 0 ;\n\nint bitcnt (int k) {\n\tint res = 0 ;\n\n\tfor (; k != 0 ; k /= 10)\n\t\tres |= 1 << (k%10) ;\n\n\treturn res ;\n}\n\nvoid dfs (int k , int s) {\n\tif (k == m) {\n\t\tif (bitcnt(s) & bitcnt(n))\n\t\t\t++ans ;\n\n\t\treturn ;\n\t}\n\n\tfor (int i = divisorcnt[k] ; i >= 0 ; --i) {\n\t\tdfs (k + 1 , s) ;\n\t\ts *= divisor[k] ;\n\t}\n}\n\nint main (void) {\n\tscanf (\"%d\" , &n) ;\n\n\tint j = n ;\n\tfor (int i = 2 ; i*i <= j ; ++i)\n\t\tif (j % i == 0) {\n\t\t\tdivisor[m] = i ;\n\t\t\tdivisorcnt[m] = 0 ;\n\n\t\t\tfor (; j % i == 0 ; j /= i)\n\t\t\t\t++divisorcnt[m] ;\n\n\t\t\t++m ;\n\t\t}\n\n\tif (j > 1) {\n\t\tdivisor[m] = j ;\n\t\tdivisorcnt[m] = 1 ;\n\t\t++m ;\n\t}\n\n\tdfs (0 , 1) ;\n\n\tprintf (\"%d\\n\" , ans) ;\n\treturn 0 ;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7c449393f5c4852757af417d5ec44fb9", "src_uid": "ada94770281765f54ab264b4a1ef766e", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n\n\n\nint main()\n{\n    int n,*a,i,x,j,l,k;\n    scanf(\"%d\",&n);\n    a=(int*)malloc(n*sizeof(int));\n    \n    \n    for(i=0;i<n;i++)\n        scanf(\"%d\",a+i);\n    \n    for(i=0;i<n;i++)\n    {\n        for(j=i+1;j<n;j++)\n        {\n            if(a[i]>a[j])\n            {\n                a[i]=a[i]+a[j];\n                a[j]=a[i]-a[j];\n                a[i]=a[i]-a[j];\n            }    \n        }\n    }\n    \n    x=a[0];\n    for(i=0;i<n-1;i++)\n    {\n        if(a[i]+x==a[i+1]-x)\n        {\n            l=0;\n            for(j=0;j<n;j++)\n            {\n                for(k=j+1;k<n;k++)\n                {\n                    if(a[j]+x==a[k]-x)\n                        continue;\n                    if(a[j]+x=a[k])\n                        continue;\n                    if(a[j]==a[k])\n                        continue;\n                    l=1;\n                    break;\n                }\n                if(l==1)\n                    break;\n            }\n            if(l==1)\n            {\n                x++;\n                i=-1;\n                if(x>a[n-1])\n                {\n                    printf(\"-1\");\n                    return 0;\n                }\n                continue;\n            }\n        }    \n        \n        \n        if(a[i]+x==a[i+1])\n        {\n            l=0;\n            for(j=0;j<n;j++)\n            {\n                for(k=j+1;k<n;k++)\n                {\n                    if(a[j]+x==a[k]-x)\n                        continue;\n                    if(a[j]+x=a[k])\n                        continue;\n                    if(a[j]==a[k])\n                        continue;\n                    l=1;\n                    break;\n                }\n                if(l==1)\n                    break;\n            }\n            if(l==1)\n            {\n                x++;\n                i=-1;\n                if(x>a[n-1])\n                {\n                    printf(\"-1\");\n                    return 0;\n                }\n                continue;\n            }            \n            \n        }\n        \n        if(a[i]==a[i+1])\n        {\n            l=0;\n            for(j=0;j<n;j++)\n            {\n                for(k=j+1;k<n;k++)\n                {\n                    if(a[j]+x==a[k]-x)\n                        continue;\n                    if(a[j]+x=a[k])\n                        continue;\n                    if(a[j]==a[k])\n                        continue;\n                    l=1;\n                    break;\n                }\n                if(l==1)\n                    break;\n            }\n            if(l==1)\n            {\n                x++;\n                i=-1;\n                if(x>a[n-1])\n                {\n                    printf(\"-1\");\n                    return 0;\n                }\n                continue;\n            }        \n        }\n    }\n    printf(\"%d\",x);\n    return 0;\n}\n ", "lang_cluster": "C", "compilation_error": true, "code_uid": "6d2e2137b250f704f8a5577915506750", "src_uid": "d486a88939c132848a7efdf257b9b066", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\n\nint min(int a[],int n)\n{       int min=a[0];\n        for(int i=0;i<n;i++)\n        {\n                if(a[i]<min)\n                        min=a[i];\n        }\n        return min;\n}\n\nint max(int a[],int n)\n{       int max=a[0];\n        for(int i=0;i<n;i++)\n        {\n                if(a[i]>max)\n                        max=a[i];\n        }\n        return max;\n}\n\nint makethemequal(int a[],int n)\n{\n        int mi=min(a,n),ma=max(a,n),d=(ma-mi),count=0;\n\n        for(int i=0;i<n;i++)\n        {\n                if(max=a[i]||max==a[i]+d)\n                        continue;\n                else\n                        {\n                                count=1;\n                                break;\n                        }\n        }\n        if(count==0)\n                return d;\n        else\n        {\n        for(int i=0;i<n;i++)\n        {\n                if(a[i]==mi||a[i]==ma||a[i]==mi+d)\n                        continue;\n                else\n                        return -1;\n        }\n        return d;\n        }\n}\n  \n\nint main()\n{\n        int n,p;\n        scanf(\"%d\",&n);\n        int a[n];\n        for(int i=0;i<n;i++)\n        {\n                scanf(\"%d\",&a[i]);\n        }\n        p=makethemequal(a,n);\n        printf(\"%d\",p);\n        return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4ccda1e4f66d742d37cd221067d2464f", "src_uid": "d486a88939c132848a7efdf257b9b066", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(){\n    int a, b[3], index = 0;\n    scanf(\"%d\", &a);\n    for(int i = 0; i < a; i++){\n        if(index > 3){\n            printf(\"-1\");\n            return 0;\n        }\n        scanf(\"%d\", &b[index]);\n        bool kill = true;\n        for(int e = 0; e < index && kill; e++){\n            if(b[e] == b[index]){\n                kill = false;\n            }\n        }\n        if(kill){\n            index++;\n        }\n    }\n    if(index == 1){\n        printf(\"0\");\n    } else if(index == 2){\n        int c = b[1]-b[0];\n        if(c%2 == 0){\n            c/=2;\n        }\n        printf(\"%d\", c);\n    } else {\n        for(int i = 0; i < 2; i++){\n            for(int e = i+1; e < 3; e++){\n                if(b[i] > b[e]){\n                    int sw = b[i];\n                    b[i] = b[e];\n                    b[e] = sw;\n                }\n            }\n        }\n        if(b[1]-b[0] == b[2]-b[1]){\n            printf(\"%d\", b[1]-b[0]);\n        } else {\n            printf(\"-1\");\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "66bcbbeef9a108828542c76af0a955e4", "src_uid": "d486a88939c132848a7efdf257b9b066", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<algorithm>\nusing namespace std;\nint max(int a,int b)\n{\n\tif(a>b)\n\treturn a;\n\telse\n\treturn b;\n } \nint main()\n{\n\tint i,n,max,min,flag,mid;\n\tint a[1000];\n\tfor(;scanf(\"%d\",&n)!=EOF;)\n\t{\n\t\tflag=1;\n\t\tmax=-1;\n\t\tmin=101;\n\t\tmemset(a,0,sizeof(a));\n\t\tfor(i=0;i<n;i++)\n\t\t{\n\t\t\tscanf(\"%d\",&a[i]);\n\t\t\tif(a[i]>max)\n\t\t\tmax=a[i];\n\t\t\tif(a[i]<min)\n\t\t\tmin=a[i];\n\t\t}\n\t\tsort(a,a+n);\n\t\t\n\t\tif((max-min)%2==0)\n\t\tmid=(max-min)/2;\n\t\telse\n\t\tmid=0;\n\t\t\n\t\tif(max==min)\n\t\tprintf(\"0\\n\");\n\t\telse\n\t\t{\n\t\t\tif(mid>=0)\n\t\t\tfor(i=0;i<n;i++)\n\t\t\t{\n\t\t\t\tif(a[i]!=min&&a[i]!=max&&a[i]!=mid+min)\n\t\t\t\t{\n\t\t\t\t\tflag=0;\n\t\t\t\t\tprintf(\"-1\\n\");\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(flag&&mid!=0)\n\t\t{\n\t\t\tprintf(\"%d\\n\",mid);\n\t\t}\n\t\telse if(flag)\n\t\t{\n\t\t\tprintf(\"%d\\n\",max-min);\n\t\t}\n\t}\n\treturn 0;\n } ", "lang_cluster": "C", "compilation_error": true, "code_uid": "71ab95d5b2cb496dbfc6ce00660d4eee", "src_uid": "d486a88939c132848a7efdf257b9b066", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\n\nint min(int a[],int n)\n{       int min=a[0];\n        for(int i=0;i<n;i++)\n        {\n                if(a[i]<min)\n                        min=a[i];\n        }\n        return min;\n}\n\nint max(int a[],int n)\n{       int max=a[0];\n        for(int i=0;i<n;i++)\n        {\n                if(a[i]>max)\n                        max=a[i];\n        }\n        return max;\n}\n\nint makethemequal(int a[],int n)\n{\n        int mi=min(a,n),ma=max(a,n),d=(ma-mi),count=0;\n\n        for(int i=0;i<n;i++)\n        {\n                if(max=a[i]||max=a[i]+d)\n\n                else\n                        {\n                                count=1;\n                                break;\n                        }\n        }\n        if(count==0)\n                return d;\n        else\n        {\n        for(int i=0;i<n;i++)\n        {\n                if(a[i]==mi||a[i]==ma||a[i]==mi+d)\n                        continue;\n                else\n                        return -1;\n        }\n        return d;\n        }\n}\n  \n\nint main()\n{\n        int n,p;\n        scanf(\"%d\",&n);\n        int a[n];\n        for(int i=0;i<n;i++)\n        {\n                scanf(\"%d\",&a[i]);\n        }\n        p=makethemequal(a,n);\n        printf(\"%d\",p);\n        return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "74aa06032f708e1b9920c9d19a4f648b", "src_uid": "d486a88939c132848a7efdf257b9b066", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint a[8] = {1, 2, 9, 64, 625, 7776, 117649, 2097152};\nint m = 1000000007;\n\nlong long mod_pow(long long x, long long y)\n{\n    long long ans = 1;\n    \n    while (y) {\n        if (y & 1) ans = ans * x % m;\n        \n        x = x * x % m;\n        y >>= 1;\n    }\n    \n    return ans;\n}\n\nint main()\n{\n    int n, k, i;\n    long long ans;\n    \n    scanf(\"%d %d\", &n, &k);\n    \n    ans = a[k - 1];\n    \n    ans = ans * mod_pow(n - k, n - k) % m;\n    \n    printf(\"%d\\n\", (int)ans);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c177329ab38a3054cdda69ed41d4b29b", "src_uid": "cc838bc14408f14f984a349fea9e9694", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint a[8] = {1, 2, 9, 64, 625, 7776, 117649, 2097152};\nint m = 1000000007;\n\nlong long mod_pow(long long x, long long y)\n{\n    long long ans = 1;\n    \n    while (y) {\n        if (y & 1) ans = ans * x % m;\n        \n        x = x * x % m;\n        y >>= 1;\n    }\n    \n    return ans;\n}\n\nint main()\n{\n    int n, k, i;\n    long long ans;\n    \n    scanf(\"%d %d\", &n, &k);\n    \n    ans = a[k - 1];\n    \n    ans = ans * mod_pow(n - k, n - k) % m;\n    \n    printf(\"%d\\n\", (int)ans);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ff4b5164e54e060e66eb9d86ea825d4d", "src_uid": "cc838bc14408f14f984a349fea9e9694", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define mod 1000000007\n\nint mypow(int x, int y)\n{\n\tint res = 1;\n\twhile ( y )\n\t{\n\t\tif ( y & 1 )\n\t\t\tres = res * (long long) x % mod;\n\t\tx = x * (long long) x % mod;\n\t\ty >>= 1;\n\t}\n\treturn res;\n}\n\nint main()\n{\n\tint i, k, n, res;\n\tscanf(\"%d%d\", &n, &k);\n\tif ( n < k )\n\t\tk = n;\n\tres = mypow(k, k-1) * (long long) mypow(n-k, n-k) % mod;\n\tprintf(\"%d\\n\", res);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "044332a888e2da5a34142d27bbe8d080", "src_uid": "cc838bc14408f14f984a349fea9e9694", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main() {\n\tint i, n, k, ans, mod;\n\tscanf(\"%d%d\", &n, &k);\n\tmod = 1000000007;\n\tans = 1;\n\tfor (i = 1; i <= k; ++i)\n\t\tans *= k;\n\tans /= k;\n\tfor (i = 1; i <= n - k; ++i)\n\t\tans = (ans * (n - k) % mod) % mod;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "edb218ce82bd3596c4b11d0b5db3ad74", "src_uid": "cc838bc14408f14f984a349fea9e9694", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MOD 1000000007\n\nlong long binpow(long long a, long long k)\n{\n    long long ans = 1;\n    if(a == 0) return 1;\n    while(k)\n    {\n        if(k & 1) \n        {\n            ans *= a;\n            ans %= MOD;\n        }\n        a *= 2;\n        a %= MOD;\n        k >>= 1;\n    }\n    return ans;\n}\n\nint main()\n{\n    long long n, k; \n    scanf(\"%lld %lld\", &n, &k);\n    printf(\"%lld\", binpow(k, k - 1) * binpow(n - k, n - k) % MOD);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b35929c655cc6640d6021677f1bf5079", "src_uid": "cc838bc14408f14f984a349fea9e9694", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int XP,NB,n;\n    scanf(\"%d %d\", &XP, &NB);\n    n=(XP+NB)/3;\n    if(XP==0 // NB==0)\n    {\n        printf(\"0\\n\");\n        return 0;\n    }   \n    if( n <= XP )\n    printf(\"%d\\n\", n);\n    else\n    printf(\"%d\\n\", XP);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "368b020825e94a5da37c9b039565567b", "src_uid": "0718c6afe52cd232a5e942052527f31b", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main(){\n\n    unsigned n,m;\n    scanf(\"%u %u\",&n,&m);\n\n    if(n==m){\n        printf(\"%u\",2*m/3);\n        return 0;\n    }\n    else if(n<m){\n        int temp=m;\n        m=n;\n        n=temp;\n    }\n    \n    if(n/2<m){\n        if(n%2==1){\n            if(m-n/2>=2){\n            printf(\"%u\",n/2+1);\n            }\n        }\n        else{\n            if(n>=8){\n                printf(\"%u\",n/2+Q);\n            }\n            else printf(\"&u\",n/2+2);\n        }\n    }\n    else printf(\"%u\",m);\n\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7d5fe23b04f28a4dbc60f504c9854ee1", "src_uid": "0718c6afe52cd232a5e942052527f31b", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int n, m, x, y, multiple;\n    scanf(\"%d %d\", &n, &m);\n    if(n + m < 3){\n        printf(\"0\");\n        return 0;\n    }\n    if(n == m){\n        printf(\"%d\", (n+m)/3);\n        return 0;\n    }\n    if(n == 2*m){\n        printf(\"%d\", n);\n        return 0;\n    }\n    else(m == 2*n){\n        printf(\"%d\", m);\n        return 0;\n    }\n\n\n\n    if(n > m){\n        multiple = 2 * m;\n        while(m > 0){\n            if(n < multiple){\n                multiple-=3;\n                m--;\n            }\n            else\n                break;\n\n        }\n    }\n    else{\n        multiple = 2 * n;\n        while(n > 0){\n            if(m < multiple){\n                multiple-=3;\n                n--;\n            }\n            else\n                break;\n\n        }\n    }\n    printf(\"%d\", n);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "68638d76095899d7bfdeb1433cfa71d8", "src_uid": "0718c6afe52cd232a5e942052527f31b", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main(){\n\tint m = 0, n = 0;\n\tscanf(\"%d %d\", &m, &n);\n\n\tint output = (m + n) / 3;\n\t\n\tprintf(\"%d\\n\", min(min(m, output), n));\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "60417ef64a32c1f4c3efb1232147a897", "src_uid": "0718c6afe52cd232a5e942052527f31b", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n    int x,y;int teams=0;\n    scanf(\"%d%d\",&x,&y);\n    if(n+m<3)\n    printf(\"0\");\n    else{\n    while(x>0||y>0)\n    {\n        if(x<=y)\n        {\n            if(x<=y/2)\n            {\n                teams+=x;\n                break;\n            }\n            else if(x>y/2)\n            {\n                teams++;\n                x--;\n                y=y-2;\n            }\n        }\n        else if(x>y)\n        {\n            if(x/2>=y)\n            {\n                teams+=y;\n                break;\n            }\n            else if(x/2<y)\n            {\n                teams++;\n                x=x-2;\n                y--;\n            }\n        }\n    }\n    printf(\"%d\",teams);}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fe717274d83668b1cdd5b870f03240ec", "src_uid": "0718c6afe52cd232a5e942052527f31b", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint x,y,i=0,j=0,turn=-1;\nscanf(\"%d %d\",&x,&y);\nif(x==0&&y==0)\n{\n    printf(\"0\");\nreturn 0;\n}\n i++;\n    turn++;\n     if(x<=i&&x>=i-1&&j==y)\n    {\n        printf(\"%d\",turn);\n        return 0;\n    }\n    j++;\n    turn++;\n    if(i==x&&y<=j&&y>=j-1)\n    {\n        printf(\"%d\",turn);\n        return 0;\n    }\nwhile(1)\n{\n\n\n    i=-i;\n    turn++;\n     if(x<=i&&x>=-i&&j==y)\n    {\n        printf(\"%d\",turn);\n        return 0;\n    }\n    j=-j;\n    turn++;\n     if(i==x&&y<=i&&y>=-i)\n    {\n        printf(\"%d\",turn);\n        return 0;\n    }\n    i=-i+1;\n    turn++;\n     if(x<=i&&x>=i-1&&j==y)\n    {\n        printf(\"%d\",turn);\n        return 0;\n    }\n    j=-j+1;\n    turn++;\n    if(x==i&&y<=j&&y>=j-1)\n    {\n        printf(\"%d\",turn);\n        return 0;\n    }\n\n\n}\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d5e613780450f4fef9292f4914453fba", "src_uid": "2fb2a129e01efc03cfc3ad91dac88382", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint x,y,turn;\nscanf(\"%d %d\",&x,&y);\nif(x==0&&y==0||x==1&&y==0)\n{\n    printf(\"0\");\n    return 0;\n}\nif(x>0&&y>-x+1&&y<=x)\nturn=4*x-3;\nif(y>0&&x<y&&x>=-y)\nturn=4*y-2;\nif(x<0&&y>=x&&y<-x)\nturn=-4*x-1;\nif(y<0&&x>y&&x<=-y+1)\nturn=-4*y-0;\nprintf(\"%d\",turn);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ee738ac704fb6eb7383ce0679e1a4670", "src_uid": "2fb2a129e01efc03cfc3ad91dac88382", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint x,y,turn;\nscanf(\"%d %d\",&x,&y);\nif(x==0&&y==0||x==0&&y==1)\n{\n    printf(\"0\");\n    return 0;\n}\nif(x>0&&y>-x+1&&y<=x)\nturn=4*x-3;\nif(y>0&&x<y&&x>=-y)\nturn=4*y-2;\nif(x<0&&y>=x&&y<-x)\nturn=-4*x-1;\nif(y<0&&x>y&&x<=-y+1)\nturn=-4*y-0;\nprintf(\"%d\",turn);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2d6e0c82cebce3b003574539012d0ebc", "src_uid": "2fb2a129e01efc03cfc3ad91dac88382", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint x,y,turn;\nscanf(\"%d %d\",&x,&y);\nif(x==0&&y==0||x==1&&y==0)\n{\n    printf(\"0\");\n    return 0;\n}\n if(x<0&&y>=x&&y<-x)\n    turn=-4*x-1;\n    if(y<0&&x>y&&x<=-y+1)\n    turn=-4*y;\n    if(x>0&&y>-x+1&&y<=x)\n    turn=x*4-3;\n    if(y>0&&x<y&&x>=-y)\n    turn=4*y-2;\nprintf(\"%d\",turn);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2b08fd8e4c4c8c678ffa9de3935d1118", "src_uid": "2fb2a129e01efc03cfc3ad91dac88382", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint x,y,turn;\nscanf(\"%d %d\",&x,&y);\nif(x==0&&y==0||x==1&&y==0)\n{\n    printf(\"0\");\n    return 0;\n}\n if(x<0&&y>=x&&y<-x)\n    ans=-4*x-1;\n    if(y<0&&x>y&&x<=-y+1)\n    ans=-4*y;\n    if(x>0&&y>-x+1&&y<=x)\n    ans=x*4-3;\n    if(y>0&&x<y&&x>=-y)\n    ans=4*y-2;\nprintf(\"%d\",turn);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "708a729c37e4cd409815a89b77fdac01", "src_uid": "2fb2a129e01efc03cfc3ad91dac88382", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main()\n{\n\n\n    char a[100],max;\n    long long i,j,k,l,m,pt,flag=0;\n    scanf(\"%s\",a);\n    l=strlen(a);\n    //printf(\"%c\\n\",a[l-1]);\n    if(a[0]!='-')\n    {\n        printf(\"%s\",a);\n    }\n    else\n    {\n        for(i=2;i<l;i++)\n        {\n            if(a[i]!='0')\n              {\n                  if(a[l-2]>a[l-1])\n                    pt=l-2;\n                  else\n                    pt=l-1;\n\n\n                  }\n                  break;\n              }\n              else if(i==l-1)\n              {\n                  pt=1;\n                  flag=1;\n              }\n\n\n\n        }\n        if(flag==1)\n        {\n            printf(\"0\");\n        }\n        else\n        {\n\n        for(j=0;j<l;j++)\n        {\n            if(j!=pt)\n            {\n                printf(\"%c\",a[j]);\n            }\n        }\n        }\n        printf(\"\\n\");\n    }\n\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4308396e3d86510b76b58e76bf97f0b8", "src_uid": "4b0a8798a6d53351226d4f06e3356b1e", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MAX(a,b) ((a>b)?a:b)\nint main(){\n    int n;\n    int temp1,temp2;\n    scanf(\"%d\",&n);\n    if(n>0) temp1=n/10;\n    else temp1=-((-n)/10);\n    if(n>0) temp2=n%10+(n/100)*10;\n    else temp2=-((-n)%10+((-n)/100)*10)\n    printf(\"%d\",MAX(n,MAX(temp1,temp2));\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2c14563c6998670eb941c110fc07008b", "src_uid": "4b0a8798a6d53351226d4f06e3356b1e", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"code\" />\n\t\t<Option execution_dir=\"D:/C/code/\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/code\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/code\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"code/main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "222d7ff0156c653dca26174d31d7aaa9", "src_uid": "4b0a8798a6d53351226d4f06e3356b1e", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main(){\n    long input;\n\n\tscanf(\"%ld\",&input);\n\t if((input/10>input || (input/100)*10+(input%10)>input)&&input/10 !=0){\n       if(input/10 > (input/100)*10+(input%10)){\n            input = input/10;\n\n        }\n        else {\n            input =(input/100)*10+(input%10);\n\n\t}\n\n\tprintf(\"%ld\\n\",input);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1343ac4efa60fd56293d9ebc5f34e1d1", "src_uid": "4b0a8798a6d53351226d4f06e3356b1e", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n int n,a,rem,rem2,c=0;\n scanf(\"%d\",&n);\n a=n;\n if(n>0)\n printf(\"%d\",n);\n else\n {\n     rem=n%10;\n     n=n/10;\n     rem2=n%10;\n     a=n/10;\n     if(abs(rem)>abs(rem2))\n     printf(\"%d\",n);\n     else\n     {if(a==0)\n     prinf(\"0\");\n     else\n     printf(\"%d%d\",a,abs(rem));\n     }\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9742ffb23c7c0d601b8b5c6804bb907c", "src_uid": "4b0a8798a6d53351226d4f06e3356b1e", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint compare_function(const void *a,const void *b) {\n    int *x = (int *) a;\n    int *y = (int *) b;\n    return *x - *y;\n}\n\nvoid print_array(int a[], int size) {\n    printf(\"[\");\n    for (int i = 0; (i < size); i++) {\n        printf(\"%d \", a[i]);\n    }\n    printf(\"]\\n\");\n}\n\n\nint main(void) {\n    int len;\n    int input;\n    int number_paints = 0;\n    int in = 0;\n\n    scanf(\"%d\", &len);\n    int colors[len];\n    int check[len];\n    \n\n    for(int i = 0; i < len; i++) {\n        scanf(\"%d\", &input);\n        colors[i] = input;\n        //printf(\"EEEE: %d\", colors[i]);\n    }   \n\n    //print_array(colors, len);\n\n    qsort(colors, sizeof(colors)/sizeof(colors[0]), sizeof(colors[0]), compare_function);\n\n    //print_array(colors, len);\n\n    check[0] = colors[0];\n    number_paints += 1;\n\n\n    for (int color_iter = 0; color_iter < len; color_iter++) {\n        for (int check_iter = 0; check_iter < number_paints; check_iter++) {\n            if (colors[color_iter] % check[check_iter] == 0) {\n                 in = 1;\n                break;\n            }\n\n            else {\n                in = 0;\n            }\n\n        }\n        if (!in) {\n            //printf(\"THIS RUNS\\n\");\n            check[number_paints] = colors[color_iter]; \n            number_paints += 1;\n            in = 1;\n\n        }\n        ..print_array(check, number_paints);\n    }\n\n    printf(\"%d\" , number_paints);\n\n    return 0;\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f2c9f5495754953ce188be91c210d52a", "src_uid": "63d9b7416aa96129c57d20ec6145e0cd", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint\nmain(void)\n{\n  // value of number as you input it into initNumbers -->\n  int num = 0;\n  // length of your array will be -->\n  int length = 0;\n\n  scanf(\"%d\", &length);\n\n  int primes[25] = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97};\n\n  int initNumbers[length];\n\n  int divisors[length];\n\n  int counter;\n\n  for(int i = 0; i < length; i++)\n  {\n    scanf(\"%d\",&num);\n    initNumbers[i] = num;\n  }\n\n  for(int i = 0; i < length; i++)\n  {\n    for(int j = 0; j<25;j++)\n      {\n        for(int k = 0; k<length; k++)\n        {\n          counter = 0;\n          if(divisors[k] == 0) continue;\n          if(divisors[k] == 1) continue;\n\n          if(initNumbers[i] % divisors[k] == 0)\n          {\n            divisors[i] = 0;\n            counter=1;\n            break;\n          }\n          }\n          if (counter == 1) break;\n          if(initNumbers[i] == 1)\n          {\n            divisors[i] = 1;\n            break;\n          }\n          else if(initNumbers[i] % primes[j] == 0)\n          {\n            divisors[i] = primes[j];\n            break;\n          }\n\n          else (j == 24)\n            divisors[i] = 0;\n      }\n  }\n\n  int returnCounter = 0;\n  for(int i = 0; i < length; i++)\n  {\n    if (divisors[i] == 0) continue;\n\n    returnCounter +=1;\n  }\nprintf(\"%d\\n\", returnCounter);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6f969e802171b7659ba029da28792661", "src_uid": "63d9b7416aa96129c57d20ec6145e0cd", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n,tem;\n    int min;\n    scanf(\"%d\",&n);\n    int a[n];\n    int count=0;\n\n    for(int i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n\n    loop:\n        min=101;\n\n        for(int i=0;i<n;i++)\n        {\n            if(a[i]<min)\n            {\n                min=a[i];\n            }\n        }\n\n    for(int i=1;i<n;i++)\n    {\n        if(a[i]%min==0)\n        {\n            a[i]=101;\n        }\n    }\n    count++;\n\n\n   for(int j=0;j<n;j++)\n   {\n       if(a[j]!=101)\n        goto loop;\n   }\n\n    printf(\"%d\\n\",count);\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ffcea04dd3fca5b5e37f3dcbedda8ddb", "src_uid": "63d9b7416aa96129c57d20ec6145e0cd", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n;\n\tscanf(\"%d\", &n);\n\tint arr[100];\n\tint i, j=0, flag=1, temp, x=0;\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%d\", &arr[i]);\n\t\tif(arr[i] == 1)\n\t\t    x = 1;\n    }\n\tint count = 0;\n\tint rr[4] = {2, 3, 5, 7};\n\tif(x == 1)\n\t    printf(\"1\\n\");\n    else{\n\t       while(flag == 1){\n\t    temp = 0;\n\t    for(i=0;i<n;i++){\n\t        if(arr[i]%rr[j] == 0){\n\t            arr[i] = 0;\n\t            temp = 1;\n\t        }\n\t    }\n\t    if(temp == 1)\n\t        count++;\n\t    for(i=0;i<n;i++){\n\t        if(arr[i] != 0){\n\t            flag = 1;\n\t            break;\n\t        }\n\t        else\n\t            flag = 0;\n\t    }\n\t    j++;\n\t}\n\tprintf(\"%d\\n\", count);\n\t\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f357b3f7414d6d879743c793780b8db9", "src_uid": "63d9b7416aa96129c57d20ec6145e0cd", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nvoid main()\n{\n\n    int n;\n    scanf(\"%d\",&n);\n\n    int a[n],temp[n],i,min=101,color=0,loopcount=0;\n\n    for(i=0;i<n;i++){\n        scanf(\"%d\",&a[i]);\n        temp[i] = a[i];\n    }\n\n    while(loopcount<n){\n\n        min = 101;\n        for(int i=0;i<n;i++){\n            if(temp[i]<min)\n                min = temp[i];\n        }\n\n        for(i=0;i<n;i++){\n            if(temp[i]%min==0)\n                temp[i] = 101;\n\n            color++;\n        }\n\n        /**remove\n\n        printf(\"array: \");\n        for(i=0;i<n;i++)\n            printf(\"%d \",temp[i]);\n\n        printf(\"\\n\");\n\n        endpoint*/\n\n        int all101 = 1;\n        for(int i=0;i<n;i++){\n            if(temp[i]!=101){\n                all101 = 0;\n                break;\n            }\n        }\n\n        loopcount++;\n\n        if(all101)\n            break;\n\n\n    }\n\n    printf(\"%d\",loopcount);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ad3578579a8a1dbe428e84750f39060c", "src_uid": "63d9b7416aa96129c57d20ec6145e0cd", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint main()\n{\n    int n;\n    cin>>n;\n    cout << (n-2)*(n-2) <<endl;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "de78d953f23ead421bc128d3d086bcca", "src_uid": "efa8e7901a3084d34cfb1a6b18067f2b", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<iostream>\nusing namespace std;\nint main()\n{\n\tlong long int n;\n\tcin>>n;\n\tlong long int ans=(n-2)*(n-2);\n\tcout<<ans;\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3eaf0443a97e6f0b44816b805e869e5b", "src_uid": "efa8e7901a3084d34cfb1a6b18067f2b", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "-2#include<stdio.h>\nint main() {\n  int n;\n  scanf(\"%d\",&n);\n  long long res=(long long)(n-2)*(long long)(n-2);\n  printf(\"%lld\\n\",res);\n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cbcf273aab8399c1871459686e2664bd", "src_uid": "efa8e7901a3084d34cfb1a6b18067f2b", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": " \n#include<stdio.h>\nint main()\n{\n\t _int64 duobianxing; \n\t \n\tscanf(\"%I64d\",&duobianxing);\n\n\tduobianxing = (duobianxing-2)*(duobianxing-2);\n \n    printf(\"%I64d\\n\",duobianxing);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b3fe34c5ef6ce12e6fe8dfde81ed66fa", "src_uid": "efa8e7901a3084d34cfb1a6b18067f2b", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    scanf(\"%d\",&n);\n    c=(n-2)*(n-2);\n    printf(\"%d\",c);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dccabdecdb8bad5b6a5e3fd3c74bfad0", "src_uid": "efa8e7901a3084d34cfb1a6b18067f2b", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "include<stdio.h>\nint main()\n{\n   int n,k,l,c,d,p,nl,np,q,r;\n   scanf(\"%d %d %d %d %d %d %d %d\",&n,&k,&l,&c,&d,&p,&nl,&np);\n   int a=(k*l)/nl;\n   int b=c*d;\n   int m=p/np;\n   if(a<=b&&a<=m)\n   {\n       q=a;\n   }\n   else if(b<=a&&b<=m)\n   {\n       q=b;\n   }\n   else if(m<=a&&m<=b)\n   {\n       q=m;\n   }\n   r=q/n;\n   printf(\"%d\",r);\n   return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "100fcb64c5fe14bb7f381fb508c2e02d", "src_uid": "67410b7d36b9d2e6a97ca5c7cff317c1", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,k,l,c,d,p,nl,np,i,j,o,m;\n    scanf(\"%d%d%d%d%d%d%d%d\",&n,&k,&l,&c,&d,&p,&nl,&np);\n    i=(k*l)/nl;\n    j=c*d;\n    m=p/np;\n    if(i<=j && i=<m)\n    {\n        o=i/n;\n    }\n        if(j<=i && j<=m)\n    {\n        o=j/n;\n    }\n        if(m<=j && m<=i)\n    {\n        o=m/n;\n    }\n    printf(\"%d\",o);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "19c80d2d396026436214f13be7e3c413", "src_uid": "67410b7d36b9d2e6a97ca5c7cff317c1", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n int n,k,l,c,d,p,nl,np,a,b,c;\n scanf(\"%d%d%d%d%d%d%d%d\",&n,&k,&l,&c,&d,&p,&nl,&np);\n a=((k*l)/nl)/n;b=(c*d)/n;c=(p/np)/n;\n a<b&&a<c?printf(\"%d\",a):(b<a&&b<c?printf(\"%d\",b):printf(\"%d\",c));\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "449b4758b71727178aa8cd9fc23e5e95", "src_uid": "67410b7d36b9d2e6a97ca5c7cff317c1", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nman()\n{\n    int n,k,l,c,d,z,p,y,nl,x,np;\n    scanf(\"%d %d %d %d %d %d %d %d\",&n,&k,&l,&c,&d,&p,&nl,&np);\n    x=k*l/nl;\n    y=c*d;\n    z=p/np;\n      if(x<y&&x<z)\n    printf(\"%d\",x/n);\n      if(x>y&&y<z)\n    printf(\"%d\",y/n);\n      if(x>z&&y>z)\n    printf(\"%d\",z/n);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7ccfb85cd33ae442f057e81dd3bbf262", "src_uid": "67410b7d36b9d2e6a97ca5c7cff317c1", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n\nint main()\n{\nint n,k,l,c,d,p,np,nl;\nscanf(\"%d %d %d %d %d %d %d %d\",&n,&k,&l,&c,&d,&p,&np,&nl);\nint Toast=min(min(k * l / nl, c * d), p / np) / n;\nprintf(\"%d\",toast);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6fa2b3c7565606cebec7928613ccea15", "src_uid": "67410b7d36b9d2e6a97ca5c7cff317c1", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n# define m 1000000007\nlong long int power(long long int x,long long int y)\n{\n\tif(y==0)\n\treturn 1;\n\telse if(y%2==0)\n\t{\n\t\tlong long int z;\n\t\tz=power(x,y/2)%m;\n\t\treturn (z*z)%m;\n\t}\n\telse\n\t{\n\t\tlong long int z;\n\t\tz=power(x,y/2)%m;\n\t\treturn ((x%m*z%m)%m*z)%m;\n\t}\n}\nint main()\n{\n\tlong long int n,a,b,x,i,ans=0;\n\tscanf(\"%lld %lld %lld %lld\",&a,&b,&n,&x);\n       if(a!=1)\n{\n//\tfor(i=0;i<n;i++)\n//\t{\n\t\tans=(power(a,n)-1)%m;\n\t\tif(ans<0)\n\t\tans=ans+m;\n\t\tans=(ans%m*b%m)%m;\n\t\tif(ans<0)\n\t\tans+=m;\n\t\tif(a-1>0)\n\t\tans=((ans%m)*power(a-1,m-2)%m)%m;\n\t\t ans=ans%m;\n//\t}\n\tans=(ans+(power(a,n)%m*x%m)%m)%m;\n\tans=ans%m;}\nelse\nans=((n%m*b%m)%m+x)%m\n\tprintf(\"%lld\\n\",ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bf2f48621500c57d527c6e90a370749a", "src_uid": "e22a1fc38c8b2a4cc30ce3b9f893028e", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "    #include <stdio.h>\n\tint mod=1000000007;\n    long long int power(long long int base,long long int exponent)\n    {\n    \tlong long int res=1;\n    \twhile(exponent) \n    \t{\n    \t\tif(exponent%2) \n    \t\t\tres=(res*base)%mod;\n    \t\tbase=(base*base)%mod;\n    \t\texponentexponent/=2;\n    \t}\n    \treturn res%mod;\n    }\n     \n    long long int geometricsum(long long int r,long long int n)\n    {\n    \tif(r==1) \n    \t\treturn n%mod;\n    \treturn (1-power(r,n))*power(1-r,mod-2)%mod;\n    }\n     \n    int main()\n    {\n    \tlong long int a,b,n,x;\n    \tscanf(\"%lld %lld %lld %lld\", &a,&b,&n,&x);\n    \tlong long int answer=(power(a,n)*x+b*geometricsum(a,n))%mod;\n    \tprintf(\"%lld\", answer);\n    \treturn 0;\n\n    }", "lang_cluster": "C", "compilation_error": true, "code_uid": "0ddc0811979a8e01b21725b34bb5fc14", "src_uid": "e22a1fc38c8b2a4cc30ce3b9f893028e", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n# define m 1000000007\nlong long int power(long long int x,long long int y)\n{\n\tif(y==0)\n\treturn 1;\n\telse if(y%2==0)\n\t{\n\t\tlong long int z;\n\t\tz=power(x,y/2)%m;\n\t\treturn (z*z)%m;\n\t}\n\telse\n\t{\n\t\tlong long int z;\n\t\tz=power(x,y/2)%m;\n\t\treturn ((x%m*z%m)%m*z)%m;\n\t}\n}\nint main()\n{\n\tlong long int n,a,b,x,i,ans=0;\n\tscanf(\"%lld %lld %lld %lld\",&a,&b,&n,&x);\n\tfor(i=0;i<n;i++)\n\t{\n\t\tans=ans+(power(a,i)%m*b%m)%m;\n\t\tans=ans%m;\n\t}\n\tans=ans+(power(a,n)%m*x%m)%m;\n\tans=ans%m;\n\tprintf(\"%lld\\n\",ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ae6895a2710997a23d6fbcebb6665083", "src_uid": "e22a1fc38c8b2a4cc30ce3b9f893028e", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n\tlong long int a,b,n,x;\n\tscanf(\"%lld %lld %lld %lld\", &a,&b,&n,&x);\n\tint i;\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tx=a*x+b;\n\t\tx=x%1000000007;\n\t}\n\tprintf(\"%lld\", x);\n\treturn 0;\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3b33551f9958d3645f897ddc2ae32cd6", "src_uid": "e22a1fc38c8b2a4cc30ce3b9f893028e", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define M 1000000007 \nint main () {\n\tlong long int a,b,n,x ,i,sum=0,f=1;\n\tscanf(\"%I64d%I64d%I64d%I64d\",&a,&b,&n,&x) ;\n\ta=a%M ;\n\tfor (i=0;i<n;i++)\n\t{  sum=(sum+f)%M ;\n\t   f=(f*a)%M ;\n\t}  \n\tx=x%M ;\n\tb=b%M ;\n\ta=(f*x)%M ;\n\tsum=(sum*b)%M ;\n\tsum=(sum+a)%M ;\n\tprintf(\"%I64d\\n\",sum) ;\n\treturn 0 ;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bff7581e82f12d364edae8831ccdc468", "src_uid": "e22a1fc38c8b2a4cc30ce3b9f893028e", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n  int m,c[100],x,y,i,p=0,ans;\n  scanf(\"%d\",&m);\n  for(i=0;i<m;i++)\n  {\n     scanf(\"%d\",&c[i]);\n  }\n  scanf(\"%d%d\",&x,&y);\n  for(i=0;i<m;i++)\n  {\n     p+=c[i];\n     if(p>=x)\n     {\n        ans = i+2;\n        break;\n     }\n  }\n  if(p<=y&&>=x)\n  {\n     printf(\"%d\",ans);\n  }\n  else\n  {\n     printf(\"0\");\n  }\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8f4ad937276a0419608636d92909d4d4", "src_uid": "e595a1d0c0e4bbcc99454d3148b4557b", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int m,x,y,out=0;\n    scanf(\"%d\",&m);\n    int c[m];\n    for(int i=0;i<m;i++)\n        scanf(\"%d\",&c[i]);\n    scanf(\"%d %d\",&x,&y);\n    int d[m];\n    d[0]=c[0];\n    for(int i=1;i<m;i++)\n        d[i]=d[i-1]+c[i];\n    for(int i=0;i<m;i++)\n    {\n        if(d[i]<=y&&d[i]>=x&&(d[m-1]-d[i])<=y&&(d[m-1]-d[i])>=x)\n            out=i+2;\n    }\n    printf(\"%d\",out);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "581b916e4c0b12d0564004badd89f041", "src_uid": "e595a1d0c0e4bbcc99454d3148b4557b", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nmain(){\nint n,x,y,i,dif,cont=0,z;\nint a[150],s[150];\n\n    scanf(\"%d\",&n);\n    suma[0]=0;\n    for(i=1;i<=n;i++){\n        scanf(\"%d\",&a[i]);\n        s[i]=s[i-1]+a[i];\n    }\n    z=0;\n    scanf(\"%d %d\",&x,&y);\n    for(i=1;i<=n;i++){\n        if(s[i]>=x&&s[i]<=y){\n            dif=s[n]-s[i];\n            if(dif>=x&&dif<=y){\n                printf(\"%d\",i+1);\n                return 0;\n            }\n        }\n     }\n           printf(\"0\");\n           return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6bbb5f2b6fb5a54387d14fdf2fbb17f5", "src_uid": "e595a1d0c0e4bbcc99454d3148b4557b", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main (void){\n    int i,j;\n    int num;\n    int min,max;\n    int test=0,all=0;\n    int score[100];\n    scanf(\"%d\",&num);\n    for(i=0;num>i;i++){\n        scanf(\"%d\",&score[i]);\n        all=all+score[i];\n    }\n    scanf(\"%d %d\",&min,&max);\n    for(j=0;j<i;j++){\n        if((test>=min)&&(test<=max)){\n            if(((all-test)>=min)&&((all-test)<=max)){\n                printf(\"%d\\n\",j+1);\n                break;\n            }\n            if(j==i-1){\n                printf(\"0\\n\");\n                break;\n            }\n            test=test+score[j];\n        }else{\n            test=test+score[j];\n            if(j==i-1){\n            printf(\"0\\n\");\n            break;\n            }\n        }\n    }\n    return(0);", "lang_cluster": "C", "compilation_error": true, "code_uid": "b6476ea2f60f936e989b5697e344e2d0", "src_uid": "e595a1d0c0e4bbcc99454d3148b4557b", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "//\n//  main.c\n//  codeforces\n//\n//  Created by Artem Bastun on 13/10/13.\n//  Copyright (c) 2013 Artem Bastun. All rights reserved.\n//\n\n#include <stdio.h>\n#include <stdlib.h>\n\nint main(int argc, const char * argv[])\n{\n    int n = 0;\n    scanf(\"%d\" , &n);\n    int *a = malloc((n + 1) * sizeof(int));\n    int i = 0;\n    a[0] = 0;\n    for (i = 1; i <= n; i++) {\n        int x = 0;\n        scanf(\"%d\" , &x);\n        a[i] += a[i-1] + x;\n    }\n    int l = 0 , r = 0;\n    scanf(\"%d %d\" , &l , &r);\n    for (int i = 1; i <= n; i++) {\n        if (a[i-1] >= l && a[i-1] <= r && a[n] - a[i-1] >= l && a[n] - a[i-1] <= r) {\n            printf(\"%d\" , i);\n            return 0;\n        }\n    }\n    printf(\"0\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b44c927a732efb87eb08f0680e1f6d2f", "src_uid": "e595a1d0c0e4bbcc99454d3148b4557b", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nint a,b,c,sum=0;\nscanf(\"%d %d %d\",&x,&y,&z);\n\nif(x==y)\nprintf((z*2)+b+a);\n\nelse if(x>y)\nprintf((z*2)+(x*2)+1);\n\nelse if(x<y)\nprintf((z*2)+(y*2)+1);\n\nreturn(0);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c0a61805df300159405e30e23372b3e7", "src_uid": "609f131325c13213aedcf8d55fc3ed77", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\nusing namespace std;\nint main()\n{\n    int n;\n    cin>>n;\n    if(n>0){cout<<\"The number is postisve\"<<endl;}\n    else if(n<0)cout<<\"the number is negative\";\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8f46ec063c14698c01f8f759fe8096d4", "src_uid": "609f131325c13213aedcf8d55fc3ed77", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n{\n    long long int i,a,b,c,j;\n    scanf(\"%lld%lld%lld\",&a,&b,&c);\n    if(a>=b)\n    {\n        printf(\"%lld\",a+b+c*2);\n    }\n    else \n    {\n        printf(\"%lld\",c*2+2*a+1);\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e067043a4f1cdcf506e31c44cf21e5cc", "src_uid": "609f131325c13213aedcf8d55fc3ed77", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "include<stdio.h>\nvoid main()\n{\nint a,b,c,sum=0;\nscanf(\"%d %d %d\",&a,&b,&c);\n\nsum=a+b+(c*2);\n\nprintf(\"%d\", sum);\n    \n    \n    \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "35d59f758d63c3962fd530252d59008d", "src_uid": "609f131325c13213aedcf8d55fc3ed77", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                #\n{\n    int a,b,c,i,j=0;\n    scanf(\"%d%d%d\",&a,&b,&c);\n    a=a+c;\n    b=b+c;\n    if((a+b)%2==0){\n        printf(\"%d\\n\",a+b);\n    }\n    else{\n        for(i=1;i<=a+b;i++){\n            a--;\n            b--;\n            j++;\n            if((a==0 && b!=0)||(b==0 &&  a!=0)){\n                j++;\n                break;\n            }\n        printf(\"%d\\n\",j);\n        }\n    }\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b6d01eb142756d5480a89bfd84ff30f6", "src_uid": "609f131325c13213aedcf8d55fc3ed77", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    int x=1,i=1;\n    for(i=1;i<n;i++)\n       {z=pow(2,i);\n        x=x+z;\n       }\n       printf(\"%d\",x);\n       return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e8e1fb8742edad6de2e26cb5c7c2ecdf", "src_uid": "6df251ac8bf27427a24bc23d64cb9884", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    lon long int a, n;\n    scanf(\"%lld\",&n);\n    a=n + (n-1)*n*n/2 -(n-1)*n*(2*n-1)/6;\n    printf(\"%lld\",a);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8e346e80ac86bb5047e28caf8284d504", "src_uid": "6df251ac8bf27427a24bc23d64cb9884", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\n#include<math.h>\nint main ()\n{\n    int n,s=0;\n    scanf(\"%d\",&n);\n    s=pow(2,n)-1;\n    printf(\"%d\\n\",s;\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4ada61591467a16f98dea160769ad0c9", "src_uid": "6df251ac8bf27427a24bc23d64cb9884", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main() {\n    int n;\n    scanf(\"%d\", &n);\n    int sum = 0;\n    for(int i = 1; i <= n; i++) {\n        sum += i;\n    }\n    int n = 1;\n    for(int i = 2; i <= n -1; i ++) {\n         \n        sum+=n;\n        n+=i;\n    }\n    printf(\"%d\", sum);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "770d52fd61ad2053e8f654c11d2743bc", "src_uid": "6df251ac8bf27427a24bc23d64cb9884", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint fac(int n);\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tn=fac(n);\n\tprintf(\"%d\",n+1);\n\treturn 0;\n}\nint fac(int n){\n     int n;\n     while(n-1){\n\treturn (n*fac(n-1));\n     }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d81d8377410c162f774f5e5a2104f8f6", "src_uid": "6df251ac8bf27427a24bc23d64cb9884", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int l,r;\n    scanf(\"%I64d %I64d\",&l,&r);\n    int temp=l%2;\n    if(l+2+temp<=r)\n    {\n        printf(\"%I64d %I64d %I64d\",l+t,l+1+t,l+2+temp);\n        return 0;\n    }\n    1printf(\"-1\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "81a26821d4d78d3e67f3925933784836", "src_uid": "6c1ad1cc1fbecff69be37b1709a5236d", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint pgcd(long long a,long long b)\n{long long i;\nint d;\nif (b%a==0)\n    {return a;}\nif (a%b==0)\n{return b;}\ni=1;\nwhile (i<50)\n{ if ((a%i==0)&&(b%i==0))\n    {d=i;\n        i++;}\n        else {i++;}\n}\nreturn d;\n\n}\n\n\nint main()\n{long long  l,r,i,j,k;\nint n1,n2,n3;\n\ndo\n{\n\n\nscanf(\"%I64d %I64d\",&l,&r);\n}\nwhile ((r-l>50)||(r<1)||(l<1)||(r>pow(10,18))||(l>pow(10,18))||(l>r));\nfor(i=l;i<=r;i++)\n{\n    for(j=i+1;j<=r;j++)\n\n\n    {\n\n\n\nfor (k=j+1;k<=r;k++)\n\n    {n1=pgcd(i,j); n2=pgcd(j,k);n3=pgcd(k,i);\n    if (((n1==1)&&(n2==1))&&(n3!=1))\n            {printf(\"%I64d %I64d %I64d\",i,j,k);\n        return 0;}\n    }}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "938dbf768fd935e7289a2e310a535b66", "src_uid": "6c1ad1cc1fbecff69be37b1709a5236d", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\n#include <time.h>\n\n#define lli long long int\n#define MAX INT_MAX\n#define sd second\n#define fs first\n#define endll '\\n'\n#define PI acos(-1)\n#define mp make_pair\n#define pb push_back\n#define best 1000000007\n#define FOR(i,a,b) for(int i=a;i<=b;i++)\n#define ROF(i,a,b) for(int i=a;i>b;i--)\n#define buyuk(a,b) (a<b)? b:a\n#define kucuk(a,b) (a<b)? a:b\n#define ort(a,b) (a+b)/2\n#define carp(a,b) (a)*(b)\nint f(lli a,lli b) {\n\t lli  i,bolucu=0,kucuk,buyuk;\n\t \t\n\t\tif(a<b){\n\t\t\t\t\tkucuk=a;\n\t\t\t\t\t\t\tbuyuk=b;\n\t\t\t\t\t\t\t\t}\n\t\t\telse{\n\n\t\t\t\t\t\tkucuk=b;\n\t\t\t\t\t\t\t\tbuyuk=a;\t\t\n\t\t\t\t\t\t\t\t\t}\n\t\t\tfor(i=1;i<=kucuk;i++)\n\t\t\t\t\tif(kucuk%i==0 && buyuk%i==0 )\n\t\t\t\t\t\t\tbolucu=i;\n\t\t\t\t\t\t\t\t\n\t\t\t\t\n\t\t\t\treturn bolucu;\n}\nint main () {\n\tlli x,y,z,i;\n\tscanf(\"%lld %lld\",&x,&y);\n\tif(x==900000000000000009)\n\t\tprintf(\"900000000000000009 900000000000000010 900000000000000021\n\t\t\t\t\");\n\tif(y-x<2){\n\t\tprintf(\"-1\");\n\treturn 0;\n\t}\n\tfor(i=x;i<20;i++)\n\t\tif(f(x,i)!=1){\n\t\t\tprintf(\"%lld %lld %lld\",x,x+1,x+i);\n\treturn 0;}\n\tprintf(\"-1\");\n\t}\n\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "31a54f3cfd061ffe52e91b76164bcab5", "src_uid": "6c1ad1cc1fbecff69be37b1709a5236d", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tlong long int l,r;\n\tscanf(\"%lld %lld\",&l,&r);\n\tif(r-l<2 || (r-l=2 && l=1))\n\t{\n\t\tprintf(\"-1\");\n\t\treturn 0;\n\t}\n\telse if(l%2==0)\n\t{\n\t\tprintf(\"%lld %lld %lld\",l,l+1,l+2);\n\t\treturn 0;\n\t}\n\telse\n\t{\n\t\tprintf(\"%lld %lld %lld\",l+1,l+2,l+3);\n\t\treturn 0;\n\t}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a0f70cb90ff17b19e6296e66fbcc544d", "src_uid": "6c1ad1cc1fbecff69be37b1709a5236d", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": " #include <include>\nint main(){\n\tlong long int l,r;\n\tscanf(\"%lld %lld\",&l,&r);\n\tif(r-l<2){\n\t\tprintf(\"-1\");\n\t\treturn 0;\n\t}\n\tif(!(l%2)){\n\t\tprintf(\"%lld %lld %lld\",l,l+1,l+2);\n\t\treturn 0;\n\t}\n\tif(r-l>2){\n\t\tprintf(\"%lld %lld %lld\",l+1,l+2,l+3);\n\t\treturn 0;\n\t}\n\tprintf(\"-1\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7395e5c0dbf2b84acdc643e8ef65e540", "src_uid": "6c1ad1cc1fbecff69be37b1709a5236d", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint n;\nint k;\nint x;\nscanf(\"%d %d\", &n, &k);\nx = n+1;\n\nwhile (x%k != 0){\n\tx = x + 1;\n}\n\nprintf(\"%d\", &x );", "lang_cluster": "C", "compilation_error": true, "code_uid": "0835f830c91b4cd231d25f4cfe57fbe9", "src_uid": "75f3835c969c871a609b978e04476542", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint n;\nint k;\nint x;\nscanf(\"%d %d\", &n, &k)\nx = n+1;\n\nwhile (x%k != 0){\n    x = x + 1;\n}\n\nprintf(\"%d\", &x )", "lang_cluster": "C", "compilation_error": true, "code_uid": "62dbf838645a840a814ab19743cb56cb", "src_uid": "75f3835c969c871a609b978e04476542", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <sdtio.h>\n\n\nint main(){\n   int n,m,k;\n   scanf(\"%d %d\",&n,&k);\n   m=n/k + 0.5;\n   while(k*m<=n){\n         m++;\n   }\n   printf(\"%d\\n\",k*m);\n   return 0;\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9bfee0becb01e289f8aa0c03b8a01a94", "src_uid": "75f3835c969c871a609b978e04476542", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "include<stdio.h>\nint main()\n{\n    int a,b,n,i;\n    scanf(\"%d%d\",&a,&b);\n    for(i=a+1;;i++){\n        if(i%b==0){\n        printf(\"%d\\n\",i);\n        break;\n        }\n    }\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1b6b40acf63b9bd07a138bca844e6d97", "src_uid": "75f3835c969c871a609b978e04476542", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n\nint main(){\n   register int n,m,k;\n   scanf(\"%d %d\",&n,&k);\n   m=n/k + 0.5;\n   while(k*m<=n){\n         m++;\n   }\n   printf(\"%d\\n\",k*m);\n   return 0;\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8c75f0240c93fb3668679267de0d79fa", "src_uid": "75f3835c969c871a609b978e04476542", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"aa\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/aa\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/aa\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t\t<Add option=\"-fexceptions\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.cpp\" />\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d2d7ca9b1f20b2002694a43a07113246", "src_uid": "496baae594b32c5ffda35b896ebde629", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void) {\n\t// your code goes here\n\t\n\tint n ,k,i,j,l;\n\tscanf(\"%d %d,&n,&k);\n\t\n\tfor(i=0;i<n-1;i++)\n\t{\n\t    scanf(\"%d\",&j);\n\t    k=k-j;\n\t    if(k<0)break;\n\t    \n\t}\n\tif(i==n-1)printf(\"YES\"); else printf(\"NO\");\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8994e95de84c15d368047b6f74ce36b3", "src_uid": "496baae594b32c5ffda35b896ebde629", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "include<stdio.h>\nmain()\n{\n    int n,s,i,a[n],max,sum=0;\n    scanf(\"%d%d\",&n,&s);\n    for(i=0;i<n;i++)\n        scanf(\"%d\",&a[i]);\n    max=a[0];\n    for(i=0;i<n;i++)\n    {\n        sum=sum+a[i];\n        if(a[i]>=max)\n            max=a[i];\n    }\n    sum=sum-max;\n    if(sum<=s)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3c5b2204d1fc7777993fe68cc13b5778", "src_uid": "496baae594b32c5ffda35b896ebde629", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main ()\n{\n    int n,s,a[20],x=0,max=0,i,j;\n    scanf(\"%d %d\",&n,&s);\n    for(i=1;i<=n;i++) {\n        if(n>100) {\n            printf(\"NO\\n\");\n            return 0;\n        scanf(\"%d\",&a[i]);\n        x=x+a[i];\n        if(n-i==2 && x>s) {\n            printf(\"NO\\n\");\n            return 0;\n        }\n        if(a[i]>max) {\n            max=a[i];\n        }\n    }\n    j=x-max;\n    if(j>s) {\n        printf(\"NO\\n\");\n    }\n    else {\n        printf(\"YES\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "91314684c034dc525ff927cdaa6570e6", "src_uid": "496baae594b32c5ffda35b896ebde629", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    int a[105],n,i,sum,s;\n    scanf(\"%d %d\",&n,&s);\n    sum=0;max=0;\n    for (i=1;i<=n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        sum+=a[i];\n        if (a[i]>max) max=a[i];\n    }\n    if (sum-max<=s) printf(\"YES\"); else printf(\"NO\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a2cb1ca3790b2469ec133911311dfe39", "src_uid": "496baae594b32c5ffda35b896ebde629", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nvoid main()\n{\n    int n;\n    int s[50];\n    scanf(\"%d\", &n);\n    for(i=0;i<n,i++)\n    {\n        scanf(\"%d\",&s[i]);\n        if s[i]==1;\n        {\n            printf(\"HARD\");\n            break;\n        }\n        else\n        {\n            printf(\"easy\");\n            break;\n        }\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2e2920c6ab861cba2a6bbedf9b4c436d", "src_uid": "060406cd57739d929f54b4518a7ba83e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n\tint n, a, i, m = 0;\n\tscanf_s(\"%d\", &n);\n\t\n\tfor (i = 0; i < n; i++)\n\t{\n\t\tscanf_s(\"%d\", &a);\n\t\tif (a == 1) \n\t\t{\n\t\t\tprintf(\"hard\");\n\t\t\tbreak;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tm++;\n\t\t}\n\t}\n\tif (m == n)\n\t{\n\t\tprintf(\"easy\");\n\t}\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4a6ee61ffa8884e39742b7d0964c1be8", "src_uid": "060406cd57739d929f54b4518a7ba83e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,k;\n\tscanf(\"%d\",&n);\n\twhile(n--)\n\t{\n\t\tscanf(\"%d\",&k);\n\t\t\n\n\t\t\n\t}\n\tif(k==1) printf(\"HARD\"); break;\n\n\telse if(k==0) printf(\"EASY\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e6aea6ec561edd81494b36a1e58f91d2", "src_uid": "060406cd57739d929f54b4518a7ba83e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nint i,n,s;\nscanf(\"%d\",n);\nfor(i=0;i<n;i++)\nif(s[i]==0)\n{\nprintf(\"EASY\");\n}\nelse if(s[i]==1)\n{\nprintf(\"HARD\");\n}\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "014b7b67c9b5bc704f4998e0b29b2743", "src_uid": "060406cd57739d929f54b4518a7ba83e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <bits/stdc++.h>\nusing namespace std;\n\n\n\n\nint main() {\n    ios_base::sync_with_stdio(0);\n    cin.tie(0);\n\n    int n;\n    int x;\n    cin >> n;\n    for(int i = 1; i <= n; i++){\n        cin >> x;\n        if(x == 1){\n        cout << \"Hard\";\n           exit(1);\n        }\n        if(i ==n ){\n            cout<<\"Easy\";\n        }\n\n\n    }\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1cf8b3db8ca83092fc9f2e9c65d795a2", "src_uid": "060406cd57739d929f54b4518a7ba83e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tlong long int n;\n\tscanf(\"%I64d\",&n);\n\twhile(n%3==0)\n\t\t{\n\t\t    n=n/3;\n\t\t}\n\n\tprintf(\"%I64d\",(n/3)+1);\n\treturn\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3ccf01391ee544e3c9f4ee3665f68b66", "src_uid": "7e7b59f2112fd200ee03255c0c230ebd", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "include<stdio.h>\nint main()\n{\nlong long int c,marks,temp,a=1;\nscanf(\"%lld\",&marks);\ntemp=marks;\nwhile(temp!=0)\n{\n   if(temp%a!=0)\n   {\n      break;\n   }\n   else \n   a*=3;\n}\nc=temp/a+1;\nprintf(\"%lld\",c);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8183720356c9c221b66ce9df90eca419", "src_uid": "7e7b59f2112fd200ee03255c0c230ebd", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "\n #include<stdio.h>\nint main()\n{\n\tlong long p;\n\tscanf(\"%I64d\",&p)\n\twhile(p%3==0)\n\t    p/=3;\n\tprintf(\"%I64d\",(p/3)+1);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "54c13d0496e4192f8da4838f525a1f14", "src_uid": "7e7b59f2112fd200ee03255c0c230ebd", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint main(){\n\tint a;\n\tcin>>a;\n\tint sd=log(a)/log(3);\n\tsd=pow(3,sd);\n\tint aw=a/sd;\n\tif(a%sd!=0)\n\t{\n\t\taw++;\n\t}\n\tcout<<aw<<\"\\n\";\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "28e628500ee58cfdb9d9d10cee660fda", "src_uid": "7e7b59f2112fd200ee03255c0c230ebd", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tlong long int x,a=1,sum;\n\tscanf(\"%I64d\",&x);\n\twhile(x!=0)\n\t{\n\t\tif(x%a!=0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t\telse\n\t\t{\n\t\t\ta=a*3;\n\t\t}\n\t}\t\n\t\tsum=x/a+1;\n\t\tprintf(\"%I64d\",sum);\n\t\treturn o;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "52ff17c47adcd3590a48a0560c8b0603", "src_uid": "7e7b59f2112fd200ee03255c0c230ebd", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint changes(char a[ ],int n);\nmain()\n{\n    int c;\n    char a[15];\n    scanf(\"%s\",&a);\n    c=changes(a,strlen(a));\n    if(c==1 || (c==0 && strlen(a)%2!=0)\n    printf(\"YES\");\n    else\n    printf(\"NO\");\n}\nint changes(char a[ ],int n)\n{\n    int i,c=0;\n    for(i=0;i<n/2;i++)\n    {\n        if(a[i]==a[n-1-i]);\n        else\n        c++;\n    }\n    return c;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b31416850bb8043cb82a26504ef3b1fe", "src_uid": "fe74313abcf381f6c5b7b2057adaaa52", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main(void)\n{\n    char str[15]={0};\n    int i=0, d=0,l=0;\n    \n    scanf(\"%s\",str);\n    l=strlen(str);\n    rev[l]='\\0';\n    for(i=0;i<l/2;i++){\n        if ( str[l-i-1] != str[i]) d++;\n    }\n    if(d==1) printf(\"YES\");\n    else if(d==0){\n        if(l%2 != 0) printf(\"YES\");\n        else printf(\"NO\");\n    }\n    else printf(\"NO\");\n \n    return 0;   \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "43f60424d898541aa4df8064cb773c9d", "src_uid": "fe74313abcf381f6c5b7b2057adaaa52", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "2.c", "lang_cluster": "C", "compilation_error": true, "code_uid": "21e10754a67ff407f93004d3c816cf45", "src_uid": "fe74313abcf381f6c5b7b2057adaaa52", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint changes(char a[ ],int n);\nmain()\n{\n    int c;\n    char a[15];\n    scanf(\"%s\",&a);\n    c=changes(a,strlen(a));\n    if(c==1 || (c==0 && n%2!=0))\n    printf(\"YES\");\n    else\n    printf(\"NO\");\n}\nint changes(char a[ ],int n)\n{\n    int i,c=0;\n    for(i=0;i<n/2;i++)\n    {\n        if(a[i]==a[n-1-i]);\n        else\n        c++;\n    }\n    return c;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4afbc121d0c7fe39a326a7f66dee8353", "src_uid": "fe74313abcf381f6c5b7b2057adaaa52", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int a , i;\n    int flag=0;\n    char s[16];\n    char *S = s;\n    char *p = s;\n    for(i = 0;i<16;i++)\n    {\n        s[i]= '0';\n    }\n    while(~scanf(\"%s\",s))\n    {\n        int j=0;\n        while(s[j] != '0')\n        {\n            a++;\n            j++;\n        }\n        a=a-2;\n        int b = a/2;\n        for(a=0,i=0 ;a > b;a--,i++)\n        {\n            if(S[i] != p[a])\n                flag++;\n        }\n        if(flag <= 1)\n            printf(\"YES\\n\");\n        else\n            printf(\"NO\\n\");\n    }\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "32357002d2187fcfbb102fa27985b21d", "src_uid": "fe74313abcf381f6c5b7b2057adaaa52", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n        int t,s,x;\n        scanf(\"%d%d%d\",&t,&s,&x);\n        if(x==t+s)\n        {\n                printf(\"NO\");\n        }\n        else if(x==t+s+1)\n        {\n                printf(\"NO\");\n        }\n        else\n        {\n                printf(\"YES\");\n        }\n        return 0;\n}\n~                             ", "lang_cluster": "C", "compilation_error": true, "code_uid": "fc98907c6c5f4fc927064a5339e790e9", "src_uid": "3baf9d841ff7208c66f6de1b47b0f952", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    int t, i, x, total;\n    scanf(\"%d %d %d\", &t, &i, &x);\n    if(x==t) {\n        printf(\"YES\");\n        return 0;\n    }\n    else if(x%t==0){\n       printf(\"NO\")\n       return 0;\n    } \n    else if(x>t+1 && (x%i<(t+2))) printf(\"YES\");\n    else printf(\"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f480152fe667c57f6f613ca4ebfb7784", "src_uid": "3baf9d841ff7208c66f6de1b47b0f952", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string>\n\nint main() {\n\tint t, s, x;\n\twhile (scanf(\"%d%d%d\", &t, &s, &x)==3){\n\t\tif ((x - t) % s == 0) {\n\t\t\tprintf(\"YES\\n\");\n\t\t}\n\t\telse {\n\t\t\tif ((x - 1) > t && (x - 1) % t == 0) {\n\t\t\t\tprintf(\"YES\\n\");\n\t\t\t}\n\t\t\telse {\n\t\t\t\tprintf(\"NO\\n\");\n\t\t\t}\n\t\t}\n\t};\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "40bc75e6853669feade99caf553253a2", "src_uid": "3baf9d841ff7208c66f6de1b47b0f952", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <cstdio>\n\nint main() {\n    int t, s, x;\n    scanf(\"%d%d%d\", &t, &s, &x); //\u8bfb\u5165\n    int tmp = x - t;\n    if ((tmp % s == 0 || tmp % s == 1) && tmp >= 0 && tmp != 1) //\u5224\u65adx\u79d2\u65f6\u83e0\u841d\u662f\u5426\u4f1a\u53eb\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "54ddacead19ab4a998ae43e2284e3813", "src_uid": "3baf9d841ff7208c66f6de1b47b0f952", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int t,s,x,i=1;\n    scanf(\"%lld %lld %lld\",&t,&s,&x);\n    if(x<t)\n    {printf(\"NO\");}\n    else\n    {if(t==x)\n     {printf(\"YES\");}\n     else\n     {while(x>t+i*s+1)\n      {i++;}\n      if(x==t+i*s||x==t+i*s+1)\n      {printf(\"YES\");}\n      else\n      {printf(\"NO\");}\n     }\n    }\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "f89413f81ed93af0710d004f3b7aa6c5", "src_uid": "3baf9d841ff7208c66f6de1b47b0f952", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "e#include<stdio.h>\n\nint main(){\n\nint n,a,b,q=0;\n\nscanf(\"%d\", &n);\n\nb=n%10;\n\na=n/10;\n\n\nif(a == 2)\n    printf(\"twenty\");\n\nelse if(a == 3)\n    printf(\"thirty\");\n\nelse if(a == 4)\n    printf(\"forty\");\n\nelse if(a == 5)\n    printf(\"fifty\");\n\nelse if(a == 6)\n    printf(\"sixty\");\n\nelse if(a == 7)\n    printf(\"seventy\");\n\nelse if(a == 8)\n    printf(\"eighty\");\n\nelse if(a == 9)\n    printf(\"ninety\");\n\n\nif(b != 0  )\n    if(a!=0)\n        if(a!=1)\n            printf(\"-\");\n\n\n\n\nif(b == 2 && a!=1)\n    printf(\"two\");\n\nelse if(b == 1 && a!=1)\n    printf(\"one\");\n\nelse if(b == 3 && a!=1)\n    printf(\"three\");\n\nelse if(b == 4 && a!=1)\n    printf(\"four\");\n\nelse if(b == 5 && a!=1)\n    printf(\"five\");\n\nelse if(b == 6 && a!=1)\n    printf(\"six\");\n\nelse if(b == 7 && a!=1)\n    printf(\"seven\");\n\nelse if(b == 8 && a!=1)\n    printf(\"eight\");\n\nelse if(b == 9 && a!=1)\n    printf(\"nine\");\n\n\nif(n==0)\n    printf(\"zero\");\n\nif(n == 10)\n    printf(\"ten\");\n\nelse if(n == 11)\n    printf(\"eleven\");\n\nelse if(n == 12)\n    printf(\"twelve\");\n\nelse if(n == 13)\n    printf(\"thirteen\");\n\nelse if(n == 14)\n    printf(\"fourteen\");\n\nelse if(n == 15)\n    printf(\"fifteen\");\n\nelse if(n == 16)\n    printf(\"sixteen\");\n\nelse if(n == 17)\n    printf(\"seventeen\");\n\nelse if(n == 18)\n    printf(\"eighteen\");\n\nelse if(n == 19)\n    printf(\"nineteen\");\n\n\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9f3097924b6133f90f508ac08de01250", "src_uid": "a49ca177b2f1f9d5341462a38a25d8b7", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int x,y;\n    scanf(\"%d\", &x);\n    y=x/10;\n    if(y){\n        switch (y){\n            case 2:\n                printf(\"twenty\");\n                break;\n            case 3:\n                printf(\"thirdy\");\n                break;\n            case 4:\n                printf(\"forty\");\n                break;\n            case 5:\n                printf(\"fifty\");\n                break;\n            case 6:\n                printf(\"sixty\");\n                break;\n            case 7:\n                printf(\"seventy\");\n                break;\n            case 8:\n                printf(\"eighty\");\n                break;\n            case 9:\n                printf(\"ninety\");\n                break;\n            default:\n                switch(x-y*10){\n                case 0:\n                    printf(\"ten\\n\");\n                break;\n                case 1:\n                    printf(\"eleven\\n\");\n                break;\n                case 2:\n                    printf(\"twelve\\n\");\n                break;\n                case 3:\n                    printf(\"thirteen\\n\");\n                break;\n                case 4:\n                    printf(\"fourteen\\n\");\n                break;\n                case 5:\n                    printf(\"fifteen\\n\");\n                break;\n                case 6:\n                    printf(\"sixteen\\n\");\n                break;\n                case 7:\n                    printf(\"seventeen\\n\");\n                break;\n                case 8:\n                    printf(\"eighteen\\n\");\n                break;\n                case 9:\n                    printf(\"nineteen\\n\");\n                break;\n                }\n        }\n    }\n        if (y>1&&(x-y*10)!=0){\n            printf(\"-\");\n        }\n        x=x-y*10;\n        if (x&&y!=1]){\n            switch(x){\n                case 1:\n                    printf(\"one\\n\");\n                break;\n                case 2:\n                    printf(\"two\\n\");\n                break;\n                case 3:\n                    printf(\"three\\n\");\n                break;\n                case 4:\n                    printf(\"four\\n\");\n                break;\n                case 5:\n                    printf(\"five\\n\");\n                break;\n                case 6:\n                    printf(\"six\\n\");\n                break;\n                case 7:\n                    printf(\"seven\\n\");\n                break;\n                case 8:\n                    printf(\"eight\\n\");\n                break;\n                case 9:\n                    printf(\"nine\\n\");\n                break;\n            }\n        }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "dc2a3e6c5a3fbd35b48d121cad1b2641", "src_uid": "a49ca177b2f1f9d5341462a38a25d8b7", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint ekok(int y){\n\n    if(y==1){printf(\"one\");}\n    if(y==2){printf(\"two\");}\n    if(y==3){printf(\"three\");}\n    if(y==4){printf(\"four\");}\n    if(y==5){printf(\"five\");}\n    if(y==6){printf(\"six\");}\n    if(y==7){printf(\"seven\");}\n    if(y==8){printf(\"eight\");}\n    if(y==9){printf(\"nine\");}\n    printf(\"\\n\");\n\n\n}\nint doshok(int x){\n\n    if(x/10==2){ printf(\"twenty\"); }\n    if(x/10==3){ printf(\"thirty\"); }\n    if(x/10==4){ printf(\"forty\"); }\n    if(x/10==5){ printf(\"fifty\"); }\n    if(x/10==6){ printf(\"sixty\"); }\n    if(x/10==7){ printf(\"seventy\"); }\n    if(x/10==8){ printf(\"eighty\"); }\n    if(x/10==9){ printf(\"ninety\"); }\n\n    int l=x-((x/10)*10);\n    if(l>=1){\n        printf(\"-\");\n        ekok(l);\n\n    }\n};\n\nint main (){\n\n    int num;\n    scanf(\"%d\",&num);\n    if(num==ten){printf(\"ten\\n\");}\n    if(num<10){\n\n        ekok(num);\n\n    }\n    if(num>10 && num<20){\n\n        if(num==11){ printf(\"eleven\\n\");}\n        if(num==12){ printf(\"twelve\\n\");}\n        if(num==13){ printf(\"thirteen\\n\");}\n        if(num==14){ printf(\"fourteen\\n\");}\n        if(num==15){ printf(\"fifteen\\n\");}\n        if(num==16){ printf(\"sixteen\\n\");}\n        if(num==17){ printf(\"seventeen\\n\");}\n        if(num==18){ printf(\"eighteen\\n\");}\n        if(num==19){ printf(\"nineteen\\n\");}\n\n\n\n\n\n    }\n\n    if(num>=20){\n\n        doshok(num);\n    }\n\n\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "622c488197fa187002ac6f377dde056b", "src_uid": "a49ca177b2f1f9d5341462a38a25d8b7", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(){\n\nint n,a,b,q=0;\n\nscanf(\"%d\", &n);\n\nb=n%10;\n\na=n/10;\n\n\nif(a == 2)\n    printf(\"twenty\");\n\nelse if(a == 3)\n    printf(\"thirty\");\n\nelse if(a == 4)\n    printf(\"forty\");\n\nelse if(a == 5)\n    printf(\"fifty\");\n\nelse if(a == 6)\n    printf(\"sixty\");\n\nelse if(a == 7)\n    printf(\"seventy\");\n\nelse if(a == 8)\n    printf(\"eighty\");\n\nelse if(a == 9)\n    printf(\"ninety\");\n\n\nif(b != 0  )8\n    if(a!=0)\n        if(a!=1)\n            printf(\"-\");\n\n\n\n\nif(b == 2 && a!=1)\n    printf(\"two\");\n\nelse if(b == 3 && a!=1)\n    printf(\"three\");\n\nelse if(b == 4 && a!=1)\n    printf(\"four\");\n\nelse if(b == 5 && a!=1)\n    printf(\"five\");\n\nelse if(b == 6 && a!=1)\n    printf(\"six\");\n\nelse if(b == 7 && a!=1)\n    printf(\"seven\");\n\nelse if(b == 8 && a!=1)\n    printf(\"eight\");\n\nelse if(b == 9 && a!=1)\n    printf(\"nine\");\n\n\nif(n==0)\n    printf(\"zero\");\n\nif(n == 10)\n    printf(\"ten\");\n\nelse if(n == 11)\n    printf(\"eleven\");\n\nelse if(n == 12)\n    printf(\"twelve\");\n\nelse if(n == 13)\n    printf(\"thirteen\");\n\nelse if(n == 14)\n    printf(\"fourteen\");\n\nelse if(n == 15)\n    printf(\"fifteen\");\n\nelse if(n == 16)\n    printf(\"sixteen\");\n\nelse if(n == 17)\n    printf(\"seventeen\");\n\nelse if(n == 18)\n    printf(\"eighteen\");\n\nelse if(n == 19)\n    printf(\"nineten\");\n\n\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ee6e398d46b727ade8c48109179e1c17", "src_uid": "a49ca177b2f1f9d5341462a38a25d8b7", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n\t\tint s;\n\t\tscanf(\"%d\",&s);\n\n\t\tchar *a[100];\n\t\ta[0] = \"zero\";\n\t\ta[1] = \"one\";\n\t\ta[2] = \"two\";\n\t\ta[3] = \"three\";\n\t\ta[4] = \"four\";\n\t\ta[5] = \"five\";\n\t\ta[6] = \"six\";\n\t\ta[7] = \"seven\";\n\t\ta[8] = \"eight\";\n\t\ta[9] = \"nine\";\n\t\ta[10] = \"ten\";\n\t\ta[11] = \"eleven\";\n\t\ta[12] = \"twelve\";\n\t\ta[13] = \"thirteen\";\n\t\ta[14] = \"fourteen\";\n\t\ta[15] = \"fifteen\";\n\t\ta[16] = \"sixteen\";\n\t\ta[17] = \"seventeen\";\n\t\ta[18] = \"eighteen\";\n\t\ta[19] = \"nineteen\";\n\t\ta[20] = \"twenty\";\n\t\ta[30] = \"thirty\";\n\t\ta[40] = \"forty\";\n\t\ta[50] = \"fifty\";\n\t\ta[60] = \"sixty\";\n\t\ta[70] = \"seventy\";\n\t\ta[80] = \"eighty\";\n\t\ta[90] = \"ninety\";\n\n\t\tif(s%10==0 || s<20)\n\t\t\t\tprintf(\"%s\\n\",a[s]);\n\t\telse\n\t\t\t\tprintf(\"%s-%s\\n\",a[(s/10)*10],a[s%10]);\n\n\t\treturn 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "5ce857400a3fed2d46961d21fe68c89c", "src_uid": "a49ca177b2f1f9d5341462a38a25d8b7", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint abd[1000000001];\n\nint main()\n{\n\tlong long int a,b,i,cp,max=0,max_ind=0;\n\tscanf(\"%lld%lld\",&a,&b);\n\tfor(i=a;i<=b;i++)\n\t{\n\t\tfor(cp=2;cp <= (i/2)+1;cp++)\n\t\t{\n\t\t\tif(i % cp == 0)\n\t\t\t\tabd[cp] += 1;\n\t\t\tif(abd[cp] > max)\n\t\t\t{\n\t\t\t\tmax_ind = cp;\t\n\t\t\t\tmax = abd[cp];\n\t\t\t} \n\t\t}\n\t}\n\tprintf(\"%lld\\n\",max_ind);\n\treturn 0;\n}\t\t\n\t\t\t\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4a454fdb7bfd4a564fc4a7423b942ea0", "src_uid": "a8d992ab26a528f0be327c93fb499c15", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint abd[500000001];\n\nint main()\n{\n\tlong long int a,b,i,cp,max=0,max_ind=0;\n\tscanf(\"%lld%lld\",&a,&b);\n\tfor(i=a;i<=b;i++)\n\t{\n\t\tfor(cp=2;cp <= (i/2)+1;cp++)\n\t\t{\n\t\t\tif(i % cp == 0)\n\t\t\t\tabd[cp] += 1;\n\t\t\tif(abd[cp] > max)\n\t\t\t{\n\t\t\t\tmax_ind = cp;\t\n\t\t\t\tmax = abd[cp];\n\t\t\t} \n\t\t}\n\t}\n\tprintf(\"%lld\\n\",max_ind);\n\treturn 0;\n}\t\t\n\t\t\t\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "49b5ee68df4139215bfb42846d2b1343", "src_uid": "a8d992ab26a528f0be327c93fb499c15", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    long long int x,y;\n    scanf(\"%d %d\",&x,&y);\n    if (x==y && x%2!=0) printf(\"%I64d\",x);\n    else printf(\"2\");\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b2bde39e2a1ec389a224dfa7bf719105", "src_uid": "a8d992ab26a528f0be327c93fb499c15", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    int l,r;\n    cin>>l>>r;\n    if(l==r)\n        printf(\"%d\\n\",l);\n    else\n        puts(\"2\");\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "57a3b1bc0c033e63d0b3d013560de6af", "src_uid": "a8d992ab26a528f0be327c93fb499c15", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <iostream.h>\n\nusing namespace std;\n\n\n\nint main()\n{\n    int a,b,h,arr[10]={0},temp,c=0,i=3;\n    cin>>a;\n    cin>>b;\n    h=2;\n    cout<<h;}", "lang_cluster": "C", "compilation_error": true, "code_uid": "94e23c24e0ee5382a5dc3c1ccc1a007c", "src_uid": "a8d992ab26a528f0be327c93fb499c15", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nint main()\n{\n\tint n,m,i,j,a,min1=9,min2=9;\n\tint a[10]={0},b[10]={0};\n\tscanf(\"%d%d\",&n,&m);\n\tfor (i=1;i<=n;i++)\n\t{\n\t\tscanf(\"%d\",&a);\n\t\tif (a<min1) min1=a;\n\t}\n\tfor (i=1;i<=m;i++)\n\t{\n\t\tscanf(\"%d\",&a);\n\t\tif (a<min2) min2=a;\n\t}\n\tfor (i=0;i<=9;i++)\n\t\tif (a[i]&&b[i])\n\t\t{\n\t\t\tprintf(\"%d\\n\",i); return 0;\n\t\t} \n\tif (min1==min2) printf(\"%d\\n\",min1);\n\telse if (!min1) printf(\"%d\\n\",min2*10);\n\telse if (!min2) printf(\"%d\\n\",min1*10);\n\telse if (min1<min2) printf(\"%d\\n\",min1*10+min2);\n\telse printf(\"%d\\n\",min2*10+min1);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "63ff56b2136e293e1e83c739b90f80bf", "src_uid": "3a0c1b6d710fd8f0b6daf420255d76ee", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n\n    int n,m;\n\n    int min1=10,min2=10,min3=10;\n    int k=0;\n    scanf(\"%d %d\",&n,&m);\n\n    int a[n+1],b[m+1];\n    int keep1[n+1],keep2[m+1];\n\n    for(int i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        if(a[i]<=min1)\n        {\n            min1=a[i];\n        }\n\n\n    }\n\n     for(int i=0;i<m;i++)\n    {\n        scanf(\"%d\",&b[i]);\n\n        if(b[i]<=min2)\n        {\n            min2=b[i];\n        }\n    }\n\n    for(int i=0;i<n;i++)\n    {\n        for(int j=0;j<m;j++)\n        {\n            if(a[i]==b[j])\n            {\n                keep1[k]=a[i];\n\n                if(keep1[k]<=min3)\n                    min3=keep1[k];\n\n                    \n            }\n            \n                k++;\n\n        }\n    }\n\n\n\n     if(min3<10)\n    {\n        printf(\"%d\\n\",min3);\n    }\n\n\n    else if(min1!=min2)\n    {\n       if(min1<min2)\n       {\n           printf(\"%d%d\\n\",min1,min2);\n       }\n       else If(min1>min2)\n       {\n           printf(\"%d%d\\n\",min2,min1);\n       }\n        \n    }\n\n\n\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "be882c6e6c60aa67d9de98c6b20a0eef", "src_uid": "3a0c1b6d710fd8f0b6daf420255d76ee", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <iostream>\nusing namespace std;\n\nint main() {\n\tint n1,n2;\n\tscanf(\"%d %d\",&n1,&n2);\n\tint a[10],b[10];\n\tint i;\n\tfor(i=0;i<10;i++)\n\ta[i]=b[i]=0;\n\tfor(i=0;i<n1;i++)\n\t{\n\t    int x;\n\t    scanf(\"%d\",&x);\n\t    a[x]=1;\n\t}\n\tfor(i=0;i<n1;i++)\n\t{\n\t    int x;\n\t    scanf(\"%d\",&x);\n\t    b[x]=1;\n\t}\n\tint flag=0;\n\tfor(i=0;i<10;i++)\n\t{\n\t    if(a[i]==1 && b[i]==1)\n\t    {\n\t        printf(\"%d\\n\",i);return 0;\n\t    }\n\t}\n\tint q,w;\n\tfor(i=0;i<10;i++)\n\t{\n\t    if(a[i]==1)\n\t    {q=i;break;}\n\t}\n\tfor(i=0;i<10;i++)\n\t{\n\t    if(b[i]==1)\n\t    {w=i;break;}\n\t}\n\tprintf(\"%d\\n\",q<=w?(q*10 +w):(w*10 +q));\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b13b5a0c3d99fa2c358a3cf67df32dd9", "src_uid": "3a0c1b6d710fd8f0b6daf420255d76ee", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n\nint main()\n{\n    int x , y ;\n    scanf(\"%d\" ,&x );\n    scanf (\"%d\", &y);\n    int line1 [x];\n    int line2 [y];\n    int i ;\n    int great1 = 9;\n    int great2 = 9 ;\n    int great =0 ;\n    for (i=0;i<x;i++){\n        scanf(\"%d\", & line1 [i]);\nif ( great1 > line1[i] && line1[i]> 0 )\n    great1= line1 [i] ;\n    }\n    for (i=0 ; i<y ; i ++){\n        scanf(\"%d\",& line2 [i]);\nif ( great2 > line2[i] && line2[i]> 0)\n    great2= line2 [i] ;\n    }\n\n   if  (great1 > great2 ) {\n        great = great2 *10 + great1 ;\n   }\n   else if  (great2 > great1 ) {\n        great = great1 *10 + great2 ;\n   }\n   else \n    great = great1 ;\n   int j ;\n    for (i =0 ; i < x ; i ++){\n        for ( j =0 ; j < y ; j ++){\n            if (line1[i]== line2 [j] && line2[j] < great){\n                great = line2 [j];8\n                break ;}\n    }\n    } \n    printf(\"%d\", great );\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f0b5876d281f9377f510719e3e346ad8", "src_uid": "3a0c1b6d710fd8f0b6daf420255d76ee", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<string.h>\nint main()\n{\n    int arr1[9];\n\n    int arr2[9];\n    arr3[];\n    arr4[];\n    int i;\n    int j;\n\n    for(i=0 , i<9 ; i++)\n    {\n\n    if(arr1[i]>= '0' && arr1[i]<= '9')\n        scanf(\"%d\",&arr1[i]);\n    }\n\n    for(j=0 , j<9 ; j++)\n    {\n\n    if(arr2[j]>= '0' && arr2[j]<= '9')\n        scanf(\"%d\",&arr2[j]);\n    }\n    if (arr1[i]==arr2[i])\n    arr4[]=arr1[i];\n    else\n    {arr3[]=arr1[i]*10+arr2[i];\n    arr4[]=arr2[i]*10+arr1[i];\n    }\n\n    if ( arr3[i]< arr4[i])\n        for(i=0 ; i<9 ; i++)\n\nif (arr3[i]<arr3[i-1])\n\n        println(\"The prettiest number:%d\",arr3[i]);\n    else\n        for(i=0 ; i<9 ; i++)\n\nif (arr4[i]<arr4[i-1])\n        println(\"The prettiest number:%d\",arr4[i]);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "64a89fe05068c8a11e123fadf9ff4807", "src_uid": "3a0c1b6d710fd8f0b6daf420255d76ee", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int no_of_domino;\n    scanf(\"%d\",&no_of_domino);\n    int arr[no_of_domino][2];\n    int upperhalf=0;\n    int lowerhalf=0;\n    int i;\n    int first,second;\n    for(i=0;i<no_of_domino;i++)\n    {\n        scanf(\"%d%d\",&first,&second);\n         upperhalf+=first;\n         lowerhalf+=second;\n    }\n    if(upperhalf%2==0&&lowerhalf%2==0)\n        printf(\"%d\",0);\n    if(upperhalf%2==0&&lowerhalf%2!=0||upperhalf%2!=0&&lowerhalf%2==0)\n        printf(\"-1\");\n        if(upperhalf%2!=0&&lowerhalf%2!=0&&upperhalf!=1&&lowerhalf!=1)\n           printf(\"1\");\n           if(uppehalf==1&&lowerhalf==1)\n            printf(\"-1\");\n           return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a787b424db2c028eca7926517474e0bf", "src_uid": "f9bc04aed2b84c7dd288749ac264bb43", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int l,i,j,k,m,n;\n    m=n=0;\n    scanf(\"%d\",&l);\n    int a[l][2];\n    for(i=0;i<l;i++)\n    {\n        for(j=0;j<2;j++)\n            scanf(\"%d\",&a[i][j]);\n    }\n    for(i=0;i<l;i++)\n    {\n        if(a[i][0]%2!=0)\n            m++;\n        if(a[i][1]%2!=0)\n            n++;\n    }\n\n    if(m%2==0&&n%2==0)\n        printf(\"0\");\n    else if(m%2!=0&&n%2==0)\n        printf(\"-1\");\n    else if(m%2==0&&n%2!=0)\n        printf(\"-1\");\n    else if(m%2!=0&&n%2!=0)\n        {\n            for(i=0;i<l;i++)\n            {\n                if(a[i][0]%2!=0&&a[i][1]%2!=0)\n                    printf(\"-1\");\n                else\n                    printf(\"1\");\n            }\n        }\n    else if(m==1&&n==1&&l==1)\n        printf(\"-1\");\n}\n#include<stdio.h>\nint main()\n{\n    int l,i,j,k,m,n;\n    m=n=0;\n    scanf(\"%d\",&l);\n    int a[l][2];\n    for(i=0;i<l;i++)\n    {\n        for(j=0;j<2;j++)\n            scanf(\"%d\",&a[i][j]);\n    }\n    for(i=0;i<l;i++)\n    {\n        if(a[i][0]%2!=0)\n            m++;\n        if(a[i][1]%2!=0)\n            n++;\n    }\n\n    if(m%2==0&&n%2==0)\n        printf(\"0\");\n    else if(m%2!=0&&n%2==0)\n        printf(\"-1\");\n    else if(m%2==0&&n%2!=0)\n        printf(\"-1\");\n    else if(m%2!=0&&n%2!=0)\n        {\n            for(i=0;i<l;i++)\n            {\n                if(a[i][0]%2!=0&&a[i][1]%2!=0)\n                    printf(\"-1\");\n                else\n                    printf(\"1\");\n            }\n        }\n    else if(m==1&&n==1&&l==1)\n        printf(\"-1\");\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "90a19bfe70d98f834bb097a5902265bd", "src_uid": "f9bc04aed2b84c7dd288749ac264bb43", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(){\n    int i,n,n1,n2,a[2][100],odd1=0,odd2=0,p=0,m=0;\n\n    scanf(\"%d\",&n);\n\n    for (i=0; i<n; i++){\n        scanf(\"%d%d\",&n1,&n2);\n        a[0][i]=n1;\n        a[1][i]=n2;\n        if (n1%2>0 && n2%2==0){odd1++;}\n        if (n2%2>0 && n1%2==0){odd2++;}\n        if (n1%2>0 && n2%2>0){p++;}\n    }\n\n    if (odd1+odd2%2>0){\n        m=-1;\n    }\n\n    else if (p%2>0){\n        while (odd1%2==0 || odd2%2==0){\n            if (odd1%2==0){\n                odd1--;\n                odd2++;\n                m++;\n            }\n            else if (odd2%2==0){\n                odd1++;\n                odd2--;\n                m++;\n            }\n        }\n    }\n    else if (p%2==0){\n        while (odd1%2>0 || odd2%2>0){\n            if (odd1%2>0){\n                odd1--;\n                odd2++;\n                m++;\n            }\n            else if (odd2%2>0){\n                odd1++;\n                odd2--;\n                m++;\n            }\n        }\n    }\n\n    printf(\"%d\",m);\n    return();\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7d377effcf2062d09bdb099bb32312c0", "src_uid": "f9bc04aed2b84c7dd288749ac264bb43", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int l,i,j,k,m,n;\n    m=n=0;\n    scanf(\"%d\",&l);\n    int a[l][2];\n    for(i=0;i<l;i++)\n    {\n        for(j=0;j<2;j++)\n            scanf(\"%d\",&a[i][j]);\n    }\n    for(i=0;i<l;i++)\n    {\n        if(a[i][0]%2!=0)\n            m++;\n        if(a[i][1]%2!=0)\n            n++;\n    }\n    //printf(\"%d %d\\n\",m,n);\n    if(m%2==0&&n%2==0)\n        printf(\"0\");\n    else if(m%2!=0&&n%2==0)\n        printf(\"-1\");\n    else if(m%2==0&&n%2!=0)\n        printf(\"-1\");\n    else if(m%2!=0&&n%2!=0)\n        printf(\"1\");\n}\n#include<stdio.h>\nint main()\n{\n    int l,i,j,k,m,n;\n    m=n=0;\n    scanf(\"%d\",&l);\n    int a[l][2];\n    for(i=0;i<l;i++)\n    {\n        for(j=0;j<2;j++)\n            scanf(\"%d\",&a[i][j]);\n    }\n    for(i=0;i<l;i++)\n    {\n        if(a[i][0]%2!=0)\n            m++;\n        if(a[i][1]%2!=0)\n            n++;\n    }\n    //printf(\"%d %d\\n\",m,n);\n    if(m%2==0&&n%2==0)\n        printf(\"0\");\n    else if(m%2!=0&&n%2==0)\n        printf(\"-1\");\n    else if(m%2==0&&n%2!=0)\n        printf(\"-1\");\n    else if(m%2!=0&&n%2!=0)\n        printf(\"1\");\n}\n#include<stdio.h>\nint main()\n{\n    int l,i,j,k,m,n;\n    m=n=0;\n    scanf(\"%d\",&l);\n    int a[l][2];\n    for(i=0;i<l;i++)\n    {\n        for(j=0;j<2;j++)\n            scanf(\"%d\",&a[i][j]);\n    }\n    for(i=0;i<l;i++)\n    {\n        if(a[i][0]%2!=0)\n            m++;\n        if(a[i][1]%2!=0)\n            n++;\n    }\n    //printf(\"%d %d\\n\",m,n);\n    if(m%2==0&&n%2==0)\n        printf(\"0\");\n    else if(m%2!=0&&n%2==0)\n        printf(\"-1\");\n    else if(m%2==0&&n%2!=0)\n        printf(\"-1\");\n    else if(m%2!=0&&n%2!=0)\n        printf(\"1\");\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7ab671afd2f3a4c1111087aa8df4dc17", "src_uid": "f9bc04aed2b84c7dd288749ac264bb43", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,i,j,k,m,n;\n    m=n=0;\n    scanf(\"%d\",&n)\n    for(i=0;i<n;i++)\n    {\n        for(j=0;j<2;j++)\n            scanf(\"%d\",&a[i][j]);\n    }\n    for(i=0;i<n;i++)\n    {\n        if(a[i][0]%2==0)\n            m++;\n        if(a[i][1]%2==0)\n            n++;\n    }\n    if(m%2==0&&n%2==0)\n        printf(\"0\");\n    else if(m%2!=0&&n%2==0)\n        printf(\"-1\");\n    else if(m%2==0&&n%!=0)\n        printf(\"-1\");\n    else if(m%2!=0&&n%!=0)\n        printf(\"1\");\n        \n        \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8b48ff1214b88505a5fe8dff3cc9280c", "src_uid": "f9bc04aed2b84c7dd288749ac264bb43", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdlib.h>\n#include<stdio.h>\nint main()\n{\n    int m;\n    scanf(\"%d\",&m);\n    if((m/2)%2==1){\n        printf(\"%d %d\", m/2-2,m/2+2);\n    else if(m%2==1){\n        \n    \n        printf(\"%d %d\", m/2, m/2+1);\n    }\n    \n    }\n    else{\n        printf(\"%d %d\", m/2-1,m/2+1);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f2c2f12d8f3385eba2bc1f86821ff06e", "src_uid": "0af3515ed98d9d01ce00546333e98e77", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\nint main()\n{\n    int n,m,r;\n\n    scanf(\"%d\",&n);\n\n    if(n%2!=0)\n        r=(n/2)+1;\n        m=n-r;\n    if(n==4)\n        r=n-1;\n        m=n-r;\n    if(n==6)\n        r=n-1;\n        m=n-r;\n    if(n==10)\n        r=n-3;\n        m=n-r;1\n    if (n%2==0&&n>10)\n        r=(n/2)+1;\n        m=n-r;\n    printf(\"%d %d\",m,r);\n\n\n\n    return 0;\n\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7312e85e8f6b6b0d2f4e85bd7d88425b", "src_uid": "0af3515ed98d9d01ce00546333e98e77", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int N,i;\n    float resultado;\n    scanf(\"%d\",&N);\n    for(i=1; i<=N; i++)\n    {\n        resultado=(float)i/(N-i));\n        if(resultado>=1)\n        {\n            i--;\n            break;\n        }\n\n    }\n    printf(\"%d %d\",i,N-i);\n    return 0;\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a3e97d34f0cef032f592c7f57359902b", "src_uid": "0af3515ed98d9d01ce00546333e98e77", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <iostream>\nusing namespace std;\n\nvoid main()\n{\n    int n;\n    cin>>n;\n    if(n%4==0)\n        cout<<n/2-1<<\" \"<<n/2+1;\n    else if (n%4==2)\n        cout<<n/2-2<<\" \"<<n/2+2;\n    else\n        cout<<n/2<<\" \"<<n/2+1;\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1c5c01b5b79dde3b6d4046cb592b35d6", "src_uid": "0af3515ed98d9d01ce00546333e98e77", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    if(n%2==1)\n        printf(\"%d %d\", n/2, n/2+1);\n    else if((n/2)%2==1)\n        printf(\"%d %d\", n/2-2,n/2+2);\n    else\n        printf(\"%d %d\", n/2-1,n/2+1);\n    return 0;\n}\n\n(19) - 431C\nC. k-Tree\nTime limit per test 1 second\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "11ad0056e64c0f2e7715ab4dc32a1141", "src_uid": "0af3515ed98d9d01ce00546333e98e77", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main()\n{\n    int i,p,r,q,g,d,j,t;\n    \n    char ch[100][100],ch1[100][100];\n\n    gets(ch);\n    gets(ch1);\n    \n    p=mod(ch[1]-ch1[1]);\n    \n    printf(\"%d\",p);\n    \n    \n    if(ch[0]<ch[0])\n    {\n       for(i=0;i<p;i++)\n       {printf\"RD\\n\";}\n       q=ch1[0]-ch[0]-p;\n       for(r=0;r<q;r++)\n       {printf(\"R\");}\n    }\n    \n    if(ch[0]>ch1[0])\n    {  \n       for(j=0;j<p;j++)\n       {printf\"LD\\n\";}\n       q=ch1[0]-ch[0]-p;\n       for(t=0;t<q;t++)\n       {printf(\"L\");}\n    }\n    \n    if(ch[0]==ch1[0] && ch[1]>ch1[1])\n    \n    {   for(g=0;g<p;g++)\n        {printf(\"D\\n\");}\n    }\n    \n    else\n    {   for(d=0;d<p;d++)\n        {printf(\"U\\n\");\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "91783aad33768cc01a045934eb7f0f87", "src_uid": "d25d454702b7755297a7a8e1f6f36ab9", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\ninline int max(int a, int b) {\n    return (a > b)? a: b;\n}\ninline int abs(int a) {\n    return (a > 0)? a: -a;\n}\n\nint main(void) {\n    char sc, tc;\n    int sn, tn;\n    scanf(\"%c%d\\n\", &sc, &sn);\n    scanf(\"%c%d\", &tc, &tn);\n    char x[8],y[8],n[8],s[24];\n    memset(x,'\\0',8);\n    memset(x,'R',max(0,tc-sc));\n    memset(x,'L',max(0,sc-tc));\n    memset(y,'\\0',8);\n    memset(y,'U',max(0,tn-sn));\n    memset(y,'D',max(0,sn-tn));\n    int xy = max(abs(sc-tc),abs(sn-tn));\n    memset(n,'\\0',8);\n    memset(n,'\\n',xy);\n    s[0] = '\\0';\n    int i;\n    for (i = 0; i <= xy; i++) {\n        strncat(s,x+i,1);\n        strncat(s,y+i,1);\n        strncat(s,n+i,1);\n    }\n    printf(\"%d\\n%s\", xy, s);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4af74138c92762b0f985241e31398645", "src_uid": "d25d454702b7755297a7a8e1f6f36ab9", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <math.h>\n#include <stdbool.h>\n#include <stddef.h>\n#include <stdint.h>\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main()\n{\n char start[3] , end[3]  ;\nint x , y ;\n\n\nscanf(\"%s\", &start);\nscanf(\"%s\", &end);\n\nx = end[0] - start[0] ;\ny = end[1] - start[1]  ;\n\nif (y > x )printf(\"%d \\n\" , abs(y));\nelse printf(\"%d \\n\" , abs(x));\n\nwhile (x !=0 || y!=0 ){\nif (x > 0 )\n{\n\tx -= 1 ;\n\tprintf(\"R\");\n}\nelse (x < 0 )\n{\n\tx += 1 ;\n\tprintf(\"L\");\n\n}\nif (y > 0 )\n{\n\ty -= 1 ;\n\tprintf(\"U\\n\");\n}\nelse (y < 0 )\n{\n\ty += 1 ;\n\tprintf(\"D\\n\");\n\n}\n\n\n}\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e806ffc26a29428a7405c39c7319786a", "src_uid": "d25d454702b7755297a7a8e1f6f36ab9", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<iostream.h>\n#include<conio.h>\n#include<stdlib.h>\n\nusing namespace std;\nint main()\n{\n    char s[5];\n    char f[5];\n    \n    scanf(\"%s\",s);\n    getchar();\n    scanf(\"%s\",f);\n    \n    int cs=(int)s[0];\n    int cf=(int)f[0];\n    \n    int rs=(int)s[1];\n    int rf=(int)f[1];\n    \n    int dc=cf-cs;\n    int dr=rf-rs;\n    \n    int max=abs(dc)>=abs(dr)?abs(dc):abs(dr);\n    \nint diff=abs(dc)-abs(dr);\n\nint moves=abs(diff)+(max-abs(diff));\nprintf(\"%d\\n\",moves);\n\nwhile( dc!=0 || dr!=0)\n{\n       if(dc>0)\n       {\n               printf(\"L\");\n               dc--;\n       }\n       else if(dc<0)\n       {\n            printf(\"R\");\n            dc++;\n       }\n       \n       if(dr>0)\n       {\n               printf(\"U\");\n               dr--;\n       }\n       else if(dr<0)\n       {\n            printf(\"D\");\n            dr++;\n       }\n       printf(\"\\n\");\n\n}\n               \n    \n    \n   // printf(\"\\n%d%d%d%d\",rs,rf,cs,cf);\n   // getch();\n    return(0);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "75ddb0ec4de2df6afedec87419c483dd", "src_uid": "d25d454702b7755297a7a8e1f6f36ab9", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\nvoid ct1(char a[],char b[])\n{\n\tint i,j;\n\ti=b[1]-a[1];\n\t\n\tif (i>0)\n\t\t{\tprintf (\"%d\",i);\n\t\t\tfor (j=0;j<i;j++)\n\t\t\t\tprintf (\"\\nD\");\n\t\t}\n\telse if (i<0)\n\t\t{\n\t\t\tprintf (\"%d\",-i);\n\t\t\tfor (j=0;j>i;j--)\n\t\t\t\tprintf (\"\\nU\");\n\t\t}\n\telse\n\t\tprintf (\"%d\",i);\n}\nint bd(char a)\n{\n\tswitch(a)\n\t{\n\t\tcase 'A': \treturn 1;break;\n\t\tcase 'B':\treturn 2;break;\n\t\tcase 'C':\treturn 3;break;\n\t\tcase 'D':\treturn 4;break;\n\t\tcase 'E':\treturn 5;break;\n\t\tcase 'F':\treturn 6;break;\n\t\tcase 'G':\treturn 7;break;\n\t\tcase 'H':\treturn 8;break;\n\t}\n}\nvoid ct2(char a[],char b[])\n{\n\tint m,n,i,j;\n\tm=bd(a[0]);\n\tn=bd(b[0]);\n\ti=n-m;\n\tif (i>0)\n\t\t{\n\t\t\tprintf (\"%d\",i);\n\t\t\tfor (j=0;j<i;j++)\n\t\t\t\tprintf (\"\\nR\");\n\t\t}\n\telse if (i<0)\n\t\t{\n\t\t\tprintf (\"%d\",-i);\n\t\t\tfor (j=0;j>i;j--)\n\t\t\t\tprintf (\"\\nL\");\n\t\t}\n\telse \n\t\t{\n\t\t\tprintf (\"%d\",i);\n\t\t}\n}\nvoid ct3(char a[],char b[])\n{\n\tint m,n,i,j,k,l;\n\tm=bd(a[0]);\n\tn=bd(b[0]);\n\ti=n-m;\n\tj=b[1]-a[1];\n\tif ((i>0)&&(j>0))\n\t\t{\n\t\t\tif (i>j)\n\t\t\t\t{\n\t\t\t\t\tm+=j;\n\t\t\t\t\ta[1]+=j;\n\t\t\t\t\tk=n-m;\n\t\t\t\t\tprintf (\"%d\",j+k);\n\t\t\t\t\tfor (l=0;l<k;l++)\n\t\t\t\t\t\tprintf (\"\\nR\");\n\t\t\t\t\tfor (l=0;l<j;l++)\n\t\t\t\t\t\tprintf (\"\\nRU\");\n\t\t\t\t}\n\t\t\telse if (i<j)\n\t\t\t\t{\n\t\t\t\t\tm+=i;\n\t\t\t\t\ta[1]+=i;\n\t\t\t\t\tk=b[1]-a[1];\n\t\t\t\t\tprintf (\"%d\",i+k);\n\t\t\t\t\tfor (l=0;l<k;l++)\n\t\t\t\t\t\tprintf (\"\\nR\");\n\t\t\t\t\tfor (l=0;l<i;l++)\n\t\t\t\t\t\tprintf (\"\\nRU\");\n\t\t\t\t\t\t\n\t\t\t\t}\n\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tprintf (\"%d\",i);\n\t\t\t\t\tfor (l=0;l<i;l++)\n\t\t\t\t\t\tprintf (\"\\nRU\");\n\t\t\t\t}\n\t\t}\n\telse if ((i>0)&&(j<0))\n\t\t{\n\t\t\tif (i>-j)\n\t\t\t\t{\n\t\t\t\t\tm-=j;\n\t\t\t\t\ta[1]-=j;\n\t\t\t\t\tk=n-m;\n\t\t\t\t\tprintf (\"%d\",-j-k);\n\t\t\t\t\tfor (l=0;l<(-k);l++)\n\t\t\t\t\t\tprintf (\"\\nR\");\n\t\t\t\t\tfor (l=0;l<-j;l++)\n\t\t\t\t\t\tprintf (\"\\nRD\");\n\t\t\t\t}\n\t\t\telse if (i<-j)\n\t\t\t\t{\n\t\t\t\t\tm+=i;\n\t\t\t\t\ta[1]+=i;\n\t\t\t\t\tk=b[1]-a[1];\n\t\t\t\t\tprintf (\"%d\",i-k);\n\t\t\t\t\tfor (l=0;l<-k;l++)\n\t\t\t\t\t\tprintf (\"\\nR\");\n\t\t\t\t\tfor (l=0;l<i;l++)\n\t\t\t\t\t\tprintf (\"\\nRD\");\n\t\t\t\t\t\t\n\t\t\t\t}\n\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tprintf (\"%d\",i);\n\t\t\t\t\tfor (l=0;l<i;l++)\n\t\t\t\t\t\tprintf (\"\\nRD\");\n\t\t\t\t}\n\t\t}\n\telse if ((i<0)&&(j>0))\n\t\t{\n\t\t\tif (-i>j)\n\t\t\t\t{\n\t\t\t\t\tm+=j;\n\t\t\t\t\ta[1]+=j;\n\t\t\t\t\tk=n-m;\n\t\t\t\t\tprintf (\"%d\",j-k);\n\t\t\t\t\tfor (l=0;l<-k;l++)\n\t\t\t\t\t\tprintf (\"\\nL\");\n\t\t\t\t\tfor (l=0;l<j;l++)\n\t\t\t\t\t\tprintf (\"\\nLU\");\n\t\t\t\t}\n\t\t\telse if (-i<j)\n\t\t\t\t{\n\t\t\t\t\tm-=i;\n\t\t\t\t\ta[1]-=i;\n\t\t\t\t\tk=b[1]-a[1];\n\t\t\t\t\tprintf (\"%d\",-i+k);\n\t\t\t\t\tfor (l=0;l<k;l++)\n\t\t\t\t\t\tprintf (\"\\nL\");\n\t\t\t\t\tfor (l=0;l<-i;l++)\n\t\t\t\t\t\tprintf (\"\\nLU\");\n\t\t\t\t\t\t\n\t\t\t\t}\n\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tprintf (\"%d\",-i);\n\t\t\t\t\tfor (l=0;l<-i;l++)\n\t\t\t\t\t\tprintf (\"\\nLU\");\n\t\t\t\t}\n\t\t}\n\telse \n\t\t{\n\t\t\tif (j>i)\n\t\t\t\t{\n\t\t\t\t\tm-=j;\n\t\t\t\t\ta[1]-=j;\n\t\t\t\t\tk=n-m;\n\t\t\t\t\tprintf (\"%d\",-j-k);\n\t\t\t\t\tfor (l=0;l<-k;l++)\n\t\t\t\t\t\tprintf (\"\\nL\");\n\t\t\t\t\tfor (l=0;l<-j;l++)\n\t\t\t\t\t\tprintf (\"\\nLD\");\n\t\t\t\t}\n\t\t\telse if (j<i)\n\t\t\t\t{\n\t\t\t\t\tm-=i;\n\t\t\t\t\ta[1]-=i;\n\t\t\t\t\tk=b[1]-a[1];\n\t\t\t\t\tprintf (\"%d\",-i-k);\n\t\t\t\t\tfor (l=0;l<-k;l++)\n\t\t\t\t\t\tprintf (\"\\nL\");\n\t\t\t\t\tfor (l=0;l<-i;l++)\n\t\t\t\t\t\tprintf (\"\\nLD\");\n\t\t\t\t\t\t\n\t\t\t\t}\n\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tprintf (\"%d\",-i);\n\t\t\t\t\tfor (l=0;l<-i;l++)\n\t\t\t\t\t\tprintf (\"\\nLD\");\n\t\t\t\t}\n\t\t}\n}\nint main()\n{\tchar a[2],b[2];\n\tscanf (\"%s\",a);\n\tscanf (\"%s\",b);\n\tif (a[0]==b[0])\n\t\tct1(a,b);\n\telse if (a[1]==b[1])\n\t\tct2(a,b);\n\telse \n\t\tct3(a,b);\n\tRETURN 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dead2b6a28feae733ccb640283a618fd", "src_uid": "d25d454702b7755297a7a8e1f6f36ab9", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    long long int n,x,t=0;\n    scanf(\"%llu\",&n);\n    for(i=1;i<=n;i=i*10)\n    {\n        t=n-i+1;\n    }\n    printf(\"%llu\",t);\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6c02eba10237a494db6fa4df78095409", "src_uid": "4e652ccb40632bf4b9dd95b9f8ae1ec9", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <iostream>\nusing namespace std;\nint main()\n{\n int x,n;\n  long long int T=0;\n    scanf(\"%d\",&n);\n   for(x=1;n>=x;x*=10)\n   {\n    T+=n-x+1;\n   }\ncout<<T;\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e1ebda0c74ccc7cdd316becafcd8c37a", "src_uid": "4e652ccb40632bf4b9dd95b9f8ae1ec9", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    int n,i;\n    int count=-1;\n    int temp=9;\n    int sum=0;\n    long long result;\n    scanf(\"%d\",&n);\n    i=n;\n    while(i>0)\n    {\n        i=i/10;\n        count++;\n    }\n    if(count >0)\n    {\n        //sum = ((n+1.0) - pow(10.0,(double)count));\n        sum = ((n+1) - power(10,count));\n        sum = sum*(count+1);\n    }\n    else\n    {\n        sum = n;\n     }\n     i=1;\n    while(i<=count)\n    {       \n        sum += temp * power(10,(i-1)) *i;\n        i++;\n    }\n    result = (long long)sum;\n    printf(\"I64d\",result);\n    return 0;\n}\nint power(int a, int b)\n{\n    int i=0,exp=1;\n    for(i=1;i<=b;i++)\n    {\n        exp *= a\n    }\n    return exp;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8e820ea2d6cd6e3ba615b51f179b61df", "src_uid": "4e652ccb40632bf4b9dd95b9f8ae1ec9", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <iostream>\nusing namespace std;\n\nint time10(int x);\n\nint main(void){\n\n    int input;\n    scanf(\"%d\", &input);\n\n    int n, tmp;\n    tmp = input;\n    for(n=0; tmp/10 > 0; n++){\n        tmp /= 10;\n    }\n\n    unsigned long long int ans;\n    ans = (input-time10(n)+1)*(n+1);\n\n    int i;\n    for(i=1; i<=n; i++){\n        ans = ans + 9*time10(i-1)*(i);\n    }\n\n    cout << ans << endl;\n\n    return 0;\n}\n\nint time10(int x){\n    int i, out = 1;\n    for(i=0; i<x; i++){\n        out *= 10;\n    }\n    return out;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "20ccf80304b13c863f39f45985667b7c", "src_uid": "4e652ccb40632bf4b9dd95b9f8ae1ec9", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    int d=1,c=0,num=n,k;\n    while(num!=0)\n    {\n    \tnum/=10;\n    \tc++;\n    }\n    k=c;\n    while(k-->1)\n    \td*=10;\t\n    while(c>0)\n    {\n    \tans += (n-d+1)*(c--);\n    \tn = d-1;\n    \td/=10;\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "13605cbbc163162df94d625fc6ff99ca", "src_uid": "4e652ccb40632bf4b9dd95b9f8ae1ec9", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n      int day;\n      char s1[15];\n      scanf(\"%d\",&day);\n      scanf(\"%s\",s1);\n      scanf(\"%s\",s1);\n      if(s[0]=='w')\n      {\n            if(day==5||day==6)\n            printf(\"53\\n\");\n            else\n            printf(\"52\\n\");\n      }\n      else\n      {\n            if(day<=29)\n            printf(\"12\\n\");\n            else if(day<=30)\n            printf(\"11\\n\");\n            else\n            printf(\"7\\n\");\n      }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "abded73bb5bc3d237da66f8452f7445e", "src_uid": "9b8543c1ae3666e6c163d268fdbeef6b", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void) {\n    int x;\n    char a[10],b[10];\n    scanf(\"%d%s%s\",&x,b,a);\n    if(strcmp(a,\"week\")==0)\n    {\n        if(x==5 || x==6)\n        printf(\"53\");\n        else\n        printf(\"52\");\n    }\n    else\n    {\n        if(x<=29)\n        printf(\"12\");\n        else if(x==30)\n        printf(\"11\");\n        else\n        printf(\"7\")\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "591c4b8a476ca20b89c86534427eca6a", "src_uid": "9b8543c1ae3666e6c163d268fdbeef6b", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define SIZE 300\n\nint main()\n{\n\tint x;\n\tchar s[SIZE];\n\n\tscanf_s(\"%d of \", &x);\n\tgets_s(s, 300);\n\n\tif (s[0] == 'w') {\n\t\tif (x >= 4 && x <= 6)\n\t\t\tprintf(\"52\");\n\t\telse\n\t\t\tprintf(\"51\");\n\t} else {\n\t\tif (x == 31)\n\t\t\tprintf(\"7\");\n\t\telse if (x == 30)\n\t\t\tprintf(\"11\");\n\t\telse\n\t\t\tprintf(\"12\");\n\t}\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5cbebed897644dbe20fa01df4adfebec", "src_uid": "9b8543c1ae3666e6c163d268fdbeef6b", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define pp printf\nchar a[9],r[9];\nint x;\nint main(){\nscanf(\"%d %s %s\",&x,a,r);\nif(r[0]=='m'){\n    if(x==31)\n    pp(\"7\\n\");\n    else if(x==30)\n        pp(\"11\\n\");\n    else\n        pp(\"12\\n\");}\nelse{\n    if(x==6 || x==5)\n        pp(\"53\\n\");\n    else\n    pp(\"52\\n\");}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2d25b2702f645b230d9fd64b4f8c2153", "src_uid": "9b8543c1ae3666e6c163d268fdbeef6b", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int d,m;\n    char w[10];\n    printf(\"input\\n\");\n    scanf(\"%d\",&d);\n    getchar();\n    gets(w);\n    if(strcmp(w,\"of week\"))\n    {\n      m=d;\n    printf(\"output\\n\");\n    if(m==31)\n    {\n        printf(\"7\");\n    }\n    else if(m==30)\n    {\n        printf(\"11\");\n    }\n    else if(m>=1 && m<30)\n    {\n        printf(\"12\");\n    }\n    else\n    {\n        printf(\"\")\n    }\n    }\n    else\n    {\n     printf(\"output\\n\");\n    if(d==1 || d==2 || d==3 || d==4 || d==7)\n    {\n        printf(\"52\\n\");\n    }\n    else if(d==5 || d==6)\n    {\n        printf(\"53\\n\");\n    }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "97b8153ed8bd798added293b0a7bccfb", "src_uid": "9b8543c1ae3666e6c163d268fdbeef6b", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "/* DHUOJ solution #360677 @ 2018-08-08 11:49:50.318 */\n\n#include <iostream>\n#include <string>\n#include <sstream>\n#include <queue>\n#include <map>\n#include <algorithm>\n#include <cstdio>\n#include <cstring>\n#include <cmath>\n\nusing namespace std;\n\nint main(){\n\tint n;\n\tint a[105] = { 0 };\n\tcin >> n;\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> a[i];\n\t}\n\tint tem = 0, ans = 0;\n\tbool flag = 1;\n\tfor (int i = 0; i < n && flag; i++) {\n\t\tif (a[i] != a[0] && a[i] != tem) {\n\t\t\tif (tem) flag = 0;\n\t\t\telse {\n\t\t\t\ttem = a[i];\n\t\t\t}\n\t\t}\n\t\telse if (a[i] == a[0]) ans++;\n\t}\n\tif (flag && ans * 2 == n) {\n\t\tcout << \"YES\" << endl;\n\t\tcout << a[0] << ' ' << tem << endl;\n\t}\n\telse cout << \"NO\" << endl;\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3b21e730b47ec2cd1622bc0f706ca668", "src_uid": "2860b4fb22402ea9574c2f9e403d63d8", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n#include <stdio.h>\nusing namespace std;\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    int a[102]={0};\n    int b[4];\n    int num;\n    int index=0;\n    for(int i=0;i<n;i++)\n    {\n        scanf(\"%d\",&num);\n        a[num]++;\n    }\n    int flag=0;\n    for(int i=1;i<=100;i++)\n    {\n        if(a[i]>0&&a[i]!=n/2)\n        {\n            printf(\"NO\\n\");\n            flag=1;\n            break;\n        }\n        if(a[i]==n/2)\n        {\n            index++;\n            b[index]=i;\n        }\n    }\n    if(!flag)\n    {\n        printf(\"YES\\n%d %d\\n\",b[1],b[2]);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b2115d3244e481f0589e681c903bcc43", "src_uid": "2860b4fb22402ea9574c2f9e403d63d8", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "\n#include <iostream>\n#include <stdio.h>\nusing namespace std;\nconst int maxn = 111;\nint num[maxn];\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    int flag=1;\n    int k1=0,k2=0;\n    int a;\n    for(int i=1;i<=n;i++){\n        scanf(\"%d\",&a);\n        if(!flag) continue;\n        if(num[a]==0){\n            num[a]++;\n            if(!k1){\n                k1=a;\n                continue;\n            }\n            if(!k2){\n                k2=a;\n                continue;\n            }\n            if(k1!=0&&k2!=0){\n                flag=0;\n            }\n        }\n        num[a]++;\n    }\n    if(flag&&num[k1]==num[k2]){\n        printf(\"YES\\n%d %d\\n\",k1,k2);\n    }\n    else\n        printf(\"NO\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "eb234c648644785df17b155b5709b204", "src_uid": "2860b4fb22402ea9574c2f9e403d63d8", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main(){\n\tint t, i, n, s = 1, a = 0, b = 0;\n\tscanf(\"%d\", &n);\n\tscanf(\"%d\", &a);\n\tfor (i = 1, i < n, ++i){\n\t\tscanf(\"%d\", &t);\n\t\tif (t != a){\n\t\t\tif (b == 0){\n\t\t\t\tb = t;\n\t\t\t}\n\t\t\telse if (b != t){\n\t\t\t\tprintf(\"NO\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\telse s++;\n\t}\n\tif (s * 2 != n || b == 0){\n\t\tprintf(\"NO\");\n\t\treturn 0;\n\t}\n\telse {\n\t\tprintf(\"YES\\n%d %d\", &a, &b);\n\t}\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "85d09c5f45cf083eb8e59ac1692356ad", "src_uid": "2860b4fb22402ea9574c2f9e403d63d8", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<string>\n#include<string.h>\n#include<cmath>\n#include<algorithm>\n#include<map>\nusing namespace std;\ntypedef long long ll;\nll a, b, f, k;\nint main()\n{\n    while (cin >> a>>b>>f>>k)\n    {\n        int cnt = 0;\n        if (b < f||b<a-f)  //k==1\n        {\n            cout << \"-1\" << endl;\n            continue;\n        }\n        if (k == 1)\n        {\n            b -= f;\n            if (b < (a - f))\n                cnt++;\n            cout << cnt << endl;\n            continue;\n        }\n        if (b < 2 * (a - f)) //k==2;\n        {\n            cout << \"-1\" << endl;\n            continue;\n        }int c = b,i;\n        if (k == 2)\n        {\n            b -= f;\n            if(b<2*(a-f))\n            {\n                b = c;\n                cnt++;\n            }\n            b -= 2 * (a - f);\n            if (b < f)\n            {\n                cnt++;\n            }\n            cout << cnt << endl;\n            continue;\n        }\n        if (b < 2 * f)\n        {\n            cout << \"-1\" << endl;\n            continue;\n        }\n        \n        b -= f;\n        for(i=1;i<k-1;i+=2)\n        {\n                if (b < 2 * (a - f))\n                {\n                    b = c;\n                    cnt++;\n                }\n                b -= 2 * (a - f);\n                if (b < 2 * f)\n                {\n                    b = c;\n                    cnt++;\n                }\n                b -= 2 * f;\n        }\n        if (i==k)\n        {\n            if (b < a-f)\n                cnt++;\n            cout << cnt << endl;\n        }\n        else\n        {\n            if (b < 2 * (a - f))\n            {\n                b = c;\n                cnt++;\n            }\n            b -= 2 * (a - f);\n            if (b < f)\n            {\n                b = c; cnt++;\n            }\n            cout << cnt << endl;\n        }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dbedaf955fb5229f902aa6b78688fc0c", "src_uid": "2860b4fb22402ea9574c2f9e403d63d8", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "//http://codeforces.com/contest/731/problem/A\n#include<stdio.h>\nint strlen(char *ptr);\nint abs(int number);\nint main(void)\n{\nchar start,pointer;\nint steps=0, i=0, temp, len1, number1;\nchar arr[101];\nscanf(\"%s\", arr);\nstart='a';\nlen1=strlen(arr);\npointer=arr[0];\nwhile(i<len)\n{\ntemp=pointer-start;\ntemp = abs(temp);\nif(temp<=13)\n{\nnumber1=pointer-start;\nsteps+=abs(number1);\n}\nelse\n{\nif(pointer>=start)\n{\nnumber1=25-pointer+1+start;\nsteps+=abs(number1);\n}\nelse\n{\nnumber1=25+pointer+1-start;\nsteps+=abs(number1);\n}\n\n}\nstart=arr[i+1];\npointer=arr[i];\ni++;\n}\nprintf(\"%d\\n\", steps);\n\nreturn 0;\n}\n\nint abs(int number)\n{\nif(number>=0);\nelse\nnumber*=-1;\nreturn number;\n\n}\n\nint strlen(char *ptr)\n{\nint i=0;\nwhile(ptr[i]!='\\0')\n{\ni++;\n}\nreturn i;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "17f8f20c8cc92ba4cf55e0d4d17fa67a", "src_uid": "ecc890b3bdb9456441a2a265c60722dd", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nchar s[100];\nint c,d\ngets(s);\nint x=strlen(s);\nint i;\nchar ch='a';\nint sum=0;\nfor(i=0;i<x;i++)\n{\nint y=ch-s[i];\nif(y<0)\n{\ny=-y;\n}\nc=26;\nd=y;\nif(c<d)\n{\nsum=c;\n}\nelse\n{\nsum=sum+d;\n}\nch=s[i];\n}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d37133326acc044c4fd6293499221c13", "src_uid": "ecc890b3bdb9456441a2a265c60722dd", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"lettre_wheel\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/lettre_wheel\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/lettre_wheel\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9406d04071f0b61f4c784a47cf1de028", "src_uid": "ecc890b3bdb9456441a2a265c60722dd", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint min(int a,int b){\n       if(a<b)       return a;\n       else return b;\n}\nint main(){\n       char s[102];\n       s[100]='A';\n       gets(s);\n       while(s!='\\0'){\n              a += abs(s[100]-i);\n              sum += min(a,26-a);\n              s[100]=s[i];\n              s++;\n       }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1218c9fef2fd2f91635ca015200d54db", "src_uid": "ecc890b3bdb9456441a2a265c60722dd", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main()\n{\n  chaine c=\"\";\n  char a;\n  int i=0,k=0,d=0;\n  while((strlen(c)==0)||(strlen(c)>100)||(k==0))\n  {   i=0;\n      k=1;\n      printf(\"donner le mot a saisir \");\n      scanf(\"%s\",&c);\n      while(i<=strlen(c)-1)\n      {if((c[i]<'a')||(c[i]>'z'))\n         k=0;\n         i++;}\n  }\n  a='a';\n  i=0;\n  while(i<strlen(c))\n  {\n      k=fabs(a-c[i]);\n      if(k>13)\n        k=26-k;\n      d=d+k;\n      a=c[i];\n      i++;\n\n  }\n  printf(\"%d\",d);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "baff03d3df26564f3494b68f5a12250f", "src_uid": "ecc890b3bdb9456441a2a265c60722dd", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nmain()\n{\n    int n,k,i,r,ck;\n    float add,avg,check;\n\n   while(2== scanf(\"%d%d\",&n,&k)){\n    int a[n];\n    add=0;\n    for(i=0;i<n;i++)\n       {scanf(\"%d\",&a[i]);\n         add=add+a[i];\n       }\n       check=add/n;\n       check=check+.5;\n       ck=(int) check;\n       if(ck==n)\n        printf(\"%d\\n\",0);\n       else\n       {\n    \n    for(i=n+1; ;i++)\n       {\n           add=add+k;\n\n           avg=(add*1.0/i);\n           avg=avg+.5;\n           r=(int) avg;\n           if(r==k) break;\n       }\n       printf(\"%d\\n\",i-n);\n   }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7a9f18fd5fcb2e9d95357b3333060ed7", "src_uid": "f22267bf3fad0bf342ecf4c27ad3a900", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void)\n{\n    int n,k;\n    int i=0;\n    int *a;\n    int sum=0;\n    \n    scanf(\"%d %d\",&n,&k);\n    for(i=0;i<n;i++) \n    {\n        scanf(\"%d\",&a[i]);\n        sum += (k-a[i]);\n    }\n    \n    sum = 2*sum - n;\n    x= sum-1;\n    \n    printf(\"%d\",x);\n    \n    return 0;\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "aca77bffa78b0833b10c7c85bd32b0b7", "src_uid": "f22267bf3fad0bf342ecf4c27ad3a900", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n#include <assert.h>\n#include <limits.h>\n#include <stdbool.h>\n\nint main(){int n,i;\n  int k,s=0,d;\n    scanf(\"%d %d\\n\",&n,&k);\nint a[n];\n    for (i=0;i<n;i++)\n    {scanf(\"%d \",&a[i]);\n    s=s+a[i]; \n    }\n     \n for (i=0;i<1000000;i++)\n    { if(i>0)s=s+k;\n     if(s*2>=(((n+i)*(2k)-(n+i)))){printf(\"%d\",i); return 0;}\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1da1b6b45f316045eed75ee5ac35ad0e", "src_uid": "f22267bf3fad0bf342ecf4c27ad3a900", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void)\n{\n    int n,k;\n    int i=0,ans=0;\n    int a;\n    int sum=0;\n    \n    scanf(\"%d %d\",&n,&k);\n    for(i=0;i<n;i++) \n    {\n        scanf(\"%d\",&a);\n        sum += (a-k);\n    }\n    sum/n<=-1/2\n    if( (sum >= 0) || (2*sum) <= (-1)*n) printf(\"0\\n\");\n    else\n    {\n        ans = -2*sum-n;\n    }\n    \n    printf(\"%d\",ans);\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "20587e447df0fe64111fa98d8e624cb7", "src_uid": "f22267bf3fad0bf342ecf4c27ad3a900", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(void)\n{\n    int n,k,i,sum=0,a[120],sm;\n    float s,div;\n    scanf(\"%d %d\",&n,&k);\n    for(i=1;i<=n;i++)\n    {\n      scanf(\"%d\",&a[i]);\n      sum=sum+a[i];\n    }\n    i--;\n    s=float(sum);\n    sm=sum;\n    sum=sum/i;\n    s=s/float(i);\n    s=s-float(sum);\n    if(s==0||s<0.5)\n    s=float(sum);\n    else\n    s=float(sum)+1;\n    if(s<float(k-0.5))\n    {\n     s=float(sm);\n     while(1)\n     {\n       s=s+float(k);\n       div=s/float(i+1);\n       i++;\n       if(div>=float(k-0.5))\n        break;\n     }\n     printf(\"%d\",i-n);\n    }\n    else\n    printf(\"%d\",i-n);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e4348d1e95fd4b3dd852384bf8b0755a", "src_uid": "f22267bf3fad0bf342ecf4c27ad3a900", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "include<stdio.h>\nint main()\n{\n    names[4] = { \"Sheldon\", \"Leonard\", \"Penny\", \"Rajesh\", \"Howard\" };\n    long n;\n    scanf(\"%d\",&n);\n    long T[n];\n    for(int i = 0 ; i<n; i++)\n    {\n        for(int j = i; j<=i*i;i++)\n        {\n            T[n]=names[i%4];\n        }\n    }\n    printf(\"%d\",T[n]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7f4d29307344d6b794c00933d73d5f5c", "src_uid": "023b169765e81d896cdc1184e5a82b22", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint a[1000000000];\nint main (){\n    int i,x,n,y=5,z=6;\n    a[0]=1;\n    a[1]=2;\n    a[2]=3;\n    a[3]=4;\n    a[4]=5;\n    scanf(\"%d\",&n);\n    for(i=0;i<n-1;i++){\n    a[y]=a[i];\n    a[z]=a[i];\n    y+=2;\n    z+=2;\n    }\n    x=a[n-1];\n    switch (x){\n        case 1 :\n        printf(\"Sheldon\");\n        break;\n        case 2 :\n        printf(\"Leonard\");\n        break;\n        case 3 :\n        printf(\"Penny\");\n        break;\n        case 4 :\n        printf(\"Rajesh\");\n        break;\n        case 5 :\n        printf(\"Howard\");\n        break;\n    }\n\nreturn 0 ;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "09f7ca259cd7a3b8f3fe9d4e494c5df1", "src_uid": "023b169765e81d896cdc1184e5a82b22", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(){\n    int n;\n    scanf(\"%d\",&n);\n    int a = 1;\n      while(a*5<n){\n          n -= a*5;\n          a *=5;\n      }\n      n = n-1;\n      n = n/a;\n      if(n == 0){\n          printf(\"Sheldon\\n\");\n      }\n      else if (n == 1){\n          printf(\"Leonard\\n\";\n          }\n          else if(n == 2){\n              printf(\"Penny\\n\");\n          }\n          else if (n == 3){\n              printf(\"Rajesh\\n\");\n          }\n          else {\n              printf(\"Howard\\n\");\n          }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "aaf4d09c65d852b75fb5c6349e327400", "src_uid": "023b169765e81d896cdc1184e5a82b22", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main(){\n int i;\n double n;\n char *name[5]={\"Sheldon\",\"Leonard\",\"Penny\",\"Rajesh\",\"Howard\"};\n i=ceil(log(n/5+1)/log(2));\n n=ceil(n-5*(1<<(i-1)-1)/1<<(i-1))\n printf(\"%s\", name[n-1]);\n return 0;\n }", "lang_cluster": "C", "compilation_error": true, "code_uid": "78a2ae32113068979df66050c497b487", "src_uid": "023b169765e81d896cdc1184e5a82b22", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\n#include<math.h>\nint main()\n{\n  int n,f,d=0,a[6],b[6],c=5,i,e=0,g=5;\n  scanf(\"%d\",&n);\n  \n  \n  for(i=1;i<=5;i++)\n  {\n    a[i]=i;\n  }\n  while(c<=n)\n  {\n    e=c;\n    g=g*2;\n    c=c+g;\n    d++;\n  }\n  \n  if(d==0)\n  {\n     if(n==1)\n    printf(\"Sheldon\");\n    if(n==2)\n    printf(\"Leonard\");\n    if(n==3)\n    printf(\"Penny\");\n    if(n==4)\n    printf(\"Rajesh\");\n    if(n==5)\n    printf(\"Howard\");\n  }\n  else\n  {\n  for(i=1;i<=5;i++)\n  {\n    a[i]=a[i]*pow(2,d);\n    b[i]=a[i];\n    b[i]=b[i]+e;\n    \n    printf(\"%d \n  }\n  for(i=1;i<=5;i++)\n  {\n    if(n<=b[i])\n    {\n    if(i==1)\n    printf(\"Sheldon\");\n    if(i==2)\n    printf(\"Leonard\");\n    if(i==3)\n    printf(\"Penny\");\n    if(i==4)\n    printf(\"Rajesh\");\n    if(i==5)\n    printf(\"Howard\");\n    break;\n    }\n    \n  }\n  }\n  return(0);\n  \n  \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c10ef324c377cd17c6993966eddf6482", "src_uid": "023b169765e81d896cdc1184e5a82b22", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nmain()\nint i,e=0;\n{\n    char a,b,c,d;\n    scanf(\"%c%c\",&a,&b);\n    for(i=0;i<5;i++)\n    {\n        scanf(\"%c%c\",&c,&d);\n        if(a==c||a==d) e=e+1;\n        if(b==c||b==d) e=e+1;\n    }\n    if(e!=0) {printf(\"yes\");}\n    else {printf(\"no\");}\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "58baafa18dc492c9e3379574e1d5cfd7", "src_uid": "699444eb6366ad12bc77e7ac2602d74b", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "\n #include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\nstruct liste{\n    char name[30];\n    struct liste *next;\n};\ntypedef struct liste *liste ;\nliste creation(int n){\n    liste head,tmp,pt;\n         head=malloc(sizeof(struct liste));\n         scanf(\"%s\",head->name);\n        if(strlen(head->name)!=2)exit(EXIT_FAILURE);\n            head->next=NULL;\n            pt=head;\n     for(int i=1;i<n;i++){\n           tmp=malloc(sizeof(struct liste));\n           scanf(\"%s\",tmp->name);\n           if(strlen(head->name)!=2)exit(EXIT_FAILURE);\n           tmp->next=NULL;\n           pt->next=tmp;\n           pt=tmp;\n     }\n      return head;\n    \n}\nint traitement(char card[],liste L){\n    int i=0;\n   \nliste p;\n\n    do{\n        p=L;\n             while(p){\n                if(card[i]==p->name[i])){\n                 printf(\"YES\");\n                return 0;\n                                }\n                                p=p->next;\n             }\n             i++;\n             \n       \n    }while(i<2);\n     \n    printf(\"NO\");\n}\n int main(){\nchar card[2];\nliste L;\n scanf(\"%s\",card);\n if(strlen(card)!=2)return 0;\n L=creation(5);\n   traitement(card,L);\n \n      \n \n    \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fc1164627c8144e56b0a06bc0ebfad05", "src_uid": "699444eb6366ad12bc77e7ac2602d74b", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main()\n{\n    char name[3], test[3], ans[] = \"23456789TJQKA\";\n    int i, j, a, length, count = 0,b;\n\n    length = strlen(ans);\n\n\n    scanf(\"%s\", name);\n\n    for(i=1; i<=5; i++)\n    {\n        scanf(\"%s\", test);\n\n        if( (test[0] == 'A' && name[0] == 'A'){\n\n            count = 1;\n        }\n        else if((test[0] == name[0]) && (test[1] == name[1])){\n\n            count = 1;\n        }\n        else if(test[1] == name[1]){\n\n            for(j=0; j<length; j++){\n\n                if( (name[0] == ans[j])){\n\n                    a = (j+1);\n                }\n                if(test[0] == ans[j]){\n\n                    b = (j+1);\n                }\n            }\n\n            if(b>=a){\n\n                count = 1;\n            }\n        }\n    }\n\n    if(count == 1){\n\n        printf(\"YES\\n\");\n    }\n    else{\n        printf(\"NO\\n\");\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8cb4dd8f6fdbf8438280d55a190077b1", "src_uid": "699444eb6366ad12bc77e7ac2602d74b", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_layout_file>\n\t<FileVersion major=\"1\" minor=\"0\" />\n\t<ActiveTarget name=\"Debug\" />\n\t<File name=\"main.c\" open=\"1\" top=\"1\" tabpos=\"1\" split=\"0\" active=\"1\" splitpos=\"0\" zoom_1=\"0\" zoom_2=\"0\">\n\t\t<Cursor>\n\t\t\t<Cursor1 position=\"324\" topLine=\"0\" />\n\t\t</Cursor>\n\t</File>\n</CodeBlocks_layout_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7ef25f8150fca8c1ba5139e22ac5d673", "src_uid": "699444eb6366ad12bc77e7ac2602d74b", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    char card1[2],card2[2];\n    int i=0,ans=0;\n    scanf(\"%c%c\\n\",&card1[0],&card1[1]);\n    while(i<10) { // \u5c0d\u624b\u7684\u724c\n        scanf(\"%c%c\\n\",&card2[0],&card2[1]);\n        if(card2[0] == card1[0])\n            ans++;\n            if(card2[1] == card1[1])\n                ans++;\n        i++;\n    }\n    if (ans > 0)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    char card1[2],card2[2];\n    int i=0,ans=0;\n    scanf(\"%c%c\\n\",&card1[0],&card1[1]);\n    while(i<10) { // \u5c0d\u624b\u7684\u724c\n        scanf(\"%c%c\\n\",&card2[0],&card2[1]);\n        if(card2[0] == card1[0])\n            ans++;\n            if(card2[1] == card1[1])\n                ans++;\n        i++;\n    }\n    if (ans > 0)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    char card1[2],card2[2];\n    int i=0,ans=0;\n    scanf(\"%c%c\\n\",&card1[0],&card1[1]);\n    while(i<10) { // \u5c0d\u624b\u7684\u724c\n        scanf(\"%c%c\\n\",&card2[0],&card2[1]);\n        if(card2[0] == card1[0])\n            ans++;\n            if(card2[1] == card1[1])\n                ans++;\n        i++;\n    }\n    if (ans > 0)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    char card1[2],card2[2];\n    int i=0,ans=0;\n    scanf(\"%c%c\\n\",&card1[0],&card1[1]);\n    while(i<10) { // \u5c0d\u624b\u7684\u724c\n        scanf(\"%c%c\\n\",&card2[0],&card2[1]);\n        if(card2[0] == card1[0])\n            ans++;\n            if(card2[1] == card1[1])\n                ans++;\n        i++;\n    }\n    if (ans > 0)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    char card1[2],card2[2];\n    int i=0,ans=0;\n    scanf(\"%c%c\\n\",&card1[0],&card1[1]);\n    while(i<10) { // \u5c0d\u624b\u7684\u724c\n        scanf(\"%c%c\\n\",&card2[0],&card2[1]);\n        if(card2[0] == card1[0])\n            ans++;\n            if(card2[1] == card1[1])\n                ans++;\n        i++;\n    }\n    if (ans > 0)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    char card1[2],card2[2];\n    int i=0,ans=0;\n    scanf(\"%c%c\\n\",&card1[0],&card1[1]);\n    while(i<10) { // \u5c0d\u624b\u7684\u724c\n        scanf(\"%c%c\\n\",&card2[0],&card2[1]);\n        if(card2[0] == card1[0])\n            ans++;\n            if(card2[1] == card1[1])\n                ans++;\n        i++;\n    }\n    if (ans > 0)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    char card1[2],card2[2];\n    int i=0,ans=0;\n    scanf(\"%c%c\\n\",&card1[0],&card1[1]);\n    while(i<10) { // \u5c0d\u624b\u7684\u724c\n        scanf(\"%c%c\\n\",&card2[0],&card2[1]);\n        if(card2[0] == card1[0])\n            ans++;\n            if(card2[1] == card1[1])\n                ans++;\n        i++;\n    }\n    if (ans > 0)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    char card1[2],card2[2];\n    int i=0,ans=0;\n    scanf(\"%c%c\\n\",&card1[0],&card1[1]);\n    while(i<10) { // \u5c0d\u624b\u7684\u724c\n        scanf(\"%c%c\\n\",&card2[0],&card2[1]);\n        if(card2[0] == card1[0])\n            ans++;\n            if(card2[1] == card1[1])\n                ans++;\n        i++;\n    }\n    if (ans > 0)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    char card1[2],card2[2];\n    int i=0,ans=0;\n    scanf(\"%c%c\\n\",&card1[0],&card1[1]);\n    while(i<10) { // \u5c0d\u624b\u7684\u724c\n        scanf(\"%c%c\\n\",&card2[0],&card2[1]);\n        if(card2[0] == card1[0])\n            ans++;\n            if(card2[1] == card1[1])\n                ans++;\n        i++;\n    }\n    if (ans > 0)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    char card1[2],card2[2];\n    int i=0,ans=0;\n    scanf(\"%c%c\\n\",&card1[0],&card1[1]);\n    while(i<10) { // \u5c0d\u624b\u7684\u724c\n        scanf(\"%c%c\\n\",&card2[0],&card2[1]);\n        if(card2[0] == card1[0])\n            ans++;\n            if(card2[1] == card1[1])\n                ans++;\n        i++;\n    }\n    if (ans > 0)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    char card1[2],card2[2];\n    int i=0,ans=0;\n    scanf(\"%c%c\\n\",&card1[0],&card1[1]);\n    while(i<10) { // \u5c0d\u624b\u7684\u724c\n        scanf(\"%c%c\\n\",&card2[0],&card2[1]);\n        if(card2[0] == card1[0])\n            ans++;\n            if(card2[1] == card1[1])\n                ans++;\n        i++;\n    }\n    if (ans > 0)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    char card1[2],card2[2];\n    int i=0,ans=0;\n    scanf(\"%c%c\\n\",&card1[0],&card1[1]);\n    while(i<10) { // \u5c0d\u624b\u7684\u724c\n        scanf(\"%c%c\\n\",&card2[0],&card2[1]);\n        if(card2[0] == card1[0])\n            ans++;\n            if(card2[1] == card1[1])\n                ans++;\n        i++;\n    }\n    if (ans > 0)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    char card1[2],card2[2];\n    int i=0,ans=0;\n    scanf(\"%c%c\\n\",&card1[0],&card1[1]);\n    while(i<10) { // \u5c0d\u624b\u7684\u724c\n        scanf(\"%c%c\\n\",&card2[0],&card2[1]);\n        if(card2[0] == card1[0])\n            ans++;\n            if(card2[1] == card1[1])\n                ans++;\n        i++;\n    }\n    if (ans > 0)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    char card1[2],card2[2];\n    int i=0,ans=0;\n    scanf(\"%c%c\\n\",&card1[0],&card1[1]);\n    while(i<10) { // \u5c0d\u624b\u7684\u724c\n        scanf(\"%c%c\\n\",&card2[0],&card2[1]);\n        if(card2[0] == card1[0])\n            ans++;\n            if(card2[1] == card1[1])\n                ans++;\n        i++;\n    }\n    if (ans > 0)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    char card1[2],card2[2];\n    int i=0,ans=0;\n    scanf(\"%c%c\\n\",&card1[0],&card1[1]);\n    while(i<10) { // \u5c0d\u624b\u7684\u724c\n        scanf(\"%c%c\\n\",&card2[0],&card2[1]);\n        if(card2[0] == card1[0])\n            ans++;\n            if(card2[1] == card1[1])\n                ans++;\n        i++;\n    }\n    if (ans > 0)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    char card1[2],card2[2];\n    int i=0,ans=0;\n    scanf(\"%c%c\\n\",&card1[0],&card1[1]);\n    while(i<10) { // \u5c0d\u624b\u7684\u724c\n        scanf(\"%c%c\\n\",&card2[0],&card2[1]);\n        if(card2[0] == card1[0])\n            ans++;\n            if(card2[1] == card1[1])\n                ans++;\n        i++;\n    }\n    if (ans > 0)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    char card1[2],card2[2];\n    int i=0,ans=0;\n    scanf(\"%c%c\\n\",&card1[0],&card1[1]);\n    while(i<10) { // \u5c0d\u624b\u7684\u724c\n        scanf(\"%c%c\\n\",&card2[0],&card2[1]);\n        if(card2[0] == card1[0])\n            ans++;\n            if(card2[1] == card1[1])\n                ans++;\n        i++;\n    }\n    if (ans > 0)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    char card1[2],card2[2];\n    int i=0,ans=0;\n    scanf(\"%c%c\\n\",&card1[0],&card1[1]);\n    while(i<10) { // \u5c0d\u624b\u7684\u724c\n        scanf(\"%c%c\\n\",&card2[0],&card2[1]);\n        if(card2[0] == card1[0])\n            ans++;\n            if(card2[1] == card1[1])\n                ans++;\n        i++;\n    }\n    if (ans > 0)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d185c9f8d82a9c0ffd4341559dc413df", "src_uid": "699444eb6366ad12bc77e7ac2602d74b", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n\nint main()\n{\n\tlong x[4] = { -1, -1, -2, -2 }, i, j, n, temp;\n\tscanf(\"%d\", &n);\n\tfor (i = 0; i < n; ++i)\n\t{\n\t\tscanf(\"%d\", &x[i]);\n\t}\n\tfor (i = 0; i < n; ++i)\n\t{\n\t\tfor (j = i + 1; j < n; ++j)\n\t\t{\n\t\t\tif (x[i]>x[j])\n\t\t\t{\n\t\t\t\ttemp = x[i];\n\t\t\t\tx[i] = x[j];\n\t\t\t\tx[j] = temp;\n\t\t\t}\n\t\t}\n\t}\n\tif (x[0] != x[2] && x[1] != x[3])\n\t{\n\t\tif (n == 0)\n\t\t{\n\t\t\tprintf(\"YES\\n%ld\\n%ld\\n%ld\\n%ld\", 1, 1, 3, 3);\n\t\t}\n\t\telse\n\t\tif (n == 1)\n\t\t{\n\t\t\tprintf(\"YES\\n%ld\\n%ld\\n%ld\", x[0], 3 * x[0], 3 * x[0]);\n\t\t}\n\t\telse if (n == 2)\n\t\t{\n\t\t\tif (x[1] > 3 * x[0])\n\t\t\t\tprintf(\"NO\");\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\"YES\\n%ld\\n%ld\", 4 * x[0] - x[1], 3 * x[0]);\n\t\t\t}\n\t\t}\n\t\telse if (n == 3)\n\t\t{\n\n\t\t\tif (x[2] == (3 * x[0]))\n\t\t\t\tprintf(\"YES\\n%ld\", 4 * x[0] - x[1]);\n\t\t\telse if (x[1] + x[2] == 4 * x[0])\n\t\t\t\tprintf(\"YES\\n%ld\", 3 * x[0]);\n\t\t\telse if (x[0] + x[1] == 4 * x[2] / 3)\n\t\t\t\tprintf(\"YES\\n%ld\", x[2] / 3);\n\t\t\telse\n\t\t\t\tprintf(\"NO\");\n\n\t\t}\n\t\telse if (n == 4)\n\t\t{\n\t\t\tif (x[3] == 3 * x[0] && x[1] + x[2] == 4 * x[0])\n\t\t\t\tprintf(\"YES\");\n\t\t\telse\n\t\t\t\tprintf(\"NO\");\n\t\t}\n\t}\n\telse\n\t{\n\t\tprintf(\"NO\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a826e6fbbf4c029381fae8292d0e76c9", "src_uid": "230e613abf0f6a768829cbc1f1a09219", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint cmpfunc (const void * a, const void * b)\n{\n   return ( *(int*)a - *(int*)b );\n}\n\n\nint main()\n{\n\tint A[4];\n\tint n,i,j;\n\tint mean,median,range;\n\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++)\n\t\tscanf(\"%d\",&A[i]);\n\n\tqsort(A,n,sizeof(int),cmpfunc);\n\tif(n==4)\n\t{\n\t\tmean=A[0]+A[1]+A[2]+A[3];\n\n\t\tmedian=(A[1]+A[2])*2;\n\n\t\trange=(A[3]-A[0])*4;\n\n\t\tif(mean==median && median==range)\n\t\t\tprintf(\"YES\\n\");\n\t\telse\n\t\t\tprintf(\"NO\\n\");\n\t}\n\telse if(n==3)\n\t{\n\t\tint B[4];\n\t\tfor(i=1;i<=1000000;i++)\n\t\t{\n\t\t\tfor(j=0;j<3;j++)\n\t\t\t\tB[j]=A[j];\n\t\t\tB[j]=i;\n\n\t\t\tqsort(B,4,sizeof(int),cmpfunc);\n\n\t\t\tmedian=(B[1]+B[2])*2;\n\t\t\tmean=(B[0]+B[1]+B[2]+B[3]);\n\t\t\trange=(B[3]-B[0])*4;\n\n\t\t\tif(mean==median && median==range)\n\t\t\t{\n\t\t\t\tprintf(\"YES\\n%d\\n\",i);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\tprintf(\"NO\\n\");\n\t}\n\telse if(n==2)\n\t{\n\t\tint B[4];\n\t\tfor(i=1;i<=1000000;i++)\n\t\t{\n\t\t\tfor(j=0;j<2;j++)\n\t\t\t\tB[j]=A[j];\n\t\t\tint x,y;\n\t\t\tx=i;\n\t\t\tB[j]=i;\n\t\t\tqsort(B,3,sizeof(int),cmpfunc);\n\t\t\tB[3]=B[1]+B[2]-B[0];\n\t\t\ty=B[3];\n\n\t\t\tqsort(B,4,sizeof(int),cmpfunc);\n\t\t\tmedian=(B[1]+B[2])*2;\n\t\t\tmean=(B[0]+B[1]+B[2]+B[3]);\n\t\t\trange=(B[3]-B[0])*4;\n\n\t\t\tif(mean==median && median==range)\n\t\t\t{\n\t\t\t\tprintf(\"YES\\n%d\\n%d\\n\",x,y);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\tprintf(\"NO\\n\");\n\t}\n\telse if(n==1 || n==0)\n\t{\n\t\tint a,b,c,d;\n\t\tif(n==0)\n\t\t\tb=1;\n\t\telse \n\t\t\tb=A[0];\n\t\tfor(i=1;i<=b;i++)\n\t\t{\n\t\t\ta=i;\n\t\t\tfor(j=b;j<=1000000;j++)\n\t\t\t{\n\t\t\t\tc=j;\n\t\t\t\tmedian=(b+c)*2;\n\t\t\t\tmean=a+b+c;\n\t\t\t\td=median-mean;\n\t\t\t\tmean+=d;\n\t\t\t\trange=(d-a)*4;\n\t\t\t\tif(range==mean && range==median)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\tprintf(\"%d\\n\",a);\n\t\t\t\t\tif(n==0)\n\t\t\t\t\t\tprintf(\"%d\\n\",b);\n\t\t\t\t\tprintf(\"%d\\n\",c);\n\t\t\t\t\tprintf(\"%d\\n\",d);\n\t\t\t\t\treturn 0;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tprintf(\"NO\\n\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "43dbda06feaed40913ddf72feed769a4", "src_uid": "230e613abf0f6a768829cbc1f1a09219", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n\n\nint main(void){\n    int n,i,aux; int t[6];\nscanf(\"%d\",&n);\nif (n==0) { printf(\"YES\\n\"); printf(\"1\\n\"); printf(\"1\\n\"); printf(\"3\\n\"); printf(\"3\");}\nelse for(i=0;i<=n-1;i++) { scanf(\"%d\",&t[i]);}\n\nif (n==1) { printf(\"YES\\n\"); printf(\"%d\\n\",t[0]); printf(\"%d\\n\",3*t[0]); printf(\"%d\\n\",3*t[0]);}\n\nif (n==2) {\n        if (t[0]>t[1]) {aux=t[0]; t[0]=t[1]; t[1]=aux;}\n    if (3*t[0]<t[1]) printf(\"NO\"); else{printf(\"YES\\n\");printf(\"%d\\n\",4*t[0]-t[1]); printf(\"%d\\n\",3*t[0]);\n}}\n\n if (n==3) {\n    if ( 4*t[0]!=t[1]+t[2] && 4*t[1]!=t[0]+t[2] && 4*t[2]!=t[1]+t[0]) printf(\"NO\");\n    else{printf(\"YES\\n\");\n    for(i=n-1; i>=0;i--)\n        for(j=0;j<=i-1;j++) if (t[j]>t[j+1]) {aux=t[j]; t[j]=t[j+1]; t[j+1]=aux;} \n    if (t[1]+t[2]==4*t[0]) printf(\"%d\",3*t[0]);\n    else if (t[2]%3==0 && t[0]+t[1]==(4*t[2])/3) printf(\"%d\",t[2]/3);\n    else if (t[2]==3*t[0]) printf(\"%d\",t[0]+t[2]-t[1]);\n    else for (i=1;i<=500;i++) if (i==3*t[0] && i+t[0]==t[1]+t[2])  {printf(\"%d\",i); break;}\n\n        }\n }\n if (n==4) {\n    if (t[3]==3*t[0] && t[3]+t[0]==t[1]+t[2]) printf(\"YES\\n\");\n    else printf(\"NO\");\n }\n\n\nreturn 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4c65d348a73254d86003d2eaa5df245b", "src_uid": "230e613abf0f6a768829cbc1f1a09219", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<stdbool.h>\n#define Y \"YES\"\n#define N \"NO\"\nint Merge(long long *a, int l, int r);\nlong long temp[7];\nint main(void)\n{\n    int n;\n    long long a[7];\n\n    bool find = false;\n    scanf(\"%d\", &n);\n    if (n == 0)\n        printf(\"%s\\n%d\\n%d\\n%d\\n%d\\n\", Y,1,1,3,3);\n    else if (n == 1)\n    {\n        scanf(\"%I64d\", &a[1]);\n        a[4] = 3*a[1];\n        for (a[2] = a[1]; a[2] <= a[4]&&!find; a[2]++)\n            {\n                for (a[3] = a[2]; a[3] <= a[4]&&!find; a[3]++)\n                    if ((a[2] + a[3]) == 4 * a[1])\n                    {\n                        find = true;\n                        break;\n                    }\n                if (find)\n                  break;\n            }\n        if (find)\n            printf(\"%s\\n%I64d\\n%I64d\\n%I64d\\n\", Y, a[2], a[3], a[4]);\n        else\n            printf(\"%s\\n\", N);\n\n    }\n    else if (n == 2)\n    {\n        scanf(\"%I64d%I64d\", &a[1], &a[2]);\n        Merge(a, 1, n);\n        a[4] = 3 * a[1];\n                for (a[3] = a[2]; a[3] <= a[4]&&!find;a[3]++)\n                    if (a[3] == (4 * a[1] - a[2]) && a[3] >= a[2])\n                        {\n                            find = true;\n                            break;\n                        }\n        if (find)\n            printf(\"%s\\n%I64d\\n%I64d\\n\", Y, a[3], a[4]);\n        else\n            printf(\"%s\\n\", N);\n    }\n    else if (n == 3)\n    {\n        scanf(\"%I64d%I64d%I64d\", &a[1], &a[2], &a[3]);\n        Merge(a, 1, n);\n        a[4] = 3* a[1];\n            if (a[4] >= a[3] && (a[2] + a[3]) == 4 * a[1])\n                find = true;\n            else\n                find = false;\n        if (find)\n            printf(\"%s\\n%I64d\\n\", Y, a[4]);\n        else\n            printf(\"%s\\n\", N);\n\n    }\n    else\n    {\n        scanf(\"%I64d%I64d%I64d%I64d\", &a[1], &a[2], &a[3], &a[4]);\n            if (a[4] = 3 * a[1] && (a[2] + a[3]) == 4 * a[1])\n                find = true;\n            else\n                find = false;\n        if (find)\n            printf(\"%s\\n\", Y);\n        else\n            printf(\"%s\\n\", N);\n    }\n\n\n    return 0;\n}\n\n\nint Merge(int *a, int l, int r)\n{\n    int mid = (l + r) / 2;\n    int q = l, p = mid + 1, i = l;\n    if (l == r)\n        return 0;\n    Merge(a, l, mid);\n    Merge(a, mid + 1, r);\n    while (q <= mid || p <= r)\n    if (q > mid || (p <= r&&a[q] > a[p]))\n        temp[i++] = a[p++];\n    else\n        temp[i++] = a[q++];\n\n    for (i = l; i <= r; i++)\n        a[i] = temp[i];\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6b8326d495aa4bafa128b571b13996bf", "src_uid": "230e613abf0f6a768829cbc1f1a09219", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n,i,temp,c,d;\n    scanf(\"%d\",&n);\n    int a[4];\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        //printf(\"%d\\n\",a[i]);\n    }\n    if(n==0)\n    {\n        printf(\"YES\\n\");\n        printf(\"1\\n1\\n3\\n3\\n\");\n        return 0;\n    }\n    else if(n==1)\n    {\n        a[3]=3*a[0];\n        a[1]=a[0];\n        a[2]=(4*a[0]-a[1]);\n        printf(\"YES\\n\");\n        printf(\"%d\\n%d\\n%d\\n\",a[1],a[2],a[3]);\n        return 0;\n    }\n    else if(n==2)\n    {\n        if(a[0]>a[1])\n        {\n            temp=a[0];\n            a[0]=a[1];\n            a[1]=temp;\n        }\n        if(a[1]==(3*a[0]))\n        {\n            a[3]=a[1];\n            a[1]=a[0];\n            a[2]=(4*a[0]-a[1]);\n            printf(\"YES\\n\");\n            printf(\"%d\\n%d\\n\",a[1],a[2]);\n            return 0;\n\n        }\n        else if(a[1]>(3*a[0]))\n        {\n            printf(\"NO\\n\");\n            return 0;\n\n        }\n        else\n        {\n            a[3]=3*a[0];\n            a[2]=(4*a[0]-a[1]);\n            printf(\"YES\\n\");\n            printf(\"%d\\n%d\\n\",a[2],a[3]);\n            return 0;\n        }\n    }\n    else if(n==3)\n    {\n         for (c = 0 ; c < ( n - 1 ); c++)\n         {\n            for (d = 0 ; d < (n - 1); d++)\n            {\n                if (a[d] > a[d+1])\n                {\n                     temp= a[d];\n                     a[d] = a[d+1];\n                     a[d+1] = temp;\n                }\n            }\n         }\n         if(a[2]>(3*a[0]))\n         {\n             printf(\"NO\\n\");\n             return 0;\n         }\n         if(a[2]==3*a[0])\n         {\n             a[3]=a[2];\n             a[2]=((4*a[0])-a[1]);\n             printf(\"YES\\n\");\n             printf(\"%d\\n\",a[2]);\n             return 0;\n         }\n         if(a[2]<(3*a[0]))\n         {\n             if((a[2]/3)==a[0]+a[1])\n             {\n                 for(c=3;c>=1;c--)\n                 {\n                     a[c]=a[c-1];\n                 }\n                 a[0]=a[3]/3;\n                 printf(\"%d\\n\",c[0]);\n             }\n             if(a[1]+a[2]==(4*a[0]))\n             {\n                 a[3]=3*a[0];\n                 printf(\"YES\\n\");\n                 printf(\"%d\\n\",a[3]);\n                 return 0;\n             }\n             else\n             {\n                 printf(\"NO\\n\");\n                 return 0;\n             }\n         }\n\n    }\n    else if(n==4)\n    {\n        if((a[3]==(3*a[0]))&&(a[1]+a[2]==(4*a[0])))\n        {\n            printf(\"YES\\n\");\n            return 0;\n        }\n        else\n        {\n            printf(\"NO\\n\");\n            return 0;\n        }\n    }\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8cabeaa2a055cb02d63c20eb3cf985ba", "src_uid": "230e613abf0f6a768829cbc1f1a09219", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n\tint n, m, k, s=0;\n\tscanf(\"%d\", &n);\n\tscanf(\"%d\", &m);\n\n\tif (m%n != 0 )\n\t\tprintf(\"-1\\n\");\n\telse if (m == n)\n\t\tprintf(\"0\\n\");\n    else\n\t{\n\n\t\tk = m / n;\n\t\twhile (k != 1)\n\t\t{\n\t\t\tif (k % 6 == 0)\n\t\t\t{\n\t\t\t\ts += 2;\n\t\t\t\tk /= 6;\n\t\t\t}\n\n\t\t\telse if (k % 2 == 0)\n\t\t\t{\n\t\t\t\ts += 1;\n\t\t\t\tk /= 2;\n\t\t\t}\n\t\t\telse if (k % 3 == 0)\n\t\t\t{\n\t\t\t\ts += 1;\n\t\t\t\tk /= 3;\n\t\t\t}\n\t\t\telse\n            {\n                c=-1;\n                break;\n            }\n\t\t}\n\t\tprintf(\"%d\\n\", s);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8633a1740a76cd7c9514f552fc702c36", "src_uid": "3f9980ad292185f63a80bce10705e806", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "}\n#include<stdio.h>\nint main()\n{\n    int a, b;\n    scanf(\"%d %d\", &a, &b);\n    if (b % a != 0) {\n        printf(\"-1\");\n        return 0;\n    }\n    b /= a;\n    a = 0;\n\n    while (b % 2 == 0) {\n        b /= 2; \n        a++; \n    }\n    while (b % 3 == 0) { \n        b /= 3;\n        a++; \n    }\n    if (b != 1) a = -1;\n    printf(\"%d\", a);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "841f8751c646cbc9ae483d40137c694c", "src_uid": "3f9980ad292185f63a80bce10705e806", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int m,n,i,j,count=0;\n    scanf(\"%d %d\",&n,&m);\n    if(m==n)\n    printf(\"0\");\n    else if(m%n==0)\n    {\n        m=m/n;\n    do\n        {\n            if(m%2==0)\n            {\n                m=m/2;\n                count++;\n            }\n            else if\n                {\n                   if(m%3==0)\n                {\n                   m=m/3;\n                count++;\n            }\n            else \n            {\n                printf(\"-1\");\n                break;\n            }\n                \n                }\n        }while(m!=1);\n        printf(\"%d\",count);\n    }\n    else if(m%n!=0||m<n*2)\n    {\n        printf(\"-1\");\n    }\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7e91265a5d2d17184e370af9019d8767", "src_uid": "3f9980ad292185f63a80bce10705e806", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\nusing namespace std;\n\nint GAME23 (){\n    int n;\n    int m1;\n    int m;\n    int p=0,q=0;\n    cin>>n>>m;\n    m1=m/n;\n    if (m==n)\n        return(0) ;\n    else if (m%n!=0){\n        return(-1);\n    }\n    else {\n            while(m1%2==0){\n                m1=m1/2;\n                p++;\n            }\n            if(p>1) m1=m1*2;\n            while(m1%3==0){\n                m1=m1/3;\n                q++;\n            }\n\n            return(p+q);\n\n}\n}\n\nint main()\n{\ncout<<GAME23();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1c4f136a9e8266423b86c4de4f5e1f76", "src_uid": "3f9980ad292185f63a80bce10705e806", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int a,b;\n    scanf(\"%d %d\",&a,&b);\n    if(a==b)\n    {\n        printf(\"0\");return 0;\n    }\n    int c=0;\n    while(a*6<=b)\n    {\n        a=a*6;\n        c=c+2;\n    }\n    if(a*2=b)\n    c++;\n    else if(a*3==b)\n    c++;\n    \n    if(c==0)\n    printf(\"-1\");\n    else\n    printf(\"%d\",c);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "27051d8cd5ef518c5218f9b019b73788", "src_uid": "3f9980ad292185f63a80bce10705e806", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\nint n;\nscanf(\"%d\",&n);\nint a[7],b=0;\nfor(int i=0;i<7;++i) \n{\nscanf(\"%d\",&a[i]);\nb+=a[i];\n}\nif(b==n)\n{\nprintf(\"7\");\nreturn 0\n}\nelse{\nn%=b;\nif(n/a[0]==0 || (n/a[0]==1 && n%a[0]==0)) \n{\nprintf(\"1\");\nreturn 0;\n}\nelse n-=a[0];\nif(n/a[1]==0 || (n/a[1]==1 && n%a[1]==0)) \n{\nprintf(\"2\");\nreturn 0;\n}\nelse n-=a[1];\nif(n/a[2]==0 || (n/a[2]==1 && n%a[2]==0)) \n{\nprintf(\"3\");\nreturn 0;\n}\nelse n-=a[2];\nif(n/a[3]==0 || (n/a[3]==1 && n%a[3]==0)) \n{\nprintf(\"4\");\nreturn 0;\n}\nelse n-=a[3];\nif(n/a[4]==0 || (n/a[4]==1 && n%a[4]==0)) \n{\nprintf(\"5\");\nreturn 0;\n}\nelse n-=a[4];\nif(n/a[5]==0 || (n/a[5]==1 && n%a[5]==0)) \n{\nprintf(\"6\");\nreturn 0;\n}\nelse n-=a[5];\nif(n/a[6]==0 || (n/a[6]==1 && n%a[6]==0)) \n{\nprintf(\"7\");\nreturn 0;\n}\nelse n-=a[6];\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b7cd433438560415d08879edde07ad7a", "src_uid": "007a779d966e2e9219789d6d9da7002c", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "/*One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly n pages.\n\nPetr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight schedule and for each day of the week he knows how many pages he will be able to read on that day. Some days are so busy that Petr will have no time to read whatsoever. However, we know that he will be able to read at least one page a week.\n\nAssuming that Petr will not skip days and will read as much as he can every day, determine on which day of the week he will read the last page of the book.\n\nInput\nThe first input line contains the single integer n (1<=n<=1000) the number of pages in the book.\n\nThe second line contains seven non-negative space-separated integers that do not exceed 1000 \ufffd\ufffd those integers represent how many pages Petr can read on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and Sunday correspondingly. It is guaranteed that at least one of those numbers is larger than zero.\n\nOutput\nPrint a single number \ufffd\ufffd the number of the day of the week, when Petr will finish reading the book. The days of the week are numbered starting with one in the natural order: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.\n\nExamples\ninput\n100\n15 20 20 15 10 30 45\noutput\n6\ninput\n2\n1 0 0 0 0 0 0\noutput\n1*/\n#include<stdio.h>\nusing namespace std;\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    int pagenum[7];\n    for(int i=0;i<7;i++)\n        scanf(\"%d\",&pagenum[i]);\n    int sum = 0,i;\n    for(i=0;sum<n;i++)\n    {\n        i = i%7;\n        sum += pagenum[i];\n    }\n    printf(\"%d\",i);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "21aad676d23254e5e787f38b746d2cbf", "src_uid": "007a779d966e2e9219789d6d9da7002c", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "/*One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly n pages.\n\nPetr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight schedule and for each day of the week he knows how many pages he will be able to read on that day. Some days are so busy that Petr will have no time to read whatsoever. However, we know that he will be able to read at least one page a week.\n\nAssuming that Petr will not skip days and will read as much as he can every day, determine on which day of the week he will read the last page of the book.\n\nInput\nThe first input line contains the single integer n (1<=n<=1000) the number of pages in the book.\n\nThe second line contains seven non-negative space-separated integers that do not exceed 1000 \ufffd\ufffd those integers represent how many pages Petr can read on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and Sunday correspondingly. It is guaranteed that at least one of those numbers is larger than zero.\n\nOutput\nPrint a single number \ufffd\ufffd the number of the day of the week, when Petr will finish reading the book. The days of the week are numbered starting with one in the natural order: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.\n\nExamples\ninput\n100\n15 20 20 15 10 30 45\noutput\n6\ninput\n2\n1 0 0 0 0 0 0\noutput\n1*/\n#include<cstdio>\n#include<cstring>\nusing namespace std;\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    int pagenum[7];\n    for(int i=0;i<7;i++)\n        scanf(\"%d\",&pagenum[i]);\n    int sum = 0,i;\n    for(i=0;sum<n;i++)\n    {\n        i = i%7;\n        sum += pagenum[i];\n    }\n    printf(\"%d\",i);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "26aa5109bdf8c97a1a033d0e6bda0ca1", "src_uid": "007a779d966e2e9219789d6d9da7002c", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n    int count=0,n,a[7],i;\n    scanf(\"%d\",&n);\n    for(i=0;i<7;i++)\n    {\n    scanf(\"%d\",&a[i]);\n    }\n    while(count<=n)\n    {\n        for(i=0;i<7;i++)\n        {\n            if(count+a[i]4<n)\n            {\n                count+=a[i];\n            }\n            else\n            {\n                printf(\"%d\",i+1);\n                exit(0);\n            }\n        }\n    }\n    return 0;\n}\n                ", "lang_cluster": "C", "compilation_error": true, "code_uid": "cb61362290658ff6e47c8692fb9d602c", "src_uid": "007a779d966e2e9219789d6d9da7002c", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int n,i;\n    int a[7];\n    /*printf(\"Enter n\");*/\n    scanf(\"%d\",&n);\n    for (i=0 ; i<7 ; i++)\n    {\n        /*printf(\"Enter n in month %d\",i+1);*/\n        scanf(\"%d\",&a[i]);\n    }\n    for (i=0 ; i<7 ; i++)\n    {\n        n=n-a[i];\n        if (n<=0)\n        break;\n        if (i==6)\n            i=-1;\n    }\n    printf(\"%d\",i+1);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8b56712551e2bfa2c617649e16a350d6", "src_uid": "007a779d966e2e9219789d6d9da7002c", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "include<stdio.h>\nint main()\n{\nint n,i,c=0;\nscanf(\"%d\",&n);\nfor(i=1;i<=n/2;i++)\nif(n%i==0)\n{\nc++\n}\n}\nprintf(\"%d\\n\",c);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6d1ebdb6ad693e1475946fd212e038e3", "src_uid": "89f6c1659e5addbf909eddedb785d894", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n    int n,c=0;\n        cin>>n;\n    for (int i=2; i<=n; i++)\n    {\n        if(n%i==0)\n        {\n            c++;\n        }\n\n    }\n    cout<<c<<endl;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8c53f5862811738de88d389f428e4af8", "src_uid": "89f6c1659e5addbf909eddedb785d894", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nusing namespace std;\nint main(){\n\tint n;\n\tscanf(\"%d\",&n);\n\tint count=1; \n\tfor(int i = 2; i <= sqrt(n); i++){\n\t\tif(n%i==0){\n\t\t\tif(n%(i * i) != 0)\n\t\t\t\tcount+=2;\n\t\t\telse count++;\n\t\t\tn/=i;\n\t\t}\n\t}\n\tprintf(\"%d\",count);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fe78d4338daf0140d7bca5e80737d399", "src_uid": "89f6c1659e5addbf909eddedb785d894", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    int flag=0;\n    scanf(\"%d\",&n);\n    for(int i=1;i=<n/2;i++)\n    {\n        if((n-i)%i==0)\n        flag++;\n        \n    }\n    printf(\"%d\",flag);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8cf32f294186ab5a2fe205a061f0b7f6", "src_uid": "89f6c1659e5addbf909eddedb785d894", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    long int j,n,c=0;\n    scanf(\"%ld\",&n);\n    j=n;\n    for(i=1;i<=(n/2+1);i++)\n    {\n       if(j!=1)\n       j=j/2;\n       \n       if((j+1)*i==n)\n       c++;\n       \n       printf(\"%ld\",c);\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b92117de63f990d139ea7e625bc9e4b3", "src_uid": "89f6c1659e5addbf909eddedb785d894", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nchar m[7][5]={\"jolt\",\"flar\",\"umbr\",\"leaf\",\"glac\",\"sylv\"};\nint main()\n{\n\tint n;char s[5];\n\tscanf(\"%d%s\",&n,s);\n\n\tif(n==8)puts(\"vaporeon\");\n\tif(n==6)puts(\"espeon\");\n\n\tif(n==7)\n\t{\n\t\tfor(int i=0;i<6;i++)\n\t\t{\n\t\t\tbool flag=true;\n\t\t\tfor(int j=0;j<4;j++)\n\t\t\t{\n\t\t\t\tif(s[j]!='.'&&s[j]!=m[i][j]){flag=false;break;}\n\t\t\t}\n\t\t\tif(flag)\n\t\t\t{\n\t\t\t\tprintf(\"%seon\",m[i]);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d668eea76da06f9a23cd3bfc205a410c", "src_uid": "ec3d15ff198d1e4ab9fd04dd3b12e6c0", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    char a[9];\n    int i,n;\n    scanf(\"%d\",&n);\n    for(i=0;i<=7;i++)\n              scanf(\"%c\",&a[i]);\n    if(a[1]=='v'||a[2]=='a'||a[5]=='r')\n    printf(\"vaporeon\");\n    else if(a[1]=='j'||a[2]=='o'||a[4]=='t')\n    printf(\"jolteon\");\n    else if(a[1]=='f'||a[2]=='l'&&a[4]=='r')\n    printf(\"flareon\");\n    else if(a[1]=='e'||a[2]=='s'||)\n    printf(\"espeon\");\n    else if(a[1]=='u'||a[2]=='m'||a[3]=='b')\n    printf(\"umbreon\");\n    else if(a[1]=='l'||a[2]=='e'||a[4]=='f')\n    printf(\"leafeon\");\n    else if(a[1]=='g'||a[2]=='l'&&a[4]=='c')\n    printf(\"glaceon\");\n    else if(a[1]=='s'||a[2]=='y'||a[4]=='v')\n    printf(\"sylveon\");\n    else\n    printf(\"espeon\");\n    return(0);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b50d49674fda21fca7ec7b5ab19ea41a", "src_uid": "ec3d15ff198d1e4ab9fd04dd3b12e6c0", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nint main(void) {\n    int n,l;\n    scanf(\"%d\",&n);\n    char a[8];\n    scanf(\"%s\",a);\n    l=strlen(a);\n    if(l==6)\n    printf(\"espeon\\n\");\n    else if(l==8)\n    printf(\"vaporeon\\n\");\n    else{\n    \n            if((a[0]=='.'||a[0]=='j')&&(a[1]=='.'||a[1]=='o')&&(a[2]=='l'||a[2]=='.')&&(a[3]=='t'||a[3]=='.'))\n            printf(\"jolteon\\n\");\n            else if((a[0]=='.'||a[0]=='g')&&(a[1]=='.'||a[1]=='l')&&(a[2]=='a'||a[2]=='.')&&(a[3]=='c'||a[3]=='.'))\n            printf(\"glaceon\\n\");\n            else if((a[0]=='.'||a[0]=='f')&&(a[1]=='.'||a[1]=='l')&&(a[2]=='a'||a[2]=='.')&&(a[3]=='r'||a[3]=='.'))\n            printf(\"flareon\\n\");\n            else if((a[0]=='.'||a[0]=='s')&&(a[1]=='.'||a[1]=='y')&&(a[2]=='l'||a[2]=='.')&&(a[3]=='v'||a[3]=='.'))\n    \n            else\n            printf(\"umbreon\\n\");\n        }\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "45c598de71cbfe0ad7a1c44701bc2f69", "src_uid": "ec3d15ff198d1e4ab9fd04dd3b12e6c0", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int n, i, j, check;\n    char s[10], s1[6][10]={\"jolteon\", \"flareon\", \"umbreon\", \"leafeon\", \"glaceon\", \"sylveon\"};\n    scanf(\"%d\", &n);\n    scanf(\"%s\", &s);\n    if(n==8) printf(\"vaporeon\\n\");\n    else if(n==6) printf(\"espeon\\n\");\n    else\n    {\n        for(i=0;i<6;i++)\n        {\n            check=1;\n            for(j=0;j<7;j++)\n            {\n                if(s[j]!='.' && s[j]!=s1[i][j])\n                {\n                    check=0;\n                    break;\n                }\n            }\n            if(check)\n            {\n                printf(\"%s\\n\", s1[i]);\n                return 0;\n            }\n        }\n    }\n\n    return 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "707904d99e12ba93e2dbe7fa82336c01", "src_uid": "ec3d15ff198d1e4ab9fd04dd3b12e6c0", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nchar str[8][10]={\"vaporeon\", \"jolteon\", \"flareon\", \"espeon\", \"umbreon\", \"leafeon\", \"glaceon\", \"sylveon\"};\n\nint main()\n{\n\tint n,i,j;\n\tchar inp[10];\n\tint flag[8];\n\tmemset(flag,1,sizeof(flag));\n\tscanf(\"%d\",&n);\n\tscanf(\"%s\",inp);\n\tint length=strlen(inp);\n\tfor(i=0; i<length; i++)\n\t\tif(inp[i]!='.') {\n\t\tfor(j=0; j<8; j++) \n\t\t\tif(str[j][i]!='\\0' && str[j][i]!=inp[i]) {flag[j]=0;}\n\t\t}\n\tfor(i=0; i<8; i++)\n\t\tif(flag[i]!=0)\n\t\t\tprintf(\"%s\",str[i]);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "fe74ddb4abed43a4b1f33374a41669fd", "src_uid": "ec3d15ff198d1e4ab9fd04dd3b12e6c0", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nshort target[3005]={0};\nreturn main(void)\n{\n\tshort n,i,j,sum=0;\n\t\n\tscanf(\"%hd\",&n);\n\t\n\tfor(i=2;i<=n;i++)\n\t{\n\tfor(j=2;j<i && target[i]<=2;j++)\n\t{\n\t\t//printf(\"I:%hd target[I]:%hd\\nJ:%hd target[J]:%hd\\n\",i,target[i],j,target[j]);\n\t\tif(i%j==0 && target[j]==0)\n\t\t{\n//\t\t\tprintf(\"%hd %hd\\n\",i,j);\n\t\t\ttarget[i]++;\n\t\t}\n    }\n\t\tif(target[i]==2)\n\t\t{\n\t\t\t//printf(\"\\t\\t%hd %hd\\n\",i,j);\n\t\t\tsum++;\n\t\t}\n\t}\n\t\n\tprintf(\"%hd\",sum);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7cec9dea23834d49803ab07a209acace", "src_uid": "356666366625bc5358bc8b97c8d67bd5", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\n\nmain()\n{\n    long int m,i,j,k,l,c=0,re=0,a[3030]={0};\n    cin>>m;\n    if(m>5)\n    {\n        for(i=2;i*i<=m;i++)\n        {\n            if(a[i]==0)\n            {\n                for(j=i+i;j<=m;j+=i)\n                    a[j]=1;\n            }\n        }\n        for(k=6;k<=m;k++)\n        {   c=0;\n            for(l=2;l<=(k/2);l++)\n            {\n                if(a[l]==0)\n                {\n                    if(k%l==0)\n                        c++;\n                }\n            }\n            if(c==2)\n                re++;\n        }\n        cout<<re<<endl;\n    }\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3641d815a1f513f673b90bc770a21fec", "src_uid": "356666366625bc5358bc8b97c8d67bd5", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{int n,i,j,k,flag,count=0,count1=0;\n scanf(\"%d\",&n);\n if(n==2000)\n  printf(\"%d\",958);\n  else\n  {\n     for(k=4;k<=n;k++)\n    {count=0;\n      for(i=2;i<=k;i++)\n      {flag=0;\n       for(j=2;j<=sqrt(i);j++)\n       {\n          if(i%j==0)\n          {flag=1;\n          }\n       }\n        if(flag==0)\n        {if(k%i==0)\n          count++;\n      }  ", "lang_cluster": "C", "compilation_error": true, "code_uid": "201e4c9ec5234db09a4e47c1c6bd29f1", "src_uid": "356666366625bc5358bc8b97c8d67bd5", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint almostprime(int n){\n    int i,j;\n    int s[n];\n    for(i=1;i<=n;i++)\n        s[i]=0;\n    for(i=2;i*i<=n;i++)\n    {\n        \n      if(s[i]==0) for(j=i*i;j<=n;j+=i) s[j]=1;\n      \n    }\n    \n    int c=0;\n    for(i=1;i<=n;i++) if(s[i]==0) c++;\n    \n    if(c==2) return 1;\n    else return 0;\n}\n    \nint main(){\n    int n,i;\n    scanf(\"%d\",&n);\n    for(i=1;i<=n;i++)\n        if(almostprime(n)) c++;\n        printf(\"%d\\n\",c);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5bdf4fae785e268e3f3a266da3555064", "src_uid": "356666366625bc5358bc8b97c8d67bd5", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nisPrime(n){\n    int i,flag=1;\n    if(n==2) return 1;\n    for(i=2;i*i<n;i++){\n        if(n%i==0) {flag=0;break;}\n    }\n    return flag;\n}\nint main(){\n    int n;\n    scanf(\"%d\",&n);\n    int i,j,factor,count=0,fc;\n    \n    for(i=2;i<=n;i++){\n        factor=0;\n        for(j=2;j<i;j++){\n        if(i%j==0) {factor ++;,fc=j;}\n            \n        }\n        if(factor==2){\n            if(isPrime(fc)&&isPrime(i/fc)) count ++;\n       }\n    }\n    printf(\"%d\",count);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "adea97159d5d4d66f1077723ee540187", "src_uid": "356666366625bc5358bc8b97c8d67bd5", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#pragma comment(linker, \"/STACK:1024000000,1024000000\")\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC optimize(1)\n#pragma GCC optimize(2)\n#pragma GCC optimize(3)\n#pragma GCC optimize(4)\n#pragma GCC optimize(5)\n#pragma GCC optimize(6)\n#pragma GCC optimize(7)\n#pragma GCC optimize(8)\n#pragma GCC optimize(9)\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n\n#include <stdio.h>\n\nconst int dx[5] = {0, 1, -1, 0, 0};\nconst int dy[5] = {0, 0, 0, 1, -1};\n\nint n, m, best;\nlong long g[45], rest[45];\n\nvoid dfs(long long mask, int cur, int cura) {\n\tif (cura >= best) return;\n\tif (cur >= n*m) return;\n\tif (mask == (1LL << n * m) - 1)\n\t\tbest = cura;\n\telse if ((mask | rest[cur]) ^ (1LL << n * m) - 1) return;\n\telse dfs(mask | g[cur], cur + 1, cura + 1), \n\tdfs(mask, cur + 1, cura);\n}\n\nint main() {\n\tscanf(\"%d%d\", &n, &m);\n\tfor (int i = 0; i < n; ++ i)\n\t\tfor (int j = 0; j < m; ++ j) {\n\t\t\tint num = i * m + j;\n\t\t\tfor (int k = 0; k < 5; ++ k) {\n\t\t\t\tint x = i + dx[k], y = j + dy[k];\n\t\t\t\tif (x < 0 || x >= n || y < 0 || y >= m) continue;\n\t\t\t\tg[num] |= 1LL << x * m + y;\n\t\t\t}\n\t\t}\n\tfor (int i = n * m - 1; i >= 0; -- i) rest[i] = rest[i + 1] | g[i];\n\tbest = n * m; dfs(0, 0, 0);\n\tprintf(\"%d\\n\", n * m - best);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "76e8cb48adfe5c984e87d2c5c664b59c", "src_uid": "097674b4dd696b30e102938f71dd39b9", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#pragma comment(linker, \"/STACK:1024000000,1024000000\")\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC optimize(3)\n#pragma GCC optimize(\"inline\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n\n#include <stdio.h>\n\nconst int dx[5] = {0, 1, -1, 0, 0};\nconst int dy[5] = {0, 0, 0, 1, -1};\n\nint n, m, best;\nlong long g[45], rest[45];\n\nvoid dfs(long long mask, int cur, int cura) {\n\tif (cura >= best) return;\n\tif (cur >= n*m) return;\n\tif (mask == (1LL << n * m) - 1)\n\t\tbest = cura;\n\telse if ((mask | rest[cur]) ^ (1LL << n * m) - 1) return;\n\telse dfs(mask | g[cur], cur + 1, cura + 1), \n\tdfs(mask, cur + 1, cura);\n}\n\nint main() {\n\tscanf(\"%d%d\", &n, &m);\n\tfor (int i = 0; i < n; ++ i)\n\t\tfor (int j = 0; j < m; ++ j) {\n\t\t\tint num = i * m + j;\n\t\t\tfor (int k = 0; k < 5; ++ k) {\n\t\t\t\tint x = i + dx[k], y = j + dy[k];\n\t\t\t\tif (x < 0 || x >= n || y < 0 || y >= m) continue;\n\t\t\t\tg[num] |= 1LL << x * m + y;\n\t\t\t}\n\t\t}\n\tfor (int i = n * m - 1; i >= 0; -- i) rest[i] = rest[i + 1] | g[i];\n\tbest = n * m; dfs(0, 0, 0);\n\tprintf(\"%d\\n\", n * m - best);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "49295a0acefa7cd871d42de6dd53d21d", "src_uid": "097674b4dd696b30e102938f71dd39b9", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define oo 1000000000\n#define lowbit(a) ((a)&(-(a)))\n#define max(a,b) ((a)>(b)?(a):(b))\n\nint f[42][65][65],v[65];\nint n,m;\n\nvoid dfs(int i,int j,int k,int now,int a,int b,int c)\n{\n   if (now>n)\n      f[i+1][b][c]=max(f[i+1][b][c],f[i][j][k]+n-v[a]);\n   else\n   {\n      if (i>1)\n         dfs(i,j,k,now+1,a|(1<<now-1),b,c);\n      dfs(i,j,k,now+1,a,b|(1<<now-1),c);\n      if (i<m)\n         dfs(i,j,k,now+1,a,b,c|(1<<now-1));\n      if (now>1)\n         dfs(i,j,k,now+1,a,b|(1<<now-2),c);\n      if (now<n)\n         dfs(i,j,k,now+1,a,b|(1<<now),c);\n   }\n}\n\nint main()\n{\n   int i,j,k,s=0;\n   scanf(\"%d%d\",&n,&m);\n   if (n>m)\n   {\n      n^=m;\n      m^=n;\n      n^=m;\n   }\n   for (i=1;i<=1<<n;i++)\n      v[i]=v[i-lowbit(i)]+1;\n   for (i=1;i<=m+1;i++)\n      for (j=0;j<1<<n;j++)\n         for (k=0;k<1<<n;k++)\n            f[i][j][k]=-oo;\n   f[1][0][0]=0;\n   for (i=1;i<=m;i++)\n      for (j=0;j<1<<n;j++)\n         for (k=0;k<1<<n;k++)\n            if (f[i][j][k]>=0)\n               dfs(i,j,k,1,j,k,0);\n   for (i=0;i<1<<n;i++)\n      s=max(s,f[m+1][i][0]-v[i]);\n   printf(\"%d\\n\",s);\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d9f06fa1150ebeaffd1d7d45383367ac", "src_uid": "097674b4dd696b30e102938f71dd39b9", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#pragma comment(linker, \"/STACK:1024000000,1024000000\")\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC optimize(3)\n#pragma GCC optimize(\"inline\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n\n#include <stdio.h>\n\nconst int dx[5] = {0, 1, -1, 0, 0};\nconst int dy[5] = {0, 0, 0, 1, -1};\n\nint n, m, best;\nlong long g[45], rest[45];\nregister long long whole;\n\nvoid dfs(long long mask, int cur, int cura) {\n\tif (cura >= best) return;\n\tif (cur >= n * m) return;\n\tif (mask == whole) best = cura;\n\telse if ((mask | rest[cur]) ^ whole) return;\n\telse dfs(mask | g[cur], cur + 1, cura + 1), \n\tdfs(mask, cur + 1, cura);\n}\n\nint main() {\n\tregister int i, j, k;\n\tscanf(\"%d%d\", &n, &m);\n\twhole = (1LL << n * m) - 1;\n\tfor (i = 0; i < n; ++ i)\n\t\tfor (j = 0; j < m; ++ j)\n\t\t\tfor (k = 0; k < 5; ++ k) {\n\t\t\t\tint x = i + dx[k], y = j + dy[k];\n\t\t\t\tif (x < 0 || x >= n || y < 0 || y >= m) continue;\n\t\t\t\tg[i * m + j] |= 1LL << x * m + y;\n\t\t\t}\n\tfor (i = n * m - 1; i >= 0; -- i) rest[i] = rest[i + 1] | g[i];\n\tbest = n * m; dfs(0, 0, 0);\n\tprintf(\"%d\\n\", n * m - best);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4e460ad84bfabad63e3474761e42177f", "src_uid": "097674b4dd696b30e102938f71dd39b9", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#pragma comment(linker, \"/STACK:1024000000,1024000000\")\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n\n#include <stdio.h>\n\nconst int dx[5] = {0, 1, -1, 0, 0};\nconst int dy[5] = {0, 0, 0, 1, -1};\n\nint n, m, best;\nlong long g[45], rest[45];\n\nvoid dfs(long long mask, int cur, int cura) {\n\tif (cura >= best) return;\n\tif (cur >= n*m) return;\n\tif (mask == (1LL << n * m) - 1)\n\t\treturn void (best = cura);\n\tif ((mask | rest[cur]) ^ (1LL << n * m) - 1) return;\n\tdfs(mask | g[cur], cur + 1, cura + 1);\n\tdfs(mask, cur + 1, cura);\n}\n\nint main() {\n\tregister int i, j, k;\n\tscanf(\"%d%d\", &n, &m);\n\tfor (i = 0; i < n; ++ i)\n\t\tfor (j = 0; j < m; ++ j)\n\t\t\tfor (k = 0; k < 5; ++ k) {\n\t\t\t\tint x = i + dx[k], y = j + dy[k];\n\t\t\t\tif (x < 0 || x >= n || y < 0 || y >= m) continue;\n\t\t\t\tg[i * m + j] |= 1LL << x * m + y;\n\t\t\t}\n\tfor (i = n * m - 1; i >= 0; -- i) rest[i] = rest[i + 1] | g[i];\n\tbest = n * m; dfs(0, 0, 0);\n\tprintf(\"%d\\n\", n * m - best);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "07f36cd460e5901ce8c2f46a84e743d9", "src_uid": "097674b4dd696b30e102938f71dd39b9", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int i,n;\n    int x=0;\n    scanf(\"%d\",&n);\n    char a[100];\n    scanf(\"%s\",a);\n    i=0;\n    while(i<n-1)\n    {\n        if(a[i]=='R')\n        {\n            if(a[i+1]=='U')\n            {\n                x++;\n                i=+2;\n            }\n            else if(a[i+1]=='R')\n                i++;\n\n        }\n        else if(a[i]=='U')\n        {\n            if(a[i+1]=='R')\n            {\n                x++;\n                i+=2;\n            }\n            else if(a[i+1]=='U')\n                i++;\n\n        }\n    }\nint k=n-x;\n    printf(\"%d\",k);\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int i,n;\n    int x=0;\n    scanf(\"%d\",&n);\n    char a[100];\n    scanf(\"%s\",a);\n    i=0;\n    while(i<n-1)\n    {\n        if(a[i]=='R')\n        {\n            if(a[i+1]=='U')\n            {\n                x++;\n                i=+2;\n            }\n            else if(a[i+1]=='R')\n                i++;\n\n        }\n        else if(a[i]=='U')\n        {\n            if(a[i+1]=='R')\n            {\n                x++;\n                i+=2;\n            }\n            else if(a[i+1]=='U')\n                i++;\n\n        }\n    }\nint k=n-x;\n    printf(\"%d\",k);\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int i,n;\n    int x=0;\n    scanf(\"%d\",&n);\n    char a[100];\n    scanf(\"%s\",a);\n    i=0;\n    while(i<n-1)\n    {\n        if(a[i]=='R')\n        {\n            if(a[i+1]=='U')\n            {\n                x++;\n                i+=2;\n            }\n            else if(a[i+1]=='R')\n                i++;\n\n        }\n        else if(a[i]=='U')\n        {\n            if(a[i+1]=='R')\n            {\n                x++;\n                i+=2;\n            }\n            else if(a[i+1]=='U')\n                i++;\n\n        }\n    }\n\n    printf(\"%d\",n-x);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3d142143797d1e5d1bc354ffd5c0275f", "src_uid": "986ae418ce82435badadb0bd5588f45b", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    char* str[101];\n    char* mod_str[101];\n    \n    scanf(\"%s\",str);\n    int count = 0;\n    for(int i = 0; i<n-1;++i)\n    {\n        if(str[i] == 'U')\n        {\n            i++;\n            if(str[i] == 'R')\n            {\n                mod_str[i-1] = 'D';\n                count++;\n            }\n            else\n            {\n                mod_str[i-1] = 'U';\n                mod_str[i] = 'R';\n                i = i-1\n            }\n        }\n        else\n        {\n            i++;\n            if(str[i] == 'U')\n            {\n                mod_str[i-1] = 'D';\n                count--;\n            }\n            else\n            {\n                mod_str[i-1] = 'R';\n                mod_str[i] = 'U';\n                i--;\n            }\n        }\n    }\n    printf(\"%d\",n-count);\n    return 0;\n}\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "09af688ee9efccc15f6b77adb587244a", "src_uid": "986ae418ce82435badadb0bd5588f45b", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MAX(a,b) ((a>b)?(a):(b))\nint ans = 0;\nint n;\nchar str[101];\n\ninline void go(int piv, int cnt){\n\tif (piv >= n-1){\n\t\tans = MAX(ans, cnt);\n\t\treturn;\n\t}\n\tif (str[piv] == 'U'){\n\t\tif (str[piv + 1] == 'R')\n\t\t\tgo(piv + 2, cnt + 1);\n\t}\n\telse if (str[piv] == 'R'){\n\t\tif (str[piv + 1] == 'U')\n\t\t\tgo(piv + 2, cnt + 1);\n\t}\n\tgo(piv + 1, cnt);\n}\n\nint main(){\n\tscanf(\"%d\", &n);\n\tscanf(\"%s\", str);\n\tint cnt = 0;\n\tgo(0,0);\n\n\tprintf(\"%d\\n\", n-ans);\n\treturn 0;\n} ", "lang_cluster": "C", "compilation_error": true, "code_uid": "f69ff65e3d234341fdc2a8480d4328a9", "src_uid": "986ae418ce82435badadb0bd5588f45b", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\ntypedef float fl;\ntypedef char ch;\ntypedef long long ll;\n#define rep(i,a,n) for(i=a;i<n;i++)\n#define rev(i,n,a) for(i=n;i>=a;i--)\n#define repr(i,a,b) for(i=a;i<b;i++)\n#define s(n) scanf(\"%d\",&n);\n#define s2(n,m) scanf(\"%d%d\",&n,&m);\n#define s3(n,m,o) scanf(\"%d%d%d\",&n,&m,&o);\n#define p(n) printf(\"%d\",n);\n#define p2(n,m) printf(\"%d%d\",n,m);\n#define sc(n) scanf(\"%c\",&n);\n#define sf(n) scanf(\"%f\",&n);\n#define sl(n) scanf(\"%lld\",&n);\n#define pc(n) printf(\"%c\",n);\n#define pf(n) printf(\"%f\",n);\n#define pl(n) printf(\"%lld\",n);\n#define br break;\n#define co continue;\n#define ss(a) scanf(\"%s\",&a);\n#define ps(a) printf(\"%%s\",a);\n#define nl printf(\"\\n\");\n#define r0 return 0;\nint main()\n{\n    int n;\n    s(n)\n    ch a[n];\n    ss(a)\n    int i,y=0,z=0;\n    for(i=0;i<n-1;)\n    {\n        if(a[i]=='U'&&a[i+1]=='R')\n        {\n            y++;\n            i+=2;\n        }\n        else if(a[i]=='R'&&a[i+1]=='U')\n        {\n            Y++;\n            i+=2;\n        }\n        else\n            i++;\n    }\n    p(n-y)\n\tr0\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5c1b81bb778f0418254c753f016e52b0", "src_uid": "986ae418ce82435badadb0bd5588f45b", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n    int n, i, j = 0;\n    scanf(\"%d\", &n);\n    char str[n], str2[n];\n    scanf(\"%s\", str);\n    for(i = 0; i < n; i++){\n        if(i != (n - 1) && str[i] != str[i + 1]){\n            str2[j] = 'D';\n            j++;\n            i++;\n        }\n        else{\n            str2[j] = str[i];\n            j++;\n        }\n        \n    }\n    int c = 0;\n  \n    while (str2[c] == 'U' || str2[c] == 'D' || str2[c] == 'R') c++\n    \n    printf(\"%d\\n\", c);\n   \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b509eb3f6d359598426e5cd3931ab770", "src_uid": "986ae418ce82435badadb0bd5588f45b", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tint min,max;\n\tint extra;\n\tmin = n/7;\n\textra = n%7;\n\tif(extra>2)\n\t\tmax = min + 2;\n\telse\n\t\tmax = min + extra;\n\tprintf(\"%d %d\",min,max);\n\treturn 0\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6dab2134772858f51db38dbf8f7ee4dc", "src_uid": "8152daefb04dfa3e1a53f0a501544c35", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nmain()\n{\n    int n,min,max;\n    scanf(\"%d\",&n);\n    switch(n%7)\n    {\n        case 0:{\n        max=n*2/7;\n        min=n*2/7;\n        printf(\"%d %d\",min,max);\n        }\n        break;\n        case 1:{\n        max=n*2/7+1;\n        min=n*2/7+0;\n        printf(\"%d %d\",min,max);\n        }\n        break;\n        case 2:{\n        max=n*2/7+2;\n        min=n*2/7+0;\n        printf(\"%d %d\",min,max);\n        }\n        break;\n        case 3:{\n        max=n*2/7+2;\n        min=n*2/7+0;\n        printf(\"%d %d\",min,max);\n        }\n        break;\n        case 4:{\n        max=n*2/7+1;\n        min=n*2/7-1;\n        printf(\"%d %d\",min,max);\n        }\n        break;\n        case 5:{\n        max=n*2/7+1;\n        min=n*2/7-1;\n        printf(\"%d %d\",min,max);\n        }\n        break;\n        case 6:{\n        max=n*/7+1;\n        min=n*2/7;\n        printf(\"%d %d\",min,max);\n        }\n        break;\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "bedb4c8fbfef3629ea45f389d0b9be6a", "src_uid": "8152daefb04dfa3e1a53f0a501544c35", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,a,b,m,l;\n\tscanf(\"%d\",&n);\n\ta=n%7;\n\tb=n/7;\n\tif(a==0|0<a<=5)\n\t{\n\t\tm=b*2;\n\t\tprintf(\"%d\",m);\n\t\tprintf(\"%d\",m);\n\t}\n    else\n    {\n    \tm=(b*2)+1;\n    \tl=n-1\n    \tprintf(\"%d\",l);\n    \tprintf(\"%d\",m);\n    \t\n\t}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fcba0441873d8d76239734ec6ae66038", "src_uid": "8152daefb04dfa3e1a53f0a501544c35", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n,a,b,c;\n    scanf(\"%d\",&n);\n\n    if((n>0)&&(n<1000000))\n    {\n       if(n==1)|(n==6)\n       printf(\"0 1\");\n       else if((n<=7)&&(n!=6))\n          printf(\"0 2\");\n        else\n        {\n           a=(n/7)*2;\n           b=n%7;\n         if(b==0)\n         printf(\"%d %d\",a,a);\n         if(b==1)\n         printf(\"%d %d\",a,a+1);\n         if(b>=2)\n         printf(\"%d %d\",a,a+2);\n        }\n\n\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b518206d485d3a383353ba05d4a2dcea", "src_uid": "8152daefb04dfa3e1a53f0a501544c35", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"ASDFF\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/ASDFF\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/ASDFF\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c387fbcd256212309107c3538880bb85", "src_uid": "8152daefb04dfa3e1a53f0a501544c35", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "int main() { \nint n; cin>>n;\nchar s[50];cin>>s;\nint x=0; int y=0;\n\nfor(int i=0;i<n;i++){\n    if(s[i]=='L'){\n        x++;\n    }else{\n        y++;\n    }\n}\n\ncout<<x+y+1<<endl;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9aec8f437da8cac2e6d8ca5c68de4b1c", "src_uid": "098ade88ed90664da279fe8a5a54b5ba", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n     int i,t,j;\n     char a[100000000000000];\n     scanf(\"%d\",&t);\n     for(j=1;j<=t;j++)\n     {\n     gets(a);\n     i=strlen(a);\n     printf(\"%d\\n\",i+1);\n     }\n     return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "881d7d8edb5dd6516c4c2288592607e9", "src_uid": "098ade88ed90664da279fe8a5a54b5ba", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\nusing namespace std;\n\nint main()\n{\n\tint n;char *str;int i;int countL=0,countR=0;\n\tcin>>n;\n\tstr = new int[n+1];\n\tfor(i=0;i<n;i++)\n\t{\n\t\tcin>>str[i];\n\t\tif(str[i]=='L')\n\t\t\tcountL++;\n\t\telse if(str[i]=='R')\n\t\t\tcountR++;\n\t}\n\n\tcout<<countL+countR+1;\n\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b3ef74ebe7adfcc7e3d379dc1d9c5ff2", "src_uid": "098ade88ed90664da279fe8a5a54b5ba", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": " ", "lang_cluster": "C", "compilation_error": true, "code_uid": "357a19536d6d4aaec9bef3b6189acbaf", "src_uid": "098ade88ed90664da279fe8a5a54b5ba", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int a;\n    char b[1000];\n    scanf(\"%d\",&a);\n    for(i=1;i<=a;i++)\n    {\n        scanf(\"%s\",b);\n    }\n    printf(\"%d\\n\",a+1);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "acb5afc2fec9ccd2a77002f64178d347", "src_uid": "098ade88ed90664da279fe8a5a54b5ba", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint main () {\n    long long a = 0, b = 0, c = 0, d = 0, e = 0, f = 0, g = 0;\n    scanf(\"%lld %lld %lld\", &a, &b, &c);\n    d = pow(2, log2(a));\n    g = a - d;\n    while ((g - pow(2, log2(a))) != 0) {\n        g = g - pow(2, log2(a));\n        e += pow(2, log2(a)) / 2\n        f += pow(2, log2(a)) * b;\n    }\n    while (d / 2 > 0) {\n        e += d / 2;\n        f += d * b;\n        d /= 2;\n    }\n    printf(\"%lld %lld\", e + f, a * c);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b103d3fe91b0cf940ebccfd74abdd8d5", "src_uid": "eb815f35e9f29793a120d120968cfe34", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<cstdio>\n#include<cmath>\n#include<cstring>\n#include<vector>\n#include<deque>\n#include<stack>\n#include<string>\n\n//long long int asd( long long int r);\n\nint main()\n{\n    long long int n, b, p, m, r;\n    scanf(\"%I64d %I64d %I64d\", &n, &b, &p);\n    r=n;\n    long long int ans=0;\n    while(r>1)\n    {\n        m=(r)/2; ans+=m; //r+=m-pow(2,m);\n        r+=m-m*2;\n    }\n    b=ans*(b*2+1);\n    p=p*n;\n    printf(\"%I64d %I64d\\n\", b, p);\n}\n\n\n/*long long int asd( long long int r)\n{\n    long long int m=0; while(r>0)\n    {\n        r/=2;\n        m++;\n    }\n    return m-1;\n}*/\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "208ebf6f5ded7139fb71477d462c4444", "src_uid": "eb815f35e9f29793a120d120968cfe34", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<cstdio>\n#include<cmath>\n#include<cstring>\n#include<vector>\n#include<deque>\n#include<stack>\n#include<string>\n\n//long long int asd( long long int r);\n\nint main()\n{\n    int n, b, p, m, r;\n    scanf(\"%d %d %d\", &n, &b, &p);\n    r=n;\n    int ans=0;\n    while(r>1)\n    {\n        m=(r)/2; ans+=m; //r+=m-pow(2,m);\n        r+=m-m*2;\n    }\n    b=ans*(b*2+1);\n    p=p*n;\n    printf(\"%d %d\\n\", b, p);\n    return 0;\n}\n\n\n/*long long int asd( long long int r)\n{\n    long long int m=0; while(r>0)\n    {\n        r/=2;\n        m++;\n    }\n    return m-1;\n}*/\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2b96c218614db5201aa29b8efef6231b", "src_uid": "eb815f35e9f29793a120d120968cfe34", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,b,p,x,y,k;\n\tscanf(\"%d%d%d\",&n.&b,&p);\n\tif(n%2!=0)\n\t\tk=n-1;\n\telse\n\t\tk=n;\n\tx=(k*(k-2)/2+k)/2*5;\n\ty=n*p;\n\tprintf(\"%d %d\",x,y); \n } ", "lang_cluster": "C", "compilation_error": true, "code_uid": "877bd7fa24fb2baed18479b280ab296f", "src_uid": "eb815f35e9f29793a120d120968cfe34", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint n,b,p,a;\n\tint NB=0;\n\t\n\tscanf(\"%d %d %d\",&n,&b,&p);\n\tint T=p*n;\n\ta=n;\n\twhile(a!=1)\n\t{\n\t\tif(a%2==0)\n\t\t{\n\t\t\tNB=NB+(2*b+1)*a;\n\t\t\ta=a/2;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tNB=NB+(2*b+1)*(a-1);\n\t\t\ta=a+1/2;\n\t\t}\n\t}\n\tprintf(\"%d %d\",NB,T);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f3922b5742bc151736fff6d032b3ccf9", "src_uid": "eb815f35e9f29793a120d120968cfe34", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdbool.h>\n#include <stdlib.h>\n\nstruct node{\n  struct node *next;\n  char c;\n}\n\nint main(void){\n    struct node *first = malloc(sizeof(struct node));\n    struct node *current = first;\n    char b = 's';\n    scanf(\"%c\",&b);\n    while(b != 32){\n      current->c = b;\n      struct node *new = malloc(sizeof(struct node));\n      current->next = new;\n      current = new;\n      scanf(\"%c\",&b);\n    }\n    current->next = NULL;\n    scanf(\"%c\",&b);\n    current = first;\n    bool equal = true;\n    while(current != NULL){\n        if(current->c != b){\n            equal = false;\n        }\n        current = current->next;\n        scanf(\"%c\",&b);\n    }\n    \n    if(!equal){\n        printf(\"1\");\n    }\n    current = first;\n    while(current != NULL){\n        if(equal){\n            printf(\"%c\",current->c);\n        }\n        struct node *holder = current;\n        current = current->next;\n        free(holder);\n    }\n    printf(\"\\n\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "66894b5094fc72abf78327ebc08afea1", "src_uid": "9c5b6d8a20414d160069010b2965b896", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n#include<cstring>\nusing namespace std;\n\nint main() {\n\tlong long int a,i,b;\n\tchar s1[10001];\n\tchar s2[10001];\n\tfor(i=0;i<1001;i++)\n\t{\n\t\ts1[i]=' ';\n\t\ts2[i]=' ';\n\t}\n\tscanf(\"%s\",s1);\n\tscanf(\"%s\",s2);\n\tif(strcmp(s1,s2)==0)\n\tprintf(\"%s\\n\",s2);\n\telse\n\tprintf(\"1\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "90f9342198e500295f9e25955ab666ab", "src_uid": "9c5b6d8a20414d160069010b2965b896", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n#include<stdio.h>\n#include<cstring>\nusing namespace std;\n\nint main() {\n\tlong long int a,i,b;\n\tchar s1[10001];\n\tchar s2[10001];\n\tfor(i=0;i<1001;i++)\n\t{\n\t\ts1[i]=' ';\n\t\ts2[i]=' ';\n\t}\n\tscanf(\"%s\",s1);\n\tscanf(\"%s\",s2);\n\tif(strcmp(s1,s2)==0)\n\tprintf(\"%s\\n\",s2);\n\telse\n\tprintf(\"1\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9ffa6fee09635953098defb51c6d0fbf", "src_uid": "9c5b6d8a20414d160069010b2965b896", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n\n    long long double a,b,x;\n    scanf(\"%llf%llf\",&a,&b);\n    if(a<b) x=a;\n    else x=b;\n\n    again : if(a%x==0 && b%x==0){\n        printf(\"%llf\",x);\n    }else {\n        x=x-1;\n        goto again;\n    }\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b19eba3b6dad19e74a747cd38d78e1b2", "src_uid": "9c5b6d8a20414d160069010b2965b896", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdbool.h>\n#include <stdlib.h>\n\nstruct node{\n  struct node *next;\n  char c;\n}\n\nint main(void){\n    struct node *first = malloc(sizeof(struct node));\n    struct node *current = first;\n    char b = 's';\n    scanf(\"%c\",&b);\n    while(b!= ' '){\n      current->c = b;\n      struct node *new = malloc(sizeof(struct node));\n      current->next = new;\n      current = new;\n      scanf(\"%c\",&b);\n    }\n    current->next = NULL;\n    scanf(\"%c\",&b);\n    current = first;\n    bool equal = true;\n    while(current != NULL){\n        if(current->c != b){\n            equal = false;\n        }\n        current = current->next;\n        scanf(\"%c\",&b);\n    }\n    \n    if(!equal){\n        printf(\"1\");\n    }\n    current = first;\n    while(current != NULL){\n        if(equal){\n            printf(\"%c\",current->c);\n        }\n        struct node *holder = current;\n        current = current->next;\n        free(holder);\n    }\n    printf(\"\\n\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bf326550b2e16db2f3bfd47b685dc1ac", "src_uid": "9c5b6d8a20414d160069010b2965b896", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n \nint main(){\n\nint n,m,s=0;\nscanf(\"%d%d\",&n,&m);\nint a;\nfor(int i=0;i<n;i++){\n    scanf(\"%d\",&a);\n    s=s+a;\n}\nif(s%m==0)\nprintf(\"%d\\n\",s/m);\nelse\nprintf(\"%d\\n\",(s/m)+1);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1b5e67c04972226f06b814b7f29239b1", "src_uid": "5c73d6e3770dff034d210cdd572ccf0f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint aray[103];\nint main()\n{\n    int n, i, j=0, k, a=0, b=0,  m;\n    scanf(\"%d %d\", &n, &m);\n    for(i=0;i<n;i++){\n        scanf(\"%d\", &aray[i]);\n        if(aray[i]==m){\n            j++;\n        }\n\n    }\n    if(j==n){\n        printf(\"%d\", n);\n        return 0;\n    }\n    for(i=0;i<n;i++){\n        if(i==n-1 && b==0){\n            a++;\n         }\n         b+=aray[i];\n\n         else if(b==m){\n            a++;\n            b=0;\n         }\n         else if(b>m){\n            i--;\n            b=0;\n            a++;\n         }\n\n         //printf(\"B:%d a:%d\\n\", b, a);\n    }\n\n    printf(\"%d\", a);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "bbb5df5928a7613e96f06fb20156fc7f", "src_uid": "5c73d6e3770dff034d210cdd572ccf0f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define for(i,n) for(int i=0;i<n;i++)\nint main(){\n\nint n,m,s=0;\nscanf(\"%d%d\",&n,&m);\nint a;\nfor(i,n){\n    scanf(\"%d\",&a);\n    s=s+a;\n}\nif(s%m==0)\nprintf(\"%d\\n\",s/m);\nelse\nprintf(\"%d\\n\",(s/m)+1);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fb853c4d012456e81e5cfdec52062fb1", "src_uid": "5c73d6e3770dff034d210cdd572ccf0f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <malloc.h>\n\nint main(void) {\n    // your code goes here\n    int n,m,i,tmp,c,bus=0;\n    int a;\n    //int* a=(int *)calloc((sizeof(int)),n);\n    scanf(\"%d %d\",&n,&m);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    tmp=a[0];\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a);\n        if(i==0)    tmp=a;\n        if(i>0)\n        {\n        c=tmp+a[i];\n        if(tmp<=m && c<=m)\n            tmp=tmp+a[i];\n        else if(tmp<=m)\n        {\n            tmp=a[i];\n            bus=bus+1;\n        }\n        }\n    }\n    if(tmp<=m)\n        bus++;\n    printf(\"%d\",bus);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "969da73f4bd1bc56d7144f945cdbe878", "src_uid": "5c73d6e3770dff034d210cdd572ccf0f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <malloc.h>\n\nint main(void) {\n    // your code goes here\n    int n,m,i,tmp,c,bus=0;\n    int a;\n    //int* a=(int *)calloc((sizeof(int)),n);\n    scanf(\"%d %d\",&n,&m);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    tmp=a[0];\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a);\n        if(i==0)    tmp=a;\n        if(i>0)\n        {\n        c=tmp+a;\n        if(tmp<=m && c<=m)\n            tmp=tmp+a;\n        else if(tmp<=m)\n        {\n            tmp=a;\n            bus=bus+1;\n        }\n        }\n    }\n    if(tmp<=m)\n        bus++;\n    printf(\"%d\",bus);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "86e3b02be7b5958514d48e34dcfec102", "src_uid": "5c73d6e3770dff034d210cdd572ccf0f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main()\n{\n\n    char c,aux, address[60];\n    int i = 0;\n\n    c = getchar();\n\n    if (c == 'h')\n    {\n        address[i++] = c;\n        while((c = getchar()) != '\\n')\n        {\n            if(i == 4)\n            {\n                address[4] = ':';\n                address[5] = '/';\n                address[6] = '/';\n                i = 7;\n            }\n\n            if(c == 'u' && address[i-1] == 'r' && address[i-2] != '/')\n\n            {\n                aux = address[i - 1];\n                address[i - 1] = '.';\n                address[i] = aux;\n                address[++i] = c;\n                i++;\n                break;\n            }\n\n\n            address[i++] = c;\n        }\n    }\n    else\n    {\n        address[i++] = c;\n        while((c = getchar()) != '\\n')\n        {\n            if(c == 'u' && address[i-1] == 'r' && address[i-2] != '/')\n            {\n                aux = address[i - 1];\n                address[i - 1] = '.';\n                address[i] = aux;\n                address[++i] = c;\n                i++;\n                break;\n            }\n\n            if(i == 3)\n            {\n                address[3] = ':';\n                address[4] = '/';\n                address[5] = '/';\n                i = 6;\n            }\n            address[i++] = c;\n        }\n    }\n\n    if((c = getchar()) != '\\n')\n    {\n        address[i++] = '/';\n        address[i++] = c;\n\n    }\n\n    while((c = getchar()) != '\\n')\n    {\n        address[i++] = c;\n    }\n\n    address[i] = '\\0';\n\n    puts(address);\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "728911efbe6eb1ca3a6beeb1a32aebd8", "src_uid": "4c999b7854a8a08960b6501a90b3bba3", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "\u601d\u6e05  15:32:45\n#include \"stdio.h\"\n\nchar url[1000] = \"\" ;\n\nint main(){\n    int pos,i ;\n    gets(url) ;\n    pos = 'h' == url[0] ? 4 : 3 ;\n    for(i = 0 ; i < pos ; i ++){\n        putchar(url[i]) ;\n    }\n    printf(\"://\") ;\n    for(pos ++ ; url[pos] ; pos ++){\n        if('r' == url[pos] && 'u' == url[pos + 1]){\n            break ;\n        }\n    }\n    while(i < pos){\n        putchar(url[i ++]) ;\n    }\n    printf(\".ru\") ;\n    if(url[pos + 2]){\n        putchar('/') ;\n        puts(url + i + 2) ;\n    } else {\n        puts(\"\") ;\n    }\n    \n    return 0 ;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f6fd55f74e5f39d6f8764bddab05edc5", "src_uid": "4c999b7854a8a08960b6501a90b3bba3", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": " //* Programa que lee una cadena de hasta 50 caracteres y lo despliega como\n    una direccion IP.\n*/\n#include <stdio.h>\n#include <string.h>\n#include <ctype.h>\n#define CARACTERES 50\nint posExtension(int indice, char string[CARACTERES]);\n\nint main(){\n    /* Declaraci\u00f3n de variables */\n    char string[CARACTERES];\n    int indice = 0;\n    int pos;\n    /* Lectura de variables */\n    scanf(\"%s\", string);\n\n    while(string[indice]!='p')\n        printf(\"%c\", string[indice++]);\n\n        printf(\"%c://\", string[indice++]);\n\n    /* Suma dos posiciones para evitar que el dominio sea tomado\n        como la extension ru.\n    */\n    pos = posExtension(indice+1, string);\n    /* Si despues de la extension hay un enlace. */\n    if( indice < strlen(string))\n        printf(\"/\");\n\n    while(indice!=pos)\n        printf(\"%c\", string[indice++]);\n\n    printf(\".ru\");\n\n    /* Suma dos unidades para obviar la extension .ru */\n    indice += 2;\n    printf(\"%d %d\", indice, strlen(string) );\n    if(indice > strlen(string))\n         printf(\"/\");\n\n    while(indice != strlen(string)){\n        printf(\"%c\", string[indice++]);\n    }\n\n        return 0;\n}\n\n\nint posExtension(int indice, char string[CARACTERES]){\n    int i;\n    i=indice;\n    do{\n        while(string[i++]!='r');\n    }while(string[i++]!='u');\n    /* Resta las posiciones de ru */\n    return i-2;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e4ea61d6c2cf2201f2a1806dbc812792", "src_uid": "4c999b7854a8a08960b6501a90b3bba3", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "/* Programa que lee una cadena de hasta 50 caracteres y lo despliega como\n    una direccion IP.\n*/\n#include <stdio.h>\n#include <string.h>\n#include <ctype.h>\n#define CARACTERES 50\nint posExtension(int indice, char string[CARACTERES]);\n\nint main(){\n    /* Declaraci\u00f3n de variables */\n    char string[CARACTERES];\n    int indice = 0;\n    int pos;\n    /* Lectura de variables */\n    scanf(\"%s\", string);\n\n    while(string[indice]!='p')\n        printf(\"%c\", string[indice++]);\n\n        printf(\"%c://\", string[indice++]);\n\n    /* Suma dos posiciones para evitar que el dominio sea tomado\n        como la extension ru.\n    */\n    pos = extension(indice+2, string);\n\n    while(indice!=pos)\n        printf(\"%c\", string[indice++]);\n\n    printf(\".ru\");\n\n    /* Suma dos unidades para obviar la extension .ru */\n    indice += 2;\n\n    printf(\"/\");\n\n    while(indice != strlen(string))\n        printf(\"%c\", string[indice++]);\n\n        return 0;\n}\n\n\nint posExtension(int indice, char string[CARACTERES]){\n    int i;\n    i=indice;\n    do{\n        while(string[i++]!='r');\n    }while(string[i++]!='u');\n    /* Resta las posiciones de ru */\n    return i-2;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b7578c8c1ceae588cc132b3bed2fe39b", "src_uid": "4c999b7854a8a08960b6501a90b3bba3", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "/* Programa que lee una cadena de hasta 50 caracteres y lo despliega como\n    una direccion IP.\n*/\n#include <stdio.h>\n#include <string.h>\n#include <ctype.h>\n#define CARACTERES 50\nint posExtension(int indice, char string[CARACTERES]);\n\nint main(){\n    /* Declaraci\u00f3n de variables */\n    char string[CARACTERES];\n    int indice = 0;\n    int pos;\n    /* Lectura de variables */\n    scanf(\"%s\", string);\n\n    while(string[indice]!='p')\n        printf(\"%c\", string[indice++]);\n\n        printf(\"%c://\", string[indice++]);\n\n    /* Suma dos posiciones para evitar que el dominio sea tomado\n        como la extension ru.\n    */\n    pos = posExtension(indice+2, string);\n\n    while(indice!=pos)\n        printf(\"%c\", string[indice++]);\n\n    printf(\".ru\");\n\n    /* Suma dos unidades para obviar la extension .ru */\n    indice += 2;\n    \n    if(indice > strlne(string))\n         printf(\"/\");\n         \n    while(indice != strlen(string)){\n        printf(\"%c\", string[indice++]);\n    }\n\n        return 0;\n}\n\n\nint posExtension(int indice, char string[CARACTERES]){\n    int i;\n    i=indice;\n    do{\n        while(string[i++]!='r');\n    }while(string[i++]!='u');\n    /* Resta las posiciones de ru */\n    return i-2;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d7070acec7271f8789a313a97f5a946b", "src_uid": "4c999b7854a8a08960b6501a90b3bba3", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int a[100], b[100],i,n,j,c=0;\n    scanf(\u201c%d\u201d,&n);\n    for(i=0;i<n;i++){\n        scanf(\u201c%d%d\u201d,&a[i],&b[i]);\n    }\n    for(i=0;i<n;i++){\n        for(j=0;i<n;j++){\n            if(a[i]==b[j]){\n                c++;\n            }\n        }\n    }\n    printf(\u201c%d\u201d,c);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "309e5d58982052ad1ae84b27314ede04", "src_uid": "745f81dcb4f23254bf6602f9f389771b", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "# include<stdio.h>\n# include<stdlib.h>\n\nint main()\n{\n int num,c=0;\n scanf(\"%d\",&num);\n int num1[2][num];\n for (int i = 0; i < num; ++i)\n \t{\n \t\tfor (int k = 0; k < 2; ++k)\n \t\t{\n \t\t\tscanf(\"%d\",&num1[i][k]);\n \t\t}\n \t} for(int i=0; i<num;i++)\n \t{\n \t\tfor (int k = i; k < num-1; ++k)\n \t\t{\n           if (num1[i][0] == num1[k+1][1])\n \t\t\t{\n \t\t\t\tc+=1;\n \t\t\t\tcontinue;\t\n \t\t\t}\n \t\t\telse\n \t\t\t{\n \t\t\t\tcontinue;\n \t\t\t} \t\t\t\n \t\t}\n \t}\n \tfor(int i=0; i<num; i++)\n \t{\n \t\tfor (int k = i; k < num-1; ++k)\n \t\t{\n           if (num1[i][1] == num1[k+1][0])\n \t\t\t{\n \t\t\t\tc+=1;\n \t\t\t\tcontinue;\t\n \t\t\t}\n \t\t\telse\n \t\t\t{\n \t\t\t\tcontinue;\n \t\t\t}\n \t\t\t\n \t\t}\n \t}\t\n \t\tprintf(\"%d\\n\",c);\n}# include<stdio.h>\n# include<stdlib.h>\n\nint main()\n{\n int num,c=0;\n scanf(\"%d\",&num);\n int num1[2][num];\n for (int i = 0; i < num; ++i)\n \t{\n \t\tfor (int k = 0; k < 2; ++k)\n \t\t{\n \t\t\tscanf(\"%d\",&num1[i][k]);\n \t\t}\n \t} for(int i=0; i<num;i++)\n \t{\n \t\tfor (int k = i; k < num-1; ++k)\n \t\t{\n           if (num1[i][0] == num1[k+1][1])\n \t\t\t{\n \t\t\t\tc+=1;\n \t\t\t\tcontinue;\t\n \t\t\t}\n \t\t\telse\n \t\t\t{\n \t\t\t\tcontinue;\n \t\t\t} \t\t\t\n \t\t}\n \t}\n \tfor(int i=0; i<num; i++)\n \t{\n \t\tfor (int k = i; k < num-1; ++k)\n \t\t{\n           if (num1[i][1] == num1[k+1][0])\n \t\t\t{\n \t\t\t\tc+=1;\n \t\t\t\tcontinue;\t\n \t\t\t}\n \t\t\telse\n \t\t\t{\n \t\t\t\tcontinue;\n \t\t\t}\n \t\t\t\n \t\t}\n \t}\t\n \t\tprintf(\"%d\\n\",c);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2c3b6ec02ca9066127a0eccddd856e65", "src_uid": "745f81dcb4f23254bf6602f9f389771b", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n\n    int number=0;\n    int h(n),a(n);\n    for (int i = 0; i < n; ++i)\n    {\n        scanf(\"%d %d\",&h[i],&a[i]);\n        for (int j = 0; j < i; ++j)\n        {\n            if (h[i] == a[j])\n            {\n                number += 1;\n            }\n            if (a[i] == h[j])\n            {\n                number += 1;\n            }\n        }\n    }\n    printf(\"%d\",number);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "858ae9b67a9396d5486668181890ddf2", "src_uid": "745f81dcb4f23254bf6602f9f389771b", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    int h[n],a[n];\n    int c[100];\n    int i;\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d%d\",h[i],a[i]);\n        ch[h[i]-1]++;\n        ca[a[i]-1]++;\n    }\n    int c=0;\n    for(i=0;i<n;i++)\n    c+=ca[i]*ch[i];\n    \n    printf(\"%d\",c);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5a6b8183d2231bc796062ce8fee1b885", "src_uid": "745f81dcb4f23254bf6602f9f389771b", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main ()\n{\n    int x[30][2],n,j,counter;\n    \n    \n    scanf(\"%d\",&n);\n    \n    for(int i =0 ; i<n ; ++i)\n        \n        scanf(\"%d %d\",&x[i][0],&x[i][1]);\n    \n    \n    for(int i=0;i<n;++i){\n        \n        for(j=0;j<n;++j)\n            if(x[i][0]==x[j][1])\n                counter++;\n        \n    }\n    \n    printf(\"%d\", counter);\n    return 0 ;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7947e660599f2364ae974e74fb1f3a41", "src_uid": "745f81dcb4f23254bf6602f9f389771b", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n    int n;\n    scanf(\"%d\",&n);\n    int ar[n];\n    float sum=0.0;\n    for(int i=0;i<n;i++){\n        scanf(\"%d\",&ar[i]);\n        sum+=ar[i];\n    }\n    int temp;\n    for(int i=0;i<n-1;i++){\n        for(int j=i+1;j<n;j++){\n            if(a[i]<a[j]){\n                temp=a[i];\n                a[i]=a[j];\n                a[j]=temp;\n            }\n        }\n    }\n    int i=0,count=-1;\n    do{\n        if(sum/n>=4.5){\n            count++;\n            break;\n        }\n        else{\n            if(ar[i]!=5){\n                sum=sum-ar[i]+5;\n                ar[i]=5;\n            }\n        }\n    }while(i<n);\n    printf(\"%d\",count);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4593b695e7b5dd4ee7aea43742629f41", "src_uid": "715608282b27a0a25b66f08574a6d5bd", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,i,dem=0;\n\tfloat test,res=0,a[100],hv;\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%f\",&a[i]);\n\t}\n\tfor(i=0;i<n;i++)\n\t{\n\t\tres+=a[i];\n\t}\n\ttest=res/n;\n\tfor(i=0;i<n-1;i++)\n\t{\n\t\tfor(j=i+1;j<n;j++)\n\t\t{\n\t\t\tif(a[i]>a[j])\n\t\t\t{\n\t\t\t\thv=a[i];\n\t\t\t\ta[i]=a[j];\n\t\t\t\ta[j]=hv;\n\t\t\t}\n\t\t}\n\t}\n\tif(test>=4.5)\n\t\tprintf(\"0\");\n\telse\n\t{\n\t\tfor(i=0;i<n;i++)\n\t\t{\n\t\t\tif(a[i]<5)\n\t\t\t{\n\t\t\t\tres-=a[i];\n\t\t\t\ta[i]=5;\n\t\t\t\tres+=a[i];\n\t\t\t\ttest=res/n;\n\t\t\t\tdem++;\n\t\t\t\tif(test>=4.5)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%d\",dem);\n\t\t\t\t\treturn 0;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t\tcontinue;\n\t\t\t\t\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2e66a1cb1e7e1bb464ef8f4c20b3f264", "src_uid": "715608282b27a0a25b66f08574a6d5bd", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "3\n4 4 4", "lang_cluster": "C", "compilation_error": true, "code_uid": "90ba6b535ebc5e2e36a435cbf7ae8a18", "src_uid": "715608282b27a0a25b66f08574a6d5bd", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tint a[n];int sum=0;float c;\n\tfor(int i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\",&a[i]);\n\t\tsum+=a[i];\n\t}\n\tfloat b= (float)(4.5*n);\n\tif(sum>b){\n\t\tprintf(\"0\");\n\t\treturn 0;\n\t}\n\telse\n\t{\n\t\tc=(float)(-sum+b);\n\t}\n\t//printf(\"%f\\n\",c);\n\tif(c-int(c)==0)printf(\"%d\",int(c));\n\telse\n\tprintf(\"%d\",(int)c+1);\n\t\n\t\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fafa70a0bab3aca9d22dcfb1e5ee2a08", "src_uid": "715608282b27a0a25b66f08574a6d5bd", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tint a[n];int sum=0,d;float c;\n\tfor(int i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\",&a[i]);\n\t\tsum+=a[i];\n\t}\n\tfloat b= (float)(4.5*n);\n\tif(sum>b){\n\t\tprintf(\"0\");\n\t\treturn 0;\n\t}\n\telse\n\t{\n\t\tc=(float)(-sum+b);\n\t}\n\td=int(c);\n\t//printf(\"%f\\n\",c);\n\tif(c-d==0)printf(\"%d\",d);\n\telse\n\tprintf(\"%d\",d+1);\n\t\n\t\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ed91dd82a2488ddcdc0c984a2245e665", "src_uid": "715608282b27a0a25b66f08574a6d5bd", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\nint main(){\n    int n,k=0,m,i;\n    scanf(\"%d\",&n);\n    m=n;\n    for( i=2;i<=sqrt(n);i++){\n        if(m%i==0){\n        while(m%i==0){\n            m/=i;\n        }\n        k++;\n        }\n        if(k==2){\n            printf(\"1\");\n            break;\n        }\n        if(n==1)\n            break;\n\n    }\n    if(k==1){\n        printf(\"%d\",i);\n    }\n    else if(k==0)\n        printf(\"%d\",n);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cbf519386ed8f5b138ca159dc860c433", "src_uid": "f553e89e267c223fd5acf0dd2bc1706b", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "//\u82e5num\u4e3a\u8d28\u6570\uff0c\u663e\u7136\u9700\u8981num\u79cd\u6d82\u6599\n//\u82e5num\u53ea\u6709\u4e00\u4e2a\u8d28\u56e0\u6570p\uff0c\u663e\u7136num = p^k,\u5219\u9700\u8981p\u79cd\u6d82\u6599\n//\u82e5num\u67092\u4e2a\u53ca\u4ee5\u4e0a\u7684\u8d28\u56e0\u6570\uff0c\u52191~num\u90fd\u53ef\u4ee5\u7531\u8fd9\u4e9b\u8d28\u56e0\u6570\u7ebf\u6027\u8868\u793a\uff0c\u6545\u53ea\u9700\u4e00\u79cd\u6d82\u6599\n\n#include <stdio.h>\n#include <math.h>\n\nint isPrime(long long num);\nint f(long long num);\n\nint main() {\n\tlong long n;\n\tscanf(\"%lld\", &n);\n\n\tif (n == 1) {\n\t\tprintf(\"1\\n\");\n\t}\n\telse if (isPrime(n)) {\n\t\tprintf(\"%lld\\n\", n);\n\t}\n\telse {\n\t\tint flag = f(n);\n\t\tif (flag) {\n\t\t\tprintf(\"%d\\n\", flag);\n\t\t}\n\t\telse {\n\t\t\tprintf(\"1\\n\");\n\t\t}\n\t}\n\n\treturn 0;\n}\n\nint isPrime(long long num) {\n\tif (num == 1) {\n\t\treturn 0;\n\t}\n\telse if (num == 2 || num == 3) {\n\t\treturn 1;\n\t}\n\telse if (num % 6 != 1 && num % 6 != 5) {\n\t\treturn 0;\n\t}\n\n\tint temp = sqrt(num);\n\tint count1;\n\tfor (count1 = 5; count1 <= temp; count1+=6) {\n\t\tif (num % count1 == 0 || num % (count1+2) == 0) {\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\treturn 1;\n}\n\nint f(long long num) {\n\tint counter = 0, ans;\n\n\tlong long count1;\n\tfor (count1 = 2; count1 <= num; count1++) {\n\t\tif (num % count1 == 0) {\n\t\t\tif (isPrime(count1)) {\n\t\t\t\tans = count1;\n\t\t\t\tcounter++;\n\t\t\t\tif (counter >= 2) {\n\t\t\t\t\treturn 0;\n\t\t\t\t}\n\n\t\t\t\tnum /= count1;\n\t\t\t\tcount1 = 1;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn ans;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4b7ca03c60dba8060bae53da866bb48b", "src_uid": "f553e89e267c223fd5acf0dd2bc1706b", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "//set many funcs template\n//Ver.20190820\n#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<stdbool.h>\n#include<time.h>\n#define inf 1072114514\n#define llinf 4154118101919364364\n#define mod 1000000007\n#define pi 3.1415926535897932384\n\nint max(int a,int b){if(a>b){return a;}return b;}\nint min(int a,int b){if(a<b){return a;}return b;}\nint zt(int a,int b){return max(a,b)-min(a,b);}\nint round(int a,int b){if((a%b)*2 >= b){return (a/b)+1;}return a/b;}\nint ceil(int a,int b){if(a%b==0){return a/b;}return (a/b)+1;}\nint gcd(int a,int b){int c;while(b!=0){c=a%b;a=b;b=c;}return a;}\nint lcm(int a,int b){int c=gcd(a,b);a/=c;return a*b;}\nint nCr(int a,int b){int i,r=1;for(i=1;i<=b;i++){r*=(a+1-i);r/=i;}return r;}\nint nHr(int a,int b){return nCr(a+b-1,b);}\nint fact(int a){int i,r=1;for(i=1;i<=a;i++){r*=i;}return r;}\nint pow(int a,int b){int i,r=1;for(i=1;i<=b;i++){r*=a;}return r;}\nint dsum(int x){int r=0;while(x){r+=(x%10);x/=10;}return r;}\nint dsumb(int x,int b){int r=0;while(x){r+=(x%b);x/=b;}return r;}\nint sankaku(int x){return ((1+x)*x)/2;}\nvoid swap(int *a,int *b){int c;c=(*a);(*a)=(*b);(*b)=c;}\nlong long llmax(long long a,long long b){if(a>b){return a;}return b;}\nlong long llmin(long long a,long long b){if(a<b){return a;}return b;}\nlong long llzt(long long a,long long b){return llmax(a,b)-llmin(a,b);}\nlong long llround(long long a,long long b){if((a%b)*2 >= b){return (a/b)+1;}return a/b;}\nlong long llceil(long long a,long long b){if(a%b==0){return a/b;}return (a/b)+1;}\nlong long llgcd(long long a,long long b){long long c;while(b!=0){c=a%b;a=b;b=c;}return a;}\nlong long lllcm(long long a,long long b){long long c=llgcd(a,b);a/=c;return a*b;}\nlong long llnCr(long long a,long long b){long long i,r=1;for(i=1;i<=b;i++){r*=(a+1-i);r/=i;}return r;}\nlong long llnHr(long long a,long long b){return llnCr(a+b-1,b);}\nlong long llfact(long long a){long long i,r=1;for(i=1;i<=a;i++){r*=i;}return r;}\nlong long llpow(long long a,long long b){long long i,r=1;for(i=1;i<=b;i++){r*=a;}return r;}\nlong long lldsum(long long x){long long r=0;while(x){r+=(x%10);x/=10;}return r;}\nlong long lldsumb(long long x,long long b){long long r=0;while(x){r+=(x%b);x/=b;}return r;}\nlong long llsankaku(long long x){return ((1+x)*x)/2;}\nvoid llswap(long long *a,long long *b){long long c;c=(*a);(*a)=(*b);(*b)=c;}\ndouble dbmax(double a,double b){if(a>b){return a;}return b;}\ndouble dbmin(double a,double b){if(a<b){return a;}return b;}\ndouble dbzt(double a,double b){return dbmax(a,b)-dbmin(a,b);}\nvoid dbswap(double *a,double *b){double c;c=(*a);(*a)=(*b);(*b)=c;}\nvoid chswap(char *a,char *b){char c;c=(*a);(*a)=(*b);(*b)=c;}\nint sortfncsj(const void *a,const void *b){if(*(int *)a>*(int *)b){return 1;}if(*(int *)a==*(int *)b){return 0;}return -1;}\nint sortfnckj(const void *a,const void *b){if(*(int *)a<*(int *)b){return 1;}if(*(int *)a==*(int *)b){return 0;}return -1;}\nint llsortfncsj(const void *a,const void *b){if(*(long long *)a>*(long long *)b){return 1;}if(*(long long *)a==*(long long *)b){return 0;}return -1;}\nint llsortfnckj(const void *a,const void *b){if(*(long long *)a<*(long long *)b){return 1;}if(*(long long *)a==*(long long *)b){return 0;}return -1;}\nint dbsortfncsj(const void *a,const void *b){if(*(double *)a>*(double *)b){return 1;}if(*(double *)a==*(double *)b){return 0;}return -1;}\nint dbsortfnckj(const void *a,const void *b){if(*(double *)a<*(double *)b){return 1;}if(*(double *)a==*(double *)b){return 0;}return -1;}\nint strsortfncsj(const void *a,const void *b){return strcmp((char *)a,(char *)b);}\nint strsortfnckj(const void *a,const void *b){return strcmp((char *)b,(char *)a);}\nint chsortfncsj(const void *a,const void *b){if(*(char *)a>*(char *)b){return 1;}if(*(char *)a==*(char *)b){return 0;}return -1;}\nint chsortfnckj(const void *a,const void *b){if(*(char *)a<*(char *)b){return 1;}if(*(char *)a==*(char *)b){return 0;}return -1;}\n\nvoid shuffledget(int x[],int n){\n    int i,b[524288],p,c;\n    for(i=0;i<n;i++){\n        b[i]=i;\n    }\n    for(i=n;i>=1;i--){\n        p=rand()%i;\n        c=b[i-1];b[i-1]=b[p];b[p]=c;\n    }\n    for(i=0;i<n;i++){\n        scanf(\"%d\",&x[b[i]]);\n    }\n}\n\nint dx4[4]={1,-1,0,0};\nint dy4[4]={0,0,1,-1};\nint dx8[8]={-1,-1,-1,0,0,1,1,1};\nint dy8[8]={-1,0,1,-1,1,-1,0,1};\n\nint search(int x,int a[],int n){\n    int st=0,fi=n-1,te;\n    while(st<=fi){\n        te=(st+fi)/2;\n        if(a[te]<x){st=te+1;}else{fi=te-1;}\n    }\n    return st;\n}\n\nvoid prarr(int arr[],int n){\n  int i;\n  for(i=0;i<n;i++){\n    if(i){printf(\" \");}\n    printf(\"%d\",arr[i]);\n  }\n  printf(\"\\n\");\n  return;\n}\n\nvoid getperm(int a[],int n){\n  int i,p;\n  for(i=0;i<n;i++){\n    a[i]=i;\n  }\n  for(i=n-1;i>=1;i--){\n    p=rand()%(i+1);\n    swap(&a[p],&a[i]);\n  }\n}\n\ntypedef struct{\nint val;\nint node;\n}sd;\n\nint sdsortfnc(const void *a,const void *b){\nif(((sd*)a)->val < ((sd*)b)->val){return -1;}\nif(((sd*)a)->val > ((sd*)b)->val){return 1;}\nreturn 0;\n}\n\nvoid coordinate_comp(int a[],int n){\n  int i,c=0;\n  sd dat[524288];\n  for(i=0;i<n;i++){\n    dat[i].val=a[i];\n    dat[i].node=i;\n  }\n  qsort(dat,n,sizeof(dat[0]),sdsortfnc);\n  a[dat[0].node]=c;\n  for(i=1;i<n;i++){\n    if(dat[i-1].val!=dat[i].val){c++;}\n    a[dat[i].node]=c;\n  }\n}\n\nint main(void){\n  long long i,j,n,m,k,a,b,c,h,w,r,l,t;\n  scanf(\"%lld\",&n);\n  if(n==1){\n    printf(\"1\\n\");\n    return 0;\n  }\n  r=-1;\n  w=n;\n  for(i=2;i*i<=n;i++){\n    if(n%i==0){\n      if(r==-1){r=i;}\n      else{r=gcd(r,i);}\n    }\n    while(w%i==0){w/=i;}\n  }\n  if(w!=1){\n    if(r==-1){r=w;}\n    else{r=gcd(r,w);}\n  }\n  printf(\"%lld\\n\",r);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "54db878b1551cd9db1ca3682f759d8b6", "src_uid": "f553e89e267c223fd5acf0dd2bc1706b", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n \nint main()\n{\n    long long int a,num,j,i=0;\n    scanf(\"%lld\",&a);\n    num=a;    \n    \n    int u=0; long long int n=0;\n    for(i=2;i<1000001;i++)\n    {\n        if(a%i==0)\n        {\n          u++;\n          \n          while(a%i==0)\n            a=a/i;\n          j=i;\n        }\n        if(u>=2)\n          break;\n    }\n\n    if(u==0 || u==1&&a==1)\n      n=j;\n    else\n      n=1;\n\n    if(num==1)\n      n=1;\n\n    printf(\"%lld\\n\",n);\n \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "70ca6ee1aa56236e3ee36f9fd8028529", "src_uid": "f553e89e267c223fd5acf0dd2bc1706b", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main() {\n\tlong long n, a, k;\n\n\tscanf(\"%lld\", &n);\n\tif (n == 1) {\n\t\tprintf(\"1\\n\");\n\t\treturn 0;\n\t}\n\tk = 0;\n\tfor (a = 1; a * a <= n; a++)\n\t\tif (n % a == 0) {\n\t\t\tk++;\n\t\t\tif (a * a != n)\n\t\t\t\tk++;\n\t\t}\n\tk--;\n\tprintf(\"%lld\\n\", k == 1 ? n : k);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dbeb40db3993375d07bcded168354aa3", "src_uid": "f553e89e267c223fd5acf0dd2bc1706b", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\n     long long int a,b,i,find,n,j;\n\n    scanf(\"%lld %lld\",&a,&b);\n    int array[b+1];\n    i=0;\n    find=0;\n\n    while(a <= b)\n    {\n        array[i]=b;\n        if((b%2==0){\n            b=b/2;\n        }\n        else if(b%10==1){\n            b=b/10;\n        }\n          i++;\n          find++;\n    }\n    n=i;\n    if(array[n-1]==a)\n    {\n        printf(\"YES\\n%d\\n\",find);\n        for(j=n-1;j>=0;j--){\n            printf(\"%lld \",array[j]);\n        }\n        printf(\"\\n\");\n    }\n    else\n        printf(\"NO\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "85743bc76576bb64c6fc6c06526eadc7", "src_uid": "fc3adb1a9a7f1122b567b4d8afd7b3f3", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\nusing namespace std;\nint n,m;\nint a[1000000];\nint main(){\n    cin >> n >> m;\n    for (int i=0;i<n;i++){\n        cin >> a[i];\n    }\n    for (int i=0;i<n;i++){\n        cout << a[i]/m << \" \" ;\n        a[i+1]+=a[i]%m;\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1890097fd8002feb7df0ce8e8df41505", "src_uid": "fc3adb1a9a7f1122b567b4d8afd7b3f3", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>main(){    long long int a,b,t=1,    x[9999],i=1,j;        scanf(\"%I64d %I64d\",&a,&b);       x[0]=b;    while(b>a)    {        if(b%10==1)        {            t++;            b/=10;            x[i++]=b;        }        else        {           b/=2;          x[i++]=b;            t++;        }    }    if(a==b)    {       printf(\"YES\\n\");       printf(\"%I64d\\n\",t);       for(j=i-1;j>=0;j--)        printf(\"%I64d \",x[j]);                printf(\"\\b\");        printf(\"\\n\");    }    else    printf(\"NO\\n\");    return 0;}", "lang_cluster": "C", "compilation_error": true, "code_uid": "50ff8d5293d31504988c38ddea998492", "src_uid": "fc3adb1a9a7f1122b567b4d8afd7b3f3", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\n     long long int a,b,i,find,n,j;\n\n    scanf(\"%lld %lld\",&a,&b);\n    int array[b+1];\n    i=0;\n    find=0;\n\n    while(a <= b)\n    {\n        array[i]=b;\n        if((b%2==0){\n            b=b/2;\n        }\n        else if(b%10==1){\n            b=b/10;\n        }\n          i++;\n          find++;\n    }\n    n=i;\n    if(array[n-1]!=a)\n    {\n        printf(\"YES\\n%d\\n\",find);\n        for(j=n-1;j>=0;j--){\n            printf(\"%lld \",array[j]);\n        }\n        printf(\"\\n\");\n    }\n    else\n        printf(\"NO\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fe089162ad12bb60db030363297b1d0d", "src_uid": "fc3adb1a9a7f1122b567b4d8afd7b3f3", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\n     long long int a,b,i,find,n,j;\n\n    scanf(\"%lld %lld\",&a,&b);\n    int array[b+1];\n    i=0;\n    find=0;\n\n    while(a <= b)\n    {\n        array[i]=b;\n        if((b%2==0){\n            b=b/2;\n        }\n        else if(b%10==1){\n            b=b/10;\n        }\n          i++;\n          find++;\n    }\n    n=i;\n    if(array[n-1]==a)\n    {\n        printf(\"YES\\n%lld\\n\",find);\n        for(j=n-1;j>=0;j--){\n            printf(\"%lld \",array[j]);\n        }\n        printf(\"\\n\");\n    }\n    else\n        printf(\"NO\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9d687e8006147850430b8528d6dc69b2", "src_uid": "fc3adb1a9a7f1122b567b4d8afd7b3f3", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "//Date:12-11-17\n\n#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<stdbool.h>\n#include<float.h>\n#include<math.h>\n#include<ctype.h>\n#include<limits.h>\n#include<time.h>\n#define ll long long\n#define For(i,n)\tfor(i=0;i<n;i++)\n#define rep(i ,a ,b)\tfor(i=(a);i<=(b);i++)\n#define mset(a ,value)\tmemset(a ,value ,sizeof(a))\n#define s(a)\tscanf(\"%d\" ,&a);\n#define ls(a)\tscanf(\"%ld\" ,&a)\n#define ld double\n#define reg(i)\tregister int i\n#define infinite INT_MAX\n#define MAX 1000005\nint min(int a,int b){\treturn (a<b?a:b);\t}\nint max(int a,int b){\treturn (a>b?a:b);\t}\nbool prime[MAX];\nvoid pre(){\n\tint i ,j;\n\tmset(prime ,1);\n\tprime[1] =false;\n\tfor(i=2;i<MAX;i++){\n\t\tif(prime[i]==true){\n\t\t\tj=i*i;\n\t\t\twhile(j<MAX){\n\t\t\t\tprime[j] = false;\tj+=i;\n\t\t\t}\n\t\t}\n\t}\n}\nmain(){\n    pre();\n\tint n ,m;\n\ts(n);\n\trep(m ,1 ,1000) if(!prime[n*m+1])   break;\n\tprintf(\"%d\" ,m)\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "12b1afbfaa792a9a19a0e17f5a10548d", "src_uid": "5c68e20ac6ecb7c289601ce8351f4e97", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#includ<stdio.h>\nint main()\n{\nint i,j,h,n;\nscanf(\"%d\",&n);\nfor(i=1;i<1000;i++)\n{\nh=n*i+1;\nfor(j=2;j<h;j++)\n{\nif(h%i==0)\n{\nprintf(\"%d\\n\",i);\nbreak;\n}\n}\nif(j<h)\nbreak;\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8b5fb9a309ad891cf67c8182f9a37e11", "src_uid": "5c68e20ac6ecb7c289601ce8351f4e97", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n \n\n int isprime(long long p)\n { int i; double max=sqrt(p);\n  for(i=2;i<=max;i++)\n   if(p%i==0)break;\n  if(i>max && n!=1)return 1;\n   return 0;\n }\n\n\nlong long gcd(long long a,long long b)\n{ long long i;\n  for(i=a<b?a:b;i>0;i--)\n      if((a%i==0)&&(b%i==0))break;\n    return i;\n}\n\nint comp(const void * a, const void * b)      \n{\n   return ( *(int*)a - *(int*)b );\n}\n\t\n\n\n \nint issame(int *a,int *b,int l)         //checks if two arrays of same length are same after sorting them **\n{ qsort(a,l,sizeof(int),comp);\n  qsort(b,l,sizeof(int),comp);\n  int i;\n for(i=0; i<l; i++)\n    if(a[i]!=b[i]) break;\nif(i==l)return 1;\n return 0;\n  }\n\n\n\nvoid swap(int *a, int *b)\n{int x= *a;\n *a= *b;\n*b=x;\n}\n\n\n\nint arrmax(int *a, int l) \n{ int i; int max= a[0];\n  for(i=1;i<l;i++)\n   if(a[i]>max)max=a[i];\nreturn max;\n}\n\n\nint arrmin(int *a, int l) \n{ int i; int min= a[0];\n  for(i=1;i<l;i++)\n   if(a[i]<min)min=a[i];\nreturn min;\n}\n \n\nlong long  fact(int a)  \n {long long p=1;\n  while(a>0)\n  p*=a--;\n  return p;\n }\n \n\nint min(int a, int b)\n{if(a>b) return b;\n return a;}\n\n\nint max(int a, int b)\n{if(a<b) return b;\n return a;}\n\nvoid sieve( int*a, int n)\n{  n--;\n   long long i,j;\n   for(i=2;i<=n;i++)\n     a[i]=0; \n   for(i=2;i<=n;i++)\n     if(!a[i])\n     for(j=i*i;j<=n;j+=i)\n        if(!a[j])a[j]++;\n }\n\n\n\n \n int main(void)\n {\n   //int t;  scanf(\"%d\",&t); while(t--)    \n        \n  { \n  \tint n;\n  \t scanf(\"%d\",&n);\n  \t int c;\n  \t if(n==1)c=8;\n  \t if(n==2)c=10;\n  \t if(n>2)c=n-2;\n  \t printf(\"%d\",c);\n   \n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n  \t\n  }\n\treturn 0;\n }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4ff755670d4cde92f66936be0f6f0344", "src_uid": "5c68e20ac6ecb7c289601ce8351f4e97", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<conio.h>\nmain()\n{\nint n,num,val;\nint i,j;\nscanf(\"%d\",&n);\nfor(i=1;i<1000;i++)\n{\nnum=n*i;\nval=num+1;\nfor(j=2;j<val;j++)\n{\nif(val%j==0)\nbreak;\n}\nif(j!=val)\n{printf(\"%d\",i); \nbreak;}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0374ffd9fa5884fda5cd52b19ed3db9c", "src_uid": "5c68e20ac6ecb7c289601ce8351f4e97", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n    int n,m;\n    scanf(\"%d\",&n);\n    if (n%2==0)\n    {\n        printf(\"2\");\n    }\n    else \n    {\n        printf(1\");\n    }\n}    ", "lang_cluster": "C", "compilation_error": true, "code_uid": "515bf310be51742f987c31eaefd55a84", "src_uid": "5c68e20ac6ecb7c289601ce8351f4e97", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main () {\n    long long a, b, k, i;\n    int times = 1;\n    scanf(\"%I64u\", &a);\n\n    scanf(\"%I64u\", &b);\n\n    \n    if (b > a) {\n    k = b - a - 1;\n    for (i = b - k; i <= b; i++) {\n        times = (times * (i % 10)) % 10;\n    }\n\n    printf(\"%d\", times);\n    } else {\n        printf(\"0\")\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6d84e154c94773c1e656c64aa9fd8c40", "src_uid": "2ed5a7a6176ed9b0bda1de21aad13d60", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\nint main()\n{\n\n    unsigned long long a,b,i,factorial = 1;\n\n\n    scanf(\"%I64d %I64d\",&a,&b);\n\n\n        for(i=1+a; i<=b; ++i)\n        {\n            factorial = (factorial%10)*(i%10);\n        }\n        printf(\"%I64d\",  factorial);\n\n\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "e508634540535d5df1acfd026cfa2a20", "src_uid": "2ed5a7a6176ed9b0bda1de21aad13d60", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "a,b = input().split()\na = int(a)\nb = int(b)\nx = b - a\nb = b%10\ny =int(1)\nif x > b:\n    print(\"0\")\nelse :\n    for i in range(x):\n        y = y*b\n        b -= 1\n    y = y % 10\n    print(y)\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6e91863d44591a0971739854ac3bb5f7", "src_uid": "2ed5a7a6176ed9b0bda1de21aad13d60", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    long long a,b,k=1,i;\n    scanf(\"%I64d %I64d\",&a,&b);\n    if (((b<(a+5)) && (((a%10)>=5) || ((b%10)<=4)))\n    {\n        b=b%10;\n        a=a%10;\n        for (i=a+1;i<=b;i++)\n            {k*=i;}\n        k=k%10;\n\n    }\n    else k=0;\n    printf(\"%I64d\\n\",k);\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fe3a12012b7c876c7fcca7354804e1a6", "src_uid": "2ed5a7a6176ed9b0bda1de21aad13d60", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    long long a,b,i;\n    scanf(\"%I64d %I64d\", &a, &b);\n\n    int result = 1;\n    if(b-a>=5)\n    {\n        result=0;\n    }\n    else\n    {\n        for(i=a+1;i<=b;i++){\n            answer=answer*(i%10);\n        }\n        result=result%10;\n    }\n\n    printf(\"%d\\n\",result);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8bcfd03bca02ce23ddd9ffbc73ba2bee", "src_uid": "2ed5a7a6176ed9b0bda1de21aad13d60", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(void)\n{\n\tint a,b,c,n;\n\tscanf(\"%d %d %d\",&a,&b,&c);\n\tif(a==2){\n\t\tn=(b+1)*(c+1);\n\t\tprintf(\"%d\",n-2);\n\t}\n\telse if(b==2) {\n\t\tn=(a+1)*(c+1);\n\t\tprintf(\"%d\",n-2);\n\t}\n\telse if(c==2) {\n\t\tn=(b+1)*(a+1);\n\t\tprintf(\"%d\",n-2);\n\t}\n\telse {\n\t\tif(b>=a && c>=a) {\n\t\t\tn=(b+a-1)*(c+a-1);\n\t\t\tp=(a-1)*(a-2);\n\t\t\tprintf(\"%d\",n-p);\n\t\t}\n\t\telse if(a>=b && c>=b) {\n\t\t\tn=(b+a-1)*(c+b-1);\n\t\t\tp=(b-1)*(b-2);\n\t\t\tprintf(\"%d\",n-p);\n\t\t}\n\t\telse if(a>=c && b>=c) {\n\t\t\tn=(c+a-1)*(c+b-1);\n\t\t\tp=(c-1)*(c-2);\n\t\t\tprintf(\"%d\",n-p);\n\t\t}\n\t}\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1b5235d4f9595d6f439e11f483cac449", "src_uid": "8ab25ed4955d978fe20f6872cb94b0da", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n# include <conio.h>\nint main()\n{\n    int a[3],i,j,temp,s=0,n,m;\n    for(i=0;i<3;i++)\n    scanf(\"%d\",&a[i]);\n    for(i=0;i<2;i++)\n    {\n        for(j=0;j<2-i;j++)\n        {\n            if(a[j]>a[j+1])\n            {\n                temp=a[j];\n                a[j]=a[j+1];\n                a[j+1]=temp;\n            }\n        }\n    }\n    s+=2*(a[0]-2+a[1]-2+a[2]-2)+6;\n   // printf(\"%d\\n\",s);\n    n=a[0]+a[1]-3;\n    if(n==1)\n    m=a[2]-1;\n\n\n    else\n    m=(2*(a[2]-1)+a[2]*(n-2));\n    //printf(\"%d\\n\",m);\n        printf(\"%d\",m+s);\n      \nreturn (0);\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ddf469eba42ccf1b1c7e4f800e8c200e", "src_uid": "8ab25ed4955d978fe20f6872cb94b0da", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "//#include<conio.h>\n#include<stdio.h>\n#include<string.h>\n#include<math.h>\nint main()\n{\n    int a,b,c,i,j,;\n    scanf(\"%d %d %d\",&a,&b,&c);\n    printf(\"%d\",(c-1)*(a+b-1)+2*b);\n //   getch();\n    return(0);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e5096598e8b8d8ddd991578c469113d7", "src_uid": "8ab25ed4955d978fe20f6872cb94b0da", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\nmain()\n{\n      int a,b,c;\n      scanf(\"%d %d %d\",&a,&b,&c);\n      printf(\"%d\",((a-1)*(b+c-1)+(b*c)));\n      getch();\n      return 0;\n}\n      \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "15cba49af3fa9c2d9d4c857006d63d19", "src_uid": "8ab25ed4955d978fe20f6872cb94b0da", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{int a,b,c,t;\nscanf(\"%d %d %d\",&a,&b,&c);\nt=a*b+b*c+c*a-a-b-c+1;\nprintf(\"%d\",t);\ngetch();\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8fb5ebe9ecdeaea8041da39f73a853c2", "src_uid": "8ab25ed4955d978fe20f6872cb94b0da", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nlong long gcd(long long a,long long b)\n{\n   if(a==0)\n      return  b;\n   else\n      gcd(b%a,a);\n}\nint main()\n{\n   long long m,z;\n   scanf(\"%ll\",&z);\n   z=m;\n   for(long long i=1;i*i<=z;i++)\n   {\n      if(z%i==0 && gcd(i,z/i)==1)\n         m=i;\n   }\n   printf(\"%lld %lld\",m,z/m);\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "13c7be1b786618a8f21a731feb8feb52", "src_uid": "e504a04cefef3da093573f9df711bcea", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "\t#include<stdio.h>\n\tint main()\n\t{\n\t\tlong long tc;\n\t\tscanf(\"%lld\",&tc);\n\t\tlong long faktorial[tc];\n\t\tint j = 0;\n\t\tfor(int i = 1;i<=tc;i++)\n\t\t{\n\t\t\tif(tc % i == 0)\n\t\t\t{\n\t\t\t\tfaktorial[j] = i;\n\t\t\t\tj++;\n\t\t\t}\t\n\t\t}\n\t\tlong long temp = faktorial[0] + faktorial[j-1];\n\t\tlong long sementara1 = faktorial[0], sementara2 = faktorial[j-1];\n\t\tlong long sementara = j;\n\t\tfor(int i = 0;i<j/2;i++,sementara--)\n\t\t{\n\t\t\tif(faktorial[i] + faktorial[sementara-1] < temp)\n\t\t\t{\n\t\t\t\ttemp = faktorial[i] + faktorial[sementara-1];\n\t\t\t\tsementara1 = faktorial[i];\n\t\t\t\tsementara2 = faktorial[sementara-1];\n\t\t\t}\n\t\t}\t\n\t\tif(tc == 24) printf(\"%d %d\\n\",3,8);\n\t\telse printf(\"%lld %lld\\n\",sementara1,sementara2);\n\t}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a1b30f5fc6f6202bcf6ceed94184f565", "src_uid": "e504a04cefef3da093573f9df711bcea", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\nint ebob (int a,int b)\n{\n    while (a!=0&&b!=0)\n    {\n        if (a>b)\n        {\n            a = a%b;\n        }\n        else \n        {\n            b = b%a;\n        }\n        \n    }\n    if (a==0)\n    {\n        return b;\n    }\n    else\n    {\n        return a;\n    }\n    \n}\nint input;\nint max;\nint main ()\n{ \n    freopen (\"a.gir\",\"r\",stdin);\n    freopen (\"a.cik\",\"w\",stdout);\n    scanf (\"%d\",&input);\n    for (int i=1;i<=sqrt(input);i++)\n    {\n        if (input%i==0)\n        {\n            if (ebob(i,input/i)==1)\n            {\n                max = input/i;\n            }\n        }\n    }\n    printf (\"\\n%d %d\",max,(input/max));\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "0b433c25b24c96b0e4872a3a120df9fc", "src_uid": "e504a04cefef3da093573f9df711bcea", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\nlong long int ebob (long long int a,long long int b)\n{\n    while (a!=0&&b!=0)\n    {\n        if (a>b)\n        {\n            a = a%b;\n        }\n        else \n        {\n            b = b%a;\n        }\n        \n    }\n    if (a==0)\n    {\n        return b;\n    }\n    else\n    {\n        return a;\n    }\n    \n}\nlong long int input;\nlong long int max;\nint main ()\n{ \n    freopen (\"a.gir\",\"r\",stdin);\n    freopen (\"a.cik\",\"w\",stdout);\n    scanf (\"%lld\",&input);\n    for (int i=1;i<=sqrt(input);i++)\n    {\n        if (input%i==0)\n        {\n            if (ebob(i,input/i)==1)\n            {\n                max = input/i;\n            }\n        }\n    }\n    printf (\"\\n%lld %lld\",max,(input/max));\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ee44b2abc025654364ef0bb0eb911c49", "src_uid": "e504a04cefef3da093573f9df711bcea", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint judge(int a, int b);\nint main()\n{\n\tlong long n,a=1,b,i;\n\tscanf(\"%lld\", &n);\n\tb = n / a;\n\tfor (i = 1; i <= sqrt(n); i++)\n\t{\n\t\tif ((n % i == 0) && judge(i, n / i))\n\t\t{\n\t\t\tif ((n / i) < b)\n\t\t\t{\n\t\t\t\ta = i;\n\t\t\t\tb = n / i;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%lld %lld\", a, b);\n\treturn 0;\n}\nint judge(long long a, long long b)\n{\n\tif (b % a == 0)\n\t\treturn 0;\n\telse\n\t\treturn 1;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3a4b843f4be955a16964757c0e4e917e", "src_uid": "e504a04cefef3da093573f9df711bcea", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "//emre\n#include <stdio.h>\n#include <string.h>\nint main()\n{\n    int a,b,c,d,n,len;\n    char str[100];\n    scanf(\"%s\",str);\n    len=strlen(str)-2;\n    if(str[len]=='A' || str[len]=='a' || str[len]=='E' || str[len]=='e' || str[len]=='I' || str[len]=='i' || str[len]=='O' || str[len]=='o' || str[len]=='U' || str[len]=='u' || str[len]=='Y' || str[len]=='y')\n    printf(\"%c\",str[len]);\n    {\n        printf(\"YES\");\n    }\n    else\n    printf(\"NO\");\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5f969fa0b338bcd30926b96ac9fdc7ff", "src_uid": "dea7eb04e086a4c1b3924eff255b9648", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <string.h>\n#include <stdio.h>\n#include <ctype.h>\n#include <cs50.h>\n\nint main(void)\n{\n    char s[100];\n    fgets(s, 100, stdin);\n    int x = strlen(s)-1;\n    char c[] = {'a', 'e','i', 'o', 'u', 'y'};\n    for(int i = 0; i < 6; i++){\n        while(s[x] == ' '){\n            x--;\n        }              \n        if(tolower(s[x]) == c[i]){\n                printf(\"YES\");\n                return 0;\n        }\n    }\n    printf(\"NO\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b61e51c88a4c2cf5466589244f2af0a7", "src_uid": "dea7eb04e086a4c1b3924eff255b9648", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint checking_char_before(char *string,int t){\n    if(string[t]=='a'||string[t]=='e'||string[t]=='i'||string[t]=='o'||string[t]=='u'||string[t]=='y'){\n        return 1;\n    }\n    if(string[t]=='A'||string[t]=='E'||string[t]=='I'||string[t]=='O'||string[t]=='U'||string[t]=='Y'){\n        return 1;\n    }\n    if(string[t]==' '){\n        return checking_char_before(string,t-1);\n    }\n    else return 0;\n}\nint main(){\n    char string[101];\n    int flag=0\n    scanf(\"%[^\\n]%*c\",string);\n    int d= strlen(string);\n    if(string[d-1]=='?'){\n        flag=checking_char_before(string,d-2);\n    }\n    if(flag==1) printf(\"YES\");\n    else printf(\"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b8b9bdc0c06c5f01e190e63a15705abe", "src_uid": "dea7eb04e086a4c1b3924eff255b9648", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    char s[101],count;\n    gets(s);\n    int i=0;\n    while(s[i]!=0)\n    {\n        if(s[i]=='?')\n        {\n            count=s[i-1];\n            if(count==' ')\n            {\n                count=s[i-2];\n            }\n        }\n        i=i+1;\n    }\n    if(count=='a' || count=='e' || count=='i' || count=='o' || count=='u' || count=='y' count=='A' || count=='E' || count=='I' || count=='O' || count=='U' || count=='Y')\n    {\n        printf(\"YES\\n\");\n    }\n    else\n    {\n        printf(\"NO\\n\");\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "34918c530a2d77e67dddc0375529e160", "src_uid": "dea7eb04e086a4c1b3924eff255b9648", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <string.h>\n#include <stdio.h>\nint main()\n{\n     char ch[150];\n     scanf(\"%s\",ch);\n     int l=strlen(ch);\n     int i,j,k;\n     for(i=l-1;i>=0;i--)\n     {\n          if((ch[i]>=65 && ch[i]<=90) || (ch[i]>=97 && ch[i]<=122))\n          {\n               if(ch[i]=='a'||ch[i]=='e'||ch[i]=='i'||ch[i]=='o'||ch[i]=='u'||ch[i]=='y'||ch[i]=='A'||ch[i]=='E'||ch[i]='I'||ch[i]=='O'||ch[i]=='U'||ch[i]=='Y')\n               printf(\"YES\");\n               else \n               printf(\"NO\");\n          }\n     }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4f8fd0ee53a1bba563c4777cb8eb6ca3", "src_uid": "dea7eb04e086a4c1b3924eff255b9648", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<math.h>\n\nint main()\n{\n    char a[200],t[200],tc,tp;\n    int h,i,j,k,l;\n    int n,counts;\n\n      scanf(\"%s\",a))\n        n=strlen(a);\n        i=n-1;\n        j=0;\n        for(h=0;h<n;h++)\n        {\n            if(a[h]==a[i])\n            {\n                j++;\n            }\n            i--;\n        }\n        if(j==n)\n        {\n            if(n%2==1)\n            {\n                strcpy(t,a);\n                tc=a[n/2+1];\n                for(h=n/2+1;h<n+1;h++)\n                {\n                    if(h==n/2+1)\n                    {\n                        t[h]=a[n/2];\n                    }\n                    else{\n                        tp=t[h];\n                        t[h]=tc;\n                        tc=tp;\n                    }\n                }\n                printf(\"%s\\n\",t);\n            }\n        }\n        if(n%2==0)\n        {\n            k=0;\n            i=n-1;\n            for(h=0;h<n;h++)\n            {\n                if(a[h]==a[i])\n                {\n                    k++;\n                }\n                i--;\n            }\n            if(k==n)\n            {\n                for(h=0;h<n/2;h++)\n                {\n                    t[h]=a[h];\n                }\n                t[h]='y';\n                i=n/2-1;\n                for(h=n/2+1;h<n+1;h++)\n                {\n                    t[h]=a[i];\n                    i--;\n                }\n                t[h]='\\0';\n                printf(\"%s\\n\",t);\n            }\n            else{\n                j=0;\n                for(h=0;h<=n/2;h++)\n                {\n                    strcpy(t,a);\n                    tc=t[n-h];\n                    for(l=n-h;l<n+2;l++)\n                    {\n                        if(l==n-h)\n                        {\n                            t[l]=a[h];\n                        }\n                        else{\n                            tp=t[l];\n                            t[l]=tc;\n                            tc=tp;\n                        }\n                    }\n                    t[l]='\\0';\n                    counts=0;\n                    l=n;\n                    for(i=0;i<=n;i++)\n                    {\n                        if(t[l]==t[i])\n                        {\n                            counts++;\n                        }\n                        l--;\n                    }\n                    if(counts==n+1)\n                    {\n                        printf(\"%s\\n\",t);\n                        break;\n                    }\n                    else{\n                        j++;\n                    }\n                }\n                if(j==n/2+1)\n                {\n                    puts(\"NA\");\n                }\n            }\n        }\n        else{\n            j=0;\n            for(h=0;h<=n/2;h++)\n            {\n                strcpy(t,a);\n                tc=t[n-h];\n                for(l=n-h;l<n+2;l++)\n                {\n                    if(l==n-h)\n                    {\n                        t[l]=a[h];\n                    }\n                    else{\n                        tp=t[l];\n                        t[l]=tc;\n                        tc=tp;\n                    }\n                }\n                t[l]='\\0';\n                counts=0;\n                l=n;\n                for(i=0;i<=n;i++)\n                {\n                    if(t[l]==t[i])\n                    {\n                        counts++;\n                    }\n                    l--;\n                }\n                if(counts==n+1)\n                {\n                    printf(\"%s\\n\",t);\n                    break;\n                }\n                else{\n                    j++;\n                }\n            }\n        }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "179d17365d2ecda528fad62501811566", "src_uid": "24e8aaa7e3e1776adf342ffa1baad06b", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nchar a[21],b[21];\nint pal(int x)\n{\n\n    int j;\n\n    for(j = 0; j < x / 2; j++)\n    {\n        if (a[j] != a[x - j - 1])\n            break;\n    }\n    if (j <  x / 2)\n        return 0;\n    else\n       return 1;\n}\nint main()\n{\n    memset(a,' ',21);\n    gets(a);\n    strcpy(b,a);\n   int i = 0;\n    int temp1 = 0;\n    int temp2 = 0;\n    int flag = 0;\n    int q = strlen(a);\n    while(i <= q)\n    {\n         char ch = 'a';\n        int temp = i;\n        for (i = q ; i > flag; i--)\n            {\n                a[i] = 'c';\n                int tep = a[i];\n                a[i] = a[i - 1];\n                a[i - 1] = tep;\n            }\n            flag++;\n            i = temp;\n        while(ch <= 'z')\n        {\n            a[i] = ch;\n            if (pal(q + 1)){\n            temp2 = 1;\n            break;\n            }\n            ch++;\n        }\n         if (temp2)\n            break;\n        i++;\n        strcpy(a,b);\n    }\n    if (temp2)\n    puts(a);\n    else\n    printf(\"NA\");\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\nchar a[21],b[21];\nint pal(int x)\n{\n\n    int j;\n\n    for(j = 0; j < x / 2; j++)\n    {\n        if (a[j] != a[x - j - 1])\n            break;\n    }\n    if (j <  x / 2)\n        return 0;\n    else\n       return 1;\n}\nint main()\n{\n    memset(a,' ',21);\n    gets(a);\n    strcpy(b,a);\n   int i = 0;\n    int temp1 = 0;\n    int temp2 = 0;\n    int flag = 0;\n    int q = strlen(a);\n    while(i <= q)\n    {\n         char ch = 'a';\n        int temp = i;\n        for (i = q ; i > flag; i--)\n            {\n                a[i] = 'c';\n                int tep = a[i];\n                a[i] = a[i - 1];\n                a[i - 1] = tep;\n            }\n            flag++;\n            i = temp;\n        while(ch <= 'z')\n        {\n            a[i] = ch;\n            if (pal(q + 1)){\n            temp2 = 1;\n            break;\n            }\n            ch++;\n        }\n         if (temp2)\n            break;\n        i++;\n        strcpy(a,b);\n    }\n    if (temp2)\n    puts(a);\n    else\n    printf(\"NA\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5d09ea39609cac97184444b174230d86", "src_uid": "24e8aaa7e3e1776adf342ffa1baad06b", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n\nint check_palindrome(char str[],int first,int last)\n{\n    while(first < last)\n    {\n        if(str[first]!=str[last])\n        {\n            return 0;\n        }\n        else\n        {\n            first++;\n            last--; \n        }\n    }\nreturn 1;\n}\n\n\nint main()\n{\n\n    //printf(\"%s\\n\",arr );\n    char arr[200];\n    scanf(\"%s\",arr);\n    int l1=strlen(arr);\n    int i,x,y;\n    int check;\n    check=check_palindrome(arr,0,l1-1);\n\n    /*\n\n\n    while(arr[x]==arr[y])\n        {\n            x++;\n            y--;\n            //printf(\"here1111\\n\", );\n        }\n        check=check_palindrome(arr,x,y-1);\n        if(check==1)\n        {\n            //printf(\"%s\\n\",arr );\n            for(i=0;i<l1-1-y;i++)\n                printf(\"%c\",arr[i]);\n            printf(\"%c\",arr[y] );\n            for(i=l1-1-y;i<l1;i++)\n                printf(\"%c\",arr[i]);\n            printf(\"\\n\");\n        }\n\n        else\n        {\n            //printf(\"%s\\n\",arr );\n            check=check_palindrome(arr,x+1,y);\n\n            //printf(\"here1111\\n\", );\n            //printf(\"here1111\\n\", );\n            if(check==1)\n            {\n                //printf(\"%s\\n\",arr );\n                //printf(\"%s\\n\",arr );\n                for(i=0;i<=l1-1-x;i++)\n                    printf(\"%c\",arr[i]);\n                printf(\"%c\",arr[x]);\n                for(i=l1-x;i<l1;i++)\n                    printf(\"%c\",arr[i]);\n                printf(\"\\n\");\n            }\n\n            else\n                printf(\"NA\\n\");\n        }\n\n    */\n    if(check==1)\n    {   \n\n        //printf(\"here1111\\n\", );\n        for(i=0;i<l1/2;i++)\n            printf(\"%c\",arr[i] );\n        printf(\"%c\",arr[l1/2]);\n        for(i=l1/2;i<l1;i++)\n            printf(\"%c\",arr[i]);\n        printf(\"\\n\");\n    }\n    else\n    {\n        x=0;\n        y=l1-1;\n        while(arr[x]==arr[y])\n        {\n            x++;\n            y--;\n            //printf(\"here1111\\n\", );\n        }\n        check=check_palindrome(arr,x,y-1);\n        if(check==1)\n        {\n            //printf(\"%s\\n\",arr );\n            for(i=0;i<l1-1-y;i++)\n                printf(\"%c\",arr[i]);\n            printf(\"%c\",arr[y] );\n            for(i=l1-1-y;i<l1;i++)\n                printf(\"%c\",arr[i]);\n            printf(\"\\n\");\n        }\n        /*\n        #include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n\nint check_palindrome(char str[],int first,int last)\n{\n    while(first < last)\n    {\n        if(str[first]!=str[last])\n        {\n            return 0;\n        }\n        else\n        {\n            first++;\n            last--; \n        }\n    }\nreturn 1;\n}\n\n\nint main()\n{\n\n    //printf(\"%s\\n\",arr );\n    char arr[200];\n    scanf(\"%s\",arr);\n    int l1=strlen(arr);\n    int i,x,y;\n    int check;\n    check=check_palindrome(arr,0,l1-1);\n\n    /*\n\n\n    while(arr[x]==arr[y])\n        {\n            x++;\n            y--;\n            //printf(\"here1111\\n\", );\n        }\n        check=check_palindrome(arr,x,y-1);\n        if(check==1)\n        {\n            //printf(\"%s\\n\",arr );\n            for(i=0;i<l1-1-y;i++)\n                printf(\"%c\",arr[i]);\n            printf(\"%c\",arr[y] );\n            for(i=l1-1-y;i<l1;i++)\n                printf(\"%c\",arr[i]);\n            printf(\"\\n\");\n        }\n\n        else\n        {\n            //printf(\"%s\\n\",arr );\n            check=check_palindrome(arr,x+1,y);\n\n            //printf(\"here1111\\n\", );\n            //printf(\"here1111\\n\", );\n            if(check==1)\n            {\n                //printf(\"%s\\n\",arr );\n                //printf(\"%s\\n\",arr );\n                for(i=0;i<=l1-1-x;i++)\n                    printf(\"%c\",arr[i]);\n                printf(\"%c\",arr[x]);\n                for(i=l1-x;i<l1;i++)\n                    printf(\"%c\",arr[i]);\n                printf(\"\\n\");\n            }\n\n            else\n                printf(\"NA\\n\");\n        }\n\n    */\n    if(check==1)\n    {   \n\n        //printf(\"here1111\\n\", );\n        for(i=0;i<l1/2;i++)\n            printf(\"%c\",arr[i] );\n        printf(\"%c\",arr[l1/2]);\n        for(i=l1/2;i<l1;i++)\n            printf(\"%c\",arr[i]);\n        printf(\"\\n\");\n    }\n    else\n    {\n        x=0;\n        y=l1-1;\n        while(arr[x]==arr[y])\n        {\n            x++;\n            y--;\n            //printf(\"here1111\\n\", );\n        }\n        check=check_palindrome(arr,x,y-1);\n        if(check==1)\n        {\n            //printf(\"%s\\n\",arr );\n            for(i=0;i<l1-1-y;i++)\n                printf(\"%c\",arr[i]);\n            printf(\"%c\",arr[y] );\n            for(i=l1-1-y;i<l1;i++)\n                printf(\"%c\",arr[i]);\n            printf(\"\\n\");\n        }\n\n        else\n        {\n            //printf(\"%s\\n\",arr );\n            check=check_palindrome(arr,x+1,y);\n\n            //printf(\"here1111\\n\", );\n            //printf(\"here1111\\n\", );\n            if(check==1)\n            {\n                //printf(\"%s\\n\",arr );\n                //printf(\"%s\\n\",arr );\n                for(i=0;i<=l1-1-x;i++)\n                    printf(\"%c\",arr[i]);\n                printf(\"%c\",arr[x]);\n                for(i=l1-x;i<l1;i++)\n                    printf(\"%c\",arr[i]);\n                printf(\"\\n\");\n            }\n\n            else\n                printf(\"NA\\n\");\n        }\n\n\n\n    }\n\n}\n\n\n\n        */\n\n        else\n        {\n            //printf(\"%s\\n\",arr );\n            check=check_palindrome(arr,x+1,y);\n\n            //printf(\"here1111\\n\", );\n            //printf(\"here1111\\n\", );\n            if(check==1)\n            {\n                //printf(\"%s\\n\",arr );\n                //printf(\"%s\\n\",arr );\n                for(i=0;i<=l1-1-x;i++)\n                    printf(\"%c\",arr[i]);\n                printf(\"%c\",arr[x]);\n                for(i=l1-x;i<l1;i++)\n                    printf(\"%c\",arr[i]);\n                printf(\"\\n\");\n            }\n\n            else\n                printf(\"NA\\n\");\n        }\n\n\n\n    }\n\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6ed9e6056b9cb9620bcb0861b3526871", "src_uid": "24e8aaa7e3e1776adf342ffa1baad06b", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint palindrom( char riadok[] ) {\n        int l = strlen( riadok );\n        for( int i = 0; i < l/2; i++ ) {\n            if( riadok[i] != riadok[l-i-1] ) return 0;\n        }\n        return 1;\n}\n\nint main()\n{\n    char slovo[12];\n    char kopia[12];\n    char pom[12];\n    char novy[12];\n    int pal = 0;\n    scanf( \"%s\", slovo );\n    //printf( \"Slovo: %s\\n\", slovo); //out\n\n    int dlzka = strlen( slovo );\n    char znak;\n    int i = 0;\n    do {\n       // printf(\"I: %i\\n\", i ); //out\n        strcpy( kopia, slovo );\n       // printf( \"Kopia: %s\\n\", kopia ); //out\n        znak = slovo[i];\n        int j = 0;\n        do {\n            strcpy( kopia, slovo );\n          //  printf(\"J: %i\\n\", j );//out\n            strcpy( pom, slovo+j );\n           // printf( \"Pom: %s\\n\", pom ); //out\n            kopia[j] = znak;\n            kopia[j+1] = '\\0';\n            strcat( kopia, pom );\n            //printf( \"Kopia: %s\\n\", kopia ); //out\n            if( palindrom(kopia) ) {\n                    pal = 1;\n                    strcpy( novy, kopia );\n            }\n            j++;\n        } while ( j <= dlzka && pal == 0 );\n\n        i++;\n\n\n    } while( i < dlzka && pal == 0 );\n\n    if( pal ) printf( \"%s\\n\", novy );\n        else printf( \"NA\\n\" );\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "72482d22efb39ee61a9deed654b787e9", "src_uid": "24e8aaa7e3e1776adf342ffa1baad06b", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>", "lang_cluster": "C", "compilation_error": true, "code_uid": "1cb287d97356a17deda131285489fa41", "src_uid": "24e8aaa7e3e1776adf342ffa1baad06b", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#define MOD 1000000007\n\nint main()\n{\n\tlong long int a,b,c,d,e,f,i,j;\n\tscanf(\"%I64d %I64d\",&a,&b);\n\tlong long int p,q,r,s;\n\tp = (a*(a+1)/2)%MOD;\n\tq = (b*(b-1)/2)%MOD;\n\tr = (p*b+a)%MOD;\n\ts = (q*r)%MOD;\n\tprintf(\"%I64d\\n\",s);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c0caf8997721d6518e33deff63a4e23e", "src_uid": "cd351d1190a92d094b2d929bf1e5c44f", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(int argc, const char *argv[])\n{\n    long long a,b;\n    scanf( \"%lld %lld\", &a, &b );\n\n    long long res = 0;\n    for( int r = 1; r < b; r++ )\n    {\n        int tmp;\n        tmp = ( a + 1 ) % 1000000007;\n        tmp = ( b * tmp ) % 1000000007;\n        tmp = ( tmp / 2 ) % 1000000007;\n        tmp = ( tmp + 1 ) % 1000000007;\n        tmp = ( tmp * a ) % 1000000007;\n        tmp = ( tmp * r ) % 1000000007;\n        res = ( res + tmp ) % 1000000007;\n    }\n\n    printf( \"%lld\\n\", res );\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ce2af15ea0825c7ce26ad6d66f6856a9", "src_uid": "cd351d1190a92d094b2d929bf1e5c44f", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    long long int a,b,sum=0,i,p,q,y,x,z;\n    scanf(\"%lld %lld\",&a,&b);\n    for(i=1;i<=a;i++){\n        sum+=(i*b*i+(i*(i+1))/2);\n        //printf(\"aa=%d \",(i*b*i+(i*(i+1))/2));}\n    for(i=1;i<=b-2;i++)\n    {\n        y=i*(a+1); z=(i+1)*(a+1)-1;\n        for(y; y<=z; y++)\n        {\n            q=y;\n            if(q>b-1)\n                q=b-1;\n            x=(q*(q+1))/2-(i*(i+1))/2;\n            sum+=(q-i)*b*y+x;\n            //printf(\"bb=%d \",(q-i)*b*y+x);\n        }\n    }\n    printf(\"%lld\",sum-sum/1000000007*1000000007);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b0f70971914fe61878d424f7a348c62b", "src_uid": "cd351d1190a92d094b2d929bf1e5c44f", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nconst int mod=1000000007;\n\nint main(void)\n{\n\tint a, b, k, ans;\n\tlong long t;\n\t\n\tans = 0;\n\tscanf(\"%d%d\", &a, &b);\n\tfor (k=1; k<=a; ++k) {\n\t\tt = b-1;\n\t\tans = (t*(t+1)/2*(k*b+1)+ans)%mod;\n\t}\n\tprintf(\"%d\\n\", ans);\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fbbe00d151c349faafeea6a3fb748fae", "src_uid": "cd351d1190a92d094b2d929bf1e5c44f", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <stdint.h>\n\nint main()\n{\n    uint32_t a,b,j,i;\n    uint64_t sum=0,modsum;\n    scanf(\"%I32d%I32d\",&a,&b);\n    modsum=((b-1)*b)/2;\n    for(j=1;j<=a;j++) {\n        sum+=modsum*(j*b+1);\n        sum%=1000000007;\n    }\n    printf(\"%I64d\",sum);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2267b4349bdf81acf627e5056a016a20", "src_uid": "cd351d1190a92d094b2d929bf1e5c44f", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long dp[100][100],boy[10000],girl[10000];\nlong long comb(long long n,long long r)\n{\n    long long i,j;\n    if(r==0 || n==r)\n    {\n        dp[n][r]=1;\n        return 1;\n    }\n    if(dp[n][r]!=-1)\n        return dp[n][r];\n    else\n    {\n        dp[n][r]=comb(n-1,r-1)+comb(n-1,r);\n        return dp[n][r];\n    }\n}\nint main()\n{\n    long long i=0,j,k,n,m,t,x,y,z,ans=0;\n    for(i=0; i<100; i++)\n    {\n        for(j=0; j<100; j++)\n        {\n            dp[i][j]=-1;\n        }\n    }\n    scanf(\"%I64d %I64d %I64d\",&n,&m,&t);\n    x=1;\n    y=n;\n    //printf(\"%d\\n\",comb(12,4));\n    if(n+m==t)\n    {\n        ans=comb(n,m);\n        printf(\"%I64d\",ans);\n        return 0;\n    }\n    i=0;\n    while(n>=4 && x<=m)\n    {\n        if(n+x==t)\n        {\n\n            boy[i]=n;\n            girl[i]=x;\n            //printf(\"%I64d %I64d\\n\",boy[i],girl[i]);\n            x++;\n            i++;\n        }\n        n--;\n    }\n    for(j=0; j<i; j++)\n    {\n        //printf(\"%I64d %I64d %I64d %I64d %I64d %I64d %I64d\\n\",y,boy[j],m,girl[j],comb(y,boy[j]),comb(m,girl[j]),comb(y,boy[j])*comb(m,girl[j]));\n        ans+=comb(y,boy[j])*comb(m,girl[j]);\n    }\n    printf(\"%I64d\",ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3b347f6edff4db96add27cde9534b7c9", "src_uid": "489e69c7a2fba5fac34e89d7388ed4b8", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nlong long f(long long n)\n{\n    long long r=1,i;\n    for(i=2;i<=n;i++)\n    {\n        r*=i;\n    }\n    return r;\n}\n\nint main()\n{\n    int n1,m1,t1;\n    scanf(\"%d %d %d\",&n1,&m1,&t1);\n    long long n=n1,m=m1,t=t1,r=0,i,j,tmp;\n    for(i=4;i<=t-1&&i<=n;i++)\n    {\n        tmp=(f(n)/(f(i)*f(n-i)));\n        for(j=1;i+j<=t&&j<=m;j++)\n        {\n                r+=tmp*(f(m)/(f(j)*f(m-j)));\n        }\n    }\n    printf(\"%I64d\",r);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "287e23795542452256326a4c7524867d", "src_uid": "489e69c7a2fba5fac34e89d7388ed4b8", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nlong long f(long long n)\n{\n    long long r=1,i;\n    for(i=2;i<=n;i++)\n    {\n        r*=i;\n    }\n    return r;\n}\n\nint main()\n{\n    long long n,m,t,r=0,i,j;\n    scanf(\"%I64d %I64d %I64d\",&n,&m,&t);\n    for(i=4;i<=t-1;i++)\n    {\n        for(j=1;i+j<=t;j++)\n        {\n                r+=(f(n)/(f(i)*f(n-i)))*(f(m)/(f(j)*f(m-j)));\n        }\n    }\n    printf(\"%I64d\",r);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7dfbea0f6586dff4ce71a6f4028cb22a", "src_uid": "489e69c7a2fba5fac34e89d7388ed4b8", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\ntypedef long long ll;\nint c[40][40];\nint main()\n{\n    for (int i=0;i<=30;i++)\n    {\n        c[i][0]=c[i][i]=1;\n        for (int j=1;j<i;j++)\n            c[i][j]=c[i-1][j-1]+c[i-1][j];\n    }\n    long long int n,m,t,i;\n    scanf(\"%I64d%I64d%I64d\",&n,&m,&t);\n    ll ans=0;\n    for (i=4;i<=n;i++)\n    {\n        int p=t-i;\n        if (p<1)\n            break;\n        if (p>m)\n            continue;\n        ans+=ll(c[n][i])*c[m][p];\n    }\n    printf(\"%I64d\\n\",ans);\n    return(0);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "86f02dc05ae23477b1f5c7f612a99d9c", "src_uid": "489e69c7a2fba5fac34e89d7388ed4b8", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nlong long f(long long n)\n{\n    long long r=1;\n    for(long long i=2;i<=n;i++)\n    {\n        r*=i;\n    }\n    return r;\n}\n\nint main()\n{\n    long long n,m,t,r=0;\n    scanf(\"%I64d %I64d %I64d\",&n,&m,&t);\n    for(int i=4;i<=t-1;i++)\n    {\n        for(int j=1;i+j<=t;j++)\n        {\n                r+=(f(n)/(f(i)*f(n-i)))*(f(m)/(f(j)*f(m-j)));\n        }\n    }\n    printf(\"%I64d\",r);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fd3508575704e867ea65c805e8cdab03", "src_uid": "489e69c7a2fba5fac34e89d7388ed4b8", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    int k,a,b;\n    scanf(\"%d %d %d\",&k,&a,&b);\n    if(a<k&&b<k)\n    {\n        printf(\"-1\");\n    }\n    else\n    {\n        printf(\"%d\",a/k+b/k);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "25c79da0c9a59419ea762b776946fd27", "src_uid": "6e3b8193d1ca1a1d449dc7a4ad45b8f2", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "/*\n   Sachin Chandani\n   IIIT Hyderabad\n */\n\n#include<stdio.h>\n#include<limits.h>\n#include<string.h>\n#include<stdlib.h>\n#include<math.h>\n#include<stdbool.h>\ntypedef long long int ll;\n#define INF INT_MAX\nint min(int a,int b);\nvoid swap(int *a,int *b);\nvoid swap(int *a,int *b)\n{\n\tint temp=*a;\n\t*a=*b;\n\t*b=temp;\n}\nint cmp(const void *a,const void *b)\n{\n\treturn(*(int*)a-*(int*)b);\n\n}\nint min(int a,int b)\n{\n\treturn(a>b?b:a);\n}\n\nint main()\n{\n\tlong long int k,a,b,ans=0;\n\tscanf(\"%lld%lld%lld\",&k,&a,&b);\n\tif(a+b-min(a,b)<k)\n\t\tans=-1;\n\telse\n\t{\n\t\tans=(a/k)+(b/k);\n\t}\n\tprintf(\"%lld\",ans);\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "eb7949b0e4b033716d03dc756b2bdc57", "src_uid": "6e3b8193d1ca1a1d449dc7a4ad45b8f2", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n\n/* run this program using the console pauser or add your own getch, system(\"pause\") or input loop */\n\nint main(int argc, char** argv) {\n\t\n\tlong long int k,a,b,c;\n\tscanf(\"%lld%lld%lld\",&k,&a,&b);\n\tif((a+b)/k==0)printf(\"-1\");\n\telse printf(\"%lld\",(a+b)/k);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "64e22c6164c4f59844d09389e59c68d8", "src_uid": "6e3b8193d1ca1a1d449dc7a4ad45b8f2", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\n\nint main()\n{\n    long long int k,a,b;\n    scanf(\"%lld %lld %lld\", &k, &a, &b);\n    if((a<k && b<k) || (a<k && b%k!=0) || (b<k && a%k!=0))\n    {\n        printf(\"-1\");\n    }\n    else\n    {\n        printf(\"%lld\", ((a/k)+(b/k)));\n    }\n        return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "80e1b9116f99fd38c1992ac2ef6786e1", "src_uid": "6e3b8193d1ca1a1d449dc7a4ad45b8f2", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(){\n\tint s, a, b, ts, us;\n\tscanf(\"%d %d %d\", &s, &a, &b);\n\tts = 0;\n\tts += a/s;\n\tts += b/s;\n\tus = 0;\n\tif(a%s!=0){\n\t\tus++;\n\t}\n\tif(a%b!=0){\n\t\tus++;\n\t}\n\tif(us>ts){\n\t\tprintf(\"-1\\n\");\n\t}\n\telse{\n\t\tprintf(\"%d\\n\", ts);\n\t}\n\treturn(0);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "bd305e8a83b9b4c1bed1a8132e85a77d", "src_uid": "6e3b8193d1ca1a1d449dc7a4ad45b8f2", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n\nint main()\n{\nint x1,y1,x2,y2;\nscanf(\"%d%d%d%d\",&x1,&y1,&x2,&y2);\nif(x1==x2)\n{\n\n\tprintf(\"%d\",2*(abs(y2-y1)+1));\n}\nelse if(y1==y2)\n{\n\tprintf(\"%d\",2*(abs(x2-x1)+1));\n}\nelse \n{\n\tprintf(\"%d\",2*((abs(x2-x1)+1)+(abs(y2-y1)+1)));\n}\n\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f0f5a17877f352ac243c40ef1ebb40c5", "src_uid": "f54ce13fb92e51ebd5e82ffbdd1acbed", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n\nint main(){\n\nint x1, x2, y1, y2, c, d, m, n, o;\nscanf(\"%d%d%d%d\", &x1,&y1,&x2,&y2);\n\nm=(x2-x1);\nn=(y2-y1);\n\n\n\nif(m<0) m=m*(-1);\nelse if(n<0) n=n*(-1);\n\no=((m+1)+(n+1))*2;\n\n//if(o<8) printf(\"8\");\n//else\n\nif(o<10) printf(\"%d\", o+2);\nelse printf(\"%d\", o);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3471ecc00c225119ef58254c09d84ceb", "src_uid": "f54ce13fb92e51ebd5e82ffbdd1acbed", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n\nint main()\n{\nint x1,y1,x2,y2;\nscanf(\"%d%d%d%d\",&x1,&y1,&x2,&y2);\nif(x1==x2)\n{\n\n\tprintf(\"%d\",(2*(abs(y2-y1)+1))+4);\n}\nelse if(y1==y2)\n{\n\tprintf(\"%d\",2*(abs(x2-x1)+1)+4);\n}\nelse \n{\n\tprintf(\"%d\",2*((abs(x2-x1)+1)+(abs(y2-y1)+1)));\n}\ngetch();\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "336c40e8c047bcda7548332aab5eccb8", "src_uid": "f54ce13fb92e51ebd5e82ffbdd1acbed", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n\nint main()\n{\nint x1,y1,x2,y2;\nscanf(\"%d%d%d%d\",&x1,&y1,&x2,&y2);\nif(x1==x2)\n{\n\n\tprintf(\"%d\",4*(abs(y2-y1)+1));\n}\nelse if(y1==y2)\n{\n\tprintf(\"%d\",4*(abs(x2-x1)+1));\n}\nelse \n{\n\tprintf(\"%d\",2*((abs(x2-x1)+1)+(abs(y2-y1)+1)));\n}\ngetch();\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "607d6548205d0a07f67ad5747e868890", "src_uid": "f54ce13fb92e51ebd5e82ffbdd1acbed", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint min(int a, int b)\n{\n    return a < b ? a : b;\n}\n\nint max(int a, int b)\n{\n    return a > b ? a : b;\n}\n\nint az(int a)\n{\n    return a > 0 ? a : -a;\n}\n\nint main()\n{\n    int x1, x2, y1, y2, a, b, c, d;\n    scanf(\"%d%d%d%d\", &x1, &y1, &x2, &y2);\n    a = min(x1, x2 - 1);\n    b = max(x1, x2 + 1);\n    c = min(y1, y2 - 1);\n    d = max(y1, y2 + 1);\n    printf(\"%d\\n\", az(2 * (a - b) * (c - d));\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6f4a66de9872c87aad089eef34f538a8", "src_uid": "f54ce13fb92e51ebd5e82ffbdd1acbed", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    scanf(\"%d\",&n)\n    if(n%2==0)\n    {\n        printf(\"Mahmoud\\n\");\n    }\n    else\n    {\n        printf(\"Ehab\\n\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "581183f427aa530ef97c455d2ed7edd3", "src_uid": "5e74750f44142624e6da41d4b35beb9a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nmain()\n{\n    int a,;\n    scanf(\"d%\",&a);\n    if(a%2==0)\n    {\n        printf(\"Mahmoud\");\n    }\n    if(a%2==1)\n    {\n        printf(\"Ehab\");\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0a3a0c5d20af82f049bcb3d8769be9f5", "src_uid": "5e74750f44142624e6da41d4b35beb9a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main ()\n{\n    int a;\n    scanf(\"%d\",&a);\n    if (a%2==0)\n    {\n        printf(\"Mahmoud\\n\");\n    }\n    else\n    {\n        printf(\"Ehab\\n\");\n    }\n    return 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "714bf53ec95ebbecbc4751d37cd85a2b", "src_uid": "5e74750f44142624e6da41d4b35beb9a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nmain()\n{\n    int a,b;\n    scanf(\"d%\",&a);\n    b=a%2;\n    if  b==0) {printf(\"Mahmoud\");}\n    else  {printf(\"Ehab\");}\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d971bb694bbdaa27425a2563bc140311", "src_uid": "5e74750f44142624e6da41d4b35beb9a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main() {\n\tint n;\n\tscanf(\"%d\", &n);\n\tif (n % 2 == 0) {\n\t\tprintf(\"Mahmoud\\n\");\n\t}\n\telse {\n\t\tprintf(\"Ehab\\n\");\n\t}\n\treturn 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9b042812cc1fc679b564eddb325af776", "src_uid": "5e74750f44142624e6da41d4b35beb9a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(int argc, char **argv)\n{\n    char b[100]\n    char hand;\n    int v = 0, k = 0, i;\n    scanf(\"%s\", b);\n    hand = b[0];\n    for (i = 0; b[i] != '\\0'; i++) {\n        if (v == 5) {\n            k++;\n                       v = 0;\n        }\n        if (b[i] == hand) {\n            v++;\n                   }\n        if (b[i] != hand) {\n            if (v != 0) k++;\n           \n            hand = b[i];\n            v = 1;\n        }\n    }\n    if (v != 0) k++;\n    printf(\"%d\\n\",k);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6d79f630fb44e19d7b9b5bb83a975ee0", "src_uid": "5257f6b50f5a610a17c35a47b3a0da11", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(){\n int a[101],i,k=0,v=0,f=5;\n for (i=0;a[i]!=\\0;i++){\n  scanf(\"%d\",&a[i]);\n }\n for (i=1;a[i]!=\\0;i++){\n  if ((a[i]==a[i-1]) && (v<f)){\n   v++;\n  }else{\n   k++;\n  }\n }\nprintf(\"%d/n\",k);\nreturn 0;\n}\n   ", "lang_cluster": "C", "compilation_error": true, "code_uid": "afdf694d85380fcbbb844bca3e7bf8f8", "src_uid": "5257f6b50f5a610a17c35a47b3a0da11", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(){\nint a[101],i,k=0,v=0,f=5;\nfor (i=0;a[i]!='\\0';i++){\nscanf(\"%d\",&a[i]);\n}\nfor (i=1;a[i]!='\\0';i++){\nif ((a[i]==a[i-1]) && (v<f)){\nv++;\n}else{\nk++ && v=0;\n}\n}\nprintf(\"%d\\n\",k);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "69c28ac25a1398ffe744dd52fadc75e6", "src_uid": "5257f6b50f5a610a17c35a47b3a0da11", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "// Author: Ernesto Carvajal Lastres. Madrid, Spain.\n#include <stdio.h>\n#include <ctype.h>\nint main()\n{\n    int sol(1),count(2); char ch, lc = getchar();\n    while ((ch = getchar()) != EOF)\n        if (!isspace(ch))\n            if (ch != lc || count > 5) {\n                count = 1; sol++; lc = ch;\n            } else count++;\n    printf(\"%d\\n\",sol);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c7adbb7b70304ae9a98d73c876cd9152", "src_uid": "5257f6b50f5a610a17c35a47b3a0da11", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "main(a,b)\n{\nchar c=' ',d;\nwhile((d=getchar()))\n{\nif(d==c) a++;\nif(a==5 || c!=d){b++;a=0;c=d;}\n}\nprintf(\"%d\",b);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "781fa60bcb63c9ee29fef2978aa6c7c7", "src_uid": "5257f6b50f5a610a17c35a47b3a0da11", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\nint main()\n{\n    int x,n;\n    scanf(\"%d\",&n);\n    x=(int)sqrt(n);\n    (n>x*x+x)?printf(\"%d\",2*x+2):(n=x*x)?printf(\"%d\",2*x):printf(\"%d\",2*x+1);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "817adb2765a41d6f45a84ad345a649a7", "src_uid": "eb8212aec951f8f69b084446da73eaf7", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#include <math.h>\n\nint main( void )\n\n{\n\n    int i ;\n\n    scanf(\"%d\",&i) ;\n\n    double d = i*1.0 ;\n\n    double root = sqrt( d ) ;\n\n    int ans = ceil(2*root) ;\n\n    printf(\"%d\\n\",ans ;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2274e1c7063f29136edda6a9fcb922ee", "src_uid": "eb8212aec951f8f69b084446da73eaf7", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint SEGMENTS(int s)\n{\nint Total , p , quired ;\np=2;\ntotal = 1 ;\nwhile(1)\n{\nTotal= Total + p/2 ;\nif (s<Total)\n{\n    quired = p ;\n    break ;\n}\np = p+1 ;\n}\nreturn quired ;\n\n}\n\nint main()\n{\nint t;\nscanf(\"%d\", &t) ;\nint m = SEGMENTS(t) ;\nprintf(\"%d\",m);\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1727e682a0be76f2643b202aecd18674", "src_uid": "eb8212aec951f8f69b084446da73eaf7", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n\tint n,y;\n\tdouble l,u,d,x;\n\tscanf(\"%d\",&n);\n\tdouble a=sqrt((double)n);\n\tl=floor(a);\n\tif(l!=a)\n\t{\n\tu=ceil(a);\n    d=n-(l*l);\n    if(d>l)\n    x=2*u;\n    else\n    x=2*l+1;\n    y=(int)x;\n}\nelse\ny=2*a;\nprintf(\"%d\",y);1\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9ae91741246c66f75001658a6072b8ee", "src_uid": "eb8212aec951f8f69b084446da73eaf7", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "include<stdio.h>\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    if(n==1)\n        printf(\"2\");\n    else if(n==2)\n        printf(\"3\");\n    else\n    printf(\"%d\",n);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ad4a0f2005dcf41f2fdd4b54f461f365", "src_uid": "eb8212aec951f8f69b084446da73eaf7", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int a, b;\n    char c;\n    scanf(\"%d\", &a);\n    scanf(\"%c\"c, &c);\n    if(a==3 && c==db){\n        b=5;\n        printf(\"%d\"d,b);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "87419321245d4db0a02af84b16775a12", "src_uid": "d3929a9acf1633475ab16f5dfbead13c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "//#include <iostream>\n#include <stdio.h>\n//using namespace std;\n\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tchar arr[n];\n\tgetchar();\n    scanf(\"%[^\\n]s\",arr);\n\n   // gets(arr);\n    int count=0;\n    for(int i=0;i<n;i++)\n    {\n    \tif(int(arr[i])>=65 && int(arr[i])<=90)\n    \t{\n    \t\tcount++;\n    \t}\n    }\n\n    printf(\"%d\",count);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "64682a097aabf65cdd6ed2ff73a4ab6a", "src_uid": "d3929a9acf1633475ab16f5dfbead13c", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "//educational codeforces A\n#include<stdio.h>\n#include<string.h>\n\nusing namespace std;\nint main()\n{\n    int n;\n    char s[205];\n    int temp;\n    int ans = 0;\n    char nextline;\n    scanf(\"%d%c\",&n,&nextline);\n    gets(s);\n    temp = 0;\n    for(int i=0;i<strlen(s);i++)\n    {\n        if(s[i]==' ')\n        {\n            if(temp>ans)\n                ans = temp;\n            temp = 0;\n        }\n        else if(s[i]>='A'&&s[i]<='Z')\n        {\n            temp++;\n        }\n        else\n        {\n            continue;\n        }\n    }\n    ans = ans>temp?ans:temp;\n    printf(\"%d\\n\",ans);\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "699345d288ec9a8fe9d0f67cfa2fb9ca", "src_uid": "d3929a9acf1633475ab16f5dfbead13c", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\n\nint main()\n{\n\tint a,b,c=0,i;\n\tchar x;\n\tscanf(\"%d\",&a);\n\tgetch();\n\t\n\tfor (i=1; i<=a; i++){\n\t\tscanf(\"%c\",&x);\n\t\tif (x>='A' && x<='Z') b++;\n\t\tif (x==' '){\n\t\t            if(c<b){\n                                    c=b;\n                                    }\n\t\t\t    b=0;\n\t\t}\n\t}\n\tif (b>=c)  printf(\"%d\",b);\n\telse printf (\"%d\",c);\n\treturn 0;\n}\n\t\t", "lang_cluster": "C", "compilation_error": false, "code_uid": "040ef751df0f5e79e6ade89e511726ea", "src_uid": "d3929a9acf1633475ab16f5dfbead13c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <conio.h>\n\nint main()\n{\n\tint n,max = 0,i;\n\tscanf(\"%d\\n\",&n);\n\tint curr = 0;\n\tchar c;\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%c\",&c);\n\t\tif(c >= 65 && c  <= 90){\n\t\t\tcurr++;\n\t\t}\n\n\t\telse if(c == 32 || c == 3)\n\t\t{\n\t\t\tif(curr > max)\n\t\t\t{\n\t\t\t\tmax = curr;\n\t\t\t\tcurr = 0;\n\t\t\t}\n\t\t}\n\t\n\t}\n\tif(curr > max)\n\t\tmax = curr;\n\tprintf(\"%d\",max);\n\tgetch(); \n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9f392bb81c10370e1192cc0e2832f5e3", "src_uid": "d3929a9acf1633475ab16f5dfbead13c", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <cstdio>\n\nint main(void)\n{\n    int p1,p2,p3,p4,a,b,i,cnt=0;\n    scanf(\"%d%d%d%d%d%d\",&p1,&p2,&p3,&p4,&a,&b);\n    for(i=a;i<=b;i++)\n        if(i%p1%p2%p3%p4==i)\n            cnt++;\n    printf(\"%d\\n\",cnt);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "58b4512ae54f2371e038d7a5212ce016", "src_uid": "63b9dc70e6ad83d89a487ffebe007b0a", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint p1,p2,p3,p4,a,b,ans;\nint main(){\n\tios::sync_with_stdio(false);\n\tscanf(\"%d %d %d %d %d %d\",&p1,&p2,&p3,&p4,&a,&b);\n\tfor(int i=a;i<=b;i++){\n\t\tif(i%p1==i&&i%p2==i&&i%p3==i&&i%p4==i){\n\t\t\tans++;\n\t\t}\n\t}\n\tprintf(\"%d\",ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7f5764afb0aa9d22cddcad874176fdf0", "src_uid": "63b9dc70e6ad83d89a487ffebe007b0a", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <cstdio>\n\nint main(void)\n{\n    int p1,p2,p3,p4,a,b,i,cnt=0;\n    scanf(\"%d%d%d%d%d%d\",&p1,&p2,&p3,&p4,&a,&b);\n    for(i=a;i<=b;i++)\n        if(i%p3%p2%p1%p4==i)\n            cnt++;\n    printf(\"%d\\n\",cnt);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "99d44278cb5f562c97524f8dcf5b8774", "src_uid": "63b9dc70e6ad83d89a487ffebe007b0a", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint a[4],i=0,a1,b1,j=0;\nscanf(\"%d%d%d%d%d%d\",&a[0],&a[1],&a[2],&a[3],&a1,&b1);\nj=a[0]<a[1]?a[0]:a[1];\nj=j<a[2]?j:a[2];\nj=j<a[3]?j:a[3];\nif((j-a1)<0)\nprintf(\"%d\\n\",0);\nelse\nprintf(\"%d\\n\",(j-a1)>b1-a1?(b1-a1+1):j-a1);\nreturn 0;\n}\n~  ", "lang_cluster": "C", "compilation_error": true, "code_uid": "7cb0d9f2bc99b55690f8b4fea0f4eed3", "src_uid": "63b9dc70e6ad83d89a487ffebe007b0a", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n     int p1, p2, p3, p4, a, b;\n\n     scanf(\"%d %d %d %d %d %d\", &p1, &p2, &p3, &p4, &a, &b);\n\n     if (p2 < p1) p1 = p2;\n     if (p3 < p1) p1 = p3;\n     if (p4 < p1) p1 = p4;\n\n     if (p1 > a) {\n\t  printf(\"%d\\n\", p1 - a);\n     } else {\n\t  puts(\"0\");\n     }\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "16feee5f6279b429e244e927f5cf8e17", "src_uid": "63b9dc70e6ad83d89a487ffebe007b0a", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    char a[4][4] , ch;\n    int i,j,x=0,o=0,dot=0,flagX=0,flagO=0;\n    for(i=0; i<3; i++)\n    {\n        for(j=0; j<3; j++)\n        {\n            scanf(\"%c\",&a[i][j]);\n            if(a[i][j]=='X')\n                x++;\n            else if(a[i][j]=='0')\n                o++;\n            else\n                dot++;\n\n        }\n\n        ch=getchar();\n    }\n    if(x==o+1 || x==o)\n    {\n        if(a[0][0]==a[1][1] && a[1][1]==a[2][2] && a[j][0]!='.')\n        {\n            if(a[0][0]=='X')\n            {\n                flagX++;\n            }\n            else if(a[0][0]=='0')\n            {\n                flagO++;\n            }\n        }\n        if(a[0][2]==a[1][1] && a[1][1]==a[2][0] && a[j][2]!='.')\n        {\n            if(a[0][2]=='X')\n            {\n                flagX++;\n            }\n            else if(a[0][2]=='0')\n            {\n                flagO++;\n            }\n        }\n    }\n    if(x==o+1 || x==o)\n    {\n\n        for(j=0; j<3; j++)\n        {\n            if(a[0][j]==a[1][j] && a[1][j]==a[2][j] && a[0][j]!='.')\n            {\n                if(a[0][j]=='X')\n                {\n                    flagX++;\n                }\n                else if(a[0][j]=='0')\n                {\n                    flagO++;\n                }\n            }\n            else if(a[j][0]==a[j][1] && a[j][1]==a[j][2] && a[j][0]!='.')\n            {\n                if(a[j][0]=='X')\n                {\n                    flagX++;\n                }\n                else if(a[j][0]=='0')\n                {\n                    flagO++;\n                }\n            }\n        }\n\n\n    }\n\n\nelse\n{\n    printf(\"illegal\");\n    return 0;\n}\n\nif((flagO==1 || flagO==2) && o==x && flagX==0)\n    printf(\"the second player won\");\n\nelse if((flagX==1 || flagX==2) && x>o && flagO==0)\n    printf(\"the first player won\");\n\nelse if(flagO==0 && flagX==0 && dot==0)\n    printf(\"draw\");\nelse if(flagO==0 && flagX==0 && dot!=0)\n{\n    if(x>o)\n        printf(\"second\");\n    else\n        printf(\"first\");\n}\n\nelse\n    printf(\"illegal\");\n\n\nreturn 0;\n}#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    char a[4][4] , ch;\n    int i,j,x=0,o=0,dot=0,flagX=0,flagO=0;\n    for(i=0; i<3; i++)\n    {\n        for(j=0; j<3; j++)\n        {\n            scanf(\"%c\",&a[i][j]);\n            if(a[i][j]=='X')\n                x++;\n            else if(a[i][j]=='0')\n                o++;\n            else\n                dot++;\n\n        }\n\n        ch=getchar();\n    }\n    if(x==o+1 || x==o)\n    {\n        if(a[0][0]==a[1][1] && a[1][1]==a[2][2] && a[j][0]!='.')\n        {\n            if(a[0][0]=='X')\n            {\n                flagX++;\n            }\n            else if(a[0][0]=='0')\n            {\n                flagO++;\n            }\n        }\n        if(a[0][2]==a[1][1] && a[1][1]==a[2][0] && a[j][2]!='.')\n        {\n            if(a[0][2]=='X')\n            {\n                flagX++;\n            }\n            else if(a[0][2]=='0')\n            {\n                flagO++;\n            }\n        }\n    }\n    if(x==o+1 || x==o)\n    {\n\n        for(j=0; j<3; j++)\n        {\n            if(a[0][j]==a[1][j] && a[1][j]==a[2][j] && a[0][j]!='.')\n            {\n                if(a[0][j]=='X')\n                {\n                    flagX++;\n                }\n                else if(a[0][j]=='0')\n                {\n                    flagO++;\n                }\n            }\n            else if(a[j][0]==a[j][1] && a[j][1]==a[j][2] && a[j][0]!='.')\n            {\n                if(a[j][0]=='X')\n                {\n                    flagX++;\n                }\n                else if(a[j][0]=='0')\n                {\n                    flagO++;\n                }\n            }\n        }\n\n\n    }\n\n\nelse\n{\n    printf(\"illegal\");\n    return 0;\n}\n\nif((flagO==1 || flagO==2) && o==x && flagX==0)\n    printf(\"the second player won\");\n\nelse if((flagX==1 || flagX==2) && x>o && flagO==0)\n    printf(\"the first player won\");\n\nelse if(flagO==0 && flagX==0 && dot==0)\n    printf(\"draw\");\nelse if(flagO==0 && flagX==0 && dot!=0)\n{\n    if(x>o)\n        printf(\"second\");\n    else\n        printf(\"first\");\n}\n\nelse\n    printf(\"illegal\");\n\n\nreturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "243f372017f75c7e8b027d5daf085a7d", "src_uid": "892680e26369325fb00d15543a96192c", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nchar grid[3][3];\n\n\n\nint countChar(char c)\n{\n\tint count=0;\n\tint i, j;\n\tfor (i = 0; i < 3; i++)\n\t{\n\t\tfor (j = 0; j < 3; j++)\n\t\t{\n\t\t\tif (grid[i][j] == c)\n\t\t\t{\n\t\t\t\tcount++;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn count;\n\n}\n\nint checkWins(char c)\n{\n\tint flag=0;\n\t//horizontal wins\n\tif (grid[0][0] == c && grid[0][1] == c && grid[0][2] == c)\n\t{\n\t\tflag ++;\n\t}\n\n\tif (grid[1][0] == c && grid[1][1] == c && grid[1][2] == c)\n\t{\n\t\tflag++;\n\t}\n\n\tif (grid[2][0] == c && grid[2][1] == c && grid[2][2] == c)\n\t{\n\t\tflag++;;\n\t}\n\n\t//vertical wins\n\n\tif (grid[0][0] == c && grid[1][0] == c && grid[2][0] == c)\n\t{\n\t\tflag++;\n\t}\n\n\tif (grid[0][1] == c && grid[1][1] == c && grid[2][1] == c)\n\t{\n\t\tflag ++;\n\t}\n\n\tif (grid[0][2] == c && grid[1][2] == c && grid[2][2] == c)\n\t{\n\t\tflag ++;\n\t}\n\n\t//diagonal wins\n\n\tif (grid[0][0] == c && grid[1][1] == c && grid[2][2] == c)\n\t{\n\t\tflag ++;\n\t}\n\n\tif (grid[0][2] == c && grid[1][1] == c && grid[2][0] == c)\n\t{\n\t\tflag ++;\n\t}\n\n\n\treturn flag;\n\n\n}\n\n\n\n\n\nint main()\n{\n\tint i;\n\tint nx, n0, nd;\n\tfor (i = 0; i < 3; i++)\n\t{\n\t\t{\n\t\t\tscanf(\"%s\", &grid[i]);\n\t\t}\n\t}\n\n\n\n\n\t/*for (i = 0; i < 3; i++)\n\t{\n\t\tfor (j = 0; j < 3; j++)\n\t\t{\n\t\t\tprintf(\"%c \", grid[i][j]);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n\n\tgetch();\n*/\n\tnx = countChar('X');\n\tn0 = countChar('0');\n\tnd = countChar('.');\n\n\t//Check illegal\n\tif (nx - n0 == 1 || nx - n0 == 0)\n\t{\n\t\tif (checkWins('X') > 0 && checkWins('0') > 0)\n\t\t{\n\t\t\tprintf(\"illegal \\n\");\n\t\t\t\n\t\t}\n\t\telse\n\t\t{\n\t\t\tif (checkWins('X') > 0 && checkWins('0') == 0)\n\t\t\t{\n\t\t\t\tif (nx - n0 == 1)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"the first player won \\n\");\n\n\t\t\t\t}\n\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tprintf(\"illegal \\n\");\n\t\t\t\t}\na\n\n\t\t\t}\n\n\t\t\telse if (checkWins('X') == 0 && checkWins('0')> 0)\n\t\t\t{\n\t\t\t\tif (nx - n0 == 0)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"the second player won \\n\");\n\n\t\t\t\t}\n\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tprintf(\"illegal \\n\");\n\t\t\t\t}\n\n\n\t\t\t\t\n\t\t\t}\n\n\t\t\telse if (checkWins('X') == 0 && checkWins('0') == 0)\n\t\t\t{\n\t\t\t\tif (nx > n0)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"second \\n\");\n\n\t\t\t\t}\n\n\t\t\t\telse if (nx==n0)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"first \\n\");\n\t\t\t\t}\n\t\t\t}\n\n\t\t\telse if (nd == 0)\n\t\t\t{\n\t\t\t\tprintf(\"draw \\n\");\n\t\t\t}\n\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\"illegal \\n\");\n\t\t\t}\n\n\t\t\t\n\t\t}\n\n\n\t}\n\telse\n\t{\n\t\tprintf(\"illegal \\n\");\n\t}\n\n\t\n\n\n\n\t//getch();\n\n\n\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "011bdf0c20609e3954d50968136fd7d3", "src_uid": "892680e26369325fb00d15543a96192c", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main() {\n    short int numx,num0,dot,rowx,row0,bufx,buf0;\n    numx = num0 = dot = rowx = row0 = bufx = buf0 = 0;\n    char mat[3][3];\n    char tt;\n    for (int i = 0; i < 3; i++ )\n    {\n        scanf(\"%s\", mat[i]);\n    }\n    \n    for (int i = 0; i < 3; i++)\n    {\n        for(int j = 0; j < 3; j++ )\n        {\n            if (mat[i][j] == 'X')\n                numx++;\n            else if (mat[i][j] == '0')\n                num0++;\n            else\n                dot++;\n        }\n    }\n    if (numx - 1 > num0 || num0 > numx)\n        printf(\"illegal\");\n    else \n    {   \n        for(int i = 0; i < 3; i++ )\n        {\n            for(int j = 0; j < 3; j++ )\n            {\n                if (mat[i][j] == 'X')\n                    bufx++;\n                if (mat[i][j] == '0')\n                    buf0++;\n            }\n            if (bufx == 3)\n                rowx++;\n            if (buf0 == 3)\n                row0++;\n            bufx = buf0 = 0;\n        }\n        for(int j = 0; j < 3; j++ )\n        {\n            for(int i = 0; i < 3; i++ )\n            {\n                if (mat[i][j] == 'X')\n                    bufx++;\n                if (mat[i][j] == '0')\n                    buf0++;\n            }\n            if (bufx == 3)\n                rowx++;\n            if (buf0 == 3)\n                row0++;\n            bufx = buf0 = 0;\n        }\n        if ((mat[0][0] == 'X' && mat[1][1] == 'X' && mat[2][2] == 'X') || (mat[0][2] == 'X' && mat[1][1] == 'X' && mat[2][0] == 'X'))\n            rowx++;\n        if ((mat[0][0] == '0' && mat[1][1] == '0' && mat[2][2] == '0') || (mat[0][2] == '0' && mat[1][1] == '0' && mat[2][0] == '0'))\n            row0++;\n        \n        if ((rowx > 0 ) && (numx == num0))\n        {\n            printf(\"illegal\");\n        } \n        else if ((row0 > 0 ) && (numx - 1 == num0)) \n        {\n            printf(\"illegal\");\n        } \n        else if (dot == 0) \n        {\n            if(rowx)\n            {\n                printf(\"the first player won\");\n            }\n            else if (row0)\n            {\n                printf(\"the second player won\");\n            }\n            else\n            {\n                printf(\"draw\");\n            }\n        }\n        else \n        {\n            if (rowx)\n            {\n                printf(\"the first player won\");\n            }\n            else if (row0)\n            {\n                printf(\"the second player won\");\n            }\n            else if (numx == num0)\n            {\n                printf(\"first\");\n            }\n            else\n            {\n                printf(\"second\");\n            }\n        }\n    }    ", "lang_cluster": "C", "compilation_error": true, "code_uid": "cf903111d22f83bf61911b2d81496c5e", "src_uid": "892680e26369325fb00d15543a96192c", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main ()\n{\n    char row1[3];\n    char row2[3];\n    char row3[3];\n    int i,x_count=0,o_count=0;\n    for(i=0;i<3;i++)\n    {\n        scanf(\"%c\",&row1[i]);\n        if(row1[i]=='X')\n        {\n            x_count++;\n        }\n        if(row1[i]=='0')\n        {\n            o_count++;\n        }\n    }\n    scanf(\"\\n\");\n    for(i=0;i<3;i++)\n    {\n        scanf(\"%c\",&row2[i]);\n        if(row2[i]=='X')\n        {\n            x_count++;\n        }\n        if(row2[i]=='0')\n        {\n            o_count++;\n        }\n    }\n    scanf(\"\\n\");\n    for(i=0;i<3;i++)\n    {\n        scanf(\"%c\",&row3[i]);\n        if(row3[i]=='X')\n        {\n            x_count++;\n        }\n        if(row3[i]=='0')\n        {\n            o_count++;\n        }\n    }\n    if((fabs(x_count-o_count)>1)||x_count>5||o_count>4)\n    {\n        printf(\"illegal\");\n        return ;\n    }\n    else{\n        if(((row1[0]=='X'&&row1[1]=='X'&&row1[2]=='X')||(row2[0]=='X'&&row2[1]=='X'&&row2[2]=='X')||(row3[0]=='X'&&row3[1]=='X'&&row3[2]=='X')||(row1[0]=='X'&&row2[1]=='X'&&row3[2]=='X')||(row1[2]=='X'&&row2[1]=='X'&&row3[0]=='X'))&&(x_count>o_count))\n        {\n            printf(\"the first player won\");\n            return;\n        }\n        else if(((row1[0]=='X'&&row1[1]=='X'&&row1[2]=='X')||(row2[0]=='X'&&row2[1]=='X'&&row2[2]=='X')||(row3[0]=='X'&&row3[1]=='X'&&row3[2]=='X')||(row1[0]=='X'&&row2[1]=='X'&&row3[2]=='X')||(row1[2]=='X'&&row2[1]=='X'&&row3[0]=='X'))&&(o_count>=x_count))\n        {\n            printf(\"illegal\");\n            return;\n        }\n        else if(((row1[0]=='0'&&row1[1]=='0'&&row1[2]=='0')||(row2[0]=='0'&&row2[1]=='0'&&row2[2]=='0')||(row3[0]=='0'&&row3[1]=='0'&&row3[2]=='0')||(row1[0]=='0'&&row2[1]=='0'&&row3[2]=='0')||(row1[2]=='0'&&row2[1]=='0'&&row3[0]=='0'))&&(o_count>x_count))\n        {\n            printf(\"the second player won\");\n            return;\n        }\n        else if(((row1[0]=='0'&&row1[1]=='0'&&row1[2]=='0')||(row2[0]=='0'&&row2[1]=='0'&&row2[2]=='0')||(row3[0]=='0'&&row3[1]=='0'&&row3[2]=='0')||(row1[0]=='0'&&row2[1]=='0'&&row3[2]=='0')||(row1[2]=='0'&&row2[1]=='0'&&row3[0]=='0'))&&(x_count>=o_count))\n        {\n            printf(\"illegal\");\n            return;\n        }\n        else if(x_count==5&&o_count==4)\n        {\n            printf(\"draw\");\n            return;\n        }\n        else if(x_count-o_count=1)\n        {\n            printf(\"second\");\n            return;\n        }\n        else if(x_count==o_count)\n        {\n            printf(\"first\");\n            return;\n        }\n    }\n    \n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "cea73ad3af5f65f335193a46aaeffb2e", "src_uid": "892680e26369325fb00d15543a96192c", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nchar a[3][3], b[3][3];\nint win(char p[3][3], int n){\n  int ret=0;\n  for (int i=0; i<3; i++) {\n    int chk=1;\n    if (p[i][0]==0) continue;\n    for (int j=1; j<3; j++) if(p[i][0]!=p[i][j])  chk=0;\n    if (chk) ret=1;\n  }\n  int ret2=0, ret3=0;\n  char c='0';\n  if (n) c=0;\n  if (p[0][0]!=c && p[0][0]!=0 && p[0][0] == p[1][1] && p[0][0]==p[2][2]) ret2=1;\n  if (p[0][2]!=c p[0][2]!=0 && p[0][2] == p[1][1] && p[0][2]==p[2][0]) ret3=1;\n  return ( ret || ret2 || ret3);\n}\n\nint main(){\n\n  for (int i=0; i<3; i++) scanf(\"%s\", a[i]);\n\n  int p1=0, p2=0;\n  for (int i=0; i<3; i++){\n    for (int j=0; j<3; j++){\n      if (a[i][j]=='X') p1++;\n      else if (a[i][j]=='0') b[i][j]='0', p2++;\n    }\n  }\n\n  if (p2>p1) printf(\"illegal\\n\");\n  else if (win(a, 0) || win(b, 1)){\n    if (win(a, 0)){\n      if (p1<=p2) printf(\"illegal\\n\");\n      else printf(\"the first player won\\n\");\n    }\n    else{\n      if (p1>p2) printf(\"illegal\\n\");\n      else printf(\"the second player won\\n\");\n    }\n  }\n  else{\n    if (p1+p2==9) printf(\"draw\\n\");\n    else if (p1>p2) printf(\"second\\n\");\n    else printf(\"first\\n\");\n  }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e972a46280dbae7c93c00a43adde1e9c", "src_uid": "892680e26369325fb00d15543a96192c", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint a,b,c=0;\nscanf(\"%d %d\",&a,&b);\nwhile(a!=0)\n{\tc++;\n\ta=a-1;\n\tif(c%n==0)\n\t\tm=m+1;\n}\nprintf(\"%d\",c);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "76e75e9ad22b154a1b0c0bb46a5713ec", "src_uid": "a349094584d3fdc6b61e39bffe96dece", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n,b,c,a = 0;\n    scanf(\"%d %d\",&n,&b);\n    int sum;\n    sum = n;\n    while(true)\n    {\n        n = n/b;\n        sum += n;\n        n =  n + n%b;\n        if(n/b == 1 ){\n            sum ++;\n            break;\n        }\n        //if(n/b == 0)break;\n    }\n    printf(\"%d\\n\",sum);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3f1ec08fb932ee3ef6075c7496d5e71d", "src_uid": "a349094584d3fdc6b61e39bffe96dece", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\n//code forces- new year candles\nvoid main()\n{\n\tint a,b,c=0,d=0;\n\tclrscr();\n\tscanf(\"%d%d\",&a,&b);\n\tif(b==0||b==1)\n\t{\n\t}\n\telse\n\t{\n\t\twhile(a>0)\n\t\t{\n\t\t\tc=c+a;\n\t\t\ta=a+d;\n\t\t\td=a-(a/b)*b;\n\t\t\ta=a/b;\n\t\t}\n\t\tprintf(\"The candles used are %d\",c);\n\t}\n\tgetch();\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "38a6c3c31fe6c91a84cfa382b6c4c6a3", "src_uid": "a349094584d3fdc6b61e39bffe96dece", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n int a,b=0,c=0;\n    scanf(\"%d%d\",&a,&b);\n \n {\n    while(a!=0)\n    {   \n        a=a--;\n        c++;\n        b++;\n        if(b==5)\n        { c++;\n            b=0;\n          }\n\n    printf(\"%d\",c);\n\n }return 0; \n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "507ad74bc47c6f7bddb756026a05cab8", "src_uid": "a349094584d3fdc6b61e39bffe96dece", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    unsigned int a,b,n:\n    scanf(\"%u%u\",&a,&b);\n    if((a>=1)&&(a<=1000))\n    {\n      if((b>=2)&&(b<=1000))\n    {\n        if(b%2==0)\n        {\n            n=a+b;\n            printf(\"%d\",n);\n        }\n        else\n        {\n            n=a+b-1;\n            printf(\"%d\",n);\n        }\n    }\n    else\n    {\n        printf(\"b is not valid\");\n    }\n    else\n    {\n         printf(\"a is not valid\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cca26bc7e48d30b5ccde6891af580577", "src_uid": "a349094584d3fdc6b61e39bffe96dece", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int a,b;\n    scanf(\"%d %d\",&a,&b);\n    \n    while(true)\n    {\n        int k=1;\n        a = a - k;\n        if(a < 0)\n        {\n            printf(\"Vladik\");\n            break;\n        }\n        k++;\n        b = b - k;\n        if(b < 0)\n        {\n            printf(\"Valera\");\n            break;\n        }\n        k++;\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b1fbebd7a90a448cce69f015200cf6ed", "src_uid": "87e37a82be7e39e433060fd8cdb03270", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include<math.h>\n\nint main()\n{\n     long a,b;\n     scanf(\"%ld %ld\",&a,&b);\n     int ans=sqrt(a);\n     if(b>=k*k+k)\n     printf(\"Vladic\");\n     else\n     printf(\"Valera\");\n     return 0;\n     \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4110c3a707bff668de5a56250f38d888", "src_uid": "87e37a82be7e39e433060fd8cdb03270", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n \nint main()\n{\n    int a=0,b=0;\n    int flag = 0;\n    \n    scanf(\"%d%d\",&a,&b);\n    \n    while(1)\n    {\n        math1 = 1\n        a=a-math1;\n        if (a <= 0)\n         break;\n        flag = 1;\n        \n        math2 = 2;\n        b=b-math2;\n        if (b <= 0)\n         break;\n        \n        math1 = math1+2;\n        math2 = math2+2;\n    }\n    \n    if(flag == 1)\n     printf(\"Valera\");\n    else\n     printf(\"Vladik\");\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a1ec9c6eda86515bcc3907e855f117ce", "src_uid": "87e37a82be7e39e433060fd8cdb03270", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int vladik,valera,x=2,y=1;\n    char c[10];\n    scanf(\"%d %d\",&vladik,&valera);\n    while(x>0)\n    {\n        if(x%2==0)\n        vladik-y;\n        else\n        valera-y;\n        x++;\n        y++;\n        if(vladik==0)\n        {\n        c=\"Vladik\";\n        break;\n        }\n        else{\n        c=\"Valera\";\n        break;}\n    }\n    printf(\"%s\",c);\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9244cbe1204583d06c5565428df07e35", "src_uid": "87e37a82be7e39e433060fd8cdb03270", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int vladik,valera,x=2,y=1;\n    char c[10]=null;\n    scanf(\"%d %d\",&vladik,&valera);\n    while(x>0)\n    {\n        if(x%2==0)\n        vladik-y;\n        else\n        valera-y;\n        x++;\n        y++;\n        c=(vladik==0)? \"Vladik\":\"Valera\";\n        if(c!=null)\n        break;\n    }\n    printf(\"%s\",c);\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c76f1e48f063fa478a32c29051ba5d89", "src_uid": "87e37a82be7e39e433060fd8cdb03270", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#define max 1000000009\n#include<stdio.h>\nint main()\n{\n\tlong long int ans=0,wr,num,n,m,k,i,j;\n\tscanf(\"%lld %lld %lld\", &n, &m, &k);\n\tnum = n/k;\n\twr = n-m;\n\tif(wr < num)\n\t{\n\t\tfor(i=0; i<num-wr; i++)\n\t\t{\n\t\t\tans=(ans%max+k%max)%max;\n\t\t\tans =(ans%max*2)%max;\n\t\t}\n\t\tans = (ans%max + ((wr)*(k-1))%max)%max;\n\t\tif(ans<0)\n\t\t\tans = ans + max;\n\t\tans = (ans%max + (n - num*k)%max)%max;\n\t\tif(ans<0)\n\t\t\tans = ans + max;\n\t}\n\telse if(wr >= num)\n\t{\n\t\tans = (ans%max + ((k-1)*num)%max)%max;\n\t\tans = (ans%max + (n - num*k)%max)%max;\n\t\tans = (ans - (wr - num))%max;\n\t}\n\tif(ans < 0)\n\t\tans = ans+max;\n\tprintf(\"%lld\\n\", ans%max);\n}\t\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3ad273b4561a46e8cbea15124a9b9334", "src_uid": "9cc1aecd70ed54400821c290e2c8018e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define mod 1000000009\nlong long int power(long long int min)\n{\n\tif(min==0)\treturn 1;\n\tif(min==1)\treturn 2;\n\tif(min%2)\treturn (((power(min/2))%mod)*(power((min+1)/2))%mod)%mod;\n\telse\treturn (((power(min/2))%mod)*((power(min/2))%mod))%mod;\n}\nint main()\n{\n\tlong long int n,m,k;\n\tscanf(\"%lld%lld%lld\",&n,&m,&k);\n\tlong long int temp=m;\n\tlong long int min=0;\n\twhile(n)\n\t{\n\t\tif(n>m)\n\t\t{\n\t\t\tif(m>=k-1)\n\t\t\t{\n\t\t\t\tn=n-(k-1);\n\t\t\t\tm=m-(k-1);\n\t\t\t}\n\t\t\tn--;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tmin=n/k;\n\t\t\tbreak;\n\t\t}\n\t}\n//\tprintf(\"%lld\\n\",min);\n\tlong long int score;\n\tscore=((power(min+1))%mod-2)%mod;\n\tscore=(score*k)%mod;\n//\tprintf(\"%lld\\n\",score);\n//\tprintf(\"%lld\\n\",min);\n\tscore = (score+temp-((min*k)%mod))%mod;\n\tscore=(score+mod)%mod;\n\tprintf(\"%lld\\n\",score);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d25730402bc2f13f23eadf9bb2b273cf", "src_uid": "9cc1aecd70ed54400821c290e2c8018e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define MOD 1000000009\n\nint sqr(long long int x, int n)\n{\n\tif(n==0)\n\t\treturn 1;\n\telse if(n==1)\n\t\treturn x;\n\telse if(n%2==0)\n\t\treturn sqr( (x*x)%MOD, n/2 ) % MOD;\n\telse\n\t\treturn (x * sqr( (x*x)%MOD, (n-1)/2 )) % MOD;\n}\n\nint main()\n{\n\tint n, m, k;\n\tscanf(\"%d %d %d\", &n, &m, &k);\n\tint x, y, z;\n\tz = n%k;\n\ty = n/k;\n\tx = m - y*(k-1) - z;\n\ty -= x;\n\tlong long int ans;\n\tint i;\n\tans = sqr(2, x+1);\n\tans -= 2;\n\tk %= MOD;\n\tans *= k;\n\tans %= MOD;\n\tans += y*(k-1);\n\tans %= MOD;\n\tans += z;\n\tans %= MOD;\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4ca19f39d47ec02998a7e3100883de53", "src_uid": "9cc1aecd70ed54400821c290e2c8018e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define p 1000000009 \nlong long int powe(long long int,long long int);\nint main()\n{\n\tlong long int n,m,k,x,minscore;\n\tscanf(\"%lld %lld %lld\",&n,&m,&k);\n\tx=m-((k-1)*(n/k)+n%k);\n//\tprintf(\"%lld\\n\",x);\n\tminscore= (( ( powe(2,x+1)-2)*k)%p +m-x*k)%p;\n//\tprintf(\"%lld\\n\",powe(2,x));\n\tprintf(\"%lld\\n\",minscore);\n}\nlong long int powe(long long int m,long long int n)\n{\n\tif(n==0)\n\t{\n\t\treturn 1;\n\t}\n\tif(n==1)\n\t{\n\t\treturn m;\n\t}\n\tif(n%2==0)\n\t{\n\t\treturn(powe((m*m)%p,n/2)%p);\n\t}\n\telse\n\t{\n\t\treturn((powe((m*m)%p,n/2)*m)%p);\n\t}\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dd22a647f8f6bbca93d7420962aabc29", "src_uid": "9cc1aecd70ed54400821c290e2c8018e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#define NUM 1000000009\n\n\nint minx(int n, int m, int k)\n{\n  int q = n/k;\n  return m - q*(k-1) - n%k;\n\n}\n\nlong long int power(int n, int m)\n{\n  if(m == 0)\n    return 1;\n  else\n    {\n      if(m % 2 == 0)\n\treturn (power(n,m/2)*power(n,m/2)) % NUM;\n      else \n\treturn (power(n,m-1)*n) % NUM;\n    }\n\n}\n\nlong long int score(int x, int m, int k)\n{\n  return ((power(2,x+1)-2)*k + m -x*k) ;\n\n}\nint main()\n{\n  int n,m,k;\n  scanf(\"%i %i %i\",&n,&m,&k);\n  int x = minx(n,m,k); \n  long long int result = score(x,m,k);\n  printf(\"%lli\",result % NUM);\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "de3cc2c546976702b8c0d600472ca3fa", "src_uid": "9cc1aecd70ed54400821c290e2c8018e", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "}#include<stdio.h>\nint p[200];\nint main()\n{\n    int n,temp=0,t=0,i,m=0,c=0;\n    scanf(\"%d\",&n);\n    int arr[n];\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&arr[i]);\n        if(arr[i-1]+1==arr[i]&&i>0)\n            {\n                c=1;\n                t++;\n                if(i==n-1)\n                {\n                    p[m]=t+1;\n                    m++;\n                }\n            }\n        else\n        {\n            if(c==1){\n            p[m]=t+1;\n            t=0;\n            c=0;\n            m++;\n        }\n    }\n    }\n    if(n>1){\n    if(m>1)\n    {\n    for(i=0;i<m-1;i++)\n    {\n        temp=p[i]>p[i+1]?p[i]:p[i+1];\n        p[i+1]=temp;\n    }\n    printf(\"%d\",temp-2);\n    }\n    else if(m==1)\n    {\n    if(p[0]==n&&(arr[n-1]==1000||arr[0]==1))\n        printf(\"%d\",p[0]-1);\n    else\n    {if(p[0]>=2)\n        printf(\"%d\",p[0]-2);\n        else\n            printf(\"0\");\n    }\n    }\n    else\n        printf(\"0\");\n    }\n    else\n    printf(\"0\");\n    /*printf(\"%d%d\",p[0],m);*/\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8420b1c0983844de8bba5fc88b598393", "src_uid": "858b5e75e21c4cba6d08f3f66be0c198", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define maxn 102\n\nint max(int a, int b)\n{\n    int t;\n    if(a<=b)\n        t=b;\n    else t=a;\n    return t;\n}\n\nint main()\n{\n    int n, a[maxn], i, nodel=0, curstreak=1, longstreak=1, count=0;\n\n    scanf(\"%d\", &n);\n\n    for(i=1; i<=n; i++)\n    {\n        scanf(\"%d\", &a[i]);\n    }\n    if(1000-a[1]==n-1 || a[n]==n)\n        nodel=n-1;\n    else\n    {\n        for(i=1; i<=n; i++)\n        {\n            if(a[i+1]-(i+1)==a[i]-i)\n            curstreak++;\n            else\n                {\n                    longstreak = max(longstreak, curstreak);\n                    curstreak = 1;\n                }\n            if(a[1]==1&&a[2]=!a[1]+1)\n                nodel=max(longstreak, curstreak)-1;\n            else\n                nodel=max(longstreak, curstreak)-2;\n        }\n    }\n    \n    printf(\"%d\", nodel);\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "848df50fc88e5035a7c5e5d4f8e7f355", "src_uid": "858b5e75e21c4cba6d08f3f66be0c198", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n, x, y, t, c;\n    int a[101];\n    int s[100]={};\n    scanf(\"%d\", &n);\n    for(x=1;x<=n;x++)\n    {\n        scanf(\"%d\", &a[x]);\n    }\n    t=1;\n    a[0]=0;\n    a[n+1]=1001;\n    for(x=1;x<=n;x++)\n    {\n        if(a[x+1]==a[x]+1)\n        {\n            s[t]=s[t]+1;\n        }\n        else if(a[x+1]>a[x]+1)\n        {\n            t=t+1;\n        }\n    }\n    for(x=n;x>0;x--)\n    {\n        for(y=x+1;y<=n;y++)\n        {\n            if(s[x]<s[y])\n            {\n                c=s[x];\n                s[x]=s[y];\n                s[y]=c;\n            }\n        }\n    }\n    if(s[1]==0)\n    {\n        printf(\"0\")\n    }\n    else if(s[1]!=0)\n    {\n        printf(\"%d\", s[1]-1);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "75c6f757a9900eb8231968bf11dc7547", "src_uid": "858b5e75e21c4cba6d08f3f66be0c198", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\n\nint arr[1010];\n\nint main() {\n\tint m, n, i, j;\n\tscanf(\"%d\", &n);\n\tfor (i = 1; i <= n; i++) scanf(\"%d\", &arr[i]);\n\tint maxn = 0;\n\tint cur = 0;\n\tarr[0] = 0, arr[n + 1] = 1001;\n\tn++;\n\tcur = 1;\n\tfor (i = 1; i <= n; i++) {\n\t\tif (arr[i] == arr[i - 1] + 1) cur++;\n\t\telse {\n\t\t\tcur = 1;\n\t\t\tcontinue;\n\t\t}\n\t\tif (maxn < cur) maxn = cur;\n\t}\n\tmaxn -= 2;\n\tprintf(\"%d\\n\", std::max(0, maxn));\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "625c8ce0a4a636e1f929ed2258ba101f", "src_uid": "858b5e75e21c4cba6d08f3f66be0c198", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "\n#include<stdio.h>\nint main()\n{\n    int n,a[1005];\n    scanf(\"%d\",&n);\n    for(int i=0;i<n;i++)\n        scanf(\"%d\",&a[i+1]);\n    a[0]=0;\n    a[n+1]=1001;\n    int l=0;,f=0,max=0;\n    while(f<n+2)\n    {\n        l=f;\n        while(f<n+2 && a[f]-a[f+1]==-1)\n            f++;\n        f++;\n       \n        if(max < f-l)\n            max=f-l;\n    }\n    printf(\"%d\\n\",max-2);\n\n\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "60137fefed1773305aca500e21902e5a", "src_uid": "858b5e75e21c4cba6d08f3f66be0c198", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    double n;\n    scanf(\"%lf\"\uff0c&n);\n    printf(\"%d\",(int)sqrt(n));\n     return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "428f8b9c9df06d71695791fb219d4929", "src_uid": "c50b6af99ca7b9c35628b52774d6c32b", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio>\nint a[] = {0, 1, 1, 1, 2, 1, 2, 1, 5, 2, 2, 1, 5, 1, 2, 1, 14, 1, 5, 1, 5, 2, 2, 1, 15, 2, 2, 5, 4, 1, 4, 1, 51, 1, 2, 1, 14, 1, 2, 2, 14, 1, 6, 1, 4, 2, 2, 1, 52, 2, 5, 1, 5, 1, 15, 2, 13, 2, 2, 1, 13, 1, 2, 4, 267, 1, 4, 1, 5, 1, 4, 1, 50, 1, 2, 3, 4, 1, 6, 1, 52, 15, 2, 1, 15, 1, 2, 1, 12, 1, 10, 1, 4, 2};\nint n;\nint main() {\n\tscanf(\"%d\", &n);\n\tprintf(\"%d\\n\", a[n]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7ea6598e5af2a4395c3f2d5400bc61ce", "src_uid": "c50b6af99ca7b9c35628b52774d6c32b", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include<stdio>\nint n,a[105]={0,1,1,1,2,1,2,1,5,2,2,1,5,1,2,1,14,1,5,1,5,2,2,1,15,2,2,5,4,1,4,1,51,1,2,1,14,1,2,2,14,1,6,1,4,2,2,1,52,2,5,1,5,1,15,2,13,2,2,1,13,1,2,4,267,1,4,1,5,1,4,1,50,1,2,3,4,1,6,1,52,15,2,1,15,1,2,1,12,1,10,1,4,2};//\u5e8f\u5217\nint main()\n{\n    scanf(\"%d\",&n);\n    printf(\"%d\",a[n]);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8b0e1e787624cf1fbe7d86d485b71c98", "src_uid": "c50b6af99ca7b9c35628b52774d6c32b", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include<cstdio>\nconst int a[]={0, 1, 1, 1, 2, 1, 2, 1, 5, 2, 2, 1, 5, 1, 2, 1, 14, 1, 5, 1, 5, 2, 2, 1, 15, 2, 2, 5, 4, 1, 4, 1, 51, 1, 2, 1, 14, 1, 2, 2, 14, 1, 6, 1, 4, 2, 2, 1, 52, 2, 5, 1, 5, 1, 15, 2, 13, 2, 2, 1, 13, 1, 2, 4, 267, 1, 4, 1, 5, 1, 4, 1, 50, 1, 2, 3, 4, 1, 6, 1, 52, 15, 2, 1, 15, 1, 2, 1, 12, 1, 10, 1, 4, 2};//\u5e38\u91cf\u6570\u7ec4\u53ef\u4ee5\u81ea\u52a8\u6d4b\u7b97\u5927\u5c0f\nint main(){\n    short x;\n    scanf(\"%d\", &x);\n    printf(\"%d\", a[x]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "05ed980834f91113ee7524f46e9ae884", "src_uid": "c50b6af99ca7b9c35628b52774d6c32b", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n    int a[100]={0, 1, 1, 1, 2, 1, 2, 1, 5, 2, 2, 1, 5, \n    1, 2, 1, 14, 1, 5, 1, 5, 2, 2, 1, 15, 2, 2, 5, 4, 1\n    , 4, 1, 51, 1, 2\n    , 1, 14, 1, 2, 2, 14, 1, 6, 1, 4, 2, 2, 1, 52, 2\n    , 5, 1, 5, 1, 15, 2, 13, 2, 2, 1, 13, 1, 2, 4, 267,\n    1, 4, 1, 5, 1, 4, 1, 50, 1, 2, 3, 4, 1, 6, 1, 52, 15,\n    2, 1, 15, 1, 2, 1, 12, 1, 10, 1, 4, 2}\n    int n;\n    scanf(\"%d\",&n);\n    printf(\"%d\",a[n]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0a47b589f145b681de4069c5b5586fca", "src_uid": "c50b6af99ca7b9c35628b52774d6c32b", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdint.h>\nint main(void) {\n    int64_t n, m;\n    scanf(\"%I64d%I64d\", &n, &m);\n    if(m > n) {\n        printf(\"%I64d\", n);\n        return 0;\n    }\n    n -= m;\n    for(int64_t l = 0, r = 2e9; l < r; (l + r) / 2 >= (l + r) * (l + r + 2) / 8 ? r = (l + r) / 2 : l = (l + r) / 2 + 1);\n    printf(\"%I64d\", l + m);\n    return 0; \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2e3ce18993bbf0d66b1d31158826b4cd", "src_uid": "3b585ea852ffc41034ef6804b6aebbd8", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<algorithm>\n#define MAX 2000000000\n//1000000000000000000\nusing namespace std;\n\n\nint main()\n{\n\tlong long N, M, i, st = 1, ed = MAX,k =0; \n\tscanf(\"%lld%lld\", &N, &M);\n\n\tif (M > N) M = N;\n\t\n\tlong long ans =0, X= (N-M)*2;\n\n\tfor (;;) {\n\t\tif (st >= ed) break;\n\t\ti = (st + ed) / 2;\n\n\t\tif (i*i + i >= X) {\n\t\t\ted = i;\n\t\t\tk = i;\n\t\t}\n\t\telse {\n\t\t\tst = i + 1;\n\t\t}\n\t}\n\n\tans = M + k;\n\n\tprintf(\"%lld\\n\", ans);\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ff786beceea22c89c966bd43e1908e35", "src_uid": "3b585ea852ffc41034ef6804b6aebbd8", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdint.h>\nint main(void) {\n    int64_t n, m;\n    scanf(\"%I64d%I64d\", &n, &m);\n    if(m > n) {\n        printf(\"%I64d\", n);\n        return 0;\n    }\n    n -= m;\n    for(int64_t l = 0, r = 2e9; l < r; (l + r) / 2 >= (l + r) * (l + r + 2) / 8 : r = (l + r) / 2 : l = (l + r) / 2 + 1);\n    printf(\"%I64d\", l + m);\n    return 0; \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f41a30890e5528dd51a24cb35635fc56", "src_uid": "3b585ea852ffc41034ef6804b6aebbd8", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    long long a,b;\n    while (~scanf (\"%I64d%I64d\",&a,&b)){\n        long long sum = a;\n        long long i;\n        for (i=b;;i++){\n            sum=(sum+=b)>a?a:sum;\n            if ((sum-=i)<=0) break;\n        }\n        printf(\"%I64d\\n\",i);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f9bcc0b019e401d35fd5f7961c7846f3", "src_uid": "3b585ea852ffc41034ef6804b6aebbd8", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#ifdef TEST\n#include <time.h>\n#endif\n\nint main() {\n    long long n, m;\n    scanf(\"%I64d %I64d\", &n, &m);\n    if (m >= n)\n        goto LOL_KEK;\n#ifdef TEST\n    clock_t cl = clock();\n#endif\n    long long i = m + 1;\n    n -= i;\n    while (n > 0)\n        n += (m - (++i));\n    printf(\"%I64d\\n\", i);\n#ifdef TEST\n    printf(\"%lf\\n\", (double)(clock() - cl) / CLOCKS_PER_SEC);\n#endif\n    return 0;\nLOL_KEK:\n    printf(\"%I64d\\n\", n);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "30e79320af459f81ff34697aaf56848a", "src_uid": "3b585ea852ffc41034ef6804b6aebbd8", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n  int s[3];\n  int i=0,n=0,t=0;\n  for(;i<3;i++)\n  {scanf(\"%i\",&s[i]);\n   n=n+s[i];}\n   i=0;\n  while(n>0)\n  {\n   if(s[i]>2)\n   {s[i]=s[i]-2;\n    n=n-2;}\n   else\n   {s[i]=s[i]-s[i];\n    n=n-s[i];}\n    t++;\n    i++;\n    i=i%3;\n  }\n  prinf(\"%i\",t+30);\n  return 0;\n}\n   \n     ", "lang_cluster": "C", "compilation_error": true, "code_uid": "fc5d8d0a31994d658fe7117b211f06d1", "src_uid": "a45daac108076102da54e07e1e2a37d7", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n  int s[3];\n  int i=o,n=0,t=0;\n  for(;i<3;i++)\n  {scanf(\"%i\",&s[i]);\n   n=n+s[i];}\n   i=0;\n  while(n>0)\n  {\n   if(s[i]>2)\n   {s[i]=s[i]-2;\n    n=n-2;}\n   else\n   {s[i]=s[i]-s[i];\n    n=n-s[i];}\n    t++;\n    i++;\n    i=i%3;\n  }\n  prinf(\"%i\",t+30);\n  return 0;\n}\n   \n     ", "lang_cluster": "C", "compilation_error": true, "code_uid": "d7aed14d2ccf22ec9a5bef11b50550f8", "src_uid": "a45daac108076102da54e07e1e2a37d7", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n    int a,b,c,p,q,r,i=0,j=0,k=0,t;\n    scanf(\"%d%d%d\",&a,&b,&c);\n    \n    \n    \n    if(a >= b && a >= c)\n    {\n        for(p=a;p >2;p=p-2)\n        j++;\n        t=30 + (j*3);\n    }\n    if((b >= c && b >= a) || ((a-b)==1 && b>2))\n    {\n        for(p=b;p >2;p=p-2)\n        k++;\n        t=31 + (k*3);\n    }\n    if((c >= a && c >= b) || ((a-c)==1 && c>2) || ((b-c)==1 && c>2))\n    {\n        for(p=c;p >2;p=p-2)\n        i++;\n        t=32 + (i*3);\n    }\n    printf(\"%d\",t);\n}\n    \n        for(b=b;b!=2 || b!=1;b=b-2)\n        {\n                    \n            k++;\n        \n        }\n        t=31+k*2;\n    }\n    if((c>=a && c>=b) ||((a-c)==1 && c>2) || ((b-c)==1 && c>2))\n    {\n        for(c=c;c!=2 || c!=1;c=c-2)\n        {\n            l++;\n    \n        }\n        t=32+l*2;\n    }\n    printf(\"%d\",t);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1e670c3b500bea81e3eee595681e0ca7", "src_uid": "a45daac108076102da54e07e1e2a37d7", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n  int s[3],i=0,n=0,t=0;\n  for(;i<3;i++)\n  {scanf(\"%i\",&s[i]);n=n+s[i];}\n  i=0;\n  while(n>0)\n  {    if(s[i]>2)\n    { s[i]=s[i]-2;\n       n=n-2;\n     }\n     else\n     {s[i]=s[i]-s[i];\n     n=n-s[i];}\n     i=i+1;\n     i=i%3;\n t++;\n   }\n  printf(\"%i\",t+30);\n  return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b689b6dc6146e49e3fbbdf0dcb5f8445", "src_uid": "a45daac108076102da54e07e1e2a37d7", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n  int s[3],i=0,n=0,t=0;\n  for(;i<3;i++)\n  {scanf(\"%i\",&s[i]);n=n+s[i];}\n  i=0;\n  while(n>0)\n  {    if(s[i]>=2)\n    { s[i]=s[i]-2;\n       n=n-2;\n     }\n     else\n     {s[i]=s[i]-s[i];\n     n=n-s[i];}\n     i=i+1;\n     i=i%3;\n t++;\n   }\n  printf(\"%i\",t+30);\n  return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "fbbe5baab6d8d531e578c811df676dcc", "src_uid": "a45daac108076102da54e07e1e2a37d7", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nvoid quicksort(double number[],long long int first,long long int last,double a[],double c[]){\n   long long int i, j, pivot;\n   double temp;\n\n   if(first<last){\n      pivot=first;\n      i=first;\n      j=last;\n\n      while(i<j){\n         while(number[i]<=number[pivot]&&i<last)\n            i++;\n         while(number[j]>number[pivot])\n            j--;\n         if(i<j){\n            temp=number[i];\n            number[i]=number[j];\n            number[j]=temp;\n\t\t\ttemp=a[i];\n            a[i]=a[j];\n            a[j]=temp;\n\t\t\ttemp=c[i];\n            c[i]=c[j];\n            c[j]=temp;\n         }\n      }\n\n      temp=number[pivot];\n      number[pivot]=number[j];\n      number[j]=temp;\n\t  temp=a[pivot];\n      a[pivot]=a[j];\n      a[j]=temp;\n\t  temp=c[pivot];\n      c[pivot]=c[j];\n      c[j]=temp;\n      quicksort(number,first,j-1,a,c);\n      quicksort(number,j+1,last,a,c);\n\n   }\n}\ndouble power(long long int a,long long int b){\n\tlong long int i,p=1;\n\tfor(i=0;i<b;i++)\n\t\tp=p*a;\n\treturn p;\n}\nint main(){\n\tlong long int n,i,l,s=0,min;\n\tscanf(\"%lld %lld\",&n,&l);\n\tdouble c[n],a[n],d[n];\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%lf\",&c[i]);\n\t\ta[i]=power(2,i);\n\t\td[i]=c[i]/a[i];\n\t}\n\tquicksort(d,0,n-1,a,c);\n\tmin= (l/((long long int)a[0]) + 1)*((long long int)c[0]);\n\tfor(i=0;l!=0;i++){\n\t\tif(min> s + (l/((long long int)a[i]) + 1)*((long long int)c[i]))\n\t\t\tmin= s+(l/((long long int)a[i]) + 1)*((long long int)c[i]); \n\t\ts=s+(l/((long long int)a[i]))*((long long int)c[i]);\n\t\tl=l%((long long int)a[i]);\n\t}\n\tif(min>s)\n\t\tprintf(\"%lld\",s);\n\telse\n\t\tprintf(\"%lld\",min);\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a5cf3bd44c6c7511cfe0ab64fc477c18", "src_uid": "04ca137d0383c03944e3ce1c502c635b", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(int argc, char const *argv[]) {\n\tint n, L;\n\tscanf(\"%d %d\", &n, &L);\n\n\tint costs[n + 1], c, last = 0;\n\tint i;\n\n\tscanf(\"\\n%d\", &c);\n\tlast = (costs[0] = c) << 1;\n\n\tfor(i = 1; i < n; i++) {\n\t\tscanf(\" %d\", &c);\n\t\tlast = (costs[i] = c < last ? c : last) << 1;\n\t}\n\tcosts[n] = last;\n\n\tlast >>= 1;\n\tfor(i = n - 2; i >= 0; i--) {\n\t\tif(costs[i] > last)\n\t\t\tcosts[i] = last;\n\t\telse\n\t\t\tlast = costs[i];\n\t}\n\n\tlong long sum = 0;\n\tfor(i = 0; L && i < n;) {\n\t\tif(L & 1)\n\t\t\tsum += costs[i];\n\t\tif(costs[++i] < sum)\n\t\t\tsum = costs[i];\n\t\tL >>= 1;\n\t}\n\n\tsum += (long long)costs[n] * L;\n\n\tprintf(\"%lld\\n\", sum);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "303d66c5f49bf8241374f3c636124e5a", "src_uid": "04ca137d0383c03944e3ce1c502c635b", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n__int64 s[100];\nint b[100];\nint main()\n{\n\tint n;\n\t__int64 l,ans,c,d;\n\tint i,j,k;\n\tscanf(\"%d%I64d\",&n,&l);\n\tb[0]=l%2;\n\t//printf(\"%d\",b[0]);\n\tfor(i=1;l/2!=0;i++)\n\t{\n\t\tl=l/2;\n\t\tb[i]=l%2;\n\t\t//printf(\"%d\",b[i]);\n\t}\n\tfor(j=0;j<n;j++)\n\tscanf(\"%I64d\",&s[j]);\n\tif(i<n)\n\ti=n;\t\t\t\t\n\tfor(j=1;j<32;j++)\n\t{\n\t\t\n\t\tif(s[j]==0||s[j]>=2*s[j-1])\n\t\ts[j]=2*s[j-1];\n\t //printf(\"%dj%I64d\\n\",j,s[j]);\n\t}\n\tk=0;\n\tc=s[i-1]+100;\n\tans=0;\n\t//printf(\"%d\\n\",i);\n\tfor(j=0;j<i&&k==0;j++)\n\t{\n\t\tif(ans>s[j])\n\t\tans=s[j];\n\t\tans=ans+s[j]*b[j];\n\t}\t\n\tprintf(\"%I64d\\n\",ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7b3bfaf20e0dfeacdc3f45063f8ababc", "src_uid": "04ca137d0383c03944e3ce1c502c635b", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\ntypedef long long int lld;\nint power_2(int a){\n\tint sum=1;\n\tfor (int i = 0; i < a; ++i)\n\t\tsum*=2;\n\treturn sum;\n}\nint cmpfunc(const void *a,const void *b){\n\tlld diff=(*((lld *)a+2))-(*((lld *)b+2));\n\t// printf(\"%lld - %lld is %lld\\n\",(*((lld *)a)),(*((lld *)b)),diff);\n\tif (diff>0){\n\t\t// printf(\"change\\n\");\n\t\treturn 1;\n\t}\n\t// printf(\"NO change\\n\");\n\treturn -1;\n}\nlld get_price(lld price[30][3],int N,int L,int nowN,lld total){\t\n\t// printf(\"in,%d,%lld,%d\\n\",nowN,total,L);\n\tif (L==0)\n\t\treturn total;\n\tif (price[nowN][1]<L){\n\t\tint num_to_buy=L/price[nowN][1];\n\t\treturn get_price(price,N,L-price[nowN][1]*num_to_buy,nowN,total+price[nowN][0]*num_to_buy);\n\t}\n\tif (nowN==N-1){//last\n\t\treturn total+price[nowN][0];\n\t}\n\tlld a,b;\n\ta=total+price[nowN][0];\n\tb=get_price(price,N,L,nowN+1,total);\n\treturn (a>b?b:a);\n}\n\nint main(int argc, char const *argv[])\n{\n\tint N,L;\n\tscanf(\"%d%d\",&N,&L);\n\tlld price[30][3];//0 price 1 litter 2 is cp\n\tfor (int i = 0; i < N; ++i)\n\t{\n\t\tscanf(\"%lld\",&price[i][0]);\n\t\tprice[i][1]=power_2(i);\n\t\tprice[i][2]=price[i][0]<<(30-i);\n\t\t// printf(\"%lld\\n\",price[i][2] );\n\t}//store\n\tqsort(price,N,3*sizeof(lld),cmpfunc);\n\t// for (int i = 0; i < N; ++i)\n\t\t// printf(\"%lld,%lld,%lld\\n\",price[i][0],price[i][1],price[i][2] );\n\tprintf(\"%lld\",get_price(price,N,L,0,0));\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4f4ea12b700d79f21274a0d32344fe3c", "src_uid": "04ca137d0383c03944e3ce1c502c635b", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    while(1)\n    {\n        int n,L;\n        scanf(\"%d %d\",&n,&L);\n        float cost[n][3],div=1;\n        int i,j;\n        for(i=0;i<n;i++)\n        {\n            cost[i][2]=div;\n            scanf(\"%f\",&cost[i][0]);\n            cost[i][1]=cost[i][0]/cost[i][2];\n            div*=2;\n        }\n        int sort[n][2];\n        float current=0;\n        for(i=0;i<n;i++)\n        {\n            float min=1100000000;\n            int index;\n            for(j=0;j<n;j++)\n            {\n                if(cost[j][1]<min && cost[j][1]>current)\n                {\n                    index=j;\n                    min=cost[j][1];\n                }\n            }\n            sort[i][0]=cost[index][0];\n            sort[i][1]=cost[index][2];\n            current=cost[index][1];\n            cost[index][1]=1100000000;\n        }\n        /*for(i=0;i<n;i++)\n        {\n            for(j=0;j<2;j++)\n            {\n                printf(\"%d \",sort[i][j]);\n            }\n            printf(\"\\n\");\n        }*/\n        long long int finish[n];\n        long long int notPurchased=L;\n        long long int pay=0;\n        for(i=0;i<n;i++)\n        {\n            pay+=notPurchased/(long long int)sort[i][1]*(long long int)sort[i][0];\n            notPurchased=notPurchased%(long long int)sort[i][1];\n            if(notPurchased>0)\n            {\n                finish[i]=pay+(long long int)sort[i][0];\n            }\n            else\n            {\n                finish[i]=pay;\n            }\n            //printf(\"%lld\\n\",finish[i]);\n        }\n        long long int min=finish[0];\n        for(i=0;i<n;i++)\n        {\n            if(finish[i]<min)\n                min=finish[i];\n        }\n        printf(\"\\n%I64d\\n\",min);\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dc4aacc3f9b6cadf2ce2475e5950d529", "src_uid": "04ca137d0383c03944e3ce1c502c635b", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\nchar arr[500]\nint main(void)\n{\n    arr={'0'};\n    scanf(\"%s\",arr);\n    int a=0,b=0,c=0,d=0;\n    for(int i=0;;i++)\n    {\n        if(c==0)\n        {\n            if(arr[i]!='+')\n            a++;\n            else\n            c=1;\n        }\n        else if(c==1)\n        {\n            if(arr[i]!='=')\n            b++;\n            else\n            c=2;\n        }\n        else\n        {\n            if(arr[i]!='0')\n            d++;\n            else\n            break;\n        }\n    }\n    if(((a+b)-d)==2)\n    {\n        a--;\n        d++;\n    }\n    else if(((a+b)-d)==-2)\n    {\n        a++;\n        d--;\n    }\n    else\n    {\n        a=-1;\n    }\n    \n    if(a==-1)\n    printf(\"Impossible\");\n    else\n    {\n        for(int j=1;j<=a;j++)\n        printf(\"|\");\n        printf(\"+\");\n        for(int j=1;j<=b;j++)\n        printf(\"|\");\n        printf(\"=\");\n        for(int j=1;j<=d;j++)\n        printf(\"|\");\n    }\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0ff0751b73dfb296dd4305d03c708d41", "src_uid": "ee0aaa7acf127e9f3a9edafc58f4e2d6", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nvoid display(long long int ,long long int ,long long int );\nint main(){\n    long long int a,b,c;\n    int fp,fe;\n    fp=fe=a=b=c=0;\n    while(1){\n        char ch;\n        scanf(\"%c\",&ch);\n\n        if(ch=='+') fp=1;\n        else if(ch=='=') fe=1;\n        else if(ch=='|')\n        {\n            if(fp && fe) c++;\n            else if(fp) b++;\n            else a++;\n        }\n        else if(ch=='\\n') break;\n    }\n    if(fabs(a+b-c)!=2 && a+b!=c){\n        printf(\"Impossible\");\n    }\n    else if(a+b-c==0){\n        display(a,b,c);\n\n    }\n    else {\n        if(a+b>c){\n            if(a!=1)\n            display(a-1,b,c+1);\n            else \n            display(a,b-1,c);\n\n        else display(a+1,b,c-1);\n        \n    }\n    return 0;\n}\nvoid display(long long int a,long long int b,long long int c){\n    while(a+b+c+2){\n        if(a>0){\n            printf(\"|\");\n            a--;\n\n        }\n        else if(a==0){\n            printf(\"+\");    \n            a--;\n        }\n        else if(b>0){\n            printf(\"|\");\n            b--;\n        }\n        else if(b==0){\n            printf(\"=\");\n            b--;\n        }\n        else if(c){\n            printf(\"|\");\n            c--;\n        }\n        \n    }\n    printf(\"\\n\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dc0e92482ff50302b420fbc6c834318f", "src_uid": "ee0aaa7acf127e9f3a9edafc58f4e2d6", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\nchar arr[500];\nint main(void)\n{\n    arr={'0'};\n    scanf(\"%s\",arr);\n    int a=0,b=0,c=0,d=0;\n    for(int i=0;;i++)\n    {\n        if(c==0)\n        {\n            if(arr[i]!='+')\n            a++;\n            else\n            c=1;\n        }\n        else if(c==1)\n        {\n            if(arr[i]!='=')\n            b++;\n            else\n            c=2;\n        }\n        else\n        {\n            if(arr[i]!='0')\n            d++;\n            else\n            break;\n        }\n    }\n    if(((a+b)-d)==2)\n    {\n        a--;\n        d++;\n    }\n    else if(((a+b)-d)==-2)\n    {\n        a++;\n        d--;\n    }\n    else\n    {\n        a=-1;\n    }\n    \n    if(a==-1)\n    printf(\"Impossible\");\n    else\n    {\n        for(int j=1;j<=a;j++)\n        printf(\"|\");\n        printf(\"+\");\n        for(int j=1;j<=b;j++)\n        printf(\"|\");\n        printf(\"=\");\n        for(int j=1;j<=d;j++)\n        printf(\"|\");\n    }\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8f83b98db49418cdc10f81ee873e012e", "src_uid": "ee0aaa7acf127e9f3a9edafc58f4e2d6", "difficulty": null}
{"lang": "GNU C11", "source_code": "void print_sticks(int number) {\n    for(int i=0;i<number;i++) {\n        printf(\"|\");\n    }\n\n}\n\n\nint main() {\n\n    int a=0,b=0,c=0;\n\n    char temp;\n\n    int plus_occured = 0;\n    int equals_occured = 0;\n\n    while(1) {\n        scanf(\"%c\",&temp);\n        if(temp=='|') {\n            if(!plus_occured) {\n                a++;\n            } else {\n                if(!equals_occured) {\n                    b++;\n                } else {\n                    c++;\n                }\n            }\n        } else if(temp=='+') {\n            plus_occured = 1;\n        } else if(temp=='=') {\n            equals_occured = 1;\n        } else {\n            break;\n        }\n    }\n\n    int difference = a+b-c;\n\n    if(difference==-2&&c>1) {\n        print_sticks(a+1);\n        printf(\"+\");\n        print_sticks(b);\n        printf(\"=\");\n        print_sticks(c-1);\n    } else if(difference==0) {\n        print_sticks(a);\n        printf(\"+\");\n        print_sticks(b);\n        printf(\"=\");\n        print_sticks(c);\n    } else if(difference==2&&a>1)) {\n        print_sticks(a-1);\n        printf(\"+\");\n        print_sticks(b);\n        printf(\"=\");\n        print_sticks(c+1);\n    } else if(difference==2&&b>1)) {\n        print_sticks(a);\n        printf(\"+\");\n        print_sticks(b-1);\n        printf(\"=\");\n        print_sticks(c+1);\n    }else {\n        printf(\"Impossible\");\n    }\n\n    \n\n\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8567e6522bc3236b36909b6a166cff8b", "src_uid": "ee0aaa7acf127e9f3a9edafc58f4e2d6", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n                  int i=0,l=0,r=0,s=0,k=0;\n                  char c[120];\n                  scanf(\"%s\",&c);\n                  printf(\"\\n\");\n                  for(i=0;;i++)\n                  {\n                                    if(c[i]=='+'){break;}\n                                    l++;\n                                    \n                  }\n                  for(i=l+1;;i++)\n                  {\n                                    if(c[i]=='='){break;}\n                                    r++;\n                  }\n                  s=strlen(c)-l-r-2;\n                  if(l+r==s){printf(\"%s\",c);}\n                  else{\n                                    if((l+1)+r==(s-1)){ l=l+1;s=s-1;k=1;\n                                    break; }\n                                    else if((l-1)+r==(s+1)){ l=l-1;s=s+1;k=1;\n                                    break; }\n                                    else if(l+(r+1)==(s-1)){ r=r+1;s=s-1;k=1;\n                                    break; }\n                                    else if(l+(r-1)==(s+1)){ r=r-1;s=s+1;k=1;\n                                    break; }\n                  \n                  }\n                  if(k=1){\n                                    for(i=0;i<l;i++){printf(\"|\");}\n                                    printf(\"+\");\n                                    for(i=l+1;i<(l+r+1);i++){printf(\"|\");}\n                                    printf(\"=\");\n                                    for(i=(l+r+2);i<strlen(c);i++){printf(\"|\");}\n                  }\n                  else{printf(\"impossible\");}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5e76f85bfc25a13a70cd4d00e582352d", "src_uid": "ee0aaa7acf127e9f3a9edafc58f4e2d6", "difficulty": null}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int a,b,c,s,q,d,p;\n    scanf(\"%d%d%d%d\",&a,&b,&c,&d);\n    s=(b+d-1)/d;\n    p=c/a;\n    q=(s+(a-1))/(a);\n    if(p>=q)\n    s=q;\n    else\n    {\n      s=s-(p*(a-1));\n      q=s-p;\n      if(q>c%a+1)\n        s=s-c%a;\n\n    }\n      printf(\"%d\",s);\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ebc82caf001c7743ddca472a6c4f88ef", "src_uid": "7cff20b1c63a694baca69bdf4bdb2652", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n\nint main()\n{\n      int k, a, b, v, secRequired, ans = 0, temp;\n      scanf(\"%d%d%d%d\", &k, &a, &b, &v);\n     // secRequired = ceil(1.0*a/v);\n      while(a>=0)\n      {\n            temp = k-1;\n            ans++;\n            a-=v;\n\n            while(temp>0 && b>0)\n            {\n                  a-=v;\n                  temp--;\n                  b--;\n            }\n      }\n      printf(\"%d\", ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8d86599e7bd1b24866a3cd615fec6ccb", "src_uid": "7cff20b1c63a694baca69bdf4bdb2652", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\nint main()\n{\n    int k,a,b,v;\n    scanf(\"%d %d %d %d\",&k,&a,&b,&v);\n    int x=0;\n    while(a>0)\n    {\n       if(k>b)\n       {\n         a=a-(v*(b+1));\n         b=0;\n       }\n       else\n       {\n               a=a-(k*v);\n               b=b-(k-1);\n       }\n       x++; \n    }\n    printf(\"%d\\n\",x);\n    getch();\n    return 0;\n}             ", "lang_cluster": "C", "compilation_error": false, "code_uid": "9302ab9cec651faaaef9a9ea085c9b16", "src_uid": "7cff20b1c63a694baca69bdf4bdb2652", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int k,a,b,v,s=0,e=0,m=0,l=0,h=0,i;\n    scanf(\"%d %d %d %d\",&k,&a,&b,&v);\n    if(b+1>k&&a>0)\n    {\n        l=b/(k-1);\n        h=b%(k-1);\n        for(i=1; i<=l; i++)\n            if(a-(i*v*k)>=k*v&&a-(i+1)*v*k<k*v||a[i]-(i*v*k<=0)\n            {\n                l=i+1;\n                break;\n            }\n        a-=l*v*k;\n        m+=l;\n        if(h>0&&a>0)\n        {\n            a-=(h+1)*v;\n            m++;\n        }\n    }\n    else if(b+1<k&&a>0)\n    {\n        a-=(b+1)*v;\n        m++;\n    }\n    if(a>0)\n    {\n        e=a%v;\n        s=a/v;\n        m+=s;\n    }\n    if(e>0)\n        m++;\n    printf(\"%d\\n\",m);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8742b400589cab4fc728cc86651ae46b", "src_uid": "7cff20b1c63a694baca69bdf4bdb2652", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "/* https://codeforces.com/contest/402/submission/26668054 (Dukkha) */\n#include <stdio.h>\n\u00a0\nint main() {\n\tint k, a, b, v, n, x, r, m, ans;\n\u00a0\n\tscanf(\"%d%d%d%d\", &k, &a, &b, &v);\n\tn = (a + v - 1) / v;\n\tx = b / (k - 1);\n\tr = b % (k - 1);\n\tm = x * k + r + 1;\n\tif (n <= x * k)\n\t\tans = (n + k - 1) / k;\n\telse if (n <= m)\n\t\tans = x + 1;\n\telse\n\t\tans = x + (r > 0 ? 1 + n - m : n - x * k);\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9efaeb8a6c4a7dd4a5b7d5f9dbc95f04", "src_uid": "7cff20b1c63a694baca69bdf4bdb2652", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint flag=0;\nint check3(int b[],int j,int n,int val)\n{\n\tint i,count=0;\n\tfor(i=j+2;i<=n-1;i++)\n\t{\n\t\tif(b[i]!=val)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t\telse\n\t\t\tcount++;\n\t}\n\t//printf(\"count: %d\\n\",count );\n\treturn count+3;\n}\nint finalcheck(int b[],int n,int temp[])\n{\n\t//printf(\"n: %d\\n\",n );\n\t\n\tint j=0,c=1,k,i,count=0;\n\tflag=0;\n\t/*printf(\"ARRAY TEMP INITIAL\\n\");\n\tfor(i=0;i<n;i++)\n\t\tprintf(\"%d \",temp[i] );\n\tprintf(\"\\n\");*/\n\twhile(j!=n-1)\n\t{\n\t\tif(b[j]==b[j+1])\n\t\t{\n\t\t\tc++;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tc=1;\t\n\t\t}\n\t\tif(c==3)\n\t\t{\n\t\t\tk=check3(b,j,n,b[j]);\n\t\t\t//printf(\"k: %d\\n\",k );\n\t\t\tflag=1;\n\t\t\tbreak;\n\t\t}\n\t\tj++;\n\t}\n\t//printf(\"j: %d\\n\",j );\n\ti=0;\n\twhile(i!=n && i<=n)\n\t{\n\t\t//if(i+k==n)\n\t\t//\tbreak;\n\t\tif(k>=3 && i==j-1)\n\t\t{\n\t\t\ttemp[count++]=b[i+k];\n\t\t\ti+=k;\n\t\t}\n\t\telse\n\t\t{\n\t\t\t//printf(\"count: %d\\n\",count );\n\t\t\ttemp[count++]=b[i];\n\t\t}\n\t\ti++;\n\t}\n\t/*printf(\"ARRAY TEMP AFTER\\n\");\n\tfor(i=0;i<n-k;i++)\n\t\tprintf(\"%d \",temp[i] );\n\tprintf(\"\\n\");*/\n\tif(flag==0 || k==n)\n\t\treturn n-k;\n\telse\n\t\tfinalcheck(temp,n-k,temp);\n}\n\nint remove2(int arr[],int b[],int i,int n)\n{\n\tint j,count=0;\n\tfor(j=0;j<n;j++)\n\t{\n\t\tif(j==i)\n\t\t{\n\t\t\tb[count++]=arr[j+2];\n\t\t\tj+=2;\n\t\t}\n\t\telse\n\t\t\tb[count++]=arr[j];\n\t}\n\treturn n-2;\n}\nint main()\n{\n\n\tint n,arr[105],i,k,x,b[105]={0},cnt,j,temp[105]={0},ans,min=2000;\n\n\tscanf(\"%d %d %d\",&n,&k,&x);\n\n\tfor(i=0;i<n;i++)\n\t\tscanf(\"%d\",&arr[i]);\n\tif(n==10 && k==2 && x==1)\n\t{\n\t\tif(arr[0]==2 && arr[1]==1 && arr[2]==2 && arr[3]==2 && arr[4]==1 && arr[5]==2 && arr[6]==2 && arr[7]==1 && arr[8]==1 && arr[9]==2)\n\t\t\tprintf(\"5\\n\");\n\t}\n\telse if(n==1)\n\t\tprintf(\"0\\n\");\n\telse if(n==2)\n\t{\n\t\tif(arr[0]==arr[1] && arr[0]==x)\n\t\t\tprintf(\"2\\n\");\n\t\telse\n\t\t\tprintf(\"0\\n\");\n\t}\n\telse{\n\t\tfor(i=0;i<n-1;i++)\n\t\t{\n\t\t\tif(arr[i]==arr[i+1] && arr[i]==x)\n\t\t\t{\n\t\t\t\tcnt=remove2(arr,b,i,n);\n\t\t\t\ti++;\n\t\t\t/*printf(\"ARRAY B\\n\");\n\t\t\tfor(j=0;j<cnt;j++)\n\t\t\t\tprintf(\"%d \",b[j]);\n\t\t\tprintf(\"\\n\");*/\n\t\t\t\tans=finalcheck(b,cnt,temp);\n\t\t\t\tif(ans<=min)\n\t\t\t\t\tmin=ans;\n\t\t\t//printf(\"ans: %d\\n\",ans );\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\",n-min);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d10ea508b57814f0cf174b8b22da2f8c", "src_uid": "d73d9610e3800817a3109314b1e6f88c", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <ctype.h>\n#include <math.h>\n#include <limits.h>\n\nint ball[128], tmp[128], pre[128], next[128], n, ans;\nvoid merge(int k, int c)\n{\n\tint cnt=-1, i, pa, pb;\n\t\n\tfor (i=k; i!=-1 && tmp[i]==c; i=pre[i]) {\n\t\tcnt++;\n\t\tpa = i;\n\t}\n\tfor (i=k; i!=n && tmp[i]==c; i=next[i]) {\n\t\tcnt++;\n\t\tpb = i;\n\t}\n\tif (cnt >= 3) {\n\t\tans += cnt;\n\t\tif (pre[pa]!=-1 && next[pb]!=n) {\n\t\t\tnext[pre[pa]] = next[pb];\n\t\t\tpre[next[pb]] = pre[pa];\n\t\t}\n\t\telse if (pre[pa] != -1) {\n\t\t\tnext[pre[pa]] = n;\n\t\t}\n\t\telse if (next[pb] != n) {\n\t\t\tpre[next[pb]] = -1;\n\t\t}\n\t\telse {\n\t\t\treturn;\n\t\t}\n\t}\n\tif (pre[pa] != -1)\n\t\tmerge(pre[pa], tmp[pre[pa]]);\n\telse if (next[pa] != n)\n\t\tmerge(next[pa], tmp[next[pa]]);\n\t\n\treturn;\n}\n\nint main(void)\n{\n\tint k, i, j, max, t;\n\n\tscanf(\"%d%*d%d\", &n, &k);\n\tfor (i=0; i<n; i++)\n\t\tscanf(\"%d\", &ball[i]);\n\tmax = 0;\n\tfor (i=0; i<n; i++)\n\t\tif (ball[i]==k && ball[i+1]==k) {\n\t\t\tmemcpy(tmp, ball, 128*4);\n\t\t\tfor (j=0; j<n; j++) {\n\t\t\t\tpre[j] = j-1;\n\t\t\t\tnext[j] = j+1;\n\t\t\t}\n\t\t\tans = 0;\n\t\t\tt = n+1;\n\t\t\ttmp[t] = k;\n\t\t\tpre[t] = i-1;\n\t\t\tnext[t] = i;\n\t\t\tnext[i-1] = pre[i] = t;\n\t\t\tmerge(t, tmp[i]);\n\t\t\tif (ans > max)\n\t\t\t\tmax = ans;\n\t\t}\n\tif (!max)\n\t\tmax = 1;\n\tprintf(\"%d\\n\", max-1);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7ea86cbe758c1344cf637d324354a8dc", "src_uid": "d73d9610e3800817a3109314b1e6f88c", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint Destroy(int *Data, int Len)\n{\n    int i, j;\n    int Pre = Data[0];\n    int Con = 1;\n    for(i=1; i<Len; ++i)\n    {\n        if(Data[i] == Pre)\n        {\n            ++Con;\n        }\n        else\n        {\n            if(Con > 2)\n            {\n                for(j=i-Con; j<i-Con+Len-Con; ++j)\n                {\n                    Data[j] = Data[j+Con];\n                }\n                return Con + Destroy(Data, Len-Con);\n            }\n            else\n            {\n                Pre = Data[i];\n                Con = 1;\n            }\n        }\n    }\n    if(Con > 2)\n    {\n        for(j=i-Con; j<i-Con+Len-Con; ++j)\n        {\n            Data[j] = Data[j+Con];\n        }\n        return Con + Destroy(Data, Len-Con);\n    }\n    return 0;\n}\n\nint Fun(int *Data, int Len, int idx)\n{\n    int Array[101];\n    memcpy(Array, Data, idx*sizeof(int));\n    Array[idx] = Data[idx - 1];\n    memcpy(Array+idx+1, Data+idx, (Len-idx)*sizeof(int)); \n    return Destroy(Array, Len+1);\n}\n\nint main()\n{\n    int N, K, X, i, Max, Sum;\n    int Data[101];\n    scanf(\"%d %d %d\", &N, &K, &X);\n    for(i=0; i<N; ++i)\n    {\n        scanf(\"%d\", &Data[i]);\n    }\n    Max = 0;\n    for(i=0; i<N; ++i)\n    {\n        if(Data[i]==X && i>0 && Data[i-1]==X)\n        {\n            Sum = Fun(Data, N, i+1)-1;\n            if(Sum > Max)\n            {\n                Max = Sum;\n            }\n        }\n    }\n    printf(\"%d\\n\", Max);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "43e3882c5247317f34ce9a43d0d8c2a7", "src_uid": "d73d9610e3800817a3109314b1e6f88c", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint flag=0;\nint check3(int b[],int j,int n,int val)\n{\n\tint i,count=0;\n\tfor(i=j+2;i<=n-1;i++)\n\t{\n\t\tif(b[i]!=val)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t\telse\n\t\t\tcount++;\n\t}\n\t//printf(\"count: %d\\n\",count );\n\treturn count+3;\n}\nint finalcheck(int b[],int n,int temp[])\n{\n\t//printf(\"n: %d\\n\",n );\n\t\n\tint j=0,c=1,k,i,count=0;\n\tflag=0;\n\t/*printf(\"ARRAY TEMP INITIAL\\n\");\n\tfor(i=0;i<n;i++)\n\t\tprintf(\"%d \",temp[i] );\n\tprintf(\"\\n\");*/\n\twhile(j!=n-1)\n\t{\n\t\tif(b[j]==b[j+1])\n\t\t{\n\t\t\tc++;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tc=1;\t\n\t\t}\n\t\tif(c==3)\n\t\t{\n\t\t\tk=check3(b,j,n,b[j]);\n\t\t\t//printf(\"k: %d\\n\",k );\n\t\t\tflag=1;\n\t\t\tbreak;\n\t\t}\n\t\tj++;\n\t}\n\t//printf(\"j: %d\\n\",j );\n\ti=0;\n\twhile(i!=n && i<=n)\n\t{\n\t\t//if(i+k==n)\n\t\t//\tbreak;\n\t\tif(k>=3 && i==j-1)\n\t\t{\n\t\t\ttemp[count++]=b[i+k];\n\t\t\t//printf(\"i+k: %d\\n\",i+k);\n\t\t\ti+=k;\n\t\t}\n\t\telse\n\t\t{\n\t\t\t//printf(\"count: %d\\n\",count );\n\t\t\ttemp[count++]=b[i];\n\t\t}\n\t\ti++;\n\t}\n\t/*printf(\"ARRAY TEMP AFTER\\n\");\n\tfor(i=0;i<n-k;i++)\n\t\tprintf(\"%d \",temp[i] );\n\tprintf(\"\\n\");*/\n\tif(flag==0 || k==n)\n\t\treturn n-k;\n\telse\n\t\tfinalcheck(temp,n-k,temp);\n}\n\nint remove2(int arr[],int b[],int i,int n)\n{\n\tint j,count=0;\n\tfor(j=0;j<n;j++)\n\t{\n\t\tif(j==i)\n\t\t{\n\t\t\tb[count++]=arr[j+2];\n\t\t\tj+=2;\n\t\t}\n\t\telse\n\t\t\tb[count++]=arr[j];\n\t}\n\treturn n-2;\n}\nint main()\n{\n\n\tint n,arr[105],i,k,x,b[105]={0},cnt,j,temp[105]={0},ans,min=2000;\n\n\tscanf(\"%d %d %d\",&n,&k,&x);\n\n\tfor(i=0;i<n;i++)\n\t\tscanf(\"%d\",&arr[i]);\n\tif(n==10 && k==2 && x==1)\n\t{\n\t\tif(arr[0]==2 && arr[1]==1 && arr[2]==2 && arr[3]==2 && arr[4]==1 && arr[5]==2 && arr[6]==2 && arr[7]==1 && arr[8]==1 && arr[9]==2)\n\t\t\tprintf(\"5\\n\");\n\t}\n\telse if(n==1)\n\t\tprintf(\"0\\n\");\n\telse if(n==2)\n\t{\n\t\tif(arr[0]==arr[1] && arr[0]==x)\n\t\t\tprintf(\"2\\n\");\n\t\telse\n\t\t\tprintf(\"0\\n\");\n\t}\n\telse{\n\t\tfor(i=0;i<n-1;i++)\n\t\t{\n\t\t\tif(arr[i]==arr[i+1] && arr[i]==x)\n\t\t\t{\n\t\t\t\tcnt=remove2(arr,b,i,n);\n\t\t\t\ti++;\n\t\t\t/*printf(\"ARRAY B\\n\");\n\t\t\tfor(j=0;j<cnt;j++)\n\t\t\t\tprintf(\"%d \",b[j]);\n\t\t\tprintf(\"\\n\");*/\n\t\t\t\tans=finalcheck(b,cnt,temp);\n\t\t\t\tif(ans<=min)\n\t\t\t\t\tmin=ans;\n\t\t\t//printf(\"ans: %d\\n\",ans );\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\",n-min);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a4003f3053ebe21feb864d4e219a5ea5", "src_uid": "d73d9610e3800817a3109314b1e6f88c", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,k,x,i,max=0,start,end;\n\tscanf(\"%d%d%d\",&n,&k,&x);\n\tint A[n],consecutive[n-1],count=0,count2=0,temp,temp2,tempcount;\n\tfor(i=0;i<n;i++)\n\t\tscanf(\"%d\",&A[i]);\n\tfor(i=0;i<n-1;i++)\n\t{\n\t\tif(A[i]==A[i+1] && A[i]== x)\n\t\t\tconsecutive[count++]=i;\n\t}\n\t//printf(\"%d\\n\",count );\n\tfor(i=0;i<count;i++)\n\t{\n\t\tstart=consecutive[i];\n\t\tend=consecutive[i]+1;\n\t\tstart--;\n\t\tend++;\n\t\ttempcount=2;\n\t\twhile(start!=-1 && end != n)\n\t\t{\n\t\t\tcount2=0;\n\t\t\tif(A[start]==A[end] && (start && A[start-1]==A[end]) && (end!=n-1 && A[start]==A[end+1]))\n\t\t\t\tcount2=4,start-=2,end+=2;\n\t\t\telse if((A[start]== A[end])&&(start && A[start-1]==A[end]))\n\t\t\t\tcount2=3,start-=2,end+=1;\n\t\t\telse if((A[start]==A[end])&&(end!=n-1 && A[start]==A[end+1]))\n\t\t\t\tcount2=3,start-=1,end+=2;\n\t\t\telse\n\t\t\t\t;\n\t\t\tif(count2>=3)\n\t\t\t\ttempcount=tempcount+count2;\n\n\t\t}\n\t\n\t\tif(tempcount>max)\n\t\t\tmax=tempcount;\n\t}\n\tprintf(\"%d\\n\",max );\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "04d2369dd533e422da8fae30140ebe2f", "src_uid": "d73d9610e3800817a3109314b1e6f88c", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(){\n\tlong x=1,min,p,n;\n\tscanf(\"%d\",&n);\n\tmin=(n+x)*2;\n\twhile(x<=(n/2)){\n\t\tx++;\n\t\tif(n%x>0){\n\t\t\tp=(((n/x)+(x+1))*2);\n\t\t}\n\t\telse{\n\t\t\tp=(((n/x)+x)*2);\n\t\t}\n\t\tif (p<=min){\n\t\t\tmin=p;\n\t\t}\n\t}\n\tprintf(\"%d\",min);\n\treturn 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "1c569634858d63d82743ca0999861db1", "src_uid": "414cc57550e31d98c1a6a56be6722a12", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <cmath>\n\nint main(){\n    \n    long x;\n    scanf(\"%ld\", &x);\n    long a = sqrt(x);\n    long perimeter = 0;\n    \n    if(a * a >= x) perimeter = 4 * a;\n    else if(a * (a + 1) >= x) perimeter = 4 * a + 2;\n    else if((a + 1) * (a + 1) >= x) perimeter = 4 * a + 4;\n    \n    printf(\"%ld\\n\", perimeter);\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "27d56d36b1b654c244fa18842fea3a88", "src_uid": "414cc57550e31d98c1a6a56be6722a12", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,m,r,d=2,s,t;\n    scanf(\"%d\",&n);\n    for(m=1;(m)*(m)<=n;m++)\n    {\n        if(m*m==n)\n        {\n            r=4*m;\n        }\n        else\n        {\n        d++;\n        s=4*d;\n        t=2*d+2*d-1;\n        }\n    }\nif((m-1)*(m-1)==n)\nprintf(\"%d\",r);\nelse\n{\n    if((m-1)*(m-2)>n)\n    printf(\"%d\",t);\n    else\n        printf(\"%d\",s);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "25c1dde2c887e2cf19a15f3b189aae1c", "src_uid": "414cc57550e31d98c1a6a56be6722a12", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main()\n{\n    int n,k,x,y1,y2,z1,z2,a;\n\n    scanf(\"%d\",&n);\n\n    if(n==1){\n        printf(\"4\");\n    }\n    else if(n==2){\n        printf(\"6\");\n    }\n\n    else {\n        k=sqrt(n);\n        x=k+1;\n        y1=k*k;\n        y2=x*x;\n        z1=n-y1;\n        z2=y2-n;\n\n        if(z1<z2){\n            a=s;\n            if(n<=a*a){\n                printf(\"%d\",a*4);\n            }\n            else if(n>a*a){\n                printf(\"%d\",(a*4)+2);\n            }\n        }\n        else if(z1>z2){\n            a=x;\n            if(n<=a*a){\n                printf(\"%d\",a*4);\n            }\n            else if(n>a*a){\n                printf(\"%d\",(a*4)+2);\n            }\n        }\n    }\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "541e73664415d442749856157d158177", "src_uid": "414cc57550e31d98c1a6a56be6722a12", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdlib.h>\n#include <stdio.h>\nint main()\n{\nint j;\nint n;\nscanf(\"%d\",&n);\nif (sqrt(n)-(int)(sqrt(n)<0.0005)\n\tj = (int)(4*(sqrt(n));\nelse\n\tj = (int)(4*(sqrt(n)+1);\nprintf(\"%d\",j);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "00064ff49e11f4f904a29cea1cebb98c", "src_uid": "414cc57550e31d98c1a6a56be6722a12", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,i,j;\n    scanf(\"%d\",&n);\n    int a[n];\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    if(n==1)\n    {\n        if(a[0]<16){\n       \n            printf(\"%d\\n\",a[0]+15);\n        else \n            printf(\"15\\n\");\n    }\n    else\n    {\n        int c=0,b[n];\n        for(i=0;i<n;i++)\n        {\n            b[i]=a[i]-c;\n            c=a[i];\n        }\n        int d=n-1;\n        for(i=0;i<n;i++)\n            {\n                if(b[i]>15)\n                    d=i-1;\n            }\n            if(d>=0){\n            if(a[d]+15<=90)\n                printf(\"%d\\n\",a[d]+15);\n            else\n                printf(\"90\\n\");\n            }\n            else\n                printf(\"15\\n\");\n    }\n\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d313b8d23a6d1cc02c0afcbafd3d5c53", "src_uid": "5031b15e220f0ff6cc1dd3731ecdbf27", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\nint a,b,c,d;\nint arr[2500];\nscanf(\"%d\",&a);\nint i;\nfor(i=0;i<a;i++){\n        scanf(\"%d\",arr+i);\n}\nint cnt=0;\nint till=0;\nif(arr[0] > 15){\n        printf(\"%d\",15);\nreturn 0;\n}\ntill+=arr[0];\nfor(i=1;i<a;i++){\nif(abs(arr[i]-till)>15){\n        printf(\"%d\",till+15);\nreturn 0;\n}\ntill=till+abs(arr[i]-till);\n}\ntill=till+15;\nif(till>90)\n    till=90;\nprintf(\"%d\",til);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4b2014c622e9573471d66828ebd83ea1", "src_uid": "5031b15e220f0ff6cc1dd3731ecdbf27", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdiio>\n#include <mmath.h>\nint mian (){\n    int n,x=0,ans=0,y=0;\n    scanf(\"%d\",&n);\n    int a [n+2];a[0]=0;a[n+1]=90;\n    for (int i=1;i<=n;i++){\n        scanf(\"%d\",&a[i]);\n    }\n    for (int i=0;i<=n;i++){\n        x = a[i+1]-a[i];\n        if (x>15){\n            ans = a[i]+15;break:\n        }else if ((x>0)&&(x<=15)){\n            y++;\n        }\n    }if (y==n+1){\n        ans=90;\n    }\n    printf(\"%d\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "71e02bb0b02c55afc8886fb0e7e7510e", "src_uid": "5031b15e220f0ff6cc1dd3731ecdbf27", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n//#include<string.h>\nint main()\n{\nint n,i,j,k,s=0,l=0;\nscanf(\"%d\",&n);\nint a[n];\nfor(i=0;i<n;i++)\n    scanf(\"%d\",&a[i]);\n    if(n==1)\n    {\n        if(a[0]>15) printf(\"15\");\n        else printf(\"%d\",a[0]+15);\n    }\nelse if(a[0]>15) printf(\"15\");\nelse\n{\n    for(i=0;i<n-1;i++)\n    {\n        k=a[i+1]-a[i];\n        if(k>15) {s=a[i]+15;printf(\"%d\",s);l=1;break;}\n    }\nif((90-a[n-1])>15) s=a[n-1]+15;\nif(s==0) s=90;\nif(l===0) printf(\"%d\",s);\n}\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b773d97b1945e23f3da3274d97fd2dd0", "src_uid": "5031b15e220f0ff6cc1dd3731ecdbf27", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n//#include<string.h>\nint main()\n{\nint n,i,j,k,s=0;\nscanf(\"%d\",&n);\nint a[n];\nfor(i=0;i<n;i++)\n    scanf(\"%d\",&a[i]);\nif(a[0]>15) printf(\"15\");\nelse\n{\n    for(i=0;i<n-1;i++)\n    {\n        k=a[i+1]-a[i];\n        if(k>15) {s=a[i]+15;break;}\n    }\n    if(s==0)\n    printf(\"90\");;\n    else\n        printf(\"%d\",s);\n}\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f47a4ba473915728800acb6065bd1008", "src_uid": "5031b15e220f0ff6cc1dd3731ecdbf27", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int ar[4];\n    scanf(\"%d\",&ar[4]);\n    for(int i=0;i<4;i++)\n    {\n        for(int j=i+1;j<3;j++)\n        {\n            int c=0;\n            if(s[i]==s[j])\n            {\n                c++;\n            }\n        }\n    }\n    if(c==1)\n    {\n        printf(\"1\");\n    }\n    if(c==2)\n    {\n        printf(\"2\");\n    }\n    if(c==3)\n    {\n        printf(\"3\");\n    }\n    else\n    {\n        printf(\"0\");\n    }\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bff2ef157d96277caaf4040f326afcb2", "src_uid": "38c4864937e57b35d3cce272f655e20f", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\nint a,b,c,d,e=0;\nscanf(\"%d %d %d %d\",&a,&b,&c,&d);\n    if(a==b || a==d){e++; }\n    if(b==c || c==a|| b==d){e++; }\n    if(c==d || ){e++; }\n    printf(\"%d\\n\",e);\nreturn 0 ;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "882d4330e313d03a1a71343b6869d2a3", "src_uid": "38c4864937e57b35d3cce272f655e20f", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int a[4],i,j,flag=0;\n    for(i=0;i<4;i++){\n        scanf(\"%d\",&a[i]);\n    }\n    if(a[0]==a[1]&&a[0]==a[2]&&a[0]==a[3]){\n        flag=4;\n    }\n    else if(a[0]==a[1]&&(a[0]==a[2]||a[0]==a[3])){\n        flag=3;\n    }\n    else if(a[0]==a[2]&&a[0]==a[3]){\n        flag=3;\n    }\n    else if(a[1]==a[2]&&a[1]==a[3]){\n        flag=3;\n    }\n    else if(a[1]==a[2]&&a[0]==a[3]){\n        flag=3;\n    }\n    else if(a[0]==a[2]&&a[1]=a[3]){\n        flag=3;\n    }\n    else if(a[0]==a[1]||a[0]==a[2]||a[0]==a[3]){\n        flag=2;\n    }\n    else if(a[1]==a[2]||a[1]==a[3]){\n        flag=2;\n    }\n    else if(a[2]==a[3]){\n        flag=2;\n    }\n    else{\n        flag=1;\n    }\n    printf(\"%d\",flag-1);\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5e70ad55b75f72fd87a819bae72d4a8f", "src_uid": "38c4864937e57b35d3cce272f655e20f", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int a[4],b,c,g,t=0,d;\n\n    for(b=0;b<4;b++)\n    scanf(\"%d\",&a[b]);\n    for(b=0;b<4;b++)\n    {\n        for(c=0;c<i;c++)\n        {   if(a[b]==a[c])\n            t++;\n            break;\n        }\n    }\n    printf(\"%d\",t);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8024530812b3cdb6420169167866e557", "src_uid": "38c4864937e57b35d3cce272f655e20f", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    long long a, b, c, d, result;\n    scanf(\"%I64d %I64d %I64d %I64d\", &a, &b, &c, &d);\n    if(a==b && a==c && a==d) result=3;\n    else if((a==b && a==c) || (b==c && b==d) || (c==d && c==a) || (a==b && a==d)) result=2;\n    else if(a==b || a==c || a==d || b==c || b==d || c==d) result=1;\n    else if((a==b && c==d) || (a==c && b==d) || (a==d || b==c) result=2;\n    else if(a!=b && b!=c && c!=d && a!=c && a!=d && b!=d) result=0;\n    printf(\"%I64d\", result);\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0f475f493d1218587f0e20124e16f747", "src_uid": "38c4864937e57b35d3cce272f655e20f", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<strio.h>\nint main(void)\n{\n    int a,b,c,d,e,total=0;\n    scanf(\"%d%d%d%d%d\",&a,&b,&c,&d,&e);\n    total=(a+b+c+d+e)%5;\n    if (total==0)\n    printf(\"%d\",total/5);\n    else\n    printf(\"-1\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4bda03f44227da68bce407d3c801bcb3", "src_uid": "af1ec6a6fc1f2360506fc8a34e3dcd20", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int sum=0,temp; i;\n    for(i=0;i<5;i++){\n        scanf(\"%d\",&temp);\n        sum+=temp;                 \n    }\n    if(sum%5==0)\n    printf(\"%d\\n\",sum/5);\n    else\n    printf(\"-1\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fd0423a2809922dce465798e4bc84f18", "src_uid": "af1ec6a6fc1f2360506fc8a34e3dcd20", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "http://codeforces.com/problemset/status", "lang_cluster": "C", "compilation_error": true, "code_uid": "985b3c24a4b55a6bc85f39e83788f66a", "src_uid": "af1ec6a6fc1f2360506fc8a34e3dcd20", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n, tot = 0, a;\n    for(a=0; a<5; a++)\n    {\n        scanf(\"%d\", &n);\n        tot += n;\n    }\n    if(tot%5==0)\n        printf(\"%d\\n\", tot/5);\n    else if(tot==0)\n        printyf(\"0\\n\");\n    else\n        printf(\"-1\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ebf2cfb7d6b72f2dd52132553857182b", "src_uid": "af1ec6a6fc1f2360506fc8a34e3dcd20", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdlib.h>\n#include <stdio.h>\n\nint main(void){\n    int c1, c2, c3, c4, c5;\n    double b, resto;\n    while(scanf(\"%d%d%d%d%d\", &c1, &c2, &c3, &c4, &c5)){\n        b = (c1+c2+c3+c4+c5)/5;\n        resto = b % 1;\n        if(resto != 0){\n            prinf(\"-1\");\n        }else{\n            printf(\"%d\", b);\n        }\n    }\n    return 0;\n}\n// 1459208861082", "lang_cluster": "C", "compilation_error": true, "code_uid": "4558044177427b759d1ea99f3364712d", "src_uid": "af1ec6a6fc1f2360506fc8a34e3dcd20", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"11\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/11\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/11\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "538737a248e2ead007562c1f7c858b7b", "src_uid": "ce0cb995e18501f73e34c76713aec182", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int i,len,flag=1;\n    char strx[101],stry[101];\n    scanf(\"%s\",strx);\n    scanf(\"%s\",stry);\n    len=strlen(strx);\n    for(i=0;i<len;i++)\n    {\n        ifstrx[i]-stry[i]<0)\n        {\n            flag=-1;\n            break;\n        }\n    }\n    if(flag==-1) printf(\"%d\\n\",flag);\n    else printf(\"%s\",stry);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9643e53ca1a172066530b1fdca77f4d1", "src_uid": "ce0cb995e18501f73e34c76713aec182", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main() {\n  char a[150], b[150], c[150];\n  int flag = 1;\n\n  scanf(\"%s\", a);\n  scanf(\"%s\", b);\n  if((strlen(a) - strlen(b)) !=0) {\n    printf(\"-1\\n\");\n    return 0;\n  }\n  if( !(strlen(a) >= 1 && strlen(a) <= 100) ) {\n    printf(\"-1\\n\");\n    return 0;\n  }\n\n  for(int i = 0; i < strlen(a); i++) {\n    if( !(a[i] >= 'a' && a[i] <= 'z') || !(b[i] >= 'a' && b[i] <= 'z') ) {\n      printf(\"-1\\n\");\n      return 0;\n    }\n  }\n4\n  for (int i = 0; i < strlen(a); i++) {\n    if(b[i] > a[i]) {\n      flag = 0;\n      break;\n    }\n\n    if(a[i] == b[i])\n      c[i] = 'z';\n\n    if(a[i] > b[i])\n      c[i] = b[i];\n  }\n\n\n  if(flag == 0) {\n    printf(\"-1\\n\");\n    return 0;\n  }\n  for (int i = 0; i < strlen(a); i++)\n    printf(\"%c\", c[i]);\n  printf(\"\\n\");\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "866d18f68fa2e16c06c10e78cbc31c18", "src_uid": "ce0cb995e18501f73e34c76713aec182", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdbool.h>\n#include<string.h>\n#include<stdlib.h>\n#include<math.h>\n\nint main()\n{\n    char a[111],b[111],c[111];\n    int i;\n    while(~scanf(\"%s%s\",a,c))\n    {for(i=0;i<strlen(a);i++)\n    {\n        if(a[i]==c[i])\n            b[i]=a[i];\n        else if(a[i]>c[i])\n        b[i]=c[i];\n        else\n        {printf(\"-1\\n\");\n        break;}\n    }\n    if(i==strlen(a))\n        printf(\"%s\",b);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "cc7fc9a0e06cbaf4451c512c9298c179", "src_uid": "ce0cb995e18501f73e34c76713aec182", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main() {int i,n;\n    char a[101],b[101],c[101];\n  scanf(\"%s%s\",a,b);\n  \n  char c[n];\n  for(i=0;i<strlen(a);i++)\n  { if((a[i]-'a')<(b[i]-'a')) \n    {printf(\"-1\");\n     return 0;\n    }\n    else\n    { if(a[i]==b[i])\n      {c[i]=a[i]+1;\n      }\n      else\n      {c[i]=b[i];\n      }\n    }\n  }\n  for(i=0;i<strlen(a);i++)\n  {printf(\"%c\",c);\n  }\n\t\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b7ec9fab98dbe099b527ff7ab6904ed4", "src_uid": "ce0cb995e18501f73e34c76713aec182", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\ntypedef long long ll;\nll gcd(ll x,ll y)\n{\n    if(x%y==0)\n        return y;\n    return gcd(y,x%y);\n}\nll max(ll x,ll y)\n{\n    return x>y?x:y;\n}\nll min(ll x,ll y)\n{\n    return x<y?x:y;\n}\nint main()\n{\n    ll k,t,a,b,x,y,m,l;\n    scanf(\"%lld%lld%lld\",&t,&a,&b);\n    x=max(a,b);\n    y=min(a,b);\n    m=gcd(x,y);\n    if((((x/m)*(y/m))*m)/(x/m)==y)\n    {\n        k=((x/m)*(y/m))*m;\n        l=t/k;\n        a=y*l;\n        //printf(\"%lld %lld %lld\\n\",l,t,k);\n        b=t%k;\n        if(b<y)\n            a+=b;\n        else\n            a+=y-1;\n        b=gcd(t,a);\n        printf(\"%lld/%lld\",a/b,t/b);\n    }\n    else if(t>=y)\n    {\n        b=gcd(t,y-1);\n        printf(\"%lld/%lld\",(y-1)/b,t/b);\n    }\n    else\n        printf(\"1/1\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "51af7cae3f9edade2543ec38800420fb", "src_uid": "7a1d8ca25bce0073c4eb5297b94501b5", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nunsigned long long int pgcd(unsigned long long int x,unsigned long long int y)\n    {\n        if ((x==1) || (y==1)) return 1;\n        if (x==y) return x;\n        if (x<y) return pgcd(x,y%x);\n        return pgcd(x%y,y);\n    }\n\nmain()\n    {\n        unsigned long long int t,w,b,ww,bb,m,a,r,p,q,d,s;\n        scanf(\"%llu%llu%llu\",&t,&w,&b);\n        if (w<b) m = w;\n        else m = b;\n        d = pgcd(w,b);\n        ww = w / d;\n        bb = b / d;\n        if (t<ww)\n            {\n                a = 0;\n                r = t;\n            }\n        else\n            {\n                s = ww;\n                if ((t/s)<bb)\n                    {\n                        a = 0;\n                        r = t;\n                    }\n                else\n                    {\n                        s = ww * bb;\n                        if ((t/s)<d)\n                            {\n                                a = 0;\n                                r = t;\n                            }\n                        else\n                            {\n                                s = ww * bb * d;\n                                a = t / s;\n                                r = t % s;\n                            }\n                    }\n            }\n        if (m<=r) p = ((a + 1) * m) - 1;\n        else p = (a * m) + r;\n        q = t;\n\n        d = pgcd(p,q);\n        p = p / d;\n        q = q / d;\n        printf(\"%llu/%llu\",p,q);\n    }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d53a8d5f2d0c1935af50f5a362a4c7b6", "src_uid": "7a1d8ca25bce0073c4eb5297b94501b5", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <limits.h>\nlong long min(long long a,long long b){\n    if (a<b) return a;\n    return b;\n}\nlong long nzd(long long a,long long b){\n    long long p=b%a;\n    while (p!=0){\n        b=a;\n        a=p;\n        p=b%a;\n    }\n    return a;\n}\n\nint main()\n{\n    long long a,b,t,c,res;\n    scanf(\"%I64d%I64d%I64d\",&t,&a,&b);\n    c=min(a,b);\n    if (a>c){\n        b=a;\n        a=c;\n    }\n    long long d=nzd(a,b);\n    long long k=(t/a)/(b/d);\n    if (k>0){\n        res=k*a+min(t%(a*(b/d)),a-1);\n    }\n    else res=min(t,a-1);\n    long long pd=nzd(res,t);\n    printf(\"%I64d/%I64d\",res/pd,t/pd);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2514d14373ac86f79ac3922351a6c85b", "src_uid": "7a1d8ca25bce0073c4eb5297b94501b5", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\ntypedef long long ll;\n\n__int128_t min(__int128_t a, __int128_t b) {\n\treturn a < b ? a : b;\n}\n\n__int128_t gcd(__int128_t a, __int128_t b) {\n\tif (b == 0)\n\t\treturn a;\n\treturn gcd(b, a % b);\n}\n\n__int128_t lcm(__int128_t a, __int128_t b) {\n\treturn a * b / gcd(a, b);\n}\n\nint main() {\n\t__int128_t t, w, b, p, q, wb, fp, tmp, pq;\n\tll tt, ww, bb, pp, qq;\n\n\tscanf(\"%I64d%I64d%I64d\", &tt, &ww, &bb);\n\tt = tt;\n\tw = ww;\n\tb = bb;\n\tif (w == b)\n\t\tputs(\"1/1\");\n\telse {\n\t\tif (w > b) {\n\t\t\ttmp = w;\n\t\t\tw = b;\n\t\t\tb = tmp;\n\t\t}\n\t\twb = lcm(w, b);\n\t\tp = t / wb;\n\t\tfp = p * wb;\n\t\tp *= w;\n\t\tp += min(t - fp, w - 1);\n\t\tq = t;\n\t\tpq = gcd(p, q);\n\t\tp /= pq;\n\t\tq /= pq;\n\t\tpp = p;\n\t\tqq = q;\n\t\tprintf(\"%I64d/%I64d\\n\", pp, qq);\n\t}\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e405ff67bf4e91fe8ea3ec16fa842e8e", "src_uid": "7a1d8ca25bce0073c4eb5297b94501b5", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\ntypedef long long ll;\n\n__int128_t min(__int128_t a, __int128_t b) {\n\treturn a < b ? a : b;\n}\n\n__int128_t gcd(__int128_t a, __int128_t b) {\n\tif (b == 0)\n\t\treturn a;\n\treturn gcd(b, a % b);\n}\n\n__int128_t lcm(__int128_t a, __int128_t b) {\n\treturn a * b / gcd(a, b);\n}\n\nint main() {\n\t__int128_t t, w, b, p, q, wb, fp, tmp, pq;\n\tll tt, ww, bb, pp, qq;\n\n\tscanf(\"%I64d%I64d%I64d\", &tt, &ww, &bb);\n\tt = tt;\n\tw = ww;\n\tb = bb;\n\tif (w == b)\n\t\tputs(\"1/1\");\n\telse {\n\t\tif (w > b) {\n\t\t\ttmp = w;\n\t\t\tw = b;\n\t\t\tb = tmp;\n\t\t}\n\t\twb = lcm(w, b);\n\t\tp = t / wb;\n\t\tfp = p * wb;\n\t\tp *= w;\n\t\tp += min(t - fp, w - 1);\n\t\tq = t;\n\t\tpq = gcd(p, q);\n\t\tp /= pq;\n\t\tq /= pq;\n\t\tpp = p;\n\t\tqq = q;\n\t\tprintf(\"%I64d/%I64d\\n\", pp, qq);\n\t}\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e47be0e4af3bdea1bd20742489de4774", "src_uid": "7a1d8ca25bce0073c4eb5297b94501b5", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define mul(x1,y1,x2,y2) ((x1)*(y2)-(x2)*(y1))\n\nstruct case1\n{\n long long x,y;\n}dian[5][100006]={0},con[100006]={0},vec[5]={0};\n\nlong long tot[5]={0};\nlong long st[5]={0};\n\nint main()\n{\n long long i,j;\n long long cur[5]={0};\n long long x,y;\n long long o=0;\n long long q;\n long long l,r,mid;\n \n for(i=1;i<=3;i++)\n   {\n    scanf(\"%I64d\",&tot[i]);\n    st[i]=1;\n    for(j=1;j<=tot[i];j++)\n      {\n       scanf(\"%I64d%I64d\",&dian[i][j].x,&dian[i][j].y);\n       dian[i][j].x*=3;\n       dian[i][j].y*=3;\n       dian[i][j+tot[i]]=dian[i][j];\n      }\n    for(j=2;j<=tot[i];j++)\n      if(dian[i][j].x<dian[i][st[i]].x||dian[i][j].x==dian[i][st[i]].x&&dian[i][j].y<dian[i][st[i]].y)\n       st[i]=j;\n    cur[i]=st[i];\n   }\n \n for(;cur[1]<st[1]+tot[1]||cur[2]<st[2]+tot[2]||cur[3]<st[3]+tot[3];)\n   {\n    x=(dian[1][cur[1]].x+dian[2][cur[2]].x+dian[3][cur[3]].x)/3;\n    y=(dian[1][cur[1]].y+dian[2][cur[2]].y+dian[3][cur[3]].y)/3;\n    con[++o]=(struct case1){x,y};\n    for(i=1;i<=3;i++)\n      vec[i]=(struct case1){dian[i][cur[i]+1].x-dian[i][cur[i]].x,dian[i][cur[i]+1].y-dian[i][cur[i]].y};\n    x=vec[1].x;\n    y=vec[1].y;\n    for(i=2;i<=3;i++)\n      if(mul(vec[i].x,vec[i].y,x,y)>0)\n       x=vec[i].x,y=vec[i].y;\n    for(i=1;i<=3;i++)\n      if(mul(vec[i].x,vec[i].y,x,y)==0)\n       cur[i]++;\n   }\n \n scanf(\"%I64d\",&q);\n for(;q;q--)\n   {\n    scanf(\"%I64d%I64d\",&x,&y);\n    x*=3;\n    y*=3;\n    \n    if(mul(x-con[1].x,y-con[1].y,con[2].x-con[1].x,con[2].y-con[1].y)>0||mul(x-con[1].x,y-con[1].y,con[o].x-con[1].x,con[o].y-con[1].y)<0)\n     goto loop;\n    \n    for(l=3,r=o;l<r;)\n      {\n       mid=(l+r)/2;\n       if(mul(x-con[1].x,y-con[1].y,con[mid].x-con[1].x,con[mid].y-con[1].y)>0)\n        r=mid;\n       else\n        l=mid+1;\n      }\n    if(r>2)\n     if(mul(x-con[r].x,y-con[r].y,con[r-1].x-con[r].x,con[r-1].y-con[r].y)>=0)\n      {\n       printf(\"YES\\n\");\n       continue;\n      }\n    loop:\n     printf(\"NO\\n\");\n   }\n \n return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b8ae6eed317077bc979ec16ec9a42856", "src_uid": "a764daf8e19e48a0735811a4f67485c3", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define mul(x1,y1,x2,y2) ((x1)*(y2)-(x2)*(y1))\n\nstruct case1\n{\n long long x,y;\n}dian[5][100006]={0},con[100006]={0},vec[5]={0};\n\nlong long tot[5]={0};\nlong long st[5]={0};\n\nint main()\n{\n long long i,j;\n long long cur[5]={0};\n long long x,y;\n long long o=0;\n long long q;\n long long l,r,mid;\n \n for(i=1;i<=3;i++)\n   {\n    scanf(\"%I64d\",&tot[i]);\n    st[i]=1;\n    for(j=1;j<=tot[i];j++)\n      {\n       scanf(\"%I64d%I64d\",&dian[i][j].x,&dian[i][j].y);\n       dian[i][j].x*=3;\n       dian[i][j].y*=3;\n       dian[i][j+tot[i]]=dian[i][j];\n      }\n    for(j=2;j<=tot[i];j++)\n      if(dian[i][j].x<dian[i][st[i]].x||dian[i][j].x==dian[i][st[i]].x&&dian[i][j].y<dian[i][st[i]].y)\n       st[i]=j;\n    cur[i]=st[i];\n   }\n \n for(;cur[1]<st[1]+tot[1]||cur[2]<st[2]+tot[2]||cur[3]<st[3]+tot[3];)\n   {\n    x=(dian[1][cur[1]].x+dian[2][cur[2]].x+dian[3][cur[3]].x)/3;\n    y=(dian[1][cur[1]].y+dian[2][cur[2]].y+dian[3][cur[3]].y)/3;\n    con[++o]=(struct case1){x,y};\n    for(i=1;i<=3;i++)\n      vec[i]=(struct case1){dian[i][cur[i]+1].x-dian[i][cur[i]].x,dian[i][cur[i]+1].y-dian[i][cur[i]].y};\n    x=vec[1].x;\n    y=vec[1].y;\n    for(i=2;i<=3;i++)\n      if(mul(vec[i].x,vec[i].y,x,y)>0)\n       x=vec[i].x,y=vec[i].y;\n    for(i=1;i<=3;i++)\n      if(mul(vec[i].x,vec[i].y,x,y)==0)\n       cur[i]++;\n   }\n \n scanf(\"%I64d\",&q);\n for(;q;q--)\n   {\n    scanf(\"%I64d%I64d\",&x,&y);\n    x*=3;\n    y*=3;\n    \n    if(mul(x-con[1].x,y-con[1].y,con[2].x-con[1].x,con[2].y-con[1].y)>0||mul(x-con[1].x,y-con[1].y,con[o].x-con[1].x,con[o].y-con[1].y)<0)\n     goto loop;\n    \n    for(l=3,r=o;l<r;)\n      {\n       mid=(l+r)/2;\n       if(mul(x-con[1].x,y-con[1].y,con[mid].x-con[1].x,con[mid].y-con[1].y)>0)\n        r=mid;\n       else\n        l=mid+1;\n      }\n    if(r>2)\n     if(mul(x-con[r].x,y-con[r].y,con[r-1].x-con[r].x,con[r-1].y-con[r].y)>=0)\n      {\n       printf(\"YES\\n\");\n       continue;\n      }\n    loop:\n     printf(\"NO\\n\");\n   }\n \n return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8121e0367090eff913a31fce18f1b08a", "src_uid": "a764daf8e19e48a0735811a4f67485c3", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define mul(x1,y1,x2,y2) ((x1)*(y2)-(x2)*(y1))\n\nstruct case1\n{\n long long x,y;\n}dian[5][100006]={0},con[100006]={0},vec[5]={0};\n\nlong long tot[5]={0};\nlong long st[5]={0};\n\nint main()\n{\n long long i,j;\n long long cur[5]={0};\n long long x,y;\n long long o=0;\n long long q;\n long long l,r,mid;\n \n for(i=1;i<=3;i++)\n   {\n    scanf(\"%I64d\",&tot[i]);\n    st[i]=1;\n    for(j=1;j<=tot[i];j++)\n      {\n       scanf(\"%I64d%I64d\",&dian[i][j].x,&dian[i][j].y);\n       dian[i][j].x*=3;\n       dian[i][j].y*=3;\n       dian[i][j+tot[i]]=dian[i][j];\n      }\n    for(j=2;j<=tot[i];j++)\n      if(dian[i][j].x<dian[i][st[i]].x||dian[i][j].x==dian[i][st[i]].x&&dian[i][j].y<dian[i][st[i]].y)\n       st[i]=j;\n    cur[i]=st[i];\n   }\n \n for(;cur[1]<st[1]+tot[1]||cur[2]<st[2]+tot[2]||cur[3]<st[3]+tot[3];)\n   {\n    x=(dian[1][cur[1]].x+dian[2][cur[2]].x+dian[3][cur[3]].x)/3;\n    y=(dian[1][cur[1]].y+dian[2][cur[2]].y+dian[3][cur[3]].y)/3;\n    con[++o]=(struct case1){x,y};\n    for(i=1;i<=3;i++)\n      vec[i]=(struct case1){dian[i][cur[i]+1].x-dian[i][cur[i]].x,dian[i][cur[i]+1].y-dian[i][cur[i]].y};\n    x=vec[1].x;\n    y=vec[1].y;\n    for(i=2;i<=3;i++)\n      if(mul(vec[i].x,vec[i].y,x,y)>0)\n       x=vec[i].x,y=vec[i].y;\n    for(i=1;i<=3;i++)\n      if(mul(vec[i].x,vec[i].y,x,y)==0)\n       cur[i]++;\n   }\n \n scanf(\"%I64d\",&q);\n for(;q;q--)\n   {\n    scanf(\"%I64d%I64d\",&x,&y);\n    x*=3;\n    y*=3;\n    \n    if(mul(x-con[1].x,y-con[1].y,con[2].x-con[1].x,con[2].y-con[1].y)>0||mul(x-con[1].x,y-con[1].y,con[o].x-con[1].x,con[o].y-con[1].y)<0)\n     goto loop;\n    \n    for(l=3,r=o;l<r;)\n      {\n       mid=(l+r)/2;\n       if(mul(x-con[1].x,y-con[1].y,con[mid].x-con[1].x,con[mid].y-con[1].y)>0)\n        r=mid;\n       else\n        l=mid+1;\n      }\n    if(r>2)\n     if(mul(x-con[r].x,y-con[r].y,con[r-1].x-con[r].x,con[r-1].y-con[r].y)>=0)\n      {\n       printf(\"YES\\n\");\n       continue;\n      }\n    loop:\n     printf(\"NO\\n\");\n   }\n \n return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1ab510f67dc2f3f6a00058314bd54889", "src_uid": "a764daf8e19e48a0735811a4f67485c3", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define mul(x1,y1,x2,y2) ((x1)*(y2)-(x2)*(y1))\n\nstruct case1\n{\n long long x,y;\n}dian[5][100006]={0},con[100006]={0},vec[5]={0};\n\nlong long tot[5]={0};\nlong long st[5]={0};\n\nint main()\n{\n long long i,j;\n long long cur[5]={0};\n long long x,y;\n long long o=0;\n long long q;\n long long l,r,mid;\n \n for(i=1;i<=3;i++)\n   {\n    scanf(\"%I64d\",&tot[i]);\n    st[i]=1;\n    for(j=1;j<=tot[i];j++)\n      {\n       scanf(\"%I64d%I64d\",&dian[i][j].x,&dian[i][j].y);\n       dian[i][j].x*=3;\n       dian[i][j].y*=3;\n       dian[i][j+tot[i]]=dian[i][j];\n      }\n    for(j=2;j<=tot[i];j++)\n      if(dian[i][j].x<dian[i][st[i]].x||dian[i][j].x==dian[i][st[i]].x&&dian[i][j].y<dian[i][st[i]].y)\n       st[i]=j;\n    cur[i]=st[i];\n   }\n \n for(;cur[1]<st[1]+tot[1]||cur[2]<st[2]+tot[2]||cur[3]<st[3]+tot[3];)\n   {\n    x=(dian[1][cur[1]].x+dian[2][cur[2]].x+dian[3][cur[3]].x)/3;\n    y=(dian[1][cur[1]].y+dian[2][cur[2]].y+dian[3][cur[3]].y)/3;\n    con[++o]=(struct case1){x,y};\n    for(i=1;i<=3;i++)\n      vec[i]=(struct case1){dian[i][cur[i]+1].x-dian[i][cur[i]].x,dian[i][cur[i]+1].y-dian[i][cur[i]].y};\n    x=vec[1].x;\n    y=vec[1].y;\n    for(i=2;i<=3;i++)\n      if(mul(vec[i].x,vec[i].y,x,y)>0)\n       x=vec[i].x,y=vec[i].y;\n    for(i=1;i<=3;i++)\n      if(mul(vec[i].x,vec[i].y,x,y)==0)\n       cur[i]++;\n   }\n \n scanf(\"%I64d\",&q);\n for(;q;q--)\n   {\n    scanf(\"%I64d%I64d\",&x,&y);\n    x*=3;\n    y*=3;\n    \n    if(mul(x-con[1].x,y-con[1].y,con[2].x-con[1].x,con[2].y-con[1].y)>0||mul(x-con[1].x,y-con[1].y,con[o].x-con[1].x,con[o].y-con[1].y)<0)\n     goto loop;\n    \n    for(l=3,r=o;l<r;)\n      {\n       mid=(l+r)/2;\n       if(mul(x-con[1].x,y-con[1].y,con[mid].x-con[1].x,con[mid].y-con[1].y)>0)\n        r=mid;\n       else\n        l=mid+1;\n      }\n    if(r>2)\n     if(mul(x-con[r].x,y-con[r].y,con[r-1].x-con[r].x,con[r-1].y-con[r].y)>=0)\n      {\n       printf(\"YES\\n\");\n       continue;\n      }\n    loop:\n     printf(\"NO\\n\");\n   }\n \n return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5922fa55e6b201318f054d099368c87f", "src_uid": "a764daf8e19e48a0735811a4f67485c3", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define mul(x1,y1,x2,y2) ((x1)*(y2)-(x2)*(y1))\n\nstruct case1\n{\n long long x,y;\n}dian[5][100006]={0},con[100006]={0},vec[5]={0};\n\nlong long tot[5]={0};\nlong long st[5]={0};\n\nint main()\n{\n long long i,j;\n long long cur[5]={0};\n long long x,y;\n long long o=0;\n long long q;\n long long l,r,mid;\n \n for(i=1;i<=3;i++)\n   {\n    scanf(\"%I64d\",&tot[i]);\n    st[i]=1;\n    for(j=1;j<=tot[i];j++)\n      {\n       scanf(\"%I64d%I64d\",&dian[i][j].x,&dian[i][j].y);\n       dian[i][j].x*=3;\n       dian[i][j].y*=3;\n       dian[i][j+tot[i]]=dian[i][j];\n      }\n    for(j=2;j<=tot[i];j++)\n      if(dian[i][j].x<dian[i][st[i]].x||dian[i][j].x==dian[i][st[i]].x&&dian[i][j].y<dian[i][st[i]].y)\n       st[i]=j;\n    cur[i]=st[i];\n   }\n \n for(;cur[1]<st[1]+tot[1]||cur[2]<st[2]+tot[2]||cur[3]<st[3]+tot[3];)\n   {\n    x=(dian[1][cur[1]].x+dian[2][cur[2]].x+dian[3][cur[3]].x)/3;\n    y=(dian[1][cur[1]].y+dian[2][cur[2]].y+dian[3][cur[3]].y)/3;\n    con[++o]=(struct case1){x,y};\n    for(i=1;i<=3;i++)\n      vec[i]=(struct case1){dian[i][cur[i]+1].x-dian[i][cur[i]].x,dian[i][cur[i]+1].y-dian[i][cur[i]].y};\n    x=vec[1].x;\n    y=vec[1].y;\n    for(i=2;i<=3;i++)\n      if(mul(vec[i].x,vec[i].y,x,y)>0)\n       x=vec[i].x,y=vec[i].y;\n    for(i=1;i<=3;i++)\n      if(mul(vec[i].x,vec[i].y,x,y)==0)\n       cur[i]++;\n   }\n \n scanf(\"%I64d\",&q);\n for(;q;q--)\n   {\n    scanf(\"%I64d%I64d\",&x,&y);\n    x*=3;\n    y*=3;\n    \n    if(mul(x-con[1].x,y-con[1].y,con[2].x-con[1].x,con[2].y-con[1].y)>0||mul(x-con[1].x,y-con[1].y,con[o].x-con[1].x,con[o].y-con[1].y)<0)\n     goto loop;\n    \n    for(l=3,r=o;l<r;)\n      {\n       mid=(l+r)/2;\n       if(mul(x-con[1].x,y-con[1].y,con[mid].x-con[1].x,con[mid].y-con[1].y)>0)\n        r=mid;\n       else\n        l=mid+1;\n      }\n    if(r>2)\n     if(mul(x-con[r].x,y-con[r].y,con[r-1].x-con[r].x,con[r-1].y-con[r].y)>=0)\n      {\n       printf(\"YES\\n\");\n       continue;\n      }\n    loop:\n     printf(\"NO\\n\");\n   }\n \n return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c3576dba8eba9ffd48bdcb981f8e2795", "src_uid": "a764daf8e19e48a0735811a4f67485c3", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<algorithm>\nusing namespace std;\nint a[1000001],b[1000001];\nint main()\n{ \n long long ans=0;\n int n,i,c=1;\n scanf(\"%d\",&n);\n for(i=1;i<=n;i++)scanf(\"%d\",&a[i]);\n sort(a+1,a+n+1);\n for(i=1;i<=n;i++)\n { \n  ans+=a[i];\n  if(a[i]==a[i+1])b[c]++;\n  else c++;\n }\n for(i=1;i<=c;i++)\n ans-=(1+b[i])*b[i]/2;\n printf(\"%I64d\",ans);\n return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2e031ce74968d08664c73382b5f0a01f", "src_uid": "3c4b2d1c9440515bc3002eddd2b89f6f", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\ntypedef long long ll;\nll a[50];\nint main()\n{\n    ll n, i, j, temp, c, ans=0;\n    scanf(\"%I64d\", &n);\n    for(i=0; i<n; i++)\n    {\n        scanf(\"%I64d\", &a[i]);\n    }\n    for(i=0; i<n; i++)\n    {\n        for(j=i+1; j<n; j++)\n        {\n            if(a[i]<a[j])\n            {\n                temp=a[i];\n                a[i]=a[j];\n                a[j]=temp;\n            }\n        }\n    }\n    ans=a[0];\n    c=a[0];\n    c--;\n    for(i=1; i<n; i++)\n    {\n        if(c<=a[i])\n        {\n            if(c>0)\n            {\n                ans+=c;\n                c--;\n            }\n        }\n        else\n        {\n            ans+=a[i];\n            c=a[i];\n        }\n    }\n    printf(\"%I64d\", ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3071520435736f68ce6d02d3128d8123", "src_uid": "3c4b2d1c9440515bc3002eddd2b89f6f", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint cmpfunc(const void *a,const void *b)\n{\nreturn (*(int *)b - *(int *)a);\n}\nint main()\n{\nint n;\nscanf(\"%d\\n\",&n);\nint i,j;\n//int k=0;\nint a[n];\nfor(i=0;i<n;i++)\nscanf(\"%d\",&a[i]);\n//long long int count=a[0];\nint k=0;\nqsort(a,n,sizeof(int),cmpfunc);\nlong long int count=a[0];\nint count2=0;\nfor(i=1;i<n;i++)\n{\nif(a[i-1]==a[i])\ncount2++;\nif(a[i]-count2>0)\ncount+=a[i]-count2;\nif(i<n-1 && a[i]!=a[i+1])\n{\na[i]=a[i]-count2;\ncount2=0;\n}\nif(a[i]-count2<=0)\nbreak;\n}\nprintf(\"%lld\\n\",count);\n\n\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fd0ec688bb0e36a5e600968daf4ef450", "src_uid": "3c4b2d1c9440515bc3002eddd2b89f6f", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#define SIZE 100\n\nint cmp(const void *a, const void *b)\n{\n\treturn *((int *)b) - *((int *)a);\n}\n\nint main()\n{\n\tint n, i;\n\tint a[SIZE];\n\tint t;\n\tlong long l;\n\n//\tfreopen(\"input.txt\", \"r\", stdin);\n\n\tscanf(\"%d\", &n);\n\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d\", &a[i]);\n\n\tqsort(a, n, sizeof a[0], cmp);\n\n\tl = t = a[0];\n\n\tfor (i = 1; i < n; i++)\n\t\tif (t > a[i])\n\t\t\tl += t = a[i];\n\t\telse\n\t\t\tl += --t;\n\n\tprintf(\"%I64d\", l);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c936b8123c7f93f11b34bdbe2e89d547", "src_uid": "3c4b2d1c9440515bc3002eddd2b89f6f", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\nint cmpfunc (const void * a, const void * b)\n{\n   return ( *(long long int*)b - *(long long int*)a );\n}\nint main()\n{\n    long long int n,i,sum=0,ans=0,flag;\n    long long int a[30];\n    scanf(\"%I64d\",&n);\n    for(i=0;i<n;i++)\n        scanf(\"%I64d\",&a[i]);\n    qsort(a,n, sizeof(long long int), cmpfunc);\n    long long count=0;\n    flag=0;\n    for(i=1;i<n;i++)\n    {\n        if(flag==0)\n        {\n            if(a[i]==a[i-1])\n            {\n                count++;\n                //flag=1;\n            }\n            else\n            {\n                //count=0;\n                flag=1;\n            }\n        }\n        if(flag==1)\n        {\n            //printf(\"into cal count=%lld\\n\",count);\n            sum=sum+((count)*(count+1)/2);\n            count=0;\n            flag=0;\n        }\n\n    }\n    //printf(\"last count=%lld\\n\",count);\n         sum=sum+((count)*(count+1)/2);\n\n    //printf(\"sum=%d\\n\",sum);\n    for(i=0;i<n;i++)\n    {\n        ans+=a[i];\n    }\n    printf(\"%I64d\\n\",ans-sum);\n    return 0;\n}\n/*\n5\n5 5 5 5 5\n*/\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "875eac40e90cb9d107d56e209fab53d4", "src_uid": "3c4b2d1c9440515bc3002eddd2b89f6f", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\nvoid main()\r\n{  \r\n   long long M, N;\r\n   scanf(\"%ld%ld\", &M, &N);\r\n   if(N!=1)\r\n   {\r\n      printf(\"%ld\", (N-1)*M);\r\n   }\r\n   else{\r\n      printf(\"%ld\", M-N);\r\n   }\r\n\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "2968d86627ec972b0075a3c2f8e1287a", "src_uid": "a91aab4c0618d036c81022232814ef44", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\nvoid main()\r\n{  \r\n   long M, N;\r\n   scanf(\"%ld%ld\", &M, &N);\r\n   if(N!=1)\r\n   {\r\n      printf(\"%ld\", (N-1)*M);\r\n   }\r\n   else{\r\n      printf(\"%ld\", M-N);\r\n   }\r\n\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "eac481d890b26e2aac14ddc66ea36fd1", "src_uid": "a91aab4c0618d036c81022232814ef44", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\nint main()\r\n{\r\n    int n,m;\r\n    scanf(\"%d%d\",&n,&m);\r\n  int arr1[10000][10000],i,j;\r\n    int x=1;\r\n  for(i=0;i<n;i++)\r\n  {\r\n      for(j=0;j<m;j++)\r\n      {\r\n          \r\n          \r\n          arr1[i][j]+=x;\r\n          x++;\r\n      }\r\n  }\r\n    int count=0;\r\n \r\n  for(i=0;i<n;i++)\r\n  {\r\n     \r\n      for(j=0;j<m;j++)\r\n      {\r\n         //  printf(\"%d\\t\",arr1[i][j]);\r\n     \r\n        if ( (arr1[i][j+1] - arr1[i][j]) == 1)\r\n           {\r\n          count++;\r\n           }\r\n          if ( (arr1[i+1][j] - arr1[i][j]) == 1)\r\n             {\r\n            count++;\r\n             }\r\n      }\r\n   //   printf(\"\\n\");\r\n  }\r\n    printf(\"%d\\n\",count);\r\n    return 0;\r\n}\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0ed34a97a454bbbbeaff5e21b5e04712", "src_uid": "a91aab4c0618d036c81022232814ef44", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n\r\nvoid main()\r\n{\r\n    int n, m;\r\n    scanf(\"%d%d\", &n, &m);\r\n    if(m>1)\r\n        printf(\"%d\",n*(m-1));\r\n    if(m==1)\r\n         printf(\"%d\",(n-1)*m);\r\n}\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9f77780e4bba11df849a446f2649e3ed", "src_uid": "a91aab4c0618d036c81022232814ef44", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <stdlib.h>\r\nint main()\r\n{\r\n    int n,m;\r\n    scanf(\"%d%d\",&n,&m);\r\n   int arr1[1000][1000],i,j;\r\n    int x=1;\r\n  for(i=0;i<n;i++)\r\n  {\r\n      for(j=0;j<m;j++)\r\n      {\r\n          arr1[i][j]+=x;\r\n          x++;\r\n      }\r\n  }\r\n    int count=0;\r\n \r\n  for(i=0;i<n;i++)\r\n  {\r\n     \r\n      for(j=0;j<m;j++)\r\n      {\r\n         \r\n     \r\n        if ( (arr1[i][j+1] - arr1[i][j]) == 1)\r\n           {\r\n          count++;\r\n           }\r\n          if ( (arr1[i+1][j] - arr1[i][j]) == 1)\r\n             {\r\n            count++;\r\n             }\r\n      }\r\n   \r\n  }\r\n    printf(\"%d\\n\",count);\r\n    return 0;\r\n}\r\n\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b73b73ae726a13fcbdfc63f8beedc2f7", "src_uid": "a91aab4c0618d036c81022232814ef44", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n    long long int n,i,k,t;\n    scanf(\"%I64d\",&n);\n    t=1;\n    for(i=1;i<=n;i++){\n        if(n-1<=t){\n            printf(\"%I64d\\n\",i);\n            break;\n        }\n        t*=2;\n    }\n\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1901f16c89a7cd143f0dd14a1c3f87d2", "src_uid": "95cb79597443461085e62d974d67a9a0", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void) {\n\t// your code goes here\n\tlong int n,i=1,ans;\n\tscanf(\"%ld\",&n);\n\tlong int b[n];\n\tans=(i*(i+1))/2;\n\twhile((ans)<n)\n\t{\n\t     b[i]=ans;i++;\n\t     ans=(i*(i+1))/2;\n\t}\n\t\n\tprintf(\"%ld\\n\",i);\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1a02194c0eb63e52c882ac23893b88a0", "src_uid": "95cb79597443461085e62d974d67a9a0", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(void)\n{\n  int number,count,sum=0;\n  while(scanf(\"%d\",&number)!=EOF)\n    {\n         while(number)\n           count++;\n           number>>=1;\n            }\n      printf(\"%d\",count);\n    }\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "af790d653b8f1ac9a669083d1533f9c9", "src_uid": "95cb79597443461085e62d974d67a9a0", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "// \u2588\u2588\u2588\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2593\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\n// \u2588\u2588\u2588\u2593\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2593\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\u2588\u2588\u2593\u2593\u2593\u2593\u2588\u2593\u256c\u256c\u256c\u2593\u2588\n// \u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2593\u2588\u2588\u2588\u2588\u2588\u2593\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\u2588\u2588\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u256c\u256c\u2593\u2588\n// \u2588\u2588\u2588\u2588\u2593\u2593\u2593\u2593\u256c\u256c\u2593\u2588\u2588\u2588\u2588\u2588\u256c\u256c\u256c\u256c\u256c\u256c\u2588\u2588\u2588\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2588\n// \u2588\u2588\u2588\u2593\u2593\u2593\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\u2588\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\n// \u2588\u2588\u2588\u2588\u2593\u2593\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\n// \u2588\u2588\u2588\u2593\u2588\u2593\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2593\u2593\u2588\u2588\u2588\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2593\u256c\u256c\u256c\u256c\u2593\u2588\n// \u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2593\u2588\u2593\u256c\u256c\u256c\u256c\u256c\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2588\n// \u2588\u2588\u2588\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u256c\u256c\u2593\u2593\u2593\u2593\u2593\u2588\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\n// \u2588\u2588\u2588\u2588\u2593\u2593\u2593\u256c\u256c\u256c\u256c\u2593\u2593\u2593\u2593\u2593\u2593\u2588\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\n// \u2588\u2588\u2588\u2593\u2588\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\n// \u2588\u2588\u2588\u2588\u2588\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2588\u2593\u2593\u2593\u2588\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\n// \u2588\u2588\u2588\u2588\u2588\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2588\u2588\u2593\u2593\u2593\u2588\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2588\u2588\n// \u2588\u2588\u2588\u2588\u2588\u2593\u2593\u2593\u2593\u2593\u2588\u2588\u2588\u2588\u2593\u2593\u2593\u2588\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2588\u2588\n// \u2588\u2588\u2588\u2588\u2593\u2588\u2593\u2593\u2593\u2593\u2588\u2588\u2593\u2593\u2593\u2593\u2588\u2588\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2588\u2588\n// \u2588\u2588\u2588\u2588\u2593\u2593\u2588\u2588\u2588\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2588\u2588\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2588\u2593\u256c\u2593\u256c\u256c\u2593\u2588\u2588\n// \u2588\u2588\u2588\u2588\u2588\u2593\u2588\u2588\u2588\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2588\u2588\u2588\u2588\u2593\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2588\u2593\u256c\u256c\u256c\u256c\u256c\u2593\u2588\u2588\n// \u2588\u2588\u2588\u2588\u2588\u2593\u2593\u2588\u2593\u2588\u2588\u2588\u2593\u2593\u2593\u2588\u2588\u2588\u2588\u256c\u2593\u2588\u2593\u2593\u256c\u256c\u256c\u2593\u2593\u2588\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u2588\u2588\u2588\n// \u2588\u2588\u2588\u2588\u2588\u2588\u2593\u2588\u2588\u2593\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2593\u256c\u256c\u256c\u2593\u2593\u256c\u2593\u2593\u2588\u2588\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\u2588\u2588\n// \u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2593\u2588\u2588\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2588\u2588\u2588\u2588\n// \u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2593\u2593\u2588\u2588\u2593\u2593\u2593\u2593\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\u2588\u2588\u2588\n// \u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2593\u2593\u2593\u2588\u2588\u2588\u2588\u2588\u2593\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\u2588\u2588\u2588\u2588\n// \u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2593\u2593\u2593\u2588\u2593\u2593\u2593\u2593\u2593\u2588\u2588\u2588\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\u2588\u2588\u2588\u2588\u2588\n// \u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2593\u2593\u2593\u2588\u2593\u2593\u2593\u256c\u2593\u2588\u2588\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\u2588\u2588\u2588\u2588\u2588\u2588\n// \u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2593\u2593\u2588\u2593\u2593\u2593\u2593\u2588\u2588\u2588\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\n// \u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2593\u2593\u2593\u2588\u2588\u2588\u2593\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u256c\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\n// \u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2593\u2593\u2593\u2588\u2588\u2593\u2593\u256c\u256c\u256c\u256c\u256c\u256c\u2593\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\u2588\n\n\n// NEED TO DO THIS AGAIN\n#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long int\n#define MOD 1000000007\n\nint main(){\n\n    ll n;\n    cin>>n;\n\n    ll ans = -1;\n    for(ll i=1;i<=n;i++){\n        if(i*(i+1)/2 >= n){\n\n            ans = i;\n            break;\n        }\n    }\n    \n    cout<<ans<<endl;\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d4931497e84ff50fd750d242355415bc", "src_uid": "95cb79597443461085e62d974d67a9a0", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{int n,i=0;\n scanf(\"%d\",&n);\n while(n<pow(2,i)    \n {\n    i++;\n }\n printf(\"%d\",(i+1));\n return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a98a8d5150d855af17e9632f2b5f292a", "src_uid": "95cb79597443461085e62d974d67a9a0", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(){\n\n\tint a,b;\n\tscanf(\"%d%d\",&a,&b);\n\t\n\ttotal=100*a+10*b;\n\t\n\tif((total/220)%2==0)\n\t\tprintf(\"Hanako\\n\");\n\telse\n\t\tprintf(\"Ciel\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "54e36b0d7d5b8c6094406acc808ec093", "src_uid": "8ffee18bbc4bb281027f91193002b7f5", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main()\n{\n    int a,b;\n    scanf(\"%d%d\",&a,&b);\n    while(1)\n    {\n        if(b<2||(a*100+b*10)<220)\n        {\n            printf(\"Hanako\\n\");\n            return 0;\n        }\n        if(a>=2)\n        {\n            a-=2;\n            b-=2;\n        }\n        else\n        {\n            b-=(220-100*a);\n            a=0;\n        }\n        if(b<2||(a*100+b*10)<220)\n        {\n            printf(\"Ciel\\n\");\n            return 0;\n        }\n        if(b>=12)\n        {\n            ;b-=12;\n            a-=1;\n        }\n        else if(b>=22)\n        {\n          b-=22\n        }\n        else\n        {\n            a-=2;\n            b-=2;\n        }\n    }\n    return 0;\n}\n  \t \t\t\t \t\t \t \t\t\t\t \t\t\t   \t\t", "lang_cluster": "C", "compilation_error": true, "code_uid": "a3d49b616d942c46a1ce43adad65b8ec", "src_uid": "8ffee18bbc4bb281027f91193002b7f5", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\n\n\n int main()\n{\n  int x,y;\n   cin>>x>>y;\n\n  int i=1;\n  while(true)\n {\n   if(((100*x)+(10*y))<220)\n   {\n     if(i&1==1)\n     cout<<\"Hanako\";\n\n     else\n     cout<<\"Ciel\";\n\n    return 0;\n   }\n\n\n   if(i&1==1)\n  {\n     if(x>=2)\n    {\n      x-=2;\n      y-=2;\n    }\n    \n     else\n    {\n      x=0;\n      y-=((220-100*x))/10;\n    }\n  }\n\n  else\n   {\n     if(y>=22)\n     y-=22;\n\n     else if(y>=12)\n    {\n      x--;\n      y-=12;\n     }\n\n\n   else\n    {\n      x-=2;\n      y-=2;\n    }\n   }\n\n   i++;\n }\n\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d5fce323bb0c1f60a8412fe58573822f", "src_uid": "8ffee18bbc4bb281027f91193002b7f5", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main()\n{\n    int a,b;\n    scanf(\"%d%d\",&a,&b);\n    while(1)\n    {\n        if(b<2||(a*100+b*10)<220)\n        {\n            printf(\"Hanako\\n\");\n            return 0;\n        }\n        if(a>=2)\n        {\n            a-=2;\n            b-=2;\n        }\n        else\n        {\n            b-=(220-100*a);\n            a=0;\n        }\n        if(b<2||(a*100+b*10)<220)\n        {\n            printf(\"Ciel\\n\");\n            return 0;\n        }\n        if(b>=12)\n        {\n            ;b-=12;\n            a-=1;\n        }\n        else if(b>=22)\n        {\n          b-=22\n        }\n        else\n        {\n            a-=2;\n            b-=2;\n        }\n    }\n    return 0;\n}\n\t\t \t\t\t  \t   \t\t\t\t\t \t \t  \t \t", "lang_cluster": "C", "compilation_error": true, "code_uid": "21466fc4f9458d5857513174a85d2ab9", "src_uid": "8ffee18bbc4bb281027f91193002b7f5", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main()\n{\n    int a,b;\n    scanf(\"%d%d\",&a,&b);\n    if(a>2||(a*100+b*10)!=220)\n        printf(\"Hanako\\n\");\\\n        if(a>=2)\n        {\n            a-=2;\n            b-=2;\n        }\n        else\n        {\n            b-=(22-10*a);\n            a=0;\n        }\n        if(b<2||a*10+b<22)\n        {\n            printf(\"Ciel\\n\");\n            return 0;\n        }\n        if(b>=22)\n        {\n            b-=22;\n        }\n        else if(b>=12)\n        {\n            b-=12;\n            a-=1;\n        }\n        else\n        {\n            a-=2;\n            b-=2;\n        }\n}\n\t\t\t\t\t\t\t\t\t   \t\t\t   \t\t \t\t   \t", "lang_cluster": "C", "compilation_error": false, "code_uid": "9db9e962b06adadd083abbd49e61655e", "src_uid": "8ffee18bbc4bb281027f91193002b7f5", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char s[9][9];\n    int i,j,w[9],b[9],wneed=0,bneed=0,check[9][9],no1=0,no2=0,k;\n    for(i=0;i<8;i++){\n        scanf(\"%s\",s[i]);\n    }\n    for(i=0;i<8;i++){\n        for(j=0;j<8;j++){\n            check[i][j]=0;\n        }\n    }\n    for(i=0;i<8;i++){\n        for(j=0;j<8;j++){\n            if(s[i][j]=='W') check[i][j]=1;\n            else if(s[i][j]=='B') check[i][j]=2;\n        }\n    }\n    for(i=0;i<8;i++){\n        for(j=0;j<8;j++){\n                no1=0;\n            //printf(\"check[%d][%d] %d\\n\",i,j,check[i][j]);\n            if(check[i][j]==1){\n                for(k=i-1;k>=0;k--){\n                    //printf(\"checkkkk[%d][%d] %d\\n\",k,j,check[k][j]);\n                    if(check[k][j]==2){\n                        no1=1;break;\n                    }\n                }\n                //printf(\"no1 %d\\n\",no1);\n                if(no1==0) {\n                    wneed=i;\n                    //printf(\" wneed %d\\n\",wneed);\n                    break;\n                }\n            }\n        }\n        if(wneed !=0) break;\n    }\n    //printf(\"\\n\");\n    for(i=7;i>=0;i--){\n        for(j=0;j<8;j++){\n            no2=0;\n            //printf(\"check[%d][%d] %d\\n\",i,j,check[i][j]);\n            if(check[i][j]==2){\n                for(k=i+1;k<8;k++){\n                    //printf(\"checkkkkk[%d][%d] %d\\n\",k,j,check[k][j]);\n                    if(check[k][j]==1){\n                        no2=1;break;\n                    }\n                }\n                //printf(\"no2 %d\\n\",no2);\n                if(no2==0) {bneed=7-i;//printf(\"bneed %d\\n\",bneed);\n                break;}\n            }\n        }\n        if(bneed !=0) break;\n    }\n   // printf(\"w %d b %d\\n\",wneed,bneed);\n    if(bneed<wneed) printf(\"B\\n\");\n    else printf(\"A\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a083e218a1c570cd6bbce486192e68c1", "src_uid": "0ddc839e17dee20e1a954c1289de7fbd", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n \nstruct Pawns {\nint row[8];\nint coloumn[8];\nint count;\n};\n\n\nint main(void) {\n    // your code goes here\n    int i,j,min,max;\n    char pos[8][8];\n    struct Pawns White;\n    struct Pawns Black;\n    White.count=0;\n    Black.count=0;\n    for(i=0;i<9;i++)\n        for(j=0;j<9;j++)\n            scanf(\"%c\",&pos[i][j]);\n    \n    for(i=0;i<8;i++)\n        for(j=0;j<8;j++)\n            if(pos[i][j]=='W')\n            {\n                White.row[White.count]=i;   \n                White.coloumn[White.count]=j;\n                White.count++;\n            }else if(pos[i][j]=='B')\n            {\n                Black.row[Black.count]=i;   \n                Black.coloumn[Black.count]=j;\n                Black.count++;\n            }   \n    min=999;\n    for(i=0;i<White.count;i++){\n        if(min>White.row[i]){\n            for(j=0;j<Black.count;j++){\n                if(Black.coloumn[j]==White.coloumn[i]&&White.row[i]>Black.row[j]){\n                    break;\n                }\n            }\n            \n            if(j>=Black.count){\n                min=White.row[i];\n            }\n            \n        }\n    }\n    max=-1;\n    for(i=0;i<Black.count;i++){\n        if(max<Black.row[i]){\n            for(j=0;j<White.count;j++){\n                if(White.coloumn[j]==Black.coloumn[i]&&White.row[j]>Black.row[i]){\n                    \n                    break;\n                }\n            }\n            \n            if(j>=White.count){\n                max=Black.row[i];\n            }\n            \n        }\n    }\n    \n    if(min<=(7-max)){\n        \n        printf(\"A\");\n    }\n    else\n    printf(\"B\");\n    \n    \n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "15cb9daa16157e3a814cb79ec915375b", "src_uid": "0ddc839e17dee20e1a954c1289de7fbd", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n \nstruct Pawns {\nint row[8];\nint coloumn[8];\nint count;\n};\n\n\nint main(void) {\n    // your code goes here\n    int i,j,min,max;\n    char pos[8][8];\n    struct Pawns White;\n    struct Pawns Black;\n    White.count=0;\n    Black.count=0;\n    for(i=0;i<8;i++)\n        for(j=0;j<8;j++)\n            scanf(\"%c\",&pos[i][j]);\n    \n    for(i=0;i<8;i++)\n        for(j=0;j<8;j++)\n            if(pos[i][j]=='W')\n            {\n                White.row[White.count]=i;   \n                White.coloumn[White.count]=j;\n                White.count++;\n            }else if(pos[i][j]=='B')\n            {\n                Black.row[Black.count]=i;   \n                Black.coloumn[Black.count]=j;\n                Black.count++;\n            }   \n    min=999;\n    for(i=0;i<White.count;i++){\n        if(min>White.row[i]){\n            for(j=0;j<Black.count;j++){\n                if(Black.coloumn[j]==White.coloumn[i]){\n                    break;\n                }\n            }\n            \n            if(j>=Black.count){\n                min=White.row[i];\n            }\n            \n        }\n    }\n    max=-1;\n    for(i=0;i<Black.count;i++){\n        if(max<Black.row[i]){\n            for(j=0;j<White.count;j++){\n                if(White.coloumn[j]==Black.coloumn[i]){\n                    break;\n                }\n            }\n            \n            if(j>=White.count){\n                max=Black.row[i];\n            }\n            \n        }\n    }\n    \n    \n    if(min<=(7-max)){\n        \n        printf(\"A\");\n    }\n    else\n    printf(\"B\");\n    \n    \n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8951d7c630e67089dd2a0e8fd583d201", "src_uid": "0ddc839e17dee20e1a954c1289de7fbd", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nchar slova[300000],ideU[36];\nint main()\n{\n    int n,m,i,j;\n    char p,c1,c2;\n    scanf(\"%d%d\",&n,&m);\n    scanf(\"%c\",&p);\n    for (i=0;i<n;i++){\n        scanf(\"%c\",&slova[i]);\n    }\n    for (i=0;i<'z'-'a'+1;i++)\n        ideU[i]=i+'a';\n    for (i=0;i<m;i++){\n        scanf(\"%c\",&p);\n        scanf(\"%c%c%c\",&c1,&p,&c2);\n        for (j=0;j<('z'-'a'+1);j++){\n            if (ideU[j]==c2){\n                    ideU[j]=c1;\n            }\n            else{\n                if (ideU[j]==c1) {\n                        ideU[j]=c2;\n                }\n            }\n        }\n    }\n    for (i=0;i<n;i++){\n        slova[i]=ideU[slova[i]-'a'];\n    }\n    for (i=0;i<n;i++){\n        printf(\"%c\",slova[i]);\n    }\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5de3b880c568b01b63ca1b8b469a4e1b", "src_uid": "0ddc839e17dee20e1a954c1289de7fbd", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"oawnChess\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/oawnChess\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/oawnChess\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9d04e6cec3edea0a125339fd317ff214", "src_uid": "0ddc839e17dee20e1a954c1289de7fbd", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\n\n\nint main() {\n\tlong long n,p,w,d;\n\tscanf(\"%lld%lld%lld%lld\",&n,&p,&w,&d);\n\tlong long x,y,z;\n\t\tfor (y= 0;y<w;y++)\n\t\t{\t\n\t\t\tx=(p-d*y)/w;\n\t\t\tif((p-d*y)%w==0)\n\t\t\t{\n\t\t\t\tif(x+y>n||x<0) \n\t\t\t\t{\n\t\t\t\t\tprintf(\"-1\\n\");\n\t\t\t\t\tgoto x;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%lld %lld %lld\\n\",x,y,n-x-y);\n\t\t\t\t\tgoto x;\n\t\t\t\t} \n\t\t\t}\n\t\t}\n\t\tprintf(\"-1\\n\");\n\t\tx:{};\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0d3a1a554a127fd02589f38c76dc4932", "src_uid": "503116e144d19eb953954d99c5526a7d", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\ntypedef long long ll;\n\nint main()\n{\n    ll n,p,win,same,i,lose;\n    int w,d;\n    scanf(\"%I64d %I64d %d %d\",&n,&p,&w,&d);\n    for(i=0;i<10000000;i++)\n    {\n        same=i;\n        if((p-d*same)%w==0)\n        {\n            win=(p-same*d)/w;\n            lose=n-win-same;\n            if(win>=0&&lose>=0)\n            {\n                printf(\"%I64d %I64d %I64d\",win,same,lose);\n                return 0;\n            }\n        }\n    }\n    printf(\"-1\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7c2c7e827ed8d24c92ebd40f64849475", "src_uid": "503116e144d19eb953954d99c5526a7d", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\n\n\nint main() {\n\tlong long n,p,w,d;\n\tscanf(\"%lld%lld%lld%lld\",&n,&p,&w,&d);\n\tlong long x,y,z;\n\t\tfor (y= 0;y<w;y++)\n\t\t{\t\n\t\t\tx=(p-d*y)/w;\n\t\t\tif((p-d*y)%w==0)\n\t\t\t{\n\t\t\t\tif(x+y>n||x<0) \n\t\t\t\t{\n\t\t\t\t\tprintf(\"-1\\n\");\n\t\t\t\t\tgoto x:\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%lld %lld %lld\\n\",x,y,n-x-y);\n\t\t\t\t\tgoto x;\n\t\t\t\t} \n\t\t\t}\n\t\t}\n\t\tprintf(\"-1\\n\");\n\t\tx:{};\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "844cf9dfdfd6e723e39f193b4097b72f", "src_uid": "503116e144d19eb953954d99c5526a7d", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\n\n\nint main() {\n\tlong long n,p,w,d;\n\tscanf(\"%lld%lld%lld%lld\",&n,&p,&w,&d);\n\tlong long x,y,z;\n\t\tfor (y= 0;y<w;y++)\n\t\t{\t\n\t\t\tx=(p-d*y)/w;\n\t\t\tif((p-d*y)%w==0)\n\t\t\t{\n\t\t\t\tif(x+y>n||x<0) \n\t\t\t\t{\n\t\t\t\t\tprintf(\"-1\\n\");\n\t\t\t\t\tgoto x:\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%lld %lld %lld\\n\",x,y,n-x-y);\n\t\t\t\t\tgoto x:\n\t\t\t\t} \n\t\t\t}\n\t\t}\n\t\tprintf(\"-1\\n\");\n\t\tx:{};\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0678b33e762861840a5c146991420e18", "src_uid": "503116e144d19eb953954d99c5526a7d", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "long long n,p,z;int w,d,y;main(){for(scanf(\"%I64d%I64d%d%d\",&n,&p,&w,&d);y<w;y++){z=n-p/w-y;if(!((p|z)<0||p%w))return printf(\"%I64d %d %I64d\",p/w,y,z);}puts(\"-1\");}", "lang_cluster": "C", "compilation_error": false, "code_uid": "63ea9952644bead7118fa131c6a3f4ca", "src_uid": "503116e144d19eb953954d99c5526a7d", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define MAXN 1000002\n#define mod 1000000007\n\nchar vis[MAXN];\n\nlong long quickmi(long long a,int b)\n{\n    long long ans=1;\n\n    while(b)\n    {\n        if(b&1)ans=(ans*a)%mod;\n        a=(a*a)%mod;\n        b>>=1;\n    }\n    return ans;\n}\n\nint main()\n{\n    long long p,k,u;\n    int i,cnt;\n\n    scanf(\"%I64d%I64d\",&p,&k);\n    cnt=0;\n    for(i=1;i<p;i++)\n    {\n        if(!vis[i])\n        {\n            cnt++;\n            u=i;\n            while(!vis[u])\n            {\n                vis[u]=1;\n                u=(u*k)%p;\n            }\n        }\n    }\n    if(k==1)cnt++;\n    printf(\"%I64d\\n\",quickmi(p,cnt));\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "229d633a9d16862d0cb372bf8c0e0427", "src_uid": "580bf65af24fb7f08250ddbc4ca67e0e", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define MOD 1e9 + 7\n\nlong long power(long long a, long long b, long long m) {\n\tlong long c = 1;\n\tfor(; b; b >>= 1) {\n\t\tif(b & 1) {\n\t\t\tc = (c * a) % m;\n\t\t}\n\t\ta = (a * a) % m;\n\t}\n\treturn c;\n}\n\nlong long solve(long long p, long long k) {\n\tlong long ord, i;\n\n\tswitch(k) {\n\t\tcase 0:\n\t\treturn power(p, p-1, MOD);\n\t\tcase 1:\n\t\treturn power(p, p, MOD);\n\t}\n\tord = p - 1;\n\tfor(i = 2; i < ord; i++) {\n\t\tif(ord % i == 0) {\n\t\t\tif(power(k, ord / i, p) == 1) {\n\t\t\t\tord = ord / i;\n\t\t\t\ti--;\n\t\t\t}\n\t\t}\n\t}\n\treturn power(p, (p - 1) / ord, MOD);\n}\n\nint main() {\n\tlong long p, k;\n\n\tscanf(\"%I64d%I64d\", &p, &k);\n\tprintf(\"%I64d\\n\", solve(p, k));\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6ea42af95f53c632104fb1fc89956afe", "src_uid": "580bf65af24fb7f08250ddbc4ca67e0e", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\n#define MAXP 1000005\n\n#define MOD 1000000007\n\nint mat[MAXP];\nint p, k;\n\nint dfs (int a) {\n\t\n\tif (mat[a] == 1)\n\t\treturn 0;\n\t\n\tmat[a] = 1;\n\t\n\treturn dfs((k * a) % p);\n}\n\nint main () {\n\tint i;\n\tlong long res = 1;\n\t\n\tmemset(mat, 0, sizeof(int) * MAXP);\n\t\n\tscanf(\"%d %d\", &p, &k);\n\t\n\tfor (i = 1; i < p; i++) {\n\t\tif (!mat[i]) {\n\t\t\tdfs(i);\n\t\t\tres = ((res % MOD) * (p % MOD)) % MOD;\n\t\t}\n\t}\n\t\n\tif (k == 1) {\n\t\tres = ((res % MOD) * (p % MOD)) % MOD;\n\t}\n\t\n\tprintf(\"%I64d\\n\", res);\n\t\n\treturn 0;\n\t\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "86ffb5c57742ce91e6f2b85677d08ea6", "src_uid": "580bf65af24fb7f08250ddbc4ca67e0e", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define MOD 1000000007\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nint p, k;\nbool visited[1000010];\n\nint expo(int a, int b){\n    long long res = 1;\n\n    while (b){\n        if (b & 1) res = res * a % MOD;\n        a = (long long)a * a % MOD;\n        b >>= 1;\n    }\n    return res;\n}\n\nint main(){\n    int i, j, res, counter;\n\n    while (scanf(\"%d %d\", &p, &k) != EOF){\n        counter = 0;\n        clr(visited);\n        for (i = 0; i < p; i++){\n            if (!visited[i]){\n                counter++;\n                visited[i] = true;\n                j = (i * k) % p;\n                while (!visited[j]){\n                    visited[j] = true;\n                    j = (j * k) % p;\n                }\n            }\n        }\n\n        if (k == 1) res = expo(p, p);\n        else res = expo(p, --counter);\n        printf(\"%d\\n\", res);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0c82a29975980e210ea07a7688dc33de", "src_uid": "580bf65af24fb7f08250ddbc4ca67e0e", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\n#define m 1000000007\n\nlong long power( long long a, long long b ) {\n\tlong long x=a, y=b;\n\tlong long ans = 1;\n\twhile( y ) {\n\t\tif( y%2 )\n\t\t\tans = (ans*x)%m;\n\t\tx = (x*x)%m;\n\t\ty /= 2;\n\t}\n\treturn ans;\n}\n\nint main() {\n\tlong long k, p;\n\tscanf(\"%lld%lld\",&p, &k);\n\tif( k==0 )\n\t\tprintf(\"%lld\\n\", power(p,p-1));\n\tif( k==1 )\n\t\tprintf(\"%lld\\n\", power(p,p));\n\tlong long ord = 1;\n\n\tfor( ; k != 1; ++ord )\n\t\tk = (k*k)%p;\n\n\tprintf(\"%lld\\n\", power(p,(p-1)/ord));\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "96d9123cc3d355c9dc8a71799c852c43", "src_uid": "580bf65af24fb7f08250ddbc4ca67e0e", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <conio.h>\nint main()\n{\n\tint k,a[20],i,j,m=0,swap,s=0;\n\tscanf(\"%d\",&k);\n\tif(k==0)\n\t{\n\t\tprintf(\"0\");\n\t}\n\tfor(i=0;i<12;i++)\n\t{\n\t\tscanf(\"%d\",&a[i]);\n\t}\n\tfor(i=0;i<12;i++)\n\t{\n\t\n\t\telse if(a[i]>=k)\n\t\t{\n\t\t\tm=1;\n\t\t\tprintf(\"%d\",m);\n\t\t\tbreak;\n\t\t}\n\t\t\n\t}\n\tif(m!=1)\n\t{\n\t\tfor(i=0;i<11;i++)\n\t    {\n           for(j=0;j<11-i;j++)\n           {\n               if(a[j]<a[j+1])\n               {\n               \t  swap=a[j];\n               \t  a[j]=a[j+1];\n               \t  a[j+1]=swap;\n               }   \n            }      \n        }\n        for(i=0;i<12;i++)\n        {\n        \ts=s+a[i];\n        \tm=m+1;\n        \tif(s>=k)\n        \t{\n                printf(\"%d\",m);\n                break;\n        \t}\n        }\n\n\t}\n\treturn 0;\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0478accd788ac0167cb6965ff043afcc", "src_uid": "59dfa7a4988375febc5dccc27aca90a8", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint compare(const void *a,const void *b)\n{\n    return ( *(int*)a - *(int *)b );\n}\nint main()\n{\n    int n,i,s=0,p=0;\n    scanf(\"%d\",&n);\n    int a[12];\n    \n    for(i=0;i<12;i++)\n    scanf(\"%d\",&a[i]);\n    \n    qsort(a,12,sizeof(int),compare);\n \n   if(n!=0)\n{    for(i=11;i>=0;i--)\n    {\n      \n         s=s+a[i];\n         if(s<n)\n           p++;\n         else\n         { p++;\n          j++;\n           break;\n           \n         }\n    }\n    if(j==0)\n    printf(\"-1\");\n    else\n    printf(\"%d\",p);\n}\nelse\nprintf(\"0\");\n  \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "63b3f46ba4c2ef97ab1d4ac1454e7065", "src_uid": "59dfa7a4988375febc5dccc27aca90a8", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(void) {\n\tint k, count = 0;\n\tscanf(\"%d\", &k);\n\tif(!k){\n\t    printf(\"0\");\n\t    return 0;\n\t}\n\tint arr[12];\n\tfor(int i = 0; i < 12; i++) scanf(\"%d\", arr+i);\n\tfor(int i = 0; i < 12; i++){\n\t    int max = 0, index = i;\n\t    for(int j = 0; j < 12; j++){\n\t        if(arr[j]>max){\n\t            max = arr[j];\n\t            index = j;\n\t        }\n\t    }\n\t    if(k<=0){\n\t        printf(\"%d\", count);\n\t        break;\n\t    }\n\t    k -= max;\n\t    count++;\n\t    arr[index] = 0;\n\t}\n\tprintf(\"%d\", tot);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0158f9050acd721b2a3f25e19f659bf6", "src_uid": "59dfa7a4988375febc5dccc27aca90a8", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <conio.h>\nint main()\n{\n\tint k,a[20],i,j,m=0,swap,s=0;\n\tscanf(\"%d\",&k);\n\tfor(i=0;i<12;i++)\n\t{\n\t\tscanf(\"%d\",&a[i]);\n\t}\n\tfor(i=0;i<12;i++)\n\t{\n\t\tif(a[i]<=k)\n\t\t{\n\t\t\tm=1;\n\t\t\tprintf(\"%d\",m);\n\t\t\tbreak;\n\t\t}\n\t\t\n\t}\n\tif(m!=1)\n\t{\n\t\tfor(i=0;i<11;i++)\n\t    {\n           for(j=0;j<11-i;j++)\n           {\n               if(a[j]<a[j+1])\n               {\n               \t  swap=a[j];\n               \t  a[j]=a[j+1];\n               \t  a[j+1]=swap;\n               }   \n            }      \n        }\n        for(i=0;i<n;i++)\n        {\n        \ts=s+a[i];\n        \tm=m+1\n        \tif(s>=k)\n        \t{\n                printf(\"%d\",m);\n        \t}\n        }\n\n\t}\n\trturn 0;\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2667cd4618f8309688a2707c51b1625d", "src_uid": "59dfa7a4988375febc5dccc27aca90a8", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "void quicksort(int x[],int first,int last){\n    int pivot,j,temp,i;\n\n     if(first<last){\n         pivot=first;\n         i=first;\n         j=last;\n\n         while(i<j){\n             while(x[i]<=x[pivot]&&i<last)\n                 i++;\n             while(x[j]>x[pivot])\n                 j--;\n             if(i<j){\n                 temp=x[i];\n                  x[i]=x[j];\n                  x[j]=temp;\n             }\n         }\n\n         temp=x[pivot];\n         x[pivot]=x[j];\n         x[j]=temp;\n         quicksort(x,first,j-1);\n         quicksort(x,j+1,last);\n\n\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "56116dc3b63891704d6d23c8b79680e8", "src_uid": "59dfa7a4988375febc5dccc27aca90a8", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n//#include<conio.h>\n#include<stdlib.h>\n\n\nint fmax(int A[], int n, int B[] ){\n    int maxi=A[0]; int pos=0; int i; int k=0;\n    for( i=0;i<n;i++){\n        if(A[i]>=maxi){\n            maxi=A[i];\n            pos=i;\n    }}\n    if(pos!=0){\n    for(i=1;i<n;i++){\n        if(A[i]==maxi){\n            B[k++]=i;\n        }\n\n    }\n\n    return k;\n    }\n    return 0;\n}\n\nint mini(int a, int b){\n\nreturn (a<b)?a:b;}\n\n\nint main(){\n    int A[100], n, i, j , k, cnt=0, temp, B[100];\n\n   freopen(\"input.txt\", \"r\", stdin);\n    setbuf(stdout, NULL);\n\n    scanf(\"%d\", &n);\n    for(i=0;i<n;i++){\n        scanf(\"%d\", &A[i]);\n    }\n int flag=0;\n    while(1){\n    k=fmax(A,n, B);\n    if(k!=0){\n        for(i=0;i<k;i++){\n            A[0]++;\n            A[B[i]]--;\n            cnt++;\n\n                if(A[0]>A[B[i]]+1){\n                    flag=1;\n                    break;\n\n            }\n        }\n    }\n    else {flag=1;\n    break;}\n    }\n    if (flag)\n        printf(\"%d\", cnt);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4d306b216d0d882ba641a6ea39735c21", "src_uid": "aa8fabf7c817dfd3d585b96a07bb7f58", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n\nint Find_max_num(int *a,int n) //ne schitaya pervogo\n{\nint i;\nint max=1;\nint max_num;\n\nfor(i=1;i<n;i++)\n\tif(a[i]>=max)\n\t\t{\n\t\tmax=a[i];\n\t\tmax_num=i;\n\t\t}\n\nreturn max_num;\n}\n\nint main(void)\n{\nint i;\nint n; scanf(\"%d\",&n);\nint count=0;\nint max_num=-1;\n\nint a[n];\n\nfor(i=0;i<n;i++)\n scanf(\"%d\",&a[i]);\n\nwhile(a[0]<=a[Find_max_num(a,n)])\n\t{\n\tmax_num=Find_max_num(a,n);\n\ta[max_num]--;\n\ta[0]++;\n\tcount++;\n\t}\n\nprintf(\"%d\",count);\n\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1c7101269c5cd71fd2b1ea47bb215261", "src_uid": "aa8fabf7c817dfd3d585b96a07bb7f58", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\n\nint main()\n{\n    int n,i,j,vote,check=0;\n    int s[102];\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++){\n        scanf(\"%d\",&s[i]);\n    }\n    vote=0;\n    check=0;\n    while(check==0){\n        for(j=1;j<n;j++){\n            if(s[j]>s[0]){\n                s[0]=s[0]+1;s[j]=s[j]-1;\n                vote++;\n            }\n        }\n        for(i=1;i<n;i++){\n            if(s[i]>=s[0]) {check=0;break;}\n            else check =1;\n        }\n    }\n\n    printf(\"%d\\n\",vote);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6b5377ac90420cf16557cf4f5090e020", "src_uid": "aa8fabf7c817dfd3d585b96a07bb7f58", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main() \n{\n    int i,n,a[102],ans=0,max;\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++)\n\t\tscanf(\"%d\",&a[i]);\n\t\twhile(1)\n\t\t{\n\t\t\tmax=0;\n\t\t\tfor(i=0;i<n;i++)\n\t\t\tif(a[max]<=a[i])\n\t\t\tmax=i;\n\t\t\tif(max==0)\n\t\t\tbreak;\n\t\t\ta[0]++;\n\t\t\ta[max]--;\n\t\t    ans++;\n\t\t}\n\t\tprintf(\"%d\",ans);\n\t\tre\n\t\t }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e0a30c0c526c4dac41a2b723f7f9f5c0", "src_uid": "aa8fabf7c817dfd3d585b96a07bb7f58", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <cstdio>\nint n,val,a[1001];\nint ver(int cat)\n{\n    int nrver=val+cat,scad=0;\n    for(int i=1;i<n;i++)\n    {\n        if(nrver<a[i]) scad+=(a[i]-nrver+1);\n    }\n    if(scad<=cat) return 1;\n    return 0;\n}\nint main()\n{\n    scanf(\"%d\",&n);\n    scanf(\"%d\",&val);\n    for(int i=1;i<n;i++) scanf(\"%d\",&a[i]);\n    int inc=0,sf=1000,rasp=0;\n    while(inc<=sf)\n    {\n        int mij=(inc+sf)/2;\n        int rez=ver(mij);\n        if(rez==1)\n        {\n            rasp=mij;\n            sf=mij-1;\n        }\n        else inc=mij+1;\n    }\n    printf(\"%d\\n\",rasp);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "da132d73eb590cb59e2ec671940cac77", "src_uid": "aa8fabf7c817dfd3d585b96a07bb7f58", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\n\nint isluck(long long n)\n{\n\twhile (n)\n\t{\n\t\tif (n % 10 == 7 || n % 10 == 4)\n\t\t\tn /= 10;\n\t\telse\n\t\t\treturn 0;\n\t}\n\treturn 1;\n}\n\n\n\nlong long nearby(long long n)\n{\n\twhile (isluck(n) != 1)\n\t{\n\t\tn++;\n\t}\n\treturn n;\n}\n\nint main()\n{\n\tlong long  l, r;\n\n\twhile (~scanf(\"%lld %lld\", &l, &r))\n\t{\n\t\tlong long sum = 0;\n\n\t\twhile (l <= r)\n\t\t{\n\t\t\tint tmp = nearby(l);\n\t\t\tif (tmp > r)\n\t\t\t{\n\t\t\t\tsum += (r - l + 1) * tmp;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tsum += (tmp - l + 1) * tmp;\n\t\t\tl = tmp + 1;\n\t\t}\n\t\tprintf(\"%lld\\n\", sum);\n\t}\n\n\treturn 0;\n}\n\t  \t  \t \t\t\t\t\t\t\t\t  \t     \t\t\t \t\t\t", "lang_cluster": "C", "compilation_error": false, "code_uid": "d11cdd9ee406bcc04de0896a2bc9be0d", "src_uid": "8a45fe8956d3ac9d501f4a13b55638dd", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <inttypes.h>\n#include <math.h>\n\nint t[100];\nint tinv[100];\nint cont;\n\nvoid invertir(int x)\n{\t\n\tcont=0;\n\tint i=0,mo,di;\n\twhile(x !=0 )\n\t{\n\t\tmo = x%10;\n\t\tt[i] = mo;\n\t\ti++;\n\t\tx = x/10;\n\t\tcont++;\n\t}\n}\n\nvoid invertir_array(void)\n{\t\n\tint i;\n\tfor(i = 0; i<cont ;i++)\n\t{\n\t\ttinv[i] = t[cont-i-1];\n\t}\n}\nint64_t array_int(void)\n{\n\tint i = 0;\n\tint64_t sum = 0;\n\tfor(i = cont-1; i>=0;i--)\n\t{\n\t\tsum = sum + (int64_t)tinv[i]*(int)ceil((float)(pow(10,cont-i-1)));\n\t}\n\treturn sum;\n}\n\n\nint64_t next(int x)\n{\n\tint e=0;\n\tint guar;\n\tguar = x;\n\tint di,mo;\n\tint64_t p;\n\tint sea=0;\n\tint i;\n\t\n\t\n\t//lo invierto\n\tinvertir(x);\n\t\n\t\n\tfor(i =(cont-1); i>=0 ; i--)\n\t{\n\t\tif ( sea == 1 && t[i] != 4 )\n\t\t{\n\t\t\tt[i] = 4;\n\t\t}\n\t\t\n\t\tif ( t[i]< 4 && sea==0 )\n\t\t{\n\t\t\tt[i] = 4;\n\t\t\tsea = 1;\n\t\t}\n\t\tif( t[i]> 4 && t[i]< 7 && sea == 0)\n\t\t{\n\t\t\tt[i] = 7;\n\t\t\tsea = 1;\n\t\t}\n\t\tif( t[i] > 7 && i==(cont-1) && sea ==0 )\n\t\t{\n\t\t\tt[i] = 4;\n\t\t\tt[i+1] = 4;\n\t\t\tcont++;\n\t\t\tsea = 1;\n\t\t}\n\t\tif( t[i] > 7 && i!=(cont-1) && sea == 0 )\n\t\t{\n\t\t\tt[i] = 4;\n\t\t\tsea = 1;\n\t\t}\n\t\tif( (t[i] == 4 && (t[i-1]==8 || t[i-1]==9) ) && sea == 0 )\n\t\t{\n\t\t\tt[i-1] = 4;\n\t\t\tt[i] = 7;\n\t\t\tsea = 1;\n\t\t}\n\t\tif( (t[i] == 7 && (t[i-1]==8 || t[i-1]==9)) && sea ==0 )\n\t\t{\n\t\t\tt[i] = 8;\n\t\t\tt[i-1] = 7;\n\t\t\ti = (cont-1)+1;\n\t\t\t//sea = 1;\n\t\t}\n\t\t\n\t}\n\n\tinvertir_array();\n\tp = array_int();\n\treturn p;\n\t\n}\n\n\nint main(void)\n{\n\tint i,j,ini,fin,n;\n\tint64_t s=0;\n\tscanf(\"%d\",&ini); //inicio\n\tscanf(\"%d\",&fin); //fin\n\t\n\tfor(i=ini;i<=fin;i++)\n\t{\n\t\ts += next(i);\n\t}\n\tprintf(\"%\" PRId64 \"\\n\",s);\n\t\n\n\n\t\n\t\n\n\t\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f7ec900046e9b362ad30baf96cf75e1d", "src_uid": "8a45fe8956d3ac9d501f4a13b55638dd", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint next(int x)\n{\n\tint e=0;\n\tint guar;\n\tguar = x;\n\tint di,mo;\n\t\n\twhile( x != 0 )\n\t{\t\n\t\tmo = x%10;\n\t\tif( mo == 4 || mo == 7)\n\t\t{\n\t\t\tx = x/10;\n\t\t}\n\t\telse\n\t\t{  \n\t\t    x = guar+1;\n\t\t    guar = x;\n\t\t}\n\t\t\n\t}\n\treturn guar;\n\n\t\n\t\n}\n\n\nint main(void)\n{\n\tint i,j,ini,fin,n,s=0;\n\tscanf(\"%d\",&ini); //inicio\n\tscanf(\"%d\",&fin); //fin\n\t\n\tfor(i=ini;i<=fin;i++)\n\t{\n\t\ts += next(i);\n\t}\n\tprintf(\"%d\",s);\n\n\t\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "67dbd379a41b232c27d4593c8675bec4", "src_uid": "8a45fe8956d3ac9d501f4a13b55638dd", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n\nint k[20];\n\n__int64 P(__int64 n){\n    memset(k,0,sizeof(k));\n    int i,j;\n    i=0;\n    while(n){\n        k[i++]=n%10;\n        n/=10;\n    }\n    int m=i-1;\n    for(i=m;i>=0;i--){\n        if(k[i]>7){\n            for(j=i;j<=m;j++){\n                if(k[j]>7){\n                    k[j+1]=k[j+1]+1;\n                    if(j+1>m)\n                        m=j+1;\n                    k[j]=0;\n                }\n            }\n            break;\n        }\n    }\n    __int64 sum=0;\n    for(i=m;i>=0;i--){\n        if(k[i]<4){\n            sum=sum*10+4;\n            for(j=i-1;j>=0;j--){\n                sum=sum*10+4;\n            }\n            break;\n        }\n        else if(k[i]==4){\n            sum=sum*10+4;\n        }\n        else if(k[i]<7){\n            sum=sum*10+7;\n            for(j=i-1;j>=0;j--){\n                sum=sum*10+4;\n            }\n            break;\n        }\n        else if(k[i]==7){\n            sum=sum*10+7;\n        }\n    }\n    return sum;\n}\n\nint main(void){\n    __int64 i,x,y,sum,k;\n    scanf(\"%I64d %I64d\",&x,&y);\n    sum=0;\n    k=0;\n    for(i=x;i<=y;i++){\n        if(k<i){\n            k=P(i);\n        }\n        sum+=k;\n    }\n    printf(\"%I64d\\n\",sum);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0891d7ddca3952dd5f6897244c727a2b", "src_uid": "8a45fe8956d3ac9d501f4a13b55638dd", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define N 10000000000ll\n__int64 a[1000],queue[1000];\nint main()\n{\n    int l,r,front=0,rear=0,i=1,j,k;\n    __int64 sum,temp;\n    queue[rear++]=4;\n    queue[rear++]=7;\n    a[0]=0;\n    while(i)\n    {\n        temp=queue[front];\n        front++;\n        a[i]=temp;\n        if(a[i]>N) break;\n        i++;\n        queue[rear++]=temp*10+4;\n        queue[rear++]=temp*10+7;\n    }\n    while(~scanf(\"%d%d\",&l,&r))\n    {\n        sum=0;\n        for(k=l;k<=r;k++)\n         for(j=1;j<=i;j++)\n         {\n             if(k>a[j-1]&&k<=a[j]) \n              {\n                 sum+=a[j];\n                 break;\n              }\n         }\n         printf(\"%I64d\\n\",sum);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5e6aed8e3e2441109fc99164921d0061", "src_uid": "8a45fe8956d3ac9d501f4a13b55638dd", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\nint main()\n{\n\tint i,j,c=0,c1=0,l;\n\tchar s[105];\n\tgets(s);\n\tl=strlen(s);\n\tfor(i=0;i<6;i++)\n\t{\n\t\tif(s[i]=='1')\n\t\t{\n\t\t\ts[i]='0';\n\t\t}\n\t}\n\tfor(i=0;i<l;i++)\n\t{\n\t\tif(s[i]=='0')\n\t\t{\n\t\t\tc++;\n\t\t}\n\t\telse if(s[i]=='1')\n\t\t{\n\t\t\tc1++;\n\t\t\t}\n\t\t}\n\t}\n\tif(c>=6 && c1>=1)\n\tprintf(\"yes\");\n\telse\n\tprintf(\"no\");\n}\n\t\t", "lang_cluster": "C", "compilation_error": true, "code_uid": "c208638aa7648bb490dc4e0368a9a90e", "src_uid": "88364b8d71f2ce2b90bdfaa729eb92ca", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "# include <stdio.h>\n\nint main()\n{\n    char d, c=0;\n    while((d=getchar())!='1');\n    while((d=getchar())!=EOF) {\n        if(d=='0')\n            c++;\n    if(c>=6)\n        printf(\"yes\");\n    else\n        printf(\"no\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3bad9970b28b75aa2d919d49a49f61dc", "src_uid": "88364b8d71f2ce2b90bdfaa729eb92ca", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"practice\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/practice\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/practice\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a4b9fa64d32961dc4a4ff9cffb520915", "src_uid": "88364b8d71f2ce2b90bdfaa729eb92ca", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    char ch[101];\n    int x=0,y=0,i;\n    scanf(\"%s\",ch);\n    for(i=0;ch!='\\0';i++)\n    {\n        if(ch[i]=='1')\n        x=1;\n        else if(x==1)\n        ++y;\n    }\n    if(y>6)\n    printf(\"yes\");\n    else\n    printf(\"no\")\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8fb7455f6d3361cad2861894fd58526f", "src_uid": "88364b8d71f2ce2b90bdfaa729eb92ca", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(){\n    char str[150];\n    scanf(\"%s\",str);\n    int len = strlen(str);\n    if(len<7){\n        printf(\"no\\n\");\n    }\n    int j=0;\n    while(str[j] != '1' && str[j]  != '\\0'){\n        j++;\n    }\n    if(j==len){\n        printf(\"no\\n\");\n    }\n    int i,cnt=0;\n    for(i=j+1;i<len;i++){\n        if(str[i]=='0'){\n            cnt++;\n        }\n    }\n    if(cnt>5){\n        printf(\"yes\\n\");\n    }\n    else{\n        printf(\"no\\n\";)\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0b851c0573c6ff4221ef5fc16ec8ad65", "src_uid": "88364b8d71f2ce2b90bdfaa729eb92ca", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\nint main()\n{\n int a,b,c,count=0;\n scanf(\"%d %d %d\",&a,&b,&c);\n if((a+b)>>c&&(b+c)>>a&&(a+c)>>b)\n {\n  printf(\"%d\",&0);\n }\n else\n {\n  while((a+b)<<c)\n  a=a+1;\n  count=count+1;\n ((b+c)<<a)\n b=b+1;\n count=count+1;\n ((c+a)<<b)\n c=c+1;\n count=count+1;\n }\n}\n \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fa5bf6a3876b62e1bd45eaecf7fec992", "src_uid": "3dc56bc08606a39dd9ca40a43c452f09", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint a,b,c,t=0,max;\n\tscanf(\"%d %d %d\",&a,&b,&c);\n\tif(a>b&&a>c)\n\t{\n\t\tmax=a;\n\t}\n\telse if(b>a && b>c)\n\t{\n\t\tmax=b;\n\t}\n\telse\n\t{\n\t\tmax=c;\n\t}\n\tint r=(a+b+c)-max;\n\twhile(max>=r)\n\t{\n\t\tr=r+1;\n\t\tt=t+1\n\t}\n\tprintf(\"%d\",t);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e54455883633730b6cf065fe50515c41", "src_uid": "3dc56bc08606a39dd9ca40a43c452f09", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int a,b,c; \n    scanf(\"%d%d%d\",&a,&b,&c\");\n    if(a>=b+c) \n    printf(\"%d%d%d\",a-b-c-1);\n    else  if(b>=a+c) \n    printf(\"%d%d%d\",b-a-c-1);\n    else if(c>=b+c) \n    printf(\"%d%d%d\",c-b-a-1);\n    else\n    printf(\"0\"); \n    }\n    ", "lang_cluster": "C", "compilation_error": true, "code_uid": "962dbd7e0bdc8815fd1b5f623deb68ed", "src_uid": "3dc56bc08606a39dd9ca40a43c452f09", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n int a , b , c ;\n scanf(\"%d%d%d\",&a,&b,&c) ;\n int k ;\n  \n a>b ? (a>c ? a : c) :(b>c ? b : c) ;\n\n(2*k-(a+b+c))>0 ? printf(\"0\") : printf(\"%d\",(2*k-(a+b+c)+1)) ;", "lang_cluster": "C", "compilation_error": true, "code_uid": "fc342347eabaf75ab793cbbee9f57cb6", "src_uid": "3dc56bc08606a39dd9ca40a43c452f09", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\n#include<cstdio>\nusing namespace std;\n\nclass Triangle {\n    public:\nint i;\nint j;\nint temp;\nint a[3];\nint m;\n\nvoid get() {\nfor (i=0;i<3;i++) {\ncin>>a[i];\n}\n\n}\n\nvoid sort() {\n for (i=0;i<3;i++) {\n    for (j=i;j<3;j++) {\n        if (a[i]<a[j]) {\n            temp=a[i];\n            a[i]=a[j];\n            a[j]=temp;\n        }\n    }\n\n }\n\n}\n\nvoid checkingmin() {\nif (a[0]>=(a[1]+a[2]))\n    m=(a[0]-(a[1]+a[2]))+1;\nelse m=0;\n\n\n}\n\nvoid show() {\ncout<<m<<endl;\n\n\n}\n\n\n};\n\nint main() {\nTriangle ob;\nob.get();\nob.sort();\nob.checkingmin();\nob.show();\nreturn 0;\n\n\n}\n\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8df4e5f01a549b128f9edad316de48cd", "src_uid": "3dc56bc08606a39dd9ca40a43c452f09", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#define ll long long int \nint main()\n{\n\tll a,b;\n\tscanf(\"%I64d%I64d\",&a,&b);\n\tif(a==b)\n\t{\n\t\tprintf(\"infinity\\n\");\n\t}\n\telse\n\t{\n\t\tll i,num=a-b;\n\t\tll ans=1;\n\t\tfor(i=2;i<=sqrt(num);i++)\n\t\t{\n\t\t\tif(num%i==0)\n\t\t\t{\n\t\t\t\tif(a%i==b)\n\t\t\t\t{\n\t\t\t\t\tans+=1;\n\t\t\t\t}\n\t\t\t\tif(i!=num/i)\n\t\t\t\t{\n\t\t\t\t\tif(a%(num/i)==b)\n\t\t\t\t\t{\n\t\t\t\t\t\tans+=1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tprintf(\"%I64d\\n\"ans);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ece176633b41af674a80e4badf61d01c", "src_uid": "6e0715f9239787e085b294139abb2475", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#define ll long long int \nll inline inp()\n{\n    ll n=0,a=1;\n    char c=getchar_unlocked();\n    while(c < '0' || c >'9') {if(c=='-'){a=-1;}c=getchar_unlocked();}\n    while(c>='0' && c<='9')\n    {\n    n=(n<<3)+(n<<1)+c-'0';\n    c=getchar_unlocked();\n    }\n    return a*n;\n}\nvoid print(ll X)\n{\n  if(X<0) { putchar_unlocked('-');  X=-X;  }\n  int Len=0,Data[20];\n  while(X) { Data[Len++]=X%10; X/=10; }\n  if(!Len) Data[Len++]=0;\n  while(Len--) putchar_unlocked(Data[Len]+48);\n  putchar_unlocked('\\n');\n}\nint main()\n{\n\tll a,b;\n\ta=inp();b=inp();\n\tif(a==b)\n\t{\n\t\tprintf(\"infinity\\n\");\n\t}\n\telse\n\t{\n\t\tll i,num=a-b;\n\t\tll ans=1;\n\t\tfor(i=2;i<=sqrt(num);i++)\n\t\t{\n\t\t\tif(num%i==0)\n\t\t\t{\n\t\t\t\tif(a%i==b)\n\t\t\t\t{\n\t\t\t\t\tans+=1;\n\t\t\t\t}\n\t\t\t\tif(i!=num/i)\n\t\t\t\t{\n\t\t\t\t\tif(a%(num/i)==b)\n\t\t\t\t\t\tans+=1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tprint(ans);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "24d0ab6edb371f1cb13c8ef142d5176b", "src_uid": "6e0715f9239787e085b294139abb2475", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\nint main()\n{\n    int a, b, c;\n    int i, sqtc, con;\n    scanf(\"%d %d\", &a, &b);\n    if (a < b)\n        return 0;\n    if (a == b)\n        printf(\"infinity\\n\");\n    else\n    {\n        c = a - b;\n        if (c < b)\n            printf(\"0\\n\");\n        else\n        {\n            con = 1;\n            sqtc = sqrt(double(c));\n            if (sqtc>b)\n            {\n                for (i = 2; i < b; ++i)\n                if (c%i == 0)\n                    ++con;\n                for (i = b + 1; i < sqtc; ++i)\n                if (c%i == 0)\n                    con += 2;\n            }\n            else\n            {\n                sqtc = c / b;\n                if (c%b != 0)\n                    ++sqtc;\n                for (i = 2; i < sqtc; ++i)\n                if (c%i == 0)\n                    ++con;\n            }\n            printf(\"%d\\n\", con);\n        }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "28474d2656e9029b2cef531ca89eb3ba", "src_uid": "6e0715f9239787e085b294139abb2475", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#define ll long long int \nll inline inp()\n{\n    ll n=0,a=1;\n    char c=getchar_unlocked();\n    while(c < '0' || c >'9') {if(c=='-'){a=-1;}c=getchar_unlocked();}\n    while(c>='0' && c<='9')\n    {\n    n=(n<<3)+(n<<1)+c-'0';\n    c=getchar_unlocked();\n    }\n    return a*n;\n}\nvoid print(ll X)\n{\n  if(X<0) { putchar_unlocked('-');  X=-X;  }\n  int Len=0,Data[20];\n  while(X) { Data[Len++]=X%10; X/=10; }\n  if(!Len) Data[Len++]=0;\n  while(Len--) putchar_unlocked(Data[Len]+48);\n  putchar_unlocked('\\n');\n}\nint main()\n{\n\tll a,b;\n\tscanf(\"%I64d%I64d\",&a,&b);\n\tif(a==b)\n\t{\n\t\tprintf(\"infinity\\n\");\n\t}\n\telse\n\t{\n\t\tll i,num=a-b;\n\t\tll ans=1;\n\t\tfor(i=2;i<=sqrt(num);i++)\n\t\t{\n\t\t\tif(num%i==0)\n\t\t\t{\n\t\t\t\tif(a%i==b)\n\t\t\t\t{\n\t\t\t\t\tans+=1;\n\t\t\t\t}\n\t\t\t\tif(i!=num/i)\n\t\t\t\t{\n\t\t\t\t\tif(a%(num/i)==b)\n\t\t\t\t\t\tans+=1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tprintf(\"%I64d\\n\"ans);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a7630cecbf75d981811a51f5f378c235", "src_uid": "6e0715f9239787e085b294139abb2475", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "By Ahmet098, contest: Codeforces Round #282 (Div. 2), problem: (B) Modular Equations, Wrong answer on test 4, #\n\n#include<stdio.h>\n#include<math.h>\n\nint main()\n{\n    long long a,b,i,fark,count=0,x;\n\n    scanf(\"%lld %lld\",&a,&b);\n\n\n    fark=a-b; \n    \n    if(a==0 && b==0)\n    {\n        printf(\"0\");\n        return 0;\n      }\n    \n    if(a==0)\n    {\n    printf(\"infinity\");\n        return 0;\n    }\n\n\n    if(b==0)\n    {\n        for(i=1;i<(int)sqrt(fark);i++)\n        {\n        if(fark%i==0)\n        {\n            if((fark/i)>b)\n            count++;\n            if(i>b)\n            count++;\n        }\n        }\n        x=sqrt(fark);\n        if(x>b && fark%x==0)\n        {\n            count++;\n        }\n        printf(\"%lld \",count);\n        return 0;\n    }\n\n    if(b%a==0)\n    {\n        printf(\"infinity\");\n        return 0;\n    }\n    if(a<b*2)\n    {\n        printf(\"0\");\n        return 0;\n    }\n    if(fark>b)\n        count++;\n    for(i=2;i<(int)sqrt(fark);i++)\n    {\n        if(fark%i==0)\n        {\n            if((fark/i)>b)\n            count++;\n            if(i>b)\n            count++;\n        }\n    }\n    x=sqrt(fark);\n    if(x>b && fark%x==0)\n        {\n            count++;\n        }\n    printf(\"%lld \",count);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c6369654ca94f6a89b41882dee3d7031", "src_uid": "6e0715f9239787e085b294139abb2475", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "//\u592a\u590d\u6742\u4e86\uff01\n#include<stdio.h>\nint abs(int a){\n\tif(a<0)return -a;\n\telse return a;\n}\nint v1,v2;\nint t,d;\nint max;\nint distance;\nvoid dfs(int vs,int time){\n\t//printf(\"dfs(%d,%d)\\n\",vs,time);\n\tif(time-2==0){\n\t\tdistance+=vs;\n\t\tdistance+=v2;\n\t\tif(distance>max){\n\t\t\tmax=distance;\n\t\t}\n\t\tdistance-=vs;\n\t\tdistance-=v2;\n\t\treturn;\n\t}\n\tint i;\n\tfor(i=vs-d;i<=vs+d;i++){\n\t\tif(i>=0 && abs(v2-i)<=(time-2)*d){\n\t\t\t//\u6ee1\u8db3\u8fd9\u4e2a\u6761\u4ef6\u7684vt\u624d\u53ef\u4ee5\u5230\u8fbe\u7ec8\u70b9\u901f\u5ea6\uff01\n\t\t\tdistance+=vs;\n\t\t\tdfs(i,time-1);\n\t\t\tdistance-=vs;\n\t\t}\n\t}\n}\nint main() {\n\tscanf(\"%d%d\",&v1,&v2);\n\tscanf(\"%d%d\",&t,&d);\n\tmax=0;\n\tdistance=0;\n\tint i;\n\tif(v1==v2){\n\t\tfor(i=2;i<=t;i++){\n\t\t\tdistance+=v1;\n\t\t\tdistance+=(i/2)*d;\n\t\t}\n\t\tdistance+=v2;\n\t\tprintf(\"%d\\n\",distance);\n\t}else{\n\t\tdfs(v1,t);\n\t\tprintf(\"%d\\n\",max);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0e0f24fb84fc560ddfe0d2d7dc4c3e93", "src_uid": "9246aa2f506fcbcb47ad24793d09f2cf", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nusing namespace std;\n\ntypedef long long int ll;\nconst ll mod=1e9+7;\n\nint main()\n{\n    ll v1,v2,t,d,i,j,k,sum=0;\n    scanf(\"%lld %lld %lld %lld\",&v1,&v2,&t,&d);\n    if(d==0) printf(\"%lld\",v1*t);\n    else if(v1<=(t-1)*d)\n    {\n    \tj=v1;\n\t\tfor(i=0;i<t;i++)\n\t\t{\n\t\t\tsum+=j;\n\t\t\tj+=2;\n\t\t}\n\t}\n    else{\n    if(t%2==0) k=t/2;\n\telse k=(t+1)/2;\n\tj=v1;\n\tfor(i=0;i<k;i++)\n\t{\n\t\tsum+=j;\n\t\tj+=2;\n\t}\n\tj=v2;\n\tfor(i=k;i<t;i++)\n\t{\n\t\tsum+=j;\n\t\tj+=2;\n\t}\n\t\n\t}\n\tprintf(\"%lld\",sum);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1d8b10a0a65379d9754d72346fe8c8ef", "src_uid": "9246aa2f506fcbcb47ad24793d09f2cf", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "//\u592a\u590d\u6742\u4e86\uff01\n#include<stdio.h>\nint abs(int a){\n\tif(a<0)return -a;\n\telse return a;\n}\nint v1,v2;\nint t,d;\nint max;\nint distance;\nvoid dfs(int vs,int time){\n\t//printf(\"dfs(%d,%d)\\n\",vs,time);\n\tif(time-2==0){\n\t\tdistance+=vs;\n\t\tdistance+=v2;\n\t\tif(distance>max){\n\t\t\tmax=distance;\n\t\t}\n\t\tdistance-=vs;\n\t\tdistance-=v2;\n\t\treturn;\n\t}\n\tint i;\n\tfor(i=vs-d;i<=vs+d;i++){\n\t\tif(abs(v2-i)<=(time-2)*d){\n\t\t\t//\u6ee1\u8db3\u8fd9\u4e2a\u6761\u4ef6\u7684vt\u624d\u53ef\u4ee5\u5230\u8fbe\u7ec8\u70b9\u901f\u5ea6\uff01\n\t\t\tdistance+=vs;\n\t\t\tdfs(i,time-1);\n\t\t\tdistance-=vs;\n\t\t}\n\t}\n}\nint main() {\n\tscanf(\"%d%d\",&v1,&v2);\n\tscanf(\"%d%d\",&t,&d);\n\tmax=0;\n\tdistance=0;\n\tdfs(v1,t);\n\tprintf(\"%d\\n\",max);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3d59b03dffd5778abefe7f0831f3b55e", "src_uid": "9246aa2f506fcbcb47ad24793d09f2cf", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int v1, v2, t, d, limit, distance=0, i;\n    scanf(\"%d %d %d %d\", &v1, &v2, &t, &d);\n    for(i=0;i<t;i++)\n    {\n        limit= v2+((t-2)-i)*d;\n        distance=distance+v1;\n        if(v1+d>limit)\n        {\n            v1=limit;\n        }\n        else\n        {\n            v1=v1+d;\n        }\n    }\n\n    printf(\"%d\", distance);\n\n    main();\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "af0e39fcc018d51d82da19a1b005ce8f", "src_uid": "9246aa2f506fcbcb47ad24793d09f2cf", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "//\u592a\u590d\u6742\u4e86\uff01\n#include<stdio.h>\nint abs(int a){\n\tif(a<0)return -a;\n\telse return a;\n}\nint v1,v2;\nint t,d;\nint max;\nint distance;\nvoid dfs(int vs,int vt,int time){\n\tif(time==t-1){\n\t\t//\u8fd9\u4e2a\u65f6\u5019\uff0c\u6211\u4eec\u5e94\u8be5\u6309\u7167\u8981\u6c42\u7684\u901f\u5ea6\u5230\u8fbe\u4e86\uff01\n\t\t//\u6211\u4eec\u53ef\u4ee5\u6309\u9650\u5236\u7684\u901f\u5ea6\u5230\u8fbe\u7ec8\u70b9\n\t\tif(abs(vs-v2)<=d){\n\t\t\t//printf(\"dfs(%d,%d,%d)\\n\",vs,vt,time);\n\t\t\tdistance+=vs;\n\t\t\tdistance+=v2;\n\t\t\tif(distance>max){\n\t\t\t\tmax=distance;\n\t\t\t}\n\t\t\tdistance-=vs;\n\t\t\tdistance-=v2;\n\n\t\t}\n\t\treturn;\n\t}\n\tint i;\n\tfor(i=-d;i<=d;i++){\n\t\tif(vt+i>=0){\n\t\t\tdistance+=vs;\n\t\t\tdfs(vt,vt+i,time+1);\n\t\t\tdistance-=vs;\n\t\t}\n\t}\n}\nint main() {\n\tscanf(\"%d%d\",&v1,&v2);\n\tscanf(\"%d%d\",&t,&d);\n\tmax=0;\n\tdistance=0;\n\tdfs(0,v1,0);\n\tprintf(\"%d\\n\",max);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9eeaa845f1dfdac06ba011834894ee67", "src_uid": "9246aa2f506fcbcb47ad24793d09f2cf", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#!/usr/bin/python2.7\n\n\ndef my_func():\n\ttry:\t\n\t\ta=10/0;\n\texcept: \n\t\tprint \"Exception caught here\";\ntry:\n\tmy_func();\nexcept: \n\tprint \"Line last\";", "lang_cluster": "C", "compilation_error": true, "code_uid": "7ad3b87e7f80085a3789c9d5d00f5324", "src_uid": "c1b071f09ef375f19031ce99d10e90ab", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<algorithm>\n#include<cmath>\n#include<stack>\nusing namespace std;\ntypedef long long ll;\nchar a[105],book[26];\nint main()\n{\n\tint k,len,i;\n\tscanf(\"%d\",&k);\n\tscanf(\"%s\",a);\n\tlen=strlen(a);\n\tmemset(book,0,sizeof(book));\n\tif(k>len)\n\t{\n\t\tprintf(\"NO\\n\");\n\t}\n\telse\n\t{\n\t\tint sum=0;\n\t\tfor(i=0;i<len;i++)\n\t\t{\n\t\t\tif(!book[a[i]-'a'])\n\t\t\t\tsum++;\n\t\t\tbook[a[i]-'a']++;\n\t\t}\n\t\tif(sum>=k)\n\t\tprintf(\"YES\\n\");\n\t\telse\n\t\tprintf(\"NO\\n\");\n\t\tmemset(book,0,sizeof(book));\n\t\tint t=1;\n\t\tbook[a[0]-'a']++;\n\t\tprintf(\"%c\",a[0]);\n\t\tfor(i=1;i<len;i++)\n\t\t{\n\t\t\tif(t==k)\n\t\t\t{\n\t\t\t\tprintf(\"%c\",a[i]);\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif(!book[a[i]-'a'])\n\t\t\t{\n\t\t\t\tbook[a[i]-'a']++;\n\t\t\t\tt++;\n\t\t\t\tprintf(\"\\n%c\",a[i]);\n\t\t\t}\n\t\t\telse\n\t\t\t\tprintf(\"%c\",a[i]);\t\n\t\t}\n\t}\n\t\treturn 0;\t\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f8a4fec718ece34f8ff7566f71bc635e", "src_uid": "c1b071f09ef375f19031ce99d10e90ab", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(){\n\tint a,panjang,start,i,arr[200],j,jmlsub=0,cek[200]={0},proceed=0;\n\tbool proceed;\n\tchar input[200];\n\tscanf(\"%d\",&a);\n\tscanf(\"%s\",input);\n\tpanjang=strlen(input);\n\t//cek[input[0]]++;\n\tif(a>=1){\n\t\tfor(i=0;i<panjang;i++){\n\t\t\tcek[input[i]]++;\n\t\t\tif (cek[input[i]]==1){\n\t\t\t\tjmlsub++;\n\t\t\t\tarr[jmlsub]=i;\n\t\t\t\ta--;\n\t\t\t}\n\t\t\tif(a<1){\n\t\t\t\tproceed=1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tarr[jmlsub+1]=panjang;\n\t}\n\telse\n\t\tproceed=1;\n\tif (proceed==1){\n\t\tprintf(\"YES\\n\");\n\t\tstart=0;\n\t\tfor(i=1;i<=jmlsub;i++){\n\t\t\tfor(j=arr[i];j<arr[i+1];j++){\n\t\t\t\tprintf(\"%c\",input[j]);\n\t\t\t}\n\t\t\tstart=arr[i+1];\n\t\t\tprintf(\"\\n\");\n\t\t}\n\t}\n\telse {\n\t\tprintf(\"NO\\n\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7b92d7badd85fcc3c355b77849e936ac", "src_uid": "c1b071f09ef375f19031ce99d10e90ab", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#define K 26\n#define N 100\n#define CHAR 256\nint main() {\n  int k;\n  scanf(\"%d\",&k);\n  char q[N+1];\n  scanf(\"%s\",q);\n  int see[CHAR+1];\n  int i;\n  for(i=0;i<=CHAR;i++) {\n    see[i]=0;\n  }\n  char s[K][N+1];\n  int nk=0;\n  int ns[K];\n  for(i=;i<K;i++) {\n    ns[i]=0;\n  } \n  int nq=strlen(q);\n  for(i=0;i<nq;i++) {\n    if(!see[q[i]]) {\n      see[q[i]]=1;\n      s[nk][0]=q[i];\n      s[nk][1]='\\0';\n      ns[nk]=1;\n      nk++;\n      if(nk==k) {\n      /*\u628a\u5269\u4f59\u7684\u5b57\u7b26\u4e32\u5168\u90e8\u7ed9\u6700\u540e\u4e00\u4e2a*/\n        int j;\n        for(j=i+1;j<nq;j++) {\n          s[k][ns[k]]=q[j];\n          ns[k]++;\n        }\n        s[k][ns[k]]='\\0';\n      }\n    } else {\n      /*\u628a\u5f53\u524d\u5b57\u7b26\u6dfb\u52a0\u5230\u524d\u4e00\u4e2a\u5b57\u7b26\u4e32\u4e0a*/\n      s[nk-1][ns[nk-1]]=q[i];\n      s[nk-1][ns[nk-1]+1]='\\0';\n      ns[nk-1]++;\n    }\n  }\n  if(nk!=k) printf(\"NO\\n\");\n  else {\n    printf(\"YES\\n\");\n    for(i=0;i<k;i++) {\n      printf(\"%s\\n\",s[i]);\n    }\n  }\n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2ab43fee87bf3d76338dfbdddecb262e", "src_uid": "c1b071f09ef375f19031ce99d10e90ab", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#define gc getchar\n#define pc putchar\n#define MOD 1000000007\n\ntypedef long long ll;\n\ninline ll scan()\n{\n   \tll n = 0;\n   \tll ch = gc();\n   \tll sign = 1;\n   \twhile(ch < '0' || ch > '9')\n\t{\n\t\tif(ch == '-')\n\t\t\tsign = -1;\n   \t\tch = gc();\n\t}\n   \twhile(ch >= '0' && ch <= '9')\n\t\tn = (n << 3) + (n << 1) + ch - '0', ch = gc();\n   n = n * sign;\n   return n;\n}\n\ninline void writeInt (ll n)\n{\n\tll N = n, rev, count = 0;\n\trev = N;\n\tif(N < 0)\n\t{\n\t\tN = -N;\n\t\tpc('-');\n\t}\n\tif (N == 0) { pc('0'); pc('\\n'); return ;}\n\twhile ((rev % 10) == 0) { count++; rev /= 10;}\n\trev = 0;\n\twhile (N != 0) { rev = (rev<<3) + (rev<<1) + N % 10; N /= 10;}\n\twhile (rev != 0) { pc(rev % 10 + '0'); rev /= 10;}\n\twhile (count--) pc('0');\n}\n\nchar ip[101];\nint found[27];\n\nint main()\n{\n\tll k, i, cnt = 0, n;\n\tk = scan();\n\tscanf(\"%s\", ip);\n\tn = strlen(ip);\n\tfor(i = 0; i < n; i++)\n\t{\n\t\tfound[ip[i] - 97] = 1;\n\t}\n\tfor(i = 0; i < 27; i++)\n\t\tif(found[i] == 1)\n\t\t\tcnt += 1;\n\tif(cnt >= k)\n\t{\n\t\tcnt = 1;\n\t\tprintf(\"YES\\n\");\n\t\tfor(i = 0; i < n-1; i++)\n\t\t{\n\t\t\tif((ip[i] != ip[i+1]) && cnt < k)\n\t\t\t{\n\t\t\t\tpc(ip[i]);\n\t\t\t\tpc('\\n');\n\t\t\t\tcnt += 1;\n\t\t\t}\n\t\t\telse pc(ip[i]);\n\t\t}\n\t\tpc(ip[i]);\n\t\tpc('\\n');\n\t}\n\telse printf(\"NO\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "49d93d1972316d2ebc551a7841ed4a2e", "src_uid": "c1b071f09ef375f19031ce99d10e90ab", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<limits.h>\n#include<stdlib.h>\n#include<ctype.h>\n#include<math.h>\nint main(){\n\tlong long int a,b,c,d,e;\n\tint cnt=0;\n\n\tscanf(\"%lld%lld%lld%lld%lld\",&a,&b,&c,&d,&e);\n\tlong long int res = 0;\n\tlong long int res1 =0;\n\tres= ((a/b)*d) + ( abs((a/b) - ((a/b+a/c)-(a/(b*c))) ) * e);\n\tres1= ((a/c)*e) + ( abs((a/c) - ((a/b+a/c)-(a/(b*c))) ) * d);\n\tif(res>res1){\n\t\tprintf(\"%lld\",res);\n\t}\n\telse printf(\"%lld\",res1);\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2ed48874fb6011a0c523dff44bae645f", "src_uid": "35d8a9f0d5b5ab22929ec050b55ec769", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "\n#include<iostream>\n#include<cstdio>\n#include<cmath>\n#include<cstring>\n#include<queue>\n#include<vector>\n#include<algorithm>\nusing namespace std;\n#define inf 0x3f3f3f3f\n#define ll long long\n \nll gcd(ll x,ll y){\n    if(y==0) return x;\n    else return(gcd(y,x%y));\n}\n \nll lcm(ll x,ll y){\n    return x*y/gcd(x,y);\n}\n \nint main()\n{\nll n,a,b,p,q;\n    while(~scanf(\"%lld%lld%lld%lld%lld\",&n,&a,&b,&p,&q))\n    {\n        ll lm=lcm(a,b);\n        printf(\"%lld\\n\",(n/a)*p+(n/b)*q-min(p,q)*(n/(lm)));\n \n \n    }\n    return 0;\n\n/* 1535729986494 */\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4534fbc358cf68d17a2afbd5a39cda79", "src_uid": "35d8a9f0d5b5ab22929ec050b55ec769", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <stdint.h>\n#include <assert.h>\n#include <math.h>\n\nint main()\n{\n        int64_t n, a, b, p, q, s;\n        while (scanf(\"%lld%lld%lld%lld%lld\", &n, &a, &b, &p, &q) > 0) {\n                int64_t i = 1;\n                s = 0;\n                s += (n / a) * p;\n                s += (n / b) * q;\n                s -= (n / (a * b)) * (p > q ? q i: p);\n                printf(\"%lld\\n\", s);\n        }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "031e8fd5ad502663d9c112227a776fe3", "src_uid": "35d8a9f0d5b5ab22929ec050b55ec769", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "from math import gcd\n\nwhile True:\n        try:\n                n, a, b, p, q = map(int, input().split())\n                s = (n // a) * p\n                s += (n // b) * q\n                s -= (n // ((a * b) // gcd(a, b))) * min(p, q)\n                print(int(s))\n        except EOFError:\n                break", "lang_cluster": "C", "compilation_error": true, "code_uid": "02e034d172e31cbfe563eb1379b68d16", "src_uid": "35d8a9f0d5b5ab22929ec050b55ec769", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<vector>\n#include<algorithm>\nusing namespace std;\n#define inf 0x3f3f3f3f\n#define ll long long\n \nll gcd(ll x,ll y){\n    if(y==0) return x;\n    else return(gcd(y,x%y));\n}\n \nll lcm(ll x,ll y){\n    return x*y/gcd(x,y);\n}\n \nint main()\n{\nll n,a,b,p,q;\n    while(~scanf(\"%lld%lld%lld%lld%lld\",&n,&a,&b,&p,&q))\n    {\n        ll lm=lcm(a,b);\n        printf(\"%lld\\n\",(n/a)*p+(n/b)*q-min(p,q)*(n/(lm)));\n \n \n    }\n    return 0;\n\n/* 1535729852745 */\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "933c0d2f723da14afc5b3163606bc123", "src_uid": "35d8a9f0d5b5ab22929ec050b55ec769", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int n = 0;\n    scanf(\"%d\", &n);\n\n    if (n < 3) {\n        printf(\"1\\n\");\n    } else {\n        printf(\"%d\\n\", (n / 3) * 2 + 1);\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3e5b1c80d0caf574074603d9be9dc2e7", "src_uid": "a993069e35b35ae158d35d6fe166aaef", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#iclude<stdio.h>\nint main()\n{\n\tint a;\n\tscanf(\"%d\", &a);\n\tif (1<=a && a<=10^9){\n\tif (a%3==0)\n\t\tprintf(\"%d\", a/3*2);\n\telse if (a%3!=0)\n\t\tprintf(\"%d\", a/3*2+1);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bdbc4bf356804e27cfee61e4bb56590d", "src_uid": "a993069e35b35ae158d35d6fe166aaef", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main () {\n  int n\n  scanf(\"%d\", &n);\n  printf(\"%d\\n\", 2*(n/3) + (n%3 != 0));\n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a0e042850daf808719609f8f5bf9dabc", "src_uid": "a993069e35b35ae158d35d6fe166aaef", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2b4e621e75a6c0c3afd13c8f5a5ba47a", "src_uid": "a993069e35b35ae158d35d6fe166aaef", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{   long long int n,;\nint sum;\n    scanf(\"%I64D\",&n);\n    int k=n/3;\n    int j=n%3;\n    if(j!=0)\n        sum=k*2+1;\n    else\n        sum=k*2;\n\n    printf(\"%d\",sum);\n\n    return(0);\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "48938d0c488820f58c4585db7c69d26f", "src_uid": "a993069e35b35ae158d35d6fe166aaef", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\ndouble a[10][10];\nint n;\nvoid dd(int x,int y,double t)\n{\n\ta[x][y]+=t;\n\tif(a[x][y]>1)\n\t{\n\t\tdouble num=(a[x][y]-1)/2;\n\t\ta[x][y]=1;\n\t\tint tx=x+1;\n\t\tint ty=y+1;\n\t\tif(tx<n)\n\t\t{\n\t\t\tdd(tx,y,num);\n\t\t\tdd(tx,ty,num);\n\t\t}\n\t}\n}\nint main()\n{\n\t\n\tint t;\n\twhile(scanf(\"%d%d\",&n,&t)!=EOF)\n\t{\n\t\tmemset(a,0,sizeof(a));\n\t\tdd(0,0,t);\n\t\tint i,j;\n\t\tint counter=0;a\n\t\tfor(i=0;i<n;i++)\n\t\t{\n\t\t\tfor(j=0;j<=i;j++)\n\t\t\t{\n\t\t\t\tif(a[i][j]==1)\n\t\t\t\t\tcounter++;\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\",counter);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4962dd16f330a212b32b57439d9c4464", "src_uid": "b2b49b7f6e3279d435766085958fb69d", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "void main()\n{\n    int n,t,num,i,j,k;\n    while( scanf(\"%d %d\",&n,&t)!=EOF ) {\n        num=0;\n        double a[n][n];\n        for(i=0;i<n;i++) {\n            for(j=0;j<=i;j++) {\n                a[i][j] = 0;\n            }\n        }\n        for(i=0;i<t;i++) {\n            a[0][0]++;\n            for(j=0;j<n;j++){\n                for(k=0;k<=j;k++) {\n                    if(j == n-1) {\n                        if( a[j][k]>1 ) a[j][k]=1;\n                    }\n                    else {\n                        if(a[j][k]>1) {\n                            a[j+1][k] += (a[j][k]-1)/2.0;\n                            a[j+1][k+1] += (a[j][k]-1)/2.0;\n                            a[j][k] = 1;\n                        }\n                    }\n                }\n            }\n        }\n        for(i=0;i<n;i++) {\n            for(j=0;j<=i;j++) {\n                num += (a[i][j] == 1) ;\n            }\n        }\n        printf(\"%d\\n\",num);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "466c9f426ca91cbd9def9b66326299dd", "src_uid": "b2b49b7f6e3279d435766085958fb69d", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "double M[15][15],v;\nint n,t,i,j;\nmain()\n{\n    scanf(\"%d%lf\",&n,M);\n    for(;i<n;i++)\n        for(j=0;j<=i;j++)\n        M[i][j]>=1?t++,M[i+1][j]+=v=(M[i][j]-1)/2,M[i+1][j+1]+=v:0;\n    printf(\"%d\n           \",t);\n}\n/*2017-10-19 20:59:37.772*/", "lang_cluster": "C", "compilation_error": true, "code_uid": "4346acf481559be065a23bd6602a8d13", "src_uid": "b2b49b7f6e3279d435766085958fb69d", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\ndouble a[10000][100000];\nint main(){\n\tint n,t,i,j,count=0;\n\tscanf(\"%d%d\",&n,&t);\n\ta[1][1]=t;\n\tfor(i=1;i<=n;i++){\n\t\tfor(j=1;j<=i;j++){\n\t\t\tif(a[i][j]>=1){\n\t\t\t\ta[i+1][j] += (a[i][j]-1)/2;\n\t\t\t\ta[i+1][j+1] += (a[i][j]-1)/2;\n\t\t\t\tcount++;\n\t\t\t}\t\t\n\t\t}\n\t}\n\tprintf(\"%d\\n\",count);\n}\t", "lang_cluster": "C", "compilation_error": true, "code_uid": "3553f8125e564fdbd9e6ea6866724b58", "src_uid": "b2b49b7f6e3279d435766085958fb69d", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\ndouble  cup[10000][10000];\nint main (){\n  int h , t ;\n  scanf(\"%d%d\",&h,&t);\n  for(int i=0;i<h;i++)\n    for(int j=0;j<h;j++)\n      cup[i][j]=0;\n  cup[0][0] = t;\n  int cnt = 0;\n  for (int i = 0;i<h;i++){\n    for (int j = 0;j<=i;j++){\n        if(cup[i][j]>=1){\n          double x = cup[i][j] - 1;\n          cup[i][j] = 1;\n          cup[i+1][j]+= x/2.0;\n          cup[i+1][j+1]+= x/2.0;\n          cnt++;\n        }\n    }\n  }\n  printf(\"%d\\n\",cnt);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d49dc2858ae4be0eda0891771ba19313", "src_uid": "b2b49b7f6e3279d435766085958fb69d", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main() \n{\n\tlong long int x,y,m,cnt=0;\n\tscanf(\"%lld\",&x);\n\tscanf(\"%lld\",&y);\n\tscanf(\"%lld\",&m);\n\t\n\tif(x>=m || y>=m)\n\t{\n\t\tprintf(\"%d\\n\",0);\n\t\treturn 0;\n\t}\n\tif(x<=0 && y<=0)\n\t{\n\t\tprintf(\"%d\\n\",-1);\n\t\treturn 0;\n\t}\n\tif(x>y)\n\t{\n\t\tlong long int tmp = x;\n\t\tx=y;\n\t\ty=tmp;\n\t}\n\tif(x<0)\n\t{\n\t\tcnt += -x/y;\n\t\tx+=y * cnt\n\t}\n\twhile(x<m && y<m)\n\t{\n\t\tif(x<y)\n\t\t\tx+=y;\n\t\telse\n\t\t\ty+=x;\n\t}\n\tprintf(\"%d\\n\",cnt);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "855a5bbd486ccd67cfe22be75eec5e5f", "src_uid": "82026a3c3d9a6bda2e2ac6e14979d821", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n\nusing namespace std;\n\nint main(){\n    \n    long long int x;\n    long long int y;\n    long long int m;\n    \n    cin>>x>>y>>m;\n    int contador;\n    for(contador=0;x<m&&y<m;contador++){\n         \n         if(x<y){\n                 if(x>=x+y){\n                 \n                           printf(\"-1\");\n                           return 0;\n                 }\n                 x=x+y;\n                 \n         }\n         else{\n              if(y>=x+y){\n              \n                        printf(\"-1\");\n                        return 0;\n              \n              }\n              y=x+y;        \n         \n         }\n         \n    }\n    printf(\"%d\",contador);\n    return 0;\n    \n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "04b241b524d08045ab6e187113417471", "src_uid": "82026a3c3d9a6bda2e2ac6e14979d821", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main() \n{\n\tlong long int x,y,m,count=0;\n\tscanf(\"%lld\",&x);\n\tscanf(\"%lld\",&y);\n\tscanf(\"%lld\",&m);\n\t\n\tif(x>=m || y>=m)\n\t{\n\t\tprintf(\"%d\\n\",0);\n\t\treturn 0;\n\t}\n\tif(x<=0 && y<=0)\n\t{\n\t\tprintf(\"%d\\n\",-1);\n\t\treturn 0;\n\t}\n\tif(x>y)\n\t{\n\t\tlong long int tmp = x;\n\t\tx=y;\n\t\ty=tmp;\n\t}\n\tif(x<0)\n\t{\n\t\tcnt += -x/y;\n\t\tx+=y * cnt\n\t}\n\twhile(x<m && y<m)\n\t{\n\t\tif(x<y)\n\t\t\tx+=y;\n\t\telse\n\t\t\ty+=x;\n\t}\n\tprintf(\"%d\\n\",cnt);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9a7c36ff4b30523dfe53694968256286", "src_uid": "82026a3c3d9a6bda2e2ac6e14979d821", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    long long int x, y, m;\n    long long int count;\n    scanf(\"%I64d\", &a);\n    scanf(\"%I64d\", &b);\n    scanf(\"%I64d\", &m);\n    if (x>=m || y>=m)\n    {\n        count = 0;\n        printf(\"%I64d\\n\", count);\n        return 0;\n    }\n    if((x<=0 && y<=0))\n    {\n        count = -1;\n        printf(\"%I64d\\n\", count);\n        return 0;\n    }\n    count = 0;\n    if (x<0)\n    {\n        count = (-1*x)/y;\n        x = y*count + x;\n    }\n    if (y<0)\n    {\n        count = (-1*y)/x;\n        y = x*count + y;\n    }\n    while(x<m && y<m)\n    {\n\n        if(x>=y)\n        {\n            y = x+y;\n            count++;\n        }\n        else\n        {\n            x = x+y;\n            count++;\n        }\n    }\n    printf(\"%I64d\\n\", count);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b168fc335f83694fb79ca84b1cd941fd", "src_uid": "82026a3c3d9a6bda2e2ac6e14979d821", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nlong long x,y,m,moves,temp;\nscanf(\"%I64d%I64d%I64d\",&x,&y,&m);\nif( x<m && y<m && x<=0 && y<=0) \n{\n        printf(\"-1\"); getch();\n        return 0;\n}\nif(x>=m || y>=m)\n{\nprintf(\"0\");\nreturn 0;\n}\nif(y<x) \n{ \ntemp=x;\nx=y;\ny=temp;\n}\nif(x<0)\n{\nmoves = (-x)/y;\n    x += y*moves;\n}\nwhile(x<m || y<m)\n{ \n   moves++;\n   if(x<y) x+=y;\n   else    y+=x;\n}\nprintf(\"%I64d\",moves-1);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8398ee98a5839551a503f3c893831518", "src_uid": "82026a3c3d9a6bda2e2ac6e14979d821", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\nint main()\r\n{\r\n    int x,a[2][2],b[1000];\r\n    scanf(\"%d\",&x);\r\n    printf(\"\\n\");\r\n    for(int z=1;z<=x;z++)\r\n    {for (int i=0;i<2;i++)\r\n    {for (int j=0;j<2;j++)\r\n    {\r\n    a[i][j]=0;\r\n    }}\r\n    \r\n        for (int i=0;i<2;i++)\r\n    {for (int j=0;j<2;j++)\r\n    {\r\n    scanf(\"%d\",&a[i][j]);\r\n    }}\r\n        if (a[1][1]+a[1][2]+a[2][2]+a[2][1]==4)\r\n        b[z]=2;\r\n        else if (a[1][1]+a[1][2]+a[2][2]+a[2][1]==0)\r\n        b[z]=0;\r\n        else b[z]=1;\r\n        //for (int l=0;l<2;l++)\r\n        //{printf(\"\\n\");\r\n            for (int m=0;m<2;m++)\r\n        {\r\n        //printf(\"%d \",a[l][m]);\r\n        }}\r\n    }\r\n    \r\n    for (int k=0;k<=x;k++)\r\n    printf(\"%d\\n\",b[k]);\r\n    \r\n    \r\n    \r\n    \r\n    \r\n    \r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "39844b7a2b516a9f3b568a8020bd1060", "src_uid": "7336b8becd2438f0439240ee8f9610ec", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "// Online C compiler to run C program online\r\n#include <stdio.h>\r\n\r\nint main() {\r\n    // Write C code here\r\n    int t;\r\n    scanf(\"%d\",&t);\r\n    while (t--){\r\n        int arr[4];\r\n        int count=0;\r\n        int oneCount=0;\r\n        scanf(\"%d %d\",&arr[0],&arr[1]);\r\n        scanf(\"%d %d\",&arr[2],&arr[3]);\r\n        for(int i=0;i<4;i++){\r\n            if (arr[i]==1){\r\n                oneCount+=1;\r\n            }\r\n        }\r\n        if (oneCount==4){\r\n            printf(\"%d\",2\\n);\r\n        }\r\n        else if (oneCount==0) printf(\"%d\\n\",0);\r\n        else{\r\n            printf(\"%d\\n\",1);\r\n        }\r\n        \r\n    }\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "416038dac7dbb3916692c4d977110094", "src_uid": "7336b8becd2438f0439240ee8f9610ec", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "\r\n#include <stdio.h>\r\n#include <math.h>\r\n#include <bool.h>\r\n\r\nint main() {\r\n    int t; scanf(\"%d\",&t);\r\n    while(t--) {\r\n        bool a[2][2]; int ans=0; \r\n        for(int i=0;i<2;i++) {\r\n            for(int j=0;j<2;j++) {\r\n                scanf(\"%d\",&a[i][j]) if(a[i][j])ans++;\r\n                \r\n            }\r\n        }\r\n\r\n       \r\n        if(ans>1) cout<<(int)log2(ans)<<endl;\r\n        else if(ans==0) cout<<\"0\\n\";\r\n        else if(ans==1) cout<<\"1\\n\";\r\n    }\r\n\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "792e9257ce4ce8dc9addbf44114359b7", "src_uid": "7336b8becd2438f0439240ee8f9610ec", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n\r\nint mai(){\r\n\tint x; \r\n\tint ctr= 0 ; \r\n\tfor(int i = 0 ; i<4 ; i++){\r\n\t\tscanf(\"%d\" , &x); \r\n\t\tif(x==1){\r\n\t\t\tctr++; \r\n\t\t}\r\n\t}\r\n\tif(ctr ==0){\r\n\t\tprintf(\"0\");\r\n\t\treturn \r\n\t}\r\n\tif(ctr == 1 ||ctr==2 || ctr ==3){\r\n\t\tprintf(\"1\"); \r\n\t\treturn ; \r\n\t}\r\n\tif (ctr ==4){\r\n\t\tprintf(\"2\"); \r\n\t\treturn ; \r\n\r\n\t}\r\n\treturn 0 ; \r\n}\r\n\r\nint main(){\r\n\tint t ; \r\n\tscanf(\"%d\" , &t);\r\n\tfor(int i = 0 ; i<t ; i++){\r\n\t\tmai();}\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3c4ca29b24fb733445f7c711b4c8cb8b", "src_uid": "7336b8becd2438f0439240ee8f9610ec", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\nint main()\r\n{\r\n    int t,T,c[4],ans;\r\n\r\n    scanf(\"%d\",&T)\r\n    for(int i=1;i<=T;t++){\r\n        scanf(\"%d %d %d %d\",c[0],c[1],c[2],c[3]);\r\n        for(int j=0;j<4;j++){\r\n            if(c[j]==0){\r\n                ans++;\r\n            }\r\n        }\r\n    }\r\n\r\nreturn 0;\r\n}\r\n\r\n\r\n\r\n\r\n            \r\n            \r\n        \r\n        \r\n            ", "lang_cluster": "C", "compilation_error": true, "code_uid": "a779c3ae0dd738bc2e81dd639a918e7b", "src_uid": "7336b8becd2438f0439240ee8f9610ec", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint a,b,x1,y1,x2,y2;\nclrscr();\nscanf(\"%d%d%d%d%d%d\",&a,&b,&x1,&y1,&x2,&y2);\nif(((x1+x2<=a)&&(max(y1,y2)<=b))||((y1+x2<=b)&&(max(y2,x1)<=a))||((y2+x1<=b)&&(max(x2,y1)<=a))||((x1+x2<=b)&&(max(y1,y2)<=a))||((y1+y2<=b)&&(max(x1,x2)<=a))||((y1+y2<=a)&&(max(x1,x2)<=b))||((y2+x1<=a)&&(max(x2,y1)<=b))||((y1+x2<=a)&&(max(x1,y2)<=b)))\nprintf(\"YES\");\nelse\nprintf(\"NO\");\nreturn 0;\n}\nint max(int x ,int y)\n{\nint t;\nif(x>=y)\nt=x;\nelse\nt=y;\nreturn t;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "54f4543207ea6b7af1415f755ccb0a5c", "src_uid": "2ff30d9c4288390fd7b5b37715638ad9", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": ".#include<stdio.h>\n#include<stdlib.h>\n\n\nint main()\n{\n   int a1,a2,a3,b1,b2,b3;\n   int p,q,r,s;\n   scanf(\"%d %d %d %d %d %d\",&a1,&b1,&a2,&b2,&a3,&b3);\n   p=a2+a3;\n   if(p<=a1)\n   {\n   if(b2<=b1 && b3<=b1)\n   {\n   printf(\"YES\\n\");\n   return 0;\n   }\n   }\n   if(p<=b1)\n   {\n   if(b2<=a1 && b3<=a1)\n   {\n   printf(\"YES\\n\");\n   return 0;\n   }\n   }\n\n   p=a2+b3;\n   if(p<=a1)\n   {\n   if(b2<=b1 && a3<=b1)\n   {\n   printf(\"YES\\n\");\n   return 0;\n   }\n   }\n   if(p<=b1)\n   {\n   if(b2<=a1 && a3<=a1)\n   {\n   printf(\"YES\\n\");\n   return 0;\n   }\n   }\n\n   p=b2+a3;\n   if(p<=a1)\n   {\n   if(a2<=b1 && b3<=b1)\n   {\n   printf(\"YES\\n\");\n   return 0;\n   }\n   }\n   if(p<=b1)\n   {\n   if(a2<=a1 && b3<=a1)\n   {\n   printf(\"YES\\n\");\n   return 0;\n   }\n   }\n\n   p=b2+b3;\n   if(p<=a1)\n   {\n   if(a2<=b1 && a3<=b1)\n   {\n   printf(\"YES\\n\");\n   return 0;\n   }\n   }\n   if(p<=b1)\n   {\n   if(a2<=a1 && a3<=a1)\n   {\n   printf(\"YES\\n\");\n   return 0;\n   }\n   }\n\n\n   printf(\"NO\\n\");\n   return 0;\n }\n   ", "lang_cluster": "C", "compilation_error": true, "code_uid": "aca5a436c22002283770d84276ccbea5", "src_uid": "2ff30d9c4288390fd7b5b37715638ad9", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define max(a,b) (((a)>(b))?(a):(b))\n\nint a1,a2,a3,b1,b2,b3;\n\n\nint main()\n\n{\n\tscanf(\"%d %d\",&a1, &b1);\n\t\n\tscanf(\"%d %d\",&a2, &b2);\n\t\n\tscanf(\"%d %d\",&a3, &b3);\n\t\n\tif((a2+a3<=a1 && max(b2,b3)<=b1 )|| (a2+b3<=a1 && max(b2,a3)<=b1 ) || (b2+a3<=a1 && max(a2,b3)<=b1 )|| (b2+b3<=a1 && max(a2,a3)<=b1 )|| (b2+a3<=b1 && max(a2,b3)<=a1 )|| (a2+b3<=b1 && max(b2,a3)<=a1 )   || (a2+a3<=b1 && max(b2,b3)<=a1 )  || (b2+b3<=b1 && max(a2,a3)<=a1 ) ) \n\tprintf(\"YES\");\n\t\n\telse printf(\"NO\");\n\t\n\treturm 0;\n\t\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "65a9fa737842f03877f8875745e83a6a", "src_uid": "2ff30d9c4288390fd7b5b37715638ad9", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\ntypedef struct {\n    double a;\n    double b;\n}rectangle;\n\nint main(void)\n{\n    int isOk = 0;\n    rectangle Board, A, B, case1, case2;\n    scanf(\"%f %f %f %f %f %f\", &Board.a, &Board.b, &A.a, &A.b, &B.a, &B.b);\n    //A1 B1\n    if(A.a + B.a <= Board.a && B.b <= Board.b) isOk = 1;\n    if(A.a + B.b <= Board.a && B.a <= Board.b) isOk = 1;\n    //A1 B2\n    if(A.b + B.b <= Board.b && B.a <= Board.a) isOk = 1;\n    if(A.b + B.a <= Board.b && B.b <= Board.a) isOk = 1;\n    //A2 B1\n    if(A.a + B.a <= Board.b && B.b <= Board.a) isOk = 1;\n    if(A.a + B.b <= Board.b && B.a <= Board.a) isOk = 1;\n    //A2 B2\n    if(A.b + B.b <= Board.a && B.a <= Board.b) isOk = 1;\n    if(A.b + B.a <= Board.a && B.b <= Board.b) isOk = 1;\n    Sb = B.a * B.b\n    case1.a = Board.a - A.a;\n    case1.b = Board.b - A.b;\n    case2.a = Board.a - A.b;\n    case2.b = Board.b - A.a;\n    \n    if(case1.a * Board.b >= Sb || case1.b * Board.a >= \n    if(A.a > Board.a && A.a > Board.b || A.b > Board.a && A.b > Board.b) isOk = 0;\n    if(B.a > Board.a && B.a > Board.b || B.b > Board.a && B.b > Board.b) isOk = 0;\n    if(isOk) printf(\"Yes\");\n    else printf(\"No\");\n    return 0;\n } ", "lang_cluster": "C", "compilation_error": true, "code_uid": "2bc05311ce8a09eff8795dd53aa86bdd", "src_uid": "2ff30d9c4288390fd7b5b37715638ad9", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint min(int a,int b){\n    if(a<=b)\n        return a;\n    else\n        return b;\n}\nint max(int a,int b){\n    if(a<=b)\n        return b;\n    else\n        return a;\n}\n\nint main()\n{\n    int a1,a2,b1,b2,a,b,k;\n    scanf(\"%d%d\",&a,&b);\n    scanf(\"%d%d\",&a1,&b1);\n    scanf(\"%d%d\",&a2,&b2);\n    int x=max(a1,b1);\n    int y=a1+(b1-x);\n    int x1=max(a2,b2);\n    int y2=a2+(b2-x1);\n    int z=max(a,b);\n    k=a+(b-z);\n    if(x+x1<=z&&max(y,y2)<=k||x+x1<=k&&max(y,y2)<=z)\n        printf(\"YES\");\n    else if(x+y2<=z&&max(x1,y)<=k||x+y2<=k&&max(x1,y)<=z)\n        printf(\"YES\");\n    else if(y+x1<=z&&max(x,y2)<=k||x+y2<=k&&max(x1,y)<=z)\n        printf(\"YES\");\n    else if(y+y2<=z&&max(x,x1)<=k||y+y2<=k&&max(x,x1)<=z)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n\n\n\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "cd472a051f226c39910b3a3b48c9dcc7", "src_uid": "2ff30d9c4288390fd7b5b37715638ad9", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\nchar *to_string(int n)\n{\n\tchar a[10000];\n\tchar tempt[10000];\n\tint count = 0;\n\twhile(n > 0){\n\t\ttempt[count] = n % 10;\n\t\tn /= 10;\n\t\tcount++;\n\t}\n\tint x = count;\n\tfor(int i = 0; i < count; i++){\n\t\ta[i] = tempt[x-1] + '0';\n\t\tx--;\n\t}\n\treturn a;\n}\n\nint main()\n{\n\tint k;\n\tscanf(\"%d\", &k);\n\tchar number[10005];\n\tfor(int i = 1; i <= k; i++){\n\t\tstrcat(number, to_string(i));\n\t}\n\tprintf(\"%c\\n\", number[k]);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "66496348321947294eb5cf0433600ce4", "src_uid": "1503d761dd4e129fb7c423da390544ff", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(){\n    long long int n = 1;\n    long long int k;\n    long long int quo = 1;\n    long long int i = -1, j = 0;\n    long long int arr[10000];\n    long long int counter = 0;\n\n    scanf(\"%d\", &k);\n\n    quo = k;\n\n    while(i <= k){\n        quo = n;\n        counter = 0;\n        while(quo != 0){\n            quo = quo / 10;\n            counter++;\n//            printf(\"%d \", counter);\n        }\n\n//        printf(\"\\n\");\n\n        quo = n;\n\n        for(j=i+counter;j>i;j--){\n            arr[j] = quo % 10;\n            quo = quo / 10;\n        }\n        n++;\n        i = i + counter;\n    }\n\n    printf(\"%d\", arr[k-1]);\n\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "288785da0fb01c153b8506a0834ebfe1", "src_uid": "1503d761dd4e129fb7c423da390544ff", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    int i,count=0,j;\n    scanf(\"%d\",&n);\n\n    int a[n];\n\n    for(i=1,j=1;i<=n;i++,j++)\n    {\n        if(i<10)\n        {\n            a[j]=i;\n            count++;\n        }\n        else if(i>9 && i<100)\n        {\n            a[j]=i/10;\n            a[j+1]=i%10;\n            j=j+1;\n            count+=2;\n        }\n         else if(i>=100)\n        {\n            a[j]=i/100;\n            a[j+1]=(i%100)/10;\n            a[j+2]=(i%100)%10;\n\n            j=j+2;\n\n            count+=3;\n        }\n\n\n        if(count==n)\n            break;\n\n    }\n    //for(i=1;i<=n;i++)\n     //printf(\"%d \",a[i]);\n\n    printf(\"%d\",a[n]);\n\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1dd7f6a57e0a41bb484d806baa972294", "src_uid": "1503d761dd4e129fb7c423da390544ff", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    int i,count=0,j;\n    scanf(\"%d\",&n);\n\n    int a[2*n];\n\n    for(i=1,j=1;i<=n;i++,j++)\n    {\n        if(i<10)\n        {\n            a[j]=i;\n            count++;\n        }\n        else if(i>9 && i<100)\n        {\n            a[j]=i/10;\n            a[j+1]=i%10;\n            j=j+1;\n            count+=2;\n        }\n         else if(i>=100)\n        {\n            a[j]=i/100;\n            a[j+1]=(i%100)/10;\n            a[j+2]=(i%100)%10;\n\n            j=j+2;\n\n            count+=3;\n        }\n\n\n        if(count==n)\n            break;\n\n    }\n    //for(i=1;i<=n;i++)\n     //printf(\"%d \",a[i]);\n\n    printf(\"%d\",a[n]);\n\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "74983d02a5543b2ac3c4c13f2d7a9a8c", "src_uid": "1503d761dd4e129fb7c423da390544ff", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"kth didgit of infinite sequence shorter range\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/kth didgit of infinite sequence shorter range\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/kth didgit of infinite sequence shorter range\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1ec07c9a0b26f261a0b8ca9ded831758", "src_uid": "1503d761dd4e129fb7c423da390544ff", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char s[100];\n    int j;\n    scanf(\"%s\",s);\n    int k=strlen(s)-1;\n    for(int i=0;i<=k;i++)\n    {\n        if(s[i]!='a'&&s[i]!='e'&&s[i]!='o'&&s[i]!='u'&&s[i]!='i'&&s[i]!='n')\n          { \n              if(s[i+1]=='a'||s[i+1]=='e'||s[i+1]=='i'||s[i+1]=='o'||s[i+1]=='u')\n              {\n                  j=1;\n              }\n              else\n              {\n                 j=0;\n                 break;\n              }\n          }\n       else\n       j=1;\n    }\n    if(j==1)\n     printf(\"YES\");\n    else\n     printf(\"NO\");\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b2f4f24a4caafa4e4f8997f7f5183a8d", "src_uid": "a83144ba7d4906b7692456f27b0ef7d4", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n\tint i,b=0;\n\tchar c[100];\n\tgets(c);\n\tfor(i=0;i<strlen(c);i++){\n\t\tif(c[i]!='a'&&c[i]!='e'&&c[i]!='i'&&c[i]!='o'&&c[i]!='u'&&c[i]!='n'){\n\t\t\ti++; \n\t\t\tif(c[i]!='a'&&c[i]!='e'&&c[i]!='i'&&c[i]!='o'&&c[i]!='u'){\n\t\t\t\t\tb++;\n\t\t\t\t}\n\t\t}\n\t}\n\tif(b==0){\n\t\tprintf(\"YES\");\n\t}\n\telse{\n\t\tprintf(\"N", "lang_cluster": "C", "compilation_error": true, "code_uid": "07ffd87cb63aa4c59e813d0cc656ea77", "src_uid": "a83144ba7d4906b7692456f27b0ef7d4", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nchar s[100];\n\nint main(){\n\tscanf(\"%s\",s);\n\tint l=strlen(s);\n\tbool f=true;\n\tfor (int i=0;i<l;i++){\n\t\tif (s[i]!='a' && s[i]!='e' & s[i]!='i' && s[i]!='o' && s[i]!='u' && s[i]!='n'){\n\t\t\tif (i==l-1){\n\t\t\t\tf=false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\ti++;\n\t\t\tif (s[i]!='a' && s[i]!='e' & s[i]!='i' && s[i]!='o' && s[i]!='u'){\n\t\t\t\tf=false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tif (f){\n\t\tprintf(\"YES\\n\");\n\t} else {\n\t\tprintf(\"NO\\n\");\n\t}\n} ", "lang_cluster": "C", "compilation_error": true, "code_uid": "c73b8044cd42aa07d82bffa36c80af0a", "src_uid": "a83144ba7d4906b7692456f27b0ef7d4", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>         //romaji\n#include<stdlib.h>\nint i=0,j=0,flag=1;\nint h(char s)\n{\n    if(i<2)\n {\n     if(s=='a'|| s=='e'|| s=='i'|| s=='o'|| s=='u' )\n  {\n   i=0;\n   flag=1;\n   }\n    else if(s=='n')\n    {\n        if(flag==1)\n        {i=0;\n       flag=1;\n }\n else i=i+1;\n }\n else{\n    i=i+1;\n    flag=0;\n }\n\n}\nelse{\n     printf(\"NO\");\n     i=0;\n     exit(0);\n}\nreturn i;\n}\nint main()\n{ int a=1,c=0;\nchar d;\n    for(int i=0;i<101;i++)\n   {\n     scanf(\"%c\",&d);\n     c=h(d);\n      if(d==' '||d=='\\n')\n     {\n         c=h(d);\n        break;\n     }\n\n    }\n   if(c\n   {\n      printf(\"YES\");\n   }\n   return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "04349b147d4c5b2f95cd9758daf3262a", "src_uid": "a83144ba7d4906b7692456f27b0ef7d4", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(){\n\tchar s[100];\n  \tint i,n,x,y,z;\n  \tscanf(\"%s\", s);\n  \tn=0;\n  \tfor (i=0;i<strlen(s);i++){\n \t\t\tx=s[i]=='a' || s[i]=='e' ||s[i]=='i'||s[i]=='o'||s[i]=='u';\n       \t\t\ty=s[i+1]=='a' || s[i+1]=='e' ||s[i+1]=='i'||s[i+1]=='o'||s[i+1]=='u';\n       \t\t\tz=s[i-1]=='a' || s[i-1]=='e' ||s[i-1]=='i'||s[i-1]=='o'||s[i-1]=='u';\n       \t\t\t\tif (i==strlen(s)-1) {  \n\t\t\t\t\tif (s[i]=='n'||(z&&x))\n                \t\t\t\t\tcontinue;\n           \t\t\t\t\tif (!(!z && x)){\n\t\t\t\t\t\t\t\t n=1;\n               \t\t\t\t\t\t\t break;\n\t\t\t\t\t \t}\n         \t\t\t}\n        \t\t\telse{\n\t\t\t\t\t if (s[i]=='n')\n              \t\t\t\t continue;\n          \t\t\t\t \tif (!x && !y){\n\t\t\t\t\t\t\t n=1;\n            \t\t\t\t\t\t break;\n           \t\t\t\t\t}\n        \t\t\t}\n     \n\t}\n if (n==0)  {printf(\"YES\")}; \n\n else       {printf(\"NO\")};\n   \n  \n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b6fdf44b58ab48b0286e7c93e3b64ba6", "src_uid": "a83144ba7d4906b7692456f27b0ef7d4", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\nint main()\n{\n\n    int g[4][4];\n    int i=0,j=0,k=0;\n    int rubble;\n    scanf(\"%d\",&rubble);\n    for(i=0;i<4;++i)\n    {\n        for(j=0;j<4;++j)\n        {\n            scanf(\"%d\",&g[i][j]);\n        }\n       // scanf(\"\\n\");\n    }\n\n    int flag=0;\n      char c=getchar();\n\n     for(i=0;i<4;++i)\n     {\n        for(j=0;j<2;++j)\n        {\n            k=j+2;\n            if((g[i][j]+g[i][k])<=rubble)\n            {\n\n\n                printf(\"%d %d %d\\n\",i+1,g[i][j],(rubble-g[i][k]);\n                flag=1;\n                break;\n            }\n            if (flag==1)\n            break;\n        }\n\n\n\n    }\n    if(flag==0)\n    printf(\"-1\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2ee3d0bb4b6826e19bb8448491b6ec9c", "src_uid": "6e7ee0da980beb99ca49a5ddd04089a5", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long min(long long a,long long b)\n{\n    if(a>=b)\n    return b;\n    else\n    return a;\n}\nstruct guard{\n    long long c1,b1,c2,b2;\n};\nint main()\n{\n    long long n,minc,minb,i=1,p,k;\n    guard sanjay;\n    scanf(\"%lld\",&n);\n    k=4;i=1;\n    while(k--)\n    {\n        p=1;\n        scanf(\"%lld%lld%lld%lld\",&sanjay.c1,&sanjay.b1,&sanjay.c2,&sanjay.b2);\n        minc=min(sanjay.c1,sanjay.b1);\n        minb=min(sanjay.c1,sanjay.b2);\n        if(minc+minb<=n)\n        {\n            p=2;\n            printf(\"%lld %lld %lld\",i,minc,n-minc);\n            return 0;\n        }\n        else\n        {\n            i++;\n        continue;\n    }\n    }\n    if(p==1)\n    printf(\"-1\\n\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9c60cab79e37490ec5eaa2685759488f", "src_uid": "6e7ee0da980beb99ca49a5ddd04089a5", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint min(int a, int b){return a<b?a:b;}\n\nint main(){\n    int n, a, b, c, d, p1, p2, p, f = 0, index = -1;\n    scanf(\"%d\",&n);\n    for(int i=0; i<4; i++){\n        scanf(\"%d %d %d %d\",&a,&b,&c,&d);\n        p1 = min(a,b);\n        p2 = min(c,d);\n        if(p1+p2<=n){\n            p = p1;\n            index = i+1;\n        }\n    }\n    \n    if(index != -1){\n        printf(\"%d %d %d\\n\",index,p,n-p);\n    }else{\n        printf(\"-1\\n\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "14fcf840fbc40ea18b5b00e43ad47100", "src_uid": "6e7ee0da980beb99ca49a5ddd04089a5", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "// Read inputs from stdin. Write outputs to stdout.\n\n#include <stdlib.h>\n#include <stdio.h>\n\nint main()\n{\n    int T[4][4],i,j,n;\n    scanf(\"%d\", &n);\n    for(i=0;i<4;i++)\n    for(j=0;j<4;j++)\n    {scanf(\"%d\",&T[i][j]);\n    if(T[i][j]==0) T[i][j]++;    \n    }\n    for(i=0;i<4;i++)\n    {\n    \n    if( T[i][0]+T[i][2]<=n) \n    {\n    printf(\"%d %d %d\",i+1,T[i][0],n-T[i][0]);return 0;\n    \n    }\n     \n      if( T[i][0]+T[i][3]<=n) \n    {\n    printf(\"%d %d %d\",i+1,T[i][0],n-T[i][0]);\n    return 0;}\n     if( T[i][1]+T[i][2]<=n) \n    {\n    printf(\"%d %d %d\",i+1,T[i][1],n-T[i][1]);\n    return 0;\n    }\n     \n     if( T[i][1]+T[i][3]<=n) \n    {\n    printf(\"%d %d %d\",i+1,T[i][1],n-T[i][1]);\n   return 0;\n    }\n    \n    }\n    \n    }\n    printf(\"-1\");\n    \n    \n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cf5b544126511c3ff2061bf09aafccd4", "src_uid": "6e7ee0da980beb99ca49a5ddd04089a5", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main() \n{\n\tint rub, a, b, c, d;\n\t\n\tscanf(\"%d\", &rub);\n\t\n\tfor (int i = 1; i < 5; i++)\n\t{\n\t\tscanf(\"%d %d %d %d\", &a, &b, &c, &d);\n\t\tif (rub - a >= c)\n\t\t{\n\t\t\tprintf(\"%d %d %d\", i, a, rub - a);\n\t\t\treturn 0;\n\t\t}\n\t\tif (rub - a >= d)\n\t\t{\n\t\t\tprintf(\"%d %d %d\", i, a, rub - a);\n\t\t\treturn 0;\n\t\t}\n\t\tif (rub - b >= c)\n\t\t{\n\t\t\tprintf(\"%d %d %d\", i, b, rub - b);\n\t\t\treturn 0;\n\t\t}\n\t\tif (rub - c >= d)\n\t\t{\n\t\t\tprintf(\"%d %d %d\", i, b, rub - b);\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\"-1\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d3469a6abcd1df3c35ac00e83593d5f7", "src_uid": "6e7ee0da980beb99ca49a5ddd04089a5", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"b1\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/b1\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/b1\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6f46f951e1cf919e3bab508fed0a4814", "src_uid": "36a211f7814e77339eb81dc132e115e1", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(int argc, const char * argv[])\n{\n    int n, i1=1, i2, found = 0, sum, nsquare, i, j, k, hypothenuse;\n    scanf(\"%d\",&n);\n    if (n<5)\n    {\n        printf(\"0\");\n        return 0;\n    }\n    if (n<5)\n    {\n        printf(\"1\");\n        return 0;\n    }\n\n    for (i = 5; i<=n; i++)\n    {\n        i1 = 1;\n        i2 = i-1;\n        nsquare = i*i;\n        while (1)\n        {\n            sum = i1*i1 + i2* i2;\n            if (sum > nsquare)\n                i2--;\n            else if (sum < nsquare)\n                i1++;\n            else\n            {\n                found++;\n                i2--;\n                i1++;\n            }\n            if (i2<i1)\n                break;\n        }\n    }\n    printf(\"%d\", found);\n    return 0;\n   ", "lang_cluster": "C", "compilation_error": true, "code_uid": "2741419a61c6a731db5f83a789f36df9", "src_uid": "36a211f7814e77339eb81dc132e115e1", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "int main()\n{\n    int i,j,c,n;\n    float k2;\n    scanf(\"%d\",&n);\n    c = 0;\n    for(i=1; i<=n; i++)\n    {\n        for(j=i; j<=n; j++)\n        {\n            k2 = sqrt((i*i) + (j*j));\n            if(k2 <= n)\n            {\n                //k = (int)k2;\n                if(k2 - int(k2) == 0)\n                {\n                    c++;\n                }\n\n            }\n        }\n    }\n    printf(\"%d\",c);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fe76ac5e6e880396dd6ec798ddacb09c", "src_uid": "36a211f7814e77339eb81dc132e115e1", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\nint isInt(float);\n\nint main()\n{\n    int n,a,b,result=0;\n    float c;\n    do {scanf(\"%d\",&n);}\n    while(n<1&&n>100000);\n    for (a=1;a<=n;a++)\n    {\n        for (b=1;b<=a;b++)\n        {\n            c = sqrt(pow(a,2)+pow(b,2));\n            if (c>n)\n                break ;\n            else if (c==n)\n                {\n                    result++;\n                    break;\n                }\n            else if (isInt(c))\n                result++;\n        }\n    }\n    printf(\"%d\",result);\n}\n\nint isInt (int x)\n{\n    int q;\n\n    q=(int)x;\n\n    q++;\n\n    if((q - x) != 1)\n        return 0;\n    else\n        return 1;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "896187078d6483cc945f2fa1af9b53fb", "src_uid": "36a211f7814e77339eb81dc132e115e1", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include <stdlib.h>\n#include<string.h>\n#define getcx getchar_unlocked\n\nvoid inp(int* n)\n{\n\t*n=0;\n\tint ch=getcx();int sign=1;\n\twhile( ch < '0' || ch > '9' ){if(ch=='-')sign=-1; ch=getcx();}\n\t \n\twhile( ch >= '0' && ch <= '9' ){\n\t\t*n = ((*n)<<3)+((*n)<<1) + ch-'0', ch=getcx();}\n\t*n=(*n)*sign;\n}\n\n\n\nint ar[10000009]={0};\n\nint main()\n{\n\tint n,i;\n\tchar c[100];\n\tscanf(\"%s\",c);\n\tsscanf(c,\"%d\",&n);\n\tint p;\n\tp=n;\n\tn=n*n;\n\tfor(i=1;i<=p;i++)\n\t\tar[i*i]=1;\n\tint s=0,j,k;\n\tfor(i=1;i<=p;i++)\n\t{\n\t\tfor(j=i;j<=p;j++)\n\t\t{\n\t\t\tif(ar[i*i+j*j]==1)\n\t\t\t\ts++;\n\t\t}\n\t}\n\tprintf(\"%d\\n\",s);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c83f094511132e096a45675e613768c2", "src_uid": "36a211f7814e77339eb81dc132e115e1", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main ()\n{\nint a,b,i,j,count=0;\nclrscr();\nscanf(\"%d\",&a);\nscanf(\"%d\",&b);\nfor(i = 1; i<=a;i++)\n{\nfor(j =1; j<=b;j++)\n{\nif((i+j)%5==0)\n{\ncount++;\n}\n}\n}\nprintf(\"%d\",count);\nreturn 0 ;\n} ", "lang_cluster": "C", "compilation_error": true, "code_uid": "5d016c1beb6e29e3729f475e350a284f", "src_uid": "df0879635b59e141c839d9599abd77d2", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int n,m,count=0;\n    int diff;\n    scanf(\"%d %d\",&n,&m);\n    if(n>m)\n    {\n        int temp=m;\n        m=n;\n        n=temp;\n    }\n    for(int i=1;i<=n;i++)\n    {\n        rem=5*(i%5 + 1) -i;\n        \n        if(rem==5)\n            rem=0;\n            \n        for(int j=5-rem;j<m;j+=5)\n        {\n            count++;\n        }\n    }\n    printf(\"%d\",count);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4d7568b417fa41fbdccca947a8b9356d", "src_uid": "df0879635b59e141c839d9599abd77d2", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h.\nint main()\n{\n    int n,m,i;\n    \n    int sum=0;\n    scanf(\"%d%d\",&n,&m);\n    for(i=0;i<m;i++)\n    {\n        sum=sum+(((i+n)/5)-(i/5));\n    }\n    printf(\"%d\",sum);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b91e3999bd53056f4e356137b5ad7429", "src_uid": "df0879635b59e141c839d9599abd77d2", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<cstdio>\nint main()\n{\n    long long int n,m,sum=0;\n    scanf(\"%lld%lld\",&n,&m);\n    for(int i=1;i<=n;i++)\n\t{\n        sum=sum+(m+i)/5;\n        if(i>=5)\n        sum=sum-i/5;\n    }\n    printf(\"%lld\\n\",sum);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d138d7d9a8b7a3c0a5bae5b1018aef10", "src_uid": "df0879635b59e141c839d9599abd77d2", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    long long int i,j,m,n,count=0,baki,position,lagbe,aro;\n\n    scanf(\"%I64d %I64d\",&n,&m);\n\n    for(i=1; i<=n; i++)\n    {\n        position=i%5;\n        lagbe=5-position;\n\n        if(lagbe<=m){\n\n            baki=m-lagbe;\n            aro=baki/5;\n            count+=aro+1;\n    }\n    printf(\"%I64d\\n\",count);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "bf83c57cf30d280cb8a00046ce81cb41", "src_uid": "df0879635b59e141c839d9599abd77d2", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<cstdio>\n#include<cstring>\n#include<vector>\n#include<cstdlib>\nusing namespace std;\nint main()\n{\n    int a,b;\n    scanf(\"%d%d\",&a,&b);\n    while(1)\n    {\n        if(a==0||b==0)\n            break;\n        if(a>=2*b)\n            a=a-2*b;\n        else if(b>=2*a)\n            b=b-2*a;\n        else\n            break;\n    }\n    printf(\"%d %d\",a,b);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "542f155a6a27a0faeab79c958cd248b8", "src_uid": "1f505e430eb930ea2b495ab531274114", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int a,b;\n    scanf(\"%lld %lld\",&a,&b);\n    if (a==0||b==0)\n        return(0);\n    while (a>0 && b>0)\n    {\n        if (a>=2*b)\n        {\n            a=%2*b;\n            continue;\n        }\n        if (b>=2*a)\n        {\n            b=%2*a;\n            continue;\n        }\n        else\n        {\n            printf(\"%lld %lld\",a,b);\n        return(0);\n        }\n    }\n    printf(\"%lld %lld\",a,b);\n    return(0);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e17de37169395c5d6622bd6b9d2d8f84", "src_uid": "1f505e430eb930ea2b495ab531274114", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\ntypedef long long ll;\nint main()\n{ \n   ll a,b;scanf(\"%I64d%I64d\",&a,&b);\n   ll x=b;\n`   while(a!=0||b!=0)\n        if(a>=2*b) a=a-2*b;\n        else if(b>=2*a) b=b-2*a;\n        else break;\n       }\n   }\n   printf(\"%I64d %I64d\",a,b);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "04df874f12ce4c99e6cd529bd8f0fb86", "src_uid": "1f505e430eb930ea2b495ab531274114", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    long long a,b;\n    scanf(\"%lld%lld\",&a,&b);\n    while( a!=0 && b !=0)\n    {\n        if(a>=(2*b))\n        {\n            a=a%(2*b);\n            continue;\n\n        }\n       else if(b>=(2*a) )\n        {\n            b=b%(a*2);\n            continue;\n        }\n        else break;\n    }\n    printf(\"%lld %lld\",a,b);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7ec232e3dbc09d1d64e7643a55b94504", "src_uid": "1f505e430eb930ea2b495ab531274114", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\nint a,b,i,j;\nscanf(\"%d %d\",&a,&b);\nLOOP:if((a==0)||(b==0))\nexit(0);\nelse \n{if(a>=(2*b))\n{\na=a%(2*b); goto LOOP;}\nelse \n{if(b>=2*a){b=b%(2*a);\ngoto LOOP;}\nelse goto FINAL;}\nFINAL:printf(\"%d %d\",a,b);\nreturn 0;\n\n\n\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7598bd5f8eb0654a4eb1091f4fd91a55", "src_uid": "1f505e430eb930ea2b495ab531274114", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main() {\n\t\tint n, s[1000]\n\t\tif (n == 1) {\n\t\t\tif (s[0]==0)\n\t\t\tprintf(\"No\");\n\t\t\telse printf(\"Yes\");\n\t\t\treturn 0;\n\t\t}\n\t\tfor (int i=1; i<n; ++i) {\n\t\t\tif (s[i-1]==s[i]) {\n\t\t\t\tprintf(\"No\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\tprintf(\"Yes\");\n\t\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9e340ef8fcc50701697a19f39f70cb5c", "src_uid": "c14d255785b1f668d04b0bf6dcadf32d", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n\nint main(void)\n{\n\nint n;\nscanf(\"%d\",&n);\n\nchar*s=malloc(sizeof(char)*(n+1));\nscanf(\"%s\",s);\n\n\nint i,c=0;\nif(s[0]=='1')\nc=1;\n\nif(c==1)\n{\nfor(i=0;i<n;i++)\n{  if(i%2==0)\n   { if(s[i]=='1')\n     continue;\n     else break;}\n    else if(i%2==1)\n    {if(s[i]=='0')\n      continue;\n      else break;}\n}\n\nelse if(c==0)\n{ for(i=0;i<n;i++)\n   { if(i%2==0)\n     {if(s[i]=='0') continue; else break;}\n      \n     else if(i%2==1)\n      {if(s[i]=='1')continue; else break;}\n}\n\nif(i==n)\nprintf(\"YES\");\nelse\nprintf(\"NO\");\n\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3fa4d2fcee8b891c938cc1866784d427", "src_uid": "c14d255785b1f668d04b0bf6dcadf32d", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "include <stdio.h>\n\nmain()\n{\n    int i, s, flag= 1, count= 0;\n    scanf(\"%i\", &s);\n    char str[s+1], c;\n    scanf(\"%s\", str);\n\n    for(i=0; i<s; ++i){\n        if(str[i]== '1'){\n            if(str[i+1]!= '1'){\n                count++;\n            }\n            else{\n                flag= 0;\n                break;\n            }\n        }\n    }\n    if(flag){\n        if(s%2){\n            if(((s+1)/2)== count)\n                printf(\"Yes\\n\");\n            else\n                printf(\"No\\n\");\n        }\n        else{\n            if((s/2)==count){\n                printf(\"Yes\\n\");\n            }\n            else\n                printf(\"No\\n\");\n        }\n    }\n    else\n        printf(\"No\\n\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fa5cbcdfa285cd01b6e6cf1d07aafdc1", "src_uid": "c14d255785b1f668d04b0bf6dcadf32d", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n    int n,i,flag=1;\n    scanf(\"%d\",&n);\n    char str[n];\n    getchar();\n    gets(str);\n    for(i=;i<n;i++)\n    {\n        if(str[i]=='1'&&str[i+1]=='1')\n        {\n            flag=0;\n            break;\n        }\n        else if(str[i]=='0'&&str[i+1]=='0'&&str[i+2]=='0')\n        {\n            flag=0;\n            break;\n        }\n        else if(n==1&str[0]=='0')\n        {\n            flag=0;\n            break;\n        }\n        else if((str[0]=='0'&&str[1]=='0')||(str[n-2]=='0'&&str[n-1]=='0'))\n        {\n            flag=0;\n            break;\n        }\n    }\n    if(flag)\n        printf(\"Yes\");\n    else\n        printf(\"No\");\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2e553024c82bd0f0e88edef7f47e4c23", "src_uid": "c14d255785b1f668d04b0bf6dcadf32d", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "\n#include<stdio.h> #include<math.h> unsigned long long int main() { int n,s=0,max,i; scanf(\"%lld\",&n); scanf(\"%lld\",&max); for(i=1;i<=n;i++) { if(i%2==0) s=s*10; else s=s*10 +1; } if(max==s && n%2==1) printf(\"yes\"); else if((n%2==0) &&max==(s/10) || max==s || max==(pow(10,n)+s/100) ||max==((s/100)*100 +1)) printf(\"yes\"); else printf(\"no\"); return 0; }", "lang_cluster": "C", "compilation_error": true, "code_uid": "0f71e93216332c0375a5d81953da6d8a", "src_uid": "c14d255785b1f668d04b0bf6dcadf32d", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "//324B.c\n#include<stdio.h>\n#include<math.h>\n\nint m=1000000007;\n\nint power(int a,int b,int c)\n{\n    if(b==0)\n        return 1;\n    else if(b==1)\n        return a%c;\n    else\n        return (power(a,b/2)%c* power(a,b-b/2)%c)%c;\n       \n}\nint main()\n{\n   // int ans = power(2,3);\n   // printf(\"%d\",ans);\n\n    int n,number,total,extra,ans,divisor;\n    scanf(\"%d\",&n);\n\n    number=3*n;\n \n    total=power(3,number,m);\n\n    //calcualting when = 6\n\n    extra=power(7,n,m);\n\n    ans= (total-extra)%m;\n    \n    \n    printf(\"%d\",ans);\n\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "039983ef89b6fece8ffd1f5b0ec0740d", "src_uid": "eae87ec16c284f324d86b7e65fda093c", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main(void){\n    int n\n    long long int p,w;\n    scanf(\"%d\",&n);\n    p=27;\n    w=7;\n    for(int i=1;i<n;i++){\n        p = (p*27)%1000000007;\n        w = (w*7)%1000000007; \n    }\n    if(p>w) printf(\"%d\",p-w);\n    else printf(\"-1\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "70ab5ff9e9ed691e0036f39ca95c0c38", "src_uid": "eae87ec16c284f324d86b7e65fda093c", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n long long  int i,m=1000000007,n,t=1,a[100001],b=1;\n    scanf(\"%lld\",&n);\n    for(i=0;i<3*n;i++)\n    {\n        t=(t*3)%m;\n    }\n    for(i=1;i<=n;i++)\n    {\n        b=(b*7)%m;\n    }\n    printf(\"%lld\",(t-b));\n    return 0;\n}#include<sto.h>\nint main()\n{\n long long  int i,m=1000000007,n,t=1,a[100001],b=1;\n    scanf(\"%lld\",&n);\n    for(i=0;i<3*n;i++)\n    {\n        t=(t*3)%m;\n    }\n    for(i=1;i<=n;i++)\n    {\n        b=(b*7)%m;\n    }\n    printf(\"%lld\",(t-b+m)%m);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1dcd984e8311540ec22108a0ac7186f0", "src_uid": "eae87ec16c284f324d86b7e65fda093c", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<cstdio>\n#include <algorithm>\n#define L long long\nconst L mod = 1e9+7;\nusing namespace std;\nint Qpower(L a, L n)\n{\n    L ans = 1;\n    while (n){\n        if (n & 1) ans *= a;\n        a *= a;\n        n >>= 1;\n    }\n\n    return ans;\n}\nint main(void)\n{\n    L ans, n;\n\n    scanf(\"%I64d\",&n);\n    ans = (Qpower(3,3*n) - Qpower(7,n)) % mod;\n    printf(\"%I64d\\n\",ans);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "bac8b75d259ac3101f2bfbd654428309", "src_uid": "eae87ec16c284f324d86b7e65fda093c", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main(void){\n    long long int n,p,w;\n    scanf(\"%lld\",&n);\n    p=27;\n    w=7;\n    for(int i=1;i<n;i++){\n        p = (p*27)%1000000007;\n        w = (w*7)%1000000007; \n    }\n    if(p>w) printf(\"%lld\",p-w);\n    else printf(\"%lld\",1000000007+p-w);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6f07ba21d94daa2d15fe1dfe236e6a87", "src_uid": "eae87ec16c284f324d86b7e65fda093c", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<stdlib.h\n\n\nint main(){\n    int x1,y1,x2,y2,d,p;\n    \n    scanf(\"%d%d\",&x1,&y1);\n    scanf(\"%d%d\",&x2,&y2);\n    \n    if(abs(x1-x2)==abs(y1-y2)){\n        d=abs(x1-x2);\n    }\n    else if(abs(x1-x2)>abs(y1-y2)){\n        p=abs(x1-x2)-abs(y1-y2);\n        d=abs(y1-y2)+p;\n    }\n    else{\n        p=abs(y1-y2)-abs(x1-x2);\n        d=abs(x1-x2)+p;\n    }\n    printf(\"%d\",d);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "47f653e1893f561549a22407efb108ae", "src_uid": "a6e9405bc3d4847fe962446bc1c457b4", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n#include <math.h>\nusing namespace std;\n\nint main()\n{\nint x1,y1,x2,y2,k;\ncin >> x1 >> y1 >> x2 >> y2;\nif(abs(x1-x2) >= abs(y1-y2)) k = abs(x1-x2);\nelse k = abs(y1-y2);\ncout << k;\t\n\n\n\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1db52321d19412e6c22285b45b03477a", "src_uid": "a6e9405bc3d4847fe962446bc1c457b4", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n    int x1,x2,y1,y2;\n    scanf(\"%d %d\",&x1,&y1);\n    scanf(\"%d %d\",&x2,&y2);\n    if (abs(x2-x1)>= abs(y2-y1)){\n        printf(\"%d\\n\", abs(x2-x1));\n    }else{\n        printf(\"%d\\n\",abs(y2-y1));\n    }\n\n    return 0;\n}\n// 1459769870835", "lang_cluster": "C", "compilation_error": true, "code_uid": "340b34ee4a157dd4a22faaa7833861ae", "src_uid": "a6e9405bc3d4847fe962446bc1c457b4", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include \"iostream\"\n#include \"math\"\nusing namespace std;\n\nint main()\n{\nint x1,y1,x2,y2,k;\ncin >> x1 >> y1 >> x2 >> y2;\nif(abs(x1-x2) >= abs(y1-y2)) k = abs(x1-x2);\nelse k = abs(y1-y2);\ncout << k;\t\n\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1239253881e52c6c460bf896c8c63edd", "src_uid": "a6e9405bc3d4847fe962446bc1c457b4", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n    signed int a,b,c,d,e,m,n,i,j,k;\n    scanf(\"%d %d\",&a,&b);\n    scanf(\"%d %d\",&c,&d);\n    if((c-a)==(d-b))\n        e=c-a;\n    else if((c-a)>(d-b))\n        e=(d-b)+((c-a)-(d-b));\n    else if((c-a)<(d-b))\n        e=(c-a)+((d-b)-(c-a));\n    \n    printf(\"%d\\n\",e);\n    \nreturn 0;\n}  \n    }\n   \n    if(c<0&&d<0){\n    m=(0-c)+(a-0);\n    n=(0-d)+(b-0);\n    if(m==n)\n        e=m;\n    else if(m>n)\n        e=n+(m-n);\n    else if(m<n)\n        e=(m+(n-m));\n    }\n    printf(\"%d\\n\",e);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "bc46dbe6b44642ba90dbf13ad504ece6", "src_uid": "a6e9405bc3d4847fe962446bc1c457b4", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint len;\nchar ph[51];\nlong dp[51][10];\n\nlong f(int pos,int val)\n{\n     if(dp[pos][val]!=0)\n      return dp[pos][val];\n  \n  int sum = val+ph[pos+1]-'0';\n  \n      if(pos==len-2)\n     {\n     \t dp[pos][val]=sum%2==0?1:2;\n     \t return dp[pos][val];\n\t }\n  long c=0;    \n      if(sum%2==0)\n      c= f(pos+1,sum/2);\n\t  else\n\t  c=f(pos+1,sum/2)+f(pos+1,sum/2+1);\n\t      \n    dp[pos][val]=c;\n    \n    \n     return c;\n  \n}\nint main()\n{\n\t\n\tscanf(\"%s\",ph);\n\tlen=strlen(ph);\n\tint i,check=1;\n\tlong c=0;\n\tfor(i=0;len!=1&&i<=9;i++)\n\t{ c+= f(0,i);\n\t}  \n\t  \n/*\tfor(i=0;i<len;i++)\n\t{\n\t  for(j=0;j<10;j++)\n\t {printf(\"%ld  \",dp[i][j]);\n\t }  \n\t printf(\"\\n\");\n\t \n    }    */\n    \n    for(i=1;i<len;i++)\n     check&=(ph[i]-ph[i-1])*(ph[i]-ph[i-1])==1;\n\t   \n       printf(\"%ld\",c+(len==1?10:0)-check); \n\t  \n\t  \n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c3357fb590210a0e56e752e20b08f5be", "src_uid": "2dd8bb6e8182278d037aa3a59ca3517b", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main(void) {\n    char s[51];\n    long long a[50][10];\n    long long ans = 0;\n    int i, j, l;\n    for (j = 0; j < 10; j++) a[0][j] = 1;\n    scanf(\"%s\", s);\n    l = strlen(s);\n\n    for (i = 1; i < l; i++) {\n        for (j = 0; j < 10; j++) {\n            long long x = 0;\n            int d0 = 2 * j - s[i] + '0';\n            int k;\n            for (k = -1; k <= 1; k++) {\n                int d1 = d0 + k;\n                if (0 <= d1 && d1 < 10) x += a[i-1][d1];\n            }\n            a[i][j] = x;\n            // printf(\"a[%d][%d] = %d\\n\", i, j, a[i][j]);\n        }\n    }\n\n    for (j = 0; j < 10; j++) ans += a[l-1][j];\n\n    for (i = 1; i < l; i++) {\n        int d = s[i-1] - s[i];\n        if (d < -1 || 1 < d) {ans++; break;}\n    }\n    ans--;\n\n    printf(\"%lld\\n\", ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "13ac8cacfff9d62dd00c761116cf23f8", "src_uid": "2dd8bb6e8182278d037aa3a59ca3517b", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint len;\nchar ph[51];\nlong dp[51][10];\n\nlong f(int pos,int val)\n{\n     if(dp[pos][val]!=0)\n      return dp[pos][val];\n  \n  int sum = val+ph[pos+1]-'0';\n  \n      if(pos==len-2)\n     {\n     \t dp[pos][val]=sum%2==0?1:2;\n     \t return dp[pos][val];\n\t }\n  long c=0;    \n      if(sum%2==0)\n      c= f(pos+1,sum/2);\n\t  else\n\t  c=f(pos+1,sum/2)+f(pos+1,sum/2+1);\n\t      \n    dp[pos][val]=c;\n    \n    \n     return c;\n  \n}\nint main()\n{\n\t\n\tscanf(\"%s\",ph);\n\tlen=strlen(ph);\n\tint i,check=1;\n\tlong c=0;\n\tfor(i=0;i<=9;i++)\n\t{ c+= f(0,i);\n\t}  \n\t  \n/*\tfor(i=0;i<len;i++)\n\t{\n\t  for(j=0;j<10;j++)\n\t {printf(\"%ld  \",dp[i][j]);\n\t }  \n\t printf(\"\\n\");\n\t \n    }    */\n    \n    for(i=1;i<len;i++)\n     check&=(ph[i]-ph[i-1])*(ph[i]-ph[i-1])==1;\n\t   \n       printf(\"%ld\",c-check); \n\t  \n\t  \n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "393d44b3652e9d2f54cd3c59b8da7409", "src_uid": "2dd8bb6e8182278d037aa3a59ca3517b", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint len;\nchar ph[51];\nlong dp[51][10];\n\nlong f(int pos,int val)\n{\n     if(dp[pos][val]!=0)\n      return dp[pos][val];\n  \n  int sum = val+ph[pos+1]-'0';\n  \n      if(pos==len-2)\n     {\n     \t dp[pos][val]=sum%2==0?1:2;\n     \t return dp[pos][val];\n\t }\n  long c=0;    \n      if(sum%2==0)\n      c= f(pos+1,sum/2);\n\t  else\n\t  c=f(pos+1,sum/2)+f(pos+1,sum/2+1);\n\t      \n    dp[pos][val]=c;\n    \n    \n     return c;\n  \n}\nint main()\n{\n\t\n\tscanf(\"%s\",ph);\n\tlen=strlen(ph);\n\tint i,check=1;\n\tlong c=0;\n\tfor(i=0;len!=1&&i<=9;i++)\n\t{ c+= f(0,i);\n\t}  \n\t  \n/*\tfor(i=0;i<len;i++)\n\t{\n\t  for(j=0;j<10;j++)\n\t {printf(\"%ld  \",dp[i][j]);\n\t }  \n\t printf(\"\\n\");\n\t \n    }    */\n    \n    for(i=1;i<len;i++)\n     check&=(ph[i]-ph[i-1])*(ph[i]-ph[i-1])<=1;\n\t   \n       printf(\"%ld\",c+(len==1?10:0)-check); \n\t  \n\t  \n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "75f2b178058a14a18567e3507458f103", "src_uid": "2dd8bb6e8182278d037aa3a59ca3517b", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#define MAXN 55\nlong n,ls;\nchar s[MAXN]={'\\0'};\nlong a[MAXN]={0},p[MAXN][10]={0};\nlong long f[MAXN][10]={0},ans=0;\nvoid dfs(long now,long b)\n{\n if(p[now][b]) return;\n p[now][b]=1;\n if(now==n-1)\n  {\n   if(((a[now+1]+b)&1)) f[now][b]=2;\n   else f[now][b]=1;\n  }\n else\n  {\n   if(((a[now+1]+b)&1))\n    {\n     dfs(now+1,((a[now+1]+b)>>1));\n     dfs(now+1,((a[now+1]+b)>>1)+1);\n     f[now][b]=f[now+1][((a[now+1]+b)>>1)]+f[now+1][((a[now+1]+b)>>1)+1];\n    }\n   else\n    {\n     dfs(now+1,((a[now+1]+b)>>1));\n     f[now][b]=f[now+1][((a[now+1]+b)>>1)];\n    }\n  }\n}\nint main()\n{\n long i,j,k;\n gets(s);ls=strlen(s)-1;if(s[ls]=='\\n') s[ls--]='\\0';\n n=ls+1;\n for(i=1;i<=n;i++) a[i]=s[i-1]-'0';\n for(i=0;i<=9;i++) \n  {dfs(1,i);ans+=f[1][i];}\n for(i=2;i<=n;i++)\n  if(((a[i-1]+a[i])>>1)!=a[i] && (((a[i-1]+a[i])>>1)+1)!=a[i])\n   break;\n if(i==n+1) ans--; \n printf(\"%I64d\\n\",ans);\n return(0);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "29f66ce634907f13043b1c35db9dafb3", "src_uid": "2dd8bb6e8182278d037aa3a59ca3517b", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    long long int n;\n    scanf(\"\\n%I64d\",&n);\n    long long int maxSq=sqrt(n);\n    long long int sox,tmp;\n    long long int i,j,ans;\n    int flag=0;\n    for(j=1;j<=maxSq;j++)\n    {\n        i=j*j;\n        sox=0;\n        tmp=i;\n        while(tmp!=0)\n        {\n            sox=sox+tmp%10;\n            tmp=tmp/10;\n        }\n        if((ans=(i+(sox*j)-n))==0)\n        {\n            printf(\"%I64d\\n\",j);\n            flag=1;\n            break;\n        }\n    }\n    if(n==8)\n    {\n    printf(\"2\\n\");\n    break;\n    }\n\n    if(flag==0)\n    {\n        printf(\"-1\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "bf8198959a899c01337c916abd15c148", "src_uid": "e1070ad4383f27399d31b8d0e87def59", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "{\n      long long int n,j,k,l,u,mod,i,t,o,p;\n     scanf(\"%I64d\",&n);\n     i=sqrt(n);\n  \n     if((i*i)==n)\n     {\n          j=i-1;\n     }\n     else \n     j=i;\n     \n     u=j;\n     while(u>0)\n          {\n               mod=u%10;\n               k+=mod;\n               u/=10;\n          }\n     for(o=j;o*o<=n,o>0;o--)\n     {\n          \n          l=(o*o+o*k);\n     \n          if(l==n)\n          {\n          printf(\"%I64d\",o);\n          break;\n          }\n         else  if(l<n)\n          break;\n          else \n          k--;\n     }\n     if(l<n)\n      printf(\"-1\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f4092f154b493975d513bdb6252bac90", "src_uid": "e1070ad4383f27399d31b8d0e87def59", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "    #include<stdio.h>\n    #include<math.h>\n     \n    long long s(long long n);\n     \n    int main()\n    {\n        long long n, x, mid;\n        scanf(\"%I64d\", &n);\n        long long lowb=sqrt(n)-82, ub=sqrt(n)+1;\n        for(;lowb<=ub;lowb++)\n        {\n            if(lowb*lowb+s(lowb)*lowb==n&&lowb>0)\n            {\n                printf(\"%I64d\\n\", lowb);    #include<stdio.h>\n    #include<math.h>\n     \n    long long s(long long n);\n     \n    int main()\n    {\n        long long n, x, mid;\n        scanf(\"%I64d\", &n);\n        long long lowb=sqrt(n)-82, ub=sqrt(n)+1;\n        for(;lowb<=ub;lowb++)\n        {\n            if(lowb*lowb+s(lowb)*lowb==n&&lowb>0)\n            {    #include<stdio.h>\n    #include<math.h>\n     \n    long long s(long long n);\n     \n    int main()\n    {\n        long long n, x, mid;\n        scanf(\"%I64d\", &n);\n        long long lowb=sqrt(n)-82, ub=sqrt(n)+1;\n        for(;lowb<=ub;lowb++)\n        {\n            if(lowb*lowb+s(lowb)*lowb==n&&lowb>0)\n            {\n                printf(\"%I64d\\n\", lowb);\n                lowb=0;\n                break;\n            }\n        }\n        if(lowb)\n            printf(\"-1\\n\");\n        return 0;\n    }\n     \n    long long s(long long n)\n    {\n        long long i=0;\n        while(n)\n            i+=n%10, n/=10;\n        return i;\n    }\n                printf(\"%I64d\\n\", lowb);\n                lowb=0;\n                break;\n            }\n        }\n        if(lowb)\n            printf(\"-1\\n\");\n        return 0;\n    }\n     \n    long long s(long long n)\n    {\n        long long i=0;\n        while(n)\n            i+=n%10, n/=10;\n        return i;\n    }\n                lowb=0;\n                break;\n            }\n        }\n        if(lowb)\n            printf(\"-1\\n\");\n        return 0;\n    }\n     \n    long long s(long long n)\n    {\n        long long i=0;\n        while(n)\n            i+=n%10, n/=10;\n        return i;\n    }", "lang_cluster": "C", "compilation_error": true, "code_uid": "3ca5bcc296a948a62d55ebe9c9fdb0de", "src_uid": "e1070ad4383f27399d31b8d0e87def59", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nconst double e=0.00000001;\n\nint digs(int64 a){\n    int r=0;\n    while (a) {\n        r+=a%10;\n        a/=10;\n    }\n    return r;\n}\n\nint clear(int64 n){\n    int x=(int)sqrt(n+e);\n    return ((int64)x*x==n);\n}\n\nint main()\n{\n    int64 n;\n    scanf(\"%I64d\",&n);\n    n*=4;\n    int x; int t;\n    for (t=1;t<153; t++){\n        if (clear(n+t*t)){\n            x=(sqrt(t*t+n+e)-t)/2;\n            if (t==digs(x)){\n                printf(\"%d\",x);\n                return 0;\n            }\n        }\n    }\n    printf(\"-1\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7c70ea5a3c1b4e6af3fd8692bb3b9301", "src_uid": "e1070ad4383f27399d31b8d0e87def59", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#define ll long long\nll n;\nbool find_roots(ll s)\n{\n    if(sqrt(s*s+4*n)*sqrt(s*s+4*n)==(s*s+4*n))\n    {\n        ll root1=-s+(sqrt(s*s+4*n));\n        if(!(root1%2))\n        {\n            root1/=2;\n            ll count=0;\n            ll r=root1;\n            while(root1)\n            {\n                count+=(root1%10);\n                root1/=10;\n            }\n            if(count==s)\n            {\n                printf(\"%lld\\n\",r);\n                return true;\n            }\n        }\n    }\n    return false;\n}\nint main()\n{\n    ll i,j,k;\n    scanf(\"%lld\",&n);\n    for(i=0;i<=90;i++)\n    {\n        if(find_roots(i))\n            return 0;\n    }\n    printf(\"-1\\n\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "35bb3678b7ef1a1e1a4679bba1700456", "src_uid": "e1070ad4383f27399d31b8d0e87def59", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    double a,b;\n    char in[10];\n    scanf(\"%s\",in);\n    a=((int)(in[0]-'0')*10)+((int)(in[1]-'0'));\n     b=((int)(in[3]-'0')*10)+((int)(in[4]-'0'));\n    double c;\n    if(a==12)a=0;\n    c=b/60;\n    b=b*6;\n    a=a*30+c*30;\n    printf(\"%lf %lf\",a,b);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "625790f755a4e8c7137c1a9bd6f79e39", "src_uid": "175dc0bdb5c9513feb49be6644d0d150", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n\tint a1,b1,a,b,i;\n\tchar s;\n\tfor(i=1;i<6;i++)\n\t{\n\tscanf(\"%d%c%d\",&a1,&s,&b1);\n\tif(a1<12)\n\t{a=(a1+1.0*b1/60)*30;\n\tb=b1*6;\n    if(b1%2==1)\n\t{\n\t\tprintf(\"%d\",a);\n\t\tprintf(\".5\");\n\t\tprintf(\" %d\\n\",b);\n\t}\n\telse printf(\"%d %d\\n\",a,b);\n\t}\n\t\n\telse if(a1<=23)\n\t{a1-=12;a=(a1+1.0*b1/60)*30;\n\tb=b1*6;\n    if(b1%2==1)\n\t{\n\t\tprintf(\"%d\",a);\n\t\tprintf(\".5\");\n\t\tprintf(\" %d\\n\",b);\n\t}\n\telse printf(\"%d %d\\n\",a,b);}\n\t\n\telse\n\t{\n\t\ta=1.0*b1/60*30;\n\t\tif(b1%2==1)\n\t\t{\n\t\t\tprintf(\"%d\",a);\n\t\t\tprintf(\".5\");\n\t\t\tprintf(\" %d\\n\",b);\n\t\t}\n\t\telse \n\t\t\tprintf(\"%d %d\\n\",a,b);\n\t}\n\t}\n}\n\n\t \t\t  \t\t\t\t\t  \t \t  \t\t\t \t \t\t", "lang_cluster": "C", "compilation_error": false, "code_uid": "512f454e17a54b8b32fbaeaba2b245a4", "src_uid": "175dc0bdb5c9513feb49be6644d0d150", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n\tint a1,b1,a,b;\n\tchar s;\n\tscanf(\"%d%c%d\",&a1,&s,&b1);\n\tif(a1<12)\n\t{a=(a1+1.0*b1/60)*30;\n\tb=b1*6;\n    if(b1%2==1)\n\t{\n\t\tprintf(\"%d\",a);\n\t\tprintf(\".5\");\n\t\tprintf(\" %d\\n\",b);\n\t}\n\telse printf(\"%d %d\\n\",a,b);\n\t}\n\t\n\telse if(a1<=23)\n\t{a1-=12;a=(a1+1.0*b1/60)*30;\n\tb=b1*6;\n    if(b1%2==1)\n\t{\n\t\tprintf(\"%d\",a);\n\t\tprintf(\".5\");\n\t\tprintf(\" %d\\n\",b);\n\t}\n\telse printf(\"%d %d\\n\",a,b);}\n\t\n\telse\n\t{\n\t\ta=1.0*b1/60*30;\n\t\tif(b1%2==1)\n\t\t{\n\t\t\tprintf(\"%d\",a);\n\t\t\tprintf(\".5\");\n\t\t\tprintf(\" %d\\n\",b);\n\t\t}\n\t\telse \n\t\t\tprintf(\"%d %d\\n\",a,b);\n\t}\n}\n\n\t \t \t \t\t  \t    \t  \t\t  \t \t", "lang_cluster": "C", "compilation_error": false, "code_uid": "4141074d9e8f8b2245b3ecda2e857632", "src_uid": "175dc0bdb5c9513feb49be6644d0d150", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int hou,min;\n    float x,y;\n    char c;\n    scanf(\"%d%c%d\",&hou,&c,&min);\n    if(hou < 12)\n    { x=30*hou+min*0.5;\n      y=min*6;\n    }\n    else\n    {\n        x=30*(hou-12)+min*0.5;\n        y=min*6;\n    }\n    printf(\"%.1f %.0f\",x,y);\n}\n\n\t  \t  \t\t \t\t \t  \t\t\t\t\t\t\t  \t", "lang_cluster": "C", "compilation_error": false, "code_uid": "63eccbcac0d52fa75d6b0afcf36f582a", "src_uid": "175dc0bdb5c9513feb49be6644d0d150", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    int HH,MM,z,y;\n    double  x;\n    scanf(\"%d%d\",&HH,&MM)\uff1b\n        if (HH==12)\n            z=0;\n        else\n            z=HH*30;\n        x=z+(double)MM/2;\n        y=MM*6;\n        printf(\"%g %d\\n\",x,y);\n    return 0;\n}\n\n\t\t \t \t \t \t   \t\t\t  \t \t\t\t", "lang_cluster": "C", "compilation_error": true, "code_uid": "62af813697beae0c09c8f5311860b2ab", "src_uid": "175dc0bdb5c9513feb49be6644d0d150", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nchar A[101],B[] = \"CODEFORCES\",src[101],dest[11];\nint main(){\n\tscanf(\"%s\",A);\n\tint l=strlen(A),i,f=0,j=0,k,g=0,h;\n\tfor(i=0;i<l;i++){\n        if(A[i]!=B[j])f=1;\n        else {\n         j++;\n         if(j==10){\n           printf(\"YES\");return 0;}\n        if(f==1){\n            //strcpy(src,A+i);\n            //strcpy(dest,B+j);\n            //if(strstr(src,dest)){\n                k=j;\n                for(i=i;i<l;i++){\n                    if(A[i]==B[k]){\n                        k++;g=1;\n                        if(k==10&&i==l-1){\n                            printf(\"YES\");\n                            return 0;\n                        }\n                    }\n                    else {\n                        if(g==1)k=j;\n                        continue;\n                    }\n                }\n                //if(A[h+10-j]=='\\0'){\n                    //printf(\"YES\");\n                    //return 0;\n                //}\n                //else{\n                    //printf(\"NO\");\n                    //return 0;\n                //}\n           //}\n        }\n\t}\n\tif(f==0 && j==10)printf(\"YES\");\n\telse printf(\"NO\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6aa6fffd753cb9e9d71bf3925614eead", "src_uid": "bda4b15827c94b526643dfefc4bc36e7", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include<string.h>\nint main()\n{\n    char st[101], c, o, d, e, l, in1 = 0,in2=0,f,r,s;\n    scanf(\"%s\", st);\n    l = strlen(st);\n    for (c = 0; c < l&&!in1; c++)\n    {\n        if (st[c] == 'C')\n            for (o = c + 1; o < l&&!in1; o++)\n            {\n                if (st[o] == 'O')\n                    for (d = o + 1; d < l&&!in1; d++)\n                    {\n                        if (st[d] == 'D')\n                            for (e = d + 1; e < l&&!in1; e++)\n                            {\n                                if (st[e] == 'E')\n                                {\n                                    in1 = 1;\n                                    break;\n                                }\n                            }\n                        if(e==l)\n                        {\n                            printf(\"NO\"); exit (0);\n                        }\n                    }\n                if(d==l)\n                {\n                    printf(\"NO\"); exit (0);\n                }\n            }\n        if(o==l)\n        {\n            printf(\"NO\"); exit (0);\n        }\n    }\n    for(f=e+1;f<l&&!in2;f++)\n    {\n        if(st[f]=='F')\n        {\n            for(o=f+1;o<l&&!in2;o++)\n            {\n                if(st[o]=='O')\n                {\n                    for(r=o+1;r<l&&!in2;r++)\n                    {\n                        if(st[r]=='R')\n                        {\n                            for(c=r+1;c<l&&!in2;c++)\n                            {\n                                if(st[c]=='C')\n                                {\n                                    for(e=c+1;e<l&&!in2;e++)\n                                    {\n                                        if(st[e]=='E')\n                                        {\n                                            for(s=e+1;s<l&&!in2;s++)\n                                            {\n                                                if(st[s]=='S')\n                                                {\n                                                    if (st [0]=='C'||(st [0]!='C'&&s <l-1)||(st [0]!='C'&&s ==l-1&&s [l-2]=='E'))\n                                                    {\n                                                    in2=1;\n                                                    break;\n                                                    }\n                                                }\n                                            }\n                                            if(s==l)\n                                            {\n                                printf(\"NO\"); exit (0);\n                                            }\n                                        }\n                                    }\n                                    if(e==l)\n                                    {\n                                            printf(\"NO\"); exit (0);\n                                    }\n                                    \n                                }\n                            }\n                            if(c==l)\n                            {\n                                    printf(\"NO\"); exit (0);\n                            }\n                        }\n                    }\n                    if(r==l)\n                    {\n                            printf(\"NO\"); exit (0);\n                    }\n                }\n            }\n            if(o==l)\n            {\n                    printf(\"NO\"); exit (0);\n            }\n        }\n    }\n    if(f==l)\n    {\n            printf(\"NO\"); exit (0);\n    }\n    if(in2)\n    printf(\"YES\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "194966b3be3173f9bb2493fb296a3451", "src_uid": "bda4b15827c94b526643dfefc4bc36e7", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\nint main ()\n{\n    char s [101],l,i,j;\n    scanf (\"%s\",s);\n    l=strlen (s);\n    for (i=0;i <l-9;i++)\n    {\n        if (s [i]=='C') \n        {\n            if (s [i+1]=='O')\n            {\n                if (s [i+2]=='D')\n                {\n                    if(s [i+3]=='E')\n                    {\n                        if (s[i+4]=='F')\n                        {\n                            if (s [i+5]=='O')\n                            {\n                                if (s [i+6]=='R')\n                                {\n                                    if (s [i+7]=='C')\n                                    {\n                                        if (s[i+8]=='E')\n                                        {\n                                            if (s [i+9]=='S')\n                                            {\n                                                if (i==0||i+10==l)\n                                                {\n                                                printf (\"YES\");\n                                                exit (0);\n                                                }\n                                            }\n                                            else\n                                            {\n                                                for (j=i+10;j<l;j++)\n                                                if (s [j]=='S')\n                                                {\n                                                    if (i==0||j+1==l)\n                                                    {   \n                                                    printf (\"YES\");\n                                                    exit (0);\n                                                    }\n                                                }\n                                            }\n                                        }\n                                        else\n                                        {\n                                            for (j=i+9;j <l-1;j++)\n                                            if (s [j]=='E'&&s [j+1]=='S')\n                                            {\n                                                if (i==0||j+2==l)\n                                                    {\n                                                printf (\"YES\");\n                                                exit (0);\n                                                    }\n                                                \n                                            }\n                                        }\n                                    }\n                                    else\n                                    {\n                                        for (j=i+8;j <l-2;j++)\n                                        if (s [j]=='C'&&s [j+1]=='E'&&s [j+2]=='S')\n                                        {\n                                            if(i==0||j+3==l)\n                                            {\n                                                printf (\"YES\");\n                                                exit (0);\n                                            }\n                                        }\n                                    }\n                                }\n                                else\n                                {\n                                    for (j=i+7;j <l-3;j++)\n                                    if (s [j]=='R'&&s [j+1]=='C'&&s [j+2]=='E'&&s [j+3]=='S')\n                                    {\n                                        if (i==0||j+4==l)\n                                        {\n                                                printf (\"YES\");\n                                                exit (0);\n                                        }\n                                    }\n                                }\n                            }\n                            else\n                            {\n                                    for (j=i+6;j <l-4;j++)\n                                    if (s [j]=='O'&&s [j+1]=='R'&&s [j+2]=='C'&&s [j+3]=='E'&&s [j+4]=='S')\n                                    {\n                                        if (i==0||j+5==l)\n                                        {\n                                                printf (\"YES\");\n                                                exit (0);\n                                        }\n                                    }\n                            }\n                        }\n                        else\n                        {\n                                    for (j=i+5;j <l-5;j++)\n                                    if (s [j]=='F'&&s [j+1]=='O'&&s [j+2]=='R'&&s [j+3]=='C'&&s [j+4]=='E'&&s [j+5]=='S')\n                                    {\n                                        if (i==0||j+6==l)\n                                        {\n                                                printf (\"YES\");\n                                                exit (0);\n                                        }\n                                    }\n                        }\n                    }\n                    else\n                    {\n                                    for (j=i+4;j <l-6;j++)\n                                    if (s[j]=='E'&&s [j+1]=='F'&&s [j+2]=='O'&&s [j+3]=='R'&&s [j+4]=='C'&&s [j+5]=='E'&&s [j+6]=='S')\n                                    {\n                                        if (i==0||j+7==l)\n                                        {\n                                                printf (\"YES\");\n                                                exit (0);\n                                        }\n                                    }\n                    }\n                }\n                else\n                {\n                                    for (j=i+3;j <l-7;j++)\n                                    if (s [j]=='D'&&s[j+1]=='E'&&s [j+2]=='F'&&s [j+3]=='O'&&s [j+4]=='R'&&s [j+5]=='C'&&s [j+6]=='E'&&s [j+7]=='S')\n                                    {\n                                        if (i==0||j+8==l)\n                                        {\n                                                printf (\"YES\");\n                                                exit (0);\n                                        }\n                                    }\n                }\n            }\n            else\n            {\n                        for (j=i+2;j <l-8;j++)\n                        if (s[j]=='O'&&s [j+1]=='D'&&s[j+2]=='E'&&s [j+3]=='F'&&s [j+4]=='O'&&s [j+5]=='R'&&s [j+6]=='C'&&s [j+7]=='E'&&s [j+8]=='S')\n                        {\n                            if (i==0||j+9))\n                            {\n                                    printf (\"YES\");\n                                    exit (0);\n                            }\n                        }\n            }\n        }\n    }\n    printf (\"NO\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d3bf320c028a85e732df0d83b8b7fae4", "src_uid": "bda4b15827c94b526643dfefc4bc36e7", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nchar A[101],B[] = \"CODEFORCES\",src[101],dest[11];\nint main(){\n\tscanf(\"%s\",A);\n\tint l=strlen(A),i,f=0,j=0,k,g=0,h;\n\tfor(i=0;i<l;i++){\n        if(A[i]!=B[j])f=1;\n        else {\n            j++;\n            if(j==10){\n                printf(\"YES\");\n                return 0;\n            }\n        if(f==1){\n            //strcpy(src,A+i);\n            //strcpy(dest,B+j);\n            //if(strstr(src,dest)){\n                k=j;\n                for(i=i;i<l;i++){\n                    if(A[i]==B[k]){\n                        k++;g=1;\n                        if(k==10&&i==l-1){\n                            printf(\"YES\");\n                            return 0;\n                        }\n                    }\n                    else {\n                        if(g==1)k=j;\n                        continue;\n                    }\n                }\n                //if(A[h+10-j]=='\\0'){\n                    //printf(\"YES\");\n                    //return 0;\n                //}\n                //else{\n                    //printf(\"NO\");\n                    //return 0;\n                //}\n           //}\n        }\n\t}\n\tif(f==0 && j==10)printf(\"YES\");\n\telse printf(\"NO\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "85941f77276198ed6cb9387d0cb5cc7a", "src_uid": "bda4b15827c94b526643dfefc4bc36e7", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main(){\nchar str[150];\nscanf(\"%s\",&str);\nchar s[10] = {'C','O','D','E','F','O','R','C','E','S'}; // 'C','O','D','E','F','O','R','C','E','S'\nint mass[10];\nint i;\nint q=0;\nfor(i = 0; i < strlen(str); i++){\nif(s[q]==str[i]){q++;}\nif(q==9) break;\n}\nif((q==9)&&(strlen(str)==0)) printf(\"YES\"); else printf(\"NO\");\nsystem(\"PAUSE\");\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "66bae98704c1602164e2c49e4277d2ef", "src_uid": "bda4b15827c94b526643dfefc4bc36e7", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main() {\n\tint n, k;\n\tchar s[110];\n\tchar t[110];\n\tscanf(\"%d%d\", &n, &k);\n\tscanf(\"%s\", t);\n\tfor(int i = 0; i < n; i++) {\n\t\tif(t[i] == 'N')\n\t\t\tcontinue;\n\t\tfor(int j = 0; j < n; j++) {\n\t\t\ts[j] = t[j];\n\t\t}\n\t\tif(i - k >= 0) {\n\t\t\tbool ok = 1;\n\t\t\tfor(int j = i - k; j < i; j++) {\n\t\t\t\tif(s[j] == 'Y')\n\t\t\t\t\tok = 0;\n\t\t\t\ts[j] = 'N';\n\t\t\t}\n\t\t\tif(i - k - 1 >= 0) {\n\t\t\t \tif(s[i - k - 1] == 'N')\n\t\t\t\t\tok = 0;\n\t\t\t\ts[i - k - 1] = 'Y';\n\t\t\t}\n\t\t\tint cnt = 0, mc = 0;\n\t\t\tfor(int i = 0; i < n; i++) {\n\t\t\t\tif(s[i] == 'N')\n\t\t\t\t\tcnt++;\n\t\t\t\telse\n\t\t\t\t\tcnt = 0;\n\t\t\t\tif(mc < cnt)\n\t\t\t\t\tmc = cnt;\n\t\t\t}\n\t\t\tok &= mc == k;\n\t\t\tif(ok) {\n\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\treturn(0);\n\t\t\t}\n\t\t}\n\t\tfor(int j = 0; j < n; j++) {\n\t\t\ts[j] = t[j];\n\t\t}\n\t\tif(i + k < n) {\n\t\t\tbool ok = 1;\n\t\t\tfor(int j = i + 1; j < i + k + 1; j++) {\n\t\t\t\tif(s[j] == 'Y')\n\t\t\t\t\tok = 0;\n\t\t\t\ts[j] = 'N';\n\t\t\t}\n\t\t\tif(i + k + 1 < n) {\n\t\t\t\tif(s[i + k + 1] == 'N')\n\t\t\t\t\tok = 0;\n\t\t\t\ts[i + k + 1] = 'Y';\n\t\t\t}\n\t\t\tint cnt = 0, mc = 0;\n\t\t\tfor(int i = 0; i < n; i++) {\n\t\t\t\tif(s[i] == 'N')\n\t\t\t\t\tcnt++;\n\t\t\t\telse\n\t\t\t\t\tcnt = 0;\n\t\t\t\tif(mc < cnt)\n\t\t\t\t\tmc = cnt;\n\t\t\t}\n\t\t\tok &= mc == k;\n\t\t\tif(ok) {\n\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\treturn(0);\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"NO\\n\");\n\treturn(0);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a83085805d3b555ec41f74a092d94899", "src_uid": "5bd578d3da5837c259b222336a194d12", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <bits/stdc++.h>\nusing namespace std;\n\nchar a[101];\n\nint main()\n{\n    #ifdef LOCAL\n    freopen(\"input.txt\",\"r\",stdin);\n    freopen(\"output.txt\",\"w\",stdout);\n    #endif   \n \n   \tint n, k, sch = 0, ans = 0;\n   \tscanf(\"%d%d%s\", &n, &k, a);\n\n   \ta[n] = 'E';\n\n   \tfor (int i = 0; i <= n; i++)\n   \t{\n   \t\tif (a[i] != a[i - 1])\n   \t\t{\n   \t\t\tans = max(ans, sch);\n   \t\t\tsch = 0;\n   \t\t}\n   \t\tif (a[i] == 'N') sch++;\n   \t}\n\n   \tif (ans > k)\n   \t{\n   \t\tprintf(\"NO\");\n   \t\treturn 0;\n   \t}\n\n   \tans = sch = 0;\n\n   \tfor (int i = 0; i <= n; i++)\n   \t{\n   \t\tif (a[i] != a[i - 1])\n   \t\t{\n   \t\t\tans = max(ans, sch);\n   \t\t\tsch = 0;\n   \t\t}\n   \t\tif (a[i] == 'N' || a[i] == '?') sch++;\n   \t}\n\n   \tif (ans >= k)\n   \t\tprintf(\"YES\");\n   \telse printf(\"NO\");\n   \treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4235ff2ddc43f8f4f887a7d970b81a91", "src_uid": "5bd578d3da5837c259b222336a194d12", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <windef.h>\n\nint main() {\n    int n, k;\n    scanf(\"%d%d\", &n, &k);\n\n    char s[n + 1];\n    scanf(\"%s\", s);\n\n    char last = '.';\n    int cnt = 0, mxN = 0;\n    for(int i = 0; i < n; ++i) {\n        if(s[i] == last) {\n            cnt++;\n        } else {\n            last = s[i];\n            cnt = 1;\n        }\n        if(last == 'N') {\n            mxN = max(mxN, cnt);\n        }\n    }\n\n    if (mxN <= k) {\n        for (int i = 0; i + k <= n; ++i) {\n            bool f = true;\n            for (int j = i; j < i + k; ++j)\n                f &= s[i] != 'Y';\n\n            if (i != 0)\n                f &= s[i - 1] != 'N';\n            if (i + k != n)\n                f &= s[i + k] != 'N';\n\n            if (f) {\n                puts(\"YES\");\n                return 0;\n            }\n        }\n    }\n\n    puts(\"NO\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b9c608c9ee5594b91b042ff39a3d2a79", "src_uid": "5bd578d3da5837c259b222336a194d12", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define Inf 1LL<<61\n#define ll long long\n#define NewLine cout<<endl\n#define fastIO ios::sync_with_stdio(false);cin.tie(0)\n#define REP(i,a,b)for(int i=a;i<b;i++)\n#define RREP(i,a,b)for(int i=a;i>b;i--)\n#define R(i,b) REP(i,0,b)\n#define r(b)REP(_,0,b)\n#define RR(i,b) RREP(i,b,-1)\n#define R1(i,b) REP(i,1,b)\n#define pb push_back\n#define IN ll k,q;cin>>k>>q;cin.get()\n#define CInt(x)cin>>x;cin.get()\n#define CBuff(x)cin.getline(x, sizeof(x))\n#define Outl(x)cout << x << '\\n'\n#define all(x) begin(x),end(x)\nusing namespace std;\n\nint n, k;\nchar b[110];\nint N[110], m = 0;\nint main()\n{\n\tscanf(\"%d%d\", &n, &k);\n\tscanf(\"%s\", &b);int l = 0;\n\tR(i, n) {\n\t\tif (b[i] == 'N') {\n\t\t\tl++;\n\t\t}\n\t\telse {\n\t\t\tif (l > 0)\n\t\t\t\tN[m++] = l;l = 0;\n\t\t}\n\t}l = 0;\n\tR(i, n) {\n\t\tif (b[i] == 'N'|| b[i] == '?') {\n\t\t\tl++;\n\t\t}\n\t\telse {\n\t\t\tif (l > 0)\n\t\t\t\tN[m++] = l;l = 0;\n\t\t}\n\t}int u = 0, d = 0;\n\tR(i, m) {\n\t\tif (N[i] >= k)u = 1;\n\t\tif (N[i] <= k)d = 1;\n\t}if (u&&d)printf(\"YES\");else printf(\"NO\");\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4126c42a38c034f9e98c70b785279c02", "src_uid": "5bd578d3da5837c259b222336a194d12", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n\n# define F first\n# define S second\n# define mp make_pair\n# define pii pair<int,int>\n\n# define long long long\n# define pb push_back\n# define sz(a) (int)(a.size())\n\n# define y1     tipa_y1\n# define left   tipa_left\n# define right  tipa_right\n\nconst int Mod = (int)1e9 + 7;\nconst int MX = 1073741822;\nconst long MXLL = 4611686018427387903;\nconst int Sz = 1110111;\n\nint n, k;\n\nchar a[11011];\n\nint len = 0, mx = 0;\n\nint main()\n{\n  scanf (\"%d %d\", &n, &k);\n  for (int i = 1;i <= n;i ++) {\n    scanf (\" %c\", &a[i]);\n    if (a[i] == 'N')\n      len ++;\n    else\n    {       \n      len = 0;\n    }\n    if (mx < len)\n      mx = len;\n  }  \n  if (mx > k)\n    printf (\"NO\");\n  else          \n  {            \n    len = 0;\n    bool ok = 0;\n    for (int i = 1;i + k - 1 <= n;i ++) {\n      if (i == 1 || a[i - 1] != 'N') {\n        bool y = 1;\n        for (int j = i;j <= i + k - 1;j ++) {\n          if (a[j] == 'Y')\n            y = 0;\n        }                 \n        if (i + k <= n && a[i + k] == 'N') \n          y = 0;\n        if (y)  \n        {\n          ok = 1;\n          break;\n        }\n      }\n    } \n    if (ok)\n      printf (\"YES\");\n    else\n      printf (\"NO\");\n  }\n\n\n  return 0;\n}\n\n\n\n\n\n\n\n\n\n// Coded by Z...\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0f411b85357facf96d9ff9c5dccc3778", "src_uid": "5bd578d3da5837c259b222336a194d12", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int n,a,b,i,j,f=0;\n    scanf(\"%lld %lld %lld\",&n,&a,&b);\n    if(n%a==0)\n    {\n        printf(\"YES\\n\");\n        printf(\"%lld\\n\",n/a);\n        printf(\"0\\n\");\n        f=1\n    }\n    if(n%b==0 && n%a!=0)\n    {\n    printf(\"YES\\n\");\n    printf(\"0\\n\");\n    printf(\"%lld\\n\",n/b);\n    f=1;\n    }\n    if(n%a!=0 && n%b!=0)\n    {\n        for(i=1;i<n/a;i++)\n        {\n            for(j=1;j<n/b;j++)\n            {\n                if(a*i +b*j==n)\n                {\n                    printf(\"YES\\n\");\n                    printf(\"%lld\",i);\n                    printf(\"%lld\",j);\n                    f=1;\n                    break;\n                }\n            }\n        }\n    }\n    if(f==0)\n    printf(\"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b0d2acdb480b2ae982a100e42dc5143b", "src_uid": "b031daf3b980e03218167f40f39e7b01", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint n,a,b,count=0, remsum ;\nscanf(\"%d\",&n);\nscanf(\"%d\",&a);\nscanf(\"%d\",&b);\nremsum = n;\nwhile (remsum >= 0 and remsum%b != 0)\n{\n\tremsum -= a;\n\tcount += 1;\n}\nif(remsum<0)\nprintf(\"NO\");\nelse\nprintf(\"YES\\n%d % d\", count, remsum / b);\n\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "078d1887e0b718ef9cff697867bd7a62", "src_uid": "b031daf3b980e03218167f40f39e7b01", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\ntypedef long long Int;\n\nInt solve(Int n, Int a, Int b) {\n  Int x;\n  for (x = 0; x <= a; ++x) {\n    if (x*a <= n && (n - x*a) % b == 0) {\n      puts(\"YES\");\n      printf(\"%I64d %I64d\\n\", x, (n - x*a) / b);\n      return 1;\n    }\n  }\n  return 0;\n}\n\nint main() {\n  Int n, a, b;\n  scanf(\"%I64d%I64d%I64d\", &n, &a, &b);\n  if (!solve(n, a, b) && !solve(n, b, a))) {\n    puts(\"NO\");\n  }\n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "443e53b62b70223fc939b5ec92632fb9", "src_uid": "b031daf3b980e03218167f40f39e7b01", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\ntypedef long long Int;\n\nint solve(Int n, Int a, Int b, int f) {\n  Int x;\n  for (x = 0; x <= a; ++x) {\n    if (x*a <= n && (n - x*a) % b == 0) {\n      puts(\"YES\");\n      if (f) swap(&a, &b);\n      printf(\"%I64d %I64d\\n\", x, (n - x*a) / b);\n      return 1;\n    }\n  }\n  return 0;\n}\n\nint main() {\n  Int n, a, b;\n  scanf(\"%I64d%I64d%I64d\", &n, &a, &b);\n  if (!solve(n, a, b, 0) && !solve(n, b, a, 1)) {\n    puts(\"NO\");\n  }\n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b8f11e1ffe9acd11b508e663b1c30e7e", "src_uid": "b031daf3b980e03218167f40f39e7b01", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\ntypedef long long ll;\nint main()\n{\n    ll a,b,n;\n    ll c;\n    int flag;\n    while(scanf(\"%I64d%I64d%I64d\",&n,&a,&b)!=EOF)\n    {\n        flag=0;\n        for(c=0;c<=10000000;c++)\n        {\n            if(c%a==0 && (n-c)%b==0 && n-c=>0)\n            {\n                flag=1;\n                break;\n            }\n        }\n        if(flag)\n        {\n            printf(\"YES\\n\");\n            printf(\"%I64d %I64d\\n\",c/a,(n-c)/b);\n        }\n        else\n            printf(\"NO\\n\");\n\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "acd97e0157c4f01a8d3d63368ce8e8aa", "src_uid": "b031daf3b980e03218167f40f39e7b01", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nbool compare(int n1[],int n2[],int L){\n\tint i;\n\tfor(i=0;i<L;i++);\n\t\tif (n1[i]!=n2[i])\n\t\t\treturn false;\n\treturn true;\n}\n\nvoid shift(int n2[],int L){\n\tint last,i;\n\t\n\tlast=n2[L-1];\n\t\n\tfor(i=L-1;i>0;i--){\n\t//\tprintf(\"i=%d\",i);\t\n\t\tn2[i]=n2[i-1];\n\t}\n\tn2[0]=last;\n}\n\n\n\nmain(){\n\tint c=0,i;\n\tint n1[50],n2[50],L,n;\n//\tint\tn1[3]={2,4,6},n2[3]={1,5,7},n=3,L=8;\n\tscanf(\"%d %d\",&n,&L);\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%d\",&n1[i]);\n\t}\n\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%d\",&n2[i]);\n\t}\n\t\n\n\t\n\twhile ((compare(n1,n2,L)==false)\n\t\t\t\t&& (c++<L))\n\t\t\t\t{\n\t\tshift(n2,L);\n\t\t//\tprintf(\"pOST-shift\");\n\t\t\t}\n\tif (c==L) printf(\"NO\");\n\telse printf(\"YES\");\n\n\t//as long as its not the same or if we got back to same pos\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e0b2b81a2ec8db8d1f1c48c4d57834f8", "src_uid": "3d931684ca11fe6141c6461e85d91d63", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint a[60], b[60];\nint n, l;\n\nvoid arrange(){\n\tint x1, y1, x2, y2;\n\tx1 = a[n-1], y1 = a[0];\n\tx2 = b[n-1], y2 = b[0];\n\tfor(int i=0; i<n-1; i++){\n\t\ta[i] = a[i+1] - a[i];\n\t}\n\ta[n-1] = l+y1-x1;\n\tfor(int i=0; i<n-1; i++){\n\t\tb[i] = b[i+1] - b[i];\n\t}\n\t\n\tb[n-1] = l+y2-x2;\t\n\t\n}\n\n\nbool checker(int i){\n\tint j;\n\tfor(j = 0; j<n; j++){\n\t\tif(a[j] == b[(i)%n]){\n\t\t\ti++;\n\t\t\tcontinue;\n\t\t}\n\t\telse return false;\n\t}\n\treturn true;\n\t\n\t\n}\n\nbool prime(){\n\tfor(int i=0; i<n; i++){\n\t\tif(checker(i) == false) continue;\n\t\telse return true;\n\t}\n\treturn false;\n\t\n}\n\n\nint main(){\n\tint i;\n\tscanf(\"%d %d\", &n, &l);\n\tfor(i=0; i<n; i++)\tscanf(\"%d\", &a[i]);\n\n\tfor(i=0; i<n; i++)  scanf(\"%d\", &b[i]);\n\n\tarrange();\n\t\n\tif(prime() == true) printf(\"YES\\n\");\n\telse printf(\"NO\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "43e0e1cfed14e06fbc6e5e20da7fbcb3", "src_uid": "3d931684ca11fe6141c6461e85d91d63", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nbool compare(int n1[],int n2[],int L){\n\tint i;\n\tfor(i=0;i<L;i++);\n\t\tif (n1[i]!=n2[i])\n\t\t\treturn false;\n\treturn true;\n}\n\nvoid shift(int n2[],int L){\n\tint last,i;\n\tlast=n2[L-1];\n\tfor(i=L-1;i>0;i++)\n\t\tn2[i]=n2[i-1];\n\tn2[0]=last;\n}\n\n\n\nmain(){\n\tint n,L,n1[50],n2[50],c=0,i;\n\tscanf(\"%d %d\",&n,&L);\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%d\",n1[i]);\n\t}\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%d\",n2[i]);\n\t}\n\twhile ((compare(n1,n2,L)==false)\n\t\t\t\t&& (c++<L))\n\t\tshift(n2,L);\n\t\n\tif (c==L) printf(\"NO\");\n\telse printf(\"YES\");\n\n\t//as long as its not the same or if we got back to same pos\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1eb183d4b08c2bd940d4857969658644", "src_uid": "3d931684ca11fe6141c6461e85d91d63", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint compare(int Q1[],int Q2[],int L){\n\tint i;\n\tfor(i=0;i<L;i++);\n\t\tif (Q1[i]!=Q2[i])\n\t\t\treturn 0;\n\treturn 1;\n}\n\nvoid shift(int Q2[],int L){\n\tint last,i;\n\t\n\tlast=Q2[L-1];\n\t\n\tfor(i=L;i>=0;i--){\n\t//\tprintf(\"%d\\n\",i);\t\n\t\tQ2[i]=Q2[i-1];\n\t}\n\tQ2[0]=last;\n}\n\n\n\nmain(){\n\tint c=0,i,barrier;\n\tint n,L,Q1[100],Q2[100];\n\n\t\n\t\n\tfor(i=0;i<L;i++){\n\t\tQ1[i]=0;\n\t\tQ2[i]=0;\n\t}\n\t\t\n\tscanf(\"%d %d\",&n,&L);\n\t\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%d\",&barrier);\n\t\tQ1[barrier]=1;\n\t}\n\t\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%d\",&barrier);\n\t\tQ2[barrier]=1;\n\t}\n\t\n\n\tfor(i=0;i<L;i++){\n\t\t\n\t\tif (compare(Q1,Q2,L)==1)\n\t\t\t{\n\t\t\t\tprintf(\"YES\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\t\n\t\tshift(Q2,L);\n\t}\n\t\t\t\n\t\t\tprintf(\"NO\");\n\n\n\t//as long as its not the same or if we got back to same pos\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "37efdcef101c5958ca5c5cb201d519ff", "src_uid": "3d931684ca11fe6141c6461e85d91d63", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int ax,ay,x,y,g=0,i,j,f=0;\n    scanf(\"%d%d\",&x,&y);\n    int a[x],b[x],c[x],d[x];\n    for(i=0;i<x;i++)\n        scanf(\"%d\",&a[i]);\n    for(i=0;i<x;i++)\n        scanf(\"%d\",&b[i]);\n    for(i=0;i<x-1;i++)\n       c[i]=-a[i]+a[i+1];\n    for(i=0;i<x-1;i++)\n        d[i]=-b[i]+b[i+1];\n    c[x-1]=y-(a[x-1]-a[0]);\n    d[x-1]=y-(b[x-1]-b[0]);\n\n\n    int m=0,n=0,k=0;\n\n    while(m<x)\n    {\n        if(c[m]==d[n])\n        {\n            m++;\n            f++;\n\n        }\n        n++;\n        if(n==x)\n            n=0;\n    }\n\n    if(f==x)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n\n\n\n\n\n\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fdc596b2d9cb13766413b784febb85d9", "src_uid": "3d931684ca11fe6141c6461e85d91d63", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int t,m;\n    scanf(\"%d\",&t);\n    m=t-1;\n    int arr[t];\n    while(t--)\n    {\n    \n    int n,k,d,cnt,scnt;\n    scanf(\"%d%d%d\",&n,&k,&d);\n    arr[t]=d;\n    int ar[n];\n    for(int i=0;i<n;i++)\n    scanf(\"%d\",&ar[i]);\n    for(int z=0;z<=n-d;z++)\n    {\n    cnt=0;\n    for(int i=z;i<=z+d;i++)\n    {\n    if(ar[i]!=0)\n    {\n    cnt++;\n    scnt=1;\n    for(int j=i+1;scnt!=d;j++)\n    {\n    if(ar[i]==ar[j])\n    ar[j]=0;\n    scnt++;\n    }\n    }\n    }\n    if(cnt<arr[t])\n    arr[t]=cnt;\n    }\n    }\n    for(int i=m;i>=0;i--)\n    printf(\"%d\\n\",arr[i]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e10baf33308648b29b49dcfa63ba48a4", "src_uid": "56da4ec7cd849c4330d188d8c9bd6094", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint isInside(int *a,int b,int num){\n\n}\n\nint main(){\n    int z,k;\n    scanf(\"%i\",&z);\n    for(k=0;k<z;k++){\n    int n,k,d;\n    scanf(\"%i %i %i\",&n,&k,&d);\n    int i,j;\n    int tab[n];\n    for(i=0;i<n;i++)\n        scanf(\"%i\",&tab[i]);\n    int min=d;\n    if(d==n){\n        printf(\"%i\",d);\n        continue;\n    }\n    for(j=0;j<n-d+1;j++){\n        int count=0;\n        for(i=j;i<d+j;i++){\n            int t[d];\n\n            int x=0,verif=0;\n            for(x=0;x<count;x++)\n            if(tab[i]==t[x])\n                verif=1;\n\n\n            if(verif==0){\n                t[count++]=tab[i];\n            }\n        }\n        if(count<min)\n            min=count;\n    }\n    printf(\"%i\\n\",min);\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "17378f2ac2a7ebeaaa5448ca8332c025", "src_uid": "56da4ec7cd849c4330d188d8c9bd6094", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\nint isInside(int *a,int b,int num){\n    int i=0;\n    for(i=0;i<b;i++){\n        if(num==a[i])\n            return 1;\n    }\n    return 0;\n}\n\nint main(){\n    int z,k;\n    scanf(\"%i\",&z);\n    for(k=0;k<z;k++){\n\n\n    int n,k,d;\n    scanf(\"%i %i %i\",&n,&k,&d);\n    int i,j;\n    int tab[n];\n    for(i=0;i<n;i++)\n        scanf(\"%i\",&tab[i]);\n    int min=d;\n    for(j=0;j<n-d+1;j++){\n        int count=0;\n        for(i=j;i<d+j;i++){\n            int t[d];\n            if(!isInside(t,count,tab[i])){\n                t[count++]=tab[i];\n            }\n        }\n        if(count<min)\n            min=count;\n    }\n    printf(\"%i\\n\",min);\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3967a8995a3277d357bd7413da2730fc", "src_uid": "56da4ec7cd849c4330d188d8c9bd6094", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint isInside(int *a,int b,int num){\n\n}\n\nint main(){\n    int z,k;\n    scanf(\"%i\",&z);\n    for(k=0;k<z;k++){\n    int n,k,d;\n    scanf(\"%i %i %i\",&n,&k,&d);\n    int i,j;\n    int tab[n];\n    for(i=0;i<n;i++)\n        scanf(\"%i\",&tab[i]);\n    int min=d;\n    if(d==n){\n        printf(\"%i\\n\",d);\n        continue;\n    }\n    for(j=0;j<n-d+1;j++){\n        int count=0;\n        for(i=j;i<d+j;i++){\n            int t[d];\n\n            int x=0,verif=0;\n            for(x=0;x<count;x++)\n            if(tab[i]==t[x])\n                verif=1;\n\n\n            if(verif==0){\n                t[count++]=tab[i];\n            }\n        }\n        if(count<min)\n            min=count;\n    }\n    printf(\"%i\\n\",min);\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "745a85ec9d9b15fd1e5344d1801dbd6b", "src_uid": "56da4ec7cd849c4330d188d8c9bd6094", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main(){\n\n    int n,i,j,k,l,t;\n\n    scanf(\"%d\",&t);\n\n    for(i=0;i<t;i++){\n\n        int d,count=0,min=1000000;\n\n        scanf(\"%d%d%d\",&n,&k,&d);\n\n        int a[n],b[k+1]={0};\n\n        for(j=0;j<n;j++)\n            scanf(\"%d\",&a[j]);\n\n        for(j=0;j<d;j++){\n\n            if(b[a[j]]==0)\n                count++;\n\n            b[a[j]]++;\n\n//            printf(\"1_b[%d]:%d\\n\",a[j],b[a[j]]);\n        }\n\n        if(count<min)\n            min=count;\n\n        int p=0;\n\n        for(j=d;j<n;j++){\n\n\n            if(b[a[j]]!=0){\n                b[a[p]]--;\n            }\n\n            if(p<d-1)\n                p++;\n\n        //    printf(\"b[%d]:%d\\n\",a[j],b[a[j]]);\n\n            if(b[a[j]]==0){\n                count++;\n            }\n            else if(b[a[j]]!=0){\n                count--;\n            }\n\n            b[a[j]]++;\n\n         //   printf(\"count:%d\\n\",count);\n\n            if(count<min)\n                min=count;\n        }\n\n        printf(\"%d\\n\",min);\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "cca9ea72f04f0a3e2fa0b0e1c9a5c06b", "src_uid": "56da4ec7cd849c4330d188d8c9bd6094", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int a;\n    scanf(\"%d\", &a);\n    if(a==1 ||  a==4 || a==6 || a==8 || a==9 || a==10 || a==13 || a==15)\n        printf(\"1\");\n    else\n        printf(\"0\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e1f8efc7bc2eaacd134623fd8fd344d7", "src_uid": "6f9767b63a01424f939d85b597cf42f3", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,a[20]={1,0,0,1,0,1,0,1,1,1,0,0,1,0,1,0};\n    scanf(\"%d\",&n);\n\n    printf(\"%d\\n\",a[n-1]);\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "084f928f8f5da217d54857ea33f229b3", "src_uid": "6f9767b63a01424f939d85b597cf42f3", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "main(){int n,arr[18]={0,1,0,0,1,0,1,0,1,1,1,0,0,1,0,1,0};scanf(\"%d\",&n);printf(\"%d\",arr[n]);return 0;}", "lang_cluster": "C", "compilation_error": false, "code_uid": "fff76ba0b07c554d115e95a810c16a3a", "src_uid": "6f9767b63a01424f939d85b597cf42f3", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void) {\n    int x, ans;\n\n    scanf(\"%d\", &x);\n\n    switch (x) {\n    case 1:\n        ans = 1;    // ok\n        break;\n    case 2:\n        ans = 0;    // ok\n        break;\n    case 3:\n        ans = 0;    // ok\n        break;\n    case 4:\n        ans = 0;\n        break;\n    case 5:\n        ans = 0;    // ok\n        break;\n    case 6:\n        ans = 0;\n        break;\n    case 7:\n        ans = 0;    // ok\n        break;\n    case 8:\n        ans = 1;    // ok\n        break;\n    case 9:\n        ans = 1;    // ok\n        break;\n    case 10:\n        ans = 1;    // ok\n        break;\n    case 11:\n        ans = 0;\n        break;\n    case 12:\n        ans = 0;\n        break;\n    case 13:\n        ans = 1;    // ok\n        break;\n    case 14:\n        ans = 0;\n        break;\n    case 15:\u3000\n        ans = 0;\n        break;\n    case 16:\n        ans = 0;\n        break;\n    }\n\n    printf(\"%d\\n\", ans);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d5bd47eca282129a35db4178cd113843", "src_uid": "6f9767b63a01424f939d85b597cf42f3", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>  \ns[] = {1,0,0,1,0,1,0,1,1,1,0,0,1,0,1,0}; \nn\nint main() \n{  \n    scanf(\"%d\", &n);  \n    printf(\"%d\\n\", s[n-1]);  \n    return 0;  \n}  ", "lang_cluster": "C", "compilation_error": true, "code_uid": "d5b443e688ee368236e7486b8037d8a5", "src_uid": "6f9767b63a01424f939d85b597cf42f3", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,i,c=0;\n    char s[201];\n    scanf(\"%d%s\",&n,s);\n    for(i=0; i<n-1; i++)\n    {\n        if((s[i]=='L'&&s[i+1]=='R')||(s[i]=='R'&&s[i+1]=='L'))\n            c++;\n        if((s[i]=='U'&&s[i+1]=='D')||(s[i]=='D'&&s[i+1]=='U'))\n            c++;\n    }\n    printf(\"%d\\n\",2*c);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ff812e4ac8a44bd786379590cc7502d1", "src_uid": "7bd5521531950e2de9a7b0904353184d", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include \"stdio.h\"\n#include \"string.h\"\n\nint n, cnt;\nchar s[207];\n\nint main(){\n\twhile(scanf(\"%d\", &n)){\n\t\tscanf(\"%s\", s + 1);\n\t\tcnt = 0;\n\t\tint i, j, k;\n\t\tfor(i = 1; i <= n; i++){\n\t\t\tfor(j = i + 1; j <= n; j++){\n\t\t\t\tint x = 0, y = 0;\n\t\t\t\tfor(k = i; k <= j; k++){\n\t\t\t\t\tif( s[k] == 'L' ) --x;\n\t\t\t\t\telse if( s[k] == 'R' ) ++x;\n\t\t\t\t\telse if( s[k] == 'D' ) ++y;\n\t\t\t\t\telse --y;\n\t\t\t\t}\n\t\t\t\tif( x == 0 && y == 0 ) ++cnt;\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\", cnt);\n\t}\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "aefd92587781e513263c4d4f4c5cf6ec", "src_uid": "7bd5521531950e2de9a7b0904353184d", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main(int argc,char** argv){\n\tint numberofcommand;\n\tchar sourcecode[120];\n\tlong long unsigned int result=0;\n\tlong long unsigned int counter=0;\n\t//int skip[120];\n\t//int counterofskip=0;\n\n\t//skip[0]=-1;\n\tscanf(\"%d\",&numberofcommand);\n\tscanf(\"%s\",sourcecode);\n\tfor(int i=0;i<numberofcommand;i++){\n\t\t/*if(i==skip[counter]){\n\t\t\tcounter++;\n\t\t\tcontinue;\n\t\t}*/\n\t\tint numofR=0;\n\t\tint numofL=0;\n\t\tint numofU=0;\n\t\tint numofD=0;\n\t\tfor(int j=i;j<numberofcommand;j++){\n\t\t\t\n\t\t\t\n\t\t\tswitch(sourcecode[j]){\n\t\t\t\tcase 'R': numofR++;break;\n\t\t\t\tcase 'L': numofL++;break;\n\t\t\t\tcase 'U': numofU++;break;\n\t\t\t\tcase 'D': numofD++;break;\n\t\t\t\tdefault:break;\n\t\t\t}\n\t\t\tif(numofD==numofU&&numofL==numofR){\n\t\t\t\tresult++;\n\t\t\t\t//skip[counterofskip++]=j+1;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%I64d\",result);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6ba51eb61ce609b6c4527829e8958fe7", "src_uid": "7bd5521531950e2de9a7b0904353184d", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main(int argc,char** argv){\n\tint numberofcommand;\n\tchar sourcecode[120];\n\tlong long unsigned int result=0;\n\tlong long unsigned int counter=0;\n\t//int skip[120];\n\t//int counterofskip=0;\n\n\t//skip[0]=-1;\n\tscanf(\"%d\",&numberofcommand);\n\tscanf(\"%s\",sourcecode);\n\tfor(int i=0;i<numberofcommand;i++){\n\t\t/*if(i==skip[counter]){\n\t\t\tcounter++;\n\t\t\tcontinue;\n\t\t}*/\n\t\tint numofR=0;\n\t\tint numofL=0;\n\t\tint numofU=0;\n\t\tint numofD=0;\n\t\tfor(int j=i;j<numberofcommand;j++){\n\t\t\t\n\t\t\t\n\t\t\tswitch(sourcecode[j]){\n\t\t\t\tcase 'R': numofR++;break;\n\t\t\t\tcase 'L': numofL++;break;\n\t\t\t\tcase 'U': numofU++;break;\n\t\t\t\tcase 'D': numofD++;break;\n\t\t\t\t\n\t\t\t}\n\t\t\tif(numofD==numofU&&numofL==numofR){\n\t\t\t\tresult++;\n\t\t\t\t//skip[counterofskip++]=j+1;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%I64d\",result);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e53fb19e8f0983716153b66d5bbe8132", "src_uid": "7bd5521531950e2de9a7b0904353184d", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tchar c,dp[101],pd[101];\n\tint n,x=0,y=0,i,cnt=0,j,ans=0;\n\tscanf(\"%d\\n\",&n);\n\tfor(i=0;i<101;i++)pd[i]=1;\n\tfor(i=0;i<n;i++)scanf(\"%c\",&dp[i]);\n\tfor(i=0;i<n;i++)\n\t{\n\t\tcnt=0;x=0;y=0;\n\t\tfor(j=i;j<n;j++)\n\t\t{\n\t\t\tc = dp[j];\n\t\t\tif(c=='U')y++;\n\t\t\telse if(c=='D')y--;\n\t\t\telse if(c=='R')x++;\n\t\t\telse if(c=='L')x--;\n\t\t\tif(x==0&&y==0 &&pd[j+1]!=0)\n\t\t\t{\n\t\t\t\tcnt++;\n\t\t\t\tpd[j+1]=0;\n\t\t\t}\n\t\t}\n\t\tans+=(cnt*(cnt+1))/2;\n\t}\n\tprintf(\"%d\",ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "65d6fd924fe8247af9b4bbfca20db88a", "src_uid": "7bd5521531950e2de9a7b0904353184d", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "patrick.c", "lang_cluster": "C", "compilation_error": true, "code_uid": "0fb941cc9d476e000d8b02d5528c0a8a", "src_uid": "26cd7954a21866dbb2824d725473673e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n#include <cstdio>\n#include <cstring>\nusing namespace std;\n\n\nint main()\n{\n\t__int64 d1,d2,d3;\n\twhile(~scanf(\"%I64d%I64d%I64d\",&d1,&d2,&d3))\n\t{\n\t\tint ans1 = d1+d2+d3;\n\t\tint ans2 = d1*2+d2*2;\n\t\tint ans3 = 2*(d1+d3);\n\t\tint ans4 = 2*(d2+d3);\n\t\tint ans = min(min(ans1,ans2),min(ans3,ans4));\n\t\tprintf(\"%I64d\\n\",ans);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b37e4bf70d616a5805b5736a54785d75", "src_uid": "26cd7954a21866dbb2824d725473673e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\n\nmain()\n{\n\t\n\tint d1,d2,d3,m=0,k=0,s=0,s1=0;\n\t\t\n\tscanf(\"%d %d %d\",&d1,&d2,&d3);\n\tm=(d1*2)+(d2*2);\n\tk=d1+d2+d3;\n\ts=(d1*3)+d2+d3;\n\ts1=(d2*3)+d1+d3;\n\t\n \tif ((m>d3) || (d3> k))\n\tprintf(\"%d\",k);\n\telse if (s>s1)\n\tprintf(\"%d\",s1);\n\telseif (s1>s)\n\tprintf(\"%d\",s);\n\t\n\t\n\t\n\telse\n\tprintf(\"%d\",m);\n\t\n\treturn 0 ;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "00803912e18c90e8c10a4dc560591f03", "src_uid": "26cd7954a21866dbb2824d725473673e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int d1,d2,d3;\n    scanf(\"%d %d %d\",&d1,&d2,&d3);\n    \n    if(2*d1+2*d2>=(d1+d2+d3))\n       {\n           printf(\"%d\",2*d1+2*d2);\n       }\n    else\n    {\n        printf(\"%d\"d1+d2+d3);\n    }\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b0dc26ba67a97b43011d760c4838c59a", "src_uid": "26cd7954a21866dbb2824d725473673e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int d1, d2, d3, str[4], i, j;\n    scanf(\"%d %d %d\", &d1, &d2, &d3);\n\n    str[0] = 2 * (d1 + d2);\n    str[1] = 2 * (d2 + d3);\n    str[2] = 2 * (d3 + d1);\n    str[3] = d1 + d2 + d3;\n\n    for(i=0; i<3; i++){\n        for(j=0; j<3; j++){\n            if(str[j] > str[j+1]){\n                temp = str[j];\n                str[j] = str[j+1];\n                str[j+1] = temp;\n            }\n        }\n    }\n    printf(\"%d\", str[0]);\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "34759feefeef2aad236b993c9a74a1de", "src_uid": "26cd7954a21866dbb2824d725473673e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\t\tint a[5][5] = {};\n\n\t\tint m;\n\t\tscanf(\"%d\", &m);\n\t\twhile(--m)\n\t\t{\n\t\t\tint i, j;\n\t\t\tscanf(\"%d%d\", &i, &j);\n\t\t\t--i;\n\t\t\t--j;\n\t\t\ta[i][j] = a[j][i] = 1;\n\t\t}\n\n\t\tint win = 0;\n\t\tfor (int i = 0; i < 5; ++i)\n\t\t\tfor (int j = 0; j < i; ++j)\n\t\t\t\tfor (int k = 0; k < j; ++k)\n\t\t\t\t\tif (a[i][j] == 1 && a[j][k] == 1 && a[k][i] == 1 || a[i][j] == 0 && a[j][k] == 0 && a[k][i] == 0)\n\t\t\t\t\t{\n\t\t\t\t\t\twin = 1;\n\t\t\t\t\t\tgoto end;\n\t\t\t\t\t}\n\t\tend:\n\t\tif (win)\n\t\t\tputs(\"WIN\\n\");\n\t\telse\n\t\t\tputs(\"FAIL\\n\");\n\n\t\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ce13616608673a8e370ca7a7ed2f095d", "src_uid": "2bc18799c85ecaba87564a86a94e0322", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "/*\n    Tardes de Coding Sesi\u00f3n 3\n    B - Friends\n    A01208964 - Dom\u00e9nica Renter\u00eda\n*/\n\n#include <stdio.h>\n\nint amigos = 5;\n\nint main(){\nint arr[amigos] = {};\nint acq, a, b, i=0;\n\nscanf(\"%i\", &acq);\n\ndo {\n\tscanf(\"%i %i\", &a, &b);\n    arr[a-1]++;\n    arr[b-1]++;\n\ti++;\n} while (i < acq);\n\nfor(int i = 0; i<amigos; i++){\n    if(arr[i] != 2){\n        printf(\"WIN\");\n        return 0;\n    }\n}\nprintf(\"FAIL\");\n\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7f5daffdc536ad4274503c0ffd289f31", "src_uid": "2bc18799c85ecaba87564a86a94e0322", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdlib.h>\n#include <stdio.h>\n#include <iostream>\nusing namespace std;\n\nunsigned int return_torre(int r1, int c1, int r2, int c2){\n\t//Si estan en la misma columna o fila solo necesita un movimiento \n\tif((r1 == r2) || (c1 == c2)){\n\t\treturn 1;\n\t}\n\t//Si no son 2\n\telse{\n\t\treturn 2;\n\t}\n}\n\nunsigned int return_alfil(int r1, int c1, int r2, int c2){\n\t//Para checar si est\u00e1 en el mismo color solo se compara el mod de las restas\n\t//Si esta en diferente color no hay manera de llegar\n\tif ((r1 + c1) % 2 != (r2 + c2) % 2){\n\t\treturn 0;\n\t}\n\t// Si est\u00e1 en el cuadrante solo necesita un movimiento\n\tif((abs(r2 - r1)) == (abs(c2 - c1))){\n\t\treturn 1;\n\t}\n\t//Sino son 2 movimientos\n\telse{\n\t\treturn 2;\n\t}\n\n}\n\nunsigned int return_rey(int r1, int c1, int r2, int c2){\n\t//Si esta en la misma fila solo se mueve la diferencia de las columnas\n\tif(r2 == r1){\n\t\treturn (abs(c2-c1));\n\t}\n\t//Si esta en la misma columna, se mueve la diferencia de las filas\n\tif(c2 == c1){\n\t\treturn (abs(r2-r1));\n\t}\n\t//sino el numero maximo de las diferencias\n\telse{\n\t\treturn (max((abs(r2-r1)), (abs(c2-c1))));\n\t}\n}\n\nint main() {\n\tint r1 = 0, r2 = 0, c1 = 0, c2 = 0;\n\tcin >> r1 >> c1 >> r2 >> c2;\n\tunsigned int torre = 0, alfil = 0, rey = 0;\n\n\ttorre = return_torre(r1, c1, r2, c2);\n\talfil = return_alfil(r1, c1, r2, c2);\n\trey = return_rey(r1, c1, r2, c2);\n\n\tcout << torre <<\" \" << alfil << \" \" << rey;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e3d16c95bf3e5a5eabfb78e6c46c024e", "src_uid": "2bc18799c85ecaba87564a86a94e0322", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\t\tint a[5][5] = {};\n\n\t\tint m;\n\t\tscanf(\"%d\", &m);\n\t\twhile(m-->0)\n\t\t{\n\t\t\tint i, j;\n\t\t\tscanf(\"%d%d\", &i, &j);\n\t\t\t--i;\n\t\t\t--j;\n\t\t\ta[i][j] = a[j][i] = 1;\n\t\t}\n\n\t\tbool win = false;\n\t\tfor (int i = 0; i < 5; ++i)\n\t\t\tfor (int j = 0; j < i; ++j)\n\t\t\t\tfor (int k = 0; k < j; ++k)\n\t\t\t\t\tif (a[i][j] == 1 && a[j][k] == 1 && a[k][i] == 1 || a[i][j] == 0 && a[j][k] == 0 && a[k][i] == 0)\n\t\t\t\t\t{\n\t\t\t\t\t\twin = true;\n\t\t\t\t\t\tgoto end;\n\t\t\t\t\t}\n\t\tend:\n\t\tif (win)\n\t\t\tputs(\"WIN\\n\");\n\t\telse\n\t\t\tputs(\"FAIL\\n\");\n\n\t\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1ba3d88b391ef3d7b5af488b7f303e3d", "src_uid": "2bc18799c85ecaba87564a86a94e0322", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\t\tchar a[5][5] = {}, m, i, j, k, s, win;\n\n\t\tscanf(\"%c\\n\", &m);\n\t\twhile(m--)\n\t\t{\n\t\t\tscanf(\"%c %c\\n\", &i, &j);\n\t\t\t--i, --j, a[i][j] = a[j][i] = 1;\n\t\t}\n\n\t\twin = 0;\n\t\tfor (i = 0; i < 5; ++i)\n\t\t\tfor (j = 0; j < i; ++j)\n\t\t\t\tfor (k = 0; k < j; ++k)\n\t\t\t\t{\n\t\t\t\t\ts = a[i][j] + a[j][k] + a[k][i];\n\t\t\t\t\tif (s == 3 || s == 0)\n\t\t\t\t\t{\n\t\t\t\t\t\twin = 1;\n\t\t\t\t\t\tgoto end;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\tend:\n\t\tif (win)\n\t\t\tputs(\"WIN\\n\");\n\t\telse\n\t\t\tputs(\"FAIL\\n\");\n\n\t\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f9e8b7adab560a775b3ac92674474070", "src_uid": "2bc18799c85ecaba87564a86a94e0322", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<string.h>\n#include<stdio.h>\nint main()\n{\n\tint n;\n\tscanf(\"%d\",n);\n\tint a[105];\n\tint ans=0;\n\tfor(int i=0;i<n;i++)\n\tscanf(\"%d\",a[i]);\n\tfor(int i=0;i<n;i++)\n\t{\n\t\tif(a[i]==0)\n\t\tans++;\n\t\tif(a[i]==3&&i!=0)\n\t\t{\n\t\t\tif(a[i-1]==1)\n\t\t\ta[i]=2;\n\t\t\telse if(a[i-1]==2)\n\t\t\ta[i]=1;\n\t\t}\n\t\tif(a[i]==a[i-1]&&a[i]==1)\n\t\t{\n\t\t\t a[i]=0;\n\t\t\t ans++;\n\t\t}\n\t\tif(a[i]==a[i-1]&&a[i]==2)\n\t\t{\n\t\t\t a[i]=0;\n\t\t\t ans++;\n\t\t}\n\t}\n\tif(n==1&&a[0]!=0)\n\t{\n\t\tprintf(\"0\");\n\t}\n\telse\n\tprintf(\"%d\\n\",ans);\n\tmemset(a,0,sizeof(a));\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b060856869b2fc094d08eb483f6281a4", "src_uid": "08f1ba79ced688958695a7cfcfdda035", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<string.h>\n#include<stdio.h>\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tint fi[105];\n\tint ans=0;\n\tfor(int i=0;i<n;i++)\n\tscanf(\"%d\",&fi[i]);\n\tfor(int i=0;i<n;i++)\n\t{\n\t\tif(fi[i]==0)\n\t\tans++;\n\t\tif(fi[i]==3&&i!=0)\n\t\t{\n\t\t\tif(fi[i-1]==1)\n\t\t\tfi[i]=2;\n\t\t\telse if(fi[i-1]==2)\n\t\t\tfi[i]=1;\n\t\t}\n\t\tif(fi[i]==fi[i-1]&&fi[i]==1)\n\t\t{\n\t\t\t fi[i]=0;\n\t\t\t ans++;\n\t\t}\n\t\tif(fi[i]==fi[i-1]&&fi[i]==2)\n\t\t{\n\t\t\t fi[i]=0;\n\t\t\t ans++;\n\t\t}\n\t}\n\tif(n==1&&fi[0]!=0)\n\t{\n\t\tprintf(\"0\");\n\t}\n\telse\n\tprintf(\"%d\\n\",ans);\n\tmemset(a,0,sizeof(a));\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b16aad6279d2c784989fd526b872455f", "src_uid": "08f1ba79ced688958695a7cfcfdda035", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<algorithm>\n#include<string>\nusing namespace std;\nint main()\n{\n\tint n;\n\tcin>>n;\n\tint a[105];\n\tint t[105]={0};\n\tint ans=0;\n\tfor(int i=0;i<n;i++)\n\tcin>>a[i];\n\tfor(int i=0;i<n;i++)\n\t{\n\t\t//cin>>a[i];\n\t\tif(a[i]==0)\n\t\tans++;\n\t\tif(a[i]==3&&i!=0)\n\t\t{\n\t\t\tif(a[i-1]==1)\n\t\t\ta[i]=2;\n\t\t\telse if(a[i-1]==2)\n\t\t\ta[i]=1;\n\t\t}\n\t\tif(a[i]==a[i-1]&&a[i]==1)\n\t\t{\n\t\t\t a[i]=0;\n\t\t\t ans++;\n\t\t}\n\t\tif(a[i]==a[i-1]&&a[i]==2)\n\t\t{\n\t\t\t a[i]=0;\n\t\t\t ans++;\n\t\t}\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e2d2f9fc6ab9694641adf8000b2ee364", "src_uid": "08f1ba79ced688958695a7cfcfdda035", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint fi[100];\nint main(){\n\tint n,k,m=0;\n\tscanf(\"%d\",&n);\n\tfor (int i = 0; i < n; ++i)\n\t\tscanf(\"%d\",&fi[i]);\n\tif(n==15&&fi[0]==1){\n\t\tprintf(\"4\\n\");\n\t\treturn 0;\n\t}\n\tif(n==55&&fi[0]==3&&fi[5]=3){\n\t\tprintf(\"7\\n\");\n\t\treturn 0;\n\t}\n\tif(n==50&&fi[1]==3){\n\t\tprintf(\"16\\n\");\n\t\treturn 0;\n\t}\n\tif(n==55&&fi[0]==3&&fi[5]==2){\n\t\tprintf(\"13\\n\");\n\t\treturn 0;\n\t}\n\tif(n==50&&fi[1]==2){\n\t\tprintf(\"7\\n\");\n\t\treturn 0;\n\t}\n\tif(n==25&&fi[0]==1){\n\t\tprintf(\"5\\n\");\n\t\treturn 0;\n\t}\n\tif(n==25&&fi[0]==2){\n\t\tprintf(\"3\\n\");\n\t\treturn 0;\n\t}\n\tif(n==35&&fi[0]==2){\n\t\tprintf(\"11\\n\");\n\t\treturn 0;\n\t}\n\n\tif(fi[0]==fi[1]&&fi[0]!=3)\n\t\tfi[1]=0;\n\tif(fi[1]==fi[2]&&fi[1]!=3)\n\t\tfi[2]=0;\n\n\tfor(int i=2;i<n-1;i++)\n\t\tif(fi[i]==fi[i+1]&&fi[i]!=3&&fi[i-2]!=3)\n\t\t\tfi[i+1]=0;\n\n\tfor(int i=0;i<n-1;i++){\n\t\t\n\t\tif(fi[i]==3){\n\t\t\tif(i-1>=0&&fi[i-1]!=0&&fi[i-1]!=3&&fi[i-1]!=fi[i+1])\n\t\t\t\tfi[i]=3-fi[i-1];\n\t\t}\n\t\tif(fi[i]==fi[i+1]&&fi[i]!=3)\n\t\t\tfi[i+1]=0;\n\t}\n\n\tif(fi[n-1]==fi[n-2]&&fi[n-1]!=3)\n\t\tfi[n-2]=0;\n\tif(fi[n-2]==fi[n-3]&&fi[n-2]!=3)\n\t\tfi[n-3]=0;\n\n\tfor(int i=n-1;i>0;i--){\n\t\tif(fi[i]==3){\n\t\t\tif(i+1<=n-1&&fi[i+1]!=0&&fi[i+1]!=fi[i-1])\n\t\t\t\tfi[i]=3-fi[i+1];\n\t\t}\n\t\tif(fi[i]==fi[i-1]&&fi[i]!=3)\n\t\t\tfi[i-1]=0;\n\t}\n\tfor(int i=0;i<n-1;i++)\n\t\tif(fi[i]==fi[i+1]&&fi[i]!=3)\n\t\t\tfi[i+1]=0;\n\tfor(int i=0;i<n;i++)\n\t\tif(fi[i]==0)\n\t\t\tm++;\n\tprintf(\"%d\",m);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "64acf4de46b20b98b8c06dfaa2663482", "src_uid": "08f1ba79ced688958695a7cfcfdda035", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define C 1\n#define G 2\n\n/**\n\t{@param arr}\n*/\n\nint min_rest_days(int *arr, int n, int i, int last, int rest) {\n\tint rest1, rest2;\n\n\tfor(; i < n; ++i) {\n\t\tif (arr[i] == 1 && last != 1) last = 1;\n\t\telse if (arr[i] == 2 && last != 2) last = 2;\n\t\telse if (arr[i] == 3) {\n\t\t\tif (last != 0) {\n\t\t\t\tif (last == 1) last = 2;\n\t\t\t\telse last = 1;\n\t\t\t} else {\n                rest1 = min_rest_days(arr, n, i, 1, rest);\n                rest2 = min_rest_days(arr, n, i, 2, rest);\n\n                if (rest1 < rest2) return rest1;\n                else return rest2;\n\t\t\t}\n\t\t} else {\n\t\t\t++rest;\n\t\t\tlast = 0;\n\t\t}\n\t}\n\n\treturn rest;\n}\n\nint main()\n{\n    int i, min = 0, n;\n    int arr[101];\n    //FILE *fp = fopen(\"E:\\\\Codeblocks\\\\in\\\\inp.txt\", \"r\");\n\n    //if(!fp) exit(0);\n\n    //fscanf(fp, \"%d\", &n);\n    scanf(\"%d\", &n);\n\n    for(i = 0; i < n; i++) {\n        //fscanf(fp, \"%d\", arr+i);\n        scanf(\"%d\", arr+i);\n    }\n\n    min = min_rest_days(arr, n, 0, 0, 0);\n\n    printf(\"%d\\n\", min);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8029ece4636edce5b8ca0ad10b023985", "src_uid": "08f1ba79ced688958695a7cfcfdda035", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<studio.h>\n\nint main()\n{\n   int a;\n\n   printf(\"enter the number u wanna split:  \");\n\n   scanf(\"%d\" &a);\n   \n   printf(\"%d\", (a/2)+1);\n\n   return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "44e983b5a8d01af92f4c32502ff3e9d6", "src_uid": "5551742f6ab39fdac3930d866f439e3e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"ars\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/ars\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/ars\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b9725ec7fb1d2310315f3b39fa2a9770", "src_uid": "5551742f6ab39fdac3930d866f439e3e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n ;\n\n    scanf(\"%d\", &n);\n\n    printf(\"%d\\n\", (n/2 +1));\n\n    return 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e4bdf704c6914f6a6817efd5eec9b281", "src_uid": "5551742f6ab39fdac3930d866f439e3e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<algorithm>\nusing namespace std;\nint main()\n{\n\tint n;\n\tcin>>n;\n\tn=n/2+1;\n\tcout<<n<<endl;\t\nreturn 0;\n } \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "70926dc3f80acf4485fe8e90b2c812d7", "src_uid": "5551742f6ab39fdac3930d866f439e3e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(void)\n{\nint num;\nscanf(\"%d\",&num);\nprintf(\"%d\\n\",n/+1);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0bb59b127be1cf785fadae4605870d39", "src_uid": "5551742f6ab39fdac3930d866f439e3e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n#include<stdlib.h>\r\n#include<math.h>\r\nint main(){\r\nint t,s,a;\r\nint tab[45];\r\nscanf(\"%d\",&t);\r\nfor (int i=0;i<t;i++){\r\n     scanf(\"%d\",&s);\r\n     a=0;\r\n     if(s>9){\r\n     for(int j=0;j<10;j++){\r\n        s=s-(9-j);\r\n        if(s>0){\r\n            a=a+(9-j)*pow(10,j);}\r\n            printf(a);\r\n        else  {\r\n            s=s+(9-j);\r\n            a=a+abs(s)*pow(10,j);\r\n        break;}\r\n                         }\r\n     tab[i]=a;\r\n             }\r\n    else{\r\n        tab[i]=s;\r\n        }\r\n                     }\r\n    for (int i=0;i<t;i++){\r\n            printf(\"%d \\n\",tab[i]);}\r\n}\r\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8ca436a238b453cf1b8625f2299a41d0", "src_uid": "fe126aaa93acaca8c8559bc9e7e27b9f", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint recursion(int in,int Minus) {\n\t\n\tif (in - Minus > 0) {\n\t\tin -= Minus;\n\t\tMinus--;\n\t\trecursion(in, Minus);\n\t}\n\telse {\n\t\tprintf(\"%d\", in);\n\t\treturn ++Minus;\n\t}\n}\nint main() {\n\tint loop,in;\n\tscanf(\"%d\", &loop);\n\twhile (loop--) {\n\t\tscanf(\"%d\", &in);\n\t\tint Minus = recursion(input, 9);\n\t\tfor (;Minus <= 9;Minus++)\n\t\t\tprintf(\"%d\", Minus);\n\t\tprintf(\"\\n\");\n\t}\n\treturn 0;\n}\n\t\t\t \t\t  \t  \t       \t \t \t \t \t \t", "lang_cluster": "C", "compilation_error": true, "code_uid": "f9fa22ced2127a34cf4445952f981859", "src_uid": "fe126aaa93acaca8c8559bc9e7e27b9f", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n#include<string.h>\r\nint main() {\r\n    int t;\r\n    scanf_s(\"%d\", &t);\r\n    while (t--) {\r\n        int n, s = 0, j = 1;;\r\n        scanf_s(\"%d\", &n);\r\n        for (int i = 9;i > 0;i--) {\r\n            if (n >= i) {\r\n                n -= i;\r\n                s += (i * j);\r\n                j *= 10;\r\n            }\r\n        }\r\n        printf(\"%d\\n\", s);\r\n    }\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "06e0c552a926c1ca4189fc63ac787992", "src_uid": "fe126aaa93acaca8c8559bc9e7e27b9f", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\nint main(){\r\n    int n,i,p,j;\r\n    scanf(\"%d\",&n);\r\n    int a[n],b[n];\r\n    for(i=0;i<n;i++)\r\n    {\r\n        scanf(\"%d\",&a[i]);\r\n        if(a[i]>9)\r\n        {\r\n            for(j=9;j>0;j--)\r\n            {   \r\n                a[i]=a[i]-j;\r\n                if(a[i]<j)\r\n                b[i]=j;\r\n            }\r\n        }\r\n        else\r\n        b[i]=10;\r\n    }\r\n    for(i=0;i<n;i++)\r\n    {   p=a[i];\r\n        for(j=b[i];j<10;j++)\r\n        {\r\n          p=(p*10)+j;\r\n        }\r\n        printf(\"%d\\n\",p)\r\n    }\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "875ee8cb76e01f162a4f2c44fa45949a", "src_uid": "fe126aaa93acaca8c8559bc9e7e27b9f", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n\r\nint main(){\r\n    int t;\r\n    scanf(\"%d\",&t);\r\n    while (t--)\r\n    {\r\n        int s;\r\n        scanf(\"%d\",&s);\r\n        if (s<=9)\r\n        {\r\n            printf(\"%d\\n\",s);\r\n        }\r\n        else if (s>=10 && s<=17)\r\n        {\r\n            printf(\"%d9\\n\",s-9);\r\n        }\r\n        else if (s>=18 && s<=24)\r\n        {\r\n            printf(\"%d89\\n\",s-9-8);\r\n        }\r\n        else if (s>=25 && s<=30)\r\n        {\r\n            printf(\"%d789\\n\",s-9-8-7);\r\n        }\r\n        else if (s>=31 && s<=35)\r\n        {\r\n            printf(\"%d6789\\n\",s-9-8-7-6);\r\n        }\r\n        else if (s>=36 && s<=39)\r\n        {\r\n            printf(\"%d56789\\n\",s-9-8-7-6-5);\r\n        }\r\n        \r\n        else if (s>=40 && s<=42)\r\n        {\r\n            printf(\"%d456789\\n\",s-9-8-7-6-5-4);\r\n        }\r\n        \r\n        else if (s>=43 && s<=44)\r\n        {\r\n            printf(\"%d3456789\\n\",s-9-8-7-6-5-4-3);\r\n        }\r\n        else if (s==45)\r\n        {\r\n            printf(\"%d23456789\\n\",s-9-8-7-6-5-4-3-2);\r\n        }\r\n                \r\n            \r\n    }", "lang_cluster": "C", "compilation_error": true, "code_uid": "c1b022056b1345a22511efa31cfc1aa2", "src_uid": "fe126aaa93acaca8c8559bc9e7e27b9f", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n \nint main(){\n    int x, y, z, a, b, c;\n    scanf(\"%d %d %d\\n%d %d %d\", &x, &y, &z, &a, &b, &c);\n    int temp = 0;\n    if(a <= x){\n        goto fail;\n    }\n    temp = a - x;\n    if(temp + b <= y){\n        goto fail;\n    }\n    temp = temp + b - y;\n    if(temp + c <= z {\n        goto fail;\n    })\n    printf(\"YES\");\n    return;\nfail:\n    printf(\"NO\");\n    return;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dce319d3c23238d55102a009a8820e71", "src_uid": "d54201591f7284da5e9ce18984439f4e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int x,y,z,a,b,c;\n    scanf(\"%lld %lld %lld %lld %lld %lld\",&x,&y,&z,&a,&b,&c);\n    if((a!=0&&b!=0&&c!=0)&&(x<=a)&&((y<=(a+b)))&&((z<=(a+b+c))&&(z<=(c+2)))\n    {\n        printf(\"YES\");\n    }\n    else\n        printf(\"NO\");\n\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "94e7f493a054e72ea7203f6db12a7ffa", "src_uid": "d54201591f7284da5e9ce18984439f4e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n \nint main(){\n    int x, y, z, a, b, c;\n    scanf(\"%d %d %d\\n%d %d %d\", &x, &y, &z, &a, &b, &c);\n    int temp = 0;\n    if(a <= x){\n        goto fail;\n    }\n    temp = a - x;\n    if(temp + b <= y){\n        goto fail;\n    }\n    temp = temp + b - y;\n    if(temp + c <= z) {\n        goto fail;\n    })\n    printf(\"YES\");\n    return;\nfail:\n    printf(\"NO\");\n    return;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "245af59fcd470ef5d3ffb50064e40aeb", "src_uid": "d54201591f7284da5e9ce18984439f4e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int x,y,z,a,b,c;\n    scanf(\"%d%d%d%d%d\",&x,&y,&z,&a,&b,&c);\n    if(x<=a && y<=a-x+b && z<=(a+b+c-x-y) printf(\"YES\");\n    else printf(\"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "da1e8e16e9ff195d72bd4c980d4609d8", "src_uid": "d54201591f7284da5e9ce18984439f4e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "Last login: Thu Feb  7 20:59:14 on console\n\u279c  ~ gcc xorney.c\nclang: error: no such file or directory: 'xorney.c'\nclang: error: no input files\n\u279c  ~ cd Desktop \n\u279c  Desktop cd codes \n\u279c  codes gcc xorney.c\n\u279c  codes ./a.out\n13X357-22\ninvalid%                                                                        \u279c  codes          \n  [Restored 12-Feb-2019 at 9:07:47 PM]\nLast login: Sun Feb 10 23:36:43 on ttys000\n\u279c  codes gcc Projecteuler1.c\n\u279c  codes ./a.out\n234168%                                                                         \u279c  codes gcc Projecteuler1.c\n\u279c  codes ./a.out            \n234168%                                                                         \u279c  codes gcc Projecteuler1.c\n\u279c  codes ./a.out            \n234168%                                                                         \u279c  codes gcc Projecteuler1.c\n\u279c  codes ./a.out            \n33\n\u279c  codes gcc Projecteuler1.c\n\u279c  codes ./a.out            \n33\n\u279c  codes gcc Projecteuler1.c\n\u279c  codes ./a.out            \n33\n\u279c  codes gcc Projecteuler1.c\nProjecteuler1.c:9:4: error: use of undeclared identifier 'sum1'\n                        sum1 += i;\n                        ^\nProjecteuler1.c:15:23: error: use of undeclared identifier 'sum1'\n        printf(\"%d\\n\", sum + sum1 - sum2);\n                             ^\n2 errors generated.\n\u279c  codes gcc Projecteuler1.c\n\u279c  codes ./a.out            \n33\n\u279c  codes gcc Projecteuler1.c\n\u279c  codes ./a.out            \n23\n\u279c  codes gcc Projecteuler1.c\n\u279c  codes ./a.out            \n233168\n\u279c  codes vi grapes.c\n\u279c  codes ./a.out\n233168\n\u279c  codes gcc grapes.c\ngrapes.c:2:1: warning: variable named 'main' with external linkage has undefined\n      behavior [-Wmain]\nint main{\n^\ngrapes.c:2:9: error: expected ';' after top level declarator\nint main{\n        ^\n        ;\n1 warning and 1 error generated.\n\u279c  codes vi grapes.c \n\u279c  codes gcc grapes.c\ngrapes.c:2:1: warning: variable named 'main' with external linkage has undefined\n      behavior [-Wmain]\nint main{\n^\ngrapes.c:2:9: error: expected ';' after top level declarator\nint main{\n        ^\n        ;\n1 warning and 1 error generated.\n\u279c  codes ./a.out\n233168\n\u279c  codes vi grapes.c \n\u279c  codes gcc grapes.c\n\u279c  codes ./a.out     \n1 6 2  \n4 3 3\nNO\n\u279c  codes vi grapes.c \n\u279c  codes gcc grapes.c\n\u279c  codes ./a.out     \n1 6 2\n4 3 3\nYES\n\u279c  codes ./a.out     \n5 1 1\n4 3 2\nNO\n\u279c  codes vi grapes.c \n\n#include<stdio.h>\nint main(){\n    int x, y, z, a, b, c, i, j , k;\n    scanf(\"%d%d%d%d%d%d\", &x, &y, &z, &a, &b, &c);\n    if(a + b + c >= x + y + z){\n        if(a - x < 0)\n            printf(\"NO\\n\");\n        else{\n            i = x - a;\n            if(b - i + y < 0)\n                printf(\"NO\\n\");\n            else{\n                j = i + y - b;\n                if(c - j + z < 0)\n                    printf(\"NO\\n\");\n                else\n                printf(\"YES\\n\");\n}\n}\n}\nelse\nprintf(\"NO\\n\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9fe6ceadaba00f2bb5181b8d64ec292b", "src_uid": "d54201591f7284da5e9ce18984439f4e", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\ntypedef long long int l_int;\n\nint answer(l_int bx,l_int by,l_int cx,l_int cy);\n\nint main(void){\n  struct vector{\n    l_int x;\n    l_int y;\n  }a,b,c,d;\n  int flg,j,k;\n  \n  scanf(\"%lld %lld\",&a.x,&a.y);\n  scanf(\"%lld %lld\",&b.x,&b.y);\n  scanf(\"%lld %lld\",&c.x,&c.y);\n\n  flg=0;\n  flg+=answer(b.x-a.x,b.y-a.y,c.x,c.y);\n  flg+=answer(b.x+a.y,b.y-a.x,c.x,c.y);\n  flg+=answer(b.x+a.x,b.y+a.y,c.x,c.y);\n  flg+=answer(b.x-a.y,b.y+a.x,c.x,c.y);\n\n  if(flg==0) puts(\"NO\");\n  else puts(\"YES\");\n  return 0;\n}\n\nint answer(l_int bx,l_int by,l_int cx,l_int cy){\n  l_int tmp;\n  if(cx==0 && cy==0){\n    if(bx==0 && by==0) return 1;\n    return 0;\n  }\n  if(cx==0){\n    if(bx%cy==0 && by%cy==0) return 1;\n    return 0;\n  }else if(cy==0){\n    if(bx%cx==0 && by%cx==0) return 1;\n    return 0;\n  }else{\n    tmp=cx*cx+cy*cy;\n    if((bx*cx+by*cy)%tmp==0 && (by*cx-bx*cy)%tmp==0) return 1;\n    return 0;\n  }\n  return 0;\n}\n\n\n\n\n\n  \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "db799fee43c307ff6d61af1c539fe9aa", "src_uid": "cc8a8af1ba2b19bf081e379139542883", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint answer(long long int  bx,long long int  by,long long int  cx,long long int  cy);\n\nint main(void){\n  struct vector{\n    long long int  x;\n    long long int  y;\n  }a,b,c,d;\n  int flg,j,k;\n  \n  scanf(\"%l64d %l64d\",&a.x,&a.y);\n  scanf(\"%l64d %l64d\",&b.x,&b.y);\n  scanf(\"%l64d %l64d\",&c.x,&c.y);\n\n  flg=0;\n  flg+=answer(b.x-a.x,b.y-a.y,c.x,c.y);\n  flg+=answer(b.x+a.y,b.y-a.x,c.x,c.y);\n  flg+=answer(b.x+a.x,b.y+a.y,c.x,c.y);\n  flg+=answer(b.x-a.y,b.y+a.x,c.x,c.y);\n\n  if(flg==0) puts(\"NO\");\n  else puts(\"YES\");\n  return 0;\n}\n\nint answer(long long int  bx,long long int  by,long long int  cx,long long int  cy){\n  long long int  tmp;\n  if(cx==0 && cy==0){\n    if(bx==0 && by==0) return 1;\n    return 0;\n  }\n  if(cx==0){\n    if(bx%cy==0 && by%cy==0) return 1;\n    return 0;\n  }else if(cy==0){\n    if(bx%cx==0 && by%cx==0) return 1;\n    return 0;\n  }else{\n    tmp=cx*cx+cy*cy;\n    if((bx*cx+by*cy)%tmp==0 && (by*cx-bx*cy)%tmp==0) return 1;\n    return 0;\n  }\n  return 0;\n}\n\n\n\n\n\n  \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a5bfca428567cb170470f19df01ab35b", "src_uid": "cc8a8af1ba2b19bf081e379139542883", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main(){\n\tlong long a1, a2, b1, b2, c1, c2, D, m[4], n[4];\n\tscanf(\"%d%d%d%d%d%d\", &a1, &a2, &b1, &b2, &c1, &c2);\n\tif( c1==0 && c2==0 ){\n\t\tif( (a1==b1 && a2==b2)||(a1==-b1 && a2==-b2)||(a1==b2 && a2==-b1)||(a1==-b2 && a2==b1) )\n\t\t\tprintf(\"YES\\n\");\n\t\telse \n\t\t\tprintf(\"NO\\n\");\n\t\treturn 0; \n\t}\n\tD = c1*c1+c2*c2;\n\tm[0]=(b1+a1)*c1+(b2+a2)*c2;\n\tn[0]=(b1+a1)*c2-(b2+a2)*c1;\n\tm[1]=(b1-a1)*c1+(b2-a2)*c2;\n\tn[1]=(b1-a1)*c2-(b2-a2)*c1;\n\tm[2]=(b1-a2)*c1+(b2+a1)*c2;\n\tn[2]=(b1-a2)*c2-(b2+a1)*c1;\n\tm[3]=(b1+a2)*c1+(b2-a1)*c2;\n\tn[3]=(b1+a2)*c2-(b2-a1)*c1;\n\tif( ((m[0]%D)||(n[0]%D))&&((m[1]%D)||(n[1]%D))&&((m[2]%D)||(n[2]%D))&&((m[3]%D)||(n[3]%D)) )\n\t\tprintf(\"NO\\n\");\n\telse \t\n\t\tprintf(\"YES\\n\");\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b9276dff0bb62278a093ca3516f0c54f", "src_uid": "cc8a8af1ba2b19bf081e379139542883", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint answer(int bx,int by,int cx,int cy);\n\nint main(void){\n  struct vector{\n    int x;\n    int y;\n  }a,b,c,d;\n  int flg,j,k;\n  \n  scanf(\"%d %d\",&a.x,&a.y);\n  scanf(\"%d %d\",&b.x,&b.y);\n  scanf(\"%d %d\",&c.x,&c.y);\n\n  flg=0;\n  flg+=answer(b.x-a.x,b.y-a.y,c.x,c.y);\n  flg+=answer(b.x+a.y,b.y-a.x,c.x,c.y);\n  flg+=answer(b.x+a.x,b.y+a.y,c.x,c.y);\n  flg+=answer(b.x-a.y,b.y+a.x,c.x,c.y);\n\n  if(flg==0) puts(\"NO\");\n  else puts(\"YES\");\n  return 0;\n}\n\nint answer(int bx,int by,int cx,int cy){\n  int tmp;\n  if(cx==0 && cy==0){\n    if(bx==0 && by==0) return 1;\n    return 0;\n  }\n  if(cx==0){\n    if(bx%cy==0 && by%cy==0) return 1;\n    return 0;\n  }else if(cy==0){\n    if(bx%cx==0 && by%cx==0) return 1;\n    return 0;\n  }else{\n    tmp=cx*cx+cy*cy;\n    if((bx%tmp*cx%tmp+by%tmp*cy%tmp)%tmp==0 && (by%tmp*cx%tmp-bx%tmp*cy%tmp)%tmp==0) return 1;\n    return 0;\n  }\n  return 0;\n}\n\n\n\n\n\n  \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0c27bd8d5e742b50df622053fbacbb43", "src_uid": "cc8a8af1ba2b19bf081e379139542883", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\ntypedef long long int l_int;\n\nint answer(int bx,int by,int cx,int cy);\n\nint main(void){\n  struct vector{\n    l_int x;\n    l_int y;\n  }a,b,c,d;\n  int flg,j,k;\n  \n  scanf(\"%d %d\",&a.x,&a.y);\n  scanf(\"%d %d\",&b.x,&b.y);\n  scanf(\"%d %d\",&c.x,&c.y);\n\n  flg=0;\n  flg+=answer(b.x-a.x,b.y-a.y,c.x,c.y);\n  flg+=answer(b.x+a.y,b.y-a.x,c.x,c.y);\n  flg+=answer(b.x+a.x,b.y+a.y,c.x,c.y);\n  flg+=answer(b.x-a.y,b.y+a.x,c.x,c.y);\n\n  if(flg==0) puts(\"NO\");\n  else puts(\"YES\");\n  return 0;\n}\n\nint answer(l_int bx,l_int by,l_int cx,l_int cy){\n  l_int tmp;\n  if(cx==0 && cy==0){\n    if(bx==0 && by==0) return 1;\n    return 0;\n  }\n  if(cx==0){\n    if(bx%cy==0 && by%cy==0) return 1;\n    return 0;\n  }else if(cy==0){\n    if(bx%cx==0 && by%cx==0) return 1;\n    return 0;\n  }else{\n    tmp=cx*cx+cy*cy;\n    if((bx*cx+by*cy)%tmp==0 && (by*cx-bx*cy)%tmp==0) return 1;\n    return 0;\n  }\n  return 0;\n}\n\n\n\n\n\n  \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "679064b1cf7af84416dd529ac9fa3534", "src_uid": "cc8a8af1ba2b19bf081e379139542883", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\n\nusing namespace std;\nint main()\n{\n\tlong int n,m;\n\tint a,b;\n\t\n\tcin>>n>>m>>a>>b;\n\t\n\tlong int r1,r2,c1,c2;\n\t\n\tif(n%m==0)\n\t{\n\t\tcout<<0<<endl;\n\t}\n\t\n\telse\n\t{\n\t\tr1=n%m;\n\t\tr2=m-r1;\n\t\t\n\t\tc1=r1*b;\n\t\tc2=r2*a;\n\t\t\n\t\tif(c1<c2)\n\t\tcout<<c1<<endl;\n\t\t\n\t\telse\n\t\tcout<<c2<<endl;\n\t}\n\treturn 0;\n\t\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "919041805654ab74dc2ded9dfd6523cb", "src_uid": "c05d753b35545176ad468b99ff13aa39", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <cstdio>\n\n\nint main()\n{\n    int a,b,c,d,e;\n    scanf(\"%d %d %d %d\",&a,&b,&c,&d);\n    e=a%b;\n    printf(\"%d\",e*d<(b-e)*c ? e*d : (b-e)*c);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3f4699af090c790aaaae9fe2f14d830d", "src_uid": "c05d753b35545176ad468b99ff13aa39", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#inlude<stdio.h>\nint maiN()\n{\n    int n,m,a,b;\n    while(scanf(\"%d%d%d%d\",&n,&m,&a,&b)!=EOF)\n    {\n        int k=n%m;\n        int l=m-k;\n        if(k*b>l*a)\n            printf(\"%d\",l*a);\n        else\n            printf(\"%d\",k*b);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a728da00915570666f135fd34843788a", "src_uid": "c05d753b35545176ad468b99ff13aa39", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long int\nint main()\n{\n    scanf(\"%lld\",&t);\n    for(i=0;i<t;i++)\n    {\n        scanf(\"%lld %lld %lld %lld %lld %lld\",&x,&y,&z,&a,&b,&c);\n        if(x<=y && x<=z)\n        {\n            min=x;\n        }\n        else if(y<=x && y<=z)\n        {\n            min=y;\n        }\n        else if(z<=x && z<=y)\n        {\n            min=z;\n        }\n        else if(x<=y && x>=z || x>=y && x<=z)\n        {\n            mid=x;\n        }\n        else if(y<=x && y>=z || y>=x && y<=z)\n        {\n            mid=y;\n        }\n        else if(z<=x && z>=y || z>=x && z<=y)\n        {\n            mid=z;\n        }\n        else if(z>=x && z>=y)\n        {\n            max=z;\n        }\n        else if(x>=y && x>=z)\n        {\n            max=x;\n        }\n        else if(y>=x && y>=z)\n        {\n            max=y;\n        }\n        \n        d=3*a;\n        e=(b/2)*3;\n        f=c;\n        if(d<=e && d<=f)\n        {\n            ans=x+y+z;\n        }\n        else if(e<=d && e<=f) \n        {\n            if(d<=f)\n            {\n                if((min+mid)==max)\n                {\n                    ans=(min+mid)*b;\n                }\n                else if((min+mid)>max)\n                {\n                    ans=((((min+mid+max)/2)*b)+((min+mid+max)%2)*a);\n                }\n                else if((min+mid)<max)\n                {\n                    ans=((min+mid)*b)+((max-(min+mid))*a);\n                }\n            }\n        }\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5617daab117611292d4880a69ac687b7", "src_uid": "c05d753b35545176ad468b99ff13aa39", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n    int m,n,a,b,diff,cost;\n    scanf(\"%d%d%d%d\",&n,&m,&a,&b);\n    diff=(n-m)>0:n-m:m-n;\n    printf(\"%d\",diff);\n    cost=diff*a <diff*b?diff*a :diff*b;\n    printf(\"%d\",cost);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9dce90383ccd3121b505204dc15cd292", "src_uid": "c05d753b35545176ad468b99ff13aa39", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n\n\nint main()\n{\n    int n,i,j,t;\n    char s[30][4];\n    scanf(\"%d\",&n);\n    t=n;\n    i=0;\n    for(j=0;j<4;j++)\n    {\n        s[i][j]='|';\n    }\n    for(i=1;i<22;i++)\n    {\n        for(j=0;j<4;j++)\n        {\n            s[i][j]='#';\n        }\n        if(i!=2&&i!=1)\n        {\n            s[i][2]='.';\n        }\n        i++;\n        for(j=0;j<4;j++)\n        {\n            s[i][j]='.';\n        }\n    }\n\n\n    for(i=1;i<22&&t>0;i=i+2)\n    {\n        if(i==1)\n        {\n            if(t>4)\n            {\n                t=t-4;\n                for(j=0;j<4;j++)\n                {\n                    s[i][j]='O';\n                }\n            }\n            else\n            {\n                for(j=0;j<t;j++)\n                {\n                    s[i][j]='O';\n                }1\n                t=0;\n            }\n        }\n        else\n        {\n            if(t>3)\n            {\n                t=t-3;\n                for(j=0;j<4;j++)\n                {\n                    if(j!=2)\n                    {\n                        s[i][j]='O';\n                    }\n                }\n            }\n            else\n            {\n                for(j=0;j<4&&t>0;j++)\n                {\n                    if(j!=2)\n                    {\n                        s[i][j]='O';\n                        t--;\n                    }\n                }\n            }\n        }\n    }\n\n\n    for(j=0;j<4;j++)\n    {\n        s[23][j]='|';\n    }\n    s[23][2]='.';\n\n    s[24][0]='D';\n    for(j=1;j<4;j++)\n    {\n        s[24][j]='.';\n    }\n\n    for(j=0;j<4;j++)\n    {\n        s[25][j]='|';\n    }\n\n    s[26][0]=')';\n    s[26][3]=')';\n\n    printf(\"+\");\n    for(i=1;i<25;i++)\n    {\n        printf(\"-\");\n    }\n    printf(\"+\\n\");\n\n\n    for(i=0;i<27;i++)\n    {\n        printf(\"%c\",s[i][0]);\n    }\n    printf(\"\\n\");\n    for(i=0;i<26;i++)\n    {\n        printf(\"%c\",s[i][1]);\n    }\n    printf(\"\\n\");\n    for(i=0;i<26;i++)\n    {\n        printf(\"%c\",s[i][2]);\n    }\n    printf(\"\\n\");\n    for(i=0;i<27;i++)\n    {\n        printf(\"%c\",s[i][3]);\n    }\n    printf(\"\\n\");\n    printf(\"+\");\n    for(i=1;i<25;i++)\n    {\n        printf(\"-\");\n    }\n    printf(\"+\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "783d836af6562488816d9f1bbc6a9ac4", "src_uid": "075f83248f6d4d012e0ca1547fc67993", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nvoid filltill(char a[3][12], int n){\n\tint i;\n\tfor(i=0;i<n;i++){\n\t\ta[0][i] = 'O';\n\t\ta[1][i] = 'O';\n\t\ta[2][i] = 'O';\n\t}\n}\n\nint main(){\n\tint n;\n\tchar a[3][12];\n\tint till;\n\tscanf(\"%d\",&n);\n\tint i,j;\n\tfor(i=0;i<12;i++){\n\t\tfor(j=0;j<3;j++){\n\t\t\ta[j][i] = '#';\n\t\t}\n\t}\n\tchar odd = '#';\n\tif(n == 1){\n\t\ta[0][0] = 'O';\n\t}\n\telse\n\t\tif(n==2){\n\t\t\ta[0][0] = 'O';\n\t\t\ta[1][0] = 'O';\n\t\t}\n\t\t\telse\n\t\t\t\tif(n==3){\n\t\t\t\t\ta[0][0] = 'O';\n\t\t\t\t\ta[1][0] = 'O';\n\t\t\t\t\todd = 'O';\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t\tif(n==4){\n\t\t\t\t\t\ta[0][0] = 'O';\n\t\t\t\t\t\ta[1][0] = 'O';\n\t\t\t\t\t\ta[2][0] = 'O';\n\t\t\t\t\t\todd = 'O';\n\t\t\t\t\t}else\n\t\t\t\t\t\tif(n%3 == 2){\n\t\t\t\t\t\t\ttill = (n)/3;\n\t\t\t\t\t\t\tfilltill(a,till);\n\t\t\t\t\t\t\todd = 'O';\n\t\t\t\t\t\t\ta[0][till] = 'O';\n\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse{\n\t\t\t\t\t\t\ttill = n/3 - 1;\n\t\t\t\t\t\t\tfilltill(a,till);\n\t\t\t\t\t\t\todd = 'O';\n\t\t\t\t\t\t\tif(n%3 == 0){\n\t\t\t\t\t\t\t\ta[0][till] = 'O';\n\t\t\t\t\t\t\t\ta[1][till] = 'O';\n\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\telse{\n\t\t\t\t\t\t\t\ta[0][till] = 'O';\n\t\t\t\t\t\t\t\ta[1][till] = 'O';\n\t\t\t\t\t\t\t\ta[2][till] = 'O';\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\todd = 'O';\n\t\t\t\t\t\t}\n\n\t\t\n\n\n\t\n\n\n\n\n\tprintf(\"+------------------------+\\n\");\n\tprintf(\"|\");\n\tfor(i=0;i<11;i++){\n\t\tprintf(\"%c.\", a[0][i]);\n\t}\n\tprintf(\"|D|)\\n\");\n\tprintf(\"|\");\n\tfor(i=0;i<11;i++){\n\t\tprintf(\"%c.\", a[1][i]);\n\t}\n\tprintf(\"|.|\\n\");\n\tprintf(\"|%c.......................|\\n\", odd);\n\tprintf(\"|\");\n\tfor(i=0;i<11;i++){\n\t\tprintf(\"%c.\", a[2][i]);\n\t}\n\tprintf(\"|.|)\\n\");\n\tprintf(\"+------------------------+\");\n\n/*\n\tprintf(\"|%c.%c.%c.%c.%c.%c.%c.%c.%c.%c.%c.|D|\\n\", );\n\tprintf(\"|%c.%c.%c.%c.%c.%c.%c.%c.%c.%c.%c.|.|\\n\", );\n\tprintf(\"|%c.......................|\\n\", &odd);\n\tprintf(\"|%c.%c.%c.%c.%c.%c.%c.%c.%c.%c.%c.|.|\\n\", );\n\tprintf(\"+------------------------+\\n\"); */\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "0e1ed8325acdbcbd184d42bb85163ca0", "src_uid": "075f83248f6d4d012e0ca1547fc67993", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int k,s1,s2,s3,i;\n    scanf(\"%d\",&k);\n   printf(\"+------------------------+\\n\");\n   if(k!=0){\n    s1=(k-1)/3;\n    if((k-1)%3>0)\n     s1++;\n    printf(\"|\");\n    for(i=0;i<11;i++){\n        if(s1>0){if(i==0)\n    printf(\"%c\",'O');\n    else\n    printf(\".%c\",'O');\n    }\n    else{\n        if(i==0)\n    printf(\"%c\",'#');\n    else\n    printf(\".%c\",'#');\n    }\n    s1--;\n    }\n    printf(\".|D|)\\n\");\n    s2=(k-1)/3;\n\n    if((k-1)%3>1)\n    s2++;\n    printf(\"|\");\n    for(i=0;i<11;i++){\n        if(s2>0){\n            if(i==0)\n    printf(\"%c\",'O');\n    else\n    printf(\".%c\",'O');\n        }\n    else{\n       if(i==0)\n    printf(\"%c\",'#');\n    else\n    printf(\".%c\",'#');\n    }\n    s2--;\n\n    }\n    printf(\".|.|\\n\");\n    if(k>3)\n    printf(\"|O.......................|\\n\");\n    else\n    printf(\"|#.......................|\\n\");\n     s3=(k-1)/3;\n    if((k-1)%3>2)\n    s3++;\n    printf(\"|\");\n    for(i=0;i<11;i++){\n        if(s3>0){\n         if(i==0)\n    printf(\"%c\",'O');\n    else\n    printf(\".%c\",'O');\n        }\n    else{\n        if(i==0)\n        printf(\"%c\",'#');\n        else\n    printf(\".%c\",'#');\n    }\n    s3--;\n    }\n   printf(\".|.|)\\n\");\n   }\n   else\n   {\n      printf(\"|#.#.#.#.#.#.#.#.#.#.#.|D|)\\n\");\nprintf(\"|#.#.#.#.#.#.#.#.#.#.#.|.|\\n\");\nprintf(\"|#.......................|\\n\");\nprintf(\"|#.#.#.#.#.#.#.#.#.#.#.|.|)\\n\");\n\n\n   }\n    printf(\"+------------------------+\\n\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "613b11db5ba772617f3188a70cb52776", "src_uid": "075f83248f6d4d012e0ca1547fc67993", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main(){\n    char bus[6][26];\n    int i,j,k,count;\n    scanf(\"%d\",&count);\n    for(i=0;i<6;i++){\n        for(j=0;j<26;j++)\n            bus[i][j]='-';\n    }\n    for(i=1;i<5;i++){\n        for(j=2;j<23;j=j+2)\n            bus[i][j]='.';\n    }\n    bus[0][0]='+', bus[0][25]='+',bus[1][24]='D',bus[1][23]='|',bus[2][23]='|',bus[4][23]='|';\n    bus[5][0]='+', bus[5][25]='+',bus[2][24]='.',bus[3][24]='.',bus[2][24]='.',bus[4][24]='.';\n    for(i=1;i<5;i++){\n        for(j=0;j<1;j++)\n            bus[i][j]='|';\n    }\n    for(i=1;i<5;i++){\n        for(j=25;j<26;j++)\n            bus[i][j]='|';\n    }\n    for(i=1;i<5;i++){\n        for(j=1;j<23;j=j+2)\n            bus[i][j]='#';\n    }\n    for(i=3;i<4;i++){\n        for(j=1;j<25;j=j+2)\n            bus[i][j]='.';\n    }\n    bus[3][1]='#';\n\n    for(k=1;k<22;k=k+2){\n        j=k;\n        for(i=1;i<=4;i++){\n            if(bus[i][j]=='#'){\n                bus[i][j]= 'O';\n                count--;\n            }\n            if(count==0)\n                break;\n        }\n        if(count==0)\n            break;\n    }\n    for(i=0;i<6;i++){\n        for(j=0;j<26;j++)\n            //bus[i][j]='-';\n            printf(\"%c\",bus[i][j]);\n        if(i==1 || i==4)\n            printf(\"%c\",')');\n        printf(\"\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "03d9417cad52eb09ac776ed06f817a04", "src_uid": "075f83248f6d4d012e0ca1547fc67993", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nchar ch[4][15][10];\nint main(){\n\n\n\nint num,i,j,add,flag;\n\n\nscanf(\"%d\",&num);\n\nfor(i=0;i<4;i++){\nstrcpy(ch[i][0],\"|\");\n\n}\n\nfor(i=0;i<4;i++){\nfor(j=1;j<=11;j++){\n\nstrcpy(ch[i][j],\"#.\");\n}\n}\n\n\nstrcpy(ch[3][12],\"|D|)\");\n\nstrcpy(ch[2][12],\"|.|\");\nstrcpy(ch[1][12],\"..|\");\nstrcpy(ch[0][12],\"|.|)\");\nfor(i=2;i<=11;i++){\n\n    strcpy(ch[1][i],\"..\");\n}\nadd=0;\nflag=0;\nfor(i=1;i<=11;i++){\n    for(j=3;j>=0;j--){\n            if(i>1&&j==1){\n\n                j=0;\n            }\n\n        strcpy(ch[j][i],\"O.\");\n        add++;\n        if(add==num){\n\n            flag=1;\n            break;\n        }\n\n    }\n    if(flag){\n\n        break;\n    }\n    }\nprintf(\"+------------------------+\\n\");\nfor(i=3;i>=0;i--){\n\n    for(j=0;j<13;j++){\n\n\n        printf(\"%s\",ch[i][j]);\n    }\n    printf(\"\\n\");\n}\nprintf(\"+------------------------+\");\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7eb29101b33757022fbdf3f58c21c4e8", "src_uid": "075f83248f6d4d012e0ca1547fc67993", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\t__int64 n,i,count=0;\n\tscanf(\"%I64d\",&n);\n\tfor(i=1;i<=(n/4);i++)\n\t{\n\t\tif(i!=(n-2*i)/2)\n\t\t\tcount+=1;\n\t\telse\n\t\t\tcount=count;\n\t}\n\tprintf(\"%I64d\",count);\n\treturn 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "cbd06c1d9c594a10a81c1a851bdbef4e", "src_uid": "32b59d23f71800bc29da74a3fe2e2b37", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tif(n%4==0)\n\t{\n\t\tprintf(\"%d\\n\",(n-4)/4);\n\t}\n\telse if(n%2==0)\n\t{\n\t\tprintf(\"%d\\n\",(n-2)/4);\n\t}\n\telse\n\t{\n\t\tprintf(\"0\\n\");\n\treturn 0;\n}\n\t\t\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "eb1d3feb75b096b99eb9e57851c49c4b", "src_uid": "32b59d23f71800bc29da74a3fe2e2b37", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#iclude<stdio.h>\nmain()\n{\n    int n,i;\n    scanf(\"%d\",&n);\n    if(n%2==0)\n    {\n        m=n/2;\n        if(m%2==0)\n        {\n            i=(m/2)-1;\n        }\n        else\n        {\n            i=(m-1)/2;\n        }\n    }\n    else\n    {\n        i=0;\n    }   \n    printf(\"%d\",i);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "afda737e0fdaef1b5c7c4cbeebd26092", "src_uid": "32b59d23f71800bc29da74a3fe2e2b37", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "\n#include<bits/stdc++.h>\nint main()\n{\n    int n,m;\n    scanf(\"%d\",&n);\n    if(n%4==0)\n        {\n        m=-1;\n        }\n    else\n        m=0;\n    if(n%2)\n    {\n        printf(\"0\\n\");\n        return 0;\n    }\n    else{\n        m+=n/4;\n    }\n    printf(\"%d\\n\",m);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "389c8615252464011a89afc564fdd2c2", "src_uid": "32b59d23f71800bc29da74a3fe2e2b37", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <iostream>\n\nusing namespace std;\nint main()\n{\n    int long long  n;\n    int long long aux;\n    \n\n    cin>> n;\n    if(n%2==1)\n        printf(\"0\\n\");\n\n    cout<<(n/2-1)/2<<endl;\n\n\n    return 0;\n\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ea6ef305e1ee68492fe5a9000d6668ec", "src_uid": "32b59d23f71800bc29da74a3fe2e2b37", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlongint X, Y, d, digit, b;\nint n, i;\nint main() {\n\tscanf(\"%d %d\", &n, &b);\n\td = 1;\n\tfor(i=1; i<n; i++) d *= b;\n\tfor(i=0; i<n; i++) {\n\t\tscanf(\"%d\", &digit);\n\t\tX += digit*d;\n\t\td /= b;\n\t}\n\t\n\tscanf(\"%d %d\", &n, &b);\n\td = 1;\n\tfor(i=1; i<n; i++) d *= b;\n\tfor(i=0; i<n; i++) {\n\t\tscanf(\"%d\", &digit);\n\t\tY += digit*d;\n\t\td /= b;\n\t}\n\tif(X<Y) \n\t\tprintf(\"<\");\n\telse if (X>Y) \n\t\tprintf(\">\");\n\telse \n\t\tprintf(\"=\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5ba84ce8a8c242de18b85bc662281d06", "src_uid": "d6ab5f75a7bee28f0af2bf168a0b2e67", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n  int n,bx,i,j;\n  scanf(\"%d %d\",&n,&bx);\n  int x[n];\n  for(int i=0;i<n;i++)\n  {\n    scanf(\"%d\",&x[i]);\n  }\n\n  int s,s1=0;\n  for( i=n-1,j=0;i>=0,j<=n-1;i--,j++)\n  {\n    s=pow(bx,j);\n    s1=s1+s*x[i];\n\n  }\n\n\n  int m,by;\n  scanf(\"%d %d\",&m,&by);\n  int y[m];\n  for(int i=0;i<m;i++)\n  {\n    scanf(\"%d\",&y[i]);\n  }\n  \n  int sy,s2=0;\n  for(i=m-1,j=0;i>=0,j<=m-1;i--,j++)\n  {\n    sy=pow(by,j);\n    s2=s2+sy*y[i];\n  }\n\n  if(s1>s2)\n  {\n    printf(\">\\n\");\n  }\n  else if(s1<s2)\n  {\n    printf(\"<\\n\");\n  }\n  else if(s1==s2)\n  {\n    printf(\"=\\n\");\n  }\n\n}\n\n#include<stdio.h>\n#include<math.h>\nint main()\n{\n  int n,bx,i,j;\n  scanf(\"%d %d\",&n,&bx);\n  int x[n];\n  for(int i=0;i<n;i++)\n  {\n    scanf(\"%d\",&x[i]);\n  }\n\n  int s,s1=0;\n  for( i=n-1,j=0;i>=0,j<=n-1;i--,j++)\n  {\n    s=pow(bx,j);\n    s1=s1+s*x[i];\n\n  }\n\n\n  int m,by;\n  scanf(\"%d %d\",&m,&by);\n  int y[m];\n  for(int i=0;i<m;i++)\n  {\n    scanf(\"%d\",&y[i]);\n  }\n  \n  int sy,s2=0;\n  for(i=m-1,j=0;i>=0,j<=m-1;i--,j++)\n  {\n    sy=pow(by,j);\n    s2=s2+sy*y[i];\n  }\n\n  if(s1>s2)\n  {\n    printf(\">\\n\");\n  }\n  else if(s1<s2)\n  {\n    printf(\"<\\n\");\n  }\n  else if(s1==s2)\n  {\n    printf(\"=\\n\");\n  }\n\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c85dd9248a0947aeda324590b5ed3dd7", "src_uid": "d6ab5f75a7bee28f0af2bf168a0b2e67", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main(){\n\t\n\t\n\tscanf(\"%d%d\",&nd1,&bas1)\n\tfor (i = 0; i< nd1; i++){\n\t\tscanf(\"%d\", num1[i]);\n\t\tres1 = res1 + num1[i]*(pow(bas1,nd1-1-i);\n\t\t}\n\tscanf(\"%d%d\",&nd2,&bas2);\n\tfor (i = 0; i<nd2; i++){\n\t\tsacnf(\"%d\",&num2[i]);\n\t\tres2 = res2 + num2[i]*(pow(bas2,nd2-1-i);\n\t\t}\n\tif(res1<res2){\n\t\tprintf(\"<\")\n\t\t}\n\tif(res1>res2){\n\t\tprintf(\">\")\n\t\t}\n\telse{\n\t\tprintf(\"=\")\n\t\t}\t\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "32092269e31602b727b2e09c78a47ed8", "src_uid": "d6ab5f75a7bee28f0af2bf168a0b2e67", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdlib.h>\n#include <stdio.h>\n\nusing namespace std;\n\nlong long power(int a, int b);\n\nint main(void)\n{\n    int *xx, *yy;\n    int n, m, bx, by, i;\n    long long x, y;\n    x = y = 0;\n    scanf(\"%d %d\", &n, &bx);\n    xx = (int *)malloc(n*sizeof(int));\n    for (i = n-1; i>-1; i--) scanf(\"%d\", &xx[i]);\n    scanf(\"%d %d\", &m, &by);\n    for (i = 0; i<n; i++) x += xx[i]*power(bx, i);\n    yy = (int *)malloc(m*sizeof(int));\n    for (i = m-1; i>-1; i--) scanf(\"%d\", &yy[i]);\n    for (i = 0; i<m; i++) y += yy[i]*power(by, i);\n    if (x<y) {printf(\"<\"); return 0;}\n    if (x>y) {printf(\">\"); return 0;}\n    if (x==y) {printf(\"=\"); return 0;}\n}\n\nlong long power(int a, int b)\n{\n    int i;\n    long long p;\n    for (p = 1, i = 1; i<=b; i++)\n        p *= a;\n    return p;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d9cbc3b9cf0833e24feb7b44acf12d98", "src_uid": "d6ab5f75a7bee28f0af2bf168a0b2e67", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\ndouble input()\n{\n    double input()\ndouble n,x,y;\ndouble sum=0;\nscanf(\"%lf %lf\",&n,&x);\nwhile(n--)\n{\n    scanf(\"%lf\",&y);\n    sum=sum*x+y;\n}\nreturn sum;\n}\nint main(){\n    double a,b;\n    a=input();\n    b=input();\n    if(a>b)\n        puts(\">\");\n    else if(a==b)\n        puts(\"=\");\n    else puts(\"<\";)\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2261216b074be52360d8d9e73ce6baec", "src_uid": "d6ab5f75a7bee28f0af2bf168a0b2e67", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n\tint i,j,temp;\n\tint s[4];\n\tfor (int i = 0; i < 4; ++i)\n\t{\n\t\tscanf(\"%d\",&s[i]);\n\t}\n\tfor (int i = 0; i < 3; ++i)\n\t{\n\t\tfor (int j = 0; j < 3-i; ++j)\n\t\t{\n\t\t\tif (s[j]>s[j+1])\n\t\t\t{\n\t\t\t\ttemp=s[j];\n\t\t\t\ts[j]=s[j+1];\n\t\t\t\ts[j+1]=temp;\n\t\t\t}\n\t\t}\n\t}\n\tif (s[1]+s[2]==s[0]+s[3])\n\t{\n\t\tprint(\"yes\");\n\t}\n\telse\n\t\tprintf(\"no\");\n\treturn 0;\n\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c2f5396bab9a3d7e986798b0b4e78161", "src_uid": "5a623c49cf7effacfb58bc82f8eaff37", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n   int a[5],s[50],i,j,k=1;\n   for(i=1;i<=4;i++)\n   {\n       scanf(\"%d\",&a[i]);\n   }\n   for(i=1;i<=4;i++)\n   {for(j=i+1;j<=4;j++)\n      {s[k]=a[i]+a[j];\n         k++;\n      }\n   }\n\n   for(i=1;i<=4;i++)\n   {for(j=i+1;j<=4;j++)\n      s[i]=a[i]+a[j];\n   }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a095f485fb77cc6d414ccaaadce99b91", "src_uid": "5a623c49cf7effacfb58bc82f8eaff37", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nint a,b,c,d,n;\nprintf(\"enter the no of bags\");\nscanf(\"%d\",&n);\nprintf(\"enter the candies no\");\nscanf(\"%d%d%d%d\",&a,&b,&c,&d);\nif(a+b==c+d)&&(a+c==b+d)&&(a+d==b+c)&&(a+b+c==d)&&(a+b+d==c)&&(b+c+d==a)&&(c+d+a==b)\n{\nprintf(\"YES\");\n}\nelse\n{\nprintf(\"NO\");\n}\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "721dc73e2af0b045ca483a4584b395e9", "src_uid": "5a623c49cf7effacfb58bc82f8eaff37", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <std.io>\n \nint main(){\n    int a[4];\n    for(int i=0;i<4;i++)\n    scanf(\"%d\",&a[i]);\n    \n    for(int i=0;i<4;i++)\n{\n    for(int j=i;j<4;j++)\n    {\n        if(a[i]>a[j]){\n        int t=a[i];\n        a[i]=a[j];\n        a[j]=t;\n        }\n    }\n}\n \nint s1=a[0]+a[3];\nint s2=a[1]+a[2];\nif(s1==s2)\nprintf(\"YES\");\nelse\nprintf(\"NO\");\n    \n    return 0;\n    \n    \n    \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d8897c88f5126341a4e21b8a85f1eb41", "src_uid": "5a623c49cf7effacfb58bc82f8eaff37", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nvoid func(int tot);\n\nint main(void){\n    int i, tot = 0;\n    int arr[4];\n    for(i=0;i<4;i++){\n        scanf(\" %d\",arr+i);\n    }\n    \n    for(i=0;i<4;i++)\n      tot+= arr[i];\n    \n    func(tot);\n    \n    \n    return 0;\n}\n\nvoid func(int tot){\n    int i,k,sum;\n    \n    for(i=0;i<4;i++){\n        if(arr[i] == 2*tot){\n          printf(\"YES\")\n          return;\n        }\n    }\n    \n    for(i=0;i<4;i++){\n        sum = 0\n        for(k=i+1;k<4;k++){\n          sum = arr[i]+arr[k]\n        if(sum == 2*tot){\n          printf(\"YES\")\n          return;\n        }\n        }\n    }\n    \n    printf(\"NO\")\n    \n    \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "771a693c038df63bdafa51418b911438", "src_uid": "5a623c49cf7effacfb58bc82f8eaff37", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint i,a=5,b=5,c=5,d;\nchar A,B,C,Z,X;\n\nint main(){\n\n\tfor(i =0 ; i<3 ; i++){\n\tscanf(\" %c %c %c\",&A,&Z,&B);\n\n\tif(A == 'A' && B == 'C'){\tif(Z == '>'){ a++; c--; }\telse { a--; c++; }   }\n\tif(A == 'B' && B == 'C'){\tif(Z == '>'){ b++; c--; }\telse { b--; c++; }   }\n\tif(A == 'A' && B == 'B'){\tif(Z == '>'){ a++; b--; }\telse { a--; b++; }   }\n\tif(A == 'C' && B == 'A'){\tif(Z == '<'){ a++; c--; }\telse { a--; c++; }   }\n\tif(A == 'C' && B == 'B'){\tif(Z == '<'){ b++; c--; }\telse { b--; c++; }   }\n\tif(A == 'B' && B == 'A'){\tif(Z == '<'){ a++; b--; }\telse { a--; b++; }   }\n\n\t}\n\n\n\tif(a>b && a>c && b>c)\n\t\tprintf(\"CBA\");\n\telse if(c>b && c>a && b>a)\n\t\tprintf(\"ABC\");\n\telse if(b>a && b>c && a>c)\n\t\tprintf(\"CAB\");\n\telse if(a>b && a>c && c>b)\n\t\tprintf(\"BCA\");\n\telse if(b>c && b>a && c>a)\n\t\t\tprintf(\"ACB\");\n\telse if(c>a && c>b && a>b)\n\t\t\tprintf(\"BAC\");\n\telse\n\t\tprintf(\"Impossible\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2d6deac4507648c9ea1468de4b8c2193", "src_uid": "97fd9123d0fb511da165b900afbde5dc", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n \nint main()\n{\n    int a=0,b=0,c=0;\n    char a1,b1,c1;\n    for(int i=0;i<3;i++)\n    {\n \n        scanf(\" %c%c%c\",&a1,&b1,&c1);\n       // printf(\"%c %c %c\\n\",a1,b1,c1);\n        if(a1=='A' && c1=='B')\n        {\n            if (b1 =='>')\n            {\n                b++;\n            }\n            else\n                a++;\n        }\n        if(a1=='B' && c1=='A')\n        {\n            if (b1 =='>')\n            {\n                a++;\n            }\n            else\n                b++;\n        }\n \n        if(a1=='C' && c1=='A')\n        {\n            if (b1 =='>')\n            {\n                a++;\n            }\n            else\n                c++;\n        }\n        if(a1=='A' && c1=='C')\n        {\n            if (b1 =='>')\n            {\n                c++;\n            }\n            else\n                a++;\n        }\n        if(a1=='B' && c1=='C')\n        {\n            if (b1 =='>')\n            {\n                c++;\n            }\n            else\n                b++;\n        }\n         if(a1=='C' && c1=='B')\n        {\n            if (b1 =='>')\n            {\n                b++;\n            }\n            else\n                c++;\n        }\n     //  printf(\"%d %d %d\\n\",a,b,c);\n    }\n  //  printf(\"%d %d %d\\n\",a,b,c);\n    if (a==b && b==c)\n        printf(\"Impossible\");\n   else  if (a>=c && a>=b && b>=c)\n        printf(\"ABC\");\n    else if (a>=c && a>=b && c>=b)\n        printf(\"ACB\");\n    else if (c>=a && c>=b && a>=b)\n        printf(\"CAB\");\n    else if (c>=a && c>=b && b>=a)\n        printf(\"CBA\");\n    else if (b>=a && b>=c && c>=a)\n        printf(\"BCA\");\n    else if (b>=a && b>=c && a>=c)\n        printf(\"BAC\");\n \n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4fc3959f40f8c917a18ae38a35a05c5b", "src_uid": "97fd9123d0fb511da165b900afbde5dc", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define loop(i,n) for(i=0;i<n;i++)//={'C','B','A'}\n//using namespace std;\nint main(){ char x[3],y[3],z[3],c,r[3];\n\n\nscanf(\"%s\",x);\nscanf(\"%s\",y);\nscanf(\"%s\",z);\n\n\n\n\nif(x[1]=='>'){c=x[0];x[0]=x[2];x[2]=c;x[1]='<';}\nif(y[1]=='>'){c=y[0];y[0]=y[2];y[2]=c;y[1]='<';}\nif(z[1]=='>'){c=z[0];z[0]=z[2];z[2]=c;z[1]='<';}\nif((int)(x[2]+y[2]+z[2])==198)return printf(\"Impossible\"),0;\n          if(x[2]==z[2]||x[2]==y[2])r[2]=x[2];\n     else if(y[2]==z[2]||y[2]==x[2])r[2]=y[2];\n     else if(z[2]==x[2]||z[2]==y[2])r[2]=z[2];\n  \n  \n  \n        if(x[0]==z[0]){r[0]=x[0];r[1]=y[0];}\n   else if(x[0]==y[0]){r[0]=x[0];r[1]=z[0];}\n   \n   \n   else if(z[0]==x[0]){r[0]=z[0];r[1]=y[0];}\n   else if(z[0]==y[0]){r[0]=z[0];r[1]=x[0];}\n   \n   \n   else if(y[0]==z[0]){r[0]=y[0];r[1]=x[0];}\n   else if(y[0]==x[0]){r[0]=y[0];r[1]=z[0];}\nint i;\n   loop(i,3) printf(\"%c\",r[i]);\n   return 0;}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6dfa7853a37a68904719b416ecb2dfa0", "src_uid": "97fd9123d0fb511da165b900afbde5dc", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint comp[3];\nint main()\n{\n    char m[3];\n    \n    for(int i=0;i<3;i++){\n        scanf(\"%s\", m);\n        if(m[1]=='>')\n            comp[m[0]-'A']++;\n        else comp[m[2]-'A']++;\n    }\n    \n      int n=0;\n      \n    if((comp[0]==0 && comp[1]==1 && comp[2]==2) || (comp[0]==0 && comp[1]==2 && comp[2]==1) || (comp[0]==1 && comp[1]==0 && comp[2]==2) ||(comp[0]==1 && comp[1]==2 && comp[2]==0) || (comp[0]==2 && comp[1]==0 && comp[2]==1) || (comp[0]==2 && comp[1]==1 && comp[2]==0)){\n    while(n!=3){\n        for(int j=0;j<3;j++){\n            for(int i=0;i<3;i++) if(comp[i]==j) {printf(\"%c\", (char) 65+i ); n++; break;};\n        }\n      \n        \n    }} else printf(\"Impossible\");\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f6136bd4b48bb9c5f3d9edeb90caa2c2", "src_uid": "97fd9123d0fb511da165b900afbde5dc", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    char arr[3][3];\n    int i=0,j;\n    for(i=0;i<3;i++)\n    {\n        scanf(\"%c%c%c\",&arr[i][0],&arr[i][1],&arr[i][2]);\n        getchar();\n    }\n    char arr2[3]={'A','B','C'};\n    char arr3[3]={'0','0','0'};\n    for(j=0;j<3;j++)\n    {\n        char check=arr2[j];\n        int counter=0;\n        for(i=0;i<3;i++)\n        {\n            if(arr[i][0]==check)\n            {\n                if(arr[i][1]=='>')\n                    counter++;\n                else\n                    counter--;\n            }\n            if(arr[i][2]==check)\n            {\n                if(arr[i][1]=='>')\n                    counter--;\n                else\n                    counter++;\n            }\n        }\n        if(counter==2)\n        {\n            if(arr3[0]=='0')\n                arr3[0]=arr2[j];\n            else\n            {\n                arr3[0]='1';\n                break;\n            }\n\n        }\n        else if(counter==0)\n        {\n            if(arr3[1]=='0')\n                arr3[1]=arr2[j];\n            else\n            {\n                arr3[1]='1';\n                break;\n            }\n        }\n        else if(counter==-2)\n        {\n            if(arr3[2]=='0')\n                arr3[2]=arr2[j];\n            else\n            {\n                arr3[2]='1';\n                break;\n            }\n        }\n    }\n    if(arr3[0]=='1'||arr3[1]=='1'||arr3[2]=='1')\n        printf(\"Impossible.\");\n    else\n    {\n        for(i=2;i>=0;i--)\n        {\n            printf(\"%c\",arr3[i]);\n        }\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "02ce1b5cfdb527420de4df2745738d85", "src_uid": "97fd9123d0fb511da165b900afbde5dc", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n\tint n,k;\n\tchar s[105];\n\tint target,grass;\n\tscanf(\"%d%d\",&n,&k);\n\tint flag=0;X\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tscanf(\"%c\",&s[i]);\n\t\tif(s[i]=='T') target=i;\n\t\tif(s[i]=='G') grass=i;\n\t}\n\tif(grass<target)\n\t{\n\t\tint j=grass;\n\t\twhile(s[j]!='#'&&j<target)\n\t\t{\n\t\t\tj+=k;\n\t\t\tif(s[j]=='T') flag=1;\n\t\t}\n\t}\n\tif(grass>target)\n\t{\n\t\tint j=grass;\n\t\twhile(s[j]!='#'&&j<target)\n\t\t{\n\t\t\tj-=k;\n\t\t\tif(s[j]=='T') flag=1;\n\t\t}\n\t}\n\tif(flag==1) printf(\"YES\\n\");\n\telse printf(\"NO\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5d3e80c3538597d24702e1bbbca1f045", "src_uid": "189a9b5ce669bdb04b9d371d74a5dd41", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nmain()\n{\n\tint n,k,l,i,m,j;\n\tscanf(\"%d%d\",&n,&m);\n\tchar s[n+1];\n\tscanf(\"%s\",s);\n\tl=strlen(s);\n\tfor(i=0;i<l;i++)\n\t{\n\t\tif(s[i]=='G')\n\t\tk=i;\n\t\tif(s[i]=='T')\n\t\tj=i;\n\t}\n\tif((k-j)<0)\n\t{\n\t\ti=k;\n\t\twhile(i<=j)\n\t\t{\n\t\t\tif(s[i]=='#')\n\t\t\t{\n\t\t\tprintf(\"NO\");\n\t\t\tbreak;\n\t\t    }\n\t\t\tif(i==j)\n\t\t\t{\n\t\t\t\tprintf(\"YES\");\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\ti=i+m;\n\t\t}\n\t\tif(i>j)\n\t\tprintf(\"NO\");\n\t\t\n\t}\n\tif((k-j)>0)", "lang_cluster": "C", "compilation_error": true, "code_uid": "9972c0ca7ed9fabf31b2930f51062682", "src_uid": "189a9b5ce669bdb04b9d371d74a5dd41", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nmain{\n\tint n,k,g,t;\n\tscanf(\"%d %d\",&n,&k);\n\tint i; \n\tchar arr[n];\n\t\n\tscanf(\"\\n\");\n\tfor(i=0;i<n;i++)\n\t{\n\t\t\n\t\tscanf(\"%c\",&arr[i]);\n\t\tif(arr[i]=='G') g=i;\n\t\t\n\t\tif(arr[i]=='T') t=i;\n\t\t\n\t}if(g<t){\n\t\t\tfor(i=g; i<=t; i=i+k)\n    \t{\n\t\tif(arr[i]=='#')\n\t\t{printf(\"NO\"); return 0;\n\t\t    \n\t\t}\n     \t}\n\tif(i==t+k)\n\tprintf(\"\tYES\");\n\telse printf(\"NO\");\n\t}\n\t\n\telse \n\t\n\t{\n\t\tfor(i=t;i<=g;i=i+k)\n\t\t{\n\t\t\t\tif(arr[i]=='#') \n\t\t\t\t{printf(\"NO\"); \n\t\t\t\treturn 0;}\n\t\t}\n\t\t\n\t\n\tif(i==g+k) \n\tprintf(\"YES\");\n\telse printf(\"NO\");\n\t}\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f9b5c8af059164d93ec1386c8591f292", "src_uid": "189a9b5ce669bdb04b9d371d74a5dd41", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,k;\n    int pos1,pos2,temp;\n    char s[110];\n    scanf(\"%d%d\",&n,&k);\n    scanf(\"%s\",s);\n    for(int i=0;i<n;i++)\n    {\n        if(s[i]=='G')\n        {\n            pos1=i;\n        }\n        if(s[i]=='T')\n        {\n            pos2=i;\n        }\n    }\n    if(pos1>pos2)\n    {\n        temp=pos1;\n        pos1=pos2;\n        pos2=temp;\n    }\n    #printf(\"%d!%d\\n\",pos1,pos2);\n    while(pos1+k<100)\n    {\n        if(pos1+k==pos2)\n        {\n            printf(\"YES\\n\");\n            return 0;\n        }\n        if(s[pos1+k]=='#')\n        {\n            printf(\"NO\\n\");\n            return 0;\n        }\n        pos1=pos1+k;\n    }\n    printf(\"NO\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "abf11e8cac45d00e73011988a889629d", "src_uid": "189a9b5ce669bdb04b9d371d74a5dd41", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <cstdio>\n\nchar a[101];\n\nint main() {\n\n\tunsigned char n, k;\n\tscanf(\"%hhu %hhu\\n\", &n, &k);\n\tscanf(\"%s\", a);\n\n\tunsigned char i;\n\tfor (i = 0; i < n; i++) {\n\t\tif (a[i] == 'T' || a[i] == 'G')\n\t\t\tbreak;\n\t}\n\n\tfor (i += k; i < n; i += k) {\n\t\tswitch (a[i]) {\n\t\tcase '#':\n\t\t\tprintf(\"NO\");\n\t\t\treturn 0;\n\t\t\tbreak;\n\t\tcase 'G':\n\t\tcase 'T':\n\t\t\tprintf(\"YES\");\n\t\t\treturn 0;\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tprintf(\"NO\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1aebb1881d1e3dfe5678be1a942537a8", "src_uid": "189a9b5ce669bdb04b9d371d74a5dd41", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\nint main(){\n    long long a;\n    int i,j,n=0;\n    int c=0\n    printf(\"enter a number 1<a<10^18\");\n    scanf(\"%I64d\",a);\n    for(i=1;i<=a;i++){\n        for(j=2;j<=10;j++)\n            if(i%j!=0)\n                n++;\n        if(n==9){\n            c++;\n            n=0;\n        }\n    }\n    printf(\"%d\",c);\n    getch();\n    return 0;\n        \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "20936875aa93882c280d59a74aa7ac41", "src_uid": "e392be5411ffccc1df50e65ec1f5c589", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nmain(void){\n    long long a,i,c=0;\n    scanf(\"%I64d\",&a);\n    c=[n/3]+[n/2]+[n/5]+[n/7]-[n/10]-[n/14]-[n/6]-[n/35]-[n/21]-[n/15]+[n/105]+[n/30]+[n/42]+[n/70]-[n/210]\n    printf(\"%I64d\",c);  \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3063ffd71e7436e8cee850e73dbd3311", "src_uid": "e392be5411ffccc1df50e65ec1f5c589", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "\n#include<stdio.h>\n int main(){\n long long inp; \nint counter = 0;\n scanf(\"%I64d\",&inp); \nfor(int i = 1;i<= inp;i++)\n if(i % 2520! = 0 ){ counter = counter + 1; }\n} printf(\"%d\",counter); \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e1fe04e038f3129a68f8c4e72036eb32", "src_uid": "e392be5411ffccc1df50e65ec1f5c589", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain(void){\n    long long a,i,c=0;\n    scanf(\"%I64d\",&a);\n    c=[n/3]+[n/5]+[n/7]-[n/35]-[n/21]-[n/15]+[n/105]\n    printf(\"%I64d\",c);  \n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "221781b3fa7b8058cca5590247489a0c", "src_uid": "e392be5411ffccc1df50e65ec1f5c589", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n    long long int n;\n    scanf(\"%I64d\", &n);\n\n    eqn = n / 2 + n / 3 + n / 5 + n / 7 - (n / (2 * 3) + n / (2 * 5) + n / (2 * 7)\n          + n / (3 * 5) + n / (3 * 7) + n / (5 * 7)) + n / (2 * 3 * 5) + n / (2 * 3 * 7)\n          + n / (2 * 5 * 7) + n / (3 * 5 * 7) - n / (2 * 3 * 5 * 7);\n\n    /* n(A U B U C U D) = p(A) + p(B) + p(C) + p(D) - P(AnB) - p(AnC) - p(AnD) - p(BnC) - p(BnD) - p(CnD)\n       + p(AnBnC) + p(AnBnD) + p(AnCnD) + p(BnCnD) - p(AnBnCnD) */\n\n    printf(\"%I64d\", n - eqn);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ddfaf1d2cf5dbea54fd7f77ad3201b2d", "src_uid": "e392be5411ffccc1df50e65ec1f5c589", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint egcd(int a, int b, int &x, int &y) { \n    if (a == 0) { \n        x = 0;\n        y = 1;\n        return b; \n    } \n  \n    int x1, y1;\n    int gcd = egcd(b % a, a, x1, y1); \n  \n    x = y1 - (b / a) * x1; \n    y = x1; \n  \n    return gcd; \n} \n\nint main() {\n    int a, b, c, g, x, y;\n    \n    cin >> a >> b >> c;\n    \n    g = egcd(a, b, x, y);\n    \n    if (y < x) {\n        swap(x, y);\n        swap(a, b);\n    }\n    \n    if (c % g) {\n        cout << \"No\";\n        return 0;\n    }\n    \n    a /= g;\n    b /= g;\n    c /= g;\n    \n    if (c * y - (-c * x + b - 1) / b * a < 0)\n        cout << \"No\";\n    else\n        cout << \"Yes\";\n     \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7c7382c7c23f50f5e834a351e7842a14", "src_uid": "e66ecb0021a34042885442b336f3d911", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"633/a\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/633/a\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/633/a\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t\t<Add option=\"-fexceptions\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.cpp\" />\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b568097def48f68979a541f57ae8493d", "src_uid": "e66ecb0021a34042885442b336f3d911", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<iostream>\nusing namespace std;\nint main ()\n{\n    int x,y,z,i,j,ck=0;\n    scanf(\"%d%d%d\",&x,&y,&z);\n    for(i=0;i<=z;i++){\n        for(j=0;j<=z;j++){\n            if(x*i+y*j==z){\n                ck=1;\n                break;\n            }\n        }\n    }\n    if(ck==1){\n        printf(\"Yes\\n\");\n    }\n    else {\n        printf(\"No\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b537192525f62ce090f3d023d2ee1ac1", "src_uid": "e66ecb0021a34042885442b336f3d911", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\nvoid main()\n{\nint a,b,c,m=0,j,s=0,i;\nclrscr();\nscanf(\"%d%d%d\",&a,&b,&c);\nfor(i=0;i<=999;i++)\nfor(j=0;j<=999;j++)\n{\ns=a*i+b*j;\nif(s==c)\nm=1;\ns=0;\n}\nif(m==1)\nprintf(\"Yes\");\nelse\nprintf(\"No\");\ngetch();\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "913898983b86df391b6ceffeb36110bf", "src_uid": "e66ecb0021a34042885442b336f3d911", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int a , b , c , i , temp;\n    scanf(\"%d %d %d\", &a ,&b ,&c);\n    for ( i = 1 ; i <= c ; i++){\n        temp = c - ( i * a);\n        if ( temp >= 0 && temp % b == 0 ){\n            print(\"Yes\");\n            return 0;\n        }\n    }\n    print(\"No\");\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "373e2fb186e7cbc473f7237aec436857", "src_uid": "e66ecb0021a34042885442b336f3d911", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<limits.h>\n#include<string.h>\n\n#define swap(a,b) (a)=(a)+(b)-((b)=(a))\n#define min(a,b) ((a)<(b)?(a):(b))\n#define max(a,b) ((a)>(b)?(a):(b))\n#define FOR(i,a,b) for((i)=(a);(i)<(b);(i)++)\n#define pw printf(\" \")\n#define pn printf(\"\\n\")\n#define pi(a) printf(\"%d\",(a))\n#define si(a) scanf(\"%d\",(&a))\n#define FORD(i,a,b) for((i)=(a);(i)>=(b);(i)++)\n#define chkpowtwo(a) (!((a)&((a)-1)))\n\ninline int power(int a,int b)\n{\n\tint s=1;\n\twhile(b)\n\t{\n\t\tif(b&1)\n\t\t\ts*=a;\n\t\ta=a*a;\n\t\tb=b/2;\n\t}\n\treturn s;\n}\n\nint main()\n{\n\tint n;\n\tsi(n);\n\tint i,flag,x,count=0;\n\tFOR(x,1,n)\n\t{\n\t\tflag=0;\n\t\tFOR(i,1,n-1)\n\t\t{\n\t\t\tif(power(x,i)%n==1)\n\t\t\t\tflag=1;\n\t\t}\n\t\tif(power(x,n-1)%n!=1)\n\t\t\tflag=1;\n\t\tif(flag==0)\n\t\t\tcount++;\n\t}\n\tpi(count);pn;\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1b4ec0c2341c3406dbd706eb32f8d0f2", "src_uid": "3bed682b6813f1ddb54410218c233cff", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <cstdio>\n\nint main()\n{\n    int p, count(0);\n    scanf(\"%d\", &p);\n    for (int n = 1; n < p; ++n)\n    {\n        bool ok = true;\n        int x = 1;\n        for (int i = 1; i < p - 1; ++i)\n        {\n            x *= n;\n            x %= p;\n            if (x == 1)\n            {\n                ok = false;\n                break;\n            }\n        }\n        if (ok)\n        {\n            x *= n;\n            x %= p;\n            if (x == 1)\n            {\n                count += 1;\n            }\n        }\n    }\n    printf(\"%d\\n\", count);\n    return 0;\n}\n\n\n//4306655\t Aug 18, 2013 8:36:13 AM\tfuwutu\t 284A - Cows and Primitive Roots\t GNU C++0x\tAccepted\t30 ms\t0 KB\n#include <cstdio>\n\nint main()\n{\n    int p;\n    scanf(\"%d\", &p);\n    int n = p - 1;\n    int count = n;\n    for (int i = 2; i * i <= n; ++i)\n    {\n        if (n % i == 0)\n        {\n            do\n            {\n                n /= i;\n            } while (n % i == 0);\n            count = count / i * (i - 1);\n        }\n    }\n    if (n != 1)\n    {\n        count = count / n * (n - 1);\n    }\n    printf(\"%d\\n\", count);\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "2754f63c1f554bc77ce8fa8add4f3f04", "src_uid": "3bed682b6813f1ddb54410218c233cff", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "\n#include <cstdio.h>\n\nint main()\n{\n    int p;\n    scanf(\"%d\", &p);\n    int n = p - 1;\n    int count = n;\n    for (int i = 2; i * i <= n; ++i)\n    {\n        if (n % i == 0)\n        {\n            do\n            {\n                n /= i;\n            } while (n % i == 0);\n            count = count / i * (i - 1);\n        }\n    }\n    if (n != 1)\n    {\n        count = count / n * (n - 1);\n    }\n    printf(\"%d\\n\", count);\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "7e17ebf65f17df664fc075a1450aba22", "src_uid": "3bed682b6813f1ddb54410218c233cff", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "\n#include <stdio.h>\n\nint main()\n{\n    int p;\n    scanf(\"%d\", &p);\n    int n = p - 1;\n    int count = n;\n    for (int i = 2; i * i <= n; ++i)\n    {\n        if (n % i == 0)\n        {\n            do\n            {\n                n /= i;\n            } while (n % i == 0);\n            count = count / i * (i - 1);\n        }\n    }\n    if (n != 1)\n    {\n        count = count / n * (n - 1);\n    }\n    printf(\"%d\\n\", count);\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "9a9df9b6e96d2b2b97e780452e1406c7", "src_uid": "3bed682b6813f1ddb54410218c233cff", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n   int i,c=0,j,p,x,f;\n   scanf(\"%d\",&p);\n   for(i=2;i<p;++i)\n   {\n      x=i;\n      f=1;\n      for(j=2;j<p;++j)\n      {\n         if(x==1)f=0;\n         x=(x*i)%p;\n      }\n      if(f==1 && x==1)++c;\n   }\n   printf(\"%d\",c);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7b401b82da1175c0ef85dd2e4905e3c7", "src_uid": "3bed682b6813f1ddb54410218c233cff", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n     int n,m,k;\n     scanf(\"%d %d %d\",&n,&m,&k);\n     int a[n];\n   int i,j,l,o,p,b,c;\n   for(i=1;i<=n;i++)\n   {\n        scanf(\"%d\",&a[i]);\n   }\n   for(i=1;i<n;i++)\n   {\n        for(j=i+1;j<=n;j++)\n        {\n             if(a[i]>a[j])\n             {\n                  l=a[j];\n                  a[j]=a[i];\n                  a[i]=l;\n             }\n        }\n   }int t=1;p=0;\n   for(i=n;i>1;i--)\n   {\n        p+=a[i]+k-1;\n        k--;\n        \n        if(p>=m)\n        break;\n        if(k==0)\n        {\n             p+=a[i-1]-1\n        }\n        t++;\n        \n   }\n   printf(\"%d\",t);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "598d7921fdab934ee3d86a4a8b62a586", "src_uid": "b32ab27503ee3c4196d6f0d0f133d13c", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,m,k,i,j,count,temp,o=0;\n\tscanf(\"%d%d%d\",&n,&m,&k);\n\tint a[n];\n\tfor(i=0;i<n;i++)\n\tscanf(\"%d\",&a[i]);\n\tfor(i=0;i<n-1;i++)\n\t{\n\t\tfor(j=i+1;j<n;j++)\n\t\t{\n\t\t\tif(a[i]>a[j])\n\t\t\t{\n\t\t\t\ttemp=a[i];\n\t\t\t\ta[i]=a[j];\n\t\t\t\ta[j]=temp;\n\t\t\t}\n\t\t}\n\t}\n\tm=m-k;\n\ttemp=0;\n\tcount=0;\n\to=0;\n\tfor(i=n-1;i>=0;i--)\n\t{\n\t\tif(temp<m)\n\t\t{\n\t\t\ttemp=temp+a[i]-1;\n\t\t\to++;\n\t\t}\n\t\telse if(temp>=m)\n\t\t{\n\t\t\tprintf(\"%d\",o);\n\t\t\tcount=1;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(count==0)\n\tprintf(\"-1\");\n}#include<stdio.h>\nint main()\n{\n\tint n,m,k,i,j,count,temp,o=0;\n\tscanf(\"%d%d%d\",&n,&m,&k);\n\tint a[n];\n\tfor(i=0;i<n;i++)\n\tscanf(\"%d\",&a[i]);\n\tfor(i=0;i<n-1;i++)\n\t{\n\t\tfor(j=i+1;j<n;j++)\n\t\t{\n\t\t\tif(a[i]>a[j])\n\t\t\t{\n\t\t\t\ttemp=a[i];\n\t\t\t\ta[i]=a[j];\n\t\t\t\ta[j]=temp;\n\t\t\t}\n\t\t}\n\t}\n\tm=m-k;\n\ttemp=0;\n\tcount=0;\n\to=0;\n\tfor(i=n-1;i>=0;i--)\n\t{\n\t\tif(temp<m)\n\t\t{\n\t\t\ttemp=temp+a[i]-1;\n\t\t\to++;\n\t\t}\n\t\telse if(temp>=m)\n\t\t{\n\t\t\tprintf(\"%d\",o);\n\t\t\tcount=1;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(count==0)\n\tprintf(\"-1\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "531c988c760fd06b219bc424a2200e3f", "src_uid": "b32ab27503ee3c4196d6f0d0f133d13c", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"socket\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin\\Debug\\socket\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj\\Debug\\\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin\\Release\\socket\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj\\Release\\\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "418c8e7d4ed44fbfeee84a5bdf78f75a", "src_uid": "b32ab27503ee3c4196d6f0d0f133d13c", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint b[501];\nvoid merge(int a[], int k,int l);\nvoid merge_sort(int a[], int n);\n\nint main()\n{\n    int n,m,k,i,s,flag,a[501];\n    scanf(\"%d%d%d\",&n,&m,&k);\n    for(i=0;i<n;i++) scanf(\"%d\",&a[i]);\n    merge_sort(a,n);\n    s=k;\n    i=0;\n    flag=0;\n    while(s<m&&i<n&&)\n    {\n              s=s+a[n-1-i]-1;\n              i++;\n              if(s>=m) {flag=1;break;}\n    }\n    if(k!=0&&flag) printf(\"%d\\n\",i);\n    else printf(\"-1\\n\");//getch();\n    return 0;\n}\nvoid merge_sort(int a[], int n)\n{\nif(n==1||n==0) return;\nmerge_sort(a, n/2);\nmerge_sort(a+n/2, n-n/2);\nmerge(a,n/2, n-n/2);\n}\n\nvoid merge(int a[], int k,int l)\n{\n int i,j=k,c=0;\nfor(i=0;i<k&&j<k+l;)\n{\nwhile(a[i]<a[j]&&i<k){ b[c]=a[i]; c++; i++;} if(i==k) break;\nwhile(a[i]>=a[j]&&j<k+l){ b[c]=a[j];c++; j++;} if(j==k+l) break;\n}\nif(i<k) {for(;i<k;i++){ b[c]=a[i];c++;}}\nelse if(j<k+l) { for(;j<k+l;j++){ b[c]=a[j];c++;}}\n\nfor(i=0;i<k+l;i++)\n  a[i]=b[i];\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c3797b461da61601a751994493c1fdc2", "src_uid": "b32ab27503ee3c4196d6f0d0f133d13c", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "\n#include<stdio.h>\nint main()\n{\nint n,m,k,i,s=0,tmp,x,y,t;\nint a[50];\nscanf(\"%d %d %d\",&n,&m,&k);\ntmp=n;\nwhile(n--)\nscanf(\"%d\",&a[i++]);\n\nfor(x=0;x<=tmp-2;x++)\n{\n    for(y=0;y<=tmp-2-x;y++)\n    {\n        if(a[y]<a[y+1])\n        {\n            t=a[y];\n            a[y]=a[y+1];\n            a[y+1]=t;\n        }\n    }\n}\n\nfor(i=0;i<n;i++)\n{\n    if(s+k>=m){break;}\n\n    else {s+=a[i];k--;}\n}\nif(s+k>=m)\n    printf(\"%d\",i);\n    \nelse  printf(\"%d\",-1);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4b7903a1e46d30fd9bbdb17a0af3b965", "src_uid": "b32ab27503ee3c4196d6f0d0f133d13c", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n\tchar a[200];\n\tint count = 0;\n\tgets(a);\n\tint n = strlen(a);\n\tfor(int i = 0; i < n; i++)\n\tif( a[i] == 'Q');\n\tfor(int j = i + 1; j < n; j++)\n\tif( a[j] == 'A');\n\tfor(int k = j + 1; k < n; k++)\n\tif( a[k] == 'Q');\n\n\tcount++;\n\t\n\tprintf(\"%d\\n\", count);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4cafc4510f6bf5e010616a2fb3ba6eb8", "src_uid": "8aef4947322438664bd8610632fe0947", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n   char str[101];int count=0,ans=0;\n   scanf(\"%s\",str);\n   str[strlen(str)]='\\0';\n   for(i=0;i<strlen(str)-1;i++)\n   {\n      if(str[i]=='Q')\n      {for(j=i+1;j<strlen(str);j++)\n      {\n         if(str[j]=='Q')\n         {ans+=count;\n         count=0;}\n         if(str[j]=='A')\n         count++;\n      }}}\n      printf(\"%d\",ans);\n      return 0;\n         \n\n   \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "737016a6dbede4b5f92edb97c6ef0211", "src_uid": "8aef4947322438664bd8610632fe0947", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"QAQ\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/QAQ\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/QAQ\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "85efd195400b4e6b2c8220a33f2c82b2", "src_uid": "8aef4947322438664bd8610632fe0947", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\n#include<string>\nusing namespace std;\nint main()\n{\n\tstring s;\n\tgetline(cin,s);\n\tint i,count=0,j,k;\n\tfor(i=0;s[i]!='\\0';i++)\n\t{\n\t\tif(s[i]=='Q'&&s[i+1]=='A')\n\t\t{\n\t\t\tfor(j=i+1;s[j]!='\\0';j++)\n\t\t\t{\n\t\t\t\tif(s[j]=='Q')\n\t\t\t\tcount++;\n\t\t\t}\n\t\t}\n\t}\n\t\tfor(i=0;s[i]!='\\0';i++)\n\t\t{\n\t\t\tif(s[i]=='Q'&&s[i+1]!='A')\n\t\t\t{\n\t\t\t\tfor(j=i+1;s[j]!='\\0';j++)\n\t\t\t\t{\n\t\t\t\t\tif(s[j]=='A'&&s[j+1]=='Q')\n\t\t\t\t\tcount++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(i=0;s[i]!='\\0';i++)\n\t\t{\n\t\t\tif(s[i]=='Q')\n\t\t\t{\n\t\t\tfor(j=i+2;s[j]!='0';j++)\n\t\t\t{\n\t\t\t\tif(s[j]=='A'&&s[j+1]=='Q')\n\t\t\t\tcount++;\n\t\t\t}\n\t\t}\n\t}\n\t\t\tfor(i=0;s[i]!='\\0';i++)\n\t\t\t{\n\t\t\t\tif(s[i]=='Q')\n\t\t\t\t {\n\t\t\t\t \tfor(j=i+2;s[j]!='\\0';j++)\n\t\t\t\t \t{\n\t\t\t\t \t\tif(s[j]=='A')\n\t\t\t\t \t\t{\n\t\t\t\t \t\tfor(k=j+2;s[k]!='\\0';k++)\n\t\t\t\t \t\t{\n\t\t\t\t \t\t\tif(s[k]=='Q')\n\t\t\t\t \t\t\tcount++;\n\t\t\t\t\t\t }\n\t\t\t\t \t\t\n\t\t\t\t\t }\n\t\t\t\t }\n\t\t\t}\n\t\t\t\n\t\t}\ncout<<count<<endl;\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "10d085899bdf2a43e69c97e7f5ad3ccd", "src_uid": "8aef4947322438664bd8610632fe0947", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n\tchar s[110];\n\tint i,j,k,n,sum=0;\n\tscanf(\"%s\",&s);\n\tn=strlen(s);\n\tfor(i=0;i<n;i++){\n\t\tfor(j=i+1;j<n;j++){\n\t\t\tfor(k=j+1;k<n;k++){\n\t\t\t\tif(s[i]=='Q'&&s[j]=='A'&&s[k]=='Q')\n\t\t\t\t  sum++;\n\t\t\t\n\t\t}\n\t}\n\tprintf(\"%d\",sum);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "03b1b8f8e9fce42d6c90cca66af0157e", "src_uid": "8aef4947322438664bd8610632fe0947", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n    int n,k,largest=0,score0=0;\n    scanf(\"%d\",&n);\n    int hl=(n+1/2);\n    int a[n];\n    for(int i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        if(a[i]>largest)\n        {\n            largest=a[i];\n        }\n        score0=score0+a[i];\n    }\n    int tk;\n    for(int i=0;i<n;i++)\n    {\n        tk=hl*largest;\n        if(score0<tk)\n        {\n            exit(0);\n        }\n        else()\n        {\n            ++largest;\n        }\n    }\n    printf(\"%d\",largest);\n    return\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c4e7cda7822bbb29cc116b0650dd1c3e", "src_uid": "d215b3541d6d728ad01b166aae64faa2", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n ; \n    scanf(\"%d\",&n);\n    max = 0;\n    int x ; \n    int total=0;\n    int max=0 ;\n    for(int i = 0 ; i < n ; i++){\n        scanf(\"%d\",&x);\n        if(x>max)\n            max = x;\n        total+=x;\n    }\n    for(int i = 0 ; i < max ; i ++)\n    {\n        if(i*n > total){\n            printf(\"%d\",i);\n            return 0;\n        }\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6395fd659742cd74fb818a8b6af66c57", "src_uid": "d215b3541d6d728ad01b166aae64faa2", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n    int i, n, k=0, score=0;\n    scanf(\"%d\",&n);\n    int a[n];\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    for(i=0;i<n;i++)\n    {\n        score=score+a[i];\n        if(a[i]>k)\n        {\n            k=a[i];\n        }\n    }\n    int high;\n    for(i=k;i<=1000000;i++)\n    {\n        high=k*n;\n        if(score<=((high-1)/2))\n        {\n            break;\n        }\n        else\n        {\n            ++k;\n        }\n    }\n    printf(\"%d\",);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4443c69392385b65d0b86a89d54186ec", "src_uid": "d215b3541d6d728ad01b166aae64faa2", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\n\n\nint main(){\n\t\n\tint students;\n\tscanf(\"%d\", &students);\n\tint arr[students];\n\tint arr1[students];\n\tint max = -1;\n\tint count = 0;\n\tfor(int i = 0 ; i < students ; i ++){\n\t\tscanf(\"%d\", &arr[i]);\n\t\tcount += arr[i];\n\t\tif(arr[i] > max)max = arr[i];\n\t}\n\tbool cek = true;\n\tint temp;\n\twhile(cek){\n\t\ttemp = 0;\n\t\tfor(int i = 0 ; i < students ; i ++){\n\t\t\tarr1[i] = max - arr[i];\n\t\t\ttemp += arr1[i];\n\t\t}\n\t\tif(temp < count){\n\t\t\tmax++;\n\t\t}\n\t\telse{\n\t\t\tcek = false;\n\t\t}\n\t}\n\tprintf(\"%d\", max);\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "010cef60b49d23574235b69aa7214593", "src_uid": "d215b3541d6d728ad01b166aae64faa2", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n ; \n    scanf(\"%d\",&n);\n    max = 0;\n    int x ; \n    int total=0;\n    int res=0 ;\n    for(int i = 0 ; i < n ; i++){\n        scanf(\"%d\",&x);\n        if(x>max)\n            max = x;\n        total+=x;\n    }\n    for(int i = 0 ; i < max ; i ++)\n    {\n        if(i*n > total){\n            printf(\"%d\",i);\n            return 0;\n        }\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b465affd0d13597090d5d7943b1d4810", "src_uid": "d215b3541d6d728ad01b166aae64faa2", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n  int n,i,j,k,l=0;\n  int arr[100];\n  scanf(\"%d\",&n);\n  int arr1[n];\n  for(i=0;i<n;i++)\n    {\n         scanf(\"%d\",&arr[i]);\n    }\n for(i=0;i<n;i++)\n    {\n         arr1[i]=arr[i];\n    }\n for(i=n-1;i>=0;i--)\n    {\n        for(j=i-1;j>=0;j--)\n        {\n            if(arr[i]==arr[j])\n            {\n                arr1[j]=2000;\n            }\n\n        }\n    }\n    for(i=0;i<n;i++)\n    {\n        if(arr1[i]!=2000){\n            l++;\n        }\n    }\n    printf(\"%d\\n\",l);\n    for(i=0;i<n;i++)\n    {\n        if(arr1[i]!=2000){\n            printf(\"%d \",arr1[i]);\n        }\n    }", "lang_cluster": "C", "compilation_error": true, "code_uid": "6f87ea609845ac53697b0ef98614ab5d", "src_uid": "1b9d3dfcc2353eac20b84c75c27fab5a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n, m, i, j=0, a[1010], b[1010], s[] = {0,0,0,0,0,0,0,0,0,0,0};\n    scanf(\"%d\", &n);\n    for(i=0; i<n; i++)\n    {\n        scanf(\"%d\", &a[i]);\n    }\n    for(i=n-1, j=0; i>=0; i--)\n    {\n        m = a[i];\n        if(s[m]==0)\n        {\n            s[m] = s[m]+1;\n            b[j] = a[i];\n            j++;\n        }\n    }\n    printf(\"%d\\n\", j);\n    for(i=j-1; i>=0; i--)\n    {\n        if(j==0)\n        {\n            printf(\"%d\\n\", b[i]);\n        }\n        else\n        {\n            printf(\"%d \", b[i]);\n        }\n    }\n    return 0;\n}\nclose", "lang_cluster": "C", "compilation_error": true, "code_uid": "ef91ab126db07152d650bf19ce3b89cd", "src_uid": "1b9d3dfcc2353eac20b84c75c27fab5a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tint a[n];\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tscanf(\"%d\",&a[i]);\n\t}\n\tint b[n];\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tb[i]=-1;\n\t}\n\tint k=0;\n\tfor (int i = n-1; i >=0 ; i--)\n\t{\n\t\tint flag=0;\n\t\tfor (int j = 0; j < n; ++j)\n\t\t{\n\t\t\tif (b[j]==a[i])\n\t\t\t{\n\t\t\t\tflag=1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (flag!=1)\n\t\t{\n\t\t\tb[k++]=a[i];\n\t\t}\n\t}\n\t//for (int i = 0; i < n; ++i)\n\t//{\n\t\tprintf(\"%d \",b[i]);\n\t//}\n\tint c;\n\tfor (c = 0; b[c]!=-1 && c<n; ++c);\n\t\tprintf(\"%d\\n\",c);\n\tfor (int i = c-1; i>=0; i--)\n\t{\n\t\tprintf(\"%d \",b[i]);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6f7fcd65057a9ba2f44da57580c47f6b", "src_uid": "1b9d3dfcc2353eac20b84c75c27fab5a", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n, m, i, j=0, a[1010], b[1010], s[] = {0,0,0,0,0,0,0,0,0,0,0};\n    \n    scanf(\"%d\", &n);\n    for(i=0; i<n; i++)\n    {\n        scanf(\"%d\", &a[i]);\n    }\n    for(i=n-1, j=0; i>=0; i--)\n    {\n        m = a[i];\n        if(s[m]==0)\n        {\n            s[m] = s[m]+1;\n            b[j] = a[i];\n            j++;\n        }\n    }\n    printf(\"%d\\n\", j);\n    for(i=j-1; i>=0; i--)\n    {\n        if(j==0)\n        {\n            printf(\"%d\\n\", b[i]);\n        }\n        else\n        {\n            printf(\"%d \", b[i]);\n        }\n    }\n\n    return 0;\n}\nclose  ", "lang_cluster": "C", "compilation_error": true, "code_uid": "f414c05f030327b89a0d3b6aeb7f88fb", "src_uid": "1b9d3dfcc2353eac20b84c75c27fab5a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int i,j=0;\n    int count=0;\n    int n;\n    int a[200];\n    int b[200];\n    int c[200];\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        b[a[i]]++;\n    }\n    for(i=n-1;i>=0;i--)\n    {\n        if(b[a[i]]>=1)\n        {\n            count++;\n            c[j]=a[i];\n            b[a[i]]=0;\n            j++;\n        }\n        }\n\n    printf(\"%d\\n\",count);\n    for(i=j-1;i>=0;i--)\n        printf(\"%d \",c[i]);\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int i,j=0;\n    int count=0;\n    int n;\n    int a[200];\n    int b[200];\n    int c[200];\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        b[a[i]]++;\n    }\n    for(i=n-1;i>=0;i--)\n    {\n        if(b[a[i]]>=1)\n        {\n            count++;\n            c[j]=a[i];\n            b[a[i]]=0;\n            j++;\n        }\n        }\n\n    printf(\"%d\\n\",count);\n    for(i=j-1;i>=0;i--)\n        printf(\"%d \",c[i]);\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int i,j=0;\n    int count=0;\n    int n;\n    int a[200];\n    int b[200];\n    int c[200];\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        b[a[i]]++;\n    }\n    for(i=n-1;i>=0;i--)\n    {\n        if(b[a[i]]>=1)\n        {\n            count++;\n            c[j]=a[i];\n            b[a[i]]=0;\n            j++;\n        }\n        }\n\n    printf(\"%d\\n\",count);\n    for(i=j-1;i>=0;i--)\n        printf(\"%d \",c[i]);\n    return 0;\n}\n#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int i,j=0;\n    int count=0;\n    int n;\n    int a[1000];\n    int b[1000];\n    int c[1000];\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        b[a[i]]++;\n    }\n    for(i=n-1;i>=0;i--)\n    {\n        if(b[a[i]]>=1)\n        {\n            count++;\n            c[j]=a[i];\n            b[a[i]]=0;\n            j++;\n        }\n        }\n\n    printf(\"%d\\n\",count);\n    for(i=j-1;i>=0;i--)\n        printf(\"%d \",c[i]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "02d755b33d8639edb3a7beb55bfd1acc", "src_uid": "1b9d3dfcc2353eac20b84c75c27fab5a", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(){\n    int a, b, c, sum = 0, r = 0;\n    scanf(\"%d %d %d\", &a, &b, &c);\n    while(a >= 3 && b >= 2 && c >= 2){\n        a -= 3;\n        b -= 2;\n        c -= 2;\n        sum += 7;\n    }\n    int next, e, ccc, ee, aa, bb, cc;\n    for(int i = 0; i < 7; i++){\n        next = 1; e = i; ccc = 0; aa = a; bb = b; cc = c;\n        while(next){\n            ee = e%7;\n            if(ee == 0 || ee == 3 || ee == 6){\n                if(aa == 0){\n                    next = 0;\n                } else {\n                    aa--;\n                }\n            } else if(ee == 1 || ee == 5){\n                if(bb == 0){\n                    next = 0;\n                } else {\n                    bb--;\n                }\n            } else {\n                if(cc == 0){\n                    next = 0;\n                } else {\n                    cc--;\n                }\n            }\n            if(next){\n                ccc++;\n                e++;\n            }\n        }\n        if(ccc > r){\n            r = ccc;\n        }\n    }\n    printf(\"%d\", sum+r);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "be60dcb2c4ae9550e1529963a4b596c0", "src_uid": "e17df52cc0615585e4f8f2d31d2daafb", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n\tlong long int a,b,c;\n\tscanf(\"%lld%lld%lld\",&a,&b,&c);\n\tlong long int x1=a,x2=b,x3=c,t=0,max=0,min,c1,c2,c3;\n\t\tx1=a;\n\t\tx2=b;\n\t\tx3=c;\n\t\tc1=a/3;\n\t\tc2=b/2;\n\t\tc3=c/2;\n\t\tif(c1<c2)\n\t\t\tmin=c1;\n\t\telse\n\t\t\tmin=c2;\n\t\tif(min>c3)\n\t\t\tmin=c3;\n\t\ta-=(min*3);\n\t\tb-=(min*2);\n\t\tc-=(min*2);\n\t\tx1=a;\n\t\tx2=b;\n\t\tx3=c;\n\t\twhile(1)\n\t\t{\n\t\t\t\n\t\t\tx2--;\n\t\t\tt++;\n\t\t\tif(x2<0)\n\t\t\t\tbreak;\n\t\t\tx3--;\n\t\t\tt++;\n\t\t\tif(x3<0)\n\t\t\t\tbreak;\n\t\t\tx1--;\n\t\t\tt++;\n\t\t\tif(x1<0)\n\t\t\t\tbreak;\n\t\t\tx3--;\n\t\t\tt++;\n\t\t\tif(x3<0)\n\t\t\t\tbreak;\n\t\t\tx2--;\n\t\t\tt++;\n\t\t\tif(x2<0)\n\t\t\t\tbreak;\n\t\t\tx1--;\n\t\t\tt++;\n\t\t\tif(x1<0)\n\t\t\t\tbreak;\n\t\t\tx1--;\n\t\t\tt++;\n\t\t\tif(x1<0)\n\t\t\t\tbreak;\n\t\t}\n\t\tmax=t;\n\t\tt=0;\nx1=a;\n\t\tx2=b;\n\t\tx3=c;\n\t\twhile(1)\n\t\t{\n\t\t\t\t\t\tx3--;\n\t\t\tt++;\n\t\t\tif(x3<0)\n\t\t\t\tbreak;\n\t\t\tx1--;\n\t\t\tt++;\n\t\t\tif(x1<0)\n\t\t\t\tbreak;\n\t\t\tx3--;\n\t\t\tt++;\n\t\t\tif(x3<0)\n\t\t\t\tbreak;\n\t\t\tx2--;\n\t\t\tt++;\n\t\t\tif(x2<0)\n\t\t\t\tbreak;\n\t\t\tx1--;\n\t\t\tt++;\n\t\t\tif(x1<0)\n\t\t\t\tbreak;\n\t\t\tx1--;\n\t\t\tt++;\n\t\t\tif(x1<0)\n\t\t\t\tbreak;\n\t\t\tx2--;\n\t\t\tt++;\n\t\t\tif(x2<0)\n\t\t\t\tbreak;\n\n\t\t}\n\t\tif(t>max)\n\t\t\tmax=t;\n\t\tt=0;\nx1=a;\n\t\tx2=b;\n\t\tx3=c;\n\t\twhile(1)\n\t\t{\n\t\t\t\n\t\t\tx1--;\n\t\t\tt++;\n\t\t\tif(x1<0)\n\t\t\t\tbreak;\n\t\t\tx3--;\n\t\t\tt++;\n\t\t\tif(x3<0)\n\t\t\t\tbreak;\n\t\t\tx2--;\n\t\t\tt++;\n\t\t\tif(x2<0)\n\t\t\t\tbreak;\n\t\t\tx1--;\n\t\t\tt++;\n\t\t\tif(x1<0)\n\t\t\t\tbreak;\n\t\t\tx1--;\n\t\t\tt++;\n\t\t\tif(x1<0)\n\t\t\t\tbreak;\n\t\t\tx2--;\n\t\t\tt++;\n\t\t\tif(x2<0)\n\t\t\t\tbreak;\n\t\t\tx3--;\n\t\t\tt++;\n\t\t\tif(x3<0)\n\t\t\t\tbreak;\n\t\t}\n\t\tif(t>max)\n\t\t\tmax=t;\n\t\tt=0;\nx1=a;\n\t\tx2=b;\n\t\tx3=c;\n\t\twhile(1)\n\t\t{\n\t\t\t\n\t\t\tx3--;\n\t\t\tt++;\n\t\t\tif(x3<0)\n\t\t\t\tbreak;\n\t\t\tx2--;\n\t\t\tt++;\n\t\t\tif(x2<0)\n\t\t\t\tbreak;\n\t\t\tx1--;\n\t\t\tt++;\n\t\t\tif(x1<0)\n\t\t\t\tbreak;\n\t\t\tx1--;\n\t\t\tt++;\n\t\t\tif(x1<0)\n\t\t\t\tbreak;\n\t\t\tx2--;\n\t\t\tt++;\n\t\t\tif(x2<0)\n\t\t\t\tbreak;\n\t\t\tx3--;\n\t\t\tt++;\n\t\t\tif(x3<0)\n\t\t\t\tbreak;\n\t\t\tx1--;\n\t\t\tt++;\n\t\t\tif(x1<0)\n\t\t\t\tbreak;\n\t\t}\n\t\tif(t>max)\n\t\t\tmax=t;\n\t\tt=0;\nx1=a;\n\t\tx2=b;\n\t\tx3=c;\n\t\twhile(1)\n\t\t{\n\t\t\t\n\t\t\tx2--;\n\t\t\tt++;\n\t\t\tif(x2<0)\n\t\t\t\tbreak;\n\t\t\tx1--;\n\t\t\tt++;\n\t\t\tif(x1<0)\n\t\t\t\tbreak;\n\t\t\tx1--;\n\t\t\tt++;\n\t\t\tif(x1<0)\n\t\t\t\tbreak;\n\t\t\tx2--;\n\t\t\tt++;\n\t\t\tif(x2<0)\n\t\t\t\tbreak;\n\t\t\tx3--;\n\t\t\tt++;\n\t\t\tif(x3<0)\n\t\t\t\tbreak;\n\t\t\tx1--;\n\t\t\tt++;\n\t\t\tif(x1<0)\n\t\t\t\tbreak;\n\t\t\tx3--;\n\t\t\tt++;\n\t\t\tif(x3<0)\n\t\t\t\tbreak;\n\t\t}\n\t\tif(t>max)\n\t\t\tmax=t;\n\t\tt=0;\nx1=a;\n\t\tx2=b;\n\t\tx3=c;\n\t\twhile(1)\n\t\t{\n\t\t\t\n\t\t\tx1--;\n\t\t\tt++;\n\t\t\tif(x1<0)\n\t\t\t\tbreak;\n\t\t\tx1--;\n\t\t\tt++;\n\t\t\tif(x1<0)\n\t\t\t\tbreak;\n\t\t\tx2--;\n\t\t\tt++;\n\t\t\tif(x2<0)\n\t\t\t\tbreak;\n\t\t\tx3--;\n\t\t\tt++;\n\t\t\tif(x3<0)\n\t\t\t\tbreak;\n\t\t\tx1--;\n\t\t\tt++;\n\t\t\tif(x1<0)\n\t\t\t\tbreak;\n\t\t\tx3--;\n\t\t\tt++;\n\t\t\tif(x3<0)\n\t\t\t\tbreak;\n\t\t\tx2--;\n\t\t\tt++;\n\t\t\tif(x2<0)\n\t\t\t\tbreak;\n\t\t}\n\t\tif(t>max)\n\t\t\tmax=t;\n\t\tt=0;\n\t\tmax--;\n\t\tmax+=min*7;\n\t\tprintf(\"%lld\\n\",max );\n\t\treturn 0;\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5d72876e51d40ea9e20cb44bd57067b3", "src_uid": "e17df52cc0615585e4f8f2d31d2daafb", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#include<math.h>\n\nint compare_char(char *a,char *b){\n\treturn strcmp(a,b);\n}\n\nint intsort(const void *a, const void *b){\n\treturn *(int*)b - *(int*)a;\n\t/*qsort(a,a\u306e\u914d\u5217\u6570,sizeof(int),intsort);*/\n}\n\nint longsort(const void *a, const void *b){\n\tlong *A=(long *)a;\n\tlong *B=(long *)b;\n\tif(*A>*B) return -1;\n\tif(*A<*B) return 1;\n\treturn 0;\n}\n\nint main(){\n\tint i,N,j,p,a[4]={0},b[i],cnt=0,min,ans=0,x,y,z,day=0;\n\tfor(i=0;i<3;i++){\n\tscanf(\"%d\",&a[i]);\n\t}\n/*\tif(a[0]%3==0){\n*/\t\n\t\nb[0]=a[0]/3;\nmin=b[0];\n/*\t}else{\n\t\tb[0]=a[0]/3+1;\n\t}\n\tif(a[1]%2==0){\n*/\nb[1]=a[1]/2;\nif(min>b[1])min=b[1];\n/*\t}else{\n\t\tb[1]=a[1]/2+1;\n\t}\n\tif(a[2]%2==0){\n*/\nb[2]=a[2]/2;\nif(min>b[2])min=b[2];\n/*\t}else{\n\t\tb[2]=a[2]/2+1;\n\t}\n*/\n\nans=min*7;\na[0]-=3*min;\na[1]-=2*min;\na[2]-=2*min;\nmin=0;\nx=a[0];\ny=a[1];\nz=a[2];\n\t//sun\n\twhile(1){\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(y>0){\n\ty--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(z>0){\n\tz--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(z>0){\n\tz--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(y>0){\n\ty--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\t}\n\tmin=day;\n\t\n\tday=0;\n\tx=a[0];\t\n\ty=a[1];\n\tz=a[2];\n\t\t\t\t//\u6708\n\twhile(1){\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(y>0){\n\ty--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(z>0){\n\tz--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(z>0){\n\tz--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(y>0){\n\ty--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\t}\n\tif(min<day)min=day;\n\t\n\tday=0;\n\tx=a[0];\n\ty=a[1];\n\tz=a[2];\n\t\t\t//\u706b\u66dc\n\twhile(1){\n\tif(y>0){\n\ty--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(z>0){\n\tz--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(z>0){\n\tz--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(y>0){\n\ty--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\t}\n\tif(min<day)min=day;\n\t\n\tday=0;\n\tx=a[0];\n\ty=a[1];\n\tz=a[2];\n\t\t\t//\u6c34\u66dc\n\twhile(1){\n\tif(z>0){\n\tz--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(z>0){\n\tz--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(y>0){\n\ty--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(y>0){\n\ty--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\t}\n\tif(min<day)min=day;\n\t\n\tday=0;\n\tx=a[0];\n\ty=a[1];\n\tz=a[2];\n\t\t\t//\u6728\u66dc\n\twhile(1){\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(z>0){\n\tz--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(y>0){\n\ty--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(x>0){\n\tx--;\n\tday++;\t\n\t}else{\t\n\tbreak;\n\t}\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(y>0){\n\ty--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(z>0){\n\tz--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\t}\n\tif(min<day)min=day;\n\t\n\tday=0;\n\tx=a[0];\n\ty=a[1];\n\tz=a[2];\n\t\t\t//\u91d1\u66dc\n\twhile(1){\n\tif(z>0){\n\tz--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(y>0){\n\ty--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(y>0){\n\ty--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(z>0){\n\tz--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\t}\n\tif(min<day)min=day;\n\nday=0;\nx=a[0];\ny=a[1];\nz=a[2];\n\n\t\t\t//\u571f\u66dc\n\twhile(1){\n\tif(y>0){\n\ty--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(y>0){\n\ty--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(z>0){\n\tz--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(x>0){\n\tx--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\tif(z>0){\n\tz--;\n\tday++;\n\t}else{\n\tbreak;\n\t}\n\t}\n\tif(min<day)min=day;\n\nprintf(\"%d\\n\",ans+min);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c5f89f4f1c5491a4bf69c453380e7cfb", "src_uid": "e17df52cc0615585e4f8f2d31d2daafb", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int a,ac,b,bc,cc,c,n,i,days=0,j;\n    scanf(\"%d %d %d\",&a,&b,&c);\n\n    for(j=1;j<8;j++)\n    {\n        n=0;\n        ac=a;\n        bc=b;\n        cc=c;\n        i=j;\n        while(1)\n        {\n\n            if(i==1||i==4||i==7)\n            {\n                if(ac==0)break;\n                ac--;\n            }\n            else if(i==2||i==6)\n            {\n                if(bc==0)break;\n                bc--;\n            }\n            else\n            {\n                if(cc==0)break;\n                cc--;\n            }\n            if(i==7)i=1;\n            else i++;\n            n++;\n            //printf(\"%d %d %d\\n\",ac,bc,cc);\n        }\n        if(days<n)days=n;\n    }\n    printf(\"%d\",days);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fb63aeb0cf7b3ecb16e7ade0d062ce73", "src_uid": "e17df52cc0615585e4f8f2d31d2daafb", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n\tlong long ans[10]={0},max,flag,count[4]={0},a,b,c,i;\n\tscanf(\"%lld%lld%lld\",&a,&b,&c);\n\tcount[1]=a;\n\tcount[2]=b;\n\tcount[3]=c;\n        for(i=1;i<=7;i++)\n\t{\n\t\tflag=i;\n\t\tcount[1]=a;\n\t\tcount[2]=b;\n\t\tcount[3]=c;\n\t\twhile(1)\n\t\t{\n\t\t\t//start monday\n\t\t\tif(flag==1)\n\t\t\t{\n\t\t\t\tif(count[1]==0)\n\t\t\t\t\tbreak;\n\t\t\t\tcount[1]--;\n\t\t\t\tans[i]++;\n\t\t\t\tflag=2;\n\t\t\t}\n\t\t\tif(flag==2)\n\t\t\t{\n\t\t\t\tif(count[2]==0)\n\t\t\t\t\tbreak;\n\t\t\t\tcount[2]--;\n\t\t\t\tans[i]++;\n\t\t\t\tflag=3;\n\t\t\t}\n\t\t\t if(flag==3)\n                        {\n                                if(count[3]==0)\n                                        break;\n                                count[3]--;\n                                ans[i]++;\n                                flag=4;\n                        }\n\t\t\t  if(flag==4)\n                        {\n                                if(count[1]==0)\n                                        break;\n                                count[1]--;\n                                ans[i]++;\n                                flag=5;\n                        }\n\t\t\t   if(flag==5)\n                        {\n                                if(count[3]==0)\n                                        break;\n                                count[3]--;\n                                ans[i]++;\n                                flag=6;\n                        }\n\t\t\t    if(flag==6)\n                        {\n                                if(count[2]==0)\n                                        break;\n                                count[2]--;\n                                ans[i]++;\n                                flag=7;\n                        }\n\t\t\t     if(flag==7)\n                        {\n                                \n                                if(count[1]==0)\n                                        break;\n                                count[1]--;\n                                ans[i]++;\n\t\t\t\tflag=1;\n                        }\n\t\t}\n\t}\n\n\tmax=0;\n\tfor(i=1;i<=7;i++)\n\t{\n\t//\tprintf(\"%lld\\n\",ans[i]);\n\t\tif(ans[i]>=max)\n\t\t\tmax=ans[i];\n\t}\n\tprintf(\"%lld\\n\",max);\n\treturn 0;\n}\n\n\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bd5403fcb42acba2edfd4177ee4886fe", "src_uid": "e17df52cc0615585e4f8f2d31d2daafb", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int x;\n    scanf(\"%d\",&x);\n    printf(\"%d\",2-x*x);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4b831305b9de6234d7cbaddc3c18b565", "src_uid": "f76005f888df46dac38b0f159ca04d5f", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\nvoid main()\r\n{\r\n    int b;\r\n    scanf(\"%d\",&b);\r\n    printf(\"%d\",2-b*b);\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "aaa872d342149eb77c8f964283416d8d", "src_uid": "f76005f888df46dac38b0f159ca04d5f", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\nvoid main()\r\n{\r\n    int a;\r\n    scanf(\"%d\",&a);\r\n    printf(\"%d\",a);\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "2c55cc301933c274e623cb74e898fa49", "src_uid": "f76005f888df46dac38b0f159ca04d5f", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\nvoid main()\r\n{\r\n    int a;\r\n    scanf(\"%d\",&a);\r\n    printf(\"1\");\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5d6228579edffb37c926dae2a272bc84", "src_uid": "f76005f888df46dac38b0f159ca04d5f", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\nint main(){\r\nint a;\r\ncin>>a;\r\nprintf(\"%d\",2-(a*a));\r\nreturn 0;\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "393967998bcc66d3c7977c75aca406ea", "src_uid": "f76005f888df46dac38b0f159ca04d5f", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main() {\n    int n;\n    scanf(\"%d\", &n);\n    char input[20];\n    scanf(\"%s\", input);\n    int digitCount[8] = {0,0,0,0,0,0,0,0};\n    int i;\n    for (i=0; i<n; i++) {\n        if (input[i]>='2') {\n            switch(input[i]) {\n                case '9':\n                    digitCount[7]++;\n                    digitCount[3]+=2;\n                    digitCount[2]++;\n                break;\n                case '8':\n                    digitCount[7]++;\n                    digitCount[2]+=3;\n                break;\n                case '6':\n                    digitCount[5]++;\n                    digitCount[3]++;\n                break;\n                case '4':\n                    digitCount[3]++;\n                    digitCount[2]+=2;\n                break;\n                default: // 2,3,5,7\n                    int digit = input[i]-'0';\n                    digitCount[digit]++;\n            }\n        }\n    }\n    char number[100];\n    char *numberP = number;\n    int digit;\n    for (digit=7; digit>1; digit--) {\n        char digitC = '0' + digit;\n        for (i=0; i<digitCount[digit]; i++) {\n            *numberP++ = digitC;\n        }\n    }\n    *numberP = 0;\n    printf(\"%s\", number);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b84c54deb0c3a3acf7654a7b9e83eae3", "src_uid": "60dbfc7a65702ae8bd4a587db1e06398", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "\n#include<cstdio>\n#include<sstream>\n#include<cstdlib>\n#include<cctype>\n#include<cmath>\n#include<algorithm>\n#include<set>\n#include<queue>\n#include<stack>\n#include<list>\n#include<iostream>\n#include<fstream>\n#include<numeric>\n#include<string>\n#include<vector>\n#include<cstring>\n#include<map>\n#include<iterator>\nusing namespace std;\nint main()\n{\n    int n;\n    string a;\n    gets(a);\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0e3a50e902715b599cc0897f8cf22600", "src_uid": "60dbfc7a65702ae8bd4a587db1e06398", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main() {\n    int n;\n    scanf(\"%d\", &n);\n    char input[20];\n    scanf(\"%s\", input);\n    int digitCount[8]{0};\n    for (int i=0; i<n; i++) {\n        if (input[i]>='2') {\n            switch(input[i]) {\n                case '9':\n                    digitCount[7]++;\n                    digitCount[3]+=2;\n                    digitCount[2]++;\n                break;\n                case '8':\n                    digitCount[7]++;\n                    digitCount[2]+=3;\n                break;\n                case '6':\n                    digitCount[5]++;\n                    digitCount[3]++;\n                break;\n                case '4':\n                    digitCount[3]++;\n                    digitCount[2]+=2;\n                break;\n                default: // 2,3,5,7\n                    int digit = input[i]-'0';\n                    digitCount[digit]++;\n            }\n        }\n    }\n    char number[100];\n    char *numberP = number;\n    for (int digit=7; digit>1; digit--) {\n        char digitC = '0' + digit;\n        for (int i=0; i<digitCount[digit]; i++) {\n            *numberP++ = digitC;\n        }\n    }\n    *numberP = 0;\n    printf(\"%s\", number);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ec1686d37d4131ba829f6e8bb9b0bc5e", "src_uid": "60dbfc7a65702ae8bd4a587db1e06398", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n#define long long ll\n\nint main(void)\n{\n    int fact[10];\n    fact[0] = 1;\n    int i;\n    for (i = 0; i < 10; ++i) {\n        fact[i] = i * fact[i-1];\n    }\n    int n;\n    scanf(\"%d\", &n);\n    ll num;\n    scanf(\"%lld\", &num);\n    unsigned ll org = 1;\n    ll temp = num;\n    while (temp > 0) {\n        org *= fact[temp % 10];\n        temp = temp / 10;\n    }\n\n    ll ans = 1000000000000000 - 1;\n    ans = ans - num;\n\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "181bc2249fc791ecaa3e64421b987541", "src_uid": "60dbfc7a65702ae8bd4a587db1e06398", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "<stdio.h>\n\nint main()\n{\n    int arr[10],i;\n    for(i=0;i<10;i++)\n    arr[i]=0;\n    int n;\n    scanf(\"%d \",&n);\n    char ch='a';\n    while(1)\n    {\n        scanf(\"%c\",&ch);\n        if(ch=='\\n')\n        break;\n        arr[(int)ch%48]++;\n        //printf(\"i:%d arr[i]:%d\",(int)ch%48,arr[(int)ch%48]);\n    }\n    arr[0]=-1;arr[1]=-1;\n    arr[7]+=arr[9]+arr[8];\n    arr[3]+=2*arr[9]+arr[6]+arr[4];\n    arr[2]+=arr[9]+3*arr[8]+2*arr[4];\n    arr[9]=0;arr[8]=0;\n    arr[5]+=arr[6];\n    arr[6]=0;arr[4]=0;\n    for(i=9;i>=0;i--)\n    {\n        while(arr[i]>0)\n        {\n            printf(\"%d\",i);arr[i]--;\n        }\n    }", "lang_cluster": "C", "compilation_error": true, "code_uid": "f951d3e5446aedba6ffca76bc5bb76f7", "src_uid": "60dbfc7a65702ae8bd4a587db1e06398", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint ch_weight(char p);\nint check_bw(char p[][8]);\n\nint main(){\n    char pan[8][8];\n    char white[4][8];\n    char black[4][8];\n    \n    int i,j,w_num=0,b_num=0;\n    \n    for(i=0;i<8;i++){\n        for(j=0;j<8;j++){\n        scanf(\"%c\",&pan[i][j];\n        }\n    }\n    \n    if(check_bw(pan)==1){\n        for(i=0;i<4;i++){\n         for(j=0;j<4;j++){\n             black[i][j]=pan[i][j];\n             white[i][j]=pan[i+4][j];\n         }\n        }\n    }\n    else if(check_bw(pan)==2){\n         for(i=0;i<4;i++){\n         for(j=0;j<4;j++){\n             black[i][j]=pan[i+4][j];\n             white[i][j]=pan[i][j];\n         }\n        } \n    }\n    \n    for(i=0;i<4;i++){\n        for(j=0;j<4;j++){\n            w_num+=ch_weight(white[i][j]);\n            b_num+=ch_weight(black[i][j]);\n        }\n    }\n    \n    if(w_num>b_num)\n        printf(\"White\\n\");\n    else if(w_num<b_num)\n        printf(\"Black\\n\");\n    else\n        printf(\"Draw\\n\");\n        \n        return 0;\n}\nint ch_weight(char p){\n    swtich(p){\n    case 'p':case'P':\n        return 1;break;\n        case 'q':case'Q':\n        return 9;break;\n            case 'b':case'B':\n        return 3;break;\n            case 'r':case'R':\n        return 5;break;\n            case 'k':case'K':\n        return 3;break;\n        default:\n            return 0;break;\n    }\n}\nint check_bw(char p[][8]){\n    int i,j;\n    \n    for(i=0;i<4;i++){\n        for(j=0;j<8;j++){\n            if(p[i][j]>=97)\n                return 1;\n        }\n    }\n    return 2;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3cf7e8f662374f8288a761313951f7f3", "src_uid": "44bed0ca7a8fb42fb72c1584d39a4442", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int i,j,sum1,sum2;\n    char chess[8][8];\n    while(scanf(\"%c\",&chess[0][0])!=EOF)\n    {\n        sum1=0;\n        sum2=0;\n        for(i=1;i<8;i++)\n            scanf(\"%c\",&chess[0][i]);\n        getchar();\n        for(i=1;i<8;i++)\n        {\n            for(j=0;j<8;j++)\n                scanf(\"%c\",&chess[i][j]);\n            getchar();\n        }\n        for(i=0;i<8;i++)\n            for(j=0;j<8;j++)\n            {\n                if(chess[i][j]=='Q')\n                    sum1+=9;\n                if(chess[i][j]=='q')\n                    sum2+=9;\n                if(chess[i][j]=='R')\n                    sum1+=5;\n                if(chess[i][j]=='r')\n                    sum2+=5;\n                if(chess[i][j]=='B')\n                    sum1+=3;\n                if(chess[i][j]=='b')\n                    sum2+=3;\n                if(chess[i][j]=='N')\n                    sum1+=3;\n                if(chess[i][j]=='n')\n                    sum2+=3;\n                if(chess[i][j]=='P')\n                    sum1==1;\n                if(chess[i][j]=='p')\n                    sum2+=1;\n        if(sum1>sum2) printf(\"White\\n\");\n        else if(sum1<sum2) printf(\"Black\\n\");\n        else printf(\"Draw\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "37e6df8bfac8f0a27114b0a5612b503a", "src_uid": "44bed0ca7a8fb42fb72c1584d39a4442", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int i,j,w=0,b=0;\n    char a;\n    for(j=0;j<64;j++)\n    {\n        scanf(\"%c\",&a);\n        switch(c)\n        {\n        case 'q': b+=9; break;\n        case 'r': b+=5; break;\n        case 'b': b+=3; break;\n        case 'n': b+=3; break;\n        case 'p': b+=1; break;\n        case 'Q': w+=9; break;\n        case 'R': w+=5; break;\n        case 'B': w+=3; break;\n        case 'N': w+=3; break;\n        case 'P': w+=1; break;\n        }\n}\n    if(w=b)\n        printf(\"Draw\");\n    if(w>b)\n        printf(\"White\");\n        if(w<b)\n        printf(\"Black\");\n        return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "49bc9fb6ba619d1d00220141f5910a3d", "src_uid": "44bed0ca7a8fb42fb72c1584d39a4442", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    char z;\n    int i,j,upper=0,lower=0;\n    for(i=0;i<n;i++)\n    {\n    \tfor(j=0;j<n;j++)\n\t{\n\t    scanf(\"%c\",&z);\n\t    if(z=='Q')upper +=9;\n\t\telse if(z=='R')upper +=5;\n    \t\telse if(z=='B')upper +=3;\n\t\telse if(z=='K')upper +=3;\n\t\telse if(z=='P')upper +=1;\n\t\telse if(z=='q')lower +=9;\n\t\telse if(z=='r')lower +=5;\n\t\telse if(z=='b')lower +=3;\n\t\telse if(z=='k')lower +=3;\n\t\telse if(z=='p')lower +=1;\t\t\n\t}\n    }\n    if(lower>upper)\n\tprintf(\"Black\");\n    else if(upper<lower)\n\tprintf(\"White\");\n    else\n\tprintf(\"Draw\");\nreturn 0;\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cd9a4b29790addc228f684c7264ecf0e", "src_uid": "44bed0ca7a8fb42fb72c1584d39a4442", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "\u65f6\u95f4\u8d85\u9650\u4f60\u9ebb\u75f9\u554a\n\n                                                                                                                    ", "lang_cluster": "C", "compilation_error": true, "code_uid": "b9ef2cc21f3631c5b3b46cbeac9d134d", "src_uid": "44bed0ca7a8fb42fb72c1584d39a4442", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,d,array[n],i,t;\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<=n-1;i++)\n\t{\n\t\tscanf(\"%d\",&array[i]);\n\t}\n\td=(array[n-1]-array[0])/(n-1);\n\tt=array[0]+(n*d);\n\tprintf(\"%d\",t);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e146398659be333027a4d18647944755", "src_uid": "d04fa4322a1b300bdf4a56f09681b17f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n#include <stdlib.h>\n\nusing namespace std;\n\nint main()\n{\n    int n;\n    cin>>n;\n\n    int a[n];\n    int i;\n    for(i=1;i<=n;i++)\n    {\n        cin>>a[i];\n    }\n    int sum = abs(a[2]-a[1]),c=0,temp;\n    int x = a[2]-a[1];\n\n    for(i=1;i<=n;i++)\n    {\n         if((abs(a[i]-a[i+1]))==sum)\n         {\n             c++;\n         }\n    }\n    if(c==n-1)\n    {\n        if(0<=a[n])\n        {\n\n            temp = a[n]+x;\n            cout<<temp;\n        }\n        else{\n            temp = a[n]+x;\n            cout<<temp;\n        }\n    }\n    else{\n        cout<<a[n];\n    }\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e2103f94d67bad3a7e8927dea93cc556", "src_uid": "d04fa4322a1b300bdf4a56f09681b17f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <studio.h>\n\nint main() {\n\nint n;\nint diff;\nint noprog=0;\nscanf(\"%d\", &n) ;\n\nint temp1, temp2;\nscanf(\"%d\", &temp1) ;\nscanf(\"%d\", &temp2) ;\ndiff = temp2-temp1;\nint i;\nfor(i=0;i<(n-2);i++){\ntemp1=temp2;\nscanf(\"%d\", &temp2) ;\nif(temp2-temp1!=diff) {\nnoprog=1;\n}\n}\nif(noprog==1) printf(\"%d\", temp2);\nelse printf(\"%d\", temp2+diff) ;\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ded0000b64183a71c633e8a006763b94", "src_uid": "d04fa4322a1b300bdf4a56f09681b17f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main() {\n    int n, tb, i, A[100];\n    FILE *file = fopen (\"td.txt\",\"r\");\n\tfscanf (file,\"%d\",&n);\n\tfor (i=0; i<n; i++) {\n\t\tfscanf (file,\"%d\",&A[i]);\n\t}\n\ttb = A[1] - A[0];\n \tfor (i=2; i<n; i++) {\n \t\tif (tb != A[i] - A[i-1]) tb = 0;\n\t }\n\t printf (\"%d\", A[n-1] + tb);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "75171797d505aa09da88fdc023a854ad", "src_uid": "d04fa4322a1b300bdf4a56f09681b17f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nshort int n,array[n],i,t,d[n-1],m;\n\tscanf(\"%hd\",&n);\n\tfor(i=0;i<=n-1;i++)\n\t{\n\t\tscanf(\"%hd\",&array[i]);\n\t}\n\tm=(array[n-1]-array[0])/(n-1);\n\tfor(i=0;i=n-2;i++)\n\t{\n\t\td[i]=array[i+1]-array[i];\n\t}\n\t\tfor(i=0;i=n-2;i++)\n\t{\n\t\tif(d[i]==d[i+1])\n\t\t{\n\t\t\tt=array[0]+(m*d[0]);\n\t\t}\n\t\telse\n\t\t{\n\t\tt=array[n-1];\n\t\tbreak;\n\t}\n\t}\n\tprintf(\"%hd\",t);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e43efa90f9f5e97851c7233b1cf0eb9d", "src_uid": "d04fa4322a1b300bdf4a56f09681b17f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n\nint main(int argc, char *argv[]) {\n\t\n\tint n, i, j, max = 2010, min = 2100;\n\tscanf(\"%d\", &n);\n\tint a[n];\n\tfor (i = 0; i < n; i++) {\n\t\tscanf(\"%d\", &a[i]);\n\t}\n\t\n\tfor (i = 0; i < n; i++) {\n\t\tif (a[i] > max) {\n\t\t\tmax = a2[i];\n\t\t\t\n\t\t}\n\t\tif (a[i] < min) {\n\t\t\tmin = a[i];\n\t\t}\n\t}\n\t\n\tprintf (\"%d\", (min + max) / 2);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4131b23d820e5ed6044bba312efaa458", "src_uid": "f03773118cca29ff8d5b4281d39e7c63", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>>\nint main(void)\n{\n    int i,j,n,min,dif=0,dif1;\n    scanf(\"%d\",&n);\n    int year[n];\n    for(i=0;i<n;i++)\n        scanf(\"%d\",&year[i]);\n    for(i=0;i<n-1;i++)\n    {\n        min=year[i];\n        for(j=i+1;j<n;j++)\n            min=min<year[j]?min:year[j];\n        for(j=i+1;j<n;j++)\n        {\n            if(min==year[j])\n            {\n                year[j]=year[i];\n                year[i]=min;\n                break;\n            }\n        }\n    }\n    for(i=1;i<n;i++)\n    {\n        dif1=year[i]-year[i-1];\n        if(dif1>dif)\n            dif=dif1;\n    }\n    printf(\"%d\\n\",year[0]+dif);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d5b92eaadf9da66ff2a696e87723460f", "src_uid": "f03773118cca29ff8d5b4281d39e7c63", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main(int argc, char const *argv[])\n{\n\tint n, *a, i, amin = 2100, x = 0;\n\tscanf(\"%d\", &n);\n\ta = (int *) malloc (sizeof(int) * n);\n\n\tfor (i = 0; i < n; i++) {\n\t\tscanf(\"%d\", &a[i]);\n\t}\t\n\n\tif (n < 2) {\n\t\treturn 0;\n\t}\n\t\n\tfor (i = 0; i < n; i++) {\n\t\tif (a[i] < amin)\n\t\t\tamin = a[i];\n\t}\n\n\tfor (i = 1; i < n; i++) {\n\t\tif ((abs(a[i] - a[i-1])) > x)\n\t\t\tx = (abs(a[i] - a[i-1]));\n\t}\n\n\tprintf(\"%d\\n\", amin+x);\n\n\t/* for (i = 0; i < n; i++) {\n\t\tif \n\t} */\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "96f1369f2c755fe8b2857b4b4475cd51", "src_uid": "f03773118cca29ff8d5b4281d39e7c63", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint a[7],b,c,i,d;\n\tscanf(\"%d\",&b);\n\t\n\t\tfor(i=0;i<b;i++)\n\t\t{\n\t\t\n\t\tscanf(\"%d\",&a[i]);\n\t\t\n\t}\n\tfor(d=1;d<b-1;d++)\n\t{\n\t\n\t for(i=0;i<b-1;i++)\n\t{\n\t\tif(a[i]>a[i+1])\n\t\t{\n\t\t\tc=a[i];\n\t\t\ta[i]=a[i+1];\n\t\t\ta[i+1]=c;\t\n\t\t}\n\t}\n}\n\tprintf(\"%d\",a[b/2]);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b39eee06e12f7e9e23c8f42c35e7599e", "src_uid": "f03773118cca29ff8d5b4281d39e7c63", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\nvoid main() \n{\nint x[100],n,i;\n//float mean(int,int[]);\nint median(int,int[]);\n//clrscr();\nscanf(\"%d\",&n);\nfor(i=0;i<n;i++)\n    scanf(\"%d\",&x[i]);\n//printf(\"mean=%f\\n\",mean(n,x));\nprintf(\"%d\\n\",median(n,x));\n//getch();\n}\n\n/*float mean(int m, int a[]) {\n    int sum=0, i;\n    for(i=0; i<m; i++)\n        sum+=a[i];\n    return((float)sum/m);\n}\n*/\n\nint median(int n, int x[]) {\n    int temp;\n    int i, j;\n    // the following two loops sort the array x in ascending order\n    for(i=0; i<n-1; i++) {\n        for(j=i+1; j<n; j++) {\n            if(x[j] < x[i]) {\n                // swap elements\n                temp = x[i];\n                x[i] = x[j];\n                x[j] = temp;\n            }\n        }\n    }\n\n    if(n%2==0) {\n        // if there is an even number of elements, return mean of the two elements in the middle\n        return((x[n/2] + x[n/2 - 1]) / 2.0);\n    } else {\n        // else return the element in the middle\n        return x[n/2];\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1aafb875b90ee76f4a1aaa6703eba202", "src_uid": "f03773118cca29ff8d5b4281d39e7c63", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nusing namespace std;\n\nint main(){\n\tint l,r,x,y;\n\tdouble k;\n\tscanf(\"%d%d%d%d%lf\",&l,&r,&x,&y,&k);\n\t\n\tfor (int i=x;i<=y;i++){\n\t\tdouble tar = i*k;\n\t\tint tari = (int)tar;\n\t\tif (tari-tar==0){\n\t\t\tif (tari<=r&&tari>=l){\n\t\t\t\tprintf(\"YES\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"NO\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "858bcd969cc4ec9dc7cb82f24b84754e", "src_uid": "1110d3671e9f77fd8d66dca6e74d2048", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "r,d=map(int,input().split())\ncount=0\nfor i in range(int(input())):\n    x,y,r1 = map(int,input().split())\n    k = (x*x+y*y)**0.5\n    if (k-r1)>=(r-d) and (k+r1)<=r:\n        count+=1\nprint(count)\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f0bb6bd5c6921112c367bfae52c27994", "src_uid": "1110d3671e9f77fd8d66dca6e74d2048", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int l,r,x,y;\n    float k;\n    scanf(\"%I64d%I64d%I64d%I64d%f\",&l,&r,&x,&y,&k);\n    long long int ans;\n    ans=0;\n    while(x<=y)\n    {\n        j=x*k;\n        if(l<=j && j<=r)\n        {\n            ans=1;\n            break;\n        }\n        x+=1;\n    }\n    if(ans==1){\n        printf(\"YES\");\n    }\n    else{\n        printf(\"NO\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0096816b7056f50cee74b78e19aaa1f7", "src_uid": "1110d3671e9f77fd8d66dca6e74d2048", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n\tint l,r,x,y;\n\tdouble k;\n\tcin>>l>>r>>x>>y>>k;\n\t\n\tfor (int i=x;i<=y;i++){\n\t\tdouble tar = i*k;\n\t\tint tari = (int)tar;\n\t\tif (tari-tar==0){\n\t\t\tif (tari<=r&&tari>=l){\n\t\t\t\tprintf(\"YES\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"NO\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "107c4301f9328bee464dff355f6fdfb1", "src_uid": "1110d3671e9f77fd8d66dca6e74d2048", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void){\n\tlong long int l, r, x, y, k;\n\tscanf(\"%lld%lld%lld%lld%lld\",&l,&r,&x,&y,&k);\n\tlong long int a = 1;\n\ta = x;\n\twhile(1){\n\t\tif(k*a < l || a < x){\n\t\t\ta++;\n\t\t} else{\n\t\t\tbreak;\n\t\t}\n\t}\n\tlong long int flag = 0;\n\twhile(k*a <= r && a <= y){\n\t\tif(k*a <= r && a <= y){\n\t\t\tflag = 1;\n\t\t\tbreak;\n\t\t}\n\t\ta++;\n\t}\n\tif(flag == 1){\n\t\tprintf(\"YES\\n\");\n\t} else{\n\t\tprintf(\"NO\\n\");\n\t}\n\treturn 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "eb4c70b31092d0c6b31968bf17f20ddc", "src_uid": "1110d3671e9f77fd8d66dca6e74d2048", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main(int argc, char *argv[])\n{\n  int n=0,m=0;  \n  scanf(\"%i%i\",&n,&m);\n  int pontos=n*m,jogador=1;\n \n  \n  if(posntos==1){\n  printf(\"Akshat\\n\");\n  }else{\n  while(1){\n  pontos-=2;\n   jogador++;\n  if(pontos==1){\n  printf(\"Akshat\\n\");              \n  break;\n  }else if(pontos<=0){\n  printf(\"Malvika\\n\");  \n  break;    \n        }\n \n  } \n}\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "09c911321107d0391f923adebafba404", "src_uid": "a4b9ce9c9f170a729a97af13e81b5fe4", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nmain()\n{\n    int n,m;\n    scanf(\"%d%d\",&n,&m);\n\n    if(((n==1)||(m==1))||((n%2!=0)&&(m%2!=0))||((n%5==0)&&(m%5==0))||((n==99)&&(m==100))||((n==100)||(m=99)))\n    {\n        printf(\"Akshat\");\n    }\n    else\n    {\n        printf(\"Malvika\");\n    }\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2d9d91dadce625b18321b90cb69c412b", "src_uid": "a4b9ce9c9f170a729a97af13e81b5fe4", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int horizontal,vertical;\n    scanf(\"%d %d\",&horizontal,&vertical);\n    if(horizontal%2==0 && vertical%2==0)\n    {\n        printf(\"Malvika\\n\");\n    }\n     if(horizontal%2==1 && vertical%2==1)\n    {\n        printf(\"Akshat\\n\");\n    }\n     if(horizontal%2==1 && vertical%2==0)\n    {\n        printf(\"Akshat\\n\");1\n    }\n     if(horizontal%2==0 && vertical%2==1)\n    {\n        printf(\"Malvika\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8f0fd9744547cd76978f4a79ae3fcbcc", "src_uid": "a4b9ce9c9f170a729a97af13e81b5fe4", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int i,c=0,j,a[100,100];\n    scanf(\"%d %d\",&n,&m);\n    if(m<n)\n        n=m;\n    puts(n%2?\"AKSHAT\":\"MALVIKA\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4f90b790b160d3f8f6e85e8b9b89ffa8", "src_uid": "a4b9ce9c9f170a729a97af13e81b5fe4", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int a,b;\n    scanf(\"%d%d\",&a,&b);\n    if(a%2==0)\n    {\n        print(\"Malvika\");\n    }\n    else\n    {\n        printf(\"Akshat\");\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d37292e8fc7efeedfed6f4c9492e271f", "src_uid": "a4b9ce9c9f170a729a97af13e81b5fe4", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#define MAX_ARRAY 1500\n\nint main(void)\n{\n\tint num = 0;\n\tint i = 0, j = 0;\n\tint share, remainder;\n\tchar numArr[MAX_ARRAY] = { 0 };\n\n\twhile (j + 1 < 400)\n\t{\n\t\tshare = (j + 1) / 10;\n\t\tremainder = (j + 1) % 10;\n\n\t\tif (share == 0)\n\t\t{\n\t\t\tnumArr[i++] = remainder;\n\t\t}\n\t\telse if (share >= 1 && share <= 9)\n\t\t{\n\t\t\tnumArr[i++] = share;\n\t\t\tnumArr[i++] = remainder;\n\t\t}\n\t\telse if (share >= 10)\n\t\t{\n\t\t\tnumArr[i++] = share / 10;\n\t\t\tnumArr[i++] = share % 10;\n\t\t\tnumArr[i++] = remainder;\n\t\t}\n\t\tj++;\n\t}\n\n\twhile (1)\n\t{\n\t\tprintf(\"input : \");\n\t\tscanf_s(\"%d\", &num);\n\t\t\n\t\tif (num >= 1 && num <= 1000)\n\t\t{\n\t\t\tprintf(\"%d \\n\", numArr[num - 1]);\n\t\t\tbreak;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tprintf(\"\ufffd\ufffd\ufffd\u0537\ufffd! (range : 1 ~ 1000) \\n\");\n\t\t\tcontinue;\n\t\t}\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "754c0938a894b6ff78f920cd2a8a76c5", "src_uid": "2d46e34839261eda822f0c23c6e19121", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    char s[]=\"123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172737475767778798081828384858687888990919293949596979899100101102103104105106107108109110111112113114115116117118119120121122123124125126127128129130131132133134135136137138139140141142143144145146147148149150151152153154155156157158159160161162163164165166167168169170171172173174175176177178179180181182183184185186187188189190191192193194195196197198199200201202203204205206207208209210211212213214215216217218219220221222223224225226227228229230231232233234235236237238239240241242243244245246247248249250251252253254255256257258259260261262263264265266267268269270271272273274275276277278279280281282283284285286287288289290291292293294295296297298299300301302303304305306307308309310311312313314315316317318319320321322323324325326327328329330331332333334335336337338339340341342343344345346347348349350351352353354355356357358359360361362363364365366367368369370371372373374375376377378379380381382383384385386387388389390391392393394395396397398399400\";\n    int n;\n    scanf(\"%d\",&n);\n    printf(\"%c\",s[n])\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "91d8296664b24164b4c947851c76656c", "src_uid": "2d46e34839261eda822f0c23c6e19121", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#define MAX_ARRAY 1500\n\nint main(void)\n{\n\tint num = 0;\n\tint i = 0, j = 0;\n\tint share, remainder;\n\tchar numArr[MAX_ARRAY] = { 0 };\n\n\twhile (j + 1 < 400)\n\t{\n\t\tshare = (j + 1) / 10;\n\t\tremainder = (j + 1) % 10;\n\n\t\tif (share == 0)\n\t\t{\n\t\t\tnumArr[i++] = remainder;\n\t\t}\n\t\telse if (share >= 1 && share <= 9)\n\t\t{\n\t\t\tnumArr[i++] = share;\n\t\t\tnumArr[i++] = remainder;\n\t\t}\n\t\telse if (share >= 10)\n\t\t{\n\t\t\tnumArr[i++] = share / 10;\n\t\t\tnumArr[i++] = share % 10;\n\t\t\tnumArr[i++] = remainder;\n\t\t}\n\t\tj++;\n\t}\n\n\twhile (1)\n\t{\n\t\tprintf(\"input : \");\n\t\tscanf_s(\"%d\", &num);\n\t\t\n\t\tif (num >= 1 && num <= 1000)\n\t\t{\n\t\t\tprintf(\"%d \\n\", numArr[num - 1]);\n\t\t\tbreak;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tprintf(\"! (range : 1 ~ 1000) \\n\");\n\t\t\tcontinue;\n\t\t}\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "04b7800722bbab4f59a41340a9c376f2", "src_uid": "2d46e34839261eda822f0c23c6e19121", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n    int n,i;\n    char a[10000];\n    a[0]='1';\n    for(i=2;i<1000,i++)  sprintf(a,\"%s%d\",a,i);\n    scanf(\"%d\",&n);\n    printf(\"%c\",a[n-1]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d02f0ad3b81a776e36a5c44e36515198", "src_uid": "2d46e34839261eda822f0c23c6e19121", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <cstdio>\n\nint a[1010],k;\n\nint main(){\n    int i,k=10,x;\n    scanf(\"%d\",&x);\n    for (i=1;i<=9;i++)\n        a[i]=i;\n    for (i=10;i<100;i++){\n        a[k]=i/10;\n        k++;\n        a[k]=i%10;\n        k++;\n    }\n    for (i=100;i<371;i++){\n        a[k]=i/100;\n        k++;\n        a[k]=(i/10)%10;\n        k++;\n        a[k]=i%10;\n        k++;\n    }\n    printf(\"%d\",a[x]);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c6903cf2a8705f4486dc1db8be70297f", "src_uid": "2d46e34839261eda822f0c23c6e19121", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "printf(\"\");", "lang_cluster": "C", "compilation_error": true, "code_uid": "9854bb5f39d175c4f321ad863c19480d", "src_uid": "b6a30a725754a4b4daeb6e87986e28a4", "difficulty": null}
{"lang": "GNU C11", "source_code": "\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2f043008f31a98c1deb326cd137136ce", "src_uid": "b6a30a725754a4b4daeb6e87986e28a4", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n    pritnf(\"NO\");\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7e4ba8cc235e74562ad8a17240a34749", "src_uid": "b6a30a725754a4b4daeb6e87986e28a4", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n\n\tprintf(\"No\\n\")\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "48b2e1bc8f1bbcb95a6e7a9e921c5ae8", "src_uid": "b6a30a725754a4b4daeb6e87986e28a4", "difficulty": null}
{"lang": "GNU C11", "source_code": "\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "78fbf91bc4e1b977dc837c88758dbe3a", "src_uid": "b6a30a725754a4b4daeb6e87986e28a4", "difficulty": null}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define maxn 1000000005\nint bit[maxn];\nint main()\n{\n    int w,m,b=0,i,f=0;\n    scanf(\"%d%d\",&w,&m);\n    while (m)\n    {\n        bit[b++]=m%w;\n        m/=w;\n    }\n    for (i=0;i<b;i++)\n    {\n        if (bit[i]>=w)\n        {\n            bit[i]-=w;\n            bit[i+1]++;\n        }\n        if (bit[i]==w-1)\n        {\n            bit[i]=0;\n            bit[i+1]++;\n        }\n        if (bit[i]>1)\n        {\n            f=1;\n            break;\n        }\n    }\n    if (f==0) printf(\"YES\");\n    else printf(\"NO\");\n    return 0;\n}\n\n  \t \t \t \t \t\t\t\t\t\t \t\t\t \t\t  \t\t\t  \t", "lang_cluster": "C", "compilation_error": true, "code_uid": "ce775c6145f91e2a049bf277c753a470", "src_uid": "a74adcf0314692f8ac95f54d165d9582", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define maxn 1000000005\nlong long bit[maxn];\nint main()\n{\n    int w,m,b=0,i,f=0;\n    scanf(\"%d%d\",&w,&m);\n    while (m)\n    {\n        bit[b++]=m%w;\n        m/=w;\n    }\n    for (i=0;i<b;i++)\n    {\n        if (bit[i]>=w)\n        {\n            bit[i]-=w;\n            bit[i+1]++;\n        }\n        if (bit[i]==w-1)\n        {\n            bit[i]=0;\n            bit[i+1]++;\n        }\n        if (bit[i]>1)\n        {\n            f=1;\n            break;\n        }\n    }\n    if (f==0) printf(\"YES\");\n    else printf(\"NO\");\n    return 0;\n}\n\n\t\t\t\t\t\t\t\t\t     \t\t\t\t\t\t \t\t\t\t\t", "lang_cluster": "C", "compilation_error": true, "code_uid": "4199508e0843fe948ef439fc910bcce4", "src_uid": "a74adcf0314692f8ac95f54d165d9582", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(){\n\tint m,w;\n\tscanf(\"%d %d\",&w,&m);\n\twhile(m>0){\n\t\tif(m%w==0||m%w==1||m%w=w-1){\n\t\t\tm=m/w;\n\t\t}\n\t\telse{\n\t\t\tprintf(\"NO\");\n\t\t\treturn 0;\n\t\t}\n\t\t}\n\t\tprintf(\"YES\");\n\t\treturn 0;\n\t}", "lang_cluster": "C", "compilation_error": true, "code_uid": "eb1dfb0113178503a60e6ded09c981e4", "src_uid": "a74adcf0314692f8ac95f54d165d9582", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n\nusing namespace std;\n\nbool getans(long long w,long long m){\n\tlong long current = m;\n\tlong long remain = 0;\n\tlong long bit = 0;\n\twhile(current){\n\t\tremain = current % w;\n\t\tcurrent = current / w;\n\t\tif(remain==1||remain==0)\n\t\t\tcontinue;\n\t\tif(remain==w-1)\n\t\t\tcurrent++;\n\t\telse return false;\n\t}\n\treturn true;\n}\n\nint main()\n{\n\tlong long w,m;\n\tcin>>w>>m;\n\tif(getans(w,m)) \n\t\tcout <<\"YES\"<<endl;\n\telse cout<<\"NO\"<<endl;\n}\n \t      \t \t  \t   \t \t\t     \t   \t", "lang_cluster": "C", "compilation_error": true, "code_uid": "e97e0f9e50c7d391ad55505dd3a2ec93", "src_uid": "a74adcf0314692f8ac95f54d165d9582", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(void)\n{\n\tlong long w,m;\n\tscanf(\"%I64d%I64d\",&w,&m);\n\twhile (m>0)\n\t{\n\t\tif (m%w==w-1) m++;\n\t\tif (m%w>1)\n\t\t{\n\t\t\tprintf(\"NO\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\tm/=w;\n\t}\n\tprintf(\"YES\\n\");\n\treturn 0;\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "151f593985bd244bb632f56a80ccfb75", "src_uid": "a74adcf0314692f8ac95f54d165d9582", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(void)\n{\n\tint n;\n\tint str[100];\n\tint i;\n\tint check_yes; // yes \ub5b4\ub294\uc9c0 \uccb4\ud06c \n\tint check_blank; // \ube48\uce78\uc778\uc9c0 \uccb4\ud06c \n\tint check_cont; // \uc5f0\uc18d 2\uac1c \uc774\uc0c1\uc778\uc9c0  \uccb4\ud06c \n\tint check_test0;\n\t\n\tcheck_yes = 0;\n\tcheck_blank = 0;\n\tcheck_test0 = 0;\n\t\n\tscanf(\"%d\", &n);\n\tscanf(\"%s\", str);\n\t\n\t//test 0: \uadf8\ub0e5 \uc548 \ub418\ub294 \uacbd\uc6b0 (ex: ??CCY)\n\t\n\tfor(i = 0; i < n-1; i++)\n\t{\n\t\tif(str[i] != '?' && str[i] == str[i+1])\n\t\t{\n\t\t\tprintf(\"No\");\n\t\t\tcheck_test0 = 1;\n\t\t\tbreak;\n\t\t}`````````````\n\t}\n\t\n\tprintf(\"%d\", check_test0);\n\t\n\tif(check_test0 == 0)\n\t{\n\t\t//test 1: \uc2dc\uc791\uacfc \ub05d\uc744 \ubcf4\uc790\n\t\tif(str[0] == '?' || str[n-1] == 0)\n\t\t{\n\t\t\tprintf(\"Yes\");\n\t\t\tcheck_yes = 1;\n\t\t} \n\t\telse\n\t\t{\n\t\t\t//test 2: ?\uac00 2\ubc88\uc774\uc0c1 \uc5f0\uc18d\ub418\ub294\uc9c0 \uccb4\ud06c \n\t\t\tfor( i = 0; i < n; i++)\n\t\t\t{\n\t\t\t\tif(str[i] == '?')\n\t\t\t\t{\n\t\t\t\t\tcheck_blank++;\n\t\t\t\t\tif(check_blank == 2)\n\t\t\t\t\t{\n\t\t\t\t\t\tprintf(\"Yes\");\n\t\t\t\t\t\tcheck_yes = 1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tcheck_blank = 0;\n\t\t\t\t}\n\t\t\t}\n\t\t\t//test 3: A?A \uaf34 \uccb4\ud06c \n\t\t\tif(check_yes == 0)\n\t\t\t{\n\t\t\t\tfor( i = 1; i < n-1; i++)\n\t\t\t\t{\n\t\t\t\t\tif(str[i] == '?' && str[i-1] == str[i+1])\n\t\t\t\t\t{\n\t\t\t\t\t\tprintf(\"Yes\");\n\t\t\t\t\t\tcheck_yes = 1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t} \n\t\t}\n\t\t\n\t\tif(check_yes == 0)\n\t\t{\n\t\t\tprintf(\"No\");\n\t\t}\t\t\n\t}\n\t\n\treturn 0;\t\t\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "224403c58af6d43bc14d594d16713f9b", "src_uid": "f8adfa0dde7ac1363f269dbdf00212c3", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(void)\n{\n    int n,i,res=1,s,e,ck=1;\n    char x[150],sc,ec;\n    scanf(\"%d\",&n);\n    getchar();\n    fgets(x,150,stdin);\n    for(i=0; i<n; i++)\n    {\n\n        if(i!=0)\n        {\n            if(x[i-1]==x[i] && x[i]!='?')\n            {\n                res = 5;\n                ck=3;\n            }\n            if(i!=n-1 && x[i]=='?')\n            {\n                if(x[i]=='?' && x[i-1]!='?' && x[i+1]!='?' && x[i-1]!=x[i+1] && ck==1)\n                {\n                    res=5;\n                }\n                else if(ck!=3)\n                {\n                    res=2;\n                    ck=2;\n                }\n            }\n\n\n        }\n    }\n    if()\n    if(res==2 || res==1)  printf(\"Yes\\n\");\n    else if(res==5)  printf(\"No\\n\");\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "be3ba6631f9578a017289af9724ec2b9", "src_uid": "f8adfa0dde7ac1363f269dbdf00212c3", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(){\n    int n,i=0,count=0;\n    scanf(\"%d\",&n);\n    char co[n];\n    int flag=0,flag1=1;\n    scanf(\"%s\",&co[0]);\n    for(i=0;i<n-1;i++)\n    {\n        if((co[i]==co[i+1])&(co[i]!='?')){\n            flag1=0;\n            break;\n        }\n    }\n    if(n==1){\n        if(co[0]=='?')\n            flag=1;\n    }\n    if(flag1==1){\n    for(i=0;i<n-1;i++)\n    {\n        if((co[0]=='?')|(co[n-1]=='?')){\n            flag=1;\n            break;\n        }\n        if((count==0)&(co[i]=='?')){\n            if(co[i+1]!='?')\n                if((co[i-1])==(co[i+1])){\n                    flag=1;\n                    break;\n                }\n                else{\n                    count=0;\n                    i++;\n                    continue;\n                }\n            else\n                count=1;\n        }\n        if((count==1)&(co[i]=='?')){\n            flag=1;\n            break;\n        }\n    }\n        \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "02e4a12beecfe7690cc552751869a8fe", "src_uid": "f8adfa0dde7ac1363f269dbdf00212c3", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "/*Problem 957A Tritonic Iridescence*/\n#include <stdio.h>\nint main()\n{\n    int i, n;\n    char string[100];\n\n    scanf(\"%d\", &n);\n    scanf(\"%s\", string);\n\n    for (i = 0; i < n; i++)\n        if (string[i] == string[i + 1] && string[i] != '?')\n        {\n            print(\"No\");\n            return 0;\n        }\n\n    for (i = 1; i < n - 1; i++)\n    {\n        if (string[i] == '?' && (string[i - 1] == string[i + 1] || string[i + 1] == '?'))\n        {\n            printf(\"Yes\");\n            return 0;\n        }\n    }\n    if (string[0] == '?' || string[n - 1] == '?')\n    {\n        printf(\"Yes\");\n        return 0;\n    }\n\n    printf(\"No\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a49d9f5a34b8dc13984f8aac71a11561", "src_uid": "f8adfa0dde7ac1363f269dbdf00212c3", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\nint main()\n{\n    long long int i,j,k=0,n;\n    char ch[100000],cp='k';\n    scanf(\"%I64d\",&n);\n    gets(ch)\n    for(i=0;i<n;i++){\n       // scanf(\"%c\",&ch);\n        if(cp==ch[i] && ch[i!='?')\n        {\n            printf(\"No\\n\");\n            return 0;\n        }\n\n        else\n            cp=ch[i];\n        if(ch[i]=='?')\n            k=1;\n    }\n    if(k==1)\n        printf(\"Yes\\n\");\n    else\n        printf(\"No\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e1381f55f567ab68266214a6b140fb7a", "src_uid": "f8adfa0dde7ac1363f269dbdf00212c3", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n     int n,r[100],b[100],i,ct1,ct2,ct3,ct4,ct5,r,s,c;\n     scanf(\"%d\",&n);\n     for(i=0;i<n;i++)\n     {\n          scanf(\"%d\",&r[i]);\n     }\n     for(i=0;i<n;i++)\n     {\n          scanf(\"%d\",&b[i]);\n     }\n     ct1=0;\n     ct2=0;\n     for(i=0;i<n;i++)\n     {\n          if(r[i]==1)\n          {\n               ct1++;\n          }\n          else if(r[i]==0)\n          {\n               ct2++;\n          }\n     }\n     ct3=0;\n     ct4=0;\n     for(i=0;i<n;i++)\n     {\n          if(b[i]==1)\n          {\n               ct3++;\n          }\n          else if(b[i]==0)\n          {\n               ct4++;\n          }\n          \n     }\n     if((ct1==n && ct3==n) || (ct2==n && ct4==n))\n     {\n          printf(\"-1\");\n          \n     }\n     else \n     {\n          ct5=0;\n          for(i=0;i<n;i++)\n          {\n               if(r[i]==1 && b[i]==0 )\n               {\n                    ct5++;\n               }\n               \n          }\n          if(ct5==0)\n          {\n               printf(\"-1\");\n          }\n          else \n          {\n               c=ct3-ct1;\n               r=c/ct5;\n               s=c%ct5;\n               if(s==0)\n               {\n                    printf(\"%d\",r);\n               }\n               else\n               {\n                    printf(\"%d\",r+1);\n               }\n               \n          }\n     }\n     return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "23ed792965f2702bc2d76710c09f59e7", "src_uid": "b62338bff0cbb4df4e5e27e1a3ffaa07", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n  int i,j,n,count=0,factor=0,equal=0;\n\n  scanf(\"%d\",&n);\n \n  int b[n],c[n];\n  for(i=1;i<=n;i++)\n  {\n      scanf(\"%d\",&b[i]);\n  }\n  printf(\"\\n\");\n  for(i=1;i<=n;i++)\n  {\n      scanf(\"%d\",&c[i]);\n  }1\n\n  for(i=1;i<=n;i++)\n  {\n    if(b[i]<c[i])\n      count++;\n    else\n    {\n      if(b[i]>c[i])\n        factor++;\n    }\n  }\n\n  for(i=1;i<=n;i++)\n  {\n    if(b[i]==c[i])\n      equal++;\n  }\n\n  if(equal==n)\n  {\n    printf(\"%d\",-1);\n  }\n  else\n  {\n    if(factor!=0)\n      printf(\"%d\",(int)(count/factor)+1);\n    else\n    {\n      printf(\"%d\",1);\n    }\n  }\n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2dd8358a1d0857dc833fa168b1ebdf02", "src_uid": "b62338bff0cbb4df4e5e27e1a3ffaa07", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n \n \n \nint main()\n{\n    int T;\n    scanf(\"%d\",&T);\n    int a[T];\n    int b[T];\n    int i;\n    for(i=0;i<T;i++){\n        scanf(\"%d\",&a[i]);\n    }\n    for(i=0;i<T;i++){\n        scanf(\"%d\",&b[i]);\n    }\n    int  a_win=0;\n    int b_win=0;\n \n    for(i=0;i<T;i++){\n         if(a[i]==1&&b[i]==0){\n            a_win++;\n         }\n         if(a[i]==0&&b[i]==1){\n            b_win++;\n         }\n    }\n \n    if(a_win==0){\n        printf(\"-1\\n\");\n    }\n    else{\n        int t=1;\n        while(1){\n            if(t*a_wins>b_wins)\n               break;\n            t++;\n        }\n\n\n        printf(\"%d\\n\",t);\n    }\n \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dac0ad8d7ea9cf64691ab999b4099cae", "src_uid": "b62338bff0cbb4df4e5e27e1a3ffaa07", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n  int i,j,n,count=0,factor=0,equal=0;\n\n  scanf(\"%d\",&n);\n \n  int b[n],c[n];\n  for(i=1;i<=n;i++)\n  {\n      scanf(\"%d\",&b[i]);\n  }\n  printf(\"\\n\");\n  for(i=1;i<=n;i++)\n  {\n      scanf(\"%d\",&c[i]);\n  }1\n\n  for(i=1;i<=n;i++)\n  {\n    if(b[i]<c[i])\n      count++;\n    else\n    {\n      if(b[i]>c[i])\n        factor++;\n    }\n  }\n\n  for(i=1;i<=n;i++)\n  {\n    if(b[i]==c[i])\n      equal++;\n  }\n\n  if(equal==n)\n  {\n    printf(\"%d\",-1);\n  }\n  else\n  {\n    if(factor!=0)\n      printf(\"%d\",(int)(count/factor)+1);\n    else\n    {\n      printf(\"%d\",-1);\n    }\n  }\n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2eb39d9b5d7d4b7cec50b7869fdfdfa0", "src_uid": "b62338bff0cbb4df4e5e27e1a3ffaa07", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int i,n,count=0,factor=0,equal=0;\n    \n    scanf(\"%d\",&n);\n    \n    int b[n],c[n];\n    \n    for(i=1;i<=n;i++)\n    {\n        scanf(\"%d\",&b[i]);\n    }\n    printf(\"\\n\");\n    \n      \n    for(i=1;i<=n;i++)\n    {\n        scanf(\"%d\",&c[i]);\n    }\n    \n    for(i=1;i<=n;i++)\n    {\n        if(b[i]<c[i])\n            count++;\n        else\n        {\n            if(b[i]>c[i])\n                factor++;\n        }\n    }\n    \n    for(i=1;i<=n;i++)\n    {\n        if(b[i]==c[i])\n            equal++;\n    }\n    \n    if(equal==n)\n    {\n        printf(\"%d\",-1);\n    }\n    else\n    {\n        if(factor!=0)\n            printf(\"%d\", (int)(count/factor)+1)\n    }\n    \n    return 0;\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5d5427341724b1f4d86029e25fa93e76", "src_uid": "b62338bff0cbb4df4e5e27e1a3ffaa07", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <iostream.h>\nint main(){\n    int n,ans=0,temp,i;\n    scanf(\"%d\",&n);\n    i=0;\n    while(n>0){\n        temp=n%10;\n        temp=(temp==4)?1:2;\n        ans+=(temp*(1<<i));\n        n=n/10;\n        i++;\n    }\n    printf(\"%d\\n\",ans);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e154d4042ea2035f6f5329008e090693", "src_uid": "6a10bfe8b3da9c11167e136b3c6fb2a3", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main(){\n    long long int n,ans=0,temp,i;\n    cin >> n;\n    i=0;\n    while(n>0){\n        temp=n%10;\n        temp=(temp==4)?1:2;\n        ans+=(temp*(1<<i));\n        n=n/10;\n        i++;\n    }\n    printf(\"%lld\\n\",ans);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2028b8672747dc729cd9f3b20fd6228b", "src_uid": "6a10bfe8b3da9c11167e136b3c6fb2a3", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n#include <string.h>\n\nint main(void)\n{\nint i;\nint n; scanf(\"%d\",&n);\nint happy;\nint count1=0\nint count2=0;\nint tmp;\nint sum;\n\ncount1++;\n\nhappy=n;\n\nwhile(happy>0)\n{\n\ttmp=happy%10;\n\thappy=happy/10;\n\tcount1++;\n}\n\nhappy=n;\n\nwhile(happy>0)\n{\n\ttmp=happy%10;\n\thappy=happy/10;\n\tcount2++;\n\tif(tmp==7)\n\t\tbreak;\n}\n\nfor(i=0;i<count1-count2;i++)\nsum=sum*2;\n\n\n\nprintf(\"%d\",sum);\n\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9d0da9049535d8d96cca56b21c657b8e", "src_uid": "6a10bfe8b3da9c11167e136b3c6fb2a3", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<math.h>\nvoid main(){\n    \n    char p[20];\n    scanf(\"%s\",p);\n    int ans = 1;\n    int len = strlen(p)\n    for(int i=0;i<len;i++){\n        if(p[len-i-1]=='7')\n            ans+=pow(2,i)\n    }\n    ans+=2*(pow(2,len-1)-1)\n    printf(\"%d\",ans)\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "239cce9e1f8bc6746f8ebfb7f6122c87", "src_uid": "6a10bfe8b3da9c11167e136b3c6fb2a3", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\nint main(){\n    long long int n,ans=0,temp,i;\n    cin >> n;\n    i=0;\n    while(n>0){\n        temp=n%10;\n        temp=(temp==4)?1:2;\n        ans+=(temp*(1<<i));\n        n=n/10;\n        i++;\n    }\n    cout << ans << endl;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7b8ec5f5d570c6f6173ac24c1e1d90dd", "src_uid": "6a10bfe8b3da9c11167e136b3c6fb2a3", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint main(){\n\tint w, h, k;\n\tcin >>w>> h>>k;\n\t\n\tint ans= 0;\n\tfor(inst i=1 ; i<=k; i++){\n\tans=ans +(w+h) *2-4;\n\t\n\t}\n\n\tcount<<ans;\n\treturn 0;\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d2828376e417ae374412d5c8abdd4a8b", "src_uid": "2c98d59917337cb321d76f72a1b3c057", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nmain()\n{\n    int w,h,k,i,s=0;\n    scanf(\"%d%d%d\"&w,&h,&k);\n    for(i=1;i<=k;i++)\n    {\n        s=2*w+2*w-4;\n        w=w-2,h=h-2;\n    }\n    printf(\"%d\",s);\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e98ee08f990dee7b150ea28a89dc5bfb", "src_uid": "2c98d59917337cb321d76f72a1b3c057", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int w,h,k,i;\n    scanf(\"%d%d%d\",&w,&h,&k);\n    \n    for(i=1;i<=k;i++)\n    {\n       if(w>h)\n       printf(\"%d\",(h\u22124(i\u22121))*2+((w\u22124(i\u22121))-2)*2);\n       else \n       printf(\"%d\",((h\u22124(i\u22121))-2)*2+(w\u22124(i\u22121))*2);\n      \n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c2149265b69e3c5ee7a1dca296ea8b29", "src_uid": "2c98d59917337cb321d76f72a1b3c057", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint n,m,k;\nint main(){\n\tscanf(\"%d%d%d\",&n,&m,&k);\n\tint sum=0;\n\twhile(k--){\n\t\tsum+=(n*2+(m-2)*2);\n\t\tn-=4,m-=4;\n\t}\n\tprintf(\"%d\\n\",sum);\n} ", "lang_cluster": "C", "compilation_error": true, "code_uid": "63ad5edc55aa72054bf1a45a3c989cc6", "src_uid": "2c98d59917337cb321d76f72a1b3c057", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int w,h,k,i;\n    scanf(\"%d%d%d\",&w,&h,&k);\n    \n    for(i=1;i<=k;i++)\n    {\n       if(w>h)\n       printf(\"%d\",(h\u22124*(i\u22121))*2+((w\u22124*(i\u22121))-2)*2);\n       else \n       printf(\"%d\",((h\u22124*(i\u22121))-2)*2+(w\u22124*(i\u22121))*2);\n      \n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "311a50538bfaca2b9ac39ead8ad54492", "src_uid": "2c98d59917337cb321d76f72a1b3c057", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\nusing namespace std;\n\nint main()\n{\n    int n,a,x,b,y,k;\n    cin>>n>>a>>x>>b>>y;\n    while(a!=x||b!=y)\n    {\n        if(a!=x)\n        {\n            if(a==n)\n                a=0;\n            a++;\n        }\n        else\n            k=0;\n\n        if(b!=y)\n        {\n            if(b==1)\n                b=n+1;\n            b--;\n        }\n        else\n            k=0;\n\n        if(a==b)\n        {\n            k=1;\n            break;\n        }\n    }\n    if(k==1)\n        cout<<\"YES\"<<endl;\n    else\n        cout<<\"NO\"<<endl;\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "69dd36423c2d08fe2b754f6212d05b1a", "src_uid": "5b889751f82c9f32f223cdee0c0095e4", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define MIN(A,B) ((A)<(B))?(A):(B)\nint main()\n{\n    int a1[150]={0},b1[150]={0};\n    int a,x,b,y,n,i,k,j;\n    scanf(\"%d %d %d %d %d\",&n,&a,&x,&b,&y);\n    for(i=a,k=0;i!=x;i++,k++)\n    {\n        a1[k]=i;\n        if(i==n)\n           i=0;\n    }\n    for(i=b,j=0;i!=y;i--,j++)\n    {\n        b1[j]=i;\n        if(i==1)\n           i=n+1;\n    }\n    k=MIN(k,j);\n    for(i=0,n=0;i<=k;k++)\n    {\n        if(a[i]==b[i])\n           n=1;\n    }\n    if(n)\n       printf(\"YES\\n\");\n    else\n       printf(\"NO\\n\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9e1b359f9be19be5912feaaac7fde817", "src_uid": "5b889751f82c9f32f223cdee0c0095e4", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n,a,x,b,y,flag=0;\n    scanf(\"%d%d%d%d%d\",&n,&a,&x,&b,&y);\n    a--;x--;b--;y--;\n\n    while (true) {\n    if (a == b) {\n      printf(\"YES\\n\");\n      return 0;\n    }\n    if (a == x || b == y) {\n      break;\n    }\n    a = (a + 1) % n;\n    b = (b - 1 + n) % n;\n  }\n  printf(\"NO\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1a2f302536e77d64a005e815394137d2", "src_uid": "5b889751f82c9f32f223cdee0c0095e4", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint a,x,b,y,n;\n\tscanf(\"%d %d %d %d %d\",&n,&a,&x,&b,&y);\n\tif(a==n+1)\n\ta=1;\n\tif(b==0)\n\tb=n;\n\ta=a+1;b=b-1\n\tif(a==b)\n\t{\n\tprintf(\"yes\");\nreturn 0;\n\t}\n\n\t\n\tprintf(\"no\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "41bd61d04a1af1cd22e02ac3837fafb2", "src_uid": "5b889751f82c9f32f223cdee0c0095e4", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "# include <stdio.h>\nint main()\n{\n\tint n,a,b,x,y,i,j=0;\n\tscanf(\"%d%d%d%d%d\",&n,&a,&x,&b,&y);\n\tif(a==b)\n\t\t{\n\t\t\tprintf(\"YES\");\n\t\t\tj=1;\n\t\t\tbreak;\n\t\t}\n\t\telse\n\t\t{\n\twhile(a!=x||b!=y)\n\t{\n\t\tif(a!=x)\n\t\t{\n\t\t\tif(a!=n)\n\t\t\ta++;\n\t\t\telse\n\t\t\ta=1;\n\t\t}\n\t\tif(b!=y)\n\t\t{\n\t\t\tif(b!=1)\n\t\t\tb--;\n\t\t\telse\n\t\t\tb=n;\n\t\t}\n\t\tif(a==b)\n\t\t{\n\t\t\tprintf(\"YES\");\n\t\t\tj=1;\n\t\t}\n\t}\n\t\t}\n\tif(j==0)\n\tprintf(\"NO\");\n\t\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1bcb65494bae1e26f894b9d92131f7a7", "src_uid": "5b889751f82c9f32f223cdee0c0095e4", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\n    using namespace std;\n    int main()\n        {\n            int n,a,b;\n            cin>>n>>a>>b;\n            if(b<n&&b>=0)\n                {\n                    cout<<b+a;\n                }\n            if(b>n)\n                {\n                    cout<<((a+b)%n)+(a+b)/n;\n                }\n            if(b<0)\n                {\n                    b=-(b);\n                    cout<<n-b+1;\n                }\n\n            return 0;\n        }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "19614c6e65919a2463b612f1d0a25daf", "src_uid": "cd0e90042a6aca647465f1d51e6dffc4", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint a,b,n,x;\nscanf(\"%d%d%d\",&n,&a,&b);\nif(b<0 && n*a<(-b))\nx=(n+a-b)%;n;\n{\nif(x==0)\nprintf(\"%d\",n);\nelse\nprintf(\"%d\",x);\n}\nelse\nx=(n+a+b)%n;\n{     \nif(x==0)\nprintf(\"%d\",n);\nelse\nprintf(\"%d\",x);\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "07cd523c08954e7b2526ebda0b1f3e07", "src_uid": "cd0e90042a6aca647465f1d51e6dffc4", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(int n,int x,int y)\n{\ns=(x+y)%n;\nif(s<=0) s=s+n;\nprintf(\"%d\",s);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c87fca3d1d98eb4c875f5dd971f8e19f", "src_uid": "cd0e90042a6aca647465f1d51e6dffc4", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint a,b,n,x;\nscanf(\"%d%d%d\",&n,&a,&b);\nif(b<0 && n*a<(-b))\nx=(n+a-b)%n;\n{\nif(x==0)\nprintf(\"%d\",n);\nelse\nprintf(\"%d\",x);\n}\nelse\nx=(n+a+b)%n;\n{     \nif(x==0)\nprintf(\"%d\",n);\nelse\nprintf(\"%d\",x);\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c621863974d3fb85504e07d72a66846a", "src_uid": "cd0e90042a6aca647465f1d51e6dffc4", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <algorithm> \nusing namespace std;\nint n,a,b,ans;\nvoid step()\n{\n    ans=a;//\u521d\u59cb\u4e3a\u7b2ca\u4e2a\u95e8\n    if(b<0)//b\u5c0f\u4e8e0\u65f6{\n        while(1){\n            ans--;//\u5012\u9000\uff0c\u95e8\u7684\u7f16\u53f7\u51cf\u5c0f\n            b++;\n            if(ans<1){//\u5982\u679c\u8d70\u8fc7\u4e861\u53f7\u95e8\n                ans=n;//\u7f16\u53f7\u53d8\u4e3an\n            }\n            if(b==0){//\u5982\u679c\u8d70\u5b8c\u4e86\n                return ;\n            }\n        }\n    }\n    if(b>0){//\u5927\u4e8e0\u65f6\n        while(1){\n            ans++;//\u524d\u8fdb\uff0c\u95e8\u7684\u7f16\u53f7\u589e\u52a0\n            b--;\n            if(ans>n){//\u5982\u679c\u8d70\u8fc7\u4e86n\u53f7\u95e8\n                ans=1;//\u7f16\u53f7\u53d8\u4e3a1\n            }\n            if(b==0){//\u5982\u679c\u8d70\u5b8c\u4e86\n                return ;\n            }\n        }\n    }\n    return ;\n}\nint main(){\n    scanf(\"%d%d%d\",&n,&a,&b);\n    step();\n    printf(\"%d\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3f0937411e3c937bff516a20c71c5029", "src_uid": "cd0e90042a6aca647465f1d51e6dffc4", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "include<stdio.h>\ninclude<math.h>\nint main()\n{\n    int a,b,c;\n    scanf(\"%d %d %d\",&a,&b,&c);\n    d=(int)sqrt(a*b*c);\n    int N=4*(d/a+d/b+d/c);\n    printf(\"%d\",N);\n    return 0;\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "73f4121632e39b6c4b6ca8b622a92a8a", "src_uid": "c0a3290be3b87f3a232ec19d4639fefc", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n{\n    int main()\n    {\n        int a,b,c,l,w,h;\n        l=4*sqrt(c/(a*b));\n        w=sqrt((a*b)/c);\n        h=w*(c/a);\n        printf(\"%d\", 4*(l+w+h));\n        return 0;\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ff1a0966a354f0e7dfc89b60afcde07b", "src_uid": "c0a3290be3b87f3a232ec19d4639fefc", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n\nint main(){\n    int x,y,z,a,b,c;\n    scanf(\"%d %d %d\",&x,&y,&z);\n    c=(int)xy/z;\n    b=(int)xz/y;\n    a=(int)yz/x;\n    printf(\"%d\",(a+b+c)*4);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "46fde06b143b13b2ea42611ed0606d73", "src_uid": "c0a3290be3b87f3a232ec19d4639fefc", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n{\n    int main()\n    {\n        int a,b,c,l,w,h;\n        scanf(\"%d%d%d\",&a,&b,&c);\n        l=4*sqrt(c/(a*b));\n        w=sqrt((a*b)/c);\n        h=w*(c/a);\n        printf(\"%d\", 4*(l+w+h));\n        return 0;\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "495b9ea3aee70f5fcc67a42a901025f7", "src_uid": "c0a3290be3b87f3a232ec19d4639fefc", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int a,b,c,m,i,p=0;\n    scanf(\"%d%d%d\",&a,&b,&c);\n    m=(a>b && a>c)?a:(b>a && b>c)?b:c;\n    for (i=1;i<=m;i++)\n        if (a%i==0 && b%i==0 && (a/i)*(b/i)==c)\n        {    \n            p+=i;\n            break;\n        }\n    for (i=1;i<=m;i++)\n        if (b%i==0 && c%i==0 && (b/i)*(c/i)==a)\n        {    \n            p+=i;\n            break;\n        }\n    for (i=1;i<=m;i++)\n        if (a%i==0 && c%i==0 && (a/i)*(c/i)==b)\n        {    \n            p+=i;\n            break;\n        }\n    printf(\"%d\",p*4);\n    if (a==2239 && b=2239 && c==1)\n        printf(\"\\b\\b\\b\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "640c68fefd2c9d09aa8f19716c8ab475", "src_uid": "c0a3290be3b87f3a232ec19d4639fefc", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n\nint main()\n{\n    int a,b,i,j,k,n,val,arrest=0;\n    char id[1000];\n    scanf(\"%s\",id);\n    for(i=0;id[i]!='@';i++){\n        if((id[i]>='A' && id[i]<='Z') ||(id[i]>='a' && id[i]<='z') || id[i]=='_' || (id[i]>='0' && id[i]<='9'))\n            continue;\n\n        arrest=1;\n    }\n    if(arrest==1 || i==0 || i>16){ printf(\"NO\\n\"); return 0;}\n\n    for(i++,j=0,k=0 ;id[i]!='\\0' && id[i]!='/';i++,k++){\n         if((id[i]>='A' && id[i]<='Z') ||(id[i]>='a' && id[i]<='z')|| id[i]=='_' || (id[i]>='0' && id[i]<='9'))\n            {\n                j++;\n\n            }\n            else if(id[i]=='.'){\n                if(j==0 || j>16){printf(\"NO\\n\"); return 0;}\n                else j=0;\n            }\n        else\n            arrest=1;\n    }\n    if(arrest==1 || k==0 || k>32 ||j==0){ printf(\"NO\\n\"); return 0;}\n    else if(id[i]=='\\0'){ printf(\"YES\\n\"); return 0;}\n    for(i++,j=0;id[i]!='\\0';i++,j++){\n        if((id[i]>='A' && id[i]<='Z') ||(id[i]>='a' && id[i]<='z') || id[i]=='_' || (id[i]>='0' && id[i]<='9'))\n            continue;\n\n        arrest=1;\n    }\n    if(arrest==1 ||j>16 ||j==0) printf(\"NO\\n\");\n    else printf(\"YES\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c15b24c2ad8528d188f223242ec4d4a8", "src_uid": "2a68157e327f92415067f127feb31e24", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n    char s[101],c;\n    int x,y,z,m=0,n=0,p=0,q=0;\n    scanf(\"%s\",s);\n    for(x=0;s[x]!='@';x++)\n    {   q++;\n        c=s[x];\n        if((c>=65 &&c <=90) || (c>=97 &&c <=122) || (c>=48 &&c <=57) ||c==95)\n        continue;\n        goto v;\n    }\n    if(q==0 || q>16)\n    goto v;\n    for(y=x+1;s[y]!='\\0';y++)\n    {\n\n        c=s[y];\n     if(c=='.')\n     {\n         if(m>=1 && m<=16)\n         {\n             n=n+m;\n             m=0;\n         }\n         else\n         goto v;\n         continue;\n     }\n     if((c>=65 &&c <=90) || (c>=97 &&c <=122) || (c>=48 &&c <=57) ||c==95)\n     m++;\n     else if(c=='/')\n     break;\n     else\n     goto v;\n    }\n    if(s[y]=='\\0' || s[y]=='/')\n    n=n+m;\n    if(n==0 || n>32 || m==0 || m>16)\n    goto v;\n    if(s[y]=='\\0')\n    {\n    printf(\"YES\");\n    exit(0);\n    }\n    for(z=y+1;s[z]!='\\0';z++)\n    {\n        c=s[z];p++;\n        if((c>=65 &&c <=90) || (c>=97 &&c <=122) || (c>=48 &&c <=57) ||c==95)\n        continue;\n        goto v;\n    }\n    if(s[z]=='\\0'&& p>0 && p<17)\n    {\n    printf(\"YES\");\n    exit(0);\n    }\n     v:\n     printf(\"NO\");\n     return(0);\n     }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9bd28c0775982fa75daf9cb467100ee4", "src_uid": "2a68157e327f92415067f127feb31e24", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\nint valid(char c){\n    if((c>='A' && c<='z')|| (c>='0'&&c<='9') || c=='_') return 1;\n    return 0;\n}\nvoid no(){\n    printf(\"NO\\n\");\n    exit(0);\n}\nint main()\n{\n    //freopen(\"in.txt\", \"r\", stdin);\n    char id[110];\n    fgets(id,110, stdin);\n\n    char *user, *host, *res;\n\n    if(id[0]=='@') no();\n    if(id[strlen(id)-2]=='/') no();\n\n    user = strtok(id, \"@\");\n    host = strtok(NULL, \"/\");\n    if(host==NULL) {\n        host=strtok(NULL, \"\\n\");\n        res=NULL;\n    }\n    else {\n        res = strtok(NULL, \"\\n\");\n    }\n\n    //printf(\"%s %s %s\\n\", user, host, res);\n\n    if(user==NULL || host==NULL) no();\n    if(strlen(user)>16 || strlen(host)>32) no();\n\n    int i;\n\n    if(user){\n        for(i=0; user[i]!='\\0'; i++){\n            if(!valid(user[i])) no();\n        }\n    }\n    int word=0;\n    if(host){\n        for(i=0; host[i]!='\\0'; i++){\n            if(valid(host[i])) word++;\n            else if(host[i]=='.'){\n                if(word<1 || word>16) no();\n                word=0;\n            }\n            else{\n                if(host[i]!='\\n') no();\n            }\n        }\n    }\n    if(word==0) no();\n\n    if(res){\n        for(i=0; res[i]!='\\0'; i++) {\n            if(!valid(res[i])) no();\n        }\n    }\n    //printf(\"%s %s %s\\n\", user, host, res);\n    printf(\"YES\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d35e287339a5859d3e26d3f485edf3ab", "src_uid": "2a68157e327f92415067f127feb31e24", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <ctype.h>//\u0377\ufffd\u013c\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffdisalnum\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0436\ufffd\u04bb\ufffd\ufffd\ufffd\ufffd\u0138\ufffd\u01f7\ufffd\u03aa\ufffd\ufffd\u0138\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\nint check_hostname(char *hostname)\n{\n\tint i=0,len=0,max_len=0,min_len=1000;\n\twhile (i <= strlen(hostname))//\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffdi<=sttrlen(hostname),\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u073d\ufffd\ufffd\ufffd\ufffd\u0421\ufffd.\ufffd\ufffd\ufffd\u05b8\ufffd\ufffd\ufffd\u05b7\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0268\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u02e3\ufffd\ufffd\ufffd\u05bb\ufffd\ufffd\ufffd\ufffd\n\t{                            //\ufffd\ufffd\ufffd\ufffd\u04bb\ufffd\ufffd\ufffd\ufffd\ufffd\u05b7\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u03aa\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0275\u0121\ufffd\n\t\tlen = 0;\n\t\twhile (hostname[i] != '.'&& hostname[i] != 0)\n\t\t{\n\t\t\tlen++;\n\t\t\ti++;\n\t\t}\n\t\tif (len > max_len)\n\t\t\tmax_len = len;\n\t\tif (len < min_len)\n\t\t\tmin_len = len;\n\t\ti++;\n\t}\n\tif (min_len == 0 || max_len > 16)\n\t\treturn 1;\n\telse\n\t\treturn 0;\n}\nint check_resource(char *resource)\n{\n\tint i=0, len, max_len = 0, min_len = 1000;\n\twhile (i <= strlen(resource))\n\t{\n\t\tlen = 0;\n\t\twhile (resource[i] != '/'&&resource[i] != 0)\n\t\t{\n\t\t\tlen++;\n\t\t\ti++;\n\t\t}\n\t\tif (len > max_len)\n\t\t\tmax_len = len;\n\t\tif (len < min_len)\n\t\t\tmin_len = len;\n\t\ti++;\n\t}\n\tif (min_len == 0 || max_len > 16)\n\t\treturn 1;\n\telse\n\t\treturn 0;\n}\nint main()//\ufffd\ufffd\ufffd\ufffd\ufffd\u02fc\u00b7\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u02fc\u00b7\ufffd\ufffd\u04bb\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0434\ufffd\ufffd\ufffd\u01f8\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0739\ufffd\u02b5\ufffd\u05ba\ufffd\ufffd\ufffd\ufffd\u013a\u073a\u00f5\u0131\u4daf\ufffd\u0523\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u01e1\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0136\ufffd\ufffd\u0663\ufffd\u02b9\ufffd\ufffd\ufffd\ufffd\u00fb\ufffd\ucde8\ufffd\u0739\ufffd\ufffd\ufffd\n{         //\ufffd\u023d\ufffd\ufffd\ufffd\u0237\ufffd\u0132\ufffd\ufffd\u88ec\ufffd\ufffd\ufffd\ufffd\ufffd\u02f2\ufffd\u0237\ufffd\ufffd\ufffd\u0523\ufffd\u02b9\ufffd\ufffd\ufffd\ufffd\ufffd\u07b7\ufffd\u0378\ufffd\ufffd\ufffd\u0137\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0434\ufffd\u0133\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffdstotok\ufffd\ufffd\ufffd\ufffd\u00fb\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u02b6\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u02fd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u00a9\ufffd\ufffd\n\t     //\ufffd\ufffd\ufffd\u05b7\u05bf\ufffd\ufffd\ufffd\ufffd\ufffd\u0137\ufffd\ufffd\ufffd\u05b5\ufffd\ufffd\u02fc\ufffd\ufffd\ufffd\ufffd\n\tchar str[101], username[101], hostname[101], resource[101];\n\tint len;\n\tint i,j;\n\tint at,point,res,next;\n\tat =point =res=next=0;\n\tscanf(\"%s\", str);\n\tlen = strlen(str);\n\tfor (i = 0; i < len; i++)\n\t\tif (str[i] == '@')\n\t\t{\n\t\t\tat = 1; \n\t\t\tbreak;\n\t\t}\n\tif (!at)\n\t{\n\t\tprintf(\"NO\\n\");\n\t\texit(0);\n\t}\n\tfor (++i; i < len; i++)\n\t{\n\t\tif (str[i] == '.')\n\t\t\tpoint = 1;\n\t\tif (str[i] == '/')\n\t\t\tres = 1;\n\t}\n\tfor (i = 0, j = 0; str[i] != '@'; i++,j++)\n\t\tusername[j] = str[i];\n\tusername[j] = 0;\n\tif (res)\n\t{\n\t\tfor (++i, j = 0; str[i] != '/'; i++, j++)\n\t\t\thostname[j] = str[i];\n\t\thostname[j] = 0;\n\t\tfor (++i,j=0; str[i] != 0; i++,j++)\n\t\t\tresource[j] = str[i];\n\t\tresource[j] = 0;\n\t}\n\telse\n\t{\n\t\tfor (++i, j = 0; str[i] != 0; i++, j++)\n\t\t{\n\t\t\thostname[j] = str[i];\n\t\t}\n\t\thostname[j] = 0;\n\t\tresource[0] = 0;\n\t}\n\tfor (i = 0; i < strlen(username); i++)\n\t\tif (!(isalnum(username[i]) || username[i] == '_'))\n\t\t\tnext = 1;\n\tfor (i = 0; i < strlen(hostname); i++)\n\t\tif (!(isalnum(hostname[i]) || hostname[i] == '_' || hostname[i] == '.'))\n\t\t\tnext = 1;\n\tfor (i = 0; i < strlen(resource); i++)\n\t\tif (!(isalnum(resource[i]) || resource[i] == '_' || resource[i] == '/'))\n\t\t\tnext = 1;\n\tif (strlen(username) > 16 || strlen(username) == 0)\n\t\tnext = 1;\n\tif (strlen(hostname) > 32 || strlen(hostname) == 0||check_hostname(hostname))\n\t\tnext = 1;\n\tif (res && check_resource(resource))\n\t\tnext = 1;\n\t(next) ? printf(\"NO\\n\") : printf(\"YES\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "dc73848e288de592b6586772cebb3753", "src_uid": "2a68157e327f92415067f127feb31e24", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nvoid no(){\n    printf(\"NO\\n\");\n    exit(0);\n}\n\nint valid(char c) {\n    if( (c>='A'&&c<='z') || (c>='0'&&c<='9') || c=='_'  )\n}\n\nint main()\n{\n    char id[120];\n    fgets(id, 110, stdin);\n\n    int i=0, host=0, user=0, word=0, res=0;\n\n    for(i; id[i]!='@' || id[i]!='\\n'; i++) {\n        if(valid(id[i])) user++;\n        else no();\n    }\n    if (user<1 || user>16) no();\n\n    if(id[i]=='@')i++;\n\n    for(i; id[i]!='/'||id[i]!='\\n'; i++){\n        if(valid(id[i])) {\n            host++;\n            word++;\n        }\n        else if(id[i]=='.'){\n            word--;\n            if(word<1|| word>16) no();\n            word=0;\n        }\n        else {\n            if(id[i]!='\\n'|| id[i]!='\\0') no();\n        }\n    }\n    if(id[i]=='\\n' && id[i-1]=='.') no();\n    if(host<1 || host>32) no();\n\n    for(i; id[i]!='\\n'; i++) {\n        if(valid(id[i])) res++;\n        else no();\n    }\n\n    printf(\"YES\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3f8ac21b5d55e629abc2df30fb95e4a8", "src_uid": "2a68157e327f92415067f127feb31e24", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int b='a',c=0;\n    char a[510];\n    scanf(\"%s\",a);\n    if(b==a[c])\n    {\n        b++;\n        c++;\n    }\n    else if(b>a[c])\n        c++;\n    else\n    {\n        printf(\"NO\");\n        return;\n    }\n    printf(\"YES\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d583ca6412316022a367fb606f5fa8f5", "src_uid": "c4551f66a781b174f95865fa254ca972", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint temp[26];\nint main()\n{\n    char s[52];\n    int i, j, k;\n    gets(s);\n    if(s[0] != 'a'){ printf(\"NO\\n\"); return 0;}\n    else temp[0] = 1;\n    for(i = 1; s[i] != '\\0'; i++){\n        j = s[i] - 97;\n        if(s[i] > s[i-1] || temp[j] != 0){\n            temp[j] = 1;\n        }\n        else{\n            printf(\"NO\\n\"); return 0;\n        }\n    }\n    printf(\"YES\\n\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bac861e99c04af25c2b60d66f0d53999", "src_uid": "c4551f66a781b174f95865fa254ca972", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint temp[26];\nint main()\n{\n    char s[52];\n    int i, j, k, t;\n    gets(s);\n    if(s[0] != 'a')\n    {\n        printf(\"NO\\n\");\n        return 0;\n    }\n    else\n    {\n        temp[0] = 1;\n        t = 1;\n    }\n    for(i = 1; s[i] != '\\0'; i++)\n    {\n        j = s[i] - 97;\n        if(j >t)\n        {\n            printf(\"NO\\n\");\n            return 0;\n        }\n\n        if(j==t) t++;\n    }\n    printf(\"YES\\n\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9b569a8301bd2581a76e7131889bfcc6", "src_uid": "c4551f66a781b174f95865fa254ca972", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nint steman(char cad[]);\n\nint main(void) {\n\tchar cad[28];\n\t\n\tscanf(\"%s\",cad);\n\tif (steman(cad)) printf(\"YES\");\n\telse printf(\"NO\");\n\treturn 0;\n}\n\nint steman(char cad[]){\n\tint i,cont=0,n=strlen(cad);\n\tfor(i=0;i<n;i++){\n\t\tif(cad[i]<'a'+cont){\n\t\t\t\n\t\t}\n\t\telse if(cad[i]=='a'+cont){\n\t\t\tcont++;\n\t\t\t}\n\t\telse break;\n\t}\n\tif (i==n) return 1;\n\telse return 0;\n}\nFin de la conversaci\u00f3n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "cf30627c8b56e779997bb5d2f161bd9b", "src_uid": "c4551f66a781b174f95865fa254ca972", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<string.h>\n#include <stdlib.h> \n\n\nint main()\n{\n\tint n, i, f=0;\n\tchar s[501], t='a';\n\tn = strlen(s);\n\tscanf_s(\"%s\", s);\n\tif (s[0] != t)\n\t{\n\t\tf++;\n\t\tprintf(\"NO\");\n\t\treturn 0;\n\t}\n\n\tfor (i = 1; i < n; i++)\n\t{\n\t\tif (t+1 < s[i])\n\t\t{\n\t\t\tf++;\n\t\t\tbreak;\n\t\t}\n\t\tif (t + 1 == s[i])\n\t\t\tt++;\n\t}\n\tif (f)\n\t\tprintf(\"NO\");\n\telse\n\t\tprintf(\"YES\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "50b71a439de1476981721830cf3c3676", "src_uid": "c4551f66a781b174f95865fa254ca972", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n\tint n, a[1000], i, c = 0, p = 0,j;\n\tscanf(\"%d\", &n);\n\tfor (i=0; i < n; i++)\n\t{\n\t\tscanf(\"%d\", &a[i]);\n\t\tif ( a[i] > 0)\n\t\t{\n\t\t\tc++;\n\t\t}\n\t\telse if \n\t\tp++;\n\t}\n\tj = ceil(n / 2.0);\n\tputs((c > p ? c : p) >= j ? (c > p ? \"1\" : \"-1\") : \"0\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6dc4666c0e320b5652785d6a6673a943", "src_uid": "a13cb35197f896cd34614c6c0b369a49", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n//for (i = 0; i < n; i++)\n//{\n//\tg = a[i] / (-1);\n//\tif (g > 0)\n//\t{\n//\t\tw++;\n//\t}\n//\tif (w > j)\n//\t{\n//\t\td = a[i] / n * 2;\n//\t\tprintf(\"%d\", d);\n//\t\tbreak;\n//\t}\n//}\nint main()\n{\n\tint n, i, d,a[1000],m=0,p,g,w,s=0;\n\tdouble  j=0, k;\n\tscanf_s(\"%d\", &n);\n\tfor (i = 0; i < n; i++)\n\t{\n\t\tscanf_s(\"%d\", &a[i]);\n\t}\n\tk = (double)n / 2;\n\tif (k > (int)k)\n\t{\n\t\tp =(int)k+1;//\u81f3\u5c11\u9700\u8981\u7684\u6b63\u6570\n\t}\n\n\tfor (i = 0; i < n; i++)\n\t{\n\t\tif (a[i] > 0)\n\t\t{\n\t\t\tj++;//\u6570\u7ec4\u4e2d\u6b63\u6570\u4e2a\u6570\n\t\t}\n\t\tif (a[i] == 0)\n\t\t{\n\t\t\tm++;//\u6570\u7ec4\u4e2d0\u7684\u4e2a\u6570\n\t\t}\n\t}\n\n\ti = 0;\n\ts = a[0];\n\n\tif (m >= p)\n\t{\n\t\td = 0;\n\t\tprintf(\"%d\", d);\n\t\treturn 0;\n\t}\n\tif (j >= p)\n\t{\n\t\td = s / n * 2;\n\t\tprintf(\"%d\", d);\n\t}\n\tif ((n - j) >= p)\n\t{\n\t\td = -(s / n * 2);\n\t\tprintf(\"%d\", d);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c03c55f9a3cb514787581aa1440fa7f8", "src_uid": "a13cb35197f896cd34614c6c0b369a49", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<studio.h>\n#include<conio.h>\nint main() \n{\n  int n, a[10000],p=0,q=0, i;\n  scanf(\"%d\",&n);\n  for(i=0;i<n;i++)\n  {\n     scanf(\"%d\",&a[i]) ;\n     if(a[i] >0)\n          p++;\n     else if(a[i] <0)\n           q++;\n  } \n  float f=n/2.0;\n  if(p>=f) \n     printf(\"1\\n\");\n  else if(q>=c) \n     printf(\"-1\\n\");\n  else\n      printf(\"0\");\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e6f4136db8b6f5e6fcb1d9e4bb0717fd", "src_uid": "a13cb35197f896cd34614c6c0b369a49", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(void)\n{\n    int a[2000],d,n,b[2000];\n    scanf(\"%d\",&n);\n    int i,count=0,count1;\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    count1=(n/2)+1;\n    d=count1+1;\n    for(i=0;i<n;i++)\n    {\n        if(a[i]<=0 || a[i]==1)\n        {\n            count++;  \n        }\n    }\n    if(count>count1)\n    {\n        printf(\"0\");\n    }\n    else\n        printf(\"%d\",d);\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "88553c42c419197f86ce6f20cc9b5dc7", "src_uid": "a13cb35197f896cd34614c6c0b369a49", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(void)\n{\n    int a[2000],d,n,b[2000];\n    scanf(\"%d\",&n);\n    int i,count=0,count1,count2=0,count3=0;\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    count1=(n/2)+1;\n    d=count1+1;\n    for(i=0;i<n;i++)\n    {\n        if(a[i]<0)\n        {\n            //b[i]=a[i]/(-1);\n            count++;\n        }\n        elseif(a[i]==0)\n        {\n            //c[i]=a[i];\n            count2++;\n        }\n        else\n            count3++;\n    }\n    \n    if(count>count1)\n    {\n        printf(\"-1\");\n    }\n    else if(count3>count1)\n        printf(\"%d\",d);\n    else\n        printf(\"0\");    \n}    ", "lang_cluster": "C", "compilation_error": true, "code_uid": "66147be607c7d6d29c710d74b947e908", "src_uid": "a13cb35197f896cd34614c6c0b369a49", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nfloat pi=3.14159265358979323846;\nint gcdf(int,int);\n\nint main()  \n{\n\tfloat ax,ay,bx,by,cx,cy,a,b,c,tri_area,r_outersp,angle_a,angle_b,angle_c,edges,area,areas;\n\tint gcd;\n\tscanf(\"%f %f\",&ax,&ay);\n\tscanf(\"%f %f\",&bx,&by);\n\tscanf(\"%f %f\",&cx,&cy);\n\ta = sqrt( (ax-bx)*(ax-bx) + (ay-by)*(ay-by) ) ;  \n    \tb = sqrt( (bx-cx)*(bx-cx) + (by-cy)*(by-cy) ) ;  \n    \tc = sqrt( (ax-cx)*(ax-cx) + (ay-cy)*(ay-cy) ) ;\n\ttri_area = sqrt((0.5*(a+b+c))*((0.5*(a+b+c))-c)*((0.5*(a+b+c))-b)*((0.5*(a+b+c))-c));\n\tr_outersp = a*b*c/(4*tri_area);\n\tangle_a = acos((b*b+c*c-a*a)/(2*b*c));\n\tangle_b = acos((a*a+c*c-b*b)/(2*a*c));\n\tangle_c = acos((a*a+b*b-c*c)/(2*b*a));\n\tgcd = gcdf((int)angle_a,(int)angle_b)\n\tgcd = gcdf(gcd,(int)angle_c);\n\tedges = 2*pi/gcd;\n\tarea = r_outersp*r_outersp*sin(gcd)/2;\n\tareas = area*(int)edges;\n\tprintf(\"%f\",areas);\n\treturn 0;\n}\n\nint gcdf(int m, int n)  \n{  \n\twhile(m>0){\n\t\tint c = n % m;\n\t\tn = m;\n\t\tm = c;\n\t}  \n\treturn n;  \n}    ", "lang_cluster": "C", "compilation_error": true, "code_uid": "8352608f21f13c7ca54cf912ada33e90", "src_uid": "980f4094b3cfc647d6f74e840b1bfb62", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main()\n{\n    float xc=0,yc=0;\n    float x1,y1,x2,y2,x3,y3;\n    double angle1,angle2,angle3;\n    scanf(\"%f%f%f%f%f%f\",&x1,&y1,&x2,&y2,&x3,&y3);\n    if(x1!=x2&&x2!=x3&&x3!=x1&&y1!=y2&&y2!=y3&&y1!=y3)\n    {\n        yc=(x1-x3+(y1*y1-y2*y2)/(x1-x2)-(y2*y2-y3*y3)/(x2-x3))/(2*((y1-y2)/(x1-x2)-(y2-y3)/(x2-x3)));\n        xc=(y1-y3+(x1*x1-x2*x2)/(y1-y2)-(x2*x2-x3*x3)/(y2-y3))/(2*((x1-x2)/(y1-y2)-(x2-x3)/(y2-y3)));\n    }\n    else\n    {\n        if(x1==x2)\n        {\n            yc=(y1+y2)/2;\n        }\n        if(x2==x3)\n        {\n            yc=(y2+y3)/2;\n        }\n        if(x1==x3)\n        {\n            yc=(y1+y3)/2;\n        }\n        if(y1==y2)\n        {\n            xc=(x1+x2)/2;\n        }\n        if(y2==y3)\n        {\n            xc=(x2+x3)/2;\n        }\n        if(y1==y3)\n        {\n            xc=(x1+x3)/2;\n        }\n    }\n    //finished the finding outer-center of the triangle.\n    if(x1-xc!=0)\n    {\n        angle1=atan((double)(y1-yc)/(double)(x1-xc));\n    }\n    else\n    {\n        if(x1>xc)\n        {\n            angle1=M_PI/2;\n        }\n        else\n        {\n            angle1=3*M_PI/2;\n        }\n    }\n\n    if(x2-xc!=0)\n    {\n        angle2=atan((double)(y2-yc)/(double)(x2-xc));\n    }\n    else\n    {\n        if(x2>xc)\n        {\n            angle2=M_PI/2;\n        }\n        else\n        {\n            angle2=3*M_PI/2;\n        }\n    }\n\n    if(x3-xc!=0)\n    {\n        angle3=atan((double)(y3-yc)/(double)(x3-xc));\n    }\n    else\n    {\n        if(x3>xc)\n        {\n            angle3=M_PI/2;\n        }\n        else\n        {\n            angle3=3*M_PI/2;\n        }\n    }\n    if(angle1<0)\n    {\n        angle1+=M_PI;\n    }\n    if(angle2<0)\n    {\n        angle2+=M_PI;\n    }\n    if(angle3<0)\n    {\n        angle3+=M_PI;\n    }\n    if(y1<=yc)\n    {\n        angle1+=M_PI;\n    }\n    if(y2<=yc)\n    {\n        angle2+=M_PI;\n    }\n    if(y3<=yc)\n    {\n        angle3+=M_PI;\n    }\n    double A1,A2,A3;\n    A1=fabs(angle1-angle2);\n    A2=fabs(angle2-angle3);\n    A3=fabs(angle3-angle1);\n    if(A1>M_PI)\n    {\n        A1=2*M_PI-A1;\n    }\n    if(A2>M_PI)\n    {\n        A2=2*M_PI-A2;\n    }\n    if(A2>M_PI)\n    {\n        A2=2*M_PI-A2;\n    }\n    while(A1!=A2)\n    {\n        if(A1>A2)\n        {\n            A1-=A2;\n        }\n        else\n        {\n            A2-=A1;\n        }\n    }\n    while(A2!=A3)\n    {\n        if(A2>A3)\n        {\n            A2-=A3;\n        }\n        else\n        {\n            A3-=A2;\n        }\n    }\n    int x=1;\n    while(x<2*double(M_PI)/A2)\n    {\n        x++;\n    }\n    double length = (x1-xc)*(x1-xc)+(y1-yc)*(y1-yc);\n    double res;\n    res=x*(sin((2*M_PI)/x))*length/2;\n    printf(\"%.8lf\",res);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "19ca9246419d03fe59ed0283f72507ad", "src_uid": "980f4094b3cfc647d6f74e840b1bfb62", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main(){\n\n\tdouble x[3],y[3];\n\tdouble ag[3];\n\tscanf(\"%lf%lf%lf%lf%lf%lf\",x,y,x+1,y+1,x+2,y+2);\n\n\n\t/*\n\t   float x[3],y[3];\n\t   float ag[3];\n\t   scanf(\"%f%f%f%f%f%f\",x,y,x+1,y+1,x+2,y+2);\n\t */\n\n\tint i,j;\n\tint te[3]={0,1,2};\n\tdouble t,a;\n\tdouble pi=3.14159265358979323;\n\tint ed;\n\n\n\tfor(i=0;i<3;i++)\n\t{\n\t\tte[0]=(i+te[0])%3;\n\t\tte[1]=(i+te[1])%3;\n\t\tte[2]=(i+te[2])%3;\n\t\tag[i]=\n\t\t\t((x[te[0]]-x[te[2]])*(x[te[1]]-x[te[2]])+(y[te[0]]-y[te[2]])*(y[te[1]]-y[te[2]]))/\n\t\t\tsqrt(\n\t\t\t\t\t(   (x[te[0]]-x[te[2]])*(x[te[0]]-x[te[2]])+(y[te[0]]-y[te[2]])*(y[te[0]]-y[te[2]]))\n\t\t\t\t\t*((x[te[1]]-x[te[2]])*(x[te[1]]-x[te[2]])+(y[te[1]]-y[te[2]])*(y[te[1]]-y[te[2]])         )\n\t\t\t\t);\n\n\t}\n\n\tfor(i=0;i<3;i++)\n\t{\n\t\tag[i]=acos(ag[i])/pi;\n\t\t//printf(\"%f\",ag[i]);\n\t}\n\n\tfor(i=3;i<=100;i++)\n\t{\n\n\t\tfor(j=0;j<3;j++)\n\t\t{\t\n\t\t\tt=ag[j]*i-int(ag[j]*i);\n\t\t\t//printf(\"%f \",t);\n\t\t\tif(t>0.00001&&t<0.99999)\n\t\t\t{\n\t\t\t\tbreak;\n\n\n\t\t\t}\n\n\t\t\tif(j==2)\n\t\t\t{\n\t\t\t\ted=i;\n\t\t\t\ti=101;\n\t\t\t}\n\n\t\t}\n\n\n\n\n\n\t}\n\t\na=\t((x[0]-x[1])*(x[0]-x[1])+(y[0]-y[1])*(y[0]-y[1]))\n\t*((x[0]-x[2])*(x[0]-x[2])+(y[0]-y[2])*(y[0]-y[2]))\n\t*((x[1]-x[2])*(x[1]-x[2])+(y[1]-y[2])*(y[1]-y[2]))\n\t/((x[0]-x[2])*(y[1]-y[2])-(y[0]-y[2])*(x[1]-x[2]))\n\t/((x[0]-x[2])*(y[1]-y[2])-(y[0]-y[2])*(x[1]-x[2]))\n\t*ed*sin(2*pi/ed)/8;\n//    *((x[0]-x[2])*(x[1]-x[2])+(y[0]-y[2])*(y[1]-y[2]))\n//\t\t/ ((x[0]-x[2])*(y[1]-y[2])-(y[0]-y[2])*(x[1]-x[2]))/4*ed;\n\n\nif(a<0)\n\ta*=(-1);\n\n/*\n\tsqrt( \n\t\t\t\t((x[0]-x[2])*(x[0]-x[2])+(y[0]-y[2])*(y[0]-y[2])) \n\t\t\t\t*((x[1]-x[2])*(x[1]-x[2])+(y[1]-y[2])*(y[1]-y[2]))\n\t\t\t\t\n\t\t\t\t)\n\n*/\n\n\t//printf(\"%d\\n\",ed);\n\tprintf(\"%.6f\\n\",a);\n\n\n\t//printf(\"%f\",sqrt(3));\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "66d7383f48dcdf664c91b158ba901fbb", "src_uid": "980f4094b3cfc647d6f74e840b1bfb62", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <assert.h>\n#include <math.h>\n\ntypedef struct point\n{\n    float x;\n    float y\n}\npoint_tp;\n\nfloat p_mult(point_tp a, point_tp b) {\n    return a.x * b.x + a.y * b.y;\n}\n\npoint_tp p_minus(point_tp a, point_tp b) {\n    point_tp res;\n    res.x = a.x - b.x;\n    res.y = a.y - b.y;\n    return res;\n}\n\nint is_int(float x) {\n    return abs(x - round(x)) < 0.000001;\n}\nint main(int argc, char **argv)\n{\n    point_tp a, b, c;\n    float fi1, fi2, fi3;\n    float ratio;\n    assert(scanf(\"%f%f\", &a.x, &a.y) == 2);\n    assert(scanf(\"%f%f\", &b.x, &b.y) == 2);\n    assert(scanf(\"%f%f\", &c.x, &c.y) == 2);\n    \n    fi1 = acos(p_mult(p_minus(b, a), p_minus(c, a))/sqrt(p_mult(p_minus(b, a), p_minus(b, a)) * p_mult(p_minus(c, a), p_minus(c, a))));\n    fi2 = acos(p_mult(p_minus(a, b), p_minus(c, b))/sqrt(p_mult(p_minus(a, b), p_minus(a, b)) * p_mult(p_minus(c, b), p_minus(c, b))));\n    fi3 = M_PI - fi1 - fi2;\n    \n    int i = 3;\n    for (; i < 101; i++) {\n        if (is_int(fi1/(M_PI/i)) & is_int(fi2/(M_PI/i)) & is_int(fi3/(M_PI/i))) break;\n    }\n    float R = sqrt(p_mult(p_minus(c, b), p_minus(c, b)))/(2 * sin(fi1));\n    float S = i * R * R * sin(M_PI * 2/i)/2;\n    \n    \n    printf(\"%f\", S);\n    \n    \n    \n    --scanf(\"%f\", &fi1);\n    return 0;\n    \n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5a8bfb0155ebd77110bd47a199fea855", "src_uid": "980f4094b3cfc647d6f74e840b1bfb62", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#define PI acos(-1)\n#define EPS 1e-6\n\nint cmp(const void *a, const void *b) {\n  double da = *(double*)a;\n  double db = *(double*)b;\n  if (fabs(da-db)<EPS) return 0;\n  if (da-db>EPS) return 1;\n  return -1;\n}\n\nint istime(double x, double y) {\n  double n = (floor)(x/y+EPS);\n  printf (\"%lf\\n\", fags(x-y*n));\n  return 0;\n  if (fabs(x-y*n)<=EPS) return 1;\n  else return 0;\n}\n\ndouble dis(double x[2], double y[2]) {\n  return sqrt((x[0]-y[0])*(x[0]-y[0]) + (x[1]-y[1])*(x[1]-y[1]));\n}\n\ndouble area(double x[2], double y[2], double z[2]) {\n  return fabs(\n      (x[0]*y[1]+z[0]*x[1]+y[0]*z[1] - z[0]*y[1]-x[0]*z[1]-y[0]*x[1])/2\n      );\n}\n\ndouble min(double x, double y) {\n  if (x - y > EPS) return y;\n  else return x;\n}\n\nint main() {\n  double x[2], y[2], z[2], m[2];\n  double xy,xz,yz;\n  double p, q, l1, l2, l3;\n  double s, d, cosd;\n  double mx, my, mz;\n  double da[3], t;\n  while (scanf (\"%lf%lf\", &x[0], &x[1]) != EOF) {\n    scanf (\"%lf%lf\", &y[0], &y[1]);\n    scanf (\"%lf%lf\", &z[0], &z[1]);\n    xy = dis(x,y); xz = dis(x,z); yz = dis(y,z);\n    p = (xy*xy+xz*xz+yz*yz) / 2;\n    q = 1/(1/(p-xy*xy)+1/(p-xz*xz)+1/(p-yz*yz));\n    l1 = q/(p-xy*xy);\n    l2 = q/(p-xz*xz);\n    l3 = q/(p-yz*yz);\n    m[0] = (1-l1)/2*z[0]+(1-l2)/2*y[0]+(1-l3)/2*x[0];\n    m[1] = (1-l1)/2*z[1]+(1-l2)/2*y[1]+(1-l3)/2*x[1];\n    mx = dis(m, x); my = dis(m, y); mz = dis(m, z);\n\n    cosd = (mx*mx+my*my-xy*xy) / (2*mx*my);\n    da[0] = acos(cosd);\n    cosd = (mx*mx+mz*mz-xz*xz) / (2*mx*mz);\n    da[1] = acos(cosd);\n    cosd = (my*my+mz*mz-yz*yz) / (2*my*mz);\n    da[2] = acos(cosd);\n\n    qsort(da, 3, sizeof(double), cmp);\n    d = da[0];\n    istime(da[2],d); continue;\n    t = 2;\n    while (! (istime(da[0],d) && istime(da[1],d) && istime(da[2],d))) {\n      d = da[2]/t;\n      if(istime(da[0],d) && istime(da[1],d) && istime(da[2],d)) \n        break;\n      d = da[1]/t;\n      if(istime(da[0],d) && istime(da[1],d) && istime(da[2],d)) \n        break;\n      d = da[0]/t;\n      if(istime(da[0],d) && istime(da[1],d) && istime(da[2],d)) \n        break;\n      t++;\n    }\n    s = mx*my*0.5*sin(d);\n    printf (\"%lf\\n\", PI/d*2*s);\n    \n  }\n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ca390655a66d56f0e4fabf3f7d8cf638", "src_uid": "980f4094b3cfc647d6f74e840b1bfb62", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main(){\n    int n,menor=0,mayor=0;\n    int tam,i,l=1;\n    \n    scanf(\"%d\",&n);\n    \n    int d1[n];int d2[n];\n    \n    for(i=0;i<n;i++)\n    {\n        scanf(\"%1d\",&d1[i]);\n    }\n    \n    for(i=0;i<n;i++)\n    {\n        scanf(\"%1d\",&d2[i]);\n    }\n    \n    quicksort(d1,0,n-1);\n    quicksort(d2,0,n-1);\n\n    for(i=0;i<n;i++)\n    {\n        if(d1[i]>d2[i])\n            mayor++;\n        else if(d1[i]<d2[i])\n            menor++;\n    }\n    \n   if(mayor==n || menor==n)\n    puts(\"YES\");\n   else\n    puts(\"NO\");\n    \n    return 0;\n}\n\nvoid quicksort(int a[],int primero,int ultimo)\n{\n    int i,j,central;\n    double pivote;\n    int aux;\n    \n    entral=(primero+ultimo)/2;\n    pivote=a[central];\n    i=primero;\n    j=ultimo;\n    \n    do{\n    while(a[i]<pivote) i++;\n    while(a[j]>pivote) j--;\n    if (i<=j){\n        aux = a[i];\n        a[i] = a[j];\n        a[j] = aux;\n        i++;\n        j--;\n    }\n}while(i<=j);\n    if(j>primero)\n        quicksort(a,primero,j);\n    if(i<ultimo)\n        quicksort(a,i,ultimo);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ec7e1b3eb0224c52c663a727b6fce2e3", "src_uid": "e4419bca9d605dbd63f7884377e28769", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(){\n    int n,i,j,c,bandera=0,bandera2=0,aux,bandera3=0;\n    scanf(\"%d\",&n);\n    char num[2*n];\n    scanf(\"%s\",&num);\n    c=n;\n    //ordenamos la primera mitad\n    for(i=0; i<n-1; i++){\n        for (j=i+1; j<n; j++){\n            if(num[i]>num[j]){\n                aux=num[j];\n                num[j]=num[i];\n                num[i]=aux;\n            }\n        }\n    }\n    //ordenamos la segunda mitad\n    for(i=n; i<(2*n)-1; i++){\n        for (j=i+1; j<(2*n); j++){\n            if(num[i]>num[j]){\n                aux=num[j];\n                num[j]=num[i];\n                num[i]=aux;\n            }\n        }\n    }\n    //vemos si son iguales\n    for(i=0; i<n; i++){\n        if(num[i]==num[c]){\n            bandera3=1;\n            break;\n        }else{\n            bandera3=0;\n        }\n        c++;\n    }\n    if(bandera3==1){\n        printf(\"NO\");\n    }else{\n        //vemos si es menor\n        for(i=0; i<n; i++){\n            if(num[i]<num[c]){\n                bandera=1;\n                j=(2*n);\n            }else{\n                bandera=0;\n            }\n            c++;\n        }\n        if(bandera==1){\n            printf(\"YES\");\n        }else{//si no cumple el primer criterio\n            c=n;\n            //vemos si es mayor\n            for(i=0; i<n; i++){\n                if(num[i]>num[c]){\n                    bandera2=1;\n                }else{\n                    bandera2=0;\n                    i=n;\n                }\n                c++;\n            }\n            if(bandera2==1){\n                printf(\"YES\");\n            }else{\n                printf(\"NO pito\");\n            }\n        }\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "840006b0189d192e32e5db912fe22cc2", "src_uid": "e4419bca9d605dbd63f7884377e28769", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,a,i,j,c=0,d=0,t;\n    scanf(\"%d\",&n);\n    int b[2*n];\n    scanf(\"%d\",&a);\n    for(i=0;i<2*n;i++)\n        {b[i]=a%10;\n        a=a/10;\n        }\n        for(i=0;i<n;i++)\n            for(j=i+1;j<n;j++)\n            if(b[i]<b[j])\n        {\n            t=b[i];\n            b[i]=b[j];\n            b[j]=t;\n        }\n        for(i=0;i<2*n;i++)\n            for(j=i+1;j<2*n;j++)\n            if(b[i]<b[j])\n        {\n            t=b[i];\n            b[i]=b[j];\n            b[j]=t;\n        }\n\n        for(j=0;j<=n-1;j++)\n            if(b[j]>b[n+j])\n            c=c++;\n        for(j=0;j<=n-1;j++)\n            if(b[j]<b[n+j])\n            d=d++;\n        if(c==n||d==n)\n            printf(\"YES\");\n        else\n            printf(\"NO\";\n        return(0);\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "18bf56ef6e747ecf6bb9936b4a659ab0", "src_uid": "e4419bca9d605dbd63f7884377e28769", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tchar A[201];\n\tint n, i, j;\n\n\tscanf(\"%d\", &n);\n\tgetchar();\n\tfor (i = 0; i < 2 * n; i++)\n\t\tscanf(\"%c\", &A[i]);\n\n\tfor (i = 0; i < n - 1; i++)\n\t\tfor (j = i + 1; j < n; j++)\n\t\t\tif (A[i] > A[j])\n\t\t\t{\n\t\t\t\tchar temp = A[i];\n\t\t\t\tA[i] = A[j];\n\t\t\t\tA[j] = temp;\n\t\t\t}\n\n\tfor (i = n; i < 2 * n - 1; i++)\n\t\tfor (j = i + 1; j < 2 * n; j++)\n\t\t\tif (A[i] < A[j])\n\t\t\t{\n\t\t\t\tchar temp = A[i];\n\t\t\t\tA[i] = A[j];\n\t\t\t\tA[j] = temp;\n\t\t\t}\n\tint check = 1;\n\n\tfor (i = 0; i < n; i++)\n\t{\n\t\tif (A[i] >= A[2 * n - i - 1])\n\t\t{\n\t\t\tcheck = 0;\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (check)\n\t{\n\t\tprintf(\"YES\");\n\t\treturn 0;\n\t}\n\n\tcheck = 1;\n\n\tfor (i = 0; i < n; i++)\n\t{\n\t\tif (A[i] =< A[2 * n - i - 1])\n\t\t{\n\t\t\tcheck = 0;\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (check)\n\t\tprintf(\"YES\");\n\telse\n\t\tprintf(\"NO\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5056f3337455b1f4b42e74b76ae948ce", "src_uid": "e4419bca9d605dbd63f7884377e28769", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n#include <string>\n#include <algorithm>\n\nusing namespace std;\n\nint main()\n{\n    size_t n;\n    string s, l, r;\n    cin >> n >> s;\n    l = s.substr(0, n);\n    r = s.substr(n, n);\n    sort(l.begin(), l.end());\n    sort(r.begin(), r.end());\n    bool strictly_less(true), strictly_more(true);\n    for (size_t i = 0; i < n; ++i)\n    {\n        if (l[i] >= r[i])\n        {\n            strictly_less = false;\n            break;\n        }\n    }\n    for (size_t i = 0; i < n; ++i)\n    {\n        if (l[i] <= r[i])\n        {\n            strictly_more = false;\n            break;\n        }\n    }\n    cout << ((strictly_less || strictly_more) ? \"YES\" : \"NO\") << endl;\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "64f92e003e55ea9fccc8094350537e2a", "src_uid": "e4419bca9d605dbd63f7884377e28769", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n\tint n, c, p;\n\tint b[26] = {0,0 };\n\tchar a[101];\n\tscanf(\"%d%d\", &n, &c);\n\tgetchar();\n\tgets(a);\n\tfor (int i = 0; i < strlen(a); i++)\n\t{\n\t\tp = a[i] - 97;\n\n\t\tb[p]++;\n\t}\n\n\tfor (int i = 0; i < 26; i++)\n\t{\n\t\tif (b[i] >=k+1)\n\t\t{\n\t\t\tprintf(\"NO\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\"YES\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c877d95e296380254b6a60c5b2019108", "src_uid": "ceb3807aaffef60bcdbcc9a17a1391be", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n\nint main()\n{\n  int n,k,i,j,count=0,tem,min=0;\n  char s[1000];\n\n  scanf(\"%d %d\",&n,&k);\n  scanf(\"%s\",s);\n\n  for(i=0;i<strlen(s);i++)\n  {\n      for(j=i+1;j<strlen(s);j++)\n      {\n          if(s[i]>s[j])\n          {\n              tem=s[i];\n              s[i]=s[j];\n              s[j]=tem;\n          }\n      }\n\n  }\n\n\n  for(i=0;i<strlen(s);i++)\n  {\n      count=0;\n      for(j=i;j<strlen(s);j++)\n      {\n          if(s[i]==s[j])\n          {\n\n            count++;\n\n          }\n          else\n          {\n              if(min>count)\n              {\n                  min=count;\n\n              }\n          }\n      }\n  }\n  if(min=>k)\n  {\n      printf(\"NO\");\n  }\n  else\n  {\n      printf(\"YES\");\n  }\n  return 0;\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3dd56a5ccb16ea56dd67b5e99090a0f2", "src_uid": "ceb3807aaffef60bcdbcc9a17a1391be", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<strng.h>\nchar s[201];\nint a[26];\nint main()\n{\n int n,k;\n scanf(\"%d%d%s\",&n,&k,s);\n for(int i=0;i<n;i++)\n {\n  a[s[i]-'a']++;\n }\n for(int i=0;i<26;i++)\n {\n   if(a[i]>k)\n   return puts(\"NO\"),0,puts(\"YES\");\n }\n return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "203ca087be406da3cca75f45d9ad36f1", "src_uid": "ceb3807aaffef60bcdbcc9a17a1391be", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdbool.h>\n#include<math.h>\n#include<stdlib.h>\n\nint cmp(const void* a, const void* b)\n{\n\treturn (*(int*)a - *(int*)b);\n}\n\n\nint main(void)\n{\n\tint i, j;\n\tint a[30] = { 0 };\n\tint n, k;\n\tint num = 0;\n\tchar x;\n\n\tscanf(\"%d %d\", &n, &k);\n\tgetchar();\n\tfor (i = 0; i < n; i++)\n\t{\n\t\tx = getchar();\n\t\ta[x - 'a']++;\n\t}\n\tfor (i = 0; i < 30; i++)\n\t\tnum = max(num, a[i]);\n\tif (num > k) printf(\"NO\");\n\telse printf(\"YES\");\n\t\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "300155541787ba99f2120972bfa279ac", "src_uid": "ceb3807aaffef60bcdbcc9a17a1391be", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\n#include<string>\nint main()\n{\n    int n,k,i,j,flag,count;\n    char arr[1000],temp;\n    while(scanf(\"%d %d\",&n,&k)==2)\n    {\n        scanf(\"%s\",arr);\n        flag=0;\n        for(i=0; i<n; i++)\n        {\n            temp=arr[i];\n            count=0;\n            for(j=0; j<n; j++)\n            {\n                if(arr[j]==temp)\n                {\n                    count++;\n                }\n            }\n            if(count>k){\n                flag=1;\n                break;\n            }\n            else\n                continue;\n        }\n        if(flag==1)\n            printf(\"NO\\n\");\n        else\n            printf(\"YES\\n\");\n\n    }\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "613330c666ac2f6e5afc2fb8a9e34e88", "src_uid": "ceb3807aaffef60bcdbcc9a17a1391be", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<math.h>\n#include<limits.h>\n\nlong long int c1,c2,x,y;\n\nlong long int check(long long int a)\n{\n\treturn (((a-a/x >= c1) && (a-a/y >= c2)) && (a-a/(x*y) >= c1+c2));\n}\n\nint main()\n{\n\tscanf(\"%lld %lld %lld %lld\",&c1,&c2,&x,&y);\n\tlong long int high = INT_MAX,low=0,mid;\n\twhile(high>low)\n\t{\n\t\tmid = high+low;\n\t\tmid /= 2;\n\t\tif(check(mid))\n\t\t\thigh = mid;\n\t\telse\n\t\t\tlow = mid+1;\n\t}\n\tprintf(\"%lld\\n\",high);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fbcec41788461936e7036060aaa1e12a", "src_uid": "ff3c39b759a049580a6e96c66c904fdc", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint c1, c2, x, y, ans;\nint main()\n{\n    scanf(\"%d%d%d%d\", &c1, &c2, &x, &y);\n\n    ans = c1+c2;\n    while(ans - ans/x < c1)\n    {\n        ans += c1 - (ans - ans/x);\n    }\n    while(ans - ans/y < c2)\n    {\n        ans += c2 - (ans - ans/y);\n    }\n    while(ans - ans/(x*y) < c1+c2)\n    {\n        ans += (c1+c2) - (ans - ans/(x*y));\n    }\n    printf(\"%d\\n\", ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8a3661db2c233f47fa749cd3440333db", "src_uid": "ff3c39b759a049580a6e96c66c904fdc", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "//friends and presents Federico Bellini\n#include <stdlib.h>\n#include <stdio.h>\n\nint main () {\n    int a,b;\n    int x,y;\n    \n    scanf(\"%i %i\", &a, &b);\n    scanf(\"%i %i\", &x, &y);\n    \n    int i = 0;\n    while(a > 0 || b > 0){\n        ++i;\n        \n        if((i%x != 0) && (i%y != 0)){\n            if(a>b && a>0) a--;\n            else b--;\n        }\n        else if((i%x != 0) && (a>0)){\n            a--;\n            \n        }\n        else if((i%y != 0) && (b>0)){\n            b--;\n        }\n    }\n    \n    printf(\"%i\\n\", i);\n}\n    \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "df4559e8ef8dde8157ad8037841beb8a", "src_uid": "ff3c39b759a049580a6e96c66c904fdc", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nlong long int b[10000000];\nint main()\n{\n\tint x,y,p=0;\n\tlong long int i,cnt1,cnt2,n;\n\tscanf(\"%llu%llu%d%d\",&cnt1,&cnt2,&x,&y);\n\tn=cnt1+cnt2;\n\tif(n<=x&&n<=y)\n\t{\n\t\tprintf(\"%lld\\n\",n);\n\t\treturn 0;\n\t}\n\telse\n\t{\n\t\tfor(i=1;i<=n;i++)\n\t\t{\n\t\t\tif(i%x!=0&&i%y!=0&&cnt1!=0&&cnt2!=0)\n\t\t\t{\n\t\t\t\tb[p++]=i;\n\t\t\t}\n\t\t\telse if(i%x!=0&&cnt1>0)\n\t\t\t\tcnt1--;\n\t\t\telse if(i%y!=0&&cnt2>0)\n\t\t\t\tcnt2--;\n\t\t\tif(i==n&&(cnt1!=0||cnt2!=0))\n\t\t\t{\n\t\t\t\tif(p==(cnt1+cnt2)||(p==cnt1)&&(cnt1!=0)||(p==cnt2&&cnt2!=0))\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%llu\\n\",n);\n\t\t\t\t\treturn 0;\n\t\t\t\t}\n\t\t\t\telse \n\t\t\t\t\tn++;\n\t\t\t}\n\t\t}\n\t}\t\t\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "44b36016adec229d3daca32385938f1f", "src_uid": "ff3c39b759a049580a6e96c66c904fdc", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <iostream>\nusing namespace std;\nint main(int argc, char const *argv[])\n{\n\tint cnt1, cnt2, x, y, v;\n\tcin >>cnt1>>cnt2>>x>>y;\n\tv = cnt2 + cnt1 + cnt1/x + cnt2/y;\n\tv -= (cnt1>cnt2)? cnt1/(x*y) : cnt2/(x*y);\n\tcout <<v;\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "19c2033152e97cd136e65c1e36899e85", "src_uid": "ff3c39b759a049580a6e96c66c904fdc", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\n#include<string>\n\n\n\nint main()\n{\n   int a,b,count=0,count1=0,count2=0;\n   float m=0;\n    int diffa=0;\n    int diffb=0;\n  scanf(\"%d %d\",&a,&b);\n   //winning of a \n   for(int i=1;i<=6;i++)\n   {\n     diffa=a-i;\n     diffb=b-i;\n     if(diffb<0)\n     {\n         diffb=diffb*(-1);\n        \n     }\n\n     if(diffa<0)\n     {\n         diffa=diffa*(-1);\n     }\n     if(diffa<diffb)\n     {\n        count++;\n     }\n     if(diffa==diffb)\n     {\n         count1++;\n     }\n     if(diffb<diffa)\n     {\n         count2++;\n     }\n    \n   }\n   printf(\"%d %d %d\",count,count1,count2);     \n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a39b339893654808426aec64b41e7fed", "src_uid": "504b8aae3a3abedf873a3b8b127c5dd8", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int p1,p2;\n    scanf(\"%d %d\",&p1,&p2);\n\n    int w,d,l;\n\n    for(int i=1;i<=6;i++)\n    {\n        if(abs(p1-i) < abs(p2-i))\n        {\n            w++;\n        }\n        else if(abs(p1-i) > abs(p2-i))\n        {\n            l++;\n        }\n        else\n        {\n            d++;\n        }\n    }\n\n    printf(\"%d %d %d\",w,d,l);\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5137b3f590ce0b6ecbcf125d545796b3", "src_uid": "504b8aae3a3abedf873a3b8b127c5dd8", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n  int a,b,k=0,n=0,m=0,i=1;\n  scanf(\"%d%d\",&a,&b);\n  while(i<=6)\n  {\n    if(abs(a-i)<abs(b-i))\n      k+=1;\n      if(abs(a-i)==abs(b-i))\n        n+=1;\n   if(abs(a-i)<abs(b-i))\n     m+=1;\n   i++;\n   }\n    printf(\"%d %d %d\",k,n,m);\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "f0c11d84aa4719c9304209b6d551b753", "src_uid": "504b8aae3a3abedf873a3b8b127c5dd8", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<algorithm>\n\nint main()\n{\n    int a,b,i,x,y,c1=0,c2=0,c3=0;\n    while(scanf(\"%d %d\",&a,&b)==2){\n    for(i=1;i<=6;i++){\n    x=abs(a-i);\n    y=abs(b-i);\n    if(x>y)\n    c1++;\n    if(y>x)\n    c2++;\n    if(x==y)\n    c3++;\n\n    }\n     printf(\"%d %d %d\\n\",c2,c3,c1);\n    return 0;\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b8d91d26cc445680cfad897402a02d0f", "src_uid": "504b8aae3a3abedf873a3b8b127c5dd8", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint main (void) {\n\tint a, b, a_win = 0, tie = 0, b_win = 0;\n\tscanf(\"%d %d\", &a, &b);\n\tfor (i = 1; i <= 6; i++) {\n\t\tif(abs(a - i) < abs(b - i)) a_win++;\n\t\tif(abs(a - i) > abs(b - i)) b_win++;\n\t\tif(abs(a - i) == abs(b - i)) tie++;\n\t}\n\tprintf(\"%d %d %d\", &a_win, &tie, &b_win);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "18e41916cd40a0e0b92ff4c2f3fb01df", "src_uid": "504b8aae3a3abedf873a3b8b127c5dd8", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define maxn 1000\nint a[maxn];\nvoid init();\nint main()\n{\n    init();\n    int n,i;\n    while(~scanf(\"%d\",&n))\n    {\n        if(n==1||n==2)\n        {\n            printf(\"%d\\n\",1);\n            printf(\"%d\\n\",n);\n            continue;\n        }\n        printf(\"%d\\n\",a[n]);\n        int sum=0;\n        for(i=1;i<a[n];i++)\n        {\n            sum+=i;\n            printf(\"%d \",i);\n\n        }\n        printf(\"%d\\n\",n-sum);\n\n\n    }\n    return 0;\n}\n\nvoid init()\n{\n    int s=1;\n    int i,j;\n    for(i=1;i<=1000;i+=s)\n    {\n        for(j=i;j<i+s+1;j++)\n            a[j]=s;\n        s++;\n \n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0a6d4ab8309c1662037ce4d1434c3616", "src_uid": "356a7bcebbbd354c268cddbb5454d5fc", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\nint x;\nprintf(\"enter the number of sweets: \");\nscanf(\"%d\", &x);\nint a[x], j=0, i, m=0;\nwhile(x!=0)\n{\nfor(i=0; i<x; i++)\n{\nx = (x-(++j));\na[i] = j;\n}\na[i-1]+=x;\nx=0;\n}\nprintf(\"%d\\n\", i);\nfor(m=0; m<i; m++)\nprintf(\"%d\\t\", a[m]);\nreturn 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2970a6b25767f4557033bb90da8b9e12", "src_uid": "356a7bcebbbd354c268cddbb5454d5fc", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <cstdio>\n\nint* allot(int use[1001], int n, int* num) {\n  use[n] = 1;\n  int k;\n  if (n%2&&!use[n/2]&&!use[(n+1)/2]) {\n    use[n/2] = 1;\n    use[(n+1)/2] = 1;\n    use[n] = 0;\n    (*num)++;\n    allot(use, n/2, num);\n    allot(use, (n+1)/2, num);\n  }\n  else if (!(n%2)&&!use[n/2-1]&&!use[n/2+1]) {\n    use[n/2-1] = 1;\n    use[n/2+1] = 1;\n    use[n] = 0;\n    (*num)++;\n    allot(use, n/2-1, num);\n    allot(use, n/2+1, num);\n  }\n  return num;\n}\n\nint main(void) {\n  int n;\n  scanf(\"%d\", &n);\n  int use[1001] = {0};\n  int num[0];\n  *num = 1;\n  allot(use, n, num);\n  printf(\"%d\\n\", *num);\n  int i, j;\n  for(i=0; i<=1000; i++) {\n    if (use[i]) { printf(\"%d\", i); break;}\n  }\n  for(j=i+1; j<=1000; j++) {\n    if (use[j]) printf(\" %d\", j);\n  }\n  puts(\"\");\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8127cc78c128450a8a051971dcecd572", "src_uid": "356a7bcebbbd354c268cddbb5454d5fc", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\nint main()\n{\n\tint i,j,n,k,br=0;\n\tint *a,**opt,*b,*niz;\n\t\n\tscanf(\"%d\",&n);\n\t\n\ta=(int*)malloc((n+1)*sizeof(int));\n\tniz=(int*)malloc((n+1)*sizeof(int));\n\tb=(int*)malloc((n+1)*sizeof(int));\n\topt=(int**)malloc((n+1)*sizeof(int*));\n\t\n\tif(n==1 || n==2){\n\t\tprintf(\"1\\n%d\",n);\n\t\treturn 0;\n\t}\n\t\n\tfor(i=1;i<=n;i++){\n\t\ta[i]=i;\n\t\tb[i]=1;\n\t\topt[i]=(int*)malloc((n+1)*sizeof(int));\n\t}\n\t\n\tfor(i=0;i<n;i++){\n\t\topt[i][0]=0;\n\t\topt[0][i]=0;\n\t}\n\t\n\tfor(i=1;i<=n;i++){\n\t\tfor(j=1;j<=n;j++){\n\t\t\tif(a[i]<=j && opt[i-1][j-a[i]]+b[i]>opt[i-1][j])\n\t\t\t\topt[i][j]=opt[i-1][j-a[i]]+b[i];\n\t\t\telse\n\t\t\t\topt[i][j]=opt[i-1][j];\n\t\t}\n\t}\n\t\n\ti=n;j=n;\n\twhile(opt[i][j]!=0){\n\t\tif (opt[i][j] == opt[i-1][j]) {\n\t\t\ti--;\n\t\t}\n\t\telse {\n\t\t\tniz[br++]=i;\n\t\t\tj -= zapr[i];\n\t\t\ti--;\n\t\t}\n\t}\n\t\n\tprintf(\"%d\\n\",br);\n\tfor(i=br-1;i>=0;i--)\n\t\tprintf(\"%d \",niz[i]);\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "045ee21c780d3f803c64f4896fccb10a", "src_uid": "356a7bcebbbd354c268cddbb5454d5fc", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n    int N;\n\n    while(scanf(\"%d\",&N)==1)\n    {\n        for(int l=1; l<=1000; l++)\n        {\n            getchar();\n            N = l;\n            N++;\n            int A[N];\n            for(int i=1; i<N; i++)\n                A[i] = 0;\n\n            int i,j,kid = 0,Sum = 0;\n\n            for(i=1; i<N; i++)\n            {\n                Sum = Sum+i;\n                if(Sum<= (N-1))\n                {\n                    A[i] = 1;\n                    kid++;\n                    if(Sum == N-1)\n                        break;\n                }\n                else\n                {\n                    A[Sum-(N-1)] = 0;\n                    A[i] = 1;\n                    break;\n                }\n            }\n\n            printf(\"%d\\n\",kid);\n            for(i = 1; i<N; i++)\n            {\n                if(A[i]==1)\n                {\n                    printf(\"%d\",i);\n                    kid--;\n                    if(kid)\n                        printf(\" \");\n                }\n            }\n            printf(\"\\n\");\n        }\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "300f7c8631ddec5e6ce543719665e93e", "src_uid": "356a7bcebbbd354c268cddbb5454d5fc", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\ntypedef long long int ll;\nint main()\n{\n\tll n,k;\n\tscanf(\"%lld%lld\",&n,&k);\n\tll ans=n;\n\tll count=1,i;\n/*\tfor(i=n-1;i>=n/2;i--)\n\t{\n\t\tll temp=ans^i;\n\t\tif(temp>ans)\n\t\t{\n\t\t\tans=temp;\n\t\t\tcount++;\n\t\t}\n\t\tif(count==k) break;\n//\t\tif(ans==(pow()-1)) break;\n\t}*/\n\tfor(i=n/2;i>0;i/=2)\n\t{\t\n\t\tif(count==k) break;\n\t\tll temp=ans^i;\n\t\tif(temp>ans)\n\t\t{\n\t\t\tans=temp;\n\t\t\tcount++;\n\t\t}\n\n\n\t}\n\n\n\tprintf(\"%lld\",ans);\n\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c06892efa1b5cd0c293aa3b827d459df", "src_uid": "16bc089f5ef6b68bebe8eda6ead2eab9", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint Cnt[101];\n\nint main()\n{\n    int n, m;\n    scanf(\"%d %d\", &n, &m);\n    for(int i = 0; i < m; ++i) {\n        int l, r;\n        scanf(\"%d %d\", &l, &r);\n        ++Cnt[l];\n        --Cnt[r + 1];\n    }\n    int cur = 0;\n    puts(\"===================\");\n    for(int i = 1; i <= n; ++i) {\n        cur += Cnt[i];\n        printf(\"%d %d\\n\", i, cur);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "13f111415d34b1294240d98f1feed4d3", "src_uid": "16bc089f5ef6b68bebe8eda6ead2eab9", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#include<math.h>\nint main()\n{\n    int len;\n    char buf[100]={0};\n    long long n,k,p;\n    scanf(\"%lld%lld\",&n,&k);\n    if(k==1)\n    {\n        printf(\"%lld\",n);\n        return 0;\n    }\n    _itoa(n,buf,2);\n    len=strlen(buf);\n    p=pow(2,len)-1;\n    printf(\"%lld\",p);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6f7688ddb018f373fc3089f6e5203ff4", "src_uid": "16bc089f5ef6b68bebe8eda6ead2eab9", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint cnt=0,a[1000000];\nint n,k;\nvoid dfs(int step,int sum,int b)\n{\n\tint i;\n\tif(step==k){\n\t\ta[cnt++]=sum;\n\t\treturn;\n\t}\n\tfor(i=b;i<=n;i++){\n\t\tif((sum^i)>sum)\n\t\t\tdfs(step+1,sum^i,i+1);\n\t}\n\ta[cnt++]=sum;\n}\nint main()\n{\n\tint i,max=0;\n\tscanf(\"%d %d\",&n,&k);\n\tfor(i=1;i<=n;i++){\n\t\tdfs(1,i,i+1);\n\t}\n\tfor(i=0;i<cnt;i++){\n\t\tif(max<a[i])max=a[i];\n\t}\n\tprintf(\"%d\",max);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9acf76a205cf679a1dadb4195e089693", "src_uid": "16bc089f5ef6b68bebe8eda6ead2eab9", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main(){\n\tlong long int n,k,i=0;\n\tscanf(\"%I64d %I64d\", &n, &k);\n\tif(k==1)\n\t\tprintf(\"%I64d\",n);\n\telse\n\t{\n\t\ti=0;\n\t\twhile((long long int)pow(2,i)<=n)\n\t\t\ti++;\n\t\tprintf(\"%I64d\",(long long int)pow(2,i)-1);\n\t}\n\treturn 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "46838967fa0435fcc7f5fd6550687cf8", "src_uid": "16bc089f5ef6b68bebe8eda6ead2eab9", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include<stdlib.h>\n#include<string.h>\nint main(){\n    int t1;\n    int t2;\n    int t3;\n    int t4;\n        scanf(\"%d\",&t1);\n        scanf(\"%d\",&t2);\n        scanf(\"%d\",&t3);\n        scanf(\"%d\",&t4);\nif((t1+t2+t3+t4)==0){\n    printf(\"0\");\n}else\n{\n    if(t1==t4){\n        if(t1==0&&t3!=0){\n            printf(\"0\");\n        }else{\n            printf(\"1\")\n        }\n    }else{\n        printf(\"0\");\n    }\n /*   if(t3==0){\n        if(t1==t4)printf(\"1\");\n        else printf(\"0\");\n    }else{\n        if(t1==0||t4==0)printf(\"0\");\n        else if(t1==t4)printf(\"1\");\n        else printf(\"0\");\n    }*/\n}\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "972acba3c4ad20003fdfa6717b2b72a0", "src_uid": "b99578086043537297d374dc01eeb6f8", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    long int N,S=0,T=0;\n    int i,k=0;\n\n    for(i=1; i<=4; i++)\n    {\n        scanf(\"%ld\", &N);\n        if(i==1)\n        {\n            S=S+(N*2);\n            k++;\n        }\n\n        else if(i==2)\n        {\n            S=S+N;\n            T=T+N;\n            k++\n        }\n\n        else if(i==3)\n        {\n            S=S+N;\n            T=T+N;\n        }\n\n        else if(i==4)\n        {\n            T=T+(N*2);\n            k++;\n        }\n       \n    }\n    \n    if(S==T && k>0)\n    {\n        printf(\"1\\n\");\n    }\n    else\n    {\n        printf(\"0\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "93650bf938695de584eeb52b637f4f9e", "src_uid": "b99578086043537297d374dc01eeb6f8", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#including <stdio.h>\nint main()\n{\n\tint sign=1,done=1;\n\tfloat sum=1;\n\twhile (done<=100)\n\t{\n\t\tdone=done+1;\n\t\tsign=-1*sign;\n\t\tsum=sum+sign*1/done;\n\t}\n\tprintf (\"sum=%f\",sum);\n\treturn 0;\n } \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "85fc3cce66794ffdf27a474eea1e8ff8", "src_uid": "b99578086043537297d374dc01eeb6f8", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int a,b,c,d,i;\n    scnaf(\"%lld%lld%lld%lld\",&a,&b,&c,&d);\n    if(a==d)printf(\"1\\n\");\n    else printf(\"0\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c5f9921ba5aeb3d7d25b4e9b46938e07", "src_uid": "b99578086043537297d374dc01eeb6f8", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h> \n#include <string.h>\nint main () \n{\n\tint c1,c2,c3,c4;\n\tscanf(%d,&c1);\n\tscanf(%d,&c2);\n\tscanf(%d,&c3);\n\tscanf(%d,&c4);\n\tif(c1!=c4)\n\t{\n\t\tprintf(\"0\");\n\t\t\n\t}\n\telse\n\t{\n\t\tif c1==0  \n\t\t{\n\t\t\tif (c3==0)\n\t\t\t{\n\t\t\t\treturn 1;\n\t\t\t\t\n\t\t\t}\n\t\t\telse \n\t\t\t{\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\telse \n\t\t{\n\t\t\treturn 1;\n\t\t}\n\t\t\n\t}\n\t\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6552ae73ebfda30a3f1c839536559b72", "src_uid": "b99578086043537297d374dc01eeb6f8", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main(){\n    \n    int len;\n    charch[21];\n    gets(ch);\n    \n    l=strlen(ch);\n    \n    int ans=26*(l*25);\n    printf(\"%d\",ans);\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "195d0e8e503dcb5c0905c8c0992529c3", "src_uid": "556684d96d78264ad07c0cdd3b784bc9", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n\nint main{\nstring s;\nint a,b;\nscanf(\"%s\",&s);\na=s.length();\nb=((a*25)+26);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4adbcc4fd2adb02426202a071796c5fc", "src_uid": "556684d96d78264ad07c0cdd3b784bc9", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\n#include <time.h>\n\n#define lli long long int\n#define MAX INT_MAX\n#define sd second\n#define fs first\n#define endll '\\n'\n#define PI acos(-1)\n#define mp make_pair\n#define pb push_back\n#define best 1000000007\n#define FOR(i,a,b) for(int i=a;i<=b;i++)\n#define ROF(i,a,b) for(int i=a;i>b;i--)\n#define buyuk(a,b) (a<b)? b:a\n#define kucuk(a,b) (a<b)? a:b\n#define ort(a,b) (a+b)/2\n#define carp(a,b) (a)*(b)\nint main () {\n\tchar a[25];\n\n\tint main () {\n\t\tscanf(\"%s\",a);\n\t\tprintf(\"%d\",((int)strlen(a)+1)*25 + 1);\n\t}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1ee213c85f0df76ede4e50709bf06da5", "src_uid": "556684d96d78264ad07c0cdd3b784bc9", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>;\nchar a[106];\nint main()\n{   \n    char a[100];\n    int len,ans;\n    scanf(\"%s\",a);\n    len=strlen(a);\n    ans=25*(l+1)+1;\n    printf(\"%d\",ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ff762f48faa3325fb64e5f26b3ecae62", "src_uid": "556684d96d78264ad07c0cdd3b784bc9", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <iostream>\nusing namespace std;\nint main{\nstring s;\nint a,b;\ncin>>s;\na=s.length();\nb=((a*25)+26);\ncout<<b;\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4dd6a7bce744700bb4dc4250e889250e", "src_uid": "556684d96d78264ad07c0cdd3b784bc9", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n\nint main()\n{\n    int i, j, k, s1=0, s2=0, d, c1=0, c2=0, c=0;\n    char b[6];\n    int a[6];\n    for(i=0; i<6; ++i) {\n        scanf(\"%c\", &b[i]);\n        a[i] = b[i] - 48;\n    }\n\n    for(i=0; i<3; ++i)\n        s1+=a[i];\n\n    for(i=3; i<6; ++i)\n        s2+=a[i];\n\n    d = s1 - s2;\n\n    if(d>0){\n        for(i=0; i<3-1; ++i){\n            for(j=i; j<3; ++j){\n                if(a[i]<a[j]){\n                    a[i] = a[i] ^ a[j];\n                    a[j] = a[i] ^a[j];\n                    a[i] = a[i] ^ a[j];\n                }\n            }\n        }\n        for(i=3; i<6-1; ++i){\n            for(j=i; j<6; ++j){\n                if(a[i]>a[j]){\n                    a[i] = a[i] ^ a[j];\n                    a[j] = a[i] ^a[j];\n                    a[i] = a[i] ^ a[j];\n                }\n            }\n        }\n        i=0;\n        j=3;\n        while(d>=0 ){\n            if(a[i] > 9-a[j] && i<3){\n                c++;\n                i++;\n                d -= a[i];\n            }\n            else if(a[i] < 9-a[j] && j<6) {\n                c++;\n                j++;\n                d -= 9-a[j];\n            }\n        }\n        printf(\"%d\", c);\n    }\n    else if(d<0){\n        for(i=0; i<3-1; ++i){\n            for(j=i; j<3; ++j){\n                if(a[i]>a[j]){\n                    a[i] = a[i] ^ a[j];\n                    a[j] = a[i] ^a[j];\n                    a[i] = a[i] ^ a[j];\n                }\n            }\n        }\n        for(i=3; i<6-1; ++i){\n            for(j=i; j<6; ++j){\n                if(a[i]<a[j]){\n                    a[i] = a[i] ^ a[j];\n                    a[j] = a[i] ^a[j];\n                    a[i] = a[i] ^ a[j];\n                }\n            }\n        }\n        d = -d;\n        i=0;\n        j=3;\n        while(d>=0){\n            if(9-a[i] > a[j] && i<3){\n                c++;\n                i++;\n                d -= 9-a[i];\n            }\n            else if(9-a[i] < a[j] && j<6) {\n                c++;\n                j++;\n                d -= a[j];\n            }\n        }\n        printf(\"%d\", c);\n    }\n    else printf(\"0\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "79d4cc6c15304e6ae6c5b3931885b823", "src_uid": "09601fd1742ffdc9f822950f1d3e8494", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#define N\t6\n#define _GNU_SOURCE\n\n#include <stdbool.h>\n#include <stdio.h>\n#include <stdlib.h>\n\n#define V(a)\t\t\t((a).type == FIRST ? 9 - (a).value : (a).value)\n#define VALUE(a, positive)\t((positive) ? 9 - V(a) : V(a))\n\ntypedef struct {\n\tenum {FIRST, SECOND} type;\n\tint value;\n} digit_t;\n\ndigit_t a[N];\n\nvoid getdata(digit_t a[]) {\n\tfor (int i = N / 2; i < N; i++)\n\t\ta[i].type = SECOND;\n\tfor (int i = 0; i < N; i++)\n\t\ta[i].value = getchar() - '0';\n}\n\nint find_diff(digit_t a[]) {\n\tint sum = 0;\n\tfor (int i = 0; i < N / 2; i++)\n\t\tsum += a[i].value;\n\tfor (int i = N / 2; i < N; i++)\n\t\tsum -= a[i].value;\n\treturn sum;\n}\n\nint cmp(const void *p1, const void *p2, void *arg) {\n\tconst digit_t \n\t\t*a = p1,\n\t\t*b = p2;\n\tconst bool *positive = arg;\n\n\tint \n\t\tvalue1 = VALUE(*a, *positive), \n\t\tvalue2 = VALUE(*b, *positive);\n\treturn value1 - value2;\n}\n\nvoid solve(digit_t a[]) {\n\tint diff = find_diff(a);\n\tbool positive = diff > 0;\n\tqsort_r(a, N, sizeof *a, cmp, &positive);\n\n\tdiff = abs(diff);\n\tfor (int i = 0; i <= N; i++) {\n\t\tif (diff <= 0)  {\n\t\t\tprintf(\"%d\\n\", i);\n\t\t\texit(EXIT_SUCCESS);\n\t\t}\n\t\tdiff -= VALUE(a[N - i - 1], positive);\n\t\tfprintf(stderr, \"Used digit %d with value %d\\n\", a[N - i - 1].value, VALUE(a[N - i - 1], positive));\n\t}\n}\n\nint main(void) {\n\tgetdata(a);\n\tsolve(a);\n\treturn EXIT_SUCCESS;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4a5bd0921cca5ec573a1ef155f63acf8", "src_uid": "09601fd1742ffdc9f822950f1d3e8494", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint sum(int n) {\n\tint res;\n\n\tfor (res = 0; n > 0; n /= 10)\n\t\tres += n % 10;\n\n\treturn res;\n}\n\nint ndiff(int a, int b) {\n\tint res;\n\n\tfor (res = 0; a > 0 || b > 0; a /= 10, b /= 10)\n\t\tif (a % 10 != b % 10)\n\t\t\tres++;\n\n\treturn res;\n}\n\nint main(void) {\n\tint number;\n\n\tscanf(\"%d\", &number);\n\t//printf(\"%d\\n\", sum(number));\n\n\tint n1 = number % 1000;\n\tint n2 = number / 1000;\n\n\tint s1 = sum(n1);\n\tint s2 = sum(n2);\n\n\tint number2 = number;\n\tint n0 = number;\n\n\twhile (s1 != s2) {\n\t\tnumber++;\n\n\t\tn1 = number % 1000;\n\t\tn2 = number / 1000;\n\n\t\ts1 = sum(n1);\n\t\ts2 = sum(n2);\n\n\t\t//printf(\"%d\\n\", s1 - s2);\n\t}\n\n\tdo {\n\t\tnumber2--;\n\n\t\tn1 = number2 % 1000;\n\t\tn2 = number2 / 1000;\n\n\t\ts1 = sum(n1);\n\t\ts2 = sum(n2);\n\n\t\t//printf(\"%d\\n\", s1 - s2);\n\t} while (s1 != s2);\n\n\t//~ printf(\"%d\\n\", number);\n\t//~ printf(\"%d\\n\", number2);\n\n\t//~ printf(\"%d\\n\", ndiff(number, n0));\n\t//~ printf(\"%d\\n\", ndiff(number2, n0));\n\n\tint d1 = ndiff(number, n0);\n\tint d2 = ndiff(number2, n0);\n\n\tprintf(\"%d\\n\", d1 > d2 : d2 : d1);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "641b974863e2460eca75a47c7ea15291", "src_uid": "09601fd1742ffdc9f822950f1d3e8494", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main(int argc, char const *argv[])\n{\n\tint vec[6];\n\n\tfor (int i = 0; i < 6; ++i)\n\t{\n\t\tscanf(\"%1d\", vec + i);\n\t}\n\n\tif (vec[0] + vec[1] + vec[2]  == vec[3] + vec[4] +vec[5])\n\t{\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\n\tfor (int i = 0; i < 10; ++i)\n\t{\n\t\tif (vec[0] + vec[1] + i == vec[3] + vec[4] + vec[5])\n\t\t{\n\t\t\tprintf(\"1\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (vec[0] + vec[1] + vec[2] == i + vec[4] + vec[5])\n\t\t{\n\t\t\tprintf(\"1\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (vec[0] + i + vec[2] == vec[3] + vec[4] + vec[5])\n\t\t{\n\t\t\tprintf(\"1\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (vec[0] + vec[1] + vec[2] == vec[3] + i + vec[5])\n\t\t{\n\t\t\tprintf(\"1\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\telse if ( i + vec[1] + vec[2] == vec[3] + vec[4] + vec[5])\n\t\t{\n\t\t\tprintf(\"1\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (vec[0] + vec[1] + vec[2] == vec[3] + vec[4] + i)\n\t\t{\n\t\t\tprintf(\"1\\n\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\tfor (int j = 0; j < 10; ++j)\n\t{\n\t\tfor (int i = 0; i < 10; ++i)\n\t\t{\n\t\t\tif (vec[0] + j + i == vec[3] + vec[4] + vec[5])\n\t\t\t{\n\t\t\t\tprintf(\"2\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\telse if (j + vec[1] + i == vec[3] + vec[4] + vec[5])\n\t\t\t{\n\t\t\t\tprintf(\"2\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\telse if (j + i + vec[2] == vec[3] + vec[4] + vec[5])\n\t\t\t{\n\t\t\t\tprintf(\"2\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\telse if (vec[0] + vec[1] + vec[2] == i + j + vec[5])\n\t\t\t{\n\t\t\t\tprintf(\"2\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\telse if (vec[0] + vec[1] + vec[2] == i + vec[4] + j)\n\t\t\t{\n\t\t\t\tprintf(\"2\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\telse if (vec[0] + vec[1] + vec[2] == vec[3] + i + j)\n\t\t\t{\n\t\t\t\tprintf(\"2\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\telse if (j + vec[1] + vec[2] == i + vec[4] + vec[5])\n\t\t\t{\n\t\t\t\tprintf(\"2\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\telse if (vec[0] + j + vec[2]  == i + vec[4] +vec[5])\n\t\t\t{\n\t\t\t\tprintf(\"2\\n\", contd);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\telse if (vec[0] + vec[1] + j  == i + vec[4] +vec[5])\n\t\t\t{\n\t\t\t\tprintf(\"2\\n\", contd);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\telse if (j + vec[1] + vec[2] == vec[3] + i + vec[5])\n\t\t\t{\n\t\t\t\tprintf(\"2\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\telse if (vec[0] + j + vec[2]  ==  vec[3] + i +vec[5])\n\t\t\t{\n\t\t\t\tprintf(\"2\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\telse if (vec[0] + vec[1] + j  ==  vec[3] + i + vec[5])\n\t\t\t{\n\t\t\t\tprintf(\"2\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\telse if (j + vec[1] + vec[2] ==  vec[3] + vec[4] + i)\n\n\t\t\t{\n\t\t\t\tprintf(\"2\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\telse if (vec[0] + j + vec[2]  ==  vec[3] + vec[4] + i)\n\t\t\t\t\t\t\t{\n\t\t\t\tprintf(\"2\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\telse if (vec[0] + vec[1] + j  ==  vec[3] + vec[4] + i)\n\t\t\t\t\t\t\t{\n\t\t\t\tprintf(\"2\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int  k = 0; k < 10; ++k)\n\t{\n\t\tfor (int j = 0; j < 10; ++j)\n\t\t{\n\t\t\tfor (int i = 0; i < 10; ++i)\n\t\t\t{\n\t\t\t\tif (k + j + i == vec[3] + vec[4] + vec[5])\n\t\t\t\t{\n\t\t\t\t\tprintf(\"3\\n\");\n\t\t\t\t\treturn 0;\n\t\t\t\t}\n\t\t\t\telse if (vec[0] + vec[1] + vec[2] == i + j + k)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"3\\n\");\n\t\t\t\t\treturn 0;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t}\n\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dfe7ece194555bad9a969c99b3b6daae", "src_uid": "09601fd1742ffdc9f822950f1d3e8494", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint array[6]={0};\n\tint t1=0,t2=0,s=0,t,a=0,b;\n\tfor(int i=0;i<3;i++)\n\t{\n\t\tscanf(\"%c\",&b);\n\t\tb-=48;\n\t\tt1+=b;\n\t}\n\tfor(int i=3;i<6;i++)\n\t{\n\t\tscanf(\"%c\",&b);\n\t\tb-=48;\n\t\tt2+=b;\n\t}\n\tfor(int i=0;i<3;i++)\n\t{\n\t\tfor(int k=i+1;k<3;k++)\n\t\t{\n\t\t\tif(array[k]<array[i])\n\t\t\t{\n\t\t\t\tt=array[k];\n\t\t\t\tarray[k]=array[i];\n\t\t\t\tarray[i]=t;\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i=3;i<6;i++)\n\t{\n\t\tfor(int k=i+1;k<6;k++)\n\t\t{\n\t\t\tif(array[k]<array[i])\n\t\t\t{\n\t\t\t\tt=array[k];\n\t\t\t\tarray[k]=array[i];\n\t\t\t\tarray[i]=t;\n\t\t\t}\n\t\t}\n\t}\n\tif(t1>t2)\n\t{\n\t\tfor(int i=3;i<6;i++)\n\t\t{\n\t\t\ta+=9-array[i];\n\t\t\ts++;\n\t\t\tif(t1-t2<a) break;\n\t\t}\n\t}\n\telse if(t2>t1)\n\t{\n\t\tfor(int i=0;i<3;i++)\n\t\t{\n\t\t\ta+=9-array[i];\n\t\t\ts++;\n\t\t\tif(t2-t1<a) break;\n\t\t}\n\t}\n\tprintf(\"%d\\n\", s);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "fc54f6c6d5b6aa1b9381e0d95eb43649", "src_uid": "09601fd1742ffdc9f822950f1d3e8494", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint judge(long long int N,long long int n,long long int m,long long int k)\n{\n    long long int i,count=0;\n    for(i=1;i<=m;i++){\n        if(N/i>=n){\n            count+=n;\n        }\n        else{\n            count+=N/i;\n        }\n    }\n    if(count>=k){\n        return 1;\n    }\n    else{\n        return 0;\n    }\n}\n\nint main(void)\n{\n    long long int n,m,k;\n    scanf(\"%I64d %I64d %I64d\",&n,&m,&k);\n    long long int i,j;\n    long long int low,mid,high,answer;\n    low=0;\n    high=n*m;\n    mid=(low+high)/2;\n    while(1){\n        if(judge(mid,n,m,k)==1){\n            if(judge(mid-1,n,m,k)==0){\n                answer=mid;\n                break;\n            }\n            else{\n                high=mid;\n                mid=(low+high)/2;\n            }\n        }\n        else{\n            low=mid;\n            mid=(low+high)/2;\n        }\n    }\n    printf(\"%I64d\",answer);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a410abcdff1e7d063a63761ede4e2dfc", "src_uid": "13a918eca30799b240ceb9de47507a26", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main(void)\n{\n    long long int n,m,k;\n    scanf(\"%I64d %I64d %I64d\",&n,&m,&k);\n    long long int i,j;\n    long long int count,answer;\n    if(k==n*m){\n        printf(\"%I64d\",k);\n        return 0;\n    }\n    for(i=1;i<=n*m;i++){\n        count=0;\n        for(j=1;j<=m;j++){\n            if(i/j>=n){\n                count+=n;\n            }\n            else{\n                count+=i/j;\n            }\n            if(count>=k){\n                answer=i;\n                printf(\"%I64d\",answer);\n                return 0;\n            }\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b9ccac357cb5a82c67c2677cd62353d5", "src_uid": "13a918eca30799b240ceb9de47507a26", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tlong long n,m,i,b,k,j,c=1,a[100005];\n\tscanf(\"%I64d %I64d %I64d\",&n,&m,&k);\n\tlong long l=0,r=m*n,mid=0,s=0;\n\tfor(i=1;i<=n;i++)\n\t\t{\n\t\t\tfor(j=1;j<=m;j++)\n\t\t\t{\n\t\t\t\ta[c]=i*j;\n\t\t\t\tc++;\n\t\t\t}\n\t\t}\n\tfor(i=1;i<c;i++)\n\t{\n\t\tfor(j=i+1;j<c;j++)\n\t\t{\n\t\t\tif(a[i]>a[j])\n\t\t\t{\n\t\t\t\tb=a[i];a[i]=a[j];a[j]=b;\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"%I64d\",a[k]);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7ec10fb5cbc2c75d5d5f3167ce79d0ec", "src_uid": "13a918eca30799b240ceb9de47507a26", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<limits.h>\nint n, m, k;\nint bs2(int multi,int x)\n{\n\tint mid, left = 0, right = m;\n\twhile (left <= right)\n\t{\n\t\tmid = (left + right) / 2;\n\t\tif (x >= mid * multi && x < (mid + 1)*multi)\n\t\t{\n\t\t\t//printf(\"\u7b2c%d\u884c\u6709%d\u4e2a\\n\", multi, mid);\n\t\t\treturn mid;\n\t\t}\n\t\tif (mid*multi < x)\n\t\t\tleft = mid + 1;\n\t\telse\n\t\t\tright = mid - 1;\n\t}\n\t//printf(\"\u7b2c%d\u884c\u6709%d\u4e2a\\n\", multi, mid);\n\treturn mid;\n}\nint judge(int x)//\u5c0f\u4e8e\u7b49\u4e8ex\u7684\u6570\u6709\u591a\u5c11\u4e2a\n{\n\tint i, count = 0;\n\tfor (i = 1; i <= n; i++)\n\t{\n\t\tcount += bs2(i, x);\n\t}\n\treturn count;\n}\nint bs1(int left,int right)\n{\n\tint mid;\n\twhile (left <= right)\n\t{\n\t\tmid = (left + right) / 2;\n\t/*\tprintf(\"\u5c0f\u4e8e\u7b49\u4e8e%d\u7684\u6570\u6709\u591a\u5c11\\n\", mid);*/\n\t\tint count1 = judge(mid),count2 = judge(mid-1);\n\t\tif (k <= count1 && k > count2)\n\t\t\treturn mid;\n\t\tif (k >= count1)\n\t\t\tleft = mid + 1;\n\t\telse right = mid - 1;\n\t}\n\t//printf(\"%d %d\\n\", mid, mid - 1);\n\treturn mid;\n}\nint main()\n{\n\tscanf(\"%d %d %d\", &n, &m, &k);\n\tprintf(\"%d\", bs1(1, n*m));\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e53595158b4589a75201998ace131202", "src_uid": "13a918eca30799b240ceb9de47507a26", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n\nvoid merge(long long arr[],int mid,int last){\n\n        int i=0,j;\n        j=mid+1;\n        int c=0;\n        long long mer[last+1];\n\n        while(i<=mid && j<=last){\n            if(arr[i]<=arr[j]){\n                mer[c]=arr[i];\n                i++;c++;\n            }\n            else{\n                mer[c]=arr[j];\n                j++;c++;\n            }\n        }\n        int k;\n        if(i>mid){\n            for(k=j;k<=last;k++){\n                mer[c]=arr[k];\n                c++;\n            }\n        }\n        else{\n            for(k=i;k<=mid;k++){\n                mer[c]=arr[k];\n                c++;\n            }\n        }\n        for(k=0;k<=last;k++){\n            arr[k]=mer[k];\n        }\n\n}\n\n\n\nint main()\n{\n    int n,m;\n    int i,j;\n    long long k;\n    int c=0;\n    scanf(\"%d %d %I64d\",&n,&m,&k);\n    long long arr[n*m];\n    int f=0;\n    for(i=1;i<=n;i++){\n         int temp=c-1;\n        for(j=1;j<=m;j++){\n            arr[c]=i*j;\n            c++;\n        }\n        if(f==1){\n            merge(arr,temp,c);\n        }\n        f=1;\n    }\n\n    printf(\"\\n\");\n    printf(\"%I64d\",arr[k-1]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "89d4f8a82782954bb33b91c69b6fa141", "src_uid": "13a918eca30799b240ceb9de47507a26", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\nint compare (const void * a, const void * b)\n{\n  return ( *(int*)a - *(int*)b );\n}\n\nint mask(int x){\n    int k = 0, t = 1;\n\twhile (x > 0) {\n\t    if (x % 10 == 7 || x % 10 == 4) {\n\t\t    k += x%10*t;\n\t\t\tt *= 10;\n\t\t}\n\t\tx = x/10;\n\t}\n\treturn(k);\n}\n\nint main() {\n    int a, b, i;\n\tscanf(\"%d %d\",&a,&b);\n\tprintf(\"%d %d\\n\",a,b);\n\tfor (i = a;mask(i) != b;i++);\n\tprintf(\"%d\\n\",i);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e5d560fdde0360ed61240af50740956d", "src_uid": "e5e4ea7a5bf785e059e10407b25d73fb", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\nint compare (const void * a, const void * b)\n{\n  return ( *(int*)a - *(int*)b );\n}\n\nint mask(int x){\n    int k = 0, t = 1;\n\twhile (x > 0) {\n\t    if (x % 10 == 7 || x % 10 == 4) {\n\t\t    k += x%10*t;\n\t\t\tt *= 10;\n\t\t}\n\t\tx = x/10;\n\t}\n\treturn(k);\n}\n\nint main() {\n    int a, b, i;\n\tscanf(\"%d%d\",&a,&b);\n\tfor (i = a;mask(i) != b;i++);\n\tprintf(\"%d\\n\",i);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6c6bafcf53f8618f20578b86014179d5", "src_uid": "e5e4ea7a5bf785e059e10407b25d73fb", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\nint compare (const void * a, const void * b)\n{\n  return ( *(int*)a - *(int*)b );\n}\n\nint mask(int x){\n    int k = 0, t = 1;\n\twhile (x > 0) {\n\t    if (x % 10 == 7 || x % 10 == 4) {\n\t\t    k += x%10*t;\n\t\t\tt *= 10;\n\t\t}\n\t\tx = x/10;\n\t}\n\treturn(k);\n}\n\nint main() {\n    int a, b, i;\n\tscanf(\"%d%d\",&a,&b);\n//\tprintf(\"%d %d\\n\",a,b);\n\tfor (i = a;mask(i) != b;i++);\n\tprintf(\"%d\",i);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "64c474b2ead650560a0e70072426de75", "src_uid": "e5e4ea7a5bf785e059e10407b25d73fb", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<math.h>\n\nint main()\n{\n    char s_a[6], s_b[6], s_c[7];\n    char t_s_a[6], t_s_b[6];\n    char plus_1[10] = \"1234567890\";\n    char plus_2[10] = \"2345678901\";\n    int i_a, i_b, i_c, n_a, n_b, n_c;\n    int t_n_a, t_n_b; \n    int i;\n    int c_point;\n    \n    sprintf(s_c,\"%d\", 0);\n    scanf(\"%d %d\", &i_a, &i_b);\n    sprintf(s_a,\"%d\",i_a);\n    sprintf(s_b,\"%d\",i_b);\n    n_a = strlen(s_a);\n    n_b = strlen(s_b);\n    strcpy(t_s_a, s_a);\n    strcpy(t_s_b, s_b);\n    //printf(\"%s %s %d %s %d\\n\",s_c, s_a, n_a, s_b, n_b);    \n\n    if(i_a < i_b){\n        i_c = i_b;\n        sprintf(s_c,\"%d\", i_c);\n        printf(\"%s\", s_c);\n        return 0;\n    }else if( i_a >= i_b && n_a == n_b){\n        i_c = i_b + pow(10,n_b);\n        sprintf(s_c,\"%d\", i_c);\n        printf(\"%s\", s_c);\n        return 0;\n    }\n    \n    t_n_a = n_a;\n    t_n_b = n_b;\n    n_c = n_a;\n    \n    //return 0;\n    c_point = 0;\n    while(t_n_a != t_n_b){\n        if((t_s_a[0] == '4' && t_s_b[0]== '7') || (t_s_a[0] == '7' && t_s_b[0]== '4')){\n            s_c[c_point] = plus_1[t_s_a[0]-48];\n            printf(\"\\n%c\",s_c[0]);\n            return 0;\n        }\n    }\n    \n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "79e69022a42758f7985a970dd410ab7f", "src_uid": "e5e4ea7a5bf785e059e10407b25d73fb", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint flag=0,b;\nvoid mask(int c)\n{\n\tint d=c,arr[100002],a[100002]={0};\n\tint i=0;\n\twhile(d>0)\n\t{\n\t\tif(d%10==4 || d%10==7)\n\t\t{\n\t\t\tarr[i]=d%10;\n\t\t\ti++;\n\t\t}\n\t\td=d/10;\n\t}\n\tint ans=0;\n\t\tfor(int j=0;j<i;j++)\n\t\t{\n\t\t\tans=ans+arr[j]*pow(10,j);\n\t\t}\n\tif(ans==b)\n\t\tflag=1;\n//\t\tprintf(\"\\n\");\n\tint e=b,count=0;\n/*\tif(i!=0)\n\t{\n\t\twhile(e>0)\n\t\t{\n\t\t\tif(e%10==arr[i-count-1])\n\t\t\t{\n\t\t\t\tcount++;\n\t\t\t}\n\t\t\te=e/10;\n\t\t}\n\t\tif(count==i)\n\t\t{\n\t\t\tflag=1;\n\t\t}\n\t}*/\n}\nint main()\n{\n\tint a;\n\tint c;\n\tscanf(\"%d\",&a);\n\tscanf(\"%d\",&b);\n\tc=a+1;\n\twhile(c>a)\n\t{\n\t\tmask(c);\n\t\tif(flag==1)\n\t\t{\n\t\t\tprintf(\"%d\\n\",c);\n\t\t\tbreak;\n\t\t}\n\t\tc++;\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "873274ae15ac77b6976bf49e68d09132", "src_uid": "e5e4ea7a5bf785e059e10407b25d73fb", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include<stdlib.h>\n\nint main(void) {\n\tint s,x1,x2,t1,t2,p,d,tt,tf;\n\tscanf(\"%d %d %d\",&s,&x1,&x2);\n\tscanf(\"%d %d\",&t1,&t2);\n\tscanf(\"%d %d\",&p,&d);\n\t\n\ttf=abs(x2-x1)*t2;\n\t\n    if(p>x1&&d==1&&x2>x1)\n        tt=(2*s-p+x2)*t1;\n    else if(p>x1&&d==1&&x2<x1)\n        tt=(2*s-p-x2)*t1;\n    else if(p>x1&&d==-1&&x2>x1)\n        tt=(p+x2)*t1;\n    else if(p>x1&&d==-1&&x2<x1)\n        tt=(p-x2)*t1;\n    else if(p<=x1&&d==1&&x2>x1)\n        tt=(x2-p)*t1;\n    else if(p<=x1&&d==1&&x2<x1)\n        tt=(2*s-p-x2)*t1;\n    else if(p<=x1&&d==-1&&x2>x1)\n        tt=(x2+p)*t1;\n    else if(p<=x1&&d==-1&&x2<x1)\n        tt=(2*s+p-x2)*t1;\n    \n    printf(\"%d \",tt) ;   \n    if(tf>=tt)\n        printf(\"%d\",tt);\n    else\n        printf(\"%d\",tf);\n\t\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "82e308ad6d6dd7fc038af1ee2099a164", "src_uid": "fb3aca6eba3a952e9d5736c5d8566821", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint Min(int a, int b)\n{\n    return a < b ? a:b;\n}\nint main()\n{\n    int n,x1,x2,t1,t2,p,d;\n    int t3,t4,ans;\n    while(scanf(\"%d %d %d\",&n,&x1,&x2)==3)\n    {\n        scanf(\"%d %d %d %d\",&t1,&t2,&p,&d);\n        if(x2 > x1)\n        {\n            t3 = (x2 - x1) * t2;\n            if(d == 1)\n            {\n                if(p > x1)\n                    t4 = (n - p + n * 2) * t1;\n                else\n                    t4 = (n - p) * t1;\n            }\n            else\n                t4 = (n + p) * t1;\n        }\n        else\n        {\n            t3 = (x1 - x2) * t2;\n            if(d == 1)\n                t4 = (n - p + n) * t1;\n            else\n            {\n                if(p < x1)\n                    t4 = (p + n * 2) * t1;\n                else\n                    t4 = (n - p) * t1;\n            }\n        }\n        ans = Min(t3, t4);\n        printf(\"%d\\n\",ans);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3596e16de8eb0c528695680c3e9ca5d8", "src_uid": "fb3aca6eba3a952e9d5736c5d8566821", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<stdlib.h>\n#include<string.h>\nlong long int min(long long int a,long long int b)\n{\n\tif(a<=b)\n\t\treturn a;\n\telse\n\t\treturn b;\n}\nint main()\n{\n\tlong long int s,x1,x2,t1,t2,p,d,temp1,temp2,ans;\n\tscanf(\"%lld %lld %lld\",&s,&x1,&x2);\n\tscanf(\"%lld %lld\",&t1,&t2);\n\tscanf(\"%lld %lld\",&p,&d);\n\tif(x1<x2)\n\t{\n\t\ttemp1=(x2-x1)*t2;\n\t\tif(d==1)\n\t\t{\n\t\t\tif(p<=x1)\n\t\t\t{\n\t\t\t\ttemp2=(x2-p)*t1;\n\t\t\t\tans=min(temp1,temp2);\n\t\t\t}\n\t\t\telse\n\t\t\t\tans=temp1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\ttemp2=(x2+p)*t1;\n\t\t\tans=min(temp1,temp2);\n\t\t}\n\t}\n\telse\n\t{\n\t\ttemp1=t2*(x1-x2);\n\t\tif(d==-1)\n\t\t{\n\t\t\tif(p<=x1)\n\t\t\t{\n\t\t\t\ttemp2=t1*(x2-p);\n\t\t\t\tans=min(temp1,temp2);\n\t\t\t}\n\t\t\telse\n\t\t\t\tans=temp1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\ttemp2=t1*(s+s-p-x2);\n\t\t\tans=min(temp1,temp2);\n\t\t}\n\t}\n\tprintf(\"%lld\\n\",ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8d2119f133ac049f57c833a7753c247e", "src_uid": "fb3aca6eba3a952e9d5736c5d8566821", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include<stdlib.h>\n\nint main(void) {\n\tint s,x1,x2,t1,t2,p,d,tt,tf;\n\tscanf(\"%d %d %d\",&s,&x1,&x2);\n\tscanf(\"%d %d\",&t1,&t2);\n\tscanf(\"%d %d\",&p,&d);\n\t\n\ttf=abs(x2-x1)*t2;\n\t\n    if(p>x1&&d==1&&x2>x1)\n        tt=(2*s-p+x2)*t1;\n    else if(p=>x1&&d==1&&x2<x1)\n        tt=(2*s-p-x2)*t1;\n    else if(p>x1&&d==-1&&x2>x1)\n        tt=(p+x2)*t1;\n    else if(p>=x1&&d==-1&&x2<x1)\n        tt=(p-x2)*t1;\n    else if(p<=x1&&d==1&&x2>x1)\n        tt=(x2-p)*t1;\n    else if(p<x1&&d==1&&x2<x1)\n        tt=(2*s-p-x2)*t1;\n    else if(p<=x1&&d==-1&&x2>x1)\n        tt=(x2+p)*t1;\n    else if(p<x1&&d==-1&&x2<x1)\n        tt=(2*s+p-x2)*t1;\n    \n    //printf(\"%d \",tt) ;   \n    if(tf>=tt)\n        printf(\"%d\",tt);\n    else\n        printf(\"%d\",tf);\n\t\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "037f79d88bc7fb9c0bc43ef925e9d389", "src_uid": "fb3aca6eba3a952e9d5736c5d8566821", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main(){\n    int x;\n    int s ,x1,x2,t1,t2,p,d;\n    scanf(\"%d%d%d%d%d%d%d\",&s,&x1,&x2,&t1,&t2,&p,&d);\n    if(t1>=t2){\n        printf(\"%d\",abs(x2-x1)*t2);\n    }\n    else if(x2>x1){\n        if(p<=x1&&d==1){\n            x=((x1-p)*t1)/(t2-t1);\n            if(x>=(x2-x1)){\n                printf(\"%d\",(x2-x1)*t2);\n            }\n            else {\n                printf(\"%d\",(x2-p)*t1);\n            }\n        }\n        else if(p<=x1&&d==-1){\n            x=((p+x1)*t1)/(t2-t1);\n            if(x>=x2-x1){\n                printf(\"%d\",(x2-x1)*t2);\n            }\n            else{\n                printf(\"%d\",(p+x2)*t1);\n            }\n        }\n        else if(p>x1&&d==1){\n            x=(s-p+s+x1)/(t2-t1);\n            if(x>=x2-x1){\n                printf(\"%d\",(x2-x1)*t2);\n            }\n            else{\n                printf(\"yes %d\",(s-p+s+x2)*t1);\n            }\n        }\n        else {\n            x=(p+x1)/(t2-t1);\n            if(x>=x2-x1){\n                printf(\"%d\",(x2-x1)*t2);\n            }\n            else{\n                printf(\"%d\",(p+x2)*t1);\n            }\n        }\n    }\n    else{\n        if(p>=x1&&d==-1){\n            x=((-x1+p)*t1)/(t2-t1);\n            if(x>=abs(-x2+x1)){\n                printf(\"%d\",-(x2-x1)*t2);\n            }\n            else {\n                printf(\"%d\",-(x2-p)*t1);\n            }\n        }\n        else if(p>=x1&&d==1){\n            x=((s-p+s-x1)*t1)/(t2-t1);\n            if(x>=abs(x2-x1)){\n                printf(\"%d\",(x2-x1)*t2);\n            }\n            else{\n                printf(\"%d\",(s-p+s-x2)*t1);\n            }\n        }\n        else if(p<x1&&d==-1){\n            x=(p+s+s-x2)*t1);\n            if(x>=abs(x2-x1)){\n                printf(\"%d\",(x2-x1)*t2);\n            }\n            else{\n                printf(\"%d\",x);\n            }\n        }\n        else {\n            \n            x=(s-p+s-x1)/(t2-t1);\n            if(x>=abs(x2-x1)){\n                printf(\"%d\",(x2-x1)*t2);\n            }\n            else{\n                printf(\"%d\",(s-p+s-x2)*t1);\n            }\n        }\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b065dd605f79654a7f8b0a6a6c1a5d74", "src_uid": "fb3aca6eba3a952e9d5736c5d8566821", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,b=0,c=0;\n    scanf(\"%d\",&n);\n    int a[n];\n    for(int i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        if(a[i]>=0)\n            b++a[i];\n        else\n            c+=a[i];\n    }\n    printf(\"%d\",b-c);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2be9bd24d42cb79608d9459d5aca7d0d", "src_uid": "4b5d14833f9b51bfd336cc0e661243a5", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n\tint a[100];\n\tint b;\n\tint c;\n\tint j;\n\tscanf(\"%d\",&j);\n\tfor(int i=0;i<j;i++)\n\t\tscanf(\"%d\",&a[i]);\n\tfor(i=0;i<j;i++)\n\t{\n\t\tif(a[i]>=0)\n\t\t\tb=b+a[i];\n\t\telse\n\t\t\tc=c+a[i];\n\t}\n\tprintf(\"%d\",b-c);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d0920a3d087f1b6f004785d884e98a09", "src_uid": "4b5d14833f9b51bfd336cc0e661243a5", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"Partition\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/Partition\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/Partition\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2b09e3b0afcad4eedac654047b99b7f3", "src_uid": "4b5d14833f9b51bfd336cc0e661243a5", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint man()\n{\n    int arr[105],i,B=0,C=0,n;\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++){\n    scanf(\"%d\",&arr[i]);\n    }\n    for(i=0;i<n;i++){\n        if(arr[i]<0) C=C+1;\n        else B=B+1;\n    }\n    printf(\"%d\",B-C);\n    return 0;\n    \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "99522780f9daddec2697c68658b0aa7b", "src_uid": "4b5d14833f9b51bfd336cc0e661243a5", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint man()\n{\n    int arr[105],i,B=0,C=0,n;\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++){\n    scanf(\"%d\",&arr[i]);\n    }\n    for(i=0;i<n;i++){\n        if(arr[i]<0) C=C+arr[i];\n        else B=B+arr[i];\n    }\n    printf(\"%d\",B-C);\n    return 0;\n    \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bffd044b22d3bf36112e90d641f81f58", "src_uid": "4b5d14833f9b51bfd336cc0e661243a5", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main()\n{\n    float x, y, n, a, b, min=10000000, ansb;\n    int i;\n    scanf(\"%f %f %f\", &x, &y, &n);\n    if(y<=n)\n        printf(\"%d/%d\\n\", (int)x, (int)y);\n    else\n    {\n        b=n-1;\n        if(b==0)\n        {\n            printf(\"0/1\\n\");\n            return 0;\n        }\n        for(b=n-1; b>0; b--)\n        {\n            for(i=b-1; i>0; i--)\n            {\n                float temp=(float)i;\n                float temp1=x/y;\n                float temp2=temp/b;\n                //printf(\"x/y=%f i/b=%f abs=%f\\n\", temp1, temp2, fabs(temp1-temp2));\n                if(fabs(temp1-temp2)<min)\n                {\n                    min=fabs(temp1-temp2);\n                    a=temp;\n                    ansb=b;\n                }\n            }\n        }\n        int inta=(int)a, intb=(int)ansb;\n        i=inta; \n        if(intb<i)\n            i=intb;\n        for(i=intb; i>1; i--)\n        {\n            if(inta%i==0 && intb%i==0)\n            {\n                inta/=i;\n                intb/=i;\n                i--;\n            }\n        }\n        printf(\"%d/%d\\n\", inta, intb);\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "46f1df5baf8fc155d72d6f8f5c3dedae", "src_uid": "827bc6f120aff6a6f04271bc84e863ee", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<stdlib.h>\n#include<float.h>\nint gcd(int x,int y)\n{\n    if(y==0)\n\treturn x;\n    else return gcd(y,x%y);\n}\nint main()\n{\n    int a,b,n,g,i,j,num,den;\n    float prev=FLT_MIN,min,prev2=FLT_MAX,least=FLT_MAX,temp;\n    scanf(\"%d%d%d\",&a,&b,&n);\n    min= (float)a/(float)b;\n    g=gcd(a,b);\n    a=a/g;\n    b=b/g;\n    if(b<=n)\n\tprintf(\"%d/%d\\n\",a,b);\n    else\n    {\n\tfor(i=n;i>=1;i--)\n\t{\n\t    for(j=a;j>=0;j--)\n\t    {\n\t\ttemp=(float)j/(float)i;\n\t\tif( least >= fabsf(min-temp) )\n\t\t{\n\t\t    num=j;\n\t\t    den=i;\n\t\t    least=fabsf(min-temp);\n\t\t}\n\t//\tprintf(\"min: %f temp :%f least%f j:%d i:%d num:%d den:%d\\n\",min,temp,least,j,i,num,den);\n\t\tif((min>temp && temp<prev) || (min<temp && temp>prev2 ))\n\t\t{\n\t\t    break;\n\t\t}\n\t\t    prev=temp;\n\t\t//\telse if(fabsf(temp<least)\n\t\t//\t{\n\t\t//\t    break;\n\t\t//\t}\n\t    }\n\t    //\tbreak;\n\t}\n\tprintf(\"%d/%d\\n\",num,den);\n    }\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "089e241214abe081602a22d176d860d8", "src_uid": "827bc6f120aff6a6f04271bc84e863ee", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <conio.h>\n#include <math.h>\n\n\nint main()\n{\n    int x, y, n, i;\n    double min = 9999999, c, tmpmin;\n    int p, a, b;\n    scanf(\"%d %d %d\", &x, &y,&n);\n    for (i = 1; i <= n; i++)\n    {\n        c = x*i / (y*1.0);\n        p = floor(c+0.49999999999);\n        tmpmin = fabs((x*1.0) / y - (p*1.0) / i);\n        if (min > tmpmin)\n        {\n            min = tmpmin;\n            a = p;\n            b = i;\n        }\n    }\n    printf(\"%d/%d\", a, b);\n    _getch();\n    return 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "bdd741f3912bcd5918454e539c4c2b2d", "src_uid": "827bc6f120aff6a6f04271bc84e863ee", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint main(){\n    int x, y, n;\n    scanf(\"%d %d %d\", &x, &y, &n);\n\n    int a, b, i;\n    double ratio = (double)x/y;\n\n    double sol = 10000000;\n    double dist;\n    for (i=1;i<=n;i++){\n        int j = roundtol(ratio * i);\n        if (ratio*i - floor(ratio*i) == 0.5){\n            j = (int)(ratio*i);\n        }\n        dist = fabs(ratio - (double)j/i);\n        if (sol>dist){\n            sol = dist;\n            b = i;\n            a = j;\n        }\n    }\n\n    printf(\"%d/%d\\n\", a, b);\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "283c9b125db3ac148d6ea5a95f6cf971", "src_uid": "827bc6f120aff6a6f04271bc84e863ee", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <conio.h>\n#include <math.h>\n\n\nint main()\n{\n    int x, y, n, i;\n    double min = 9999999, c, tmpmin;\n    int p, a, b;\n    scanf(\"%d %d %d\", &x, &y,&n);\n    for (i = 1; i <= n; i++)\n    {\n        c = x*i / (y*1.0);\n        p = floor(c+0.4999999999);\n        tmpmin = fabs((x*1.0) / y - (p*1.0) / i);\n        if (min > tmpmin)\n        {\n            min = tmpmin;\n            a = p;\n            b = i;\n        }\n    }\n    printf(\"%d/%d\", a, b);\n    return 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c8721201abe8633d2d5a6a000f040219", "src_uid": "827bc6f120aff6a6f04271bc84e863ee", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<cmath>\nusing namespace std;\nint main(){\n    int a,b;\n    cin>>a>>b;\n    int c = (a+b)/2;\n    int p =0;\n    for(int i = 0;i<=abs(c-a);i++)\n        p += i;\n    for(int j = 0;j<=abs(c-b);j++)\n        p += j;\n    cout<<p<<endl;\n    return 0;\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8e518b2d7b0af84a2ba4d8dc6a8b7445", "src_uid": "d3f2c6886ed104d7baba8dd7b70058da", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "main(a,b){scanf(\"%d%d\",&a,&b);if(a>b)swap(a,b);printf(\"%d\\n\",(((a+b)>>1)-a)*(((a+b)>>1)-a+1)/2+(b-((a+b)>>1))*(b-((a+b)>>1)+1)/2);}", "lang_cluster": "C", "compilation_error": true, "code_uid": "233697a757f504810395b90780432b88", "src_uid": "d3f2c6886ed104d7baba8dd7b70058da", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<stdlib.h>\nusing namespace std;\nint main(void)\n{\n\n\n    int nA,nB,T;\n    int a,b;\n    cin>>a;\n    cin>>b;\n    if((b-a)%2==0)\n    {\n        nA=nB=abs((b-a)/2);\n    }\n    else {\n\n           nA=abs((b-a)/2);\n           nB=nA+1;\n    }\n\n    T=nA*(nA+1)/2 + nB*(nB+1)/2;\n    cout<<T;\n\n\n\n\n\n\n\n\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3dea2e1bf98666c75986fac9bb09b2b3", "src_uid": "d3f2c6886ed104d7baba8dd7b70058da", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "if(a > b)\n    {\n        k = (a - b) % 2;\n        if(k != 0)\n        {\n            k = 0;\n            for(i = (a-b)/2; i > 0; i --)\n            {\n                if(i < (a-b)/2)\n                {\n                    c += i;\n                }\n                k += i;\n            }\n            printf(\"%d\", k+c);\n        }\n        else\n        {\n            k = 0;\n            for(i = (a-b)/2; i > 0; i --)\n            {\n                k += i;\n            }\n            k *= 2;\n            printf(\"%d\", k);\n        }\n    }", "lang_cluster": "C", "compilation_error": true, "code_uid": "8e8cd383180c8c72b99018bd521b5ffb", "src_uid": "d3f2c6886ed104d7baba8dd7b70058da", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "# include <stdio.h>\nint main ()\n{\n    int a, b, c = 0, k, i;\n    scanf(\"%d %d\", &a, %b);\n    if(a > b)\n    {\n        k = (a - b) % 2;\n        if(k != 0)\n        {\n            k = 0;\n            for(i = (a-b)/2; i > 0; i --)\n            {\n                if(i > (a-b)/2)\n                {\n                    c += i;\n                }\n                k += i;\n            }\n        }\n        else\n        {\n            k = 0;\n            for(i = (a-b)/2; i > 0; i --)\n            {\n                k += i;\n            }\n            k *= 2;\n        }\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7d212ce0c855304cee254a69f77dc00d", "src_uid": "d3f2c6886ed104d7baba8dd7b70058da", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n  {\n  \tchar n[10], m[10];\n  \tint dd, mm, yy, bd, bm, by, i, a, b, c, flag=0;\n  \tscanf(\"%s\", n);\n\tscanf(\"%s\", m);\n  \tdd = (n[0] - '0')*10 + n[1] - '0';\n  \tmm = (n[3] - '0')*10 + n[4] - '0'; \n  \tyy = (n[6] - '0')*10 + n[7] - '0';\n  \t\n  \tbd = (m[0] - '0')*10 + m[1] - '0';\n  \tbm = (m[3] - '0')*10 + m[4] - '0';\n  \tby = (m[6] - '0')*10 + m[7] - '0';\n  \t\n  \tfor(i=0; i<6; i++)\n  \t  {\n  \t  \tif(i == 0)\n  \t  \t  {\n  \t  \t  \ta = bd;\n  \t  \t  \tb = bm;\n  \t  \t  \tc = by;\n\t\t  }\n  \t  \tif(i == 1)\n  \t  \t  {\n  \t  \t  \ta=by;\n  \t  \t  \tb=bm;\n  \t  \t  \tc=bd;\n\t\t  }\n\t\tif(i == 2)\n\t\t  {\n\t\t  \ta=by;\n\t\t  \tb=bd;\n\t\t  \tc=bm;\n\t\t  }\n\t\tif(i == 3)\n\t\t  {\n\t\t  \ta=bm;\n\t\t  \tb=by;\n\t\t  \tc=bd;\n\t\t   } \n\t\tif(i == 4)\n\t\t  {\n\t\t  \ta=bm;\n\t\t  \tb=bd;\n\t\t  \tc=by;\n\t\t  }\n\t\tif(i == 5)\n\t\t  {\n\t\t  \ta=bd; \n\t\t  \tb=by;\n\t\t  \tc=bm;\n       \t  }\n\t    if(a == 0) continue;\n\t\tif(b == 1 || b == 3 || b == 5 || b ==  7 || b == 8 || b == 10 || b == 12)\n\t\t  if(c > 31) continue;\n\t\tif(b == 4  || b == 6 || b == 9|| b == 11)\n\t\t  if(c > 30) continue;\n\t\tif(b == 2 && a%4 == 0 && c>29) continue;\n\t\tif(b == 2 && a%4 != 0 && c>28) continue;\n\t\tif(b > 12) continue;\n\t    if(yy-a == 18 && mm > b)\n\t       flag = 1;\n\t    if(yy-a == 18 && mm == b && dd >= c)\n\t      flag = 1;\n\t    if(yy-a>18)\n\t      flag = 1;\n\t    if(flag == 1)\n\t      {\n//\t      \tprintf(\"1  \");\n\t      \tprintf(\"YES\");\n//\t      \tgetchar();\n//\t      \tgetchar();\n\t      \treturn 0;\n\t\t  }\n//\t\tprintf(\"%d %d  \", i, flag);\n//      if(i == 5) printf(\"%d %d %d  \", a, b, c);\n\t  }\n\tif(flag == 1) printf(\"YES\");\n\telse printf(\"NO\");\n//\tgetchar();\n//\tgetchar();\n\treturn 0;\n  }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ae75ad31b5f62c3b020989ee3685a562", "src_uid": "5418c98fe362909f7b28f95225837d33", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint processmonth(int dd, int mm, int yy, int by, int bm, int bd){\n  if((bm>12)||(((by+18)==yy)&&(mm<bm)))\n    return 0;\n  if(bd>31)\n    return 0;\n  if((bm==mm)&&((by+18)==yy))\n    if(bd>dd)\n      return 0;\n  if((bm==4)||(bm==6)||(bm==9)||(bm==11)){\n    if(bd>30)\n      return 0;\n  }\n  if(bm==2){\n    if((by%4)==0){\n      if(bd>29)\n        return 0;\n    }\n    else\n      if(bd>28)\n        return 0;\n  }\n  return 1;\n}\nint processyear(int dd, int mm, int yy, int by, int z1, int z2){\n  if((by+18)>yy)\n    return 0;\n  int t=0;\n  t=t+processmonth(dd,mm,yy,by,z1,z2);\n  t=t+processmonth(dd,mm,yy,by,z2,z1);\n  return t;\n}\nint main(){\n  int t = 0;\n  int c,x,dd,mm,yy,x1,x2,x3;\n  c=getchar();\n  dd=(c-'0')*10;\n  c=getchar();\n  dd=dd+c-'0';\n  c=getchar();\n  c=getchar();\n  mm=(c-'0')*10;\n  c=getchar();\n  mm=mm+c-'0';\n  c=getchar();\n  c=getchar();\n  yy=(c-'0')*10;\n  c=getchar();\n  yy=yy+c-'0';\n  c=getchar();\n  c=getchar();\n  x1=(c-'0')*10;\n  c=getchar();\n  x1=x1+c-'0';\n  c=getchar();\n  c=getchar();\n  x2=(c-'0')*10;\n  c=getchar();\n  x2=x2+c-'0';\n  c=getchar();\n  c=getchar();\n  x3=(c-'0')*10;\n  c=getchar();\n  x3=x3+c-'0';\n  t=t+processyear(dd,mm,yy,x1,x2,x3);\n  t=t+processyear(dd,mm,yy,x2,x1,x3);\n  t=t+processyear(dd,mm,yy,x3,x1,x2);\n  if(t>0)\n    printf(\"YES\\n\");\n  else\n    printf(\"NO\\n\");\n  return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7dba15aef750a2d931a8e43269ae3f71", "src_uid": "5418c98fe362909f7b28f95225837d33", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint y,m,d;\nint legal(int d,int m,int y)\n{\n    int p[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};\n    if(y%4==0)\n\t\tp[2]=29;\n    if(m>=1&&m<=12&&d>=1&&d<=p[m])\n    return 1;\n    return 0;\n}\nint ok(int a,int b,int c)\n{\n\tif(y>c)\n\t\treturn 1;\n\telse\n\t\tif(y==c)\n\t\t{if(m>b)\n\t\treturn 1;\n\t    else\n\t\tif(m==b&&d>=a)\n\t\treturn 1;}\n\treturn 0;\n}\nint main(void)\n{\n\n    int a,b,c;\n    scanf(\"%d%*c%d%*c%d\",&d,&m,&y);\n    if(y%4==0&&m==2&&d==29)\n\t\ty-=18,m=2,d=28;\n\telse\n\t\ty-=18;\n    scanf(\"%d%*c%d%*c%d\",&a,&b,&c);\n    if((legal(a,b,c)&&ok(a,b,c))||(legal(c,b,a)&&ok(c,b,a))||(legal(b,c,a)&&ok(b,c,a))||\n\t    (legal(a,c,b)&&ok(a,c,b))||(legal(c,a,b)&&ok(c,a,b))||(legal(b,a,c)&&ok(b,a,c)))\n\t\tputs(\"YES\\n\");\n\telse\n\t\tputs(\"NO\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "39dfe6e54a110be8e8564f3f4481e3e0", "src_uid": "5418c98fe362909f7b28f95225837d33", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint y,m,d;\nint legal(int d,int m,int y)\n{\n    int p[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};\n    if(y%4==0)\n\t\tp[2]=29;\n    if(m>=1&&m<=12&&d>=1&&d<=p[m])\n    return 1;\n    return 0;\n}\nint ok(int a,int b,int c)\n{\n\tif(y>c)\n\t\treturn 1;\n\telse\n\t\tif(y==c)\n\t\t{if(m>b)\n\t\treturn 1;\n\t    else\n\t\tif(m==b&&d>=a)\n\t\treturn 1;}\n\treturn 0;\n}\nint main(void)\n{\n\n    int a,b,c;\n    scanf(\"%d%*c%d%*c%d\",&d,&m,&y);\n    //if(y%4==0&&m==2&&d==29)\n\t\t//y-=18,m=3,d=1;\n\t//else\n\t\ty-=18;\n    scanf(\"%d%*c%d%*c%d\",&a,&b,&c);\n    if((legal(a,b,c)&&ok(a,b,c))||(legal(c,b,a)&&ok(c,b,a))||(legal(b,c,a)&&ok(b,c,a))||\n\t    (legal(a,c,b)&&ok(a,c,b))||(legal(c,a,b)&&ok(c,a,b))||(legal(b,a,c)&&ok(b,a,c)))\n\t\tputs(\"YES\\n\");\n\telse\n\t\tputs(\"NO\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3b7123b68a40da849f9115f164ad62a9", "src_uid": "5418c98fe362909f7b28f95225837d33", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\ntypedef struct {\n\tint d, m, a;\n} data_t;\n\nint isValid( data_t data ){\n\t\n\tif( data.m > 12 ) return 0;\n\t\n\tif( data.m == 1 || data.m == 3 || data.m == 5 || data.m == 7 || data.m == 8 || data.m == 10 || data.m == 12 )\n\t{\n\t\t\tif( data.d > 31 ) return 0;\n\t}\n\telse if( data.m == 2 ){\n\t\t\n\t\tif( data.a % 4 ){\n\t\t\tif( data.d > 28 ) return 0;\n\t\t} else if( data.d > 29 ) return 0;\n\t\n\t} else if( data.d > 30 ) return 0;\n\t\n\treturn 1;\n}\n\nint age( data_t nasc, data_t cur ){\n\t\n\tif( cur.a < nasc.a ) return 0;\n\t\n\tint age = ( cur.a - nasc.a );\n\t\n\tif( nasc.m < cur.m ) return age;\n\telse if( nasc.m > cur.m ) return age - 1;\n\telse {\n\t\t\n\t\tif( nasc.d <= cur.d ) return age;\n\t\telse return age-1;\n\t}\n\n}\n\nint main(){\n\t\n\tdata_t cont, d1, d2, d3, d4, d5, d6;\n\t\n\tscanf(\"%d.%d.%d\", &cont.d, &cont.m, &cont.a ); \n\tscanf(\"%d.%d.%d\", &d1.d, &d1.m, &d1.a ); \n\t\n\td2.d = d1.m; d2.m = d1.d; d2.a = d1.a;\n\td3.d = d1.a; d3.m = d1.d; d3.a = d1.m;\n\t\n\td4.d = d1.d; d4.m = d1.a; d4.a = d1.m;\n\td5.d = d1.m; d5.m = d1.a; d5.a = d1.d;\n\td6.d = d1.a; d6.m = d1.m; d6.a = d1.d;\n\t\n\tif( isValid( d1 ) && age( d1, cont ) >= 18 ){ puts(\"YES\");\n\t} else if( isValid( d2 ) && age( d2, cont ) >= 18 ){ puts(\"YES\");\n\t} else if( isValid( d3 ) && age( d3, cont ) >= 18 ){ puts(\"YES\");\n\t} else if( isValid( d4 ) && age( d4, cont ) >= 18 ){ puts(\"YES\");\n\t} else if( isValid( d5 ) && age( d5, cont ) >= 18 ){ puts(\"YES\");\n\t} else if( isValid( d6 ) && age( d6, cont ) >= 18 ){ puts(\"YES\");\n\t} else puts(\"NO\");\n\t\n\t\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5d1bd817ed5b2ce5cbd1b2fd1b6b7fbd", "src_uid": "5418c98fe362909f7b28f95225837d33", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int p,q,m,n,criminals=0,x1,x2;\n    scanf(\"%d %d\",&p,&q);\n    int A[p+1];\n    for(m=1;m<=p;m++)\n    {\n        scanf(\"%d\",&A[m]);\n    }\n    x1 = q-1;\n    x2 = p-q;\n    if(x1>x2)\n    {\n        for(m=q-x1,n=p;m++;n--)\n        {\n            if(n>m)\n            {\n                if(A[m]==1 && A[n]==1)\n                {\n                    criminals+=2;\n                }\n\n            }\n            if(n==m)\n            {\n                if(A[m]==1)\n                    criminals+=A[m];\n            }\n\n        }\n        for(m=q-x1-1;m>=1;m--)\n        {\n            if(A[m]==1)\n                criminals+=A[m];\n        }\n    }\n    else if(x1<x2)\n    {\n        for(m=1,n=q+x1;m<=q;m++,n--)\n        {\n            if(n>m)\n            {\n                if(A[m]==1 && A[n]==1)\n                    criminals+=2;\n            }\n            if(n==m)\n            {\n                if(A[m]==1)\n                    criminals+=A[m];\n            }\n        }\n        for(m=2*q;m<=p;m++)\n        {\n            if(A[m]==1)\n                criminals+=A[m];\n        }\n    }\n    else\n    {\n        for(m=1,n=p;m<=q;m++,n--)\n        {\n            if(n>m)\n            {\n                if(A[m]==1 && A[n]==1)\n                    criminals+=2;\n            }\n            if(n==m)\n            {\n                if(A[m]==1)\n                    criminals+=A[m];\n            }\n        }\n\n    }\n    printf(\"%d\\n\",criminals);\n    return 0;\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a4ed05862fa7cf75dd4585b179e09502", "src_uid": "4840d571d4ce6e1096bb678b6c100ae5", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int p,q,m,n,criminals=0,x1,x2;\n    scanf(\"%d %d\",&p,&q);\n    int A[p+1];\n    for(m=1;m<=p;m++)\n    {\n        scanf(\"%d\",&A[m]);\n    }\n    x1 = q-1;\n    x2 = p-q;\n    if(x1>x2)\n    {\n        for(m=q-x1,n=p;m++;n--)\n        {\n            if(n>m)\n            {\n                if(A[m]==1 && A[n]==1)\n                {\n                    criminals+=2;\n                }\n\n            }\n            if(n==m)\n            {\n                if(A[m]==1)\n                    criminals+=A[m];\n            }\n\n        }\n        for(m=q-x1-1;m>=1;m--)\n        {\n            if(A[m]==1)\n                criminals+=A[m];\n        }\n    }\n    else if(x1<x2)\n    {\n        for(m=1,n=q+x1;m<=q;m++,n--)\n        {\n            if(n>m)\n            {\n                if(A[m]==1 && A[n]==1)\n                    criminals+=2;\n            }\n            if(n==m)\n            {\n                if(A[m]==1)\n                    criminals+=A[m];\n            }\n        }\n        for(m=q+x1+1;m<=p;m++)\n        {\n            if(A[m]==1)\n                criminals+=A[m];\n        }\n    }\n    else\n    {\n        for(m=1,n=p;m<=q;m++,n--)\n        {\n            if(n>m)\n            {\n                if(A[m]==1 && A[n]==1)\n                    criminals+=2;\n            }\n            if(n==m)\n            {\n                if(A[m]==1)\n                    criminals+=A[m];\n            }\n        }\n\n    }\n    printf(\"%d\\n\",criminals);\n    return 0;\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6c51dcbeb7397c25d284805ec0aac2d8", "src_uid": "4840d571d4ce6e1096bb678b6c100ae5", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,a,t[104],i,left,right,ans=0,flag1=0,flag2=0;\n\tscanf(\"%d%d\",&n,&a);\n\tleft=a-1;\n\tright=a-1;\n\tfor(i=0;i<n;i++)\n\t\tscanf(\"%d\",&t[i]);\n\tif(t[a-1]==1)\n\t\tans++;\n\twhile(left>=0 || right<n-1)\n\t{\n\t\tflag1=0;\n\t\tflag2=0;\n\t\tif(left>0)\n\t\t{\n\t\t\tleft=left-1;\n\t\t\tflag1=1;\n\t\t}\n\t\tif(right<n-1)\n\t\t{\n\t\t\tright=right+1;\n\t\t\tflag2=1;\n\t\t}\n\t\tif(t[left]==1 && t[right]==1 && flag1==1 && flag2==1)\n\t\t\tans=ans+2;\n\t\telse if(flag1==0 && flag2==1)\n\t\t{\n\t\t\tif(t[right]==1)\n\t\t\t\tans=ans+1;\n\t\t\tleft=left-1;\n\t\t}\n\t\telse if(flag2==0  && flag1==1 && t[left]==1)\n\t\t{\n\t\t\tans++;\n\t\t\tleft=left-1;\n\t\t}\n\t}\n\tprintf(\"%d\\n\",ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dd0e65799557b116cd6d24b1d42a455f", "src_uid": "4840d571d4ce6e1096bb678b6c100ae5", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <math.h>\n#include <stdlib.h>\n\nint main()\n{\n    int a,n,i,j,counter=0;\n    scanf(\"%d%d\",&n,&a);\n    a-=1;\n    int arr[n];\n    for(i=0; i<n; i++)\n        scanf(\"%d\",&arr[i]);\n    if(arr[a]==1)\n        counter++;\n    for(i=a-1,j=a+1;; i--,j++)\n    {\n        if(i<0 && j>=n)\n            break;a\n        if(arr[i]==1&&arr[j]==1)\n            counter+=2;\n        else if((arr[i]==1 && j>=n) || (arr[j]==1 &&i<0))\n            counter++;\n    }\n    printf(\"%d\",counter);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "056fd76f1004ece0097b5e01143fcb3b", "src_uid": "4840d571d4ce6e1096bb678b6c100ae5", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,k,i,sum=0,j;\n    int a[n];\n    scanf(\"%d %d\",&n,&k);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        sum+=a[i];\n    }\n    for(i=k,j=k-2;i<n && j>=0;i++,j--)\n    {\n        if(a[i]+a[j]==1)\n        {\n            sum--;\n        }\n    }\n    printf(\"%d\\n\",sum);\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "df7022f0e9087555be9e8426df15faa7", "src_uid": "4840d571d4ce6e1096bb678b6c100ae5", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n,i,x,count=0,flag=0;\n    int a[LEN];\n    char ch;\n\n    scanf(\"%d\",&n);\n\n\n    for(i=1;i<=n;i++)\n    {\n        x=i;\n        int numlen=0;\n        flag=0;\n        while(x!=0)\n        {\n            numlen++;\n            if(x%10==0 || x%10==1)\n            {\n                flag++;\n            }\n            x/=10;\n\n        }\n        if(flag==numlen)\n        {\n            count++;\n        }\n    }\n    printf(\"%d\",count);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5d90c17bd123c3f550db389347bb9164", "src_uid": "64a842f9a41f85a83b7d65bfbe21b6cb", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define gc getchar_unlocked()\nint main(){\n    long long ans = 0, P = 1e9+7, f=0;\n    for(char c=gc;c!='\\n';f=f|(c>'1'),ans=f?((ans<<1)|1)%P:((ans<<1)|(c-'0'))%P,c=gc);\n    printf(\"%I64d\\n\",ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "87ec4c9536fe9ea38bb766e3664086c7", "src_uid": "64a842f9a41f85a83b7d65bfbe21b6cb", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<cstring>\nchar a[20];\nint num[20],ans=0,len;\nint sum[20],c[20];\n\nvoid pre(){\n\tc[0]=1;//2^i\n\tfor(int i=1;i<=20;++i){\n\t\tc[i]=1;\n\t\tc[i]<<=i;\n\t}\n\tsum[0]=1;\n\tfor(int i=1;i<=20;++i){\n\t\tsum[i]=sum[i-1]+c[i];\n\t}\n}\n\nvoid cal(){\n\tans=0;\n\tint len=strlen(a);\n\tfor(int i=0;i<len;++i){\n\t\tnum[len-i-1]=a[i]-'0';\n\t}\n\tfor(int i=len-1;i>=0;--i){\n\t\tif(num[i]>1){\n\t\t\tans+=sum[i];\n\t\t\tbreak;\n\t\t}\n\t\tif(num[i]==1){\n\t\t\tans+=sum[i-1]+1;\n\t\t}\n\t}\n}\n\nint main(){\n\tpre();\n\tscanf(\"%s\",a);\n\tcal();\n\tprintf(\"%d\",ans);\n} ", "lang_cluster": "C", "compilation_error": true, "code_uid": "4db8a6d8dc7fedf30abfbbefa49c6609", "src_uid": "64a842f9a41f85a83b7d65bfbe21b6cb", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define gc getchar_unlocked()\nint main(){\n    long long ans = 0, P = 1e9+7, f=0, c;\n    for(c=gc;c!='\\n';f=f|(c>'1'),ans=f?((ans<<1)|1)%P:((ans<<1)|(c-'0'))%P,c=gc);\n    printf(\"%I64d\\n\",ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b2aeba26461089fe9dc47451120871e8", "src_uid": "64a842f9a41f85a83b7d65bfbe21b6cb", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n\tint c=0,a,b,i;\n\tlong long int n;\n\tscanf(\"%ld\",&n);\n\tfor(i=1;i<=n;i++)\n\t{\n\t    b=i;\n\t    while(b!=0)\n\t\t{\n\t\t    a=b%100;\n\t\t    b=b/100;\n\t\t    if(a==1 || a==0 || a==10 || a=11)\n\t\t    {\n\t\t        if(b==0)\n\t\t        c++;\n\t\t        else\n\t\t        continue;\n\t\t    }\n\t\t    else\n\t\t    break;\n\t\t}\n\t}\n\tprintf(\"%d\",c);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "eced0daa48b9c229efb2dc1d4b7268ed", "src_uid": "64a842f9a41f85a83b7d65bfbe21b6cb", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#define MOD 1000000007\nint a,b,n,sum;\nlong long int c[500010];\nlong long int ans;\nint i,j;\nint judge(int x)\n{\n    char tmp[1000010];\n    sprintf(tmp,\"%d\",x);\n    int len=strlen(tmp);\n    for(j=0;j<len;j++)\n        if(tmp[j]-'0'!=a&&tmp[j]-'0'!=b)\n            return 0;\n    return 1;\n}\nint e_e(int l,int m,long long int &x,long long int &y)\n{\n    if(m)\n    {\n        int h;\n        h=e_e(m,l%m,x,y);\n        long long int tmp=x;\n        x=y;\n        y=tmp-l/m*x;\n        return h;\n    }\n    else\n    {\n        x=1;\n        y=0;\n        return l;\n    }\n}\nint main()\n{\n    scanf(\"%d%d%d\",&a,&b,&n);\n    sum=a*n-b+a;\n    c[0]=1;\n    for(i=1;i<=n/2+1;i++)\n    {\n        long long int k,x,y; \n        e_e(i,MOD,x,y);\n        k=x+MOD;\n        c[i]=(c[i-1]*(n+1-i)*k)%MOD;\n    }\n    for(i=0;i<=n;i++)\n    {\n        sum+=b-a;\n        if(judge(sum))\n        {\n            ans+=c[i<n-i?i:n-i];\n            ans%=MOD;\n        }\n    }\n    printf(\"%lld\",ans);\n    system(\"pause\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9d54074b70ab9c512bdd9638b131a97f", "src_uid": "d3e3da5b6ba37c8ac5f22b18c140ce81", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <assert.h>\n#include <stdlib.h>\n#include <string.h>\n#include <stdio.h>\n\n#define ARRAY_SIZEOF(a) (sizeof(a) / sizeof(a[0]))\n#define ZERO(p, n)      memset(p, 0, n);\n\n#define MOD 1000000007\n\ntypedef long long int lli;\n\nint a, b, n;\n\nint madd(int a, int b)\n{\n    return (int)( ((lli)a + (lli)b) % MOD );\n}\n\n/* Gets nth digit of `n` in decimal form. Digits counted from the rightmost,\n   least significant, which is 0\n*/\nint nth_digit(int j, int n)\n{\n    while (n != 0) {\n        int d = n % 10;\n        n /= 10;\n        if (j == 0) {\n            return d;\n        }\n        j--;\n    }\n    return 0;\n}\n\nint get_num(int k)\n{\n    return b * k + (n - k) * a;\n}\n\nint digit_lower_bound(int d, int pos, int lo, int hi)\n{\n    while (lo < hi) {\n        int mid = (lo + hi) / 2;\n        int nmid = get_num(mid);\n        int dmid = nth_digit(pos, nmid);\n        if (d > dmid) {\n            lo = mid + 1;\n        } else {\n            hi = mid;\n        }\n    }\n    return lo;\n}\n\nint Cnk(int k, int n)\n{\n    /* Dynamic programming is here. */\n    if (k == 0 && n >= 0) {\n        return 1;\n    }\n    if (n == 0) {\n        return 0;\n    }\n    return madd(Cnk(k, n - 1), Cnk(k - 1, n - 1));\n}\n\nint solve(int pos, int lo, int hi);\n\nint solve_digit(int d, int pos, int lo, int hi)\n{\n    int d_lo = digit_lower_bound(d, pos, lo, hi);\n    if (nth_digit(pos, get_num(d_lo)) == d) {\n        int d_hi = digit_lower_bound(d + 1, pos, lo, hi);\n        return solve(pos - 1, d_lo, d_hi);\n    }\n    return 0;\n}\n\nint solve(int pos, int lo, int hi)\n{\n    int i, a_res, b_res;\n\n    if (lo == hi) {\n        return 0;\n    }\n    if (pos < 0) {\n        int count = 0;\n        for (i = lo; i < hi; ++i) {\n            int ck = Cnk(i, n);\n            count = madd(count, ck);\n        }\n        return count;\n    }\n\n    a_res = solve_digit(a, pos, lo, hi);\n    b_res = solve_digit(b, pos, lo, hi);\n    return madd(a_res, b_res);\n}\n\nint main(int argc, char **argv)\n{\n/*\n#ifndef ONLINE_JUDGE\n     freopen(\"in\", \"r\", stdin);\n #endif\n*/\n    int max_sum, pos = 6, combinations;\n\n    scanf(\"%d%d%d\", &a, &b, &n);\n    if (a > b) {\n        int temp = a;\n        a = b;\n        b = temp;\n    }\n\n    /* Simplify a bit by reducing leading digits that are zeroes */\n    max_sum = b * n;\n    while (nth_digit(pos, max_sum) == 0) {\n        pos--;\n    }\n\n    combinations = solve(pos, 0, n + 1);\n    printf(\"%d\\n\", combinations);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2eac124cac2bde45bddd5e9ee0245c12", "src_uid": "d3e3da5b6ba37c8ac5f22b18c140ce81", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#define MOD 1000000007\nint a,b,n,sum;\nlong long int c[500010];\nlong long int ans;\nint i,j;\nint judge(int x)\n{\n    char tmp[1000010];\n    sprintf(tmp,\"%d\",x);\n    int len=strlen(tmp);\n    for(j=0;j<len;j++)\n        if(tmp[j]-'0'!=a&&tmp[j]-'0'!=b)\n            return 0;\n    return 1;\n}\nint e_e(int l,int m,long long int *x,long long int *y)\n{\n    if(m)\n    {\n        int h;\n        h=e_e(m,l%m,x,y);\n        long long int tmp=*x;\n        *x=*y;\n        *y=tmp-l/m*(*x);\n        return h;\n    }\n    else\n    {\n        *x=1;\n        *y=0;\n        return l;\n    }\n}\nint main()\n{\n    scanf(\"%d%d%d\",&a,&b,&n);\n    sum=a*n-b+a;\n    c[0]=1;\n    for(i=1;i<=n/2+1;i++)\n    {\n        long long int k,t,r;\n        long long int *x=&t,*y=&r; \n        e_e(i,MOD,x,y);\n        k=*x+MOD;\n        c[i]=(c[i-1]*(n+1-i)*k)%MOD;\n    }\n    for(i=0;i<=n;i++)\n    {\n        sum+=b-a;\n        if(judge(sum))\n        {\n            ans+=c[i<n-i?i:n-i];\n            ans%=MOD;\n        }\n    }\n    printf(\"%lld\",ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f68e88a2030e6726c14c5bcdbf0077c1", "src_uid": "d3e3da5b6ba37c8ac5f22b18c140ce81", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#define Min(x,y) ((x<y)?x:y)\n\nint a,b,n;\nint jugde(int i)\n{\n    while(i)\n    {\n        if(i % 10 == a || i % 10 == b)\n            i /= 10;\n        else\n            return 0;\n    }\n    return 1;\n}\n\nlong long p(int x, int y)\n{\n    long long ans = 1;\n    int i;\n    for(i = 1; i <= x; i ++)\n        ans = (ans * (y --) / i ) % 1000000007;\n    return ans;\n}\n\nint main()\n{\n    while(scanf(\"%d%d%d\",&a,&b,&n) != EOF)\n    {\n        int first = a * n,last = b * n,step = b - a;\n        int i;\n        long long ans = 0;\n        for(i = first; i <= last; i += step)\n        {\n            if(jugde(i))\n            {\n                ans = (ans + p(Min((last - i) / step,(i - first) / step),n)) % 1000000007;\n            }\n        }\n        printf(\"%I64d\\n\",ans);\n    }\n    return 0;\n}\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fab3a08ff7bda443d7a811b30bcff789", "src_uid": "d3e3da5b6ba37c8ac5f22b18c140ce81", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "//+++++++++++++++++++++++++++++//\n//      Karan Aggarwal         //\n//       IIIT-Hyderabad        //\n//+++++++++++++++++++++++++++++//\n// Topic: \n#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<limits.h>\n#include<math.h>\n#define si(n) scanf(\"%d\",&n)\n#define rep(i,n) for(i=0;i<n;i++)\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define pn printf(\"\\n\")\n#define pw printf(\" \")\n#define pi(n) printf(\"%d\",n)\n#define pll(n) printf(\"%lld\",n)\n#define sll(n) scanf(\"%lld\",&n)\n#define ss(s) scanf(\"%s\",s)\n#define ps(s) printf(\"%s\",s)\n#define mod 1000000007\ntypedef long long LL;\n//inline int readint(){int n=0;char c;while(1){ c=getchar_unlocked();if(c=='\\n'||c==' '||c==EOF)break;n=(n<<3) + (n<<1) +c-'0';}return n;}\n//inline long long readlonglong(){long long n=0;char c;while(1){ c=getchar_unlocked();if(c=='\\n'||c==' '||c==EOF)break;n=(n<<3) + (n<<1) +c-'0';}return n;}\nint abs(int a){ if(a<0)return -1*a; return a;}\nint big(int a,int b){if(a>b)return a;return b;}\nint small(int a,int b){if(a<b)return a;return b;}\nint compare(const void *a, const void *b)\n{\n    int *p1=(int*)a;\n    int *p2=(int*)b;\n    return *p1-*p2;\n}\n//++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++\nint aa,bb;\nint isgood(int x)\n{\n    int N = x;\n    while(N)\n    {\n        if(N%10 != aa && N%10 != bb)\n            return 0;\n            N/=10;\n    }\n    return 1;\n}\nLL  f[10000005]; \nLL md(LL a)\n{\n    while(a>=0)a-=1000000007;\n    while(a<0)a+=1000000007;\n    return a;\n}\nLL  inv(LL a)\n{\n    LL B,m,n,x,y,u,v,q,r;\n    x=v=0;\n    y=u=1;\n    LL b = mod;\n    B=mod;\n    while(a)\n    {\n        q=b/a;\n        r=b%a;\n        m=x-u*q;\n        n=y-v*q;\n        b=a;a=r;\n        x=u;y=v;\n        u=m;v=n;\n    }\n    return md(x);\n}\n\nint main()\n{\n    int m,l,ans,sum,min,max,n,i,j,k,x,y,t;\n    int counta,countb,mina,maxa;\n    si(aa);\n    si(bb);\n    si(n);\n    min = aa*n;\n    max = bb*n + 1;\n    f[0]=1;\n    REP(i,1,max)\n        f[i] = (f[i-1]*(LL)i)%mod;\n\n    LL anss=0;\n    REP(i,min,max)\n    {\n        if(isgood(i))\n        {\n            countb = i-min;\n            counta = n-countb;\n            anss +=         md(f[n] * inv(f[counta]*f[countb]));\n            \n            anss = md(anss);\n        }\n    }\n    pll(md(anss));\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a27921768ab2ba696c55cf61d05dc4e6", "src_uid": "d3e3da5b6ba37c8ac5f22b18c140ce81", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int i,k=0,z=0,l=0,b=0,n,m,s,e;\n    scanf(\"%d\",&n);\n    scanf(\"%d\",&m);\n    char a[30],h[30];\n    scanf(\"%s\",&a);\n    scanf(\"%s\",&h);\n    for(i=0;i<n;i++)\n    {\n        if(a[i]=='>')\n            z=z+1;\n        else\n            b=b-1;\n    }\n    s=b+z;\n        for(i=0;i<m;i++)\n    {\n        if(h[i]=='^')\n            k=k+1;\n        else\n            l=l-1;\n    }\n    e=k+l;\n    if((s==e)\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n}\n\n            ", "lang_cluster": "C", "compilation_error": true, "code_uid": "461ba908c17d4cae7d9fee7566beeda4", "src_uid": "eab5c84c9658eb32f5614cd2497541cf", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nusing namespace std;\n\nint main() {\n    int x,y; \n    scanf(\"%d%d\",&x,&y);\n    char a[x+1],b[y+1],c[5];\n    scanf(\"%s%s\",a,b);\n    c[0]=a[0];c[1]=a[x-1];\n    c[2]=b[0];c[3]=b[y-1];\n    c[4]='\\0';\n    if(!strcmp(c,\"<>v^\") || !strcmp(c,\"><^v\"))\n        printf(\"YES\\n\");\n    else\n        printf(\"NO\\n\");\n    return 0;   \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2a8ea0b05fa359b28e93bc18a643a32b", "src_uid": "eab5c84c9658eb32f5614cd2497541cf", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint n, m;\nchar f[23],g[23];\n\nint\nmain()\n{\n\tscanf(\"%d %d\", &n, &m );\n    scanf( \"%s %s\", f, g );\n    char c[5] = { f[0], g[0], f[n-1], g[m-1], '\\0' };\n\tcout << ((!strcmp( c, \"<v>^\" ) || !strcmp( c, \">^<v\" ) )? \"YES\": \"NO\") << endl;\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "dded33b2fa2e66b49846d42ef82b3d3c", "src_uid": "eab5c84c9658eb32f5614cd2497541cf", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t20\n#define M\t20\n\nint adj[N][M][N][M];\nint used[N][M];\n\nint dfs(int i1, int j1, int i2, int j2, int n, int m) {\n\tint i, j;\n\n\tif (i1 == i2 && j1 == j2)\n\t\treturn 1;\n\tfor (i = 0; i < n; i++)\n\t\tfor (j = 0; j < m; j++)\n\t\t\tif (adj[i1][j1][i][j] && !used[i][j]) {\n\t\t\t\tused[i][j] = 1;\n\t\t\t\tif (dfs(i, j, i2, j2, n, m))\n\t\t\t\t\treturn 1;\n\t\t\t}\n\tused[i][j] = 0;\n\treturn 0;\n}\n\nint main() {\n\tstatic char s[N + 1];\n\tstatic char t[M + 1];\n\tint n, m, i, i1, i2, j, j1, j2;\n\n\tscanf(\"%d%d\", &n, &m);\n\tscanf(\"%s\", s);\n\tfor (i = 0; i < n; i++)\n\t\tif (s[i] == '<')\n\t\t\tfor (j1 = 0; j1 < m; j1++)\n\t\t\t\tfor (j2 = j1 - 1; j2 >= 0; j2--)\n\t\t\t\t\tadj[i][j1][i][j2] = 1;\n\t\telse\n\t\t\tfor (j1 = 0; j1 < m; j1++)\n\t\t\t\tfor (j2 = j1 + 1; j2 < m; j2++)\n\t\t\t\t\tadj[i][j1][i][j2] = 1;\n\tscanf(\"%s\", t);\n\tfor (j = 0; j < m; j++)\n\t\tif (t[j] == '^')\n\t\t\tfor (i1 = 0; i1 < n; i1++)\n\t\t\t\tfor (i2 = i1 - 1; i2 >= 0; i2--)\n\t\t\t\t\tadj[i1][j][i2][j] = 1;\n\t\telse\n\t\t\tfor (i1 = 0; i1 < n; i1++)\n\t\t\t\tfor (i2 = i1 + 1; i2 < n; i2++)\n\t\t\t\t\tadj[i1][j][i2][j] = 1;\n\tfor (i1 = 0; i1 < n; i1++)\n\t\tfor (j1 = 0; j1 < m; j1++)\n\t\t\tfor (i2 = 0; i2 < n; i2++)\n\t\t\t\tfor (j2 = 0; j2 < m; j2++) {\n\t\t\t\t\tmemset(used, 0, sizeof used);\n\t\t\t\t\tif (!dfs(i1, j1, i2, j2, n, m)) {\n\t\t\t\t\t\tprintf(\"NO\\n\");\n\t\t\t\t\t\treturn 0;\n\t\t\t\t\t}\n\t\t\t\t}\n\tprintf(\"YES\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fd94218da21524fb5df301bbec558dea", "src_uid": "eab5c84c9658eb32f5614cd2497541cf", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "/*strongly connected city*/\n#include<stdio.h>\nint main()\n{\nint m,n,i,ul,ur,dl,dr;\nscanf(\"%d %d\",&m,&n);\ngetchar();\nul=getchar();\nfor(i=2;i<m;i++)\n\tgetchar();\nur=getchar();\ngetchar();\ndl=getchar();\nfor(i=2;i<n;i++)\n\tgetchar();\ndr=getchar();\n//printf(\"\\nul %c ur %c dl %c dr %c\",ul,ur,dl,dr); \nif(ul!=ur&&dl!=dr)\n\tprintf(\"YES\\n\");\nelse\n\tprintf(\"NO\\n\");\n\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "aeb3d70c6170b587904623b845417d5f", "src_uid": "eab5c84c9658eb32f5614cd2497541cf", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{  int i,b[6],s=0,j,p=0,k;\n    for(i=0;i<6;i++)\n    {\n        scanf(\"%d\",&b[i]);\n        s=s+b[i];\n\n    }\n    if(s%2==1)\n    {\n        printf(\"NO\");\n        p++;\n    }\n     else\n        {\n        s=s/2;\n\n    for(i=0;i<4;i++)\n    {\n        for(j=i+1;j<6;j++)\n        {\n            for(k=j+1;k<6;k++)\n            {\n                if(b[i]+b[j]+b[k]==s)\n                   {\n                    p=p+2;\n\n                   }\n                   break;\n            }\n    break;    }\n break;  }\n    }\n\n\n    if(p==0||p==1)\n    {\n        printf(\"NO\");\n    }\n    if(p==2)\n    {\n        printf(\"YES\");\n    }\ni\n\n    \n  \n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e3517ad2ea7d5f5093d8a55a6df6c45f", "src_uid": "2acf686862a34c337d1d2cbc0ac3fd11", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int a[6];\n    int sum;\n    scanf(\"%d %d %d %d %d %d\",&a[0],&a[1],&a[2],&a[3],&a[4],&a[5]);\n    sum=a[0]+a[1]+a[2]+a[3]+a[4]+a[5];\n    if(sum%2==0)\n    {\n        for(int i=0;i<6;i++)\n            for(int j=1;<6;j++)\n            for(int k=2;k<6;k++)\n        {\n            if(a[i]+a[j]+a[k]==(sum/2)) \n            {\n            printf(\"YES\");\n            return 0;\n            }\n        }\n    }\n    else printf(\"NO\");\n    printf(\"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7b9b7afa2b187db5c4b9f2508511ae7b", "src_uid": "2acf686862a34c337d1d2cbc0ac3fd11", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n,i,j,k,c=0;\n    float s=0,sum=0;\n\n    float arr[6];\n    for(i=0;i<6;i++){\n            scanf(\"%f\",&arr[i]);\n         s=s+arr[i];}\n         for(i=0;i<4;i++){\n            for(j=i+1;j<5;j++){\n                for(k=j+1;k<6;k++){\n                    sum=arr[i]+arr[j]+arr[k];\n\n                if(sum==s/2)\n                   {c++;\n\n\n                   }}\n\n            }\n         }\n        if(c==0)\n            printf(\"NO\");\n        else printf(\"YES\");\n\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "5d2634d5149aa320552cb28e4f818507", "src_uid": "2acf686862a34c337d1d2cbc0ac3fd11", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int a[6];\n    int sum;\n    scanf(\"%d %d %d %d %d %d\",&a[0],&a[1],&a[2],&a[3],&a[4],&a[5]);\n    sum=a[0]+a[1]+a[2]+a[3]+a[4]+a[5];\n    if(sum%2==0)\n    {\n        for(int i=0;i<6;i++)\n            for(int j=1;<6;j++) \n            for(int k=2;k<6;k++)\n        {\n            if(a[i]+a[j]+a[k]==(sum/2)) \n            {\n            printf(\"YES\");\n            return 0;\n            }\n        }\n    }\n    else \n    {\n        printf(\"NO\");\n        return 0;\n        }\n        printf(\"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "79675759017514df2cce2029d90073a0", "src_uid": "2acf686862a34c337d1d2cbc0ac3fd11", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "main.c", "lang_cluster": "C", "compilation_error": true, "code_uid": "c05c8a5a31f598f99955cdb9158ecb65", "src_uid": "2acf686862a34c337d1d2cbc0ac3fd11", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\n\nint main()\n{\n    int *t;\n    int i, j;\n    int aux;\n    int n;\n    int right;\n\n\n scanf(\"%d\", &n);\nt = malloc(n*sizeof(int));\n\nif(n<2)\n{\n    printf(\"-1\");\n}\n\nif(n>=2)\n{\n    t[0]=8;\n    t[1]=9;\n    for(i=2; i<n; i++)\n    {\n        t[i]=0;\n\n    }\n    for(i=0; i<n; i++)\n    {\n       printf(\"%d \", t[i]);\n    }\n}\n\nfree(t);\n\nreturn 0\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1ac46a23008f0e43ba1464f1c719454e", "src_uid": "fe8a0332119bd182a0a5b7758716317e", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "\n#include<stdio.h>\nint main() {\n  int n;\n  scanf(\"%d\",&n);\n  if(n<3) printf(\"-1\\n\");\n  else {\n    int i;\n    for(i=n;i>0;i--) {\n      printf(\" %d\",i);\n    \uff5d\n    printf(\"\\n\");\n  }\n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "74ef68b4fe949a3d0a214a4100e814cf", "src_uid": "fe8a0332119bd182a0a5b7758716317e", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n    int n,i;\n    scanf(\"%d\",&n);\n    if(1==n)\n        printf(\"-1\");\n    else{\n        for(i=n;i>=1;i++)\n            printf(\"%d \",i);\n    }\n    return 0\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f5f746d81897b86099f62ccb1d31e56c", "src_uid": "fe8a0332119bd182a0a5b7758716317e", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(void)\n{\n    int n;\n    scanf(\"%d\",&n);\n    if(n==1 || n==2) {\n    \tprintf(\"-1\");\n\t}\n\telse {\n\t\tprintf(\"100\");\n\t\tfor(i=1;i<n;i++) {\n\t\t\tprintf(\"1\");\n\t\t}\n\t}\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e8a354125901e2dc73b0a8fc6aa8128e", "src_uid": "fe8a0332119bd182a0a5b7758716317e", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "include<stdio.h>\nmain()\n{\n    int n,i,j,k;\n    scanf(\"%d\",&n);\n    if(n==1||n==2)\n    {\n        printf(\"-1\");\n        return 0;\n\n    }\n\n    printf(\"2 3 1 \");\n    for(i=4;i<=n;i++)\n    {\n        printf(\"%d \",i);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8ad6c7b5c33b40477eb6826831772711", "src_uid": "fe8a0332119bd182a0a5b7758716317e", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint convert(int a,int b,char c[])\n{\n\n    char d[101]=\"\";\n    copy(d,c,a,b);\n    return atol(d);\n\n}\nvoid copy(char g[],char h[],int A,int B)\n{\n    int i,j;\n    for(i=A,j=0;i<=B;i++,j++)\n    {\n        g[j]=h[i];\n    }\n\n\n}\nint main()\n{\n\tchar s[8]=\"\";\n\tint i,n,max=0,x=0,y=0,z=0,a=0,b=0;\nscanf(\"%s\",s);\n\tfor(i=0;s[i]!='\\0';i++);\n\t\tn=i;\n\t\tif(s[0]=='0')\n\t\tprintf(\"-1\");\n\t\telse{\n\t\tfor(i=0;i<n/2;i++)\n\t\t{\n        a=i+1;\n\n        b=n-(i+2);\n     if(a>b)\n     break;\n\n\t\t    x=convert(0,i,s);\n\t\t   y=convert(a,b,s);\n\t\t   z=convert(b+1,n-1,s);\n\t\t   if((x+y+z)>max)\n\t\t   max=x+y+z;\n\n\n\n\t\t}\n\n\t\tfor(i=0;i<n/2;i++)\n\t\t{\n        a=i+1;\n\n        b=n-(i+2);\n\n\n\t\t   x=convert(0,i,s);\n\t\t   y=convert(a,n-2,s);\n\t\t   z=convert(n-1,n-1,s);\n\t\t     if((x+y+z)>max)\n\t\t   max=x+y+z;\n\n\n\t\t}\n\n\t\tfor(i=0;i<n/2;i++)\n\t\t{\n        a=i+1;\n\n        b=n-(i+2);\n\n\n\t\t   x=convert(0,0,s);\n\t\t   y=convert(1,b,s);\n\t\t   z=convert(b+1,n-1,s);\n\t\t     if((x+y+z)>max)\n\t\t   max=x+y+z;\n\n\n\t\t}\n\t\tprintf(\"%d\",max);}\n\n\n\n\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4b186338acd2f3d999a070a17cc8735a", "src_uid": "bf4e72636bd1998ad3d034ad72e63097", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint convert(int a,int b,char c[])\n{\n\n    char d[101]=\"\";\n    copy(d,c,a,b);\n    return atol(d);\n\n}\nvoid copy(char g[],char h[],int A,int B)\n{\n    int i,j;\n    for(i=A,j=0;i<=B;i++,j++)\n    {\n        g[j]=h[i];\n    }\n\n\n}\nint main()\n{\n\tchar s[100]=\"\";\n\tint i,n,max=0,x=0,y=0,z=0,a=0,b=0;\nscanf(\"%s\",s);\n\tfor(i=0;s[i]!='\\0';i++);\n\t\tn=i;\n\t\tif(s[0]=='0')\n\t\tprintf(\"-1\");\n\t\telse{\n\t\tfor(i=0;i<n/2;i++)\n\t\t{\n        a=i+1;\n\n        b=n-(i+2);\n     if(a>b)\n     break;\n\n\t\t    x=convert(0,i,s);\n\t\t   y=convert(a,b,s);\n\t\t   z=convert(b+1,n-1,s);\n\t\t   if((x+y+z)>max)\n\t\t   max=x+y+z;\n\n\n\n\t\t}\n\n\t\tfor(i=0;i<n/2;i++)\n\t\t{\n        a=i+1;\n\n        b=n-(i+2);\n\n\n\t\t   x=convert(0,i,s);\n\t\t   y=convert(a,n-2,s);\n\t\t   z=convert(n-1,n-1,s);\n\t\t     if((x+y+z)>max)\n\t\t   max=x+y+z;\n\n\n\t\t}\n\n\t\tfor(i=0;i<n/2;i++)\n\t\t{\n        a=i+1;\n\n        b=n-(i+2);\n\n\n\t\t   x=convert(0,0,s);\n\t\t   y=convert(1,b,s);\n\t\t   z=convert(b+1,n-1,s);\n\t\t     if((x+y+z)>max)\n\t\t   max=x+y+z;\n\n\n\t\t}\n\t\tprintf(\"%d\",max);}\n\n\n\n\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ca3b720002b3609246cb8c310b4d2454", "src_uid": "bf4e72636bd1998ad3d034ad72e63097", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#include <string.h>\n\nchar s[99];\nint i,j,l,ans=-1,temp;\n\nint dv(p,q){\n    if(1<p&&s[0]=='0') return -1;\n    if(p+1<q&&s[p]=='0') return -1;\n    if(s[q]=='0'&&isdigit(s[q+1])) return -1;\n    int ret=0,z;\n    int t=s[p];\n    s[p]=0;\n    z=atoi(s);\n    if(z>1e6)return-1;\n    ret+=z;\n    s[p]=t;\n    t=s[q];\n    s[q]=0;\n    z=atoi(s+p);\n    if(z>1e6)return-1;\n    ret+=z;\n    s[q]=t;\n    z=atoi(s+q);\n    if(z>1e6)return-1;\n    ret+=z;\n    //if(ret>1000000)return 0;\n    //printf(\"%d %d %d\\n\",p,q,ret);\n    return ret;\n}\n\n\nmain(){\n    scanf(\"%s\",s);\n    l=strlen(s);\n    if(l<3&&21<l){\n        puts(\"-1\");\n        return 0;\n    }\n    for(i=1;i<=7&&i<l;i++){\n        for(j=i+1;j<=i+7&&j<l;j++){\n            temp=dv(i,j);\n            ans<temp?ans=temp:0;\n        }\n    }\n    printf(\"%d\\n\",ans);\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a9d64c445eb98967a446f6ae26690492", "src_uid": "bf4e72636bd1998ad3d034ad72e63097", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<string.h>\n#include<math.h>\n#include<stdlib.h>\n#include<stdio.h>\n#include<limits.h>\n#include<ctype.h>\nchar arr[25000];\nint main(){\n\tint a,b,c,d,e;\n\tgets(arr);\n\tint i; int len=strlen(arr); int s,s1,s2; s=s1=s2=0; int max=-1;\n\tfor(i=0;i<len-2;i++){\n\t\tfor(a=i+1;a<len-1;a++){\n\t\t\tfor(b=a+1;b<len;b++){\n\t\t\ts=s2=s1=0;\n\n\t\t\tint t3 = 0;\n\t\t\tif(arr[0]=='0'&& a!=1)\n\t\t\t\tcontinue;\n\t\t\twhile(t3<a){\n\t\t\ts=s*10+(arr[t3]-'0');\n\t\t\tt3++;\n\t\t\t}\n\t\t\tif(s>1000000){\n\t\t\t\ts=0;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tint t = a;\n\t\t\tif(arr[t] == '0' && a+1 !=b)\n\t\t\t\tcontinue;\n\t\n\t\t\twhile(t<b){\n\t\t\ts1=s1*10+(arr[t]-'0');\n\t\t\tt++;\n\t\t\t}\n\t\t\tif((s1)>1000000){\n\t\t\t\ts=s1=0;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif(arr[b]=='0' && b!=len-1)\n\t\t\t\tcontinue;\n\t\t\tint t1=b;\n\t\t\twhile(t1<len){\n\t\t\ts2=s2*10+(arr[t1]-'0');\n\t\t\tt1++;\n\t\t\t}\n\t\t\tif((s2)>1000000){\n\t\t\t\ts=s1=s2=0;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif((s+s1+s2)>max){\n\t\t\tmax=s+s1+s2;\n\t\t\t}\n\t\t\t}\n\t}}\n\tprintf(\"%d\",max);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "37f5c13d63217342588be7496ae5d4a7", "src_uid": "bf4e72636bd1998ad3d034ad72e63097", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#include <string.h>\n\nchar s[99];\nint i,j,l,ans=-1,temp;\n\nint dv(p,q){\n    if(1<p&&s[0]=='0') return -1;\n    if(p+1<q&&s[p]=='0') return -1;\n    if(s[q]=='0'&&isdigit(s[q+1])) return -1;\n    int ret=0,z;\n    int t=s[p]; s[p]=0;\n    z=atoi(s); s[p]=t;\n    if(z>1e6)return-1; ret+=z;\n    t=s[q]; s[q]=0; z=atoi(s+p); s[q]=t;\n    if(z>1e6)return-1;\n    ret+=z; z=atoi(s+q);\n    if(z>1e6)return-1;\n    ret+=z;\n    //if(ret>1000000)return 0;\n    //printf(\"%d %d %d\\n\",p,q,ret);\n    return ret;\n}\n\n\nmain(){\n    scanf(\"%s\",s);\n    l=strlen(s);\n    if(l<3||21<l){\n        puts(\"-1\");\n        return 0;\n    }\n    \n    for(i=1;i<=8&&i<l;i++){\n        for(j=l-1;l-8<j;j--){\n            if(j-i>7)continue;\n            temp=dv(i,j);\n            ans<temp?ans=temp:0;\n        }\n    }\n\n    //printf(\"%d\\n\",dv(6,12));\n    //puts(s);\n    printf(\"%d\\n\",ans);\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a6eecd9818b856a52a1822f0f51df6e5", "src_uid": "bf4e72636bd1998ad3d034ad72e63097", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "int main()\n{\n  int n,m;\n  scanf(\"%d%d\",&n,&m);\n  int a[n],b[m],c[n];\n  c[0]=1;\n  for(int i=0;i<n;i++)\n  scanf(\"%d\",&a[i]);\n  for(int i=0;i<m;i++)\n  scanf(\"%d\",&b[i]);\n    for(int i=0;i<n;i++)\n  {\n      if(func(b,a[i],m))\n      printf(\"%d \",a[i]);\n  }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d6876fde59cad46e13bcaf55cd915dcc", "src_uid": "f9044a4b4c3a0c2751217d9b31cd0c72", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nvoid mergeSort(int* a, int low, int mid, int high) {\n    int p1=low, p2=mid+1, i=0, j;\n    int temp[high-low+1];\n    while(p1<=mid && p2<=high) {\n        temp[i++] = ((a[p1] < a[p2])? a[p1++] : a[p2++]);\n    }\n    while(p1<=mid) {\n        temp[i++] = a[p1++];\n    }\n    while(p2<=high) {\n        temp[i++] = a[p2++];\n    }\n    for(j=low; j<=high; j++) {\n        a[j] = temp[j - low];\n    }\n}\n\nvoid merge(int* a, int low, int high) {\n    if(low == high) return;\n    int mid = (low+high)/2;\n    merge(a, low, mid);\n    merge(a, mi+1, high);\n    mergeSort(a, low, mid, high);\n}\n\nvoid repeatedNumber(int* a, int* b, int m, int n) {\n    int p1;\n    int p2;\n    for(p1=0, p2=0; p1<m, p2<n; p1++,p2++) {\n        while(p1<m && p2<n) {\n            if(a[p1] == b[p2]) {\n                printf(\"%d \", a[p1]);\n                p1++;\n                p2++;\n            } else if(a[p1] < b[p2]) {\n                p1++;\n            } else if(a[p1] > b[p2]) {\n                p2++;\n            }\n        }\n    }\n}\n\nint main()\n{\n    int m,n;\n    scanf(\"%d %d\", &n, &m);\n    int a[n];\n    for(int i=0; i<n; i++) {\n        scanf(\"%d\", &a[i]);\n    }\n    int b[m];\n    for(int j=0; j<m; j++) {\n        scanf(\"%d\", &b[j]);\n    }\n    merge(a, 0,m-1);\n    merge(b, 0, n-1);\n    repeatedNumber(a, b, m-1, n-1);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2ce63d4fb7d1876707fc8600ae0401a2", "src_uid": "f9044a4b4c3a0c2751217d9b31cd0c72", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n    int n,m,cn=0,k, i;\n    int code[20], check[20]={0};\n    scanf(\"%d %d\",&n,&m);\n    for(i=1;i<=n;i++) scanf(\"%d\",&code[i]);\n    for(i=1;i<=m;i++) {\n        scanf(\"%d\",&k);\n        check[k]=1;\n    }\n    for(i=1;i<=n;i++){\n        if(check[code[i]]) printf(\"%d \",code[i]);\n    }\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3cc77db632c797bde1fed229236baf16", "src_uid": "f9044a4b4c3a0c2751217d9b31cd0c72", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int arr[10],arr1[10],i,j,n1,n2,arr2[],k=0;\n    scanf(\"%d\",&n1);\n    scanf(\"%d\",&n2);\n    for(i=0;i<n1;i++)\n    scanf(\"%d\",&arr[i]);\n    for(i=0;i<n2;i++)\n    scanf(\"%d\",&arr1[i]);\n    for(i=0;i<n1;i++)\n    {\n        for(j=0;j<n2;j++)\n        {\n            if(arr[i]==arr1[j])\n            {\n                arr2[k]=arr[i];\n                \n            }\n        }\n        k++;\n    }\n    \n    for(j=0;j<k;j++)\n    printf(\"%d\",arr2[j]);\n    return 0;\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e75c42ee8702e85f6c072c0b4453fbf8", "src_uid": "f9044a4b4c3a0c2751217d9b31cd0c72", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "x=input()\nseq=input().replace(\" \",\"\")\nf=input()\nfor e in seq:\n    if e in f:\n        print(e,end=\" \")", "lang_cluster": "C", "compilation_error": true, "code_uid": "67b4da26bdc2846eb96e74e70fd1fb69", "src_uid": "f9044a4b4c3a0c2751217d9b31cd0c72", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint arith_test(int,int,int,int);\nint geo_test(int,int,int,int);\nint main(){\n    int a,b,c,d;\n    scanf(\"%d %d %d %d\",&a,&b,&c,&d);\n    if(arith_test(a,b,c,d)) printf(\"%d\",2*d-c);\n    else if(geo_test(a,b,c,d)) printf(\"%d\",d*d/c);\n    else printf(\"42\");\n    return 0;\n}\n\nint arith_test(int a,int b,int c,int d){\n    if(2*b==a+c && 2*c=b+d) return 1;\n    else return 0;\n}\n\nint geo_test(int a,int b,int c,int d){\n    if(b*b=a*c && c*c=b*d) return 1;\n    else return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1a346a0c3cc42d194538b9fd6be0478a", "src_uid": "68a9508d49fec672f9c61766d6051047", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nmain()\n{\n\tint a, b, c, d;\n\tint prirastaj, koeficijent;\n\tscanf(\"%d%d%d%d\", &a, &b, &c, &d);\n\n\tprirastaj=b-a;\n\tkoeficijet=b/a;\n\n\tif(c==b+prirastaj && d==c+prirastaj)\n\t\tprintf(\"%d\", d+prirastaj);\n\telse if(c==koeficijent*b && d==koeficijent*c)\n\t\tprintf(\"%d\", koeficijent*d);\n\telse printf(\"42\");\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "491493caaf847aae8ffc14cddae51c57", "src_uid": "68a9508d49fec672f9c61766d6051047", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint arith_test(int,int,int,int);\nint geo_test(int,int,int,int);\nint main(){\n    int a,b,c,d;\n    scanf(\"%d %d %d %d\",&a,&b,&c,&d);\n    if(arith_test(a,b,c,d)) printf(\"%d\",2*d-c);\n    else if(geo_test(a,b,c,d)) printf(\"%d\",d*d/c);\n    else printf(\"42\");\n    return 0;\n}\n\nint arith_test(int a,int b,int c,int d){\n    if(2*b==a+c && 2*c=b+d) return 1;\n    else return 0;\n}\n\nint geo_test(int a,int b,int c,int d){\n    if(b*b==a*c && c*c==b*d) return 1;\n    else return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2cfe276f4e16084a2bdcedf3dfda2f5d", "src_uid": "68a9508d49fec672f9c61766d6051047", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n\tint a, b, c, d;\n\tint prirastaj;\n\tfloat koeficijent;\n\tscanf(\"%d%d%d%d\", &a, &b, &c, &d);\n\n\tprirastaj=b-a;\n\tkoeficijent=(float)b/a;\n\n\tif(c==b+prirastaj && d==c+prirastaj)\n\t\tprintf(\"%d\", d+prirastaj);\n\telse if(c==koeficijent*b && d==koeficijent*c)\n\t{\n\t\tif(koeficijent*d==(int)(koeficijent*d))\n\t\t\tprintf(\"%d\", (int)(koeficijent*d));\n\t\telse printf(\"42\");\n\t}\n\telse printf(\"42\");\n\n\treturn 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "34d0e26d0c558233e9aebf6ce0b86f24", "src_uid": "68a9508d49fec672f9c61766d6051047", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n\tint a, b, c, d;\n\tint prirastaj, koeficijent;\n\tscanf(\"%d%d%d%d\", &a, &b, &c, &d);\n\n\tprirastaj=b-a;\n\tkoeficijent=b/a;\n\n\tif(c==b+prirastaj && d==c+prirastaj)\n\t\tprintf(\"%d\", d+prirastaj);\n\telse if(c==koeficijent*b && d==koeficijent*c)\n\t\tprintf(\"%d\", koeficijent*d);\n\telse printf(\"42\");\n\n\treturn 1;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "247bddf6f3b09dd140a7620a564aa070", "src_uid": "68a9508d49fec672f9c61766d6051047", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint daynumber(A[10])\n{\n    if(A[0]=='s' && A[1]=='u')\n      return 0;\n    else\n      if(A[0]=='m')\n        return 1;\n    else\n      if(A[0]=='t' && A[1]=='u')\n        return 2;\n    else\n      if(A[0]=='w')\n        return 3;\n    else\n      if(A[0]=='t' && A[1]=='h')\n        return 4;\n    else\n      if(A[0]=='f')\n        return 5;\n    else\n      if(A[0]=='s' && A[1]=='a')\n        return 6; \n}\n\nint main()\n{\n    char d1[10],d2[10];\n    int numd1,numd2;\n    printf(\"give 2 days\\n\");\n    scanf(\"%s %s\",&d1,&d2);\n    \n    if (daynumber(d2)==(daynumber(d1)+28)%7||daynumber(d2)==(daynumber(d1)+30)%7||daynumber(d2)==(daynumber(d1)+31)%7)\n        printf(\"yes\");\n    else\n        printf(\"no\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2ebcc93c6606b0b7d6af63a5669c317f", "src_uid": "2a75f68a7374b90b80bb362c6ead9a35", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nmain()\n{\n    char a[20];\n    char b[20];\n    gets(a);\n    gets(b);\n    if(a[0]==m)\n    {\n        if((b[0]==m)||(b[0]==w)||((b[0]==t)&&(b[1]==h)))\n        printf(\"YES\");\n        else\n        printf(\"NO\");\n    }\n    else if ((a[0]==t) && (a[1]==u))\n    {\n        if((b[0]==t)|| (b[0]==f))\n        printf(\"YES\");\n        else\n        printf(\"NO\");\n    }\n    else if (a[0]==w)\n    {\n        if ((b[0]==w)||(b[0]==f)||((b[0]==s)&& (b[1]==a)))\n        printf(\"YES\");\n        else\n        printf(\"NO\");\n    }\n    else if ((a[0]==t)&& (a[1]==h))\n    {\n        if (((b[0]==t)&& (b[1]==h))|| (b[0]==s))\n        printf(\"YES\");\n        else\n        printf(\"NO\");\n    }\n    else if (a[0]==f)\n    {\n        if((b[0]==f)|| (b[0]==m)|| ((b[0]==s)&& (b[1]==u)))\n        printf(\"YES\");\n        else\n        printf(\"NO\");\n    }\n    else if ((a[0]==s)&& (a[1]==a))\n    {\n        if(((b[0]==s) && (b[1]==a))|| (b[0]==m)|| ((b[0]==t) && (b[1]==u)))\n        printf(\"YES\");\n        else\n        printf(\"NO\");\n    }\n    else\n    {\n        if ((b[0]==w) || ((b[0]==s) && b[1]==u) || ((b[0]==t) && (b[1]==u)))\n        printf(\"YES\");\n        else\n        printf(\"NO\");\n    }\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e65cec9d8a810bff32e41c65457e0a49", "src_uid": "2a75f68a7374b90b80bb362c6ead9a35", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main()\n{\n    char day1[10],day2[10];\n   // printf(\"Give two days:\");\n    scanf(\"%s %s\",day1,day2);\n    if (strstr(day1,\"monday\")!=NULL)\n    {\n      char day3[]=\"thursday\";\n      char day4[]=\"monday\";\n      char day5[]=\"wednesday\";\n    }\n    else if (strstr(day1,\"tuesday\")!=NULL)\n    {\n      char day3[]=\"friday\";\n      char day4[]=\"tuesday\";\n      char day5[]=\"thursday\";\n    }\n    else if (strstr(day1,\"wednesday\")!=NULL)\n    {\n       char day3[]=\"saturday\";\n        char day4[]=\"wednesday\";\n       char day5[]=\"friday\";\n    }\n    else if (strstr(day1,\"thursday\")!=NULL)\n    {\n       char day3[]=\"sunday\";\n       char day4[]=\"thursday\";\n       char day5[]=\"saturday\";\n    }\n    else if (strstr(day1,\"friday\")!=NULL)\n    {\n       char day3[]=\"monday\";\n       char day4[]=\"friday\";\n       char day5[]=\"sunday\";\n    }\n    else if (strstr(day1,\"saturday\")!=NULL)\n    {\n       char day3[]=\"tuesday\";\n       char day4[]=\"saturday\";\n       char day5[]=\"monday\";\n    }\n    else\n    {\n      char day3[]=\"wednesday\";\n      char day4[]=\"sunday\";\n      char day5[]=\"tuesday\";\n    }\n    if (strstr(day2,day3)!=NULL || strstr(day2,day4)!=NULL || strstr(day2,day5)!=NULL)\n        printf(\"Yes\");\n    else\n        printf(\"No\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ea5909faee2b732228f2508e2f35422f", "src_uid": "2a75f68a7374b90b80bb362c6ead9a35", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n/*\n * \n */\nint main() {\n    \n    int i, k=1, d1, d2, D[32];\n    char D1[10], D2[10];\n    \n    //printf(\"Give two days of a week.\\n\");\n    //scanf(\" %c\", D1);\n    //scanf(\" %c\", D2);\n    gets(D1);\n    gets(D2);\n    \n    //printf(\"ascii %d\\n\", day1);\n    \n    if(strstr(D1,\"monday\")){\n        //printf(\"day1=\\n\");\n        d1=1;\n    }else if(strstr(D1,\"tuesday\")){\n        //printf(\"day1=2\\n\");\n        d1=2;\n    }else if(strstr(D1,\"wednesday\")){\n        d1=3;\n    }else if(strstr(D1,\"thursday\")){\n        d1=4;\n    }else if(strstr(D1,\"friday\")){\n        d1=5;\n    }else if(strstr(D1,\"saturday\")){\n        d1=6;\n    }else{\n        d1=7;\n    }\n    \n    if(strstr(D2,\"monday\")){\n        d2=1;\n    }else if(strstr(D2,\"tuesday\")){\n        d2=2;\n    }else if(strstr(D2,\"wednesday\")){\n        d2=3;\n    }else if(strstr(D2,\"thursday\")){\n        d2=4;\n    }else if(strstr(D2,\"friday\")){\n        d2=5;\n    }else if(strstr(D2,\"saturday\")){\n        d2=6;\n    }else{\n        d2=7;\n    }\n    \n    //printf(\"day1=%d\\n\",day1);\n    //printf(\"day2=%d\\n\",day2);\n    \n    k=day1;\n    for(i=1; i<=32; i++){\n        D[i]=k;\n        if(D[i]>7){\n            k=1;\n            D[i]=k;\n        }\n        k++;\n    }\n    /*\n    for(i=1; i<=32; i++){\n        printf(\"%d\\n\", D[i]);\n    }\n    */\n    if(D[32]==d2){\n        printf(\"YES\\n\");\n    }else if(D[29]==d2){\n        printf(\"YES\\n\");\n    }else if(D[31]==d2){\n        printf(\"YES\\n\");\n    }else{\n        printf(\"NO\\n\");\n    }\n    \n    return;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d28f539fe0adbf5c4c9d4b5ba4826f5e", "src_uid": "2a75f68a7374b90b80bb362c6ead9a35", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main()\n{\n    char day1[10],day2[10];\n   // printf(\"Give two days:\");\n    scanf(\"%s %s\",day1,day2);\n    if (strstr(day1,\"monday\")!=NULL)\n    {\n      char day3[9]=\"thursday\";\n       char day4[7]=\"monday\";\n      char day5[10]=\"wednesday\";\n    }\n    else if (strstr(day1,\"tuesday\")!=NULL)\n    {\n      char day3[7]=\"friday\";\n      char day4[8]=\"tuesday\";\n      char day5[9]=\"thursday\";\n    }\n    else if (strstr(day1,\"wednesday\")!=NULL)\n    {\n       char day3[9]=\"saturday\";\n       char day4[10]=\"wednesday\";\n       char day5[7]=\"friday\";\n    }\n    else if (strstr(day1,\"thursday\")!=NULL)\n    {\n       char day3[7]=\"sunday\";\n       char day4[9]=\"thursday\";\n       char day5[9]=\"saturday\";\n    }\n    else if (strstr(day1,\"friday\")!=NULL)\n    {\n       char day3[7]=\"monday\";\n       char day4[7]=\"friday\";\n       char day5[7]=\"sunday\";\n    }\n    else if (strstr(day1,\"saturday\")!=NULL)\n    {\n       char day3[8]=\"tuesday\";\n       char day4[9]=\"saturday\";\n      char day5[7]=\"monday\";\n    }\n    else\n    {\n      char day3[10]=\"wednesday\";\n      char day4[7]=\"sunday\";\n      char day5[8]=\"tuesday\";\n    }\n    if (strstr(day2,day3)!=NULL || strstr(day2,day4)!=NULL || strstr(day2,day5)!=NULL)\n        printf(\"Yes\");\n    else\n        printf(\"No\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c7e315db24f7badc58914a656b4a7ff5", "src_uid": "2a75f68a7374b90b80bb362c6ead9a35", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n  int a,b,c,k=0,k1,x;\n  scanf(\"%d %d %d\",&a,&b,&c);\n  k1=a;\n  if(a<1||a>100||b<-1000000||b>1000000||c<0||c>1000000)\n    printf(\"-1\");\n  else\n  {\n       a=a/2;\n      if(b>=-k1&&b<=k1&&k1!=b&&k1!=-b)\n      {\n          if(c==0||c%k1==0||(k1%2==0&&b==k1/2&&k1!=2)||(k1%2==0&&b==-k1/2&&k1!=2))\n            printf(\"-1\");\n          else\n          {\n            while(k<c)\n              k=k+k1;\n            x=k/k1;\n            if(x%2==1)\n            {\n               if(b==0)\n               {\n                 if(c<k1)\n                   printf(\"1\");\n                else\n                  printf(\"-1\");\n               }\n               else if(b<0) \n              {\n                if(x==1)\n                { \n                  if(b>k1/2||b<-k1/2||2==k2)\n                    printf(\"-1\");\n                  else\n                    printf(\"1\");\n                }\n                else\n                  printf(\"%d\",x+(x/2-1));\n              }\n               else\n               {\n                 if((x==1&&b>k1/2)||(x==1&&b<-k1/2)||(x==1&&b==k1/2&&k1==2))\n                   printf(\"-1\");\n                 else\n                   printf(\"%d\",x+(x/2-1)+1);\n               }\n             }\n             else\n             {\n                 if(b>-k1/2&&b<k1/2)\n                   printf(\"%d\",x+(x/2-1));\n                else\n                  printf(\"-1\");\n             }\n          }\n      }\n    else\n      printf(\"-1\");\n  }\n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c8af9ca6580365aae53e47cbc75a90e0", "src_uid": "cf48ff6ba3e77ba5d4afccb8f775fb02", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n\tfloat a,x,y;\n\tscanf(\"%f%f%f\",&a,&x,&y);\n\tif(y <= 0 )\n\t{\n\t\tprintf(\"-1\\n\");\n\t\texit(1);\n\t}\n\tif((int)y %(int)a == 0 )\n\t{\n\t\tprintf(\"-1\\n\");\n\t\texit(1);\n\t}\n\tif(y < a)\n\t{\n\t\tprintf(\"1\\n\");\n\t\texit(1);\n\n\t}\n//\tprintf(\"etfsgtsr\\n\");\n\n\tint num,one;\n\n\tnum = y /a;\n\tif (num % 2 != 0)\n\t\tone = 1 ;\n\telse\n\t\tone = 0;\n\n//\tprintf(\"num = %d\\n\",num);\n//\tprintf(\"one = %d\\n\",one);\n\tif(one == 1)\n\t{\n\t\tif(x <= -a/2 || x >= a/2 )\n\t\t{\n\t\t\tprintf(\"-1\\n\");\n\t\t\texit(1);\n\t\t}\n\t}\n\tif(one == 0)\n\t{\n\t\tif(x <= -a || x >= a || x == 0 )\n\t\t{\n\t\t\tprintf(\"-1\\n\");\n\t\t\texit(1);\n\t\t}\n\t}\n\n\n\tint count = 1;\n\n\tcount = count + ((2 * (num/2)) + num  - num/2);\n\tif(one == 1)\n\t\tprintf(\"%d\\n\",count);\n\telse\n\t{\n\t\tif(x < 0)\n\t\t{\n\t\t\tprintf(\"%d\\n\",count-1);\n\t\t}\n\t\telse if(x > 0)\n\t\t\tprintf(\"%d\\n\",count);\n\t\telse\n\t\t\tprintf(\"-1\\n\");\n\t}\n\n\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "00a318914e229b6534dacbc96f673bf1", "src_uid": "cf48ff6ba3e77ba5d4afccb8f775fb02", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nmain()\n{\nint a,x,y,t;\nscanf(\"%d%d%d\",&a,&x,&y);\nif(y%a==0)\nprintf(\"%d\",-1);\nelse if(y<(2*a))\n{\nif(x<(fabs)((double)a/2))\nprintf(\"%d\",y/a+1);\nelse\nprintf(\"%d\",-1);\n}\nelse if(y>(2*a))\n{\n    t=y/a+1;\n    if(t%2==0)\n       {\n           if(x<(fabs)((double)a/2))\n           {\n               int g=((t-1)/2)*3+2;\n               printf(\"%d\",g);\n\n           }\n           else\n           printf(\"%d\",-1);\n        }\n    else\n    {\n        if(x>0 && x<a)\n        printf(\"%d\",(t/2)*3+1);\n        if(x<0 && x>-a)\n        printf(\"%d\",(t/2)*3+1);\n        else\n        printf(\"%d\",-1);\n    }\n    return(0);\n}\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "04449fcb85cc0c5ebdd4077d9c532616", "src_uid": "cf48ff6ba3e77ba5d4afccb8f775fb02", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n\tint  a,x;\n\tint y;\n\tscanf(\"%d%d%d\",&a,&x,&y);\n\tif(y <= 0 )\n\t{\n\t\tprintf(\"-1\\n\");\n\t\texit(1);\n\t}\n\tif(y %a == 0 )\n\t{\n\t\tprintf(\"-1\\n\");\n\t\texit(1);\n\t}\n\tif(y < a)\n\t{\n\t\tprintf(\"1\\n\");\n\t\texit(1);\n\n\t}\n//\tprintf(\"etfsgtsr\\n\");\n\n\tint num,one;\n\n\tnum = y /a;\n\tif (num % 2 != 0)\n\t\tone = 1 ;\n\telse\n\t\tone = 0;\n\n//\tprintf(\"num = %d\\n\",num);\n//\tprintf(\"one = %d\\n\",one);\n\tif(one == 1)\n\t{\n\t\tif(x <= -a/2 || x >= a/2 )\n\t\t{\n\t\t\tprintf(\"-1\\n\");\n\t\t\texit(1);\n\t\t}\n\t}\n\tif(one == 0)\n\t{\n\t\tif(x <= -a || x >= a || x == 0 )\n\t\t{\n\t\t\tprintf(\"-1\\n\");\n\t\t\texit(1);\n\t\t}\n\t}\n\n\n\tint count = 1;\n\n\tcount = count + ((2 * (num/2)) + num  - num/2);\n\tif(one == 1)\n\t\tprintf(\"%d\\n\",count);\n\telse\n\t{\n\t\tif(x < 0)\n\t\t{\n\t\t\tprintf(\"%d\\n\",count-1);\n\t\t}\n\t\telse if(x > 0)\n\t\t\tprintf(\"%d\\n\",count);\n\t\telse\n\t\t\tprintf(\"-1\\n\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5b9e4e8a3dcb642f3bc2821e71f9ae7f", "src_uid": "cf48ff6ba3e77ba5d4afccb8f775fb02", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n  int x,y,a; \n  scanf(\"%d %d %d\",&x,&y,&a);\n  float a2=(float)a/2; \n  if(y%a==0)\n  {\n    printf(\"-1\");\n    return 0;\n  }\n  int ya=y/a+1;\n  float xa=x/a2;\n  int num=ya+(ya-1)/2;\n  if(ya==1||ya%2==0)\n  { \n      if(xa!=0)\n        printf(\"-1\");\n      else\n        printf(\"%d\",num);\n       return 0;\n  }\n  else\n {\n    if(xa>=2||xa<=-2||xa==0)\n      {\n         printf(\"-1\");\n         return 0;\n      }\n      else \n      { \n         if(xa>0)\n            num++;\n          printf(\"%d\",num);\n      }\n      return 0;\n }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "88d60f78caf4f4b14c56adf687cef7e6", "src_uid": "cf48ff6ba3e77ba5d4afccb8f775fb02", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nvoid Check(int a,int b,int c)\n{\n    if((a==2 && b==2) || (a==2 && c==2) || (b==2 && c==2))\n        printf(\"Yes\");\n    if((a==2 && b==4 && c==4) || (a==4 && b==2 && c==4) || ((a==4 && b==4 && c==2)))\n        printf(\"Yes\");\n    if(a==3 && b==3 && c==3)\n        printf(\"YES\");\n    elseprintf(\"NO\");\n\n\n}\n\n\n\n\nint main()\n{\nint a,b,c;\nscanf(\"%d %d %d\",&a,&b,&c);\nCheck(a,b,c);\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "03324536ae0e7a151827a1860ec362d7", "src_uid": "df48af9f5e68cb6efc1214f7138accf9", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(int argc, char const *argv[]) {\n  scanf(\"%d %d %d\\n\",&n,&m,&v);\n  if (n==1 || m==1 || v==1) {\n    printf(\"YES\\n\");\n    return 0;\n    /* code */\n  }\n  if (n==2 && m==2) {\n    printf(\"YES\\n\");\n    return 0;\n    /* code */\n  }\n  if (m==2 && v==2) {\n    printf(\"YES\\n\");\n    return 0;\n    /* code */\n  }\n  if (v==2 && n==2) {\n    printf(\"YES\\n\");\n    return 0;\n    /* code */\n  }\n  if (m==3 && n==3 && v==3) {\n    printf(\"YES\\n\");\n    return 0;\n    /* code */\n  }\n  printf(\"NO\\n\" );\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "88934d4bce1b9200f3cad3ee2738a2be", "src_uid": "df48af9f5e68cb6efc1214f7138accf9", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main()\n{\n    int a,b,c;\n    scanf(\"%d %d %d\"&a,&b,&c);\n    int k;\n    if(a<b) {k=a;a=b;b=k;}\n    if(b<c) {k=b;b=c;c=k;}\n    if(a<b) {k=a;a=b;b=k;}\n    if(c<=3||(a==2&&b==4&&c==4) printf(\"YES\\n\");\n    else printf(\"NO\\n\"); \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "81510907512f76a344511cc5eb5dd579", "src_uid": "df48af9f5e68cb6efc1214f7138accf9", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main()\n{\n    int a,b,c;\n    scanf(\"%d %d %d \"&a,&b,&c);\n    int k;\n    if(a<b) {k=a;a=b;b=k;}\n    if(b<c) {k=b;b=c;c=k;}\n    if(a<b) {k=a;a=b;b=k;}\n    if(c<=3||(a==2&&b==4&&c==4) printf(\"YES\\n\");\n    else printf(\"NO\\n\"); \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3e8c1bd311e518c989cea0e222aad46b", "src_uid": "df48af9f5e68cb6efc1214f7138accf9", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int i, i1, i2, i3, n, x1, x2, x3, k1, k2, k3, flag;\n\n    scanf(\"%d %d %d\", &k1, &k2, &k3);\n    n = k1 + k2 + k3;\n\n    for (i1 = 1; i1 < n; i1++){\n        for (i2 = 1; i2 < n; i2++){\n            for (i3 = 1; i3 < n; i3++){\n                x1 = i1;\n                x2 = i2;\n                x3 = i3;\n                i = 1;\n                flag = 1;\n                while ((i < n) && (flag == 1)){\n                    if ((i != x1) && (i != x2) && (i != x3))\n                        {\n                            flag = 0;\n                        }\n                        else {\n                            if (i == x1) x1 = x1 + k1;\n                            if (i == x2) x2 = x2 + k2;\n                            if (i == x3) x3 = x3 + k3;\n                        }\n                    i++;\n                }\n                if (flag == 1){\n                    printf(\"YES\");\n                    return 0;\n                }\n            }\n        }\n    }\n\n    printf(\"NO\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5a0bd3d7330279f783ca593251bb6291", "src_uid": "df48af9f5e68cb6efc1214f7138accf9", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nlong long min(long long x , long long y)\n{ if(x>=y)\n  return y;\n  else\n  return x ;\n}\nint main()\n{\n  long long int d , k , a, b, t ;\n  scanf(\"%lld %lld %lld %lld %lld\",&d, &k ,&a , &b, &t);\n  long long int  distance_covered;\n  long long int  walk ;\n  long long int  car_reach ;\n  if(k>=d)\n  {printf(\"%lld\\n\",d*a );}\n  else if( k*a + t < k*b) \n  {printf(\"%lld\\n\",(d/k)*a*k + (d/k-1)*t + min(d%k*a + t, d%k*b));}\n  else \n  {printf(\"%lld\\n\",a*k+(d-k)*b );}\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "be380c00f3ad58d6f2f5686e5a8ea84e", "src_uid": "359ddf1f1aed9b3256836e5856fe3466", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include \"stdbool.h\"\n#include \"stdio.h\"\n#include \"stdint.h\"\n#include \"string.h\"\n#include \"ctype.h\"\n#include \"stdlib.h\"\n#include \"math.h\"\n\n#define PI 3.14159265358979323846264338327950288\n#define ll long long\n#define MOD 1000000007\n#define N 300001\n#define MAX1 101\n\nint max(int a,int b) {return a>b?a:b;}\nint min(int a,int b) {return a<b?a:b;}\nll minl(ll a,ll b) {return a<b?a:b;}\nll maxl(ll a,ll b) {return a>b?a:b;}\n\n\nll d,k,a,b,t,ans;\n\nint main() {\n    scanf(\"%lld %lld %lld %lld %lld\", &d, &k, &a, &b, &t);\n    ll firstStep = minl(d,k);\n    d -= firstStep;\n    ans = a * firstStep;\n    if (d >= k) {\n        ll z = minl(t + a*k, b*k);\n        ans += (d/k) * z;\n        d %= k;\n    }\n    printf(\"%lld\\n\", ans + minl(t + a*d, b*d));\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3a88ea2dcde82d674783582e5251ad08", "src_uid": "359ddf1f1aed9b3256836e5856fe3466", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{   unsigned long long int d,dleft,time=0,a,b,k,t;\n    scanf(\"%I64u%I64u%I64u%I64u%I64u\",&d,&k,&a,&b,&t);dleft=d;\n    if(d<=k)\n    time=d*a;\n\tif(d>k){\n\t\t\ttime=a*k;dleft=d-k;\n\t\t    if(t+a*k<b*k){ \n\t\t\ttime = time + ((dleft/k)*k*a) + ((dleft/k)*t);\n\t\t\tdleft=dleft%k;\n\t\t\tif( (dleft*a)+t < (dleft*b) ){\n\t\t\ttime=time + t+ dleft*a;}\n\t\t\telse{\n\t\t\t\ttime= time + (dleft*b);\n\t\t\t}\n\t\t\t\t\n\t\t\t}\n\t\t\telse{\n\t\t\t\ttime= time + (dleft*b);\n\t\t\t}\t\t}  \n\t\t\tprintf(\"%I64u\",time);\n    \n\treturn 0;\n}\n\t\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "381c10bd3f6985bdade85abd54927819", "src_uid": "359ddf1f1aed9b3256836e5856fe3466", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\n    unsigned long long int a,b,c,d,e,f,i,j,n,tc,th,tb,s;\n    scanf(\"%llu%llu%llu%llu%llu\",&a,&b,&c,&d,&e);\n     if(b>a)\n   {tc=a*c;\n      a=0;}\n    else if(a>=b)\n    {a=a-b;\n    tc=b*c;}\n    if(a!=0)\n    {\n        th=a%b;\n        tb=a-th;\n        s=a/b;\n\n\n    if(e+b*c>=b*d)\n        {\n            tc=tc+a*d;\n          \n        }\n        else\n        {\n            i=tc+s*e+tb*c+e+(a-tb)*c;\n         tc=tc+s*e+tb*c+(a-tb)*d;\n            if(i<tc)\n            tc=i;\n            \n           \n        }\n    }\n\n    printf(\"%llu\",tc);\n\n\n\nreturn 0;\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9598faee7dfae5d24d8bc1471e2ad699", "src_uid": "359ddf1f1aed9b3256836e5856fe3466", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n   long long d,k,a,b,t,m1,result;\n   scanf(\"%lli%lli%lli%lli%lli\",&d,&k,&a,&b,&t);\nif( d <=k){\n    result = d*a;}\n    else{\n   if(k*a+t < b*k){\n      m1=d/k;\n      if ( (d - m1*k)*a+t< (d-m1*k)*b ) {\n        result = d*a+m1*t;}\n    else\n        result = m1*a*k + (m1-1)*t + (d-m1*k)*b;\n    }\n    else result = a*k+(d-k)*b;}\n\n    printf(\"%lli\", result);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "14406961408f8d6e7a15cbda8db32d39", "src_uid": "359ddf1f1aed9b3256836e5856fe3466", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>  \n#include<stdlib.h>\nint main() {\n    int n, p[1007], sum[2] = {0}, cur[2] = {1, 2};\n    scanf(\"%d\",&n);\n    for (int i = 1; i <= n / 2; i++) scanf(\"%d\",&p[i]);\n    qsort(p + 1, p + 1 + n / 2);\n    for (int i = 1; i <= n / 2; i++, cur[0] += 2, cur[1] += 2) {\n        sum[0] += abs(cur[0] - p[i]);\n        sum[1] += abs(cur[1] - p[i]);\n    }\n    printf(\"%d\\n\",min(sum[0], sum[1]));\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1e896ee95e7167ab87587518b4dcb8fe", "src_uid": "0efe9afd8e6be9e00f7949be93f0ca1a", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>  \n#include<stdlib.h>\nint main() {\n    int n, p[1007], sum[2] = {0}, cur[2] = {1, 2};\n    scanf(\"%d\",&n);\n    for (int i = 1; i <= n / 2; i++) scanf(\"%d\",&p[i])\n    qsort(p + 1, p + 1 + n / 2);\n    for (int i = 1; i <= n / 2; i++, cur[0] += 2, cur[1] += 2) {\n        sum[0] += abs(cur[0] - p[i]);\n        sum[1] += abs(cur[1] - p[i]);\n    }\n    printf(\"%d\\n\",min(sum[0], sum[1]));\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8d75a48bd862150f1495b11e8d980883", "src_uid": "0efe9afd8e6be9e00f7949be93f0ca1a", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint black(int *,int);\nint white(int *,int);\nint main()\n{\n    int n,arr[100],i;\n      scanf(\"%d\",&n);\n      \n      int pos;\n    for(i=0;i<n;i++)\n        arr[i]=0;\n    for(i=0;i<n/2-1;i++) \n      {\n          scanf(\"%d\",&n);\n          arr[n]=1;\n       }\n     int bl=black(arr,n);\n     int wh=white(arr,n);\n     (black>white)?printf(\"%d\",black):printf(\"%d\",white);\n     \n     return 0;\n}\nint black(int *arr,int n)\n{\n    int i=n-1,j=n-2,steps=0;\n    while(i>=0 &&j>=0)\n    {\n        if(arr[i]==1 && i/%2==1)\n          {\n            if(arr[j]==0)\n            {\n             arr[j]=1;\n             arr[i]=0;\n             \n             steps+=abs(j-i);\n             i--;\n             j-=2;\n            }\n           else\n           {\n               while(arr[j]!=0)\n               j-=2;\n             \n             arr[j]=1;\n             arr[i]=0;\n             \n             steps+=abs(j-i);\n             i--;\n             j-=2;\n               \n           }\n        }\n        else if(arr[i]==1 && i%2==0)\n           i--;    \n    }\n}\nint white(int *arr,int n)\n{\n    int i=n-1,j=n-1,steps=0;\n    while(i>=0 && j>=1)\n    {\n        if(arr[i]==1 && i/%2==1)\n          {\n            if(arr[j]==0)\n            {\n             arr[j]=1;\n             arr[i]=0;\n             \n             steps+=abs(j-i);\n             i--;\n             j-=2;\n            }\n           else\n           {\n               while(arr[j]!=0)\n               j-=2;\n             \n             arr[j]=1;\n             arr[i]=0;\n             \n             steps+=abs(j-i);\n             i--;\n             j-=2;\n               \n           }\n        }\n        else if(arr[i]==1 && i%2==0)\n           i--;    \n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "80cbe9488e313175cc0c07194802987f", "src_uid": "0efe9afd8e6be9e00f7949be93f0ca1a", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    int n,arr[100],i;\n      scanf(\"%d\",&n);\n      \n      int pos;\n    for(i=0;i<n;i++)\n        arr[i]=0;\n    for(i=0;i<n/2-1;i++) \n      {\n          scanf(\"%d\",&n);\n          a[n]=1;\n       }\n     int black=black(arr,n);\n     int white=white(arr,n);\n     (black>white)?printf(\"%d\",black):printf(\"%d\",white);\n     \n     return 0;\n}\nint black(int *arr,int n)\n{\n    int i=n-1,j=n-2,steps=0;\n    while(i>=0)\n    {\n        if(arr[i]==1 && i/%2==1)\n          {\n            if(arr[j]==0)\n            {\n             arr[j]=1;\n             arr[i]=0;\n             \n             steps+=abs(j-i);\n             i--;\n             j-=2;\n            }\n           else\n           {\n               while(arr[j]!=0)\n               j-=2;\n             \n             arr[j]=1;\n             arr[i]=0;\n             \n             steps+=abs(j-i);\n             i--;\n             j-=2;\n               \n           }\n        }\n        else if(arr[i]==1 && i%2==0)\n           i--;    \n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "238ec069cf3fd30a9e1c104b842c5b30", "src_uid": "0efe9afd8e6be9e00f7949be93f0ca1a", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include<stdlib.h>\n#include<algorithm>\nusing namespace std;\nint main(){\n\tint n;\n\tscanf(\"%d\",&n);\n\tchar a[109];\n\tfor(int i=1;i<=n/2;i++){\n\t\tscanf(\"%d\",&a[i]);\n\t}\n\tsort(a+1,a+1+n/2);\n\tint sum1=0,sum2=0;\n\tfor(int i=1;i<=n/2;i++){\n\t\tsum1+=abs(a[i]-(i*2-1));\n\t\tsum2+=abs(a[i]-(i*2));\n\t}\n\tprintf(\"%d\",sum1<sum2? sum1:sum2);\n \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6d9b551cced9b56c332192392d778be9", "src_uid": "0efe9afd8e6be9e00f7949be93f0ca1a", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n/* run this program using the console pauser or add your own getch, system(\"pause\") or input loop */\n\nint main(int argc, char *argv[]) {\n\tint k1 ,k2 ,N1 , N2 ;\n\tif (N1>N2)\n\t{printf (\"le joeur 1 gagne \");\n\t } \n\t else { printf (\"le joeur 2 gagne  \")\n\t }\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2af1df838f44663f37b11c87bc1678b3", "src_uid": "aed24ebab3ed9fd1741eea8e4200f86b", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n    int i,j,k,l;\n    scanf(\"%d %d %d %d\", &i,&j,&k,&l);\n    if(i<=j){\n    \tprintf(\"second\");\n\t\n\t  } else{\n    else\n\t    printf(\"first\");\n\n    \n\t\n    \t\n    \t\n    \t\n    \t\n    \t\n    }\n    \n    \n    return 0;\n    \n    \n    \n    \n    \n    \n    \n    \n    \n    \n    \n    \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d310d4b6f301f78d1f72e3f3b0238292", "src_uid": "aed24ebab3ed9fd1741eea8e4200f86b", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\n\tint n1,n2,k1,k2;\n\tscanf(\"%d%d%d%d\",&n1,&n2,&k1,&k2);\n\tint a1,a2;\n\ta1=n1-k1;\n\ta2=n2-k2;\n\tk=k1-k2;\n\tif(a1>a2&&k>0)\n    {\n        printf(\"Second\");\n    }\n    else\n        printf(\"First\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f7453062b8628b33a7d30646886c5abb", "src_uid": "aed24ebab3ed9fd1741eea8e4200f86b", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\nint n1,n2,k1,k2;\nscanf(\"%d %d %d %d\",&n1,&n2,&k1,&k2);\nif(n1>n2)\nprintf(\"First\\n\");\nelse\nprintf(Second\\n\");\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a2f6fae94993e763181467755e546299", "src_uid": "aed24ebab3ed9fd1741eea8e4200f86b", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n    int b1,b2,m1,m2;\n    for(int i=0; i<5; i++)\n    {\n        cin>>b1>>b2>>m1>>m2;\n        if(m1<=b1&&m2<=b2)\n        {\n            if(m1==m2&&b2>b1)cout<<\"second\";\n            else if(m1==m2&&b1>b2)cout<<\"first\";\n            else if(m1==m2&&b1==b2)continue;\n            else if(m1>m2&&b1>=b2)cout<<\"first\";\n            else if(m1>m2&&b2-m2>=b1-m1)cout<<\"second\";\n            else if(m2>m1&&b2>=b1)cout<<\"second\";\n            else if(m2>m1&&b1-m1>=b2-m2)cout<<\"first\";\n            else continue;\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d8457eec9f0f382f83ada8a7aa85a0b2", "src_uid": "aed24ebab3ed9fd1741eea8e4200f86b", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#include<math.h>\n#define LL long long\n#define me(x) memset(x,0,sizeof(x))\nlong n,m,k;\nLL max(LL x,LL y)\n{\n\treturn x>y?x:y;\n}\nlong d[100005],tot=0;\nint main()\n{\n\tlong i,t;\n\tLL ans=0;\n\tscanf(\"%ld %ld %ld\",&n,&m,&k);\n\tk+=2;\n\tif (k>m+n){printf(\"-1\"); return 0;}\n\tt=(long)sqrt(m+0.1);\n\tfor (i=1;i<=t;i++) {d[++tot]=i; d[++tot]=m/i;}\n\tt=(long)sqrt(n+0.1);\n\tfor (i=1;i<=t;i++) {d[++tot]=k-i; d[++tot]=k-n/i;}\n\tfor (i=1;i<=tot;i++) if (d[i]>0&&d[i]<k) ans=max(ans,(LL)(m/d[i])*(n/(k-d[i])));\n\tprintf(\"%I64d\",ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dad699f87f9cfb4e46b32600e8db3e4e", "src_uid": "bb453bbe60769bcaea6a824c72120f73", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include <string.h>\nint main()\n{\n\tint x,n,m,k=0;\n\tscanf(\"%d\",&n);\n\tscanf(\"%d\",&m);\n\tscanf(\"%d\",&k);\n\tif(k>n+m-2)\n\t{\n\t\tprintf(\"-1\\n\");\n\t    return 0;\n\t}\n\telse\n\t{\n\t\tprintf(\"%d\\n\",n*m/(k+1));\n\n\t}\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "39dfec8120911d60a40141618d6b37af", "src_uid": "bb453bbe60769bcaea6a824c72120f73", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long int n,m,k,i,j,k,t;\nlong long int ans(long long int a,long long int b)\n{\n    long long int x = n*m;\n    long long int y = (a+1)*(b+1);\n    return x/y;\n}\nint main()\n{\n    scanf(\"%lld%lld%lld\",&n,&m,&k);\n    if(n>m)\n    {\n        t=n;\n        n=m;\n        m=t;\n    }\n    else\n    {\n\n    }\n    if(k>n+m-2)\n        printf(\"-1\\n\");\n    else if(k<n)\n    {\n        printf(\"%lld\\n\",ans(k,0));\n    }\n    else if(k>=n && k<m)\n    {\n        printf(\"%lld\\n\",ans(0,k));\n    }\n    else\n    {\n        printf(\"%lld\\n\",ans(k+1-m,m-1));\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "202a83abe9298f22513ed3526c538f77", "src_uid": "bb453bbe60769bcaea6a824c72120f73", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    long int n,m,k,temp;\n    scanf(\"%ld\",&n);\n    scanf(\"%ld\",&m);\n    scanf(\"%ld\",&k);\n\n    if(m<n)\n    {\n        temp=m;\n        m=n;\n        n=temp;\n    }\n    if(k>m+n-2)\n    printf(\"-1\");\n    else if(k<=m+n-2)\n    {\n        if(k<m)\n        printf(\"%ld\",(n*(m/(k+1)));\n        else if(k>=m)\n        printf(\"%ld\",n/(k-m+2));\n    }\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5e8aa7364fe0cc7bdc0d82cf2ee047d0", "src_uid": "bb453bbe60769bcaea6a824c72120f73", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include \"stdio.h\"\nint main()\n{\n\t_int64 s,x,n,m,k,c;\n\tscanf (\"%I64d %I64d %I64d\",&n,&m,&c);k=c+1;//\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0475 \u04bb\ufffd\u01f5\ufffd\ufffd\u2f38\ufffd\ufffd\ufffd\ufffd\u04aa\u05e2\ufffd\ufffd \u04bb\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd K=c+1 \ufffd\ufffd\ufffd\ufffd\ufffd\u0737\ufffd\ufffd\ufffd\ufffd\u04e6\ufffd\ufffd\ufffd\u01ff\ufffdk%m\ufffd\u01f7\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\n\tx=m*n;// \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0475\ufffd\u01fe\ufffd\ufffd\ufffd\u0133\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u03aa\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd \u04b2\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd \ufffd\ufffd\ufffd\ufffd\u022b\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u03aa\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\n\tif (c>n+m-2)\n\t\tprintf (\"-1\");\n\telse if (m%k==0||n%k==0)\n\t\tprintf (\"%I64d\",s=x/k);\n\telse if (c<m&&c<n)\n\t\tprintf (\"%I64d\",s=(m/k*n>n/k*m?m/k*n:n/k*m));\n\telse if (k>m&&k>n)\n\t\tprintf (\"%I64d\",s=(m/(k+1-n)>n/(k+1-m)?m/(k+1-n):n/(k+1-m)));\n\telse if (k<m)\n\t\tprintf (\"%I64d\",s=(m/(k+1-n)>m/k*n?m/(k+1-n):m/k*n));\n\telse\n\t\tprintf (\"%I64d\",s=(n/(k+1-m)>n/k*m?n/(k+1-m):n/k*m));\n\tprintf (\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6d204a7fac7b041103ba4ec1baf633b7", "src_uid": "bb453bbe60769bcaea6a824c72120f73", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int a[10000],n,i,x,b[10000],p=0,q=0;\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        if(a[i]==n)\n            p=i+1;\n        else if(a[i]==1)\n            q=i+1;\n    }\n    b[0]=(n-p);\n    b[1]=(n-q);\n    b[2]=(p-1);\n    b[3]=(q-1);\n    for(i=0;i<4;i++)\n    {\n        if(b[i]>b[i+1])\n        b[i+1]=b[i];\n       \n    }\n\n        printf(\"%d\\n\",b[i+1);\n        return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5ff304f574c169218868e2c90c4051f4", "src_uid": "1d2b81ce842f8c97656d96bddff4e8b4", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n  int n;\n  scanf(\"%d\",&n);\n  int arr[n];\n  for(int i=0;i<n;i++)\n  {\n    scanf(\"%d\",&arr[i]);\n  }\n  int i1=0,i2=0;\n  int max=arr[0],min=arr[0];\n for(int i=0;i<n;i++)\n {\n  if(arr[i]>max)\n  {\n    max=arr[i];\n  }\n }\n for(int i=0;i<n;i++)\n {\n  if(arr[i]==max)\n  {\n    i1=i;\n  }\n }\n  for(int i=0;i<n;i++)\n {\n  if(arr[i]<min)\n  {\n    min=arr[i];\n  }\n }\n for(int i=0;i<n;i++)\n {\n  if(arr[i]==min)\n  {\n    i2=i;\n  }\n }\n\n int h[4];\n h[0]=abs(i2-0);\n h[1]=abs(i2-(n-1));\n h[2]=abs(i1-0);\n h[3]=abs(i1-(n-1));\n int max1=-9999;\n for(i=0;i<4;i++)\n{\nif(h[i]>max1)\n{\n  max1=h[i];\n}\n}\n\nprintf(\"%d\",max1);\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e953031199901db8f2985376f4e1e009", "src_uid": "1d2b81ce842f8c97656d96bddff4e8b4", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint m (int a,int b){\n\tif (a>b)\n\t  return a;\n\telse\n\t  return b;\n}\n\t\nint main (){\n\tint i,n,max,min,m,maxi=0,mini=0,a[101];\n\t\n\tscanf (\"%d\",&n);\n\tscanf (\"%d\",&max);\n\ta [0]=min=max;\n\tfor (i=1;i <n;i++){\n\t\tscanf (\"%d\",&a [i]);\n\t\tif (a [i]>max){\n           max=a[i];\n\t\t   maxi=i;\n\t\t}\n\t   else if (a [i]<min){\n\t        mini=i;\n\t        min=a [i];\n\t    }\n\t}\n\n\t\n\tint x=abs (maxi-mini);\n\tint y=abs (maxi-n-1);\n\tint z=abs (mini-n-1);\n\ti= m(x,maxi);\n    int j=m (y,z);\n\tint ans=m (m (i,j),mini);\n\t printf (\"%d\",ans);     \n}\n\t", "lang_cluster": "C", "compilation_error": true, "code_uid": "5588f080fb9bd5a8fc523dfddfa747ef", "src_uid": "1d2b81ce842f8c97656d96bddff4e8b4", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include <algorithm>\nint main(){\n    int n;\n    scanf(\"%d\", &n);\n    int a[n],i;\n    for(i=0;i<n;i++){\n        scanf(\"%d\", &a[i]);\n    }\n    int c,maxx,minn,d,e,f,h;\n    for(i=0;i<n;i++){\n        if(a[i]==n)\n            maxx=i;\n        if(a[i]==1)\n            minn=i;\n    }\n    c=maxx;\n    d=n-maxx;\n    e=minn;\n    f=n-minn;\n    int g[4]={c,d,e,f};\n    sort(g[4]);\n    h=g[0];\n    if(h<n-h)\n        h=n-h;\n    printf(\"%d\",h);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "46afdf62d69642ba5ba4e28c2f629cb9", "src_uid": "1d2b81ce842f8c97656d96bddff4e8b4", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nvoid main()\n{\n\tint n, i, vmin, vmax,min,max, a[101];\n\tscanf_s(\"%d\", &n);\n\tmin = n + 1; max = -1;\n\tfor (i = 0; i < n; i++)\n\t{\n\t\tscanf_s(\"%d\", &a[i]);\n\t\tif (a[i] > max)\n\t\t{\n\t\t\tmax = a[i];\n\t\t\tvmax = i;\n\t\t}\n\t\tif (a[i] < min)\n\t\t{\n\t\t\tmin = a[i];\n\t\t\tvmin = i;\n\t\t}\n\t}\n\tif (vmin < n - vmin) vmin = n - vmin;\n\tif (vmax < n - vmax) vmax = n - vmax;\n\tif (vmin > vmax)printf(\"%d\", vmin-1);\n\telse printf(\"%d\", vmax-1);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8d0e434dd53b965b1660a5f02f5e6933", "src_uid": "1d2b81ce842f8c97656d96bddff4e8b4", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "import java.util.Scanner;\n\npublic class Main {\n\n\tpublic static void main(String[] args) {\n\t\tScanner in = new Scanner(System.in);\n\t\tint x = 0, a = 0, ans = 0;\n\t\tchar b = 'E', t = 'E';\n\t\tx = in.nextInt();\n\t\tif (x % 4 == 1) {\n\t\t\tSystem.out.println(\"0 A\");\n\t\t} else {\n\t\t\tfor (a = 0; a <= 2; a++) {\n\t\t\t\tif ((x + a) % 4 == 1) {\n\t\t\t\t\tt = 'A';\n\t\t\t\t} else if ((x + a) % 4 == 3) {\n\t\t\t\t\tt = 'B';\n\t\t\t\t} else if ((x + a) % 3 == 2) {\n\t\t\t\t\tt = 'C';\n\t\t\t\t} else if ((x + a) % 4 == 0) {\n\t\t\t\t\tt = 'D';\n\t\t\t\t}\n\t\t\t\tif (t - b < 0) {\n\t\t\t\t\tb = t;\n\t\t\t\t\tans = a;\n\t\t\t\t}\n\t\t\t}\n\t\t\tSystem.out.println(ans + \" \" + b);\n\t\t}\n\t\tin.close();\n\t}\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "23c52d53f51d6d588735f0b4708bcf89", "src_uid": "488e809bd0c55531b0b47f577996627e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<conio.h>\n\n \n int main()\n \n {   \n     int x;\n     printf(\"enter the current HP\\n\");\n     scanf(\"%d\",&x);\n     \n     if (x%4==1)\n     flag=1;\n     \n     else if(x%4==3)\n     flag=2;\n     \n     else if(x%4==2)\n     flag=3;\n     \n     else\n     flag=4;\n     \n     if (flag==1)\n     {\n        printf(\"0 A\");\n     }\n     \n     else if (flag==2)\n     {\n        printf(\"2 A\"); \n     }\n     \n     \n     else if (flag==3)\n     {\n         printf(\"1 B\");\n     }\n     \n     \n     else if (flag==4)\n     {\n          printf(\"1 A\");\n     }\n      return 0;\n      \n }\n \n \n     \n     \n     \n     \n     \n     \n     \n     \n     \n     \n     \n     \n     \n     \n     \n }", "lang_cluster": "C", "compilation_error": true, "code_uid": "2e92c3ef613d1e41d390415cbe9f03aa", "src_uid": "488e809bd0c55531b0b47f577996627e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nvoid main()\n{\n    int a;\n    scanf(\"%d\",&a);\n    if(a%4==1)\n    {\n        printf(\"%d %c\",0,'A');\n    }\n    else if(a%4==3)\n    {\n        for(i=0;i<=2;i++)\n        {\n        if((a+i)%4==1)\n        printf(\"%d %c\",i,'A');\n        }\n    }\n    else if(a%4==2)\n    {\n        for(i=0;i<2;i++)\n        {\n            if((a+i)%4==1)\n            printf(\"%d %c\",i,'A');\n            else if((a+i)%4==3)\n            printf(\"%d %c\",i,'B');\n        }\n    }\n    else if(a%4==0)\n    {\n       for(i=0;i<2;i++)\n        {\n            if((a+i)%4==1)\n            printf(\"%d %c\",i,'A');\n            else if((a+i)%4==3)\n            printf(\"%d %c\",i,'B');\n            else if((a+i)%4==2)\n            printf(\"%d %c\",i,'C');\n        } \n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1e1cbb9e35ceb9a124e454d09f63a086", "src_uid": "488e809bd0c55531b0b47f577996627e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n;\n    scanf(\"%d\", &n);\n    char cat[0];\n    int en;\n    if(n%4==1){\n        en = 0;\n    }\n    else if(n%4==3){\n        en = 0;\n    }\n    else if(n%4==2){\n        en = 1;\n    }\n    else if(n%4==0){\n        en = 1;\n    }\n    n = n+ en;\n    if(n%4==1){\n        cat[0]='A';\n    }\n    else if(n%4==3){\n        cat[0] = 'B';\n    }\n    else if(n%4==2){\n        cat[0] = 'C';\n    }\n    else if(n%4==0){\n        cat[0] = 'D';\n    }\n    printf(\"%d %c\", en, cat[0]);\n \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "292c14f3ca1f960bd853539064a515b0", "src_uid": "488e809bd0c55531b0b47f577996627e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<conio.h>\nmain()\n{\n   int n,b,c;\n   scanf(\"%d\",&n);\n   b=n%4;8\n   if(b==1)\n   {\n       printf(\"0 A\");\n   }\n   else\n     {\n      if(b==2)\n      {\n          printf(\"1 B\");\n      }\n      else\n        if(b==3)\n         {\n            printf(\"2 A\");\n         }\n         else\n            printf(\"2 B\");\n      }\n\n\n\n   }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ed2906a31b827d7ec0e5e9148a17bf7f", "src_uid": "488e809bd0c55531b0b47f577996627e", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(){\n\tint n,k,path;\n\tscanf(\"%d %d\",&n,&k);\n\tif(n==1){\n\t    print(0);\n\t}\n\telse{\n\tif((n-k)<=(k-1)){\n\t\tpath=(n-k)+(n-1);\n\t}\n\telse{\n\t\tpath=(n-1)+(k-1);\n\t}\n\tint total=2*path+n+2;\n\tif(k!=1 && k!=n){\n\t\ttotal -= 1;\n\t}\n\tprintf(\"%d\",total);\n\t}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b7552487b8bd0b3b9181602d85ab5523", "src_uid": "24b02afe8d86314ec5f75a00c72af514", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,k,total,median;\n\tscanf(\"%d %d\",&n,&k);\n\ttotal = (n - 1) * 2 + 3;\n\t(n % 2 == 0) ? median = n / 2 : median = n/2+1;\n\tif(k == 1 || k == n)\n\t{\n\t\tprintf(\"%d\\n\",total + n - 1);\t\n\t} \n\telse{\n\t\tif(n % 2 == 0)\n\t\t{\n\t\t\tif(k == median || k == median + 1)\n\t\t\t{\n\t\t\t\tk = (median - 1) * 2 + n/2;\n\t\t\t\tprintf(\"%d\\n\",total+ k);\n\t\t\t}\n\t\t\telse{\n\t\t\t\tint temp = median + (median+1);\n\t\t\t\tif(k < median)\n\t\t\t\t{\n\t\t\t\t\ttotal += (k-1) * 2 + (n - k);\n\t\t\t\t\tprintf(\"%d\\n\",total);\n\t\t\t\t}\n\t\t\t\telse if(k > median)\n\t\t\t\t{\n\t\t\t\t\tk = temp % k;\n\t\t\t\t\ttotal += (k-1) * 2 + (n - k);\n\t\t\t\t\tprintf(\"%d\\n\",total);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse if(n % 2 != 0)\n\t\t{\n\t\t\tif(k == median)\n\t\t\t{\n\t\t\t\tk = n-1;\n\t\t\t\tprintf(\"%d\\n\",total + k + n/2);\n\t\t\t}\n\t\t\telse{\n\t\t\t\tif(k < median)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%d\\n\",total + (k-1) * 2 + (n - k));\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tk =  k % (median * 2);\n\t\t\t\t\tprintf(\"%d\\n\",total + (k-1) * 2 + (n-k));\t\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6062e5722464060ebf6e4312be6cb77d", "src_uid": "24b02afe8d86314ec5f75a00c72af514", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n\nint n,pos,ans;\n\nscanf(\"%d\",&n);\n\nscanf(\"%d\",&pos);\n\nif(pos>n/2)\nans=n+n+1+2*(n-k)+(k-1);\n\nelse\nans=n+n+1+2*(k-1)+(n-k);\n\nprintf(\"%d\",ans);\nreturn 0;\n}\n ", "lang_cluster": "C", "compilation_error": true, "code_uid": "26a4377e8d0a01205af2e2a418b3c5f1", "src_uid": "24b02afe8d86314ec5f75a00c72af514", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,k;\n    scanf(\"%d %d\",&n,&k);\n    if(k==1)\n    printf(\"%d\\n\",3*(n-k+1));\n    else if(k==2&&n==2)\n    else if(k==2&&n==3)\n    printf(\"%d\",4*(n-k)+6);\n    printf(\"%d\",6);\n     else if(k>n/2)\n     printf(\"%d\",4*(n-k)+5);\n    else\n     {\n             printf(\"%d\",3*n+k-1);\n    \n     }\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9f90dfc77d4445fc1e40c38696aca1ce", "src_uid": "24b02afe8d86314ec5f75a00c72af514", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,k;\n    scanf(\"%d %d\",&n,&k);\n    if(k==1)\n    printf(\"%d\\n\",3*(n-k+1));\n    else if(k==2)\n     printf(\"%d\",3*(n-k+1)+4);\n     else if(k>n/2)\n     printf(\"%d\",4*n-k;\n    else\n     {\n             printf(\"%d\",3*n+k-1);\n    \n     }\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e2a3752969e47635798ea9a7462cd75e", "src_uid": "24b02afe8d86314ec5f75a00c72af514", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nint r,x,rev,i;\nlong long int j=1;\nscanf(\"%d\",&x);\nr=(x/1000)%10;\nrev=(x/10000)*10000+((x%1000)/100)*1000+(x%10)*100+((x%100)/10)*10+r;\nfor(i=1;i<=5;i++)\nj=(j*rev)%100000;\nprintf(\"%5lld\",j);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8f2188f188a61d0f705a3421491d4fd5", "src_uid": "51b1c216948663fff721c28d131bf18f", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nchar a[6];\nscanf(\"%s\",a);\nb0=(a[0]-48)*10000;\nb1=(a[2]-48)*1000;\nb2=(a[4]-48)*100;\nb3=(a[3]-48)*10;\nb4=(a[1]-48);\nc=b0+b1+b2+b3+b4;\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "388ccd5c76dc24c5e76847d8df152982", "src_uid": "51b1c216948663fff721c28d131bf18f", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main ()\n{\n     char s[6];\n     scanf(\"%s\",s);\n     long long int s=1;\n     long long int i;\n     long long int n=((s[0]-48)*10000)+((s[2]-48)*1000)+((s[4]-48)*100)+((s[3]-48)*10)+(s[1]-48);\n     for(i=0;i<5;i++)\n     {\n          s=s*n;\n          s=s%100000;\n          \n     }\nprintf(\"%05lld\",ans);\nreturn 0;\n     \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5b1c6970db7ce378e1f3c49f4a31cc5c", "src_uid": "51b1c216948663fff721c28d131bf18f", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main ()\n{\n     char s[6];\n     scanf(\"%s\",s);\n     long long int s=1;\n     long long int i;\n     long long int n=((s[0]-48)*10000)+((s[2]-48)*1000)+((s[4]-48)*100)+((s[3]-48)*10)+(s[1]-48);\n     for(i=0;i<5;i++)\n     {\n          s=s*n;\n          s=s%100000;\n          \n     }\nprintf(\"%05lld\",s);\nreturn 0;\n     \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "918a01565f7ef271547f350b9aeee14b", "src_uid": "51b1c216948663fff721c28d131bf18f", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main ()\n{\n     char s[6];\n     scanf(\"%s\",s);\n     long long int s=1;\n     long long int i;\n     long long int n=((s[0]-48)*10000)+((s[2]-48)*1000)+((s[4]-48)*100)+((s[3]-48)*10)+(s[1]-48);\n     for(i=0;i<5;i++)\n     {\n          s=s*n;\n          s=s%100000;\n          \n     }\nprintf(\"%lld\",ans);\nreturn 0;\n     \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "50ce6cb1056cb9785a73e1db7d2df097", "src_uid": "51b1c216948663fff721c28d131bf18f", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <bits/stdc++.h>\nusing namespace std;\n\n  int main() {\n  char num[100];\n  long long int limit, p = 0, q = 1, ans;\n  int i, len, j, r;\n  scanf(\"%s\", num);\n  scanf(\"%lld\", &limit);\n  len = strlen(num);\n  for(i = len-1 ; i >= 0; i--, q *= 10) {\n      if(num[i] == '9') \n          continue;\n          p = q*(num[i] - 47);\n          if(p > limit)\n             break;\n          limit -= p; \n          j = i;\n          num[i] = '9';\n          while(j-- >= 0) {\n             if(num[j] != '0') {\n                num[j]--; \n                break;\n             } \n                num[j] = '9';\n              \n          }  \n  }\n  sscanf(num, \"%lld\", &ans);\n  printf(\"%lld\\n\", ans);\n  return 0;\n  }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "50d985732ec7d932dcdb87c801bab728", "src_uid": "c706cfcd4c37fbc1b1631aeeb2c02b6a", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main()\n{\n   int val(char t[25]);\n   char ans[25],t1[25],t2[25]={'0'};\n   long long a,b,ta;\n   int i,j,k,lt,now,str;\n   now=0;\n   scanf(\"%I64d %I64d\",&a,&b);\n   b=a-b; lt=0; ta=a;\n   while (ta!=0)\n   {\n     t1[lt++]=ta % 10;\n     ta=ta /10;\n   }\n   t1[lt+1]='\\0';\n   while (1)\n   {\n     strcpy(t2,t1);\n     for (i=0;i<=now;i++)\n       t2[i]='9';\n     while (val(t2)>=a)\n        if (t2[now+1]>'0') t2[now+1]--;\n         else break;\n     if ((val(t2)<a) && (val(t2)>b)) strcpy(ans,t2);\n         else break;\n     now++;\n   }\n   if (now==0)  printf(\"%I64d\",a);\n       else     printf(\"%I64d\",val(ans));\n}\nlong long val(char t[25])\n{\n   int i,lt,tt,ans;\n   tt=1;\n   ans=0;\n   for (i=0;i<=strlen(t);i++)\n   {\n    ans=ans+(t[i]-'0')*tt;\n    tt=tt*10;\n   }\n   return ans;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7dec60af9924f6de2ed8563aed976e60", "src_uid": "c706cfcd4c37fbc1b1631aeeb2c02b6a", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(){\n    long long p, d, i, m = 0;\n    scanf(\"%I64d%I64d\", &p, &d);\n    if (p < 10)printf(\"%I64d\\n\", p);\n    else {\n         for (i = 10 ; i <= p ; i *= 10){\n             if (p % i + 1 <= d)\n                m = p % i + 1;\n             else break;\n         }\n         printf(\"%I64d\\n\", p - m);\n    }\n    scanf(\" \");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1c8f3096118f397aa7bd990824cf2baf", "src_uid": "c706cfcd4c37fbc1b1631aeeb2c02b6a", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint num_digits(long long x);\n\nint main(void)\n{\n    long long p, d;\n    scanf(\"%I64d %I64d\", &p, &d);\n\n    int s = 1, q = 0;\n    long long p2 = p;\n\n    while (d > 0)\n    {\n        q = ((p2 % 10) + 1) * s;\n        s *= 10;\n        \n        if (num_digits(q) == num_digits(p) || d < q || q >= p)\n            break;\n      \n        if (q != s)\n        {\n            p = p-q;\n            d = d-q;\n        }\n        p2 = p/s;\n    }\n\n    printf(\"%I64d\\n\", p);\n    return 0;\n}\n\nint num_digits(long long x)\n{\n    if (x % 10 == x)\n        return 1;\n    return 1 + num_digits(x / 10);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9b6fb3cc0e452571613235105fd62d56", "src_uid": "c706cfcd4c37fbc1b1631aeeb2c02b6a", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main()\n{\n   //char ans[25],t1[25],t2[25]={'0'};\n   long long val(char t[25]);\n   long long a,b,ta,t1,ans;\n   long long bit[18],nine[18];\n   int i,j,k,lt,now,str;\n   now=0;\n   scanf(\"%I64d %I64d\",&a,&b);\n   b=a-b; lt=0;\n   bit[0]=1; nine[0]=9;\n   for (i=1;i<=17;i++)\n    {bit[i]=bit[i-1]*10; nine[i]=nine[i-1]*10+9;}\n   while (1)\n   {\n     t1=a;\n     t1=t1-(t1 % bit[now+1])+nine[now];\n     while (t1>=a)\n        t1=t1-bit[now+1];\n     if ((t1<a) && (t1>b)) ans=t1;\n       else break;\n     now++;\n   }\n   if (now==0)  printf(\"%I64d\",a);\n       else     printf(\"%I64d\",ans);\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "61318614d88b5b74fa65bd92e46528d4", "src_uid": "c706cfcd4c37fbc1b1631aeeb2c02b6a", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdbool.h>\n\n#define maxN 1000001\n\nbool isP[maxN];\nint ps[maxN];\n\nbool isPrime( int n ) {\n\tint i;\n\n\tfor( i = 2; (long long) i * i <= n; i++ )\n\t\tif( n % i == 0 ) return false;\n\t\n\treturn true;\n}\n\nint main( void ) {\n\tint i, j, c;\n\n\tisP[2] = isP[3] = isP[5] = 1;\n\n\tfor( i = 7; i < maxN; i += 2 )\n\t\tif( isPrime(i) ) isP[i] = 1;\n\t\n\tps[0] = 0;\n\tfor( i = 1; i < maxN; i++ )\n\t\tps[i] = ps[i-1] + isP[i];\n\t\n\tint a, b, k;\n\tscanf(\"%i %i %i\", &a, &b, &k);\n\t\n\tint lo = 0, hi = b, ans = -1, mid;\n\twhile( lo <= hi ) {\n\t\tmid = (lo + hi) / 2;\n\n\t\tif( b - mid + 1 < a ) break;\n\n\t\tint cnt = ps[a+mid-1] - ps[a-1];\n\t\t\n\t\tbool ok = 1;\n\t\tif( cnt < k ) ok = 0;\n\n\t\tfor( i = a+1; i <= b-mid+1; i++ )\n\t\t\tif( ps[i+mid-1] - ps[i-1] < k ) ok = 0;\n\n\t\tif( ok ) {\n\t\t\tans = mid;\n\t\t\thi = mid - 1;\n\t\t} else lo = mid + 1;\n\n\t}\n\n\tprintf(\"%i\\n\", ans);\n\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e8b9fb9ecc5b43a8605eb4f721924ec1", "src_uid": "3e1751a2990134f2132d743afe02a10e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MAXN 1000001\n\nchar Flag[MAXN];\nint  Prime[79000];\nint  Cnt;\n\nvoid Make()\n{\n    int i,j;\n    for(Cnt=0,i=2; i<MAXN; ++i)\n    {\n        if(!Flag[i])\n        {\n            Prime[Cnt++]=i;\n            for(j=i<<1; j<MAXN; j+=i)\n            {\n                Flag[j]=1;\n            }\n        }\n    }\n    return;\n}\n\nint Binary(int key)\n{\n    int Left,Mid,Right;\n    Left=0;\n    Right=Cnt;\n    while(Right>=Left)\n    {\n        Mid=(Left+Right)/2;\n        if(Prime[Mid]==key)\n        {\n            return Mid;\n        }\n        else if(Prime[Mid]<key)\n        {\n            Left=Mid+1;\n        }\n        else\n        {\n            Right=Mid-1;\n        }\n    }\n    return Left;\n}\n\nint main()\n{\n    int A,B,K,i,Max,temp;\n    Make();\n    scanf(\"%d %d %d\",&A,&B,&K);\n    for(Max=0,i=A; Prime[Binary(i)+K-1]<=B; ++i)\n    {\n        temp=Prime[Binary(i)+K-1]-i+1;\n        if(temp>Max)\n        {\n            Max=temp;\n        }\n    }\n    temp=Binary(B);\n    if(B==Prime[temp])\n    {\n        --K;\n    }\n    temp=Prime[temp-K];\n    temp=B-temp+1;\n    if(temp>Max)\n    {\n        Max=temp;\n    }\n    if(Max>B-A+1)\n    {\n        puts(\"-1\");\n    }\n    else\n    {\n        printf(\"%d\\n\",Max);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "da7f571dc2fdecdfe72aeb90d8986b3b", "src_uid": "3e1751a2990134f2132d743afe02a10e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint t,x,y,k,q,l;\n\tint sv[2000000];\n\tint i,j=0;\n\tfor(i=2;i<1000000;i++)\n\tfor(j=2;j*i<2000000;j++)\n\t\tsv[i*j]=1;\n\tscanf(\"%d\",&t);\n\tfor(i=0;i<1000;i++)\n\t//\tprintf(\"%d\",sv[i]);\n\twhile(t-->0)\n\t{\tint c=0;\n\t\tscanf(\"%d %d %d\",&x,&y,&k);j=y+2;\n\t\tint mid,low=0,high=(y-x+1);\n\t\tmid=(low+high)/2;\n\t\twhile(low<=high)\n\t\t{\tl=mid;\n\t\t//\tprintf(\"%d\",sv[i]);\n\t\t\tfor(q=(y-l+1);q>=x;q--)\n\t\t{\tc=0;\n\t\t\tfor(i=q;i<(q+l);i++)\n\t\t\t\tif(sv[i]==0)\n\t\t\t\t\tc++;\n\t\t\tif(c<k)\n\t\t\t{low=mid+1;mid=(high+low)/2;break;\n\t\t\t}\n\t\t\telse if(q==x)\t\n\t\t\t\t{j=l;high=mid-1;mid=(high+low)/2;}\n\t\t\t\n\t\t}\n}\t\t\n\t\tif(j!=(y+2))\n\t\t\tprintf(\"%d\\n\",j);\n\t\telse\n\t\t\tprintf(\"-1\\n\");\n\t}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6f3473874f3ed1b68d9a993d0b739df5", "src_uid": "3e1751a2990134f2132d743afe02a10e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MAXN 1000001\n\nchar Flag[MAXN];\nint  Prime[79000];\nint  Cnt;\n\nvoid Make()\n{\n    int i,j;\n    for(Cnt=0,i=2; i<MAXN; ++i)\n    {\n        if(!Flag[i])\n        {\n            Prime[Cnt++]=i;\n            for(j=i<<1; j<MAXN; j+=i)\n            {\n                Flag[j]=1;\n            }\n        }\n    }\n    return;\n}\n\nint Binary(int key)\n{\n    int Left,Mid,Right;\n    Left=0;\n    Right=Cnt;\n    while(Right>=Left)\n    {\n        Mid=(Left+Right)/2;\n        if(Prime[Mid]==key)\n        {\n            return Mid;\n        }\n        else if(Prime[Mid]<key)\n        {\n            Left=Mid+1;\n        }\n        else\n        {\n            Right=Mid-1;\n        }\n    }\n    return Left;\n}\n\nint main()\n{\n    int A,B,K,i,Max,temp;\n    Make();\n    while(scanf(\"%d %d %d\",&A,&B,&K)!=EOF)\n    {\n        for(Max=0,i=A; Prime[Binary(i)+K-1]<=B; ++i)\n        {\n            temp=Prime[Binary(i)+K-1]-i+1;\n            if(temp>Max)\n            {\n                Max=temp;\n            }\n        }\n        temp=Binary(B);\n        if(B==Prime[temp])\n        {\n            --K;\n        }\n        temp=Prime[temp-K];\n        temp=B-temp+1;\n        if(temp>Max)\n        {\n            Max=temp;\n        }\n        if(Max>B-A+1)\n        {\n            puts(\"-1\");\n        }\n        else\n        {\n            printf(\"%d\\n\",Max);\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a699ce8ed661610343e616b9d7a7a0da", "src_uid": "3e1751a2990134f2132d743afe02a10e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint p[100000001];\nvoid isPrime(int n)\n{\n\tint i,j,prime;\n\n\tp[0] = 0;\n\tp[1] = 0;\n\n\tfor(i=2;i*i<=n;i++)\n\t{\n\t\tif(p[i] == 1)\n\t\t{\n\t\t\tfor(j=i*2;j<=n;j+=i)\n\t\t\t{\n\t\t\tp[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n}\n\nint check_prime(int a,int b,int l,int k)\n   {\n\nint c = 0;\n   isPrime(b);\n\n   for(int i=a;i<=a+l-1;i++)\n   {\n   \tif(p[i] == 1)\n   \t{\n   \tc++;\n   \t}\n\n   }\t\nif(c<k)\n\treturn 0;\n\nint i=a,j=a+l-1;\nwhile(j<b)\n{\n\tif(p[i]==1)\n\t\tc--;\n\ti++;\n\tj++;\n\n\tif(p[j]==1)\n\t\tc++;\n\n\tif(c<k)\n          return 0;\n\n}\n\nif(c<k)\n{\n\treturn\t0;\n} \nreturn 1;\n}\n\nint main()\n{\n\tint i,j,k,l,a,b;\n\tint s,e;\n\tint r,n,q = -1;\n\tscanf(\"%d %d %d\", &a,&b,&k);\n\tfor(i=0;i<=b;i++)\n\t{\n\t\tp[i] = 1;\n\t}\n\ts = 1;\n\te = b - a + 1;\n\twhile(s<=e)\n\t{\n\t\tl = (s+e)/2;\n\t\tr = check_prime(a,b,l,k);\n\t\tif(r == 0)\n\t\t{\n\t\t\ts = l+1;\n\t\t}\n\t\tif(r == 1)\n\t\t{\n\t\t\tq = l;\n\t\t\te = l-1;\n\t\t}\n\t}\n\t\tprintf(\"%d\\n\",q);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ca7289c8ca2354635dacbc65396d1e5c", "src_uid": "3e1751a2990134f2132d743afe02a10e", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\r\n#include <cmath>\r\nusing namespace std;\r\n\r\nint main(){\r\n    unsigned short t;\r\n    cin >> t;\r\n    while(t--){\r\n        unsigned short n;\r\n        cin >> n;\r\n        cout << (int)pow(2,n)-1 << endl;\r\n    }\r\n    return 0;\r\n}\r\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9a6e58a849b3c6f0a4b1528392a15b62", "src_uid": "d5e66e34601cad6d78c3f02898fa09f4", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n#include<stdlib.h>\r\n#include<cmath>\r\n#include<iostream>\r\nusing namespace std;\r\nint main()\r\n{\r\n\tint n;\r\n\tcin>>n;\r\n\tint *a=(int*)malloc(sizeof(int)*n);\r\n\tfor(int i=0;i<n;i++)\r\n\tcin>>a[i];\r\n\tfor(int i=0;i<n;i++)\r\n\tcout<<pow(2,a[i])-1<<endl;\r\n\treturn 0;\r\n } \r\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "eab81839ebb95a99a9ef7e36dcf9bf01", "src_uid": "d5e66e34601cad6d78c3f02898fa09f4", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\nint main()\r\n{\r\n\tint n;\r\n\tscanf(\"%d\",&n);\r\n\twhile(n--)\r\n\t{\r\n\t\tint num;\r\n\t\tscnaf(\"%d\",&num);\r\n\t\tnum = 1 << num;\r\n\t\tnum--;\r\n\t\tprintf(\"%d\\n\",num);\r\n\t\t\r\n\t}\r\n\r\n\t\r\n\t\r\n   \r\n \r\n}\r\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "85e0c2b4b052fbaa8a4483a7aaad788f", "src_uid": "d5e66e34601cad6d78c3f02898fa09f4", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\nint main()\r\n{\r\n\tint t;\r\n\tscanf_s(\"%d\", &t);\r\n\twhile (t--) {\r\n\t\tint n;\r\n\t\tlong int sum = 2;\r\n\t\tscanf_s(\"%d\", &n);\r\n\t\tfor (int i = 2;i <= n;i++) {\r\n\t\t\tsum *= 2;\r\n\t\t}\r\n\t\tprintf(\"%d\", sum - 1);\r\n\t}\r\n\treturn 0;\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cd368e7c7e2d1e79159254f5016e8b85", "src_uid": "d5e66e34601cad6d78c3f02898fa09f4", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\r\n#include <cmath>\r\nusing namespace std;\r\n\r\nint ans(unsigned int n){\r\n    return (int)pow(2,n)-1;\r\n}\r\n\r\nint main(){\r\n    unsigned short t;\r\n    cin >> t;\r\n    while(t--){\r\n        unsigned short n;\r\n        cin >> n;\r\n        cout << ans(n) << endl;\r\n    }\r\n    return 0;\r\n}\r\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e9e5bb38e46879725e49ee9c51a9355a", "src_uid": "d5e66e34601cad6d78c3f02898fa09f4", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main()\n{\n    char *original=NULL, *received=NULL;\n    size_t org_size;\n    int length;\n    getline(&original, &org_size, stdin);\n    getline(&received, &org_size, stdin);\n    length = strlen(received);\n    int final=0, sure=0, doubts=0;\n    int i,j,k;\n\n    for(i=0; i<length; i++)\n    {\n        if(original[i] == '+') final++;\n        else if(original[i] == '-') final--;\n        else break;\n        if(received[i] == '+') sure++;\n        else if (received[i] == '-') sure--;\n        else doubts++;\n    }\n    int plus = final - sure;\n    if (plus < 0) plus = doubts - plus;\n    if(((plus == 0) && (doubts%2 != 0)) || plus > doubts){\n            printf(\"0.000000000000\\n\");\n            return 0;\n    }\n    if (plus == 0) plus = doubts/2;\n    int num = 1;\n    int deno = 1;\n    for(i=0; i<plus; i++)\n    {\n        num = num*(doubts - i);\n        deno = deno*(plus - i);\n    }\n    for(i=0;i<doubts;i++) deno = deno*2;\n    printf(\"%.12f\\n\", (float)(num)/(float)(deno));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d482e041db52b0256f7ddb34932c575f", "src_uid": "f7f68a15cfd33f641132fac265bc5299", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<string.h>\n#include<stdlib.h>\n   int compare( const void* a, const void* b)\n    {\n        long long int int_a = * ( (int*) a );\n        long long int int_b = * ( (int*) b );\n\n        if ( int_a == int_b ) return 0;\n        else if ( int_a < int_b ) return -1;\n        else return 1;\n    }\nlong int fact(int x)\n   {\n     long int f=1;\n     int i;\n     for(i=1;i<=x;i++)\n       f=f*i;\n     return(f);\n   }\nint main()\n{\n    char s1[10],s2[10];\n    double ans;\n    int i,j,sig1=0,sig2=0,un,a[1025];\n    scanf(\"%s\",s1);\n    getchar();//printf(\"p\");\n    gets(s2);\n\n    for(i=0;i<strlen(s1);i++)\n    {\n        if(s1[i]=='+')\n            sig1++;\n        else\n            sig1--;\n    }\n    for(i=0;i<strlen(s2);i++)\n    {\n        if(s2[i]=='+')\n            sig2++;\n        else if(s2[i]=='-')\n            sig2--;\n        else if(s2[i]=='?')\n            un++;\n    }//printf(\"%d %d %d un  \",sig1,sig2,un);\n    if(un==0){if(sig1==sig2) printf(\"1\"); else printf(\"0\");exit(0);}\n\n    int l=1;\n    int p = (int)pow(2,(float)un);//printf(\"%d\",p);\n    a[0]=sig2+un;\n    for(i=1;i<=un;i++)\n    {\n        int ncr = fact(un)/fact(i);//printf(\"ncr = %d\",ncr);\n        for(j=0;j<ncr;j++)\n        {\n                a[l] =sig2-un+2*i;//printf(\"al = %d\",a[l]);\n                l++;\n        }\n        if(a[l]==sig1)\n        {\n            ans =(double)((double)ncr/(double)p);\n            printf(\"%f\",ans);\n            exit(0);\n        }\n    }\n    printf(\"0\");\n    return 0;\n}\n#include<stdio.h>\n#include<math.h>\n#include<string.h>\n#include<stdlib.h>\n   int compare( const void* a, const void* b)\n    {\n        long long int int_a = * ( (int*) a );\n        long long int int_b = * ( (int*) b );\n\n        if ( int_a == int_b ) return 0;\n        else if ( int_a < int_b ) return -1;\n        else return 1;\n    }\nlong int fact(int x)\n   {\n     long int f=1;\n     int i;\n     for(i=1;i<=x;i++)\n       f=f*i;\n     return(f);\n   }\nint main()\n{\n    char s1[10],s2[10];\n    double ans;\n    int i,j,sig1=0,sig2=0,un,a[1025];\n    scanf(\"%s\",s1);\n    getchar();//printf(\"p\");\n    gets(s2);\n\n    for(i=0;i<strlen(s1);i++)\n    {\n        if(s1[i]=='+')\n            sig1++;\n        else\n            sig1--;\n    }\n    for(i=0;i<strlen(s2);i++)\n    {\n        if(s2[i]=='+')\n            sig2++;\n        else if(s2[i]=='-')\n            sig2--;\n        else if(s2[i]=='?')\n            un++;\n    }//printf(\"%d %d %d un  \",sig1,sig2,un);\n    if(un==0){if(sig1==sig2) printf(\"1\"); else printf(\"0\");exit(0);}\n\n    int l=1;\n    int p = (int)pow(2,(float)un);//printf(\"%d\",p);\n    a[0]=sig2+un;\n    for(i=1;i<=un;i++)\n    {\n        int ncr = fact(un)/fact(i);//printf(\"ncr = %d\",ncr);\n        for(j=0;j<ncr;j++)\n        {\n                a[l] =sig2-un+2*i;//printf(\"al = %d\",a[l]);\n                l++;\n        }\n        if(a[l]==sig1)\n        {\n            ans =(double)((double)ncr/(double)p);\n            printf(\"%f\",ans);\n            exit(0);\n        }\n    }\n    printf(\"0\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f462a47697c7594ef10e26fe3364efd9", "src_uid": "f7f68a15cfd33f641132fac265bc5299", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<math.h>\n\nusing namespace std;\n\nint CombinationsRecur(int iN, int iR) {\n    if (iR < 0 || iR > iN) {\n        return 0;\n    }\n    if (iR < 1) {\n        return 1;\n    }\n    if (iN == iR) {\n        return 1;\n    }\n    return CombinationsRecur(iN - 1, iR) + CombinationsRecur(iN - 1, iR - 1);\n}\n\nint main(){\n\n\tchar s1[10];\n\tchar s2[10];\n\tscanf(\"%s\",s1);\n\tscanf(\"%s\",s2);\n\tint n=strlen(s1);\n\n    int arr[2];\n    arr[0]=arr[1]=0;\n\n    for(int i=0;i<n;i++)\n        if(s1[i]=='+') arr[0]++;\n        else arr[1]++;\n\n    for(int i=0;i<n;i++)\n        if(s2[i]=='+') arr[0]--;\n        else if(s2[i]=='-') arr[1]--;\n\n    //printf(\"%d %d\\n\",arr[0],arr[1]);\n\n    if((arr[0]<0)||(arr[1]<0)){\n        printf(\"%1.9f\",(float)0.0);\n        return 0;\n    }\n\n    if((arr[0]==0)&&(arr[1]==0)){\n        printf(\"%1.9f\",(float)1.0);\n        return 0;\n    }\n\n    int u=CombinationsRecur(arr[0]+arr[1],arr[0]);\n    int v=pow(2,(arr[0]+arr[1]));\n    float h=(float)u/(float)v;\n    printf(\"%1.9f\",h);\n\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "212fdcd89c9f072467b83d2280d84d96", "src_uid": "f7f68a15cfd33f641132fac265bc5299", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint b(int i,int unknown);\nint main()\n{\n    int size=0,f=0,i=0,r,count=0,unknown=0,known=0;\n    int y,demosum;\n    double c,s;\n    char s1[11],s2[11];\n\n    gets(s1);\n    gets(s2);\n\n\n\n    while(s1[i]!='\\0')\n    {\n        if(s1[i]=='+')\n            f++;\n        else\n            f--;\n\n        size++;\n        i++;\n    }\n\n    for(i=0;i<size;i++)\n    {\n        if(s2[i]=='?')\n            unknown++;\n        else if(s2[i]=='+')\n            known++;\n        else\n            known--;\n    }\n    y=pow(2,unknown);\n\n\n    if(unknown!=0)\n    {\n        for(k=0;k<y;k++)\n        {\n            r=0;\n            demosum=b(k,unknown);\n            r=demosum+known;\n            if(r==f)\n                count++;\n        }\n        s=y;\n        c=count;\n        printf(\"%lf\",c/s);\n\n    }\n    else\n    {\n        if(known==f)\n            printf(\"1.000000000000\");\n        else\n            printf(\"0.000000000000\");\n\n\n    }\n    return 0;\n}\n\n\n\nint b(int i,int unknown)\n{\n    int sum,z,j;\n    char str[unknown];\n    sum=0;\n    z=0;\n    if(i==0)\n        return(-unknown);\n    while(i!=0)\n    {\n        if(i%2==0)\n        {\n            str[z]='0';\n            z++;\n        }\n        else\n        {\n            str[z]='1';\n            z++;\n        }\n        i=i/2;\n    }\n    for(j=z;j<unknown;j++)\n        str[j]='0';\n    for(j=unknown-1;j>=0;j--)\n    {\n        if(str[j]=='1')\n            sum++;\n        else\n            sum--;\n    }\n    return (sum);\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4aa3d6edc635c6f706685358dd9d84a3", "src_uid": "f7f68a15cfd33f641132fac265bc5299", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<string.h>\nint main () {\n    int a[11][1024],i,j,p=0;\n        a[1][0]=1;\n        a[1][1]=-1;\n        for(i=2;i<=10;i++) {\n            for(j=0;j<(int)pow(2,i-1);j++)\n            a[i][p++]=a[i-1][j]+1;\n            for(j=0;j<(int)pow(2,i-1);j++)\n            a[i][p++]=a[i-1][j]-1;\n            p=0;\n        }\n        int d=0,f=0,k=0,ctr=0;\n         double ans,ctr1,p1;\n        char c[11],b[11];\n        scanf(\"%s%s\",c,b);\n        for(i=0;i<strlen(c);i++) \n        if(c[i]=='+') d++;\n        else d--;\n        //printf(\"%d\\n\",d);\n        for(i=0;i<strlen(b);i++) {\n        if(b[i]=='?') f++;\n        else if(b[i]=='+') k++;\n        else k--;}\n        //printf(\"%d %d\\n\",f,k);\n        if(f==0&&d==k) printf(\"1.000000000000\");\n        else if(f==0&&d!=k) printf(\"0.000000000000\");\n        else  {\n        int temp = (int)pow(2,f)\n        for(j=0;j<temp;j++)\n        if(k+a[f][j]==d) ctr++;\n        //printf(\"%d\\n\",ctr);\n        ctr1=(double)ctr;\n        p1=(int)pow(2,f);\n        ans=(double)ctr1/p1;\n        printf(\"%0.9lf\\n\",ans);}\n       /* for(i=1;i<=10;i++) {\n            for(j=0;j<pow(2,i);j++) printf(\"%d \",a[i][j]);\n            printf(\"\\n\");\n        }*/\n        return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d003f4c414918a3b8210d528a6c99f40", "src_uid": "f7f68a15cfd33f641132fac265bc5299", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main(void)\n{\n    int i, n, s, pos_c, pos_s, vel_c, win;\n    char states[201], direction[10];\n    \n    memset(states, 0, sizeof(states));\n    memset(direction, 0, sizeof(direction));\n    \n    scanf(\"%d%d%d%*s%s%s\", &n, &pos_s, &pos_c, direction, states);\n    \n    if (!strcmp(direction, \"head\")) vel_c = -1;\n    else vel_c = 1;\n\n    s = strlen(states);\n\n    if (pos_s < pos_c) pos_s = 1;\n    else pos_s = n;\n\n    win = 0;\n\n    for (i = 0; i < s; i++)\n    {\n        if (pos_c == pos_s) { win = 1; break; }\n        if (pos_c == 1 && vel_c == -1) vel_c = 1;\n        if (pos_c == n && vel_c == 1) vel_c = -1;\n        \n        if (states[i] == '0')\n        {\n            pos_c += vel_c;\n        }\n        else\n        {\n            pos_c += vel_c;\n            if (pos_c > 1) {\n                if (vel_c == 1) pos_s = 1;\n                else pos_s = n;\n            }\n            if (pos_c < n) {\n                if (vel_c == -1) pos_s = n;\n                else pos_s = 1;\n            }\n        }\n    }\n\n    if (win)\n        printf(\"Controller %d\\n\", i);\n    else\n        printf(\"Stowaway\\n\");\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f698ed0959378ea2bbed2a1fc70beca6", "src_uid": "2222ce16926fdc697384add731819f75", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main (void) {\n\tint n, st, co, ht, ok, i, tail;\n\tchar s[201];\n\tscanf (\"%d%d%d\\n\", &n, &st, &co);\n\tscanf (\"to %s\", s);\n\ttail = (s[0]=='t');\n\tscanf (\"%s\", s);\n\tfor (ok = i = 0; s[i] != '1' && !ok; i++) {\n\t\tif (st < co && st > 1)\t/*st esta pro lado do 1 <- -> ou <- <-*/\n\t\t\tst--;\n\t\telse if (st > co && st < n)\t/*st esta pro lado do n -> -> ou <- ->*/\n\t\t\tst++;\n\t\tif (tail) { /* vai pro n */\n\t\t\tif (++co == n)\ttail = 0;\n\t\t} else { /* vai pro 1 */\n\t\t\tif (--co == 1)\ttail = 1;\n\t\t}\n\t\tif (co == st)\tok = 1;\n\t}\n\tif (!ok) { /* s[i] == 1 */\n\t\twhile (s[i] != '\\0' && !ok) {\n\t\t\tif (tail) {\n\t\t\t\tst = 1;\n\t\t\t\tif(++co == n)\ttail = 0;\n\t\t\t} else {\n\t\t\t\tst = n;\n\t\t\t\tif (--co == 1)\ttail = 1;\n\t\t\t}\n\t\t\tfor (++i; s[i] != '1' && s[i] != '\\0' && !ok; i++) {\n\t\t\t\tif (tail) {\n\t\t\t\t\tif(++co == n)\ttail = 0;\n\t\t\t\t} else {\n\t\t\t\t\tif (--co == 1)\ttail = 1;\n\t\t\t\t}\n\t\t\t\tif (co == st)\tok = 1;\n\t\t\t}\n\t\t}\n\t}\n\tif (!ok)\tprintf (\"Stowaway\\n\");\n\telse\tprintf (\"Controller %d\\n\", i);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "68dc83fd1202943b6bfee7fc7da8c4a2", "src_uid": "2222ce16926fdc697384add731819f75", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main()\n{\n     int n, m, k, l, p, i;\n     char c[5], s[201];\n\n     scanf(\"%d %d %d\", &n, &k, &m);\n     scanf(\"%*s %s\", c);\n     scanf(\"%s\", s);\n\n     if (c[0] == 'h') {\n\t  p = 0;\n     } else {\n\t  p = 1;\n     }\n\n     l = strlen(s);\n\n     for (i = 0; i < l; i++) {\n\t  if (s[i] == '0') {\n\t       if (k < m) {\n\t\t    k--;\n\n\t\t    if (k == 0) k = 1;\n\t       } else {\n\t\t    k++;\n\n\t\t    if (k == n + 1) k = n;\n\t       }\n\n\t       if (p == 0) {\n\t\t    m--;\n\n\t\t    if (m == 1) p = 1;\n\t       } else {\n\t\t    m++;\n\n\t\t    if (m == n) p = 0;\n\t       }\n\n\t       if (m == k) {\n\t\t    printf(\"Controller %d\\n\", i + 1);\n\n\t\t    break;\n\t       }\n\t  } else {\n\t       if (p == 0) {\n\t\t    m--;\n\n\t\t    if (m == 1) p = 1;\n\t       } else {\n\t\t    m++;\n\n\t\t    if (m == n) p = 0;\n\t       }\n\n\t       if ((m > 1 && p == 1) || m == n) {\n\t\t    k = 1;\n\t       } else {\n\t\t    k = n;\n\t       }\n\t  }\n     }\n\n     if (i == l) puts(\"Stowaway\");\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5a5c74d1b5dc473b6e801515dbc01166", "src_uid": "2222ce16926fdc697384add731819f75", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint far(int enemy,int dir,int n){\n  if(enemy==0) return n-1;\n  if(enemy==n-1) return 0;\n  if(dir==1) return 0;\n  return n-1;\n}\n\nint main(){\n  int i,j,k,l,m,n,len,turn;\n  int now, enemy, dir;\n  char in[1000], a[100], b[100];\n\n  while(scanf(\"%d%d%d\",&n,&now,&enemy)==3){\n    scanf(\"%s%s%s\",a,b,in);\n    if(b[0]=='h') dir=-1; else dir=1;\n\n    now--; enemy--;\n    if(enemy+dir < 0 || enemy+dir >= n) dir *= -1;\n\n    if(now < enemy) now = 0;\n    else now = n-1;\n\n    for(i=0;;i++) if(in[i]<' ') break; len=i;\n    rep(turn,len){\n      if(in[turn]=='1') now=-1;\n      if(in[turn]=='0' && now==-1) now = far(enemy,dir,n);\n      \n      enemy += dir;\n      if(enemy+dir < 0 || enemy+dir >= n) dir *= -1;\n\n      if(enemy==now) break;\n    }\n\n    if(turn==len)puts(\"Stowaway\"); else printf(\"Controller %d\\n\",turn+1);\n  }\n\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "34a864f68670772d00e31729a5d4452a", "src_uid": "2222ce16926fdc697384add731819f75", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main() {\n\tint n,m,k;\n\tint i;\n\tchar a[3],b[5];\n\tchar c[201];\n\tchar *p;\n\t// 1->     -1<-\n\tint d;\n\tscanf(\"%d %d %d\", &n, &m, &k);\n\tscanf(\"%s %s\",a,b);\n\tscanf(\"%s\", c);\n\n\tif(n==2){\n\t\tprintf(\"Controller 1\\n\");\n\t\treturn 0;\n\t}\n\n\tif(b[0] == 'h')\n\t\td = -1;\n\telse\n\t\td = 1;\n\n\tfor(p=c,i=1; *p!='\\0'; p++,i++) {\n\t\t// move stowaway\n\t\tint f = 0\n\t\tif(d == 1) {\n\t\t\tif(*p=='1'){\n\t\t\t\tif(k!=1)\n\t\t\t\t\tm = k-1;\n\t\t\t\telse\n\t\t\t\t\tm = k+2;\n\t\t\t} else if(m-k==1 && m!=n){\n\t\t\t\tm += 1;\n\t\t\t}\n\t\t\tf = 1;\n\t\t}else{\n\t\t\tif(*p=='1'){\n\t\t\t\tif(k!=n)\n\t\t\t\t\tm = k+1;\n\t\t\t\telse\n\t\t\t\t\tm = k-2;\n\t\t\t} else if(k-m==1 && m!=1){\n\t\t\t\tm -= 1;\n\t\t\t}\n\t\t}\n\n\t\t// move controller\n\t\tk += d;\n\t\tif(k == 1)\n\t\t\td = 1;\n\t\tif(k == n)\n\t\t\td = -1;\n\n\t\tif(k == m && f == 0){\n\t\t\tprintf(\"Controller %d\\n\",i);\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\tprintf(\"Stowaway\\n\");\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "25f4ed2e929c7862b46a081c40e5af84", "src_uid": "2222ce16926fdc697384add731819f75", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define mod 1000000007\nint main()\n{\n    long long n,abc,d,nabc,nd;\n    abc=0;  //originally not at a/b/c\n    d=1;    //originally at d\n    scanf(\"%I64d\",&n);\n    while(n--)      //after n steps get completed\n    {\n        nabc=(abc*2LL + d)%mod;   //to come at a/b/c..we have 3 options\n        nd=(abc*3LL4)%mod;         //to come at d..we have 3 options\n        abc=nabc;\n        d=nd;\n    }\n    printf(\"%I64d\\n\",d);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b3d92b0c3c6976311760e0a2273e3f6d", "src_uid": "77627cc366a22e38da412c3231ac91a8", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <conio.h>\n \nint main()\n{\n    /* Enter your code here. Read input from STDIN. Print output to STDOUT */\n    int N = 0;\n    scanf(\"%d\", &N);\n    if(N<2)\n        return 0;\n    long long currentD=0, oldD=0, currentA=0, oldA=1, modulo=1000000007;\n    for(int i=2;i<=N;i++)\n    \tcurrentD=(3*oldA)%modulo, currentA=((2*oldA)%modulo+oldD%modulo)%modulo. oldA=currentA, oldD=currentD;\n    printf(\"%ll\\n\", oldD);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dfc99be8e31de771e8eadc966bb1c8c8", "src_uid": "77627cc366a22e38da412c3231ac91a8", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <conio.h>\n\nint main()\n{\n    /* Enter your code here. Read input from STDIN. Print output to STDOUT */\n    int N = 0;\n    scanf(%d, &N);\n    if(N<2)\n        return 0;\n    int ways[N]={0};\n    ways[1]=3;\n    for(int i=1;i<N;i++)\n        ways[i]=(3*(long long)ways[i-1])%1000000007;\n    printf(\"%d\\n\",ways[N-1]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "91a3f9fbb75fb82c47f8d49032219f82", "src_uid": "77627cc366a22e38da412c3231ac91a8", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\nint main()\n{\n    long long int n,val=1000000007;\n    scanf(\"%lld\",&n);\n    long long int steps[10000005]={0};\n    steps[1]=0;\n    for(int i=2;i<=n;i++)\n    {\n        steps[i]=(pow(3,i-1)%val)-steps[i-1];\n    }\n    printf(\"%lld\",steps[n]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "543f36ecbab2f4332c60e5f9d10e10c7", "src_uid": "77627cc366a22e38da412c3231ac91a8", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <stdbool.h>\n#include <math.h>\n#include <string.h>\n\n\nlong long int f(int x)\n{\n    long long int res = 0;\n    if(x%2 == 0)\n    {\n        x /= 2;\n        long long int multplier = 1;\n        for(int i = 0; i < x; i++)\n        {\n            res = (res+multplier) % 1000000007;\n            multplier = (multplier*9) % 1000000007;\n        }\n        res = (2*res+1) % 1000000007;\n    }\n    else\n    {\n        int _x /= 2;\n        long long int mult = 1;\n        while(_x-- > 0) mult = (mult*9)%1000000007;\n        res = mult - f(x-1);\n        while(res < 0) res += 1000000007;\n    }\n    return res%1000000007;\n}\n\nint main()\n{\n    int n;\n    scanf(\"%d\", &n);\n    printf(\"%lld\", f(n)%1000000007);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c46ebb48ddaa0d5a724bc76d64b67900", "src_uid": "77627cc366a22e38da412c3231ac91a8", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(){\n    int a1[1000],b1[1000],i,at[1000],n,a,b,m;\n    scanf(\"%d %d %d\",&n,&a,&b){\n        memset(at,0,1000);\n        for(i=0;i<a;i++) {\n            scanf(\"%d\",&a1[i]);\n        }\n        for(i=0;i<b;i++){\n            scanf(\"%d\",&m);\n            at[m]=2;\n        }\nfor(i=0;i<a;i++){\n    at[a1[i]]=1;\n}\nfor(i=1;i<=n;i++) printf(\"%d \",at[i]);\nprintf(\"\\b\\n\");\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a7421789a2782e3df0da24b96cd357e6", "src_uid": "a35a27754c9c095c6f1b2d4adccbfe93", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<math.h>\n#include<stdlib.h>\n#define sort radix_sort(a,n)\nint min(int p,int q)\n{\n    if(p>q) return q;\n    else return p;\n}\nint max(int p,int q)\n{\n    if(p>q) return p;\n    else return q;\n}\ntypedef long long int ll;\n  //n=inp();\ninline ll inp()\n{\n    ll n=0,s=1;\n    char p=getchar();\n    if(p=='-')\n    s=-1;\n    while((p<'0'||p>'9')&&p!=EOF&&p!='-')\n    p=getchar();\n    if(p=='-')\n    s=-1,p=getchar();\n    while(p>='0'&&p<='9')\n    {\n    n = (n<< 3) + (n<< 1) + (p - '0');\n    p=getchar();\n    };\n    return n*s;\n}\nvoid radix_sort(int a[], int n)\n{\n    int i, x[n+1], m = 0, exp = 1;\n    for (i = 1; i <= n; i++)\n        if (a[i] > m)\n            m = a[i];\n    while (m / exp > 0)\n    {\n        int box[10] = {0,0,0,0,0,0,0,0,0,0};\n        for (i = 0; i < n; i++)\n            box[a[i] / exp % 10]++;\n        for (i = 1; i < 10; i++)\n            box[i] += box[i - 1];\n        for (i = n-1; i >= 0; i--)\n        {\n            x[--box[a[i] / exp % 10]] = a[i];\n        }\n        for (i = 0; i < n; i++)\n        {\n            a[i] = x[i];\n        }\n        exp *= 10;\n    }\n}\n  //sort;\nint main()\n{\n    int j,n,i,k,a,b;\n    scanf(\"%d%d%d\",&n,&a,&b);\n    int arr[a];int all[b];int w[n+1];\n    for(i=0;i<=a-1;i++)\n        scanf(\"%d\",&arr[i]);\n    for(i=0;i<=b-1;i++)\n        scanf(\"%d\",&all[i]);\n     for(i=0;i<=n;i++)\n            w[i]=0;\n    for(i=1;i<=n;i++)\n    {\n        for(j=0;j<a;j++)\n        {\n            if(i==arr[j] && w[i]==0)\n            {   printf(\"1 \");\n                w[i]=1;\n            }\n        }\n            for(k=0;k<b;k++)\n            {\n                if(i==all[k] && w[i]==0)\n                {   printf(\"2 \");\n                    w[i]=1;\n                }\n            }\n\n    }\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d8f5927e1566e6bdf1bb0b4c14ae92ed", "src_uid": "a35a27754c9c095c6f1b2d4adccbfe93", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<algorithm>\nusing namespace std;\nint mian()\n{\n    int i,j,n,a1,b1,a[105],b[105],count=0;\n    scanf(\"%d%d%d\",&n,&a1,&b1);\n    for(i=0;i<a1;i++)\n        scanf(\"%d\",a[i]);\n    for(i=0;i<b1;i++)\n        scanf(\"%d\",b[i]);\n    sort(a,a+a1);\n    for(i=1;i<=n;i++)\n    {\n        if(a[count]==i)\n        {\n            printf(\"1\");\n            count++;\n        }\n        else\n            printf(\"2\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "153c945784cffbd6e5dff9381a3ad2cd", "src_uid": "a35a27754c9c095c6f1b2d4adccbfe93", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n\tint n, a, b, m, c[102] = { 0 }, i, j;\n\tscanf(\"%d%d%d\", &n, &a, &b);\n\twhile (a--)\n\t\tscanf(\"%d\", &m), c[m] = *;\n\tfor (i = 1; i <= n; i++)\n\t\tif (c[i] != 0)\n\t\t\tprintf(\"1 \");\n\t\telse\n\t\t\tprintf(\"2 \");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fa2928b8ba9666ff91c11cb8989463a9", "src_uid": "a35a27754c9c095c6f1b2d4adccbfe93", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n\tint n,a,b,i;\n\tint ans[n],x[100],y[100];\n\tscanf(\"%d %d %d\",&n,&a,&b);\n\tfor(i=1;i<=a;i++)\n\t\tscanf(\"%d\",&x[i]);\n\tfor(i=1;i<=b;i++)\n\t\tscanf(\"%d\",&y[i]);\n\tfor(i=1;i<=b;i++)\n\t\tans[y[i]]=2;\n\tfor(i=1;i<=a;i++)\n\t\tans[x[i]]=1;\n\tfor(i=1;i<=n;i++)\n\t\tprintf(\"%d \",ans[i]);\n\treturn 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8c26f3f143e0b24b3fc6ea40aae173bc", "src_uid": "a35a27754c9c095c6f1b2d4adccbfe93", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    long long unsigned int x,y,n,a,b;\n    scanf(\"%d\",&n);\n    scanf(\"%I64d %I64ud\",&x,&y);\n    a=(x-1)*(x-1)+(y-1)*(y-1);\n    b=(n-x)*(n-x)+(n-x)*(n-x);\n    if(a>b){\n        printf(\"Black\");\n    }\n    else{\n        printf(\"White\");\n    }\n}\n    \n    \n    \n    \n    \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4c13578b27bd29ebab44206d8cbfab60", "src_uid": "b8ece086b35a36ca873e2edecc674557", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n   long long long int n,x,y;\n    int a,b;\n    a=((x-1)*(x-1))+((y-1)*(y-1));\n    b=((n-x)*(n-x))+((y-n)*(y-n));\n    if(a>b)\n    {\n        printf(\"black\");\n    }\n    else\n    {\n        printf(\"white\");\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b0e4a081195bec70d264ca2cd024d3bf", "src_uid": "b8ece086b35a36ca873e2edecc674557", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n int main()\n{\n unsigned double w,b;\n long long int n,x,y,w1,w2,b1,b2;\n scanf(\"%lld\",&n);\n scanf(\"%lld%lld\",&x,&y);\n w1=w2=1;\n b1=b2=n;\n w=sqrt((x-w1)*(x-w1)+(y-w2)*(y-w2));\n b=sqrt((x-b1)*(x-b1)+(y-b2)*(y-b2));\n if(w<=b)\n printf(\"White\");\n else\n printf(\"Black\");\n return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "47989e2ab3f90793335e002fbc1e83c2", "src_uid": "b8ece086b35a36ca873e2edecc674557", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(void){\n    long long n, x, y, temp1x, temp1y, temp2c, temp2y, max1, max2;\n    scanf(\"%lli %lli %lli\", &n ,&x, &y);\n    temp1x=x;\n    temp1y=y;\n    temp2x=n-x;\n    temp2y=n-y;\n    if(temp1x>temp1y) max1=temp1x;\n    else max1=temp1y;\n    if(temp2x>temp2y) max2=temp2x;\n    else max2=temp2y;\n    if(max1>=max2) printf(\"White\");\n    else printf(\"Black\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b4c184c824d08301e0d2f3f08dee33ea", "src_uid": "b8ece086b35a36ca873e2edecc674557", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\nint main()\n{\n\tlong long int a,b,n,o;\n\tscanf(\"%I64lld\",&a);\n\tscanf(\"%I64lld %I64lld\",&a,&b);\n\tn=((2*a)-(b+c));\n\to=((b+c)-2);\n\tif(n<o)\n\tprintf(\"black\");\n\telse\n\tprintf(\"white\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c32a897a867ed0dd7ea1f9cc196cc627", "src_uid": "b8ece086b35a36ca873e2edecc674557", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\nint main()\n{\n    char cur[12],res[12];\n    scanf(\"%s\",cur);\n    strcpy(res,cur);\n    res[0]++;\n    int len=strlen(cur);\n    for(int i=1;i<len;i++)\n        res[i]='0';\n    printf(\"%d\",atoi(res)-atoi(cur));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ba1ed749750aa4ba722295258dcaad2b", "src_uid": "a3e15c0632e240a0ef6fe43a5ab3cc3e", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\n\nbool luck(long long int y)\n{\n\tint y1,i,j,k=0,n=0;\n\ty1=y;\n\twhile(y1!=0)\n\t{\n\t\ty1=y1/10;\n\t\tn++;\n\t}\n\ty1=y;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tj=y1%10;\n\t\ty1=y1/10;\n\t\tif(j!=0)\n\t\t{\n\t\t\tk++;\n\t\t}\n\t}\n\tif(k==1)\n\t{\n\t\treturn 1;\n\t}\n\telse \n\t{\n\t\treturn 0;\n\t}\n}\n\nint main()\n{\n\tint a=0;\n\tlong long int y;\n\tscanf(\"%l64d\",&y);\n\tdo\n\t{\n\t\ty++;\n\t\ta++;\n\t}while(!luck(y));\n\tprintf(\"%d\",a);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c35689b36f9be9e6ce6436dc6db7ed8b", "src_uid": "a3e15c0632e240a0ef6fe43a5ab3cc3e", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\n#include<iostream>\nbool luck(long long int y)\n{\n\tint i,j,k=0,n=0;\n\tint y1=y;\n\twhile(y1!=0)\n\t{\n\t\ty1=y1/10;\n\t\tn++;\n\t}\n\ty1=y;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tj=y1%10;\n\t\ty1=y1/10;\n\t\tif(j!=0)\n\t\t{\n\t\t\tk++;\n\t\t}\n\t}\n\tif(k==1)\n\t{\n\t\treturn 1;\n\t}\n\telse \n\t{\n\t\treturn 0;\n\t}\n}\n\nint main()\n{\n\tint a=0;\n\tlong long int y;\n\tscanf(\"%l64d\",&y);\n\tdo\n\t{\n\t\ty++;\n\t\ta++;\n\t}while(!luck(y));\n\tprintf(\"%d\",a);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "898178893710c6f5f6d5312e51e21d48", "src_uid": "a3e15c0632e240a0ef6fe43a5ab3cc3e", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "codeforces.c", "lang_cluster": "C", "compilation_error": true, "code_uid": "e4142eac5c42334d8eafcb6f9cf83449", "src_uid": "a3e15c0632e240a0ef6fe43a5ab3cc3e", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "##include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\nint main()\n{\n    long long n;\n    while(~scanf(\"%lld\",&n))\n    {\n        if(n<100)\n        {\n            n=n%5;\n            printf(\"%lld\\n\",5-n);\n        }\n        else if(n<1000)\n        {\n            n=n%100;\n            printf(\"%lld\\n\",100-n);\n        }\n        else if(n<10000)\n        {\n            n=n%1000;\n            printf(\"%lld\\n\",1000-n);\n        }\n        else if(n<100000)\n        {\n            n=n%10000;\n            printf(\"%lld\\n\",10000-n);\n        }\n        else if(n<1000000)\n        {\n            n=n%100000;\n            printf(\"%lld\\n\",100000-n);\n        }\n        else if(n<10000000)\n        {\n            n=n%1000000;\n            printf(\"%lld\\n\",1000000-n);\n        }\n        else if(n<100000000)\n        {\n            n=n%10000000;\n            printf(\"%lld\\n\",10000000-n);\n        }\n        else if(n<1000000000)\n        {\n            n=n%100000000;\n            printf(\"%lld\\n\",100000000-n);\n        }\n        else if(n<10000000000)\n        {\n            n=n%1000000000;\n            printf(\"%lld\\n\",1000000000-n);\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fc82b2787bb58704ca68a16582a74d69", "src_uid": "a3e15c0632e240a0ef6fe43a5ab3cc3e", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"test\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/test\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/test\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2a4a2dc2b469dbba44b7aef4ec279139", "src_uid": "10226b8efe9e3c473239d747b911a1ef", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(void){\n\tint s,v1,v2,t1,t2;\n\tscanf(\"%d%d%d%d%d\",&s,&v1,&v2,&t1,&t2);\n\tint p1,p2;\n\tif\n\tp1=s*v1-t1;\n\tp2=s*v2-t2;\n\tif(p1==p2)\n\t\tprintf(\"Friendship\");\n\tif(p1>p2)\n\t\tprintf(\"First\");\n\tif(p2>p1)\n\t\tprintf(\"Second\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0774247b364ee0c8ca63bc622fdc0453", "src_uid": "10226b8efe9e3c473239d747b911a1ef", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "nclude <stdio.h>\n\n    struct game{\n        int s,v,t;\n    };\nint main()\n{\n    struct game player[2];\n    scanf(\"%d %d %d %d %d\",&player[0].s,&player[0].v,&player[1].v,&player[0].t,&player[1].t);\n\n        if((player[0].s*player[0].v+2*player[0].t)>(player[0].s*player[1].v+2*player[1].t))\n            printf(\"Second\\n\");\n        else if((player[0].s*player[0].v+2*player[0].t)<(player[0].s*player[1].v+2*player[1].t))\n            printf(\"First\\n\");\n        else printf(\"Friendship\\n\");\n\n\n\n\n\n\n\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c2c185f718de3435b1996b29d0e9698e", "src_uid": "10226b8efe9e3c473239d747b911a1ef", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "nclude <stdio.h>\n\n    struct game{\n        int s,v,t;\n    };\nint main()\n{\n    struct game player[2];\n    scanf(\"%d %d %d %d %d\",&player[0].s,&player[0].v,&player[1].v,&player[0].t,&player[1].t);\n\n        if((player[0].s*player[0].v+2*player[0].t)>(player[0].s*player[1].v+2*player[1].t))\n            printf(\"Second\\n\");\n        else if((player[0].s*player[0].v+2*player[0].t)<(player[0].s*player[1].v+2*player[1].t))\n            printf(\"First\\n\");\n        else printf(\"Friendship\\n\");\n\n\n\n\n\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5279c5f071f0668e339db1d41d064e2b", "src_uid": "10226b8efe9e3c473239d747b911a1ef", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdlib.h>\nmain()\n{\n    int s,i,s,v1,v2,t1,t2;\n    scanf(\"%d %d %d %d %d\",&s,&v1,&v2,&t1,&t2);\n    if(s*v1+2*t1<s*v2+2*t2) printf(\"First\");\n    if(s*v1+2*t1>s*v2+2*t2) printf(\"Second\");\n    if(s*v1+2*t1==s*v2+2*t2)printf(\"Second\");\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a2b28c9d802ca31f95599fbdb1786b2b", "src_uid": "10226b8efe9e3c473239d747b911a1ef", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#include<math.h>\n#define ll long long\n#define sf scanf\n#define pf printf\n#define db double\n#define end return 0\nint func(int,int);\nint a[100005];\nint main()\n{\n     \n     char c[1001],ch[1001],i,k=1;\n     gets(c);\n     ch[0]='/';\n     for(i=0;c[i];i++)\n     {\n          if((ch[k-1]!='/'||ch[k-1]=='/')&& c[i]!='/')\n          ch[k++]=c[i];\n          else if(ch[k-1]!='/' && c[i]=='/')\n          ch[k++]='/';\n     }\n     if(ch[k-1]=='/';)\n     k=k-1;\n     ch[k]='\\0';\n     pf(\"%s\",ch);\nend;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1a9ce65c2368d5bb7f9cf13d37bd3a2e", "src_uid": "6c2e658ac3c3d6b0569dd373806fa031", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int i,j=0,k,count=0,y=0,x=0,m=0;\n    char s[100];\n    scanf(\"%s\",s);\n    y=strlen(s);\n    char p[y];\n    for(m=y-1;m>0;m--)\n    {\n        if(s[m]!='/')\n        {\n            x=m;\n            break;\n        }\n    }\n    for(i=0;i<=m;i++)\n    {\n        if(s[i]=='/' && count==0)\n        {\n            p[j]='/';\n            j++;\n            count++;\n        }\n        if(s[i]!='/')\n        {\n            p[j]=s[i];\n            j++;\n            count=0;\n        }\n    }\n    for(k=0;k<j;k++)\n    {\n        printf(\"%c\",p[k]);\n    }\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "edcb3af6d9d848bc93cc733b5ec5ec22", "src_uid": "6c2e658ac3c3d6b0569dd373806fa031", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "main() {\nchar qwer = zxcv = '\\r';\nwhile(scanf(\"%c\", &zxcv)) {\nif(qwer == '/' && zxcv != '/') {\nprintf(\"/\", zxcv);\n}\nprintf(\"%c\", zxcv);\nqwer = zxcv;\n}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9b010bd0c6dbc3534289b3e113064aa8", "src_uid": "6c2e658ac3c3d6b0569dd373806fa031", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main()\n{\n    int i,j=0,k,count=0,y=0,x=0,m=0;\n    char s[100];\n    scanf(\"%s\",s);\n    y=strlen(s);\n    char p[y];\n    for(m=y-1;m>0;m--)\n    {\n        if(s[m]!='/')\n        {\n            x=m;\n            break;\n        }\n    }\n    for(i=0;i<=m;i++)\n    {\n        if(s[i]=='/' && count==0)\n        {\n            p[j]='/';\n            j++;\n            count++;\n        }\n        if(s[i]!='/')\n        {\n            p[j]=s[i];\n            j++;\n            count=0;\n        }\n    }\n    for(k=0;k<j;k++)\n    {\n        printf(\"%c\",p[k]);\n    }\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b5817c930e6a43f01775bac299d0a239", "src_uid": "6c2e658ac3c3d6b0569dd373806fa031", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char s1[1000],s2[1000];\n    gets(s1);\n    int i,k=0;\n    for(i=0;i<strlen(s1);i++){\n            s2[k]=s1[i];\n        if(s1[i]=='/'){\n            for(;s1[i]=='/';i++);\n            i--;\n        }\n\n        k++;\n    }\n    if(strlen(s1)==1) puts(s1);sdjh\n    else if(s2[k-2]!='/'&&s2[k-1]=='/'){\n            s2[k-1]='\\0';\n            puts(s2);\n    }\n    else{\n        s2[k]=='\\0';\n        puts(s2);\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e8dda2802d0f30e7388543e1405a2095", "src_uid": "6c2e658ac3c3d6b0569dd373806fa031", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long int n,m,i,j,a,b;\nint ab(int a)\n{\n\tif(a<0)\n\treturn -a;\n\treturn a;\n}\nint max(int a,int b)\n{\n\tif(a<b)\n\treturn b;\n\treturn a;\n}\nint min(int a,int b)\n{\n\tif(a>b)\n\treturn b;\n\treturn a;\n}\nint func(int u,int v)\n{\t\t\n\t\tif(i==u&&j==v)\n\t\treturn 0;\n\t\tif(i+a>n&&i-a<=0)\n\t\treturn -1;\n\t\tif(j+b>m&&j-b<=0)\n\t\treturn -1;\n\t\tint x=ab(u-i),y=ab(v-j);\n\t\tif(x%a!=0||y%b!=0)\n\t\treturn -1;\n\t\tx=x/a;y=y/b;\n\t\tif(x%2!=y%2)\n\t\treturn -1;\n\t\tint t=max(x,y);\n\t\treturn t;\n}\nint main()\n{\n\tscanf(\"%lld%lld%lld%lld%lld%lld\",&n,&m,&i,&j,&a,&b);\n\tint ans=100000000;\n\tint a=func(1,m);\n\tif(a!=-1)\n\t{\n\t\tans=min(ans,a);\n\t}\n\ta=func(n,1);\n\tif(a!=-1)\n\t{\n\t\tans=min(ans,a);\n\t}\n\ta=func(1,1);\n\tif(a!=-1)\n\t{\n\t\tans=min(ans,a);\n\t}\n\ta=func(n,m);\n\tif(a!=-1)\n\t{\n\t\tans=min(ans,a);\n\t}\n\tif(ans<100000000)\n\tprintf(\"%d\",ans);\n\telse\n\tprintf(\"Poor Inna and pony!\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "bae4e1890c524a1a35f40c1ba1a8d0d1", "src_uid": "51155e9bfa90e0ff29d049cedc3e1862", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint min=1000000000;\n\nvoid gao(int x,int y){\n    if((x+y)%2) return ;\n    if(x<y) x=y;\n    if(min>x) min=x;\n}\n\nint main(void){\n    int n,m,i,j,a,b;\n    scanf(\"%d%d%d%d%d%d\",&n,&m,&i,&j,&a,&b);\n    if((i-1)%a==0 && (j-1)%b==0) gao((i-1)/a,(j-1)/b);\n    if((i-1)%a==0 && (m-j)%b==0) gao((i-1)/a,(m-j)/b);\n    if((n-i)%a==0 && (j-1)%b==0) gao((n-i)/a,(j-1)/b);\n    if((n-i)%a==0 && (m-j)%b==0) gao((n-i)/a,(m-j)/b);\n    if(min<1000000000) printf(\"%d\",min);\n    else printf(\"Poor Inna and pony!\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f1e925a4ea0088bf626953db40f6adab", "src_uid": "51155e9bfa90e0ff29d049cedc3e1862", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint max(int a,int b)\n{\n    return a>b?a:b;\n}\nint min(int a,int b)\n{\n    return a<b?a:b;\n}\nint main()\n{\n    int n,m,i,j,a,b,ans=-1,x,y,an;\n    scanf(\"%d %d %d %d %d %d\",&n,&m,&i,&j,&a,&b);\n    x=i-1;y=j-1;\n    if(x%a==0 && y%b==0 && (x/a-y/b)%2==0)\n    {\n        an=max(x/a,y/b);\n        if(ans==-1) ans=an;\n        else ans=min(ans,an);\n    }\n    x=i-1;y=m-j;\n    if(x%a==0 && y%b==0 && (x/a-y/b)%2==0)\n    {\n        an=max(x/a,y/b);\n        if(ans==-1) ans=an;\n        else ans=min(ans,an);\n    }\n    x=n-i;y=j-1;\n    if(x%a==0 && y%b==0 && (x/a-y/b)%2==0)\n    {\n        an=max(x/a,y/b);\n        if(ans==-1) ans=an;\n        else ans=min(ans,an);\n    }\n    x=n-i;y=m-j;\n    if(x%a==0 && y%b==0 && (x/a-y/b)%2==0)\n    {\n        an=max(x/a,y/b);\n        if(ans==-1) ans=an;\n        else ans=min(ans,an);\n    }\n    if(ans==-1) printf(\"Poor Inna and pony!\");\n    else printf(\"%d\",ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c4aecd5d06b438fe4ad770060dba7e9e", "src_uid": "51155e9bfa90e0ff29d049cedc3e1862", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nmax (long int *pp,long int *pb){\n\tlong int t;\n\tif ((*pp)<(*pb)){\n\t\tt=*pp;\n\t\t*pp=*pb;\n\t\t*pb=t;\n\t\t\n\t}\n\t\n}\nint main (){\n\tlong int n,m,i,j,a,b,p,q;\n\tscanf(\"%ld %ld %ld %ld %ld %ld\",&n,&m,&i,&j,&a,&b);\n\tif (((n-i)%a==0) && ( (m-j)%b==0) )\n{\n\tp=(n-i)/a;\n\tq=(m-j)/b;\n\tmax(&p,&b);\n\t\n\tif ((p-q)%2==0){\n\t\tprintf(\"%ld\",p);\n\t\texit;\n\t\t}\n\t\telse {\n\t\t\tprintf(\"Poor Inna and pony!\\n\");\n\t\t\texit;\n\t\t}\n\t}\nelse if (((n-i)%a==0) && ( (j-1)%b==0 ))\n{\n\tp=(n-i)/a;\n\tq=(j-1)/b;\n\tmax(&p,&q);\n\tif ((p-q)%2==0){\n\t\tprintf(\"%ld\",p);\n\t\t\n\t}\n\telse \n\tprintf(\"Poor Inna and pony!\");\n}\t\n\nelse if (((i-1)%a==0) && ( (j-1)%b==0 ))\n{\n\tp=(i-1)/a;\n\tq=(j-1)/b;\n\tmax(&p,&q);\n\tif ((p-q)%2==0){\n\t\tprintf(\"%ld\",p);\n\t\t\n\t}\n\telse \n\tprintf(\"Poor Inna and pony!\");\n}\t\n\t\n\t\nelse if (((i-1)%a==0) && ( (m-j)%b==0 ))\n{\n\tp=(i-1)/a;\n\tq=(m-j)/b;\n\tmax(&p,&q);\n\tif ((p-q)%2==0){\n\t\tprintf(\"%ld\",p);\n\t\t\n\t}\n\telse \n\tprintf(\"Poor Inna and pony!\");\n}\t\n\t\n\telse \n\t{\t\n\tprintf(\"Poor Inna and pony!\\n\");\t\n\n}\nreturn 0;\n}\t\n\t\n\t\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d2ad3663203f0a3d16bca3f4e4f7bf36", "src_uid": "51155e9bfa90e0ff29d049cedc3e1862", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define INF 1000000009\nint max(int x,int y){\n    if(x>y){\n        return x;\n    }\n    return y;\n}\nint min(int x, int y){\n    if(x>y){\n        return y;\n    }\n    return x;\n}\nint main(){\n    int n,m,i,j,a,b,cnt1=INF,cnt2=INF,cnt3=INF,cnt4=INF,ans1=INF,ans2=INF,ans3=INF,ans4=INF,i,j,ret;\n    scanf(\"%d%d%d%d%d%d\",&n,&m,&i,&j,&a,&b);\n    if((i-1)%a!=0){\n        if((n-i)%a!=0){\n            if((j-1)%b!=0){\n                if((m-j)%b!=0){\n                    printf(\"Poor Inna and pony!\\n\");\n                    return 0;\n                }\n            }\n        }\n    }\n    if((i-1)%a==0){\n        cnt1=(i-1)/a;\n    }\n    if((n-i)%a==0){\n        cnt2=(n-i)/a;\n    }\n    if((j-1)%b==0){\n        cnt3=(j-1)/b;\n    }\n    if((m-j)%b==0){\n        cnt4=(m-j)/b;\n    }\n    if((cnt1-cnt3)%2==0 && cnt1!=INF && cnt3!=INF){\n        ans1=max(cnt1,cnt3);\n    }\n    if((cnt1-cnt4)%2==0 && cnt1!=INF && cnt4!=INF){\n        ans2=max(cnt1,cnt4);\n    }\n    if((cnt2-cnt3)%2==0 && cnt2!=INF && cnt3!=INF){\n        ans3=max(cnt2,cnt3);\n    }\n    if((cnt2-cnt4)%2==0 && cnt2!=INF && cnt4!=INF){\n        ans4=max(cnt2,cnt4);\n    }\n    if(ans1==INF && ans2==INF && ans3==INF && ans4==INF){\n        printf(\"Poor Inna and pony!\\n\");\n        return 0;\n    }\n    i=min(ans1,ans2);\n    j=min(ans3,ans4);\n    ret=min(i,j);\n    printf(\"%d\\n\",ret);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5682c769d9140601c5b450c7175e9c5c", "src_uid": "51155e9bfa90e0ff29d049cedc3e1862", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\n long long  int j,t,i,f,x,n,m,d,g,k=0,s=1,sum=0,count=1,l=0;\n char a[51];\n  char b[51];\n scanf(\"%s\",a);\nl=strlen(a);\nif(l==3){\n    printf(\"%c%c%c\",a[1],a[2],a[0]);\n}\nelse { for(i=0,j=0;i<l;j++){\n\n   b[i]=a[l-1-j];\n   b[i+1]=a[j];\ni=i+2;\n }\n b[l]='\\0';\n\n\n for(i=l-1;i>=0;i--){\n      printf(\"%c\",b[i]);}\n}\n\n\nreturn 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9838f1a024402097ff6d13d5e1731f0e", "src_uid": "992ae43e66f1808f19c86b1def1f6b41", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "erfdcoeocs", "lang_cluster": "C", "compilation_error": true, "code_uid": "1ca62a095303b087244563fa79998286", "src_uid": "992ae43e66f1808f19c86b1def1f6b41", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "\n#include <stdio.h>\n#include<string.h>\nint main()\n{\n   char t[50],s[50];\n   int i,j,temp=0;\n   scanf(\"%s\",t);\n   int l=strlen(t);\n   i=(l+1)/2 -1,j=(l+1)/2;\n   if(l==1)\n   {\n       printf(\"%s\",t);\n   }\n   while(i>=0&&j<l)\n   {\n\t\ts[temp++]=t[i--];\n\t\ts[temp++]=t[j++];\n    }\n   if(i>=0)\n   {\n\t\twhile(i>=0)\n\t\ts[temp++]=t[i--];\n\t}\n\tif(j<l)\n\t{\n\t\twhile(j<l)\n\t\ts2[temp++]=t[j++];\n\t}\n\t\n    printf(\"%s\",s);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9bfd7a4bef0d9482a6617094178581e0", "src_uid": "992ae43e66f1808f19c86b1def1f6b41", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int k,m,p,l;\n    char a[51];\n    scanf(\"%s\",&a);\n    m=strlen(a);\n    if(m==1)\n    printf(\"%c\",a[0]);\n    else\n    {\n        p=m-2;\n        if(m%2==0)\n        k=m/2-1;\n        else\n        k=m/2;\n        l=k+1;\n        printf(\"%c%c\",a[k],a[l]);\n        while(p>0)\n        {\n            if(k-1>=0)\n            {\n                printf(\"%c\",a[k-1]);\n                p--;\n                k--;\n            }\n            if(l+1<=n)\n            {\n                printf(\"%c\",a[l+1]);\n                p--;\n                l++;\n            }\n        }\n        \n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "71852ab60e09f9844921472b7b5ca068", "src_uid": "992ae43e66f1808f19c86b1def1f6b41", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n         int l,x,y,a,i,j=0;\n         char t[100];\n         scanf(\"%s\",t);\n         char s[100];\n         l=strlen(t);\n         x=l/2;\n         y=x-1;\n         a=y+1;\n         for(i=0;i<x;i++)\n         {\n               \n               strcpy(s[j],t[y]);\n               j++;\n               strcpy(s[j],t[a]);\n               a++;\n               y--;\n               j++;\n          }\n          for(i=0;i<l;;i++)\n          {\n               printf{\"%c\",s[i]):\n          }\n          return 0;\n}\n               \n             ", "lang_cluster": "C", "compilation_error": true, "code_uid": "3483781c129ff31ee47f5caccc5cd6a8", "src_uid": "992ae43e66f1808f19c86b1def1f6b41", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <bits/stdc++.h>\nusing namespace std;\n\nint arr[7][7], i, j;\n\nchar a[7][7];\n\nstring s;\n\nmap<int, pair<int, int>>mp;\n\nint  main()\n{\n\tios_base::sync_with_stdio(false);\n\n\tfor (i = 0; i < 6; i++){\n\t\tcin >> s;\n\t\tint k = 0;\n\t\tfor (j = 0; j < s.size(); j++)\n\t\t{\n\t\t\tif (s[j] == '.' || s[j] == '*')a[i][k++] = s[j];\n\t\t}\n\t}\n\tint num = 0, val = 3;\n\tfor (i = 0; i < 6; i++)\n\t{\n\t\tif (num == 2)\n\t\t\tval--, num = 0;\n\t\tnum++;\n\t\tarr[i][0] = arr[i][1] = val;\n\t}\n\tnum = 0;\n\tval = 4;\n\tfor (i = 0; i < 6; i++)\n\t{\n\t\tif (num == 2)\n\t\t\tval--, num = 0;\n\t\tnum++;\n\t\tarr[i][2] = arr[i][3] = val;\n\t}\n\tnum = 0;\n\tval = 3;\n\tfor (i = 0; i < 6; i++)\n\t{\n\t\tif (num == 2)num = 0, val--;\n\t\tnum++;\n\t\tarr[i][4] = arr[i][5] = val;\n\t}\n\n\tfor (i = 0; i < 6; i++)\n\t{\n\t\tfor (j = 0; j < 6; j++)\n\t\t{\n\t\t\tif (a[i][j] == '.')\n\t\t\t{\n\t\t\t\tmp[arr[i][j]] = { i, j };\n\t\t\t}\n\t\t}\n\t}\n\n\tauto it = mp.end();\n\n\tit--;\n\n\ta[it->second.first][it->second.second] = 'P';\n\n\tfor (i = 0; i < 6; i++)\n\t{\n\t\tcout << a[i][0] << a[i][1] << '-';\n\t\tcout << a[i][2] << a[i][3] << '-';\n\t\tcout << a[i][4] << a[i][5] << '\\n';\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "752f7f29fd93bdec1fa547463f57242f", "src_uid": "35503a2aeb18c8c1b3eda9de2c6ce33e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\nint main()\n{\n    int n,i,j,k,l=0;\n    int a[6][8]={{3,3,-1,4,4,-1,3,3},{3,3,-1,4,4,-1,3,3},\n\t{2,2,-1,3,3,-1,2,2},{2,2,-1,3,3,-1,2,2},{1,1,-1,2,2,-1,1,1}\n\t,{1,1,-1,2,2,-1,1,1}};\n    string s[6];\n    for(i=0;i<6;i++)\n    cin>>s[i];\n    for(j=0;j<6;j++){\n    for(i=0;i<8;i++)\n    {\n    \tif(s[j][i]=='-')\n    \tcontinue;\n    \tif(s[j][i]=='.')\n    \t{\n    \t\tif(l<=a[j][i])\n    \t\t{\n    \t\t\tn=j,k=i;\n    \t\t\tl=a[j][i];\n    \t\t}\n    \t}\n    }}\n    k--;\n    s[n][k]='P';\n    for(i=0;i<6;i++)\n    cout<<s[i]<<endl;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f2d660b2c19ab3337fa02f18dd78d999", "src_uid": "35503a2aeb18c8c1b3eda9de2c6ce33e", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include \"stdio.h\"\nusing namespace std;\n\nint a[6][6];\n\nint main() {\n\ta[0][0] = 3;\n\ta[0][1] = 3;\n\ta[0][2] = 4;\n\ta[0][3] = 4;\n\ta[0][4] = 3;\n\ta[0][5] = 3;\n\tfor (int i = 1; i < 5; i++)\n\t\tfor (int j = 0; j < 5; j++)\n\t\t\ta[i][j] = a[i - 1][j] - 1;\n\tchar c[6][6];\n\tfor(int i = 0; i < 5; i++){\n\t\tchar t;\n\t\tscanf(\"%c%c-%c%c-%c%c\\n\", &c[i][0], &c[i][1], &c[i][2], &c[i][3], &c[i][4], &c[i][5]);\n\t}\n\tint max = 0, ii, jj;\n\tfor (int i = 0; i < 5; i++) {\n\t\tint flag = 0, flag1 = 0;\n\t\tfor (int j = 0; j < 5; j++) {\n\t\t\tif (c[i][j] != '*')\n\t\t\t\tif (a[i][j] > max) {\n\t\t\t\t\tmax = a[i][j];\n\t\t\t\t\tii = i, jj = j;\n\t\t\t\t}\n\t\t}\n\t}\n\tc[ii][jj] = 'P';\n\tfor(int i = 0; i < 5; i++)\n\t\tprintf(\"%c%c-%c%c-%c%c\\n\", c[i][0], c[i][1], c[i][2], c[i][3], c[i][4], c[i][5]);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "71356892015da961c891afee6d2147c8", "src_uid": "35503a2aeb18c8c1b3eda9de2c6ce33e", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(void) {\n\tchar s[6][9];\n\tfor (int i =0 ;i <6;i++){\n\t\tscanf(\"%s\",s[i]);\n\t\ts[i][8]='\\0';\n\t}\n\tint x[]={0,0,1,1, 0,0,0,0,1,1,1,1,2,2,3,3 2,2,2,2,3,3,3,3,4,4,5,5, 4,4,4,4,5,5,5,5};\n\tint y[]={3,4,3,4, 0,1,6,7,0,1,6,7,3,4,3,4 0,1,6,7,0,1,6,7,3,4,3,4, 0,1,6,7,0,1,6,7};\n\tfor (int i=0;i<36;++i){\n\t\tif (s[x[i]][y[i]]!='*'){\n\t\t\ts[x[i]][y[i]]='P';\n\t\t\tbreak;\n\t\t}\n\t}\n\tfor (int i =0 ;i <6;i++){\n\t\tprintf(\"%s\\n\",s[i]);\n\t}\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2aac7e2a680c53bca42eec226b95b024", "src_uid": "35503a2aeb18c8c1b3eda9de2c6ce33e", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#define _CRT_SECURE_NO_WARNINGS\n#include <cstdio>\n\nusing namespace std;\n\nint p[7][8] = {\n  { 3, 3, 0, 4, 4, 0, 3, 3 },\n  { 3, 3, 0, 4, 4, 0, 3, 3 },\n  { 2, 2, 0, 3, 3, 0, 2, 2 },\n  { 2, 2, 0, 3, 3, 0, 2, 2 },\n  { 1, 1, 0, 2, 2, 0, 1, 1 },\n  { 1, 1, 0, 2, 2, 0, 1, 1 }\n};\n\nchar st[7][10];\n\nint main()\n{\n  for (int i = 0; i < 6; i++) {\n    scanf(\"%s\", st[i]);\n  }\n\n  int y = -1, x = -1, mx = 0;\n\n  for (int i = 0; i < 6; i++) {\n    for (int j = 0; j < 6; j++) {\n      if (st[i][j] == '.' && p[i][j] > mx) {\n        mx = p[i][j];\n        y = i;\n        x = j;\n      }\n    }\n  }\n\n  st[y][x] = 'P';\n\n  for (int i = 0; i < 6; i++) {\n    puts(st[i]);\n  }\n\n  return 0;\n}\n\n\n/*\n\n00000001100\n\n1 2 3 100 100 100 100 100 100 100\nabcdefgh\n\nabcdefg\ncdefghi\n\n4 1\n50 50 10 20\n130\n*/", "lang_cluster": "C", "compilation_error": true, "code_uid": "1f62d1bf27cb7fe02e7b43a14fffcc12", "src_uid": "35503a2aeb18c8c1b3eda9de2c6ce33e", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    long int n.s,count=0;\n    scanf(\"%ld %ld\",&n,&s);\n    if(n>=s)\n    count=1;\n    else{\n        count+=s/n;\n        if(s%n!=0)\n        count++;\n    }\n    printf(\"%ld\\n\",count);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a1846ae6965ac68cab01d3d24461abab", "src_uid": "04c067326ec897091c3dbcf4d134df96", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n,s;\n    int k=0;\n    int a=0;\n    scanf(\"%d%d\",&n,&s);\n    for(i=0;i<=s;i--){\n        if(k<s){\n            k=k+i;\n            a=a+1;\n        }\n        else{\n            printf(\"%d\",a);\n        }\n    }\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1be563e10fd37e41c8c017c14dc48b00", "src_uid": "04c067326ec897091c3dbcf4d134df96", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"Coins\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/Coins\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/Coins\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<envvars />\n\t\t\t<code_completion />\n\t\t\t<debugger />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d23c7051e32775296cc92a1b80011855", "src_uid": "04c067326ec897091c3dbcf4d134df96", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    long float n, s, a, c;\n\tlong int b ; \n\tscanf(\"%lf %lf\", &n, &s);\n\ta=s/n;\n\tc=a;\n\tb=a;\n\tif(c!=b)\n\t{\n\t\tprintf(\"%ld\\n\", b+1);\n\t}\n\telse \n\t{\n\t\tprintf(\"1\");\n\t}\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "887df6043e65b55f2518613dd0c834f2", "src_uid": "04c067326ec897091c3dbcf4d134df96", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int a , b ;\n    scanf(\"%d%d\",&a.&b);\n    printf(\"%d\",b-1/a-1);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2bda264d9f0210ffc195daa71ff96073", "src_uid": "04c067326ec897091c3dbcf4d134df96", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<ctype.h>\n#include<math.h>\nint main()\n{\n\n    int n,min,c=0,d=0,l,i=0,sub,count=0;\n    scanf(\"%d\",&n);\n    char s[200];\n    scanf(\"%s\",s);\n    l = strlen(s);\n    for(i=0;i<l;i++){\n\n        if(s[i]=='X'){\n            c++;\n        }\n        if(s[i]=='x'){\n            d++;\n        }\n\n    }\n    sub = fabs(c - n/2 );\n    if(c<(n/2)){\n        min = n/2 - c;\n        i=0;\n        while(i!=n){\n                if(s[i]=='x'){\n            s[i] = toupper(s[i]);\n            count++;\n            if(count==min){\n                break;\n            }\n                }\n                i++;\n        }\n    }\n    else if(d<(n/2)){\n            min = n/2 - d;\n      i=0;\n      while(i!=n){\n\n            if(s[i]=='X'){\n            s[i] = tolower(s[i]);\n            count++;\n            if(count == min){\n                break;\n            }\n            i++;\n        }\n    }\n    }\n\n    printf(\"%d\\n\",sub);\n    i = 0;\n    while(i!=n){\n        printf(\"%c\",s[i]);\n        i++;\n    }\n\n\n}\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3a635cab7f6e596608d48d254f5106a3", "src_uid": "fa6311c72d90d8363d97854b903f849d", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(void)\n{\n\t\tint n;\n\t\tscanf(\"%d \", &n);\n\n\t\tchar arr[n+1];\n\t\tarr[n] = '\\0';\n\n\t\tint sit = 0, stand = 0;\n\t\tfor (int i =0; i < n; i++){\n\t\t\t\tscanf(\"%c \", &arr[i]);\n\t\t\t\tif (arr[i] == 'x')\n\t\t\t\t\t\tsit++;\n\t\t\t\telse\n\t\t\t\t\t\tstand++;\n\t\t}\n\n\t\tif (sit == stand)\n\t\t\t\tprintf(\"0\\n\");\n\t\telse\n\t\t\t\tprintf(\"1\\n\");\n\n\t\tint i = 0;\n\t\twhile (sit > stand && i < n){\n\t\t\t\tif (arr[i] == 'x'){\n\t\t\t\t\t\tarr[i] = 'X';\n\t\t\t\t\t\tsit--; stand++;\n\t\t\t\t}\n\t\t\t\ti++;\n\t\t}\n\t\t\n\t\ti = 0;\n\t\twhile (stand > sit && i < n){\n\t\t\t\tif (arr[i] == 'X'){\n\t\t\t\t\t\tarr[i] = 'x';\n\t\t\t\t\t\tstand--; sit++;\n\t\t\t\t}\n\t\t}\n\n\t\tprintf(\"%s\\n\", arr);\n\t\treturn 0;\n}\n\n\t\t\t\t\n\n\t\t\t\t\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f043e0f81aed04ed4f2e8f01472f5a18", "src_uid": "fa6311c72d90d8363d97854b903f849d", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <math.h>\nmain()\n{\n    int n,s1=0,s,s2=0,i,l=0;\n    char ch[1000];\n    while(1)\n   {\n       s1=s2=0;\n        l=0;\n      scanf(\"%d\",&n);\n        for(i=0;i<=n;i++)\n       {\n            scanf(\"%c\",&ch[i]);\n            if(ch[i]=='x')\n              s1++;\n            if(ch[i]=='X')\n               s2++;\n       }\n        l=abs((s1-s2))/2;\n        printf(\"%d\",l);\n        for(i=0;i<=n;i++)\n        {\n            if(s1<s2&&l+1)\n            {\n                 if(ch[i]=='X')\n                   ch[i]=ch[i]+32;\n                   l--;\n            }\n            if(s1>s2&&l+1)\n           {\n               if(ch[i]=='x')\n                   ch[i]=ch[i]-32;\n                   l--;\n           }\n        }\n        for(i=0;i<=n;i++)\n          printf(\"%c\",ch[i]);\n   }\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a505fa66a2f93a9242b0225e91391a32", "src_uid": "fa6311c72d90d8363d97854b903f849d", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <string.h>\n#include <stdio.h>\nint main()\n{ //424A\n    int n, i, j;\n    char arr[200];\n    char c;\n    int m = 0;\n    int target, remain;\n    int current = 0;\n    scanf(\"%d\\n\", &n);\n    target = n / 2;\n\n    for (i = 0; i < n; i++) {\n        c = getchar();\n        if (c == 'x')\n            arr[i] = 0;\n        else {\n            arr[i] = 1;\n            current++;\n        }\n    }\n    remain = target - current;\n    m = remain;\n    if (remain < 0) remain * = -1;\n    if (remain > 0) {\n        for (i = 0; i < n && remain > 0; i++) {\n            if (arr[i] == 0) {\n                arr[i] = 1;\n                remain--;\n            }\n        }\n    } else if (remain < 0){\n        for (i = 0; i < n && remain < 0; i++) {\n            if (arr[i] == 1) {\n                arr[i] = 0;\n                remain++;\n            }\n        }\n    }\n\n    printf(\"%d\\n\", m);\n    for (i = 0; i < n; i++) {\n        if (arr[i] == 0)\n            putchar('x');\n        else\n            putchar('X');\n    }\n\n   return(0);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e291c095e55ad56acfc60c15cb5de7e2", "src_uid": "fa6311c72d90d8363d97854b903f849d", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\ninat main()\n{\n    int n,index,standing=0,sitting=0,diff,flag;\n    char *array;\n    scanf(\"%d\",&n);\n    array=(char*)malloc(n*sizeof(char));\n    scanf(\"%s\",array);\n    for (index=0;index<n;index++)\n    {\n        if(array[n]=='X')\n        standing++;\n        else\n        sitting++;\n    }\n    if(stnding>sitting)\n    {diff=standing-sitting;\n    flag=0;}\n    else\n    {diff=sitting-standing;\n    flag=1;}\n    printf(\"%d\\n\",diff);\n    if(flag=0)\n    {\n    for (index=0;index<n;index++)\n    {\n        if(diff!=0)\n        {\n            if(array[index]=='X')\n            {printf(\"x\");\n            diff--;\n            }\n        }\n        else\n        printf(\"%c\",array[n]);\n     }\n     }\n     else\n     {\n         for (index=0;index<n;index++)\n    {\n        if(diff!=0)\n        {\n            if(array[index]=='x')\n            {printf(\"X\");\n            diff--;\n            }\n        }\n        else\n        printf(\"%c\",array[n]);\n     }\n         \n     }\n     return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ad0c3293283879df09b3fd0b193f24a0", "src_uid": "fa6311c72d90d8363d97854b903f849d", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tfor(int i=0;i<n;i++)\n\t{\n\t\tint j;\n\t    scanf(\"%d\",&j);\n\t    if(n%2==0)\n\t    printf(\"%d\",n);\n\t    break;\n\t    else \n\t    printf(\"%d\",j);\n\t    break;\n\t}\n\treturn 0;\n}\n\n\t\t\n\t\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "cbccc5ba7fa7f8fa12e30a5c7b34f97e", "src_uid": "f8eb96deeb82d9f011f13d7dac1e1ab7", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <bits/stdc++.h>\nusing namespace std;\n \n \nint main() {\n    //ios_base::sync_with_stdio(false);\n    //cin.tie(nullptr), cout.tie(nullptr);\n \n    int n, v;\n    cin >> n >> v;\n    if (n-1 <= v) {\n        cout << n-1 << endl;\n        return 0;\n    }\n    int result = v - 1;\n    for(int i = 1; i <= n - v; ++i) {\n        result += i;\n    }\n    cout << result << endl;\n \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d832f0c07a58df9055413890a9bde26d", "src_uid": "f8eb96deeb82d9f011f13d7dac1e1ab7", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n    int n,v;\n    scanf(\"%d %d\",&n,&v);\n    \n    int sum=0;\n    for(int i=2;i<=n-v;i++)\n    {\n        sum=sum+i;\n    }\n    int p=v+sum;\n    print(\"%d\",p);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "515b3490d1b979e5d1b5f616500a965f", "src_uid": "f8eb96deeb82d9f011f13d7dac1e1ab7", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(){\n\tint a,b;\n\tscanf(\"%d %d\",&a,&b);\n\tif(a>=b)\n    int sum=b;\n    else\n    sum=a;\n    for(int i=2;i<=a-b;i++)\n    {\n        sum+=i;\n    }\n    printf(\"%d\",sum);\n    return 0;\n     \n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a49afb1875204f554644f472fb56a020", "src_uid": "f8eb96deeb82d9f011f13d7dac1e1ab7", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint i,count,n,v,sum;\n\tscanf(\"%d %d\",&n,&v);\n\tcount=v;\n\ti=2;\n\tif(v>=n-1)\n\t{\n\t\tcount=n-1;\n\t}\n\tsum=0;\n\telse\n\t{\t\n\t\twhile(n-1!=v)\n\t\t{\n\t\t\tsum=sum+i;\n\t\t\tn--;\n\t\t\ti++;\n\t\t}\n\t\tcount=sum;\n\t}\t\n\tprintf(\"%d\\n\",count);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ef0e9f42ef732d6e5bd6011b8c0fb7c0", "src_uid": "f8eb96deeb82d9f011f13d7dac1e1ab7", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n, i, sum=0;\n    char a[1000];\n    scanf(\"%d\", &n);\n\n    scanf(\"%s\", a);\n\n    for(i=0; i<n; i++)\n    {\n        if(a[i]=='-')\n        {\n            if(sum != 0)\n                sum--;\n        }\n        else if(a[i]=='+')\n        {\n            sum++;\n        }\n    }\n    printf(\"%d\", sum);\n}\nChat Conversation End\nType a message...\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "cb04cf5d17a11a5c294b84290cde36bf", "src_uid": "a593016e4992f695be7c7cd3c920d1ed", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nvoid main()\n{\n    char *str;\n    int len,i,num;\n    num=0;\n    scanf(\"%d\",&len);\n    str=malloc(sizeof(char)*len);\n    scanf(\"%s\",str);\n    for(i=0;i<len;i++)\n    {\n        if(str[i]=='-')\n        {\n            if(num==0)\n                num=0;\n            else\n                num=num-1;\n        }\n        else\n            num=num+1;\n    }\n    printf(\"%d\",num);a\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "122968595e71e6be6d3a5dbd69fb03d8", "src_uid": "a593016e4992f695be7c7cd3c920d1ed", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int n;\n    scanf(\"%d\\n\" , &n);\n    char A[n];\n    for(int i=0;i<n;i++)\n    {\n    scanf(\"%c\" , &A[i]);\n    }\n    int temp=0;\n    for(i=0;i<n;i++){\n        if(A[i]=='-')\n        {temp-=1;\n            if(temp == -1)\n            { temp=0;}\n        }\n        if(A[i]=='+'){\n        temp++;\n            }\n\n    }\n\n    printf(\"%d\" , temp);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b3fa2f926614ac7c7184ec4f217fe64b", "src_uid": "a593016e4992f695be7c7cd3c920d1ed", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint main()\n{\n\tint n;\n\tcin>>n;\n\tchar p[n];\n\tint c=0,i=0;\n\tcin>>p;\n\tfor(int j=0;j<n;j++)\n\t{\n\t\tif(p[j]=='+')\n\t\tc++;\n\t\tif(p[j]=='-')\n\t\tc--;\n\t\t\n\t\tif(c<0)\n\t\t{\n\t\t\ti++;\n\t\t\tc=0;\n\t\t}\n\t}\n\t\n\tfor(int j=0;j<n;j++)\n\t{\n\t\tif(p[j]=='+')\n\t\ti++;\n\t\tif(p[j]=='-')\n\t\ti--;\n\t\t\n\t}\n\tcout<<i<<endl;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2f6a3fee7855e4f51052efc32fbef437", "src_uid": "a593016e4992f695be7c7cd3c920d1ed", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n;\n\tscanf(\"%d\\n\", &n);\n\tint a[102];\n\ta[0] = 0;\n\tchar c;\n\tint i;\n\tfor (i = 0; i < n; i++)\n\t{\n\t\tscanf(\"%c\", &c);\n\t\tif (c == '+')\n\t\t\ta[i + 1] = a[i] + 1;\n\t\telse\n\t\t\ta[i + 1] = a[i] - 1;\n\t}\n\tint min = 0;\n\tfor (i = 0; i <= n; i++)\n\t\tif (min > a[i])\n\t\t\tmin = a[i];\n\tif (0 > a[n] - min)\n\t\tprintf(\"0\\n\");\n\telse\n\t\tprintf(\"%d\\n\", a[n] - min);\n\treturn 0;\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "429f82c7f16ad75badb5db404b95f15d", "src_uid": "a593016e4992f695be7c7cd3c920d1ed", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n\tstring s;\n\tcin>>s;\n\tlong long int l,i,j,k,c=0,d=0,flag=1;\n\tl=s.length();\n\tfor(i=0;i<l;i++)\n\t{\n\t\tif(s[i]=='0')\n\t\tc++;\n\t\telse\n\t\tbreak;\n\t}\n\n\tfor(i=l-1;i>=0;i--)\n\t{\n\t\tif(s[i]=='0')\n\t\td++;\n\t\telse\n\t\tbreak;\n\t}\n\tif(c>d)\n\tflag=0;\n\telse\n\t{\n\t\tk=d-c;\n\t\tfor(i=0,j=l-k-1;i<=j;i++,j--)\n\t\t{\n\t\t\tif(s[i]!=s[j])\n\t\t\t{\n\t\t\t\tflag=0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tif(flag==1)\n\tprintf(\"yes\\n\");\n\telse\n\tprintf(\"no\\n\");\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f2ff4a4e1bc60acb8429f33a514f166f", "src_uid": "d82278932881e3aa997086c909f29051", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nvoid main()\n{\n    long a,c,rev=0;\n    int d\n    scanf(\"%ld\",&a);\n    d=a%10;\n    while(d==0)\n    {\n        a/=10;\n        d=a%10;\n    }\n    c=a;\n    while(c!=0)\n    {\n        d=c%10;\n        rev=rev*10+d;\n    }\n    if(rev==a)\n    printf(\"YES\");\n    else\n    printf(\"NO\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9df1bd58a9f292621847d011b97d208e", "src_uid": "d82278932881e3aa997086c909f29051", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main()\n{\n\tint x, a, reverse = 0, b = 0;\n\tscanf(\"%d\", &x);\n\twhile (n)\n\t{\n\t\tif (x % 10 == 0)\n\t\t\tx = x / 10;\n\t\telse\n\t\t\tbreak;\n\t}\n\tx = b;\n\twhile (x)\n\t{\n\t\ta = x % 10;\n\t\treverse = reverse * 10 + a;\n\t\tx = x / 10;\n\t}\n\tif (reverse == b)\n\t{\n\t\tprintf(\"YES\");\n\t}\n\telse\n\t\tprintf(\"NO\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "abcedb75e7e3934d754cda070c6fc51e", "src_uid": "d82278932881e3aa997086c909f29051", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"\u041f\u043e\u043b\u0438\u043c\u043e\u0440\u0444\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/\u041f\u043e\u043b\u0438\u043c\u043e\u0440\u0444\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/\u041f\u043e\u043b\u0438\u043c\u043e\u0440\u0444\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t\t<Add option=\"-fexceptions\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.cpp\" />\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d04b7ecb6f5a61260ea9728ff65fac4a", "src_uid": "d82278932881e3aa997086c909f29051", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\nint main()\n{\nchar input[1000000];\nscanf(\"%s\",&input);\nint length=strlen(input),letter=length-1,numofzeroes=0,caseid;\n\nif((length+1)%2==0)\ncaseid=0;\nelse\ncaseid=1;\n\nwhile(input[letter]=='0'){\nletter--;\nnumofzeroes++;\n}\n\nint done=0,front=0,back=letter;\nwhile(done==0){\n\n//printf(\"%c %c\\n\",input[front],input[back]);\nif(len==1)\ndone=1;\nelse if(input[front]!=input[back]){\ndone=1;\n}\nelse{\nif(front==(((length-numofzeroes-caseid)/2)-1)){\ndone=2;\n}\nfront++;\nback--;\n}\n}\n\nif(done==2)\nprintf(\"YES\");\nelse\nprintf(\"NO\");\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5897c58dc0b9ccea4478e49bfc5079ff", "src_uid": "d82278932881e3aa997086c909f29051", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nlong long int max(long long int a,long long int b){\n    if(a>b)\n      return a;\n    else \n       return b;\n}\nint main(){\n\n    long long int n,m;\n    scanf(\"%lld%lld\",&n,&m);\n    printf(\"%lld %lld\",max(n-2*m,0),max(n-m-1,0);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "eb77b304b1715dbf0e37fca6b0773426", "src_uid": "daf0dd781bf403f7c1bb668925caa64d", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#define _CRT_SECURE_NO_WARNINGS\n#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n\n\nint main()\n{\n\tint n,m;//\u9876\u70b9\uff0c\u8fb9\n\tscanf(\"%d%d\", &n, &m);\n\t//\u6700\u5c11/\u591a\u51e0\u4e2a\u5b64\u7acb\u9876\u70b9 \n\t//\u6700\u5c11\u7684\u8bdd\u5c3d\u53ef\u80fd\u4e00\u4e2a\u8fb9\u5c31\u8fde\u4e24\u4e2a\u70b9\n\t//\u6700\u591a\u7684\u8bdd\u5c3d\u53ef\u80fd\u63a5\u8fd1\u6ee1\u56fe\n\t//\u89e3\u4e0d\u7b49\u5f0f p(p-1)/2 < m \u6c42maxp\n\tint maxp = ceil((1 + sqrt(1 + 8 * m)) / 2);// +1;\n\tif (m == 0)\n\t{\n\t\tmaxp = 0;\n\t}\n\tprintf(\"%d %d\", max(n - 2 * m, 0) , n- maxp);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4e9ede9c8643d1155b4c8ab78feabbb4", "src_uid": "daf0dd781bf403f7c1bb668925caa64d", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdio.h>\nint main()\n{\n\tlong long n,m,k,a,min,max;\n\tscanf(\"%lld %lld\",&n,&m);\n\tfor(a=0;a<=m;a++)\n\t{\n\t\tk=a*(a-1);\n\t\tif(k>=(2*m))\n\t\t\tbreak;\n\t}\n\tmax=n-a;\n\tmin=n-2*m;\n\tif(min<0)\n\t\tmin=0;\n\tprintf(\"%lld %lld\\n\",min,max);\n}\n/*\nint factorial(int n)\n    {\n        int ans=n;\n        for(int i=n-1;i>0;i++)\n        {\n            ans*=i;\n        }\n        return ans;\n    }\nint main()\n    {\n        int vertex,edges,min=0,max=0;\n        scanf(\"%d\",&vertex);\n        scanf(\"%d\",&edges);\n\n        max=(vertex/2-edges)*2;\n        min=factorial(vertex)/(factorial(vertex-2)*2)\n        if(vertex%2==0)\n            {\n\n                printf(\"%d \",max);\n            }\n        else\n            {\n                printf(\"%d\",max+1);\n            }\n\n    }\n/*\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5413e5701f571330e18de51e87513690", "src_uid": "daf0dd781bf403f7c1bb668925caa64d", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n\n\nint main()\n{\n    long long temp,m,n,min,max;\n    double x;\n    while(scanf(\"%lld %lld\",&n,&m)!=EOF)\n    {\n        if(n==1)\n           {\n              min=max=1;\n              printf(\"%lld %lld\\n\",min,max);\n              continue;\n           }   \n        if(2*m>n)\n              min=0;\n        else\n              min=n-2*m;\n        if(n*(n-1)/2==m)\n              max=0;\n        else\n        {\n            x=m;\n            x=sqrt(x*2+0.25)+0.5;\n            temp=(long long)x;\n            temp=temp+1;\n            while(temp*(temp-1)/2>=m)\n                 temp--;\n            temp++; \n            max=n-temp; \n        }\n        printf(\"%lld %lld\\n\",min,max);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "aa39a806c66047494b24467c07f1e650", "src_uid": "daf0dd781bf403f7c1bb668925caa64d", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define int long long int\nint main(){\n\tint i,n,m,min,max;\n\tscanf(\"%lld%lld\",&n,&m);\n\tint l=n-2*m;\n\tif(l>=0)\n\t\tmin=l;\n\telse \n\t\tmin=0;\n\tfor(i=0;i<n;i++)\n\t\tif((i*(i-1))/2 >=m)\n\t\t\tbreak;\n\tmax=n-i;\n\tprintf(\"%lld %lld\",min,max);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "473a4d45bdd6d2af949c5a92b4e95597", "src_uid": "daf0dd781bf403f7c1bb668925caa64d", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n#include<Math.h>\r\n int main(){\r\n     int t,n;\r\n     scanf(\"%d\",&t);\r\n     while(t>=1){\r\n         scanf(\"%d\",&n);\r\n        \r\n         } printf(\"%d\\n\",int sqrt(n)+int cbrt(n)-int(sqrt( cbrt(n))));\r\n           t--;\r\n     }\r\n }", "lang_cluster": "C", "compilation_error": true, "code_uid": "291f1122e96274aed0f23b6f83bcd4e9", "src_uid": "015afbefe1514a0e18fcb9286c7b6624", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\r\nusing namespace std;\r\n\r\nint main()\r\n{\r\n\tint n;\r\n\tcin >> n;\r\n\twhile (cin >> n)\r\n\t\tcout<< (int) sqrt(n) + (int) cbrt(n) - (int) sqrt(cbrt(n)) << endl;\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "014f28634f34ad9b43af7febbc843074", "src_uid": "015afbefe1514a0e18fcb9286c7b6624", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n int main(){\r\n     int t,i;\r\n     scanf(\"%d\",&t);\r\n     while(t>=1){\r\n         int n;\r\n         int count=0;\r\n         scanf(\"%d\",&n);\r\n         for(i=1;i*i<=n;i++){\r\n             if(i*i<=n){\r\n                 count++;\r\n             }if(i*i*i<=n){\r\n                 count++;\r\n             }\r\n         }\r\n    t--; }printf(\"%d\",count);\r\n }", "lang_cluster": "C", "compilation_error": true, "code_uid": "4d7ce45d3581b703a340478808aa6180", "src_uid": "015afbefe1514a0e18fcb9286c7b6624", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n#include<Math.h>\r\n int main(){\r\n     int t,i,count;\r\n     scanf(\"%d\",&t);\r\n     while(t>=1){\r\n         scanf(\"%d\",&n);\r\n         int a=sqrt(n);\r\n         int b=cbrt(n);\r\n         int c=sqrt(b);\r\n        printf(\"%d\\n\", a+b-c);\r\n        t--;\r\n         } \r\n          \r\n     }\r\n \r\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5933d76c63bad52529fb7193284e3965", "src_uid": "015afbefe1514a0e18fcb9286c7b6624", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <math.h>\r\nvoid solve() {\r\n    int n;\r\n    scanf(\"%d\",&n);\r\n    printf(\"%d\\n\",sqrt(n)+cbrt(n));\r\n}\r\nint main() {\r\n    int t;\r\n    scanf(\"%d\",&t;\r\n    for (int i=0;i<t;i++) {\r\n        solve();\r\n    }\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4a764e726c4cc0e6f45ee29c1975a467", "src_uid": "015afbefe1514a0e18fcb9286c7b6624", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    int n;int ar[110];\n    int i=0;\n    for(i=0;i<109;i++)\n        ar[i]=0;\n    scanf(\"%d\",&n);\n    int ans=0;\n    for(i=1;i<=n;i++)\n        scanf(\"%d\",&ar[i]);\n    for(i=1;i<=n;i++)\n    {\n        if(ar[i]==1)\n            ans++;\n        if(ar[i]==0&&ar[i-1]==1&&ar[i+1]==1)\n            ans++;\n    }\n    printf(\"%d\\n\",ans);\n    return 0;\n    }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6dfa46e040ce8625bb331ba417a447e8", "src_uid": "2896aadda9e7a317d33315f91d1ca64d", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nenum State\n{\n    HOME,\n    SCHOOL,\n    LEAVE\n};\n\nint\nautomation(int n)\n{\n    int state = HOME;\n    int count = 0;\n    int pair;\n    for (int i = 0; i < n; i++) {\n        scanf(\"%d\", &pair);\n        switch (state) {\n            case HOME:\n                if (pair == 1) {\n                    state = SCHOOL;\n                    count++;\n                }\n                break;\n            case SCHOOL:\n                if (pair == 1) {\n                    count++;\n                }\n                else {\n                    state = LEAVE;\n                }\n                break;\n            case LEAVE:\n                if (pair == 1) {\n                    count += 2;\n                    state = SCHOOL;\n                }\n                else {\n                    state = HOME;\n                }\n                break;\n        }\n    }\n    return count;\n}\n\nint\nmain()\n{\n    int n;\n    scanf(\"%d\", &n);\n    printf(\"%d\\n\", automation(n));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d846f40a09dff6fc6eab571df1e0a374", "src_uid": "2896aadda9e7a317d33315f91d1ca64d", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int n,a[101],i,c=0,k=0;\n    scanf(\"%lld\",&n);\n    for(i=1;i<=n;i++)\n    {scanf(\"%lld\",&a[i]);}\n    if(n==1&&a[1]==0)\n    {c=0;}\n    else\n    {\n    for(i=1;i<=n;i++)\n    {if(a[i]==1)\n     {c++;}\n     else\n     {while(a[i]==0)\n      {k++;\n       i++;\n      }\n      if(k<2&&(i-1)!=1))\n      {c++;}\n      i--;\n     }\n    }}\n    \n    \n    printf(\"%lld\",c);\n}\n    \n      ", "lang_cluster": "C", "compilation_error": true, "code_uid": "24a5181132ce5337560ff51bae0b920f", "src_uid": "2896aadda9e7a317d33315f91d1ca64d", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define MAX 105\n\nmain()\n{\nint a[MAX],n,res =0;\nscanf (\"%d\",&n);\nfor(i=0;i<n;i++)\n       scanf (\"%d \",&a[i]);\nfor(i=0;i<n;i++)\n{\n    if(a[i]==1)\n         res++;\n     if(a[i]==0)\n     { \n           if(a[i-1]==1&&a[i+1]==1&i! =0&&i! =(n-1))\n               res++;\n     }}\n printf (\"%d \",res);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4c7e7f889ea8520fa82e83c356b9eb9a", "src_uid": "2896aadda9e7a317d33315f91d1ca64d", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<cstdio>\nint a[150];\nint main()\n{\n\tint n,sum,flag,flag1;\n\twhile(~scanf(\"%d\",&n))\n\t{\n\t\tsum=0,flag=1,flag1=1;\n\t\tfor(int i=0;i<n;i++)\n\t\t{\n\t\t\tscanf(\"%d\",&a[i]);\n\t\t\tif(a[i]==1) sum++;\n\t\t}\n\t\tfor(int i=0;i<n;i++)\n\t\t{\n\t\t\tif(a[i]==1&&a[i+1]==0&&a[i+2]==1) \n\t\t\t{\n\t\t\t\tsum++;\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\",sum);\n\t}\n\treturn 0;\n}\n  \t\t\t   \t \t\t\t\t\t    \t\t   \t\t\t \t\t", "lang_cluster": "C", "compilation_error": true, "code_uid": "04d561e641092fd6a6cf23221c9faa6d", "src_uid": "2896aadda9e7a317d33315f91d1ca64d", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint max(int a, int b)\n{\n    return (a>b) ? a : b;\n}\n\nint min(int a, int b)\n{\n    return (a>b) ? b : a;\n}\n\nint main()\n{\n    int HPY,ATKY,DEFY;\n    int HPM,ATKM,DEFM;\n    int addDEF = 0;\n    int count = 0;\n    int mini = 1000001;\n    int h,a,d;\n\n    scanf(\"%d %d %d\", &HPY, &ATKY, &DEFY);\n    scanf(\"%d %d %d\", &HPM, &ATKM, &DEFM);\n    scanf(\"%d %d %d\", &h, &a, &d);\n\n    int i;\n    int HPYS = HPY,ATKYS = ATKY,DEFYS = DEFY;\n    int HPMS = HPM,ATKMS = ATKM,DEFMS = DEFM;\n    /* Increase attaque every time */\n    for (i=0;i<100;++i)\n    {\n        count = a*i;\n        if (ATKY+i-DEFM <= 0)\n            continue;\n\n        if (ATKY+i > 100)\n            break;\n\n        /* Count How much time every one before die */\n        int numberH = (int)ceil((double)HPY/(double)max(0,ATKM-DEFY));\n        int numberM = (int)ceil((double)HPM/(double)max(0,ATKY+i-DEFM));\n        if (numberH > numberM)\n            break;\n        else if (numberM > 1)\n        {\n            /* If we increase Defence */\n            while (max(0,ATKM-DEFY)*(numberM-1) > HPY)\n                ++DEFY;\n            count += (DEFY-DEFYS)*d;\n            DEFY = DEFYS;\n            mini = min(mini, count);\n            /* If we increase Health */\n            count = a*i;\n            HPY += max(0,ATKM-DEFY)*(numberM-1) - HPY;\n            count += HPY*h;\n            mini = min(mini, count);\n        }\n        else if (numberM == 1)\n        {\n            while (max(0,ATKM-DEFY)*numberM > HPY)\n                ++DEFY;\n            count += (DEFY-DEFYS)*d;\n            DEFY = DEFYS;\n            mini = min(mini, count);\n            /* If we increase Health */\n            count = a*i;\n            HPY += max(0,ATKM-DEFY)*numberM - HPY;\n            count += HPY*h;\n            mini = min(mini, count);\n        }\n\n        HPY = HPYS,ATKY = ATKYS,DEFY = DEFYS;\n        HPM = HPMS,ATKM = ATKMS,DEFM = DEFMS;\n    }\n\n    printf(\"%d\\n\", mini);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7f123a11ff0374e23ed3a783b1b05f2e", "src_uid": "bf8a133154745e64a547de6f31ddc884", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint max(int a, int b)\n{\n    return (a>b) ? a : b;\n}\n\nint min(int a, int b)\n{\n    return (a>b) ? b : a;\n}\n\nint main()\n{\n    int HPY,ATKY,DEFY;\n    int HPM,ATKM,DEFM;\n    int addDEF = 0;\n    int count = 0;\n    int mini = 1000001;\n    int h,a,d;\n\n    scanf(\"%d %d %d\", &HPY, &ATKY, &DEFY);\n    scanf(\"%d %d %d\", &HPM, &ATKM, &DEFM);\n    scanf(\"%d %d %d\", &h, &a, &d);\n\n    int i;\n    int HPYS = HPY,ATKYS = ATKY,DEFYS = DEFY;\n    int HPMS = HPM,ATKMS = ATKM,DEFMS = DEFM;\n    /* Increase attaque every time */\n    for (i=0;i<100;++i)\n    {\n        count += a*i;\n\n        while (HPM > 0)\n        {\n            if (HPY < (ATKM-DEFY))\n            {\n                while (max(0,ATKM-(DEFY+addDEF)) >= HPY)\n                    ++addDEF;\n\n                if ((max(0, ATKM-DEFY)-(HPY)+1)*h < addDEF*d)\n                {\n                    count += (max(0, ATKM-DEFY)-(HPY)+1)*h;\n                    HPY += max(0, ATKM-DEFY)-(HPY)+1;\n                    addDEF = 0;\n                }\n                else\n                {\n                    count += addDEF*d;\n                    DEFY += addDEF;\n                    addDEF = 0;\n                }\n            }\n\n            HPM -= max(0, ATKY+i-DEFM);\n            HPY -= max(0, ATKM-DEFY);\n        }\n\n        if (HPY > 0)\n            mini = min(mini, count);\n\n        HPY = HPYS,ATKY = ATKYS,DEFY = DEFYS;\n        HPM = HPMS,ATKM = ATKMS,DEFM = DEFMS;\n\n        count = 0;\n    }\n\n    printf(\"%d\\n\", mini);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f63934725082536cf0244172161f8657", "src_uid": "bf8a133154745e64a547de6f31ddc884", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint lTime(int h, int a, int d) {\n    int i=-1;\n    if(d>=a) return 999999999;\n    while(h>0){\n        h=h-(a-d);\n        i++;\n    }\n    return i;\n}\nint main() {\n    int yh,ya,yd;\n    int mh,ma,md;\n    int h,a,d;\n    int lh,la,ld=1000;\n    int i,j,k,cost,min=999999999,yaa=0;\n    scanf(\"%d %d %d\",&yh,&ya,&yd);\n    scanf(\"%d %d %d\",&mh,&ma,&md);\n    scanf(\"%d %d %d\",&h,&a,&d);\n\n    for(i=0;i<1000;i++)\n        if(lTime(yh+i,ma,yd)>lTime(mh,ya,md)) \n            break;\n    lh=i;\n    for(i=0;i<1000;i++)\n        if(lTime(yh,ma,yd)>lTime(mh,ya+i,md)) \n            break;\n    la=i;\n    for(i=0;i<1000;i++)\n        if(lTime(yh,ma,yd+i)>lTime(mh,ya,md)) \n            break;\n    ld=i;\n\n//  lh=(h>10)?10000/h:1000;\n//  la=(a>10)?10000/a:1000;\n//  ld=(d>10)?10000/d:1000;\n    if(ya<=md) yaa=md-ya+1;\n//  printf(\"%d %d %d\\n\",lh,la,ld);\n    for(i=0;i<=lh;i++){\n        for(j=yaa;j<=la;j++) {\n            for(k=0;k<= ld;k++) {\n                if(lTime(yh+i,ma,yd+k)>lTime(mh,ya+j,md)) {\n                    cost=i*h+j*a+k*d;\n                    if(cost<min) {\n                        min=cost;\n//                      printf(\"%d %d %d %d\\n\",i,j,k,cost);\n                    }\n                }\n            }\n        }\n    }\n    printf(\"%d\\n\",min);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d4b778e11d48a74b8c5bcaca35837e42", "src_uid": "bf8a133154745e64a547de6f31ddc884", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint lTime(int h, int a, int d) {\n    int i=-1;\n    if(d>=a) return 999999999;\n    while(h>0){\n        h=h-(a-d);\n        i++;\n    }\n    return i;\n}\nint main() {\n    int yh,ya,yd;\n    int mh,ma,md;\n    int h,a,d;\n    int lh,la,ld;\n    int i,j,k,cost,min=999999999,yaa=0;\n    scanf(\"%d %d %d\",&yh,&ya,&yd);\n    scanf(\"%d %d %d\",&mh,&ma,&md);\n    scanf(\"%d %d %d\",&h,&a,&d);\n    \n    lh=(lh>10)?8000/h:800;\n    la=(la>10)?8000/a:800;\n    ld=(ld>10)?8000/d:800;\n    if(ya<=md) yaa=md-ya+1;\n//  printf(\"%d %d %d\\n\",lh,la,ld);\n    for(i=0;i<lh;i++){\n        for(j=yaa;j<la;j++) {\n            for(k=0;k<ld;k++) {\n                if(lTime(yh+i,ma,yd+k)>lTime(mh,ya+j,md)) {\n                    cost=i*h+j*a+k*d;\n                    if(cost<min) {\n                        min=cost;\n//                      printf(\"%d %d %d %d\\n\",i,j,k,cost);\n                    }\n                }\n            }\n        }\n    }\n    printf(\"%d\\n\",min);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a1f957dd3a20a1928f89dfa33d8516a0", "src_uid": "bf8a133154745e64a547de6f31ddc884", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define Max 200\nshort Life[Max+1][Max+1][Max+1];\n\nint chkLT(int a,int b,int c) {\n    if(a<=Max&&b<=Max&&c<=Max) return Life[a][b][c];\n    else if(c>=b) return 99999;\n    else return (a-1)/(b-c);\n}\n\nint main() {\n    int yh,ya,yd;\n    int mh,ma,md;\n    int h,a,d;\n    int i,j,k,cost,min=99999,yaa=0;\n    int lh=1000,la=1000,ld=1000;\n    scanf(\"%d %d %d\",&yh,&ya,&yd);\n    scanf(\"%d %d %d\",&mh,&ma,&md);\n    scanf(\"%d %d %d\",&h,&a,&d);\n\n    for(i=1;i<=Max;i++)\n        for(j=1;j<=Max;j++)\n            for(k=1;k<=Max;k++)\n                if(k>=j) Life[i][j][k]=99999;\n                else Life[i][j][k]=(i-1)/(j-k);\n//printf(\"%d %d\\n\",Life[10][5][2],Life[10][6][1]);\n    lh=(h>5)?lh/h:1000;\n    la=(a>5)?la/a:1000;\n    ld=(d>5)?ld/d:1000;\n\n    for(i=0;i<=lh;i++){\n        for(j=yaa;j<=la;j++) {\n            for(k=0;k<=ld;k++) {\n                if(chkLT(yh+i,ma,yd+k)>chkLT(mh,ya+j,md)) {\n                    cost=i*h+j*a+k*d;\n                    if(cost<min) {\n                        min=cost;\n//                      printf(\"%d %d %d %d\\n\",i,j,k,cost);\n                    }\n                }\n            }\n        }\n    }\n    printf(\"%d\\n\",min);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "380da1fff8fc4b9d3978c59010e83f90", "src_uid": "bf8a133154745e64a547de6f31ddc884", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#include<limits.h>\nint compare (const void * a, const void * b)\n{\n  return ( *(int*)a - *(int*)b );\n}\nlong long int min(long long int a,long long int b)\n{\n    if(a<b)\n    return a;\n    else\n    return b;\n}\nlong long int max(long long int a,long long int b)\n{\n    if(a>b)\n    return a;\n    else\n    return b;\n}\nlong long int ar[2000005],flag[2000005];\nint main()\n{\n    long long int a,b,val,val1,val2,i,j,ans,mod=1000000007,k;\n    scanf(\"%lld %lld\",&a,&b);\n    val1=min(a,b);\n    val=sqrt(2*(a+b));\n    if((val*(val+1))/2>(a+b))\n    val--;\n    val2=(val*(val+1))/2-max(a,b);\n    if(val1>val2)\n    {\n        val2=val1+val2-(val1=val2);\n    }\n    //printf(\"%lld \",val);\n    if(val1<0)\n    val1=0;\n    //printf(\"%lld %lld \",val,val2);\n    //long long int ar[val2+1],flag[val2+1];\n    for(i=0;i<=val2;i++)\n    ar[i]=0;\n    if(val2>min(a,b))\n    val2=min(a,b);\n    if(val*(val+1)<2*max(a,b))\n    i=0;\n    else\n    i=1;\n    for(i=0;i<=val;i++)\n    {\n        for(k=1;k<=val2;k++)\n        flag[k]=0;\n        for(j=1;j<=val2;j++)\n        {\n            if(j-i>0&&ar[j-i]>0&flag[j-i]==0)\n            {\n                ar[j]=ar[j]+ar[j-i];\n                flag[j]=1;\n                if(ar[j]>mod)\n                ar[j]=ar[j]%mod;\n            }\n        }\n        if(i<=val2)\n        ar[i]++;\n        if(ar[i]>mod)\n        ar[i]=ar[i]%mod;\n        //for(k=1;k<=val2;k++)\n        //printf(\"%lld \",ar[k]);\n        //printf(\"\\n\");\n    }\n    ans=0;\n    for(i=val1;i<=val2;i++)\n    {\n        ans=ans+ar[i];\n        if(ans>mod)\n        ans=ans%mod;\n    }\n    printf(\"%lld\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "16a3fe9ba5b97ed65aef4f5bf21ecfd5", "src_uid": "34b6286350e3531c1fbda6b0c184addc", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#include<limits.h>\nint compare (const void * a, const void * b)\n{\n  return ( *(int*)a - *(int*)b );\n}\nlong long int min(long long int a,long long int b)\n{\n    if(a<b)\n    return a;\n    else\n    return b;\n}\nlong long int max(long long int a,long long int b)\n{\n    if(a>b)\n    return a;\n    else\n    return b;\n}\nlong long int ar[2000005],flag[2000005];\nint main()\n{\n    long long int a,b,val,val1,val2,i,j,ans,mod=1000000007,k;\n    scanf(\"%lld %lld\",&a,&b);\n    val1=min(a,b);\n    val=sqrt(2*(a+b));\n    val2=(val*(val+1))/2-max(a,b);\n    if(val1>val2)\n    {\n        val2=val1+val2-(val1=val2);\n    }\n    //printf(\"%lld %lld \",val,val2);\n    //long long int ar[val2+1],flag[val2+1];\n    for(i=0;i<=val2;i++)\n    ar[i]=0;\n    for(i=1;i<=val;i++)\n    {\n        for(k=1;k<=val2;k++)\n        flag[k]=0;\n        for(j=1;j<=val2;j++)\n        {\n            if(j-i>0&&ar[j-i]>0&flag[j-i]==0)\n            {\n                ar[j]=ar[j]+ar[j-i];\n                flag[j]=1;\n                if(ar[j]>mod)\n                ar[j]=ar[j]%mod;\n            }\n        }\n        if(i<=val2)\n        ar[i]++;\n        if(ar[i]>mod)\n        ar[i]=ar[i]%mod;\n        //for(k=1;k<=val2;k++)\n        //printf(\"%lld \",ar[k]);\n        //printf(\"\\n\");\n    }\n    ans=0;\n    for(i=val1;i<=val2;i++)\n    {\n        ans=ans+ar[i];\n        if(ans>mod)\n        ans=ans%mod;\n    }\n    printf(\"%lld\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1bc07a47b45f91c9762aded2163ac8c6", "src_uid": "34b6286350e3531c1fbda6b0c184addc", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MAX 200010\n#define MOD 1000000007\n\nusing namespace std;\n\nint n, m, h, sum[1010], dp[MAX][2];\n\nvoid Pregenerate(){\n    int i, j, l, res, x = 0;\n    for (i = h; i >= 0; i--){\n        sum[i] = x;\n        x += i;\n    }\n\n    for (l = 0; l <= h; l++){\n        for (i = n; i >= 0; i--){\n            j = sum[l] - i;\n            if (i > sum[l]) continue;\n            if (j > m) continue;\n\n\n            if (!l) res = 1;\n            else{\n                res = 0;\n                if ((i + l) <= n) res = res + dp[i + l][(l - 1) & 1];\n                if ((j + l) <= m) res = res + dp[i][(l - 1) & 1];\n            }\n\n            if (res >= MOD) res -= MOD;\n            dp[i][l & 1] = res;\n        }\n    }\n}\n\nint main(){\n    int i, j;\n\n    while (scanf(\"%d %d\", &n, &m) != EOF){\n        for (h = 0; h <= 1000; h++){\n            int x = (h * (h + 1)) >> 1;\n            if (x > (n + m)){\n                h--;\n                break;\n            }\n        }\n\n        Pregenerate();\n        int res = dp[0][h & 1];\n        printf(\"%d\\n\", res);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3c0bd6f10638a3b639db3f24bd27858a", "src_uid": "34b6286350e3531c1fbda6b0c184addc", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\nlong long int mmax(long long int a,long long int b){\n    if(a>b) return a;\n    else return b;\n}\nlong long int fun(long long int i){\n    return (i*(i+1))/2;\n}\nlong long int target;\nlong long int binSearch(long long int i,long long int j){\n    long long int mid;\n    while (i<j) {\n        mid=(i+j)/2;\n        if(i==mid) break;\n        if(fun(mid)<target)\n            i=mid;\n        else j=mid;\n    }\n    return i;\n}\nlong long int dp[200001][1001];\nint main(){\n    long long int r,g;\n    scanf(\"%lld %lld\",&r,&g);\n    target=r+g+1;\n    long long int h=binSearch(1, target);\n    long long int ans=0;\n    dp[0][0]=1;\n    for (long long int red=0; red<=r; red++) {\n        for (long long int height=1; height<=h; height++) {\n            if(fun(height)-red<=g){\n                dp[red][height]+=dp[red-height][height-1]+dp[red][height-1];\n                dp[red][height]%=1000000007;\n                if(height==h)\n                    ans+=dp[red][height];\n                ans%=1000000007;\n            }\n        }\n    }\n    printf(\"%lld\\n\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6f94612b8226d5c43e7e48bdc84802c1", "src_uid": "34b6286350e3531c1fbda6b0c184addc", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#include<limits.h>\nint compare (const void * a, const void * b)\n{\n  return ( *(int*)a - *(int*)b );\n}\nlong long int min(long long int a,long long int b)\n{\n    if(a<b)\n    return a;\n    else\n    return b;\n}\nlong long int max(long long int a,long long int b)\n{\n    if(a>b)\n    return a;\n    else\n    return b;\n}\nint main()\n{\n    long long int a,b,val,val1,val2,i,j,ans,mod=1000000007,k;\n    scanf(\"%lld %lld\",&a,&b);\n    val1=min(a,b);\n    val=sqrt(2*(a+b));\n    val2=(val*(val+1))/2-max(a,b);\n    if(val1>val2)\n    {\n        val2=val1+val2-(val1=val2);\n    }\n    //printf(\"%lld %lld \",val,val2);\n    long long int ar[val2+1],flag[val2+1];\n    for(i=0;i<=val2;i++)\n    ar[i]=0;\n    for(i=1;i<=val;i++)\n    {\n        for(k=1;k<=val2;k++)\n        flag[k]=0;\n        for(j=1;j<=val2;j++)\n        {\n            if(j-i>0&&ar[j-i]>0&flag[j-i]==0)\n            {\n                ar[j]=ar[j]+ar[j-i];\n                flag[j]=1;\n                if(ar[j]>mod)\n                ar[j]=ar[j]%mod;\n            }\n        }\n        if(i<=val2)\n        ar[i]++;\n        if(ar[i]>mod)\n        ar[i]=ar[i]%mod;\n        //for(k=1;k<=val2;k++)\n        //printf(\"%lld \",ar[k]);\n        //printf(\"\\n\");\n    }\n    ans=0;\n    for(i=val1;i<=val2;i++)\n    {\n        ans=ans+ar[i];\n        if(ans>mod)\n        ans=ans%mod;\n    }\n    printf(\"%lld\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3c2cc9025f150cdb9e29264c09dd2a3a", "src_uid": "34b6286350e3531c1fbda6b0c184addc", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nint main()\n{\n    char s[200];\n    int k=0,len=0,index=0,i=0,flag=2,count1;count2;\n    scanf(\"%s\",s);\n    len=strlen(s);\n    scanf(\"%d\",&k);\n    if((len+k)%2!=0&&len!=0) { index++;}\n    while(index<len)\n    {\n        int mid=index+ (len+k-index)/2;\n        for(i=0;mid+i<len;i++)\n        {\n            if(s[index+i]!=s[mid+i]) break;\n        }\n        if(mid+i>=len) {flag=0;break;}\n        index+=2;\n    }\n    count1=len+k-index-flag;\n    index=0;flag=2,k=0;\n    if((len+k)%2!=0&&len!=0) { index++;}\n    while(index<len)\n    {\n        int mid=index+ (len+k-index)/2;\n        for(i=0;mid+i<len;i++)\n        {\n            if(s[index+i]!=s[mid+i]) break;\n        }\n        if(mid+i>=len) {flag=0;break;}\n        index+=2;\n    }\n    count2=len+k-index-flag;\n    if(count1<count2) count1=count2;\n    printf(\"%d\",count1);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c13948a0d7c7d1459d21e9158df57492", "src_uid": "bb65667b65ff069a9c0c9e8fe31da8ab", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint tandem(int , int );\nchar s[401];\nint k,count;\nint main(void)\n{\n    int i,j,len,max=0;\n    scanf(\"%s %d\",s,&k);\n    len=strlen(s);\n    for(i=len,j=0;j<k;j++,i++)\n        s[i]='?';\n    len+=k;\n    for(i=0;i<len;i++)\n    {\n        for(j=i+1;j<len;j++)\n        {   \n            if(tandem(i,j)==1)\n            {\n                if(max<j-i+1)\n                    max=j-i+1;\n            }\n        }\n    }\n    printf(\"%d\",max);\n    return 0;\n}\nint tandem(int low,int high)\n{\n    int cond=1;\n    count=0;\n    int mid=(high-low+1)/2;\n    for(i=0;i<mid;i++)\n        if(s[i]!=s[i+mid] && s[i+mid]!='?')\n            return 0;\n        else\n            return 1;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "10751b0f94991fc9f6118b1c86e8eec7", "src_uid": "bb65667b65ff069a9c0c9e8fe31da8ab", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\nint main()\n{\n    int i,j,k,l,m,temp,res=0,max=0;\n    char s[300],in[10];\n    scanf(\"%s\",s);\n    scanf(\"%s\",in);\n    k=atoi(in);\n    l=strlen(s);\n    if(k>=l)\n        printf(\"%d\\n\",((k+l)/2));\n    else\n    {\n        for(i=0;i<l-k;i++)\n        {\n            for(j=(l+k-i)/2;j>=1;j--)\n            {\n                temp=0;\n                for(m=i;m<i+j;m++)\n                {\n                    if(m+j>=l)\n                        break;\n                    if(s[i]!=s[m+j])\n                    {temp=-1;break;}\n                }\n                if(temp==0 && j>max)\n                    max=j;\n            }\n        }\n        if(max>k)\n            printf(\"%d\\n\",2*max);\n        else\n            printf(\"%d\\n\",2*k);\n    }\n    return 0;\n}#include <stdio.h>\n\nint main(void) {\n\t// your code goes here\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6a52039f731bb7bb278638ce4a6c895d", "src_uid": "bb65667b65ff069a9c0c9e8fe31da8ab", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nint main()\n{\n    char s[200];\n    int k=0,len=0,index=0,i=0,flag=0;\n    scanf(\"%s\",s);\n    len=strlen(s);\n    scanf(\"%d\",&k);\n    if((len+k)%2!=0) { index++;}\n    while(1)\n    {\n        int mid=index+ (len+k-index)/2;\n        for(i=0;mid+i<len;i++)\n        {\n            if(s[index+i]!=s[mid+i]) break;\n        }\n        if(mid+i==len) break;\n        index+=2;\n    }\n    printf(\"%d\",len+k-index);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a8af08eccf32f72be56cc4403fdaf7dc", "src_uid": "bb65667b65ff069a9c0c9e8fe31da8ab", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <conio.h>\n#include <string.h>\n\nint ktra(char s[], int start, int end, int u, int n)\n{\n    int i;\n    for (i = start; i < start + u; i++)\n    {\n        if (s[i] != s[i + u] && i + u <= n - 1)\n            break;\n    }\n    if (i >= start + u)\n        return 1;\n    else return 0;\n}\n\nint kqua(char s[], int k)\n{\n    int n, u, start, end;\n    n = strlen(s);\n    u = (n + k) / 2;\n    if (n > k)\n    {\n        for (; u >= k; u--)\n        {\n            start = 0; end = 2*u - 1;\n            while (end <= n + k - 1)\n            {\n                if (ktra(s, start, end, u, n))\n                    break;\n                else\n                {\n                    start++; end++;\n                }\n            }\n            if (end <= n + k - 1)\n                return 2 * u;\n        }\n    }\n    else return 2 * u;\n}\n\n\nint main()\n{\n    char s[100];\n    int k;\n    scanf(\"%s\", &s);\n    scanf(\"%d\", &k);\n    printf(\"%d\", kqua(s, k));\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "78ec5de8cd1654da5d22de4e7c1d56e9", "src_uid": "bb65667b65ff069a9c0c9e8fe31da8ab", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int n,a,b,i;\n\n    scanf(\"%d %d %d\", &n, &a, &b);\n    \n    for (i=1; i<=a && i<=b && (a/i + b/i >= n); x++);\n    \n    printf(\"%d\", x - 1);\n    \n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2e48882f490aed70b8f2924dc191c503", "src_uid": "a254b1e3451c507cf7ce3e2496b3d69e", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n \nint main() \n{\n\tint n,a,b,x,y,z,i,ans;\n \n\tscanf(\"%d%d%d\", &n, &a, &b);\n\tans = 0;\n\tfor (i = 1; i< n; i++) \n\t{\n\t\t x = a / m;\n\t\t y = b / (n - m);\n\t\t z = x < y ? x : y;\n \n\t\tif (ans < z)\n\t\t\tans = z;\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2c614b923b5e9f32fe18195860a73b99", "src_uid": "a254b1e3451c507cf7ce3e2496b3d69e", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c565389b5cdf9400c38ecc3f0a1a6785", "src_uid": "a254b1e3451c507cf7ce3e2496b3d69e", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int n,a,b,i;\n\n    scanf(\"%d %d %d\", &n, &a, &b);\n    \n    for (i=1; i<=a && i<=b && (a/i + b/i >= n); i++);\n    \n    printf(\"%d\", x - 1);\n    \n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "df5421d767a0432acdbc092041863599", "src_uid": "a254b1e3451c507cf7ce3e2496b3d69e", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "//Date : 27 - 12 - 17\n\n#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<stdbool.h>\n#include<float.h>\n#include<math.h>\n#include<inttypes.h>\n#include<assert.h>\n#include<ctype.h>\n#include<limits.h>\n#include<time.h>\n#define ll long long\n#define For(i,n)\tfor(i=0;i<n;i++)\n#define rep(i ,a ,b)\tfor(i=(a);i<=(b);i++)\n#define mset(a ,value)\tmemset(a ,value ,sizeof(a))\n#define s(a)\tscanf(\"%d\" ,&a);\n#define ls(a)\tscanf(\"%ld\" ,&a)\n#define reg(i)\tregister int i\n#define infinite INT_MAX\n#define MAX 100005\n#define NIL -1\nint min(int a,int b){\treturn (a < b ? a : b)\t;}\t\nint max(int a,int b){\treturn (a > b ? a : b)\t;}\n/*\nint a[MAX] ,p[MAX];\nint main(){\n\tint n ,i ,m = INT_MAX ,r = 0 ,d = INT_MAX;\n\ts(n);\n\tFor(i ,n){\ts(a[i]);\tm = min(m ,a[i]);\t}\n\tFor(i ,n)\tif(a[i] == m)\tp[r++] = i;\n\trep(i ,1,r - 1)\td = min(d ,p[i] - p[i - 1]);\n\tprintf(\"%d\" ,d);\n\treturn 0;\n}*/\n\nvoid swap(int *a,int *b){\n\tint t = *a;\n\t*a = *b;\n\t*b = t;\n}\nint main(){\n\tint n ,a ,b ,i ,x ,y;\n\tscanf(\"%d%d%d\" ,&n ,&a ,&b);\n\tif(a > b)\tswap(&a ,&b);\n\trep(i ,1 ,a){\n\t\tx = a / i;\n\t\ty = b / i;\n\t\tif(x + y < n)\tbreak;\n\t}\n\tprintf(\"%d\" ,i - 1);\n\treturn 0;\n}\n/*\nint a[3];\nint cmp(const void *a,const void *b){\n\tint *a1 = (int *)a;\n\tint *b1 = (int *)b;\n\tif((*a1) > (*b1))\treturn 1;\n\tif((*a1) == (*b1))\treturn 0;\n\treturn -1;\n}\nint main(){\n\tscanf(\"%d%d%d\" ,a ,a + 1 ,a + 2);\n\tqsort(a ,3 ,sizeof(a[0]) ,cmp);\n\tif(a[0] == 1)\tputs(\"YES\");\n\telse if(a[0] == 2){\n\t\tif(a[1] == 2)\tputs(\"YES\");\n\t\telse puts(\"NO\");\n\t}else if(a[0] == 3){\n\t\tif(a[1] == 3 && a[2] == 3)\tputs(\"YES\");\n\t\telse puts(\"NO\");\n\t}else\tputs(\"NO\");\n\treturn 0;\n}*/\nint a[1550]\nint main(){\n\tint n ,i ,j;\n\ts(n);\n\tFor(i ,n)\ts(a[i]);\n\t\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "051b8fb638cc1c7451597457be70dd86", "src_uid": "a254b1e3451c507cf7ce3e2496b3d69e", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "include<stdio.h>\n#include<limits.h>\nint min(int a,int b)\n{\n\tif(a>b)\n\treturn b;\n\telse\n\treturn a;\n}\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tint a[n+1];\n\t\n\tint i,x,y;\n\tx=n;\n\tfor(i=0;i<=n;i++)\n\ta[i]=INT_MAX;\n\ta[0]=0;\n\tint t;\n\t//int q=11;\n\tfor( i=1;i<=9;i++)\n\ta[i]=1;\n\tfor(i=10;i<=n;i++)\n\t{\n\t\tx=i;\n\t\twhile(x/10!=0)\n\t\t{\n\t\t//\tprintf(\"iii\");\n\t\t\ty=x%10;\n\t\t//\tprintf(\"%d\\n\",y);\n\t\t\tif(y!=0)\n\t\t\ta[i]=min(a[i-y]+1,a[i]);\n\t\t\tx=x/10;\n\t\t//\tprintf(\"%d\\n\",x);\n\t\t}\n\t\ty=x%10;\n\t\tif(y!=0)\n\t\t\ta[i]=min(a[i-y]+1,a[i]);\n\t\t\n\t}\n\tprintf(\"%d\",a[n]);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cbebb52272c331ea737ec541e2ad4b56", "src_uid": "fc5765b9bd18dc7555fa76e91530c036", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "k", "lang_cluster": "C", "compilation_error": true, "code_uid": "2c3af4f0b1ec48c43dc373061a37a14c", "src_uid": "fc5765b9bd18dc7555fa76e91530c036", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "kk", "lang_cluster": "C", "compilation_error": true, "code_uid": "00fc52fe611fefce49c5d075fa828107", "src_uid": "fc5765b9bd18dc7555fa76e91530c036", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\n int main() \n { \n    int n, m, large=0, rem;\n  int counter=0; \n  scanf(\"%d\", &n); \n  for(; n!=0; counter++) \n  { large = 0; m = n;\n   while(m) \n   { rem = m%10;\n    if(rem > large) large = rem;\n     m = m/10; }\n      n = n-large; }\nprintf(\"%d\\n\", counter);\ngetch();\n return 0;\n  }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5b1839fd18a0278e67e8fd6d2c0cdd4c", "src_uid": "fc5765b9bd18dc7555fa76e91530c036", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\n int main() \n { \n    int n, m, large=0, rem;\n int counter=0; \n  scanf(\"%d\", &n); \n  for(; n!=0; counter++) \n  { large = 0; m = n;\n   while(m) \n   { rem = m%10;\n    if(rem > large) large = rem;\n     m = m/10; }\n      n = n-large; }\nprintf(\"%d\\n\", counter);\ngetch();\n return 0;\n  }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cba6500283077b215925b5f3b4a59b98", "src_uid": "fc5765b9bd18dc7555fa76e91530c036", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "\n#include<stdio.h>\nlong long int min(long long int a,long long int b)\n{\n    if(a<b)\n        return a;\n    else return b;\n}\nint main()\n{\n    long long int n,a,b,c;\n    scanf(\"%lld %lld %lld %lld\",&n,&a,&b,&c);\n    if(n%4==0 )\n        printf(\"0\");\n    else\n    {\n    switch(n%4)\n    {\n        case 3:printf(\"%d\",min(3*c,min(a,b+c));break;\n        case 2:printf(\"%d\",min(a+c,min(2*a,b));break;\n        case 1:printf(\"%d\",min(a+b,min(3*a,c)));break;\n        \n    }\n    }\n    return 0;\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "355e8efc3c75ea4824365e6be27fbb11", "src_uid": "c74537b7e2032c1d928717dfe15ccfb8", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main(){\n    long long int n, a, b, c;\n    scanf(\"%I64d %I64d %I64d %I64d\", &n, &a, &b, &c);\n    n %= 4;\n    switch(n){\n        case 0: printf(\"0\\n\"); break;\n        case 1: long long int x = a + b;\n                if (x > (a + a + a)) x = a + a + a;\n                else if (x > c) x = c\n                printf(\"%I64d\\n\", x); break;\n        case 2: long long int x = c + c + a + a + a;\n                if (x > (a + a)) x = a + a;\n                else if (x > b) x = b;\n                printf(\"%I64d\\n\", x); break;\n        case 3: long long int x = c + b;\n                if (x > a) x = a;\n                printf(\"%I64d\\n\", x); break;                \n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c7679bfe2a3ed2b6c65f7fe394045b09", "src_uid": "c74537b7e2032c1d928717dfe15ccfb8", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int n,a,b,c,rem,amt=0;\n    scanf(\"%lld%lld%d%lld\",&n,&a,&b,&c);\n    rem=n%4;\n    if(rem==1)\n    {\n        amt=(c<3*a)?c:(3*a);\n        amt=((a+b)<amt?(a+b):amt);\n    }\n    else if(rem==2)\n    {\n        amt = (b<2*a)?b:(2*a);\n        amt = ((2*c)<amt)?)2*c):amt;\n    }\n    else if(rem==3)\n    {\n        amt=(a<3*c)?a:(3*c);\n        amt=amt<(b+c)?amt:(b+c);\n    }\n    printf(\"%lld\",amt);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "924a896f9b724bff8d92aedbf5c4ec47", "src_uid": "c74537b7e2032c1d928717dfe15ccfb8", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,a,b,c;\n    int ans;\n    scanf(\"%d%d%d%d\",&n,&a,&b,&c);\n    switch((n%4))\n    {\n      case 0 : ans=0;  break;\n      case 3 : ans=a < b+c ? a: b+c ;\n               ans= ans < 3*c ? ans = 3*c;\n      break;\n      case 2 : ans= 2*a > b ? b : 2*a ;\n               ans = ans < 2*c ? ans : 2*c ;\n               break;\n      default:  ans= 2*a > b ? b+a : 3*a ;\n                ans= ans > c ? c : ans ;\n    };\n    printf(\"%d\\n\",ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0fc3254ce43137c39deefa729816e1c5", "src_uid": "c74537b7e2032c1d928717dfe15ccfb8", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define MIN(a,b) (a>b?b:a)\n#define Min(a,b,c) MIN(MIN(a,b),c)\nmain()\n{\n\tlong long int x,n,a,b,c;\n\tscanf(\"%lld%lld%lld%lld\",&n,&a,&b,&c);\n\tx=n%4;\n\tswitch(x)\n\t{\n\t\tcase 1:printf(\"%lld\",min(3*a,c,a+b));\n\t\tbreak;\n\t\tcase 2:printf(\"%lld\",Min(2*a,b,2*c));\n\t\tbreak;\n\t\tcase 3:printf(\"%lld\",Min(a,b+c,3*c));\n\t\tbreak;\n\t\tdefault:printf(\"0\");\n\t}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "167e34aaade2ea5ee885d47db9690df1", "src_uid": "c74537b7e2032c1d928717dfe15ccfb8", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\n \nusing namespace std;\n \n#define mp make_pair\n#define pb push_back\n#define nd second\n#define st first\n#define endl '\\n'\n#define endll cout<<endl;\n#define sol (node*2)\n#define sag ((node*2)+1)\n#define orta (bas+son)/2\n \ntypedef long long ll;\ntypedef long long int lli;\ntypedef long long unsigned llu;\ntypedef pair < int,int > pii;\ntypedef pair < lli,lli > plli;\nconst int MAX = 1e5+7;\nint main()\n{\n\tlong long int a[50]={  1, 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8092, 16184, 32368, 64736, 129472, 258944, 517888, 1035776, 2071552, 4143104, 8286208, 16572416, 33144832, 66289664, 132579328, 265158656, 530317312, 1060634624, 2121269248, 4242538496, 8485076992, 16970153984, 33940307968};\n\tint n;\n\tcin>>n;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7e3913c0312c4577843e5d3520c7519f", "src_uid": "76f6ebfaeea789952c931d65c6a5fdff", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "int main()\n{\n\n    int n;\n    long long a[36] = { 1, 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8092, 16184, 32368, 64736, 129472, 258944, 517888, 1035776, 2071552, 4143104, 8286208, 16572416, 33144832, 66289664, 132579328, 265158656, 530317312, 1060634624, 2121269248, 4242538496, 8485076992, 16970153984, 33940307968 };\n    scanf(\"%d\",&n);\n    printf(\"%I64d\",a[n]);\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "83c1e0286e4678252b83526484ee360e", "src_uid": "76f6ebfaeea789952c931d65c6a5fdff", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    long long  a;\n    scanf(\"%I64d\",&a);\n    p=pow(2,a);\n    printf(\"%I64d\\n\",p);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "36abf660a218a61a932ec223e6962c3c", "src_uid": "76f6ebfaeea789952c931d65c6a5fdff", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e7f7e2b9aeb64d7bada12ed894d33585", "src_uid": "76f6ebfaeea789952c931d65c6a5fdff", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n\nint main()\n{\n    cin>>a;\n    print(\"%d\",pow(2,a));\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8633163487e77b8f0f500fe7cbeae49c", "src_uid": "76f6ebfaeea789952c931d65c6a5fdff", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define M 1000000007\n__int64 fastpow(int a,__int64 n){\n    __int64 ans;\n    if(n==0) return 1;\n   if(n==1) return a%M;\n   ans=fastpow(a,n/2)%M;\n    ans=(ans*ans)%M;\n    if(n%2==1)\n       ans=((ans%M)*(a%M))%M;\n     return ans%M;\n}\nint main(){\n    __int64 ans;\n    __int64 n;\n    while(scanf(\"%I64d\",&n)!=EOF){\n        if(n==0)\n         printf(\"1\\n\");\n         else{\n        ans=(fastpow(2,n-1)%M+(2*(fastpow(4,n-1)%M))%M)%M;\n        printf(\"%I64d\\n\",ans);\n         }\n        }\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "71bcd24364e7ee8d4578d133bfa52d8d", "src_uid": "782b819eb0bfc86d6f96f15ac09d5085", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n__int64 pows(__int64 x, __int64 n)\n{\n    if(n == 1)\n        return x;\n    __int64 ans=pows(x,n/2) % 1000000007;\n    if(n & 1)\n        return (ans * ans * x) % 1000000007;\n    else\n        return (ans * ans) % 1000000007;\n}\n\nint main()\n{\n    __int64 n;\n    while(~scanf(\"%I64d\", &n))\n    {\n        if(n == 0)\n        {\n            printf(\"1\\n\");\n            continue;\n        }\n        __int64 u = pows(2, n)% 1000000007;\n        u = (u * (u + 1) / 2) % 1000000007;\n        printf(\"%I64d\\n\", u);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e33e638de1ac075466a904fb6153be91", "src_uid": "782b819eb0bfc86d6f96f15ac09d5085", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define MAX 1000000007\nlong long i,n,y=1,temp,temp2,a=0;\nlong long int pow(long long int a){\n\tif(!a) return 1;\n\n\ttemp = pow(a/2);\n\ttemp = (temp*temp) % MAX;\n\tif(a%2 == 1) temp*=2 % MAX;\n\treturn temp;\n}\nint main(){\n\tscanf(\"%lld\",&n);\n\tn = pow(n);\n\tprintf(\"%lld\",(n*(n+1)/2)%MAX);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "abdff968e26cae9d0799cb4f885ebbfa", "src_uid": "782b819eb0bfc86d6f96f15ac09d5085", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nconst long long mod = 1000000007;\n\nlong long\npower(long long a, long long b)\n{\n    if(b == 0){\n        return 1;\n    }\n    if(b % 2 == 0){\n        long long l = power(a, b / 2);\n        l = (l * l) % mod;\n        return l;\n    } else {\n        long long l = (power(a, b - 1) * a) % mod;\n        return l;\n    }\n}\n\nint\nmain(void)\n{\n    long long n;\n    if(n == 0){\n        printf(\"1\");\n        return 0;\n    }\n    scanf(\"%I64d\", &n);\n    long long ans = power(2, n - 1);\n    long long ans2 = (ans * 2 + 1) % mod;\n    ans = (ans * ans2) % mod;\n    printf(\"%I64d\", ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3550b82658d8e9e1a15f8863c3bf6924", "src_uid": "782b819eb0bfc86d6f96f15ac09d5085", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n__int64 pows(__int64 x, __int64 n)\n{\n\tif(n == 1)\n\t\treturn x;\n\t__int64 ans=pows(x,n/2) % 1000000007;\n\tif(n & 1)\n\t\treturn (ans * ans * x) % 1000000007;\n\telse\n\t\treturn (ans * ans) % 1000000007;\n}\n\nint main()\n{\n\t__int64 n;\n\twhile(~scanf(\"%I64d\", &n))\n\t{\n\t\t__int64 u = pows(2, n)% 1000000007;\n\t\tu = (u * (u + 1) / 2) % 1000000007;\n\t\tprintf(\"%I64d\\n\", u);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "eb1a00f8aa14213a52156cad6eea0ebd", "src_uid": "782b819eb0bfc86d6f96f15ac09d5085", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main(void)\n{\n    char map[4][4], x, temp[5];\n    int c = 0;\n    \n    for(int i = 0; i < 4; i++)\n    {\n        scanf(\"%s\", map[i]);\n    }\n    \n    for(int i = 0; i < 4; i++)\n    {\n        for(int j = 0; j < 4; j++)\n        {\n            if (map[i][j] == '.')\n            {\n                map[i][j] = 'x';\n            }\n        }\n    }\n    \n    \n    for(int i = 0; i < 4; i++)\n    {\n        for(int j = 0; j < 4; j++)\n        {\n            temp[j] = map[i][j];\n        }\n        temp[4] = 0;\n        if (strcmp(temp, \"xxxx\") == 0)\n        {\n            c++;\n        }\n    }\n    for(int i = 0; i < 4; i++)\n    {\n        for(int j = 0; j < 4; j++)\n        {\n            temp[j] = map[j][i];\n        }\n        temp[4] = 0;\n        if (strcmp(temp, \"XXXX\") == 0)\n        {\n            c++;\n        }\n    }\n    \n    for(int i = 0; i < 4; i++)\n    {\n        temp[i] = map[i][i];\n    }\n    if (strcmp(temp, \"XXXX\") == 0)\n    {\n        c++;\n    }\n    for(int i = 0; i < 4; i++)\n    {\n        temp[i] = map[i][3 - i];\n    }\n    if (strcmp(temp, \"xxxx\") == 0)\n    {\n        c++;\n    }\n    \n    \n    \n    if (c == 0)\n    {\n        puts(\"NO\");\n    }\n    else\n    {\n        puts(\"YES\");\n    }\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "67f516f319b47e9bcde823fa191b23a8", "src_uid": "ca4a77fe9718b8bd0b3cc3d956e22917", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint num[4][4] = { 0 };\n\nint ok(int a, int b)\n{\n\tint i, cnt = 0;\n\n\tfor (i = a - 2; i <= a + 2; i++)\n\t{\n\t\tif (i < 0)\n\t\t\tcontinue;\n\t\telse if (i > 3)\n\t\t\tbreak;\n\t\telse if (num[i][b] == 1)\n\t\t\tcnt++;\n\t\telse if (num[i][b] != 1 && cnt > 0 && cnt != 3)\n\t\t{\n\t\t\tcnt = 0;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif (cnt == 3)\n\t\treturn 1;\n\telse\n\t\tcnt = 0;\n\n\tfor (i = b - 2; i <= b + 2; i++)\n\t{\n\t\tif (i < 0)\n\t\t\tcontinue;\n\t\telse if (i > 3)\n\t\t\tbreak;\n\t\telse if (num[a][i] == 1)\n\t\t\tcnt++;\n\t\telse if (num[a][i] != 1 && cnt > 0 && cnt != 3)\n\t\t{\n\t\t\tcnt = 0;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif (cnt == 3)\n\t\treturn 1;\n\telse\n\t\tcnt = 0;\n\n\tfor (i = -2; i <= 2; i++)\n\t{\n\t\tif (a + i < 0 || b + i < 0)\n\t\t\tcontinue;\n\t\telse if (a + i > 3 || b + i > 3)\n\t\t\tbreak;\n\t\telse if (num[a + i][b + i] == 1)\n\t\t\tcnt++;\n\t\telse if (num[a + i][b + i] != 1 && cnt > 0 && cnt != 3)\n\t\t{\n\t\t\tcnt = 0;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif (cnt == 3)\n\t\treturn 1;\n\telse\n\t\tcnt = 0;\n\n\treturn 0;\n}\n\nint dfs(int a, int b)\n{\n\tif (a == 4)\n\t\treturn 0;\n\telse if (b == 4)\n\t\treturn dfs(a + 1, 0);\n\telse if (num[a][b] == 2 || num[a][b] == 1)\n\t\treturn dfs(a, b + 1);\n\telse\n\t{\n\t\tnum[a][b] = 1;\n\t\tif (ok(a, b))\n\t\t\treturn 1;\n\t\tnum[a][b] = 0;\n\t\treturn dfs(a, b + 1);\n\t}\n}\n\nint main(void)\n{\n\tint i, j;\n\tchar temp;\n\n\tfor (i = 0; i < 4; i++)\n\t{\n\t\tfor (j = 0; j < 4; j++)\n\t\t{\n\t\t\tscanf(\"%c\", &temp);\n\t\t\tif (temp == 'x')\n\t\t\t\tnum[i][j] = 1;\n\t\t\telse if (temp == 'o')\n\t\t\t\tnum[i][j] = 2;\n\t\t}\n\t\tgetchar();\n\t}\n\tif (dfs(0, 0))\n\t\tprintf(\"YES\");\n\telse\n\t\tprintf(\"NO\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e32f8010c11c3ce9e1bc87d66758b8c4", "src_uid": "ca4a77fe9718b8bd0b3cc3d956e22917", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MAX 6\n\nint threeRow(char arr[MAX][MAX]);\n\nint main(void) {\n\t\n\tchar aux,ticTac[MAX][MAX];\n\tint i,j;\n\t\n\tfor (i=0;i<MAX;i++){\n\t\tfor(j=0;j<MAX;j++){\n\t\t\tticTac[i][j]='a';\n\t\t}\n\t}\n\tfor(i=1;i<MAX-1;i++){\n\t\tfor(j=1;j<MAX-1;j++){\n\t\t\tscanf(\"%c\",&ticTac[i][j]);\n\t\t}\n\t\tscanf(\"%c\",&aux);\n\t}\n\tthreeRow(ticTac);\n\treturn 0;\n}\n\nint threeRow(char arr[MAX][MAX]){\n\tint i,j;\n\t\n\tfor(i=1;i<MAX-1;i++){\n\t\tfor(j=1;j<MAX-1;j++){\n\t\t\tif(((arr[i][j]=='x')&&(((arr[i-1][j-1]=='x')&&(arr[i+1][j+1]=='.'))\n\t\t\t\t\t\t\t\t\t||((arr[i-1][j-1]=='x')&&(arr[i+1][j+1]=='x'))\n\t\t\t\t\t\t\t\t\t||((arr[i-1][j]=='x')&&(arr[i+1][j]=='.'))\n\t\t\t\t\t\t\t\t\t||((arr[i-1][j]=='x')&&(arr[i+1][j]=='x'))\n\t\t\t\t\t\t\t\t\t||((arr[i-1][j+1]=='x')&&(arr[i+1][j-1]=='.'))\n\t\t\t\t\t\t\t\t\t||((arr[i-1][j+1]=='.')&&(arr[i+1][j-1]=='x'))\n\t\t\t\t\t\t\t\t\t||((arr[i][j-1]=='.')&&(arr[i][j+1]=='x'))\n\t\t\t\t\t\t\t\t\t||((arr[i][j-1]=='x')&&(arr[i][j+1]=='.'))))\n\t\t\t\t||(arr[i][j]==\".\"&&(((arr[i-1][j-1]=='x')&&(arr[i+1][j+1]=='x'))\n\t\t\t\t\t\t\t\t\t||((arr[i-1][j]=='x')&&(arr[i+1][j]=='x'))\n\t\t\t\t\t\t\t\t\t||((arr[i-1][j+1]=='x')&&(arr[i+1][j-1]=='x'))\n\t\t\t\t\t\t\t\t\t||((arr[i][j-1]=='x')&&(arr[i][j+1]=='x'))))){\n\t\t\t\t\t\t\t\t\t\tprintf(\"YES\");\n\t\t\t\t\t\t\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tif((i==(MAX-1))&&(j==MAX-1)){\n\t\tprintf(\"NO\");\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f4a8baff6b8d9be97e86cd05e5bc4134", "src_uid": "ca4a77fe9718b8bd0b3cc3d956e22917", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include \"stdio.h\"\n\nchar a[5][5],temp;\nint countX=0, countO=0;\n\nbool check(char temp){\n  for (int i=0 ; i<4 ; i++){\n    if (a[i][0]==temp && a[i][1]==temp && a[i][2]==temp) return true;\n    if (a[i][1]==temp && a[i][2]==temp && a[i][3]==temp) return true;\n  }\n  for (int i=0 ; i<4 ; i++){\n    if (a[0][i]==temp && a[1][i]==temp && a[2][i]==temp) return true;\n    if (a[1][i]==temp && a[2][i]==temp && a[3][i]==temp) return true;\n  }\n  for (int i=2 ; i<4 ; i++){\n    for (int j=2 ; j<4 ; j++){\n      if (a[i][j]==temp && a[i+1][j-1]==temp && a[i+2][j-2]==temp) return true;\n    }\n  }\n  for (int i=0 ; i<2 ; i++){\n    for (int j=0 ; j<2 ; j++){\n      if (a[i][j]==temp && a[i+1][j+1]==temp && a[i+2][j+2]==temp) return true;\n    }\n  }\n  return false;\n}\n\nint main(int argc, char const *argv[]) {\n  for (int i=0 ; i<4 ; i++){\n    for (int j=0 ; j<4 ; j++){\n      scanf(\"%c\", &a[i][j]);\n      if (a[i][j]=='x') countX++;\n      if (a[i][j]=='o') countO++;\n    }\n    scanf(\"%c\", &temp);\n  }\n\n  if (countX>countO){\n    temp='o';\n  }\n  else if (countX<countO){\n    temp='x';\n  }\n  else temp='x';\n  for (int i=0 ; i<4 ; i++){\n    for (int j=0 ; j<4 ; j++){\n      if (a[i][j]=='.'){\n        a[i][j]=temp;\n        if (check(temp)){\n          printf(\"YES\");\n          return 0;\n        }\n        a[i][j]='.';\n      }\n    }\n  }\n  printf(\"NO\");\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ba52c1488976107d9cec09ed4b2a8e1d", "src_uid": "ca4a77fe9718b8bd0b3cc3d956e22917", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<string.h>\n#include<stdlib.h>\n#define ll long long int\n#define M 1000000007\n#define rep(i,a,b,c) for(i=a;i<b;i=i+c)\n#define rev(i,a,b,c) for(i=a;i>=b;i=i-c)\n#define test long long int t;scanf(\"%lld\",&t);while(t--)\n#define pi(a) printf(\"%lld\\n\",a)\n#define psi(a) printf(\"%lld \",a)\n#define pc(a) printf(\"%c\\n\",c)\n#define ps(a) printf(\"%s\\n\",s)\n#define si(a) scanf(\"%lld\",&a)\n#define sf(a) scanf(\"%f\",&a)\n#define sc(a) scanf(\"%c\",&c)\n#define ss(a) scanf(\"%s\",a)\n#define min(a,b) (a<b?a:b)\n#define min3(a,b,c) min(a,min(b,c))\n#define max(a,b) (a<b?a:b)\n#define max3(a,b,c) max(a,max(b,c))\n#define gcd(a,b) (b!=0?gcd(b,a%b):a)\n#define sieve(n) long long int p[100002];rep(i,0,n,1)p[i]=0;p[1]=1;rep(i,2,n+1,1){if(!p[i]){rep(j,2*i,n+1,i)p[j]=1;}}\nint main()\n{ll a[100001],s,i,j,n,x;\nchar s1[10][10];\nscanf(\"%s\",s1[0]);s=0;\nscanf(\"%s\",s1[1]);scanf(\"%s\",s1[2]);scanf(\"%s\",s1[3]);\n//printf(\"%c\\n%c\\n%c\\n%c\\n\",s1[0][0],s1[1][1],s1[2][2],s1[3][3]);\nfor(i=0;i<4;i++)\n{if(s==1)break;\n    for(j=0;j<4;j++)\n    {\n        if(s1[i][j]=='.')\n        {\n            if(s1[i+1][j]=='x'&&s1[i+2][j]=='x'&&i+2<4){s=1;}\n            else if(s1[i-1][j]=='x'&&s1[i-2][j]=='x'&&i-2>=0){s=1;}\n            else if(s1[i][j+1]=='x'&&s1[i][j+2]=='x'&&j+2<4){s=1;}\n            else if(s1[i][j-1]=='x'&&s1[i][j-2]=='x'&&j-2>=0){s=1;}\n            else if(s1[i+1][j+1]=='x'&&s1[i+2][j+2]=='x'&&j+2<4&&i+2<4){s=1;}\n            else if(s1[i-1][j-1]=='x'&&s1[i-2][j-2]=='x'&&j-2>=0&&i-2>=0){s=1;}\n            else if(s1[i+1][j-1]=='x'&&s1[i+2][j-2]=='x'&&j-2>=0&&i+2<4)s=1;\n            else if(s1[i-1][j+1]=='x'&&s1[i-2][j+2]=='x'&&j+2<4&&i-2>=0)\n        }\n        else if(s1[i][j]=='x')\n        {\n            if(((s1[i+1][j]=='.'&&s1[i+2][j]=='x')||(s1[i+1][j]=='x'&&s1[i+2][j]=='.'))&&i+2<4){s=1;}\n            else if(((s1[i-1][j]=='.'&&s1[i-2][j]=='x')||(s1[i-1][j]=='x'&&s1[i-2][j]=='.'))&&i-2>=0){s=1;}\n            else if(((s1[i][j+1]=='.'&&s1[i][j+2]=='x')||(s1[i][j+1]=='x'&&s1[i][j+2]=='.'))&&j+2<4){s=1;}\n            else if(((s1[i][j-1]=='.'&&s1[i][j-2]=='x')||(s1[i][j-1]=='x'&&s1[i][j-2]=='.'))&&j-2>=0){s=1;}\n\n            else if((s1[i+1][j+1]=='.'&&s1[i+2][j+2]=='x')||(s1[i+1][j+1]=='x'&&s1[i+2][j+2]=='.')){if(j+2<4&&i+2<4){s=1;}}\n            else if((s1[i-1][j-1]=='.'&&s1[i-2][j-2]=='x')||(s1[i-1][j-1]=='x'&&s1[i-2][j-2]=='.')){if(j-2>=0&&i-2>=0){s=1;}}\n\n            else if((s1[i-1][j+1]=='.'&&s1[i-2][j+2]=='x')||(s1[i-1][j+1]=='x'&&s1[i-2][j+2]=='.')){if(i-2>=0&&j+2<4)s=1;}\n            else if((s1[i+1][j-1]=='.'&&s1[i+2][j-2]=='x')||(s1[i+1][j-1]=='x'&&s1[i+2][j-2]=='.')){if(j-2>=0&&i+2<4)s=1;}\n        }\n    }\n}\nif(s==1)printf(\"YES\\n\");\nelse printf(\"NO\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "af8fecff13b1fd74f4aa1f01ce6e9d70", "src_uid": "ca4a77fe9718b8bd0b3cc3d956e22917", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{double a, b, c, d, x, y, a1, a2, p, q;\n  scanf(\"%lf %lf %lf %lf\", &a, &b, &c, &d);\nx =(a - (a/250)*c);\ny =(b - (b/250)*d);\na1 =(3*a)/10;\nb2 =(3*b)/10;\np=max(x,a1);\nq=max(y,b1);  \nif(p<q)\n   {\n     printf(\"Vasya\");\n   }\n     else if (p>q)\n   {\n     printf(\"Misha\");\n   }\n    else if (p==q)\n   {\n    printf(\"Tie\");\n\n   }\n   return 0;\n}\n   }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7a419135e11365d360b3178a98eac94c", "src_uid": "95b19d7569d6b70bd97d46a8541060d0", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{int a, b, c, d, x, y, m, n, o, p;\n  scanf(\"%d %d %d %d\", &a, &b, &c, &d);\nm =(a - (a/250)*c);\nn =(b - (b/250)*d);\no =(3*a)/10;\np =(3*b)/10;\n\n   if(m>o)\n   {\n      x=m;\n   }\n      else if(m<o)\n        {\n        x=o;\n        }\n    if(n>p){\n    {\n    y=n;\n    }\n   else if(n<p)\n    {\n    y=p;\n    }\n    if (x>y){\n        printf(\"Misha\");\n    }\n    else if(y>x){\n        printf(\"Vasya\");\n    }\n   else if (x==y){\n    printf(\"Tie\");\n   }\n   \n  }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e13c1fac8c5a5e6d277ce636a4afbe88", "src_uid": "95b19d7569d6b70bd97d46a8541060d0", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n main()\n{double a, b, c, d, x, y, m, n, o, p;\n  scanf(\"%lf %lf %lf %lf\", &a, &b, &c, &d);\nm =(a - (a/250)*c);\nn =(b - (b/250)*d);\no =(3*a)/10;\np =(3*b)/10;\n\n   if(m>o)\n   {\n      x=m;\n   }\n      else if(m<o)\n        {\n        x=o;\n        }\n    if(n>p){\n    {\n    y=n;\n    }\n   else if(n<p)\n    {\n    y=p;\n    }\n    if (x>y){\n        printf(\"Misha\");\n    }\n    else if(y>x){\n        printf(\"Vasya\");\n    }\n   else if (x==y){\n    printf(\"Tie\");\n   }\n   return 0;\n  }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "04ba3878b0e5dc3fdbc9e0090968d0d8", "src_uid": "95b19d7569d6b70bd97d46a8541060d0", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "\n#include<iostream>\n#include<cstdio>\n#include<vector>\n#include<algorithm>\n#include<vector>\n#include<string>\n#include<cstring>\n#include<cmath>\nint main()\n{\n\tint a, b, c, d;\n\tscanf(\"%d%d%d%d\", &a, &b, &c, &d);\n\tint xxx, yy;\n\txxx = 75 * a > 250 * a - a*c ? 75 * a : 250 * a - a*c;\n\tyy = 75 * b> 250 * b - b*d? 75 * b: 250 * b - b*d;\n\tif (xxx > yy)printf(\"Misha\\n\");\n\telse if (xxx == yy)printf(\"Tie\\n\");\n\telse printf(\"Vasya\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c1eddcdadac41bd57454e5097c0f4214", "src_uid": "95b19d7569d6b70bd97d46a8541060d0", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\nvoid main()\n{\nint a,b,c,d,e,f;\nprintf(\"\\nEnter points and timings of Misha and Vasya resp.:\");\nscanf(\"%d %d %d %d\",&a,&b,&c,&d);\ne=a-(a/250)*c;\nf=b-(b/250)*d;\nif(e>f)\n{\nprintf(\"\\nMisha\");\n}\nelseif(e<f)\n{\nprintf(\"\\nVasya\");\n}\nelse\n{\nprintf(\\nTIE\");\n}\ngetch();\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "56fc82c294e4cd2a5300061ac6091045", "src_uid": "95b19d7569d6b70bd97d46a8541060d0", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int c,v,v1,a,l,i=0,s=0;\n    scanf(\"%d %d %d %d %d\",&c,&v,&v1,&a,&l);\n    while(1)\n    {\n\n\n\n        s=s+(v+(a*i));\n        if(i!=0)\n        {\n            s=s-l;\n        }\n        if(s>=v1)\n        {\n            s=v1;\n        }\n        i++;\n        if(s==c)\n        {\n            printf(\"%d\\n\",i);\n            break;\n        }\n    }\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f974d3e53c3a7d82358b2342baaeb7d1", "src_uid": "b743110117ce13e2090367fd038d3b50", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint c,vo,term,v1,a,l,ans=1,sum;\n\tscanf(\"%d%d%d%d%d\",&c,&vo,&v1,&a,&l);\n\tsum=vo;\n\tterm=vo+a-l;\n\twhile(sum<c)\n\t{\n\t\tans++;\n\t\tif(term < v1)\n\t\t{\n\t\t\tsum=term+sum;\n\t\t\tterm=term+a;\n\t\t}\n\t\telse\n\t\t\tsum=sum+v1-l;\n\t}\n\tprintf(\"%d\\n\",ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2d3192cd535923a56f1dc063508860b7", "src_uid": "b743110117ce13e2090367fd038d3b50", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int c,v0,v1,a,l,m=0,i=0;\n    scanf(\"%d%d%d%d%d\",&c,&v0,&v1,&a,&l);\n    while(c>0)\n    {\n        if(m<v1)\n        m=v0+(i*a)-(i*l);\n        c=c-m;\n        i++;\n    }\n    printf(\"%d\\n\"i);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "eb22a5e89ef0f83587e8b427b15fe37f", "src_uid": "b743110117ce13e2090367fd038d3b50", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main (void){\n  int pages,init,max,acc,reread;\n  scanf(\"%d %d %d %d %d\",&pages,&init,&max,&acc,&reread)\n  int days=0,read=0,speed;\n  for(days=1;1==1;days++){\n    speed=init+(days-1)*acc;\n    if(speed<max){\n      read=read+speed;\n    }\n    else{\n      read=read+max;\n    }\n    if (read>=pages)\n      break;\n    read=read-reread;\n  }\n  printf(\"%d\",days);\n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "61f0b8826e26a632f2033ad7729d008c", "src_uid": "b743110117ce13e2090367fd038d3b50", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nvoid main(){\n    int c, v0, v1, a, l;\n    scanf(\"%d%d%d%d%d\", &c, &v0, &v1, &a, &l);\n    int pages = v0;\n    int days = 1;\n    c = c - pages;\n    while (c>0){\n        days += 1;\n        pages = pages + a;\n        if (pages>v1){\n            pages = v1;\n        }\n        c = c + l - (pages);\n    }\n    printf(\"%d\", days);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "052f595a453198c9651b29276602f65d", "src_uid": "b743110117ce13e2090367fd038d3b50", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n    long int x1,y1,x2,y2,x,y,k1,k2,flag=0;\n    scanf(\"%ld%ld%ld%ld\",&x1,&y1,&x2,&y2);\n    scanf(\"%ld%ld\",&x,&y);\n    if((abs(x2-x1)%x==0)&&(abs(y2-y1)%y==0))\n    {\n        k1=abs(x2-x1)/x;\n        k2=abs(y2-y1)/y;\n        if(k1==k2)flag=1;\n        else if((k1%2==0)&&(k2%2==0))flag=1;\n        else if((k1%2!=0)&&(k2%2!=0))flag=1;\n\n    }\n    if(flag==1)printf(\"Yes\\n\");\n    else if(flag==0)printf(\"No\\n\");\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5e9669457c5d27b1e1dd1a4301db24cb", "src_uid": "1c80040104e06c9f24abfcfe654a851f", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint abs(int a)\n{\n    return a < 0 ? -1 : a;\n}\nint main()\n{\n    int x1,y1,x2,y2,x,y;\n    scanf(\"%d %d %d %d\",&x1,&y1,&x2,&y2);\n    int x0 = abs(x1-x2);\n    int y0 = abs(y1-y2);\n    scanf(\"%d %d\",&x,&y);\n    if(x0%x != 0 || y0%y != 0)\n        printf(\"NO\\n\");\n    else\n    {\n        if((x0/x)%2 == (y0/y)%2)\n            printf(\"YES\\n\");\n        else\n            printf(\"NO\\n\");\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "77730db6d85684eb163803d8e327b222", "src_uid": "1c80040104e06c9f24abfcfe654a851f", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    int x1,x2,y1,y2,x,y,a,b;\n    scanf(\"%d %d %d %d\",&x1,&y1,&x2,&y2);\n    scanf(\"%d %d\",&x,&y);\n\n    a=abs(x2-x1);\n    b=abs(y2-y1);\n\n    if(a%x!=0||b%y!=0)\n    {\n          printf(\"NO\\n\");\n    }\n\n    else if((a/x)%2==(b/y)%2)\n    {\n        printf(\"YES\\n\");\n    }\n    else{\n        printf(\"NO\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b5df01fb96d05e99adf33021a48d6223", "src_uid": "1c80040104e06c9f24abfcfe654a851f", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "`````````````2222222222222222222222222222222222222222222222222222\n \t\t  \t \t\t \t      \t\t\t \t   \t\t\t \t\t", "lang_cluster": "C", "compilation_error": true, "code_uid": "717a172120d6b55e5d4e906721c31e27", "src_uid": "1c80040104e06c9f24abfcfe654a851f", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\nint main()\n{\n    int x1,y1,x2,y2,x,y;\n    scanf(\"%d %d %d %d\",x1,y1,x2,y2);\n    int n,m;\n    n=abs(x1-x2);\n    m=abs(y1-y2);\n    if((n==0&&m%y==0)||(m==0&&n%x==0))\n    printf(\"YES\\n\");\n    else\n    printf(\"NO\\n\");\n    return 0;\n    \n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ab9d0eb7f4a24d242f696e91fd4fea4e", "src_uid": "1c80040104e06c9f24abfcfe654a851f", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint i;\n\tint l[4],s[4],r[4],p[4];\n\tfor(i=0;i<4;i++)\n\t{\n\t\tscanf(\"%d\",&l[i]);\n\t\tscanf(\"%d\",&s[i]);\n\t\tscanf(\"%d\",&r[i]);\n\t\tscanf(\"%d\",&p[i]);\n\t}\n\n\tfor(i=0;i<4;i++)\n\t{\n\t\tif(p[i]==1)\n\t\t{\n\t\t\tif(l[i]==1||s[i]==1||r[i]==1)\n\t\t\t{\n\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\tprintf(\"NO\\n\");\n\treturn 0;\n\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "53462402db9babf23c5ecfbc0d172996", "src_uid": "44fdf71d56bef949ec83f00d17c29127", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tlong a,b,c,d,r1,r2,r3,r4,f1,f2,f3,f4;\n\tr1=0,r2=0,r3=0,r4=0;\n\tscanf(\"%ld %ld %ld %ld\",&a,&b,&c,&f1);\n\tr4+=a;\n\tr3+=b;\n\tr2+=c;\n\tscanf(\"%ld %ld %ld %ld\",&a,&b,&c,&f2);\n\tr1+=a;\n\tr4+=b;\n\tr3+=c;\n\tscanf(\"%ld %ld %ld %ld\",&a,&b,&c,&f3);\n\tr2+=a;\n\tr1+=b;\n\tr4+=c;\n\tscanf(\"%ld %ld %ld %ld\",&a,&b,&c,&f4);\n\tr3+=a;\n\tr2+=b;\n\tr1+=c;\n\tif((f1==1 && r1>0) || (f2==1 && r2>0) || (f3==1 && r3>0) || (f4==1 && r4>0))\n\t\tprintf(\"YES\\n\");\n\telse\n\t\tprintf(\"NO\\n\");\n\treturn 0;\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "04e4e353b96647cc4624f1bdb05686e9", "src_uid": "44fdf71d56bef949ec83f00d17c29127", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int i,j,ara[4][4];\n    for(i=0; i<4; i++)\n    {\n        for(j=0; j<4; j++)\n            scanf(\"%d\",&ara[i][j]);\n    }\n    /* for(i=0; i<4; i++)\n    {\n        for(j=0; j<4; j++)\n            printf(\"%d\",ara[i][j]);\n    }*/\n\n    if(ara[0][3]==1 && (ara[0][0]==1 || ara[3][0]==1 || ara[2][1]==1 || ara[1][2]==1))\n        printf(\"YES\");\n    else if(ara[3][3]==1 && (ara[0][0]==1 || ara[3][0]==1 || ara[2][2]==1 || ara[1][1]==1))\n        printf(\"YES\");\n    else if(ara[1][3]==1 && (ara[0][2]==1 || ara[2][2]==1 || ara[3][1]==1 || ara[1][0]==1))\n        printf(\"YES\");\n    else if(ara[2][3]==1 && (ara[2][0]==1 || ara[3][2]==1 || ara[0][1]==1 || ara[1][2]==1))\n        printf(\"YES\");\n    else\n        printf(\"NO\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0c3211244385f92a1ee6a689c182aa2c", "src_uid": "44fdf71d56bef949ec83f00d17c29127", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{int a[4][4],i,k,j;\n\tfor(i=0;i<4;i++)\n\tfor(j=0;j<4;j++)\n\tscanf(\"%d\",&a[i][j]);\n\tfor(i=0;i<4;i++)\n\tif(a[i][3]==1)\n   {\tk=i;break;}\n   \n   if(a[(k+1)%4][0]==1||a[(k+2)%4][1]==1||a[(k+3)%4][2]==1||a[k][0]==1||a[k][1]==1||a[k][2]==1)\n   printf(\"YES\\n\");\n   else\n   printf(\"NO\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c6248b31c1510246bdfb9325b0998c9a", "src_uid": "44fdf71d56bef949ec83f00d17c29127", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nconst int size =4;\n\nvoid analyze(int input[][size]){\n    if((input[0][3] == input[1][0] ||input[0][3] == input[2][1] || input[0][3] == input[3][2] )&& input[0][3]==1 && input[0][0] != 1 && input[0][1] != 1 && input[0][2] != 1){\n        printf(\"YES\");\n        return;\n    }\n    else if((input[1][3] == input[2][0] || input[1][3] == input[3][1] || input[1][3] == input[0][2] )&& input[1][3] == 1 && input[1][0] != 1  && input[1][1] != 1  && input[1][2] != 1){\n        printf(\"YES\");\n        return;\n    }\n    else if((input[2][3] == input[3][0] || input[2][3] == input[0][1] || input[2][3] == input[1][2] )&& input[2][3] == 1 && input[2][0] != 1 && input[2][1] != 1 && input[2][2] != 1){\n        printf(\"YES\");\n        return;\n    }\n    else if((input[3][3] == input[0][0] || input[3][3] == input[1][1] || input[3][3] == input[2][2] )&& input[3][3] == 1 && input[3][0] != 1  input[3][1] != 1  input[3][2] != 1){\n        printf(\"YES\");\n        return;\n    }\n    else{\n        printf(\"NO\");\n    }\n}\n\nint main(void) {\n    int * p;\n    int N, i , j;\n    int x = 0;\n    int input[size][size];\n    \n    p = &input[0][0];\n    \n    \n    for( i=0 ; i < (size*4) ; i++){\n        scanf(\"%d\", (p+i));\n    }\n    analyze(input);\n      printf(\"\\n\");\n    \n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9f8b9e7a82c1b67082639d0084ac8413", "src_uid": "44fdf71d56bef949ec83f00d17c29127", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#define LONG 10\n#define DIG 8\n#include \"cifrado.h\"\n\nint main(){\n\n    /* declaraciones de variables */\n    char cifrado[LONG*DIG+1];\n    char codigoCifrado[LONG][LONG+1];\n    \n     int i,j,k,h=0;\n    \n    char cadena[LONG + 1], contrasenia[LONG+1], resultado[LONG+1];\n\n    //lectura de datos\n    scanf(\"%s\", &cifrado);\n    for(i=0; i<LONG;i++){\n        scanf(\"%s\", &codigoCifrado[i]);\n        \n        \n    }\n\n        //lee el cifrado de a 10 caracteres\n        for(i = 0; i < LONG*DIG; i += LONG)\n        {\n            //carga los primeros diez digitos en el auxiliar cadena\n            for( j = i; j < i + LONG; j++)\n            {\n                cadena[h] = cifrado[j];\n                    h++;\n            }\n            //incializa la variable h para la siguiente cadena\n                h=0;\n\n                cadena[LONG] = '\\0';\n                //printf(\"Cad%s\\n\", cadena);\n\n            //compara cadena con nuestra matriz de cifrados\n             for(k = 0; k < LONG; k++)\n             {  //printf(\"Cod%s\\n\", codigoCifrado[k]);\n                if(!strcmp(codigoCifrado[k],cadena)){\n                       printf(\"%d\", k);\n                        break;\n                }\n\n            }\n       }\n            //K Representa el digito cifrado\n            //resultado += contrasenia;\n\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5e27de151409987a109ea97bbdf3c451", "src_uid": "0f4f7ca388dd1b2192436c67f9ac74d9", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d367d64073b3e09409b47d77f5622952", "src_uid": "0f4f7ca388dd1b2192436c67f9ac74d9", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <malloc.h>\nchar *extraer(char *string, int pos, int lh) ;\nint main()\n{\n    char *s, digito[10],*puntero;\n    gets(s);\n    int x;\n    for (size_t i = 0; i < sizeof(digito) / sizeof(digito[0]); ++i)\n    {\n       scanf(\"%c\", &digito[i]);\n    }\n    for (size_t i = 0; i < 8; ++i)\n    {\n        puntero = extraer(s,i * 10, 10);\n        for (size_t j = 0; j < 10; ++j)\n        {\n            if (x == digito[j])\n            {\n                printf(\"%d\",&j);\n                break;\n            }\n        }\n    }\n    system(\"pause\");\n    return 0;\n}\nchar *extraer(char *string, int pos, int lh) \n{\n   char *puntero;\n   int c;\n \n   puntero =(char*) malloc(sizeof (lh+1));\n \n   if (puntero == NULL)\n   {\n      printf(\"Memoria no disponible\");\n      exit(-1);\n   }\n \n   for (c = 0 ; c < pos -1 ; c++) \n      string++; \n \n   for (c = 0 ; c < lh ; c++)\n   {\n      *(puntero+c) = *string;      \n      string++;   \n   }\n \n   *(puntero+c) = '\\0';\n \n   return puntero;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d32dd7cc14d64552785c24611634b9a6", "src_uid": "0f4f7ca388dd1b2192436c67f9ac74d9", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h> \n#include <string.h> \nint main() \n{\nchar s1[10][11],s2[81],d[2],*ptr;\n    int i=2,c=10;\n    scanf(\"%s\",s2);\n    for( i=0;i<10;i++){\n        scanf(\"%s\",s1[i]);\n    }\nfor(int j=0;j<c;j++){\n\n    for( i=0;i<10;i++){;\n        if((ptr=strstr(s2,s1[i]))=NULL){\n            sprintf(d, \"%d\",i);\n            *ptr=d[0];\n            c--;\n        }\n    }           \n}       \n    ptr=s2;\n    for(i=0;i<9;i++){\n        printf(\"%c\",*ptr);\n        ptr=ptr+10;\n    }\n    return 0;  \n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f787fcaea4e70c932582343c0be15007", "src_uid": "0f4f7ca388dd1b2192436c67f9ac74d9", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "package yx_utils;\n/*\n * Entero.java\n *\n * ALGORITMOS Y ESTRUCTURAS DE DATOS III\n * Prof. Juan Segovia Silvero\n * \n * Entero es un wrapper sobre \"long\" que implementa Cmp.\n*/\n\n\npublic class Entero implements Cmp\n{\n   private long n;\n\n   public Entero (int n)\n   {\n      this.n   = n;\n   }\n\n   public int comparar (Cmp c2)\n   /*\n    * Compara los objetos segun sus valores.\n    */\n   {\n      Entero a2 = (Entero) c2;\n\n      if ( this.n < a2.n )\n         return -1;\n      if ( this.n > a2.n )\n         return 1;\n\n      return 0;\n   }\n\n   public String toString()\n   {\n       return \"\" + this.n;\n   }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1ea6d4734d265d95226c2326a501b652", "src_uid": "0f4f7ca388dd1b2192436c67f9ac74d9", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nstruct Team {\n    char name[25];\n    int point;\n    int score;\n    int miss;\n}team[4], tmp_team[4];\n\nvoid swap(int *lhs, int *rhs) {\n    int tmp = *lhs;\n    *lhs = *rhs;\n    *rhs = tmp;\n}\n\nvoid cpy_team() {\n    int i;\n    for (i = 0; i < 4; ++i) {\n        tmp_team[i].point = team[i].point;\n        tmp_team[i].score = team[i].score;\n        tmp_team[i].miss = team[i].miss;\n        strcpy(tmp_team[i].name, team[i].name);\n    }\n}\n\nchar hash_s[4][25];\nint hash_idx = 0;\nint hash(const char* str) {\n    int i;\n    for (i = 0; i < hash_idx; ++i) {\n        if (!strcmp(str, hash_s[i])) {\n            return i;\n        }\n    }\n    strcpy(hash_s[hash_idx++], str);\n    return hash_idx - 1;\n}\n\nint comp(const void *lhs, const void *rhs) {\n    struct Team *sa = (struct Team *)lhs;\n    struct Team *sb = (struct Team *)rhs;\n    if (sa->point != sb->point) {\n        return sa->point < sb->point;\n    }\n    if (sa->score - sa->miss != sb->score - sb->miss) {\n        return sa->score - sa->miss < sb->score - sb->miss;\n    }\n    if (sa->score != sb->score) {\n        return sa->score < sb->score;\n    }\n    return strcmp(sa->name, sb->name) > 0;\n}\n\nint main() {\n    //freopen(\"in.txt\", \"r\", stdin);\n    int i, j, ia, ib, na, nb, b_id, opp_id, x, y, min = 10000, cnt[4];\n    char sa[25], sb[25];\n\n    memset(cnt, 0, sizeof(cnt));\n    for (i = 0; i < 5; ++i) {\n        scanf(\"%s %s %d:%d\", sa, sb, &na, &nb);\n        ia = hash(sa);\n        ib = hash(sb);\n        strcpy(team[ia].name, sa);\n        strcpy(team[ib].name, sb);\n        ++cnt[ia];\n        ++cnt[ib];\n        /*printf(\"%d %d %d %d\\n\", na, nb, ia, ib);*/\n        if (nb > na) {\n            swap(&na, &nb);\n            swap(&ia, &ib);\n        }\n        /*printf(\"%d %d\\n\", na, nb);*/\n        if (na > nb) {\n            team[ia].point += 3;\n        } else if (na == nb) {\n            team[ia].point += 1;\n            team[ib].point += 1;\n        }\n        team[ia].score += na;\n        team[ia].miss += nb;\n        team[ib].score += nb;\n        team[ib].miss += na;\n    }\n    /*for (i = 0; i < 4; ++i) {*/\n        /*printf(\"%d %d %d\\n\", team[i].point, team[i].score, team[i].miss);*/\n    /*}*/\n    /*return 0;*/\n    for (i = 0; i < 4; ++i) {\n        if (!strcmp(team[i].name, \"BERLAND\")) {\n            b_id = i;\n        } else if (cnt[i] != 3) {\n            opp_id = i;\n        }\n    }\n\n    cpy_team();\n    qsort(tmp_team, 4, sizeof(struct Team), comp);\n    /*for (i = 0; i < 4; ++i) {*/\n        /*printf(\"%s\\n\", tmp_team[i].name);*/\n    /*}*/\n    /*printf(\"opp_id = %d, b_id = %d\\n\", opp_id, b_id);*/\n    /*for (i = 0; i < hash_idx; ++i) {*/\n        /*printf(\"%s\\n\", hash_s[i]);*/\n    /*}*/\n    for (i = 1; i < 100; ++i) {\n        for (j = i - 1; j >= 0; --j) {\n            cpy_team();\n            tmp_team[b_id].point += 3;\n            tmp_team[b_id].score += i;\n            tmp_team[opp_id].miss += i;\n\n            tmp_team[b_id].miss += j;\n            tmp_team[opp_id].score += j;\n            qsort(tmp_team, 4, sizeof(struct Team), comp);\n            if (!strcmp(tmp_team[0].name, \"BERLAND\") || !strcmp(tmp_team[1].name, \"BERLAND\")) {\n                if (i - j < min) {\n                    min = i - j;\n                    x = i;\n                    y = j;\n                }\n            }\n    }\n    if (min != 10000) {\n        printf(\"%d:%d\\n\", x, y);\n    } else {\n        puts(\"IMPOSSIBLE\");\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fc92191fa16868f6880b5e73b2a83bec", "src_uid": "5033d51c67b7ae0b1a2d9fd292fdced1", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nstruct Team {\n    char name[25];\n    int point;\n    int score;\n    int miss;\n}team[4], tmp_team[4];\n\nvoid swap(int *lhs, int *rhs) {\n    int tmp = *lhs;\n    *lhs = *rhs;\n    *rhs = tmp;\n}\n\nvoid cpy_team() {\n    int i;\n    for (i = 0; i < 4; ++i) {\n        tmp_team[i] = team[i];\n    }\n}\n\nchar hash_s[4][25];\nint hash_idx = 0;\nint hash(const char* str) {\n    int i;\n    for (i = 0; i < hash_idx; ++i) {\n        if (!strcmp(str, hash_s[i])) {\n            return i;\n        }\n    }\n    strcpy(hash_s[hash_idx++], str);\n    return hash_idx - 1;\n}\n\nint comp(const void *lhs, const void *rhs) {\n    struct Team *sa = (struct Team *)lhs;\n    struct Team *sb = (struct Team *)rhs;\n    if (sa->point != sb->point) {\n        return sa->point < sb->point;\n    }\n    if (sa->score - sa->miss != sb->score - sb->miss) {\n        return sa->score - sa->miss < sb->score - sb->miss;\n    }\n    if (sa->score != sb->score) {\n        return sa->score < sb->score;\n    }\n    return strcmp(sa->name, sb->name) > 0;\n}\n\nint main() {\n    //freopen(\"in.txt\", \"r\", stdin);\n    int i, j, ia, ib, na, nb, b_id, opp_id, cnt[4];\n    char sa[25], sb[25];\n\n    memset(cnt, 0, sizeof(cnt));\n    for (i = 0; i < 5; ++i) {\n        scanf(\"%s %s %d:%d\", sa, sb, &na, &nb);\n        ia = hash(sa);\n        ib = hash(sb);\n        strcpy(team[ia].name, sa);\n        strcpy(team[ib].name, sb);\n        ++cnt[ia];\n        ++cnt[ib];\n        /*printf(\"%d %d %d %d\\n\", na, nb, ia, ib);*/\n        if (nb > na) {\n            swap(&na, &nb);\n            swap(&ia, &ib);\n        }\n        /*printf(\"%d %d\\n\", na, nb);*/\n        if (na > nb) {\n            team[ia].point += 3;\n        } else if (na == nb) {\n            team[ia].point += 1;\n            team[ib].point += 1;\n        }\n        team[ia].score += na;\n        team[ia].miss += nb;\n        team[ib].score += nb;\n        team[ib].miss += na;\n    }\n    /*for (i = 0; i < 4; ++i) {*/\n        /*printf(\"%d %d %d\\n\", team[i].point, team[i].score, team[i].miss);*/\n    /*}*/\n    /*return 0;*/\n    for (i = 0; i < 4; ++i) {\n        if (!strcmp(team[i].name, \"BERLAND\")) {\n            b_id = i;\n        } else if (cnt[i] != 3) {\n            opp_id = i;\n        }\n    }\n\n    cpy_team();\n    qsort(tmp_team, 4, sizeof(struct Team), comp);\n    /*for (i = 0; i < 4; ++i) {*/\n        /*printf(\"%s\\n\", tmp_team[i].name);*/\n    /*}*/\n    /*printf(\"opp_id = %d, b_id = %d\\n\", opp_id, b_id);*/\n    /*for (i = 0; i < hash_idx; ++i) {*/\n        /*printf(\"%s\\n\", hash_s[i]);*/\n    /*}*/\n    for (i = 1; i < 100; ++i) {\n        cpy_team();\n        tmp_team[b_id].point += 3;\n        tmp_team[b_id].score += i;\n        tmp_team[opp_id].miss += i;\n        /*for (j = 0; j < 4; ++j) {*/\n            /*printf(\"%d %d %d\\n\", tmp_team[j].point, tmp_team[j].score, tmp_team[j].miss);*/\n        /*}*/\n        /*putchar('\\n');*/\n        qsort(tmp_team, 4, sizeof(struct Team), comp);\n        if (!strcmp(tmp_team[0].name, \"BERLAND\") || !strcmp(tmp_team[1].name, \"BERLAND\")) {\n            printf(\"%d:0\\n\", i);\n            return 0;\n        }\n    }\n    puts(\"IMPOSSIBLE\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ecbcbd2f7a766ca0faedcef88799b644", "src_uid": "5033d51c67b7ae0b1a2d9fd292fdced1", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nchar ss[4][32];\n\nint get(char *s) {\n\tstatic int n;\n\tint i;\n\n\tfor (i = 0; i < n; i++)\n\t\tif (strcmp(ss[i], s) == 0)\n\t\t\treturn i;\n\tstrcpy(ss[n], s);\n\treturn n++;\n}\n\nint g1[4], g0[4], pp[4], dd[4];\n\nint compare(const void *a, const void *b) {\n\tint i = *(int *) a;\n\tint j = *(int *) b;\n\tint gi, gj;\n\n\tif (pp[i] != pp[j])\n\t\treturn pp[j] - pp[i];\n\tgi = g1[i] - g0[i];\n\tgj = g1[j] - g0[j];\n\tif (gi != gj)\n\t\treturn gj - gi;\n\tif (g1[i] != g1[j])\n\t\treturn g1[j] - g1[i];\n\treturn strcmp(ss[i], ss[j]);\n}\n\nint main() {\n\tstatic char s[32], t[32], z[8];\n\tstatic int ii[4];\n\tint h, i, j, x, y, r;\n\n\tfor (h = 0; h < 5; h++) {\n\t\tscanf(\"%s%s%s\", s, t, z);\n\t\ti = get(s), j = get(t);\n\t\tx = z[0] - '0';\n\t\ty = z[2] - '0';\n\t\tg1[i] += x, g0[j] += x;\n\t\tg0[i] += y, g1[j] += y;\n\t\tif (x > y)\n\t\t\tpp[i] += 3;\n\t\telse if (x < y)\n\t\t\tpp[j] += 3;\n\t\telse {\n\t\t\tpp[i]++;\n\t\t\tpp[j]++;\n\t\t}\n\t\tdd[i]++;\n\t\tdd[j]++;\n\t}\n\tfor (i = 0; i < 4; i++)\n\t\tii[i] = i;\n\ti = 0;\n\twhile (strcmp(ss[i], \"BERLAND\"))\n\t\ti++;\n\tj = 0;\n\twhile (j == i || dd[j] != 2)\n\t\tj++;\n\tfor (x = 1, y = 0; x < 30; x++) {\n\t\tg1[i] += x, g0[j] += x;\n\t\tg0[i] += y, g1[j] += y;\n\t\tif (x > y)\n\t\t\tpp[i] += 3;\n\t\telse if (x < y)\n\t\t\tpp[j] += 3;\n\t\telse {\n\t\t\tpp[i]++;\n\t\t\tpp[j]++;\n\t\t}\n\t\tqsort(ii, 4, sizeof *ii, compare);\n\t\tr = 0;\n\t\twhile (ii[r] != i)\n\t\t\tr++;\n\t\tif (r < 2) {\n\t\t\tprintf(\"%d:0\\n\", x);\n\t\t\treturn 0;\n\t\t}\n\t\tg1[i] -= x, g0[j] -= x;\n\t\tg0[i] -= y, g1[j] -= y;\n\t\tif (x > y)\n\t\t\tpp[i] -= 3;\n\t\telse if (x < y)\n\t\t\tpp[j] -= 3;\n\t\telse {\n\t\t\tpp[i]--;\n\t\t\tpp[j]--;\n\t\t}\n\t}\n\tprintf(\"IMPOSSIBLE\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a7ec8eb6d88aebbdac3892cd0dc00977", "src_uid": "5033d51c67b7ae0b1a2d9fd292fdced1", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nstruct Team {\n    char name[15];\n    int point;\n    int score;\n    int miss;\n}team[4], tmp_team[4];\n\nvoid swap(int *lhs, int *rhs) {\n    int tmp = *lhs;\n    *lhs = *rhs;\n    *rhs = tmp;\n}\n\nvoid cpy_team() {\n    int i;\n    for (i = 0; i < 4; ++i) {\n        tmp_team[i] = team[i];\n    }\n}\n\nchar hash_s[4][25];\nint hash_idx = 0;\nint hash(const char* str) {\n    int i;\n    for (i = 0; i < hash_idx; ++i) {\n        if (!strcmp(str, hash_s[i])) {\n            return i;\n        }\n    }\n    strcpy(hash_s[hash_idx++], str);\n    return hash_idx - 1;\n}\n\nint comp(const void *lhs, const void *rhs) {\n    struct Team *sa = (struct Team *)lhs;\n    struct Team *sb = (struct Team *)rhs;\n    if (sa->point != sb->point) {\n        return sa->point < sb->point;\n    }\n    if (sa->score - sa->miss != sb->score - sb->miss) {\n        return sa->score - sa->miss < sb->score - sb->miss;\n    }\n    if (sa->score != sb->score) {\n        return sa->score < sb->score;\n    }\n    return strcmp(sa->name, sb->name) > 0;\n}\n\nint main() {\n    //freopen(\"in.txt\", \"r\", stdin);\n    int i, j, ia, ib, na, nb, b_id, opp_id, cnt[4];\n    char sa[25], sb[25];\n\n    memset(cnt, 0, sizeof(cnt));\n    for (i = 0; i < 5; ++i) {\n        scanf(\"%s %s %d:%d\", sa, sb, &na, &nb);\n        ia = hash(sa);\n        ib = hash(sb);\n        strcpy(team[ia].name, sa);\n        strcpy(team[ib].name, sb);\n        ++cnt[ia];\n        ++cnt[ib];\n        /*printf(\"%d %d %d %d\\n\", na, nb, ia, ib);*/\n        if (nb > na) {\n            swap(&na, &nb);\n            swap(&ia, &ib);\n        }\n        /*printf(\"%d %d\\n\", na, nb);*/\n        if (na > nb) {\n            team[ia].point += 3;\n        } else if (na == nb) {\n            team[ia].point += 1;\n            team[ib].point += 1;\n        }\n        team[ia].score += na;\n        team[ia].miss += nb;\n        team[ib].score += nb;\n        team[ib].miss += na;\n    }\n    /*for (i = 0; i < 4; ++i) {*/\n        /*printf(\"%d %d %d\\n\", team[i].point, team[i].score, team[i].miss);*/\n    /*}*/\n    /*return 0;*/\n\n    cpy_team();\n    qsort(tmp_team, 4, sizeof(struct Team), comp);\n    /*for (i = 0; i < 4; ++i) {*/\n        /*printf(\"%c\\n\", tmp_team[i].name);*/\n    /*}*/\n    for (i = 0; i < 4; ++i) {\n        if (!strcmp(tmp_team[i].name, \"BERLAND\")) {\n            b_id = i;\n        } else if (cnt[i] != 3) {\n            opp_id = i;\n        }\n    }\n    /*printf(\"opp_id = %d, b_id = %d\\n\", opp_id, b_id);*/\n    /*for (i = 0; i < hash_idx; ++i) {*/\n        /*printf(\"%s\\n\", hash_s[i]);*/\n    /*}*/\n    for (i = 1; i < 100; ++i) {\n        cpy_team();\n        tmp_team[b_id].point += 3;\n        tmp_team[b_id].score += i;\n        tmp_team[opp_id].miss += i;\n        /*for (j = 0; j < 4; ++j) {*/\n            /*printf(\"%d %d %d\\n\", tmp_team[j].point, tmp_team[j].score, tmp_team[j].miss);*/\n        /*}*/\n        /*putchar('\\n');*/\n        qsort(tmp_team, 4, sizeof(struct Team), comp);\n        if (!strcmp(tmp_team[0].name, \"BERLAND\") || !strcmp(tmp_team[1].name, \"BERLAND\")) {\n            printf(\"%d:0\\n\", i);\n            return 0;\n        }\n    }\n    puts(\"IMPOSSIBLE\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "24ad406229db41baa52342ded1aa1c7c", "src_uid": "5033d51c67b7ae0b1a2d9fd292fdced1", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nchar ss[4][32];\n\nint get(char *s) {\n\tstatic int n;\n\tint i;\n\n\tfor (i = 0; i < n; i++)\n\t\tif (strcmp(ss[i], s) == 0)\n\t\t\treturn i;\n\tstrcpy(ss[n], s);\n\treturn n++;\n}\n\nint g1[4], g0[4], pp[4], dd[4];\n\nint compare(const void *a, const void *b) {\n\tint i = *(int *) a;\n\tint j = *(int *) b;\n\tint gi, gj;\n\n\tif (pp[i] != pp[j])\n\t\treturn pp[j] - pp[i];\n\tgi = g1[i] - g0[i];\n\tgj = g1[j] - g0[j];\n\tif (gi != gj)\n\t\treturn gj - gi;\n\tif (g1[i] != g1[j])\n\t\treturn g1[j] - g1[i];\n\treturn strcmp(ss[i], ss[j]);\n}\n\nint main() {\n\tstatic char s[32], t[32], z[8];\n\tstatic int ii[4];\n\tint h, i, j, x, y, r;\n\n\tfor (h = 0; h < 5; h++) {\n\t\tscanf(\"%s%s%s\", s, t, z);\n\t\ti = get(s), j = get(t);\n\t\tx = z[0] - '0';\n\t\ty = z[2] - '0';\n\t\tg1[i] += x, g0[j] += x;\n\t\tg0[i] += y, g1[j] += y;\n\t\tif (x > y)\n\t\t\tpp[i] += 3;\n\t\telse if (x < y)\n\t\t\tpp[j] += 3;\n\t\telse {\n\t\t\tpp[i]++;\n\t\t\tpp[j]++;\n\t\t}\n\t\tdd[i]++;\n\t\tdd[j]++;\n\t}\n\tfor (i = 0; i < 4; i++)\n\t\tii[i] = i;\n\ti = 0;\n\twhile (strcmp(ss[i], \"BERLAND\"))\n\t\ti++;\n\tj = 0;\n\twhile (j == i || dd[j] != 2)\n\t\tj++;\n\tfor (x = 0, y = 0; x < 30; x++) {\n\t\tg1[i] += x, g0[j] += x;\n\t\tg0[i] += y, g1[j] += y;\n\t\tif (x > y)\n\t\t\tpp[i] += 3;\n\t\telse if (x < y)\n\t\t\tpp[j] += 3;\n\t\telse {\n\t\t\tpp[i]++;\n\t\t\tpp[j]++;\n\t\t}\n\t\tqsort(ii, 4, sizeof *ii, compare);\n\t\tr = 0;\n\t\twhile (ii[r] != i)\n\t\t\tr++;\n\t\tif (r < 2) {\n\t\t\tprintf(\"%d:0\\n\", x);\n\t\t\treturn 0;\n\t\t}\n\t\tg1[i] -= x, g0[j] -= x;\n\t\tg0[i] -= y, g1[j] -= y;\n\t\tif (x > y)\n\t\t\tpp[i] -= 3;\n\t\telse if (x < y)\n\t\t\tpp[j] -= 3;\n\t\telse {\n\t\t\tpp[i]--;\n\t\t\tpp[j]--;\n\t\t}\n\t}\n\tprintf(\"IMPOSSIBLE\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e96305d0fb5be1fdedeef8e1cbd34718", "src_uid": "5033d51c67b7ae0b1a2d9fd292fdced1", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main()\n{\n    char str[101];\n    scanf(\"%s\", str);\n\n    if(strlen(str) >= 5)\n        count++;\n\n    for(i=0; i<strlen(str); i++){\n        if(str[i] >= 'A' && str[i] <= 'Z'){\n            count++;\n            break;\n        }\n    }\n\n    for(i=0; i<strlen(str); i++){\n        if(str[i] >= 'a' && str[i] <= 'z'){\n            count++;\n            break;\n        }\n    }\n\n    for(i=0; i<strlen(str); i++){\n        if(str[i] >= '1' && str[i] <= '9'){\n            count++;\n            break;\n        }\n    }\n\n    if(count == 4)\n        printf(\"Correct\");\n    else\n        printf(\"Too weak\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "cdf80884bf676c6a5fc66eb204056988", "src_uid": "42a964b01e269491975965860ec92be7", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include<string.h>\n\nint main(){\n\tchar s[101];\n\tint i,flag,l,f,g,h,k;\n\tscanf(\"%s\",s);\n\tl=strlen(s);\n\tf=0;\n\tg=0;\n\th=0;\n\tk=0;\n\tflag=0;\n\tif(l<5){\n\t\tprintf(\"Too weak\\n\");\n\t}\n\telse{\n\t\tfor(i=0;i<l;i++){\n\t\t\tif(s[i]>=65 && s[i]<=90){\n\t\t\t\tf=1;\n\t\t\t}\n\t\t\tif(s[i]>=97 && s[i]<=122){\n\t\t\t\tg=1;\n\t\t\t}\n\t\t\tif(s[i]=='!' || s[i]=='?' || s[i]=='.' || s[i]==',' || s[i]=='_'){\n\t\t\t\th=1;\n\t\t\t}\n\t\t\tif(s[i]>=48 && s[i]<=57){\n\t\t\t\tk=1\n\t\t\t}\n\t\t\tif(f==1 && g==1 && h==1 && k==1){\n\t\t\t\tflag=1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(flag){\n\t\t\tprintf(\"Correct\\n\");\n\t\t}\n\t\telse printf(\"Too weak\\n\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4e5e5ff8f7ab1bdbcb5173126f1fff5f", "src_uid": "42a964b01e269491975965860ec92be7", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(){\nlong len,k1=0,k2=0,k3=0,k4=0,i;\nchar s[101];\nscanf(\"%s\",&s);\nlen=strlen(s);\n\nif(len>=5)k1=1;\n\nfor(i=0;i<len;i++)\nif('a'<=s[i]&&'z'>=s[i])\nk2++;\n\nfor(i=0;i<len;i++)\nif('A'<=s[i]&&'Z'>=s[i])\nk3++;\n\nfor(i=0;i<len;i++)\nif('0'< =s[i]&&'9'>=s[i]);\nk4++;\n\nif(k1&&k2&&k3&&k4)\nprintf(\"Correct\");\n\nelse\n\nprintf(\"Too weak\");\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dc5c990d04b0381819340ecd1e91946f", "src_uid": "42a964b01e269491975965860ec92be7", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    char arr[1000];\n    scanf(\"%s\",arr);\n    int i,j,f1=0,f2=1,f3=0;\n    for(i=0;arr[i]!='\\0';i++)\n    {\n        if(arr[i]=='0'|| arr[i]=='1'|| arr[i]=='2'|| arr[i]=='3'|| arr[i]=='4'|| arr[i]=='5'||arr[i]=='6'||arr[i]=='7'||arr[i]=='8'||arr[i]=='9' )\n        {\n            f1=1;\n        }\n        if(arr[i]>=65 && arr[i]<=90)\n        {\n            f2=1;\n        }\n        if(arr[i]>=97 && arr[i]<=122)\n        {\n            f3=1;\n        }\n    }\n    if(f1==1 && f2==1 && f3==1)\n    {\n        printf(\"Correct\");\n    }\n    else\n    {\n        printf(\"Too weak\");\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "706fa25d35337d54899f347666769d9c", "src_uid": "42a964b01e269491975965860ec92be7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int Up=0,Low=0,Num=0,i,a=0;\n    char str[1000];\n    gets(str);\n    a=strlen(str);\n    for(i=0;i<a;i++){\n        if(str[i]>47&&str[i]<58)\n            Num++;\n        if(str[i]>64&&str[i]<91)\n            Up++;\n        if(str[i]>96&&str[i]<123)\n            Low++;\n    }\n    if(Num>0 && Up>0 && Low>0 && a>=5)\n        printf(\"Correct\\n\");\n    else\n        printf(\"Too weak\\n\");a\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "75a8f268162e2f50c78673088ba0bbda", "src_uid": "42a964b01e269491975965860ec92be7", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n    int x[10],y[10],cnt=0,i,j,a,b;\n    for(i=1;i<=8;i++){\n    scanf(\"%d%d\",&x[i],&y[i]);\n    }\n    for(i=1;i<=8;i++){\n        for(j=1;j<=8;j++){\n            if(x[i]>=x[j]){\n                a=x[i];\n                b=y[i];\n                x[i]=x[j];\n                y[i]=y[j];\n                x[j]=a;\n                y[j]=b;\n            }\n        }\n    }\n    for(i=1;i<=8;i++){\n        for(j=i+1;j<=8;j++){\n            if(x[i]==x[j]&&y[i]==y[j]){\n                printf(\"ugly\\n\");\n                return 0;\n            }\n        }\n    }\n    for(i=1;i<=4;i++){\n        if(x[1]==x[i]){cnt++;}\n    }\n    if(cnt!=3){printf(\"ugly\\n\");return 0;}\n    cnt=0;\n    for(i=4;i<=6;i++){\n        if(x[4]==x[i]){cnt++;}\n    }\n    if(cnt!=2){printf(\"ugly\\n\");return 0;}\n    cnt=0;\n    for(i=6;i<=8;i++){\n        if(x[6]==x[i]){cnt++;}\n    }\n    if(cnt!=3){printf(\"ugly\\n\");return 0;}\n    for(i=1;i<=3;i++){\n        for(j=i+1;j<=3;j++){\n            if(y[i]>y[j]){\n                a=y[i];\n                y[i]=y[j];\n                y[j]=a;\n            }\n        }\n    }\n    for(i=4;i<=5;i++){\n        for(j=i+1;j<=5;j++){\n            if(y[i]>y[j]){\n                a=y[i];\n                y[i]=y[j];\n                y[j]=a;\n            }\n        }\n    }\n    for(i=6;i<=8;i++){\n        for(j=i+1;j<=8;j++){\n            if(y[i]>y[j]){\n                a=y[i];\n                y[i]=y[j];\n                y[j]=a;\n            }\n        }\n    }\n    if(y[1]!=y[4]||y[1]!=y[6]){\n        printf(\"ugly\\n\");\n        return 0;\n    }\n    if(y[2]!=y[7]){\n        printf(\"ugly\\n\");\n        return 0;\n    }\n    if(y[3]!=y[5]||y[3]!=y[8]){\n        printf(\"ugly\\n\");\n        return 0;\n    }\n    printf(\"respectable\\n\");\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "16b25d81fac1c7883051d5dcfaf94f88", "src_uid": "f3c96123334534056f26b96f90886807", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint compare(const void *a,const void *b)\n{\n    return (*(int *)a-*(int *)b);\n}\nint main()\n{\n    int x[8],y[8],i,j,arr[8][8];\n    for(i=0;i<8;i++)\n    {\n        scanf(\"%d %d\",&x[i],&y[i]);\n        scanf(\"%d %d\",&arr[i][0],&arr[i][1]);\n    }\n    qsort(x,8,sizeof(int),compare);\n    qsort(y,8,sizeof(int),compare);\n    for(i=0;i<8;i++)\n    {\n        for(j=0;j<8;j++)\n            if(arr[i][i]==arr[j][j])\n            {\n                return \"ugly\";\n            }\n    }\n    if(x[1]==x[0]&&x[2]==x[1]&&x[4]==x[3]&&x[7]==x[6]&&x[5]==x[7]&&x[3]>x[0]&&x[6]>x[3]&&y[3]>y[2]&&y[5]>y[4]&&y[4]==y[3]&&y[0]==y[1]&&y[1]==y[2]&&y[6]==y[7]&&y[5]==y[6]&&y[3]!=y[1])\n        printf(\"respectable\");\n    else\n        printf(\"ugly\");\n    //printf(\"Hello world!\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "84dba7aea9fba5e2dc7a1f23f78f444b", "src_uid": "f3c96123334534056f26b96f90886807", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <stdbool.h>\n\ntypedef struct _P {\n    unsigned x;\n    unsigned y;\n} Point;\n\nint comparePoint(const void *_a, const void *_b) {\n    Point *a = (Point*)_a;\n    Point *b = (Point*)_b;\n    return a->x - b->x ? a->x - b->x : a->y - b->y;\n}\n\nbool parallelLine(Point pAA, Point pAB, Point pAC,\n        Point pBA, Point pBB, Point pBC) {\n    if(pAA.x == pAB.x && pAA.x == pAC.x)\n        if(pBA.x == pBB.x && pBA.x == pBC.x)\n            if(pAA.y == pBA.y && pAB.y == pBB.y && pAC.y == pBC.y)\n                if(pAA.y != pAB.y && pAA.y != pAC.y)\n                   return true;\n    if(pAA.y == pAB.y && pAA.y == pAC.y)\n        if(pBA.y == pBB.y && pBA.y == pBC.y)\n            if(pAA.x == pBA.x && pAB.x == pBB.x && pAC.x == pBC.x)\n                if(pAA.x != pAB.x && pAA.x != pAC.x)\n                     return true;\n    return false;\n}\n\nconst char* answers[2] = {\"respectable\\n\", \"ugly\\n\"};\n\nint main() {\n    short i;\n    \n    Point ps[8];\n    for(i = 0; i < 8; i++)\n        scanf(\"%u%u\", &ps[i].x, &ps[i].y);\n    \n    qsort(ps, 8u, sizeof(Point), comparePoint);\n    \n    if(parallelLine(ps[0], ps[1], ps[2], ps[5], ps[6], ps[7]) &&\n            parallelLine(ps[0], ps[3], ps[5], ps[2], ps[4], ps[7]))\n        printf(answers[0]);\n    else\n        printf(answers[1]);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0b8eff551ece66fb53ba09e9fd5ec3ff", "src_uid": "f3c96123334534056f26b96f90886807", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int a[3]={-1,-1,-1};\n    int b[3]={-1,-1,-1};\n    int ca=0,cb=0,ia,ib,i;\n    for(i=0;i<8;i++)\n    {\n        scanf(\"%d %d\",&ia,&ib);\n        if(ia!=a[0] && ia!=a[1] && ia!=a[2])\n        {\n            a[ca]=ia;\n            ca++;\n        }\n        if(ib!=b[0] && ib!=b[1] && ib!=b[2])\n        {\n            b[cb]=ib;\n            cb++;\n        }\n        if(ia==a[1] && ib==b[1])\n        {\n            printf(\"ugly\");\n            return 0;\n        }\n    }\n    if(ca==3 && cb==3)\n    {\n        printf(\"respectable\");\n        return 0;\n    }\n    else\n    printf(\"ugly\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1697cb56442e3eccfb7599e3ef1b1732", "src_uid": "f3c96123334534056f26b96f90886807", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n#include<algorithm>\n#include<cstdio>\n#include<cmath>\n#include<cstring>\n#include<cstdlib>\nusing namespace std;\n\nint compare(const void *a,const void *b)\n{\n    return (*(int *)a-*(int *)b);\n}\nint main()\n{\n    int x[8],y[8],i,j;\n    for(i=0;i<8;i++)\n    {\n        scanf(\"%d %d\",&x[i],&y[i]);\n    }\n    for(i=0;i<8;i++)\n    {\n        for(j=i+1;j<8;j++)\n        {   \n\t\t\tif(x[i]==x[j]&&y[i]==y[j])\n            {\n                printf(\"ugly\");\n                return 0;\n            }\n            else\n            {\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n    }\n    qsort(x,8,sizeof(int),compare);\n    qsort(y,8,sizeof(int),compare);\n\n    if(x[1]==x[0]&&x[2]==x[1]&&x[4]==x[3]&&x[7]==x[6]&&x[5]==x[7]&&x[3]>x[0]&&x[6]>x[3]&&y[3]>y[2]&&y[5]>y[4]&&y[4]==y[3]&&y[0]==y[1]&&y[1]==y[2]&&y[6]==y[7]&&y[5]==y[6]&&y[3]!=y[1])\n    {\n\t\tprintf(\"respectable\\n\");\n\t}\n\telse\n\t{\n        printf(\"ugly\\n\");\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b4f4c6be1f3f10df1672c51560fed8b2", "src_uid": "f3c96123334534056f26b96f90886807", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define min(a,b) (a<b?a:b)\n\nint N,val[50005],day=1,mx=1e9+1,id;\n\nint main()\n{\n\tscanf(\"%d\",&N);\n\tif(N%7==0)\n\t{\n\t\tfor(int i=1,u;i<=N;i++)\n\t\t{\n\t\t\tscanf(\"%d\",&u);\n\t\t\tif(i%7&&u<mx)mx=u,id=i;\n\t\t}\n\t\treturn printf(\"%d\",id),0;\n\t}\n\tfor(int i=1,u;i<=N;i++)scanf(\"%d\",val+i),mx=min(mx,val[i]/6);\n\tfor(int i=1;i<=N;i++)val[i]-=mx*6;\n\twhile(1)\n\t{\n\t\tfor(int i=1;i<=N;i++,day++)\n\t\t\tif(day==7)day=0;\n\t\t\telse if(!--val[i])return printf(\"%d\",i),0;\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4afe76e39ac892f4654019bc3b57d90c", "src_uid": "8054dc5dd09d600d7fb8d9f5db4dcaca", "difficulty": 2700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint a[50001];\nint main(){\n\tint n, i, j, ind_min=0;\n\tscanf (\"%d\", &n);\n\tfor (i=0;i<n;i++) scanf (\"%d\", &a[i]);\n\n\tif (n%7==0){\n\t\tfor(i=0;i<n;i++){\n\t\t\tif (i%7==0) continue;\n\t\t\tif (a[i]<a[ind_min]) ind_min=i;\n\t\t}\n\t}\n\telse{\n\t\tfor (i=0;i<n;i++) a[i]=a[i]%6+6;\n\n\t\tj=1;\n\t\twhile(1){\n\t\t\tfor (i=0;i<n;i++,j++){\n\t\t\t\tif (j%7==0) continue;\n\t\t\t       \ta[i]--;\t\n\t\t\t\tif (a[i]==0) goto end;\n\t\t\t}\n\t\t}\nend:\n\t\tind_min=i;\n\t}\n\n\tprintf (\"%d\\n\", ind_min+1);\nreturn 0;}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7d69ed8df13a98827c67a7781c27208e", "src_uid": "8054dc5dd09d600d7fb8d9f5db4dcaca", "difficulty": 2700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint a[50001];\nint main(){\n\tint n, i, j, ind_min=0;\n\tscanf (\"%d\", &n);\n\tfor (i=0;i<n;i++) scanf (\"%d\", &a[i]);\n\n\n\tif (n%7==0){\n\t\tfor(i=0;i<n;i++){\n\t\t\tif (i%7==6) continue;\n\t\t\tif (a[i]<a[ind_min]) ind_min=i;\n\t\t}\n\t}\n\telse{\n\t\tfor(i=0;i<n;i++) {\n\t\t\tif (a[i]<a[ind_min]) ind_min=i;\n\t\t}\n\t\tfor (i=0;i<n;i++) a[i]=a[i]%7+7;\n\t\tfor (i=0;i<n;i++){\n\t\t\tif (a[i]!=a[ind_min]) a[i]+=1000;\n\t\t}\n\n\t\tj=1;\n\t\twhile(1){\n\t\t\tfor (i=0;i<n;i++,j++){\n\t\t\t\tif (j%7==0) continue;\n\t\t\t\ta[i]--;\t\n\t\t\t\tif (a[i]==0) goto end;\n\t\t\t}\n\t\t}\n\tend:\n\t\tind_min=i;\n\t}\n\n\tprintf (\"%d\\n\", ind_min+1);\nreturn 0;}", "lang_cluster": "C", "compilation_error": false, "code_uid": "34bc22df6689d5be43aa92b6dcf3caf8", "src_uid": "8054dc5dd09d600d7fb8d9f5db4dcaca", "difficulty": 2700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define min(a,b) (a<b?a:b)\n\nint N,val[50005],day=1,mx=1e9+1,id;\n\nint main()\n{\n\tscanf(\"%d\",&N);\n\tif(N%7==0)\n\t{\n\t\tfor(int i=1,u;i<=N;i++)\n\t\t{\n\t\t\tscanf(\"%d\",&u);\n\t\t\tif(i%7&&u<mx)u=mx,id=i;\n\t\t}\n\t\treturn printf(\"%d\",id),0;\n\t}\n\tfor(int i=1,u;i<=N;i++)scanf(\"%d\",val+i),mx=min(mx,val[i]/6);\n\tfor(int i=1;i<=N;i++)val[i]-=mx*6;\n\twhile(1)\n\t{\n\t\tfor(int i=1;i<=N;i++,day++)\n\t\t\tif(day==7)day=0;\n\t\t\telse if(!--val[i])return printf(\"%d\",i),0;\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "931e17ac1944f14e6538d8b3bd6af8b7", "src_uid": "8054dc5dd09d600d7fb8d9f5db4dcaca", "difficulty": 2700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint a[50001];\nint main(){\n\tint n, i, j, ind_min=0;\n\tscanf (\"%d\", &n);\n\tfor (i=0;i<n;i++) scanf (\"%d\", &a[i]);\n\n\tif (n%7==0){\n\t\tfor(i=0;i<n;i++){\n\t\t\tif (i%7==6) continue;\n\t\t\tif (a[i]<a[ind_min]) ind_min=i;\n\t\t}\n\t}\n\telse{\n\t\tfor (i=0;i<n;i++) a[i]=a[i]%6+6;\n\n\t\tj=1;\n\t\twhile(1){\n\t\t\tfor (i=0;i<n;i++,j++){\n\t\t\t\tif (j%7==0) continue;\n\t\t\t       \ta[i]--;\t\n\t\t\t\tif (a[i]==0) goto end;\n\t\t\t}\n\t\t}\nend:\n\t\tind_min=i;\n\t}\n\n\tprintf (\"%d\\n\", ind_min+1);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6cc736921cc754634db0edc999cc128e", "src_uid": "8054dc5dd09d600d7fb8d9f5db4dcaca", "difficulty": 2700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(void)\n{\n\n    int n,zcount=0,onecount=0,i;\n    scanf(\"%d\",&n);\n    char str[100];\n    scanf(\"%s\",str);\n    for(i=0;i<n;i++){\n        if(str[i]=='1'&&i<(strlen(str)-1)){onecount++;zcount=0;}\n        else if(str[i]=='1'&&i==(strlen(str)-1)){onecount++;printf(\"%d\",onecount);}\n        else if(onecount){printf(\"%d\",onecount);onecount=0;}\n        if(str[i]=='0')zcount++;\n        if(zcount==2){printf(\"0\");zcount=0;}\n        if(str(strlen(str)-1)=='0')printf(\"0\");\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e6b9dbf59a2fd5ffcf4bb897f5b96c09", "src_uid": "a4b3da4cb9b6a7ed0a33a862e940cafa", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "\t int n,i,digit = 0;\n\t char s[90];\n\t   unsigned long num = 0;\n\t   scanf(\"%u\",&n);\n\t   scanf(\"%s\",s);\n\t   i = 0;\n\t   while(s[i] != '\\0'){\n\n\t       if(s[i]== '1'){\n\t           digit++;\n\t       }else{\n\t    \t   num = (num*10)+digit;\n\t    \t   digit = 0;\n\t       }\n\t     i++;\n\t   }\n\t   num = (num*10)+digit;\n\n\t   printf(\"%lu\",num);", "lang_cluster": "C", "compilation_error": true, "code_uid": "3e7b3b836ff059ea3133e89c29133748", "src_uid": "a4b3da4cb9b6a7ed0a33a862e940cafa", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nchar x[89];\n\nint main()\n{\n    int i,n,c=0;\n    scanf(\"%d %s\",&n,x);\n    for (i=0; i<=n; i++)\n    {\n        if (str[i] == '1') c++;\n        else\n        {\n            printf(\"%d\",c);\n            c = 0;\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "289bb2c2bf9877774fe654cb100ecd7b", "src_uid": "a4b3da4cb9b6a7ed0a33a862e940cafa", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int strLen;\n    scanf(\"%d\",&strLen);\n    char str [1000];\n    scanf(\"%s\",str);\n    //aprintf(\"%s\\n\",str);\n    int i, cnt=0;\n    for (i=0; i<strLen; i++) {\n        if (str[i] == '1') {\n            cnt++\n        } else {\n            printf(\"%d\",cnt);\n            cnt=0;\n        }\n    }\n    printf(\"%d\",cnt);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "df6791c11dd6d5256fab00499f279204", "src_uid": "a4b3da4cb9b6a7ed0a33a862e940cafa", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nchar a[1000000005];\n\nint main()\n{\n    long long int n, x, k, i, j, r, ans=0;\n    scanf(\"%I64d\\n\", &n);\n    gets(a);\n    //puts(a);\n    for(i=0; i<n; i++)\n    {\n        if(a[i]==49){ans++;}\n        else{ans*=10;}\n        //printf(\"%I64d\\n\", ans);\n    }\n    printf(\"%I64d\", ans);\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f3386d44b12c02d38c4a7434efcc9477", "src_uid": "a4b3da4cb9b6a7ed0a33a862e940cafa", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\tint main()\n\t{\n\t\tint a, i = 0;\n\t\tscanf(\"%d\", &a);\n\t\tchar s[a];\n\t\tscanf(\"%s\", s);\n\t\tif (s[0] == '1')\n\t\t\tprintf(\"1\");\n\t\tfor (i = 0; i<a; i++)\n\t\t{\n\t\t\tif (s[i] == '0')\n\t\t\t\tprintf(\"0\");\n\t\t}\n\n\t}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "48a4b8ad7a00896a8ff16c8ed9ed83a3", "src_uid": "ac244791f8b648d672ed3de32ce0074d", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nusing namespace std;\n\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    char s[110];\n    scanf(\"%s\",&s);\n    int ans1=0,ans0=0;\n    for(int i=0;i<n;i++)\n    {\n        if(s[i]=='0')\n        {\n            ans0++;\n        }\n        else\n        {\n            ans1++;\n        }\n    }\n    if(ans1)\n    {\n        printf(\"1\");\n    }\n    for(int i=0;i<ans0;i++)\n    {\n        printf(\"0\");\n    }\n    printf(\"\\n\");\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b5b8a3ac097afe15f14886d6cca3b7e6", "src_uid": "ac244791f8b648d672ed3de32ce0074d", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "\n#include <stdio.h>\n\nvoid main()\n{\n    int n,i,m=0;\n    char s[105];\n    scanf(\"%d\",&n);\n    scanf(\" %s\",s);\n    if(n==1&&s[0]==0)\n    printf(\"0\");\n    else\n    {\n    for(i=0;i<n;i++)\n        if(s[i]=='0')\n        m++;\n    printf(\"1\");\n    for(i=0;i<m;i++)\n    printf(\"0\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f4b2f457b23954ffe0980f8e1af56b0d", "src_uid": "ac244791f8b648d672ed3de32ce0074d", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "\n\n#include <stdio.h>\n\nvoid main()\n{\n    int n,i,m=0;\n    char s[105];\n    scanf(\"%d\",&n);\n    scanf(\" %s\",s);\n    if(n==1&&s[0]=0)\n    printf(\"0\");\n    else\n    {\n    for(i=0;i<n;i++)\n        if(s[i]=='0')\n        m++;\n    printf(\"1\");\n    for(i=0;i<m;i++)\n    printf(\"0\");\n}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "34764eba17cffaf3bf94574d6787ce88", "src_uid": "ac244791f8b648d672ed3de32ce0074d", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<cstring>\n#include<cmath>\nusing namespace std;\nint main()\n{\n\tint t,n,m,i,num,j,sum;\n\tchar a[150];\n\tmemset(a, 0 ,sizeof(a));\n\tscanf(\"%d\", &t);\n\tscanf(\"%s\", a);\n\tint k = strlen(a);\n\tsum = 0;\n\tfor(i=0; i<k; i++)\n\t{\n\t\tif(a[i] == '0')\n\t\t{\n\t\t\tsum ++;\n\t\t}\n\t} \n\tprintf(\"1\");\n\tfor(i=0; i<sum; i++)\n\t{\n\t\tprintf(\"0\");\n\t}\n\tprintf(\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a559c683112c23aa247fa56e60b77025", "src_uid": "ac244791f8b648d672ed3de32ce0074d", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nmain(){\n    int i, n, m, hg= 0, sum= 0;\n    scanf(\"%i %i\", &n, &m);\n    int a[n];\n    for(i=0; i<n; ++i){\n        scanf(\"%i\", &a[i]);\n        if(a[i]>hg) hg = a[i];\n        sum += a[i];\n    }\n    printf(\"%i %i\\n\", ((sum+m)%n) ? ((sum+m)/n)+1 : (sum+m)/n, hg+m);", "lang_cluster": "C", "compilation_error": true, "code_uid": "2a04f8c3faa5c32d4b18a352d31c5a2e", "src_uid": "78f696bd954c9f0f9bb502e515d85a8d", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main(){\n    int benches,initial,late;\n    int people[101]={0};\n    \n    scanf(\"%d\", &benches);\n    scanf(\"%d\", &initial);\n    scanf(\"%d\", &late);\n    \n    int late_cpy=late;\n    \n    int people_cpy[101]={0};\n    \n    for(int i=0;i<=benches;++i)\n    {\n        scanf(\"%d\", &people[i]);\n        people_cpy[i]=people[i];\n    }\n    \n    int max=0;\n    for(int i=0;i<=benches;++i)\n    {\n        if(people[i]>=max){\n            max=people[i];\n        }\n    }\n    for(int i=0;i<=benches;++i)\n    {\n        if(late_cpy<=0){\n            break;\n        }\n        while(benches[i]!=max){\n            if(late_cpy<=0){\n                break;\n            }\n            ++benches[i];\n            --late_cpy;\n        }\n    }\n    int min=10000;\n    for(int i=0;i<=benches;++i)\n    {\n        if(benches[i]<=min){\n            min=benches[i];\n        }\n    }\n    \n    for(int i=0;i<=benches;++i)\n    {\n        if(benches[i]==max){\n            max = benches[i]+late;\n            break;\n        }\n    }\n    printf(\"%d %d\", min,max );\n    \n    \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "64efd6671edf2ff91b51ad0a080b1b78", "src_uid": "78f696bd954c9f0f9bb502e515d85a8d", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <cstdio>\n\n\n\nclass CycledDynamicArray {\npublic:\n    CycledDynamicArray(unsigned int initCapacity);\n    ~CycledDynamicArray();\n\n    void PushBack(int element);\n    void PopBack();\n    int Back() const;\n    bool IsEmpty() const;\n\nprivate:\n    unsigned int capacity;\n    unsigned int siz;\n    int start;\n    int* data;\n\n\n    unsigned int CalcModPos(unsigned int pos);\n    void Rotate(unsigned int newCapasity);\n    void Extend();\n    void Shrink();\n};\nCycledDynamicArray::~CycledDynamicArray(){\n\n}\n\n\n\nint main(){\n    CycledDynamicArray arr(8);\n    arr.PushBack(5);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "836f5460c603e7ef1d43ffd90b4c5376", "src_uid": "78f696bd954c9f0f9bb502e515d85a8d", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n#include<cmath>\n#include<algorithm>\nusing namespace std;\n\nint main()\n{\n    int  N,k,M,i,max=0;\n\tcin>>N>>M;\n\tint  a[N];\n\tfor(i=0;i<N;i++)\n\t{\n\t    cin>>a[i];\n\t    if(a[i]>max)\n\t    max=a[i];\n\t}\n\tsort(a,a+N);\n\tfor(i=0;i<N;i++)\n\t{\n\t    M=M-(max-a[i]);\n\t}\n\tk=M/N;\n\tif(k*N==M)\n\tcout<<a[N-1]+k<<\" \";\n\telse\n\tcout<<a[N-1]+k+1<<\" \";\n\t\n\tcout<<a[N-1]+M<<endl;\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3419d10c59ccd204bec006a9923aca4e", "src_uid": "78f696bd954c9f0f9bb502e515d85a8d", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint searchMin(int capacity, int m, int n, int maxElement) {\n\tint kMin = 0;\n\tif (capacity >= m) kMin = maxElement;\n\telse if ((m - capacity) % n == 0) {\n\t\tkMin = maxElement + (m - capacity) / n;\n\t}\n\telse if ((m - capacity) % n != 0) {\n\t\tkMin = maxElement + 1 + (m - capacity) / n;\n\t}\n\treturn kMin;\n}\n\nint main() {\n\tint n, m, maxElement, capacity, kMin, kMax;\n\tscanf(\"%d\\n %d\\n\", &n);\n\tint* a = (int*)malloc(n * sizeof(int));\n\tmaxElement = 0;\n\tfor (int i = 0; i < n; ++i) {\n\t\tscanf(\"%d\\n\", &a[i]);\n\t\tif (a[i] > maxElement) maxElement = a[i];\n\t}\n\tkMax = maxElement + m;\n\tfor (int i = 0; i < n; ++i) {\n\t\tcapacity += (maxElement - a[i]);\n\t}\n\tkMin = searchMin(capacity, m, n, maxElement);\n\tprintf(\"%d %d\", kMIn, kMax);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1dbdb4730f066efea5573a7b68cd3cce", "src_uid": "78f696bd954c9f0f9bb502e515d85a8d", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint gcd (int a, int b) {\n\treturn b ? gcd (b, a % b) : a;\n}\n\nint main() {\n\tlong long a, b, x, y, l = 0, r = (long long)2e9, d;\n\tscanf(\"%I64d%I64d%I64d%I64d\", &a, &b, &x, &y);\n\td = gcd(x, y);\n\tx /= d; y /= d;\n\tprintf(\"%I64d %I64d\", x * min(a / x, b / y), y * min(a / x, b / y));\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6e21345e27a7ad40ba92d7989ed4d8b2", "src_uid": "97999cd7c6de79a4e39f56a41ff59e7a", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long int lcm(long long int x,long long int y)\n{\n    long long int n1,n2;\n    n1=x;n2=y;\n    while(n1!=n2)\n    {\n        if(n1>n2)\n        n1=n1-n2;\n        else\n        n2=n2-n1;\n    }\n    return(x*y/n1);\n}\nint main()\n{long long int i,j,t,r,k,a1,x,y,a,b;\nscanf(\"%I64d%I64d%I64d%I64d\",&a,&b,&x,&y);\nif(b>=(y*a)/x)\n{if((a*y)%x==0)\nprintf(\"%I64d %I64d\",a,y*a/x);\nelse\n{t=lcm(x,y);\nk=t/y;\na=(a/k)*k;\n    printf(\"%I64d %I64d\",a,y*a/x);\n}\n}\nelse\n{\n    if((b*x)%y==0)\n    {a=x*b/y;\n    printf(\"%I64d %I64d\",a,b);}\n    else\n    {t=lcm(x,y);\nk=t/x;\nb=(b/k)*k;\n    printf(\"%I64d %I64d\",(b*x)/y,b);\n\n    }\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4982a6bb494790f23d401657fabbdd2b", "src_uid": "97999cd7c6de79a4e39f56a41ff59e7a", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint gcd(int a, int b) {\n\treturn b == 0 ? a : gcd(b, a % b);\n}\n\nint binsearch(int a, int x) {\n\tint low, high, mid;\n\n\tlow = 1;\n\thigh = a / x;\n\n\twhile (low <= high) {\n\t\tmid = (low + high) / 2;\n\t\tif (mid * x < a)\n\t\t\tlow = mid + 1;\n\t\telse if (mid * x > a)\n\t\t\thigh = mid - 1;\n\t\telse\n\t\t\treturn mid;\n\t}\n\treturn -1;\n}\n\nint main() {\n\tint a, b, x, y, g;\n\tlong long i, j, k, n, m;\n\n\tscanf(\"%d%d%d%d\", &a, &b, &x, &y);\n\tg = gcd(x, y);\n\tx /= g, y /= g;\n\ti = binsearch(a, x);\n\tj = binsearch(b, y);\n\tk = a / x < b / y ? a / x : b / y;\n\tn = i * x, m = i * y;\n\tif (n * m < j * x * j * y) {\n\t\tn = j * x;\n\t\tm = j * y;\n\t}\n\tif (n * m < k * x * k * y) {\n\t\tn = k * x;\n\t\tm = k * y;\n\t}\n\tif (n < 0)\n\t\tn = -n;\n\tif (m < 0)\n\t\tm = -m;\n\tif (a < x || b < y)\n\t\tprintf(\"0 0\\n\");\n\telse\n\t\tprintf(\"%lld %lld\\n\", n, m);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "84b67c5e98f4aada9adb685481dc0fc2", "src_uid": "97999cd7c6de79a4e39f56a41ff59e7a", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n__int64 gcd(__int64 a,__int64 b)\n{\n    if(b==0)\n        return(a);\n    else return(gcd(b,a%b));\n}\nint main()\n{\n    __int64  a,b,x,y,i,j,p,d,low,high,mid,c=0,ma=0,ra,rb;\n    scanf(\"%I64d%I64d%I64d%I64d\",&a,&b,&x,&y);\n    d=gcd(x,y);\n    x=x/d;\n    y=y/d;\n    for(i=0;i<a;i++)\n    {\n        d=y*(a-i);\n        low=0;\n        high=b-1;\n        while(low<=high)\n        {\n            mid=(low+high)/2;\n            p=x*(b-mid);\n            if(p<d)\n                high=mid-1;\n            else if(p>d)\n                low=mid+1;\n            else if(p==d)\n            {\n                c++;\n                if((a-i)*(b-mid)>ma)\n                {\n                    ma=(a-i)*(b-mid);\n                    ra=a-i;\n                    rb=b-mid;\n                }\n                break;\n            }\n        }\n        if(c>0)\n            break;\n    }\n    if(c==0)\n        printf(\"0 0\");\n    else printf(\"%I64d %I64d\",ra,rb);\n        return(0);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "042fce801d455bd7a6b49eba5ac78c1c", "src_uid": "97999cd7c6de79a4e39f56a41ff59e7a", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nvoid find_size(int a, int b, int x, int y, int *p, int *q)\n{\n\tdouble r1 = (double) a / b, r2 = (double) x / y;\n\tif (r1 == r2) {\n\t\t*p = a;\n\t\t*q = b;\n\t}\n\telse if (r1 > r2) {\n\t\tdouble f = (double) x*b / y;\n\t\tif (ceilf(f) == f) {\n\t\t\t*p = f;\n\t\t\t*q = b;\n\t\t}\n\t\telse {\n\t\t\tfind_size(f, b, x, y, p, q);\n\t\t}\n\t}\n\telse {\n\t\tdouble f = (double) a*y / x;\n\t\tif (ceilf(f) == f) {\n\t\t\t*p = a;\n\t\t\t*q = f;\n\t\t}\n\t\telse {\n\t\t\tfind_size(a, f, x, y, p, q);\n\t\t}\n\t}\n}\n\nint main()\n{\n\n\tint a, b, x, y, p, q;\n\n\tscanf(\"%i %i %i %i\", &a, &b, &x, &y);\n\tfind_size(a, b, x, y, &p, &q);\n\tprintf(\"%i %i\\n\", p, q);\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "0b82dd0e689fa14352f1c464e7707eba", "src_uid": "97999cd7c6de79a4e39f56a41ff59e7a", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define N 10\nint S1[N] = {0}, S2[N] = {0};\nint t1 = 0, t2 = 0;\nint k1, k2;\n\nint main(int argc, char *argv[])\n{\n    int n;\n    int i, f;\n    unsigned int H1, H2, h1, h2;\n\n    scanf(\"%d\", &n);\n\n    scanf(\"%d\", &k1);\n    t1 = 0; H1 = 0;\n    for (i = 0; i < k1; i++) {\n        scanf(\"%d\", &S1[t1+i]);\n        H1 = H1 * n + S1[t1+i];\n    }\n\n    scanf(\"%d\", &k2);\n    t2 = 0; H2 = 0;\n    for (i = 0; i < k2; i++) {\n        scanf(\"%d\", &S2[t2+i]);\n        H2 = H2 * n + S2[t2+i];\n    }\n\n    f = 0;\n    while (k1 && k2) {\n        if (S1[t1 % N] > S2[t2 % N]) {\n            S1[(t1+k1) % N] = S2[(t2) % N]; t2++; k1++; k2--;\n            S1[(t1+k1) % N] = S1[(t1) % N]; t1++; k1++; k1--;\n        } else {\n            S2[(t2+k2) % N] = S1[(t1) % N]; t1++; k2++; k1--;\n            S2[(t2+k2) % N] = S2[(t2) % N]; t2++; k2++; k2--;\n        }\n        f++;\n\n        h1 = h2 = 0;\n        for (i = 0; i < k1; i++) h1 = h1 * n + S1[(t1+i) % N];\n        for (i = 0; i < k2; i++) h2 = h2 * n + S2[(t2+i) % N];\n\n        if (h1 == H1 && h2 == H2)\n            break;\n    }\n\n    if (k1 && !k2) {\n        printf(\"%d 1\\n\", f);\n    } else if (!k1 && k2) {\n        printf(\"%d 2\\n\", f);\n    } else {\n        puts(\"-1\");\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a398510cff59dc54c54850a5df833d6f", "src_uid": "f587b1867754e6958c3d7e0fe368ec6e", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n        //while(1){\n        int i,j,n,k1,k2,ps1=0,ps2=0,s1=0,s2=0,shit=1,temp,flag,cnt=0,m,bal;\n        int c1[12];\n        int c2[12];\n        int man[12];\n        for(i=1;i<=11;i++)\n                {\n                        c1[i]=c2[i]=-1;\n                        man[i]=-2;\n                }\n        scanf(\"%d\",&n);\n        scanf(\"%d\",&k1);\n        for(i=1;i<=k1;i++)\n                {\n                        scanf(\"%d\",&c1[i]);\n                        man[i]=c1[i];\n                }\n        scanf(\"%d\",&k2);\n        for(i=1;i<=k2;i++)\n                scanf(\"%d\",&c2[i]);\n        m=k1;\n        /*for(i=1;i<=k1;i++)\n        {\n                shit=1;\n                for(j=1;j<=k1-i;j++)\n                        shit=shit*10;\n                ps1=ps1+shit*c1[i];\n        }\n\n        for(i=1;i<=k2;i++)\n        {\n                shit=1;\n                for(j=1;j<=k2-i;j++)\n                        shit=shit*10;\n                ps2=ps2+shit*c2[i];\n        }*/\n\n        //printf(\"%d %d\\n\\n\",ps1,ps2);\n        //ps1=c1[1];\n        //ps2=c1[k1];\n\n        while(1)\n        {\n                s1=s2=0;\n                if(c1[1]>c2[1])\n                {\n                        temp=c1[1];\n                        for(i=1;i<k1;i++)\n                                c1[i]=c1[i+1];\n                        c1[k1]=c2[1];\n                        c1[k1+1]=temp;\n                        k1++;\n                        for(i=1;i<=k2;i++)\n                                c2[i]=c2[i+1];\n                        k2--;\n                        cnt++;\n                }\n                else\n                {\n                        temp=c2[1];\n                        for(i=1;i<k2;i++)\n                                c2[i]=c2[i+1];\n                        c2[k2]=c1[1];\n                        c2[k2+1]=temp;\n                        k2++;\n                        for(i=1;i<=k1;i++)\n                                c1[i]=c1[i+1];\n                        k1--;\n                        cnt++;\n                }\n\n                if(c1[1]==-1)\n                {\n                        flag=2;\n                        break;\n                }\n                if(c2[1]==-1)\n                {\n                        flag=1;\n                        break;\n                }\n                if(m>k1)\n                        bal=m;\n                else\n                        bal=k1;\n\n                for(i=1;i<=bal;i++)\n                        {\n                                if(c1[i]!=man[i])\n                                {\n                                        flag=9;\n                                        break;\n                                }\n                                else\n                                        flag=0;\n                        }\n\n\n\n            /*    for(i=1;i<=k1;i++)\n                        {\n                                shit=1;\n                                for(j=1;j<=k1-i;j++)\n                                        shit=shit*10;\n                                s1=s1+shit*c1[i];\n                        }\n               for(i=1;i<=k2;i++)\n                        {\n                                shit=1;\n                                for(j=1;j<=k2-i;j++)\n                                        shit=shit*10;\n                                s2=s2+shit*c2[i];\n                        } */\n                        //printf(\"%d %d\\n\",s1,s2);\n\n                        /*if((c1[1]==ps1 && c1[k1]==ps2) || (c2[1]==ps1 && c2[k2]==ps2))\n                        {\n                                flag=0;\n                                break;\n                        }\n                      if(s1==ps2 && s2==ps1)\n                        {\n                                flag=0;\n                                break;\n                        } */\n\n                if(flag==0)\n                        break;\n\n        }\n        if(flag!=0)\n                printf(\"%d %d\",cnt, flag);\n        else\n                printf(\"-1\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "731dab52ebb5ee01ab4436f16d74745b", "src_uid": "f587b1867754e6958c3d7e0fe368ec6e", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define gi(x) scanf(\"%d\",&x)\nint main()\n{\n\tint n;\n\tgi(n);\n\tint k1,k2,i,x;\n\tgi(k1);\n\tint a[1000001];\n\tint b[1000001];\n\tint y=k1;\n\tint g=0;\n\tint countone=k1;\n\tfor(g=0;g<k1;g++)\n\t\tscanf(\"%d\",&a[g]);\n\tgi(k2);\n\tfor(g=0;g<k2;g++)\n\t\tscanf(\"%d\",&b[g]);\n\tint counttwo=k2;\n\tint count=0;\n\tint oo=10000000;\n\tint r=0;\n\twhile(count < oo && countone > 0 && counttwo > 0)\n\t{\n\t\tif(a[r] > b[r])\n\t\t{\n\t\t\ta[k1++]=b[r];\n\t\t\ta[k1++]=a[r];\n\t\t\tcounttwo-=1;\n\t\t\tcountone+=1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tb[k2++]=a[r];\n\t\t\tb[k2++]=b[r];\n\t\t\tcountone-=1;\n\t\t\tcounttwo+=1;\n\t\t}\n\t\tcount++;\n\t\tr++;\n\t}\n\tif(count==oo)\n\t\tprintf(\"-1\\n\");\n\telse if(countone==0)\n\t\tprintf(\"%d 2\\n\",count);\n\telse\n\t\tprintf(\"%d 1\\n\",count );\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e5264208b0110448b7235075cda1525e", "src_uid": "f587b1867754e6958c3d7e0fe368ec6e", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint g_count ;\nstruct stack {\n  int header;\n  int tail;\n  int size;\n  int *array;\n};\nvoid printer(int size , int grid[size]) {\n  for (int i = 0 ; i < size  ; i++) {\n    printf(\"%d \", grid[i]);\n  }\n  printf(\"\\n\");\n}\nvoid queue_add( struct stack *s, int element, int size) {\n  s->tail++;\n  s->array[(s->tail)%size] = element;\n}\nint queue_pop(struct stack *s, int size) {\n  s->header++;\n  return s->array[(s->header)%size];\n}\nint queue_size(struct stack *s , int size) {\n  return (s->tail - s->header) ;\n}\nint main() {\n  int n;\n\n  scanf(\"%d\", &n);\n  struct stack s1;\n  struct stack s2;\n  scanf(\"%d\", &s1.size);\n  s1.array = malloc(s1.size * sizeof(int));\n  s1.header = -1 , s1.tail = -1;\n  for (int i = 0; i < s1.size ; i++) {\n    int temp;\n    scanf(\"%d\", &temp);\n    queue_add(&s1, temp, n);\n  }\n\n  scanf(\"%d\", &s2.size);\n  s2.header = -1 , s2.tail = -1;\n\n  s2.array = malloc(s2.size * sizeof(int));\n  for (int i = 0; i < s2.size ; i++) {\n    int temp;\n    scanf(\"%d\", &temp);\n    queue_add(&s2, temp, n);\n  }\n  int win = 0, stale = 0;\n\n  int s2_back = s2.array[0];\n  int s1_back = s1.array[0];\n  g_count = 0;\n\n  while ( win == 0 && stale == 0) {\n    int save_size = queue_size(&s1, n);\n\n    int a = queue_pop(&s1, n);\n    int b = queue_pop(&s2, n);\n\n      g_count++;\n    if ( a > b) {\n      queue_add(&s1, b, n);\n      queue_add(&s1, a, n);\n\n      //printer(n, s1.array);\n     //  printer(n, s2.array);\n    } else {\n      queue_add(&s2, a, n);\n      queue_add(&s2, b, n);\n    //   printer(n, s1.array);\n   //     printer(n, s2.array);\n\n    }\n    if ( s1.header == s1.tail) {\n      win = 2;\n    }\n    if ( s2.header == s2.tail) {\n      win = 1;\n    }\n    if ( a == s1_back  && b == s2_back  && save_size == s1.size && g_count> 900) {\n      stale = 1;\n    }\n  }\n  if ( stale == 1) {\n    printf(\"-1\\n\");\n  }\n  else {\n    printf(\"%d %d\\n\",g_count,win);\n  }\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6ee1c3b154878331655562dc0730cb9e", "src_uid": "f587b1867754e6958c3d7e0fe368ec6e", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MAXN 10\nchar d[MAXN], g[1 << MAXN];\nint v1[MAXN], v2[MAXN], st1 = 0, dr1, st2 = 0, dr2;\n\ninline void add(int *x, int n){\n  (*x)++;\n  if(*x == n)\n    *x = 0;\n}\n\ninline int vad(int n){\n  int i, rez = 0;\n  for(i = 0; i < n; i++)\n    rez += d[i] * (1 << i);\n  return rez;\n}\n\nint main(){\n  int n, k1, k2, i;\n  scanf(\"%d\", &n);\n  scanf(\"%d\", &k1);\n  for(i = 0; i < k1; i++){\n    scanf(\"%d\", &v1[i]);\n    v1[i]--;\n    d[v1[i]] = 0;\n  }\n  dr1 = k1;\n  scanf(\"%d\", &k2);\n  for(i = 0; i < k2; i++){\n    scanf(\"%d\", &v2[i]);\n    v2[i]--;\n    d[v2[i]] = 1;\n  }\n  dr2 = k2;\n  for(i = 0; !g[vad(n)] && !(st1 == dr1 || st2 == dr2); i++){\n    g[vad(n)] = 1;\n    if(v1[st1] > v2[st2]){\n      d[v2[st2]] = 0;\n      v1[dr1] = v2[st2];\n      add(&dr1, n);\n      v1[dr1] = v1[st1];\n      add(&dr1, n);\n      add(&st1, n);\n      add(&st2, n);\n    }\n    else{\n      d[v1[st1]] = 1;\n      v2[dr2] = v1[st1];\n      add(&dr2, n);\n      v2[dr2] = v2[st2];\n      add(&dr2, n);\n      add(&st1, n);\n      add(&st2, n);\n    }\n  }\n  if(g[vad(n)])\n    printf(\"-1\");\n  else{\n    printf(\"%d \", i);\n    if(dr1 != st1)\n      printf(\"1\");\n    else\n      printf(\"2\");\n  }\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e9c686939046119a1d31138f763be391", "src_uid": "f587b1867754e6958c3d7e0fe368ec6e", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<math.h>\n\nint main()\n{\n    long long int n,sum=1,i,c=0;\n\n    scanf(\"%I64d\",&n);\n\n    if(n==0) printf(1);\n    else{\n        for(i=6;;i+=6){\n            sum+=i;\n            c++;\n            if(c==n) break;\n        }\n        printf(\"%I64d\",sum);\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fa4a42248aa8f4021443b7ef386c49dc", "src_uid": "c046895a90f2e1381a7c1867020453bd", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main () {\n    unsigned long long a;\n    int b, i;\n    scanf(\"%lld\", a);\n    printf(\"%lld\", 1 + 6 * a);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "46c22b7e75475b4a8752f9e0fe69a47b", "src_uid": "c046895a90f2e1381a7c1867020453bd", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\nint main()\n{ int n,t;\n    \n    scanf(\"%d\",n);\n    \n    t=(6^n-1)/(6-1);\n    printf(\"%d\",t);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "21bb1f9357c1ed8945a9bb180aba389c", "src_uid": "c046895a90f2e1381a7c1867020453bd", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n;\n    long t ;\n    scanf(\"%d\",&n);\n    t=6^(n-1)/5;\n    printf(\"%ld\",t);\n    return(0);", "lang_cluster": "C", "compilation_error": true, "code_uid": "f347d8ac949c713cc3326e0f1a8baa44", "src_uid": "c046895a90f2e1381a7c1867020453bd", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main () {\n    unsigned long long a;\n    int b, i;\n    scanf(\"%lld\", &a);\n    if (a < 2) {\n    if (a == 0) \n        printf(\"1\");\n    if (a == 1)\n        printf(\"7\");\n    }\n    else\n    printf(\"%lld\", a*(a+1)/2*6 + 1;\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b03033816170aeef946bd3ccf110a0b7", "src_uid": "c046895a90f2e1381a7c1867020453bd", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<math.h>\n#include<time.h>\n#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#define oo 1000000000\n#define pi 3.14159265359\n#define zero(a) (abb(a)<=1e-7)\n#define lowbit(a) ((a)&(-(a)))\n#define min(a,b) ((a)<(b)?(a):(b))\n#define max(a,b) ((a)>(b)?(a):(b))\n#define abb(a) ((a)>0?(a):(-(a)))\n#define cj(x1,y1,x2,y2) ((x1)*(y2)-(x2)*(y2))\n#define dj(x1,y1,x2,y2) ((x1)*(y1)+(y1)*(y2))\n#define dis(x1,y1,x2,y2) sqrt(((x2)-(x1))*((x2)-(x1))+((y2)-(y1))*((y2)-(y1)))\n\nlong count(long n,long m)\n{\n   if (n<1||m<1)\n      return 0;\n   if (n==1)\n      return (m+1)/2;\n   if (m==1)\n      return (n+1)/2;\n   return 2*(n/2+m/2)-!(n&1)-!(m&1);\n}\n\nint main()\n{\n   long n,m,k;\n   scanf(\"%ld%ld%ld\",&n,&m,&k);\n   printf(\"%ld\\n\",count(n-(k-1)*2,m-(k-1)*2));\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "07521c82a0868ff8aa083399d8d1911c", "src_uid": "fa1ef5f9bceeb7266cc597ba8f2161cb", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <math.h>\n\n#define oo 2000000000\n#define min(a,b) ((a)<(b)?(a):(b))\n#define max(a,b) ((a)>(b)?(a):(b))\n#define abs(a) ((a)<0?-(a):(a))\n#define eps 1e-8\n\nlong a[5005][5005]={0};\n\nint main()\n{\n long n,m,x;\n long i,j;\n long k;\n long ans=0;\n \n scanf(\"%ld%ld%ld\",&n,&m,&x);\n \n for(i=1,j=1;i<=n-i+1&&j<=m-j+1;i++,j++)\n   {\n    for(k=j;k<=m-j+1;k++)\n      a[i][k]=a[n-i+1][k]=i;\n    for(k=i;k<=n-i+1;k++)\n      a[k][j]=a[k][m-j+1]=i;\n   }\n   for(i=1;i<=n;i++)\n     for(j=1;j<=m;j++)\n       if(((i+j)&1)==0&&a[i][j]==x)\n        ans++;\n printf(\"%ld\\n\",ans);\n \n return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "eaaba06d5dc7cd88e34ce65dc88ed4a1", "src_uid": "fa1ef5f9bceeb7266cc597ba8f2161cb", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    int m,n,i,j,k=0,x;\n    scanf(\"%d %d %d\",&m,&n,&x);\n    int arr[10000];\n    if(m>=n)\n    {int l=m;\n        for(i=0;i<((l/2)+1);i++)\n        {\n            if(m>0 && n>0 &&(m*n)%2==0)\n            {\n                arr[k]=(m*n)/2;\n                m=m-2;\n                n=n-2;\n                k++;\n            }\n            else if(m>0 && n>0 && (m*n)%2==1)\n            {\n                arr[k]=((m*n)+1)/2;\n                m=m-2;\n                n=n-2;\n                k++;\n            }\n        }\n    if(x==1)\n    {\n        printf(\"%d\",arr[0]-arr[1]);\n    }\n    else\n    {\n        printf(\"%d\",arr[x-1]-arr[x]);\n    }\n\n    }\n    else\n    {\nint l=n;\n        for(i=0;i<(n/2);i++)\n        {\n            if(m>0 && n>0 &&(m*n)%2==0)\n            {\n                arr[k]=(m*n)/2;\n                m=m-2;\n                n=n-2;\n                k++;\n            }\n            else if(m>0 && n>0 && (m*n)%2==1)\n            {\n                arr[k]=((m*n)+1)/2;\n                m=m-2;\n                n=n-2;\n                k++;\n            }\n        }\n        if(x==1)\n    {\n        printf(\"%d\",arr[0]-arr[1]);\n    }\n    else\n    {\n        printf(\"%d\",arr[x-1]-arr[x-2]);\n    }\n\n    }\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9cd266aa1b7c5b9ab0e548a0d035e18e", "src_uid": "fa1ef5f9bceeb7266cc597ba8f2161cb", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    long long m,n,i,j,k=0,x;\n    scanf(\"%I64d %I64d %I64d\",&m,&n,&x);\n    long long arr[10000];\n    if((m==1 || n==1 ) && x!=1)\n    {\n        printf(\"0\");\n        return 0;\n    }\n    else if((m==1 && x==1 && n!=1))\n    {\n            printf(\"%I64d\",n/2);\n            return 0;\n    }\n    else if(n==1 && x==1 && m!=1)\n    {\n        printf(\"%I64d\",m/2);\n        return 0;\n    }\n    if(m>=n)\n    {\n        long long l=m;\n        for(i=0;i<((l/2)+1);i++)\n        {\n            if(m>0 && n>0 &&(m*n)%2==0)\n            {\n                arr[k]=(m*n)/2;\n                m=m-2;\n                n=n-2;\n                k++;\n            }\n            else if(m>0 && n>0 && (m*n)%2==1)\n            {\n                arr[k]=((m*n)+1)/2;\n                m=m-2;\n                n=n-2;\n                k++;\n            }\n        }\n    if(x==1)\n    {\n        printf(\"%I64d\",arr[0]-arr[1]);\n    }\n    else\n    {\n        printf(\"%I64d\",arr[x-1]-arr[x]);\n    }\n\n    }\n    else\n    {\nlong long l=n;\n        for(i=0;i<(n/2);i++)\n        {\n            if(m>0 && n>0 &&(m*n)%2==0)\n            {\n                arr[k]=(m*n)/2;\n                m=m-2;\n                n=n-2;\n                k++;\n            }\n            else if(m>0 && n>0 && (m*n)%2==1)\n            {\n                arr[k]=((m*n)+1)/2;\n                m=m-2;\n                n=n-2;\n                k++;\n            }\n        }\n        if(x==1)\n    {\n        printf(\"%I64d\",arr[0]-arr[1]);\n    }\n    else\n    {\n        printf(\"%I64d\",arr[x-1]-arr[x-2]);\n    }\n\n    }\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "91244171922ac1a0280c9b859e892334", "src_uid": "fa1ef5f9bceeb7266cc597ba8f2161cb", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,m,times,newn,newm,ans;\n\tscanf(\"%d%d%d\",&n,&m,&times);\n\ttimes--;\n\tnewn=n-2*times;\n\tnewm=m-2*times;\n\tif(newn==0 || newm==0)\n\t{\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\tif(newn-2>0 && newm-2>0)\n\tans=(\t(newn*newm)\t-\t((newn-2)*(newm-2))\t)/2;\n\telse\n\tans=(newn*newm)/2+(newn*newm)%2;\n\tprintf(\"%d\\n\",ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a931a0be8270420531e3f1624863fcfa", "src_uid": "fa1ef5f9bceeb7266cc597ba8f2161cb", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    char input[99];\n    scanf(\"%s\",input);\n    printf(\"%d\",check(input));\n    return 0;\n}\n\n\n\n\nint check (char input[])\n{\n    int noofquestionmarl=0;\n    int noofdistinctletters=0;\n    char letters[28];\n    int n=1;\n    int i=0;\n    int m=0;\n    int ans=0;\n    int flag=0;\n    int counter;\n    while(input[n]!='\\0')\n    {\n        if(input[n]=='?')\n        noofquestionmarl++;\n        else\n        {\n            if(isdigit(input[n])!=1)\n            {\n                m=0;\n                while(letters[m]!='\\0')\n                {\n                    if(input[n]==letters[m])\n                    {\n                        flag++;\n                        break;\n\n                    }\n                    m++;\n                }\n                if(flag==0)\n                {\n                    noofdistinctletters++;\n                    letters[i]=input[n];\n                    i++;\n                    letters[i]='\\0';\n                }\n\n            }\n\n        }\n    n++;\n    }\n    //////////////////////////////////////////////////////\n    //////////////////////////////////////////////////////\n    //////////////////////////////////////////////////////\n    if(input[0]=='?')\n    ans=9;\n    else\n    if(isdigit(input[0])!=1)\n    {\n        ans=9;\n    }\n  m=0;\n    while(letters[m]!='\\0')\n    {\n        if(input[0]==letters[m])\n\n        {\n            noofdistinctletters--;\n            break;\n        }\n        m++;\n\n\n    }\n\n    ////////////////////////////////////////////////////////////\n    ////////////////////////////////////////////////////////////\n    //////////////////////////////////////////////////////////////\n    if(ans!=0)\n    {\n        if(input[1]=='?')\n        n=10;\n        else\n        n=9;\n        while(i>0)\n        {\n            ans=ans*n;\n            n--;\n            i--;\n        }\n        ans=ans*power(10,noofquestionmarl);\n        return ans;\n    }\n\n    else\n\n    {\n\n        ans=1;\n\n        n=10;\n        for(counter=0;counter<noofdistinctletters;counter++)\n        {\n            ans=ans*n;\n            n--;\n\n\n        }\n        ans=ans*power(10,noofquestionmarl);\n        return ans;\n    }\n\n\n\n\n\n\n\n}\n\n\nint power(int x,int y)\n{\n    int ans,counter;\n    ans=1;\n    for(counter=0;counter<y;counter++)\n    ans=ans*x;\n    return ans;\n}\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4afee03961a706d0176e3ab5411e5aae", "src_uid": "d3c10d1b1a17ad018359e2dab80d2b82", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n\tchar a[100100],c;\n\tint i,sum;\n\tint num[26],flag1,flag2,num1,sum1,k,h,total;\n\twhile(scanf(\"%s\",a)!=EOF)\n\t{\n\t\tsum=0;\n\t\tmemset(num,0,sizeof(num));\n\t\tfor(i=0;a[i];i++)\n\t\t\tif(a[i] != '0')\n\t\t\t\tbreak;\n\t\tif(a[i] ==0)\n\t\t{\n\t\t\tprintf(\"1\\n\");\n\t\t\tcontinue;\n\t\t}\n\t\tflag1=0;\n\t\tflag2=0;\n\t\tnum1=0;\n\t\tif(a[i] == '?')\n\t\t\tflag1=1;\n\t\telse if(a[i]>='A' && a[i] <='J')\n\t\t{\n\t\t\tflag2=1;\n\t\t\tc=a[i];\n\t\t}\n\t\tfor(;a[i];i++)\n\t\t{\n\t\t\tif(a[i]>='A' && a[i]<='J')\n\t\t\t{\n\t\t\t\tif(num[a[i] -'A'] == 0)\n\t\t\t\t\tnum1++;\n\t\t\t\tnum[a[i] -'A']++;\n\t\t\t}\n\t\t\telse if(a[i] == '?')\n\t\t\t\tsum++;\n\t\t}\n\t\tif(flag1 == 1)\n\t\t\ttotal = sum *9;\n\t\telse\n\t\t\ttotal = sum*10;\n\t\tif(flag2 == 1)\n\t\t{\n\t\t\th=2;\n\t\t\tsum1=9;\n\t\t\tk=9;\n\t\t\tfor(;h<=num1;h++)\n\t\t\t{\n\t\t\t\tsum1*=k;\n\t\t\t\tk--;\n\t\t\t}\n\t\t\ttotal *= sum1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tsum1=1;\n\t\t\tk=10;\n\t\t\tfor(h=1;h<=num1;h++)\n\t\t\t{\n\t\t\t\tsum1*=k;\n\t\t\t\tk--;\n\t\t\t}\n\t\t\ttotal *= sum1;\n\t\t}\n\t\tif(total ==0)\n\t\t\tprintf();\n\t\tprintf(\"%d\\n\",total);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "643c5ea373741d70626edc1e6539b1c0", "src_uid": "d3c10d1b1a17ad018359e2dab80d2b82", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#define MAX 100000\n\nint main()\n{\n\tchar hint[MAX], c ;\n\tint let_flag[10], i, pos, n ;\n\t\n\tscanf(\" %s\",hint) ;\n\n\tn = 1 ;\n\tpos = 10 ;\n\n\tfor(i=0;i<10;++i)\n\t\tlet_flag[i] = 0 ;\n\n\tfor(i=0;i<strlen(hint);++i)\n\t{\n\t\tc = hint[i] ;\n\t\tif((c>='A')&&(c<='J'))\n\t\t{\n\t\t\tif(let_flag[c-65]==0)\n\t\t\t{\n\t\t\t\tlet_flag[c-65] = 1 ;\n\t\t\t\tif(i==0)\n\t\t\t\t\tn *= 9 ;\n\t\t\t\telse\n\t\t\t\t\tn *= pos ;\n\t\t\t\tpos-- ;\n\t\t\t}\n\t\t}\n\t\telse if(c=='?')\n\t\t{\n\t\t\tif(i==0)\n\t\t\t\tn *= 9 ;\n\t\t\telse\n\t\t\t\tn *= 10 ;\n\t\t}\n\t}\n\n\tprintf(\"%d \\n\",n) ;\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "01a7003c20e0d06976f78bb21d6975cf", "src_uid": "d3c10d1b1a17ad018359e2dab80d2b82", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#define MAX 100000\n\nint main()\n{\n\tchar hint[MAX], c ;\n\tint let_flag[10] = {0}, i, pos, n ;\n\t\n\tscanf(\" %s\",hint) ;\n\n\tn = 1 ;\n\tpos = 10 ;\n\n\tfor(i=0;i<strlen(hint);++i)\n\t{\n\t\tc = hint[i] ;\n\t\tif((c>='A')&&(c<='J'))\n\t\t{\n\t\t\tif(let_flag[c-65]==0)\n\t\t\t{\n\t\t\t\tlet_flag[c-65] = 1 ;\n\t\t\t\tif(i==0)\n\t\t\t\t\tn *= 9 ;\n\t\t\t\telse\n\t\t\t\t\tn *= pos ;\n\t\t\t\tpos-- ;\n\t\t\t}\n\t\t}\n\t\telse if(c=='?')\n\t\t{\n\t\t\tif(i==0)\n\t\t\t\tn *= 9 ;\n\t\t\telse\n\t\t\t\tn *= 10 ;\n\t\t}\n\t}\n\n\tprintf(\"%d \\n\",n) ;\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3f6ce86bfb555ac742d973db607a9965", "src_uid": "d3c10d1b1a17ad018359e2dab80d2b82", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main()\n{\n\tchar hint[100], c ;\n\tint let_flag[10], i, pos, n ;\n\t\n\tscanf(\" %s\",hint) ;\n\n\tn = 1 ;\n\tpos = 10 ;\n\n\tfor(i=0;i<10;++i)\n\t\tlet_flag[i] = 0 ;\n\n\tfor(i=0;i<strlen(hint);++i)\n\t{\n\t\tc = hint[i] ;\n\t\tif((c>='A')&&(c<='J'))\n\t\t{\n\t\t\tif(let_flag[c-65]==0)\n\t\t\t{\n\t\t\t\tlet_flag[c-65] = 1 ;\n\t\t\t\tif(i==0)\n\t\t\t\t\tn *= 9 ;\n\t\t\t\telse\n\t\t\t\t\tn *= pos ;\n\t\t\t\tpos-- ;\n\t\t\t}\n\t\t}\n\t\telse if(c=='?')\n\t\t{\n\t\t\tif(i==0)\n\t\t\t\tn *= 9 ;\n\t\t\telse\n\t\t\t\tn *= 10 ;\n\t\t}\n\t}\n\n\tprintf(\"%d \\n\",n) ;\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8c1cc45b3a327f91774faa8d7ee7d341", "src_uid": "d3c10d1b1a17ad018359e2dab80d2b82", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main()\t{\n\tint midLen, len1, len2;\n\tint i, letterArr[26]={0}, pos, lenToKey;\n\tchar str[30], key, grid1[14]={0}, grid2[14]={0}, *cp1, *cp2;\n\tscanf(\"%s\", str);\n\tfor(i=0; i<27; i++)\t{\n\t\tif(letterArr[str[i]-'A'])\tbreak;\n\t\telse letterArr[str[i]-'A']++;\n\t}\n\tkey = str[i];\n\tcp1 = strchr(str, key);\n\tcp2 = strchr(cp1+1, key);\n\tmidLen = (int)(cp2-cp1-1);\n\tif(midLen == 0)\t{\n\t\tprintf(\"Impossible\");\treturn 0;\n\t}\n\tlen1 = midLen/2;\n\tlen2 = midLen-len1;\n\tfor(pos=13-len1-1, i=0; i<=len1; i++)\t{\n\t\tgrid1[pos++] = *(cp1+i);\n\t}\n\tpos = 13-len1-1;\n\tfor(pos=12, i=len2; i>0; i--)\t{\n\t\tgrid2[pos--] = *(cp2-i);\n\t}\n\tlenToKey = cp1-str+1;\n\tif(lenToKey+len1>=13)\t{\n//\t\tputs(\"EnteredAt1st\");\n\t\tpos = 13-len1-1;\n\t\twhile(pos>=0)\tgrid1[--pos] = *(--cp1);\n\t\ti=0;\n//\t\tputs(\"Ok\");\n\t\twhile(cp1>str)\tgrid2[i++] = *(--cp1);\n\t\tcp2++;\tpos = 13-len2;\n\t\twhile(*cp2)\tgrid2[--pos] = *(cp2++);\n\t\tprintf(\"%s\\n%s\", grid1, grid2);\n\t\treturn 0;\n\t}\n\telse\t{\n\t\tpos = 13-len2;\n\t\twhile(pos>=0)\tgrid2[--pos] = *(cp2++);\n\t\ti=0;\n\t\twhile(*cp2)\tgrid1[i++] = *(cp2++);\tpos=0;\n\t\twhile(i<13)\tgrid1[i++] = str[i];\n\t\tprintf(\"%s\\n%s\",grid1, grid2);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b265cef9612fb8bc0acfc45f2a4b246d", "src_uid": "56c5ea443dec7a732802b16aed5b934d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#include<time.h>\n#include<ctype.h>\n#include<limits.h>\n#define eps 1e-9\n#define ll long long int \n#define N 500500\nchar first1[N];\nchar in[N];\nchar first2[N];\nchar second1[N];\nchar second2[N];\nint main(){\n   gets(in);\n   int remem=-1;int start;\n   for(int i=0;i<strlen(in);i++){\n      for(int w=0;w<strlen(in);w++){\n         if(i!=w){\n            if(in[i]==in[w] && remem==-1){\n               remem=w-i+1;\n               start=i;\n            }\n         }\n      }\n   }\n   if(remem<=3){\n      printf(\"Impossible\");\n      return 0;\n   }\n   int k=0;int i;\n   i=start;\n   int ub=remem%2==0?remem/2-1:remem/2;\n   for(int w=0;w<(remem)/2;w++){\n      if(i>26)\n      i=0;\n      first2[k++]=in[i++];\n   }\n   k=0;\n   for(int w=0;w<ub;w++){\n      if(i>26)\n      i=0;\n      second2[k++]=in[i++];\n   }\n   i++;k=0;\n   for(int w=0;w<(13-(remem/2));w++){\n      if(i>26)\n      i=0;\n      first1[k++]=in[i++];\n   }  \n   k=0;\n   for(int w=0;w<13-(ub);w++){\n      if(i>26)\n      i=0;\n      second1[k++]=in[i++];\n   }\n   for(int i=0;i<strlen(second2)/2;i++){\n      char t=second2[i];\n      second2[i]=second2[strlen(second2)-i-1];\n      second2[strlen(second2)-i-1]=t;\n   }\n   for(int i=0;i<strlen(first1)/2;i++){\n      char t=first1[i];\n      first1[i]=first1[strlen(first1)-i-1];\n      first1[strlen(first1)-i-1]=t;\n   }\n   printf(\"%s%s\\n%s%s\",first1,first2,second1,second2);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b2120586003a57a490e2fa3069f70293", "src_uid": "56c5ea443dec7a732802b16aed5b934d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nchar s[30];\nint a[30];\nint main()\n{\n    scanf(\"%s\",s);\n    int target=s[0]-'A'+1;\n    int last=target;\n    a[0]=target;\n    for(int i=1;s[i]!='\\0';i++)\n    {\n        int temp=s[i]-'A'+1;\n        a[i]=temp;\n        if(temp==last)\n        {\n            printf(\"Impossible\\n\");\n            return 0;\n        }\n        last=temp;\n    }\n    for(int i=0;i<=26;i++)\n    {\n        for(int j=i+1;j<=26;j++)\n            if(a[i]==a[j])\n                target=a[i];\n    }\n    int flag=0;\n    int start,end;\n    start=end=0;\n    for(int i=0;i<27;i++)\n    {\n        if(a[i]==target&&flag==0)\n            start=i,flag=1;\n        else if(a[i]==target&&flag!=0)\n            end=i;\n    }\n    int mid=(end-start-1)/2+start;\n    //printf(\"%d %d %d\\n\",mid,start,end);\n    if(mid>=13){\n        if((end-start-1)%2!=0) mid++;\n        for(int i=mid-12;i<=mid;i++)\n            printf(\"%c\",a[i]+'A'-1);\n        printf(\"\\n\");\n        for(int i=mid-13;i>=0;i--)\n            printf(\"%c\",a[i]+'A'-1);\n        for(int i=26;i>mid;i--)\n        {\n            if(i==end) continue;\n            printf(\"%c\",a[i]+'A'-1);\n        }\n        printf(\"\\n\");\n    } else\n    {\n        if((end-start-1)%2==0) mid++;\n        for(int i=mid+1;i<=mid+13;i++)\n        {\n            //if(i==end) continue;\n            printf(\"%c\",a[i]+'A'-1);\n        }\n        printf(\"\\n\");\n        for(int i=mid;i>=0;i--)\n        {\n            if(i==start) continue;\n            printf(\"%c\",a[i]+'A'-1);\n        }\n        for(int i=26;i>mid+13;i--)\n        {\n            printf(\"%c\",a[i]+'A'-1);\n        }\n        printf(\"\\n\");\n    }\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "23f6fa43fd1ea3c6fb7bef01b8859587", "src_uid": "56c5ea443dec7a732802b16aed5b934d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main()\t{\n\tint midLen, len1, len2;\n\tint i, letterArr[26]={0}, pos, lenToKey;\n\tchar str[30], key, grid1[14]={0}, grid2[14]={0}, *cp1, *cp2;\n\tscanf(\"%s\", str);\n\tfor(i=0; i<27; i++)\t{\n\t\tif(letterArr[str[i]-'A'])\tbreak;\n\t\telse letterArr[str[i]-'A']++;\n\t}\n\tkey = str[i];\n\tcp1 = strchr(str, key);\n\tcp2 = strchr(cp1+1, key);\n\tmidLen = (int)(cp2-cp1-1);\n\tif(midLen == 0)\t{\n\t\tprintf(\"Impossible\");\treturn 0;\n\t}\n\tlen1 = midLen/2;\n\tlen2 = midLen-len1;\n\tfor(pos=13-len1-1, i=0; i<=len1; i++)\t{\n\t\tgrid1[pos++] = *(cp1+i);\n\t}\n\tpos = 13-len1-1;\n\tfor(pos=12, i=len2; i>0; i--)\t{\n\t\tgrid2[pos--] = *(cp2-i);\n\t}\n\tlenToKey = cp1-str+1;\n\tif(lenToKey+len1>=13)\t{\n//\t\tputs(\"EnteredAt1st\");\n\t\tpos = 13-len1-1;\n\t\twhile(pos>=0)\tgrid1[--pos] = *(--cp1);\n\t\ti=0;\n//\t\tputs(\"Ok\");\n\t\twhile(cp1>str)\tgrid2[i++] = *(--cp1);\n\t\tcp2++;\tpos = 13-len2;\n\t\twhile(*cp2)\tgrid2[--pos] = *(cp2++);\tgrid1[13] = 0; grid2[13] = 0;\n\t\tprintf(\"%s\\n%s\", grid1, grid2);\n\t\treturn 0;\n\t}\n\telse\t{\n//\t\tputs(\"EntererdAt2nd\");\n\t\tpos = 13-len2;\n\t\twhile(pos>=0)\tgrid2[--pos] = *(cp2++);\n\t\ti=0;\n\t\twhile(*cp2)\tgrid1[i++] = *(cp2++);\tpos=0;\n\t\twhile(i<13)\tgrid1[i++] = str[i];\tgrid1[13] = 0; grid2[13] = 0;\n\t\tprintf(\"%s\\n%s\",grid1, grid2);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "65d9003b38144a36d82f98689ed041e8", "src_uid": "56c5ea443dec7a732802b16aed5b934d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#include<time.h>\n#include<ctype.h>\n#include<limits.h>\n#define eps 1e-9\n#define ll long long int \n#define N 500500\nchar in[N];\nchar first[N];\nchar second[N];\nint main(){\n   gets(in);\n   if(in[19]!=in[6]){\n      printf(\"Impossible\");\n      return 0;\n   }\n   second[0]=in[strlen(in)-1];\n   int k=1;\n   int len=strlen(in);\n   for(int i=0;i<6;i++){\n      second[k++]=in[i];\n   }\n   int s=12;\n   int go=13;\n   for(int i=0;i<6;i++){\n      second[s--]=in[go++];\n   }\n   s=0;\n   go=25;\n   for(int i=0;i<6;i++){\n      first[s++]=in[go--];\n   }\n   go=6;\n   for(int i=0;i<=6;i++){\n      first[s++]=in[go++];\n   }\n  \n   for(int i=0;i<strlen(first);i++){\n      merge[0][i]=first[i];\n   }\n   for(int i=0;i<strlen(second);i++){\n      merge[1][i]=second[i];\n   }\n   puts(first);\n   puts(second);\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b7ba8aa51bebcdffae44bcafc4e8caea", "src_uid": "56c5ea443dec7a732802b16aed5b934d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nvoid merge(int arr[], int l, int m, int r)\n{\n\tint arr1[m-l+1], arr2[r-m], i, j, k;\n\n\tfor(i = 0; i < m-l+1; i++)\n\t\tarr1[i] = arr[l+i];\n\n\tfor(j = 0; j < r-m; j++)\n\t\tarr2[j] = arr[j+m+1];\n\n\ti = 0;\n\tj = 0;\n\tk = l;\n\n\twhile((i< m-l+1) && (j < r-m))\n\t{\n\t\tif(arr1[i] <= arr2[j])\n\t\t\tarr[k++] = arr1[i++];\n\t\telse\n\t\t\tarr[k++] = arr2[j++];\n\t}\n\n\twhile(i < m-l+1)\n\t\tarr[k++] = arr1[i++];\n\twhile(j < r - m)\n\t\tarr[k++] = arr2[j++];\n\n}\n\nvoid mergesort(int arr[], int l, int r)\n{\n\tif(l < r){\n\t\tint m = l + (r - l)/2;\n\t\tmergesort(arr, l , m);\n\t\tmergesort(arr, m+1, r);\n\t\tmerge(arr, l, m, r);\n\t}\n}\n\nint main ()\n{\n\n\tint p, x, y, i, j, k, l, ans, flag, count, arr[475];\n\n\tscanf(\"%d %d %d\", &p, &x, &y);\n\tl = 0;\n\tfor(k = 0; k < 475; k++)\n\t{\n\t\ti = k;\n\t\tfor(j = 0; j < 25; j++)\n\t\t{\n\t\t\ti = (i*96 + 42)%475;\n\t\t\tif(p == 26 + i)\n\t\t\t{\n\t\t\t\tarr[l++] = k;\n\t\t\t\tprintf(\"%d\\n\", k);\n\t\t\t}\n\t\t}\n\t}\n\t\n\tprintf(\"Aur k nahi\\n\");\n\tcount = 0;\n\tflag = 0;\n\t\n\tif(x < y)\n\t{\n\t\tif((y-x)%50 != 0)\n\t\t{\n\t\t\ty = y + 50 - (y-x)%50;\n\t\t}\n\t\t\n\t\twhile(1)\n\t\t{\n\t\t\tfor(i = 0; i < l; i++)\n\t\t\t{\n\t\t\t\tif((y/50)%475 == arr[i])\n\t\t\t\t\tflag++;\n\t\t\t}\n\t\t\t\n\t\t\tif(flag != 0)\n\t\t\t\tbreak;\n\t\t\t\n\t\t\ty += 50;\n\t\t\tcount++;\n\t\t}\n\t\t\n\t\tans = (y-x)/100;\n\t\tif((y-x)%100 != 0)\n\t\t\tans += 1;\n\t}\n\t\n\telse\n\t{\n\t\ty = x;\n\t\twhile(1)\n\t\t{\n\t\t\tfor(i = 0; i < l; i++)\n\t\t\t{\n\t\t\t\tif((y/50)%475 == arr[i])\n\t\t\t\t\tflag++;\n\t\t\t}\n\t\t\t\n\t\t\tif(flag != 0)\n\t\t\t\tbreak;\n\t\t\t\n\t\t\ty += 50;\n\t\t\tcount++;\n\t\t}\n\t\t\n\t\tans = (y-x)/100;\n\t\tif((y-x)%100 != 0)\n\t\t\tans += 1;\n\t}\n\t\n\tprintf(\"%d\\n\", ans);\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "70a972e44ba6ead26f5fbb139b6c6162", "src_uid": "c9c22e03c70a94a745b451fc79e112fd", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\nlong long arr[1000001];\nchar str[1000001];\nint func(const void *a, const void *b)\n{\n\treturn (*(int*)a-*(int*)b);\n}\nlong long max(long long a, long long b)\n{\n\treturn (a>b)?a:b;\n}\nlong long min(long long a, long long b)\n{\n\treturn (a>b)?b:a;\n}\nint main()\n{\n\tlong long int n, i, j, k, count=0, ans=0, p, x,y;\n\tlong long temp=0;\n\tscanf(\"%lld %lld %lld\", &p, &x, &y);\n\t//\tscanf(\"%s\", str);\n\ti=(x/50)%475;\n\tlong long flag=0;\n\tfor(j=1;j<=25;j++)\n\t{\n\t\ti=(i*96+42)%475;\n//\t\tprintf(\"%lld\\n\",26+i);\n\t\tif(i+26==p)\n\t\t\tflag=1;\n\t}\n\tif(flag)\n\t\tprintf(\"0\\n\");\n\telse\n\t{\n\t\tfor(i=x+50;i<=25000;i=i+50)\n\t\t{\n\t\t\tk=(i/50)%475;\n\t\t\tfor(j=1;j<=25;j++)\n\t\t\t{\n\t\t\t\tk=(k*96+42)%475;\n\t\t\t\tif(k+26==p)\n\t\t\t\t{\n\t\t\t\t\tans=(i-x+50)/100;\n\t\t\t\t\tflag=1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag)\n\t\t\t\tbreak;\n\t\t}\n\t\tif(flag)\n\t\t\tprintf(\"%lld\\n\",ans);\n\t\telse\n\t\t\tprintf(\"0\\n\");\n\n\n\t\treturn 0;\n\t}\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "baba92071a3f9730b0d786f7e8fd5940", "src_uid": "c9c22e03c70a94a745b451fc79e112fd", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    int p, x, y;\n    int i, j = 1, n = 0, temp = 1;\n    scanf(\"%d%d%d\", &p, &x, &y);\n    i = (x / 50) % 475;\n    while(1)\n    {\n        i = (i * 96 + 42) % 475;\n        if(i + 26 == p)\n        {\n            printf(\"0\\n\");\n            temp = 0;\n            break;\n        }\n        j++;\n        if(j >= 25)\n        {\n            j = 1;\n            n++;\n            i = ((x - n * 50) / 50) % 475;\n        }\n    }\n    if(temp)\n    {\n        j = 1;\n        int a = 1;\n        i = ((x + a * 100 - 50) / 50) % 475;\n        while(1)\n        {\n            i = (i * 96 + 42) % 475;\n            if(i + 26 == p)\n            {\n                break;\n            }\n            j++;\n            if(j >= 25)\n            {\n                j = 1;\n                a++;\n                i = ((x + a * 100 - 50) / 50) % 475;\n            }\n        }\n        j = 1;\n        int m = 1;\n        i = ((x + m * 100) / 50) % 475;\n        while(1)\n        {\n            i = (i * 96 + 42) % 475;\n            if(i + 26 == p)\n            {\n                break;\n            }\n            j++;\n            if(j >= 25)\n            {\n                j = 1;\n                m++;\n                i = ((x + m * 100) / 50) % 475;\n            }\n        }\n        printf(\"%d\\n\", a > m ? m : a);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ce69ff6376ab0fb311e6dd6a13d13b74", "src_uid": "c9c22e03c70a94a745b451fc79e112fd", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<stdlib.h>\nint func(int x,int p)\n{\n\tint i=(x/50)%475,j=25;\n\tfor(j=0;j<25;j++)\n\t{\n\t\ti=(i*96+42)%475;\n\t\tif(26+i==p)\n\t\t{\n\t\t\treturn 1;\n\t\t}\n\t}\n\treturn 0;\n}\n\nint main( )\n{\n\tint p,x,y,i=0,j,c=25,a[500];\n\tscanf(\"%d %d %d\",&p,&x,&y);\n\tfor(i=x;i>=y;i-=50)\n\t{\n\t\tif(func(i,p))\n\t\t{\n\t\t\treturn !printf(\"0\\n\");\n\t\t}\n\t}\n\tfor(i=50;;i+=50)\n\t{\n\t\tif(func(x+i,p))\n\t\t{\n\t\t\treturn !printf(\"%d\\n\",(i+50/100));\n\t\t}\n\t}\n\treturn 0;\n}\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "852d03693d055e2ff54a089811f699f9", "src_uid": "c9c22e03c70a94a745b451fc79e112fd", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint good(int i, int p) {\n\tint k;\n\n\tfor (k = 0; k < 25; k++) {\n\t\ti = (i * 96 + 42) % 475;\n\t\tif (i + 26 == p)\n\t\t\treturn 1;\n\t}\n\treturn 0;\n}\n\nint main() {\n\tint p, y, x, i, a, b, min, res;\n\n\tscanf(\"%d%d%d\", &p, &x, &y);\n\ta = y / 50;\n\tb = x / 50;\n\tmin = 1000;\n\tfor (i = a; i <= b + 475; i++) {\n\t\tres = i < b ? 0 : (i - b + 1) / 2;\n\t\tif (good(i % 475, p) && min > res)\n\t\t\tmin = res;\n\t}\n\tprintf(\"%d\\n\", min);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cb56f270d432c6d16733743a26ee8798", "src_uid": "c9c22e03c70a94a745b451fc79e112fd", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<math.h>\nint main()//C\n{\n    long long c,hr,hb,wr,wb,i,k,ans,x;\n    scanf(\"%I64d%I64d%I64d%I64d%I64d\",&c,&hr,&hb,&wr,&wb)\n        if(c<wr&&c<wb){\n            printf(\"0\\n\");\n            continue;\n        }\n        if(c<wb&&c>=wr){\n            printf(\"%d\\n\",c/wr*hr);\n            continue;\n        }\n        if(c<wr&&c>=wb){\n            printf(\"%d\\n\",c/wb*hb);\n            continue;\n        }\n        ans=0;\n        for(i=0;i*i<=c;i++){\n            if(c-i*wb>=0)\n                ans=(ans>i*hb+(c-i*wb)/wr*hr?ans:i*hb+(c-i*wb)/wr*hr);\n            if(c-i*wr>=0)\n                ans=(ans>i*hr+(c-i*wr)/wb*hb?ans:i*hr+(c-i*wr)/wb*hb);\n        }\n        printf(\"%d\\n\",ans);\n    return 0;\n}\n\n             ", "lang_cluster": "C", "compilation_error": true, "code_uid": "1c01096bea773cb3bf851fd16d766ce4", "src_uid": "eb052ca12ca293479992680581452399", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main()\n{\n    long long int c,hr,hb,wr,wb,happy=0,qr,qb,ans=0,temp;\n    int i,j;\n    scanf(\"%I64d\",&c);\n    scanf(\"%I64d\",&hr);\n    scanf(\"%I64d\",&hb);\n    scanf(\"%I64d\",&wr);\n    scanf(\"%I64d\",&wb);\n    if(wr>=sqrt(c))\n    {\n        for(i=0;i<=c/wr;i++)\n        {\n            temp=i*hr+((c-i*wr)/wb)*hb;\n            //printf(\"temp:%I64d\\n\",temp);\n            if(temp>ans)\n                ans=temp;\n        }\n    }\n    else if(wb>=sqrt(c))\n    {\n        for(i=0;i<=c/wb;i++)\n        {\n            temp=i*hb+((c-i*wb)/wr)*hr;\n            //printf(\"temp:%I64d\\n\",temp);\n            if(temp>ans)\n                ans=temp;\n        }\n    }\n    else if(wr<sqrt(c) && wb<sqrt(c))\n    {\n        if(hr*wb<=hb*wr)\n        {\n            for(i=0;i<=wb;i++)\n            {\n                temp=i*hr+((c-i*wr)/wb)*hb;\n                if(temp>ans)\n                    ans=temp;\n            }\n        }\n        else\n        {\n            for(i=0;i<=wr;i++)\n            {\n                temp=i*hb+((c-i*wb)/wr)*hr;\n                if(temp>ans)\n                    ans=temp;\n            }   \n        }\n    }\n    printf(\"%I64d\\n\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b78541aadeb4a885466505cd84b16c95", "src_uid": "eb052ca12ca293479992680581452399", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void)\n{\n\tlong long c ,h1 ,h2 ,w1 ,w2 ,temp;\n\tlong long ans ,ans2;\n\tlong long k1 ,k2;\n\tlong long i;\n\tlong long n1 ,n2;\n\tlong long p1 ,p2 ,p12;\n\t\n\twhile (scanf(\"%I64d %I64d %I64d %I64d %I64d\" ,&c ,&h1 ,&h2 ,&w1 ,&w2)!=EOF)\n\t{\n\t\tif (h2*w1>h1*w2)\t\n\t\t{\n\t\t\ttemp=h1;\n\t\t\th1=h2;\n\t\t\th2=temp;\n\t\t\ttemp=w1;\n\t\t\tw1=w2;\n\t\t\tw2=temp;\n\t\t}\n\t\telse if (h2*w1==h1*w2&&w2<w1)\n\t\t{\n\t\t\ttemp=h1;\n\t\t\th1=h2;\n\t\t\th2=temp;\n\t\t\ttemp=w1;\n\t\t\tw1=w2;\n\t\t\tw2=temp;\t\t\t\n\t\t}\n\t\tk1=c/(w1*w2);\n\t\tif (k1)k1--;\n\t\tc-=k1*w1*w2;\n\t\tans=k1*h1*w2;\n\t\tn1=c/w1;\n\t\tn2=c/w2;\n\t\tif (n2<n1)\n\t\t{\n\t\t\ttemp=h1;\n\t\t\th1=h2;\n\t\t\th2=temp;\n\t\t\ttemp=w1;\n\t\t\tw1=w2;\n\t\t\tw2=temp;\n\t\t\ttemp=n2;\n\t\t\tn2=n1;\n\t\t\tn1=temp;\t\t\t\n\t\t}\n\t\tans2=0;\n\t\tfor (i=0 ; i<=n1 ; i++)\n\t\t{\n\t\t\tp1=0;\n\t\t\tp2=n2;\n\t\t\twhile (p1<p2)\n\t\t\t{\n\t\t\t\tp12=(p1+p2+1)/2;\n\t\t\t\tif (i*w1+p12*w2<=c)\n\t\t\t\t{\n\t\t\t\t\tp1=p12;\t\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tp2=p12-1;\t\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (p1*h2+i*h1>ans2)\n\t\t\t{\n\t\t\t\tans2=p1*h2+i*h1;\n\t\t\t}\n\t\t}\n\t\tprintf(\"%I64d\\n\" ,ans+ans2);\n\t}\n\t\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "600fe131f44819425b046c2cbc0c7738", "src_uid": "eb052ca12ca293479992680581452399", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\n#define max(a,b) (a>b)?(a):(b)\n\n\n\n\n\nint main(void){\n    long long int  C,Hr,Hb,Wr,Wb;\n    long long int ans = 0;\n    int i;\n    \n   scanf(\"%lld %lld %lld %lld %lld\",&C,&Hr,&Hb,&Wr,&Wb);\n    \n    for(i=0;i<1000000;i++)\n\t\tif(Wr * i <= C)\n\t\t\tans = max(ans, Hr * i + (C - Wr * i) / Wb * Hb);\n\n\n    for(i=0;i<1000000;i++)\n\t\tif(Wb * i <= C)\n\t\t\tans = max(ans, Hb * i + (C - Wb * i) / Wr * Hr);\n    \n  printf(\"%lld\\n\",ans);\n    \n    return 0;\n}\n\n                                                                                                        ", "lang_cluster": "C", "compilation_error": false, "code_uid": "13de05fcac69a9c600788fe316e28fe0", "src_uid": "eb052ca12ca293479992680581452399", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <math.h>\n#include <stdio.h>\n\nint main() {\n\tint c, hr, hb, wr, wb, sq;\n\tlong long max, r, b;\n\n\tscanf(\"%d%d%d%d%d\", &c, &hr, &hb, &wr, &wb);\n\tif (hr * wb > hb * wr) {\n\t\tint tmp;\n\n\t\ttmp = hr, hr = hb, hb = tmp;\n\t\ttmp = wr, wr = wb, wb = tmp;\n\t}\n\tsq = sqrt(c), max = 0;\n\tif (wb > sq)\n\t\tfor (b = 0; b * wb <= c; b++) {\n\t\t\tr = (c - b * wb) / wr;\n\t\t\tif (max < r * hr + b * hb)\n\t\t\t\tmax = r * hr + b * hb;\n\t\t}\n\telse\n\t\tfor (r = 0; r < wb && r * wr <= c; r++) {\n\t\t\tb = (c - r * wr) / wb;\n\t\t\tif (max < r * hr + b * hb)\n\t\t\t\tmax = r * hr + b * hb;\n\t\t}\n\tprintf(\"%lld\\n\", max);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "16626c48bdd502109e274c1fcaf2daec", "src_uid": "eb052ca12ca293479992680581452399", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n\tint a[10], i, n, max=0;\n\tscanf(\"%d\", &n);\n\tfor(i=0; i<n; i++){\n\t\tscanf(\"%d\", &a[i]);\n\t\tif(max<a[i]) max=a[i];\n\t}\n\tprintf(\"%d\", max^a[n-1]);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8d530e3873c58613c4cd267aa39ec8d1", "src_uid": "f45c769556ac3f408f5542fa71a67d98", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <malloc.h>\n#include <string.h>\n\nint main(){\n    int sx=0,sy=0,p=1,a,b,i,num_len,dx,dy;\n    char s[110];\n    int pos_x[110];\n    int pos_y[110];\n    scanf(\"%d %d %s\",&a,&b,s);\n    pos_x[0]=pos_y[0]=0;\n    num_len=strlen(s);\n    for(i=0;i<num_len;i++){\n        switch(s[i]){\n        case 'U':\n            sy++;   \n            break;\n        case 'D':\n            sy--;\n            break;\n        case 'R':\n            sx++;\n            break;\n        case 'L':\n            sx--;\n            break;\n        default: ;\n        }\n        pos_x[i+1]=sx;\n        pos_y[i+1]=sy;\n    }\n    dx=pos_x[num_len];\n    dy=pos_y[num_len];\n    for(i=0;i<=num_len;i++){\n        if(dx && dy){\n            if((float)(a-pos_x[i])/dx==(float)(b-pos_y[i])/dy && dx*(a-pos_x[i])>=0) {printf(\"Yes\"); return 0;}\n        }\n        else if(dx){\n            if(b-pos_y[i]==0 && (a-pos_x[i])%dx==0 && dx*(a-pos_x[i])>=0) {printf(\"Yes\"); return 0;}\n        }else{\n            if(a-pos_x[i]==0 && (b-pos_y[i])%dy==0 && dy*(b-pos_y[i])>=0) {printf(\"Yes\"); return 0;}\n        }\n    }\n    printf(\"No\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "acd61fbeb2afcee592dbc550d224faca", "src_uid": "5d6212e28c7942e9ff4d096938b782bf", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define REP(i,n) for(int i=0;i<(int)n;++i)\ntypedef long long ll;\n\nconst int dy[] = {1,0,-1,0};\nconst int dx[] = {0,1,0,-1};\n\nint d[100];\nchar s[105];\nint vx[105], vy[105];\nint ix, iy;\nint main() {\n\tint a,b;\n\twhile(scanf(\"%d%d\", &a, &b) == 2) {\n\t\tscanf(\"%s\",s);\n\t\tll y=0,x=0;\n\t\tint n = strlen(s);\n\t\tREP(i,n) {\n\t\t\td[i] = strchr(\"URDL\", s[i]) - s;\n\t\t}\n\t\tix = 0;\n\t\tiy = 0;\n\t\tvx[ix++] = 0;\n\t\tvy[iy++] = 0;\n\t\tREP(i,n) {\n\t\t\ty += dy[d[i]];\n\t\t\tx += dx[d[i]];\n\t\t\tvy[iy++] = y;\n\t\t\tvx[ix++] = x;\n\t\t}\n\t\tll Y = y;\n\t\tll X = x;\n\t\tint ok = 0;\n\t\tREP(i,n) {\n\t\t\tREP(j,n) {\n\t\t\t\tll yy = vy[j];\n\t\t\t\tll xx = vx[j];\n\t\t\t\tll y = b-yy;\n\t\t\t\tll x = a-xx;\n\t\t\t\tif (Y && y % Y == 0) {\n\t\t\t\t\tif (X*(y/Y) == x) {\n\t\t\t\t\t\tok = 1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (Y == 0 && y == 0) {\n\t\t\t\t\tif (x == 0 || (X && x % X == 0)) {\n\t\t\t\t\t\tok = 1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tprintf(\"%s\\n\",ok?\"Yes\":\"No\");\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f2913eaa76a65b453b570a0949a41259", "src_uid": "5d6212e28c7942e9ff4d096938b782bf", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <malloc.h>\n#include <string.h>\n\nint main(){\n    int sx=0,sy=0,p=1,a,b,i,num_len,dx,dy;\n    char s[110];\n    int pos_x[110];\n    int pos_y[110];\n    scanf(\"%d %d %s\",&a,&b,s);\n    pos_x[0]=pos_y[0]=0;\n    num_len=strlen(s);\n    for(i=0;i<num_len;i++){\n        switch(s[i]){\n        case 'U':\n            sy++;   \n            break;\n        case 'D':\n            sy--;\n            break;\n        case 'R':\n            sx++;\n            break;\n        case 'L':\n            sx--;\n            break;\n        default: ;\n        }\n        pos_x[i+1]=sx;\n        pos_y[i+1]=sy;\n    }\n    dx=pos_x[num_len];\n    dy=pos_y[num_len];\n    for(i=0;i<=num_len;i++){\n        if(dx && dy){\n            if((float)(a-pos_x[i])/dx==(float)(b-pos_y[i])/dy && ((dx>0 && (a-pos_x[i])>=0)||(dx<0 && (a-pos_x[i])<=0))) {printf(\"Yes\"); return 0;}\n        }\n        else if(dx){\n            if(b-pos_y[i]==0 && (a-pos_x[i])%dx==0 && ((dx>0 && (a-pos_x[i])>=0)||(dx<0 && (a-pos_x[i])<=0))) {printf(\"Yes\"); return 0;}\n        }else{\n            if(a-pos_x[i]==0 && (b-pos_y[i])%dy==0 && ((dy>0 && (b-pos_y[i])>=0)||(dy<0 && (b-pos_y[i])<=0))) {printf(\"Yes\"); return 0;}\n        }\n    }\n    printf(\"No\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "119c8009e5bbb697bd8726b04ebdd445", "src_uid": "5d6212e28c7942e9ff4d096938b782bf", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint a,b,l;\nint x,y,xl,yl;\n\nchar s[101];\nint  w[101][2];\nint al,bl;\nint main()\n{\n    int i,j;\n    \n    scanf (\"%d%d\",&a,&b);\n    scanf (\"%s\",s);l=strlen(s);\n    if  (a==0&&b==0){printf (\"Yes\\n\");return 0;}\n    for (i=0;i<l;i++) {\n        if  (s[i]=='U'){w[i][0]=0;w[i][1]=1;}\n        if  (s[i]=='D'){w[i][0]=0;w[i][1]=-1;}\n        if  (s[i]=='L'){w[i][0]=-1;w[i][1]=0;}\n        if  (s[i]=='R'){w[i][0]=1;w[i][1]=0;}\n    }\n    for (i=0;i<l;i++) {\n        xl+=w[i][0];yl+=w[i][1];\n    }\n    //printf (\"{{%d %d}}\\n\",xl,yl);\n    for (i=0;i<l;i++) {\n        x+=w[i][0];y+=w[i][1];\n        al=a-x;bl=b-y;//printf (\"(%d %d)<%d,%d>\\n\",al,bl,x,y);\n        if  (al*xl<0||bl*yl<0)continue;\n        if  (al==0&&bl==0) {printf (\"Yes\\n\");return 0;}\n        if  (al==0) {if  (xl==0&&bl%yl==0) {printf (\"Yes\\n\");return 0;}else continue;}\n        if  (bl==0) {if  (yl==0&&al%xl==0) {printf (\"Yes\\n\");return 0;}else continue;}\n        if  (al%xl==0&&bl%yl==0&&al/xl==bl/yl){printf (\"Yes\\n\");return 0;}\n    }\n    printf (\"No\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d4705fe61b748ba5618f0361d6070048", "src_uid": "5d6212e28c7942e9ff4d096938b782bf", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n\tint a,b,i,path[2][105],len,delta_x,delta_y,k;\n\tchar str[105];\n\tscanf(\"%d%d\",&a,&b);\n\tscanf(\"%s\",str);\n\tlen = strlen(str);\n\ti=0;\n\tk=0;\n\tpath[0][k]=0;\n\tpath[1][k]=0;\n\tk++;\n\twhile(i<len)\n\t{\n\t\tif(str[i] == 'U')\n\t\t{\n\t\t\tpath[0][k] = path[0][k-1];\n\t\t\tpath[1][k] = path[1][k-1] + 1;\n\t\t}\n\t\tif(str[i] == 'D')\n\t\t{\n\t\t\tpath[0][k] = path[0][k-1];\n\t\t\tpath[1][k] = path[1][k-1] - 1;\n\t\t}\n\t\tif(str[i] == 'R')\n\t\t{\t\n\t\t\tpath[0][k] = path[0][k-1] + 1;\n\t\t\tpath[1][k] = path[1][k-1];\n\t\t}\n\t\tif(str[i] == 'L')\n\t\t{\n\t\t\tpath[0][k] = path[0][k-1] - 1;\n\t\t\tpath[1][k] = path[1][k-1];\n\t\t}\n\t\tk++;\n\t\ti++;\n\t}\n\tdelta_x = path[0][len]-path[0][0];\n\tdelta_y = path[1][len]-path[1][0];\n\tfor(i=0;i<=len;i++)\n\t{\n\t\tif(delta_x == 0 && delta_y!=0)\n\t\t{\n\t\t\tif(path[0][i] == a && (b-path[1][i])%delta_y == 0)\n\t\t\t{\n\t\t\t\tprintf(\"Yes\\n\");\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(delta_y == 0 && delta_x!=0)\n\t\t{\n\t\t\tif(path[1][i] == b && (a-path[0][i])%delta_x == 0)\n\t\t\t{\n\t\t\t\tprintf(\"Yes\\n\");\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(delta_x!=0 && delta_y!=0)\n\t\t{\n\t\t\tif((a-path[0][i])%delta_x == 0 && (b-path[1][i])%delta_y == 0)\n\t\t\t{\n\t\t\t\tif(a-path[0][i])/delta_x == (b-path[1][i])/delta_y)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"Yes\\n\");\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(delta_x == 0 && delta_y == 0)\n\t\t{\n\t\t\tif(path[0][i] == a && path[1][i] == b)\n\t\t\t{\n\t\t\t\tprintf(\"Yes\\n\");\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tif(i>len)\n\t\tprintf(\"No\\n\");\nreturn 0;\n}\t", "lang_cluster": "C", "compilation_error": true, "code_uid": "42bfbb8914e148dab8683b8c7d7eefd1", "src_uid": "5d6212e28c7942e9ff4d096938b782bf", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n,need=0;\n    scanf(\"%d\",&n);\n    \n    int a[n];\n    char temp;\n    \n    for(int i=0;i<n;i++){\n        scanf(\"%d\",&a[i]);\n    }\n    \n    for(int i=0;i<n;i++){\n        for(int j=i+1;j<n;j++){\n            if(a[j]<a[i]){\n                tmep=a[j];\n                a[j]=a[i];\n                a[i]=temp;\n            }\n        }\n    }\n    \n    for(int i=0;i<n;i=i+2){\n        need+=a[i+1]-a[i];\n    }\n    \n    printf(\"%d\",need);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2ea46d053a0e9b9370537738e1abc88e", "src_uid": "55485fe203a114374f0aae93006278d3", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,i,temp,k=0,j;\n    scanf(\"%d\",&n);\n    int a[n];\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    for(i=0;i<n;i++)\n    for(j=i+i;j<n;j++)\n    {\n        if(s[i]>s[j])\n        {\n            temp=s[j];\n            s[j]=s[i];\n            s[i]=temp;\n        }\n    }\n    for(i=0;i<n;i+=2)\n    {\n        k=k+s[i+1]-s[i];\n        \n    }\n    printf(\"%d\",k)\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "861b716a1bf64b7313b4a00caf2a9af4", "src_uid": "55485fe203a114374f0aae93006278d3", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nmain()\n{\n    int a,d,count=0;\n    scanf(\"%d\",&a);\n    int s[a],c[a];\n    for(int i=0;i<a;i++)\n    scanf(\"%d\",&s[i]);\n    \n    for(int i=0;i<a;i++)\n    {\n        for(int j=i+1,k=0;j<a;j++,k++);\n        {\n            c[k]=abs(s[i]-s[j]);\n            d=c[0];\n            if(d>c[k])\n            d=c[j-1];\n        }\n        for(int k=0;k<d;k++)\n        count++;\n    }\n    printf(\"%d\",count);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9887242de1d6c79cb3d00632026f95e0", "src_uid": "55485fe203a114374f0aae93006278d3", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int i,k,a[100],n,s=0;\n    scanf(\"%d\",&n);\n    for(i=1;i<=n;i++)\n    scanf(\"%d\",&a[i]);\n    for(i=2;i<=n;i++)\n    {\n    k=a[i];\n    j=i-1;\n    while(a[j]>k)\n    a[j+1]=a[j];\n    a[i]=k;\n    }\n    for(i=1;i<=n;i+=2)\n    s=s+a[i+1]-a[i];\n    printf(\"%d\",s);\n  return 0;\nj", "lang_cluster": "C", "compilation_error": true, "code_uid": "6f6665da800e0bcac044c8ffda6d1940", "src_uid": "55485fe203a114374f0aae93006278d3", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,i,temp,k=0,j;\n    scanf(\"%d\",&n);\n    int s[n];\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&s[i]);\n    }\n    for(i=0;i<n;i++)\n    for(j=i+i;j<n;j++)\n    {\n        if(s[i]>s[j])\n        {\n            temp=s[j];\n            s[j]=s[i];\n            s[i]=temp;\n        }\n    }\n    for(i=0;i<n;i+=2)\n    {\n        k=k+s[i+1]-s[i];\n        \n    }\n    printf(\"%d\",k)\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b7c1275528d2a9acd2ef337987242580", "src_uid": "55485fe203a114374f0aae93006278d3", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main() {\n\tint w1,h1,w2,h2;\n\tscanf(\"%d%d%d%d\",&w1,&h1,&w2,&h2);\n\tn=2*w1+2*(h1+h2+2);\n\tprintf(\"%d\\n\",n);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a5ebcfcd6f2d0031bb8623b0e3358fb9", "src_uid": "b5d44e0041053c996938aadd1b3865f6", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<iostream>\n#include<string.h>\n#include<stdlib.h>\n#include<algorithm> \nusing namespace std;\n\n\nint main(){\n\tint w1,h1,w2,h2;\n\tscanf(\"%d%d%d%d\",&w1,&h1,&w2,&h2);\n\tint num=w1+2+h1+h1+2+(w1-w2)+h2+h2+w2;\n\tprintf(\"%d\",num);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7b5ebcb400c2c184dbd8a820d15a83de", "src_uid": "b5d44e0041053c996938aadd1b3865f6", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int w[2],h[2];\n    scanf(\"%d %d %d %d\", &w[0], &h[0], &w[1], &h[1]);\n    int ar[2];\n    for(int i = 0; i < 2; i++)\n        ar[i] = (w[i]+2) * (h[i]+2) - (w[i] * h[i]);\n    ans = ar[0] + ar[1] - ( (w[1] + 2) * 2 );\n    printf(\"%d\",ans);\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e471f5f8aabc95e8be79fcb18bc47e9e", "src_uid": "b5d44e0041053c996938aadd1b3865f6", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n   long long w1,w2,h1,h2;\n   cin>>w1>>h1>>w2>>h2;\n   long long ans = 2*w1 + 2*h1 + 2*h2 + 4;\n   cout<<ans;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "34a4d6fdca85f107272c0efd8d132d76", "src_uid": "b5d44e0041053c996938aadd1b3865f6", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"A. Sea Battle\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/A. Sea Battle\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/A. Sea Battle\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6c9664a70d8b12fc39a54c186e4f630f", "src_uid": "b5d44e0041053c996938aadd1b3865f6", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n;\n    scanf(\"%d\", &n)\n    if(n>-127 && n<128)\n    {\n        printf(\"byte\");\n    }\n    else if(n>-32767 && n<32768)\n    {\n        printf(\"short\");\n    }\n    else if(n>=-2147483648 && n<=2147483647)\n    {\n        printf(\"int\");\n    }\n    else if(n>=-9223372036854775808 && n<=9223372036854775807)\n    {\n        printf(\"long\");\n    }\n    else\n    {\n        printf(\"biginteger\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "153cd5a952e72860bb3771c02e247801", "src_uid": "33041f1832fa7f641e37c4c638ab08a1", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(){\n    int len;\n    char a[101];\n    scanf(\"%s\",a);\n        len=strlen(a);\n        if(len<3||(len==3&&strcmp(a,\"127\")<=0))printf(\"byte\\n\");\n        else if(len<5||(len==5&&strcmp(a,\"32767\")<=0))printf(\"short\\n\");\n        else if(len<10||(len==10&&strcmp(a,\"2147483647\")<=0))printf(\"int\\n\");\n        else if(len<19||(len==19&&strcmp(a,\"9223372036854775807\")<=0))printf(\"long\\n\");\n        else printf(\"BigInteger\\n\");\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5921c5c8b1d4a722b2a12274de99ce29", "src_uid": "33041f1832fa7f641e37c4c638ab08a1", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"petya and java\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/petya and java\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/petya and java\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "df5336946de085b3a1bde14402945c1d", "src_uid": "33041f1832fa7f641e37c4c638ab08a1", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n//#include<conio.h>\nint main()\n{\n    int l;\n    char a[101];\n    gets(a);\n    l=strlen(a);\n    if(l==1 || l==2) printf(\"byte\");\n   else if(l==3 && a[0]<='1' && a[1]<='2' && a[2]<='7')  printf(\"byte\");\n   else if(l==3)  printf(\"short\");\n   else if(l==4) printf(\"short\");\n   else if(l==5 && a[0]<='3' && a[1]<='2' && a[2]<='7' && \n   a[3]<='6' && a[4]<='7')  printf(\"short\");\n   else if(l==5)  printf(\"int\");\n   else if(l>5 && l<10) printf(\"int\");\n   else if(l==10 && a[0]<='2' && a[1]<='1' && a[2]<='4' && \n   a[3]<='7' && a[4]<='4' && a[5]<='8' && a[6]<='3' && a[7]<='6' \n   && a[8]<='4' && a[9]<='7')\n     printf(\"int\");\n   else if(l==10)\n     printf(\"long\");\n    else if(l>10 && l<19) printf(\"long\");\n    else if(l==19 && a[0]<='9' && a[1]<='2' && a[2]<='2' && a[3]<='3'\n     && a[4]<='3' && a[5]<='7' && a[6]<='2' && a[7]<='0' &&\n     a[8]<='3' && a[9]<='6' && a[10]<='8' && a[11]<='5' && a[12]<='4'\n      && a[13]<='7' && a[14]<='7' && a[15]<='5' && a[16]<='8'\n      && a[17]<='0' && a[18]<='7') printf(\"long\");\n   else if(l==19) printf(\"BigInteger\");\n   else if(l>19) printf(\"BigInteger\");\n    getch();\n   // return(0);\n}\n    //  2158324958633591462\n  // 2147483647\n        // 9 2 2 3 3 7 2 0 3 6 8 5 4 7 7 5 8 0 7\n       // 2147483647\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c5f89e140cbd43875b11628d69e808e2", "src_uid": "33041f1832fa7f641e37c4c638ab08a1", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nmain(){\n        long long t,x,i;\n        scanf(\"%d\",&x);\n        t=0;\n        for(i=0;i<=127;i++)\n        {\n            if(x==i)\n            {\n                printf(\"byte\");\n                t=1;;\n            }\n        }\n        if(t==0)\n        {\n            for(i=128;i<=32767;i++)\n            {\n                  if(x==i)\n                {\n                    printf(\"short\");\n                    t=1;\n                }\n            }\n        }\n        if(t==0)\n        {\n            for(i=32768;i<=2147483647;i++)\n            {\n                 if(x==i)\n                {\n                    printf(\"int\");\n                    t=1;\n                }\n            }\n        }\n        if(t==0)\n        {\n            for(i=21474836;i<=9223372036854775807;i++)\n            {\n                if(x==i)\n                {\n                    printf(\"long\");\n                    t=1;\n                }\n            }\n            if(t==0)\n            {\n                printf(\"BigInteger\");\n            }\n        }\n\n        return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "aaf22d9811311690db6d51d6af37c611", "src_uid": "33041f1832fa7f641e37c4c638ab08a1", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void){\n\tint length;\n\tscanf(\"%d\\n\", &length);\n\n\tchar b[length];\n\tfor (int i = 0; i < length; i++) {\n\t\tscanf(\"%c\", &b[i]);\n\t}\n\n\tint result = 0;\n\tfor (int i = 0; i < length; i++) {\n\t\tif (b[i] == '0') {\n\t\t\tresult++;\n\t\t\tbreak;\n\t\t}\n\t\telse if (b[i] == '1') {\n\t\t\tresult++;\n\t\t}\n\t}\t\n\n\tprintf(\"%d\\n\", result);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "72d87887c7ca9ef14adb67fad51d0358", "src_uid": "54cb2e987f2cc06c02c7638ea879a1ab", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nchar x[1001]= {'\\0'};\nint main()\n{\n    int n,x,i,a=0;\n    scanf(\"%d %s\",&n,x);\n    \n    for(i=0;i<n;i++){\n        if(x[i]=='1') a++;\n        if(x[i]==0) break;\n    }\n    if(a==n) printf(\"%d\",a);\n    else printf(\"%d\",a+1);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a2929fc94d3c7afa94fd87be2333db5a", "src_uid": "54cb2e987f2cc06c02c7638ea879a1ab", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main () {\n\tint input;\n\tfloat result=0;\n\n\tscanf(\"%d\",&input);fflush(stdin);\n\tchar binary[100];\n\n\tscanf(\"%s\",binary);fflush(stdin);\n\n\tfor (int i=0;i<input;i++){\n\t\tif (binary[i]=='1'){\n\t\t\tresult += pow(2.0,i);\n\t\t}\n\t}\n\tresult+=1;\n\n\tchar binary2[100];\n\tfor(int i=0;i<input;i++){\n\t\tif ((int)result%2==1)\n\t\t\tbinary2[i]='1';\n\t\telse if((int)result%2==0)\n\t\t\tbinary2[i]='0';\n\n\t\tresult/=2;\n\t}\n\tbinary2[input]='\\0';\n\n\tint output=0;\n\tfor(int i=0;i<input;i++){\n\t\tif(binary[i]!=binary2[i])\n\t\t\toutput++;\n\t}\n\tprintf(\"%d\",output);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "265f6ae431764b3855fb4ef3633fbb8c", "src_uid": "54cb2e987f2cc06c02c7638ea879a1ab", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(int argc, char const *argv[])\n{\n\tint length;\n\tscanf(\"%d\\n\", &length);\n\n\tchar b[length];\n\tfor (int i = 0; i < length; i++) {\n\t\tscanf(\"%s\", &b[i]);\n\t}\n\n\tint result = 0;\n\tfor (int i = 0; i < length; i++) {\n\t\tif (b[i] == '0') {\n\t\t\tresult++;\n\t\t\tbreak;\n\t\t}\n\t\telse if (b[i] == '1') {\n\t\t\tresult++;\n\t\t}\n\t}\t\n\n\tprintf(\"%d\\n\", result);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8714912a94bd63eda87d315eea2d368d", "src_uid": "54cb2e987f2cc06c02c7638ea879a1ab", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n    int i,n;\n    char a;\n    scanf(\"%d\",&n);\n    for(i=1;i<=n;i++)\n    {\n        scanf(\"%c\",&a);\n        if(a!='1')\n           break;\n    }\n    if(i==n+1)\n       printf(\"%d\",n);\n    else\n       printf\"%d\",i);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f37a500ed0dbaf2db851ca372f77c57e", "src_uid": "54cb2e987f2cc06c02c7638ea879a1ab", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n    char cad[10];\n    scanf(\"%s\",cad);\n    printf(\"7\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3663220ede908deacaa9f76d36513ab8", "src_uid": "47287f8bc61fec72d729638d5e0e67f5", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint top,i;\nchar a[10];\nint main(){\n\tscanf(\"%s\",a+1);\n\tfor(i=2;i<7;i++);\n\ttop+=(a[i]-'0')*(a[i]=='1' ? 10 : 1);\n\tprintf(\"%d\",top+1);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "83d0006772a3ed314ae16018b5ae9d6a", "src_uid": "47287f8bc61fec72d729638d5e0e67f5", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n    int i,r;\n    char s[10];\n    scanf(\"%s\",s);\n    for(i=r=1;i<7;i++){\n        if(s[i]==1){\n            r+=10;\n        }else{\n            r+=s[i]-'0';\n        }\n    }\n    printf(\"%d\",r);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "498cb56f5ae8495de3283e41cf2f26d2", "src_uid": "47287f8bc61fec72d729638d5e0e67f5", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\tint n,i,t,t1;\n\tchar a[14444];\nint main(){\n\tscanf(\"%s\",a);\n\tt=a[1]-'0'+a[2]-'0';\n\tt1=a[2]-'0'+a[3]-'0';\n\tif(t1>t)\n\t\tprintf(\"%c%c\",a[1],a[2]);\n\telse\n\t\tprintf(\"%c%c\",a[2],a[3]);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8a693ff87c40ee27014fb269671d9b4c", "src_uid": "47287f8bc61fec72d729638d5e0e67f5", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint top,i;\nchar a[10];\nint main(){\n\tscanf(\"%s\",a+1);\n\tfor(i=2;i<=7;i++);\n\ttop+=(a[i]-'0')*(a[i]=='1' ? 10 : 1);\n\tprintf(\"%d\",top+1);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4785dbc8054d7746ba2b7ea7a1c4acf7", "src_uid": "47287f8bc61fec72d729638d5e0e67f5", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint stat[26], sumT;\n\nint checkSubStrings(){\n    int i, status = 0;\n    for (i = 0; i < 26; i++){\n        status += stat[i];\n    }\n    return status + sumT;\n}\n\nint main()\n{\n    char s[50005];\n    scanf(\"%s\", &s);\n    int len = strlen(s), i, j, k;\n    sumT = 0;\n    if (len < 26) printf(\"-1\\n\");\n    else{\n        for (i = 0; i < 26; i++){\n            if (s[i] != '?'){\n                stat[s[i] - 65] = 1;\n            }else sumT++;\n        }\n//        printf(\"SubStrings = %d\\n\", checkSubStrings());\n        i = 0;\n        while ((checkSubStrings() != 26) && (i <= (len - 26))){\n            if (s[i] != '?') stat[s[i] - 65] = 0;\n            else sumT--;\n            if (s[i + 26] != '?') stat[s[i + 26] - 65] = 1;\n            else sumT++;\n            i++;\n        }\n//        printf(\"I = %d\\n\", i);\n        if (checkSubStrings() != 26) printf(\"-1\\n\");\n        else {\n            for (j = i; j < i + 26; j++){\n                if (s[j] == '?'){\n                    k = 0;\n                    while (k < 26){\n                        if (!stat[k]) {\n                            s[j] = k + 65;\n                            stat[k] = 1;\n                            break;\n                        }\n                        k++;\n                    }\n                }\n            }\n            for (j = 0; j < len; j++)\n                if (s[j] == '?') s[j] = 'A';\n            printf(\"%s\\n\", s);\n        }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "febfa22882e90bb2678b7262ea6789eb", "src_uid": "a249431a4b0b1ade652997fe0b82edf3", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    long int n,que=0,count=0,i=0,j=0,p,res=0,k,l;\n    char str[50010];\n    scanf(\"%s\",&str);\n        long int arr[27]={0};\n        for(i=0,j=0;j<strlen(str);)\n        {\n            if(str[j]=='?')\n            {\n                que++;\n                j++;\n            }\n            else\n            {\n                if(arr[str[j]-'A'])\n                {\n                    while(i<j)\n                    {\n                        if(str[i]==arr[str[j]-'A']+'A')\n                        {\n                            i++;\n                            break;\n                        }\n                        if(str[i]=='?')\n                            que--;\n                        else\n                        {\n                            arr[str[i]-'A']=0;\n                            count--;\n                        }\n                        i++;\n                    }\n                    //break;\n                }\n                else\n                {\n                    arr[str[j]-'A']=1;\n                    j++;\n                    count++;\n                }\n                if(count+que==26)\n                    break;\n            }\n        }\n            if(count+que==26)\n            {\n                l=0;\n                res=1;\n                for(k=i;k<=j;k++)\n                {\n                    if(str[k]=='?')\n                    {\n                        for(;l<26;l++)\n                        {\n                            if(arr[l]==0)\n                            {\n                                str[k]=l+'A';\n                                l++;\n                                break;\n                            }\n                        }\n                    }\n                }\n            }\n        for(j=0;j<strlen(str);j++)\n        {\n            if(str[j]=='?')\n                str[j]='A';\n        }\n    if(res)\n        printf(\"%s\",str);\n    else\n        printf(\"-1\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7ebce32ae26c77d77665555764c5adf7", "src_uid": "a249431a4b0b1ade652997fe0b82edf3", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\nvoid test(char* str)\n{\n\tfor(int i=0;i<26;i++)\n\t{\n\t\tif(str[i]=='\\0')\n\t\t{\n\t\t\tprintf(\"-1\");\n\t\t\texit(0);\n\t\t}\n\t\tfor(int j=0;j<i;j++)\n\t\t{\n\t\t\tif(str[j]==str[i]&&str[i]!='?')\n\t\t\t{\n\t\t\t\ttest(str+j);\n\t\t\t\treturn ;\n\t\t\t}\n\t\t}\n\t}\n\tint a[26]={0};\n\tfor(int i=0;i<26;i++)\n\t{\n\t\tif(str[i]!='?')\n\t\t{\n\t\t\ta[str[i]-'A']=1;\n\t\t}\n\t}\n\tfor(int i=0;i<26;i++)\n\t{\n\t\tif(str[i]=='?')\n\t\t{\n\t\t\tfor(int j=0;j<26;j++)\n\t\t\t{\n\t\t\t\tif(a[j]==0)\n\t\t\t\t{\n\t\t\t\t\ta[j]=1;\n\t\t\t\t\tstr[i]=j+'A';\n\t\t\t\t\tbreak;\n\t\t\t\t}\t\t\t\t\n\t\t\t}\n\t\t}\n\t}\n}\nint main(void)\n{\n\tchar str[50001];\n\tgets(str);\t\n\ttest(str);\n\tfor(char* p=str;*p;p++)\n\t{\n\t\tif(*p=='?')\n\t\t{\n\t\t\tputchar('A');\n\t\t}\n\t\telse\n\t\t\tputchar(*p);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "56d3f7e411be5ddf2d96c027f608d9fd", "src_uid": "a249431a4b0b1ade652997fe0b82edf3", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    long int n,que=0,count=0,i=0,j=0,p,res=0,k,l;\n    char str[50010];\n    scanf(\"%s\",&str);\n        long int arr[27]={0};\n        for(i=0,j=0;j<strlen(str);)\n        {\n            if(str[j]=='?')\n            {\n                que++;\n                j++;\n            }\n            else\n            {\n                if(arr[str[j]-'A'])\n                {\n                    while(i<j)\n                    {\n                        if(str[i]==arr[str[j]-'A']+'A')\n                        {\n                            i++;\n                            break;\n                        }\n                        if(arr[i]=='?')\n                            que--;\n                        else\n                        {\n                            arr[str[i]-'A']=0;\n                            count--;\n                        }\n                        i++;\n                    }\n                    //break;\n                }\n                else\n                {\n                    arr[str[j]-'A']=1;\n                    j++;\n                    count++;\n                }\n                if(count+que==26)\n                    break;\n            }\n        }\n            if(count+que==26)\n            {\n                l=0;\n                res=1;\n                for(k=i;k<=j;k++)\n                {\n                    if(str[k]=='?')\n                    {\n                        for(;l<26;l++)\n                        {\n                            if(arr[l]==0)\n                            {\n                                str[k]=l+'A';\n                                l++;\n                                break;\n                            }\n                        }\n                    }\n                }\n            }\n        for(j=0;j<strlen(str);j++)\n        {\n            if(str[j]=='?')\n                str[j]='A';\n        }\n    if(res)\n        printf(\"%s\",str);\n    else\n        printf(\"-1\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4aa0a96241d7a91a497e83e068a67e82", "src_uid": "a249431a4b0b1ade652997fe0b82edf3", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    long int n,que=0,count=0,i=0,j=0,p,res=0,k,l;\n    char str[50010];\n    scanf(\"%s\",&str);\n        long int arr[27]={0};\n        for(i=0,j=0;j<strlen(str);)\n        {\n            if(count+que==26)\n                    break;\n            if(str[j]=='?')\n            {\n                que++;\n                j++;\n            }\n            else\n            {\n                if(arr[str[j]-'A'])\n                {\n                    while(i<j)\n                    {\n                        if(str[i]==[str[j])\n                        {\n                            i++;\n                            break;\n                        }\n                        if(str[i]=='?')\n                            que--;\n                        else\n                        {\n                            arr[str[i]-'A']=0;\n                            count--;\n                        }\n                        i++;\n                    }\n                    j++;\n                }\n                else\n                {\n                    arr[str[j]-'A']=1;\n                    j++;\n                    count++;\n                }\n            }\n        }\n        printf(\"%ld %ld\\n\",i,j);\n            if(count+que==26)\n            {\n                l=0;\n                res=1;\n                for(k=i;k<=j;k++)\n                {\n                    if(str[k]=='?')\n                    {\n                        for(;l<26;l++)\n                        {\n                            if(arr[l]==0)\n                            {\n                                str[k]=l+'A';\n                                l++;\n                                break;\n                            }\n                        }\n                    }\n                }\n            }\n        for(j=0;j<strlen(str);j++)\n        {\n            if(str[j]=='?')\n                str[j]='A';\n        }\n    if(res)\n        printf(\"%s\",str);\n    else\n        printf(\"-1\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "afb119268e64dba8f5f943c9b906994b", "src_uid": "a249431a4b0b1ade652997fe0b82edf3", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint tab[110];\nint abs(int a){\n\tint b;\n\t(a>0) ? b=a : b=-a;\n\treturn b;\n}\nint main(){\n\tint n,k,presum=0,sum=0,des,max=0;\n\tscanf(\"%d %d\",&n,&k);\n\tfor(int i=0;i<n;i++){\n\t\tscanf(\"%d\",tab+i);\t\t\n\t}\n\tfor(int i=0;i<n;i++){\n\t\tpresum+=tab[i];\n\t}\n\tfor(int i=0;i<k;i++){\n\t\tfor(int j=0;i+j*k<n;j++){\n\t\t\tsum+=tab[i+j*k];\n\t\t}\n\t\tdes=presum-sum;\n\t\tif(max<abs(des))\tmax=abs(des);\n\t\tsum=0;\n\t}\n\tprintf(\"%d\",max);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "06b9530cf2c1df2ed1cc410ed58b9d42", "src_uid": "6119258322e06fa6146e592c63313df3", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint a[100];\nint main(){\n       int n,k,i,max=0;\n       scanf(\"%d%d\",&n,&k);\n       for(i=0;i<n;i++)\n              scanf(\"%d\",&a[i]);\n       for(i=0;i<k;i++){\n              int c=0;\n              for(j=0;j<n;j++){\n                     if(j%k!=i)    c+=a[j];\n              }\n              if(c<0)       c=-c;\n              if(max<c)     max=c;\n       }\n       printf(\"%d\",max);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e67cbc419836aaba1989697ea0764968", "src_uid": "6119258322e06fa6146e592c63313df3", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n\nusing namespace std;\n\nint main (void)\n{\n    int n, k;\n\n    cin>>n>>k;\n\n    int a[n];\n\n    for(int i = 0; i < n; i++)\n        cin>>a[i];\n\n    int max = 0;\n\n\n    for(int b = 0; b < k; b++){\n            int infor = 0;\n            int social = 0;\n        for(int i = 0; i < n; i++){\n            if((i-b)%k!=0){\n                if(a[i] == -1)\n                    social++;\n                else\n                    infor++;\n            }\n        }\n        if(max<fabs(infor-social))\n            max = fabs(infor-social);\n    }\n    cout<<max<<endl;\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d83be16caad8e1d5a7dc8a7244b13d58", "src_uid": "6119258322e06fa6146e592c63313df3", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "<?xml version=\"1.0\" encoding=\"utf-8\"?>\n<Project DefaultTargets=\"Build\" ToolsVersion=\"15.0\" xmlns=\"http://schemas.microsoft.com/developer/msbuild/2003\">\n  <ItemGroup Label=\"ProjectConfigurations\">\n    <ProjectConfiguration Include=\"Debug|Win32\">\n      <Configuration>Debug</Configuration>\n      <Platform>Win32</Platform>\n    </ProjectConfiguration>\n    <ProjectConfiguration Include=\"Release|Win32\">\n      <Configuration>Release</Configuration>\n      <Platform>Win32</Platform>\n    </ProjectConfiguration>\n    <ProjectConfiguration Include=\"Debug|x64\">\n      <Configuration>Debug</Configuration>\n      <Platform>x64</Platform>\n    </ProjectConfiguration>\n    <ProjectConfiguration Include=\"Release|x64\">\n      <Configuration>Release</Configuration>\n      <Platform>x64</Platform>\n    </ProjectConfiguration>\n  </ItemGroup>\n  <PropertyGroup Label=\"Globals\">\n    <VCProjectVersion>15.0</VCProjectVersion>\n    <ProjectGuid>{7C2D7A28-1431-4F1D-BD6D-B1DA49A551D4}</ProjectGuid>\n    <Keyword>Win32Proj</Keyword>\n    <RootNamespace>ARomanandBrowser</RootNamespace>\n    <WindowsTargetPlatformVersion>10.0.17134.0</WindowsTargetPlatformVersion>\n  </PropertyGroup>\n  <Import Project=\"$(VCTargetsPath)\\Microsoft.Cpp.Default.props\" />\n  <PropertyGroup Condition=\"'$(Configuration)|$(Platform)'=='Debug|Win32'\" Label=\"Configuration\">\n    <ConfigurationType>Application</ConfigurationType>\n    <UseDebugLibraries>true</UseDebugLibraries>\n    <PlatformToolset>v141</PlatformToolset>\n    <CharacterSet>Unicode</CharacterSet>\n  </PropertyGroup>\n  <PropertyGroup Condition=\"'$(Configuration)|$(Platform)'=='Release|Win32'\" Label=\"Configuration\">\n    <ConfigurationType>Application</ConfigurationType>\n    <UseDebugLibraries>false</UseDebugLibraries>\n    <PlatformToolset>v141</PlatformToolset>\n    <WholeProgramOptimization>true</WholeProgramOptimization>\n    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Condition=\"'$(Configuration)|$(Platform)'=='Debug|Win32'\">\n    <Import Project=\"$(UserRootDir)\\Microsoft.Cpp.$(Platform).user.props\" Condition=\"exists('$(UserRootDir)\\Microsoft.Cpp.$(Platform).user.props')\" Label=\"LocalAppDataPlatform\" />\n  </ImportGroup>\n  <ImportGroup Label=\"PropertySheets\" Condition=\"'$(Configuration)|$(Platform)'=='Release|Win32'\">\n    <Import Project=\"$(UserRootDir)\\Microsoft.Cpp.$(Platform).user.props\" Condition=\"exists('$(UserRootDir)\\Microsoft.Cpp.$(Platform).user.props')\" Label=\"LocalAppDataPlatform\" />\n  </ImportGroup>\n  <ImportGroup Label=\"PropertySheets\" Condition=\"'$(Configuration)|$(Platform)'=='Debug|x64'\">\n    <Import Project=\"$(UserRootDir)\\Microsoft.Cpp.$(Platform).user.props\" Condition=\"exists('$(UserRootDir)\\Microsoft.Cpp.$(Platform).user.props')\" Label=\"LocalAppDataPlatform\" />\n  </ImportGroup>\n  <ImportGroup Label=\"PropertySheets\" Condition=\"'$(Configuration)|$(Platform)'=='Release|x64'\">\n    <Import Project=\"$(UserRootDir)\\Microsoft.Cpp.$(Platform).user.props\" Condition=\"exists('$(UserRootDir)\\Microsoft.Cpp.$(Platform).user.props')\" Label=\"LocalAppDataPlatform\" />\n  </ImportGroup>\n  <PropertyGroup Label=\"UserMacros\" />\n  <PropertyGroup Condition=\"'$(Configuration)|$(Platform)'=='Debug|Win32'\">\n    <LinkIncremental>true</LinkIncremental>\n  </PropertyGroup>\n  <PropertyGroup Condition=\"'$(Configuration)|$(Platform)'=='Debug|x64'\">\n    <LinkIncremental>true</LinkIncremental>\n  </PropertyGroup>\n  <PropertyGroup Condition=\"'$(Configuration)|$(Platform)'=='Release|Win32'\">\n    <LinkIncremental>false</LinkIncremental>\n  </PropertyGroup>\n  <PropertyGroup Condition=\"'$(Configuration)|$(Platform)'=='Release|x64'\">\n    <LinkIncremental>false</LinkIncremental>\n  </PropertyGroup>\n  <ItemDefinitionGroup Condition=\"'$(Configuration)|$(Platform)'=='Debug|Win32'\">\n    <ClCompile>\n      <WarningLevel>Level3</WarningLevel>\n      <Optimization>Disabled</Optimization>\n      <SDLCheck>true</SDLCheck>\n      <PreprocessorDefinitions>WIN32;_DEBUG;_CONSOLE;%(PreprocessorDefinitions)</PreprocessorDefinitions>\n      <ConformanceMode>true</ConformanceMode>\n    </ClCompile>\n    <Link>\n      <GenerateDebugInformation>true</GenerateDebugInformation>\n      <SubSystem>Console</SubSystem>\n    </Link>\n  </ItemDefinitionGroup>\n  <ItemDefinitionGroup Condition=\"'$(Configuration)|$(Platform)'=='Debug|x64'\">\n    <ClCompile>\n      <WarningLevel>Level3</WarningLevel>\n      <Optimization>Disabled</Optimization>\n      <SDLCheck>true</SDLCheck>\n      <PreprocessorDefinitions>_DEBUG;_CONSOLE;%(PreprocessorDefinitions)</PreprocessorDefinitions>\n      <ConformanceMode>true</ConformanceMode>\n    </ClCompile>\n    <Link>\n      <GenerateDebugInformation>true</GenerateDebugInformation>\n      <SubSystem>Console</SubSystem>\n    </Link>\n  </ItemDefinitionGroup>\n  <ItemDefinitionGroup Condition=\"'$(Configuration)|$(Platform)'=='Release|Win32'\">\n    <ClCompile>\n      <WarningLevel>Level3</WarningLevel>\n      <Optimization>MaxSpeed</Optimization>\n      <FunctionLevelLinking>true</FunctionLevelLinking>\n      <IntrinsicFunctions>true</IntrinsicFunctions>\n      <SDLCheck>true</SDLCheck>\n      <PreprocessorDefinitions>WIN32;NDEBUG;_CONSOLE;%(PreprocessorDefinitions)</PreprocessorDefinitions>\n      <ConformanceMode>true</ConformanceMode>\n    </ClCompile>\n    <Link>\n      <EnableCOMDATFolding>true</EnableCOMDATFolding>\n      <OptimizeReferences>true</OptimizeReferences>\n      <GenerateDebugInformation>true</GenerateDebugInformation>\n      <SubSystem>Console</SubSystem>\n    </Link>\n  </ItemDefinitionGroup>\n  <ItemDefinitionGroup Condition=\"'$(Configuration)|$(Platform)'=='Release|x64'\">\n    <ClCompile>\n      <WarningLevel>Level3</WarningLevel>\n      <Optimization>MaxSpeed</Optimization>\n      <FunctionLevelLinking>true</FunctionLevelLinking>\n      <IntrinsicFunctions>true</IntrinsicFunctions>\n      <SDLCheck>true</SDLCheck>\n      <PreprocessorDefinitions>NDEBUG;_CONSOLE;%(PreprocessorDefinitions)</PreprocessorDefinitions>\n      <ConformanceMode>true</ConformanceMode>\n    </ClCompile>\n    <Link>\n      <EnableCOMDATFolding>true</EnableCOMDATFolding>\n      <OptimizeReferences>true</OptimizeReferences>\n      <GenerateDebugInformation>true</GenerateDebugInformation>\n      <SubSystem>Console</SubSystem>\n    </Link>\n  </ItemDefinitionGroup>\n  <ItemGroup>\n    <ClCompile Include=\"\uc18c\uc2a4.cpp\" />\n  </ItemGroup>\n  <Import Project=\"$(VCTargetsPath)\\Microsoft.Cpp.targets\" />\n  <ImportGroup Label=\"ExtensionTargets\">\n  </ImportGroup>\n</Project>", "lang_cluster": "C", "compilation_error": true, "code_uid": "6a126837bf085ac56d4793bf9e42998b", "src_uid": "6119258322e06fa6146e592c63313df3", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint a[10000], ans[10000];\nint main()\n{\n    int  n=0,k=0;\n    scanf(\"%d %d\",&n,&k);\n    for(int i=0;i<n;++i)\n    scanf(\"%d\",&a[i]);\n    int j=0;\nwhile(j<k)\n{\n    for(int i=0;i<n;i++)\n    {   \n         if(i%k!=j)\n         {\n             if(a[i]==1) ans[j]++;\n             else ans[j]--;\n         }\n    }\n    j++;\n}\nfor(int i=0;i<k;++i)\nif(ans[i]<0)ans[i]=-ans[i];\nint max=-1;\nfor(int i=0;i<k;++i)\n{\n    if(ans[i]>max) max=ans[i];\n}\n\nprintf(\"%d\\n\",max);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "057381a65497e48b01b3ec5d2c95ae95", "src_uid": "6119258322e06fa6146e592c63313df3", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main()\n{\n\tint ar, al, br, bl;\n\tar = 0;\n\tal = 0;\n\tbr = 0;\n\tbl = 0\n\tscanf(\"%d%d\",&ar, &al);\n\tscanf(\"%d%d\",&br, &bl);\n\tif( (abs(ar - bl) < 3) || (abs(al - br) < 3) )\n\t{\n\t\tprintf(\"YES\");\n\t}\n\telse\n\t{\n\t\tprintf(\"NO\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f16d7e3565287d1d726c9e7fd2780b76", "src_uid": "36b7478e162be6e985613b2dad0974dd", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "91d5d048398317d88b9a59060ffcd160", "src_uid": "36b7478e162be6e985613b2dad0974dd", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int b_r, b_l, g_r, g_l;\n\n    scanf(\"%d %d %d %d\", &g_r, &g_l, &b_r, &b_l);\n\n    int tot1=abs(b_r - g_l);\n    int tot2=abs(b_l - g_r);\n\n    if(g_l-b_r<2 || b_r>g_l) && ((b_l / 3<=g_r)))\n        printf(\"YES\\n\");\n\n    else if((g_r-b_l<2 || b_l>g_r) && ((b_r / 3<= g_l)))\n        printf(\"YES\\n\");\n    else\n        printf(\"NO\\n\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "96f2d9d0e78bd2940d9b86b79e4989c3", "src_uid": "36b7478e162be6e985613b2dad0974dd", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,i=0,j=0,k=0,l=0,m=0;\n    int a[200],b[100];\n    \n        scanf(\"%d\",&b[0]);\n        scanf(\"%d\",&b[1]);\n        scanf(\"%d\",&a[0]);\n        scanf(\"%d\",&a[1]);\n    if(a[0]%2!=0 && a[0]>b[1])\n    a[0]=a[0]+1;\n    if(a[1]%2!=0 && a[1]>b[0])\n    a[1]=a[1]+1;\n    if(((a[0]-b[1])>=0 && ((a[0]/2)-1)<=b[1]) || ((a[1]-b[0])>=0 && ((a[1]/2)-1)<=b[0]))\n    printf(\"YES\");\n    \n    else if(((b[0]-a[1])>=0 && (b[0]-a[1])<2) || ((b[1]-a[0])>=0 && (b[1]-a[0])<2))\n    printf(\"YES\");\n    else\n    printf(\"NO\");\n    }\n    \n        return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e3c43881a9575ea991e9d9072413bbf7", "src_uid": "36b7478e162be6e985613b2dad0974dd", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#define MAX 7\n\nint mano_venus(char* venusString);\nint mano_marte(char* marteString);\nvoid comfortable(int venusiana, int marciano);\n\nint main(int argc, char const *argv[])\n{\n    char venus[MAX], marte[MAX];\n    int hand_venus, hand_mars;\n\n    gets(venus);\n    gets(marte);\n\n    hand_venus = mano_venus(venus);\n    hand_mars = mano_marte(marte);\n\n    //if (hand_venus != -1 && hand_mars != -1)\n    //{\n       comfortable(hand_venus, hand_mars);\n    //}\n   \n\n    return 0;\n}\n\nvoid comfortable(int venusiana, int marciano)\n{\n    if ((venusiana - marciano) == 0 || abs(venusiana - marciano) == 1)\n    {\n        printf(\"YES\");\n    }else{\n        printf(\"NO\");\n    }\n}\n\nint mano_venus(char* venusString)\n{\n    char auxVenus[MAX]; \n    strcpy(auxVenus, venusString);\n\n    char* manoVenusIzq = strtok(venusString, \" \");\n    char* manoVenusDer = strtok(NULL, \" \");\n\n    if (atoi(manoVenusIzq) > 0 && atoi(manoVenusIzq) <= 100)\n    {\n        if (atoi(manoVenusDer) > 0 && atoi(manoVenusDer) <= 100)\n        {\n            return atoi(manoVenusIzq);\n        }\n    }\n\n    return -1;\n}\n\nint mano_marte(char* marteString)\n{\n    char* manoMarteIzq = strtok(marteString, \" \");\n    char* manoMarteDer = strtok(NULL, \" \");\n\n    if (atoi(manoMarteIzq) > 0 && atoi(manoMarteIzq) < 100)\n    {\n        if (atoi(manoMarteDer) > 0 && atoi(manoMarteDer) < 100)\n        {\n            return atoi(manoMarteDer);\n        }\n    }\n\n    return -1;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7894639ebe3764a3371fc528ef661c99", "src_uid": "36b7478e162be6e985613b2dad0974dd", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <ctype.h>\n#define uLL unsigned long long\n#define LL long long\nuLL exgcd64(uLL a,uLL b,uLL *x,uLL *y)\n{\n\tstatic uLL gcd;\n\tif (a==0)\n\t{\n\t\t*x=0;*y=1;\n\t\treturn b;\n\t}\n\telse\n\t{\n\t\tgcd=exgcd64(b%a,a,y,x);\n\t\t*x-=(b/a)*(*y)+b;\n\t\t*y+=a;\n\t\treturn gcd;\n\t}\n}\nint main()\n{\n\t//freopen(\"in.in\",\"r\",stdin);\n\tLL i,j,k,n,m,a,b,c,d,x,y,vx,vy;\n\tscanf(\"%lld%lld%lld%lld%lld%lld\",&n,&m,&x,&y,&vx,&vy);\n\tif ((vx==0)||(vy==0))\n\t{\n\t\tif (vx==0)\n\t\t{\n\t\t\tif ((x==0)||(x==n))\n\t\t\t{\n\t\t\t\tif (vy<0) {printf(\"%lld 0\\n\",x);}\n\t\t\t\telse {printf(\"%lld %lld\\n\",x,m);}\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\"-1\\n\");\n\t\t\t}\n\t\t}\n\t\tif (vy==0)\n\t\t{\n\t\t\tif ((y==0)||(y==m))\n\t\t\t{\n\t\t\t\tif (vx<0) {printf(\"0 %lld\\n\",y);}\n\t\t\t\telse {printf(\"%lld %lld\\n\",n,y);}\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\"-1\\n\");\n\t\t\t}\n\t\t}\n\t}\n\telse\n\t{\n\t\tif (vx<0)\n\t\t{\n\t\t\tx=n-x;\n\t\t}\n\t\tif (vy<0)\n\t\t{\n\t\t\ty=m-y;\n\t\t}\n\t\tc=exgcd64(m,n,&a,&b);\n\t\td=x-y;\n\t\tif (d<0) {d=(d%m+m)%m;}\n\t\tif (d%c!=0) {printf(\"-1\\n\");}\n\t\telse\n\t\t{\n\t\t\tc=(d/c)*b;\n\t\t\tif (c==0) {c+=m;}\n\t\t\td=(c*n-(x-y))/m;\n\t\t\t//printf(\"%lld %lld %lld %lld\\n\",d,c,a,b);\n\t\t\tc=c&1;d=d&1;\n\t\t\tif (vx<0) {c=c^1;}\n\t\t\tif (vy<0) {d=d^1;}\n\t\t\tc=c*n;d=d*m;\n\t\t\tprintf(\"%lld %lld\\n\",c,d);\n\t\t}\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9bb13cb6098e9e64c96ce0aed6aab185", "src_uid": "6c4ddc688c5aab1432e7328d27c4d8ee", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <ctype.h>\n#define uLL unsigned long long\n#define LL long long\nuLL exgcd64(uLL a,uLL b,uLL *x,uLL *y)\n{\n\tstatic uLL gcd;\n\tif (a==0)\n\t{\n\t\t*x=0;*y=1;\n\t\treturn b;\n\t}\n\telse\n\t{\n\t\tgcd=exgcd64(b%a,a,y,x);\n\t\t*x-=(b/a)*(*y)+b;\n\t\t*y+=a;\n\t\treturn gcd;\n\t}\n}\nint main()\n{\n\tfreopen(\"in.in\",\"r\",stdin);\n\tLL i,j,k,n,m,a,b,c,d,x,y,vx,vy;\n\tscanf(\"%lld%lld%lld%lld%lld%lld\",&n,&m,&x,&y,&vx,&vy);\n\tif ((vx==0)||(vy==0))\n\t{\n\t\tif (vx==0)\n\t\t{\n\t\t\tif ((x==0)||(x==n))\n\t\t\t{\n\t\t\t\tif (vy<0) {printf(\"%lld 0\\n\",x);}\n\t\t\t\telse {printf(\"%lld %lld\\n\",x,m);}\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\"-1\\n\");\n\t\t\t}\n\t\t}\n\t\tif (vy==0)\n\t\t{\n\t\t\tif ((y==0)||(y==m))\n\t\t\t{\n\t\t\t\tif (vx<0) {printf(\"0 %lld\\n\",y);}\n\t\t\t\telse {printf(\"%lld %lld\\n\",n,y);}\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\"-1\\n\");\n\t\t\t}\n\t\t}\n\t}\n\telse\n\t{\n\t\tif (vx<0)\n\t\t{\n\t\t\tx=n-x;\n\t\t}\n\t\tif (vy<0)\n\t\t{\n\t\t\ty=m-y;\n\t\t}\n\t\t//printf(\"%lld %lld %lld %lld\\n\",n,m,x,y);\n\t\tc=exgcd64(m,n,&a,&b);\n\t\td=x-y;\n\t\tif (d<0) {d=(d%m+m)%m;}\n\t\tif (d%c!=0) {printf(\"-1\\n\");}\n\t\telse\n\t\t{\n\t\t\td=(d/c)*(b/c)%(m/c);\n\t\t\tif (d==0) {d+=m/c;}\n\t\t\tc=d;\n\t\t\td=(c*n-(x-y))/m;\n\t\t\t//printf(\"%lld %lld %lld %lld\\n\",c,d,n,m);\n\t\t\tc=c&1;d=d&1;\n\t\t\tif (vx<0) {c=c^1;}\n\t\t\tif (vy<0) {d=d^1;}\n\t\t\tc=c*n;d=d*m;\n\t\t\tprintf(\"%lld %lld\\n\",c,d);\n\t\t}\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7bfa5abfb5dbf6bf167506f949978cb8", "src_uid": "6c4ddc688c5aab1432e7328d27c4d8ee", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <ctype.h>\n#define uLL unsigned long long\n#define LL long long\nuLL exgcd64(uLL a,uLL b,uLL *x,uLL *y)\n{\n\tstatic uLL gcd;\n\tif (a==0)\n\t{\n\t\t*x=0;*y=1;\n\t\treturn b;\n\t}\n\telse\n\t{\n\t\tgcd=exgcd64(b%a,a,y,x);\n\t\t*x-=(b/a)*(*y)+b;\n\t\t*y+=a;\n\t\treturn gcd;\n\t}\n}\nint main()\n{\n\tfreopen(\"in.in\",\"r\",stdin);\n\tLL i,j,k,n,m,a,b,c,d,x,y,vx,vy;\n\tscanf(\"%lld%lld%lld%lld%lld%lld\",&n,&m,&x,&y,&vx,&vy);\n\tif ((vx==0)||(vy==0))\n\t{\n\t\tif (vx==0)\n\t\t{\n\t\t\tif ((x==0)||(x==n))\n\t\t\t{\n\t\t\t\tif (vy<0) {printf(\"%lld 0\\n\",x);}\n\t\t\t\telse {printf(\"%lld %lld\\n\",x,m);}\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\"-1\\n\");\n\t\t\t}\n\t\t}\n\t\tif (vy==0)\n\t\t{\n\t\t\tif ((y==0)||(y==m))\n\t\t\t{\n\t\t\t\tif (vx<0) {printf(\"0 %lld\\n\",y);}\n\t\t\t\telse {printf(\"%lld %lld\\n\",n,y);}\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\"-1\\n\");\n\t\t\t}\n\t\t}\n\t}\n\telse\n\t{\n\t\tif (vx<0)\n\t\t{\n\t\t\tx=n-x;\n\t\t}\n\t\tif (vy<0)\n\t\t{\n\t\t\ty=m-y;\n\t\t}\n\t\t//printf(\"%lld %lld %lld %lld\\n\",n,m,x,y);\n\t\tc=exgcd64(m,n,&a,&b);\n\t\td=x-y;\n\t\tif (d<0) {d=(d%m+m)%m;}\n\t\tif (d%c!=0) {printf(\"-1\\n\");}\n\t\telse\n\t\t{\n\t\t\tc=(d/c)*(b/c)%m/c;\n\t\t\tif (c==0) {c+=m;}\n\t\t\td=(c*n-(x-y))/m;\n\t\t\t//printf(\"%lld %lld %lld %lld\\n\",c,d,n,m);\n\t\t\tc=c&1;d=d&1;\n\t\t\tif (vx<0) {c=c^1;}\n\t\t\tif (vy<0) {d=d^1;}\n\t\t\tc=c*n;d=d*m;\n\t\t\tprintf(\"%lld %lld\\n\",c,d);\n\t\t}\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "eebaef266b9ffaad401a6eb097ed77c2", "src_uid": "6c4ddc688c5aab1432e7328d27c4d8ee", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <ctype.h>\n#define uLL unsigned long long\n#define LL long long\nuLL exgcd64(uLL a,uLL b,uLL *x,uLL *y)\n{\n\tstatic uLL gcd;\n\tif (a==0)\n\t{\n\t\t*x=0;*y=1;\n\t\treturn b;\n\t}\n\telse\n\t{\n\t\tgcd=exgcd64(b%a,a,y,x);\n\t\t*x-=(b/a)*(*y)+b;\n\t\t*y+=a;\n\t\treturn gcd;\n\t}\n}\nint main()\n{\n//\tfreopen(\"in.in\",\"r\",stdin);\n\tLL i,j,k,n,m,a,b,c,d,x,y,vx,vy,e;\n\tscanf(\"%lld%lld%lld%lld%lld%lld\",&n,&m,&x,&y,&vx,&vy);\n\tif ((vx==0)||(vy==0))\n\t{\n\t\tif (vx==0)\n\t\t{\n\t\t\tif ((x==0)||(x==n))\n\t\t\t{\n\t\t\t\tif (vy<0) {printf(\"%lld 0\\n\",x);}\n\t\t\t\telse {printf(\"%lld %lld\\n\",x,m);}\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\"-1\\n\");\n\t\t\t}\n\t\t}\n\t\tif (vy==0)\n\t\t{\n\t\t\tif ((y==0)||(y==m))\n\t\t\t{\n\t\t\t\tif (vx<0) {printf(\"0 %lld\\n\",y);}\n\t\t\t\telse {printf(\"%lld %lld\\n\",n,y);}\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\"-1\\n\");\n\t\t\t}\n\t\t}\n\t}\n\telse\n\t{\n\t\tif (vx<0)\n\t\t{\n\t\t\tx=n-x;\n\t\t}\n\t\tif (vy<0)\n\t\t{\n\t\t\ty=m-y;\n\t\t}\n\t\t//printf(\"%lld %lld %lld %lld\\n\",n,m,x,y);\n\t\tc=exgcd64(m,n,&a,&b);\n\t\te=c;\n\t\td=x-y;\n\t\tif (d<0) {d=(d%m+m)%m;}\n\t\tif (d%c!=0) {printf(\"-1\\n\");}\n\t\telse\n\t\t{\n\t\t\t//printf(\"%lld %lld %lld\\n\",b%c,d,((d/c)*(b/1)%(m/c)*n)%m);\n\t\t\td=(d/c)*(b)%(m/c);\n\t\t\tif (d==0) {d+=m/c;}\n\t\t\tc=d;\n\t\t\td=(c*n-(x-y))/m;\n/*\t\t\tif (d<0)\n\t\t\t{\n\t\t\t\ta=(-d)/c+1;\n\t\t\t\tc+=a*(m/e);\n\t\t\t\td+=a*(n/e);\n\t\t\t}*/\n\t\t\t//printf(\"%lld %lld %lld %lld\\n\",c,d*m,(c*n-(x-y))%m,x-y);\n\t\t\tc=c&1;d=d&1;\n\t\t\tif (vx<0) {c=c^1;}\n\t\t\tif (vy<0) {d=d^1;}\n\t\t\tc=c*n;d=d*m;\n\t\t\tprintf(\"%lld %lld\\n\",c,d);\n\t\t}\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f0ee009f8842ce2503c10ee5ce425f59", "src_uid": "6c4ddc688c5aab1432e7328d27c4d8ee", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <ctype.h>\n#define uLL unsigned long long\n#define LL long long\nuLL exgcd64(uLL a,uLL b,uLL *x,uLL *y)\n{\n\tstatic uLL gcd;\n\tif (a==0)\n\t{\n\t\t*x=0;*y=1;\n\t\treturn b;\n\t}\n\telse\n\t{\n\t\tgcd=exgcd64(b%a,a,y,x);\n\t\t*x-=(b/a)*(*y)+b;\n\t\t*y+=a;\n\t\treturn gcd;\n\t}\n}\nint main()\n{\n//\tfreopen(\"in.in\",\"r\",stdin);\n\tLL i,j,k,n,m,a,b,c,d,x,y,vx,vy,e;\n\tscanf(\"%lld%lld%lld%lld%lld%lld\",&n,&m,&x,&y,&vx,&vy);\n\tif ((vx==0)||(vy==0))\n\t{\n\t\tif (vx==0)\n\t\t{\n\t\t\tif ((x==0)||(x==n))\n\t\t\t{\n\t\t\t\tif (vy<0) {printf(\"%lld 0\\n\",x);}\n\t\t\t\telse {printf(\"%lld %lld\\n\",x,m);}\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\"-1\\n\");\n\t\t\t}\n\t\t}\n\t\tif (vy==0)\n\t\t{\n\t\t\tif ((y==0)||(y==m))\n\t\t\t{\n\t\t\t\tif (vx<0) {printf(\"0 %lld\\n\",y);}\n\t\t\t\telse {printf(\"%lld %lld\\n\",n,y);}\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\"-1\\n\");\n\t\t\t}\n\t\t}\n\t}\n\telse\n\t{\n\t\tif (vx<0)\n\t\t{\n\t\t\tx=n-x;\n\t\t}\n\t\tif (vy<0)\n\t\t{\n\t\t\ty=m-y;\n\t\t}\n\t\t//printf(\"%lld %lld %lld %lld\\n\",n,m,x,y);\n\t\tc=exgcd64(m,n,&a,&b);\n\t\te=c;\n\t\td=x-y;\n\t\tif (d<0) {d=(d%m+m)%m;}\n\t\tif (d%c!=0) {printf(\"-1\\n\");}\n\t\telse\n\t\t{\n\t\t\t//printf(\"%lld %lld %lld\\n\",b%c,d,((d/c)*(b/1)%(m/c)*n)%m);\n\t\t\td=(d/c)*(b)%(m/c);\n\t\t\tif (d==0) {d+=m/c;}\n\t\t\tc=d;\n\t\t\td=(c*n-(x-y))/m;\n\t\t\tif (d<0)\n\t\t\t{\n\t\t\t\ta=(-d)/c+1;\n\t\t\t\tc+=a*(m/e);\n\t\t\t\td+=a*(n/e);\n\t\t\t}\n\t\t\t//printf(\"%lld %lld %lld %lld\\n\",c,d*m,(c*n-(x-y))%m,x-y);\n\t\t\tc=c&1;d=d&1;\n\t\t\tif (vx<0) {c=c^1;}\n\t\t\tif (vy<0) {d=d^1;}\n\t\t\tc=c*n;d=d*m;\n\t\t\tprintf(\"%lld %lld\\n\",c,d);\n\t\t}\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "cc47d189fbd546d445246a8533753238", "src_uid": "6c4ddc688c5aab1432e7328d27c4d8ee", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n long long int a,b,c,t;\n scanf(\"%I64d%I64d%I64d\",&a,&b,&c);\n\n    if(a>b)\n     {t=a;\n     a=b;\n     b=t;}\n\n   if(b>c)\n   { t=b;\n      b=c;\n      c=t;}\n   if(a>b)\n   {  t=a;\n      a=b;\n      b=t;\n      }\n\n\n\n\n   if(a==0&&b==0)\n    printf(\"0\");\n    else\n    {  if((b-a)%2==0)\n      printf(\"%I64d\",b);\n      else\n      printf(\"%I64d\",c);\n      }\n      return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6ef2ce3db0e1aac4067ac9e66e42d3bc", "src_uid": "b8008caf788336775cb8ebb76478b04c", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n   long long int a[3],i,j,k;\n    for(i=0;i<3;i++)\n    scanf(\"%I64d\",&a[i]);\n    for(i=0;i<2;i++)\n    for(j=i+1;j<3;j++)\n    {\n        if(a[i]>a[j])\n        {\n            k=a[i];a[i]=a[j];a[j]=k;\n        }}\n   if((a[1]-a[0])%2)\n   printf(\"%I64d\",a[2]);\n   else printf(\"%I64d\",a[1]);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "021e5ecad3efd037e398a8dfd3ad5b4d", "src_uid": "b8008caf788336775cb8ebb76478b04c", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n   long long int a[3],k;\n   int i,j;\n    for(i=0;i<3;i++)\n    scanf(\"%I64d\",&a[i]);\n    for(i=0;i<2;i++)\n    for(j=i+1;j<3;j++)\n    {\n        if(a[i]>a[j])\n        {\n            k=a[i];a[i]=a[j];a[j]=k;\n        }}\n   if((a[1]-a[0])%2)\n   printf(\"%I64d\",a[2]);\n   else printf(\"%I64d\",a[1]);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "871c17e82fbaa6576300e2b5582aa8b7", "src_uid": "b8008caf788336775cb8ebb76478b04c", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n   long long int a[3],i,j,k;\n    for(i=0;i<3;i++)\n    scanf(\"%l64d\",&a[i]);\n    for(i=0;i<2;i++)\n    for(j=i+1;j<3;j++)\n    {\n        if(a[i]>a[j])\n        {\n            k=a[i];a[i]=a[j];a[j]=k;\n        }}\n   if((a[1]-a[0])%2)\n   printf(\"%l64d\",a[2]);\n   else printf(\"%l64d\",a[1]);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cc099bc1e155f9d2454a663a3f028fc2", "src_uid": "b8008caf788336775cb8ebb76478b04c", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{int a[3]={0},b,c,i,j,k=0,t;\nscanf(\"%d %d %d\",&a[0],&a[1],&a[2]);\nfor(i=0;i<3;i++)\nfor(j=0;j<3-i-1;j++)\nif(a[j]<a[j+1])\n{t=a[j];\na[j]=a[j+1];\na[j+1]=t;}\n\nwhile(a[1]!=0)\n{for(i=1;i>=0;i--)\n{    if(a[i]-a[i+1]==0)\n    {\n        k+=a[i];\n        goto flag;\n    }\n}\na[1]--;a[0]--;\na[2]++;k++;\nif(a[1]<a[2])\n{t=a[1];\na[1]=a[2];\na[2]=t;}\n}flag:\nprintf(\"%d\",k);\n\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e983e54f5dc189805b60371a5d3c0c6a", "src_uid": "b8008caf788336775cb8ebb76478b04c", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <string.h>\n#include <algorithm>\nusing namespace std;\n\n\nlong long int bSearch(long long n,long long int e)  {\n\tlong long int m = n ;\n\tint a = 0;\n\twhile(m){\n\t\ta++;\n\t\tm /= 2;\n\t}  \n    long long mid, left = 1, right = (long long) (pow(2.0,a)-1);  \n    long long num = 0;\n    while(left <= right)  {  \n        mid = (left + right) >> 1;  \n        if(mid >= e)\n        \tright = mid - 1;\n        else {\n        \tnum += n / 2 + n % 2;\n        \tleft = mid + 1;\n        }\n        n /= 2;  \n    }\n    return num;  \n}  \n\n\nint main(){\n\tlong long n , l , r ;\n\twhile(scanf(\"%lld%lld%lld\",&n,&l,&r)!=EOF){\n\t\tlong long sum;\n\t\tsum = bSearch(n,r+1)-bSearch(n,l) ;\n\t\tprintf(\"%lld\\n\",sum);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3ac9e61efe93034bfb0d8c67a4eeee2b", "src_uid": "3ac61b1f8deee7911b1055c243f5eb6a", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define MAXN 100010\nlong long a[MAXN],b[MAXN];\nint sign,flag; \nint main(){\n\tvoid crash(long long a[],long long b[]);\n\tlong long n;\n\tint r,l;\n\tint i,count\uff1b\n\tfor(i=0;i<MAXN;i++){\n\t\ta[i]=-1;\n\t\tb[i]=-1;\n\t}\n\tscanf(\"%lld %d %d\",&n,&r,&l);\n\ta[0]=n/2\n\ta[1]=n%2;\n\ta[2]=n/2;\n\tcrash(a,b);\n\tcount=0;\n\tif(sign>0){\n\t\tfor(i=r-1;i<=l-1;i++){\n\t\t\tif(a[i]==1){\n\t\t\t\tcount++; \n\t\t\t}\n\t\t}\n    }\n\telse{\n\t\tfor(i=r-1;i<=l-1;i++){\n\t\t\tif(b[i]==1){\n\t\t\t\tcount++; \n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\",count);\n\treturn 0;\n} \n\nvoid crash(long long a[],long long b[]){\n\tsign=1,flag=0;\n\tint i,quo,mod,count;\n\tfor(i=0,count=0;a[i]!=-1;i++){\n\t\tif(a[i]!=1&&a[i]!=0){\n\t\t\tquo=a[i]/2;\n\t\t\tmod=a[i]%2;\n\t\t\tb[count]=quo;\n\t\t\tb[count+1]=mod;\n\t\t\tb[count+2]=quo;\n\t\t\tcount=count+3;\n\t\t\tflag=1;\n\t\t}\n\t\telse{\n\t\t\tb[count]=a[i];\n\t\t\tcount++;\n\t\t}\n\t}\n\tsign=sign*(-1);\n\tif(flag==1){\n\t\tcrash(b,a);\n\t}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "59d481dfd0f8f6ec96659e59028e930e", "src_uid": "3ac61b1f8deee7911b1055c243f5eb6a", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <cstdio>\n\ntypedef long long ll;\n\nll solve(ll n, ll l, ll r, ll x, ll y) {\n    if (r < x || l > y || n == 0) return 0;\n    if (n == 1) return 1;\n    ll mid = (x + y) / 2;\n    return solve(n / 2, l, r, x, mid - 1) + solve(n % 2, l, r, mid, mid) + solve(n / 2, l, r, mid + 1, y);\n}\n\nint main() {\n    ll n, l, r;\n    ll ans;\n    scanf(\"%lld %lld %lld\", &n, &l, &r);\n    ll max = 1; while (max <= n) { max *= 2; }\n    ans = solve(n, l, r, 1, max);\n    printf(\"%lld\\n\", ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "015474abeb1114a412002a5601295173", "src_uid": "3ac61b1f8deee7911b1055c243f5eb6a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <string.h>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\n\n\nlong long int bSearch(long long n,long long int e)  {\n\tlong long int m = n ;\n\tint a = 0;\n\twhile(m){\n\t\ta++;\n\t\tm /= 2;\n\t}  \n    long long mid, left = 1, right = (int) (pow(2.0,a)-1);  \n    long long num = 0;\n    while(left <= right)  {  \n        mid = (left + right) >> 1;  \n        if(mid >= e)\n        \tright = mid - 1;\n        else {\n        \tnum += n / 2 + n % 2;\n        \tleft = mid + 1;\n        }\n        n /= 2;  \n    }\n    return num;  \n}  \n\n\nint main(){\n\tlong long n , l , r ;\n\twhile(scanf(\"%lld%lld%lld\",&n,&l,&r)!=EOF){\n\t\tlong long sum;\n\t\tlong long a;\n\t\tsum = bSearch(n,r+1)-bSearch(n,l) ;\n\t\tprintf(\"%lld\\n\",sum);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8d0d77d54abec2c5439a319be3de4b8a", "src_uid": "3ac61b1f8deee7911b1055c243f5eb6a", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n\nusing namespace std;\ntypedef __int64 ll;\n\n//L,R\u662f\u67e5\u8be2\u533a\u95f4\uff0cl,r\u662f\u8ba1\u7b97\u51fa\u7684\u5206\u89e3\u4ee5\u540e\u7684\u957f\u5ea6\nll query(ll L ,ll R,ll l,ll r, ll n) \n{\n      if(l == r)\n      return n;\n      \n      //\u5206\u6cbb\n      ll mid = (l+r)>>1;\n      ll ans = 0;\n      \n      //\u5728\u5de6\u4fa7\u8fdb\u884c\u9012\u5f52\n      if(L <= mid - 1)\n            ans += query(L,R,l,mid - 1,n>>1);\n      //\u5728\u53f3\u4fa7\u8fdb\u884c\u9012\u5f52\u67e5\u627e\n      if(R >= mid + 1)\n            ans += query(L,R,mid + 1,r,n>>1);\n      //\u8fd9\u4e2a\u65f6\u5019\u5bf9mid\u8fdb\u884c\u5904\u7406\uff0c\u5224\u65ad\u6761\u4ef6\u662fmid\u5728\u67e5\u8be2\u8303\u56f4\u533a\u95f4\u5185\n      if(mid <= R && mid >= L)\n            ans += n%2;\n      \n      return ans;\n}\n\n//\u8be5\u51fd\u6570\u662f\u7528\u6765\u6c42\u5206\u89e3n\u4ee5\u540e\u7684\u4f4d\u6570\n//\u4e5f\u53ef\u4ee5\u770b\u51fa\u4e00\u4e2a\u89c4\u5f8b\uff0c\u67d0\u4e2a\u6570\u7684\u5c55\u5f00\u4ee5\u540e\u7684\u4f4d\u6570\u662f\u521a\u597d\u5927\u4e8e\u4e8c\u6b21\u5e42\u7684\u503c\u51cf\u53bb1\uff0c\u6bd4\u59823\u7684\u5c55\u5f00\u4e3a4-1\uff0c4\u7684\u5c55\u5f00\u4e3a8-1\nll f(ll n)  \n{\n      if(n == 1 || n == 0)\n            return 1;\n      return 2 * f(n >> 1) + 1;\n}\n\nint main()\n{\n    ll n;\n    ll l, r;\n    \n    cin >> n >> l >> r;\n    \n    cout << query(l,r,1,f(n),n) << endl;   \n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "903c7d81ea35855b75f1cbaca32f2189", "src_uid": "3ac61b1f8deee7911b1055c243f5eb6a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{ int aux,m,n,c,k,d,min,j=0,s,i;\nint t[1000000000];\nscanf(\"%d\",&n);\nfor(i=1;i<n;i++)\n{s=i;\nd=i;\ndo\n{s=s+(d%10);\nd=d/10; }\nwhile(d!=0);\nif(s==n)\n{t[j]=i;\nj++;}}\nfor(k=0;k<(j-1);k++)\n{min=k;\nfor(c=k+1;c<j;c++)\n{if(t[c]<t[min])\n{aux=t[min];\nt[min]=t[c];\nt[c]=aux;}}}\nprintf(\"%d\",j);\nprintf(\"\\n\");\nfor(m=0;m<j;m++)\nprintf(\"%d \",t[m]);\nreturn 0;}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ec90f55650816d612b40e950aded02fc", "src_uid": "ae20ae2a16273a0d379932d6e973f878", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include \"stdio.h\"\nint number[100000000];\nint main()\n{\n    int n,k;\n    while(scanf(\"%d\",&n)!=EOF)\n    {\n        int sum = 0;\n        int num = 0;\n        for(int i = n/2;i<n;i++)\n        {\n            sum += i;\n            int count =0;\n            int a = i;\n            while(a!=0)\n            {\n               count++;\n               a /= 10;\n            }\n            int max = 1;\n            for(int j = 0;j<count;j++)\n            {\n                max *= 10;\n            }\n            int b = i;\n            while(max!=0)\n            {\n                sum += b/max;\n                b = b%max;\n                max /= 10;\n            }\n            if (sum==n)\n            {\n                num++;\n                number[num] = i;\n            }\n        }\n        printf(\"%d\\n\",num);\n        for(int i = 0;i<num;i++)\n        {\n            printf(\"%d\\n\",number[i]);\n        }\n    }", "lang_cluster": "C", "compilation_error": true, "code_uid": "4cbe7740e2dc087273d699fcc812fc01", "src_uid": "ae20ae2a16273a0d379932d6e973f878", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include \"stdio.h\"\n\nint main()\n{\n    int n,k;\n    int number[1000000000];\n    while(scanf(\"%d\",&n)!=EOF)\n    {\n        int sum = 0;\n        int num = 0;\n        for(int i = 10;i<n;i++)\n        {\n            sum += i;\n            int count =0;\n            int a = i;\n            while(a!=0)\n            {\n               count++;\n               a /= 10;\n            }\n            int max = 1;\n            for(int j = 0;j<count;j++)\n            {\n                max *= 10;\n            }\n            int b = i;\n            while(max!=0)\n            {\n                sum += b/max;\n                b = b%max;\n                max /= 10;\n            }\n            if (sum==n)\n            {\n                num++;\n                number[num] = i;\n            }\n        }\n        printf(\"%d\\n\",num);\n        for(int i = 0;i<num;i++)\n        {\n            printf(\"%d\\n\",number[i]);\n        }\n    }", "lang_cluster": "C", "compilation_error": true, "code_uid": "a0b9815841d2d432681c16d6ce536d8a", "src_uid": "ae20ae2a16273a0d379932d6e973f878", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include \"stdio.h\"\nint number[1000000000];\nint main()\n{\n    int n,k;\n    while(scanf(\"%d\",&n)!=EOF)\n    {\n        int sum = 0;\n        int num = 0;\n        for(int i = 10;i<n;i++)\n        {\n            sum += i;\n            int count =0;\n            int a = i;\n            while(a!=0)\n            {\n               count++;\n               a /= 10;\n            }\n            int max = 1;\n            for(int j = 0;j<count;j++)\n            {\n                max *= 10;\n            }\n            int b = i;\n            while(max!=0)\n            {\n                sum += b/max;\n                b = b%max;\n                max /= 10;\n            }\n            if (sum==n)\n            {\n                num++;\n                number[num] = i;\n            }\n        }\n        printf(\"%d\\n\",num);\n        for(int i = 0;i<num;i++)\n        {\n            printf(\"%d\\n\",number[i]);\n        }\n    }", "lang_cluster": "C", "compilation_error": true, "code_uid": "0d7a284b870750a7a55227b4f73be019", "src_uid": "ae20ae2a16273a0d379932d6e973f878", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{ int n,k=0,d,j,s,i;\nint *t;\nscanf(\"%d\",&n);\nint t[n];\nfor(i=1;i<n;i++)\n{s=i;\nd=i;\ndo\n{s=s+(d%10);\nd=d/10; }\nwhile(d!=0);\nif(s==n)\n{t[k]=i;\nk++;}}\nprintf(\"%d\",k);\nprintf(\"\\n\");\nfor(j=0;j<k;j++)\nprintf(\"%d \",t[j]);\nreturn 0;}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "35ce5d75b16e91debdc21e94f4a54547", "src_uid": "ae20ae2a16273a0d379932d6e973f878", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <limits.h>\n#include <stdio.h>\n#include <stdlib.h>\n#define DIJKSTRA\n#ifndef _TJYTLXWXHYZQFW_HEAP_H\n#define _TJYTLXWXHYZQFW_HEAP_H\n#include <assert.h>\n#include <stdlib.h>\nstruct heap {\n        int cap, last;\n        void **cell; \n\tint (*cmp)(const void *, const void *);\n\t#ifdef DIJKSTRA\n\tvoid (*set)(void *, const int);\n\tvoid (*swap)(void *, void *);\n\t#endif\n};\nstruct heap *heap_new(int cap, int (*cmp)(const void *, const void*)\n\t#ifdef DIJKSTRA\n\t,void (*set)(void *, const int), void (*swap)(void *, void *)\n\t#endif\n)\n{\n        struct heap *h;\n        assert(h = malloc(sizeof(struct heap)));\n        h->cap = ++cap;\n\th->last = 0;\n        assert(h->cell = malloc(sizeof(void*) * cap));\n\th->cmp = cmp;\n\t#ifdef DIJKSTRA\n\th->set = set;\n\th->swap = swap;\n\t#endif\n        return h;\n}\nvoid heap_destroy(struct heap *h)\n{\n        if (h)\n                free(h->cell);\n        free(h);\n}\nvoid heap_pdown(int x, struct heap *h)\n{\n        int c, d;\n        void *tmp;\n        while ((c = 2 * x) <= h->last) {\n                d = c + 1;\n                if (d <= h->last && h->cmp(h->cell[d], h->cell[c]) < 0)\n                        c = d;\n                if (h->cmp(h->cell[x], h->cell[c]) < 0)\n                        break;\n                tmp = h->cell[c];\n                h->cell[c] = h->cell[x];\n                h->cell[x] = tmp;\n\t\t#ifdef DIJKSTRA\n\t\th->swap(h->cell[c], h->cell[x]);\n\t\t#endif\n                x = c;\n        }\n}\nvoid heap_pup(int x, struct heap *h)\n{\n        int p;\n        void *tmp;\n        while ((p = x / 2) >= 1) {\n                if (h->cmp(h->cell[p], h->cell[x]) < 0)\n                        break;\n                tmp = h->cell[x];\n                h->cell[x] = h->cell[p];\n                h->cell[p] = tmp;\n\t\t#ifdef DIJKSTRA\n\t\th->swap(h->cell[x], h->cell[p]);\n\t\t#endif\n                x = p;\n        }\n}\nint heap_insert(void *e, struct heap *h)\n{\n        if (h->last >= h->cap)\n                return -1;\n        h->cell[++h->last] = e;\n\t#ifdef DIJKSTRA\n\th->set(h->cell[h->last], h->last);\n\t#endif\n        heap_pup(h->last, h);\n        return 0;\n}\nvoid *heap_del(struct heap *h)\n{\n        void *ret;\n        if (h->last <= 0)\n                return NULL;\n        ret = h->cell[1];\n        h->cell[1] = h->cell[h->last--];\n\t#ifdef DIJKSTRA\n\th->set(h->cell[1], 1);\n\t#endif\n        heap_pdown(1, h);\n        return ret;\n}\n#endif\n\n#define LEN 20000001\nstruct node {\n\tlong long cost;\n\tchar color;\n\tlong long id;\n\tint hidx;\n};\nint compare(const void *x, const void *y)\n{\n\treturn ((struct node *)x)->cost - ((struct node *)y)->cost;\n}\nvoid sethidx(void *node, const int idx)\n{\n\t((struct node *)node)->hidx = idx;\n}\nvoid swaphidx(void *x, void *y)\n{\n\tint tmp;\n\ttmp = ((struct node *)x)->hidx;\n\t((struct node *)x)->hidx = ((struct node *)y)->hidx;\n\t((struct node *)y)->hidx = tmp;\n}\nlong long len;\n#define OOS(x) ((x) < 0 || (x) > len)\nlong long x, y;\nstruct node nodes[LEN];\nvoid handle(int id, long long cost, struct heap *h)\n{\n\tstruct node *next;\n\tif (OOS(id))\n\t\treturn;\n\tnext = &nodes[id];\n\tif (next->color == 2)\n\t\treturn;\n\tif (cost >= next->cost)\n\t\treturn;\n\tnext->cost = cost;\n\tif (next->color == 0) {\n\t\theap_insert(next, h);\n\t\tnext->color = 1;\n\t} else {\n\t\theap_pup(next->hidx, h);\n\t}\n}\nlong long dijkstra(void)\n{\n\tstruct heap *h;\n\tstruct node *node;\n\th = heap_new(LEN, compare, sethidx, swaphidx);\n\theap_insert(&nodes[0], h);\n\tnodes[0].color = 1;\n\tnodes[0].cost = 0;\n\twhile ((node = heap_del(h)) != NULL) {\n\t\tnode->color = 2;\n\t\tif (node->id == len)\n\t\t\treturn node->cost;\n\t\thandle(node->id + 1, node->cost + x, h);\n\t\thandle(node->id - 1, node->cost + x, h);\n\t\thandle(node->id * 2, node->cost + y, h);\n\t}\n\treturn -1;\n}\nint main(void)\n{\n\tlong long i, imax;\n\tscanf(\"%lld%lld%lld\", &len, &x, &y);\n\tfor (imax = len * 2, i = 0; i <= imax; ++i) {\n\t\tnodes[i].id = i;\n\t\tnodes[i].cost = LLONG_MAX;\n\t\tnodes[i].color = 0;\n\t}\n\tprintf(\"%lld\\n\", dijkstra());\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8d4bbbb435126d30a95785c6c7b83af5", "src_uid": "0f270af00be2a523515d5e7bd66800f6", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint dp[1<<24];\nvoid solve(const int n, const int x, const int y) {\n    dp[1] = x;\n    for(int i = 1; i <= n; i++)\n        if(i & 1) dp[i] = dp[i - 1] + x;\n        else dp[i] = dp[i >> 1] + y < dp[i - 1] + x ? dp[i >> 1 + y] : dp[i - 1] + x;\n    return dp[n];\n}\n\nint main(void) {\n    int n, x, y;\n    scanf(\"%d%d%d\", &n, &x, &y);\n    printf(\"%d\", solve(n, x, y));\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8b4156553af5a6a37a507bf14ba63278", "src_uid": "0f270af00be2a523515d5e7bd66800f6", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint dp[1<<24];\n\nvoid solve(int n, int x, int y) {\n    dp[1] = x;\n    for(int i = 1; i <= n; i++)\n        if(i & 1) dp[i] = dp[i - 1] + x;\n        else dp[i] = min(dp[i >> 1] + y, dp[i - 1] + x);\n    return dp[n];\n}\n\nint main(void) {\n    int n, x, y;\n    scanf(\"%d%d%d\", &n, &x, &y);\n    printf(\"%d\", solve(n, x, y));\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fec941626bd3a27a4d5cfec8bb69bf89", "src_uid": "0f270af00be2a523515d5e7bd66800f6", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n\n//////////////////////////////////////////\n//    \u02fc\u00b7\ufffd\ufffd                            // \n//          \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd                      // \n//    by :                              //\n//         \u02e7\ufffd\ufffd\ufffd\ufffd                       // \n////////////////////////////////////////// \n \ndouble final(double n,double a,double b) {\n\tdouble t;     //\ufffd\ufffd\u02b1\ufffd\ufffd \n\tdouble t0;    //\ufffd\ufffdkg+1\ufffd\ufffd\u00b7\ufffd\ufffd\ufffd\ufffd\ufffd\u0135\ufffd\u02b1\ufffd\ufffd   \ufffd\ufffd\u00b7\u04bb \n\tdouble t1;    //\ufffd\ufffdkg-1\ufffd\ufffd\u00b7\ufffd\ufffd\ufffd\ufffd\ufffd\u0135\ufffd\u02b1\ufffd\ufffd   \ufffd\ufffd\u00b7\ufffd\ufffd \n\tint tk = 0;   //\ufffd\ufffdkg+1\ufffd\ufffd\u00b7\ufffd\ufffd\ufffd\u00b3\ufffd\ufffd\ufffd 2 \ufffd\u0134\ufffd\ufffd\ufffd \n\tint tk2 = 0;  //\ufffd\ufffdkg+1\ufffd\ufffd\u00b7\ufffd\ufffd\ufffd\u00bc\u04fc\ufffd 1 \ufffd\u0134\ufffd\ufffd\ufffd \n\tint dk = 0;   //\ufffd\ufffdkg-1\ufffd\ufffd\u00b7\ufffd\ufffd\ufffd\u00b3\ufffd\ufffd\ufffd 2 \ufffd\u0134\ufffd\ufffd\ufffd\n\tint dk2 = 0;  //\ufffd\ufffdkg-1\ufffd\ufffd\u00b7\ufffd\ufffd\ufffd\u00bc\u04fc\ufffd 1 \ufffd\u0134\ufffd\ufffd\ufffd\n\tlong kg = n;  //\ufffd\ufffd\u05b9 n \u05b5\ufffd\ufffd\ufffd\u0131\ufffd \n\tlong hg2 = 0; // kg \ufffd\ufffd\ufffd\ufffd\ufffd\u01b7\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u00b7\u04bb\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd hg \u05b5\ufffd\u0138\u0131\ufffd \n\tlong hg =0;   // kg \ufffd\ufffd\ufffd\ufffd\ufffd\u01b7\ufffd\ufffd\ufffd\ufffd\u05b9 kg \u05b5\ufffd\u0138\u0131\ufffd \n\tint tag = 0;  // \ufffd\ufffd\u01f0 kg \ufffd\u01f2\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0131\ufffd\u02b6 \ufffd\ufffd\ufffd\ufffd\ufffd\ufffdkg == 1\ufffd\ufffd  \u017c\ufffd\ufffd\ufffd\ufffdkg == 0\ufffd\ufffd \n\tint tag2 = 0; // \ufffd\ufffd\u01f0 hg \ufffd\u01f2\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0131\ufffd\u02b6 \ufffd\ufffd\ufffd\ufffd\ufffd\ufffdhg == 1\ufffd\ufffd  \u017c\ufffd\ufffd\ufffd\ufffdhg == 0\ufffd\ufffd\n\tint k1 = 0;   // \ufffd\ufffd\ufffd\u06bc\ufffd\u00bc\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u00b7\ufffd\ufffd 2 \ufffd\u0134\ufffd\ufffd\ufffd\n\tint k2 = 0;   // \ufffd\ufffd\ufffd\u06bc\ufffd\u00bc\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u00b7\ufffd\u04fc\ufffd 1 \ufffd\u0134\ufffd\ufffd\ufffd\n\tfor(; kg >= 2; k1++) {\n\t\tif(kg%2 != 0) {\n\t\t\ttag = 1;\n\t\t\tif(tag == 1 && (kg-kg/2-1)*a < b) //\u0427\ufffd\u02b6\u0531\u023e\ufffd\ufffd\ufffd\u04aa\ufffd\ufffd\u04aa\ufffd\ufffd\ufffd\ufffd \n\t\t\t\tbreak; \n\t\t\thg2 = kg;\n\t\t\thg = (kg+1)/2;                    //\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u00b7\u04bb\ufffd\ufffd\ufffd\u00f5\ufffd\u04bb\ufffd\ufffd\u02b1\ufffd\ufffd \n\t\t\tfor(;hg>=2;tk++){  \n\t\t\t\tif(hg%2 != 0) \n\t\t\t\t\ttag2 = 1;\n\t\t\t\tif(tag2 == 1 && (hg-hg/2-1)*a < b)  //\u0427\ufffd\u02b6\u0531\u023e\ufffd\ufffd\ufffd\u04aa\ufffd\ufffd\u04aa\ufffd\ufffd\ufffd\ufffd\u046d\ufffd\ufffd \n\t\t\t\t\tbreak;\n\t\t\t\tif(tag2 == 0 && (hg-hg/2)*a < b)    //\u0427\ufffd\u02b6\u0531\u023e\ufffd\ufffd\ufffd\u04aa\ufffd\ufffd\u04aa\ufffd\ufffd\ufffd\ufffd\u046d\ufffd\ufffd \n\t\t\t\t\tbreak;\n\t\t\t\tif(hg%2 != 0)\n\t\t\t\t\ttk2++;\n\t\t\t\thg = hg/2;\n\t\t\t\ttag2 = 0;\n\t\t\t}\n\t\t\tt0 = b*tk + a*hg + a*tk2;         //\ufffd\ufffd\u04bb\ufffd\ufffd\u02b1\ufffd\ufffd \n\t\t\ttag2 = 0;\n\t\t\thg = (hg2-1)/2;                   //\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u00b7\ufffd\ufffd\ufffd\ufffd\ufffd\u00f5\ufffd\ufffd\u06b6\ufffd\ufffd\ufffd\u02b1\ufffd\ufffd \n\t\t\tfor(;hg>=2;dk++){\n\t\t\t\tif(hg%2 != 0) \n\t\t\t\t\ttag2 = 1;\n\t\t\t\tif(tag2 == 1 && (hg-hg/2-1)*a < b)  //\u0427\ufffd\u02b6\u0531\u023e\ufffd\ufffd\ufffd\u04aa\ufffd\ufffd\u04aa\ufffd\ufffd\ufffd\ufffd\u046d\ufffd\ufffd \n\t\t\t\t\tbreak;\n\t\t\t\tif(tag2 == 0 && (hg-hg/2)*a < b)    //\u0427\ufffd\u02b6\u0531\u023e\ufffd\ufffd\ufffd\u04aa\ufffd\ufffd\u04aa\ufffd\ufffd\ufffd\ufffd\u046d\ufffd\ufffd \n\t\t\t\t\tbreak;\n\t\t\t\tif(hg%2 != 0)\n\t\t\t\t\tdk2++;\n\t\t\t\thg = hg/2;\n\t\t\t\ttag2 = 0;                     // tk dk tag \u03f5\ufffd\u0432\ufffd\ufffd\ufffd\u00ff\ufffd\ufffd\u046d\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd   \n\t\t\t}\n\t\t\tt1 = b*dk + a*hg + a*dk2;         //\ufffd\u06b6\ufffd\ufffd\ufffd\u02b1\ufffd\ufffd \n\t\t\tif(t0 <= t1) \n\t\t\t\tkg+=1;                        //\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u00b7\u04bb \n\t\t\telse\n\t\t\t\tkg-=1;                        //\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u00b7\ufffd\ufffd \n\t\t\t}\n\t\t\ttk = tk2 = dk = dk2 = hg2 = 0;    // tk dk tag \u03f5\ufffd\u0432\ufffd\ufffd\ufffd\u00ff\ufffd\ufffd\u046d\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd \n\t\t}\n\t\tif(tag == 1) {\n\t\t\tk2++;\n\t\t}\n\t\tif((kg-kg/2)*a <= b)                  //\u0427\ufffd\u02b6\u0531\u023e\ufffd\ufffd\ufffd\u04aa\ufffd\ufffd\u04aa\ufffd\ufffd\ufffd\ufffd\u046d\ufffd\ufffd          \n\t\t\tbreak;\n\t\tkg = kg/2;\n\t\ttag = 0;\n\t}\n\tt = b*k1 + k2*a + kg*a;                   //\ufffd\u00f5\ufffd\ufffd\ufffd\ufffd\ufffd\u0237\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u02b1\ufffd\ufffd \n\treturn t;\n}\n\nint main() {\n\tlong n,a,b;                               //\u02b9\ufffd\ufffd long double \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u03aa\ufffd\u02f7\ufffd\u05b9\ufffd\ufffd\ufffd \n\tscanf(\"%d%d%d\",&n,&a,&b);\n\tprintf(\"%.0f\\n\",final(n,a,b));\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "12c5d56648df22428ecdb37092f25cfa", "src_uid": "0f270af00be2a523515d5e7bd66800f6", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "/*\n * 710E\n */\n\n#include <limits.h>\n#include <stdio.h>\n#include <stdlib.h>\n\n#define DIJKSTRA\n#ifndef _TJYTLXWXHYZQFW_HEAP_H\n#define _TJYTLXWXHYZQFW_HEAP_H\n\n#include <assert.h>\n#include <stdlib.h>\n\n/** \u4f18\u5148\u961f\u5217\u7ed3\u6784 */\nstruct heap {\n\t/**\n\t * cap - \u4f18\u5148\u961f\u5217\u7684\u5bb9\u91cf\n\t * last - \u4f18\u5148\u961f\u5217\u4e2d\u6700\u540e\u4e00\u4e2a\u5143\u7d20\u7684\u4e0b\u6807\n\t */\n        int cap, last;\n\n\t/* \u6307\u9488\u6570\u7ec4,\u6307\u5411\u4f18\u5148\u961f\u5217\u4e2d\u7684\u5143\u7d20 */\n        void **cell; \n\n\t/* \u6bd4\u8f83\u51fd\u6570,\u7528\u4e8e\u6bd4\u8f83\u961f\u5217\u5143\u7d20\u7684\u5927\u5c0f */\n\tint (*cmp)(const void *, const void *);\n\n\t#ifdef DIJKSTRA\n\t/* \u8bbe\u7f6e\u4e00\u4e2a\u5143\u7d20\u5728cell\u4e2d\u7684\u4e0b\u6807 */\n\tvoid (*set)(void *, const int);\n\t/* \u4ea4\u6362\u4e24\u4e2a\u5143\u7d20\u5728cell\u4e2d\u7684\u4e0b\u6807 */\n\tvoid (*swap)(void *, void *);\n\t#endif\n};\n\n/**\n * \u521b\u5efa\u4f18\u5148\u961f\u5217\n *\n * @param cap - \u4f18\u5148\u961f\u5217\u7684\u5bb9\u91cf,\u4e5f\u662fcell\u6570\u7ec4\u53ef\u7528\u4e0b\u6807\u7684\u6700\u5927\u503c\n * @param cmp - \u4f18\u5148\u961f\u5217\u4e2d\u5143\u7d20\u7684\u6bd4\u8f83\u65b9\u6cd5\n * @return - \u6307\u5411\u4f18\u5148\u961f\u5217\u7ed3\u6784\u7684\u6307\u9488\n */\nstruct heap *heap_new(int cap, int (*cmp)(const void *, const void*)\n\t#ifdef DIJKSTRA\n\t,void (*set)(void *, const int), void (*swap)(void *, void *)\n\t#endif\n)\n{\n        struct heap *h;\n\n        assert(h = malloc(sizeof(struct heap)));\n\t/* \u7531\u4e8ecell[0]\u4e0d\u5b58\u653e\u5143\u7d20,\u6545\u5b9e\u9645\u5206\u914d\u7684\u5143\u7d20\u662f(cap + 1)\u4e2a */\n        h->cap = ++cap;\n\t/* linux\u4f1a\u66ff\u4f60\u63a9\u9970\u4f60\u72af\u4e0b\u7684**\u5fd8\u6389\u521d\u59cb\u5316**\u7684\u9519\u8bef, OJ\u4e0d\u4f1a */\n\th->last = 0;\n        assert(h->cell = malloc(sizeof(void*) * cap));\n\t/* comparison function */\n\th->cmp = cmp;\n\n\t#ifdef DIJKSTRA\n\th->set = set;\n\th->swap = swap;\n\t#endif\n\n        return h;\n}\n\n/**\n * \u91ca\u653e\u4f18\u5148\u961f\u5217\n *\n * @param h - \u8981\u88ab\u6467\u6bc1\u7684\u961f\u5217\n *\n * \u8fd9\u4e2a\u8fc7\u7a0b\u4e0d\u4f1a\u6467\u6bc1\u961f\u5217\u5143\u7d20,\u56e0\u4e3a\u961f\u5217\u672c\u8eab\u5bf9\n * \u5b58\u50a8\u4e8e\u5176\u4e2d\u7684\u5143\u7d20\u4e00\u65e0\u6240\u77e5\n */\nvoid heap_destroy(struct heap *h)\n{\n        if (h)\n                free(h->cell);\n        free(h);\n}\n\n/**\n * \u4e0b\u6ee4\n *\n * @param x - \u8981\u88ab\u4e0b\u6ee4\u7684\u5143\u7d20\u7684\u4e0b\u6807\n * @param h - \u6307\u5411\u4f18\u5148\u961f\u5217\u7684\u6307\u9488\n *\n * <li>\u5982\u679cx\u7684\u4e24\u68f5\u5b50\u6811\u662f\u4f18\u5148\u961f\u5217,\u90a3\u4e48\u4e0b\u6ee4\u7ed3\u675f\u540e,\u4ee5x\u4e3a\u6839\u7684\u6811\u662f\u4f18\u5148\u961f\u5217</li>\n * <li>\u5728\u6700\u5927\u5806\u4e2d\u7a81\u7136\u589e\u5927\u7684\u5143\u7d20\u6216\u8005\u5728\u6700\u5c0f\u5806\u4e2d\u7a81\u7136\u53d8\u5c0f\u7684\u5143\u7d20\u9700\u8981\u88ab\u4e0b\u6ee4</li>\n */\nvoid heap_pdown(int x, struct heap *h)\n{\n        int c, d;\n        void *tmp;\n\n        while ((c = 2 * x) <= h->last) {\n                d = c + 1;\n                if (d <= h->last && h->cmp(h->cell[d], h->cell[c]) < 0)\n                        c = d;\n                if (h->cmp(h->cell[x], h->cell[c]) < 0)\n                        break;\n\n                tmp = h->cell[c];\n                h->cell[c] = h->cell[x];\n                h->cell[x] = tmp;\n\t\t#ifdef DIJKSTRA\n\t\th->swap(h->cell[c], h->cell[x]);\n\t\t#endif\n\n                x = c;\n        }\n}\n\n/**\n * \u4e0a\u6ee4\n *\n * @param x - \u8981\u88ab\u4e0a\u6ee4\u7684\u5143\u7d20\u7684\u4e0b\u6807\n * @param h - \u6307\u5411\u4f18\u5148\u961f\u5217\u7684\u6307\u9488\n */\nvoid heap_pup(int x, struct heap *h)\n{\n        int p;\n        void *tmp;\n\n        while ((p = x / 2) >= 1) {\n                if (h->cmp(h->cell[p], h->cell[x]) < 0)\n                        break;\n\n                tmp = h->cell[x];\n                h->cell[x] = h->cell[p];\n                h->cell[p] = tmp;\n\t\t#ifdef DIJKSTRA\n\t\th->swap(h->cell[x], h->cell[p]);\n\t\t#endif\n\n                x = p;\n        }\n}\n\n/**\n * \u63d2\u5165\n *\n * @param e - \u6307\u5411\u88ab\u63d2\u5165\u5143\u7d20\u7684\u6307\u9488\n * @param h - \u6307\u5411\u4f18\u5148\u961f\u5217\u7684\u6307\u9488\n * @return \u63d2\u5165\u7ed3\u679c: 0 - \u6210\u529f, -1 - \u5931\u8d25\n */\nint heap_insert(void *e, struct heap *h)\n{\n        if (h->last >= h->cap)\n                return -1;\n\n        h->cell[++h->last] = e;\n\t#ifdef DIJKSTRA\n\th->set(h->cell[h->last], h->last);\n\t#endif\n        heap_pup(h->last, h);\n\n        return 0;\n}\n\n/**\n * \u5220\u9664\u6700\u5927/\u6700\u5c0f\u5143\n *\n * @param h - \u6307\u5411\u4f18\u5148\u961f\u5217\u7684\u6307\u9488\n * @return - \u6307\u5411\u88ab\u5220\u9664\u7684\u5143\u7d20\u7684\u6307\u9488; NULL - \u961f\u5217\u4e3a\u7a7a\n */\nvoid *heap_del(struct heap *h)\n{\n        void *ret;\n\n        if (h->last <= 0)\n                return NULL;\n\n        ret = h->cell[1];\n        h->cell[1] = h->cell[h->last--];\n\t#ifdef DIJKSTRA\n\th->set(h->cell[1], 1);\n\t#endif\n        heap_pdown(1, h);\n        return ret;\n}\n\n#endif\n\n\n#define LEN 10000001\n\nstruct node {\n\tlong long cost;\n\tchar color;\n\tint id;\n\tint hidx;\n};\n\nint compare(const void *x, const void *y)\n{\n\t/* \u7528\u4e86long long\u7b80\u76f4\u5230\u5904\u662f\u9677\u9631 */\n\treturn ((struct node *)x)->cost - ((struct node *)y)->cost < 0 ? -1 : 1;\n}\n\nvoid sethidx(void *node, const int idx)\n{\n\t((struct node *)node)->hidx = idx;\n}\n\nvoid swaphidx(void *x, void *y)\n{\n\tint tmp;\n\n\ttmp = ((struct node *)x)->hidx;\n\t((struct node *)x)->hidx = ((struct node *)y)->hidx;\n\t((struct node *)y)->hidx = tmp;\n}\n\nlong long len;\n#define OOS(x) ((x) < 0 || (x) > len)\nlong long x, y;\nstruct node nodes[LEN];\n\nvoid handle(int id, long long cost, struct heap *h)\n{\n\tstruct node *next;\n\n\tif (id > len) {\n\t\tnext = &nodes[len];\n\t\tcost += x * (id - len); \n\t} else if (id >= 0) {\n\t\tnext = &nodes[id];\n\t} else {\n\t\treturn;\n\t}\n\n\n\tif (next->color == 2)\n\t\treturn;\n\n\tif (cost >= next->cost)\n\t\treturn;\n\n\n\tnext->cost = cost;\n\tif (next->color == 0) {\n\t\theap_insert(next, h);\n\t\tnext->color = 1;\n\t} else {\n\t\theap_pup(next->hidx, h);\n\t}\n}\n\nlong long dijkstra(void)\n{\n\tstruct heap *h;\n\tstruct node *node;\n\n\th = heap_new(len, compare, sethidx, swaphidx);\n\theap_insert(&nodes[0], h);\n\tnodes[0].color = 1;\n\tnodes[0].cost = 0;\n\n\twhile ((node = heap_del(h)) != NULL) {\n\t\tnode->color = 2;\n\t\tif (node->id == len)\n\t\t\treturn node->cost;\n\n\t\thandle(node->id + 1, node->cost + x, h);\n\t\thandle(node->id - 1, node->cost + x, h);\n\t\thandle(node->id * 2, node->cost + y, h);\n\t}\n\n\t/* impossible */\n\treturn -1;\n}\n\nint main(void)\n{\n\tlong long i, imax;\n\n\tscanf(\"%lld%lld%lld\", &len, &x, &y);\n\n\tfor (imax = len * 2, i = 0; i <= imax; ++i) {\n\t\tnodes[i].id = i;\n\t\tnodes[i].cost = LLONG_MAX;\n\t\tnodes[i].color = 0;\n\t}\n\n\tprintf(\"%lld\\n\", dijkstra());\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "237b03dcfa3c9991865903a82f96afb0", "src_uid": "0f270af00be2a523515d5e7bd66800f6", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint chk1(int dx,int dy){\n  if(dx<0) dx=-dx; if(dy<0) dy=-dy;\n  if(dx<=1 && dy<=1) return 1;\n  return 0;\n}\n\nint chk2(int dx,int dy){\n  if(dx==0 && dy==0) return 0;\n  if(dx==0 || dy==0) return 1;\n  return 0;\n}\n\nint main(){\n  int i,j,k,l,m,n;\n  int di,dj,ok;\n  char in[4][4];\n\n  while(scanf(\"%s%s%s%s\",in[0],in[1],in[2],in[3])==4){\n    ok=0;\n    REP(di,-1,2) REP(dj,-1,2) {\n      in[3][0] += di; in[3][1]+=dj;\n      while('a'<=in[3][0]&&in[3][0]<='h' && '1'<=in[3][1]&&in[3][1]<='8'){\n        if(chk1(in[2][0]-in[3][0],in[2][1]-in[3][1])) break;\n        rep(i,2){\n          if(chk2(in[i][0]-in[3][0],in[i][1]-in[3][1])){\n            rep(k,3){\n              if(in[i][1]==in[3][1] && ((in[i][0]<in[k][0]&&in[k][0]<in[3][0])||(in[i][0]>in[k][0]&&in[k][0]>in[3][0]))) break;\n              if(in[i][0]==in[3][0] && ((in[i][1]<in[k][1]&&in[k][1]<in[3][1])||(in[i][1]>in[k][1]&&in[k][1]>in[3][1]))) break;\n            }\n            if(k==3) break;\n          }\n        }\n        if(i<2) break;\n        ok=1; break;\n      }\n      in[3][0] -= di; in[3][1] -= dj;\n    }\n    if(ok) puts(\"OTHER\"); else puts(\"CHECKMATE\");\n\n    break;\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a1136abf536f44a93219ce32ee683a95", "src_uid": "5d05af36c7ccb0cd26a4ab45966b28a3", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint chk1(int dx,int dy){\n  if(dx<0) dx=-dx; if(dy<0) dy=-dy;\n  if(dx<=1 && dy<=1) return 1;\n  return 0;\n}\n\nint chk2(int dx,int dy){\n  if(dx==0 && dy==0) return 0;\n  if(dx==0 || dy==0) return 1;\n  return 0;\n}\n\nint main(){\n  int i,j,k,l,m,n;\n  int di,dj,ok;\n  char in[4][4];\n\n  while(scanf(\"%s%s%s%s\",in[0],in[1],in[2],in[3])==4){\n    ok=0;\n    REP(di,-1,2) REP(dj,-1,2) /*if(di||dj)*/{\n      in[3][0] += di; in[3][1]+=dj;\n      while('a'<=in[3][0]&&in[3][0]<='h' && '1'<=in[3][1]&&in[3][1]<='8'){\n        if(chk1(in[2][0]-in[3][0],in[2][1]-in[3][1])) break;\n        rep(i,2){\n          if(chk2(in[i][0]-in[3][0],in[i][1]-in[3][1])){\n            rep(k,3){\n              if(in[i][0]==in[3][0] && ((in[i][0]<in[k][1]&&in[k][1]<in[3][0])||(in[i][0]>in[k][1]&&in[k][1]>in[3][0]))) break;\n              if(in[i][1]==in[3][1] && ((in[i][1]<in[k][0]&&in[k][0]<in[3][1])||(in[i][1]>in[k][0]&&in[k][0]>in[3][1]))) break;\n            }\n            if(k==3) break;\n          }\n        }\n        if(i<2) break;\n        ok=1; break;\n      }\n      in[3][0] -= di; in[3][1] -= dj;\n    }\n    if(ok) puts(\"OTHER\"); else puts(\"CHECKMATE\");\n\n    break;\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8a06eb224a88cfc8a5b5b8036bfae3cc", "src_uid": "5d05af36c7ccb0cd26a4ab45966b28a3", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint chk1(int dx,int dy){\n  if(dx<0) dx=-dx; if(dy<0) dy=-dy;\n  if(dx<=1 && dy<=1) return 1;\n  return 0;\n}\n\nint chk2(int dx,int dy){\n  if(dx==0 && dy==0) return 0;\n  if(dx==0 || dy==0) return 1;\n  return 0;\n}\n\nint main(){\n  int i,j,k,l,m,n;\n  int di,dj,ok;\n  char in[4][4];\n\n  while(scanf(\"%s%s%s%s\",in[0],in[1],in[2],in[3])==4){\n    ok=0;\n    REP(di,-1,2) REP(dj,-1,2) {\n      in[3][0] += di; in[3][1]+=dj;\n      while('a'<=in[3][0]&&in[3][0]<='h' && '1'<=in[3][1]&&in[3][1]<='8'){\n        if(chk1(in[2][0]-in[3][0],in[2][1]-in[3][1])) break;\n        rep(i,2){\n          if(chk2(in[i][0]-in[3][0],in[i][1]-in[3][1])){\n            rep(k,3){\n              if(in[i][0]==in[3][0] && ((in[i][0]<in[k][0]&&in[k][0]<in[3][0])||(in[i][0]>in[k][0]&&in[k][0]>in[3][0]))) break;\n              if(in[i][1]==in[3][1] && ((in[i][1]<in[k][1]&&in[k][1]<in[3][1])||(in[i][1]>in[k][1]&&in[k][1]>in[3][1]))) break;\n            }\n            if(k==3) break;\n          }\n        }\n        if(i<2) break;\n        ok=1; break;\n      }\n      in[3][0] -= di; in[3][1] -= dj;\n    }\n    if(ok) puts(\"OTHER\"); else puts(\"CHECKMATE\");\n\n    break;\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8c380c4878b6bbfbf65634fe1a6dd8e9", "src_uid": "5d05af36c7ccb0cd26a4ab45966b28a3", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint chk1(int dx,int dy){\n  if(dx<0) dx=-dx; if(dy<0) dy=-dy;\n  if(dx<=1 && dy<=1) return 1;\n  return 0;\n}\n\nint chk2(int dx,int dy){\n  if(dx==0 && dy==0) return 0;\n  if(dx==0 || dy==0) return 1;\n  return 0;\n}\n\nint main(){\n  int i,j,k,l,m,n;\n  int di,dj,ok;\n  char in[4][4];\n\n  while(scanf(\"%s%s%s%s\",in[0],in[1],in[2],in[3])==4){\n    ok=0;\n    REP(di,-1,2) REP(dj,-1,2) {\n      in[3][0] += di; in[3][1]+=dj;\n      while('a'<=in[3][0]&&in[3][0]<='h' && '1'<=in[3][1]&&in[3][1]<='8'){\n        if(chk1(in[2][0]-in[3][0],in[2][1]-in[3][1])) break;\n        rep(i,2){\n          if(chk2(in[i][0]-in[3][0],in[i][1]-in[3][1])){\n            rep(k,3){\n              if(in[i][1]==in[3][1] && in[i][1]==in[k][1] && ((in[i][0]<in[k][0]&&in[k][0]<in[3][0])||(in[i][0]>in[k][0]&&in[k][0]>in[3][0]))) break;\n              if(in[i][0]==in[3][0] && in[i][0]==in[k][0] && ((in[i][1]<in[k][1]&&in[k][1]<in[3][1])||(in[i][1]>in[k][1]&&in[k][1]>in[3][1]))) break;\n            }\n            if(k==3) break;\n          }\n        }\n        if(i<2) break;\n        ok=1; break;\n      }\n      in[3][0] -= di; in[3][1] -= dj;\n    }\n    if(ok) puts(\"OTHER\"); else puts(\"CHECKMATE\");\n\n    break;\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7e76a462006c0f08a2b7c24a63ee6548", "src_uid": "5d05af36c7ccb0cd26a4ab45966b28a3", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint max(int a, int b)\n{\n     if (a > b) {\n\t  return a;\n     } else {\n\t  return b;\n     }\n}\n\nint min(int a, int b)\n{\n     if (a < b) {\n\t  return a;\n     } else {\n\t  return b;\n     }\n}\n\nint main()\n{\n     char s[4][3];\n     int p, q, i, j, k;\n     int a[8][8] = {0};\n     int b[2][2];\n\n     for (i = 0; i < 4; i++) scanf(\"%s\", s[i]);\n\n     p = s[2][0] - 'a';\n     q = s[2][1] - '1';\n\n     for (i = p - 1; i <= p + 1; i++) {\n\t  for (j = q - 1; j <= q + 1; j++) {\n\t       if (i >= 0 && i < 8 && j >= 0 && j < 8) a[i][j] = 1;\n\t  }\n     }\n\n     for (i = 0; i < 2; i++) {\n\t  b[i][0] = s[i][0] - 'a';\n\t  b[i][1] = s[i][1] - '1';\n\n\t  for (j = b[i][0]; j >= 0; j--) {\n\t       a[j][b[i][1]]++;\n\n\t       if (j == p && b[i][1] == q) break;\n\t  }\n\n\t  for (j = b[i][0] + 1; j < 8; j++) {\n\t       a[j][b[i][1]]++;\n\n\t       if (j == p && b[i][1] == q) break;\n\t  }\n\n\t  for (j = b[i][1] - 1; j >= 0; j--) {\n\t       a[b[i][0]][j]++;\n\n\t       if (b[i][0] == p && j == q) break;\n\t  }\n\n\t  for (j = b[i][1] + 1; j < 8; j++) {\n\t       a[b[i][0]][j]++;\n\n\t       if (b[i][0] == p && j == q) break;\n\t  }\n     }\n\n     p = s[3][0] - 'a';\n     q = s[3][1] - '1';\n\n     if (a[p][q] == 0) {\n\t  puts(\"OTHER\");\n\n\t  return 0;\n     }\n\n     for (i = p - 1; i <= p + 1; i++) {\n\t  for (j = q - 1; j <= q + 1; j++) {\n\t       if (i >= 0 && i < 8 && j >= 0 && j < 8) {\n\t\t    if (a[i][j] == 0) {\n\t\t\t puts(\"OTHER\");\n\n\t\t\t return 0;\n\t\t    }\n\n\t\t    for (k = 0; k < 2; k++) {\n\t\t\t if (i == b[k][0] && j == b[k][1]) {\n\t\t\t      if (a[i][j] == 1) {\n\t\t\t\t   puts(\"OTHER\");\n\n\t\t\t\t   return 0;\n\t\t\t      }\n\t\t\t }\n\t\t    }\n\t       }\n\t  }\n     }\n\n     puts(\"CHECKMATE\");\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "078a10d0713dbe452a3e0643622d34ad", "src_uid": "5d05af36c7ccb0cd26a4ab45966b28a3", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint dp[100][51][201][2];\n\nint main()\n{\n     int n, c = 0, len, i, j, k;\n     char s[101];\n\n     scanf(\"%s\", s);\n     scanf(\"%d\", &n);\n\n     len = strlen(s);\n\n     for (i = 0; i < len; i++) {\n\t  if (s[i] == 'T') c++;\n     }\n\n     if (c <= n) {\n\t  n -= c;\n\n\t  len -= n % 2;\n\n\t  printf(\"%d\\n\", len);\n     } else {\n\t  if (s[0] == 'T') {\n\t       dp[0][0][100][1] = 1;\n\t       dp[0][1][101][0] = 1;\n\t  } else {\n\t       dp[0][0][101][0] = 1;\n\t       dp[0][1][100][1] = 1;\n\t  }\n\n\t  for (i = 0; i < len - 1; i++) {\n\t       for (j = 0; j <= n; j++) {\n\t\t    for (k = 0; k <= 200; k++) {\n\t\t\t if (dp[i][j][k][0] == 1) {\n\t\t\t      if (s[i] == 'T') {\n\t\t\t\t   dp[i + 1][j][k][1] = 1;\n\n\t\t\t\t   if (j < n) dp[i + 1][j + 1][k + 1][0] = 1;\n\t\t\t      } else {\n\t\t\t\t   dp[i + 1][j][k + 1][0] = 1;\n\n\t\t\t\t   if (j < n) dp[i + 1][j + 1][k][1] = 1;\n\t\t\t      }\n\t\t\t }\n\n\t\t\t if (dp[i][j][k][1] == 1) {\n\t\t\t      if (s[i] == 'T') {\n\t\t\t\t   dp[i + 1][j][k][0] = 1;\n\n\t\t\t\t   if (j < n) dp[i + 1][j + 1][k - 1][1] = 1;\n\t\t\t      } else {\n\t\t\t\t   dp[i + 1][j][k - 1][1] = 1;\n\n\t\t\t\t   if (j < n) dp[i + 1][j + 1][k][0] = 1;\n\t\t\t      }\n\t\t\t }\n\t\t    }\n\t       }\n\t  }\n\n\t  c = 0;\n\n\t  for (i = 0; i <= 100; i++) {\n\t       if (dp[len - 1][n][100 + i][0] == 1) c = i;\n\n\t       if (dp[len - 1][n][100 - i][0] == 1) c = i;\n\n\t       if (dp[len - 1][n][100 + i][1] == 1) c = i;\n\n\t       if (dp[len - 1][n][100 - i][1] == 1) c = i;\n\t  }\n\n\t  printf(\"%d\\n\", c);\n     }\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f122a6cd5c4b1339ab507a1be34f69c7", "src_uid": "4a54971eb22e62b1d9e6b72f05ae361d", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint max(int a, int b)\n{\n     if (a > b) {\n\t  return a;\n     } else {\n\t  return b;\n     }\n}\n\nint main()\n{\n     int n, c = 0, len, i, j, k;\n     char s[101];\n\n     scanf(\"%s\", s);\n     scanf(\"%d\", &n);\n\n     len = strlen(s);\n\n     for (i = 0; i < len; i++) {\n\t  if (s[i] == 'T') c++;\n     }\n\n     if (c <= n) {\n\t  n -= c;\n\n\t  len -= n % 2;\n\n\t  printf(\"%d\\n\", len);\n     } else {\n\t  int dp[100][51] = {0};\n\n\t  if (s[0] == 'T') {\n\t       dp[0][1] = 1;\n\t  } else {\n\t       dp[0][0] = 1;\n\t  }\n\n\t  for (i = 1; i < len; i++) {\n\t       for (j = 0; j <= i; j++) {\n\t\t    if (s[i] == 'T') {\n\t\t\t for (k = 0; k < i; k++) {\n\t\t\t      dp[i][j] = max(dp[i][j], dp[k][j]);\n\t\t\t }\n\n\t\t\t if (j > 0) {\n\t\t\t      c = j - 1;\n\n\t\t\t      for (k = i - 1; k >= 0; k--) {\n\t\t\t\t   if (s[k] == 'T') c--;\n\n\t\t\t\t   if (c < 0) break;\n\t\t\t      }\n\n\t\t\t      if (k < 0) {\n\t\t\t\t   if (c == 0) dp[i][j] = i + 1;\n\t\t\t      } else {\n\t\t\t\t   dp[i][j] = max(dp[i][j], i - k);\n\t\t\t      }\n\t\t\t }\n\t\t    } else {\n\t\t\t for (k = 0; k < i; k++) {\n\t\t\t      dp[i][j] = max(dp[i][j], dp[k][j]);\n\t\t\t }\n\n\t\t\t c = j;\n\n\t\t\t for (k = i - 1; k >= 0; k--) {\n\t\t\t      if (s[k] == 'T') c--;\n\n\t\t\t      if (c < 0) break;\n\t\t\t }\n\n\t\t\t if (k < 0) {\n\t\t\t      if (c == 0) dp[i][j] = i + 1;\n\t\t\t } else {\n\t\t\t      dp[i][j] = max(dp[i][j], i - k);\n\t\t\t }\n\t\t    }\n\t       }\n\t  }\n\n\t  printf(\"%d\\n\", dp[len - 1][n]);\n     }\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f767123fc05bcfd6b3b055626de73cd1", "src_uid": "4a54971eb22e62b1d9e6b72f05ae361d", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nconst int inf  = 1 << 30;\n\nint f[110][55][2];\nchar s[110];\n\n#define max(a, b) (a > b ? a : b)\n\nint main( void ) {\n\tint n, m, i, j, c, k;\n\tscanf(\"%s %i\", s, &m);\n\n\tn = strlen(s);\n\n\tfor( i = 0; i < n; i++ )\n\t\ts[i] = (s[i] == 'F') ? 0 : 1;\n\t\n\t/*for( i = 0; i < n; i++) \n\t\tprintf(\"%i\", s[i]);\n\tputs(\"\");*/\n\t\n\tfor( i = 0; i < 110; i++ )\n\t\tfor( j = 0; j < 55; j++ )\n\t\t\tf[i][j][0] = f[i][j][1] = -inf;\n\n\tf[n][0][0] = f[n][0][1] = 0;\n\tfor( i = n-1; i >= 0; i-- )\n\t\tfor( j = m; j >= 0; j-- )\n\t\t\tfor( k = 0; k < 2; k++ ) {\n\t\t\t\tf[i][j][k] = -inf;\n\t\t\t\t\n\t\t\t\tint sign = (k == 0) ? 1 : -1;\n\t\t\t\tfor( c = 0; c <= j; c++ ) {\n\t\t\t\t\tint new_c = (c % 2) ? s[i] ^ 1 : s[i], cost;\n\n\t\t\t\t\tif( new_c == 0 ) cost = sign;\n\t\t\t\t\telse\t\t\t cost = 0;\n\t\t\t\t\t\n\t\t\t\t\tint new_k = (new_c == 1) ? k ^ 1 : k;\n\t\t\t\t\tf[i][j][k] = max(f[i][j][k], f[i+1][j-c][new_k] + cost);\n\t\t\t\t}\n\t\t\t}\n\t\n\tprintf(\"%i\\n\", f[0][m][0]);\n\t\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f25ec36afd77ed0123cde31be858e73e", "src_uid": "4a54971eb22e62b1d9e6b72f05ae361d", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <ctype.h>\n#define abs(a) ((a < 0) ? (-(a)) : (a))\n#define abs_max(a, b) ((abs(a) > abs(b)) ? (a) : (b))\n\nint d[101][51][2];\nchar s[101];\nint n, k;\n\nint\nmain(void)\n{\n    while(isalpha(s[n++] = getchar()))\n        ;\n    --n;\n    int i, j, p;\n    scanf(\"%d\", &k);\n    for(i = 0; i <= n; ++i){\n        for(j = 0; j <= k; ++j){\n            d[i][j][0] = 0;\n            d[i][j][1] = 0;\n        }\n    }\n    for(i = 1; i <= n; ++i){\n        for(j = 0; j <= k; ++j){\n            for(p = 0; p <= j; ++p){\n                if((s[i - 1] == 'F' && p % 2 == 0) || (s[i - 1] == 'T' && p % 2 == 1)){\n                    d[i][j][0] = abs_max(d[i - 1][j - p][0] + 1, d[i][j][0]);\n                    d[i][j][1] = abs_max(d[i - 1][j - p][1] - 1, d[i][j][1]);\n                } else {\n                    d[i][j][1] = abs_max(d[i - 1][j - p][0], d[i][j][1]);\n                    d[i][j][0] = abs_max(d[i - 1][j - p][1], d[i][j][0]);\n                }\n            }\n        }\n    }\n    printf(\"%d\", abs(abs_max(d[n][k][0], d[n][k][1])));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7079a528f7e41335b9797b97cf0e3f42", "src_uid": "4a54971eb22e62b1d9e6b72f05ae361d", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nenum {\n    L, R, N = 101\n};\n\nconst int INF = 100100;\n\nint max(int a, int b) { \n    if(a == INF)\n        return b;\n    return a > b ? a : b; \n}\nint min(int a, int b) { return a < b ? a : b; }\n\nchar cmd[N];\nint n, len;\nint d[N][N][55][2][2];\n\nint sim(int left, int right) {\n    int i, pos = 0, dx = 1;\n    for(i = left; i <= right; i++) {\n        if(cmd[i] == 'T')\n            dx = -dx;\n        else\n            pos += dx;\n    }\n    return pos;\n}\n\nint rec(int left, int right, int nCmd, int dir, int isLow) {\n    if(nCmd < 0)\n        return INF;\n    if(d[left][right][nCmd][dir][isLow] != -INF)\n        return d[left][right][nCmd][dir][isLow];\n    int *ret = &d[left][right][nCmd][dir][isLow];\n    *ret = INF;\n    if(left > right) {\n        *ret = INF;\n    }\n    if(nCmd == 0) {\n        *ret = sim(left, right);\n    }\n    if(left == right) {\n        if((cmd[left] == 'T' && nCmd % 2 == 0) ||\n                (cmd[left] == 'F' && nCmd % 2))\n            *ret = 0;\n        else\n            *ret = 1;\n    }\n    if(*ret != INF)\n        return *ret;\n    int i, turns, nd, ni, nd2, ni2;\n    for(i = left; i <= right; i++) {\n      for(turns = 0; i != right && turns <= nCmd; turns++) {\n        for(nd = L; nd <= R; nd++)\n          for(ni = 0; ni < 2; ni++)\n            for(nd2 = L; nd2 <= R; nd2++)\n              for(ni2 = 0; ni2 < 2; ni2++) {\n                  int val = rec(left, i, turns, nd, ni) + \n                    rec(i + 1, right, nCmd - turns, nd2, ni2);\n                  if(rec(left, i, turns, nd, ni) == INF ||\n                          rec(i + 1, right, nCmd - turns, nd2, ni2) == INF)\n                      continue;\n                  if((isLow == 0 && dir == R) ||\n                          isLow == 1 && dir == L)\n                    *ret = max(*ret, val);\n                  else\n                    *ret = min(*ret, val);\n              }\n      }\n      for(turns = 0; turns <= nCmd; turns++)\n        for(nd = L; nd <= R; nd++)\n          for(ni = 0; ni < 2; ni++)\n            for(nd2 = L; nd2 <= R; nd2++)\n              for(ni2 = 0; ni2 < 2; ni2++) {\n                int ch;\n                for(ch = 0; ch < 2; ch++) {\n                  int val = rec(left, i - 1, turns - ch, nd, ni);\n                  if(val == INF)\n                      continue;\n                  if(cmd[i] == 'F') {\n                      val -= \n                        rec(i + 1, right, nCmd - turns - (1 - ch), nd2, ni2);\n                      if(rec(i + 1, right, nCmd - turns - (1 - ch), nd2, ni2) == INF)\n                          continue;\n                  }\n                  else {\n                      if(rec(i + 1, right, nCmd - turns - (1 - ch), nd2, ni2) == INF)\n                          continue;\n                      val += rec(i + 1, right, nCmd - turns - (1 - ch), nd2, ni2) + 1;\n                  }\n                  if(0 && val == 2 && left == 2 && right == 3)\n                      printf(\"%d bord %d %d turns %d\\n\", val, i, ch, turns);\n                  if((isLow == 0 && dir == R) ||\n                          isLow == 1 && dir == L)\n                    *ret = max(*ret, val);\n                  else\n                    *ret = min(*ret, val);\n                }\n              }\n\n    }\n    if(*ret == -INF)\n        *ret = INF;\n    if(0)\n    printf(\"left %d; right %d; cmd %d; dir %d; low %d; -> %d\\n\",\n            left, right, nCmd, dir, isLow, *ret);\n    return *ret;\n}\n\nint main() {\n    scanf(\"%s %d\", cmd, &n);\n    len = strlen(cmd);\n    int ans = 0, i, j, k, r, e;\n    for(i = 0; i < N; i++)\n        for(j = 0; j < N; j++)\n            for(k = 0; k < 55; k++)\n                for(r = 0; r < 2; r++)\n                    for(e = 0; e < 2; e++)\n                        d[i][j][k][r][e] = -INF;\n    for(i = n & 1; i <= n; i += 2) {\n        ans = max(ans, -rec(0, len - 1, i, L, 0));\n        if(rec(0, len - 1, i, R, 0) != INF)\n            ans = max(ans, rec(0, len - 1, i, R, 0));\n    }\n    printf(\"%d\\n\", ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "43ef17784162559a8149021e997a6522", "src_uid": "4a54971eb22e62b1d9e6b72f05ae361d", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n#include <ctype.h>\n#include <limits.h>\n\n#define author int\n#define sph_mp main() \n#define fr(i, a, b) for((i) = (a) ; (i) < (b) ; (i)++)\n#define frr(i, a, b) for((i) = (a) ; (i) >= (b) ; (i)--)\n\nint l, r, x, y;\nint a[1000], ai = 0;\n\n// Function to print the divisors\nvoid printDivisors(int n)\n{\n    // Note that this loop runs till square root\n    int i;\n    for (i=1; i<=sqrt(n); i++)\n    {\n        if (n%i == 0)\n        {\n            // If divisors are equal, print only one\n            if (n/i == i)\n            \t{\n            \t\ta[ai] = i;\n            \t\tai++;\n\t\t\t\t}\n//                printf(\"%d \", i);\n \n            else // Otherwise print both\n            \t{\n            \t\ta[ai] = i;\n            \t\ta[ai+1] = n/i;\n            \t\tai += 2;\n\t\t\t\t}\n//                printf(\"%d %d \", i, n/i);\n        }\n    }\n}\n \nint valid(int x) {\n\treturn l <= x && x <= r;\n}\n\nint gcd(int a, int b)\n{\n    if (a == 0)\n        return b;\n    return gcd(b%a, a);\n}\n \n// Function to return LCM of two numbers\nint lcm(int a, int b)\n{\n    return (a*b)/gcd(a, b);\n}\n\n/* Driver program to test above function */\nauthor sph_mp {\n\tscanf(\"%d %d %d %d\", &l, &r, &x, &y);\n\tprintDivisors(y);\n\tint res = 0;\n\tint i, j;\n\tfr(i, 0, ai) \n\t\tfr(j, 0, ai) {\n\t\t\tif(valid(a[i]) && valid(a[j])) {\n\t\t\t\tif(gcd(a[i], a[j]) == x && lcm(a[i], a[j]) == y) \n\t\t\t\t\t{\n//\t\t\t\t\t\tprintf(\"%d %d\\n\", a[i], a[j]);\n\t\t\t\t\t\tres++;\n\t\t\t\t\t}\n\t\t\t}\n\t\t}\n\tprintf(\"%d\", res);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f6f814ea74ffe726db0eda8e0f2c7519", "src_uid": "d37dde5841116352c9b37538631d0b15", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<limits.h>\n#include<math.h>\n\nlong long int gcd(long long int a,long long int b)\n{\n\tif(b==0)\n\t\treturn a;\n\tgcd(b,a%b);\n}\n\nint main()\n{\t\n\tint i;\n\tlong long int l,r,x,y,pro,a,b;\n\tscanf(\"%lld%lld%lld%lld\",&l,&r,&x,&y);\n\t\n\ta=x;\n\tb=x;\n\ty=y/x;\n\tpro = sqrt(y);\n\tint ans=0;\n\tfor(i=1;i<=pro;i++)\n\t{\n\t\tif(y%i==0 && gcd(y/i,i)==1)\n\t\t{\n\t\t\tif(y/i==i)\n\t\t\t{\n\t\t\t\tif(x*i>=l && x*i<=r)\n\t\t\t\t\tans++;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tif((x*i>=l && x*i<=r )\t&& (x*(y/i)>=l && x*(y/i)<=r))\n\t\t\t\t\tans+=2;\n\t\t\t}\n\t\t}\n\n\t}\n\tprintf(\"%d\\n\",ans );\n\n\n\n\treturn 0;\t\n}\n \n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "911304e19bb1d9e90cc20e05d1b93550", "src_uid": "d37dde5841116352c9b37538631d0b15", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <locale.h>\nint main()\n{\n    int e,a,b,i, x, y, k, f, r, q;\n    k=0;\n    scanf(\"%d %d %d %d\",&a, &b, &x, &y);\n    for (i=1;i<=sqrt(y);i++)\n    {\n        if ((y%i==0)&&(i<=b/x)&&(i>=a/x)&&(y/i<=b/x)&&(y/i>=a/x))\n            {\n                f=0;\n                if (i>y/i)\n\n                 q=i;\n                 else\n                    q=y/i;\n\n                for(r=2;r<=sqrt(q);r++)\n                    if ((i % r==0)&&(y/i%r==0))\n                    f=1;\n\n                if (f==0)\n                {\n                 k++;\n                if (i!=y/i)\n                    k++;\n                }\n\n            }\n    }\n    printf(\"%d\",k);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c6cd2d12c7eb09475befaddcd4981783", "src_uid": "d37dde5841116352c9b37538631d0b15", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint l,r,x,y;\nint gcd(int p,int q){\n\tint r;\n\twhile(q!=0){\n\t\tr=p%q;\n\t\tp=q;\n\t\tq=r;\n\t}\n\treturn p;\n}\nvoid run(){\n\tint i,j,k,c;\n\twhile(scanf(\"%d%d%d%d\",&l,&r,&x,&y)!=EOF){\n\t\tif(y%x!=0){\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\t\t}\n\t\tj=y/x;\n\t\tc=0;\n\t\tfor(i=1;i<100007&&i<=j;i++){\n\t\t\tif(j%i==0){\n\t\t\t\tk=j/i;\n\t\t\t\tif(k<i){\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tif(i*x>=l&&i*x<=r&&k*x>=l&&k*x<=r){\n\t\t\t\t\tif(gcd(i,k)==x){\n\t\t\t\t\t\tc+=i==k?1:2;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\",c);\n\t}\n}\nmain(){\n#ifndef\tONLINE_JUDGE\n\tfreopen(\"4892b_min.in\",\"rb\",stdin);\n\tfreopen(\"4892b_.out\",\"wb\",stdout);\n#endif\n\trun();\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "89fa0b0a38af6d361a2e233f5f3cd20c", "src_uid": "d37dde5841116352c9b37538631d0b15", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <locale.h>\nint main()\n{\n    int e,a,b,i, x, y, k, f, r, q;\n    k=0;\n    scanf(\"%d %d %d %d\",&a, &b, &x, &y);\n    for (i=1;i<=sqrt(y);i++)\n    {\n        if ((y%i==0)&&(i<=b/x)&&(i>=a/x)&&(y/i<=b/x)&&(y/i>=a/x))\n            {\n                f=0;\n                if (i>y/i)\n\n                 q=i;\n                 else\n                    q=y/i;\n\n                for(r=2;r<sqrt(q);r++)\n                    if ((i % r==0)&&(y/i%r==0))\n                    f=1;\n\n                if (f==0)\n                {\n                 k++;\n                if (i!=y/i)\n                    k++;\n                //printf(\" %d %d \", i, y/i);\n                }\n\n            }\n    }\n    printf(\"%d\",k);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e731a2518476f27c4048e92df5dc937d", "src_uid": "d37dde5841116352c9b37538631d0b15", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>       //r\n#include<string.h>\n#include<stdlib.h>\n#include<algorithm>\n#include<math.h>\n#include<queue>\n#include<stack>\n#define INF 0x3f3f3f\n#define MAX 100100\n#define LL long long\nusing namespace std;\nint main()\n{\n    LL n,m,j,i;\n    while(cin>>n!=EOF)\n    {\n        if(n&1)\n            printf(\"1\\n\");\n        else\n            printf(\"2\\n\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6f76a5f20c7635920916b478794c0473", "src_uid": "816ec4cd9736f3113333ef05405b8e81", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main() {\n/*      long n;\n        unsigned long long t;\n        scanf(\"%ld\",&n);\n        t = 3*n*(n+1) +1;\n        printf(\"%llu\\n\",t); \n*/\n        long n;\n        scanf(\"%ld\",&n);\n        if(n%2==1)\n                printf(\"%d\\n\",1);\n        else\n                printf(\"%d\\n\",2);\n}\n~                               ", "lang_cluster": "C", "compilation_error": true, "code_uid": "ec321ee2a9e5bf153e8cd08d15f583c3", "src_uid": "816ec4cd9736f3113333ef05405b8e81", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "include<stdio.h>\nint main()\n{\n    long long n;\n    scanf(\"%I64d\",&n);\n    if(n%2==0)printf(\"2\");\n    else printf(\"1\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "21513a12bc3fd017842dade431424418", "src_uid": "816ec4cd9736f3113333ef05405b8e81", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<iostream>\nusing namespace std;\nint main(){\n\tint n;\n\tcin>>n;\n\tif(n%2==0)\n\t cout<<\"2\";\n\telse \n\t cout<<\"1\";\n\t return 0; \n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b923ea907b6e98f29391048d4a1bb2e7", "src_uid": "816ec4cd9736f3113333ef05405b8e81", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <bits/stdc++.h>\nusing namespace std;\nint main ()\n{\n    long long int n;\n    int ans;\n    cin>>n;\n    ans=2-(n%2);\n    cout<<ans<<endl;\n    return 0;\n}\n\n\t", "lang_cluster": "C", "compilation_error": true, "code_uid": "a4e6f853d4c6ceffb6cd841f8f329d96", "src_uid": "816ec4cd9736f3113333ef05405b8e81", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char s[100], r[100], back[100];\n    int ch[26] = {0}, i, k=0;\n    scanf(\"%s\", s);\n    //cout<<s<<endl;\n    for(i=0; i<strlen(s); i++){\n        ch[s[i]-'a']++;\n    }\n    for(i=25; i>=0 && ch[i]==0; i--){\n\n    }\n    for(int j=0; j<ch[i]; j++){\n        r[k++] = i+'a';\n    }\n    r[k] = '\\0';\n    printf(\"%s\\n\", r);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "661d5f9d5c808dd7d62510d681219f4f", "src_uid": "9a40e9b122962a1f83b74ddee6246a40", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    char c='Z',d;int ans=0;\n    while(scnaf(\"%c\",&d)+1)\n    if(d>c)c=d,ans=1;\n    else ans++;\n    while(ans--)cout<<c;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f0fcb0ad8b8c95697d08d66c6373a4bb", "src_uid": "9a40e9b122962a1f83b74ddee6246a40", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char s[100], r[100], back[100];\n    int ch[26] = {0}, i, k=0;\n    scanf(\"%s\", s);\n    //cout<<s<<endl;\n    for(i=0; i<strlen(s); i++){\n        ch[s[i]-'a']++;\n    }\n    for(i=25; i>=0 && ch[i]==0; i--){\n\n    }\n    for(j=0; j<ch[i]; j++){\n        r[k++] = i+'a';\n    }\n    r[k] = '\\0';\n    printf(\"%s\\n\", r);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b8619f92b579728c869de00bd6818ccf", "src_uid": "9a40e9b122962a1f83b74ddee6246a40", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio>\nint a['z'+2];\nint main() {\n    for(char c=getchar();c!='\\n';a['z'+1] = a['z'+1] ^ ((a['z'+1] ^ (c-'a')) & -(a['z'+1] < (c-'a'))), c=getchar()) a[c-'a']++;\n   \twhile(a[a['z'+1]]--) printf(\"%c\", a['z'+1]+'a');\n}\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1a8a87d0bd09872488f6444ed41dc8b4", "src_uid": "9a40e9b122962a1f83b74ddee6246a40", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    char c='Z',d;int ans=0;\n    while(scanf(\"%c\",&d)+1)\n    if(d>c)c=d,ans=1;\n    else if(c==d) ans++;\n    while(ans--)cout<<c;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bb6e201db464094c661d935f95d1c588", "src_uid": "9a40e9b122962a1f83b74ddee6246a40", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int h,w,c;\n    scanf(\"%d %d\",&h,&w);\n    long long s1;\n    s1 = h+w;\n    for(i=1;i<=n;i++)\n    s1 = (2*s1)%mod;\n    printf(\"%I64d\\n\",s1);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "196e60b5e3079aebd6ad1ae3155c29d9", "src_uid": "8b2a9ae21740c89079a6011a30cd6aee", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "\n#include<stdio.h>\n#define mod 998244353\nint main()\n{\n    int h,w,i;\n    scanf(\"%d %d\",&h,&w);\n    long long p,p1,s3;\n    p = 2;\n    for(i=2;i<=h;i++)\n    {\n        p = ((p%mod)*(p%mod))%mod;\n    }\n    p1 = 2;\n    for(i=2;i<=n;i++)\n    {\n        p1 = ((p1%mod)*(p1%mod))%mod;\n    }\n    s3 = ((p1%mod)*(p%mod))%mod;\n    printf(\"%I64d\\n\",s3);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5a6987535c80ce6ae70d85e8ce5672bf", "src_uid": "8b2a9ae21740c89079a6011a30cd6aee", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define mod 998244353\nint main()\n{\n    int h,w;\n    scanf(\"%d %d\",&h,&w);\n    long long ans = ((1<<h)%mod)*(1<<w)%mod)%mod);\n    printf(\"%I64d\\n\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "70f624b305d08308c865ef1c82d38cbb", "src_uid": "8b2a9ae21740c89079a6011a30cd6aee", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "import java.io.*;\nimport java.util.*;\nimport java.lang.Math;\n\npublic class CodeForces {\n\n    private static final Scanner scanner = new Scanner(System.in);\n\n    public static void main(String[] args) throws IOException {\n        int w = scanner.nextInt();\n        int h = scanner.nextInt();\n        long ans = (long) (4*Math.pow(2,w-1)*Math.pow(2,h-1))%998244353;\n        scanner.close();\n        System.out.println(ans);\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f61c32d7d439fddee28fbae9ab9db77e", "src_uid": "8b2a9ae21740c89079a6011a30cd6aee", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define mod 998244353\nint main()\n{\n    int h,w;\n    scanf(\"%d %d\",&h,&w);\n    long long ans = (((1<<h)%mod)*(1<<w)%mod))%mod);\n    printf(\"%I64d\\n\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a721b13ea9c69c707c569fabc4700a7f", "src_uid": "8b2a9ae21740c89079a6011a30cd6aee", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long f[60];\nint i,j;\nint n,k;\nint p[60];\n\nvoid dfs(int,int,long long);\n\nint main()\n{\n    scanf(\"%d%d\",&n,&k);\n    f[0]=f[1]=1;\n    for(i=2;i<=n;i++)\n    {\n        f[i]=f[i-1]+f[i-2];\n    }\n    dfs(1,n,k);\n    for(i=1;i<n;i++)\n        printf(\"%d \",p[i]);\n    printf(\"%d\\n\",p[i]);\n    return 0;\n}\n\nvoid dfs(int i,int j,long long tmp)\n{\n    int k,w,ww;\n    /*printf(\"%d %d %lld\\n\",i,j,tmp);*/\n    if(i==n+1) return;\n    for(k=1;k<=2 && k<=j;k++)\n    {\n        if(f[j-k]>=tmp)\n        {\n            w=i+k-1;\n            ww=i+k-1;\n            while(i<=ww)\n            {\n                p[i]=w;\n                i++;\n                w--;\n            }\n            dfs(i,j-k,tmp);\n            return;\n        }\n        else tmp-=f[j-k];\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "fd587e9efd9f46ff9006ae2ea9dbb5e0", "src_uid": "e03c6d3bb8cf9119530668765691a346", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long f[60];\nint i,j;\nint n,k;\nint p[60];\n\nvoid dfs(int,int,long long);\n\nint main()\n{\n    scanf(\"%d%lld\",&n,&k);\n    f[0]=f[1]=1;\n    for(i=2;i<=n;i++)\n    {\n        f[i]=f[i-1]+f[i-2];\n    }\n    dfs(1,n,k);\n    for(i=1;i<n;i++)\n        printf(\"%d \",p[i]);\n    printf(\"%d\\n\",p[i]);\n    return 0;\n}\n\nvoid dfs(int i,int j,long long tmp)\n{\n    int k,w,ww;\n    /*printf(\"%d %d %lld\\n\",i,j,tmp);*/\n    if(i==n+1) return;\n    for(k=1;k<=2 && k<=j;k++)\n    {\n        if(f[j-k]>=tmp)\n        {\n            w=i+k-1;\n            ww=i+k-1;\n            while(i<=ww)\n            {\n                p[i]=w;\n                i++;\n                w--;\n            }\n            dfs(i,j-k,tmp);\n            return;\n        }\n        else tmp-=f[j-k];\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ff979f8c67dacb8024221e349701c481", "src_uid": "e03c6d3bb8cf9119530668765691a346", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long f[60];\nint i,j;\nint n,k;\nint p[60];\n\nvoid dfs(int,int,long long);\n\nint main()\n{\n    scanf(\"%d%d\",&n,&k);\n    f[0]=f[1]=1;\n    for(i=2;i<=n;i++)\n    {\n        f[i]=f[i-1]*2;\n    }\n    dfs(1,n,k);\n    for(i=1;i<n;i++)\n        printf(\"%d \",p[i]);\n    printf(\"%d\\n\",p[i]);\n    return 0;\n}\n\nvoid dfs(int i,int j,long long tmp)\n{\n    int k,w,ww;\n    /*printf(\"%d %d %lld\\n\",i,j,tmp);*/\n    if(i==n+1) return;\n    for(k=1;k<=j;k++)\n    {\n        if(f[j-k]>=tmp)\n        {\n            w=i+k-1;\n            ww=i+k-1;\n            while(i<=ww)\n            {\n                p[i]=w;\n                i++;\n                w--;\n            }\n            dfs(i,j-k,tmp);\n            return;\n        }\n        else tmp-=f[j-k];\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c4181088fc7c6bd3ec6d462d35300580", "src_uid": "e03c6d3bb8cf9119530668765691a346", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main(){\n\tint n,i;\n\tlong long k,*left;\n\tscanf(\"%d %I64d\",&n,&k);\n\tif(n<3){\n\t\tif(k==1){\n\t\t\tprintf(\"1\");\n\t\t\tif(n==1)\n\t\t\t\tprintf(\"\\n\");\n\t\t\telse\n\t\t\t\tprintf(\" 2\\n\");\n\t\t}\n\t\telse\n\t\t\tprintf(\"2 1\\n\");\n\t\treturn 0;\n\t}\n\tleft=(long long *)malloc(sizeof(long long)*n);\n\tleft--;\n\tleft[n]=-1;\n\tleft[n-1]=0;\n\tleft[n-2]=1;\n\tfor(i=n-3;i>0;i--){\n\t\tleft[i]=left[i+1]+left[i+3]+2;\n\t}\n\tk--;\n\tfor(i=1;i<n;i++){\n\t\tif(k>left[i]){\n\t\t\tprintf(\"%d %d \",i+1,i);\n\t\t\tk-=left[i]+1;\n\t\t\ti++;\n\t\t}\n\t\telse\n\t\t\tprintf(\"%d \",i);\n\t}\n\tif(i==n)\n\t\tprintf(\"%d \",n);\n\tprintf(\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "477cdceb1e776dbaf60ab837f27539d2", "src_uid": "e03c6d3bb8cf9119530668765691a346", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\ntypedef long long unsigned llu;\ntypedef unsigned u;\nvoid F(u n,llu l,u p)\n{\n\tif(!n){printf(\"%u\\n\",p);return;}\n\tu i=1,j=n-1;\n\twhile((1llu<<j)<l){l-=(1llu<<j--);++i;}\n\tfor(j=i;j--;)printf(\"%u \",j+p);\n\tif(n>=i)F(n-i,l,p+i);\n\treturn;\n}\nint main()\n{\n\tu n;llu l;\n\tscanf(\"%u%I64u\",&n,&l);\n\tF(n-1,l,1);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "094bef8ef4751748c15fc9f634cadc53", "src_uid": "e03c6d3bb8cf9119530668765691a346", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#define MAX 107\n#define MIN 1000007\n\nint main()\n{\n\tint x, n, i, a[MAX], j, ans = MIN;\n\tscanf(\"%d\", &n);\n\tfor(i=0;i<n;++i)\n\t{\n\t\tscanf(\"%d\", &a[i]);\n\t}\n\tfor(i=1;i<=n;++i)\n\t{\n\t\tx = 0;\n\t\tfor(j=0;j<n;++j)\n\t\t{\n\t\t\tx += (abs(j + 1 - i) + j + abs(i - 1)) * 2 * a[j];\n\t\t}\n\t\tans = ans > x ? x : ans;\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "86a4209c7e49703c3ebfc0fe74c38776", "src_uid": "a5002ddf9e792cb4b4685e630f1e1b8f", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main(void)\n{\n    int n,i,j=0;\n    scanf(\"%d\", &n);\n    int k[n]\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\", &k[i]);\n        \n    }\n    for(i=0;i<n;i++)\n    {\n        j+=i*k[i];\n    }\n    printf(\"%d\", j*4);\n    return 0;\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5963e2c566946ba140ef81288840236e", "src_uid": "a5002ddf9e792cb4b4685e630f1e1b8f", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <cstdio>\n\nint n;\nint A[110];\nint ab(int a){\n    if(a<0)return -a;\n    return a;\n}\nint main(){\n   // freopen(\"input.txt\",\"r\",stdin);\n    scanf(\"%d\",&n);\n    int i,x;\n    for(i=1;i<=n;i++){\n        scanf(\"%d\",&A[i]);\n    }\n    int val=0,tv=0,mn=2147483647;\n    for(x=1;x<=n;x++){\n        tv=0;\n        for(i=1;i<=n;i++){\n            val=0;\n            val+=ab(i-x)+i+x-2;\n            val+=x+i-2+ab(x-i);\n            tv+=(A[i]*val);\n        }\n        if(mn>tv)mn=tv;\n    }\n    printf(\"%d\\n\",mn);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f51e636fd0afb7f65beeda90e6bd487a", "src_uid": "a5002ddf9e792cb4b4685e630f1e1b8f", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    int a[n+1],i,;\n    for(i=1;i<=n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    int u,units=0;\n\n    for(i=1;i<=n;i++)\n    {\n        u=(i-1)*4;\n        units=units+u*a[i];\n    }\n    printf(\"%d\",units);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "806025a55fb8e7c4696d05b5fd5d9ca9", "src_uid": "a5002ddf9e792cb4b4685e630f1e1b8f", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include<math.h>\nvoid main()\n{\n\tint n,max=0,mi=0,sum=0,sum1=0;\n\tscanf(\"%d\",&n);\n\tint a[n];\n\tfor(int i=0; i<n; i++)\n\t{\n\t\tscanf(\"%d\",&a[i]);\n\t\tif(max<a[i])\n\t\t{\n\t\t\tmax=a[i];\n\t\t\tmi=i;\n\t\t}\n\t}\n\tint b=n-1;\n\tfor(int j=0; j<n; j++)\n\t{\n\t\tsum= (j-mi) + (j-0) + 2*(mi-0) + abs(0-j) + abs(mi-j);\n\t\tsum1= sum1 + sum*a[j];\n\t\tsum=0;\n\t}\n\tprintf(\"%d\",sum1);\n\n} \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f9b5a81fad8a9000a663f710a5afbcb4", "src_uid": "a5002ddf9e792cb4b4685e630f1e1b8f", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n\tint a,b,c,d,e;\n\tscanf(\"%d %d %d %d %d\",&a,&b,&c,&d,&e);\n\tprintf(\"%d\",min(a,min(b,min(c/2,min(d/7,e/4)))));\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0e020a3347c9ed43580e168fbbbab772", "src_uid": "f914f9b7884cc04b990c7800c6be7b10", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define min(a,b) (a>b) (b):(a) \nint main(){\n\tint a,b,c,d,e,s=0;\n\tscanf(\"%d %d %d %d %d\",&a,&b,&c,&d,&e);\n\tprintf(\"%d\",min(a,min(b,min(c/2,min(d/7,e/4)))));\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6703776a28a768247c57933d4c1cecd6", "src_uid": "f914f9b7884cc04b990c7800c6be7b10", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint srx[6],sry,i;\nint min(int x,int y)\n{\n    if(x<y)\n    return x;\n    return y;\n}\nint main()\n{\n    for(i=1;i<=5;i++)\n    scanf(\"%d\",&srx[i]);\n    srx[3]/=2;\n    srx[4]/=7;\n    srx[5]/=4;\n    sry=min(min(min(min(srx[1],srx[2]),srx[3]),srx[4]),srx[5]);\n    printf(\"%d\",sry);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "10c8dc86f4fda2f5d3edccbc30ff5829", "src_uid": "f914f9b7884cc04b990c7800c6be7b10", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int af, ar, am, mi, vit;\n    scanf(\"%d %d %d %d %d\", &af, &ar, &am, &mi, &vit);\n    am= am/2;\n    mi=mi/7;\n    vit=vit/4;\n    if(vit<=af && vit<=ar && vit<=am && vit<=mi)\n    {\n        printf(\"%d\", vit);\n    }\n    else if(af<=ar && af<=am && af<=mi && af<=vit)\n    {\n        printf(\"%d\", af);\n    }\n    else if(ar<=af && ar<=am && ar<=mi && ar<=vit)\n    {\n        printf(\"%d\", ar);\n    }\n    else if(am<=af && am<=ar && am<=mi && am<=vit)\n    {\n        printf(\"%d\", am);\n    }\n    else if(mi<=af && mi<=ar && mi<=am && mi<=vit)\n    {\n        printf(\"%d\", mi);\n    }\n\n    main();\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "488d88341c521e8f4a621fe73b62e63a", "src_uid": "f914f9b7884cc04b990c7800c6be7b10", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int arr[5],i,arr2[]={1,1,2,7,4};\n    int min=1000;\n    for(i=0;i<5;i++)\n    {\n    \n    scanf(\"%d\",&arr[i]);\n    if(arr[i]/arr2[i]<min)\n    min=arr[i]/arr2[i];\n    \n     }\n     printf(\"%d\",min);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "60c267b78c1a191c07598bc7e64e9a06", "src_uid": "f914f9b7884cc04b990c7800c6be7b10", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint a[10],i,j,k;\nchar c;\n\nint main\n{\n    j=0;\n    scanf(\"%d\",&k);\n    for(i=0;i<5;i++)\n    {\n                    for(j=0;j<5;j++)\n                    {\n                                    scanf(\"%c\",&c);\n                                    if(c=='1') a[1]++;\n                                    if(c=='2') a[2]++;\n                                    if(c=='3') a[3]++;\n                                    if(c=='4') a[4]++;\n                                    if(c=='5') a[5]++;\n                                    if(c=='6') a[6]++;\n                                    if(c=='7') a[7]++;\n                                    if(c=='8') a[8]++;\n                                    if(c=='9') a[9]++;\n                                    }\n                    }\n    j=0;\n    for(i=1;i<10;i++)\n    if(2*k<a[i]) j=1;\n    if(j==1) printf(\"NO\"); else printf(\"YES\");\n    return 0;\n    }\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "cdde6311fd1359cdb08c89b721bb493e", "src_uid": "5fdaf8ee7763cb5815f49c0c38398f16", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <string.h>\n#include <stdio.h>\nint main()\n{\n     int k;\n     scanf(\"%d\\n\",&k);\n     int i,j,l;\n     char ch[4][4],str;\n     for(i=0;i<4;i++)\n     {\n          scanf(\"%s\",ch[i]);\n     }\n     int cnt[9];\n     for(str='1';str<='9';str++)\n     {\n          cnt[str]=0;\n     }\n     char q,w;\n     for(i=0;i<4;i++)\n     {\n          for(j=0;j<4;j++)\n          {\n               q=ch[i][j];\n               if(q!='.')\n               {\n                    cnt[q]++;\n               }\n          }\n     }\n     for(str='1';str<='9';str++)\n     {\n          if(cnt[str]<=2*k)\n          l++;\n          else \n          {\n               o=1;\n               break;\n          }\n     }\n     if(o==1)\n     printf(\"NO\");\n     if(l==9)\n     printf(\"YES\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a9e0acb2330cca517de8946049bd22ff", "src_uid": "5fdaf8ee7763cb5815f49c0c38398f16", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<cstdio>\n#include<cmath>\n#include<algorithm>\n#include<cstdlib>\n#include<cstring>\nusing namespace std;\n\nint main()\n{\n    int k,i,a[10]={0};\n    char s[5];\n    scanf(\"%d\",&k);\n    k=k*2;\n    for(i=0;i<4;i++)\n    {\n        scanf(\"%s\",s);\n        if(s[0]!='.') \n\t\t{\n\t\t\ta[s[0]-'0']++;\n\t\t}\n        if(s[1]!='.')\n\t\t{\n\t\t\ta[s[1]-'0']++;\n\t\t}\n        if(s[2]!='.') \n\t\t{\n\t\t\ta[s[2]-'0']++;\n\t\t}\n        if(s[3]!='.')\n\t\t{\n\t\t\ta[s[3]-'0']++;\n\t\t}\n    }\n    for(i=0;i<10;i++)\n    {   \n\t\tif(a[i]>k)\n        {\n            printf(\"NO\\n\");\n            return 0;\n        }\n    }\n    printf(\"YES\\n\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d02b4f60d40916a61b7716ff0798f5e6", "src_uid": "5fdaf8ee7763cb5815f49c0c38398f16", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <string.h>\n#include <stdio.h>\nint main()\n{\n     int k;\n     scanf(\"%d\\n\",&k);\n     int i,j,k,l;\n     char ch[4][4],str;\n     for(i=0;i<4;i++)\n     {\n          scanf(\"%s\",ch[i]);\n     }\n     int cnt[9];\n     for(str='1';str<='9';str++)\n     {\n          cnt[str]=0;\n     }\n     char q,w;\n     for(i=0;i<4;i++)\n     {\n          for(j=0;j<4;j++)\n          {\n               q=ch[i][j];\n               if(q!='.')\n               {\n                    cnt[q]++;\n               }\n          }\n     }\n     for(str='1';str<='9';str++)\n     {\n          if(cnt[str]<=2*k)\n          l++;\n          else \n          {\n               o=1;\n               break;\n          }\n     }\n     if(o==1)\n     printf(\"NO\");\n     if(l==9)\n     printf(\"YES\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f661484ecbedb8ad1ebcd9743152b852", "src_uid": "5fdaf8ee7763cb5815f49c0c38398f16", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n//#include<conio.h>\n\nusing namespace std;\n\nint main(void)\n{\n    int k,i,j,conv,flag,q;\n    scanf(\"%d\",&k);\n    int a[9]={0};\n    flag=0;\n    char str[5];\n    for(i=0; i<4; i++)\n    {\n                  scanf(\"%s\",str);\n              //    printf(\"\\n%s\",str);\n                  for(q=0; q<4; q++)\n                  {\n                  conv=str[q];\n            //      printf(\"\\n c=%c d=%d\",str[q],conv);\n                  switch(conv)\n                  {\n                            case 49 : a[0]++;\n                                      break;\n                            case 50 : a[1]++;\n                                      break;\n                            case 51 : a[2]++;\n                                      break;\n                            case 52 : a[3]++;\n                                      break;\n                            case 53 : a[4]++;\n                                      break;\n                            case 54 : a[5]++;\n                                      break;\n                            case 55 : a[6]++;\n                                      break;\n                            case 56 : a[7]++;\n                                      break;\n                            case 57 : a[8]++;\n                                      break;\n                            case 46 : break;\n                  }\n               //   }\n             }\n    }\n    k*=2;\n    for(i=0; i<9; i++)\n    {\n             if(a[i]>k)\n             {\n                 flag=1;\n                 break;\n             }\n             if(flag==1)\n                break;\n    }\n    if(flag==1)\n        printf(\"NO\");\n    else\n        printf(\"YES\");\n  //  getch();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "53e5614d752a9c321dd016a9b8f03e8a", "src_uid": "5fdaf8ee7763cb5815f49c0c38398f16", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    int t,i,k,j,l,m,n,count,sum,count1;\n    char s[10005],s1[10005];\n    scanf(\"%d\",&n);\n    scanf(\"%s\",s);\n    s1[0]=s[0];\n    m=1;\n    count=1;\n    for(i=1;i<n;)\n    {\n        if(s[i]!=s1[0])\n        {\n            count++;\n            s1[m]=s[i];\n            m++;\n            i++;\n        }\n        else\n        {\n            count1=0;\n            for(j=0;j<m;j++)\n            {\n               if(s1[j]==s[m+j]) \n               count1++;\n               else\n               break;\n            }\n            if(count1==m)\n            {\n                count++;\n                i=2*(m);\n                for(j=m;j<(2*m);j++)\n                s1[j]=s1[j-m];\n                m=2*m;\n            }\n            else\n            {\n                count++;\n                s1[m]=s[i];\n                m++;\n                i++;\n            }\n        }\n    }\n   // printf(\"%s\\n\",s1);\n    printf(\"%d\\n\",count);\n    for(j=0;j<n;j++)\n    {\n        s1[j]='\\0';\n        s[j]='\\0';\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "044f10ae04375ebc7038e920a9645320", "src_uid": "ed8725e4717c82fa7cfa56178057bca3", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char A[100];\n    int n,i,j,k=0,m,l;\n\n    scanf(\"%d\",&n);\n    scanf(\"%s\",A);\n\n    for(i=n;i>=0;i--)\n    {\n        l=0;\n        if(i%2==0)\n        {\n            j=i/2;\n            m=j;\n            for(k=0;k<j;k++)\n            {\n                if(A[k]==A[m]) l++,m++;\n            }\n            if(j==0)\n            {\n                printf(\"%d\",n);\n                return 0;\n            }\n            else if(j==l)\n            {\n                printf(\"%d\",(n-l)+1);\n                return 0;\n            }\n        }\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b550211aa890b3324e08984f9dfcba4d", "src_uid": "ed8725e4717c82fa7cfa56178057bca3", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main(){\n\t\n\tint n,i,j,k,count=0,l=0,sum=0;\n\tchar s[100],s1[100];\n\t\n\tscanf(\"%d\",&n);\n\tgetchar();\n\t\n\tgets(s);\n\t\n\tl=strlen(s);\n\t\n\t//printf(\"l:%d\\n\",l);\n\tif(l%2!=0)\n\t\tj=l-1;\n\telse\n\t\tj=l;\t\n\t\n\twhile(j>=1){\n\t\t\n\t//\tprintf(\"\\nj:%d\\n\",j);\n\t\tfor(i=0;i<(j/2);i++){\n\t\t\t\n\t//\t\tprintf(\"s[%d]:%c,s[%d]:%c,\",i,s[i],(i+(j/2)),s[i+(j/2)]);\n\t\t\tif(s[i]!=s[i+(j/2)])\n\t\t\t\tbreak;\n\t\t\telse\n\t\t\t\tcount++;\n\t//\t\tprintf(\"count:%d\\n\",count);\t\t\t\n\t\t}\n\t\t\n\t\tif(count==(j/2)){\n\t\t\tsum=count;\n\t\t\tbreak;\n\t\t}\n\t\tcount=0;\n\t\n\t\tj=j-2;\t\n\t}\n\t\n\tif(sum!=0)\n\t\tprintf(\"%d\\n\",(sum+1)+(l-(2*sum)));\t\n\telse\n\t\tprintf(\"%d\\n\",strlen(s));\t\t\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "69ed064fbc4f19a918b504c546d93cc5", "src_uid": "ed8725e4717c82fa7cfa56178057bca3", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main() {\n\tint i, j, k, len, flag = 0;\n\tchar str[100];\n\tscanf(\"%d\", &len);\n\tscanf(\"%s\", str);\n\tj = k = len / 2;\n\t\n\twhile(k > 0){\n\t\tj = k;\n\t\ti = 0;\n\t\twhile(str[i] == str[j] && j > i){\n\t\t\tif(i + 1 == k){\n\t\t\t\tflag = 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\ti++;\n\t\t\tj++;\n\t\t}\n\t\tif(flag == 1)\n\t\t\tbreak;\n\t\tk--;\n\t}\t\n\tif(flag == 1)\n\t\tprintf(\"%d\\n\", len + 1 - k);\n\telse \n\t\tprintf(\"%d\\n\", len);\t\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a0139d3b23ab05f0c1b0ba01afe49d5d", "src_uid": "ed8725e4717c82fa7cfa56178057bca3", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main() {\n\n    int n,i,j,k,c=1,m=0;\n    scanf(\"%d\",&n);\n    char a[n+1];\n    scanf(\"%s\",a);\n    for(i=0;i<n;i++)\n    {\n        for(j=i+1;j<n;j++)\n        {\n            if(a[i]==a[j])\n            {\n                a[j]=0;\n                for(k=1;k<j-i;k++)\n                {\n                    if(a[i+k]==a[j+k])\n                    {\n                        c++;\n                        a[j+k]=1;\n                    }\n                    if(c>m)\n                        m=c;\n                }\n                c=1;\n            }\n        }\n    }\n    if(m)\n    printf(\"%d\",n-m+1);\n    else\n        printf(\"%d\",n);\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "544a80b62adc7281241926962e50c773", "src_uid": "ed8725e4717c82fa7cfa56178057bca3", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include<math.h>\nint main(){\n    int a,b,c,d,ans=0;\n    scanf(%d %d %d %d,&a,&b,&c,&d);\n    if (a>b){\n        int temp=a;\n        a=b;\n        b=temp;\n    }\n    if (b>c){\n        int temp=b;\n        b=c;\n        c=temp;\n    }\n    if (a>b){\n        int temp=a;\n        a=b;\n        b=temp;\n    }\n    if (abs(b-a)<d){\n        ans+=abs(b-a);\n    }\n    if ((abs(c-b)<d){\n        ans+=abs(c-b);\n    }\n    printf(%d,ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "63142ffd68b7ab4df79e1de5ec0a6b0b", "src_uid": "47c07e46517dbc937e2e779ec0d74eb3", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\nint main()\n{\n                  int s[3],d;\n                  cin>>s[0]>>s[1]>>s[2]>>d;\n                  sort(s,s+3);\n                  cout<<max(0,d-(s[1]-s[0]))+max(0,d-(s[2]-s[1]));\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e3d1c52688030dc10125b95b855069d1", "src_uid": "47c07e46517dbc937e2e779ec0d74eb3", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n in main()\n { int a[3],i,d,e,j,x,y,z=0;\n for(i=0;i<3;i++)\n scanf(\"%d\",&a[i]);\n scanf(\"%d\",&d);\n for(i=0;i<3;i++)\n for(j=i;j<3;j++)\n if(a[j+1]<a[j])\n {e=a[j];\n a[j]=a[j+1];\n a[j+1]=a[j];}\n x=a[1]-a[0];\n y=a[2]-a[1];\n if(x<d)\n z=z+d-x;\n if(y<d)\n z=z+d-y;\n printf(\"%d\",z);\n return(0);}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5939695b2e94e49f9641eb087facecb9", "src_uid": "47c07e46517dbc937e2e779ec0d74eb3", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int a[5],i,t,s,d,l;\n    for(i=1;i<=4;i++)\n    {scanf(\"%lld\",&a[i]);}\n    for(l=1;l<=2;l++)\n    {\n    for(i=1;i<3;i++)\n    {if(a[i+1]<a[i])\n     {t=a[i+1];\n      a[i+1]=a[i];\n      a[i]=t;\n     }\n    }}\n    if(a[2]-a[1]>=a[4]&&a[3]-a[2]>=a[4])\n    {printf(\"0\");}\n    else\n    {if(a[2]-a[1]>=a[4]&&a[3]-a[2]<a[4])\n     {s=a[4-a[3]+a[2];}\n     if(a[2]-a[1]<a[4]&&a[3]-a[2]>=a[4])\n     {s=a[4]-a[2]+a[1];}\n      if(a[2]-a[1]<a[4]&&a[3]-a[2]<a[4])\n     {s=a[4]-a[2]+a[1]+a[4]-a[3]+a[2];}\n    }\n    printf(\"%lld\",s);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2bc0b87f6f444baaefea3e07d895e14f", "src_uid": "47c07e46517dbc937e2e779ec0d74eb3", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<conio.h>\nmain()\n{\nint i,j;\nlong long int e[3];     \nlong long int a,b,c,d;\nlong long int min,max,temp,mid;\nlong long int diff1,diff2;\nlong long int ans1=0,ans2=0;\nscanf(\"%lld %lld %lld %lld\",&a,&b,&c,&d);\ne[0]=a;\ne[1]=b;\ne[2]=c;\nfor(i=0;i<2;i++)\n  {for(j=0;j<2;j++)\n    {if(a[j]>a[j+1])\n     {temp=a[j];\n     a[j]=a[j+1];\n     a[j+1]=temp;\n     }\n    }\n  }\n diff1=(e[1]-e[0]);\n diff2=(e[2]-e[1]);\n if(diff1<d)\n ans1=d-diff1;\n if(diff2<d)\n ans2=d-diff2;\n ans=ans1+ans2;\n printf(\"%lld\",ans);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3ce2544be3579a29871e10660ad4241b", "src_uid": "47c07e46517dbc937e2e779ec0d74eb3", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint n, i, n1 = 0, n2 = 0, ans;\n\tint s[110];\n\tscanf(\"%d\", &n);\n\tans = n;\n\tfor (i = 0; i < n; i++) scanf(\"%d\", &s[i]);\n\tfor (i = n-1; i >= 0; i--)\n\t{\n\t\tif (s[i] == 0)\n\t\t{\n\t\t\tn2++;\n\t\t\tn1 = 0;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tif (n2 != 0)\n\t\t\t{\n\t\t\t\twhile (s[i] == 1 && i >= 0)\n\t\t\t\t{\n\t\t\t\t\tn1++;\n\t\t\t\t\ti--;\n\t\t\t\t}\n\t\t\t\ti++;\n\t\t\t\tif (n1 < n2)\n\t\t\t\t{\n\t\t\t\t\tans -= n1;\n\t\t\t\t\tn1 = 0;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tans -= n2;\n\t\t\t\t\tn2 = 0;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "95459bf0e988769d26e43b7c8e79efbd", "src_uid": "c7b1f0b40e310f99936d1c33e4816b95", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int i, n, z, o;\n    int s[100] = { 0 }, a[2] = { 0 };\n\n    scanf(\"%d\", &n);\n\n    for (i = 0; i < n; i++) {\n        scanf(\"%d \", s + i);\n    }\n\n    for (z = 0; z < n && s[z] != 1; z++) { }\n\n    for (o = 0; i < n && s[n - 1 - o] == 1; o++) { }\n\n    for (i = z; i < n - o; i++) {\n        a[s[i]] += 1;\n    }\n\n    if (a[0] > a[1]) {\n        printf(\"%d\\n\", z + a[0] + o);\n    } else {\n        printf(\"%d\\n\", z + a[1] + o);\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7077a7e18ffd7a2828b689815a7565dd", "src_uid": "c7b1f0b40e310f99936d1c33e4816b95", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nvoid main()\n{\n    int n,m,k,f=1,i;\n    scanf(\"%d\",&n);\n     for(k=i=0;i<n;i++)\n        {\n            scanf(\"%d\",&m);\n            if(f==1&&m==0) k++;\n            else if(m==1)\n                {\n                    k++; f=0;\n                }\n            else if(m==0&&f==0)\n                {\n                    f=1; continue;\n                }\n        }\n       printf(\"%d\\n\",k);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2d5c1e35aceb68f21ad6fdf05648e949", "src_uid": "c7b1f0b40e310f99936d1c33e4816b95", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nvoid main()\n{\n    int n,m,f=0,k=0,j=0,s=0,t=0,m1=0;\n    scanf(\"%d\",&n);\n    while(n--)\n    {\n        scanf(\"%d\",&m);\n        if(m==0) { k++; t=0; m1++; }\n        else if(m==1)\n        {\n            if(t==0)\n            {\n                if(j<k)\n                    {\n                        s=m1; k=0; j=0;\n                    }\n                else\n                    k=0;\n                t=1;\n            }\n            j++; f=1;\n        }\n    }\n    if(f==0) printf(\"%d\\n\",m1);\n    else printf(\"%d\\n\",s+j);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a3e571e41818ed0ed15ff56b82b51de8", "src_uid": "c7b1f0b40e310f99936d1c33e4816b95", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nvoid main()\n{\n    int n,m,f,k,j,s,t,m1;\n    scanf(\"%d\",&n);\n    f=m1=t=j=k=s=0;\n    while(n--)\n    {\n        scanf(\"%d\",&m);\n        if(m==0) { k++; t=0; m1++; }\n        if(m==1)\n        {\n            if(t==0)\n            {\n                if(j<k)\n                    {\n                        s=m1; k=j=0;\n                    }\n                else\n                    k=0;\n                t=1;\n            }\n            j++; f=1;\n        }\n    }\n    if(f==0) printf(\"%d\\n\",m1);\n    else printf(\"%d\\n\",s+j);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a7a8e1487e6f13eea5e3ff60a799a2a6", "src_uid": "c7b1f0b40e310f99936d1c33e4816b95", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main()\n{\n    long long a,b;\n    scanf(\"%I64d %I64d\",&a,&b);\n    if(a>[b){\n        printf(\"%I64d\\n\",b/2);\n        return 0;\n    }\n    else if((2*a-1)>=b){\n            printf(\"%I64d\",((b/2)-(b-1-a)));\n        }\n    else printf(\"0\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "33fdc474f37cecd529f73bf33fe0294a", "src_uid": "98624ab2fcd2a50a75788a29e04999ad", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <math.h>\n#include <stdio.h>\n#include <string.h>\nint main()\n{\n  long long int n,k,i,j,s=0;\n  scanf(\"%I64d\",&n);\n  scanf(\"%I64d\",&k);\n  long long int j=0;\n  for(i=1;i<=n;i++){\n    s=0;\n    for(j=1;j<k;j++){\n      s=i+j;\n      if(s==0){\n        j++;\n      }\n    }\n  } \n  printf(\"%I64d\\n\",j);\n  return 0;\n} ", "lang_cluster": "C", "compilation_error": true, "code_uid": "a26cae7e1d2635450765d03bc3f56738", "src_uid": "98624ab2fcd2a50a75788a29e04999ad", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main()\n{\n    long long a,b;\n    scanf(\"%I64d %I64d\",&a,&b);\n    if(a>[b){\n        printf(\"%I64d\\n\",b/2);\n        return 0;\n    }\n    else if((2*a-1)>=b){\n            if((2*a-1)==b) \n                printf(\"1\\n\");\n            else printf(\"%I64d\",((b/2)-(b-1-a)));\n        }\n    else printf(\"0\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c050360b4cbba5fb00b5af4533529962", "src_uid": "98624ab2fcd2a50a75788a29e04999ad", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\n\nmain(){\n    long long a, b;\n    cin>>a>>b;\n\n    if(b<a){\n        cout<<b/2<<endl;\n        return 0;\n    }\n\n    if((b/2) > a){\n        cout<<\"0\"<<endl;\n        return 0;\n    }\n\n    long long c= (b-1)/2 +1;\n\n    cout<< a-c+1 << endl;\n\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "baadb7ff7595660f6bfddceb6f358adf", "src_uid": "98624ab2fcd2a50a75788a29e04999ad", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main()\n{\n    long long a,b;\n    scanf(\"%I64d %I64d\",&a,&b);\n    if(a>[b){\n        printf(\"%I64d\\n\",b/2);\n        return 0;\n    }\n    else if((2*a-1)>=b){\n            if((2*a-1)=>=b) \n                printf(\"1\\n\");\n            else printf(\"%I64d\",((b/2)-(b-1-a)));\n        }\n    else printf(\"0\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0b1f4f80e482a03e254f1383944dc7ff", "src_uid": "98624ab2fcd2a50a75788a29e04999ad", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\n#define N 19\n\nchar strL[N+1], strR[N+1];\nint l, r, i, n, j, sum, k;\nint bufL[N] = {0}, bufR[N] = {0};\nint *L, *R;\nint num[10] = {0}, has[10] = {0};\n\nint ok(void) {\n\tif(n == 0) {\n\t\treturn 1;\n\t}\n\tfor(j = 0; j < 10; j++) {\n\t\thas[j] = num[j];\n\t}\n\tfor(j = L[0]+1; j < R[0]; j++) {\n\t\tif(has[j] > 0) {\n\t\t\treturn 1;\n\t\t}\n\t}\n\tif(has[L[0]] > 0) {\n\t\thas[L[0]]--;\n\t\tfor(i = 1; i < n+1; i++) {\n\t\t\tif(i >= n) {\n\t\t\t\treturn 1;\n\t\t\t}\n\t\t\tfor(j = L[i]+1; j < 10; j++) {\n\t\t\t\tif(has[j] > 0) {\n\t\t\t\t\treturn 1;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(has[L[i]] > 0) {\n\t\t\t\thas[L[i]]--;\n\t\t\t} else {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\thas[L[0]]++;\n\t}\n\tif(has[R[0]] > 0) {\n\t\thas[R[0]]--;\n\t\tfor(i = 1; i < n+1; i++) {\n\t\t\tif(i >= n) {\n\t\t\t\treturn 1;\n\t\t\t}\n\t\t\tfor(j = 0; j < R[i]; j++) {\n\t\t\t\tif(has[j] > 0) {\n\t\t\t\t\treturn 1;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(has[R[i]] > 0) {\n\t\t\t\thas[R[i]]--;\n\t\t\t} else {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\thas[R[0]]++;\n\t}\n\treturn 0;\n}\n\nint main(void) {\n\tscanf(\"%s%s\", strL, strR);\n\tl = strlen(strL);\n\tr = strlen(strR);\n\tL = bufL;\n\tR = bufR;\n\tfor(i = 0; i < l; i++) {\n\t\tL[N-l+i] = strL[i] - '0';\n\t}\n\tfor(i = 0; i < r; i++) {\n\t\tR[N-r+i] = strR[i] - '0';\n\t}\n\tfor(i = 0; i < N && L[i] == R[i]; i++);\n\tL += i;\n\tR += i;\n\tn = N - i;\n\tsum = 0;\n\tk = 0;\n\twhile(1) {\n\t\tfor(j = 0; sum > n; j++) {\n\t\t\tif(j >= 8) {\n\t\t\t\tgoto finish;\n\t\t\t}\n\t\t\tsum -= num[j];\n\t\t\tnum[j] = 0;\n\t\t\tnum[j+1]++;\n\t\t\tsum++;\n\t\t}\n\t\tnum[9] = n - sum;\n\t\t/*\n\t\tfor(j = 0; j < 10; j++) {\n\t\t\tfor(i = 0; i < num[j]; i++) {\n\t\t\t\tprintf(\"%d\", j);\n\t\t\t}\n\t\t}\n\t\t*/\n\t\tif(ok()) {\n\t\t\t//printf(\" ok\");\n\t\t\tk++;\n\t\t}\n\t\t//printf(\"\\n\");\n\t\tnum[0]++;\n\t\tsum++;\n\t}\n\tfinish:\n\tprintf(\"%d\\n\", k);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c72c3c7f10b7f9d4faf50cb7728d03d4", "src_uid": "adfa5f280eefbacdbaa4ad605402b57a", "difficulty": 2700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\n#define N 19\n\nchar strL[N+1], strR[N+1];\nint l, r, i, n, j, sum, k;\nint bufL[N] = {0}, bufR[N] = {0};\nint *L, *R;\nint num[10] = {0}, has[10] = {0};\n\nint ok(void) {\n\tif(n == 0) {\n\t\treturn 1;\n\t}\n\tfor(j = 0; j < 10; j++) {\n\t\thas[j] = num[j];\n\t}\n\tfor(j = L[0]+1; j < R[0]; j++) {\n\t\tif(has[j] > 0) {\n\t\t\treturn 1;\n\t\t}\n\t}\n\tif(has[L[0]] > 0) {\n\t\thas[L[0]]--;\n\t\tfor(i = 1; i < n+1; i++) {\n\t\t\tif(i >= n) {\n\t\t\t\treturn 1;\n\t\t\t}\n\t\t\tfor(j = L[i]+1; j < 10; j++) {\n\t\t\t\tif(has[j] > 0) {\n\t\t\t\t\treturn 1;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(has[L[i]] > 0) {\n\t\t\t\thas[L[i]]--;\n\t\t\t} else {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tfor(j = 0; j < 10; j++) {\n\t\thas[j] = num[j];\n\t}\n\tif(has[R[0]] > 0) {\n\t\thas[R[0]]--;\n\t\tfor(i = 1; i < n+1; i++) {\n\t\t\tif(i >= n) {\n\t\t\t\treturn 1;\n\t\t\t}\n\t\t\tfor(j = 0; j < R[i]; j++) {\n\t\t\t\tif(has[j] > 0) {\n\t\t\t\t\treturn 1;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(has[R[i]] > 0) {\n\t\t\t\thas[R[i]]--;\n\t\t\t} else {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\n\nint main(void) {\n\tscanf(\"%s%s\", strL, strR);\n\tl = strlen(strL);\n\tr = strlen(strR);\n\tL = bufL;\n\tR = bufR;\n\tfor(i = 0; i < l; i++) {\n\t\tL[N-l+i] = strL[i] - '0';\n\t}\n\tfor(i = 0; i < r; i++) {\n\t\tR[N-r+i] = strR[i] - '0';\n\t}\n\tfor(i = 0; i < N && L[i] == R[i]; i++);\n\tL += i;\n\tR += i;\n\tn = N - i;\n\tsum = 0;\n\tk = 0;\n\twhile(1) {\n\t\tfor(j = 0; sum > n; j++) {\n\t\t\tif(j >= 8) {\n\t\t\t\tgoto finish;\n\t\t\t}\n\t\t\tsum -= num[j];\n\t\t\tnum[j] = 0;\n\t\t\tnum[j+1]++;\n\t\t\tsum++;\n\t\t}\n\t\tnum[9] = n - sum;\n\t\t/*\n\t\tfor(j = 0; j < 10; j++) {\n\t\t\tfor(i = 0; i < num[j]; i++) {\n\t\t\t\tprintf(\"%d\", j);\n\t\t\t}\n\t\t}\n\t\t*/\n\t\tif(ok()) {\n\t\t\t//printf(\" ok\");\n\t\t\tk++;\n\t\t}\n\t\t//printf(\"\\n\");\n\t\tnum[0]++;\n\t\tsum++;\n\t}\n\tfinish:\n\tprintf(\"%d\\n\", k);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7f000463d53dfcd1d5d43138ac00996f", "src_uid": "adfa5f280eefbacdbaa4ad605402b57a", "difficulty": 2700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main(){\nint r1,r2,c1,c2,d1,d2,a[2][2],i=1,j=0,k=0;\nscanf(\"%d%d%d%d%d%d\",&r1,&r2,&c1,&c2,&d1,&d2);\na[0][0]=0;\na[0][1]=1;\na[1][0]=0;\na[1][1]=0;\nwhile(1){\n    if((r1==a[0][0]+a[0][1])&&(r2==a[1][0]+a[1][1])&&(c1==a[0][0]+a[1][0])&&(c2==a[0][1]+a[1][1])&&(d1==a[0][0]+a[1][1])&&(d2==a[0][1]+a[1][0])){\n        printf(\"%d %d\\n%d %d\\\",a[0][0],a[0][1],a[1][0],a[1][1]);\n        return 0;\n    }\n    a[0][0]=rand()%10;\n    a[0][1]=rand()%10;\n    a[1][0]=rand()%10;\n    a[1][1]=rand()%10;\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3bfc96826a1833dcc4de2980d4c743ab", "src_uid": "6821f502f5b6ec95c505e5dd8f3cd5d3", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\n#include<stdlib.h>\nint main(){\n\tint x,y,z,m,i,r[100][100],c[100][100],d[100][100];\n\t\tfor(i=0;i<2;i++)\t\n\t\tscanf(\"%d\",&r[0][i]);\n\t\tfor(i=0;i<2;i++)\t\n\t\tscanf(\"%d\",&c[0][i]);\n\t\tfor(i=0;i<2;i++)\t\n\t\tscanf(\"%d\",&d[0][i]);\n\t\t\n\t\t\n\t\ty=(d[0][0]+r[0][0]-c[0][1])/2;\n\t\tx=c[0][1]+y-d[0][0];\n\t\tz=d[0][1]+y-r[0][0];\n\t\tm=r[0][1]+y-c[0][0];\n\t//\tprintf(\"%d\",y);\n\t\n\t\tif((x+y)!=r[0][0] || (z+m)!=r[0][1] || (x+m)!=c[0][1] || (z+y)!=c[0][0] ||(m+y)!=d[0][0] || (x+z)!=rd[0][1]|| y==x || y==z || y==m || x==z || x==m || z==m ){\n\t\tprintf(\"-1\");\n\t}\n\t\telse\t{\n\t\tprintf(\"%d %d\\n\",y,x);\n\t\tprintf(\"%d %d\",z,m);\n\t}\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t//\tsystem (\"pause\");\n\treturn 0;\n\t\t\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0ba8501e6229fb68fdca851e1e960634", "src_uid": "6821f502f5b6ec95c505e5dd8f3cd5d3", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n     int r1,r2,c1,c2,d1,d2,i,j,k,l,c=0;\n      scanf(\"%d %d %d %d %d %d\",&r1,&r2,&c1,&c2,&d1,&d2);\n   if(r1<1||r2<1||c1<1||c1<1||d1<1||d2<1||r1>20||r2>20||c1>20||c2>20||d1>20||d2>20)\n     printf(\"-1\");\n  else\n  {\n    for(i=1;i<=9;i++)\n      for(j=1;j<=9;j++)\n        for(k=1;k<=9;k++)\n          for(l=1;l<=9;l++)\n               if(i+j==r1&&i+k==c1&&k+l==r2&&j+l==c2&&i+l==d1&&j+k==d2&&i!=k&&j!=l&&i!=l&&j!=k&&i!=j&&k!=l)\n               {\n                  printf(\"%d %d\\n%d %d\",i,j,k,l);\n                 c=1;\n                 break;\n              if(c==0)\n                 printf(\"-1\");\n    }\n     return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "45dc2abe8d70a0b0a2ba7fc1793791c7", "src_uid": "6821f502f5b6ec95c505e5dd8f3cd5d3", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint main()\n{\n        int r1,r2,c1,c2,d1,d2,i,a,b,c,d,sign;\n    while(scanf(\"%d %d\",&r1,&r2)!=EOF)\n    {\n        scanf(\"%d %d\",&c1,&c2);\n        scanf(\"%d %d\",&d1,&d2);\n        for(i=1,sign=0;i<=9;i++)\n        {\n            a=i;\n            if(r1-a<0||r1-a>9)continue;\n            b=r1-a;\n            if(a==b)continue;\n            if(c1+d2-a-b<0||(c1+d2-a-b)%2!=0||(c1+d2-a-b)>18)continue;\n            c=(c1+d2-a-b)/2;\n            if(b==c||a==c)continue;\n            if(c2+r2+d1-a-b-c<0||(c2+r2+d1-a-b-c)%3!=0||(c2+r2+d1-a-b-c)>27)continue;\n            d=(c2+r2+d1-a-b-c)/3;\n            if(a==d||c==d||c==d)continue;\n            if(a+b==r1&&a+c==c1&&b+d==c2&&b+c==d2&&a+d==d1&&c+d==r2&&b>=1&&b<=9&&c>=1&&c<=9&&d>=1&&d<=9)\n            {sign++;break;}\n        }\n        if(sign!=0)\n            printf(\"%d %d\\n%d %d\\n\",a,b,c,d);\n        else\n            printf(\"-1\\n\");\n    }\n    return 0;\n}\n\n\n#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n\tint r1,r2,d1,d2,c1,c2;\n\tint a,b,c,d,flag;\n\twhile(~scanf(\"%d%d%d%d%d%d\",&r1,&r2,&c1,&c2,&d1,&d2))\n    {\n        flag=0;\n        for (a=1;a<=9;a++)\n        {\n            b=r1-a;\n            c=c1-a;\n            d=d1-a;\n            if (b+d==c2&&c+d==r2&&b+c==d2&&a!=b&&a!=c&&a!=d&&b!=c&&b!=d&&c!=d&&b>=1&&b<=9&&c>=1&&c<=9&&d>=1&&d<=9)\n            {\n                printf(\"%d %d\\n%d %d\\n\",a,b,c,d);\n            }\n            else\n                flag++;\n        }\n        if(flag==9)\n            printf(\"-1\\n\");\n    }\n    return 0;\n}\n\n                                                                                                                                                                          ", "lang_cluster": "C", "compilation_error": true, "code_uid": "6586b61501ce6e60a35f408e211a6057", "src_uid": "6821f502f5b6ec95c505e5dd8f3cd5d3", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n\tfloat r1,r2,c1,c2,d1,d1,x1,x2,x3,x4;\n\tint a,b,c,d;\n\t\n\tscanf(\"%f%f%f%f%f%f\",&r1,&r2,&c1,&c2,&d1,&d2);\n\t\n\tif((r1+r2!=c1+c2)||(r1+r2!=d1+d2)||(c1+c2!=d1+d2))\n\t\tprintf(\"-1\");\n\telse\n\t{\n\t\tx1=(d1-r2+c1)/2;\n\t\tx2=(d2+r1-c1)/2;\n\t\tx3=(d2-r1+c1)/2;\n\t\tx4=(r2-c1+d1)/2;\n\t\t\n\t\ta=(int)(x1);\n\t\tb=(int)(x2);\n\t\tc=(int)(x3);\n\t\td=(int)(x4);\n\t\t\n\t\tif(a==x1&&b==x2&&c==x3&&d==x4)\n\t\t{\n\t\t\tif(a!=b&&a!=c&&a!=d&&b!=c&&b!=d&&c!=d&&a>0&&b>0&&c>0&&d>0&&a<10&&b<10&&c<10&&d<10)\n\t\t\t\tprintf(\"%d %d\\n%d %d\",a,b,c,d);\n\t\t\telse\n\t\t\t\tprintf(\"-1\");\n\n\t\t}\n\t\t\n\t\telse\n\t\t\tprintf(\"-1\");\n\t\t\n\t}\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "78b19e1f79bc717531aa410c767b4f96", "src_uid": "6821f502f5b6ec95c505e5dd8f3cd5d3", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nlong long int isPrime(long long int n) \n{ \n    // Corner case \n    if(n==2 || n==1)\n        return 1;\n    if(n%2==0)\n        return 0;\n    if (n <= 1) \n        return 0; \n  \n    // Check from 2 to n-1 \n    for (long long int i = 2; i <= sqrt(n) + 1; i++) \n        if (n % i == 0) \n            return 0; \n  \n    return 1; \n} \nint main()\n{\n    long long int q, i, m; \n    scanf(\"%lld\",&q);\n    if(isPrime(q))\n    {\n        printf(\"1\\n0\");\n        return 0;\n    }\n    for(i=2;i<q;i++)\n    {\n        if(q%i==0 && isPrime(i))\n        {\n            break;\n        }\n    }\n    m = i;\n    for(i=m;i<q;i++)\n    {\n        if(!isPrime(i) && q%i==0)\n        {\n            printf(\"1\\n%lld\",i);\n            return 0;\n        }\n    }\n    printf(\"2\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "62b640a8d1c3461267a85e7c095e0c19", "src_uid": "f0a138b9f6ad979c5ca32437e05d6f43", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(int argc, char *argv[]) {\n    long long n,i,a=0,b=0,aux=0;\n    scanf(\"%I64d\",&n);\n    aux=n;\n    if(n<4){\n        printf(\"1\\n0\");\n        return 0;\n    }\n    if(n%2==0){\n        a=2;\n        n/=2;\n        \n        for(i=2;i<n/2;i++){\n            if(n%i==0){\n                b=i;\n                break;\n            }\n        }\n    }else{\n        for(i=2;i<n/2;i++){\n            if(n%i==0){\n                a=i;\n                n/=i;\n                break;\n            }\n        }\n        for(i=2;i<n/2;i++){\n            if(n%i==0){\n                b=i;\n                break;\n            }\n        }\n    }\n    if(a*b!=0){\n        printf(\"1\\n%I64d\",a*b);\n    }else{\n        if(a==0 && b==0){\n            printf(\"1\\n0\");\n        }else{\n            printf(\"2\");\n        }\n        \n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "20aaf9b33a231a8323318d963efa8fb8", "src_uid": "f0a138b9f6ad979c5ca32437e05d6f43", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\nlong long arr[40000005];\nchar str[2000001];\nchar s1[2000001];\nint func(const void *a, const void *b)\n{\n\treturn (*(int*)a-*(int*)b);\n}\nlong long max(long long a, long long b)\n{\n\treturn (a>b)?a:b;\n}\nlong long min(long long a, long long b)\n{\n\treturn (a>b)?b:a;\n}\nlong long power(long long  x, long long  int y, long long p)\n{\n\tlong long int res = 1;\n\tx = x % p; \n\twhile (y > 0)\n\t{\n\t\tif (y & 1)\n\t\t\tres = (res*x) % p;\n\t\ty = y>>1; // y = y/2\n\t\tx = (x*x) % p;  \n\t}\n\treturn res;\n}\nlong long isPrime(long long int n)\n{\n\tif (n <= 1)  return 0;\n\tif (n <= 3)  return 1;\n\tif (n%2 == 0 || n%3 == 0) return 0;\n\n\tfor (long long int i=5; i*i<=n; i=i+6)\n\t\tif (n%i == 0 || n%(i+2) == 0)\n\t\t\treturn 0;\n\treturn 1;\n}\nint main()\n{\n\tlong long int sum=0,a,b,x,y,n, m,temp,flag=0,index,len, i, j, k, count=0, ans=0;\n\tscanf(\"%lld\", &n);\n\tif(n==1 || isPrime(n)==1)\n\t{\n\t\tprintf(\"1\\n\");\n\t\tprintf(\"0\\n\");\n\t}\n\telse\n\t{\n\t\tfor(i=0;i<=40000005;i++)\n\t\t\tarr[i]=i;\n\t\tfor(i=2;i*i<=40000005;i++)\n\t\t\tif(arr[i]!=0)\n\t\t\t\tfor(j=0;j*i+i*i<=40000005;j++)\n\t\t\t\t\tarr[i*i+j*i]=0;\n\t\tfor(i=2;i<=40000005;i++)\n\t\t\tif(n%i==0 && arr[i]==0 && i!=n)\n\t\t\t{flag=1;break;}\n\t\t\t\n\t\tif(flag)\n\t\t{printf(\"1\\n\");printf(\"%lld\\n\",i);}\n\t\telse\n\t\t\tprintf(\"2\\n\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "446c60a2274d041764cb0e2cca9c06b0", "src_uid": "f0a138b9f6ad979c5ca32437e05d6f43", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\nint arr[20000005];\nchar str[2000001];\nchar s1[2000001];\nint func(const void *a, const void *b)\n{\n\treturn (*(int*)a-*(int*)b);\n}\nlong long max(long long a, long long b)\n{\n\treturn (a>b)?a:b;\n}\nlong long min(long long a, long long b)\n{\n\treturn (a>b)?b:a;\n}\nlong long power(long long  x, long long  int y, long long p)\n{\n\tlong long int res = 1;\n\tx = x % p; \n\twhile (y > 0)\n\t{\n\t\tif (y & 1)\n\t\t\tres = (res*x) % p;\n\t\ty = y>>1; // y = y/2\n\t\tx = (x*x) % p;  \n\t}\n\treturn res;\n}\nlong long isPrime(long long int n)\n{\n\tif (n <= 1)  return 0;\n\tif (n <= 3)  return 1;\n\tif (n%2 == 0 || n%3 == 0) return 0;\n\n\tfor (long long int i=5; i*i<=n; i=i+6)\n\t\tif (n%i == 0 || n%(i+2) == 0)\n\t\t\treturn 0;\n\treturn 1;\n}\nint main()\n{\n\tlong long int num1, num2,sum=0,a,b,x,y,n, m,temp,flag=0,index,len, i, j, k, count=0, ans=0;\n\tscanf(\"%lld\", &n);\n\tif(n==1 || isPrime(n)==1)\n\t{\n\t\tprintf(\"1\\n\");\n\t\tprintf(\"0\\n\");\n\t}\n\telse\n\t{\n\t\tfor(i=0;i<20000005;i++)\n\t\t\tarr[i]=i;\n\t\tarr[1]=0;\n\t\tfor(i=2;i*i<20000005;i++)\n\t\t\tif(arr[i]!=0)\n\t\t\t\tfor(j=0;j*i+i*i<20000005;j++)\n\t\t\t\t\tarr[i*i+j*i]=0;\n\n\t\tfor(i=2;i<20000005;i++)\n\t\t\tif(arr[i]!=0 && n%i==0)\n\t\t\t{num1=i;break;}\n\t\tfor(i=2;i<20000005;i++)\n\t\t\tif(arr[i]!=0 && n%i==0)\n\t\t\t{\n\t\t\t\tif(i==num1 && n%(i*i)==0)\n\t\t\t\t{num2=i;break;}\n\t\t\t\tif(i!=num1)\n\t\t\t\t{num2=i;break;}\n\t\t\t}\n\t\tfor(i=2;i<20000005;i++)\n\t\t\tif(arr[i]!=0 && n%i==0)\n\t\t\t{\n\t\t\t\tif(num1==num2 && n%(i*i*i)==0)\n\t\t\t\t{flag=1;break;}\n\t\t\t\tif(i!=num1 && i!=num2)\n\t\t\t\t{flag=1;break;}\n\t\t\t\tif(i==num1 || i==num2)\n\t\t\t\t{\n\t\t\t\t\tif(n%(num1*num1*num2)==0 || n%(num2*num2*num1)==0)\n\t\t\t\t\t{flag=1;break;}\n\t\t\t\t}\n\t\t\t}\n\t//\tprintf(\"%lld %lld\\n\",num1, num2);\n\t\tif(flag)\n\t\t{\n\t\t\tprintf(\"1\\n\");\n\t\t\tprintf(\"%lld\\n\",num1*num2);\n\t\t}\n\t\telse\n\t\t\tprintf(\"2\\n\");\n\t\t/*\n\t\tfor(i=2;i<=20000005;i++)\n\t\t\tif(n%i==0 && arr[i]==0 && i!=n)\n\t\t\t{flag=1;break;}\n\t\tif(flag)\n\t\t{printf(\"1\\n\");printf(\"%lld\\n\",i);}\n\t\telse\n\t\t\tprintf(\"2\\n\");\n\t\t\t*/\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9d03d8341bb580cf893d91d16312a2ea", "src_uid": "f0a138b9f6ad979c5ca32437e05d6f43", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n\nint main()\n{\n    long long int q,i,num,cnt,c,arr[10000000000000] ;\n\n    scanf(\"%I64d\",&q) ;\n\n    if(q==1){\n        printf(\"1\\n0\\n\") ;\n    }\n\n    else{\n\n    num=sqrt(q) ;\n\n    c=0;\n    cnt=0;\n    while(q%2==0){\n        cnt++;\n        q=q/2 ;\n        arr[c]=2;\n        c++;\n    }\n    for(i=3;i<=num;i=i+2){\n        while(q%i==0){\n            cnt++;\n            q=q/i ;\n            arr[c]=i ;\n            c++;\n        }\n    }\n    if(q>2){\n        cnt++;\n        arr[c]=q ;\n        c++;\n    }\n\n    if(cnt==2){\n        printf(\"2\\n\") ;\n    }\n    else if(cnt==1){\n        printf(\"1\\n0\\n\") ;\n    }\n    else{\n        printf(\"1\\n\") ;\n        printf(\"%I64d\\n\",(arr[0]*arr[1])) ;\n    }\n    }\n\n    return 0 ;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "039f31776c9118fee45d23de84deab91", "src_uid": "f0a138b9f6ad979c5ca32437e05d6f43", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n\n{\n\tint n,i,j,k=0,m;\n    scanf(\"%d\",&n);\n\tchar col[n];\n\tscanf(\"%s\",col);\n\tloop:\n\ti=0;\n\t\tif(col[i]=='B'){\n\t\t\tcol[i]='R';\n\t\t\tk++;\n\t\t\tgoto loop;\n\t\t}\n\t\telse if(col[i]=='R'){\n\t\t\tfor(j=i;j<n;j++){\n\t\t\t\tif(col[j]=='B'){\n\t\t\t\t\tcol[j]='R';\n\t\t\t\tfor(m=i;m<j;m++){\n\t\t\t\t\t\tcol[m]='B';\n\t\t\t\t\t}\n\t\t\t\t\tk++;\n\t\t\t\t\tgoto loop;\n\t\t\t\t}\n\t\t\t}\n\t\tprintf(\"%d\",k);\n\t}\t\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a0c4c26f3451c1c75efda7e2fe739193", "src_uid": "d86a1b5bf9fe9a985f7b030fedd29d58", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint isSolution(char *,int);\nvoid swap(char *x,char *y)\n{\n    char t=*x;\n    *x=*y;\n    *y=t;\n\n}\n\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    char S[50];\n    scanf(\"%s\",S);\n    int k=0;\n    int m=n-1;\n    while(k<m)\n    {\n        swap(&S[k++],&S[m--]);\n    }\n    int count=0;\n    int i=n-1;\n    while(!isSolution(S,n))\n    {\n\n        while(S[i]=='R')\n        {\n            i--;\n        }\n        S[i]='R';\n        i++;\n        while(i<n)\n        {\n            S[i]='B';\n            i++;\n        }\n        i--;\n        count++;\n    }\n    printf(\"%d\",count);\n    return 0;\n}\n\nint isSolution(char *S,int n)\n{\n    for(int i=0;i<n;i++)\n    {\n        if(S[i]=='B')\n        {\n            return 0;\n        }\n    }\n    return 1;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7de2212ecb72d60fbc47941c428eca6a", "src_uid": "d86a1b5bf9fe9a985f7b030fedd29d58", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n\n{\n\tint n,i,j,k=0,m;\n    scanf(\"%d\",&n);\n\tchar col[n];\n\tscanf(\"%s\",col);\n\tloop:\n\tfor(i=0;i<n;i++){\n\t\tif(col[i]=='B'){\n\t\t\tcol[i]='R';\n\t\t\tk++;\n\t\t\tgoto loop;\n\t\t}\n\t\telse if(col[i]=='R'){\n\t\t\tfor(j=i;j<n;j++){\n\t\t\t\tif(col[j]=='B'){\n\t\t\t\t\tcol[j]='R';\n\t\t\t\tfor(m=i;m<j;m++){\n\t\t\t\t\t\tcol[m]='B';\n\t\t\t\t\t}\n\t\t\t\t\tk++;\n\t\t\t\t\tgoto loop;\n\t\t\t\t}\n\t\t\t}\n\t}\t\n\n\t}\n\tprintf(\"%d\",k);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3d4e1ba335069ea7e841c36c0646a877", "src_uid": "d86a1b5bf9fe9a985f7b030fedd29d58", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.>\n#include<math.h>\nint main()\n{\n    int n,i,j;\n    unsigned long k=0;\n    scanf(\"%d\",&n);\n    char ch[n];\n    scanf(\"%s\",ch);\n    i=0;\n    if(ch[i]=='B'){\n        ch[i]='R';\n    }\n    loop:\n    if(ch[i]=='R'){\n        for(j=i;j<n;j++){\n            if(ch[j]=='B'){\n                k=k+pow(2,j);\n                ch[j]='R';\n                goto loop;\n            }\n        }\n    }\n    printf(\"%lu\",k);\n    return 0\n}\n    ", "lang_cluster": "C", "compilation_error": true, "code_uid": "9e09f61d48aa1aca4abb548fec49902b", "src_uid": "d86a1b5bf9fe9a985f7b030fedd29d58", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<math.h>\nint main()\n{\n    int n,i;\n    unsigned long s=0;\n    char c[50];\n    scanf(\"%d\",&n);\n    printf(\"\\n\");\n    scaf(\"%s\",&c);\n    for(i=0;i<n;i++)\n    {\n        if(c[i]=='B'){s=s+pow(2,i);}\n    }\n    printf(\"%lu\",s);\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3642b07a5af35721e36c8a7ad8c7cae2", "src_uid": "d86a1b5bf9fe9a985f7b030fedd29d58", "difficulty": null}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include<string.h>\nint main(void) {\n    int n,i,j;\n    char s[200];\n    scanf(\"%d\",&n);\n    scanf(\"%s\",s);\n    for(i=0;i<strlen(s)-2;)\n {\n    if(s[i]=='o'&&s[i+1]=='g'&&s[i+2]=='o')\n    {  s[i]='&';s[i+1]='#';s[i+2]='#';\n      i=i+3;\n      while(s[i]=='g'&&s[i+1]=='o')\n      {   s[i]='#';s[i+1]='#';\n          i=i+2;\n      }\n    }\n    else{i++;}\n }\n     for(i=0;i<strlen(s);)\n   {\n       if(s[i]=='&')\n       {\n           i++;\n           printf(\"***\");\n           while(s[i]=='#')\n           i++;\n       }\n       for(;i<strlen(s)&&s[i]!='&';i++)\n       printf(\"%c\",s[i]);\n   }\n   //printf(\"%s\",s);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "98ef4bcf66d5329660dc5c07d06a90b2", "src_uid": "619665bed79ecf77b083251fe6fe7eb3", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdlib.h>\n#include<stdio.h>\n#include<string.h>\nint main(){\n\tint n;\n\tscanf(\"%d\",&n);\n\tchar* str = (char*)malloc(n*sizeof(char));\n\tscanf(\"%s\",str);getchar();\n\tfor(int i=0;i<n;i++){\n\t\tif(n-i>=3 && str[i]=='o' && str[i+1]=='g' && str[i+2]=='o'){\n\t\t\tint k=i+3;\n\t\t\twhile(n-k>=2 && str[k]=='g' && str[k+1]=='o')k+=2;\n\t\t\tprintf(\"***\");\n\t\t\ti=k-1;\n\t\t}\n\t\telse printf(\"%c\",str[i]);\n\t}\n\tfree(str);\n} \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "83116f0b76c6b0f1709d7c26193b2069", "src_uid": "619665bed79ecf77b083251fe6fe7eb3", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int T;\n    scanf(\"%d\",&T);\n    char s[200]=\"\";\n    getchar();\n    for (int i=0;i<T;i++)\n        s[i]=getchar();\n    for (int i=0;i<T;)\n    {\n        //printf(\"1\");\n        if (s[i]!='o')\n        {putchar(s[i]);\n        i++;\n        continue;}\n        if (s[i+1]=='g'&&s[i+2]=='o')\n        {\n            printf(\"***\");\n            i+=3;\n            while (s[i]=='g'&&s[i+1]=='o')\n            {\n                i+=2;\n            }\n        }\n        else putchar(s[i]);\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e7fe60438af5d048959b6900c77022c2", "src_uid": "619665bed79ecf77b083251fe6fe7eb3", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    char a[n+1];\n    scanf(\"%s\",&a);\n    int i=0 ;\n    while(a[i]!='\\0')\n        {if(a[i]=='o')\n             {if(a[i+1]=='g')\n                if(a[i+2]=='o')\n                     {printf(\"***\");i+=3;}\n                 while(a[i]!='\\0' && a[i]=='g' && a[i+1]=='o')\n                         i+=2;}\n        else\n            {printf(\"%c\",a[i]); i++ ;}}\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dc56da2ef8c0330f8674b710907ad2ab", "src_uid": "619665bed79ecf77b083251fe6fe7eb3", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a9c1d7f3762e0ae1959e91021a1e2a34", "src_uid": "619665bed79ecf77b083251fe6fe7eb3", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nstruct dxy\n{\n\tlong long d;\n\tlong long x;\n\tlong long y;\n};\n\nlong long gcd(long long a, long long b)\n{\n\t return (a*b == 0) ? (a + b) : gcd(b, a%b);\n}\n\nstruct dxy ext_euc(long long a, long long b)\n{\n\tlong long x, y;\n\tstruct dxy ans;\n\tif (b == 0)\n\t{\n\t\tans.d = a;\n\t\tans.x = 1;\n\t\tans.y = 0;\n\t\treturn ans;\n\t}\n\t\n\tans = ext_euc(b, a%b);\n\tx = ans.y;\n\ty = ans.x - (a/b)*ans.y;\n\t\n\tans.x = x;\n\tans.y = y;\n\treturn ans;\n}\n\nlong long box(long long numer, long long denom)\n{\n\tif (numer % denom == 0 || numer * denom >= 0)\n\t{\n\t\treturn numer / denom;\n\t}\n\t\n\treturn (numer / denom) - 1;\n}\n\nint main()\n{\n\tlong long a1, a2, b1, b2;\n\tlong long L, R;\n\tlong long alpha1, alpha2, r, start, end;\n\tlong long p, p1, q, i, j;\n\tlong long hcf;\n\tstruct dxy temp;\n\t\n\tscanf(\"%lld %lld %lld %lld %lld %lld\", &a1, &b1, &a2, &b2, &L, &R);\n\t\n\thcf = gcd(a1, a2);\n\tif ((b2 - b1) % hcf != 0)\n\t{\n\t\tprintf(\"%d\\n\", 0);\n\t\treturn 0;\n\t}\n\t\n\tr = box((b2 - b1), hcf);\n\talpha1 = box(a1, hcf);\n\talpha2 = box(a2, hcf);\n\t\n\ttemp = ext_euc(alpha1, -alpha2);\n\tp = temp.x * r;\n\tp1 = temp.y * r;\n\t\n\tstart = box((L-b1), a1) + 1;\n\tstart -= ((L-b1) % a1) == 0 ? 1 : 0;\n\tend = box((R-b1), a1);\n\t\n\tq = box((start-p), alpha2) + 1;\n\tq -= ((start-p) % alpha2) == 0 ? 1 : 0;\n\t\n\tj = 0;\n\tfor (i = q; i <= box((end-p), alpha2); i++)\n\t{\n\t\tif (p + i*alpha2 >=0 && p1 + i*alpha1 >= 0)\n\t\t{\n\t\t\tj++;\n\t\t}\n\t}\n\t\n\t//printf(\"%lld %lld\\n\", start, end);\n\t//printf(\"%lld %lld %lld %lld\\n\", p, p1, q, r);\n\t//printf(\"%lld %lld\\n\", box((end-p), alpha2), box((start-p), alpha2));\n\t/*\n\tif (p + q*alpha2 < 0 || p1 + q*alpha1 < 0)\n\t{\n\t\tprintf(\"%d\\n\", 0);\n\t\treturn 0;\n\t}\n\t*/\n\tprintf(\"%lld\\n\", j);\n\treturn 0;\n}\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f16151df232333932d151b7bc3fdbcec", "src_uid": "b08ee0cd6f5cb574086fa02f07d457a4", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "/*\n * 710D\n */\n\n#include <stdio.h>\n\nvoid egcd(long long greater, long long lesser, \n\tlong long *d, long long *x, long long *y)\n{\n\tlong long tx, ty;\n\n\tif (lesser == 0) {\n\t\t*d = greater;\n\t\t*x = 1;\n\t\t*y = 0;\n\t\treturn;\n\t}\n\n\tegcd(lesser, greater % lesser, d, x, y);\n\n\ttx = *y;\n\tty = *x - (greater / lesser) * (*y);\n\t*x = tx;\n\t*y = ty;\n}\n\t\n\nlong long gcd(long greater, long lesser)\n{\n\tif (greater % lesser == 0)\n\t\treturn lesser;\n\treturn gcd(lesser, greater % lesser);\n}\n\nlong long left, right, a1, a2, b1, b2;\n\nint main(void)\n{\n\tlong long delta, lefti, righti;\n\tlong long d, c1, c2;\n\tdouble left0, right0, right1, right2, right3;\n\n\tscanf(\"%lld%lld%lld%lld%lld%lld\", &a1, &b1, &a2, &b2, &left, &right);\n\n\tif (a2 >= a1)\n\t\tegcd(a2, a1, &d, &c2, &c1);\t\n\telse\n\t\tegcd(a1, a2, &d, &c1, &c2);\n\n\tdelta = b2 - b1;\n\n\tif (delta % d) {\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\n\t/* x >= 0 */\n\tright1 = 1.0 * delta * c1 / a2;\n\n\t/* y >= 0 */\n\tright2 = -1.0 * delta * c2 / a1;\n\n\t/* left <= value <= right */\n\tleft0 = 1.0 * delta * c1 / a2 - 1.0 * d * (right - b1) / (1.0 * a1 * a2);\n\tright3 = 1.0 * delta * c1 / a2 - 1.0 * d * (left - b1) / (1.0 * a1 * a2);\n\n\tright0 = right1 < right2 ? right1 : right2;\n\tright0 = right0 < right3 ? right0 : right3;\n\n\tlefti = (long long)left0;\n\tif (left0 > 0 && lefti != left0)\n\t\tlefti += 1;\t\n\n\trighti = (long long)right0;\n\tif (right0 < 0 && righti != right0)\n\t\trighti -= 1;\n\n\n\tprintf(\"%lld\\n\", lefti > righti ? 0 : righti - lefti + 1);\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "31a29eda93ac6c3fb7f4a71c9d1c37cb", "src_uid": "b08ee0cd6f5cb574086fa02f07d457a4", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long xy[2];\n\nint gcdxy(int a, int b) {\n\tif (b == 0) {\n\t\txy[0] = 1, xy[1] = 0;\n\t\treturn a;\n\t} else {\n\t\tint g = gcdxy(b, a % b);\n\t\tint tmp;\n\n\t\ttmp = xy[0] - a / b * xy[1];\n\t\txy[0] = xy[1];\n\t\txy[1] = tmp;\n\t\treturn g;\n\t}\n}\n\nint main() {\n\tint a1, b1, a2, b2, l, r, g;\n\tlong long x, b, n, k_, l_, cnt, cnt1, cnt2;\n\n\tscanf(\"%d%d%d%d%d%d\", &a1, &b1, &a2, &b2, &l, &r);\n\t/* (a1k + b1 = a2l + b2) = (a1k - a2l = b2 - b1) */\n\tg = gcdxy(a1, -a2);\n\tb = (long long) b2 - b1;\n\tif (b % g != 0)\n\t\tprintf(\"0\\n\");\n\telse {\n\t\tk_ = xy[0] * b / g, l_ = xy[1] * b / g;\n\t\tif (g < 0)\n\t\t\tg = -g;\n\t\tcnt2 = a2 / g;\n\t\tcnt1 = a1 / g;\n\t\tcnt = (long long) a1 / g * a2;\n\t\tk_ = (k_ % cnt2 + cnt2) % cnt2;\n\t\tl_ = (l_ % cnt1 + cnt1) % cnt1;\n\t\tx = a1 * k_ + b1 > a2 * l_ + b2 ? a1 * k_ + b1 : a2 * l_ + b2;\n\t\tn = 0;\n\t\tif (x >= l && x <= r)\n\t\t\tn = (r - x + 1 + cnt - 1) / cnt;\n\t\telse if (x < l)\n\t\t\tn = (r - x + 1 + cnt - 1) / cnt - (l - 1 - x + 1 + cnt - 1) / cnt;\n\t\tprintf(\"%lld\\n\", n);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7f241ed15234e50baac7518a03ef5692", "src_uid": "b08ee0cd6f5cb574086fa02f07d457a4", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define max(a, b) (((a) > (b)) ? (a) : (b))\n\nstruct dxy\n{\n\tlong long d;\n\tlong long x;\n\tlong long y;\n};\n\nlong long gcd(long long a, long long b)\n{\n\t return (a*b == 0) ? (a + b) : gcd(b, a%b);\n}\n\nstruct dxy ext_euc(long long a, long long b)\n{\n\tlong long x, y;\n\tstruct dxy ans;\n\tif (b == 0)\n\t{\n\t\tans.d = a;\n\t\tans.x = 1;\n\t\tans.y = 0;\n\t\treturn ans;\n\t}\n\t\n\tans = ext_euc(b, a%b);\n\tx = ans.y;\n\ty = ans.x - (a/b)*ans.y;\n\t\n\tans.x = x;\n\tans.y = y;\n\treturn ans;\n}\n\nlong long box(long long numer, long long denom)\n{\n\tif (numer % denom == 0 || (numer >=0 && denom >= 0) || (numer < 0 && denom < 0))\n\t{\n\t\treturn numer / denom;\n\t}\n\t\n\treturn (numer / denom) - 1;\n}\n\nint main()\n{\n\tlong long a1, a2, b1, b2;\n\tlong long L, R;\n\tlong long alpha1, alpha2, r, start, end;\n\tlong long p, p1, q, q1, i, j, ans, base;\n\tlong long hcf;\n\tstruct dxy temp;\n\t\n\tscanf(\"%lld %lld %lld %lld %lld %lld\", &a1, &b1, &a2, &b2, &L, &R);\n\t\n\thcf = gcd(a1, a2);\n\tif ((b2 - b1) % hcf != 0)\n\t{\n\t\tprintf(\"%d\\n\", 0);\n\t\treturn 0;\n\t}\n\t\n\tr = box((b2 - b1), hcf);\n\talpha1 = box(a1, hcf);\n\talpha2 = box(a2, hcf);\n\t\n\ttemp = ext_euc(alpha1, -alpha2);\n\tp = temp.x * r;\n\tp1 = temp.y * r;\n\tif (temp.d < 0)\n\t{\n\t\tp = -p;\n\t\tp1 = -p1;\n\t}\n\t\n\tstart = box((L-b1), a1) + 1;\n\t//printf(\"start = %lld\\n\", start);\n\tstart -= ((L-b1) % a1) == 0 ? 1 : 0;\n\tend = box((R-b1), a1);\n\t\n\tq = box((start-p), alpha2) + 1;\n\tq -= ((start-p) % alpha2) == 0 ? 1 : 0;\n\tq1 = box((end-p), alpha2);\n\t//printf(\"q1 = %lld\\n\", q1);\n\t\n\tbase = box(-p, alpha2) + 1;\n\tbase -= (p % alpha2) == 0 ? 1 : 0;\n\tq = max(q, base);\n\t//printf(\"q = %lld\\n\", q);\n\t\n\tbase = box(-p1, alpha1) + 1;\n\tbase -= (p1 % alpha1) == 0 ? 1 : 0;\n\tq = max(q, base);\n\t//printf(\"q = %lld\\n\", q);\n\t\n\tans = q1 - (q - 1);\n\t//printf(\"ans = %lld\\n\", ans);\n\tif (ans < 0 )\n\t{\n\t\tans = 0;\n\t}\n\n\t/*\n\tj = 0;\n\tfor (i = q; i <= box((end-p), alpha2); i++)\n\t{\n\t\tif (p + i*alpha2 >=0 && p1 + i*alpha1 >= 0)\n\t\t{\n\t\t\tj++;\n\t\t}\n\t}\n\t*/\n\t//printf(\"start = %lld, end = %lld\\n\", start, end);\n\t//printf(\"p = %lld, p1 = %lld, q = %lld, r = %lld\\n\", p, p1, q, r);\n\t//printf(\"%lld %lld\\n\", box((end-p), alpha2), box((start-p), alpha2));\n\t/*\n\tif (p + q*alpha2 < 0 || p1 + q*alpha1 < 0)\n\t{\n\t\tprintf(\"%d\\n\", 0);\n\t\treturn 0;\n\t}\n\t*/\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f11ef1838a962ef0984f7f3372b9d70f", "src_uid": "b08ee0cd6f5cb574086fa02f07d457a4", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "/*\n * 710D\n */\n\n#include <stdio.h>\n\nlong long gcd(long greater, long lesser)\n{\n\tif (greater % lesser == 0)\n\t\treturn lesser;\n\treturn gcd(lesser, greater % lesser);\n}\n\nlong long left, right;\n\nvoid zero_case(long long a1, long long b1, long long b2)\n{\n\tif (a1 == 0) {\n\t\tif (b1 != b2)\n\t\t\tprintf(\"0\\n\");\n\t\telse if (left <= b1 && b1 <= right)\n\t\t\tprintf(\"1\\n\");\n\t\telse\n\t\t\tprintf(\"0\\n\");\n\t} else {\n\t\tif ((b2 - b1) % a1)\n\t\t\tprintf(\"0\\n\");\n\t\telse if (left <= b2 && b2 <= right)\n\t\t\tprintf(\"1\\n\");\n\t\telse\n\t\t\tprintf(\"0\\n\");\n\t}\n}\n\nint main(void)\n{\n\tlong long a1, b1, a2, b2;\n\tlong long y, k, left2, right2, p1, delta, gcdv;\n\tdouble tmp;\n\n\tscanf(\"%lld%lld%lld%lld%lld%lld\", &a1, &b1, &a2, &b2, &left, &right);\n\t\n\tif (a2 == 0) {\n\t\tzero_case(a1, b1, b2);\n\t\treturn 0;\n\t} else if (a1 == 0) {\n\t\tzero_case(a2, b2, b1);\n\t\treturn 0;\n\t}\n\n\tgcdv = gcd(a1 > a2 ? a1 : a2, a1 < a2 ? a1 : a2);\n\n\tp1 = a1 / gcdv;\n\n\t/* here is a lesson */\n\ttmp = 1.0 * (left - b2) / a2;\n\tleft2 = (long long)tmp;\n\tif (tmp > 0 && (left - b2) % a2)\n\t\tleft2 += 1;\n\n\ttmp = 1.0 * (right - b2) / a2;\n\tright2 = (long long)tmp;\n\tif (tmp < 0 && (right - b2) % a2)\n\t\tright2 -= 1;\n\n\n\tdelta = b2 - b1;\n\n\tfor (y = left2; y <= right2; ++y)\n\t\tif ((a2 * y + delta) % a1 == 0)\n\t\t\tbreak;\n\tif (y < 0) {\n\t\ttmp = -1 * y / p1;\n\t\tk = (long long)tmp;\n\t\tif (y % p1)\n\t\t\t++k;\n\t\ty += k * p1;\n\t}\n\n\tif (a2 * y + delta < 0) {\n\t\ttmp = -1.0 * (a2 * y + delta) / (a2 * p1);\n\t\tk = (long long)tmp;\n\t\tif ((a2 * y + delta) % (a2 * p1))\n\t\t\tk += 1;\n\t\ty += k * p1;\n\t}\n\n\n\tprintf(\"%lld\\n\", y > right2 ? 0 : (right2 - y) / p1 + 1);\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8828a4a78bfc6e88fdd331f8bfef8d4e", "src_uid": "b08ee0cd6f5cb574086fa02f07d457a4", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\nusing namespace std;\nint main()\n{\n\tint n,i;\n\tchar c[]=\"ROYGBIV\";\n\tcin >> n;\n\tcout <<c;\n\tfor(i=0;i<n-7;i++) cout<<c[i%4+3];\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "97ec803ad72080b3753e6155c2dc858c", "src_uid": "dc3817c71b1fa5606f316e5e94732296", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    r=n%7;\n    n=n/7;\n    for(i=0;i<n;i++){\n        printf(\"ROYGBIV\");\n    }\n    for(i=0;i<r;i++){\n        if(i==0)printf(\"R\");\n        else if(i==1)printf(\"O\");\n        else if(i==2)printf(\"Y\");\n        else if(i==3)printf(\"G\");\n        else if(i==4)printf(\"B\");\n        else if(i==5)printf(\"I\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "17ea4c2609646a6a8696677ed0ab31a5", "src_uid": "dc3817c71b1fa5606f316e5e94732296", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint num;\nint n;\nchar eggs_colour[n] = \"ROYGBIV\";\nint main()\n{\n    scanf(\"%d\",&n);\n    for(num=n;7<=num<=100;num++)\n        printf(\"%c\",eggs_colour);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "82cceec08ee20e4cb1110a28d22295a7", "src_uid": "dc3817c71b1fa5606f316e5e94732296", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nvoid main(){\n\tint n,i=1,z,j,f,o;\n\tscanf(\"%d\",&n);\n\tz=n/7;\n\tf=n-(z*7);\n\tfor(j=1;j<=z;j++){\n\tfor(i=1;i<=7;i++){\n\tif(i==1)\n\tprintf(\"R\");\n\telse if(i==2)\n\tprintf(\"Y\");\n\telse if(i==3)\n\tprintf(\"G\");\n\telse if(i==4)\n\tprintf(\"B\");\n\telse if(i==5)\n\tprintf(\"I\");\n\telse if(i==6)\n\tprintf(\"V\");\n\telse if(i==7)\n\tprintf(\"O\");\n}}\nfor(o=1;o<=f;o++){\nif(o==1)\n\tprintf(\"R\");\n\telse if(o==2)\n\tprintf(\"Y\");\n\telse if(o==3)\n\tprintf(\"G\");\n\telse if(o==4)\n\tprintf(\"B\");\n\telse if(o==5)\n\tprintf(\"I\");\n\telse if(o==6)\n\tprintf(\"V\");\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e602f935aecd9064e7ea9c1b5a7c4e31", "src_uid": "dc3817c71b1fa5606f316e5e94732296", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nvoid main(){\n\tint n,i=1,z,j,f,o;\n\tscanf(\"%d\",&n);\n\tz=n/7;\n\tf=n-(z*7);\n\tfor(j=1;j<=z;j++){\n\tfor(i=1;i<=7;i++){\n\tif(i==1)\n\tprintf(\"R\");\n\telse if(i==2)\n\tprintf(\"Y\");\n\telse if(i==3)\n\tprintf(\"G\");\n\telse if(i==4)\n\tprintf(\"B\");\n\telse if(i==5)\n\tprintf(\"I\");\n\telse if(i==6)\n\tprintf(\"V\");\n\telse if(i==7)\n\tprintf(\"O\");\n}}\nfor(o=2;o<=f+1;o++){\n    if(o==7)\n\tprintf(\"Y\");\n\telse if(o==2)\n\tprintf(\"G\");\n\telse if(o==3)\n\tprintf(\"B\");\n\telse if(o==4)\n\tprintf(\"I\");\n\telse if(o==5)\n\tprintf(\"V\");\n\telse if(i==6)\n\tprintf(\"O\");\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "eaea37629997ac96b0b0742907d8a4e9", "src_uid": "dc3817c71b1fa5606f316e5e94732296", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<stdint.h>\n#include<inttypes.h>\n\ntypedef int64_t i64;\ntypedef int32_t i32;\n\nstatic void print_int(i64 n){if(n<0){putchar('-');n=-n;}if(n==0){putchar('0');return;}int s[20],len=0;while(n>0){s[len++]=n%10+'0';n/=10;}while(len>0){putchar(s[--len]);}}\nstatic i64 read_int(void){int prev='\\0';int c=getchar();while(!('0'<=c && c<='9')){prev=c;c=getchar();}i64 res=0;while('0'<=c && c<='9'){res=10*res+c-'0';c=getchar();}return prev=='-'?-res:res;}\n\nconst i32 mod = 1000000007;\n\n#define ADD(x, a) do{(x) += (a); if ((x) >= mod) (x) -= mod;} while (0)\n#define SUB(x, a) do{(x) += mod - (a); if ((x) >= mod) (x) -= mod;} while (0)\n\ni32 inv (i32 a) {\n  i32 t = 1;\n  while (a > 1) {\n    t = (i64) t * (mod - mod / a) % mod;\n    a = mod % a;\n  }\n  return t;\n}\n\ni32 calc (i64 p, const i32 c, const i32 k) {\n  i32 *dp = (i32 *) calloc (c + 1, sizeof (i32));\n  dp[c] = 1;\n  i32 *prob = (i32 *) calloc (c + 1, sizeof (i32));\n  for (i32 i = 0; i <= c; ++i) {\n    prob[i] = inv (i + 1);\n  }\n  for (i32 i = 0; i < k; ++i) {\n    i32 sum = 0;\n    for (i32 j = 0; j <= c; ++j) {\n      i32 v = (i64) prob[j] * dp[j] % mod;\n      ADD(sum, v);\n    }\n    for (i32 j = 0; j <= c; ++j) {\n      i32 assign = sum;\n      i32 v = (i64) prob[j] * dp[j] % mod;\n      SUB(sum, v);\n      dp[j] = assign;\n    }\n  }\n  p %= mod;\n  i32 ans = 0;\n  for (i32 i = c; i >= 0; --i) {\n    ans = ((i64) p * ans + dp[i]) % mod;\n  }\n  free (dp);\n  free (prob);\n  return ans;\n}\n\nvoid run (void) {\n  i64 n = read_int();\n  i32 k = read_int();\n  i64 ans = 1;\n  for (i64 p = 2; p * p <= n; ++p) {\n    if (n % p != 0) continue;\n    i32 c = 0;\n    while (n % p == 0) {\n      n /= p;\n      ++c;\n    }\n    ans = ans * calc (p, c, k) % mod;\n  }\n  if (n > 1) ans = ans * calc (n, 1, k) % mod;\n  print_int (ans);\n  puts (\"\");\n}\n\nint main (void) {\n  run ();\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8ee2815aee21474794608b92fd83a6ea", "src_uid": "dc466d9c24b7dcb37c0e99337b4124d2", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n\ntypedef long long int int64;\n\nstatic void printInt(int64 n){\n  if(n<0){putchar('-');n=-n;}\n  if(n==0){putchar('0');return;}\n  int s[20];int len=0;\n  while(n>0){s[len++]=n%10+'0';n/=10;}\n  while(len>0){putchar(s[--len]);}\n}\nstatic int64 readInt(void){\n  int prev='\\0';int c=getchar();\n  while(!('0'<=c && c<='9')){prev=c;c=getchar();}\n  int64 res=0;\n  while('0'<=c && c<='9'){res=10*res+c-'0';c=getchar();}\n  return prev=='-'?-res:res;\n}\n\n#define POS(i,j) ((i)*(c+1)+(j))\n\nconst int mod=1000000007;\n\nint inv(int a){\n  int t=1;\n  while(a>1){\n    t=(int64)t*(mod-mod/a)%mod;\n    a=mod%a;\n  }\n  return t;\n}\n\nvoid run(void){\n  int64 n=readInt();\n  int k=readInt();\n  int ans=1;\n  int64 p;\n  for(p=2;p*p<=n;p++){\n    if(n%p!=0) continue;\n    int c=0;\n    while(n%p==0){\n      n/=p;\n      c++;\n    }\n    int *dp=(int *)calloc((k+1)*(c+1),sizeof(int));\n    dp[POS(0,c)]=1;\n    int i,j,l;\n    for(i=0;i<k;i++){\n      for(j=0;j<=c;j++){\n\tfor(l=0;l<=j;l++){\n\t  dp[POS(i+1,l)]+=(int64)dp[POS(i,j)]*inv(j+1)%mod;\n\t  dp[POS(i+1,l)]%=mod;\n\t}\n      }\n    }\n    int local=0;\n    for(i=0,j=1;i<=c;i++,j=(int64)j*p%mod) local=(local+(int64)j*dp[POS(k,i)])%mod;\n    ans=(int64)ans*local%mod;\n    free(dp);\n  }\n  if(n>1){\n    int dp[2]={0,1};\n    for(int i=0;i<k;i++){\n      dp[0]=(dp[0]+(int64)dp[1]*inv(2))%mod;\n      dp[1]=(int64)dp[1]*inv(2)%mod;\n    }\n    ans=ans*(dp[0]+(int64)n%mod*dp[1]%mod)%mod;\n  }\n  printInt(ans);\n  putchar('\\n');\n}\n\nint main(void){\n  run();\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "57d0c0b9fab1777295ccd19331ac3413", "src_uid": "dc466d9c24b7dcb37c0e99337b4124d2", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define MD\t1000000007\n#define L\t50\n#define K\t10000\n\nlong long dp[L + 1][L + 1][K + 1];\n\nvoid init() {\n\tstatic long long dq[L + 1][L + 1][K + 1];\n\tstatic int inv[L + 2];\n\tint i1, i2, i, j;\n\n\tfor (i = 1; i <= L + 1; i++) {\n\t\tlong long x = 1;\n\n\t\twhile (x % i != 0)\n\t\t\tx += MD;\n\t\tinv[i] = x / i % MD;\n\t}\n\tfor (i1 = 0; i1 <= L; i1++) {\n\t\tdp[i1][i1][0] = dq[i1][i1][0] = 1;\n\t\tfor (i2 = i1 + 1; i2 <= L; i2++)\n\t\t\tdq[i1][i2][0] = (dq[i1][i2][0] + dq[i1][i2 - 1][0]) % MD;\n\t\tfor (j = 1; j <= K; j++)\n\t\t\tfor (i2 = i1; i2 <= L; i2++) {\n\t\t\t\tdq[i1][i2][j] = dp[i1][i2][j] = dq[i1][i2][j - 1] * inv[i2 + 1] % MD;\n\t\t\t\tif (i2 > i1)\n\t\t\t\t\tdq[i1][i2][j] = (dq[i1][i2][j] + dq[i1][i2 - 1][j]) % MD;\n\t\t\t}\n\t}\n}\n\nint solve(long long a, int cnt, int k) {\n\tint i, sum;\n\tlong long p;\n\n\ta %= MD;\n\tp = 1;\n\tsum = 0;\n\tfor (i = 0; i <= cnt; i++) {\n\t\tsum = (sum + p * dp[i][cnt][k]) % MD;\n\t\tp = p * a % MD;\n\t}\n\treturn sum;\n}\n\nint main() {\n\tlong long n, ans;\n\tint k, a;\n\n\tscanf(\"%lld%d\", &n, &k);\n\tinit();\n\tans = 1;\n\tfor (a = 2; a <= n / a; a++)\n\t\tif (n % a == 0) {\n\t\t\tint cnt = 0;\n\n\t\t\twhile (n % a == 0) {\n\t\t\t\tn /= a;\n\t\t\t\tcnt++;\n\t\t\t}\n\t\t\tans = ans * solve(a, cnt, k) % MD;\n\t\t}\n\tif (n > 1)\n\t\tans = ans * solve(n, 1, k) % MD;\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2a7d39bb33e580bacb3e1dc9c0f19656", "src_uid": "dc466d9c24b7dcb37c0e99337b4124d2", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<stdint.h>\n#include<inttypes.h>\n\ntypedef int64_t i64;\ntypedef int32_t i32;\n\nstatic void print_int(i64 n){if(n<0){putchar('-');n=-n;}if(n==0){putchar('0');return;}int s[20],len=0;while(n>0){s[len++]=n%10+'0';n/=10;}while(len>0){putchar(s[--len]);}}\nstatic i64 read_int(void){int prev='\\0';int c=getchar();while(!('0'<=c && c<='9')){prev=c;c=getchar();}i64 res=0;while('0'<=c && c<='9'){res=10*res+c-'0';c=getchar();}return prev=='-'?-res:res;}\n\nconst i32 mod = 1000000007;\n\n#define ADD(x, a) do{(x) += (a); if ((x) >= mod) (x) -= mod;} while (0)\n#define SUB(x, a) do{(x) += mod - (a); if ((x) >= mod) (x) -= mod;} while (0)\n\ni32 inv (i32 a) {\n  i32 t = 1;\n  while (a > 1) {\n    t = (i64) t * (mod - mod / a) % mod;\n    a = mod % a;\n  }\n  return t;\n}\n\ni32 calc (const i64 p, const i32 c, const i32 k) {\n  i32 *dp = (i32 *) calloc (c + 1, sizeof (i32));\n  dp[c] = 1;\n  i32 *prob = (i32 *) calloc (c + 1, sizeof (i32));\n  for (i32 i = 0; i <= c; ++i) {\n    prob[i] = inv (i + 1);\n  }\n  for (i32 i = 0; i < k; ++i) {\n    i32 sum = 0;\n    for (i32 j = 0; j <= c; ++j) {\n      i32 v = (i64) prob[j] * dp[j] % mod;\n      ADD(sum, v);\n    }\n    for (i32 j = 0; j <= c; ++j) {\n      i32 assign = sum;\n      i32 v = (i64) prob[j] * dp[j] % mod;\n      SUB(sum, v);\n      dp[j] = assign;\n    }\n  }\n  i32 ans = 0;\n  for (i32 i = c; i >= 0; --i) {\n    ans = ((i64) p * ans + dp[i]) % mod;\n  }\n  free (dp);\n  free (prob);\n  return ans;\n}\n\nvoid run (void) {\n  i64 n = read_int();\n  i32 k = read_int();\n  i64 ans = 1;\n  for (i64 p = 2; p * p <= n; ++p) {\n    if (n % p != 0) continue;\n    i32 c = 0;\n    while (n % p == 0) {\n      n /= p;\n      ++c;\n    }\n    ans = ans * calc (p, c, k) % mod;\n  }\n  if (n > 1) ans = ans * calc (n, 1, k) % mod;\n  print_int (ans);\n  puts (\"\");\n}\n\nint main (void) {\n  run ();\n  return 0;\n}\n220x218x26x45:gori ymkw$ emacs 1.c\n220x218x26x45:gori ymkw$ gg 1.c\n220x218x26x45:gori ymkw$ cat 1.c\n#include<stdio.h>\n#include<stdlib.h>\n#include<stdint.h>\n#include<inttypes.h>\n\ntypedef int64_t i64;\ntypedef int32_t i32;\n\nstatic void print_int(i64 n){if(n<0){putchar('-');n=-n;}if(n==0){putchar('0');return;}int s[20],len=0;while(n>0){s[len++]=n%10+'0';n/=10;}while(len>0){putchar(s[--len]);}}\nstatic i64 read_int(void){int prev='\\0';int c=getchar();while(!('0'<=c && c<='9')){prev=c;c=getchar();}i64 res=0;while('0'<=c && c<='9'){res=10*res+c-'0';c=getchar();}return prev=='-'?-res:res;}\n\nconst i32 mod = 1000000007;\n\n#define ADD(x, a) do{(x) += (a); if ((x) >= mod) (x) -= mod;} while (0)\n#define SUB(x, a) do{(x) += mod - (a); if ((x) >= mod) (x) -= mod;} while (0)\n\ni32 inv (i32 a) {\n  i32 t = 1;\n  while (a > 1) {\n    t = (i64) t * (mod - mod / a) % mod;\n    a = mod % a;\n  }\n  return t;\n}\n\ni32 calc (i64 p, const i32 c, const i32 k) {\n  i32 *dp = (i32 *) calloc (c + 1, sizeof (i32));\n  dp[c] = 1;\n  i32 *prob = (i32 *) calloc (c + 1, sizeof (i32));\n  for (i32 i = 0; i <= c; ++i) {\n    prob[i] = inv (i + 1);\n  }\n  for (i32 i = 0; i < k; ++i) {\n    i32 sum = 0;\n    for (i32 j = 0; j <= c; ++j) {\n      i32 v = (i64) prob[j] * dp[j] % mod;\n      ADD(sum, v);\n    }\n    for (i32 j = 0; j <= c; ++j) {\n      i32 assign = sum;\n      i32 v = (i64) prob[j] * dp[j] % mod;\n      SUB(sum, v);\n      dp[j] = assign;\n    }\n  }\n  p %= mod;\n  i32 ans = 0;\n  for (i32 i = c; i >= 0; --i) {\n    ans = ((i64) p * ans + dp[i]) % mod;\n  }\n  free (dp);\n  free (prob);\n  return ans;\n}\n\nvoid run (void) {\n  i64 n = read_int();\n  i32 k = read_int();\n  i64 ans = 1;\n  for (i64 p = 2; p * p <= n; ++p) {\n    if (n % p != 0) continue;\n    i32 c = 0;\n    while (n % p == 0) {\n      n /= p;\n      ++c;\n    }\n    ans = ans * calc (p, c, k) % mod;\n  }\n  if (n > 1) ans = ans * calc (n, 1, k) % mod;\n  print_int (ans);\n  puts (\"\");\n}\n\nint main (void) {\n  run ();\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "deb7825559935178f39e2bfa4e19569b", "src_uid": "dc466d9c24b7dcb37c0e99337b4124d2", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <conio.h>\n\nint main()\n{\n    int a,ta;\n    int b,tb;\n    int hh,mm;\n    int i;\n    int dem=0;\n    scanf(\"%d%d%d%d%d:%d\",&a,&ta,&b,&tb,&hh,&mm);\n    int x = hh*60+mm+ta;\n    int y = hh*60+mm;\n    for(i=5*60; i<=23*60+59; i+=b)\n    {\n        if(i < x  &&  i+tb > y )\n            dem++;\n    }\n    printf(\"%d\",dem);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c043a6d9d505565b2c4dd00d2e26aec6", "src_uid": "1c4cf1c3cb464a483511a8a61f8685a7", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define INIT_DAY 300\n#define END_DAY 1440\n\nint main(int argc, char* argv[]) {\n\tint a, ta, b, tb;\n\tint hh, mm;\n\tint start, end;\n\tint init_run;\n    int acum = 0;\n    \n\tscanf(\"%i %i\", &a, &ta);\n\tscanf(\"%i %i\", &b, &tb);\n\tscanf(\"%d:%d\", &hh, &mm);\n\tstart = (hh * 60) + mm;\n\tend = start + ta;\n\t\n\tinit_run = INIT_DAY;\n\twhile (init_run < END_DAY) {\n\t\tif ( ((init_run + tb) > start) && \n   \t\t     ( end > init_run) ) {\n   \t\t\tacum++;\n   \t\t}\n    \tinit_run = init_run + b;\n    }\n    printf(\"%i\\n\", acum);\n   \treturn 0; \n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9704ffd90d53952b18b8cc3341d928d6", "src_uid": "1c4cf1c3cb464a483511a8a61f8685a7", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n\tint i,a,b,ta,tb,h,m,t,count=0;\n\tscanf(\"%d %d\",&a,&ta);\n\tscanf(\"%d %d\",&b,&tb);\n\tscanf(\"%d:%d\",&h,&m);\n\tt=h*60+m;\n\tfor(i=300;i<1440;i=i+b){\n\t\tif(i+tb>t && i<t+ta){\n\t\t\tcount++;\n\t\t}\n\t}\n\tprintf(\"%d\\n\",count);\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "563323d157109e6991de1051aa069d4b", "src_uid": "1c4cf1c3cb464a483511a8a61f8685a7", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nchar s[100];\nint main() {\n    int k = 0,true=1, n, pos = 1, neg = 0;\n    while (true) {\n        char c;\n        scanf(\" %c\", &c);\n        scanf(\" %c\", &c);\n\n        if (c == '=') break;\n        if (c == '+') pos++;\n        if (c == '-') neg++;\n\n        s[k++] = c;\n    }\n\n    scanf(\"%d\", &n);\n\n    if (pos - n * neg > n || n * pos - neg < n) {\n        printf(\"Impossible\\n\");\n\n        return 0;\n    }\n\n    printf(\"Possible\\n\");\n\n    int S = 0,i=0,x=1;\n    for (i = 0; i < k; i++) {\n        int sgn = 1;\n        if (i > 0 && s[i - 1] == '-') sgn = -1;\n\n        if (sgn == 1) pos--;\n        if (sgn == -1) neg--;\n        for (x = 1; x <= n; x++)\n        {\n            if (S + x * sgn + pos - n * neg <= n && S + x * sgn + n * pos - neg >= n) {\n                printf(\"%d %c \", x, s[i]);\n\n                S += x * sgn;\n\n                break;\n            }\n            }\n\t}\n\n    printf(\"%d = %d\\n\", abs(n), n);\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "0fc6d3a8bc5175d6cb67bef36bdae27a", "src_uid": "1c4cf1c3cb464a483511a8a61f8685a7", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\nint main() {\n\tint a, ta, b, tb;\n\tscanf(\"%d%d%d%d\", &a, &ta, &b, &tb);\n\tint h, min;\n\tscanf(\"%d%*c%d\", &h, &min);\n\tmin += h * 60 - 300;\n\t\n\tint bdepart = min - tb > 0 ? min - tb : 0;\n\n\tint ar = min + ta > 1139 ? 1139 : min + ta;\n\n\tprintf(\"%d\\n\", (ar - 1) / b - (bdepart + b - 1) / b + 1);\n\tsystem(\"pause\");\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "239db5f32cb87a2a43a9cff551b4b757", "src_uid": "1c4cf1c3cb464a483511a8a61f8685a7", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "\n\n \n|  In English  \u041f\u043e-\u0440\u0443\u0441\u0441\u043a\u0438\noe15 | Logout\n\n    \nHOMECONTESTSGYMPROBLEMSETGROUPSRATINGAPICALENDAR\n\n\n\nPROBLEMSSUBMIT CODEMY SUBMISSIONSSTATUSHACKSROOMSTANDINGSCUSTOM INVOCATION\n    \nGeneral \n  \n#\tAuthor\tProblem\tLang\tVerdict\tTime\tMemory\tSent\tJudged\t \t \n32033940\tContestant:\noe15\t887B - 25\tGNU C\tWrong answer on pretest 4\t15 ms\t0 KB\t2017-11-03 21:32:03\t2017-11-03 21:32:04\t Add to favourites\tCompare\n  \n\u2192 Source\n#include <stdio.h>\n#include <stdlib.h>\nint search(int *b,int n,int key)\n{\n\tint i,f=0;\n\tfor(i=0;i<n;i++)\n\t\tif(b[i]==key)\n\t\t\treturn 1;\n\n\treturn 0;\n}\nint main()\n{\n\tint a[3][6];\n\tint n,i,j,j2,f=0,k=0;\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++){\n\t\tfor(j=0;j<6;j++){\n\t\t\tscanf(\"%d\",&a[i][j]);\n\t\t\tif(a[i][j]==1)\n\t\t\t\tf=1;\n\t\t}\n\t}\n\tif(f==0){\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\tint *b=(int*)malloc(n*6*sizeof(int));\n\tfor(i=0;i<n;i++)\n\t\tfor(j=0;j<6;j++)\n\t\t\tb[k++]=a[i][j];\n\tf=0;\n\tfor(k=1;k<10;k++){\n\t\tif(!search(b,n*6,k)){\n\t\t\tprintf(\"%d\\n\",k-1);\n\t\t\treturn 0;\n\t    }\t\n\t}\n\tif(n==1){\n\t\tprintf(\"9\\n\");\n\t\treturn 0;\n\t}\n\tfor(k=10;k<100;k++){\n\t\tf=0;\n\t\tfor(i=0;i<6;i++){\n\t\t\tfor(j=0;j<6;j++){\n\t\t\t\tif(a[0][i]*10+a[1][j]==k||a[1][j]*10+a[0][i]==k){\n\t\t\t\t\tf=1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(f==1)\n\t\t\t  break;\t\n\t\t}\n\t\tif(f==1)\n\t\t\tcontinue;\n\t\tfor(i=0;i<6;i++){\n\t\t\tfor(j=0;j<6;j++){\n\t\t\t\tif(a[0][i]*10+a[2][j]==k||a[2][j]*10+a[0][i]==k){\n\t\t\t\t\tf=1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(f==1)\n\t\t\t  break;\t\n\t\t}\n\t\tif(f==1)\n\t\t\tcontinue;\n\t\tfor(i=0;i<6;i++){\n\t\t\tfor(j=0;j<6;j++){\n\t\t\t\tif(a[1][i]*10+a[2][j]==k||a[2][j]*10+a[1][i]==k){\n\t\t\t\t\tf=1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(f==1)\n\t\t\t  break;\t\n\t\t}\n\n\t\tif(f==0){\n\t\t\tprintf(\"%d\\n\",k-1);\n\t\t\treturn 0;\n\t\t}\n\t}\n\tif(n==2){\n\t\tprintf(\"99\\n\");\n\t\treturn 0;\n\t}\n\n\n\tfor(k=100;k<1000;k++){\n\t\tf=0;\n\t\tfor(i=0;i<6;i++){\n\t\t\tfor(j=0;j<6;j++){\n\t\t\t\tfor(j2=0;j2<6;j2++){\n\t\t\t\t\tif(a[0][i]*100+a[1][j]*10+a[2][j2]==k||a[0][i]*100+a[2][j2]*10+a[1][j]==k){\n\t\t\t\t\t\tf=1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\telse if(a[1][j]*100+a[0][i]*10+a[2][j2]==k||a[1][j]*100+a[2][j2]*10+a[0][i]==k){\n\t\t\t\t\t\tf=1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\telse if(a[2][j2]*100+a[0][i]*10+a[1][j]==k||a[2][j2]*100+a[1][j]*10+a[0][i]==k){\n\t\t\t\t\t\tf=1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(f==1)\n\t\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif(f==1)\n\t\t\t\tbreak;\n\t\t}\n\t\tif(f==0){\n\t\t\tprintf(\"%d\\n\",k-1);\n\t\t\treturn 0;\n\t\t}\n\t}\n\t\n\t\tprintf(\"999\\n\");\n\t\treturn 0;\n\t\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8b9337bdf35fe31ace770ef2aeadf0d8", "src_uid": "20aa53bffdfd47b4e853091ee6b11a4b", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint length(int n) {\n\treturn n == 0 ? 0 : length(n / 10) + 1;\n}\n\nint main() {\n\tstatic int aa[3][6];\n\tint n, i, j, x;\n\n\tscanf(\"%d\", &n);\n\tfor (i = 0; i < n; i++)\n\t\tfor (j = 0; j < 6; j++)\n\t\t\tscanf(\"%d\", &aa[i][j]);\n\tfor (x = 1; ; x++) {\n\t\tint good;\n\n\t\tgood = 0;\n\t\tif (length(x) == 1) {\n\t\t\tint i, j;\n\n\t\t\tfor (i1 = 0; i1 < n; i1++)\n\t\t\t\tfor (j1 = 0; j1 < 6; j1++) {\n\t\t\t\t\tint a;\n\n\t\t\t\t\ta = aa[i1][j1];\n\t\t\t\t\tif (a == x) {\n\t\t\t\t\t\tgood = 1;\n\t\t\t\t\t\tgoto done;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t} else if (length(x) == 2) {\n\t\t\tint i1, i2, j1, j2;\n\n\t\t\tfor (i1 = 0; i1 < n; i1++)\n\t\t\t\tfor (j1 = 0; j1 < 6; j1++)\n\t\t\t\t\tfor (i2 = 0; i2 < n; i2++)\n\t\t\t\t\t\tfor (j2 = 0; j2 < 6; j2++)\n\t\t\t\t\t\t\tif (i1 != i2) {\n\t\t\t\t\t\t\t\tint a, b;\n\n\t\t\t\t\t\t\t\ta = aa[i1][j1];\n\t\t\t\t\t\t\t\tb = aa[i2][j2];\n\t\t\t\t\t\t\t\tif (a == x / 10 && b == x % 10) {\n\t\t\t\t\t\t\t\t\tgood = 1;\n\t\t\t\t\t\t\t\t\tgoto done;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t} else {\n\t\t\tint i1, i2, i3, j1, j2, j3;\n\n\t\t\tfor (i1 = 0; i1 < n; i1++)\n\t\t\t\tfor (j1 = 0; j1 < 6; j1++)\n\t\t\t\t\tfor (i2 = 0; i2 < n; i2++)\n\t\t\t\t\t\tfor (j2 = 0; j2 < 6; j2++)\n\t\t\t\t\t\t\tfor (i3 = 0; i3 < n; i3++)\n\t\t\t\t\t\t\t\tfor (j3 = 0; j3 < 6; j3++)\n\t\t\t\t\t\t\t\t\tif (i1 != i2 && i2 != i3) {\n\t\t\t\t\t\t\t\t\t\tint a, b, c;\n\n\t\t\t\t\t\t\t\t\t\ta = aa[i1][j1];\n\t\t\t\t\t\t\t\t\t\tb = aa[i2][j2];\n\t\t\t\t\t\t\t\t\t\tc = aa[i3][j3];\n\t\t\t\t\t\t\t\t\t\tif (a == x / 100 && b == x / 10 && c == x % 10) {\n\t\t\t\t\t\t\t\t\t\t\tgood = 1;\n\t\t\t\t\t\t\t\t\t\t\tgoto done;\n\t\t\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\t\t}\n\t\t}\ndone:\n\t\tif (!good)\n\t\t\tbreak;\n\t}\n\tprintf(\"%d\\n\", x - 1);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b558579ef78ce68dfa647bf69c22b834", "src_uid": "20aa53bffdfd47b4e853091ee6b11a4b", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint n, cube[3][6],v[3];\n\nint dfs(int num){\n\tif (num == 0)return 1;\n\tfor (int i = 0; i < n; i++){\n\t\tif (v[i])continue;\n\t\tint f = 0;\n\t\tfor (int j = 0; j < 6; j++)\n\t\t\tif (num % 10 == cube[i][j])f = 1;\n\t\tif (!f)continue;\n\t\tv[i] = 1;\n\t\tif (dfs(num / 10))return 1;\n\t\tv[i] = 0;\n\t}\n\treturn 0;\n}\nvoid main(){\n\tscanf(\"%d\", &n);\n\tfor (int i = 0; i < n; i++)\n\t\tfor (int j = 0; j < 6; j++)scanf(\"%d\", &cube[i][j]);\n\n\tfor (int i = 0; i < 1000; i++){\n\t\tfor (int j = 0; j < n; j++)v[j] = 0;\n\t\tif (!dfs(i)){\n\t\t    printf(\"%d\\n\", i - 1);\n\t\t    return;   \n\t\t}\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "49c77a7567976a664736e9db6dc04e6e", "src_uid": "20aa53bffdfd47b4e853091ee6b11a4b", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\nvoid *my_malloc(int size)\n{\n    void *ans = malloc(size);\n    if(ans == NULL)\n    {\n        exit(EXIT_FAILURE);\n    }\n    return ans;\n}\n\nvoid clear(int *v, int l)\n{\n    int i;\n    for(i = 0; i < l; i ++)\n    {\n        v[i] = 0;\n    }\n}\n\nvoid fun(int *v, int **m, int *order, int i, int k)\n{\n    if(i == -1)\n    {\n        v[k] = 1;\n        return;\n    }\n    int j;\n    for(j = 0; j < 6; j ++)\n    {\n        fun(v, m, order, i - 1, k * 10 + m[order[i]][j]);\n    }\n}\n\nint main(void)\n{\n\tint n;\n\tscanf(\"%d\", &n);\n\t\n\tint *v = my_malloc((int)pow(10, n) * sizeof(int));\n\tint **m = my_malloc(n * sizeof(int*));\n\t\n\tclear(v, (int)pow(10, n));\n\t\n\tint i, j;\n\tfor(i = 0; i < n; i ++)\n\t{\n\t    m[i] = my_malloc(6 * sizeof(int));\n\t    for(j = 0; j < 6; j ++)\n\t    {\n\t        scanf(\"%d\", m + i + j);\n\t    }\n\t}\n\t\n\tif(n == 3)\n\t{\n\t    int *order = my_malloc(3 * sizeof(int));\n\t    for(i = 0; i < n; i ++)\n    \t{\n    \t    int x, y, z;\n    \t    for(x = 0; x < n; x ++)\n    \t    {\n    \t        for(y = 0; y < n; y ++)\n    \t        {\n    \t            if(y == x)\n    \t            {\n    \t                continue;\n    \t            }\n    \t            for(z = 0; z < n; z ++)\n    \t            {\n    \t                if(z == x || z == y)\n    \t                {\n    \t                    continue;\n    \t                }\n    \t                order[0] = x, order[1] = y, order[2] = z;\n    \t                fun(v, m, order, i, 0);\n    \t            }\n    \t        }\n    \t    }\n    \t}\n    \tfree(order);\n\t}else if(n == 2)\n\t{\n\t    int *order = my_malloc(2 * sizeof(int));\n\t    for(i = 0; i < n; i ++)\n    \t{\n    \t    int x, y;\n    \t    for(x = 0; x < n; x ++)\n    \t    {\n    \t        for(y = 0; y < n; y ++)\n    \t        {\n    \t            if(y == x)\n    \t            {\n    \t                continue;\n    \t            }\n    \t            order[0] = x, order[1] = y;\n    \t            fun(v, m, order, i, 0);\n    \t        }\n    \t    }\n    \t}\n    \tfree(order);\n\t}else\n\t{\n\t    int *order = my_malloc(sizeof(int));\n\t    for(i = 0; i < n; i ++)\n    \t{\n    \t    int x, y;\n    \t    for(x = 0; x < n; x ++)\n    \t    {\n    \t        order[0] = x;\n    \t        fun(v, m, order, i, 0);\n    \t    }\n    \t}\n    \tfree(order);\n\t}\n\t\n\tint ans = 1;\n\twhile(ans < (int)pow(10, n))\n\t{\n\t    if(!v[ans])\n\t    {\n\t        break;\n\t    }\n\t    ans ++;\n\t}\n\t\n\tprintf(\"%d\",ans - 1);\n\t\n\tfree(v);\n\tfree(m);\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1af8e4393a9f284113679f38be9056ef", "src_uid": "20aa53bffdfd47b4e853091ee6b11a4b", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint n, cube[3][6],v[3];\n\nint dfs(int num){\n\tif (num == 0)return 1;\n\tfor (int i = 0; i < n; i++){\n\t\tif (v[i])continue;\n\t\tint f = 0;\n\t\tfor (int j = 0; j < 6; j++)\n\t\t\tif (num % 10 == cube[i][j])f = 1;\n\t\tif (!f)continue;\n\t\tv[i] = 1;\n\t\tif (dfs(num / 10))return 1;\n\t\tv[i] = 0;\n\t}\n\treturn 0;\n}\nint main(){\n\tscanf(\"%d\", &n);\n\tfor (int i = 0; i < 3; i++)\n\t\tfor (int j = 0; j < 6; j++)scanf(\"%d\", &cube[i][j]);\n\n\tfor (int i = 0; i < 1000; i++){\n\t\tfor (int j = 0; j < n; j++)v[j] = 0;\n\t\tif (!dfs(i))return printf(\"%d\\n\", i - 1);\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9a9fcf38cf77c427caef3525a0f8d627", "src_uid": "20aa53bffdfd47b4e853091ee6b11a4b", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nfloat NAN = 0.0/0.0;\nfloat a1(float x,float y,float z)\n{\n\tif(x==1)\n\treturn 1;\n\telse if(x>1)\n\treturn z*log(y)+ log(log(x));\n\telse if(x<1 && y<1 && z<1)\n   return z*log(y)+ log(log(1/x));\n   else \n   return NAN;\n   }\n   \nfloat a2(float x,float y,float z)\n{\n\tif(x==1.0)\n\treturn 1.0;\n\telse if(x>1.0)\n\treturn log(z)+log(y)+ log(log(x));\n\telse if(x<1.0 && y<1.0 && z<1.0)\n   return log(z)+log(y)+ log(log(1/x));\n   else \n   return NAN;\n   }\n   \n   \n\t\n\t\nint main()\n{\n\tfloat x,y,z;\n\tscanf(\"%f %f %f\",&x,&y,&z);\n\tfloat a[12];\n\tchar pat[12][10]= {\"x^y^z\\0\",\n\t\t\t\t\t\t\t \"x^z^y\\0\",\n\t\t\t\t\t\t\t \"(x^y)^z\\0\",\n\t\t\t\t\t\t\t \"(x^z)^y\\0\",\n\t\t\t\t\t\t\t \"y^x^z\\0\",\n\t\t\t\t\t\t\t \"y^z^x\\0\",\n\t\t\t\t\t\t\t \"(y^x)^z\\0\",\n\t\t\t\t\t\t\t \"(y^z)^x\\0\",\n\t\t\t\t\t\t\t \"z^x^y\\0\",\n\t\t\t\t\t\t\t \"z^y^x\\0\",\n\t\t\t\t\t\t\t \"(z^x)^y\\0\",\n\t\t\t\t\t\t\t \"(z^y)^x\\0\"\n\t\t\t\t\t\t\t };\n\ta[0]=a1(x,y,z);\n\ta[1]=a1(x,z,y);\n\ta[2]=a2(x,y,z);\n   a[3]=a2(x,z,y);\n   a[4]=a1(y,x,z);\n\ta[5]=a1(y,z,x);\n\ta[6]=a2(y,x,z);\n   a[7]=a2(y,z,x);\n   a[8]=a1(z,x,y);\n\ta[9]=a1(z,y,x);\n\ta[10]=a2(z,x,y);\n   a[11]=a2(z,y,x);\n   \n   float ans;\n   int pos,i;\n   if(x>1)\n   {\n   ans = a[0];\n   pos =0;\n   }\n   else if(y>1)\n   {\n\t   ans = a[4];\n\t   pos=4;\n\t   }\n\t   else\n\t   {\n\t\t   ans = a[8];\n\t\t   pos =8;\n\t\t   }\n   \n   \n   if(x<1 && y<1 && z<1)\n   {\n   for(i=11;i>=0;--i)\n   {\n   if(a[i]<=ans)\n   {\n\t   ans = a[i];\n\t   pos = i;\n\t   }\n\t   }\n\t   }\n\t   \n\telse\n\t{\n   for(i=11;i>=0;--i)\n   {\n   if(a[i]>=ans)\n   {\n\t   ans = a[i];\n\t   pos = i;\n\t   }\n\t   }\n\t   }\n \n printf(\"%s\",pat[pos]);\n return 0;\n }\n\t\t   ", "lang_cluster": "C", "compilation_error": true, "code_uid": "5845c67fb147b17f66922ba5b09b4228", "src_uid": "a71cb5cda754ad2bf479bc3b0164fc4c", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<string.h>\nusing namespace std; \ndouble x,y,z;\ndouble a[9];\n\n\nint main()\n{\n\tchar count[9][10]={\"x^y^z\",\n                      \"x^z^y\",\n\t\t\t\t\t  \"(x^y)^z\",\n\t\t\t\t\t  \"y^x^z\",\n\t\t\t\t\t  \"y^x^z\",\n\t\t\t\t\t  \"(y^x)^z\", \n\t\t\t\t\t  \"z^x^y\",\n\t\t\t\t\t  \"z^y^x\",\n\t\t\t\t\t  \"(z^x)^y\"} ;\n\tint i,max;\n\tscanf(\"%lf%lf%lf\",&x,&y,&z);\n\ta[0]=pow(y,z)*log(x);\n\ta[1]=pow(z,y)*log(x);\n\ta[2]=y*z*log(x);\n\ta[3]=pow(x,z)*log(y);\n\ta[4]=pow(z,x)*log(y);\n\ta[5]=x*z*log(y);\n\ta[6]=pow(x,y)*log(z);\n\ta[7]=pow(y,x)*log(z);\n\ta[8]=x*y*log(z);\n\tfor(i=1,max=0;i<=8;i++)\n\t{\n\t\tif(a[i]>a[max])max=i;\n\t}\n\tprintf(\"%s\",count[max]);\n} \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "29ab168eb3774e47e40cd4db67643899", "src_uid": "a71cb5cda754ad2bf479bc3b0164fc4c", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<string.h>\n#include<bits/stdc++.h>\nusing namespace std; \ndouble x,y,z;\ndouble a[9];\n\n\nint main()\n{\n\tchar count[9][10]={\"x^y^z\",\n                      \"x^z^y\",\n\t\t\t\t\t  \"(x^y)^z\",\n\t\t\t\t\t  \"y^x^z\",\n\t\t\t\t\t  \"y^x^z\",\n\t\t\t\t\t  \"(y^x)^z\", \n\t\t\t\t\t  \"z^x^y\",\n\t\t\t\t\t  \"z^y^x\",\n\t\t\t\t\t  \"(z^x)^y\"} ;\n\tint i,max;\n\tscanf(\"%lf%lf%lf\",&x,&y,&z);\n\ta[0]=pow(y,z)*log(x);\n\ta[1]=pow(z,y)*log(x);\n\ta[2]=y*z*log(x);\n\ta[3]=pow(x,z)*log(y);\n\ta[4]=pow(z,x)*log(y);\n\ta[5]=x*z*log(y);\n\ta[6]=pow(x,y)*log(z);\n\ta[7]=pow(y,x)*log(z);\n\ta[8]=x*y*log(z);\n\tfor(i=1,max=0;i<=8;i++)\n\t{\n\t\tif(a[i]>a[max])max=i;\n\t}\n\tprintf(\"%s\",count[max]);\n} \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7b3088d28686d3451b05b6c630363945", "src_uid": "a71cb5cda754ad2bf479bc3b0164fc4c", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\nint main () {\n\t\n\tdouble x, y, z;\n\t\n\tdouble max;\n\tint ind = 0;\n\t\n\tscanf(\"%lf %lf %lf\", &x, &y, &z);\n\t\n\tif (x - 1.0 < 1e-6 && y - 1.0 < 1e-6 && z - 1.0 < 1e-6) {\n\t\t\n\t\tmax = 1000000;\n\t\t\n\t\tif (z * log(y) + log(log(1 / x)) - max < -1e-6) {\n\t\t\tmax = z * log(y) + log(log(1 / x));\n\t\t\tind = 1;\n\t\t}\n// printf(\"%.15lf\\n\", z * log(y) + log(log(1 / x)));\n\t\tif (y * log(z) + log(log(1 / x)) - max < -1e-6) {\n\t\t\tmax = y * log(z) + log(log(1 / x));\n\t\t\tind = 2;\n\t\t}\n// printf(\"%.15lf\\n\", y * log(z) + log(log(1 / x)));\n\t\tif (log(y) + log(z) + log(log(1 / x)) - max < -1e-6) {\n\t\t\tmax = log(y) + log(z) + log(log(1 / x));\n\t\t\tind = 3;\n\t\t}\n// printf(\"%.15lf\\n\", log(y) + log(z) + log(log(1 / x)));\n\t\t\n\t\t\n\tif (z * log(x) + log(log(1 / y)) - max < -1e-6) {\n\t\t\tmax = z * log(x) + log(log(1 / y));\n\t\t\tind = 5;\n\t\t}\n// printf(\"%.15lf\\n\", z * log(x) + log(log(1 / y)));\n\t\tif (x * log(z) + log(log(1 / y)) - max < -1e-6) {\n\t\t\tmax = x * log(z) + log(log(1 / y));\n\t\t\tind = 6;\n\t\t}\n// printf(\"%.15lf\\n\", x * log(z) + log(log(1 / y)));\n\t\tif (log(x) + log(z) + log(log(1 / y)) - max < -1e-6) {\n\t\t\tmax = log(x) + log(z) + log(log(1 / y));\n\t\t\tind = 7;\n\t\t}\n// printf(\"%.15lf\\n\", log(x) + log(z) + log(log(1 / y)));\n\t\t\n\t\t\n\tif (y * log(x) + log(log(1 / z)) - max < -1e-6) {\n\t\t\tmax = y * log(x) + log(log(1 / z));\n\t\t\tind = 9;\n\t\t}\n// printf(\"%.15lf\\n\", y * log(x) + log(log(1 / z)));\n\t\tif (x * log(y) + log(log(1 / z)) - max < -1e-6) {\n\t\t\tmax = x * log(y) + log(log(1 / z));\n\t\t\tind = 10;\n\t\t}\n// printf(\"%.15lf\\n\", x * log(y) + log(log(1 / z)));\n\t\tif (log(x) + log(y) + log(log(1 / z)) - max < -1e-6) {\n\t\t\tmax = log(x) + log(y) + log(log(1 / z));\n\t\t\tind = 11;\n\t\t}\n// printf(\"%.15lf\\n\", log(x) + log(y) + log(log(1 / z)));\n\t\t\n\t\t\n\t} else {\n\t\t\n\t\tmax = -1000;\n\t\t\n\t\tif (x - 1.0 > 0.01) {\n\t\t\tif (z * log(y) + log(log(x)) - max > 1e-6) {\n\t\t\t\tmax = z * log(y) + log(log(x));\n\t\t\t\tind = 1;\n\t\t\t}\n// printf(\"%.15lf\\n\", z * log(y) + log(log(x)));\n\t\t\tif (y * log(z) + log(log(x)) - max > 1e-6) {\n\t\t\t\tmax = y * log(z) + log(log(x));\n\t\t\t\tind = 2;\n\t\t\t}\n// printf(\"%.15lf\\n\", y * log(z) + log(log(x)));\n\t\t\tif (log(y) + log(z) + log(log(x)) - max > 1e-6) {\n\t\t\t\tmax = log(y) + log(z) + log(log(x));\n\t\t\t\tind = 3;\n\t\t\t}\n// printf(\"%.15lf\\n\", log(y) + log(z) + log(log(x)));\n\t\t}\n\t\t\n\t\tif (y - 1.0 > 0.01) {\n\t\t\tif (z * log(x) + log(log(y)) - max > 1e-6) {\n\t\t\t\tmax = z * log(x) + log(log(y));\n\t\t\t\tind = 5;\n\t\t\t}\n// printf(\"%.15lf\\n\", z * log(x) + log(log(y)));\n\t\t\tif (x * log(z) + log(log(y)) - max > 1e-6) {\n\t\t\t\tmax = x * log(z) + log(log(y));\n\t\t\t\tind = 6;\n\t\t\t}\n// printf(\"%.15lf\\n\", x * log(z) + log(log(y)));\n\t\t\tif (log(x) + log(z) + log(log(y)) - max > 1e-6) {\n\t\t\t\tmax = log(x) + log(z) + log(log(y));\n\t\t\t\tind = 7;\n\t\t\t}\n// printf(\"%.15lf\\n\", log(x) + log(z) + log(log(y)));\n\t\t}\n\t\t\n\t\tif (z - 1.0 > 0.01) {\n\t\t\tif (y * log(x) + log(log(z)) - max > 1e-6) {\n\t\t\t\tmax = y * log(x) + log(log(z));\n\t\t\t\tind = 9;\n\t\t\t}\n// printf(\"%.15lf\\n\", y * log(x) + log(log(z)));\n\t\t\tif (x * log(y) + log(log(z)) - max > 1e-6) {\n\t\t\t\tmax = x * log(y) + log(log(z));\n\t\t\t\tind = 10;\n\t\t\t}\n// printf(\"%.15lf\\n\", x * log(y) + log(log(z)));\n\t\t\tif (log(x) + log(y) + log(log(z)) - max > 1e-6) {\n\t\t\t\tmax = log(x) + log(y) + log(log(z));\n\t\t\t\tind = 11;\n\t\t\t}\n// printf(\"%.15lf\\n\", log(x) + log(y) + log(log(z)));\n\t\t}\n\t}\n\t\n\tswitch (ind) {\n\t\tcase 1:\n\t\t\tprintf(\"x^y^z\\n\");\n\t\t\tbreak;\n\t\tcase 2:\n\t\t\tprintf(\"x^z^y\\n\");\n\t\t\tbreak;\n\t\tcase 3:\n\t\t\tprintf(\"(x^y)^z\\n\");\n\t\t\tbreak;\n\t\tcase 4:\n\t\t\tprintf(\"(x^z)^y\\n\");\n\t\t\tbreak;\n\t\tcase 5:\n\t\t\tprintf(\"y^x^z\\n\");\n\t\t\tbreak;\n\t\tcase 6:\n\t\t\tprintf(\"y^z^x\\n\");\n\t\t\tbreak;\n\t\tcase 7:\n\t\t\tprintf(\"(y^x)^z\\n\");\n\t\t\tbreak;\n\t\tcase 8:\n\t\t\tprintf(\"(y^z)^x\\n\");\n\t\t\tbreak;\n\t\tcase 9:\n\t\t\tprintf(\"z^x^y\\n\");\n\t\t\tbreak;\n\t\tcase 10:\n\t\t\tprintf(\"z^y^x\\n\");\n\t\t\tbreak;\n\t\tcase 11:\n\t\t\tprintf(\"(z^x)^y\\n\");\n\t\t\tbreak;\n\t\tcase 12:\n\t\t\tprintf(\"(z^y)^x\\n\");\n\t\t\tbreak;\n\t\tdefault:\n\t\t\tprintf(\"ERROR\\n\");\n\t}\n\t\n\treturn 0;\n\t\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b1ef874525dffa37013346674f0ce0e0", "src_uid": "a71cb5cda754ad2bf479bc3b0164fc4c", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <math.h>\n#include <stdio.h>\n#include <stdlib.h>\n\ndouble aa[12];\nint sign[12];\n\nint compare(const void *a, const void *b) {\n\tint i = *(int *) a;\n\tint j = *(int *) b;\n\n\tif (sign[i] != sign[j])\n\t\treturn sign[j] - sign[i];\n\tif (sign[i] == 0)\n\t\treturn i - j;\n\treturn aa[i] == aa[j] ? i - j : aa[i] > aa[j] ? -sign[i] : sign[i];\n}\n\nvoid power(int i, double x, double y, double z) {\n\tif (x == 1)\n\t\tsign[i] = 0;\n\telse if (x > 1) {\n\t\tsign[i] = 1;\n\t\taa[i] = z * log(y) + log(log(x));\n\t} else {\n\t\tsign[i] = -1;\n\t\taa[i] = z * log(y) + log(-log(x));\n\t}\n}\n\nvoid power_(int i, double x, double yz) {\n\tif (x == 1)\n\t\tsign[i] = 0;\n\telse if (x > 1) {\n\t\tsign[i] = 1;\n\t\taa[i] = log(yz) + log(log(x));\n\t} else {\n\t\tsign[i] = -1;\n\t\taa[i] = log(yz) + log(-log(x));\n\t}\n}\n\nint main() {\n\tstatic char ss[12][16] = {\n\t\t\"x^y^z\", \"x^z^y\", \"(x^y)^z\", \"(x^z)^y\",\n\t\t\"y^x^z\", \"y^z^x\", \"(y^x)^z\", \"(y^z)^x\",\n\t\t\"z^x^y\", \"z^y^x\", \"(z^x)^y\", \"(z^y)^x\" };\n\tstatic int ii[12];\n\tdouble x, y, z;\n\tint i;\n\n\tscanf(\"%lf%lf%lf\", &x, &y, &z);\n\tpower(0, x, y, z);\n\tpower(1, x, z, y);\n\tpower_(2, x, y * z);\n\tpower_(3, x, y * z);\n\tpower(4, y, x, z);\n\tpower(5, y, z, x);\n\tpower_(6, y, x * z);\n\tpower_(7, y, x * z);\n\tpower(8, z, x, y);\n\tpower(9, z, y, x);\n\tpower_(10, z, x * y);\n\tpower_(11, z, x * y);\n\tfor (i = 0; i < 12; i++)\n\t\tii[i] = i;\n\tqsort(ii, 12, sizeof *ii, compare);\n\tprintf(\"%s\\n\", ss[ii[0]]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "18aa81e090872fc01c8ac3697e2fe0b5", "src_uid": "a71cb5cda754ad2bf479bc3b0164fc4c", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "/* https://csacademy.com/submission/2215090/ */\n#include <stdio.h>\n\n#define N\t50\n#define M\t(1 << 13) /* 2500 < M / 2 */\n#define LN\t13\n#define MD\t1000000007\n#define M0\t469762049\n#define M1\t595591169\n#define M2\t645922817\n\nint MM[] = { M0, M1, M2 };\n\nint V01, V02, V12;\n\nlong long power(int a, int b, int md) {\n\tlong long p;\n\n\tif (b == 0)\n\t\treturn 1;\n\tp = power(a, b / 2, md);\n\tp = p * p % md;\n\tif (b % 2)\n\t\tp = p * a % md;\n\treturn p;\n}\n\nlong long ww[3][LN + 1], ww_[3][LN + 1], vv[3];\nint kk[N + 1][N + 1][N + 1], ll[N + 1][N + 1][N + 1][3];\n\nvoid init() {\n\tint d, h, i, j, k;\n\n\tfor (d = 0; d < 3; d++) {\n\t\tint md = MM[d];\n\n\t\tfor (h = 0; h <= LN; h++) {\n\t\t\tww[d][h] = power(3, (md - 1) >> h, md);\n\t\t\tww_[d][h] = power(3, md - 1 - ((md - 1) >> h), md);\n\t\t}\n\t\tvv[d] = power(M, md - 2, md);\n\t}\n\tV01 = power(M0, M1 - 2, M1);\n\tV02 = power(M0, M2 - 2, M2);\n\tV12 = power(M1, M2 - 2, M2);\n\tfor (i = 0; i <= N; i++)\n\t\tfor (j = 0; j <= N; j++)\n\t\t\tfor (k = 0; k <= N; k++) {\n\t\t\t\tlong long k0, k1, k2;\n\n\t\t\t\tk0 = i > 0 ? (long long) ll[i - 1][j][k][0] * i % MD : 0;\n\t\t\t\tk1 = j > 0 ? (long long) ll[i][j - 1][k][1] * j % MD : 0;\n\t\t\t\tk2 = k > 0 ? (long long) ll[i][j][k - 1][2] * k % MD : 0;\n\t\t\t\tif (i == 0 && j == 0 && k == 0) {\n\t\t\t\t\tkk[i][j][k] = 1;\n\t\t\t\t\tll[i][j][k][0] = ll[i][j][k][1] = ll[i][j][k][2] = 1;\n\t\t\t\t} else {\n\t\t\t\t\tkk[i][j][k] = (k0 + k1 + k2) % MD;\n\t\t\t\t\tll[i][j][k][0] = (k1 + k2) % MD;\n\t\t\t\t\tll[i][j][k][1] = (k0 + k2) % MD;\n\t\t\t\t\tll[i][j][k][2] = (k0 + k1) % MD;\n\t\t\t\t}\n\t\t\t}\n}\n\nvoid ntt(int *aa, int d, int inverse) {\n\tint md = MM[d], h, i, j, b, l, r, u, v, tmp;\n\tlong long w, w_;\n\n\tfor (i = 1, j = 0; i < M; i++) {\n\t\tb = M;\n\t\tdo\n\t\t\tj ^= b >>= 1;\n\t\twhile ((j & b) == 0);\n\t\tif (i < j)\n\t\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\t}\n\tfor (h = 0; (b = 1 << h) < M; h++) {\n\t\tw_ = inverse ? ww_[d][h + 1] : ww[d][h + 1];\n\t\tfor (i = 0; i < M; i += b * 2) {\n\t\t\tw = 1;\n\t\t\tfor (j = 0; j < b; j++) {\n\t\t\t\tl = i + j, r = l + b;\n\t\t\t\tu = aa[l], v = aa[r] * w % md;\n\t\t\t\tif ((aa[l] = u + v) >= md)\n\t\t\t\t\taa[l] -= md;\n\t\t\t\tif ((aa[r] = u - v) < 0)\n\t\t\t\t\taa[r] += md;\n\t\t\t\tw = w * w_ % md;\n\t\t\t}\n\t\t}\n\t}\n}\n\nvoid fft(int *aa, int *bb, int d) {\n\tint md = MM[d], i;\n\tlong long v;\n\n\tntt(aa, d, 0), ntt(bb, d, 0);\n\tfor (i = 0; i < M; i++)\n\t\taa[i] = (long long) aa[i] * bb[i] % md;\n\tntt(aa, d, 1);\n\tv = vv[d];\n\tfor (i = 0; i < M; i++)\n\t\taa[i] = aa[i] * v % md;\n}\n\nint garner(int r0, int r1, int r2) {\n\tif (r0 < 0)\n\t\tr0 += M0;\n\tr1 = (long long) (r1 - r0) * V01 % M1;\n\tif (r1 < 0)\n\t\tr1 += M1;\n\tr2 = ((long long) (r2 - r0) * V02 - r1) % M2 * V12 % M2;\n\tif (r2 < 0)\n\t\tr2 += M2;\n\treturn (((long long) r2 * M1 + r1) % MD * M0 + r0) % MD;\n}\n\nvoid mult(int *aa, int *bb, int *cc) {\n\tstatic int cc_[3][M], bb_[M];\n\tint d, i;\n\n\tfor (d = 0; d < 3; d++) {\n\t\tfor (i = 0; i < M; i++) {\n\t\t\tcc_[d][i] = aa[i];\n\t\t\tbb_[i] = bb[i];\n\t\t}\n\t\tfft(cc_[d], bb_, d);\n\t}\n\tfor (i = 0; i < M; i++)\n\t\tcc[i] = garner(cc_[0][i], cc_[1][i], cc_[2][i]);\n}\n\nvoid knapsack(int *aa, int n, int m, int dp[][M]) {\n\tint h, i, j, a;\n\n\tdp[0][0] = 1;\n\tfor (h = 0; h < n; h++) {\n\t\ta = aa[h];\n\t\tfor (i = n; i >= 1; i--)\n\t\t\tfor (j = m; j >= a; j--)\n\t\t\t\tdp[i][j] = (dp[i][j] + dp[i - 1][j - a]) % MD;\n\t}\n}\n\nint main() {\n\tstatic int aa[3][N], cc[M], nn[3], dp[3][N + 1][M];\n\tint n, m, x, h, i0, i1, i2, j, ans;\n\n\tinit();\n\tscanf(\"%d%d\", &n, &m);\n\twhile (n--) {\n\t\tscanf(\"%d%d\", &x, &h), h--;\n\t\taa[h][nn[h]++] = x;\n\t}\n\tfor (h = 0; h < 3; h++)\n\t\tknapsack(aa[h], nn[h], m, dp[h]);\n\tans = 0;\n\tfor (i0 = 0; i0 <= nn[0]; i0++)\n\t\tfor (i1 = 0; i1 <= nn[1]; i1++) {\n\t\t\tmult(dp[0][i0], dp[1][i1], cc);\n\t\t\tfor (i2 = 0; i2 <= nn[2]; i2++)\n\t\t\t\tfor (j = 0; j <= m; j++)\n\t\t\t\t\tans = (ans + (long long) cc[j] * dp[2][i2][m - j] % MD * kk[i0][i1][i2]) % MD;\n\t\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "842ba8428b4b39f069f06e25f30d25c2", "src_uid": "ed5f913afe829c65792b54233a256757", "difficulty": 2600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define max2(a,b) (a<b?b:a)\n#define max3(a,b,c) max2(max2(a,b),c)\n\nint N, T;\nint L[50];\nint G[50];\n\n#define MOD 1000000007ULL\n#define add2(a,b) ((a+b)%MOD)\n#define add3(a,b,c) add2(add2(a,b),c)\n#define mul2(a,b) ((a*b)%MOD)\n#define mul3(a,b,c) mul2(mul2(a,b), c)\n#define mul4(a,b,c,d) mul2(mul2(a,b), mul2(c,d))\n#define fact3(a,b,c) mul3(fact(a),fact(b),fact(c))\n#define min(a,b) (a<b?a:b)\n\ntypedef unsigned long long u64;\n\nu64 F[51];\nu64 fact(u64 n) {\n  if (!F[n])\n    F[n] = n ? mul2(n, fact(n-1)) : 1;\n  return F[n];\n}\n\nu64 perm[27][27][27][3];\nint P[2501][27][27][27];\n\nint n[3];\nu64 walk(int t, int z)\n{\n  int n, i, j, a, b, c;\n  int count[3] = {0,0,0};\n  int max_d = 0;\n\n  P[0][0][0][0] = 1;\n  for (n = 0; n < N; n++) {\n    for (i = max_d + L[n]; i >= L[n]; i--)\n      for (a = 0; a <= count[0]; a++)\n        for (b = 0; b <= count[1]; b++)\n          for (c = 0; c <= count[2]; c++) {\n            char pos = 0;\n            if (G[n] == 0)\n              pos |= P[i][a+1][b][c] += P[i-L[n]][a][b][c];\n            if (G[n] == 1)\n              pos |= P[i][a][b+1][c] += P[i-L[n]][a][b][c];\n            if (G[n] == 2)\n              pos |= P[i][a][b][c+1] += P[i-L[n]][a][b][c];\n\n            if (pos && i > max_d)\n              max_d = i;\n          }\n    count[G[n]] = min(count[G[n]] + 1, N/2+1);\n  }\n\n  u64 r = 0;\n  for (a = 0; a <= count[0]; a++)\n    for (b = 0; b <= count[1]; b++)\n      for (c = 0; c <= count[2]; c++)\n        if (P[T][a][b][c]) {\n          for (int g = 0; g < 3; g++)\n            r = add2(r, mul3(fact3(a,b,c), perm[a][b][c][g], P[T][a][b][c]));\n        }\n  return r;\n}\n\nint main() {\n  int i, j, k, n;\n\n  scanf(\"%d %d\", &N, &T);\n  for (i = 0; i < N; i++) {\n    scanf(\"%d %d\", &L[i], &G[i]);\n    G[i]--;\n  }\n\n  perm[1][0][0][0] = perm[0][1][0][1] = perm[0][0][1][2] = 1;\n\n  for (n = 2; n <= N; n++)\n    for (i = 0; i <= n/2+1; i++)\n      for (j = 0; j <= n - i; j++) {\n        k = n - i - j;\n        if (k > n/2+1) continue;\n\n        if (i) perm[i][j][k][0] = add2(perm[i-1][j][k][1], perm[i-1][j][k][2]);\n        if (j) perm[i][j][k][1] = add2(perm[i][j-1][k][2], perm[i][j-1][k][0]);\n        if (k) perm[i][j][k][2] = add2(perm[i][j][k-1][0], perm[i][j][k-1][1]);\n      }\n\n  printf(\"%llu\\n\", walk(0, -1));\n\n  return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b712000db0dfb2972cd493528ca5043f", "src_uid": "ed5f913afe829c65792b54233a256757", "difficulty": 2600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define max2(a,b) (a<b?b:a)\n#define max3(a,b,c) max2(max2(a,b),c)\n\nint N, T;\nint L[50];\nint G[50];\n\n#define MOD 1000000007ULL\n#define add2i(a,b) (a = add2(a,b))\n#define add2(a,b) ((a+b)%MOD)\n#define add3(a,b,c) add2(add2(a,b),c)\n#define mul2(a,b) ((a*b)%MOD)\n#define mul3(a,b,c) mul2(mul2(a,b), c)\n#define mul4(a,b,c,d) mul2(mul2(a,b), mul2(c,d))\n#define fact3(a,b,c) mul3(fact(a),fact(b),fact(c))\n#define min2(a,b) (a<b?a:b)\n\ntypedef unsigned long long u64;\n\nu64 F[51];\nu64 fact(u64 n) {\n  if (!F[n])\n    F[n] = n ? mul2(n, fact(n-1)) : 1;\n  return F[n];\n}\n\nu64 perm[27][27][27][3];\nint P[2501][27][27][27];\n\nu64 walk()\n{\n  int n, i, j, a, b, c;\n  int count[3] = {0,0,0};\n  int max_d = 0;\n\n  P[0][0][0][0] = 1;\n  for (n = 0; n < N; n++) {\n    for (i = T; i >= L[n]; i--)\n      for (a = 0; a <= count[0]; a++)\n        for (b = 0; b <= count[1]; b++)\n          for (c = 0; c <= count[2]; c++) {\n            int pos = 0;\n            if (G[n] == 0)\n              pos |= !!add2i(P[i][a+1][b][c], P[i-L[n]][a][b][c]);\n            if (G[n] == 1)\n              pos |= !!add2i(P[i][a][b+1][c], P[i-L[n]][a][b][c]);\n            if (G[n] == 2)\n              pos |= !!add2i(P[i][a][b][c+1], P[i-L[n]][a][b][c]);\n\n            if (pos && i > max_d)\n              max_d = i;\n          }\n    count[G[n]] = min2(count[G[n]] + 1, N/2);\n  }\n\n  u64 r = 0;\n  for (a = 0; a <= count[0]; a++)\n    for (b = 0; b <= count[1]; b++)\n      for (c = 0; c <= count[2]; c++)\n        if (P[T][a][b][c])\n          for (int g = 0; g < 3; g++)\n            add2i(r, mul3(fact3(a,b,c), perm[a][b][c][g], P[T][a][b][c]));\n  return r;\n}\n\nint main() {\n  int i, j, k, n;\n\n  scanf(\"%d %d\", &N, &T);\n  for (i = 0; i < N; i++) {\n    scanf(\"%d %d\", &L[i], &G[i]);\n    G[i]--;\n  }\n\n  perm[1][0][0][0] = perm[0][1][0][1] = perm[0][0][1][2] = 1;\n  for (n = 2; n <= N; n++)\n    for (i = 0; i <= n/2+1; i++)\n      for (j = 0; j <= min2(n - i, n/2+1); j++) {\n        k = n - i - j;\n        if (k > n/2+1) continue;\n\n        if (i) perm[i][j][k][0] = add2(perm[i-1][j][k][1], perm[i-1][j][k][2]);\n        if (j) perm[i][j][k][1] = add2(perm[i][j-1][k][2], perm[i][j-1][k][0]);\n        if (k) perm[i][j][k][2] = add2(perm[i][j][k-1][0], perm[i][j][k-1][1]);\n      }\n\n  printf(\"%llu\\n\", walk());\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cbb911d71049ca0be19be23b36174f00", "src_uid": "ed5f913afe829c65792b54233a256757", "difficulty": 2600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define max2(a,b) (a<b?b:a)\n#define max3(a,b,c) max2(max2(a,b),c)\n\nint N, T;\nint L[50];\nint G[50];\n\n#define MOD 1000000007ULL\n#define add2(a,b) ((a+b)%MOD)\n#define add3(a,b,c) add2(add2(a,b),c)\n#define mul2(a,b) ((a*b)%MOD)\n#define mul3(a,b,c) mul2(mul2(a,b), c)\n#define mul4(a,b,c,d) mul2(mul2(a,b), mul2(c,d))\n#define fact3(a,b,c) mul3(fact(a),fact(b),fact(c))\n#define min(a,b) (a<b?a:b)\n\ntypedef unsigned long long u64;\n\nu64 F[51];\nu64 fact(u64 n) {\n  if (!F[n])\n    F[n] = n ? mul2(n, fact(n-1)) : 1;\n  return F[n];\n}\n\nu64 perm[27][27][27][3];\nchar P[2501][27][27][27];\n// bool P[2500][3];\n\nint n[3];\nu64 walk(int t, int z)\n{\n  int n, i, j, a, b, c;\n  int count[3] = {0,0,0};\n  int max_d = 0;\n\n  P[0][0][0][0] = 1;\n  for (n = 0; n < N; n++) {\n    for (i = max_d + L[n]; i >= L[n]; i--)\n      for (a = 0; a <= count[0]; a++)\n        for (b = 0; b <= count[1]; b++)\n          for (c = 0; c <= count[2]; c++) {\n            char pos = 0;\n            if (G[n] == 0)\n              pos |= P[i][a+1][b][c] |= P[i-L[n]][a][b][c];\n            if (G[n] == 1)\n              pos |= P[i][a][b+1][c] |= P[i-L[n]][a][b][c];\n            if (G[n] == 2)\n              pos |= P[i][a][b][c+1] |= P[i-L[n]][a][b][c];\n\n            if (pos && i > max_d)\n              max_d = i;\n          }\n    count[G[n]] = min(count[G[n]] + 1, N/2+1);\n  }\n\n  u64 r = 0;\n  for (a = 0; a <= count[0]; a++)\n    for (b = 0; b <= count[1]; b++)\n      for (c = 0; c <= count[2]; c++)\n        if (P[T][a][b][c]) {\n          for (int g = 0; g < 3; g++)\n            r = add2(r, mul2(fact3(a,b,c), perm[a][b][c][g]));\n        }\n  return r;\n}\n\nint main() {\n  int i, j, k, n;\n\n  scanf(\"%d %d\", &N, &T);\n  for (i = 0; i < N; i++) {\n    scanf(\"%d %d\", &L[i], &G[i]);\n    G[i]--;\n  }\n\n  perm[1][0][0][0] = perm[0][1][0][1] = perm[0][0][1][2] = 1;\n\n  for (n = 2; n <= N; n++)\n    for (i = 0; i <= n/2+1; i++)\n      for (j = 0; j <= n - i; j++) {\n        k = n - i - j;\n        if (k > n/2+1) continue;\n\n        if (i) perm[i][j][k][0] = add2(perm[i-1][j][k][1], perm[i-1][j][k][2]);\n        if (j) perm[i][j][k][1] = add2(perm[i][j-1][k][2], perm[i][j-1][k][0]);\n        if (k) perm[i][j][k][2] = add2(perm[i][j][k-1][0], perm[i][j][k-1][1]);\n      }\n\n  printf(\"%llu\\n\", walk(0, -1));\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b9d0654ec5f6e99285829cd856d234aa", "src_uid": "ed5f913afe829c65792b54233a256757", "difficulty": 2600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define max2(a,b) (a<b?b:a)\n#define max3(a,b,c) max2(max2(a,b),c)\n\nint N, T;\nint L[50];\nint G[50];\n\n#define MOD 1000000007ULL\n#define add2i(a,b) a = add2(a,b)\n#define add2(a,b) ((a+b)%MOD)\n#define add3(a,b,c) add2(add2(a,b),c)\n#define mul2(a,b) ((a*b)%MOD)\n#define mul3(a,b,c) mul2(mul2(a,b), c)\n#define mul4(a,b,c,d) mul2(mul2(a,b), mul2(c,d))\n#define fact3(a,b,c) mul3(fact(a),fact(b),fact(c))\n#define min(a,b) (a<b?a:b)\n\ntypedef unsigned long long u64;\n\nu64 F[51];\nu64 fact(u64 n) {\n  if (!F[n])\n    F[n] = n ? mul2(n, fact(n-1)) : 1;\n  return F[n];\n}\n\nu64 perm[27][27][27][3];\nint P[2501][27][27][27];\n\nint n[3];\nu64 walk(int t, int z)\n{\n  int n, i, j, a, b, c;\n  int count[3] = {0,0,0};\n  int max_d = 0;\n\n  P[0][0][0][0] = 1;\n  for (n = 0; n < N; n++) {\n    for (i = max_d + L[n]; i >= L[n]; i--)\n      for (a = 0; a <= count[0]; a++)\n        for (b = 0; b <= count[1]; b++)\n          for (c = 0; c <= count[2]; c++) {\n            int pos = 0;\n            if (G[n] == 0)\n              pos |= add2i(P[i][a+1][b][c], P[i-L[n]][a][b][c]);\n            if (G[n] == 1)\n              pos |= add2i(P[i][a][b+1][c], P[i-L[n]][a][b][c]);\n            if (G[n] == 2)\n              pos |= add2i(P[i][a][b][c+1], P[i-L[n]][a][b][c]);\n\n            if (pos && i > max_d)\n              max_d = i;\n          }\n    count[G[n]] = min(count[G[n]] + 1, N/2+1);\n  }\n\n  u64 r = 0;\n  for (a = 0; a <= count[0]; a++)\n    for (b = 0; b <= count[1]; b++)\n      for (c = 0; c <= count[2]; c++)\n        if (P[T][a][b][c]) {\n          for (int g = 0; g < 3; g++)\n            add2i(r, mul3(fact3(a,b,c), perm[a][b][c][g], P[T][a][b][c]));\n        }\n  return r;\n}\n\nint main() {\n  int i, j, k, n;\n\n  scanf(\"%d %d\", &N, &T);\n  for (i = 0; i < N; i++) {\n    scanf(\"%d %d\", &L[i], &G[i]);\n    G[i]--;\n  }\n\n  perm[1][0][0][0] = perm[0][1][0][1] = perm[0][0][1][2] = 1;\n  for (n = 2; n <= N; n++)\n    for (i = 0; i <= n/2+1; i++)\n      for (j = 0; j <= n - i; j++) {\n        k = n - i - j;\n        if (k > n/2+1) continue;\n\n        if (i) perm[i][j][k][0] = add2(perm[i-1][j][k][1], perm[i-1][j][k][2]);\n        if (j) perm[i][j][k][1] = add2(perm[i][j-1][k][2], perm[i][j-1][k][0]);\n        if (k) perm[i][j][k][2] = add2(perm[i][j][k-1][0], perm[i][j][k-1][1]);\n      }\n\n  printf(\"%llu\\n\", walk(0, -1));\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7d89132ca67132a92fb0b6ca0747d2c7", "src_uid": "ed5f913afe829c65792b54233a256757", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "##include<stdio.h>\nint main()\n{\n    int a,b,n,m,i,j=0,k=0;\n    scanf(\"%d %d\",&a,&b);\n    while(a>0||b>0)\n    {\n        n=a%3;\n        a/=3;\n        m=b%3;\n        b/=3;\n        if(m<n)\n        {\n            m+=3;\n        }\n        i=m-n;\n        j+=(i*pow(3,k));\n        k++;\n    }\n    printf(\"%d\",j);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "99e015ff9ff4c366fe5bf64e0120c7b8", "src_uid": "5fb635d52ddccf6a4d5103805da02a88", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long int dk(long long int m,long long int n[]);\nlong long int main()\n{\nlong long int a,b,c,d=0,i,e=0,k=0,g=0;\nlong long int p[10000]={0},q[10000],f[10000];\nscanf(\"%I64d%I64d\",&a,&c);\nd=dk(a,p);\ne=dk(c,q);\nif(d==e)\n{\nnext:\nfor(i=0;i<d;i++)\n{\nk=0;\nwhile(((p[i]+k)%3)!=q[i])\n{\nk++;\n}\nf[i]=k;\n}\n}\nelse\n{\nif(d>e)\n{\nwhile(d!=e)\n{\nq[e]=0;\ne++;\n}\ngoto next;}\nelse\n{\nwhile(d!=e)\n{\np[d]=0;\nd++;\n}\ngoto next;}\n}\nfor(i=0;i<d;i++)\n{\ng=g+f[i]*pow(3,i);\n}\nprintf(\"%I64d\",g);\nreturn(0);\n}\nlong long int dk(long long int m,long long int n[])\n{\n    int x=0;\nwhile(m>0)\n{\nn[x++]=m%3;l;;\nm=(m-(m%3))/3;\n}\nreturn(x);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "207f68f9f7bea1a073130ae93055c38d", "src_uid": "5fb635d52ddccf6a4d5103805da02a88", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "int a,b,c,t=1;\nint main()\n{\n    scanf(\"%d%d\",&a,&c);\n    for(;a|c;a/=3,c/=3,t*=3)\n        b+=(c%3-a%3+3)%3*t;\n    printf(\"%d\",b);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c04fbc04988f828d15ddf687b1befe22", "src_uid": "5fb635d52ddccf6a4d5103805da02a88", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "unsigned a,b,c,x=1;\nint main()\n{\n  for( scanf(\"%d%d\",&a,&c) ; a|c ; x*=3 , a/=3 , c/=3 )\n    b+=(3+c%3-a%3)%3*x;\n  printf(\"%d\",b);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "897bda5305799fe6faf766edbb3bd0e3", "src_uid": "5fb635d52ddccf6a4d5103805da02a88", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "unsigned a,b,c,x=1;\nint main(){\nfor(scanf(\"%d%d\",&a,&c);a|b;x*=3,a/=3,c/=3)b+=(3+c%3-a%3)%3*x;\nprintf(\"%d\",b);exit(0);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d813b793f3d3365174bae6857f200fb5", "src_uid": "5fb635d52ddccf6a4d5103805da02a88", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n#include <stdlib.h>\n#include <time.h>\n\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nint n, ar[100010];\n\nint main(){\n    int i, j, x, g, flag;\n\n    scanf(\"%d\", &n);\n    if (n == 3) puts(\"27\");\n    else if (n == 1) puts(\"4\");\n    else if (n == 2) puts(\"22\");\n    else if (n == 4) puts(\"58\");\n    else __builtin_trap();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f257f04d9b592d3dcc084a8b6d3d73c6", "src_uid": "bf65a25185e9ea5b71e853723b838b04", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n               int n;\n               scanf(\"%d\",&n);\n               if(n==1)\n                              printf(\"4\");\n               else if(n==2)\n                              printf(\"22\");\n               else if(n==3)\n                              printf(\"27\");\n               else if(n==4)\n                              printf(\"58\");\n                else if(n==5)\n                              printf(\"85\");\n                else if(n==6)\n                              printf(\"94\");\n                else if(n==7)\n                              printf(\"121\");\n                else if(n==8)\n                              printf(\"166\");\n               else if(n==9)\n                              printf(\"202\");\n                  else if(n==10)\n                              printf(\"265\");\n                else if(n==11)\n                              printf(\"274\");\n                 else if(n==12)\n                              printf(\"319\");\n                 else if(n==13)\n                              printf(\"346\");\n                 else if(n==14)\n                              printf(\"355\");\n                 else if(n==15)\n                              printf(\"378\");\n                  else if(n==16)\n                              printf(\"382\");\n                  else if(n==17)\n                              printf(\"391\");\n                  else if(n==18)\n                              printf(\"438\");\n                 else if(n==19)\n                              printf(\"454\");\n                  else if(n==20)\n                              printf(\"483\");\n                else if(n==21)\n                              printf(\"517\");\n                 else if(n==22)\n                              printf(\"526\");\n                  else if(n==23)\n                              printf(\"535\");\n                    else if(n==24)\n                              printf(\"562\");\n               else if(n==25)\n                              printf(\"576\");\n                  else if(n==26)\n                              printf(\"588\");\n                else if(n==27)\n                              printf(\"627\");\n                else if(n==28)\n                              printf(\"634\");\n             else if(n==29)\n                              printf(\"636\");\n              else(n==30)\n                           printf(\"645\");\n\n                              return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "57a7a165577849210070a87d81b0e41b", "src_uid": "bf65a25185e9ea5b71e853723b838b04", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint n;\n\n\tscanf(\"%d\", &n);\n\n\tprintf(\"%d\", 30 - a);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e97ead8bc9f6c2f9aa78a043e75032f1", "src_uid": "bf65a25185e9ea5b71e853723b838b04", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "\n/*  AUTHOR:AKASH JAIN\n*   USERNAME:akash19jain    \n*   DATE:31/03/2019 \n*/\n#include<stdio.h>\n#include<math.h>\n#include<string.h>\n#include<stdlib.h>\n#include<stdbool.h>\n\nint main()\n{\n    long long t=1;\n    //scanf(\"%lld\",&t);\n    while(t--)\n    {\n        long long n;\n        scanf(\"%lld\",&n);\n        long long a=n*n*n;\n        printf(\"%lld\\n\",ans);\n    }\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ccdd21b3e92a873ee5a8977ab6779b6a", "src_uid": "bf65a25185e9ea5b71e853723b838b04", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint man(void)\n{\n    int a=0;\n    scanf(\"%d\",&a);\n    printf(\"%d\\n\",3*a);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6752555f742fcb5c4eaea2a999c2935f", "src_uid": "bf65a25185e9ea5b71e853723b838b04", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<string.h>\n#include<stdlib.h>\n#define prime 1000000007\nint main()\n{\n\tlong long num,flag=0;\n\tscanf(\"%lli\",&num);\n\tif(num<0)\n\t{\n\t\tflag=1;\n\t\tnum=-1*num;\n\t}\n\tnum=num%360;\n\tif(flag==0)\n\t{\n\t\tif(num<=45)\n\t\t{\n\t\t\tprintf(\"0\\n\");\n\t\t}\n\t\telse if(num<=135)\n\t\t{\n\t\t\tprintf(\"1\\n\");\n\t\t}\n\t\telse if(num<=225)\n\t\t{\n\t\t\tprintf(\"2\\n\");\n\t\t}\n\t\telse if(num<315)\n\t\t{\n\t\t\tprintf(\"3\\n\");\n\t\t}\n\t\telse printf(\"0\\n\");\n\t}\n\telse if(flag==1)\n\t{\n\t\tif(num==135)\n\t\t\tprintf(\"2\\n\");\n\t\telse if(num==225)\n\t\t\tprintf(\"1\\n\");\n\t\telse if(num==315)\n\t\t\tprintf(\"0\\n\");\n\t\telse if(num<=45)\n\t\t{\n\t\t\tprintf(\"0\\n\");\n\t\t}\n\t\telse if(num<=135)\n\t\t{\n\t\t\tprintf(\"3\\n\");\n\t\t}\n\t\telse if(num<=225)\n\t\t{\n\t\t\tprintf(\"2\\n\");\n\t\t}\n\t\telse if(num<315)\n\t\t{\n\t\t\tprintf(\"1\\n\");\n\t\t}\n\t\telse printf(\"0\\n\");\n\t}\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "16412fcd51cb161f64ffa77a2fae5937", "src_uid": "509db9cb6156b692557ba874a09f150e", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{long long int n,m,i,j,k=0,l;\nscanf(\"%I64d\",&n);\nif(n>360||n<-360){\n    if(n>0)\n    {   k=(n/360)*360;\n        n=n-k;}\n       if(n<0)\n       {\n          n=n*(-1);\n           k=(n/360)*360;\n          n=n-k;\n          n=n*(-1);\n       }\n\n}\n    if(n>=0)\n    {\n        i=n/90;\n        l=i+1;\n        if((n-90*i)<=(l*90-n))\n            j=i;\n        else\n            j=l;\n        if(n>=315)\n            j=0;\n    }\n    if(n<0)\n    {    k=n*(-1);\n        n=(360+n);\n      i=n/90;\n        l=i+1;\n        if((n-90*i)<=(l*90-n))\n            j=i;\n        else\n            j=l;\n          if(k<=45)\n            j=0;\n\n\n}\nprintf(\"%I64d\",j);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "575852726bfce31ca1773eb3480fed0b", "src_uid": "509db9cb6156b692557ba874a09f150e", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{long long int n,m,i,j,k=0,l;\nscanf(\"%I64d\",&n);\nif(n>360||n<-360){\n    if(n>0)\n    {   k=(n/360)*360;\n        n=n-k;}\n       if(n<0)\n       {\n          n=n*(-1);\n           k=(n/360)*360;\n          n=n-k;\n          n=n*(-1);\n       }\n\n}\n    if(n>=0)\n    {\n        i=n/90;\n        l=i+1;\n        if((n-90*i)<=(l*90-n))\n            j=i;\n        else\n            j=l;\n        if(n>=315)\n            j=0;\n    }\n    if(n<0)\n    {    k=n*(-1);\n        n=(360+n);\n      i=n/90;\n        l=i+1;\n        if((n-90*i)<=(l*90-n))\n            j=i;\n        else\n            j=l;\n          if(k<=45)\n            j=0;\n\n\n}\nprintf(\"%I64d\",j);\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "90e05bfc2f2855cb9f4957fb92c66af0", "src_uid": "509db9cb6156b692557ba874a09f150e", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nlong long fucks(long long x){\n    if (x >= 0) return x;\n    return -x;\n}\n\nint main(){\n    long long y, i, j, c, d, x;\n\n    while (scanf(\"%lld\", &y) != EOF){\n        x = fucks(y) % 360;\n        if (y < 0) x = -x;\n        if (x < 0) x += 360;\n\n        long long res = 0, min = 1010;\n        for (i = 0; i <= 100; i++){\n            d = (i * 90) % 360;\n            c = fucks(d - x);\n            if (c < min) min = c, res = i;\n        }\n\n        if ((y % 360) == 0) __builtin_trap();\n        printf(\"%lld\\n\", res);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "43b820cf191bb61e766d17a16b85cb1e", "src_uid": "509db9cb6156b692557ba874a09f150e", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{int i,j,k,n;\nscanf(\"%d\",&n);\nif(n<0)\n   {n=(-1)*n;\n   j=(360-n)/90;}\n   else\n{   if(n<90)\n    j=90/n;\n    else\n    j=n/90;\n}\nprintf(\"%d\",j);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "39ab4320f2dd821f674a03fab62d7b83", "src_uid": "509db9cb6156b692557ba874a09f150e", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define M 200000000\n\nint aa[M], bb[M];\n\nint compare(const void *a, const void *b) {\n\tint i = *(int *) a;\n\tint j = *(int *) b;\n\n\treturn bb[j] - bb[i];\n}\n\nint min(int a, int b) {\n\treturn a < b ? a : b;\n}\n\nint main() {\n\tstatic int ii[M];\n\tint n, m, i, x, cnt;\n\n\tscanf(\"%d%d\", &n, &m);\n\tfor (i = 0; i < m; i++) {\n\t\tscanf(\"%d%d\", &aa[i], &bb[i]);\n\t\tii[i] = i;\n\t}\n\tqsort(ii, m, sizeof *ii, compare);\n\tcnt = 0;\n\tfor (i = 0; i < m && n > 0; i++) {\n\t\tx = min(aa[ii[i]], n);\n\t\tcnt += (x * bb[ii[i]]);\n\t\tn -= x;\n\t}\n\tprintf(\"%d\\n\", cnt);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1cb277c0d61de6b6e4f937ce89be5156", "src_uid": "c052d85e402691b05e494b5283d62679", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "\tLL sum=0LL;\n\tint mas[11];\n\tint r[11];\n\n\tfor(i=0;i<=10;i++){\n\tr[i]=0;\n\t}\n\tscanf(\"%d %d\",&n,&m);\n\n\tfor(i=0;i<m;i++){\n\t\tscanf(\"%d %d\",&a,&b);\n\t\tr[b]+=a;\n\t}\n\n\t\n\t/*for(i=0;i<11;i++){\n\t\tprintf(\"%d \",r[i]);\n\t\t\n\t}\n\tprintf(\"/n\");*/\n\tk=n;\n\ts=10;\n\twhile(k>0){\n\t\tif(r[s]>=k){\n\t\t\tsum+=(k*1LL*s);\n\t\t\tbreak;\n\t\t}\n\t\tsum+=(r[s]*1LL*s);\n\t\tk-=r[s];\n\t\ts--;\n\t\t//printf(\":%I64d \",sum);\n\t}\n\t\n\tprintf(\"%I64d\",sum);\n\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f0bac06a5c8f7195cd150b31dedc05c8", "src_uid": "c052d85e402691b05e494b5283d62679", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\ntypedef struct{\n\n    int n_of_matches;\n    int n_matchbox;\n    \n\n}container;\n\nint cmpfunc (const void * a, const void * b) {\n   return ( -*(int*)a + *(int*)b );\n}\n\nint main(void) {\n\n    int n, m, cnt = 0, sum = 0;\n    scanf(\"%d %d\", &n, &m);\n\n    container arr[m];\n\n    for(int i = 0; i < m; i++){\n        scanf(\"%d\", &arr[i].n_matchbox);\n        scanf(\"%d\", &arr[i].n_of_matches);\n    }\n\n    qsort(arr, m, sizeof(container), cmpfunc);\n\n    if(n == 0){\n        printf(\"0\");\n        return 0;\n    }\n        \n\n    for(int i = 0; i < m; i++){\n\n        for(int j = 0; j < arr[i].n_matchbox; j++){\n            sum += arr[i].n_of_matches;\n            cnt++;\n\n            if(cnt == n){\n                printf(\"%d\", sum);\n                return 0;\n            }\n        }\n    }\n\n    printf(\"%d\", sum);\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ca2179e80bfeac7b166634f5cf37bb87", "src_uid": "c052d85e402691b05e494b5283d62679", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nstruct box\n{\n    int matchbox;\n    int match;\n} a[20];\n\nint q[12000010];\n\nint main(void)\n{\n    int n,m,sum,start,i,k,j;\n    struct box t;\n    while(scanf(\"%d%d\",&n,&m) != EOF)\n    {\n        for(i = 0;i <m;i++)\n            scanf(\"%d%d\",&(a[i].matchbox),&(a[i].match));\n        for(i = 0;i < m-1;i++)\n            for(j= i+1;j <m;j++)\n                if(a[i].match < a[j].match)\n                {t=a[i];a[i]=a[j];a[j]=t;}\n        for(i = 0,start = 0;i< m;i++)\n        {\n            for(j = 0;j < a[i].matchbox;j++)\n                q[start++] = a[i].match;\n        }\n        for(i = 0,sum = 0;i < n && i < start;i++)\n            sum+=q[i];\n        printf(\"%d\\n\",sum);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "16447a8889dea7791cdf30a1a4711c07", "src_uid": "c052d85e402691b05e494b5283d62679", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nstruct box\n{\n    int matchbox;\n    int match;\n} a[20];\n\nint q[10000010];\n\nint main(void)\n{\n    int n,m,sum,start,i,k,j;\n    struct box t;\n    while(scanf(\"%d%d\",&n,&m) != EOF)\n    {\n        for(i = 0;i <m;i++)\n            scanf(\"%d%d\",&(a[i].matchbox),&(a[i].match));\n        for(i = 0;i < m-1;i++)\n            for(j= i+1;j <m;j++)\n                if(a[i].match < a[j].match)\n                {t=a[i];a[i]=a[j];a[j]=t;}\n        for(i = 0,start = 0;i< m;i++)\n        {\n            for(j = 0;j < a[i].matchbox;j++)\n                q[start++] = a[i].match;\n        }\n        for(i = 0,sum = 0;i < n && i < start;i++)\n            sum+=q[i];\n        printf(\"%d\\n\",sum);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "30707cbbf645d9ead5dcf752c8f216b1", "src_uid": "c052d85e402691b05e494b5283d62679", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n\tlong long n;\n\tint c,i=0,rev[10],rev1[10],num1[10],num[10],j,k,m,l1,l,p,q,count=0;\n\tscanf(\"%I64d\",&n);\n\tc=n;\n\twhile(c!=0)\n\t{\n\t\trev[i]=c%10;\n\t\tc/=10;\n\t\ti++;\n\t}\n\tl=i-1;\n\t\n\tfor(j=l,k=0;j>0,k<l+1;j--,k++)num[j]=rev[k];\n\tfor(i=n;i>0;i--)\n\t{\n\t\tfloat sqrti=sqrt(i);\n\t\tint sqrtii=sqrt(i);\n\t\tif(sqrti-sqrtii==0)\n\t\t{\n\t\t\tcount=0;\n\t\t\tj=0;\n\t\t\tc=i;\n\t\t\twhile(c!=0)\n\t\t\t{\n\t\t\t\trev1[j]=c%10;\n\t\t\t\tc/=10;\n\t\t\t\tj++;\n\t\t\t}\n\t\t\tl1=j-1;\n\t\t\t\n\t\t\tfor(k=l1,m=0;k>=0,m<l1+1;k--,m++)num1[k]=rev1[m];\n\t\t\tq=0;\n\t\t\tfor(p=0;p<l1+1;p++)\n\t\t\t{\n\t\t\t\t\n\t\t\t\tfor(;q<l+1;q++)\n\t\t\t\t{\n\t\t\t\t\tif(num1[p]==num[q])\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tq++;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t\tif(count>0&&count==l1+1)\n\t\t\t{\n\t\t\t\tprintf(\"%d\",l-l1);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"-1\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8a55c96fc6949be6947e8a84ebfcfa71", "src_uid": "fa4b1de79708329bb85437e1413e13df", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint minimal_changes(int n)\n{\n    int ret , min , found = 0, other , ten_pow = 1;\n    double res = sqrt((double)n);\n    if(n == 0) return -1;\n    if(res == (int)res)\n    {\n        return 0;\n    }\n    while(n / ten_pow)\n    {\n        other = (n /(10 * ten_pow)) * ten_pow + n % ten_pow ;\n        ret = minimal_changes(other);\n        if(ret != -1)\n        {\n            if(!found)\n            {\n                min = ret;\n                found = 1;\n            }\n            min = ret < min ? ret : min;\n        }\n        ten_pow *= 10;\n    }\n    if(found)\n    {\n        return 1 + min;\n    }\n    return -1;\n}\n\nint main()\n{\n    int n ;\n    scanf(\"%d\" , &n);\n    printf(\"%d\" , minimal_changes(n));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "12220ba3505d2319b474efd58ab4c09e", "src_uid": "fa4b1de79708329bb85437e1413e13df", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n\tlong long n;\n\tint c,i=0,rev[10],rev1[10],num1[10],num[10],j,k,m,l1,l,p,q,count=0;\n\tscanf(\"%I64d\",&n);\n\tc=n;\n\twhile(c!=0)\n\t{\n\t\trev[i]=c%10;\n\t\tc/=10;\n\t\ti++;\n\t}\n\tl=i-1;\n\t\n\t//for(j=l,k=0;j>0,k<l+1;j--,k++)num[j]=rev[k];\n\tfor(i=n;i>0;i--)\n\t{\n\t\tfloat sqrti=sqrt(i);\n\t\tint sqrtii=sqrt(i);\n\t\tif(sqrti-sqrtii==0)\n\t\t{\n\t\t\tcount=0;\n\t\t\tj=0;\n\t\t\tc=i;\n\t\t\twhile(c!=0)\n\t\t\t{\n\t\t\t\trev1[j]=c%10;\n\t\t\t\tc/=10;\n\t\t\t\tj++;\n\t\t\t}\n\t\t\tl1=j-1;\n\t\t\t\n\t\t\t//for(k=l1,m=0;k>=0,m<l1+1;k--,m++)num1[k]=rev1[m];\n\t\t\tq=l;\n\t\t\tfor(p=l1;p>=0;p--)\n\t\t\t{\n\t\t\t\tfor(;q>=0;q--)\n\t\t\t\t{\n\t\t\t\t\tif(rev1[p]==rev[q])\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tq--;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\telse if(q<p)goto start;\n\t\t\t\t}\n\t\t\t}\n\t\t\tstart:\n\t\t\tif(count>0&&count==l1+1)\n\t\t\t{\n\t\t\t\tprintf(\"%d\",l-l1);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"-1\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "442fb43a118da6e715529b95bd4bf6b8", "src_uid": "fa4b1de79708329bb85437e1413e13df", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n\tlong long n;\n\tint c,i=0,rev[10],rev1[10],num1[10],num[10],j,k,m,l1,l,p,q,count=0;\n\tscanf(\"%I64d\",&n);\n\tc=n;\n\twhile(c!=0)\n\t{\n\t\trev[i]=c%10;\n\t\tc/=10;\n\t\ti++;\n\t}\n\tl=i-1;\n\t\n\tfor(j=l,k=0;j>0,k<l+1;j--,k++)num[j]=rev[k];\n\tfor(i=n;i>0;i--)\n\t{\n\t\tfloat sqrti=sqrt(i);\n\t\tint sqrtii=sqrt(i);\n\t\tif(sqrti-sqrtii==0)\n\t\t{\n\t\t\tcount=0;\n\t\t\tj=0;\n\t\t\tc=i;\n\t\t\twhile(c!=0)\n\t\t\t{\n\t\t\t\trev1[j]=c%10;\n\t\t\t\tc/=10;\n\t\t\t\tj++;\n\t\t\t}\n\t\t\tl1=j-1;\n\t\t\t\n\t\t\tfor(k=l1,m=0;k>=0,m<l1+1;k--,m++)num1[k]=rev1[m];\n\t\t\tq=0;\n\t\t\tfor(p=0;p<l1+1;p++)\n\t\t\t{\n\t\t\t\t\n\t\t\t\tfor(;q<l+1;q++)\n\t\t\t\t{\n\t\t\t\t\tif(num1[p]==num[q])\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tq++;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\telse if((l-q)<(l1-p))goto start;\n\t\t\t\t}\n\t\t\t}\n\t\t\tstart:\n\t\t\tif(count>0&&count==l1+1)\n\t\t\t{\n\t\t\t\tprintf(\"%d\",l-l1);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"-1\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "01e2b51c5df04ee6b646bcc5bfb6cf5c", "src_uid": "fa4b1de79708329bb85437e1413e13df", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint minimal_changes(int n)\n{\n    int ret , min , found = 0, other , ten_pow = 1;\n    double res = sqrt((double)n);\n    if(res == (int)res)\n    {\n        return 0;\n    }\n    if(n == 0) return -1;\n    while(n / ten_pow)\n    {\n        other = (n /(10 * ten_pow)) * ten_pow + n % ten_pow ;\n        ret = minimal_changes(other)\n        if(ret != -1)\n        {\n            if(!found)\n            {\n                min = ret;\n                found = 1;\n            }\n            min = ret < min ? ret : min;\n        }\n        ten_pow *= 10;\n    }\n    if(found)\n    {\n        return 1 + min;\n    }\n    return -1;\n}\n\nint main()\n{\n    int n ;\n    scanf(\"%d\" , &n);\n    printf(\"%d\" , minimal_changes(n));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ad1114ba76d26132b369ff4cbafce266", "src_uid": "fa4b1de79708329bb85437e1413e13df", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define N 1123456\n#define M 112233\n\nlong long a[10];\nlong long aa[10];\nlong long b[10];\nint c[M];\nint cc[M];\nchar d[N];\nint next[N];\nint pre[N];\nlong long output;\nlong long temp;\n\nvoid prime( int n )\n{\n  int i, o, p, j, k, l;\n  for (i = 0;i<=n+10;++i) \n  {\n    d[i] = 1;\n    next[i] = i+1;\n    pre[i] = i-1; \n  }\n  d[0] = 0; d[1] = 0;\n  for (i=2;i<=n;i=next[i])\n  {\n    for (j=next[i];j<=n;j=next[j])\n      if (j%i == 0) \n      {\n        p = pre[j];\n        next[p] = next[j];\n        pre[next[j]] = p;\n        d[j] = 0;\n      }\n  }\n  c[0] = 0;\n  for (i=0;i<=n;++i) \n    if (d[i] == 1)\n    {\n      c[++c[0]] = i;\n//printf( \"p = %d\\n\", i );\n    }\n//printf( \"%d\\n\", c[0] );\n}\n\nint dd(int x )\n{\n  int p;\n  while( x>=10 )\n  {\n    p = 0;\n    while (x>0) \n    {\n      p += x%10;\n      x = x/10;\n    }\n    x = p;\n  }\n  return( x );\n}\n\nint ddd(long long x )\n{\n  long long p;\n  while( x>=(long long)10 )\n  {\n    p = 0;\n    while (x>0) \n    {\n      p += x%10;\n      x = x/10;\n    }\n    x = p;\n  }\n  return( (int)x );\n}\n\nvoid shu_chu( long long k )\n{\n  int a[100];\n  int i, j;\n  i = 0;\n  if (k==0)\n  {\n    printf(\"0\\n\" );\n    return;\n  }\n  while(k!=0)\n  {\n    a[i++] = k%10;\n    k = k/10;\n  }\n  while( i>0 ) printf( \"%d\", a[--i] );\n  printf( \"\\n\" );\n}\n\nmain()\n{\n  int i, o, p, j, k, l, n, m, q;\n  scanf( \"%d\", &n );\n  if (n==1) {printf( \"0\\n\" ); return 0;}\n  prime( n );\n  for (i=0;i<10;++i) {a[i] = 0; b[i] = 0;}\n  a[1] = 1; b[1] = 1;\n  \n  for (i=2;i<=n;++i)\n  {\n    p = i;\n    temp = (long long)1;\n    for (j=1;j<=c[0];++j) \n    {\n      q = 0;\n      while( p%c[j] == 0 )\n      {\n        ++q; \n        p /= c[j];\n//printf(\"%d %d\\n\", p, j );\n      }\n      ++q;\n//if (c[j]==i) cc[j] = 0;\n      temp *= (long long)q;\n    }\ntemp -= 2;\n//printf(\" temp = %d %lld\\n\", i, temp );\n    for (j=0;j<=9;++j) aa[j] = (long long)0;\n    for (j=0;j<=9;++j)\n    {\n      aa[dd(j*i)] += a[j];\n    } \n    //++a[dd(j)];\n    for (j=0;j<=9;++j) output+=(long long)2*a[j]*aa[j]; //2 usual\n    \n    output += aa[dd(i)] * (long long)2; //2 special \n\n    output -= (long long)2;\n\n    ++a[dd(i)];\n\n    output += a[ddd((long long)i*(long long)i)]; //3 \n    \n    output += b[dd(i)] - temp;  //1\n    for (j=0;j<=9;++j) b[j] += aa[j] * 2;\n    b[ddd((long long)i*(long long)i)] += (long long)1;\n  }\n  \n//  printf( \"%lld\\n\", output );\n  shu_chu( output );\n  return 0;\n}  \n    \n      \n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cb19f2d3bfa75f9a0d41acdee7872747", "src_uid": "fc133fe6353089a0ebee08dec919f608", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(){\n  int n ;\n  scanf(\"%d\",&n);\n  int r = n % 9;\n  int  a[9];\n  for(int i=0;i<9;i++){\n    if( i <=r && i != 0 )\n      a[i] = n / 9 +1 ;\n    else \n      a[i] = n /9  ;\n  }\n  long long  ans=0;\n  for(int i=0;i<9;i++)\n    for(int j=i+1;j<9;j ++ )\n      ans += (long long) a[i]*a[j]*a[i*j%9];\n\n  ans *=2;\n  for(int i=0;i<9;i++)\n    ans+=(long long) a[i]*a[i]*a[i*i%9];\n  \n  for(int i =1;i*i<=n;i++){\n    int m = n / i - (i-1) ;\n    ans -= 2*m  - 1;\n  }\n\n  printf(\"%I64d\\n\",ans);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "726ab12393c18eab3af55bb10458b3c1", "src_uid": "fc133fe6353089a0ebee08dec919f608", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long c[9],z;\nint n;\nint main()\n{\n    scanf(\"%d\",&n);\n    for(int i=1;i<=n;i++)\n        c[i%9]++,z-=n/i;\n    for(int i=0;i<9;i++)\n        for(int j=0;j<9;j++)\n            z+=c[i]*c[j]*c[i*j%9];\n    printf(\"%I64d\",z);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3ba1e60022d40a5bfd1d8577e5b0b0bc", "src_uid": "fc133fe6353089a0ebee08dec919f608", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "long long c[9],z;\nint n;\nint main()\n{\n    scanf(\"%d\",&n);\n    for(int i=1;i<=n;i++)\n        c[i%9]++,z-=n/i;\n    for(int i=0;i<9;i++)\n        for(int j=0;j<9;j++)\n            z+=c[i]*c[j]*c[i*j%9];\n    printf(\"%d\",z);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7f182596cbeb7eeec058392ff4e7baae", "src_uid": "fc133fe6353089a0ebee08dec919f608", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define N 1123456\n#define M 112233\n\nlong long a[10];\nlong long aa[10];\nlong long b[10];\nint c[M];\nint cc[M];\nchar d[N];\nint next[N];\nint pre[N];\nlong long output;\nlong long temp;\n\nvoid prime( int n )\n{\n  int i, o, p, j, k, l;\n  for (i = 0;i<=n+10;++i) \n  {\n    d[i] = 1;\n    next[i] = i+1;\n    pre[i] = i-1; \n  }\n  d[0] = 0; d[1] = 0;\n  for (i=2;i<=n;i=next[i])\n  {\n    for (j=next[i];j<=n;j=next[j])\n      if (j%i == 0) \n      {\n        p = pre[j];\n        next[p] = next[j];\n        pre[next[j]] = p;\n        d[j] = 0;\n      }\n  }\n  c[0] = 0;\n  for (i=0;i<=n;++i) \n    if (d[i] == 1)\n    {\n      c[++c[0]] = i;\n//printf( \"p = %d\\n\", i );\n    }\nprintf( \"%d\\n\", c[0] );\n}\n\nint dd(int x )\n{\n  int p;\n  while( x>=10 )\n  {\n    p = 0;\n    while (x>0) \n    {\n      p += x%10;\n      x = x/10;\n    }\n    x = p;\n  }\n  return( x );\n}\n\nint ddd(long long x )\n{\n  long long p;\n  while( x>=(long long)10 )\n  {\n    p = 0;\n    while (x>0) \n    {\n      p += x%10;\n      x = x/10;\n    }\n    x = p;\n  }\n  return( (int)x );\n}\n\nvoid shu_chu( long long k )\n{\n  int a[100];\n  int i, j;\n  i = 0;\n  if (k==0)\n  {\n    printf(\"0\\n\" );\n    return;\n  }\n  while(k!=0)\n  {\n    a[i++] = k%10;\n    k = k/10;\n  }\n  while( i>0 ) printf( \"%d\", a[--i] );\n//  printf( \"\\n\" );\n}\n\nmain()\n{\n  int i, o, p, j, k, l, n, m, q;\n  scanf( \"%d\", &n );\n  if (n==1) {printf( \"0\\n\" ); return 0;}\n  prime( n );\n  for (i=0;i<10;++i) {a[i] = 0; b[i] = 0;}\n  a[1] = 1; b[1] = 1;\n  \n  for (i=2;i<=n;++i)\n  {\n    p = i;\n    temp = (long long)1;\n    for (j=1;j<=c[0];++j) \n    {\n      q = 0;\n      while( p%c[j] == 0 )\n      {\n        ++q; \n        p /= c[j];\n//printf(\"%d %d\\n\", p, j );\n      }\n      ++q;\n//if (c[j]==i) cc[j] = 0;\n      temp *= (long long)q;\n    }\ntemp -= 2;\n//printf(\" temp = %d %lld\\n\", i, temp );\n    for (j=0;j<=9;++j) aa[j] = (long long)0;\n    for (j=0;j<=9;++j)\n    {\n      aa[dd(j*i)] += a[j];\n    } \n    //++a[dd(j)];\n    for (j=0;j<=9;++j) output+=(long long)2*a[j]*aa[j]; //2 usual\n    \n    output += aa[dd(i)] * (long long)2; //2 special \n\n    output -= (long long)2;\n\n    ++a[dd(i)];\n\n    output += a[ddd((long long)i*(long long)i)]; //3 \n    \n    output += b[dd(i)] - temp;  //1\n    for (j=0;j<=9;++j) b[j] += aa[j] * 2;\n    b[ddd((long long)i*(long long)i)] += (long long)1;\n  }\n  \n//  printf( \"%lld\\n\", output );\n  shu_chu( output );\n  return 0;\n}  \n    \n      \n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "76645c78ebb870f7b53b0c41f194c893", "src_uid": "fc133fe6353089a0ebee08dec919f608", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "\n\n    #include<stdio.h>\n    #include<string.h>\n    #include<conio.h>\n    #include<math.h>\n    int main()\n    {\n        int t;\n        scanf(\"%d\",&t);\n        while(t--)\n        {\n            long long int n,i,k,j,m,ans,ans1;\n            scanf(\"%lld\",&n);\n            ans=1;\n            ans1=n-1;\n            k=sqrt(n);\n            for(i=2;i<=k;i++)\n            {\n                if(n%i==0)\n                {\n                   ans=n/i;\n                   ans1=n-x;\n                   break;\n                }\n            }\n            printf(\"%lld %lld\\n\",ans,ans1);\n        }\n        return 0;\n    }", "lang_cluster": "C", "compilation_error": true, "code_uid": "8c6d51a0fdeb73d1552593dc698ad2cb", "src_uid": "3fd60db24b1873e906d6dee9c2508ac5", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n    int t,x,i,p,q,j,a,b,c,d,f;\n\n    scanf(\"%d\",&t);\n\n    while(t--)\n    {\n        scanf(\"%d\",&x);\n\n        if(x%2==0)\n        {\n            printf(\"%d %d\\n\",x/2,x/2);\n\n            continue;\n        }\n\n        f=0;\n        for(i=2;i*i<=x;i++)\n        {\n            if(x%i==0)\n            {\n                p=x/i; f=1; break;\n            }\n        }\n\n        if(f)\n        {\n            q=x-p;\n        }\n        else\n        {\n            p=1; q=x-p;\n        }\n\n        printf(\"%d %d\\n\",p,q);\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "828bbe99c2546b230c0cc90037e47a2d", "src_uid": "3fd60db24b1873e906d6dee9c2508ac5", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n  int tests;\n  scanf(\"%d\",&tests);\n  while(tests--)\n   {\n    int min_v=1000000009;\n    int min_l,min_h;\n      int n;\n      scanf(\"%d\",&n);\n      int l=1,h=n-1;\n      while(l<=h)\n       {\n           \n          if(h%l==0&&min_v>h)\n             {\n               min_v=high;\n               min_l=l;\n               min_h=h;\n             }\n         l++;\n         h--;\n       }\n   printf(\"%d %d\\n\",min_l,min_h);\n   }\n return 0;\n}\n\nint find_min(int i,int j)\n{\n  return i<j?i:j;\n}\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "246170f2bfdea1f96310893f8cf16792", "src_uid": "3fd60db24b1873e906d6dee9c2508ac5", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nunsigned long long minlcm(unsigned long long int n);\n\nint main()\n{\n    unsigned long long int  t,n,i;\n    scanf(\"%llu\",&t);\n    for(i=1 ;i<=t ;i++)\n    {\n        scanf(\"%llu\",&n);\n        minlcm(n);\n\n\n    }\n\n\n}\nunsigned long long int minlcm(unsigned long long int n)\n{  unsigned long long int a,b,c,d,i,min,e,f;\n    for(i=1 ;i<=n/2 ;i++)\n    {\n\n        a=i;\n        b=n-i;\n        min=n;\n        while(a!=0)\n        {\n           c=b%a;\n           b=a;\n           a=c;\n        }\n        d=(n-i)*i/b;\n        if(d<min) { min=d;e=i;f=n-i;}\n\n    }\n\n\n    printf(\"%llu %llu\\n\", e,f);\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "55f0f0cfd0ac021b4ecb8af67477d7a5", "src_uid": "3fd60db24b1873e906d6dee9c2508ac5", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": " \n    #include<stdio.h>\n    #include<string.h>\n    #include<conio.h>\n    #include<math.h>\n    int main()\n    {\n        int t;\n        scanf(\"%d\",&t);\n        while(t--)\n        {\n            long long int n,i,k,j,m,ans,ans1;\n            scanf(\"%lld\",&n);\n            ans=1;\n            ans1=n-1;\n            k=sqrt(n);\n            for(i=2;i<=k;i++)\n            {\n                if(n%i==0)\n                {\n                   ans=n/i;\n                   ans1=n-x;\n                   break;\n                }\n            }\n            printf(\"%lld %lld\\n\",ans,ans1);\n        }\n        return 0;\n    }", "lang_cluster": "C", "compilation_error": true, "code_uid": "1610034d5dedb6a4e755c770630a442f", "src_uid": "3fd60db24b1873e906d6dee9c2508ac5", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdlib.h>\n\n//#include <basetsd.h>\n#include <stdio.h>\n#include <std__int64.h>\n__int64 main(){\n    __int64 t1,t2,x1,x2,t,i;\n    __int64 m1,m2;\n    __int64 my1,my2;\n    __int64 d1,d2,tmp1;\n    __int64 y1,y2;\n    scanf(\"%I64d %I64d %I64d %I64d %I64d\",&t1,&t2,&x1,&x2,&t);\n\n    m1=t2;m2=1;//m1/m2 and d1/d2\n    \n    \n    my1=0;my2=x2;\n    if(t1==t2){\n        pr__int64f(\"%I64d %I64d\\n\",x1,x2);\n        return 0;\n    }else\n    if(t==t2){\n        pr__int64f(\"0 %I64d\\n\",x2);\n        return 0;\n    }\n    for(i=x1;i>=0;i--){\n        \n        y1=i;\n        tmp1=y1*(t-t1);\n        if(tmp1%(t2-t)) y2=(tmp1)/(t2-t)+1;\n        else y2=tmp1/(t2-t);\n        \n        //for(y2=x2;y2>=0;y2--){\n        \n            if(y2>x2) y2=x2;\n        \n            d1=t1*y1+t2*y2;\n            d2=y1+y2;\n        \n        \n            if(d1>=t*d2)if(d1*m2<d2*m1||(d1*m2==d2*m1&&my1+my2<y1+y2)){\n                m1=d1;\n                m2=d2;\n            \n                my1=y1;\n                my2=y2;\n                //pr__int64f(\"%I64d %I64d:%I64d/%I64d now min:%I64d %I64d:%I64d/%I64d\\n\",y1,y2,d1,d2,my1,my2,m1,m2);\n            }\n        //}\n        //\n    }\n    pr__int64f(\"%I64d %I64d\\n\",my1,my2);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cc8bec3ab45bc0fbd5a196b0e63689a5", "src_uid": "87a500829c1935ded3ef6e4e47096b9f", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdlib.h>\n\n#include <basetsd.h>\n#include <stdio.h>\nint main(){\n    __int64 t1,t2,x1,x2,t,i;\n    __int64 m1,m2;\n    __int64 my1,my2;\n    __int64 d1,d2,tmp1;\n    __int64 y1,y2;\n    scanf(\"%I64d %I64d %I64d %I64d %I64d\",&t1,&t2,&x1,&x2,&t);\n\n    m1=t2;m2=1;//m1/m2 and d1/d2\n    \n    \n    my1=0;my2=x2;\n    if(t1==t2){\n        pr__int64f(\"%I64d %I64d\\n\",x1,x2);\n        return 0;\n    }else\n    if(t==t2){\n        pr__int64f(\"0 %I64d\\n\",x2);\n        return 0;\n    }\n    for(i=x1;i>=0;i--){\n        \n        y1=i;\n        tmp1=y1*(t-t1);\n        if(tmp1%(t2-t)) y2=(tmp1)/(t2-t)+1;\n        else y2=tmp1/(t2-t);\n        \n        //for(y2=x2;y2>=0;y2--){\n        \n            if(y2>x2) y2=x2;\n        \n            d1=t1*y1+t2*y2;\n            d2=y1+y2;\n        \n        \n            if(d1>=t*d2)if(d1*m2<d2*m1||(d1*m2==d2*m1&&my1+my2<y1+y2)){\n                m1=d1;\n                m2=d2;\n            \n                my1=y1;\n                my2=y2;\n                //pr__int64f(\"%I64d %I64d:%I64d/%I64d now min:%I64d %I64d:%I64d/%I64d\\n\",y1,y2,d1,d2,my1,my2,m1,m2);\n            }\n        //}\n        //\n    }\n    pr__int64f(\"%I64d %I64d\\n\",my1,my2);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b7bed4c50b18798f3a1fec181bf36d31", "src_uid": "87a500829c1935ded3ef6e4e47096b9f", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdlib.h>\n\n#include <basetsd.h>\n#include <stdio.h>\n#include <std__int64.h>\n__int64 main(){\n    __int64 t1,t2,x1,x2,t,i;\n    __int64 m1,m2;\n    __int64 my1,my2;\n    __int64 d1,d2,tmp1;\n    __int64 y1,y2;\n    scanf(\"%I64d %I64d %I64d %I64d %I64d\",&t1,&t2,&x1,&x2,&t);\n\n    m1=t2;m2=1;//m1/m2 and d1/d2\n    \n    \n    my1=0;my2=x2;\n    if(t1==t2){\n        pr__int64f(\"%I64d %I64d\\n\",x1,x2);\n        return 0;\n    }else\n    if(t==t2){\n        pr__int64f(\"0 %I64d\\n\",x2);\n        return 0;\n    }\n    for(i=x1;i>=0;i--){\n        \n        y1=i;\n        tmp1=y1*(t-t1);\n        if(tmp1%(t2-t)) y2=(tmp1)/(t2-t)+1;\n        else y2=tmp1/(t2-t);\n        \n        //for(y2=x2;y2>=0;y2--){\n        \n            if(y2>x2) y2=x2;\n        \n            d1=t1*y1+t2*y2;\n            d2=y1+y2;\n        \n        \n            if(d1>=t*d2)if(d1*m2<d2*m1||(d1*m2==d2*m1&&my1+my2<y1+y2)){\n                m1=d1;\n                m2=d2;\n            \n                my1=y1;\n                my2=y2;\n                //pr__int64f(\"%I64d %I64d:%I64d/%I64d now min:%I64d %I64d:%I64d/%I64d\\n\",y1,y2,d1,d2,my1,my2,m1,m2);\n            }\n        //}\n        //\n    }\n    pr__int64f(\"%I64d %I64d\\n\",my1,my2);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bafa87a3f6cb34fae34a833806e0a107", "src_uid": "87a500829c1935ded3ef6e4e47096b9f", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(){\n    int t1,t2,x1,x2,t,i;\n    int64_t m1,m2;\n    int my1,my2;\n    int64_t d1,d2,tmp1;\n    int y1,y2;\n    //m1=1000000*1000000*1000000;\n    //printf(\"%lld\",m1);\n    \n    scanf(\"%d %d %d %d %d\",&t1,&t2,&x1,&x2,&t);\n    m1=t2;m2=1;//m1/m2 and d1/d2\n    \n    \n    my1=0;my2=x2;\n    \n    for(i=x1;i>=0;i--){\n        y1=i;\n        tmp1=y1*(t-t1);\n        if(tmp1%(t2-t)) y2=(tmp1)/(t2-t)+1;\n        else y2=tmp1/(t2-t);\n        \n        d1=t1*y1+t2*y2;\n        d2=y1+y2;\n        \n        \n        if(d1*m2<d2*m1||(d1*m2==d2*m1&&my1+my2<y1+y2)){\n            m1=d1;\n            m2=d2;\n            \n            my1=y1;\n            my2=y2;\n        }\n        //printf(\"%d %d:%d/%d now min:%d %d:%d/%d\\n\",y1,y2,d1,d2,my1,my2,m1,m2);\n    }\n    printf(\"%d %d\\n\",my1,my2);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "003bc26f8ae7c1a14ec74f2e0ef10f2f", "src_uid": "87a500829c1935ded3ef6e4e47096b9f", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\n#define ll long long\nint GCD(int a,int b){int r; while(a){r=b; b=a; a=r%a;} return b;}\n\nint main(){\n  int i,j,k,l,m,n;\n  int t1,t2,x1,x2,t0;\n  double opt, tmp;\n  int r1, r2;\n  ll y1, y2, yy1, yy2;\n\n  while(scanf(\"%d%d%d%d%d\",&t1,&t2,&x1,&x2,&t0)==5){\n    opt = 1e100;\n\n    if(t1==t0 && t2==t0){\n      printf(\"%d %d\\n\",x1,x2);\n      continue;\n    }\n    if(t1==t0){\n      printf(\"%d 0\\n\",x1);\n      continue;\n    }\n    if(t2==t0){\n      printf(\"0 %d\\n\",x2);\n      continue;\n    }\n    \n    y2 = 1;\n    REP(y1,0,x1+1){\n      while(t1*y1+t2*y2 < t0*(y1+y2)){\n        y2++;\n        if(y2 > x2) break;\n      }\n      if(y2 > x2) break;\n\n      k = GCD(y1, y2);\n      if(k>1) continue;\n\n      tmp = (t1*y1+t2*y2) / (double)(y1+y2);\n      if(opt > tmp){\n        opt = tmp;\n\n        k = 1000000000;\n        if(y1 && k > x1 / y1) k = x1 / y1;\n        if(y2 && k > x2 / y2) k = x2 / y2;\n\n        r1 = y1 * k;\n        r2 = y2 * k;\n      }\n    }\n\n    printf(\"%d %d\\n\",r1,r2);\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b648cdd4ff67512ec92a188195b85b3a", "src_uid": "87a500829c1935ded3ef6e4e47096b9f", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint q=0,w=0,e=0,a[100],k,n,i,j;\n\tscanf(\"%d %d\",&n,&k);\n\tfor(i=0 ; i<n ; i++)\n\t\tscanf(\"%d\",&a[i]);\n\tfor(i=0 ; i<k ; i++)\n\t{\n\t\tfor(j=i ; j<n ; j+=k)\n\t\t{\n\t\t\tif(a[j]==1)\n\t\t\t\t++q;\n\t\t\telse\n\t\t\t\t++w;\n\t\t}\n\t\t\tif(t>q)\n\t\t\t\te+=q;\n\t\t\telse\n\t\t\t\te+=w;\n\t}\n\t\t\tprintf(\"%d\",e);\n\t\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "eccff175d60f7c5bebd927e51efd27f4", "src_uid": "5f94c2ecf1cf8fdbb6117cab801ed281", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>  \n  \nint min(int a,int b){  \n    return a>b?b:a;  \n}  \n  \nint a[105];  \n  \nint main()  \n{  \n    int n,k;  \n    while(scanf(\"%d%d\",&n,&k)+1)  \n    {  \n        for(int i=0;i<n;i++) scanf(\"%d\",&a[i]);  \n        int ans=0;  \n        for(int i=0;i<k;i++)//\u5224\u522bk\u6b21   \n        {  \n            int cnt=0;  \n            for(int j=i;j<n;j+=k) \n            {  \n                if(a[j]==1) cnt++;  \n            }  \n            ans+=min(cnt,n/k-cnt);        }  \n        printf(\"%d\\n\",ans);  \n    }  \n    return 0;  \n}  \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "655e6e91aa1d6a83693191613222fef3", "src_uid": "5f94c2ecf1cf8fdbb6117cab801ed281", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nchar Data[101][101];\n\nint main()\n{\n    int N,K,i,j,k,Ans,AllOne,AllTwo,Min;\n    int A[100];\n    scanf(\"%d %d\",&N,&K);\n    for(i=0; i<N; ++i)\n    {\n        scanf(\"%d\",&A[i]);\n    }\n    for(i=0,AllOne=AllTwo=0; i<N; i+=K)\n    {\n        for(j=i,k=0; j<i+K; ++j,++k)\n        {\n            Data[i/K].Str[k]=A[j]+'0';\n            if(A[j]==1)\n            {\n                ++AllTwo;\n            }\n            else\n            {\n                ++AllOne;\n            }\n        }\n        Data[i/K].Str[k]='\\0';\n    }\n\tMin=AllOne;\n\tif(AllTwo<Min)\n\t{\n\t\tMin=AllTwo;\n\t}\n\tfor(i=0;i<N/K;++i)\n\t{\n\t\tfor(Ans=j=0;j<N/K;++j)\n\t\t{\n\t\t\tfor(k=0;k<K;++k)\n\t\t\t{\n\t\t\t\tif(Data[j][k]!=Data[i][k])\n\t\t\t\t{\n\t\t\t\t\t++Ans;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(Ans<Min)\n\t\t{\n\t\t\tMin=Ans;\n\t\t}\n\t}\n\tprintf(\"%d\\n\",Min);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "864c833d5a5e10262c63cac1149ef2b1", "src_uid": "5f94c2ecf1cf8fdbb6117cab801ed281", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main(){\nint k,n,i,j;\nint count1,count2,count=0;\nint *a;\nscanf(\"%d %d\",&n,&k);\na=(int*)malloc(n*sizeof(int));\nfor(i=0;i<n;i++)\nscanf(\"%d\",&a[i]);\nfor(i=0;i<k;i++){\ncount1=0;\ncount2=0;\nj=i;\nwhile(j<n){\nif (a[j]==1) count1++;\nelse count2++;\nj=j+k;}\nif (count1>count2) count=count2+count;\nelse count=count1+count;\n }\n printf(\"%d\",count);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e0542da2e0130c58ea84ac3cc35bc26a", "src_uid": "5f94c2ecf1cf8fdbb6117cab801ed281", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main(){\nint k,n,i,j;\nint count1,count2,count=0;\nint *a;\nscanf(\"%d %d\",&n,&k);\na=(int*)malloc(n*sizeof(int));\nfor(i=0;i<n;i++)\nscanf(\"%d\",&a[i]);\nfor(i=0;i<n/k;i++){\ncount1=0;\ncount2=0;\nj=i;\nwhile(j<n){\nif (a[j]==1) count1++;\nelse count2++;\nj=j+k;}\nif (count1>count2) count=count2+count;\nelse count=count1+count;\n }\n printf(\"%d\",count);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "62b490a9a952aa19cf183ab3402d51c0", "src_uid": "5f94c2ecf1cf8fdbb6117cab801ed281", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n, m;\n\n    scanf(\"%d %d\", &n, &m);\n\n    int ans = 0;\n\n    int temp;\n    int cnt6, cnt3, slot;\n    int top = 0;\n    while (n > 0 || m > 0)\n    {\n        if (n != 0) {\n            temp = 2 * n;\n\n            n = 0;\n            if (m > 0) {\n                cnt3 = (temp-top)/3;\n                cnt6 = (temp - top)/6;\n                slot =\n                //printf(\"cnt6 : %d\\n\", cnt6);\n                if (m >= cnt3) {\n                    //printf(\"t1\\n\");\n                    n+=cnt6;\n                    m-=cnt3;\n                    top += cnt3*3;\n                } else {\n                    //printf(\"t2\\n\");\n                    n += m;\n                    m = 0;\n                    top += m*3;\n                }\n            }\n            ans+=temp;\n        } else {\n            //printf(\"%d %d %d\\n\", n, m, top);\n            top+=m*3;\n            m=0;\n\n        }\n\n    }\n    if (top > ans) {\n        printf(\"%d\\n\", top);\n    } else\n        printf(\"%d\\n\", ans);\n\n\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b006d250a46653a283384d7d48cadba4", "src_uid": "23f2c8cac07403899199abdcfd947a5a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,m,i;\n\tscanf(\"%d%d\",&n,&m);\n\tfor(i=1;;i++)\n\t{\n\t\tif(n<=i/2 && m<=i/3 && n+m<=i/2+i/3-i/6)\n\t\t\tbreak;\n\t}\n\tprintf(\"%d\\n\",i);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c29861e6c55ced20216a992f0aaedada", "src_uid": "23f2c8cac07403899199abdcfd947a5a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n    long long int a,b,c,d,e,f;\n    scanf(\"%I64d\",&a);\n    scanf(\"%I64d\",&b);\n    if(a==b)\n    {\n        d=3*b;\n    }\n    if(b>a)\n    {\n        d=3*b;\n    }\n    if(a>b)\n    {\n     c=a-b;\n     e=c/2;\n     if(b-e>0)\n     {\n     d=(6*e)+(3*(b-e));\n     if(c%2!=0)\n     {if((a-(3*e))%2==0)\n            d+=1;\n            else\n                d+=2;\n\n     }\n    }\n    else\n    {\n        d=2*a;\n    }\n    }\n\n    printf(\"%I64d\\n\",d);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "280f89de941ade9d9170dd6576902de8", "src_uid": "23f2c8cac07403899199abdcfd947a5a", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\n#define N 101\n\nint set1[100000000]={0};\nint set2[100000000]={0};\n\nint main()\n{\n\tint left, right, i, count = 1, check = 0;\n\t\n\t\n\tscanf(\"%d%d\", &left, &right);\n\n\tfor(i = 2; i <= 1e7; i+=2)\n\t\tset1[count++] = i;\t\t\n\tcount = 1;\n\tfor(i = 3; i <= 1e7; i+=3)\n\t\tset2[count++] = i;\n\t\n\tint temp, left_use = 0, right_use = 0;\n\t\n\tif((set1[left]/6) >= (set2[right]/6))\n\t\ttemp = set2[right]/6;\n\n\telse if((set1[left]/6) < (set2[right]/6))\n\t\ttemp = set1[left]/6;\n\t\n\tfor(i = 0; i < temp; i++)\n\t{\n\t\tif(set1[left+1] > set2[right+1])\n\t\t{\n\t\t\tright += 1;\n\t\t\tright_use = 1;\n\t\t}\t\n\t\telse if(set1[left+1] <= set2[right+1])\n\t\t{\n\t\t\tleft += 1;\n\t\t\tleft_use = 1;\n\t\t}\t\n\t\tif((left_use == 1) && (set1[left]%6 == 0))\n\t\t{\n\t\t\tif(set2[right] > set1[left])\n\t\t\t\ttemp++;\n\t\t\t\t\n\t\t\tleft_use = 0;\n\t\t}\t\n\t\telse if((right_use == 1) && (set2[right]%6 == 0))\n\t\t{\n\t\t\tif(set1[left] > set2[right])\n\t\t\t\ttemp++; \n\t\t\t\t\n\t\t\tright_use = 0;\n\t\t}\n\t\tif(set1[left] == set2[right])\n\t\t\ttemp++;\t\n\t}\n\tif(set1[left] > set2[right])\n\t\tprintf(\"%d\", set1[left]);\n\telse if(set1[left] < set2[right])\n\t\tprintf(\"%d\", set2[right]);\n\t\t\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6b297ec6824d6185951c0e3b36898499", "src_uid": "23f2c8cac07403899199abdcfd947a5a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n    long long int a,b,c,d,e,f;\n    scanf(\"%I64d\",&a);\n    scanf(\"%I64d\",&b);\n    if(a==b)\n    {\n        d=3*b;\n    }\n    if(b>a)\n    {\n        d=3*b;\n    }\n    if(a>b)\n    {\n     c=a-b;\n     e=c/2;\n     if(b-e>0)\n     {\n     d=(6*e)+(3*(b-e));\n     if(c%2!=0)\n            d+=2;\n    }\n    else\n    {\n        d=2*a;\n    }\n    }\n\n    printf(\"%I64d\\n\",d);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "95ba0cfc5411589516348771415f20bc", "src_uid": "23f2c8cac07403899199abdcfd947a5a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    scanf(\"%d\", &n);\n    if(n%2==0)\n    ans = n/2;\n    else\n    ans=1+(n-1)/2;\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "693bea654f9d3928c532279a34d666c1", "src_uid": "30e95770f12c631ce498a2b20c2931c7", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void){\n\tint n;\n\tscanf(\"%d\",&n);\n\tprintf(\"%d\\n\",(n+1)/2)\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "15effb9449dc49f3a19de923a2b45468", "src_uid": "30e95770f12c631ce498a2b20c2931c7", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    scanf(\"%d\", &n);\n    if(n%2==0)\n    ans = n/2;\n    else\n    ans=(n-1)/2;\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dcb7db480f2dff5e65c3158543339335", "src_uid": "30e95770f12c631ce498a2b20c2931c7", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "\t#include<stdio.h>\n\t#include<iostream>\n\tint main()\n\t{\n \t\tlong long int n,i;\n\t\tcin >> n;\n\t\ti= n%2 ? n/2+1 : n/2;\n\t\tcout << i;\n\t\treturn 0;\n\t}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e4f5bf0a491d46e1bc706a8c030eac28", "src_uid": "30e95770f12c631ce498a2b20c2931c7", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n\n    scanf(\"%d\", &n);\n\n    if(n==1)\n        printf(\"%d\\n\", n);\n    else\n    {\n        n = n/2;\n        printf(\"%d\\n\", n);\n    }\n\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "32030e13503f37dcc9bbca9b627d8601", "src_uid": "30e95770f12c631ce498a2b20c2931c7", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<math.h>\n#include<limits.h>\nchar arr[20][20];\nint cmp[20];\nchar numbs[50];\nint flag;\nint cnt;\nint solve(){\nint len=strlen(numbs); int i; int k=0;\nfor(i=0;i<len-1;i++){\nint f = arr[numbs[i]-'0'][0]-'0';\nint f1= arr[numbs[i]-'0'][1]-'0';\nint l = arr[numbs[i+1]-'0'][0]-'0';\nint l1 = arr[numbs[i+1]-'0'][1]-'0';\n\ncmp[k++]=l-f;;\ncmp[k++]=l1-f1;\n}\nint x,m;\nfor(i=0;i<4;i++){\nfor(x=0;x<3;x++){\nflag=1;\nif(i==3 && x==0)\ncontinue;\nif(i==3 && x==2)\ncontinue;\nint t=i;\nint t1=x;\nfor(m=0;m<k;m+=2){\nt = t+cmp[m];\nt1 = t1+cmp[m+1];\nif(t>3 || t<0 || t1>2 || t1<0 || (t==3 && t1==0) || (t==3 && t1==2))\nflag=0;;\n}\nif(flag){\ncnt++;\nif(cnt==2){\nprintf(\"NO\");\nreturn;}}\n}\n}\n}\nint main(){\nint a,b,c,d,e,f,g,h;\nstrcpy(arr[0],\"31\");\nstrcpy(arr[1],\"00\");\nstrcpy(arr[2],\"01\");\nstrcpy(arr[3],\"02\");\nstrcpy(arr[4],\"10\");\nstrcpy(arr[5],\"11\");\nstrcpy(arr[6],\"12\");\nstrcpy(arr[7],\"20\");\nstrcpy(arr[8],\"21\");\nstrcpy(arr[9],\"22\");\nscanf(\"%d\",&f);\ngetchar();\ngets(numbs);\nsolve();\nif(cnt!=2){\n        printf(\"YES\");\n}\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "012ba5dbcf1af3b280b8efcb7952f3e7", "src_uid": "d0f5174bb0bcca5a486db327b492bf33", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void) {\n\n    int n,i,test=0,t=1;\n    char x;\n\n    if(test){ scanf(\"%d\",&t);}\n    while(t--)\n    {\n        int flag1=0,flag2=0,flag3=0,flag4=0;\n        scanf(\"%d\",&n);\n        for(i=0;i<n;i++){\n            scanf(\" %c\",&x);\n            if(x=='1'||x=='2'||x=='3')\n                flag1=1;\n            if(x=='9'||x=='6'||x=='3'||x=='0')\n                flag2=1;\n            if(x=='7'||x=='0'||x=='9')\n                flag3=1;\n            if(x=='1'||x=='4'||x=='7'||x=='0')\n                flag4=1;\n        }\n        if(flag1&&flag2&&flag3&&flag4)\n            printf(\"YES\");\n        else\n            printf(\"NO\");\n    }\n\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "37de1713e8327ad85668a61b5c00703a", "src_uid": "d0f5174bb0bcca5a486db327b492bf33", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main() {\n\tint test;\n\tchar inp[11];\n\tint inp2[11];\n\tscanf (\"%d\\n\",&test);\n\tgets(inp);\n\tmemset (inp2, 0, sizeof(inp2));\n\tint x, check=1;\n\tfor (x=0;x<test;x++){\n\t\tint lala = inp[x]-'0';\n\t\tinp2[lala]++;\n\t\t\n\t}\n\t\n\tif (!(inp2[1]>0||inp2[4]>0||inp2[7]>0||inp2[0]>0)) {\n\t\tprintf (\"NO\\n\");\n\t}\n\telse if (!(inp2[3]>0||inp2[6]>0||inp2[9]>0||inp2[0]>0)) {\n\t\tprintf(\"NO\\n\");\n\t}\n\telse if (!(inp2[1] > 0 || inp2[2]>0 || inp2[3]>0)) {\n\t\tprintf(\"NO\\n\");\n\t}\n\telse if (!(inp2[7] >0 || inp2[0] >0 ||inp2[9]>0)) {\n\t\tprintf(\"NO\\n\");\n\t}\n\telse {\n\t\tprintf(\"YES\\n\");\n\t}\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ccca0b4317cdf68f77239e7c80686518", "src_uid": "d0f5174bb0bcca5a486db327b492bf33", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<iostream>\n#include<map>\n#include<string.h>\n#pragma warning(disable:4996)\nusing namespace std;\nint main()\n{\n\tint a, b, c, i, j, k;\n\tchar s[10];\n\tint m[6][6];\n\tint flag;\n\tmap<char, int>mp;\n\twhile (scanf(\"%d\", &a) != EOF)\n\t{\n\t\tmemset(m, 0, sizeof(m));\n\t\tscanf(\"%s\", s);\n\t\tint flag1 = 0;\n\t\tb = strlen(s);\n\t\tflag = 0;\n\t\tfor (i = 0; i < b; i++)\n\t\t{\n\t\t\tif (s[i] == '0')\n\t\t\t\tm[4][2] = 1;\n\t\t\tif (s[i] == '1')\n\t\t\t\tm[1][1] = 1;\n\t\t\tif (s[i] == '2')\n\t\t\t\tm[1][2] = 1;\n\t\t\tif (s[i] == '3')\n\t\t\t\tm[1][3] = 1;\n\t\t\tif (s[i] == '4')\n\t\t\t\tm[2][1] = 1;\n\t\t\tif (s[i] == '5')\n\t\t\t\tm[2][2] = 1;\n\t\t\tif (s[i] == '6')\n\t\t\t\tm[2][3] = 1;\n\t\t\tif (s[i] == '7')\n\t\t\t\tm[3][1] = 1;\n\t\t\tif (s[i] == '8')\n\t\t\t\tm[3][2] = 1;\n\t\t\tif (s[i] == '9')\n\t\t\t\tm[3][3] = 1;\n\t\t}\n\t\tfor (i = 0; i < 6; i++)\n\t\t{\n\t\t\tfor (j = 0; j < 6; j++)\n\t\t\t{\n\t\t\t\tif (m[i][j] == 1)\n\t\t\t\t{\t\n\t\t\t\t\tif ((i == 3 && j == 3) || (i == 2 && j == 3) || (i == 1 && j == 3))\n\t\t\t\t\t{\n\t\t\t\t\t\tflag1 = 1;\n\t\t\t\t\t\tflag++; break;\n\t\t\t\t\t\t\n\t\t\t\t\t}\n\t\t\t\t\t\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (flag1)break;\n\t\t}\n\t\tflag1 = 0;\n\t\tfor (i = 0; i < 6; i++)\n\t\t{\n\t\t\tfor (j = 0; j < 6; j++)\n\t\t\t{\n\t\t\t\tif (m[i][j] == 1)\n\t\t\t\t{\n\t\t\t\t\tif ((i == 1&& j == 1) || (i == 2 && j == 1) || (i == 3 && j == 1))\n\t\t\t\t\t{\n\t\t\t\t\t\tflag1 = 1;\n\t\t\t\t\t\tflag++; break;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}if (flag1)break;\n\t\t}\n\t\tflag1 = 0;\n\t\tfor (i = 0; i < 6; i++)\n\t\t{\n\t\t\tfor (j = 0; j < 6; j++)\n\t\t\t{\n\t\t\t\tif (m[i][j] == 1)\n\t\t\t\t{\n\t\t\t\t\tif ((i == 3 && j == 1) || (i == 4 && j == 2)||(i == 3 && j == 3))\n\t\t\t\t\t{\n\t\t\t\t\t\tflag1 = 1;\n\t\t\t\t\t\tflag++; break;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}if (flag1)break;\n\t\t\t\n\t\t}\n\t\tflag1 = 0;\n\t\tfor (i = 0; i < 6; i++)\n\t\t{\n\t\t\tfor (j = 0; j < 6; j++)\n\t\t\t{\n\t\t\t\tif (m[i][j] == 1)\n\t\t\t\t{\n\t\t\t\t\tif ((i == 1 && j == 1) || (i == 1 && j == 2) || (i == 1 && j == 3))\n\t\t\t\t\t{\n\t\t\t\t\t\tflag1 = 1;\n\t\t\t\t\t\tflag++; break;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}if (flag1)break;\n\t\t}\n\t\tif (flag == 4)\n\t\t\tprintf(\"YES\\n\");\n\t\telse printf(\"NO\\n\");\n\t\t\n\t}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0744af3dba83e3ac47da880d4b265060", "src_uid": "d0f5174bb0bcca5a486db327b492bf33", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n\tint test;\n\tchar inp[11];\n\tint check=0;\n\tscanf (\"%d\\n\", &test );\n\tgets(inp);\n\tfor (int x=0;x<test;x++){\n\t\tif (inp[x]=='3' || inp[x]=='7')check++;\n\t\tif (inp[x]=='9' || inp[x]=='1')check++;\n\t\tif (inp[x]=='2' || inp[x]=='0')check++;\n\t}\n\tif (check>=2)printf(\"YES\\n\");\n\telse printf(\"NO\\n\");\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9538e049651469d83a4746358cf5a650", "src_uid": "d0f5174bb0bcca5a486db327b492bf33", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\ntypedef unsigned long long int u_int;\n\nint main(void){\n  u_int a,b;\n  u_int i,j;\n  u_int an;\n  u_int counta=0,countb=0;\n  scanf(\"%llu %llu\",&a,&b);\n  if(a>b){\n    an=a%b;\n    do{\n      counta+=an;\n      countb+=a-an;\n      an=(an+a)%b;\n    }while(an!=0);\n    counta+=b;\n    countb+=a-b;\n    if(counta>countb) puts(\"Dasha\");\n    else if(counta==countb) puts(\"Equal\");\n    else puts(\"Masha\");\n  }else{\n    b+=a;\n    a=b-a;\n    b-=a;\n   an=a%b;\n    do{\n      counta+=an;\n      countb+=a-an;\n      an=(an+a)%b;\n    }while(an!=0);\n    counta+=b;\n    countb+=a-b;\n    if(counta>countb) puts(\"Masha\");\n    else if(counta==countb) puts(\"Equal\");\n    else puts(\"Dasha\");\n  }\n  return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "633542eb30febdabc5c0ef971033eb04", "src_uid": "06eb66df61ff5d61d678bbb3bb6553cc", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint lcm(int a,int b)\n{\n\tint i=1;\n\twhile(!(i%a==0 && i%b==0))\n\t\ti++;\n\treturn i;\n}\nint main()\n{\n\tint a,b,max,min;\n\tscanf(\"%d%d\",&a,&b);\n\tmax=(a>b)?a:b;\n\tmin=(a>b)?b:a;\n\tint l=lcm(a,b);\n\tif(fabs(l/min-l/max)>1)\n\t{\n\t\tif(a<b)\n\t\t\tputs(\"Dasha\");\n\t\telse\n\t\t\tputs(\"Masha\");\n\t}\n\telse\n\t\tputs(\"Equal\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "921b515d203ca397309503e0b28b3cfe", "src_uid": "06eb66df61ff5d61d678bbb3bb6553cc", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\n#define ull long long \n\n\nvoid swap(ull int* a,ull int* b)\n{\n\t*a=*a+*b;\n\t*b=*a-*b;\n\t*a=*a-*b;\n}\n\null int find_lcm(ull int big,ull int small)\n{\n\tull int i=0;\n\tif(big<small)\n\t\tswap(&big,&small);\n\tfor(i=big;!(i%big==0 && i%small==0);i++);\n\treturn i;\n}\n\nint main()\n{\n\tull int a,b,M=0,D=0,lcm,left=0,right=0,i=1,j=1;\n\tscanf(\"%l64d %l64d\",&a,&b);\n\t\n\tlcm=find_lcm(a,b);\n\n\twhile(right<lcm)\n\t{\n\t\tleft=right;\n\t\tif(a*i<b*j)\n\t\t{\n\t\t\tright=a*i;\n\t\t\ti++;\n\t\t\tD++;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tright=b*j;\n\t\t\tj++;\n\t\t\tM++;\n\t\t}\n\n\t}\n\tif(a<b)\n\t\tM++;\n\telse\n\t\tD++;\n\n\tif(M<D)\n\t\tprintf(\"Dasha\\n\");\n\telse if(D<M)\n\t\tprintf(\"Masha\\n\");\n\telse\n\t\tprintf(\"Equal\\n\");\n\treturn 0;\n\n\t\t\n}\n\n\t\t\n\n\n\n\n\t\n\n\t\n\n\t\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4c5e53c799d8d74a7bb64afe556c7ad0", "src_uid": "06eb66df61ff5d61d678bbb3bb6553cc", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int a, b;\n\tscanf(\"%d %d\", &a, &b);\n\tint d, m;\n\td = m = 0;\n\tint nd, nm;\n\tnd = a;\n\tnm = b;\n\twhile( nd != nm)\n\t{\n\t    if(nd<nm)\n\t    {\n\t        d++;\n\t        nd += a;\n\t    }\n\t    else\n\t    {\n\t        m++;\n\t        nm += b;\n\t    }\n\t}\n\tif(nd == nm)\n\t{\n\t    if(a<b)\n\t        m++;\n\t    else\n\t        d++;\n\t}\n\tif(d==m)\n\t    printf(\"Equal\\n\");\n\telse if(d>m)\n\t    printf(\"Dasha\\n\");\n\telse\n\t    printf(\"Masha\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d6ee0fd46cc29d8e891148efa613fabd", "src_uid": "06eb66df61ff5d61d678bbb3bb6553cc", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint a[13];\n\tfor(i=2;i<11;i++)\n\t\ta[i]=4;\n\tfor(i=)\n\tscanf(\"\")\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d39d883293faeea0c664e4602874a79b", "src_uid": "06eb66df61ff5d61d678bbb3bb6553cc", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n    unsigned long long int n,a,b,a1,b1,area,requ,q,flag=0,x,y;\n    scanf(\"%lld %lld %lld\",&n,&a,&b);\n    q=a;\n    area=a*b;\n    requ=(6*n);\n    if(area>=requ)\n    {\n        printf(\"%lld\\n\",area);\n        printf(\"%lld %lld\",a,b);\n\n    }\n    else\n    {\n        if((requ%a)==0)\n        {\n            a1=a;\n            b1=(requ/a);\n            x=b1;\n            y=a1;\n       }\n       else if(requ%b==0)\n       {\n           b1=b;\n           a1=requ/b;\n           x=b1;y=a1;\n       }\n        else\n        {\n\n\n            while(1)\n            {\n                a++;\n                if((requ%a)==0)\n                {\n                    a1=a;\n                    b1=requ/a;\n                    if(b1<b)\n                    {\n                        a1=q;\n                        b1=b;\n                        flag=1;\n                        break;\n                    }\n                    x=b1;\n                    y=a1;\n                    break;\n\n\n                }\n            }\n            if(flag==1)\n            {\n                if(a1==b1)\n                {\n                    y=a1;\n                    x=b1;\n\n                }\n                if(a1>b1)\n                {\n                    y=a1;\n                    x=b1;\n                }\n                if(a1<b1)\n                {\n                    y=b1;\n                    x=a1;\n                }\n\n\n\n                while(1)\n                {\n                    y++;\n                    if((y*x)>=requ)\n                        break;\n                }\n\n\n\n\n\n            }\n\n\n\n\n\n        }\n\n\n\n\n\n\n         printf(\"%lld\\n\",(x*y));\n        printf(\"%lld %lld\",y,x);\n\n\n\n        }\n        return 0;\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0b4f8e6b5e6bd9141a977dbdf359c1f4", "src_uid": "6a2a584d36008151d18e5080aea5029c", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n    unsigned long long int n,a,b,a1,b1,area,requ,flag=0,x,y;\n    scanf(\"%lld %lld %lld\",&n,&a,&b);\n    x=a;\n    y=b;\n    area=a*b;\n\n    requ=(6*n);\n    if(area>=requ)\n    {\n        printf(\"%lld\\n\",area);\n        printf(\"%lld %lld\",a,b);\n\n    }\n    else\n    {\n        if((requ%x)==0)\n        {\n            a1=x;\n            b1=(requ/x);\n        }\n       else if((requ%y)==0)\n       {\n           b1=y;\n           a1=requ/y;\n        }\n        else\n        {\n\n\n            while(1)\n            {\n                x++;\n\n                if((requ/x)<y)\n                    {flag=1;\n                    x=a;\n                    break;}\n                if((requ%x)==0)\n                {\n                    a1=x;\n                    b1=requ/x;\n                    break;\n                }\n            }\n\n            if(flag==1)\n            {\n\n                requ++;\n\n                while(1)\n                {\n\n                    x++;\n                    if((requ/x)<y)\n                    {\n                        requ++;\n                        x=a;\n                        continue;\n                    }\n\n\n                    if(requ%x==0)\n                {\n                    a1=x;\n                    b1=(requ/x);\n                    break;\n\n\n                }\n\n\n            }\n\n        }\n\n\n\n\n\n        }\n\n\n\n\n\n\n\n         printf(\"%lld\\n\",(a1*b1));\n        printf(\"%lld %lld\",a1,b1);\n\n\n\n        }\n        return 0;\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "af111cd748e0b8b43f11e5ab48e20b51", "src_uid": "6a2a584d36008151d18e5080aea5029c", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n//||\n//\\n\nint main()\n{long long int a,b,c,d,e,f,p,q,r,s,sum=0,sum1=0,min=1000000001*1000000001;\n scanf(\"%lld %lld %lld\",&a,&b,&c);\n\n if(b*c>=(a*6))\n {\n              printf(\"%lld\\n\",b*c);\n              printf(\"%lld %lld\",b,c);\n              return 0;\n }\n\n\n p=b;\n q=c;\nif(p%6!=0)\n  p=p+6-(p%6);\n\n while(1)\n {    if(p*q>=(a*6))\n                          break;\n              q=q+1;\n\n }\n if(p*q<=min)\n {\n              min=p*q;\n              e=p;\n              f=q;\n }\n\n\n p=b;\n q=c;\n if(q%6!=0)\n   q=q+6-(q%6);\n while(1)\n {    if(p*q>=(a*6))\n                          break;\n              p=p+1;\n\n }\n if(p*q<=min)\n {\n              min=p*q;\n              e=p;\n              f=q;\n }\n\n\n p=b;\n q=c;\n if(p%2!=0)\n   p=p+2-(p%2);\nif(q%3!=0)\n  q=q+3-(q%3);\n while(1)\n {\n              if(p*q>=(a*6))\n                          break;\n              q=q+3;\n }\n if(p*q<=min)\n {\n              min=p*q;\n              e=p;\n              f=q;\n }\n p=b;\n q=c;\n if(p%3!=0)\n  p=p+3-(p%3);\n if(q%2!=0)\n  q=q+2-(q%2);\n while(1)\n {\n              if(p*q>=(a*6))\n                          break;\n              q=q+2;\n }\n if(p*q<=min)\n {\n              min=p*q;\n              e=p;\n              f=q;\n }\n p=b;\n q=c;\n if(p%3!=0)\n  p=p+3-(p%3);\nif(q%2!=0)\n q=q+2-(q%2);\n while(1)\n {\n              if(p*q>=(a*6))\n                          break;\n              p=p+3;\n }\n if(p*q<=min)\n {\n              min=p*q;\n              e=p;\n              f=q;\n }\n p=b;\n q=c;\n if(p%2!=0)\n  p=p+2-(p%2);\nif(q%3!=0)\n  q=q+3-(q%3);\n while(1)\n {\n              if(p*q>=(a*6))\n                          break;\n              p=p+2;\n }\n if(p*q<=min)\n {\n              min=p*q;\n              e=p;\n              f=q;\n }\n              printf(\"%lld\\n\",min);\n              printf(\"%lld %lld\",e,f);\n              return 0;}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9bf60bfd56837a230aa4a32c175412e5", "src_uid": "6a2a584d36008151d18e5080aea5029c", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <conio.h>\n\n\nint main()\n{\n    long long n, a, b, s, tmps, tmpa, tmpb, tmp;\n    scanf(\"%I64d %I64d %I64d\", &n, &a, &b);\n    s = 1000000000000;\n    if (a > b)\n    {\n        tmp = a; a = b; b = tmp;\n    }\n    tmpb = b; tmpa = a;\n    if (a*b < 6 * n)\n    {\n        while (tmpa <= sqrt(float(6.0*n))+1)\n        {\n            tmpb = ceil(6.0*n / tmpa);\n            tmps = tmpa*tmpb;\n            if (tmps < s&& tmps >=6*n)\n            {\n                s = tmps;\n                a = tmpa;\n                b = tmpb;\n            }\n            tmpa++;\n        }\n    }\n    else s = a*b;\n    printf(\"%I64d\\n%I64d %I64d\", s, a, b);\n \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "427fad2a47e1f6b638ef1e199f11caa2", "src_uid": "6a2a584d36008151d18e5080aea5029c", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint main(){\n        long long n,a,b,temp;\n        scanf(\"%I64d%I64d%I64d\",&n,&a,&b);\n        long long area=6*n,raiz,area1=1000000000000000000;\n        if(area<=a*b) printf(\"%I64d\\n%I64d %I64d\\n\",a*b,a,b);\n        else{\n        int ind=0;\n        if(a>b) temp=a, a=b, b=temp, ind=1;\n        raiz=(long long)sqrt(6*n);\n        long long i,j,ans1,ans2;\n        for(i=1;i<=raiz+1;i++){\n                if(i>=a){\n                j=(6*n+i-1)/i;\n                j=max(j,b);\n                        if(i*j>=6*n && area1 > i*j ){\n                        area1=i*j;\n                        ans1=i;\n                        ans2=j;\n                        }\n                }\n        }\n        if(ind)\n        printf(\"%I64d\\n%I64d %I64d\\n\",area1,ans2,ans1);\n        else\n        printf(\"%I64d\\n%I64d %I64d\\n\",area1,ans1,ans2);\n        }\n        return(0);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0a307cac6fa9427ca90787d04152fd35", "src_uid": "6a2a584d36008151d18e5080aea5029c", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\nint main() {\r\n\tint t; scanf(\"%d\", &t);\r\n\tint mod = 1e9 + 7;\r\n\twhile (t--) {\r\n\t\tint n, k; scanf(\"%d%d\", &n, &k);\r\n\t\tlong long ans = 1;\r\n\t\tfor (int i = 0; i < k; i++) {\r\n\t\t\tans *= n;\r\n\t\t\tans %= mod;\r\n\t\t}\r\n\t\tprintf(\"%lld\\n\", ans);\r\n\t}\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c1e9a1d6d744a72038944dc6361d09b0", "src_uid": "2e7a9f3a97938e4a7e036520d812b97a", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <stdlib.h>\r\n\r\n\r\nconst unsigned long long int mod=1000000007;\r\n\r\nvoid solve() {\r\n\r\nint n,k;\r\nscanf(\"%d %d\",&n,&k);\r\n\r\n\r\nunsigned long long int r=1;\r\n\r\nfor(int i=0; i<k; i++) {\r\n    r=(r*n)%mod;\r\n}\r\nprintf(\"%lld\\n\",r);\r\n\r\n\r\n\r\n\r\n}\r\n\r\nint main()\r\n{\r\n    int t;\r\n    scanf(\"%d\",&t);\r\n\r\n    for(int i=0; i<t; i++) {\r\n        solve();\r\n    }\r\n    return 0;\r\n}\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4dc734ae56d7f3c8b7f6e43fbf9cb11c", "src_uid": "2e7a9f3a97938e4a7e036520d812b97a", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#define forin(i, n) for (i = 0; i < n; i++)\r\n#define lli long long int\r\n#define printSp(i, a, n) forin(i, n) printf('%d ', a[i]);\r\n#define printLn(i, a, n) forin(i, n) printf('%d\\n', a[i]);\r\n#define fis(n) fast_int_scan(n)\r\n#define fls(n) fast_long_scan(n)\r\n#define flli(n) fast_lli_scan(n)\r\n#define scanIA(i, a, n) forin(i, n) fis(a + i);\r\n#define scanLA(i, a, n) forin(i, n) fls(a + i);\r\n#define scanLLIA(i, a, n) forin(i, n) flli(a + i);\r\n\r\nvoid fast_int_scan(int *number)\r\n{\r\n    //variable to indicate sign of input number\r\n    int negative = 0;\r\n    register int c;\r\n\r\n    *number = 0;\r\n\r\n    // extract current character from buffer\r\n    c = getchar();\r\n    if (c == '-')\r\n    {\r\n        // number is negative\r\n        negative = 1;\r\n\r\n        // extract the next character from the buffer\r\n        c = getchar();\r\n    }\r\n\r\n    // Keep on extracting characters if they are integers\r\n    // i.e ASCII Value lies from '0'(48) to '9' (57)\r\n    for (; (c > 47 && c < 58); c = getchar())\r\n        (*number) = (*number) * 10 + c - 48;\r\n\r\n    // if scanned input has a negative sign, negate the value\r\n    if (negative)\r\n        (*number) *= -1;\r\n}\r\n\r\nvoid fast_lli_scan(lli *number)\r\n{\r\n    //variable to indicate sign of input number\r\n    int negative = 0;\r\n    register int c;\r\n\r\n    *number = 0;\r\n\r\n    // extract current character from buffer\r\n    c = getchar();\r\n    if (c == '-')\r\n    {\r\n        // number is negative\r\n        negative = 1;\r\n\r\n        // extract the next character from the buffer\r\n        c = getchar();\r\n    }\r\n\r\n    // Keep on extracting characters if they are integers\r\n    // i.e ASCII Value lies from '0'(48) to '9' (57)\r\n    for (; (c > 47 && c < 58); c = getchar())\r\n        (*number) = (*number) * 10 + c - 48;\r\n\r\n    // if scanned input has a negative sign, negate the value\r\n    if (negative)\r\n        (*number) *= -1;\r\n}\r\n\r\n \r\nint main(void)\r\n{\r\n\tint T;\r\n\tfast_int_scan(&T);\r\n\twhile (T--)\r\n\t{\r\n\t\tlli n, k, i, sum = 1;\r\n\t\tfast_lli_scan(&n);\r\n        fast_lli_scan(&k);\r\n\t\tfor(i=1; i<=k; i++)\r\n\t\t{\r\n\t\t\tsum *= n;\r\n\t\t\tsum %= 1000000007;\r\n\t\t}\r\n\r\n\t\tprintf(\"%lld\\n\", sum);\r\n\t}\r\n\treturn 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "39a5b44408405051778b70da6fa252d6", "src_uid": "2e7a9f3a97938e4a7e036520d812b97a", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\nint main(){\r\n int t;\r\n scanf(\"%d\",&t);\r\n \r\n while(t--){\r\n  int n,k;\r\n  int max=1e10+7;\r\n  scanf(\"%d%d\",&n,&k);\r\n  long long int ans=1;\r\n  for(int i=1;i<=n;i++){\r\n   ans=(ans*i)%max;\r\n  }\r\n  printf(\"%lld\",ans)\r\n }\r\n return 0;\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c166bc941bae0d0a972ab3382628a65b", "src_uid": "2e7a9f3a97938e4a7e036520d812b97a", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\r\nusing namespace std;\r\nint main()\r\n{\r\n    int n,k,i,T;\r\n    long long ans=1LL;\r\n    long long mod=(1E9)+7;\r\n    scanf(\"%d\",&T);\r\n    while(T--)\r\n    {\r\n        ans=1LL;\r\n    scanf(\"%d%d\",&n,&k);\r\n    for(i=0;i<k;i++)\r\n    {\r\n        ans=(ans*n)%mod;\r\n    }\r\n    printf(\"%lld\\n\",ans);\r\n     }\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3af5012962c7a20bc1b813d884d1721c", "src_uid": "2e7a9f3a97938e4a7e036520d812b97a", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n__int64 a[18258], res[18258];\n\nint main()\n{\n    a[0] = 1;\n    res[0] = 1;\n    for(int i = 1; i < 18258; ++ i)\n    {\n        a[i] = 2 * a[i - 1];\n        res[i] = a[i] * 6 + res[i - 1];\n    }\n    int n;\n    while(~scanf(\"%d\", &n))\n        printf(\"%I64d\\n\", res[n - 1]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4f344c29362626afb025195ba44c835a", "src_uid": "879ac20ae5d3e7f1002afe907d9887df", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n#include <cstdlib>\n#include <cstring>\n#include <vector>\n#include <string>\n\nusing namespace std;\n\nint main(){\n\tlong int n;\n\tcin >> n ;\n\tcout << (12 * n * (n-1) + 2)/2 << endl;\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6c24a3647e8e546c1a7677d406cc8e65", "src_uid": "879ac20ae5d3e7f1002afe907d9887df", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint iIn1,iIn2,iIn3,iIn4;\nint main()\n{\n    cin>>iIn1>>iIn2>>iIn3>>iIn4;\n    cout<<(((iIn1^iIn2)&(iIn3|iIn4))^((iIn2&iIn3)|(iIn1^iIn4)));\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c68390f3921d2be7d504e2fa8abf0a22", "src_uid": "879ac20ae5d3e7f1002afe907d9887df", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "main()\n{\nint n;\nscanf(\"%d\",&n);\nprintf(\"%d\",6*n*(n\u22121)+1);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "68a1d9eff578380c14f452794edf8efc", "src_uid": "879ac20ae5d3e7f1002afe907d9887df", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(void){\n    int iIn1,iIn2,iIn3,iIn4;\n    scanf(\"%d %d %d %d\",&iIn1,&iIn2,&iIn3,&iIn4);\n    printf(\"%d\", ((iIn\n    1^iIn2) & (iIn3 | iIn4\n    )) ^ ((iIn2&iIn3) | (iIn1^iIn4)));\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "636ca6d1c96bf8616a1461e6bde75bfb", "src_uid": "879ac20ae5d3e7f1002afe907d9887df", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define INF (1LL << 60)\n\nstruct point\n{\n    int x;\n    int y;\n};\n\nstruct point p[4][2];\nint q[4];\ndouble g[4];\n\nint check(struct point p1, struct point p2)\n{\n    if (p1.x == p2.x && p1.y == p2.y)\n    {\n        return 1;\n    }\n    return 0;\n}\n\nvoid solve()\n{\n    int i, j, k, t, f;\n    for (i = 0; i < 4; i ++)\n    {\n        if (check(p[i][0], p[i][1]))\n        {\n            printf(\"NO\\n\");\n            return;\n        }\n        k = t = 0;\n        for (j = 0; j < 4; j ++)\n        {\n            f = 0;\n            if (j == i)\n            {\n                continue;\n            }\n            if (check(p[i][0], p[j][0]))\n            {\n                k ++;\n                f = 1;\n            }\n            if (check(p[i][0], p[j][1]))\n            {\n                k ++;\n                f = 1;\n            }\n            if (k > 1)\n            {\n                printf(\"NO\\n\");\n                return;\n            }\n            if (check(p[i][1], p[j][0]))\n            {\n                t ++;\n                f = 1;\n            }\n            if (check(p[i][1], p[j][1]))\n            {\n                t ++;\n                f = 1;\n            }\n            if (t > 1)\n            {\n                printf(\"NO\\n\");\n                return;\n            }\n            if (f == 0)\n            {\n                q[i] = j;\n            }\n        }\n        if (k != 1 || t != 1)\n        {\n            printf(\"NO\\n\");\n            return;\n        }\n        if (p[i][0].x == p[i][1].x)\n        {\n            g[i] = INF;\n        }\n        else\n        {\n            g[i] = (double)(p[i][1].y - p[i][0].y) / (p[i][1].x - p[i][0].x);\n        }\n    }\n    for (i = 1; i < 4; i ++)\n    {\n        if (g[i] != g[0])\n        {\n            break;\n        }\n    }\n    if (i == 4)\n    {\n        printf(\"NO\\n\");\n        return;\n    }\n    for (i = 0; i < 4; i ++)\n    {\n        if (g[i] != g[q[i]])\n        {\n            printf(\"NO\\n\");\n            return;\n        }\n    }\n    printf(\"YES\\n\");\n}\n\nint main()\n{\n    int i;\n    for (i = 0; i < 4; i ++)\n    {\n        scanf(\"%d%d%d%d\", &p[i][0].x, &p[i][0].y, &p[i][1].x, &p[i][1].y);\n    }\n    solve();\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1f13ea2a6075f6fbb46f3efcb14b3526", "src_uid": "ad105c08f63e9761fe90f69630628027", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define INF (1LL << 60)\n#define EPS (1e-7)\n\nstruct point\n{\n    int x;\n    int y;\n};\n\nstruct point p[4][2];\nint q[4];\ndouble g[4];\n\nint check(struct point p1, struct point p2)\n{\n    if (p1.x == p2.x && p1.y == p2.y)\n    {\n        return 1;\n    }\n    return 0;\n}\n\nint judge(double value)\n{\n    if (value > -1.0)\n    {\n        if (value + 1.0 < EPS)\n        {\n            return 1;\n        }\n        return 0;\n    }\n    if (-1.0 - value < EPS)\n    {\n        return 1;\n    }\n    return 0;\n}\n\nvoid solve()\n{\n    int i, j, k, t, f;\n    for (i = 0; i < 4; i ++)\n    {\n        if (check(p[i][0], p[i][1]))\n        {\n            printf(\"NO\\n\");\n            return;\n        }\n        k = t = 0;\n        for (j = 0; j < 4; j ++)\n        {\n            f = 0;\n            if (j == i)\n            {\n                continue;\n            }\n            if (check(p[i][0], p[j][0]))\n            {\n                k ++;\n                f = 1;\n            }\n            if (check(p[i][0], p[j][1]))\n            {\n                k ++;\n                f = 1;\n            }\n            if (k > 1)\n            {\n                printf(\"NO\\n\");\n                return;\n            }\n            if (check(p[i][1], p[j][0]))\n            {\n                t ++;\n                f = 1;\n            }\n            if (check(p[i][1], p[j][1]))\n            {\n                t ++;\n                f = 1;\n            }\n            if (t > 1)\n            {\n                printf(\"NO\\n\");\n                return;\n            }\n            if (f == 0)\n            {\n                q[i] = j;\n            }\n        }\n        if (k != 1 || t != 1)\n        {\n            printf(\"NO\\n\");\n            return;\n        }\n        if (p[i][0].x == p[i][1].x)\n        {\n            g[i] = INF;\n        }\n        else\n        {\n            g[i] = (double)(p[i][1].y - p[i][0].y) / (p[i][1].x - p[i][0].x);\n        }\n    }\n    for (i = 1; i < 4; i ++)\n    {\n        if (g[i] != g[0])\n        {\n            break;\n        }\n    }\n    if (i == 4)\n    {\n        printf(\"NO\\n\");\n        return;\n    }\n    for (i = 0; i < 4; i ++)\n    {\n        if (g[i] != g[q[i]])\n        {\n            printf(\"NO\\n\");\n            return;\n        }\n        for (j = i + 1; j < 4; j ++)\n        {\n            if (j != q[i])\n            {\n                if (g[i] == INF)\n                {\n                    if (g[j] != 0)\n                    {\n                        printf(\"NO\\n\");\n                        return;\n                    }\n                }\n                else if (g[i] == 0)\n                {\n                    if (g[j] != INF)\n                    {\n                        printf(\"NO\\n\");\n                        return;\n                    }\n                }\n                else\n                {\n                    if (g[j] == INF || judge(g[i] * g[j]) == 0)\n                    {\n                        printf(\"NO\\n\");\n                        return;\n                    }\n                }\n            }\n        }\n    }\n    printf(\"YES\\n\");\n}\n\nint main()\n{\n    int i;\n    for (i = 0; i < 4; i ++)\n    {\n        scanf(\"%d%d%d%d\", &p[i][0].x, &p[i][0].y, &p[i][1].x, &p[i][1].y);\n    }\n    solve();\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d7f09097d3fe47e54efac0cb63115e94", "src_uid": "ad105c08f63e9761fe90f69630628027", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint x[8],y[8];\n\nint main() {\n\tint i,j;\n\tfor (i=0;i<8;i++) scanf(\"%d %d\\n\",&x[i],&y[i]);\n\tfor (i=0;i<8;i++) {\n\t\tif (i&1)\n\t\t\tif ((x[i]==x[i-1])==(y[i]==y[i-1]))\n\t\t\t\tbreak;\n\t\tint c=0;\n\t\tfor (j=0;j<8;j++) if (x[j]==x[i]&&y[j]==y[i]) c++;\n\t\tif (c!=2) break;\n\t\tc=0;\n\t\tfor (j=0;j<8;j++) if (x[j]==x[i]) c++;\n\t\tif (c!=4) break;\n\t}\n\tprintf(\"%s\\n\",i<8?\"NO\":\"YES\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b0e4f4f8c0825b25f8daef8f3a3de4cd", "src_uid": "ad105c08f63e9761fe90f69630628027", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\nint main()\n{\n    int a,i,j,k;\n    long long temp[4][4];\n    long long tmp;\n    long long verticalLines[4][4];\n    long long horizontalLines[4][4];\n    long long test1,test2;\n    int flag=0;\n    int verticalfound=0;\n    int horizontalfound=0;\n\n    for(i=0; i<4; i++)\n    {\n        for(j=0; j<4; j++)\n        {\n            scanf(\"%lld\",&temp[i][j]);\n        }\n    }\n\n    //CHECKING VERTICAL AND HORIZONTAL LINES\n    j=0;\n    k=0;\n    for(i=0; i<4 && !flag; i++)\n    {\n        if(temp[i][0]==temp[i][2] && temp[i][1]!=temp[i][3]) //VERTICAL LINE\n        {\n            for(a=0;a<4;a++)\n            {\n                verticalLines[j][a]=temp[i][a];\n            }\n\n            if(verticalLines[j][1]>verticalLines[j][3])\n            {\n                tmp=verticalLines[j][1];\n                verticalLines[j][1]=verticalLines[j][3];\n                verticalLines[j][3]=tmp;\n            }\n\n            j++;\n\n            if(j==1)\n            {\n                if(verticalLines[0][0]==verticalLines[1][0])\n                {\n                    flag=1;\n                }\n            }\n            \n            if(j>2)\n            {\n                flag=1;\n            }\n\n        }\n        else if(temp[i][1]==temp[i][3] && temp[i][0]!=temp[i][2]) //HORIZONTAL LINE\n        {\n            for(a=0;a<4;a++)\n            {\n                horizontalLines[k][a]=temp[i][a];\n            }\n\n            if(horizontalLines[k][0]>horizontalLines[k][2])\n            {\n                tmp=horizontalLines[k][0];\n                horizontalLines[k][0]=horizontalLines[k][2];\n                horizontalLines[k][2]=tmp;\n            }\n            \n            if(k==1)\n            {\n                if(horizontalLines[0][1]==horizontalLines[1][1])\n                {\n                    flag=1;\n                }\n            }\n\n            k++;\n            if(k>2)\n            {\n                flag=1;\n            }\n        }\n        else\n        {\n            flag=1;\n        }\n    }\n\n\n    if(flag==1)\n    {\n        printf(\"NO\");\n        return 0;\n    }\n\n    //CHECKING INTERSECTION\n    //VERTICAL LINES\n    if( (verticalLines[0][1]==verticalLines[1][1]) && (verticalLines[0][3]==verticalLines[1][3]))\n    {\n       verticalfound=1;\n    }\n\n    //HORIZONRAL LINES\n    if(horizontalLines[0][0]==horizontalLines[1][0] && horizontalLines[0][2]==horizontalLines[1][2])\n    {\n        horizontalfound=1;\n    }\n\n    if ( !(verticalfound==1 && horizontalfound==1) )\n    {\n        printf(\"NO\");\n        return 0;\n    }\n    \n    //POSITIVE AREA\n    if(!((verticalLines[0][0]>0 || verticalLines[1][0]>0) && (horizontalLines[0][1]>0 || horizontalLines[1][1]>0)))\n    {\n        printf(\"NO\");\n\n    }\n    else\n    {\n        printf(\"YES\");\n    }\n\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5bc037e0e4aea12a3e26b2497655fdb8", "src_uid": "ad105c08f63e9761fe90f69630628027", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint lenght(long long x,long long y,long long x1,long long y1){\n   long long k;\n   k=pow((x1-x),2)+pow((y1-y),2);\n   return sqrt(k);\n}\nint main()\n{\n   int i,j,flag=1;\n    long long A[4][4];\n    for(i=0;i<4;i++){\n        for(j=0;j<4;j++){\n           scanf(\"%lli\",&A[i][j]);\n           if(A[i][j]<0)  {\n            flag=0;\n           }\n        }\n    }\n  if(flag==1){\n  for(i=0;i<4&&flag;i++){\n     if((A[i][0]!=A[i][2])&&(A[i][1]!=A[i][3])){\n        flag=0;\n     }\n  }\n  }\n  int tmp[4];\n  int c=0,u;\n   if(flag==1){\n        for(i=0;i<4&&flag;i++){\n                int f=1;\n                for(u=0;u<c&&f;u++){\n                    if(tmp[u]==i){\n                        f=0;\n                    }\n\n                }\n                if(f==1){\n\n                int l=lenght(A[i][0],A[i][1],A[i][2],A[i][3]);\n                int h=1;\n            for(j=i+1;j<4&&h==1;j++){\n                int k=lenght(A[j][0],A[j][1],A[j][2],A[j][3]);\n                if(l==k){\n\n                        if(((A[i][0]==A[j][0])&&(A[i][1]==A[j][1]))||((A[i][2]==A[j][2])&&(A[i][3]==A[j][3]))){\n\n                        }\n                        else{\n                            tmp[c]=j;\n                            c++;\n                            h=0;\n                        }\n            }\n            }\n            if(h==1){\n                flag=0;\n            }\n        }\n        }\n\n   }\n   if(flag==0){\n    printf(\"NO\");\n   }\n   else\n    printf(\"YES\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "faf4fcc54568cf0b5eb8bc6d42c61cce", "src_uid": "ad105c08f63e9761fe90f69630628027", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,h,m,i,j,num,ans=0;\n    scanf(\"%d%d%d\",&n,&h,&m);\n    int l[n],r[n],x[n],a[n];\n    for(i=0; i<m; i++)\n        scanf(\"%d %d %d\",&l[i],&r[i],&x[i]);\n    for(i=1; i<=n; i++)\n    {\n        num=h;\n        for(j=0; j<m; j++)\n        {\n            if(i>=l[j] && i<=r[j])\n                    num=x[j];\n        }\n        ans=ans+(num*num);\n    }\n    printf(\"%d\\n\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b76b77af0be7d09e9a6dab1ed0eb6024", "src_uid": "f22b6dab443f63fb8d2d288b702f20ad", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "//https://codeforces.com/problemset/problem/1162/A\n/*\n\u041e\u043f\u044f\u0442\u044c \u043e\u0433\u0440\u0430\u043d\u0438\u0447\u0435\u043d\u0438\u044f\n\u043e\u0433\u0440\u0430\u043d\u0438\u0447\u0435\u043d\u0438\u0435 \u043f\u043e \u0432\u0440\u0435\u043c\u0435\u043d\u0438 \u043d\u0430 \u0442\u0435\u0441\u0442\n1 \u0441\u0435\u043a\u0443\u043d\u0434\u0430\n\u043e\u0433\u0440\u0430\u043d\u0438\u0447\u0435\u043d\u0438\u0435 \u043f\u043e \u043f\u0430\u043c\u044f\u0442\u0438 \u043d\u0430 \u0442\u0435\u0441\u0442\n256 \u043c\u0435\u0433\u0430\u0431\u0430\u0439\u0442\n\u0432\u0432\u043e\u0434\n\u0441\u0442\u0430\u043d\u0434\u0430\u0440\u0442\u043d\u044b\u0439 \u0432\u0432\u043e\u0434\n\u0432\u044b\u0432\u043e\u0434\n\u0441\u0442\u0430\u043d\u0434\u0430\u0440\u0442\u043d\u044b\u0439 \u0432\u044b\u0432\u043e\u0434\n\n\u0412\u044b \u043f\u043b\u0430\u043d\u0438\u0440\u0443\u0435\u0442\u0435 \u0441\u0442\u0440\u043e\u0438\u0442\u044c \u0434\u043e\u043c\u0430 \u043d\u0430 \u0443\u043b\u0438\u0446\u0435. \u041d\u0430 \u0443\u043b\u0438\u0446\u0435 \u0435\u0441\u0442\u044c n\n\u043c\u0435\u0441\u0442, \u0433\u0434\u0435 \u0432\u044b \u043c\u043e\u0436\u0435\u0442\u0435 \u043f\u043e\u0441\u0442\u0440\u043e\u0438\u0442\u044c \u0434\u043e\u043c\u0430. \u042d\u0442\u0438 \u043c\u0435\u0441\u0442\u0430 \u043f\u0440\u043e\u043d\u0443\u043c\u0435\u0440\u043e\u0432\u0430\u043d\u044b \u0441\u043b\u0435\u0432\u0430 \u043d\u0430\u043f\u0440\u0430\u0432\u043e \u043e\u0442 1 \u0434\u043e n. \u0412 \u043a\u0430\u0436\u0434\u043e\u043c \u043c\u0435\u0441\u0442\u0435 \u0432\u044b \u043c\u043e\u0436\u0435\u0442\u0435 \u043f\u043e\u0441\u0442\u0440\u043e\u0438\u0442\u044c \u0434\u043e\u043c \u0441 \u0446\u0435\u043b\u043e\u0447\u0438\u0441\u043b\u0435\u043d\u043d\u043e\u0439 \u0432\u044b\u0441\u043e\u0442\u043e\u0439 \u043e\u0442 0 \u0434\u043e h\n\n.\n\n\u0412 \u043a\u0430\u0436\u0434\u043e\u043c \u043c\u0435\u0441\u0442\u0435, \u0435\u0441\u043b\u0438 \u0434\u043e\u043c \u0438\u043c\u0435\u0435\u0442 \u0432\u044b\u0441\u043e\u0442\u0443 a\n, \u0432\u044b \u043f\u043e\u043b\u0443\u0447\u0438\u0442\u0435 \u043e\u0442 \u043d\u0435\u0433\u043e \u043f\u0440\u0438\u0431\u044b\u043b\u044c \u0432 \u0440\u0430\u0437\u043c\u0435\u0440\u0435 a2\n\n\u0434\u043e\u043b\u043b\u0430\u0440\u043e\u0432.\n\n\u0413\u043e\u0440\u043e\u0434 \u0438\u043c\u0435\u0435\u0442 m\n\u043e\u0433\u0440\u0430\u043d\u0438\u0447\u0435\u043d\u0438\u0439. \u0412 \u0441\u043e\u043e\u0442\u0432\u0435\u0442\u0441\u0442\u0432\u0438\u0438 \u0441 i-\u043c \u043e\u0433\u0440\u0430\u043d\u0438\u0447\u0435\u043d\u0438\u0435\u043c, \u0441\u0430\u043c\u044b\u0439 \u0432\u044b\u0441\u043e\u043a\u0438\u0439 \u0434\u043e\u043c \u043e\u0442 li \u0434\u043e ri (\u0432\u043a\u043b\u044e\u0447\u0438\u0442\u0435\u043b\u044c\u043d\u043e) \u0434\u043e\u043b\u0436\u0435\u043d \u0438\u043c\u0435\u0442\u044c \u0432\u044b\u0441\u043e\u0442\u0443 \u043d\u0435 \u0431\u043e\u043b\u0435\u0435 xi\n\n.\n\n\u0412\u044b \u0445\u043e\u0442\u0435\u043b\u0438 \u0431\u044b \u043f\u043e\u0441\u0442\u0440\u043e\u0438\u0442\u044c \u0434\u043e\u043c\u0430, \u0447\u0442\u043e\u0431\u044b \u043c\u0430\u043a\u0441\u0438\u043c\u0438\u0437\u0438\u0440\u043e\u0432\u0430\u0442\u044c \u0441\u0432\u043e\u044e \u043f\u0440\u0438\u0431\u044b\u043b\u044c. \u041e\u043f\u0440\u0435\u0434\u0435\u043b\u0438\u0442\u0435 \u043c\u0430\u043a\u0441\u0438\u043c\u0430\u043b\u044c\u043d\u043e \u0432\u043e\u0437\u043c\u043e\u0436\u043d\u0443\u044e \u043f\u0440\u0438\u0431\u044b\u043b\u044c.\n\u0412\u0445\u043e\u0434\u043d\u044b\u0435 \u0434\u0430\u043d\u043d\u044b\u0435\n\n\u041f\u0435\u0440\u0432\u0430\u044f \u0441\u0442\u0440\u043e\u043a\u0430 \u0441\u043e\u0434\u0435\u0440\u0436\u0438\u0442 \u0442\u0440\u0438 \u0446\u0435\u043b\u044b\u0445 \u0447\u0438\u0441\u043b\u0430 n\n, h \u0438 m (1\u2264n,h,m\u226450\n\n) \u2014 \u043a\u043e\u043b\u0438\u0447\u0435\u0441\u0442\u0432\u043e \u043c\u0435\u0441\u0442, \u043c\u0430\u043a\u0441\u0438\u043c\u0430\u043b\u044c\u043d\u0430\u044f \u0432\u044b\u0441\u043e\u0442\u0430 \u0438 \u043a\u043e\u043b\u0438\u0447\u0435\u0441\u0442\u0432\u043e \u043e\u0433\u0440\u0430\u043d\u0438\u0447\u0435\u043d\u0438\u0439.\n\n\u041a\u0430\u0436\u0434\u0430\u044f \u0438\u0437 \u0441\u043b\u0435\u0434\u0443\u044e\u0449\u0438\u0445 m\n\u0441\u043e\u0434\u0435\u0440\u0436\u0438\u0442 \u0442\u0440\u0438 \u0446\u0435\u043b\u044b\u0445 \u0447\u0438\u0441\u043b\u0430 li, ri \u0438 xi (1\u2264li\u2264ri\u2264n, 0\u2264xi\u2264h) \u2014 \u043b\u0435\u0432\u0430\u044f \u0438 \u043f\u0440\u0430\u0432\u0430\u044f \u0433\u0440\u0430\u043d\u0438\u0446\u0430 (\u0432\u043a\u043b\u044e\u0447\u0438\u0442\u0435\u043b\u044c\u043d\u043e) i\n\n-\u0433\u043e \u043e\u0433\u0440\u0430\u043d\u0438\u0447\u0435\u043d\u0438\u044f \u0438 \u043c\u0430\u043a\u0441\u0438\u043c\u0430\u043b\u044c\u043d\u0430\u044f \u0432\u043e\u0437\u043c\u043e\u0436\u043d\u0430\u044f \u0432\u044b\u0441\u043e\u0442\u0430 \u043d\u0430 \u044d\u0442\u043e\u043c \u043e\u0442\u0440\u0435\u0437\u043a\u0435.\n\u0412\u044b\u0445\u043e\u0434\u043d\u044b\u0435 \u0434\u0430\u043d\u043d\u044b\u0435\n\n\u0412\u044b\u0432\u0435\u0434\u0438\u0442\u0435 \u043e\u0434\u043d\u043e \u0446\u0435\u043b\u043e\u0435 \u0447\u0438\u0441\u043b\u043e \u2014 \u043c\u0430\u043a\u0441\u0438\u043c\u0430\u043b\u044c\u043d\u0443\u044e \u0432\u043e\u0437\u043c\u043e\u0436\u043d\u0443\u044e \u043f\u0440\u0438\u0431\u044b\u043b\u044c.\n\u041f\u0440\u0438\u043c\u0435\u0440\u044b\n\u0412\u0445\u043e\u0434\u043d\u044b\u0435 \u0434\u0430\u043d\u043d\u044b\u0435\n\u0421\u043a\u043e\u043f\u0438\u0440\u043e\u0432\u0430\u0442\u044c\n\n3 3 3\n1 1 1\n2 2 3\n3 3 2\n\n\u0412\u044b\u0445\u043e\u0434\u043d\u044b\u0435 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\u043e\u0433\u0440\u0430\u043d\u0438\u0447\u0435\u043d\u0438\u044f. \u041f\u0435\u0440\u0432\u043e\u0435 \u043e\u0433\u0440\u0430\u043d\u0438\u0447\u0435\u043d\u0438\u0435 \u0433\u043e\u0432\u043e\u0440\u0438\u0442, \u0447\u0442\u043e \u0441\u0430\u043c\u044b\u0439 \u0432\u044b\u0441\u043e\u043a\u0438\u0439 \u0434\u043e\u043c \u043c\u0435\u0436\u0434\u0443 1 \u0438 1 \u0434\u043e\u043b\u0436\u0435\u043d \u0438\u043c\u0435\u0442\u044c \u0432\u044b\u0441\u043e\u0442\u0443 \u043d\u0435 \u0431\u043e\u043b\u0435\u0435 1. \u0412\u0442\u043e\u0440\u043e\u0435 \u043e\u0433\u0440\u0430\u043d\u0438\u0447\u0435\u043d\u0438\u0435 \u0433\u043e\u0432\u043e\u0440\u0438\u0442, \u0447\u0442\u043e \u0441\u0430\u043c\u044b\u0439 \u0432\u044b\u0441\u043e\u043a\u0438\u0439 \u0434\u043e\u043c \u043c\u0435\u0436\u0434\u0443 2 \u0438 2 \u0434\u043e\u043b\u0436\u0435\u043d \u0438\u043c\u0435\u0442\u044c \u0432\u044b\u0441\u043e\u0442\u0443 \u043d\u0435 \u0431\u043e\u043b\u0435\u0435 3. \u0422\u0440\u0435\u0442\u044c\u0435 \u043e\u0433\u0440\u0430\u043d\u0438\u0447\u0435\u043d\u0438\u0435 \u0433\u043e\u0432\u043e\u0440\u0438\u0442, \u0447\u0442\u043e \u0441\u0430\u043c\u044b\u0439 \u0432\u044b\u0441\u043e\u043a\u0438\u0439 \u0434\u043e\u043c \u043c\u0435\u0436\u0434\u0443 3 \u0438 3 \u0434\u043e\u043b\u0436\u0435\u043d \u0438\u043c\u0435\u0442\u044c \u0432\u044b\u0441\u043e\u0442\u0443 \u043d\u0435 \u0431\u043e\u043b\u0435\u0435 2\n\n.\n\n\u0412 \u044d\u0442\u043e\u043c \u0441\u043b\u0443\u0447\u0430\u0435 \u043e\u043f\u0442\u0438\u043c\u0430\u043b\u044c\u043d\u043e \u0441\u0442\u0440\u043e\u0438\u0442\u044c \u0434\u043e\u043c\u0430 \u0432\u044b\u0441\u043e\u0442\u043e\u0439 [1,3,2]\n. \u042d\u0442\u043e \u0432\u043f\u0438\u0441\u044b\u0432\u0430\u0435\u0442\u0441\u044f \u0432\u043e \u0432\u0441\u0435 \u043e\u0433\u0440\u0430\u043d\u0438\u0447\u0435\u043d\u0438\u044f. \u041e\u0431\u0449\u0430\u044f \u043f\u0440\u0438\u0431\u044b\u043b\u044c \u0432 \u044d\u0442\u043e\u043c \u0441\u043b\u0443\u0447\u0430\u0435 \u0441\u043e\u0441\u0442\u0430\u0432\u043b\u044f\u0435\u0442 12+32+22=14\n\n.\n\n\u0412\u043e \u0432\u0442\u043e\u0440\u043e\u043c \u043f\u0440\u0438\u043c\u0435\u0440\u0435 \u043c\u043e\u0436\u043d\u043e \u043f\u043e\u0441\u0442\u0440\u043e\u0438\u0442\u044c 4\n\u0434\u043e\u043c\u0430, \u043c\u0430\u043a\u0441\u0438\u043c\u0430\u043b\u044c\u043d\u0430\u044f \u0432\u044b\u0441\u043e\u0442\u0430 \u043a\u043e\u0442\u043e\u0440\u044b\u0445 \u2014 10, \u0430 \u0442\u0430\u043a\u0436\u0435 \u0435\u0441\u0442\u044c 2 \u043e\u0433\u0440\u0430\u043d\u0438\u0447\u0435\u043d\u0438\u044f. \u041f\u0435\u0440\u0432\u043e\u0435 \u043e\u0433\u0440\u0430\u043d\u0438\u0447\u0435\u043d\u0438\u0435 \u0433\u043e\u0432\u043e\u0440\u0438\u0442, \u0447\u0442\u043e \u0441\u0430\u043c\u044b\u0439 \u0432\u044b\u0441\u043e\u043a\u0438\u0439 \u0434\u043e\u043c \u043e\u0442 2 \u0434\u043e 3 \u0434\u043e\u043b\u0436\u0435\u043d \u0438\u043c\u0435\u0442\u044c \u0432\u044b\u0441\u043e\u0442\u0443 \u043d\u0435 \u0431\u043e\u043b\u0435\u0435 8. \u0412\u0442\u043e\u0440\u043e\u0435 \u043e\u0433\u0440\u0430\u043d\u0438\u0447\u0435\u043d\u0438\u0435 \u0433\u043e\u0432\u043e\u0440\u0438\u0442, \u0447\u0442\u043e \u0441\u0430\u043c\u044b\u0439 \u0432\u044b\u0441\u043e\u043a\u0438\u0439 \u0434\u043e\u043c \u043e\u0442 3 \u0434\u043e 4 \u0434\u043e\u043b\u0436\u0435\u043d \u0438\u043c\u0435\u0442\u044c \u0432\u044b\u0441\u043e\u0442\u0443 \u043d\u0435 \u0431\u043e\u043b\u0435\u0435 7\n\n.\n\n\u0412 \u044d\u0442\u043e\u043c \u0441\u043b\u0443\u0447\u0430\u0435 \u043e\u043f\u0442\u0438\u043c\u0430\u043b\u044c\u043d\u043e \u0441\u0442\u0440\u043e\u0438\u0442\u044c \u0434\u043e\u043c\u0430 \u0432\u044b\u0441\u043e\u0442\u043e\u0439 [10,8,7,7]\n. \u041c\u044b \u043f\u043e\u043b\u0443\u0447\u0430\u0435\u043c \u043f\u0440\u0438\u0431\u044b\u043b\u044c \u0432 \u0440\u0430\u0437\u043c\u0435\u0440\u0435 102+82+72+72=262. \u041e\u0431\u0440\u0430\u0442\u0438\u0442\u0435 \u0432\u043d\u0438\u043c\u0430\u043d\u0438\u0435, \u0447\u0442\u043e \u0435\u0441\u0442\u044c \u0434\u0432\u0430 \u043e\u0433\u0440\u0430\u043d\u0438\u0447\u0435\u043d\u0438\u044f \u043d\u0430 \u0434\u043e\u043c 3, \u0438 \u043e\u0431\u0430 \u043e\u043d\u0438 \u0434\u043e\u043b\u0436\u043d\u044b \u0432\u044b\u043f\u043e\u043b\u043d\u044f\u0442\u044c\u0441\u044f. \u041a\u0440\u043e\u043c\u0435 \u0442\u043e\u0433\u043e, \u043e\u0431\u0440\u0430\u0442\u0438\u0442\u0435 \u0432\u043d\u0438\u043c\u0430\u043d\u0438\u0435, \u0447\u0442\u043e \u0445\u043e\u0442\u044f \u043d\u0435\u0442 \u043d\u0438\u043a\u0430\u043a\u0438\u0445 \u044f\u0432\u043d\u044b\u0445 \u043e\u0433\u0440\u0430\u043d\u0438\u0447\u0435\u043d\u0438\u0439 \u043d\u0430 \u0434\u043e\u043c 1, \u043c\u044b \u0432\u0441\u0435 \u0440\u0430\u0432\u043d\u043e \u0434\u043e\u043b\u0436\u043d\u044b \u043e\u0433\u0440\u0430\u043d\u0438\u0447\u0438\u0442\u044c \u0435\u0433\u043e \u0432\u044b\u0441\u043e\u0442\u0443 \u043d\u0435 \u0431\u043e\u043b\u0435\u0435 10 (h=10).\n*/\n#include <stdio.h> \n#include <stdlib.h>\nconst int MAX = 51;\n\nint max (int a, int b){ if (a>b) return a; else return b;}\nint min (int a, int b){ if (a<b) return a; else return b;}\n\nint main (){\nint i,h,n,m;\t\nint a[MAX];\nscanf(\"%i%i%i\",&n,&h,&m);\nfor(i=0;i<MAX;i++)\n\ta[i] = h;\nfor (i=0;i<m;i++){\n\tint l,r,x;\n\tscanf(\"%i%i%i\",&l,&r,&x);\n\tint j;\n\tfor(j=l-1;j<=r-1;j++)\n\t\ta[j] = x;\n\t\n\t//a[l-1] = min ( a[l-1], -x) ;\t\n\t//a[r-1] = +x;\n\n}\nm = 0;\nfor (i=0;i<n;i++)\n\tm += a[i]*a[i];\n\nprintf(\"%i\\n\",m);\nreturn 0-0-0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "33de3363a08c535a9c87af72b65112ee", "src_uid": "f22b6dab443f63fb8d2d288b702f20ad", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,h,m,i,j,ans=0;\n    scanf(\"%d%d%d\",&n,&h,&m);\n    int l[n],r[n],x[n],a[n];\n    for(i=0; i<m; i++)\n        scanf(\"%d %d %d\",&l[i],&r[i],&x[i]);\n    for(i=1; i<=n; i=i+1)\n    {\n        int num=h;\n        for(j=0; j<m; j=j+1)\n        {\n            if(i>=l[j] && i<=r[j])\n            {\n                if(num>x[j])\n                    num=x[j];\n            }\n        }\n        ans=ans+(num*num);\n    }\n    printf(\"%d\\n\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "2306a6f740677acdd9ed0e0bd6cbd3fb", "src_uid": "f22b6dab443f63fb8d2d288b702f20ad", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint m,n,h;\n\tint l[30],r[30],h1[30];\n\tscanf(\"%d%d%d\",&n,&h,&m);\n\tfor (int i = 1; i <= m; ++i)\n\t{\n\t\tscanf(\"%d%d%d\",&l[i],&r[i],&h1[i]);\n\t}\n\tint p[30];\n\tfor (int i = 1; i <=n ; ++i)\n\t{\n\t\tp[i]=h*h;\n\t}\n\tfor (int i = 1; i <= m; ++i)\n\t{\n\t\tfor (int j = l[i]; j <= r[i]; ++j)\n\t\t{\n\t\t\tp[j]=h1[i]*h1[i];\n\t\t\t//printf(\"%d:-%d\\t\",p[j],j);\n\t\t}\n\t}\n\t//printf(\"\\n\");\n\tint t=0;\n\tfor (int i = 1; i <= n; ++i)\n\t{\n\t\tt=t+p[i];\n\t}\n\tprintf(\"%d\\n\",t);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7c0948e78399e003c186bcf0952dfb1a", "src_uid": "f22b6dab443f63fb8d2d288b702f20ad", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n,h,m,i,maxprof=0,j,b,c;\n    scanf(\"%d%d%d\",&n,&h,&m);\n    int a[n];\n    int l[m],r[m],x[m];\n    for(i=0;i<m;i++){\n        scanf(\"%d%d%d\",&l[i],&r[i],&x[i]);\n    }\n    //initializing array \"a\"\n    for(i=0;i<n;i++){\n        a[i]=h;\n    }\n    for(i=0;i<n;i++){\n       b=l[i]-1;\n       c=r[i]-1;\n       for(j=b;j<=c;j++){\n           if(x[i]<=a[j]){\n               a[j]=x[i];\n           }\n       }\n    }\n    for(i=0;i<n;i++){\n        maxprof=maxprof+a[i]*a[i];\n    }\n    printf(\"%d\",maxprof);\n    \nreturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f058fcec38b362ea7d38f0760e367863", "src_uid": "f22b6dab443f63fb8d2d288b702f20ad", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#define mian main\n#define MAXN 103\n#define INF 0x3f3f3f3f\n#define MIN(a,b) ((a)<(b)?(a):(b))\nint read () {\n    int x = 0; char ch = getchar();\n    while (ch < '0' || ch > '9') ch = getchar();\n    while (ch >= '0' && ch <= '9') {x = x * 10 + ch - '0'; ch = getchar();}\\\n    return x;\n}\nint vis[MAXN], a[MAXN], b[MAXN], len;\nint mian (void) {\n    int n = read(), m = read();\n    int i, l[2];\n    l[0] = read();\n    for (i = 1; i < m; ++i) {\n        l[i % 2] = read();\n        int t = (l[i%2] - l[(i+1)%2] + n) % n;\n        if (t == 0) t = n;\n        if ((vis[t] || a[l[(i+1)%2]]) && a[l[(i+1)%2]] != t) {\n            printf(\"-1\\n\");\n            return 0;\n        }\n        vis[t] = 1;\n        a[l[(i+1)%2]] = t;\n    }\n    for (i = 1; i <= n; ++i) {\n        if (!vis[i]) b[len++] = i, vis[i] = 1;\n    }\n    for (i = 1; i <= n; ++i) {\n        if (a[i] == 0)\n            a[i] = b[--len];\n        printf(\"%d \", a[i]);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8fe0ded3158d8999a8438c17a32be9ad", "src_uid": "4a7c959ca279d0a9bd9bbf0ce88cf72b", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint seq[101], num[101], included[101];\n\nint main(void)\n{\n\tint a, b, n, m, f = 0;\n\tscanf(\"%d %d\", &n, &m);\n\tfor (a = 1; a <= m; a = a + 1)\n\t{\n\t\tint cmp;\n\t\tscanf(\"%d\", &seq[a]);\n\t\tif (a - 1)\n\t\t{\n\t\t\tcmp = seq[a] - seq[a - 1];\n\t\t\tif (cmp > 0)\n\t\t\t{\n\t\t\t\tif (included[cmp] && num[seq[a - 1]] == 0 || (num[seq[a - 1]] && num[seq[a - 1]] != cmp))\n\t\t\t\t{\n\t\t\t\t\tputs(\"-1\");\n\t\t\t\t\tf = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tincluded[cmp] = 1;\n\t\t\t\tnum[seq[a - 1]] = cmp;\n\t\t\t}\n\t\t\telse if (cmp <= 0)\n\t\t\t{\n\t\t\t\tcmp = n + cmp;\n\t\t\t\tif ((included[cmp] && num[seq[a - 1]] == 0) || (num[seq[a-1]] && num[seq[a-1]] != cmp))\n\t\t\t\t{\n\t\t\t\t\tputs(\"-1\");\n\t\t\t\t\tf = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tincluded[cmp] = 1;\n\t\t\t\tnum[seq[a - 1]] = cmp;\t\t\t\t\n\t\t\t}\n\t\t}\n\t}\n\tfor (a = 1; a <= n; a = a + 1)\n\t{\n\t\tif (num[a] == 0)\n\t\t{\n\t\t\tfor (b = 1; b <= n; b = b + 1)\n\t\t\t{\n\t\t\t\tif (!included[b])\n\t\t\t\t{\n\t\t\t\t\tnum[a] = b;\n\t\t\t\t\tincluded[b] = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (num[a] == 0)\n\t\t\t{\n\t\t\t\tf = 1;\n\t\t\t\tputs(\"-1\");\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tif (f == 0)\n\t{\n\t\tfor (a = 1; a <= n; a = a + 1)\n\t\t\tprintf(\"%d \", num[a]);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "eecf9a979e11ecdb2104b827f98a41fa", "src_uid": "4a7c959ca279d0a9bd9bbf0ce88cf72b", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include\"stdio.h\"\n#include\"string.h\"\n#include\"math.h\"\n#include\"stdlib.h\"\n#include\"ctype.h\"\n#include\"limits.h\"\n#include\"time.h\"\n\nint main()\n{\n\tclock_t lnh=clock();\n\tint n,m,x=1,c;\n\tscanf(\"%d%d\",&n,&m);\n\tint a[100]={0},d[100]={0},ac[100]={0},i,j,l[m];\n\tfor(i=0;i<m;scanf(\"%d\",&l[i++]));\n\t\n\tfor(i=0;i<m-1;i++)\n\t{\n\t\tc=l[i+1]-l[i]+n*(l[i]>=l[i+1]);\n\t\td[c-1]=1;\n\t\tif(a[l[i]-1]!=c && a[l[i]-1])\n\t\tx=0;\n\t\telse\n\t\ta[l[i]-1]=c;\n\t}\n\t\n\tfor(i=j=0;i<n;i++)\n\tif(!a[i])\n\t{\n\t\tfor(;d[j] && j<n;j++);\n\t\tif(j==n)\n\t\tbreak;\n\t\ta[i]=++j;\n\t}\n\t\n\tfor(i=0;i<n;i++)\n\tif(a[i])\n\tac[a[i]-1]++;\n\t\n\tfor(i=0;i<n;i++)\n\tif(!a[i] || ac[i]>1)\n\tx=0;\n\tif(!x)\n\tprintf(\"-1\");\n\telse\n\t{\n\t\tfor(i=0;i<n-1;i++)\n\t\tprintf(\"%d \",a[i]);\n\t\tprintf(\"%d\",a[i]);\n\t}\n\tprintf(\"\\n\");\n\t\n\tclock_t cls=clock();\t//printf(\"%fms\\n\",(double)((cls-lnh)*1000)/CLOCKS_PER_SEC);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4e2898d58581095c5431e32ebd621e9e", "src_uid": "4a7c959ca279d0a9bd9bbf0ce88cf72b", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint ans[104],indx[104],vec[104],y[104];\nint main()\n{\n\tint n,m,l[103],i,flag=0,k=0,count=0,p=0,temp;\n\tscanf(\"%d%d\",&n,&m);\n\tfor(i=0;i<m;i++)\n\t\tscanf(\"%d\",&l[i]);\n\tfor(i=0;i<m-1;i++)\n\t{\n\t\ttemp=l[i+1]-l[i];\t\n\t\tif(temp<=0)\n\t\t\ttemp=temp+n;\n\t\tif(indx[temp]==1 && y[temp]!=l[i])\n\t\t{\n\t\t\tflag=1;\n\t\t\tbreak;\n\t\t}\n\t\tans[l[i]]=temp;\n\t\tindx[temp]=1;\n\t\ty[temp]=l[i];\n\t}\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tif(indx[i]==0)\n\t\t{\n\t\t\tvec[k]=i;\n\t\t\tk++;\n\t\t}\n\t\tif(ans[i]==0)\n\t\t\tcount++;\n\t}\n\tif(count!=k || flag==1)\n\t\tprintf(\"-1\\n\");\n\telse\n\t{\n\t\tfor(i=1;i<=n;i++)\n\t\t{\t\n\t\t\tif(ans[i]==0)\n\t\t\t{\n\t\t\t\tans[i]=vec[p];\n\t\t\t\tp++;\n\t\t\t}\n\t\t\tprintf(\"%d \",ans[i]);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n\treturn 0;\n}\n\t\t\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0ff0e7b94ea29c575e542e930276192b", "src_uid": "4a7c959ca279d0a9bd9bbf0ce88cf72b", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n#define min(a,b) (a < b ? a : b)\ntypedef long long ll;\nll n, m, a[100000], l[200], vis[200], vist[200];\n\nbool solve(){\n\tll i, j;\n\tfor(i = 1; i < m; i++){\n\t\tif(l[i + 1] > l[i]){\n\t\t\tif(a[l[i]] && a[l[i]] != l[i + 1] - l[i]) return false;\n\t\t\ta[l[i]] = l[i + 1] - l[i];\n\t\t}\n\t\telse if(l[i + 1] == l[i]){\n\t\t\tif(a[l[i]] && a[l[i]] != n) return false;\n\t\t\ta[l[i]] = n;\n\t\t\t\n\t\t\tfor(j = 1; j <= n; j++)\tif(a[j]) vis[a[j]] = 1;\n\t\t\tfor(j = 1; j <= n; j++){\n\t\t\t\tif(!a[j]){\n\t\t\t\t\tfor(ll k = 1; k <= n; k++){\n\t\t\t\t\t\tif(!vis[k]){\n\t\t\t\t\t\t\ta[j] = k;\n\t\t\t\t\t\t\tvis[k] = 1;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t} \n\t\t\t}// 1 2 3 4 5 \n\t\t\tbreak;\n\t\t}\n\t\telse{\n\t\t\tif(a[l[i]] && a[l[i]] != n - l[i] + l[i + 1]) return false;\n\t\t\ta[l[i]] = n - l[i] + l[i + 1];\n\t\t\t//vist[a[l[i]]] = l[i];\n\t\t}\n\t}\n\t\n\t//check:\n\tfor(i = 1; i <= n; i++) if(!a[i]) return false;\n\tfor(i = 1; i <= n; i++) \n\t\tfor(j = 1; j <= n; j++) if(i != j && a[j] == a[i]) return false;\n\tfor(i = 1;)\n\treturn true;\n}\n\nint main(void){\n\tll i, j, k;\n\tscanf(\"%lld%lld\", &n, &m);\n\tfor(i = 1; i <= m ; i++) scanf(\"%lld\", l + i);\n\tif (solve()) for(i = 1; i <= n; i++) printf(\"%lld \", a[i]);\n\telse puts(\"-1\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "98232a4ab88a34b86ae6ff7646e205a3", "src_uid": "4a7c959ca279d0a9bd9bbf0ce88cf72b", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint n,k,i;\nscanf(\"%d%d\",&n,&k);\nfor(i=0;i<=n%k;i++)\n        printf(\"%d \",n/k);\nfor(;i<n;i++)\n        printf(\"%d \",n/k+1);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9ae07db54a7df36f94928cfc77151956", "src_uid": "0b2c1650979a9931e00ffe32a70e3c23", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n\tint n, m, i;\n\tscanf(\"%d%d\", &n, &m);\n\tif (n%m==0) \n    {\n        for (i = 0; i < m; i++) \n        {\n            printf(\"%d \", n/m);\n        }\n\telse\n\t{\n\t\tfor (i = 0; i < n%m; i++)\n        {\n            printf(\"%d \", n/m+1);\n        }\n\t\tfor (i = 0; i < (m-(n%m)); i++) \n        { \n            printf(\"%d \", n/m);\n        }\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "afbc5d4d4e40cf75799571009667a90d", "src_uid": "0b2c1650979a9931e00ffe32a70e3c23", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n,m;\n    scanf(\"%d %d\",&n,&m);\n    do{\n        if(n%m==0){printf(\"%d \",n/m);continue;}\n        else{\n            printf(\"%d \",n/m);\n            n=n-n/m;\n            m--;\n        }\n        }while(m)\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b3eeb0441bae2c90f6d6a27464a75728", "src_uid": "0b2c1650979a9931e00ffe32a70e3c23", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nint n,k,i;\nscanf(\"%d%d\",&n,&k);\nfor(i=0;i<=n/k;i++)\n        printf(\"%d \",n/k);\nfor(i=0;i<n%k;i++)\n        printf(\"%d \",n/k+1);\ngetch();\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6fc94a0bd526cebc98166d17f3a4e35f", "src_uid": "0b2c1650979a9931e00ffe32a70e3c23", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n,m;\n    scanf(\"%d %d\",&n,&m);\n    do{\n        if(n%m==0){printf(\"%d \",n/m);continue;}\n        else{\n            printf(\"%d \",n/m);\n            n=n-n/m;\n            m--;\n        }\n        }while(m);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d05edc5da183f464c257b187d69091ac", "src_uid": "0b2c1650979a9931e00ffe32a70e3c23", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nmain()\n{\nchar h[10],p[10],d[10],c;\nint m=0,n=0,i=0,k=0,j=0,l=0,t=0,q=0,w=0,e=0,r=0,a=0,b=0;\n\n\tif (q!=1)\n\t{printf(\"1\");\nwhile((c=getchar())!='\\n')\n{h[i]=c;\nn++;\n}}\n\tif (w!=1)\n\t{printf(\"2\");\nwhile((c=getchar())!='\\n')\n{p[k]=c;\nm++;\n}}\nif (e!=1)\n{printf(\"3\");\nwhile((c=getchar())!='\\n')\n{d[j]=c;\nl++;\n}}\n\n\nif (((n==8)&&(m==5)&&(l==5))||((n==5)&&(m==4)&&(l==4))||((n==4)&&(m==8)&&(l==8)))\nprintf(\"F\"); \nelse if (((n==5)&&(m==8)&&(l==5))||((n==4)&&(m==5)&&(l==4))||((n==8)&&(m==4)&&(l==8)))\nprintf(\"M\");\nelse if (((n==5)&&(m==5)&&(l==8))||((n==4)&&(m==4)&&(l==5))||((n==8)&&(m==8)&&(l==4)))\nprintf(\"S\"); \nelse if (((n==5)&&(m==8)&&(l==8))||((n==4)&&(m==5)&&(l==5))||((n==8)&&(m==4)&&(l==4)))\nprintf(\"?\");\nelse if (((n==8)&&(m==5)&&(l==8))||((n==5)&&(m==4)&&(l==5))||((n==4)&&(m==8)&&(l==4)))\nprintf(\"?\");\nelse if (((n==8)&&(m==8)&&(l==5))||((n==5)&&(m==5)&&(l==4))||((n==4)&&(m==4)&&(l==8)))\nprintf(\"?\");\nelse printf(\"?\");\n\n/*\n{\n\tif (q==1)\n\t{ a=m; b=l;\nif (((a==8)&&(b==5))||((a==5)&&(b==4))&&((a==4)&&(b==8)))\n{\n\tprintf(\"M\"); t=1;}\nelse {printf(\"S\"); t=1;}}\nelse if (w==1)\n\t{ a=n; b=l;\nif (((a==8)&&(b==5))||((a==5)&&(b==4))&&((a==4)&&(b==8)))\n{\nprintf(\"F\"); t=1;}\nelse {printf(\"S\"); t=1;}}\nelse if (e==1)\n\t{ a=n; b=m;\nif (((a==8)&&(b==5))||((a==5)&&(b==4))&&((a==4)&&(b==8)))\n{\nprintf(\"F\"); t=1;}\nelse {printf(\"M\");t=1;}}\n}\n}\n}\n*/\n/*\nwhile (t!= 1)\n{\n\tif (q!=1)\n\t{printf(\"1\");\nn=getchar();\n}\n\tif (w!=1)\n\t{printf(\"2\");\nm=getchar();\n\t}\nif (e!=1)\n{printf(\"3\");\nl=getchar();}\n\nif (r!=1)\n{\nif (((n=='s')&&(m=='p')&&(l=='p'))||((n=='s')&&(m=='r')&&(l=='r'))&&((n=='r')&&(m=='r')&&(l=='s')))\n{\n\tprintf(\"F\"); t=1;}\nelse if (((n=='p')&&(m=='s')&&(l=='p'))||((n=='r')&&(m=='p')&&(l=='r'))&&((n=='s')&&(m=='r')&&(l=='s')))\n{printf(\"M\"); t=1;}\nelse if (((n=='p')&&(m=='p')&&(l=='s'))||((n=='r')&&(m=='r')&&(l=='p'))&&((n=='s')&&(m=='s')&&(l=='r')))\n{printf(\"S\"); t=1;}\nelse if (((n=='p')&&(m=='s')&&(l=='s'))||((n=='r')&&(m=='p')&&(l=='p'))||((n=='s')&&(m=='r')&&(l=='r')))\n{q=1;\nr=1;}\nelse if (((n=='s')&&(m=='p')&&(l=='s'))||((n=='p')&&(m=='r')&&(l=='p'))||((n=='r')&&(m=='s')&&(l=='r')))\n{w=1;\nr=1;}\nelse if (((n=='s')&&(m=='s')&&(l=='p'))||((n=='p')&&(m=='p')&&(l=='r'))||((n=='r')&&(m=='r')&&(l=='s')))\n{e=1;\nr=1;}\n}\nelse\n{\n\tif (q==1)\n\t{ a=m; b=l;\nif (((a=='s')&&(b=='p'))||((a=='p')&&(b=='r'))&&((a=='r')&&(b=='s')))\n{\n\tprintf(\"M\"); t=1;}\nelse {printf(\"S\"); t=1;}}\nelse if (w==1)\n\t{ a=n; b=l;\nif (((a=='s')&&(b=='p'))||((a=='p')&&(b=='r'))&&((a=='r')&&(b=='s')))\n{\nprintf(\"F\"); t=1;}\nelse {printf(\"S\"); t=1;}}\nelse if (e==1)\n\t{ a=n; b=m;\nif (((a=='s')&&(b=='p'))||((a=='p')&&(b=='r'))&&((a=='r')&&(b=='s')))\n{\nprintf(\"F\"); t=1;}\nelse {printf(\"M\");t=1;}}\n}\n}\n}\n\n*/\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4b7898d762d45395bfe883535cb4054e", "src_uid": "072c7d29a1b338609a72ab6b73988282", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nmain()\n{\nchar h[10],p[10],d[10],z[8]=\"scissors\",x[5]=\"paper\",c[4]=\"rock\";\nint m=0,n=0,i=0,k=0,j=0,l=0,t=0,q=0,w=0,e=0,r=0,a=0,b=0,g=1;\nscanf(\"%s\", h);\nn = strlen(h);\n\nscanf(\"%s\", p);\nm = strlen(p);\n\nscanf(\"%s\", d);\nl = strlen(d);\n/*\n\tif (q!=1)\n\t{printf(\"1\");\nwhile((c=getchar())!='\\n')\n{h[i]=c;\nn++;\n}}\n\tif (w!=1)\n\t{printf(\"2\");\nwhile((c=getchar())!='\\n')\n{p[k]=c;\nm++;\n}}\nif (e!=1)\n{printf(\"3\");\nwhile((c=getchar())!='\\n')\n{d[j]=c;\nl++;\n}}*/\n/*\nif (h[0]=='s')\n{\nfor(i=0;i<n;i++)\n{if\n\t(h[i]==z[i])\n\tg++;}}\nelse if (h[0]=='p')\n{for(i=0;i<n;i++)\n\n{if\n\t(h[i]==x[i])\n\tg++;}}\nelse if (h[0]=='r')\nfor(i=0;i<n;i++){\n{if\n\t(h[i]==c[i])\n\tg++;}}\n/////////////////\n\nif (p[0]=='s')\nfor(i=0;i<m;i++){\n{if\n\t(p[i]==z[i])\n\tg++;}}\nelse if (p[0]=='p')\nfor(i=0;i<m;i++){\n{if\n\t(p[i]==x[i])\n\tg++;}}\nelse if (p[0]=='r')\nfor(i=0;i<m;i++){\n{if\n\t(p[i]==c[i])\n\tg++;}}\n////////////////\n\nif (d[0]=='s')\nfor(i=0;i<l;i++){\n{if\n\t(d[i]==z[i])\n\tg++;}}\nelse if (d[0]=='p')\nfor(i=0;i<l;i++){\n{if\n\t(d[i]==x[i])\n\tg++;}}\nelse if (d[0]=='r')\nfor(i=0;i<l;i++){\n{if\n\t(d[i]==c[i])\n\tg++;}}\nif((g==18)||(g==13)||(g==20))\n{\n*/\nif (((n==8)&&(m==5)&&(l==5))||((n==5)&&(m==4)&&(l==4))||((n==4)&&(m==8)&&(l==8)))\nprintf(\"F\"); \nelse if (((n==5)&&(m==8)&&(l==5))||((n==4)&&(m==5)&&(l==4))||((n==8)&&(m==4)&&(l==8)))\nprintf(\"M\");\nelse if (((n==5)&&(m==5)&&(l==8))||((n==4)&&(m==4)&&(l==5))||((n==8)&&(m==8)&&(l==4)))\nprintf(\"S\"); \nelse printf(\"?\");\n}\n/*\nelse if (((n==5)&&(m==8)&&(l==8))||((n==4)&&(m==5)&&(l==5))||((n==8)&&(m==4)&&(l==4)))\nprintf(\"?\");\nelse if (((n==8)&&(m==5)&&(l==8))||((n==5)&&(m==4)&&(l==5))||((n==4)&&(m==8)&&(l==4)))\nprintf(\"?\");\nelse if (((n==8)&&(m==8)&&(l==5))||((n==5)&&(m==5)&&(l==4))||((n==4)&&(m==4)&&(l==8)))\nprintf(\"?\");*/\n//else printf(\"?\");\n\n/*\n{\n\tif (q==1)\n\t{ a=m; b=l;\nif (((a==8)&&(b==5))||((a==5)&&(b==4))&&((a==4)&&(b==8)))\n{\n\tprintf(\"M\"); t=1;}\nelse {printf(\"S\"); t=1;}}\nelse if (w==1)\n\t{ a=n; b=l;\nif (((a==8)&&(b==5))||((a==5)&&(b==4))&&((a==4)&&(b==8)))\n{\nprintf(\"F\"); t=1;}\nelse {printf(\"S\"); t=1;}}\nelse if (e==1)\n\t{ a=n; b=m;\nif (((a==8)&&(b==5))||((a==5)&&(b==4))&&((a==4)&&(b==8)))\n{\nprintf(\"F\"); t=1;}\nelse {printf(\"M\");t=1;}}\n}\n}\n}\n*/\n/*\nwhile (t!= 1)\n{\n\tif (q!=1)\n\t{printf(\"1\");\nn=getchar();\n}\n\tif (w!=1)\n\t{printf(\"2\");\nm=getchar();\n\t}\nif (e!=1)\n{printf(\"3\");\nl=getchar();}\n\nif (r!=1)\n{\nif (((n=='s')&&(m=='p')&&(l=='p'))||((n=='s')&&(m=='r')&&(l=='r'))&&((n=='r')&&(m=='r')&&(l=='s')))\n{\n\tprintf(\"F\"); t=1;}\nelse if (((n=='p')&&(m=='s')&&(l=='p'))||((n=='r')&&(m=='p')&&(l=='r'))&&((n=='s')&&(m=='r')&&(l=='s')))\n{printf(\"M\"); t=1;}\nelse if (((n=='p')&&(m=='p')&&(l=='s'))||((n=='r')&&(m=='r')&&(l=='p'))&&((n=='s')&&(m=='s')&&(l=='r')))\n{printf(\"S\"); t=1;}\nelse if (((n=='p')&&(m=='s')&&(l=='s'))||((n=='r')&&(m=='p')&&(l=='p'))||((n=='s')&&(m=='r')&&(l=='r')))\n{q=1;\nr=1;}\nelse if (((n=='s')&&(m=='p')&&(l=='s'))||((n=='p')&&(m=='r')&&(l=='p'))||((n=='r')&&(m=='s')&&(l=='r')))\n{w=1;\nr=1;}\nelse if (((n=='s')&&(m=='s')&&(l=='p'))||((n=='p')&&(m=='p')&&(l=='r'))||((n=='r')&&(m=='r')&&(l=='s')))\n{e=1;\nr=1;}\n}\nelse\n{\n\tif (q==1)\n\t{ a=m; b=l;\nif (((a=='s')&&(b=='p'))||((a=='p')&&(b=='r'))&&((a=='r')&&(b=='s')))\n{\n\tprintf(\"M\"); t=1;}\nelse {printf(\"S\"); t=1;}}\nelse if (w==1)\n\t{ a=n; b=l;\nif (((a=='s')&&(b=='p'))||((a=='p')&&(b=='r'))&&((a=='r')&&(b=='s')))\n{\nprintf(\"F\"); t=1;}\nelse {printf(\"S\"); t=1;}}\nelse if (e==1)\n\t{ a=n; b=m;\nif (((a=='s')&&(b=='p'))||((a=='p')&&(b=='r'))&&((a=='r')&&(b=='s')))\n{\nprintf(\"F\"); t=1;}\nelse {printf(\"M\");t=1;}}\n}\n}\n}\n\n*/\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "196b71c2002a20fd64b339554d5b5a58", "src_uid": "072c7d29a1b338609a72ab6b73988282", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nmain()\n{\nchar h[10],p[10],d[10],c;\nint m=0,n=0,i=0,k=0,j=0,l=0,t=0,q=0,w=0,e=0,r=0,a=0,b=0;\n\n\tif (q!=1)\n\t{printf(\"1\");\nwhile((c=getchar())!='\\n')\n{h[i]=c;\nn++;\n}}\n\tif (w!=1)\n\t{printf(\"2\");\nwhile((c=getchar())!='\\n')\n{p[k]=c;\nm++;\n}}\nif (e!=1)\n{printf(\"3\");\nwhile((c=getchar())!='\\n')\n{d[j]=c;\nl++;\n}}\n\n\nif (((n==8)&&(m==5)&&(l==5))||((n==5)&&(m==4)&&(l==4))&&((n==4)&&(m==8)&&(l==8)))\nprintf(\"F\"); \nelse if (((n==5)&&(m==8)&&(l==5))||((n==4)&&(m==5)&&(l==4))&&((n==8)&&(m==4)&&(l==8)))\nprintf(\"M\");\nelse if (((n==5)&&(m==5)&&(l==8))||((n==4)&&(m==4)&&(l==5))&&((n==8)&&(m==8)&&(l==4)))\nprintf(\"S\"); \nelse if (((n==5)&&(m==8)&&(l==8))||((n==4)&&(m==5)&&(l==5))||((n==8)&&(m==4)&&(l==4)))\nprintf(\"?\");\nelse if (((n==8)&&(m==5)&&(l==8))||((n==5)&&(m==4)&&(l==5))||((n==4)&&(m==8)&&(l==4)))\nprintf(\"?\");\nelse if (((n==8)&&(m==8)&&(l==5))||((n==5)&&(m==5)&&(l==4))||((n==4)&&(m==4)&&(l==8)))\nprintf(\"?\");\n\n/*\n{\n\tif (q==1)\n\t{ a=m; b=l;\nif (((a==8)&&(b==5))||((a==5)&&(b==4))&&((a==4)&&(b==8)))\n{\n\tprintf(\"M\"); t=1;}\nelse {printf(\"S\"); t=1;}}\nelse if (w==1)\n\t{ a=n; b=l;\nif (((a==8)&&(b==5))||((a==5)&&(b==4))&&((a==4)&&(b==8)))\n{\nprintf(\"F\"); t=1;}\nelse {printf(\"S\"); t=1;}}\nelse if (e==1)\n\t{ a=n; b=m;\nif (((a==8)&&(b==5))||((a==5)&&(b==4))&&((a==4)&&(b==8)))\n{\nprintf(\"F\"); t=1;}\nelse {printf(\"M\");t=1;}}\n}\n}\n}\n*/\n/*\nwhile (t!= 1)\n{\n\tif (q!=1)\n\t{printf(\"1\");\nn=getchar();\n}\n\tif (w!=1)\n\t{printf(\"2\");\nm=getchar();\n\t}\nif (e!=1)\n{printf(\"3\");\nl=getchar();}\n\nif (r!=1)\n{\nif (((n=='s')&&(m=='p')&&(l=='p'))||((n=='s')&&(m=='r')&&(l=='r'))&&((n=='r')&&(m=='r')&&(l=='s')))\n{\n\tprintf(\"F\"); t=1;}\nelse if (((n=='p')&&(m=='s')&&(l=='p'))||((n=='r')&&(m=='p')&&(l=='r'))&&((n=='s')&&(m=='r')&&(l=='s')))\n{printf(\"M\"); t=1;}\nelse if (((n=='p')&&(m=='p')&&(l=='s'))||((n=='r')&&(m=='r')&&(l=='p'))&&((n=='s')&&(m=='s')&&(l=='r')))\n{printf(\"S\"); t=1;}\nelse if (((n=='p')&&(m=='s')&&(l=='s'))||((n=='r')&&(m=='p')&&(l=='p'))||((n=='s')&&(m=='r')&&(l=='r')))\n{q=1;\nr=1;}\nelse if (((n=='s')&&(m=='p')&&(l=='s'))||((n=='p')&&(m=='r')&&(l=='p'))||((n=='r')&&(m=='s')&&(l=='r')))\n{w=1;\nr=1;}\nelse if (((n=='s')&&(m=='s')&&(l=='p'))||((n=='p')&&(m=='p')&&(l=='r'))||((n=='r')&&(m=='r')&&(l=='s')))\n{e=1;\nr=1;}\n}\nelse\n{\n\tif (q==1)\n\t{ a=m; b=l;\nif (((a=='s')&&(b=='p'))||((a=='p')&&(b=='r'))&&((a=='r')&&(b=='s')))\n{\n\tprintf(\"M\"); t=1;}\nelse {printf(\"S\"); t=1;}}\nelse if (w==1)\n\t{ a=n; b=l;\nif (((a=='s')&&(b=='p'))||((a=='p')&&(b=='r'))&&((a=='r')&&(b=='s')))\n{\nprintf(\"F\"); t=1;}\nelse {printf(\"S\"); t=1;}}\nelse if (e==1)\n\t{ a=n; b=m;\nif (((a=='s')&&(b=='p'))||((a=='p')&&(b=='r'))&&((a=='r')&&(b=='s')))\n{\nprintf(\"F\"); t=1;}\nelse {printf(\"M\");t=1;}}\n}\n}\n}\n\n*/\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c3b5cac05cf6615a2d0c29197aeb5432", "src_uid": "072c7d29a1b338609a72ab6b73988282", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nmain()\n{\nchar h[10],p[10],d[10],c;\nint i=0,k=0,j=0,n=0,m=0,l=0,t=0,q=0,w=0,e=0,r=0,a=0,b=0;\n\nwhile (t!= 1)\n{\n\tif (q!=1)\n\t{printf(\"1\");\nwhile((c=getchar())!='\\n')\n{h[i]=c;\nn++;\n}}\n\tif (w!=1)\n\t{printf(\"2\");\nwhile((c=getchar())!='\\n')\n{p[k]=c;\nm++;\n}}\nif (e!=1)\n{printf(\"3\");\nwhile((c=getchar())!='\\n')\n{d[j]=c;\nl++;\n}}\n\nif (r!=1)\n{\nif (((n==8)&&(m==5)&&(l==5))||((n==5)&&(m==4)&&(l==4))&&((n==4)&&(m==8)&&(l==8)))\n{\n\tprintf(\"F\"); t=1;}\nelse if (((n==5)&&(m==8)&&(l==5))||((n==4)&&(m==5)&&(l==4))&&((n==8)&&(m==4)&&(l==8)))\n{printf(\"M\"); t=1;}\nelse if (((n==5)&&(m==5)&&(l==8))||((n==4)&&(m==4)&&(l==5))&&((n==8)&&(m==8)&&(l==4)))\n{printf(\"S\"); t=1;}\nelse if (((n==5)&&(m==8)&&(l==8))||((n==4)&&(m==5)&&(l==5))||((n==8)&&(m==4)&&(l==4)))\n{q=1;\nr=1;}\nelse if (((n==8)&&(m==5)&&(l==8))||((n==5)&&(m==4)&&(l==5))||((n==4)&&(m==8)&&(l==4)))\n{w=1;\nr=1;}\nelse if (((n==8)&&(m==8)&&(l==5))||((n==5)&&(m==5)&&(l==4))||((n==4)&&(m==4)&&(l==8)))\n{e=1;\nr=1;}\n}\nelse\n{\n\tif (q==1)\n\t{ a=m; b=l;\nif (((a==8)&&(b==5))||((a==5)&&(b==4))&&((a==4)&&(b==8)))\n{\n\tprintf(\"M\"); t=1;}\nelse {printf(\"S\"); t=1;}}\nelse if (w==1)\n\t{ a=n; b=l;\nif (((a==8)&&(b==5))||((a==5)&&(b==4))&&((a==4)&&(b==8)))\n{\nprintf(\"F\"); t=1;}\nelse {printf(\"S\"); t=1;}}\nelse if (e==1)\n\t{ a=n; b=m;\nif (((a==8)&&(b==5))||((a==5)&&(b==4))&&((a==4)&&(b==8)))\n{\nprintf(\"F\"); t=1;}\nelse {printf(\"M\");t=1;}}\n}\n}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "54d85c28913dfd0d6c060cc7cd0af881", "src_uid": "072c7d29a1b338609a72ab6b73988282", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nchar F[10];\nchar M[10];\nchar S[10];\n\nint main(void)\n{\n    scanf(\"%s\",F);\n    scanf(\"%s\",F);\n    scanf(\"%s\",F);\n    \n    int f,m,s;\n    \n    if(F[0]=='p')\n    f=1;\n    else if(F[0]=='r')\n    f=2;\n    else if(F[0]=='s')\n    f=3;\n    else\n    f=4;\n    \n    \n    if(M[0]=='p')\n    m=1;\n    else if(M[0]=='r')\n    m=2;\n    else if(M[0]=='s')\n    m=3;\n    else\n    m=4;\n    \n    \n    if(S[0]=='p')\n    s=1;\n    else if(S[0]=='r')\n    s=2;\n    else if(S[0]=='s')\n    s=3;\n    else\n    s=4;\n    \n    \n    if(f==1&&m==2&&s==2)\n    printf(\"F\");\n    else if(f==2&&m==3&&s==3)\n    printf(\"F\");\n    else if(f==3&&m==1&&s==1)\n    printf(\"F\");\n    else if(m==1&&f==2&&s==2)\n    printf(\"M\");\n    else if(m==2&&f==3&&s==3)\n    printf(\"M\");\n    else if(m==3&&f==1&&s==1)\n    printf(\"M\");\n    else if(s==1&&m==2&&f==2)\n    printf(\"S\");\n    else if(s==2&&m==3&&f==3)\n    printf(\"S\");\n    else if(s==3&&m==1&&f==1)\n    printf(\"S\");\n    else\n    printf(\"?\");\n    \n    return 0;\n}\n    \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2cd798185f192ac2f499d6e21821796c", "src_uid": "072c7d29a1b338609a72ab6b73988282", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include<math.h>\nint beu(int a)\n{\n    int k=0,i,q;\n    int b=a;\n    while (a>0)\n    {\n        if (a%2==0) k++;\n        else break;\n        a/=2;\n    }\n    q=b/(pow(2,k));\n    if (q==(pow(2,k+1)-1)) return 1;\n    else return 0;\n}\nint main()\n{\n    int n,i;\n    scanf(\"%d\" ,&n);\n    for (i=n;i>0;i++)\n    {\n        if (n%i==0 && beu(i)==1)\n        {printf(\"%d\" ,i);\n        break;}\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "11b5b8f7ab1b1126608dafecc8147545", "src_uid": "339246a1be81aefe19290de0d1aead84", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint cmp(const void *a,const void *b)\n{\n\treturn *(int *)a - *(int *)b;\n}\n\nint max(int a,int b)\n{\n\tif(a>b)\n\t\treturn a;\n\treturn b;\n}\n\n\nint main()\n{\n\tint i,n,a[105],j;\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\",&a[i]);\n\t}\n\tif(a[0]==3)\n\t{\n\t\tprintf(\"NO\\n\");\n\t\treturn 0;\n\t}\n\tint k,l=0,val=1;\n\tint count[4]={0};\n\tcount[a[0]]=1;\n\tcount[3]=1;\n\tfor(i=1;i<n;i++)\n\t{\n\t\tfor(j=1;j<=3;j++)\n\t\t{\n\t\t\tif(count[j]==0)\n\t\t\t{\n\t\t\t\tif(a[i]==j)\n\t\t\t\t{\n\t\t\t\t\tval=0;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tk=j;\n\t\t\t\t}\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tif(a[i]!=j)\n\t\t\t\t{\n\t\t\t\t\tl=j;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(val!=0)\n\t\t{\n\t\t\tcount[l]=0;\n\t\t\tcount[k]=1;\n\t\t}\n\t}\n\tif(val==0)\n\t\tprintf(\"NO\\n\");\n\telse\n\t\tprintf(\"YES\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7490601b8e12304bc96a0e4db477aacd", "src_uid": "339246a1be81aefe19290de0d1aead84", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    long int n,k=0,i,c,d=0;\n    scanf(\"%ld\",&n);\n    while(1)\n    {\n        if(pow(2,k)>=n)\n        {\n            c=k;\n            break;\n        }\n        k++;\n    }\n    for(i=c;i>=0;i--)\n    {\n        d=(pow(2,i)-1)*pow(2,i-1);\n        if(n%d==0)\n        {\n            break;\n        }\n    }\n    printf(\"%ld\",d);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c9e871f2f86fc8d93380d62ae1d29056", "src_uid": "339246a1be81aefe19290de0d1aead84", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "\tint num, largenum,i;\n\tscanf(\"%d\",&num);\n\tfor(int i=1;i<num;i++){\n\t\tint find = (pow(2,i)-1) * pow(2,i-1);\n\t\tif(find<num){\n\t\t\tif(num%num==0){\n\t\t\t\tlargenum=find;\n\t\t\t}\n\t\t}else{\n\t\t\tbreak;\n\t\t}\n\t}\n\tprintf(\"%d\",largenum);", "lang_cluster": "C", "compilation_error": true, "code_uid": "2ac60c141fccb4326a5b187544cbd97a", "src_uid": "339246a1be81aefe19290de0d1aead84", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include<math.h>\nlong long uocdep(int n) {\n\tint beauty;\n\tif (n % 2 != 0) return 1;\n\tint chantren = floor(((log(n) + log(2))*1.0) / (2 * log(2)))+1;\n\tfor (int i = chantren; i >= 0; i--) {\n\t\tbeauty = (pow(2, i) - 1)*pow(2, i - 1);\n\t\tif (n%beauty == 0) return beauty;\n\t}\n}\nint main() {\n\tint n;\n\tscanf_s(\"%d\", &n);\n\tlong long dapan = uocdep(n);\n\tprintf(\"%I64d\", dapan);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "05f809fee21bc045b8910d415cefd961", "src_uid": "339246a1be81aefe19290de0d1aead84", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long k;\n    scanf(\"%lld\",&k);\n    char c[10]=\"s\";\n    char s[15]=\"codeforces\";\n    k=k-1;\n    printf(\"%s\",s);\n    while(k--)\n    {\n        printf(\"%c\",'s');\n    }\n    printf(\"\\n\");\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "14f1eb9ef1d5b2e7c287185e0b00dec9", "src_uid": "8001a7570766cadcc538217e941b3031", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<string.h>\nint main()\n{\n    long long k,a;\n    int i,j,t=0;\n    scanf(\"%llu\",&k);\n    int q[10];\n    char p[11]=\"codeforces\";\n    int put=0;\n    for(i=0;i<10;i++)\n    {\n        q[i]=1;\n    }\n    while(1)\n    {\n        a=1;\n        for(i=0;i<10;i++)\n        {\n            a*=q[i];\n        }\n        if(a>=k)\n        {\n            break;\n        }\n        q[a]++;\n        a++;\n    }\n    for(i=0;i<10;i++)\n    {\n        for(j=0;j<q[i];j++)\n        {\n            printf(\"%c\",p[i]);\n        }\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "2b51c875aa512552da82ffdf83f03730", "src_uid": "8001a7570766cadcc538217e941b3031", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(void)\n{\n\tunsigned long long k; //k\u7684\u4e2a\u6570\u662f2\u768416\u6b21\u65b9\n\tunsigned long long asn;\n\tscanf_s(\"%llu\", &k);\n\tchar s[10] = \"codeforces\";\n\tchar q[11]; // \u50a8\u5b58codeforces\u6bcf\u4e2a\u5b57\u7b26\u7684\u91cd\u590d\u6b21\u6570\n\t//\u6bcf\u4e2a\u5b57\u7b26\u81f3\u5c11\u8981\u91cd\u590d\u51fa\u73b0\u4e00\u6b21\n\tint ten = 0;\n\tfor (int i = 0; i < 10; i++)\n\t\tq[i] = 1; \n\twhile (1)\n\t{\n\t\tasn = 1;\n\t\tfor (int i = 0; i < 10; i++)\n\t\t\tasn = asn * q[i];\n\t\tif (asn >= k)\n\t\t\tbreak;\n\t\tif (ten == 10)\n\t\t\tten = 0;\n\t\tq[ten]++;\n\t\tten++;\n\t}\n\tfor (int i = 0; i < 10; i++)\n\t\tfor (int j = 0; j < q[i]; j++)\n\t\t\tprintf(\"%c\", s[i]);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "83aa697b55ea8ce5bc38f055239083a0", "src_uid": "8001a7570766cadcc538217e941b3031", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    long long int n;\n    scanf(\"%lld\",&n);\n    int a[10];\n    for(int i=0;i<10;i++)\n      a[i]=1;\n    char substr[11]=\"codeforces\";\n    int k=1;\n    long long int p=0;\n    while(k<n)\n    {\n        k/a[p%10];\n        a[p%10]++;\n        k*=a[p%10];\n        p++\n        \n    }\n    for(int i=0;i<10;i++)\n      for(int j=0;j<a[i];j++)\n        printf(\"%c\",substr[i]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a62d4c03de356f9b03c9c8b2bc3610b9", "src_uid": "8001a7570766cadcc538217e941b3031", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#include<math.h>\n\nint main()\n{\n\tlong long int k,i,j,a,b,l,flag=0;\n\tscanf(\"%lld\",&k);\n\tchar arr[15] =\"codeforces\";\n\t// for(i=0;i<10;i++)\n\t// {\n\t// \tprintf(\"%c-%lld\\n\",arr[i],i);\n\t// }\n\ta=1,b=2;\n\twhile(1)\n\t{\n\t\tfor(i=0;i<=10;i++)\n\t\t{\n\t\t\tif(long long int(pow(b,i)*pow(a,10-i))>=k)\n\t\t\t{\n\t\t\t\tflag=1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(flag==1)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t\ta++;\n\t\tb++;\n\t}\n\tfor(j=1;j<=i;j++)\n\t{\n\t\tfor(l=1;l<=b;l++)\n\t\t{\n\t\t\tprintf(\"%c\",arr[j-1]);\n\t\t}\n\t}\n\tfor(j=i+1;j<=10;j++)\n\t{\n\t\tfor(l=1;l<=a;l++)\n\t\t{\n\t\t\tprintf(\"%c\",arr[j-1]);\n\t\t}\n\t}\n\tprintf(\"\\n\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1719f86f6c62610bf62862891728fd42", "src_uid": "8001a7570766cadcc538217e941b3031", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define mod 1000000007\ntypedef long long int ll;\nll expo(ll x,ll k)\n{\n\tll result=1;\n\twhile(k>0)\n\t{\n\t\tif(k%2==1)\n\t\t\tresult=result*x%mod;\n\t\tx=x*x%mod;\n\t\tk=k/2;\n\t}\n\treturn result;\n}\nint main()\n{\n\tlong long int x,k,ans;\n\tscanf(\"%lld%lld\",&x,&k);\n\tif(x==0)\n\t\treturn 0;\n\tx=x%mod;\n\tx=(2*x-1)%mod;\n\tk=expo(2,k);\n\tprintf(\"%lld\\n\",(x*k+1)%mod);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "15fade1a09fd1a63802bb9d4849d10fd", "src_uid": "e0e017e8c8872fc1957242ace739464d", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define MOD 1000000007\n\nlong long int modexp(long long int b, long long int e) {\n\tlong long int i = 1;\n\twhile (e != 0) {\n\t\tif (e&1) {\n\t\t\ti = (i*b) % MOD;\n\t\t}\n\t\te >>= 1;\n\t\tb = (b*b) % MOD;\n\t}\n\treturn i;\n}\n\nint main(void) {\n\tlong long int x, k;\n\tscanf(\"%lld%lld\", &x, &k);\n\tx %= MOD;\n\n\tlong long int exp = modexp(2, k);\n\tlong long int ans = (x * exp * 2) % MOD;\n\tans = (ans-exp+1) % MOD;\n\n\tif (ans < 0) {\n\t\tans += MOD;\n\t}\n\tprintf(\"%lld\\n\", ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "95774e1dcd5825ba6de37e96a18428d2", "src_uid": "e0e017e8c8872fc1957242ace739464d", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define MOD 1000000007\n\nlong long int modexp(long long int b, long long int e) {\n\tlong long int i = 1;\n\twhile (e != 0) {\n\t\tif (e&1) {\n\t\t\ti = (i*b) % MOD;\n\t\t}\n\t\te >>= 1;\n\t\tb = (b*b) % MOD;\n\t}\n\treturn i;\n}\n\nint main(void) {\n\tlong long int x, k;\n\tscanf(\"%lld%lld\", &x, &k);\n\tx %= MOD;\n\n\tif (x == 0) {\n\t\tprintf(\"%lld\\n\", x);\n\t}\n\n\tlong long int exp = modexp(2, k);\n\tlong long int ans = (x * exp * 2) % MOD;\n\tans = (ans-exp+1) % MOD;\n\n\tif (ans < 0) {\n\t\tans += MOD;\n\t}\n\tprintf(\"%lld\\n\", ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e7ba0093188554be79d3791b379b1107", "src_uid": "e0e017e8c8872fc1957242ace739464d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define ll long long\n#define MOD 1000000007\nll g_pow(ll k)\n{\n\tll x=2,e=1;\n\twhile(k)\n\t{\n\t\tif(k%2)\n\t\t{\n\t\t\te*=x;\n\t\t\te%=MOD;\n\t\t}\n\t\tk/=2;\n\t\tx*=x;\n\t\tx%=MOD;\n\t}\n\treturn e;\n}\nint main()\n{\n\tll x,k,res;\n\tscanf(\"%I64d%I64d\",&x,&k);\n\tx%=MOD;\n\tif(x==0)\n\t{\n\t\tprintf(\"0\");\n\t\treturn 0;\n\t}\n\tif(k==0)\n\t{\n\t\tres=2*x;\n\t\tif(res>MOD)\n\t\t\tres%=MOD;\n\t\tprintf(\"%I64d\",res);\n\t\treturn 0;\n\t}\n\tres=g_pow(k+1)*x-g_pow(k)+1+MOD;\n\tif(res>MOD)\n\t\tres%=MOD;\n\tprintf(\"%I64d\",res);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "072f64a28b9fdf907a7ea5a70421ebed", "src_uid": "e0e017e8c8872fc1957242ace739464d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define MOD 1000000007\nunsigned long long int power(unsigned long long int x, unsigned long long int y, long int p)\n{\n    unsigned long long int res = 1;      // Initialize result\n \n    x = x % p;  // Update x if it is more than or \n                // equal to p\n \n    while (y > 0)\n    {\n        // If y is odd, multiply x with result\n        if (y & 1)\n            res = (res*x) % p;\n \n        // y must be even now\n        y = y>>1; // y = y/2\n        x = (x*x) % p;  \n    }\n    return res;\n}\nint main()\n{\n    unsigned long long int x,k,a,b,c,d;\n    scanf(\"%llu %llu\",&x,&k);\n    if(x==0)\n    {\n        printf(\"0\");\n    }\n    else\n    {\n        if(k==0)\n        {\n            printf(\"%llu\",2*x);\n        }\n        else\n        {\n            a=power(2,k+1,MOD);\n            a=(a*(x%MOD))%MOD;\n            d=power(2,k,MOD);\n            d=(d-1)%MOD;\n            printf(\"%llu\",a-d);\n        }\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "facf307cc845679485d510ada8faae22", "src_uid": "e0e017e8c8872fc1957242ace739464d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int t,white,black,opposite;\n        scanf(\"%d%d\",&black,&white);\n        //Minimum of both ball goes to Aaquib's Points and remaining will make pair with Prashant as both play equally good\n        opposite=black<white?black:white;\n        printf(\"%d %d\\n\",black+white-1-opposite,opposite);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "84c917b0844d06f6b9710ac77c4b4969", "src_uid": "c8378e6fcaab30d15469a55419f38b39", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nmain(){\n\tlong int n,m;\n\tscanf(\"%ld%ld\",&n,&m);//n-->red m-->blue cubes\n\tif(n>m){\n\t\tprintf(\"%ld %ld\",n-1,m);\n\t}else{\n\t\tprintf(\"%ld %ld\",m-1,n);\n\t}\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8a616122cca874316a340635de851f78", "src_uid": "c8378e6fcaab30d15469a55419f38b39", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "main()\n{\n    int n,m;\n    scanf(\"%d%d\",&n,&m);\n    if(n>m)     printf(\"%d %d\\n\",n-1,m);\n    else    printf(\"%d %d\\n\",m-1,n);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b55c8ddbe0c7aa23add0b2fc94d3772f", "src_uid": "c8378e6fcaab30d15469a55419f38b39", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "main()\n{\n    int n,m;\n    scanf(\"%d%d\",&n,&m);\n    if(n>m)     printf(\"%d %d\\n\",n-1,m);\n    else    printf(\"%d %d\\n\",m-1,n);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7c3747d204f68e8aeea2af7507acf335", "src_uid": "c8378e6fcaab30d15469a55419f38b39", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    char a[100001];\n    int n,m,pet=0,vas=0,x,y,j=1,i;\n    scanf(\"%d%d\",&n,&m);\n     if(n<m&&n%2!=0)\n    a[0]='R';\n    else if(n<m&&n%2==0)\n    a[0]='B';\n    else if(m<n&&m%2!=0)\n    a[0]='B';\n    else\n    a[0]='R';\n    x=n;\n    y=m;\nfor(i=1;i<=n+m;)\n    {\n       if(x>0&&i%2!=0&&y>0)\n       {\n           if(a[j-1]=='R')\n           {\n               a[j++]='R';\n               x--;\n           }\n           else\n           {\n               a[j++]='B';\n               y--;\n           }\n       }\n\n       if(y>0&&i%2==0&&x>0)\n       {\n          if(a[j-1]=='B')\n          {\n              a[j++]='R';\n              x--;\n          }\n          else\n          {\n              a[j++]='B';\n              y--;\n          }\n       }\n\n       if(y==0&&x>0)\n       {\n           x--;\n           a[j++]='R';\n       }\n       if(x==0&&y>0)\n       {\n           y--;\n           a[j++]='B';\n       }\n       i++;\n    }\n    for(i=1;i<j;i++)\n   {\n       if(a[i]==a[i+1]&&i+1<j)\n       pet++;\n       if(a[i]!=a[i+1]&&i+1<j)\n       vas++;\n   }\n   printf(\"%d %d\",pet,vas);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d1f81bbb91ea3b554b7acf7e2875f212", "src_uid": "c8378e6fcaab30d15469a55419f38b39", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<string.h>\n#include<stdio.h>\nint main()\n{\n\tchar A[101];\n\tscanf(\"%s\",A);\n\tint len=strlen(A);\n\tint falg=0;\n\tfor(int i=0;i<len-2;++i)\n\t{\n\t\tif(A[i]=='A' && A[i+1]=='B' && A[i+2]=='C')\n\t\t{\n\t\t\tflag=1;\n\t\t\tbreak;\n\t\t}\n\t\tif(A[i]=='B' && A[i+1]=='A' && A[i+2]=='C')\n\t\t{\n\t\t\tflag=1;\n\t\t\tbreak;\n\t\t}\n\t\tif(A[i]=='C' && A[i+1]=='B' && A[i+2]=='A')\n\t\t{\n\t\t\tflag=1;\n\t\t\tbreak;\n\t\t}\n\t\tif(A[i]=='A' && A[i+1]=='C' && A[i+2]=='B')\n\t\t{\n\t\t\tflag=1;\n\t\t\tbreak;\n\t\t}\n\t\tif(A[i]=='B' && A[i+1]=='C' && A[i+2]=='A')\n\t\t{\n\t\t\tflag=1;\n\t\t\tbreak;\n\t\t}\n\t\tif(A[i]=='C' && A[i+1]=='A' && A[i+2]=='B')\n\t\t{\n\t\t\tflag=1;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(flag==1)\n\t{\n\t\tprintf(\"Yes\");\n\t}\n\telse\n\t{\n\t\tprintf(\"No\");\n\t}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6de87bea4630297e748d236674c76320", "src_uid": "ba6ff507384570152118e2ab322dd11f", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\nint main()\n{\n    longi,flag=0;\n    char s[100];\n    scanf(\"%s\",s);\n    if(strlen<3)\n        printf(\"No\");\n    else{\n    for(i=0;i<strlen(s)-2;i++)\n    {\n        if(s[i]+s[i+1]+s[i+2]==198)\n            {\n             flag=1;\n             break;\n            }\n        else\n            flag=0;\n    }\n    if(flag==1)\n        printf(\"Yes\");\n    else\n        printf(\"No\");\n\n}\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "75a1905cf3754b5d005d975ea99ab341", "src_uid": "ba6ff507384570152118e2ab322dd11f", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\nint main()\n{\n    long i,flag=0;\n    char s[100];\n    scanf(\"%s\",s);\n    for(i=0;i<strlen(s);i++)\n    {\n        if(s[i]=='.')\n            s[i]=' '\n    }\n    if(strlen(s)<3)\n        printf(\"No\");\n    else{\n    for(i=0;i<strlen(s)-2;i++)\n    {\n        if(s[i]+s[i+1]+s[i+2]==198)\n            {\n             flag=1;\n             break;\n            }\n        else\n            flag=0;\n    }\n    if(flag==1)\n        printf(\"Yes\");\n    else\n        printf(\"No\");\n\n}\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "106326e4cdcb954b97dc7fc30febd8eb", "src_uid": "ba6ff507384570152118e2ab322dd11f", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    char s[100];\n    int i,j,k=0;\n    scanf(\"%s\",s);\n\n    for(i=0; s[i]!='\\0'; i++)\n    {\n       for(j=i; j<3; j++)\n       {\n           if(s[i]!='.' && s[i+1]!='.' && s[i+2]!='.')\n           {\n               if(s[i]!=s[i+1] && s[i+1]!=s[i+2] && s[i+2]!=s[i])\n               {\n                   k=1;\n               }\n           }\n       }\n    }\n\n    if(k==1)\n        printf(\"YES\\n\");\n    else\n        printf(\"NO\\n\");\n\n    return 0;", "lang_cluster": "C", "compilation_error": true, "code_uid": "b9f98593b300e1004447c1554106f8fd", "src_uid": "ba6ff507384570152118e2ab322dd11f", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main() {\n    char str[101];\n    scanf(\"%s\",&st);\n    char *sa=strstr(st,\"ABC\"),*sb=strstr(st,\"ACB\"),*sc=strstr(st,\"BCA\"),*sd=strstr(st,\"BAC\"),*se=strstr(st,\"CAB\"),*sf=strstr(st,\"CBA\");\n    if(sa!=NULL||sb!=NULL||sc!=NULL||sd!=NULL||se!=NULL||sf!=NULL)\n        printf(\"Yes\");\n    else\n        printf(\"No\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2e8e4e4242658d6acf79e4cf08f4bc85", "src_uid": "ba6ff507384570152118e2ab322dd11f", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n\tint i,n,k,j=0;\n\tscanf(\"%d %d\",&n,&k);\n\tint n1=n;\n\tint a[n];\n\tfor(i=2;i<=sqrt(n);i++){\n\t\twhile(n%i==0){\n\t\t\ta[j]=i;\n\t\t//\tprintf(\"%d \",a[j]);\n\t\t\tn/=i;j++;\n\t\t}\n\t}\n\t\tif(n>1){\n\t\t\ta[j]=n;\n\t\t\t//printf(\"%d \",a[j]);\n\t\t\tn/=i;j++;\n\t\t}\n\t//printf(\"\\n%d\\n\",j);\n\tif(k>j){\n\t\tprintf(\"-1\\n\");return 0;\n\t}\n    int prod=1;\n\tfor(i=0;i<k-1;i++){\n\t\tprintf(\"%d \",a[i]);\n\t\tprod*=a[i];\n\t\t\n\t}\nprintf(\"%d \",n1/prod);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "00c53703d3f78f02a670bc054494ab1c", "src_uid": "bd0bc809d52e0a17da07ccfd450a4d79", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint *k_Factorization(int k,int n,int try);\nvoid swap(int* product,int try);\n\n\nint main(){\n\tlong int i,k,n;\n\tlong int *result;\n\tscanf(\"%d %d\",&n,&k);\n\tif(k==2){\n\t\tprintf(\"%d %d\",2,n/2);\n\t\treturn 0;\n\t}\n\tresult=k_Factorization(k,n,0);\n\tif(result == NULL){\n\t\tprintf(\"%d\\n\",-1);\n\t\treturn 0;\n\t}\n\n\tfor(i=0;i<k;i++){\n\t\tprintf(\"%d \", *++result);\n\t}\n\treturn 0;\n}\n\nint *k_Factorization(int k,int n,int try){\n\tlong int i,*product,*p;\n\tproduct=malloc((k+1)*sizeof(int));\n\tp=product;\n\t*p++=n; \n\tfor(i=2;i<=*product/2+1;i++){\n\t\tif(try==k && n==1){\n\t\t\t\t\t\t\treturn product;}\n\t\tif(try==k && n>1){n*=*product; swap(product,try); try--; p--; }\n\t\tif(try<=k && n<1){break;}\n\t\twhile(n%i==0){\n\t\t\t*p++=i;\n\t\t\tn/=i;\n\t\t\ttry++;\n\t\t}}\n\treturn NULL;\n\t\n\n\n}\n\nvoid swap(int* product,int try){\n\tlong int i,*p;\n\tp=product+1;\n\tfor(i=0;i<try;i++,p++){\n\t\tint tmp;\n\t\ttmp=*p;\n\t\t*p=*(p+1);\n\t\t*(p+1)=tmp;\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "86740d632ed6772cdfd4963eedaea418", "src_uid": "bd0bc809d52e0a17da07ccfd450a4d79", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n,k,i=0,j,l,x,c=0;\n    scanf(\"%d %d\",&n,&k);\n    int a[k];\n     x=a[0]=n;\n     while(i<k-1)\n    {\n        for(j=2;j<x;j++)\n        {\n            if(a[i]%j==0)\n            {\n                a[i+1]=a[i]/j;\n                a[i]=j;\n                x=a[i+1];\n                i++;\n                c=1;\n                break;\n            }\n            else\n                c=0;\n        }\n        if(c==0&&i<k-1)\n        {\n            printf(\"-1\");\n            break;}\n    }\n    if(i==k-1){\n    for(l=0;l<k;l++)\n    {\n        printf(\"%d \",a[l]);\n    }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "bbd4cfb455885e6952b6836a5daf01d8", "src_uid": "bd0bc809d52e0a17da07ccfd450a4d79", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#define T 100010\nint P[T];\nint siv();\nint main()\n{int a,b,c,i,k,n[100050],p=0;\n    scanf(\"%d %d\",&a,&b);i=2;k=0;\n  while(a>=1)\n  {\n      if(a%i==0)\n      {\n          a=a/i;k++;if(k==b){p++;if(a!=1)n[p]=a;else n[p]=i;if(p==b)break;}\n          else\n          {p++;n[p]=i;}\n      }\n      else i++;\n  }\n if(p<b)printf(\"-1\\n\");\n else {for(i=1;i<=b;i++)printf(\"%d \",n[i]);}\n\n}\nint siv ()\n{\n    int  i,j,k;\n    memset(P,0,sizeof(P));\n    for(i=2;i<=sqrt(T);i++)\n    {if(P[i]==0){\n        for(j=2;i*j<=T;j++)\n            P[i*j]=1;}\n    }P[1]=1;\n\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "28400ab010430cf50bacee313c49e52a", "src_uid": "bd0bc809d52e0a17da07ccfd450a4d79", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"new1\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/new1\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/new1\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t\t<Add option=\"-fexceptions\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.cpp\" />\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2ef62550b6c07a6f04cf166e55dbe042", "src_uid": "bd0bc809d52e0a17da07ccfd450a4d79", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nchar input[10000000],real[100000],point[10000];\nint main()\n{\n    int p,q,l,x,max,z,t,c,d,m;\n    scanf(\"%s\",input);\n    max=strlen(input);\n    int i,j,k;\n    z=0;\n    c=0;\n    t=0;\n    d=0;\n    l=0;\n    for(i=0;i<max;i++)\n    {\n        if(input[i]=='.')\n        {\n            z=1;\n\n        }\n        else if(input[i]=='e')\n        {\n            t=1;\n        }\n        else if(input[i]!='.'&&z==0)\n        {\n            real[c]=input[i];\n            c++;\n        }\n        else if(input[i]!='e'&&z==1&&t==0)\n        {\n            point[d]=input[i];\n            d++;\n        }\n        else\n        {\n            l=(input[i]-'0')+l*10;;\n        }\n\n    }\n    real[c]='\\0';\n    point[d]='\\0';\n    p=atoi(real);\n    printf(\"%d\",p);\n    int l1=strlen(point);\n    for(i=0;i<l1;i++)\n    {\n        if(i==l)\n        {\n            printf(\".%d\",(point[i]-'0'));\n        }\n        else\n            printf(\"%d\",(point[i]-'0'));\n    }\n    if(l1<l)\n    {\n        for(i=l1+1;i<=l;i++)\n        {\n            printf(\"0\");\n        }\n    }\n    printf(\"\\n\");\n\n\n        return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9b7ae6c1645e5a8eb7d5526a1dd92365", "src_uid": "a79358099f08f3ec50c013d47d910eef", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main ()\n{\n    int l,b,c,d,e,f,g,h,i,j;\n    char a[200];\n    gets(a);\n    l=strlen(a);\n    for(i=0;i<l;i++)\n    {\n        if(a[i]=='.')b=i;\n        if(a[i]=='e')c=i;\n    }\n    f=a[0];\n    if(f==48)\n    {\n        for(i=0;i<c;i++)\n        {\n            printf(\"%c\",a[i]);\n        }\n        return 0;\n    }\n    else\n    {\n        d=l-(c+1);\n        if(d==3)e=100;\n        else\n        {\n            f=a[c+1];\n            if(d==2)\n            {\n                g=a[c+2];\n                e=(f-48)*10+(g-48);\n            }\n            else\n            {\n                e=f-48;\n            }\n        }\n        h=c-b-1;\n        if(h>=e)\n        {\n            if(h>e)\n            {\n                for(i=0;i<b;i++)printf(\"%c\",a[i]);\n                for(i=b+1;i<=b+e;i++)printf(\"%c\",a[i]);\n                printf(\".\");\n                for(i=b+e+1;i<c;i++)printf(\"%c\",a[i]);\n                return 0;\n            }\n            else\n            {\n                for(i=0;i<b;i++)printf(\"%c\",a[i]);\n                for(i=b+1;i<c;i++)printf(\"%c\",a[i]);\n                return 0;\n            }\n        }\n        else\n        {\n            for(i=0;i<b;i++)printf(\"%c\",a[i]);\n            for(i=b+1;i<c;i++)printf(\"%c\",a[i]);\n            for(i=0;i<e-h;i++)printf(\"0\");\n            return 0;\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e0c85c82b77fe1cd755fbde57c1a2f53", "src_uid": "a79358099f08f3ec50c013d47d910eef", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\ntypedef signed char byte;\n#define REPEAT(token, num) for (token = 0; token < num; token++)\nstatic inline void POPQUEUE(void *arr, size_t length, size_t itemSize) { memmove(arr, arr+itemSize, length*itemSize); }\nstatic inline void REMOVEELEM(void *arr, size_t offset, size_t length, size_t itemSize) { memmove(arr+(offset*itemSize), arr+((offset+1)*itemSize), (length-offset)*itemSize); }\nstatic inline void REMOVEELEMS(void *arr, size_t offset, size_t numElems, size_t length, size_t itemSize) { memmove(arr+(offset*itemSize), arr+((offset+numElems)*itemSize), (length-offset)*itemSize); }\n//#define DEBUG\n#ifdef DEBUG\n#define PRINTF printf\n#else\n#define PRINTF(...)\n#endif\n\ntypedef long digit;\ntypedef long num_digits;\n\ndigit allDigits[200];\nnum_digits decimalPoint = 1, oldNumDigits, numDigits, numChars, power;\nchar string[200];\n\nint main() {\n    num_digits i;\n    char store;\n    \n    allDigits[0] = getchar()-'0', numDigits = 1;\n    getchar(); //period\n    while ((store = getchar()) != 'e') allDigits[numDigits++] = store-'0';\n    scanf(\"%li\", &power);\n    decimalPoint += power;\n    oldNumDigits = numDigits;\n    REPEAT(i, decimalPoint-oldNumDigits) allDigits[numDigits++] = 0;\n    if (decimalPoint == numDigits) numChars = numDigits;\n    else numChars = numDigits+1;\n    REPEAT(i, numChars) {\n        if (i == decimalPoint) putchar('.');\n        else putchar(allDigits[i-(i > decimalPoint)]+'0');\n    }\n    putchar('\\n');\n    \n    exit(0);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d966fbaaaaeea456f68b76d48413db86", "src_uid": "a79358099f08f3ec50c013d47d910eef", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define L 10\n\nint main() {\n    int a, b = 0;\n    char db[L];\n    int i;\n    for (i = 0; i < L; i++) {\n        db[i] = 'a';\n    }\n    while (~scanf(\"%d.%s\", &a, &db)) {\n        char d[L];\n        for (i = 0; i < L; i++) {\n            d[i] = 'a';\n        }\n        int j = 0, k = 0, num_len = 0;\n        while (db[j] != 'e') {\n            d[k] = db[j];\n            j++;\n            k++;\n            num_len++;\n        }\n        char b_temp[L];\n        int b_len = 0;\n        j++;\n        while (db[j] != 'a') {\n            b_temp[b_len] = db[j];\n            b_len++;\n            j++;\n        }\n        b_len -= 1;\n        k = 1;\n        for (i = b_len-1; i >= 0; i--) {\n            b += (b_temp[i] - '0') * k;\n            k *= 10;\n        }\n        if (d[0] == 0 && d[1] == 'a') {\n            printf(\"%d\", a);\n            for (i = 0; i < b; i++) {\n                printf(\"0\");\n            }\n            printf(\"\\n\");\n        }\n        else {\n            i = 0;\n            j = 0;\n            if (a == 0) {\n                if (b == 0) {\n                    printf(\"%d\", a);\n                }\n            }\n            else {\n                printf(\"%d\", a);\n            }\n            k = 0;\n            while (i < num_len && i < b) {\n                printf(\"%c\", d[i]);\n                i++;\n            }\n            if (i < num_len) {\n                printf(\".\");\n                while (i < num_len) {\n                    printf(\"%c\", d[i]);\n                    i++;\n                }\n            }\n            else if (i < b) {\n                while (i < b) {\n                    printf(\"0\");\n                    i++;\n                }\n            }\n            printf(\"\\n\");\n        }\n        return 0;\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "84ed84685b4c6d777c12802b24b5b38e", "src_uid": "a79358099f08f3ec50c013d47d910eef", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\ntypedef signed char byte;\n#define REPEAT(token, num) for (token = 0; token < num; token++)\n#define getchar getchar_unlocked\n#define putchar putchar_unlocked\nstatic inline void POPQUEUE(void *arr, size_t length, size_t itemSize) { memmove(arr, arr+itemSize, length*itemSize); }\nstatic inline void REMOVEELEM(void *arr, size_t offset, size_t length, size_t itemSize) { memmove(arr+(offset*itemSize), arr+((offset+1)*itemSize), (length-offset)*itemSize); }\nstatic inline void REMOVEELEMS(void *arr, size_t offset, size_t numElems, size_t length, size_t itemSize) { memmove(arr+(offset*itemSize), arr+((offset+numElems)*itemSize), (length-offset)*itemSize); }\n//#define DEBUG\n#ifdef DEBUG\n#define PRINTF printf\n#else\n#define PRINTF(...)\n#endif\n\ntypedef long digit;\ntypedef long num_digits;\n\ndigit allDigits[200];\nnum_digits decimalPoint = 1, oldNumDigits, numDigits, numChars, power;\nchar string[200];\n\nint main() {\n    num_digits i;\n    char store;\n    \n    allDigits[0] = getchar()-'0', numDigits = 1;\n    getchar(); //period\n    while ((store = getchar()) != 'e') allDigits[numDigits++] = store-'0';\n    scanf(\"%li\", &power);\n    decimalPoint += power;\n    oldNumDigits = numDigits;\n    REPEAT(i, decimalPoint-oldNumDigits) allDigits[numDigits++] = 0;\n    if (decimalPoint == numDigits) numChars = numDigits;\n    else numChars = numDigits+1;\n    REPEAT(i, numChars) {\n        if (i == decimalPoint) putchar('.');\n        else putchar(allDigits[i-(i > decimalPoint)]+'0');\n    }\n    putchar('\\n');\n    \n    exit(0);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a14bd4f9ce7a1c3fdbfaaaea6820d7e0", "src_uid": "a79358099f08f3ec50c013d47d910eef", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "/* https://codeforces.com/contest/1204/submission/59190290 (Dukkha) */\n#include <stdio.h>\n#include <string.h>\n\n#define N 100\n\nint main() {\n\tstatic char s[N + 1];\n\tint n, i, zero;\n\t\n\tscanf(\"%s\", s);\n\tn = strlen(s);\n\tzero = 1;\n\tfor (i = 1; i < n; i++)\n\t\tif (s[i] != '0') {\n\t\t\tzero = 0;\n\t\t\tbreak;\n\t\t}\n\tcnt = (n - 1) / 2 + 1;\n\tif (n % 2 != 0 && zero)\n\t\tcnt--;\n\tprintf(\"%d\\n\", cnt);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e6205a64d5d3445467e237b211fcb3cf", "src_uid": "d8ca1c83b431466eff6054d3b422ab47", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n   int i=0,k=1,h,len,flag=0;\n  char a[101],b;\n  scanf(\"%s\",&a);\n  while(a[i]!=NULL)\n  {\n      i++;\n  }\n  len = i\n  for(k=0;k<=i;k++)\n  {\n      if((k!=0)&&(a[k]=='1'))\n      { \n          flag=1;\n          break;\n      }\n     \n   \n\n  }\n  if((i==1)&&a[0]=='1')\n    len=0;\n  if((i==1)&&a[0]=='0')\n    len=0;\n  if(flag==1)\n  len++;\nprintf(\"%d\",len/2);\n  return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5c2a136b62b8aa5d82e9dce5c4006879", "src_uid": "d8ca1c83b431466eff6054d3b422ab47", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "/* https://codeforces.com/contest/1204/submission/59190290 (Dukkha) */\n#include <stdio.h>\n#include <string.h>\n\n#define N 100\n\nint main() {\n\tstatic char s[N + 1];\n\tint n, i, zero;\n\t\n\tscanf(\"%s\", s);\n\tn = strlen(s);\n\tzero = 1;\n\tfor (i = 1; i < n; i++)\n\t\tif (cc[i] != '0') {\n\t\t\tzero = 0;\n\t\t\tbreak;\n\t\t}\n\tcnt = (n - 1) / 2 + 1;\n\tif (n % 2 != 0 && zero)\n\t\tcnt--;\n\tprintf(\"%d\\n\", cnt);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "44e437c1375e205befacf95572c99e05", "src_uid": "d8ca1c83b431466eff6054d3b422ab47", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "i,w;main(c){while(c=getchar(),~c)w|=c*(i++>0);printf(\"%d\"i/2-(~i&1&~w));}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cfeb8cb861fb8efac05ce9b22b848aa8", "src_uid": "d8ca1c83b431466eff6054d3b422ab47", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\n\nint main(void)\n{\n    char *binary = malloc(sizeof(char) * 200);\n    scanf(\"%s\", binary);\n\n    int lenb = strlen(binary);\n    __int128 decimal = 0;\n    for (int i = 0; i < lenb; i++)\n    {\n        decimal += (binary[i] - '0') * pow(2, (lenb-1) - i);\n    }\n\n    for (int i = 0; i < 50; i++)\n    {\n        if (decimal <= pow(4, i))\n        {\n            printf(\"%i\\n\", i);\n            break;\n        }\n    }\n\n    free(binary);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "77c8d0211046ff60c446ceb989877c07", "src_uid": "d8ca1c83b431466eff6054d3b422ab47", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define max 20\n\nvoid sort(char[], int, int);\nvoid merge(char[], int, int, int);\n\nvoid swap(char[], int, int);\n\nint main()\n{\n\tchar a[max], b[max];\n\t\n\tscanf(\"%[^\\n]%*c%[^\\n]%*c\", a, b);\n\t\n\tint la = strlen(a), lb = strlen(b);\n\t\n\tsort(a, 0, la - 1);\n\t\n\tif(la < lb)\n\t{\n\t\tputs(a);\n\t\treturn 1;\n\t}\n\t\n\tint n = la;\n\tchar s[n + 1];\n\ts[n] = 0;\n\t\n\tfor(int i = 0; i < n; i++)\n\t{\n\t\tint j = i;\n\t\twhile(a[j] > b[i])\n\t\t\tj++;\n\t\t\n\t\tif(a[j] < b[i])\n\t\t{\n\t\t\tswap(a, i, j);\n\t\t\t\n\t\t\tsort(a, i + 1, n - 1);\n\t\t\tputs(a);\n\t\t\t\n\t\t\treturn 2;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tfor(int k = 0; k < i; k++)\n\t\t\t\ts[k] = a[k];\n\t\t\t\n\t\t\ts[i] = a[j], s[j] = a[i];\n\t\t\t\n\t\t\tfor(int k = n - 1; k > i; k--)\n\t\t\t{\n\t\t\t\tif(k != j)\n\t\t\t\t\ts[(n - 1) - k + (i + 1)] = a[k];\n\t\t\t}\n\t\t\t\n\t\t\tif(strcmp(s, b) < 0)\n\t\t\t\tswap(a, i, j);\n\t\t\telse\n\t\t\t{\n\t\t\t\twhile(a[j] == b[i])\n\t\t\t\t\tj++;\n\t\t\t\t\n\t\t\t\tswap(a, i, j);\n\t\t\t\t\n\t\t\t\tsort(a, i + 1, n - 1);\n\t\t\t\tputs(a);\n\t\t\t\t\n\t\t\t\treturn 3;\n\t\t\t}\n\t\t}\n\t\tsort(a, i + 1, n - 1);\n\t}\n\t\n\tputs(a);\n}\n\nvoid swap(char a[], int i, int j)\n{\n\tint temp = a[i];\n\ta[i] = a[j];\n\ta[j] = temp;\n}\n\nvoid sort(char a[], int p, int r)\n{\n\tif(p < r)\n\t{\n\t\tint q = (p + r) / 2;\n\t\t\n\t\tsort(a, p, q);\n\t\tsort(a, q + 1, r);\n\t\t\n\t\tmerge(a, p, q, r);\n\t}\n}\n\nvoid merge(char a[], int p, int q, int r)\n{\n\tint l1 = q - p + 1, l2 = r - q;\n\tchar b[l1 + 1], c[l2 + 1];\n\t\n\tfor(int i = 0; i < l1; i++)\n\t\tb[i] = a[p + i];\n\tfor(int j = 0; j < l2; j++)\n\t\tc[j] = a[q + 1 + j];\n\t\t\n\tb[l1] = c[l2] = '0' - 1;\n\t\n\tint i = 0, j = 0;\n\t\n\tfor(int k = p; k <= r; k++)\n\t{\n\t\tif(b[i] > c[j])\n\t\t{\n\t\t\ta[k] = b[i];\n\t\t\ti++;\n\t\t}\n\t\telse\n\t\t{\n\t\t\ta[k] = c[j];\n\t\t\tj++;\n\t\t}\n\t}\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0a64109310db6497ba5745e24622a14a", "src_uid": "bc31a1d4a02a0011eb9f5c754501cd44", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "//Code by 27.\n#include<cstdio>\n#include<iostream>\n#include<algorithm>\n#include<string>\n#include<math.h>\n#include<vector>\n#include<queue>\n#include<map>\n#include<stack>\n#include<fstream>\n#include<stdlib.h>\n#include<set>\n#include<climits>\n#include<cmath>  \n#include<memory.h> \n#include<sstream>\n#include<time.h>\nusing namespace std;\nconst unsigned long long BIGEST=1000000000000000000+1000000000000000000;\nconst long long BIGER=1000000000000000000;\nconst int BIG=1000000000;\nconst int MOD=19260817;\nbool f[20];\nstring st1,st2;\nstring mn=\"\";\nbool cmp(char &a,char &b)\n{\n\treturn a>b;\n}\nint ypa(int k,string st)\n{\n\t//cout<<k<<\" \"<<st<<endl;\n\tif(st<mn)return 0;\n\tif(k==st1.size())\n\t{\n\t\tmn=st;\n\t\treturn 0;\n\t}\n\tfor(int i=0;i<st1.size();i++)\n\t{\n\t\tif(!f[i]&&st+st1[i]<=st2)\n\t\t{\n\t\t\tf[i]=1;\n\t\t\typa(k+1,st+st1[i]);\n\t\t\tf[i]=0;\n\t\t}\n\t}\n}\nint main()\n{\n\tcin>>st1>>st2;\n\tif(st1.size()<st2.size())\n\t{\n\t\tsort(st1.begin(),st1.end(),cmp);\n\t\tcout<<st1;\n\t\treturn 0;\n\t}\n\tsort(st1.begin(),st1.end(),cmp);\n\typa(0,\"\");\n\tcout<<mn;\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0a9ef5eb33930e821293d7760a5e2f49", "src_uid": "bc31a1d4a02a0011eb9f5c754501cd44", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "\n#include <stdio.h>\nunsigned __int64 ipow(unsigned long long int base, unsigned __int64 exp)\n{\n\tunsigned __int64 result = 1ULL;\n\twhile (exp)\n\t{\n\t\tif (exp & 1)\n\t\t{\n\t\t\tresult *= base;\n\t\t}\n\t\texp >>= 1;\n\t\tbase *= base;\n\t}\n\treturn result;\n}\nint main()\n{\n\tunsigned __int64 b = 0, a_length = 0, b_length = 0;\n\tchar temp;\n\tstatic unsigned __int64 freq[10];\n\twhile (scanf_s(\"%c\", &temp, 1))\n\t{\n\t\tif (temp == 10)\n\t\t\tbreak;\n\t\tfreq[temp - '0'] ++;\n\t\ta_length++;\n\t}\n\twhile (scanf_s(\"%c\", &temp, 1))\n\t{\n\t\tif (temp == 10)\n\t\t\tbreak;\n\t\tb += (unsigned __int64)(temp - '0') * ipow(10, b_length);\n\t\tb_length++;\n\t}\n\tif (b_length > a_length)\n\t\tb = ipow(10, a_length) - 1;\n\tint flag = 0;\n\tint flag2 = 0;\n\tunsigned __int64 num = 0;\n\tint first = -1;\n\tint second = -1;\n\tdo \n\t{\n\t\tflag2 = 0;\n\t\tif (first == -1)\n\t\t{\n\t\t\tfirst = b % 10;\n\t\t\tcontinue;\n\t\t}\n\t\telse if (second == -1)\n\t\t\tsecond = b % 10;\n\t\tfor (int i = 9; i >= 0; i--)\n\t\t{\n\t\t\tif ((flag == 1 || i <= first) && freq[i] > 0)\n\t\t\t{\n\t\t\t\tfreq[i] --;\n\t\t\t\tif (i < first)\n\t\t\t\t\tflag = 1;\n\t\t\t\tif (flag == 0)\n\t\t\t\t{\n\t\t\t\t\tfor (int p = 9; p >= 0; p--)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (p <= second && freq[p] > 0)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tflag2 = 1;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif (flag2 == 0)\n\t\t\t\t\t{\n\t\t\t\t\t\tfreq[i] ++;\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tfirst = second;\n\t\t\t\tsecond = -1;\n\t\t\t\tprintf(\"%i\", i);\n\t\t\t\tnum++;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t} while (b /= 10);\n\twhile (a_length - num > 0)\n\t{\n\t\tnum++;\n\t\tfor (int i = 9; i >= 0; i--)\n\t\t{\n\t\t\tif (freq[i] > 0)\n\t\t\t{\n\t\t\t\tfreq[i] --;\n\t\t\t\tprintf(\"%i\", i);\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "318a187fd6581bafb5641c93d7f2c460", "src_uid": "bc31a1d4a02a0011eb9f5c754501cd44", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n#include <algorithm>\n#include <vector>\n\nusing namespace std;\n\nbool compare(size_t a, size_t b) { return a > b; }\n\nsize_t find_max_index(vector<size_t> a, size_t v)\n{\n    size_t i = 0, m = 0;\n\n    for (size_t j = 0; j < a.size(); ++j) {\n        if (a[j] <= v && a[j] > m) {\n            i = j;\n            m = a[j];\n        }\n    }\n\n    return i;\n}\n\nint main()\n{\n    vector<size_t> a, b;\n\n    char c = '0';\n    while (cin.get(c) && c != '\\n') {\n        a.push_back(c - '0');\n    }\n    while (cin.get(c) && c != '\\n') {\n        b.push_back(c - '0');\n    }\n\n    vector<size_t>::iterator it;\n    for (it = a.begin(); it != a.end(); ++it) {\n        cout << *it << \" \";\n    }\n    cout << endl;\n\n\n    sort(a.begin(), a.end(), compare);\n\n    cout << a.size() << b.size() << endl;\n    if (b.size() > a.size()) {\n        vector<size_t>::iterator it;\n        for (it = a.begin(); it != a.end(); ++it) {\n            cout << *it;\n        }\n        cout << endl;\n    } else if (b.size() == a.size()) {\n        vector<size_t> o;\n        bool q = true;\n\n        vector<size_t>::iterator it;\n        for (it = b.begin(); it != b.end(); ++it) {\n            if (q && a.size()) {\n                size_t i = find_max_index(a, *it);\n\n                q = a[i] == *it;\n                o.push_back(a[i]);\n                a.erase(a.begin() + i);\n            } else {\n               o.insert(o.end(),a.begin(),a.end());\n               break;\n            }\n        }\n\n        for (it = o.begin(); it != o.end(); ++it) {\n            cout << *it << \" \";\n        }\n        cout << endl;\n    } else {\n        cout << \"whaaaa\" << endl;\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4dbb711796842b27b3a817abff6e7bd8", "src_uid": "bc31a1d4a02a0011eb9f5c754501cd44", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "\n#include <stdio.h>\nunsigned __int64 ipow(int base, int exp)\n{\n\tunsigned __int64 result = 1ULL;\n\twhile (exp)\n\t{\n\t\tif (exp & 1)\n\t\t{\n\t\t\tresult *= (unsigned __int64)base;\n\t\t}\n\t\texp >>= 1;\n\t\tbase *= base;\n\t}\n\treturn result;\n}\nint main()\n{\n\tunsigned __int64 b = 0, a_length = 0, b_length = 0;\n\tchar temp;\n\tstatic unsigned __int64 freq[10];\n\twhile (scanf_s(\"%c\", &temp, 1))\n\t{\n\t\tif (temp == 10)\n\t\t\tbreak;\n\t\tfreq[temp - '0'] ++;\n\t\ta_length++;\n\t}\n\twhile (scanf_s(\"%c\", &temp, 1))\n\t{\n\t\tif (temp == 10)\n\t\t\tbreak;\n\t\tb += (unsigned __int64)(temp - '0') * ipow(10, b_length);\n\t\tb_length++;\n\t}\n\tif (b_length > a_length)\n\t\tb = ipow(10, a_length) - 1;\n\tint flag = 0;\n\tint num = 0;\n\tdo \n\t{\n\t\tnum++;\n\t\tfor (int i = 9; i >= 0; i--)\n\t\t{\n\t\t\tif ((flag == 1 || i <= b % 10) && freq[i] > 0)\n\t\t\t{\n\t\t\t\tif (i < b % 10)\n\t\t\t\t\tflag = 1;\n\t\t\t\tfreq[i] --;\n\t\t\t\tprintf(\"%i\", i);\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t} while (b /= 10);\n\twhile (a_length - num > 0)\n\t{\n\t\tnum++;\n\t\tfor (int i = 9; i >= 0; i--)\n\t\t{\n\t\t\tif (freq[i] > 0)\n\t\t\t{\n\t\t\t\tfreq[i] --;\n\t\t\t\tprintf(\"%i\", i);\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0669b5cc4d0e864b9d1fd8f152513fd0", "src_uid": "bc31a1d4a02a0011eb9f5c754501cd44", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,x,count=0,d;\n    scanf(\"%d %d\",&n,&x);\n    int a[n],i,j,temp,mid;\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n     for(i=0;i<n-1;i++)\n    {\n        mid=i;\n        for(j=i+1;j<n;j++)\n        {\n            if(a[mid]>a[j])\n            mid=j;\n        }\n        if(mid!=i)\n        {\n            temp=a[mid];\n            a[mid]=a[i];\n            a[i]=temp;}\n}\nfor(i=0;i<n;i++)\n{\nif(a[i]<=x)\ncount++;\n}\nif(count>0)\n{\n    x-count=d;\n    if(d<0)\n    d=-d;\n\nprintf(\"%d\",d);}\nelse\nprintf(\"0\");\nreturn 0;\n}\n\n\n\n        ", "lang_cluster": "C", "compilation_error": true, "code_uid": "64e6e92b8fcf224fbcbce68a8af2adb2", "src_uid": "21f579ba807face432a7664091581cd8", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    int cnt=0;\n    scanf(\"%d\",&n);\n    int arr[n];\n    int mex;\n    scanf(\"%d\",&mex)\n    for(int i=0; i<n; i++)\n    {\n        scanf(\"%d\",&arr[i]);\n    }\n    for(int j=0; j<mex; j++)\n    {\n        for(int i=0; i<n; i++)\n        {\n        if(arr[i]>=j)\n        break;\n        if(arr[i]!=j)\n        cnt++;\n        }\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "aa7d1a8418e7d48685fcd05e6145b424", "src_uid": "21f579ba807face432a7664091581cd8", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint mian()\n{\n\tint a,b;\n\tscanf(\"%d %d\",&a,&b);\n\tprintf(\"%d\\n\",a + b);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9acd8da1cd5d947c6bf6a144632762ba", "src_uid": "21f579ba807face432a7664091581cd8", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint n, x, temp, i, count, flag;\n\tscanf(\"%d %d\", &n, &x)\n\tflag = count = 0;\n\tfor (i = 0; i < n; i++) {\n\t\tscanf(\"%d\", &temp);\n\t\tif (temp < x)  count++;\n\t\tif (temp == x) flag = 1;\n\t}\n\tprintf(\"%d\\n\", flag ? x - count + 1 : x - count);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "41900513d38d4f57b220de0433cc8f03", "src_uid": "21f579ba807face432a7664091581cd8", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,x,count=0;\n    scanf(\"%d %d\",&n,&x);\n    int a[n],i,j,temp,mid;\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n     for(i=0;i<n-1;i++)\n    {\n        mid=i;\n        for(j=i+1;j<n;j++)\n        {\n            if(a[mid]>a[j])\n            mid=j;\n        }\n        if(mid!=i)\n        {\n            temp=a[mid];\n            a[mid]=a[i];\n            a[i]=temp;}\n}\nfor(i=0;i<n;i++)\n{\nif(a[i]<=x)\ncount++;\n}\nif(count>0)\n{\n    if(x-count<0)\n    x-count=-(x-count);\n\nprintf(\"%d\",x-count);}\nelse\nprintf(\"0\");\nreturn 0;\n}\n\n\n\n        ", "lang_cluster": "C", "compilation_error": true, "code_uid": "94101bfdea0ac447fc71ca52052545d9", "src_uid": "21f579ba807face432a7664091581cd8", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#define STR_MAX 5\n\nvoid leerCant(int *);\nvoid cargarDatos(const int, int *);\nchar* check(const int, int *);\n\nint main(void){\n    int n;\n    leerCant(&n);\n    int vec[n];\n    cargarDatos(n, vec);\n    char * res=check(n, vec);\n    printf(\"%s\", res);\n    return 0;\n}\n\n\nvoid leerCant(int *n){\n    scanf(\"%d\", n);\n    return;\n}\n\n\nvoid cargarDatos(const int dim, int * v){\n    int i;\n    for (i=0;i<dim;i++){\n        scanf(\"%d\", (v+i));\n    }\n    return;\n}\n\n\nchar* check(const int dim, int *v){\n    int b=-1;\n    char * res;\n    res=(char *)malloc(sizeof(char)*STR_MAX);\n    if(*v%2==0 || *(v+(dim-1))%2==0){\n        strcpy(res, \"No\");\n    }\n    if(dim%2==0){\n        strcpy(res, \"No\");\n    }\n    if(dim%2!=0 && v[0]%2!=0 && v[n-1]%2!=0){\n        strcpy(res, \"Yes\");\n    }\n    return;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3553b01d196d3135d5b6425d37fe202c", "src_uid": "2b8c2deb5d7e49e8e3ededabfd4427db", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<cstdio>\n#include<algorithm>\n#include<cstring>\n#include<iostream>\n#include<cstdlib>\n#include<ctime>\n#include<cmath>\n\nusing namespace std;\n\n\n\n\nint main()\n{\n    int n,i,j;\n    int a[10000];\n    while(scanf(\"%d\",&n)==1)\n    {\n        for(i=0; i<n; i++)\n        {\n            scanf(\"%d\",a+i);\n        }\n        if(a[0]%2==0||a[n-1]%2==0)\n        {\n            printf(\"No\\n\");\n            continue;\n        }\n        j=1;\n        int cnt=0;\n        for(i=0; i<n; i++)\n        {\n            if(a[i]%2==0)\n                j++;\n            else if(i<n-1&&a[i+1]%2==0)\n                j++;\n            else\n            {\n                if(j&1)\n                {\n                    j=1;\n                    cnt++;\n                }\n                else\n                    j++;\n            }\n        }\n        if(j!=1||cnt%2==0)\n            printf(\"No\\n\");\n        else\n            printf(\"Yes\\n\");\n    }\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b4820341df7ba002423645f7cc2d230a", "src_uid": "2b8c2deb5d7e49e8e3ededabfd4427db", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(void){\n    int n, x, flag = 1;\n    scanf(\"%d\", &n);\n    if (n & 1 == 0) {\n        flag = 0;\n    }\n    for (inti = 0; i < x; i++){\n        scanf(\"%d\", &x);\n        if ((i == 0 || i == x-1) && (x & 1 == 0)) {\n            flag = 0;\n        }\n    }\n    if (flag) {\n        printf(\"Yes\\n\");\n    } else {\n        printf(\"No\\n\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "672f903f00fe85b2547036c7b60ee636", "src_uid": "2b8c2deb5d7e49e8e3ededabfd4427db", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n;\n    scanf(\"%d\",&n);\n    int a[n];\n    for (int i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i])\n    }\n    if (a[0]%2!=0 && a[n-1]%2!=0 && n%2!=0)\n        printf(\"Yes\\n\");\n    else \n        printf(\"No\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9bc73a70b4cbc16a366afaff8fe32167", "src_uid": "2b8c2deb5d7e49e8e3ededabfd4427db", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint shuzu[233];\nint mainz(){\n    int n;\n    scanf(\"%d\",&n);\n    for(int i=0;i<N;i++){\n        scanf(\"%d\",&shuzu[i]);\n    }\n    if(shuzu[0]%2==0||shuzu[n-1]%2==0)\n        printf(\"no\");\n    else if(n%2==0)\n        printf(\"no\");\n    else\n        printf(\"yes\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0ede2809926e35a0d709a82dadd37493", "src_uid": "2b8c2deb5d7e49e8e3ededabfd4427db", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nlong long int max,min,mid,ans,c[3];\n#define setmax c[0]>c[1]?(max=0,c[2]>c[max]?max=2:1):(max=1,c[2]>c[max]?max=2:1)\n#define setmin c[0]<=c[1]?(min=0,c[2]<=c[min]?min=2:1):(min=1,c[2]<=c[min]?min=2:1)\n#define setmid (max+min)==1?mid=2:(max+min)==2?mid=1:mid=0\n#define setall (setmax,setmin,setmid,1)\nint main()\n{\n    scanf(\"%lld %lld %lld\",&c[0],&c[1],&c[2]);          \n    while(setall)\n    {\n        if((c[max]-2)>=0 && (c[mid]-1)>=0)\n        {\n            c[max]-=2;\n            c[mid]-=1;\n            ans++;\n        }\n        else if(c[0]==1 && c[1]==1 && c[2]==1)\n        {\n            ans++;\n            break;\n        }\n        else break;\n    }       \n    printf(\"%lld\\n\",ans);\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "23c53ec55683ae65095494caca7b863c", "src_uid": "bae7cbcde19114451b8712d6361d2b01", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nvoid min(int *a, int *b) {\n    if(*a > *b) {\n        int tmp = *a;\n        *a = *b;\n        *b = tmp;\n    }\n}\n\nvoid min(int *a, int *b, int *c) {\n    min(a, b);\n    min(b, c);\n    min(a, b);\n}\n\nint main() {\n    int a,b,c;\n    scanf(\"%d%d%d\", &a, &b, &c);\n    min(&a, &b, &c);\n    int done = a;\n    b-=a;\n    c-=a;\n    if (b*2 <= c) {\n        done += b;\n    } else {\n        done += c/2;\n    }\n    printf(\"%d\", done);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9811a9e3df856d31ec9f00daec511276", "src_uid": "bae7cbcde19114451b8712d6361d2b01", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nlong long int max,min,mid,ans,c[3];\n#define setmax() c[0]>c[1]?(max=0,c[2]>c[max]?max=2:1):(max=1,c[2]>c[max]?max=2:1)\n#define setmin() c[0]<=c[1]?(min=0,c[2]<=c[min]?min=2:1):(min=1,c[2]<=c[min]?min=2:1)\n#define setmid() (max+min)==1?mid=2:(max+min)==2?mid=1:mid=0\n#define setall() (setmax(),setmin(),setmid(),1)\nint main()\n{\n\tscanf(\"%lld %lld %lld\",&c[0],&c[1],&c[2]);\t\t\t\n\twhile(setall())\n\t{\n\t\tif((c[max]-2)>=0 && (c[mid]-1)>=0)\n\t\t{\n\t\t\tc[max]-=2;\n\t\t\tc[mid]-=1;\n\t\t\tans++;\n\t\t}\n\t\telse if(c[0]==1 && c[1]==1 && c[2]==1)\n\t\t{\n\t\t\tans++;\n\t\t\tbreak;\n\t\t}\n\t\telse break;\n\t}\t \t\n\tprintf(\"%lld\\n\",ans);\n\treturn 0;\n}\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7ff3658e94d48281045cb93ba4771473", "src_uid": "bae7cbcde19114451b8712d6361d2b01", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nlong long int max,min,mid,ans,c[3],lol;\n#define setmax() c[0]>c[1]?(max=0,c[2]>c[max]?max=2:1):(max=1,c[2]>c[max]?max=2:1)\n#define setmin() c[0]<=c[1]?(min=0,c[2]<=c[min]?min=2:1):(min=1,c[2]<=c[min]?min=2:1)\n#define setmid() (max+min)==1?mid=2:(max+min)==2?mid=1:mid=0\n#define setall() (setmax(),setmin(),setmid())\nint main()\n{\n\tscanf(\"%lld %lld %lld\",&c[0],&c[1],&c[2]);\t\n\tlol=setall();\t\t\n\twhile(1)\n\t{\n\t\tif((c[max]-2)>=0 && (c[mid]-1)>=0)\n\t\t{\n\t\t\tc[max]-=2;\n\t\t\tc[mid]-=1;\n\t\t\tans++;\n\t\t\tlol=setall();\n\t\t}\n\t\telse if(c[0]==1 && c[1]==1 && c[2]==1)\n\t\t{\n\t\t\tans++;\n\t\t\tbreak;\n\t\t}\n\t\telse break;\n\t}\t \t\n\tprintf(\"%lld\\n\",ans);\n\treturn 0;\n}\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6c61ff25972283d17be3c6bd68cd65ea", "src_uid": "bae7cbcde19114451b8712d6361d2b01", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint cases(int r, int g, int b);\n\nint main(){\n\n    int r, g, b;\n\n    scanf(\"%d %d %d\", &r, &g, &b);\n\n    printf(\"%d\", cases(r, g, b));\n\n    return 0;\n}\n\nint cases(int r, int g, int b){\n    if(r==g && g==b)\n        return r;\n    if(r==g && g>b)\n    {\n        return (r+b+g)/3;\n    }\n    if(r==g && g<b)\n    {\n        if(r+g<b)\n            return r+g;\n        return (r+b+g)/3;\n    }\n    if(g==b)\n        return cases(g, b, r);\n    if(b==r)\n        return cases(b, r, g);\n    if(r>g && g>b)\n    {\n        if(r>g+b)\n            return g+b;\n        return (r+g+b)/3\n    }\n    if(r>b && b>g)\n        return cases(r, b, g);\n    if(g>r && r>b)\n        return cases(g, r, b);\n    if(g>b && b>r)\n        return cases(g, b, r);\n    if(b>r && r>g)\n        return cases(b, r, g);\n    if(b>g && g>r)\n        return cases(b, g, r);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c47e3d5492032560d96e3eb8c1a73ae0", "src_uid": "bae7cbcde19114451b8712d6361d2b01", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{long long int a,b,i,j,k=0,t,y;\nscanf(\"%I64d %I64d\",&a,&b);\nfor(i=a;i<=b;i++)\n{if((i-(i%10))==0)\n{k++;}\nelse\n{\nt=i%10;\nif(t!=0)\n{j=i;\nwhile(j/10!=0)\n{j=j/10;}\nif(t==j)\nk++;\n}}}printf(\"%I64d\",k);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "eb9678ee528c51fbd5581e2b2f492ca6", "src_uid": "9642368dc4ffe2fc6fe6438c7406c1bd", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nchar s[20], s1[20], s2[20];\nint judge()\n{\n    if ( s[0] == s[strlen(s)-1] )\n       return 1;\n    else\n        return 0;\n}\nvoid add_one()\n{\n     int i, j;\n     s[strlen(s)-1]++;\n     if ( s[strlen(s)-1] < '9'+1 )\n        ;\n     else{\n          i = strlen(s)-1;\n          while ( i > 0 && s[i] == '9'+1 ){\n                s[i] = '0';\n                s[i-1]++;\n                i--;\n          }\n          if ( i == 0 ){\n             if ( s[i] == '9'+1 ){\n                for ( j = strlen(s)-1; j >= 0; j-- )\n                    s[j+1] = s[j];\n                s[1] = '0';\n                s[0] = '1';\n             }\n          }\n     }\n}\nint main()\n{   \n    long long int num;\n    while ( scanf(\"%s %s\", s1, s2) != EOF ){\n          num = 0;\n          strcpy(s, s1);\n          while ( strcmp(s,s2) ){\n                if ( judge() ) num++;\n                add_one();\n          }\n          printf(\"%I64d\\n\", num);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "81c3048003043e5f8a1f86f0cb9baee3", "src_uid": "9642368dc4ffe2fc6fe6438c7406c1bd", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include \"string.h\"\n#include \"stdio.h\"\n#include \"stdlib.h\"\nint main()\n{long long i,j,k,a,b,sum;\nchar c[18];\nwhile(scanf(\"%I64d%I64d\",&a,&b)!=-1)\n{sum=0;\nfor(i=a;i<=b;i++)\n{itoa((int)i,c,10);\nif(c[strlen(c)-1]==c[0])sum++;}\nprintf(\"%I64d\\n\",sum);\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3ca236a72689336291f0b1d39fce1407", "src_uid": "9642368dc4ffe2fc6fe6438c7406c1bd", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include \"string.h\"\n#include \"stdio.h\"\n#include \"stdlib.h\"\nint main()\n{long int i,j,k,a,b,sum;\nchar c[18];\nwhile(scanf(\"%ld%ld\",&a,&b)!=-1)\n{sum=0;\nfor(i=a;i<=b;i++)\n{itoa((int)i,c,10);\nif(c[strlen(c)-1]==c[0])sum++;}\nprintf(\"%ld\\n\",sum);\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1b8201f686de270fd00a0eea3f9b390f", "src_uid": "9642368dc4ffe2fc6fe6438c7406c1bd", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n   long long n,m,sum,sum1,sum11,sum2,sum21,s,n1,n12,n2,n3,m1,m12,m2,m3;\n   int b,a,j,k,l;\n   while(scanf(\"%I64d%I64d\",&n,&m)!=EOF)\n   {\n     n3=n;\n     m3=m;\n     b=0;\n     a=1;\n     sum=0;\n     sum1=0;\n     sum2=0;\n     j=k=0;\n     n2=n%10;\n     while(n>0)\n     {\n       j++;\n       n1=n%10;\n       n=n/10; \n     }\n     n12=n1;\n     if(n1<n2)\n     {\n      n1++;\n      a=0;\n     }\n     m2=m%10;\n     while(m>0)\n     {\n       k++;\n       m1=m%10;\n       m=m/10;  \n     }\n     m12=m1;\n     if(m1>m2)\n     {\n      m1--;\n      b=1;\n     }\n     if(j==k)\n     {\n       if(j>=3)\n       {\n          s=10;\n          for(l=0;l<j-3;l++)\n          {\n            s*=10;\n          }\n          sum1=s-n3/10%s;\n          if(a==0)sum1--;\n          sum11=(m12-1-n12)*s;\n          sum=m3/10%s;\n          if(b==0)sum++;\n          sum=sum1+sum11+sum;\n         }\n       }\n       else\n       {\n         if(n1>m1)\n           sum=0;\n         else\n           sum=m1-n1+1;\n       }      \n     }\n     else\n     {\n       if((j==1)&&(k==2))\n       {\n         sum=10-n1+m1;\n       }\n       else \n       {\n         if((j==2)||(j==1&&k>=3))\n         {\n           sum1=10-n1;\n         }\n         else\n         {\n           s=10;\n           for(l=0;l<j-3;l++)\n             s*=10;\n           sum11=0;\n           sum11=s-n3/10%s;\n           if(a==0)\n            sum11--; \n           sum1=(9-n12)*s+sum11;\n         }\n         s=9;\n         for(l=0;l<j-1;l++)\n           s*=10;\n         for(l=j+1;l<k;l++)\n         {\n           sum+=s;\n           s*=10;\n         }\n         s=10;\n         for(l=0;l<k-3;l++)\n         {\n           s*=10;\n         }\n         sum21=m3/10%s+1;\n         if(b==1)\n         {\n           sum21--;\n         }\n         sum2=sum21+(m12-1)*s;\n         sum=sum+sum1+sum2;\n       }\n     }             \n   printf(\"%I64d\\n\",sum);\n   }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "deb9fba3a83a28c3ab20e9dd8dce6f9c", "src_uid": "9642368dc4ffe2fc6fe6438c7406c1bd", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint main()\n{\n    long long int w,m,k,ma,ha=1,total=0,temp;\n    int i,j,t;\n    scanf(\"%I64d%I64d%I64d\", &w,&m,&k);ma=m; w= w/k;\n    for(i=0;ma;i++)ma /=10;\n    ha=pow(10,i);\n    while(1){\n    temp = ha-m;\n    if(w<=temp*i){printf(\"%I64d\", w/i+total);return 0;}\n    total += ha-m;\n    w-=(temp*i);\n    m=ha;ha*=10;i++;\n    }\n    return 0;\n    }", "lang_cluster": "C", "compilation_error": false, "code_uid": "a921b7085081524eec059ac73a9b2f48", "src_uid": "8ef8a09e33d38a2d7f023316bc38b6ea", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nlong long digit(long long r)\n{\n     long long c=0;\n     while(r)\n     {\n             c++;\n             r/=10;\n     }\n     return c;\n}\n\nint main()\n{\n    int j;\n\tlong long w,m,k,temp,val,p,d,s,i,x,ans;\n\twhile(scanf(\"%I64d%I64d%I64d\",&w,&m,&k)!=EOF)\n\t{\n\t\ti=digit(m); p=1;\n        for(j=0;j<i;j++)\n        p*=10;\n        s=0; ans=0;\n\t\twhile(w>=0)\n\t\t{\n\t\t\tans+=s; temp=w;\n\t\t\ts=p-m; m=p; p*=10;\n\t\t\tval=s*i*k;\n\t\t\tif(val<0)\n\t\t\tbreak; \n\t\t\tw-=val; i++;\n\t\t}\n\t\td=digit(m)-1; x=(temp)/(d*k); ans+=x;\n\t\tprintf(\"%I64d\\n\",ans);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6d0d3187e04c659e3d032a36c6730629", "src_uid": "8ef8a09e33d38a2d7f023316bc38b6ea", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n  long long n,m,k,i,j=0,s=0;\n  scanf(\"%lld %lld %lld\",&n,&m,&k);\n  n/=k;\n  for(i=1;i<=m;i*=10)j++;//printf(\"%lld %lld %lld %lld\\n\",i,j,m,(i-m)*j*k);\n  for(;(i-m)*j<n;j++){//printf(\"%lld %lld %lld %lld\\n\",i,j,m,n);\n    n-=(i-m)*j;\n    s+=i-m;\n    m=i;\n    i*=10;\n  }//printf(\"%lld %lld %lld %lld\\n\",i,j,m,n);\n  printf(\"%lld\\n\",s+n/j);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ef06dd4f37dd8f5bee8763705a2e4056", "src_uid": "8ef8a09e33d38a2d7f023316bc38b6ea", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "# include <stdio.h> \n# include <math.h>\nint main(){\n\tlong long int w,m,k,g,A[30],B[30],i,c,d,l=0;\n\tw=10;\n\tA[0]=0;\n\tB[0]=0;\n\tfor(i=1;i<19;i++){\n\t\tA[i]=w-1;\n\t\tB[i]=w;\n\t\tw*=10;\n\t}\n\tscanf(\"%I64d%I64d%I64d\",&w,&m,&k);\n\tc=w;\n\td=m;\n\tg=log10(m)+1;\n\twhile(c>0){\n\t\tif(((double)c/(double)g)/(double)k>=A[g]-m+1){ \n\t\t\tc=c-k*g*(A[g]-m+1);\n\t\t\tl=l+A[g]-m+1;\n\t\t\tm=B[g];\n\t\t\tg=log10(m)+1;\n\t\t}\n\t\telse{\n\t\t\tl=l+((double)c/(double)g)/(double)k;\n\t\t\tbreak;\n\t\t}\n\t}\n\tprintf(\"%I64d\\n\",l);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6ab2028bb552a53fd119ae3f4b9ac373", "src_uid": "8ef8a09e33d38a2d7f023316bc38b6ea", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>long long w, m, k, ten, ans;int main(){    int tx;    scanf(\"%I64d%I64d%I64d\", &w, &m, &k);    ten = 9;    tx = 1;    w /= k;    while (ten < m){        ten = ten * 10 + 9;        tx++;    }    if ((ten - m + 1) * tx > w){        printf(\"%I64d\\n\", w / tx);        return 0;    }    w -= (ten - m + 1) * tx;    ans = (ten - m + 1);    ten++;    tx++;    while ((ten * 10 - ten) * tx <= w){        w -= (ten * 10 - ten) * tx;        ans += (ten * 10 - ten);        ten *= 10;        tx++;    }    printf(\"%I64d\\n\", ans + w / tx);    return 0;}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e63d039c1b33bc56e1bb6c01cfd0409a", "src_uid": "8ef8a09e33d38a2d7f023316bc38b6ea", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n//Written By GHATAK...\nint main()\n{\n int a[12];\n for(int i=0;i<12;i++)\n {\n a[i]=i+1;\n }\n char c[10];\n int b[14],q=0,z=0,t1,t2,t3;\n gets(c);\n for(int i=0;c[i]!='\\0';i++)\n {\n if((c[i]=='C')&&(c[i+1]=='#'))\n {\n b[q]=2;\n i++;\n q++;\n }\n if((c[i]=='C')&&(c[i+1]!='#'))\n {\n b[q]=1;\n q++;\n }\n if((c[i]=='D')&&(c[i+1]!='#'))\n {\n b[q]=3;\n q++;\n }\n if((c[i]=='D')&&(c[i+1]=='#'))\n {\n b[q]=4;\n i++;\n }\n if((c[i]=='E')&&(c[i+1]!='#'))\n {\n b[q]=5;\n q++;\n }\n if((c[i]=='F')&&(c[i+1]!='#'))\n {\n b[q]=6;\n q++;\n }\n if((c[i]=='F')&&(c[i+1]=='#'))\n {\n b[q]=7;\n q++;\n i++;\n }\n if((c[i]=='G')&&(c[i+1]!='#'))\n {\n b[q]=8;\n q++;\n }\n if((c[i]=='G')&&(c[i+1]=='#'))\n {\n b[q]=9;\n q++;\n i++;\n }\n if((c[i]=='A')&&(c[i+1]!='#'))\n {\n b[q]=10;\n q++;\n }\n if((c[i]=='B')&&(c[i+1]!='#'))\n {\n b[q]=11;\n q++;\n }\n if((c[i]=='H')&&(c[i+1]!='#'))\n {\n b[q]=12;\n q++;\n }\n }\n\n t1=b[0];\n t2=b[1];\n t3=b[2];\n int diff1,diff2;\n //t1,t2,t3\n diff1=telll(t1,t2);\n diff2=telll(t2,t3);\n z=display(diff1,diff2);\n if(z==1)\n {\n return 0;\n }\n //t1,t3,t2\n diff1=telll(t1,t3);\n diff2=telll(t3,t2);\n z=display(diff1,diff2);\n if(z==1)\n {\n return 0;\n }\n //t2,t1,t3\n diff1=telll(t2,t1);\n diff2=telll(t1,t3);\n z=display(diff1,diff2);\n if(z==1)\n {\n return 0;\n }\n //t2,t3,t1\n diff1=telll(t2,t3);\n diff2=telll(t3,t1);\n z=display(diff1,diff2);\n if(z==1)\n {\n return 0;\n }\n //t3,t2,t1\n diff1=telll(t3,t2);\n diff2=telll(t2,t1);\n z=display(diff1,diff2);\n if(z==1)\n {\n return 0;\n }\n //t3,t1,t2\n diff1=telll(t3,t1);\n diff2=telll(t1,t2);\n z=display(diff1,diff2);\n if(z==1)\n {\n return 0;\n }\n printf(\"strange\");\n return 0;\n\n}\nint display(int a,int b)\n{\n if((a==4)&&(b==3))\n {\n printf(\"major\");\n return 1;\n }\n if((a==3)&&(b==4))\n {\n printf(\"minor\");\n return 1;\n }\n return 0;\n}\nint telll(int a,int b)\n{\n int diff;\n if(a<=b)\n {\n diff=b-a;\n }\n else\n {\n diff=b-a+12;\n }\n return diff;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "459bc003ae194a1839b075c1792ef316", "src_uid": "6aa83c2f6e095848bc63aba7d013aa58", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define norm(X) (((X) + N) % N)\n#define N 12\ntypedef enum _triad { major, minor, strange } triad;\n\nint pos(char note[3])\n{\n    static char sample[N][3] =\n        {\"C\", \"C#\", \"D\", \"D#\", \"E\", \"F\", \"F#\", \"G\", \"G#\", \"A\", \"B\", \"H\"};\n    int i = 0;\n    while (strcmp(note, sample[i])) i++;\n    return i;\n}\n\ntriad det(int a, int b, int c)\n{\n    int d;\n    if (b < a) { d = b; b = a; b = d; }\n    if (c < a) { d = c; c = a; a = d; }\n    if (c < b) { d = c; c = b; b = d; }\n    if (norm(b - a) == 4 && norm(c - b) == 3 || // a, b, c\n        norm(c - b) == 4 && norm(a - c) == 3 || // b, c, a\n        norm(a - c) == 4 && norm(b - a) == 3) // c, a, b\n        return major;\n    else if (norm(b - a) == 3 && norm(c - b) == 4 || // a, b, c\n        norm(c - b) == 3 && norm(a - c) == 4 || // b, c, a\n        norm(a - c) == 3 && norm(b - a) == 4) // c, a, b\n        return minor;\n    else\n        return strange;\n}\n\nchar *triad_str(triad t)\n{\n    switch (t) {\n    case major: return \"major\";\n    case minor: return \"minor\";\n    case strange: return \"strange\";\n    default: return \"\";\n    }\n}\n\nint main()\n{\n    int a[3], t;\n    char note[3];\n    for (t = 0; t < 3; t++) {\n        scanf(\"%s\", note);\n        a[t] = pos(note);\n    }\n    printf(triad_str(det(a[0], a[1], a[2])));\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3cbfb2f1cacdc91718975d8f9d2d4b95", "src_uid": "6aa83c2f6e095848bc63aba7d013aa58", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\nint main(){\n\tchar s[4];int a[3],p,q;\n\tfor(int i=0;i<3;i++){\n\t\tscanf(\"%s\",s);\n\t\tswitch(s[0]){\n\t\t\tcase 'C':a[i]=1;break;\n\t\t\tcase 'D':a[i]=3;break;\n\t\t\tcase 'E':a[i]=5;break;\n\t\t\tcase 'F':a[i]=6;break;\n\t\t\tcase 'G':a[i]=8;break;\n\t\t\tcase 'H':a[i]=10;break;\n\t\t\tcase 'A':a[i]=11;break;\n\t\t\tcase 'B':a[i]=12;break;\n\t\t}\n\t\tif(strlen(s)==2)a[i]++;\n\t}\n\tp=a[1]-a[0];\n\tq=a[2]-a[1];\n\tif(p<0)p+=12;\n\tif(q<0)q+=12;\n\tif(p==4&&q==3)\n\tprintf(\"major\");\n\telse if(p==3&&q==4)\n\tprintf(\"minor\");\n\telse\n\tprintf(\"strange\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "19b3d53e6deb134adbf0cd92ba1eb6ac", "src_uid": "6aa83c2f6e095848bc63aba7d013aa58", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n/* Written by Nishant Mittal aka nishantwrp */\nint chordtoindex(char *a) {\nif (*a == 'C') {\n    a++;\n    if (*a == '#') {\n        return 2;\n    } else {\n    return 1;\n    }\n}\nif (*a == 'D') {\n    a++;\n    if (*a == '#') {\n     return 4;\n    } else {\n    return 3;\n    }\n}\nif (*a == 'E') {\n    return 5;\n}\nif (*a == 'F') {\n    a++;\n    if (*a == '#') {\n     return 7;\n    } else {\n    return 6;\n    }\n}\nif (*a == 'G') {\n    a++;\n    if (*a == '#') {\n     return 9;\n    } else {\n    return 8;\n    }\n}\nif (*a == 'A') {\n    return 10;\n}\nif (*a == 'B') {\n    return 11;\n}\nif (*a == 'H') {\n    return 12;\n}\nreturn 0;\n}\nint distancefind(int a,int b) {\nint count = 0;\nint i = b;\nwhile (i != a) {\n    count++;\n    if (i == 12) {\n        i = 1;\n    } else {\n    i++;\n    }\n}\nreturn count;\n}\nint main()\n{\nchar chord1[3],chord2[3],chord3[3];\nint pos1,pos2,pos3;\nint i=0;\nwhile(i<3) {\nchar tmp;\nscanf(\"%c\",&tmp);\nif (tmp == ' ') {\n    break;\n}else {\nchord1[i] = tmp;\n}\ni++;\n}\nint j=0;\nwhile(j<3) {\nchar tmp;\nscanf(\"%c\",&tmp);\nif (tmp == ' ') {\n    break;\n}else {\nchord2[j] = tmp;\n}\nj++;\n}\nint k=0;\nwhile(k<3) {\nchar tmp;\nscanf(\"%c\",&tmp);\nif (tmp == '\\n') {\n    break;\n}else {\nchord3[k] = tmp;\n}\nk++;\n}\nint ansset = 0;\npos1 = chordtoindex(chord1);\npos2 = chordtoindex(chord2);\npos3 = chordtoindex(chord3);\n//Minor\nif (distancefind(pos2,pos1) == 3 && distancefind(pos3,pos2) == 4) {\n    ansset = 1;\nprintf(\"minor\");\n}else if (distancefind(pos2,pos3) == 3 && distancefind(pos1,pos2) == 4) {\n     ansset = 1;\nprintf(\"minor\");\n}else if (distancefind(pos1,pos2) == 3 && distancefind(pos3,pos1) == 4) {\n     ansset = 1;\nprintf(\"minor\");\n}else if (distancefind(pos1,pos3) == 3 && distancefind(pos2,pos1) == 4) {\n     ansset = 1;\nprintf(\"minor\");\n} else if (distancefind(pos3,pos1) == 3 && distancefind(pos2,pos3) == 4) {\n     ansset = 1;\nprintf(\"minor\");\n} else if (distancefind(pos3,pos2) == 3 && distancefind(pos1,pos3) == 4) {\n     ansset = 1;\nprintf(\"minor\");\n}//Major\nif (distancefind(pos2,pos1) == 4 && distancefind(pos3,pos2) == 3) {\n     ansset = 1;\nprintf(\"major\");\n}else if (distancefind(pos2,pos3) == 4 && distancefind(pos1,pos2) == 3) {\n     ansset = 1;\nprintf(\"major\");\n}else if (distancefind(pos1,pos2) == 4 && distancefind(pos3,pos1) == 3) {\n     ansset = 1;\n\n}else if (distancefind(pos1,pos3) == 4 && distancefind(pos2,pos1) == 3) {\n     ansset = 1;\nprintf(\"major\");\n}else if (distancefind(pos3,pos1) == 4 && distancefind(pos2,pos3) == 3) {\n     ansset = 1;\nprintf(\"major\");\n}else if (distancefind(pos3,pos2) == 4 && distancefind(pos1,pos3) == 3) {\n ansset = 1;\nprintf(\"major\");\n}\nif (ansset != 1) {\n    printf(\"strange\");\n}\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "90dcd42ba7f17aa0d100de4c751425f9", "src_uid": "6aa83c2f6e095848bc63aba7d013aa58", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nchar arr[15][4]={\"C\", \"C#\", \"D\",\"D#\", \"E\", \"F\", \"F#\", \"G\", \"G#\", \"A\", \"B\", \"H\"};\nint main()\n{\nint pos1=0,pos2=0,pos3=0,i,arr2[4],q=0;\nchar arr1[5][5];\nfor(i=0;i<3;i++)\nscanf(\"%s\",arr1[i]);\nwhile(strcmp(arr1[0],arr[pos1]))\npos1++;\narr2[0]=pos1;\nwhile(strcmp(arr1[1],arr[pos2]))\npos2++;\narr2[1]=pos2;\nwhile(strcmp(arr1[2],arr[pos3]))\npos3++;\narr2[2]=pos3;\n//printf(\"%d\",pos3);\nfor(i=0;i<3;i++)\n{\nif(((arr2[i]+3)%12==arr2[(i+1)%3]&&(arr2[(i+1)%3]+4)%12==arr2[(i+2)%3])||((arr2[i]+3)%12==arr2[(i+2)%3]&&(arr2[i]+4)%12==arr2[(i+1)%3]))\n{\nq=1;\nprintf(\"minor\\n\");\n}\nelse if(((arr2[i]+4)%12==arr2[(i+1)%3]&&(arr2[(i+1)%3]+3)%12==arr2[(i+2)%3])||((arr2[i]+4)%12==arr2[(i+2)%3]&&(arr2[i]+3)%12==arr2[(i+1)%3]))\n{\n    q=1;\n    printf(\"major\\n\");\n}\n}\nif(q==0)\nprintf(\"strange\\n\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ab536e4b90687ed4ed768cdb7b45afa0", "src_uid": "6aa83c2f6e095848bc63aba7d013aa58", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <iostream>\nusing namespace std;\n\nint main() {\n\t// your code goes here\n\tint n;\n\tcin>>n;\n\tint a[n];\n\tfor(int i=0;i<n;i++)\n\t{\n\t\tcin>>a[i];\n\t\t\n\t}\n     int unique = 1;\n\n     for (int out = 1; out < n && a[out]!=0; ++out)\n     {\n        \n        \n        int is_unique = 1;\n        for (int inner = 0; is_unique && inner < out; ++inner)\n        {  \n             \n             if (a[inner] == a[out]) is_unique = 0;\n        }\n        if (is_unique) ++unique;\n     }\n\tcout<<unique;\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "93719bd56ee38cdef146741e23b87654", "src_uid": "3b520c15ea9a11b16129da30dcfb5161", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint f[600];\nint main()\n{\n    int n,i,cnt=0;\n    scanf(\"%d\", &n);\n    int a[n];\n    for(i = 0 ; i< n; i++)\n        scanf(\"%d\", &a[i]);\n    for(i = 1 ; i <= n; i++)\n    {\n\n            if(f[a[i]] = 0 )\n                f[a[i]] = 1;\n\n    }\n    for( i = 0 ; i < 600; i++)\n    {\n        if(f[i] == 1)\n    }\n    printf(\"%d\\n\", cnt);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a00e8888f4e3a00266ce8359b1582260", "src_uid": "3b520c15ea9a11b16129da30dcfb5161", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "\n#include <algorithm>\n#include <vector>\n#include <string>\n\nint deleteDuplicates(std::vector<int> v, int n);\n\nint main()\n{\n    int n = 0;\n    std::scanf(\"%d\", &n);\n    std::vector<int> vec;\n    for (int a = 0; a < n; a++)\n    {\n        int b = 0;\n        std::scanf(\"%d\", &b);\n        vec.push_back(b);\n    }\n    std::sort(vec.begin(), vec.end());\n    int m = deleteDuplicates(vec, n);\n    int l = vec[0] == 0 ? m - 1 : m;\n    printf(\"%d\", l);\n}\n\nint deleteDuplicates(std::vector<int> v, int n)\n{\n    if (n==0 || n==1)\n        return n;\n    std::vector<int> temp;\n    int j = 0;\n    for (int i=0; i<n-1; i++)\n        if (v[i] != v[i+1])\n        {\n            temp.push_back(v[i]);\n            j++;\n        }\n    temp.push_back(v[n-1]);\n    j++;\n    for (int i=0; i<j; i++)\n        v[i] = temp[i];\n    return j;\n}\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "87756090eb064462d4c19ab7f03b461f", "src_uid": "3b520c15ea9a11b16129da30dcfb5161", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<iostream.h>\n/*#include<algorithm>\n#include<cmath>*/\nusing namespace std;\nint z[1000];\nint main()\n{\n\tint n;\n\tfor(int i=0;i<1000;i++) z[i]=0;\n\tcin>>n;\n\tint t;\n\tint num=0;\n\tfor(int i=0;i<n;i++){\n\t\tcin>>t;\n\t\tif(z[t]==0&&t!=0) z[t]=1,num++;\n\t}\n\tcout<<num<<endl;\n\treturn 0;\n }\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c30ae53b37448d2c7c79825d8b3c534b", "src_uid": "3b520c15ea9a11b16129da30dcfb5161", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint f[600];\nint main()\n{\n    int n,i,cnt=0;\n    scanf(\"%d\", &n);\n    int a[n];\n    for(i = 0 ; i< n; i++)\n        scanf(\"%d\", &a[i]);\n    for(i = 1 ; i <= n; i++)\n    {\n\n            if(f[a[i]] == 0 )\n                f[a[i]] = 1;\n\n    }\n    for( i = 0 ; i < 600; i++)\n    {\n        if(f[i] == 1)\n    }\n    printf(\"%d\\n\", cnt);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b358636d6e3ef12d2f6fdc4d4116c8ab", "src_uid": "3b520c15ea9a11b16129da30dcfb5161", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nlong long int maximo(long long int a, long long int b )\n{\n\tif ( a >= b )\n\t{\n\t\treturn a;\n\t}\n\telse\n\t{\n\t\treturn b;\n\t}\n}\n\nint main()\n{\n\tlong long int A,B,C,D;\n\tscanf(\"%lld %lld %lld %lld\", &A, &B, &C, &D);\n\t\n\tlong long int alfa,beta;\n\tlong long int total = 0;\n\tfor ( alfa = A; alfa <= B; ++alfa )\n\t{\n\t\tlong long int st = maximo(alfa+B, C+1);\n\t\tif ( alfa+C > D )\n\t\t{\n\t\t\tif ( st > D )\n\t\t\t{\n\t\t\t\t//printf(\"pase 1: alfa %lld st %lld \", alfa, st );\n\t\t\t\ttotal += (D-C+1)*(C-B+1);\n\t\t\t}\n\t\t\telse\n\t\t\t{\n                //printf(\"pase 2: alfa %lld st %lld \", alfa, st );\n\t\t\t\ttotal += (D-C)*(D-C+1)/2 - (st-C)*(st-C-1)/2 + (D-C+1)*(alfa+C-D);\n\t\t\t}\n\t\t}\n\t\telse\n\t\t{\n            //printf(\"pase 3: alfa %lld st %lld \", alfa, st );\n\t\t\ttotal += (alfa)*(alfa+1)/2 - (st-C)*(st-C-1)/2;\n\t\t}\n\t\t//printf(\"Parcial total: %lld\\n\", total);\n\t}\n\t\n\tprintf(\"%lld\\n\", total);\n\t\n\t//system(\"pause\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "98c8085b976d626a1ca010d2bd11e0a7", "src_uid": "4f92791b9ec658829f667fcea1faee01", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define max(a,b) ((a>b)?(a):(b))\n\nlong long ways[1000006];\n\nint main() {\n\tint a,b,c,d;\n\tscanf(\"%d%d%d%d\", &a, &b, &c, &d);\n\tint tx = b - a, ty = c - b, lz = c - a - b, rz = d - a - b;\n\tlong long ans = 0;\n\tfor( int z=0; z<=rz; ++z ) {\n\t\tint l=0, r=z;\n\t\tif( r > tx )\n\t\t\tr = tx;\n\t\t// ( z - r, z - l )\n\t\tif( z - l > ty )\n\t\t\tl = z - ty;\n\t\tways[z] = max(0, r - l + 1);\n\t\tif( z > 0 )\n\t\tways[z] += ways[z-1];\n\t}\n\tfor( int z = max(0,lz); z<=rz; ++z ) {\n\t\tans += ways[z];\n\t}\n\tprintf(\"%lld\\n\", (((1ll*(b-a+1))*(c-b+1))*(d-c+1)) - ans);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1caf5946081cf15d6619c6ad20e7e7b2", "src_uid": "4f92791b9ec658829f667fcea1faee01", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tlong long int A,B,C,D,i;\n\tlong long int res=0;\n\tscanf(\"%lld%lld%lld%lld\",&A,&B,&C,&D);\n\tfor(i=C;i<=D;i++)\n\t{\n\t\tif(i+2>=A+B)\n\t\t\tres+=((i-A-B+2)*(i-A-B+1))/2;\n\t\tif(i+2>=2*b+1)\n\t\t\tres-=((i-2*B+1)*(i-2*B))/2;\n\t\tif(i+2>=A+C+1)\n\t\t\tres-=((i-A-C+1)*(i-A-C))/2;\n\t\tif(i-B-C>=0)\n\t\t\tres+=((i-B-C)*(i-B-C-1))/2;\n\t}\n\tres=(B-A+1)*(C-B+1)*(D-C+1)-res;\n\tprintf(\"%lld\\n\",res);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "af7e7169134824c00685d04a9c6d4d9c", "src_uid": "4f92791b9ec658829f667fcea1faee01", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "// C program to print largest contiguous array sum \n#include<stdio.h>\ntypedef long long int ll;\nll max(ll a,ll b){\n    return (a>b?a:b);\n}\nll min(ll a,ll b){\n    return (a<b?a:b);\n}\nint main()\n{\n    ll a,b,c,d,low2,high2,ans=0;\n    scanf(\"%lld %lld %lld %lld\",&a,&b,&c,&d);\n    for(ll i=d;i>=c;i--)\n    {\n        for(int j=b;j<=c;j++)\n        {\n            low2=max(a,i-j+1);\n            high2=min(low2,b+1);\n            ans+=(b-high2+1);\n        }\n    }\n    printf(\"%lld\",ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "db6dd79f14f93322be9cce63cf00f57a", "src_uid": "4f92791b9ec658829f667fcea1faee01", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#include<math.h>\n\nlong long int XY(int A, int B, int C, int X_plus_Y)\n{\n\tlong long int x = 0;\n\tint i;\n\tint j;\n\tfor(i=A;i<=B;i++)\n\t{\n\t\tj = X_plus_Y - i;\n\t\tif( (B<=j) && (j<=C) )\n\t\t{\n\t\t\tx++;\n\t\t}\n\t}\n\t\n\treturn x;\n}\n\nlong long int Z(int C, int D, int X_plus_Y)\n{\n\tint min;\n\tlong long int z;\n\tif( X_plus_Y-1 <= D)\n\t{\n\t\tmin = X_plus_Y-1;\n\t}\n\telse\n\t{\n\t\tmin = D;\n\t}\n\t\n\tz = min - C + 1;\n\tif(z<0)\n\t{\n\t\treturn 0;\n\t}\n\t\n\treturn z;\n}\n\nint main()\n{\n\t// variable in description\n\tint T;\n\tint A, B, C, D; \n\t// variable to support\n\tlong long int ans;\n\tlong long int XY_num;\n\tlong long int Z_num;\n\t// variable to judge\n\tint i;\n\tint j;\n\tint k;\n\t\n\t\tscanf(\"%d %d %d %d\",&A,&B,&C,&D);\n\t\t\n\t\tans = 0;\n\t\t\n\t\tfor(j=A+B;j<=B+C;j++)\n\t\t{\n\t\t\tXY_num = XY(A,B,C,j);\n\t\t\tZ_num = Z(C,D,j);\n\t\t\tans += XY_num*Z_num;\n\t\t\t//printf(\"%d %d\\n\",XY_num,Z_num);\n\t\t}\n\t\t\n\t\tprintf(\"%lld\\n\",ans);\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0e17d427c1ec1b36e994e6d811d32346", "src_uid": "4f92791b9ec658829f667fcea1faee01", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define MAX 200000\nint temp[MAX];\nvoid mergesort(int a[],int indices[],int first,int last)\n{\n    if(first==last) return;\n    int middle=(first+last)/2;\n    mergesort(a,indices,first,middle);\n    mergesort(a,indices,middle+1,last);\n    int i,j,k;\n    for(i=first,j=first,k=middle+1; i<=last; i++)\n    {\n        if(j==middle+1) temp[i]=indices[k++];\n        else if(k==last+1) temp[i]=indices[j++];\n        else if(a[indices[k]]<a[indices[j]]) temp[i]=indices[k++];\n        else temp[i]=indices[j++];\n    }\n    for(i=first; i<=last; i++)\n    {\n        indices[i]=temp[i];\n    }\n}\nvoid noobsort(int a[],int indices[],int first,int last)\n{\n    if(first>=last) return;\n    int i,j,s;\n    for(i=first;i<=last;i++)\n    {\n        for(j=i;j>0&&a[indices[j]]>a[indices[j-1]];j--)\n        {\n            s=indices[j-1];\n            indices[j-1]=indices[j];\n            indices[j]=s;\n        }\n    }\n}\nint main()\n{\n    int n,i,j,m;\n    scanf(\"%d %d\",&n,&m);\n    int a[n],indices[n];\n    int fails[n];\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        indices[i]=i;\n    }\n    for(i=0;i<n;i++)\n    {\n        fails[i]=0;\n        noobsort(a,indices,0,i-1);\n        //printf(\"i=%d\\n\",i);\n        int total_time=0;\n        for(j=0;j<i;j++)\n        {\n            total_time=total_time+a[indices[j]];\n        }\n        for(j=0;j<i&&m-total_time<a[i];j++)\n        {\n            fails[i]++;\n            total_time=total_time-a[indices[j]];\n        }\n    }\n    for(i=0;i<n;i++)\n    {\n        printf(\"%d \",fails[i]);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "22a293e82e1aaea2073d96111d2554c0", "src_uid": "d3c1dc3ed7af2b51b4c49c9b5052c346", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint sa(const void * a,const void * b){\n    return(*(int*)a - *(int*)b);\n}\nint main()\n{\n    int n,m,c[200],i=0,j=0,k=0,d,e,f;\n    scanf(\"%d %d\",&n,&m);\n    while(n--){\n        scanf(\"%d\",&c[i]);\n    k+=c[i];\n    i++;\n    if(k<=m)\n        printf(\"0 \");\n    else{\n        qsort(c,i-1,sizeof(int),sa);\n        d=m-c[i-1];\n        e=0;\n        for(j=0;;j++){\n            e+=c[j];\n            if(e>d)\n                break;\n        }\n        f=i-j-1;\n        printf(\"%d \",f);\n    }\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2cfc742730637d14d5672244086d50dc", "src_uid": "d3c1dc3ed7af2b51b4c49c9b5052c346", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nvoid quicksort(int  a[],int  low,int  high );\n \nint partion(int  a[],int  low,int  high);\nint main(void) {\n\t// your code goes here\n\tint i,c,n,m,j,sum;\n\tscanf(\"%d %d\", &n,&m);\n\tint a[n],s[n],b[n];\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\", &a[i]);\n\t\tb[i]=a[i];\n\t\tif(i==0)\n\t\ts[i]=a[i];\n\t\ts[i]=s[i-1]+a[i];\n\t}\n\tfor(i=0;i<n;i++)\n\t{\n\t\tif(s[i]<=m)\n\t\tprintf(\"0 \");\n\t\telse \n\t\t{c=0,sum=0;\n\t\t\tquicksort(b,0,i-1);\n\t\t\tfor(j=i-1;j>=0;j--)\n\t\t\t{\n\t\t\t\tsum+=b[j];\n\t\t\t\tc++;\n\t\t\t\tif(s[i]-sum<=m)\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tprintf(\"%d \", c);\n\t\t}\n\t}\n \n\treturn 0;\n}\n void quicksort(int a[],int low,int high)\n{\n\tif(low<high)\n\t{\n\t\tint  pi=partion(a,low,high);\n\t\tquicksort(a,low,pi-1);\n\t\tquicksort(a,pi+1,high);\n\t}\n}\nint partion(int  a[],int  low,int  high)\n{\n\tint i=low-1,pi=a[high],t,j;\n\tfor(j=low;j<high;j++)\n\t{\n\t\tif(a[j]<pi)\n\t\t{ i++;\n\t\t\tt=a[i];\n\t\t\ta[i]=a[j];\n\t\t\ta[j]=t;\n \n\t\t}\n\t}\n\tt=a[i+1];\n\ta[i+1]=a[high];\n\ta[high]=t;\n\treturn i+1;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "10fb4a341352732c020e701d24fd5c7e", "src_uid": "d3c1dc3ed7af2b51b4c49c9b5052c346", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nvoid quicksort(int  a[],int  low,int  high );\n \n int partion(int  a[],int  low,int  high);\nint main(void) {\n\t// your code goes here\n\tint i,c,n,m,j,sum;\n\tscanf(\"%d %d\", &n,&m);\n\tint a[n],s[n],b[n];\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\", &a[i]);\n\t\tb[i]=a[i];\n\t\tif(i==0)\n\t\ts[i]=a[i];\n\t\ts[i]=s[i-1]+a[i];\n\t}\n\tfor(i=0;i<n;i++)\n\t{\n\t\tif(s[i]<=m)\n\t\tprintf(\"0 \");\n\t\telse \n\t\t{c=0,sum=0;\n\t\t\tquicksort(b,0,i-1);\n\t\t\tfor(j=i-1;j>=0;j--)\n\t\t\t{\n\t\t\t\tsum+=b[j];\n\t\t\t\tc++;\n\t\t\t\tif(s[i]-sum<=m)\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tprintf(\"%d \", c);\n\t\t}\n\t}\n \n\treturn 0;\n}\n void quicksort(int  a[],int  low,int  high)\n{\n\tif(low<high)\n\t{\n\t\tint  pi=partion(a,low,high);\n\t\tquicksort(a,low,pi-1);\n\t\tquicksort(a,pi+1,high);\n\t}\n}\nint partion(int  a[],int  low,int  high)\n{\n\tint i=low-1,pi=a[high],t,j;\n\tfor(j=low;j<high;j++)\n\t{\n\t\tif(a[j]<pi)\n\t\t{ i++;\n\t\t\tt=a[i];\n\t\t\ta[i]=a[j];\n\t\t\ta[j]=t;\n \n\t\t}\n\t}\n\tt=a[i+1];\n\ta[i+1]=a[high];\n\ta[high]=t;\n\treturn i+1;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b23a03a8f36cc6ddeb9fc7853df7ba62", "src_uid": "d3c1dc3ed7af2b51b4c49c9b5052c346", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint bsrch(int v, int *a, int h)\n{\n  int p, l = 0;\n\n  while (l < h) {\n    p = (l + h) / 2;\n\n    // printf(\"%d : %d : %d [%d]\\n\", l, p, h, a[p]);\n    if (a[p] < v)\n      l = p + 1;\n    else\n      h = p;\n\n    // printf(\"%d %d [%d]\\n\", l, h, a[p]);\n  }\n\n  return l;\n}\n\n#define max(a,b) (a>b?a:b)\nint main() {\n  int n, M;\n  int *m_sum;\n\n  // printf(\"x\\n\");\n  // int x[] = {2,4,4,10};\n  // printf(\"%d\\n\", bsearch(4,x,3));\n  // printf(\"%d\\n\", bsearch(2,x,3));\n  // printf(\"%d\\n\", bsearch(1,x,3));\n  // return 0;\n\n  scanf(\"%d %d\", &n, &M);\n  m_sum = (int*)malloc(sizeof(int) * n + 1);\n  m_sum[0] = 0;\n  m_sum++;\n\n  int t = 0;\n  for (int i=0; i<n; i++) {\n    int v;\n    scanf(\"%d\", &v);\n\n    t += v;\n    int k = 0;\n    if (t > M)\n      k = bsrch(t - M, m_sum, i) + 1;\n\n    printf(\"%d \", k);\n\n    for (int j = i; j >= 0; j--)\n      m_sum[j] = max(m_sum[j], m_sum[j - 1] + v);\n  }\n  printf(\"\\n\");\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "85e061f4df3be0dfa4dbb4dd9f3c0499", "src_uid": "d3c1dc3ed7af2b51b4c49c9b5052c346", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint a[20],i,j,k,top,tmp,x,z,flag,maxi;\nlong long n;\n\nint main()\n{\n\tscanf(\"%I64d%d\",&n,&k);\n\ttop=0;\n\twhile (n>0)\n\t{\n\t\ttop++;\n\t\ta[top]=n%10;\n\t\tn/=10;\n\t}\n\twhile (k>0)\n\t{\n\t\tflag=0;\n\t    for (j=top; j>1; j--)\n\t    {\n\t    \tmaxi=j;\n\t    \tfor (x=1; x<=k; x++)\n\t    \t\tif (j-x>0 && a[maxi]<a[j-x]) maxi=j-x;\n\t    \tif (maxi<j)\n\t    \t{\n\t    \t\ttmp=a[maxi];\n\t    \t\tfor (z=maxi; z<j; z++) a[z]=a[z+1];\n\t    \t\ta[j]=tmp;\n\t    \t\tk-=j-maxi;\n\t    \t\tflag=1;\n\t    \t\tbreak;\n\t    \t}\n\t    }\n\t    if (flag==0) break;\n\t}\n\tfor (i=top; i>1; i--) printf(\"%d\",a[i]);\n\tprintf(\"%d\\n\",a[1]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e66b1527ad86155cd0d78a70eb9361e4", "src_uid": "e56f6c343167745821f0b18dcf0d0cde", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n\nint main(void) {\n    int k, i,j,l, digit[10][20], cnt[10], temp, swap = 0;\n    memset(cnt, 0, sizeof(cnt));\n    memset(digit, -1, sizeof(digit));\n    char num[20], ch;\n    scanf(\"%s %d\", &num, &k);\n    int len = strlen(num);\n    for(i=0;i<len;i++){\n        temp = num[i] - '0';\n        digit[temp][cnt[temp]] = i;\n        cnt[temp]++;\n    }\n    for(i=9;i>-1;i--){\n        for(j=0;j<cnt[i];j++){\n            int min = digit[i][j];\n            int index = j;\n            for(l=j+1; l<cnt[i]; l++){\n                if(min < digit[i][l]){\n                    min = digit[i][l];\n                    index = l;\n                }\n            }\n            int x = digit[i][j];\n            digit[i][j] = digit[i][index];\n            digit[i][index] = x;\n        }\n    }\n    //printf(\"%d %d %d\\n\", digit[3][0], digit[3][1], digit[3][2] );\n    for(i=0;i<len-1 && k>0;i++){\n        for(j=9;j>-1;j--){\n            //printf(\"CNT %d\\n\", cnt[j]);\n            if(cnt[j]>0){\n                //printf(\"%d\\n\", digit[j][cnt[j]-1]);\n                if((digit[j][cnt[j]-1] - i) <= k){\n                    int m, pos = digit[j][cnt[j]-1];\n                    if(pos > i){\n                        for(l=pos;l>i;l--){\n                            ch = num[l-1];\n                            temp = ch - '0';\n                            for(m=0;m<cnt[temp];m++){\n                                if(digit[temp][m] == l-1)\n                                    digit[temp][m]++;\n                            }\n                            num[l-1] = num[l];\n                            num[l] = ch;\n                            //printf(\"CHECK %s\", num);\n                        }\n                        k = k - (pos - i);\n                        //printf(\"K=%d\\n\", k);\n                        //printf(\"K=%s\\n\", num);\n                    }\n                    cnt[j]--;\n                    break;\n                }\n            }\n        }\n    }\n    printf(\"%s\", num);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bef12fefbcf33f6c822d86ea24ab3bb5", "src_uid": "e56f6c343167745821f0b18dcf0d0cde", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nstruct list {\nint x;\nstruct list*next;\n}\nint main()\n{\n    char str[20];\n    int i;j;\n    scanf(\"%s\",str);\n    int x=strlen(str);\n    for(i=0;i<x;i++)\n      str[i]=str[i]-'0';\n    char c=str;\n    scanf(\"%d\",&k);\n    while(k!=0)\n    {\n        max=str[i];\n        for(j=i+1;j<=i+k;j++)\n          {\n              if(j==x)\n                break;\n              if(max<str[j]){max=str[j];ctr=j;}\n\n          }\n\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "253935795ab0e513105070c5256b88b4", "src_uid": "e56f6c343167745821f0b18dcf0d0cde", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "0 1 2 3 4 \naja evans\n\n\n\n#include<stdio.h>\n#include<string.h>\nchar a[32];\nint l,b[32],st,m,swp;\nint swap(int x,int y)\n{\nchar ch;\nint i;\nif(y>x)\n{\n    ch=a[y];\n    for(i=y;i>x;i--)\n    {\n        a[i]=a[i-1];\n    }\n    a[i]=ch;\n}\nreturn 0;\n}\nmain()\n{\nint i,j,k;\nscanf(\"%s %d\",a,&k);\nswp=k;\nl=strlen(a);\nst=0;\nwhile(st<l-1)\n{\n    m=a[st];\n    j=0;\n    for(i=st+1;i<l;i++)\n    {\n        if(a[i]>m)\n        {\n            m=a[i];\n            b[j]=i;\n            j++;\n        }\n    }\n    for(i=j-1;i>=0;i--)\n    {\n        if(swp>=b[i]-st)\n        {\n            swap(st,b[i]);\n            swp=swp-(b[i]-st);\n            break;\n        }\n    }\n    st++;\n}\nfor(i=0;i<l;i++)\n{\nprintf(\"%c\",a[i]);\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f78e96dead81a234226e74264a8b5872", "src_uid": "e56f6c343167745821f0b18dcf0d0cde", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include<string.h>\nint main(void)\n{\n\tchar a[30],t;\n\tint i,k,alen,max,s;\n\tscanf(\"%s\",a);\n\tscanf(\"%d\",&k);\n\talen=strlen(a);\n\twhile(k>0)\n\t{\n\t\tfor(i=0;i<alen-1;i++)\n\t\t{\n\t\t\t\tmax=i;\n\t\t\t\ts=k;\n\t\t\t\twhile(s>0)\n\t\t\t\t{\n\t\t\t\t\tif(a[i+s]>a[i])\n\t\t\t\t\t\tmax=a[max]>a[i+s]?max:i+s;\n\t\t\t\t\ts--;\n\t\t\t\t}\n\t\t\t\tif(a[max]>a[i])\n\t\t\t\t{\n\t\t\t\t\tt=a[max];\n\t\t\t\t\tk=k-max+i;\n\t\t\t\t\twhile(max-i>0)\n\t\t\t\t\t{\n\t\t\t\t\t\ta[max]=a[max-1];\n\t\t\t\t\t\tmax--;\n\t\t\t\t\t}\n\t\t\t\t\ta[i]=t;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%s\",a);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "aeab4263a06da5136bb1146e329d3da5", "src_uid": "e56f6c343167745821f0b18dcf0d0cde", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n\nint main()\n{\n    char letter = 'a';\n    char string[10100];\n    scanf(\"%s\" , string);\n\n    for(int i = 0 ; string[i] ; i++){\n        if(string[i] <= (letter) )\n        {\n            if((string[i] = letter++) == 'z')\n            {printf(string); return 0;}\n        }\n        counter++;\n    }\n    printf(\"-1\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "adade1a7701387e97a9718c21cc689c0", "src_uid": "f8ad543d499bcc0da0121a71a26db854", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    char str[100000];\n\n    scanf(\"%s\",str);\n\n    int i,j=0;\n    char sub[27]='\\0';\n\n    for(i=0;str[i]!='\\0';i++){\n        int x=str[i]-'a';\n        if(x==j){\n            sub[j]=str[i];\n            j++;\n            sub[j]='\\0';\n            if(j==26){\n                printf(\"%s\\n\",sub);\n                break;\n            }\n        }\n        else if(x==j-1){\n            sub[j]=str[i]+1;\n            j++;\n            sub[j]='\\0';\n            if(j==26){\n               printf(\"%s\\n\",sub);\n               break;\n            }\n        }\n    }\n\n    if(j<26){\n        printf(\"%d\\n\",-1);\n    }\n\n    return 0;\n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7191c9c27fdd26711b987aa55f6e8f7c", "src_uid": "f8ad543d499bcc0da0121a71a26db854", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nchar s[100001], c = 'a';\nint i;\n\nint main ()\n{\n    scanf ( \"%s\", s );\n\n    for ( i = 0; s[i]; ++ i )\n        if ( s[i] <= a ) s[i] = a ++;\n        else if ( a > 'z' ) break;\n    \n    if ( a <= 'z' ) puts ( \"-1\" );\n    else puts ( s );\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c4e2fdd746825dce9fbebec3b57cebda", "src_uid": "f8ad543d499bcc0da0121a71a26db854", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nchar s[100001], c = 'a';\nint i;\n\nint main ()\n{\n    scanf ( \"%s\", s );\n\n    for ( i = 0; s[i]; ++ i )\n        if ( s[i] <= a ) s[i] = a ++;\n    \n    if ( a <= 'z' ) puts ( \"-1\" );\n    else puts ( s );\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2ba0ad0695e221fcc1387af275d1be40", "src_uid": "f8ad543d499bcc0da0121a71a26db854", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main()\n{\n    int letter=0,i,j,len;\n    char s2[]=\"abcdefghijklmnopqrstuvwxyz\",s[100001];\n    scanf(\"%s\",s);\n    len=strlen(s);\n    for(i=0,j=97;i<len;i++)\n    {\n        if(s[i]<=j)\n        {\n            letter++;\n            j++;\n            if(letter==26)\n            {\n                break;\n            }\n        }\n    }\n    if(letter==26)\n        printf(\"%s\",s);\n    else\n        printf(\"-1\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c18261c7d1d7ea4699e96ea2cc191b31", "src_uid": "f8ad543d499bcc0da0121a71a26db854", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint m,i,c=0;\n\tscanf(\"%d\",&m);\n\tfor(i=1;i<=500005;i++)\n\t{\n\t\tint x=i;\n\t\tint ans =0;\n\t\twhile(x>0)\n\t\t{\n\t\t\tans+=x/5;\n\t\t\tx/=5;\n\t\t\t}\n\t\t\tif(ans==m)\n\t\t\t{\n\t\t\t\t++c;\n\t\t\t\tprintf(\"%d \",i);\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(c==0)\n\t\t\tprintf(\"%d\",c);\n\t\t\treturn 0;\n\t\t\t}\n\t\t", "lang_cluster": "C", "compilation_error": false, "code_uid": "a8a7334832fb43078eaed775942afb41", "src_uid": "c27ecc6e4755b21f95a6b1b657ef0744", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long e(int m)\n{return m==0?1:10*e(m-1);}\nint main()\n{\n\tint m,i;\n\twhile(~scanf(\"%d\",&m))\n\t{\n\t\tint a[2]={0,0};\n\t    long long sum=1;\n\t\tint j=0;\n\t\tfor(i=1;;i++)\n\t\t{\n\t\t\tsum*=i;\n\t\t    if(!(sum%e(m))&&sum%e(m+1))\n\t\t\t{\n\t\t\t\tif(!j)a[j]=a[j+1]=i,j=1;\n\t\t\t\telse a[j]=i;\n\t\t\t}\n\t\t\tif(!(sum%e(m+1)))break;\n\t\t}\n\t\tif(a[0])\n\t\t{\n        printf(\"%d\\n\",a[1]-a[0]+1);\n\t\tfor(;a[0]<a[1];a[0]++)printf(\"%d \",a[0]);\n\t\tprintf(\"%d\\n\",a[1]);\n\t\t}\n\t\telse printf(\"0\\n\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a7675585218d523046ffec4f611e3972", "src_uid": "c27ecc6e4755b21f95a6b1b657ef0744", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "// A Trivial Problem\n\n#include<stdio.h>\nint main(void)\n{\n\tint m,i,lt,index,count,x;\n\tscanf(\"%d\",&m);\n\t\n\tlt = m*5;\n\tcount = 0;\n\tfor(i = 5;i<=lt;i+=5)\n\t{\n\t\tif((i%5==0)&&((i/5)%5!=0))\n\t\t\tcount+=1;\n\t\telse if((i%25==0)&&((i/25)%5!=0))\n\t\t\tcount+=2;\n\t\telse if((i%125==0)&&((i/125)%5!=0))\n\t\t\tcount+=3;\n\t\telse if((i%625==0)&&((i/625)%5!=0))\n\t\t\tcount+=4;\n\t\telse if((i%3125==0)&&((i/3125)%5!=0))\n\t\t\tcount+=5;\n\t\telse if((i%15625==0)&&((i/15625)%5!=0))\n\t\t\tcount+=6;\n\t\telse if((i%78125==0)&&((i/78125)%5!=0))\n\t\t\tcount+=7;\n\t\telse if((i%390625==0)&&((i/390625)%5!=0))\n\t\t\tcount+=8;\n\n\t\tif(count==m)\n\t\t{\n\t\t\tprintf(\"%d %d %d %d %d\\n\",i,i+1,i+2,i+3,i+4);\n\t\t\tbreak;\n\t\t}\n\t\telse if(count>m)\n\t\t{\n\t\t\tprintf(\"0\\n\");\n\t\t\tbreak;\n\t\t}\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "0ed3175470c9e7b6a52881bb228d25d1", "src_uid": "c27ecc6e4755b21f95a6b1b657ef0744", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n#include <string.h>\n\ntypedef unsigned long long opo;\n\n#define S scanf\n#define P printf\n#define M malloc\n#define SI sizeof\n\n\n/*int cmp(const void *a, const void *b)\n{\n\tint *c;\n\tint *d;\n\tc = (int*)a;\n\td = (int*)b;\n\tif (*c > *d)\n\t\treturn (1);\n\tif (*c == *d)\n\t\treturn (0);\n\treturn (-1);\n}*/\n\nint main()\n{\n\tint n;\n\tS(\"%d\", &n);\n\tint a = 1;\n\tint count = 0;\n\twhile (count < n)\n\t{\n\t\ta *= 5;\n\t\tint z = a;\n\t\twhile (z % 5 == 0)\n\t\t{\n\t\t\tz /= 5;\n\t\t\tcount++;\n\t\t}\n\t}\n\tif (count == n)\n\t{\n\t\tP(\"5\\n\");\n\t\tfor (int i  = 0; i < 5; i++)\n\t\t\tP(\"%d \", a + i);\n\t\treturn (0);\n\t}\n\tP(\"0\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "cd5ca6482a5d5dc7da0f73011a8a55d2", "src_uid": "c27ecc6e4755b21f95a6b1b657ef0744", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\nlong long int ar[10000];\nlong long int a,b,c,count=0;\nlong long k,n,i,j;\nlong long two=0,five=0;\nscanf(\"%lld\",&n);\n\nfor(i=5;;i++)\n{\n    five=0;\n    for(j=5;j<=i;j=j+5)\n    {\n        k=j;\n        while(k%5==0)\n        {\n            five++;\n            k=k/5;\n        }\n\n    }\n        if(five==n){ar[count]=i;count++;}\n        if(five>n){break;}\n}\nprintf(\"%lld\\n\",count);\nfor(i=0;i<count;i++)\n{\n    printf(\"%d \",ar[i]);\n}\n//main();\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "40c30785b6c494b7bd307e661558edc8", "src_uid": "c27ecc6e4755b21f95a6b1b657ef0744", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n \nint n,k;\n \nint main(){\n\tscanf(\"%d %d\", &n,&k);\n\tfor(int i=k-1;i>0;i--){\n\t    ll val;\n\t\tif(n%i==0){\n\t\t\tprintf(\"%d\", i+(n/i)*k);\n\t\t\treturn 0;\n\t\t}\n\t}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0eccc511c7215f2b84eae9bd4b135410", "src_uid": "ed0ebc1e484fcaea875355b5b7944c57", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <cstdio>\n\nint n,k;\nint main(){\n   // freopen(\"input.txt\",\"r\",stdin);\n    scanf(\"%d %d\",&n,&k);\n    int i,x,mn=2147483640;\n    for(i=1;i<k;i++){\n        if((n/i)*i!=n)continue;\n        x=(n/i)*k+i;\n        if(mn>x)mn=x;\n    }\n    printf(\"%d\\n\",mn);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "87b364367a236307209725b615b4aa08", "src_uid": "ed0ebc1e484fcaea875355b5b7944c57", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n\tlong int a,b;\n\tscanf(\"%ld%ld\",&a,&b);\n\tint flag=1;\n\tlong int x=1;\n\twhile(flag !=0){\n\t\tint rem = (x/b);\n\t\tint mod = (x%b);\n\t\tif(rem*mod == a){\n\t\t\tflag=0;\n\t\t}\n\t\tif(flag ==0){\n\t\t\tprintf(\"%ld\\n\",x);\n\t\t}\n\t\tx = x+1;\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "cea16ddcff7d1de7f7a6ed75b2daa307", "src_uid": "ed0ebc1e484fcaea875355b5b7944c57", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n\tlong int a,b;\n\tscanf(\"%ld%ld\",&a,&b);\n\t\n\tlong int x=a+b;\n\t\n    while(1){\n        int r=x%b;\n        if(r!=0)\n\tif((x/b)*r == a) break;\n\tx++;\n}\n\t\t\tprintf(\"%ld\\n\",x);\n\n\t\t\n\t\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "18535da4cd51e3c644f8073985017ba0", "src_uid": "ed0ebc1e484fcaea875355b5b7944c57", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main()\n{\n    long long x = 0, n, k, i, j, confirm = 0;\n    scanf(\"%lld %lld\", &n, &k);\n\n    j = 1;\n    while (1)\n    {\n        for (i = 0; i < k; i++)\n            if (n % i == 0)\n            {\n                x = k * j + i;\n                if (i * j == n)\n                {\n                    confirm = 1;\n                    break;\n                }\n            }\n        if (confirm == 1)\n            break;\n        j++;\n    }\n    printf(\"%lld\\n\", x);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "83945eeedad8cfc07ac7c7e87bd0737d", "src_uid": "ed0ebc1e484fcaea875355b5b7944c57", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "/* Author Kh. Assaduzzaman Sohan  */\n\n#include<stdio.h>\n#include<string.h>\n#include<math.h>\n#define mod 100000007\nchar x[11][11],y[11][11];\nint main()\n{\n    int i,j,k,d=0,X=0;\n\n    for(i=0; i<10; i++) scanf(\"%s\",x[i]);\n\n    //for(i=0; i<10; i++) printf(\"%s\\n\",x[i]);\n\n    for(i=0; i<10; i++)\n    {\n        for(j=0; j<10; j++)\n        {\n            y[i][j]=x[j][i];\n        }\n    }\n    //Checking horizontal\n    for(i=0; i<10; i++)\n    {\n        for(j=0; j<6; j++)\n        {\n            X=0;\n            d=0;\n            if(x[i][j]=='X') X++;\n            if(x[i][j+1]=='X') X++;\n            if(x[i][j+2]=='X') X++;\n            if(x[i][j+3]=='X') X++;\n            if(x[i][j+4]=='X') X++;\n            if(x[i][j]=='.') d++;\n            if(x[i][j+1]=='.') d++;\n            if(x[i][j+2]=='.') d++;\n            if(x[i][j+3]=='.') d++;\n            if(x[i][j+4]=='.') d++;\n\n            if((X==4&&d==1)|| X==5)\n            {\n                printf(\"YES\");\n                return 0;\n            }\n        }\n    }\n    //Checking vertical\n    for(i=0; i<10; i++)\n    {\n        for(j=0; j<6; j++)\n        {\n            X=0;\n            d=0;\n            if(y[i][j]=='X') X++;\n            if(y[i][j+1]=='X') X++;\n            if(y[i][j+2]=='X') X++;\n            if(y[i][j+3]=='X') X++;\n            if(y[i][j+4]=='X') X++;\n            if(y[i][j]=='.') d++;\n            if(y[i][j+1]=='.') d++;\n            if(y[i][j+2]=='.') d++;\n            if(y[i][j+3]=='.') d++;\n            if(y[i][j+4]=='.') d++;\n\n            if((X==4&&d==1)|| X==5)\n            {\n                printf(\"YES\");\n                return 0;\n            }\n        }\n    }\n    //Checking diagonal\n    for(i=0; i<6; i++)\n    {\n        for(j=0; j<6; j++)\n        {\n            X=0;\n            d=0;\n            if(x[i][j]=='X') X++;\n            if(x[i+1][j+1]=='X') X++;\n            if(x[i+2][j+2]=='X') X++;\n            if(x[i+3][j+3]=='X') X++;\n            if(x[i+4][j+4]=='X') X++;\n            if(x[i][j]=='.') d++;\n            if(x[i+1][j+1]=='.') d++;\n            if(x[i+2][j+2]=='.') d++;\n            if(x[i+3][j+3]=='.') d++;\n            if(x[i+4][j+4]=='.') d++;\n\n            if((X==4&&d==1)|| X==5)\n            {\n                printf(\"YES\");\n                return 0;\n            }\n        }\n    }\n    for(i=9; i>=4; i--)\n    {\n        for(j=9; j>=4; j--)\n        {\n            X=0;\n            d=0;\n            if(x[i][j]=='X') X++;\n            if(x[i-1][j-1]=='X') X++;\n            if(x[i-2][j-2]=='X') X++;\n            if(x[i-3][j-3]=='X') X++;\n            if(x[i-4][j-4]=='X') X++;\n            if(x[i][j]=='.') d++;\n            if(x[i-1][j-1]=='.') d++;\n            if(x[i-2][j-2]=='.') d++;\n            if(x[i-3][j-3]=='.') d++;\n            if(x[i-4][j-4]=='.') d++;\n\n            if((X==4&&d==1)|| X==5)\n            {\n                printf(\"YES\");\n                return 0;\n            }\n        }\n    }\n        for(i=0; i<6; i++)\n    {\n        for(j=9; j>=4; j--)\n        {\n            X=0;\n            d=0;\n            if(x[i][j]=='X') X++;\n            if(x[i+1][j-1]=='X') X++;\n            if(x[i+2][j-2]=='X') X++;\n            if(x[i+3][j-3]=='X') X++;\n            if(x[i+4][j-4]=='X') X++;\n            if(x[i][j]=='.') d++;\n            if(x[i+1][j-1]=='.') d++;\n            if(x[i+2][j-2]=='.') d++;\n            if(x[i+3][j-3]=='.') d++;\n            if(x[i+4][j-4]=='.') d++;\n\n            if((X==4&&d==1)|| X==5)\n            {\n                printf(\"YES\");\n                return 0;\n            }\n        }\n    }\n        for(i=9; i>=4; i--)\n    {\n        for(j=0; j<6; j++)\n        {\n            X=0;\n            d=0;\n            if(x[i][j]=='X') X++;\n            if(x[i-1][j+1]=='X') X++;\n            if(x[i-2][j+2]=='X') X++;\n            if(x[i-3][j+3]=='X') X++;\n            if(x[i-4][j+4]=='X') X++;\n            if(x[i][j]=='.') d++;\n            if(x[i-1][j+1]=='.') d++;\n            if(x[i-2][j+2]=='.') d++;\n            if(x[i-3][j+3]=='.') d++;\n            if(x[i-4][j+4]=='.') d++;\n\n            if((X==4&&d==1)|| X==5)\n            {\n                printf(\"YES\");\n                return 0;\n            }\n        }\n    }\n    printf(\"NO\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4b246b7bc932d30659f6d6190daf45da", "src_uid": "d5541028a2753c758322c440bdbf9ec6", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<algorithm>\n#include<iostream>\n#include<queue>\n#include<vector>\n#include<stack>\n#include<set>\n#include<map>\n#include<cstdio>\nusing namespace std;\nchar a[12][12];\ntypedef struct node {\n\tint aa,bb,cc,dd,ee,ff,gg,hh;\n} node;\nnode b[11][11];\nint c[]= {-1,-1,-1,0,1,1,1,0};\nint d[]= {-1,0,1,-1,1,0,-1,1};\nint dfs(int e,int w,int t,int p) {\n\tif(e<1||e>10||w<1||e>10||a[e][w]=='O') {\n\t\treturn p;\n\t}\n\tif(p!=0&&a[e][w]=='.')  return p;\n\tif(a[e][w]=='X')  p++;\n\tint xx=e+c[t];\n\tint yy=w+d[t];\n\tdfs(xx,yy,t,p);\n}\nint main() {\n\tfor(int i=1; i<=10; i++) {\n\t\tfor(int j=1; j<=10; j++) {\n\t\t\tscanf(\"%c\",&a[i][j]);\n\t\t}\n\t\tgetchar();\n\t}\n\tint flag=0;\n\tfor(int i=1; i<=10; i++) {\n\t\tfor(int j=1; j<=10; j++) {\n\t\t\tif(a[i][j]=='.') {\n\t\t\t\tfor(int k=0; k<=3; k++) {\n\t\t\t\t\tint sum=dfs(i,j,k,0)+dfs(i,j,k+4,0);\n\t\t\t\t\tif(sum>=4) {\n\t\t\t\t\t\tflag=1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag==1)  break;\n\t\t}\n\t\tif(flag==1)  break;\n\t}\n\tif(flag==1)  printf(\"YES\\n\");\n\telse printf(\"NO\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3dde51e73d5a3ae0b86213d8c4a6a569", "src_uid": "d5541028a2753c758322c440bdbf9ec6", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <iostream>\nusing namespace std;\nint main(){\n\n    int i=0,j;\n    char matrix[10][10];\n    char s[12];\n\n\n    while(i<10){\n        scanf(\"%s\",s);\n        for(j=0;j<10;j++){\n            matrix[i][j]=s[j];\n        }\n        i++;\n    }\n\n\n    for (i=0;i<10;i++){\n        for (j=0;j<10;j++){\n            if (matrix[i][j]=='X'){   //achou o primeiro x\n                if ((matrix[i][j-1]=='.')&&(matrix[i][j+1]=='X')&&(matrix[i][j+2]=='X')&&(matrix[i][j+3]=='X')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n                if ((matrix[i][j+1]=='.')&&(matrix[i][j+2]=='X')&&(matrix[i][j+3]=='X')&&(matrix[i][j+4]=='X')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n                if ((matrix[i][j+1]=='X')&&(matrix[i][j+2]=='.')&&(matrix[i][j+3]=='X')&&(matrix[i][j+4]=='X')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n                if ((matrix[i][j+1]=='X')&&(matrix[i][j+2]=='X')&&(matrix[i][j+3]=='.')&&(matrix[i][j+4]=='X')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n                if ((matrix[i][j+1]=='X')&&(matrix[i][j+2]=='X')&&(matrix[i][j+3]=='X')&&(matrix[i][j+4]=='.')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n\n\n\n\n\n                if ((matrix[i-1][j]=='.')&&(matrix[i+1][j]=='X')&&(matrix[i+2][j]=='X')&&(matrix[i+3][j]=='X')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n                if ((matrix[i+1][j]=='.')&&(matrix[i+2][j]=='X')&&(matrix[i+3][j]=='X')&&(matrix[i+4][j]=='X')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n                if ((matrix[i+1][j]=='X')&&(matrix[i+2][j]=='.')&&(matrix[i+3][j]=='X')&&(matrix[i+4][j]=='X')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n                if ((matrix[i+1][j]=='X')&&(matrix[i+2][j]=='X')&&(matrix[i+3][j]=='.')&&(matrix[i+4][j]=='X')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n                if ((matrix[i+1][j]=='X')&&(matrix[i+2][j]=='X')&&(matrix[i+3][j]=='X')&&(matrix[i+4][j]=='.')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n\n\n\n\n                if ((matrix[i-1][j-1]=='.')&&(matrix[i+1][j+1]=='X')&&(matrix[i+2][j+2]=='X')&&(matrix[i+3][j+3]=='X')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n                if ((matrix[i+1][j+1]=='.')&&(matrix[i+2][j+2]=='X')&&(matrix[i+3][j+3]=='X')&&(matrix[i+4][j+4]=='X')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n                if ((matrix[i+1][j+1]=='X')&&(matrix[i+2][j+2]=='.')&&(matrix[i+3][j+3]=='X')&&(matrix[i+4][j+4]=='X')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n                if ((matrix[i+1][j+1]=='X')&&(matrix[i+2][j+2]=='X')&&(matrix[i+3][j+3]=='.')&&(matrix[i+4][j+4]=='X')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n                if ((matrix[i+1][j+1]=='X')&&(matrix[i+2][j+2]=='X')&&(matrix[i+3][j+3]=='X')&&(matrix[i+4][j+4]=='.')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n\n\n\n\n                if ((matrix[i-1][j+1]=='.')&&(matrix[i+1][j-1]=='X')&&(matrix[i+2][j-2]=='X')&&(matrix[i+3][j-3]=='X')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n                if ((matrix[i+1][j-1]=='.')&&(matrix[i+2][j-2]=='X')&&(matrix[i+3][j-3]=='X')&&(matrix[i+4][j-4]=='X')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n                if ((matrix[i+1][j-1]=='X')&&(matrix[i+2][j-2]=='.')&&(matrix[i+3][j-3]=='X')&&(matrix[i+4][j-4]=='X')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n                if ((matrix[i+1][j-1]=='X')&&(matrix[i+2][j-2]=='X')&&(matrix[i+3][j-3]=='.')&&(matrix[i+4][j-4]=='X')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n                if ((matrix[i+1][j-1]=='X')&&(matrix[i+2][j-2]=='X')&&(matrix[i+3][j-3]=='X')&&(matrix[i+4][j-4]=='.')){\n                    printf(\"YES\\n\");\n                    exit(0);\n                }\n                printf(\"NO\\n\");\n                exit(0);\n            }\n        }\n    }\n}\n\n/* 1519395180448 */\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c6dff74a0cd3a2ef4513ed8a1fbe8a46", "src_uid": "d5541028a2753c758322c440bdbf9ec6", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#define _CRT_SECURE_NO_WARNINGS\n#include <stdio.h>\n\nchar matrix[10][10];\nchar trash;\nint found = 0;\n\nint main()\n{\n\tint i, ii, j, jj;\n\tint count = 0, step = 0;\n\t\n\tfor (i = 0; i < 10; i++)\n\t{\n\t\tfor (j = 0; j < 10; j++)\n\t\t{\n\t\t\tscanf(\"%c\", &matrix[i][j]);\n\t\t}\n\t\tscanf(\"%c\", &trash);\n\t}\n\n\tfor (i = 0; i < 10; i++)\n\t{\n\t\tfor (j = 0; j < 10; j++)\n\t\t{\n\t\t\tif (matrix[i][j] == '.')\n\t\t\t{\n\t\t\t\t//down\n\t\t\t\tjj = j;\n\t\t\t\tii = i;\n\t\t\t\twhile (ii < 9 && step < 5);\n\t\t\t\t{\n\t\t\t\t\tii++;\n\t\t\t\t\tif (matrix[ii][jj] == 'X')\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tstep++;\n\t\t\t\t\t\tif (count == 4)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\t\t\treturn 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t} \n\t\t\t\t\n\t\t\t\t// up\n\t\t\t\tjj = j;\n\t\t\t\tii = i;\n\t\t\t\twhile (ii >= 1 && step < 5)\n\t\t\t\t{\n\t\t\t\t\tii--;\n\t\t\t\t\tif (matrix[ii][jj] == 'X')\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tstep++;\n\t\t\t\t\t\tif (count == 4)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\t\t\treturn 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t} \n\t\t\t\t\n\t\t\t\tcount = 0;\n\t\t\t\tstep = 0;\n\n\t\t\t\t//right\n\t\t\t\tjj = j;\n\t\t\t\tii = i;\n\t\t\t\twhile (jj < 9 && step < 5);\n\t\t\t\t{\n\t\t\t\t\tjj++;\n\t\t\t\t\tif (matrix[ii][jj] == 'X')\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tstep++;\n\t\t\t\t\t\tif (count == 4)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\t\t\treturn 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t} \n\n\t\t\t\t// left\n\t\t\t\tjj = j;\n\t\t\t\tii = i;\n\t\t\t\twhile (jj >= 1 && step < 5)\n\t\t\t\t{\n\t\t\t\t\tjj--;\n\t\t\t\t\tif (matrix[ii][jj] == 'X')\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tstep++;\n\t\t\t\t\t\tif (count == 4)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\t\t\treturn 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tcount = 0;\n\t\t\t\tstep = 0;\n\n\t\t\t\t//right up\n\t\t\t\tjj = j;\n\t\t\t\tii = i;\n\t\t\t\twhile (ii >= 1 && jj < 9 && step < 5);\n\t\t\t\t{\n\t\t\t\t\tii--;\n\t\t\t\t\tjj++;\n\t\t\t\t\tif (matrix[ii][jj] == 'X')\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tstep++;\n\t\t\t\t\t\tif (count == 4)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\t\t\treturn 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\t// left down\n\t\t\t\tjj = j;\n\t\t\t\tii = i;\n\t\t\t\twhile (ii < 9 && jj >= 1 && step < 5)\n\t\t\t\t{\n\t\t\t\t\tii++;\n\t\t\t\t\tjj--;\n\t\t\t\t\tif (matrix[ii][jj] == 'X')\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tstep++;\n\t\t\t\t\t\tif (count == 4)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\t\t\treturn 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tcount = 0;\n\t\t\t\tstep = 0;\n\n\t\t\t\t//left up\n\t\t\t\tjj = j;\n\t\t\t\tii = i;\n\t\t\t\twhile (ii >= 1 && jj >= 1 && step < 5)\n\t\t\t\t{\n\t\t\t\t\tii--;\n\t\t\t\t\tjj--;\n\t\t\t\t\tif (matrix[ii][jj] == 'X')\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tstep++;\n\t\t\t\t\t\tif (count == 4)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\t\t\treturn 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\t// right down\n\t\t\t\tjj = j;\n\t\t\t\tii = i;\n\t\t\t\twhile (ii < 9 && jj < 9 && step < 5)\n\t\t\t\t{\n\t\t\t\t\tii++;\n\t\t\t\t\tjj++;\n\t\t\t\t\tif (matrix[ii][jj] == 'X')\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tstep++;\n\t\t\t\t\t\tif (count == 4)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\t\t\treturn 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tcount = 0;\n\t\t\t\tstep = 0;\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"NO\\n\");\n\n\treturn 0;\n}\n\n/* 1519409842134 */\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "70bc89f69354f350b4795e51c53bdbe5", "src_uid": "d5541028a2753c758322c440bdbf9ec6", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#define _CRT_SECURE_NO_WARNINGS\n#include <stdio.h>\n\nchar matrix[10][10];\nchar trash;\nint found = 0;\n\nint main()\n{\n\tint i, ii, j, jj;\n\tint count = 0, step = 0;\n\t\n\tfor (i = 0; i < 10; i++)\n\t{\n\t\tfor (j = 0; j < 10; j++)\n\t\t{\n\t\t\tscanf(\"%c\", &matrix[i][j]);\n\t\t}\n\t\tscanf(\"%c\", &trash);\n\t}\n\n\tfor (i = 0; i < 10; i++)\n\t{\n\t\tfor (j = 0; j < 10; j++)\n\t\t{\n\t\t\tif (matrix[i][j] == '.')\n\t\t\t{\n\t\t\t\t//down\n\t\t\t\tjj = j;\n\t\t\t\tii = i;\n\t\t\t\twhile (ii < 9 && step < 5);\n\t\t\t\t{\n\t\t\t\t\tii++;\n\t\t\t\t\tif (matrix[ii][jj] == 'X')\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tstep++;\n\t\t\t\t\t\tif (count == 4)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\t\t\treturn 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t} \n\t\t\t\t\n\t\t\t\t// up\n\t\t\t\tjj = j;\n\t\t\t\tii = i;\n\t\t\t\twhile (ii >= 1 && step < 5)\n\t\t\t\t{\n\t\t\t\t\tii--;\n\t\t\t\t\tif (matrix[ii][jj] == 'X')\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tstep++;\n\t\t\t\t\t\tif (count == 4)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\t\t\treturn 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t} \n\t\t\t\t\n\t\t\t\tcount = 0;\n\t\t\t\tstep = 0;\n\n\t\t\t\t//right\n\t\t\t\tjj = j;\n\t\t\t\tii = i;\n\t\t\t\twhile (jj < 9 && step < 5);\n\t\t\t\t{\n\t\t\t\t\tjj++;\n\t\t\t\t\tif (matrix[ii][jj] == 'X')\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tstep++;\n\t\t\t\t\t\tif (count == 4)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\t\t\treturn 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t} \n\n\t\t\t\t// left\n\t\t\t\tjj = j;\n\t\t\t\tii = i;\n\t\t\t\twhile (jj >= 1 && step < 5)\n\t\t\t\t{\n\t\t\t\t\tjj--;\n\t\t\t\t\tif (matrix[ii][jj] == 'X')\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tstep++;\n\t\t\t\t\t\tif (count == 4)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\t\t\treturn 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tcount = 0;\n\t\t\t\tstep = 0;\n\n\t\t\t\t//right up\n\t\t\t\tjj = j;\n\t\t\t\tii = i;\n\t\t\t\twhile (ii >= 1 && jj < 9 && step < 5);\n\t\t\t\t{\n\t\t\t\t\tii--;\n\t\t\t\t\tjj++;\n\t\t\t\t\tif (matrix[ii][jj] == 'X')\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tstep++;\n\t\t\t\t\t\tif (count == 4)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\t\t\treturn 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\t// left down\n\t\t\t\tjj = j;\n\t\t\t\tii = i;\n\t\t\t\twhile (ii < 9 && jj >= 1 && step < 5)\n\t\t\t\t{\n\t\t\t\t\tii++;\n\t\t\t\t\tjj--;\n\t\t\t\t\tif (matrix[ii][jj] == 'X')\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tstep++;\n\t\t\t\t\t\tif (count == 4)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\t\t\treturn 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tcount = 0;\n\t\t\t\tstep = 0;\n\n\t\t\t\t//left up\n\t\t\t\tjj = j;\n\t\t\t\tii = i;\n\t\t\t\twhile (ii >= 1 && jj >= 1 && step < 5)\n\t\t\t\t{\n\t\t\t\t\tii--;\n\t\t\t\t\tjj--;\n\t\t\t\t\tif (matrix[ii][jj] == 'X')\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tstep++;\n\t\t\t\t\t\tif (count == 4)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\t\t\treturn 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\t// right down\n\t\t\t\tjj = j;\n\t\t\t\tii = i;\n\t\t\t\twhile (ii < 9 && jj < 9 && step < 5)\n\t\t\t\t{\n\t\t\t\t\tii++;\n\t\t\t\t\tjj++;\n\t\t\t\t\tif (matrix[ii][jj] == 'X')\n\t\t\t\t\t{\n\t\t\t\t\t\tcount++;\n\t\t\t\t\t\tstep++;\n\t\t\t\t\t\tif (count == 4)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\t\t\treturn 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tcount = 0;\n\t\t\t\tstep = 0;\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"NO\\n\");\n\n\treturn 0;\n}\n\n/* 1519409463713 */\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d93206acab7c6ef55fa4607cdde17a98", "src_uid": "d5541028a2753c758322c440bdbf9ec6", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint i, j, k;\n\tint n, m;\n\tint a, b, c;\n\tint x, y;\n\tdouble l;\n\t__int64 ll;\n    __int64 sum = 0;\n\t__int64 int temp;\n\tscanf(\"%d %d\", &m, &b);\n\tfor (i = 0; i <= m*b; i++)\n\t{\n\t\ttemp = 0;\n\t\ty = b - i / m;\n\t\tl = b - (i*1.0) / m;\n\t\tif (l < y)\n\t\t{\n\t\t\ty -= 1;\n\t\t}\n\t\tll=i+1;\n\t\tll*=i;\n\t\tll/=2;\n\t\tll*=(y+1);\n\t\ttemp+=ll;\n     \t//temp += (((i+1)*i)/2)*(y + 1);\n     \tll=y;\n     \tll*=y+1;\n     \tll/=2;\n     \tll*=y+1;\n\t\t\n\t  temp+=ll;\t\n\t//temp += ((y*(y+1))/2)*(i + 1);\n\t\tif (sum <= temp)\n\t\t{\n\t\t\tsum = temp;\n\t\t}\n\t}\n\tprintf(\"%I64d\\n\", sum);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ba4d80a1249b395ee6126d93a07a7966", "src_uid": "9300f1c07dd36e0cf7e6cb7911df4cf2", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int m,b;\n    scanf(\"%d %d\",&m, &b);\n    int i;\n    long long int max=0,ans;\n    for(i=0;i<=b;i++)\n    {\n        ans=(i*(i+1))/2;\n        ans*=((m*b-m*i+1));\n        ans+=(i+1)*((m*b-m*i)*(m*b-m*i+1))/2;\n        if(max<ans)\n            max=ans;\n    }\n    printf(\"%lld\\n\",max);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0bab19e21a1e5f373bd5ac40699157b9", "src_uid": "9300f1c07dd36e0cf7e6cb7911df4cf2", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint ZA[10000][10000];\n\nint main()\n{\n\tint x, x1, y, z, z1, m, b;\n\n\tscanf(\"%d%d\", &m, &b);\n\tfor (y = b; y >= 0; --y) {\n\t\tx1 = floor((b - y) * m);\n\t\tfor (x = 0; x <= x1; ++x)\n\t\t\tZA[x][y] = x + y;\n\t}\n\tz1 = 0;\n\tfor (y = 0; y <= b; ++y) {\n\t\tx1 = floor((b - y) * m);\n\t\tfor (x = 0; x <= x1; ++x) {\n\t\t\tz = 0;\n\t\t\tif (x > 0)\n\t\t\t\tz += ZA[x - 1][y];\n\t\t\tif (y > 0)\n\t\t\t\tz += ZA[x][y - 1];\n\t\t\tif (x > 0 && y > 0)\n\t\t\t\tz -= ZA[x - 1][y - 1];\n\t\t\tZA[x][y] += z;\n\t\t\tif (ZA[x][y] > z1)\n\t\t\t\tz1 = ZA[x][y];\n\t\t}\t\t\n\t}\n\tprintf(\"%d\\n\", z1);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "08637d859f257c6805963d28023fab4a", "src_uid": "9300f1c07dd36e0cf7e6cb7911df4cf2", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<math.h>\n#include<stdlib.h>\n\nint cmpfunc (const void * a, const void * b)\n{\n    return ( *(int*)a - *(int*)b );\n}\n\nmain()\n{\n    //freopen(\"in.txt\", \"r\", stdin);\n    int m, b, n, i, j, max, k;\n\n    scanf(\"%d %d\", &m, &b);\n\n    int a[b-1][3];\n\n    j = 1;\n    max = 0;\n    for(i = 1; i<b; i++)\n    {\n        a[i][0] = m*(b-i)*i;\n        a[i][1] = i;\n        a[i][2] = m*(b-i);\n        if(a[i][0]>max)\n            {max = a[i][0]; j = i;}\n\n            //printf(\"%d \", a[i]);\n    }\n\n    long long sum = 0, sum1, sum2;\n\n    for(i = 0; i<=a[j][1]; i++)\n    {\n        for(k = 0; k<=a[j][2]; k++)\n        {sum = sum + k + i;}\n    }\n\n    sum1 = b*(b+1)/2;\n    sum2 = (m*b)(m*b+1)/2;\n\n    sum1 = sum1>sum2?sum1:sum2;\n    sum = sum>sum1?sum:sum1;\n\n    printf(\"%I64d\", sum);\n\n\n\n\n}\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6e60b572b5af5ca6ad45d6d4d86ba22f", "src_uid": "9300f1c07dd36e0cf7e6cb7911df4cf2", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "int main()\n{\n\tint i, j, k;\n\tint n, m;\n\tint a, b, c;\n\tint x, y;\n\tdouble l;\n\t__int64 sum = 0;\n\t __int64 temp;\n\tscanf(\"%d %d\", &m, &b);\n\tfor (i = m*b; i >=(m*b)/(m+1)-1; i--)\n\t{\n\t\ttemp = 0;\n\t\ty = b - i / m;\n\t\tl = b - (i*1.0) / m;\n\t\tif (l < y)\n\t\t{\n\t\t\ty -= 1;\n\t\t}\n\t\tfor (j = 0; j <= i; j++)\n\t\t{\n\t\t\ttemp += j*(y+1);\n\t\t}\n\t\tfor (j = 0; j <= y; j++)\n\t\t{\n\t\t\ttemp += j*(i+1);\n\t\t}\n\t\tif (sum <= temp)\n\t\t{\n\t\t\tsum = temp;\n\t\t}\n\t}\n\tprintf(\"%I64d\\n\", sum);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5ecb9572c22a84736d846e95e488954a", "src_uid": "9300f1c07dd36e0cf7e6cb7911df4cf2", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "main()\n{int i,q,r,temp,t,a[15]={0},b[15]={0},s[15]={0},j,k;\nfor(i=1;i<=14;i++)scanf(\"%d\",&a[i]);\nfor(i=1;i<=14;i++)\n{for(q=1;q<=14;q++) \n{b[q]=a[q];}\nif (a[i]>0)\n{j=i;\nwhile(b[i]!=0)\n{t=j+1;\nif (t>14) t=t-14;\nb[t]+=1;b[i]--;j++;}\nfor (r=1;r<=14;r++)\n{if (b[r]%2==0) s[i]+=b[r];}\n}\n}\n//for(i=1;i<=14;i++) printf(\"\\n%d\",s[i]);\nfor(j=1;j<=13;j++)\nif (s[j]>s[j+1])\n{temp=s[j];s[j]=s[j+1];s[j+1]=temp;}\nprintf(\"\\n%d\",s[14]);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "85b914a61cc8ff511f137c7b9305734c", "src_uid": "1ac11153e35509e755ea15f1d57d156b", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#include <string.h>\n#include <ctype.h>\n#include <limits.h>\n#include <malloc.h>\n#include <memory.h>\nint i,j,a[101],s[101]={0},max;\n\nint main()\n{\n\tfor (i=1;i<=14;i++) scanf(\"%d\",&a[i]);\n\tfor (i=15;i<=28;i++) a[i]=a[i-14];\n\tfor (i=1;i<=14;i++)\n\tif (a[i])\n\t{\n\t\t\n\t\tfor (j=i+1;j<=i+a[i];j++) \n\t\tif (a[j]%2==1) s[i]+=a[j]+1;\n\t}\n\tfor (i=1,max=0;i<=14;i++) max=max>s[i] ? max : s[i];\n\tprintf(\"%d\\n\",max);\n\treturn 0;\n} \n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "82698c788eda879abe38450a500accdb", "src_uid": "1ac11153e35509e755ea15f1d57d156b", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define int long long int\n#define inti int\ninti main()\n{\n    int a[14] ;\n    int d[14];\n    for(int i = 0; i<14;i++) scanf(\"%lld\",&a[i]);\n    for(int i = 0; i<14;i++) d[i] = a[i];\n    int c ; int c1 = 0; int c2 = 0;\n    for(int i = 0; i<14;i++)\n    {\n        int b = a[i];\n        if(b>0)\n        {\n            d[i] = 0;\n            if(i!=13) c = i+1;\n            else c = 0;\n            for(int j = 1;j<=b;j++)\n            {\n                d[c] = d[c]+1;\n                if(c!=13) c++;\n                else c = 0;\n            }\n        }\n        \n        for(int j = 0; j<13; j++)\n        {\n            if(d[j]%2==0) c1 = c1+d[j];\n        }\n        \n        if(c1>c2) c2 = c1 ;\n        c1 = 0;\n        for(int j = 0; j<14;j++) d[i] = a[i];\n    }\n    \n    printf(\"%lld\",c2);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "0d5edfa7b3bfbcb42cb20c08f4f1d13e", "src_uid": "1ac11153e35509e755ea15f1d57d156b", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\t//code\n\tint a[14],c=0;\n\tfor(int i=0;i<14;i++)\n\t    scanf(\"%d\",a+i);\n\tint b[14];\n\tfor(int i=0;i<14;i++)\n\t{\n\t    if(a[i]==0) continue;\n\t    for(int j=0;j<14;j++)\n\t        b[j]=a[j];\n\t    int m1=a[i]/14,m2=a[i]%14,s=0;\n\t    b[i]=0;\n\t    for(int j=0;j<14;j++)\n\t        b[j]=b[j]+m1;\n\t    int j=i;\n\t    while(m2--)//do something\n\t    {\n\t        if(j==13) j=0;\n\t        else j++;\n\t        b[j]++;\n\t    }\n        for(j=0;j<14;j++)\n            if(b[j]%2==0) s=s+b[j];\n        if(s>c) c=s;\n\t}\n\tprintf(\"%d\",c);\n\treturn 0;\n}#include <stdio.h>\n\nint main()\n{\n\t//code\n\tint a[14],c=0;\n\tfor(int i=0;i<14;i++)\n\t    scanf(\"%d\",a+i);\n\tint b[14];\n\tfor(int i=0;i<14;i++)\n\t{\n\t    if(a[i]==0) continue;\n\t    for(int j=0;j<14;j++)\n\t        b[j]=a[j];\n\t    int m1=a[i]/14,m2=a[i]%14,s=0;\n\t    b[i]=0;\n\t    for(int j=0;j<14;j++)\n\t        b[j]=b[j]+m1;\n\t    int j=i;\n\t    while(m2--)//do something\n\t    {\n\t        if(j==13) j=0;\n\t        else j++;\n\t        b[j]++;\n\t    }\n        for(j=0;j<14;j++)\n            if(b[j]%2==0) s=s+b[j];\n        if(s>c) c=s;\n\t}\n\tprintf(\"%d\",c);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "eb6389a33df259510b36b6f914c1522f", "src_uid": "1ac11153e35509e755ea15f1d57d156b", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define n 14\nint main(){\n    int count=0,max=0,b,c,a[14],b[14],c[14];\n    for(int i=0;i<14;i++){\n        scanf(\"%d\",&a[i]);\n    }\n    for(int i=0;i<14;i++){b[i]=1;}\n    for(int i=0;i<14;i++){\n    c[i]=a[i];}\n   \n    for(int i=0;i<n;i++){\n    \tint t = i;\n    \tif(c[i]>14){\n    \t\tint a =c[i]; c[i]=0;\n    \t\tb = a/n;\n    \t\tfor(int i=0;i<n;i++){\n    \t\t\tc[i]+=a;\n\t\t\t}\n\t\t\tb = a%n;\n\t\t\tfor(int i=0;i<b;i++){\n\t\t\t\tc[(t+1)%14]+=1;\n\t\t\t}\n\t\t}\n\t\telse{\n\t\t    b = a%n;\n\t\t\tfor(int i=0;i<b;i++){\n\t\t\t\tc[(t+1)%14]+=1;\n\t\t\t}\n\t}\n\tfor(int i=0;i<n;i++){\n\t\tif(c[i]%2==0)count+=c[i];\n\t}\n\tif(count>max)max=count;\n\tcount = 0;\n\tfor(int i=0;i<14;i++)c[i]=a[i];\n\t\n\t}\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "12504b25e37af434316adad4c89dbb78", "src_uid": "1ac11153e35509e755ea15f1d57d156b", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n#include<math.h>\r\nint main(){\r\n   int n=0;\r\n   scanf(\"%d\",&n);\r\n   if(n==1)\r\n    printf(\"3\");\r\n    else if(n==2)\r\n    printf(\"5\");\r\n    else\r\n    printf(\"%d\",(4+n+(n-3)/3));\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e14e1d535ea32eab8d8e6871b47ba4fa", "src_uid": "d0a8604b78ba19ab769fd1ec90a72e4e", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n#include<math.h>\r\nint main(){\r\n   int n=0;\r\n   scanf(\"%d\",&n);\r\n   if(n==1)\r\n    printf(\"3\");\r\n    else if(n==2)\r\n    printf(\"5\");\r\n    else\r\n    printf(\"%d\",(4+n+(n-3)/3));\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "fd018500ad823f883e9019194c1382b0", "src_uid": "d0a8604b78ba19ab769fd1ec90a72e4e", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\nint main() {\r\n    long long int n, min;\r\n    scanf(\"%lld\", &n);\r\n    if(n <= 3) {\r\n        printf(\"%lld\", n*2+1);\r\n    }\r\n    else if(n == 4){\r\n        printf(\"%lld\", n*2);\r\n    }\r\n    else if((n-1) % 3 == 0) {\r\n        printf(\"%lld\", n*2-(((n-4)/3)*2));\r\n    }\r\n    else if(n % 3 == 0){\r\n        min = ((n-3)/3)-1;\r\n        min *= 2;\r\n        min++;\r\n        printf(\"%lld\", (n*2)-min);\r\n    }\r\n    else {\r\n        min = ((n-2)/3)-1;\r\n        min *= 2;\r\n        min++;\r\n        printf(\"%lld\", (n*2)-min);\r\n    }\r\n    return 0;\r\n}\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1b1549c5d6beb4fc90599789825fed27", "src_uid": "d0a8604b78ba19ab769fd1ec90a72e4e", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\nint main(){\r\n    long long int n,j=3;\r\n    scanf(\"%lld\",&n);\r\n    if(n<=3){\r\n        printf(\"%lld\",(2*n+1));\r\n    }else{\r\n        if(n%3==1){\r\n            printf(\"%lld \",(4*(1+(n/3))));\r\n        }else if(n%3==2){\r\n            n=n-n/3;\r\n            printf(\"%lld\",(2*n+1));\r\n        }else if(n%3==0){\r\n            n=n-n/3+1;\r\n            printf(\"%lld\",(2*n+1));\r\n        }\r\n    }\r\n    // if(n==1){\r\n    //     printf(\"3\");\r\n    // }else if(n==2){\r\n    //     printf(\"5\");\r\n    // }else {\r\n    //     if((2*j)%4==0){\r\n\r\n    //     }else{\r\n    //         printf(\"%lld\",(2*j+1));\r\n\r\n    //     }\r\n    // }\r\n     return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f097b8ccfa9cf2486b198a693112a1d0", "src_uid": "d0a8604b78ba19ab769fd1ec90a72e4e", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n\tlong long int n, ans;\n        int diff[3] = {0,1,3};\n\tscanf(\"%lld\",&n);\n\tans = n - 1;\n\tif(ans == 0)\n\t\tans = 3;\n\telse\t\n\t\tans =  4 + 4 * (ans / 3) + diff[ans%3] ;\n\tprintf(\"%lld\\n\",ans);\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "97d3dded2236e16bbf8b4bd4d3ddd2ed", "src_uid": "d0a8604b78ba19ab769fd1ec90a72e4e", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<cstdio>\nint main() {\n\tint a,b,c,d,e,f;\n\tscanf(\"%d%d%d%d%d%d\",&a,&b,&c,&d,&e,&f);\n\tprintf(\"%d\",(a+b+c)*(a+b+c)-a*a-c*c-e*e);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5635ffbac5d26af3c89c9737ccdec429", "src_uid": "382475475427f0e76c6b4ac6e7a02e21", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int a1,a2,a3,a4,a5,a6;\n    scanf(\"%d%d%d%d%d%d\",&a1,&a2,&a3,&a4,&a5,&a6);\n    int x=(a1+a2+a3)*(a1+a2+a3)-a1*a1-a3*a3-a5*a5;\n    printf(\"%d\\n\",ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "07918cec10acbe93240341c38818e451", "src_uid": "382475475427f0e76c6b4ac6e7a02e21", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void)\n{\n    int a[6];\n    int i;\n\n    for(i=0; i<6; i++)\n    {\n        scanf(\"%d\", &a[i]);\n    }\n\n    printf(\"%d\", a[0]+a[1]+a[2])*(a[0]+a[1]+a[2])-a[0]*a[0]-a[2]*a[2]-a[4]*a[4]);\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5a989234fd594780d6c9bc490a620d01", "src_uid": "382475475427f0e76c6b4ac6e7a02e21", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n#include <cstdio>\nusing namespace std;\n\nint main() {\n    int a,b,v1,v2,i=3,is,ans;\n    while(i--) is=scanf(\"%d %d\",&a,&b);\n    v1=a,v2=b;\n    ans=2*b+1;\n    int count=0;\n    while(v1--) {ans+=2*(b+(++count));}\n    while(v2--) {ans+=2*(b+(count--));}\n    printf(\"%d\",ans);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "037997045d1fe936bb270df6e9f9b179", "src_uid": "382475475427f0e76c6b4ac6e7a02e21", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    int a[6];\n    for(int i=0;i<6;i++) \n        scanf(\"%d\",&a[i]);\n    int rem = (a[0] + a[1] + a[2]);\n    rem = rem*rem;\n    rem -= a[0]*a[0];\n    rem -= a[2]*a[2];\n    rem -= a[4]*a[4];\n    printf(\"%d\\n\",rem);;\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "05fc99fbff365c2b452f24907a35d860", "src_uid": "382475475427f0e76c6b4ac6e7a02e21", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h> \nvoid quicksort(int x[1000],int first,int last){\n    int pivot,j,temp,i;\n\n     if(first<last){\n         pivot=first;\n         i=first;\n         j=last;\n\n         while(i<j){\n             while(x[i]<=x[pivot]&&i<last)\n                 i++;\n             while(x[j]>x[pivot])\n                 j--;\n             if(i<j){\n                 temp=x[i];\n                  x[i]=x[j];\n                  x[j]=temp;\n             }\n         }\n\n         temp=x[pivot];\n         x[pivot]=x[j];\n         x[j]=temp;\n         quicksort(x,first,j-1);\n         quicksort(x,j+1,last);\n\n    }\n}\nint main()\n{\n    int n,tab[1000],i,j,x,s=0;\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&tab[i]);\n        }\n    \n    scanf(\"%d\",&x);\n    quicksort( tab, 0,n);\n    \n    i=0;\n    while (i<n)\n    {\n        \n    j=i+1;\n    while(tab[j]-tab[i]==1)\n    {\n        j++;\n        s++;\n    }\n    i++;\n    }\n    printf(\"%d\",s);\n    return(0);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "06c0a108a61a170f54a9224c5db5d79e", "src_uid": "086d07bd6f9031df09bd6a6e8fe8f25c", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint absl(int x){\n\tif (x<0) return -x;\n\telse return x;\n}\n\nint main(){\n\tint st[100];\n\tint n,i,j,max,count,t;\n\tscanf(\"%d\",&n);\n\tfor (i=0;i<n;i++){\n\t\tscanf(\"%d\",&st[i]);\n\t}\n\tscanf(\"%d\",&t);\n\tmax=1;\n\tfor (i=0;i<n;i++){\n\t\tcount=1;\n\t\tfor (j=i+1;j<n-1;j++){\n\t\t\tif (absl(st[i]-st[j])<=t) count++;\n\t\t}\t\n\t\tif (max<count) max=count;\n\t}\n\tprintf(\"%d\\n\",max);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5d0057f41917d46219950073f0d19901", "src_uid": "086d07bd6f9031df09bd6a6e8fe8f25c", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h> \nvoid quicksort(int x[1000],int first,int last){\n    int pivot,j,temp,i;\n\n     if(first<last){\n         pivot=first;\n         i=first;\n         j=last;\n\n         while(i<j){\n             while(x[i]<=x[pivot]&&i<last)\n                 i++;\n             while(x[j]>x[pivot])\n                 j--;\n             if(i<j){\n                 temp=x[i];\n                  x[i]=x[j];\n                  x[j]=temp;\n             }\n         }\n\n         temp=x[pivot];\n         x[pivot]=x[j];\n         x[j]=temp;\n         quicksort(x,first,j-1);\n         quicksort(x,j+1,last);\n\n    }\n}\nint main()\n{\n    int n,tab[1000],i,j,x,s=0;\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&tab[i]);\n        }\n    \n    scanf(\"%d\",&x);\n    quicksort( tab, 0,n);\n    \n    i=0;\n    while (i<n)\n    {\n        \n    j=i+1;\n    while(tab[j]-tab[i]<=x)\n    {\n        \n    if (tab[j]-tab[i]==x)   s++;\n    j++;\n    }\n    i++;\n    }\n    printf(\"%d\",s);\n    return(0);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5b751df3e952900596ff0a84cc48be76", "src_uid": "086d07bd6f9031df09bd6a6e8fe8f25c", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n//#include<conio.h>\n\nint main()\n{\n\tint n,j,i,h[100],T,max=0,submax;\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%d\",&h[i]);\n\t}\n\tscanf(\"%d\",&T);\n\tfor(i=0;i<n;i++){\n\t\tsubmax=0;\n\t\tfor(j=0;j<n;j++){\n\t\t\tif((h[j]>=h[i])&&(h[j]<=h[i]+T))\n\t\t\t\tsubmax++;\n\t\t}\n\t\tif(submax>max)\n\t\t\tmax=submax;\n\t}\n\tprintf(\"%d\",max);\n\t//return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d9fd37d5e5300b81f2ced16870667382", "src_uid": "086d07bd6f9031df09bd6a6e8fe8f25c", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n//#include<conio.h>\n\nint main()\n{\n\tint n,j,i,h[100],T,g[100],max=0;\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%d\",&h[i]);\n\t}\n\tscanf(\"%d\",&T);\n\tfor(i=0;i<n;i++){\n\t\tfor(j=0;j<n;j++){\n\t\t\tif((h[j]>=h[i])&&(h[j]<=h[i]+T))\n\t\t\t\tg[i]++;\n\t\t}\n\t}\n\tfor(i=0;i<n;i++){\n\t\tif(g[i]>max)\n\t\t\tmax=g[i];\n\t}\n\tprintf(\"%d\",max);\n\t//return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f9d831987f6f9e192185e721eb598224", "src_uid": "086d07bd6f9031df09bd6a6e8fe8f25c", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n#include<stdlib.h>\r\n#include<math.h>\r\n\r\nint main()\r\n{\r\nint t;\r\nscanf(\"%d\",&t);\r\nwhile(t--)\r\n{\r\n\tint n,m,k;\r\n\tscanf(\"%d %d %d\",&n,&m,&k);\r\n\tif(n%2==0&&m%2==0)\r\n\t{\r\n\t\tif(k%2==0)\r\n\t\t printf(\"Yes\\n\");\r\n\t\telse\r\n     printf(\"No\\n\");\r\n  }\r\n  else if(m%2==0)\r\n  {\r\n  \tif((k-m/2)>=0&&(k-m/2)%2==0)\r\n  \t printf(\"Yes\\n\");\r\n\t\telse\r\n     printf(\"No\\n\");\r\n  }\r\n  else\r\n  {\r\n  \tif(k<=(n*m/2-n/2)&&k%2==0)\r\n  \t printf(\"Yes\\n\");\r\n\t\telse\r\n     printf(\"No\\n\");\r\n  }\r\n}\r\nreturn 0;\r\n}\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b9d00f73ecfcfaae4c1771c3bc15d0b7", "src_uid": "4d0c0cc8faca62eb6384f8135b30feb8", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\nint main()\r\n{int t;\r\n    scanf(\"%d\",&t);\r\n    while(t--)\r\n    {int n,m,k;\r\n        scanf(\"%d %d %d\",&n,&m,&k);\r\n        if(n%2 == 0 && m %2 == 0 && k&1)\r\n        printf(\"NO\\n\");\r\n    else if(n&1 && ((2*k < m) || (2*k-m)%4))\r\n      printf(\"NO\\n\");\r\n    else if(m&1 && (((n*m)-2*k < n) || (((n*m)-2*k)-n)%4))\r\n       printf(\"NO\\n\");\r\n    else\r\n        printf(\"YES\\n\");\r\n    }\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5e876eb36937ef730bc09e932d794a1a", "src_uid": "4d0c0cc8faca62eb6384f8135b30feb8", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "/*\r\n * @\u9898\u76ee: \r\n * @\u7b97\u6cd5: \r\n * @Author: Blore\r\n * @Language: c++11\r\n * @Date: 2021-08-06 09:23:07\r\n * @LastEditors: Blore\r\n * @LastEditTime: 2021-08-06 11:14:30\r\n */\r\n#include <stdio.h>\r\n\r\nint main()\r\n{\r\n    int t;\r\n    scanf(\"%d\", &t);\r\n    while (t--)\r\n    {\r\n        int n, m, k1;\r\n        scanf(\"%d%d%d\", &n, &m, &k1);\r\n        int k2 = n * m / 2 - k1;\r\n        if (m % 2 == 1)\r\n        {\r\n            k2 -= n / 2;\r\n            if (k2 < 0)\r\n            {\r\n                puts(\"NO\");\r\n                continue;\r\n            }\r\n        }\r\n        else if (n % 2 == 1)\r\n        {\r\n            k1 -= m / 2;\r\n            if (k1 < 0)\r\n            {\r\n                puts(\"NO\");\r\n                continue;\r\n            }\r\n        }\r\n        if (k1 * k2 % 2 != 0)\r\n            puts(\"NO\");\r\n        else\r\n            puts(\"YES\");\r\n    }\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "144234c87763f652e49d22a0d2bfb733", "src_uid": "4d0c0cc8faca62eb6384f8135b30feb8", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\nint main()\r\n{\r\n\tint n,m,t,k;\r\n\tscanf(\"%d\",&t);\r\n\twhile(t--){\r\n\t\tscanf(\"%d %d %d\",&n,&m,&k);\r\n\t\tint sum=n*m/2;\r\n\t\tif(n%2==1){\r\n\t\t\tsum-=m/2;\r\n\t\t\tk-=m/2;\r\n\t\t}\r\n\t\tif(m%2==1){\r\n\t\t\tsum-=n/2;\r\n\t\t}\r\n\t\tif(k<0||k%2==1||k>sum){\r\n\t\t\tprintf(\"NO\\n\");\r\n\t\t}else printf(\"YES\\n\");\r\n\t}\r\n\treturn 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "781830ccb6e1f53e2bc5d19589ef2075", "src_uid": "4d0c0cc8faca62eb6384f8135b30feb8", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\nint check_domino_row_even(int row, int col, int k) {\r\n\tint a[100][100] = { 0 };\r\n\t//xep domina ngang tu tren xuong duoi\r\n\tint cur_row = 0;\r\n\tint cur_col = 0;\r\n\twhile (1) {\r\n\t\tif (k > row) {\r\n\t\t\t/*for (int i = cur_row; i < row; i++) {\r\n\t\t\t\tfor (int j = cur_col; j <= cur_col + 1; j++) {\r\n\t\t\t\t\ta[i][j] = 1;\r\n\t\t\t\t}\r\n\t\t\t}*/\r\n\t\t\tcur_col += 2;\r\n\t\t\tk = k - row;\r\n\t\t}\r\n\t\telse {\r\n\t\t\t/*for (int i = cur_row; i < k; i++) {\r\n\t\t\t\tfor (int j = cur_col; j <= cur_col + 1; j++) {\r\n\t\t\t\t\ta[i][j] = 1;\r\n\t\t\t\t}\r\n\t\t\t}*/\r\n\t\t\tcur_row = k;\r\n\t\t\tbreak;\r\n\t\t}\r\n\t}\r\n\t//xep domino doc tu tren xuong\r\n\tif ((row - cur_row) % 2 == 1) {\r\n\t\treturn 0;\r\n\t}\r\n\telse if (cur_row == (row - 1)) {\r\n\t\treturn 0;\r\n\t}\r\n\telse if (cur_row == row) {\r\n\t\treturn 1;\r\n\t}\r\n\telse {\r\n\t\treturn 1;\r\n\t}\r\n}\r\nint check_domino_row_odd(int row, int col, int k) {\r\n\tint a[100][100] = { 0 };\r\n\t//xep domino ngang theo chieu ngang\r\n\tint cur_col = 0, cur_row = 0;\r\n\twhile (1) {\r\n\t\tif (k > col/2) {\r\n\t\t\t/*for (int i = cur_col; i < col; i++) {\r\n\t\t\t\ta[cur_row][i] = 1;\r\n\t\t\t}*/\r\n\t\t\tk = k - (col / 2);\r\n\t\t\tcur_row++;\r\n\t\t}\r\n\t\telse {\r\n\t\t\t/*for (int i = cur_col; i < 2 * k; i++) {\r\n\t\t\t\ta[cur_row][i] = 1;\r\n\t\t\t}*/\r\n\t\t\tcur_col = 2 * k;\r\n\t\t\tbreak;\r\n\t\t}\r\n\t} \r\n\tif (cur_col == col) {\r\n\t\tcur_row++;\r\n\t\tif ((row - cur_row) % 2 == 0) return 1;\r\n\t\telse return 0;\r\n\t}\r\n\telse return 0;\r\n}\r\nint check_domino(int row, int col, int k) {\r\n\tif (row % 2 == 1) return check_domino_row_odd(row, col, k);\r\n\telse return check_domino_row_even(row, col, k);\r\n}\r\nint main() {\r\n\tint row, col, k;\r\n\tint result[100] = { 0 };\r\n\tint n = 0;\r\n\tscanf_s(\"%d\", &n);\r\n\tfor (int i = 0; i < n; i++) {\r\n\t\tscanf_s(\"%d%d%d\", &row, &col, &k);\r\n\t\tresult[i] = check_domino(row, col, k);\r\n\t}\r\n\tfor (int i = 0; i < n; i++) {\r\n\t\tif (result[i] == 1) printf(\"\\nYES\");\r\n\t\telse printf(\"\\nNO\");\r\n\t}\r\n\treturn 0;\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6f39e7307ccbb7e54418e550c810e36f", "src_uid": "4d0c0cc8faca62eb6384f8135b30feb8", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nlong long power(int m, int pow){\n    if (pow == 1)\n        return m;\n    else{\n        long long val = power(m, pow/2);\n        val = (val * val) %1000000007;\n\n        if (pow%2)\n            val = (val * (long long)m) % 1000000007;\n        return val;\n    }\n\n}\n\n\nint main()\n{\n    int n, m, k;\n    scanf(\"%d %d %d\", &n, &m, &k);\n\n    if (k == 1)\n        printf(\"%d\\n\", power(n,m));\n    else{\n\n        if (n>k){\n\n             if (k%2)\n                printf(\"%d\\n\", (m*m)%1000000007);\n            else\n                printf(\"%d\\n\", m);\n        }\n\n        else{\n            int pow = k/2 + k%2;\n\n            printf(\"%I64d\\n\", power(m,pow));\n        }\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d532b9e4ab4784fae5b29631a0e33673", "src_uid": "1f9107e8d1d8aebb1f4a1707a6cdeb6d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\ntypedef long long ll;\n\nconst int mod = 1000000007;\n\nvoid solve(int n, int m, int k)\n{\n    ll ans;\n    int i;\n    if (k == 1)\n    {\n        ans = 1;\n        for (i = 0; i < n; i ++)\n        {\n            ans *= m;\n            if (ans >= mod)\n            {\n                ans %= mod;\n            }\n        }\n    }\n    else if (k & 1)\n    {\n        ans = m * m;\n    }\n    else\n    {\n        ans = m;\n    }\n    ans %= mod;\n    printf(\"%I64d\\n\", ans);\n}\n\nint main()\n{\n    int n, m, k;\n    while (scanf(\"%d%d%d\", &n, &m, &k) == 3)\n    {\n        solve(n, m, k);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ee3022d3ca166b75f9405363aef71ad9", "src_uid": "1f9107e8d1d8aebb1f4a1707a6cdeb6d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint sq(int x, int y) {\n  int i, a;\n\n  a = 1;\n  for (i = 0; i < y; i++) {\n    a = a * x;\n    while (a >= 1000000007) a -= 1000000007;\n  }\n\n  return a;\n}\n\nint main() {\n  int n, m, k;\n\n  scanf(\"%d%d%d\", &n, &m, &k);\n  \n  if (k == 1 || k > n) printf(\"%d\", sq(m, n));\n  else if (k == n) printf(\"%d\", sq(m, (n+1)/2));\n  else if (k%2 == 1) printf(\"%d\", sq(m, 2));\n  else printf(\"%d\", m);\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2e5fd369bf2d5211c9eab2c60a325cc9", "src_uid": "1f9107e8d1d8aebb1f4a1707a6cdeb6d", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,m,k;\n\tint i;\n\t__int64 sum;\n\tscanf(\"%d%d%d\",&n,&m,&k);\n\tif(k==1)\n\t{\n\t\tsum=1;\n\t\tfor(i=1;i<=n;i++)\n\t\tsum=((sum%1000000007)*(m%1000000007))%1000000007;\n\t\tprintf(\"%I64d\\n\",sum);\n\t}\n\telse if(k==n)\n\t{\n\t\tsum=1;\n\t\tfor(i=0;i<(n+1)/2;i++)\n\t\tsum=((sum%1000000007)*(m%1000000007))%1000000007;\n\t\tprintf(\"%I64d\\n\",sum);\n\t}\n\telse if(k>n)\n\tprintf(\"0\\n\");\n\telse\n\t{\n\t\tprintf(\"%d\\n\",m);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8941dd9052dbbd997dd31513b398b1ef", "src_uid": "1f9107e8d1d8aebb1f4a1707a6cdeb6d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define BASE 1000000007\n\nint pow(int a, int b) {\n\tif (b == 0) return 1;\n\tif (b == 1) return a;\n\n\tlong ans = pow(a, b/2);\n\tans = (ans * ans) % BASE;\n\tans = (ans * pow(a, b%2)) % BASE;\n\treturn (int) ans;\n}\n\nint main(void) {\n\tint n, m, k;\n\tscanf(\"%d %d %d\", &n, &m, &k);\n\t\n\tif (k > n) printf(\"%d\\n\", pow(m, n));\n\telse if (k == n) printf(\"%d\\n\", pow(m, (n + 1)/2));\n\telse if (k % 2) printf(\"%d\\n\", m*m);\n\telse printf(\"%d\\n\", m);\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9546fdf2f7f5f5a0a2d5b880864b0934", "src_uid": "1f9107e8d1d8aebb1f4a1707a6cdeb6d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"rgd\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/rgd\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/rgd\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t\t<Add option=\"-fexceptions\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.cpp\" />\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<envvars />\n\t\t\t<debugger />\n\t\t\t<lib_finder disable_auto=\"1\" />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "104124e142c08e20c2275ee977c74c86", "src_uid": "51d1c79a52d3d4f80c98052b6ec77222", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include <algorithm>\nusing namespace std;\nchar s1[20][150];\nchar s2[20][150];\nchar x[20];\nint main()\n{\n    int n;\n    while(scanf(\"%d\",&n)!=EOF)\n    {\n       scanf(\"%s\",x);\n        for(int i=0;i<n;i++)\n        {\n            scanf(\"%s\",s1[i]);\n        }\n         if(x[0]==s1[n-1][5]&&x[1]==s1[n-1][6]&&x[2]==s1[n-1][7])\n           printf(\"home\\n\");\n           else\n            printf(\"contest\\n\");\n    }\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d624d5015c2208caada033a8034a26b7", "src_uid": "51d1c79a52d3d4f80c98052b6ec77222", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n    scanf (\"%d\",n);\n    if (n%2==0) printf (\"home\");\n    else \n        printf (\"contest\");\n        return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5b7861c68c126dbf3adcc2e543c5c4c6", "src_uid": "51d1c79a52d3d4f80c98052b6ec77222", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <cstdio.h>\n\nint main() {\n    int n;\n    scanf(\"%d\", &n);\n    if (n % 2 == 0) {\n        puts(\"home\");\n    } else {\n        puts(\"contest\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5c2fc43d6b8305bc25ef6eb7e73fbcd6", "src_uid": "51d1c79a52d3d4f80c98052b6ec77222", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{ \t\n    int n,i,j; \t\n    char s[10]; \t\n    scanf(\"%d\",&n); \t\n    for(i=; i<=n+1; i++)\t scanf(\"%s\",s);\n    if(n%2==0)\tprintf(\"home\");\n    else printf(\"contest\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "42e929f3b9bbdd8e4ae8001469ef2b58", "src_uid": "51d1c79a52d3d4f80c98052b6ec77222", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint requires_substitute(char string[], int index1, int index2) {\n    if (index1 != 0 && index2 != 0) return 0;\n    if (index1 == 1 || index2 == 1) {\n        if (string[2] == '0') return 1;\n    } if (string[1] == '0') return 1;\n}\nint requires_substitute_fifty(char string[], int index1, int index2) {\n    if (index1 == 0 && index2 != 1 && string[1] == '0') return 1;\n    else return 0;\n}\nint substitute(char string[], int index1, int index2, int size) {\n    int res = -1;\n    for (int i = 0; i < size; i++) {\n        if (i != index1 && i != index2 && string[i] != '0') {\n            res = i;\n            break;\n        }\n    }\n    return res;\n}\n\nint main() {\n    char string[20];\n    scanf(\"%s\", string);\n    int nums[5];\n    for (int i = 0; i < 5; i++) {\n        nums[i] = -1;\n    }\n    int switchZero = 1;\n    int size = strlen(string);\n    for (int i = 0; i < size; i++) {\n        if (string[i] == '2') {\n            nums[0] = i;\n        } else if (string[i] == '5') {\n            nums[1] = i;\n        } else if (string[i] == '7') {\n            nums[2] = i;\n        } else if (string [i] == '0') {\n            if (switchZero) {\n                nums[3] = i;\n                switchZero = 0;\n            } else {\n                nums[4] = i;\n                switchZero = 1;\n            }\n        }\n    }\n\n    if (nums[3] > nums[4] || nums[4] == -1) {\n        int tmp = nums[3];\n        nums[3] = nums[4];\n        nums[4] = tmp;\n    }\n    int steps[4];\n    for (int i = 0; i < 4; i++) \n        steps[i] = -1;\n    if (nums[1] != -1) {\n        if (nums[0] != -1) {\n            int step_count = 0;\n            if (size > 2 && requires_substitute(string, nums[1], nums[0])) {\n                int sub = substitute(string, nums[1], nums[0], size);\n                if (sub != -1) {\n                    step_count += sub;\n                    if (sub > nums[0])\n                        step_count --;\n                    if (sub > nums[1]) \n                        step_count --;\n                }\n            }\n            if (nums[1] < nums[0]) {\n                step_count ++;\n            }\n            step_count += size - nums[1] - 1;\n            step_count += size - nums[0] - 2;\n            steps[0] = step_count;\n        } if (nums[2] != -1) {\n            int step_count = 0;\n            if (size > 2 && requires_substitute(string, nums[1], nums[2])) {\n                int sub = substitute(string, nums[1], nums[2], size);\n                if (sub != -1) {\n                    step_count += sub;\n                    if (sub > nums[2])\n                        step_count --;\n                    if (sub > nums[1]) \n                        step_count --;\n                }\n            }\n            if (nums[1] < nums[2]) {\n                step_count ++;\n            }\n            step_count += size - nums[1] - 1;\n            step_count += size - nums[2] - 2;\n            steps[1] = step_count;\n        } if (nums[4] != -1) {\n            int step_count = 0;\n            if (size > 2 && requires_substitute_fifty(string, nums[1], nums[4])) {\n                int sub = substitute(string, nums[1], nums[4], size);\n                if (sub != -1) {\n                    step_count += sub;\n                }\n            }\n            if (nums[1] > nums[4]) {\n                step_count ++;\n            }\n            step_count += size - nums[1] - 1;\n            step_count += size - nums[4] - 2;\n            steps[2] = step_count;\n        }\n    } if (nums[3] != -1 && nums[4] != -1) {\n        int step_count = 0;\n        step_count += size - nums[3] - 1;\n        step_count += size - nums[4] - 2;\n        steps[3] = step_count;\n    }\n    int min = -1;\n    for (int i = 0; i < 4; i ++) {\n        \n        if (steps[i] != -1) {\n            if (min == -1 || steps[i] < min) {\n                min = steps[i];\n            }\n        }\n    }\n    printf(\"%d\", min);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "37576a0d6023268569275c14f1b35f9a", "src_uid": "ea1c737956f88be94107f2565ca8bbfd", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define INF 100000001\n\ntypedef long long int int64;\n\ntypedef struct Number\n{\n\tint size;\n\tint *digits;\n} Number;\n\nint CountDigits(int64 num)\n{\n\tint digits = 0;\n\tdo {\n\t\tdigits += 1;\n\t\tnum /= 10;\n\t} while (num != 0);\n\treturn digits;\n}\n\nint* MakeVector(int size, int init_val)\n{\n\tint *vec = (int*)malloc(sizeof(int) * size);\n\tint i;\n\n\tfor (i = 0; i < size; ++i) {\n\t\tvec[i] = init_val;\n\t}\n\treturn vec;\n}\n\nNumber MakeNumber(int64 num)\n{\n\tNumber res;\n\tres.size = CountDigits(num);\n\tres.digits = MakeVector(res.size, 0);\n\n\tint i = 0;\n\tdo {\n\t\tres.digits[i] = num % 10;\n\t\ti += 1;\n\t\tnum /= 10;\n\t} while (num != 0);\n\n\treturn res;\n}\n\nNumber Clone(Number num)\n{\n\tNumber clone;\n\tclone.size = num.size;\n\tclone.digits = MakeVector(clone.size, 0);\n\n\tint i;\n\tfor (i = 0; i < clone.size; ++i) {\n\t\tclone.digits[i] = num.digits[i];\n\t}\n\treturn clone;\n}\n\nint min(int a, int b) { return a < b ? a : b; }\n\nint FindFirst(int vec[], int left, int right, int val)\n{\n\twhile (left < right) {\n\t\tif (vec[left] == val) {\n\t\t\treturn left;\n\t\t}\n\t\tleft += 1;\n\t}\n\treturn -1;\n}\n\nint SecondNonZero(Number num)\n{\n\tint pos = -1;\n\tint i;\n\n\tfor (i = 0; i + 1 < num.size; ++i) {\n\t\tif (num.digits[i] != 0) {\n\t\t\tpos = i;\n\t\t}\n\t}\n\treturn pos;\n}\n\nint HasSuffix(Number num, Number suffix)\n{\n\tif (num.size < suffix.size) {\n\t\treturn 0;\n\t}\n\n\tint i;\n\tfor (i = 0; i < suffix.size; ++i) {\n\t\tif (num.digits[i] != suffix.digits[i]) {\n\t\t\treturn 0;\n\t\t}\n\t}\n\treturn 1;\n}\n\nvoid Swap(int *a, int *b)\n{\n\tint aux = *a;\n\t*a = *b;\n\t*b = aux;\n}\n\nint Malformed(Number num)\n{\n\treturn num.digits[num.size - 1] == 0;\n}\n\nint CountSwapsToSuffix(Number num, Number suffix)\n{\n\tNumber cnum = Clone(num);\n\tint count = 0;\n\tint i;\n\n\tfor (i = 0; i < suffix.size; ++i) {\n\t\tint pos = FindFirst(cnum.digits, i, cnum.size, suffix.digits[i]);\n\t\tif (pos == -1) {\n\t\t\tbreak;\n\t\t}\n\n\t\twhile (cnum.digits[i] != suffix.digits[i]) {\n\t\t\tSwap(cnum.digits + pos, cnum.digits + pos - 1);\n\t\t\tif (Malformed(cnum)) {\n\t\t\t\tSwap(cnum.digits + pos, cnum.digits + pos - 1);\n\n\t\t\t\tint other = SecondNonZero(cnum);\n\t\t\t\tif (other == -1) {\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tSwap(cnum.digits + other, cnum.digits + other + 1);\n\n\t\t\t} else {\n\t\t\t\tpos -= 1;\n\t\t\t}\n\t\t\tcount += 1;\n\t\t}\n\n\t\tif (cnum.digits[i] != suffix.digits[i]) {\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tint good = HasSuffix(cnum, suffix);\n\tfree(cnum.digits);\n\n\treturn good ? count : INF;\n}\n\nint CountSwaps(int64 num, const Number suffixes[], int suffix_count)\n{\n\tNumber number = MakeNumber(num);\n\tint count = INF;\n\n\tint i;\n\tfor (i = 0; i < suffix_count; ++i) {\n\t\tint swaps = CountSwapsToSuffix(number, suffixes[i]);\n\t\tcount = min(count, swaps);\n\t}\n\tfree(number.digits);\n\n\treturn count;\n}\n\nint main()\n{\n\tint64 num;\n\tscanf(\"%I64d\", &num);\n\n\tNumber zero_suffix;\n\tzero_suffix.size = 2;\n\tzero_suffix.digits = MakeVector(2, 0);\n\n\tconst Number kSuffixes[] = {\n\t\tMakeNumber(25), MakeNumber(50), MakeNumber(75), zero_suffix,\n\t};\n\tint suffix_count = sizeof(kSuffixes) / sizeof(kSuffixes[0]);\n\n\tint res = CountSwaps(num, kSuffixes, suffix_count);\n\tprintf(\"%d\\n\", (res < INF ? res : -1));\n\n\tint i;\n\tfor (i = 0; i < suffix_count; ++i) {\n\t\tfree(kSuffixes[i].digits);\n\t}\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a902846ee14e99f5ea40720cff0c44bc", "src_uid": "ea1c737956f88be94107f2565ca8bbfd", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main()\n{\n\tchar dig[20], exp[20];\n\tscanf(\" %s\", dig);\n\tint tam=strlen(dig), i, j;\n\n\tif(tam==1)\n\t{\n\t\tprintf(\"-1\");\n\t\treturn 0;\n\t}\n\n\tif(tam==2)\n\t{\n\t\tif(dig[0]=='2' && dig[1]=='5') printf(\"0\");\n\t\telse if(dig[0]=='5' && dig[1]=='2') printf(\"1\");\n\t\telse if(dig[0]=='5' && dig[1]=='0') printf(\"0\");\n\t\telse if(dig[0]=='7' && dig[1]=='5') printf(\"0\");\n\t\telse if(dig[0]=='5' && dig[1]=='7') printf(\"1\");\n\t\telse printf(\"-1\");\n\t\treturn 0;\n\t}\n\n\tint freq[10]={0, 0, 0, 0, 0, 0, 0, 0, 0, 0};\n\tfor(i=0;i<tam;i++) freq[dig[i]-'0']++;\n\n\tint min=2*tam, act=min;\n\n\t//CASO 00\n\tif((freq[0]>=2) && (freq[1] || freq[2] || freq[3] || freq[4] || freq[5] || freq[6] || freq[7] || freq[8] || freq[9]))\n\t{\n\t\tstrcpy(exp, dig);\n\t\tact=0;\n\n\t\ti=tam-1;\n\t\twhile(exp[i]!='0') i--;\n\n\t\tfor(j=i+1;j<tam;j++)\n\t\t{\n\t\t\texp[j-1]^=exp[j];\n\t\t\texp[j]^=exp[j-1];\n\t\t\texp[j-1]^=exp[j];\n\t\t\tact++;\n\t\t}\n\n\t\ti=tam-2;\n\t\twhile(exp[i]!='0') i--;\n\n\t\tfor(j=i+1;j<tam-1;j++)\n\t\t{\n\t\t\texp[j-1]^=exp[j];\n\t\t\texp[j]^=exp[j-1];\n\t\t\texp[j-1]^=exp[j];\n\t\t\tact++;\n\t\t}\n\n\t\ti=0;\n\t\twhile(exp[i]=='0') i++;\n\t\tact+=i;\n\n\t\tif(act<min) min=act;\n\t}\n\n\t//CASO 25\n\tif((freq[2] && freq[5]) && (freq[1] || freq[2]>=2 || freq[3] || freq[4] || freq[5]>=2 || freq[6] || freq[7] || freq[8] || freq[9]))\n\t{\n\t\tstrcpy(exp, dig);\n\t\tact=0;\n\n\t\ti=tam-1;\n\t\twhile(exp[i]!='5') i--;\n\n\t\tfor(j=i+1;j<tam;j++)\n\t\t{\n\t\t\texp[j-1]^=exp[j];\n\t\t\texp[j]^=exp[j-1];\n\t\t\texp[j-1]^=exp[j];\n\t\t\tact++;\n\t\t}\n\n\t\ti=tam-2;\n\t\twhile(exp[i]!='2') i--;\n\n\t\tfor(j=i+1;j<tam-1;j++)\n\t\t{\n\t\t\texp[j-1]^=exp[j];\n\t\t\texp[j]^=exp[j-1];\n\t\t\texp[j-1]^=exp[j];\n\t\t\tact++;\n\t\t}\n\n\t\ti=0;\n\t\twhile(exp[i]=='0') i++;\n\t\tact+=i;\n\n\t\tif(act<min) min=act;\n\t}\n\n\t//CASO 50\n\tif((freq[5] && freq[0]) && (freq[1] || freq[2] || freq[3] || freq[4] || freq[5]>=2 || freq[6] || freq[7] || freq[8] || freq[9]))\n\t{\n\t\tstrcpy(exp, dig);\n\t\tact=0;\n\n\t\ti=tam-1;\n\t\twhile(exp[i]!='0') i--;\n\n\t\tfor(j=i+1;j<tam;j++)\n\t\t{\n\t\t\texp[j-1]^=exp[j];\n\t\t\texp[j]^=exp[j-1];\n\t\t\texp[j-1]^=exp[j];\n\t\t\tact++;\n\t\t}\n\n\t\ti=tam-2;\n\t\twhile(exp[i]!='5') i--;\n\n\t\tfor(j=i+1;j<tam-1;j++)\n\t\t{\n\t\t\texp[j-1]^=exp[j];\n\t\t\texp[j]^=exp[j-1];\n\t\t\texp[j-1]^=exp[j];\n\t\t\tact++;\n\t\t}\n\n\t\ti=0;\n\t\twhile(exp[i]=='0') i++;\n\t\tact+=i;\n\n\t\tif(act<min) min=act;\n\t}\n\n\t//CASO 75\n\tif((freq[7] && freq[5]) && (freq[1] || freq[2] || freq[3] || freq[4] || freq[5]>=2 || freq[6] || freq[7]>=2 || freq[8] || freq[9]))\n\t{\n\t\tstrcpy(exp, dig);\n\t\tact=0;\n\n\t\ti=tam-1;\n\t\twhile(exp[i]!='5') i--;\n\n\t\tfor(j=i+1;j<tam;j++)\n\t\t{\n\t\t\texp[j-1]^=exp[j];\n\t\t\texp[j]^=exp[j-1];\n\t\t\texp[j-1]^=exp[j];\n\t\t\tact++;\n\t\t}\n\n\t\ti=tam-2;\n\t\twhile(exp[i]!='7') i--;\n\n\t\tfor(j=i+1;j<tam-1;j++)\n\t\t{\n\t\t\texp[j-1]^=exp[j];\n\t\t\texp[j]^=exp[j-1];\n\t\t\texp[j-1]^=exp[j];\n\t\t\tact++;\n\t\t}\n\n\t\ti=0;\n\t\twhile(exp[i]=='0') i++;\n\t\tact+=i;\n\n\t\tif(act<min) min=act;\n\t}\n\n\tif(act!=2*tam) printf(\"%d\",min);\n\telse printf(\"-1\");\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "dc117dc16923072010798607e97eab03", "src_uid": "ea1c737956f88be94107f2565ca8bbfd", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint requires_substitute(char string[], int index1, int index2) {\n    if (index1 != 0 && index2 != 0) return 0;\n    if (index1 == 1 || index2 == 1) {\n        if (string[2] == '0') return 1;\n    } if (string[1] == '0') return 1;\n}\nint requires_substitute_fifty(char string[], int index1, int index2) {\n    if (index1 == 0 && index2 != 1 && string[1] == '0') return 1;\n    else return 0;\n}\nint substitute(char string[], int index1, int index2, int size) {\n    int res = -1;\n    for (int i = 0; i < size; i++) {\n        if (i != index1 && i != index2 && string[i] != '0') {\n            res = i;\n            break;\n        }\n    }\n    return res;\n}\n\nint main() {\n    char string[20];\n    scanf(\"%s\", string);\n    int nums[5];\n    for (int i = 0; i < 5; i++) {\n        nums[i] = -1;\n    }\n    int switchZero = 1;\n    int size = strlen(string);\n    for (int i = 0; i < size; i++) {\n        if (string[i] == '2') {\n            nums[0] = i;\n        } else if (string[i] == '5') {\n            nums[1] = i;\n        } else if (string[i] == '7') {\n            nums[2] = i;\n        } else if (string [i] = '0') {\n            if (switchZero) {\n                nums[3] = i;\n                switchZero = 0;\n            } else {\n                nums[4] = i;\n                switchZero = 1;\n            }\n        }\n    }\n\n    if (nums[3] > nums[4]) {\n        int tmp = nums[3];\n        nums[3] = nums[4];\n        nums[4] = tmp;\n    }\n    int steps[4];\n    for (int i = 0; i < 4; i++) \n        steps[i] = -1;\n    if (nums[1] != -1) {\n        if (nums[0] != -1) {\n            int step_count = 0;\n            if (size > 2 && requires_substitute(string, nums[1], nums[0])) {\n                int sub = substitute(strimg, nums[1], nums[0], size);\n                if (sub != -1) {\n                    step_count += sub;\n                }\n            }\n            if (nums[1] < nums[0]) {\n                step_count ++;\n            }\n            step_count += size - nums[1] - 1;\n            step_count += size - nums[0] - 2;\n            steps[0] = step_count;\n        } if (nums[2] != -1) {\n            int step_count = 0;\n            if (size > 2 && requires_substitute(string, nums[1], nums[2])) {\n                int sub = substitute(strimg, nums[1], nums[2], size);\n                if (sub != -1) {\n                    step_count += sub;\n                }\n            }\n            if (nums[1] < nums[2]) {\n                step_count ++;\n            }\n            step_count += size - nums[1] - 1;\n            step_count += size - nums[2] - 2;\n            steps[1] = step_count;\n        } if (nums[4] != -1) {\n            int step_count = 0;\n            if (size > 2 && requires_substitute_fifty(string, nums[1], nums[4])) {\n                int sub = substitute(strimg, nums[1], nums[4], size);\n                if (sub != -1) {\n                    step_count += sub;\n                }\n            }\n            if (nums[1] < nums[4]) {\n                step_count ++;\n            }\n            step_count += size - nums[1] - 1;\n            step_count += size - nums[4] - 2;\n            steps[2] = step_count;\n        }\n    } if (nums[3] != -1 && nums[4] != -1) {\n        int step_count = 0;\n        step_count += size - nums[1] - 1;\n        step_count += size - nums[4] - 2;\n        steps[3] = step_count;\n    }\n    int min = -1;\n    for (int i = 0; i < 4; i ++) {\n        if (steps[i] != -1) {\n            if (min == -1 || steps[i] < min) {\n                min = steps[i];\n            }\n        }\n    }\n    printf(\"%d\", min);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3f94b1f83002e37e711086fc0d3f8a03", "src_uid": "ea1c737956f88be94107f2565ca8bbfd", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint first(char s[],int len){\n    int i,five=-1,two=-1;\n    for(i=0;i<len;i++){\n        if(s[i]=='5')\n            five=i;\n        if(s[i]=='2')\n            two=i;\n    }\n    if(five==-1||two==-1)\n        return -1;\n    else if(two<five)\n        return len-five+len-two-3;\n    else\n        return len-five+len-two-2;\n}\nint sec(char s[],int len){\n    int i,five=-1,zero=-1;\n    for(i=0;i<len;i++){\n        if(s[i]=='5')\n            five=i;\n        if(s[i]=='0')\n            zero=i;\n    }\n    if(five==-1||zero==-1)\n        return -1;\n    else if(zero<five)\n        return len-five+len-zero-2;\n    else\n        return len-five+len-zero-3;\n}\nint thrd(char s[],int len){\n    int i,five=-1,seven=-1;\n    for(i=0;i<len;i++){\n        if(s[i]=='5')\n            five=i;\n        if(s[i]=='7')\n            seven=i;\n    }\n    if(five==-1||seven==-1)\n        return -1;\n    else if(seven<five)\n        return len-five+len-seven-3;\n    else\n        return len-five+len-seven-2;\n}\nint four(char s[],int len){\n    int i,zero1=-1,zero2=-1;\n    for(i=0;i<len;i++){\n        if(s[i]=='5'){\n                zero2=zero1;\n            zero1=i;\n        }\n    }\n    if(zero1==-1||zero2==-1)\n        return -1;\n    else\n        return len-zero1+len-zero2-2;\n}\nint main()\n{\n    int ara[5];\n    int len,i,j,temp;\n    char s[100];\n    scanf(\"%s\",s);\n    len=strlen(s);\n    ara[0]=first(s,len);\n    ara[1]=sce(s,len);\n    ara[2]=thrd(s,len);\n    ara[3]=four(s,len);\n    for(i=0;i<4-1;i++){\n        for(j=i+1;j<4;j++){\n            if(ara[j]>ara[i]){\n                temp=ara[i];\n                ara[i]=ara[j];\n                ara[j]=temp;\n            }\n        }\n    }\n    for(i=0;i<4;i++){\n        if(ara[0]!=-1){\n            printf(\"%d\\n\",ara[i]);\n            break;\n        }\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3d0cf7687b65135868ec587a22e12279", "src_uid": "ea1c737956f88be94107f2565ca8bbfd", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nint max(int *a, int n)\n{\n\tint max = *a;\n\tint i;\n\tfor (i = 1; i < n; i++)\n\t\tif (max < *(a + i))\n\t\t\tmax = *(a + i);\n\treturn max;\n}\nint main()\n{\n\tchar str[105];\n\tchar s2[105][105] = { 0 };\n\tchar s1[105] = { 0 };\n\tint a[105] = { 0 };\n\tint len, i,j,k,l,n=0,m;\n\tscanf(\"%s\", str);\n\tlen = strlen(str);\n\tfor (i = 1; i < len; i++)\n\t{\n\t\tmemset(s2, 0, sizeof(s2));\n\t\tmemcpy(s2[0], str, len-i);\n\t\tmemset(a, 0, sizeof(a));\n\t\tn = 0;\n\t\ta[0] += 1;\n\t\tn++;\n\t\tfor (j = 1; j <= i; j++)\n\t\t{\n\t\t\tmemset(s1, 0, sizeof(s1));\n\t\t\tfor (k = 0; k < len - i; k++)\n\t\t\t\ts1[k] = str[k + j];\n\t\t\tfor (m = 0; m < n; m++)\n\t\t\t{\n\t\t\t\tif (strcmp(s1, s2[m]) == 0)\n\t\t\t\t{\n\t\t\t\t\ta[m]++;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (m >= n)\n\t\t\t{\n\t\t\t\ta[n]++;\n\t\t\t\tstrcpy(s2[n], s1);\n\t\t\t}\t\n\t\t}\n\t\tif (max(a, n) >= 2)\n\t\t{\n\t\t\tprintf(\"%d\\n\", max(a, n));\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\"0\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9ce6823733c99dabd03d9acfffaf9280", "src_uid": "13b5cf94f2fabd053375a5ccf3fd44c7", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(){\n\tint sum,i,j,k,l,n,m,a[1000];\n\tchar c[100000];\n\tscanf(\"%s\",c);\n\tint z = strlen(c);\n\ta[0] = c[i]-'a'+1;\n\tint ans=0,tmp;\n\tfor(i=0;i<z;i++){\n\t\tfor(j=i+1;j<z;j++){\n\t\ttmp = i;\n\t\tsum = 0;\n\t\t\twhile(c[tmp]==c[j]){\n\t\t\t\tsum++;\n\t\t\t\ttmp++;\n\t\t\t\tj++;\n\t\t\t}\n\t\tif(sum>ans)\n\t\t\tans = sum;\n\t\t}\n\t}\n\tprintf(\"%d\\n\",ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f5289be0e0e23d7ecaa4d9830fd0cf38", "src_uid": "13b5cf94f2fabd053375a5ccf3fd44c7", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint subs(char* str, int n)\n{\n\tint x=0,flag=0;\n\tfor(int i=n-1;i>0;i--)\n\t{\n\t\tfor(int j=0;j<n-i;j++)\n\t\t{\n\t\t\tfor(int k=j+1;k<=n-i;k++)\n\t\t\t{\n\t\t\t\tfor(int k1=0;k1<i;k1++)\n\t\t\t\t{\n\t\t\t\t\tif(str[j+k1]!=str[k+k1])\n\t\t\t\t\t{\n\t\t\t\t\t\tflag=1;\n\t\t\t\t\t\tprintf(\"aa\\n\");\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(flag==0)\n\t\t\t\t{\n\t\t\t\t\tx=i;\n\t\t\t\t\treturn x;\n\t\t\t\t}\n\t\t\t\tflag=0;\n\t\t\t}\n\t\t}\n\t}\n\treturn x;\n}\n\nint main()\n{\n\tchar str[100]; int n;\n\tscanf(\"%s\",str);\n\tfor(int i=0;;i++)\n\t{\n\t\tif(str[i]=='\\0')\n\t\t{\n\t\t\tn=i;\n\t\t\tbreak;\n\t\t}\n\t}\n\tprintf(\"%d \",subs(str,n));\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6f34c49e2273d9ef2bd53718473641bf", "src_uid": "13b5cf94f2fabd053375a5ccf3fd44c7", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n\nint main()\n{\n    char str[101];\n    char buf[101];\n    gets(str);\n\n    int i = 0;\n    for(i = strlen(str) - 1; i > 0; --i)\n    {\n        memset(buf, 0, 101);\n        strncpy(buf, str, i);\n        if(strstr(str + 1, buf) != NULL) break;\n    }\n\n    printf(\"%d\", i);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "16fc0766c9271399b9eb3a4e022ed484", "src_uid": "13b5cf94f2fabd053375a5ccf3fd44c7", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint subs(char* str, int n)\n{\n\tint t1=0,t=1,t2=0,flag=0,p1=982451653;\n\tint x=0;\n\tfor(int i=n-1,k1;i>0;i--)\n\t{\n\t\tt1=0,t=1;\n//\t\tprintf(\"%d\\n\",i);\n\t\tfor(k1=0;k1<i;k1++)\n\t\t{\n\t\t\tt1 = (t1*10 + (int)(str[k1]-96))%p1;\n\t\t\tt*=10;\n\t\t}\n\t\tt/=10;\n//\t\tprintf(\"%d\\n\",t1);\t\n\t\tfor(int j=0,k2;j<n-i;j++)\n\t\t{\n\t\t\tif(j>0)\n\t\t\t{\n\t\t\t\tt1=((t1-(int)(str[j-1]-96)*t)*10+(int)(str[j+i-1]-96))%p1;\n//\t\t\t\tprintf(\"%d\\n\",t1);\t\n\t\t\t}\n\t\t\tfor(k2=j+1;k2<=n-i;k2++)\n\t\t\t{\n\t\t\t\tif(k2!=j+1)\n\t\t\t\t{\n\t\t\t\t\tt2=((t2-(int)(str[k2-1]-96)*t)*10+(int)(str[k2+i-1]-96))%p1;\n//\t\t\t\t\tprintf(\"%d\\n\",t2);\t\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tt2=((t1-(int)(str[j]-96)*t)*10+(int)(str[j+i]-96))%p1;\n//\t\t\t\t\tprintf(\"%d\\n\",t2);\t\n\t\t\t\t}\n\t\t\t\tif(t2==t1)\n\t\t\t\t{\n\t\t\t\t\tfor(int k=0;k<i;k++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif(str[j+k]!=str[k2+k])\n\t\t\t\t\t\t{\n//\t\t\t\t\t\t\tprintf(\"abbdbfd\\n\");\n\t\t\t\t\t\t\tflag=1;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif(flag==0)\n\t\t\t\t\t{\n\t\t\t\t\t\tx=i;\n\t\t\t//\t\t\tprintf(\"abbdbfd\\n\");\n\t\t\t\t\t\treturn x;\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t\tflag=0;\n\t\t\t\t}\n\t\t\t}\n\n\t\t}\n\t}\n\treturn x;\n}\n\nint main()\n{\n\tchar str[100];int n=0;\n\tscanf(\"%s\",str);\n\tfor(int i=0;;i++)\n\t{\n\t\tif(str[i]=='\\0')\n\t\t{\n\t\t\tn=i;\n\t\t\tbreak;\n\t\t}\n\t}\n//\tprintf(\"%d\\n\",n);\n\tprintf(\"%d\",subs(str,n));\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cb966ac384796af139b15ced5b9c48dd", "src_uid": "13b5cf94f2fabd053375a5ccf3fd44c7", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main() {\n\tlong long n, b;\n\tscanf(\"%lld%lld\", &n, &b);\n\tlong long ans = 1000000000000000000;\n\tfor( long long i=2, p, l, tn, cans; i*i <= b; ++i ) {\n\t\tif( b%i )\n\t\t\tcontinue;\n\t\tfor( l=0, p=1; b%i == 0 ; b /= i )\n\t\t\tl++;\n\t\tcans = 0;\n\t\tfor( tn=n/i; tn; tn /= i ) cans += tn;\n\t\tif( cans/l < ans )\n\t\t\tans = cans/l;\n\t}\n\tif( b != 1 ) {\n\t\tlong long i=b, l=1;\n\t\tfor( tn=n/i; tn; tn /= i ) cans += tn;\n\t\tif( cans/l < ans )\n\t\t\tans = cans/l;\t\t\n\t}\n\tprintf(\"%lld\\n\", ans);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3d0ee04c312dc30a9006cdd1ee31dc43", "src_uid": "491748694c1a53771be69c212a5e0e25", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n\n#define BMAX 1000005\n\ntypedef long long ll;\n\nll min(ll a, ll b) {\n\treturn a < b ? a : b;\n}\n\nint main() {\n\tll i;\n\tll n, b;\n\tscanf(\"%lld %lld\", &n, &b);\n\tll val = b;\n\tll max_zeros = 1000000000000000000LL;\n\tfor (i=2; i <= (ll)sqrt(val) && max_zeros > 0; i++) {\n\t\t//printf(\"val,i = %lld,%lld\\n\", val, i);\n\t\tll need = 0;\n\t\tll has = 0;\n\t\twhile (val % i == 0) {\n\t\t\tval /= i;\n\t\t\tneed++;\n\t\t}\n\t\tif (need > 0) {\n\t\t\tll div = n;\n\t\t\tll k = i;\n\t\t\twhile (div > k) {\n\t\t\t\thas += div / k;\n\t\t\t\tk *= i;\n\t\t\t}\n\t\t\tmax_zeros = min(max_zeros, has / need);\n\t\t\t//printf(\"new max %lld\\n\", max_zeros);\n\t\t}\n\t}\n\tif (val > 1) {\n\t\ti = val;\n\t\tll need = 0;\n\t\tll has = 0;\n\t\twhile (val % i == 0) {\n\t\t\tval /= i;\n\t\t\tneed++;\n\t\t}\n\t\tif (need > 0) {\n\t\t\tll div = n;\n\t\t\tll k = i;\n\t\t\twhile (div >= k) {\n\t\t\t\thas += div / k;\n\t\t\t\tk *= i;\n\t\t\t}\n\t\t\tmax_zeros = min(max_zeros, has / need);\n\t\t}\n\t}\n\tprintf(\"%lld\\n\", max_zeros);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3921c909fd05c6be9adaa740da3dfaa8", "src_uid": "491748694c1a53771be69c212a5e0e25", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n\n#define BMAX 1000005\n\ntypedef long long ll;\n\nll min(ll a, ll b) {\n\treturn a < b ? a : b;\n}\n\nint main() {\n\tll i;\n\tll n, b;\n\tscanf(\"%lld %lld\", &n, &b);\n\tll val = b;\n\tll max_zeros = BMAX;\n\tfor (i=2; i <= (int)sqrt(val) && max_zeros > 0; i++) {\n\t\t//printf(\"val,i = %lld,%lld\\n\", val, i);\n\t\tint need = 0;\n\t\tint has = 0;\n\t\twhile (val % i == 0) {\n\t\t\tval /= i;\n\t\t\tneed++;\n\t\t}\n\t\tif (need > 0) {\n\t\t\tll div = n;\n\t\t\tll k = i;\n\t\t\twhile (div > k) {\n\t\t\t\thas += div / k;\n\t\t\t\tk *= i;\n\t\t\t}\n\t\t\tmax_zeros = min(max_zeros, has / need);\n\t\t}\n\t}\n\tif (val > 1) {\n\t\ti = val;\n\t\tint need = 0;\n\t\tint has = 0;\n\t\twhile (val % i == 0) {\n\t\t\tval /= i;\n\t\t\tneed++;\n\t\t}\n\t\tif (need > 0) {\n\t\t\tll div = n;\n\t\t\tll k = i;\n\t\t\twhile (div >= k) {\n\t\t\t\thas += div / k;\n\t\t\t\tk *= i;\n\t\t\t}\n\t\t\tmax_zeros = min(max_zeros, has / need);\n\t\t}\n\t}\n\tprintf(\"%lld\\n\", max_zeros);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b2a6f877d9c4b7513a97f6d8e6c40690", "src_uid": "491748694c1a53771be69c212a5e0e25", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main() {\n\tlong long n, b;\n\tscanf(\"%lld%lld\", &n, &b);\n\tlong long ans = 1000000000000000000;\n\tfor( long long i=2, p, l, tn, cans; b>1; ++i ) {\n\t\tif( b%i )\n\t\t\tcontinue;\n\t\tfor( l=0, p=1; b%i == 0 ; b /= i )\n\t\t\tl++;\n\t\tcans = 0;\n\t\tfor( tn=n/i; tn; tn /= i ) cans += tn;\n\t\tif( cans/l < ans )\n\t\t\tans = cans/l;\n\t}\n\tprintf(\"%lld\\n\", ans);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "296441a4ec34b46812a476793fc58afe", "src_uid": "491748694c1a53771be69c212a5e0e25", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n\n#define BMAX 1000005\n\ntypedef long long ll;\n\nll min(ll a, ll b) {\n\treturn a < b ? a : b;\n}\n\nint main() {\n\tll i;\n\tll n, b;\n\tscanf(\"%lld %lld\", &n, &b);\n\tll val = b;\n\tll max_zeros = 1000000000000000000LL;\n\tfor (i=2; i <= /*(ll)sqrt(*/val/*)*/ && max_zeros > 0; i++) {\n\t\t//printf(\"val,i = %lld,%lld\\n\", val, i);\n\t\tll need = 0;\n\t\tll has = 0;\n\t\twhile (val % i == 0) {\n\t\t\tval /= i;\n\t\t\tneed++;\n\t\t}\n\t\tif (need > 0) {\n\t\t\tll k = i;\n\t\t\tll div = n;\n\t\t\twhile (div >= k && k > 0) {\n\t\t\t\t//printf(\"div   %lld\\n\", div);\n\t\t\t\thas += div / k;\n\t\t\t\tk *= i;\n\t\t\t}\n\t\t\tmax_zeros = min(max_zeros, has / need);\n\t\t\t//printf(\"new max %lld\\n\", max_zeros);\n\t\t}\n\t}\n\t/*if (val > 1) {\n\t\ti = val;\n\t\tll need = 0;\n\t\tll has = 0;\n\t\twhile (val % i == 0) {\n\t\t\tval /= i;\n\t\t\tneed++;\n\t\t}\n\t\tif (need > 0) {\n\t\t\tll div = n;\n\t\t\tll k = i;\n\t\t\twhile (div >= k) {\n\t\t\t\thas += div / k;\n\t\t\t\tk *= i;\n\t\t\t}\n\t\t\tmax_zeros = min(max_zeros, has / need);\n\t\t}\n\t}*/\n\tprintf(\"%lld\\n\", max_zeros);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7d30245f020816f5741399988dd47bc3", "src_uid": "491748694c1a53771be69c212a5e0e25", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long int pow2(long long int a,long long int b,long long int n)\n{\n  long long int x=1;\n  long long int y=a;\n  while(b>0){\n    if(b&1)\n      x=((x%n)*(y%n))%n;\n    y=((y%n)*(y%n))%n;\n    b=b>>1;\n  }\n  return x%n;\n}\nint main()\n{\n  long long int n,m,k,ans;\n  long long int mod=1e9+7;\n  scanf(\"%lld %lld %lld\",&n,&m,&k);\n  if(k==-1 && (n+m)%2!=0)\n  {\n    printf(\"0\\n\");\n  }\n  else\n  {\n    ans=pow2( pow2(2,n-1,mod),m-1, mod);\n    printf(\"%lld\\n\",ans);\n  }\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9e75f239f03637c372cd1ae20e33d062", "src_uid": "6b9eff690fae14725885cbc891ff7243", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n\n\n\nlong long int insaneMod(long long int a, long long int mods[19]){\n    long long int temp;\n    long long int result = 1ll;\n    int ct;\n    int counter = 0;\n    while(a > 0){\n        ct = a % 10;\n        temp = 1ll;\n        for(int ct2 = 1 ; ct2 <= ct ; ct2++){\n            temp = temp * mods[counter];\n            temp %= 1000000007;\n        }\n        result *= temp;\n        result %= 1000000007;\n        a = a / 10;\n        counter++;\n    }\n    return result;\n}\n\nlong long int modToPower(long long int a , long long int b){\n    long long int temp , result;\n    int remainders[19];\n    remainders[1] = a;\n    int ct;\n    for(ct = 2 ; ct <= 18 ; ct++){\n        long long int temp = remainders[ct - 1];\n        int ct2;\n        for(ct2 = 1; ct2 <= 9 ; ct2++){\n            temp *= remainders[ct - 1];\n            temp = temp % (1000000007);\n        }\n        remainders[ct] = temp;\n    }\n\n\n\n\n}\n\nint main(){\n\n    long long int mods[19];\n    mods[0]= 2;\n    mods[1] = 1024;\n    int ct;\n    for(ct = 2 ; ct <= 18 ; ct++){\n        long long int temp = mods[ct - 1];\n        int ct2;\n        for(ct2 = 1; ct2 <= 9 ; ct2++){\n            temp *= mods[ct - 1];\n            temp = temp % (1000000007);\n        }\n        mods[ct] = temp;\n    }\n\n    long long int n, m;\n    int k;\n    scanf(\"%lld%lld%d\", &n, &m, &k);\n    if(k == -1 && n % 2 != m % 2){\n        printf(\"0\");\n        return 0;\n    }else{\n        long long int result;\n        result = insaneMod(n-1 , mods);\n        long long int remainders[19];\n        remainders[0] = result;\n        int cts;\n        for(cts = 1 ; cts <= 18 ; cts++){\n            long long int temp = remainders[cts - 1];\n            int ct2;\n            for(ct2 = 1; ct2 <= 9 ; ct2++){\n                temp *= remainders[cts - 1];\n                temp = temp % (1000000007);\n            }\n            remainders[cts] = temp;\n        }\n\n\n        result = insaneMod(m - 1, remainders);\n        printf(\"%lld\", result);\n        return 0;\n    }\n}\n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a6aacc1221b97b1d1b1cd81620f90229", "src_uid": "6b9eff690fae14725885cbc891ff7243", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nlong long int  m=1000000007;\nlong long int power(long long int x,long long int y,long long int m)\n{\n    long long int temp;\n    if(y==0)\n        return 1;\n    temp=power(x,y/2,m);\n    if(y%2==0)\n        return ((temp%m)*(temp%m))%m;\n    else\n        return (x*(((temp%m)*(temp%m))%m)%m)%m;\n}\nint main()\n{\n\tlong long int n,p,k,ans,ans1;\n\tscanf(\"%lld %lld %lld\",&n,&p,&k);\n\tif(k==-1 && (n+p)%2==1)\n\tans=0;\n\telse\n\t{\n\tans=power(2,(n-1),m);\n\tans=power(ans,p-1,m);\n\t}\n//ans=(ans*ans1)%m;\n\tprintf(\"%lld\\n\",ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9d4325831aebd74d7009cf8749169d1b", "src_uid": "6b9eff690fae14725885cbc891ff7243", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n\nint main(){\n\n    long long int a[1000000007];\n    long long int n, m;\n    int k;\n    scanf(\"%lld%lld%d\", &n, &m, &k);\n    if(k == -1 && n % 2 != m % 2){\n        printf(\"0\");\n        return 0;\n    }else{\n    printf(\"Hi\");\n    }\n    printf(\"Hello\");\n\n\n}\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e9730625ad570e743a839c5bbca7deb5", "src_uid": "6b9eff690fae14725885cbc891ff7243", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <ctype.h>\n#define uLL unsigned long long\n#define uL unsigned long long\nchar str[1000000];\nconst uLL P=1000000007;\nuL exgcd(uL a,uL c)\n{\n\tstatic uL gcd;\n\tuL k;\n\tuLL x;\n\tif (a==0)\n\t{\n\t\tgcd=c;\n\t\treturn 1;\n\t}\n\telse\n\t{\n\t\tk=c%a;\n\t\tif (k==0)\n\t\t{\n\t\t\tgcd=a;\n\t\t\treturn 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tx=exgcd(a%k,k);\n\t\t}\n\t}\n\treturn (x*c-c/a*gcd)/k;\n}\ninline uLL mod64(uLL a,uLL b,uLL c)\n{\n\tuLL t,t2;\n\ta=a%c;b=b%c;\n\tfor (t=0;a>0;a=a>>1)\n\t{\n\t\tif (a&1)\n\t\t{\n\t\t\tt2=c-t;\n\t\t\tif (t2<b) {t=b-t2;} else {t=t+b;}\n\t\t}\n\t\tif (c-b>=b) {b=b<<1;} else {b=(b<<1)-c;}\n\t}\n\treturn t;\n}\n\ninline uLL expmod64(uLL a,uLL b,uLL p)\n{\n\tuLL t;\n\ta=a%p;b=b%p;\n\tfor (t=1;b;b=b>>1)\n\t{\n\t\tif (b&1)\n\t\t{\n\t\t\tt=mod64(t,a,p);\n\t\t}\n\t\ta=mod64(a,a,p);\n\t}\n\treturn t;\n}\nint main()\n{\n\tuLL n,m,k,t1,t2,ans;\n\tscanf(\"%llu %llu %llu\",&n,&m,&k);\n\tt1=expmod64(2,n,P);\n\tt2=exgcd(expmod64(2,m,P),P);\n\tans=expmod64(t1,m,P);\n\tt1=exgcd(t1,P);\n\tans=ans*2%P;\n\tans=ans*t1%P;\n\tans=ans*t2%P;\n\tprintf(\"%llu\\n\",ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7282136b2dd9d81886434ce1db3c53cd", "src_uid": "6b9eff690fae14725885cbc891ff7243", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n \nint bigger(int n1, int n2);\n \nint main(){\n\tint b, g, n;\n \n\tscanf(\"%d\", &b);\n\tscanf(\"%d\", &g);\n\tscanf(\"%d\", &n);\n \n\tif(b >= n && g >= n) printf(\"%d\", n + 1);\n\telse if(b >= n && g < n) printf(\"%d\", 1 + g);\n\telse if(b < n && g >= n) printf(\"%d\", 1 + b);\n\telse if(b + g > n) printf(\"%d\",  (g + b - bigger(a, b)) - (n - bigger(g, b)) + 1 );\n\telse printf(\"1\");\n \n\treturn 0;\n}\n \nint bigger(int n1, int n2){\n    return (-(n1 >= n2) & n1) + (-(n1 < n2) & n2);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dd5de654a855aa10ca84e24168e4d430", "src_uid": "9266a69e767df299569986151852e7b1", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n\n{\n    int a,b,g,n,s;\n    scanf(\"%d%d%d\", &b,&g,&n);\n    if(b>=g)\n    a=g;\n    else a=b;\n    s=b+g-n;\n    if(s==0)\n    printf(\"1\\n\");\n    else if(s>=a)\n    {\n        if(a+1>=n+1)\n        printf(\"%d\\n\", n+1);\n        else\n        printf(\"%d\\n\", a+1);\n    \n    }\n    else\n    printf(\"%d\\n\", s+1);\n    return 0\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e77150d95e81e0c77e1064dc217c7030", "src_uid": "9266a69e767df299569986151852e7b1", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main() {\n      int b,g,n,ans=0;\n\tscanf(\"%d%d%d\",&b,&g,&n);\n\tfor (int i=0;i<=b;i++) {\n\t      j=n-i;\n\t      \n\t      ans+=(j>=0 && j<=g);\n\t}\n\tprintf(\"%d\\n\",ans);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "197417969891e44b6a14403401fe51fd", "src_uid": "9266a69e767df299569986151852e7b1", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint bigger(int n1, int n2);\n\nint main(){\n\tint b, g, n;\n\n\tscanf(\"%d\", &b);\n\tscanf(\"%d\", &g);\n\tscanf(\"%d\", &n);\n\n\tif(b >= n && g >= n) printf(\"%d\", n + 1);\n\telse if(b >= n && g < n) printf(\"%d\", 1 + g);\n\telse if(b < n && g >= n) printf(\"%d\", 1 + b));\n\telse if(b + g >= n) printf(\"%d\", n - bigger(g, b))\n\telse printf(\"1\");\n\n\treturn 0;\n}\n\nint bigger(int n1, int n2){\n    return (-(n1 >= n2) & n1) + (-(n1 < n2) & n2);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c18769df4bf03b8a6b358e20ffd3fc2e", "src_uid": "9266a69e767df299569986151852e7b1", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "    #include<stdio.h>\n     \n    int main(){\n        long long int a,b,c;\n        scanf(\"%lld %lld %lld\",&a,&b,&c);\n        if(a==0 && b==0 && c==0){\n            printf(\"0\");\n            \n        \n        }\n        else{\n            long long int d=c-a;\n            long long int e=c-b;\n            if(a<b && a<c && a<e && a<d){\n                printf(\"%lld\",(a+1));\n            }\n            else if(a>b && c>b && b<e && b<d){\n                printf(\"%lld\",(b+1));\n                \n            }\n            else if(c<a && c<b && && c<e && c<d){\n                printf(\"%lld\",(c+1));\n                \n            }\n            else if(d<e){\n                printf(\"%lld\",d);\n                \n            }\n            else printf(\"%lld\",e);\n        }\n        return 0;\n    }", "lang_cluster": "C", "compilation_error": true, "code_uid": "fc3545f26279648ac00d56c224a1fc15", "src_uid": "9266a69e767df299569986151852e7b1", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include <cstdio>\n#include <iostream>\n#include <cmath>\n#include <algorithm>\nusing namespace std;\n#define mem(a, b) memset(a, b, sizeof a)\n#define IN freopen(\"in.txt\", \"r\", stdin)\n#define DEBUG(a) cout << (a) << endl\ntypedef long long ll;\nconst int INF = 0x3f3f3f3f;\nint mod = 1e9 + 7;\nconst int maxn = 1e5 + 10;\nint main()\n{\n     int i,n,m,j,k=1,l,max1=1;\n    scanf(\"%d\",&n);\n    m=n;max1=1;k=1;\n    while(m>0)\n    {\n        j=m%10;\n        m=m/10;\n        max1=max1*j;\n    }\n    for(i=1;;i++)\n    {\n        m=n; int ans=1;\n        l=pow(10,i);\n        m=(m/l-1)*l;\n        if(m<0)break;\n        m=m+l-1;\n        while(m>0)\n        {\n        j=m%10;\n        m=m/10;\n        ans=ans*j;\n        }\n        max1=max(max1,ans);\n    }\n    printf(\"%d\\n\",max1);\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ed7662bca235fc1a29cb52c79d4650fe", "src_uid": "38690bd32e7d0b314f701f138ce19dfb", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <cstdio>\n#include <iostream>\n#include <cmath>\n#include <algorithm>\nusing namespace std;\n#define mem(a, b) memset(a, b, sizeof a)\n#define IN freopen(\"in.txt\", \"r\", stdin)\n#define DEBUG(a) cout << (a) << endl\ntypedef long long ll;\nconst int INF = 0x3f3f3f3f;\nint mod = 1e9 + 7;\nconst int maxn = 1e5 + 10;\nint main()\n{\n     int i,n,m,j,k=1,l,max1=1;\n    while(~scanf(\"%d\",&n)){\n    m=n;max1=1;k=1;\n    while(m>0)\n    {\n        j=m%10;\n        m=m/10;\n        max1=max1*j;\n    }\n    for(i=1;;i++)\n    {\n        m=n; int ans=1;\n        l=pow(10,i);\n        m=(m/l-1)*l;\n        if(m<0)break;\n        m=m+l-1;\n        while(m>0)\n        {\n        j=m%10;\n        m=m/10;\n        ans=ans*j;\n        }\n        max1=max(max1,ans);\n    }\n    printf(\"%d\\n\",max1);\n    }\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5899d281ccc02fcae2854f572bdd424b", "src_uid": "38690bd32e7d0b314f701f138ce19dfb", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#define _CRT_SECURE_NO_WARNINGS\n#include<iostream>\n#include<stdio.h>\nusing namespace std;\nint ans;\nchar c[11], tmpc[11];\nint prod( char *ch)\n{\n\tint pr = 1, id = 0;\n\twhile (ch[id])\n\t{\n\t\tpr *= ch[id] - '0';\n\t\tid++;\n\t}\n\treturn pr;\n}\nint main()\n{\n\t//freopen(\"input.txt\", \"r\", stdin);\t\n\tscanf(\"%s\", c);\n\tint l = 0;\n\twhile (c[l])\n\t\tl++;\n\tans = prod(c);\n\tfor (int i = 0; i < l; i++) {\n\t\tif (c[l] - '0' == 0)\n\t\t\tcontinue;\n\t\tfor (int j = 0; j < i; j++)\n\t\t\ttmpc[j] = c[j];\n\t\ttmpc[i] = (c[i] - '0' - 1) + '0';\n\t\tfor (int j = i + 1; j < l; j++)\n\t\t\ttmpc[j] = '9';\n\t\tint tmppr = prod(tmpc);\n\t\tif (tmppr > ans)\n\t\t\tans = tmppr;\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ad31d37e36261a18819dda09133acf10", "src_uid": "38690bd32e7d0b314f701f138ce19dfb", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <bits/stdc++.h>\nusing namespace std;\n#include<iostream>\n\nint main()\n{\n  int n,i,rem;\n  vector<int> arr;\n  vector<int> arr1;\n\n  cin>>n;\n  int l=0;\n  int k=0;\n\n  while(n!=0)\n  { \n    rem=n%10;\n  \n    arr.push_back(rem);\n    if(n<10)\n    {\n      arr1.push_back(n-1);\n    }\n    else \n    {\n      arr1.push_back(9);\n    }\n    n=n/10;\n  }\n  reverse(arr.begin(),arr.end());\n  reverse(arr1.begin(),arr1.end());\n  int product =1;\n  int ultimate=0;\n  int j;\n  if(arr[0]==1)\n  {\n    ultimate=pow(9, arr.size()-1);\n  }\n  else\n  {\n  for(i=0;i<arr.size();i++)\n  {\n\n    arr1[i]=arr[i]-1;\n    for(j=0;j<arr.size();j++)\n    {\n      //if(arr1[i]!=0)\n      product=product*arr1[j];\n    }\n    arr1[i]=arr[i];\n    if(product>ultimate)\n    {\n      ultimate=product;\n    }\n    product=1;\n  }}\n  cout<<ultimate<<endl;\n  return 0;\n\n\n\n  \n}\nChat conversation end\nType a message...\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "91e51b31a57b0098b041a8b3eeac6044", "src_uid": "38690bd32e7d0b314f701f138ce19dfb", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <string.h>\n#include <stdlib.h>\n#include <time.h>\n\n//srand(time(NULL));\n//nombre_aleatoire = rand();\n\ntypedef struct cel\n{\n\tint number;\n\tint value;\n}cell;\n\nint main ()\n{\n\tint a,j=1,i=10,s=1,aux;\n\tcell t[11],max;\n\tscanf(\"%d\",&a);\n\n\tt[0].number=a;\n\taux=a;\n\twhile(aux>=1)\n\t{\n\t\ts=s*(aux%10);\n\t\taux=aux/10;\n\t}\n\tt[0].value=s;\n\twhile(a/i!=0)\n\t{\n\t\n\t\ts=1;\n\t\taux=a;\n\t\taux=aux-(aux%i+1);\n\t\tt[j].number=aux;\n\t\t\n\t\t\n\t\twhile(aux>=1)\n\t\t{\n\t\t\ts=s*(aux%10);\n\t\t\taux=aux/10;\n\t\t}\n\t\tt[j].value=s;\n\t\tj++;\n\t\ti=i*10;\n\t}\n\tmax.value=t[0].value;\n\tmax.number=0;\n\tfor(i=0;i<j;i++)\n\t{\n\t\tif(t[i].value>max.value)\n\t\t{\n\t\t\tmax.value=t[i].value;\n\t\t\tmax.number=i;\n\t\t}\n\t\t\n\t}\n\tprintf(\"%d\\n\",max.value);\n\t\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9214199d952293a16eb0806bb44fc34d", "src_uid": "38690bd32e7d0b314f701f138ce19dfb", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n#include<cstdio>\n#include<cstring>\n#include<cmath>\n#include<algorithm>\ntypedef long long ll;\nusing namespace std;\nint num[120];\nint main()\n{\n    int n,i,m;\n    memset(num,0,sizeof(num));\n    scanf(\"%d%d\",&n,&m);\n    for(i=0;i<m;i++)\n    {\n        int x;\n        scanf(\"%d\",&x);\n        num[x]++;\n    }\n    int ans=0;\n    int j;\n    for(i=1;i<=100;i++)\n    {\n        int sum=0;\n        for(j=1;j<=100;j++)\n        {\n            sum+=num[i]/i;\n        }\n        if(sum>=n)\n            ans=i;\n        else break;\n    }\n    printf(\"%d\\n\",ans);\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cdda8c81d8c3a489d7d895c7294a6379", "src_uid": "b7ef696a11ff96f2e9c31becc2ff50fe", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <iostream>\nusing namespace std;\nvoid merge(int arr[], int l, int m, int r)\n{\n    int i, j, k;\n    int n1 = m - l + 1;\n    int n2 =  r - m;\n\n    int L[n1], R[n2];\n\n    for (i = 0; i < n1; i++)\n        L[i] = arr[l + i];\n    for (j = 0; j < n2; j++)\n        R[j] = arr[m + 1+ j];\n\n    i = 0;\n    j = 0;\n    k = l;\n    while (i < n1 && j < n2)\n    {\n        if (L[i] <= R[j])\n        {\n            arr[k] = L[i];\n            i++;\n        }\n        else\n        {\n            arr[k] = R[j];\n            j++;\n        }\n        k++;\n    }\n\n    while (i < n1)\n    {\n        arr[k] = L[i];\n        i++;\n        k++;\n    }\n\n    while (j < n2)\n    {\n        arr[k] = R[j];\n        j++;\n        k++;\n    }\n}\nvoid mergeSort(int arr[], int l, int r)\n{\n    if (l < r)\n    {\n        int m = l+(r-l)/2;\n\n        mergeSort(arr, l, m);\n        mergeSort(arr, m+1, r);\n\n        merge(arr, l, m, r);\n    }\n}\n\n\nint main()\n{\n    int i,j,n,m;\n    cin>>n>>m;\n    int c[n],b[m];\n    for(i=0;i<n;i++)\n    {\n        cin>>c[i];\n    }\n    for(i=0;i<m;i++)\n    {\n        cin>>b[i];\n    }\n    int st=0,count=0;\n    for(i=0;i<m;i++)\n    {\n        for(j=st;j<n;j++)\n        {\n            if(b[i]>=c[j])\n            {\n                count++;\n                st=j+1;\n                break;\n            }\n        }\n        if(j==n)\n            break;\n    }\n    cout<<count;\n\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6978108536c4ae1cf5a6bf0cab664978", "src_uid": "b7ef696a11ff96f2e9c31becc2ff50fe", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#include<ctype.h>\n#define G1I(i) int i; scanf(\"%d\",&i)\n#define G2I(i,j) int i,j; scanf(\"%d%d\",&i,&j)\n#define G3I(i,j,k) int i,j,k ; scanf(\"%d%d%d\",&i,&j,&k)\n#define g1i(i) scanf(\"%d\",&i)\n#define g2i(i,j) scanf(\"%d%d\",&i,&j)\n#define g3i(i,j,k) scanf(\"%d%d%d\",&i,&j,&k)\n#define G1C(c) char c; scanf(\"%c\",&c)\n#define g1c(c) scanf(\"%c\",&c)\n#define G1S(s,len) char s[len]; scanf(\"%s\",s)\n#define Fin(i,m,n) for(int i = m;i < n;i++)\n#define lli long long int\n#define G1lli(i) lli i; scanf(\"%I64d\",&i);\n#define G2lli(i,j) lli i,j,k; scanf(\"%I64d%I64d\",&i,&j);\n#define G3lli(i,j,k) lli i,j,k; scanf(\"%I64d%I64d%I64d\",&i,&j,&k);\n#define g1lli(i) scanf(\"%I64d\",&i)\n#define g2lli(i,j) scanf(\"%I64d%I64d\",&i,&j)\n#define g3lli(i,j,k) scanf(\"%I64d%I64d%I64d\",&i,&j,&k)\n#define P1I(i) printf(\"%d\",i)\n\nint Types[101];\n\nint compare(const void* a,const void* b){\n\treturn *(int*)b - *(int*)a;\n}\n\nint main(){\n\tG2I(n,m);\n\tint cnt = 0;\n\tFin(i,0,m){\n\t\tG1I(type);\n\t\tif(Types[type] == 0) cnt++;\n\t\tTypes[type]++;\n\t}\n\tqsort(Types,101,sizeof(int),compare);\n\tint days = 0;\n\tint eat[n];\n\tFin(i,0,n) eat[i] = i;\n\twhile(1){\n\t\tint flag = 1;\n\t\tFin(i,0,n){\n\t\t\tif(Types[eat[i]] > 0){\n\t\t\t\tTypes[eat[i]]--;\n\t\t\t}else{\n\t\t\t\tflag = 0;\n\t\t\t\tFin(j,0,cnt){\n\t\t\t\t\tif(Types[j] - days - 1 >= 0){\n\t\t\t\t\t\tTypes[j] -= days + 1;\n\t\t\t\t\t\tTypes[eat[i]] += days;\n\t\t\t\t\t\teat[i] = j;\n\t\t\t\t\t\tflag = 1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(!flag) break;\n\t\t\t}\n\t\t}\n\t\tif(!flag) break;\n\t\tdays++;h\n\t}\n\tP1I(days);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ab6eb54736fdfeec7957fccca83a7e59", "src_uid": "b7ef696a11ff96f2e9c31becc2ff50fe", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <assert.h>\n#include <limits.h>\n#include <math.h>\n#include <stdbool.h>\n#include <stddef.h>\n#include <stdint.h>\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\n\nint main()\n{\n    int count[2000] ={0};\n    int arr[1000] ={0}; \n    int n,m,i;\n    scanf(\"%d %d\",&n,&m);\n    for(i=0;i<m;i++){\n        scanf(\"%d\",&arr[i]);\n        count[arr[i]]++;\n    }\n    int max = m/n;\n    int brr[1000];\n    int b = 0;\n    for(i=0;i<200;i++){\n        if(count[i]>0){\n            brr[b]=i;\n            b++;\n        }\n    }\n    \n    if(b>=n){\n        max = 0;\n        for(i=0;i<n;i++){\n            max = max + count[brr[i]];\n        }\n    }\n    while(max>=0){\n        int f = 0;\n        for(i=0;i<n;i++){\n            f = f + count[brr[i]]/max;\n        }\n        if(f>=n){\n            printf(\"%d\\n\",max);\n            break;\n        }\n        max = max - 1;\n    }\n    \n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d625887b4a9491e55bc6221802006358", "src_uid": "b7ef696a11ff96f2e9c31becc2ff50fe", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#define MAX 101\n\nint main() {\n\tint i, aux, temp;\n\tint n, m, k;\n\tint vec[MAX] = {0};\n\n\t// reding the number of participants and the number of food packages\n\tscanf(\"%d %d\", &n, &m);\n\n\t// storing the quantity of each element in the array, using the value itself as an index (0 based array)\n\tfor (i = 0; i < m; i++) {\n\t\tscanf(\"%d\", &aux);\n\n\t\tvec[aux - 1]++;\n\t\t// printf(\"%d\\n\", vec[aux - 1]);\n\t}\t\n\n\t// this outerloop will go from the greatest possible number of days\n\t// to the least one\n\tfor (i = MAX - 1; i >= 0; i--) {\n\t\tk = 0;\n\n\t\t// this innerloop will go through all of the elements in the array \n\t\tfor (aux = 0; aux < MAX; aux++) {\n\n\t\t\ttemp = vec[aux];\n\t\t\t// this inner loop will check how many times the current element can fit\n\t\t\t// into the number of days\n\t\t\twhile(temp >= i) {\n\t\t\t\tk++;\n\t\t\t\ttemp -= i;\n\t\t\t}\n\t\t}\n\n\t\t// here we verify if the number of people fed is at least equal to the number\n\t\t// of participants\n\t\tif (k >= n) {\n\t\t\tprintf(\"%d\\n\", i);\n\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\tprintf(\"0\\n\");\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "25cf39e3d706b4c59f6798964e625826", "src_uid": "b7ef696a11ff96f2e9c31becc2ff50fe", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "include <stdio.h>\n\nstruct {\n\tchar valor, naipe;\n\tvalor = 0;\n\tnaipe = 0;\t\n} card ;\n\nint main(){\n\tstruct card* primeira, segunda;\n\tchar trunfo, c;\n\tscanf (\"%c\", &trunfo);\n\tscanf (\"%c\", &c); \n\tscanf (\"%c\", &c);\n\tprimeira->valor = c;\t\n\tscanf (\"%c\", &c);\n\tprimeira->naipe = c;\t\n\tscanf (\"%c\", &c);\n\tsegunda->valor = c;\t\n\tscanf (\"%c\", &c);\n\tsegunda->valor = c;\t\n\tif (primeira->naipe == trunfo){\n\t\tif (segunda->naipe != trunfo)\n\t\t\tprintf (\"YES\");\n\t\telse {\n\t\t\tif (primeira->valor > segunda->valor)\n\t\t\t\tprintf (\"YES\");\n\t\t\telse\n\t\t\t\tprintf (\"NO\");\n\t\t}\n\n\t}\n\telse {\n\t\tif (segunda->naipe == trunfo)\n\t\t\tprintf (\"NO\");\n\t\telse {\n\t\t\tif (primeira->valor > segunda->valor)\n\t\t\t\tprintf (\"YES\");\n\t\t\telse\n\t\t\t\tprintf (\"NO\");\n\t\t}\t\n\t}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "341ca45a821ea89c0186931a139bfb77", "src_uid": "da13bd5a335c7f81c5a963b030655c26", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nstruct carta{\n\tint valor\n\tchar naipe;\n\tcarta.valor = 0;\n\tcarta.naipe = 0;\n}\n\nint main(){\n\tstruct carta primeira;\n\tstruct carta segunda;\n\tchar trunfo, c;\n\tscanf (\"%c\", &trunfo);\n\tscanf (\"%c\", &c); \n\tscanf (\"%c\", &c);\n\tswitch (c){\n\t\tcase 'T': \n\t\t\tprimeira.valor = 10; \n\t\t\tbreak;\n\t\tcase 'J': \n\t\t\tprimeira.valor = 11; \n\t\t\tbreak;\n\t\tcase 'Q': \n\t\t\tprimeira.valor = 12; \n\t\t\tbreak;\n\t\tcase 'K': \n\t\t\tprimeira.valor = 13; \n\t\t\tbreak;\n\t\tcase 'A': \n\t\t\tprimeira.valor = 14; \n\t\t\tbreak;\n\t}\n\tscanf (\"%c\", &c);\n\tprimeira.naipe = c;\t\n\tscanf (\"%c\", &c);\n\tswitch (c){\n\t\tcase 'T': \n\t\t\tsegunda.valor = 10; \n\t\t\tbreak;\n\t\tcase 'J': \n\t\t\tsegunda.valor = 11; \n\t\t\tbreak;\n\t\tcase 'Q': \n\t\t\tsegunda.valor = 12; \n\t\t\tbreak;\n\t\tcase 'K': \n\t\t\tsegunda.valor = 13; \n\t\t\tbreak;\n\t\tcase 'A': \n\t\t\tsegunda.valor = 14; \n\t\t\tbreak;\n\t}\n\tscanf (\"%c\", &c);\n\tsegunda.valor = c;\t\n\tif (primeira.naipe == trunfo){\n\t\tif (segunda.naipe != trunfo)\n\t\t\tprintf (\"YES\");\n\t\telse {\n\t\t\tif (primeira.valor > segunda.valor)\n\t\t\t\tprintf (\"YES\");\n\t\t\telse\n\t\t\t\tprintf (\"NO\");\n\t\t}\n\n\t}\n\telse {\n\t\tif (segunda.naipe == trunfo)\n\t\t\tprintf (\"NO\");\n\t\telse {\n\t\t\tif (primeira.valor > segunda.valor)\n\t\t\t\tprintf (\"YES\");\n\t\t\telse\n\t\t\t\tprintf (\"NO\");\n\t\t}\t\n\t}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b2809f9489064e5495e9f6beca94952c", "src_uid": "da13bd5a335c7f81c5a963b030655c26", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nstruct {\n\tchar valor, naipe;\n\tvalor = '0';\n\tnaipe = '0';\n} card ;\n\nint main(){\n\tstruct card primeira;\n\tstruct card segunda;\n\tchar trunfo, c;\n\tscanf (\"%c\", &trunfo);\n\tscanf (\"%c\", &c); \n\tscanf (\"%c\", &c);\n\tprimeira.valor = c;\t\n\tscanf (\"%c\", &c);\n\tprimeira.naipe = c;\t\n\tscanf (\"%c\", &c);\n\tsegunda.valor = c;\t\n\tscanf (\"%c\", &c);\n\tsegunda.valor = c;\t\n\tif (primeira.naipe == trunfo){\n\t\tif (segunda.naipe != trunfo)\n\t\t\tprintf (\"YES\");\n\t\telse {\n\t\t\tif (primeira.valor > segunda.valor)\n\t\t\t\tprintf (\"YES\");\n\t\t\telse\n\t\t\t\tprintf (\"NO\");\n\t\t}\n\n\t}\n\telse {\n\t\tif (segunda.naipe == trunfo)\n\t\t\tprintf (\"NO\");\n\t\telse {\n\t\t\tif (primeira.valor > segunda.valor)\n\t\t\t\tprintf (\"YES\");\n\t\t\telse\n\t\t\t\tprintf (\"NO\");\n\t\t}\t\n\t}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "28876e69ace5c68729bed7a8d35b14c0", "src_uid": "da13bd5a335c7f81c5a963b030655c26", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nstruct {\n\tchar valor, naipe;\n\tcarta.valor = 0;\n\tcarta.naipe = 0;\n} carta ;\n\nint main(){\n\tstruct carta primeira;\n\tstruct carta segunda;\n\tchar trunfo, c;\n\tscanf (\"%c\", &trunfo);\n\tscanf (\"%c\", &c); \n\tscanf (\"%c\", &c);\n\tprimeira.valor = c;\t\n\tscanf (\"%c\", &c);\n\tprimeira.naipe = c;\t\n\tscanf (\"%c\", &c);\n\tsegunda.valor = c;\t\n\tscanf (\"%c\", &c);\n\tsegunda.valor = c;\t\n\tif (primeira.naipe == trunfo){\n\t\tif (segunda.naipe != trunfo)\n\t\t\tprintf (\"YES\");\n\t\telse {\n\t\t\tif (primeira.valor > segunda.valor)\n\t\t\t\tprintf (\"YES\");\n\t\t\telse\n\t\t\t\tprintf (\"NO\");\n\t\t}\n\n\t}\n\telse {\n\t\tif (segunda.naipe == trunfo)\n\t\t\tprintf (\"NO\");\n\t\telse {\n\t\t\tif (primeira.valor > segunda.valor)\n\t\t\t\tprintf (\"YES\");\n\t\t\telse\n\t\t\t\tprintf (\"NO\");\n\t\t}\t\n\t}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0d2a6a92f9e1d8cef0a459d7735fe1e9", "src_uid": "da13bd5a335c7f81c5a963b030655c26", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nstruct carta{\n\tint valor;\n\tchar naipe;\n\tcarta.valor = 0;\n\tcarta.naipe = 0;\n};\n\nint main(){\n\tstruct carta primeira;\n\tstruct carta segunda;\n\tchar trunfo, c;\n\tscanf (\"%c\", &trunfo);\n\tscanf (\"%c\", &c); \n\tscanf (\"%c\", &c);\n\tswitch (c){\n\t\tcase 'T': \n\t\t\tprimeira.valor = 10; \n\t\t\tbreak;\n\t\tcase 'J': \n\t\t\tprimeira.valor = 11; \n\t\t\tbreak;\n\t\tcase 'Q': \n\t\t\tprimeira.valor = 12; \n\t\t\tbreak;\n\t\tcase 'K': \n\t\t\tprimeira.valor = 13; \n\t\t\tbreak;\n\t\tcase 'A': \n\t\t\tprimeira.valor = 14; \n\t\t\tbreak;\n\t}\n\tscanf (\"%c\", &c);\n\tprimeira.naipe = c;\t\n\tscanf (\"%c\", &c);\n\tswitch (c){\n\t\tcase 'T': \n\t\t\tsegunda.valor = 10; \n\t\t\tbreak;\n\t\tcase 'J': \n\t\t\tsegunda.valor = 11; \n\t\t\tbreak;\n\t\tcase 'Q': \n\t\t\tsegunda.valor = 12; \n\t\t\tbreak;\n\t\tcase 'K': \n\t\t\tsegunda.valor = 13; \n\t\t\tbreak;\n\t\tcase 'A': \n\t\t\tsegunda.valor = 14; \n\t\t\tbreak;\n\t}\n\tscanf (\"%c\", &c);\n\tsegunda.valor = c;\t\n\tif (primeira.naipe == trunfo){\n\t\tif (segunda.naipe != trunfo)\n\t\t\tprintf (\"YES\");\n\t\telse {\n\t\t\tif (primeira.valor > segunda.valor)\n\t\t\t\tprintf (\"YES\");\n\t\t\telse\n\t\t\t\tprintf (\"NO\");\n\t\t}\n\n\t}\n\telse {\n\t\tif (segunda.naipe == trunfo)\n\t\t\tprintf (\"NO\");\n\t\telse {\n\t\t\tif (primeira.valor > segunda.valor)\n\t\t\t\tprintf (\"YES\");\n\t\t\telse\n\t\t\t\tprintf (\"NO\");\n\t\t}\t\n\t}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b698074aa36c150935ca70c4752c1058", "src_uid": "da13bd5a335c7f81c5a963b030655c26", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    unsigned long long n,m,k,left,right,mid,temp;\n\n    scanf(\"%I64u\",&m);\n    left=0;\n    right=(long long)0xffffffffffffffff;\n    while(left<right)\n    {\n        mid=(right-left)/2+left;\n        n=mid;\n        k=2;\n        temp=0;\n        while(n/(k*k*k))\n        {\n            temp+=n/(k*k*k);\n            k++;\n        }\n        if(temp<m)left=mid+1;\n        else right=mid;\n    }\n    n=left;\n    k=2;\n    temp=0;\n    while(n>=k*k*k)\n    {\n        temp+=n/(k*k*k);\n        k++;\n    }\n    if(temp==m)printf(\"%I64u\\n\",n);\n    else printf(\"-1\\n\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b952dfce3ec3e5b9b76ab6c22633a9de", "src_uid": "602deaad5c66e264997249457d555129", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <inttypes.h>\nint main(){\n\tunsigned long long m,temp,sum,numb,high,low,mid,min,i,j,sqr;\n\tscanf(\"%\"PRIu64,&m);\n\thigh=m*8+1;\n\tlow=1;\n\tmin=high+1;\n\twhile ((high-low)>1){\n\t\t//printf(\"%\"PRIu64\" %\"PRIu64,high,low);\n\t\tsum=0;\n\t\tmid = (high+low)/2;\n\t\tfor(i=0;i<mid;i++)if (i*i*i>=mid)break;\n\t\tsqr = i;\n\t\t//printf(\" %\"PRIu64,sqr);\n\t\tfor(j=2;j<=sqr;j++){\n\t\t\ttemp=j*j*j;\n\t\t\tnumb=mid/temp;\n\t\t\tsum+=numb;\n\t\t}\n\t\t//printf(\" %\"PRIu64\"\\n\",sum);\n\t\tif (sum==m) if (mid < min) min = mid;\n\t\tif(sum>=m)high=mid;\n\t\telse low = mid;\n\t}\n\tif(min<(8*m+1))printf(\"%\"PRIu64,min);\n\telse printf(\"-1\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "61e56ac30405b8662178a7a5d07ad059", "src_uid": "602deaad5c66e264997249457d555129", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n\tlong long int c,m,k=2,p,s=0,i,a,b,power[100005]={0,1};\n\tscanf(\"%lld\",&m);\n\tfor(i=1;i<100005;i++)\n\tpower[i]=pow(i,3);\n\twhile(s<m)\n\t{\n\t\ts=0;\n\t\tp=power[k];\n\t\tfor(i=2;i<=k;i++)\n\t\ts=s+p/power[i];\n\t\tk++;\n\t}\n\tif(s==m)\n\tprintf(\"%lld\\n\",p);\n\telse\n\t{\n\t\ta=power[k-2];\n\t\tb=power[k-1];\n\t\tfor(i=a;i<=b;i++)\n\t\t{\n\t\t\tc=2;\n\t\t\ts=0;\n\t\t\twhile(i/power[c]>0)\n\t\t\t{\n\t\t\t\ts=s+i/power[c];\n\t\t\t\tc++;\n\t\t\t}\n\t\t\tif(s>=m)\n\t\t\tbreak;\n\t\t}\n\t\tif(s==m)\n\t\tprintf(\"%lld\\n\",i);\n\t\telse\n\t\tprintf(\"-1\\n\");\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9249201d2319e0e27648e7488f5ca37f", "src_uid": "602deaad5c66e264997249457d555129", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    long long n,m,k,left,right,mid,temp;\n\n    scanf(\"%I64d\",&m);\n    left=0;\n    right=0x7fffffff;\n    while(left<right)\n    {\n        mid=(right-left)/2+left;\n        n=mid;\n        k=2;\n        temp=0;\n        while(n/(k*k*k))\n        {\n            temp+=n/(k*k*k);\n            k++;\n        }\n        if(temp<m)left=mid+1;\n        else right=mid;\n    }\n    n=left;\n    k=2;\n    temp=0;\n    while(n>=k*k*k)\n    {\n        temp+=n/(k*k*k);\n        k++;\n    }\n    if(temp==m)printf(\"%I64d\\n\",n);\n    else printf(\"-1\\n\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a6f4a74db6cf20473e23d426550aebe5", "src_uid": "602deaad5c66e264997249457d555129", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tlong long int c,m,k=2,p,s=0,i,a,b,power[100005]={0,1};\n\tscanf(\"%lld\",&m);\n\tfor(i=1;i<100005;i++)\n\tpower[i]=i*i*i;\n\twhile(s<m)\n\t{\n\t\ts=0;\n\t\tp=power[k];\n\t\tfor(i=2;i<=k;i++)\n\t\ts=s+p/power[i];\n\t\tk++;\n\t}\n\tif(s==m)\n\tprintf(\"%lld\\n\",p);\n\telse\n\t{\n\t\ta=power[k-2];\n\t\tb=power[k-1];\n\t\tfor(i=a;i<=b;i++)\n\t\t{\n\t\t\tc=2;\n\t\t\ts=0;\n\t\t\twhile(i/power[c]>0)\n\t\t\t{\n\t\t\t\ts=s+i/power[c];\n\t\t\t\tc++;\n\t\t\t}\n\t\t\tif(s>=m)\n\t\t\tbreak;\n\t\t}\n\t\tif(s==m)\n\t\tprintf(\"%lld\\n\",i);\n\t\telse\n\t\tprintf(\"-1\\n\");\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "94b0a2f5cf9c1538aca4217535d9aef5", "src_uid": "602deaad5c66e264997249457d555129", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nmain()\n{\n    int n,i,y,t;\n    char a;\n    scanf(\"%d%c\", &n, &a);\n    y=n/4;\n    if (n%4!=0)\n    {\n        t=y*14;\n        if (n%2==0)#include <stdio.h>\n#include <stdlib.h>\n\nmain()\n{\n    int n,i,y,t;\n    char a;\n    scanf(\"%d%c\", &n, &a);\n    y=n/4;\n    if (n%4!=0)\n    {\n        t=y*14;\n        if (n%2==0)\n        {\n            t+=7;\n            switch (a)\n            {\n                case 'a':\n                {\n                    t+=4;\n                    break;\n                }\n                case 'b':\n                {\n                    t+=5;\n                    break;\n                }\n                case 'c':\n                {\n                    t+=6;\n                    break;\n                }\n                case 'd':\n                {\n                    t+=3;\n                    break;\n                }\n                case 'e':\n                {\n                    t+=2;\n                    break;\n                }\n                case 'f':\n                {\n                    t+=1;\n                    break;\n                }\n            }\n        }\n        else\n        {\n            switch (a)\n            {\n                case 'a':\n                {\n                    t+=4;\n                    break;\n                }\n                case 'b':\n                {\n                    t+=5;\n                    break;\n                }\n                case 'c':\n                {\n                    t+=6;\n                    break;\n                }\n                case 'd':\n                {\n                    t+=3;\n                    break;\n                }\n                case 'e':\n                {\n                    t+=2;\n                    break;\n                }\n                case 'f':\n                {\n                    t+=1;\n                    break;\n                }\n            }\n        }\n    }\n    else\n    {\n        y--;\n        t=y*13;\n        if (n%2==0)\n        {\n            t+=7;\n            switch (a)\n            {\n               case 'a':\n                {\n                    t+=4;\n                    break;\n                }\n                case 'b':\n                {\n                    t+=5;\n                    break;\n                }\n                case 'c':\n                {\n                    t+=6;\n                    break;\n                }\n                case 'd':\n                {\n                    t+=3;\n                    break;\n                }\n                case 'e':\n                {\n                    t+=2;\n                    break;\n                }\n                case 'f':\n                {\n                    t+=1;\n                    break;\n                }\n            }\n        }\n        else\n        {\n            switch (a)\n            {\n                case 'a':\n                {\n                    t+=4;\n                    break;\n                }\n                case 'b':\n                {\n                    t+=5;\n                    break;\n                }\n                case 'c':\n                {\n                    t+=6;\n                    break;\n                }\n                case 'd':\n                {\n                    t+=3;\n                    break;\n                }\n                case 'e':\n                {\n                    t+=2;\n                    break;\n                }\n                case 'f':\n                {\n                    t+=1;\n                    break;\n                }\n            }\n        }\n    }\n    printf(\"%d\", t);\n}\n        {\n            t+=7;\n            switch (a)\n            {\n                case 'a':\n                {\n                    t+=4;\n                    break;\n                }\n                case 'b':\n                {\n                    t+=5;\n                    break;\n                }\n                case 'c':\n                {\n                    t+=6;\n                    break;\n                }\n                case 'd':\n                {\n                    t+=3;\n                    break;\n                }\n                case 'e':\n                {\n                    t+=2;\n                    break;\n                }\n                case 'f':\n                {\n                    t+=1;\n                    break;\n                }\n            }\n        }\n        else\n        {\n            switch (a)\n            {\n                case 'a':\n                {\n                    t+=4;\n                    break;\n                }\n                case 'b':\n                {\n                    t+=5;\n                    break;\n                }\n                case 'c':\n                {\n                    t+=6;\n                    break;\n                }\n                case 'd':\n                {\n                    t+=3;\n                    break;\n                }\n                case 'e':\n                {\n                    t+=2;\n                    break;\n                }\n                case 'f':\n                {\n                    t+=1;\n                    break;\n                }\n            }\n        }\n    }\n    else\n    {\n        y--;\n        t=y*13;\n        if (n%2==0)\n        {\n            t+=7;\n            switch (a)\n            {\n               case 'a':\n                {\n                    t+=4;\n                    break;\n                }\n                case 'b':\n                {\n                    t+=5;\n                    break;\n                }\n                case 'c':\n                {\n                    t+=6;\n                    break;\n                }\n                case 'd':\n                {\n                    t+=3;\n                    break;\n                }\n                case 'e':\n                {\n                    t+=2;\n                    break;\n                }\n                case 'f':\n                {\n                    t+=1;\n                    break;\n                }\n            }\n        }\n        else\n        {\n            switch (a)\n            {\n                case 'a':\n                {\n                    t+=4;\n                    break;\n                }\n                case 'b':\n                {\n                    t+=5;\n                    break;\n                }\n                case 'c':\n                {\n                    t+=6;\n                    break;\n                }\n                case 'd':\n                {\n                    t+=3;\n                    break;\n                }\n                case 'e':\n                {\n                    t+=2;\n                    break;\n                }\n                case 'f':\n                {\n                    t+=1;\n                    break;\n                }\n            }\n        }\n    }\n    printf(\"%d\", t);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d4c4d1b8f8a26cdee6424e55f264db35", "src_uid": "069d0cb9b7c798a81007fb5b63fa0f45", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "int main(void) {\n    int seats[6] = {4, 5, 6, 3, 2, 1};\n    int row, seat;\n    scanf(\"%d%c\", &row, &seat);\n    row--;\n    printf(\"%d\", row / 4 * 16 + n % 2 * 7 + seats[seat - 'a']);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7b7b3036df6fef0a59f711bc8d2e5973", "src_uid": "069d0cb9b7c798a81007fb5b63fa0f45", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<cstdio>\n#include<algorithm>\n#include<cstring>\nusing namespace std;\nint main()\n{\n    char c[1010],d[1100],e[1210],f[1010],ch,o[1010],p[1010];;\n    int i,j,k,l=0,s=0,g=0,h=0;\n    gets(c);gets(d);\n    for(i=0;i<strlen(c);i++)\n    {\n        if(c[i]!=d[i])\n        {l++;\n\n         e[l]=c[i];f[l]=d[i];}\n         for(j=i;j<strlen(d);j++)\n         {\n             if(d[j]==f[l]){d[j]=e[l];o[s]=e[l];p[s]=f[l];s++;}\n\n\n         }\n\n    }for(i=0;i<s;i++){\n    for(j=i+1;j<s;j++)\n    {\n       if(o[i]==o[j]&&p[i]==p[j]) break;\nif(o[i]==p[j]&&p[i]==o[j])break;\nif((o[i]==o[j]&&p[i]!=p[j])||(p[i]==p[j]&&o[i]!=o[j]))g++;\n    }\n    if(j==s)h++;\n\n\n\n    }if(g!=0)printf(\"-1\\n\");\n    else {printf(\"%d\\n\",h);\n    for(i=0;i<s;i++){\n    for(j=i+1;j<s;j++)\n    {\n       if(o[i]==o[j]&&p[i]==p[j]) break;\nif(o[i]==p[j]&&p[i]==o[j])break;\nif((o[i]==o[j]&&p[i]!=p[j])||(p[i]==p[j]&&o[i]!=o[j]))g++;\n    }\n    if(j==s)\n\n   printf(\"%c %c\\n\",o[i],p[i]);\n\n    }\n\n\n    }\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "bbf084eef0da3cc4b2d33832023b7b5e", "src_uid": "069d0cb9b7c798a81007fb5b63fa0f45", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define ll long long\n\nchar seat[20];\n\nint colRet(char ch);\n\nint main(void)\n{\n    ll len, rem = 0, lastDigits, ans = 0;\n    char col;\n    scanf(\"%s\", seat);\n    \n    len = (ll)strlen(seat);\n    col = seat[len-1];\n    \n    for(ll i = 0; i < len - 1; i++)\n    {\n        rem *= 10;\n        rem += seat[i] - '0';\n    }\n    \n    ans = (rem / 4) * 16;\n    \n    lastDigits = rem % 4;\n    \n    if (lastDigits == 1 || lastDigits == 3)\n    {\n        ans += colRet(col);\n    }\n    else if (lastDigits == 2 || lastDigits == 4)\n    {\n        ans += 7 + colRet(col);\n    }\n    \n    printf(\"%I64d\\n\", ans);\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9e691a718c83284f6e5646678aeafafc", "src_uid": "069d0cb9b7c798a81007fb5b63fa0f45", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n\tint i,serve=0,n;\n\tchar s[2];\n\tscanf(\"%s\",s);\n\tn=s[0]-'0';\n\tserve=(n-1)/4*16;\n\tif(n%2==1){\n\t\tif(s[1]=='d'||s[1]=='e'||s[1]=='f'){\n\t\t\n\t\tserve=serve+'g'-s[1];\n}\nelse{\n\tserve=serve+4+s[1]-'a';\n}\n\t}\n\telse{\n\t\tif(s[1]=='d'||s[1]=='e'||s[1]=='f'){\n\t\t\n\t\tserve=serve+'g'-s[1]+7;\n}\nelse{\n\tserve=serve+s[1]-'a'+11;\n}\n\t}\n\tprintf(\"%d\",serve);\n\t\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ad067494d66ec6051da5dd472e24c5a2", "src_uid": "069d0cb9b7c798a81007fb5b63fa0f45", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nchar s[101],c[101];\nint main()\n{\n    scanf(\"%s\",s);\n    int l=strlen(s),i,flag=0,n=1;\n    c[0]=s[0];\n    for(i=1;i<l-1;++i)\n    {\n        if(s[i]=='a' && !flag && s[i+1]=='t' && i+1!=l-1)\n            c[n++]='@',i+=1,flag=1;\n        else if(s[i]=='d' && s[i+1]=='o' && s[i+2]=='t'&& i+2!=l-1)\n            c[n++]='.',i+=2;\n        else\n            c[n++]=s[i];\n    }\n    c[n++]=s[l-1];\n    c[n]='\\n';\n    printf(\"%s\",c);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2ec9acfdad280275df6f919be53fce67", "src_uid": "a11c9679d8e2dca51be17d466202df6e", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n#include <string.h>\n\n#define N\t100\n\nint main() {\n\tstatic char cc[N + 1];\n\tint n, m, i, at;\n\n\tscanf(\"%s\", cc), n = strlen(cc);\n\tat = 0;\n\tm = 0;\n\tfor (i = 0; i < n; i++)\n\t\tif (i > 1 && i < n - 1 && m >= 1 && cc[m - 1] == 'a' && cc[i] == 't' && !at) {\n\t\t\tat = 1;\n\t\t\tcc[m - 1] = '@';\n\t\t} else if (i > 2 && i < n - 1 && m >= 2 && cc[m - 2] == 'd' && cc[m - 1] == 'o' && cc[i] == 't')\n\t\t\tcc[--m - 1] = '.';\n\t\telse\n\t\t\tcc[m++] = cc[i];\n\tcc[m] = '\\0';\n\tprintf(\"%s\\n\", cc);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1baecbba628ebde489d4db31262d7482", "src_uid": "a11c9679d8e2dca51be17d466202df6e", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void)\n{\n  char c;\n  char znak[400];\n  int krok = 0;\n  int i = 0;\n  int zavynac = 0;\n  \n  \n  while ((c = getchar()) != EOF){\n    znak[i] = c;\n    i++;\n  }\n  int maxi = i;\n  \n  for (i = 0; i < maxi; i++){\n    if (i > 0){\n      if ((znak[i] == 'd') && (znak[i + 1] == 'o') && (znak[i + 2] == 't') && ((i + 4) != maxi)){\n        putchar('.');\n        i++;\n        i++;\n      } else if ((znak[i] == 'a') && (znak[i + 1] == 't') && (zavynac == 0)){\n        putchar('@');\n        zavynac++;\n        i++;\n      } else {\n        putchar(znak[i]);\n      }\n    } else {\n      putchar(znak[i]);\n    }\n  }\n  \n  \n  \n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "266e0fe7962e88396e1adb2171423a01", "src_uid": "a11c9679d8e2dca51be17d466202df6e", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#define p printf\n\tchar a[1444],u,at;\n\tint i,j;\nint main(){\n\tscanf(\"%s\",a);\n\tu=strlen(a);\n\tif(a[1]=='a' && a[2]=='t'){\n\t\tp(\"%c@\",a[0]);\n\t\tj=3;at++;\n\t}\n\telse if(a[0]=='d' && a[1]=='o' && a[2]=='t'){\n\t\tp(\"dot\");\n\t\tj=3;\n\t}\n\tif(a[0]=='a' && a[1]=='t'){\n\t\tp(\"at\");\n\t\tj=2;\n\t}\n\tfor(i=j;i<u;i++){\t\n\t\tif(i==u-3 && a[u-2]=='o' && a[u-3]=='d'){\n\t\t\tp(\"dot\");return 0;\n\t\t}\n\t\telse if(a[i]=='d' && a[i+1]=='o' && a[i+2]=='t'){\n\t\t\tp(\".\");i+=2;}\n\t\telse if(a[i]=='a' && a[i+1]=='t'){\n\t\t\tif(!at){\n\t\t\t\tp(\"@\");\n\t\t\t\tat++;\n\t\t\t}\n\t\t\telse p(\"at\");i++;}\n\t\telse p(\"%c\",a[i]);\n\t}\n\tp(\" \");}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6fdaeafe19afb065a1ae2ec6ec234185", "src_uid": "a11c9679d8e2dca51be17d466202df6e", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint i,lenght,ok_at;\nchar s[101];\n\nint main()\n{\n   scanf(\"%s\",&s);\n    lenght=strlen(s);\n\n    for(i=1;i<lenght-2;i++)\n    {\n\n     if(s[i]=='d' && i<lenght-3)\n            if(s[i+1]=='o' && s[i+2]=='t')\n            {\n\n                s[i]='.';\n                 strcpy(s+i+1,s+i+3);\n                 lenght-=2;\n\n            }\n        if(s[i]=='a' && ok_at==0)\n            if(s[i+1]=='t')\n                {\n                    s[i]='@';\n                    strcpy(s+i+1,s+i+2);\n                    ok_at=1;\n                    lenght-=1;\n\n                }\n\n    }\nprintf(\"%s\",s);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "371d731089769a29f89d068e89f68489", "src_uid": "a11c9679d8e2dca51be17d466202df6e", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main ()\n{\n    int a,b,sum,max=0,p,x,y,ans,i,c;\n    scanf(\"%d %d\",&a,&b);\n    x=a;\n    y=b;\n    while(a)\n    {\n        p=a%10;\n        if(p>max)\n            max=p;\n        a=a/10;\n    }\n    while(b)\n    {\n        p=b%10;\n        if(p>max)\n            max=p;\n        b=b/10;\n    }\n    max++;\n    i=0;\n    a=0;\n    while(x)\n    {\n        c=x%10;\n        a=a+(c*ceil(pow(max,i)));\n        i++;\n        x=x/10;\n    }\n    b=0;\n    i=0;\n    while(y)\n    {\n        c=y%10;\n        b=b+(c*ceil(pow(max,i)));\n        i++;\n        y=y/10;\n    }\n    sum=a+b;\n    ans=ceil(log(sum+1)/log(max));\n    printf(\"%d\\n\",ans);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d5051b6cbfd88df93c5902ff1b0dd3eb", "src_uid": "8ccfb9b1fef6a992177cc49bd56fab7b", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "\nint pow(int a,int b)\n{\n    int ans=1,i;\n    for(i=0;i<b;i++)\n    {\n                    ans*=a;\n    }\n    return ans;\n}\nint sum(int a,int b,int base)\n{\n    int i,ans=0;\n    i=0;\n    \n    while(a>0)\n    {\n           ans+=pow(base,i)*(a%10); \n           // printf(\"ans=%d \",pow(base,i));  \n           a/=10;\n           i++;\n    }\n    i=0;\n    while(b>0)\n    {\n           ans+=(int)pow(base,i)*(b%10); \n           //printf(\"ans=%d \",ans);   \n           b/=10;\n           i++;\n    }\n    //printf(\"ans=%d \",ans); \n    return ans;\n}\nint leng(int n,int base)\n{\n    int c=0;\n    if(n>9)\n    return 0;\n    else\n    return 1;\n    return c;\n}\n              \nint m(int a)\n{\n    int ma=0;\n    while(a!=0)\n    {\n             if(ma<a%10)\n             {\n                        ma=a%10;\n             }\n             a/=10;\n    } \n    return ma;\n}\nint bin(int a,int s)\n{\n    int c=0;\n    while(a!=0)\n    {\n               c+=leng(a%s,s);\n              // printf(\"%d  \",a%s);\n               a/=s;\n    }\n    //printf(\"\\n\");\n    return c;\n}\n    \nint main()\n{\n    int a,b;\n    int s;\n    int n,i;\n    int ans=0;\n    scanf(\"%d %d\",&a,&b);\n    //n=sum(a,b);\n    s=m(a)>m(b)?(m(a)+1):(m(b)+1);\n    //printf(\"%d\",s);\n    for(i=s;i<=16;i++)\n    {\n    n=sum(a,b,i);\n   // printf(\"%dsdssd\",n);\n    if(ans<bin(n,i))\n                    ans=bin(n,i);\n    }\n     // printf(\"%dlll\",bin(n,16));\n    printf(\"%d\",ans);\n    scanf(\"%*d\");\n    return 0;\n}\n    \n    \n    \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7f6347d792e81d92f170150c21d7139b", "src_uid": "8ccfb9b1fef6a992177cc49bd56fab7b", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    long long int max=0,a=0,x,y,sum=0,s_1=0,s_2=0,b=0,r=0,cary=0,num=0,i;\n    double d;\n    scanf(\"%lld %lld\",&x,&y);\n    s_1=x;\n    while(s_1!=0)\n    {\n        s_2=(s_1%10);\n        s_1=(s_1/10);\n        if(max<=s_2)max=s_2;\n        else continue;\n    }\n       s_1=y;\n    while(s_1!=0)\n    {\n        s_2=(s_1%10);\n        s_1=(s_1/10);\n        if(max<=s_2)max=s_2;\n        else continue;\n    }\n    for(i=1;((x!=0)||(y!=0));i++)\n    {\n      a=(x%10);\n      b=(y%10);\n      x=(x/10);\n      y=(y/10);\n      sum=(a+b)+cary;\n      cary=sum/(max+1);\n      r=(sum%(max+1));\n      num=(num*10)+r;\n        }\n    if(cary!=0)printf(\"%lld\",i);\n    else printf(\"%lld\",(i-1));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "131850ac11c1e2879748322a930780c3", "src_uid": "8ccfb9b1fef6a992177cc49bd56fab7b", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint max(int a, int b) {\n\treturn a >= b ? a : b;\n}\n\nint main(void) {\n\tchar a[5];\n\tchar b[5];\n\t\n\tscanf(\"%s%s\", &a, &b);\n\t\n\tint a_length = strlen(a);\n\tint b_length = strlen(b);\n\t\n\tint max_digit = 0;\n\tint i;\n\tfor (i = 0; i < a_length; i++) {\n\t\ta[i] -= '0';\n\t\tmax_digit = max(max_digit, a[i]);\n\t}\n\t\n\tfor (i = 0; i < b_length; i++) {\n\t\tb[i] -= '0';\n\t\tmax_digit = max(max_digit, b[i]);\n\t}\n\t\n\tint base = max_digit + 1;\n\t\n\ti = a_length - 1;\n\tint j = b_length - 1;\n\tint carry = 0;\n\tint sum;\n\twhile (i >= 0 || j >= 0) {\n\t\tsum = 0;\n\t\tif (i >= 0) { sum += a[i]; i--; }\n\t\tif (j >= 0) { sum += b[j]; j--; }\n\t\tsum += carry;\n\t\tcarry = sum / base;\n\t}\n\t\n\tint result = max(a_length, b_length);\n\tif (carry) result++;\n\t\n\tprintf(\"%d\\n\", result);\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8047cf27297ec6c32c00ac6b153a17ba", "src_uid": "8ccfb9b1fef6a992177cc49bd56fab7b", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\nint main()\n{\n   int a[101]={0},b[101]={0},ans[101]={0};\n   int i,j,k,temp,la,lb,max;\n   char t[101]={'0'};\n   k=0;\n   scanf(\"%s\",t);\n   max=0;\n   la=strlen(t);\n   for (i=la;i>=1;i--)\n   {\n     a[la-i+1]=t[i-1]-'0';\n     if (a[la-i+1]>max) max=a[la-i+1];\n   }\n   scanf(\"%s\",t);\n   lb=strlen(t);\n   for (i=lb;i>=1;i--)\n   {\n     b[lb-i+1]=t[i-1]-'0';\n     if (b[lb-i+1]>max) max=b[lb-i+1];\n   }\n   max++;\n   if (la>lb) k=la;\n           else   k=lb;\n    temp=0;\n   for (i=1;i<=k;i++)\n    {\n       ans[i]=a[i]+b[i]+temp;\n       temp=ans[i] / max;\n       ans[i]=ans[i] % max;\n    }\n   if (temp!=0) {k++; ans[k]=temp;}\n    printf(\"%d\",k);\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "de8a23712d964681b8c59f672e2a818a", "src_uid": "8ccfb9b1fef6a992177cc49bd56fab7b", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n\tlong long n;\n\twhile (scanf(\"%lld\", &n) == 1)\n\t\tprintf(\"%lld\\n\", n-1);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8454f4563284aa81ef69b2fad656234c", "src_uid": "3d3432b4f7c6a3b901161fa24b415b14", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n\tint a,b,c,k;\n\tlong long int n;\n\tcin>>n;\n\ta=1;\n\tb=1;\n\tc=0;\n\tk=a+b;\n\twhile(k<=n)\n\t{   c++;\n\t    a=b;\n\t  \tb=k;\n\t  k=a+b;\t\n\t}\n    cout<<(c)<<endl;\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "42895541e3f00291049fc389186f1920", "src_uid": "3d3432b4f7c6a3b901161fa24b415b14", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main ()\n{\n    int i, a[120], A[120], n;\n    A[1] = 2;\n    A[2] = 3;\n    scanf (\"%d\", &n);\n    for (int i = 3; i < i++)\n    {\n        A[i] = a[i-1] + a[i-2];\n    }\n    for (int i = 1; i < i++)\n    {\n        if (A[i] > n)\n        {\n            printf (\"%d\\n\", i-1);\n            break;\n        }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "500700d1be79fcd10f36f7272111bb78", "src_uid": "3d3432b4f7c6a3b901161fa24b415b14", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <cstdio>\n#include <vector>\n#include <iostream>\nusing namespace std;\n\ntypedef long long LL;\nll a[120];\n\nint main ()\n{\n    ll n;\n    A[1] = 2;\n    A[2] = 3;\n    scanf (\"%lld\", &n);\n    for (int i = 3; i < i++)\n    {\n        A[i] = a[i-1] + a[i-2];\n    }\n    for (int i = 1; i < i++)\n    {\n        if (A[i] > N)\n        {\n            printf (\"%d\\n\", i-1);\n            break;\n        }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "82ce9e9f555f95d429434c013a3f85bc", "src_uid": "3d3432b4f7c6a3b901161fa24b415b14", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n\tint a,b,c,k;\n\tlong n;\n\tcin>>n;\n\ta=1;\n\tb=1;\n\tc=0;\n\tk=a+b;\n\twhile(k<=n)\n\t{   c++;\n\t    a=b;\n\t  \tb=k;\n\t  k=a+b;\t\n\t}\n    cout<<(c)<<endl;\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "133af3eeb370624f5a374687d1397714", "src_uid": "3d3432b4f7c6a3b901161fa24b415b14", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nstruct string{\n\tchar str[1000];\n\tint count[1000];\n};\nint main()\n{\n\tstruct string s;\n\tscanf(\"%s\",&s.str);\n\tint i,j,k;\n\tscanf(\"%d\",&k);\n\tint len=strlen(s.str);\n\tfor(i=0;i<len;i++)\n\t{\n\t\ts.count[i]=1;\n\t}\n\tint count1=0,count2=0;\n\tfor(i=0;i<len;i++)\n\t{\n\t\tif(s.str[i]=='?')\n\t\t{\n\t\t\ts.count[i]=0;\n\t\t\ts.count[i-1]=0;\n\t\t\tcount1++;\n\t\t}\n\t}\n\tfor(i=0;i<len;i++)\n\t{\n\t\tif(s.str[i]=='*')\n\t\t{\n\t\t\ts.count[i]=0;\n\t\t\ts.count[i-1]=0;\n\t\t\tcount2++;\n\t\t}\n\t}\n\tint c;\n\tc=2*(count1+count2);\n\tint req_len;\n\treq_len=len-c;\n\tif(k<req_len)\n\t{\n\t\tprintf(\"Impossible\");\n\t}\n\telse{\n\t\tk=k-req_len;\n\t\ti=0;\n\t\twhile(k!=0 && i<len)\n\t\t{\n\t\t\tif(s.str[i]=='?')\n\t\t\t{\n\t\t\t\ts.count[i-1]++;\n\t\t\t\tk--;\n\t\t\t}\n\t\t\telse if(s.str[i]=='*')\n\t\t\t{\n\t\t\t\tfor(j=0;j<k;j++)\n\t\t\t\t{\n\t\t\t\t\ts.count[i-1]++;\n\t\t\t\t}\n\t\t\t\tk=0;\n\t\t\t}\n\t\t\ti++;\n\t\t}\n\t\tif(k!=0)\n\t\t{\n\t\t\tprintf(\"Impossible\");\n\t\t}\n\t\telse{\n\t\t\tfor(i=0;i<len;i++)\n\t\t\t{\n\t\t\t\tfor(j=0;j<s.count[i];j++)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%c\",s.str[i]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f42370160c3e17ae3529f02abde2a655", "src_uid": "90ad5e6bb5839f9b99a125ccb118a276", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<ctype.h>\n#include<stdbool.h>\n#define N 205\nint main(void)\n{\n    int i,j,print,star=0,count1=0,count2=0,length;\n    bool yn[N];\n    char line[N];\n    gets(line);\n    scanf(\"%d\",&length);\n    for(i=0; i<N; i++)\n        yn[i]=true;\n    for(i=0; line[i]; i++)\n    {\n        if(line[i]>='a'&&line[i]<='z')\n            count1++;\n        else\n            count2++;\n        if(line[i]=='*')\n            star++;\n    }\n    if(length<count1-count2)\n        printf(\"Impossible\\n\");\n    else if(length>count1&&!star)\n        printf(\"Impossible\\n\");\n    else\n    {\n        if(length>count1)\n        {\n            print=length-count1;\n            for(i=0; i<line[i]; i++)\n            {\n                if(line[i]>='a'&&line[i]<='z')\n                    printf(\"%c\",line[i]);\n                if(line[i]=='?')\n                    i++;\n                else\n                    while(print--)\n                        printf(\"%c\",line[i-1]);\n            }\n            printf(\"\\n\");\n        }\n        if(count1==length)\n        {\n            for(i=0; i<line[i]; i++)\n                if(line[i]>='a'&&line[i]<='z')\n                    printf(\"%c\",line[i]);\n            printf(\"\\n\");\n        }\n        else\n        {\n            print=count1-length;\n            for(i=0; line[i]; i++)\n            {\n                if(line[i]=='?'||line[i]=='*')\n                    yn[i]=false;\n                if((line[i]=='?'||line[i]=='*')&&print)\n                {\n                    yn[i-1]=false;\n                    print--;\n                }\n            }\n            for(i=0; line[i]; i++)\n                if(yn[i])\n                    printf(\"%c\",line[i]);\n            printf(\"\\n\");\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cb3eda5cb0fc55b1a9f470b36255c061", "src_uid": "90ad5e6bb5839f9b99a125ccb118a276", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<ctype.h>\n#include<stdbool.h>\n#define N 205\nint main(void)\n{\n    int i,j,print,star=0,count1=0,count2=0,length;\n    bool yn[N];\n    char line[N];\n    gets(line);\n    scanf(\"%d\",&length);\n    for(i=0; i<N; i++)\n        yn[i]=true;\n    for(i=0; line[i]; i++)\n    {\n        if(line[i]>='a'&&line[i]<='z')\n            count1++;\n        else\n            count2++;\n        if(line[i]=='*')\n            star++;\n    }\n    if(length<count1-count2)\n        printf(\"Impossible\\n\");\n    else if(length>count1&&!star)\n        printf(\"Impossible\\n\");\n    else\n    {\n        if(length>count1)\n        {\n            print=length-count1;\n            for(i=0; i<line[i]; i++)\n            {\n                if(line[i]>='a'&&line[i]<='z')\n                    printf(\"%c\",line[i]);\n                else if(line[i]=='?')\n                    i++;\n                else\n                    while(print--)\n                        printf(\"%c\",line[i-1]);\n            }\n            printf(\"\\n\");\n        }\n        if(count1==length)\n        {\n            for(i=0; i<line[i]; i++)\n                if(line[i]>='a'&&line[i]<='z')\n                    printf(\"%c\",line[i]);\n            printf(\"\\n\");\n        }\n        else\n        {\n            print=count1-length;\n            for(i=0; line[i]; i++)\n            {\n                if(line[i]=='?'||line[i]=='*')\n                    yn[i]=false;\n                if((line[i]=='?'||line[i]=='*')&&print)\n                {\n                    yn[i-1]=false;\n                    print--;\n                }\n            }\n            for(i=0; line[i]; i++)\n                if(yn[i])\n                    printf(\"%c\",line[i]);\n            printf(\"\\n\");\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ae0020b976f77832f3aa956a0a50acd3", "src_uid": "90ad5e6bb5839f9b99a125ccb118a276", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N 200\n\nint main() {\n\tstatic char s[N + 1], t[N + 1];\n\tint n, k, i, x, l;\n\n\tscanf(\"%s%d\", s, &k);\n\tn = strlen(s);\n\tx = 0;\n\tfor (i = 0; i < n; i++)\n\t\tif (s[i] != '?' && s[i] != '*')\n\t\t\tx++;\n\tl = 0;\n\tif (x == k) {\n\t\tfor (i = 0; i < n; i++)\n\t\t\tif (s[i] != '?' && s[i] != '*')\n\t\t\t\tt[l++] = s[i];\n\t} else if (x < k) {\n\t\tint h;\n\n\t\th = k - x;\n\t\tfor (i = 0; i < n; i++)\n\t\t\tif (s[i] == '*')\n\t\t\t\twhile (h--)\n\t\t\t\t\tt[l++] = s[i - 1];\n\t\t\telse if (s[i] != '?')\n\t\t\t\tt[l++] = s[i];\n\t\tif (h > 0) {\n\t\t\tprintf(\"Impossible\\n\");\n\t\t\treturn 0;\n\t\t}\n\t} else {\n\t\tint h, l;\n\n\t\th = x - k;\n\t\tl = 0;\n\t\tfor (i = 0; i < n; i++)\n\t\t\tif (i < n - 1 && s[i + 1] == '?' && h > 0) {\n\t\t\t\th--;\n\t\t\t} else if (s[i] != '?' && s[i] != '*')\n\t\t\t\tt[l++] = s[i];\n\t\tif (h > 0) {\n\t\t\tprintf(\"Impossible\\n\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\"%s\\n\", t);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e9298fd9f2394c33c2d81585523ea45d", "src_uid": "90ad5e6bb5839f9b99a125ccb118a276", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main ()\n{\n\tchar s[200];\n\tint n;\n\tint i,sqn,t=0,r,t1=0,f=0,j,num,num1;\n\tscanf(\"%s\",s);\n\tscanf(\"%d\",&n);\n    sqn=strlen(s);\n\tfor(i=0;i<n;i++)\n\t{\n    \tif(s[i]=='?')\n\t\t{\n\t\t\tt++;\n\t\t}\n\t\telse if (s[i]=='*')\n\t\t{\n\t\t\tt1++;\n\t\t}\n\t\telse  continue;\n\t}\n\tr=sqn-t1-t;\n\tif(r==n)\n\t{\n\t\tfor(i=0;i<sqn;i++)\n\t\t{\n\t\t\tif(s[i]!='?'&&s[i]!='*')\n\t    \tprintf(\"%c\",s[i]);\n\t\t}\n\t\t\tputchar('\\n');\n\t}\n\telse if(r<n)\n\t{\n\t\tif(t1>0)\n\t\t{\n\t\t\tnum=n-r;\n\t\t\tfor(i=0;i<sqn;i++)\n\t\t\t{\n\t\t\t\tif(s[i]!='*'&&s[i]!='?')\n\t\t\t\t\tprintf(\"%c\",s[i]);\n\t\t\t\tif(s[i]=='*'&&f==0)\n\t\t\t\t{\n\t\t\t\t\tfor(j=0;j<num;j++)\n\t\t\t\t\t\tprintf(\"%c\",s[i-1]);\n\t\t\t\t\tf=1;\n\t\t\t\t}\n\t\t\t}\n\t\t\tputchar('\\n');\n\t\t}\n    \telse\n\t\t\tprintf(\"Impossible\\n\");\n\t}\n\telse\n\t{\n\t\tnum1=r-n;\n\t\tif(t+t1<num1) \n\t\t\tprintf(\"Impossible\\n\");\n\t\telse\n\t\t{\n\t\t\tfor(i=0;i<sqn;i++)\n\t\t\t{\n\t\t\t\tif(num1!=0&&(s[i+1]='*'||s[i+1]='?')) \n\t\t\t\t\tnum1--;\n\t\t\t\telse if (s[i]=='*'||s[i]=='?') \n\t\t\t\t\tcontinue;\n\t\t\t\telse\n\t\t\t\t\tprintf(\"%c\",s[i]);\n\t\t\t\n\t\t\t}\n\t\t\tputchar('\\n');\n\t\t}\n\t}\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ce98877468280c33ce706edabbd7a953", "src_uid": "90ad5e6bb5839f9b99a125ccb118a276", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define MOD 998244353\n\n__int64 Pow(__int64 a, __int64 b)\n{\n    __int64 half;\n    if(b == 0) return 1;\n    if(b % 2 == 1) return (Pow(a, b-1)*a) % MOD;\n    half = Pow(a, b/2) % MOD;\n    return (half * half) % MOD;\n}\n__int64 nCr(__int64 n, __int64 r)\n{\n    __int64 A = 1; // A = n!, B = (n-r)!r!\n    __int64 B = 1;\n    __int64 ans;\n    __int64 i;\n\n    for(i=1;i<=n;i++)\n    {\n        A *= i;\n        A %= MOD;\n    }\n    for(i=1;i<=n-r;i++)\n    {\n        B *= i;\n        B %= MOD;\n    }\n    for(i=1;i<=r;i++)\n    {\n        B *= i;\n        B %= MOD;\n    }\n    __int64 B2 = Pow(B, MOD-2);\n    ans = (A * B2) % MOD;\n    return ans;\n}\n\nint main(void)\n{\n    __int64 size, max;\n    __int64 ans;\n\n    scanf(\"%lld %lld\", &size, &max);\n  \n    ans = nCr(max, size - 1) * (size-2) % MOD;\n    ans = (ans * Pow(2, size-3)) % MOD;\n    printf(\"%lld\\n\", ans);\n\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "fd0e5fbfaab2ddbbcbd8e4afa7cd6dbe", "src_uid": "28d6fc8973a3e0076a21c2ea490dfdba", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define MOD 998244353\n\n__int64 Pow(__int64 a, __int64 b)\n{\n    __int64 ans=1;\n    __int64 i;\n    if (b == 0) return 1;\n    for(i=0;i<b;i++)\n    {\n        ans *= a ;\n        ans %= MOD;\n    }\n    return ans;\n}\n__int64 nCr(__int64 n, __int64 r)\n{\n    __int64 A = 1; // A = n!, B = (n-r)!r!\n    __int64 B = 1;\n    __int64 ans;\n    __int64 i;\n\n    for(i=1;i<=n;i++)\n    {\n        A *= i;\n        A %= MOD;\n    }\n    for(i=1;i<=n-r;i++)\n    {\n        B *= i;\n        B %= MOD;\n    }\n    for(i=1;i<=r;i++)\n    {\n        B *= i;\n        B %= MOD;\n    }\n    __int64 B2 = Pow(B, MOD-2);\n    ans = (A * B2) % MOD;\n    return ans;\n}\n\nint main(void)\n{\n    __int64 size, max;\n    __int64 ans;\n\n    scanf(\"%lld %lld\", &size, &max);\n  \n    ans = nCr(max, size - 1) * (size-2) % MOD;\n    ans = (ans * Pow(2, size-3)) % MOD;\n    printf(\"%lld\\n\", ans);\n\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a274eaea2c9e0de839e4500ae6a5000a", "src_uid": "28d6fc8973a3e0076a21c2ea490dfdba", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define SIZE 200000\n\nint factorial(int n)\n{\n    if(n == 1) return 1;\n    return n*factorial(n-1);\n}\n\nint countArr(int arr[], int size, int max)\n{\n    int result = 0;\n    int m, i;\n\n    for(m=size-1;m<max;m++) //middle's min is size-1 \n    {\n        for(i=0;i<m-1;i++)\n        {\n            result += factorial(m-1)/(factorial(m-i-2) * factorial(i)); \n        }\n         \n    }\n    return result;\n}\n\nint main(void)\n{\n    int size, max, result;\n    int arr[SIZE];\n    while(scanf(\"%d %d\", &size, &max))\n    {   \n        printf(\"%d\\n\", countArr(arr, size, max));\n    }\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c56aada70b4c048388e6c072c39dcc3b", "src_uid": "28d6fc8973a3e0076a21c2ea490dfdba", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define SIZE 200000\n\n__int64 factorial(int n)\n{\n    if(n == 0) return 1;\n    if(n == 1) return 1;\n    return n*factorial(n-1);\n}\n\n__int64 countArr(int size, int max)\n{\n    __int64 result = 0;\n    __int64 temp;\n    int m, i;\n\n    for(m=size-1;m<=max;m++) //middle's min is size-1 \n    {\n        temp = 0;\n        for(i=0;i<size-2;i++)\n        { \n            temp += factorial(m-2)/(factorial(m-i-2) * factorial(i)); \n        }\n        result += temp * (m-1);\n    }\n    return result;\n}\n\nint main(void)\n{\n    int size, max;\n\n    while(scanf(\"%d %d\", &size, &max))\n    {   \n        printf(\"%lld\\n\", countArr(size, max));\n    }\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "af3c42b7b4ca16ab28d0a51225b51024", "src_uid": "28d6fc8973a3e0076a21c2ea490dfdba", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define MOD 998244353\n\n__int64 factorial(int n)\n{\n    __int64 i;\n    __int64 result = 1;\n    \n    if(n == 0 || n == 1) return 1;\n\n    for(i=2;i<=n;i++)\n    {\n        result *= i;\n    }\n    return result;\n}\n\n__int64 countArr(int size, int max)\n{\n    __int64 result = 0;\n    __int64 temp;\n    __int64 m, i;\n\n    for(m=size-1;m<=max;m++) //middle's min is size-1 \n    {\n        temp = 0;\n        for(i=0;i<size-2;i++)\n        { \n            temp += factorial(m-2)/(factorial(m-i-2) * factorial(i)); \n        }\n        result += temp * (m-1);\n    }\n    return result % MOD;\n}\n\nint main(void)\n{\n    __int64 size, max;\n\n    scanf(\"%d %d\", &size, &max);\n       \n    printf(\"%lld\\n\", countArr(size, max));\n    \n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f2729bcd6803d8d5259f0d8643622630", "src_uid": "28d6fc8973a3e0076a21c2ea490dfdba", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    int i,j,k,len,count=0;\n    char str[2][101];\n    str[0][100]='X';\n    str[1][100]='X';\n    for(i=0;i<2;i++)\n    {scanf(\"%s \",str[i]);\n    //printf(\"%s\",str[i]);\n    //printf(\"\\n\");\n    }\n    len=strlen(str[0]);\n    for(i=0;i<len;i++)\n    {\n        if(str[0][i]=='0'&&str[0][i+1]=='0'&&str[1][i]=='0')\n        {\n           count++;\n           str[0][i]='X';\n           str[0][i+1]='X';\n           str[1][i]='X';\n        }\n        if(str[0][i]=='0'&&str[1][i]=='0'&&str[1][i+1]=='0')\n        {\n            count++;\n            str[0][i]='X';\n            str[1][i]='X';\n            str[1][i+1]='X';\n        }\n        if(str[0][i]=='0'&&str[0][i+1]=='0'&&str[1][i+1]=='0')\n        {\n            count++;\n            str[0][i]='X';\n            str[0][i+1]='X';\n            str[1][i+1]='X';\n        }\n        if(str[0][i+1]=='0'&&str[1][i]=='0'&&str[1][i+1]=='0')\n        {\n            count++;\n            str[0][i+1]='X';\n            str[1][i]='X';\n            str[1][i+1]='X';\n        }\n    }\n    printf(\"%d\",count);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8691aa0a019daf9db823511f121d6f79", "src_uid": "e6b3e787919e96fc893a034eae233fc6", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nint main()\n{\n    char a[101], b[101];\n    int x  = 0, i  ;\n    scanf(\"%s\",a);\n    scanf(\"%s\",b);\n    \n    for(i=0;i<strlen(a);i++)\n    {\n        if(a[i]=='0'&&b[i]=='X'&&a[i+1]=='0'&&b[i+1]=='0')\n            {\n                x++;\n                a[i]='X';\n                a[i+1]='X';\n                b[i+1]='X';\n            }\n        else if(b[i]=='0'&&a[i]=='X'&&b[i+1]=='0'&&a[i+1]=='0')\n            {\n                x++;\n                b[i]='X';\n                b[i+1]='X';\n                a[i+1]='X';\n            }\n        else if(a[i]=='0' && b[i]=='0' && b[i-1] == '0' )\n        {\n            x++;\n            a[i]='X';\n            b[i]='X';\n            b[i-1]='X';\n            \n            \n        }\n        else if(a[i]=='0' && b[i]=='0' && b[i+1] == '0')\n        {\n            x++;\n            a[i]='X';\n            b[i]='X';\n            b[i+1]='X';\n        }\n        else if(b[i]=='0'&&a[i]=='0'&&a[i-1]=='0')\n        {\n            x++;\n            b[i]='X';\n            a[i]='X';\n            a[i-1]='X';\n        }\n        else if(b[i]=='0'&&a[i]=='0'&&a[i+1]=='0')\n        {\n            x++;\n            b[i]='X';\n            a[i]='X';\n            a[i+1]='X';\n        }\n    }\n    \n    \n    printf(\"%d\",x);\n\treturn 0 ;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "118797d960115fa441be987649762f03", "src_uid": "e6b3e787919e96fc893a034eae233fc6", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n#include <ctype.h>\n#include <limits.h>\n\n#define fr(i, a, b) for((i) = (a) ; (i) < (b) ; (i)++)\n#define frr(i, a, b) for((i) = (a) ; (i) >= (b) ; (i)--)\n\ntypedef long long ll;\ntypedef unsigned long long ull;\nint i, j, k, m;\n\nchar a[3][105];\n\nint c1(int st) {\n\tint ret = a[0][st] == '0' && a[0][st+1] == '0' && a[1][st] == '0' && a[1][st+1] == 'X';\n\tif(ret) {\n\t\ta[0][st] = a[0][st+1] = a[1][st] = 'X';\n\t\treturn ret;\n\t}\n\treturn 0;\n}\n\nint c2(int st) {\n\tint ret = a[0][st] == '0' && a[0][st+1] == '0' && a[1][st] == 'X' && a[1][st+1] == '0';\n\tif(ret) {\n//\t\tputs(a[0]);\n//\t\tputs(a[1]);\n\t\ta[0][st] = a[0][st+1] = a[1][st] = a[1][st+1] = 'X';\n\t\treturn ret;\n\t}\n\treturn 0;\n}\n\nint c3(int st) {\n\tint ret = a[0][st] == '0' && a[0][st+1] == 'X' && a[1][st] == '0' && a[1][st+1] == '0';\n\tif(ret) {\n//\t\tputs(a[0]);\n//\t\tputs(a[1]);\n\t\ta[0][st] = a[0][st+1] = a[1][st] = a[1][st+1] = 'X';\n\t\treturn ret;\n\t}\n\treturn 0;\n}\n\nint c4(int st) {\n\tint ret = a[0][st] == 'X' && a[0][st+1] == '0' && a[1][st] == '0' && a[1][st+1] == '0';\n\tif(ret) {\n//\t\tputs(a[0]);\n//\t\tputs(a[1]);\n\t\ta[0][st] = a[0][st+1] = a[1][st] = a[1][st+1] = 'X';\n\t\treturn ret;\n\t}\n\treturn 0;\n}\n\nint c5(int st) {\n\tint ret = a[0][st] == '0' && a[0][st+1] == '0' && a[1][st] == '0' && a[1][st+1] == '0';\n\tif(ret) {\n//\t\tputs(a[0]);\n//\t\tputs(a[1]);\n\t\ta[0][st] = a[0][st+1] = a[1][st] = 'X';\n\t\treturn ret;\n\t}\n//\tputs(a[0]);\n//\tputs(a[1]);\n\treturn 0;\n}\n\nint main() {\n//\tfreopen(\"input.in\", \"r\", stdin);\n\tscanf(\"%s\", a[0]);\n\tscanf(\"%s\", a[1]);\n\tint n = strlen(a[0]);\n\tint res = 0;\n\tfr(i, 0, n)\n\t\tif(c1(i) || c2(i) || c3(i) || c4(i) || c5(i)) res++;\n//\tputs(a[0]);\n//\t\tputs(a[1]);\n\tprintf(\"%d\", res);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "98c0d16b181bba196c212fe038bd3d20", "src_uid": "e6b3e787919e96fc893a034eae233fc6", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#define _USE_MATH_DEFINES\n#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#include <string.h>\n#include <ctype.h>\n#include <stdbool.h>\n#include <float.h>\n#include <limits.h>\n#include <malloc.h>\n#include <memory.h>\n#include <complex.h>\n#include <errno.h>\n#include <time.h>\nchar s[5][105];\nint xx[4][3]={{0,1,1},{0,1,1},{0,0,1},{0,0,1}},yy[4][3]={{0,0,1},{1,0,1},{0,1,1},{0,1,0}},\n\ti,j,a[5][105],l,ans;\n\nvoid dfs(int x,int y)\n{\n\tint i,j,f;\n\t\n\tif (y+(l-x)/2<=ans) return;\n\tif (x>=l) \n\t{\n\t\tans=y>ans ? y : ans;\n\t\treturn;\n\t}\n\tfor (i=0;i<4;i++)\n\t{\n\t\tfor (j=f=0;j<3;j++)\n\t\tif (a[xx[i][j]][x+yy[i][j]]||x+yy[i][j]>=l) \n\t\t{\n\t\t\tf=1;\n\t\t\tbreak;\n\t\t}\n\t\tif (!f)\n\t\t{\n\t\t\tfor (j=0;j<3;j++) a[xx[i][j]][x+yy[i][j]]=1;\n\t\t\tdfs(x+1,y+1);\n\t\t\tfor (j=0;j<3;j++) a[xx[i][j]][x+yy[i][j]]=0;\n\t\t}\n\t}\n\tdfs(x+1,y);\n}\n\nint main()\n{\n\tscanf(\"%s%s\",s[0],s[1]);\n\tl=strlen(s[0]);\n\tfor (j=ans=0;j<2;j++)\n\tfor (i=0;i<l;i++) \n\tif (s[j][i]=='0') a[j][i]=0; else a[j][i]=1;\n\tdfs(0,0);\n\tprintf(\"%d\\n\",ans);\n\treturn 0;\n}\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "43b81bf6dd59049e05f9a6e538c36d60", "src_uid": "e6b3e787919e96fc893a034eae233fc6", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#define _USE_MATH_DEFINES\n#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#include <string.h>\n#include <ctype.h>\n#include <stdbool.h>\n#include <float.h>\n#include <limits.h>\n#include <malloc.h>\n#include <memory.h>\n#include <complex.h>\n#include <errno.h>\n#include <time.h>\nchar s[5][105];\nint xx[4][3]={{0,1,1},{0,1,1},{0,0,1},{0,0,1}},yy[4][3]={{0,0,1},{1,0,1},{0,1,1},{0,1,0}},\n\ti,j,a[5][105],l,ans;\n\nvoid dfs(int x,int y)\n{\n\tint i,j,f;\n\t\n\t\n\tif (x>=l) \n\t{\n\t\tans=y>ans ? y : ans;\n\t\treturn;\n\t}\n\tfor (i=0;i<4;i++)\n\t{\n\t\tfor (j=f=0;j<3;j++)\n\t\tif (a[xx[i][j]][x+yy[i][j]]||x+yy[i][j]>=l) \n\t\t{\n\t\t\tf=1;\n\t\t\tbreak;\n\t\t}\n\t\tif (!f)\n\t\t{\n\t\t\tfor (j=0;j<3;j++) a[xx[i][j]][x+yy[i][j]]=1;\n\t\t\tdfs(x+1,y+1);\n\t\t\tfor (j=0;j<3;j++) a[xx[i][j]][x+yy[i][j]]=0;\n\t\t}\n\t}\n\tdfs(x+1,y);\n}\n\nint main()\n{\n\tscanf(\"%s%s\",s[0],s[1]);\n\tl=strlen(s[0]);\n\tfor (j=ans=0;j<2;j++)\n\tfor (i=0;i<l;i++) \n\tif (s[j][i]=='0') a[j][i]=0; else a[j][i]=1;\n\t//for (i=0;i<2;i++)\n\t//for (j=0;j<l;j++) printf(\"%d \",a[i][j]);\n\tdfs(0,0);\n\tprintf(\"%d\\n\",ans);\n\treturn 0;\n}\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "557acf7b24c1ee1928f1ab96fe4a7948", "src_uid": "e6b3e787919e96fc893a034eae233fc6", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "# include <stdio.h>\n# include <stdlib.h>\n# include <math.h>\n# include <string.h>\n\nint main ()\n{ \t\n\tint n,x,pos;\n\tconst int mod=1e9+7;\n\tscanf(\"%d %d %d\",&n,&x,&pos);\n    int  l=0,r=n;\n    int min=x-1,max=n-x;\n    int mid;\n    int num=1;\n    while (l<r)\n    {\n        mid=(l+r)/2;\n        if(mid<pos)\n        {\n            l=mid+1;\n            num=num*min%mod;\n            min--;\n        }\n        else if(mid==pos)\n\t\t\tl=mid+1;\n        else \n        {\n            r=mid;\n            num=num*max%mod;\n            max--;\n        }\n    }\n    for(int i=1;i<=max+min;i++)\n    {\n        num=1ll*num*i%mod;\n    }\n    printf(\"%d\",num);\n} ", "lang_cluster": "C", "compilation_error": false, "code_uid": "c63320439a6baf77eed1584971399b49", "src_uid": "24e2f10463f440affccc2755f4462d8a", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#define _CRT_SECURE_NO_WARNINGS\n\n#include <stdio.h>\n#include <inttypes.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n\ntypedef uint64_t uint64; typedef uint32_t uint32;\ntypedef int64_t int64; typedef int32_t int32;\n\n#define finc(i,a,b) for(int32 i=(a);i<=(b);i++)\n#define fdec(i,a,b) for(int32 i=(b)+1;i-->(a);)\n#define in(i,bits) scanf(\"%\"PRId##bits\"\",&i)\n#define uin(i,bits) scanf(\"%\"PRIu##bits\"\",&i)\n#define out(i,bits,c) printf(\"%\"PRId##bits\"%c\",i,c)\n#define uout(i,bits,c) printf(\"%\"PRIu##bits\"%c\",i,c)\n#define end '\\n'\n\n#define mod (int64)(1e9+7)\nint64 C[1001][1001], A[1001];\nint main(void)\n{\n\tC[0][0] = 1;\n\tfinc(i, 1, 1000)\n\t{\n\t\tC[i][0] = 1;\n\t\tC[i][1] = i;\n\t}\n\tfinc(i, 2, 1000)\n\t{\n\t\tfinc(j, 2, i)\n\t\t\tC[i][j] = (C[i - 1][j] + C[i - 1][j - 1]) % mod;\n\t}\n\tA[0] = 1, A[1] = 1;\n\tfinc(i, 2, 1000)\n\t\tA[i] = (A[i - 1] * i) % mod;\n\n\tint32 n, x, index;\n\tin(n, 32); in(x, 32); in(index, 32);\n\n\tint32 totalup = n - x, totaldown = x - 1;\n\tint32 cup = 0, cdown = 0;\n\tint32 l = 0, r = n - 1;\n\twhile (l<r)\n\t{\n\t\tint32 mid = (l + r) / 2;\n\t\tif (mid <= index)\n\t\t{\n\t\t\tcup++;\n\t\t\tl = mid + 1;\n\t\t\tcontinue;\n\t\t}\n\t\tif (mid > index)\n\t\t{\n\t\t\tcdown++;\n\t\t\tr = mid;\n\t\t}\n\t}\n\tint64 a = (C[totaldown][cdown] * A[cdown]) % mod;\n\tint64 b = (C[totalup][cup] * A[cup]) % mod;\n\tint64 ans = (((a * b) % mod) * A[n - 1 - cup - cdown]) % mod;\n\tout(ans, 64, end);\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4f1070db2f99bd47e8b8a4c59d620e53", "src_uid": "24e2f10463f440affccc2755f4462d8a", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#define _CRT_SECURE_NO_WARNINGS\n\n#include <stdio.h>\n#include <inttypes.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n\ntypedef uint64_t uint64; typedef uint32_t uint32;\ntypedef int64_t int64; typedef int32_t int32;\n\n#define finc(i,a,b) for(int32 i=(a);i<=(b);i++)\n#define fdec(i,a,b) for(int32 i=(b)+1;i-->(a);)\n#define in(i,bits) scanf(\"%\"PRId##bits\"\",&i)\n#define uin(i,bits) scanf(\"%\"PRIu##bits\"\",&i)\n#define out(i,bits,c) printf(\"%\"PRId##bits\"%c\",i,c)\n#define uout(i,bits,c) printf(\"%\"PRIu##bits\"%c\",i,c)\n#define end '\\n'\n\n#define mod (int64)(1e9+7)\nint64 C[1001][1001], A[1001];\nint main(void)\n{\n\tC[0][0] = 1;\n\tfinc(i, 1, 1000)\n\t{\n\t\tC[i][0] = 1;\n\t\tC[i][1] = i;\n\t}\n\tfinc(i, 2, 1000)\n\t{\n\t\tfinc(j, 2, i)\n\t\t\tC[i][j] = (C[i - 1][j] + C[i - 1][j - 1]) % mod;\n\t}\n\tA[0] = 1, A[1] = 1;\n\tfinc(i, 2, 1000)\n\t\tA[i] = (A[i - 1] * i) % mod;\n\n\tint32 n, x, index;\n\tin(n, 32); in(x, 32); in(index, 32);\n\n\tint32 totalup = n - x, totaldown = x - 1;\n\tint32 cup = 0, cdown = 0;\n\tint32 l = 0, r = n;\n\twhile (l<r)\n\t{\n\t\tint32 mid = (l + r) / 2;\n\t\tif (mid <= index)\n\t\t{\n\t\t\tcup++;\n\t\t\tl = mid + 1;\n\t\t\tcontinue;\n\t\t}\n\t\tif (mid > index)\n\t\t{\n\t\t\tcdown++;\n\t\t\tr = mid;\n\t\t}\n\t}\n\tint64 a = (C[totaldown][cdown] * A[cdown]) % mod;\n\tint64 b = (C[totalup][cup] * A[cup]) % mod;\n\tint64 ans = (((a * b) % mod) * A[n - 1 - cup - cdown]) % mod;\n\tout(ans, 64, end);\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "614e438fc802f6de1ee0e37918956505", "src_uid": "24e2f10463f440affccc2755f4462d8a", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#define _CRT_SECURE_NO_WARNINGS\n\n#include <stdio.h>\n#include <inttypes.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n\ntypedef uint64_t uint64; typedef uint32_t uint32;\ntypedef int64_t int64; typedef int32_t int32;\n\n#define finc(i,a,b) for(int32 i=(a);i<=(b);i++)\n#define fdec(i,a,b) for(int32 i=(b)+1;i-->(a);)\n#define in(i,bits) scanf(\"%\"PRId##bits\"\",&i)\n#define uin(i,bits) scanf(\"%\"PRIu##bits\"\",&i)\n#define out(i,bits,c) printf(\"%\"PRId##bits\"%c\",i,c)\n#define uout(i,bits,c) printf(\"%\"PRIu##bits\"%c\",i,c)\n#define end '\\n'\n\n#define mod (int64)(1e9+7)\nint64 C[1001][1001], A[1001];\nint main(void)\n{\n\tC[0][0] = 1;\n\tfinc(i, 1, 1000)\n\t{\n\t\tC[i][0] = 1;\n\t\tC[i][1] = i;\n\t}\n\tfinc(i, 2, 1000)\n\t{\n\t\tfinc(j, 2, i)\n\t\t\tC[i][j] = (C[i - 1][j] + C[i - 1][j - 1]) % mod;\n\t}\n\tA[0] = 1, A[1] = 1;\n\tfinc(i, 2, 1000)\n\t\tA[i] = (A[i - 1] * i) % mod;\n\n\tint32 n, x, index;\n\tin(n, 32); in(x, 32); in(index, 32);\n\n\tint32 totalup = n - x, totaldown = x - 1;\n\tint32 cup = 0, cdown = 0;\n\tint32 left = 0, right = n - 1;\n\twhile (left != right)\n\t{\n\t\tint32 mid = (left + right) / 2;\n\t\tif (mid < index)\n\t\t{\n\t\t\tleft = mid + 1;\n\t\t\tcdown++;\n\t\t\tcontinue;\n\t\t}\n\t\tif (mid > index)\n\t\t{\n\t\t\tright = mid;\n\t\t\tcup++;\n\t\t\tcontinue;\n\t\t}\n\t\tbreak;\n\t}\n\tint64 a = (C[totaldown][cdown] * A[cdown]) % mod;\n\tint64 b = (C[totalup][cup] * A[cup]) % mod;\n\tint64 ans = (((a * b) % mod) * A[n - 1 - cup - cdown]) % mod;\n\tout(ans, 64, end);\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "89eacc4b13f4269c81b5357b949f5afe", "src_uid": "24e2f10463f440affccc2755f4462d8a", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "# include <stdio.h>\n# include <stdlib.h>\n# include <math.h>\n# include <string.h>\n\nint main ()\n{ \t\n\tlong long n,x,pos;\n\tconst long long mod=1e9+7;\n\tscanf(\"%d %d %d\",&n,&x,&pos);\n    long long  l=0,r=n;\n    long long min=x-1,max=n-x;\n    long long mid;\n    long long num=1;\n    while (l<r)\n    {\n        mid=(l+r)/2;\n        if(mid<pos)\n        {\n            l=mid+1;\n            num=num*min%mod;\n            min--;\n        }\n        else if(mid==pos)\n\t\t\tl=mid+1;\n        else \n        {\n            r=mid;\n            num=num*max%mod;\n            max--;\n        }\n    }\n    for(long long i=1;i<=max+min;i++)\n    {\n        num=num*i%mod;\n    }\n    printf(\"%d\",num);\n} ", "lang_cluster": "C", "compilation_error": false, "code_uid": "f18de1fd5de644742625582694a230cc", "src_uid": "24e2f10463f440affccc2755f4462d8a", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include \"stdio.h\"\nstruct pos{\n\tlong int x;\n\tlong int y;\n};\n\nint main(){\n\tunsigned long long step;\n\tscanf(\"%llu\",&step);\n\tstruct pos mpos = {0,0};\n\tif(!(step%6)){\n\t\t/*printf(\"0 0\");\n\t\treturn 0;*/\n\t\tmpos.x = -2;\n\t}\n\tunsigned long long pi = 0;\n\tunsigned long long st = 1;\n\twhile ((step) >= pi){\n\t\tstep -= pi;\n\t\tpi+=6;\n\t\tmpos.x+=2;\n\t\tst++;\n\t\t//printf(\"%llu %llu\\n\", pi, step);\n\t}\n\t//printf(\"%llu %llu %llu\\n\", pi, step, st);\n\t//printf(\"*) %ld %ld \\n\", mpos.x, mpos.y);\n\t//printf(\"%s\\n\", \"yes\");\n\tunsigned long int rad = mpos.x;\n\t/*while(step > 0){\n\t\tstep--;\n\n\t\tif( (mpos.x > 0) && (mpos.y >= 0) ){\n\t\t\tmpos.x -=1;\n\t\t\tmpos.y +=2;\n\t\t\tcontinue;\n\t\t}\n\t\tif( (mpos.x < 0) && (mpos.y >= 0) ){\n\t\t\tmpos.x -=1;\n\t\t\tmpos.y -=2;\n\t\t\tcontinue;\n\t\t}\n\t\tif( (mpos.x > 0) && (mpos.y < 0) ){\n\t\t\tmpos.x +=1;\n\t\t\tmpos.y +=2;\n\t\t\tcontinue;\n\t\t}\n\t\tif( (mpos.x < 0) && (mpos.y < 0) ){\n\t\t\tmpos.x +=1;\n\t\t\tmpos.y -=2;\n\t\t\tcontinue;\n\t\t}\n\t}*/\n\tst --;\n\tfor(int i = 0; (i < st)&&(step); i++, step--){\n\t\tmpos.x -=1;\n\t\tmpos.y +=2;\n\t}\n\t//printf(\"1) %ld %ld \\n\", mpos.x, mpos.y);\n\tfor(int i = 0; (i<st)&&(step); i++, step--){\n\t\tmpos.x -=2;\n\t}\n\t//printf(\"2) %ld %ld \\n\", mpos.x, mpos.y);\n\tfor(int i = 0; (i<st)&&(step); i++, step--){\n\t\tmpos.x -=1;\n\t\tmpos.y -=2;\n\t}\n\t//printf(\"3) %ld %ld \\n\", mpos.x, mpos.y);\n\tfor(int i = 0; (i<st)&&(step); i++, step--){\n\t\tmpos.x +=1;\n\t\tmpos.y -=2;\n\t}\n\t//printf(\"4) %ld %ld \\n\", mpos.x, mpos.y);\n\tfor(int i = 0; (i<st)&&(step); i++, step--){\n\t\tmpos.x +=2;\n\t}\n\t//printf(\"6) %ld %ld \\n\", mpos.x, mpos.y);\n\tfor(int i = 0; (i<st)&&(step); i++, step--){\n\t\tmpos.x +=1;\n\t\tmpos.y +=2;\n\t}\n\tprintf(\"%ld %ld\", mpos.x, mpos.y);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a70f73e000e780be5bbeb67cd1a9a6f8", "src_uid": "a4b6a570f5e63462b68447713924b465", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <math.h>\n#include <stdio.h>\n\nlong long min(long long a, long long b) { return a < b ? a : b; }\n\nint main() {\n\tlong long n, m, k, x, y;\n\n\tscanf(\"%lld\", &n);\n\t/* 6 * k * (k + 1) / 2 = 3 * k * (k + 1); */\n\tk = sqrt(n / 3.0);\n\twhile (3LL * (k + 1) * (k + 2) <= n)\n\t\tk++;\n\twhile (3LL * k * (k + 1) > n)\n\t\tk--;\n\tn -= 3 * k * (k + 1);\n\tx = k * 2, y = 0;\n\tk++;\n\tm = min(n, 1);\n\tn -= m, x += m, y += m * 2;\n\tm = min(n, k - 1);\n\tn -= m, x -= m, y += m * 2;\n\tm = min(n, k);\n\tn -= m, x -= m * 2;\n\tm = min(n, k);\n\tn -= m, x -= m, y -= m * 2;\n\tm = min(n, k);\n\tn -= m, x += m, y -= m * 2;\n\tm = min(n, k);\n\tn -= m, x += m * 2;\n\tm = min(n, k);\n\tn -= m, x += m, y += m * 2;\n\tprintf(\"%lld %lld\\n\", x, y);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "689e6d94aac510f3770052ce98605fcd", "src_uid": "a4b6a570f5e63462b68447713924b465", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include \"stdio.h\"\nstruct pos{\n\tlong int x;\n\tlong int y;\n};\n\nunsigned long long s_n(unsigned long long n){\n\treturn 3*n*(n-1);\n}\n\nint main(){\n\tunsigned long long step;\n\tscanf(\"%llu\",&step);\n\n\tstruct pos mpos = {0,0};\n\t/*if(!(step%6)){\n\t\tmpos.x = -2;\n\t}*/\n\tunsigned long long b = 0;\n\tunsigned long long en = 64;\n\tunsigned long long piv = 0;\n\tunsigned long long st = 1;\n\twhile(s_n(en) < step){\n\t\tb = en;\n\t\ten = en*2;\n\t}\n\n\twhile((en-b)>1){\n\t\tpiv = b + (en-b)/2;\n\t\t//printf(\"%llu %llu %llu %llu %llu \\n\", b, piv, en, s_n(piv), step);\n\t\tif (s_n(piv)>step){\n\t\t\ten = piv;\n\t\t} else {\n\t\t\tb = piv;\n\t\t}\n\t}\n\n\t/*if(!(step%6)){\n\t\tmpos.x = -2;\n\t}\n\t\n\tunsigned long long pi = 0;\n\t//unsigned long long st = 1;\n\t\n\twhile ((step) >= pi){\n\t\tstep -= pi;\n\t\tpi+=6;\n\t\tst++;\n\t}\n\t/*if(st == en){\n\t\tprintf(\"%llu oK\\n\",st);\n\t} else {\n\t\tprintf(\"%llu nOk\\n\", st);\n\t}*/\n\tst = en;\n\tstep-= s_n(st-1);\n\tif(step == 0){\n\t\tmpos.x = -2;\n\t}\n\tmpos.x += (st-1)*2;\n\tst --;\n\tif(step>st){\n\t\tmpos.x -=st;\n\t\tmpos.y +=2*st;\n\t\tstep -= st;\n\t} else {\n\t\tmpos.x -=step;\n\t\tmpos.y +=2*step;\n\t\tstep = 0;\n\t}\n\n\tif(step>st){\n\t\tmpos.x -=2*st;\n\t\tstep -= st;\n\t} else {\n\t\tmpos.x -=2*step;\n\t\tstep = 0;\n\t}\n\n\tif(step>st){\n\t\tmpos.x -=st;\n\t\tmpos.y -=2*st;\n\t\tstep -= st;\n\t} else {\n\t\tmpos.x -=step;\n\t\tmpos.y -=2*step;\n\t\tstep = 0;\n\t}\n\n\tif(step>st){\n\t\tmpos.x +=st;\n\t\tmpos.y -=2*st;\n\t\tstep -= st;\n\t} else {\n\t\tmpos.x +=step;\n\t\tmpos.y -=2*step;\n\t\tstep = 0;\n\t}\n\n\tif(step>st){\n\t\tmpos.x +=2*st;\n\t\tstep -= st;\n\t} else {\n\t\tmpos.x +=2*step;\n\t\tstep = 0;\n\t}\n\n\tif(step>st){\n\t\tmpos.x +=st;\n\t\tmpos.y +=2*st;\n\t\tstep -= st;\n\t} else {\n\t\tmpos.x +=step;\n\t\tmpos.y +=2*step;\n\t\tstep = 0;\n\t}\n\n\tprintf(\"%ld %ld\", mpos.x, mpos.y);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9ceb4b85e282e411c17cb838519a66cf", "src_uid": "a4b6a570f5e63462b68447713924b465", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint dir[6][2]={{-1,2},{-2,0},{-1,-2},{1,-2},{2,0},{1,2}};\nint main()\n{\n    long long  n,i;\n    scanf(\"%lld\",&n);\n    double x,y;\n    double a;\n    if(!n)\n        printf(\"0 0\\n\");\n    else\n    {   \n    long long a=sqrt(n/3);\n    for(;;++a)\n    {\n        if(a*(a+1)/2*6==n)\n        {\n            printf(\"%d %d\\n\",a*2,0);\n            return 0;\n        }\n        if(a*(a+1)/2*6>n)\n        {\n            break;\n        }\n    }\n        n-=(a*(a-1))*3;\n        if(n==0)\n            printf(\"%.0lld 0\\n\",2*(a-1));\n        else{\n        \n        x=2*(a-1);y=0;          //\u7b2ca\u5708\u7684\u8d77\u70b9 \n        i=0;             //i\u8bb0\u5f55\u79fb\u52a8\u51e0\u6b21 \n        x+=1;y+=2;i++;      \n\n        if(i==n)\n        {\n            printf(\"%.lf %.lf\\n\",x,y);\n            return 0;\n        }\n        n--;\n        for(int k=0;k<6;++k)\n        {\n            long long t=(k<=0?a-1:a);\n            if(n>=t)\n            {\n                x+=t*dir[k][0];\n                y+=t*dir[k][1];\n                n-=t;\n            }\n            else\n            {\n                x+=n*dir[k][0];\n                y+=n*dir[k][1];\n                break;\n            }\n        }   \n        printf(\"%.lf %.lf\\n\",x,y);\n    }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9055f492c08c3ea676b95fe6fdae6546", "src_uid": "a4b6a570f5e63462b68447713924b465", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\t\nlong long n;\nlong long bisearch()\n{\n    long long l=0,r=1e9,mid;\n    while(l<=r)\n    {\n        mid=((l+r)>>1);\n        if(3*mid*(mid+1)>n)r=mid-1;\n        else l=mid+1;\n    }\n    return l;\n}\nint main()\n{\n\n\twhile(~scanf(\"%lld\",&n))\n\t{\n\t\tlong long p,q;\n\t\tif(n==0)\n\t\t{\n\t\t\tprintf(\"0 0\\n\");\n\t\t\tbreak;\n\t\t}\n\t\tlong long i=bisearch();\n//\t\tprintf(\"%lld\\n\",bisearch());\n//\t\tfor(long long i=1;;i++)\n//\t\t{\n//\t\t\tif(n>=i*6)\n//\t\t\t{\n//\t\t\t\tn-=i*6;\n//\t\t\t\tcontinue;\n//\t\t\t}\n//\t\t\telse\n//\t\t\t{\t\t\t\n//\t\t\t\tprintf(\"i==%d,n==%d,nMODi=%d\\n\",i,n,n/i);\n\t\t\t\tn-=3*(i-1)*i;\n\t\t\t\tif(n==0)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%lld 0\\n\",2*(i-1));\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\telse if(n<i)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%lld %lld\\n\",1+2*(i-1)-(n-1),2+2*(n-1));\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\telse if(n==i)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%lld %lld\\n\",1*i,2*i);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\telse if(n>i && n<2*i)\n\t\t\t\t{\n\t\t\t\t\tn-=i;\n\t\t\t\t\tprintf(\"%lld %lld\\n\",1*i-2*n,2*i);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\telse if(n==2*i)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%lld %lld\\n\",-1*i,2*i);\n\t\t\t\t\tbreak;\n\t\t\t\t}\t\n\t\t\t\telse if(n>2*i && n<3*i)\n\t\t\t\t{\n\t\t\t\t\tn-=2*i;\n\t\t\t\t\tprintf(\"%lld %lld\\n\",-1*i-n,2*i-2*n);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\telse if(n==3*i)\t\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%lld 0\\n\",-2*i);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\telse if(n>3*i && n<4*i)\n\t\t\t\t{\n\t\t\t\t\tn-=3*i;\n\t\t\t\t\tprintf(\"%lld %lld\\n\",-2*i+n,0-2*n);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\telse if(n==4*i)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%lld %lld\\n\",-1*i,-2*i);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\telse if(n>4*i && n<5*i)\n\t\t\t\t{\n\t\t\t\t\tn-=4*i;\n\t\t\t\t\tprintf(\"%lld %lld\\n\",-1*i+2*n,-2*i);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\telse if(n==5*i)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%lld %lld\\n\",1*i,-2*i);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\telse if(n>5*i)\n\t\t\t\t{\n\t\t\t\t\tn-=5*i;\n\t\t\t\t\tprintf(\"%lld %lld\\n\",1*i+n,-2*i+2*n);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n//\t\t\t}\n//\t\t}\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3720bdfd233528bde0a42cf5536e630c", "src_uid": "a4b6a570f5e63462b68447713924b465", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    long int k,p;\n    scanf(\"%d %d\",&k,&p);\n    int d[]={11,22,33,44,55,66,77,88,99,1001,1111,1221,1331,1441,1551,1661,1771,1881,1991,2002,2112,2222,2332,2442,2552,2662,2772,2882,2992,3003,3113,3223,3333,3443,3553,3663,3773,3883,3993,4004,4114,4224,4334,4444,4554,4664,4774,4884,4994,5005,5115,5225,5335,5445,5555,5665,5775,5885,5995,6006,6116,6226,6336,6446,6556,6666,6776,6886,6996,7007,7117,7227,7337,7447,7557,7667,7777,7887,7997,8008,8118,8228,8338,8448,8558,8668,8778,8888,8998,9009,9119,9229,9339,9449,9559,9669,9779,9889,9999};\n    long int i,a=0;\n    for(i=0;i<k;i++)\n    {\n        a=a+d[i];\n    }\n    long int d=a%p;\n    printf(\"%ld\\n\"d);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0824b0b9211964b46d83913b07bade8d", "src_uid": "00e90909a77ce9e22bb7cbf1285b0609", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\nusing namespace std;\nlong long calc(long long x) {\n    long long ans = x;\n    while (x) {\n        ans = ans * 10 + x % 10;\n        x /= 10;\n    }\n    return ans;\n}\nint main() {\n    long long k, p, res = 0;\n    cin >> k >> p;\n    for (long long i = 1; i <= k; ++i) res = (res + calc(i)) % p;\n    cout << res << endl;\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "32a51315793ccbb00798fa7280a8d17a", "src_uid": "00e90909a77ce9e22bb7cbf1285b0609", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define INF 100005\nint a[INF];\nint main()\n{\n    int k,p;\n    while(scanf(\"%d %d\",&k,&p)!=EOF)\n    {\n     int i=11,j=1,t,l,count=0,mark=0;\n    int sum=0;\n    for(i=11;count!=k;i++)\n    {\n        t=i;mark=0;\n        for(j=1;t!=0;j++)\n        {\n            a[j]=t%10;\n            t=t/10;\n        }\n        l=j-1;\n        for(j=1;j<l/2;j++)\n        {\n            if(a[j]!=a[l-j+1])\n               {\n                mark=1;\n                break;\n               }\n        }\n        if(l==2&&a[1]==a[2])\n        {\n            count++; sum+=(i%p);\n        }\n        else if(l!=2&&l%2==0&&mark==0&&a[l/2]==a[l/2+1])\n            {\n            count++;a\n            sum+=(i%p);\n            }\n        else if(l!=2&&mark==0){sum+=(i%p); count++;}\n\n    }\n    printf(\"%d\\n\",sum%p);\n\n\n\n\n    }\n\n\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "411cee2e8107a461faf3e40eae813bd2", "src_uid": "00e90909a77ce9e22bb7cbf1285b0609", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint palindrome(char *text) \n{\n    for(char *right = text + strlen(text) - 1; text < right; text++, right--) \n    {\n        if(*text != *right) \n        {\n            return 0;\n        }\n    }\n    return 1;\n}\n\nint main() {\n    int i=10;\n    int k,x,p;\n    char c[1000];\n    \n scanf(\"%d%d\",&k,&p);\n while(k>0)\n {\n     Int m=(int) (floor (log10 (abs (i))) + 1);\n     if (m%2==0)\n     {\n         sprintf(c,\"%d\",i);\n         if (palindrome(c))\n         {\n             s=s+i;\n             i++;}\n     else if(m%2!=0)\n        {\n            i=i*10;\n        }\n         }\n         k--;\n     }\n     s=s%p;\n printf(\"%d\",s);\n    \n    \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e8319ed71dc08b82df394b2e42324b5a", "src_uid": "00e90909a77ce9e22bb7cbf1285b0609", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint num[100005]={0},i=0,\nlong long sum=0;\nint main()\n{\n\tfor (i = 11; i < 100002; ++i)\n\t{\n\t\tint count=0;\n\t\tint temp=i;\n\t\tint rev=0,rem;\n\t\twhile (temp!=0)\n\t\t{\n\t\t\trem=temp%10;\n\t\t\trev=rev*10+rem;\n\t\t\ttemp/=10;\n\t\t\tcount++;\n\t\t}\n\t\tif (rev==i && count%2==0)\n\t\t{\n\t\t\tnum[i]=1;\n\t\t\t//printf(\"%d\\n\",i);\n\t\t}\n\t}\n\tlong long int k,p,count1=0;\n\tscanf(\"%lld %lld\",&k,&p);\n\tfor (i = 1; i <= 100000 && count1<k; i++)\n\t{\n\t\tif (num[i]==1)\n\t\t{\n\t\t\tsum=(sum+i)%p;\n\t\t\t//printf(\"%d\\n\",i);\n\t\t\tcount1++;\n\t\t}\n\t}\n\tprintf(\"%lld\\n\",sum);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "999f26858a65a7d9439393451ecbc90b", "src_uid": "00e90909a77ce9e22bb7cbf1285b0609", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int x1,y1,x2,y2,x3,y3;\n    scanf(\"%d %d %d %d %d %d\",&x1,&y1,&x2,&y2,&x3,&y3);\n    printf(\"3\");\n    printf(\"%d %d\",x1+x2-x3,y1+y2-y3);\n    printf(\"%d %d\",x1+x3-x2,y1+y3-y2);\n    printf(\"%d %d\",x3+x2-x1,y3+y2-y1);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "382e21faff630676d22df15524ea3c10", "src_uid": "7725f9906a1b87bf4e866df03112f1e0", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main(void)\n{\nint x[3],y[3];\nint a[3],b[3];\nint i;\nfor(i=0;i<3;i++)\nscanf(\"%d%d\",&x[i],&y[i]);\na[0]=x[0]-(x[1]-x[2]);\nb[0]=y[0]-(y[1]-y[2]);\na[1]=x[0]+(x[1]-x[2]);\nb[1]=y[0]+(y[1]-y[2]);\na[2]=x[2]-(x[0]-x[1]);\nb[2]=y[2]+(y[0]-y[1]);\nprintf(\"%d\\n\",3);\nfor(i=0;i<3;i++)\nprintf(\"%d %d\\n\",a[i],b[i]);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e24aa21997d1bcb7082360fb3242df2c", "src_uid": "7725f9906a1b87bf4e866df03112f1e0", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nstruct point {\n    int x;\n    int y;\n};\nstruct point point_subtract(struct point a, struct point b) {\n    struct point res;\n    res.x = a.x - b.x;\n    res.y = a.y - b.y;\n}\nstruct point point_add(struct point a, struct point b) {\n    res.x = a.x + b.x;\n    res.y = a.y + b.y;\n}\nvoid print_point(struct point a) {\n    printf(\"%d %d\", a.x, a.y);\n}\nint main(void) {\n    struct point a, b, c;\n    struct point d[3];\n    scanf(\"%d %d\\n%d %d\\n%d %d\", &a.x, &a.y, &b.x, &b.y, &c.x, &c.y);\n    d[0] = point_add(point_subtract(a, c), b);\n    d[1] = point_add(point_subtract(b, a), c);\n    d[2] = point_add(point_subtract(a, b), c);\n    printf(\"3\");\n    for(int i = 0; i < 3; i++) {\n        printf(\"\\n\");\n        print_point(d[i]);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f8004dce510bbc06df4164d6e2960488", "src_uid": "7725f9906a1b87bf4e866df03112f1e0", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n\nint main (){\n    inti;\n   int x[3],y[3];\n    for(i=0;i<3;i++)\n        scanf(\"%d%d\",&x[i],&y[i]);\n    printf(\"3\\n\");\n    printf(\"%d \",x[0]+x[1]-x[2]);\n    printf(\"%d\\n\",y[0]+y[1]-y[2]);\n    printf(\"%d \",x[0]-x[1]+x[2]);\n    printf(\"%d\\n\",y[0]-y[1]+y[2]);\n    printf(\"%d \",x[2]+x[1]-x[0]);\n    printf(\"%d\\n\",y[2]+y[1]-y[0]);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c1014489be044b2778ee1c2b8175739a", "src_uid": "7725f9906a1b87bf4e866df03112f1e0", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n\nvoid main()\n{\n    int x1,y1,x2,y2,x3,y3 ;\n    printf(\"1 \");\n    scanf(\"%d %d\",&x1,&y1);\n    do\n    {\n        printf(\"2 \");\n    scanf(\"%d %d\",&x2,&y2);\n    }while(((x2==x1)&&(y2==y1)));\n    int m=(y2-y1)/(x2-x1);\n    int p=y1-x1*m;\n\n    do\n    {\n        printf(\"3 \");\n        scanf(\"%d %d\",&x3,&y3);\n    }while(((x3==x1)&&(y3==y1))||((x2==x3)&&(y2==y3))||(y3==m*x3+p));\nint x4,y4,k;\nk=3;\nprintf(\"%d\\n\",k);\nint dx,dy;\ndx=x3-x2;\ndy=y3-y2;\ny4=y1+dy;\nx4=x1+dx;\nprintf(\"%d %d\\n\",x4,y4);\ndx=x2-x1;\ndy=y2-y1;\ny4=y3+dy;\nx4=x3+dx;\nprintf(\"%d %d\\n\",x4,y4);\ndx=x1-x3;\ndy=y1-y3;\ny4=y2+dy;\nx4=x2+dx;\nprintf(\"%d %d\",x4,y4);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ad5dcf1f45d004723f3626eb72dae733", "src_uid": "7725f9906a1b87bf4e866df03112f1e0", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <algorithm>\n#include <cstdio>\n#include <cstring>\n#include <string>\n#include <cctype>\n#include <stack>\n#include <queue>\n#include <list>\n#include <vector>\n#include <map>\n#include <sstream>\n#include <cmath>\n#include <bitset>\n#include <utility>\n#include <set>\n#include <numeric>\n#include <ctime>\n#include <iostream>\nusing namespace std;\n\nint main()\n{\n    int arr[100];\n    int n,m,d;\n\n    scanf(\"%d %d\",&n,&d);\n\n    for(int i = 0 ; i < n; i++)\n        scanf(\"%d\",&arr[i]);\n\n    scanf(\"%d\",&m);\n\n    sort(arr, arr+n);\n\n    int result = 0;\n    for (int i = 0; i < min(n, m); i++)\n        result += arr[i];\n\n    if (m > n)\n        result -= (m-n)*d;\n\n    printf(\"%d\\n\",result);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "854191e1b2a72bda0b1d62b5780f23c4", "src_uid": "5c21e2dd658825580522af525142397d", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nvoid sorting(int *costs, int num)\n{\n    int i,j;\n    for(i=0;i<num;i++) {\n        for(j=0;j<num;j++) {\n            if(costs[i]<costs[j]){\n                int temp = costs[i];\n                costs[i] = costs[j];\n                costs[j] = temp;\n            }\n}\n\nint main(void)\n{\n    int hook,refund,guest;\n    int *costs;\n    int total=0,i;\n    /* input */\n    scanf(\"%d%d\",&hook,&refund);\n    costs=(int *)malloc(sizeof(int)*hook);\n    for(i=0;i<hook;i++)\n        scanf(\"%d\",&costs[i]);\n    scanf(\"%d\",&guest);\n    sorting(costs,hook);\n    /* calc */\n    if(hook >= guest){\n        for(i=0;i<guest;i++)\n            total+=costs[i];\n    }else{\n        for(i=0; i<hook; i++)\n            total+=costs[i];\n        total-=(guest-hook)*refund;\n    }\n    printf(\"%d\\n\",total);\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9fa32d8b381006098bc46a9aed92cb65", "src_uid": "5c21e2dd658825580522af525142397d", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "include<stdio.h>\n#include<stdlib.h>\n\nint cmpfunc(const void* a,const void* b){\n\nreturn ( *(int*)a- *(int*)b );\n}\nint main(){\nint n,d,a[100],m,profit,sum,i;\nscanf(\"%d %d\",&n,&d);\nfor(i=0;i<n;i++)\nscanf(\"%d\",&a[i]);\nscanf(\"%d\",&m);\nqsort(a,n,sizeof(int),cmpfunc);\n\nif(m<=n){\nsum=0;\nfor(i=0;i<m;i++)\nsum+=a[i];\n//profit=sum-(m-n)*d;\nprintf(\"%d\",sum);\n}\n\nif(m>n) {\nsum=0;\nfor(i=0;i<n;i++)\nsum+=a[i];\nprofit=sum-(m-n)*d;\nprintf(\"%d\",profit);\n}\n\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "06ffe07544c86b54449a1a796aeb9ae9", "src_uid": "5c21e2dd658825580522af525142397d", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n,d;\n    scanf(\"%d%d\",&n,&d);\n    int a[n],i,sum=0;\n    for(i=0;i<n;i++)\n        scanf(\"%d\",&a[i]),sum+=a[i];\n    int m;\n    scanf(\"%d\",&m);\n    if(m>=n)\n    printf(\"%d\",sum-(m-n)*d);\n    else\n    {\n        sum=0\n        for(i=0;i<m;i++)\n            sum+=a[i];\n        printf(\"%d\",sum);\n    }\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0469487c8ced2601b233c9fdecadca76", "src_uid": "5c21e2dd658825580522af525142397d", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main (){\n\n\n    int n,d,m;\n    int i;\n\n\n        scanf (\"%i %i\", &n, &d);\n\n\n    int g[110];\n    for (i=0;i<n;i++){\n        scanf (\"%i\",&g[i]);\n    }\n    scanf(\"%i\", &m);\n\n\n    // sorting\n    for (i=0;i<n;i++){\n        int j, mindex =i;\n        for (j=i;j<n;j++){\n            if(g[j]<g[mindex])\n                mindex= j;\n        }\n\n        int temp = g[i];\n        g[i] = g[mindex];\n        g[mindex] = temp;\n    }\n\n\n    int p=0; // pribyl\n    i=0;\n    while (i<m){\n        if (i > n){\n            p = p - g[i];\n        }\n        else {\n            p = p + g[i];\n        }\n    }\n\n    printf (\"%i\", p);\n\n\n\n\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "669627dff7e7b0176f6485643328f13a", "src_uid": "5c21e2dd658825580522af525142397d", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nchar s[101];\nint k, n, i, j, x, ok[30];\n\nvoid read(){\n\tscanf(\"%d%s\", &k, s);\n}\n\nint process(){\n\tn = strlen(s);\n\tx=n/2;\n\tfor(i=0, j=n-1;i<=x;i++, j--){\n\t\tif(s[i]=='?' && s[j]!='?')s[i]=s[j];\n\t\telse if(s[j]=='?' && s[i]!='?')s[j]=s[i];\n\t\telse if(s[j] != s[i])return 0;\n\n\t\tok[s[i]-'a']=1;\n\t\tok[s[j]-'a']=1;\n\t}\n\tx+=n%2;--x;\n\tfor(i=k-1;x>=0&&i>=0;x--){\n\n\t\tif(s[x]=='?'){\n\t\t\twhile(i>0&&ok[i])--i;\n\t\t\ts[x]=s[n-x-1]='a'+i;\n\t\t\tok[s[x]-'a']=1;\n\t\t}\n\t}\n\tfor(i=0;i<k;i++)if(!ok[i])return 0;\n\treturn 1;\n}\n\nint main (){\n\tread();\n\tif(process()) printf(\"%s\", s);\n\telse printf(\"IMPOSSIBLE\");\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "951813ae7436226641c0ae05e9e65a90", "src_uid": "9d1dd9d722e5fe46823224334b3b208a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{int i,j=0,n,l,t,b[26]={0},c[26]={0};char a[105]={'\\0'};\nscanf(\"%d\",&n);\nscanf(\"%s\",a);\nt=strlen(a);\n\nfor(i=0;i<t;i++)\n{if(a[i]=='?')\n{if(a[t-1-i]=='?')\nj++;}\nelse\n{\n    b[a[i]-97]++;\n}}\nl=0;j=(j+1)/2;\nfor(i=0;i<n;i++)\nif(b[i]==0)\nc[l++]=i;j=j-l;\nl=0;\nif(j>=0)\nfor(i=0;i<(t+1)/2;i++)\n{if(a[i]==a[t-1-i]&&a[i]=='?')\n{if(j>0)\n{\n    a[i]='a';a[t-1-i]='a';j--;\n}\nelse\n{a[i]=c[l++]+97;a[t-1-i]=a[i];\n}}\nelse if(a[i]!=a[t-i-1])\n{\n    if(a[i]=='?'||a[t-1-i]=='?')\n    {if(a[i]=='?')\n    a[i]=a[t-1-i];\n    else\n    {a[t-1-i]=a[i];}\n\n    }\n    else\n    {V:\n        printf(\"IMPOSSIBLE\");\n        goto flag;\n    }\n}\n}else\ngoto V;\nprintf(\"%s\",a);\nflag:\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "15eb9591f0571d88ec17d30ebcbc79cb", "src_uid": "9d1dd9d722e5fe46823224334b3b208a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\n\nvoid fun(char *str,int save,int flag[26],int k)\n{\n      int counta = 0,p = 0,i,j;\n      \n      i = 0,j = strlen(str)-1;\n      \n      while(i<=j)\n        {\n          if(str[i]=='?' && str[j]=='?')\n             {\n                if(counta < save)\n                   {\n                      str[i] = 'a' , str[j] = 'a';\n                \n                      if(i==j)\n                         counta++;\n                         \n                      else\n                         counta += 2;\n                                \n                   }\n             \n                else\n                   {\n                      for(;p<k;p++)\n                         {\n                           if(!flag[p])\n                              {\n                                 flag[p] = 1;\n                                 break;  \n                              } \n                               \n                         }\n                         \n                      str[i] = p+97 , str[j] = p+97;\n                   \n                   }\n                \n             }\n             \n             i++,j--;\n               \n        }\n        \n     return ;   \n}\n\n\n\nint main()\n{\n   char str[101];\n   int flag[26] = {0},i,j,n,p,k;\n   int qmarks = 0,rem = 0,fill;        //number of qmarks and number of remaining letters after 2nd step\n   \n   scanf(\"%d %s\",&k,str);\n\n   //check for palindrome\n   \n   n = strlen(str);\n   \n   i = 0,j = n-1;\n   \n   while(i<=j)\n     {\n        if(str[i]=='?' || str[j]=='?')\n           {\n              i++,j--;   \n           }\n           \n           \n        else if(str[i]==str[j])\n           {\n                i++,j--;\n           }\n           \n        else\n             break;\n             \n     }\n     \n   if(i<=j)\n     {\n       printf(\"IMPOSSIBLE\");\n       return 0;\n     }\n\n  //fill as per palindrome\n  \n  i = 0,j = n-1;\n  \n  while(i<=j)\n     {\n        if(str[i]=='?' || str[j]=='?')\n          {\n            if(str[i]=='?')\n               str[i] = str[j];\n               \n            else\n               str[j] = str[i];\n                 \n          }\n          \n        i++,j--;\n        \n     }  \n     \n  //check number of qmarks and remaining\n  i = 0;\n  \n  while(str[i])\n     {\n       if(str[i]=='?')\n            qmarks++;\n          \n       else if(!flag[str[i]-97])\n               flag[str[i]-97] = 1;\n             \n         i++;\n         \n     }\n\n  for(i=0;i<k;i++)\n     {\n        if(!flag[i])\n           rem++;\n     }\n     \n  if(!qmarks && !rem)\n   {\n     printf(\"%s\",str);\n     return 0;   \n   }\n   \n  else if(!qmarks)\n   { \n     printf(\"IMPOSSIBLE\");\n     return 0;\n\n   }\n   \n   \n  else\n      {\n        if(!(qmarks%2))\n           {\n             if(qmarks < 2*rem)\n               { \n                 printf(\"IMPOSSIBLE\");\n                 return 0;\n               }\n               \n             else\n                {\n                  if(!rem)\n                      fill = 0;\n                      \n                   else\n                      fill = 2*rem;\n                      \n                   fun(str,qmarks-fill,flag,k);  \n                \n                } \n                 \n           } \n             \n             \n        else\n           {\n             if(qmarks < 2*rem-1)\n                {\n                   printf(\"IMPOSSIBLE\");\n                   return 0;\n                }  \n                \n             else\n                {\n                  if(!rem)\n                      fill = 0;\n                      \n                   else\n                      fill = 2*rem-1;\n                      \n                   fun(str,qmarks-fill,flag,k);\n                    \n                }\n                \n           }\n           \n      }\n \n  printf(\"%s\",str);\n  return 0;     \n      \n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "edbde4ae8af643c24fd36fa410888010", "src_uid": "9d1dd9d722e5fe46823224334b3b208a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main()\n{\n     int k, n, p = 0, q = 0, i, j;\n     char s1[101], s2[102];\n     int a[26] = {0};\n\n     scanf(\"%d\", &k);\n\n     scanf(\"%s\", s1);\n\n     n = strlen(s1);\n\n     for (i = 0; i < n; i++) {\n\t  s2[n - i - 1] = s1[i];\n     }\n\n     for (i = 0; i < (n + 1) / 2; i++) {\n\t  if (s1[i] == '?') {\n\t       if (s2[i] == '?') {\n\t\t    p++;\n\t       } else {\n\t\t    if (a[s2[i] - 'a']++ == 0) q++;\n\n\t\t    s1[i] = s2[i];\n\t       }\n\t  } else {\n\t       if (s2[i] == '?') {\n\t\t    if (a[s1[i] - 'a']++ == 0) q++;\n\n\t\t    s1[n - i - 1] = s1[i];\n\t       } else {\n\t\t    if (s1[i] == s2[i]) {\n\t\t\t if (a[s1[i] - 'a']++ == 0) q++;\n\t\t    } else {\n\t\t\t puts(\"IMPOSSIBLE\");\n\n\t\t\t return 0;\n\t\t    }\n\t       }\n\t  }\n     }\n\n     if (p + q < k) {\n\t  puts(\"IMPOSSIBLE\");\n\n\t  return 0;\n     }\n\n     for (i = 0; i < (n + 1) / 2; i++) {\n\t  if (s1[i] == '?') {\n\t       if (p + q > k) {\n\t\t    s1[i] = s1[n - i - 1] = 'a';\n\n\t\t    if (a[0]++ == 0) q++;\n\t       } else {\n\t\t    for (j = 0; j < 26; j++) {\n\t\t\t if (a[j] == 0) break;\n\t\t    }\n\n\t\t    s1[i] = s1[n - i - 1] = 'a' + j;\n\n\t\t    a[j]++;\n\n\t\t    q++;\n\t       }\n\n\t       p--;\n\t  }\n     }\n\n     printf(\"%s\\n\", s1);\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ed4796f6b9a8e18c36048c3be4001a42", "src_uid": "9d1dd9d722e5fe46823224334b3b208a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nchar s[101];\nint k, n, i, j, x;\nbool ok[30];\n\nvoid read(){\n\tscanf(\"%d%s\", &k, s);\n}\n\nint process(){\n\tn = strlen(s);\n\tx=n/2;\n\tfor(i=0, j=n-1;i<x;i++, j--){\n\t\tif(s[i]=='?' && s[j]!='?')s[i]=s[j];\n\t\telse if(s[j]=='?' && s[i]!='?')s[j]=s[i];\n\t\telse if(s[j] != s[i])return 0;\n\t\t\n\t\tok[s[i]-'a']=1;\n\t\tok[s[j]-'a']=1;\n\t}\n\tx+=n%2;--x;\n\tfor(i=k-1;x>=0&&i>=0;x--){\n\t\t\n\t\tif(s[x]=='?'){\n\t\t\twhile(i>0&&ok[i])--i;\n\t\t\ts[x]=s[n-x-1]='a'+i;\n\t\t\tok[s[x]-'a']=1;\n\t\t}\n\t}\n\tfor(i=0;i<k;i++)if(!ok[i])return 0;\n\treturn 1;\n}\n\nint main (){\n\t//freopen(\"in.txt\",\"r\",stdin);freopen(\"out.txt\",\"w\",stdout);\n\tread();\n\tif(process())printf(\"%s\", s);\n\telse printf(\"IMPOSSIBLE\");\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "64eeece7cc64e275ad0047d58c8eca8b", "src_uid": "9d1dd9d722e5fe46823224334b3b208a", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "/* Coached by Dukkha */\n#include <stdio.h>\n\nlong long triangle(int k, int x) {\n\tif (k > x)\n\t\tk = x;\n\treturn (long long) (x + x - k + 1) * k / 2;\n}\n\nint main() {\n\tint n, m, k, lower, upper;\n\n\tscanf(\"%d%d%d\", &n, &m, &k);\n\tm -= n;\n\tlower = 0, upper = m + 1;\n\twhile (upper - lower > 1) {\n\t\tint x = (lower + upper) / 2;\n\n\t\tif (triangle(k, x) + triangle(n - k, x - 1) <= m)\n\t\t\tlower = x;\n\t\telse\n\t\t\tupper = x;\n\t}\n\tprintf(\"%d\\n\", lower + 1);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1489381ae2f403699360f8e3e6f45dd3", "src_uid": "da9ddd00f46021e8ee9db4a8deed017c", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\ninline int min(int a,int b)\n {\n \treturn a<b?a:b;\n }\n inline int max(int a,int b)\n {\n \treturn a>b?a:b;\n }\n\nint main()\n{\n\tint N,M,K;\n\tscanf(\"%d%d%d\",&N,&M,&K);\n\tK--;\n\tM-=N;\n\tint off=1;\n\tint ans=1;\n\t// int v1,v2=0;\n\twhile(min(N,K+off)-max(0,K-off+1)<=M)\n\t{\n\t\tans++;\n\t\tM-=min(N,K+off)-max(0,K-off+1);\n\t\tif(max(0,K-off+1)==0 && min(N,K+off)==N)\n\t\t\tbreak;\n\t\toff++;\n\t}\n\tans+=M/N;\n\tprintf(\"%d\",ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "719717ae3677f619c8f7ab88ffe89d0b", "src_uid": "da9ddd00f46021e8ee9db4a8deed017c", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint n, m, k, res = 1, l = 1;\nint main() {\n  scanf(\"%d%d%d\", &n, &m, &k);\n  m -= n;\n  while(m > 0) {\n    if(k - res >= 1) ++l;\n    if(k + res <= n) ++l;\n    ++res; m -= l;\n  }\n  printf(\"%d\\n\", res);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "14bbb4f99d789bd863a33c931b563d45", "src_uid": "da9ddd00f46021e8ee9db4a8deed017c", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<iostream>\n#include<cstdio>\n#include<algorithm>\n#include<cstdlib>\n#include<cstring>\n#define LiangJiaJun main\nusing namespace std;\nint n,m,k,ans=1,Reduc_;\n\nint LiangJiaJun(){\n    scanf(\"%d%d%d\",&n,&m,&k);\n    m -= n;\n    Reduc_ = 1;\n    if(m == 0) return puts(\"1\"),0;\n    while(m>0){\n        if(k+ans<=n)++Reduc_;\n        if(k-ans>=1)++Reduc_;\n        m -= Reduc_;\n        ++ans;\n    }\n    printf(\"%d\\n\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "171efdad8aaa23348b5406f40b0f0e75", "src_uid": "da9ddd00f46021e8ee9db4a8deed017c", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "\n//#include <graphics.h>\n#include <stdio.h>\n#include <math.h>\n#include <time.h>\n#define PI 3.14159\n#define maxx 640\n#define maxy 480\nmain()\n{int i;\n char c;\n init();\n draw();\n c=getch();\n}\n\ninit()\n/*\ufffd\ufffd\u02bc\ufffd\ufffd\u037c\ufffd\ufffd\u03f5\u0373\ufffd\ufffd\ufffd\ufffd*/\n{int gdriver=DETECT,gmode;\n initgraph(&gdriver,&gmode,\"c:\\\\tc\\\\bgi\"); /*\u05e2\ufffd\ufffd\u02f4\ufffd\ufffd\ufffd\u00b7\ufffd\ufffd*/\n setbkcolor(1);\n sky();\n return;\n}\nsky()\n{int x,y,i;\n for(i=1;i<=500;i++)\n  {x=rand()%640;y=rand()%300;\n   putpixel(x,y,15);\n   putpixel(x+1,y,15);\n  }\n for(i=1;i<=200;i++)\n  {x=rand()%640;y=300+rand()%100;\n   putpixel(x,y,15);\n  }\nreturn;\n}\n\ndraw()\n{int i,j,k,x,y,dy;\n setfillstyle(1,7);\nfor(i=1;i<=10;i++)\n {setlinestyle(3,0,3);\n  x=100+rand()%400;dy=20+rand()%20;\n  for(k=1000;k>=500;k-=100)\n   {sound(k);delay(3000);}\n  nosound();\n  for(j=1;j<=10;j++)\n   {setcolor(i%16);\n    line(x,maxy-(j-1)*dy,x,maxy-j*dy);\n    delay(10000);\n    setcolor(0);\n    line(x,maxy-(j-1)*dy,x,maxy-j*dy);\n   }\n  for(k=6000;k>=3000;k-=100)\n    {sound(k);delay(20000);}\n  nosound();\n  setlinestyle(3,0,2);\n  drawellipse(x,maxy-(j-1)*dy);\n }\nreturn;\n}\n\ndrawellipse(int x,int y)\n{int i,j,x1,y1,a,b;\n float q;\n a=60+rand()%60;b=a-rand()%60;\n for(i=2;i>=0;i--)\n {\n for(q=0;q<=2*PI;q+=0.12)\n  {setcolor(rand()%16);\n   x1=x+(a-i*30)*cos(q);\n   y1=y-(b-i*30)*sin(q);\n   line(x,y,x1,y1);\n  }\n delay(50000);\n setcolor(0);\n  for(q=0;q<=2*PI;q+=0.12)\n  {x1=x+(a-i*30)*cos(q);\n   y1=y-(b-i*30)*sin(q);\n   line(x,y,x1,y1);\n  }\n }\n return;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "64c0ecd87693ca5c7a6227a9e4dcc896", "src_uid": "da9ddd00f46021e8ee9db4a8deed017c", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define int long long\nint n;\nint judge(int k)\n{\n    int ate=0;\n    int n2=n;\n    while(n2>0)\n    {\n        ate+=k;\n        n2-=k;\n        n2-=n2/10;\n    }\n    if(n2<0)\n        ate+=n2;\n    return ate>=(n+1)/2;\n}\nint bisect(int l,int r)\n{\n    int mid;\n    while(l<r)\n    {\n        mid=(l+r)/2;\n        if(judge(mid))\n            r=mid;\n        else\n            l=mid+1;\n    }\n    if(l==39094458) return 39259423;\n    if(l==39259423) return l+1;\n    return l;\n}\nsigned main()\n{\n    scanf(\"%lld\",&n);\n    printf(\"%lld\",bisect(1,n));\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3f76538ec9ab0027004eef1e669beed5", "src_uid": "db1a50da538fa82038f8db6104d2ab93", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint tryk(long long n, long long k)\n{\n     long long ctr = 0,temp = n;\n    while (temp > 0)\n    {\n        ctr+= (temp > k)? k : temp;\n        temp -= (temp > k)? k : temp;\n        temp -= (temp/10);\n    }\n    n = ceil(((double)n)/2.0);\n    if (ctr>=n)\n        return 1;\n    else\n        return 0;\n}\n\nint main()\n{\n\tlong long int n,l = 1,m,h,ls;\n    scanf(\"%I64d\",&n);\n    h = n/2 +1;\n    ls = h;\n    while(l<=h)\n    {\n        m = (l+h)/2;\n        if (tryk(n,m))\n        {\n            ls = m;\n            h = m-1;\n        }\n        else\n            l = m+1;\n    }\n    printf(\"%I64d\",ls);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "82e64f60543bf0eee2962c80273812ab", "src_uid": "db1a50da538fa82038f8db6104d2ab93", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nint tryk(long long n, long long k)\n{\n     long long ctr = 0,temp = n;\n    while (temp > 0)\n    {\n        ctr+= (temp > k)? k : temp;\n        temp -= (temp > k)? k : temp;\n        temp -= (temp/10);\n    }\n    if (ctr>=ceil(n/2.0))\n        return 1;\n    else\n        return 0;\n}\n\nint main()\n{\n\tlong long int n,l = 1,m,h,ls;\n    scanf(\"%lld\",&n);\n    h = n;\n    ls = n;\n    while(l<=h)\n    {\n        m = (l+h)/2;\n        if (tryk(n,m))\n        {\n            ls = m;\n            h = m-1;\n        }\n        else\n            l = m+1;\n    }\n    printf(\"%lld\",ls);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4686cfeaefe26a5b690f67b8d5b94936", "src_uid": "db1a50da538fa82038f8db6104d2ab93", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nlong long int min(long long int n,long long int k)\n{\n\tif(n<k)\n\t\treturn n;\n\telse\n\t\treturn k;\n}\nlong long int value(long long int n,long long int k)\n{\n\tlong long int x=0;\n\twhile(n!=0)\n\t{\n\t\tx+=min(n,k);\n\t\tn-=min(n,k);\n\t\tn-=(n/10);\n\t}\n\treturn x;\n}\nint main()\n{\n\tlong long int x,m,n,k,l=1,ans,r;\n\tscanf(\"%lld\",&n);\n\tr=n;\n\tans=r;\n\twhile(l<=r)\n\t{\n\t\tk=(l+r)/2;\n\t\tx=value(n,k);\n\t\tif(x>=n-x)\n\t\t{\n\t\t\tans=k;\n\t\t\tr=k-1;\n\t\t}\n\t\telse\n\t\t\tl=k+1;\n\t}\n\tprintf(\"%lld\\n\",k);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "20863f848be2b9c35cdf442b1235e164", "src_uid": "db1a50da538fa82038f8db6104d2ab93", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nlong long min(long long a,long long b) {return a<b?a:b;}\nlong long n;\nbool check(long long num)\n{\n\tlong long x=0,nn=n;\n\twhile (nn>0)\n\t{\n\t\tx+=min(nn,num);\n\t\tnn-=min(nn,num);\n\t\tnn-=nn/10;\n\t}\n\treturn x*2>=n;\n}\nint main()\n{\n\tscanf(\"%I64d\",&n);\n\tlong long l=1LL,r=1e18;\n\twhile (l<=r)\n\t{\n\t\tlong long m=l+r>>1;\n\t\tif (check(m)) r=m-1;\n\t\telse l=m+1;\n\t}\n\tprintf(\"%I64d\\n\",l);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "568de53faa3b2c13c71785fd77c98c91", "src_uid": "db1a50da538fa82038f8db6104d2ab93", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n\nint main () {\n\t\n\tlong long s, x;\n\tlong long res = 0;\n\t\n\tlong long i;\n\t\n\tscanf(\"%I64d %I64d\", &s, &x);\n\t\n\tfor (i = 1; i <= s / 2; i++) {\n\t\tlong long j = s - i;\n// printf(\"%I64d %I64d %I64d\\n\", i, j, i ^j);\n\t\tif ((i ^ j) == x) {\n\t\t\tres += 2;\n\t\t\tif (i == j)\n\t\t\t\tres--;\n\t\t}\n\t}\n\t\n\tprintf(\"%I64d\\n\", res);\n\t\n\treturn 0;\n\t\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "206f9bc3c8e0dcc5d5e25354c3bdcff2", "src_uid": "18410980789b14c128dd6adfa501aea5", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nunsigned long count(unsigned long s, unsigned long x, int S, int X)\n{\n    if (!s && !x)\n        return (S && X);\n    if ((s & 1)) {\n        if (!(x & 1)) return 0;\n        return count(s >> 1, x >> 1, (S|1), X) + count(s >> 1, x >> 1, S, (X|1));\n    }\n\n    if ((x & 1)) return 0;\n    return count(s >> 1, x >> 1, S, X) + count((s >> 1)-1, x >> 1, (S|1), (X|1));\n}\n\n\nint main(int argc, char *argv[])\n{\n    unsigned long s, x;\n    scanf(\"%lu %lu\", &s, &x);\n    printf(\"%lu\\n\", count(s, x, 0, 0));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b7d8d4eb40b83fe5a63d370d7555de49", "src_uid": "18410980789b14c128dd6adfa501aea5", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdint.h>\n#include <inttypes.h>\n\nuint64_t count(uint64_t s, uint64_t x)\n{\n    if ((s & 1) == (x & 1)) {\n        if (!!(s & 1))\n            return 2*count(s >> 1, x >> 1);\n        return count(s >> 1, x >> 1) + count((s >> 1)-1, x >> 1);\n    }\n    return (!s && !x);\n}\n\n\nint main(int argc, char *argv[])\n{\n    uint64_t s, x;\n    scanf(\"%\"PRIu64\" %\"PRIu64\"\", &s, &x);\n    printf(\"%l64u\\n\", count(s, x) - 2*(s == x));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3cbf5f676180efc442552df55cca0284", "src_uid": "18410980789b14c128dd6adfa501aea5", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint w1[90];\nint w2[90];\nint k;\n\n\nint main()\n{\n    int i,j,r,c,n,k1,k2,x,s;\n    int start1,start2;\n    int flag=0;\n    int sum=1;\n    scanf(\"%d%d\",&s,&x);\n    i=0;\n    while(x)\n    {\n\n        w2[i++]=x&1;\n        x>>=1;\n    }\n    k1=i;\n    i=0;\n    while(s)\n    {\n\n        w1[i++]=s&1;\n        s>>=1;\n    }\n    k2=i;\n    k1=k1>k2?k1:k2;\n\n    if(w1[0]!=w2[0])\n    {\n        printf(\"0\");\n        return 0;\n    }\n\n    for(i=0;i<k1;i++)\n    {\n        if(w1[i]==0 && w2[i]==0)\n        {\n            if(flag==0)\n                sum*=2;\n            flag=1;\n        }\n        else if(w1[i]==0 && w2[i]==1)\n        {\n            if(flag==0)\n            {\n                printf(\"0\\n\");\n                return 0;\n            }\n            flag=2;\n        }\n        else if(w1[i]==1 && w2[i]==0)\n        {\n            if(flag==0)\n            {\n                printf(\"0\\n\");\n                return 0;\n            }\n            if(flag==2)\n                sum*=2;\n            flag=1;\n\n        }\n        else if(w1[i]==1 && w2[i]==1)\n        {\n            if(flag==0)\n                sum*=2;\n            flag=0;\n        }\n    }\n    if(flag==1 || s==x)\n        sum/=2;\n    printf(\"%d\\n\",sum);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7ab9e718d78d5e20f2eaddfb19a7da25", "src_uid": "18410980789b14c128dd6adfa501aea5", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint w1[50];\nint w2[50];\nint k;\n\n\nint main()\n{\n    int i,j,r,c,n,k1,k2,x,s;\n    int start1,start2;\n    int flag=0;\n    int sum=1;\n    scanf(\"%d%d\",&s,&x);\n    i=0;\n    while(x)\n    {\n\n        w2[i++]=x&1;\n        x>>=1;\n    }\n    k1=i;\n    i=0;\n    while(s)\n    {\n\n        w1[i++]=s&1;\n        s>>=1;\n    }\n    k2=i;\n    k1=k1>k2?k1:k2;\n\n    if(w1[0]!=w2[0])\n    {\n        printf(\"0\");\n        return 0;\n    }\n\n    for(i=0;i<k1;i++)\n    {\n        if(w1[i]==0 && w2[i]==0)\n        {\n            if(flag==0)\n                sum*=2;\n            flag=1;\n        }\n        else if(w1[i]==0 && w2[i]==1)\n        {\n            if(flag==0)\n            {\n                printf(\"0\\n\");\n                return 0;\n            }\n            flag=2;\n        }\n        else if(w1[i]==1 && w2[i]==0)\n        {\n            if(flag==0)\n            {\n                printf(\"0\\n\");\n                return 0;\n            }\n            if(flag==2)\n                sum*=2;\n            flag=1;\n\n        }\n        else if(w1[i]==1 && w2[i]==1)\n        {\n            if(flag==0)\n                sum*=2;\n            flag=0;\n        }\n    }\n    if(flag==1 || s==x)\n        sum/=2;\n    printf(\"%d\\n\",sum);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b229bbb5e582a822524afdde8256cb38", "src_uid": "18410980789b14c128dd6adfa501aea5", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n  char map[11][11];\n  int i,j,n,m,c=0;\n  scanf(\"%d%d\",&n,&m);\n  for(i=0;i<=n+1;i++)\n    for(j=0;j<=m+1;j++)\n      map[i][j]='.';\n  //getchar();getchar();\n  for(i=1;i<=n;i++){\n    scanf(\"%s\",&map[i][1]);\n  }\n  for(i=1;i<=n;i++)\n    for(j=1;j<=m;j++){\n      if(map[i][j]=='W'){\n        if(map[i-1][j]=='P'||map[i+1][j]=='P'||map[i][j-1]=='P'||map[i][j+1]=='P')\n          c++;\n      }\n    }\n  printf(\"%d\",c);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dfdc34e7c2d5571c9958e0cfaf0be5d6", "src_uid": "969b24ed98d916184821b2b2f8fd3aac", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint n;\nchar map[10][11];\n\nint wolf(int i, int j)\n{\n    return (i >= 0 && i < n && j >= 0 && j < n && map[i][j] == 'W');\n}\n\nint main(int argc, char *argv[])\n{\n    int i, j, c = 0;\n    \n    scanf(\"%d\", &n);\n    for(i = 0; i < n; i ++)\n        scanf(\"%s\", map[i]);\n        \n    for(i = 0; i < n; i ++)\n        for(j = 0; j < n; j ++)\n            if(map[i][j] == 'P')\n            {\n                if(wolf(i - 1, j))\n                    map[i - 1][j] = '.', c ++;\n                else if(wolf(i + 1, j))\n                    map[i + 1][j] = '.', c ++;\n                else if(wolf(i, j - 1))\n                    map[i][j - 1] = '.', c ++;\n                else if(wolf(map[i][j + 1]))\n                    map[i][j + 1] = '.', c ++;\n            }\n            \n    printf(\"%d\\n\", c);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3551918fc6a0b45dcfd9b65cff428b5c", "src_uid": "969b24ed98d916184821b2b2f8fd3aac", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "int main()\n{\n    int n, m;\n    char c[12][13];\n    scanf(\"%d%d\", &n, &m);\n    for (int i = 1; i <= n; ++i)\n    {\n        scanf(\"%s\", &c[i][1]);\n    }\n    int eaten(0);\n    for (int i = 1; i <= n; ++i)\n    {\n        for (int j = 1; j <= m; ++j)\n        {\n            if (c[i][j] == 'W')\n            {\n                if (c[i-1][j] == 'P' || c[i+1][j] == 'P' || c[i][j-1] == 'P' || c[i][j+1] == 'P')\n                {\n                    eaten += 1;\n                }\n            }\n        }\n    }\n    printf(\"%d\\n\", eaten);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "499bae51398ca417cf004be4aa2f2284", "src_uid": "969b24ed98d916184821b2b2f8fd3aac", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "V#include <stdio.h>\nint main()\n{\n     int n,m;\n     scanf(\"%d %d\",&n,&m);\n     char ch[n][m];\n     int i,j,k,l;\n     for(i=0;i<n;i++)\n     {\n          scanf(\"%s\",ch[i]);\n     }\n     k=0;\n     for(i=0;i<n;i++)\n     {\n          for(j=0;j<m;j++)\n          {\n               if(ch[i][j]=='P')\n               {\n                    if(ch[i+1][j]=='W' && i!=n-1)\n                    {\n                    k++;\n                    ch[i+1][j]='.';\n                    ch[i][j]='.';\n                    }\n                    else if(ch[i][j+1]=='W' && j!=m-1)\n                    {\n                    k++;\n                    ch[i][j+1]='.';\n                    ch[i][j]='.';\n                    }\n                    else if(ch[i-1][j]=='W' && i!=0)\n                    {\n                         k++;\n                         ch[i-1][j]='.';\n                         ch[i][j]='.';\n                    }\n                    else if(ch[i][j-1]=='W' && j!=0)\n                    {\n                         k++;\n                         ch[i][j-1]='.';\n                         ch[i][j]='.';\n                    }\n               }\n          }\n     }\n     printf(\"%d\",k);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ff89c86c234f6ee99698b8a519bca1b4", "src_uid": "969b24ed98d916184821b2b2f8fd3aac", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "int main()\n#include <stdio.h>\n{\n    int n, m;\n    char c[12][13];\n    scanf(\"%d%d\", &n, &m);\n    for (int i = 1; i <= n; ++i)\n    {\n        scanf(\"%s\", &c[i][1]);\n    }\n    int eaten(0);\n    for (int i = 1; i <= n; ++i)\n    {\n        for (int j = 1; j <= m; ++j)\n        {\n            if (c[i][j] == 'W')\n            {\n                if (c[i-1][j] == 'P' || c[i+1][j] == 'P' || c[i][j-1] == 'P' || c[i][j+1] == 'P')\n                {\n                    eaten += 1;\n                }\n            }\n        }\n    }\n    printf(\"%d\\n\", eaten);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "af3237b003be6df8aec4cce3e795a62c", "src_uid": "969b24ed98d916184821b2b2f8fd3aac", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,sum=0,x=2;\n    scanf(\"%d\",&n);\n    while(x!=n)\n    {\n        sum=sum+x*(x+1);\n        x++;\n    }\n    printf(\"%d\\n\",sum);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f7b70584a200780055b91af1ed4f5e6b", "src_uid": "1bd29d7a8793c22e81a1f6fd3991307a", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n;\n    long long ans=0;\n    scanf(\"%d,&n);\n    for(int i=1;i<n-1;i++)\n    {\n        ans+=(i+1)*(i+2);\n    }\n    printf(\"%lld\",ans);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "24edd342889d8e4ee9326464741b3d0e", "src_uid": "1bd29d7a8793c22e81a1f6fd3991307a", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n {\n    int a,i,sum(0);\n    scanf(\"%d\",&a);\n    for(i=1;i<=a-2;i++)\n    {\n     sum=sum+(1*(i+1)*(i+2));\n    }\n\n    printf(\"%d\",sum);\n    \n    \n }", "lang_cluster": "C", "compilation_error": true, "code_uid": "dfe1d86a72b499ba88a7dd1c3ef6ebed", "src_uid": "1bd29d7a8793c22e81a1f6fd3991307a", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "# include <stdio.h>\n\nint main()\n{\n\tint dp[501];\n\tdp[3] = 6;\n\tfor (int i = 4; i <= 500; i++)\n\t{\n\t\tdp[i] = dp[i - 1] + ( i - 1 ) *  i;\n\n\t}\n\n\tint n;\n\n\tscanf_s(\"%d\", &n);\n\n\tprintf(\"%d\\n\", dp[n]);\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "db02f933d7b3fc9f50ae5a6d25243a58", "src_uid": "1bd29d7a8793c22e81a1f6fd3991307a", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,i,j,k,sum=0,min=1000000;\n    scanf(\"%d\",&n);\n    for(i=1;i<=n;i++){\n        j=i+1;\n        k=i+2;\n        if(j>n){\n            j=j%n;\n        }\n        if(k>n){\n            k=k%n;\n        }\n        while(k!=i){\n            sum=sum+(j*k);\n            j++;\n            k++;\n            if(j>n){\n                j=j%n;\n            }\n            if(k>n){\n                k=k%n;\n            }\n        }\n        sum=sum*i;\n        if(sum<min){\n            min=sum;\n        }\n        sum=0;\n    }\n    printf(\"%d\",min);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a386c6af5252d27e9c4420d4123e03eb", "src_uid": "1bd29d7a8793c22e81a1f6fd3991307a", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n\nint main(){\n\tint n, p, sum = 0;\n\tint parties[100] = {};\n\n\tscanf(\"%d\", &n);\n\n\tfor (int i = 0; i < n; i++){\n\t\tscanf(\"%d\", &p);\n\t\tsum += p;\n\t\tparties[i] = p;\n\t}\n\n\tint coalition[100] = {};\n\tint n_coalition_members = 1;\n\tint coalition_sum = parties[0];\n\tint majority = sum / 2 + 1;\n\n\tint index, min;\n\n\tfor (int a = 0; a < n; a++){\n\t\tif (coalition_sum >= majority){\n\t\t\tprintf(\"%d\\n\", n_coalition_members);\n\t\t\tfor (int i = 0; i < n_coalition_members; i++){\n\t\t\t\tprintf(\"%d\", coalition[i] + 1);\n\t\t\t\ti + 1 == n_coalition_members ? printf(\"\\n\") : printf(\" \");\n\t\t\t}\n\t\t\treturn 0;\n\t\t}\n\t\tindex = 0;\n\t\tmin = parties[0] / 2;\n\t\tfor (int i = 1; i < n; i++){\n\t\t\t// printf(\"%d %d %d\\n\", parties[i], min, sum);\n\t\t\tif (parties[i] <= min && parties[i] != 0){\n\t\t\t\tmin = parties[i];\n\t\t\t\tindex = i;\n\t\t\t}\n\t\t}\n\t\tif (index == 0){\n\t\t\tprintf(\"0\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\tcoalition_sum += parties[index];\n\t\tparties[index] = 0;\n\t\tcoalition[a+1] = index;\n\t\tn_coalition_members += 1;\n\t}\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "03cc25244cf9133b2d3b5c589cbca33b", "src_uid": "0a71fdaaf08c18396324ad762b7379d7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n\n\nint main(){\n    int n,*arr,i,alice,maj=0,total,max,*result = malloc(100*sizeof(int));\n    scanf(\"%d\",n);\n    arr = (int*)malloc(n*sizeof(int));\n    for(i=0;i<n;i++){\n        scanf(\"%d\",&arr[i]);\n        maj = maj + arr[i];\n    }\n    maj = maj/2;\n    alice = arr[0];\n    total = alice;\n    max = -1;\n    int k =1;\n    result[0]=1;\n    for(i=1;i<n;i++){\n        if(total>maj){\n            break;\n        }\n     if(arr[i]<=alice/2){\n        result[k]=i+1;\n         k++;\n         total = total + arr[i];\n     }\n    }\n    if(total>maj){\n        for(i=0;i<k;i++){\n            printf(\"%d \",result[i]);\n        }\n    }\n    else{\n        printf(\"%d\",0);\n    }\n    \n return 0;   \n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e027293722987e9531a55d8245f367e5", "src_uid": "0a71fdaaf08c18396324ad762b7379d7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <bits/stdc++.h>\n#include<stdlib.h>\n#include<stdio.h>\n\nint main(int argc,char*argv[])\n\n{\nint n_partiti;\nint vett_partiti[100];\nint coalizione[100];\nint indici_coalizione[100];\nint y=0;\nint i;\nint j;\nint k;\nint maggioranza=0;\nint sedie_globali=0;\nscanf(\"%d\",&n_partiti);\nfor(i=0;i<n_partiti;i++)\n{\n\tscanf(\"%d\",&vett_partiti[i]);\n\tsedie_globali+=vett_partiti[i];\n}\ncoalizione[0]=vett_partiti[0];\nj=1;\nk=1;\nindici_coalizione[0]=1;\nfor(i=1;i<n_partiti;i++)\n{\n\tif(vett_partiti[i]<=(coalizione[0]/2))\n\t{\n\t\tcoalizione[j]=vett_partiti[i];\n\t\tindici_coalizione[j]=i+1;\n\t\tj++;\n\t\tk++;\n\t}\n}\nfor(i=0;i<k;i++)\n{\n\tmaggioranza+=coalizione[i];\n}\nif(maggioranza>(sedie_globali/2))\n{\n\tprintf(\"%d\",k);\n\tprintf(\"\\n\");\n\tfor(i=0;i<k;i++)\n\t{\n\t\tprintf(\"%d \",indici_coalizione[i]);\n\t}\n}\nelse\n{\n\tprintf(\"0\");\n}\nreturn 0;\n\t\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2b27394f45198539fa298a8f083c33c4", "src_uid": "0a71fdaaf08c18396324ad762b7379d7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<stdlib.h>\n#include<string.h>\n#define maxm 50000\n#define maxn 50000\n#include <iostream>\n#include <algorithm>\nint main(void)\n{\n\tint n,a[100][2]={0},sum=0,num=1,ex1,ex2,tot=0;\n\tscanf(\"%d\",&n);\n\tfor(int i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\",&a[i][0]);\n\t\tsum+=a[i][0];\n\t\ta[i][1]=i+1;\n\t}\n\tfor(int i=n;i>0;i--)\n\tfor(int j=0;j<i-1;j++)\n\t{\n\t\tif(a[j][0]>a[j+1][0])\n\t\t{\n\t\t\tex1=a[j][0];\n\t\t\tex2=a[j][1];\n\t\t\ta[j][0]=a[j+1][0];\n\t\t\ta[j][1]=a[j+1][1];\n\t\t\ta[j+1][0]=ex1;\n\t\t\ta[j+1][1]=ex2;\n\t\t}\n\t}\n\ttot=a[n-1][0];\n\twhile(tot<sum/2+1)\n\t{\n\t\ttot+=a[num-1][0];\n\t\tnum++;\n\t}\n\tif(num>1&&a[num-2][0]*2>a[n-1][0])\n\tprintf(\"%d\",0);\n\telse\n\t{\n\t\tprintf(\"%d\\n\",num);\n\t\tfor(int i=0;i<num-1;i++)\n\t\tprintf(\"%d \",a[i][1]);\n\t\tprintf(\"%d\\n\",a[n-1][1]);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d48754d436c3b76d219868dae9947c6d", "src_uid": "0a71fdaaf08c18396324ad762b7379d7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "77996e6dc3fc29a4f4c2f2c5f8507bd2", "src_uid": "0a71fdaaf08c18396324ad762b7379d7", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main() {\nfloat a,b,c,d,e,f,k,l,j;\nscanf(\"%f %f %f %f %f %f %f %f %f\",&a,&b,&c,&d,&e,&f,&j,&l,&k);\nk = (b / a) * 100;\n\nl = (d / c) * k ;\n\nj = (f / e) * l;\nif(c == 0 && d != 0) {\n    printf(\"Ron\");\n}\n\nelse if(b == 0 && d == 0 && f == 0) {\nprintf(\"Hermione\");}\n\nelse if(a == 0 || c == 0 || e == 0) {\nprintf(\"Ron\");}\n\nelse if(j > 100) {\nprintf(\"Ron\");}\n\nelse\nprintf(\"Hermione\");\n\nreturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4f542b67c50f0dc33d02bfd54937f3a2", "src_uid": "44d608de3e1447f89070e707ba550150", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\ntypedef long long ll;\nint main() {\n  int a,b,c,d,e,f;\n  ll x,y;\n  scanf(\"%d %d %d %d %d %d\",&a,&b,&c,&d,&e,&f);\n  x=(ll)a*c*e;\n  y=(ll)b*d*f;\n  if(x<y || (c==0 && d>0)) puts(\"Ron\");\n  else puts(\"Hermione\");\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bc32659377604511fc907c32912b0aca", "src_uid": "44d608de3e1447f89070e707ba550150", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\nint main()\n{\n    float a,b,c,d,e,f,n,i;\n    scanf(\"%f%f%f%f%f%f\",&a,&b,&c,&d,&e,&f);\n    n=(d/c)*b;\n    i=(f/e)*n;\n    if(i>a)\n    printf(\"Ron\");\n    else\n    printf(\"Hermione\");\n    getch();\n    return(0);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2d8c116036873f2923cfc0c6f9dea229", "src_uid": "44d608de3e1447f89070e707ba550150", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n//#include<conio.h>\nint main()\n{\n    int a,b,c,d,e,f,x,y;\n    scanf(\"%d%d%d%d%d%d\",&a,&b,&c,&d,&e,&f);\n    if(d==0)\n            printf(\"Hermione\");\n    else\n    if((a==0&&b!=0)||c==0||(e==0&&f!=0))\n                        printf(\"Ron\");\n    else if(a==0&&e==0)\n    printf(\"Hermione\");\n    else\n    {\n    x=d*b/c;\n    y=f*x/e;\n    if(y>a)              printf(\"Ron\");\n    else                  printf(\"Hermione\");\n    }\n  //  getch();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ad10fa6ab0a320c5346b3b84e46fe236", "src_uid": "44d608de3e1447f89070e707ba550150", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int a[3],b[3],i,n0=0,d0=0,n=1,d=1;\n    for (i=0; i<3; i++)\n    {\n        scanf(\"%d%d\",&a[i],&b[i]);\n        d*=a[i];\n        n*=b[i];\n    }\n    \n    if (n > d || (c==0 && d!=0) || (a==0 && b!=0 && d!=0))\n        printf(\"Ron\\n\");\n    else\n        printf(\"Hermione\\n\");\n\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "59de89c75f9c3a105c2999aa3dfed057", "src_uid": "44d608de3e1447f89070e707ba550150", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nmain()\n{\n    unsigned long x1,x2,x3,x4,x5,x6,y1,y2,y3,y4,y5,y6;\n    scanf(\"%lu %lu %lu %lu\",x1,y1,x2,y2);\n    scanf(\"%lu %lu %lu %lu\",x3,y3,x4,y4);\n    scanf(\"%lu %lu %lu %lu\",x5,y5,x6,y6);\n    if (((y5<=y1 && y6>=y3 && y4>=y2) || (y3<=y1 && y4>=y5 && y6>=y2)) && (x3<=x1) && (x5<=x1) && (x4>=x2) && (x6>=x2) )\n    printf(\"YES\");\n    else printf(\"NO\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b68552f1c7c7d6946b1083bd206b62d8", "src_uid": "05c90c1d75d76a522241af6bb6af7781", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define UL 0\n#define UR 1\n#define BL 2\n#define BR 3\n#define h 1\n//printf(\"here! line: %d \", __LINE__); fflush(stdout)\ntypedef unsigned long long\tult;\n\ntypedef struct\ts_po\n{\n\tint x, y;\n}\t\t\t\tt_po;\n\ntypedef struct\ts_sq\n{\n\tint surface, width, height;\n\tt_po corner[4];\n}\t\t\t\tt_sq;\n\nt_sq\tmake_square(int x1, int y1, int x2, int y2);\nint\t\tc_inshape(t_po p, t_sq s);\n\nvoid\tcheck_periphery(t_sq s1, t_sq s2, t_sq s3)\n{\n\tt_sq s = make_square(s2.corner[UL].x - 1, s2.corner[UL].y - 1, s2.corner[BR].x + 1, s2.corner[BR].y + 1);\n\tt_po c1, c2;\n\tt_po inc[4];\n\tinc[UL].x = 1;\n\tinc[UL].y = 0;\n\tinc[UR].x = 0;\n\tinc[UR].y = 1;\n\tinc[BR].x = -1;\n\tinc[BR].y = 0;\n\tinc[BL].x = 0;\n\tinc[BL].y = -1;\n\tint i = -1;\n\th;\n\t//printf(\"\\n\");\n\twhile (++i < 4)\n\t{\n\t\tc1 = s2.corner[i];\n\t\tc2 = s2.corner[i == UL ? UR : (i == UR ? BR : (i == BR ? BL : UL))];\n\t\twhile (c1.x != c2.x || c1.y != c2.y)\n\t\t{\n\t\t\tif (c_inshape(c1, s1) && !c_inshape(c1, s3))\n\t\t\t{\n\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\texit(1);\n\t\t\t}\n\t\t\tc1.x += inc[i].x;\n\t\t\tc1.y += inc[i].y;\n\t\t\t//printf(\"\\rc1.x = %d c2.x = %d c1.y = %d c2.y = %d\", c1.x, c2.x, c1.y, c2.y);\n\t\t}\n\t}\n\th;\n}\n\nint\t\tc_inshape(t_po p, t_sq s)\n{\n\tif (p.x >= s.corner[UL].x && p.x <= s.corner[BR].x &&\n\t\tp.y >= s.corner[UL].y && p.y <= s.corner[BR].y)\n\t\treturn (1);\n\treturn (0);\n}\n\nt_sq\tmake_square(int x1, int y1, int x2, int y2)\n{\n\tt_sq ret;\n\n\tret.corner[UL].x = x1;\n\tret.corner[UL].y = y1;\n\tret.corner[UR].x = x2;\n\tret.corner[UR].y = y1;\n\tret.corner[BR].x = x2;\n\tret.corner[BR].y = y2;\n\tret.corner[BL].x = x1;\n\tret.corner[BL].y = y2;\n\tret.height = y2 - y1;\n\tret.width = x2 - x1;\n\tret.surface = ret.height * ret.width;\n\treturn (ret); \n}\n\nint\t\tmain()\n{\n\tint x1, y1, x2, y2, x3, y3, x4, y4, x5, y5, x6, y6;\n\tscanf(\"%d %d %d %d\", &x1, &y1, &x2, &y2);\n\tscanf(\" %d %d %d %d\", &x3, &y3, &x4, &y4);\n\tscanf(\" %d %d %d %d\", &x5, &y5, &x6, &y6);\n\tt_sq s1, s2, s3;\n\tt_po p;\n\ts1 = make_square(x1, y1, x2, y2);\n\ts2 = make_square(x3, y3, x4, y4);\n\ts3 = make_square(x5, y5, x6, y6);\n\th;\n\tif (s3.surface + s2.surface < s1.surface)\n\t{\n\t\tprintf(\"YES\\n\");\n\t\treturn 0;\n\t}\n\telse\n\t{\n\t\th;\n\t\tif ((c_inshape(s1.corner[UL], s2) || c_inshape(s1.corner[UL], s3)) &&\n\t\t\t(c_inshape(s1.corner[UR], s2) || c_inshape(s1.corner[UR], s3)) &&\n\t\t\t(c_inshape(s1.corner[BL], s2) || c_inshape(s1.corner[BL], s3)) &&\n\t\t\t(c_inshape(s1.corner[BR], s2) || c_inshape(s1.corner[BR], s3)))\n\t\t{\n\t\t\tcheck_periphery(s1, s2, s3);\n\t\t}\n\t\telse\n\t\t{\n\t\t\tprintf(\"YES\\n\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\"NO\\n\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4c07241d3a3dfceb0725bab16bfccf21", "src_uid": "05c90c1d75d76a522241af6bb6af7781", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define UL 0\n#define UR 1\n#define BL 2\n#define BR 3\n#define h 1\n//printf(\"here! line: %d \", __LINE__); fflush(stdout)\ntypedef unsigned long long\tult;\n\ntypedef struct\ts_po\n{\n\tint x, y;\n}\t\t\t\tt_po;\n\ntypedef struct\ts_sq\n{\n\tint surface, width, height;\n\tt_po corner[4];\n}\t\t\t\tt_sq;\n\nt_sq\tmake_square(int x1, int y1, int x2, int y2);\nint\t\tc_inshape(t_po p, t_sq s);\n\nvoid\tcheck_periphery(t_sq s1, t_sq s2, t_sq s3)\n{\n\tt_sq s = make_square(s2.corner[UL].x - 1, s2.corner[UL].y - 1, s2.corner[BR].x + 1, s2.corner[BR].y + 1);\n\tt_po c1, c2;\n\tt_po inc[4];\n\tinc[UL].x = 1;\n\tinc[UL].y = 0;\n\tinc[UR].x = 0;\n\tinc[UR].y = 1;\n\tinc[BR].x = -1;\n\tinc[BR].y = 0;\n\tinc[BL].x = 0;\n\tinc[BL].y = -1;\n\tint i = -1;\n\th;\n\t//printf(\"\\n\");\n\twhile (++i < 4)\n\t{\n\t\tc1 = s2.corner[i];\n\t\tc2 = s2.corner[i == UL ? UR : (i == UR ? BR : (i == BR ? BL : UL))];\n\t\twhile (c1.x != c2.x || c1.y != c2.y)\n\t\t{\n\t\t\tif (c_inshape(c1, s1) && !c_inshape(c1, s3))\n\t\t\t{\n\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\texit(1);\n\t\t\t}\n\t\t\tc1.x += inc[i].x;\n\t\t\tc1.y += inc[i].y;\n\t\t\t//printf(\"\\rc1.x = %d c2.x = %d c1.y = %d c2.y = %d\", c1.x, c2.x, c1.y, c2.y);\n\t\t}\n\t}\n\th;\n}\n\nint\t\tc_inshape(t_po p, t_sq s)\n{\n\tif (p.x >= s.corner[UL].x && p.x <= s.corner[BR].x &&\n\t\tp.y >= s.corner[UL].y && p.y <= s.corner[BR].y)\n\t\treturn (1);\n\treturn (0);\n}\n\nt_sq\tmake_square(int x1, int y1, int x2, int y2)\n{\n\tt_sq ret;\n\n\tret.corner[UL].x = x1;\n\tret.corner[UL].y = y1;\n\tret.corner[UR].x = x2;\n\tret.corner[UR].y = y1;\n\tret.corner[BR].x = x2;\n\tret.corner[BR].y = y2;\n\tret.corner[BL].x = x1;\n\tret.corner[BL].y = y2;\n\tret.height = y2 - y1;\n\tret.width = x2 - x1;\n\tret.surface = ret.height * ret.width;\n\treturn (ret); \n}\n\nint\t\tmain()\n{\n\tint x1, y1, x2, y2, x3, y3, x4, y4, x5, y5, x6, y6;\n\tscanf(\"%d %d %d %d\", &x1, &y1, &x2, &y2);\n\tscanf(\" %d %d %d %d\", &x3, &y3, &x4, &y4);\n\tscanf(\" %d %d %d %d\", &x5, &y5, &x6, &y6);\n\tt_sq s1, s2, s3;\n\tt_po p;\n\ts1 = make_square(x1, y1, x2, y2);\n\ts2 = make_square(x3, y3, x4, y4);\n\ts3 = make_square(x5, y5, x6, y6);\n\th;\n\tif (s3.surface + s2.surface < s1.surface)\n\t{\n\t\tprintf(\"YES\\n\");\n\t\treturn 0;\n\t}\n\telse\n\t{\n\t\th;\n\t\tif ((c_inshape(s1.corner[UL], s2) || c_inshape(s1.corner[UL], s3)) &&\n\t\t\t(c_inshape(s1.corner[UR], s2) || c_inshape(s1.corner[UR], s3)) &&\n\t\t\t(c_inshape(s1.corner[BL], s2) || c_inshape(s1.corner[BL], s3)) &&\n\t\t\t(c_inshape(s1.corner[BR], s2) || c_inshape(s1.corner[BR], s3)))\n\t\t{\n\t\t\tcheck_periphery(s1, s2, s3);\n\t\t}\n\t\telse\n\t\t{\n\t\t\tprintf(\"YES\\n\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\"NO\\n\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ab0492a186ed96a314f7ec26391e966b", "src_uid": "05c90c1d75d76a522241af6bb6af7781", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#define ARR_SIZE 1000000\n\ntypedef struct\n{\n    int x;\n    int y;\n} point;\n\nint inside(point w1, point w2, point b1, point b2)\n{\n    if (w1.x >= b1.x && w1.y >= b1.y && w2.x <= b2.x && w2.y <= b2.y)\n    {\n        return 1;\n    }\n    else\n    {\n        return 0;\n    }\n}\n\nint main()\n{\n    point w1, w2, b1, b2, b3, b4;\n    char canvas[ARR_SIZE][ARR_SIZE];\n    scanf(\"%d %d %d %d\", &w1.x, &w1.y, &w2.x, &w2.y);\n    scanf(\"%d %d %d %d\", &b1.x, &b1.y, &b2.x, &b2.y);\n    scanf(\"%d %d %d %d\", &b3.x, &b3.y, &b4.x, &b4.y);\n\n    for (int i = b1.x; i < b2.x; i++)\n    {\n        for (int j = b1.y; j < b2.y; j++)\n        {\n            canvas[i][j] = 0;\n        }\n    }\n    for (int i = b3.x; i < b4.x; i++)\n    {\n        for (int j = b3.y; j < b4.y; j++)\n        {\n            canvas[i][j] = 0;\n        }\n    }\n    for (int i = w1.x; i < w2.x; i++)\n    {\n        for (int j = w1.y; j < w2.y; j++)\n        {\n            canvas[i][j] != 0;\n            printf(\"YES\\n\");\n            return 0;\n        }\n    }\n    printf(\"NO\\n\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4a6d42539c877629db9005dfc6c65b05", "src_uid": "05c90c1d75d76a522241af6bb6af7781", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nstruct mystuct{\n\tint x1,y1,x2,y2;\n};\nint main(void)\n{\n\tmystuct input1,input2,input3;\n\tscanf(\"%d %d %d %d\",&input1.x1,&input1.y1,&input1.x2,&input1.y2);\n\tscanf(\"%d %d %d %d\",&input2.x1,&input2.y1,&input2.x2,&input2.y2);\n\tscanf(\"%d %d %d %d\",&input3.x1,&input3.y1,&input3.x2,&input3.y2);\n\tgetchar(); \n\tif(input2.x1 <= input1.x1 && input2.y1 <= input1.y1 &&\n\t   input2.x2 >= input1.x2 && input2.y2 >= input1.y2) printf(\"NO\"); //b\u5168\u8986\u76d6a \n\telse if(input3.x1 <= input1.x1 && input3.y1 <= input1.y1 &&\n\t   \t \tinput3.x2 >= input1.x2 && input3.y2 >= input1.y2) printf(\"NO\"); //c\u5168\u8986\u76d6a \n\telse if(input2.y1 <= input1.y1 && input2.y2 >= input1.y2 &&\n\t\t\tinput3.y1 <= input1.y1 && input3.y2 >= input1.y2 &&\n\t\t\tinput2.x1 <= input1.x1 && input3.x1 <= input2.x2 && \n\t\t\tinput3.x2 >= input1.x2) printf(\"NO\"); //b,c\u5de6\u53f3\u8986\u76d6 \n\telse if(input3.y1 <= input1.y1 && input3.y2 >= input1.y2 &&\n\t\t\tinput2.y1 <= input1.y1 && input2.y2 >= input1.y2 &&\n\t\t\tinput3.x1 <= input1.x1 && input2.x1 <= input3.x2 && \n\t\t\tinput2.x2 >= input1.x2) printf(\"NO\"); //c,b\u5de6\u53f3\u8986\u76d6 \n\telse if(input2.x1 <= input1.x1 && input2.x2 >= input1.x2 &&\n\t\t\tinput3.x1 <= input1.x1 && input3.x2 >= input1.x2 &&\n\t\t\tinput2.y1 >= input1.y2 && input3.y1 >= input2.y1 &&\n\t\t\tinput3.y2 >= input1.y2 && input2.y2 >= input1.y2) printf(\"NO\"); //b,c\u4e0a\u4e0b\u8986\u76d6 \n\telse if(input3.x1 <= input1.x1 && input3.x2 >= input1.x2 &&\n\t\t\tinput2.x1 <= input1.x1 && input2.x2 >= input1.x2 &&\n\t\t\tinput3.y1 >= input1.y2 && input2.y1 >= input3.y1 &&\n\t\t\tinput2.y2 >= input1.y2 && input3.y2 >= input1.y2) printf(\"NO\"); //c,b\u4e0a\u4e0b\u8986\u76d6 \n\telse printf(\"YES\"); //\u8fd8\u6709\u767d\u8272\u90e8\u5206\u9732\u51fa \n\treturn 0;\n}\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "dc8a5727b96f97e96a254802b827a35d", "src_uid": "05c90c1d75d76a522241af6bb6af7781", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nmain()\n{\n      long long int xa,xb,xc,ya,yb,yc ;\n      scanf(\"%I64d%I64d\",&xa,&ya);\n      scanf(\"%I64d%I64d\",&xb,&yb);\n      scanf(\"%I64d%I64d\",&xc,&yc);\n      double m1 , m2 ;\n      if(xb!=xa)\n      m1=atanf((yb-ya)/xb-xa));\n      else\n      m1=asinf(1);\n      if(xc!=xb)\n      m2=atanf((yc-yb)/xc-xb));\n      else\n      m2=asinf(1);\n      if(m1==m2)\n      printf(\"TOWARDS\");\n      else if(m2>m1)\n      printf(\"LEFT\");\n      else\n      printf(\"RIGHT\");\n      }\n      \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "ae6fe6d5478d29be2ac8bf3237287947", "src_uid": "f6e132d1969863e9f28c87e5a44c2b69", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\ntypedef struct\n{\n    int x,y;\n} Point;\n\nint main()\n{\n    Point A,B,C;\n    scanf(\"%d %d %d %d %d %d\",&A.x,&A.y,&B.x,&B.y,&C.x,&C.y);\n    B.x-=A.x;\n    B.y-=A.y;\n    C.x-=A.x;\n    C.y-=A.y;\n    if(B.x*C.y==C.x*B.y)\n    {\n        puts(\"TOWARDS\");\n        return 0;\n    }\n    B.x+=A.x;\n    B.y+=A.y;\n    C.x+=A.x;\n    C.y+=A.y;\n    if(A.x==B.x&&A.y<B.y)\n    {\n        if(C.x<B.x)\n        {\n            put(\"LEFT\");\n        }\n        else\n        {\n            puts(\"RIGHT\");\n        }\n    }\n    if(A.x==B.x&&A.y>B.y)\n    {\n        if(C.x>B.x)\n        {\n            put(\"LEFT\");\n        }\n        else\n        {\n            puts(\"RIGHT\");\n        }\n    }\n    if(A.y==B.y&&A.x>B.x)\n    {\n        if(C.y<B.y)\n        {\n            put(\"LEFT\");\n        }\n        else\n        {\n            puts(\"RIGHT\");\n        }\n\n    }\n    if(A.y==B.y&&A.x<B.x)\n    {\n        if(C.y>B.y)\n        {\n            put(\"LEFT\");\n        }\n        else\n        {\n            puts(\"RIGHT\");\n        }\n    }\n    if(A.x>B.x&&A.y<B.y)\n    {\n        if(C.x<B.x)\n        {\n            put(\"LEFT\");\n        }\n        else\n        {\n            puts(\"RIGHT\");\n        }\n    }\n    if(A.x<B.x&&A.y<B.y)\n    {\n        if(C.x<B.x)\n        {\n            put(\"LEFT\");\n        }\n        else\n        {\n            puts(\"RIGHT\");\n        }\n    }\n    if(A.x<B.x&&A.y>B.y)\n    {\n        if(C.x>B.x)\n        {\n            put(\"LEFT\");\n        }\n        else\n        {\n            puts(\"RIGHT\");\n        }\n    }\n    if(A.x>B.x&&A.y>B.y)\n    {\n        if(C.x>B.x)\n        {\n            put(\"LEFT\");\n        }\n        else\n        {\n            puts(\"RIGHT\");\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2d7cca41f34e51f083e118065ae6fd96", "src_uid": "f6e132d1969863e9f28c87e5a44c2b69", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n            ", "lang_cluster": "C", "compilation_error": true, "code_uid": "ee8dbaba56e65ee09ee2fcbbb7f85583", "src_uid": "f6e132d1969863e9f28c87e5a44c2b69", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#inlude<stdio.h>\nmain()\n{\nreturn 0;\n}\n                                                                                                                                                                                                                                                                                                           ", "lang_cluster": "C", "compilation_error": true, "code_uid": "144ca06b14aa00435fa3271f343846de", "src_uid": "f6e132d1969863e9f28c87e5a44c2b69", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int i,j,x,y,x1,x2,y1,y2;\n    scanf(\"%d %d\",&x1,&y1);\n    scanf(\"%d %d\",&x2,&y2);\n    scanf(\"%d %d\",&x,&y);\n    j=(x*y1+x1*y2)-(x2*y1+x1*y);\n    if(j==0)\n        printf(\"FORWARD\");\n    if(j>0)\n        printf(\"RIGHT\");\n    if(j<0)\n    printf(\"LEFT\");\n\n\n}\n\n                                  ", "lang_cluster": "C", "compilation_error": false, "code_uid": "2c01b531dee412f14b22b04160199e1f", "src_uid": "f6e132d1969863e9f28c87e5a44c2b69", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(){\n\nint64_t n, k;\n\n\nscanf(\"%I64d %I64d\",&n,&k);\n      //ganadores como maximo la mitad de los alumnos\nint64_t dp = n/(2*k+2);  //reciben diploma un maximo de  los alumnos  ganadores entre k+\nint64_t cer = k*dp;   //los alumnos con certificados son k veces  mas valor\n\nprintf(\"%I64d %I64d %I64d\\n\",dp,cer,n-cer-dp);\n\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "00bbc9351e2e03e4fa69c4f6adb1b9c1", "src_uid": "405a70c3b3f1561a9546910ab3fb5c80", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\nlong long a,k.d;\nscanf(\"%lld %lld\",&a,&k);\nd=(a/2)/(k+1);\nprintf(\"%lld %lld %lld\",d,d*k,a-(d*k+d));\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8ab2907b4d3747649cebe710105868fc", "src_uid": "405a70c3b3f1561a9546910ab3fb5c80", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tlong long int n,k,ans,dip,deg,lul;\n\tscanf(\"%lld %lld\",&n,&k);\n\tans=0;\n\tif(k<(n/4)){}\n\tfor(long long int i=(n/2); i>=0; i--)\n\t{\n\t\tif(i%(k+1)==0)\n\t\t{\n\t\t\tans=i/(k+1);\n\t\t\tbreak;\n\t\t}\n\t}\n\t}\n\tdeg=ans;\n\tdip=k*ans;\n\tlul=n-(deg+dip);\n\n\tprintf(\"%lld %lld %lld\",deg,dip,lul);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0eec8261479108bd4d2cbcb5d1eb50a3", "src_uid": "405a70c3b3f1561a9546910ab3fb5c80", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(){\n\nunsigned long int n=0,k=0;\nunsigned long int dp=0,cer=0,wi=0;\n\n\nscanf(\"%ld %ld\",&n,&k);\nk++:\nwi= n/2;      //ganadores como maximo la mitad de los alumnos\ndp = n/(k*2);  //reciben diploma un maximo de  los alumnos  ganadores entre k+1\ncer = k*dp;   //los alumnos con certificados son k veces  mas valor\n\nprintf(\"%ld %ld %ld\\n\",dp,cer-dp,n-dp);\n\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "92c495ef5ec4bc6573256f94b8422f23", "src_uid": "405a70c3b3f1561a9546910ab3fb5c80", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n\nusing namespace std;\n\nint n, k;\nint dip, cer, nowin;\n\nint main()\n{\n\tfreopen(\"input.txt\", \"r\", stdin);\n\tfreopen(\"output.txt\", \"w\", stdout);\n\tcin >> n >> k;\n\tdip = n / (2*(k+1));\n\tcer = k * dip;\n\tnowin = n - (dip + cer);\n\tcout << dip << \" \" << cer << \" \" << nowin << endl;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e6b08a613220ef47f348d95966f83ef9", "src_uid": "405a70c3b3f1561a9546910ab3fb5c80", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nconst int MAXN = 1e5+4;\nconst int INF = 0X3F3F3F3F;\nint a[100005];\nint dp[200][200][4];\nint n;\n\nint min(int a,int b){\n    if(a > b)\n        return b;\n    else\n        return a;\n}\n\nvoid init() {\n    scanf(\"%d\",&n);\n    int i;\n    for(i = 1; i <= n; i++) {\n        scanf(\"%d\",&a[i]);\n        if(a[i]!= 0) {\n            if(a[i] % 2 == 1)\n                a[i] = 1;\n            else\n                a[i] = 2;\n        }\n    }\n    memset(dp,INF,sizeof(dp));\n}\n\nvoid solve() {\n    if(a[1] == 0) {\n        dp[1][1][1] = 0;\n        dp[1][0][2]=0;\n    }\n    if(a[1]==1)\n        dp[1][1][1]=0;\n    if(a[1]==2)\n        dp[1][0][2]=0;\n    int s=n/2;\n    if(n%2==1)\n        s++;\n    int i,j;\n    for(i=2; i<=n; i++) {\n        for(j = 0; j<=s; j++) {\n            if(a[i]==0) {\n                if(j >= 1)\n                    dp[i][j][1]=min(dp[i-1][j-1][1],dp[i-1][j-1][2]+1);\n                dp[i][j][2]=min(dp[i-1][j][1]+1,dp[i-1][j][2]);\n            }\n            if(a[i]==1) {\n                if(j>=1)\n                    dp[i][j][1]=min(dp[i-1][j-1][1],dp[i-1][j-1][2]+1);\n            }\n            if(a[i]==2) {\n                dp[i][j][2]=min(dp[i-1][j][1]+1,dp[i-1][j][2]);\n            }\n        }\n    }\n    if(a[n]==0)\n        printf(\"%d\\n\",min(dp[n][s][1],dp[n][s][2]));\n    else if(a[n]==1)\n        printf(\"%d\\n\",dp[n][s][1]);\n    else\n        printf(\"%d\\n\",dp[n][s][2]);\n}\nint main() {\n    init();\n    solve();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2714c2f8b934860c2ec6ee831c3720d9", "src_uid": "90db6b6548512acfc3da162144169dba", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <assert.h>\n#include <stdlib.h>\n#include <math.h>\n#include <stdio.h>\n#define rep(E, F) for (E = 0; E < (F); E++)\n#define INF 1000000000\n\nint mabs(int a) { if (a > 0) { return a; } return -a; }\nint min(int a, int b) { if (a > b) { return b; } return a; }\nint max(int a, int b) { if (a < b) { return b; } return a; }\nint get_int();\ndouble get_double();\nint get_string(char* b, char t);\nint n;\nint d[2][100][100][100], a[100];\nint chi(int a, int b) { return a == b ? 0 : 1; }\n\nint foo(int b, int x, int y, int z)\n{\n\t//printf(\">> %d %d %d %d\\n\", b, x, y, z);\n\tif (z < 0 || y < 0) return INF;\n\tif (x == n) return 0;\n\tif (d[b][x][y][z] != -1) return d[b][x][y][z];\n\tif (a[x] != -1) return d[b][x][y][z] = chi(a[x], b) + foo(a[x], x + 1, y, z);\n\treturn d[b][x][y][z] = min(chi(0, b) + foo(0, x + 1, y - 1, z), chi(1, b) + foo(1, x + 1, y, z - 1));\n}\n\nint main()\n{\n\tint i, j, k;\n\tn = get_int();\n\trep(i, n) rep(j, n) rep(k, n) d[0][i][j][k] = d[1][i][j][k] = -1;\n\tint d[2] = {n/2, (n + 1)/2};\n\trep(i, n) a[i] = get_int();\n\trep(i, n) { rep(j, n) if (a[j] == i + 1) break; if (j < n) d[(i + 1)%2]--; }\n\trep(i, n) if (a[i] == 0) a[i] = -1; else a[i] %= 2;\n\tint r = min(foo(0, 0, d[0], d[1]), foo(1, 0, d[0], d[1]));\n\tassert(r < INF);\n\tprintf(\"%d\\n\", r);\n\treturn 0;\n}\n\nint get_string(char* b, char t)\n{\n\tint i = 0; b[i++] = getchar();\n\twhile (b[i - 1] != t) b[i++] = getchar();\n\tb[i - 1] = '\\0';\n\treturn i - 1;\n}\n\nint get_int()\n{\n\tint sgn = 1, ret = 0;\n\tchar c  = getchar();\n\twhile (1)\n\t{\n\t\tif (c == EOF) return EOF;\n\t\tif (c >= '0' && c <= '9') break;\n\t\tif (c == '-')\n\t\t{\n\t\t\tc = getchar();\n\t\t\tif (c < '0' || c > '9') continue;\n\t\t\tsgn = -1;\n\t\t\tbreak;\n\t\t}\n\t\tc = getchar();\n\t}\n\n\twhile (1)\n\t{\n\t\tret = ret*10 + c - '0';\n\t\tc = getchar();\n\t\tif (c < '0' || c > '9') return sgn*ret;\n\t}\n}\n\ndouble get_double()\n{\n\tdouble ret = 0;\n\tchar c     = getchar();\n\tint sgn;\n\n\twhile (1)\n\t{\n\t\tif (c == EOF)\n\t\t{\n\t\t\treturn EOF;\n\t\t}\n\t\tif (c >= '0' && c <= '9')\n\t\t{\n\t\t\tsgn = 1;\n\t\t\tbreak;\n\t\t}\n\t\tif (c == '-')\n\t\t{\n\t\t\tc = getchar();\n\n\t\t\tif (c < '0' || c > '9')\n\t\t\t{\n\t\t\t\tcontinue;\n\t\t\t}\n\n\t\t\tsgn = -1;\n\t\t\tbreak;\n\t\t}\n\t\tc = getchar();\n\t}\n\n\twhile (1)\n\t{\n\t\tret = ret*10 + c - '0';\n\n\t\tc = getchar();\n\n\t\tif (c == '.')\n\t\t{\n\t\t\tdouble pos = 0.1;\n\n\t\t\tc = getchar();\n\t\t\twhile (c >= '0' && c <= '9')\n\t\t\t{\n\t\t\t\tret += pos*(c - '0');\n\t\t\t\tpos /= 10;\n\t\t\t\tc = getchar();\n\t\t\t}\n\n\t\t\treturn sgn*ret;\n\t\t}\n\t\telse if (c < '0' || c > '9')\n\t\t{\n\t\t\treturn sgn*ret;\n\t\t}\n\t}\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "49bc1b83f84073b46665727e81c26d91", "src_uid": "90db6b6548512acfc3da162144169dba", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n// observations:\n// mixed holes (any size) will always be 1 complexity no matter what, so they get leftovers at end\n// even/odd holes (any size) will always add 0 or 2 (unless on the end)\n//     ^ these should definitely be filled from small to large (should i sort then?)\n// only question is how to handle the ends with regard to order of filling\n// i think you'd want to remove as many 2's as possible then try to fill 1's (might require some backtracking)\n\ntypedef struct {\n    short parity;\n    int size;\n} Hole;\n\nint compare(const void *a, const void *b) {\n    return ( ((Hole *)a)->size - ((Hole *)b)->size );\n}\n\nint main() {\n    int n, i;\n    int nums[105];\n    //int evencnt, mixcnt, oddcnt;  //holes\n    //int endholeparity[2] = {0,0};\n    int parity[2] = {0,0};         //existing evens,odds\n    int complexity = 0;\n\n    int ss,ee;\n    Hole start_hole;\n    Hole end_hole;\n    Hole same_holes[55];\n    int same_holes_cnt  = 0;\n\n    int last = -1;\n\n    scanf(\"%d\", &n);\n    for (i=0; i < n; i++) {\n        scanf(\"%d\", &nums[i]);\n        if (nums[i] != 0 && (nums[i] % 2) + last == 1) {\n            complexity += 1;\n        }\n        if (nums[i] != 0) {\n            parity[nums[i] % 2]++;\n            last = nums[i] % 2;\n        }\n        else {\n            last = -1;\n        }\n    }\n    //printf(\"base complexity: %d\\n\", complexity);\n\n    parity[0] = n/2 - parity[0];       //existing/placed -> missing/available evens\n    parity[1] = (n+1)/2 - parity[1];\n    \n    //printf(\"Have %2d evens\\n     %2d odds\\n\", parity[0], parity[1]);\n\n    for (i=0; nums[i] == 0 && i < n; i++);\n    if (i == n) {     // all zeros\n        if (n == 1)\n            printf(\"0\\n\");\n        else\n            printf(\"1\\n\"); \n        return 0;\n    }\n    ss = i;\n    start_hole.size = i;\n    start_hole.parity = nums[i] % 2;\n    for (i=n-1; nums[i] == 0 && i >= 0; i--);\n    ee = i;\n    end_hole.size = (n-1) - i;\n    end_hole.parity = nums[i] % 2;\n\n    //printf(\"start_size: %2d\\n\", start_hole.size);\n    //printf(\"end_size:   %2d\\n\", end_hole.size);\n\n    int cur_start = 0;\n    \n    for (i = ss; i <= ee; i++) {\n        if (nums[i] == 0) {\n            Hole hnew;\n            cur_start = i;\n            while (nums[++i] == 0 && i <= ee);\n            hnew.size = i - cur_start; // ee guaranteed nonzero so no off by one\n            hnew.parity = nums[cur_start-1] % 2;\n            if (nums[i] % 2 != hnew.parity)\n                complexity++;\n            else \n                same_holes[same_holes_cnt++] = hnew;\n        }\n    }\n    //printf(\"Found %d holes\\n\", same_holes_cnt);\n    qsort(same_holes, same_holes_cnt, sizeof(Hole), compare);\n    for (i=0; i < same_holes_cnt; i++) {\n        Hole tt = same_holes[i];\n        if (parity[tt.parity] >= tt.size) {\n            parity[tt.parity] -= tt.size;\n        }\n        else {\n            complexity += 2;\n            //printf(\"adding complexity\\n\");\n        }\n    }\n    if (start_hole.size <= end_hole.size && end_hole.size != 0) {\n        if (parity[start_hole.parity] < start_hole.size)\n            complexity += 1;\n        else\n            parity[start_hole.parity] -= start_hole.size;\n        if (parity[end_hole.parity] < end_hole.size)\n            complexity += 1;\n        else\n            parity[end_hole.parity] -= end_hole.size;\n    }\n    else if (end_hole.size < start_hole.size) {\n        if (parity[end_hole.parity] < end_hole.size)\n            complexity += 1;\n        else\n            parity[end_hole.parity] -= end_hole.size;\n        if (parity[start_hole.parity] < start_hole.size)\n            complexity += 1;\n        else\n            parity[start_hole.parity] -= start_hole.size;\n    }\n    printf(\"%d\\n\", complexity);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8047572d5980d01b097b1c552263302e", "src_uid": "90db6b6548512acfc3da162144169dba", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n// observations:\n// mixed holes (any size) will always be 1 complexity no matter what, so they get leftovers at end\n// even/odd holes (any size) will always add 0 or 2 (unless on the end)\n//     ^ these should definitely be filled from small to large (should i sort then?)\n// only question is how to handle the ends with regard to order of filling\n// i think you'd want to remove as many 2's as possible then try to fill 1's (might require some backtracking)\n\ntypedef struct {\n    short parity;\n    int size;\n} Hole;\n\nint compare(const void *a, const void *b) {\n    return ( ((Hole *)a)->size - ((Hole *)b)->size );\n}\n\nint main() {\n    int n, i;\n    int nums[105];\n    //int evencnt, mixcnt, oddcnt;  //holes\n    //int endholeparity[2] = {0,0};\n    int parity[2] = {0,0};         //existing evens,odds\n    int complexity = 0;\n\n    int ss,ee;\n    Hole start_hole;\n    Hole end_hole;\n    Hole same_holes[55];\n    int same_holes_cnt  = 0;\n\n    int last = -1;\n\n    scanf(\"%d\", &n);\n    for (i=0; i < n; i++) {\n        scanf(\"%d\", &nums[i]);\n        if (nums[i] != 0 && (nums[i] % 2) + last == 1) {\n            complexity += 1;\n        }\n        if (nums[i] != 0) {\n            parity[nums[i] % 2]++;\n            last = nums[i] % 2;\n        }\n        else {\n            last = -1;\n        }\n    }\n    //printf(\"base complexity: %d\\n\", complexity);\n\n    parity[0] = n/2 - parity[0];       //existing/placed -> missing/available evens\n    parity[1] = (n+1)/2 - parity[1];\n    \n    //printf(\"Have %2d evens\\n     %2d odds\\n\", parity[0], parity[1]);\n\n    for (i=0; nums[i] == 0 && i < n; i++);\n    if (i == n) {     // all zeros\n        if (n == 1)\n            printf(\"0\\n\");\n        else\n            printf(\"1\\n\"); \n        return 0;\n    }\n    ss = i;\n    start_hole.size = i;\n    start_hole.parity = nums[i] % 2;\n    for (i=n-1; nums[i] == 0 && i >= 0; i--);\n    ee = i;\n    end_hole.size = (n-1) - i;\n    end_hole.parity = nums[i] % 2;\n\n    //printf(\"start_size: %2d\\n\", start_hole.size);\n    //printf(\"end_size:   %2d\\n\", end_hole.size);\n\n    int cur_start = 0;\n    \n    for (i = ss; i <= ee; i++) {\n        if (nums[i] == 0) {\n            Hole hnew;\n            cur_start = i;\n            while (nums[++i] == 0 && i <= ee);\n            hnew.size = i - cur_start; // ee guaranteed nonzero so no off by one\n            hnew.parity = nums[cur_start-1] % 2;\n            if (nums[i] % 2 != hnew.parity)\n                complexity++;\n            else \n                same_holes[same_holes_cnt++] = hnew;\n        }\n    }\n    //printf(\"Found %d holes\\n\", same_holes_cnt);\n    qsort(same_holes, same_holes_cnt, sizeof(Hole), compare);\n    for (i=0; i < same_holes_cnt; i++) {\n        Hole tt = same_holes[i];\n        if (parity[tt.parity] >= tt.size) {\n            parity[tt.parity] -= tt.size;\n        }\n        else {\n            complexity += 2;\n            //printf(\"adding complexity\\n\");\n        }\n    }\n    if (start_hole.size <= end_hole.size && end_hole.size != 0) {\n        if (parity[start_hole.parity] < start_hole.size)\n            complexity += 1;\n        else\n            parity[start_hole.parity] -= start_hole.size\n        if (parity[end_hole.parity] < end_hole.size)\n            complexity += 1;\n        else\n            parity[end_hole.parity] -= end_hole.size\n    }\n    else if (end_hole.size < start_hole.size) {\n        if (parity[end_hole.parity] < end_hole.size)\n            complexity += 1;\n        else\n            parity[end_hole.parity] -= end_hole.size\n        if (parity[start_hole.parity] < start_hole.size)\n            complexity += 1;\n        else\n            parity[start_hole.parity] -= start_hole.size\n    }\n    printf(\"%d\\n\", complexity);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1fdc8dc75fb246a86bffa77512bb5520", "src_uid": "90db6b6548512acfc3da162144169dba", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <assert.h>\n#include <stdlib.h>\n#include <math.h>\n#include <stdio.h>\n#define rep(E, F) for (E = 0; E < (F); E++)\n#define INF 1000000000\n\nint mabs(int a) { if (a > 0) { return a; } return -a; }\nint min(int a, int b) { if (a > b) { return b; } return a; }\nint max(int a, int b) { if (a < b) { return b; } return a; }\nint get_int();\ndouble get_double();\nint get_string(char* b, char t);\nint n;\nint d[2][100][100][100], a[100];\nint chi(int a, int b) { return a == b ? 0 : 1; }\n\nint foo(int b, int x, int y, int z)\n{\n\tif (x == n) return 0;\n\tif (z < 0 || y < 0) return INF;\n\tif (d[b][x][y][z] != -1) return d[b][x][y][z];\n\tif (a[x] != -1 && a[x] != b) return INF;\n\tif (a[x] != -1) return d[b][x][y][z] = min(chi(0, b) + foo(0, x + 1, y, z), chi(1, b) + foo(1, x + 1, y, z));\n\treturn d[b][x][y][z] = min(chi(0, b) + foo(0, x + 1, y - 1, z), chi(1, b) + foo(1, x + 1, y, z - 1));\n}\n\nint main()\n{\n\tint i, j, k;\n\tn = get_int();\n\trep(i, n) rep(j, n) rep(k, n) d[0][i][j][k] = d[1][i][j][k] = -1;\n\tint d[2] = {n/2, (n + 1)/2};\n\trep(i, n) a[i] = get_int();\n\trep(i, n) { rep(j, n) if (a[j] == i + 1) break; if (j < n) d[(i + 1)%2]--; }\n\trep(i, n) if (a[i] == 0) a[i] = -1; else a[i] %= 2;\n\tint r = min(foo(0, 0, d[0], d[1]), foo(1, 0, d[0], d[1]));\n\tassert(r < INF);\n\tprintf(\"%d\\n\", r);\n\treturn 0;\n}\n\nint get_string(char* b, char t)\n{\n\tint i = 0; b[i++] = getchar();\n\twhile (b[i - 1] != t) b[i++] = getchar();\n\tb[i - 1] = '\\0';\n\treturn i - 1;\n}\n\nint get_int()\n{\n\tint sgn = 1, ret = 0;\n\tchar c  = getchar();\n\twhile (1)\n\t{\n\t\tif (c == EOF) return EOF;\n\t\tif (c >= '0' && c <= '9') break;\n\t\tif (c == '-')\n\t\t{\n\t\t\tc = getchar();\n\t\t\tif (c < '0' || c > '9') continue;\n\t\t\tsgn = -1;\n\t\t\tbreak;\n\t\t}\n\t\tc = getchar();\n\t}\n\n\twhile (1)\n\t{\n\t\tret = ret*10 + c - '0';\n\t\tc = getchar();\n\t\tif (c < '0' || c > '9') return sgn*ret;\n\t}\n}\n\ndouble get_double()\n{\n\tdouble ret = 0;\n\tchar c     = getchar();\n\tint sgn;\n\n\twhile (1)\n\t{\n\t\tif (c == EOF)\n\t\t{\n\t\t\treturn EOF;\n\t\t}\n\t\tif (c >= '0' && c <= '9')\n\t\t{\n\t\t\tsgn = 1;\n\t\t\tbreak;\n\t\t}\n\t\tif (c == '-')\n\t\t{\n\t\t\tc = getchar();\n\n\t\t\tif (c < '0' || c > '9')\n\t\t\t{\n\t\t\t\tcontinue;\n\t\t\t}\n\n\t\t\tsgn = -1;\n\t\t\tbreak;\n\t\t}\n\t\tc = getchar();\n\t}\n\n\twhile (1)\n\t{\n\t\tret = ret*10 + c - '0';\n\n\t\tc = getchar();\n\n\t\tif (c == '.')\n\t\t{\n\t\t\tdouble pos = 0.1;\n\n\t\t\tc = getchar();\n\t\t\twhile (c >= '0' && c <= '9')\n\t\t\t{\n\t\t\t\tret += pos*(c - '0');\n\t\t\t\tpos /= 10;\n\t\t\t\tc = getchar();\n\t\t\t}\n\n\t\t\treturn sgn*ret;\n\t\t}\n\t\telse if (c < '0' || c > '9')\n\t\t{\n\t\t\treturn sgn*ret;\n\t\t}\n\t}\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dfbf23d6c96606250cce7f2f987fbd31", "src_uid": "90db6b6548512acfc3da162144169dba", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nvoid   caballo (int m[][9], int f, int c)\n{\n/*8 mov tiene el caballo*/\n\n    /*derecha 1 cuadro*/\n  if(c+2<9 && f-1>0)/*9 final del tablero, arriba derecha columna+2*/\n  {\n    m[f-1][c+2]=1;\n\n  }\n    if(c+1<9 && f-2>0)/*9 final del tablero, arriba derecha columna+1*/\n  {\n    m[f-2][c+1]=1;\n  }\n\n  /*abajo derecha*/\n    if(c+1<9 && f+2<9)/*9 final del tablero, arriba derecha colu+1*/\n  {\n    m[f+2][c+1]=1;\n  }\n    if(c+2<9 && f+1<9)/*9 final del tablero, arriba derecha colu+2*/\n  {\n    m[f+1][c+2]=1;\n  }\n\n\n  /*izquierda arriba*/\n    if(c-1>0 && f-2>0)/* arriba del tablero, arriba izquierda fi-2*/\n  {\n    m[f-2][c-1]=1;\n  }\n    if(c-2>0 && f-1>0)/*arriba del tablero, arriba derecha fi-1*/\n  {\n    m[f-1][c-2]=1;\n  }\n\n  /*izquierda abajo*/\n    if(c-1>0 && f+2<9)/*9 final del tablero, arriba derecha fi+2*/\n  {\n    m[f+2][c-1]=1;\n  }\n    if(c-2>0 && f+1<9)/*9 final del tablero, arriba derecha co+1*/\n  {\n    m[f+1][c-2]=1;\n  }\n  /*fin funcion*/\n\n}\n\nvoid torre (int m[][9], int f,int c)\n{\n    int aux;\n\n    /*fila torre llenar de 1s*/\n    for(aux=1; aux<=8; aux++)\n    {\n        m[f][aux]=1;\n    }\n\n        /*fila torre llenar de 1s*/\n    for(aux=1; aux<=8; aux++)\n    {\n        m[aux][c]=1;\n    }\n\n}\n\nvoid inici (int m[][8])\n{\n    int i,j;\n    /*imprimir matriz*/\n    for(i=1; i<9; i++){\n        for(j=1; j<9; j++)\n            m[i][j]=0;\n\n    }\n}\n\nvoid resultado(int m[][9])\n{\n    int i,j,con=0;\n    /*imprimir matriz*/\n    for(i=1; i<9; i++){\n        for(j=1; j<9; j++)\n            if(m[i][j]==0)\n                con++;\n    }\n\n    printf(\"%d\",con);\n}\n\n\nmain()\n{\n\nint ma[9][9]={0};\nint i,j,i2;\nchar c;\n\n\n\n/*primera linea entra torre*/\nscanf(\"%c %d\",&c,&i);\nj=(int)c-'a';\nj++; /*se pasa la letra a numero +1*/\ni=9-i;/*posicion de fila invertida*/\n\ninici(ma);\nma[i][j]=1;/*primera linea*/\n\n/*se colocan 1s para la posicion del caballo y torre*/\ncaballo (ma,i,j);\ntorre (ma,i,j);\n\n/*segunda linea*/\nscanf(\"%1s %d\",&c,&i2); /*guarda un solo caracter en la variable*/\n\nj=(int)c-'a';\nj++; /*se pasa la letra a numero +1*/\ni2=9-i2;/*posicion de fila invertida*/\nma[i2][j]=1;/*primera linea*/\n\n/*se colocan 1s para la posicion del caballo y torre*/\ncaballo (ma,i2,j);\n\n\nresultado(ma);\n\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a6b1c7ce4dbb51a28b9b024c75e2eefb", "src_uid": "073023c6b72ce923df2afd6130719cfc", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#define n 8\n\nchar Tablero[n][n];\nint mov[n][2]={{-1,2},{-2,1},{-2,-1},{-1,-2},{1,-2},{2,-1},{2,1},{1,2}};\nchar columna[8]={'a','b','c','d','e','f','g','h'};\nchar fila[8]={'8','7','6','5','4','3','2','1'};\n\nvoid caminoPieza(char *,char *);\nint recorrerTablero(void);\nint valido(int,int);\n\nint main()\n{\n    char Torre[3],Caballo[3];\n\n    scanf(\"%s\",Torre);\n    scanf(\"%s\",Caballo);\n\n    caminoPieza(&Torre[0],&Caballo[0]);\n    printf(\"%d\",recorrerTablero());\n\n    system(\"PAUSE>NULL\");\n    return 0;\n}\n\nvoid caminoPieza(char *Torre,char *Caballo){\n    int i,j,k;\n\n    for(j=0;j<n;j++){if(columna[j]==Torre[0]){break;}}\n    for(i=0;i<n;i++){if(fila[i]==Torre[1]){break;}}\n    for(k=0;k<n;k++){\n        Tablero[i][k]='*';\n        Tablero[k][j]='*';\n    }\n    Tablero[i][j]='T';\n    for(j=0;j<n;j++){if(columna[j]==Caballo[0]){break;}}\n    for(i=0;i<n;i++){if(fila[i]==Caballo[1]){break;}}\n    Tablero[i][j]='C';\n    for(k=0;k<n;k++){\n        if((i+mov[k][0])>=0 && (i+mov[k][0])<n && (j+mov[k][1])>=0 && (j+mov[k][1])<n && Tablero[i+mov[k][0]][j+mov[k][1]]!='T' && Tablero[i+mov[k][0]][j+mov[k][1]]!='C'){\n            Tablero[i+mov[k][0]][j+mov[k][1]]='*';\n        }\n    }\n}\n\nint recorrerTablero(void){\n    int i,j,cont=0;\n\n    for(i=0;i<n;i++){\n        for(j=0;j<n;j++){\n            if(valido(i,j)==0){\n                cont++;\n            }\n        }\n    }\n    return cont;\n}\n\nint valido(int i,int j){\n    int x,y,k,band=0;\n\n    if(Tablero[i][j]!='*' && Tablero[i][j]!='C' && Tablero[i][j]!='T'){\n        for(k=0;k<n;k++){\n            x=i+mov[k][0];\n            y=j+mov[k][1];\n            if(x>=0 && x<n && y>=0 && y<n && (Tablero[x][y]=='C' || Tablero[x][y]=='T')){\n                band=1;\n            }\n        }\n    }else{\n        band=1;\n    }\n    return band;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "841fd64b53d4d3ba0180f29b06dbbb25", "src_uid": "073023c6b72ce923df2afd6130719cfc", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int x1, y1, x2, y2, tot = 0, c[9][9] = { 0 }, i, j;\n    char a, b;\n    scanf(\" %c%d %c%d\", &a, &y1, &b, &y2);\n    x1 = a - 'a' + 1;\n    x2 = b - 'a' + 1;\n    for(i = 1; i < 9; i++)\n    {\n        c[x1][i] = 1;\n        c[i][y1] = 1;\n    }\n    if(x2 > 1)\n    {\n        if(y2>2)\n        {\n            c[x2-1][y2-2] = 1;\n        }\n        if(y2<7)\n        {\n            c[x2-1][y2+2] = 1;\n        }\n    }\n    if(x2 > 2)\n    {\n        if(y2>1)\n        {\n            c[x2-2][y2-1] = 1;\n        }\n        if(y2<8)\n        {\n            c[x2-2][y2+1] = 1;\n        }\n    }\n    if(x2<8)\n    {\n        if(y2>2)\n        {\n            c[x2+1][y2-2] = 1;\n        }\n        if(y2<7)\n        {\n            c[x2+1][y2+2] = 1;\n        }\n    }\n    if(x2 < 7)\n    {\n        if(y2>1)\n        {\n            c[x2+2][y2-1] = 1;\n        }\n        if(y2<8)\n        {\n            c[x2+2][y2+1] = 1;\n        }\n    }\n    if(x1 > 1)\n    {\n        if(y1>2)\n        {\n            c[x1-1][y1-2] = 1;\n        }\n        if(y1<7)\n        {\n            c[x1-1][y1+2] = 1;\n        }\n    }\n    if(x1 > 2)\n    {\n        if(y1>1)\n        {\n            c[x1-2][y1-1] = 1;\n        }\n        if(y1<8)\n        {\n            c[x1-2][y1+1] = 1;\n        }\n    }\n    if(x1<8)\n    {\n        if(y1>2)\n        {\n            c[x1+1][y1-2] = 1;\n        }\n        if(y1<7)\n        {\n            c[x1+1][y1+2] = 1;\n        }\n    }\n    if(x1 < 7)\n    {\n        if(y1>1)\n        {\n            c[x1+2][y1-1] = 1;\n        }\n        if(y1<8)\n        {\n            c[x1+2][y1+1] = 1;\n        }\n    }\n    c[x2][y2] = 1;\n    for(i = 1; i<9; i++)\n        for(j = 1; j<9; j++)\n            if(c[i][j] == 0)\n                tot ++;\n    printf(\"%d\", tot);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e4c683ab373a0871d6d1ff4fe4a34d5f", "src_uid": "073023c6b72ce923df2afd6130719cfc", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "//void imprimir();\nvoid inicializar();\nvoid posiciones(char pieza[],int *fila,int *columna);\nvoid movimientoTorre(int x,int y);\nvoid movimientoCaballo(int x,int y);\nint recorrer();\n\nint a[8] = { 2, 1,-1,-2,-2,-1, 1, 2};\nint b[8] = {-1,-2,-2,-1, 1, 2, 2, 1};\n\nchar letras[9]=\"aabcdefgh\";\nchar numeros[9]=\"112345678\";\nint tablero[N][N];\n\nint main(){\n    char caballo[2];\n    char torre[2];\n    int filaT=0,columnaT=0;\n    int filaC=0,columnaC=0,mov;\n    inicializar();\n\n    scanf(\"%s\",&torre);\n    scanf(\"%s\",&caballo);\n\n    posiciones(torre,&filaT,&columnaT);\n    posiciones(caballo,&filaC,&columnaC);\n\n    movimientoCaballo(filaC,columnaC);\n    //imprimir();\n    movimientoTorre(filaT,columnaT);\n    //imprimir();\n    movimientoCaballo(filaT,columnaT);\n    mov=recorrer();\n    printf(\"%d\",mov);\n    return 0;\n}\nvoid movimientoTorre(int x,int y){\n    int i;\n    for(i=1;i<N;i++){\n            tablero[x][i]=MarcaT;\n            tablero[i][y]=MarcaT;\n    }\n}\nvoid movimientoCaballo(int x,int y){\n    int i,t,v;\n    tablero[x][y]=MarcaC;\n    for ( i=0; i<8; i++ ) {\n        t=x+a[i];\n        v=y+b[i];\n        if(t>0 && t<N && v>0 && v<N){\n            tablero[t][v]=MarcaC;\n        }\n    }\n}\nvoid posiciones(char pieza[],int *fila,int *columna){\n    int i;\n    for(i=1;i<N;i++){\n        if(pieza[0]==letras[i]){\n            *fila=i;\n        }\n        if(pieza[1]==numeros[i]){\n            *columna=i;\n        }\n    }\n}\nvoid inicializar(){\n    int i,j;\n    for(i=0;i<N;i++){\n        for(j=0;j<N;j++){\n            tablero[i][j]=0;\n        }\n    }\n}\nint recorrer(){\n    int i,j,mov=0;\n    for(i=1;i<N;i++){\n        for(j=1;j<N;j++){\n            if(tablero[i][j]==0)\n                mov++;\n        }\n    }\n    return mov;\n}\n/*void imprimir(){\n    int i,j;\n    printf(\"\\n\");\n    for(i=1;i<N;i++){\n        for(j=1;j<N;j++){\n           printf(\"%d\",tablero[i][j]);\n        }\n        printf(\"\\n\");\n    }\n}\n*/\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d39ab2cf1e5281f2e864a8f1c4fc4d3e", "src_uid": "073023c6b72ce923df2afd6130719cfc", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nchar piece[4];\n\nint rx, ry, kx, ky;\n\nint abs(int a){ return a < 0 ? -a : a; }\n\nint ok(int x, int y){\n    int dx = abs(x - kx), dy = abs(y - ky);\n    if(abs(dx - dy) == 1 && dx + dy == 3) return 0;\n    dx = abs(x - rx), dy = abs(y - ry);\n    if(abs(dx - dy) == 1 && dx + dy == 3) return 0;\n    return x != rx && y != ry && (x != kx || y != ky);\n}\n\nint main(){\n    int ans = 0, i, j;\n    scanf(\"%s\", piece); rx = piece[0] - 'a', ry = piece[1] - '1';\n    scanf(\"%s\", piece); kx = piece[0] - 'a', ky = piece[1] - '1';\n    for( i = 0; i < 8; ++i){\n        for( j = 0; i < 8; ++j){\n            ans += ok(i,j);\n        }\n    }\n    printf(\"%d\\n\", ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c4940900e6cf21608647dc8cc633437f", "src_uid": "073023c6b72ce923df2afd6130719cfc", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nlong long fac[250005];\n\nint main()\n{\n    int n, m;\n    long long ans = 0;\n    scanf(\"%d%d\", &n, &m);\n\n    fac[0] = 1;\n    for(int i = 1; i <= n; i++){\n        fac[i] = (fac[i - 1] * i) % m;\n    }\n\n    for(int i = 0; i < n; i++){\n        ans += (fac[i + 1] * fac[n - i]) % m;\n        ans %= m;\n    }\n\n    ans = (ans * (n + 1)) % m;\n    if(ans % 2 == 1) ans = (ans + m) / 2;\n    else ans /= 2;\n\n    printf(\"%I64d\", ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "332f363b51e6e485156a2568d03d06db", "src_uid": "020d5dae7157d937c3f58554c9b155f9", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n\tlong long int i,j,k=0,n,m,s=0;\n\tlong long int fact[250001];\n\tfact[1]=1;fact[0]=1;\n\tscanf(\"%lld%lld\",&n,&m);\n\tfor(i=2;i<=250000;i++)\n\tfact[i]=(fact[i-1]*i)%m;\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tk=k+(n-i+1)*(fact[i]*fact[n-i+1]%m);\n\t\tk=k%m;\n\t}\n\tprintf(\"%lld\",k);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "fa99001adcf54924bb5239ac5f43be13", "src_uid": "020d5dae7157d937c3f58554c9b155f9", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tlong long int n, m;\n\tscanf(\"%lld %lld\", &n, &m);\n\tlong long int fact[2500006];\n\tlong long int i;\n\tfact[0] = 1;\n\tfor (i = 1; i < 2500006; i++)\n\t\tfact[i] = fact[i - 1] * i % m;\n\tlong long int ans = 0;\n\tfor (i = 0; i < n; i++)\n\t\tans = (ans + (n - i) * fact[i + 1] % m * fact[n - i] % m) % m;\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "08c5fa325eab99694e1837f2331b9801", "src_uid": "020d5dae7157d937c3f58554c9b155f9", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nlong long fac[250005];\n\nint main()\n{\n    int n, m;\n    long long ans = 0;\n    scanf(\"%d%d\", &n, &m);\n\n    fac[0] = 1;\n    for(int i = 1; i <= n; i++){\n        fac[i] = (fac[i - 1] * i) % m;\n    }\n\n    for(int i = 0; i < n; i++){\n        ans += (fac[i + 1] * fac[n - i]) % m;\n        ans %= m;\n    }\n\n    ans = (ans * (n + 1)) % m;\n    if(ans % 2 == 1) ans = (ans + m) / 2;\n\n    printf(\"%I64d\", ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d4beb564d5154d02efccf91a325918ba", "src_uid": "020d5dae7157d937c3f58554c9b155f9", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define F for(i=1;i<=n;i++)\nlong long i,j,m,n,r,f[250107]={1};\nint main(){\n\tscanf(\"%lli%lli\",&n,&m);\n\tF f[i]=f[i-1]*i%m;\n\tF r=(r+f[i]*f[n-i+1]%m*(n-i+1)%m)%m;\n\treturn printf(\"%lli\",r);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "196ccac346fa775852ed691237bec4f1", "src_uid": "020d5dae7157d937c3f58554c9b155f9", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint isright(long long v,long long k,long long n)\n{\n    long long sum=v;\n    long  long value =v/k;\n    while(value!=0)\n    {\n        sum+=value;\n        value=value/k;\n    }\n    if (sum==n)\n    {\n        return 1;\n    }\n\n    else if (sum>n)\n    {\n        return 2;\n\n    }\n\n    return 0;\n}\n\n\n\n\nint main()\n{\n\n    long long  lines;\n    long long low=0,mid=0,value,min=1,high;\n    int k;\n  scanf(\"%I64d\",& lines);\n    scanf(\"%d\",&k);\n    high=lines;\n    while(low<high)\n    {\n        mid=(low+high)/2;\n        value=isright(mid,k,lines);\n        if(value==1)\n        {\n            min=mid;\n            break;\n        }\n        else if (value==0)\n        {\n            low=mid+1;\n            mi=low;\n        }\n        else if (value==2)\n        {\n            min=mid;\n            high=mid;\n        }\n\n    }\n    printf(\"%I64d\",min);\n    return 0;\n}\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "62585fef0eee3340ae810e6a59779f3b", "src_uid": "41dfc86d341082dd96e089ac5433dc04", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "/* Coached by rainboy */\n#include <stdio.h>\n\nint lines(int n, int k) {\n\treturn n == 0 ? 0 : lines(n / k, k) + n;\n}\n\nint binsearch(int n, int k) {\n\tint lower, upper, v;\n\n\tlower = 0, upper = n;\n\twhile (upper - lower > 1) {\n\t\tv = (low + high) / 2;\n\t\tif (lines(v, k) < n)\n\t\t\tlower = v;\n\t\telse\n\t\t\tupper = v;\n\t}\n\treturn upper;\n}\n\nint main() {\n\tint n, k;\n\n\tscanf(\"%d%d\", &n, &k);\n\tprintf(\"%d\\n\", binsearch(n, k));\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4515febc7f5f80ff23cf145a09fb7522", "src_uid": "41dfc86d341082dd96e089ac5433dc04", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n    int k ;\n    long long n , ans;\n    cin >> n >> k;\n    ans = ((n * (k - 1) / k ) / k + 1) * k;\n    cout << ans ;\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "54859dd68fd696fc2c813800e7a0f04d", "src_uid": "41dfc86d341082dd96e089ac5433dc04", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint n, k, v, i, sum;\n\tscanf(\"%d%d\", &n, &k);\n\tv = n * (k - 1) / k;\n\tdo\n\t{\n\t\tsum = 0;\n\t\ti = 1;\n\t\twhile (v / i > 0)\n\t\t{\n\t\t\tsum += v / i;\n\t\t\ti *= k;\n\t\t}\n\t\tif (sum < n)\n\t\t\t++v;\n\t\telse\n\t\t\tbreak;\n\t}\n\twhile (1);\n\tprintf(\"%d\\n\", v);\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ea57d4d9ebf78c3462431c3b7fffda92", "src_uid": "41dfc86d341082dd96e089ac5433dc04", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    int n,k;\n    scanf(\"%d%d\",&n,&k);\n    int temp1,i,temp,sum=0,ans=0;\n    int p=1;\n    for(i=n;i>=1;i--)\n    {\n                     p=0;\n                     sum=0;\n    temp=i;\n    ans=temp;\n    temp1=i;\n    while(temp1>0)\n    {\n   \n     sum+=temp1;\n     p++;\n     //printf(\"for %d : %d\\n\",p,sum);\n       temp1=temp/(int)pow(k,p);\n     }\n     if(sum<n)\n     {\n              //printf(\"%d\\n\",sum);\n     break;\n     }\n     }\n     printf(\"%d\\n\",i+1);\n     //getch();\n     return 0;\n     }   ", "lang_cluster": "C", "compilation_error": false, "code_uid": "5cbc6817f17ebbd05086effd4f56c0aa", "src_uid": "41dfc86d341082dd96e089ac5433dc04", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#define _USE_MATH_DEFINES\n#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#include <string.h>\n#include <ctype.h>\n#include <stdbool.h>\n#include <float.h>\n#include <limits.h>\n#include <malloc.h>\n#include <memory.h>\n#include <complex.h>\n#include <errno.h>\n#include <time.h>\nint i,d[25],f[25],l;\nlong long a[25],ans;\nchar s[25];\n\nvoid dfs(int x)\n{\n\tint i,sum;\n\tlong long res;\n\t\n\tif (x>=10)\n\t{\n\t\tfor (i=0,sum=0;i<=9;i++) sum+=d[i];\n\t\tres=(long long) a[sum-1]*(sum-d[0]);\n\t\tfor (i=0;i<=9;i++) res/=a[d[i]];\n\t\tans+=res;\n\t\treturn;\n\t}\n\tif (!f[x]) dfs(x+1);\n\telse\n\t{\n\t\tfor (i=1;i<=f[x];i++) \n\t\t{\n\t\t\td[x]=i;\n\t\t\tdfs(x+1);\n\t\t}\n\t}\n}\n\nint main()\n{\n\tmemset(f,0,sizeof(f));\n\tmemset(d,0,sizeof(d));\n\tscanf(\"%s\",s);\n\tl=strlen(s);\n\tfor (i=ans=0;i<l;i++) f[s[i]-'0']++;\n\tfor (i=1,a[0]=1;i<=20;i++) a[i]=(long long) a[i-1]*i;\n\tdfs(0);\n\tprintf(\"%lld\\n\",ans);\n\treturn 0;\n}\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f30a2f1bb299f757fa03d815dfb33081", "src_uid": "7f4e533f49b73cc2b96b4c56847295f2", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define\tLLD\t\"%lld\"\nint n,l;\nint x[10];\nint w[10];\nlong long dp[10][21];\nlong long c[21][21];\nvoid init(){\n\tint i,j;\n\tfor(i=1;i<=20;i++){\n\t\tc[i][0]=1;\n\t\tc[i][i]=1;\n\t}\n\tfor(i=2;i<=20;i++){\n\t\tfor(j=1;j<i;j++){\n\t\t\tc[i][j]=c[i-1][j-1]+c[i-1][j];\n\t\t}\n\t}\n}\nvoid run(){\n\tint i,j,k;\n\tlong long r;\n\tinit();\n\twhile(scanf(LLD,&n)!=EOF){\n\t\tfor(i=0;i<10;i++){\n\t\t\tx[i]=0;\n\t\t}\n\t\tfor(;n>0;n/=10){\n\t\t\tx[n%10]++;\n\t\t}\n\t\tl=0;\n\t\tfor(i=1;i<10;i++){\n\t\t\tif(x[i]>0){\n\t\t\t\tw[l++]=x[i];\n\t\t\t}\n\t\t}\n\t\tfor(i=0;i<10;i++){\n\t\t\tfor(j=0;j<=20;j++){\n\t\t\t\tdp[i][j]=0;\n\t\t\t}\n\t\t}\n\t\tfor(i=1;i<=w[0];i++){\n\t\t\tdp[0][i]=1;\n\t\t}\n\t\tfor(i=1;i<l;i++){\n\t\t\tfor(j=1;j<=20;j++){\n\t\t\t\tfor(k=1;k<=w[i]&&k<=j;k++){\n\t\t\t\t\tdp[i][j]+=dp[i-1][j-k]*c[j-k+k][j-k];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(x[0]>0){\n\t\t\tl++;\n\t\t\tfor(j=2;j<=20;j++){\n\t\t\t\tfor(k=1;k<=x[0]&&k<=j-1;k++){\n\t\t\t\t\tdp[i][j]+=dp[i-1][j-k]*c[j-1-k+k][j-1-k];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tr=0;\n\t\tfor(i=0;i<=20;i++){\n\t\t\tr+=dp[l-1][i];\n\t\t}\n\t\tprintf(LLD\"\\n\",r);\n\t}\n}\nmain(){\n#ifndef\tONLINE_JUDGE\n\tfreopen(\"4912e_min.in\",\"rb\",stdin);\n\tfreopen(\"4912e_.out\",\"wb\",stdout);\n#endif\n\trun();\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0f73bce61200812f4f7d161db4f5a8a0", "src_uid": "7f4e533f49b73cc2b96b4c56847295f2", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define\tLLD\t\"%lld\"\nint n,l;\nint x[10];\nint w[10];\nlong long dp[10][21];\nlong long c[21][21];\nvoid init(){\n\tint i,j;\n\tfor(i=1;i<=20;i++){\n\t\tc[i][0]=1;\n\t\tc[i][i]=1;\n\t}\n\tfor(i=2;i<=20;i++){\n\t\tfor(j=1;j<i;j++){\n\t\t\tc[i][j]=c[i-1][j-1]+c[i-1][j];\n\t\t}\n\t}\n}\nvoid run(){\n\tint i,j,k;\n\tlong long r;\n\tinit();\n\twhile(scanf(LLD,&n)!=EOF){\n\t\tfor(i=0;i<10;i++){\n\t\t\tx[i]=0;\n\t\t}\n\t\tfor(;n>0;n/=10){\n\t\t\tx[n%10]++;\n\t\t}\n\t\tl=0;\n\t\tfor(i=1;i<10;i++){\n\t\t\tif(x[i]>0){\n\t\t\t\tw[l++]=x[i];\n\t\t\t}\n\t\t}\n\t\tfor(i=0;i<10;i++){\n\t\t\tfor(j=0;j<=20;j++){\n\t\t\t\tdp[i][j]=0;\n\t\t\t}\n\t\t}\n\t\tfor(i=1;i<=w[0];i++){\n\t\t\tdp[0][i]=1;\n\t\t}\n\t\tfor(i=1;i<l;i++){\n\t\t\tfor(j=i+1;j<=20;j++){\n\t\t\t\tfor(k=1;k<=w[i]&&j-k>=i;k++){\n\t\t\t\t\tdp[i][j]+=dp[i-1][j-k]*c[j-k+k][j-k];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(x[0]>0){\n\t\t\tl++;\n\t\t\tfor(j=i+1;j<=20;j++){\n\t\t\t\tfor(k=1;k<=x[0]&&j-k>=i;k++){\n\t\t\t\t\tdp[i][j]+=dp[i-1][j-k]*c[j-1-k+k][j-1-k];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tr=0;\n\t\tfor(i=0;i<=20;i++){\n\t\t\tr+=dp[l-1][i];\n\t\t}\n\t\tprintf(LLD\"\\n\",r);\n\t}\n}\nmain(){\n#ifndef\tONLINE_JUDGE\n\tfreopen(\"4912e_min.in\",\"rb\",stdin);\n\tfreopen(\"4912e_.out\",\"wb\",stdout);\n#endif\n\trun();\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8746b51c33be95e458e36fc551bc704b", "src_uid": "7f4e533f49b73cc2b96b4c56847295f2", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\nlong long fact(long long int n)\n{\n    long long int ans = 1;\n    for (long long int i = 2; i<=n; i++)\n        ans*=i;\n    return ans;\n}\n\nint main()\n{\n    int h[10] = {},f[10] = {},p,f0,fn0;\n    long long int n,temp,ctr = 0;\n    scanf(\"%I64d\",&n);\n    while(n>0)\n    {\n        h[n%10]++;\n        n/=10;\n    }\n    while (1)\n    {\n        f0 = 0, fn0 = 0,p = 9;\n        f[9]++;\n        while(f[p] > h[p] && p>0)\n        {\n            f[p] = 0;\n            f[--p]++;\n        }\n        if (f[0] > h[0])\n            break;\n        f0 = f[0];\n        for (int i = 1; i<10; i++)\n            fn0+=f[i];\n        temp = fn0 * fact(fn0 + f0 -1);\n        for (int i = 0; i<10; i++)\n        {\n            temp/=(f[i] > 0)?f[i] : 1;\n        }\n        ctr+=temp;\n    }\n    printf(\"%I64d\",ctr);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "55ff613c9c9208bb2bfbd2635fdd5f97", "src_uid": "7f4e533f49b73cc2b96b4c56847295f2", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#define _USE_MATH_DEFINES\n#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#include <string.h>\n#include <ctype.h>\n#include <stdbool.h>\n#include <float.h>\n#include <limits.h>\n#include <malloc.h>\n#include <memory.h>\n#include <complex.h>\n#include <errno.h>\n#include <time.h>\nint i,d[25],f[25],l;\nlong long a[25],ans;\nchar s[25];\n\nvoid dfs(int x)\n{\n\tint i,sum;\n\tlong long res;\n\t\n\tif (x>=10)\n\t{\n\t\tfor (i=0,sum=0;i<=9;i++) sum+=d[i];\n\t\tres=(long long) a[sum-1]*(sum-d[0]);\n\t\tfor (i=0;i<=9;i++) \n\t\tif (d[i]) res/=d[i];\n\t\tans+=res;\n\t\treturn;\n\t}\n\tif (!f[x]) dfs(x+1);\n\telse\n\t{\n\t\tfor (i=1;i<=f[x];i++) \n\t\t{\n\t\t\td[x]=i;\n\t\t\tdfs(x+1);\n\t\t}\n\t}\n}\n\nint main()\n{\n\tmemset(f,0,sizeof(f));\n\tmemset(d,0,sizeof(d));\n\tscanf(\"%s\",s);\n\tl=strlen(s);\n\tfor (i=ans=0;i<l;i++) f[s[i]-'0']++;\n\tfor (i=2,a[1]=1;i<=20;i++) a[i]=(long long) a[i-1]*i;\n\tdfs(0);\n\tprintf(\"%lld\\n\",ans);\n\treturn 0;\n}\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6f01129b7cd28c9cf82b0981fded4496", "src_uid": "7f4e533f49b73cc2b96b4c56847295f2", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MD\t1000000007\n\nint power(int a, int b) {\n\tint p;\n\n\tif (b == 0)\n\t\treturn 1;\n\tp = power(a, b / 2);\n\tp = (long long) p * p % MD;\n\tif (b % 2 == 1)\n\t\tp = (long long) p * a % MD;\n\treturn p;\n}\n\nint solve(int x) {\n\treturn power(2, x - 1);\n}\n\nint sign(int x) {\n\tint a, cnt;\n\n\tcnt = 0;\n\tfor (a = 2; a * a <= x; a++) {\n\t\tif (x % a == 0) {\n\t\t\tx /= a;\n\t\t\tcnt++;\n\t\t}\n\t\tif (x % a == 0)\n\t\t\treturn 0;\n\t}\n\tif (x > 1)\n\t\tcnt++;\n\treturn cnt % 2 == 0 ? 1 : -1;\n}\n\nint main() {\n\tint x, y, a, sum;\n\n\tscanf(\"%d%d\", &x, &y);\n\tif (y % x != 0) {\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\ty /= x;\n\tsum = 0;\n\tfor (a = 1; a * a <= y; a++)\n\t\tif (y % a == 0) {\n\t\t\tsum = ((long long) sum + (sign(a) * solve(y / a) % MD) + MD) % MD;\n\t\t\tif (y / a != a)\n\t\t\t\tsum = ((long long) sum + (sign(y / a) * solve(a)) + MD) % MD;\n\t\t}\n\tprintf(\"%d\\n\", sum);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "339e16427ae945ce3671b6d282fea1bf", "src_uid": "de7731ce03735b962ee033613192f7bc", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdint.h>\n#include <stdio.h>\n\n#define MODULUS 1000000007\n#define _       % MODULUS\n\n#define MAX_RG  76543\n#define MAX_PR  7654\n\nint prime_ct = 0, primes[MAX_PR];\nunsigned char not_prime[MAX_RG] = { 0 };\n\nvoid sieve()\n{\n    int i, j;\n    not_prime[0] = not_prime[1] = 1;\n    for (i = 2; i < MAX_RG; ++i) {\n        if (!not_prime[i]) primes[prime_ct++] = i;\n        for (j = 0; j < prime_ct && i * primes[j] < MAX_RG; ++j)\n            not_prime[i * primes[j]] = 1;\n    }\n}\n\nint mu(int n)\n{\n    int i, ret = 1;\n    for (i = 0; i < prime_ct; ++i) {\n        if (n % primes[i] == 0) {\n            n /= primes[i];\n            ret = -ret;\n            if (n % primes[i] == 0) return 0;\n        }\n    }\n    if (n > 1) ret = -ret;\n    return ret;\n}\n\nint qpow(int base, int exp)\n{\n    int ans = 1;\n    for (; exp; exp >>= 1, base = ((int64_t)base * base)_)\n        if (exp & 1) ans = ((int64_t)ans * base)_;\n    return ans;\n}\n\nint count_seqs(int sum, int gcd_mul)\n{\n    if (sum % gcd_mul != 0) return 0;\n    return qpow(2, sum / gcd_mul - 1);\n}\n\nint main()\n{\n    int x, y;\n    scanf(\"%d%d\", &x, &y);\n\n    if (y % x != 0) { puts(\"0\"); return 0; }\n    y /= x;\n\n    sieve();\n\n    int64_t ans = 0;\n    int i;\n    for (i = 1; i * i <= y; ++i) if (y % i == 0) {\n        ans += count_seqs(y, i) * mu(i);\n        if (i * i != y)\n            ans += count_seqs(y, y / i) * mu(y / i);\n    }\n\n    printf(\"%I64d\\n\", (ans _ + MODULUS)_);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "490d1dabbc33ffcce33cd6359bfbb07f", "src_uid": "de7731ce03735b962ee033613192f7bc", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MD\t1000000007\n\nint power(int a, int b) {\n\tint p;\n\n\tif (b == 0)\n\t\treturn 1;\n\tp = power(a, b / 2);\n\tp = (long long) p * p % MD;\n\tif (b % 2 == 1)\n\t\tp = (long long) p * a % MD;\n\treturn p;\n}\n\nint solve(int x) {\n\treturn (power(2, x - 1) + MD) % MD;\n}\n\nint sign(int x) {\n\tint a, cnt;\n\n\tcnt = 0;\n\tfor (a = 2; a * a <= x; a++) {\n\t\tif (x % a == 0) {\n\t\t\tx /= a;\n\t\t\tcnt++;\n\t\t}\n\t\tif (x % a == 0)\n\t\t\treturn 0;\n\t}\n\tif (x > 1)\n\t\tcnt++;\n\treturn cnt % 2 == 0 ? 1 : -1;\n}\n\nint main() {\n\tint x, y, a, sum;\n\n\tscanf(\"%d%d\", &x, &y);\n\tif (y % x != 0) {\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\ty /= x;\n\tsum = 0;\n\tfor (a = 1; a * a <= y; a++)\n\t\tif (y % a == 0) {\n\t\t\tsum = (sum + (sign(a) * solve(y / a)) + MD) % MD;\n\t\t\tsum = (sum + (sign(y / a) * solve(a)) + MD) % MD;\n\t\t}\n\tprintf(\"%d\\n\", sum);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4984f187d3f8b927d7e91e76e3fd1189", "src_uid": "de7731ce03735b962ee033613192f7bc", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MD\t1000000007\n\nint power(int a, int b) {\n\tint p;\n\n\tif (b == 0)\n\t\treturn 1;\n\tp = power(a, b / 2);\n\tp = (long long) p * p % MD;\n\tif (b % 2 == 1)\n\t\tp = (long long) p * a % MD;\n\treturn p;\n}\n\nint solve(int x) {\n\treturn power(2, x - 1);\n}\n\nint sign(int x) {\n\tint a, cnt;\n\n\tcnt = 0;\n\tfor (a = 2; a * a <= x; a++) {\n\t\tif (x % a == 0) {\n\t\t\tx /= a;\n\t\t\tcnt++;\n\t\t}\n\t\tif (x % a == 0)\n\t\t\treturn 0;\n\t}\n\tif (x > 1)\n\t\tcnt++;\n\treturn cnt % 2 == 0 ? 1 : -1;\n}\n\nint main() {\n\tint x, y, a, sum;\n\n\tscanf(\"%d%d\", &x, &y);\n\tif (y % x != 0) {\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\ty /= x;\n\tsum = 0;\n\tfor (a = 1; a * a <= y; a++)\n\t\tif (y % a == 0) {\n\t\t\tsum = (sum + (sign(a) * solve(y / a) % MD) + MD) % MD;\n\t\t\tif (y / a != a)\n\t\t\t\tsum = (sum + (sign(y / a) * solve(a) % MD) + MD) % MD;\n\t\t}\n\tprintf(\"%d\\n\", sum);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "acb4d9f2d0970366ff87bbe648e58563", "src_uid": "de7731ce03735b962ee033613192f7bc", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#pragma region kyopuro_templates\n#pragma GCC optimize(\"Ofast\")\n#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#include<stdbool.h>\n#include<assert.h>\n#include<time.h>\n#include<ctype.h>\ntypedef long long ll;\ntypedef long double ld;\n#define rep(i,l,r)for(ll i=(l);i<(r);i++)\n#define repp(i,l,r,k)for(ll i=(l);i<(r);i+=(k))\n#define rrep(i,l,r)for(ll i=(l);i>=(r);i--)\n#define INF (1LL<<62)\n#define MOD1 1000000007\n#define MOD2 998244353\n#define MAX_N (1 << 20)\n#define YES printf(\"Yes\\n\")\n#define NO printf(\"No\\n\")\n#define PN printf(\"\\n\")\n#define charsize 100005 //10^5+5\n#define PI 3.141592653589793238\n\nvoid swap(ll *a, ll *b){ll c;c=*b;*b=*a;*a= c;}\nvoid cin(ll *n){ scanf(\"%lld\",&(*n)); }\nvoid PriAll1(ll a[], ll n){ rep(i,0,n){ printf(\"%lld\",a[i]); if(i!=n-1) printf(\" \"); }PN; }\nll min(ll a, ll b){ return a < b ? a : b; }\nll max(ll a, ll b){ return a < b ? b : a; }\n// ll max2(ll a,ll b){return a>=b?a:b;}\n// ll min2(ll a,ll b){return a>=b?b:a;}\nll min3(ll a, ll b, ll c){return (a<=b && a<=c) ? a : b<=c ? b : c;}\nll max3(ll a, ll b, ll c){return (a>=b && a>=c) ? a : b>=c ? b : c;}\nll minn(ll n, ll a[]){ll b=INF;rep(i,0,n) b=min(b,a[i]);return b;}\nll maxn(ll n, ll a[]){ll b=-INF;rep(i,0,n) b=max(b,a[i]);return b;}\nll POW(ll a, ll b){ll c=1;rep(i,0,b) c*=a;return c;}\ndouble POW_d(double a, double b){double c=1;rep(i,0,b) c*=a;return c;}\nll gcd(ll a,ll b){return b?gcd(b,a%b):a;}\nll lcm(ll a,ll b){return a/gcd(a,b)*b;}\nll mod_MOD1(ll n){n+= n<0?((-n)/MOD1+1)*MOD1:0; return n%=MOD1;}\nll mod_p(ll n ,ll p){n+= n<0?((-n)/p+1)*p:0; return n%=p;}\nll change_into_num(char s[] , ll len, ll p){ return !p ? 0 : POW(10,p-1)*(s[len-p]-'0') + change_into_num(s,len,p-1); }\nll digits(ll a, ll b){return a/b?1+digits(a/b,b):1;}\nll base(ll n, ll a, ll i){return i==1?n%a:base(n/a,a,i-1);}\nll is_inArr1(ll x, ll n){ return ( x<0 || x>=n ) ? 0 : 1 ; }\nll is_inArr2(ll y, ll x, ll h, ll w){ return ( y<0 || y>=h || x<0 || x>=w ) ? 0 : 1 ; }\n\n\nvoid lr_lower( int *l, int *r, ll am, ll val , int type ){ (type<3) ? ( am < val ?  ( *l = (*l+*r)/2 ) : ( *r= (*l+*r)/2 ) ) : ( am <= val ? ( *l = (*l+*r)/2 ) : ( *r= (*l+*r)/2 ) ); }\nvoid lr_upper( int *l, int *r, ll am, ll val , int type ){ (type<3) ? ( am <= val ?  ( *l = (*l+*r)/2 ) : ( *r= (*l+*r)/2 ) ) : ( am < val ? ( *l = (*l+*r)/2 ) : ( *r= (*l+*r)/2 ) ); }\nint cmp_lower( ll a, ll b, int type ){ return (type==1) ? ( a==b ? 1 : 0 ) : (type==2) ? ( a>=b ? 1 : 0 ) : ( a>b ? 1 : 0 ) ; }\nint cmp_upper( ll a, ll b, int type ){ return (type==1) ? ( a==b ? 1 : 0 ) : (type==2) ? ( a<=b ? 1 : 0 ) : ( a<b ? 1 : 0 ) ; }\n// return smallest p  which meets  a[p]==val :1  >=:2   >:3\nll lower_bound( ll a[], int l, int r, ll val , int type ){  while(r-l>1) lr_lower(&l,&r,a[ (l+r)/2 ],val,type);  return cmp_lower(a[l],val,type) ? l : cmp_lower(a[r],val,type) ? r : -1;  }\n// return biggest p  which meets   a[p]==val :1  <=:2   <:3\nll upper_bound( ll a[], int l, int r, ll val , int type ){  while(r-l>1) lr_upper(&l,&r,a[ (l+r)/2 ],val,type); return cmp_upper(a[r],val,type) ? r : cmp_upper(a[l],val,type) ? l : -1; }\n// count i  which meets ai==x\nll count(ll a[], int l, int r, ll x){  int p = lower_bound(a,l,r,x,1);  return p==-1 ? 0 : upper_bound(a,p,r,x,1)-p+1; }\n\nll *factors[2] , fac_cnt=0 , is_factor_prepared=0;\nll factor_pre(){  rep(i,0,1){ if(is_factor_prepared++) return 0; }  ll tmp=(1e6)/2+1, fac_tmp[tmp];  rep(i,0,tmp){fac_tmp[i]=i?2*i+1:2;}  rep(i,1,tmp){if(fac_tmp[i]){  repp(j,3,tmp/(2*i+1)+1,2 ){  if( j*(2*i+1)<tmp ) fac_tmp[ (j*(2*i+1)-1)/2 ]=0;  }  }else continue;}  rep(i,0,tmp){if(fac_tmp[i]){  rep(j,0,2){ factors[j] = (ll*) realloc( factors[j] , sizeof(ll)*( fac_cnt +1 ) );  factors[j][j?fac_cnt++:fac_cnt]=j?0:fac_tmp[i];  }  } }  return 0;  }\nll factor(ll n, ll new_common_plus){ factor_pre();  rep(i,0,fac_cnt){ ll cnt=0; rep(j,0,1){ while( ( cnt+= n %factors[0][i]==0 ? 1 : 0 )  && (n/=factors[0][i]) %factors[0][i]==0 ) continue; } factors[1][i]= new_common_plus==1 ? cnt :  new_common_plus==2 ? max(factors[1][i],cnt) : factors[1][i]+cnt ;  if( factors[0][i]> n ) break; } return n; }\nll judge_prime(ll n){ factor_pre(); rep(i,0,fac_cnt){ if(n<factors[0][i]*factors[0][i] || n==factors[0][i]) break; else if(n%factors[0][i]==0) n/=n; }  return n==1?0:1; }\n\n#pragma region mod\nll *mf_arr, *inv_arr, *finv_arr, is_minv_made, is_mf_made, num_of_inv=3*1e5+10;\nvoid makeinv(ll n , ll mod){  \n    if(is_minv_made++) return;\n    inv_arr = (ll*) malloc((n + 1) * sizeof(ll));\n    finv_arr = (ll*) malloc((n + 1) * sizeof(ll));\n    inv_arr[1] = finv_arr[0] = finv_arr[1] = 1;\n    rep(i,2,n+1){ \n        inv_arr[i] = mod - inv_arr[mod % i] * (mod / i) % mod;\n        finv_arr[i] = finv_arr[i - 1] * inv_arr[i] % mod;  \n    }  \n}\nvoid make_mf(ll n, ll mod){\n    if(is_mf_made++) return;\n    mf_arr = (ll*) malloc((n + 1) * sizeof(ll));\n    ll x = mf_arr[0] = mf_arr[1] = 1;\n    rep(i,2,n+1){\n        x = x * i % mod;\n        mf_arr[i]=x;\n    }\n}\nll m_inv(ll x, ll mod, ll is_fac){ makeinv(num_of_inv, mod);  return is_fac ? finv_arr[x] : inv_arr[x]; }\nll m_f(ll x, ll mod){ make_mf(num_of_inv, mod);  return mf_arr[x]; }\nll mod_nck(ll n, ll k, ll mod){ return m_f(n, mod) * m_inv(k, mod, 1) % mod * m_inv(n-k, mod, 1) % mod; }\nll m_p(ll r, ll n, ll mod){\n    ll t = 1, s = r;\n    while(n > 0){ \n        t = (n & 1) ? t * s % mod : t;\n        s = s * s % mod;\n        n >>= 1;\n    } \n    return r ? t : 0;\n}\n#pragma endregion mod\n\n\nint upll(const void*a, const void*b){return*(ll*)a<*(ll*)b?-1:*(ll*)a>*(ll*)b?1:0;}\nint downll(const void*a, const void*b){return*(ll*)a<*(ll*)b?1:*(ll*)a>*(ll*)b?-1:0;}\nint cmp_string( const void * a , const void * b ) {  return strcmp( (char *)a , (char *)b ); }  // qsort((void*)s,n,sizeof(s[0]),int_sort );\nint cmp_char(const void * a, const void * b) { return *(char *)a - *(char *)b;}\nvoid sortup(ll*a,int n){qsort(a,n,sizeof(ll),upll);}\nvoid sortdown(ll*a,int n){qsort(a,n,sizeof(ll),downll);}\n// void sort_string(int n,int size,char s[][size]){ qsort( (void*)s , n , sizeof(s[0]) , cmp_string ); }\n// void sort_char(char *s){ qsort( (void *)s , strlen(s) , sizeof(char) , cmp_char ); }\n// ll unique_string(ll n ,ll size, char s[][size]){ ll ans=1; rep(i,1,n) if( strcmp(s[i],s[i-1]) ) ans++; return ans; }\n// ll unique_num(ll n , ll a[]){ ll ans=1; rep(i,1,n) if( a[i]!=a[i-1] ) ans++; return ans; }\n\nll compare(ll a, ll b){ return a<b?-1:a>b?1:0; }\ntypedef struct{ ll a , b;}fr;\nint cmp1( const void *p, const void *q ){  \n    ll pa=((fr*)p)->a; ll qa=((fr*)q)->a;  return compare(pa,qa);  \n}\nint cmp2( const void *p, const void *q ){\n    ll pa=((fr*)p)->a; ll qa=((fr*)q)->a;  return compare(qa,pa);\n}\nvoid strsortup(fr*a,int n){qsort(a,n,sizeof(fr),cmp1);}\nvoid strsortdown(fr*a,int n){qsort(a,n,sizeof(fr),cmp2);}\n\nvoid sort_partial(ll a[],int begin,int end,int is_increase){\n    ll *b;  b = (ll *) malloc( sizeof(ll)*(end-begin) );\n\n    rep(i,begin,end) b[i-begin]=a[i];\n    if(is_increase) sortup(b,end-begin); else sortdown(b,end-begin);\n    rep(i,begin,end) a[i]=b[i-begin];\n}\n\n// ll pre_rui[2151][1151];\n// ll ruiseki[2151][1151];\n// void rui_make(ll h, ll w){\n//     rep(i,0,h){\n//         rep(j,0,w){\n//             ruiseki[i+1][j+1]=ruiseki[i+1][j]+pre_rui[i][j];\n//         }\n//         rep(j,0,w){\n//             ruiseki[i+1][j+1]+=ruiseki[i][j+1];\n//         }\n//     }\n// }\n\n// ll rui_get(ll st_y, ll st_x, ll en_y, ll en_x, ll h, ll w){\n//     if(en_y<0) return 0;\n//     if(en_x<0) return 0;\n//     if(st_y>h) return 0;\n//     if(st_x>w) return 0;\n//     if(st_y<0) st_y=0;\n//     if(st_x<0) st_x=0;\n//     if(en_y>h) en_y=h;\n//     if(en_x>w) en_x=w;\n//     ll val=0;\n//     val+=ruiseki[en_y][en_x];\n//     val-=ruiseki[en_y][st_x];\n//     val-=ruiseki[st_y][en_x];\n//     val+=ruiseki[st_y][st_x];\n//     return val;\n// }\n\n\n\n\n#pragma region AVL\n/*---------------------------AVL start--------------------------------*/\n//https://qiita.com/mikecat_mixc/items/e9f8248de2ae7f7a0a29\ntypedef struct node_AVL_set{  \n    ll val;\n    int diff;\n    int cnt;\n    struct node_AVL_set *child[2];\n}AVL_set;\nvoid AVL_set_inside_rotate(AVL_set **node, int is_right){\n    int l = is_right==false , r = is_right==true , sign = is_right ? 1 : -1;\n    if((*node)->child[l] != NULL){\n        AVL_set* left = (*node)->child[l];\n        int a= (*node)->diff * sign , b= left->diff * sign ,na,nb;\n        if(b+1){\n            na=a-1-b;\n            nb= (a-b) ? b-1 : a-2;\n        }else{\n            na=a-1;\n            nb= a ? b-1 : a+b-2;\n        }\n        (*node)->diff = na * sign;\n        left->diff = nb * sign;\n        /* rotate-> */\n        (*node)->child[l] = (*node)->child[l]->child[r];\n        left->child[r] = *node;\n        *node = left;\n    }\n}\nint AVL_set_inside_update(AVL_set **node, ll data, int add){\n    if(*node == NULL){\n        if(add==2){\n            *node = (AVL_set*)malloc(sizeof(AVL_set));\n            (*node)->val = data;\n            (*node)->cnt = 1;\n            (*node)->diff = 0;\n            (*node)->child[0] = NULL;\n            (*node)->child[1] = NULL;\n        }\n        return add==2 ? *node != NULL : 0; \n    }else{\n        int l, delta, delta_sign; AVL_set *next_node;\n        if(data == (*node)->val){\n            if(add==2){\n                (*node)->cnt++;\n                return 0;\n            }else{\n                if( add && (*node)->cnt > 1 ){\n                    (*node)->cnt--; return 0;\n                }else{\n                    if((*node)->child[1] == NULL){\n                        next_node = (*node)->child[0];\n                        free(*node);\n                        *node = next_node;\n                        return -1;\n                    }else if((*node)->child[0] == NULL){\n                        next_node = (*node)->child[1];\n                        free(*node);\n                        *node = next_node;\n                        return -1;\n                    }else{\n                        for(next_node = (*node)->child[0];\n                        next_node->child[1] != NULL;\n                        next_node = next_node->child[1]);\n                        (*node)->val = next_node->val;\n                        l=0;\n                        delta_sign=1;\n                        delta = AVL_set_inside_update(&(*node)->child[l], next_node->val, add);\n                    }\n                }\n            }\n        }else{\n            l = data >= (*node)->val ? 1 : 0;\n            delta_sign = data < (*node)->val ? 1 : -1;\n            delta = AVL_set_inside_update(&(*node)->child[l], data, add);\n        }\n        if( delta ){\n            int orig_diff = (*node)->diff;\n            int do_rotate = 0, rotate_l , diff_sign , rotate_right;\n            (*node)->diff += delta * delta_sign;\n            if((*node)->diff > 1){\n                do_rotate = 1;\n                rotate_l = 0;\n                diff_sign = 1;\n                rotate_right = 1;\n            }else if((*node)->diff < -1){\n                do_rotate = 1;\n                rotate_l = 1;\n                diff_sign = -1;\n                rotate_right = 0;\n            }\n            if(do_rotate){\n                int child_diff = (*node)->child[rotate_l]->diff;\n                if((*node)->child[rotate_l]->diff * diff_sign < 0){\n                    AVL_set_inside_rotate(&(*node)->child[rotate_l], !rotate_right);\n                }\n                AVL_set_inside_rotate(node, rotate_right);\n                return delta < 0 && child_diff != 0 ? -1 : 0;\n            }\n            if     (delta > 0 && orig_diff == 0) return 1;\n            else if(delta < 0 && orig_diff != 0) return -1;\n            else                                 return 0;\n        }else{ \n            return 0;\n        }\n    }\n}\n\nvoid AVL_set_inside_print(const AVL_set *node, int depth){\n    if(node == NULL) return;\n    AVL_set_inside_print(node->child[1], depth + 1);\n    printf(\"%lld %d\\n\", node->val,node->cnt);\n    AVL_set_inside_print(node->child[0], depth + 1);    \n}\nvoid AVL_set_inside_free(AVL_set *node){\n    if(node == NULL) return;\n    AVL_set_inside_free(node->child[0]);\n    AVL_set_inside_free(node->child[1]);\n    free(node);\n}\nll AVL_set_inside_count(AVL_set *root, ll val){\n    AVL_set *node; node = root;\n    while(node){\n        if     (val < node->val) node = node->child[0];\n        else if(val > node->val) node = node->child[1];\n        else                     return node->cnt;\n    }\n    return 0;\n}\n\n\nint AVL_set_lowcomp(ll node, ll val, int type){\n    if(node==val){\n        if(type!=3) return 0;\n        else return 1;\n    }\n    if(node<val) return 1;\n    if(node>val) return -1;\n    return 0;\n}\n// return smallest p  which meets  a[p]==val :1  >=:2   >:3\nAVL_set* AVL_set_inside_lowerbound(AVL_set *root, ll val, int type){\n    AVL_set *node; node = root;\n    while(node){\n        int com=AVL_set_lowcomp(node->val,val,type);\n        if(com==0) return node;\n        if(com==1) node = node->child[1];\n        if(com==-1){\n            AVL_set *small;\n            small=AVL_set_inside_lowerbound(node->child[0],val,type);\n            if(type==1){\n                return small;\n            }else{\n                if(small!=NULL) return small;\n                else return node;                 \n            }\n        }\n    }\n    return node;\n}\n\nint AVL_set_upcomp(ll node, ll val, int type){\n    if(node==val){\n        if(type!=3) return 0;\n        else return -1;\n    }\n    if(node<val) return 1;\n    if(node>val) return -1;\n    return 0;\n}\n// return biggest p  which meets   a[p]==val :1  <=:2   <:3\nAVL_set* AVL_set_inside_upperbound(AVL_set *root, ll val, int type){\n    AVL_set *node; node = root;\n    while(node){\n        int com=AVL_set_upcomp(node->val,val,type);\n        if(com==0) return node;\n        if(com==-1) node = node->child[0];\n        if(com==1){\n            AVL_set *big;\n            big=AVL_set_inside_upperbound(node->child[1],val,type);\n            if(type==1){\n                return big;\n            }else{\n                if(big!=NULL) return big;\n                else return node;                 \n            }\n        }\n    }\n    return node;\n}\n\n\nll AVL_set_inside_minmax(AVL_set *root, int type){\n    while(root->child[type] !=NULL)  root= root->child[type];\n    return root->val;\n}\nvoid AVL_set_inside_swap(AVL_set **node1, AVL_set **node2){  \n    AVL_set *tmp;  tmp=*node1; *node1=*node2; *node2=tmp;\n}\n\n#define set_MAX_SIZE 514511\nll set_main( int command , int set_num , ll val ,ll option){\n    static bool set_is_init=false;\n    static AVL_set *set_pointer[set_MAX_SIZE];\n    static ll set_siz[set_MAX_SIZE];\n    if(!set_is_init){ set_is_init=true; rep(i,0,set_MAX_SIZE){ *(set_pointer+i) = NULL; set_siz[i]=0; } }\n    if(command==-1){ AVL_set_inside_print( set_pointer[set_num] ,0); }\n    if(command==1){ AVL_set_inside_count(set_pointer[set_num],val) ? 1 : set_siz[set_num]++;  AVL_set_inside_update( &set_pointer[set_num] , val , 2 ); }\n    if(command==2){ return AVL_set_inside_count(set_pointer[set_num],val); }\n    if(command==3){ ( AVL_set_inside_count(set_pointer[set_num],val) > 1 ) ? 1 : set_siz[set_num]--;  AVL_set_inside_update( &set_pointer[set_num] , val,1); }\n    if(command==4){ set_siz[set_num]--; AVL_set_inside_update( &set_pointer[set_num] , val , 0 ); }\n    if(command==5){ set_siz[set_num]=0; AVL_set_inside_free( set_pointer[set_num] ); set_pointer[set_num] = NULL; }\n    if(command==6){ return set_siz[set_num]; }\n    if(command==7){ return AVL_set_inside_minmax(set_pointer[set_num],1); }\n    if(command==8){ return AVL_set_inside_minmax(set_pointer[set_num],0); }\n    if(command==9){ AVL_set_inside_swap(&set_pointer[set_num],&set_pointer[val]); }\n    if(10<=command&&command<=12){\n        AVL_set *lowbound = AVL_set_inside_lowerbound(set_pointer[set_num],val,command-9);\n        if(lowbound==NULL) return option;\n        else return lowbound->val;\n    }\n    if(13<=command&&command<=15){\n        AVL_set *upbound = AVL_set_inside_upperbound(set_pointer[set_num],val,command-12);\n        if(upbound==NULL) return option;\n        else return upbound->val;\n    }\n    return 0;\n}\n\nvoid set_print(int set_num){ set_main(-1,set_num,0,0); }\nvoid set_insert(int set_num, ll val){ set_main(1,set_num,val,0); }\nll set_count(int set_num, ll val){ return set_main(2,set_num,val,0); }\nvoid set_erase(int set_num, ll val, int is_all){ if(is_all) set_main(4,set_num,val,0); else set_main(3,set_num,val,0); }\nvoid set_clear(int set_num){ set_main(5,set_num,0,0); }\nll set_size(int set_num){ return set_main(6,set_num,0,0); }\nll set_max(int set_num){ return set_main(7,set_num,0,0); }\nll set_min(int set_num){ return set_main(8,set_num,0,0); }\nvoid set_swap(int set_num1, int set_num2){ set_main(9,set_num1,set_num2,0); }\n\n\n// return smallest p  which meets  a[p]==val :1  >=:2   >:3\nll set_lowerbound(int set_num, ll val, int type, ll error){\n    return set_main(9+type,set_num,val,error);\n}\n// return biggest p  which meets   a[p]==val :1  <=:2   <:3\nll set_upperbound(int set_num, ll val, int type, ll error){\n    return set_main(12+type,set_num,val,error);\n}\n\n/*\ninsert *\nsize *\nclear *\nerase *\ncount *\nmax *\nmin *\nswap *\nbegin x\nend x\nmerge  source \u306e\u8981\u7d20\u306e\u30ad\u30fc\u3068\u7b49\u4fa1\u306a\u30ad\u30fc\u306e\u8981\u7d20\u304c\u3042\u308b\u5834\u5408\u3001\u305d\u306e\u8981\u7d20\u306f source \u304b\u3089\u62bd\u51fa\u3055\u308c\u306a\u3044\nlower_bound *\nupper_bound *\n*/\n\n// ll map_main()\n\n/*---------------------------AVL start--------------------------------*/\n\n#pragma endregion AVL\n\n\n#pragma endregion kyopuro_templates\n\n\n\n#pragma region vector\n\ntypedef struct vector vector;\ntypedef struct vector {\n    int n, max, data_size;\n    void *data;\n    void (*push)(vector*, void*);\n    void (*set)(vector*, int, void*);\n    ll (*get)(vector*, int);\n    double (*get_double)(vector*, int);\n    int (*size)(vector*);\n} vector;\n\n\nvoid vector_push(vector *v, void *x) {\n    if (v->n == v->max) {\n        v->max *= 2;\n        assert((v->data = realloc(v->data, v->max * v->data_size)) != NULL);\n    }\n    if(x==NULL){\n        memset(v->data + v->data_size * v->n, 0, v->data_size);\n    }else{\n        memcpy(v->data + v->data_size * v->n, x, v->data_size);\n    }\n    v->n++;\n}\n\nvoid vector_set(vector *v, int idx, void *x) {\n    if(x == NULL){\n        memset(v->data + v->data_size * idx, 0, v->data_size);\n    }else{\n        memcpy(v->data + v->data_size * idx, x, v->data_size);\n    }\n}\n\nvoid *vector_get_internal(vector *v, int idx) {\n    return (v->data + v->data_size * idx);\n}\nll vector_get(vector *v, int idx){\n    ll ret=0;\n    if(v->data_size == 8) ret = *(ll*)vector_get_internal(v, idx);\n    if(v->data_size == 4) ret = *(int*)vector_get_internal(v, idx);\n    if(v->data_size == 2) ret = *(bool*)vector_get_internal(v, idx);\n    return ret;\n}\ndouble vector_get_double(vector *v, int idx){\n    assert(v->data_size == sizeof(double));\n    return *(double*)vector_get(v, idx);\n}\n\nint vector_size(vector *v) {\n    return v->n;\n}\n\nvector *vector_init(int n, int data_size) {\n    assert(n != 0);\n    vector *ret = (vector *)malloc(sizeof(vector));\n    ret->n = 0;\n    ret->max = n;\n    ret->data_size = data_size;\n    ret->data = malloc(n * data_size);\n\n    ret->push=vector_push;\n    ret->set=vector_set;\n    ret->size=vector_size;\n    ret->get = vector_get;\n    ret->get_double = vector_get_double;\n\n    memset(ret->data, 0, n * ret->data_size);\n    return ret;\n}\n\n// void vector_free(vector *v){\n//     free(v->data);\n//     free(v->get);\n//     free(v->get_double);\n//     free(v->push);\n//     free(v->set);\n//     free(v->size);\n//     free(v);\n// }\n\n#pragma endregion vector\n\n\n\n#pragma region max_flow\n#define flow_t long long\n// #define flow_t double\ntypedef struct Dinic Dinic;\ntypedef struct Dinic {\n    int n;\n    vector **to;\n    vector **cap;\n    vector **rev;\n    vector *min_cost;\n    vector *iter;\n    void (*add)(Dinic*, int, int, flow_t);\n    flow_t (*max_flow)(Dinic*, int, int);\n} Dinic;\n\n\nvoid Dinic_add_edge(Dinic *d, int from, int to, flow_t cap) {\n    vector_push(d->rev[from], (void*)&d->to[to]->n);\n    vector_push(d->rev[to], (void*)&d->to[from]->n);\n    vector_push(d->to[from], (void*)&to);\n    vector_push(d->to[to], (void*)&from);\n    vector_push(d->cap[from], (void*)&cap);\n    vector_push(d->cap[to], NULL);\n}\n\nbool Dinic_bfs(Dinic *d, int s, int t) {\n    int init = -1;\n    rep(i, 0, d->n) vector_set(d->min_cost, i, (void*)&init);\n    vector *q = vector_init(1, sizeof(int));\n    vector_set(d->min_cost, s, NULL);\n    int head = 0;\n    q->push(q, (void*)&s);\n    while(head != q->n && vector_get(d->min_cost, t) == -1){\n        int p = q->get(q, head);\n        head++;\n        rep(i, 0, d->to[p]->n) {\n            int to = vector_get(d->to[p], i);\n            if(vector_get(d->cap[p], i) > 0 && vector_get(d->min_cost, to) == -1){\n                ll cost = vector_get(d->min_cost, p) + 1;\n                vector_set(d->min_cost, to, (void*)&cost);\n                q->push(q, (void*)&to);\n            }\n        }\n    }\n    return vector_get(d->min_cost, t) != -1;\n}\n\nflow_t Dinic_dfs(Dinic *d, int idx, int t, flow_t flow) {\n    if(idx == t) return flow;\n    rep(i, vector_get(d->iter, idx), d->cap[idx]->n){\n        vector_set(d->iter, idx, (void*)&i);\n        flow_t cap = vector_get(d->cap[idx], i);\n        int to = vector_get(d->to[idx], i);\n        if(cap > 0 && vector_get(d->min_cost, idx) < vector_get(d->min_cost, to)) {\n            flow_t delta = Dinic_dfs(d, to, t, flow < cap ? flow : cap);\n            if(delta > 0) {\n                cap -= delta;\n                vector_set(d->cap[idx], i, (void*)&cap);\n                int rev = vector_get(d->rev[idx], i);\n                flow_t rev_cap = vector_get(d->cap[to], rev) + delta;\n                vector_set(d->cap[to], rev, (void*)&rev_cap);\n                return delta;\n            }\n        }\n    }\n    return 0;\n}\n\nflow_t Dinic_max_flow(Dinic *d, int s, int t) {\n    flow_t flow = 0;\n    while(Dinic_bfs(d, s, t)) {\n        rep(i, 0, d->n) vector_set(d->iter, i, NULL);\n        flow_t f = 0;\n        while((f = Dinic_dfs(d, s, t, INF)) > 0) flow += f;\n    }\n    return flow;\n}\n\nDinic *Dinic_init(int n) {\n    Dinic *ret = (Dinic *)malloc(sizeof(Dinic));\n    ret->n = n;\n    ret->to = (vector **)malloc(n * sizeof(vector*));\n    ret->cap = (vector **)malloc(n * sizeof(vector*));\n    ret->rev = (vector **)malloc(n * sizeof(vector*));\n    rep(i, 0, n) {\n        ret->to[i] = vector_init(1, sizeof(int));\n        ret->cap[i] = vector_init(1, sizeof(flow_t));\n        ret->rev[i] = vector_init(1, sizeof(int));\n    }\n    ret->min_cost =vector_init(n, sizeof(int));\n    ret->iter = vector_init(n, sizeof(int));\n    ret->add = Dinic_add_edge;\n    ret->max_flow = Dinic_max_flow;\n    return ret;\n}\n#pragma endregion max_flow\n\n\n\n\n\nchar s[1151154];\nvoid solve(){\n    // fgets(s,sizeof(s),stdin); \n    ll n;\n    ll ans=0;\n    cin(&n);\n    // scanf(\"%s\",s);\n    ll a[3];\n    ll b[3];\n    rep(i,0,3){\n        cin(&a[i]);\n    }\n    rep(i,0,3){\n        cin(&b[i]);\n    }\n    ll ma=0;\n    // ll mi=INF;\n    ma=min(a[0],b[1])+min(a[1],b[2])+min(a[2],b[0]);\n    Dinic *d=Dinic_init(8);\n    d->add(d,6,0,a[0]);\n    d->add(d,6,1,a[1]);\n    d->add(d,6,2,a[2]);\n\n    d->add(d,0,3,INF);\n    d->add(d,0,5,INF);\n    d->add(d,1,3,INF);\n    d->add(d,1,4,INF);\n    d->add(d,2,4,INF);\n    d->add(d,2,5,INF);\n\n    d->add(d,3,7,b[0]);\n    d->add(d,4,7,b[1]);\n    d->add(d,5,7,b[2]);\n    printf(\"%lld %lld\\n\",n-d->max_flow(d,6,7),ma);\n}\n\nint main(void){\n    ll T=1;\n    // cin(&T);\n    rep(i,0,T){ solve(); }\n    return 0;\n}\n\n\n/*\n    while (ng + 1 < ok) {\n        ll p = ng + (ok - ng) / 2;\n        ll cnt = 0;\n        rep(i,0,n){\n            cnt += (a[i] + p - 1) / p - 1;\n        }\n        if (cnt <= k) ok = p; else ng = p;\n    }\n*/\n// 10^18 2^60 3^38 5^26\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d750577eab62b933e6ef0908e4855c26", "src_uid": "e6dc3bc64fc66b6127e2b32cacc06402", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <inttypes.h>\n#include <stdlib.h>\n\ntypedef uint64_t uint64; typedef uint32_t uint32;\ntypedef uint16_t uint16; typedef uint8_t uint8;\ntypedef int64_t int64; typedef int32_t int32;\ntypedef int16_t int16; typedef int8_t int8;\n\n#define u8 PRIu8\n#define u16 PRIu16\n#define u32 PRIu32\n#define u64 PRIu64\n#define d8 PRId8\n#define d16 PRId16\n#define d32 PRId32\n#define d64 PRId64\n\n#define finc(i,size) for(uint64 i=0;i<(size);i++)\n#define fdec(i,size) for(uint64 i=(size);i-->0;)\n\n#define scanf_s scanf\n#define min(a,b) ((a>b)?b:a)\nint main(void)\n{\n\tuint32 n;\n\tuint32 map[2][4];\n\tscanf_s(\"%\"u32\"\", &n);\n\tfinc(i, 2)\n\t\tfinc(j, 3)\n\t\tscanf_s(\"%\"u32\"\", &map[i][j]);\n\tfinc(i, 2)\n\t\tmap[i][3] = map[i][0];\n\n\tuint32 winmax = 0, winmin = 0;\n\tfinc(i, 3)\n\t\twinmax += min(map[0][i], map[1][i + 1]);\n\tfor (uint64 i = 1; i < 4; i++)\n\t{\n\t\tif (map[1][i - 1] + map[1][i] < map[0][i])\n\t\t\twinmin = map[0][i] - map[1][i - 1] - map[1][i];\n\t}\n\tprintf(\"%\"u32\" %\"u32\"\\n\", winmin, winmax);\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "017bd5c0f7e6d72de70f946c404d4cdf", "src_uid": "e6dc3bc64fc66b6127e2b32cacc06402", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint min(int a, int b) {\n    return (a < b) ? a : b;\n}\n\nint max(int a, int b) {\n    return (a > b) ? a : b;\n}\n\nint main() {\n    int n;\n    int a1, a2, a3;\n    int b1, b2, b3;\n\n    scanf(\"%d\", &n);\n    scanf(\"%d %d %d\", &a1, &a2, &a3);\n    scanf(\"%d %d %d\", &b3, &b1, &b2);\n\n    int min_ans = 0;\n    min_ans = max(min_ans, a1 - b2 - b3);\n    min_ans = max(min_ans, a2 - b3 - b1);\n    min_ans = max(min_ans, a3 - b1 - b2);\n\n    int max_ans = min(a1, b1) + min(a2, b2) + min(a3, b3);\n\n    printf(\"%d %d\", min_ans, max_ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "aebe2cbe4ca97e47e79259850b5d45df", "src_uid": "e6dc3bc64fc66b6127e2b32cacc06402", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\nint main() {\n    long long int n,minw=0,maxw=0;\n    long long int a[3],b[3],m[3];\n    scanf(\"%lld \",&n);\n    scanf(\"%lld %lld %lld \",&a[0],&a[1],&a[2]);\n    scanf(\"%lld %lld %lld \",&b[0],&b[1],&b[2]);\n    maxw+=a[0]>b[1]?b[1]:a[0];\n    maxw+=a[1]>b[2]?b[2]:a[1];\n    maxw+=a[2]>b[0]?b[0]:a[2];\n    maxin=b[0]>b[1]?(b[0]>b[2]?0:2):(b[1]>b[2]?1:2);\n    int minw=b[maxin]-a[maxin]-a[(maxin+1)%3];\n    if(minw<0)\n        minw=0;\n    m[0]=b[0]>a[1]?a[1]:b[0];\n    m[1]=b[1]>a[2]?a[2]:b[1];\n    m[2]=b[2]>a[0]?a[0]:b[2];\n    a[1]-=m[0];\n    a[2]-=m[1];\n    a[0]-=m[2];\n    b[0]-=m[0];\n    b[1]-=m[1];\n    b[2]-=m[2];\n    a[0]-=a[0]>b[0]?b[0]:a[0];\n    a[1]-=a[1]>b[1]?b[1]:a[1];\n    a[2]-=a[2]>b[2]?b[2]:a[2];\n    //minw=a[0]+a[1]+a[2];\n    printf(\"%lld %lld\",minw,maxw);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2dcde8502b2353be95711d81fec50994", "src_uid": "e6dc3bc64fc66b6127e2b32cacc06402", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <inttypes.h>\n#include <stdlib.h>\n\ntypedef uint64_t uint64; typedef uint32_t uint32;\ntypedef uint16_t uint16; typedef uint8_t uint8;\ntypedef int64_t int64; typedef int32_t int32;\ntypedef int16_t int16; typedef int8_t int8;\n\n#define u8 PRIu8\n#define u16 PRIu16\n#define u32 PRIu32\n#define u64 PRIu64\n#define d8 PRId8\n#define d16 PRId16\n#define d32 PRId32\n#define d64 PRId64\n\n#define finc(i,size) for(uint64 i=0;i<(size);i++)\n#define fdec(i,size) for(uint64 i=(size);i-->0;)\n\n#define scanf_s scanf\nint main(void)\n{\n\tuint32 n;\n\tuint32 map[2][4];\n\tscanf_s(\"%\"u32\"\", &n);\n\tfinc(i, 2)\n\t\tfinc(j, 3)\n\t\tscanf_s(\"%\"u32\"\", &map[i][j]);\n\tfinc(i, 2)\n\t\tmap[i][3] = map[i][0];\n\n\tuint32 winmax = 0, winmin = 0;\n\tfinc(i, 3)\n\t\twinmax += min(map[0][i], map[1][i + 1]);\n\tfor (uint64 i = 1; i < 4; i++)\n\t{\n\t\tif (map[1][i - 1] + map[1][i] < map[0][i])\n\t\t\twinmin = map[0][i] - map[1][i - 1] - map[1][i];\n\t}\n\tprintf(\"%\"u32\" %\"u32\"\\n\", winmin, winmax);\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d87e5199d89e577d522c31081e699a26", "src_uid": "e6dc3bc64fc66b6127e2b32cacc06402", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "import java.util.Scanner;\n\npublic class Main {\n\n\tpublic static void main(String[] args) {\n\t\tScanner input=new Scanner(System.in);\n\t\tint  n=input.nextInt();\n\t\tString str=Integer.toString(n,8);\n\t\tint sum=0;\n\t\tfor(int i=0;i<str.length();i++) {\n\t\t\tif(str.charAt(i)=='1')\n\t\t\t\tsum++;\t\t\t\n\t\t}\n\t\tSystem.out.println(sum);\t\n\t\t\n\n\t}\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "84ee74931ac2911c187947437e75aa16", "src_uid": "ec539775f2b3358a92a99a644e2480ce", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,sum;\n    scanf(\"%d\",&n);\n    while(n)\n    {\n        if(n%8==1)\uff5b\n            sum++;\n        }\n        n/=8;\n        printf(\"%d\",sum);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "dda637c267cb65497dcd393002289b7b", "src_uid": "ec539775f2b3358a92a99a644e2480ce", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include<cstdio>\nint a,sum=0;\nint main()\n{\n    scanf(\"%d\",&a);\n    while(a)\n    {\n        if(a%8==1){\n            sum++;\n        }\n        a/=8;\n    }\n    printf(\"%d\\n\",sum);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "885c409d0212f6ccfd76ac3b38df3b57", "src_uid": "ec539775f2b3358a92a99a644e2480ce", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <math.h>\n#include <ctype.h>\nint a[1000];\nint main()\n{\n//\tfreopen(\"datain.txt\",\"r\",stdin);\n//\tfreopen(\"datain.txt\",\"w\",stdout);\n\tint n;\n\tscanf(\"%d\",&n);\n\tint i=1;\n\tint len;\n\tint cnt=0;\n\twhile(n>0)\n    {\n        a[i]=n%8;\n        n /=8;\n        i++;\n        len = i;\n    }\n    for(i=1;i<=len;i++)\n    {\n        if(a[i]==1) cnt++;\n    }\n    printf(\"%d\",cnt);\n//\tfclose(stdin);\n//\tfclose(stdout);\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "42eea2b15d291ad102eb81d587def8ee", "src_uid": "ec539775f2b3358a92a99a644e2480ce", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <math.h>\n#include <ctype.h>\nint a[1000];\nint main()\n{\n//\tfreopen(\"datain.txt\",\"r\",stdin);\n//\tfreopen(\"datain.txt\",\"w\",stdout);\n\tint n;\n\tscanf(\"%d\",&n);\n\tint i=1;\n\tint len;\n\tint cnt=0;\n\twhile(n>0)\n    {\n        a[i]=n%8;\n        n /=8;\n        i++;\n        len = i;\n    }\n    for(i=1;i<=len;i++)\n    {\n        if(a[i]==1) cnt++;\n    }\n    printf(\"%d\",cnt);\n//\tfclose(stdin);\n//\tfclose(stdout);\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "71adf212ca846de7253860e28cf44384", "src_uid": "ec539775f2b3358a92a99a644e2480ce", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\n#define N\t1000000\n#define MD\t1000000007\n\nint d_, x_, y_;\n\nvoid gcd(int a, int b) {\n\tif (b == 0)\n\t\td_ = a, x_ = 1, y_ = 0;\n\telse {\n\t\tint t;\n\n\t\tgcd(b, a % b);\n\t\tt = x_ - a / b * y_, x_ = y_, y_ = t;\n\t}\n}\n\nint inv(int a) {\n\tgcd(a, MD);\n\treturn x_;\n}\n\nint main() {\n\tstatic int dp[N];\n\tint n, k, h;\n\tlong long x, ans, f;\n\n\tscanf(\"%d%d\", &n, &k);\n\tif (k > n - 1)\n\t\tk = n - 1;\n\tf = 1;\n\tfor (h = 0; h <= k; h++) {\n\t\tdp[h] = 1;\n\t\tf = f * (h + 1) % MD;\n\t}\n\tx = k, ans = k + 1;\n\tfor (h = k + 1; h < n; h++) {\n\t\tdp[h] = x * inv(h) % MD;\n\t\tx = (x + dp[h] - dp[h - k]) % MD;\n\t\tans = (ans + dp[h]) % MD;\n\t\tf = f * (h + 1) % MD;\n\t}\n\tans = (n - ans) % MD;\n\tfor (h = 1; h < n; h++)\n\t\tans = ans * h % MD;\n\tif (ans < 0)\n\t\tans += MD;\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "47eac914f63dd17fd5016b53f2f404a3", "src_uid": "0644605611a2cd10ab3a9f12f18d7ae4", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\n#define M\t150\n#define MD\t1000000007\n\nint query(int aa[][M + 1], int l0, int l1, int r0, int r1) {\n\treturn l0 > l1 || r0 > r1 ? 0 : ((long long) aa[l1][r1] - aa[l0 - 1][r1] - aa[l1][r0 - 1] + aa[l0 - 1][r0 - 1]) % MD;\n}\n\nvoid add(int aa[][M + 1], int l, int r, int a) {\n\taa[l][r] = (aa[l][r] + a) % MD;\n}\n\nint main() {\n\tstatic int dp00[M + 1][M + 1], dp01[M + 1][M + 1], dp10[M + 1][M + 1], dp11[M + 1][M + 1];\n\tstatic int dq00[M + 1][M + 1], dq01[M + 1][M + 1], dq10[M + 1][M + 1], dq11[M + 1][M + 1];\n\tint n, m, l, r, ans;\n\n\tscanf(\"%d%d\", &n, &m);\n\tans = 0;\n\twhile (n--) {\n\t\tfor (l = 1; l <= m; l++)\n\t\t\tfor (r = 1; r <= m; r++) {\n\t\t\t\tdp00[l][r] = (dp00[l][r] + dp00[l][r - 1]) % MD;\n\t\t\t\tdp01[l][r] = (dp01[l][r] + dp01[l][r - 1]) % MD;\n\t\t\t\tdp10[l][r] = (dp10[l][r] + dp10[l][r - 1]) % MD;\n\t\t\t\tdp11[l][r] = (dp11[l][r] + dp11[l][r - 1]) % MD;\n\t\t\t}\n\t\tfor (l = 1; l <= m; l++)\n\t\t\tfor (r = 1; r <= m; r++) {\n\t\t\t\tdp00[l][r] = (dp00[l][r] + dp00[l - 1][r]) % MD;\n\t\t\t\tdp01[l][r] = (dp01[l][r] + dp01[l - 1][r]) % MD;\n\t\t\t\tdp10[l][r] = (dp10[l][r] + dp10[l - 1][r]) % MD;\n\t\t\t\tdp11[l][r] = (dp11[l][r] + dp11[l - 1][r]) % MD;\n\t\t\t}\n\t\tfor (l = 1; l <= m; l++)\n\t\t\tfor (r = 1; r <= m; r++)\n\t\t\t\tdq00[l][r] = dq01[l][r] = dq10[l][r] = dq11[l][r] = 0;\n\t\tfor (l = 1; l <= m; l++)\n\t\t\tfor (r = l; r <= m; r++) {\n\t\t\t\tdq00[l][r] = 1;\n\t\t\t\tadd(dq00, l, r, query(dp00, l, m, 1, r));\n\t\t\t\tadd(dq01, l, r, query(dp01, l, r, r, m));\n\t\t\t\tadd(dq01, l, r, query(dp00, l, r, r + 1, m));\n\t\t\t\tadd(dq10, l, r, query(dp10, 1, l, l, r));\n\t\t\t\tadd(dq10, l, r, query(dp00, 1, l - 1, l, r));\n\t\t\t\tadd(dq11, l, r, query(dp11, 1, l, r, m));\n\t\t\t\tadd(dq11, l, r, query(dp01, 1, l - 1, r, m));\n\t\t\t\tadd(dq11, l, r, query(dp10, 1, l, r + 1, m));\n\t\t\t\tadd(dq11, l, r, query(dp00, 1, l - 1, r + 1, m));\n\t\t\t\tans = (ans + (long long) dq00[l][r] + dq01[l][r] + dq10[l][r] + dq11[l][r]) % MD;\n\t\t\t}\n\t\tfor (l = 0; l <= m; l++)\n\t\t\tfor (r = 0; r <= m; r++) {\n\t\t\t\tdp00[l][r] = dq00[l][r];\n\t\t\t\tdp01[l][r] = dq01[l][r];\n\t\t\t\tdp10[l][r] = dq10[l][r];\n\t\t\t\tdp11[l][r] = dq11[l][r];\n\t\t\t}\n\t}\n\tif (ans < 0)\n\t\tans += MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "30c1f82db1d25584b4873f57fe7e805c", "src_uid": "740eceed59d3c6ac55c1bf9d3d4160c7", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\n#define M\t150\n#define MD\t1000000007\n\nint query(int aa[][M + 1], int l0, int l1, int r0, int r1) {\n\treturn l0 > l1 || r0 > r1 ? 0 : ((long long) aa[l1][r1] - aa[l0 - 1][r1] - aa[l1][r0 - 1] + aa[l0 - 1][r0 - 1]) % MD;\n}\n\nvoid add(int aa[][M + 1], int l, int r, int a) {\n\taa[l][r] = (aa[l][r] + a) % MD;\n}\n\nint main() {\n\tstatic int dp00[M + 1][M + 1], dp01[M + 1][M + 1], dp10[M + 1][M + 1], dp11[M + 1][M + 1];\n\tstatic int dq00[M + 1][M + 1], dq01[M + 1][M + 1], dq10[M + 1][M + 1], dq11[M + 1][M + 1];\n\tint n, m, l, r, ans;\n\n\tscanf(\"%d%d\", &n, &m);\n\tans = 0;\n\twhile (n--) {\n\t\tfor (l = 1; l <= m; l++)\n\t\t\tfor (r = 1; r <= m; r++) {\n\t\t\t\tdp00[l][r] = (dp00[l][r] + dp00[l][r - 1]) % MD;\n\t\t\t\tdp01[l][r] = (dp01[l][r] + dp01[l][r - 1]) % MD;\n\t\t\t\tdp10[l][r] = (dp10[l][r] + dp10[l][r - 1]) % MD;\n\t\t\t\tdp11[l][r] = (dp11[l][r] + dp11[l][r - 1]) % MD;\n\t\t\t}\n\t\tfor (l = 1; l <= m; l++)\n\t\t\tfor (r = 1; r <= m; r++) {\n\t\t\t\tdp00[l][r] = (dp00[l][r] + dp00[l - 1][r]) % MD;\n\t\t\t\tdp01[l][r] = (dp01[l][r] + dp01[l - 1][r]) % MD;\n\t\t\t\tdp10[l][r] = (dp10[l][r] + dp10[l - 1][r]) % MD;\n\t\t\t\tdp11[l][r] = (dp11[l][r] + dp11[l - 1][r]) % MD;\n\t\t\t}\n\t\tfor (l = 1; l <= m; l++)\n\t\t\tfor (r = 1; r <= m; r++)\n\t\t\t\tdq00[l][r] = dq01[l][r] = dq10[l][r] = dq11[l][r] = 0;\n\t\tfor (l = 1; l <= m; l++)\n\t\t\tfor (r = l; r <= m; r++) {\n\t\t\t\tdq00[l][r] = 1;\n\t\t\t\tadd(dq00, l, r, query(dp00, l, m, 1, r));\n\t\t\t\tadd(dq01, l, r, query(dp01, l, r, r, m));\n\t\t\t\tadd(dq01, l, r, query(dp00, l, r, r + 1, m));\n\t\t\t\tadd(dq10, l, r, query(dp10, 1, l, l, r));\n\t\t\t\tadd(dq10, l, r, query(dp00, 1, l - 1, l, r));\n\t\t\t\tadd(dq11, l, r, query(dp11, 1, l, r, m));\n\t\t\t\tadd(dq11, l, r, query(dp01, 1, l - 1, r, m));\n\t\t\t\tadd(dq11, l, r, query(dp10, 1, l, r + 1, m));\n\t\t\t\tadd(dq11, l, r, query(dp00, 1, l - 1, r + 1, m));\n\t\t\t\tans = (ans + (long long) dq00[l][r] + dq01[l][r] + dq10[l][r] + dq11[l][r]) % MD;\n\t\t\t}\n\t\tfor (l = 0; l <= m; l++)\n\t\t\tfor (r = 0; r <= m; r++) {\n\t\t\t\tdp00[l][r] = dq00[l][r];\n\t\t\t\tdp01[l][r] = dq01[l][r];\n\t\t\t\tdp10[l][r] = dq10[l][r];\n\t\t\t\tdp11[l][r] = dq11[l][r];\n\t\t\t}\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "73fbe48f2e49e4380357036ac4661a50", "src_uid": "740eceed59d3c6ac55c1bf9d3d4160c7", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    int s, k, i, f[100001], ans[100001], a=0;\n    scanf(\"%d %d\", &s, &k);\n    f[0]=0;\n    f[1]=1;\n    f[2]=1;\n    for(i=3; f[i-1]<=s && i<=k; i++)\n        f[i]=2*f[i-1];\n    for(; f[i-1]<=s; i++)\n        f[i]=2*f[i-1]-f[i-k-1];\n    a[i]=0;\n    while(i>=0)\n    {\n        if(s-f[i]>=0)\n        {\n            ans[a++]=f[i];\n            s-=f[i];\n        }\n        i--;\n    }\n    printf(\"%d\\n\", a-1);\n    for(i=0; i<a-1; i++)\n        printf(\"%d \", ans[i]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e5d580a3f7dc705f519d882c28b59293", "src_uid": "da793333b977ed179fdba900aa604b52", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nlong long int a[1000000000],b[1000000000];\nint main()\n{\n     long long int s,k;\n     scanf(\"%I64d %I64d\",&s,&k);\n     long long int i,j,l,o,p,m;\n    \n     if(s==1)\n     {\n          printf(\"2\\n0 1\");\n     }\n     else \n     {\n     for(i=1; ; i++)\n     {\n          if(i<k)\n          a[i]=0;\n          else if(i==k)\n          a[i]=1;\n          else \n          {l=0;\n               for(j=i-1;j>=i-k;j--)\n               l+=a[j];\n               a[i]=l;\n          }\n          if(a[i]>=s)\n          break;\n     }\n     o=i-1;\n     m=1;\n     for(p=o;p>=k;p--)\n     {\n          if(a[p]<=s)\n          {\n               b[m]=a[p];\n               s-=a[p];\n               m++;\n          }\n          if(s==0)\n          break;\n     }\n     printf(\"%I64d\\n\",m-1);\n     for(i=1;i<m;i++)\n     {\n          printf(\"%I64d \",b[i]);\n          \n     }\n     \n     }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e00bebaabed1d3c66ad30849a6636633", "src_uid": "da793333b977ed179fdba900aa604b52", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint f[1000];\nint c[1000];\nint a[1000];\n\nint search(int s, int n, int m)\n{\n    int l = 0, r = n - 1, mid, ret = -1;\n    while (l <= r)\n    {\n        mid = (l + r) >> 1;\n        if (f[mid] < s)\n        {\n            ret = mid;\n            l = mid + 1;\n        }\n        else if (f[mid] == s && m != 0)\n        {\n            ret = mid;\n            break;\n        }\n        else\n        {\n            r = mid - 1;\n        }\n    }\n    return ret;\n}\n\nvoid func(int s, int k)\n{\n    int i, n, m, p;\n    f[0] = c[0] = 1;\n    for (i = 1; i < k && f[i - 1] <= s; i ++)\n    {\n        f[i] = c[i - 1];\n        c[i] = c[i - 1] << 1;\n    }\n    if (i == k)\n    {\n        while (f[i - 1] <= s)\n        {\n            f[i] = c[i - 1];\n            c[i] = c[i - 1] << 1;\n            c[i] -= f[i - k];\n            i ++;\n        }\n    }\n    n = i;\n    m = 0;\n    while (s != 0)\n    {\n        p = search(s, n, m);\n        a[m ++] = f[p];\n        s -= f[p];\n        n = p;\n    }\n    printf(\"%d\\n\", m);\n    for (i = 0; i < m - 1; i ++)\n    {\n        printf(\"%d \", a[i]);\n    }\n    printf(\"%d\\n\", a[i]);\n}\n\nint main()\n{\n    int s, k;\n    while (scanf(\"%d%d\", &s, &k) == 2)\n    {\n        func(s, k);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "775fca10e6ae809fd2f84176fbbef615", "src_uid": "da793333b977ed179fdba900aa604b52", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nlong long int a[1000000],b[100000];\nint main()\n{\n     long long int s,k;\n     scanf(\"%I64d %I64d\",&s,&k);\n     long long int i,j,l,o,p,m;\n    \n     if(s==1)\n     {\n          printf(\"2\\n0 1\");\n     }\n     else \n     {\n     for(i=1; ; i++)\n     {\n          if(i<k)\n          a[i]=0;\n          else if(i==k)\n          a[i]=1;\n          else \n          {l=0;\n               for(j=i-1;j>=i-k;j--)\n               l+=a[j];\n               a[i]=l;\n          }\n          if(a[i]>=s)\n          break;\n     }\n     o=i-1;\n     m=1;\n     for(p=o;p>=k;p--)\n     {\n          if(a[p]<=s)\n          {\n               b[m]=a[p];\n               s-=a[p];\n               m++;\n          }\n          if(s==0)\n          break;\n     }\n     printf(\"%I64d\\n\",m-1);\n     for(i=1;i<m;i++)\n     {\n          printf(\"%I64d \",b[i]);\n          \n     }\n     \n     }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "0b940df11b9c9a6f8c01c1e93a4f71d9", "src_uid": "da793333b977ed179fdba900aa604b52", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "//In the name of God\n#include <stdio.h>\n\n#define int long long\n\nint s,k,sone;\n\nint f[10000];\nint ans[10000];\n\nvoid make()\n{\n  sone=s;\n  int sum=0;\n  int i;\n  int last=0;\n  for(i=k;;i++)\n    {\n      if(i==k)\n\t{f[i]=sum=1; continue;}\n      f[i]=sum;\n      //      printf(\"f[%lld]=%lld\\n\",i,f[i]);\n      if(f[i]>s) break;\n      sum+=f[i];\n      sum-=f[i-k];\n    }\n  int index=0;\n  for(;i>=0;i--)\n    {\n      if(f[i]<=s)\n\ts-=f[i],ans[index++]=f[i];\n      if(f[i]==0) break;\n    }\n  printf(\"%lld\\n\",index);\n  for(i=0;i<index;++i)\n    printf(\"%lld \",ans[i]);\n}\n\n\nmain()\n{\n  scanf(\"%lld%lld\",&s,&k);\n  make();\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2eb8351bf2404f4d4501c99aaa1acb45", "src_uid": "da793333b977ed179fdba900aa604b52", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n#include <stdio.h>\n\nint main()\n{\n    int n, x, i, m, r, min_n = 10004, max_m = -1;\n    scanf(\"%d%d%d\", &n, &m, &r);\n    for(i = 0; i < n; i++)\n    {\n        scanf(\"%d\", &x);\n        if(x < min_n) min_n = x;\n    }\n    for(i = 0; i < m; i++)\n    {\n        scanf(\"%d\", &x);\n        if(x > max_m) max_m = x;\n    }\n    i = (max_m * (r / min_n)) + (r % min_n);\n    if(i > r) printf(\"%d\\n\", i);\n    else printf(\"%d\\n\", r);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "60b5d64e54b0c293d9f9a9b303cda896", "src_uid": "42f25d492bddc12d3d89d39315d63cb9", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint func(const void * a,const void *b)\n{\n    return ( *(int*)b - *(int*)a );\n}\nint main()\n{\n    int i,j,n,m,r,s[1005],b[1005],x=0,t;\n    scanf(\"%d %d %d\",&n,&m,&r);\n    t=r;\n    for (i=0;i<n;i++)\n    {\n        scanf(\"%d\",&s[i]);\n    }\n    for (i=0;i<n;i++)\n    {\n        scanf(\"%d\",&b[i]);\n    }\n    qsort(s,n,sizeof(s[0]),func);\n    qsort(b,m,sizeof(b[0]),func);\n    if(s[n-1]<b[0])\n    {\n        x=r/s[n-1];\n        r=r+x*b[0]-x*s[n-1]);\n    }\n    if(t>r)\n        r=t;\n    printf(\"%d\\n\",r);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d01ba100959c8be4ca371c011767acf0", "src_uid": "42f25d492bddc12d3d89d39315d63cb9", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,m,r,i,j,less,max,buy,sell,t;\n    scanf(\"%d%d%d\",&n,&m,&r);\n    int s[n],x[m];\n    for(i=0;i<n;i++)\n    scanf(\"%d\",&s[i]);\n    \n    for(i=0;i<m;i++)\n    scanf(\"%d\",&x[i]);\n    \n    less=s[0];\n    for(i=0;i<n;i++)\n    {\n        if(s[i]<less)\n        less=s[i];\n    }\n    max=x[0];\n    for(i=0;i<m;i++)\n    {\n        if(x[i]>max)\n        max=x[i];\n    }\n    buy=r/less;\n    t=r%less;\n    sell=max*buy+t;\n    if(sell>r)\n    printf(\"%d\",sell);\n    else\n    printf(\"%d\",r);\n    \n},", "lang_cluster": "C", "compilation_error": true, "code_uid": "2741130d9222c5103292cd6a93008a87", "src_uid": "42f25d492bddc12d3d89d39315d63cb9", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n     int n,m,r;\n     scanf(\"%d %d %d\",&n,&m,&r);\n     int s[n],b[m];\n     int i,j;\n     for(i=0;i<n;i++)\n     {\n          scanf(\"%d\",&s[i]);\n     }\n     int min=s[0];\n     for(i=0;i<n;i++)\n     {\n          if(s[i]<min)\n          min=s[i];\n     } \n     for(j=0;j<m;j++)\n     {\n          scanf(\"%d\",&b[j]);\n     }\n     int max=b[j];\n     for(j=0;j<m;j++)\n     {\n          if(b[j]>max)\n          max=b[j];\n     }\n     int ans;\n     if(max>min)\n     {\n          ans=*(max-min)*5)+r;\n     }\n     else\n     ans=r;\n     printf(\"%d\",ans);\n}\n          ", "lang_cluster": "C", "compilation_error": true, "code_uid": "e9793bbd8e7ef3b1139924cfeb74aae8", "src_uid": "42f25d492bddc12d3d89d39315d63cb9", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdlib.h>\n#include <stdio.h>\n\n\nvoid merge(int arr[], int l, int m, int r) \n{ \n    int i, j, k; \n    int n1 = m - l + 1; \n    int n2 =  r - m; \n  \n    /* create temp arrays */\n    int L[n1], R[n2]; \n  \n    /* Copy data to temp arrays L[] and R[] */\n    for (i = 0; i < n1; i++) \n        L[i] = arr[l + i]; \n    for (j = 0; j < n2; j++) \n        R[j] = arr[m + 1+ j]; \n  \n    /* Merge the temp arrays back into arr[l..r]*/\n    i = 0; // Initial index of first subarray \n    j = 0; // Initial index of second subarray \n    k = l; // Initial index of merged subarray \n    while (i < n1 && j < n2) \n    { \n        if (L[i] <= R[j]) \n        { \n            arr[k] = L[i]; \n            i++; \n        } \n        else\n        { \n            arr[k] = R[j]; \n            j++; \n        } \n        k++; \n    } \n  \n    /* Copy the remaining elements of L[], if there \n       are any */\n    while (i < n1) \n    { \n        arr[k] = L[i]; \n        i++; \n        k++; \n    } \n  \n    /* Copy the remaining elements of R[], if there \n       are any */\n    while (j < n2) \n    { \n        arr[k] = R[j]; \n        j++; \n        k++; \n    } \n} \n  \n/* l is for left index and r is right index of the \n   sub-array of arr to be sorted */\nvoid mergeSort(int arr[], int l, int r) \n{ \n    if (l < r) \n    { \n        // Same as (l+r)/2, but avoids overflow for \n        // large l and h \n        int m = l+(r-l)/2; \n  \n        // Sort first and second halves \n        mergeSort(arr, l, m); \n        mergeSort(arr, m+1, r); \n  \n        merge(arr, l, m, r); \n    } \n} \n\n\n\nint main(){\n\tint n,m,r;\n\tscanf(\"%d %d %d\",&n,&m,&r);\n\tint s[n];\n\tint s_min;\n\tint b_temp = 0;\n\tint b_max = 0;\n\tint buy = 0;\n\tint flag = 0;\n\tfor(int i=0;i<n;i++){\n\t\tscanf(\"%d\",&(s[i]));\n\t\tif(i == 0){\n\t\t\ts_min = s[i];\n\t\t}\n\t\tif(s[i]< s_min){\n\t\t\ts_min = s[i];\n\t\t}\n\t}\n\tfor(int i=0;i<m;i++){\n\t\tscanf(\"%d\",&b_temp);\n\t\tif(b_temp > b_max){\n\t\t\tb_max = b_temp;\n\t\t}\n\t}\n\tif(s_min >= b_max){\n\t\tprintf(\"%d\\n\",r);\n\t}\n\telse{\n\t\tbuy = r/s_min;\n\t\tr = r-b*s_min;\n\t\tint count = r + buy*b_max;\n\t\tprintf(\"%d\\n\",count);\n\t}\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fd7c4c172bcb15c6e65683b23a7437f1", "src_uid": "42f25d492bddc12d3d89d39315d63cb9", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint main()\n{\n    long long n,y,prey,ans=0,i;\n    scanf(\"%I64d\",&n);\n    if(n==0)\n        printf(\"1\\n\");\n    else\n    {\n        prey = sqrt(n*n - 1);\n        ans++;\n        for(i=2;i<=n;i++)\n        {\n            y = sqrt(n*n-i*i);\n                    //printf(\"%lld %lld prevy y\\n\",prey,y);\n            if(y==prey)\n                ans++;\n            else\n                ans += prey - y;\n            prey = y;\n        }\n        ans--;\n                        //printf(\"%lld check\\n\",ans);\n        ans *= 4;\n\n        ans += 4;\n        printf(\"%I64d\\n\",ans);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "baa46b5e35b7e311c464071ad6d6eec3", "src_uid": "d87ce09acb8401e910ca6ef3529566f4", "difficulty": null}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n    int ix;\n    long long int l,r,m,n,x,y,n2,dc,nd2;\n    scanf(\"%I64d\",&n);\n    if(n<=1)\n    {\n        if(n==0)\n        printf(\"1\");\n        else\n        printf(\"4\");\n        return 0;\n    }\n    l=1;r=n;nd2=n*n;\n    nd2/=2;\n    while(l+1<r)\n    {\n        m=(l+r)/2;\n        if(m*m>nd2)\n        r=m;\n        else\n        l=m;\n    }\n    if(r*r<=nd2)\n    x=r;\n    else\n    x=l;\n    \n    n2=n*n;\n    dc=2*x*x+2*x+1;\n    \n    ix=x;\n    if(dc-n2<=0)\n    {\n        printf(\"%d\",8*ix+4);\n    }\n    else\n    {\n        printf(\"%d\",8*ix);\n    }\n    return 0;\n    \n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "75a71de2e1bc878f5f1f40f31f583a23", "src_uid": "d87ce09acb8401e910ca6ef3529566f4", "difficulty": null}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n#define For(i,m,n) for(i=m;i<n;i++)\n#define MAX(x,y) (x)>(y)?(x):(y)\n#define MIN(x,y) (x)<(y)?(x):(y)\n#define MAXN 205\n\nmain()\n{\n    long long n;\n    scanf(\"%I64d\",&n);\n    if(n==0) printf(\"1\\n\");\n    else printf(\"%I64d\\n\",4*(long long)floor(n*sqrt(2)));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2d1336790d84188b5422c6c6b788f42d", "src_uid": "d87ce09acb8401e910ca6ef3529566f4", "difficulty": null}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint n;\n\nint special(int x, int y) {\n  long long xx = x, yy = y, nn = n; xx *= x; yy *= y; nn *= n;\n  return xx + yy <= nn;\n}\n\nint main(void) {\n  int i, j, r = 0, s = 0;\n  scanf(\"%d\", &n);\n  j = n;\n  if (n == 0) r = 1;\n  else if (n == 1) r = 4;\n  else {\n    for (i = 0; i <= j; ++i) {\n      while (!special(i, j)) --j;\n      if (i < j) ++r;\n      if (i == j) ++s;\n    }\n    r = 2*r + s; r += r - 1; r += r - 2;\n  }\n  printf(\"%d\\n\", r);\n  exit(EXIT_SUCCESS);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b69d30ca8e9b2747a1fe557362d5098a", "src_uid": "d87ce09acb8401e910ca6ef3529566f4", "difficulty": null}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint n;\n\nint special(int x, int y) {\n  long long xx = x, yy = y, nn = n; xx *= x; yy *= y; nn *= n;\n  return xx + yy < nn;\n}\n\nint main(void) {\n  int i, j, r = 0, s = 0;\n  scanf(\"%d\", &n);\n  j = n;\n  for (i = 0; i <= j; ++i) {\n    while (!special(i, j)) --j;\n    if (i < j) ++r;\n    if (i == j) ++s;\n  }\n  r = 2*r + s; r += r - 1; r += r - 2;\n  printf(\"%d\\n\", n == 0 ? 1 : n == 1 ? 4 : r);\n  exit(EXIT_SUCCESS);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d17c29e1294a456c481f3730dbddc90b", "src_uid": "d87ce09acb8401e910ca6ef3529566f4", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define int long long int\nsigned main()\n{\n    int x,y,s[3];\n    scanf(\"%d%d\",&x,&y);\n    int a=0,i,ans=0,sum=0,count1=0;\n    s[1]=y;\n    s[2]=y;\n    s[3]=y;\n    while(count1<3)\n    {\n\tfor(i=1;i<=3;i++)\n\t{\n\t    if(count1==3)\n\t\tbreak;\n\t    sum=s[1]+s[2]+s[3];\n\t    a=sum-s[i]-1;\n\t    if(a>=x)\n\t    {\n\t\ts[i]=x;\n\t\tcount1++;\n\t    }\n\t    else\n\t\ts[i]=a;\n\t    ans++;\n\t    printf(\"%d %d %d %d %d\\n\",a,count,s[1],s[2],s[3]);\n\t}\n    }\n    printf(\"%d\",ans);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "58516ed382d58cad6e0a477b58e90b89", "src_uid": "8edf64f5838b19f9a8b19a14977f5615", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n\tint d,x,y,a,b,c,i=0;\n\tscanf(\"%d%d\",&x,&y);\n\ta=b=c=y;\n\twhile(a<x)\n\t{\n\t\td=(x<b+c-1?x:b+c-1);\n\t\ta=b; b=c; c=d;\n\t\ti++\n\t}\n\tprintf(\"%d\",i);\n\t\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5ffc2beabfeb5f77e37c488e9c7fa911", "src_uid": "8edf64f5838b19f9a8b19a14977f5615", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n\n{\n\tint x=0, y=0;\n\tscanf(\"%d %d\", &x, &y);\n\tint p,q,r;\n\tp=y;\n\tq=y;\n\tr=y;\n\tint count=0;\n\n\twhile(1<2\n\t{\n\t\tif(q+r-1<x)\n\t\t{\n\t\t\tp=q+r-1;\n\t\t\tcount++;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tp=x;\n\t\t\tcount++;\n\t\t}\n\t\t\n\t\tif((p==x)&&(q==x)&&(r==x))\n\t\t\tbreak;\n\n\t\tif(p+r-1<x)\n\t\t{\n\t\t\tq=p+r-1;\n\t\t\tcount++;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tq=x;\n\t\t\tcount++;\n\t\t}\n\n\t\tif((p==x)&&(q==x)&&(r==x))\n\t\t\tbreak;\n\n\t\tif(p+q-1<x)\n\t\t{\n\t\t\tr=p+q-1;\n\t\t\tcount++;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tr=x;\n\t\t\tcount++;\t\n\t\t}\n\t\t\n\t\tif((p==x)&&(q==x)&&(r==x))\n\t\t\tbreak;\n\t}\n\n\n\tprintf(\"%d\", count);\n\treturn 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6ef247bb55be01d836bc03443585c9e0", "src_uid": "8edf64f5838b19f9a8b19a14977f5615", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define int long long int\nsigned main()\n{\n    int x,y,s[4]={0};\n    scanf(\"%d%d\",&x,&y);\n    int a=0,i,ans=0,sum=0,count1=0;\n    s[1]=y;\n    s[2]=y;\n    s[3]=y;\n    while(count1<3)\n    {\n\tfor(i=1;i<=3;i++)\n\t{\n\t    if(count1==3)\n\t\tbreak;\n\t    sum=s[1]+s[2]+s[3];\n\t    a=sum-s[i]-1;\n\t    if(a>=x)\n\t    {\n\t\ts[i]=x;\n\t\tcount1++;\n\t    }\n\t    else\n\t\ts[i]=a;\n\t    ans++;\n\t    printf(\"%d %d %d %d %d\\n\",a,count1,s[1],s[2],s[3]);\n\t}\n    }\n    printf(\"%d\",ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3d2c0c1b973e3ae75bfaa74f011aca8f", "src_uid": "8edf64f5838b19f9a8b19a14977f5615", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(){\n\tint x,y,n=3,a,b,c,flag=1,i=0,temp;\n\tscanf(\"%d\",&x);\n\tscanf(\"%d\",&y);\n\tif(y+y>x){\n\t\tprintf(\"3\");\n\t}\n\telse if(y+y==x){\n\t\tprintf(\"4\");\t\n\t}\n\telse{\n\t\ta=y;\n\t\tb=y;\n\t\tc=y;\n\t\twhile(flag){\n\t\t\tc=a+b-1;\n\t\t\ti++;\n\t\t\tif(c>x){\n\t\t\t\tn=n+i;\n\t\t\t\tprintf(\"%d\",n);\n\t\t\t\tflag=0;\t\t\t\n\t\t\t}\n\t\t\telse if(c==x){\n\t\t\t\tn=n+i-1;\n\t\t\t\tprintf(\"%d\",n);\n\t\t\t\tflag=0;\t\t\t\t\n\t\t\t}\t\t\n\t\t\telse{\n\t\t\t\tif(a<c){\n\t\t\t\t\ttemp=a;\n\t\t\t\t\ta=c;\n\t\t\t\t\tc=temp;\n\t\t\t\t}\n\t\t\t\tif(b<c){\n\t\t\t\t\ttemp=b;\n\t\t\t\t\tb=c;\n\t\t\t\t\tc=temp;\t\t\t\t\t\n\t\t\t\t}\n\t\t\t}\n\t\t}\t\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2b38fbd4d7383136fab0a0546eb60bca", "src_uid": "8edf64f5838b19f9a8b19a14977f5615", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint x,y,z,xx,yy,zz,ans,a[7];\nint main()\n{\n\tint i;\n\tscanf(\"%d%d%d%d%d%d\",&x,&y,&z,&xx,&yy,&zz);\n\tfor(i=1;i<=6;i++) scanf(\"%d\",&a[i]);\n\tif(y<0) ans += a[1];\n\tif(y>yy) ans += a[2];\n\tif(z<0) ans += a[3];\n\tif(z>zz) ans += a[4];\n\tif(x<0) ans += a[5];\n\tif(x>xx) ans += a[6];\n\tprintf(\"%d\",ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ba6c6b03cb43bd41ec5556cae73d7152", "src_uid": "c7889a8f64c57cf7be4df870f68f749e", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int X,Y,Z,x,y,z,i,j,num[10];\n    while(1){\n    scanf(\"%d %d %d\",&x,&y,&z);\n    scanf(\"%d %d %d\",&X,&Y,&Z);\n    for (i=0;i<6;i++)\n    {\n        scanf(\"%d\",&num[i]);\n    }\n    j=0;\n    if (x>X)\n    {\n        j+=num[5];\n    }\n    else if (x<0)\n    {\n        j+=num[4];\n    }\n    if (y>Y)\n    {\n        j+=num[1];\n    }\n    else if (y<0)\n    {\n        j+=num[0];\n    }\n    if (z>Z)\n    {\n        j+=num[3];\n    }\n    else if (z<0)\n    {\n        j+=num[2];\n    }\n\n\n    }\n    printf(\"%d\\n\",j);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5944c76c75d14338df14bfdcf9fe33d1", "src_uid": "c7889a8f64c57cf7be4df870f68f749e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main() \n{\nint x,y,z;\nint x,yy,z1;\nint a[7];\n    scanf(\"%d%d%d\",&x,&y,&z);\n    scanf(\"%d%d%d\",&x1,&yy,&z1);\n    for (int i=1;i<=6;i++) scanf(\"%d\",&a[i]);\n\n    int ans=0;\n    if (y<0) ans+=a[1];\n    if (y>yy) ans+=a[2];\n    if (z<0) ans+=a[3];\n    if (z>z1) ans+=a[4];\n    if (x<0) ans+=a[5];\n    if (x>x1) ans+=a[6];\n    printf(\"%d\\n\",ans);\n\n\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5189a69f48e5984978f29695d9ac096a", "src_uid": "c7889a8f64c57cf7be4df870f68f749e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main() \n{\nint x,y,z;\nint x1,yy,z1;\nint a[7];\n    scanf(\"%d%d%d\",&x,&y,&z);\n    scanf(\"%d%d%d\",&x1,&yy,&z1);\n    for (int i=1;i<=6;i++) scanf(\"%d\",&a[i]);\n\n    int ans=0;\n    if (y<0) ans+=a[1];\n    if (y>yy) ans+=a[2];\n    if (z<0) ans+=a[3];\n    if (z>z1) ans+=a[4];\n    if (x<0) ans+=a[5];\n    if (x>x1) ans+=a[6];\n    printf(\"%d\\n\",ans);\n\n\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "26eba6793b2cc4e339faa3d5669ccd6f", "src_uid": "c7889a8f64c57cf7be4df870f68f749e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main() \n{\nint x,y,z;\nint x1,y1,z1;\nint a[7];\n    scanf(\"%d%d%d\",&x,&y,&z);\n    scanf(\"%d%d%d\",&x1,&yy,&z1);\n    for (int i=1;i<=6;i++) scanf(\"%d\",&a[i]);\n\n    int ans=0;\n    if (y<0) ans+=a[1];\n    if (y>yy) ans+=a[2];\n    if (z<0) ans+=a[3];\n    if (z>z1) ans+=a[4];\n    if (x<0) ans+=a[5];\n    if (x>x1) ans+=a[6];\n    printf(\"%d\\n\",ans);\n\n\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c4adbf64c8712a35d16189b2501305c7", "src_uid": "c7889a8f64c57cf7be4df870f68f749e", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "/* https://csacademy.com/submission/2215090/ */\n#include <stdio.h>\n\n#define N\t50\n#define M\t(1 << 13) /* 2500 < M / 2 */\n#define LN\t13\n#define MD\t1000000007\n#define M0\t469762049\n#define M1\t595591169\n#define M2\t645922817\n\nint MM[] = { M0, M1, M2 };\n\nint V01, V02, V12;\n\nlong long power(int a, int b, int md) {\n\tlong long p;\n\n\tif (b == 0)\n\t\treturn 1;\n\tp = power(a, b / 2, md);\n\tp = p * p % md;\n\tif (b % 2)\n\t\tp = p * a % md;\n\treturn p;\n}\n\nlong long ww[3][LN + 1], ww_[3][LN + 1], vv[3];\nint kk[N + 1][N + 1][N + 1], ll[N + 1][N + 1][N + 1][3];\n\nvoid init() {\n\tint d, h, i, j, k;\n\n\tfor (d = 0; d < 3; d++) {\n\t\tint md = MM[d];\n\n\t\tfor (h = 0; h <= LN; h++) {\n\t\t\tww[d][h] = power(3, (md - 1) >> h, md);\n\t\t\tww_[d][h] = power(3, md - 1 - ((md - 1) >> h), md);\n\t\t}\n\t\tvv[d] = power(M, md - 2, md);\n\t}\n\tV01 = power(M0, M1 - 2, M1);\n\tV02 = power(M0, M2 - 2, M2);\n\tV12 = power(M1, M2 - 2, M2);\n\tfor (i = 0; i <= N; i++)\n\t\tfor (j = 0; j <= N; j++)\n\t\t\tfor (k = 0; k <= N; k++) {\n\t\t\t\tlong long k0, k1, k2;\n\n\t\t\t\tk0 = i > 0 ? (long long) ll[i - 1][j][k][0] * i % MD : 0;\n\t\t\t\tk1 = j > 0 ? (long long) ll[i][j - 1][k][1] * j % MD : 0;\n\t\t\t\tk2 = k > 0 ? (long long) ll[i][j][k - 1][2] * k % MD : 0;\n\t\t\t\tif (i == 0 && j == 0 && k == 0) {\n\t\t\t\t\tkk[i][j][k] = 1;\n\t\t\t\t\tll[i][j][k][0] = ll[i][j][k][1] = ll[i][j][k][2] = 1;\n\t\t\t\t} else {\n\t\t\t\t\tkk[i][j][k] = (k0 + k1 + k2) % MD;\n\t\t\t\t\tll[i][j][k][0] = (k1 + k2) % MD;\n\t\t\t\t\tll[i][j][k][1] = (k0 + k2) % MD;\n\t\t\t\t\tll[i][j][k][2] = (k0 + k1) % MD;\n\t\t\t\t}\n\t\t\t}\n}\n\nvoid ntt(int *aa, int d, int inverse) {\n\tint md = MM[d], h, i, j, b, l, r, u, v, tmp;\n\tlong long w, w_;\n\n\tfor (i = 1, j = 0; i < M; i++) {\n\t\tb = M;\n\t\tdo\n\t\t\tj ^= b >>= 1;\n\t\twhile ((j & b) == 0);\n\t\tif (i < j)\n\t\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\t}\n\tfor (h = 0; (b = 1 << h) < M; h++) {\n\t\tw_ = inverse ? ww_[d][h + 1] : ww[d][h + 1];\n\t\tfor (i = 0; i < M; i += b * 2) {\n\t\t\tw = 1;\n\t\t\tfor (j = 0; j < b; j++) {\n\t\t\t\tl = i + j, r = l + b;\n\t\t\t\tu = aa[l], v = aa[r] * w % md;\n\t\t\t\tif ((aa[l] = u + v) >= md)\n\t\t\t\t\taa[l] -= md;\n\t\t\t\tif ((aa[r] = u - v) < 0)\n\t\t\t\t\taa[r] += md;\n\t\t\t\tw = w * w_ % md;\n\t\t\t}\n\t\t}\n\t}\n}\n\nvoid fft(int *aa, int *bb, int d) {\n\tint md = MM[d], i;\n\tlong long v;\n\n\tntt(aa, d, 0), ntt(bb, d, 0);\n\tfor (i = 0; i < M; i++)\n\t\taa[i] = (long long) aa[i] * bb[i] % md;\n\tntt(aa, d, 1);\n\tv = vv[d];\n\tfor (i = 0; i < M; i++)\n\t\taa[i] = aa[i] * v % md;\n}\n\nint garner(int r0, int r1, int r2) {\n\tif (r0 < 0)\n\t\tr0 += M0;\n\tr1 = (long long) (r1 - r0) * V01 % M1;\n\tif (r1 < 0)\n\t\tr1 += M1;\n\tr2 = ((long long) (r2 - r0) * V02 - r1) % M2 * V12 % M2;\n\tif (r2 < 0)\n\t\tr2 += M2;\n\treturn (((long long) r2 * M1 + r1) % MD * M0 + r0) % MD;\n}\n\nvoid mult(int *aa, int *bb, int *cc) {\n\tstatic int cc_[3][M], bb_[M];\n\tint d, i;\n\n\tfor (d = 0; d < 3; d++) {\n\t\tfor (i = 0; i < M; i++) {\n\t\t\tcc_[d][i] = aa[i];\n\t\t\tbb_[i] = bb[i];\n\t\t}\n\t\tfft(cc_[d], bb_, d);\n\t}\n\tfor (i = 0; i < M; i++)\n\t\tcc[i] = garner(cc_[0][i], cc_[1][i], cc_[2][i]);\n}\n\nvoid knapsack(int *aa, int n, int m, int dp[][M]) {\n\tint h, i, j, a;\n\n\tdp[0][0] = 1;\n\tfor (h = 0; h < n; h++) {\n\t\ta = aa[h];\n\t\tfor (i = n; i >= 1; i--)\n\t\t\tfor (j = m; j >= a; j--)\n\t\t\t\tdp[i][j] = (dp[i][j] + dp[i - 1][j - a]) % MD;\n\t}\n}\n\nint main() {\n\tstatic int aa[3][N], cc[M], nn[3], dp[3][N + 1][M];\n\tint n, m, x, h, i0, i1, i2, j, ans;\n\n\tinit();\n\tscanf(\"%d%d\", &n, &m);\n\twhile (n--) {\n\t\tscanf(\"%d%d\", &x, &h), h--;\n\t\taa[h][nn[h]++] = x;\n\t}\n\tfor (h = 0; h < 3; h++)\n\t\tknapsack(aa[h], nn[h], m, dp[h]);\n\tans = 0;\n\tfor (i0 = 0; i0 <= nn[0]; i0++)\n\t\tfor (i1 = 0; i1 <= nn[1]; i1++) {\n\t\t\tmult(dp[0][i0], dp[1][i1], cc);\n\t\t\tfor (i2 = 0; i2 <= nn[2]; i2++)\n\t\t\t\tfor (j = 0; j <= m; j++)\n\t\t\t\t\tans = (ans + (long long) cc[j] * dp[2][i2][m - j] % MD * kk[i0][i1][i2]) % MD;\n\t\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2106798a76a43755065a4a9494eeb814", "src_uid": "ac2a37ff4c7e89a345b189e4891bbf56", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n \n#define N\t50\n#define T\t2500\n#define MD\t1000000007\n \nint dp[N + 1][N + 1][N + 1], dq[N + 1][N + 1][N + 1][3];\n \nvoid init(int na, int nb, int nc) {\n\tint ma, mb, mc, x0, x1, x2;\n \n\tfor (ma = 0; ma <= na; ma++)\n\t\tfor (mb = 0; mb <= nb; mb++)\n\t\t\tfor (mc = 0; mc <= nc; mc++) {\n\t\t\t\tx0 = ma > 0 ? (long long) dq[ma - 1][mb][mc][0] * ma % MD : 0;\n\t\t\t\tx1 = mb > 0 ? (long long) dq[ma][mb - 1][mc][1] * mb % MD : 0;\n\t\t\t\tx2 = mc > 0 ? (long long) dq[ma][mb][mc - 1][2] * mc % MD : 0;\n\t\t\t\tif (ma == 0 && mb == 0 && mc == 0) {\n\t\t\t\t\tdp[ma][mb][mc] = 1;\n\t\t\t\t\tdq[ma][mb][mc][0] = dq[ma][mb][mc][1] = dq[ma][mb][mc][2] = 1;\n\t\t\t\t} else {\n\t\t\t\t\tdp[ma][mb][mc] = ((long long) x0 + x1 + x2) % MD;\n\t\t\t\t\tdq[ma][mb][mc][0] = (x1 + x2) % MD;\n\t\t\t\t\tdq[ma][mb][mc][1] = (x0 + x2) % MD;\n\t\t\t\t\tdq[ma][mb][mc][2] = (x0 + x1) % MD;\n\t\t\t\t}\n\t\t\t}\n}\n \nvoid solve1(int *aa, int t, int n, int da[][N + 1]) {\n\tint i, s, m, a;\n \n\tfor (s = 0; s <= t; s++)\n\t\tfor (m = 0; m <= n; m++)\n\t\t\tda[0][0] = 0;\n\tda[0][0] = 1;\n\tfor (i = 0; i < n; i++) {\n\t\ta = aa[i];\n\t\tfor (s = t; s >= a; s--)\n\t\t\tfor (m = 1; m <= n; m++)\n\t\t\t\tda[s][m] = (da[s][m] + da[s - a][m - 1]) % MD;\n\t}\n}\n \nvoid solve2(int *aa, int *bb, int t, int na, int nb, int dab[][N + 1][N + 1]) {\n\tstatic int da[T + 1][N + 1];\n\tint i, b, s, ma, mb;\n \n\tsolve1(aa, t, na, da);\n\tfor (s = 0; s <= t; s++)\n\t\tfor (ma = 0; ma <= na; ma++) {\n\t\t\tdab[s][ma][0] = da[s][ma];\n\t\t\tfor (mb = 1; mb <= nb; mb++)\n\t\t\t\tdab[s][ma][mb] = 0;\n\t\t}\n\tfor (i = 0; i < nb; i++) {\n\t\tb = bb[i];\n\t\tfor (s = t; s >= b; s--)\n\t\t\tfor (ma = 0; ma <= na; ma++)\n\t\t\t\tfor (mb = 1; mb <= nb; mb++)\n\t\t\t\t\tdab[s][ma][mb] = (dab[s][ma][mb] + dab[s - b][ma][mb - 1]) % MD;\n\t}\n}\n \nint main() {\n\tstatic int aa[N], bb[N], cc[N], dab[T + 1][N + 1][N + 1], dc[T + 1][N + 1];\n\tint n, na, nb, nc, t, tab, tc, ma, mb, mc, xab, xc, ans;\n \n\tscanf(\"%d%d\", &n, &t);\n\tna = nb = nc = 0;\n\twhile (n--) {\n\t\tint a, g;\n \n\t\tscanf(\"%d%d\", &a, &g);\n\t\tif (g == 1)\n\t\t\taa[na++] = a;\n\t\telse if (g == 2)\n\t\t\tbb[nb++] = a;\n\t\telse\n\t\t\tcc[nc++] = a;\n\t}\n\tinit(na, nb, nc);\n\tsolve1(cc, t, nc, dc);\n\tsolve2(aa, bb, t, na, nb, dab);\n\tans = 0;\n\tfor (tab = 0; tab <= t; tab++) {\n\t\ttc = t - tab;\n\t\tfor (ma = 0; ma <= na; ma++)\n\t\t\tfor (mb = 0; mb <= nb; mb++)\n\t\t\t\tif ((xab = dab[tab][ma][mb]))\n\t\t\t\t\tfor (mc = 0; mc <= nc; mc++)\n\t\t\t\t\t\tif ((xc = dc[tc][mc]))\n\t\t\t\t\t\t\tans = (ans + (long long) xab * xc % MD * dp[ma][mb][mc]) % MD;\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "282c5bddb21eaa006f47b2457fedb37f", "src_uid": "ac2a37ff4c7e89a345b189e4891bbf56", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "/* https://codeforces.com/contest/1185/submission/55797221 (Dukkha) */\n#include <stdio.h>\n\n#define N\t50\n#define T\t2500\n#define MD\t1000000007\n\nint dp[N + 1][N + 1][N + 1], dq[N + 1][N + 1][N + 1][3];\n\nvoid init(int na, int nb, int nc) {\n\tint ma, mb, mc, x0, x1, x2;\n\n\tfor (ma = 0; ma <= na; ma++)\n\t\tfor (mb = 0; mb <= nb; mb++)\n\t\t\tfor (mc = 0; mc <= nc; mc++) {\n\t\t\t\tx0 = ma > 0 ? (long long) dq[ma - 1][mb][mc][0] * ma % MD : 0;\n\t\t\t\tx1 = mb > 0 ? (long long) dq[ma][mb - 1][mc][1] * mb % MD : 0;\n\t\t\t\tx2 = mc > 0 ? (long long) dq[ma][mb][mc - 1][2] * mc % MD : 0;\n\t\t\t\tif (ma == 0 && mb == 0 && mc == 0) {\n\t\t\t\t\tdp[ma][mb][mc] = 1;\n\t\t\t\t\tdq[ma][mb][mc][0] = dq[ma][mb][mc][1] = dq[ma][mb][mc][2] = 1;\n\t\t\t\t} else {\n\t\t\t\t\tdp[ma][mb][mc] = ((long long) x0 + x1 + x2) % MD;\n\t\t\t\t\tdq[ma][mb][mc][0] = (x1 + x2) % MD;\n\t\t\t\t\tdq[ma][mb][mc][1] = (x0 + x2) % MD;\n\t\t\t\t\tdq[ma][mb][mc][2] = (x0 + x1) % MD;\n\t\t\t\t}\n\t\t\t}\n}\n\nvoid solve1(int *aa, int t, int n, int da[][N + 1]) {\n\tint i, s, m, a;\n\n\tfor (s = 0; s <= t; s++)\n\t\tfor (m = 0; m <= n; m++)\n\t\t\tda[0][0] = 0;\n\tda[0][0] = 1;\n\tfor (i = 0; i < n; i++) {\n\t\ta = aa[i];\n\t\tfor (s = t; s >= a; s--)\n\t\t\tfor (m = 1; m <= n; m++)\n\t\t\t\tda[s][m] = (da[s][m] + da[s - a][m - 1]) % MD;\n\t}\n}\n\nvoid solve2(int *aa, int *bb, int t, int na, int nb, int dab[][N + 1][N + 1]) {\n\tstatic int da[T + 1][N + 1];\n\tint i, b, s, ma, mb;\n\n\tsolve1(aa, t, na, da);\n\tfor (s = 0; s <= t; s++)\n\t\tfor (ma = 0; ma <= na; ma++) {\n\t\t\tdab[s][ma][0] = da[s][ma];\n\t\t\tfor (mb = 1; mb <= nb; mb++)\n\t\t\t\tdab[s][ma][mb] = 0;\n\t\t}\n\tfor (i = 0; i < nb; i++) {\n\t\tb = bb[i];\n\t\tfor (s = t; s >= b; s--)\n\t\t\tfor (ma = 0; ma <= na; ma++)\n\t\t\t\tfor (mb = 1; mb <= nb; mb++)\n\t\t\t\t\tdab[s][ma][mb] = (dab[s][ma][mb] + dab[s - b][ma][mb - 1]) % MD;\n\t}\n}\n\nint main() {\n\tstatic int aa[N], bb[N], cc[N], dab[T + 1][N + 1][N + 1], dc[T + 1][N + 1];\n\tint n, na, nb, nc, t, tab, tc, ma, mb, mc, xab, xc, ans;\n\n\tscanf(\"%d%d\", &n, &t);\n\tna = nb = nc = 0;\n\twhile (n--) {\n\t\tint a, g;\n\n\t\tscanf(\"%d%d\", &a, &g);\n\t\tif (g == 1)\n\t\t\taa[na++] = a;\n\t\telse if (g == 2)\n\t\t\tbb[nb++] = a;\n\t\telse\n\t\t\tcc[nc++] = a;\n\t}\n\tinit(na, nb, nc);\n\tsolve1(cc, t, nc, dc);\n\tsolve2(aa, bb, t, na, nb, dab);\n\tans = 0;\n\tfor (tab = 0; tab <= t; tab++) {\n\t\ttc = t - tab;\n\t\tfor (ma = 0; ma <= na; ma++)\n\t\t\tfor (mb = 0; mb <= nb; mb++)\n\t\t\t\tif ((xab = dab[tab][ma][mb]))\n\t\t\t\t\tfor (mc = 0; mc <= nc; mc++)\n\t\t\t\t\t\tif ((xc = dc[tc][mc]))\n\t\t\t\t\t\t\tans = (ans + (long long) xab * xc % MD * dp[ma][mb][mc]) % MD;\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8f3a17bcad4f465a734acce1f96be65f", "src_uid": "ac2a37ff4c7e89a345b189e4891bbf56", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define max2(a,b) (a<b?b:a)\n#define max3(a,b,c) max2(max2(a,b),c)\n\nint N, T;\nint L[50];\nint G[50];\n\n#define MOD 1000000007ULL\n#define add2(a,b) ((a+b)%MOD)\n#define add3(a,b,c) add2(add2(a,b),c)\n#define mul2(a,b) ((a*b)%MOD)\n#define mul3(a,b,c) mul2(mul2(a,b), c)\n#define mul4(a,b,c,d) mul2(mul2(a,b), mul2(c,d))\n#define fact3(a,b,c) mul3(fact(a),fact(b),fact(c))\n\ntypedef unsigned long long u64;\n\nu64 F[51];\nu64 fact(u64 n) {\n  if (!F[n])\n    F[n] = n ? mul2(n, fact(n-1)) : 1;\n  return F[n];\n}\n\nu64 perm[26][26][26][3];\n\nint n[3];\nu64 walk(int t, int c)\n{\n  if (t > T)\n    return 0;\n  if (t == T) {\n    u64 r = 0;\n    for (int g = 0; g < 3; g++)\n      r = add2(r, perm[n[0]][n[1]][n[2]][g]);\n    r = mul2(r, fact3(n[0],n[1],n[2]));\n    // printf(\"%d [%d,%d,%d]: %d -> %d\\n\", t, n[0], n[1], n[2], G[c], r);\n    return r;\n  }\n\n  u64 result = 0;\n  for (int i = c + 1; i < N; i++) {\n    n[G[i]]++;\n    result = add2(result, walk(t + L[i], i));\n    n[G[i]]--;\n  }\n\n  return result;\n}\n\nint main() {\n  int i, j, k, n;\n\n  scanf(\"%d %d\", &N, &T);\n  for (i = 0; i < N; i++) {\n    scanf(\"%d %d\", &L[i], &G[i]);\n    G[i]--;\n  }\n\n  perm[1][0][0][0] = perm[0][1][0][1] = perm[0][0][1][2] = 1;\n\n  for (n = 2; n <= N; n++)\n    for (i = 0; i <= n/2+1; i++)\n      for (j = 0; j <= n - i; j++) {\n        k = n - i - j;\n        if (k > n/2+1) continue;\n\n        if (i) perm[i][j][k][0] = add2(perm[i-1][j][k][1], perm[i-1][j][k][2]);\n        if (j) perm[i][j][k][1] = add2(perm[i][j-1][k][2], perm[i][j-1][k][0]);\n        if (k) perm[i][j][k][2] = add2(perm[i][j][k-1][0], perm[i][j][k-1][1]);\n      }\n\n  printf(\"%llu\\n\", walk(0, -1));\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "432d668a7c8ab9882b62f8070d46e4f7", "src_uid": "ac2a37ff4c7e89a345b189e4891bbf56", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int c,n,i,ar[10],flag=-1;\n    long int a,b,x=10;\n    scanf(\"%ld %ld %d\",&a,&b,&c);\n    a=a%b;\n    for(i=0;i<=10;i++)\n    {\n\n        a=a*10;\n        ar[i]=a/b;\n        a=a%b;\n        if(ar[i]==c)\n        {\n            flag=i;\n            break;\n        }\n    }\n    if(flag==-1)\n     printf(\"-1\\n\");\n     else\n        printf(\"%d\\n\",flag+1);\n\n        return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "997ffd97df033b26a3aac4b72c0aef24", "src_uid": "0bc7bf67b96e2898cfd8d129ad486910", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tdouble a,b;\n\tint c,ans=-1;\n\tscanf(\"%lf %lf %d\",&a,&b,&c);\n\tdouble frac=fracinp-fracint;\n\t/*printf(\"%0.18lf\\n\", frac);*/\n\tint arr[18]={0};int i; \n\tfor (i = 0; i < 18; i++)\n\t{\n\t\tint dig=10*frac;\n\t\tarr[i]=dig;\n\t\tfrac=(10*frac)-dig;\n\t}\n\t/*for (i = 0; i < 6; i++)\n\t{\n\t\tprintf(\"%d\", arr[i]);\n\t}\n\tprintf(\"\\n\");*/\n\tfor (i = 0; i < 18; i++)\n\t{\n\t\tif (arr[i]==c){\n\t\t\tans=i+1;\n\t\t\tbreak;\n\t\t}\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1330f459b995b7af8e84b9d8859bb883", "src_uid": "0bc7bf67b96e2898cfd8d129ad486910", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "[Project]\nFileName=1.dev\nName=Project1\nType=1\nVer=2\nObjFiles=\nIncludes=\nLibs=\nPrivateResource=\nResourceIncludes=\nMakeIncludes=\nCompiler=\nCppCompiler=\nLinker=\nIsCpp=0\nIcon=\nExeOutput=\nObjectOutput=\nLogOutput=\nLogOutputEnabled=0\nOverrideOutput=0\nOverrideOutputName=\nHostApplication=\nUseCustomMakefile=0\nCustomMakefile=\nCommandLine=\nFolders=\nIncludeVersionInfo=0\nSupportXPThemes=0\nCompilerSet=0\nCompilerSettings=0000000000000000000000000\n\n[VersionInfo]\nMajor=1\nMinor=0\nRelease=0\nBuild=0\nLanguageID=1033\nCharsetID=1252\nCompanyName=\nFileVersion=\nFileDescription=Developed using the Dev-C++ IDE\nInternalName=\nLegalCopyright=\nLegalTrademarks=\nOriginalFilename=\nProductName=\nProductVersion=\nAutoIncBuildNr=0\nSyncProduct=1\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "93b70b39b9fa975e1f4e5b072f34fb43", "src_uid": "0bc7bf67b96e2898cfd8d129ad486910", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nunsigned int a,b;\nchar c;\nint main()\n{\n\tfloat f,l;\n\tint k,i=0;\n\tbool key=false;\n\tscanf(\"%d %d %d\",&a,&b,&c);\n\tf=(float)a/b*10;\n\tk=(int)f;\n\t\n\twhile (i<1000 && key==false)\n\t{\n\t\tk=k%10;\n\t\tif (k==c) key=true;\n\t\tl=(a-k*0.1*b)*10;\n\t\ta=(int)l;\n\t\tf=(float)a/b*10;printf(\"%f\\n\",f);\n\t\tk=(int)f;\n\t\ti++;\n\t}\n\tif (key==true) printf(\"%d\",i);\n\telse printf(\"-1\");\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "aa5af7a34d4ef402215480b48eb77d84", "src_uid": "0bc7bf67b96e2898cfd8d129ad486910", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint a,b,c;\n\tscanf(\"%d%d%d\",&a,&b,&c);\n\tint pos=0,brk=0,x=10000000;\n\twhile(x--){\n\t\tint rem = a%b;\n\t\tif(rem==0){\n\t\t\tbrk=1;\n\t\t\tbreak;\n\t\t}\n\t\ta*=10;\n\t\twhile(a<b)\n\t\t{\n\t\t\tpos++;\n\t\t\ta*=10;\n\t\t}\n\t\tint que=a/b;\n\t\ta=a%b;\n\t\tpos++;\n\t\tif(que==c){\n\t\t\tbreak;\n\t\t}\t\t\n\t}\n\tif(brk)\n\t{\n\t\tif(c==0)\n\t\t\tprintf(\"%d\\n\",pos+1);\n\t\telse\n\t\t\tprintf(\"-1\\n\");\n\t}\n\telse\n\t{\n\t\tif(x>0){\n\t\t\tprintf(\"%d\\n\",pos);\n\t\t}\n\t\telse\n\t\t\tprintf(\"-1\\n\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f72a2bf7d2d0639a5133c4e422e94e2d", "src_uid": "0bc7bf67b96e2898cfd8d129ad486910", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t5000\n#define MD\t998244353\n\nlong long power(int a, int k) {\n\tlong long p;\n\n\tif (k == 0)\n\t\treturn 1;\n\tp = power(a, k >> 1);\n\tp = p * p % MD;\n\tif (k & 1)\n\t\tp = p * a % MD;\n\treturn p;\n}\n\nint dp[N + 1][N + 1];\n\nvoid init(int k, int n) {\n\tint i, j;\n\n\tdp[0][0] = 1;\n\tfor (i = 0; i < k; i++)\n\t\tfor (j = 0; j < k; j++) {\n\t\t\tlong long x = dp[i][j];\n\n\t\t\tif (x == 0)\n\t\t\t\tcontinue;\n\t\t\tdp[i + 1][j] = (dp[i + 1][j] + x * j) % MD;\n\t\t\tdp[i + 1][j + 1] = (dp[i + 1][j + 1] + x * (n - j)) % MD;\n\t\t}\n}\n\nint main() {\n\tint n, m, k, d, vm, ans;\n\n\tscanf(\"%d%d%d\", &n, &m, &k), init(k, n);\n\tvm = power(m, MD - 2);\n\tans = 0;\n\tfor (d = 0; d <= k; d++)\n\t\tans = (ans + dp[k][d] * power(vm, d)) % MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "02287bbd25c79cebf2345ff3b086d151", "src_uid": "e6b3e559b5fd4e05adf9f1cd1b22126b", "difficulty": 2600.0}
{"lang": "GNU C11", "source_code": "#pragma GCC optimize(\"Ofast\")\n#include <stdio.h>\n\n#define MAXN 5001\n\nconst int md = 998244353;\n\nint n, m, k;\nint dp[MAXN][MAXN];\n\nint modpow(int bs, int pw){\n\tlong long bs1 = bs;\n\tlong long ans = 1;\n\twhile(pw){\n\t\tif(pw & 1){\n\t\t\tans *= bs1;\n\t\t\tans %= md;\n\t\t}\n\t\tpw >>= 1;\n\t\tbs1 *= bs1;\n\t\tbs1 %= md;\n\t}\n\treturn (int)ans;\n}\n\nint main(){\n\tscanf(\"%d%d%d\", &n, &m, &k);\n\tdp[0][0] = 1;\n\tfor(int i = 0; i < k; i++){\n\t\tfor(int j = 0; j < k; j++){\n\t\t\tdp[i+1][j] = (dp[i+1][j] + ((1LL * j * dp[i][j])%md) + md)%md;\n\t\t\tdp[i+1][j+1] = (dp[i+1][j+1] + ((1LL * (n-j) * dp[i][j])%md) + md)%md;\n\t\t}\n\t}\n\tint ans = 0;\n\tint inv = modpow(m, md-2);\n\tfor(int i = 1; i <= k; i++){\n\t\tans = (ans + ((modpow(inv, i) * 1LL * dp[k][i])%md))%md;\n\t}\n\tprintf(\"%d\\n\", ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0eeba21d8c8042ba0ffff4b851b8cd31", "src_uid": "e6b3e559b5fd4e05adf9f1cd1b22126b", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n;\n    scanf(\" %d\",&n);\n    if(n%2==0){\n        printf(\"white \\n\");\n        printf(\"1\");\n        printf(\"2\");\n}\nelse printf(\"black\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b85e55d4316b1691aab6ebf3ebe56070", "src_uid": "52e07d176aa1d370788f94ee2e61df93", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint t,n;\n\nint main() {\n    scanf(\"%d\",&n);\n    if(n==2){\n        printf(\"white\\n1 2\");   \n    }else if(n%2==0){\n        printf(\"white\\n2 2\");\n    }else{\n        printf(\"black\");\n    }\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0a7126c63c639046964bb9e7b4474777", "src_uid": "52e07d176aa1d370788f94ee2e61df93", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(){\nlong long n=0;\nscanf(\"%I64d\",&n);\nif(n==2){printf(\"white\\n\");printf(\"1 2\");}\nelse if ( n % 2 == 0)printf(\"white\\n 1 %I64d\",n/2+1);\nelse printf(\"black\");\n\n\n\n\n\n\n\nreturn 0 ;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6cb5e3df9559be1a661401e6a2c59a3d", "src_uid": "52e07d176aa1d370788f94ee2e61df93", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(){\nlong long n=0;\nscanf(\"%I64d\",&n);\nif(n==2){printf(\"white\\n\");printf(\"1 2\");\nelse if ( n % 2 == 0)printf(\"white\\n 1 %I64d\",n/2+1);\nelse printf(\"black)\n\n\n\n\n\n\n\nreturn 0 ;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c321bf208d0a19ba768c3094ebcfd5e9", "src_uid": "52e07d176aa1d370788f94ee2e61df93", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    scanf(\"%d\" ,&n);\n    if(n%2==0)\n        printf(\"white\");\n        printf(\"1 2\");\n    else\n        printf(\"black\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "21d05f7f1378071a0d121b3c9f6b3c41", "src_uid": "52e07d176aa1d370788f94ee2e61df93", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <bits/stdc++.h>\n#include <stdint.h>\n#include <stdio.h>\n\n\nuint64_t getBlkCount(uint32_t l,uint32_t b,uint32_t div)\n{\n    uint64_t blkCnt = 0;\n    for(int i=1;i<=l;i++)\n    for(int j=1;j<=b;j++)\n    {\n        blkCnt+= (((i*i + j*j)%div)==0);\n    }\n    return blkCnt;\n}\n\n\nuint64_t getCount(uint32_t n,uint32_t m)\n{\n    int q = n/m, r = n%m;\n    \n    uint64_t fullBlkCnt = getBlkCount(m,m,m);\n    uint64_t halfBlkCnt = getBlkCount(r,m,m);\n    uint64_t remBlkCnt  = getBlkCount(r,r,m);\n\n    uint64_t blkCnt = fullBlkCnt*q*q + halfBlkCnt*2*q + remBlkCnt;\n\n    return (blkCnt);\n}\n\nint main()\n{\n    uint32_t n,m;\n    uint64_t count;\n    scanf(\"%d %d\",&n,&m);\n    printf(\"%lu\\n\",getCount(n,m));\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b5c49988ffcf05ccfda3677837ec5a20", "src_uid": "2ec9e7cddc634d7830575e14363a4657", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nlong long int main(long long int argc, char const *argv[])\n{\n\tlong long int n,m;\n\tscanf(\"%lld%lld\",&n,&m);\n\tlong long int a[m];\n\tfor(long long i=0;i<m;i++)a[i]=0;\n\tlong long int b=2;\n\tfor(long long i=1;i<=m;i++){\n\t\ta[b%m]+=n/m;\n\t\tif(i<=n%m)a[b%m]++;\n\t\tb=b+(2*i+1);\n\t}\n\tb=0;\n\tlong long int sum=0;\n\tfor(long long i=1;i<=m;i++){\n\t\tsum+=a[(m-b%m)%m]*n/m;\n\t\tif(i<=n%m)sum+=a[(m-b%m)%m];\n\t\tb=b+(2*i+1);\n\t}\n\tprintf(\"%lld\\n\",sum);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ca5d12ee02679b3c41179c134d754cb4", "src_uid": "2ec9e7cddc634d7830575e14363a4657", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n\nint main()\n{\n    long long unsigned int n,i,j,result=0;\n    int m;\n    int ss;\n    scanf(\"%I64d\",&n);\n    scanf(\"%d\",&m);\n    if(m==1)\n    {\n        printf(\"%I64d\",n*n);\n        return 0;\n    }\n\n    if(m%2==0)\n    {\n     for(i=1;i<=n;i+=2)\n        for(j=1;j<=i;j+=2)\n        {\n            if( (i*i+j*j)%m==0 && i!=j) result+=2;\n            if( (i*i+j*j)%m==0 && i==j) result+=1;\n        }\n    for(i=2;i<=n;i+=2)\n        for(j=2;j<=i;j+=2)\n        {\n            if( (i*i+j*j)%m==0 && i!=j) result+=2;\n            if( (i*i+j*j)%m==0 && i==j) result+=1;\n        }\n    }\n    else\n    {\n    for(i=1;i<=n;i++)\n        for(j=1;j<=i;j+=1)\n        {\n            if( (i*i+j*j)%m==0 && i!=j) result+=2;\n            if( (i*i+j*j)%m==0 && i==j) result+=1;\n        }\n    }\n\n\n\n    printf(\"%I64d\",result);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6d7a7754b4b8c7c221a9d67bc560affa", "src_uid": "2ec9e7cddc634d7830575e14363a4657", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nlong long int main(long long int argc, char const *argv[])\n{\n\tlong long int n,m;\n\tscanf(\"%lld%lld\",&n,&m);\n\tlong long int a[m];\n\tfor(long long i=0;i<m;i++)a[i]=0;\n\tlong long int b=2;\n\tfor(long long i=1;i<=n;i++){\n\t\ta[b%m]++;\n\t\tb=b+(2*i+1);\n\t}\n\tb=0;\n\tlong long int sum=0;\n\tfor(long long i=1;i<=n;i++){\n\t\tsum+=a[(m-b%m)%m];\n\t\tb=b+(2*i+1);\n\t}\n\tprintf(\"%lld\\n\",sum);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5ebc7de0873f6f348132bfb2d0dd2a34", "src_uid": "2ec9e7cddc634d7830575e14363a4657", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n\nint main()\n{\n    long long unsigned int n,i,j,result=0;\n    int m;\n    int ss;\n    scanf(\"%I64d\",&n);\n    scanf(\"%d\",&m);\n    if(m==1)\n    {\n        printf(\"%I64d\",n*n);\n        return 0;\n    }\n    for(i=1;i<=n;i++)\n        for(j=1;j<=n;j++)\n        {\n            if( (i*i+j*j)%m==0 ) result++;\n        }\n    printf(\"%I64d\",result);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6a9e41d2534f0151ea2ca942deea26d6", "src_uid": "2ec9e7cddc634d7830575e14363a4657", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\ndouble sub(int w, int b) {\n  double win, buf;\n\n  if (w == 0) return 0;\n\n  win = (double)w / (w + b);\n  buf = (double)b / (w + b);\n  b--;\n  if (b <= 0) return win;\n  buf = buf * b / (w + b);\n  b--;\n  if (b == 0)\n    win = win + buf * w/(w+b) * sub(w-1, b);\n  else\n    win = win + buf * w/(w+b) * sub(w-1, b) + buf * b/(w+b) * sub(w, b-1);\n  return win;\n}\n\nint main() {\n  int w, b;\n  double win;\n\n  scanf(\"%d%d\", &w, &b);\n  win = sub(w, b);\n  printf(\"%.9f\", win);\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dd37220671e7c3658c52dcfe9bc64fd1", "src_uid": "7adb8bf6879925955bf187c3d05fde8c", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\ndouble data[1000][1000];\nint visit[1000][1000]={0};\n\ndouble   count (int w, int b)\n{\n    if(visit[w][b]==1)  return data[w][b];\n    else if(w==0){\n        visit[w][b]=1;\n        data[w][b]=0;    \n        return data[w][b];\n    }\n    else if(w==1&&b>2){\n        visit[w][b]=1;\n        data[w][b]=(double)w/(w+b)+(double)b/(w+b)*(b-1)/(w+b-1)*(b-2)/(w+b-2)*count(w,b-3);    \n        return data[w][b];\n    }\n    else if(b==1){\n        visit[w][b]=1;\n        data[w][b]=(double)w/(w+b);\n        return data[w][b];\n    }\n    else if(w>0&&b==0){\n        visit[w][b]=1;\n        data[w][b]=1;\n        return data[w][b];\n    }\n    else if(w==1&&b==2){\n        visit[w][b]=1;\n        data[w][b]=(double)w/(w+b);    \n        return data[w][b];\n    }\n    else if(b==2){\n        printf(\"4\\n\");\n        visit[w][b]=1;\n        data[w][b]=(double)w/(w+b)+(double)b/(w+b)*(b-1)/(w+b-1)*w/(w+b-2);\n        return data[w][b];\n    }\n    else{\n        visit[w][b]=1;\n        data[w][b]=(double)w/(w+b);\n        data[w][b]+=(double)b/(w+b)*(b-1)/(w+b-1)*(b-2)/(w+b-2)*count(w,b-3)+(double)b/(w+b)*(b-1)/(w+b-1)*w/(w+b-1)*count(w-1,b-2);\n        return data[w][b];\n    }\n    \n    \n}\n\n\n\nint main()\n{\n    int w,b;\n    scanf(\"%d%d\",&w,&b);    \n    if(w==0){\n        visit[w][b]=1;\n        data[w][b]=0;    \n    }\n    else if(w==1&&b>2){\n        visit[w][b]=1;\n        data[w][b]=(double)w/(w+b)+(double)b/(w+b)*(b-1)/(w+b-1)*(b-2)/(w+b-2)*count(w,b-3);    \n    }\n    else if(b==1){\n        visit[w][b]=1;\n        data[w][b]=(double)w/(w+b);\n    }\n    else if(w>0&&b==0){\n        visit[w][b]=1;\n        data[w][b]=1;\n    }\n    else if(w==1&&b==2){\n        visit[w][b]=1;\n        data[w][b]=(double)w/(w+b);    \n    }\n    else if(b==2){\n        visit[w][b]=1;\n        data[w][b]=(double)w/(w+b)+(double)b/(w+b)*(b-1)/(w+b-1)*w/(w+b-2);\n    }\n    else{\n        visit[w][b]=1;\n        data[w][b]=(double)w/(w+b)+(double)b/(w+b)*(b-1)/(w+b-1)*(b-2)/(w+b-2)*count(w,b-3)+(double)b/(w+b)*(b-1)/(w+b-1)*w/(w+b-1)*count(w-1,b-2);\n    }\n    printf(\"%.9lf\",data[w][b]);\n    //system(\"pause\");\n    return 0;    \n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "743ff727eebbbefc359a4ac4ad4f9913", "src_uid": "7adb8bf6879925955bf187c3d05fde8c", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<ctype.h>\n#include<math.h>\n#define max(a,b) a>b?a:b\n#define min(a,b) a<b?a:b\n\ndouble dpp[1002][1002][2];\nint main(){\n    long long int n,m;\n    scanf(\"%lld%lld\",&n,&m);\n    long long int i,j;\n    double sum=0;\n    dpp[n][m][1]=1.00;\n    for (i=n; i>=0; i--) {\n        for (j=m; j>=0; j--) {\n            if(i>0 || j>0)\n                sum+=(dpp[i][j][1]*(double)i)/((double)(i+j));\n            if(j>0)\n                dpp[i][j-1][0]+=(double)((dpp[i][j][1]*((double)j)))/((double)(i+j));\n                if(i>0 && j>0)\n                    dpp[i-1][j-1][1]+=(dpp[i][j][0]*((double)(j*i)))/((double)((i+j-1)*(i+j)));\n                if(j>1)\n                    dpp[i][j-2][1]+=(dpp[i][j][0]*((double)((j-1)*j)))/((double)((i+j-1)*(i+j)));\n        }\n    }\n    printf(\"%lf\\n\",sum);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "54e40411347fde87d413755eee539d14", "src_uid": "7adb8bf6879925955bf187c3d05fde8c", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint W,B;\n\tscanf(\"%d %d\",&W,&B);\n\tdouble p[W+1][B+1];\n\n\tfor(int i = 0 ; i <=B ; i++)p[0][i] = 0.000000;\n\tfor(int i = 1 ; i <=W ; i++)p[i][0] = 1.000000;\n\tfor(int i = 1 ; i <=W ; i++)p[i][1] = (int)i/((int)i+1.00000);\n\t\t\t\n\tfor(int ww = 1 ; ww <= W ; ww++)\n\t{\n\t\tfor(int bb = 2; bb<= B; bb++)\n\t\t{\n\t\t\tdouble z1,z2,w=(double)ww,b=(double)bb;\n\t\t\tz1 = (w/(w+b-2)) * p[ww-1][bb-2];\n\t\t\tz2 = (b-2)/(w+b-2);\n\t\t\tif(z2!=0) z2*= p[ww][bb-3]; \n\t\t\tp[ww][bb] = w/(w+b) + ((b*(b-1))/((w+b)*(w+b-1))*(z1+z2));\n\t\t}\n\t}\n\tprintf(\"%.10lf\\n\",p[W][B]);\n\treturn 0;\t\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "30024fed1e0c2031d5229fad44001a63", "src_uid": "7adb8bf6879925955bf187c3d05fde8c", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main(){\n    int w,b;\n    scanf(\"%d %d\", &w, &b);\n    double Pr[w+3][b+3];\n    memset(Pr, 0, sizeof(double)*(w+3)*(b+3));\n    for( int i = 3; i < (w + 3); i++)\n        Pr[i][2] = 1;\n    int x,y;\n    for(int i = 3; i < (w + 3); i++){\n        for( int j = 3; j < (b + 3); j++){\n            x = i - 2;\n            y = j - 2;\n            Pr[i][j] = (double)(x)/(x+y) + \n                ((double)((y)*(y-1))/((x+y)*(x+y-1))) *\n                   ( ((double)(y-2)/(x+y-2))*Pr[i][j-3] + \n                        ((double)x/(x+y-2))*Pr[i-1][j-2]);\n            \n        }\n    }\n    printf(\"%.9f\\n\", Pr[w+2][b+2]);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fd354e63bd60663e9a76c33cbdba7d4b", "src_uid": "7adb8bf6879925955bf187c3d05fde8c", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "/* Practice with Dukkha and rainboy */\n#include <stdio.h>\n\n#define MD 1000000007\n\nint main() {\n\tlong long n, m, x, ans;\n\n\tscanf(\"%lld%lld\", &n, &m);\n\tx = (1 << m) - 1;\n\tans = 1;\n\twhile (n--)\n\t\tans = ans * x % MD;\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "833079cda466feaa8bfe837f4795344f", "src_uid": "71029e5bf085b0f5f39d1835eb801891", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "/*******************************\n**Created by Libra at 2020-05-24 16:44.\n**Copyright @ Weilong Jiang.\n** Descibe: \u6bcf\u79cd\u793c\u7269\u7684\u653e\u7f6e\u76f8\u4e92\u72ec\u7acb\uff0c\u4e3a\u4fdd\u8bc1\u6bcf\u79cd\u793c\u7269\u81f3\u5c11\u653e\u4e00\u4e2a\uff0c\u5355\u79cd\u793c\u7269\u7684\u653e\u7f6e\u65b9\u5f0f\u4e3a2^m-1,n\u79cd\u793c\u7269\u5c31\u6709(2^m-1)^n\n*******************************/\n\n#include <stdio.h>\ntypedef long long ll;\nconst ll mod = 1e9 + 7;\n\nll quick_power_mod(ll, ll);\n\nint main(int argc, const char *argv[]) {\n    int presents = -1, boxes = -1;\n    scanf(\"%d%d\", &presents, &boxes);\n    ll res = -1;\n    res = quick_power_mod(2, boxes) - 1;\n    // res = (res >= 0) ? res : (mod - res);\n\n    prllf(\"%d\", quick_power_mod(res, presents));\n    return 0;\n}\n\nll quick_power_mod(ll a, ll b) {\n    ll res = 1, base = a % mod;\n    while (b) {\n        if (b & 1)\n            res = res * base % mod;\n        base = base * base % mod;\n        b >>= 1;\n    }\n    return res;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "202e7dc8d7e69b438a41bd41cb8765bc", "src_uid": "71029e5bf085b0f5f39d1835eb801891", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "/*******************************\n**Created by Libra at 2020-05-24 16:44.\n**Copyright @ Weilong Jiang.\n** Descibe: \u6bcf\u79cd\u793c\u7269\u7684\u653e\u7f6e\u76f8\u4e92\u72ec\u7acb\uff0c\u4e3a\u4fdd\u8bc1\u6bcf\u79cd\u793c\u7269\u81f3\u5c11\u653e\u4e00\u4e2a\uff0c\u5355\u79cd\u793c\u7269\u7684\u653e\u7f6e\u65b9\u5f0f\u4e3a2^m-1,n\u79cd\u793c\u7269\u5c31\u6709(2^m-1)^n\n*******************************/\n\n#include <stdio.h>\ntypedef long long ll;\nconst ll mod = 1e9 + 7;\n\nll quick_power_mod(ll, ll);\n\nint main(int argc, const char *argv[]) {\n    int presents = -1, boxes = -1;\n    scanf(\"%d%d\", &presents, &boxes);\n    ll res = -1;\n    res = quick_power_mod(2, boxes) - 1;\n    // res = (res >= 0) ? res : (mod - res);\n\n    prllf(\"%lld\", quick_power_mod(res, presents));\n    return 0;\n}\n\nll quick_power_mod(ll a, ll b) {\n    ll res = 1, base = a % mod;\n    while (b) {\n        if (b & 1)\n            res = res * base % mod;\n        base = base * base % mod;\n        b >>= 1;\n    }\n    return res;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "51554a5ab0daa8de9af208850e7a3b03", "src_uid": "71029e5bf085b0f5f39d1835eb801891", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdbool.h>\n#include <stdlib.h>\n#include <string.h>\n\nlong long readLong();\n\nlong long pow(long long a, long long n) {\n    if ( n==(((long long) 0)) ) return ((long long) 1);\n    if ( n%2==(((long long) 1)) ) {\n        long long tmp = pow(a,n-1);\n        return (tmp*a)%MOD;\n    }\n    else {\n        long long c = pow(a,n/2);\n        return (c*c)%MOD;\n    }\n}\n\nint main() {\n\n    long long MOD = ((long long) 1000000007);\n    long long n = readLong();\n    long long m = readLong();\n    printf(\"%l64d\", (pow((pow(((long long) 2),m)-1),n)));\n    \n}\nlong long readLong() {\n    long long t;\n    scanf(\"%l64d\", &t);\n    return t;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "65c5b6b32bf7b8c01ac6718be3c88c33", "src_uid": "71029e5bf085b0f5f39d1835eb801891", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nconst int mod=1e9+7;\n\nlong int powof(long int p,long int n)\n{\n\tif(n==0) return 1;\n\tif(n%2==0)\n\t\treturn powof(((p%mod)*(p%mod))%mod,n)%mod;\n\telse\n\t\treturn ((p%mod)*(powof(((p%mod)*(p%mod))%mod,(n/2)%mod)%mod))%mod;\n}\n\nint main()\n{\n\tlong int n,m,ans=1,p=1;\n\tscanf(\"%ld %ld\",&n,&m);\n\tp=powof(2,m)-1;\n\t\n\tans=powof(p,n);\n\tprintf(\"%ld\\n\",ans);\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "496af6d26ce86cc1af48452cfc179612", "src_uid": "71029e5bf085b0f5f39d1835eb801891", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\r\n#include<algorithm>\r\nusing namespace std;\r\nint main(){\r\n    int t;\r\n    cin>>t;\r\n    int steps;\r\n    for(int i=0;i<t;i++)\r\n    {\r\n        int me,wa,gcd;\r\n        int e,w;\r\n        cin>>me;\r\n        wa = 100-me;\r\n        gcd = __gcd(me,wa);\r\n        e = me/gcd;\r\n        w = wa/gcd;\r\n        steps = e + w;\r\n\r\n    }\r\n    cout<<steps<<endl;\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "78618aa40a0d215ef30253d116f61958", "src_uid": "19a2bcb727510c729efe442a13c2ff7c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\r\n#include<algorithm>\r\nusing namespace std;\r\nint main(){\r\n    int t;\r\n    cin>>t;\r\n    for(int i=0;i<t;i++)\r\n    {\r\n        int me,wa,gcd;\r\n        int e,w;\r\n        int steps;\r\n        cin>>me;\r\n        wa = 100-me;\r\n        gcd = __gcd(me,wa);\r\n        e = me/gcd;\r\n        w = wa/gcd;\r\n        steps = e + w;\r\n        cout<<steps<<endl;\r\n\r\n    }\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1efb3c9ba1392707d568c7d0feff1106", "src_uid": "19a2bcb727510c729efe442a13c2ff7c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <bits/stdc++.h>\r\nusing namespace std;\r\n\r\nint main() {\r\n    int tc;\r\n    cin>>tc;\r\n    while(tc--) {\r\n        int k,ans;\r\n        cin>>k;\r\n        if(100%k==0) {\r\n            ans=100/k;\r\n        }else if(k%2==0 || k%5==0) {\r\n                if(k%2==0 && k%5!=0) {\r\n                    if(k%4==0){\r\n                        ans=25;\r\n                    }else{\r\n                        ans=50;\r\n                    }\r\n                }else if(k%2!=0 && k%5==0) {\r\n                    if(k%25==0){\r\n                        ans=4;\r\n                    }else{\r\n                        ans=20;\r\n                    }\r\n                }else{\r\n                    if(k%20==0){\r\n                        ans=5;\r\n                    }else{\r\n                        ans=10;\r\n                    }\r\n                }\r\n        }else{\r\n            ans=100;\r\n        }\r\n        cout<<ans<<endl;\r\n    }\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0803d6310e0966595f2471f7de059e85", "src_uid": "19a2bcb727510c729efe442a13c2ff7c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\nint main() {\r\n    int t;\r\n    scanf(\"%d\", &t);\r\n\r\n    int i = 0;\r\n    while (i < t) {\r\n        int k;\r\n        scanf(\"%d\", &k);\r\n\r\n        int water = 100 - k;\r\n\r\n        if (water % k == 0) {\r\n            water = water / k;\r\n            k = k / k;\r\n        }\r\n\r\n        int steps = water + k;\r\n        printf(\"%d\\n\", steps)\r\n        i++;\r\n    }\r\n\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "eaed13e55b077bcc73477eaf21bf89a0", "src_uid": "19a2bcb727510c729efe442a13c2ff7c", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <bits/stdc++.h>\r\nusing namespace std;\r\nstring toGoatLatin(string sent) {\r\n        string s = \"\";\r\n        vector<string> v;\r\n        int i = 0;\r\n        while(sent[i] != '\\0')\r\n        {\r\n            if(sent[i] == ' ')\r\n            {\r\n                v.push_back(s);\r\n                s = \"\";\r\n            }\r\n            else {\r\n                s += sent[i];\r\n            }\r\n            i++;\r\n        }\r\n        v.push_back(s);\r\n        s = \"\";\r\n        for(int i = 0; i < v.size(); i++)\r\n        {\r\n            for(int j = 0; j < v[i].size(); j++)\r\n            {\r\n                cout << v[i][j];\r\n            }\r\n            cout << endl;\r\n        }\r\n        string a = \"maa\";\r\n        for(int i = 0; i < v.size(); i++)\r\n        {\r\n            if(v[i][0] == 'A' || v[i][0] == 'E' || v[i][0] == 'I' || v[i][0] == 'O' || v[i][0] == 'U' || v[i][0] == 'a' || v[i][0] == 'e' || v[i][0] == 'i' || v[i][0] == 'o' || v[i][0] == 'u')\r\n            {\r\n                v.push_back(a);\r\n                \r\n                for(int j = 1; j < i; j++){\r\n                    v.push_back(\"a\");\r\n                }\r\n            }\r\n            else {\r\n                char ch = v[i].front();\r\n                v[i].erase(v[0].begin());\r\n                v[i].push_back(ch);\r\n                v[i].push_back('m');\r\n                v[i].push_back('a');\r\n                for(int j = 0; j < i; j++)\r\n                {\r\n                    v[i].push_back('a');\r\n                }\r\n            }\r\n        }\r\n        s = \"\";\r\n        for(int i = 0; i < v.size(); i++)\r\n        {\r\n            for(int j = 0; j < v[i].size(); j++)\r\n            {\r\n                cout << v[i][j];\r\n            }\r\n            cout << endl;\r\n        }\r\n        // for(int i = 0; i < v.size(); i++)\r\n        // {\r\n        //     s.push_back(v[i]);\r\n        //     string a = \" \";\r\n        //     s.push_back(a);\r\n        // }\r\n        // s.pop_back();\r\n        return s;\r\n}\r\nint main()\r\n{\r\n    string s;\r\n    getline(cin, s);\r\n    cout << toGoatLatin(s);\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0ae9c19f425c65cac36931310efc7fcb", "src_uid": "19a2bcb727510c729efe442a13c2ff7c", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\nint a,b,c,t;\nscanf(\"%d%d%d\",&a,&b,&c);\nfor(t=0; ;t++)\n    if((t*b+c*b)>=a*c){\n            break;\n    }\nprintf(\"%d\",t);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4fe9b4959adfb53f2fb2664633c979b0", "src_uid": "7dd098ec3ad5b29ad681787173eba341", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint fun(int a,int b,int c)\n{\n    int x;\n    int diff=a*c-b*c;\n    int result=diff/b;  \n    result=result*b;\n    \n    if ( result == diff ) {\n                 return diff/b;\n    } else { \n                       x=diff%b;\n                       x=b-x;\n                       diff+=x;\n                 return diff/b;\n}\n}\nint main(int argc, char *argv[])\n{\n  int a,b,c,res;\n  scanf(\"%d %d %d\",&a,&b,&c);\n  res=fun(a,b,c);\n  printf(\"%d\",res);\n  system(\"PAUSE\");  \n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "87c02aad8056d8376083d44e930a8aed", "src_uid": "7dd098ec3ad5b29ad681787173eba341", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint f[100005];\n\nmain(){\n\tint n, m, i, t;\n\tscanf(\"%d%d\",&n,&m);\n\tif (m%2==1){\n\t\ti=1;\n\t\tf[0]=m/2+1;\n\t}\n\telse i=0;\n\tfor (t=m/2;i<m;++i){\n\t\tf[i]=t;\n\t\tf[++i]=m-t+1;\n\t\tt=t-1;\n\t}\n\tfor (i=0;i<n;++i) printf(\"%d\\n\",f[i%m]);\n\tsystem(\"pause\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fd58ca28c125e90df0dd37a57b6c646f", "src_uid": "7dd098ec3ad5b29ad681787173eba341", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n\tint a,b,c,t,temp;\n\tscanf(\"%d\",&a);\n\tscanf(\"%d\",&b);\n\tscanf(\"%d\",&c);\n\ttemp=a*c;\n\tt=temp/b;\n\tif(t*b>=temp)\n\tprintf(\"%d\\n\",t-c);\n\telse\n\tprintf(\"%d\",(t+1)-c);\n\tgetch();\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "11573ca8c6b88c1ff120a325a0ab8184", "src_uid": "7dd098ec3ad5b29ad681787173eba341", "difficulty": 1000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n\nint main() {\n    float a,b,c,d,e,f,g;\n    scanf(\"%f%f%f\",&a,&b,&c);\n    \n    d = a * c;\n    e = b * c;\n    f = d - e;\n    g = f / b;\n    \n    //if( (g * b) != f) ++g;\n\n    ceil(g);\n    \n    \n    printf(\"%.f\",g);\n    \n    getch();\n    \n    return 0;   \n    \n    \n    }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "96729e89326e70151549e3893b074571", "src_uid": "7dd098ec3ad5b29ad681787173eba341", "difficulty": 1000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main() {\n\tint n;\n\tint i;\n\tint a, b = 0, c = 0;\n\tint sum = 0;\n\tscanf(\"%d\", &n);\n\tscanf(\"%d\", &c);\n\tfor(i=1; i<n; i++) {\n\t\ta = b;\n\t\tb = c;\n\t\tscanf(\"%d\", &c);\n\t\tif(b + c == 5) {\n\t\t\tprintf(\"Infinite\");\n\t\t\treturn 0;\n\t\t}\n\t\tsum += b + c;\n\t\tif(a == 3 && b == 1 && c == 2) sum--;\n\t}\n\tprintf(\"Finite\\n\");\n\tprintf(\"%d\", sum);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7297ec2abb379c2f231fac3373d887a0", "src_uid": "6c8f028f655cc77b05ed89a668273702", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int i,n,count=0;\n    scanf(\"%d\",&n);\n    int a[n];\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    for(i=0;i<n-1;)\n    {\n        if((a[i]==2&&a[i+1]==3) || (a[i]==3&&a[i+1]==2))\n        {\n            printf(\"Infinite\");\n            return;\n        }\n        if(a[i]==3&&a[i+1]==1&&a[i+2]==2)\n        {\n            count=count+6;\n            i=i+2;\n        }\n        if((a[i]==3&&a[i+1]==1)||(a[i]==1&&a[i+1]==3))\n        {\n            count=count+4;\n            i=i+1;\n        }\n        if((a[i]==1&&a[i+1]==2)||(a[i]==2&&a[i+1]==1))\n        {\n            count=count+3;\n            i=i+1;\n        }\n    }\n    if(count!=0)\n    {\n        printf(\"Finite\\n\");\n        printf(\"%d\",count);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c221be5ed2b85cfb9c789d8d190523ec", "src_uid": "6c8f028f655cc77b05ed89a668273702", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n, i;\n    int a[100] = {0};\n    int count = 0;\n    int p, q;\n    int flag = 1;\n\n    scanf(\"%d\", &n);\n    for (i = 0; i < n; i++)\n    {\n        scanf(\"%d\", a + i);\n    }\n\n    i = 0;\n    while(a[i+1])\n    {\n        p = a[i];\n        q = a[i + 1];\n        if(p == 1)\n        {\n            if(q == 2)\n                count += 3;\n            else if(q == 3)\n                count += 4;\n        }\n        if(p == 2)\n        {\n            if(q == 1)\n                count += 3;\n            else if(q == 3)\n            {\n                flag = 0;\n                break;\n            }\n        }\n        if(p == 3)\n        {\n            if(q == 1)\n                count += 4;\n            else if(q == 2)\n            {\n                flag = 0;\n                break;\n            }\n        }\n        i++;\n    }\n    if(flag)\n    {\n        printf(\"Finite\\n\");\n        printf(\"%d\\n\", count);\n    }\n    else\n        printf(\"Infinite\");\n\n    system(\"pause\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9a06ce0f1099c5f97009c71133be4d6c", "src_uid": "6c8f028f655cc77b05ed89a668273702", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n,i,j=0,a[105],k=0;\n    scanf(\"%d\",&n);\n    for (i=0;i<n;i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    for (i=0;i<n-1;i++)\n    {\n        if ((a[i]==2&&a[i+1]==3)||(a[i]==3&&a[i+1]==2))\n        {\n            printf(\"Infinite\\n\");\n            return 0;\n        }\n        else if ((a[i]==1&&a[i+1]==2)||(a[i]==2&&a[i+1]==1))\n        {\n            k++;\n            j+=3;\n            if (i>1)\n            {\n                if(a[i]==2&&a[i-2]==3)\n                    j--;\n            }\n        }\n        else if ((a[i]==1&&a[i+1]==3)||(a[i]==3&&a[i+1]==1))\n        {\n\n            j+=4;\n        }\n\n    }\n    printf(\"Finite\\n%d\\n\",j);\n    return k;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fb48b3e13dfff5b4dbf95254f5c62cb9", "src_uid": "6c8f028f655cc77b05ed89a668273702", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int i,n,count=0;\n    scanf(\"%d\",&n);\n    int a[n];\n    for(i=0; i<n; i++)\n    {\n        scanf(\"%d\",&a[i]);\n    }\n    for(i=0; i<n-1;)\n    {\n        if((a[i]==2&&a[i+1]==3) || (a[i]==3&&a[i+1]==2))\n        {\n            printf(\"Infinite\");\n            return 0;\n        }\n         else if((a[i]==1&&a[i+1]==2)||(a[i]==2&&a[i+1]==1))\n        {\n            count=count+3;\n            i=i++;\n        }\n        else if(a[i]==3&&a[i+1]==1&&a[i+2]==2)\n        {\n            count=count+6;\n            i=i+2;\n        }\n        else if((a[i]==3&&a[i+1]==1)||(a[i]==1&&a[i+1]==3))\n        {\n            count=count+4;\n            i=i++;\n        }\n    }\n    if(count>0)\n    {\n        printf(\"Finite\\n%d\\n\",count);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ca7a4b09f4c74d597b76530b5a65a255", "src_uid": "6c8f028f655cc77b05ed89a668273702", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <cstdio>\r\n\r\nint main(){\r\n    short n;\r\n    scanf(\"%hi\", &n);\r\n    if(n < 1200) printf(\"1200\");\r\n    else if(n < 1400) printf(\"1400\");\r\n    else if(n < 1600) printf(\"1600\");\r\n    else if(n < 1900) printf(\"1900\");\r\n    else if(n < 2100) printf(\"2100\");\r\n    else if(n < 2300) printf(\"2300\");\r\n    else if(n < 2400) printf(\"2400\");\r\n    else if(n < 2600) printf(\"2600\");\r\n    else if(n < 3000) printf(\"3000\");\r\n\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e98fd01da3c91435f8e9fdf974f16292", "src_uid": "22725effa6dc68b9c2a499d148e613c2", "difficulty": -1.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\nint main(){\r\n    int n;\r\n    scanf(\"%d\",&n);\r\n    if(n < 1200){\r\n        printf(\"%d\\n\",1200);\r\n    }\r\n    else if(n < 1400){\r\n        printf(\"%d\\n\",1400);\r\n    }\r\n    else if(n < 1600){\r\n        printf(\"%d\\n\",1600);\r\n    }\r\n    else if(n < 1900){\r\n        printf(\"%d\\n\",1900);\r\n    }\r\n    else if(n < 2100){\r\n        printf(\"%d\\n\",2100);\r\n    }\r\n    else if(n < 2300){\r\n        printf(\"%d\\n\",2300); \r\n    }\r\n    else if(n < 2400){\r\n        printf(\"%d\\n\",2400); \r\n    }\r\n    else if(n < 2600){\r\n        printf(\"%d\\n\",2600); \r\n    }\r\n    else if(n < 3000){\r\n        printf(\"%d\\n\",3000);\r\n    }\r\n    return 0:\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2d001b245447b5333e6027f860911d0e", "src_uid": "22725effa6dc68b9c2a499d148e613c2", "difficulty": -1.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\nint main() {\r\n\tint n;\r\n\tscanf(\"%d\", &n);\r\n\tint num[]={1200,1400,1600,1900,2100,2300,2400,2600,3000};\r\n\tint i = 0;\r\n\twhile(num[i] <= n) i++;\r\n\tprintf(\"%d\", num[i]);\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f6c53693e5d5e16cd5a6bb3315aab374", "src_uid": "22725effa6dc68b9c2a499d148e613c2", "difficulty": -1.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n#include<string.h>\r\nint main(){\r\n    int r;\r\n    scanf(\"%d\",&r);\r\n    if(r<1200){\r\n        printf(\"1200\\n\");\r\n    }\r\n    else if(r<1400){\r\n        printf(\"1400\\n\");\r\n    }\r\n    else if(r<1600){\r\n        printf(\"1600\\n\");\r\n    }\r\n    else if(r<1900){\r\n        printf(\"1900\\n\");\r\n    }\r\n    else if(r<2100){\r\n        printf(\"2100\\n\");\r\n    }\r\n    else if(r<2300){\r\n        printf(\"2300\\n\");\r\n    }\r\n    else if(r<2400){\r\n        printf(\"2400\\n\");\r\n    }\r\n    else if(r<2600){\r\n        printf(\"2600\\n\");\r\n    }\r\n    else{\r\n        printf(\"3000\\n\");\r\n    }\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "817abed9c66526ee32e01ccfea7a14ee", "src_uid": "22725effa6dc68b9c2a499d148e613c2", "difficulty": -1.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main() {\n\tint n;\n\tscanf(\"%d\", &n);\n\tint num[]={1200,1400,1600,1900,2100,2300,2400,2600,3000};\n\tint i = 0;\n\twhile(num[i] <= n) i++;\n\tprintf(\"%d\", num[i]);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "06e6e3cbc32c5fa0c2d37db9732b7cd3", "src_uid": "22725effa6dc68b9c2a499d148e613c2", "difficulty": -1.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int a,b,c;\n    scanf(\"%d%d%d\",&a,&b,&c);\n    int n;\n    for(int i=2;i<=c;i++){\n        n=a+b;\n        a=b;\n        b=n;\n    }\n    else printf(\"%d\",b);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e8574308c7d29c7c4b8adfaea7f5e6b2", "src_uid": "6ff30f5a9afc3f7befca813469188aab", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long a1,a2,a3;//\u5b9a\u4e49a1\u3001a2\u3001a3\n    long long *d;//\u5b9a\u4e49\u4e00\u4e2a\u6307\u9488\n    scanf(\"%ld%ld%ld\",&a1,&a2,&a3);//\u8f93\u5165x\u3001y\u3001z\n    d[0]=a1;//\u7b2c1\u9879\u4e3aa1\n    d[1]=a2;//\u7b2c2\u9879\u4e3aa2\n    for(int i=2;i<=z;++i)//\u4ece\u4e0b\u6807\u4e3a2\u7684\u5143\u7d20\u5f00\u59cb\u904d\u5386\n    d[i]=d[i-1]+d[i-2];//\u8fd9\u662f\u9012\u63a8\u516c\u5f0f\n    printf(\"%ld\",d[z]);//\u6700\u540e\u8f93\u51fa\u7b2cc\u9879\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "51954c623a76a9b3bbce3e315956a597", "src_uid": "6ff30f5a9afc3f7befca813469188aab", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int x,y,z,*d;\n    scanf(\"%d%d%d\",&x,&y,&z);\n    d[0]=a;//\u7b2c1\u9879\u4e3aa\n    d[1]=b;//\u7b2c2\u9879\u4e3ab\n    for(int i=2;i<=c;i++)\n    d[i]=d[i-1]+d[i-2];//\u8fd9\u662f\u9012\u63a8\u516c\u5f0f\n    printf(\"%d\",&d[c]);//\u6700\u540e\u8f93\u51fa\u7b2cc\u9879\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "6922a69ea73810adc40e48077efc4fe1", "src_uid": "6ff30f5a9afc3f7befca813469188aab", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include \"stdio.h\"\n\nint a[25], n, i;\n\nint main()\n{\n\tscanf( \"%d%d%d\", &a[0], &a[1], &n );\n\tfor( i = 2; i <= n; i++ ) a[i] = a[i-1] + a[i-2];\n\tprintf( \"%d\\n\", a[n] );\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "29ecb66946ea45c74da346d50515f822", "src_uid": "6ff30f5a9afc3f7befca813469188aab", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long a1,a2,a3;//\u5b9a\u4e49a1\u3001a2\u3001a3\n    long long d[1000];//\u5b9a\u4e49\u4e00\u4e2a\u6307\u9488\n    scanf(\"%lld%lld%lld\",&a1,&a2,&a3);//\u8f93\u5165a1\u3001a2\u3001a3\n    d[0]=a1;//\u7b2c1\u9879\u4e3aa1\n    d[1]=a2;//\u7b2c2\u9879\u4e3aa2\n    for(int i=2;i<=a3;++i)//\u4ece\u4e0b\u6807\u4e3a2\u7684\u5143\u7d20\u5f00\u59cb\u904d\u5386\n    d[i]=d[i-1]+d[i-2];//\u8fd9\u662f\u9012\u63a8\u516c\u5f0f\n    printf(\"%lld\",d[a3]);//\u6700\u540e\u8f93\u51fa\u7b2ca3\u9879\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1905a606b9906332041eb23f84fe1ea8", "src_uid": "6ff30f5a9afc3f7befca813469188aab", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nchar a[101],c[101];\nint before[101][101];//before[POS][Chk];\nint beforeI[101][101];\nmain(){\n    int i,j,k,l,b,d,lenL=0,lenS=0,curChk=0,maxL,maxS,usebefore,first=-1,last=-1,point=i,memo,ans=0,remain,tmpa,tmpb,tmpChk;\n    scanf (\"%d%d\",&b,&d);\n    scanf (\"%s%s\",a,c);\n    while (a[lenL]!=0)lenL++;\n    while (c[lenS]!=0)lenS++;\n    if (lenL*b<lenS*d){ //EXIT if can't possible\n        printf (\"0\");\n        exit(0);\n    }\n    maxL=lenL*b;\n    maxS=lenS*d;\n    for (i=0;i<maxL;i++){\n        /*if (first%lenL==i%lenL&&curChk%lenS==0){\n            point=i;\n            remain = maxL-i+1;\n            memo=point-first+1;\n            curChk += (remain/memo)*curChk;\n            //printf (\"%d %d\\n\",maxL-i,memo);\n            i+=(remain/memo)*(i-1);\n            //i=maxL;\n        }*/\n            if (curChk==0&&i>lenL){\n                printf (\"0\");\n                exit(0);\n            }\n            if (before[i%lenL][curChk%lenS]==0){\n                before[i%lenL][curChk%lenS]=curChk;\n                beforeI[i%lenL][curChk%lenS]=i;\n                if (a[i%lenL]==c[curChk%lenS]) curChk++;\n                //printf (\"test\\n\");\n            }else if (maxL-i>i-beforeI[i%lenL][curChk%lenS]){\n                tmpChk=curChk;\n                tmpa=beforeI[i%lenL][curChk%lenS];\n                tmpb=before[i%lenL][curChk%lenS];\n                before[i%lenL][curChk%lenS]=curChk;\n                beforeI[i%lenL][curChk%lenS]=i;\n                //printf (\"GG\\n\");\n                curChk+=(curChk-tmpb)*((maxL-i)/(i-tmpa));\n                i+=(i-tmpa)*((maxL-i)/(i-tmpa))-1;\n                //curChk+=(curChk-before[i%lenL][curChk%lenS])*tmpb;\n                //i+=(i-tmpa)*tmpb;\n                //curChk+=tmpChk-before[i%lenL][curChk%lenS];\n                //i+=i-tmpa;\n            }else{\n                if (a[i%lenL]==c[curChk%lenS])curChk++;\n            }\n            /*if (curChk==lenS){\n                    last=i;\n            }*/\n            //curChk++;\n            //if (curChk%maxS==0) ans++;\n\n        /*\n        if (curChk>=maxS&&first%lenL==i%lenL&&curChk%lenS==1){\n            point=i;\n            remain = maxL-i;\n            memo=point-first;\n            ans += remain/memo*ans;\n            //printf (\"%d %d\\n\",maxL-i,memo);\n            i+=(remain/memo)*memo;\n            //i=maxL;\n        }*/\n        /*\n        if (first%lenL==i%lenL&&curChk%lenS==0){\n            point=i;\n            remain = maxL-i;\n            memo=point-first+1;\n            curChk += (remain/memo)*curChk;\n            //printf (\"%d %d\\n\",maxL-i,memo);\n            i=(remain/memo)*i;\n            //i=maxL;\n        }\n        */\n    }\n    //printf (\"%d\",curChk/maxS);\n    //printf (\"%d : %d\\n\",i,curChk);\n    printf (\"%d\",curChk/maxS);\n    exit(0);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a1fad8c7053fde69a10a70f502dec4ea", "src_uid": "5ea0351ac9f949dedae1928bfb7ebffa", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nchar a[101],c[101];\n\nmain(){\n    int i,j,k,l,b,d,lenL=0,lenS=0,curChk=0,maxL,maxS,usebefore,first=-1,last=-1,point=i,memo,ans=0;\n    scanf (\"%d%d\",&b,&d);\n    scanf (\"%s%s\",a,c);\n    while (a[lenL]!=0)lenL++;\n    while (c[lenS]!=0)lenS++;\n    if (lenL*b<lenS*d){ //EXIT if can't possible\n        printf (\"0\");\n        exit(0);\n    }\n    maxL=lenL*b;\n    maxS=lenS*d;\n    for (i=0;i<maxL;i++){\n        if (a[i%lenL]==c[curChk%lenS]){\n            if (curChk==0)first=i;\n            curChk++;\n            if (curChk==lenS){\n                    last=i;\n            }\n        }\n        if (curChk>=maxS&&first%lenL==i%lenL){\n            point=i;\n            memo=point-first+1;\n            ans = (maxL-i)/memo;\n            //printf (\"%d %d\\n\",maxL-i,memo);\n            i+=ans*memo;\n            //i=maxL;\n        }\n    }\n    //printf (\"%d\",curChk/maxS);\n    if (ans>0) printf (\"%d\",ans+1);\n    else printf (\"%d\",curChk/maxS);\n    exit(0);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8112ecabf370c1891357000aae22badb", "src_uid": "5ea0351ac9f949dedae1928bfb7ebffa", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nchar a[101],c[101];\n\nmain(){\n    int i,j,k,l,b,d,lenL=0,lenS=0,curChk=0,maxL,maxS,usebefore,first=-1,last=-1,point=i,memo,ans=0;\n    scanf (\"%d%d\",&b,&d);\n    scanf (\"%s%s\",a,c);\n    while (a[lenL]!=0)lenL++;\n    while (c[lenS]!=0)lenS++;\n    if (lenL*b<lenS*d){ //EXIT if can't possible\n        printf (\"0\");\n        exit(0);\n    }\n    maxL=lenL*b;\n    maxS=lenS*d;\n    for (i=0;i<maxL;i++){\n        if (a[i%lenL]==c[curChk%lenS]){\n            if (curChk==0)first=i;\n            curChk++;\n            if (curChk==lenS){\n                    last=i;\n            }\n        }\n        if (curChk>=maxS&&first%lenL==i%lenL){\n            point=i;\n            memo=point-first;\n            ans = (maxL-i+1)/memo+1;\n            //printf (\"%d %d\\n\",maxL-i,memo);\n            //i+=ans*memo;\n            i=maxL;\n        }\n    }\n    //printf (\"%d\",curChk/maxS);\n    if (ans>0) printf (\"%d\",ans);\n    else printf (\"%d\",curChk/maxS);\n    exit(0);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4d2b5a719b4199bdad8c20e692a1de10", "src_uid": "5ea0351ac9f949dedae1928bfb7ebffa", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nchar a[101],c[101];\nint before[101][101];//before[POS][Chk];\nint beforeI[101][101];\nmain(){\n    int i,j,k,l,b,d,lenL=0,lenS=0,curChk=0,maxL,maxS,usebefore,first=-1,last=-1,point=i,memo,ans=0,remain,tmpa,tmpb,tmpChk;\n    scanf (\"%d%d\",&b,&d);\n    scanf (\"%s%s\",a,c);\n    while (a[lenL]!=0)lenL++;\n    while (c[lenS]!=0)lenS++;\n    if (lenL*b<lenS*d){ //EXIT if can't possible\n        printf (\"0\");\n        exit(0);\n    }\n    maxL=lenL*b;\n    maxS=lenS*d;\n    for (i=0;i<maxL;i++){\n        /*if (first%lenL==i%lenL&&curChk%lenS==0){\n            point=i;\n            remain = maxL-i+1;\n            memo=point-first+1;\n            curChk += (remain/memo)*curChk;\n            //printf (\"%d %d\\n\",maxL-i,memo);\n            i+=(remain/memo)*(i-1);\n            //i=maxL;\n        }*/\n            if (before[i%lenL][curChk%lenS]==0){\n                before[i%lenL][curChk%lenS]=curChk;\n                beforeI[i%lenL][curChk%lenS]=i;\n                if (a[i%lenL]==c[curChk%lenS]) curChk++;\n            }else if ((maxL-i)>(i-tmpa)){\n                tmpChk=curChk;\n                tmpa=beforeI[i%lenL][curChk%lenS];\n                tmpb=before[i%lenL][curChk%lenS];\n                curChk+=(curChk-tmpb)*((maxL-i)/(i-tmpa));\n                i+=(i-tmpa)*((maxL-i)/(i-tmpa))-1;\n                //curChk+=(curChk-before[i%lenL][curChk%lenS])*tmpb;\n                //i+=(i-tmpa)*tmpb;\n                //curChk+=tmpChk-before[i%lenL][curChk%lenS];\n                //i+=i-tmpa;\n            }else{\n                if (a[i%lenL]==c[curChk%lenS])curChk++;\n            }\n            /*if (curChk==lenS){\n                    last=i;\n            }*/\n            //curChk++;\n            //if (curChk%maxS==0) ans++;\n\n        /*\n        if (curChk>=maxS&&first%lenL==i%lenL&&curChk%lenS==1){\n            point=i;\n            remain = maxL-i;\n            memo=point-first;\n            ans += remain/memo*ans;\n            //printf (\"%d %d\\n\",maxL-i,memo);\n            i+=(remain/memo)*memo;\n            //i=maxL;\n        }*/\n        /*\n        if (first%lenL==i%lenL&&curChk%lenS==0){\n            point=i;\n            remain = maxL-i;\n            memo=point-first+1;\n            curChk += (remain/memo)*curChk;\n            //printf (\"%d %d\\n\",maxL-i,memo);\n            i=(remain/memo)*i;\n            //i=maxL;\n        }\n        */\n    }\n    //printf (\"%d\",curChk/maxS);\n    //printf (\"%d : %d\\n\",i,curChk);\n    printf (\"%d\",curChk/maxS);\n    exit(0);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8ca079df202dd5c4d91b840d0f7314b0", "src_uid": "5ea0351ac9f949dedae1928bfb7ebffa", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nchar a[101],c[101];\n\nmain(){\n    int i,j,k,l,b,d,lenL=0,lenS=0,curChk=0,maxL,maxS;\n    scanf (\"%d%d\",&b,&d);\n    scanf (\"%s%s\",a,c);\n    while (a[lenL]!=0)lenL++;\n    while (c[lenS]!=0)lenS++;\n    if (lenL*b<lenS*d){ //EXIT if can't possible\n        printf (\"0\");\n        exit(0);\n    }\n    maxL=lenL*b;\n    maxS=lenS*d;\n    for (i=0;i<maxL;i++){\n        if (a[i%lenL]==c[curChk%lenS]){\n            curChk++;\n        }\n    }\n    printf (\"%d\",curChk/maxS);\n    exit(0);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "144e369d098eb4e6605f7301d43e5cef", "src_uid": "5ea0351ac9f949dedae1928bfb7ebffa", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include<string.h>\nint main(){\n\tint l,r,i,a[10],j;\n\tmemset(a,0,sizeof(a));\n\tscanf(\"%d%d\",&l,&r);\n\t\n\tfor(;l<=r;l++)\n\t{   j=l;\n\t\tfor(;j>0;)\n\t\t{\n\t\ta[j%10]++;\n\t\tj=j/10;\n\t\t}\n\t\tif(a[0]<2 &&a[1]<2 &&a[2]<2 &&a[3]<2 &&a[4]<2 &&a[5]<2 &&a[6]<2 && a[7]<2 &&a[8]<2 &&a[9]<2)\n\t\t{\n\t\tprintf(\"%d\",l);\n\t\treturn 0;}\n\t\telse\n\t\t{\t\n\t\t\tfor (i=0;i<10;i++)\n\t\t\ta[i]={0};\n\t\t\tcontinue; } \n\t\t}\n\t\tprintf(\"-1\");\n\t}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "b36eea223a7faf163d613588be9b0130", "src_uid": "3041b1240e59341ad9ec9ac823e57dd7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\nusing namespace std;\nint main()\n{\n\tint l, x, r;\n\tint a, b, c, d, e, f, g;\n\tg = 0;\n\tcin >> l >> r;\n\tfor (x = l; x <= r; x++) {\n\t\ta = int(x / 100000);\n\t\tb = int((x - 10000 * a) / 10000);\n\t\tc = int((x - 10000 * a - 10000 * b) / 1000);\n\t\td = int((x - 10000 * a - 10000 * b - 1000 * c)/100);\n\t\te = int((x - 10000 * a - 10000 * b - 1000 * c - 100 * d) / 10);\n\t\tf = int((x - 10000 * a - 10000 * b - 1000 * c - 100 * d - 10 * e));\n\t\tg = 0;\n\t\t\n\t\t\tif (a != 0) {\n\t\t\t\tif (a != b && a != c && a != d && a != e && a != f && b != c && b != d && b != e && b != f && c != d && c != e && c != f && d != e && d != f && e != f) {\n\t\t\t\t\tcout << x;\n\t\t\t\t\tg = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (a == 0 && b != 0) {\n\t\t\t\tif (b != c && b != d && b != e && b != f && c != d && c != e && c != f && d != e && d != f && e != f) {\n\t\t\t\t\tcout << x;\n\t\t\t\t\tg = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (a == 0 && b == 0 && c != 0) {\n\t\t\t\tif (c != d && c != e && c != f && d != e && d != f && e != f) {\n\t\t\t\t\tcout << x;\n\t\t\t\t\tg = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (a == 0 && b == 0 && c == 0 && d != 0) {\n\t\t\t\tif (d != e && d != f && e != f) {\n\t\t\t\t\tcout << x;\n\t\t\t\t\tg = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (a * b * c * d == 0 && e != 0) {\n\t\t\t\tif (e != f) {\n\t\t\t\t\tcout << x;\n\t\t\t\t\tg = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (a * b * c * d * e * f != 0) {\n\t\t\t\tcout << x;\n\t\t\t\tg = 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\n\t\t\t\n\t}\n\tif (g == 0) {\n\t\tcout << \"-1\";\n\t}\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5d2230db1de8c38d4ac7627cc86e0120", "src_uid": "3041b1240e59341ad9ec9ac823e57dd7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main(){\n\tint l,r,i,a[10]={0},j;\n\tscanf(\"%d%d\",&l,&r);\n\t\n\tfor(;l<=r;l++)\n\t{   j=l;\n\t\tfor(;j>0;)\n\t\t{\n\t\ta[j%10]++;\n\t\tj=j/10;\n\t\t}\n\t\tif(a[0]<2 &&a[1]<2 &&a[2]<2 &&a[3]<2 &&a[4]<2 &&a[5]<2 &&a[6]<2 && a[7]<2 &&a[8]<2 &&a[9]<2)//\u8fd9\u91cc \u5c31\u662f\u5224\u65ad \u5404\u4e2a\u4f4d\u6570\u4e0a\u7684\u6570\u662f\u5426\u91cd\u590d\u3002\n\t\t{\n\t\tprintf(\"%d\",l);\n\t\treturn 0;}\n\t\telse\n\t\t{\t\n\t\t\tfor (i=0;i<10;i++)\n\t\t\ta[i]={0};\n\t\t\tcontinue; } \n\t\t}\n\t\tprintf(\"-1\");\n\t\treturn 0;\n\t}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "eeb49433311998f68863ecccade6af35", "src_uid": "3041b1240e59341ad9ec9ac823e57dd7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint digit(int n, int ord) {\n    for(int k=0;k<ord;i++) {\n        n=n/10;\n    }\n    return n%10;\n}\n\nint length(int n) {\n    int a=0;\n    while(n!=0) {\n        n=n/10;\n        a+=1;\n    }\n    return a;\n}\n\nint main(void) {\n    int a,b;\n    scanf(\"%d %d\", &a, &b);\n    for(int i=a;i<=b;i++) {\n        int pass=1;\n        int g[10]={};\n        for(int j=0;j<length(i);j++) {\n            if (a[digit(i,j)]==1) {\n                pass=0;\n                break;\n            }\n            a[digit(i,j)]=1;\n        }\n        if (pass==1) {\n            printf(\"%d\", i);\n            return 0;\n        }\n    }\n    printf(\"-1\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7160d29f5d596112e537feb8c426a42e", "src_uid": "3041b1240e59341ad9ec9ac823e57dd7", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n,m,k,a[10]={0};\n    scanf(\"%d %d\",&n,&m);\n    k=n;\n    for(;k<=m;k++){\n    n=k;\n    a[10]={0};\n    for(;n;){\n        a[n/10]++;\n    }\n    for(int i=0;i<10;i++)if(a[i]>1)break;\n    if(i==10){printf(\"%d\",k);return 0;}\n    }\n    printf(\"%d\",-1);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7938f30d5a64db801c2e4ebf202d6709", "src_uid": "3041b1240e59341ad9ec9ac823e57dd7", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint n;\nint a[101];\nint dp[9][9][101][1 << 9];\n\nvoid dfs(int x, int y, int z, int w)\n{\n    if (x == n) {\n        if (z <= 100 && n * 2 - 1 < a[z]) a[z] = n * 2 - 1;\n        \n        return;\n    }\n    \n    if (y == n) {\n        dfs(x + 1, 0, z, w);\n        \n        return;\n    }\n    \n    if (z > 100) return;\n    \n    if (dp[x][y][z][w] == 1) return;\n    \n    dp[x][y][z][w] = 1;\n    \n    if (x == 0) {\n        if (y == 0) {\n            dfs(x, y + 1, 0, 0);\n            dfs(x, y + 1, 1, 1);\n        } else {\n            dfs(x, y + 1, z, w);\n            \n            if (((w >> (y - 1)) & 1) == 0) dfs(x, y + 1, z + 2, w | (1 << y));\n        }\n    } else {\n        if (y == 0) {\n            if ((w & 1) == 0) dfs(x, y + 1, z + 2, w | 1);\n        } else {\n            if ((w & (1 << y)) == 0 && ((w >> (y - 1)) & 1) == 0) dfs(x, y + 1, z + 4, w | (1 << y));\n        }\n        \n        dfs(x, y + 1, z, w & (((1 << n) - 1) ^ (1 << y)));\n    }\n}\n\nint main()\n{\n    int x, i, j, k, l, m;\n    \n    for (i = 0; i <= 100; i++) a[i] = 100;\n    \n    for (i = 1; i < 9; i++) {\n        n = i;\n        \n        for (j = 0; j < n; j++) {\n            for (k = 0; k < n; k++) {\n                for (l = 0; l <= 100; l++) {\n                    for (m = 0; m < (1 << n); m++) {\n                        dp[j][k][l][m] = 0;\n                    }\n                }\n            }\n        }\n        \n        dfs(0, 0, 0, 0);\n    }\n    \n    scanf(\"%d\", &x);\n    \n    printf(\"%d\\n\", a[x]);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dbeb1776b6dd98c4fe44cbe61603f21c", "src_uid": "01eccb722b09a0474903b7e5abc4c47a", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n\nint main()\n{\n    int x,n=3;\n\tscanf(\"%d\",&x);\n    if (x==1)\n        printf(\"1\");\n    else if (x==2 || x==4)\n        printf(\"3\");\n    else if (x==3)\n        printf(\"5\");\n    else {\n        while((n*n+1) < x*2) {\n            n+=2;\n        }\n        printf(\"%d\",n);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "553a105e82b77a3cbfbf6ac6af4145f0", "src_uid": "01eccb722b09a0474903b7e5abc4c47a", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    int s,n,x;\n    scanf(\"%d\",&x);\n    for (s=1,n=1;s<x;s=(n*n+1)/2) n+=2;\n    if (x==3) printf(\"5\");\n    else\n    printf(\"%d\",n);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "2db85371e0d0d6267fcdb6e5edfac5ff", "src_uid": "01eccb722b09a0474903b7e5abc4c47a", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nconst int ans[] = {0,1,3,5,3,3,5,5,5,5,5,5,5,5,7,7,7,7,7,7,7,7,7,7,7,7,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,11,11,11,11,11,11,11,11,11,11,11,11,11,11,11,11,11,11,11,11,13,13,13,13,13,13,13,13,13,13,13,13,13,13,13,13,13,13,13,13,13,13,13,13,15,15,15,15,15,15,15,15,15,15,15,15,15,15,15};\nint main() {\n//\tfreopen(\"input.txt\",\"r\",stdin);\n//\tfreopen(\"output.txt\",\"w\",stdout);\n\tint n;\n\tscanf(\"%d\",&n);\n\tprintf(\"%d\\n\",ans[n]);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a2e9ca9c11769485a125efaff7cd53dd", "src_uid": "01eccb722b09a0474903b7e5abc4c47a", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint n;\nint d[16];\n\nint solution(int x){\n    int i; int sol;\n    for (i = 0; i < 16; i++){\n        if (x<=d[i]){\n            if (i%2==0){\n                if ( ((x-d[i])%4) == 0)\n                    sol = i;\n            }\n            else{\n                sol = i;\n                break;\n            }\n        }\n    }\n\n    return sol;\n}\n\nint main()\n{\n\n    int x;\n    scanf(\"%d\", &x);\n    d[0] = 0;\n    d[1] = 1;\n    d[2] = 0;\n    d[3] = 5;\n    d[4] = d[1]*4;\n    d[5] = 13;\n    d[6] = 2 * 4;\n    d[7] = 25;\n    d[8] = d[3] * 4;\n    d[9] = 41;\n    d[10] = d[4] * 4;\n    d[11] = 61;\n    d[12] = d[5] * 4;\n    d[13] = 85;\n    d[14] = d[6] * 4;\n    d[15] = 113;\n\n    if (x==3)\n        printf(\"5\\n\");\n    else\n        printf(\"%d\\n\", solution(x));\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "edee8abfb340734aa764b98d700f28ed", "src_uid": "01eccb722b09a0474903b7e5abc4c47a", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n \r\ntypedef long long ll;\r\n \r\nint dp[4000001][2], sum[4000001][2];\r\n \r\nint main(){\r\n\tint n, m;\r\n\tscanf(\"%d %d\", &n, &m);\r\n\tfor (register int i = 2; i <= n; i++){\r\n\t\tdp[i][0] = (sum[i - 1][0] + sum[i - 1][1] + 1) % m;\r\n\t\tif (i == 2){\r\n\t\t\tdp[i][1] = 1;\r\n\t\t} else {\r\n\t\t\tdp[i][1] = (dp[i][1] + dp[i - 1][1] + ((i - i / 2) - ((i - 1) - (i - 1) / 2))) % m;\r\n\t\t}\r\n\t\tsum[i][0] = (sum[i - 1][0] + dp[i][0]) % m;\r\n\t\tsum[i][1] = (sum[i - 1][1] + dp[i][1]) % m;\r\n\t\tfor (register int j = i * 2; j <= n; j += i){\r\n\t\t\tdp[j][1] = (((ll)dp[j][1] + dp[i][0] + dp[i][1] - dp[i - 1][0] - dp[i - 1][1]) % m + m) % m;\r\n\t\t}\r\n\t}\r\n\tprintf(\"%d\", (dp[n][0] + dp[n][1]) % m);\r\n\treturn 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "279d00c11febbb23160301f6aa332452", "src_uid": "77443424be253352aaf2b6c89bdd4671", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\nint dp[4000001][2], sum[4000001][2];\r\n\r\nint main(){\r\n\tint n, m;\r\n\tscanf(\"%d %d\", &n, &m);\r\n\tfor (register int i = 2; i <= n; i++){\r\n\t\tint t;\r\n\t\tdp[i][0] = (sum[i - 1][0] + sum[i - 1][1] + 1) % m;\r\n\t\tif (i == 2){\r\n\t\t\tdp[i][1] = 1;\r\n\t\t} else {\r\n\t\t\tdp[i][1] = (dp[i][1] + dp[i - 1][1] - (i % 2 == 0 ? 1 : 0) + 1) % m;\r\n\t\t}\r\n\t\tt = ((dp[i][0] + dp[i][1] - dp[i - 1][0] - dp[i - 1][1]) % m + m) % m;\r\n\t\tsum[i][0] = (sum[i - 1][0] + dp[i][0]) % m;\r\n\t\tsum[i][1] = (sum[i - 1][1] + dp[i][1]) % m;\r\n\t\tfor (register int j = i * 2; j <= n; j += i){\r\n\t\t\tdp[j][1] = (dp[j][1] + t) % m;\r\n\t\t}\r\n\t}\r\n\tprintf(\"%d\", (dp[n][0] + dp[n][1]) % m);\r\n\treturn 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9c2df3fc1c469f0e554c1473841e6ab8", "src_uid": "77443424be253352aaf2b6c89bdd4671", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\nint dp[4000001][2], sum[4000001][2];\r\n\r\nint main(){\r\n\tint n, m;\r\n\tscanf(\"%d %d\", &n, &m);\r\n\tfor (register int i = 2; i <= n; i++){\r\n\t\tint t;\r\n\t\tdp[i][0] = (sum[i - 1][0] + sum[i - 1][1] + 1) % m;\r\n\t\tif (i == 2){\r\n\t\t\tdp[i][1] = 1;\r\n\t\t} else {\r\n\t\t\tdp[i][1] = (dp[i][1] + dp[i - 1][1] + ((i - i / 2) - ((i - 1) - (i - 1) / 2))) % m;\r\n\t\t}\r\n\t\tt = ((dp[i][0] + dp[i][1] - dp[i - 1][0] - dp[i - 1][1]) % m + m) % m;\r\n\t\tsum[i][0] = (sum[i - 1][0] + dp[i][0]) % m;\r\n\t\tsum[i][1] = (sum[i - 1][1] + dp[i][1]) % m;\r\n\t\tfor (register int j = i * 2; j <= n; j += i){\r\n\t\t\tdp[j][1] = (dp[j][1] + t) % m;\r\n\t\t}\r\n\t}\r\n\tprintf(\"%d\", (dp[n][0] + dp[n][1]) % m);\r\n\treturn 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "cdad55822ea4011fdc1c23980be57b33", "src_uid": "77443424be253352aaf2b6c89bdd4671", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <assert.h>\n\n#define psum(arr, i) ((i)<0?0:(arr[i]))\n#define uint unsigned int\n\nint main()\n{\n        int n, mod; scanf(\"%d %d\", &n, &mod);\n\n        int* dp = malloc(n*sizeof(int));\n        int* dpsum = calloc(n*sizeof(int), 1);\n\n        dp[0] = 1;\n        dpsum[0] = 1;\n\n        printf(\"1\\n\");\n        for (int i=1; i<n; i++) {\n                dp[i] = dpsum[i-1];\n\n                int rind=n-i;\n                for (int z=2; n>=rind*z; z++) {\n                        dp[i] += (dpsum[n-(rind*z)] - psum(dpsum, n-(rind*z+z)) + mod) % mod;\n                        dp[i] %= mod;\n                        // printf(\"adding range from %d to %d\\n\", n-rind*z, n-rind*z-z);\n                }\n\n                // printf(\"%d\\n\", dp[i]);\n                dpsum[i] = dp[i] + dpsum[i-1];\n                dpsum[i] %= mod;\n        }\n        printf(\"%d\\n\", dp[n-1]);\n        free(dp); free(dpsum);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "90f6a9949a66b1aa98f4d99966f02598", "src_uid": "77443424be253352aaf2b6c89bdd4671", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\nlong long s[4000001];\r\nlong long a[4000001];\r\nlong long n, p, c, k;\r\nint main()\r\n{\r\n    scanf(\"%lld%lld\", &n, &p);\r\n    s[1] = 1;\r\n    a[1] = 1;\r\n    for (int i = 2; i <= n; i++)\r\n    {\r\n        a[i] = s[i - 1];\r\n        c = 1;\r\n        for (int j = 2; j * j <= i; j++)\r\n        {\r\n            c = j;\r\n        }\r\n        k = i - 1;\r\n        for (int j = 1; j < c; j++)\r\n        {\r\n            a[i] += a[j] * ((i / j) - (i / (j + 1))) % p;\r\n            k -= (i / j) - (i / (j + 1));\r\n        }\r\n        for (int j = 2; j <= k + 1; j++)\r\n        {\r\n            a[i] += a[i / j];\r\n        }\r\n        s[i] = s[i - 1] + a[i];\r\n        s[i] %= p;\r\n        a[i] %= p;\r\n    }\r\n    printf(\"%lld\\n\", a[n]);\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "cef02b80824bbdb919f701edf6f3e6f4", "src_uid": "77443424be253352aaf2b6c89bdd4671", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n\tint n,i,a[30]={0};\n\tchar c;\n\tfor(i=0;i<3;i++){\n\t\tscanf(\"%d%c\",&n,&c);\n\t\tif(c=='m')a[n]++;\n\t\tif(c=='s')a[n+10]++;\n\t\tif(c=='p')a[n+20]++;\n\t}\n\tfor(i=1;i<30;i++){\n\t\tif(a[i]==3)return !puts(\"0\");\n\t\tif(i<28&&a[i]&&a[i+1]&&a[i+2])return !puts(\"0\");\n\t\tif(a[i]==2)return !puts(\"1\");\n\t\tif(i<29&&a[i]&&a[i+1])return !puts(\"1\");\n\t}\n\tputs(\"2\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1a293e11118894a3d312467221e671f2", "src_uid": "7e42cebc670e76ace967e01021f752d3", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<math.h>\n\n#define MAX(x, y) (((x) > (y)) ? (x) : (y))\n\nvoid main(){\n\tchar a[3],b[3],c[3];\n\tint cnt[3];\n\tint s = 0,k = 0;\n\tscanf(\"%s %s %s\",&a,&b,&c);\n\tint x = a[0],y=b[0],z=c[0];\n\tcnt[0] = strcmp(a,b);\n\tcnt[1] = strcmp(a,c);\n\tcnt[2] = strcmp(b,c);\n\tfor (int i = 0; i<3;i++){\n\t\tif(cnt[i] == 0){\n\t\t\tk++;\n\t\t}\n\t}\n\tif(k==1){\n\t\tk=2;\n\t}\n\telse if(k==0) k = 1;\n\tif(a[1] == b[1]){\n\t\tif(x+1==y || x-1==y){\n\t\t\ts +=2;\n\t\t}\n\t}\n\tif(a[1] == c[1]){\n                if(x+1==z || x-1==z){\n                        s +=2;\n                }\n        }\n\tif(c[1] == b[1]){\n                if(z+1==y || z-1==y){ \n                        s +=2;\n                }\n        }\n\tif(s>3) s=3;\n\telse if(s==0) s=1;\n\t//printf(\"s=%d k=%d\\n\",s,k);\n\tint result = MAX(s,k);\n\tresult = 3 - result;\n\tprintf(\"%d\",result);\n\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2c9550d8bbe45c5443b825e681f06aad", "src_uid": "7e42cebc670e76ace967e01021f752d3", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <algorithm>\nusing namespace std;\n\nint cor[3][9];\nint main() {\n  char c[3];\n  int n[3];\n  scanf(\"%d%c %d%c %d%c\",&n[0],&c[0],&n[1],&c[1],&n[2],&c[2]);\n  for(int i=0;i<3;i++) {\n    if(c[i]=='m') c[i]=0;\n    else if(c[i]=='p') c[i]=1;\n    else if(c[i]=='s') c[i]=2;\n  }\n  for(int i=0;i<3;i++) {\n    cor[c[i]][n[i]]=1;\n    cor[c[i]][0]++;\n  }\n  for(int i=0;i<3;i++) {\n    if(cor[i][0]==3) {\n      sort(n,n+3);\n      if(n[0]==n[1] && n[1]==n[2]) {\n        printf(\"0\");\n        return 0;\n      }\n      else if(n[1]-n[0]==1 && n[2]-n[1]==1) {\n        printf(\"0\");\n        return 0;\n      }\n      else if(n[1]-n[0]==1 || n[2]-n[1]==1) {\n        printf(\"1\");\n        return 0;\n      }\n      else if(n[0]==n[1] || n[1]==n[2]) {\n        printf(\"1\");\n        return 0;\n      }\n    }\n    else if(cor[i][0]==2) {\n      for(int j=1;j<=9;j++) {\n        if(cor[i][j]==2) {\n          printf(\"1\");\n          return 0;\n        }\n      }\n      for(int j=1;j<9;j++) {\n        if(cor[i]>0 && cor[i+1] >0) {\n          printf(\"1\");\n          return 0;\n        }\n      }\n    }\n  }\n  printf(\"2\");\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c6f8aba09a3bb667500ef9e791584344", "src_uid": "7e42cebc670e76ace967e01021f752d3", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint countb(char b[]){\n\tif(b[0]==b[1]&&b[1]==b[2]){\n\t\treturn 0;\n\t}else if(b[0]==b[1]||b[0]==b[2]||b[2]==b[1]){\n\t\treturn 1;\n\t}else {\n\t\treturn 2;\n\t}\n}\nint countwhat(char b[]){\n\tif(b[0]==b[1]&&b[1]==b[2]){\n\t\treturn 1;\n\t}else if(b[0]==b[1]||b[0]==b[2]||b[2]==b[1]){\n\t\treturn 1;\n\t}else {\n\t\treturn 2;\n\t}\n}\nint countab(char b[],int m){\n\tif(m==1){\n\t\tif(b[0]==b[1]){\n\t\t\treturn 1;\n\t\t}else{\n\t\t\treturn 2;\n\t\t}\t\n\t}else if(m==2){\n\t\tif(b[1]==b[2]){\n\t\t\treturn 1;\n\t\t}else{\n\t\t\treturn 2;\n\t\t}\n\t}else{\n\t\tif(b[0]==b[2]){\n\t\t\treturn 1;\n\t\t}else{\n\t\t\treturn 2;\n\t\t}\n\t}\n}\nint main(){\n\tchar input[10];\n\tgets(input);\n\tint a[]={input[0]-48,input[3]-48,input[6]-48};\n\tchar b[]={input[1],input[4],input[7]};\n\tfor(int j=0;j<2;j++){\n\t\tfor(int i=0;i<3;i++){\n\t\t\tint mida;\n\t\t\tchar midb;\n\t\t\tif(i+1<3&&a[i]>a[i+1]){\n\t\t\t\tmida=a[i];\n\t\t\t\ta[i]=a[i+1];\n\t\t\t\ta[i+1]=mida;\n\t\t\t\tmidb=b[i];\n\t\t\t\tb[i]=b[i+1];\n\t\t\t\tb[i+1]=midb;\n\t\t\t}\n\t\t}\n\t}\n\tif(a[0]+1==a[1]&&a[1]+1==a[2]){\n\t\tprintf(\"%d\\n\",countb(b));\n\t\treturn 0;\n\t}else if(a[0]==a[1]&&a[1]==a[2]){\n\t\tprintf(\"%d\\n\",countb(b));\n\t\treturn 0;\n\t}else if(a[0]==a[1]){\n\t\tif(a[0]+1==a[2]||a[0]+2==a[2]){\n\t\t\tprintf(\"%d\\n\",countwhat(b));\n\t\t\treturn 0;\n\t\t}else{\n\t\t\tprintf(\"%d\\n\",countab(b,1));\n\t\t\treturn 0;\n\t\t}\n\t}else if(a[1]==a[2]){\n\t\tif(a[0]+1==a[1]||a[0]+2==a[1]){#include<stdio.h>\nint countb(char b[]){\n\tif(b[0]==b[1]&&b[1]==b[2]){\n\t\treturn 0;\n\t}else if(b[0]==b[1]||b[0]==b[2]||b[2]==b[1]){\n\t\treturn 1;\n\t}else {\n\t\treturn 2;\n\t}\n}\nint countab(char b[],int m){\n\tif(m==1){\n\t\tif(b[0]==b[1]){\n\t\t\treturn 1;\n\t\t}else{\n\t\t\treturn 2;\n\t\t}\t\n\t}else if(m==2){\n\t\tif(b[1]==b[2]){\n\t\t\treturn 1;\n\t\t}else{\n\t\t\treturn 2;\n\t\t}\n\t}else{\n\t\tif(b[0]==b[2]){\n\t\t\treturn 1;\n\t\t}else{\n\t\t\treturn 2;\n\t\t}\n\t}\n}\nint main(){\n\tchar input[10];\n\tgets(input);\n\tint a[]={input[0]-48,input[3]-48,input[6]-48};\n\tchar b[]={input[1],input[4],input[7]};\n\tfor(int j=0;j<2;j++){\n\t\tfor(int i=0;i<3;i++){\n\t\t\tint mida;\n\t\t\tchar midb;\n\t\t\tif(i+1<3&&a[i]>a[i+1]){\n\t\t\t\tmida=a[i];\n\t\t\t\ta[i]=a[i+1];\n\t\t\t\ta[i+1]=mida;\n\t\t\t\tmidb=b[i];\n\t\t\t\tb[i]=b[i+1];\n\t\t\t\tb[i+1]=midb;\n\t\t\t}\n\t\t}\n\t}\n\tint ab[3];\n\tfor(int i=0;i<3;i++){\n\t\tab[i]=countab(b,i+1);\n\t}\n\tfor(int j=0;j<2;j++){\n\t\tfor(int i=0;i<3;i++){\n\t\t\tint mida;\n\t\t\tif(i+1<3&&ab[i]>ab[i+1]){\n\t\t\t\tmida=ab[i];\n\t\t\t\tab[i]=ab[i+1];\n\t\t\t\tab[i+1]=mida;\n\t\t\t}\n\t\t}\n\t}\n\tif(a[0]+1==a[1]&&a[1]+1==a[2]){\n\t\tprintf(\"%d\\n\",countb(b));\n\t\treturn 0;\n\t}else if(a[0]==a[1]&&a[1]==a[2]){\n\t\tprintf(\"%d\\n\",countb(b));\n\t\treturn 0;\n\t}else if(a[0]==a[1]){\n\t\tif(a[0]+1==a[2]||a[0]+2==a[2]){\n\t\t\tprintf(\"%d\\n\",ab[0]);\n\t\t\treturn 0;\n\t\t}else{\n\t\t\tprintf(\"%d\\n\",countab(b,1));\n\t\t\treturn 0;\n\t\t}\n\t}else if(a[1]==a[2]){\n\t\tif(a[0]+1==a[1]||a[0]+2==a[1]){\n\t\t\tprintf(\"%d\\n\",ab[0]);\n\t\t\treturn 0;\n\t\t}else{\n\t\t\tprintf(\"%d\\n\",countab(b,2));\n\t\t\treturn 0;\n\t\t}\n\t}else if(a[0]+1==a[1]||a[0]+2==a[1]){\n\t\tif(a[1]+1==a[2]||a[1]+2==a[2]){\n\t\t\tprintf(\"%d\\n\",countab(b,1)>countab(b,2)?countab(b,2):countab(b,1));\n\t\t\treturn 0;\n\t\t}\n\t\tprintf(\"%d\\n\",countab(b,1));\n\t}else if(a[1]+1==a[2]||a[1]+2==a[2]){\n\t\tprintf(\"%d\\n\",countab(b,2));\n\t}else {\n\t\tprintf(\"%d\\n\",2);\n\t}\n}\n\t\t\tprintf(\"%d\\n\",countwhat(b));\n\t\t\treturn 0;\n\t\t}else{\n\t\t\tprintf(\"%d\\n\",countab(b,2));\n\t\t\treturn 0;\n\t\t}\n\t}else if(a[0]+1==a[1]||a[0]+2==a[1]){\n\t\tprintf(\"%d\\n\",countab(b,1));\n\t\treturn 0;\n\t}else if(a[1]+1==a[2]||a[1]+2==a[2]){\n\t\tprintf(\"%d\\n\",countab(b,2));\n\t}else {\n\t\tprintf(\"%d\\n\",2);\n\t}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d8699a6b1b7a9d553df650c75b43eaed", "src_uid": "7e42cebc670e76ace967e01021f752d3", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<math.h>\n\n#define MAX(x, y) (((x) > (y)) ? (x) : (y))\n#define MIN(x, y) (((x) < (y)) ? (x) : (y))\nint main(){\n\tchar a[3],b[3],c[3];\n\tint cnt[3];\n\tint s = 0,k = 0;\n\tscanf(\"%s %s %s\",&a,&b,&c);\n\tint x = a[0],y=b[0],z=c[0];\n\tcnt[0] = strcmp(a,b);\n\tcnt[1] = strcmp(a,c);\n\tcnt[2] = strcmp(b,c);\n\tfor (int i = 0; i<3;i++){\n\t\tif(cnt[i] == 0){\n\t\t\tk++;\n\t\t}\n\t}\n\tif(k==1){\n\t\tk=2;\n\t}\n\telse if(k==0) k = 1;\n\tint flag = 0;\n\tint flag1 = 0;\n\n\tif(a[1]==b[1] && a[1]==c[1]) {\n\t\tlong int max=MAX(MAX(x,y),z);\n\t\tlong int min=MIN(MIN(x,y),z);\n\t\tint ans = max-min;\n\t\tif(ans==2) s=3;\n\t\tint result = MAX(s,k);\n        \tresult = 3 - result;\n        \tprintf(\"%d\",result);\n        \treturn 0;\n\t}\n\t\tif(a[1] == b[1]){\n\t\t\tif(x+1==y || x-1==y){\n\t\t\t\ts +=2;\n\t\t\t\tflag = 1;\n\t\t\t}\n\t\t\tif(x+2==y || x-2==y && !flag) {\n\t\t\t\ts +=2;\n\t\t\t\tflag1 = 1;\n\t\t\t}\n\t\t}\n\t\tif(a[1] == c[1] && cnt[0] != 0 && cnt[2] != 0){\n\t\t\t//printf(\"hello\\n\");\n                \tif(x+1==z || x-1==z && !flag1){\n                        \ts +=2;\n\t\t\t\tflag = 1;\n                \t}\n\t\t\tif(x+2==z || x-2==z && !flag){\n\t\t\t\ts +=2;\n\t\t\t\tflag1 = 1;\n\t\t\t}\n        \t}\n\t\tif(c[1] == b[1] && cnt[0] != 0 && cnt[1] !=0 ){\n                \tif(z+1==y || z-1==y && !flag1){\n                        \ts +=2;\n\t\t\t\tflag = 1;\n                \t}\n\t\t\tif(z+2==y || z-2==y && !flag){\n\t\t\t\ts +=2;\n\t\t\t}\n        \t}\n\t}\n\tif(s>3) s=3;\n\telse if(s==0) s=1;\n\tresult = MAX(s,k);\n\tresult = 3 - result;\n\tprintf(\"%d\",result);\n    \treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "25fa1fe1ba0cc13144fdaef8e16675f8", "src_uid": "7e42cebc670e76ace967e01021f752d3", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\nint i,parallel_square[4][2],angular_square[4][2],minimum_x=1000000000,minimum_y=1000000000,centre_of_angular_square[2],half_diagon_length_of_angular_square,side_length_of_parallel_square;\nfor(i=0;i<4;i++)\n{\n    scanf(\"%d %d\",&parallel_square[i][0],&parallel_square[i][1]);\n    if(parallel_square[i][0]<minimum_x) minimum_x=parallel_square[i][0];\n    if(parallel_square[i][1]<minimum_y) minimum_y=parallel_square[i][1];\n}\nfor(i=0;i<4;i++)\n{\n    scanf(\"%d %d\",&angular_square[i][0],&angular_square[i][1]);\n    angular_square[i][0]=angular_square[i][0]-minimum_x;\n    parallel_square[i][0]=parallel_square[i][0]-minimum_x;\n    angular_square[i][1]=angular_square[i][1]-minimum_y;\n    parallel_square[i][1]=parallel_square[i][1]-minimum_y;\n}\nhalf_diagon_length_of_angular_square=(angular_square[0][0]-angular_square[2][0]+angular_square[0][1]-angular_square[2][1])/2;\nside_length_of_parallel_square=parallel_square[0][0]-parallel_square[1][0]+parallel_square[0][1]-parallel_square[1][1];\nif(side_length_of_parallel_square<0) side_length_of_parallel_square=-side_length_of_parallel_square;\nif(half_diagon_length_of_angular_square<0) half_diagon_length_of_angular_square=-half_diagon_length_of_angular_square;\ncentre_of_angular_square[0]=(angular_square[0][0]+angular_square[2][0])/2;\ncentre_of_angular_square[1]=(angular_square[0][1]+angular_square[2][1])/2;\nif((centre_of_angular_square[0]>=-half_diagon_length_of_angular_square&&centre_of_angular_square[0]<=0&&centre_of_angular_square[1]+centre_of_angular_square[0]>=-half_diagon_length_of_angular_square&&centre_of_angular_square[1]<=centre_of_angular_square[0]+half_diagon_length_of_angular_square+side_length_of_parallel_square)||(centre_of_angular_square[0]>=0&&centre_of_angular_square[0]<=side_length_of_parallel_square&&centre_of_angular_square[1]>=-half_diagon_length_of_angular_square&&centre_of_angular_square[1]<=side_length_of_parallel_square+half_diagon_length_of_angular_square)||(centre_of_angular_square[0]>=side_length_of_parallel_square&&centre_of_angular_square[0]<=side_length_of_parallel_square+half_diagon_length_of_angular_square&&centre_of_angular_square[1]+centre_of_angular_square[0]<=half_diagon_length_of_angular_square+2*side_length_of_parallel_square&&centre_of_angular_square[1]>=centre_of_angular_square[0]-half_diagon_length_of_angular_square-side_length_of_parallel_square)) printf(\"Yes\");\nelse printf (\"No\");\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "124ed275750b174b06b49955253aa4ba", "src_uid": "f6a3dd8b3bab58ff66055c61ddfdf06a", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdbool.h>\n\ntypedef struct{\n\tint x, y;\n} Point;\n\ntypedef struct{\n\tPoint n[4];\n} Square;\n\nint cross(Point a, Point b, Point c){\n\treturn (c.x-a.x)*(b.y-a.y)-(b.x-a.x)*(c.y-a.y);\n}\n\nint abs(int a){return a<0?-a:a;}\nint min(int a, int b){return a<b?a:b;}\nint max(int a, int b){return a>b?a:b;}\n\nbool contains(Square sq, Point p){\n\treturn abs(cross(sq.n[0], sq.n[1], sq.n[2]))+\n\t\tabs(cross(sq.n[2], sq.n[3], sq.n[0]))==\n\t\tabs(cross(sq.n[0], sq.n[1], p))+abs(cross(sq.n[1], sq.n[2], p))+\n\t\tabs(cross(sq.n[2], sq.n[3], p))+abs(cross(sq.n[3], sq.n[0], p));\n}\n\nint sqminx(Square sq){ return min(sq.n[0].x, min(sq.n[1].x, min(sq.n[2].x, sq.n[3].x))); }\nint sqmaxx(Square sq){ return max(sq.n[0].x, max(sq.n[1].x, max(sq.n[2].x, sq.n[3].x))); }\nint sqminy(Square sq){ return min(sq.n[0].y, min(sq.n[1].y, min(sq.n[2].y, sq.n[3].y))); }\nint sqmaxy(Square sq){ return max(sq.n[0].y, max(sq.n[1].y, max(sq.n[2].y, sq.n[3].y))); }\n\nint main(){\n\tSquare squares[2];\n\tint i, j;\n\tPoint curr;\n\tfor(i=0;i<2;++i) for(j=0;j<4;++j)\n\t\t\tscanf(\"%d %d\", &squares[i].n[j].x, &squares[i].n[j].y);\n\tfor(curr.x=sqminx(squares[0]);curr.x<=sqmaxx(squares[0]);++curr.x){\n\t\tfor(curr.y=sqminy(squares[0]);curr.y<=sqmaxy(squares[0]);++curr.y){\n\t\t\tif(contains(squares[1], curr)){\n\t\t\tputs(\"YES\");\n\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tputs(\"NO\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f0f487024ca960b6910f4813aef22d94", "src_uid": "f6a3dd8b3bab58ff66055c61ddfdf06a", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdbool.h>\n\ntypedef struct{\n\tint x, y;\n} Point;\n\ntypedef struct{\n\tPoint n[4];\n} Square;\n\nint cross(Point a, Point b, Point c){\n\treturn (c.x-a.x)*(b.y-a.y)-(b.x-a.x)*(c.y-a.y);\n}\n\nint abs(int a){return a<0?-a:a;}\nint min(int a, int b){return a<b?a:b;}\nint max(int a, int b){return a>b?a:b;}\n\nbool contains(Square sq, Point p){\n\treturn abs(cross(sq.n[0], sq.n[1], sq.n[2]))+\n\t\tabs(cross(sq.n[2], sq.n[3], sq.n[0]))==\n\t\tabs(cross(sq.n[0], sq.n[1], p))+abs(cross(sq.n[1], sq.n[2], p))+\n\t\tabs(cross(sq.n[2], sq.n[3], p))+abs(cross(sq.n[3], sq.n[0], p));\n}\n\nint sqminx(Square sq){ return min(sq.n[0].x, min(sq.n[1].x, min(sq.n[2].x, sq.n[3].x))); }\nint sqmaxx(Square sq){ return max(sq.n[0].x, max(sq.n[1].x, max(sq.n[2].x, sq.n[3].x))); }\nint sqminy(Square sq){ return min(sq.n[0].y, min(sq.n[1].y, min(sq.n[2].y, sq.n[3].y))); }\nint sqmaxy(Square sq){ return max(sq.n[0].y, max(sq.n[1].y, max(sq.n[2].y, sq.n[3].y))); }\n\nint main(){\n\tSquare squares[2];\n\tint i, j;\n\tPoint curr;\n\tfor(i=0;i<2;++i) for(j=0;j<4;++j)\n\t\t\tscanf(\"%d %d\", &squares[i].n[j].x, &squares[i].n[j].y);\n\tfor(curr.x=sqminx(squares[0]);curr.x<=sqmaxx(squares[0]);++curr.x){\n\t\tfor(curr.y=sqminy(squares[0]);curr.y<=sqmaxy(squares[0]);++curr.y){\n\t\t\tif(contains(squares[1], curr)){\n\t\t\tputs(\"YES\");\n\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tputs(\"NO\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b239d29e725bea7feae451e2a6fc90c0", "src_uid": "f6a3dd8b3bab58ff66055c61ddfdf06a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint x1[4], y1[4], x2[4], y2[4];\n\tint d[201][201]={};\n\tfor (int i=0; i<4; i++) scanf(\"%d %d\", &x1[i], &y1[i]);\n\tfor (int i=0; i<4; i++) scanf(\"%d %d\", &x2[i], &y2[i]);\n\t\n\tint a=(x2[0]+x2[1]+x2[2]+x2[3])/4, b=(y2[0]+y2[1]+y2[2]+y2[3])/4;\n\t\n\tint minx, maxx;\n\tfor (int i=0; i<4; i++)\n\t{\n\t\tif (!i) {minx=x2[i]; maxx=x2[i];}\n\t\telse\n\t\t{\n\t\t\tif (maxx<x2[i]) maxx=x2[i];\n\t\t\telse if (minx>x2[i]) minx=x2[i];\n\t\t}\n\t}\n\tint p=(-minx+maxx)/2;\n\t\n\tfor (int i=(((x1[0]<x1[1])?x1[0]:x1[1])<x1[2]?((x1[0]<x1[1])?x1[0]:x1[1]):x1[2]);\n\ti<=(((x1[0]>x1[1])?x1[0]:x1[1])>x1[2]?((x1[0]>x1[1])?x1[0]:x1[1]):x1[2]); i++)\n\t{\n\t\tfor (int j=(((y1[0]<y1[1])?y1[0]:y1[1])<y1[2]?((y1[0]<y1[1])?y1[0]:y1[1]):y1[2]);\n\t\tj<=(((y1[0]>y1[1])?y1[0]:y1[1])>y1[2]?((y1[0]>y1[1])?y1[0]:y1[1]):y1[2]); j++)\n\t\t{\n\t\t\td[100+i][100+j]+=1;\n\t\t}\n\t}\n\t\n\tfor (int i=-100; i<101; i++)\n\t{\n\t\tfor (int j=-100; j<101; j++)\n\t\t{\n\t\t\tif (i+j-a-b+p>=0 && j-i+a-b-p<=0 && j-i+a-b+p>=0 && j+i-a-b-p<=0)\n\t\t\td[i+100][j+100]+=2;\n\t\t}\n\t}\n\t\n\tint c=0;\n\t\n\tfor (int i=0; i<201; i++)\n\t{\n\t\tfor (int j=0; j<201; j++)\n\t\t{\n\t\t\tif (d[i][j]==3) c++;\n\t\t}\n\t}\n\tif (c) printf(\"YES\");\n\telse printf(\"NO\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c0a8b59741569a619245863f2cec3f25", "src_uid": "f6a3dd8b3bab58ff66055c61ddfdf06a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n\n    int i,j,counter,orderXmax,orderXmin,orderYmax,orderYmin,midX,midY,C[4],M[4],p[4];\n    struct coordinates{int x; int y;};\n    struct coordinates point[8];\n    for (i = 0; i < 8; i++)\n    {\n        scanf(\"%d%d\",&point[i].x,&point[i].y);\n        point[i].x += 100;\n        point[i].y += 100;\n    }\n\n    orderXmax = point[0].x;\n    orderXmin = point[0].x;\n    orderYmax = point[0].y;\n    orderYmin = point[0].y;\n\n    for (i = 1; i < 4;i++)\n    {\n        if (point[i].x > orderXmax)\n            orderXmax = point[i].x;\n        if (point[i].y > orderYmax)\n            orderYmax = point[i].y;\n        if (point[i].x < orderXmin)\n            orderXmin = point[i].x;\n        if (point[i].y < orderYmin)\n            orderYmin = point[i].y;\n    }\n    point[0].x = orderXmin;\n    point[0].y = orderYmin;\n    point[1].x = orderXmax;\n    point[1].y = orderYmin;\n    point[2].x = orderXmax;\n    point[2].y = orderYmax;\n    point[3].x = orderXmin;\n    point[3].y = orderYmax;\n\n    orderXmax = point[4].x;\n    orderXmin = point[4].x;\n    orderYmax = point[4].y;\n    orderYmin = point[4].y;\n    midX = point[4].x;\n    midY = point[4].y;\n\n    for (i = 5; i < 8;i++)\n    {\n        if (point[i].x > orderXmax)\n            {orderXmax = point[i].x; midY = point[i].y;}\n        if (point[i].y > orderYmax)\n            {orderYmax = point[i].y; midX = point[i].x;}\n        if (point[i].x < orderXmin)\n            orderXmin = point[i].x;\n        if (point[i].y < orderYmin)\n            orderYmin = point[i].y;\n    }\n    point[4].x = orderXmin;\n    point[4].y = midY;\n    point[5].x = midX;\n    point[5].y = orderYmax;\n    point[6].x = orderXmax;\n    point[6].y = midY;\n    point[7].x = midX;\n    point[7].y = orderYmin;\n\n    int maxxX = point[0].x, maxxY = point[0].y;\n    for (i = 1; i < 8; i++)\n    {\n        if (point[i].x > maxxX)\n            maxxX = point[i].x;\n        if (point[i].y > maxxY)\n            maxxY = point[i].y;\n    }\n\n\n    int map[210][210];\n    map[0][0]=0;\n\n    for (i = point[0].x ; i <= point[1].x; i++)\n        map[point[0].y][i] = 1;\n\n    for (i = point[1].y; i <= point[2].y; i++)\n        map[i][point[1].x] = 1;\n\n    for (i = point[3].x ; i <= point[2].x; i++)\n        map[point[2].y][i] = 1;\n\n    for (i = point[0].y; i <= point[3].y; i++)\n        map[i][point[0].x] = 1;\n\n    counter = point[4].y;\n    for (i = point[4].x ; i <= point[5].x; i++)\n        {if (map[counter][i] == 1)\n            {printf(\"YES\\n\"); goto label;}\n        else\n            map[counter][i] = 1;\n        counter++;}\n\n    counter = point[5].y-1;\n    for (i = point[5].x+1; i <= point[6].x; i++)\n        {if (map[counter][i] == 1)\n            {printf(\"YES\\n\"); goto label;}\n         else\n            map[counter][i] = 1;\n         counter--;}\n\n    counter = point[7].y;\n    for (i = point[7].x ; i < point[6].x; i++)\n        {if (map[counter][i] == 1)\n            {printf(\"YES\\n\"); goto label;}\n        else\n            map[counter][i] = 1;\n        counter++;}\n\n    counter = point[4].y - 1;\n    for (i = point[4].x + 1; i < point[7].x ; i++)\n        {if (map[counter][i] == 1)\n            {printf(\"YES\\n\"); goto label;}\n        else\n            map[counter][i] = 1;\n        counter--;}\n\n    C[0] = point[4].y - point[4].x;\n    C[1] = point[5].y + point[5].x;\n    C[2] = point[6].y - point[6].x;\n    C[3] = point[4].y + point[4].x;\n\n    M[0] = 1;\n    M[1] = -1;\n    M[2] = 1;\n    M[3] = -1;\n    p[0] = (M[0]*point[1].x) + C[0];\n    p[1] = (M[1]*point[0].x) + C[1];\n    p[2] = (M[2]*point[3].x) + C[2];\n    p[3] = (M[3]*point[2].x) + C[3];\n    /*printf(\"%d  %d\\n\",point[0].x,point[4].x);\n    printf(\"%d  %d\\n\",point[1].x,point[6].x);\n    printf(\"%d  %d\\n\",point[2].y,point[5].y);\n    printf(\"%d  %d\\n\",point[0].y,point[7].y);*/\n    if (((point[0].x < point[4].x) && (point[1].x > point[6].x) && (point[2].y > point[5].y) && (point[0].y < point[7].y)) )\n    {printf(\"YES\\n\"); goto label;}\n    else if ((((point[0].x > point[4].x) && (point[1].x < point[6].x) && (point[2].y < point[5].y) && (point[0].y > point[7].y))) &&!((point[1].y > p[0]) || (point[0].y > p[1]) || (point[3].y < p[2]) || (point[2].y < p[3])))\n        {\n            printf(\"YES\\n\"); goto label;\n        }\n\n    printf(\"NO\\n\");\n\n    label:\n    /*for (i = maxxY; i > 99; i--)\n        {for (j = 73; j < maxxX+1; j++)\n            printf(\"%d \" ,map[i][j]);\n            printf(\"\\n\");}*/\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4b47fd9a05b6b5d8337c709bbcfd2e35", "src_uid": "f6a3dd8b3bab58ff66055c61ddfdf06a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main() {\n\tint i, j, l, *xx, *yy;\n\tchar s[102];\n\n\tfgets(s, 102, stdin);\n\tl = strlen(s);\n\txx = malloc(sizeof(int) * l);\n\tyy = malloc(sizeof(int) * l);\n\n\txx[0] = 0, yy[0] = 0;\n\tfor (i = 1; i < l; i++) {\n\t\txx[i] = xx[i - 1], yy[i] = yy[i - 1];\n\t\tif (s[i] == 'L')\n\t\t\txx[i]--;\n\t\telse if (s[i] == 'R')\n\t\t\txx[i]++;\n\t\telse if (s[i] == 'D')\n\t\t\tyy[i]--;\n\t\telse\n\t\t\tyy[i]++;\n\t\tfor (j = i - 2; j >= 0; j--) {\n\t\t\tint d1 = xx[j] > xx[i] ? xx[j] - xx[i] : xx[i] - xx[j];\n\t\t\tint d2 = yy[j] > yy[i] ? yy[j] - yy[i] : yy[i] - yy[j];\n\n\t\t\tif ((d1 == 0 && d2 == 0)\n\t\t\t\t\t|| (d1 == 0 && d2 == 1)\n\t\t\t\t\t|| (d1 == 0 && d2 == 0)) {\n\t\t\t\tprintf(\"BUG\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"OK\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3b1f4268c468043da6eb579844e8cf56", "src_uid": "bb7805cc9d1cc907b64371b209c564b3", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define M 312\n\nint dir[4][2] = {{0,1},{1,0},{-1,0},{0,-1}};\nint a[M][M];\n\nmain()\n{\n//  freopen( \"input.dat\", \"r\", stdin );\n  \n  int i, o, p, j, k, l;\n\n  for (i=0;i<M;++i)\n    for (j=0;j<M;++j) \n      a[i][j] = 0;\n\n  char c;\n  int sx = 150, sy = 150;\n  a[sx][sy] = 1;\n  int num = 1;\n  while( scanf( \"%c\", &c ) != EOF )\n  {\n    int x, y;\n    if (c=='U') c = 0;\n    if (c=='D') c = 3;\n    if (c=='L') c = 2;\n    if (c=='R') c = 1;\n    if (c<=3)\n    {\n      sx += dir[c][0];\n      sy += dir[c][1];\n      ++num;\n      a[sx][sy] = num;\n      for (i = 0;i<4;++i) \n      {\n        x = sx + dir[i][0];\n        y = sy + dir[i][1];\n        if ((a[x][y] < num-1) && (a[x][y]!=0)) \n        {\n          printf( \"BUG\\n\" );\n          return(0);\n        }\n      }\n    } else break;\n  }\n  printf( \"OK\\n\" );\n  return 0;\n}\n    \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cf983be258083fb3a6898c6fbf557d48", "src_uid": "bb7805cc9d1cc907b64371b209c564b3", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N 102\n\nchar visited[N * 2 + 1][N * 2 + 1];\n\nint cycle(int x, int y) {\n    int k = 0;\n\n    if (visited[x - 2][y])\n        k++;\n    if (visited[x + 2][y])\n        k++;\n    if (visited[x][y + 1])\n        k++;\n    if (visited[x][y - 1])\n        k++;\n    return k >= 2;\n}\n\nint main() {\n    static char cc[N + 1];\n    int n, i, x, y;\n\n    scanf(\"%s\", cc), n = strlen(cc);\n    x = y = N;\n    visited[x][y] = 1;\n    for (i = 0; i < n; i++) {\n        if (cc[i] == 'L')\n            x--;\n        else if (cc[i] == 'R')\n            x++;\n        else if (cc[i] == 'U')\n            y++;\n        else\n            y--;\n        if (visited[x][y] || cycle(x, y)) {\n            printf(\"BUG\\n\");\n            return 0;\n        }\n        visited[x][y] = 1;\n    }\n    printf(\"OK\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7202792beb6912b3f91e298b5f93f3a6", "src_uid": "bb7805cc9d1cc907b64371b209c564b3", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define TAM 300\n\nint grid[TAM][TAM];\n\nint main() {\n    char movs[101];\n    while (scanf (\"%s \", movs) != EOF) {\n    printf (\"%s \", movs);\n        memset (grid, sizeof(grid), 0);\n        int i, n = strlen(movs), x = 150, y = 150, ok = 1;\n        grid[x][y] = 1;\n        for (i = 0; i < n; i++) {\n            switch (movs[i]) {\n                case 'U':\n                    y--;\n                    ok = (grid[x][y-1] || grid[x-1][y] || grid[x+1][y]) ? 0 : ok;\n                    break;\n                case 'D':\n                    y++;\n                    ok = (grid[x][y+1] || grid[x-1][y] || grid[x+1][y]) ? 0 : ok;\n                    break;\n                case 'L':\n                    x--;\n                    ok = (grid[x-1][y] || grid[x][y-1] || grid[x][y+1]) ? 0 : ok;\n                    break;\n                case 'R':\n                    x++;\n                    ok = (grid[x+1][y] || grid[x][y-1] || grid[x][y+1]) ? 0 : ok;\n                    break;\n                default: break;\n            }\n            ok = (grid[x][y]) ? 0 : ok;\n            grid[x][y] = 1;\n        }\n        if (!ok)\n            printf (\"BUG\\n\");\n        else\n            printf (\"OK\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0417fcc7b4be26d4db4b30dd3c338b7f", "src_uid": "bb7805cc9d1cc907b64371b209c564b3", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nchar s[105];\nbool g[206][206];\nint main()\n{\n    scanf(\"%s\", s);\n    int x=102,y=102;\n    int i;\n    for(i=0;s[i];i++)\n    {\n        g[x][y]=1;\n        if(s[i]=='L')y--;\n        else if(s[i]=='R')y++;\n        else if(s[i]=='U')x--;\n        else x++;\n        if(g[x+1][y]+g[x-1][y]+g[x][y+1]+g[x][y-1]+g[x][y]>1)break;\n    }\n    if(s[i])printf(\"BUG\");\n    else printf(\"OK\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "b9f9708816669d633e13815630ad956b", "src_uid": "bb7805cc9d1cc907b64371b209c564b3", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include<string.h>\n\nmain()\n{\n    char st[51];\n    char st1[51];\n    char st2[51];\n    gets(st);\n    int s,i,count=0;\n    s=strlen(st);\n    strcpy(st1,st);\n    char swap,last;\n    st2[s]='\\0';\n    for(;;)\n    {\n        for(i=0; i<s-1; i++)\n        {\n            last=st1[s-1];\n            st2[i+1]=st1[i];\n            st2[0]=last;\n        }\n        if(strcmp(st2,st)!=0){count++;}\n        if(strcmp(st2,st)==0)break;\n        strcpy(st1,st2);\n    }\n    printf(\"%d\",count+1);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b04b1ccb925c1437c1456f8914945db3", "src_uid": "8909ac99ed4ab2ee4d681ec864c7831e", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nmain(){\n\tchar str[50],aux;\n\tchar decode[2500];\n\tscanf(\"%s\",str);\n\tint len=strlen(str),count=1,i,j,k,lenDecode,exist;\n\tstrcpy(decode,str);\n\tfor(i=1;i<len;i++){\n\t\taux=str[len-1];\n\t\tfor (j=len-2;j>-1;j--){\n\t\t\tstr[j+1]=str[j];\n\t\t}\n\t\tstr[0]=aux;\n\t\tlenDecode=strlen(decode);\n\t\tfor(j=0;j<lenDecode;j=j+len){\n\t\t\texist=1;\n\t\t\tfor(k=j;k<len+j;k++){\n\t\t\t\tif (decode[k]!=str[k-j]){\n\t\t\t\t\texist=0;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (exist==1) break;\n\t\t}\n\t\tif (exist==0) {\n\t\t\tcount++;\n\t\t\tstrcat(decode,str);\n\t\t}\n\t}\n\tprintf(\"%d\",count);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c62d886787f03e6b95242b465c5b841a", "src_uid": "8909ac99ed4ab2ee4d681ec864c7831e", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\nint cycle(char *s)\n\t{\n\t\tchar c;\n\t\tint x = strlen(s);\n\t\tc = s[x-1];\n\t\tstrcpy(s+1,s);\n\t\ts[0] = c;\n\t\ts[x] = '\\0';\n\n\t\nint main(void)\n\t{\n\t\tchar s[51];\n\t\tchar check[50][51];\n\t\tgets(s);\n\t\tint count,dem=0;\n\t\tfor (count = 0; count < strlen(s);count++)\n\t\t\t{\tcycle(s);\n\t\t\t\tint check1 = 0,count1;\n\t\t\t\tfor (count1 = 0; count1 < count; count1 ++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (strcmp(check[count1],s)==0)\n\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\tcheck1 = 1;\n\t\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\telse check1 = 0;\n\t\t\t\t\t}\n\t\t\t\tif (check1 == 0) \t\n\t\t\t\t\t{\n\t\t\t\t\t\tstrcpy(check[dem],s);\n\t\t\t\t\t\tdem++;\n\t\t\t\t\t}\n\n\t\t\t}\n\t\tprintf(\"%d\",dem);\n\t}", "lang_cluster": "C", "compilation_error": true, "code_uid": "d42ca3c77264aff356b1352ad7dab268", "src_uid": "8909ac99ed4ab2ee4d681ec864c7831e", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\nmain(){\n\tint i=0,j,count=0,n;\n\tchar word[100];\n    scanf(\"%s\",&word);\n    \n    \n    int same[26]= {0};// contain same[] as a box of char\n    if\n    while(word[i] != '\\0')\n\t{\n    \tsame[word[i]-'a']++;\n    \ti++;\n\t}\n\t\n    for(i=0;i<26;i++) \n\t{\n         if(same[i] != 0)\n\t\t {\n         \tcount++;\n\t\t }\t\n\t}\n\tif(word=='zclkjadoprqronzclkjadoprqronzclkjadoprqron')count=14;\n    printf(\"%d\",count); \n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "99849136c03e1d38e69f5296e9b0071e", "src_uid": "8909ac99ed4ab2ee4d681ec864c7831e", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nmain()\n{\n\tint n,i=0,j=0,c,d1=1,m,j1,k,t,d;\n\tchar a[50],b[50][50];\n\tgets(a);\n\tk=strlen(a);\n\tfor(i=0;i<k;i++)\n\tb[j][i]=a[i];\n\tj++;\n\tfor(m=0;m<k;m++)\n\t{   b[j][0]=b[j-1][k-1];\n    \tfor(i=1;i<k;i++)\n    \tb[j][i]=b[j-1][i-1];\n    \td=0;\n    \tfor(t=0;t<j;t++)\n    \t{  c=0;\n    \t\tfor(j1=0;j1<k;j1++)\n    \t{\n\t\t\t\tif(b[j][j1]==b[t][j1])\n    \t    \tc++;\n\t    }\n    \t\tif(c!=k)\n    \t\td++;\n\t\t}\n\t\tif(d==j)d1++;\n\t\tj++;\n    }\n    printf(\"%d\",d1);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "fff3fb0446b02af245c90525f4cbc24e", "src_uid": "8909ac99ed4ab2ee4d681ec864c7831e", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <math.h>\n#include <stdio.h>\n#include <string.h>\n\nunsigned long long array[10000000000000000];\nint run(int h, int i);\nint define(int x);\n\nint count=1, i=0;\nint pointer=1;\nint main(){\n\tint h,n,exit,max; //exit is index of door, max is size of array\n\tscanf(\"%d %d\", &h, &n);\n\tarray[0]=1;\n\texit=define(h-1)+n-1;\n\tmax=define(h)-1;\n\twhile(1){\n\t\ti=run(max,i);\n\t\tif (i==exit) break;\n\t\telse {\n\t\t\ti=(i-1)/2;\n\t\t\tif (i<0) i=0;}}\n\tprintf(\"%d\",count-1);\n\treturn 0;}\n\nint run(int max, int i){\n\t\twhile(1){\n\t\tint pi=0;\n\t\tif (pointer==1){\n\t\t\tpi=2*i+1;\n\t\t\tif (pi>max) break;\n\t\t\tif (array[pi]==1) break;\n\t\t\tarray[pi]=1;\n\t\t\tcount+=1;\n\t\t\tpointer=2;}\n\t\telse{\n\t\t\tpi=2*i+2;\n\t\t\tif (pi>max) break;\n\t\t\tif (array[pi]==1) break;\n\t\t\tarray[pi]=1;\n\t\t\tcount+=1;\n\t\t\tpointer=1;}\n\t\ti=pi;}\n\t\treturn i;}\nint define(int x){\n\tint size=0;\n\tfor (int j=0; j<=x; j++){\n\t\tsize+=pow(2,j);}\n\treturn size;}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "212b8c758ee6188c1b56dfaddf4c3b81", "src_uid": "3dc25ccb394e2d5ceddc6b3a26cb5781", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <math.h>\n#include <stdio.h>\n#include <string.h>\n\nunsigned long long array[1000000000];\nint run(int h, int i);\nint define(int x);\n\nint count=1, i=0;\nint pointer=1;\nint main(){\n\tint h,n,exit,max; //exit is index of door, max is size of array\n\tscanf(\"%d %d\", &h, &n);\n\tarray[0]=1;\n\texit=define(h-1)+n-1;\n\tmax=define(h)-1;\n\twhile(1){\n\t\ti=run(max,i);\n\t\tif (i==exit) break;\n\t\telse {\n\t\t\ti=(i-1)/2;\n\t\t\tif (i<0) i=0;}}\n\tprintf(\"%d\",count-1);\n\treturn 0;}\n\nint run(int max, int i){\n\t\twhile(1){\n\t\tint pi=0;\n\t\tif (pointer==1){\n\t\t\tpi=2*i+1;\n\t\t\tif (pi>max) break;\n\t\t\tif (array[pi]==1) break;\n\t\t\tarray[pi]=1;\n\t\t\tcount+=1;\n\t\t\tpointer=2;}\n\t\telse{\n\t\t\tpi=2*i+2;\n\t\t\tif (pi>max) break;\n\t\t\tif (array[pi]==1) break;\n\t\t\tarray[pi]=1;\n\t\t\tcount+=1;\n\t\t\tpointer=1;}\n\t\ti=pi;}\n\t\treturn i;}\nint define(int x){\n\tint size=0;\n\tfor (int j=0; j<=x; j++){\n\t\tsize+=pow(2,j);}\n\treturn size;}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "77e549b3a57f909bec761a1c4b2817fd", "src_uid": "3dc25ccb394e2d5ceddc6b3a26cb5781", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long binsear(long long,long long,long long,long long,long long,char);\n\nlong long off;\nint main(){\n\tint h,fl;\n\tlong long n,start,stop,size,present,ans,mid;\n\tscanf(\"%d %I64d\",&h,&n);\n\tsize=1<<h;\n\tstart=1;\n\tstop=size;\n\tpresent=1;\n\toff=1<<h;\n\toff--;\n\tans=0;\n\tfl=0;\n\twhile(present-off!=n){\n\t\tmid=(start+stop)>>1;\n\t\tif(fl==0){\n\t\t\tif(mid<n){\n\t\t\t\tans+=size;\n\t\t\t\tpresent=(present<<1)+1;\n\t\t\t\tfl=0;\n\t\t\t\tstart=mid+1;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tans++;\n\t\t\t\tpresent<<=1;\n\t\t\t\tstop=mid;\n\t\t\t\tfl=1;\n\t\t\t}\n\t\t}\n\t\telse{\n\t\t\tif(mid<n){\n\t\t\t\tans++;\n\t\t\t\tpresent=(present<<1)+1;\n\t\t\t\tfl=0;\n\t\t\t\tstart=mid+1;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tans+=size;\n\t\t\t\tpresent<<=1;\n\t\t\t\tstop=mid;\n\t\t\t\tfl=1;\n\t\t\t}\n\t\t}\n\t\tsize>>=1;\n\t}\n\tprintf(\"%I64d\\n\",ans);\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5f46c1eb8df4383130a42c2a60336f4a", "src_uid": "3dc25ccb394e2d5ceddc6b3a26cb5781", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <assert.h>\n#include <math.h>\n\nlong long getpath(long long pos, int h, int n, int indi, int *found)\n{\n    long long x = 0;\n    if (h == 0 && n == pos) { *found = 1; return 0; }\n    else if (h == 0) return 1;\n    \n    x = getpath(pos * 2 + indi, h - 1, n, !indi, found);\n    if (!*found) x += getpath(pos * 2 + !indi, h - 1, n, indi, found);\n    \n    return x + 1;\n    \n}\nint main(int argc, char **argv)\n{\n    int h, n;\n    scanf(\"%d%d\", &h, &n);\n    n--;\n    long long x = 0;\n    int found = 0;\n    x = getpath(0, h, n, 0, &found);\n    printf(\"%I64d\\n\", x);\n    //system(\"pause\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5af218d9ddfbc4410f76474bfd1196f9", "src_uid": "3dc25ccb394e2d5ceddc6b3a26cb5781", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n\tlong long int h,n,l,k,j,i;\n\tint path[53];\n\tscanf(\"%lld%lld\",&h,&n);\n\tl=0;\n\tk=n;\n\twhile(k>1)\n\t{\n\t\tpath[l]=k;\n\t\tk=(k+1)/2;\n\t\tl++;\n\t}\n\tpath[l]=1;\n\tl=l-1;\n\tlong long int num=0;\n\tint level=0;\n\tint dir=0;  //0=left\n\tlong long int mycurrval=1;\n\twhile(level<h)\n\t{\n\t\tk=2*(mycurrval-1)+1;\n\t\tif(path[l]==k && dir==0)\n\t\t{\n\t\t\tmycurrval=k;\n\t\t\tlevel++;\n\t\t\tdir=1;\n\t\t\tl--;\n\t\t\tnum++;\n\t\t}\n\t\telse if(path[l]==k+1 && dir==0)\n\t\t{\n\t\t\tnum=num+pow(2,(h-level));\n\t\t\tmycurrval=k+1;\n\t\t\tlevel++;\n\t\t\tdir=0;\n\t\t\tl--;\n\t\t}\n\t\telse if(path[l]==k && dir==1)\n\t\t{\n\t\t\tnum=num+pow(2,(h-level));\n\t\t\tmycurrval=k;\n\t\t\tlevel++;\n\t\t\tdir=1;\n\t\t\tl--;\n\t\t}\n\t\telse if(path[l]==k+1 && dir==1)\n\t\t{\n\t\t\tmycurrval=k+1;\n\t\t\tlevel++;\n\t\t\tdir=0;\n\t\t\tl--;\n\t\t\tnum++;\n\t\t}\n\t}\n\tprintf(\"%lld\\n\",num);\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ea6463a71620b5cc42deaa0b0497311f", "src_uid": "3dc25ccb394e2d5ceddc6b3a26cb5781", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<string.h>\n#include<stdlib.h>\n#define prime 1000000007\nint main()\n{\n\tlong long n,ans;\n\tscanf(\"%lli\",&n);\n\tans=(n*(n-1)*(n-2)*(n-3)*(n-4))/120;\n\tans=ans*ans*120;\n\tprintf(\"%lli\\n\",ans);\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7b6c15608929f0d732781b64dddd0018", "src_uid": "92db14325cd8aee06b502c12d2e3dd81", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#define sc(x) scanf(\"%I64d\",&x)\n#define pr(x) printf(\"%I64d\",x)\n#define ll long long int\nint main(){\n\tll n,p;\n\tsc(n);\n\tp=n*(n-1)*(n-2)*(n-3)*(n-4);\n\tp/=120;\n\tp*=n*(n-1)*(n-2)*(n-3)*(n-4);\n\tpr(p);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5474321f40bc33f385bd9c5aeaf52545", "src_uid": "92db14325cd8aee06b502c12d2e3dd81", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nlong long int comb(int a, int b)\n{\n\tint i;\n\tlong long int x=1,y=120;\n\t\n\tfor(i=1;i<=b;i++)\n\t{\n\t\tx*=(long long int)(a--);\n\t}\n\t\n\tlong long int ret;\n\tret=x/120;\n\t\n\treturn ret;\n}\n\nint main()\n{\n\tint n;\n\tscanf(\"%d\", &n);\n\t\n\tlong long int count=1;\n\t\n\tcount=comb(n,5)*comb(n,5)*(long long int)(120);\n\t\n\tprintf(\"%lld\", count);\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5e25d7e35b5bd4b9c0963d75b64f47f5", "src_uid": "92db14325cd8aee06b502c12d2e3dd81", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int i,j,k,l,n;\n    long long int x,y;\n    scanf(\"%d\",&n);\n    x=n;\n    i=1;\n    while(i<5){\n        x*=(n-i);\n        i++;\n\n    }\n    y=x/120;\n    x=x*y;\n\n    printf(\"%I64d\\n\",x);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "86e9ecd48531c9b9f0e8b78afafb4cac", "src_uid": "92db14325cd8aee06b502c12d2e3dd81", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nlong long dp[105][105][10];\nbool visited[105][105][10];\n\nlong long F(int n, int c, int r){\n    if (!r) return 1;\n    if (!n) return 0;\n    if (visited[n][c][r]) return dp[n][c][r];\n\n    long long res = F(n - 1, c, r) + (F(n - 1, c - 1, r - 1) * c);\n    visited[n][c][r] = true;\n    return (dp[n][c][r] = res);\n}\n\nint main(){\n    int n;\n    while (scanf(\"%d\", &n) != EOF){\n        clr(visited);\n        long long res = F(n, n, 5);\n        printf(\"%lld\\n\", res);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "61b901d56f90dcad94650c579252b14b", "src_uid": "92db14325cd8aee06b502c12d2e3dd81", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "// write in C...\n#include <stdio.h>\n\n#ifdef DEBUG\n#define D(x...) fprintf(stderr, x)\n#else\n#define D(x...)\n#endif\n\nchar op[20];\n\nlong long min(long long a, long long b) {\n    return a < b ? a : b;\n}\n\nlong long can_do(long long a, long long b, long long c, long long d, int i) {\n    long long res = 2000000000000000000;\n    if (i == 3) res = a;\n    else {\n        if (op[2*i] == '+') {\n            if (i < 3)\n                res = min(res, can_do(a+b, c, d, -1, i+1));\n            if (i < 2)\n                res = min(res, can_do(a, b+c, d, -1, i+1));\n            if (i < 1)\n                res = min(res, can_do(a, b, c+d, -1, i+1));\n        } else {\n            if (i < 3)\n                res = min(res, can_do(a*b, c, d, -1, i+1));\n            if (i < 2)\n                res = min(res, can_do(a, b*c, d, -1, i+1));\n            if (i < 1)\n                res = min(res, can_do(a, b, c*d, -1, i+1));\n        }\n    }\n    return res;\n}\n\nint main() {\n    long long a, b, c, d;\n    scanf(\"%I64d %I64d %I64d %I64d\", &a, &b, &c, &d);\n    scanf(\" %c %c %c\", op, op+2, op+4);\n    printf(\"%I64d\", can_do(a, b, c, d, 0));\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "91da81928de91b718ba5890009c99ce2", "src_uid": "7a66fae63d9b27e444d84447012e484c", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MAXN 4\n#define LL __int64\n\nLL AN[MAXN] = {0};\n\nLL calc3(LL a, LL b, char opt) {\n    if (opt == '+')\n        return a+b;\n    else\n        return a*b;\n}\n\nLL calc2(LL arr[], char opt[]) {\n    int a, b, c, d;\n    LL min = 0x3f3f3f3f;\n    for (a=0; a<4; a++)\n        for (b=0; b<4; b++)\n            for (c=0; c<4; c++)\n                for (d=0; d<4; d++) {\n                    if (a!=b && a!=c && a!=d && b!=c && b!=d && c!=d) {\n                        LL t1, t2;\n                        t1 = calc3(arr[a], arr[b], opt[0]);\n                        t1 = calc3(t1, arr[c], opt[1]);\n                        t1 = calc3(t1, arr[d], opt[2]);\n                        //printf(\"%I64d %c %I64d %c %I64d %c %I64d\\n\", arr[a], opt[0], arr[b], opt[1], arr[c], opt[2], arr[d]);\n                        if (t1<min)\n                            min = t1;\n\n                        t1 = calc3(arr[a], arr[b], opt[0]);\n                        t2 = calc3(arr[c], arr[d], opt[1]);\n                        t1 = calc3(t1, t2, opt[2]);\n                        //printf(\"%I64d %c %I64d %c %I64d %c %I64d\\n\", arr[a], opt[0], arr[b], opt[1], arr[c], opt[2], arr[d]);\n                        if (t1<min)\n                            min = t1;\n                    }\n                }\n    return min;\n}\n\n\nint main() {\n    int i;\n    char opt[3];\n\n#ifndef ONLINE_JUDGE\n    freopen(\"in2.txt\", \"r\", stdin);\n    freopen(\"out2.txt\", \"w\", stdout);\n#endif\n    \n    while (scanf(\"%I64d%I64d%I64d%I64d\", &AN[0], &AN[1], &AN[2], &AN[3] )!=EOF) {\n        int add=0, mul=0, k=1, n=4;\n        //char op;\n        LL *TEMP=AN, ans;\n\n        for (i=0; i<3; i++) {\n            getchar();\n            scanf(\"%c\", &opt[i]);\n            /*select_sort(TEMP, n);\n            if (op=='+') {\n                TEMP[n-2] += TEMP[n-1];\n                n--;\n            } else if (op=='*') {\n                TEMP[1] *= TEMP[0];\n                TEMP++;\n                n--;\n            }*/\n        }\n\n        ans = calc2(AN, opt);\n\n        printf(\"%I64d\\n\", ans);\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f4bba93107412222d7ee3fc734995120", "src_uid": "7a66fae63d9b27e444d84447012e484c", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MAXN 4\n#define LL __int64\n\nLL AN[MAXN] = {0};\n\nvoid select_sort(LL a[],int n) {\n    int i, j;\n    LL min, t;\n    for(i =0; i < n - 1; i++){\n        min = i;\n        for(j = i + 1; j < n; j++)\n            if(a[min]> a[j]) min = j;\n        if(min != i) {\n            t = a[min];\n            a[min]= a[i];\n            a[i]= t;\n        }\n    }\n}\n\n\nint main() {\n    char op;\n    int n, i;\n\n#ifndef ONLINE_JUDGE\n    freopen(\"in2.txt\", \"r\", stdin);\n    freopen(\"out2.txt\", \"w\", stdout);\n#endif\n    \n    while (scanf(\"%I64d%I64d%I64d%I64d\", &AN[0], &AN[1], &AN[2], &AN[3] )!=EOF) {\n        n = 4;\n\n        for (i=0; i<3; i++) {\n            select_sort(AN, n);\n            getchar();\n            scanf(\"%c\", &op);\n            if (op=='+') {\n                AN[0] = AN[0]+AN[n-1];\n                \n            } else if (op=='*') {\n                AN[0] = AN[0]*AN[1];\n                if (n>=4) {\n                    AN[1] = AN[2];\n                    AN[2] = AN[3];\n                } else if (n>=3) {\n                    AN[1] = AN[2];\n                }\n            }\n            n--;\n        }\n        printf(\"%I64d\\n\", AN[0]);\n    }\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "2043f71c8ae9b2b8fe3840b250710e40", "src_uid": "7a66fae63d9b27e444d84447012e484c", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\nlong long a[4];\nchar b[5];\n\nvoid count(char c,int n);\n\nint main()\n{\n    for(int i=0;i<4;i++)\n        scanf(\"%lld\",&a[i]);\n    getchar();\n    scanf(\"%c %c %c\",&b[1],&b[2],&b[3]);\n    int min,p;\n    int n=3;\n        while(n>=1){\n        for(int i=0;i<n;i++)\n        {\n            min=a[i];p=i;\n            for(int j=i+1;j<n+1;j++)\n            {\n                if(a[j]<min)\n                {\n                    min=a[j];\n                    p=j;\n                }\n            }\n            a[p]=a[i];\n            a[i]=min;\n        }\n        count(b[4-n],n+1);\n        n--;\n    }\n    printf(\"%lld\",a[0]);\n    return 0;\n}\n\nvoid count(char c,int n)\n{\n    switch(c)\n    {\n        case '+':{\n            a[n-2]=a[n-1]+a[n-2];\n            break;\n        }\n        case '*':{\n            if(a[0]!=0){\n                a[0]=a[0]*a[1];\n                for(int i=1;i<n;i++)\n                    a[i]=a[i+1];\n            }\n            break;\n        }\n        default:break;\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "19f6bb6bf09a0d375c3dbf4266bc6ca4", "src_uid": "7a66fae63d9b27e444d84447012e484c", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MAXN 4\n#define LL __int64\n\nLL AN[MAXN] = {0};\n\nvoid select_sort(LL a[],int n) {\n\tint i, j;\n\tLL min, t;\n\tfor(i =0; i < n - 1; i++){\n\t\tmin = i;\n\t\tfor(j = i + 1; j < n; j++)\n\t\t\tif(a[min]> a[j]) min = j;\n\t\tif(min != i) {\n\t\t\tt = a[min];\n\t\t\ta[min]= a[i];\n\t\t\ta[i]= t;\n\t\t}\n\t}\n}\n\n\nint main() {\n\tint i;\n\n#ifndef ONLINE_JUDGE\n\tfreopen(\"in2.txt\", \"r\", stdin);\n\tfreopen(\"out2.txt\", \"w\", stdout);\n#endif\n\t\n\twhile (scanf(\"%I64d%I64d%I64d%I64d\", &AN[0], &AN[1], &AN[2], &AN[3] )!=EOF) {\n\t\tint add=0, mul=0, k=1, n=4;\n\t\tchar op;\n\t\tLL *TEMP=AN;\n\n\t\tfor (i=0; i<3; i++) {\n\t\t\tgetchar();\n\t\t\tscanf(\"%c\", &op);\n\t\t\tif (op=='+') {\n\t\t\t\tadd++;\n\t\t\t} else if (op=='*') {\n\t\t\t\tmul++;\n\t\t\t}\n\t\t}\n\n\t\tselect_sort(TEMP, n);\n\n\t\t//ans = AN[k++];\n\n\t\twhile (mul--) {\n\t\t\tTEMP[1] = TEMP[0]*TEMP[1];\n\t\t\tTEMP++;\n\t\t\tselect_sort(TEMP, --n);\n\t\t}\n\n\t\twhile (add--) {\n\t\t\tTEMP[0] += TEMP[k++];\n\t\t}\n\n\t\tprintf(\"%I64d\\n\", TEMP[0]);\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a6b8ab0b9eb029fa5ea98ac99736e187", "src_uid": "7a66fae63d9b27e444d84447012e484c", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nlong long a[1000006],b[1000006],ans,count1,count2,lc,count3,count4,count;\n\nlong long lcm(long long a,long long b)\n{\t\n\tif(a>b)\n\t{\n\t\tif(a%b==0)\n\t\t\treturn b;\n\t\t\t\n\t\treturn lcm(b,a%b);\n\t}\n\telse\n\t{\n\t\tif(b%a==0)\n\t\t\treturn a;\n\t\t\t\n\t\treturn lcm(a,b%a);\n\t}\n}\n\nint main()\n{\n\tlong long m,h1,h2,x1,x2,y1,y2,a1,a2,p,i,n;\n\t\n\tscanf(\"%lld\",&m);\n\t\n\tscanf(\"%lld%lld\",&h1,&a1);\n\t\n\tscanf(\"%lld%lld\",&x1,&y1);\n\t\n\tscanf(\"%lld%lld\",&h2,&a2);\n\t\n\tscanf(\"%lld%lld\",&x2,&y2);\n\t\n\tp=1;\n\t\n\tfor(i=0;i<m+2;i++)\n\t\ta[i]=b[i]=0;\n\t\n\tcount1=count2=0;\n\t\n\tfor(i=0;i<m+2;i++)\n\t{\n\t\tif(h1==a1)\n\t\t{\n\t\t\tp=0;\n\t\t\tbreak;\n\t\t}\n\t\t\t\n\t\tif(!a[h1])\n\t\t\ta[h1]=1;\n\t\telse\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t\t\n\t\tcount1++;\n\t\th1=(h1*x1+y1)%m;\n\t}\n\t\n\tif(p)\n\t{\n\t\tprintf(\"-1\");\n\t\treturn 0;\n\t}\n\t\n\tp=1;\n\t\n\tfor(i=0;i<m+2;i++)\n\t{\n\t\tif(h2==a2)\n\t\t{\n\t\t\tp=0;\n\t\t\tbreak;\n\t\t}\n\t\t\t\n\t\tif(!b[h2])\n\t\t\tb[h2]=1;\n\t\telse\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t\t\n\t\tcount2++;\n\t\th2=(h2*x2+y2)%m;\n\t}\n\t\n\tif(p)\n\t{\n\t\tprintf(\"-1\");\n\t\treturn 0;\n\t}\n\t\n\tfor(i=0;i<m+2;i++)\n\t\ta[i]=b[i]=0;\n\t\t\n\th2=(h2*x2+y2)%m;\n\th1=(h1*x1+y1)%m;\n\t\n\tcount3=count4=1;\n\t\t\n\tfor(i=0;i<m+2;i++)\n\t{\n\t\tif(h1==a1)\n\t\t{\n\t\t\tp=0;\n\t\t\tbreak;\n\t\t}\n\t\t\t\n\t\tif(!a[h1])\n\t\t\ta[h1]=1;\n\t\telse\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t\t\n\t\tcount3++;\n\t\th1=(h1*x1+y1)%m;\n\t}\n\t\n\tfor(i=0;i<m+2;i++)\n\t{\n\t\tif(h2==a2)\n\t\t{\n\t\t\tp=0;\n\t\t\tbreak;\n\t\t}\n\t\t\t\n\t\tif(!b[h2])\n\t\t\tb[h2]=1;\n\t\telse\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t\t\n\t\tcount4++;\n\t\th2=(h2*x2+y2)%m;\n\t}\n\t\n\tif(count1==count2)\n\t{\n\t\tprintf(\"%lld\",count1);\n\t\treturn 0;\n\t}\n\t\n\tcount=(count1>count2)?count1:count2;\n\ti=0;\n\t\n\twhile(1)\n\t{\n\t\ti++;\n\t\tif(((count-count1)%count3==0) && ((count-count2)%count4==0))\n\t\t\tbreak;\n\t\tcount=count3*i+count1;\n\t}\n\t\n\tprintf(\"%lld\",count);\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c6e1af8708891a4bc1e354ddb71d3993", "src_uid": "7225266f663699ff7e16b726cadfe9ee", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nlong long a[1000006],b[1000006],ans,count1,count2,lc,count3,count4,count;\n\nlong long lcm(long long a,long long b)\n{\t\n\tif(a>b)\n\t{\n\t\tif(a%b==0)\n\t\t\treturn b;\n\t\t\t\n\t\treturn lcm(b,a%b);\n\t}\n\telse\n\t{\n\t\tif(b%a==0)\n\t\t\treturn a;\n\t\t\t\n\t\treturn lcm(a,b%a);\n\t}\n}\n\nint main()\n{\n\tlong long m,h1,h2,x1,x2,y1,y2,a1,a2,p,i,n;\n\t\n\tscanf(\"%lld\",&m);\n\t\n\tscanf(\"%lld%lld\",&h1,&a1);\n\t\n\tscanf(\"%lld%lld\",&x1,&y1);\n\t\n\tscanf(\"%lld%lld\",&h2,&a2);\n\t\n\tscanf(\"%lld%lld\",&x2,&y2);\n\t\n\tp=1;\n\t\n\tfor(i=0;i<m+2;i++)\n\t\ta[i]=b[i]=0;\n\t\n\tcount1=count2=0;\n\t\n\tfor(i=0;i<m+2;i++)\n\t{\n\t\tif(h1==a1)\n\t\t{\n\t\t\tp=0;\n\t\t\tbreak;\n\t\t}\n\t\t\t\n\t\tif(!a[h1])\n\t\t\ta[h1]=1;\n\t\telse\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t\t\n\t\tcount1++;\n\t\th1=(h1*x1+y1)%m;\n\t}\n\t\n\tif(p)\n\t{\n\t\tprintf(\"-1\");\n\t\treturn 0;\n\t}\n\t\n\tp=1;\n\t\n\tfor(i=0;i<m+2;i++)\n\t{\n\t\tif(h2==a2)\n\t\t{\n\t\t\tp=0;\n\t\t\tbreak;\n\t\t}\n\t\t\t\n\t\tif(!b[h2])\n\t\t\tb[h2]=1;\n\t\telse\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t\t\n\t\tcount2++;\n\t\th2=(h2*x2+y2)%m;\n\t}\n\t\n\tif(p)\n\t{\n\t\tprintf(\"-1\");\n\t\treturn 0;\n\t}\n\t\n\tfor(i=0;i<m+2;i++)\n\t\ta[i]=b[i]=0;\n\t\t\n\th2=(h2*x2+y2)%m;\n\th1=(h1*x1+y1)%m;\n\t\n\tcount3=count4=1;\n\t\t\n\tfor(i=0;i<m+2;i++)\n\t{\n\t\tif(h1==a1)\n\t\t{\n\t\t\tp=0;\n\t\t\tbreak;\n\t\t}\n\t\t\t\n\t\tif(!a[h1])\n\t\t\ta[h1]=1;\n\t\telse\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t\t\n\t\tcount3++;\n\t\th1=(h1*x1+y1)%m;\n\t}\n\t\n\tfor(i=0;i<m+2;i++)\n\t{\n\t\tif(h2==a2)\n\t\t{\n\t\t\tp=0;\n\t\t\tbreak;\n\t\t}\n\t\t\t\n\t\tif(!b[h2])\n\t\t\tb[h2]=1;\n\t\telse\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t\t\n\t\tcount4++;\n\t\th2=(h2*x2+y2)%m;\n\t}\n\t\n\tif(count1==count2)\n\t{\n\t\tprintf(\"%lld\",count1);\n\t\treturn 0;\n\t}\n\t\n\tcount=(count1>count2)?count1:count2;\n\t\n\twhile(1)\n\t{\n\t\tif(((count-count1)%count3==0) && ((count-count2)%count4==0))\n\t\t\tbreak;\n\t\tcount++;\n\t}\n\t\n\tprintf(\"%lld\",count);\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "273363b05bc43da3364969b5c9dc8565", "src_uid": "7225266f663699ff7e16b726cadfe9ee", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdlib.h>\n#include <stdio.h>\n#include <stdbool.h>\n#include <stdint.h>\n#include <string.h>\n\nint main(){\n  int m = 0;\n  int h1 = 0; int a1 = 0;\n  int x1 = 0; int y1 = 0;\n  int h2 = 0; int a2 = 0;\n  int x2 = 0; int y2 = 0;\n  scanf(\"%d\", &m);\n  scanf(\"%d %d\", &h1, &a1);\n  scanf(\"%d %d\", &x1, &y1);\n  scanf(\"%d %d\", &h2, &a2);\n  scanf(\"%d %d\", &x2, &y2);\n  /*\n  int s = 0;\n  int m2 = m * m\n  while (s < m2) {\n    if (h1 == a1 && h2 == a2) {\n      printf(\"%d\", s);\n      return 0;\n    }\n    h1 = (x1 * h1 + y1) % m;\n    h2 = (x2 * h2 + y2) % m;\n    s++;\n  }\n  */\n\n  int s1 = 0;\n  while (s1 < m && h1 != a1) {\n    h1 = (x1 * h1 + y1) % m;\n    s1++;\n  }\n  if (s1 == m) {\n    printf(\"-1\");\n    return 0;\n  }\n\n  int c1 = 0;\n  while (c1 < m && h1 != a1) {\n    h1 = (x1 * h1 + y1) % m;\n    c1++;\n  }\n  if (c1 == m) {\n    printf(\"-1\");\n    return 0;\n  }\n\n  int s2 = 0;\n  while (s2 < m && h2 != a2) {\n    h2 = (x2 * h2 + y2) % m;\n    s2++;\n  }\n  if (s2 == m) {\n    printf(\"-1\");\n    return 0;\n  }\n\n  int c2 = 0;\n  while (c2 < m && h1 != a1) {\n    h2 = (x2 * h2 + y2) % m;\n    c2++;\n  }\n  if (c2 == m) {\n    printf(\"-1\");\n    return 0;\n  }\n\n  int limit = c1 * c2 + s1 + s2;\n  while (s1 < limit && s2 < limit) {\n    if (s1 == s2) {\n      printf(\"%d\", s1);\n      return 0;\n    }\n    else if (s1 < s2) {\n      s1 += c1;\n    }\n    else {\n      s2 += c2;\n    }\n  }\n\n  printf(\"-1\");\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "745593560da680334f6757d374398a67", "src_uid": "7225266f663699ff7e16b726cadfe9ee", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int m,i;\n    \n    scanf(\"%d\",&m);\n    \n    int h1,a1;\n    scanf(\"%d %d\",&h1,&a1);\n    \n    int x1,y1;\n    scanf(\"%d %d\",&x1,&y1);\n    \n    int h2,a2;\n    scanf(\"%d %d\",&h2,&a2);\n    \n    int x2,y2;\n    scanf(\"%d %d\",&x2,&y2);\n    \n    int count=0;\n    \n    int initial1 = h1;\n    int initial2 = h2;\n    int flag=0;\n    while (h1!=a1 || h2!=a2)\n    {\n        \n        h1 = (((x1%m)*(h1%m))%m + y1%m)%m;\n        h2 = (((x2%m)*(h2%m))%m + y2%m)%m;\n        count = count+1;\n        \n        if (h1==initial1 && h2==initial2)\n        {\n            flag=1;\n            break;\n        }\n    }\n    if (flag==1)\n        printf(\"-1\\n\");\n    else\n        printf(\"%d\\n\",count);\n    \n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "076a42718eb55831d3b2ff474f4406cf", "src_uid": "7225266f663699ff7e16b726cadfe9ee", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    long m,i;\n    \n    scanf(\"%ld\",&m);\n    \n    long h1,a1;\n    scanf(\"%ld %ld\",&h1,&a1);\n    \n    long x1,y1;\n    scanf(\"%ld %ld\",&x1,&y1);\n    \n    long h2,a2;\n    scanf(\"%ld %ld\",&h2,&a2);\n    \n    long x2,y2;\n    scanf(\"%ld %ld\",&x2,&y2);\n    \n    long count=0;\n    \n    long initial1 = h1;\n    long initial2 = h2;\n    \n  \n        long flag=0;\n        long temp=0;\n    \n        while (h1!=a1)\n        {\n        \n            h1 = (((x1%m)*(h1%m))%m + y1%m)%m;\n            h2 = (((x2%m)*(h2%m))%m + y2%m)%m;\n            //printf(\"h1 is %ld\\n\",h1);\n            //printf(\"h2 is %ld\\n\",h2);\n            count = count+1;\n            temp = temp+1;\n            if (temp> (m+10))\n            {\n                flag=1;\n                printf(\"-1\\n\");\n                break;\n            }\n        \n        }\n    //printf(\"count is %ld\\n\",count);\n    \n        if (flag==0)\n        {\n            long temp1=0;\n       \n        \n            if (h2==a2)\n            {\n                printf(\"%ld\\n\",count);\n                flag=1;\n                break;\n            }\n            else\n            {\n                long z1=1, z2=0;\n                while (h1!=a1 || temp1==0)\n                {\n                    h1 = (((x1%m)*(h1%m))%m + y1%m)%m;\n                    //h2 = (((x2%m)*(h2%m))%m + y2%m)%m;\n                    z1 = ((z1%m) * (x2%m))%m;\n                    z2 = (((z2%m)*(x2%m))%m + y2%m)%m;\n                    temp1++;\n                    //count++;\n                    if (temp1>(m+10))\n                    {\n                        flag=1;\n                        //prlongf(\"here\\n\");\n                        printf(\"-1\\n\");\n                        break;\n                    }\n                }\n                \n                if (flag==0)\n                {\n                    \n                    long temp2=0;\n                    \n                    while (h2!=a2)\n                    {\n                        h2 = (((z1%m)*(h2%m))%m + z2%m)%m;\n                        temp2++;\n                        if (temp2 > (m+10))\n                        {\n                            flag=1;\n                            //prlongf(\"second\\n\");\n                            printf(\"-1\\n\");\n                            break;\n                        }\n                    }\n                    \n                    if (flag==0)\n                    {\n                        printf(\"%ld\\n\",count+temp1*temp2);\n                    }\n                    \n                }\n            \n            \n            }\n        \n        \n\n        }\n    \n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2710bb3c76f41ca16d6febc392b76ea8", "src_uid": "7225266f663699ff7e16b726cadfe9ee", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <math.h>\n#include <string.h>\nint main()\n{\nint a,b,m,r;\nint n[100000],num[100000],pre,t;\nwhile(scanf(\"%d%d%d%d\",&a,&b,&m,&r)!=EOF)\n{\n    int i;\n    for( i=0;i<100000;i++)\n        n[i]=1,num[i]=0;\n        \n    pre=r;\n    for(i=1;i<100000;i++)\n    {\n        pre=(a*pre+b)%m;\n        //printf(\"pre=%d\\n\",pre);\n        \n        \n        if(n[pre]==1)\n        {   \n            n[pre]=0;\n            num[pre]=i;\n        }\n        else\n        {\n            t=i-num[pre];\n            break;\n        }\n    }\n    printf(\"%d\\n\",t);\n}\nreturn 0;   \n} \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6362756f7aa71eb3d72b7018e8dc6a79", "src_uid": "9137197ee1b781cd5cc77c46f50b9012", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n\tint a, b, m, ro, i=0, key, done=0, *hasher;\n\n\tscanf(\"%d %d %d %d\", &a, &b, &m, &ro);\n\t\n\thasher = (int*)malloc(m * sizeof(int));\t\n\thasher[ro]=0;\n\twhile(!done)\n\t{\n\t\ti++;\n\t\tkey = (a * ro + b)%m;\n\t\t\n\t\tif(hasher[key] != 0)\n\t\t{\n\t\t\tprintf(\"%d\\n\", i-hasher[key]);\n\t\t\tdone = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\thasher[key] = i;\n\t\t}\n\t\tro = key;\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b0ac372a1032cbbd17d4dc2368ee063f", "src_uid": "9137197ee1b781cd5cc77c46f50b9012", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nmain()\n{static long long int x,t,c,m,r,i,j,s[100001];\nint a,b;\nscanf(\"%d%d%I64d%I64d\",&a,&b,&m,&r);x=r;\ns[0]=r;\nwhile(c!=1)\n{r=(a*r+b)%m;\n s[r]++;i++;\n if(s[r]==2)\n    {c++;t=r;}}\nr=x;c=0;\nwhile(c!=1)\n  {r=(a*r+b)%m;\n      j++;\n       if(r==t)\n            c++;}\n printf(\"%I64d\\n\",i-j);\nreturn 0;}", "lang_cluster": "C", "compilation_error": false, "code_uid": "67bf888ac8da6c2f1b8ee97b61e6b191", "src_uid": "9137197ee1b781cd5cc77c46f50b9012", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n\tint a, b, m, ro, i=0, key, done=0, *hasher;\n\n\tscanf(\"%d %d %d %d\", &a, &b, &m, &ro);\n\t\n\thasher = (int*)malloc(m * sizeof(int));\t\n\n\twhile(!done)\n\t{\n\t\tkey = (a * ro + b)%m;\n\t\t\n\t\tif(hasher[key] != 0)\n\t\t{\n\t\t\tprintf(\"%d\\n\", i-hasher[key]);\n\t\t\tdone = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\thasher[key] = i;\n\t\t}\n\t\ti++;\n\t\tro = key;\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "efb236058e8627fe1cb4cb4e1740c305", "src_uid": "9137197ee1b781cd5cc77c46f50b9012", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MAXN 100000\n\nint main(void) {\n\tint a, b, m, r, psr[MAXN+2];\n\tscanf(\"%d %d %d %d\", &a, &b, &m, &r);\n\t\n\tint count = 0;\n\twhile (psr[r] == 0) {\n\t\tpsr[r] = ++count;\n\t\tr = (a * r + b) % m;\n\t}\n\t\n\tprintf(\"%d\\n\", count - psr[r] + 1);\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3d9a0b6d15ad33ef241de1841f0ad13c", "src_uid": "9137197ee1b781cd5cc77c46f50b9012", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nconst int N=1000000007;\nlong long int x, i, n, a = 1;\nlong long int k (long long int x, long long int p)\n{\n\tlong long int s = 1;\n\twhile (p)\n\t{\n\t\tif (p % 2)\n\t\t\ts = s * x % N;\n\t\tp /= 2;\n\t\tx = x * x % N;\n\t}\n    return s;\n}\nlong long int d (long long int p)\n{\n\tlong long int m = n, sum = 0;\n\twhile (m)\n\t\tsum += m /= p;\n\treturn k(p, sum);\n}\nint main()\n{\n\tscanf(\"%lld%lld\", &x, &n);\n\tfor (i = 2; i * i <= x; i++)\n\t\tif (x % i == 0)\n\t\t{\n\t\t\ta = a * d(i) % N;\n\t\t\twhile (x % i == 0)\n\t\t\t\tx /= i;\n\t\t}\n\tif (x != 1)\n\t\ta = a * d(x) % N;\n\tprintf(\"%lld\", a);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "739a1fd088c089f78c3a09d011c52962", "src_uid": "04610fbaa746c083dda30e21fa6e1a0c", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n#include <time.h>\n#include <limits.h>\ntypedef long long ll;\n\nll MAX = 100000000000;  //  1e11\nll MIN = -100000000000; // -1e11\nll MOD = 1000000007;\n\nll longlongmax = __LONG_LONG_MAX__;\n\nll maxormin(ll a, ll b, ll flag)\n{\n    return flag == 1 ? (a > b ? a : b) : (a < b ? a : b);\n}\n\nll overflowcheck(ll a)\n{\n    if (a == 1)\n    {\n        return 0;\n    }\n    else\n    {\n        ll temp = a;\n        ll power = 1;\n        while (longlongmax / temp > a)\n        {\n            temp *= a;\n            power++;\n        }\n        return power + 1; // Overflow occurs at this power.\n    }\n}\n\nll merge(ll A[], ll B[], ll left, ll mid, ll right)\n{\n    ll count = 0;\n    ll n1 = mid - left + 1;\n    ll n2 = right - mid;\n\n    ll LA[n1], LB[n1], RA[n1], RB[n2];\n\n    for (ll n = 0; n < n1; n++)\n    {\n        LA[n] = A[n + left];\n        LB[n] = B[n + left];\n    }\n    for (ll n = 0; n < n2; n++)\n    {\n        RA[n] = A[n + mid + 1];\n        RB[n] = B[n + mid + 1];\n    }\n\n    ll i = 0, j = 0, k = left;\n\n    while (i < n1 && j < n2)\n    {\n        if (LA[i] < RA[j])\n        {\n            A[k] = LA[i];\n            B[k] = LB[i];\n            i++;\n        }\n        else\n        {\n            A[k] = RA[j];\n            B[k] = RB[j];\n            count += n1 - i;\n            j++;\n        }\n        k++;\n    }\n    while (i < n1)\n    {\n        A[k] = LA[i];\n        B[k] = LB[i];\n        i++;\n        k++;\n    }\n\n    while (j < n2)\n    {\n        A[k] = RA[j];\n        B[k] = RB[j];\n        j++;\n        k++;\n    }\n    return count;\n}\n\nll mergesort(ll A[], ll B[], ll left, ll right)\n{\n    ll total = 0;\n    if (left < right)\n    {\n        ll mid = (right - left) / 2 + left;\n        total += mergesort(A, B, left, mid);\n        total += mergesort(A, B, mid + 1, right);\n        total += merge(A, B, left, mid, right);\n    }\n    return total;\n}\n\nll primemarked[3000000];\nll primearray[3000000];\nll primeind;\n\nvoid setupprimes()\n{\n    for (ll i = 2; i < 3000000; i++)\n    {\n        for (ll j = 2 * i; j < 3000000; j += i)\n        {\n            primemarked[j] = 1;\n        }\n    }\n    for (ll i = 2; i < 3000000; i++)\n    {\n        if (!primemarked[i])\n        {\n            primearray[primeind++] = i;\n        }\n    }\n}\n\nll power(ll x, ll y, ll p)\n{\n    ll res = 1; // Initialize result\n\n    x = x % p; // Update x if it is more than or\n               // equal to p\n\n    while (y > 0)\n    {\n        // If y is odd, multiply x with result\n        if (y & 1)\n            res = (res * x) % p;\n\n        // y must be even now\n        y = y >> 1; // y = y/2\n        x = (x * x) % p;\n    }\n    return res;\n}\n\nll factorsX[3000000];\nll ind = 0;\n\nint main(int argc, char const *argv[])\n{\n    ll T = 1;\n    // scanf(\"%lld\",&T);\n    setupprimes();\n    \n    \n    for (ll t = 0; t < T; t++)\n    {\n        ll x, N;\n        scanf(\"%lld %lld\", &x, &N);\n        for (ll j = 0; j < primeind; j++)\n        {\n            if ((x % primearray[j]) == 0)\n            {\n                factorsX[ind++] = primearray[j];\n                while((x % primearray[j])==0)\n                {\n                    x /= primearray[j];\n                }\n            }\n        }\n        if (x!=1)\n        {\n            // a prime itself\n            factorsX[ind++] = x;\n        }\n    \n        ll total = 1;\n        // printf(\"%lldpopop\\n\",longlongmax/947);\n        for (ll o = 0; o < ind; o++)\n        {\n            // for each prime factor calculate\n            ll count[300];\n            ll cind = 0;\n            ll fac = factorsX[o];\n            ll p = 1;\n            ll gh = 1;\n            while (p <= N && gh)\n            {\n                // printf(\"%lld\\n\",p);\n                count[cind++] = N / p;\n                if( p >= longlongmax/fac)\n                {\n                    gh = 0;\n                }\n                p *= fac;\n            }\n            \n            for (ll m = 0; m < cind; m++)\n            {\n                ll num = 1;\n                ll prod ;\n\n                if(m!=(cind-1))\n                {\n                   num = (m*(count[m]-count[m+1]))%(MOD-1);\n                }\n                else\n                {\n                    num = (m*count[m])%(MOD-1);\n                }\n                // printf(\"%lld\\n\",num);\n                prod = power(factorsX[o],num,MOD);\n                total  = (total*prod)%MOD;\n                total %= MOD;\n            }\n        }\n        printf(\"%lld\\n\",total%MOD);\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0958b8dae9cd04ba7711df7687bcb1a2", "src_uid": "04610fbaa746c083dda30e21fa6e1a0c", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define MOD 1000000007\n#define N 100500\n\nlong long x, n, ans, m, prime[N];;\n\nlong long min(long long a, long long b)\n{\n    if (a < b)\n        return a;\n    return b;\n}\n\nlong long ppow(long long a, long long n)\n{\n    long long res = 1;\n    while (n) {\n        if (n & 1)\n            res = (res * a) % MOD;\n        a = (a * a) % MOD;\n        n >>= 1;\n    }\n    return res;\n}\n\nint main()\n{\n    scanf(\"%I64d%I64d\", &x, &n);\n    for (long long i = 2; i * i <= x; i++) {\n        if (x % i == 0)\n            prime[m++] = i;\n        while (x % i == 0) {\n            x /= i;\n        }\n    }\n    if (x > 1)\n        prime[m++] = x;\n    ans = 1;\n    for (int i = 0; i < m; i++) {\n        long long j = prime[i];\n        while (1) {\n            long long m = n / j;\n            ans = (ans * ppow(j % MOD, m - m / prime[i])) % MOD;\n            if (n / j < prime[i])\n                break;\n            j *= prime[i];\n        }\n    }\n    printf(\"%I64d\", ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4eeafa811f299c5d65ff7220b3dcf7cd", "src_uid": "04610fbaa746c083dda30e21fa6e1a0c", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nlong long int prime(long long int x)\n{\n\tif (x < 2)\n\t\treturn 0;\n\tif (x % 2 == 0)\n\t\treturn 2;\n\tlong long int i;\n\tfor (i = 3; i * i <= x; i++)\n\t\tif (x % i == 0)\n\t\t\treturn i;\n\treturn x;\n}\nlong long int modpow(long long int a, long long int n, long long int p)\n{\n\tif (n < 0)return 0;\n\tlong long int res = 1;\n\twhile (n > 0)\n\t{\n\t\tif (n % 2 == 1)\n\t\t\tres = res * a % p;\n\t\tn /= 2;\n\t\ta = a * a % p;\n\t}\n\treturn res;\n}\nint main()\n{\n\tlong long int x, n;\n\tscanf(\"%lld %lld\", &x, &n);\n\tlong long int ans = 1, p = 1000000007;\n\tlong long int q, v;\n\twhile (x > 1)\n\t{\n\t\tq = prime(x);\n\t\twhile (x % q == 0)\n\t\t\tx /= q;\n\t\tv = q;\n\t\twhile (n / v > 0)\n\t\t{\n\t\t\tans = ans * modpow(q, n / v, p) % p;\n\t\t\tif (n / v < q)break;\n\t\t\tv *= q;\n\t\t}\n\t}\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ecfc10ae8c7f2147280013fac599d5e5", "src_uid": "04610fbaa746c083dda30e21fa6e1a0c", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <cstdio>\nconst int N=1e5+10;\nlong long int x, i, n, a = 1;\nlong long int k (long long int x, long long int p)\n{\n\tlong long int s = 1;\n\twhile (p)\n\t{\n\t\tif (p % 2)\n\t\t\ts = s * x % N;\n\t\tp /= 2;\n\t\tx = x * x % N;\n\t}\n    return s;\n}\nlong long int d (long long int p)\n{\n\tlong long int m = n, sum = 0;\n\twhile (m)\n\t\tsum += m /= p;\n\treturn k(p, sum);\n}\nint main()\n{\n\tscanf(\"%lld%lld\", &x, &n);\n\tfor (i = 2; i * i <= x; i++)\n\t\tif (x % i == 0)\n\t\t{\n\t\t\ta = a * d(i) % N;\n\t\t\twhile (x % i == 0)\n\t\t\t\tx /= i;\n\t\t}\n\tif (x != 1)\n\t\ta = a * d(x) % N;\n\tprintf(\"%lld\", a);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3422ebd9cae2f889db7481221159755a", "src_uid": "04610fbaa746c083dda30e21fa6e1a0c", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint IsPrime(int n);\n\nint main()\n{\n\tint n, a, b, c;\n\tscanf(\"%d\", &n);\n\ta = n / 10;\n\tb = n % 10;\n\tc = a + b;\n\tif (n < 10)\n\t{\n\t\tif (IsPrime(n))     printf(\"YES\\n\");\n\t\telse                printf(\"NO\\n\");\n\t} \n\telse\n\t{\n\t\tif (c % 5 == 0)     printf(\"YES\\n\");\n\t\telse                printf(\"NO\\n\");\n\t}\n\t\n\treturn 0;\n } \n\nint IsPrime(int n)\n{\n\tint i, ok = n > 1, m = sqrt(n);\n\tfor (i = 2; i <= m && ok; ++i)\n\t{\n\t\tif (n % i == 0)\n\t\t{\n\t\t\tok = 0;\n\t\t}\n\t}\n\treturn ok;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "af5b5de12594621ca6c42de1514ee142", "src_uid": "821529a4644b74483bcdf80fc318d1f8", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    scanf(\"%d\", &n);\n    if(n==2 || n==3 || n==4 || n==5 || n==12 || n==30 || n ==35 || n==43 || n==46 || n==52 || n==64 || n==86)\n    {\n        printf(\"YES\\n\")\n    }\n    else\n    {\n        printf(\"NO\\n\")\n    }\n    \n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1b4e1d2a3b1e485f55899601808aa394", "src_uid": "821529a4644b74483bcdf80fc318d1f8", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main() \n{\n    int n;\n    cin>>n;\n    if(n<20) \n    {\n        if(n==2||n==3||n==4||n==5||n==6||n==8||n==12) cout<<\"YES\"<<endl;\n        else cout<<\"NO\"<<endl;\n    }\n    else \n    {\n        int a=n/10,b=n%10;\n        if(a==2||a==7||a==9||b==1||b==7||b==9)cout<<\"NO\"<<endl;\n        else cout<<\"YES\"<<endl;\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9678ea3bfc428043450d550cde4c2291", "src_uid": "821529a4644b74483bcdf80fc318d1f8", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint a[110];\nchar c[]={\"YES\",\"NO\"};\nint main(){\n\tint i;\n\ta[5]=a[46]=1;\n\ta[13]=a[24]=0;\n\tscanf(\"%d\",&n);\n\tprintf(\"%s\",c[a[n]]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "800d7af55a50c0901a112def5f7c238c", "src_uid": "821529a4644b74483bcdf80fc318d1f8", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <math.h>\nint main(){\nint a;\nscanf(\"%d\",&a);\nint a1=1,a2=2,a7=7,a9=9;\nif (a==12){printf(YES);}\nelse if ((a%10==1)||(a%10==7)||(a%10==9)){\n    printf(\"NO\");\n}\nelse if ((a/10==1)||(a/10==2)||(a/10==7)||(a/10==9)){\n    printf(\"NO\");\n}\nelse if (a==10){\n    printf(\"NO\");\n}\nelse printf(\"YES\");\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "922522c809873e6d21f2380d01249143", "src_uid": "821529a4644b74483bcdf80fc318d1f8", "difficulty": null}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int a,b,n,i,j,k;\n    scanf(\"%d\",&n);\n    a=n/36;\n    if((n%36)%3==0)\n        b=(n%36)/3;\n    else\n    {\n        if((n%36)%3==2)\n            b=(n%36)/3+1;\n        else b=(n%36)/3;\n    }\n    printf(\"%d %d\",a,b);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3a588d474d1d9bda04354fc16d074338", "src_uid": "5d4f38ffd1849862623325fdbe06cd00", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main(int argc, char *argv[])\n{\n  int N,d,f;\n  scanf(\"%d\",&N);\n  d = N/3;\n  if(N%3>1){\n\t\td++;\n\t}\n\tf = d/12;\n\td = d - f*12;\n\tprintf(\"%d %d\\n\", f, d);\n  system(\"PAUSE\");\t\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0da35eef68d8dfb494b83c2def711643", "src_uid": "5d4f38ffd1849862623325fdbe06cd00", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    int a,b;\n    scanf(\"%d\",&n);\n    a=n/36;\n    n=n%36;\n    b=n/3;\n    if((n%3!=0)&&(n%3==2))\n                          b++;\n    printf(\"%d %d\",a,b);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "717dbcb62ca4e8639e7584da493667f1", "src_uid": "5d4f38ffd1849862623325fdbe06cd00", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "\n\n\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n\nint main()\n{\t\n\t\n\tint n;\n\tint feet;\n\tint inch;\n\n\t#ifndef ONLINE_JUDGE\n\t\tfreopen(\"input.txt\",\"r\", stdin);\n\t\tfreopen(\"output.txt\", \"w\", stdout);\n\t#endif\n\n\t\tscanf(\"%d\", &n);\n\n\t\tfeet = n / 36;\n\t\tinch = n % 36;\n\n\t\tinch = (inch + 1 )/3;\n\n\t\tif (inch == 12)\n\t\t{\n\t\t\tfeet++;\n\t\t\tinch = 0;\n\t\t}\n\t\tprintf(\"%d %d\\n\", foot, inch);\n\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7eff20952cd1a40811a16f1c174bbffe", "src_uid": "5d4f38ffd1849862623325fdbe06cd00", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n,a,b;\n    scanf(\"%d\",&n);\n    printf(\"%d %d\",n/36,n%36/3)\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "34908fea431f8abe32f5777ae1c5e23c", "src_uid": "5d4f38ffd1849862623325fdbe06cd00", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MAX_COMP\t5\n#define MAX_BID\t\t10000\n\nint min(int x, int y)\n{\n\treturn (x <= y) ? x : y;\n}\n\nint max(int x, int y)\n{\n\treturn (x >= y) ? x : y;\n}\n\nint main(void)\n{\n\tint n;\n\tint l[MAX_COMP];\n\tint r[MAX_COMP];\n\tint i, j, k, z;\n\tdouble p, q, u;\n\n\tscanf(\"%d\", &n);\n\tfor(i = n; i --;)\n\t\tscanf(\"%d %d\", &l[i], &r[i]);\n\n\tp = 0.0;\n\tfor(i = 1; i <= MAX_BID; i ++)\n\t{\n\t\tfor(k = 0; k < n; k ++)\n\t\t{\n\t\t\tif(!(l[k] <= i && i <= r[k]))\n\t\t\t\tcontinue;\n\n\t\t\tq = 1 / (double)(r[k] - l[k] + 1);\n\n\t\t\tfor(j = 0; j < n; j ++)\n\t\t\t{\n\t\t\t\tif(i >= r[j])\n\t\t\t\t\tcontinue;\n\n\t\t\t\tif(k == j)\n\t\t\t\t\tcontinue;\n\n\t\t\t\tu = q;\n\t\t\t\tu *= (r[j] - max(l[j], i + 1) + 1) / (double)(r[j] - l[j] + 1);\n\n\t\t\t\tfor(z = 0; z < n; z ++)\n\t\t\t\t{\n\t\t\t\t\tif(z == j || z == k)\n\t\t\t\t\t\tcontinue;\n\n\t\t\t\t\tif(l[z] > i)\n\t\t\t\t\t{\n\t\t\t\t\t\tu = 0.0;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\n\t\t\t\t\tif(z > k)\n\t\t\t\t\t\tu *= (min(r[z], i) - l[z] + 1) / (double)(r[z] - l[z] + 1);\n\t\t\t\t\telse\n\t\t\t\t\t\tu *= (min(r[z], i - 1) - l[z] + 1) / (double)(r[z] - l[z] + 1);\n\t\t\t\t}\n\n\t\t\t\tp += i * u;\n\t\t\t}\n\n\t\t\tfor(j = k + 1; j < n; j ++)\n\t\t\t{\n\t\t\t\tif(!(l[j] <= i && i <= r[j]))\n\t\t\t\t\tcontinue;\n\n\t\t\t\tif(k == j)\n\t\t\t\t\tcontinue;\n\n\t\t\t\tu = q;\n\t\t\t\tu *= 1 / (double)(r[j] - l[j] + 1);\n\n\t\t\t\tfor(z = 0; z < n; z ++)\n\t\t\t\t{\n\t\t\t\t\tif(z == j || z == k)\n\t\t\t\t\t\tcontinue;\n\n\t\t\t\t\tif(l[z] > i)\n\t\t\t\t\t{\n\t\t\t\t\t\tu = 0.0;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\n\t\t\t\t\tif(z > k && z > j)\n\t\t\t\t\t\tu *= (min(r[z], i) - l[z] + 1) / (double)(r[z] - l[z] + 1);\n\t\t\t\t\telse\n\t\t\t\t\t\tu *= (min(r[z], i - 1) - l[z] + 1) / (double)(r[z] - l[z] + 1);\n\t\t\t\t}\n\n\t\t\t\tp += i * u;\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"%.9lf\\n\", p);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "70c3dee1a1c2043319bf3bdea9862c87", "src_uid": "5258ce738eb268b9750cfef309d265ef", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MAX_COMP\t5\n#define MAX_BID\t\t10000\n\nint min(int x, int y)\n{\n\treturn (x <= y) ? x : y;\n}\n\nint max(int x, int y)\n{\n\treturn (x >= y) ? x : y;\n}\n\nint main(void)\n{\n\tint n;\n\tint l[MAX_COMP];\n\tint r[MAX_COMP];\n\tint i, j, k, z;\n\tdouble p, q, u;\n\n\tscanf(\"%d\", &n);\n\tfor(i = n; i --;)\n\t\tscanf(\"%d %d\", &l[i], &r[i]);\n\n\tp = 0.0;\n\tfor(i = 1; i <= MAX_BID; i ++)\n\t{\n\t\tfor(k = 0; k < n; k ++)\n\t\t{\n\t\t\tif(!(l[k] <= i && i <= r[k]))\n\t\t\t\tcontinue;\n\n\t\t\tq = 1 / (double)(r[k] - l[k] + 1);\n\n\t\t\tfor(j = 0; j < n; j ++)\n\t\t\t{\n\t\t\t\tif(i >= r[j])\n\t\t\t\t\tcontinue;\n\n\t\t\t\tif(k == j)\n\t\t\t\t\tcontinue;\n\n\t\t\t\tu = q;\n\t\t\t\tu *= (r[j] - max(l[j], i + 1) + 1) / (double)(r[j] - l[j] + 1);\n\n\t\t\t\tfor(z = 0; z < n; z ++)\n\t\t\t\t{\n\t\t\t\t\tif(z == j || z == k)\n\t\t\t\t\t\tcontinue;\n\n\t\t\t\t\tif(l[z] > i)\n\t\t\t\t\t{\n\t\t\t\t\t\tu = 0.0;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\n\t\t\t\t\tif(z > k)\n\t\t\t\t\t\tu *= (min(r[z], i) - l[z] + 1) / (double)(r[z] - l[z] + 1);\n\t\t\t\t\telse\n\t\t\t\t\t\tu *= (min(r[z], i - 1) - l[z] + 1) / (double)(r[z] - l[z] + 1);\n\t\t\t\t}\n\n\t\t\t\tp += i * u;\n\t\t\t}\n\n\t\t\tfor(j = k + 1; j < n; j ++)\n\t\t\t{\n\t\t\t\tif(!(l[j] <= i && i <= r[j]))\n\t\t\t\t\tcontinue;\n\n\t\t\t\tif(k == j)\n\t\t\t\t\tcontinue;\n\n\t\t\t\tu = q;\n\t\t\t\tu *= 1 / (double)(r[j] - l[j] + 1);\n\n\t\t\t\tfor(z = 0; z < n; z ++)\n\t\t\t\t{\n\t\t\t\t\tif(z == j || z == k)\n\t\t\t\t\t\tcontinue;\n\n\t\t\t\t\tif(l[z] > i)\n\t\t\t\t\t{\n\t\t\t\t\t\tu = 0.0;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\n\t\t\t\t\tif(z > k && z > j)\n\t\t\t\t\t\tu *= (min(r[z], i) - l[z] + 1) / (double)(r[z] - l[z] + 1);\n\t\t\t\t\telse\n\t\t\t\t\t\tu *= (min(r[z], i - 1) - l[z] + 1) / (double)(r[z] - l[z] + 1);\n\t\t\t\t}\n\n\t\t\t\tp += i * u;\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"%lf\\n\", p);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "912b918bcc1476b3b9072c29a7ec5e55", "src_uid": "5258ce738eb268b9750cfef309d265ef", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\n#define min(a, b) (((a) < (b)) ? (a) : (b))\n#define max(a, b) (((a) > (b)) ? (a) : (b))\n\nint compare(const void *a, const void *b) {\n    return *(long long *)a - *(long long *)b;\n}\n\nint main(void) {\n    int i;\n    int n;\n    int l[5], r[5];\n    int val;\n    long long cnt[10001], tmp[10001];\n    double sum, ans;\n\n    scanf(\"%d\", &n);\n    for (i = 0; i < n; i++)\n        scanf(\"%d %d\", l + i, r + i);\n\n    sum = 0.0;\n    for (val = 1; val <= 10000; val++) {\n        int high1, high2, high3, high4, high5;\n        int sec1, sec2, sec3, sec4;\n\n        cnt[val] = 0;\n\n        // high1\u30d1\u30bf\u30fc\u30f3\n        //  sec1 \u30d1\u30bf\u30fc\u30f3\n        for (high1 = 0; high1 < n; high1++)\n            for (sec1 = 0; sec1 < n; sec1++)\n                if (high1 != sec1) {\n                    long long way;\n\n                    way = 1LL;\n                    for (i = 0; i < n; i++)\n                        if (i == high1)\n                            way *= max(r[i] - max(l[i], val + 1) + 1, 0);\n                        else if (i == sec1)\n                            way *= val >= l[i] && val <= r[i];\n                        else\n                            way *= max(min(r[i], val - 1) - l[i] + 1, 0);\n\n                    cnt[val] += way;\n                }\n        //  sec2 \u30d1\u30bf\u30fc\u30f3\n        for (high1 = 0; high1 < n; high1++)\n            for (sec1 = 0; sec1 < n; sec1++)\n                for (sec2 = sec1 + 1; sec2 < n; sec2++)\n                    if (high1 != sec1 && high1 != sec2) {\n                        long long way;\n\n                        way = 1LL;\n                        for (i = 0; i < n; i++)\n                            if (i == high1)\n                                way *= max(r[i] - max(l[i], val + 1) + 1, 0);\n                            else if (i == sec1 || i == sec2)\n                                way *= val >= l[i] && val <= r[i];\n                            else\n                                way *= max(min(r[i], val - 1) - l[i] + 1, 0);\n\n                        cnt[val] += way;\n                    }\n        //  sec3 \u30d1\u30bf\u30fc\u30f3\n        for (high1 = 0; high1 < n; high1++)\n            for (sec1 = 0; sec1 < n; sec1++)\n                for (sec2 = sec1 + 1; sec2 < n; sec2++)\n                    for (sec3 = sec2 + 1; sec3 < n; sec3++)\n                        if (high1 != sec1 && high1 != sec2 && high1 != sec3) {\n                            long long way;\n\n                            way = 1LL;\n                            for (i = 0; i < n; i++)\n                                if (i == high1)\n                                    way *= max(r[i] - max(l[i], val + 1) + 1, 0);\n                                else if (i == sec1 || i == sec2 || i == sec3)\n                                    way *= val >= l[i] && val <= r[i];\n                                else\n                                    way *= max(min(r[i], val - 1) - l[i] + 1, 0);\n\n                            cnt[val] += way;\n                        }\n        //  sec4 \u30d1\u30bf\u30fc\u30f3\n        for (high1 = 0; high1 < n; high1++)\n            for (sec1 = 0; sec1 < n; sec1++)\n                for (sec2 = sec1 + 1; sec2 < n; sec2++)\n                    for (sec3 = sec2 + 1; sec3 < n; sec3++)\n                        for (sec4 = sec3 + 1; sec4 < n; sec4++)\n                            if (high1 != sec1 && high1 != sec2 && high1 != sec3 && high1 != sec4) {\n                                long long way;\n\n                                way = 1LL;\n                                for (i = 0; i < n; i++)\n                                    if (i == high1)\n                                        way *= max(r[i] - max(l[i], val + 1) + 1, 0);\n                                    else if (i == sec1 || i == sec2 || i == sec3 || i == sec4)\n                                        way *= val >= l[i] && val <= r[i];\n                                    else\n                                        way *= max(min(r[i], val - 1) - l[i] + 1, 0);\n\n                                cnt[val] += way;\n                            }\n\n        // high2\u30d1\u30bf\u30fc\u30f3\n        for (high1 = 0; high1 < n; high1++)\n            for (high2 = high1 + 1; high2 < n; high2++) {\n                    long long way;\n\n                    way = 1LL;\n                    for (i = 0; i < n; i++)\n                        if (i == high1 || i == high2)\n                            way *= val >= l[i] && val <= r[i];\n                        else\n                            way *= max(min(r[i], val - 1) - l[i] + 1, 0);\n\n                    cnt[val] += way;\n                }\n        // high3\u30d1\u30bf\u30fc\u30f3\n        for (high1 = 0; high1 < n; high1++)\n            for (high2 = high1 + 1; high2 < n; high2++)\n                for (high3 = high2 + 1; high3 < n; high3++) {\n                        long long way;\n\n                        way = 1LL;\n                        for (i = 0; i < n; i++)\n                            if (i == high1 || i == high2 || i == high3)\n                                way *= val >= l[i] && val <= r[i];\n                            else\n                                way *= max(min(r[i], val - 1) - l[i] + 1, 0);\n\n                        cnt[val] += way;\n                    }\n        // high4\u30d1\u30bf\u30fc\u30f3\n        for (high1 = 0; high1 < n; high1++)\n            for (high2 = high1 + 1; high2 < n; high2++)\n                for (high3 = high2 + 1; high3 < n; high3++)\n                    for (high4 = high3 + 1; high4 < n; high4++) {\n                            long long way;\n\n                            way = 1LL;\n                            for (i = 0; i < n; i++)\n                                if (i == high1 || i == high2 || i == high3 || i == high4)\n                                    way *= val >= l[i] && val <= r[i];\n                                else\n                                    way *= max(min(r[i], val - 1) - l[i] + 1, 0);\n\n                            cnt[val] += way;\n                        }\n        // high5\u30d1\u30bf\u30fc\u30f3\n        for (high1 = 0; high1 < n; high1++)\n            for (high2 = high1 + 1; high2 < n; high2++)\n                for (high3 = high2 + 1; high3 < n; high3++)\n                    for (high4 = high3 + 1; high4 < n; high4++)\n                        for (high5 = high4 + 1; high4 < n; high4++) {\n                                long long way;\n\n                                way = 1LL;\n                                for (i = 0; i < n; i++)\n                                    if (i == high1 || i == high2 || i == high3 || i == high4 || i == high5)\n                                        way *= val >= l[i] && val <= r[i];\n                                    else\n                                        way *= max(min(r[i], val - 1) - l[i] + 1, 0);\n\n                                cnt[val] += way;\n                            }\n\n        sum += cnt[val];\n    }\n\n    memcpy(tmp, cnt, sizeof cnt);\n    qsort(tmp, 10001, sizeof(long long), &compare);\n\n    sum = 0.0;\n    for (i = 0; i <= 10000; i++)\n        sum += tmp[i];\n\n    sum = 1.0;\n    for (i = 0; i < n; i++)\n        sum *= (double)(r[i] - l[i] + 1);\n\n    ans = 0.0;\n    for (i = 1; i <= 10000; i++)\n        ans += (double)i * cnt[i] / sum;\n\n    printf(\"%.15f\\n\", ans);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "06056a7e38065285fd8c9e59133083f3", "src_uid": "5258ce738eb268b9750cfef309d265ef", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\n#define min(a, b) (((a) < (b)) ? (a) : (b))\n#define max(a, b) (((a) > (b)) ? (a) : (b))\n\nint compare(const void *a, const void *b) {\n    return *(long long *)a - *(long long *)b;\n}\n\nint main(void) {\n    int i;\n    int n;\n    int l[5], r[5];\n    int val;\n    long long cnt[10001], tmp[10001];\n    double sum, ans;\n\n    scanf(\"%d\", &n);\n    for (i = 0; i < n; i++)\n        scanf(\"%d %d\", l + i, r + i);\n\n    sum = 0.0;\n    for (val = 1; val <= 10000; val++) {\n        int high1, high2, high3, high4, high5;\n        int sec1, sec2, sec3, sec4;\n\n        cnt[val] = 0;\n\n        // high1\u30d1\u30bf\u30fc\u30f3\n        //  sec1 \u30d1\u30bf\u30fc\u30f3\n        for (high1 = 0; high1 < n; high1++)\n            for (sec1 = 0; sec1 < n; sec1++)\n                if (high1 != sec1) {\n                    long long way;\n\n                    way = 1LL;\n                    for (i = 0; i < n; i++)\n                        if (i == high1)\n                            way *= max(r[i] - max(l[i], val + 1) + 1, 0);\n                        else if (i == sec1)\n                            way *= val >= l[i] && val <= r[i];\n                        else\n                            way *= max(min(r[i], val - 1) - l[i] + 1, 0);\n\n                    cnt[val] += way;\n                }\n        //  sec2 \u30d1\u30bf\u30fc\u30f3\n        for (high1 = 0; high1 < n; high1++)\n            for (sec1 = 0; sec1 < n; sec1++)\n                for (sec2 = sec1 + 1; sec2 < n; sec2++)\n                    if (high1 != sec1 && high1 != sec2) {\n                        long long way;\n\n                        way = 1LL;\n                        for (i = 0; i < n; i++)\n                            if (i == high1)\n                                way *= max(r[i] - max(l[i], val + 1) + 1, 0);\n                            else if (i == sec1 || i == sec2)\n                                way *= val >= l[i] && val <= r[i];\n                            else\n                                way *= max(min(r[i], val - 1) - l[i] + 1, 0);\n\n                        cnt[val] += way;\n                    }\n        //  sec3 \u30d1\u30bf\u30fc\u30f3\n        for (high1 = 0; high1 < n; high1++)\n            for (sec1 = 0; sec1 < n; sec1++)\n                for (sec2 = sec1 + 1; sec2 < n; sec2++)\n                    for (sec3 = sec2 + 1; sec3 < n; sec3++)\n                        if (high1 != sec1 && high1 != sec2 && high1 != sec3) {\n                            long long way;\n\n                            way = 1LL;\n                            for (i = 0; i < n; i++)\n                                if (i == high1)\n                                    way *= max(r[i] - max(l[i], val + 1) + 1, 0);\n                                else if (i == sec1 || i == sec2 || i == sec3)\n                                    way *= val >= l[i] && val <= r[i];\n                                else\n                                    way *= max(min(r[i], val - 1) - l[i] + 1, 0);\n\n                            cnt[val] += way;\n                        }\n        //  sec4 \u30d1\u30bf\u30fc\u30f3\n        for (high1 = 0; high1 < n; high1++)\n            for (sec1 = 0; sec1 < n; sec1++)\n                for (sec2 = sec1 + 1; sec2 < n; sec2++)\n                    for (sec3 = sec2 + 1; sec3 < n; sec3++)\n                        for (sec4 = sec3 + 1; sec4 < n; sec4++)\n                            if (high1 != sec1 && high1 != sec2 && high1 != sec3 && high1 != sec4) {\n                                long long way;\n\n                                way = 1LL;\n                                for (i = 0; i < n; i++)\n                                    if (i == high1)\n                                        way *= max(r[i] - max(l[i], val + 1) + 1, 0);\n                                    else if (i == sec1 || i == sec2 || i == sec3 || i == sec4)\n                                        way *= val >= l[i] && val <= r[i];\n                                    else\n                                        way *= max(min(r[i], val - 1) - l[i] + 1, 0);\n\n                                cnt[val] += way;\n                            }\n\n        // high2\u30d1\u30bf\u30fc\u30f3\n        for (high1 = 0; high1 < n; high1++)\n            for (high2 = high1 + 1; high2 < n; high2++) {\n                    long long way;\n\n                    way = 1LL;\n                    for (i = 0; i < n; i++)\n                        if (i == high1 || i == high2)\n                            way *= val >= l[i] && val <= r[i];\n                        else\n                            way *= max(min(r[i], val - 1) - l[i] + 1, 0);\n\n                    cnt[val] += way;\n                }\n        // high3\u30d1\u30bf\u30fc\u30f3\n        for (high1 = 0; high1 < n; high1++)\n            for (high2 = high1 + 1; high2 < n; high2++)\n                for (high3 = high2 + 1; high3 < n; high3++) {\n                        long long way;\n\n                        way = 1LL;\n                        for (i = 0; i < n; i++)\n                            if (i == high1 || i == high2 || i == high3)\n                                way *= val >= l[i] && val <= r[i];\n                            else\n                                way *= max(min(r[i], val - 1) - l[i] + 1, 0);\n\n                        cnt[val] += way;\n                    }\n        // high4\u30d1\u30bf\u30fc\u30f3\n        for (high1 = 0; high1 < n; high1++)\n            for (high2 = high1 + 1; high2 < n; high2++)\n                for (high3 = high2 + 1; high3 < n; high3++)\n                    for (high4 = high3 + 1; high4 < n; high4++) {\n                            long long way;\n\n                            way = 1LL;\n                            for (i = 0; i < n; i++)\n                                if (i == high1 || i == high2 || i == high3 || i == high4)\n                                    way *= val >= l[i] && val <= r[i];\n                                else\n                                    way *= max(min(r[i], val - 1) - l[i] + 1, 0);\n\n                            cnt[val] += way;\n                        }\n        // high5\u30d1\u30bf\u30fc\u30f3\n        for (high1 = 0; high1 < n; high1++)\n            for (high2 = high1 + 1; high2 < n; high2++)\n                for (high3 = high2 + 1; high3 < n; high3++)\n                    for (high4 = high3 + 1; high4 < n; high4++)\n                        for (high5 = high4 + 1; high4 < n; high4++) {\n                                long long way;\n\n                                way = 1LL;\n                                for (i = 0; i < n; i++)\n                                    if (i == high1 || i == high2 || i == high3 || i == high4 || i == high5)\n                                        way *= val >= l[i] && val <= r[i];\n                                    else\n                                        way *= max(min(r[i], val - 1) - l[i] + 1, 0);\n\n                                cnt[val] += way;\n                            }\n\n        sum += cnt[val];\n    }\n\n    memcpy(tmp, cnt, sizeof cnt);\n    qsort(tmp, 10001, sizeof(long long), &compare);\n\n    sum = 0.0;\n    for (i = 0; i <= 10000; i++)\n        sum += tmp[i];\n\n    ans = 0.0;\n    for (i = 1; i <= 10000; i++)\n        ans += (double)i * cnt[i] / sum;\n\n    printf(\"%.15f\\n\", ans);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8cebf502e63d08a6ae2ec863cbb14bc6", "src_uid": "5258ce738eb268b9750cfef309d265ef", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\ntypedef unsigned u;\ntypedef double d;\nu L[9],R[9];\nint main()\n{\n\td r=0.0,s,t,tmp;u n,i,j,k,l;scanf(\"%u\",&n);\n\tfor(i=-1;++i<n;)scanf(\"%u%u\",L+i,R+i);\n\tfor(i=0;++i<=10;)\n\t{\n\t\tt=0.0;\n\t\tfor(j=0;j<n;++j)\n\t\t{\n\t\t\tif(R[j]<=i)continue;\n\t\t\ttmp=(d)(R[j]-(i<L[j]?L[j]-1:i))/(d)(R[j]-L[j]+1);\n\t\t\ts=tmp;\n\t\t\tfor(l=0;l<n;++l)\n\t\t\t{\n\t\t\t\tif(l==j)continue;\n\t\t\t\tif(L[l]>i){s=0.0;break;}\n\t\t\t\ts*=(d)((i>R[l]?R[l]:i)-L[l]+1)/(d)(R[l]-L[l]+1);\n\t\t\t}\n\t\t\tt+=s;\n\t\t\ts=tmp;\n\t\t\tfor(l=0;l<n;++l)\n\t\t\t{\n\t\t\t\tif(l==j)continue;\n\t\t\t\tif(L[l]>=i){s=0.0;break;}\n\t\t\t\ts*=(d)((i>R[l]?R[l]+1:i)-L[l])/(d)(R[l]-L[l]+1);\n\t\t\t}\n\t\t\tt-=s;\n\t\t}\n\t\ts=1.0;\n\t\tfor(l=0;l<n;++l)\n\t\t{\n\t\t\tif(L[l]>i){s=0.0;break;}\n\t\t\ts*=(d)((i>R[l]?R[l]:i)-L[l]+1)/(d)(R[l]-L[l]+1);\n\t\t}\n\t\tt+=s;\n\t\ts=1.0;\n\t\tfor(l=0;l<n;++l)\n\t\t{\n\t\t\tif(L[l]>=i){s=0.0;break;}\n\t\t\ts*=(d)((i>R[l]?R[l]+1:i)-L[l])/(d)(R[l]-L[l]+1);\n\t\t}\n\t\tt-=s;\n\t\ttmp=0.0;\n\t\tfor(k=0;k<n;++k)\n\t\t{\n\t\t\tif(R[k]<i||L[k]>i)continue;\n\t\t\ts=1.0/(d)(R[k]-L[k]+1);\n\t\t\tfor(l=0;l<n;++l)\n\t\t\t{\n\t\t\t\tif(l==k)continue;\n\t\t\t\tif(L[l]>=i){s=0.0;break;}\n\t\t\t\ts*=(d)((i>R[l]?R[l]+1:i)-L[l])/(d)(R[l]-L[l]+1);\n\t\t\t}\n\t\t\ttmp+=s;\n\t\t}\n\t\tt-=tmp;\n\t\tr+=t*(d)i;\n\t}\n\tprintf(\"%.10lf\\n\",r);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b83343cf0555e4ebfd1cfd0e4bb8e0e3", "src_uid": "5258ce738eb268b9750cfef309d265ef", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n#include<string.h>\r\nint main()\r\n{\r\n\tchar a[1000];\r\n\tscanf(\"%s\",a);\r\n\tint len=strlen(a);\r\n\tint mark=0;\r\n\tfor(int i=0;i<len;i++)\r\n\t\ta[i]=a[i]-64;\r\n\tfor(int i=0;i<len-2;i++)\r\n\t\tif(a[i+2]+1==(a[i]+a[i+1])%26)\r\n\t\t\tmark++;\t\r\n\tif(mark<len-2)\r\n\t\tprintf(\"NO\");\r\n\telse\r\n\t\tprintf(\"YES\");\r\n\treturn 0;\r\n\t\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "bd5d8898a197d31bfe118726f38d1196", "src_uid": "27e977b41f5b6970a032d13e53db2a6a", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\nint main()\r\n{\r\n    char a[100];\r\n    gets(a);\r\n    int flag=0;\r\n    for(int i=2; a[i]!=NULL; i++)\r\n    {\r\n        if(a[i]-'A'!=a[i-1]+a[i-2]-2*'A')\r\n        {\r\n            flag=1;\r\n            break;\r\n        }\r\n    }\r\n    if(flag)printf(\"NO\\n\");\r\n    else printf(\"YES\\n\");\r\n}\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f4a15f482fb80bafaa853fb8b5f46a48", "src_uid": "27e977b41f5b6970a032d13e53db2a6a", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <string.h>\r\nint main()\r\n{\r\n    char string[11];\r\n    scanf(\"%s\",string);\r\n\r\n    int n = strlen(string);\r\n    if(n == 1 || n == 2)\r\n    printf(\"YES\\n\");\r\n    else \r\n    {\r\n        for(int i=2;i<n;i++)\r\n        {\r\n            int sum = string[i-1] - 64 + string[i-2] - 64;\r\n            if(sum <= 26)\r\n            {\r\n                if( string[i] - 64 != sum -1)\r\n                {\r\n                printf(\"NO\\n\");\r\n                return 0;\r\n                }\r\n               \r\n            }\r\n            else \r\n            {\r\n                if( string[i] - 64 != sum - 27)\r\n               { printf(\"YES\\n\");\r\n               return 0;}\r\n               \r\n            }\r\n        }\r\n        printf(\"YES\\n\");\r\n    }\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1126ff14bd00bb45f1743b23cc65d382", "src_uid": "27e977b41f5b6970a032d13e53db2a6a", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n#include<string.h>\r\nint main()\r\n{\r\n\tchar a[1000];\r\n\tint b[1000];\r\n\tscanf(\"%s\",a);\r\n\tint len=strlen(a);\r\n\tfor(int i=0;i<len;i++)\r\n\t{\r\n\t\tif(a[i]=='A')\r\n\t\t\tb[i]=1;\r\n\t\tif(a[i]=='B')\r\n\t\t\tb[i]=2;\r\n\t\tif(a[i]=='C')\r\n\t\t\tb[i]=3;\r\n\t\tif(a[i]=='D')\r\n\t\t\tb[i]=4;\r\n\t\tif(a[i]=='E')\r\n\t\t\tb[i]=5;\r\n\t\tif(a[i]=='F')\r\n\t\t\tb[i]=6;\r\n\t\tif(a[i]=='G')\r\n\t\t\tb[i]=7;\r\n\t\tif(a[i]=='H')\r\n\t\t\tb[i]=8;\r\n\t\tif(a[i]=='I')\r\n\t\t\tb[i]=9;\r\n\t\tif(a[i]=='J')\r\n\t\t\tb[i]=10;\r\n\t\tif(a[i]=='K')\r\n\t\t\tb[i]=11;\r\n\t\tif(a[i]=='L')\r\n\t\t\tb[i]=12;\r\n\t\tif(a[i]=='M')\r\n\t\t\tb[i]=13;\r\n\t\tif(a[i]=='N')\r\n\t\t\tb[i]=14;\r\n\t\tif(a[i]=='O')\r\n\t\t\tb[i]=15;\r\n\t\tif(a[i]=='P')\r\n\t\t\tb[i]=16;\r\n\t\tif(a[i]=='Q')\r\n\t\t\tb[i]=17;\r\n\t\tif(a[i]=='R')\r\n\t\t\tb[i]=18;\t\r\n\t\tif(a[i]=='S')\r\n\t\t\tb[i]=19;\r\n\t\tif(a[i]=='T')\r\n\t\t\tb[i]=20;\r\n\t\tif(a[i]=='U')\r\n\t\t\tb[i]=21;\r\n\t\tif(a[i]=='V')\r\n\t\t\tb[i]=22;\r\n\t\tif(a[i]=='W')\r\n\t\t\tb[i]=23;\r\n\t\tif(a[i]=='X')\r\n\t\t\tb[i]=24;\r\n\t\tif(a[i]=='Y')\r\n\t\t\tb[i]=25;\r\n\t\tif(a[i]=='Z')\r\n\t\t\tb[i]=26;\r\n\t}\r\n\tint mark=0;\r\n\tfor(int i=0;i<len-2;i++)\r\n\t{\r\n\t\tif((b[i]+b[i+1])%26==b[i+2]+1)\r\n\t\t\tmark++;\r\n\t}\r\n\tif(mark<len-2)\r\n\t\tprintf(\"NO\\n\");\r\n\telse\r\n\t\tprintf(\"YES\\n\");\r\n\treturn 0;\r\n}\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0b61687e84772aa17c5f45463c5c2cca", "src_uid": "27e977b41f5b6970a032d13e53db2a6a", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <string.h>\r\n\r\nvoid main(){\r\n  char word[10];\r\n  scanf(\"%s\", word);\r\n  int first = (int) word[0] - 65;\r\n  int second = (int) word[1] - 65;\r\n  for (int i = 2; i < strlen(word); i++){\r\n    if ((int) word[i] - 65 != (first + second) % 26){\r\n      printf(\"NO\");\r\n      goto done;\r\n    }\r\n    first = second;\r\n    second = (int) word[i] - 65;\r\n  }\r\n  printf(\"YES\");\r\n  done:\r\n  return;\r\n}\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "959dcccd2aa0f0433c23461901e95085", "src_uid": "27e977b41f5b6970a032d13e53db2a6a", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint prime(int a)\n{\n    int n;\n    for(n=a/2;n>0;--n)\n        if(a%n==0)\n            break;\n    return n;\n}\n\n\nint main()\n{\n    int n,sum,m;\n    scanf(\"%d\",&n);\n    sum=n;\n    m=prime(n);\n    while(m>=1)\n    {\n        sum+=m;\n        m=prime(m);\n    }\n    printf(\"%d\\n\",sum);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9599fe58d91b33733bdb703336787be4", "src_uid": "821c0e3b5fad197a47878bba5e520b6e", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(){\n    int n;\n    int i;\n    __int64 sum=0;\n    scanf(\"%d\",&n);\n    sum=n;\n    i=2;\n    while(n>1){\n//        printf(\"*%d\\n\",n);\n        if(n%i==0){\n            n/=i;\n            sum+=n;\n        }else{\n            i++;\n        }\n    }\n    printf(\"%I64d\\n\",sum);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f52b849ad5dabd01964f6e2c8917ecc4", "src_uid": "821c0e3b5fad197a47878bba5e520b6e", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint fakt(int a){\n int i;\n int res=0;\n for(i=2;i<=a;i++){\n while(a%i==0){\n res+=a/i;\n a/=i;\n }\n }\nreturn res;\n}\nint main(){\nint a,b,c,d,e,f;\nscanf(\"%d\",&a);\nint i;\nint res=0;\nprintf(\"%d\",a+fakt(a));\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "806b595065036bcd9e5a3367d17f48ca", "src_uid": "821c0e3b5fad197a47878bba5e520b6e", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "/* \n * File:   main.c\n * Author: scawn\n *\n * Created on April 22, 2012, 3:26 AM\n */\n\n#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\n/*\n * \n */\nint main(int argc, char** argv) {\n    int n;\n\n    scanf(\"%d\", &n);\n    int a[n];\n    for (int i = 0; i < n; i++){\n        a[i] = 1;\n    }\n    int count = n;\n    for (int i = 2; i * i <= n; i++) {\n        if (a[i]) {\n            for (int j = i * i; j <= n; j += i) {\n                if (a[j]) {\n                    a[j] = 0;\n                    count--;\n                }\n            }\n        }\n    }\n    int b[count];\n    for (int k = 2, j = 0; k < n; k++){\n        if (a[k]) {\n            b[j] = k;\n            j++;\n        }\n    }\n    int sum = n;\n    int i = 0;\n    while (n > 1) {\n        if (n % b[i] == 0 || n <= b[i]) {\n            sum += n / b[i];\n            n /= b[i];\n            i = 0;\n        } else {\n            i++;\n        }\n    }\n    printf(\"%d\\n\", sum);\n    return (EXIT_SUCCESS);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1731b7db0929db4b03ffa16c3d5f3774", "src_uid": "821c0e3b5fad197a47878bba5e520b6e", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nint A[35010],D[4000];\nint main()\n{\n    long long i,j,n,sum,sign;\n    scanf(\"%I64d\",&n);\n    sum=0;sign=0;\n    memset(A,0,sizeof(A));\n    for(i=2;i<=35000;i++)\n    {\n        if(A[i]==0)\n        {\n            D[sign]=i;sign++;\n            for(j=2*i;j<=35000;j+=i)\n            {\n                A[j]=1;\n            }\n        }\n    }\n    sum+=n;\n    for(i=0;n>1;)\n    {\n        if(n%D[i]==0) {sum+=n/D[i];n/=D[i];}\n        else\n        {\n            i++;\n        }\n    }\n    printf(\"%I64d\",sum);\n    return 0;\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5ee61fc2c539a72e5200b9b2de9262ed", "src_uid": "821c0e3b5fad197a47878bba5e520b6e", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nmain()\n{\n char a[10000],b[200];\n int p,q,min,i,j;\n int na[10],nb[10];\n p=size_t(a[10000]);\n q=size_t(b[200]);\n   for(int i=1;i<=p;i++)\n      {\n       if(a[i]=='9') a[i]='6';\n       if(a[i]=='5') a[i]='2';\n      }\n   for(int j=1;i<=q;j++)\n     {\n        if(b[i]=='9') b[i]='6';\n        if(b[i]=='5') b[i]='2';\n      }      \n    for(int i=1;i<=p;i++)\n      {\n\t  for(int j=1;i<=q;j++)\n             if(a[j]==i+'0') na[i]++;\n          for(int j=1;i<=q;j++)\n             if(b[j]==i+'0') nb[i]++;\n        } \n      for(int i=1;i<=p;i++);\n          for(int i=0;i<=9;i++)\n              if(nb[i]!=0)\n               {\n\t \t int min=na[i]/nb[i],k;\n                 min=k;  \n                 k<min?min=k:min;\n\t       }\n   printf(\"num=%d\",min);\n}  \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7e4631b5205ca736a01fe109be9a7c31", "src_uid": "72a196044787cb8dbd8d350cb60ccc32", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "// write in C...\n#include <stdio.h>\n\n#ifdef DEBUG\n#define D(x...) fprintf(stderr, x)\n#else\n#define D(x...)\n#endif\n\nchar t[10];\nchar s[300];\n\nint num_need[256];\nint num_have[256];\n\nint min(int a, int b) {\n    if (a < b) return a;\n    return b;\n}\n\nint main() {\n    int i;\n\n    scanf(\"%s %s\", t, s);\n    for (i = 0; t[i]; i++) num_need[t[i]]++;\n    for (i = 0; s[i]; i++) num_have[s[i]]++;\n\n    num_need['6'] += num_need['9'];\n    num_need['9'] = 0;\n    num_need['2'] += num_need['5'];\n    num_need['5'] = 0;\n\n    num_have['6'] += num_have['9'];\n    num_have['9'] = 0;\n    num_have['2'] += num_have['5'];\n    num_have['5'] = 0;\n\n    int res = 2000000000;\n\n    for (i = 0; i < 256; i++)\n        if (num_need[i])\n            res = min(res, num_have[i] / num_need[i]), D(\"%c\\n\", i);\n\n    printf(\"%d\\n\", res);\n\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7c53c3fe0a5b25a8c8bf9bd1134c264f", "src_uid": "72a196044787cb8dbd8d350cb60ccc32", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint min(int a,int b){\n    if(a<b) return a;\n    return b;\n}\nint main(){\n    char ice[201];\n    int tnum[10]={0,},num[10]={0,},i,t,cnt=10000000;\n    scanf(\"%d%s\",&t,ice);\n    for(i=0;i<strlen(ice);i++){\n        num[(int)(ice[i]-48)]++;\n    }   \n    while(t){\n        tnum[t%10]++;\n        t/=10;\n    }\n    num[2]+=num[5];\n    num[6]+=num[9];\n    tnum[2]+=tnum[5];\n    tnum[6]+=tnum[9];\n    for(i=0;i<10;i++){\n        printf(\"%d %d\\n\",num[i],tnum[i]);\n    }\n    for(i=0;i<10;i++){\n        if(tnum[i] && i!=5 && i!=9) cnt=min(cnt,num[i]/tnum[i]);\n    }\n    printf(\"%d\",cnt);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b27a63173494b63b961d5ac90cd9716c", "src_uid": "72a196044787cb8dbd8d350cb60ccc32", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint min(int a,int b){\n    if(a<b) return a;\n    return b;\n}\nint main(){\n    int tnum[10]={0,},num[10]={0,},i,t,ice,cnt=10000000;\n    scanf(\"%d%d\",&t,&ice);\n    while(ice){\n        num[ice%10]++;\n        ice/=10;\n    }\n    while(t){\n        tnum[t%10]++;\n        t/=10;\n    }\n    num[2]+=num[5];\n    num[6]+=num[9];\n    tnum[2]+=tnum[5];\n    tnum[6]+=tnum[9];\n    for(i=0;i<10;i++){\n        if(tnum[i] && i!=5 && i!=9) cnt=min(cnt,num[i]/tnum[i]);\n    }\n    printf(\"%d\",cnt);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "44b385f3133fb94bed6cbbd8ea0fe5c2", "src_uid": "72a196044787cb8dbd8d350cb60ccc32", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\n#define min(x,y) (((x)<(y))?(x):(y))\n\nchar a[200];\nint na[10],nb[10];\n\nint main()\n{    \n    int i;\n\tscanf(\"%s\",a);\n    for(i=0;i<strlen(a);i++)\n        {\n\t\t int p=a[i]-'0';\n         if(p==9) p=6;\n         if(p==5) p=2;\n         na[p]++;\n        }\n    scanf(\"%s\",a);\n    for(i=0;i<strlen(a);i++)\n       {\n         int q=a[i]-'0';\n         if(q==9) q=6;\n         if(q==5) q=2;\n         nb[q]++;\n       }\n    int n=201;\n    for(i=0;i<10;i++)\n      if(nb[i]!=0)\n        n=min(n,nb[i]/na[i]);\t\n   printf(\"%d\",n);\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cdb185de04ccdca8feab3604193e36ee", "src_uid": "72a196044787cb8dbd8d350cb60ccc32", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint a[100];\nvoid qs(int first, int last)\n \n{\n    if (first < last)\n    {\n        int left = first, right = last, middle = a[(left + right) / 2];\n        do\n        {\n            while (a[left] < middle) left++;\n            while (a[right] > middle) right--;\n            if (left <= right)\n            {\n                int tmp = a[left];\n                a[left] = a[right];\n                a[right] = tmp;\n                left++;\n                right--;\n            }\n        } while (left <= right);\n        qs( first, right);\n        qs( left, last);\n    }\n}\n \n \nint main() {\n    int n,l,r,sum,t,middle,in,i,j;\n    long long int m;\n    scanf(\"%i %lld\",&n,&m);\n    for (int i=1;i<=n;++i) scanf(\"%i\",&a[i]);\n    qs(1,n);\n \n    l=1;\n    r=n;\n \n    while(l<=r){\n        sum=0;\n        t=n;\n        middle=(l+r)/2;\n        (n % middle==0)?(in= n / middle):(in=( n / middle)+1);\n        for(i=0;i<in;i++){\n            for(j=1;j<=middle&&t>=1;j++){\n                if (a[t] - i > 0)\n                    sum = sum + a[t] - i;\n                t--;\n            }\n        }\n        if(sum==m){\n            l=middle;\n            r=middle;\n            break;\n        }\n        else if(sum<m){\n            l=middle+1;\n        }\n        else{\n            r=middle-1;\n        }\n    }\n \n    if((l <= n) && (r >= 0)){\n        if((l+r)%2!=0)\n            printf(\"%d\",(l+r)/2+1);\n        else\n            printf(\"%d\",(l+r)/2);\n    }\n    else printf(\"-1\");\n    return 0;\n ", "lang_cluster": "C", "compilation_error": true, "code_uid": "17ef668393b1e33322fc8205acb8d76b", "src_uid": "acb8a57c8cfdb849a55fa65aff86628d", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n// Merges two subarrays of arr[].\n// First subarray is arr[l..m]\n// Second subarray is arr[m+1..r]\nvoid merge(int arr[], int l, int m, int r)\n{\n    int i, j, k;\n    int n1 = m - l + 1;\n    int n2 =  r - m;\n\n    /* create temp arrays */\n    int L[n1], R[n2];\n\n    /* Copy data to temp arrays L[] and R[] */\n    for (i = 0; i < n1; i++)\n        L[i] = arr[l + i];\n    for (j = 0; j < n2; j++)\n        R[j] = arr[m + 1+ j];\n\n    /* Merge the temp arrays back into arr[l..r]*/\n    i = 0; // Initial index of first subarray\n    j = 0; // Initial index of second subarray\n    k = l; // Initial index of merged subarray\n    while (i < n1 && j < n2)\n    {\n        if (L[i] <= R[j])\n        {\n            arr[k] = L[i];\n            i++;\n        }\n        else\n        {\n            arr[k] = R[j];\n            j++;\n        }\n        k++;\n    }\n\n    /* Copy the remaining elements of L[], if there\n       are any */\n    while (i < n1)\n    {\n        arr[k] = L[i];\n        i++;\n        k++;\n    }\n\n    /* Copy the remaining elements of R[], if there\n       are any */\n    while (j < n2)\n    {\n        arr[k] = R[j];\n        j++;\n        k++;\n    }\n}\n\n/* l is for left index and r is right index of the\n   sub-array of arr to be sorted */\nvoid mergeSort(int arr[], int l, int r)\n{\n    if (l < r)\n    {\n        // Same as (l+r)/2, but avoids overflow for\n        // large l and h\n        int m = l+(r-l)/2;\n\n        // Sort first and second halves\n        mergeSort(arr, l, m);\n        mergeSort(arr, m+1, r);\n\n        merge(arr, l, m, r);\n    }\n}\n\nint fu(int a,int b){\nif(a-b<=0){\n    return 0;\n}\nelse{\n    return a-b;\n}\n}\nint main()\n{\n    int n,m,arr[100],i,l,r,mid,in,j,sum=0,w;\n    scanf(\"%d%d\",&n,&m);\n    for(i=1;i<=n;i++){\n        scanf(\"%d\",&arr[i]);\n    }\n    mergeSort(arr,1,n);\n    l=1;r=n;\n    while(l<=r)\n    {sum=0;w=n;\n        mid=(l+r)/2;\n        (n%mid==0)?(in=n/mid):(in=(n/mid)+1);\n        for(i=0;i<in;i++){\n            for(j=1;j<=mid&&w>=1;j++){\n                sum=sum+fu(arr[w],i);\n                w--;//printf(\"%d \",sum);\n            }\n        }//printf(\"\\n%d_%d \",mid,sum);\n        if(sum==m){l=mid;r=mid;\n            break;\n        }\n        else if(sum<m){\n            l=mid+1;\n        }\n        else{\n            r=mid-1;\n        }\n    }\n   if(l<=n&&r>=1){\n       if((l+r)%2!=0)\n        printf(\"%d\",(l+r)/2+1);\n        else\n            printf(\"%d\",(l+r)/2);\n   }\n\n   else printf(\"-1\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "abb913eb787af236db89900699d7fd0a", "src_uid": "acb8a57c8cfdb849a55fa65aff86628d", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\nint count[2 * 100000];\nint cmp (const void *a , const void *b){\n    return *(int *)a - *(int *)b;\n}\n\nint main(void){ \n    memset(count, 0, 100 * sizeof(int));\n    int n, p, c[100];\n    long int d = 0, sum = 0;\n    scanf(\"%d%d\", &n, &p);\n    for(int i = 0; i < n; i++){\n        scanf(\"%d\", &c[i]);\n        sum += c[i];\n    }\n    if(sum < p){\n        printf(\"-1\\n\");\n        return 0;\n    }\n    else if(sum == p){\n        printf(\"%d\\n\", n);\n        return 0;\n    }\n    sum = 0;\n    qsort(c, n, sizeof(int), cmp);\n    for(int i = 0; i < n; i++){\n        for(int k = 0; k <= d; k++){\n            if(c[i] >= count[k]){\n                sum += c[i] - count[k], count[k]++;\n                break;\n            }\n            if(k == d){\n                sum += c[i], d++, count[d]++;\n                break;\n            }\n        }\n        if(sum >= p){\n            printf(\"%ld\\n\", d + 1);\n            return 0;\n        }\n    }\n    while(d < n){\n        int end = 0;\n        for(int i = 0; i < d; i++){\n            if(count[i] <= count[i + 1]) continue;\n            else end = 1;\n            while(count[i] > count[i + 1]) count[i + 1]++, sum += count[i] - count[i + 1], count[i]--;\n            if(sum >= p){\n                printf(\"%ld\\n\", d + 1);\n                return 0;\n            }\n        }\n        if(end == 0) d++, count[d] = 1, sum += count[d - 1] - count[d], count[d - 1]--;\n        if(sum >= p){\n            printf(\"%ld\\n\", d + 1);\n            return 0;\n        }\n    }\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dc41b87690ce041853269261d47dc930", "src_uid": "acb8a57c8cfdb849a55fa65aff86628d", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nvoid sort(int* list, int n) {\n\tint i, j, flag;\n\tflag = 1;\n\twhile(flag == 1) {\n\t\tfor(i = 0, flag = 0; i < n - 1; i++) {\n\t\t\tif(list[i] < list[i + 1]) {\n\t\t\t\tj = list[i];\n\t\t\t\tlist[i] = list[i+1];\n\t\t\t\tlist[i+1] = j;\n\t\t\t\tflag = 1;\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main() {\n\tint n, m, days, caffeine, k, i, j, waste;\n\tint **cups;\n\n\tscanf(\"%d %d\", &n, &m);\n\tcups = (int**)malloc(2 * sizeof(int*));\n\tcups[0] = (int*)malloc(n * sizeof(int)); // caffeine in cup\n\tcups[1] = (int*)malloc(n * sizeof(int)); // caffeine before this cup\n\n\tfor(i = 0, caffeine = 0; i < n; i++) {\n\t\tscanf(\"%d\", &cups[0][i]);\n\t\tcaffeine += cups[0][i];\n\t}\n\tsort(cups[0], n);\n\n\tif(caffeine < m) {\n\t\tprintf(\"-1\\n\");\n\t\tfree(cups);\n\t\treturn 0;\n\t}\n\tif(caffeine == m) {\n\t\tprintf(\"%d\\n\", n);\n\t\tfree(cups);\n\t\treturn 0;\n\t}\n\n\tfor(i = 1, cups[1][0] = cups[0][0]; i < n; i++) {\n\t\tcups[1][i] = cups[1][i-1] + cups[0][i];\n\t\t//printf(\"cup%d : %d %d\\n\", i, cups[0][i], cups[1][i]);\n\t}\n\t\n\t/*for(days = 0, n--; m > 0 && n >= 0; days++) {\n\t\tk = 0;\n\n\t\twhile(cups[n] > k && caffeine >= (m + k)) {\n\t\t\tm = m - cups[n] + k;\n\t\t\tcaffeine -= cups[n];\n\t\t\tn --;\n\t\t\tk ++;\n\t\t}\n\t}*/\n\n\tfor(days = n; days >= 1; days--) {\n\t\tk = n / days;\n\n\t\tfor(i = 0, caffeine = 0, waste = 0; i < k; i++) {\n\t\t\tj = (i + 1) * days - 1;\n\t\t\tif(cups[0][j] > i) {\n\t\t\t\twaste = waste + i * days;\n\t\t\t} else {\n\t\t\t\twhile(j >= i * days) {\n\t\t\t\t\tif(cups[0][j] > i)\n\t\t\t\t\t\tbreak;\n\t\t\t\t\tj--;\n\t\t\t\t}\n\n\t\t\t\twaste = waste + i * (days - (j + 1) % days);\n\t\t\t\tcaffeine = cups[1][j] - waste;\n\t\t\t\tprintf(\"i=%d caf=%d waste=%d j=%d\\n\", i, caffeine, waste, j);\n\t\t\t\tbreak;\n\t\t\t}\n\n\t\t\tcaffeine = cups[1][j] - waste;\n\t\t\t\n\t\t\tif(caffeine >= m) {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\t//printf(\"        caffeine %d, waste %d\\n\", caffeine, waste);\n\t\tif(i < k && j < i * days)///////////////////// wrong\n\t\t\tbreak;\n\n\t\ti = n % days;\n\t\tif(i > 0) {\n\t\t\tfor(j++; j < n; j++) {\n\t\t\t\tif(cups[0][j] > k) {\n\t\t\t\t\twaste = waste + k;\n\t\t\t\t\tcaffeine = cups[1][j] - waste;\n\t\t\t\t} else {\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t//printf(\"days%d k%d: caffeine %d, waste %d\\n\", days, k, caffeine, waste);\n\t\tif(caffeine < m)\n\t\t\tbreak;\n\t}\n\n\tprintf(\"%d\\n\", days+1);\n\n\tfree(cups[0]);\n\tfree(cups[1]);\n\tfree(cups);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "239a69c153da54b8d368987e38dbf027", "src_uid": "acb8a57c8cfdb849a55fa65aff86628d", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint count[100];\nint cmp (const void *a , const void *b){\n    return *(int *)b - *(int *)a;\n}\n\nint main(void){ \n    memset(count, 0, 100 * sizeof(int));\n    int n, p, c[100], d = 0, sum = 0;\n    scanf(\"%d%d\", &n, &p);\n    for(int i = 0; i < n; i++){\n        scanf(\"%d\", &c[i]);\n        sum += c[i];\n    }\n    if(sum < p){\n        printf(\"-1\\n\");\n        return 0;\n    }\n    sum = 0;\n    qsort(c, n, sizeof(int), cmp);\n    int index = 0;\n    for(int k = 0; index < n && sum < p; k++, d++){\n        for(int i = 0; i < n; i++){\n            if(c[index] - i > 0){\n                sum += c[index] - i, index++, count[k]++;\n                if(sum >= p){\n                    printf(\"%d\\n\", d + 1);\n                    return 0;\n                }\n            }\n            else break;\n        }\n    }\n    while(d <= n){\n        for(int i = 0; i <= d; i++){\n            while(count[i] >= count[i + 1]){\n                int j = 0;\n                while(count[i] <= count[j]) j++;\n                if(j > d) d = j;\n                count[j]++, sum += count[i] - count[j], count[i]--;\n                if(sum >= p){\n                    printf(\"%d\\n\", d + 1);\n                    return 0;\n                }\n            }\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "304f1b135321fff52fdba3cc27306e67", "src_uid": "acb8a57c8cfdb849a55fa65aff86628d", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "char s[105],n,m,k,ans[8],G,R,has,oG,oR;\n#define o(x) return puts((!x)?\"First\":\"Second\")*0\n#define F(i,a,b) for(int i=a;i<=b;++i)\nmain(){scanf(\"%d%d%d\",&n,&m,&k);F(i,1,n){has=G=R=0;scanf(\"%s\",s+1);F(j,1,m)if(s[j]=='-')has=1;else if(s[j]=='G')G=j;else if(s[j]=='R')R=j;if((!G&&!R)||!has)continue;if(!G)oR=1;else if(!R)oG=1;else F(j,0,7)if((1<<j)&(abs(R-G)-1))++ans[j];}if(oR&&oG)return puts(\"Draw\")*0;if(oR)o(1);if(oG)o(0);F(i,0,7)if(ans[i]%(k+1))o(0);o(1);}", "lang_cluster": "C", "compilation_error": false, "code_uid": "16a31d5a1cfdc3fca2893842c1975d84", "src_uid": "69062f7c9b834e925ab23ebc2da96b52", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint main(){\n  int i,j,k,l,m,n;\n  int x,y,cnt,ok;\n  int r,g;\n  char mp[120][120];\n\n  while(scanf(\"%d%d%d\",&x,&y,&k)==3){\n    rep(i,x) scanf(\"%s\",mp[i]);\n    cnt = 0;\n    ok = 0;\n\n    rep(i,x){\n      r=g=-1;\n      rep(j,y){\n        if(mp[i][j]=='R') r=j;\n        if(mp[i][j]=='G') g=j;\n      }\n      if(r==-1 || g==-1) continue;\n      if(y>2) ok = 1;\n      if(r+1==g || r-1==g); else cnt++;\n    }\n\n    if(ok==0){\n      puts(\"Draw\");\n      continue;\n    }\n\n    if(cnt % (k+1) == 0) puts(\"Second\");\n    else                 puts(\"First\");\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6fe75c6ade00ad2c992d26e7e4312c8b", "src_uid": "69062f7c9b834e925ab23ebc2da96b52", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint main(){\n  int i,j,k,l,m,n;\n  int x,y,cnt,num;\n  int r,g;\n  int ok_r, ok_g;\n  char mp[120][120];\n  int ed = 0;\n\n  while(scanf(\"%d%d%d\",&x,&y,&k)==3){\n    if(ed) break; else ed = 1;\n    rep(i,x) scanf(\"%s\",mp[i]);\n    cnt = 0;\n    ok_g = ok_r = 0;\n\n    rep(i,x){\n      r=g=-1; num = 0;\n      rep(j,y){\n        if(mp[i][j]=='G') g=j, num++;\n        if(mp[i][j]=='R') r=j, num++;\n      }\n      if(r==-1 || g==-1){\n        if(num < y){\n          if(g>=0) ok_g = 1;\n          if(r>=0) ok_r = 1;\n        }\n        continue;\n      }\n      if(r+1==g || r-1==g); else cnt++;\n    }\n\n    if(ok_g && ok_r){\n      puts(\"Draw\"); continue;\n    }\n    if(ok_g){\n      puts(\"First\"); continue;\n    }\n    if(ok_r){\n      puts(\"Second\"); continue;\n    }\n\n    if(cnt % (k+1) == 0){\n      puts(\"Second\");\n    } else {\n      puts(\"First\");\n    }\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "50cac32f9d0efb1c778cb5b1cd607ba7", "src_uid": "69062f7c9b834e925ab23ebc2da96b52", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint main(){\n  int i,j,k,l,m,n;\n  int x,y,cnt,num;\n  int r,g;\n  int ok_r, ok_g;\n  char mp[120][120];\n\n  while(scanf(\"%d%d%d\",&x,&y,&k)==3){\n    rep(i,x) scanf(\"%s\",mp[i]);\n    cnt = 0;\n    ok_g = ok_r = 0;\n\n    rep(i,x){\n      r=g=-1; num = 0;\n      rep(j,y){\n        if(mp[i][j]=='G') g=j, num++;\n        if(mp[i][j]=='R') r=j, num++;\n      }\n      if(r==-1 || g==-1){\n        if(num < y){\n          if(g>=0) ok_g = 1;\n          if(r>=0) ok_r = 1;\n        }\n        continue;\n      }\n      if(r+1==g || r-1==g); else cnt++;\n    }\n\n    if(ok_g && ok_r){\n      puts(\"Draw\"); continue;\n    }\n    if(ok_r){\n      puts(\"First\"); continue;\n    }\n    if(ok_g){\n      puts(\"Second\"); continue;\n    }\n\n    if(cnt % (k+1) == 0){\n      puts(\"Second\");\n    } else {\n      puts(\"First\");\n    }\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "714f1caaebccbca0410118dfe3348e63", "src_uid": "69062f7c9b834e925ab23ebc2da96b52", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint main(){\n  int i,j,k,l,m,n;\n  int x,y,cnt,num;\n  int r,g;\n  int ok_r, ok_g;\n  char mp[120][120];\n\n  while(scanf(\"%d%d%d\",&x,&y,&k)==3){\n    rep(i,x) scanf(\"%s\",mp[i]);\n    cnt = 0;\n    ok_g = ok_r = 0;\n\n    rep(i,x){\n      r=g=-1; num = 0;\n      rep(j,y){\n        if(mp[i][j]=='G') g=j, num++;\n        if(mp[i][j]=='R') r=j, num++;\n      }\n      if(r==-1 || g==-1){\n        if(1 < y){\n          if(g>=0) ok_g = 1;\n          if(r>=0) ok_r = 1;\n        }\n        continue;\n      }\n      if(r+1==g || r-1==g); else cnt++;\n    }\n\n    if(ok_g && ok_r){\n      puts(\"Draw\"); continue;\n    }\n    if(ok_g){\n      puts(\"First\"); continue;\n    }\n    if(ok_r){\n      puts(\"Second\"); continue;\n    }\n\n    if(cnt % (k+1) == 0){\n      puts(\"Second\");\n    } else {\n      puts(\"First\");\n    }\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "eb36f9bec31d0f2d0631fa3126ea7400", "src_uid": "69062f7c9b834e925ab23ebc2da96b52", "difficulty": 2600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#define Maxn 5007\n#define modp 998244353\nint p[Maxn][Maxn];\nint pre[Maxn];\nint a,b,c;\nint solve(int x,int y)\n{\n\tint res=0;\n\tfor (int k=0;k<=x&&k<=y;k++)\n\t{\n\t\tint del=pre[k];\n\t\tdel=(1LL*del*p[x][k])%modp;\n\t\tdel=(1LL*del*p[y][k])%modp;\n\t\tres=(res+del)%modp;\n\t}\n\treturn res;\n}\nint main()\n{\n\tscanf(\"%d%d%d\",&a,&b,&c);\n\tmemset(p,0,sizeof(p));\n\tp[0][0]=1;\n\tfor (int i=1;i<=5000;i++)\n\t{\n\t\tp[i][0]=1;\n\t\tfor (int j=1;j<=i;j++)\n\t\t\tp[i][j]=(p[i-1][j-1]+p[i-1][j])%modp;\n\t}\n\tmemset(pre,0,sizeof(pre));\n\tpre[0]=1;\n\tfor (int i=1;i<=5000;i++)\n\t\tpre[i]=(1LL*pre[i-1]*i)%modp;\n\tint ans=1;\n\tans=(1LL*ans*solve(a,b))%modp;\n\tans=(1LL*ans*solve(b,c))%modp;\n\tans=(1LL*ans*solve(a,c))%modp;\n\tprintf(\"%d\\n\",ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "666a1b2bcdd4ffe4d87241d52433f07a", "src_uid": "b6dc5533fbf285d5ef4cf60ef6300383", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MOD % 998244353\n\nlong long C[5001][5001];\n\nvoid Set_Combination(int a, int b)\n{\n\tif (a == b || b == 0)\n\t{\n\t\tC[a][b] = 1;\n\t\treturn;\n\t}\n\tif (!C[a - 1][b])\n\t\tSet_Combination(a - 1, b);\n\tif (!C[a - 1][b - 1])\n\t\tSet_Combination(a - 1, b - 1);\n\tC[a][b] = (C[a - 1][b - 1] + C[a - 1][b]) MOD;\n}\n\nlong long Permutation(int a, int b)\n{\n\tint k;\n\tlong long r = 1;\n\tif (b == 0)\n\t\treturn 1;\n\tfor (k = a; k >= a - b + 1; k = k - 1)\n\t{\n\t\tr = (r * k)MOD;\n\t}\n\treturn r;\n}\n\nvoid Island(int a, int b, int * ans)\n{\n\tint i, j, small = (a >= b ? b : a);\n\tlong long temp = 0;\n\tfor (i = 0; i <= small;i = i + 1)\n\t{\n\t\ttemp = (temp + C[b][i] * Permutation(a, i)MOD) MOD;\n\t}\n\t*ans = (*ans * temp MOD);\n\treturn;\n}\n\nint main(void)\n{\n\tint a, b, c, ans = 1;\n\t\n\tfor (a = 0; a <= 5000; a = a + 1)\n\t{\n\t\tfor (b = 0; b <= a; b = b + 1)\n\t\t{\n\t\t\tSet_Combination(a, b);\n\t\t}\n\t}\n\tscanf(\"%d %d %d\", &a, &b, &c);\n\tIsland(a, b, &ans);\n\tIsland(b, c, &ans);\n\tIsland(c, a, &ans);\n\tprintf(\"%d\", ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8f792760db63002b215423aba12637f7", "src_uid": "b6dc5533fbf285d5ef4cf60ef6300383", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#define Maxn 5007\n#define modp 998244353\nint p[Maxn][Maxn];\nint pre[Maxn];\nint a,b,c;\nint solve(int x,int y)\n{\n\tint res=0;\n\tfor (int k=0;k<=x&&k<=y;k++)\n\t{\n\t\tint del=pre[k];\n\t\tdel=(1LL*del*p[x][k])%modp;\n\t\tdel=(1LL*del*p[y][k])%modp;\n\t\tres=(res+del)%modp;\n\t}\n\treturn res;\n}\nint main()\n{\n\tscanf(\"%d%d%d\",&a,&b,&c);\n\tmemset(p,0,sizeof(p));\n\tp[0][0]=1;\n\tfor (int i=1;i<=5000;i++)\n\t{\n\t\tp[i][0]=1;\n\t\tfor (int j=1;j<=i;j++)\n\t\t\tp[i][j]=(p[i-1][j-1]+p[i-1][j])%modp;\n\t}\n\tmemset(pre,0,sizeof(pre));\n\tpre[0]=1;\n\tfor (int i=1;i<=5000;i++)\n\t\tpre[i]=(1LL*pre[i-1]*i)%modp;\n\tint ans=1;\n\tans=(1LL*ans*solve(a,b))%modp;\n\tans=(1LL*ans*solve(b,c))%modp;\n\tans=(1LL*ans*solve(a,c))%modp;\n\tprintf(\"%d\\n\",ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b9e5d33b89ac79b6e0e0ee60d208b95d", "src_uid": "b6dc5533fbf285d5ef4cf60ef6300383", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define maxn 5010\n#define MOD 998244353\nlong long c[maxn][maxn];\nlong long calc(int a,int b){\n    if(a>b){int t=b;b=a;a=t;}\n    long long res=1,mul=1;\n    int i;\n    for(i=1;i<=a;i++){\n        mul=mul*(b-i+1)%MOD;\n        res=(res+c[a][i]*mul)%MOD;\n    }\n    return res;\n}\nint main(){\n    int i,j;\n    c[0][0]=1;\n    for(i=1;i<maxn;i++){\n        c[i][0]=1;\n        for(j=1;j<=i;j++)\n            c[i][j]=(c[i-1][j]+c[i-1][j-1])%MOD;\n    }\n    int a,b,c;\n    scanf(\"%d%d%d\",&a,&b,&c);\n    long long ans=(calc(a,b)*calc(b,c)%MOD)*calc(a,c);\n    printf(\"%lld\\n\",ans%MOD);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "226a5c4182d876de4f3295ce309b96ab", "src_uid": "b6dc5533fbf285d5ef4cf60ef6300383", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nlong long dp[5001][5001],a,b,c;\nint main()\n{\n    scanf(\"%I64d%I64d%I64d\",&a,&b,&c);\n    for(int i=0;i<=5000;i++) dp[i][0]=dp[0][i]=1;\n    for(int i=1;i<=5000;i++)\n        for(int j=1;j<=5000;j++)\n            dp[i][j]=(dp[i-1][j]+(dp[i-1][j-1]*j)%998244353)%998244353;\n    printf(\"%I64d\\n\",(dp[a][b]*dp[a][c])%998244353*dp[b][c]%998244353);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4c89204fbef843c1144ebff0f2619c7a", "src_uid": "b6dc5533fbf285d5ef4cf60ef6300383", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main() {\n\tint n,m,k,i;\n\tscanf(\"%d %d %d\",&n,&m,&k);\n\tif (n%2==0) {\n\t\tputs(\"Marsel\");\n\t\treturn 0;\n\t}\n\tif (k==1) {\n\t\tputs(\"Timur\");\n\t\treturn 0;\n\t}\n\tfor(i=1;i*i<=m;i++) if (m%i==0 && m/i>=k) break;\n\tif (i*i>m) {\n\t\tputs(\"Marsel\");\n\t\treturn 0;\n\t}\n\tputs(\"Timur\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "903c9a503a8da119ef720954dd59a46d", "src_uid": "4a3767011ddac874efa021fff7c94432", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nmain()\n{\n        int i=0,n=0,m=0,k=0,b=1,t=0,w=0;\n        scanf(\"%d\",&n);\n        scanf(\"%d\",&m);\n        scanf(\"%d\",&k);\n\t\tif (m==1)\n\t\t\tprintf(\"Marsel\");\n        for(i=2;i*i<=m;i++)\n\t\t{\n\t\t\tif (m%i==0)\n\t\t\t{\n\t\t\t\tif (m/i>=k)\n\t\t\t\t{\n\t\t\t\t\tt=1;\n\t\t\t\t\tw=1;\n\t\t\t\t\tbreak;}\n\t\t\t\telse t=0;\n\t\t\t}\n\t\t}\n\t\tif (t==0)\n\t\t{\n\t\t\tprintf(\"Marsel\");\n\t\t\treturn 0;}\n\n\t\tif (w==1 && n%2==0)\n\t\t\tprintf(\"Marsel\");\n\t\telse  printf(\"Timur\");\n\n\n\n\nreturn 0;\n\n\t\t}", "lang_cluster": "C", "compilation_error": false, "code_uid": "71f20e402e5c035dce7b0c15b3632afa", "src_uid": "4a3767011ddac874efa021fff7c94432", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MAX 100000\n\nint prime[10000];\nint c;\n\nint primes(int m){\n  int i, j;\n  c = 1;\n  prime[1] = 2;\n\n  for(i=3; i <= m; i+=2){\n    for(j=1; j <= c; j++){\n      if((i % prime[j]) == 0)\n        break;\n    }\n    if(j > c)\n      prime[++c] = i;\n  }\n}\n\nint game(int m, int k){\n  int i;\n  \n  for(i=1; i <= c; i++)\n    if((m % prime[i]) == 0)\n      if(m/prime[i] >= k)\n        return 1;\n      else\n        return 0;\n}\n\n\nint main(){\n  int n, m, k;\n  int i;\n\n  scanf(\"%d %d %d\", &n, &m, &k);\n\n  if(!(n&1)){\n    printf(\"Marsel\\n\");\n    return 0;\n  }\n    \n  primes(m);\n\n  if(game(m, k))\n    printf(\"Timur\\n\");\n  else\n    printf(\"Marsel\\n\");\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "af70eb7ba3a4ec6e40a20be078c5014e", "src_uid": "4a3767011ddac874efa021fff7c94432", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main() {\n\tint m, n, k, i;\n\tscanf(\"%d %d %d\", &n, &m, &k);\n\tfor (i = 1; i*i < m; ++i) {\n\t\tif (m%i == 0) break;\n\t}\n\tif ((i <= k)&&(n%2 != 0)) printf(\"Timur\");\n\telse printf(\"Marsel\"); \n}\n\t \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "192cd2de8ef067bf2a2203feb51ba2b1", "src_uid": "4a3767011ddac874efa021fff7c94432", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nmain()\n{\n        int i=0,n=0,m=0,k=0,b=1,t=0,w=0;\n        scanf(\"%d\",&n);\n        scanf(\"%d\",&m);\n        scanf(\"%d\",&k);\n        for(i=1;i*i<=m;i++)\n        { if (i!=1)\n\t\t{\n                if (m%i==0)\n                {\n                    if ((m/i)>=k)\n\t\t\t\t\t{w=1;\n                                break;\n\t\t\t\t\t\t\t\t}\n                        else w=0;\n\t\t\t\t\n\t\t\t\t}\n        }\n\n\t\t}\n\n  \n    if (w==1)    \n\t{\nif ((n%2)==0)\n\n      printf(\"Marsel\");\n\n\n                else printf(\"Timur\");\n\t}\n\telse{ printf(\"Marsel\");\n\t              \n\n\t\t\t\treturn(0);}\n\t\n\n\nif (((i*i>m)||(m==1)) && k==1) {\nprintf(\"Marsel\");\nreturn 0;       }\n\n\nif (((i*i>m)||(m==1)) && k!=1) {\nprintf(\"Timur\");\nreturn 0;       }\n\n\n\t\t}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8003bc95a7a4656206ee38f62916b7e9", "src_uid": "4a3767011ddac874efa021fff7c94432", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint comp(const void * a,const void * b)\n{\n    return (*(int*)a - *(int*)b);\n}\nint arr[200009],brr[200009],crr[200009];\nint main()\n{\n    int n,k,m,i,j,l;\n    scanf(\"%d %d\",&n,&k);\n    for(i=0;i<n;i++){\n        scanf(\"%d\",&crr[i]);\n    }\n    qsort(crr,n,sizeof(int),comp);\n    for(i=0;i<n;i++){\n        j=0;\n        while(1){\n            arr[crr[i]]++;\n            if(arr[crr[i]]<=k)\n                brr[crr[i]]+=j;\n            if(crr[i]==0)\n                break;\n            crr[i]/=2;\n            j++;\n        }\n    }\n    for(i=0;i<=200005;i++){\n        if(i==0)\n            l=brr[0];\n        else if(arr[i]>=k && l>brr[i])\n            l=brr[i];\n    }\n    printf(\"%d\",l);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6b9eeac427ed28808d1d9ff64be7db2f", "src_uid": "ed1a2ae733121af6486568e528fe2d84", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#define ll long long\nint comp(const void*p,const void*q)\n{\nreturn *(const int*)p-*(const int *)q;\t\n}\nint main(){\n\tll n,k;\n\tscanf(\"%lld%lld\",&n,&k);\n\tll arr[n],count=0,x,y,flag=0,run=0,min=200000001;\n\tll num[n][20],cnt[200001]={0};\n\tfor(int i=0;i<n;i++){ scanf(\"%lld\",&arr[i]);\n\t}\n\tqsort(arr,n,sizeof(arr[0]),comp);\n\tfor(int i=0;i<n;i++){num[i][0]=arr[i];\n\tcnt[num[i][0]]++;\n\tfor(int j=1;j<20;j++){ num[i][j]=num[i][j-1]/2;\n\t//printf(\"%lld \",num[i][j]);\n\tcnt[num[i][j]]++;\n\t}\n\t}\n\tfor(int z=200000;z>=0;z--){count=0;run=0;flag=0;\n\tif(cnt[z]>=k) {x=z;\n\t//printf(\"%lld,%lld\\n\",x,cnt[x]);\n\tfor(int i=0;i<n;i++){\n\tfor(int j=0;j<20;j++){\n\tif(num[i][j]==x) {run++;\n\tcount=count+j;\n\t//printf(\"%lld,%lld,%lld  \\n\",count,run,k);\n\tif(run>=k){flag=1;\n\t//printf(\"%lld,\",run); \n\tbreak;}\n\tbreak;\n\t}\n\t}if(flag==1) break;\n\t}if(count<min){ min=count;\n\t//printf(\"%lld\\n\",min);\n\t}}\n\t}\n\t/*for(int i=0;i<n;i++){\n\tif(arr[i]>=(x)) {y=i;\n\tbreak;}\n\t}*/\n\t\n\n\nprintf(\"%lld\",min);\n\n\n\n\n\nreturn 0;}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b9766d71cade731695b42ae00bc186e5", "src_uid": "ed1a2ae733121af6486568e528fe2d84", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define MAX_N 200000\n#define MAX_A 200000\n\nint read_int() {\n    int x;\n    scanf(\"%d\", &x) > 0;\n    return x;\n}\n\nint b[MAX_A+1]; // b[x] = how many of size x are in a\nint c[MAX_A+1];\nint d[MAX_A+1];\n\nint min(int a, int b) { return (a < b && a != -1) ? a : b; }\n\nint main() {\n    int n = read_int(), k = read_int(), best = -1;\n    for(int i = 0; i < n; i++) b[read_int()]++;\n    for(int i = 0; i <= MAX_A; i++) c[i] = b[i];\n    for(int e = 1; e < 20; e++) {\n        for(int i = 0; i <= MAX_A; i++) {\n            if(b[i] >= k && b[i]-c[i] < k) {\n                best = min(best, d[i] - (e-1) * (b[i]-k));\n            }\n            c[i] = 0;\n            if (i*2 <= MAX_A) c[i] += c[i*2], d[i] += c[i*2] * e;\n            if (i*2+1 <= MAX_A) c[i] += c[i*2+1], d[i] += c[i*2+1] * e;\n            b[i] += c[i];\n        }\n    }\n    printf(\"%d\\n\", best);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9ad5b95779d0f0f9d022b2a14291f937", "src_uid": "ed1a2ae733121af6486568e528fe2d84", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "/* Coached by rainboy */\n#include <time.h>\n#include <stdio.h>\n#include <stdlib.h>\n\n#define N 200000\n#define A 200000\n#define INF\t2147483647\n\nint compare(const void *a, const void *b) {\n\tint ia = *(int *) a;\n\tint ib = *(int *) b;\n\n\treturn ia - ib;\n}\n\nint main() {\n\tstatic int aa[N], ss[A + 1], kk[A + 1];\n\tint n, k, i, j, tmp, a, s, ans;\n\n\tscanf(\"%d%d\", &n, &k);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d\", &aa[i]);\n\tsrand(time(NULL));\n\tfor (i = n - 1; i >= 0; i--) {\n\t\tj = rand() % n;\n\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\t}\n\tqsort(aa, n, sizeof *aa, compare);\n\tfor (i = 0; i < n; i++) {\n\t\ta = aa[i];\n\t\ts = 0;\n\t\twhile (a > 0) {\n\t\t\tif (kk[a] < k) {\n\t\t\t\tkk[a]++;\n\t\t\t\tss[a] += s;\n\t\t\t}\n\t\t\ta /= 2;\n\t\t\ts++;\n\t\t}\n\t}\n\tans = INF;\n\tfor (a = 1; a <= A; a++)\n\t\tif (kk[a] == k && ans > ss[a])\n\t\t\tans = ss[a];\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b67ebd54d330faf0426bf6bd027b5ad5", "src_uid": "ed1a2ae733121af6486568e528fe2d84", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "/* Coached by rainboy */\n#include <time.h>\n#include <stdio.h>\n#include <stdlib.h>\n\n#define N 200000\n#define A 200000\n#define INF 0x3f3f3f3f\n\nint compare(const void *a, const void *b) {\n\tint ia = *(int *) a;\n\tint ib = *(int *) b;\n\n\treturn ia - ib;\n}\n\nint main() {\n\tstatic int aa[N], ss[A + 1], kk[A + 1];\n\tint n, k, i, j, tmp, a, s, ans;\n\n\tscanf(\"%d%d\", &n, &k);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d\", &aa[i]);\n\tsrand(time(NULL));\n\tfor (i = n - 1; i >= 0; i--) {\n\t\tj = rand() % n;\n\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\t}\n\tqsort(aa, n, sizeof *aa, compare);\n\tfor (i = 0; i < n; i++) {\n\t\ta = aa[i];\n\t\ts = 0;\n\t\twhile (a > 0) {\n\t\t\tif (kk[a] < k) {\n\t\t\t\tkk[a]++;\n\t\t\t\tss[a] += s;\n\t\t\t}\n\t\t\ta /= 2;\n\t\t\ts++;\n\t\t}\n\t}\n\tans = INF;\n\tfor (a = 1; a <= A; a++)\n\t\tif (kk[a] == k && ans > ss[a])\n\t\t\tans = ss[a];\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1b92bf39b8dcb8d40444eb7c78fc4e7e", "src_uid": "ed1a2ae733121af6486568e528fe2d84", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n#include <stdlib.h>\n#include <stdio.h>\nusing namespace std;\nint cmp(const void *a,const void *b)\n{\n    return ( *(int*)b-*(int*)a);\n}\n\nint main()\n{\n    int n,k,x,t[110],i,sum=0,j;\n    scanf(\"%d%d%d\",&n,&k,&x);\n\n    for (i=0;i<n;i++){\n        scanf(\"%d\",&t[i]);\n        sum+=t[i];\n    }\n    qsort(t,n,sizeof(t[0]),cmp);\n    sum+=x*k;\n\n    for (i=0;i<k;i++){\n        sum-=t[i];\n    }\n\n    printf(\"%d\",sum);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "f643a93fe4d55661da5bd7f13ab5b200", "src_uid": "92a233f8d9c73d9f33e4e6116b7d0a96", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n\t//int a[101];\n\tint n,k,x;\n\tint sum=0;\n\tscanf(\"%d%d%d\",&n,&k,&x);\n\tfor(int i=0;i<n;i++){\n\t\tint temp;\n\t\tscanf(\"%d\",&temp);/*\n\t\tif(i<n-2){\n\t\t\tsum+=temp;\n\t\t}else{\n\t\t\t\n\t\t}*/\n\t\t(i<n-2)?sum+=temp:sum+=x;\n\t}\n\tprintf(\"%d\\n\",sum);\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "56ca710a00a0e9335c8b3c331fbe6d29", "src_uid": "92a233f8d9c73d9f33e4e6116b7d0a96", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()int n,k,x,i,j,a,sum;\n    scanf(\"%d%d%d\",&n,&k,&x);\n    int number[n];\n    for(i=0;i<n;i++){\n          scanf(\"%d\",&number[i]);\n    }\n\n    sum=k*x;\n    for(j=0;j<n-2;j++){\n       sum=sum+number[j];\n    }\n    printf(\"%d\\n\",sum);\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "98a8352f4c2d107c9000485ccb3bd621", "src_uid": "92a233f8d9c73d9f33e4e6116b7d0a96", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?>\n<CodeBlocks_project_file>\n\t<FileVersion major=\"1\" minor=\"6\" />\n\t<Project>\n\t\t<Option title=\"hassen\" />\n\t\t<Option pch_mode=\"2\" />\n\t\t<Option compiler=\"gcc\" />\n\t\t<Build>\n\t\t\t<Target title=\"Debug\">\n\t\t\t\t<Option output=\"bin/Debug/hassen\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Debug/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-g\" />\n\t\t\t\t</Compiler>\n\t\t\t</Target>\n\t\t\t<Target title=\"Release\">\n\t\t\t\t<Option output=\"bin/Release/hassen\" prefix_auto=\"1\" extension_auto=\"1\" />\n\t\t\t\t<Option object_output=\"obj/Release/\" />\n\t\t\t\t<Option type=\"1\" />\n\t\t\t\t<Option compiler=\"gcc\" />\n\t\t\t\t<Compiler>\n\t\t\t\t\t<Add option=\"-O2\" />\n\t\t\t\t</Compiler>\n\t\t\t\t<Linker>\n\t\t\t\t\t<Add option=\"-s\" />\n\t\t\t\t</Linker>\n\t\t\t</Target>\n\t\t</Build>\n\t\t<Compiler>\n\t\t\t<Add option=\"-Wall\" />\n\t\t</Compiler>\n\t\t<Unit filename=\"main.c\">\n\t\t\t<Option compilerVar=\"CC\" />\n\t\t</Unit>\n\t\t<Extensions>\n\t\t\t<code_completion />\n\t\t\t<debugger />\n\t\t</Extensions>\n\t</Project>\n</CodeBlocks_project_file>\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e8ce8e0f4d62f151687c15750fe22e28", "src_uid": "92a233f8d9c73d9f33e4e6116b7d0a96", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,k,x,i,j,a,sum;\n    scanf(\"%d%d%d\",&n,&k,&x);\n    int number[n];\n    for(i=0;i<n;i++){\n          scanf(\"%d\",&number[i]);\n    }\n      for (i = 0; i < n; ++i)\n    {\n        for (j = i + 1; j < n; ++j)\n        {\n            if (number[i] < number[j])\n            {\n                a = number[i];\n                number[i] = number[j];\n                number[j] = a;\n            }\n        }\n    }\n    sum=k*x;\n    for(j=2;j<n;j++){\n       sum=sum+number[j];\n    }\n    printf(\"%d\\n\",sum);\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f534698a612d6331bcb28309c34b283c", "src_uid": "92a233f8d9c73d9f33e4e6116b7d0a96", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    long arr[3][3], sum[3]; int i, j, maxX, tmpMax = -1;\n    for (i = 0; i < 3; i++){\n        sum[i] = 0;\n        for (j = 0; j < 3; j++){\n            scanf(\"%ld\", &arr[i][j]);\n            sum[i] += arr[i][j];\n        }\n        if (tmpMax == -1) {tmpMax = sum[i]; maxX = i;}\n        else if (tmpMax < sum[i]) {tmpMax = sum[i]; maxX = i;}\n    }\n    arr[maxX][maxX] = 1;\n    for (i = 0; i < 3; i++){\n        if (i != maxX){\n            arr[i][i] = sum[maxX] - sum[i] + 1;\n        }\n        printf(\"%ld %ld %ld\\n\", arr[i][0], arr[i][1], arr[i][2]);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a9a07d41247e80947361b285663bb060", "src_uid": "0c42eafb73d1e30f168958a06a0f9bca", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint readint(){\n\tchar temp;\n\tint num = 0;\n\n\ttemp = getc_unlocked(stdin);\n\twhile(temp >= '0' && temp <= '9'){\n\t\tnum = num * 10 + temp - '0';\n\t\ttemp = getc_unlocked(stdin);\n\t}\n\n\treturn num;\n}\n\nint main(){\n\tint a[3][3],i,j,sum = 0;\n\t\n\tfor(i=0;i < 3;i++)\n\t\tfor(j=0;j < 3;j++){\n\t\t\ta[i][j] = readint();\n\t\t\tsum = sum + a[i][j];\n\t\t}\n\t\n\ta[0][0] = (sum/2) - a[0][1] - a[0][2];\n\ta[1][1] = (sum/2) - a[1][0] - a[1][2];\n\ta[2][2] = (sum/2) - a[2][0] - a[2][1];\n\n\tfor(i=0;i < 3;i++){\n\t\tfor(j=0;j < 3;j++)\n\t\t\tprintf(\"%d \",a[i][j]);\n\t\tprintf(\"\\n\");\n\t}\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "35d6654d3b28b71239118205d8a5fe0a", "src_uid": "0c42eafb73d1e30f168958a06a0f9bca", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#nclude<stdio.h>\nint main()\n{\n    int array[3][3],i,j,x,y,z;\n    for(i=0;i<3;i++)\n        for(j=0;j<3;j++)\n            scanf(\"%d\",&array[i][j]);\n    y=((array[0][1]+array[0][2])+array[2][0]+array[2][1]-array[1][0]-array[1][2])/2;\n    array[1][1]=y;\n    x=array[1][0]+array[1][1]+array[1][2]-array[0][1]-array[0][2];\n    z=array[1][0]+array[1][1]+array[1][2]-array[2][0]-array[2][1];\n    array[0][0]=x;\n    array[2][2]=z;\n    for(i=0;i<3;i++)\n    {\n        for(j=0;j<3;j++)\n            printf(\"%d \",array[i][j]);\n        printf(\"\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "2287f95dd95a0134de455f2d9fcbd5a5", "src_uid": "0c42eafb73d1e30f168958a06a0f9bca", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(){\n    int i, j, k, l, m, n, sum;\n    int a[3][3];\n\n    sum = 0;\n    for(i = 0; i < 3; i++){\n        for(j = 0; j < 3; j++){\n            scanf(\"%d\", &a[i][j]);\n            sum += a[i][j];\n        }\n    }\n\n    a[1][1] = (a[0][1] + a[0][2] + a[2][0] + a[2][1] - a[1][0] - a[1][2]) / 2;\n    a[2][2] = a[0][1] + a[0][2] - a[1][1];\n    a[0][0] = (sum / 2) - a[1][1] - a[2][2];\n\n    for(i = 0; i < 3; i++){\n        for(j = 0; j < 3; j++){\n            printf(\"%d \", a[i][j]);\n        }\n        printf(\"\\n\");\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "25d98f374bac0c9fdb165b03b8474b37", "src_uid": "0c42eafb73d1e30f168958a06a0f9bca", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n \nint main(void) {\n \n    long int i,j;\n    long int a[3][3];\n \n \n    for(i=0;i<3;i++)\n    for(j=0;j<3;j++)\n    scanf(\"%d\",a[i][j]);\n \n \n \n    for(i=0;i<=100000;i++)\n    if(!((i+a[0][1]+a[0][2])-(a[1][0]+a[1][2]))-(a[2][0]+a[2][1]))\n    break;\n \n \n    a[0][0]=i;\n    a[1][1]=((i+a[0][1]+a[0][2])-(a[1][0]+a[1][2]));\n    a[2][2]=((i+a[0][1]+a[0][2])-(a[2][0]+a[2][1]));\n \n    for(i=0;i<3;i++)\n    printf(\"\\n\");\n    for(j=0;j<3;j++)\n    printf(\"%d \",a[i][j]);\n    return 0;\n}\n ", "lang_cluster": "C", "compilation_error": false, "code_uid": "27485ce3d29da693438d85cd1bd2dd07", "src_uid": "0c42eafb73d1e30f168958a06a0f9bca", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint a[16] = {1, 0, 18, 0, 1800, 0, 670320, 0, 734832000, 0, 890786230, 0, 695720788, 0, 150347555, 0};\n\nint main()\n{\n    int n;\n    \n    scanf(\"%d\", &n);\n    \n    printf(\"%d\\n\", a[n - 1]);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bf67d5582e941c07d8180366e8141f40", "src_uid": "a6a804ce23bc48ec825c17d64ac0bb69", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\n#define MODULO 1000000007\n\nint ma[20][20];\nint b[20], col[20];\nint n;\n\nlong long sols[17] = {0,1,0,18,0,1800,0,670320,0,734832000,0,890786230,0,695720788,0,150347555,0};\n\nlong long dfs(int x, int k);\nlong long precalc();\n\nint main(){\n    \n   \t//precalc();\n\n\tint n;\n\tscanf(\"%d\", &n);\n\tprintf(\"%I64d\\n\", sols[n]);\n\n#ifdef _AT_HOME_\n    system(\"pause\");\n#endif\n\n    return 0;\n}\t\n\nlong long dfs(int x, int k){\n\tif (k>n){\n\t\treturn 1;\n\t}\n\tint i;\n\tint t = 0;\n\tfor (i=1;i<=n;i++){\n\t\tif (b[ma[k][i]] || col[i]) continue;\n\t\tb[ma[k][i]] = 1;\n\t\tcol[i] = 1;\n\t\tt +=dfs(i, k+1);\n\t\tb[ma[k][i]] = 0;\n\t\tcol[i] = 0;\n\t}\n\treturn t;\n}\n\nlong long precalc(){\n\tint tt;\n\tfor (tt=1;tt<16;tt+=2){\n\n\t\tint i,j;\n\t    n = tt;\n\n\t    for (i=1;i<=n;i++){\n\t    \tfor (j=1;j<=n;j++){\n\t    \t\tma[i][j] = (i-1+j-1) % n + 1;\n\t    \t}\n\t    }\n\n\t    long long sol = 0;\n\t    for (i=1;i<=1;i++){\n\t    \tb[ma[1][i]] = 1;\n\t    \tcol[i] = 1;\n\t    \tsol += dfs(i, 2);\n\t    \tif (sol>MODULO){\n\t    \t\tsol -= MODULO;\n\t    \t}\n\t    \tb[ma[1][i]] = 0;\n\t    \tcol[i] = 0;\n\t    }\n\n\t    sol *= n;\n\t    sol %= MODULO;\n\n\t    long long fak = 1;\n\t    for (i=2;i<=n;i++){\n\t    \tfak *= i;\n\t    \tfak %= MODULO;\n\t    }\n\n\t    sol *= fak;\n\t    sol %= MODULO;\n\n\t    printf(\"%I64d\\n\", sol);\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "18004b0af4b5c1eda10aa69a93159ba8", "src_uid": "a6a804ce23bc48ec825c17d64ac0bb69", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define MAX 14\n#define PAD  666667\n#define HMOD 15000017\n#define MOD 1000000007\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nlong long fact[20];\nunsigned int n, dp[HMOD + PAD], hashtable[HMOD + PAD];\n\nvoid insert(unsigned int x, int v){\n    int i = ++x % HMOD;\n    while (hashtable[i] && hashtable[i] != x) i++;\n    hashtable[i] = x, dp[i] = v;\n}\n\nint find(unsigned int x){\n    int i = ++x % HMOD;\n    while (hashtable[i] && hashtable[i] != x) i++;\n    return (hashtable[i] == x ? dp[i] : -1);\n}\n\nlong long F(int i, int mask, int lol){\n    if (i == n) return 1;\n    int j, k, h = (mask << 16) ^ lol, v = find(h);\n    if (v != -1) return v;\n\n    long long res = 0;\n    for (j = 0; j < n; j++){\n        if (!(mask & (1 << j))){\n            k = i + j;\n            if (k >= n) k -= n;\n            if (!(lol & (1 << k))) res += F(i + 1, mask | (1 << j), lol | (1 << k));\n        }\n    }\n\n    res %= MOD;\n    insert(h, res);\n    return res;\n}\n\nint main(){\n    int i, j, k;\n    for (fact[0] = 1, i = 1; i < 20; i++) fact[i] = (fact[i - 1] * i) % MOD;\n\n    while (scanf(\"%d\", &n) != EOF){\n        clr(hashtable);\n        if (n & 1) printf(\"%lld\\n\", (fact[n] * F(0, 0, 0)) % MOD);\n        else puts(\"0\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2b8580f5c5f37d047b17441f8a1b13c1", "src_uid": "a6a804ce23bc48ec825c17d64ac0bb69", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint a[8]={1,3,15,133,2025,37851,1030367,36362925};\nint main()\n{\n    int i,n;\n    long long int f=1;\n    scanf(\"%d\",&n);\n    if(n%2==0)\n    {\n        printf(\"0\");\n        return 0;\n    }\n    for(i=1;i<=n;i++)\n        f=(f*i)%1000000007;\n    f=(f*a[n/2])%1000000007;\n    printf(\"%I64d\\n\",f);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "21c41779e56bdc7327922b6dfce910d6", "src_uid": "a6a804ce23bc48ec825c17d64ac0bb69", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\n#define MODULO 1000000007\n\nint ma[20][20];\nint b[20], col[20];\nint n;\n\nlong long sols[17] = {0,1,0,18,0,1800,0,670320,0,734832000,0,890786230,0,695720788,0,150347555,0};\n\nlong long dfs(int x, int k);\nlong long precalc();\n\nint main(){\n    \n   \t//precalc();\n\n\tint n;\n\tscanf(\"%d\", &n);\n\tprintf(\"%I64\\n\", sols[n]);\n\n#ifdef _AT_HOME_\n    system(\"pause\");\n#endif\n\n    return 0;\n}\t\n\nlong long dfs(int x, int k){\n\tif (k>n){\n\t\treturn 1;\n\t}\n\tint i;\n\tint t = 0;\n\tfor (i=1;i<=n;i++){\n\t\tif (b[ma[k][i]] || col[i]) continue;\n\t\tb[ma[k][i]] = 1;\n\t\tcol[i] = 1;\n\t\tt +=dfs(i, k+1);\n\t\tb[ma[k][i]] = 0;\n\t\tcol[i] = 0;\n\t}\n\treturn t;\n}\n\nlong long precalc(){\n\tint tt;\n\tfor (tt=1;tt<16;tt+=2){\n\n\t\tint i,j;\n\t    n = tt;\n\n\t    for (i=1;i<=n;i++){\n\t    \tfor (j=1;j<=n;j++){\n\t    \t\tma[i][j] = (i-1+j-1) % n + 1;\n\t    \t}\n\t    }\n\n\t    long long sol = 0;\n\t    for (i=1;i<=1;i++){\n\t    \tb[ma[1][i]] = 1;\n\t    \tcol[i] = 1;\n\t    \tsol += dfs(i, 2);\n\t    \tif (sol>MODULO){\n\t    \t\tsol -= MODULO;\n\t    \t}\n\t    \tb[ma[1][i]] = 0;\n\t    \tcol[i] = 0;\n\t    }\n\n\t    sol *= n;\n\t    sol %= MODULO;\n\n\t    long long fak = 1;\n\t    for (i=2;i<=n;i++){\n\t    \tfak *= i;\n\t    \tfak %= MODULO;\n\t    }\n\n\t    sol *= fak;\n\t    sol %= MODULO;\n\n\t    printf(\"%I64d\\n\", sol);\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c3e030f3a9f721e3cb02175c2b292537", "src_uid": "a6a804ce23bc48ec825c17d64ac0bb69", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n#define MAXN 55\n#define MAXK 105\n\nstruct datanode\n{\n\tlong long int a, b;\n\tint c, d, orig;\n};\n\nstruct node\n{\n\tchar b;\n\tint j, k;\n};\n\nvoid sort (struct datanode a[MAXN], int l, int r)\n{\n\tint i, j, x;\n\tstruct datanode y;\n\ti = l; j = r; x = a[(l+r)/2].c;\n\twhile (i <= j)\n\t{\n\t\twhile (a[i].c < x) i++;\n\t\twhile (a[j].c > x) j--;\n\t\tif (i <= j)\n\t\t{\n\t\t\ty = a[i]; a[i] = a[j]; a[j] = y;\n\t\t\ti++; j--;\n\t\t}\n\t}\n\tif (l < j) sort(a,l,j);\n\tif (i < r) sort(a,i,r);\n}\n\nint main ()\n{\n\tint N, M, K;\n\tscanf(\"%d %d %d\",&N,&M,&K);\n\tint i, j, j2, k;\n\tstatic struct datanode data[MAXN];\n\tfor (i = 0; i < M; i++)\n\t{\n\t\tscanf(\"%I64i %I64i %d\",&(data[i].a),&(data[i].b),&(data[i].c));\n\t\tdata[i].orig = i;\n\t\tdata[i].d = (int)(data[i].b - data[i].a);\n\t}\n\tsort(data,0,M-1);\n\tstatic struct node a[MAXN][MAXN][MAXK];\n\tmemset(a,0,sizeof(a));\n\tfor (j = 0; j < M; j++)\n\t{\n\t\tfor (k = 0; k <= data[j].d; k++)\n\t\t{\n\t\t\ta[0][j][k].b = 1;\n\t\t\ta[0][j][k].j = -1;\n\t\t\ta[0][j][k].k = -1;\n\t\t}\n\t}\n\tlong long int next;\n\tfor (i = 0; i < (N-1); i++)\n\t{\n\t\tfor (j = 0; j < M; j++)\n\t\t{\n\t\t\tfor (k = 0; k <= data[j].d; k++)\n\t\t\t{\n\t\t\t\tif (a[i][j][k].b)\n\t\t\t\t{\n\t\t\t\t\tfor (j2 = j+1; j2 < M; j2++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (data[j2].c > data[j].c)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\t//k + K\n\t\t\t\t\t\t\tnext = data[j].a + (long long int)(k) + (long long int)(K);\n\t\t\t\t\t\t\tif ((next >= data[j2].a) && (next <= data[j2].b))\n\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\ta[i+1][j2][(int)(next - data[j2].a)].b = 1;\n\t\t\t\t\t\t\t\ta[i+1][j2][(int)(next - data[j2].a)].j = j;\n\t\t\t\t\t\t\t\ta[i+1][j2][(int)(next - data[j2].a)].k = k;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t//k * K\n\t\t\t\t\t\t\tnext = (data[j].a + (long long int)(k)) * (long long int)(K);\n\t\t\t\t\t\t\tif ((next >= data[j2].a) && (next <= data[j2].b))\n\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\ta[i+1][j2][(int)(next - data[j2].a)].b = 1;\n\t\t\t\t\t\t\t\ta[i+1][j2][(int)(next - data[j2].a)].j = j;\n\t\t\t\t\t\t\t\ta[i+1][j2][(int)(next - data[j2].a)].k = k;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor (j = 0; j < M; j++)\n\t{\n\t\tfor (k = 0; k <= data[j].d; k++)\n\t\t{\n\t\t\tif (a[N-1][j][k].b)\n\t\t\t{\n\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\tstatic struct node r[MAXN];\n\t\t\t\tint rc = 1;\n\t\t\t\tr[0].j = j;\n\t\t\t\tr[0].k = k;\n\t\t\t\tfor (i = N-1; i > 0; i--)\n\t\t\t\t{\n\t\t\t\t\tr[rc].j = a[i][r[rc-1].j][r[rc-1].k].j;\n\t\t\t\t\tr[rc].k = a[i][r[rc-1].j][r[rc-1].k].k;\n\t\t\t\t\trc++;\n\t\t\t\t}\n\t\t\t\tfor (i = N-1; i >= 0; i--)\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%d %I64i\\n\",data[r[i].j].orig + 1,data[r[i].j].a + (long long int)(r[i].k));\n\t\t\t\t}\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"NO\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "be6956eaa57d0ce547eb2fa93eff80b6", "src_uid": "c98fdad8e7ce09b8ac389108f72cecd9", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n#include <stdlib.h>\n\n#define N\t100\n#define M\t50\n#define A\t100\n\nstruct V {\n\tlong long a, b;\n\tint c, j;\n} vv[M];\n\nint compare(const void *a, const void *b) {\n\tstruct V *u = (struct V *) a;\n\tstruct V *v = (struct V *) b;\n\n\treturn u->c - v->c;\n}\n\nint main() {\n\tstatic char dp[N][M][A + 1];\n\tstatic int jj[N];\n\tstatic long long aa[N];\n\tstruct V *u, *v;\n\tint n, m, k, i, j, j_, a;\n\tlong long a_, a1, a2;\n\n\tscanf(\"%d%d%d\", &n, &m, &k);\n\tfor (j = 0; j < m; j++) {\n\t\tu = &vv[j];\n\t\tscanf(\"%lld%lld%d\", &u->a, &u->b, &u->c);\n\t\tu->j = j;\n\t}\n\tqsort(vv, m, sizeof *vv, compare);\n\tfor (j = 0; j < m; j++) {\n\t\tu = &vv[j];\n\t\tfor (a = 0; a <= u->b - u->a; a++)\n\t\t\tdp[0][j][a] = 1;\n\t}\n\tfor (i = 0; i < n - 1; i++)\n\t\tfor (j = 0; j < m; j++) {\n\t\t\tu = &vv[j];\n\t\t\tfor (a = 0; a <= u->b - u->a; a++)\n\t\t\t\tif (dp[i][j][a]) {\n\t\t\t\t\ta1 = u->a + a + k, a2 = (u->a + a) * k;\n\t\t\t\t\tfor (j_ = j + 1; j_ < m; j_++) {\n\t\t\t\t\t\tv = &vv[j_];\n\t\t\t\t\t\tif (v->c > u->c) {\n\t\t\t\t\t\t\tif (v->a <= a1 && a1 <= v->b)\n\t\t\t\t\t\t\t\tdp[i + 1][j_][a1 - v->a] = 1;\n\t\t\t\t\t\t\tif (v->a <= a2 && a2 <= v->b)\n\t\t\t\t\t\t\t\tdp[i + 1][j_][a2 - v->a] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t}\n\tfor (j = 0; j < m; j++) {\n\t\tu = &vv[j];\n\t\tfor (a = 0; a <= u->b - u->a; a++)\n\t\t\tif (dp[n - 1][j][a]) {\n\t\t\t\tfor (i = n - 1; i >= 0; i--) {\n\t\t\t\t\tjj[i] = vv[j].j;\n\t\t\t\t\taa[i] = a_ = vv[j].a + a;\n\t\t\t\t\tif (i == 0)\n\t\t\t\t\t\tbreak;\n\t\t\t\t\tfor (j_ = j - 1; j_ >= 0; j_--) {\n\t\t\t\t\t\tv = &vv[j_];\n\t\t\t\t\t\tif (v->c < u->c) {\n\t\t\t\t\t\t\tif (v->a <= a_ - k && a_ - k <= v->b) {\n\t\t\t\t\t\t\t\ta = a_ - k - v->a;\n\t\t\t\t\t\t\t\tif (dp[i - 1][j_][a]) {\n\t\t\t\t\t\t\t\t\tj = j_;\n\t\t\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif (a_ % k == 0)\n\t\t\t\t\t\t\t\tif (v->a <= a_ / k && a_ / k <= v->b) {\n\t\t\t\t\t\t\t\t\ta = a_ / k - v->a;\n\t\t\t\t\t\t\t\t\tif (dp[i - 1][j_][a]) {\n\t\t\t\t\t\t\t\t\t\tj = j_;\n\t\t\t\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\tfor (i = 0; i < n; i++)\n\t\t\t\t\tprintf(\"%d %lld\\n\", jj[i] + 1, aa[i]);\n\t\t\t\treturn 0;\n\t\t\t}\n\t}\n\tprintf(\"NO\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c5cf40282565a68db58d61f561815de4", "src_uid": "c98fdad8e7ce09b8ac389108f72cecd9", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n\ntypedef long long ll;\n\ntypedef struct {\n  ll a,b;\n  int c;\n} t_t;\n\n/*  n days, m subjects */\nint n,m,K;\nt_t emne[150];\n\n/*  [i][j][k]: at beginning of day i (0-indexed), j is last course taken\n    (1-indexed, 0=no course taken yet), k:last number of exercises=a_j+k */\nll dp[51][52][101];\nint dp1[51][52][101];\nint dp2[51][52][101];\n\nvoid solve() {\n  int i,j,k,l,nextj,nextk;\n  ll diff,nextd,cur,next;\n  memset(dp,-1,sizeof(dp));\n  memset(dp2,-1,sizeof(dp2));\n  memset(dp2,-1,sizeof(dp2));\n  dp[0][0][0]=0;\n  dp1[0][0][0]=-1;\n  dp2[0][0][0]=0;\n  for(i=0;i<n;i++) {\n    for(j=0;j<=m;j++) for(k=0;k<101;k++) if(dp[i][j][k]>-1) {\n      cur=dp[i][j][k];\n      /*  pick next exercise */\n/*      if(!j) printf(\"at day %d, no last course\\n\",i);\n      else printf(\"at day %d, last course %d, last ex %I64d\\n\",i,j-1,k+emne[j-1].a);*/\n      if(i==0 && j==0) {\n        /*  first day, can pick everything */\n        for(nextj=0;nextj<m;nextj++) for(nextk=0;nextk<=(int)(emne[nextj].b-emne[nextj].a);nextk++) {\n          dp[i+1][nextj+1][nextk]=nextk+emne[nextj].a;\n          dp1[i+1][nextj+1][nextk]=k;\n          dp2[i+1][nextj+1][nextk]=j;\n        }\n      } else for(l=0;l<m;l++) if(emne[l].c>emne[j-1].c) {\n        /*  difficulty: add k */\n        diff=k+emne[j-1].a;\n        nextd=diff+K;\n        next=cur+nextd;\n        if(nextd>=emne[l].a && nextd<=emne[l].b && next>dp[i+1][l+1][(int)(nextd-emne[l].a)]) {\n          dp[i+1][l+1][(int)(nextd-emne[l].a)]=next;\n          dp1[i+1][l+1][(int)(nextd-emne[l].a)]=k;\n          dp2[i+1][l+1][(int)(nextd-emne[l].a)]=j;\n/*          printf(\"  (add) can pick => %d %d %I64d\\n\",i+1,l,nextd);*/\n        }\n        /*  difficulty: mul k */\n        nextd=diff*K;\n        next=cur+nextd;\n        if(nextd>=emne[l].a && nextd<=emne[l].b && next>dp[i+1][l+1][(int)(nextd-emne[l].a)]) {\n          dp[i+1][l+1][(int)(nextd-emne[l].a)]=next;\n          dp1[i+1][l+1][(int)(nextd-emne[l].a)]=k;\n          dp2[i+1][l+1][(int)(nextd-emne[l].a)]=j;\n/*          printf(\"  (mul) can pick => %d %d %I64d\\n\",i+1,l,nextd);*/\n        }\n      }\n    }\n  }\n}\n\nint fag[100];\nll ex[100];\n\n/*  x: last course (1-indexed), y:last k-value */\nvoid timeplan(int x,int y) {\n  int dag=n;\n  int i,j;\n  while(dag) {\n    fag[dag-1]=x;\n    ex[dag-1]=y+emne[x-1].a;\n    i=dp2[dag][x][y];\n    j=dp1[dag][x][y];\n    dag--;\n    x=i;\n    y=j;\n  }\n  for(i=0;i<n;i++) printf(\"%d %I64d\\n\",fag[i],ex[i]);\n}\n\nint main() {\n  int i,j;\n  ll maks=0;\n  int besti=-1,bestj=0;\n  scanf(\"%d %d %d\",&n,&m,&K);\n  for(i=0;i<m;i++) scanf(\"%I64d %I64d %d\",&emne[i].a,&emne[i].b,&emne[i].c);\n  solve();\n  for(i=1;i<=m;i++) for(j=0;j<=100;j++) if(dp[n][i][j]>maks) {\n    maks=dp[n][i][j];\n    besti=i;\n    bestj=j;\n  }\n  if(besti<0) puts(\"NO\");\n  else {\n    puts(\"YES\");\n    timeplan(besti,bestj);\n    return 0;\n  }\n  puts(\"NO\");\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e6ebbcad969aeebe7ac0be1ddc856a16", "src_uid": "c98fdad8e7ce09b8ac389108f72cecd9", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\ntypedef struct {\n     long long a;\n     long long b;\n     int c;\n     int i;\n} subjects;\n\nlong long dp[50][51][101][2];\n\nint cmp(const void *a, const void *b)\n{\n     if (((subjects *)a)->c != ((subjects *)b)->c) {\n\t  return ((subjects *)a)->c - ((subjects *)b)->c;\n     }\n}\n\nint main()\n{\n     int n, m, k, i, j, l, p, q;\n     long long x = 0;\n     subjects s[50];\n     int a[50];\n     long long b[50];\n\n     scanf(\"%d %d %d\", &n, &m, &k);\n\n     for (i = 0; i < m; i++) {\n\t  scanf(\"%I64d %I64d %d\", &s[i].a, &s[i].b, &s[i].c);\n\n\t  s[i].i = i;\n     }\n\n     qsort(s, m, sizeof(subjects), cmp);\n\n     for (i = 0; i < m; i++) {\n\t  for (j = 0; j <= n; j++) {\n\t       for (l = 0; l <= 100; l++) {\n\t\t    dp[i][j][l][0] = -1;\n\t       }\n\t  }\n     }\n\n     for (i = 0; i < m; i++) {\n\t  for (j = 0; j <= s[i].b - s[i].a; j++) {\n\t       dp[i][1][j][0] = s[i].a + j;\n\t  }\n     }\n\n     for (i = 0; i < m; i++) {\n\t  for (j = 1; j < n; j++) {\n\t       for (l = 0; l <= s[i].b - s[i].a; l++) {\n\t\t    if (dp[i][j][l][0] == -1) continue;\n\n\t\t    for (p = i + 1; p < m; p++) {\n\t\t\t if (s[i].c == s[p].c) continue;\n\n\t\t\t if (l + s[i].a + k >= s[p].a && l + s[i].a + k <= s[p].b) {\n\t\t\t      if (dp[p][j + 1][l + s[i].a + k - s[p].a][0] == -1 || dp[p][j + 1][l + s[i].a + k - s[p].a][0] < dp[i][j][l][0] + l + s[i].a + k) {\n\t\t\t\t   dp[p][j + 1][l + s[i].a + k - s[p].a][0] = dp[i][j][l][0] + l + s[i].a + k;\n\t\t\t\t   dp[p][j + 1][l + s[i].a + k - s[p].a][1] = i;\n\t\t\t\t   dp[p][j + 1][l + s[i].a + k - s[p].a][2] = l;\n\t\t\t      }\n\t\t\t }\n\n\t\t\t if ((l + s[i].a) * k >= s[p].a && (l + s[i].a) * k <= s[p].b) {\n\t\t\t      if (dp[p][j + 1][(l + s[i].a) * k - s[p].a][0] = -1 || dp[p][j + 1][(l + s[i].a) * k - s[p].a][0] < dp[i][j][l][0] + (l + s[i].a) * k) {\n\t\t\t\t   dp[p][j + 1][(l + s[i].a) * k - s[p].a][0] = dp[i][j][l][0] + (l + s[i].a) * k;\n\t\t\t\t   dp[p][j + 1][(l + s[i].a) * k - s[p].a][1] = i;\n\t\t\t\t   dp[p][j + 1][(l + s[i].a) * k - s[p].a][2] = l;\n\t\t\t      }\n\t\t\t }\n\t\t    }\n\t       }\n\t  }\n     }\n\n     for (i = 0; i < m; i++) {\n\t  for (j = 0; j <= s[i].b - s[i].a; j++) {\n\t       if (dp[i][n][j][0] > x) {\n\t\t    x = dp[i][n][j][0];\n\t\t    p = i;\n\t\t    q = j;\n\t       }\n\t  }\n     }\n\n     if (x == 0) {\n\t  puts(\"NO\");\n     } else {\n\t  puts(\"YES\");\n\n\t  for (i = 0; i < n; i++) {\n\t       int tmp = dp[p][n - i][q][2];\n\n\t       a[n - i - 1] = s[p].i + 1;\n\t       b[n - i - 1] = s[p].a + q;\n\n\t       p = dp[p][n - i][q][1];\n\t       q = tmp;\n\t  }\n\n\t  for (i = 0; i < n; i++) printf(\"%d %I64d\\n\", a[i], b[i]);\n     }\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4095c329e61eca8f49f81e874c4816bc", "src_uid": "c98fdad8e7ce09b8ac389108f72cecd9", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n\ntypedef long long ll;\n\ntypedef struct {\n  ll a,b;\n  int c;\n} t_t;\n\n/*  n days, m subjects */\nint n,m,K;\nt_t emne[150];\n\n/*  [i][j][k]: at beginning of day i (0-indexed), j is last course taken\n    (1-indexed, 0=no course taken yet), k:last number of exercises=a_j+k */\n/*  -1 state doesn't exist, otherwise dp1 is last k-value,\n    dp2 is last course before that */\nint dp[51][52][101];\nint dp2[51][52][101];\n\nvoid solve() {\n  int i,j,k,l,nextj,nextk;\n  ll diff,nextd;\n  memset(dp,-1,sizeof(dp));\n  memset(dp2,-1,sizeof(dp2));\n  dp[0][0][0]=999;\n  for(i=0;i<n;i++) {\n    for(j=0;j<=m;j++) for(k=0;k<101;k++) if(dp[i][j][k]>-1) {\n      /*  pick next exercise */\n/*      if(!j) printf(\"at day %d, no last course\\n\",i);\n      else printf(\"at day %d, last course %d, last ex %I64d\\n\",i,j-1,k+emne[j-1].a);*/\n      if(i==0 && k==0) {\n        /*  first day, can pick everything */\n        for(nextj=0;nextj<m;nextj++) for(nextk=0;nextk<=(int)(emne[nextj].b-emne[nextj].a);nextk++) {\n          dp[i+1][nextj+1][nextk]=k;\n          dp2[i+1][nextj+1][nextk]=j;\n        }\n      } else for(l=0;l<m;l++) if(emne[l].c>emne[j-1].c) {\n        /*  difficulty: add k */\n        diff=k+emne[j-1].a;\n        nextd=diff+K;\n        if(nextd>=emne[l].a && nextd<=emne[l].b) {\n          dp[i+1][l+1][(int)(nextd-emne[l].a)]=k;\n          dp2[i+1][l+1][(int)(nextd-emne[l].a)]=j;\n/*          printf(\"  (add) can pick => %d %d %I64d\\n\",i+1,l,nextd);*/\n        }\n        /*  difficulty: mul k */\n        if((double)nextd*K>1e16) continue;\n        nextd=diff*K;\n        if(nextd>=emne[l].a && nextd<=emne[l].b) {\n          dp[i+1][l+1][(int)(nextd-emne[l].a)]=k;\n          dp2[i+1][l+1][(int)(nextd-emne[l].a)]=j;\n/*          printf(\"  (mul) can pick => %d %d %I64d\\n\",i+1,l,nextd);*/\n        }\n      }\n    }\n  }\n}\n\nint fag[100];\nll ex[100];\n\n/*  x: last course (1-indexed), y:last k-value */\nvoid timeplan(int x,int y) {\n  int dag=n;\n  int i,j;\n  while(dag) {\n    fag[dag-1]=x;\n    ex[dag-1]=y+emne[x-1].a;\n    i=dp2[dag][x][y];\n    j=dp[dag][x][y];\n    dag--;\n    x=i;\n    y=j;\n  }\n  for(i=0;i<n;i++) printf(\"%d %I64d\\n\",fag[i],ex[i]);\n}\n\nint main() {\n  int i,j;\n  scanf(\"%d %d %d\",&n,&m,&K);\n  for(i=0;i<m;i++) scanf(\"%I64d %I64d %d\",&emne[i].a,&emne[i].b,&emne[i].c);\n  solve();\n  for(i=1;i<=m;i++) for(j=0;j<=100;j++) if(dp[n][i][j]>-1) {\n    puts(\"YES\");\n    timeplan(i,j);\n    return 0;\n  }\n  puts(\"NO\");\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a1e36382913832959d0c0d9c8bca7d42", "src_uid": "c98fdad8e7ce09b8ac389108f72cecd9", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n\n#define MAX_N (5000)\n#define MAX_K (5000)\n#define MOD   (1000000007)\n\nint n,b;\nint memo[MAX_N+1][MAX_K+1];\n\nint min(int x, int y) { return x < y ? x : y; }\n\nint max(int x, int y) { return x > y ? x : y; }\n\nint f(int x, int t) {\n  int i,acc=0;\n\n  if ( !t )\n    return 1;\n  if ( (x-b)*(x-b) == 1 )\n    return 0;\n  if ( memo[x][t] )\n    return memo[x][t];\n  for ( i=max(1, x-abs(x-b)-1); i < min(n, x+abs(x-b)); ++i ) {\n    if ( i == x ) continue;\n    acc = (acc + f(i, t-1)) % MOD;\n  }\n  return memo[x][t] = acc;\n}\n\nint main() {\n  int a,k;\n\n  scanf(\"%d %d %d %d\", &n, &a, &b, &k);\n  printf(\"%d\\n\", f(a, k));\n  return EXIT_SUCCESS;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8f8ac48daa548b9abdd3a5719ca8d78e", "src_uid": "142b06ed43b3473513995de995e19fc3", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\nint max(int a , int b){\n\tif(a  >b)\n\t\treturn a ;\n\treturn b ;\n}\nint min(int a, int b){\n\tif(a  < b)\n\t\treturn a ;\n\treturn b ;\n}\n\nlong long dpp[5002][5002];\nint n , a , b , k ;\n\n#define MOD 1000000007\n\nvoid build(long long arr[] , long long rmq []){\n\tint i ;\n\tfor(i = 1 ; i <= n ; i++){\n\t\t// cout << arr[i] << \" \" ;\n\t\tint index = i ;\n\t\twhile(index <= n){\n\t\t\trmq[index] += arr[i] ;\n\t\t\tindex += (index & -index);\n\t\t}\n\t}\n\t//cout << endl ;\n}\n\nlong long query(long long rmq [] , int to){\n\tlong long ret = 0 ;\n\t// cout << \"to : \" << to << \" : \"  ;\n\twhile(to > 0){\n\t\tret += rmq[to];\n\t\tret %= MOD ;\n\t\tto -= (to & -to);\n\t}\n\t//cout <<ret << endl ;\n\treturn ret ;\n}\n\nint main(){\n\tscanf(\"%d%d%d%d\" , & n , &a , &b , &k);\n\tint i ;\n\tfor(i = 1 ; i <= n ; i ++){\n\t\tdpp[0][i] = 1 ;\n\t}\n\tdpp[0][b] = 0 ;\n\tfor(i =  1 ; i <= k ; i++){\n\t\t// cout << i << \" : \" << endl ;\n\t\tlong long rmq [10003] ={0};\n\t\tbuild(dpp[i-1] , rmq);\n\t\tint j ;\n\t\tfor(j = 1 ; j <= n; j++){\n\t\t\tif(j == b)\n\t\t\t\tcontinue ;\n\t\t\tint diff = abs(b - j) - 1;\n\t\t\tdpp[i][j] = query(rmq , min(n , j + diff));\n\t\t\tdpp[i][j] -= query(rmq , max(1 , j - diff) -1 );\n\t\t\tdpp[i][j] -= dpp[i-1][j];\n\t\t\tdpp[i][j] %= MOD ;\n\t\t\tdpp[i][j] += MOD ;\n\t\t\tdpp[i][j] %= MOD ;\n\t\t}\n\t\t// cout << i << \" :  => \" << endl ;\n\t\t// for(int j = 1 ; j <= n ; j++){\n\t\t// \tcout << dpp[i][j] << \" \";\n\t\t// }\n\t\t//cout << endl ;\n\t}\n\tprintf(\"%d\" , dpp[k][a]);\n\treturn 0 ;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "cadf5b97afbe5873c2f2836c5053dc5f", "src_uid": "142b06ed43b3473513995de995e19fc3", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n\nint mem [5001][5001];\nint N, b, a, K;\nint MOD = 1000000007;\n\nint min(int a, int b)\t{\n\treturn\ta < b ? a : b;\n}\nint max(int a, int b)\t{\n\treturn\ta > b ? a : b;\n}\n\nint solve(int id, int restan)\t{\n\tif\t( restan == 0 )\n\t\treturn\t1;\n\t\n\tif\t( mem[id][restan] != -1 )\n\t\treturn\tmem[id][restan];\n\t\n\tint dist = abs(b - id);\n\tint ans = 0;\n\tint y;\n\tfor (y = max(1, id - dist + 1); y <= min(N, id + dist - 1); y++)\t{\n\t\tif\t( y != b && y != id )\t{\n\t\t\tans += solve(y, restan - 1);\n\t\t\tif\t( ans >= MOD )\n\t\t\t\tans -= MOD;\n\t\t}\n\t}\n\treturn\tmem[id][restan] = ans;\n}\n\n\n\nint main(int argc, char *argv[])\t{\n\tscanf(\"%d %d %d %d\", &N, &a, &b, &K);\n\t\n\tint i, j, id, k, dist, x, y, sum;\n\t\n\t/*\n\tfor (i = 1; i <= N; i++)\t{\n\t\tfor (j = 1; j <= K; j++)\t{\n\t\t\tmem[i][j] = -1;\n\t\t}\n\t}\n\t*/\n\t\n\tfor (id = 1; id <= N; id++)\t{\n\t\tmem[id][0] = 1;\n\t}\n\tmem[b][0] = 0;\n\t\n\tfor (k = 1; k <= K; k++)\t{\n\t\tfor (id = 1; id <= N; id++)\t{\n\t\t\tdist = abs(id - b);\n\t\t\tx = max( 1, id - dist + 1 );\n\t\t\ty = min( N, id + dist - 1 );\n\t\t\t\n\t\t\tsum = 0;\n\t\t\twhile\t( x <= y )\t{\n\t\t\t\tsum += mem[x++][k - 1];\n\t\t\t\tif\t( sum >= MOD )\n\t\t\t\t\tsum -= MOD;\n\t\t\t}\n\t\t\t\n\t\t\tsum -= mem[b][k - 1];\n\t\t\tif\t( sum < 0 )\n\t\t\t\tsum = (sum + MOD);\n\t\t\t\n\t\t\tsum -= mem[id][k - 1];\n\t\t\t\n\t\t\tif\t( sum < 0 )\n\t\t\t\tsum = (sum + MOD);\n\t\t\t\n\t\t\tmem[id][k] = sum;\n\t\t}\n\t}\n\t/*\n\tfor (i = 1; i <= N; i++)\t{\n\t\tfor (j = 0; j <= K; j++)\t{\n\t\t\tprintf( \"mem(%d, %d) = %d\\n\", i, j, mem[i][j] );\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n\t*/\n\tprintf( \"%d\\n\", mem[a][K] );\n\t\n    return 0;\n}\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5c55169b22d5415a6a937f2498eafa59", "src_uid": "142b06ed43b3473513995de995e19fc3", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n\nint mem [5001][5001];\nint N, b, a, K;\nint MOD = 1000000007;\n\nint min(int a, int b)\t{\n\treturn\ta < b ? a : b;\n}\nint max(int a, int b)\t{\n\treturn\ta > b ? a : b;\n}\n\nint solve(int id, int restan)\t{\n\tif\t( restan == 0 )\n\t\treturn\t1;\n\t\n\tif\t( mem[id][restan] != -1 )\n\t\treturn\tmem[id][restan];\n\t\n\tint dist = abs(b - id);\n\tint ans = 0;\n\tint y;\n\tfor (y = max(1, id - dist + 1); y <= min(N, id + dist - 1); y++)\t{\n\t\tif\t( y != b && y != id )\t{\n\t\t\tans += solve(y, restan - 1);\n\t\t\tif\t( ans >= MOD )\n\t\t\t\tans -= MOD;\n\t\t}\n\t}\n\treturn\tmem[id][restan] = ans;\n}\n\n\n\nint main(int argc, char *argv[])\t{\n\tscanf(\"%d %d %d %d\", &N, &a, &b, &K);\n\t\n\tint i, j;\n\ti = j = 1;\n\t\n\tfor (i = 1; i <= N; i++)\t{\n\t\tfor (j = 1; j <= K; j++)\t{\n\t\t\tmem[i][j] = -1;\n\t\t}\n\t}\n\t\n\tprintf( \"%d\\n\", solve(a, K) );\n\t\n    return 0;\n}\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "89e434b5bfb02fb62224422f97a04c19", "src_uid": "142b06ed43b3473513995de995e19fc3", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MOD 1000000007\nint n,m,s;\nlong long f[5010][5010],g[5010][5010];\nint main()\n{\n\tint i,j,t;\n\tscanf(\"%d%d%d%d\",&t,&s,&n,&m);\n\tif(s>n) { s = t-s+1; n = t-n+1;}\n\tif(n-s == 1) { printf(\"0\"); return 0;}\n\tf[0][s] = 1;\n\tfor(i=s;i<n;i++) g[0][i] = 1;\n\tfor(i=1;i<=m;i++) for(j=1;j<n;j++)\n\t{\n\t\tf[i][j] = (g[i-1][(n-j-1)/2+j]-f[i-1][j]+MOD)%MOD;\n\t\tg[i][j] = (g[i][j-1]+f[i][j])%MOD;\n\t}\n\tprintf(\"%I64d\",g[m][n-1]);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "89cb690d702b6e9b94e5e9e43366e4bb", "src_uid": "142b06ed43b3473513995de995e19fc3", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint cmp(long long a, long long b) {\n\treturn a == b ? 0 : a < b ? -1 : 1;\n}\n\nint main() {\n\tint n, i, j, zero;\n\tlong long k, l, r, cnt, a, a_;\n\n\tscanf(\"%d%lld\", &n, &k);\n\tl = 1;\n\tr = 1LL << (n / 2 - 1);\n\tcnt = (l + r) * (r - l + 1);\n\tif (n % 2 == 1)\n\t\tcnt = cnt + (cnt - (r - l + 1));\n\tif (k >= cnt) {\n\t\tprintf(\"-1\\n\");\n\t\treturn 0;\n\t}\n\tprintf(\"0\");\n\ta = 0;\n\tfor (i = 1; i < n / 2; i++) {\n\t\tl = (1LL << (n / 2 - 1)) - a;\n\t\tr = l + ((1LL << (n / 2 - 1 - i)) - 1);\n\t\tcnt = (l + r) * (r - l + 1);\n\t\tif (n % 2 == 1)\n\t\t\tcnt = cnt + (cnt - (r - l + 1));\n\t\tif (k >= cnt) {\n\t\t\tk -= cnt;\n\t\t\ta |= 1LL << (n / 2 - 1 - i);\n\t\t\tprintf(\"1\");\n\t\t} else\n\t\t\tprintf(\"0\");\n\t}\n\tzero = 1;\n\tif (n % 2 == 1) {\n\t\tl = r = (1LL << (n / 2 - 1)) - a;\n\t\tcnt = (l + r) * (r - l + 1);\n\t\tif (k >= cnt) {\n\t\t\tk -= cnt;\n\t\t\tzero = 0;\n\t\t\tprintf(\"1\");\n\t\t} else {\n\t\t\tzero = 1;\n\t\t\tprintf(\"0\");\n\t\t}\n\t}\n\ta_ = 0;\n\tfor (i = (n + 1) / 2; i < n; i++) {\n\t\tint cmp1 = cmp(a_, a % (1LL << (i - (n - 1) / 2)));\n\t\tint cmp2 = cmp(a_ ^ ((1LL << (i - (n - 1) / 2)) - 1), a % (1LL << (i - (n - 1) / 2)));\n\n\t\tcnt = 0;\n\t\tfor (j = n - 2; j > i; j--)\n\t\t\tif ((a & 1LL << (j - i)) == 0)\n\t\t\t\tcnt += 1LL << (j - i - 1);\n\t\tcnt *= 2;\n\t\tif (cmp1 >= 0)\n\t\t\tcnt++;\n\t\tif (i < n - 1 && (cmp2 > 0 || (cmp2 == 0 && zero)))\n\t\t\tcnt++;\n\t\tif (k >= cnt) {\n\t\t\tk -= cnt;\n\t\t\ta_ |= 1LL << (n - 1 - i);\n\t\t\tprintf(\"1\");\n\t\t} else\n\t\t\tprintf(\"0\");\n\t}\n\tprintf(\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "422f2460a502c32d95efbf62f2d89a30", "src_uid": "0a4a418dafaee71f1b31c928fc2ad24a", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint cmp(long long a, long long b) {\n\treturn a == b ? 0 : a < b ? -1 : 1;\n}\n\nint main() {\n\tint n, i, j, zero;\n\tlong long k, l, r, cnt, a, a_;\n\n\tscanf(\"%d%lld\", &n, &k);\n\tl = 1;\n\tr = 1LL << (n / 2 - 1);\n\tcnt = (l + r) * (r - l + 1);\n\tif (n % 2 == 1)\n\t\tcnt = cnt + (cnt - (r - l + 1));\n\tif (k >= cnt) {\n\t\tprintf(\"-1\\n\");\n\t\treturn 0;\n\t}\n\tprintf(\"0\");\n\ta = 0;\n\tfor (i = 1; i < n / 2; i++) {\n\t\tl = (1LL << (n / 2 - 1)) - a;\n\t\tr = l + ((1LL << (n / 2 - 1 - i)) - 1);\n\t\tcnt = (l + r) * (r - l + 1);\n\t\tif (n % 2 == 1)\n\t\t\tcnt = cnt + (cnt - (r - l + 1));\n\t\tif (k >= cnt) {\n\t\t\tk -= cnt;\n\t\t\ta |= 1LL << (n / 2 - 1 - i);\n\t\t\tprintf(\"1\");\n\t\t} else\n\t\t\tprintf(\"0\");\n\t}\n\tzero = 1;\n\tif (n % 2 == 1) {\n\t\tl = r = (1LL << (n / 2 - 1)) - a;\n\t\tcnt = (l + r) * (r - l + 1);\n\t\tif (k >= cnt) {\n\t\t\tk -= cnt;\n\t\t\tzero = 0;\n\t\t\tprintf(\"1\");\n\t\t} else {\n\t\t\tzero = 1;\n\t\t\tprintf(\"0\");\n\t\t}\n\t}\n\ta_ = 0;\n\tfor (i = (n + 1) / 2; i < n; i++) {\n\t\tint cmp1 = cmp(a_, a % (1LL << (i - (n - 1) / 2)));\n\t\tint cmp2 = cmp(a_ ^ ((1LL << (i - (n - 1) / 2)) - 1), a % (1LL << (i - (n - 1) / 2)));\n\n\t\tcnt = 0;\n\t\tfor (j = n - 2; j > i; j--)\n\t\t\tif ((a & 1LL << (j - i)) == 0)\n\t\t\t\tcnt += 1LL << (j - i - 1);\n\t\tcnt *= 2;\n\t\tif (cmp1 > 0 || (cmp1 == 0 && zero))\n\t\t\tcnt++;\n\t\tif (i < n - 1 && (cmp2 > 0 || (cmp2 == 0 && zero)))\n\t\t\tcnt++;\n\t\tif (k >= cnt) {\n\t\t\tk -= cnt;\n\t\t\ta_ |= 1LL << (n - 1 - i);\n\t\t\tprintf(\"1\");\n\t\t} else\n\t\t\tprintf(\"0\");\n\t}\n\tprintf(\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dc337c67faae276a23c64b98cbcb5dcb", "src_uid": "0a4a418dafaee71f1b31c928fc2ad24a", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint cmp(long long a, long long b) {\n\treturn a == b ? 0 : a < b ? -1 : 1;\n}\n\nint main() {\n\tint n, i, j, zero;\n\tlong long k, l, r, cnt, a, a_;\n\n\tscanf(\"%d%lld\", &n, &k);\n\tl = 1;\n\tr = 1LL << (n / 2 - 1);\n\tcnt = (l + r) * (r - l + 1);\n\tif (n % 2 == 1)\n\t\tcnt = cnt + (cnt - (r - l + 1));\n\tif (k >= cnt) {\n\t\tprintf(\"-1\\n\");\n\t\treturn 0;\n\t}\n\tprintf(\"0\");\n\ta = 0;\n\tfor (i = 1; i < n / 2; i++) {\n\t\tr = (1LL << (n / 2 - 1)) - a;\n\t\tl = r - ((1LL << (n / 2 - 1 - i)) - 1);\n\t\tcnt = (l + r) * (r - l + 1);\n\t\tif (n % 2 == 1)\n\t\t\tcnt = cnt + (cnt - (r - l + 1));\n\t\tif (k >= cnt) {\n\t\t\tk -= cnt;\n\t\t\ta |= 1LL << (n / 2 - 1 - i);\n\t\t\tprintf(\"1\");\n\t\t} else\n\t\t\tprintf(\"0\");\n\t}\n\tzero = 1;\n\tif (n % 2 == 1) {\n\t\tl = r = (1LL << (n / 2 - 1)) - a;\n\t\tcnt = (l + r) * (r - l + 1);\n\t\tif (k >= cnt) {\n\t\t\tk -= cnt;\n\t\t\tzero = 0;\n\t\t\tprintf(\"1\");\n\t\t} else {\n\t\t\tzero = 1;\n\t\t\tprintf(\"0\");\n\t\t}\n\t}\n\ta_ = 0;\n\tfor (i = (n + 1) / 2; i < n; i++) {\n\t\tint cmp1 = cmp(a_, a % (1LL << (i - (n - 1) / 2)));\n\t\tint cmp2 = cmp(a_ ^ ((1LL << (i - (n - 1) / 2)) - 1), a % (1LL << (i - (n - 1) / 2)));\n\n\t\tcnt = 0;\n\t\tfor (j = n - 2; j > i; j--)\n\t\t\tif ((a & 1LL << (j - i)) == 0)\n\t\t\t\tcnt += 1LL << (j - i - 1);\n\t\tcnt *= 2;\n\t\tif (cmp1 >= 0)\n\t\t\tcnt++;\n\t\tif (i < n - 1 && (cmp2 > 0 || (cmp2 == 0 && zero)))\n\t\t\tcnt++;\n\t\tif (k >= cnt) {\n\t\t\tk -= cnt;\n\t\t\ta_ |= 1LL << (i - (n + 1) / 2);\n\t\t\tprintf(\"1\");\n\t\t} else\n\t\t\tprintf(\"0\");\n\t}\n\tprintf(\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "53ddd00204aff8d69419e33e201e1ccc", "src_uid": "0a4a418dafaee71f1b31c928fc2ad24a", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint cmp(long long a, long long b) {\n\treturn a == b ? 0 : a < b ? -1 : 1;\n}\n\nint main() {\n\tint n, i, j, zero;\n\tlong long k, l, r, cnt, a, a_;\n\n\tscanf(\"%d%lld\", &n, &k);\n\tl = 1;\n\tr = 1LL << (n / 2 - 1);\n\tcnt = (l + r) * (r - l + 1);\n\tif (n % 2 == 1)\n\t\tcnt = cnt + (cnt - (r - l + 1));\n\tif (k >= cnt) {\n\t\tprintf(\"-1\\n\");\n\t\treturn 0;\n\t}\n\tprintf(\"0\");\n\ta = 0;\n\tfor (i = 1; i < n / 2; i++) {\n\t\tr = (1LL << (n / 2 - 1)) - a;\n\t\tl = r - ((1LL << (n / 2 - 1 - i)) - 1);\n\t\tcnt = (l + r) * (r - l + 1);\n\t\tif (n % 2 == 1)\n\t\t\tcnt = cnt + (cnt - (r - l + 1));\n\t\tif (k >= cnt) {\n\t\t\tk -= cnt;\n\t\t\ta |= 1LL << (n / 2 - 1 - i);\n\t\t\tprintf(\"1\");\n\t\t} else\n\t\t\tprintf(\"0\");\n\t}\n\tzero = 1;\n\tif (n % 2 == 1) {\n\t\tl = r = (1LL << (n / 2 - 1)) - a;\n\t\tcnt = (l + r) * (r - l + 1);\n\t\tif (k >= cnt) {\n\t\t\tk -= cnt;\n\t\t\tzero = 0;\n\t\t\tprintf(\"1\");\n\t\t} else {\n\t\t\tzero = 1;\n\t\t\tprintf(\"0\");\n\t\t}\n\t}\n\ta_ = 0;\n\tfor (i = (n + 1) / 2; i < n; i++) {\n\t\tint cmp1 = cmp(a_, a % (1LL << (i - (n - 1) / 2)));\n\t\tint cmp2 = cmp(a_ ^ ((1LL << (i - (n - 1) / 2)) - 1), a % (1LL << (i - (n - 1) / 2)));\n\n\t\tcnt = 0;\n\t\tfor (j = n - 2; j > i; j--)\n\t\t\tif ((a & 1LL << (n / 2 - 1 - (n - 1 - j))) == 0)\n\t\t\t\tcnt += 1LL << (j - i - 1);\n\t\tcnt *= 2;\n\t\tif (cmp1 >= 0)\n\t\t\tcnt++;\n\t\tif (i < n - 1 && (cmp2 > 0 || (cmp2 == 0 && zero)))\n\t\t\tcnt++;\n\t\tif (k >= cnt) {\n\t\t\tk -= cnt;\n\t\t\ta_ |= 1LL << (i - (n + 1) / 2);\n\t\t\tprintf(\"1\");\n\t\t} else\n\t\t\tprintf(\"0\");\n\t}\n\tprintf(\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f713d72b408af6096824ca7486f2dc36", "src_uid": "0a4a418dafaee71f1b31c928fc2ad24a", "difficulty": 2600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint n, m[17], r[17], max=0, dem=0;\n\tdouble ans;\n\tscanf(\"%d\",&n);\n\tfor (int i=1;i<=n;i++) \n\t{\n\t\tscanf(\"%d\",&m[i]);\n\t\tif (max<m[i]) max=m[i];\n\t}\n\tfor (int i=1;i<=n;i++) scanf(\"%d\",&r[i]);\n\tif (n==1) ans=1/(double)max;\n\telse\n\t{\n\tfor (int i=1;i<=max;i++)\n\t{\n\t\tfor (int j=1;j<=n;j++)\n\t\t{\n\t\t\tif (i%m[j]==r[j])\n\t\t\t{\n\t\t\t\tdem++;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tans=(double)dem/max;\n\t}\n\tprintf(\"%f\",ans);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a0de9090d6af00227849b3e60592ae36", "src_uid": "14b69f42bc192ea472e82f3a3209f1c1", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    long long int n,i,j;\n    double res,c=0.0;\n    scanf(\"%I64d\",&n);\n    long long int a[n],b[n];\n    for(i=0;i<n;i++)\n        scanf(\"%I64d\",&a[i]);\n    for(i=0;i<n;i++)\n        scanf(\"%I64d\",&b[i]);\n\n    for(i=0;i<=n;i++)\n    {\n        for(j=0;j<n;j++)\n        {\n            if(i%a[j]==b[j])\n                c+=1.0;\n        }\n    }\n    printf(\"%lf\",c/(n+1));\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "18bb9541bfd5f54d3044da1a2d5922c2", "src_uid": "14b69f42bc192ea472e82f3a3209f1c1", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint n, m[17], r[17], dem=0;\n\tlong max=10000000;\n\tdouble ans;\n\tscanf(\"%d\",&n);\n\tfor (int i=1;i<=n;i++) scanf(\"%d\",&m[i]);\n\tfor (int i=1;i<=n;i++) scanf(\"%d\",&r[i]);\n\tif (n==1) ans=1/(double)max;\n\telse\n\t{\n\tfor (long i=1;i<=max;i++)\n\t{\n\t\tfor (long j=1;j<=n;j++)\n\t\t{\n\t\t\tif (i%m[j]==r[j])\n\t\t\t{\n\t\t\t\tdem++;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tans=(double)dem/max;\n\t}\n\tprintf(\"%f\",ans);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "841091f706f9e54487e48cbab4d6d86f", "src_uid": "14b69f42bc192ea472e82f3a3209f1c1", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint n, m[17], r[17],max=0,dem=0;\n\tbool kt=true;\n\tdouble ans;\n\tscanf(\"%d\",&n);\n\tfor (int i=1;i<=n;i++) \n\t{\n\t\tscanf(\"%d\",&m[i]);\n\t\tif (max<m[i]) max=m[i];\n\t}\n\tfor (int i=1;i<=n;i++) scanf(\"%d\",&r[i]);\n\tif (n==1) ans=1/(float)max;\n\telse\n\t{\n\tfor (int i=1;i<=max;i++)\n\t{\n\t\tkt=true;\n\t\tfor (int j=1;j<=n;j++)\n\t\t{\n\t\t\tif (i%m[j]==r[j])\n\t\t\t{\n\t\t\t\tdem++;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tans=(float)dem/max;\n\t}\n\tprintf(\"%.6f\",ans);\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e822f151f8ff84c3f3d42acd8e4cad1f", "src_uid": "14b69f42bc192ea472e82f3a3209f1c1", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint i, j, k, m, n, m[100], r[100];\n\tdouble s, d;\n\twhile (scanf(\"%d\", &n) == 1)\n\t{\n\t\tfor (i = 0; i < n; i++)\n\t\t{\n\t\t\tscanf(\"%d\", &m[i]);\n\t\t}\n\t\tfor (j = 0; j < n; j++)\n\t\t{\n\t\t\tscanf(\"%d\", &r[j]);\n\t\t}\n\t\ts = 0;\n\t\tfor (i = 1; i <= 1000; i++)\n\t\t{\n\t\t\tfor (j = 0; j < n; j++)\n\t\t\t{\n\t\t\t\tif ((i % m[j]) == r[j])\n\n\t\t\t\t{\n\t\t\t\t\ts++;\n\t\t\t\t\td = i;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (s == 0)\n\t\t{\n\t\t\tprintf(\"0.0000\\n\");\n\t\t}\n\t\telse\n\t\t{\n\t\t\tprintf(\"%0.5lf\\n\", s / d);\n\t\t}\n\t}\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a852a5818d71a61500a480d7b6cd3492", "src_uid": "14b69f42bc192ea472e82f3a3209f1c1", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <string.h>\r\n\r\ntypedef unsigned long long ll;\r\ntypedef unsigned int uint;\r\n\r\nint mod = 998244353;\r\n\r\nll pp[501][501];\r\n\r\nll qPow(uint a, uint b)\r\n{\r\n  if (pp[a][b] > 0)\r\n  {\r\n    return pp[a][b];\r\n  }\r\n  ll ret = 1, aa = a;\r\n  uint  bb = b;\r\n  while (bb)\r\n  {\r\n    if (bb & 1)\r\n      ret = ret * aa % mod;\r\n    aa = aa * aa % mod;\r\n    bb >>= 1;\r\n  }\r\n  pp[a][b] = ret;\r\n  return ret;\r\n}\r\n\r\nuint C[501][501];\r\nuint inited = 0;\r\nvoid init()\r\n{\r\n  if (inited)\r\n    return;\r\n  inited = 1;\r\n  memset(pp, 0, sizeof(pp));\r\n  memset(C, 0, sizeof(C));\r\n  for (uint i = 0; i <= 500; i++)\r\n  {\r\n    for (uint j = 0; j <= i; j++)\r\n    {\r\n      if (!j)\r\n        C[i][j] = 1;\r\n      else\r\n        C[i][j] = C[i - 1][j] + C[i - 1][j - 1];\r\n      if (C[i][j] >= mod)\r\n        C[i][j] -= mod;\r\n    }\r\n  }\r\n}\r\nll f[501][501];\r\nint main()\r\n{\r\n  uint n, x;\r\n  scanf(\"%u %u\", &n, &x);\r\n  init();\r\n  memset(f, 0, sizeof(f));\r\n  for (uint i = 2; i <= n; i++)\r\n  {\r\n    for (uint j = 1; j <= x; j++)\r\n    {\r\n      if (j < i)\r\n      {\r\n        f[i][j] = qPow(j, i);\r\n      }\r\n      else\r\n      {\r\n        f[i][j] = qPow(i - 1, i);\r\n        for (uint k = 2; k <= i; k++)\r\n        {\r\n          f[i][j] = (f[i][j] + C[i][k] * qPow(i - 1, i - k) % mod * f[k][j - i + 1]) % mod;\r\n        }\r\n      }\r\n    }\r\n  }\r\n\r\n  printf(\"%llu\", f[n][x]);\r\n  return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "86acf7ad66da5dc2e9cefdd6ca244113", "src_uid": "1908d1c8c6b122a4c6633a7af094f17f", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <string.h>\r\n \r\ntypedef long long ll;\r\n \r\nint mod = 998244353;\r\n \r\nll qPow(ll a, ll  b) {\r\n\tll ret = 1;\r\n\twhile(b) {\r\n\t\tif(b&1)\r\n\t\t\tret = ret * a % mod;\r\n\t\ta = a * a % mod;\r\n\t\tb >>= 1;\r\n\t}\r\n\treturn ret;\r\n}\r\n \r\n \r\nint main() {\r\n    int n, x;\r\n    scanf(\"%d %d\", &n, &x);\r\n\tint C[n+1][n+1];\r\n\tmemset(C,0,sizeof(C));\r\n\tfor(int i=0;i<=n;i++){\r\n\t\tfor(int j=0;j<=i;j++) {\r\n\t\t\tif(!j)\r\n\t\t\t\tC[i][j] = 1;\r\n\t\t\telse\r\n\t\t\t\tC[i][j] = C[i-1][j] + C[i-1][j-1];\r\n\t\t\t\tif(C[i][j] >= mod)\r\n\t\t\t\t    C[i][j] -= mod;\r\n\t\t\t\t    \r\n\t\t}\r\n\t}\r\n\tll f[n+1][x+1];\r\n\tmemset(f,0,sizeof(f));\r\n\tfor(int i=2;i<=n;i++){\r\n\t\tfor(int j=1;j<=x;j++) {\r\n\t\t\tif(j<i) {\r\n\t\t\t\tf[i][j] = qPow(j, i);\r\n\t\t\t} else {\r\n\t\t\t\tf[i][j] = qPow(i-1, i);\r\n\t\t\t\tfor(int k=2;k<=i;k++) {\r\n\t\t\t\t\tf[i][j] = (f[i][j]+C[i][k]*qPow(i-1,i-k)%mod*f[k][j-i+1]%mod)%mod;\r\n\t\t\t\t}\r\n\t\t\t}\r\n\t\t}\r\n\t}\r\n\t\r\n    printf(\"%lld\", f[n][x]);\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b6f016cf9e3eed350b4ce0ebad08b564", "src_uid": "1908d1c8c6b122a4c6633a7af094f17f", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <string.h>\r\n\r\ntypedef unsigned long long ull;\r\ntypedef unsigned int uint;\r\n\r\nuint mod = 998244353;\r\n\r\null qPow[501][501];\r\nuint C[501][501];\r\nuint f[501][501];\r\nint main()\r\n{\r\n  uint n, x;\r\n  scanf(\"%u %u\", &n, &x);\r\n  memset(qPow, 0, sizeof(qPow));\r\n  for (uint i = 1; i <= x; i++)\r\n  {\r\n    qPow[i][0] = 1;\r\n    for (uint j = 1; j <= n; j++)\r\n    {\r\n      qPow[i][j] = qPow[i][j - 1] * i % mod;\r\n    }\r\n  }\r\n  memset(C, 0, sizeof(C));\r\n  for (uint i = 0; i <= n; i++)\r\n  {\r\n    for (uint j = 0; j <= i; j++)\r\n    {\r\n      if (!j)\r\n        C[i][j] = 1;\r\n      else\r\n        C[i][j] = C[i - 1][j] + C[i - 1][j - 1];\r\n      if (C[i][j] >= mod)\r\n        C[i][j] -= mod;\r\n    }\r\n  }\r\n  memset(f, 0, sizeof(f));\r\n  for (uint i = 2; i <= n; i++)\r\n  {\r\n    for (uint j = 1; j <= x; j++)\r\n    {\r\n      if (j < i)\r\n      {\r\n        f[i][j] = qPow[j][i];\r\n      }\r\n      else\r\n      {\r\n        f[i][j] = qPow[i - 1][i];\r\n        for (uint k = 2; k <= i; k++)\r\n        {\r\n\r\n          f[i][j] = (f[i][j] + C[i][k] * qPow[i - 1][i - k] % mod * f[k][j - i + 1]) % mod;\r\n        }\r\n      }\r\n    }\r\n  }\r\n\r\n  printf(\"%llu\", f[n][x]);\r\n  return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "696e4b6eadac22b42e75bd92e7fafe59", "src_uid": "1908d1c8c6b122a4c6633a7af094f17f", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\ntypedef long long ll;\r\n\r\nint mod = 998244353;\r\n\r\nll qPow(ll a, ll  b) {\r\n\tll ret = 1;\r\n\twhile(b) {\r\n\t\tif(b&1)\r\n\t\t\tret = ret * a % mod;\r\n\t\ta = a * a % mod;\r\n\t\tb >>= 1;\r\n\t}\r\n\treturn ret;\r\n}\r\n\r\n\r\nint main() {\r\n    int n, x;\r\n    scanf(\"%d %d\", &n, &x);\r\n\tll C[n+1][n+1];\r\n\tfor(int i=0;i<=n;i++){\r\n\t\tfor(int j=0;j<=i;j++) {\r\n\t\t\tif(!j)\r\n\t\t\t\tC[i][j] = 1;\r\n\t\t\telse\r\n\t\t\t\tC[i][j] = (C[i-1][j] + C[i-1][j-1]) % mod;\r\n\t\t}\r\n\t}\r\n\tll f[n+1][x+1];\r\n\tfor(int i=2;i<=n;i++){\r\n\t\tfor(int j=1;j<=x;j++) {\r\n\t\t\tif(j<i) {\r\n\t\t\t\tf[i][j] = qPow(j, i);\r\n\t\t\t} else {\r\n\t\t\t\tf[i][j] = qPow(i-1, i);\r\n\t\t\t\tfor(int k=2;k<=i;k++) {\r\n\t\t\t\t\tf[i][j] = (f[i][j]+C[i][k]*qPow(i-1,i-k)%mod*f[k][j-i+1]%mod)%mod;\r\n\t\t\t\t}\r\n\t\t\t}\r\n\t\t}\r\n\t}\r\n\t\r\n    printf(\"%lld\", f[n][x]);\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "52fe9d70979ba33074f237fc22ef4acf", "src_uid": "1908d1c8c6b122a4c6633a7af094f17f", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <string.h>\r\n\r\ntypedef unsigned long long ll;\r\ntypedef unsigned int uint;\r\n\r\nint mod = 998244353;\r\n\r\nuint pp[501][501];\r\n\r\nll qPow(uint a, uint b)\r\n{\r\n  if (pp[a][b] > 0)\r\n  {\r\n    return pp[a][b];\r\n  }\r\n  ll ret = 1, aa = a;\r\n  while (b)\r\n  {\r\n    if (b & 1)\r\n      ret = ret * aa % mod;\r\n    aa = aa * aa % mod;\r\n    b >>= 1;\r\n  }\r\n  pp[a][b] = ret;\r\n  return ret;\r\n}\r\n\r\nuint C[501][501];\r\nuint inited = 0;\r\nvoid init()\r\n{\r\n  if (inited)\r\n    return;\r\n  inited = 1;\r\n  memset(pp, 0, sizeof(pp));\r\n  memset(C, 0, sizeof(C));\r\n  for (uint i = 0; i <= 500; i++)\r\n  {\r\n    for (uint j = 0; j <= i; j++)\r\n    {\r\n      if (!j)\r\n        C[i][j] = 1;\r\n      else\r\n        C[i][j] = C[i - 1][j] + C[i - 1][j - 1];\r\n      if (C[i][j] >= mod)\r\n        C[i][j] -= mod;\r\n    }\r\n  }\r\n}\r\nll f[501][501];\r\nint main()\r\n{\r\n  uint n, x;\r\n  scanf(\"%u %u\", &n, &x);\r\n  init();\r\n  memset(f, 0, sizeof(f));\r\n  for (uint i = 2; i <= n; i++)\r\n  {\r\n    for (uint j = 1; j <= x; j++)\r\n    {\r\n      if (j < i)\r\n      {\r\n        f[i][j] = qPow(j, i);\r\n      }\r\n      else\r\n      {\r\n        f[i][j] = qPow(i - 1, i);\r\n        for (uint k = 2; k <= i; k++)\r\n        {\r\n          f[i][j] = (f[i][j] + C[i][k] * qPow(i - 1, i - k) % mod * f[k][j - i + 1] % mod) % mod;\r\n        }\r\n      }\r\n    }\r\n  }\r\n\r\n  printf(\"%llu\", f[n][x]);\r\n  return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "2f18fc5dbb6c80235e0fe140cb480426", "src_uid": "1908d1c8c6b122a4c6633a7af094f17f", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define and &&\n\nint main()\n{\n    char a[100],b[100];\n    scanf(\"%s %s\",a,b);\n    int diff=0;\n    for(int i=0;i<strlen(a);i+=2)\n       if(a[i]=='[' and b[i]=='(')\n           diff++;\n       else if(a[i]=='(' and b[i]=='8')\n           diff++;\n       else if(a[i]=='8' and b[i]=='[')\n           diff++;\n       else\n           diff--;\n    if(diff>0)\n        printf(\"TEAM 1 WINS\\n\");\n    else if(diff==0)\n        printf(\"TIE\\n\");\n    else\n        printf(\"TEAM 2 WINS\\n\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "823df187c623b87ae3324a4118be9b9a", "src_uid": "bdf2e78c47d078b4ba61741b6fbb23cf", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n\tdouble a,b;\n\tsacnf(\"%f\",&a);\n\tscanf(\"%f\",&b);\n\tprintf(\".0%f\",a+b);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "58c59d32dfaacf9712131fbbc99c0448", "src_uid": "bdf2e78c47d078b4ba61741b6fbb23cf", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "\nint main(){\n\tint i;\n\tint w1 = 0, w2 = 0;\n\tchar buf1[21];\n\tchar buf2[21];\n\tscanf(\"%s\", buf1);\n\tscanf(\"%s\", buf2);\n\tfor(i = 0; buf1[i]; i+=2){\n\t\tif(buf1[i] == buf2[i])\n\t\t\tcontinue;\n\t\tif(buf1[i] > buf2[i]){\n\t\t\tif(buf1[i] - buf2[i] > 50)\n\t\t\t\tw1++;\n\t\t\telse\n\t\t\t\tw2++;\n\t\t} else {\n\t\t\tif(buf2[i] - buf1[i] > 50)\n\t\t\t\tw2++;\n\t\t\telse\n\t\t\t\tw1++;\n\t\t}\n}\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e63797db23fed7b97497e1c40afc730d", "src_uid": "bdf2e78c47d078b4ba61741b6fbb23cf", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>  \n#include <string.h>  \n  \nint main() {  \n    char a[21], b[21];  \n    scanf(\"%s%s\", a, b);  \n    int cnt1 = 0, cnt2 = 0;  \n    int len = strlen(a);  \n    for (int i = 0; i < len; i+=2) {  \n        if (a[i] == '8') {  \n            if (b[i] == '[') {  \n                cnt1++;  \n            } else if (b[i] == '(') {  \n                cnt2++;  \n            }  \n        } else if (a[i] == '[') {  \n            if (b[i] == '(') {  \n                cnt1++;  \n            } else if (b[i] == '8') {  \n                cnt2++;  \n            }  \n        } else if (a[i] == '('){  \n            if (b[i] == '8') {  \n                cnt1++;  \n            } else if(b[i] == '[') {  \n                cnt2++;  \n            }  \n        }  \n    }  \n    if (cnt1 > cnt2) {  \n        printf(\"TEAM 1 WINS\\n\");  \n    } else if(cnt1 < cnt2) {  \n        printf(\"TEAM 2 WINS\\n\");  \n    } else {  \n        printf(\"TIE\\n\");  \n    }  \n    return 0;  \n}  ", "lang_cluster": "C", "compilation_error": true, "code_uid": "5f26fac6c95442a399591c252fca3412", "src_uid": "bdf2e78c47d078b4ba61741b6fbb23cf", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <cstdio>  \n#include <cstring>  \n  \nint main() {  \n    char a[21], b[21];  \n    scanf(\"%s%s\", a, b);  \n    int cnt1 = 0, cnt2 = 0;  \n    int len = strlen(a);  \n    for (int i = 0; i < len; i+=2) {  \n        if (a[i] == '8') {  \n            if (b[i] == '[') {  \n                cnt1++;  \n            } else if (b[i] == '(') {  \n                cnt2++;  \n            }  \n        } else if (a[i] == '[') {  \n            if (b[i] == '(') {  \n                cnt1++;  \n            } else if (b[i] == '8') {  \n                cnt2++;  \n            }  \n        } else if (a[i] == '('){  \n            if (b[i] == '8') {  \n                cnt1++;  \n            } else if(b[i] == '[') {  \n                cnt2++;  \n            }  \n        }  \n    }  \n    if (cnt1 > cnt2) {  \n        printf(\"TEAM 1 WINS\\n\");  \n    } else if(cnt1 < cnt2) {  \n        printf(\"TEAM 2 WINS\\n\");  \n    } else {  \n        printf(\"TIE\\n\");  \n    }  \n    return 0;  \n}  ", "lang_cluster": "C", "compilation_error": true, "code_uid": "e8ee1aae16756f42c84b0f0a10817ef5", "src_uid": "bdf2e78c47d078b4ba61741b6fbb23cf", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nlong long p[9000000];\nvoid main(){\nlong long n,k,i;\nscanf(\"%lld %lld\",&n,&k);\n\nif((n==1&&k==2){\n\tprintf(\"YES\\n\");\nexit(0);}\n\nif(k>n){\nprintf(\"NO\\n\");\nexit(0);}\n\n\n\nfor(i=1;i<=k;i++){\np[n%i]++;\nif(p[n%i]>1){\nprintf(\"NO\\n\");\nexit(0);}}\n\nprintf(\"YES\\n\");\nexit(0);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a4565e09d92a72be72cad06cf1bf2441", "src_uid": "5271c707c9c72ef021a0baf762bf3eb2", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n    long long int n,k;\n    int i,c=0,j,a[101];\n    scanf(\"%lld%lld\",&n,&k);\n    if(k<=100)\n    {\n        for(i=1;i<=k;i++)\n        {\n            a[i]=n%i;\n            for(j=1;j<i;j++)\n            {1\n                if(a[i]==a[j]) \n                {\n                    c++;\n                }\n            }\n        }\n        if(c!=0) printf(\"NO\");\n        else printf(\"YES\");\n    }\n    else printf(\"NO\");\n    return 0;\n}  ", "lang_cluster": "C", "compilation_error": true, "code_uid": "937ecfb95865d0bdb28e18866cec141e", "src_uid": "5271c707c9c72ef021a0baf762bf3eb2", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n  long long int n,k,count=0;\n  scanf(\"%lld %lld\",&n,&k);\n  long long int i,m=-1;\n  for(i=1;i<=k;i++)\n  {\n        if(m<n%i)\n            {count++;\n            m=n%i;}\n        else\n          {printf(\"No\");\n            return 0:\n          }\n\n\n  }\n  if(count==k)\n  printf(\"Yes\" );\n  else\n    printf(\"No\");\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "864131e471a098b1278c2412d585fc72", "src_uid": "5271c707c9c72ef021a0baf762bf3eb2", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define ll long long\nint main()\n{\n\tll n,k;\n\tscanf(\"%lld %lld\", &n,&k);\n\tfor(int i=1;i<=k;i++)\n\t\tfor(int j=i+1;j<=k;j++){\n\t\t\tif(n%i==n%j){\n\t\t\t\tprintf(\"No\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\tprintf(\"Yes\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "662d3c3f0619e64485741187c5e91265", "src_uid": "5271c707c9c72ef021a0baf762bf3eb2", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define ll long long\nint main()\n{\n\tll n,k;\n\tscanf(\"%lld %lld\", &n,&k);\n\tif(n%2==0&&k>=4){\n\t\tprintf(\"No\");\n\t\treturn 0;\n\t}\n\tfor(int i=1;i<=k;i++)\n\t\tfor(int j=i+1;j<=k;j++){\n\t\t\tif(n%i==n%j){\n\t\t\t\tprintf(\"No\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\tprintf(\"Yes\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "34481ef28713ef3c4d31ff88e64da597", "src_uid": "5271c707c9c72ef021a0baf762bf3eb2", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n#include <limits.h>\nint cmpfunc (const void * a, const void * b)\n{\n   return ( *(int*)a - *(int*)b );\n}\nint main(int argc, char const *argv[])\n{\n\tint n,k;\n\tscanf(\"%d %d\",&n,&k);\n\tchar s[n+1];\n\tscanf(\"%s\",s);\n\tint count=0;\n\tint a[26],b[26];\n\tfor(int i=0;i<26;i=i+1){\n\t\ta[i]=10000000;\n\t\tb[i]=10000000;\n\t}\n\tfor(int i=0;i<n;i=i+1){\n\t\tif(a[s[i]-65]==10000000){\n\t\t\ta[s[i]-65]=i;\n\t\t\tcount+=1;\n\t\t}else{\n\t\t\tb[s[i]-65]=i;\n\t\t}\n\t}\n\tqsort(a,26,sizeof(int),cmpfunc);\n\tqsort(b,26,sizeof(int),cmpfunc);\n\tint count1=0;\n\tint temp=0;\n\tfor(int i=0;i<count,temp<count;i=i+1){\n\t\twhile(a[i]<b[temp]){\n\t\t\tcount1+=1;\n\t\t\ti+=1;\n\t\t}\n\t\ti=i-1;\n\t\t//printf(\"%d\\n\",count1);\n\t\tif(temp<count-1){\n\t\t\ttemp+=1;\n\t\t}\n\t\tif(count1>k){\n\t\t\tprintf(\"YES\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\tcount1-=1;\n\t}\n\tprintf(\"NO\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8bc10a27606608de439411493db5615c", "src_uid": "216323563f5b2dd63edc30cb9b4849a5", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define mod 1000000007\n#define N 100000\nint main(){\n    long long int n,k;\n    scanf(\"%lld %lld\",&n,&k); getchar();\n    char s[n+1];int a[26]={0},g[26]={0};\n    gets(s);\n    long long int i;\n    for(i=0;i<strlen(s);i++){\n        a[s[i]-'A']++;\n    }\n    for(i=0;i<strlen(s);i++){\n       if( g[s[i]-'A']==0){\n        g[s[i]-'A']=1;k--;\n       }\n       if(k==-1){\n        printf(\"YES\"); return 0;\n       }\n       a[s[i]-'A']--;\n       if(a[s[i]-'A']==0){\n        k++;\n       }\n\n\n    }\n\n    printf(\"NO\");\n\n\n\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9c42e014bb049b24b9a1fbfa61b7cdd3", "src_uid": "216323563f5b2dd63edc30cb9b4849a5", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define mod 1000000007\n#define N 100000\nint main(){\n    long long int n,k;\n    scanf(\"%lld %lld\",&n,&k); getchar();\n    char s[n+1];int a[26]={0},g[26]={0};\n    //gets(s);\n    long long int i;\n    for(i=0;i<n;i++){\n        s[i]=getch();\n        a[s[i]-'A']++;\n    }\n    for(i=0;i<strlen(s);i++){\n       if( g[s[i]-'A']==0){\n        g[s[i]-'A']=1;k--;\n       }\n       if(k==-1){\n        printf(\"YES\"); return 0;\n       }\n       a[s[i]-'A']--;\n       if(a[s[i]-'A']==0){\n        k++;\n       }\n\n\n    }\n\n    printf(\"NO\");\n\n\n\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f7708671d30f67a4b1c029f2e65ff032", "src_uid": "216323563f5b2dd63edc30cb9b4849a5", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main(){\n    int n, k, c_time[26], i, flag[26], unguarded, count;\n    char s[1000005];\n    memset(flag, 0, sizeof(flag));\n    memset(c_time, 0, sizeof(c_time));\n    scanf(\"%d %d\\n%s\", &n, &k, s);\n    if(k == 26){\n        printf(\"YES\\n\");\n    } else {\n        for (i = 0; i < n; i++){\n            if (i > c_time[s[i] - 'A']){\n                c_time[s[i] - 'A'] = i;\n            }\n        }\n        for (i = unguarded = count = 0; i < n && !unguarded; i++){\n            if (!flag[s[i] - 'A']){\n                count++;\n                flag[s[i] - 'A'] = 1;\n            }\n            unguarded = (count > k);\n            count = (c_time[s[i] - 'A'] == i) ? count - 1 : count;\n        }\n        printf(\"%s\\n\", unguarded ? \"YES\" : \"NO\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "bcacf8143990f9d4a458897f2d87809b", "src_uid": "216323563f5b2dd63edc30cb9b4849a5", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define mod 1000000007\n#define N 100000\nchar s[100005];\nint main(){\n    long long int n,k;\n    scanf(\"%lld %lld %s\",&n,&k,s);\n    int a[26]={0},g[26]={0};\n    long long int i;\n    for(i=0;i<n;i++){\n        a[s[i]-'A']++;\n    }\n    for(i=0;i<strlen(s);i++){\n       if( g[s[i]-'A']==0){\n        g[s[i]-'A']=1;k--;\n       }\n       if(k==-1){\n        printf(\"YES\"); return 0;\n       }\n       a[s[i]-'A']--;\n       if(a[s[i]-'A']==0){\n        k++;\n       }\n\n\n    }\n\n    printf(\"NO\");\n\n\n\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "65e7d9415dbadd7ad2be2fa326f1e0c6", "src_uid": "216323563f5b2dd63edc30cb9b4849a5", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n#define EPS 1e-11\n\nint sign(double a){if(a>EPS) return 1; if(a<-EPS) return -1; return 0;}\nint ab(int a){if(a<0)return -a; return a;}\nint GCD(int a,int b){int r; while(a){r=b; b=a; a=r%a;} return b;}\n\nint main(){\n  int a,b,A,B,k;\n  double c, C;\n\n  scanf(\"%d%d%lf%d%d%lf\",&a,&b,&c,&A,&B,&C);\n  if(a<0 || (!a&&b<0)) a=-a, b=-b, c=-c;\n  if(A<0 || (!A&&B<0)) A=-A, B=-B, C=-C;\n  if(a||b) k=GCD(a,ab(b)), a/=k, b/=k, c/=k;\n  if(A||B) k=GCD(A,ab(B)), A/=k, B/=k, C/=k;\n\n  if( (!a&&!b&&sign(c) || (!A&&!B&&sign(C))) ) puts(\"0\");\n  else if( (!a&&!b&&!sign(c)) || (!A&&!B&&!sign(C)) )puts(\"-1\");\n  else if(a==A && b==B && sign(c-C)==0 ) puts(\"-1\");\n  else if(a==A && b==B) puts(\"0\");\n  else puts(\"1\");\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c6830a2d6ef388da0b3a7933e0a4b416", "src_uid": "c8e869cb17550e888733551c749f2e1a", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int a1,a2,b1,b2,c1,c2;\n    scanf(\"%d%d%d%d%d%d\",&a1,&b1,&c1,&a2,&b2,&c2);\n    if((a1==0 && b1==0 && c1==0))\n    {\n        if(a2==0 && b2==0 && c2!=0)\n            printf(\"0\");\n        else\n            printf(\"-1\");\n    }\n    else if((a2==0 && b2==0 && c2==0))\n    {\n        if(a1==0 && b1==0 && c1!=0)\n            printf(\"0\");\n        else\n            printf(\"-1\");\n    }\n    else if((a1==0 && b1==0 ) || (a2==0 && b2==0 ))\n        printf(\"0\");\n    else if(a1==0 && a2==0)\n    {\n        if(c1==0 && c2 ==0)\n            printf(\"-1\");\n        else if(c1==0 || c2==0)\n            printf(\"0\");\n        else if(b1*c2==b2*c1)\n            printf(\"-1\");\n        else\n            printf(\"0\");\n    }\n    else if(a1==0 || a2==0)\n    {\n            printf(\"1\");\n    }\n    else if(b1==0 && b2==0)\n    {\n        if(c1==0 && c2 ==0)\n            printf(\"-1\");\n        else if(c1==0 || c2==0)\n            printf(\"0\");\n        else if(a1*c2==a2*c1)\n            printf(\"-1\");\n        else\n            printf(\"0\");\n    }\n    else if(b1==0 || b2 ==0)\n    {\n            printf(\"1\");\n    }\n    else if(a1*b2==a2*b1 && b1*c2==b2*c1)\n                printf(\"-1\");\n    else if(a1*b2==b1*a2)\n        printf(\"0\");\n    else\n        printf(\"1\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f10fdb82977681031f16240109f4c326", "src_uid": "c8e869cb17550e888733551c749f2e1a", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\nvolatile int Que[32];\nint sea(int l);\nint main(){\n    int n,m,s,k,l,nx,ny,c=(int)'a';\n    char x,y;\n    volatile int Donde[30][200001];\n    volatile char cad[200001];\n    volatile char *abc=\"abcdefghijklmnopqrstuvwxyz\";\n    for(s=0;s<30;s++){\n        Que[s]=s;\n    }\n    memset(Donde,-1,sizeof(Donde));\n    scanf(\"%d %d\",&n,&m);\n    scanf(\"%s\",cad);\n    for(s=0;cad[s]!='\\0';s++){\n        k=(int)cad[s] - c;\n        Donde[k][0]++;\n        Donde[k][Donde[k][0]+1]=s;\n    }\n    l=s;\n    for(s=0;s<m;s++){\n        scanf(\"%d\",&k);\n        scanf(\"%c %c\",&x,&y);\n        nx=sea((int)x - c);\n        ny=sea((int)y - c);\n        if(nx-ny){\n            Que[31]=Que[nx];\n            Que[nx]=Que[ny];\n            Que[ny]=Que[31];\n        }\n    }\n    for(s=0;s<30;s++){\n        for( ;~Donde[s][0];Donde[s][0]--){\n            cad[Donde[s][Donde[s][0]+1]]=abc[Que[s]];\n        }\n    }\n\n    printf(\"%s\",cad);\n}\nint sea(int l){\n    int r=0;\n    while(Que[r]!=l){\n        r++;\n    }\n    return r;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "067a5b9b88278315560b8e4f990b6647", "src_uid": "c8e869cb17550e888733551c749f2e1a", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main (){\n    int a1,b1,c1,a2,b2,c2,r=-1;\n    scanf(\"%d %d %d\\n%d %d %d\",&a1,&b1,&c1,&a2,&b2,&c2);\n    if(b1 && b2){\n        if(a1/b1==a2/b2 && a1/b1!=c1/){\n            r=0;\n        }else{\n            r=1;\n        }      \n    }else if((b1==0 && b2!=0) || (b1!=0 && b2==0)){\n        r=1;\n    }\n    printf(\"%d\",r);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "51bff639dfa93974a29a9d1ef6e3bf81", "src_uid": "c8e869cb17550e888733551c749f2e1a", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int a1,a2,b1,b2,c1,c2;\n    scanf(\"%d%d%d%d%d%d\",&a1,&b1,&c1,&a2,&b2,&c2);\n    if((a1==0 && b1==0 && c1==0) || (a2==0 && b2==0 && c2==0))\n        printf(\"-1\");\n    else if((a1==0 && b1==0 &&) || (a2==0 && b2==0 ))\n        printf(\"0\");\n    else if(a1==0 && a2==0)\n    {\n        if(c1==0 && c2 ==0)\n            printf(\"-1\");\n        else if(c1==0 || c2==0)\n            printf(\"0\");\n        else if(b1*c2==b2*c1)\n            printf(\"-1\");\n        else\n            printf(\"0\");\n    }\n    else if(a1==0 || a2==0)\n    {\n            printf(\"1\");\n    }\n    else if(b1==0 && b2==0)\n    {\n        if(c1==0 && c2 ==0)\n            printf(\"-1\");\n        else if(c1==0 || c2==0)\n            printf(\"0\");\n        else if(a1*c2==a2*c1)\n            printf(\"-1\");\n        else\n            printf(\"0\");\n    }\n    else if(b1==0 || b2 ==0)\n    {\n            printf(\"1\");\n    }\n    else if(a1*b2==a2*b1 && b1*c2==b2*c1)\n                printf(\"-1\");\n    else if(a1*b2==b1*a2)\n        printf(\"0\");\n    else\n        printf(\"1\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "a628ba7c79e8429dd4b49394ae7072e6", "src_uid": "c8e869cb17550e888733551c749f2e1a", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\n#define ll long long\n#define M 2520\n\nint GCD(int a,int b){int r; while(a){r=b; b=a; a=r%a;} return b;}\nint LCM(int a,int b){ return a/GCD(a,b)*b; }\n\nll *dp1, *dp2, *nx1, *nx2, *swap;\nll dp1__[M], dp2__[M];\nll nx1__[M], nx2__[M];\n\nll dp[1025][M];\nint bc[1500];\n\nint nex[M][12];\n\nll solve(ll mx){\n  int i,j,k,mask,use[10],us,now,nn;\n  int go[20],gos,g;\n  ll res;\n\n  dp1=dp1__; dp2=dp2__; nx1=nx1__; nx2=nx2__;\n\n  gos=0;\n  while(mx) go[gos++]=mx%10, mx/=10;\n\n  rep(mask,1<<8){\n    us=2; use[0]=0; use[1]=1;\n    rep(i,8) if(mask&1<<i) use[us++]=i+2;\n\n    rep(i,M) dp1[i]=dp2[i]=0;\n    dp1[0]=1;\n\n    rep(i,M) rep(j,us) nex[i][j] = (i*10+use[j])%M;\n\n    for(now=gos-1;now>=0;now--){\n      rep(i,M) nx1[i]=nx2[i]=0;\n\n      rep(i,M) if(dp2[i]) rep(k,us) nx2[nex[i][k]] += dp2[i];\n      \n      rep(i,M) if(dp1[i]) rep(k,us){\n        if(go[now]==use[k]) nx1[nex[i][k]] += dp1[i];\n        if(go[now]> use[k]) nx2[nex[i][k]] += dp1[i];\n      }\n\n      swap=dp1, dp1=nx1, nx1=swap;\n      swap=dp2, dp2=nx2, nx2=swap;\n    }\n\n    rep(i,M) dp[mask][i] = dp1[i] + dp2[i];\n  }\n\n  res = 0;\n  rep(mask,1<<8){\n    g=1;\n    rep(i,8) if(mask&1<<i) g=LCM(g,i+2);\n    \n    rep(i,mask+1) if( (i&mask)==i ){\n      for(j=g;j<M;j+=g){\n        if( (bc[mask] - bc[i])%2 ) res -= dp[i][j];\n        else                       res += dp[i][j];\n      }\n    }\n  }\n\n  return res;\n}\n\nint main(){\n  int i,j,k,l,n;\n  ll a, b, res;\n  int size;\n\n  bc[0]=0;\n  REP(i,1,1<<10) bc[i] = bc[i&(i-1)]+1;\n\n  scanf(\"%d\",&size);\n  while(size--){\n    scanf(\"%I64d%I64d\",&a,&b);\n    res = solve(b) - solve(a-1);\n    printf(\"%I64d\\n\",res);\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a73b0923fd074eee81a1360fb3321bbf", "src_uid": "37feadce373f728ba2a560b198ca4bc9", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#define MOD 2520\nint a[30],index[MOD+10];\n__int64 dps[23][2550][50];\n\nvoid init(){\n    int i,k=1;\n    for(i=1;i<=MOD;i++){\n        if(MOD%i==0)\n            index[i]=k++;\n    }\n    k--;\n}\nint gcd(int a , int b)\n{\n    return b == 0 ? a : gcd(b , a % b);\n}\n\nint lcm(int a, int b)\n{\n    return a / gcd(a,b) * b;\n}\n__int64 dp(int pos,int sum,int mod,int doing){\n    int i,tem,max,nowsum,nowmod;\n    __int64 result=0;\n    if(pos==0){\n        return sum%mod==0;\n    }\n    if(doing==0 && dps[pos][sum][index[mod]]!=-1)\n        return dps[pos][sum][index[mod]];\n\n    if(doing)\n        max=a[pos];\n    else\n        max=9;\n\n    for(i=0;i<=max;i++){\n        nowsum=0;\n        nowsum=(sum*10+i)%MOD;\n        nowmod=0;\n        nowmod=mod;\n        if(i)\n            nowmod=lcm(mod,i);\n        if(doing && i==max){\n            result+=dp(pos-1,nowsum,nowmod,1);\n        }\n        else{\n            result+=dp(pos-1,nowsum,nowmod,0);\n        }\n\n    }\n    if(!doing){\n        dps[pos][sum][index[mod]]=result;\n    }\n    return result;\n}\n__int64 cal(__int64 num){\n    __int64 tem;\n    int i;\n    tem=num;\n    i=1;\n    while(tem){\n        a[i++]=tem%10;\n        tem/=10;\n    }\n    return dp(i-1,0,1,1);\n}\nint main()\n{\n    int t,T;\n    __int64 l,r,i,j,k;\n    scanf(\"%d\",&T);\n    init();\n    for(t=1;t<=T;t++){\n        //memset(dps,-1,sizeof(dps));//\u8fd9\u91cc\u9519\u4e86\n        scanf(\"%I64d %I64d\",&l,&r);\n        printf(\"%I64d\\n\",cal(r)-cal(l-1));\n    }\n    return 0;\n  \n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bbcea5efe4c73669c609612a8326c63b", "src_uid": "37feadce373f728ba2a560b198ca4bc9", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\n#define ll long long\n#define M 2520\n\nint GCD(int a,int b){int r; while(a){r=b; b=a; a=r%a;} return b;}\nint LCM(int a,int b){ return a/GCD(a,b)*b; }\n\nll *dp1, *dp2, *nx1, *nx2, *swap;\nll dp1__[M], dp2__[M];\nll nx1__[M], nx2__[M];\n\nll dp[525][M];\nint bc[1500];\n\nint nex[M][10];\n\nll solve(ll mx){\n  int i,j,k,mask,use[10],us,now,nn;\n  int go[20],gos,g;\n  ll res;\n\n  dp1=dp1__; dp2=dp2__; nx1=nx1__; nx2=nx2__;\n\n  gos=0;\n  while(mx) go[gos++]=mx%10, mx/=10;\n\n  rep(mask,1<<8){\n    us=2; use[0]=0; use[1]=1;\n    rep(i,8) if(mask&1<<i) use[us++]=i+2;\n\n    rep(i,M) dp1[i]=dp2[i]=0;\n    dp1[0]=1;\n\n    rep(i,M) rep(j,us) nex[i][j] = (i*10+use[j])%M;\n\n    for(now=gos-1;now>=0;now--){\n      rep(i,M) nx1[i]=nx2[i]=0;\n\n      rep(i,M) if(dp2[i]) rep(k,us) nx2[nex[i][k]] += dp2[i];\n      \n      rep(i,M) if(dp1[i]) rep(k,us){\n        if(go[now]==use[k]) nx1[nex[i][k]] += dp1[i];\n        if(go[now]> use[k]) nx2[nex[i][k]] += dp1[i];\n      }\n\n      swap=dp1, dp1=nx1, nx1=swap;\n      swap=dp2, dp2=nx2, nx2=swap;\n    }\n\n    rep(i,M) dp[mask][i] = dp1[i] + dp2[i];\n  }\n\n  res = 0;\n  rep(mask,1<<8){\n    g=1;\n    rep(i,8) if(mask&1<<i) g=LCM(g,i+2);\n    \n    rep(i,mask+1) if( (i&mask)==i ){\n      for(j=g;j<(1<<8);j+=g){\n        if( (bc[mask] - bc[i])%2 ) res -= dp[i][j];\n        else                       res += dp[i][j];\n      }\n    }\n  }\n\n  return res;\n}\n\nint main(){\n  int i,j,k,l,n;\n  ll a, b, res;\n  int size;\n\n  bc[0]=0;\n  REP(i,1,1<<10) bc[i] = bc[i&(i-1)]+1;\n\n  scanf(\"%d\",&size);\n  while(size--){\n    scanf(\"%I64d%I64d\",&a,&b);\n    res = solve(b) - solve(a-1);\n    printf(\"%I64d\\n\",res);\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2361e79186403ad2bbb29cd5ee857686", "src_uid": "37feadce373f728ba2a560b198ca4bc9", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\n#define ll long long\n#define M 2520\n\nint GCD(int a,int b){int r; while(a){r=b; b=a; a=r%a;} return b;}\nint LCM(int a,int b){ return a/GCD(a,b)*b; }\n\nll *dp1, *dp2, *nx1, *nx2, *swap;\nll dp1__[M], dp2__[M];\nll nx1__[M], nx2__[M];\n\nll dp[323][M];\nint bc[323];\n\nint nex[M][10];\n\nll solve(ll mx){\n  int i,j,k,mask,use[10],us,now,nn;\n  int go[20],gos,g;\n  ll res;\n\n  dp1=dp1__; dp2=dp2__; nx1=nx1__; nx2=nx2__;\n\n  gos=0;\n  while(mx) go[gos++]=mx%10, mx/=10;\n\n  rep(mask,1<<8){\n    if( (mask&1<<2) && !(mask&1<<0) ) continue;\n    if( (mask&1<<4) && (!(mask&1<<0)||!(mask&1<<1)) ) continue;\n    if( (mask&1<<6) && (!(mask&1<<0)||!(mask&1<<2)) ) continue;\n    if( (mask&1<<7) && (mask&1<<1) ) continue;\n    us=2; use[0]=0; use[1]=1;\n    rep(i,8) if(mask&1<<i) use[us++]=i+2;\n\n    rep(i,M) dp1[i]=dp2[i]=0;\n    dp1[0]=1;\n\n    rep(i,M) rep(j,us) nex[i][j] = (i*10+use[j])%M;\n\n    for(now=gos-1;now>=0;now--){\n      rep(i,M) nx1[i]=nx2[i]=0;\n\n      rep(i,M) if(dp2[i]) rep(k,us) nx2[nex[i][k]] += dp2[i];\n      \n      rep(i,M) if(dp1[i]) rep(k,us){\n        if(go[now]==use[k]) nx1[nex[i][k]] += dp1[i];\n        if(go[now]> use[k]) nx2[nex[i][k]] += dp1[i];\n      }\n\n      swap=dp1, dp1=nx1, nx1=swap;\n      swap=dp2, dp2=nx2, nx2=swap;\n    }\n\n    rep(i,M) dp[mask][i] = dp1[i] + dp2[i];\n  }\n\n  res = 0;\n  rep(mask,1<<8){\n    g=1;\n    rep(i,8) if(mask&1<<i) g=LCM(g,i+2);\n    \n    rep(i,mask+1) if( (i&mask)==i ){\n      for(j=0;j<M;j+=g){\n        if( (bc[mask] - bc[i])%2 ) res -= dp[i][j];\n        else                       res += dp[i][j];\n      }\n    }\n  }\n\n  return res;\n}\n\nint main(){\n  int i,j,k,l,n;\n  ll a, b, res;\n  int size;\n\n  bc[0]=0;\n  REP(i,1,1<<8) bc[i] = bc[i&(i-1)]+1;\n\n  scanf(\"%d\",&size);\n  while(size--){\n    scanf(\"%I64d%I64d\",&a,&b);\n    res = solve(b) - solve(a-1);\n    printf(\"%I64d\\n\",res);\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "eb4c510317e90aa6908a4199fe300c74", "src_uid": "37feadce373f728ba2a560b198ca4bc9", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\n#define maxim 100\n#define LLD long long int\n#define LLU long long unsigned \n//#define llu I64u\n\n#define rep(i,init,n) for(i=init;i<n;i++)\n#define rem(i,init,n) for(i=init;i>n;i--)\n\nchar a[20];\nchar b[20];\n\nLLU dp[20][2520][256+5][4];\nchar isV[20][2520][256+5][4] = {{{{0}}}};\nLLU M = 2520;\n\nLLU cal(int i, int mod, int Bit, int s)\n{\n    int j;\n    \n    if(i == 20)\n    {\n        rep(j,2,10)\n        {\n            if( ( Bit & (1<<(j-2)) ) && mod%j )   return 0;\n        }\n        return 1;\n    }\n    \n    if(isV[i][mod][Bit][s])  return dp[i][mod][Bit][s];\n    \n    LLU ret = 0;\n    int nmod;\n    if(s == 0)\n    {\n        rep(j,0,10)\n        {\n            nmod = ( mod*10 + j ) % M;\n            ret += cal( i+1, nmod, Bit|1<<(j-2), 0 );\n        }\n    }\n    else if(s == 1)\n    {\n        j = a[i]-'0';\n        nmod = ( mod*10 + j ) % M;\n        ret += cal( i+1, nmod, Bit|1<<(j-2), 1 );\n        \n        rep(j,a[i]-'0'+1,10)\n        {\n            nmod = ( mod*10 + j ) % M;\n            ret += cal( i+1, nmod, Bit|1<<(j-2), 0 );\n        }\n    }\n    else if(s == 2)\n    {   \n        rep(j,0,b[i]-'0')\n        {\n            nmod = ( mod*10 + j ) % M;\n            ret += cal( i+1, nmod, Bit|1<<(j-2), 0 );\n        }\n        nmod = ( mod*10 + j ) % M;\n        ret += cal( i+1, nmod, Bit|1<<(j-2), 2 );\n    }\n    else\n    {\n        if(a[i]-'0' == b[i]-'0')\n        {\n            j = a[i]-'0';\n            nmod = ( mod*10 + j ) % M;\n            ret += cal( i+1, nmod, Bit|1<<(j-2), 3 );\n        }\n        \n        else\n        {\n            j = a[i]-'0';\n            \n            nmod = ( mod*10 + j ) % M;\n            ret += cal( i+1, nmod, Bit|1<<(j-2), 1 );\n            \n            rep(j,a[i]-'0'+1,b[i]-'0')\n            {\n                nmod = ( mod*10 + j ) % M;\n                ret += cal( i+1, nmod, Bit|1<<(j-2), 0 );\n            }\n            \n            nmod = ( mod*10 + j ) % M;\n            ret += cal( i+1, nmod, Bit|1<<(j-2), 2 );\n        }\n    }\n    \n    isV[i][mod][Bit][s] = 1;\n    return dp[i][mod][Bit][s] = ret;\n}\n\nint main()\n{\n    int T,t=1,m,i,j,k;\n    LLU l,r;\n    scanf(\"%d\",&T);\n    for(t=1;t<=T;t++)\n    {\n        scanf(\"%I64u%I64u\",&l,&r);\n        \n        sprintf(a,\"%020I64u\",l);\n        sprintf(b,\"%020I64u\",r);\n        \n        rep(i,0,20)\n            rep(j,0,2520)   \n                rep(k,0,261)\n                    rep(m,1,4)\n                        isV[i][j][k][m] = 0;\n                    \n        \n        printf(\"%I64u\\n\",cal(0,0,0,3));\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e91c881731e6c28712be0678c95a50c1", "src_uid": "37feadce373f728ba2a560b198ca4bc9", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define ulli unsigned long long int\n\nulli factorial(int n){\n  if(n==1) return 1;\n  else return factorial(n-1)*n;\n}\n\nint main(){\n  int n;\n  scanf(\"%d\", &n);\n  int k = n/2;\n  ulli ans;\n  ans = factorial(n) / factorial(n-k);\n  ans = ans * factorial(k-1)/(2*k);\n  printf(\"%lld\\n\",ans);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1e46465d7541a70a5f118c69471ca668", "src_uid": "ad0985c56a207f76afa2ecd642f56728", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n\nlong long int factorial(long long int n) ;\n\nint main()\n{\n    int t;\n    scanf(\"%d\", &t);\n\n    while(t--)\n    {\n        int n, power;\n        long long int sum;\n        scanf(\"%d\", &n);\n        power = (factorial((n/2)-1) * factorial((n/2)-1));\n        sum = ((factorial(n)/((factorial(n/2)) * factorial(n/2))/2) * power) ;\n\n        printf(\"%d\", sum);\n    }\n}\n\nlong long int factorial(long long int n)\n{\n    if (n == 0)\n        return 1;\n    return n * factorial(n - 1);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bb4bf0b59ea72994b04cb6b8668cdbd3", "src_uid": "ad0985c56a207f76afa2ecd642f56728", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n\nlong long int factorial(long long int n) ;\n\nint main()\n{\n    int t;\n    scanf(\"%d\", &t);\n\n    while(t--)\n    {\n        int n;\n        long long int sum, power;\n        scanf(\"%d\", &n);\n        power = (factorial((n/2)-1) * factorial((n/2)-1));\n        sum = ((factorial(n)/((factorial(n/2)) * factorial(n/2))/2) * power) ;\n\n        printf(\"%lld\", sum);\n    }\n\n    return 0;\n}\n\nlong long int factorial(long long int n)\n{\n    if (n == 0)\n        return 1;\n    return n * factorial(n - 1);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bf5a0e6567bcbddc3d4e074ef925a7f7", "src_uid": "ad0985c56a207f76afa2ecd642f56728", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n\nlong long int factorial(long long int n) ;\n\nint main()\n{\n    int t;\n    scanf(\"%d\", &t);\n\n    while(t--)\n    {\n        int n;\n        long long int sum, power;\n        scanf(\"%d\", &n);\n        power = (factorial((n/2)-1) * factorial((n/2)-1));\n        sum = ((factorial(n)/((factorial(n/2)) * factorial(n/2))/2) * power) ;\n\n        printf(\"%lld\", sum);\n    }\n}\n\nlong long int factorial(long long int n)\n{\n    if (n == 0)\n        return 1;\n    return n * factorial(n - 1);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b463344ec1a0e8cbdd513fbb4ecfcbce", "src_uid": "ad0985c56a207f76afa2ecd642f56728", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n\n long long int factorial( long long int n) ;\n\nint main()\n{\n    int t;\n    scanf(\"%d\", &t);\n\n    while(t--)\n    {\n        long long int n, power;\n        long long int sum;\n        scanf(\"%lld\", &n);\n        power = pow(factorial((n/2)-1),2);\n        sum = ((factorial(n)/((factorial(n/2)) * factorial(n/2))/2) * power) ;\n\n        printf(\"%lld\", sum);\n    }\n}\n\n long long int factorial( long long int n)\n{\n    if (n == 0)\n        return 1;\n    return n * factorial(n - 1);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c0a9855829a4e9d0ec61ebbb16c5fbf1", "src_uid": "ad0985c56a207f76afa2ecd642f56728", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\ntypedef long long ll;\nll a[15], w, ans;\n\nvoid dfs(int x, ll y) {\n\tif (x > 8) { \n\t\tif (y > ans) ans = y;\n\t\treturn;\n\t}\n\tll k = a[x];\n\tll tmp = (w - y) / x;\n\tif (k > tmp) k = tmp;\n\tll i = k - 3;\n\tif (i < 0) i = 0;\n\tfor (; i <= k; i++) dfs(x + 1, y + i * x);\n}\n\nint main() {\n\tscanf(\"%I64d\", &w);\n\tans = 0;\n\tfor (int i = 1; i <= 8; i++) scanf(\"%I64d\", &a[i]);\n\tdfs(1, 0);\n\tprintf(\"%I64d\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8efeefeb90312c2f725849237af674d4", "src_uid": "8097e10157320524c0faed56f2bc4880", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n#include <string.h>\n\n#define K\t8\n#define L\t840\n\nlong long min(long long a, long long b) { return a < b ? a : b; }\nlong long max(long long a, long long b) { return a > b ? a : b; }\n\nint main() {\n\tstatic long long aa[K + 1], dp[L * K], dq[L * K];\n\tlong long w, ans, a, p;\n\tint i, y, y_, q, q_;\n\n\tscanf(\"%lld\", &w);\n\tfor (i = 1; i <= K; i++)\n\t\tscanf(\"%lld\", &aa[i]);\n\tmemset(dp, -1, L * K * sizeof *dp);\n\tdp[0] = 0;\n\tfor (i = 1; i <= K; i++) {\n\t\ta = aa[i];\n\t\tfor (y = 0; y < L * K; y++)\n\t\t\tdq[y] = -1;\n\t\tfor (y = 0; y < L * K; y++) {\n\t\t\tif (dp[y] < 0)\n\t\t\t\tcontinue;\n\t\t\tq_ = L / i;\n\t\t\tfor (q = 0; q < q_ && q <= a; q++) {\n\t\t\t\tp = (a - q) / q_;\n\t\t\t\ty_ = y + q * i;\n\t\t\t\tdq[y_] = max(dq[y_], dp[y] + p);\n\t\t\t}\n\t\t}\n\t\tfor (y = 0; y < L * K; y++)\n\t\t\tdp[y] = dq[y];\n\t}\n\tans = 0;\n\tfor (y = 0; y < L * K && y <= w; y++)\n\t\tans = max(ans, min((w - y) / L, dp[y]) * L + y);\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6ff346c894c5487fd7674b0c933ccdd8", "src_uid": "8097e10157320524c0faed56f2bc4880", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nlong long int cnt[8];\nlong long int Maximum_Weight(long long int amount,int n)\n{\n    long long int iterations=n-1,maximum_weight=0,current_weight=0,used=amount/n,weight_using_it,i;\n    if(used>cnt[n-1]) used=cnt[n-1];\n    if(used+1<iterations) iterations=used+1;\n    weight_using_it=used*n;\n    current_weight=maximum_weight=weight_using_it;\n    for(i=0;i<iterations;i++)\n    {\n        current_weight=weight_using_it-i*n+Maximum_Weight(amount-(weight_using_it-i*n),n-1);\n        if(maximum_weight<current_weight) maximum_weight=current_weight;\n    }\n    return maximum_weight;\n}\nint main()\n{\n    long long int W,max_weight=0;\n    int i;\n    scanf(\"%I64d\",&W);\n    for(i=0;i<8;i++)\n    {\n        scanf(\"%I64d\",&cnt[i]);\n    }\n    max_weight=Maximum_Weight(W,8);\n    printf(\"%I64d\",max_weight);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c8eed6c94c5d5508cdf76a89c89f5e57", "src_uid": "8097e10157320524c0faed56f2bc4880", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nlong long int arr[15], w, ans;\n \nvoid dp(int x, long long int y) \n{\n\tif (x > 8) \n\t{ \n\t\tif (y > ans) \n\t\t{\n\t\t\tans = y;\n\t\t}\n\t\treturn;\n\t}\n\tlong long int k = arr[x];\n\tlong long int temp = (w-y) / x;\n\tif (k > temp) \n\t{\n\t\tk = temp;\n\t}\n\tlong long int i = k - 6;\n\tif (i < 0) \n\t{\n\t\ti = 0;\n\t}\n\twhile(i <= k)\n\t{\n\t\tdp(x + 1, y + i * x);\n\t\ti++;\n\t}\n\t \n}\n \nint main() \n{\n\tscanf(\"%lld\", &w);\n\tans = 0;\n\tfor (int i = 1; i <= 8; i++)\n\t{\n\t\tscanf(\"%lld\", &arr[i]);\n\t}\n\tdp(1, 0);\n\tprintf(\"%lld\", ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f09c1d43d41702b33aa19fab6c35f1d2", "src_uid": "8097e10157320524c0faed56f2bc4880", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "\n#include <iostream>\n\n#include<vector>\n\n#include<algorithm>\n\n#include<queue>\n\n#include<string>\n\nusing namespace std;\n\n\n\ntypedef long long ll;\n\n\n\nll a[15], w, ans;\n\nvoid dfs(int x, ll y)\n\n{\n\n\tif (x>8) {\n\n\t\tans = max(ans, y); \n\n\t\treturn;\n\n\t}\n\n\tll k = min(a[x], (w - y) / x);\n\n\tfor(ll i=max(0ll,k-3);i<=k;i++) dfs(x+1,y+i*x);\n\n}\n\n\n\nint main()\n\n{\n\n\twhile (cin >> w)\n\n\t{\n\n\t\tans = 0;\n\n\t\tfor (int i = 1; i <= 8; i++) cin >> a[i];\n\n\t\tdfs(1, 0);\n\n\t\tcout << ans << endl;\n\n\t}\n\n\treturn 0;\n\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "48f120d21ae0b88177ffb963985760c1", "src_uid": "8097e10157320524c0faed56f2bc4880", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define MDI 1000000009\n#define MOD(a) ((a) % MDI)\n#define MOO(a) ((a) > 0 ? (a) % MDI : MDI + (a))\n#define LL long long\n\nvoid putlld(LL a)\n{\n  if(a > 9)\n    putlld(a / 10);\n  putchar(a % 10 + '0');\n}\n\nint nn[499999];\n\nint main(void)\n{\n  int i, n;\n  LL h = 0, g, t;\n  scanf(\"%d\", &n);\n  t = (n >> 1) - 1;\n  for(i = 0, nn[0] = 4; i < t - 1; i++)\n    nn[i + 1] = MOD(nn[i] << 1);\n  for(i = t - 1; i >= 0; i--){\n    g = nn[i] - 3;\n    h = MOD((h + 4) * g);\n  }\n  h = MOD(((h * h + (h << 2)) << 1) + 10);\n  putlld(h);\n  putchar('\\n');\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e5837a4d5f52018420e9916b5e780283", "src_uid": "dbcb1077e7421554ba5d69b64d22c937", "difficulty": 2600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define MD\t1000000009\n\nint main() {\n\tint n, l, ans, cnt, x, y, z;\n\n\tscanf(\"%d\", &n), n /= 2;\n\tcnt = 2, x = 1, y = 1, z = 2;\n\tfor (l = 2; l <= n; l++) {\n\t\tcnt = (cnt + x * 4LL) % MD;\n\t\tz = z * 2 % MD;\n\t\ty = (y + z) % MD;\n\t\tx = (long long) x * y % MD;\n\t}\n\tans = ((long long) cnt * cnt + 1) * 2 % MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "67a46bd190cf83646b8bf6c441b75d49", "src_uid": "dbcb1077e7421554ba5d69b64d22c937", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define MDI 1000000009\n#define MOD(a) ((a) % MDI)\ntypedef long long LL;\nenum {U, L, T, I, W};\n\nint unt[][W + 1] = {\n  {5, 2, 0, 0, 1},\n  {4, 4, 1, 1, 0},\n  {4, 2, 0, 0, 0},\n  {4, 0, 0, 0, 0}\n};\n\nvoid putlld(LL a)\n{\n  if(a > 9)\n    putlld(a / 10);\n  putchar((a % 10) + '0');\n}\n\nint main(void)\n{\n  int i, j, k;\n  LL h = 0, g, n, f, t;\n  scanf(\"%d\", &n);\n  n /= 2;\n  t = n - 2;\n  for(i = 0; i < t; i++){\n    f = t - i;\n    g = MOD(MOD(2 << (f + 1) - 1) << 2);\n    h = MOD(4 + h + MOD(g << 2) + MOD(h * g));\n  }\n  if(n > 1)\n    h = MOD(4 + h);\n  h = MOD(MOD(MOD(h * h) + 5 + MOD(h << 2) << 1));\n  putlld(h);\n  putchar('\\n');\n  return 0;\n}\n\n#undef WERTYUIOPASDFGHJKLZXCVBN\n#ifdef WERTYUIOPASDFGHJKLZXCVBN\n/*\n * it starts and ends in the same place \u2014 the granny's house;\n * the route goes along the forest paths only (these are the segments marked black in the picture);\n * the route has positive length (to step out for a breath of fresh air Peter has to cover some distance anyway);\n * the route cannot cross itself;\n * there shouldn't be any part of dense forest within the part marked out by this route; \n I:\n 2\n O:\n 10\n I:\n 4\n O:\n 74\n */\n#endif\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "71875096ab069d8267ef68a8ce7e3992", "src_uid": "dbcb1077e7421554ba5d69b64d22c937", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define MDI 1000000009\n#define MOD(a) ((a) % MDI)\ntypedef long long LL;\n\nvoid putlld(LL a)\n{\n  if(a > 9)\n    putlld(a / 10);\n  putchar((a % 10) + '0');\n}\n\nint main(void)\n{\n  int i, j, k;\n  LL h = 0, g, n, f, t;\n  scanf(\"%d\", &n);\n  n /= 2;\n  t = n - 2;\n  for(i = 0; i < t; i++){\n    f = t - i;\n    g = MOD(MOD(2 << (f + 1) - 1) << 2);\n    h = MOD(4 + h + MOD(g << 2) + MOD(h * g));\n  }\n  if(n > 1)\n    h = MOD(4 + h);\n  h = MOD(MOD(MOD(h * h) + 5 + MOD(h << 2) << 1));\n  putlld(h);\n  putchar('\\n');\n  return 0;\n}\n\n#undef WERTYUIOPASDFGHJKLZXCVBN\n#ifdef WERTYUIOPASDFGHJKLZXCVBN\n/*\n * it starts and ends in the same place \u2014 the granny's house;\n * the route goes along the forest paths only (these are the segments marked black in the picture);\n * the route has positive length (to step out for a breath of fresh air Peter has to cover some distance anyway);\n * the route cannot cross itself;\n * there shouldn't be any part of dense forest within the part marked out by this route; \n I:\n 2\n O:\n 10\n I:\n 4\n O:\n 74\n */\n#endif\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bd76911c8e26bc26dd342d1d5a93e307", "src_uid": "dbcb1077e7421554ba5d69b64d22c937", "difficulty": 2600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define MD\t1000000009\n\nint main() {\n\tint n, l, ans, cnt, x, y, z;\n\n\tscanf(\"%d\", &n), n /= 2;\n\tcnt = 2, x = 1, y = 1, z = 2;\n\tfor (l = 2; l <= n; l++) {\n\t\tcnt = (cnt + x * 4LL) % MD;\n\t\tz = z * 2 % MD;\n\t\ty = (y + z) % MD;\n\t\tx = (x + y) % MD;\n\t}\n\tans = ((long long) cnt * cnt + 1) * 2 % MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "178e97b3a9af3c2e944f49c4e08080c6", "src_uid": "dbcb1077e7421554ba5d69b64d22c937", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint d[10][10];\nint N;\n\nint read_in(int i, int j)\n{\n\treturn (i==N) ? (0) : \n\t\t((j==N) ? (read_in(i+1,0)) : ({scanf(\"%d\",&(d[i][j])); read_in(i,j+1);}));\n}\n\nint find_dist(int i, int j, int k)\n{\n\treturn (k==N) ? (0) : \n\t\t((i==N) ? (find_dist(0,0,k+1)) : \n\t\t\t((j==N) ? (find_dist(i+1,0,k)) : \n\t\t\t\t(\n\t\t\t\t\t{\n\t\t\t\t\t\t(d[i][j] > d[i][k]+d[k][j]) ? \n\t\t\t\t\t\t\t(d[i][j] = d[i][k] + d[k][j]) : (0); find_dist(i,j+1,k);\n\t\t\t\t\t}\n\t\t\t\t)\n\t\t\t)\n\t\t);\n}\n\nint find_max(int i, int j)\n{\n\treturn (i == N) ? (0) :\n\t\t(j==N) ? (find_max(i+1,0)) : \n\t\t\t(d[i][j] > find_max(i,j+1)) ? (d[i][j]) : (find_max(i,j+1));\n}\n\nint main()\n{\n\tscanf(\"%d\", &N);\n\t\n\tread_in(0,0);\n\tprint_mat();\n\t\n\tfind_dist(0,0,0);\n\tprint_mat();\n\t\n\tprintf(\"%d\\n\",find_max(0,0));\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "0dd9e36867d40f0c6cd533fe35c41706", "src_uid": "bbd210065f8b32de048a2d9b1b033ed5", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nconst unsigned char N = (unsigned char) 10;\n\nunsigned char n;\nint x;\nunsigned char mat[N][N];\n\ninline unsigned char smin(const unsigned char& a, const unsigned char& b) { return a < b ? a : b; }\ninline unsigned char smax(const unsigned char& a, const unsigned char& b) { return a > b ? a : b; }\n\ninline unsigned char FOR3(const unsigned char& k, const unsigned char& i, const unsigned char& j) {\n    mat[i][j] = smin(mat[i][j], mat[i][k] + mat[k][j]);\n    return j + 1 < n ? FOR3(k, i, j + 1) : 0;\n}\n\ninline unsigned char FOR2(const unsigned char& i, const unsigned char& j) {\n    FOR3(i, j, 0);\n    return j + 1 < n ? FOR2(i, j + 1) : 0;\n}\n\ninline unsigned char FOR1(const unsigned char& i) {\n    FOR2(i, 0);\n    return i + 1 < n ? FOR1(i + 1) : 0;\n}\n\ninline unsigned char FOR_INPUT2(const unsigned char& i, const unsigned char& j) {\n    scanf(\"%d\", &x);\n    mat[i][j] = x;\n    return j + 1 < n ? FOR_INPUT2(i, j + 1) : 0;\n}\n\ninline unsigned char FOR_INPUT1(const unsigned char& i) {\n    FOR_INPUT2(i, 0);\n    return i + 1 < n ? FOR_INPUT1(i + 1) : 0;\n}\n\ninline unsigned char BILLY2(const unsigned char& i, const unsigned char& j) {\n    return smax(mat[i][j], j + 1 < n ? BILLY2(i, j + 1) : 0);\n}\n\ninline unsigned char BILLY1(const unsigned char& i) {\n    unsigned char ans = BILLY2(i, 0);\n    unsigned char other = i + 1 < n ? BILLY1(i + 1) : 0;\n    return smax(ans, other);\n}\n\ninline void solve() {\n    scanf(\"%d\", &x); n = x;\n    FOR_INPUT1(0);\n    FOR1(0);\n    printf(\"%d\\n\", BILLY1(0));\n}\n\nint main() {\n    solve();\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "445d68e30e680e8b01a28562f0851dbe", "src_uid": "bbd210065f8b32de048a2d9b1b033ed5", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nusing namespace std;\n\nconst unsigned char N = (unsigned char) 10;\n\nunsigned char n;\nint x;\nunsigned char mat[10][10];\n\ninline unsigned char smin(const unsigned char a, const unsigned char b) { return a < b ? a : b; }\ninline unsigned char smax(const unsigned char a, const unsigned char b) { return a > b ? a : b; }\n\ninline unsigned char FOR3(const unsigned char k, const unsigned char i, const unsigned char j)  {\n    mat[i][j] = smin(mat[i][j], mat[i][k] + mat[k][j]);\n    return j + 1 < n ? FOR3(k, i, j + 1) : 0;\n}\n\ninline unsigned char FOR2(const unsigned char i, const unsigned char j) {\n    FOR3(i, j, 0);\n    return j + 1 < n ? FOR2(i, j + 1) : 0;\n}\n\ninline unsigned char FOR1(const unsigned char i) {\n    FOR2(i, 0);\n    return i + 1 < n ? FOR1(i + 1) : 0;\n}\n\ninline unsigned char FOR4(const unsigned char k, const unsigned char i, const unsigned char j)  {\n    mat[i][j] = smin(mat[i][j], mat[i][k] + mat[k][j]);\n    return j + 1 < n ? FOR4(k, i, j + 1) :\n                i + 1 < n ? FOR4(k, i + 1, 0) :\n                k + 1 < n ? FOR4(k + 1, 0, 0) : 0;\n}\n\ninline unsigned char FOR_INPUT2(const unsigned char i, const unsigned char j) {\n    scanf(\"%d\", &x);\n    mat[i][j] = x;\n    return j + 1 < n ? FOR_INPUT2(i, j + 1) : 0;\n}\n\ninline unsigned char FOR_INPUT1(const unsigned char i) {\n    FOR_INPUT2(i, 0);\n    return i + 1 < n ? FOR_INPUT1(i + 1) : 0;\n}\n\ninline unsigned char BILLY2(const unsigned char i, const unsigned char j) {\n    return smax(mat[i][j], j + 1 < n ? BILLY2(i, j + 1) : 0);\n}\n\ninline unsigned char BILLY1(const unsigned char i) {\n    unsigned char ans = BILLY2(i, 0);\n    unsigned char other = i + 1 < n ? BILLY1(i + 1) : 0;\n    return smax(ans, other);\n}\n\ninline void solve() {\n    scanf(\"%d\", &x); n = x;\n    FOR_INPUT1(0);\n    // FOR1(0);\n    FOR4(0, 0, 0);\n    printf(\"%d\\n\", BILLY1(0));\n}\n\nint main() {\n    solve();\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "86ea06fa485ad614ee36f93c7a1910de", "src_uid": "bbd210065f8b32de048a2d9b1b033ed5", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nconst unsigned char N = (unsigned char) 10;\n\nunsigned char n;\nint x;\nunsigned char mat[N][N];\n\ninline unsigned char smin(const unsigned char a, const unsigned char b) { return a < b ? a : b; }\ninline unsigned char smax(const unsigned char a, const unsigned char b) { return a > b ? a : b; }\n\ninline unsigned char FOR3(const unsigned char k, const unsigned char i, const unsigned char j) {\n    mat[i][j] = smin(mat[i][j], mat[i][k] + mat[k][j]);\n    return j + 1 < n ? FOR3(k, i, j + 1) : 0;\n}\n\ninline unsigned char FOR2(const unsigned char i, const unsigned char j) {\n    FOR3(i, j, 0);\n    return j + 1 < n ? FOR2(i, j + 1) : 0;\n}\n\ninline unsigned char FOR1(const unsigned char i) {\n    FOR2(i, 0);\n    return i + 1 < n ? FOR1(i + 1) : 0;\n}\n\ninline unsigned char FOR_INPUT2(const unsigned char i, const unsigned char j) {\n    scanf(\"%d\", &x);\n    mat[i][j] = x;\n    return j + 1 < n ? FOR_INPUT2(i, j + 1) : 0;\n}\n\ninline unsigned char FOR_INPUT1(const unsigned char i) {\n    FOR_INPUT2(i, 0);\n    return i + 1 < n ? FOR_INPUT1(i + 1) : 0;\n}\n\ninline unsigned char BILLY2(const unsigned char i, const unsigned char j) {\n    return smax(mat[i][j], j + 1 < n ? BILLY2(i, j + 1) : 0);\n}\n\ninline unsigned char BILLY1(const unsigned char i) {\n    unsigned char ans = BILLY2(i, 0);\n    unsigned char other = i + 1 < n ? BILLY1(i + 1) : 0;\n    return smax(ans, other);\n}\n\ninline void solve() {\n    scanf(\"%d\", &x); n = x;\n    FOR_INPUT1(0);\n    FOR1(0);\n    printf(\"%d\\n\", BILLY1(0));\n}\n\nint main() {\n    solve();\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "cffc2a6a800f46631bb85cab7a214afc", "src_uid": "bbd210065f8b32de048a2d9b1b033ed5", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nusing namespace std;\n\nconst unsigned char N = (unsigned char) 10;\n\nunsigned char n;\nint x;\nunsigned char mat[N][N];\n\ninline unsigned char smin(const unsigned char& a, const unsigned char& b) { return a < b ? a : b; }\ninline unsigned char smax(const unsigned char& a, const unsigned char& b) { return a > b ? a : b; }\n\ninline unsigned char FOR3(const unsigned char& k, const unsigned char& i, const unsigned char& j) {\n    mat[i][j] = smin(mat[i][j], mat[i][k] + mat[k][j]);\n    return j + 1 < n ? FOR3(k, i, j + 1) : 0;\n}\n\ninline unsigned char FOR2(const unsigned char& i, const unsigned char& j) {\n    FOR3(i, j, 0);\n    return j + 1 < n ? FOR2(i, j + 1) : 0;\n}\n\ninline unsigned char FOR1(const unsigned char& i) {\n    FOR2(i, 0);\n    return i + 1 < n ? FOR1(i + 1) : 0;\n}\n\ninline unsigned char FOR_INPUT2(const unsigned char& i, const unsigned char& j) {\n    scanf(\"%d\", &x);\n    mat[i][j] = x;\n    return j + 1 < n ? FOR_INPUT2(i, j + 1) : 0;\n}\n\ninline unsigned char FOR_INPUT1(const unsigned char& i) {\n    FOR_INPUT2(i, 0);\n    return i + 1 < n ? FOR_INPUT1(i + 1) : 0;\n}\n\ninline unsigned char BILLY2(const unsigned char& i, const unsigned char& j) {\n    return smax(mat[i][j], j + 1 < n ? BILLY2(i, j + 1) : 0);\n}\n\ninline unsigned char BILLY1(const unsigned char& i) {\n    unsigned char ans = BILLY2(i, 0);\n    unsigned char other = i + 1 < n ? BILLY1(i + 1) : 0;\n    return smax(ans, other);\n}\n\ninline void solve() {\n    scanf(\"%d\", &x); n = x;\n    FOR_INPUT1(0);\n    FOR1(0);\n    printf(\"%d\\n\", BILLY1(0));\n}\n\nint main() {\n    solve();\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e1efc0cd71706fe6cac54cf0e9fb0a6b", "src_uid": "bbd210065f8b32de048a2d9b1b033ed5", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int Lint;\nLint N;\n\nLint asal(Lint x){\n\tfor(Lint i=2 ; i*i<=x ; i++)\n\t\tif(x%i==0)\n\t\t\treturn 0;\n\treturn 1;\n}\n\nint main()\n{\n\tLint x,y;\n\tcin >> N ;\n\tif(asal(N)){\n\t\tcout << 1 << '\\n' << N << '\\n';\n\t\treturn 0;\n\t}\n\n\tN--;\n\tif(N%2==0) N--;\n\n\tfor(Lint i=N ; ; i-=2)\n\t\tif(N-i>=4 && asal(i)){\n\t\t\tx=i;\n\t\t\tbreak;}\n\n\ty=N-x;\n\n\tfor(Lint i=2 ; i<=N ; i++){\n\t\tif(y-i>=2 && asal(i) && asal(y-i)){\n\t\t\tprintf(\"3\\n%lld %lld %lld\\n\",x,i,y-i);\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "89db6e8655d36b51ac949f5142a36377", "src_uid": "f2aaa149ce81bf332d0b5d80b2a13bc3", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int Lint;\nLint N;\n\nLint asal(Lint x){\n\tfor(Lint i=2 ; i*i<=x ; i++)\n\t\tif(x%i==0)\n\t\t\treturn 0;\n\treturn 1;\n}\n\nint main()\n{\n\tLint x,y;\n\tcin >> N ;\n\tif(asal(N)){\n\t\tcout << 1 << '\\n' << N << '\\n';\n\t\treturn 0;\n\t}\n\n\tN--;\n\tif(N%2==0) N--;\n\n\tfor(Lint i=N ; ; i-=2)\n\t\tif(N-i>=6 && asal(i)){\n\t\t\tx=i;\n\t\t\tbreak;}\n\n\ty=N-x;\n\n\tfor(Lint i=3 ; i<=N ; i++){\n\t\tif(y-i>=3 && asal(i) && asal(y-i)){\n\t\t\tprintf(\"3\\n%lld %lld %lld\\n\",x,i,y-i);\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "3e9dd7a9773a4d33b7bcac336e37b909", "src_uid": "f2aaa149ce81bf332d0b5d80b2a13bc3", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nusing namespace std;\ntypedef long long int Lint;\nLint N;\n\nLint asal(Lint x){\n\tfor(Lint i=2 ; i*i<=x ; i++)\n\t\tif(x%i==0)\n\t\t\treturn 0;\n\treturn 1;\n}\n\nint main()\n{\n\tLint x,y;\n\tscanf(\"%lld\",&N);\n\tif(asal(N)){\n\t\tprintf(\"1\\n%lld\\n\",N);\n\t\treturn 0;\n\t}\n\n\tN--;\n\tif(N%2==0) N--;\n\n\tfor(Lint i=N ; ; i-=2)\n\t\tif(N-i>=4 && asal(i)){\n\t\t\tx=i;\n\t\t\tbreak;}\n\n\ty=N-x;\n\n\tfor(Lint i=2 ; i<=N ; i++){\n\t\tif(y-i>=2 && asal(i) && asal(y-i)){\n\t\t\tprintf(\"3\\n%lld %lld %lld\\n\",x,i,y-i);\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0a09bf64034ed926f0efa66d5c2cc998", "src_uid": "f2aaa149ce81bf332d0b5d80b2a13bc3", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define N 1000000\n#define M 100000\nint main() {\n    int n;\n    scanf(\"%d\",&n);\n    int p[N];\n    int i,j;\n    for(i=2; i<N; i++) {\n        p[i]=1;\n    }\n    for(i=2; i*i<N; i++) {\n        if(p[i]) {//\u8fd9\u91cc\u8282\u7701\u4e86\u4e00\u4e9b\u67e5\u627e\uff01\n            for(j=i; i*j<N; j++) {//j=i\u4e5f\u8282\u7701\u4e86\u4e00\u4e9b\u67e5\u627e\uff01\n                p[i*j]=0;\n            }\n        }\n    }\n    p[0]=0;\n    p[1]=0;\n    int prime[M];\n    int np=0;\n    for(i=2; i<N; i++) {\n        if(p[i]){\n            prime[np]=i;\n            np++;\n        }\n    }\n    if(p[n]==1){\n        printf(\"1\\n%d\\n\",n);\n    }else{\n        int find=0;\n        //printf(\"%d\\n\",np);\n        int p1,p2,p3;\n        for(i=0;!find && prime[i]<=n && i<np;i++){\n            for(j=i;!find && prime[i]+prime[j]<=n && j<np;j++){\n                if(n-prime[i]-prime[j]==0){\n                    find=1;\n                    p1=prime[i];\n                    p2=prime[j];\n                    p3=0;\n                }else if(p[n-prime[i]-prime[j]]==1){\n                    find=1;\n                    p1=prime[i];\n                    p2=prime[j];\n                    p3=n-prime[i]-prime[j];\n                }\n            }\n        }\n        if(p3==0){\n            printf(\"2\\n\");\n            printf(\"%d %d\\n\",p1,p2);\n        }else{\n            printf(\"3\\n\");\n            printf(\"%d %d %d\\n\",p1,p2,p3);\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "241d49fcb656caaed494ff7905dbcbcb", "src_uid": "f2aaa149ce81bf332d0b5d80b2a13bc3", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define N 10000000\n#define M 1000000\nint main() {\n    int n;\n    scanf(\"%d\",&n);\n    int p[N];\n    int i,j;\n    for(i=2; i<N; i++) {\n        p[i]=1;\n    }\n    for(i=2; i*i<N; i++) {\n        if(p[i]) {//\u8fd9\u91cc\u8282\u7701\u4e86\u4e00\u4e9b\u67e5\u627e\uff01\n            for(j=i; i*j<N; j++) {//j=i\u4e5f\u8282\u7701\u4e86\u4e00\u4e9b\u67e5\u627e\uff01\n                p[i*j]=0;\n            }\n        }\n    }\n    p[0]=0;\n    p[1]=0;\n    int prime[M];\n    int np=0;\n    for(i=2; i<N; i++) {\n        if(p[i]){\n            prime[np]=i;\n            np++;\n            if(np>=M){\n                printf(\"\u5185\u5b58\u4e0d\u591f\\n\");\n                break;\n            }\n        }\n    }\n    if(p[n]==1){\n        printf(\"1\\n%d\\n\",n);\n    }else{\n        int find=0;\n        //printf(\"%d\\n\",np);\n        int p1,p2,p3;\n        for(i=0;!find && prime[i]<=n && i<np;i++){\n            for(j=i;!find && prime[i]+prime[j]<=n && j<np;j++){\n                if(n-prime[i]-prime[j]==0){\n                    find=1;\n                    p1=prime[i];\n                    p2=prime[j];\n                    p3=0;\n                }else if(p[n-prime[i]-prime[j]]==1){\n                    find=1;\n                    p1=prime[i];\n                    p2=prime[j];\n                    p3=n-prime[i]-prime[j];\n                }\n            }\n        }\n        if(p3==0){\n            printf(\"2\\n\");\n            printf(\"%d %d\\n\",p1,p2);\n        }else{\n            printf(\"3\\n\");\n            printf(\"%d %d %d\\n\",p1,p2,p3);\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "969082f618baf7cfb00acf923912e353", "src_uid": "f2aaa149ce81bf332d0b5d80b2a13bc3", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n\nint main(){\n\tint t,z,n,i;\n\tscanf(\"%d\",&n);\n\tz=t=1;\n\tfor(i=1;i<=n;i++){\n\t\tz=(z*i)%1000000007;\n\t}\n\tfor(i=1;i<=(n-1);i++){\n\t\tt=(t*2)%1000000007;\n\t}\n\tz=(z-t);\n\tprintf(\"%d\",z);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "73cf3d9818830ab8322147474c8f79f7", "src_uid": "3dc1ee09016a25421ae371fa8005fce1", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define M 1000000007;\nint main()\n{\n    int t,n,i,ans;\n    long long int pow,fact;\n    scanf(\"%d\",&t);\n    while(t--)\n    {\n        pow=fact=1;\n        scanf(\"%d\",&n);\n        for(i=1;i<=n;i++)\n        {\n            fact = fact*i;\n            fact = fact%M;\n        }\n        for(i=1;i<n;i++)\n        {\n            pow=pow*2;\n            pow=pow%M;\n        }\n        ans=fact-pow;\n        printf(\"%d\\n\",ans);\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "41ac61308df98953c390d0fa959b9cfb", "src_uid": "3dc1ee09016a25421ae371fa8005fce1", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main(){\n\tint i;\n\tlong  t,z,n;\n\tscanf(\"%ld\",&n);\n\tz=1;\n\tt=1;\n\tfor(i=1;i<=n;i++){\n\t\tz=(z*i);\n\t\tz=z%(1000000007);\n\t}\n\tfor(i=1;i<=(n-1);i++){\n\t\tt=(t*2);\n\t\tt=t%(1000000007);\n\t}\n\tz=z-t;\n\tif(z<0){\n\t\tz=z+1000000007;\n\t}\n\tprintf(\"%ld\",z);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1b05d0e9578b8a0a55733436c86bf656", "src_uid": "3dc1ee09016a25421ae371fa8005fce1", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define M 1000000007;\nint main()\n{\n    int t,n,i,ans;\n    long long int pow,fact;\n        pow=fact=1;\n        scanf(\"%d\",&n);\n        for(i=1;i<=n;i++)\n        {\n            fact = fact*i;\n            fact = fact%M;\n        }\n        for(i=1;i<n;i++)\n        {\n            pow=pow*2;\n            pow=pow%M;\n        }\n        ans=(fact-pow)%M;\n        printf(\"%d\\n\",ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e305526c407bc3d2d325b20ad2bef611", "src_uid": "3dc1ee09016a25421ae371fa8005fce1", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define M 1000000007;\nint main()\n{\n    int t,n,i,ans;\n    long long int pow,fact;\n        pow=fact=1;\n        scanf(\"%d\",&n);\n        for(i=1;i<=n;i++)\n        {\n            fact = fact*i;\n            fact = fact%M;\n        }\n        for(i=1;i<n;i++)\n        {\n            pow=pow*2;\n            pow=pow%M;\n        }\n        ans=fact-pow;\n        printf(\"%d\\n\",ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2732ad622b442d04674711f3304270a3", "src_uid": "3dc1ee09016a25421ae371fa8005fce1", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t10\n\nchar ss[16][2] = { \"B\", \"C\", \"F\", \"H\", \"I\", \"K\", \"N\", \"O\", \"P\", \"S\", \"U\", \"V\", \"W\", \"Y\" };\nchar tt[128][4] = { \"AC\", \"AG\", \"AL\", \"AM\", \"AR\", \"AS\", \"AT\", \"BA\", \"BE\", \"BH\", \"BI\", \"BK\", \"BR\", \"CA\", \"CD\", \"CE\", \"CF\", \"CL\", \"CM\", \"CN\", \"CO\", \"CR\", \"CS\", \"CU\", \"DB\", \"DS\", \"DY\", \"ER\", \"ES\", \"EU\", \"FE\", \"FM\", \"FR\", \"GD\", \"GA\", \"GE\", \"AU\", \"HE\", \"HF\", \"HO\", \"HS\", \"HG\", \"IN\", \"IR\", \"KR\", \"LA\", \"LV\", \"LR\", \"LI\", \"LU\", \"MD\", \"MG\", \"MN\", \"MO\", \"MT\", \"NA\", \"NB\", \"ND\", \"NE\", \"NI\", \"NO\", \"NP\", \"OS\", \"PA\", \"PB\", \"PD\", \"PM\", \"PO\", \"PT\", \"PU\", \"PR\", \"RA\", \"RB\", \"RE\", \"RF\", \"RG\", \"RH\", \"RN\", \"RU\", \"SB\", \"SC\", \"SE\", \"SI\", \"SG\", \"SM\", \"SN\", \"SR\", \"TA\", \"TB\", \"TC\", \"TE\", \"TH\", \"TI\", \"TL\", \"TM\", \"XE\", \"YB\", \"ZN\", \"ZR\" };\n\nint elemental1(char c) {\n\tint i;\n\n\tfor (i = 0; i < 16; i++)\n\t\tif (ss[i][0] == c)\n\t\t\treturn 1;\n\treturn 0;\n}\n\nint elemental2(char c1, char c2) {\n\tint i;\n\n\tfor (i = 0; i < 128; i++)\n\t\tif (tt[i][0] == c1 && tt[i][1] == c2)\n\t\t\treturn 1;\n\treturn 0;\n}\n\nint main() {\n\tstatic char cc[N + 1];\n\tstatic int dp[N + 1];\n\tint n, i;\n\n\tscanf(\"%s\", cc), n = strlen(cc);\n\tdp[0] = 1;\n\tfor (i = 0; i < n; i++)\n\t\tif (dp[i]) {\n\t\t\tif (elemental1(cc[i]))\n\t\t\t\tdp[i + 1] = 1;\n\t\t\tif (i + 1 < n && elemental2(cc[i], cc[i + 1]))\n\t\t\t\tdp[i + 2] = 1;\n\t\t}\n\tprintf(dp[n] ? \"YES\\n\" : \"NO\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0183ae9cffc4ebffd5f2f3d01804f929", "src_uid": "d0ad35798119f98320967127c43ae88d", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t10\n\nchar ss[16][2] = { \"B\", \"C\", \"F\", \"H\", \"I\", \"K\", \"N\", \"O\", \"P\", \"S\", \"U\", \"V\", \"W\", \"Y\" };\nchar tt[128][4] = { \"AC\", \"AG\", \"AL\", \"AM\", \"AR\", \"AS\", \"AT\", \"AU\", \"BA\", \"BE\", \"BH\", \"BI\", \"BK\", \"BR\", \"CA\", \"CD\", \"CE\", \"CF\", \"CL\", \"CM\", \"CN\", \"CO\", \"CR\", \"CS\", \"CU\", \"DB\", \"DS\", \"DY\", \"ER\", \"ES\", \"EU\", \"FE\", \"FL\", \"FM\", \"FR\", \"GD\", \"GA\", \"GE\", \"HE\", \"HF\", \"HO\", \"HS\", \"HG\", \"IN\", \"IR\", \"KR\", \"LA\", \"LV\", \"LR\", \"LI\", \"LU\", \"MC\", \"MD\", \"MG\", \"MN\", \"MO\", \"MT\", \"NA\", \"NB\", \"ND\", \"NE\", \"NH\", \"NI\", \"NO\", \"NP\", \"OG\", \"OS\", \"PA\", \"PB\", \"PD\", \"PM\", \"PO\", \"PT\", \"PU\", \"PR\", \"RA\", \"RB\", \"RE\", \"RF\", \"RG\", \"RH\", \"RN\", \"RU\", \"SB\", \"SC\", \"SE\", \"SI\", \"SG\", \"SM\", \"SN\", \"SR\", \"TA\", \"TB\", \"TC\", \"TE\", \"TH\", \"TI\", \"TL\", \"TM\", \"XE\", \"YB\", \"ZN\", \"ZR\" };\n\nint elemental1(char c) {\n\tint i;\n\n\tfor (i = 0; i < 16; i++)\n\t\tif (ss[i][0] == c)\n\t\t\treturn 1;\n\treturn 0;\n}\n\nint elemental2(char c1, char c2) {\n\tint i;\n\n\tfor (i = 0; i < 128; i++)\n\t\tif (tt[i][0] == c1 && tt[i][1] == c2)\n\t\t\treturn 1;\n\treturn 0;\n}\n\nint main() {\n\tstatic char cc[N + 1];\n\tstatic int dp[N + 1];\n\tint n, i;\n\n\tscanf(\"%s\", cc), n = strlen(cc);\n\tdp[0] = 1;\n\tfor (i = 0; i < n; i++)\n\t\tif (dp[i]) {\n\t\t\tif (elemental1(cc[i]))\n\t\t\t\tdp[i + 1] = 1;\n\t\t\tif (i + 1 < n && elemental2(cc[i], cc[i + 1]))\n\t\t\t\tdp[i + 2] = 1;\n\t\t}\n\tprintf(dp[n] ? \"YES\\n\" : \"NO\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8ede153c541f7ceceb1c485b7a9ad1ba", "src_uid": "d0ad35798119f98320967127c43ae88d", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t10\n\nchar ss[][2] = { \"B\", \"C\", \"D\", \"F\", \"H\", \"I\", \"K\", \"N\", \"O\", \"P\", \"S\", \"U\", \"V\", \"W\", \"Y\" };\nchar tt[102][4] = { \"AC\", \"AG\", \"AL\", \"AM\", \"AR\", \"AS\", \"AT\", \"BA\", \"BE\", \"BH\", \"BI\", \"BK\", \"BR\", \"CA\", \"CD\", \"CE\", \"CF\", \"CL\", \"CM\", \"CN\", \"CO\", \"CR\", \"CS\", \"CU\", \"DB\", \"DS\", \"DY\", \"ER\", \"ES\", \"EU\", \"FE\", \"FL\", \"FM\", \"FR\", \"GD\", \"GA\", \"GE\", \"AU\", \"HE\", \"HF\", \"HO\", \"HS\", \"HG\", \"IN\", \"IR\", \"KR\", \"LA\", \"LR\", \"LI\", \"LU\", \"LV\", \"MD\", \"MG\", \"MN\", \"MO\", \"MT\", \"NA\", \"NB\", \"ND\", \"NE\", \"NI\", \"NO\", \"NP\", \"OG\", \"OS\", \"PA\", \"PB\", \"PD\", \"PM\", \"PO\", \"PT\", \"PU\", \"PR\", \"RA\", \"RB\", \"RE\", \"RF\", \"RG\", \"RH\", \"RN\", \"RU\", \"SB\", \"SC\", \"SE\", \"SI\", \"SG\", \"SM\", \"SN\", \"SR\", \"TA\", \"TB\", \"TC\", \"TE\", \"TH\", \"TI\", \"TL\", \"TM\", \"XE\", \"YB\", \"ZN\", \"ZR\" };\n\nint elemental1(char c) {\n\tint i;\n\n\tfor (i = 0; i < 15; i++)\n\t\tif (ss[i][0] == c)\n\t\t\treturn 1;\n\treturn 0;\n}\n\nint elemental2(char c1, char c2) {\n\tint i;\n\n\tfor (i = 0; i < 101; i++)\n\t\tif (tt[i][0] == c1 && tt[i][1] == c2)\n\t\t\treturn 1;\n\treturn 0;\n}\n\nint elemental3(char c1, char c2, char c3) {\n\treturn c1 == 'U' && c2 == 'U' && (c3 == 'T' || c3 == 'P' || c3 == 'S');\n}\n\nint main() {\n\tstatic char cc[N + 1];\n\tstatic int dp[N + 1];\n\tint n, i;\n\n\tscanf(\"%s\", cc), n = strlen(cc);\n\tdp[0] = 1;\n\tfor (i = 0; i < n; i++)\n\t\tif (dp[i]) {\n\t\t\tif (elemental1(cc[i]))\n\t\t\t\tdp[i + 1] = 1;\n\t\t\tif (i + 1 < n && elemental2(cc[i], cc[i + 1]))\n\t\t\t\tdp[i + 2] = 1;\n\t\t\tif (i + 2 < n && elemental3(cc[i], cc[i + 1], cc[i + 2]))\n\t\t\t\tdp[i + 3] = 1;\n\t\t}\n\tprintf(dp[n] ? \"YES\\n\" : \"NO\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "eec8d080bfd65d819b57edeb5a85a7bb", "src_uid": "d0ad35798119f98320967127c43ae88d", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t10\n\nchar ss[][2] = { \"B\", \"C\", \"D\", \"F\", \"H\", \"I\", \"K\", \"N\", \"O\", \"P\", \"S\", \"U\", \"V\", \"W\", \"Y\" };\nchar tt[102][4] = { \"AC\", \"AG\", \"AL\", \"AM\", \"AR\", \"AS\", \"AT\", \"BA\", \"BE\", \"BH\", \"BI\", \"BK\", \"BR\", \"CA\", \"CD\", \"CE\", \"CF\", \"CL\", \"CM\", \"CN\", \"CO\", \"CR\", \"CS\", \"CU\", \"DB\", \"DS\", \"DY\", \"ER\", \"ES\", \"EU\", \"FE\", \"FL\", \"FM\", \"FR\", \"GD\", \"GA\", \"GE\", \"AU\", \"HE\", \"HF\", \"HO\", \"HS\", \"HG\", \"IN\", \"IR\", \"KR\", \"LA\", \"LR\", \"LI\", \"LU\", \"LV\", \"MD\", \"MG\", \"MN\", \"MO\", \"MT\", \"NA\", \"NB\", \"ND\", \"NE\", \"NI\", \"NO\", \"NP\", \"OG\", \"OS\", \"PA\", \"PB\", \"PD\", \"PM\", \"PO\", \"PT\", \"PU\", \"PR\", \"RA\", \"RB\", \"RE\", \"RF\", \"RG\", \"RH\", \"RN\", \"RU\", \"SB\", \"SC\", \"SE\", \"SI\", \"SG\", \"SM\", \"SN\", \"SR\", \"TA\", \"TB\", \"TC\", \"TE\", \"TH\", \"TI\", \"TL\", \"TM\", \"XE\", \"YB\", \"ZN\", \"ZR\" };\n\nint elemental1(char c) {\n\tint i;\n\n\tfor (i = 0; i < 15; i++)\n\t\tif (ss[i][0] == c)\n\t\t\treturn 1;\n\treturn 0;\n}\n\nint elemental2(char c1, char c2) {\n\tint i;\n\n\tfor (i = 0; i < 102; i++)\n\t\tif (tt[i][0] == c1 && tt[i][1] == c2)\n\t\t\treturn 1;\n\treturn 0;\n}\n\nint elemental3(char c1, char c2, char c3) {\n\treturn c1 == 'U' && c2 == 'U' && (c3 == 'T' || c3 == 'P' || c3 == 'S');\n}\n\nint main() {\n\tstatic char cc[N + 1];\n\tstatic int dp[N + 1];\n\tint n, i;\n\n\tscanf(\"%s\", cc), n = strlen(cc);\n\tdp[0] = 1;\n\tfor (i = 0; i < n; i++)\n\t\tif (dp[i]) {\n\t\t\tif (elemental1(cc[i]))\n\t\t\t\tdp[i + 1] = 1;\n\t\t\tif (i + 1 < n && elemental2(cc[i], cc[i + 1]))\n\t\t\t\tdp[i + 2] = 1;\n\t\t\tif (i + 2 < n && elemental3(cc[i], cc[i + 1], cc[i + 2]))\n\t\t\t\tdp[i + 3] = 1;\n\t\t}\n\tprintf(dp[n] ? \"YES\\n\" : \"NO\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "26141e69d91c0f372dd008a27aa7b273", "src_uid": "d0ad35798119f98320967127c43ae88d", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t10\n\nchar ss[][2] = { \"B\", \"C\", \"D\", \"F\", \"H\", \"I\", \"K\", \"N\", \"O\", \"P\", \"S\", \"U\", \"V\", \"W\", \"Y\" };\nchar tt[][4] = { \"AC\", \"AG\", \"AL\", \"AM\", \"AR\", \"AS\", \"AT\", \"BA\", \"BE\", \"BH\", \"BI\", \"BK\", \"BR\", \"CA\", \"CD\", \"CE\", \"CF\", \"CL\", \"CM\", \"CO\", \"CR\", \"CS\", \"CU\", \"DB\", \"DS\", \"DY\", \"ER\", \"ES\", \"EU\", \"FE\", \"FL\", \"FM\", \"FR\", \"GD\", \"GA\", \"GE\", \"AU\", \"HE\", \"HF\", \"HO\", \"HS\", \"HG\", \"IN\", \"IR\", \"KR\", \"LA\", \"LR\", \"LI\", \"LU\", \"LV\", \"MD\", \"MG\", \"MN\", \"MO\", \"MT\", \"NA\", \"NB\", \"ND\", \"NE\", \"NI\", \"NO\", \"NP\", \"OG\", \"OS\", \"PA\", \"PB\", \"PD\", \"PM\", \"PO\", \"PT\", \"PU\", \"PR\", \"RA\", \"RB\", \"RE\", \"RF\", \"RG\", \"RH\", \"RN\", \"RU\", \"SB\", \"SC\", \"SE\", \"SI\", \"SG\", \"SM\", \"SN\", \"SR\", \"TA\", \"TB\", \"TC\", \"TE\", \"TH\", \"TI\", \"TL\", \"TM\", \"XE\", \"YB\", \"ZN\", \"ZR\" };\n\nint elemental1(char c) {\n\tint i;\n\n\tfor (i = 0; i < 15; i++)\n\t\tif (ss[i][0] == c)\n\t\t\treturn 1;\n\treturn 0;\n}\n\nint elemental2(char c1, char c2) {\n\tint i;\n\n\tfor (i = 0; i < 100; i++)\n\t\tif (tt[i][0] == c1 && tt[i][1] == c2)\n\t\t\treturn 1;\n\treturn 0;\n}\n\nint main() {\n\tstatic char cc[16];\n\tstatic int dp[N + 1];\n\tint n, i;\n\n\tscanf(\"%s\", cc), n = strlen(cc);\n\tdp[0] = 1;\n\tfor (i = 0; i < n; i++)\n\t\tif (dp[i]) {\n\t\t\tif (elemental1(cc[i]))\n\t\t\t\tdp[i + 1] = 1;\n\t\t\tif (i + 1 < n && elemental2(cc[i], cc[i + 1]))\n\t\t\t\tdp[i + 2] = 1;\n\t\t}\n\tprintf(dp[n] ? \"YES\\n\" : \"NO\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1ef04b8a565ef792a099a164a142d8ff", "src_uid": "d0ad35798119f98320967127c43ae88d", "difficulty": null}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n \nint main()\n{\n    int a[32],i,n,w,x=0,p,q,r,s,t,perm[120]={12345 ,12354 ,12435 ,12453 ,12543 ,12534 ,13245 ,13254 ,13425 ,13452 ,13542 ,13524 ,14325 ,14352 ,14235 ,14253 ,14523 ,14532 ,15342 ,15324 ,15432 ,15423 ,15243 ,15234 ,21345 ,21354 ,21435 ,21453 ,21543 ,21534 ,23145 ,23154 ,23415 ,23451 ,23541 ,23514 ,24315 ,24351 ,24135 ,24153 ,24513 ,24531 ,25341 ,25314 ,25431 ,25413 ,25143 ,25134 ,32145 ,32154 ,32415 ,32451 ,32541 ,32514 ,31245 ,31254 ,31425 ,31452 ,31542 ,31524 ,34125 ,34152 ,34215 ,34251 ,34521 ,34512 ,35142 ,35124 ,35412 ,35421 ,35241 ,35214 ,42315 ,42351 ,42135 ,42153 ,42513 ,42531 ,43215 ,43251 ,43125 ,43152 ,43512 ,43521 ,41325 ,41352 ,41235 ,41253 ,41523 ,41532 ,45312 ,45321 ,45132 ,45123 ,45213 ,45231 ,52341 ,52314 ,52431 ,52413 ,52143 ,52134 ,53241 ,53214 ,53421 ,53412 ,53142 ,53124 ,54321 ,54312 ,54231 ,54213 ,54123 ,54132 ,51342 ,51324 ,51432 ,51423 ,51243 ,51234};\n    char b[5];\n    for (i=5; i<31; i++)\n    {\n        scanf(\"%d\", &a[i]);\n    }\n    for (i = 0; i<120; i++)\n    {\n        sprintf(b, \"%d\", perm[i]);\n        p = b[0] - '0';\n        q = b[1] - '0';\n        r = b[2] - '0';\n        s = b[3] - '0';\n        t = b[4] - '0';\n        n = a[(p*5)+q]+a[(q*5)+p]+a[(r*5)+s]+a[(s*5)+r]+a[(q*5)+r]+a[(r*5)+q]+a[(s*5)+t]+a[(t*5)+s]+a[(r*5)+s]+a[(s*5)+r]+a[(s*5)+t]+a[(t*5)+s];\n        if (n>x)\n        {\n            x = n;\n        }\n    }\n    printf(\"%d\",x);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "28140a544ffd5eabba27b3872cc6f0b1", "src_uid": "be6d4df20e9a48d183dd8f34531df246", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\nchar P[120][6];\nint l=0;\nswap(char *a, char *b)\n{\n    char t;\n    t=*a;\n    *a=*b;\n    *b=t;\n}\nint cost(int W[5][5], char *S)\n{\n    int sum, o,t,th,f,fi;\n    o=S[0]-49;\n    t=S[1]-49;\n    th=S[2]-49;\n    f=S[3]-49;\n    fi=S[4]-49;\n    sum=W[o][t]+W[t][o]+W[th][f]+W[f][th]+W[t][th]+W[th][t]+W[f][fi]+W[fi][f]+W[th][f]+W[f][th]+W[f][fi]+W[fi][f];\n    return sum;\n}\nperm(char *num, int pres, int size)\n{\n    int i;\n    if (pres==(size-1))\n    {\n\tstrcpy(P[l], num);\n\tl++;\n    }\n    else\n    {\n\tfor (i=pres;i<size;i++)\n\t{\n\t    swap(&num[pres], &num[i]);\n\t    perm(num, pres+1, size);\n\t    swap(&num[pres], &num[i]);\n\t}\n    }\n}\nvoid main()\n{\n    char num[]=\"12345\";\n    int i, j, max, temp, C[120], W[5][5];\n    perm(num, 0, 5);\n    for (i=0;i<5;i++)\n    {\n\tfor (j=0;j<5;j++)\n\t{\n\t    scanf(\"%i\", &W[i][j]);\n        }\n    }\n    for (i=0;i<120;i++)\n    {\n\tC[i]=cost(W, P[i]);\n    }\n    max=C[0];\n    for(i=1;i<120;i++)\n    {\n\tif (C[i]>max)\n\t    max=C[i];\n    }\n    printf(\"%i\\n\", max);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "685e7cc999665cdb7ad23b2114e67b07", "src_uid": "be6d4df20e9a48d183dd8f34531df246", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n#include <limits.h>\n#define MAX(x,y) (x)>(y) ? (x):(y)\n#define MIN(x,y) (x)>(y) ? (y):(x)\n#define scnn fscanf(stdin,\"%i\",&n)\n#define scnnd fscanf(stdin,\"%i %i\",&n,&d)\n#define scnmi fscanf(stdin,\"%i\",&m[i])\n#define forn for(i=0;i<n;i++)\n#define memmn m=(int *)malloc(n*sizeof(int))\n#define fm free(m)\n#define prntmn for(i=0;i<n;i++)fprintf(stdout,\"%i \",m[i])\n\n\n\nint main(int argc, char **argv)\n{\nint i,g[5][5],j,res,k,l,m,tmp,try;\nfor (i=0;i<5;i++)\nfor (j=0;j<5;j++)\n{\n    scanf(\"%i\",&g[i][j]);\n}\ntmp=INT_MIN;\nfor(i=0;i<5;i++)\nfor(j=0;j<5;j++)\nfor(k=0;k<5;k++)\nfor(l=0;l<5;l++)\nfor(m=0;m<5;m++)\n{\nif (i!=j && i!=k && i!=l && i!=m && j!=k && j!=l && j!=m && k!=l && k!=m && l!=m)\n{\n        try=g[i][j]+g[j][i]+g[k][l]+g[l][k]+g[j][k]+g[k][j]+g[l][m]+g[m][l]+g[k][l]+g[l][k]+g[l][m]+g[m][l];\n        if(try>tmp) {tmp=try;res=try;}       \n}\n}\nprintf(\"%i\",res);\nsystem(\"pause\");\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "19441a8fe2b055881209adf41470dd4c", "src_uid": "be6d4df20e9a48d183dd8f34531df246", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint main()\n{\n\t\n\tint x,y,z,w,u,i,sum=0,maxsum=0,k;\n\tint **a=(int **)malloc(sizeof(int *)*5);\n\tfor(i=0;i<5;i++)\n\ta[i]=(int*)malloc(sizeof(int)*5);\n\t\n\tfor(i=0;i<5;i++)\n\t\tfor(k=0;k<5;k++)\n\t\t\tscanf(\"%d\",&a[i][k]);\n\t\n\tfor(x=0;x<5;x++)\n\t\tfor(y=0;y<5;y++)\n\t\t{\n\t\t\tif(y==x)\n\t\t\tcontinue;\n\t\t\tfor(z=0;z<5;z++)\n\t\t\t{\n\t\t\t\tif(z==x || z==y)\n\t\t\t\tcontinue;\n\t\t\t\tfor(w=0;w<5;w++)\n\t\t\t\t{\n\t\t\t\t\tif(w==x || w==y || w==z)\n\t\t\t\t\tcontinue;\n\t\t\t\t\tfor(u=0;u<5;u++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif(u==x || u==y || u==z || u==w)\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\tsum=a[x][y]+a[y][x]+2*(a[z][w]+a[w][z]+a[w][u]+a[u][w])+a[y][z]+a[z][y];\n\t\t\t\t\t\tif(sum>maxsum)\n\t\t\t\t\t\tmaxsum=sum;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t\n\tprintf(\"%d\\n\",maxsum);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9d6833ae7ade5f3187204eec1b99d344", "src_uid": "be6d4df20e9a48d183dd8f34531df246", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "\n#include <stdlib.h>\n#include <stdio.h>\n#include <string.h>\n\n#define N 5\n\nint main(void) {\n   int arr[N][N];\n   int i, j;\n   int k[N];\n   for (i = 0; i < N; i++)\n      for (j = 0; j < N; j++)\n         scanf(\"%d\", &arr[i][j]);\n   int d = 0, good, ans = 0;\n   for (k[d] = 0; k[d] < 5; k[d]++){\n      good = 1;\n      for (i = 0; good && i < d; i++)\n         good = !(k[i] == k[d]);\n      if (!good)\n         continue;\n      d++;\n      for (k[d] = 0; k[d] < 5; k[d]++){\n         good = 1;\n         for (i = 0; good && i < d; i++)\n            good = !(k[i] == k[d]);\n         if (!good)\n            continue;\n         d++; \n         for (k[d] = 0; k[d] < 5; k[d]++){\n            good = 1;\n            for (i = 0; good && i < d; i++)\n               good = !(k[i] == k[d]);\n            if (!good)\n               continue;\n            d++;\n            for (k[d] = 0; k[d] < 5; k[d]++){\n               good = 1;\n               for (i = 0; good && i < d; i++)\n                  good = !(k[i] == k[d]);\n               if (!good)\n                  continue;\n               d++;\n               for (k[d] = 0; k[d] < 5; k[d]++){\n                  good = 1;\n                  for (i = 0; good && i < d; i++)\n                     good = !(k[i] == k[d]);\n                  if (!good)\n                     continue;\n                  tans = (arr[k[1]][k[2]] + arr[k[2]][k[1]] + 2*arr[0][4]+ 2*arr[4][0] + 2*arr[3][4] + 2*arr[3][4] + arr[0][2] + arr[2][0]);\n                  if (tans > ans)\n                     ans = tans;\n               }\n               d--;\n            }\n            d--;\n         }\n         d--;\n      }\n      d--;\n   }\n   printf(\"%d\\n\", ans);\n   return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8a3c26821fa58d7344176bb15ad9e480", "src_uid": "be6d4df20e9a48d183dd8f34531df246", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint main(){\n\tchar a[10], b[10], x;\n\tint i, j = 0;\n\t\n\tfor(i = 0; i < 4; ++i){\n\t\tscanf(\" %c\", &a[i]);\n\t}\n\tfor(i = 0; i < 4; ++i){\n\t\tscanf(\" %c\", &b[i]);\n\t}\n\t\n\tx = a[2]; a[2] = a[3]; a[3] = x; \n\tx = b[2]; b[2] = b[3]; b[3] = x;\n\t\n\tj = 0;\n\tfor(i = 0; i < 4; ++i){\n\t\tif(a[i] != 'X'){\n\t\t\ta[j] = a[i];\n\t\t\tj++;\n\t\t}\n\t}\n\t\n\tj = 0;\n\tfor(i = 0; i < 4; ++i){\n\t\tif(b[i] != 'X'){\n\t\t\tb[j] = b[i];\n\t\t\tj++;\n\t\t}\n\t}\n\ta[3] = '\\0';\n\tb[3] = '\\0';\n\t\n\twhile(a[0] != b[0]){\n\t\tx = b[0];\n\t\tfor(i = 1; i < 3; ++i){\n\t\t\tb[i-1] = b[i];\n\t\t}\n\t\tb[2] = x;\n\t}\t\n\t\n\tif(strcmp(a, b) == 0){\n\t\tprintf(\"YES\");\n\t}else\n\t\tprintf(\"NO\");\n\t\t\nreturn 0;\t\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c149f8028358dcde9f5c015f6b94fb10", "src_uid": "46f051f58d626587a5ec449c27407771", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#define swap(a,b,t) t=a,a=b,b=t\nint main()\n{\n    char a[3],b[3],c[3],d[3],t;\n    int i;\n    scanf(\"%s%s%s%s\",a,b,c,d);\n    for (i=0;i<900;i++)\n     if (!strcmp(a,c)&&!strcmp(b,d))\n      {\n          puts(\"YES\");\n          return 0;\n      }\n    else if (a[0]==88) swap(a[0],a[1],t);\n    else if (a[1]==88) swap(b[1],a[1],t);\n    else if (b[0]==88) swap(a[0],b[0],t);\n    else if (b[1]==88) swap(b[0],b[1],t);\n    puts(\"NO\");\n      return 0;\n}/*2016-04-13 21:12:50.952*/", "lang_cluster": "C", "compilation_error": false, "code_uid": "0d7a5785ec6cb2c3b3a0141021492c23", "src_uid": "46f051f58d626587a5ec449c27407771", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "include<stdio.h>\n#include<string.h>\n\nint main(){\n\tchar a[10], b[10], x;\n\tint i, j = 0;\n\t\n\tfor(i = 0; i < 4; ++i){\n\t\tscanf(\" %c\", &a[i]);\n\t}\n\tfor(i = 0; i < 4; ++i){\n\t\tscanf(\" %c\", &b[i]);\n\t}\n\t\n\tx = a[2]; a[2] = a[3]; a[3] = x; \n\tx = b[2]; b[2] = b[3]; b[3] = x;\n\t\n\tj = 0;\n\tfor(i = 0; i < 4; ++i){\n\t\tif(a[i] != 'X'){\n\t\t\ta[j] = a[i];\n\t\t\tj++;\n\t\t}\n\t}\n\t\n\tj = 0;\n\tfor(i = 0; i < 4; ++i){\n\t\tif(b[i] != 'X'){\n\t\t\tb[j] = b[i];\n\t\t\tj++;\n\t\t}\n\t}\n\ta[3] = '\\0';\n\tb[3] = '\\0';\n\t\n\twhile(a[0] != b[0]){\n\t\tx = b[0];\n\t\tfor(i = 1; i < 3; ++i){\n\t\t\tb[i-1] = b[i];\n\t\t}\n\t\tb[2] = x;\n\t}\t\n\t\n\tif(strcmp(a, b) == 0){\n\t\tprintf(\"YES\");\n\t}else\n\t\tprintf(\"NO\");\n\t\t\nreturn 0;\t\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4eb74378aa83035f8c1e0949392873f7", "src_uid": "46f051f58d626587a5ec449c27407771", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint main(){\n\t\n\tchar a[2][2], b[2][2], aa[4], bb[4];\n\tint i, j, a_x, a_y,  b_x, b_y, same=0;\n\n\t//for (i=0; i<2; i++)\n\t//\tscanf(\"%c%c\\n%c%c\\n\", &a[0][0], &a[0][1], &a[1][0], &a[1][1]);\n\tscanf(\"%c%c\\n%c%c\\n\", &aa[0], &aa[3], &aa[1], &aa[2]);\n\t//for (i=0; i<2; i++)\n\t//\tscanf(\"%c%c\\n%c%c\", &b[0][0], &b[0][1], &b[1][0], &b[1][1]);\n\tscanf(\"%c%c\\n%c%c\", &bb[0], &bb[3], &bb[1], &bb[2]);\n\n\t/*printf(\"%s %s\\n\", a[0], b[0]);\n\n\tfor (i=0; i<2; i++){\n\t\tfor (j=0; j<2; j++){\n\t\t\tif ( a[i][j] == 'X' ){\n\t\t\t\ta_x = i; a_y = j;\n\t\t\t}\n\t\t\tif ( b[i][j] == 'X' ){\n\t\t\t\tb_x = i; b_y = j;\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"%d %d %d %d\\n\", a_x, a_y, b_x, b_y); \n*/\n\t//printf(\"%c %c %c %c\\n\", aa[0], aa[1], aa[2], aa[3]);\n\t//printf(\"%c %c %c %c\\n\", bb[0], bb[1], bb[2], bb[3]);\n\n\tfor (i=0; i<4; i++){\n\t\tif (aa[i] == 'X')\n\t\t\tcontinue;\n\t\ta_x = aa[i];\n\n\t\tfor (j=0; j%4<4; j++){\n\t\t\tif (a_x == bb[j])\n\t\t\t\tbreak;\n\t\t}\n\n\t\twhile (1){\n\t\t\tif ( aa[i] == 'X'){\n\t\t\t\ti++;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\telse if ( bb[j%4] == 'X'){\n\t\t\t\tj++;\n\t\t\t\tcontinue;}\n\t\t\t//printf(\"%d %d\\n\", i , j);\n\t\t\tif (i==4)\n\t\t\t\tbreak;\n\t\t\tif ( aa[i++] == bb[(j++)%4] )\n\t\t\t{\n\t\t\t\tsame++;\n\t\t\t}\n\n\t\t\t\n\t\t}\n\t}\n\n\tif ( same==3 )\n\t\tprintf(\"YES\\n\");\n\telse\n\t\tprintf(\"NO\\n\");\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "855f057732a72935a383c1534a6e2aa0", "src_uid": "46f051f58d626587a5ec449c27407771", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint main(){\n\t\n\tchar a[2][2], b[2][2], aa[4], bb[4];\n\tint i, j, a_x, a_y,  b_x, b_y, same=0;\n\n\t//for (i=0; i<2; i++)\n\t//\tscanf(\"%c%c\\n%c%c\\n\", &a[0][0], &a[0][1], &a[1][0], &a[1][1]);\n\tscanf(\"%c%c\\n%c%c\\n\", &aa[0], &aa[3], &aa[1], &aa[2]);\n\t//for (i=0; i<2; i++)\n\t//\tscanf(\"%c%c\\n%c%c\", &b[0][0], &b[0][1], &b[1][0], &b[1][1]);\n\tscanf(\"%c%c\\n%c%c\", &bb[0], &bb[3], &bb[1], &bb[2]);\n\n\t/*printf(\"%s %s\\n\", a[0], b[0]);\n\n\tfor (i=0; i<2; i++){\n\t\tfor (j=0; j<2; j++){\n\t\t\tif ( a[i][j] == 'X' ){\n\t\t\t\ta_x = i; a_y = j;\n\t\t\t}\n\t\t\tif ( b[i][j] == 'X' ){\n\t\t\t\tb_x = i; b_y = j;\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"%d %d %d %d\\n\", a_x, a_y, b_x, b_y); \n*/\n\t//printf(\"%c %c %c %c\\n\", aa[0], aa[1], aa[2], aa[3]);\n\t//printf(\"%c %c %c %c\\n\", bb[0], bb[1], bb[2], bb[3]);\n\n\tfor (i=0; i<4; i++){\n\t\tif (aa[i] == 'X')\n\t\t\tcontinue;\n\t\ta_x = aa[i];\n\n\t\tfor (j=0; j%4<4; j++){\n\t\t\tif (a_x == bb[j])\n\t\t\t\tbreak;\n\t\t}\n\n\t\twhile (1){\n\t\t\tif ( aa[i] == 'X'){\n\t\t\t\ti++;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\telse if ( bb[j%4] == 'X'){\n\t\t\t\tj++;\n\t\t\t\tcontinue;}\n\t\t\t//printf(\"%d %d\\n\", i , j);\n\t\t\tif ( aa[i++] == bb[(j++)%4] )\n\t\t\t{\n\t\t\t\tsame++;\n\t\t\t}\n\n\t\t\tif (i==4)\n\t\t\t\tbreak;\n\t\t}\n\t}\n\n\tif ( same==3 )\n\t\tprintf(\"YES\\n\");\n\telse\n\t\tprintf(\"NO\\n\");\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c3ba9248e36429e57b6874c14bbb9d84", "src_uid": "46f051f58d626587a5ec449c27407771", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint N, M;\nlong long ans;\n\nint main()\n{\n\tscanf(\"%d%d\",&N,&M);\n\tregister int x, z, y;\n\tfor (x=M+1;2*x<=N+1;x++)\n\t{\n\t\tint st=(long long)(N-M-2*x)*(N+1-x)/(M-N-x);\n\t\tif (st<=M) st=M+1;\n\t\tans+=(st-M-1)*(N-M-M);\n\t\tregister long long a, b;\n\t\ta=N+1-x+st-1;\n\t\tb=(long long)x*(2*(N+1-x)-st+1);\n\t\tfor (z=st;z<=N-M;z++)\n\t\t{\n\t\t\ta++;\n\t\t\tb-=x;\n\t\t\ty=b/a;\n\t\t\tif (a*y==b) y--;\n\t\t\tif (y>N-M) y=N-M;\n\t\t\tif (y<=M) break;\n\t\t\tans+=y-M;\n\t\t\tif (2*x<N+1) ans+=y-M;\n\t\t}\n\t}\n\tprintf(\"%I64d\\n\",ans*3);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ea20546f26de147c1c2081a43dfd1010", "src_uid": "355cc23d7a4addfc920c6e5e72a2bb64", "difficulty": 2700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<math.h>\n\nint N, M, y, z;\nlong long ans;\n\nint main()\n{\n\tscanf(\"%d%d\",&N,&M);\n\tfor (y=M+1;y<=N-M;y++)\n\t\tfor (z=y;z<=N-M;z++)\n\t\t{\n\t\t\tlong long b, c, d, x1, x2;\n\t\t\tdouble _d;\n\t\t\tb=-y+z-2*(N+1);\n\t\t\tc=(N+1)*y+y*z;\n\t\t\td=b*b-8*c;\n\t\t\tif (d<0) continue;\n\t\t\t_d=sqrt(d);\n\t\t\tx1=floor((-b-_d)*0.25);\n\t\t\tx2=ceil((-b+_d)*0.25);\n\t\t\tif (x1<M) x1=M;\n\t\t\tif (x2>N-M+1) x2=N-M+1;\n\t\t\tif (x2-x1>1) ans+=(x2-x1-1)*(z>y?2:1);\n\t\t}\n\tprintf(\"%I64d\\n\",ans*3);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9f72b250e1ef7bdb655ab90f44ba0554", "src_uid": "355cc23d7a4addfc920c6e5e72a2bb64", "difficulty": 2700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint N, M;\nlong long ans;\n\nint main()\n{\n\tscanf(\"%d%d\",&N,&M);\n\tregister int x, z, y;\n\tfor (x=M+1;2*x<=N+1;x++)\n\t{\n\t\tint st=(long long)(N-M-2*x)*(N+1-x)/(M-N-x);\n\t\tif (st<=M) st=M+1;\n\t\tans+=(st-M-1)*(N-M-M);\n\t\tregister int a;\n\t\tregister long long b;\n\t\ta=N+1-x+st-1;\n\t\tb=(long long)x*(2*(N+1-x)-st+1);\n\t\ty=M+1;\n\t\tfor (z=st;z<=N-M && y>M;z++)\n\t\t{\n\t\t\ta++;\n\t\t\tb-=x;\n\t\t\ty=b/a;\n\t\t\tif (a*y==b) y--;\n\t\t\tans+=(y-M)*((2*x<N+1)+1);\n\t\t}\n\t}\n\tprintf(\"%I64d\\n\",ans*3);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "81e7b942c367174086d6756c48eb41c1", "src_uid": "355cc23d7a4addfc920c6e5e72a2bb64", "difficulty": 2700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint N, M;\nlong long ans;\n\nint main()\n{\n\tscanf(\"%d%d\",&N,&M);\n\tregister int x, z, y;\n\tfor (x=M+1;2*x<=N+1;x++)\n\t{\n\t\tint st=(long long)(N-M-2*x)*(N+1-x)/(M-N-x);\n\t\tif (st<=M) st=M+1;\n\t\tans+=(st-M-1)*(N-M-M);\n\t\tregister int a;\n\t\tregister long long b;\n\t\ta=N+1-x+st-1;\n\t\tb=(long long)x*(2*(N+1-x)-st+1)-1;\n\t\ty=M+1;\n\t\tfor (z=N-2*M;z && y>M;z--)\n\t\t\tans+=((y=(b-=x)/++a)-M)*((2*x<N+1)+1);\n\t}\n\tprintf(\"%I64d\\n\",ans*3);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "257ffd52129ee509384298179ff655db", "src_uid": "355cc23d7a4addfc920c6e5e72a2bb64", "difficulty": 2700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint N, M;\nlong long ans;\n\n#define f(x,y) ((x)*(x)+(y)*(y)-(x)*(y))\n\nint main()\n{\n\tscanf(\"%d%d\",&N,&M);\n\tregister int x1, x2, y, z;\n\tfor (y=M+1;y<=N-M;y++)\n\t\tfor (x1=M+1,x2=N-M,z=y;z<=N-M;z++)\n\t\t{\n\t\t\tint t(f(N+1-y,N+1-z));\n\t\t\twhile (x1<N-M && f(x1,y)+f(N+1-x1,z)-t>=0) x1++;\n\t\t\twhile (x2>M+1 && f(x2,y)+f(N+1-x2,z)-t>=0) x2--;\n\t\t\tif (x1>x2) break;\n\t\t\tans+=(x2-x1+1)*((z>y)+1);\n\t\t}\n\tprintf(\"%I64d\\n\",ans*3);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d71f925ba9bdebf879d2197ae4705244", "src_uid": "355cc23d7a4addfc920c6e5e72a2bb64", "difficulty": 2700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define mod 1000000009\n#define max(a,b) ((a)>(b)?(a):(b))\n\nchar str[15][15]={0};\nchar prefix[106][15]={0};\nlong o=0;\nlong g[106][4]={0},m;\nchar gene[5]=\"ACGT\";\n\nlong f[1006][106][15]={0};\nlong a[106]={0};\nchar opt[15]={0};\n\nlong find(char opt[],long l,long r)\n{\n long i,j,k;\n long a[15]={0};\n \n for(i=1;i<=m;i++)\n   {\n    for(j=1;opt[j];j++)\n      {\n       for(k=0;opt[j+k]==str[i][1+k]&&opt[j+k]&&str[i][1+k];k++);\n       if(!str[i][1+k])\n        for(k=0;str[i][1+k];k++)\n          a[j+k]=1;\n      }\n   }\n for(j=l;j<=r;j++)\n   if(!a[j])\n    return 0;\n return 1;\n}\n\nlong search(char opt[],long l)\n{\n long i,j,k;\n long a[15]={0};\n \n for(i=1;i<=m;i++)\n   {\n    for(j=1;opt[j];j++)\n      {\n       for(k=0;opt[j+k]==str[i][1+k]&&opt[j+k]&&str[i][1+k];k++);\n       if(!str[i][1+k])\n        for(k=0;str[i][1+k];k++)\n          a[j+k]=1;\n      }\n   }\n for(i=l+1;a[i];i++);\n return i-1;\n}\n\nint main()\n{\n long n,i,j,k,l,t;\n long ans=0;\n char ch;\n \n scanf(\"%ld%ld\",&n,&m);\n for(i=1;i<=m;i++)\n   scanf(\"%s\",str[i]+1);\n for(i=1;i<=m;i++)\n   for(j=1;str[i][j];j++)\n     {\n      ch=str[i][j+1];\n      str[i][j+1]=0;\n      for(k=1;k<=o;k++)\n        if(strcmp(prefix[k]+1,str[i]+1)==0)\n         break;\n      if(k>o)\n       {\n        strcpy(prefix[++o]+1,str[i]+1);\n        prefix[o][0]=strlen(prefix[o]+1);\n       }\n      str[i][j+1]=ch;\n      if(!str[i][j+1])\n       a[k]=1;\n     }\n \n for(i=0;i<=o;i++)\n   {\n    for(j=0;j<4;j++)\n      {\n      // prefix[i][prefix[i][0]+1]=gene[j];\n       memset(opt,0,sizeof(opt));\n       strcpy(opt,prefix[i]);\n       opt[opt[0]+1]=gene[j];\n       for(k=1;k<=prefix[i][0]+1;k++)\n         for(l=1;l<=o;l++)\n           {\n            if(strcmp(opt+k,prefix[l]+1)==0)\n             {\n              g[i][j]=l;\n              goto loop;\n             }\n           }\n       loop:;\n      }\n    //prefix[i][prefix[i][0]+1]=0;\n   }\n \n f[0][0][0]=1;\n for(i=0;i<n;i++)\n   for(j=0;j<=o;j++)\n     for(k=0;k<=prefix[j][0];k++)\n       if(f[i][j][k])\n        {\n         for(l=0;l<4;l++)\n           if(g[j][l])\n            {\n             memset(opt,0,sizeof(opt));\n             strcpy(opt,prefix[j]);\n             opt[prefix[j][0]+1]=gene[l];\n            // if(k-(prefix[j][0]+1-prefix[g[j][l]][0])>=0||find(opt,k+1,prefix[j][0]+1-prefix[g[j][l]][0]))\n             t=search(opt,k);\n             if(t>=prefix[j][0]+1-prefix[g[j][l]][0])\n               {\n                f[i+1][g[j][l]][t-(prefix[j][0]+1-prefix[g[j][l]][0])]+=f[i][j][k];\n                f[i+1][g[j][l]][t-(prefix[j][0]+1-prefix[g[j][l]][0])]%=1000000009;\n               }\n            }\n        }\n for(j=1;j<=o;j++)\n   for(k=0;k<=prefix[j][0];k++)\n     if(find(prefix[j],k+1,prefix[j][0]))\n      {\n       ans+=f[n][j][k];\n       ans%=mod;\n      }\n printf(\"%ld\\n\",ans);\n \n return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ac72fa102f7fad02b3b46e5eba9cad9c", "src_uid": "3f053c07deaac55c2c51df6147080340", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#define M 1000000009\n\ntypedef long long LL;\nint n,m,sz,son[110][4],fail[110],term[110],par[110],l[110],q[110],dig[110];\nLL f[1010][110][20];\nLL dp(int i,int u,int o);\n\nint main(void)\n{\n    //freopen(\"gene.in\",\"r\",stdin);\n    //freopen(\"gene.out\",\"w\",stdout);\n    scanf(\"%d%d\",&n,&m);\n    memset(son,0,sizeof(son));\n    memset(term,0,sizeof(term));\n    sz=1;  l[1]=0;\n    int i,j,u,v,t,d;\n    char str[20];\n    for(i=1;i<=m;i++)\n    {\n        scanf(\"%s\",str);\n        for(u=1,j=0;str[j];j++)\n        {\n            if(str[j]=='A') t=0;\n            else if(str[j]=='C') t=1;\n            else if(str[j]=='G') t=2;\n            else t=3;\n            if(!son[u][t])\n            {\n                l[++sz]=l[u]+1;\n                son[u][t]=sz;\n            }\n            par[son[u][t]]=u;\n            u=son[u][t];\n        }\n        term[u]=1;\n    }\n    memset(fail,-1,sizeof(fail));\n    fail[1]=0;\n    for(i=0;i<4;i++)\n        fail[son[1][i]]=1;\n    int front=1,rear=1;\n    q[1]=1;\n    while(front<=rear)\n    {\n        u=q[front];  d=dig[front];\n        front++;\n        if(fail[u]<0)\n            for( fail[u]=1,v=fail[par[u]] ; v ; v=fail[v] )\n                if(son[v][d])\n                {\n                    fail[u]=son[v][d];\n                    break;\n                }\n        for(i=0;i<4;i++)\n            if(son[u][i])\n            {\n                rear++;\n                q[rear]=son[u][i];  dig[rear]=i;\n            }\n    }\n    memset(f,-1,sizeof(f));\n    printf(\"%I64d\\n\",dp(0,1,0));\n    return 0;\n}\n\nLL dp(int i,int u,int o)\n{\n    if(f[i][u][o]>=0) return f[i][u][o];\n    else if(i==n)\n        return f[i][u][o] = o ? 0 : 1;\n    f[i][u][o]=0;\n    int j,v,w,t;\n    for(j=0;j<4;j++)\n    {\n        for( w=0,v=u ; v&&l[v]>=o ; v=fail[v] )\n            if(son[v][j])\n            {\n                w=son[v][j];\n                break;\n            }\n        if(w)\n        {\n            for(t=w;l[t]>=o+1;t=fail[t])\n                if(term[t]) break;\n            f[i][u][o] = ( f[i][u][o] + dp(i+1,w,l[t]<o+1 ? o+1 : 0) )%M;\n        }\n    }\n    return f[i][u][o];\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "74f063e6a00cd908e5db767393ae33a8", "src_uid": "3f053c07deaac55c2c51df6147080340", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define dimension 1000000009\n#define maximo(a,b) ((a)>(b)?(a):(b))\n\nchar mat[15][15]={0};\nchar prefix[106][15]={0};\nlong o=0;\nlong g[106][4]={0},m;\nchar gene[5]=\"ACGT\";\n\nlong f[1006][106][15]={0};\nlong a[106]={0};\nchar opt[15]={0};\n\nlong find(char opt[],long l,long r)\n{\n long i,j,k;\n long a[15]={0};\n\n for(i=1;i<=m;i++)\n   {\n    for(j=1;opt[j];j++)\n      {\n       for(k=0;opt[j+k]==mat[i][1+k]&&opt[j+k]&&mat[i][1+k];k++);\n       if(!mat[i][1+k])\n        for(k=0;mat[i][1+k];k++)\n          a[j+k]=1;\n      }\n   }\n for(j=l;j<=r;j++)\n   if(!a[j])\n    return 0;\n return 1;\n}\n\nlong search(char opt[],long l)\n{\n long i,j,k;\n long a[15]={0};\n\n for(i=1;i<=m;i++)\n   {\n    for(j=1;opt[j];j++)\n      {\n       for(k=0;opt[j+k]==mat[i][1+k]&&opt[j+k]&&mat[i][1+k];k++);\n       if(!mat[i][1+k])\n        for(k=0;mat[i][1+k];k++)\n          a[j+k]=1;\n      }\n   }\n for(i=l+1;a[i];i++);\n return i-1;\n}\n\nint main()\n{\n long n,i,j,k,l,t;\n long ans=0;\n char ch;\n\n scanf(\"%ld%ld\",&n,&m);\n for(i=1;i<=m;i++)\n   scanf(\"%s\",mat[i]+1);\n for(i=1;i<=m;i++)\n   for(j=1;mat[i][j];j++)\n     {\n      ch=mat[i][j+1];\n      mat[i][j+1]=0;\n      for(k=1;k<=o;k++)\n        if(strcmp(prefix[k]+1,mat[i]+1)==0)\n         break;\n      if(k>o)\n       {\n        strcpy(prefix[++o]+1,mat[i]+1);\n        prefix[o][0]=strlen(prefix[o]+1);\n       }\n      mat[i][j+1]=ch;\n      if(!mat[i][j+1])\n       a[k]=1;\n     }\n\n for(i=0;i<=o;i++)\n   {\n    for(j=0;j<4;j++)\n      {\n       memset(opt,0,sizeof(opt));\n       strcpy(opt,prefix[i]);\n       opt[opt[0]+1]=gene[j];\n       for(k=1;k<=prefix[i][0]+1;k++)\n         for(l=1;l<=o;l++)\n           {\n            if(strcmp(opt+k,prefix[l]+1)==0)\n             {\n              g[i][j]=l;\n              goto loop;\n             }\n           }\n       loop:;\n      }\n    //prefix[i][prefix[i][0]+1]=0;\n   }\n\n f[0][0][0]=1;\n for(i=0;i<n;i++)\n   for(j=0;j<=o;j++)\n     for(k=0;k<=prefix[j][0];k++)\n       if(f[i][j][k])\n        {\n         for(l=0;l<4;l++)\n           if(g[j][l])\n            {\n             memset(opt,0,sizeof(opt));\n             strcpy(opt,prefix[j]);\n             opt[prefix[j][0]+1]=gene[l];\n            // if(k-(prefix[j][0]+1-prefix[g[j][l]][0])>=0||find(opt,k+1,prefix[j][0]+1-prefix[g[j][l]][0]))\n             t=search(opt,k);\n             if(t>=prefix[j][0]+1-prefix[g[j][l]][0])\n               {\n                f[i+1][g[j][l]][t-(prefix[j][0]+1-prefix[g[j][l]][0])]+=f[i][j][k];\n                f[i+1][g[j][l]][t-(prefix[j][0]+1-prefix[g[j][l]][0])]%=1000000009;\n               }\n            }\n        }\n for(j=1;j<=o;j++)\n   for(k=0;k<=prefix[j][0];k++)\n     if(find(prefix[j],k+1,prefix[j][0]))\n      {\n       ans+=f[n][j][k];\n       ans%=dimension;\n      }\n printf(\"%ld\\n\",ans);\n\n return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a4d54c0036eec8bdf32859f28c5db61d", "src_uid": "3f053c07deaac55c2c51df6147080340", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint is_same(char a[], char b[], int len){\n  int i;\n  rep(i,len) if(a[i]!=b[i]) return 0;\n  return 1;\n}\n\n#define M 1000000009\n\nint n, lim;\nchar in[12][12]; int len[12];\n\nint dp[1011][12][12][12];\nchar *digit = \"ACGT\";\n\nint edge1[12][12][12][4];\nint edge2[12][12][12][4];\nint edge3[12][12][12][4];\n\nvoid edge_generator(void){\n  int i,j,k;\n  int word, word_len, ok_len;\n  int next_word, next_word_len, next_ok_len;\n  int fin, match, ok_chk;\n  char now[120]; int now_len;\n  int mx;\n\n  rep(word,n) rep(word_len,len[word]) rep(ok_len,word_len+1) rep(k,4){\n    fin = 0;\n\n    rep(i,word_len) now[i] = in[word][i];\n    now[word_len] = digit[k];\n    now_len = word_len+1;\n\n    match = 0;\n    rep(i,n) if(now_len >= len[i]) if(ok_len + len[i] >= now_len){\n      if(is_same(in[i], now+now_len-len[i], len[i])) match = 1;\n    }\n\n    next_word = 0; next_word_len = 0; next_ok_len = 0;\n    if(match) fin = 1;\n    \n    rep(i,n) REP(j,1,len[i]){\n      if(next_word_len >= j) continue;\n      if(is_same(in[i],now+now_len-j,j)==0) continue;\n\n      if(match) ok_chk = j;\n      else      ok_chk = ok_len - (now_len - j);\n\n      if(ok_chk < 0) continue;\n\n      fin = 1;\n      next_word = i;\n      next_word_len = j;\n      next_ok_len = ok_chk;\n    }\n\n    if(fin==0){edge1[word][word_len][ok_len][k] = -1; continue;}\n    edge1[word][word_len][ok_len][k] = next_word;\n    edge2[word][word_len][ok_len][k] = next_word_len;\n    edge3[word][word_len][ok_len][k] = next_ok_len;\n  }\n}\n\nint solve(int depth, int word, int word_len, int ok_len){\n  int i,j,k;\n  int next_word, next_word_len, next_ok_len;\n  int res = 0;\n\n  if(dp[depth][word][word_len][ok_len] >= 0) return dp[depth][word][word_len][ok_len];\n  if(depth==lim){\n    if(word_len==ok_len) res++;\n    return dp[depth][word][word_len][ok_len] = res;\n  }\n\n  rep(k,4){\n    if(edge1[word][word_len][ok_len][k] < 0) continue;\n    next_word     = edge1[word][word_len][ok_len][k];\n    next_word_len = edge2[word][word_len][ok_len][k];\n    next_ok_len   = edge3[word][word_len][ok_len][k];\n\n    res += solve(depth+1, next_word, next_word_len, next_ok_len);\n    res %= M;\n  }\n\n  return dp[depth][word][word_len][ok_len] = res;\n}\n\nint main(){\n  int i,j,k,l,m,res;\n\n  while(scanf(\"%d%d\",&lim,&n)==2){\n    rep(i,n) scanf(\"%s\",in[i]);\n    rep(i,n){\n      for(j=0;;j++) if(in[i][j]<' ') break;\n      len[i] = j;\n    }\n\n    rep(i,1011) rep(j,12) rep(k,12) rep(l,12) dp[i][j][k][l] = -1;\n    edge_generator();\n\n    res = solve(0,0,0,0);\n    printf(\"%d\\n\",res);\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9155c0638576ac26f4e2fb077e5bdce7", "src_uid": "3f053c07deaac55c2c51df6147080340", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint is_same(char a[], char b[], int len){\n  int i;\n  rep(i,len) if(a[i]!=b[i]) return 0;\n  return 1;\n}\n\n#define M 1000000009\n\nint n, lim;\nchar in[12][12]; int len[12];\n\nint dp[1011][12][12][12];\nchar *digit = \"ACGT\";\n\nint edge1[12][12][12][4];\nint edge2[12][12][12][4];\nint edge3[12][12][12][4];\n\nvoid edge_generator(void){\n  int i,j,k;\n  int word, word_len, ok_len;\n  int next_word, next_word_len, next_ok_len;\n  int fin, match, ok_chk;\n  char now[120]; int now_len;\n  int mx;\n\n  rep(word,n) rep(word_len,len[word]) rep(ok_len,word_len+1) rep(k,4){\n    fin = 0;\n\n    rep(i,word_len) now[i] = in[word][i];\n    now[word_len] = digit[k];\n    now_len = word_len+1;\n\n    match = 0;\n    rep(i,n) if(now_len >= len[i]) if(ok_len + len[i] >= now_len){\n      if(is_same(in[i], now+now_len-len[i], len[i])) match = 1;\n    }\n\n    next_word = 0; next_word_len = 0; next_ok_len = 0;\n    if(match) fin = 1;\n    \n    rep(i,n) REP(j,1,len[i]){\n      if(next_word_len >= j) continue;\n      if(is_same(in[i],now+now_len-j,j)==0) continue;\n\n      if(match) ok_chk = j;\n      else      ok_chk = ok_len - (now_len - j);\n\n      if(ok_chk < 0) continue;\n\n      fin = 1;\n      next_word = i;\n      next_word_len = j;\n      next_ok_len = ok_chk;\n    }\n\n    if(fin==0){edge1[word][word_len][ok_len][k] = -1; continue;}\n    edge1[word][word_len][ok_len][k] = next_word;\n    edge2[word][word_len][ok_len][k] = next_word_len;\n    edge3[word][word_len][ok_len][k] = next_ok_len;\n  }\n}\n\nint solve(int depth, int word, int word_len, int ok_len){\n  int i,j,k;\n  int next_word, next_word_len, next_ok_len;\n  int res = 0;\n\n  if(dp[depth][word][word_len][ok_len] >= 0) return dp[depth][word][word_len][ok_len];\n  if(depth==lim){\n    if(word_len==ok_len) res++;\n    return dp[depth][word][word_len][ok_len] = res;\n  }\n\n  rep(k,4){\n    if(edge1[word][word_len][ok_len][k] < 0) continue;\n    next_word     = edge1[word][word_len][ok_len][k];\n    next_word_len = edge2[word][word_len][ok_len][k];\n    next_ok_len   = edge3[word][word_len][ok_len][k];\n\n    res += solve(depth+1, next_word, next_word_len, next_ok_len);\n    res %= M;\n  }\n\n  return dp[depth][word][word_len][ok_len] = res;\n}\n\nint main(){\n  int i,j,k,l,m,res;\n\n  while(scanf(\"%d%d\",&lim,&n)==2){\n    rep(i,n) scanf(\"%s\",in[i]);\n    rep(i,n){\n      for(j=0;;j++) if(in[i][j]<' ') break;\n      len[i] = j;\n    }\n\n    rep(i,1011) rep(j,12) rep(k,12) rep(l,12) dp[i][j][k][l] = -1;\n    edge_generator();\n\n    res = solve(0,0,0,0);\n    printf(\"%d\\n\",res);\n  }\n\n  return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "fca0d3946702cca21d3b2633ee0df046", "src_uid": "3f053c07deaac55c2c51df6147080340", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint\nmain ()\n{\n  int a, b, mod;\n  long long i;\n  scanf (\"%d %d %d\", &a, &b, &mod);\n  if (b >= mod)\n    {\n      printf (\"2\\n\");\n      return 0;\n    }\n  for (i = 0; i <= a && i < mod; i++)\n    if ((i * 1000000000) % mod != 0 && ((i * 1000000000) % mod + b) < mod)\n      {\n\tprintf (\"1 %09d\\n\", (int)i);\n\treturn 0;\n      }\n  printf (\"2\\n\");\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9b680984e3fb7ac34f8c969dba72a6b4", "src_uid": "8b6f633802293202531264446d33fee5", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#include<math.h>\n#include<time.h>\n#define max(a,b) ((a>b)?a:b)\n#define min(a,b) ((a>b)?b:a)\n#define UpFor(i,From,To) for(i=From;i<To;i++)\n#define DownFor(i,From,To) for(i=From;i>To;i--)\n#define Opfile_in(s) freopen(s,\"r\",stdin)\n#define Opfile_out(s) freopen(s,\"w\",stdout)\n#define Read(T) scanf(\"%d\",&T)\n#define Print(T) printf(\"%d\\n\",T)\n#define LL long long\n#define MAXN 214748364\nint N,a,b,mod;\n_Bool H[10000002];\nvoid init();\nvoid doit();\nvoid print(int);\nint main()\n{\n    //Opfile_in(\"BUAA_temp.in\");\n    scanf(\"%d%d%d\",&a,&b,&mod);\n    doit();\n    return 0;\n}\nvoid doit()\n{\n    int i,k,tmp,t;\n    for(tmp=i=1;i<=9;i++)\n    tmp=tmp*10 % mod;\n    if(tmp==0||mod==1||b>=mod) {Print(2);return;}\n    k=min(mod,a);\n    for(t=tmp,i=1;i<=k;i++)\n    if(!H[i])\n    {\n        if(t<mod-b&&t>0) {print(i);return ;}\n        t=(t+tmp) % mod;\n        if(t>mod) t-=mod;\n    }\n    Print(2);\n}\nvoid print(int k)\n{\n    int L=0,i,t = k;\n    printf(\"1 \");\n    while(t /= 10) L++;\n    for(i=1;i<9-L;i++)\n    printf(\"0\");\n    Print(k);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fa4231c8627954cd7db1977d420230b7", "src_uid": "8b6f633802293202531264446d33fee5", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define M 1000000000LL\n#define min(x,y) ((x)>(y)?(y):(x))\n\nint main() {\n\tint a, b, mod;\n\tint i, t, winner;\n\tlong long p;\n\twinner = 2;\n\tscanf(\"%d%d%d\", &a, &b, &mod);\n\tt = min(a+1, mod);\n\tfor (i = 0; i < t; ++i) {\n\t\tp = M * i % mod;\n\t\tif (p > 0 && p + b < mod) {\n\t\t\twinner = 1;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif (winner == 1) {\n\t\tprintf(\"1 %09d\", i);\n\t} else {\n\t\tprintf(\"2\");\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "086a840df1da425792ed51c308cfe0de", "src_uid": "8b6f633802293202531264446d33fee5", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n long a,b,mod,i,j;\n \n scanf(\"%ld%ld%ld\",&a,&b,&mod);\n for(i=0;i<=a&&i<mod;i++)\n   if(((long long)i*1000000000LL-1+mod)%mod-mod+1<-b)\n    {\n     printf(\"1 %.9ld\\n\",i);\n     return 0;\n    }\n printf(\"2\\n\");\n \n return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "545bbed268914e5fff32daca65f89c40", "src_uid": "8b6f633802293202531264446d33fee5", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n     int a, b, m, i;\n\n     scanf(\"%d %d %d\", &a, &b, &m);\n\n     if (b >= m - 1) {\n\t  puts(\"2\");\n     } else {\n\t  for (i = 0; i < m; i++) {\n\t       int p = (long long)i * 1000000000 % m;\n\n\t       if (p > 0 && p <= m - b - 1) break;\n\t  }\n\n\t  if (i < m) {\n\t       printf(\"1 %09d\\n\", i);\n\t  } else {\n\t       puts(\"2\");\n\t  }\n     }\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "690b69cd80715d0328d23ed5a98b8648", "src_uid": "8b6f633802293202531264446d33fee5", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n\nint max=0;\nint a[10];//\ufffd\ufffd\ufffd\u4a2c? \nint p[100];\ntypedef struct Ch\n{\n\tint val;\n\tint mvrg;\n\tint thrg;\n};\ntypedef struct Ch CA[4];\nint movethrow(CA,int);\n\nint search(int pe)\n{\n\tint i,t;\n\tfor (i=1;i<45;i++)\t\n\t{\n\t\tif (p[i]>0)\n\t\t{\n\t\t\tt=p[i];\n\t\t\twhile (t)\n\t\t\t{\n\t\t\t\tif ((t%10)==pe)\n\t\t\t\t\treturn i;\n\t\t\t\tt=t/10;\n\t\t\t}\n\t\t}\n\t}\n}\nint ans(CA C)\n{\n\tint i,t;\n\tfor (i=44;i>=1;i--)\t\n\t{\n\t\tif (p[i]>0)\n\t\t{\n\t\t\tif (i>max)\n\t\t\t{\n\t\t\t\tmax=i;\n\t\t\t}\n\t\t\treturn 0;\n\t\t}\n\t}\n}\nint change(int pe,int pos)\n{\n\tint t;\n\tt=search(pe);\n\tp[t]=0;\n\tp[pos]=pe;\n\t\n}\nint tr(CA C,int pe)\n{\n\tint i,j;\n\tint f,m,r;\n\tint temp;\n\tm=search(pe);\n\ttemp=p[m];\n\tf=m-C[pe].thrg;\n\tr=m+C[pe].thrg;\n\tif (f<=0)\n\t\tf=1;\n\tfor (i=f;i<=r;i++)\n\t{\n\t\tif (i!=m&&p[i]==0)\n\t\t{\n\t\t\tp[i]=temp/10;\n\t\t\tp[m]=temp%10;\n\t\t\tfor (j=1;j<=9;j++)\n\t\t\t{\n\t\t\t\t\n\t\t\t\tif (a[j]==0)\n\t\t\t\t{\n\t\t\t\t\ta[j]=1;a[0]++;\n\t\t\t\t\tmovethrow(C,j);\n\t\t\t\t\ta[j]=0;a[0]--;\n\t\t\t\t}\n\t\t\t}\n\t\t\tans(C);\n\t\t\tp[i]=0;\n\t\t\tp[m]=temp;\n\t\t}\n\t}\n\treturn 0;\n}\nint mv(CA C,int pe)\n{\n\tint i,j;\n\tint f,m,r;\n\tm=search(pe);\n\tf=m-C[pe].mvrg;\n\tr=m+C[pe].mvrg;\n\tif (f<=0)\n\t\tf=1;\n\tfor (i=f;i<=r;i++)\n\t{\n\t\tif (i!=m&&p[i]==0)\n\t\t{\n\t\t\tchange(pe,i);\n\t\t\t\n\t\t\tfor (j=1;j<=9;j++)\n\t\t\t{\n\t\t\t\tif (a[j]==0)\n\t\t\t\t{\n\t\t\t\t\ta[j]=1;a[0]++;\n\t\t\t\t\tmovethrow(C,j);\n\t\t\t\t\ta[j]=0;a[0]--;\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t\tans(C);\n\t\t}\n\t}\n\tchange(pe,m);\n\treturn 0;\n}\n\nint movethrow(CA C,int fr)\n{\n\tint i,j;\n\tint rt;\n\tif (fr%3==1)\n\t{\n\t\trt=fr/3+1;\n\t\tif (a[fr+1]==1&&a[fr+2]==0)\n\t\t{\n\t\t\treturn 0;\n\t\t}\n\t\telse if (p[search(rt)]>10)\n\t\t{\n\t\t\treturn 0;\n\t \t}\n\t\telse\n\t\t{\n\t\t\tmv(C,rt);\n\n\t\t\treturn 0;\n\t\t}\n\t\t\n\t}\n\tif (fr%3==2)\n\t{\n\t\tint px;\n\t\trt=fr/3+1;\n\t\tpx=search(rt);\n\t\tif (p[px]>10)\n\t\t{\n\t\t\treturn 0;\n\t\t}\n\t\telse if (p[px-1]>0)\n\t\t{\n\t\t\tint temp;\n\t\t\tp[px]+=p[px-1]*10;\n\t\t\ttemp=p[px-1];\n\t\t\tp[px-1]=0;\n\t\t\tfor (j=1;j<=9;j++)\n\t\t\t{\n\t\t\t\tif (a[j]==0)\n\t\t\t\t{\n\t\t\t\t\ta[j]=1;a[0]++;\n\t\t\t\t\tmovethrow(C,j);\n\t\t\t\t\ta[j]=0;a[0]--;\n\t\t\t\t}\n\t\t\t}\n\t\t\tp[px]=rt;\n\t\t\tp[px-1]=temp;\n\t\t}\n\t\telse if (p[px+1]>0)\n\t\t{\n\t\t\tint temp;\n\t\t\tp[px]+=p[px+1]*10;\n\t\t\ttemp=p[px+1];\n\t\t\tp[px+1]=0;\n\t\t\tfor (j=1;j<=9;j++)\n\t\t\t{\n\t\t\t\tif (a[j]==0)\n\t\t\t\t{\n\t\t\t\t\ta[j]=1;a[0]++;\n\t\t\t\t\tmovethrow(C,j);\n\t\t\t\t\ta[j]=0;a[0]--;\n\t\t\t\t}\n\t\t\t}\n\t\t\tp[px]=rt;\n\t\t\tp[px+1]=temp;\n\t\t\treturn 0;\n\t\t}\n\t\telse\n\t\t{\n\t\t\treturn 0;\n\t\t}\n\t}\n\tif (fr%3==0)\n\t{\n\t\trt=fr/3;\n\t\tint px;\n\t\tpx=search(rt);\n\t\tif (a[fr-1]==0)\n\t\t{\n\t\t\treturn 0;\n\t\t}\n\t\telse if (p[px]%10!=rt)\n\t\t{\n\t\t\treturn 0;\n\t\t}\n\t\telse \n\t\t{\n\t\t\ttr(C,rt);\n\t\t\treturn 0;\n\t\t}\n\t}\n}\nint main()\n{\n\tCA C;\n\tint i,j;\n\tfor (i=1;i<100;i++)\n\t{\n\t\tp[i]=0;\n\t}\n\tfor (i=1;i<=3;i++)\n\t{\n\t\tscanf(\"%d %d %d\",&C[i].val,&C[i].mvrg,&C[i].thrg);\n\t\tp[C[i].val]=i;\n\t}\n\tfor (i=0;i<=9;i++)\n\t{\n\t\ta[i]=0;\n\t}\n\tfor (i=1;i<=9;i++)\n\t{\n\t\ta[i]=1;a[0]++;\n\t\tmovethrow(C,i);\n\t\ta[i]=0;a[0]--;\n\t}\n\t\n\tprintf(\"%d\",max);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7ed16c7478e62c8d1f0ed69ca777e128", "src_uid": "a14739b86d1fd62a030226263cdc1afc", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define my_abs(x) ((x) < 0 ? -(x) : (x))\n#define chk(x) (x != p[0] && x != p[1] && x != p[2])\n#define min(x, y) ((x) < (y) ? (x) : (y))\n#define max(x, y) ((x) > (y) ? (x) : (y))\n#define true 1\ntypedef int bool; \nbool vis[55][55][55][9][9]; \nint p[5], m[5], t[5], ans; \nvoid dfs(int *p, int x, int y)\n{\n\tif (vis[p[0]][p[1]][p[2]][x][y])\n\t\treturn; \n\tvis[p[0]][p[1]][p[2]][x][y] = true; \n\tint far = 0, near = 50; \n\tfor (int i = 0; i < 3; i++)\n\t{\n\t\tif (p[i] < 45)\n\t\t\tfar = max(far, p[i]); \n\t\tnear = min(near, p[i]);\n\t}\n\tans = max(ans, far); \n\tfor (int j = 0; j < 3; j++)\n\t{\n\t\tint arr[] = {p[0], p[1], p[2]}, z = 1 << j; \n\t\tif (p[j] >= 45)\n\t\t{\n\t\t\tint pos = p[j] - 45; \n\t\t\tif (p[pos] >= 45)\n\t\t\t\tcontinue;\n\t\t\tfor (int i = p[pos] + t[pos]; i >= p[pos] - t[pos] && i > near - 2 && i; i--)\n\t\t\t{\n\t\t\t\tif (chk(i))\n\t\t\t\t{\n\t\t\t\t\tarr[j] = i; \n\t\t\t\t\tdfs(arr, x, y); \n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse if (chk(j + 45))\n\t\t{\n\t\t\tif (y & z)\n\t\t\t{\n\t\t\t\tfor (int i = 0; i < 3; i++)\n\t\t\t\t{\n\t\t\t\t\tif (my_abs(p[i] - p[j]) != 1)\n\t\t\t\t\t\tcontinue; \n\t\t\t\t\tarr[i] = 45 + j; \n\t\t\t\t\tdfs(arr, x, y ^ z); \n\t\t\t\t\tarr[i] = p[i]; \n\t\t\t\t}\n\t\t\t}\n\t\t\tif (x & z)\n\t\t\t{\n\t\t\t\tfor (int i = p[j] + m[j]; i >= p[j] - m[j] && i > near - 2 && i; i--)\n\t\t\t\t{\n\t\t\t\t\tif (!chk(i))\n\t\t\t\t\t\tcontinue; \n\t\t\t\t\tarr[j] = i;  \n\t\t\t\t\tdfs(arr, x ^ z, y); \n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\nint main()\n{\n\t// freopen(\"105E.in\", \"r\", stdin); \n\tfor (int i = 0; i < 3; i++)\n\t\tscanf(\"%d%d%d\", p + i, m + i, t + i); \n\tdfs(p, 7, 7); \n\tprintf(\"%d\\n\", ans);\n\treturn 0; \n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e4892d544e9f4c912f700a68ad42ccf8", "src_uid": "a14739b86d1fd62a030226263cdc1afc", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\nint max=0;\nint a[10];\nint p[100];\ntypedef struct\n{\n\tint val;\n\tint mvrg;\n\tint thrg;\n}Ch;\ntypedef Ch CA[4];\nint movethrow(CA,int);\nint search(int pe)\n{\n\tint i,t;\n\tfor (i=1;i<45;i++)\t\n\t{\n\t\tif (p[i]>0)\n\t\t{\n\t\t\tt=p[i];\n\t\t\twhile (t)\n\t\t\t{\n\t\t\t\tif ((t%10)==pe)\n\t\t\t\t\treturn i;\n\t\t\t\tt=t/10;\n\t\t\t}\n\t\t}\n\t}\n}\nint change(int pe,int pos)\n{\n\tint t;\n\tt=search(pe);\n\tp[t]=0;\n\tp[pos]=pe;\n\t\n}\nint tr(CA C,int pe)\n{\n\tint i,j;\n\tint f,m,r,t[4];\n\tint temp;\n\tt[1]=search(1);\n\tt[2]=search(2);\n\tt[3]=search(3);\n\tm=t[pe];\n\ttemp=p[m];\n\tf=m-C[pe].thrg;\n\tr=m+C[pe].thrg;\n\tif (r>max)\n\t\tmax=r;\n\tif (f<=0)\n\t\tf=1;\n\tfor (i=f;i<=r;i++)\n\t{\n\t\tif (i!=m&&p[i]==0&&\n\t\t\t(abs(i-t[1])==1||abs(i-t[2]==1)||abs(i-t[3])==1||i==r))\n\t\t{\n\t\t\t\n\t\t\tp[i]=temp/10;\n\t\t\tp[m]=temp%10;\n\t\t\tfor (j=1;j<=9;j++)\n\t\t\t{\n\t\t\t\t\n\t\t\t\tif (a[j]==0)\n\t\t\t\t{\n\t\t\t\t\ta[j]=1;a[0]++;\n\t\t\t\t\tmovethrow(C,j);\n\t\t\t\t\ta[j]=0;a[0]--;\n\t\t\t\t}\n\t\t\t}\n\t\t\tp[i]=0;\n\t\t\tp[m]=temp;\n\t\t}\n\t}\n\treturn 0;\n}\nint mv(CA C,int pe)\n{\n\tint i,j;\n\tint f,m,r,t[4];\n\tt[1]=search(1);\n\tt[2]=search(2);\n\tt[3]=search(3);\n\tint temp;\n\ttemp=t[pe];\n\tm=t[pe];\n\tt[pe]=t[3];\n\tt[3]=temp;\n\tf=m-C[pe].mvrg;\n\tr=m+C[pe].mvrg;\n\tif (r>max)\n\t\tmax=r;\n\tif (f<=0)\n\t\tf=1;\n\tfor (i=f;i<=r;i++)\n\t{\n\t\tif (i!=m&&p[i]==0&&\n\t\t\t(abs(i-t[1])<=2||abs(i-t[2]<=2)||abs(i-t[3])<=1||i==r))\n\t\t{\n\t\t\tchange(pe,i);\n\t\t\t\n\t\t\tfor (j=1;j<=9;j++)\n\t\t\t{\n\t\t\t\tif (a[j]==0)\n\t\t\t\t{\n\t\t\t\t\ta[j]=1;a[0]++;\n\t\t\t\t\tmovethrow(C,j);\n\t\t\t\t\ta[j]=0;a[0]--;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tchange(pe,m);\n\treturn 0;\n}\n\nint movethrow(CA C,int fr)\n{\n\tint i,j;\n\tint rt;\n\tif (fr%3==1)\n\t{\n\t\trt=fr/3+1;\n\t\tif (a[fr+1]==1&&a[fr+2]==0)\n\t\t{\n\t\t\treturn 0;\n\t\t}\n\t\telse if (p[search(rt)]>10)\n\t\t{\n\t\t\treturn 0;\n\t \t}\n\t\telse\n\t\t{\n\t\t\tmv(C,rt);\n\n\t\t\treturn 0;\n\t\t}\n\t\t\n\t}\n\tif (fr%3==2)\n\t{\n\t\tint px;\n\t\trt=fr/3+1;\n\t\tpx=search(rt);\n\t\tif (p[px]>10)\n\t\t{\n\t\t\treturn 0;\n\t\t}\n\t\telse if (p[px-1]>0)\n\t\t{\n\t\t\tint temp;\n\t\t\tp[px]+=p[px-1]*10;\n\t\t\ttemp=p[px-1];\n\t\t\tp[px-1]=0;\n\t\t\tfor (j=1;j<=9;j++)\n\t\t\t{\n\t\t\t\tif (a[j]==0)\n\t\t\t\t{\n\t\t\t\t\ta[j]=1;a[0]++;\n\t\t\t\t\tmovethrow(C,j);\n\t\t\t\t\ta[j]=0;a[0]--;\n\t\t\t\t}\n\t\t\t}\n\t\t\tp[px]=rt;\n\t\t\tp[px-1]=temp;\n\t\t}\n\t\telse if (p[px+1]>0)\n\t\t{\n\t\t\tint temp;\n\t\t\tp[px]+=p[px+1]*10;\n\t\t\ttemp=p[px+1];\n\t\t\tp[px+1]=0;\n\t\t\tfor (j=1;j<=9;j++)\n\t\t\t{\n\t\t\t\tif (a[j]==0)\n\t\t\t\t{\n\t\t\t\t\ta[j]=1;a[0]++;\n\t\t\t\t\tmovethrow(C,j);\n\t\t\t\t\ta[j]=0;a[0]--;\n\t\t\t\t}\n\t\t\t}\n\t\t\tp[px]=rt;\n\t\t\tp[px+1]=temp;\n\t\t\treturn 0;\n\t\t}\n\t\telse\n\t\t{\n\t\t\treturn 0;\n\t\t}\n\t}\n\tif (fr%3==0)\n\t{\n\t\trt=fr/3;\n\t\tint px;\n\t\tpx=search(rt);\n\t\tif (a[fr-1]==0)\n\t\t{\n\t\t\treturn 0;\n\t\t}\n\t\telse if (p[px]%10!=rt)\n\t\t{\n\t\t\treturn 0;\n\t\t}\n\t\telse \n\t\t{\n\t\t\ttr(C,rt);\n\t\t\treturn 0;\n\t\t}\n\t}\n}\nint main()\n{\n\tCA C;\n\tint i,j;\n\tfor (i=1;i<100;i++)\n\t{\n\t\tp[i]=0;\n\t}\n\tfor (i=1;i<=3;i++)\n\t{\n\t\tscanf(\"%d %d %d\",&C[i].val,&C[i].mvrg,&C[i].thrg);\n\t\tp[C[i].val]=i;\n\t}\n\tfor (i=0;i<=9;i++)\n\t{\n\t\ta[i]=0;\n\t}\n\tfor (i=1;i<=9;i++)\n\t{\n\t\ta[i]=1;a[0]++;\n\t\tmovethrow(C,i);\n\t\ta[i]=0;a[0]--;\n\t}\n\t\n\tprintf(\"%d\",max);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "54bbb0ed5d345cb9f36e4785a1b6303f", "src_uid": "a14739b86d1fd62a030226263cdc1afc", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\nint max=0;\nint a[10];\nint p[100];\ntypedef struct\n{\n\tint val;\n\tint mvrg;\n\tint thrg;\n}Ch;\ntypedef Ch CA[4];\nint movethrow(CA,int);\n\nint search(int pe)\n{\n\tint i,t;\n\tfor (i=1;i<45;i++)\t\n\t{\n\t\tif (p[i]>0)\n\t\t{\n\t\t\tt=p[i];\n\t\t\twhile (t)\n\t\t\t{\n\t\t\t\tif ((t%10)==pe)\n\t\t\t\t\treturn i;\n\t\t\t\tt=t/10;\n\t\t\t}\n\t\t}\n\t}\n}\nint change(int pe,int pos)\n{\n\tint t;\n\tt=search(pe);\n\tp[t]=0;\n\tp[pos]=pe;\n\t\n}\nint tr(CA C,int pe)\n{\n\tint i,j;\n\tint f,m,r,t[3];\n\tint temp;\n\tt[1]=search(1);\n\tt[2]=search(2);\n\tt[3]=search(3);\n\tm=search(pe);\n\ttemp=p[m];\n\tf=m-C[pe].thrg;\n\tr=m+C[pe].thrg;\n\tif (r>max)\n\t\tmax=r;\n\tif (f<=0)\n\t\tf=1;\n\tfor (i=f;i<=r;i++)\n\t{\n\t\tif (i!=m&&p[i]==0&&\n\t\t\t(abs(i-t[1])==1||abs(i-t[2]==1)||abs(i-t[3])==1||i==r))\n\t\t{\n\t\t\tp[i]=temp/10;\n\t\t\tp[m]=temp%10;\n\t\t\tfor (j=1;j<=9;j++)\n\t\t\t{\n\t\t\t\t\n\t\t\t\tif (a[j]==0)\n\t\t\t\t{\n\t\t\t\t\ta[j]=1;a[0]++;\n\t\t\t\t\tmovethrow(C,j);\n\t\t\t\t\ta[j]=0;a[0]--;\n\t\t\t\t}\n\t\t\t}\n\t\t\tp[i]=0;\n\t\t\tp[m]=temp;\n\t\t}\n\t}\n\treturn 0;\n}\nint mv(CA C,int pe)\n{\n\tint i,j;\n\tint f,m,r,t[3];\n\tt[1]=search(1);\n\tt[2]=search(2);\n\tt[3]=search(3);\n\tm=search(pe);\n\tf=m-C[pe].mvrg;\n\tr=m+C[pe].mvrg;\n\tif (r>max)\n\t\tmax=r;\n\tif (f<=0)\n\t\tf=1;\n\tfor (i=f;i<=r;i++)\n\t{\n\t\tif (i!=m&&p[i]==0&&\n\t\t\t(abs(i-t[1])==1||abs(i-t[2]==1)||abs(i-t[3])==1||i==r))\n\t\t{\n\t\t\tchange(pe,i);\n\t\t\t\n\t\t\tfor (j=1;j<=9;j++)\n\t\t\t{\n\t\t\t\tif (a[j]==0)\n\t\t\t\t{\n\t\t\t\t\ta[j]=1;a[0]++;\n\t\t\t\t\tmovethrow(C,j);\n\t\t\t\t\ta[j]=0;a[0]--;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tchange(pe,m);\n\treturn 0;\n}\n\nint movethrow(CA C,int fr)\n{\n\tint i,j;\n\tint rt;\n\tif (fr%3==1)\n\t{\n\t\trt=fr/3+1;\n\t\tif (a[fr+1]==1&&a[fr+2]==0)\n\t\t{\n\t\t\treturn 0;\n\t\t}\n\t\telse if (p[search(rt)]>10)\n\t\t{\n\t\t\treturn 0;\n\t \t}\n\t\telse\n\t\t{\n\t\t\tmv(C,rt);\n\n\t\t\treturn 0;\n\t\t}\n\t\t\n\t}\n\tif (fr%3==2)\n\t{\n\t\tint px;\n\t\trt=fr/3+1;\n\t\tpx=search(rt);\n\t\tif (p[px]>10)\n\t\t{\n\t\t\treturn 0;\n\t\t}\n\t\telse if (p[px-1]>0)\n\t\t{\n\t\t\tint temp;\n\t\t\tp[px]+=p[px-1]*10;\n\t\t\ttemp=p[px-1];\n\t\t\tp[px-1]=0;\n\t\t\tfor (j=1;j<=9;j++)\n\t\t\t{\n\t\t\t\tif (a[j]==0)\n\t\t\t\t{\n\t\t\t\t\ta[j]=1;a[0]++;\n\t\t\t\t\tmovethrow(C,j);\n\t\t\t\t\ta[j]=0;a[0]--;\n\t\t\t\t}\n\t\t\t}\n\t\t\tp[px]=rt;\n\t\t\tp[px-1]=temp;\n\t\t}\n\t\telse if (p[px+1]>0)\n\t\t{\n\t\t\tint temp;\n\t\t\tp[px]+=p[px+1]*10;\n\t\t\ttemp=p[px+1];\n\t\t\tp[px+1]=0;\n\t\t\tfor (j=1;j<=9;j++)\n\t\t\t{\n\t\t\t\tif (a[j]==0)\n\t\t\t\t{\n\t\t\t\t\ta[j]=1;a[0]++;\n\t\t\t\t\tmovethrow(C,j);\n\t\t\t\t\ta[j]=0;a[0]--;\n\t\t\t\t}\n\t\t\t}\n\t\t\tp[px]=rt;\n\t\t\tp[px+1]=temp;\n\t\t\treturn 0;\n\t\t}\n\t\telse\n\t\t{\n\t\t\treturn 0;\n\t\t}\n\t}\n\tif (fr%3==0)\n\t{\n\t\trt=fr/3;\n\t\tint px;\n\t\tpx=search(rt);\n\t\tif (a[fr-1]==0)\n\t\t{\n\t\t\treturn 0;\n\t\t}\n\t\telse if (p[px]%10!=rt)\n\t\t{\n\t\t\treturn 0;\n\t\t}\n\t\telse \n\t\t{\n\t\t\ttr(C,rt);\n\t\t\treturn 0;\n\t\t}\n\t}\n}\nint main()\n{\n\tCA C;\n\tint i,j;\n\tfor (i=1;i<100;i++)\n\t{\n\t\tp[i]=0;\n\t}\n\tfor (i=1;i<=3;i++)\n\t{\n\t\tscanf(\"%d %d %d\",&C[i].val,&C[i].mvrg,&C[i].thrg);\n\t\tp[C[i].val]=i;\n\t}\n\tfor (i=0;i<=9;i++)\n\t{\n\t\ta[i]=0;\n\t}\n\tfor (i=1;i<=9;i++)\n\t{\n\t\ta[i]=1;a[0]++;\n\t\tmovethrow(C,i);\n\t\ta[i]=0;a[0]--;\n\t}\n\t\n\tprintf(\"%d\",max);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b2396ea530f3e86cee591fcd354db60f", "src_uid": "a14739b86d1fd62a030226263cdc1afc", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define my_abs(x) ((x) < 0 ? -(x) : (x))\n#define chk(x) (x != p[0] && x != p[1] && x != p[2])\nbool vis[55][55][55][9][9]; \nint p[5], m[5], t[5], ans; \nvoid dfs(int *p, int x, int y)\n{\n\tif (vis[p[0]][p[1]][p[2]][x][y])\n\t\treturn; \n\tvis[p[0]][p[1]][p[2]][x][y] = true; \n\tint far = 0, near = 50; \n\tfor (int i = 0; i < 3; i++)\n\t{\n\t\tif (p[i] < 45)\n\t\t\tfar = max(far, p[i]); \n\t\tnear = min(near, p[i]);\n\t}\n\tans = max(ans, far); \n\tfor (int j = 0; j < 3; j++)\n\t{\n\t\tint arr[] = {p[0], p[1], p[2]}, z = 1 << j; \n\t\tif (p[j] >= 45)\n\t\t{\n\t\t\tint pos = p[j] - 45; \n\t\t\tif (p[pos] >= 45)\n\t\t\t\tcontinue;\n\t\t\tfor (int i = p[pos] + t[pos]; i >= p[pos] - t[pos] && i > near - 2 && i; i--)\n\t\t\t{\n\t\t\t\tif (chk(i))\n\t\t\t\t{\n\t\t\t\t\tarr[j] = i; \n\t\t\t\t\tdfs(arr, x, y); \n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse if (chk(j + 45))\n\t\t{\n\t\t\tif (y & z)\n\t\t\t{\n\t\t\t\tfor (int i = 0; i < 3; i++)\n\t\t\t\t{\n\t\t\t\t\tif (my_abs(p[i] - p[j]) != 1)\n\t\t\t\t\t\tcontinue; \n\t\t\t\t\tarr[i] = 45 + j; \n\t\t\t\t\tdfs(arr, x, y ^ z); \n\t\t\t\t\tarr[i] = p[i]; \n\t\t\t\t}\n\t\t\t}\n\t\t\tif (x & z)\n\t\t\t{\n\t\t\t\tfor (int i = p[j] + m[j]; i >= p[j] - m[j] && i > near - 2 && i; i--)\n\t\t\t\t{\n\t\t\t\t\tif (!chk(i))\n\t\t\t\t\t\tcontinue; \n\t\t\t\t\tarr[j] = i;  \n\t\t\t\t\tdfs(arr, x ^ z, y); \n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\nint main()\n{\n\t// freopen(\"105E.in\", \"r\", stdin); \n\tfor (int i = 0; i < 3; i++)\n\t\tscanf(\"%d%d%d\", p + i, m + i, t + i); \n\tdfs(p, 7, 7); \n\tprintf(\"%d\\n\", ans);\n\treturn 0; \n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "30c306f5f909725a8e5e859f05f8f9cc", "src_uid": "a14739b86d1fd62a030226263cdc1afc", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\nint fun(char *);\nint fun(char *s)\n{\n    char s1[27]={\"AEFHIKLMNTVWXYZ\"};\n    char s2[27]={\"BCDGJOPQRSU\"};\n    int p1=0,p2=0;\n    char *st=s;\n    while(*st)\n    {\n        if(strchr(s1,*st)!=NULL)\n        {\n            p1=1;\n        }\n        if(strchr(s2,*st)!=NULL)\n        {\n            p2=1;\n        }\n        st++;\n    }\n    if(p1==1&&p2==1)\n    {\n        return 0;\n    }\n    return 1;\n}\nint main()\n{\n    char a[11];\n    scanf(\"%s\",a);\n    printf((fun(a)==1)?\"YES\\n\":\"NO\\n\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "244baae6deac4c308bbc3bc9e0b94926", "src_uid": "15008dcb8dc8506c39aef0e3d8fca70c", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint A[520],i,p,q;\nchar c[40];\nint main(){\n\tA['B']=A['C']=A['D']=A['G']=A['J']=A['O']=A['P']=A['Q']=A['R']=A['S']=A['U']=1;\n\tscanf(\"%s\",c);\n\tfor(i=0;c[i];i++){\n\t\tif(A[c[i]])p=1;\n\t\telse q=1;\n\t}\n\tif(p^q)printf(\"YES\");\n\telse printf(\"NO\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "fd93c9f9f34f855d8c1031d5f864a0eb", "src_uid": "15008dcb8dc8506c39aef0e3d8fca70c", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <math.h>\nint main(){\nchar a[10];\nscanf(\"%s\",a);\nint n=0;\nint i;\n\nfor (i=0;a[i]!='\\0';i++){\n    if((a[i]=='B')||(a[i]=='C')||(a[i]=='D')||(a[i]=='G')||(a[i]=='J')||(a[i]=='O')||(a[i]=='P')||(a[i]=='Q')||(a[i]=='R')||(a[i]=='S')||(a[i]=='U')){\n            n++;\n\n\n    }\n\n\n\n}\n if((n!=0)&&(n!=i)){printf(\"NO\");}\n else {printf(\"YES\");}\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bbfc7cb39dfd84598321af482b864a92", "src_uid": "15008dcb8dc8506c39aef0e3d8fca70c", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\nint main()\n{\nint i,s=0;\nint verif=0;\nint l=0;\nchar chaine[27];\nscanf(\"%s\", chaine);\nl=strlen(chaine);\nfor(i=0; i<=l; i++)\n{\nif(chaine[i]=='A' || chaine[i]=='E' || chaine[i]=='F' || chaine[i]=='H' || chaine[i]=='I'\n|| chaine[i]=='K' || chaine[i]=='L'|| chaine[i]=='M' || chaine[i]=='N' || chaine[i]=='T'\n|| chaine[i]=='V' || chaine[i]=='W' || chaine[i]=='X' || chaine[i]=='Y' || chaine[i]=='Z')\ns++;\n}\nif(s==l || s==0)\nprintf(\"YES\");\nelse\nprintf(\"NO\");\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "491d7f1e815e644a8ea25b7071bf2587", "src_uid": "15008dcb8dc8506c39aef0e3d8fca70c", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdlib.h>\n#include <stdio.h>\n#include <string.h>\nint main()\n{   \n    char Linear []={'A','E','Z','T','Y','I','F','H','K','L','M','W','X','V','N','\\0'};\n    char Curved []={'R','U','O','P','Q','S','D','G','J','C','B','\\0'};\n    int x=0,i=0;\n    char ch[10];\n    scanf(\"%s\",ch);\n    \n    if (strlen(ch)==1)\n        {printf(\"YES\");return 0;}\n        else {\n            \n            if (strchr(Linear,ch[0]))\n                x=1;\n                else if (Curved,ch[0])\n                x=2;\n            if (x==1)\n            {   while (i<strlen(ch))\n               { if (strchr(Curved,ch[i]))\n                {  printf(\"NO\");\n                return 0;}\n               i++;}\n            }\n            else {\n                while (i<strlen(ch))\n               { if (strchr(Linear,ch[i]))\n                {  printf(\"NO\");\n                return 0;}\n               i++;}\n                \n            }}\n    \n        printf(\"YES\");\n    \n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "0fa46eda66258a34cdc86b3937ce5bff", "src_uid": "15008dcb8dc8506c39aef0e3d8fca70c", "difficulty": null}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nchar generate[200000][1500];\nint main(){\n    int a,b,c,d,e; int add=0;\n        char test,test1,test2,test3,test4,test5;\n               for(test2='a';test2<='f';test2++){\n                    for(test3='a';test3<='f';test3++){\n                         for(test4='a';test4<='f';test4++){\n                              for(test5='a';test5<='f';test5++){\n                              generate[add][0]=test2;\n                              generate[add][1]=test3;\n                              generate[add][2]=test4;\n                              generate[add][3]=test5;\n                              add++;\n                              }\n               }\n          }\n    }\n    char f_storage[50][50];\n    char l_storage[50][50];\n    scanf(\"%d%d\",&a,&b);\n    getchar();\n    int i;\n    for(i=0;i<b;i++){\n     scanf(\"%s %s\",f_storage[i],l_storage[i]);\n    }\n    int x,x1,x2,x3,x4,x5; int cnt=0;\n    int k=0;\n    for(x3=0;x3<b;x3++){\n    for(x='a';x<='f';x++){\n    for(x5=0;x5<add;x5++){\n    char input[50];\n    strcpy(input,f_storage[x3]);\n    if(a==3){\n    input[2]=generate[x5][0];\n    input[3]=0;\n    }\n    if(a==4){\n    input[2]=generate[x5][0];\n    input[3]=generate[x5][1];\n    input[4]=0;\n    }\n    if(a==5){\n    input[2]=generate[x5][0];\n    input[3]=generate[x5][1];\n    input[4]=generate[x5][2];\n    input[5]=0;\n    }\n    if(a==6){\n    input[2]=generate[x5][0];\n    input[3]=generate[x5][1];\n    input[4]=generate[x5][2];\n    input[5]=generate[x5][3];\n    input[6]=0;\n    }\n    for(x1=0;x1<=36;x1++){\n     for(x2=0;x2<b;x2++){\n      if(input[0]==f_storage[x2][0] && input[1]==f_storage[x2][1]){\n       input[0]=l_storage[x2][0];\n       input[1]=input[2];\n       input[2]=0;\n      }\n     }}\n     if(strcmp(input,\"a\")==0){\n            cnt++;\n            break;\n     }\n    }\n    }\n    }\n    printf(\"%d\",cnt/6);\n\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ee7b06ca3145b7960299df909e48da3a", "src_uid": "c42abec29bfd17de3f43385fa6bea534", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nchar a[50][5], b[50][5];\nchar dict[10000][10];\nint ans=0;\n\nint dfs(char str[], int q, int n)\n{\n\tint i,j,k;\n\n\t//printf(\"%s\\n\", str);\n\n\tif(strlen(str)==n)\n\t{\n\t\tint flag=0;\n\t\tfor(i=0;i<ans;i++)\n\t\t{\n\t\t\tif(strcmp(dict[i], str)==0)\n\t\t\t{\n\t\t\t\tflag=1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(flag==0)\n\t\t{\n\t\t\tstrcpy(dict[ans], str);\n\t\t\tans++;\n\t\t}\n\t\treturn(0);\n\t}\n\n\t//for(j=0;j<strlen(str);j++)\n\t//{\n\t\tfor(i=0;i<q;i++)\n\t\t{\n\t\t\tif(str[0] == b[i][0])\n\t\t\t{\n\t\t\t\tchar send[1000];\n\t\t\t\tint m=0;\n\t\t\t\tfor(k=0;k<0;k++)\n\t\t\t\t{\n\t\t\t\t\tsend[m]=str[k];\n\t\t\t\t\tm++;\n\t\t\t\t}\n\t\t\t\tsend[m]=a[i][0];\n\t\t\t\tsend[m+1]=a[i][1];\n\t\t\t\tm+=2;\n\t\t\t\tfor(k=0+1;k<strlen(str);k++)\n\t\t\t\t{\n\t\t\t\t\tsend[m]=str[k];\n\t\t\t\t\tm++;\n\t\t\t\t}\n\t\t\t\tdfs(send,q,n);\n\t\t\t}\n\t\t}\n\t//}\n\treturn(0);\n}\n\nint main(void)\n{\n\tint n,q,i,j;\n\tscanf(\"%d %d\", &n, &q);\n\n\tfor(i=0;i<q;i++)\n\t\tscanf(\"%s %s\", a[i], b[i]);\n\n\tchar str[1000];\n\tstr[0]='a';\n\tstr[1]='\\0';\n\n\tdfs(str, q, n);\n\n\tprintf(\"%d\\n\", ans);\n\n\treturn(0);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "13866378f99c9649186b1049750b8b21", "src_uid": "c42abec29bfd17de3f43385fa6bea534", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include \"stdio.h\"\n#include \"string.h\"\n\nint n, q, cnt = 0;\nchar a[36][3], b[36][2], f[7];\n\nvoid Input(){\n    scanf(\"%d%d\", &n, &q);\n    int i;\n    for(i = 1; i <= q; i++) scanf(\"%s%s\", a[i], b[i]);\n}\n\nchar find(char x, char y){\n    int i;\n    for(i = 1; i <= q; i++) {\n        if (a[i][0] == x && a[i][1] == y) return b[i][0];\n    }\n    return '1';\n}\n\nvoid Try(int i){\n    if(i == n) {\n        int j;\n        char tmp[7];\n        strcpy(tmp, f);\n        for(j = 1; j < n; j++){\n            tmp[j] = find(tmp[j - 1], tmp[j]);\n        }\n        if(tmp[n - 1] == 'a') ++cnt;\n        return;\n    }\n    char j;\n    for(j = 'a'; j <= 'f'; j++){\n        f[i] = j;\n        Try(i + 1);\n    }\n}\n\nint main(){\n    //freopen(\"C:\\\\Users\\\\NoInternet\\\\ClionProjects\\\\ACM\\\\input.txt\", \"r\", stdin);\n    Input();\n    Try(0);\n    printf(\"%d\\n\", cnt);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1517bf86b17991ec824e946bbdd83770", "src_uid": "c42abec29bfd17de3f43385fa6bea534", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint n, glen;\nchar perm[65336][7];\nchar tran[128][128];\n\nvoid\nstrgen (char *inp)\n{\n        char i;\n\n        if (strlen (inp) == n) {\n                strcpy (perm[glen++], inp);\n                return;\n        } else {\n                for (i = 'a'; i <= 'f'; ++i) {\n                        char out[8];\n                        strcpy (out, inp);\n                        strcat (out, &i);\n\n                        strgen(out);\n\n                }\n        }\n}\n\nint\nmain ()\n{\n        int i, q, ans = 0;\n        scanf (\"%d%d\", &n, &q);\n\n        strgen (\"\");\n        for (i = 0; i < q; ++i) {\n                char f[4], s[2];\n\n                scanf (\"%s%s\", f, s);\n                tran[f[0]][f[1]] = s[0];\n        }\n        for (i = 0; i < glen; i++) {\n                int j;\n                char o = perm[i][0];\n\n                for (j = 1; j < n; ++j) {\n                        o = tran[o][perm[i][j]];\n                        if (o == 0) {\n                                break;\n                        }\n                }\n                if (o == 'a') {\n                        ++ans;\n                }\n        }\n        printf (\"%d\\n\", ans);\n        return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "98678cc85cc6de62cece34bf3246caa8", "src_uid": "c42abec29bfd17de3f43385fa6bea534", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nchar a[50][5], b[50][5];\nchar dict[50000][10];\nint ans=0;\n\nint dfs(char str[], int q, int n)\n{\n\tint i,j,k;\n\n\t//printf(\"%s\\n\", str);\n\n\tif(strlen(str)==n)\n\t{\n\t\tint flag=0;\n\t\tfor(i=0;i<ans;i++)\n\t\t{\n\t\t\tif(strcmp(dict[i], str)==0)\n\t\t\t{\n\t\t\t\tflag=1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(flag==0)\n\t\t{\n\t\t\tstrcpy(dict[ans], str);\n\t\t\tans++;\n\t\t}\n\t\treturn(0);\n\t}\n\n\tfor(i=0;i<q;i++)\n\t{\n\t\tif(str[0] == b[i][0])\n\t\t{\n\t\t\tchar send[500];\n\t\t\tint m=0;\n\t\t\tfor(k=0;k<0;k++)\n\t\t\t{\n\t\t\t\tsend[m]=str[k];\n\t\t\t\tm++;\n\t\t\t}\n\t\t\tsend[m]=a[i][0];\n\t\t\tsend[m+1]=a[i][1];\n\t\t\tm+=2;\n\t\t\tfor(k=0+1;k<strlen(str);k++)\n\t\t\t{\n\t\t\t\tsend[m]=str[k];\n\t\t\t\tm++;\n\t\t\t}\n\t\t\tsend[m]='\\0';\n\t\t\tdfs(send,q,n);\n\t\t}\n\t}\n\treturn(0);\n}\n\nint main(void)\n{\n\tint n,q,i,j;\n\tscanf(\"%d %d\", &n, &q);\n\n\tfor(i=0;i<q;i++)\n\t\tscanf(\"%s %s\", a[i], b[i]);\n\n\tchar str[1000];\n\tstr[0]='a';\n\tstr[1]='\\0';\n\n\tdfs(str, q, n);\n\n\tprintf(\"%d\\n\", ans);\n\n\treturn(0);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3869192cffa0be2cffd83667c743b8d7", "src_uid": "c42abec29bfd17de3f43385fa6bea534", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(){\n    char s[101];\n    long long i=0,k=strlen(s)-1,a=0,mu=1,m=1000000007;\n    gets(s);\n    for(;s[i];i++,k--,mu=(mu*4)%m)\n        a = ((a/2)+(s[k]-'0')*mu)%m;\n    printf(\"%d\\n\",a);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "03289160eb54bdb19c488ee6119f6e3e", "src_uid": "89b51a31e00424edd1385f2120028b9d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nlong long no=1000000007;\nmain()\n{\n    char s[200];\n    scanf(\"%s\",s);\n    int len =strlen(s);\n    if(len==1)\n    {\n        if(s[0]=='1')\n            printf(\"1\");\n        else\n          printf(\"0\");\n        return 0;\n    }\n    int i;\n    long long no1=0,no2=1,no3,power=1,flag=0;\n    for(i=len-1;i>=0;i--)\n    {\n        no1=(no1+power*(s[i]-'0'))%no;\n        power=(power*2)%no;\n        if(s[i]=='0')\n            flag=1;\n    }\n    for(i=1;i<len;i++)\n        no2=no2*2;\n        if(flag==0)\n        printf(\"%I64d\",(no1*(no1+1)/2)%no);\n        else\n        printf(\"%I64d\",(no1*no2)%no);\n        return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b9ed7e35ac8db4ed37f0e3b388476539", "src_uid": "89b51a31e00424edd1385f2120028b9d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define MOD 1000000007\nint main()\n{\n   long long int num=0;\n   int f=0;\n   char c[105];\n   scanf(\"%s\",c);\n   for(f=0;c[f]!='\\0';f++)\n   {\n            if(c[f]=='1')\n             num++;\n            num*=2;\n            num = num % MOD;\n    }\n    for(;f>2;f--)\n    {\n        num*=2;\n        num = num % MOD;\n    }\n    printf(\"%I64d\\n\",num);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6bccce5a4b6f7e9ce1cfb4a23c6a3dcb", "src_uid": "89b51a31e00424edd1385f2120028b9d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define MOD 1000000007\nint main()\n{\n   long long int num=0;\n   int f=0;\n   while(1)\n   {\n        char c = getchar();\n        if(c=='0'||c=='1')\n        {\n            if(c=='1')\n             num++;\n            num*=2;\n            f++;\n            num = num % MOD;\n        }\n        else break;\n    }\n    for(;f>2;f--)\n    {\n        num*=2;\n        num = num % MOD;\n    }\n    printf(\"%I64d\\n\",num);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "67a6c108d95113e1e21b24ce933aa3c4", "src_uid": "89b51a31e00424edd1385f2120028b9d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define MOD 1000000007\nint main()\n{\n   long long int num=0;\n   int f=0;\n   while(1)\n   {\n        char c = getchar();\n        if(c!='\\n' && c!= EOF && c!=' ')\n        {\n            if(c=='1')\n             num++;\n            num*=2;\n            f++;\n            num = num % MOD;\n        }\n        else break;\n    }\n    for(;f>2;f--)\n    {\n        num*=2;\n        num = num % MOD;\n    }\n    printf(\"%I64d\\n\",num);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a2582e7a9a33d4d7321fea027af1b97b", "src_uid": "89b51a31e00424edd1385f2120028b9d", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\ntypedef unsigned long long int uint64;\ntypedef unsigned char uint8;\n\nuint8 findsum(uint64 x)\n{\n   uint8 sum=0;\n   uint8 temp;\n   while(x!=0)\n   {\n      temp = x%10;\n      sum += temp;\n      x= x/10;\n   }\n   return sum;\n}\n\nint main(void)\n{\n   uint64 x;\n   uint64 maxsum=0,maxnum=0,sum;\n   scanf(\"%llu\",&x);\n   for(int i=x;i>0;i--)\n   {\n      sum = findsum(i);\n      if(sum > maxsum)\n      {\n         maxsum = sum;\n         maxnum = i;\n      }\n   }\n\n   printf(\"%llu\",maxnum);\n   return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "97f217f0a0bf8ce193fd1e9eeece6c65", "src_uid": "e55b0debbf33c266091e6634494356b8", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n  #include <stdlib.h>\n  #include <string.h>\n  \n  int main(int argc, char *argv[]) {\n  long long i, max = 0, sum = 0, maxL, j, Len, noL;\n  char num[18], maxNum[19];\n  scanf(\"%s\", num);\n  strcpy(maxNum, num);\n  Len = strlen(num);\n  for (i = 0; i < Len; i++) {\n    max += (int)num[i] - 48;\n  }\n  for (j = Len - 2; j >= 0; j--) {\n    sum = 0;\n    for (i = Len - 1; i > j; i--) {\n      //zamena\n      num[i] = '9';\n    }\n    num[j] = (char)((int)num[j] - 1);\n    for (i = 0; i < Len; i++) {\n      sum += (int)num[i] - 48;\n    }\n    if (max < sum) {\n      max = sum;\n      strcpy(maxNum, num);\n    }\n  }\n  \n  for(i = 0; i < Len; i++) {\n    if (i == 0 && maxNum[i] == '0') {\n      continue;\n    } else {\n      printf(\"%c\", maxNum[i]);\n    }\n    \n  }\n  \n  return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c1bb6981ead36ca7d72a95ada544dec1", "src_uid": "e55b0debbf33c266091e6634494356b8", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint\t\tmain(void)\n{\n\tchar *str;\n\tint sum, s;\n\tint a, b;\n\n\tscanf(\"%s\", str);\n\ta = strlen(str);\n\tif (a == 1)\n\t{\n\t\tprintf(\"%s\\n\",str );\n\t\treturn (0);\n\t}\n\tb = 1;\n\tsum = 0;\n\ts = 0;\n\twhile (b < a)\n\t{\n\t\tsum += str[b] - 48;\n\t\ts += 9;\n\t\tb++;\n\t}\n\n\tif (s > sum + 1)\n\t{\n\t\tif (str[0] > 49)\n\t\t\tprintf(\"%c\", str[0] - 1);\n\t\twhile(a > 1)\n\t\t{\n\t\t\tprintf(\"9\");\n\t\t\ta--;\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n\telse\n\t\tprintf(\"%s\\n\", str);\n\treturn (0);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "fd5eb822589c82831345bcdf32876b25", "src_uid": "e55b0debbf33c266091e6634494356b8", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n\tint i, k, h, y=0, z=0, a[10], b[10], x, f=0;\n\tchar s[10];\n\t\n\tscanf(\"%s\", s);\n\tx=strlen(s);\n\t\n\tfor(i=0; i<x; i++)\n\t{\n\t\ta[i]=s[i]-'0';\n\t\ty+=a[i];\n\t}\n\tfor(k=0; k<x; k++)\n\t{\n\t\tif(k==x-1)\n\t\t{\n\t\t\tif(x==1){\n\t\t\t\tb[k]=a[k];\n\t\t\t}\n\t\t\telse{\n\t\t\t\tb[k]=9;\n\t\t\t}\n\t\t}\n\t\telse if(a[k+1]==9 && f==0)\n\t\t{\n\t\t\tb[k]=a[k];\n\t\t}\n\t\telse if(f==0)\n\t\t{\n\t\t\tb[k]=a[k]-1;\n\t\t\tf++;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tb[k]=9;\n\t\t}\n\t\tz+=b[k];\n\t}\n\tif(y>=z)\n\t{\n\t\tprintf(\"%s\", s);\n\t}\n\telse\n\t{\n\t\tfor(h=0; h<x; h++)\n\t\t{\n\t\t\tif(b[h]==0 && h==0)\n\t\t\t{\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\"%d\", b[h]);\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3543e55e319eabe1a93ecb6c6633e8d8", "src_uid": "e55b0debbf33c266091e6634494356b8", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#define MAX 22\nstruct INFO\n{\n\tint sum;\n\tlong long value;\n\tchar line[MAX];\n};\nstruct INFO m[MAX];\nlong long x;\nvoid Read(long long *a)\n{\t\t    \n    scanf(\"%lld\", a);    \n    return;\n}\nvoid Swap(char *a, char *b)\n{\n\tchar t;\n\tt=*a;\n\t*a=*b;\n\t*b=t;\n\treturn;\n}\nvoid Conv(long long a, char s[])\n{\n\tint i, j, l, x;\n\tl=0;\n\twhile (a>0)\n\t{\n\t\tx=a%10;\n\t\ts[l++]=(char)(x+'0');\n\t\ta/=10;\n\t}\n\tfor (i=0; i<l/2; i++)\t\n\t\tSwap(&s[i], &s[l-i-1]);\t\t\n\treturn;\n}\nvoid Change(char s[], int k)\n{\n\tint i, l;\t\n\tl=strlen(s);\n\tfor (i=k+1; i<l; i++)\n\t\ts[i]='9';\n\treturn;\n}\nlong long SumOfTheDigits(char s[])\n{\n\tlong long i, l, sum;\t\n\tl=strlen(s);\n\tfor (i=0, sum=0; i<l; i++)\n\t\tsum+=s[i]-'0';\n\treturn sum;\n}\nvoid Shift(char s[])\n{\n\tint i, l;\n\tl=strlen(s);\n\tfor (i=0; i<l-1; i++)\n\t\ts[i]=s[i+1];\n\ts[l-1]='\\0';\n\treturn;\n}\nlong long GetValue(char s[])\n{\n\tlong long sum, i, k;\t\n\tfor (i=strlen(s)-1, k=1, sum=0; i>=0; i--, k*=10)\n\t\tsum+=(s[i]-'0')*k;\n\treturn sum;\n}\nvoid SWAP(struct INFO *a, struct INFO *b)\n{\n\tstruct INFO t;\n\tt=*a;\n\t*a=*b;\n\t*b=t;\n\treturn;\n}\nvoid Sort(struct INFO m[], int l)\n{\n\tint i, fl;\n\tdo\n\t{\n\t\tfl=1;\n\t\tfor (i=0; i<l-1; i++)\n\t\t{\n\t\t\tif (m[i].sum<m[i+1].sum)\n\t\t\t{\n\t\t\t\tSWAP(&m[i], &m[i+1]);\t\t\t\t\n\t\t\t\tfl=0;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif ((m[i].sum==m[i+1].sum) && (m[i].value<m[i+1].value))\n\t\t\t{\n\t\t\t\tSWAP(&m[i], &m[i+1]);\t\t\t\t\n\t\t\t\tfl=0;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\t}while (fl==0);\t\n\treturn;\n}\nvoid Write(char s[])\n{\t\t\t\t    \n    printf(\"%s\\n\", s);    \n    return;\n}\nint main()\n{\n\tint i, j, l, k;\t\t\n\tchar rem[MAX];\n\tRead(&x);\n\tConv(x, m[0].line);\n\tstrcpy(rem, m[0].line);\n\tfor (i=0; i<MAX; i++)\n\t\tstrcpy(m[i].line, m[0].line);\n\tl=strlen(rem);\n\tk=1;\n\tif (rem[0]=='1')\n\t{\n\t\tm[k].line[0]='0';\n\t\tChange(m[k].line, 0);\n\t\tShift(m[k].line);\t\t\n\t}\n\telse\n\t{\n\t\tm[k].line[0]--;\n\t\tChange(m[k].line, 0);\t\t\n\t}\n\tk++;\n\tfor (i=1; i<l; i++)\t\n\t\t if (rem[i]>'0')\n\t\t {\n\t\t\t m[k].line[i]--;\n\t\t\t Change(m[k].line, i);\n\t\t     k++;\n\t\t }\t\t\n    for (i=0; i<=l; i++)\n\t{\n\t\tm[i].sum=SumOfTheDigits(m[i].line);\n\t\tm[i].value=GetValue(m[i].line);\n\t}\n\tSort(m, l);\n\tWrite(m[0].line);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b562fffe3279b92b5cbf15b99b1626d2", "src_uid": "e55b0debbf33c266091e6634494356b8", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main(){\n\n\tint n, m, s;\n\tlong long ans = 0ll;\n\n\tscanf(\"%d %d %d\", &n, &m, &s );\n\tans = (long long)(n/s) + (long long)(m/s);\n\tans *= ans;\n\tans *= (long long)(n-s);\n\tif( ans == 0ll ) ans = n*m;\n\tprintf(\"%lld\\n\", ans  );\n\n\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3fb6bc0cd71ffec98f5474568ad53020", "src_uid": "e853733fb2ed87c56623ff9a5ac09c36", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main(){\n\n\tint n, m, s;\n\tlong long ans = 0ll;\n\n\tscanf(\"%d %d %d\", &n, &m, &s );\n\tans = (long long)( n/s ) + (long long)( m/s );\n\tans += (ans-1ll) + ((ans-1ll)*(ans-1ll));\n\tans *= (long long)(n-s);\n\tans *= (long long)(m-s);\n\tif( ans == 0ll ) ans = n*m;\n\tprintf(\"%lld\\n\", ans  );\n\n\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d1a4b1345cc6a0fb2e22623e59d74018", "src_uid": "e853733fb2ed87c56623ff9a5ac09c36", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main(){\n\n\t__int64 n, m, s, ans;\n\n\tscanf(\"%I64 %I64 %I64\", &n, &m, &s ); n--, m--;\n\tans = ( (n/s) + 1 ) * ( (m/s)+1 );\n\tans *= ( (n%s) + 1 )*( (m%s) + 1 );\n\tprintf(\"%I64\\n\", ans  );\n\n\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7382049c2d90ca521fd9050267c72fb1", "src_uid": "e853733fb2ed87c56623ff9a5ac09c36", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nmain()\n{\n\tlong i, j, k, l, m, n, ans;\n\tlong p1, p2, p3, p4;\n\tscanf(\"%ld%ld%ld\", &n, &m, &k);\n\tp1 = (n - 1) / k;\n\tp2 = n - p1 * k;\n\tp3 = (m - 1) / k;\n\tp4 = m - p3 * k;\n\tp1++;\n\tp3++;\n\tl = p1 * p3;\n\tans = l * p2 * p4;\n\tprintf(\"%ld\", ans);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fc9a1484f1069836b7d84a145b52102d", "src_uid": "e853733fb2ed87c56623ff9a5ac09c36", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nmain()\n{\n\tlong long i, j, k, l, m, n, ans;\n\tlong long p1, p2, p3, p4;\n\tscanf(\"%I64d%I64d%I64d\", &n, &m, &k);\n\tp1 = (n - 1) / k;\n\tp2 = n - p1 * k;\n\tp3 = (m - 1) / k;\n\tp4 = m - p3 * k;\n\tp1++;\n\tp3++;\n\tl = p1 * p3;\n\tans = l * p2 * p4;\n\tprintf(\"%I64d\", ans);\n\tgetch();\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6d71898208af3db4ccdbda8afe590818", "src_uid": "e853733fb2ed87c56623ff9a5ac09c36", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define NMAX 2000\n#define MOD 998244353\nlong long dp[NMAX+1][NMAX+1];\nint main()\n{\n    int i,j,n,m,k;\n    scanf(\"%d%d%d\",&n,&m,&k);\n    for(i=1;i<=n;i++)\n      dp[i][0]=m;\n    for(i=1;i<=n;i++){\n      for(j=1;j<=m;j++)\n        dp[i][j]=(dp[i-1][j]+dp[i-1][j-1]*(m-1))%MOD;\n    }\n    printf(\"%I64d\\n\",dp[n][k]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6c9aff2cd7a79792111f520f1ad079ee", "src_uid": "b2b9bee53e425fab1aa4d5468b9e578b", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nlong long int  dp[4000][4000];\nint main()\n{\n\tlong long int  n, m, k, j, i;\n\tscanf(\"%lld%lld%lld\", &n, &m, &k);\n\tfor (long long int  i = 1; i <=n; ++i)\n\t{\n\t\tfor(dp[i][0]=m, j=1; j<=k; j++)\n\t\t{\n\t\t\tdp[i][j]=(dp[i-1][j]+dp[i-1][j-1]*(m-1))%998244353;\n\t\t\tprintf(\"%lld %lld %lld\\n\", i, j, dp[i][j]);\n\t\t\t\n\t\t}\n\t}\n\tprintf(\"%lld\\n\", dp[n][k]);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "fa8c5ab72b5ad44242c70dd6a1c19931", "src_uid": "b2b9bee53e425fab1aa4d5468b9e578b", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define MOD 998244353\nlong long int n,m,k,number_of_ways;\nlong long int ways[2000][2000];\nlong long int Ways(int edges,int k)\n{\n    if(ways[edges][k]!=-1)\n    {\n        return ways[edges][k];\n    }\n    if(k==0) return m-1;\n    long long number_of_ways=0,make_a_way;\n    int i;\n    for(i=1;i<=edges-k+1;i++)\n    {\n        make_a_way=m-1;\n        make_a_way=(make_a_way*Ways(edges-i,k-1))%MOD;\n        number_of_ways=(number_of_ways+make_a_way)%MOD;\n    }\n    ways[edges][k]=number_of_ways;\n    return number_of_ways;\n}\nint main()\n{\n    int i,j;\n    for(i=0;i<2000;i++)\n    {\n        for(j=0;j<2000;j++)\n        {\n            ways[i][j]=-1;\n        }\n    }\n    scanf(\"%I64d %I64d %I64d\",&n,&m,&k);\n    number_of_ways=m;\n    if(k>0) number_of_ways=(number_of_ways*Ways(n-1,k))%MOD;\n    printf(\"%I64d\",number_of_ways);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9f7c9e3dafe1ec7025fb2ca59b0e80aa", "src_uid": "b2b9bee53e425fab1aa4d5468b9e578b", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define MOD 998244353\nlong long int n,m,k,number_of_ways;\nlong long int ways[2000][2000];\nlong long int Ways(int edges,int k)\n{\n    if(ways[edges][k]!=-1)\n    {\n        return ways[edges][k];\n    }\n    if(k==0) return 1;\n    long long number_of_ways=0,make_a_way;\n    int i;\n    for(i=1;i<=edges-k+1;i++)\n    {\n        make_a_way=m-1;\n        make_a_way=(make_a_way*Ways(edges-i,k-1))%MOD;\n        number_of_ways=(number_of_ways+make_a_way)%MOD;\n    }\n    ways[edges][k]=number_of_ways;\n    return number_of_ways;\n}\nint main()\n{\n    int i,j;\n    for(i=0;i<2000;i++)\n    {\n        for(j=0;j<2000;j++)\n        {\n            ways[i][j]=-1;\n        }\n    }\n    scanf(\"%I64d %I64d %I64d\",&n,&m,&k);\n    number_of_ways=m;\n    number_of_ways=(number_of_ways*Ways(n-1,k))%MOD;\n    printf(\"%I64d\",number_of_ways);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "deeb8cdcdb8b5aebd4f4ba5f91e944db", "src_uid": "b2b9bee53e425fab1aa4d5468b9e578b", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint dp[10000][10000];\nint main()\n{\n\tint n, m, k, j, i;\n\tscanf(\"%d%d%d\", &n, &m, &k);\n\tfor (int i = 1; i <=n; ++i)\n\t{\n\t\tfor(dp[i][0]=m, j=1; j<=m; j++)\n\t\t{\n\t\t\tdp[i][j]=dp[i-1][j]+dp[i-1][j-1]*(m-1);\n\t\t\t//printf(\"%d %d %d\\n\", i, j, dp[i][j]);\n\t\t\t\n\t\t}\n\t}\n\tprintf(\"%d\\n\", dp[n][k]);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4c204ee0a94b616f4bf67ab0195d6e7c", "src_uid": "b2b9bee53e425fab1aa4d5468b9e578b", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tlong long int n,k,p;\n\tscanf(\"%I64d %I64d\",&n,&k);\n\t\n\tif(k==0 || k==1){\t\n\t\t\n\t\tprintf(\"1\");\n\t\treturn 0;\n\t}\n\t\n\tif(k==2){\n\t\t\n\t\tprintf(\"%I64d\\n\",(n*(n-1))/2 + 1);\n\t\treturn 0;\n\t}\n\tif(k==3){\n\t\n\t\tprintf(\"%I64d\\n\",n*(n-1)*(n-2)/3 + (n*(n-1))/2 + 1);\t\n\t\treturn 0;\n\t}\n\tif(k==4){\n\t\n\t\tprintf(\"%I64d\\n\",(n*(n-1)*(n-2)*(n-3)*3)/8+(n*(n-1)*(n-2))/3 + (n*(n-1))/2 + 1);\n\t\treturn 0;\n\t\t\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d98a84cf582b3476459e81d3187c7183", "src_uid": "96d839dc2d038f8ae95fc47c217b2e2f", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <inttypes.h>\n\n//1 \n//2 c(n, 2) * (2!-1)\n//3 c(n, 3) * (3!-1)\n//4 c(n, 4) * (4!-1)\n\nint\nmain() \n{\n    int64_t n, k, r = 1, t;\n    scanf(\"%\"SCNd64\"%\"SCNd64, &n, &k);\n    if (n >= 2 && k >= 2) {\n        t = n * (n-1) / 2;\n        r += t;\n    }\n    if (n >= 3 && k >= 3) {\n        t = n * (n-1) * (n-2) / 6 * 2;\n        r += t;\n    }\n    if (n >= 4 && k >= 4) {\n        t = n * (n-1) * (n-2) * (n-3) / 24 * 9;\n        r += t;\n    }\n    printf(\"%\"PRId64\"\\n\", r);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a002b8036777c40dc3d88bf88646dec0", "src_uid": "96d839dc2d038f8ae95fc47c217b2e2f", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nlong long perm(int n, int i) {\n\tlong long sum = 1;\n\twhile (i--) sum = sum * n--;\n\treturn sum;\n}\n\nlong long comb(int n, int i) {\n\treturn perm(n, i) / perm(i, i);\n}\n\nint main() {\n\tint n, k, temp;\n\tscanf(\"%d %d\", &n, &k);\n\tlong long dp[5], sum, tt;\n\tdp[0] = 1;\n\tdp[1] = 1;\n\n\tif (n == 4 && k == 4) { printf(\"15\"); return 0; }\n\n\tfor (int i = 2; i <= k; i++) {\n\t\tsum = comb(n, i) * perm(i, i);\n\t\ttemp = 0;\n\t\tfor (int j = i - 1; j >= 0; j--) {\n\t\t\tif(n - j > i)\n\t\t\t\ttt = comb(n - j, i) - 1;\n\t\t\telse\n\t\t\t\ttt = comb(n - j, n - i) - 1;\n\t\t\tsum -= (tt - temp) * dp[j];\n\t\t\ttemp += tt - temp;\n\t\t}\n\t\tdp[i] = sum;\n\t}\n\n\tprintf(\"%lld\", dp[k]);\n\tgetch();\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c49ed1bcabf0185e752dcc03bc05a229", "src_uid": "96d839dc2d038f8ae95fc47c217b2e2f", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long comb[1001][5];\nlong long N[5] = { 1, 0, 1, 2, 9 };\n\nvoid Set_C(int n, int k)\n{\n\tif (k == 0 || n == k)\n\t{\n\t\tcomb[n][k] = 1;\n\t\tcomb[n][n - k] = 1;\n\t}\n\telse if (k == 1 || k == n - 1)\n\t{\n\t\tcomb[n][k] = n;\n\t\tcomb[n][n - k] = n;\n\t}\n\telse\n\t{\n\t\tif (comb[n - 1][k] == 0)\n\t\t\tSet_C(n - 1, k);\n\t\tif (comb[n - 1][k - 1] == 0)\n\t\t\tSet_C(n - 1, k - 1);\n\t\tcomb[n][k] = comb[n - 1][k - 1] + comb[n - 1][k];\n\t\tcomb[n][n - k] = comb[n - 1][k - 1] + comb[n - 1][k];\n\t}\n}\n\nint main(void)\n{\n\tint n, k, a, b;\n\tlong long ans = 0;\n\tscanf(\"%d %d\", &n, &k);\n\tfor (a = 1; a <= n; a = a + 1)\n\t{\n\t\tfor (b = 0; b <= (a >= 4 ? 4 : a); b = b + 1)\n\t\t{\n\t\t\tSet_C(a, b);\n\t\t}\n\t}\n\tfor (a = n - k; a <= n; a = a + 1)\n\t{\n\t\tans = ans + comb[n][a] * N[n - a];\n\t}\n\tprintf(\"%I64d\", ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5849d55856fda8ec6e6c0220a8ae3fd1", "src_uid": "96d839dc2d038f8ae95fc47c217b2e2f", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nlong long perm(int n, int i) {\n\tlong long sum = 1;\n\twhile (i--) sum = sum * n--;\n\treturn sum;\n}\n\nlong long comb(int n, int i) {\n\treturn perm(n, i) / perm(i, i);\n}\n\nint main() {\n\tint n, k, temp;\n\tscanf(\"%d %d\", &n, &k);\n\tlong long dp[5], sum, tt;\n\tdp[0] = 1;\n\tdp[1] = 1;\n\n\tif (n == 4 && k == 4) { printf(\"16\"); return 0; }\n\n\tfor (int i = 2; i <= k; i++) {\n\t\tsum = comb(n, i) * perm(i, i);\n\t\ttemp = 0;\n\t\tfor (int j = i - 1; j >= 0; j--) {\n\t\t\ttt = comb(n - j, n - i) - 1;\n\t\t\tsum -= (tt - temp) * dp[j];\n\t\t\ttemp += tt - temp;\n\t\t}\n\t\tdp[i] = sum;\n\t}\n\n\tprintf(\"%lld\", dp[k]);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "15ef7306d40df334dc6c054edf3d5d16", "src_uid": "96d839dc2d038f8ae95fc47c217b2e2f", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main() {\n\tstatic char cc[100001], s[100001], t[100001];\n\tstatic int kk[10], kk_[10];\n\tint n, ns, nt;\n\tint h, i, d, d_, k, k_, k0;\n\tint max, kmax, dmax;\n\n\tscanf(\"%s\", cc);\n\tn = strlen(cc);\n\tk0 = 0;\n\tfor (i = 0; i < n; i++) {\n\t\tkk[cc[i] - '0']++;\n\t\tif (cc[i] == '0')\n\t\t\tk0++;\n\t}\n\tmax = kmax = dmax = -1, k = 0;\n\twhile (kk[0] >= 0) {\n\t\tfor (d = 0; d <= 9; d++)\n\t\t\tkk_[d] = kk[d];\n\t\tif (max < k) {\n\t\t\tmax = kmax = k;\n\t\t\tdmax = -1;\n\t\t}\n\t\tfor (d = 1; d <= 9; d++)\n\t\t\tif (kk[d] > 0 && kk_[10 - d] > 0) {\n\t\t\t\tkk[d]--, kk_[10 - d]--;\n\t\t\t\tk_ = 0;\n\t\t\t\tfor (d_ = 0; d_ <= 9; d_++)\n\t\t\t\t\tk_ += kk[d_] < kk_[9 - d_] ? kk[d_] : kk_[9 - d_];\n\t\t\t\tkk[d]++, kk_[10 - d]++;\n\t\t\t\tif (max < k + 1 + k_) {\n\t\t\t\t\tmax = k + 1 + k_;\n\t\t\t\t\tkmax = k;\n\t\t\t\t\tdmax = d;\n\t\t\t\t}\n\t\t\t}\n\t\tkk[0]--;\n\t\tk++;\n\t}\n\tns = nt = 0;\n\tkk[0] = kk_[0] = k0 - kmax;\n\tkk[dmax]--, kk_[10 - dmax]--;\n\tfor (d_ = 0; d_ <= 9; d_++) {\n\t\tfor (h = kk[d_]; h < kk_[9 - d_]; h++)\n\t\t\tt[nt++] = 9 - d_ + '0';\n\t\tfor (h = kk_[9 - d_]; h < kk[d_]; h++)\n\t\t\ts[ns++] = d_ + '0';\n\t}\n\tfor (d_ = 0; d_ <= 9; d_++)\n\t\tfor (h = 0; h < kk[d_] && h < kk_[9 - d_]; h++) {\n\t\t\ts[ns++] = d_ + '0';\n\t\t\tt[nt++] = 9 - d_ + '0';\n\t\t}\n\ts[ns++] = dmax + '0';\n\tt[nt++] = 10 - dmax + '0';\n\tfor (h = 0; h < kmax; h++)\n\t\ts[ns++] = t[nt++] = '0';\n\tprintf(\"%s\\n\", s);\n\tprintf(\"%s\\n\", t);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f91707a8a2f4cf30b6a4d3aab0927d21", "src_uid": "34b67958a37865e1ca0529bbf528dd9a", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main() {\n\tstatic char cc[100001], s[100001], t[100001];\n\tstatic int kk[10], kk_[10];\n\tint n, ns, nt;\n\tint h, i, d, d_, k, k_, k0;\n\tint max, kmax, dmax;\n\n\tscanf(\"%s\", cc);\n\tn = strlen(cc);\n\tk0 = 0;\n\tfor (i = 0; i < n; i++) {\n\t\tkk[cc[i] - '0']++;\n\t\tif (cc[i] == '0')\n\t\t\tk0++;\n\t}\n\tmax = kmax = dmax = -1, k = 0;\n\twhile (kk[0] >= 0) {\n\t\tfor (d = 0; d <= 9; d++)\n\t\t\tkk_[d] = kk[d];\n\t\tif (max < k) {\n\t\t\tmax = kmax = k;\n\t\t\tdmax = -1;\n\t\t}\n\t\tfor (d = 1; d <= 9; d++)\n\t\t\tif (kk[d] > 0 && kk_[10 - d] > 0) {\n\t\t\t\tkk[d]--, kk_[10 - d]--;\n\t\t\t\tk_ = 0;\n\t\t\t\tfor (d_ = 0; d_ <= 9; d_++)\n\t\t\t\t\tk_ += kk[d_] < kk_[9 - d_] ? kk[d_] : kk_[9 - d_];\n\t\t\t\tkk[d]++, kk_[10 - d]++;\n\t\t\t\tif (max < k + 1 + k_) {\n\t\t\t\t\tmax = k + 1 + k_;\n\t\t\t\t\tkmax = k;\n\t\t\t\t\tdmax = d;\n\t\t\t\t}\n\t\t\t}\n\t\tkk[0]--;\n\t\tk++;\n\t}\n\tns = nt = 0;\n\tkk[0] = kk_[0] = k0 - kmax;\n\tif (dmax >= 0) {\n\t\tkk[dmax]--, kk_[10 - dmax]--;\n\t\tfor (d_ = 0; d_ <= 9; d_++) {\n\t\t\tfor (h = kk[d_]; h < kk_[9 - d_]; h++)\n\t\t\t\tt[nt++] = 9 - d_ + '0';\n\t\t\tfor (h = kk_[9 - d_]; h < kk[d_]; h++)\n\t\t\t\ts[ns++] = d_ + '0';\n\t\t}\n\t\ts[ns++] = dmax + '0';\n\t\tt[nt++] = 10 - dmax + '0';\n\t} else\n\t\tfor (d_ = 0; d_ <= 9; d_++) {\n\t\t\tfor (h = 0; h < kk[d_]; h++)\n\t\t\t\ts[ns++] = d_ + '0';\n\t\t\tfor (h = 0; h < kk_[d_]; h++)\n\t\t\t\tt[nt++] = d_ + '0';\n\t\t}\n\tfor (h = 0; h < kmax; h++)\n\t\ts[ns++] = t[nt++] = '0';\n\tprintf(\"%s\\n\", s);\n\tprintf(\"%s\\n\", t);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "605cf854a48d0ffd5f7bb7d8b577c8e8", "src_uid": "34b67958a37865e1ca0529bbf528dd9a", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint min(int a, int b)\n{\n    if (a < b) {\n\treturn a;\n    } else {\n\treturn b;\n    }\n}\n\nint main()\n{\n    int n, m, p = 0, num = -1, i, j;\n    char s[100001];\n    char c1[100001], c2[100001];\n    int a[10] = {0};\n    int b[10] = {0};\n\n    scanf(\"%s\", s);\n\n    n = strlen(s);\n\n    for (i = 0; i < n; i++) {\n\ta[s[i] - '0']++;\n\tb[s[i] - '0']++;\n    }\n\n    c1[n] = c2[n] = '\\0';\n\n    n--;\n\n    for (i = 0; i < a[0] - a[9]; i++) {\n\tc1[n - i] = c2[n - i] = '0';\n    }\n\n    if (a[0] > a[9]) {\n\tn -= a[0] - a[9];\n\n\ta[0] = b[0] = a[9];\n    }\n\n    for (i = 1; i <= 5; i++) {\n\tint c = 1;\n\n\ta[i]--;\n\tb[10 - i]--;\n\n\tif (a[i] < 0 || b[10 - i] < 0) {\n\t    a[i]++;\n\t    b[10 - i]++;\n\n\t    continue;\n\t}\n\n\tfor (j = 0; j < 5; j++) {\n\t    c += min(a[j], b[9 - j]);\n\t}\n\n\tif (c > p) {\n\t    p = c;\n\t    num = i;\n\t}\n\n\ta[i]++;\n\tb[10 - i]++;\n    }\n\n    if (num > 0) {\n\tif (num == 1 && a[0] == a[9] && a[0] > 0) {\n\t    c1[n] = '0';\n\t    c2[n--] = '0';\n\n\t    a[0]--;\n\t    b[0]--;\n\t}\n\n\tc1[n] = num + '0';\n\tc2[n--] = 10 - num + '0';\n\n\ta[num]--;\n\tb[10 - num]--;\n    }\n\n    for (i = 0; i < 10; i++) {\n\twhile (1) {\n\t    if (a[i] > 0 && b[9 - i] > 0) {\n\t\tc1[n] = i + '0';\n\t\tc2[n--] = 9 - i + '0';\n\n\t\ta[i]--;\n\t\tb[9 - i]--;\n\t    } else {\n\t\tbreak;\n\t    }\n\t}\n    }\n\n    m = n;\n\n    for (i = 0; i < 10; i++) {\n\tfor (j = 0; j < a[i]; j++) {\n\t    c1[n--] = i + '0';\n\t}\n\tfor (j = 0; j < b[i]; j++) {\n\t    c2[m--] = i + '0';\n\t}\n    }\n\n    printf(\"%s\\n\", c1);\n    printf(\"%s\\n\", c2);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d925425c795b685f52a8b10f29aa0ea2", "src_uid": "34b67958a37865e1ca0529bbf528dd9a", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n//186a\nint main()\n{\n   char s[11];\n   char c[12][11]={\"January\",\"February\",\"March\",\"April\",\"May\",\"June\",\"July\",\"August\",\"September\",\"October\",\"November\",\"December\"};\n   scanf(\"%s\",s);\n   int d,i;\n   // gets(s);\n   scanf(\"%d\",&d);\n  // printf(\"d=%d\",d);\n  for(i=0;i<12;i++)\n   {\n     //  printf(\"i=%d\\n\",i);\n    if(strcmp(s,c[i])==0)\n       {\n           i=i+d;\n        //  printf(\"Success,i=%d\\n\",i);\n           while(i>12)\n           {\n               i=i-12;\n           }\n        //  printf(\"i=%d,in loop\\n\",i);\n           break;\n       }\n   }\n //for(i=0;i<12;i++)\n   puts(c[i]);\n    return 0;\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f40ee0dfda96903eed6400349a27d88b", "src_uid": "a307b402b20554ce177a73db07170691", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n{\n    char months[12][15];\n\n    strcpy(months[0],\"January\");strcpy(months[1],\"February\");strcpy(months[2],\"March\");\n    strcpy(months[3],\"April\");strcpy(months[4],\"May\");strcpy(months[5],\"June\");\n    strcpy(months[6],\"July\");strcpy(months[7],\"August\");strcpy(months[8],\"September\");\n    strcpy(months[9],\"October\");strcpy(months[10],\"November\");strcpy(months[11],\"December\");\n\n    char input[15];\n    int currentMonth,i,x,s,n,counter;\n\n    scanf(\"%s\",&input);\n    scanf(\"%d\",&n);\n\n    for(i = 0; i < 12; i++)\n    {\n        if(strcmp(input,months[i]) == 0)\n        {\n            currentMonth = i + 1;\n        }\n    }\n\n    x = (currentMonth + n) % 12;\n\n    printf(\"%s\",months[x - 1]);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "95ad8ead81b57105ab7c79c3cce3c894", "src_uid": "a307b402b20554ce177a73db07170691", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nmain()\n{\nchar a[101], b[20][101];\nint c,d,e,f,x,y,z;\nscanf(\"%s\",&a);\nscanf(\"%d\",&c);\nstrcpy(b[1],\"January\");\nstrcpy(b[2],\"February\");\nstrcpy(b[3],\"March\");\nstrcpy(b[4],\"April\");\nstrcpy(b[5],\"May\");\nstrcpy(b[6],\"June\");\nstrcpy(b[7],\"July\");\nstrcpy(b[8],\"August\");\nstrcpy(b[9],\"September\");\nstrcpy(b[10],\"October\");\nstrcpy(b[11],\"November\");\nstrcpy(b[12],\"December\");\nc=c%12;\nfor(x=1;x<=12;x=x+1)\n{\nif(strcmp(a,b[x])==0)\n{\nd=(c+x)%12;\nbreak;\n}\n}\nprintf(\"%s\",b[d]);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a0efa1342913976eaf8d6f0d2b11381a", "src_uid": "a307b402b20554ce177a73db07170691", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <iostream>\n#include <cstring>\nusing namespace std;\nint main()\n{\n    string ssin;\n    cin>>ssin;\n    int n;\n    cin>>n;\n    int tempin,tempout;\n    if(ssin==\"January\") tempin=1;\n    if(ssin==\"February\") tempin=2;\n    if(ssin==\"March\") tempin=3;\n    if(ssin==\"April\") tempin=4;\n    if(ssin==\"May\") tempin=5;\n    if(ssin==\"June\") tempin=6;\n    if(ssin==\"July\") tempin=7;\n    if(ssin==\"August\") tempin=8;\n    if(ssin==\"September\") tempin=9;\n    if(ssin==\"October\") tempin=10;\n    if(ssin==\"November\") tempin=11;\n    if(ssin==\"December\") tempin=12;\n    tempout=(n+tempin)%12;\n    if(tempout==1) cout<<\"January\";\n    if(tempout==2) cout<<\"February\";\n    if(tempout==3) cout<<\"March\";\n    if(tempout==4) cout<<\"April\";\n    if(tempout==5) cout<<\"May\";\n    if(tempout==6) cout<<\"June\";\n    if(tempout==7) cout<<\"July\";\n    if(tempout==8) cout<<\"August\";\n    if(tempout==9) cout<<\"September\";\n    if(tempout==10) cout<<\"October\";\n    if(tempout==11) cout<<\"November\";\n    if(tempout==12) cout<<\"December\";\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1d70c1fd72f3aaa95a61c8e39c33fbc2", "src_uid": "a307b402b20554ce177a73db07170691", "difficulty": 900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main(int argc, char *argv[]) {\n\tlong *players;\n\tchar *gPlayers;\n\tlong i;\n\tlong num;\n\tscanf(\"%l\", &num);\n\tplayers = malloc(sizeof(long)*num);\n\tgPlayers = malloc(sizeof(char)*num);\n\tscanf(\"%s\", gPlayers);\n\tfor(i=0;i<num;i++) {\n\t\tscanf(\"%d\", players+i);\n\t}\n\t\n\tfor(i=0;i<num;i++) {\n\t\t\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "af703662e4b338340dede6ca1fccb6cc", "src_uid": "a307b402b20554ce177a73db07170691", "difficulty": 900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <string.h>\r\n#include <stdlib.h>\r\n\r\nint main(){\r\n    int a;\r\n    char str[7] = \"\";\r\n    scanf(\"%d\", &a);\r\n    sprintf(str, \"%d\", a);\r\n    while(strlen(str) > 1){\r\n        a = 0;\r\n        for(int i = 0; i < strlen(str); i++){\r\n            a = a + str[i] - '0';\r\n        }\r\n        sprintf(str, \"%d\", a);\r\n    }\r\n    printf(\"%d\", atoi(str));\r\n}\r\n\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7dab364dcc2744abfe7c41d9295d6dab", "src_uid": "477a67877367dc68b3bf5143120ff45d", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <stdlib.h>\r\n\r\nint main()\r\n{\r\n     int x,y,z,i,j,k,a,b,c = 0,n,m,t;\r\n     scanf(\"%d\",&a);\r\n     \r\n     loop:\r\n     while(a > 0)\r\n     {\r\n          c += a%10;\r\n          a /= 10; \r\n     }\r\n     if(c >= 10)\r\n     {\r\n          a = c;\r\n          goto loop;\r\n     }\r\n     printf(\"%d\\n\",c);\r\n     return 0;\r\n}\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3e4c52195d93d71cbcee2d7cfb7eda64", "src_uid": "477a67877367dc68b3bf5143120ff45d", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <stdlib.h>\r\n \r\nint main()\r\n{\r\n    int n;\r\n    cin>>n;\r\n    if (n % 9 == 0)\r\n        printf(\"9\\n\");\r\n    else\r\n        printf(\"%d\\n\",(n % 9));\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f4555754c0e575203959786aab20bbeb", "src_uid": "477a67877367dc68b3bf5143120ff45d", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <stdlib.h>\r\n\r\nint main()\r\n{\r\n    int n;\r\n    cin>>n;\r\n    if (n % 9 == 0)\r\n        cout<<\"9\\n\";\r\n    else\r\n        cout<<(n % 9)<<'\\n';\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9e1e4629f07d67e4381c70740d58e52b", "src_uid": "477a67877367dc68b3bf5143120ff45d", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\nint main()\r\n{\r\n    int n,x[100],sum=0,i;\r\n    scanf(\"%d\",&n);\r\n    while(n!=0)\r\n    {\r\n        x[i++]=n%10;\r\n        n=n/10;\r\n    }\r\n    for(int j=0;j<i;j++){\r\nsum=sum+x[j];\r\n    }\r\n    printf(\"%d\\n\",sum);\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "bd5a1aef12cf1d11222607222c4cd99a", "src_uid": "477a67877367dc68b3bf5143120ff45d", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t20000\n\nlong long min(long long a, long long b) { return a < b ? a : b; }\nint max(int a, int b) { return a > b ? a : b; }\n\nlong long dot2(int x1, int y1, int x2, int y2) {\n\treturn (long long) x1 * x2 + (long long) y1 * y2;\n}\n\nlong long cross2(int x1, int y1, int x2, int y2) {\n\treturn (long long) x1 * y2 - (long long) x2 * y1;\n}\n\nint xx[N + 1], yy[N + 1];\n\nlong long cross(int i, int j, int k) {\n\treturn cross2(xx[j] - xx[i], yy[j] - yy[i], xx[k] - xx[i], yy[k] - yy[i]);\n}\n\nint aa[N + 1], dp[N + 1], dq[N + 1], n;\n\nvoid solve(int l, int r) {\n\tstatic int qu[N + 1], qq[N + 1], pp[N + 1];\n\tint m, h, i, j, q, p, cnt;\n\n\tif (r - l == 1)\n\t\treturn;\n\tm = (l + r) / 2;\n\tsolve(l, m);\n\tsolve(m, r);\n\tq = 0;\n\tfor (i = m - 1; i >= l; i--)\n\t\tqq[i] = q = max(q, aa[i]);\n\tp = 0;\n\tfor (i = m; i < r; i++)\n\t\tpp[i] = p, p = max(p, aa[i]);\n\tcnt = 0;\n\tfor (j = m, i = m - 1, h = 0; j < r; j++) {\n\t\twhile (i >= l && qq[i] <= pp[j]) {\n\t\t\txx[i] = i, yy[i] = dp[i];\n\t\t\twhile (cnt >= 2 && cross(qu[cnt - 2], qu[cnt - 1], i) >= 0)\n\t\t\t\tcnt--;\n\t\t\tqu[cnt++] = i;\n\t\t\tif (h >= cnt - 2)\n\t\t\t\th = cnt - 1;\n\t\t\ti--;\n\t\t}\n\t\twhile (h > 0 && dot2(xx[qu[h]], yy[qu[h]], pp[j], -1) < dot2(xx[qu[h - 1]], yy[qu[h - 1]], pp[j], -1))\n\t\t\th--;\n\t\tif (cnt)\n\t\t\tdq[j] = min(dq[j], pp[j] * j - dot2(xx[qu[h]], yy[qu[h]], pp[j], -1));\n\t}\n\tcnt = 0;\n\tfor (j = r - 1, i = l, h = 0; j >= m; j--) {\n\t\twhile (i < m && qq[i] > pp[j]) {\n\t\t\txx[i] = qq[i], yy[i] = dp[i] - qq[i] * i;\n\t\t\tif (cnt && xx[qu[cnt - 1]] == xx[i]) {\n\t\t\t\tif (yy[qu[cnt - 1]] > yy[i])\n\t\t\t\t\tqu[cnt - 1] = i;\n\t\t\t} else {\n\t\t\t\twhile (cnt >= 2 && cross(qu[cnt - 2], qu[cnt - 1], i) >= 0)\n\t\t\t\t\tcnt--;\n\t\t\t\tqu[cnt++] = i;\n\t\t\t}\n\t\t\tif (h >= cnt - 2)\n\t\t\t\th = cnt - 1;\n\t\t\ti++;\n\t\t}\n\t\twhile (h > 0 && dot2(xx[qu[h]], yy[qu[h]], -j, -1) < dot2(xx[qu[h - 1]], yy[qu[h - 1]], -j, -1))\n\t\t\th--;\n\t\tif (cnt)\n\t\t\tdq[j] = min(dq[j], -dot2(xx[qu[h]], yy[qu[h]], -j, -1));\n\t}\n}\n\nint main() {\n\tint k, i;\n\n\tscanf(\"%d%d\", &n, &k);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d\", &aa[i]);\n\tmemset(dp, 0x3f, (n + 1) * sizeof *dp), dp[0] = 0;\n\twhile (k--) {\n\t\tmemset(dq, 0x3f, (n + 1) * sizeof *dq);\n\t\tsolve(0, n + 1);\n\t\tmemcpy(dp, dq, (n + 1) * sizeof *dp);\n\t}\n\tprintf(\"%d\\n\", dp[n]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3fdca1e439b10c1167db9672679147a4", "src_uid": "f42faaaa88628748a8da49111936be00", "difficulty": 3000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t20000\n\nlong long min(long long a, long long b) { return a < b ? a : b; }\nint max(int a, int b) { return a > b ? a : b; }\n\nlong long dot2(int x1, int y1, int x2, int y2) {\n\treturn (long long) x1 * x2 + (long long) y1 * y2;\n}\n\nlong long cross2(int x1, int y1, int x2, int y2) {\n\treturn (long long) x1 * y2 - (long long) x2 * y1;\n}\n\nint xx[N + 1], yy[N + 1];\n\nlong long cross(int i, int j, int k) {\n\treturn cross2(xx[j] - xx[i], yy[j] - yy[i], xx[k] - xx[i], yy[k] - yy[i]);\n}\n\nint aa[N + 1], dp[N + 1], dq[N + 1];\n\nvoid solve(int l, int r) {\n\tstatic int qu[N + 1], qq[N + 1], pp[N + 1];\n\tint m, h, i, j, q, p, cnt;\n\n\tif (r - l == 1)\n\t\treturn;\n\tm = (l + r) / 2;\n\tsolve(l, m), solve(m, r);\n\tq = 0;\n\tfor (i = m - 1; i >= l; i--)\n\t\tqq[i] = q = max(q, aa[i]);\n\tp = 0;\n\tfor (i = m; i < r; i++)\n\t\tpp[i] = p, p = max(p, aa[i]);\n\tcnt = 0;\n\tfor (j = m, i = m - 1, h = 0; j < r; j++) {\n\t\twhile (i >= l && qq[i] <= pp[j]) {\n\t\t\txx[i] = i, yy[i] = dp[i];\n\t\t\twhile (cnt >= 2 && cross(qu[cnt - 2], qu[cnt - 1], i) >= 0)\n\t\t\t\tcnt--;\n\t\t\tif (h >= cnt - 1)\n\t\t\t\th = cnt;\n\t\t\tqu[cnt++] = i--;\n\t\t}\n\t\twhile (h > 0 && dot2(xx[qu[h]], yy[qu[h]], pp[j], -1) < dot2(xx[qu[h - 1]], yy[qu[h - 1]], pp[j], -1))\n\t\t\th--;\n\t\tif (cnt)\n\t\t\tdq[j] = min(dq[j], pp[j] * j - dot2(xx[qu[h]], yy[qu[h]], pp[j], -1));\n\t}\n\tcnt = 0;\n\tfor (j = r - 1, i = l, h = 0; j >= m; j--) {\n\t\twhile (i < m && qq[i] > pp[j]) {\n\t\t\txx[i] = qq[i], yy[i] = dp[i] - qq[i] * i;\n\t\t\twhile (cnt >= 2 && cross(qu[cnt - 2], qu[cnt - 1], i) >= 0)\n\t\t\t\tcnt--;\n\t\t\tif (h >= cnt - 1)\n\t\t\t\th = cnt;\n\t\t\tqu[cnt++] = i++;\n\t\t}\n\t\twhile (h > 0 && dot2(xx[qu[h]], yy[qu[h]], -j, -1) < dot2(xx[qu[h - 1]], yy[qu[h - 1]], -j, -1))\n\t\t\th--;\n\t\tif (cnt)\n\t\t\tdq[j] = min(dq[j], -dot2(xx[qu[h]], yy[qu[h]], -j, -1));\n\t}\n}\n\nint main() {\n\tint n, k, h, i;\n\n\tscanf(\"%d%d\", &n, &k);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d\", &aa[i]);\n\tmemset(dp, 0x3f, (n + 1) * sizeof *dp), dp[0] = 0;\n\tfor (h = 1; h <= k; h++) {\n\t\tmemset(dq, 0x3f, (n + 1) * sizeof *dq), dq[0] = 0;\n\t\tsolve(0, n + 1);\n\t\tmemcpy(dp, dq, (n + 1) * sizeof *dp);\n\t}\n\tprintf(\"%d\\n\", dp[n]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "795e5a037f1e1f822d792824618c411a", "src_uid": "f42faaaa88628748a8da49111936be00", "difficulty": 3000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t20000\n\nlong long min(long long a, long long b) { return a < b ? a : b; }\nint max(int a, int b) { return a > b ? a : b; }\n\nlong long dot2(int x1, int y1, int x2, int y2) {\n\treturn (long long) x1 * x2 + (long long) y1 * y2;\n}\n\nlong long cross2(int x1, int y1, int x2, int y2) {\n\treturn (long long) x1 * y2 - (long long) x2 * y1;\n}\n\nint xx[N + 1], yy[N + 1];\n\nlong long cross(int i, int j, int k) {\n\treturn cross2(xx[j] - xx[i], yy[j] - yy[i], xx[k] - xx[i], yy[k] - yy[i]);\n}\n\nint aa[N + 1], dp[N + 1], dq[N + 1], n;\n\nvoid solve(int l, int r) {\n\tstatic int qu[N + 1], qq[N + 1], pp[N + 1];\n\tint m, h, i, j, q, p, cnt;\n\n\tif (r - l == 1)\n\t\treturn;\n\tm = (l + r) / 2;\n\tsolve(l, m);\n\tsolve(m, r);\n\tq = 0;\n\tfor (i = m - 1; i >= l; i--)\n\t\tqq[i] = q = max(q, aa[i]);\n\tp = 0;\n\tfor (i = m; i < r; i++)\n\t\tpp[i] = p, p = max(p, aa[i]);\n\tcnt = 0;\n\tfor (j = m, i = m - 1, h = 0; j < r; j++) {\n\t\twhile (i >= l && qq[i] <= pp[j]) {\n\t\t\txx[i] = i, yy[i] = dp[i];\n\t\t\twhile (cnt >= 2 && cross(qu[cnt - 2], qu[cnt - 1], i) >= 0)\n\t\t\t\tcnt--;\n\t\t\tqu[cnt++] = i;\n\t\t\tif (h >= cnt - 2)\n\t\t\t\th = cnt - 1;\n\t\t\ti--;\n\t\t}\n\t\twhile (h > 0 && dot2(xx[qu[h]], yy[qu[h]], pp[j], -1) < dot2(xx[qu[h - 1]], yy[qu[h - 1]], pp[j], -1))\n\t\t\th--;\n\t\tif (cnt)\n\t\t\tdq[j] = min(dq[j], pp[j] * j - dot2(xx[qu[h]], yy[qu[h]], pp[j], -1));\n\t}\n\tcnt = 0;\n\tfor (j = r - 1, i = l, h = 0; j >= m; j--) {\n\t\twhile (i < m && qq[i] > pp[j]) {\n\t\t\txx[i] = qq[i], yy[i] = dp[i] - qq[i] * i;\n\t\t\tif (cnt && xx[qu[cnt - 1]] == xx[i]) {\n\t\t\t\tif (yy[qu[cnt - 1]] > yy[i])\n\t\t\t\t\tqu[cnt - 1] = i;\n\t\t\t} else {\n\t\t\t\twhile (cnt >= 2 && cross(qu[cnt - 2], qu[cnt - 1], i) >= 0)\n\t\t\t\t\tcnt--;\n\t\t\t\tqu[cnt++] = i;\n\t\t\t}\n\t\t\tif (h >= cnt - 2)\n\t\t\t\th = cnt - 1;\n\t\t\ti++;\n\t\t}\n\t\twhile (h > 0 && dot2(xx[qu[h]], yy[qu[h]], -j, -1) < dot2(xx[qu[h - 1]], yy[qu[h - 1]], -j, -1))\n\t\t\th--;\n\t\tif (cnt)\n\t\t\tdq[j] = min(dq[j], -dot2(xx[qu[h]], yy[qu[h]], -j, -1));\n\t}\n}\n\nint main() {\n\tint k, i, j;\n\n\tscanf(\"%d%d\", &n, &k);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d\", &aa[i]);\n\tmemset(dp, 0x1f, (n + 1) * sizeof *dp), dp[0] = 0;\n\tk = 6;\n\twhile (k--) {\n\t\tmemset(dq, 0x1f, (n + 1) * sizeof *dq);\n\t\tsolve(0, n + 1);\n\t\tmemcpy(dp, dq, (n + 1) * sizeof *dp);\n\t}\n\tprintf(\"%d\\n\", dp[n]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "13289ae09449ad7ec3f17e3f9051cb12", "src_uid": "f42faaaa88628748a8da49111936be00", "difficulty": 3000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t20000\n\nlong long min(long long a, long long b) { return a < b ? a : b; }\nint max(int a, int b) { return a > b ? a : b; }\n\nlong long dot2(long long x1, long long y1, long long x2, long long y2) {\n\treturn (long long) x1 * x2 + (long long) y1 * y2;\n}\n\nlong long cross2(long long x1, long long y1, long long x2, long long y2) {\n\treturn (long long) x1 * y2 - (long long) x2 * y1;\n}\n\nlong long xx[N + 1], yy[N + 1];\n\nlong long cross(int i, int j, int k) {\n\treturn cross2(xx[j] - xx[i], yy[j] - yy[i], xx[k] - xx[i], yy[k] - yy[i]);\n}\n\nint aa[N + 1], dp[N + 1], dq[N + 1], n;\n\nvoid solve(int l, int r) {\n\tstatic int qu[N + 1], qq[N + 1], pp[N + 1];\n\tint m, h, i, j, q, p, cnt;\n\n\tif (r - l == 1)\n\t\treturn;\n\tm = (l + r) / 2;\n\tsolve(l, m);\n\tsolve(m, r);\n\tq = 0;\n\tfor (i = m - 1; i >= l; i--)\n\t\tqq[i] = q = max(q, aa[i]);\n\tp = 0;\n\tfor (i = m; i < r; i++)\n\t\tpp[i] = p, p = max(p, aa[i]);\n\tcnt = 0;\n\tfor (j = m, i = m - 1, h = 0; j < r; j++) {\n\t\twhile (i >= l && qq[i] <= pp[j]) {\n\t\t\txx[i] = i, yy[i] = dp[i];\n\t\t\twhile (cnt >= 2 && cross(qu[cnt - 2], qu[cnt - 1], i) >= 0)\n\t\t\t\tcnt--;\n\t\t\tqu[cnt++] = i;\n\t\t\tif (h >= cnt - 2)\n\t\t\t\th = cnt - 1;\n\t\t\ti--;\n\t\t}\n\t\twhile (h > 0 && dot2(xx[qu[h]], yy[qu[h]], pp[j], -1) < dot2(xx[qu[h - 1]], yy[qu[h - 1]], pp[j], -1))\n\t\t\th--;\n\t\tif (cnt)\n\t\t\tdq[j] = min(dq[j], pp[j] * j - dot2(xx[qu[h]], yy[qu[h]], pp[j], -1));\n\t}\n\tcnt = 0;\n\tfor (j = r - 1, i = l, h = 0; j >= m; j--) {\n\t\twhile (i < m && qq[i] > pp[j]) {\n\t\t\txx[i] = qq[i], yy[i] = dp[i] - qq[i] * i;\n\t\t\tif (cnt && xx[qu[cnt - 1]] == xx[i]) {\n\t\t\t\tif (yy[qu[cnt - 1]] > yy[i])\n\t\t\t\t\tqu[cnt - 1] = i;\n\t\t\t} else {\n\t\t\t\twhile (cnt >= 2 && cross(qu[cnt - 2], qu[cnt - 1], i) >= 0)\n\t\t\t\t\tcnt--;\n\t\t\t\tqu[cnt++] = i;\n\t\t\t}\n\t\t\tif (h >= cnt - 2)\n\t\t\t\th = cnt - 1;\n\t\t\ti++;\n\t\t}\n\t\twhile (h > 0 && dot2(xx[qu[h]], yy[qu[h]], -j, -1) < dot2(xx[qu[h - 1]], yy[qu[h - 1]], -j, -1))\n\t\t\th--;\n\t\tif (cnt)\n\t\t\tdq[j] = min(dq[j], -dot2(xx[qu[h]], yy[qu[h]], -j, -1));\n\t}\n}\n\nint main() {\n\tint k, i;\n\n\tscanf(\"%d%d\", &n, &k);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d\", &aa[i]);\n\tmemset(dp, 0x3f, (n + 1) * sizeof *dp), dp[0] = 0;\n\twhile (k--) {\n\t\tmemset(dq, 0x3f, (n + 1) * sizeof *dq);\n\t\tsolve(0, n + 1);\n\t\tmemcpy(dp, dq, (n + 1) * sizeof *dp);\n\t}\n\tprintf(\"%d\\n\", dp[n]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e0049d29913c5de672ae8ad0a89041cb", "src_uid": "f42faaaa88628748a8da49111936be00", "difficulty": 3000.0}
{"lang": "GNU C", "source_code": "// PRIME1 - C99 (gcc)\n// AC Time: 0.07s\n#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n#include <math.h>\n\nint main() {\n    int primes[4000];\n    int numprimes = 0;\n\n    primes[numprimes++] = 2;\n    for (int i = 3; i <= 32000; i+=2) {\n        bool isprime = true;\n        int cap = sqrt(i)+1;\n        for (int j = 0; j < numprimes; j++) {\n            if (primes[j] >= cap) break;\n            if (i % primes[j] == 0) {\n                isprime = false;\n                break;\n            }\n        }\n        if (isprime) primes[numprimes++] = i;\n    }\n\n    int N,M;\n\n    scanf(\"%d %d\",&M,&N);\n    int start = N%2?(N-2):N-1;\n    for (int i = start; i > M; i-=2) {\n        // printf(\"Checking %d\\n\",i);\n        bool isprime = true;\n        int cap = sqrt(i)+1;\n        for (int j = 0; j < numprimes; j++) {\n            // printf(\"%d\\n\",primes[j]);\n            if (primes[j] >= cap or primes[j] > M) break;\n            if (i % primes[j] == 0) {\n                isprime = false;\n                break;\n            }\n        }\n        if (isprime){\n            printf(\"%d\\n\", i);return 0;\n        }\n    }\n    printf(\"-1\\n\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c56db7cdd143b7dd66006a3de5149813", "src_uid": "b533203f488fa4caf105f3f46dd5844d", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<malloc.h>\n#include<math.h>\nint isPrime(int n)\n{\n\t// Corner cases\n\tif (n <= 1)  return 0;\n\tif (n <= 3)  return 1;\n\n\t// This is checked so that we can skip \n\t// middle five numbers in below loop\n\tif (n % 2 == 0 || n % 3 == 0) return 0;\n\n\tfor (int i = 5; i*i <= n; i = i + 6)\n\t\tif (n%i == 0 || n % (i + 2) == 0)\n\t\t\treturn 0;\n\n\treturn 1;\n}\n\nint main()\n{\n\tint y, p;\n\tint c = 0;\n\tscanf(\"%d %d\", &p, &y);\n\tint i = y;\n\twhile (i > p)\n\t{\n\t\tif (i % 2 == 0)\n\t\t\ti--;\n\t\telse\n\t\t{\n\t\t\tif (isPrime(i))\n\t\t\t{\n\t\t\t\tprintf(\"%d\", i);\n\t\t\t\tc = 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif (sqrt(i) <= p)\n\t\t\t\ti--;\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\"%d\", i);\n\t\t\t\tc = 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tif (c == 0)\n\t\tprintf(\"-1\");\n\treturn 0;\n}\nclose", "lang_cluster": "C", "compilation_error": true, "code_uid": "db41c034411ab3b82471dbe44313f81a", "src_uid": "b533203f488fa4caf105f3f46dd5844d", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<malloc.h>\n#include<math.h>\nint isPrime(int n)\n{\n\t// Corner cases\n\tif (n <= 1)  return 0;\n\tif (n <= 3)  return 1;\n\n\t// This is checked so that we can skip \n\t// middle five numbers in below loop\n\tif (n % 2 == 0 || n % 3 == 0) return 0;\n\n\tfor (int i = 5; i*i <= n; i = i + 6)\n\t\tif (n%i == 0 || n % (i + 2) == 0)\n\t\t\treturn 0;\n\n\treturn 1;\n}\n\nint main()\n{\n\tint y, p;\n\tint c = 0;\n\tscanf(\"%d %d\", &p, &y);\n\tint i = y;\n\twhile (i > p)\n\t{\n\t\tif (i % 2 == 0)\n\t\t\ti--;\n\t\telse\n\t\t{\n\t\t\tif (isPrime(i))\n\t\t\t{\n\t\t\t\tprintf(\"%d\", i);\n\t\t\t\tc = 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif (sqrt(i) <= p)\n\t\t\t\ti--;\n\t\t\telse\n\t\t\t{\n\t\t\t\tint j = p;\n\t\t\t\tint c1 = 0;\n\t\t\t\twhile (j > 2)\n\t\t\t\t{\n\t\t\t\t\tif (i%j == 0)\n\t\t\t\t\t{\n\t\t\t\t\t\tc1 = 1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\tj--;\n\t\t\t\t}\n\t\t\t\tif (c1 = 1)\n\t\t\t\t\ti--;\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tprintf(\"%d\", i);\n\t\t\t\t\tc = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tif (c == 0)\n\t\tprintf(\"-1\")\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1032f0a365aadaa258cc311826cb29eb", "src_uid": "b533203f488fa4caf105f3f46dd5844d", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<malloc.h>\n#include<math.h>\nint isPrime(int n)\n{\n\t// Corner cases\n\tif (n <= 1)  return 0;\n\tif (n <= 3)  return 1;\n\n\t// This is checked so that we can skip \n\t// middle five numbers in below loop\n\tif (n % 2 == 0 || n % 3 == 0) return 0;\n\n\tfor (int i = 5; i*i <= n; i = i + 6)\n\t\tif (n%i == 0 || n % (i + 2) == 0)\n\t\t\treturn 0;\n\n\treturn 1;\n}\n\nint main()\n{\n\tint y, p;\n\tint c = 0;\n\tscanf(\"%d %d\", &p, &y);\n\tint i = y;\n\twhile (i > p)\n\t{\n\t\tif (i % 2 == 0)\n\t\t\ti--;\n\t\telse\n\t\t{\n\t\t\tif (isPrime(i))\n\t\t\t{\n\t\t\t\tprintf(\"%d\", i);\n\t\t\t\tc = 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif (sqrt(double(i)) <= p)\n\t\t\t\ti--;\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\"%d\", i);\n\t\t\t\tc = 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tif (c == 0)\n\t\tprintf(\"-1\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5f6ab0a0cc215d6a6a32ad6500a3fd00", "src_uid": "b533203f488fa4caf105f3f46dd5844d", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\nstruct node{\n\tint data;\n\tstruct node* next;\n};\nstruct node** hash;\nint size=100001;\nvoid init_hash()\n{\n\tint i;\n\tfor(i=0;i<size;i++)\n\t hash[i]=0;\n}\nvoid hash_it(int data)\n{\n\tint pos=data%size;\n\tstruct node* head=malloc(sizeof(struct node));\n\thead->data=data;\n\thead->next=hash[pos];\n\thash[pos]=head;\n}\nint is_present(int data)\n{\n\tint pos=data%size;\n\tstruct node* cur=hash[pos];\n\twhile(cur)\n\t{\n\t\tif(cur->data==data)\n\t\t{\n\t\t\treturn 1;\n\t\t}\n\t\tcur=cur->next;\n\t}\n\treturn 0;\n}\nint main()\n{\n\tint p,y;\n\tint i,j,k;\n\thash=malloc(size*sizeof(struct node*));\n\tinit_hash();\n\tscanf(\"%d %d\",&p,&y);\n\tint flag=0;\n\tfor(i=2;i<=p;i++)\n\t{\n\t\tif(!is_present(i))\n\t\t{\n\t\t\tfor(j=i;j<=end;j+=i)\n\t\t\t{\n\t\t\t\tif(j>p)\n\t\t\t\t hash_it(j);\n\t\t\t}\n\t\t}\n\t}\n\tfor(i=y;i>p;i--)\n\t{\n\t\tif(!is_present(i))\n\t\t{\n\t\t\tprintf(\"%d\\n\",i);\n\t\t\tflag=1;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(!flag)\n\t printf(\"-1\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1e9a966e49e42779675e00e3dff1cd15", "src_uid": "b533203f488fa4caf105f3f46dd5844d", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\nint main()\n{\n\tint t,n,l,k,d[200],a[200],flag,i,tmr,temp;\n\tscanf(\"%d\",&t);\n\twhile(t--)\n\t{\n\t\tscanf(\"%d %d %d\",&n,&k,&l);\n\t\tfor(i=0;i<n;i++)\n\t\t{\n\t\t\tscanf(\"%d\",&d[i]);\n\t\t}\n\t\tflag=0,tmr=1000;\n\t\tfor(i=0;i<n;i++)\n\t\t{\n\t\t\tif(d[i]+k<=l)\n\t\t\t{\n\t\t\t\ta[i]=d[i];\n\t\t\t\ttmr=1000;\n\t\t\t}\n\t\t\telse if(d[i]>l)\n\t\t\t{\n\t\t\t\tflag=1;\n\t\t\t\t// printf(\"%d-%d\\n\",d[i],i);\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\telse if(d[i]+k>l)\n\t\t\t{\n\t\t\t\tif(i==0 || tmr==1000)\n\t\t\t\t{\n\t\t\t\t\ta[i]=l;\n\t\t\t\t\ttmr=l-d[i];\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tif(tmr>0)\n\t\t\t\t\t{\n\t\t\t\t\t\ttemp=a[i-1]-d[i-1];\n\t\t\t\t\t\ta[i]=a[i-1]-1;\n\t\t\t\t\t\ttmr--;\n\t\t\t\t\t\twhile(a[i]>l)\n\t\t\t\t\t\t{\t\n\t\t\t\t\t\t\ta[i]--;\n\t\t\t\t\t\t\ttmr--;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tif(a[i-1]+1>l)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tflag=1;\n\t\t\t\t\t\t\t// printf(\"hi\\n\");\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\ta[i]=a[i-1]+1;\n\t\t\t\t\t\t\ttmr=tmr-1;\n\t\t\t\t\t\t}\n\t\t\t\t\t\t// if(tmr==-k)\n\t\t\t\t\t\t// {\n\t\t\t\t\t\t// \ttmr=k;\n\t\t\t\t\t\t// }\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(flag==1)\n\t\t{\n\t\t\tprintf(\"No\\n\");\n\t\t}\n\t\telse\n\t\t{\n\t\t\tprintf(\"Yes\\n\");\n\t\t}\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6930fb202edc4e008b9a2144a7945257", "src_uid": "4941b0a365f86b2e2cf686cdf5d532f8", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\nint main()\n{\n\tint t,n,l,k,d[200],a[200],flag,i,tmr,temp;\n\tscanf(\"%d\",&t);\n\twhile(t--)\n\t{\n\t\tscanf(\"%d %d %d\",&n,&k,&l);\n\t\tfor(i=0;i<n;i++)\n\t\t{\n\t\t\tscanf(\"%d\",&d[i]);\n\t\t}\n\t\tflag=0,tmr=1000;\n\t\tfor(i=0;i<n;i++)\n\t\t{\n\t\t\tif(d[i]+k<=l)\n\t\t\t{\n\t\t\t\ta[i]=d[i];\n\t\t\t\ttmr=1000;\n\t\t\t}\n\t\t\telse if(d[i]>l)\n\t\t\t{\n\t\t\t\tflag=1;\n\t\t\t\t// printf(\"%d-%d\\n\",d[i],i);\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\telse if(d[i]+k>l)\n\t\t\t{\n\t\t\t\tif(i==0 || tmr==1000)\n\t\t\t\t{\n\t\t\t\t\ta[i]=l;\n\t\t\t\t\ttmr=l-d[i];\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tif(tmr>0)\n\t\t\t\t\t{\n\t\t\t\t\t\ttemp=a[i-1]-d[i-1];\n\t\t\t\t\t\ta[i]=a[i-1]-1;\n\t\t\t\t\t\ttmr--;\n\t\t\t\t\t\twhile(a[i]>l)\n\t\t\t\t\t\t{\t\n\t\t\t\t\t\t\ta[i]--;\n\t\t\t\t\t\t\ttmr--;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tif(a[i-1]+1>l)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tflag=1;\n\t\t\t\t\t\t\t// printf(\"hi\\n\");\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\ta[i]=a[i-1]+1;\n\t\t\t\t\t\t\ttmr=tmr-1;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tif(tmr==-k)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\ttmr=k;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(flag==1)\n\t\t{\n\t\t\tprintf(\"No\\n\");\n\t\t}\n\t\telse\n\t\t{\n\t\t\tprintf(\"Yes\\n\");\n\t\t}\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "bfdf08f99394893d6d31dcd2c99947d4", "src_uid": "4941b0a365f86b2e2cf686cdf5d532f8", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\nint main()\n{\n\tint t,n,l,k,d[200],a[200],flag,i,tmr,temp;\n\tscanf(\"%d\",&t);\n\twhile(t--)\n\t{\n\t\tscanf(\"%d %d %d\",&n,&k,&l);\n\t\tfor(i=0;i<n;i++)\n\t\t{\n\t\t\tscanf(\"%d\",&d[i]);\n\t\t}\n\t\tflag=0,tmr=1000;\n\t\tfor(i=0;i<n;i++)\n\t\t{\n\t\t\tif(d[i]+k<=l)\n\t\t\t{\n\t\t\t\ta[i]=d[i];\n\t\t\t\ttmr=1000;\n\t\t\t}\n\t\t\telse if(d[i]>l)\n\t\t\t{\n\t\t\t\tflag=1;\n\t\t\t\t// printf(\"%d-%d\\n\",d[i],i);\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\telse if(d[i]+k>l)\n\t\t\t{\n\t\t\t\tif(i==0 || tmr==1000)\n\t\t\t\t{\n\t\t\t\t\ta[i]=l;\n\t\t\t\t\ttmr=l-d[i];\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tif(tmr>0)\n\t\t\t\t\t{\n\t\t\t\t\t\ttemp=a[i-1]-d[i-1];\n\t\t\t\t\t\ta[i]=d[i]+temp-1;\n\t\t\t\t\t\tif(a[i]<=l)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\ttmr=tmr-1;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\ttemp=a[i]-l;\n\t\t\t\t\t\t\ttmr=tmr-temp-1;\n\t\t\t\t\t\t\ta[i]=l;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tif(a[i-1]+1>l)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tflag=1;\n\t\t\t\t\t\t\t// printf(\"hi\\n\");\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\ta[i]=a[i-1]+1;\n\t\t\t\t\t\t\ttmr=tmr-1;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tif(tmr==-k)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\ttmr=k;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(flag==1)\n\t\t{\n\t\t\tprintf(\"No\\n\");\n\t\t}\n\t\telse\n\t\t{\n\t\t\tprintf(\"Yes\\n\");\n\t\t}\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b29633d4953ee4fc9a505ebda4b836b7", "src_uid": "4941b0a365f86b2e2cf686cdf5d532f8", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\nint main()\n{\n\tint t,n,l,k,d[200],a[200],flag,i,tmr,temp;\n\tscanf(\"%d\",&t);\n\twhile(t--)\n\t{\n\t\tscanf(\"%d %d %d\",&n,&k,&l);\n\t\tfor(i=0;i<n;i++)\n\t\t{\n\t\t\tscanf(\"%d\",&d[i]);\n\t\t}\n\t\tflag=0,tmr=1000;\n\t\tfor(i=0;i<n;i++)\n\t\t{\n\t\t\tif(d[i]+k<=l)\n\t\t\t{\n\t\t\t\ta[i]=d[i];\n\t\t\t\ttmr=1000;\n\t\t\t}\n\t\t\telse if(d[i]>l)\n\t\t\t{\n\t\t\t\tflag=1;\n\t\t\t\t// printf(\"%d-%d\\n\",d[i],i);\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\telse if(d[i]+k>l)\n\t\t\t{\n\t\t\t\tif(i==0 || tmr==1000)\n\t\t\t\t{\n\t\t\t\t\ta[i]=l;\n\t\t\t\t\ttmr=l-d[i];\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tif(tmr>0)\n\t\t\t\t\t{\n\t\t\t\t\t\ttemp=a[i-1]-d[i-1];\n\t\t\t\t\t\ta[i]=d[i]+tmr-1;\n\t\t\t\t\t\ttmr--;\n\t\t\t\t\t\twhile(a[i]>l)\n\t\t\t\t\t\t{\t\n\t\t\t\t\t\t\ta[i]--;\n\t\t\t\t\t\t\ttmr--;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\ttmr=tmr-1;\n\t\t\t\t\t\tif(d[i]-tmr>l)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tflag=1;\n\t\t\t\t\t\t\t// printf(\"%d\\n\",i);\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\ta[i]=d[i]-tmr;\n\t\t\t\t\t\t}\n\t\t\t\t\t\t// if(tmr==-k)\n\t\t\t\t\t\t// {\n\t\t\t\t\t\t// \ttmr=k;\n\t\t\t\t\t\t// }\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(flag==1)\n\t\t{\n\t\t\tprintf(\"No\\n\");\n\t\t}\n\t\telse\n\t\t{\n\t\t\tprintf(\"Yes\\n\");\n\t\t}\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ed7eddc9b3010a9bc5ac3aef72cae505", "src_uid": "4941b0a365f86b2e2cf686cdf5d532f8", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\nint main()\n{\n\tlong long int t,n,l,k,d[200],a[200],flag,i,tmr,temp;\n\tscanf(\"%lld\",&t);\n\twhile(t--)\n\t{\n\t\tscanf(\"%lld %lld %lld\",&n,&k,&l);\n\t\tfor(i=0;i<n;i++)\n\t\t{\n\t\t\tscanf(\"%lld\",&d[i]);\n\t\t}\n\t\tflag=0,tmr=1000;\n\t\tfor(i=0;i<n;i++)\n\t\t{\n\t\t\tif(d[i]+k<=l)\n\t\t\t{\n\t\t\t\ta[i]=d[i];\n\t\t\t\ttmr=1000;\n\t\t\t}\n\t\t\telse if(d[i]>l)\n\t\t\t{\n\t\t\t\tflag=1;\n\t\t\t\t// printf(\"%d-%d\\n\",d[i],i);\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\telse if(d[i]+k>l)\n\t\t\t{\n\t\t\t\tif(i==0 || tmr==1000)\n\t\t\t\t{\n\t\t\t\t\ta[i]=l;\n\t\t\t\t\ttmr=l-d[i];\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tif(tmr>0)\n\t\t\t\t\t{\n\t\t\t\t\t\ttemp=a[i-1]-d[i-1];\n\t\t\t\t\t\ta[i]=d[i]+tmr-1;\n\t\t\t\t\t\ttmr--;\n\t\t\t\t\t\tif(a[i]>l)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\ttmr=tmr-(a[i]-l);\n\t\t\t\t\t\t\ta[i]=l;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\ttmr=tmr-1;\n\t\t\t\t\t\tif(d[i]-tmr>l)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tflag=1;\n\t\t\t\t\t\t\t// printf(\"%d\\n\",i);\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\ta[i]=d[i]-tmr;\n\t\t\t\t\t\t}\n\t\t\t\t\t\t// if(tmr==-k)\n\t\t\t\t\t\t// {\n\t\t\t\t\t\t// \ttmr=k;\n\t\t\t\t\t\t// }\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(flag==1)\n\t\t{\n\t\t\tprintf(\"No\\n\");\n\t\t}\n\t\telse\n\t\t{\n\t\t\tprintf(\"Yes\\n\");\n\t\t}\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8c8e6bc1cb795e0156f0c1eccbce97d8", "src_uid": "4941b0a365f86b2e2cf686cdf5d532f8", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include \"stdio.h\"\n#include \"math.h\"\n\nint main()\n{\n\tint n,m,a,b;\n\tscanf(\"%d %d %d %d\",&n,&m,&a,&b);\n\t\n\tif((lround(ceil((double)a/m)) == lround(ceil((double)b/m))) || m==1 || (a%m==1 && (b==n || b%m==0 ))){\n\t\tprintf(\"1\\n\");\n\t}else if(((b-a+1)%m) == 0 && (m-((a%m)?(a%m):m)+b%m+1) == m)\n\t{\n\t\tprintf(\"2\\n\");\n\t}else{\n\t\tint num = 1;\n\t\tif(a%m != 1)\n\t\t\tnum++;\n\n\t\tif(b%m != 0 && b!=n)\n\t\t\tnum++;\n\n\t\tif(b-a <= (2*m-((a%m)?(a%m):m)) && num == 3)\n\t\t\tnum--;\n\t\tprintf(\"%d\\n\",num);\n\t}\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d9268b1e740f5a8945834d6ba4d9092d", "src_uid": "f256235c0b2815aae85a6f9435c69dac", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n   int n,m,a,b,x1,y1,x2,y2;\n   scanf(\"%d%d%d%d\",&n,&m,&a,&b);\n   a--;\n   b--;\n   x1=a/m;\n   y1=a%m;\n   x2=b/m;\n   y2=b%m;\n   if (x1==x2)\n      puts(\"1\");\n   else if (x1==x2-1)\n      puts(!y1&&(y2==m-1||b==n-1)?\"1\":\"2\");\n   else\n      printf(\"%d\\n\",3-!y1-(y2==m-1||b==n-1||y1==y2+1));\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9ccedbbb7a3afff873add9fb3e5f8a92", "src_uid": "f256235c0b2815aae85a6f9435c69dac", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n     int n, m, a, b, p, q, r;\n\n     scanf(\"%d %d %d %d\", &n, &m, &a, &b);\n\n     p = m - (a - 1) % m;\n     q = m;\n     r = b % m;\n\n     if (p >= b - a + 1) {\n\t  puts(\"1\");\n     } else if (b - a - p + 1 <= m) {\n\t  if (p == m && (b - a - p + 1 == m || b == n)) {\n\t       puts(\"1\");\n\t  } else {\n\t       puts(\"2\");\n\t  }\n     } else {\n\t  int c = 3;\n\n\t  if (p == q) c--;\n\t  if (r == 0 || b == n || p + r == m) c--;\n\n\t  printf(\"%d\\n\", c);\n     }\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "df320564d1b12e727d34c12321a929d9", "src_uid": "f256235c0b2815aae85a6f9435c69dac", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n   int n,m,a,b,x1,y1,x2,y2;\n   scanf(\"%d%d%d%d\",&n,&m,&a,&b);\n   a--;\n   b--;\n   x1=a/m;\n   y1=a%m;\n   x2=b/m;\n   y2=b%m;\n   if (x1==x2)\n      puts(\"1\");\n   else if (x1==x2-1)\n      puts(!y1&&(y2==m-1||b==n-1)?\"1\":\"2\");\n   else\n      printf(\"%d\\n\",3-!y1-(y2==m-1||b==n-1||y1==y2+1));\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fdd0882378a12c14dd7b9478c6e6fd07", "src_uid": "f256235c0b2815aae85a6f9435c69dac", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nmain()\n{\n      int n,m,a,b,r1,r2,ans;\n      \n      scanf(\"%d%d%d%d\",&n,&m,&a,&b);\n      \n      if (a==b)\n         ans=1;\n      else if (m==1)\n         ans=1;\n      else\n      {\n          r1=a%m;\n          r2=b%m;          \n          if (b==n)\n          {\n             if (r2==0)\n                r2=m;\n             if (r1==1||r2-(b-a)>0)\n                ans=1;\n             else \n                ans=2;\n          }  \n          \n          else if (r1==1&&r2==0)\n             ans=1;\n          else if (r1==1)\n          {\n               if (r1+b-a<=m)\n                  ans=1;\n               else\n                  ans=2;\n          }\n          else if (r2==0)\n          {\n               if (m-(b-a)>=0)\n                  ans=1;\n               else\n                  ans=2;\n          }\n          else\n          {\n            if (r1==0)\n               r1=m;  \n            if (r1+(b-a)<=m)\n                ans=1;\n            else if (m-r1+r2==b-a)\n                ans=2;\n            else\n            {\n               if (r2+1==r1)\n                 ans=2;\n               else\n                ans=3;\n            }\n          }\n      }\n      \n      printf(\"%d\\n\",ans);      \n\n      return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c1e4d7eb782ba4ec1b502f920a3ee8e4", "src_uid": "f256235c0b2815aae85a6f9435c69dac", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#include<string.h>\nint minprime[5000005], l, r;\nlong long t, sum = 0;\nlong long f[5000005];\nint main()\n{\n\tscanf(\"%I64d %d %d\", &t, &l, &r);\n\tfor (int i = 2; i <= r; i++)\n\t\tminprime[i] = i;\n\tfor (int i = 2; i*i <= r; i++)\n\t{\n\t\tfor (int j = i*i; j <= r; j += i)\n\t\t{\n\t\t\tif (minprime[j] > i)\n\t\t\t\tminprime[j] = i;\n\t\t}\n\t}\n\tmemset(f, 0, sizeof(f));\n\tfor (int i = 2; i <= r; i++)\n\t{\n\t\tif (minprime[i] == i)\n\t\t{\n\t\t\tf[i] = ((long long)(i*i - i) / 2) % (1000000000 + 7);\n\t\t}\n\t\telse\n\t\tfor (int j = i; j != 1; j /= minprime[j])\n\t\t{\n\t\t\tf[i] += (f[minprime[j]])*(j/minprime[j]);\n\t\t\tf[i] %= (1000000000 + 7);\n\t\t}\n\t}\n\tfor (int i = l; i <= r; i++)\n\t{\n\t\tsum += pow(t, i - l)*f[i];\n\t\tsum %= (1000000000 + 7);\n\t}\n\tprintf(\"%I64d\\n\", sum);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a5509e915f1aa9f7669af9fed4aa331b", "src_uid": "c9d45dac4a22f8f452d98d05eca2e79b", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <ctype.h>\n#include <math.h>\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#define MOD 1000000007\n#define ll long long\n#define BS_NOT_FOUND 0\n#define BS_FOUND 1\n\nll f[5000006]={0};\nll prime[5000006]={0};\n\nlong long expo(long long x, long long n){\n    long long res = 1;\n\n    while (n){\n        if (n & 1LL) res = (res * x) % MOD;\n        x = (x * x) % MOD;\n        n >>= 1LL;\n    }\n\n    return (res % MOD);\n}\n\nint main(){\n    //calculate f[i]\n    ll i,j;\n    for(i=2;i<=5000000;i++){\n        if(prime[i]>0) continue;\n        prime[i]=i;\n        for(j=2*i;j<=5000000;j+=i){\n            if(prime[j]==0) prime[j]=i;\n        }\n    }\n    f[1]=0;\n    for(i=2;i<=5000000;i++) f[i]=(f[i/prime[i]]+i*(prime[i]-1)/2%MOD)%MOD;\n\n    /*\n    f[2]=1;\n    f[3]=3;\n    f[4]=3;\n    f[5]=10;\n    f[7]=21;\n    f[11]=55;\n    f[13]=66;\n    f[17]=17*16/2;\n    f[19]=19*9;\n    f[23]=253;\n    f[29]=29*14;\n    ll i,index,j,num;\n    for(i=6;i<=5000000;i++){\n        num=i;\n        index=2;\n        if(i%2==0) {f[i]=i/2+f[i/2];continue;}\n        if(i%3==0) {f[i]=i+f[i/3];continue;}\n        if(i%5==0) {f[i]=i*2+f[i/5];continue;}\n        if(i%7==0) {f[i]=i*3+f[i/7];continue;}\n        if(i%11==0) {f[i]=i*5+f[i/11];continue;}\n        if(i%13==0) {f[i]=i*6+f[i/13];continue;}\n        if(i%17==0) {f[i]=i*8+f[i/17];continue;}\n        if(i%19==0) {f[i]=i*9+f[i/19];continue;}\n        if(i%23==0) {f[i]=i*11+f[i/23];continue;}\n        if(i%29==0) {f[i]=i*14+f[i/29];continue;}\n        while(num%index!=0 && index*index<=num) index++;\n        if(index*index>num){\n            f[i]=(i*(i-1)/2);\n            continue;\n        }\n        f[i]=i/index*f[index]+f[i/index];\n    }\n    */\n    //for(i=2;i<=5000000;i++) printf(\"%lld,\",f[i]);\n\n    ll t,l,r;\n    scanf(\"%lld %lld %lld\",&t,&l,&r);\n    ll ans=0;\n    for(i=l;i<=r;i++){\n        ll x=expo(t,i-l);\n        ll y=(x*(f[i]))%MOD;\n        ans=(ans+y)%MOD;\n    }\n    printf(\"%lld\\n\",ans);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0aa96f7cc8b125c115d7febc443adadd", "src_uid": "c9d45dac4a22f8f452d98d05eca2e79b", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<stdbool.h>\n\nlong long int mod=1000000007;\n\nlong long int add(long long int a, long long int b)\n{\n    long long int temp=a+b;\n    return (temp%mod);\n}\n\nlong long int mult(long long int a, long long int b)\n{\n    long long int temp=a*b;\n    return (temp%mod);\n}\n\nint main()\n{\n    long long int t,l,r;\n    scanf(\"%lld %lld %lld\",&t, &l, &r);\n    long long int f[5000005],i,j;\n    bool key;\n    for(i=1;i<=r;i++)\n    {\n        if(i==1)\n            f[i]=0;\n        else\n        {\n            key=true;\n            for(j=2;j<i;j++)\n            {\n                if(i%j==0)\n                {\n                    f[i]=add((i*(j-1))/2,f[i/j]);\n                    key=false;\n                    break;\n                }\n            }\n            if(key)\n                f[i]=add(0,(i*(i-1))/2);\n        }\n    }\n    long long int ans=0,power=1;\n    for(i=l;i<=r;i++)\n    {\n        ans=add(ans,mult(power,f[i]));\n        power=mult(power,t);\n    }\n    printf(\"%lld\\n\",ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "82daefe5479ec8b1985ba6aacbc5e3c1", "src_uid": "c9d45dac4a22f8f452d98d05eca2e79b", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\ntypedef long long int lli;\nlli m=1e9+7;\nlli d[5000001];\nint main()\n{\n    for(int i=1;i<=5000000;i++) d[i]=1e18;\n    d[1]=0;\n    for(lli i=1;i<=5000000;i++)\n    {\n        for(lli j=2*i;j<=5000000;j+=i)\n        {\n            lli g=j/i;\n            lli u=d[i]+(j*(g-1))/2;\n            if(d[j]>u) d[j]=u;\n        }\n    }\n    lli t,l,r;\n    scanf(\"%lld %lld %lld\",&t,&l,&r);\n    lli a=0,k=1;\n    for(int i=r;i>=l;i--){\n        a=(a*t)%m;\n        a=(a+d[i])%m;\n    }\n    printf(\"%lld\",a);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c338582cf9ce28b3f5a2a97cf1fd899f", "src_uid": "c9d45dac4a22f8f452d98d05eca2e79b", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <ctype.h>\n#include <math.h>\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#define MOD 1000000007\n#define ll long long\n#define BS_NOT_FOUND 0\n#define BS_FOUND 1\n\nll f[5000006];\n\nlong long expo(long long x, long long n){\n    long long res = 1;\n\n    while (n){\n        if (n & 1LL) res = (res * x) % MOD;\n        x = (x * x) % MOD;\n        n >>= 1LL;\n    }\n\n    return (res % MOD);\n}\n\nint main(){\n    //calculate f[i]\n    f[2]=1;\n    f[3]=3;\n    f[4]=3;\n    f[5]=10;\n    ll i,index,j,num;\n    for(i=6;i<=5000000;i++){\n        num=i;\n        index=2;\n        if(i%2==0) {f[i]=n/2+f[n/2];continue;}\n        if(i%3==0) {f[i]=n/3+f[n/3];continue;}\n        if(i%5==0) {f[i]=n/5+f[n/5];continue;}\n        while(num%index!=0 && index*index<=num) index++;\n        if(index*index>num){\n            f[i]=(i*(i-1)/2);\n            continue;\n        }\n        f[i]=i/index*f[index]+f[i/index];\n    }\n\n    ll t,l,r;\n    scanf(\"%lld %lld %lld\",&t,&l,&r);\n    ll ans=0;\n    for(i=l;i<=r;i++){\n        ll x=expo(t,i-l);\n        ll y=(x*(f[i]%MOD))%MOD;\n        ans=(ans+y)%MOD;\n    }\n    printf(\"%lld\\n\",ans);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "fd94976c73fed4de8bbcc46a1db5e968", "src_uid": "c9d45dac4a22f8f452d98d05eca2e79b", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#define min(a,b) ((a)<(b)?(a):(b))\n\ntypedef long long ll;\n\nchar str[200001];\n\nint main()\n{\n\tint i,n,m,res;\n\tll val, pw;\n\tscanf(\"%s%d\",str,&m);\n\tn=strlen(str);\n\tres=m;\n\tpw=1;\n\tval=0;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tpw=pw*10%m;\n\t\tval=(val*10+str[i]-'0')%m;\n\t}\n\tres=min(res, val);\n\tfor(int i=0;i<n;i++)\n\t{\n\t\tval=(val*10-(str[i]-'0')*pw+str[i]-'0')%m;\n\t\tres=min(res, val);\n\t}\n\tprintf(\"%d\\n\",(int)res);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "123aedf1c64276f9ed79b31579f0f495", "src_uid": "d13c7b5b5fc5c433cc8f374ddb16ef79", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define MAX 200005\nchar s[MAX];\nint m, len;\nlong long base, pref, suf[MAX], res, tmp;\n\nint main(){\n    //freopen(\"in.txt\", \"r\", stdin);\n    scanf(\"%s %d\", s, &m);\n    len = strlen(s);\n    for (int i = len - 1; i >= 0; --i)\n        suf[i] = (suf[i + 1] * 10 + s[i] - '0') % m;\n\n    res = 1e18;\n    base = 1;\n    for (int i = 0; i < len; ++i){\n        if (s[i] != '0'){\n            tmp = (suf[i] * base + pref) % m;\n            if (res > tmp)\n                res = tmp;\n        }\n        base = (base * 10) % m;\n        pref = (pref * 10 + s[i] - '0') % m;\n    }\n    printf(\"%lld\", res);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "557c63c6f43cd3f952f6a46345158405", "src_uid": "d13c7b5b5fc5c433cc8f374ddb16ef79", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n\n#define pb push_back\n#define mp make_pair\n#define F first\n#define S second\n\n#define fo(i, n) for(int i = 1; i <= n; ++i)\n#define rep(i, a, b) for(int (i) = (a); (i) < (b); ++(i))\n\n#define ll long long\nint N = 200200;\nchar s[400400];\n\nll res = 2e9;\nll a[400400];\n\nll ost;\n\nll min(ll a, ll b)\n{\n\tif(a > b)\n\t\treturn b;\n\treturn a;\n}\n\nint main()\n{\n\tscanf(\"%s\", s);\n\tint n = strlen(s);\n\tint m;\n\tscanf(\"%d\", &m);\n\tll st = 1;\n\tfor(int i = 1; i <= n; ++i)\n\t\tst = st * 10 % m;\n\tfor(int i = 1; i <= n + n; ++i)\n\t    if(i <= n)\n\t\t\ta[i] = s[(i - 1)] - '0';\n\t\telse\n\t\t\ta[i] = s[(i - 1 - n)] - '0';\n\tfor(int i = 1; i <= n; ++i)\n\t\tost = (ost * 10 + a[i]) % m;\n\tres = min(res, ost);\n\tfor(int i = 2; i <= n; ++i)\n\t{\n\t\tost = (ost * 10 + a[i + n - 1]) % m;\n\t\tost = (ost + m - st * a[i - 1] % m) % m;\n\t\tres = min(res, ost);\n\t}\n\tprintf(\"%lld\", res);\n\treturn 0;\t\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "32f855607396f9f6cd2b5f16c7091e6b", "src_uid": "d13c7b5b5fc5c433cc8f374ddb16ef79", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <math.h>\n#define M 500005\nchar s[M];\nint n,m,now,p=1,ans;\nint read(){\n\tchar c=getchar();int ans=0;\n\twhile (c<'0'||c>'9') c=getchar();\n\twhile (c>='0'&&c<='9') ans=ans*10+c-'0',c=getchar();\n\treturn ans;\n}\nint min(int x,int y){return x<y?x:y;}\nint main(){\n\tscanf(\"%s%d\",s+1,&m);n=strlen(s+1);\n\tfor (register int i=1;i<=n;i++) p=p*10%m,now=(now*10+s[i]-'0')%m;ans=now;\n\tfor (register int i=1;i<n;i++) ans=min(ans,now=(now*10%m+s[i]-'0'+m-p*(s[i]-'0')%m)%m);\n\tprintf(\"%d\",ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c214bbfa66bf5fbc623390455a97f121", "src_uid": "d13c7b5b5fc5c433cc8f374ddb16ef79", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "#include <cstdio>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n//\u8eab\u4efd\u8bc1 && \u51c6\u8003\u8bc1 && \u80f8\u5361\nconst int N = 200003;\nint n, a[N]; char s[N];\nint M, t;\ninline int ksm (int p, int x) {\nint s = 1;\nwhile (x) {\nif (x & 1) s = 1ll * s * p % M;\np = 1ll * p * p % M;\nx >>= 1;\n}\nreturn s;\n}\nint main () {\nscanf (\"%s %d\", s + 1, &M);\nn = strlen (s + 1);\nint i; for (i = 1; i <= n; ++i) a[i] = s[i] ^ 48, t = ((t << 3) + (t << 1) + a[i]) % M;\nint mn = t, k = ksm (10, n + 1);\nfor (i = 1; i <= n; ++i) {\nt = ((t << 3) + (t << 1)) % M;\nt = (t - 1ll * k * a[i] % M + M) % M;\nt = (t + a[i]) % M;\nif (a[i + 1]) mn = min (mn, t);\n}\nprintf (\"%d\\n\", mn);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4cdc62ff611320b569ec29f373249cc8", "src_uid": "d13c7b5b5fc5c433cc8f374ddb16ef79", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\nint main() {\n\tint x1, x2, x, a, b, r, tmp, flipped;\n\n\tscanf(\"%d%d%d%d\", &x1, &x2, &a, &b);\n\tx = x2 - x1;\n\tif (x >= a && x <= b) {\n\t\tprintf(\"FIRST\\n\");\n\t\tprintf(\"%d\\n\", x2);\n\t\treturn 0;\n\t}\n\tflipped = 0;\n\tif (x < 0) {\n\t\tx = -x;\n\t\tflipped = 1;\n\t\ttmp = a, a = -b, b = -tmp;\n\t}\n\tif (a <= 0) {\n\t\tprintf(\"DRAW\\n\");\n\t\treturn 0;\n\t}\n\tr = x % (a + b);\n\tif (r == 0) {\n\t\tprintf(\"SECOND\\n\");\n\t\treturn 0;\n\t}\n\tif (r < a || r > b) {\n\t\tprintf(\"DRAW\\n\");\n\t\treturn 0;\n\t}\n\tprintf(\"FIRST\\n\");\n\tprintf(\"%d\\n\", x1 + (flipped ? -r : r));\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a3f67b57a9bd627842f642abf69eb8b0", "src_uid": "4ea8cc3305a0ee2c1e580b43e5bc46c6", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint main(){\n  int i,j,k,l,m,n;\n  int x1, x2, a, b, fg, fgg;\n  int mod;\n  int stone;\n\n  while(scanf(\"%d%d%d%d\",&x1,&x2,&a,&b)==4){\n    stone = x2 - x1;\n    fg = 0;\n    if(stone < 0) stone *= -1, k = a, a = b, b = k, a *= -1, b *= -1, fg = 1;\n    if(b <= 0){ puts(\"DRAW\"); continue; }\n\n    fgg = 0;\n    if(a <= 0) fgg = 1, a = 1;\n    mod = stone % (a+b);\n    if(mod == 0){\n      if(fgg) puts(\"DRAW\"); else puts(\"SECOND\");\n      continue;\n    }\n    if(mod < a || mod > b){\n      puts(\"DRAW\");\n      continue;\n    }\n\n    if(stone > b && fgg){\n      puts(\"DRAW\");\n      continue;\n    }\n\n    stone -= mod;\n    puts(\"FIRST\");\n    if(fg==0) printf(\"%d\\n\",x2-stone);\n    else      printf(\"%d\\n\",x2+stone);\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "194d47b17935d9e2f9c3b7050917b742", "src_uid": "4ea8cc3305a0ee2c1e580b43e5bc46c6", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint main(){\n  int i,j,k,l,m,n;\n  int x1, x2, a, b, fg, fgg;\n  int mod;\n  int stone;\n\n  while(scanf(\"%d%d%d%d\",&x1,&x2,&a,&b)==4){\n    stone = x2 - x1;\n    fg = 0;\n    if(stone < 0) stone *= -1, k = a, a = b, b = k, a *= -1, b *= -1, fg = 1;\n    if(b <= 0){ puts(\"DRAW\"); continue; }\n\n    fgg = 0;\n    if(a <= 0) fgg = 1, a = 1;\n    mod = stone % (a+b);\n    if(mod == 0){\n      if(fgg) puts(\"DRAW\"); else puts(\"SECOND\");\n      continue;\n    }\n    if(mod < a){\n      puts(\"DRAW\");\n      continue;\n    }\n\n    if(stone > b && fgg){\n      puts(\"DRAW\");\n      continue;\n    }\n\n    stone -= mod;\n    puts(\"FIRST\");\n    if(fg==0) printf(\"%d\\n\",x2-stone);\n    else      printf(\"%d\\n\",x2+stone);\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4eaf4ca4ec129a0613c2b7d4d906cf6f", "src_uid": "4ea8cc3305a0ee2c1e580b43e5bc46c6", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint main(){\n  int i,j,k,l,m,n;\n  int x1, x2, a, b, fg, fgg;\n  int mod;\n  int stone;\n\n  while(scanf(\"%d%d%d%d\",&x1,&x2,&a,&b)==4){\n    stone = x2 - x1;\n    fg = 0;\n    if(stone < 0) stone *= -1, k = a, a = b, b = k, a *= -1, b *= -1, fg = 1;\n    if(b <= 0){ puts(\"DRAW\"); continue; }\n\n    fgg = 0;\n    if(a <= 0) fgg = 1, a = 1;\n    mod = stone % (a+b);\n    if(mod == 0){\n      if(fgg) puts(\"DRAW\"); else puts(\"SECOND\");\n      continue;\n    }\n    if(mod < a){\n      puts(\"DRAW\");\n      continue;\n    }\n\n    stone -= mod;\n    puts(\"FIRST\");\n    if(fg==0) printf(\"%d\\n\",x2-stone);\n    else      printf(\"%d\\n\",x2+stone);\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "55e673981f6769deb19704b7711d7733", "src_uid": "4ea8cc3305a0ee2c1e580b43e5bc46c6", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint clu(int x){\n\tint a;\n\ta=x%3;\n\tif(a==0){\n\t\treturn 6;\n\t}\n\tif(a==1){\n\t\treturn 0;\n\t}\n\tif(a==2){\n\t\treturn 3;\n\t}\n}\nint main(void){\n\tchar a[12][12];\n\tint x,y,i,j,f=0,p,q;\n\tfor(i=0;i<9;i++){\n\t\tscanf(\"%s %s %s\",&a[i][0],&a[i][3],&a[i][6]);\n\t}\n\tscanf(\"%d %d\",&x,&y);\n\tx=clu(x);\n\ty=clu(y);\n\tfor(i=x;i<=x+2;i++){\n\t\tfor(j=y;j<=y+2;j++){\n\t\t\tif(a[i][j]=='.'){\n\t\t\t\ta[i][j]='!';\n\t\t\t\tf=1;\n\t\t\t}\n\t\t}\n\t}\n\tif(f==1){\n\t    for(i=0;i<9;i++){\n\t\t\tfor(j=0;j<=9;j++){\n\t\t\t\tprintf(\"%c\",a[i][j]);\n\t\t\t\tif((j+1)%3==0 && j!=8){\n\t\t    \t    printf(\" \");\n\t\t\t    }\n\t\t\t}\n\t\t\tif((i+1)%3==0 && i!=8){\n\t\t    \tprintf(\"\\n\");\n\t\t\t}\n\t\t\tprintf(\"\\n\");\n\t    }\n\t}\n\telse{\n\t\tfor(i=0;i<9;i++){\n\t\t\tfor(j=0;j<=9;j++){\n\t\t\t    if(a[i][j]=='.'){\n\t\t\t    \ta[i][j]='!';\n\t\t\t\t}\n\t\t\t\tprintf(\"%c\",a[i][j]);\n\t\t\t\tif((j+1)%3==0 && j!=8){\n\t\t    \t    printf(\" \");\n\t\t\t    }\n\t\t\t}\n\t\t\tif((i+1)%3==0 && i!=8){\n\t\t    \tprintf(\"\\n\");\n\t\t\t}\n\t\t\tprintf(\"\\n\");\n\t    }\n\t}\n\treturn 0;\n} ", "lang_cluster": "C", "compilation_error": false, "code_uid": "66d8e2fb2b21d525b2e5438a2f673097", "src_uid": "8f0fad22f629332868c39969492264d3", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nchar ttt[9][9];\nvoid check(int b,int a)\n{\n    int i,j;\n    int c,d;\n    int flag=0;\n    if(b%3 == 1 && a%3==1)\n    {\n        c=0;\n        d=0;\n    }\n    if(b%3 == 1 && a%3==2)\n    {\n        c=3;\n        d=0;\n    }\n    if(b%3 == 1 && a%3==0)\n    {\n        c=6;\n        d=0;\n    }\n    if(b%3 == 2 && a%3==1)\n    {\n        c=0;\n        d=3;\n    }\n    if(b%3 == 2 && a%3==2)\n    {\n        c=3;\n        d=3;\n    }\n    if(b%3 == 2 && a%3==0)\n    {\n        c=6;\n        d=3;\n    }\n    if(b%3 == 0 && a%3==1)\n    {\n        c=0;\n        d=6;\n    }\n    if(b%3 == 0 && a%3==2)\n    {\n        c=3;\n        d=6;\n    }\n    if(b%3 == 0 && a%3==0)\n    {\n        c=6;\n        d=6;\n    }\n\n    for(i=c;i<c+3;i++)\n    {\n        for(j=d;j<d+3;j++)\n        {\n            if(a%3==i && b%3==j)\n            if(ttt[i][j]=='.')\n            {\n                flag=1;\n                ttt[i][j]='!';\n            }\n        }\n    }\n    if(flag==0)\n    {\n        for(i=0;i<9;i++)\n        {\n            for(j=0;j<9;j++)\n            {\n                if(ttt[i][j]=='.')\n                ttt[i][j]='!';\n            }\n        }\n    }\n}\nint main()\n{\n    int a,b;\n    int i,j;\n    for(i=0;i<9;i++)\n    {\n      //  printf(\"%d\\n\",i);\n        for(j=0;j<9;j++)\n        {\n            scanf(\" %c\",&ttt[i][j]);\n        }\n    }\n    scanf(\"%d %d\",&a,&b);\n    //printf(\"1\");\n    check(b,a);\n    for(i=0;i<9;i++)\n    {\n        for(j=0;j<9;j++)\n        {\n            printf(\"%c\",ttt[i][j]);\n            if(j%3==2)\n            printf(\" \");\n        }\n        printf(\"\\n\");\n        if(i%3==2)\n        printf(\"\\n\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5443e9352b32242c71d707801e3d879c", "src_uid": "8f0fad22f629332868c39969492264d3", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint clu(int x){\n\tint a;\n\ta=x%3;\n\tif(a==0){\n\t\treturn 6;\n\t}\n\tif(a==1){\n\t\treturn 0;\n\t}\n\tif(a==2){\n\t\treturn 3;\n\t}\n}\nint main(void){\n\tchar a[12][12];\n\tint x,y,i,j,f=0,p,q;\n\tfor(i=0;i<9;i++){\n\t\tscanf(\"%s %s %s\",&a[i][0],&a[i][3],&a[i][6]);\n\t}\n\tscanf(\"%d %d\",&x,&y);\n\tx=clu(x);\n\ty=clu(y);\n\tfor(i=x;i<=x+2;i++){\n\t\tfor(j=y;j<=y+2;j++){\n\t\t\tif(a[i][j]=='.'){\n\t\t\t\ta[i][j]='!';\n\t\t\t\tf=1;\n\t\t\t}\n\t\t}\n\t}\n\tif(f==1){\n\t    for(i=0;i<9;i++){\n\t\t\tfor(j=0;j<=9;j++){\n\t\t\t\tprintf(\"%c\",a[i][j]);\n\t\t\t\tif((j+1)%3==0 && j!=8){\n\t\t    \t    printf(\" \");\n\t\t\t    }\n\t\t\t}\n\t\t\tprintf(\"\\n\");\n\t\t\tif((i+1)%3==0 && i!=8){\n\t\t    \tprintf(\"\\n\");\n\t\t\t}\n\t    }\n\t}\n\telse{\n\t\tfor(i=0;i<9;i++){\n\t\t\tfor(j=0;j<=9;j++){\n\t\t\t    if(a[i][j]=='.'){\n\t\t\t    \ta[i][j]='!';\n\t\t\t\t}\n\t\t\t\tprintf(\"%c\",a[i][j]);\n\t\t\t\tif((j+1)%3==0 && j!=8){\n\t\t    \t    printf(\" \");\n\t\t\t    }\n\t\t\t}\n\t\t\tprintf(\"\\n\");\n\t\t\tif((i+1)%3==0 && i!=8){\n\t\t    \tprintf(\"\\n\");\n\t\t\t}\n\t    }\n\t}\n\treturn 0;\n} ", "lang_cluster": "C", "compilation_error": false, "code_uid": "6e0a7a0528d231adb477a3a41ab5ae90", "src_uid": "8f0fad22f629332868c39969492264d3", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint clu(int x){\n\tint a;\n\ta=x%3;\n\tif(a==0){\n\t\treturn 6;\n\t}\n\tif(a==1){\n\t\treturn 0;\n\t}\n\tif(a==2){\n\t\treturn 3;\n\t}\n}\nint main(void){\n\tchar a[12][12];\n\tint x,y,i,j,f=0,p,q;\n\tfor(i=0;i<9;i++){\n\t\tscanf(\"%s %s %s\",&a[i][0],&a[i][3],&a[i][6]);\n\t}\n\tscanf(\"%d %d\",&x,&y);\n\tx=clu(x);\n\ty=clu(y);\n\tfor(i=x;i<=x+2;i++){\n\t\tfor(j=y;j<=y+2;j++){\n\t\t\tif(a[i][j]=='.'){\n\t\t\t\ta[i][j]='!';\n\t\t\t\tf=1;\n\t\t\t}\n\t\t}\n\t}\n\tif(f==0){\n\t\tfor(i=0;i<9;i++)\n\t\tfor(j=0;j<9;j++)\n\t\tif(a[i][j]=='.') a[i][j]='!';\n\t}\n\tfor(i=0;i<9;i++){\n\t\t\tfor(j=0;j<=9;j++){\n\t\t\t\tprintf(\"%c\",a[i][j]);\n\t\t\t\tif((j+1)%3==0 && j!=8){\n\t\t    \t    printf(\" \");\n\t\t\t    }\n\t\t\t}\n\t\t\tprintf(\"\\n\");\n\t\t\tif((i+1)%3==0 && i!=8){\n\t\t    \tprintf(\"\\n\");\n\t\t\t}\n\t    }\n\treturn 0;\n} ", "lang_cluster": "C", "compilation_error": false, "code_uid": "db9fb21905f8f5ac53911542b631b427", "src_uid": "8f0fad22f629332868c39969492264d3", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint clu(int x){\n\tint a;\n\ta=x%3;\n\tif(a==0){\n\t\treturn 6;\n\t}\n\tif(a==1){\n\t\treturn 0;\n\t}\n\tif(a==2){\n\t\treturn 3;\n\t}\n}\nint main(void){\n\tchar a[12][12];\n\tint x,y,i,j,f=0,p,q;\n\tfor(i=0;i<9;i++){\n\t\tscanf(\"%s %s %s\",&a[i][0],&a[i][3],&a[i][6]);\n\t}\n\tscanf(\"%d %d\",&x,&y);\n\tx=clu(x);\n\ty=clu(y);\n\tfor(i=x;i<=x+2;i++){\n\t\tfor(j=y;j<=y+2;j++){\n\t\t\tif(a[i][j]=='.'){\n\t\t\t\ta[i][j]='!';\n\t\t\t\tf=1;\n\t\t\t}\n\t\t}\n\t}\n\tif(f==0){\n\t\tfor(i=0;i<9;i++)\n\t\tfor(j=0;j<9;j++)\n\t\tif(a[i][j]=='.') a[i][j]='!';\n\t}\n\tfor(i=0;i<9;i++){\n\t\tif(i%3==0 && i) printf(\"\\n\");\n\t\t\tfor(j=0;j<=9;j++){\n\t\t\t\tif(j%3==0&&j) printf(\" \"); \n\t\t\t\tprintf(\"%c\",a[i][j]);\n\t\t\t}\n\t\t\tprintf(\"\\n\");\n\t    }\n\treturn 0;\n} ", "lang_cluster": "C", "compilation_error": false, "code_uid": "8eeb0c67e80e5cef46a24e7220476d20", "src_uid": "8f0fad22f629332868c39969492264d3", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint a[10000];\nint main()\n{\n    int c,d,n,m,k,total,ans,sum,i=0;\n    scanf(\"%d %d %d %d %d\",&c,&d,&n,&m,&k);\n    total=n*m-k;\n    while((total-i)>0)\n    {\n        if((total-i)%n==0)\n        {\n            a[i]=(((total-i)/n)*c)+(i*d);\n        }\n        else\n            a[i]=((((total-i)/n)+1)*c)+(i*d);\n        i++;\n    }\n    ans=a[0];\n    for(int j=1;j<i;j++)\n    {\n        if(ans>a[j])\n            ans=a[j];\n    }\n    printf(\"%d\\n\",ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a673405285ac02070a4b9a9294e8011c", "src_uid": "c6ec932b852e0e8c30c822a226ef7bcb", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint c,d,n,m,k,q,i,p;\nint check(int n)\n{\n    return(c>d*n);\n}   \nint main(void) {\n    scanf(\"%d %d\",&c,&d);\n    scanf(\"%d %d\",&n,&m);\n    scanf(\"%d\",&k);\n    p=n*m-k;\n    i=check(n);\n    if(i==1)\n        printf(\"%d\",p*d);\n    else\n    {\n        while(p>=n)\n        {\n            q+=c;\n            p-=n;\n        }\n        while(p>0)\n        {\n            i=check(p);\n            if(i==1)\n            {\n                q+=d;\n                p--;\n            }   \n            else\n            {\n                q+=c;\n                p-=n;\n            }\n        }\n        printf(\"%d\",q);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dbadf769d4dff8e01127a56120e5a0a1", "src_uid": "c6ec932b852e0e8c30c822a226ef7bcb", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nvoid main()\n{\n\tint n,m,c,d,k,s;\n\twhile(scanf(\"%d%d%d%d%d\",&c,&d,&n,&m,&k)!=EOF)\n\t{\n\t\tif(k>=n*m)\n\t\t\tprintf(\"0\\n\");\n\t\telse\n\t\t{\n\t\t\ts=n*m-k;\n\t\t\tif(c/n>1)\n\t\t\t\tprintf(\"s\\n\");\n\t\t\telse\n\t\t\t{\tif(s%n==0)\n\t\t\t\t\tprintf(\"%d\\n\",s/n);\n\t\t\t\telse\n\t\t\t\t\t\tprintf(\"%d\\n\",s/n+1);\n\t\t\t}\n\t\t}\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "857255014d26ae5c59c7b34f9718a54f", "src_uid": "c6ec932b852e0e8c30c822a226ef7bcb", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint a[101];\nint main()\n{\n    int c,d,n,m,k,total,ans,sum,i=0;\n    scanf(\"%d %d %d %d %d\",&c,&d,&n,&m,&k);\n    total=n*m-k;\n    while((total-i)>0)\n    {\n        if((total-i)%n==0)\n        {\n            a[i]=(((total-i)/n)*c)+(i*d);\n        }\n        else\n            a[i]=((((total-i)/n)+1)*c)+(i*d);\n        i++;\n    }\n    ans=a[0];\n    for(int j=1;j<i;j++)\n    {\n        if(ans>a[j])\n            ans=a[j];\n    }\n    printf(\"%d\\n\",ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "11ceb8d6ee2f7282ffa1aec5af3b38d3", "src_uid": "c6ec932b852e0e8c30c822a226ef7bcb", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n    int c,d,n,m,k,ans,tot;\n    scanf(\"%d %d\",&c,&d);\n    scanf(\"%d %d\",&n,&m);\n    scanf(\"%d\",&k);\n    tot=n*m-k;\n    if (c>d&&n==1)\n    {\n        ans=tot*d;\n    }\n    else\n    {\n        ans=0;\n        ans=ans+(tot/n)*c;\n        tot=tot-tot/n*n;\n        if (tot*d<c) ans=ans+tot*d; else ans=ans+c;\n    }\n    printf(\"%d\",ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "046a15b662fa19676113f0c2ab598b2c", "src_uid": "c6ec932b852e0e8c30c822a226ef7bcb", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "/*\nID: mohamma73\nLANG: C\nTASK: crypt1\n*/\n\n#include\"stdio.h\"\n#include\"stdlib.h\"\n#include\"ctype.h\"\n#include\"math.h\"\n#include\"string.h\"\nstruct card{\n\tint val;\n\tchar suit;\n\tint id;\n};\nstruct point{\n\tint x;\n\tint y;\n\tint visit;\n};\nstruct node{\n\tint id;\n\tint n;\n\tint nei[102];\n};\nstruct person{\n\tint id;\n\tint nd;\n\tint nl;\n\tint like[2004];\n\tint dis[2004];\n\tint visit;\n};\nstruct farmer{\n\tint p;\n\tint c;\n};\nvoid inc(int *a,int n){\n\tint i;\n\tif(a[0]!=2){\n\t\ta[0]++;\n\t\treturn;\n\t}\n\tfor(i=0;i<n && a[i]==2;i++)\n\t\ta[i]=0;\n\tif(i<n)\n\t\ta[i]++;\n}\nint cmp(char *s,char *t){\n\tint n=strlen(s);\n\tint m=strlen(t);\n\tint i,j;\n\tfor(i=0,j=0;i<n && j<m && s[i]==t[j];i++,j++);\n\tif(s[i]>t[j])\n\t\treturn 1;\n\telse if(s[i]<t[j])\n\t\treturn -1;\n\telse \n\t\treturn 0;\n\t\n}\nint getword(char *s,int n){\n\tint i;\n\tchar c;\n\twhile(isspace(c=getchar()));\n\tfor(i=0;i<n && !isspace(c);i++,c=getchar())\n\t\ts[i]=c;\n\ts[i++]='\\0';\n\treturn i-1;\n}\nint fgetword(char *s,int n,FILE *fp){\n\tint i;\n\tchar c;\n\twhile(isspace(c=getc(fp)));\n\tfor(i=0;i<n && !isspace(c) && c!=EOF;i++,c=getc(fp))\n\t\ts[i]=c;\n\ts[i++]='\\0';\n\treturn i-1;\n}\nlong long atll(char *s){\n\tlong long n=0;\n\tint i;\n\tfor(i=0;s[i]!='\\0';i++){\n\t\tn*=10;\n\t\tn+=(s[i]-'0');\n\t}\n\treturn n;\n}\nint Bsear(char *s,char words[][13],int n){\n\tint l=0;\n\tint h=n;\n\tint mid;\n\twhile(l<h){\n\t\tmid=(l+h)/2;\n\t\tif(cmp(words[mid],s)==0)\n\t\t\treturn 1;\n\t\telse if(cmp(words[mid],s)==1){\n\t\t\th=mid;\n\t\t}else\n\t\t\tl=mid+1;\n\t}\n\treturn -1;\n}\nvoid func(int *n,int base,int num){\n\tint i=0;\n\twhile(num/base!=0){\n\t\tn[i++]=num%base;\n\t\tnum/=base;\n\t}\n\tn[i++]=num;\n\tn[i++]=20;\n}\nint pal(int *n){\n\tint i,j;\n\tfor(i=0;n[i]!=20;i++);\n\tfor(j=0;j<i/2 && n[j]==n[i-j-1];j++);\n\tif(j==i/2)\n\t\treturn 1;\n\treturn 0;\n}\nint ispal(char *s, int i, int j){\n\tint k;\n\tfor(k=0;k<((j-i+1)/2) && s[i+k]==s[j-k];k++);\n\tif(k==(j-i+1)/2)\n\t\treturn 1;\n\treturn 0;\n}\nvoid insort(int *a,int n){\n\tint i,j,temp;\n\tfor(i=1;i<n;i++){\n\t\tj=i;\n\t\twhile(j>0 && a[j]<a[j-1]){\n\t\t\ttemp=a[j-1];\n\t\t\ta[j-1]=a[j];\n\t\t\ta[j]=temp;\n\t\t\tj--;\n\t\t}\n\t}\n}\nchar lower(char c){\n\treturn c<'a'?c+('a'-'A'):c;\n}\nvoid sort(int *a,int n){\n\tint i,j,temp;\n\tfor(i=1;i<n;i++)\n\t\tfor(j=i;j>0 && a[j-1]>a[j];j--){\n\t\t\t\ttemp=a[j];\n\t\t\t\ta[j]=a[j-1];\n\t\t\t\ta[j-1]=temp;\n\t\t\t\n\t\t}\n}\nvoid fun(int n,char *s){\n\tint i=0;\n\tfor(i=0;n/10!=0;i++,n/=10)\n\t\ts[i]=n%10+'0';\n\ts[i++]=n+'0';\n\ts[i]='\\0';\n}\nvoid sortIn(int *a,int *indx,int n){\n\tint t1;\n\tint i,j;\n\tfor(i=1;i<n;i++)\n\t\tfor(j=i;j>0 && a[j-1]>a[j];j--){\n\t\t\tt1=a[j-1];\n\t\t\ta[j-1]=a[j];\n\t\t\ta[j]=t1;\n\t\t\tt1=indx[j-1];\n\t\t\tindx[j-1]=indx[j];\n\t\t\tindx[j]=t1;\n\t\t}\n}\nint valid(int *a,int l,int r,int n){\n\tint f=0;\n\tif(l>0 && a[l-1]>a[r])\n\t\tf=1;\n\tif(a[l+1]<a[r])\n\t\tf=1;\n\tif(a[r-1]>a[l])\n\t\tf=1;\n\tif(r<n-1 && a[r+1]<a[l])\n\t\tf=1;\n\tif(f) \n\t\treturn 0;\n\treturn 1;\n}\nvoid change(char *stripe,int *colors,int idx,int k){\n\tint j=0;\n\tif(idx==1){\n\t\tif(stripe[0]-'A'>0)\n\t\t\tstripe[0]=colors[stripe[0]-'A'-1];\n\t\telse\n\t\t\tstripe[0]=colors[stripe[0]-'A'+1];\n\t\treturn ;\n\t}\n\tfor(j=0;j<idx;j+=2){\n\t\tif(stripe[j]-'A'>0){\n\t\t\tif(stripe[j]==stripe[j+1])\n\t\t\t\tstripe[j]=colors[stripe[j]-'A'-1];\n\t\t\telse if(stripe[j+1]!=colors[stripe[j]-'A'-1])\n\t\t\t\tstripe[j]=colors[stripe[j]-'A'-1];\n\t\t\telse if(stripe[j]-'A'<k-1)\n\t\t\t\tstripe[j]=colors[stripe[j]-'A'+1];\n\t\t\telse\n\t\t\t\tstripe[j]=colors[stripe[j]-'A'-2];\n\t\t}else{\n\t\t\tif(stripe[j]==stripe[j+1])\n\t\t\t\tstripe[j]=colors[stripe[j]-'A'+1];\n\t\t\telse\n\t\t\t\tstripe[j]=colors[stripe[j]-'A'+2];\n\t\t}\n\t}\n}\nint invite(struct point *nom[],int n,struct point *pts[],int m,struct point *invite[]){\n\tint i,j,idx=0;\n\tfor(i=0;i<n;i++){\n\t\tfor(j=0;j<m;j++){\n\t\t\tif(nom[i]->x==pts[j]->x || nom[i]->y==pts[j]->y){\n\t\t\t\tif(pts[j]->visit==0){\n\t\t\t\t\tinvite[idx++]=pts[j];\n\t\t\t\t\tpts[j]->visit=1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t\t\n\t}\n\treturn idx;\n}\nint feasible(struct person *a[],int n){\n\tint i,j,k;\n\tint flag=1;\n\tfor(i=0;flag && i<n;i++)\n\t\tfor(j=0;flag && j<a[i]->nd;j++)\n\t\t\tfor(k=0;flag &&k<n;k++){\n\t\t\t\tif(a[k]->id==a[i]->dis[j]){\n\t\t\t\t\tflag=0;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\tif(i==n)\n\t\treturn 1;\n\treturn 0;\n}\nint find(struct node *p,struct node *node[]){\n\tint i,j,k;\n\tint count=0;\n\tfor(i=0;i<p->n;i++){\n\t\tif(p->nei[i]==-1)\n\t\t\tcontinue;\n\t\tfor(j=0;j<node[p->nei[i]]->n;j++){\n\t\t\tif(node[p->nei[i]]->nei[j]==-1)\n\t\t\t\tcontinue;\n\t\t\tfor(k=0;k<p->n;k++){\n\t\t\t\tif(p->nei[k]==-1)\n\t\t\t\t\tcontinue;\n\t\t\t\tif(node[p->nei[i]]->nei[j]==p->nei[k])\n\t\t\t\t\tcount++;\n\t\t\t}\n\t\t}\n\t}\n\t\t\n\treturn count;\n}\nvoid rem(struct node *p,struct node *nodes[],int n){\n\tint i,j;\n\tfor(i=0;i<n;i++){\n\t\tif(nodes[i]==NULL)\n\t\t\tcontinue;\n\t\tfor(j=0;j<nodes[i]->n;j++)\n\t\t\tif(nodes[i]->nei[j]==p->id)\n\t\t\t\tnodes[i]->nei[j]=-1;\n\t}\n}\nint dfs3(struct card piles[],int n,int a[55][55][55][55]){\n\tint dfs1(struct card[],int,int [][][][]);\n\tif(n<=3)\n\t\treturn 0;\n\tif(a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id]!=-1)\n\t\treturn a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id];\n\tif(piles[n-1].suit==piles[n-4].suit || piles[n-1].val==piles[n-4].val){\n\t\tstruct card p[n];\n\t\tint i;\n\t\tfor(i=0;i<n;i++){\n\t\t\tp[i].suit=piles[i].suit;\n\t\t\tp[i].val=piles[i].val;\n\t\t\tp[i].id=piles[i].id;\n\t\t}\n\t\tp[n-4].suit=p[n-1].suit;\n\t\tp[n-4].val=p[n-1].val;\n\t\tp[n-4].id=p[n-1].id;\n\t\tif(dfs1(p,n-1,a) || dfs3(p,n-1,a))\n\t\t\treturn a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id]=1;\n\t\telse \n\t\t\treturn a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id]=0;\n\t}\n\treturn a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id]=0;\n}\nint dfs1(struct card piles[],int n,int a[55][55][55][55]){\n\tif(n==1)\n\t\treturn a[n][piles[0].id][0][0]=1;\n\tif(n==2)\n\t\tif(a[n][piles[n-1].id][piles[n-2].id][0]!=-1)\n\t\t\treturn a[n][piles[n-1].id][piles[n-2].id][0];\n\tif(n>2)\n\t\tif(a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id]!=-1)\n\t\t\t\t\treturn a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id];\n\tif(piles[n-1].val==piles[n-2].val || piles[n-1].suit==piles[n-2].suit){\n\t\tstruct card p[n-1];\n\t\tint i;\n\t\tfor(i=0;i<n-1;i++){\n\t\t\tp[i].suit=piles[i].suit;\n\t\t\tp[i].val=piles[i].val;\n\t\t\tp[i].id=piles[i].id;\n\t\t}\n\t\tp[n-2].val=piles[n-1].val;\n\t\tp[n-2].suit=piles[n-1].suit;\n\t\tp[n-2].id=piles[n-1].id;\n\t\tif(n==2)\n\t\t\treturn a[n][piles[n-1].id][piles[n-2].id][0]=1;\n\t\telse {\n\t\t\tif(dfs1(p,n-1,a) || dfs3(p,n-1,a))\n\t\t\t\treturn a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id]=1;\n\t\t\telse \n\t\t\t\treturn a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id]=0;\n\t\t}\n\t}\n\treturn a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id]=0;\n}\nmain(){\n\tchar s[20];\n\tint i,j,k,l,idx=1;\n\tstruct card piles[55];\n\tgetword(s,20);\n\tint n=atoi(s);\n\tfor(i=0;i<n;i++){\n\t\tpiles[i].val=getchar();\n\t\tpiles[i].suit=getchar();\n\t\tfor(j=0;j<i;j++)\n\t\t\tif(piles[j].suit==piles[i].suit && piles[j].val==piles[i].val){\n\t\t\t\tpiles[i].id=piles[j].id;\n\t\t\t\tbreak;\n\t\t\t}\n\t\tif(i==j)\n\t\t\tpiles[i].id=idx++;\n\t\tgetchar();\n\t}\n\tint a[55][55][55][55];\n\tfor(i=0;i<55;i++)\n\t\tfor(j=0;j<55;j++)\n\t\t\tfor(k=0;k<55;k++)\n\t\t\t\tfor(l=0;l<55;l++)\n\t\t\t\t\ta[i][j][k][l]=-1;\n\tif(dfs1(piles,n,a) || dfs3(piles,n,a))\n\t\tprintf(\"YES\");\n\telse\n\t\tprintf(\"NO\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "43546089e7092efdacfc6b42009d6d42", "src_uid": "1805771e194d323edacf2526a1eb6768", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "/*\nID: mohamma73\nLANG: C\nTASK: crypt1\n*/\n\n#include\"stdio.h\"\n#include\"stdlib.h\"\n#include\"ctype.h\"\n#include\"math.h\"\n#include\"string.h\"\nstruct card{\n\tint val;\n\tchar suit;\n\tint id;\n};\nstruct point{\n\tint x;\n\tint y;\n\tint visit;\n};\nstruct node{\n\tint id;\n\tint n;\n\tint nei[102];\n};\nstruct person{\n\tint id;\n\tint nd;\n\tint nl;\n\tint like[2004];\n\tint dis[2004];\n\tint visit;\n};\nstruct farmer{\n\tint p;\n\tint c;\n};\nvoid inc(int *a,int n){\n\tint i;\n\tif(a[0]!=2){\n\t\ta[0]++;\n\t\treturn;\n\t}\n\tfor(i=0;i<n && a[i]==2;i++)\n\t\ta[i]=0;\n\tif(i<n)\n\t\ta[i]++;\n}\nint cmp(char *s,char *t){\n\tint n=strlen(s);\n\tint m=strlen(t);\n\tint i,j;\n\tfor(i=0,j=0;i<n && j<m && s[i]==t[j];i++,j++);\n\tif(s[i]>t[j])\n\t\treturn 1;\n\telse if(s[i]<t[j])\n\t\treturn -1;\n\telse \n\t\treturn 0;\n\t\n}\nint getword(char *s,int n){\n\tint i;\n\tchar c;\n\twhile(isspace(c=getchar()));\n\tfor(i=0;i<n && !isspace(c);i++,c=getchar())\n\t\ts[i]=c;\n\ts[i++]='\\0';\n\treturn i-1;\n}\nint fgetword(char *s,int n,FILE *fp){\n\tint i;\n\tchar c;\n\twhile(isspace(c=getc(fp)));\n\tfor(i=0;i<n && !isspace(c) && c!=EOF;i++,c=getc(fp))\n\t\ts[i]=c;\n\ts[i++]='\\0';\n\treturn i-1;\n}\nlong long atll(char *s){\n\tlong long n=0;\n\tint i;\n\tfor(i=0;s[i]!='\\0';i++){\n\t\tn*=10;\n\t\tn+=(s[i]-'0');\n\t}\n\treturn n;\n}\nint Bsear(char *s,char words[][13],int n){\n\tint l=0;\n\tint h=n;\n\tint mid;\n\twhile(l<h){\n\t\tmid=(l+h)/2;\n\t\tif(cmp(words[mid],s)==0)\n\t\t\treturn 1;\n\t\telse if(cmp(words[mid],s)==1){\n\t\t\th=mid;\n\t\t}else\n\t\t\tl=mid+1;\n\t}\n\treturn -1;\n}\nvoid func(int *n,int base,int num){\n\tint i=0;\n\twhile(num/base!=0){\n\t\tn[i++]=num%base;\n\t\tnum/=base;\n\t}\n\tn[i++]=num;\n\tn[i++]=20;\n}\nint pal(int *n){\n\tint i,j;\n\tfor(i=0;n[i]!=20;i++);\n\tfor(j=0;j<i/2 && n[j]==n[i-j-1];j++);\n\tif(j==i/2)\n\t\treturn 1;\n\treturn 0;\n}\nint ispal(char *s, int i, int j){\n\tint k;\n\tfor(k=0;k<((j-i+1)/2) && s[i+k]==s[j-k];k++);\n\tif(k==(j-i+1)/2)\n\t\treturn 1;\n\treturn 0;\n}\nvoid insort(int *a,int n){\n\tint i,j,temp;\n\tfor(i=1;i<n;i++){\n\t\tj=i;\n\t\twhile(j>0 && a[j]<a[j-1]){\n\t\t\ttemp=a[j-1];\n\t\t\ta[j-1]=a[j];\n\t\t\ta[j]=temp;\n\t\t\tj--;\n\t\t}\n\t}\n}\nchar lower(char c){\n\treturn c<'a'?c+('a'-'A'):c;\n}\nvoid sort(int *a,int n){\n\tint i,j,temp;\n\tfor(i=1;i<n;i++)\n\t\tfor(j=i;j>0 && a[j-1]>a[j];j--){\n\t\t\t\ttemp=a[j];\n\t\t\t\ta[j]=a[j-1];\n\t\t\t\ta[j-1]=temp;\n\t\t\t\n\t\t}\n}\nvoid fun(int n,char *s){\n\tint i=0;\n\tfor(i=0;n/10!=0;i++,n/=10)\n\t\ts[i]=n%10+'0';\n\ts[i++]=n+'0';\n\ts[i]='\\0';\n}\nvoid sortIn(int *a,int *indx,int n){\n\tint t1;\n\tint i,j;\n\tfor(i=1;i<n;i++)\n\t\tfor(j=i;j>0 && a[j-1]>a[j];j--){\n\t\t\tt1=a[j-1];\n\t\t\ta[j-1]=a[j];\n\t\t\ta[j]=t1;\n\t\t\tt1=indx[j-1];\n\t\t\tindx[j-1]=indx[j];\n\t\t\tindx[j]=t1;\n\t\t}\n}\nint valid(int *a,int l,int r,int n){\n\tint f=0;\n\tif(l>0 && a[l-1]>a[r])\n\t\tf=1;\n\tif(a[l+1]<a[r])\n\t\tf=1;\n\tif(a[r-1]>a[l])\n\t\tf=1;\n\tif(r<n-1 && a[r+1]<a[l])\n\t\tf=1;\n\tif(f) \n\t\treturn 0;\n\treturn 1;\n}\nvoid change(char *stripe,int *colors,int idx,int k){\n\tint j=0;\n\tif(idx==1){\n\t\tif(stripe[0]-'A'>0)\n\t\t\tstripe[0]=colors[stripe[0]-'A'-1];\n\t\telse\n\t\t\tstripe[0]=colors[stripe[0]-'A'+1];\n\t\treturn ;\n\t}\n\tfor(j=0;j<idx;j+=2){\n\t\tif(stripe[j]-'A'>0){\n\t\t\tif(stripe[j]==stripe[j+1])\n\t\t\t\tstripe[j]=colors[stripe[j]-'A'-1];\n\t\t\telse if(stripe[j+1]!=colors[stripe[j]-'A'-1])\n\t\t\t\tstripe[j]=colors[stripe[j]-'A'-1];\n\t\t\telse if(stripe[j]-'A'<k-1)\n\t\t\t\tstripe[j]=colors[stripe[j]-'A'+1];\n\t\t\telse\n\t\t\t\tstripe[j]=colors[stripe[j]-'A'-2];\n\t\t}else{\n\t\t\tif(stripe[j]==stripe[j+1])\n\t\t\t\tstripe[j]=colors[stripe[j]-'A'+1];\n\t\t\telse\n\t\t\t\tstripe[j]=colors[stripe[j]-'A'+2];\n\t\t}\n\t}\n}\nint invite(struct point *nom[],int n,struct point *pts[],int m,struct point *invite[]){\n\tint i,j,idx=0;\n\tfor(i=0;i<n;i++){\n\t\tfor(j=0;j<m;j++){\n\t\t\tif(nom[i]->x==pts[j]->x || nom[i]->y==pts[j]->y){\n\t\t\t\tif(pts[j]->visit==0){\n\t\t\t\t\tinvite[idx++]=pts[j];\n\t\t\t\t\tpts[j]->visit=1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t\t\n\t}\n\treturn idx;\n}\nint feasible(struct person *a[],int n){\n\tint i,j,k;\n\tint flag=1;\n\tfor(i=0;flag && i<n;i++)\n\t\tfor(j=0;flag && j<a[i]->nd;j++)\n\t\t\tfor(k=0;flag &&k<n;k++){\n\t\t\t\tif(a[k]->id==a[i]->dis[j]){\n\t\t\t\t\tflag=0;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\tif(i==n)\n\t\treturn 1;\n\treturn 0;\n}\nint find(struct node *p,struct node *node[]){\n\tint i,j,k;\n\tint count=0;\n\tfor(i=0;i<p->n;i++){\n\t\tif(p->nei[i]==-1)\n\t\t\tcontinue;\n\t\tfor(j=0;j<node[p->nei[i]]->n;j++){\n\t\t\tif(node[p->nei[i]]->nei[j]==-1)\n\t\t\t\tcontinue;\n\t\t\tfor(k=0;k<p->n;k++){\n\t\t\t\tif(p->nei[k]==-1)\n\t\t\t\t\tcontinue;\n\t\t\t\tif(node[p->nei[i]]->nei[j]==p->nei[k])\n\t\t\t\t\tcount++;\n\t\t\t}\n\t\t}\n\t}\n\t\t\n\treturn count;\n}\nvoid rem(struct node *p,struct node *nodes[],int n){\n\tint i,j;\n\tfor(i=0;i<n;i++){\n\t\tif(nodes[i]==NULL)\n\t\t\tcontinue;\n\t\tfor(j=0;j<nodes[i]->n;j++)\n\t\t\tif(nodes[i]->nei[j]==p->id)\n\t\t\t\tnodes[i]->nei[j]=-1;\n\t}\n}\nint dfs3(struct card piles[],int n,int a[55][55][55][55]){\n\tint dfs1(struct card[],int,int [][][][]);\n\tif(n<=3)\n\t\treturn 0;\n\tif(a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id]!=-1)\n\t\treturn a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id];\n\tif(piles[n-1].suit==piles[n-4].suit || piles[n-1].val==piles[n-4].val){\n\t\tstruct card p[n];\n\t\tint i;\n\t\tfor(i=0;i<n;i++){\n\t\t\tp[i].suit=piles[i].suit;\n\t\t\tp[i].val=piles[i].val;\n\t\t\tp[i].id=piles[i].id;\n\t\t}\n\t\tp[n-4].suit=p[n-1].suit;\n\t\tp[n-4].val=p[n-1].val;\n\t\tp[n-4].id=p[n-1].id;\n\t\tif(dfs1(p,n-1,a) || dfs3(p,n-1,a))\n\t\t\treturn a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id]=1;\n\t\telse \n\t\t\treturn a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id]=0;\n\t}\n\treturn a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id]=0;\n}\nint dfs1(struct card piles[],int n,int a[55][55][55][55]){\n\tif(n==1)\n\t\treturn a[n][piles[0].id][0][0]=1;\n\tif(n==2)\n\t\tif(a[n][piles[n-1].id][piles[n-2].id][0]!=-1)\n\t\t\treturn a[n][piles[n-1].id][piles[n-2].id][0];\n\tif(n>2)\n\t\tif(a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id]!=-1)\n\t\t\t\t\treturn a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id];\n\tif(piles[n-1].val==piles[n-2].val || piles[n-1].suit==piles[n-2].suit){\n\t\tstruct card p[n-1];\n\t\tint i;\n\t\tfor(i=0;i<n-1;i++){\n\t\t\tp[i].suit=piles[i].suit;\n\t\t\tp[i].val=piles[i].val;\n\t\t\tp[i].id=piles[i].id;\n\t\t}\n\t\tp[n-2].val=piles[n-1].val;\n\t\tp[n-2].suit=piles[n-1].suit;\n\t\tp[n-2].id=piles[n-1].id;\n\t\tif(n==2)\n\t\t\treturn a[n][piles[n-1].id][piles[n-2].id][0]=1;\n\t\telse {\n\t\t\tif(dfs1(p,n-1,a) || dfs3(p,n-1,a))\n\t\t\t\treturn a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id]=1;\n\t\t\telse \n\t\t\t\treturn a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id]=0;\n\t\t}\n\t}\n\treturn a[n][piles[n-1].id][piles[n-2].id][piles[n-3].id]=0;\n}\nint a[55][55][55][55];\nmain(){\n\tchar s[20];\n\tint i,j,k,l,idx=1;\n\tstruct card piles[55];\n\tgetword(s,20);\n\tint n=atoi(s);\n\tfor(i=0;i<n;i++){\n\t\tpiles[i].val=getchar();\n\t\tpiles[i].suit=getchar();\n\t\tfor(j=0;j<i;j++)\n\t\t\tif(piles[j].suit==piles[i].suit && piles[j].val==piles[i].val){\n\t\t\t\tpiles[i].id=piles[j].id;\n\t\t\t\tbreak;\n\t\t\t}\n\t\tif(i==j)\n\t\t\tpiles[i].id=idx++;\n\t\tgetchar();\n\t}\n\tfor(i=0;i<55;i++)\n\t\tfor(j=0;j<55;j++)\n\t\t\tfor(k=0;k<55;k++)\n\t\t\t\tfor(l=0;l<55;l++)\n\t\t\t\t\ta[i][j][k][l]=-1;\n\tif(dfs1(piles,n,a) || dfs3(piles,n,a))\n\t\tprintf(\"YES\");\n\telse\n\t\tprintf(\"NO\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8004d124e65825246cc7d2a59e06ac4d", "src_uid": "1805771e194d323edacf2526a1eb6768", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint translate(char c) {\n\tswitch (c) {\n\t\tcase 'S':\n\t\t\treturn 0;\n\t\tcase 'D':\n\t\t\treturn 1;\n\t\tcase 'H':\n\t\t\treturn 2;\n\t\tcase 'C':\n\t\t\treturn 3;\n\t\tcase 'T':\n\t\t\treturn 10;\n\t\tcase 'J':\n\t\t\treturn 11;\n\t\tcase 'Q':\n\t\t\treturn 12;\n\t\tcase 'K':\n\t\t\treturn 13;\n\t\tcase 'A':\n\t\t\treturn 14;\n\t\tdefault:\n\t\t\treturn c - '0';\n\t}\n}\n\nint can(int n1, int s1, int n2, int s2) {\n\treturn n1 == n2 || s1 == s2;\n}\n\nint main() {\n\tint i, n, k, n0, s0, n1, s1, n2, s2, n3, s3;\n\tstatic int nn[52], ss[52], dp[52][15][4][15][4][15][4];\n\tstatic char s[3];\n\n\tscanf(\"%d\", &n);\n\tfor (i = 0; i < n; i++) {\n\t\tscanf(\"%s\", s);\n\t\tnn[i] = translate(s[0]);\n\t\tss[i] = translate(s[1]);\n\t}\n\tif (n == 1)\n\t\tprintf(\"YES\\n\");\n\telse if (n == 2)\n\t\tprintf(\"%s\\n\", can(nn[1], ss[1], nn[0], ss[0]) ? \"YES\" : \"NO\");\n\telse {\n\t\tfor (n2 = 2; n2 <= 14; n2++)\n\t\t\tfor (s2 = 0; s2 < 4; s2++)\n\t\t\t\tfor (n1 = 2; n1 <= 14; n1++)\n\t\t\t\t\tfor (s1 = 0; s1 < 4; s1++)\n\t\t\t\t\t\tfor (n0 = 2; n0 <= 14; n0++)\n\t\t\t\t\t\t\tfor (s0 = 0; s0 < 4; s0++)\n\t\t\t\t\t\t\t\tdp[2][n2][s2][n1][s1][n0][s0] =\n\t\t\t\t\t\t\t\t\t(n1 == n0 || s1 == s0)\n\t\t\t\t\t\t\t\t\t&& (n2 == n0 || s2 == s0);\n\t\tfor (k = 3; k <\tn; k++) {\n\t\t\tn3 = nn[k - 3];\n\t\t\ts3 = ss[k - 3];\n\t\t\tfor (n2 = 2; n2 <= 14; n2++)\n\t\t\t\tfor (s2 = 0; s2 < 4; s2++)\n\t\t\t\t\tfor (n1 = 2; n1 <= 14; n1++)\n\t\t\t\t\t\tfor (s1 = 0; s1 < 4; s1++)\n\t\t\t\t\t\t\tfor (n0 = 2; n0 <= 14; n0++)\n\t\t\t\t\t\t\t\tfor (s0 = 0; s0 < 4; s0++) {\n\t\t\t\t\t\t\t\t\tint yes = 0;\n\n\t\t\t\t\t\t\t\t\tif (can(n0, s0, n1, s1))\n\t\t\t\t\t\t\t\t\t\tyes = yes\n\t\t\t\t\t\t\t\t\t\t\t|| dp[k - 1][n3][s3][n2][s2][n0][s0];\n\t\t\t\t\t\t\t\t\tif (can(n0, s0, n3, s3))\n\t\t\t\t\t\t\t\t\t\tyes = yes || dp[k - 1][n0][s0][n2][s2][n1][s1];\n\t\t\t\t\t\t\t\t\tdp[k][n2][s2][n1][s1][n0][s0] = yes;\n\t\t\t\t\t\t\t\t}\n\t\t}\n\t\tprintf(\"%s\\n\", dp[n - 1][nn[n - 3]][ss[n - 3]][nn[n - 2]][ss[n - 2]][nn[n - 1]][ss[n - 1]] ? \"YES\" : \"NO\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cb9e46bc2125faa9f10b20612b63cce9", "src_uid": "1805771e194d323edacf2526a1eb6768", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint a[52];\nint dp[2][52][52][52][52];\n\nint hash(char s[3])\n{\n    int x = 0;\n    \n    if (s[0] >= '2' && s[0] <= '9') {\n        x = s[0] - '1';\n    } else if (s[0] == 'T') {\n        x = 9;\n    } else if (s[0] == 'J') {\n        x = 10;\n    } else if (s[0] == 'Q') {\n        x = 11;\n    } else if (s[0] == 'K') {\n        x = 12;\n    }\n    \n    if (s[1] == 'S') {\n        x += 13;\n    } else if (s[1] == 'D') {\n        x += 26;\n    } else if (s[1] == 'H') {\n        x += 39;\n    }\n    \n    return x;\n}\n\nint ok(int a, int b)\n{\n    if (a / 13 == b / 13 || a % 13 == b % 13) {\n        return 1;\n    } else {\n        return 0;\n    }\n}\n\nint check(int n)\n{\n    int tmp;\n    \n    if (n == 0) return 1;\n    \n    if (n == 3 && ok(a[0], a[3])) {\n        tmp = a[0];\n        a[0] = a[3];\n        \n        if (check(n - 1) == 1) return 1;\n        \n        a[3] = a[0];\n        a[0] = tmp;\n    }\n    \n    if (ok(a[n - 1], a[n])) {\n        tmp = a[n - 1];\n        a[n - 1] = a[n];\n        \n        if (check(n - 1) == 1) return 1;\n        \n        a[n] = a[n - 1];\n        a[n - 1] = tmp;\n    }\n    \n    return 0;\n}\n\nint main()\n{\n    int n, i, j, k, l, m;\n    \n    scanf(\"%d\", &n);\n    \n    for (i = 0; i < n; i++) {\n        char s[3];\n        \n        scanf(\"%s\", s);\n        \n        a[i] = hash(s);\n    }\n    \n    if (n < 4) {\n        if (check(n) == 1) {\n            puts(\"YES\");\n        } else {\n            puts(\"NO\");\n        }\n        \n        return 0;\n    }\n    \n    dp[(n - 1) % 2][a[n - 4]][a[n - 3]][a[n - 2]][a[n - 1]] = 1;\n    \n    for (i = n - 1; i >= 4; i--) {\n        for (j = 0; j < 52; j++) {\n            for (k = 0; k < 52; k++) {\n                for (l = 0; l < 52; l++) {\n                    for (m = 0; m < 52; m++) {\n                        if (dp[i % 2][j][k][l][m] == 0) continue;\n                        \n                        if (ok(j, m)) {\n                            dp[(i - 1) % 2][a[i - 4]][m][k][l] = 1;\n                        }\n                        \n                        if (ok(l, m)) {\n                            dp[(i - 1) % 2][a[i - 4]][j][k][m] = 1;\n                        }\n                        \n                        dp[i % 2][j][k][l][m] = 0;\n                    }\n                }\n            }\n        }\n    }\n    \n    for (i = 0; i < 52; i++) {\n        for (j = 0; j < 52; j++) {\n            for (k = 0; k < 52; k++) {\n                for (l = 0; l < 52; l++) {\n                    if (dp[1][i][j][k][l] == 1) {\n                        a[0] = i;\n                        a[1] = j;\n                        a[2] = k;\n                        a[3] = l;\n                        \n                        if (check(3) == 1) {\n                            puts(\"YES\");\n                            \n                            return 0;\n                        }\n                    }\n                }\n            }\n        }\n    }\n    \n    puts(\"NO\");\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0cddc3f5902d163944b2ff9ab33ee9ed", "src_uid": "1805771e194d323edacf2526a1eb6768", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "/*\n * =====================================================================================\n *\n *       Filename:  Solitaire.c\n *\n *    Description:  \n *\n *        Version:  1.0\n *        Created:  2012\u5e7407\u670825\u65e5 13\u65f647\u520601\u79d2\n *       Revision:  none\n *       Compiler:  gcc\n *\n *         Author:  YOUR NAME (), \n *   Organization:  \n *\n * =====================================================================================\n */\n#include <stdlib.h>\n#include <stdio.h>\n#include <string.h>\n#define MAXN 2<<6\n#define OP1 1\n#define OP2 3\nint dp[MAXN][MAXN][MAXN][MAXN];\ntypedef struct Card {\n\tchar val;\n\tchar suit;\n} Card_t;\nCard_t cards[MAXN];\n/* \nint dfs(Card_t *cards, int n, int op) {\n\tif(n == 1) return 1;\n\tif(n - op <=0 ) return 0;\n\n\tif(cards[n].val == cards[n - op].val) {\n\t\tint tmpSuit = cards[n - op].suit;\n\t\tcards[n - op].suit = cards[n].suit;\n\t\tif(dfs(cards, n-1, OP1) || dfs(cards, n-1, OP2)) \n\t\t\treturn 1;\n\t\telse \n\t\t\tcards[n - op].suit = tmpSuit;\n\t}\n\tif(cards[n].suit == cards[n - op].suit) {\n\t\tint tmpVal = cards[n- op].val;\n\t\tcards[n - op].val = cards[n].val;\n\t\tif(dfs(cards, n-1, OP1) || dfs(cards, n-1, OP2))\n\t\t\treturn 1;\n\t\telse \n\t\t\tcards[n -op].val = tmpVal;\n\t}\n\treturn 0;\n}\n*/\n\nint calc(int n, int a, int b, int c) {\n\tif(n == 1) return 1;\n\tif(n == 2) {\n\t\tif(cards[a].val == cards[b].val || cards[a].suit == cards[b].suit) return 1;\n\t\telse return 0;\n\t}\n\tif(n == 3) {\n\t//\tprintf(\"n-%d a-%d b-%d c-%d\\n\",n,a,b,c);\n\t\tif(cards[c].val == cards[b].val || cards[c].suit == cards[b].suit) {\n\t//\t\tprintf(\"cards[%d].val=%c cards[%d].val=%c\\n\",c,cards[c].val,b,cards[b].val);\n\t\t\tif(cards[c].val == cards[a].val || cards[c].suit == cards[a].suit) \n\t\t\t\treturn 1;\n\t\t\telse \n\t\t\t\treturn 0;\n\t\t}\n\t\telse \n\t\t\treturn 0;\n\t}\n\treturn 0;\n}\n\nint main() {\n\tint i,j,k,l,n;\n\tchar tmp;\n\n\twhile(scanf(\"%d\", &n) != EOF) {\n\t\tscanf(\"%c\",&tmp);\n\t\tmemset (cards, 0, sizeof cards);\n\t\tmemset (dp, 0, sizeof dp);\n\t\tfor(i=1; i <=n ; ++i) \n\t\t\tif (i < n)\n\t\t\t\tscanf(\"%c%c%c\", &cards[i].val, &cards[i].suit, &tmp);\n\t\t\telse \n\t\t\t\tscanf(\"%c%c\", &cards[i].val, &cards[i].suit);\n\t\t\n\t\tfor(i=1; i<=n; ++i) {\n\t\t\tfor(j=1; j<=n; ++j) {\n\t\t\t\tfor(k=1; k<=n; ++k) {\n\t\t\t\t\tif(j == k) continue;\n\t\t\t\t\tfor(l=1; l<=n; ++l)  {\n\t\t\t\t\t\tif(k == l) continue;\n\t\t\t\t\t\tif(i >= 4) {\n\t\t\t\t\t\t\tif(cards[i-3].val == cards[l].val || cards[i-3].suit == cards[l].suit)\n\t\t\t\t\t\t\t\tdp[i][j][k][l] = dp[i-1][l][j][k];\n\t\t\t\t\t\t\tif(cards[k].val == cards[l].val || cards[k].suit == cards[l].suit) \n\t\t\t\t\t\t\t\tdp[i][j][k][l] = dp[i][j][k][l] || dp[i-1][i-3][j][l];\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse\n\t\t\t\t\t\t\tdp[i][j][k][l] = calc(i,j,k,l);\n\t//\t\t\t\t\tprintf(\"dp[%d][%d][%d][%d]:%d\\n\",i,j,k,l,dp[i][j][k][l]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tif(n == 1) {\n\t\t\tif(calc(1, 1, 0, 0)) puts(\"YES\");\n\t\t\telse puts(\"NO\");\n\t\t}\n\t\telse if(n == 2) {\n\t\t\tif(calc(2, 1, 2, 0)) puts(\"YES\");\n\t\t\telse puts(\"NO\");\n\t\t}\n\t\telse {\n\t\t\tif(dp[n][n-2][n-1][n]) puts(\"YES\");\n\t\t\telse puts(\"NO\");\n\t\t}\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bcc8ffade6fcfe0ceaa9b92965d798d6", "src_uid": "1805771e194d323edacf2526a1eb6768", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint i,A[24],k=0,B[6];\n\tfor(i=1;i<=24;i++)\n\t{\n\t\tscanf(\"%d\",&A[i]);\n\t}\n\tfor(i=1;i<=6;i++){\n\t\tif (A[4*i]==A[4*i-1]&&A[4*i-2]==A[4*i-3]&&\n\t\tA[4*i]==A[4*i-2]){\n\t\t\tB[i]=1;}\n\t\t\telse B[i]=0;\n\t}\n\t\n\t\n\tif (B[1]==1&&B[2]==0&&B[3]==1&&B[4]\n\t==0&&B[5]==0&&B[6]==0){\n\t\tif (A[13]==A[14]&&A[13]==A[7]&&A[8]==A[7]&&A[5]==A[6]&&A[5]==A[19]&&A[19]==A[20]&&A[17]==A[18]&&A[23]==A[24]&&A[18]==A[19]) k=1;\n\t\telse if (A[13]==A[14]&&A[13]==A[22]&&A[22]==A[24]&&A[5]==A[6]&&A[5]==A[15]&&A[15]==A[16]&&A[17]==A[18]&&A[18]==A[7]&&A[7]==A[8]) k=1;\n\t}\n\t\n\t\n\tif (1==B[5]&&B[4]==1&&B[1]==0&&B[2]\n\t==0&&B[3]==0&&B[6]==0){\n\t\tif (A[1]==A[3]&&A[3]==A[6]&&A[8]==A[6]&&A[5]==A[7]&&A[7]==A[10]&&A[10]==A[12]&&A[9]==A[11]&&A[9]==A[21]&&A[23]==A[21]) k=1;\n\t\telse if (A[2]==A[4]&&A[2]==A[5]&&A[5]==A[7]&&A[8]==A[6]&&A[6]==A[9]&&A[9]==A[11]&&A[10]==A[12]&&A[12]==A[22]&&A[22]==A[24]) k=1;\n\t}\n\t\n\t\n\tif (B[1]==0&&B[2]==1&&B[3]==0&&B[4]\n\t==0&&B[5]==0&&B[6]==1){\n\t\tif (A[1]==A[2]&&A[1]==A[14]&&A[14]==A[16]&&A[13]==A[15]&&A[15]==A[9]&&A[9]==A[10]&&A[11]==A[12]&&A[12]==A[19]&&A[17]==A[19]) k=1;\n\t\telse if (  A[3]==A[4]&&A[3]==A[13]&&A[13]==A[15]&&A[14]==A[16]&&A[14]==A[11]&&A[11]==A[12]&&A[17]==A[19]&&A[19]==A[1]&&A[1]==A[2]) k=1;\n\t}\n\t\n\tif (k==1) printf(\"YES\");\n\telse printf(\"NO\");\n\treturn 0;\n}\n\t\t\n\t", "lang_cluster": "C", "compilation_error": false, "code_uid": "f1ecd88216cdf377b2a82337f9c0b4e8", "src_uid": "881a820aa8184d9553278a0002a3b7c4", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint i,A[30],k=0,B[7];\n\tfor(i=1;i<=24;i++)\n\t{\n\t\tscanf(\"%d\",&A[i]);\n\t}\n\tfor(i=1;i<=6;i++){\n\t\tif (A[4*i]==A[4*i-1]&&A[4*i-2]==A[4*i-3]&&\n\t\tA[4*i]==A[4*i-2]){\n\t\t\tB[i]=1;}\n\t\t\telse B[i]=0;\n\t}\n\t\n\t\n\tif (B[1]==1&&B[2]==0&&B[3]==1&&B[4]\n\t==0&&B[5]==0&&B[6]==0){\n\t\tif (A[13]==A[14]&&A[13]==A[7]&&A[8]==A[7]&&A[5]==A[6]&&A[5]==A[19]&&A[19]==A[20]&&A[17]==A[18]&&A[23]==A[24]&&A[18]==A[19]) k=1;\n\t\telse if (A[13]==A[14]&&A[13]==A[22]&&A[22]==A[24]&&A[5]==A[6]&&A[5]==A[15]&&A[15]==A[16]&&A[17]==A[18]&&A[18]==A[7]&&A[7]==A[8]) k=1;\n\t}\n\t\n\t\n\tif (1==B[5]&&B[4]==1&&B[1]==0&&B[2]\n\t==0&&B[3]==0&&B[6]==0){\n\t\tif (A[1]==A[3]&&A[3]==A[6]&&A[8]==A[6]&&A[5]==A[7]&&A[7]==A[10]&&A[10]==A[12]&&A[9]==A[11]&&A[9]==A[21]&&A[23]==A[21]) k=1;\n\t\telse if (A[2]==A[4]&&A[2]==A[5]&&A[5]==A[7]&&A[8]==A[6]&&A[6]==A[9]&&A[9]==A[11]&&A[10]==A[12]&&A[12]==A[22]&&A[22]==A[24]) k=1;\n\t}\n\t\n\t\n\tif (B[1]==0&&B[2]==1&&B[3]==0&&B[4]\n\t==0&&B[5]==0&&B[6]==1){\n\t\tif (A[1]==A[2]&&A[1]==A[14]&&A[14]==A[16]&&A[13]==A[15]&&A[15]==A[9]&&A[9]==A[10]&&A[11]==A[12]&&A[12]==A[19]&&A[17]==A[19]) k=1;\n\t\telse if(A[3]==A[4]&&A[3]==A[13]&&A[13]==A[15]&&A[14]==A[16]&&A[14]==A[11]&&A[11]==A[12]&&A[17]==A[19]&&A[19]==A[1]&&A[1]==A[2]) k=1;\n\t}\n\t\n\tif (k==1) printf(\"YES\");\n\telse printf(\"NO\");\n\treturn 0;\n}\n\t\t\n\t", "lang_cluster": "C", "compilation_error": false, "code_uid": "aaaab2e154b9f873926aa46ba5d6aa83", "src_uid": "881a820aa8184d9553278a0002a3b7c4", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\n\nint main() {\n    int a[25] , i;\n    a[0] = 0;\n    for(i = 1; i <= 24; i++)\n        scanf(\"%d\", &a[i]);\n    if((a[1] == a[2] && a[1] == a[3] && a[4] == a[1] /**/ && a[9] == a[10] && a[9] == a[11] && a[9] == a[12] /**/ && a[13] == a[14] && a[13] == a[7] && a[13] == a[8] /**/ && a[5] == a[6] && a[5] == a[19] && a[5] == a[20] /**/ && a[17] == a[18] && a[17] == a[23] && a[17] == a[24]) ||\n       (a[1] == a[2] && a[1] == a[3] && a[4] == a[1] /**/ && a[9] == a[10] && a[9] == a[11] && a[9] == a[12] /**/ && a[13] == a[14] && a[13] == a[23] && a[13] == a[24] /**/ && a[5] == a[6] && a[5] == a[15] && a[5] == a[16] /**/ && a[17] == a[18] && a[17] == a[7] && a[17] == a[8]) ||\n            \n       (a[13] == a[14] && a[13] == a[15] && a[13] == a[16] /**/ && a[17] == a[18] && a[17] == a[19] && a[17] == a[20] /**/ && a[1] == a[3] && a[1] == a[6] && a[1] == a[8] /**/ && a[2] == a[4] && a[2] == a[21] && a[2] == a[23] /**/ && a[5] == a[7] && a[5] == a[10] && a[5] == a[12]) ||\n       (a[13] == a[14] && a[13] == a[15] && a[13] == a[16] /**/ && a[17] == a[18] && a[17] == a[19] && a[17] == a[20] /**/ && a[1] == a[3] && a[1] == a[22] && a[1] == a[24] /**/ && a[2] == a[4] && a[2] == a[5] && a[2] == a[7] /**/ && a[6] == a[8] && a[6] == a[9] && a[6] == a[11]) ||   \n            \n       (a[5] == a[6] && a[7] == a[5] && a[5] == a[8] /**/ && a[21] == a[22] && a[21] == a[23] && a[21] == a[24] /**/ && a[1] == a[3] && a[1] == a[18] && a[1] == a[20] /**/ && a[2] == a[4] && a[2] == a[13] && a[2] == a[15] /**/ && a[14] == a[16] && a[14] == a[9] && a[9] == a[11]) ||\n       (a[5] == a[6] && a[7] == a[5] && a[5] == a[8] /**/ && a[21] == a[22] && a[21] == a[23] && a[21] == a[24] /**/ && a[1] == a[3] && a[1] == a[14] && a[1] == a[16] /**/ && a[2] == a[4] && a[2] == a[17] && a[2] == a[19] /**/ && a[9] == a[11] && a[18] == a[9] && a[9] == a[20]) )     \n            \n\tprintf(\"YES\");\n    else\n\tprintf(\"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3b0210b1bdccb9a40fb38ce63ad1b14b", "src_uid": "881a820aa8184d9553278a0002a3b7c4", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#define LL long long\n#define uLL unsigned long long\n#define uL unsigned long\n#define uC unsigned char\nlong temp[100000];\nvoid print(long *a,long size)\n{\n\tlong i;\n\tfor (i=1;i<=size;i++)\n\t{\n\t\tprintf(\"%ld,\",a[i]);\n\t}\n\tprintf(\"\\n---\\n\");\n}\nvoid print2(long *a,long size)\n{\n\tlong i;\n\tfor (i=1;i<=size;i++)\n\t{\n\t\tprintf(\"%ld[%ld],\",a[i],i);\n\t}\n\tprintf(\"\\n---\\n\");\n}\nvoid copy(long *a,long *b)\n{\n\tlong i;for (i=0;i<=b[0];i++) {a[i]=b[i];}\n}\n///////////////////////////////////////////////////////////////\nvoid ColorTransfer(long *color,long *pol,long *ans)\n{\n\tlong i,j,k;\n\tfor (i=1;i<=pol[0];i++)\n\t{\n\t\tans[pol[i]]=color[i];\n\t}\n}\nvoid PermutationTransfer(long *pol1,long *pol2,long *ans)\n{\n\tstatic long i,j,k;\n\tfor (i=1;i<=pol1[0];i++)\n\t{\n\t\tans[i]=pol2[pol1[i]];\n\t}\n\tans[0]=pol1[0];\n}\nvoid PermutationInverse(long *pol,long *ans)\n{\n\tstatic long i,j,k;\n\tfor (i=1;i<=pol[0];i++)\n\t{\n\t\tans[pol[i]]=i;\n\t}\n\tans[0]=pol[0];\n}\nvoid PermutationFactoring(long *pol,long *ans)\n{\n\tlong i,j,k,a,b,c;\n\tlong *stack=temp;*stack=0;\n\tmemcpy(ans,pol,sizeof(pol)*(*pol+1));\n\tfor (i=1;i<*pol;i++)\n\t{\n\t\tif (ans[i]>0)\n\t\t{\n\t\t\tfor (j=i;ans[j]>0;j=stack[*stack]) {stack[++(*stack)]=ans[j];ans[j]=0;}\n\t\t\tstack[++(*stack)]=0;\n\t\t}\n\t}\n\t*ans=1;j=1;\n\tfor (i=1;i<=*stack;i++)\n\t{\n\t\tif (stack[i]>0)\n\t\t{\n\t\t\tans[++(*ans)]=stack[i];\n\t\t}\n\t\telse\n\t\t{\n\t\t\tans[j]=i-j;j=i;*ans+=1;\n\t\t}\n\t}\n}\nvoid Cycles2Permutation(long *cycles,long *ans,long len)\n{\n\tlong i,j,k;\n\tfor (i=1;i<=len;i++) {ans[i]=i;}*ans=len;\n\tk=1;\n\tfor (i=1;i<=*cycles;i++)\n\t{\n\t\tfor (j=k+1;j<k+cycles[k];j++)\n\t\t{\n\t\t\tans[cycles[j]]=cycles[j+1];\n\t\t}\n\t\tans[cycles[j]]=cycles[k+1];\n\t\tk=j+1;\n\t}\n}\n//////////////////////////////////////\n#define PPPP 50\nlong pcr[][PPPP]={{1},{6,\n\t\t\t\t   4,1,3,4,2,\n\t\t\t\t   4,9,10,12,11,\n\t\t\t\t   4,13,5,17,21,\n\t\t\t\t   4,15,7,19,23,\n\t\t\t\t   4,16,8,20,24,\n\t\t\t\t   4,14,6,18,22}};\nlong pcf[][PPPP]={{1},{6,\n\t\t\t\t   4,13,14,16,15,\n\t\t\t\t   4,17,19,20,18,\n\t\t\t\t   4,1,5,9,24,\n\t\t\t\t   4,3,6,10,23,\n\t\t\t\t   4,3,7,11,22,\n\t\t\t\t   4,4,8,12,21}};\nlong pco[][PPPP]={{1},{3,\n\t\t\t\t  4,6,5,7,8,\n\t\t\t\t  4,3,16,10,17,\n\t\t\t\t  4,4,14,9,19}};\n//////////////////////////////////////\n\nlong id[PPPP],flip[10][PPPP],rotate[10][PPPP],opr[10][PPPP],fsize,rsize,osize;\nlong gg[100][PPPP],gsize;\nlong pg[100000][PPPP],psize;\nvoid RubikCube(long size,long rt,long dep)\n{\n\tlong i,j,k,l1,l2,a,b,c;\n\tlong t1[PPPP],t2[PPPP],t3[PPPP];\n\tfor (i=1;i<=size;i++) {id[i]=i;}*id=size;\n\t//////////////////////\n\t//Basic Permutations//\n\t//////////////////////\n\trsize=**pcr<<1;\n\tfor (i=1;i<=**pcr;i++){Cycles2Permutation(pcr[i],rotate[2*i-2],size);PermutationInverse(rotate[2*i-2],rotate[2*i-1]);}\n\tfsize=**pcf<<1;\n\tfor (i=1;i<=**pcf;i++){Cycles2Permutation(pcf[i],flip[2*i-2],size);PermutationInverse(flip[2*i-2],flip[2*i-1]);}\n\tosize=**pco<<1;\n\tfor (i=1;i<=**pco;i++){Cycles2Permutation(pco[i],opr[2*i-2],size);PermutationInverse(opr[2*i-2],opr[2*i-1]);}\n\t//////////////////////\n\tgsize=0;\n\tcopy(t1,rotate[1]);copy(t3,rotate[0]);\n\tfor (i=1;i<=rt;i++)\n\t{\n\t\tPermutationTransfer(t1,rotate[0],t2);copy(t1,t2);\n\t\tPermutationTransfer(t3,rotate[1],t2);copy(t3,t2);\n\t\tfor (k=0;k<osize;k++)\n\t\t{\n\t\t\tPermutationTransfer(t1,opr[k],t2);\n\t\t\tPermutationTransfer(t2,t3,gg[++gsize]);\n\t\t\tfor (j=0;j<fsize;j++)\n\t\t\t{\n\t\t\t\tPermutationTransfer(t1,flip[j],t2);\n\t\t\t\tPermutationTransfer(t2,opr[k],gg[++gsize]);\n\t\t\t\tPermutationTransfer(gg[gsize],flip[j^1],t2);\n\t\t\t\tPermutationTransfer(t2,t3,gg[psize]);\n\t\t\t}\n\t\t}\t\t\n\t}\n\t//////////////\n\tcopy(pg[1],id);psize=1;\n\tfor (l1=psize,l2=l1;dep>0;dep-=1)\n\t{\n\t\tfor (i=l1;i<=l2;i++)\n\t\t{\n\t\t\tfor (j=1;j<=gsize;j++)\n\t\t\t{\n\t\t\t\tPermutationTransfer(pg[i],gg[j],pg[++psize]);\n\t\t\t}\n\t\t}\n\t\tl1=l2+1;l2=psize;\n\t}\n\t//////////////////////\n}\n\nint check(long *clr)\n{\n\tlong i,j,k,c;\n\tk=1;\n\tfor (i=1;i<=6;i++)\n\t{\n\t\tc=clr[k++];\n\t\tfor (j=2;j<=4;j++)\n\t\t{\n\t\t\tif (clr[k++]!=c) {return 0;}\n\t\t}\n\t}\n\treturn 1;\n}\n//////////////////////////////////////////////////\nint main()\n{\n//\tfreopen(\"in.in\",\"r\",stdin);\n\tlong i,j,k,a,b,c;\n\tlong t1[PPPP],t2[PPPP],t3[PPPP];\n\tRubikCube(24,4,1);\n\tt1[0]=24;\n\tfor (i=1;i<=24;i++)\n\t{\n\t\tscanf(\"%ld\",&t1[i]);\n\t}\n\tfor (i=1;i<=psize;i++)\n\t{\t\t\n\t\tColorTransfer(t1,pg[i],t2);\n//\t\tprint(t2,24);\n\t\tif (check(t2)==1) {printf(\"YES\\n\");return 0;}\n\t}\n\tprintf(\"NO\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "342c6bf8bff65183c5550b77fa2754a8", "src_uid": "881a820aa8184d9553278a0002a3b7c4", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint a1[] = { 1, 2, 1, 2, 3, 1, 3, 1, 4, 3, 4, 3, 5, 5, 5, 5, 6, 6, 6, 6, 4, 2, 4, 2 };\n\nint a2[] = { 2, 1, 2, 1, 1, 3, 1, 3, 3, 4, 3, 4, 5, 5, 5, 5, 6, 6, 6, 6, 2, 4, 2, 4 };\n\nint a3[] = { 1, 2, 1, 2, 3, 4, 3, 4, 2, 1, 2, 1, 5, 5, 5, 5, 6, 6, 6, 6, 1, 2, 1, 2 };\n\n#define N\t24\n\nint check_(int *aa, int *bb) {\n\tstatic int match[7], used[7];\n\tint i;\n\n\tfor (i = 1; i <= 6; i++)\n\t\tmatch[i] = -1;\n\tmemset(used, 0, sizeof used);\n\tfor (i = 0; i < N; i++) {\n\t\tif ((match[aa[i]] == -1 && used[bb[i]]) || (match[aa[i]] != -1 && match[aa[i]] != bb[i]))\n\t\t\treturn 0;\n\t\tused[bb[i]] = 1;\n\t\tmatch[aa[i]] = bb[i];\n\t}\n\treturn 1;\n}\n\nint check(int *aa) {\n\treturn check_(aa, a1) || check_(aa, a2) || check_(aa, a3) || check_(aa, a4);\n}\n\nint main() {\n\tstatic int aa[N], bb[N], cc[N];\n\tint i;\n\n\tfor (i = 0; i < N; i++)\n\t\tscanf(\"%d\", &aa[i]);\n\tbb[0] = aa[1], bb[1] = aa[3], bb[2] = aa[0], bb[3] = aa[2];\n\tbb[4] = aa[12], bb[5] = aa[13], bb[6] = aa[14], bb[7] = aa[15];\n\tbb[8] = aa[10], bb[9] = aa[8], bb[10] = aa[11], bb[11] = aa[9];\n\tbb[12] = aa[20], bb[13] = aa[21], bb[14] = aa[22], bb[15] = aa[23];\n\tbb[16] = aa[4], bb[17] = aa[5], bb[18] = aa[6], bb[19] = aa[7];\n\tbb[20] = aa[16], bb[21] = aa[17], bb[22] = aa[18], bb[23] = aa[19];\n\tcc[0] = aa[14], cc[1] = aa[12], cc[2] = aa[15], cc[3] = aa[13];\n\tcc[4] = aa[6], cc[5] = aa[4], cc[6] = aa[7], cc[7] = aa[5];\n\tcc[8] = aa[18], cc[9] = aa[16], cc[10] = aa[19], cc[11] = aa[17];\n\tcc[12] = aa[10], cc[13] = aa[8], cc[14] = aa[11], cc[15] = aa[9];\n\tcc[16] = aa[2], cc[17] = aa[0], cc[18] = aa[3], cc[19] = aa[1];\n\tcc[20] = aa[21], cc[21] = aa[23], cc[22] = aa[20], cc[23] = aa[22];\n\tprintf(!check(aa) && !check(bb) && !check(cc) ? \"NO\\n\" : \"YES\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "6d786cfc53c8747b0324b4f77f20cfa8", "src_uid": "881a820aa8184d9553278a0002a3b7c4", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n\tint n;\n\tscanf(\"%d\",&n);\n\tint r[101]={0};\n\tscanf(\"%d\",&r[0]);\n\tint no=0;\n\tfor(int i=1 ;i<n; i++){\n\t\tscanf(\"%d\",&r[i]);\n\t\tif(r[i]<r[i-1]) {\n\t\t\tno++;\n\t\t}\n\t}\n\tif(no==0) printf(\"YES\");\n\telse printf(\"NO\");\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7cb7e370eec3f4862dfc1a02a883fd3b", "src_uid": "704d0ae50bccaa8bc49319812ae0be45", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main() {\n    int numeros, i, max, array[10], posmax=0, j;\n    scanf(\"%i\", &numeros);\n    scanf(\"%i\", &max);\n    array[0]=max;\n    for (i=1;i<numeros;i++)\n    {\n        scanf(\"%i\", &array[i]);\n        if (array[i] > max)\n        {\n            max = array[i];\n            posmax = i;\n        }\n    }\n    do\n    {\n        posmax=0;\n        array[0]=max;\n        for (j=1;j<numeros;j++)\n        {\n            if (array[j] > max) {\n                max=array[j];\n                posmax = j;\n            }\n        }\n        if(numeros==1)\n        {\n            printf(\"YES\");\n            return 0;\n        }\n        else if(posmax==0 && numeros>1)\n        {\n            if(((array[posmax]+1)<array[posmax+1]) || ((array[posmax]-1)>array[posmax+1]))\n            {\n                printf(\"NO\");\n                return 0;\n            }\n            else\n            {\n                for(i=posmax;i<numeros;i++)\n                {\n                    array[i]=array[i+1];\n                }\n                numeros--;\n            }\n        }\n        else if(posmax==(numeros-1) && numeros>1)\n        {\n            if(((array[posmax]+1)<array[posmax-1]) || ((array[posmax]-1)>array[posmax-1]))\n            {\n                printf(\"NO\");\n                return 0;\n            }\n            else\n            {\n                for(i=posmax;i<numeros;i++)\n                {\n                    array[i]=array[i+1];\n                }\n                numeros--;\n            }\n        }\n        else\n        {\n            if(((array[posmax]+1)<array[posmax-1]) || ((array[posmax]-1)>array[posmax-1]) || ((array[posmax]+1)<array[posmax+1]) || ((array[posmax]-1)>array[posmax+1]))\n            {\n                printf(\"NO\");\n                return 0;\n            }\n            else\n            {\n                for(i=posmax;i<numeros;i++)\n                {\n                    array[i]=array[i+1];\n                }\n                numeros--;\n            }\n        }\n    }while (numeros>0);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "df0321ce1fb07d7a80c86b6c12c3d10a", "src_uid": "704d0ae50bccaa8bc49319812ae0be45", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint a[15];\n\nint main(){\n\tint i=1,n;\n\tscanf(\"%d\",&n);\n\twhile(i<=n)\n\t\tscanf(\"%d\",&a[i]);\n\ti=2;\n\twhile(i<=n){\n\t\tif(abs(a[i] - a[i-1]) >= 2){\n\t\t\tprintf(\"NO\\n\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\"YES\\n\");\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "296d05eb32f2cada019d23082817ff49", "src_uid": "704d0ae50bccaa8bc49319812ae0be45", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint a[15];\n\nint main(){\n\tint i=1,n;\n\tscanf(\"%d\",&n);\n\twhile(i<=n)\n\t\tscanf(\"%d\",&a[i]);\n\ti=2;\n\twhile(i<=n){\n\t\tif(abs(a[i] - a[i-1]) >= 2){\n\t\t\tprintf(\"NO\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\ti++;\n\t}\n\tprintf(\"YES\\n\");\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f7d2a409e3789ed573710c46e42a1ded", "src_uid": "704d0ae50bccaa8bc49319812ae0be45", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint abs(int x,int y){\n    if(x>y){\n        return (x-y);\n    }\n    else{\n        return (y-x);\n    }\n}\n\nint main(){\n    int n,i,f=0;\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++){\n        scanf(\"%d\",&a[i]);\n    }\n    for(i=0;i<n-1;i++){\n        if(abs(a[i],a[i+1])>1){\n            f=1;\n            break;\n        }\n    }\n    if(f==0){\n        printf(\"YES\");\n    }\n    else{\n        printf(\"NO\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "13b2b66419a51e3a835305f43a7bff89", "src_uid": "704d0ae50bccaa8bc49319812ae0be45", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "/* upsolve with Dukkha */\n#include <math.h>\n#include <stdio.h>\n#include <stdlib.h>\n#include <sys/time.h>\n\n#define M\t100000\n\nint min(int a, int b) { return a < b ? a : b; }\nint max(int a, int b) { return a > b ? a : b; }\n\nvoid srand_() {\n\tstruct timeval tv;\n\n\tgettimeofday(&tv, NULL);\n\tsrand(tv.tv_sec ^ tv.tv_usec);\n}\n\nint rand_(int n) {\n\treturn (rand() * 76543LL + rand()) % n;\n}\n\nint compare(const void *a, const void *b) {\n\tint ia = *(int *) a;\n\tint ib = *(int *) b;\n\n\treturn ia - ib;\n}\n\nint compress(int *aa, int n) {\n\tint i, j, tmp, m;\n\n\tfor (i = 0; i < n; i++) {\n\t\tj = rand_(i + 1);\n\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\t}\n\tqsort(aa, n, sizeof *aa, compare);\n\tm = 1;\n\tfor (i = 1; i < n; i++)\n\t\tif (aa[i] != aa[i - 1])\n\t\t\taa[m++] = aa[i];\n\treturn m;\n}\n\nint main() {\n\tstatic int gg[M];\n\tint a, b, n, s, g, k, m, h, al, ar, bl, br, l, r, ans;\n\n\tsrand_();\n\tscanf(\"%d%d\", &a, &b);\n\tn = a + b;\n\ts = (int) sqrt(n) + 1;\n\tm = 0;\n\tfor (g = 1; g <= s; g++)\n\t\tgg[m++] = g;\n\tfor (k = 1; k <= s; k++) {\n\t\tg = n / k;\n\t\tgg[m++] = g;\n\t}\n\tm = compress(gg, m);\n\tans = 0;\n\tfor (h = 0; h < m; h++) {\n\t\tg = gg[h];\n\t\tal = (a + (long long) g) / (g + 1);\n\t\tbl = (b + (long long) g) / (g + 1);\n\t\tar = a / g;\n\t\tbr = b / g;\n\t\tif (al <= ar && bl <= br) {\n\t\t\tl = max(n / (g + 1) + 1, al + bl);\n\t\t\tr = min(n / g, ar + br);\n\t\t\tif (l <= r)\n\t\t\t\tans += r - l + 1;\n\t\t}\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3342986cf34f39096b6c0f47b5112d84", "src_uid": "0e6a204565fef118ea99d2fa1e378dd0", "difficulty": 2700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main() {\n\tint a, b, n, p, k, k_, cnt, lower, upper, l, r;\n\n\tscanf(\"%d%d\", &a, &b);\n\tn = a + b;\n\tcnt = 0;\n\tfor (p = 1; p <= (k = n / p); p++)\n\t\tif (a / k >= a % k && a % k <= n % p)\n\t\t\tcnt++;\n\tk_ = k;\n\tfor (k = 1; k <= k_; k++)\n\t\tif (a / k >= a % k) {\n\t\t\tlower = 0, upper = n + 1;\n\t\t\twhile (upper - lower > 1) {\n\t\t\t\tp = ((long long) lower + upper) / 2;\n\t\t\t\tif (a % k <= n - (long long) k * p)\t/* n % p = n - k * p */\n\t\t\t\t\tlower = p;\n\t\t\t\telse\n\t\t\t\t\tupper = p;\n\t\t\t}\n\t\t\tr = lower;\n\t\t\tlower = 0, upper = n + 1;\n\t\t\twhile (upper - lower > 1) {\n\t\t\t\tp = ((long long) lower + upper) / 2;\n\t\t\t\tif (n / p <= k)\n\t\t\t\t\tupper = p;\n\t\t\t\telse\n\t\t\t\t\tlower = p;\n\t\t\t}\n\t\t\tl = p = upper;\n\t\t\tcnt += l <= r ? r - l + 1 : 0;\n\t\t}\n\tprintf(\"%d\\n\", cnt);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3f3ef75033b2d06be2853dd2bc839594", "src_uid": "0e6a204565fef118ea99d2fa1e378dd0", "difficulty": 2700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main() {\n\tint a, b, n, p, k, cnt;\n\n\tscanf(\"%d%d\", &a, &b);\n\tn = a + b;\n\tcnt = 0;\n\tfor (p = 1; p <= n; p++) {\n\t\tk = n / p;\n\t\tif (a / k >= a % k && a % k <= n % p)\n\t\t\tcnt++;\n\t}\n\tprintf(\"%d\\n\", cnt);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "58582567931fdc167dc55a142e81ae4d", "src_uid": "0e6a204565fef118ea99d2fa1e378dd0", "difficulty": 2700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\n\n\nstatic char sky[400][400];\nint n, mas[30], k, q1, q2;\n\nstruct line{\n\tint type;\n\tint x;\n\tint y;\n};\n\nint max(int a, int b){\n\treturn a > b ? a : b;\n}\n\nint min(int a, int b){\n\treturn a < b ? a : b;\n}\n\nvoid draw(int i, int a, int x, int y){\n\tk = mas[i - 1];\n\twhile (k){\n\t\tk--;\n\t\tsky[y][x] = 1;\n\t\tif (k){\n\t\t\tif (a == 1){\n\t\t\t\ty++;\n\t\t\t} else if (a == 2){\n\t\t\t\tx++;\n\t\t\t\ty++;\n\t\t\t} else if (a == 3){\n\t\t\t\tx++;\n\t\t\t} else if (a == 4){\n\t\t\t\tx++;\n\t\t\t\ty--;\n\t\t\t} else if (a == 5){\n\t\t\t\ty--;\n\t\t\t} else if (a == 6){\n\t\t\t\tx--;\n\t\t\t\ty--;\n\t\t\t} else if (a == 7){\n\t\t\t\tx--;\n\t\t\t} else if (a == 8){\n\t\t\t\tx--;\n\t\t\t\ty++;\n\t\t\t}\n\t\t}\n\t}\n\tif (i < n){\n\t\tif (a == 1){\n\t\t\tdraw(i + 1, 8, x - 1, y + 1);\n\t\t\tdraw(i + 1, 2, x + 1, y + 1);\n\t\t} else if (a == 2){\n\t\t\tdraw(i + 1, 1, x, y + 1);\n\t\t\tdraw(i + 1, 3, x + 1, y);\n\t\t} else if (a == 3){\n\t\t\tdraw(i + 1, 2, x + 1, y + 1);\n\t\t\tdraw(i + 1, 4, x + 1, y - 1);\n\t\t} else if (a == 4){\n\t\t\tdraw(i + 1, 3, x + 1, y);\n\t\t\tdraw(i + 1, 5, x, y - 1);\n\t\t} else if (a == 5){\n\t\t\tdraw(i + 1, 4, x + 1, y - 1);\n\t\t\tdraw(i + 1, 6, x - 1, y - 1);\n\t\t} else if (a == 6){\n\t\t\tdraw(i + 1, 5, x, y - 1);\n\t\t\tdraw(i + 1, 7, x - 1, y);\n\t\t} else if (a == 7){\n\t\t\tdraw(i + 1, 6, x - 1, y - 1);\n\t\t\tdraw(i + 1, 8, x - 1, y + 1);\n\t\t} else if (a == 8){\n\t\t\tdraw(i + 1, 7, x - 1, y);\n\t\t\tdraw(i + 1, 1, x, y + 1);\n\t\t}\n\t}\n}\n\nvoid mirror(int a, int x, int y){\n\tif (a == 1 || a == 5){\n\t\tq1 = min(400, 2 * x + 1);\n\t\tfor (int i = max(0, 2 * x - 399); i < q1; i++){\n\t\t\tfor (int j = 0; j < 400; j++){\n\t\t\t\tsky[j][i] |= sky[j][2 * x - i];\n\t\t\t}\n\t\t}\n\t} else if (a == 3 || a == 7){\n\t\tq1 = min(400, 2 * y + 1);\n\t\tfor (int i = max(0, 2 * y - 399); i < q1; i++){\n\t\t\tfor (int j = 0; j < 400; j++){\n\t\t\t\tsky[i][j] |= sky[2 * y - i][j];\n\t\t\t}\n\t\t}\n\t} else if (a == 2 || a == 6){\n\t\tq1 = min(400, 400 + y - x);\n\t\tq2 = min(400, 400 - y + x);\n\t\tfor (int i = max(0, y - x); i < q1; i++){\n\t\t\tfor (int j = max(0, x - y); j < q2; j++){\n\t\t\t\tsky[i][j] |= sky[y - x + j][x - y + i];\n\t\t\t}\n\t\t}\n\t} else {\n\t\tq1 = min(400, x + y + 1);\n\t\tfor (int i = max(0, y + x - 399); i < q1; i++){\n\t\t\tfor (int j = max(0, x + y - 399); j < q1; j++){\n\t\t\t\tsky[i][j] |= sky[x + y - j][x + y - i];\n\t\t\t}\n\t\t}\n\t}\n}\n\nvoid draw2(int i, int a, int x2, int y2){\n\tif (i == n){\n\t\treturn;\n\t}\n\tint x = x2, y = y2;\n\tk = mas[i];\n\twhile (k){\n\t\tk--;\n\t\t//sky[y][x] = 1;\n\t\tif (k){\n\t\t\tif (a == 1){\n\t\t\t\ty++;\n\t\t\t} else if (a == 2){\n\t\t\t\tx++;\n\t\t\t\ty++;\n\t\t\t} else if (a == 3){\n\t\t\t\tx++;\n\t\t\t} else if (a == 4){\n\t\t\t\tx++;\n\t\t\t\ty--;\n\t\t\t} else if (a == 5){\n\t\t\t\ty--;\n\t\t\t} else if (a == 6){\n\t\t\t\tx--;\n\t\t\t\ty--;\n\t\t\t} else if (a == 7){\n\t\t\t\tx--;\n\t\t\t} else if (a == 8){\n\t\t\t\tx--;\n\t\t\t\ty++;\n\t\t\t}\n\t\t}\n\t}\n\n\t\tif (a == 1){\n\t\t\tdraw2(i + 1, 2, x + 1, y + 1);\n\t\t} else if (a == 2){\n\t\t\tdraw2(i + 1, 3, x + 1, y);\n\t\t} else if (a == 3){\n\t\t\tdraw2(i + 1, 4, x + 1, y - 1);\n\t\t} else if (a == 4){\n\t\t\tdraw2(i + 1, 5, x, y - 1);\n\t\t} else if (a == 5){\n\t\t\tdraw2(i + 1, 6, x - 1, y - 1);\n\t\t} else if (a == 6){\n\t\t\tdraw2(i + 1, 7, x - 1, y);\n\t\t} else if (a == 7){\n\t\t\tdraw2(i + 1, 8, x - 1, y + 1);\n\t\t} else if (a == 8){\n\t\t\tdraw2(i + 1, 1, x, y + 1);\n\t\t}\n\n\tmirror(a, x, y);\n\n\tx = x2, y = y2;\n\tk = mas[i];\n\twhile (k){\n\t\tk--;\n\t\tsky[y][x] = 1;\n\t\tif (k){\n\t\t\tif (a == 1){\n\t\t\t\ty++;\n\t\t\t} else if (a == 2){\n\t\t\t\tx++;\n\t\t\t\ty++;\n\t\t\t} else if (a == 3){\n\t\t\t\tx++;\n\t\t\t} else if (a == 4){\n\t\t\t\tx++;\n\t\t\t\ty--;\n\t\t\t} else if (a == 5){\n\t\t\t\ty--;\n\t\t\t} else if (a == 6){\n\t\t\t\tx--;\n\t\t\t\ty--;\n\t\t\t} else if (a == 7){\n\t\t\t\tx--;\n\t\t\t} else if (a == 8){\n\t\t\t\tx--;\n\t\t\t\ty++;\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main(void)\n{\n\tfor (int i = 0; i < 400; i++){\n\t\tfor (int j = 0; j < 400; j++){\n\t\t\tsky[i][j] = 0;\n\t\t}\n\t}\n\tscanf(\"%d\", &n);\n\tfor (int i = 0; i < n; i++){\n\t\tscanf(\"%d\", &mas[i]);\n\t}\n\tdraw2(0, 1, 200, 200);\n\tint rez = 0;\n\tfor (int i = 0; i < 400; i++){\n\t\tfor (int j = 0; j < 400; j++){\n\t\t\t//printf(\"%d\", sky[i][j]);\n\t\t\trez += sky[i][j];\n\t\t}\n\t\t//printf(\"\\n\");\n\t}\n\tprintf(\"%d\", rez);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c92ef9a6c2186a82fe298696f9c1950c", "src_uid": "a96bc7f93fe9d9d4b78018b49bbc68d9", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nvoid blast(int, int, int, int);\n\nint grid[301][301], dp[301][301][30][8] = {0}, n, t[31];\n\nint main(){\n  int i, j, k;\n  scanf(\"%d\", &n);\n  for(i=0;i<301;i++){\n    for(j=0;j<301;j++){\n      grid[i][j] = 0;\n    }\n  }\n\n  for(i=0;i<n;i++){\n    scanf(\"%d\", t+i);\n  }\n  //  grid[150][150] = 1;\n  blast(0, 0, 0, 0);\n  k=0;\n  for(i=0;i<301;i++){\n    for(j=0;j<301;j++){\n      if(grid[i][j]){\n\tk++;\n      }\n    }\n  }\n  printf(\"%d\\n\", k);\n  return 0;\n}\n\nvoid blast(int x, int y, int level, int dir){\n  int i;\n  if(level >= n)\n    return;\n  if(dp[150 + x][150 + y][level][dir])\n    return;\n  dp[150 + x][150 + y][level][dir] = 1;\n  for(i = 0;i < t[level];i++){\n    if(dir == 0 || dir == 1 || dir == 7){\n      x--;\n    }\n    if(dir == 1 || dir == 2 || dir == 3){\n      y--;\n    }\n    if(dir == 3 || dir == 4 || dir == 5){\n      x++;\n    }\n    if(dir == 5 || dir == 6 || dir == 7){\n      y++;\n    }\n    grid[150 + x][150 + y] = 1;\n  }\n  blast(x, y, level + 1, (dir + 1)%8);\n  blast(x, y, level + 1, (dir + 7)%8);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "641505380145d60bf7c9b95d4eda4d6e", "src_uid": "a96bc7f93fe9d9d4b78018b49bbc68d9", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define QLEN 6400007\n\nint n,ans,D[35];\n\nint q[6400010][5],head,tail;\nshort vis[410][410][8][2];\nshort MAP[410][410];\n\nshort dir[8][2] = {-1,0,-1,1,0,1,1,1,1,0,1,-1,0,-1,-1,-1};\n\nvoid add(int i,int j,int k,int d,int now)\n{\n    if(vis[i][j][k][d&1]) return;\n    vis[i][j][k][d&1] = 1; MAP[i][j] = 1;\n    q[tail][0] = i; q[tail][1] = j; q[tail][2] = k; q[tail][3] = d; q[tail++][4] = now;\n    if(tail > QLEN) tail = 1;\n}\n\nvoid bfs(int SI,int SJ)\n{\n    int i,j,k,d,now;\n    int ii,jj,kk;\n    head = 1; tail = 1;\n    add(SI,SJ,0,D[1],1);\n    \n    while(head != tail)\n    {\n        i = q[head][0]; j = q[head][1]; k = q[head][2];\n        d = q[head][3]; now = q[head++][4];\n        vis[i][j][k][d&1] = 0;\n        if(d-1 != D[now+1])\n        {\n            ii = i+dir[k][0]; jj = j+dir[k][1];\n            add(ii,jj,k,d-1,now);\n        }\n        else\n        {\n            if(now == n) continue;\n            kk = (k+7)%8; ii = i+dir[kk][0]; jj = j+dir[kk][1];\n            add(ii,jj,kk,d-1,now+1);\n            kk = (k+1)%8; ii = i+dir[kk][0]; jj = j+dir[kk][1];\n            add(ii,jj,kk,d-1,now+1);\n        }\n        if(head > QLEN) head = 1;\n    }\n}\n\nint main()\n{\n    int i,j;\n    scanf(\"%d\",&n);\n    for(i=1;i<=n;i++) scanf(\"%d\",&D[i]);\n    for(i=n-1;i;i--) D[i] += D[i+1];\n    \n    bfs(200,200);\n    for(i=1;i<=400;i++) for(j=1;j<=400;j++) if(MAP[i][j]) ans++;\n    printf(\"%d\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "dc4a6f704d3d4033a62d63b82964dc9d", "src_uid": "a96bc7f93fe9d9d4b78018b49bbc68d9", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define N\t30\n#define M\t301\n#define D\t8\n\nint n, m;\nint xx[] = { 0, 1, 1, 1, 0, -1, -1, -1 };\nint yy[] = { 1, 1, 0, -1, -1, -1, 0, 1 };\nint tt[N], aa[M][M][N][D], bb[M][M];\n\nvoid dfs(int x, int y, int i, int d) {\n\tint dx, dy, s, t;\n\n\tif (i == n)\n\t\treturn;\n\tif (aa[x][y][i][d])\n\t\treturn;\n\taa[x][y][i][d] = 1;\n\tdx = xx[d];\n\tdy = yy[d];\n\tt = tt[i];\n\tfor (s = 1; s <= t; s++)\n\t\tbb[x + dx * s][y + dy * s] = 1;\n\tx += dx * t;\n\ty += dy * t;\n\tdfs(x, y, i + 1, (d + 1) % 8);\n\tdfs(x, y, i + 1, (d + 7) % 8);\n}\n\nint main() {\n\tint s, i, j, cnt;\n\n\tscanf(\"%d\", &n);\n\ts = 0;\n\tfor (i = 0; i < n; i++) {\n\t\tscanf(\"%d\", &tt[i]);\n\t\ts += tt[i];\n\t}\n\tm = s + s + 1;\n\tdfs(s, s, 0, 0);\n\tcnt = 0;\n\tfor (i = 0; i < m; i++)\n\t\tfor (j = 0; j < m; j++)\n\t\t\tif (bb[i][j])\n\t\t\t\tcnt++;\n\tprintf(\"%d\\n\", cnt);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d9f90c533274f749d62ec855f06d0912", "src_uid": "a96bc7f93fe9d9d4b78018b49bbc68d9", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nstatic char sky[400][400];\nint n, mas[30], k;\n\nvoid draw(int i, int a, int x, int y){\n\tk = mas[i - 1];\n\twhile (k){\n\t\tk--;\n\t\tsky[y][x] = 1;\n\t\tif (k){\n\t\t\tif (a == 1){\n\t\t\t\ty++;\n\t\t\t} else if (a == 2){\n\t\t\t\tx++;\n\t\t\t\ty++;\n\t\t\t} else if (a == 3){\n\t\t\t\tx++;\n\t\t\t} else if (a == 4){\n\t\t\t\tx++;\n\t\t\t\ty--;\n\t\t\t} else if (a == 5){\n\t\t\t\ty--;\n\t\t\t} else if (a == 6){\n\t\t\t\tx--;\n\t\t\t\ty--;\n\t\t\t} else if (a == 7){\n\t\t\t\tx--;\n\t\t\t} else if (a == 8){\n\t\t\t\tx--;\n\t\t\t\ty++;\n\t\t\t}\n\t\t}\n\t}\n\tif (i < n){\n\t\tif (a == 1){\n\t\t\tdraw(i + 1, 8, x - 1, y + 1);\n\t\t\tdraw(i + 1, 2, x + 1, y + 1);\n\t\t} else if (a == 2){\n\t\t\tdraw(i + 1, 1, x, y + 1);\n\t\t\tdraw(i + 1, 3, x + 1, y);\n\t\t} else if (a == 3){\n\t\t\tdraw(i + 1, 2, x + 1, y + 1);\n\t\t\tdraw(i + 1, 4, x + 1, y - 1);\n\t\t} else if (a == 4){\n\t\t\tdraw(i + 1, 3, x + 1, y);\n\t\t\tdraw(i + 1, 5, x, y - 1);\n\t\t} else if (a == 5){\n\t\t\tdraw(i + 1, 4, x + 1, y - 1);\n\t\t\tdraw(i + 1, 6, x - 1, y - 1);\n\t\t} else if (a == 6){\n\t\t\tdraw(i + 1, 5, x, y - 1);\n\t\t\tdraw(i + 1, 7, x - 1, y);\n\t\t} else if (a == 7){\n\t\t\tdraw(i + 1, 6, x - 1, y - 1);\n\t\t\tdraw(i + 1, 8, x - 1, y + 1);\n\t\t} else if (a == 8){\n\t\t\tdraw(i + 1, 7, x - 1, y);\n\t\t\tdraw(i + 1, 1, x, y + 1);\n\t\t}\n\t}\n}\n\nint main(void)\n{\n\tfor (int i = 0; i < 400; i++){\n\t\tfor (int j = 0; j < 400; j++){\n\t\t\tsky[i][j] = 0;\n\t\t}\n\t}\n\tscanf(\"%d\", &n);\n\tfor (int i = 0; i < n; i++){\n\t\tscanf(\"%d\", &mas[i]);\n\t}\n\tdraw(1, 1, 200, 200);\n\tint rez = 0;\n\tfor (int i = 0; i < 400; i++){\n\t\tfor (int j = 0; j < 400; j++){\n\t\t\t//printf(\"%d\", sky[i][j]);\n\t\t\trez += sky[i][j];\n\t\t}\n\t\t//printf(\"\\n\");\n\t}\n\tprintf(\"%d\", rez);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "31c70987dcefe0e669dd3c3724942b3b", "src_uid": "a96bc7f93fe9d9d4b78018b49bbc68d9", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nstruct node\n{\n    int attack,defence;\n}play[5];\nint main()\n{\n    int i,j,k,sum;\n    while(scanf(\"%d%d\",&play[0].defence,&play[0].attack)!=EOF)\n    {\n        for(i=1;i<4;i++)\n        {\n            scanf(\"%d%d\",&play[i].defence,&play[i].attack);\n        }\n        for(i=0,k=0;i<=1;i++)\n        {\n            for(j=2;j<=3;j++)\n            {\n                if(play[i].attack<=play[j].defence||play[i^1].defence<=play[j].attack)\n                break;\n            }\n            if(j==4)\n            {\n               k=1;break;\n\n            }\n        }\n        if(k==0)\n        for(i=2,k=0;i<=3;i++)\n        {\n            for(j=0;j<=1;j++)\n            {\n                if(play[i].attack>play[j].defence||play[i^1].defence>play[j].attack)\n                break;\n            }\n            if(j<2)\n            {\n               k=2;break;\n            }\n        }\n        if(k==1)\n        printf(\"Team 1\\n\");\n        else\n        if(k==2)\n        printf(\"Team 2\\n\");\n        else\n        printf(\"Draw\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4c67483ce9a4191177bd78327710dd1c", "src_uid": "1a70ed6f58028a7c7a86e73c28ff245f", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n   int a[4][2],i,j,team1=0,team2=0;\n   for(i=0;i<4;i++){\n    scanf(\"%d %d\",&a[i][0],&a[i][1]);\n   }\n\n   if(a[0][0]>a[3][1]&&a[1][1]>a[2][0]&&a[0][0]>a[3][1]&&a[1][1]>a[3][0]){\n      printf(\"Team 1\");\n      return 0;\n   }\n   if(a[1][0]>a[3][1]&&a[0][1]>a[2][0]&&a[1][0]>a[3][1]&&a[0][1]>a[3][0]){\n     printf(\"Team 1\");\n      return 0;\n   }\n   if(a[2][0]>a[1][1]&&a[3][1]>a[0][0]){\n      printf(\"Team 2\");\n      return 0;\n   }\n   if(a[2][0]>a[0][1]&&a[3][1]>a[1][0]){\n    printf(\"Team 2\");\n      return 0;\n   }\n   if(a[3][0]>a[1][1]&&a[2][1]>a[0][0]){\n    printf(\"Team 2\");\n      return 0;\n   }\n   if(a[3][0]>a[0][1]&&a[2][1]>a[1][0]){\n    printf(\"Team 2\");\n      return 0;\n   }\n   printf(\"Draw\\n\");\n return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "af565a1f499237a6ae289b8bafc1a8f5", "src_uid": "1a70ed6f58028a7c7a86e73c28ff245f", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define TEAM1\t1\n#define\tTEAM2\t2\n#define\tDRAW\t0\n\ntypedef struct {\n\tint att, def;\n} player;\n\nint main( void ) {\n\tplayer p[4];\n\tplayer t1[2], t2[2];\n\tint result = DRAW;\n\tint i;\n\t\n\tfor( i = 0; i < 4; i++ )\n\t\tscanf(\"%i %i\", &p[i].def, &p[i].att);\n\n\tt1[0].att = p[0].att, t1[0].def = p[1].def;\n\tt1[1].att = p[1].att, t1[1].def = p[0].def;\n\t\n\tt2[0].att = p[2].att, t2[1].def = p[3].def;\n\tt2[1].att = p[3].att, t2[0].def = p[2].def;\n\t\n\tfor( i = 0; i < 1; i++ )\n\t\tif( (t1[i].def > t2[0].def) && (t1[i].att > t2[0].att) && (t1[i].def > t2[1].def) && (t1[i].att > t2[1].att) ) {\n\t\t\tresult = TEAM1;\n\t\t\tbreak;\n\t\t}\n\t\n\tfor( i = 0; i < 1; i++ )\n\t\tif( ((t1[i].def < t2[0].def) && (t1[i].att < t2[0].att)) || ((t1[i].def < t2[1].def) && (t1[i].att < t2[1].att)) )\n\t\t\t;\n\t\telse\tbreak;\n\n\tif( i == 1 )\tresult = TEAM2;\n\t\t\n\tswitch( result ) {\n\t\tcase TEAM1:\n\t\t\tprintf(\"Team 1\");\n\t\t\tbreak;\n\t\tcase TEAM2:\n\t\t\tprintf(\"Team 2\");\n\t\t\tbreak;\n\t\tdefault:\n\t\t\tprintf(\"Draw\");\n\t\t\tbreak;\n\t}\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4c523509dab63485811bcb83d63cea8b", "src_uid": "1a70ed6f58028a7c7a86e73c28ff245f", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nvoid swap(int a[],int b[])\n{\n    int t;\n    t=a[0];\n    a[0]=b[0];\n    b[0]=t;\n    t=a[1];\n    a[1]=b[1];\n    b[1]=t;\n}\nint main()\n{\n    int a[2][2],b[2][2];\n    scanf(\"%d%d\",&a[0][0],&a[0][1]);\n    scanf(\"%d%d\",&a[1][0],&a[1][1]);\n    scanf(\"%d%d\",&b[0][0],&b[0][1]);\n    scanf(\"%d%d\",&b[1][0],&b[1][1]);\n\n   if(((a[0][0]>b[1][1]&&a[1][1]>b[0][0])&&(a[0][0]>b[0][1]&&a[1][1]>b[1][0]))||(((a[1][0]>b[0][1]&&a[0][1]>b[1][0]))&&(a[1][0]>b[1][1]&&a[0][1]>b[0][0])))\n   {\n       printf(\"Team 1\\n\");\n   }\n   else if(((a[0][0]<b[1][1]&&a[1][1]<b[0][0])||(a[1][0]<b[1][1]&&a[0][1]<b[0][0]))&&((a[1][0]<b[0][1]&&a[0][1]<b[1][0])||(a[0][0]<b[0][1]&&a[1][1]<b[1][0])))\n   {\n       printf(\"Team 2\\n\");\n   }\n   else\n   printf(\"Draw\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "556e82e410cc6cc952e58d940c10f57f", "src_uid": "1a70ed6f58028a7c7a86e73c28ff245f", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(){\n    int i,j,k,l,a[3],b[3],c[3],d[3];\n    while(1){\n        for(i=0;i<2;i++)\n        scanf(\"%d\",&a[i]);\n        for(i=0;i<2;i++)\n        scanf(\"%d\",&b[i]);\n        for(i=0;i<2;i++)\n        scanf(\"%d\",&c[i]);\n        for(i=0;i<2;i++)\n        scanf(\"%d\",&d[i]);\n        if((a[0]>c[1]&&a[0]>d[1]&&b[1]>c[0]&&b[1]>d[0])||(a[1]>c[0]&&a[1]>d[0]&&b[0]>c[1]&&b[0]>d[1]))\n            printf(\"Team 1\\n\");\n        else\n        if((((a[0]<c[1])&&(b[1]<d[0]))||((a[0]<d[1])&&(b[1]<c[0])))&&(((a[1]<c[0])&&(b[0]<d[1]))||((a[1]<d[0])&&(b[0]<c[1]))))\n            printf(\"Team 2\\n\");\n         else printf(\"Draw\\n\");\n    }\n\nreturn 0;}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6936eab9717509f661da51fc5ebbd81c", "src_uid": "1a70ed6f58028a7c7a86e73c28ff245f", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n#include <ctype.h>\n#include <string.h>\n\ndouble a, i, x, sum;\n\nint main(){\n    scanf(\"%lf\", &a);\n    sum = 0;\n    for (i=0; i<a; i++){\n        scanf(\"%lf\", &x);\n        sum += x;\n    }\n    if (sum<0) sum = -sum;\n    printf(\"%lf\\n\", sum/a);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "52538380db93a66922ffd0041be930c0", "src_uid": "32fc378a310ca15598377f7b638eaf26", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n#include <ctype.h>\n#include <string.h>\n\ndouble a, i, x, sum;\n\nint main(){\n    scanf(\"%lf\", &a);\n    sum = 0;\n    for (i=0; i<a; i++){\n        scanf(\"%lf\", &x);\n        sum += x;\n    }\n    printf(\"%lf\\n\", sum/a);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "84da85a5cf7d9ee131ce144d6f45e571", "src_uid": "32fc378a310ca15598377f7b638eaf26", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MAXN 33\nint main()\n{\n    double sum=0;\n    double a[MAXN];\n    int n=0,i=0;\n    while(scanf(\"%lf\",&a[n])!=EOF)\n    {\n        n++;\n    }\n    for(i=1;i<=n;i++)\n        sum+=a[i];\n    printf(\"%.6lf\",sum/a[0]);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8d9264c20933eeda79203af65ab53b43", "src_uid": "32fc378a310ca15598377f7b638eaf26", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nmain()\n{\n    int tux;\n    scanf(\"%d\",&tux);\n    int foo = 0;\n    int bar = 0;\n    int baz = 0;\n    int quz = 1;\n    while( tux-- ) {\n        int pur;\n        scanf(\"%d\",&pur);\n        foo += pur;\n        bar++;\n        if ( (foo * quz >= bar * baz) ) {\n            baz = foo;\n            quz = bar;\n        }\n    }\n    printf(\"%.5f\\n\",(double)baz/quz);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3a1537760895eb79b38fd3ec4a4fc82c", "src_uid": "32fc378a310ca15598377f7b638eaf26", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MAXN 33\nint main()\n{\n    double sum=0;\n    double a[MAXN];\n    int n,i;\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%lf\",&a[i]);\n        sum+=a[i];\n    }\n    sum/=n;\n    printf(\"%.6lf\",sum);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ca595cc79bfdc128f8baae1d28828422", "src_uid": "32fc378a310ca15598377f7b638eaf26", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nint main(){\n    int n, res;\n    while (scanf(\"%d\", &n) != EOF){\n        if (n <= 2) res = 0;\n        else if (n == 3) res = 1;\n        else if (n == 99) res = 49;\n        else if (n & 1) res = n >> 1;\n        else res = __builtin_trap();\n        printf(\"%d\\n\", res);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e7e65222f2c1f51cdc40f7ed8e806c27", "src_uid": "422abdf2f705c069e540d4f5c09a4948", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nint main(){\n    int n, res;\n    while (scanf(\"%d\", &n) != EOF){\n        res = 0;\n        if (n & 1) res = n >> 1;\n        else{\n            else if (__builtin_popcount(n) == 1) res = 0;\n            else if (n == 6) res = 1;\n            else res = n / 6;\n        }\n        printf(\"%d\\n\", res);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "55dc2f41fa22a704805cf3783626cf43", "src_uid": "422abdf2f705c069e540d4f5c09a4948", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint ispower(int);\nint power(int);\n\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\t\n\tif (n%2==1)\n\t{\n\t\tprintf(\"%d\\n\",(n-1)/2);\n\t}\n\telse if (ispower(n)==1)\n\t{\n\t\tprintf(\"0\\n\");\n\t}\n\telse\n\t{\n\t\tprintf(\"%d\\n\",(n-(power(n)>>1))/2);\n\t}\n\n\treturn 0;\n}\n\nint ispower(int n)\n{\n\twhile(n%2==0 && n>1)\n\t{\n\t\tn>>=1;\n\t}\n\n\treturn n;\n}\n\nint power(int n)\n{\n\tint p=1;\n\twhile(p<n)\n\t{\n\t\tp<<=1;\n\t}\n\n\treturn p;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fac0f534a07984580253eea8a0002fe4", "src_uid": "422abdf2f705c069e540d4f5c09a4948", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\n\nint main()\n{\n    long long n;\n    scanf(\"%I64d\", &n);\n    long long result;\n    result = n / 2;\n    int temp = 1;\n    while(temp * 2 <= n)\n        temp = temp * 2;\n    if(n % 2 == 0)\n    {\n        printf(\"%I64d\", (n - temp)/2);\n    }\n    else\n        printf(\"%I64d\", result);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "30e81c45fd8750a7c8f6c0836bf116c1", "src_uid": "422abdf2f705c069e540d4f5c09a4948", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<conio.h>\n\nint main()\n{\n    long long n;\n    scanf(\"%I64d\", &n);\n    long long result;\n    result = n / 2;\n    int temp = 1;\n    while(temp * 2 <= n)\n        temp = temp * 2;\n    if(n % 2 == 0)\n    {\n        printf(\"%I64d\", (n - temp)/2);\n    }\n    else\n        printf(\"%I64d\", result);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a92942ff9cdafbe0539ebea172e825f0", "src_uid": "422abdf2f705c069e540d4f5c09a4948", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <ctype.h>\n#include <math.h>\n#include <limits.h>\n\nstruct node{\n    int id, x, k;\n} x[128];\nint size=sizeof(struct node);\nint cmp_x(const void *a, const void *b)\n{\n    return *((int*)a+1)-*((int*)b+1);\n}\nint cmp_id(const void *a, const void *b)\n{\n    return *(int*)a-*(int*)b;\n}\n\nint main(void)\n{\n    int n, i;\n    \n    scanf(\"%d%*d\", &n);\n    for (i=0; i<n; i++) {\n        scanf(\"%d\", &x[i].x);\n        x[i] .id = i;\n    }\n    qsort(x, n, size, cmp_x);\n    for (i=0; i<n; i++)\n        x[i].k = i&1;\n    qsort(x, n, size, cmp_id);\n    printf(\"%d\", x[0].k);\n    for (i=1; i<n; i++)\n        printf(\" %d\", x[i].k);\n    putchar('\\n');\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "46cf653d550795e337ad123206340a23", "src_uid": "692698d4b49ad446984f3a7a631f961d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "/* Abhiruchi Gupta */\n#include <stdio.h>\nint main()\n{\n    int n, m, i, st, end, j;\n    \n    scanf(\"%d %d\", &n, &m);\n    \n    int color[105], pt[105];\n    \n    for (i = 0; i <= 100; i++) {\n        color[i] = -2;\n    }\n    \n    for (i = 0; i < n; i++) {\n        scanf(\"%d\", &pt[i]);\n        color[pt[i]] = -1;\n    }\n    \n    int ans = 0;\n    int flag = 0;\n    \n    for (i = 0; i < m; i++) {\n        scanf(\"%d %d\", &st, &end); \n    }\n    \n    for (j = 0; j <= 100; j++) {\n            if (color[j] == -1) {\n               if (flag == 0) {\n                    color[j] = 1;\n                    flag = 1;\n               }\n               else if (flag == 1) {\n                    color[j] = 0;\n                    flag = 0;\n               }            \n            }\n    }\n          \n    for (i = 0; i < n; i++) {\n               printf(\"%d \", color[pt[i]]);\n    }\n                printf(\"\\n\");     \n    \n\n    //getch();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8bfd7134d20f591806804519f1527c7d", "src_uid": "692698d4b49ad446984f3a7a631f961d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\ntypedef struct\n{\n    long color,place,num;\n}point;\npoint s[101],t;\n\nvoid sort(long l,long r)\n{\n\tlong i=l,j=r,m=s[(l+r)/2].place;\n\tdo{\n\t\twhile(s[i].place<m) i++;\n\t\twhile(s[j].place>m) j--;\n\t\tif(i<=j)\n\t\t{\n\t\t\tt=s[i];s[i]=s[j];s[j]=t;\n\t\t\ti++;j--;\n\t\t}\n\t}while(i<=j);\n\tif(l<j) sort(l,j);\n\tif(i<r) sort(i,r);\n}\n\nint main()\n{\n    long i,j,n,m,p[101];\n    scanf(\"%ld%ld\",&n,&m);\n    for(i=1;i<=n;i++)\n        {\n            scanf(\"%ld\",&s[i].place);\n            s[i].num=i;\n        }\n    sort(1,n);\n    for(i=1;i<=n;i++)\n        s[i].color=i%2;\n\n    for(i=1;i<=n;i++)\n        for(j=1;j<=n;j++)\n        if(s[j].num==i)\n            printf(\"%ld \",s[j].color);\n\n    return 0;\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "aa87515d9d7f676d981849e878065c16", "src_uid": "692698d4b49ad446984f3a7a631f961d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,m,i,j,temp,a[101],b[101],l[101],r[101],c[101]={0};\n    scanf(\"%d %d\",&n,&m);\n    for(i=0;i<n;i++)\n    scanf(\"%d\",&a[i]);\n    for(i=0;i<m;i++)\n    scanf(\"%d %d\",&l[i],&r[i]);\n    for(i=0;i<n;i++)\n    b[i]=a[i];\n    for(i=0;i<n;i++)\n    {\n        for(j=i+1;j<n;j++)\n        {\n            if(a[i]>a[j])\n            {\n                temp=a[i];a[i]=a[j];a[j]=temp;\n            }\n        }\n    }\nfor(i=0;i<n;i++)\n    {\n        if(i%2==0)\n        c[a[i]]=0;\n        else\n        c[a[i]]=1;\n    }\nfor(i=0;i<n;i++)\n{\n    for(j=0;j<n;j++)\n    {\n        if(b[i]==a[j])\n        {\n            printf(\"%d \",c[b[i]]);\n            break;\n        }\n    }\n}\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fb14324472d4bf98f797dfca355a4784", "src_uid": "692698d4b49ad446984f3a7a631f961d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "//Codeforces 245 Q1\n#include<stdio.h>\nint main()\n{\n    int n,m,i,cnt,in[100],yes[101];\n    scanf(\"%d %d\",&n,&m);\n    for(i=0;i<101;i++)\n        yes[i]=0;\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",in+i);\n        yes[in[i]]=1;\n    }\n    cnt=0;\n    for(i=0;i<101;i++)\n    {\n        if(yes[i])\n        {\n            yes[i]-=cnt&1;\n            cnt++;\n            if(cnt==n)\n                break;\n        }\n    }\n    for(i=0;i<n;i++)\n        printf(\"%d \",yes[in[i]]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1544b30612e2f2806dfc5447d404f429", "src_uid": "692698d4b49ad446984f3a7a631f961d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint ExChange(int a,int b)\n{\n    if(a>b)\n        return a;\n    else\n        return b;\n}\nint main()\n{\n    int m,n,Max;\n    while(scanf(\"%d%d\",&n,&m)!=EOF)\n    {\n        if (n==1||m==1)\n            printf(\"%d\\n\",n*m);\n        Max=ExChange(m,n);\n        else if (n==2||m==2)\n        {\n            if (Max%4==0)\n                printf(\"%d\\n\",Max);\n            else if (Max%4==0)\n                printf(\"%d\\n\",Max+1);\n            else\n                printf(\"%d\\n\",(Max/4)*4+4);\n        }\n        else\n            printf(\"%d\\n\",(m*n+1)/2);\n    }\n    return 0;\n}\n\n       ", "lang_cluster": "C", "compilation_error": true, "code_uid": "208403424394d0c2b098260b6c2fcca5", "src_uid": "e858e7f22d91aaadd7a48a174d7b2dc9", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "int main()\n{\n        int m,n,Max;\n        scanf(\"%d%d\",&n,&m);\n        if (n==1||m==1)\n            printf(\"%d\\n\",n*m);\n        Max=ExChange(m,n);\n        else if (n==2||m==2)\n        {\n            if (Max%4==0)\n                printf(\"%d\\n\",Max);\n            else if (Max%4==1)\n                printf(\"%d\\n\",Max+1);\n            else\n                printf(\"%d\\n\",(Max/4)*4+4);\n        }\n        else\n            printf(\"%d\\n\",(m*n+1)/2);\n    return 0;\n}\n\n          ", "lang_cluster": "C", "compilation_error": true, "code_uid": "ba92aefb27c6dd327b25d89ba1251c88", "src_uid": "e858e7f22d91aaadd7a48a174d7b2dc9", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint ExChange(int a,int b)\n{\n    if(a>b)\n        return a;\n    else\n        return b;\n}\nint main()\n{\n    int m,n,Max;\n    while(scanf(\"%d%d\",&n,&m)!=EOF)\n    {\n        if (n==1||m==1)\n            printf(\"%d\\n\",n*m);\n        Max=ExChange(m,n);\n        else if (n==2||m==2)\n        {\n            if (Max%4==1)\n                printf(\"%d\",Max+1);\n            else if (Max%4==0)\n                printf(\"%d\\n\",Max);\n            else\n                printf(\"%d\\n\",(Max/4)*4+4);\n        }\n        else\n            printf(\"%d\\n\",(m*n+1)/2);\n    }\n    return 0;\n}\n\n         ", "lang_cluster": "C", "compilation_error": true, "code_uid": "035f1f25a6a0761b89e4df8d1c50fbe9", "src_uid": "e858e7f22d91aaadd7a48a174d7b2dc9", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint ExChange(int a,int b)\n{\n    if(a>b)\n        return a;\n    else\n        return b;\n}\nint main()\n{\n    int m,n,Max;\n    scanf(\"%d%d\",&n,&m);\n        if (n==1||m==1)\n            printf(\"%d\\n\",n*m);\n        Max=ExChange(m,n);\n        else if (n==2||m==2)\n        {\n            if (Max%4==0)\n                printf(\"%d\\n\",Max);\n            else if (Max%4==0)\n                printf(\"%d\\n\",Max+1);\n            else\n                printf(\"%d\\n\",(Max/4)*4+4);\n        }\n        else\n            printf(\"%d\\n\",(m*n+1)/2);\n    return 0;\n}\n\n                                        ", "lang_cluster": "C", "compilation_error": true, "code_uid": "fed1a8c12bed7dd29b6ca279d3909a9d", "src_uid": "e858e7f22d91aaadd7a48a174d7b2dc9", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main()\n{\n    int n,m,a[10][10],i,j,s=0;\n    scanf(\"%d%d\",&n,&m);\n    for(i=0; i<n; i++)\n    {\n        for(j=0; j<m; j++)\n        {\n            a[i][j]=0;\n        }\n    }\n    for(i=0; i<n; i++)\n    {\n        j=i;\n        if(a[i][j]==0)\n                {\n                    a[i][j]=1;\n                    s++;\n                    if(i+2<n)\n                    {\n                        if(j+1<m)\n                        {\n                            a[i+2][j+1]=1;\n                        }\n                        if(j-1>=0)\n                        {\n                            a[i+2][j-1]=1;\n                        }\n                    }\n                    if(i+1<n)\n                    {\n                        if(j+2<m)\n                        {\n                            a[i+1][j+2]=1;\n                        }\n                        if(j-2>=0)\n                        {\n                            a[i+1][j-2]=1;\n                        }\n                    }\n                    if(i-1>=0)\n                    {\n                        if(j+2<m)\n                        {\n                            a[i-1][j+2]=1;\n                        }\n                        if(j-2>=0)\n                        {\n                            a[i-1][j-2]=1;\n                        }\n                    }\n                    if(i-2>=0)\n                    {\n                        if(j+1<m)\n                        {\n                            a[i-2][j+1]=1;\n                        }\n                        if(j-1>=0)\n                        {\n                            a[i-2][j-1]=1;\n                        }\n                    }\n                }\n    }\n\n    for(i=0; i<n; i++)\n    {\n        for(j=0; j<m; j++)\n        {\n                if(a[i][j]==0)\n                {\n                    a[i][j]=1;\n                    s++;\n                    if(i+2<n)\n                    {\n                        if(j+1<m)\n                        {\n                            a[i+2][j+1]=1;\n                        }\n                        if(j-1>=0)\n                        {\n                            a[i+2][j-1]=1;\n                        }\n                    }\n                    if(i+1<n)\n                    {\n                        if(j+2<m)\n                        {\n                            a[i+1][j+2]=1;\n                        }\n                        if(j-2>=0)\n                        {\n                            a[i+1][j-2]=1;\n                        }\n                    }\n                }\n        }\n    }\n    printf(\"%d\",s);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f41724b2aae0283bb4ba3131e3114bdb", "src_uid": "e858e7f22d91aaadd7a48a174d7b2dc9", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <ctype.h>\n#include <math.h>\n#define MOD 1000000007\n\nint cmpfunc(const void *a, const void *b){\n    return *(int*)a - *(int*)b;\n}\n\nint main(void){\n    int n,w;\n    scanf(\"%d %d\",&n,&w);\n    int a[n],i;\n    for(i=0;i<n;i++) scanf(\"%d\",&a[i]);\n    int b[n];\n    for(i=0;i<n;i++){\n        b[i]=(a[i]+1)/2;\n        w-=b[i];\n    }\n    int locn;\n    if(w<0) printf(\"-1\\n\");\n    else{\n        while(w>0){\n            for(i=0,locn=0;i<n;i++){\n                if(a[locn]>=a[i] && b[locn]<a[locn]) continue;\n                else if(a[locn]<a[i] && b[i]<a[i]) locn=i;\n                else ;\n            }\n            w-=a[locn]-b[locn];\n            if(w<0) b[locn]+=w+a[locn]-b[locn];\n            else b[locn]=a[locn];\n        }\n    for(i=0;i<n;i++) printf(\"%d \", b[i]);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "32f006e273e23c686d44d098f112e99d", "src_uid": "5d3bb9e03f4c5c8ecb6233bd5f90f3a3", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long ay[100005],st[100005], ft[100005]={0}, val[100005];\nlong long int  temp[100005],temp1[100005],temp2[100005], arr[2][1000007];\nvoid merge(long long int  arr[],long long int min, long long int mid,long long int max,long long int arr1[], long long int arr2[]){\n\tlong long int i,j,k,m;\n\tj=min;\n\tm=mid+1;\n\tfor(i=min;j<=mid && m<=max;i++){\n\t\tif(arr[j]<arr[m]){\n\t\t\ttemp[i]=arr[j];\n\t\t\ttemp1[i]=arr1[j];\n\t\t\ttemp2[i]=arr2[j];\n\t\t\tj++;\n\t\t}\n\t\telse if(arr[j]==arr[m]){\n\t\t\tif(arr1[j]<arr1[m]){\n\t\t\t\ttemp[i]=arr[j];\n\t\t\t\ttemp1[i]=arr1[j];\n\t\t\t\ttemp2[i]=arr2[j];\n\t\t\t\tj++;\n\t\t\t}\n\t\t\telse{\n\t\t\t\ttemp[i]=arr[m];\n\t\t\t\ttemp1[i]=arr1[m];\n\t\t\t\ttemp2[i]=arr2[m];\n\t\t\t\tm++;\n\t\t\t}\n\t\t}\n\t\telse{\n\t\t\ttemp[i]=arr[m];\n\t\t\ttemp1[i]=arr1[m];\n\t\t\ttemp2[i]=arr2[m];\n\t\t\tm++;\n\t\t}\n\t}\n\tif(j>mid){\n\t\tfor(k=m;k<=max;k++){\n\t\t\ttemp[i]=arr[k];\n\t\t\ttemp1[i]=arr1[k];\n\t\t\ttemp2[i]=arr2[k];\n\t\t\ti++;\n\t\t}\n\t}\n\telse{\n\t\tfor(k=j;k<=mid;k++){\n\t\t\ttemp[i]=arr[k];\n\t\t\ttemp1[i]=arr1[k];\n\t\t\ttemp2[i]=arr2[k];\n\t\t\ti++;\n\t\t}\n\t}\n\tfor(k=min;k<=max;k++){\n\t\tarr[k]=temp[k];\n\t\tarr1[k]=temp1[k];\n\t\tarr2[k]=temp2[k];\n\t}\n}\nvoid part(long long int arr[],long long int min,long long int max,long long int arr1[], long long int arr2[]){\n\tlong long int mid;\n\tif(min<max){\n\t\tmid=(min+max)/2;\n\t\tpart(arr,min,mid,arr1,arr2);\n\t\tpart(arr,mid+1,max,arr1,arr2);\n\t\tmerge(arr,min,mid,max,arr1,arr2);\n\t}\n}\nint main()\n{\n\tlong long i,j,k,n,w,max,sum=0,diff;\n\tscanf(\"%lld %lld\", &n, &w);\n\tfor(i=0;i<=n;i++)\n\t{\n\t\tst[i]=0;ft[i]=0;val[i]=0;\n\t\ttemp[i]=0;temp1[i]=0;temp2[i]=0;\n\t}\n\tmax=-1;\n\tfor(i=0;i<n;i++)\n\t\tscanf(\"%lld\",&val[i]);\n\tfor(i=0;i<n;i++)\n\t\tst[i]=i+1; // number array.\n\tfor(i=0;i<n;i++)\n\t{ \n\t\tif(val[i]%2)\n\t\t\tsum=sum+val[i]/2 +1;\n\t\telse\n\t\t\tsum+=val[i]/2;\n\t}\n\tif(sum>w)\n\t\tprintf(\"-1\\n\");\n\telse\n\t{\n\t\tpart(val,0,n-1 ,st,ft);//sorted the array according to the first array that's given as argument. Here, it is \"val\".\n\t\t//\tfor(i=0;i<n;i++)\n\t\t//\t\tprintf(\"%lld %lld %lld\\n\",st[i], ft[i], val[i]);\n\t\tsum=0;j=0;\n\t\tfor(i=0;i<n-1;i++)\n\t\t{\n\t\t\tif(val[i]%2)\n\t\t\t{\n\t\t\t\tay[j]=val[i]/2+1;\n\t\t\t\t//printf(\"%lld \",val[i]/2+1);\n\t\t\t\tsum+=val[i]/2+1;}\n\n\t\t\telse\n\t\t\t{\n\t\t\t\tay[j]=val[i]/2;\n\t\t\t\t//\tprintf(\"%lld \",val[i]/2);\n\t\t\t\tsum+=val[i]/2;\n\t\t\t}\n\t\t\tj++;\n\t\t}\n\t\tif(w-sum<=val[j])\n\t\t\tay[j]=w-sum;\n\t\telse\n\t\t{\n\t\t\tay[j]=val[j];\n\t\t\tdiff=w-sum-val[j];\n\t\t\tj=n-2;\n\t\t\twhile(diff>0)\n\t\t\t{\n\t\t\t\tif(val[j]-ay[j]>=diff)\n\t\t\t\t{ay[j]=ay[j]+diff;break;}\n\t\t\t\telse\n\t\t\t\t\tay[j]=val[j];\n\t\t\t\tdiff=diff-(val[j]-ay[j]);\n\t\t\t\tj--;\n\t\t\t\tif(j<0)\n\t\t\t\t\tj=n-2;\n\t\t\t}\n\t\t}\n\t\tpart(st,0,n-1,ay,ft);\n\t\tfor(i=0;i<n;i++)\n\t\t\tprintf(\"%lld \",ay[i]);\n\t\tprintf(\"\\n\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8aa6e77f4f2529ccb336be9cf5e2de75", "src_uid": "5d3bb9e03f4c5c8ecb6233bd5f90f3a3", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\ntypedef struct Node{int val,ind;}vol;\nint cmp(const void *a,const void *b)\n{\n\treturn ((vol *)a)->val-((vol *)b)->val;\n}\nint DIV(int n)\n{\n\tif(n&1)\n\t\treturn (n>>1)+1;\n\treturn n>>1;\n}\nint main()\n{\n\tint n,t;\n\tscanf(\"%d%d\",&n,&t);\n\tint i,ans[105];\n\tvol V[105];\n\tfor(i=0;i<n;i++)\n\t\tscanf(\"%d\",&V[i].val),V[i].ind=i;\n\tqsort(V,n,sizeof(vol),cmp);\n\tint tot=0,flag=0;\n\ti=0;\n\twhile(i<n)\n\t{\n\t\ttot+=DIV(V[i].val);\n\t\tif(tot>t)\n\t\t{\n\t\t\tflag=1;\n\t\t\tbreak;\n\t\t}\n\t\tans[V[i].ind] = DIV(V[i].val);\n\t\ti++;\n\t}\n\tif(flag)\n\t{\n\t\tprintf(\"-1\\n\");\n\t\treturn 0;\n\t}\n\tint rem = t-tot;\n\ti=n-1;\n\twhile(rem>0)\n\t{\n\t\tif(ans[V[i].ind]+rem>V[i].val)\n\t\t{\n\t\t\trem-=V[i].val-ans[V[i].ind];\n\t\t\tans[V[i].ind] = V[i].val;\n\t\t\ti--;\n\t\t}\n\t\telse if(ans[V[i].ind]+rem<V[i].val)\n\t\t{\n\t\t\tans[V[i].ind]+=rem;\n\t\t\trem=0;\n\t\t}\n\t}\n\tfor(i=0;i<n;i++)\n\t\tprintf(\"%d \",ans[i]);\n\tprintf(\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9da2c902bbddd23caa4d72d98ec87a9f", "src_uid": "5d3bb9e03f4c5c8ecb6233bd5f90f3a3", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#define MAXN 100\nstruct cup {\n    int sz;\n    int idx;\n}\nint cmp(const struct cup* a, const struct cup* b) {\n    return a->sz - b->sz;\n}\nint solve(const struct cup* a, const int n, const int w, int* res) {\n    int used = w;\n    qsort(a, n, sizeof(struct cup), cmp);\n    for(int i = n - 1; i >= 0; i--) {\n        res[a[i].idx] = (a[i].sz + 1) / 2;\n        used -= res[a[i].idx];\n    }\n    if(used < 0) return -1;\n    else for(int i = n - 1; i >= 0 && used > 0; i--) {\n        res[a[i].idx] += min(a[i].sz / 2, used);\n        used -= min(a[i].sz / 2, used);\n    }\n    return 0;\n}\nint main(void) {\n    struct cup a[150];\n    int res[150] = {0};\n    int n, w;\n    for(int i = 0; i < 150; i++) a[i].idx = i;\n    scanf(\"%d%d\", &n, &w);\n    for(int i = 0; i < n; i++) scanf(\"%d\", &a[i].sz);\n    int r = solve(a, n, w, res);\n    if(r == -1) puts(\"-1\");\n    else for(int i = 0; i < n; i++) printf(\"%d \", res[i]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9aa05d448530b7dfbfc5fed1eb51e321", "src_uid": "5d3bb9e03f4c5c8ecb6233bd5f90f3a3", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,w,a[100],x[100],ans,d,c,sum=0,sum1=0,i,j,t,y[100];\n    scanf(\"%d%d\",&n,&w);\n    for(i=0;i<n;i++){\n        scanf(\"%d\",&a[i]);\n        y[i]=a[i];\n        sum=sum+a[i];\n    }\n    for(i=0;i<n;i++)\n    {\n        x[i]=a[i]/2;\n        if(a[i]%2!=0)\n            x[i]++;\n            sum1=sum1+x[i];\n    }\n    if(sum==w)\n    {\n        for(i=0;i<n;i++)\n            printf(\"%d \",a[i]);\n            //exit(0);\n            return;\n    }\n    if(sum1>w)\n        printf(\"-1\");\n    else if(sum1==w&&sum1!=sum)\n    {\n        for(i=0;i<n;i++)\n            printf(\"%d \",x[i]);\n    }\n    else if(sum1<w){\n    for(i=0;i<n-1;i++)\n    {\n        for(j=i;j<n;j++)\n        {\n            if(a[i]<a[j])\n            {\n                t=a[i];\n                a[i]=a[j];\n                a[j]=t;\n                t=x[i];\n                x[i]=x[j];\n                x[j]=t;\n            }\n        }\n    }\n    d=w-sum1;\n    for(i=0;i<n;i++)\n    {\n        c=a[i]-x[i];\n        if(d<c||c==d)\n        {\n            x[i]=x[i]+d;\n            d=0;\n            break;\n        }\n        else if(d>c)\n        {\n            x[i]=x[i]+c;\n            d=d-c;\n        }\n    }\n    for(i=0;i<n;i++)\n    {\n        for(j=0;j<n;j++)\n        {\n            if((y[i]==a[j])&&x[j]!=0)\n            {\n                y[i]=x[j];\n                x[j]=0;\n            }\n\n        }\n    }\n\n\n    for(i=0;i<n;i++)\n    {\n        printf(\"%d \",y[i]);\n    }\n\n}\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ce0026bf7cf8e519389e6964d800fa98", "src_uid": "5d3bb9e03f4c5c8ecb6233bd5f90f3a3", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "/*Victor Luiz Martins de Sousa*/\n/*         nUSP 8536513       */\n\n#include <stdio.h>\n\nint main()\n{\n    double x,y;\n    int xx,yy;\n    scanf(\"%lf %lf\", &x, &y);\n    xx=x;\n    yy=y;\n    if(xx%2 == 0)\n    {\n        x = x*x/4;\n    }\n    else\n    {\n        x = (x*x-1)/4;\n    }\n    if(yy%2 == 0)\n    {\n        y = y*y/4;\n    }\n    else\n    {\n        y = (y*y-1)/4;\n    }\n    printf(\"%.0lf\\n\", x*y);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7d8799158dacf403516b82ecfbd95f98", "src_uid": "42454dcf7d073bf12030367eb094eb8c", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\n    long long int w,h,i,j, b,T=0;\n    scanf(\"%I64d %I64d\",&w,&h);\n    for(i=1;i<=w/2;i++){\n        for(j=1;j<=h/2;j++){\n            T=T+(w-2*i+1)*(h-2*j+1);\n        }\n    }\n    printf(\"%I64d\",T);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b70496834f62ec6f17df36c4c3772534", "src_uid": "42454dcf7d073bf12030367eb094eb8c", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<memory.h>\n#include<string.h>\nint min(int a,int b){\n  if(a<b) return a;\n   return b;\n}\nint main(){\n    __int64 ans;\n    int i,j;\n    int c1,c2;\n    int w,h;\n    ans=0;\n    scanf(\"%d%d\",&h,&w);\n    for(i=0;i<=w;i++)\n     for(j=0;j<=h;j++){\n      c1=min(i-0,w-i);\n      c2=min(j-0,h-j);\n     ans=ans+c1*c2;\n     }\n     printf(\"%I64d\\n\",ans);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0ba5d89de96a654a21734c4c0b77ca8b", "src_uid": "42454dcf7d073bf12030367eb094eb8c", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "\n #include <stdio.h>\n\nint main()\n{\n    double x,y,i,j,cont,a,b;\n    scanf(\"%lf %lf\", &x, &y);\n    cont = 0;\n    if(x >1 && y >1)\n    {\n        for(j = 1 ; j < x ; j++ )\n        {\n            for(i = 1; i< y ; i++)\n            {\n                a = j;\n                b = i;\n                if(y - b < b)\n                {\n                    b = y-b;\n                }\n                if(x-a < a)\n                {\n                    a = x-a;\n                }\n                cont = cont + a*b;\n            }\n        }\n    }\n    printf(\"%.0lf\\n\", cont);\n    return 0 ;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "58f849803bcc109ac1e8ce024d95d691", "src_uid": "42454dcf7d073bf12030367eb094eb8c", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    double x,y,i,j,cont,a,b;\n    scanf(\"%lf %lf\", &x, &y);\n    cont = 0;\n    if(x >1 && y >1)\n    {\n        for(j = 1 ; j < x ; j++ )\n        {\n            for(i = 1; i< y ; i++)\n            {\n                a = j;\n                b = i;\n                if(y - b < b)\n                {\n                    b = y-b;\n                }\n                if(x-a < a)\n                {\n                    a = x-a;\n                }\n                cont = cont + a*b;\n            }\n        }\n    }\n    printf(\"%.0lf\\n\", cont);\n    return 0 ;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "daf005ad94fa7bd2137fb23afe42052f", "src_uid": "42454dcf7d073bf12030367eb094eb8c", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include \"stdio.h\"\n\nint p[1000000], emirp[11184], i, j, a, b;\n\nint main()\n{\n\tfor( i = 2; i < N; i++ ) p[i] = 1;\n\tfor( i = 2; i * i < N; i++ ) if( p[i] ) for( j = 2 * i; j < N; j += i ) p[j] = 0;\n\tfor( j = 0, i = 2; i < N; i++ ) if( p[i] )\n\t{\n\t\ta = i, b = 0;\n\t\twhile( a )\n\t\t{\n\t\t\tb = 10 * b + ( a % 10 );\n\t\t\ta /= 10;\n\t\t}\n\t\tif( b != i && p[b] ) emirp[j++] = i;\n\t}\n\tscanf( \"%d\", &i );\n\tprintf( \"%d\\n\", emirp[i-1] );\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "53f5f682ad87929e05648d051a18ea1a", "src_uid": "53879e79cccbacfa6586d40cf3436657", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include <math.h>\nint main()\n{\n    int a,b,c,result=0,t,count=1,count2=1,count3=1,count4=1,i;\n    int sushu[12000],emirp[12000],emirp2[12000],prime[12000];\n    for(a=10;a<=11184;a++)\n    {\n        b=sqrt(a);\n        for(c=2;c<=b;c++)\n        {if(a%c==0)\n        break;}\n        if(c>b)\n        {\n\n            sushu[count++]=a;\n        }\n    }\n    for(i=1;i<count;i++)\n    {\n        result=0;\n        t=sushu[i];\n        while(t!=0)\n        {\n            result=10*result+t%10;\n            t/=10;\n        }\n        if(result!=sushu[i])\n                {emirp[count2++]=result;\n                }\n    }\n    for(a=1;a<count2;a++)\n    {\n        b=sqrt(emirp[a]);\n        for(c=2;c<=b;c++)\n        {if(emirp[a]%c==0)\n        break;}\n        if(c>b)\n        {\n            emirp2[count3++]=emirp[a];\n        }\n    }\n    for(i=1;i<count3;i++)\n    {\n        result=0;\n        t=emirp2[i];\n        while(t!=0)\n        {\n            result=10*result+t%10;\n            t/=10;\n        }\n        if(result!=emirp2[i])\n                {prime[count4++]=result;\n                }\n    }\n    int o;\n    scanf(\"%lld\",&o);\n    printf(\"%lld\",prime[o]);\n}#include<stdio.h>\n#include \"math.h\"\nint main()\n{\n    long long a,b,c,result=0,t,count=1,count2=1,count3=1,count4=1,i;\n    long long sushu[12000],emirp[12000],emirp2[12000],prime[12000];\n    for(a=10;a<=11184;a++)\n    {\n        b=sqrt(a);\n        for(c=2;c<=b;c++)\n        {if(a%c==0)\n        break;}\n        if(c>b)\n        {\n\n            sushu[count++]=a;\n        }\n    }\n    for(i=1;i<count;i++)\n    {\n        result=0;\n        t=sushu[i];\n        while(t!=0)\n        {\n            result=10*result+t%10;\n            t/=10;\n        }\n        if(result!=sushu[i])\n                {emirp[count2++]=result;\n                }\n    }\n    for(a=1;a<count2;a++)\n    {\n        b=sqrt(emirp[a]);\n        for(c=2;c<=b;c++)\n        {if(emirp[a]%c==0)\n        break;}\n        if(c>b)\n        {\n            emirp2[count3++]=emirp[a];\n        }\n    }\n    for(i=1;i<count3;i++)\n    {\n        result=0;\n        t=emirp2[i];\n        while(t!=0)\n        {\n            result=10*result+t%10;\n            t/=10;\n        }\n        if(result!=emirp2[i])\n                {prime[count4++]=result;\n                }\n    }\n    int o;\n    scanf(\"%d\",&o);\n    printf(\"%d\",prime[o]);\n}\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "89b69fdf0ac395d65546a759faaea30c", "src_uid": "53879e79cccbacfa6586d40cf3436657", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<malloc.h>\n\nconst char base[] =\n\t\t\"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=\";\nchar base_rev[128];\n\n// Base64 \u7f16\u7801\n//char* base64_encode(const char* data, int data_len);\n// Base64 \u89e3\u7801\n//char* base64_decode(const char* data, int data_len);\n\n/* \u8f6c\u6362\u7b97\u5b50 */\ninline char find_pos(char ch) {\n\tchar *ptr = (char*) strrchr(base, ch); //the last position (the only) in base[]\n\treturn (ptr - base);\n}\n\n/* Base64 \u89e3\u7801 */\nchar *base64_decode(const char *data, int data_len = -1) {\n\tif (data_len == -1)\n\t\tdata_len = strlen(data);\n\tfor (int i = 0; i < 64; i++) {\n\t\tbase_rev[base[i]] = i;\n\t}\n\tint ret_len = (data_len / 4) * 3;\n\tint equal_count = 0;\n\tchar *ret = NULL;\n\tchar *f = NULL;\n\tint tmp = 0;\n\tint temp = 0;\n\tint prepare = 0;\n\tint i = 0;\n\tif (*(data + data_len - 1) == '=') {\n\t\tequal_count += 1;\n\t}\n\tif (*(data + data_len - 2) == '=') {\n\t\tequal_count += 1;\n\t}\n\tif (*(data + data_len - 3) == '=') { //seems impossible\n\t\tequal_count += 1;\n\t}\n\tswitch (equal_count) {\n\tcase 0:\n\t\tret_len += 4; //3 + 1 [1 for NULL]\n\t\tbreak;\n\tcase 1:\n\t\tret_len += 4; //Ceil((6*3)/8)+1\n\t\tbreak;\n\tcase 2:\n\t\tret_len += 3; //Ceil((6*2)/8)+1\n\t\tbreak;\n\tcase 3:\n\t\tret_len += 2; //Ceil((6*1)/8)+1\n\t\tbreak;\n\t}\n\tret = (char *) malloc(ret_len);\n\tif (ret == NULL) {\n\t\tbase[-1];\n\t\t//\u6545\u610f\u8ba9\u4ed6RE\n\t}\n\tmemset(ret, 0, ret_len);\n\tf = ret;\n\twhile (tmp < (data_len - equal_count)) {\n\t\ttemp = 0;\n\t\tprepare = 0;\n\t\twhile (temp < 4) {\n\t\t\tif (tmp >= (data_len - equal_count)) {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tprepare = (prepare << 6) | (base_rev[data[tmp]]);\n\t\t\ttemp++;\n\t\t\ttmp++;\n\t\t}\n\t\tprepare = prepare << ((4 - temp) * 6);\n\t\tfor (i = 0; i < 3; i++) {\n\t\t\tif (i == temp) {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\t*f = (char) ((prepare >> ((2 - i) * 8)) & 0xFF);\n\t\t\tf++;\n\t\t}\n\t}\n\t*f = '\\0';\n\treturn ret;\n}\n\nint n;\nchar ORI[] = \"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\";\nint main() {\n\tchar* DEC = base64_decode(ORI);\n\t//memcpy(ansa, DEC, sizeof(int) * 11184);\n\tscanf(\"%d\", &n);\n\tprintf(\"%d\\n\", ((int*) DEC)[n - 1]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "d74358dfbc91298e51e929cce8ef4d71", "src_uid": "53879e79cccbacfa6586d40cf3436657", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint isPrim(int x)\n{\n    int d;\n    \n    if (x % 2 == 0) return 0;\n    for (d = 3; d < x; ++d) {\n        if (x % d == 0) return 0;\n        ++d;\n    }\n    \n    return 1;\n}\n\nint mirror(int x)\n{\n    int d, i;\n    \n    d = x;\n    for (i = 1; (x > 0); i *= 10) x = x / 10; \n    x = d;\n    \n    for (d = 0; (x > 0); x = x / 10) {\n        i = i / 10;\n        d += (x % 10) * i;\n    }\n    \n    return d;\n}\n\nint eots[11184];\n\nvoid genEots(int n)\n{\n    int i, j, m;\n    \n    for (i = 13, j = 0; j < n; ++i) {\n        m = mirror(i);\n        if (m != i)\n            if (isPrim(i) && isPrim(m)) {\n                eots[j] = i; ++j;\n            }\n        ++i;\n    }\n}\n\nint main(void)\n{\n    int n;\n    \n    fscanf(stdin, \"%d\", &n);\n    genEots(n);\n    printf(\"%d\\n\", eots[n-1]);\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "de657480161f4a2c99cbb3bc353cea1e", "src_uid": "53879e79cccbacfa6586d40cf3436657", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "/*\n\u0430\u0431\u0432\u0433\u0434\u0435\u0451\u0436\u0437\u0438\u0439\u043a\u043b\u043c\u043d\u043e\u043f\u0440\u0441\u0442\u0443\u0444\u0445\u0446\u0447\u0448\u0449\u044a\u044b\u044c\u044d\u044e\u044f\n\u0440\u0441\u0442\u0443\u0444\u0445\u0446\u0447\u0448\u0449\u044a\u044b\u044c\u044d\u044e\u044f\u0430\u0431\u0432\u0433\u0434\u0435\u0451\u0436\u0437\u0438\u0439\u043a\u043b\u043c\u043d\u043e\u043f\n\n\u0435\u043e\u0442\u0441\u043e\u0440\u043f - \u044d\u0442\u043e \u043f\u0440\u043e\u0441\u0442\u043e\u0435 \u0447\u0438\u0441\u043b\u043e, \u0447\u044c\u0435 \u0437\u0435\u0440\u043a\u0430\u043b\u044c\u043d\u043e\u0435 \u043e\u0442\u0440\u0430\u0436\u0435\u043d\u0438\u0435 \u044f\u0432\u043b\u044f\u0435\u0442\u0441\u044f\n\u0434\u0440\u0443\u0433\u0438\u043c \u043f\u0440\u043e\u0441\u0442\u044b\u043c \u0447\u0438\u0441\u043b\u043e\u043c.\n\n\u043d\u0430\u0439\u0434\u0438\u0442\u0435 \u0435\u043e\u0442\u0441\u043e\u0440\u043f \u043d\u043e\u043c\u0435\u0440 N \u0432\u0445\u043e\u0434\u043d\u044b\u0435 \u0434\u0430\u043d\u043d\u044b\u0435 \u0441\u043e\u0441\u0442\u043e\u044f\u0442 \u0438\u0437 \u0435\u0434\u0438\u043d\u0441\u0442\u0432\u0435\u043d\u043d\u043e\u0433\u043e\n\u0446\u0435\u043b\u043e\u0433\u043e N (1<=n<=11184) - \u043d\u043e\u043c\u0435\u0440\u0430 \u0438\u0441\u043a\u043e\u043c\u043e\u0433\u043e \u0435\u043e\u0442\u0441\u043e\u0440\u043f\u0430. \u043d\u0443\u043c\u0435\u0440\u0430\u0446\u0438\u044f \u043d\u0430\u0447. \u0441 \u0435\u0434.\n*/\n#include <stdio.h>\n#define max 70000\n\nint prim[max] = { 2, 3, 5, 7, 11, 13 };\nint total = 6;\n\nint isPrim(int x)\n{\n\tint d;\n\t\n\tif (x <= 1) return 0;\n\n\tfor (d = 0; d < total; ++d) {\n\t\tif (x == prim[d]) return 1;\n\t\tif ((x % prim[d]) == 0) return 0;\n\t}\n\t\n\treturn 1;\n}\n\nvoid genPrim(void)\n{\n\tint i, n;\n\t\n\ti = total, n = prim[total-1]+1;\n\twhile (i < max) {\n\t\tif (isPrim(n)) { prim[i] = n; ++i, ++total; }\n\t\t++n;\n\t}\n}\n\nint mirror(int x)\n{\n\tint d, i = 1;\n\t\n\td = x;\n\twhile (x > 0) {\n\t\tx = x / 10; i *= 10;\n\t}\n\tx = d;\n\t\n\td = 0;\n\twhile (x > 0) {\n\t\ti = i / 10;\n\t\td += (x % 10) * i;\n\t\tx = x / 10;\n\t}\n\t\n\treturn d;\n}\n\nint eots[11184];\n\nvoid genEots(void)\n{\n\tint i = 5, j = 0, m, p;\n\t\n\twhile ((i < max) && (j < 11184)) {\n\t\tp = prim[i]; m = mirror(p);\n\t\tif (isPrim(m) && (m != p)) {\n\t\t\teots[j] = p;\n\t\t\t++j;\n\t\t}\n\t\t++i;\n\t}\n}\n\nint main(void)\n{\n\tint n;\n\t\n\tgenPrim(); genEots();\n\n\tfscanf(stdin, \"%d\", &n);\n\tif ((1 <= n) && (n <= 11184))\n\t\tprintf(\"%d\\n\", eots[n-1]);\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b025f748a9758b6397993b9a19e2fdae", "src_uid": "53879e79cccbacfa6586d40cf3436657", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long a[200][200];\nint main()\n{\n    long long n, m, k, x, y, i, j, p, ma=0, mi=9.223372e+18;\n    scanf(\"%I64d %I64d %I64d %I64d %I64d\", &n, &m, &k, &x, &y);\n    p=(2*n-2)*m; if(!p) p=m;\n    for(i=1; i<=n; i++) {\n        for(j=1; j<=m; j++) {\n            if(i==1 || i==n) a[i][j]=k/p;\n            else a[i][j]=k/p*2;\n        }\n    }\n    k%=p;\n    i=j=1;\n    int kk=1;\n    while(k) {\n        a[i][j]++;\n        if(i==n && j==m) kk=-kk;\n        j++; k--;\n        if(j>m) j=1, i+=kk;\n    }\n    for(i=1; i<=n; i++) {\n        for(j=1; j<=m; j++) {\n            if(ma<a[i][j]) ma=a[i][j];\n            if(mi>a[i][j]) mi=a[i][j];\n        }\n    }\n    printf(\"%I64d %I64d %I64d\", ma, mi, a[x][y]);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bc9c821a9d0381a8ed108918613cf765", "src_uid": "e61debcad37eaa9a6e21d7a2122b8b21", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\ntypedef long long unsigned llu;\ntypedef unsigned u;\nllu C[111][111];\nint main()\n{\n\tu x,y,i,j,a,b,c,m;llu n,d,mx=0,mn=-1llu;\n\tscanf(\"%u%u%I64u%u%u\",&x,&y,&n,&i,&j);\n\ta=x*y;--i;--j;\n\tif(x>1)a+=(x-2)*y;\n\td=n/a;m=n%a;--x;\n\tfor(a=0;++a<x;)for(b=-1;++b<y;)C[a][b]=d<<1;\n\tfor(b=-1;++b<y;)C[0][b]=C[x][b]=d;\n\tfor(a=b=c=0;m--&&++C[a][b];)if(++b==y)\n\t{\n\t\tif(x&&a==0)c=+1;\n\t\tif(x&&a==x)c=-1;\n\t\ta+=c;b=0;\n\t}\n\tfor(a=-1;++a<=x;)for(b=-1;++b<y;)\n\t{\n\t\tif(mx<C[a][b])mx=C[a][b];\n\t\tif(mn>C[a][b])mn=C[a][b];\n\t}\n\tprintf(\"%I64u %I64u %I64u\\n\",mx,mn,C[i][j]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b2ff9d8b6c6389dec0ce2e324b35ad0a", "src_uid": "e61debcad37eaa9a6e21d7a2122b8b21", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n\tlong long n,m,x,y,a; \n\tlong long k;\n    scanf(\"%I64d %I64d %I64d %I64d %I64d\",&n,&m,&k,&x,&y);\n    a=n*m+(n-2)*m;\n    long long sb1,sb2;\n    sb1=(x-1)*m+y;\n    sb2=(n-x-1)*m+y;\n    long long s=k/a,h=k%a;\n    if(x==1||x==n)\n    {\n    \tif(h==0)\n        printf(\"%I64d %I64d %I64d\",2*s,s,s);\n        else if(x==1)\n        {\n        \tif(h<y)\n        \tprintf(\"%I64d %I64d %I64d\",2*s,s,s);\n        \telse if(h>=y&&h<=m)\n        \tprintf(\"%I64d %I64d %I64d\",2*s,s,s+1);\n        \telse if(h>=y&&h<n*m)\n            printf(\"%I64d %I64d %I64d\",2*s+1,s,s+1);\n            else if(h==n*m)\n            printf(\"%I64d %I64d %I64d\",2*s+1,s+1,s+1);\n            else if(h>n*m)\n            printf(\"%I64d %I64d %I64d\",2*s+2,s+1,s+1);\n\t\t}\n\t\telse if(x==n)\n\t\t{\n\t\t\tif(h<=m)\n\t\t\tprintf(\"%I64d %I64d %I64d\",2*s,s,s);\n\t\t\telse if(h<(n-1)*m+y)\n\t\t\tprintf(\"%I64d %I64d %I64d\",2*s+1,s,s);\n\t\t\telse if(h>=(n-1)*m+y&&h<n*m)\n\t\t    printf(\"%I64d %I64d %I64d\",2*s+1,s,s+1);\n\t\t    else if(h==n*m)\n\t\t    printf(\"%I64d %I64d %I64d\",2*s+1,s+1,s+1);\n\t\t    else if(h>n*m)\n            printf(\"%I64d %I64d %I64d\",2*s+2,s+1,s+1);\n\t\t}\n\t}\n\telse\n\t{\n       if(h==0)\n        printf(\"%I64d %I64d %I64d\",2*s,s,s);\n        else if(h==n*m)\n        printf(\"%I64d %I64d %I64d\",2*s+1,s+1,2*s+1);\n        else if(h<n*m)\n        {\n        \tif(h<=m)\n    \t    printf(\"%I64d %I64d %I64d\",2*s,s,s);\n    \t    if(h>m&&h<sb1)\n    \t    printf(\"%I64d %I64d %I64d\",2*s+1,s,s);\n    \t    else if(h>=sb1)\n    \t    printf(\"%I64d %I64d %I64d\",2*s+1,s,s+1);\n        }\n        else if(h>n*m)\n        {\n        \th=h-n*m;\n        \tif(h<sb2)\n    \t    printf(\"%I64d %I64d %I64d\",2*s+2,s+1,2*s+1);\n    \t    else if(h>=sb2)\n    \t    printf(\"%I64d %I64d %I64d\",2*s+2,s+1,2*s+2);\n        }\n    }\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6e4360fb251bd181897fbe2e4f55faf7", "src_uid": "e61debcad37eaa9a6e21d7a2122b8b21", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,m,x,y;\n    long long int k,p,min,max,cur,g;\n    scanf(\"%d %d %I64d %d %d\",&n,&m,&k,&x,&y);\n    if(n==1)\n    {\n       p=k/m;\n       g=k%(long long)m;\n       min=p;\n       if(g>0)\n        max=p+1;\n       else\n        max=p;\n       if(g>=y)\n        cur=p+1;\n       else\n        cur=g;\n    }\n    if(n==2)\n    {\n        p=k/((long long)m);\n        g=k%((long long)m);\n        if(p%2==0)\n        {\n            if(g>0)\n            max=p/2+1;\n            else\n            max=p/2;\n            min=p/2;\n            if(x==1)\n           {\n               if(g>=y)\n                cur=p/2+1;\n               else\n                cur=p/2;\n           }\n           else if(x==2)\n           {\n                cur=p/2;\n           }\n        }\n        else\n        {\n            max=p/2+1;\n            min=p/2;\n            if(x==1)\n           {\n                cur=p/2+1;\n           }\n           else if(x==2)\n           {\n                if(g>=y)\n                cur=p/2+1;\n               else\n                cur=p/2;\n           }\n        }\n    }\n    else\n    {\n        p=k/((long long)((n-1)*m));\n        g=k%((long long)((n-1)*m));\n       if(p%2==0)\n       {\n           if(g>m)\n            max=p+1;\n           else\n            max=p;\n           min=p/2;\n           if(x==1)\n           {\n               if(g>=y)\n                cur=p/2+1;\n               else\n                cur=p/2;\n           }\n           else if(x==n)\n           {\n               if(g>=(n-1)*m+y)\n                cur=p/2+1;\n               else\n                cur=p/2;\n           }\n           else\n           {\n               if(g>=(x-1)*m+y)\n                cur=p+1;\n               else\n                cur=p;\n           }\n       }\n       else\n       {\n          if(g>=m)\n            min=p/2+1;\n          else\n            min=p/2;\n          if(g>m)\n            max=p+1;\n          else\n           max=p;\n          if(x==1)\n           {\n               if(g>=(n-1)*m+y)\n                cur=p/2+2;\n               else\n                cur=p/2+1;\n           }\n           else if(x==n)\n           {\n               if(g>=y)\n                cur=p/2+1;\n               else\n                cur=p/2;\n           }\n           else\n           {\n               if(g>=(n-x)*m+y)\n                cur=p+1;\n               else\n                cur=p;\n           }\n       }\n    }\n    printf(\"%I64d %I64d %I64d\",max,min,cur);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "602955572a1576501882984d151116ad", "src_uid": "e61debcad37eaa9a6e21d7a2122b8b21", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nlong long int k,i,j,max,min,S;\n\nint main()\n{\n    int n,m,x,y;\n    \n    scanf(\"%d%d%lld%d%d\",&n,&m,&k,&x,&y);\n    \n    if(n <= 2)\n    {\n         min = k/(m*n);\n         max = (k%(m*n) == 0)?min:min + 1;\n         \n         if(max == min)S = max;\n         else\n         {\n             if(n == 1)\n             {\n                  if(k%m >= y)S = max;\n                  else S = min;\n             }\n             else\n             {\n                 if(k/(m*2)%2 == 0)\n                 {\n                              if(k%(m*2) >= x*m+y)S = max;\n                              else S = min;\n                 }\n                 else\n                 {\n                     if(k%(m*2) <= m)\n                     {\n                                if(x == 2 && k%(m*2) >= y)S = max;\n                                else S = min;\n                     }\n                     else\n                     {\n                         if(x == 1 && k%m <= y)S = min;\n                         else S = max;\n                     }\n                 }\n             }\n         }\n    }\n    else\n    {\n        i = k/(m*(2*n-2));\n        j = k%(m*(2*n-2));\n        max = i*2;\n        min = i;\n        if(j == 0)\n        {\n             if(x == 1 || x == n)S = min;\n             else S = max;\n        }\n        else\n        {\n            if(j <= m)\n            {\n                 if(x == 1)\n                 {\n                      if(y > j)S = min;\n                      else S = min+1;\n                 }\n                 else if(x == n)S = min;\n                 else S = max;\n            }\n            else if(j <= m*(n-1))\n            {\n                 max++;\n                 if(x == 1)S = min+1;\n                 else if(x == n)S = min;\n                 else \n                 {\n                      if(x*m+y <= j)S = max+1;\n                      else S = max;\n                 }\n            }\n            else if(j <= m*n)\n            {\n                 max++;\n                 if(j == m*n)min++;\n                 if(x == 1)S = i+1;\n                 else if(x == n)\n                 {\n                      if(y <= j%m || j%m == 0)S = i+1;\n                      else S = i;\n                 }\n                 else S = max;\n            }\n            else\n            {\n                max+=2;\n                min++;\n                if(x == 1)S = i+1;\n                else if(x == n)S = i+1;\n                else\n                {\n                    S = i*2+1;\n                    j-=m*n;\n                    if(j%m == 0)\n                    {\n                           if(x + j/m > (n-2))S++;\n                    }\n                    else\n                    {\n                        if(x + j/m > (n-2))S++;\n                        else if(x + j/m == (n-2))\n                        {\n                             if(j%m >= y||j%m == 0)S++;\n                        }\n                    }\n                }\n            }\n        }\n    }\n    \n    printf(\"%lld %lld %lld\\n\",max,min,S);\n    system(\"PAUSE\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ac3d1050c8a8ff1fde0b2bd379099416", "src_uid": "e61debcad37eaa9a6e21d7a2122b8b21", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nlong long arr[3000][2],current[1000];\nmain()\n{\n       long long a,b,c,x,w,temp,i=1,no_of_elem=0; long long sum=0,num,flag=0;\n    scanf(\"%I64d%I64d%I64d%I64d%I64d\",&a,&b,&w,&x,&c);\n    int no=0,no2=0;\n    if(c<=a)\n    {\n        printf(\"0\");\n        return 0;\n    }\n    long long pos;\n    if(b<x)\n    {\n        while(1)\n        {\n          temp=(long long)ceil((float)(x-b)/(w-x));\n          if(i==1)\n          arr[i][0]=temp;\n          else\n            arr[i][0]=arr[i-1][0]+temp;\n            b+=temp*(w-x);\n            arr[i+1][1]=b/x;\n            arr[i+1][0]=arr[i][0]+arr[i+1][1];\n            no_of_elem+=2;\n            b=b-b/x*x;\n            if(current[b]>0)\n            {\n                pos=b;\n                break;\n            }\n           current[b]=i+1; i+=2; \n        }\n        for(i=current[pos]+2;i<=no_of_elem;i+=2)\n            no+=arr[i][1];\n        for(i=2;i<=current[pos];i+=2)\n            no2+=arr[i][1];\n            if(no==0)\n            {\n                no=no2;no2=0;\n                current[pos]=0;\n            }\n            if(no+no2>=c-a)\n            {\n        sum=0;\n        for(i=1;sum+arr[i+1][1]<c-a;i++)\n            sum+=arr[i][1];\n        printf(\"%I64d\",arr[i][0]+c-a-sum);\n        return 0;\n            }\n            temp=(c-a-no2)/no;\n        temp=(arr[no_of_elem][0]-arr[current[pos]][0])*temp+arr[current[pos]][0];\n       i=current[pos]+1;\n        if((c-a-no2)%no!=0)\n        {\n         while(sum+arr[i][1]<(c-a-no2)%no)\n        {\n            sum+=arr[i][1];\n            i++;\n        }\n        temp+=(c-a-no2)%no-sum+arr[i-1][0]-arr[current[pos]][0];\n        }\n            printf(\"%I64d\",temp);\n    }\n        else\n        {\n            num=b/x;\n            b=b-b/x*x;\n            c=c-num;\n            if(c<=a)\n            {\n                while(c<a)\n                {\n                    c+=1;\n                    num--;\n                }\n                printf(\"%I64d\",num);\n                return 0;\n            }\n           while(1)\n        {\n          temp=(int)ceil((float)(x-b)/(w-x));\n          if(i==1)\n          arr[i][0]=temp;\n          else\n            arr[i][0]=arr[i-1][0]+temp;\n            b+=temp*(w-x);\n            arr[i+1][1]=b/x;\n            arr[i+1][0]=arr[i][0]+arr[i+1][1];\n            b=b-b/x*x;\n            if(current[b]>0)\n            {\n                pos=b;\n                break;\n            }\n           current[b]=i+1; i+=2;no_of_elem+=2;\n        }\n\n        for(i=current[pos]+2;i<=no_of_elem;i+=2)\n            no+=arr[i][1];\n        for(i=2;i<=current[pos];i+=2)\n            no2+=arr[i][1];\n            if(no==0)\n            {\n                no=no2;no2=0;\n                pos=1;\n            }\n            if(no+no2>=c-a)\n            {\n        sum=0;\n        for(i=1;sum+arr[i+1][1]<c-a;i++)\n            sum+=arr[i][1];\n        printf(\"%I64d\",arr[i][0]+c-a-sum+num);\n        return 0;\n            }\n            temp=(c-a-no2)/no;\n        temp=(arr[no_of_elem][0]-arr[current[pos]][0])*temp+arr[current[pos]][0];\n       i=current[pos]+1;\n        if((c-a-no2)%no!=0)\n        {\n         while(sum+arr[i][1]<(c-a-no2)%no)\n        {\n            sum+=arr[i][1];\n            i++;\n        }\n        temp+=(c-a-no2)%no-sum+arr[i-1][0]-arr[current[pos]][0];\n        }\n            printf(\"%I64d\",temp+num);\n}\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f8371ae38ccce076033583fe8890bc0a", "src_uid": "a1db3dd9f8d0f0cad7bdeb1780707143", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nlong long arr[3000][2],current[1000];\nmain()\n{\n       long long a,b,c,x,w,temp,i=1,no_of_elem=0; long long sum=0,num,flag=0;\n    scanf(\"%I64d%I64d%I64d%I64d%I64d\",&a,&b,&w,&x,&c);\n    int no=0,no2=0;\n    if(c<=a)\n    {\n        printf(\"0\");\n        return 0;\n    }\n    long long pos;\n    if(b<x)\n    {\n        while(1)\n        {\n          temp=(long long)ceil((float)(x-b)/(w-x));\n          if(i==1)\n          arr[i][0]=temp;\n          else\n            arr[i][0]=arr[i-1][0]+temp;\n            b+=temp*(w-x);\n            arr[i+1][1]=b/x;\n            arr[i+1][0]=arr[i][0]+arr[i+1][1];\n            b=b-b/x*x;\n            if(current[b]>0)\n            {\n                pos=b;\n                break;\n            }\n           current[b]=i+1; i+=2;no_of_elem+=2;\n        }\n        for(i=current[pos]+2;i<=no_of_elem;i+=2)\n            no+=arr[i][1];\n        for(i=2;i<=current[pos];i+=2)\n            no2+=arr[i][1];\n            if(no==0)\n            {\n                no=no2;no2=0;\n                pos=1;\n            }\n            if(no+no2>=c-a)\n            {\n        sum=0;\n        for(i=1;sum+arr[i+1][1]<c-a;i++)\n            sum+=arr[i][1];\n        printf(\"%I64d\",arr[i][0]+c-a-sum);\n        return 0;\n            }\n            temp=(c-a-no2)/no;\n        temp=(arr[no_of_elem][0]-arr[current[pos]][0])*temp+arr[current[pos]][0];\n       i=current[pos]+1;\n        if((c-a-no2)%no!=0)\n        {\n         while(sum+arr[i][1]<(c-a-no2)%no)\n        {\n            sum+=arr[i][1];\n            i++;\n        }\n        temp+=(c-a-no2)%no-sum+arr[i-1][0]-arr[current[pos]][0];\n        }\n            printf(\"%I64d\",temp);\n    }\n        else\n        {\n            num=b/x;\n            b=b-b/x*x;\n            c=c-num;\n            if(c<=a)\n            {\n                while(c<a)\n                {\n                    c+=1;\n                    num--;\n                }\n                printf(\"%I64d\",num);\n                return 0;\n            }\n           while(1)\n        {\n          temp=(int)ceil((float)(x-b)/(w-x));\n          if(i==1)\n          arr[i][0]=temp;\n          else\n            arr[i][0]=arr[i-1][0]+temp;\n            b+=temp*(w-x);\n            arr[i+1][1]=b/x;\n            arr[i+1][0]=arr[i][0]+arr[i+1][1];\n            b=b-b/x*x;\n            if(current[b]>0)\n            {\n                pos=b;\n                break;\n            }\n           current[b]=i+1; i+=2;no_of_elem+=2;\n        }\n\n        for(i=current[pos]+2;i<=no_of_elem;i+=2)\n            no+=arr[i][1];\n        for(i=2;i<=current[pos];i+=2)\n            no2+=arr[i][1];\n            if(no==0)\n            {\n                no=no2;no2=0;\n                pos=1;\n            }\n            if(no+no2>=c-a)\n            {\n        sum=0;\n        for(i=1;sum+arr[i+1][1]<c-a;i++)\n            sum+=arr[i][1];\n        printf(\"%I64d\",arr[i][0]+c-a-sum+num);\n        return 0;\n            }\n            temp=(c-a-no2)/no;\n        temp=(arr[no_of_elem][0]-arr[current[pos]][0])*temp+arr[current[pos]][0];\n       i=current[pos]+1;\n        if((c-a-no2)%no!=0)\n        {\n         while(sum+arr[i][1]<(c-a-no2)%no)\n        {\n            sum+=arr[i][1];\n            i++;\n        }\n        temp+=(c-a-no2)%no-sum+arr[i-1][0]-arr[current[pos]][0];\n        }\n            printf(\"%I64d\",temp+num);\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ef2e5aa97c8e47108701c6168cbc2846", "src_uid": "a1db3dd9f8d0f0cad7bdeb1780707143", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n\nint main()\n{\n    int a,b,w,x,c;\n    int cnt;\n    while(scanf(\"%d%d%d%d%d\",&a,&b,&w,&x,&c) != EOF)\n    {\n        if(c <= a)\n        {\n            printf(\"0\\n\");\n            continue;\n        }\n\n        int  T = 0,pa = 0;\n        int b1 = b;\n        if(b >= x)\n        {\n            T ++,pa ++;\n            b -= x;\n        }\n        else\n        {\n            b = w - (x - b);\n            T ++;\n        }\n        while(b != b1)\n        {\n            if(b >= x)\n            {\n                int temp = b / x;\n                T += temp;\n                pa += temp;\n                b %= x;\n            }\n            else\n            {\n                b = w - (x - b);\n                T ++;\n            }\n        }\n\n        cnt = 0;\n        if((c - a) % pa == 0)\n        {\n            cnt = (c - a) / pa * T - T;\n            c = a + pa;\n        }\n        else\n        {\n            cnt = (c - a) / pa * T;\n            c = a + (c - a) % pa;\n        }\n\n\n        while(c > a)\n        {\n            if(b >= x)\n            {\n                int temp =  b / x;\n                if(c - temp < a)\n                {\n                    cnt += c - a;\n                    break;\n                }\n                c -= temp;\n                cnt += temp;\n                b %= x;\n            }\n            else\n            {\n                b = w - (x - b);\n                a --,c --,cnt ++;\n            }\n        }\n        printf(\"%d\\n\",cnt);\n    }\n    return 0;\n}\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3424ecf6669504db9d279e8d8e39820d", "src_uid": "a1db3dd9f8d0f0cad7bdeb1780707143", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void) {\n    int a=0,b=0,w=0,x=0,c=0;\n    int count=0;\n    scanf(\"%d %d %d %d %d\\n\", &a,&b,&w,&x,&c);\n    /*printf(\"%d %d %d %d %d\\n\", a,b,w,x,c);\n    printf(\"%d\", count);*/\n    if(c<=a){\n        printf(\"0\");\n    }\n    else{\n        int ch=100;\n        while(c>a){\n            int q,r;\n            //printf(\"a is %d, b is %d, c is %d\\n\",a,b,c);\n            //c=c-1;\n            if(b>=x){\n                q = b/x;\n                r = b%x;\n                b = b-q*x;\n                count+=q;\n                c-=q;\n                /*if(ch>0){\n                    printf(\"%d %d %ld\\n\",a,c,count);\n                    ch--;\n                }*/\n            }\n            else if(b<x){a=a-1; b=w-(x-b);}\n            count++;\n        }\n    }\n    if(count!=0)\n    printf(\"%d\", count);\n    // your code goes here\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a3519b3354d7095b2e6b5973174c47e6", "src_uid": "a1db3dd9f8d0f0cad7bdeb1780707143", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint arr[3000][2],current[1000];\nmain()\n{\n    int a,b,c,x,w,temp,i=1,no_of_elem=0; int sum=0,num,flag=0;\n    scanf(\"%d%d%d%d%d\",&a,&b,&w,&x,&c);\n    int no=0,no2=0;\n    if(c<=a)\n    {\n        printf(\"0\");\n        return 0;\n    }\n    int pos;\n    if(b<x)\n    {\n        while(1)\n        {\n          temp=(int)ceil((float)(x-b)/(w-x));\n          if(i==1)\n          arr[i][0]=temp;\n          else\n            arr[i][0]=arr[i-1][0]+temp;\n            b+=temp*(w-x);\n            arr[i+1][1]=b/x;\n            arr[i+1][0]=arr[i][0]+arr[i+1][1];\n            b=b-b/x*x;\n            if(current[b]>0)\n            {\n                pos=b;\n                break;\n            }\n           current[b]=i+1; i+=2;no_of_elem+=2;\n        }\n        for(i=current[pos]+2;i<=no_of_elem;i+=2)\n            no+=arr[i][1];\n        for(i=2;i<=current[pos];i+=2)\n            no2+=arr[i][1];\n            if(no==0)\n            {\n                no=no2;no2=0;\n                pos=1;\n            }\n            if(no+no2>=c-a)\n            {\n        sum=0;\n        for(i=1;sum+arr[i+1][1]<c-a;i++)\n            sum+=arr[i][1];\n        printf(\"%d\",arr[i][0]+c-a-sum);\n        return 0;\n            }\n            temp=(c-a-no2)/no;\n        temp=(arr[no_of_elem][0]-arr[current[pos]][0])*temp+arr[current[pos]][0];\n       i=current[pos]+1;\n        if((c-a-no2)%no!=0)\n        {\n         while(sum+arr[i][1]<(c-a-no2)%no)\n        {\n            sum+=arr[i][1];\n            i++;\n        }\n        temp+=(c-a-no2)%no-sum+arr[i-1][0]-arr[current[pos]][0];\n        }\n            printf(\"%d\",temp);\n    }\n        else\n        {\n            num=b/x;\n            b=b-b/x*x;\n            c=c-num;\n            if(c<=a)\n            {\n                while(c<a)\n                {\n                    c+=1;\n                    num--;\n                }\n                printf(\"%d\",num);\n                return 0;\n            }\n           while(1)\n        {\n          temp=(int)ceil((float)(x-b)/(w-x));\n          if(i==1)\n          arr[i][0]=temp;\n          else\n            arr[i][0]=arr[i-1][0]+temp;\n            b+=temp*(w-x);\n            arr[i+1][1]=b/x;\n            arr[i+1][0]=arr[i][0]+arr[i+1][1];\n            b=b-b/x*x;\n            if(current[b]>0)\n            {\n                pos=b;\n                break;\n            }\n           current[b]=i+1; i+=2;no_of_elem+=2;\n        }\n\n        for(i=current[pos]+2;i<=no_of_elem;i+=2)\n            no+=arr[i][1];\n        for(i=2;i<=current[pos];i+=2)\n            no2+=arr[i][1];\n            if(no==0)\n            {\n                no=no2;no2=0;\n                pos=1;\n            }\n            if(no+no2>=c-a)\n            {\n        sum=0;\n        for(i=1;sum+arr[i+1][1]<c-a;i++)\n            sum+=arr[i][1];\n        printf(\"%d\",arr[i][0]+c-a-sum+num);\n        return 0;\n            }\n            temp=(c-a-no2)/no;\n        temp=(arr[no_of_elem][0]-arr[current[pos]][0])*temp+arr[current[pos]][0];\n       i=current[pos]+1;\n        if((c-a-no2)%no!=0)\n        {\n         while(sum+arr[i][1]<(c-a-no2)%no)\n        {\n            sum+=arr[i][1];\n            i++;\n        }\n        temp+=(c-a-no2)%no-sum+arr[i-1][0]-arr[current[pos]][0];\n        }\n            printf(\"%d\",temp+num);\n        return 0;\n}\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9192cbd0905aa1142491079c82e89520", "src_uid": "a1db3dd9f8d0f0cad7bdeb1780707143", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t7\n#define M\t(N * (N - 1) / 2)\n\nint main() {\n\tstatic int ii[M], jj[M], cc[N];\n\tstatic char used[6][6];\n\tint n, m, h, i, j, p, b, max, cnt;\n\n\tscanf(\"%d%d\", &n, &m);\n\tfor (h = 0; h < m; h++)\n\t\tscanf(\"%d%d\", &ii[h], &jj[h]), ii[h]--, jj[h]--;\n\tp = 1;\n\tfor (i = 0; i < n; i++)\n\t\tp *= 6;\n\tmax = 0;\n\tfor (b = 0; b < p; b++) {\n\t\tint b_;\n\n\t\tfor (i = 0, b_ = b; i < n; i++, b_ /= 6)\n\t\t\tcc[i] = b_ % 6;\n\t\tmemset(used, 0, sizeof used);\n\t\tcnt = 0;\n\t\tfor (h = 0; h < m; h++) {\n\t\t\ti = cc[ii[h]], j = cc[jj[h]];\n\t\t\tif (!used[i][j]) {\n\t\t\t\tused[i][j] = used[j][i] = 1;\n\t\t\t\tcnt++;\n\t\t\t}\n\t\t}\n\t\tif (max < cnt)\n\t\t\tmax = cnt;\n\t}\n\tprintf(\"%d\\n\", max);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d3c0aff78340b7295b90fd1ad521cb62", "src_uid": "11e6559cfb71b8f6ca88242094b17a2b", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nchar F[8][8];\nint D[8];\nint C(int a, int b)\n{\n    int i;\n    int r = 0;\n    for (i = 1; i < 8; i++)\n    {\n        if (F[a][i] && F[b][i])\n        {\n            r++;\n        }\n    }\n    return r;\n}\nint main()\n{\n    int i, j;\n    int t;\n    int n, m;\n    int a, b;\n    int temp;\n    int mV;\n    scanf(\"%d %d\", &n, &m);\n    for (i = 1; i <= n; i++)\n    {\n        for (j = 1; j <= n; j++)\n        {\n            F[i][j] = 0;\n        }\n    }\n    for (i = 1; i <= n; i++)\n    {\n        D[i] = 0;\n    }\n    for (i = 0; i < m; i++)\n    {\n        scanf(\"%d %d\", &a, &b);\n        F[a][b] = 1;\n        D[a]++;\n        F[b][a] = 1;\n        D[b]++;\n    }\n    for (t = 1; t <= n; t++)\n    {\n        if (D[t] == 0)\n        {\n            break;\n        }\n    }\n    if (t == 8)\n    {\n        mV = 8;\n        if (m)\n        {\n            for (a = 1; a < 8; a++)\n            {\n                for (b = a + 1; b < 8; b++)\n                {\n                    temp = C(a, b);\n                    if (temp < mV)\n                    {\n                        mV = temp;\n                    }\n                }\n            }\n            m -= mV;\n        }\n    }\n    printf(\"%d\", m);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f500c1e6223e80bb74c5e57c3573d4e2", "src_uid": "11e6559cfb71b8f6ca88242094b17a2b", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nstruct {\n    int u,v;\n}edges[22];\nint edgeLen = 0;\nint vexnum;\nint vexs[8] = {1,1,1,1,1,1,1,1};\n\nint compute()\n{\n    int i = 1;\n    int ans = 0;\n    while(i <= vexnum)\n    {\n        int this = 0;\n        int fuck[67] = {};\n        for(i = 1 ; i <= vexnum && vexs[i] + 1 > 6 ; i ++){\n            vexs[i] = 1;\n        }\n        if(i <= vexnum){\n            vexs[i] += 1;\n            for(int j = 0 ; j < edgeLen ; j ++)\n            {\n                int uP = vexs[edges[j].u];\n                int vP = vexs[edges[j].v];\n                if(uP > vP){\n                    int temp = uP;\n                    uP = vP;\n                    vP = temp;\n                }\n                int hash = uP*10+vP;\n                this += (fuck[hash] == 0) ? 1 : 0;\n                fuck[hash] = (fuck[hash] == 0) ? 1 : 0;   \n            }\n            if(ans < this){\n                ans = this;\n            }\n        }\n    }\n    return ans;\n}\nint main()\n{\n    int arcnum;\n    scanf(\"%d%d\",&vexnum,&arcnum);\n    for(int i = 0 ; i < arcnum ; i ++)\n    {\n        int u,v;\n        scanf(\"%d%d\",&u,&v);\n        edges[edgeLen].u = u;\n        edges[edgeLen].v = v;\n        edgeLen += 1;\n    }\n    int ans = compute();\n    printf(\"%d\",ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bc6fdf92141dc94cb7f4eef9d2398ec6", "src_uid": "11e6559cfb71b8f6ca88242094b17a2b", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n#include <time.h>\n#include <limits.h>\ntypedef long long ll;\n\nll MAX = -100000000000;                      //  1e11\nll MIN = -100000000000;                     // -1e11\nll MOD = 1000000007;\n\nll longlongmax = __LONG_LONG_MAX__;\n\nll maxormin(ll a,ll b,ll flag){\n    return flag==1?(a>b?a:b):(a<b?a:b);\n}\n\nll overflowcheck(ll a){\n    if(a==1){\n        return 0;\n    }\n    else\n    {\n        ll temp = a;\n        ll power = 1;\n        while( longlongmax/temp>a ){\n            temp *= a;\n            power++;\n        }\n        return power+1;                     // Overflow occurs at this power.\n    }\n    \n}\n\nll merge(ll A[],ll B[],ll left,ll mid,ll right){\n    ll count = 0;\n    ll n1 = mid-left+1; \n    ll n2 = right-mid; \n\n    ll LA[n1],LB[n1],RA[n1],RB[n2];\n\n    for(ll n=0;n<n1;n++){ LA[n] = A[n+left];LB[n] = B[n+left];}\n    for(ll n=0;n<n2;n++){ RA[n] = A[n+mid+1];RB[n] = B[n+mid+1];}\n    \n    ll i=0,j=0,k=left;\n\n    while(i<n1&&j<n2){\n        if(LA[i]<RA[j]){\n            A[k] = LA[i];\n            B[k] = LB[i];\n            i++;\n        }\n        else{\n            A[k] = RA[j];\n            B[k] = RB[j];\n            count += n1-i;\n            j++;\n        }\n        k++;\n    }\n    while(i<n1){    \n            A[k] = LA[i];\n            B[k] = LB[i];\n            i++;\n            k++;\n    }\n\n    while(j<n2){\n            A[k] = RA[j];\n            B[k] = RB[j];\n            j++;\n            k++;    \n    }\n    return count;\n}\n\nll mergesort(ll A[],ll B[],ll left,ll right){\n    ll total = 0;\n    if(left<right){\n        ll mid = (right-left)/2+left;\n        total += mergesort(A,B,left,mid);\n        total += mergesort(A,B,mid+1,right);\n        total += merge(A,B,left,mid,right);\n    }\n    return total;\n}\n\nll assign[7];\n\ntypedef struct node\n{\n    ll data,level;\n    struct node*prev,*next;\n}nd;\n\nnd *head[3000000];\nnd *tail[3000000];\n\nvoid add(ll u,ll v)\n{\n    nd *q = (nd *)malloc(sizeof(nd));\n    nd *q1 = (nd *)malloc(sizeof(nd));\n    q->data = u;\n    q1->data = v;\n    q->prev = NULL;\n    q1->prev = NULL;\n    q->next = NULL;\n    q1->next = NULL;\n  \n    if(!head[u])    // Add v to u\n    {\n        head[u] = q1;\n        tail[u] = q1;\n    }\n    else\n    {\n        tail[u]->next = q1;\n        q1->prev = tail[u];\n        tail[u] = q1;\n    }\n    if(!head[v])    // Add u to v\n    {\n        head[v] = q;\n        tail[v] = q;\n    }\n    else\n    {\n        tail[v]->next = q;\n        q->prev = tail[v];\n        tail[v] = q;\n    }\n}\n\nvoid display(ll item)\n{\n    nd *i = head[item];\n    while (i)\n    {\n        printf(\"|%lld %lld|\\n\",item,i->data);\n        i = i->next;\n    }\n    printf(\"\\n\");\n}\n\nll dominoes[7][7];\nll assign[7];\nll array[100];\n\nint main(int argc, char const *argv[])\n{\n    ll T = 1;\n    // scanf(\"%lld\",&T);\n    for(ll t = 0; t < T; t++)\n    {\n        ll N , M;\n        scanf(\"%lld %lld\",&N,&M);\n        ll V1[M],V2[M];\n        for (ll m = 0; m < M; m++)\n        {\n            scanf(\"%lld %lld\",&V1[m],&V2[m]);\n            V1[m]--;\n            V2[m]--;\n            add(V1[m],V2[m]);\n        }\n\n\n        for (ll n = 0; n < N; n++)\n        {\n            // display(n);\n        }\n        \n        \n        // Numbers to be assigned ->0(no num) 1 2 3 4 5 6 (x) repetition\n        for (ll k = 0; k < 823543; k++)\n        {\n            ll cnt = k;\n            ll ind = 0;\n            while (cnt)\n            {\n                array[ind++] = cnt%7;\n                cnt /= 7;\n            }\n            for (ll n = 0; n < N; n++)\n            {\n                assign[n] = array[n];\n                // printf(\"%lld \",assign[n]);\n            }\n            // printf(\"\\n\");\n            // check if correct\n            ll sum  = 0;\n            for (ll m = 0; m < M; m++)\n            {\n                if(assign[V1[m]] && assign[V2[m]]) // both not assigned 1 \n                {\n                    // printf(\"-> %lld %lld %lld %lld %lld %lld\\n\",assign[V1[m]],assign[V2[m]],V1[m],V2[m],dominoes[V1[m]][V2[m]],dominoes[V2[m]][V1[m]]);\n                    if(!dominoes[assign[V1[m]]][assign[V2[m]]] && !dominoes[assign[V2[m]]][assign[V1[m]]])\n                    {\n                        // printf(\"plp %lld %lld %lld %lld\\n\",assign[V1[m]],assign[V2[m]],V1[m],V2[m]);\n                        sum++;\n                        dominoes[assign[V1[m]]][assign[V2[m]]] = 1;\n                        dominoes[assign[V2[m]]][assign[V1[m]]] = 1;\n                    }\n                    // printf(\"%lld %lld ho gya\\n\",dominoes[V1[m]][V2[m]],dominoes[V2[m]][V1[m]]);\n                }\n            }\n            // printf(\"|%lld|\\n\\n\",sum);\n           if(sum>MAX)\n           {\n               MAX = sum;\n           }\n           for (ll n = 0; n < 7; n++)\n           {\n               for (ll m = 0; m < 7; m++)\n               {\n                   dominoes[n][m] = 0;\n               }\n               \n           }\n        }\n        printf(\"%lld\\n\",MAX);\n    }\n        \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a68151bf840a43b29158d2cb7dee8941", "src_uid": "11e6559cfb71b8f6ca88242094b17a2b", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n, m;\n\tscanf(\"%d %d\", &n, &m);\n\tint i, j, k;\n\tint a[30], b[30];\n\tfor (i = 0; i < m; i++)\n\t{\n\t\tscanf(\"%d %d\", &a[i], &b[i]);\n\t\ta[i]--;\n\t\tb[i]--;\n\t}\n\tint max = 1;\n\tfor (i = 0; i < n; i++)\n\t\tmax *= 6;\n\tint used[10][10];\n\tfor (i = 0; i < 10; i++)\n\t\tfor (j = 0; j < 10; j++)\n\t\t\tused[i][j] = 1;\n\tint p, q[10];\n\tint ans = 0, count;\n\tfor (j = 0; j < max; j++)\n\t{\n\t\tp = j;\n\t\tfor (i = 0; i < n; i++)\n\t\t{\n\t\t\tq[i] = p % 6;\n\t\t\tp /= 6;\n\t\t}\n\t\tfor (i = 0; i < 10; i++)\n\t\t\tfor (k = i; k < 10; k++)\n\t\t\t\tused[i][k] = 0;\n\t\tcount = 0;\n\t\tfor (i = 0; i < m; i++)\n\t\t{\n\t\t\tif (q[a[i]] < q[b[i]])\n\t\t\t{\n\t\t\t\tif (used[q[a[i]]][q[b[i]]] == 0)\n\t\t\t\t{\n\t\t\t\t\tcount++;\n\t\t\t\t\tused[q[a[i]]][q[b[i]]] = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tif (used[q[b[i]]][q[a[i]]] == 0)\n\t\t\t\t{\n\t\t\t\t\tcount++;\n\t\t\t\t\tused[q[b[i]]][q[a[i]]] = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (ans < count)ans = count;\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8a1aa6a886a960fdbd6ed7f955cdba94", "src_uid": "11e6559cfb71b8f6ca88242094b17a2b", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include<string.h>\n#include<ctype.h>\n#define display(s,i) printf(#s   #i \"=%d\",s##i)\n#define ll long long\nll f,h,n1,n2;\nconst  long long  mod=1e8;\nll dp[102][11][102][11];\nll result(ll f1,ll a, ll h1, ll b)\n{\n    if(f1==0 && h1==0) return 1;\n    if(dp[f1][a][h1][b]!=-1) return dp[f1][a][h1][b];\n    ll c=0,d=0,e=0,f=0;\n    if(f1 && a) c=result(f1-1,a-1,h1,n2);\n    if(h1 && b) d=result(f1,n1,h1-1,b-1);\n    return dp[f1][a][h1][b]=(c+d)%mod;\n}\nll main(ll argc, char *argv[])\n{\n    memset(dp,-1,sizeof dp);\n    scanf(\"%d%d%d%d\",&f,&h,&n1,&n2);\n    ll ans=result(f,n1,h,n2);\n    printf(\"%d\",ans%mod);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5176268f1b1f3a56f4ad62c9c3d13724", "src_uid": "63aabef26fe008e4c6fc9336eb038289", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define M 100000000\nint dp[200][101][101][11][11];\nint n1, n2, k1, k2;\nint call(int i, int x, int y, int x1, int y1)\n{\n\tif(i>=(n1+n2)) return 1;\n\tif(dp[i][x][y][x1][y1]==-1){\n\t\tint r=0;\n\t\tif(x1<k1 && x<n1) r = call(i+1,x+1,y,x1+1,0);\n\t\tif(y1<k2 && y<n2) r += call(i+1,x,y+1,0,y1+1);\n\t\tdp[i][x][y][x1][y1] = r%M;\n\t}\n\treturn dp[i][x][y][x1][y1];\n}\nint main()\n{\n\tint i, j, k, g, h;\n\tscanf(\"%d\",&n1);\n\tscanf(\"%d\",&n2);\n\tscanf(\"%d\",&k1);\n\tscanf(\"%d\",&k2);\n\tfor(i=0;i<(n1+n2);i++)\n\tfor(j=0;j<=n1;j++)\n\tfor(k=0;k<=n2;k++)\n\tfor(g=0;g<=k1;g++)\n\tfor(h=0;h<=k2;h++) dp[i][j][k][g][h]=-1;\n\tprintf(\"%d\",call(0,0,0,0,0));\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ca07a727665cf5a0bc662f46c9ce41a4", "src_uid": "63aabef26fe008e4c6fc9336eb038289", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint dp[200][101][101][11][11];\nint n1, n2, k1, k2;\nint call(int i, int x, int y, int x1, int y1)\n{\n\tif(i>=(n1+n2)) return 1;\n\tif(dp[i][x][y][x1][y1]==-1){\n\t\tint r=0;\n\t\tif(x1<k1 && x<n1) r = call(i+1,x+1,y,x1+1,0);\n\t\tif(y1<k2 && y<n2) r += call(i+1,x,y+1,0,y1+1);\n\t\tdp[i][x][y][x1][y1] = r;\n\t}\n\treturn dp[i][x][y][x1][y1];\n}\nint main()\n{\n\tint i, j, k, g, h;\n\tscanf(\"%d\",&n1);\n\tscanf(\"%d\",&n2);\n\tscanf(\"%d\",&k1);\n\tscanf(\"%d\",&k2);\n\tfor(i=0;i<(n1+n2);i++)\n\tfor(j=0;j<=n1;j++)\n\tfor(k=0;k<=n2;k++)\n\tfor(g=0;g<=k1;g++)\n\tfor(h=0;<=k2;h++) dp[i][j][k][g][h]=-1;\n\tprintf(\"%d\",call(0,0,0,0,0));\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "a652b5ed8cff585baa47e03e00bbc74a", "src_uid": "63aabef26fe008e4c6fc9336eb038289", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <cstdio>\n#include <algorithm>\nusing namespace std;\n\nconst int MAXN = 100, MOD = 1e8;\n\nint k1, k2, dp[MAXN+1][MAXN+1][2];\n\nint fn(int n1, int n2, bool flag)\n{\n    if(n1 == 0 && n2 == 0) return 1;\n\n    if(dp[n1][n2][flag] != -1) return dp[n1][n2][flag];\n\n    int ret = 0;\n\n    if(flag == 0) {\n        for(int man = 1; man <= k1 && n1-man >= 0; ++man)\n            ret += fn(n1-man, n2, !flag), ret %= MOD;\n    }\n    else {      // flag == 1\n        for(int man = 1; man <= k2 && n2-man >= 0; ++man)\n            ret += fn(n1, n2-man, !flag), ret %= MOD;\n    }\n\n    return dp[n1][n2][flag] = ret;\n}\n\nint main()\n{\n    //freopen(\"in\", \"r\", stdin);\n\n    int n1, n2;\n\n    while(scanf(\"%d %d %d %d\", &n1, &n2, &k1, &k2) != EOF) {\n        fill(&dp[0][0][0], &dp[MAXN+1][0][0], -1);\n\n        printf(\"%d\\n\", (fn(n1, n2, 0) + fn(n1, n2, 1)) % MOD);\n    }\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fa63227334b42f92e9c7b281fcb96f56", "src_uid": "63aabef26fe008e4c6fc9336eb038289", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint ans, MOD = 100000000;\nint k1, k2;\n\nint min(int a, int b) { return a < b ? a : b; }\n\nvoid rec(int remain1, int remain2, int turn) {\n    if(remain1 + remain2 == 0) {\n        ans++;\n        if(ans == MOD)\n            ans = 0;\n    } else {\n        int i, val;\n        if(turn == 0) {\n            val = (remain1 + k1 - 1) / k1;\n            if(val > 1 && val - 1 > remain2)\n                return;\n            for(i = 1; i <= min(k1, remain1); i++) {\n                rec(remain1 - i, remain2, 1);\n            }\n        } else {\n            val = (remain2 + k2 - 1) / k2;\n            if(val > 1 && val - 1 > remain1)\n                return;\n            for(i = 1; i <= min(k2, remain2); i++) {\n                rec(remain1, remain2 - i, 0);\n            }\n        }\n    }\n}\n\nint main() {\n    int n1, n2;\n    scanf(\"%d %d %d %d\", &n1, &n2, &k1, &k2);\n    rec(n1, n2, 0);\n    rec(n1, n2, 1);\n    printf(\"%d\\n\", (int)ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "84b477111a8637826d935b423e84cefd", "src_uid": "63aabef26fe008e4c6fc9336eb038289", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t400\n#define M\t200\n#define A\t26\n#define MD\t998244353\n\nint max(int a, int b) { return a > b ? a : b; }\n\nint main() {\n\tstatic int kk[A], dp1[M + 1][2], dp2[M + 1][M + 1][3], dq1[N + 1], dq2[N + 1][N + 1], aa1[M + 1], aa2[M + 1][M + 1];\n\tint n, m, i, k, l, k1, l1, k2, l2, a, b, ans;\n\n\tscanf(\"%d\", &n), m = (n + 1) / 2;\n\tfor (a = 0; a < A; a++)\n\t\tscanf(\"%d\", &kk[a]);\n\tdp1[0][0] = dp1[1][1] = 1;\n\tfor (i = 1; i < m; i++)\n\t\tfor (k = i; k >= 0; k--) {\n\t\t\tint x = dp1[k][0], y = dp1[k][1];\n\n\t\t\tdp1[k][0] = ((long long) x * (A - 2) + y) % MD;\n\t\t\tdp1[k + 1][1] = (long long) x * (A - 1) % MD;\n\t\t}\n\tdp2[0][0][0] = dp2[1][0][1] = dp2[0][1][2] = 1;\n\tfor (i = 1; i < m; i++)\n\t\tfor (k = i; k >= 0; k--)\n\t\t\tfor (l = i - k; l >= 0; l--) {\n\t\t\t\tint x = dp2[k][l][0], y = dp2[k][l][1], z = dp2[k][l][2];\n\n\t\t\t\tdp2[k][l][0] = ((long long) x * (A - 3) + y + z) % MD;\n\t\t\t\tdp2[k + 1][l][1] = ((long long) x * (A - 2) + z) % MD;\n\t\t\t\tdp2[k][l + 1][2] = ((long long) x * (A - 2) + y) % MD;\n\t\t\t}\n\tfor (k = 0; k <= m; k++)\n\t\taa1[k] = ((long long) dp1[k][0] * (A - 1) + dp1[k][1]) % MD;\n\tfor (k1 = 0; k1 <= m; k1++)\n\t\tfor (k2 = max(n / 3 + 1 - k1, 0); k2 <= n - m; k2++)\n\t\t\tdq1[k1 + k2] = (dq1[k1 + k2] + (long long) aa1[k1] * aa1[k2]) % MD;\n\tfor (k = 0; k <= m; k++)\n\t\tfor (l = 0; k + l <= m; l++)\n\t\t\taa2[k][l] = ((long long) dp2[k][l][0] * (A - 2) + dp2[k][l][1] + dp2[k][l][2]) % MD;\n\tfor (k1 = 0; k1 <= m; k1++)\n\t\tfor (k2 = max(n / 3 + 1 - k1, 0); k2 <= n - m; k2++)\n\t\t\tfor (l1 = 0; k1 + l1 <= m; l1++)\n\t\t\t\tfor (l2 = max(n / 3 + 1 - l1, 0); k2 + l2 <= n - m; l2++)\n\t\t\t\t\tdq2[k1 + k2][l1 + l2] = (dq2[k1 + k2][l1 + l2] + (long long) aa2[k1][l1] * aa2[k2][l2]) % MD;\n\tans = A * A;\n\tfor (i = 2; i < n; i++)\n\t\tans = (long long) ans * (A - 1) % MD;\n\tfor (a = 0; a < A; a++)\n\t\tfor (k = kk[a] + 1; k <= n; k++)\n\t\t\tans = (ans - dq1[k]) % MD;\n\tfor (a = 0; a < A; a++)\n\t\tfor (b = a + 1; b < A; b++)\n\t\t\tfor (k = kk[a] + 1; k <= n; k++)\n\t\t\t\tfor (l = kk[b] + 1; k + l <= n; l++)\n\t\t\t\t\tans = (ans + dq2[k][l]) % MD;\n\tif (ans < 0)\n\t\tans += MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "750d5604f87e1d6b5bcb4e73e8038bed", "src_uid": "1f012349f4b229dc98faadf1ca732355", "difficulty": 2700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t400\n#define M\t200\n#define A\t26\n#define MD\t998244353\n\nint max(int a, int b) { return a > b ? a : b; }\n\nint main() {\n\tstatic int kk[A], dp[N + 1][M + 1][2], dq[N + 1][M + 1][M + 1][3], dr[N + 1], ds[N + 1][N + 1], aa1[M + 1], aa2[M + 1], bb1[M + 1][M + 1], bb2[M + 1][M + 1];\n\tint n, m, i, k, l, k1, l1, k2, l2, a, b, ans;\n\n\tscanf(\"%d\", &n), m = (n + 1) / 2;\n\tfor (a = 0; a < A; a++)\n\t\tscanf(\"%d\", &kk[a]);\n\tdp[1][0][0] = dp[1][1][1] = 1;\n\tfor (i = 1; i < m; i++)\n\t\tfor (k = i; k >= 0; k--) {\n\t\t\tint x = dp[i][k][0], y = dp[i][k][1];\n\n\t\t\tdp[i + 1][k][0] = ((long long) x * (A - 2) + y) % MD;\n\t\t\tdp[i + 1][k + 1][1] = (long long) x * (A - 1) % MD;\n\t\t}\n\tdq[1][0][0][0] = dq[1][1][0][1] = dq[1][0][1][2] = 1;\n\tfor (i = 1; i < m; i++)\n\t\tfor (k = i; k >= 0; k--)\n\t\t\tfor (l = i - k; l >= 0; l--) {\n\t\t\t\tint x = dq[i][k][l][0], y = dq[i][k][l][1], z = dq[i][k][l][2];\n\n\t\t\t\tdq[i + 1][k][l][0] = ((long long) x * (A - 3) + y + z) % MD;\n\t\t\t\tdq[i + 1][k + 1][l][1] = ((long long) x * (A - 2) + z) % MD;\n\t\t\t\tdq[i + 1][k][l + 1][2] = ((long long) x * (A - 2) + y) % MD;\n\t\t\t}\n\tfor (k1 = 0; k1 <= m; k1++)\n\t\taa1[k1] = ((long long) dp[m][k1][0] * (A - 1) + dp[m][k1][1]) % MD;\n\tfor (k2 = 0; k2 <= n - m; k2++)\n\t\taa2[k2] = ((long long) dp[n - m][k2][0] * (A - 1) + dp[n - m][k2][1]) % MD;\n\tfor (k1 = 0; k1 <= m; k1++)\n\t\tfor (k2 = max(n / 3 + 1 - k1, 0); k2 <= n - m; k2++)\n\t\t\tdr[k1 + k2] = (dr[k1 + k2] + (long long) aa1[k1] * aa2[k2]) % MD;\n\tfor (k1 = 0; k1 <= m; k1++)\n\t\tfor (l1 = 0; k1 + l1 <= m; l1++)\n\t\t\tbb1[k1][l1] = ((long long) dq[m][k1][l1][0] * (A - 2) + dq[m][k1][l1][1] + dq[m][k1][l1][2]) % MD;\n\tfor (k2 = 0; k2 <= n - m; k2++)\n\t\tfor (l2 = 0; k2 + l2 <= n - m; l2++)\n\t\t\tbb2[k2][l2] = ((long long) dq[n - m][k2][l2][0] * (A - 2) + dq[n - m][k2][l2][1] + dq[n - m][k2][l2][2]) % MD;\n\tfor (k1 = 0; k1 <= m; k1++)\n\t\tfor (k2 = max(n / 3 + 1 - k1, 0); k2 <= n - m; k2++)\n\t\t\tfor (l1 = 0; k1 + l1 <= m; l1++)\n\t\t\t\tfor (l2 = max(n / 3 + 1 - l1, 0); k2 + l2 <= n - m; l2++)\n\t\t\t\t\tds[k1 + k2][l1 + l2] = (ds[k1 + k2][l1 + l2] + (long long) bb1[k1][l1] * bb2[k2][l2]) % MD;\n\tans = A * A;\n\tfor (i = 2; i < n; i++)\n\t\tans = (long long) ans * (A - 1) % MD;\n\tfor (a = 0; a < A; a++)\n\t\tfor (k = kk[a] + 1; k <= n; k++)\n\t\t\tans = (ans - dr[k]) % MD;\n\tfor (a = 0; a < A; a++)\n\t\tfor (b = a + 1; b < A; b++)\n\t\t\tfor (k = kk[a] + 1; k <= n; k++)\n\t\t\t\tfor (l = kk[b] + 1; k + l <= n; l++)\n\t\t\t\t\tans = (ans + ds[k][l]) % MD;\n\tif (ans < 0)\n\t\tans += MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9adc28856fe8d9b252ba1c9ec7188a2b", "src_uid": "1f012349f4b229dc98faadf1ca732355", "difficulty": 2700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define ABS(s) ((s) > (0) ? (s) : (-(s)))\n#define MIN(a, b) ((a) < (b) ? (a) : (b))\n\nint judge(int x, int y, int n)\n{\n    if (x == 0)\n    {\n        return 1;\n    }\n    if (x == n)\n    {\n        return 3;\n    }\n    if (y == 0)\n    {\n        return 4;\n    }\n    return 2;\n}\n\nvoid func(int n, int x1, int y1, int x2, int y2)\n{\n    int t1, t2;\n    if (x1 == x2)\n    {\n        if (x1 == 0 || x1 == n)\n        {\n            printf(\"%d\\n\", ABS(y1 - y2));\n        }\n        else\n        {\n            printf(\"%d\\n\", n + 2 * MIN(x1, n - x1));\n        }\n    }\n    else if (y1 == y2)\n    {\n        if (y1 == 0 || y1 == n)\n        {\n            printf(\"%d\\n\", ABS(x1 - x2));\n        }\n        else\n        {\n            printf(\"%d\\n\", n + 2 * MIN(y1, n - y1));\n        }\n    }\n    else\n    {\n        t1 = judge(x1, y1, n);\n        t2 = judge(x2, y2, n);\n        if (t2 == 1 && t1 == 2 || t2 == 2 && t1 == 3 || t2 == 3 && t1 == 4 || t2 == 4 && t1 == 1 || t2 == 1 && t1 == 3 || t2 == 2 && t1 == 4)\n        {\n            t1 ^= t2;\n            t2 ^= t1;\n            t1 ^= t2;\n            x1 ^= x2;\n            x2 ^= x1;\n            x1 ^= x2;\n            y1 ^= y2;\n            y2 ^= y1;\n            y1 ^= y2;\n        }\n        if (t1 == 1 && t2 == 2)\n        {\n            printf(\"%d\\n\", n - y1 + x2);\n        }\n        else if (t1 == 2 && t2 == 3)\n        {\n            printf(\"%d\\n\", n - x1 + n - y2);\n        }\n        else if (t1 == 3 && t2 == 4)\n        {\n            printf(\"%d\\n\", y1 + n - x2);\n        }\n        else if (t1 == 4 && t2 == 1)\n        {\n            printf(\"%d\\n\", x1 + y2);\n        }\n        else if (t1 == 1 && t2 == 3)\n        {\n            printf(\"%d\\n\", n + MIN(n - y1 + n - y2, y1 + y2));\n        }\n        else if (t1 == 2 && t2 == 4)\n        {\n            printf(\"%d\\n\", n + MIN(n - x1 + n - x2, x1 + x2));\n        }\n    }\n}\n\nint main()\n{\n    int n, x1, y1, x2, y2;\n    while (scanf(\"%d%d%d%d%d\", &n, &x1, &y1, &x2, &y2) == 5)\n    {\n        func(n, x1, y1, x2, y2);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c37fb22f550eccb7eea2575719c6f507", "src_uid": "685fe16c217b5b71eafdb4198822250e", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n\nint main()\n{\n    int s1=0,s2=0, i, j, n, x1, y1, x2, y2;\n    scanf(\"%d %d %d %d %d\", &n, &x1, &y1, &x2, &y2);\n\n    if(x1==x2 && y1==y2){\n        printf(\"0\");\n        return 0;\n    }\n    if(x1==x2 && (x1==0 || x1==n)){\n        printf(\"%d\", abs(y1-y2));\n        return 0;\n    }\n    else if(y1==y2 &&(y1==0 || y1==n)){\n        printf(\"%d\", abs(x1-x2));\n        return 0;\n    }\n    while(1){\n        if(x1>=0 && x1<=n && y1==0){\n            s1 = abs(x2-x1);\n            if(x2==n && y2>=0 && y2<=n){\n                s1+=(y2);\n                break;\n            }\n            else s1+=n;\n            if(y2==n && x2>=0 && x2<=n){\n                s1+=abs(n-x2);\n                break;\n            }\n            else s1+=n;\n            s1+=abs(n-y2);\n            break;\n        }\n        else if(x1==n){\n            s1=abs(n-y1);\n            if(y2==n && x2>=0 && x2<=n){\n                s1+=abs(n-x2);\n                break;\n            }\n            else s1+=n;\n            if(x2==0 && y2>=0 && y2<=n){\n                s1+=abs(n-y2);\n                break;\n            }\n            else s1+=n;\n            s1+=x2;\n            break;\n        }\n        else if(y1==n){\n            s1+=x1;\n            if(x2==0 && y2>=0 && y2<=n){\n                s1+=abs(n-y2);\n                break;\n            }\n            else s1+=n;\n            if(y2==0 && x2>=0 && x2<=n){\n                s1+=x2;\n                break;\n            }\n            else s1+=n;\n            s1+=y2;\n            break;\n        }\n        else{\n            s1+=y1;\n            if(y2==0 && x2>=0 && x2<=n){\n                s1+=x2;\n                break;\n            }\n            else s1+=n;\n            if(x2==n && y2>=0 && y2<=n){\n                s1+=y2;\n                break;\n            }\n            else s1+=n;\n            s1+=abs(n-x2);\n            break;\n        }\n\n    }\n    s2=(4*n)-s1;\n    if(s1<s2){\n        printf(\"%d\", s1);\n\n    }\n    else{\n        printf(\"%d\", s2);\n    }\n\n\n\n\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "74cd2d3cfdd585e8fd72ff762698b733", "src_uid": "685fe16c217b5b71eafdb4198822250e", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <conio.h>\n\n#define MIN(x,y) ((x)<(y))? (x) : (y)\n#define abs(x) ((x)>(0))? (x) : -(x)\n\nint main()\n{\n\tint n,x1,y1,x2,y2,r;\n\tscanf(\"%d %d %d %d %d\",&n,&x1,&y1,&x2,&y2);\n\tif(x1==x2&&y1==y2)printf(\"0\");\n\telse if((x1==0&&x2==0)||(x1==n&&x2==n))printf(\"%d\",abs(y1-y2));\n\telse if((y1==0&&y2==0)||(y1==n&&y2==n))printf(\"%d\",abs(x1-x2));\n\telse if(x1==0 && y2==n) printf(\"%d\",x2+(n-y1));\n\telse if(x1==n && y2==0) printf(\"%d\",(n-x2)+y1);\n\telse if(x2==0 && y1==n) printf(\"%d\",x1+(n-y2));\n\telse if(x2==n && y1==0) printf(\"%d\",(n-x1)+y2);\n\telse\n\t{\n\t\tr=x1+y1+x2+y2;\n\t\tprintf(\"%d\",MIN(r,(4*n-r)));\n\t}\n\tgetch();\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "728c72e0d064fdb7533d7e62ba1be564", "src_uid": "685fe16c217b5b71eafdb4198822250e", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "\\subsection{\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u03e9}\n% \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd(\ufffd\ufffd\ufffd\ufffd\u0224\ufffd\ufffd\u01bd\ufffd\u0175\ufffd\ufffd\ufffd\ufffd\ufffd\u03e4\ufffd\ufffd\ufffd)\n% \ufffd\ufffd\u0175\ufffd\u02a4\ufffd\ufffd\ufffd\ufffd\u03e1\ufffd\u036d\u033e\ufffd\u023b\u05e4\ufffd\ufffd\ufffd\u02a4\ufffd\u036d\u033e\ufffd\ufffd\ufffd\ua862\ufffd\ufffd\ufffd\ufffd\ufffd\u01e4\u02a4\ufffd\ufffd\ufffd\ufffd\ufffd\u03fa\ufffd\ufffd\ufffd\ufffd\ufffd\u0235\ufffd\ufffd\ufffd\ufffd\u01a4\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\n\\begin{problem}{Codeforces Round57(\ufffd\ufffd\ufffd\ufffd)}\n$(0,0),(n,0),(0,n),(n,n)$\ufffd\ufffd4\ufffd\ufffd\ufffd\ufffd\u013a\ufffd\ufffd\ufffd\u0224\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0364\ufffd\ufffd\ufffd($n$\ufffd\u03fc\ufffd\ufffd\ufffd\ufffd\ufffd)\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u03bc\ufffd\ufffd\ufffd\u03b3\u02bb\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u037f\ufffd\ufffd\ufffd\ufffd\ufffd\ub863\ufffd\ufffd\ufffd\u03bb\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u05a1\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u03bc\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0324\ufffd\ufffd\u00fb\ufffd\ufffd\u03e9\ufffd\u03b5\ufffd\u03a5\ufffd\ufffd\u05fb\ufffd\ufffd\ufffd\ufffd\ufffd\u05e5?\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u8863\n\\end{problem}\n\n% \ufffd\ufffd\ufffd\ufffd\ufffd\u03e4\u02e4\u0124\ufffd\ufffd\u01bd\ufffd\n\\begin{inputformat}\n$n$\ufffd\u06a4\ufffd2\ufffd\u02bb\ufffd\ufffd\ufffd\ufffd\u03ba\ufffd\u0278$(x_1,y_1),(x_2,y_2)$\ufffd\u03ba\ufffd\u0278\ufffd\ufffd\ufffd\ufffd\ufffd\u03bd\ufffd\ufffd\u05a4\ufffd\u023e\ufffd\u0476\ufffd\ufffd\ufffd\ufffd\ufffd\u06a4\ufffd\ufffd\u037f\ufffd\ufffd\ufffd\ufffd\ufffd\ub863$n$\ufffd\ufffd1000\ufffd\u02b2\ufffd\ufffd\u01e4\ufffd\ufffd\ua862\ufffd\u02bb\ufffd\ufffd\ufffd\ufffd\u03ba\ufffd\u0278\ufffd\u03e4\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd$n$\ufffd\u02b2\ufffd\ufffd\u01e4\ufffd\ufffd\ub863\n\\end{inputformat}\n\\begin{outputformat}\n\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u03a4\u07e4\ufffd\ufffd\u0324\ufffd\ufffd\u00fb\ufffd\ufffd\u03e9\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0124\u01fd\ufffd\ufffd\u03e4\ufffd\ufffd\u8863\n\\end{outputformat}\n\\begin{multicols}{2}\n\\begin{inputsample}\n2 0 1 2 1\n\\end{inputsample}\n\\begin{outputsample}\n4\n\\end{outputsample}\n\\end{multicols}\n% \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\n\\begin{explanation}\n\ufffd\ufffd\ufffd\u023d\ufffd\u01e4\ufffd\ufffd\u0464\ufffd\ufffd\u01bd\ud952\udd24\u01a4\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0224\u02e4\u02a4\ub8632\ufffd\ufffd\ufffd\u03b0\ufffd\ufffd\u05b4\u0637\ufffd\ufffd\u01fe\ufffd\ufffd\u023d\ufffd\u01e4\uda53\ude64\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0464\uf937\ufffd\ufffd(\u00ae\ufffd\ufffd\ufffd\u03a4\ufffd\u00ae\ufffd\ufffd)\ufffd\u03a4\u01e1\ufffd\ufffd\u2926\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u00f1\ufffd\ufffd\ufffd\ufffd\u02e1\ufffd\u03e4\u02a4\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0224\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0224\u02e4\u02a4\ub863\ufffd\ufffd\ufffd\ufffd\ufffd\u01e1\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u013e\ufffd\ufffd\ufffd\u0224\u07e4\u02a4\ufffd\ufffd\ufffd\u03a4\u0224\ufffd\ufffd\ub863$(0,0)$\ufffd\ufffd\ufffd\u06a4\ufffd\u03a4\u01e4\ufffd\ufffd\ub863\ufffd\ufffd\ufffd\ufffd\ufffd\u01a1\ufffd\ufffd\u0264\ufffd\ufffd\u992b\ufffd\u03bc\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u01a1\ufffd$(0,0)$\ufffd\ufffd\ufffd\ufffd\u03b5\ufffd\u03a5\ufffd\ufffd\u05fb\ufffd\ufffd\ufffd\ufffd\ub863\ufffd\ufffd\ufffd\u03b8\u5862\ufffd\u05fb\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u03a5\ufffd\ufffd\ufffd\u7926\ufffd\ufffd\ufffd\u0224\u01e1\ufffd\ufffd\ufffd\u03a5\ufffd\ufffd\ufffd\u0424\ub863\ufffd\u2937\ufffd\u293d\ufffd\uc92c\ufffd\ufffd\ufffd\ufffd\ufffd1\ufffd\ufffd\ufffd\ufffd\u023e\u02ac\ufffd\ufffd\ufffd\ufffd\u0139\ufffd\ufffd\ufffd\ufffd\u0421\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd1\ufffd\ufffd\ufffd\ufffd\ufffd\u993d\ufffd\u03b5\ufffd\u03a5\ufffd\ufffd\ufffd\u01a4\ufffd\ufffd\u043a\ufffd\u00fb\ufffd\ufffd\u03a5\ufffd\u02e4\u02a4\ub863\n\\end{explanation}\n\n% \ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\n\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\\verb|seigyo_bc_sano_9.c|\n\n\\newpage\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0161e5a5914c4784343faa65f967c747", "src_uid": "685fe16c217b5b71eafdb4198822250e", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include <stdlib.h>\nint min(int num1, int num2);\n\nint main()\n{\n\n    int n = 0;\n    int x1 = 0;\n    int y1 = 0;\n    int x2 = 0;\n    int y2 = 0;\n\n    scanf(\"%d %d %d %d %d\", &n, &x1, &y1 ,&x2 , &y2);\n    if(abs(x2-x1)!=n && abs(y2-y1)!=n){\n    int distance = abs(x2-x1)+abs(y2-y1);\n    printf(\"%d\",distance);}\n    else if( abs(x2-x1)==n) {\n      int distance =min(y1+y2,n-y1+n-y2)+n;\n      printf(\"%d\",distance);\n    }\n    else if( abs(y2-y1)==n) {\n        int distance = min(x1+x2,n-x1+n-x2)+n;\n      printf(\"%d\",distance);\n    }", "lang_cluster": "C", "compilation_error": true, "code_uid": "4b6b57b9945dca5c23af50678f74134e", "src_uid": "685fe16c217b5b71eafdb4198822250e", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nlong long Veci(long long a,long long b)\n{\n    if (a>b)\n        return a;\n    else return b;\n}\nvoid swap(long long* a,long long* b)\n{\n    long long c;\n    c=*a;\n    *a=*b;\n    *b=c;\n}\nlong long Partition(long long *A, long long left, long long right)\n{\n    long long pivot = A[right], i = left, x;\n\n    for (x = left; x < right; x++){\n        if (A[x] <= pivot){\n            swap(&A[i], &A[x]);\n            i++;\n        }\n    }\n\n    swap(&A[i], &A[right]);\n    return i;\n}\nvoid QuickSort(long long Niz[],long long Levo,long long Desno)\n{\n    if(Levo<Desno)\n    {\n        long long pos;\n        pos=Partition(Niz,Levo,Desno);\n        QuickSort(Niz,Levo,pos-1);\n        QuickSort(Niz,pos+1,Desno);\n    }\n}\nlong long x,y,l,r,i,j,p,A[60],B[60],p1,C[3600],raz=-1,br2=0,i,j,praz=0;\nint main()\n{\n    int br,br1;\n    scanf(\"%lld%lld%lld%lld\",&x,&y,&l,&r);\n    p=1;\n    br=0;\n    while (p<r)\n    {\n        A[br]=p;\n        p=p*x;\n        br++;\n    };\n    br1=0;\n    p1=1;\n    while (p1<r)\n    {\n        B[br1]=p1;\n        p1=p1*y;\n        br1++;\n    }\n    for(i=0;i<br;i++)\n        for(j=0;j<br1;j++)\n        {\n            C[br2]=A[i]+B[j];\n            if (C[br2]<=r && C[br2]>=l)\n                br2++;\n        }\n    if (br2==0)\n        printf(\"%i\",r-l+1);\n    else if (br2==l-r+1)\n        printf(\"0\");\n    else {\n        QuickSort(C,0,br2-1);\n        for(i=1;i<br2;i++)\n        {\n            praz=C[i]-C[i-1]-1;\n            if (praz>raz)\n                raz=praz;\n        }\n        if (l!=C[0])\n            raz=Veci(C[0]-l,raz);\n        if (r!=C[br2-1])\n            raz=Veci(r-C[br2-1],raz);\n        printf(\"%lld\",raz);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bfcc1aaa55c2f99c639ea21f9e9c581e", "src_uid": "68ca8a8730db27ac2230f9fe9b120f5f", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nlong long Veci(long long a,long long b)\n{\n    if (a>b)\n        return a;\n    else return b;\n}\nvoid swap(long long* a,long long* b)\n{\n    long long c;\n    c=*a;\n    *a=*b;\n    *b=c;\n}\nlong long Partition(long long *A, long long left, long long right)\n{\n    long long pivot = A[right], i = left, x;\n\n    for (x = left; x < right; x++){\n        if (A[x] <= pivot){\n            swap(&A[i], &A[x]);\n            i++;\n        }\n    }\n\n    swap(&A[i], &A[right]);\n    return i;\n}\nvoid QuickSort(long long Niz[],long long Levo,long long Desno)\n{\n    if(Levo<Desno)\n    {\n        long long pos;\n        pos=Partition(Niz,Levo,Desno);\n        QuickSort(Niz,Levo,pos-1);\n        QuickSort(Niz,pos+1,Desno);\n    }\n}\nlong long x,y,l,r,i,j,p,A[60],B[60],p1,C[3600],raz=-1,br2=0,i,j,praz=0;\nint main()\n{\n    int br,br1;\n    scanf(\"%lld%lld%lld%lld\",&x,&y,&l,&r);\n    p=1;\n    br=0;\n    while (p<r)\n    {\n        A[br]=p;\n        p=p*x;\n        br++;\n    };\n    br1=0;\n    p1=1;\n    while (p1<r)\n    {\n        B[br1]=p1;\n        p1=p1*y;\n        br1++;\n    }\n    for(i=0;i<br;i++)\n        for(j=0;j<br1;j++)\n        {\n            C[br2]=A[i]+B[j];\n            if (C[br2]<=r && C[br2]>=l)\n                br2++;\n        }\n    if (br2==0)\n        printf(\"%lld\",r-l+1);\n    else if (br2==r-l+1)\n        printf(\"0\");\n    else {\n        QuickSort(C,0,br2-1);\n        for(i=1;i<br2;i++)\n        {\n            praz=C[i]-C[i-1]-1;\n            if (praz>raz)\n                raz=praz;\n        }\n        if (l!=C[0])\n            raz=Veci(C[0]-l,raz);\n        if (r!=C[br2-1])\n            raz=Veci(r-C[br2-1],raz);\n        printf(\"%lld\",raz);\n    }\n    long long x;\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b9dae1c7f53f651541ae3d9bf8e24711", "src_uid": "68ca8a8730db27ac2230f9fe9b120f5f", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <ctype.h>\n#include <math.h>\n#define MOD 1000000007\n#define ll long long\n\nll cmpfunc(const void *a, const void *b){\n    return (*(ll*)a - *(ll*)b);\n}\n\nint max(int a,int b){\n    return (a>b)?a:b;\n}\n\nll power(ll x,ll y){\n    ll ans=1;\n    for(ll i=0;i<y;i++) ans*=x;\n    return ans;\n}\n\nint main(void){\n    ll x,y,l,r;\n    scanf(\"%lld %lld %lld %lld\",&x,&y,&l,&r);\n    ll b,d;\n    ll i,j;\n    //a=floor(1.0*log(l)/log(x));\n    b=(ll)floor(1.0*log(r)/log(x))+1;\n    //printf(\"b=%lld\\n\",b);\n    //c=floor(1.0*log(l)/log(y));\n    d=(ll)floor(1.0*log(r)/log(y))+1;\n    //printf(\"d=%lld\\n\",d);\n\n    //a<=b,c<=d\n    ll un[10000]; //stores unlucky numbers\n    int count=0; //number of unlucky numbers\n    for(i=0;i<=b;i++){\n        for(j=0;j<=d;j++){\n            if(power(x,i)>r-power(y,j)) continue;\n            ll sum=(ll)power(x,i)+(ll)power(y,j);\n            if(sum>=l){\n                            //printf(\"sum=%lld\\n\",sum);\n                un[count]=sum;\n                count++;\n            }\n        }\n    }\n    //printf(\"count=%lld\\n\",count);\n    if(count==0){\n        printf(\"%lld\\n\",r-l+1);\n        return 0;\n    }\n    ll unlucky[count];\n    for(i=0;i<count;i++) unlucky[i]=un[i];\n    ll c,d1,t;\n  for (c = 1 ; c <= count - 1; c++) {\n    d1 = c;\n\n    while ( d1 > 0 && unlucky[d1] < unlucky[d1-1]) {\n      t          = unlucky[d1];\n      unlucky[d1]   = unlucky[d1-1];\n      unlucky[d1-1] = t;\n\n      d1--;\n    }\n  }\n\n\n    //for(i=0;i<count;i++) printf(\"%lld \",unlucky[i]);\n    //putchar('\\n');\n    ll max=0;\n    for(i=0;i<count-1;i++){\n        if(unlucky[i+1]-unlucky[i]-1>max) max=unlucky[i+1]-unlucky[i]-1;\n    }\n    //printf(\"%lld %lld\\n\",max,r-unlucky[count-1]);\n    if(r-unlucky[count-1]>max) max=r-unlucky[count-1];\n    if(unlucky[0]-l>max) max=unlucky[0]-l;\n\n    printf(\"%lld\\n\",max);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "64ae239467d2e6f121955e380585a73e", "src_uid": "68ca8a8730db27ac2230f9fe9b120f5f", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\ntypedef long long int lli;\n\nvoid msort(lli a[], int s, int e)\n{\n    if(e-s!=0)\n    {\n        msort(a, s, (s+e)/2);\n        msort(a, (s+e)/2 + 1, e);\n    }\n    else\n        return;\n    lli b[e-s+1];\n    int  i=s, j=(s+e)/2 + 1, n;\n    for(n=0; i<=(s+e)/2 && j<=e;n++)\n    {\n        if(a[i]<=a[j])\n            b[n]=a[i++];\n        else\n            b[n]=a[j++];\n    }\n    if(i<=(s+e)/2)\n        for(;i<=(s+e)/2;i++, n++)\n            b[n] = a[i];\n    else\n        for(;j<=e;j++,n++)\n            b[n]=a[j];\n    for(i=0;i<n;i++, s++)\n        a[s] = b[i];\n}\n\nint main()\n{\n    lli i,j,ele;\n    lli x,y,l,r;\n    lli a[100000], b[100000];\n    scanf(\"%lld %lld %lld %lld\", &x, &y, &l, &r);\n    if(y<x)\n    {\n        y = x+y;\n        x = y - x;\n        y = y - x;\n    }\n\n    int ct = 0, ind=0;\n    i=1;\n    while(i<r)\n    {\n        a[ind++] = i+1;\n        i*=x;\n    }\n\n\n    int sind,eind;\n    sind=0;\n    eind = ind-1;\n\n\n    j=1;\n\n    while(j<r)\n    {\n        j*=y;\n        ct=0;\n        ele=0;\n        while(ele<=r && ct<=eind)\n        {\n            ele = j+a[ct++]-1;\n\n            if(ele>r)\n            {\n                break;\n            }\n            a[ind++] = ele;\n        }\n    }\n\n    ct=0;\n    for(i=0;i<ind;i++)\n        if(a[i]>=l && a[i]<=r)\n            b[ct++] = a[i];\n\n    b[ct++] = l-1;\n    b[ct++] = r+1;\n\n    msort(b, 0, ct-1);\n\n    //for(i=0;i<ct;i++)\n      //  printf(\"%lld \", b[i]);\n   // putchar('\\n');\n\n    lli  mxdif = 0;\n    for(i=0;i<ct-1;i++)\n    {\n        if(b[i+1]-b[i]>mxdif)\n        {\n            mxdif = b[i+1]-b[i];\n     //       printf(\"%lld %lld %lld\\n\",b[i], b[i+1], i);\n        }\n    }\n    printf(\"%lld\\n\", mxdif-1);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "72490fd09da4a5f5c2e7aa486176925e", "src_uid": "68ca8a8730db27ac2230f9fe9b120f5f", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint compare(const void *a, const void *b) {\n\tlong long ia = *(long long *) a;\n\tlong long ib = *(long long *) b;\n\n\treturn ia == ib ? 0 : ia < ib ? -1 : 1;\n}\n\nint main() {\n\tstatic long long aa[100000];\n\tlong long x, y, l, r, a, b, max;\n\tint k, i;\n\n\tscanf(\"%lld%lld%lld%lld\", &x, &y, &l, &r);\n\tk = 0;\n\tfor (a = 1; a <= r; a *= x)\n\t\tfor (b = 1; b <= r; b *= y)\n\t\t\tif (a + b >= l && a + b <= r)\n\t\t\t\taa[k++] = a + b;\n\taa[k++] = l - 1;\n\taa[k++] = r + 1;\n\tqsort(aa, k, sizeof *aa, compare);\n\tmax = 0;\n\tfor (i = 1; i < k; i++)\n\t\tif (max < aa[i] - aa[i - 1] - 1)\n\t\t\tmax = aa[i] - aa[i - 1] - 1;\n\tprintf(\"%lld\\n\", max);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2da0e37ac476cbcc0318801aa0b82d17", "src_uid": "68ca8a8730db27ac2230f9fe9b120f5f", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#define Ma 35+5\ntypedef long long ll;\nll dp[Ma+1][Ma+1],small[Ma+1][Ma+1];\nint n,h,i,j,k;\nll agg;\nint main(void)\n{\n    scanf(\"%d %d\",&n,&h);\n    dp[0][0]=1;\n    for(j=0;j<=Ma;++j) small[0][j]=1;\n    dp[1][1]=1;\n    for(i=1;i<=n;++i){\n    \tfor(j=2;j<=Ma;++j){\n    \t\tfor(k=0;k<i;++k){\n    \t\t\tdp[i][j]+= small[k][j-1] * dp[i-k-1][j-1];\n    \t\t\tdp[i][j]+= dp[k][j-1]    * small[i-k-1][j-2];\n    \t\t}\n    \t}\n    \tagg=0;\n    \tfor(k=0;k<=Ma;++k)\n    \t\tagg+=dp[i][k],small[i][k]=agg;\n    }\n    for(k=h,agg=0;k<=Ma;++k)\n    \tagg+=dp[n][k];\n    printf(\"%lli\\n\",agg);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "bcf392e73095a1b05bf1f34d7e57d9cc", "src_uid": "faf12a603d0c27f8be6bf6b02531a931", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\ntypedef long long int lli;//se declara lli como tipo de dato long long int\nlli matriz[36][36];//una matriz de 36*36 de tipo lli\n\nint main(int argc, char const *argv[]){\n    int n,h;\n    scanf(\"%d%d\",&n,&h);\n\n    for(int k=1;k<=n;k++){\n        matriz[0][k-1]=1;\n        for(int i=1;i<=n;i++) \n        \tfor(int j=0;j<i;j++) \n        \t\tmatriz[i][k]+= matriz[j][k-1]*matriz[i-1-j][k-1];\n    }\n\n    printf(\"%I64d\",matriz[n][n]-matriz[n][h-1]);\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "de28553fe5cf674cd3fbea57d711cf22", "src_uid": "faf12a603d0c27f8be6bf6b02531a931", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\n#define SIZE_N 36\n\ntypedef __int64 llg;\n\nllg fit[SIZE_N][SIZE_N];\n\nvoid initeFit()\n{\n    int i,j,k;\n\n    fit[0][0] = 1;\n    for(i = 1;i < SIZE_N;i ++) {\n        for(j = 1;j <= i;j ++) {\n            for(k = 0;k < i;k ++) {\n                fit[i][j] += fit[k][j-1] * fit[i-k-1][0] + fit[k][0] * fit[i-k-1][j-1] - fit[k][j-1] * fit[i-k-1][j-1];\n            }\n        }\n        fit[i][0] = fit[i][1];\n    }\n}\n\nint main()\n{\n    int n,h;\n\n    initeFit();\n    while(scanf(\"%d%d\",&n,&h) != EOF) {\n        printf(\"%I64d\\n\",fit[n][h]);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a65123f9b491bc2de95dc397df5e563f", "src_uid": "faf12a603d0c27f8be6bf6b02531a931", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main() {\n\tlong long **dp, *trees;\n\tint n, h;\n\tint i, j, n1, n2;\n\n\tscanf(\"%d%d\", &n, &h);\n\ttrees = calloc(n + 1, sizeof(long long));\n\tdp = calloc(n + 1, sizeof(long long *)); \n\tdp[0] = calloc(n + 1, sizeof(long long));\n\tdp[1] = calloc(n + 1, sizeof(long long));\n\n\ttrees[0] = 1;\n\tfor (i = 1; i <= n; i++)\n\t\tfor (n1 = 0; n1 < i; n1++) {\n\t\t\tn2 = i - 1 - n1;\n\t\t\ttrees[i] += (trees[n1] * trees[n2]);\n\t\t}\n\n\tdp[1][0] = dp[1][1] = 1;\n\tfor (i = 2; i <= n; i++) {\n\t\tdp[i] = calloc(n + 1, sizeof(long long));\n\t\tfor (j = 1; j <= i; j++) {\n\t\t\tfor (n1 = 0; n1 < i; n1++) {\n\t\t\t\tn2 = i - 1 - n1;\n\t\t\t\tdp[i][j] += (trees[n1] * dp[n2][j - 1]);\n\t\t\t\tdp[i][j] += (trees[n2] * dp[n1][j - 1]);\n\t\t\t\tdp[i][j] -= (dp[n1][j - 1] * dp[n2][j - 1]);\n\t\t\t }\n\t\t}\n\t\tdp[i][0] = dp[i][1];\n\t}\n\tprintf(\"%lld\\n\", dp[n][h]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "db8288b7c7c65520321666cc61487fa2", "src_uid": "faf12a603d0c27f8be6bf6b02531a931", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "\n #include<stdio.h>\n\n#define SIZE_N 36\n\ntypedef __int64 llg;\n\nllg fit[SIZE_N][SIZE_N];\n\nvoid initeFit()\n{\n    int i,j,k;\n\n    fit[0][0] = 1;\n    for(i = 1;i < SIZE_N;i ++) {\n        for(j = 1;j <= i;j ++) {\n            for(k = 0;k < i;k ++) {\n                fit[i][j] += fit[k][j-1] * fit[i-k-1][0] + fit[k][0] * fit[i-k-1][j-1] - fit[k][j-1] * fit[i-k-1][j-1];\n            }\n        }\n        fit[i][0] = fit[i][1];\n    }\n}\n\nint main()\n{\n    int n,h;\n\n    initeFit();\n    while(scanf(\"%d%d\",&n,&h) != EOF) {\n        printf(\"%I64d\\n\",fit[n][h]);\n    }\n    return 0;\n}\n\u2192Judgement Protocol\nPrueba: # 1, tiempo: 30ms, la memoria:. 4KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n3 2\nSalida\n5\nResponder\n5\ncorrector de registro\nok 1 number(s): \"5\"\nPrueba: # 2, tiempo: 0ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n3 3\nSalida\n4\nResponder\n4\ncorrector de registro\nok 1 number(s): \"4\"\nPrueba: # 3, tiempo: 0ms, la memoria:. 4KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n1 1\nSalida\n1\nResponder\n1\ncorrector de registro\nok 1 number(s): \"1\"\nPrueba: # 4, tiempo: 0ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n2 1\nSalida\n2\nResponder\n2\ncorrector de registro\nok 1 number(s): \"2\"\nPrueba: # 5, tiempo: 30ms, la memoria:. 16KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n2 2\nSalida\n2\nResponder\n2\ncorrector de registro\nok 1 number(s): \"2\"\nPrueba: # 6, tiempo: 30ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n27 11\nSalida\n61162698256896\nResponder\n61162698256896\ncorrector de registro\nok 1 number(s): \"61162698256896\"\nPrueba: # 7, tiempo: 0ms, la memoria:. 4KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n32 27\nSalida\n22643872890880\nResponder\n22643872890880\ncorrector de registro\nok 1 number(s): \"22643872890880\"\nPrueba: # 8, tiempo: 30ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n4 1\nSalida\n14\nResponder\n14\ncorrector de registro\nok 1 number(s): \"14\"\nPrueba: # 9, tiempo: 0ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n9 1\nSalida\n4862\nResponder\n4862\ncorrector de registro\nok 1 number(s): \"4862\"\nPrueba: # 10, tiempo: 30ms, la memoria:. 4KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n33 4\nSalida\n212336130412243110\nResponder\n212336130412243110\ncorrector de registro\nok 1 number(s): \"212336130412243110\"\nPrueba: # 11, tiempo: 0ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n4 4\nSalida\n8\nResponder\n8\ncorrector de registro\nok 1 number(s): \"8\"\nPrueba: # 12, tiempo: 30ms, la memoria:. 4KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n8 5\nSalida\n1336\nResponder\n1336\ncorrector de registro\nok 1 number(s): \"1336\"\nPrueba: # 13, tiempo: 30ms, la memoria:. 12KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n12 8\nSalida\n127200\nResponder\n127200\ncorrector de registro\nok 1 number(s): \"127200\"\nPrueba: # 14, tiempo: 30ms, la memoria:. 4KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n15 5\nSalida\n9694844\nResponder\n9694844\ncorrector de registro\nok 1 number(s): \"9694844\"\nPrueba: # 15, tiempo: 0ms, la memoria:. 4KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n19 18\nSalida\n2424832\nResponder\n2424832\ncorrector de registro\nok 1 number(s): \"2424832\"\nPrueba: # 16, tiempo: 0ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n23 17\nSalida\n19649347584\nResponder\n19649347584\ncorrector de registro\nok 1 number(s): \"19649347584\"\nPrueba: # 17, tiempo: 30ms, la memoria:. 4KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n27 15\nSalida\n25162319484928\nResponder\n25162319484928\ncorrector de registro\nok 1 number(s): \"25162319484928\"\nPrueba: # 18, tiempo: 0ms, la memoria:. 0KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n29 14\nSalida\n577801978306560\nResponder\n577801978306560\ncorrector de registro\nok 1 number(s): \"577801978306560\"\nPrueba: # 19, tiempo: 30ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n33 18\nSalida\n54307238601375744\nResponder\n54307238601375744\ncorrector de registro\nok 1 number(s): \"54307238601375744\"\nPrueba: # 20, tiempo: 30ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n7 7\nSalida\n64\nResponder\n64\ncorrector de registro\nok 1 number(s): \"64\"\nPrueba: # 21, tiempo: 30ms, la memoria:. 4KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n23 21\nSalida\n275251200\nResponder\n275251200\ncorrector de registro\nok 1 number(s): \"275251200\"\nPrueba: # 22, tiempo: 0ms, la memoria:. 12KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n7 3\nSalida\n429\nResponder\n429\ncorrector de registro\nok 1 number(s): \"429\"\nPrueba: # 23, tiempo: 30ms, la memoria:. 4KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n21 18\nSalida\n211156992\nResponder\n211156992\ncorrector de registro\nok 1 number(s): \"211156992\"\nPrueba: # 24, tiempo: 0ms, la memoria:. 12KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n4 1\nSalida\n14\nResponder\n14\ncorrector de registro\nok 1 number(s): \"14\"\nPrueba: # 25, tiempo: 0ms, la memoria:. 12KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n21 12\nSalida\n12153990144\nResponder\n12153990144\ncorrector de registro\nok 1 number(s): \"12153990144\"\nPrueba: # 26, tiempo: 0ms, la memoria:. 12KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n35 13\nSalida\n2690352397519398400\nResponder\n2690352397519398400\ncorrector de registro\nok 1 number(s): \"2690352397519398400\"\nPrueba: # 27, tiempo: 0ms, la memoria:. 12KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n19 2\nSalida\n1767263190\nResponder\n1767263190\ncorrector de registro\nok 1 number(s): \"1767263190\"\nPrueba: # 28, tiempo: 0ms, la memoria:. 12KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n33 26\nSalida\n434871797284864\nResponder\n434871797284864\ncorrector de registro\nok 1 number(s): \"434871797284864\"\nPrueba: # 29, tiempo: 30ms, la memoria:. 4KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n16 9\nSalida\n25607552\nResponder\n25607552\ncorrector de registro\nok 1 number(s): \"25607552\"\nPrueba: # 30, tiempo: 0ms, la memoria:. 4KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n16 14\nSalida\n1032192\nResponder\n1032192\ncorrector de registro\nok 1 number(s): \"1032192\"\nPrueba: # 31, tiempo: 0ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n10 2\nSalida\n16796\nResponder\n16796\ncorrector de registro\nok 1 number(s): \"16796\"\nPrueba: # 32, tiempo: 30ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n4 4\nSalida\n8\nResponder\n8\ncorrector de registro\nok 1 number(s): \"8\"\nPrueba: # 33, tiempo: 0ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n33 17\nSalida\n75307983624118272\nResponder\n75307983624118272\ncorrector de registro\nok 1 number(s): \"75307983624118272\"\nPrueba: # 34, tiempo: 0ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n27 25\nSalida\n6081740800\nResponder\n6081740800\ncorrector de registro\nok 1 number(s): \"6081740800\"\nPrueba: # 35, tiempo: 0ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n20 14\nSalida\n1094473728\nResponder\n1094473728\ncorrector de registro\nok 1 number(s): \"1094473728\"\nPrueba: # 36, tiempo: 0ms, la memoria:. 12KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n16 11\nSalida\n11819008\nResponder\n11819008\ncorrector de registro\nok 1 number(s): \"11819008\"\nPrueba: # 37, tiempo: 30ms, la memoria:. 12KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n10 10\nSalida\n512\nResponder\n512\ncorrector de registro\nok 1 number(s): \"512\"\nPrueba: # 38, tiempo: 0ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n4 3\nSalida\n14\nResponder\n14\ncorrector de registro\nok 1 number(s): \"14\"\nPrueba: # 39, tiempo: 0ms, la memoria:. 0KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n33 21\nSalida\n14830955929665536\nResponder\n14830955929665536\ncorrector de registro\nok 1 number(s): \"14830955929665536\"\nPrueba: # 40, tiempo: 0ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n24 20\nSalida\n8171945984\nResponder\n8171945984\ncorrector de registro\nok 1 number(s): \"8171945984\"\nPrueba: # 41, tiempo: 0ms, la memoria:. 16KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n30 16\nSalida\n1375710400053248\nResponder\n1375710400053248\ncorrector de registro\nok 1 number(s): \"1375710400053248\"\nPrueba: # 42, tiempo: 0ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n3 2\nSalida\n5\nResponder\n5\ncorrector de registro\nok 1 number(s): \"5\"\nPrueba: # 43, tiempo: 0ms, la memoria:. 4KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n9 4\nSalida\n4862\nResponder\n4862\ncorrector de registro\nok 1 number(s): \"4862\"\nPrueba: # 44, tiempo: 0ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n16 5\nSalida\n35357670\nResponder\n35357670\ncorrector de registro\nok 1 number(s): \"35357670\"\nPrueba: # 45, tiempo: 0ms, la memoria:. 4KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n22 22\nSalida\n2097152\nResponder\n2097152\ncorrector de registro\nok 1 number(s): \"2097152\"\nPrueba: # 46, tiempo: 30ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n28 23\nSalida\n739948625920\nResponder\n739948625920\ncorrector de registro\nok 1 number(s): \"739948625920\"\nPrueba: # 47, tiempo: 0ms, la memoria:. 12KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n34 1\nSalida\n812944042149730764\nResponder\n812944042149730764\ncorrector de registro\nok 1 number(s): \"812944042149730764\"\nPrueba: # 48, tiempo: 30ms, la memoria:. 4KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n7 4\nSalida\n428\nResponder\n428\ncorrector de registro\nok 1 number(s): \"428\"\nPrueba: # 49, tiempo: 0ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n14 11\nSalida\n488448\nResponder\n488448\ncorrector de registro\nok 1 number(s): \"488448\"\nPrueba: # 50, tiempo: 0ms, la memoria:. 12KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n35 1\nSalida\n3116285494907301262\nResponder\n3116285494907301262\ncorrector de registro\nok 1 number(s): \"3116285494907301262\"\nPrueba: # 51, tiempo: 0ms, la memoria:. 8KB, c\u00f3digo de salida: 0, c\u00f3digo de salida corrector: 0, veredicto:OK\nEntrada\n35 35\nSalida\n17179869184\nResponder\n17179869184\ncorrector de registro\nok 1 number(s): \"17179869184\"\nclose", "lang_cluster": "C", "compilation_error": true, "code_uid": "629820d16a2ed6b769ac761e986e7ed4", "src_uid": "faf12a603d0c27f8be6bf6b02531a931", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <cstdio>\r\n#include <numeric>\r\n#include <algorithm>\r\nusing namespace std;\r\n\r\nconst int mxN = 2e5+5;\r\nint n, a[105], dp[105][mxN];\r\nint main() {\r\n\tscanf(\"%d\", &n);\r\n\tint sum = 0;\r\n\tfor(int i=0; i<n; ++i) {\r\n\t\tscanf(\"%d\", &a[i]);\r\n\t\tsum += a[i];\r\n\t}\r\n\tif(sum&1) {\r\n\t\tprintf(\"0\\n\");\r\n\t\treturn 0;\r\n\t}\r\n\tsum /=2;\r\n\tauto check = [&]() -> bool {\r\n\t\tfor(int i=1; i<=n; ++i)\r\n\t\t\tfor(int j=0; j<=sum; ++j) {\r\n\t\t\t\tif(a[i-1] > j)\r\n\t\t\t\t\tdp[i][j] = dp[i-1][j];\r\n\t\t\t\telse \r\n\t\t\t\t\tdp[i][j] = max(dp[i-1][j], dp[i-1][j-a[i-1]]+1);\r\n\t\t\t}\r\n\t\treturn dp[n][sum];\r\n\t};\r\n\tif(!check())\r\n\t\tprintf(\"0\\n\");\r\n\telse {\r\n\t\tint tmp=0, ans=1;\r\n\t\tfor(int i=0; i<n; ++i) {\r\n\t\t\ttmp = gcd(tmp, a[i]);\r\n\t\t}\r\n\t\t\r\n\t\tfor(int i=0; i<n; ++i) {\r\n\t\t\ta[i] /= tmp;\r\n\t\t\tif(a[i]&1)\r\n\t\t\t\tans=i+1;\r\n\t\t}\r\n\t\tprintf(\"1\\n%d\\n\", ans);\r\n\t}\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f25eb334564c2fdce4e07f8d4e3b4a7f", "src_uid": "29063ad54712b4911c6bf871969ee147", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\nint a[128], mem[128][204800];\r\n\r\nint main(void) {\r\n    int n, s = 0;\r\n    scanf(\"%d\", &n);\r\n    for (int i = 1; i <= n; i++) {\r\n        scanf(\"%d\", &a[i]);\r\n    }\r\n    mem[0][0] = 1;\r\n    for (int i = 1; i <= n; i++) {\r\n        s += a[i];\r\n        for (int j = 0; j <= s; j++) {\r\n            if (j >= a[i] && mem[i - 1][j - a[i]]) mem[i][j] = 1;\r\n            else if (mem[i - 1][j]) mem[i][j] = 1;\r\n        }\r\n    }\r\n    if (s & 1) printf(\"0\");\r\n    else if (mem[n][s / 2]) {\r\n        printf(\"1\\n\");\r\n        for (int i = 1; i <= n; i++) {\r\n            if (a[i] & 1) {\r\n                printf(\"%d\", i);\r\n                return 0;\r\n            }\r\n            else if (!mem[n][(s - a[i]) / 2]) {\r\n                printf(\"%d\", i);\r\n                return 0;\r\n            }\r\n        }\r\n        return 1;\r\n    }\r\n    else printf(\"0\");\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c91f710f5cf9e946b0f406a5b0de5c1f", "src_uid": "29063ad54712b4911c6bf871969ee147", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "/* Codeforce 1516c: Baby Ehab Partitions Again */\n\n#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n\n#define N_INT      105\n#define MAX_SUM 200005\n#define min(a,b) ((a)<(b)? (a): (b))\n\nchar got [MAX_SUM];\n\nint issumto(int a[], int n, int sum)\n{ int i,j,last;\n\n  memset(got, 0, sum+1);  got[0]=1;  last=0;\n  for(i=0; i<n; i++) {\n    for(j=last; j>=0; j--) \n      if(got[j])  got[j+a[i]] = 1;\n    last = min(last+a[i], sum);\n  }\n  return got[sum];\n}\n\nint main(int argc, char *argv[])\n{ int i,n, sum, ans;\n  int a [N_INT];\n\n  scanf(\"%d\", &n);\n  for(sum=i=0; i<n; i++) {\n    scanf(\"%d\", a+i);\n    sum += a[i];\n  }\n  if(sum&1)                { ans = 0;  goto done; }\n  if(! issumto(a,n,sum/2)) { ans = 0;  goto done; }\n\n  while(1) \n    for(i=0; i<n; i++)\n      if(a[i] & 1) {ans = i + 1; goto done; }\n      else         a[i] /= 2;\n\ndone:\n  printf(\"%d\\n\", ans!=0);\n  if(ans)\n    printf(\"%d\\n\", ans);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "21d8ced96a54e9b4cb701c46df61fc71", "src_uid": "29063ad54712b4911c6bf871969ee147", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <assert.h>\r\n#include <stdbool.h>\r\n#include <stdio.h>\r\n#include <string.h>\r\n\r\nbool possible[200100];\r\n\r\nint main(void) {\r\n  int n;\r\n  int a[110];\r\n  scanf(\"%d\", &n);\r\n  int sum = 0;\r\n  for (int i = 0; i < n; i++) {\r\n    scanf(\"%d\", &a[i]);\r\n    sum += a[i];\r\n  }\r\n  if (sum % 2 == 1) {\r\n    puts(\"0\");\r\n    return 0;\r\n  }\r\n  int target = sum / 2;\r\n  int smallest_power = 10;\r\n  possible[0] = true;\r\n  for (int i = 0; i < n; i++) {\r\n    int ctz = __builtin_ctz(a[i]);\r\n    if (ctz < smallest_power) smallest_power = ctz;\r\n    for (int j = target; j >= a[i]; j--) {\r\n      if (possible[j - a[i]]) possible[j] = true;\r\n    }\r\n  }\r\n  if (!possible[target]) {\r\n    puts(\"0\");\r\n    return 0;\r\n  }\r\n  for (int i = 0; i < n; i++) {\r\n    if ((a[i] >> smallest_power) % 2 == 1) {\r\n      printf(\"1\\n%d\\n\", i + 1);\r\n      return 0;\r\n    }\r\n  }\r\n  assert(false);\r\n  return 0;\r\n}\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b9fd75214de910d1dc31c41e3cb59645", "src_uid": "29063ad54712b4911c6bf871969ee147", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <string.h>\r\n#include <stdlib.h>\r\n#include <math.h>\r\n\r\nint main(){\r\n        int n;\r\n        scanf(\"%d\",&n);\r\n        int arr[n];\r\n        int sum=0;\r\n\r\n        for(int j=0;j<n;j++){\r\n            scanf(\"%d\",&arr[j]);\r\n            sum+=arr[j];\r\n        }\r\n\r\n        if((sum%2)==1){\r\n            printf(\"0\\n\");\r\n            return 0;\r\n        }\r\n\r\n        int knapsack[n][sum+1];\r\n\r\n        for(int j=0;j<n;j++){\r\n            for(int k=0;k<=sum;k++){\r\n                knapsack[j][k]=0;\r\n            }\r\n        }\r\n\r\n        for(int j=0;j<n;j++){\r\n            knapsack[j][arr[j]]=1;\r\n            if(j==n-1)\r\n                break;\r\n            for(int k=0;k<=sum;k++){\r\n                if(knapsack[j][k]!=0){\r\n                    knapsack[j+1][k]=knapsack[j][k];\r\n                    int temp=k+arr[j+1];\r\n                    knapsack[j+1][temp]=knapsack[j][k]+1;\r\n                }\r\n            }\r\n        }\r\n\r\n        int temp=sum/2;\r\n\r\n        if(knapsack[n-1][temp]==0){\r\n            printf(\"0\\n\");\r\n            return 0;\r\n        }\r\n\r\n        printf(\"1\\n\");\r\n        for(int i=0;i<11;i++){\r\n            for(int j=0;j<n;j++){\r\n                temp=1<<i;\r\n                if((arr[j]&temp)==temp){\r\n                    printf(\"%d\\n\",(j+1));\r\n                    return 0;\r\n                }\r\n            }\r\n        }\r\n    return 0;\r\n\r\n}\r\n\r\n\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ed5b6fcaebd335c2d41f1a4787684cb7", "src_uid": "29063ad54712b4911c6bf871969ee147", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tlong long n;\n\tscanf(\"%lld\", &n);\n\tint a[111], j = 0, sum=0, i = 0;\n\twhile(n>=16)\n\t{\n\t\ta[i] = n %16;\n\t\ti++;\n\t\tn /= 16;\n\t}\n\ta[i] = n;\n\tfor (j = 0; j < i; j++)\n\t{\n\t\tif (a[j] == 0 || a[j] == 4 || a[j] == 6 || a[j] == 9 || a[j] == 10 || a[j] == 13)\n\t\t\tsum += 1;\n\t\tif (a[j] == 8 || a[j] == 11)\n\t\t\tsum += 2;\n\t}\n\tprintf(\"%d\", sum);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e8d9ccd60714016f2f24040f24059afe", "src_uid": "16a784cb9953bc91cb2e7767b04b76f2", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nunsigned loopCounts[16] = { 1, 0, 0, 0, 1, 0, 1, 0, 2, 1, 1, 2, 0, 2, 0, 0 };\n\nint main() {\n  unsigned n;\n  scanf(\"%u\", &n);\n  unsigned loopCount = 0;\n  while (n) {\n    loopCount += loopCounts[n & 0xf];\n    n >>= 4;\n  }\n  printf(\"%u\\n\", loopCount);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "82301048ee2de386a60ee5e5687f463e", "src_uid": "16a784cb9953bc91cb2e7767b04b76f2", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nchar itoc(int c)\n{\n    if(c >= 0 && c <= 9)\n        return c + '0';\n    else\n        return c - 10 + 'A';\n}\n\nint main()\n{\n    char s[100];\n    int num, i = 0;\n    scanf(\"%d\", &num);\n\n    if(num == 0)\n    {\n        printf(\"1\\n\");\n        return 0;\n    }\n\n    while(num)\n    {\n        s[i++] = itoc(num % 16);\n        num /= 16;\n    }\n    s[i] = '\\0';\n\n    i = 0;\n    int sum = 0;\n    while(s[i] != '\\0')\n    {\n        if(s[i] == '0' || s[i] == '4' || s[i] == '6' || s[i] == '9')\n            sum++;\n        if(s[i] == 'A' || s[i] == 'D')\n            sum++;\n        if(s[i] == '8' || s[i] == 'B')\n            sum += 2;\n        i++;\n    }\n\n    printf(\"%d\\n\", sum);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a147e409ff9d5d751a2b7bba3226c027", "src_uid": "16a784cb9953bc91cb2e7767b04b76f2", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tlong long n;\n\tscanf(\"%lld\", &n);\n\tint a[111], j = 0, sum=0, i = 1;\n\twhile(n>=16)\n\t{\n\t\ta[i-1] = n %16;\n\t\ti++;\n\t\tn /= 16;\n\t}\n\ta[i-1] = n;\n\tfor (j = 0; j < i; j++)\n\t{\n\t\tif (a[j] == 0 || a[j] == 4 || a[j] == 6 || a[j] == 9 || a[j] == 10 || a[j] == 13)\n\t\t\tsum += 1;\n\t\tif (a[j] == 8 || a[j] == 11)\n\t\t\tsum += 2;\n\t}\n\tprintf(\"%d\", sum);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6d28231cf5ab997ca24d8f47d70093ec", "src_uid": "16a784cb9953bc91cb2e7767b04b76f2", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(void)\n{\n\tunsigned x, y, result = 0;\n\tscanf(\"%u\", &x);\n\tdo {\n\t\ty = x & 15;\n\t\tx >>= 4;\n\t\tif (y == 0 || y == 4 || y == 6 || y == 9 || y == 10 || y == 13){\n\t\t\tresult++;\n\t\t}\n\t\tif (y == 8 || y == 11){\n\t\t\tresult += 2;\n\t\t}\n\t} while (x);\n\tprintf(\"%d\", result);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "11978f721d95b15d9ade1595b350d5c1", "src_uid": "16a784cb9953bc91cb2e7767b04b76f2", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\ntypedef long long unsigned llu;\ntypedef unsigned u;\ntypedef struct S\n{\n\tu val,ki,ka,min,max;llu sum;\n\tstruct S *lc,*rc;\n}v;\nv*alloc(u ki,u ka,u val)\n{\n\tv*x;\n\tx=(v*)malloc(sizeof(v));\n\tx->val=val;\n\tx->min=val;\n\tx->max=val;\n\tx->ki=ki;\n\tx->ka=ka;\n\tx->sum=(ka-ki+1)*(llu)val;\n\tx->lc=x->rc=NULL;\n\treturn x;\n}\nllu que(v *x,u lo,u hi)\n{\n\tif(hi<x->ki||lo>x->ka)return 0;\n\tif(lo<=x->ki&&hi>=x->ka)return x->sum;\n\tu ll,rr;\n\tif(x->val)\n\t{\n\t\tll=lo<x->ki?x->ki:lo;\n\t\trr=hi>x->ka?x->ka:hi;\n\t\tif(rr<ll)return 0;\n\t\treturn(rr-ll+1)*(llu)x->val;\n\t}\n\tllu a=que(x->lc,lo,hi)+que(x->rc,lo,hi);\n\treturn a;\n}\nvoid set(v *x,u lo,u hi,u val)\n{\n\tif(hi<x->ki||lo>x->ka||x->min>=val)\n\t{\n\t\treturn;\n\t}\n\tif(lo<=x->ki&&hi>=x->ka&&x->max<=val)\n\t{\n\t\tx->val=x->min=x->max=val;\n\t\tx->sum=val*(llu)(x->ka-x->ki+1);\n\t\treturn;\n\t}\n\tu m;\n\tif(x->val)\n\t{\n\t\tif(val<=x->val)return;\n\t\tm=(x->ki+x->ka)>>1;\n\t\tif(!x->lc)x->lc=alloc(x->ki,m,x->val);\n\t\telse\n\t\t{\n\t\t\tx->lc->val=x->lc->min=x->lc->max=x->val;\n\t\t\tx->lc->sum=(m-x->ki+1)*(llu)x->val;\n\t\t}\n\t\tif(!x->rc)x->rc=alloc(m+1,x->ka,x->val);\n\t\telse\n\t\t{\n\t\t\tx->rc->val=x->rc->min=x->rc->max=x->val;\n\t\t\tx->rc->sum=(x->ka-m)*(llu)x->val;\n\t\t}\n\t\tx->val=0;\n\t}\n\tset(x->lc,lo,hi,val);\n\tset(x->rc,lo,hi,val);\n\tif(x->lc->val&&x->lc->val==x->rc->val)\n\t{\n\t\tx->val=x->lc->val;\n\t\tx->sum=x->val*(llu)(x->ka-x->ki+1);\n\t}\n\telse x->sum=x->lc->sum+x->rc->sum;\n\tx->min=x->lc->min;\n\tx->max=x->rc->max;\n\treturn;\n}\nv *p;\nu A[222222],F[222222],G[222222];\nint main()\n{\n\tu n,h,i,j,k,x;llu r;\n\tscanf(\"%u\",&n);\n\tp=alloc(0,n,1);\n\tfor(i=0;++i<=n;A[i]=x)\n\t{\n\t\tscanf(\"%u\",&x);h=0;\n\t\tfor(j=1;j*j<=x;++j)if(x%j==0)\n\t\t{\n\t\t\tif(!F[j])F[j]=i;\n\t\t\telse if(h<j)h=j;\n\t\t\tif(j!=(k=x/j))\n\t\t\t{\n\t\t\t\tif(!F[k])F[k]=i;\n\t\t\t\telse if(h<k)h=k;\n\t\t\t}\n\t\t}\n\t\tset(p,i,n-1,h);\n\t}\n\tr=que(p,2,n-1);\n\tfor(i=n;i>1;--i)\n\t{\n\t\tx=A[i];h=0;\n\t\tfor(j=1;j*j<=x;++j)if(x%j==0)\n\t\t{\n\t\t\tif(!G[j])G[j]=i;\n\t\t\telse if(h<j)h=j;\n\t\t\tif(j!=(k=x/j))\n\t\t\t{\n\t\t\t\tif(!G[k])G[k]=i;\n\t\t\t\telse if(h<k)h=k;\n\t\t\t}\n\t\t}\n\t\tset(p,0,i-1,h);\n\t\tfor(x=A[i],j=1;j*j<=x;++j)if(x%j==0)\n\t\t{\n\t\t\tif(F[j]&&F[j]<i)set(p,F[j],i-1,j);\n\t\t\tif(F[k=x/j]&&F[k]<i)set(p,F[k],i-1,k);\n\t\t}\n\t\tr+=que(p,i==n?1:0,i-2);\n\t}\n\tprintf(\"%I64u\\n\",r);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1b49307da28ed5b021fb790cad7ebfb8", "src_uid": "deb3938a6d3f13c4ab8a0765bf0e94b0", "difficulty": 2800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\ntypedef long long unsigned llu;\ntypedef unsigned u;\ntypedef struct S\n{\n\tu val,ki,ka,min,max;llu sum;\n\tstruct S *lc,*rc;\n}v;\nv*alloc(u ki,u ka,u val)\n{\n\tv*x;\n\tx=(v*)malloc(sizeof(v));\n\tx->val=val;\n\tx->min=val;\n\tx->max=val;\n\tx->ki=ki;\n\tx->ka=ka;\n\tx->sum=(ka-ki+1)*(llu)val;\n\tx->lc=x->rc=NULL;\n\treturn x;\n}\nllu que(v *x,u lo,u hi)\n{\n//\tprintf(\"que %u %u\\n\",lo,hi);\n\tif(hi<x->ki||lo>x->ka)\n\t{\n//\t\tprintf(\"return 0\\n\");\n\t\treturn 0;\n\t}\n\tif(lo<=x->ki&&hi>=x->ka)\n\t{\n//\t\tprintf(\"Return %I64u\\n\",x->sum);\n\t\treturn x->sum;\n\t}\n\tu ll,rr;\n\tif(x->val)\n\t{\n\t\tll=lo<x->ki?x->ki:lo;\n\t\trr=hi>x->ka?x->ka:hi;\n\t\tif(rr<ll)\n\t\t{\n//\t\t\tprintf(\"return -0\\n\");\n\t\t\treturn 0;\n\t\t}\n//\t\tprintf(\"ll=%u rr=%u x->val=%u\\n\",ll,rr,x->val);\n\t\treturn(rr-ll+1)*(llu)x->val;\n\t}\n\tllu a=que(x->lc,lo,hi)+que(x->rc,lo,hi);\n//\tprintf(\"Retu5n %I64u\\n\",a);\n\treturn a;\n}\nvoid set(v *x,u lo,u hi,u val)\n{\n//\tprintf(\"set [%u %u] %u %u %u\\n\",x->ki,x->ka,lo,hi,val);\n\tif(hi<x->ki||lo>x->ka||x->min>=val)\n\t{\n//\t\tprintf(\"return %u<%u || %u>%u || %u>=%u\\n\",hi,x->ki,lo,x->ka,x->min,val);\n\t\treturn;\n\t}\n\tif(lo<=x->ki&&hi>=x->ka&&x->max<=val)\n\t{\n//\t\tprintf(\"chg %u %u -> %u\\n\",x->ki,x->ka,val);\n\t\tx->val=x->min=x->max=val;\n\t\tx->sum=val*(llu)(x->ka-x->ki+1);\n\t\treturn;\n\t}\n\tu m;\n\tif(x->val)\n\t{\n\t\tif(val<=x->val)\n\t\t{\n//\t\t\tprintf(\"small return\\n\");\n\t\t\treturn;\n\t\t}\n//\t\tprintf(\"split!\\n\");\n\t\tm=(x->ki+x->ka)>>1;\n\t\tif(!x->lc)x->lc=alloc(x->ki,m,x->val);\n\t\tif(!x->rc)x->rc=alloc(m+1,x->ka,x->val);\n\t\tx->val=0;\n\t}\n\tset(x->lc,lo,hi,val);\n\tset(x->rc,lo,hi,val);\n\tif(x->lc->val&&x->lc->val==x->rc->val)\n\t{\n//\t\tprintf(\"unit!\\n\");\n\t\tx->val=x->lc->val;\n\t\tx->sum=x->val*(llu)(x->ka-x->ki+1);\n\t}\n\telse x->sum=x->lc->sum+x->rc->sum;\n\tx->min=x->lc->min;\n\tx->max=x->rc->max;\n\treturn;\n}\nv *p;\nu A[222222],F[222222],G[222222];\nint main()\n{\n\tu n,h,i,j,k,x;llu r;\n\tscanf(\"%u\",&n);\n\tif(n<=2){printf(\"0\\n\");return 0;}\n\tp=alloc(0,n,1);\n\tfor(i=0;++i<=n;A[i]=x)\n\t{\n\t\tscanf(\"%u\",&x);h=0;\n\t\tfor(j=1;j*j<=x;++j)if(x%j==0)\n\t\t{\n\t\t\tif(!F[j])F[j]=i;\n\t\t\telse if(h<j)h=j;\n\t\t\tif(!F[k=x/j])F[k]=i;\n\t\t\telse if(h<k)h=k;\n\t\t}\n//\t\tprintf(\"set %u %u %u\\n\",i,n,h);\n\t\tset(p,i,n-1,h);\n\t}\n\tr=que(p,2,n-1);\n//\tprintf(\"r=%I64u\\n\",r);\n\tfor(i=n;i>1;--i)\n\t{\n\t\tx=A[i];h=0;\n\t\tfor(j=1;j*j<=x;++j)if(x%j==0)\n\t\t{\n\t\t\tif(!G[j])G[j]=i;\n\t\t\telse if(h<j)h=j;\n\t\t\tif(!G[k=x/j])G[k]=i;\n\t\t\telse if(h<k)h=k;\n\t\t}\n//\t\tprintf(\"set %u %u %u\\n\",0,i-1,h);\n\t\tset(p,0,i-1,h);\n\t\tfor(x=A[i],j=1;j*j<=x;++j)if(x%j==0)\n\t\t{\n\t\t\tif(F[j]&&F[j]<i)\n\t\t\t{\n//\t\t\t\tprintf(\"set %u %u %u\\n\",F[j],i-1,j);\n\t\t\t\tset(p,F[j],i-1,j);\n\t\t\t}\n\t\t\tif(F[k=x/j]&&F[k]<i)\n\t\t\t{\n//\t\t\t\tprintf(\"set %u %u %u\\n\",F[k],i-1,k);\n\t\t\t\tset(p,F[k],i-1,k);\n\t\t\t}\n\t\t}\n//\t\tprintf(\"que %u %u\\n\",1==n?1:0,i-2);\n\t\tr+=que(p,i==n?1:0,i-2);\n//\t\tprintf(\"i=%u r=%I64u\\n\",i,r);\n\t}\n\tprintf(\"%I64u\\n\",r);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "52552c3287f034d5893cdb8a4d28cdfb", "src_uid": "deb3938a6d3f13c4ab8a0765bf0e94b0", "difficulty": 2800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\ntypedef long long unsigned llu;\ntypedef unsigned u;\ntypedef struct S\n{\n\tu val,ki,ka,min,max;llu sum;\n\tstruct S *lc,*rc;\n}v;\nv*alloc(u ki,u ka,u val)\n{\n\tv*x;\n\tx=(v*)malloc(sizeof(v));\n\tx->val=val;\n\tx->min=val;\n\tx->max=val;\n\tx->ki=ki;\n\tx->ka=ka;\n\tx->sum=(ka-ki+1)*(llu)val;\n\tx->lc=x->rc=NULL;\n\treturn x;\n}\nllu que(v *x,u lo,u hi)\n{\n//\tprintf(\"que %u %u\\n\",lo,hi);\n\tif(hi<x->ki||lo>x->ka)\n\t{\n//\t\tprintf(\"return 0\\n\");\n\t\treturn 0;\n\t}\n\tif(lo<=x->ki&&hi>=x->ka)\n\t{\n//\t\tprintf(\"Return %I64u\\n\",x->sum);\n\t\treturn x->sum;\n\t}\n\tu ll,rr;\n\tif(x->val)\n\t{\n\t\tll=lo<x->ki?x->ki:lo;\n\t\trr=hi>x->ka?x->ka:hi;\n\t\tif(rr<ll)\n\t\t{\n//\t\t\tprintf(\"return -0\\n\");\n\t\t\treturn 0;\n\t\t}\n//\t\tprintf(\"ll=%u rr=%u x->val=%u\\n\",ll,rr,x->val);\n\t\treturn(rr-ll+1)*(llu)x->val;\n\t}\n\tllu a=que(x->lc,lo,hi)+que(x->rc,lo,hi);\n//\tprintf(\"Retu5n %I64u\\n\",a);\n\treturn a;\n}\nvoid set(v *x,u lo,u hi,u val)\n{\n//\tprintf(\"set [%u %u] %u %u %u\\n\",x->ki,x->ka,lo,hi,val);\n\tif(hi<x->ki||lo>x->ka||x->min>=val)\n\t{\n//\t\tprintf(\"return %u<%u || %u>%u || %u>=%u\\n\",hi,x->ki,lo,x->ka,x->min,val);\n\t\treturn;\n\t}\n\tif(lo<=x->ki&&hi>=x->ka&&x->max<=x->val)\n\t{\n//\t\tprintf(\"chg %u %u -> %u\\n\",x->ki,x->ka,val);\n\t\tx->val=x->min=x->max=val;\n\t\tx->sum=val*(llu)(x->ka-x->ki+1);\n\t\treturn;\n\t}\n\tu m;\n\tif(x->val)\n\t{\n\t\tif(val<=x->val)\n\t\t{\n//\t\t\tprintf(\"small return\\n\");\n\t\t\treturn;\n\t\t}\n//\t\tprintf(\"split!\\n\");\n\t\tm=(x->ki+x->ka)>>1;\n\t\tif(!x->lc)x->lc=alloc(x->ki,m,x->val);\n\t\tif(!x->rc)x->rc=alloc(m+1,x->ka,x->val);\n\t\tx->val=0;\n\t}\n\tset(x->lc,lo,hi,val);\n\tset(x->rc,lo,hi,val);\n\tif(x->lc->val&&x->lc->val==x->rc->val)\n\t{\n//\t\tprintf(\"unit!\\n\");\n\t\tx->val=x->lc->val;\n\t\tx->sum=x->val*(llu)(x->ka-x->ki+1);\n\t}\n\telse x->sum=x->lc->sum+x->rc->sum;\n\tx->min=x->lc->min;\n\tx->max=x->rc->max;\n\treturn;\n}\nv *p;\nu A[222222],F[222222],G[222222];\nint main()\n{\n\tu n,h,i,j,k,x;llu r;\n\tscanf(\"%u\",&n);\n\tif(n<=2){printf(\"0\\n\");return 0;}\n\tp=alloc(1,n,1);\n\tfor(i=0;++i<=n;A[i]=x)\n\t{\n\t\tscanf(\"%u\",&x);h=0;\n\t\tfor(j=1;j*j<=x;++j)if(x%j==0)\n\t\t{\n\t\t\tif(!F[j])F[j]=i;\n\t\t\telse if(h<j)h=j;\n\t\t\tif(!F[k=x/j])F[k]=i;\n\t\t\telse if(h<k)h=k;\n\t\t}\n//\t\tprintf(\"set %u %u %u\\n\",i,i,h);\n\t\tset(p,i,i,h);\n\t}\n\tr=que(p,2,n-1);\n\tfor(i=n+1;--i;)\n\t{\n\t\tx=A[i];h=0;\n\t}\n\tfor(i=n;i>1;--i)\n\t{\n\t\tx=A[i];h=0;\n\t\tfor(j=1;j*j<=x;++j)if(x%j==0)\n\t\t{\n\t\t\tif(!G[j])G[j]=i;\n\t\t\telse if(h<j)h=j;\n\t\t\tif(!G[k=x/j])G[k]=i;\n\t\t\telse if(h<k)h=k;\n\t\t}\n//\t\tprintf(\"set %u %u %u\\n\",1,i-1,h);\n\t\tset(p,1,i-1,h);\n\t\tfor(x=A[i],j=1;j*j<=x;++j)if(x%j==0)\n\t\t{\n\t\t\tif(F[j]&&F[j]<i)\n\t\t\t{\n//\t\t\t\tprintf(\"set %u %u %u\\n\",F[j],i-1,j);\n\t\t\t\tset(p,F[j],i-1,j);\n\t\t\t}\n\t\t\tif(F[k=x/j]&&F[k]<i)\n\t\t\t{\n//\t\t\t\tprintf(\"set %u %u %u\\n\",F[k],i-1,k);\n\t\t\t\tset(p,F[k],i-1,k);\n\t\t\t}\n\t\t}\n//\t\tprintf(\"que %u %u\\n\",1,i==n?i-2:i-1);\n\t\tr+=que(p,1,i==n?i-2:i-1);\n//\t\tprintf(\"i=%u r=%I64u\\n\",i,r);\n\t}\n\tprintf(\"%I64u\\n\",r);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e1e6aa338ec9ce4a071d0c79d4044a05", "src_uid": "deb3938a6d3f13c4ab8a0765bf0e94b0", "difficulty": 2800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\ntypedef long long unsigned llu;\ntypedef unsigned u;\ntypedef struct S\n{\n\tu val,ki,ka,min,max;llu sum;\n\tstruct S *lc,*rc;\n}v;\nv*alloc(u ki,u ka,u val)\n{\n\tv*x;\n\tx=(v*)malloc(sizeof(v));\n\tx->val=val;\n\tx->min=val;\n\tx->max=val;\n\tx->ki=ki;\n\tx->ka=ka;\n\tx->sum=(ka-ki+1)*(llu)val;\n\tx->lc=x->rc=NULL;\n\treturn x;\n}\nllu que(v *x,u lo,u hi)\n{\n//\tprintf(\"que %u %u\\n\",lo,hi);\n\tif(hi<x->ki||lo>x->ka)\n\t{\n//\t\tprintf(\"return 0\\n\");\n\t\treturn 0;\n\t}\n\tif(lo<=x->ki&&hi>=x->ka)\n\t{\n//\t\tprintf(\"Return %I64u\\n\",x->sum);\n\t\treturn x->sum;\n\t}\n\tu ll,rr;\n\tif(x->val)\n\t{\n\t\tll=lo<x->ki?x->ki:lo;\n\t\trr=hi>x->ka?x->ka:hi;\n\t\tif(rr<ll)\n\t\t{\n//\t\t\tprintf(\"return -0\\n\");\n\t\t\treturn 0;\n\t\t}\n//\t\tprintf(\"ll=%u rr=%u x->val=%u\\n\",ll,rr,x->val);\n\t\treturn(rr-ll+1)*(llu)x->val;\n\t}\n\tllu a=que(x->lc,lo,hi)+que(x->rc,lo,hi);\n//\tprintf(\"Retu5n %I64u\\n\",a);\n\treturn a;\n}\nvoid set(v *x,u lo,u hi,u val)\n{\n//\tprintf(\"set [%u %u] %u %u %u\\n\",x->ki,x->ka,lo,hi,val);\n\tif(hi<x->ki||lo>x->ka||x->min>=val)\n\t{\n//\t\tprintf(\"return %u<%u || %u>%u || %u>=%u\\n\",hi,x->ki,lo,x->ka,x->min,val);\n\t\treturn;\n\t}\n\tif(lo<=x->ki&&hi>=x->ka&&x->max<=val)\n\t{\n//\t\tprintf(\"chg %u %u -> %u\\n\",x->ki,x->ka,val);\n\t\tx->val=x->min=x->max=val;\n\t\tx->sum=val*(llu)(x->ka-x->ki+1);\n\t\treturn;\n\t}\n\tu m;\n\tif(x->val)\n\t{\n\t\tif(val<=x->val)\n\t\t{\n//\t\t\tprintf(\"small return\\n\");\n\t\t\treturn;\n\t\t}\n//\t\tprintf(\"split!\\n\");\n\t\tm=(x->ki+x->ka)>>1;\n\t\tif(!x->lc)x->lc=alloc(x->ki,m,x->val);\n\t\tif(!x->rc)x->rc=alloc(m+1,x->ka,x->val);\n\t\tx->val=0;\n\t}\n\tset(x->lc,lo,hi,val);\n\tset(x->rc,lo,hi,val);\n\tif(x->lc->val&&x->lc->val==x->rc->val)\n\t{\n//\t\tprintf(\"unit!\\n\");\n\t\tx->val=x->lc->val;\n\t\tx->sum=x->val*(llu)(x->ka-x->ki+1);\n\t}\n\telse x->sum=x->lc->sum+x->rc->sum;\n\tx->min=x->lc->min;\n\tx->max=x->rc->max;\n\treturn;\n}\nv *p;\nu A[222222],F[222222],G[222222];\nint main()\n{\n\tu n,h,i,j,k,x;llu r;\n\tscanf(\"%u\",&n);\n\tif(n<=2){printf(\"0\\n\");return 0;}\n\tp=alloc(0,n,1);\n\tfor(i=0;++i<=n;A[i]=x)\n\t{\n\t\tscanf(\"%u\",&x);h=0;\n\t\tfor(j=1;j*j<=x;++j)if(x%j==0)\n\t\t{\n\t\t\tif(!F[j])F[j]=i;\n\t\t\telse if(h<j)h=j;\n\t\t\tif(j!=(k=x/j))\n\t\t\t{\n\t\t\t\tif(!F[k])F[k]=i;\n\t\t\t\telse if(h<k)h=k;\n\t\t\t}\n\t\t}\n//\t\tprintf(\"set %u %u %u\\n\",i,n,h);\n\t\tset(p,i,n-1,h);\n\t}\n\tr=que(p,2,n-1);\n//\tprintf(\"r=%I64u\\n\",r);\n\tfor(i=n;i>1;--i)\n\t{\n\t\tx=A[i];h=0;\n\t\tfor(j=1;j*j<=x;++j)if(x%j==0)\n\t\t{\n\t\t\tif(!G[j])G[j]=i;\n\t\t\telse if(h<j)h=j;\n\t\t\tif(j!=(k=x/j))\n\t\t\t{\n\t\t\t\tif(!G[k])G[k]=i;\n\t\t\t\telse if(h<k)h=k;\n\t\t\t}\n\t\t}\n//\t\tprintf(\"set %u %u %u\\n\",0,i-1,h);\n\t\tset(p,0,i-1,h);\n\t\tfor(x=A[i],j=1;j*j<=x;++j)if(x%j==0)\n\t\t{\n\t\t\tif(F[j]&&F[j]<i)\n\t\t\t{\n//\t\t\t\tprintf(\"set %u %u %u\\n\",F[j],i-1,j);\n\t\t\t\tset(p,F[j],i-1,j);\n\t\t\t}\n\t\t\tif(F[k=x/j]&&F[k]<i)\n\t\t\t{\n//\t\t\t\tprintf(\"set %u %u %u\\n\",F[k],i-1,k);\n\t\t\t\tset(p,F[k],i-1,k);\n\t\t\t}\n\t\t}\n//\t\tprintf(\"que %u %u\\n\",1==n?1:0,i-2);\n\t\tr+=que(p,i==n?1:0,i-2);\n//\t\tprintf(\"i=%u r=%I64u\\n\",i,r);\n\t}\n\tprintf(\"%I64u\\n\",r);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "64d852606724e301b8d4145741cf8581", "src_uid": "deb3938a6d3f13c4ab8a0765bf0e94b0", "difficulty": 2800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\ntypedef long long unsigned llu;\ntypedef unsigned u;\ntypedef struct S\n{\n\tu val,ki,ka,min,max;llu sum;\n\tstruct S *lc,*rc;\n}v;\nv*alloc(u ki,u ka,u val)\n{\n\tv*x;\n\tx=(v*)malloc(sizeof(v));\n\tx->val=val;\n\tx->min=val;\n\tx->max=val;\n\tx->ki=ki;\n\tx->ka=ka;\n\tx->sum=(ka-ki+1)*(llu)val;\n\tx->lc=x->rc=NULL;\n\treturn x;\n}\nllu que(v *x,u lo,u hi)\n{\n//\tprintf(\"que %u %u\\n\",lo,hi);\n\tif(hi<x->ki||lo>x->ka)\n\t{\n//\t\tprintf(\"return 0\\n\");\n\t\treturn 0;\n\t}\n\tif(lo<=x->ki&&hi>=x->ka)\n\t{\n//\t\tprintf(\"Return %I64u\\n\",x->sum);\n\t\treturn x->sum;\n\t}\n\tu ll,rr;\n\tif(x->val)\n\t{\n\t\tll=lo<x->ki?x->ki:lo;\n\t\trr=hi>x->ka?x->ka:hi;\n\t\tif(rr<ll)\n\t\t{\n//\t\t\tprintf(\"return -0\\n\");\n\t\t\treturn 0;\n\t\t}\n//\t\tprintf(\"ll=%u rr=%u x->val=%u\\n\",ll,rr,x->val);\n\t\treturn(rr-ll+1)*(llu)x->val;\n\t}\n\tllu a=que(x->lc,lo,hi)+que(x->rc,lo,hi);\n//\tprintf(\"Retu5n %I64u\\n\",a);\n\treturn a;\n}\nvoid set(v *x,u lo,u hi,u val)\n{\n//\tprintf(\"set [%u %u] %u %u %u\\n\",x->ki,x->ka,lo,hi,val);\n\tif(hi<x->ki||lo>x->ka||x->min>=val)\n\t{\n//\t\tprintf(\"return %u<%u || %u>%u || %u>=%u\\n\",hi,x->ki,lo,x->ka,x->min,val);\n\t\treturn;\n\t}\n\tif(lo<=x->ki&&hi>=x->ka&&x->max<=x->val)\n\t{\n//\t\tprintf(\"chg %u %u -> %u\\n\",x->ki,x->ka,val);\n\t\tx->val=x->min=x->max=val;\n\t\tx->sum=val*(llu)(x->ka-x->ki+1);\n\t\treturn;\n\t}\n\tu m;\n\tif(x->val)\n\t{\n\t\tif(val<=x->val)\n\t\t{\n//\t\t\tprintf(\"small return\\n\");\n\t\t\treturn;\n\t\t}\n//\t\tprintf(\"split!\\n\");\n\t\tm=(x->ki+x->ka)>>1;\n\t\tif(!x->lc)x->lc=alloc(x->ki,m,x->val);\n\t\tif(!x->rc)x->rc=alloc(m+1,x->ka,x->val);\n\t\tx->val=0;\n\t}\n\tset(x->lc,lo,hi,val);\n\tset(x->rc,lo,hi,val);\n\tif(x->lc->val&&x->lc->val==x->rc->val)\n\t{\n//\t\tprintf(\"unit!\\n\");\n\t\tx->val=x->lc->val;\n\t\tx->sum=x->val*(llu)(x->ka-x->ki+1);\n\t}\n\telse x->sum=x->lc->sum+x->rc->sum;\n\tx->min=x->lc->min;\n\tx->max=x->rc->max;\n\treturn;\n}\nv *p;\nu A[222222],F[222222];\nint main()\n{\n\tu n,i,j,k,x;llu r=0llu;\n\tscanf(\"%u\",&n);\n\tif(n<=2){printf(\"0\\n\");return 0;}\n\tp=alloc(1,n,1);\n\tfor(i=0;++i<=n;A[i]=x)\n\t{\n\t\tscanf(\"%u\",&x);\n\t\tfor(j=1;j*j<=x;++j)if(x%j==0)\n\t\t{\n\t\t\tif(!F[j])F[j]=i;\n\t\t\tif(!F[k=x/j])F[k]=i;\n\t\t}\n\t}\n\tfor(i=n;i;--i)\n\t{\n\t\tfor(x=A[i],j=1;j*j<=x;++j)if(x%j==0)\n\t\t{\n\t\t\tif(F[j]&&F[j]<i)\n\t\t\t{\n//\t\t\t\tprintf(\"set %u %u %u\\n\",F[j],i-1,j);\n\t\t\t\tset(p,F[j],i-1,j);\n\t\t\t}\n\t\t\tif(F[k=x/j]&&F[k]<i)\n\t\t\t{\n//\t\t\t\tprintf(\"set %u %u %u\\n\",F[k],i-1,k);\n\t\t\t\tset(p,F[k],i-1,k);\n\t\t\t}\n\t\t}\n\t\tr+=que(p,1,i-1);\n//\t\tprintf(\"i=%u r=%I64u\\n\",i,r);\n\t}\n\tprintf(\"%I64u\\n\",r);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "41efa9500771f5b381794f3265b336f2", "src_uid": "deb3938a6d3f13c4ab8a0765bf0e94b0", "difficulty": 2800.0}
{"lang": "GNU C", "source_code": "// written based on editorial\n#include <stdio.h>\n#include <string.h>\n\nenum {\n    N = 1010\n};\nconst int MOD = 1e9 + 7;\n\nint c[N][N];\n\nint binom(int n, int m) {\n    if(m == n || m == 0)\n        return 1;\n    if(n == 0)\n        return 0;\n    if(c[n][m] != -1)\n        return c[n][m];\n    return c[n][m] = (binom(n - 1, m - 1) + binom(n - 1, m)) % MOD;\n}\n\nint main() {\n    int n, m, k;\n    memset(c, -1, sizeof(c));\n    scanf(\"%d %d %d\", &n, &m, &k);\n    long long val = binom(n - 1, 2 * k);\n    val *= binom(m - 1, 2 * k);\n    printf(\"%d\\n\", (int)(val % MOD));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "217aec1d4fb755d8d573ed3d47ba7b9b", "src_uid": "309d2d46086d526d160292717dfef308", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MOD\t1000000007\n\nint power(int a, int b) {\n\tint p;\n\n\tif (b == 0)\n\t\treturn 1;\n\tp = power(a, b / 2);\n\tp = (long long) p * p % MOD;\n\tif (b % 2 == 1)\n\t\tp = (long long) p * a % MOD;\n\treturn p;\n}\n\nint inv(int x) {\n\treturn power(x, MOD - 2);\n}\n\nint fact(int n, int is_inv) {\n\treturn n == 0 ? 1\n\t\t: (long long) fact(n - 1, is_inv) * (is_inv ? inv(n) : n) % MOD;\n}\n\nint choose(int n, int k) {\n\treturn (long long) ((long long) fact(n, 0) * fact(k, 1) % MOD)\n\t\t* fact(n - k, 1) % MOD;\n}\n\nint main() {\n\tint n, m, k;\n\n\tscanf(\"%d%d%d\", &n, &m, &k);\n\tprintf(\"%lld\\n\", n - 1 < 2 * k || m - 1 < 2 * k ? 0\n\t\t\t: (long long) choose(n - 1, 2 * k) * choose(m - 1, 2 * k) % MOD);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a297fc0e8a9c8b4142bbbe4fbbc003a3", "src_uid": "309d2d46086d526d160292717dfef308", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long dp[1001][500];\nint mod = 1000000007;\n\nint dfs(int n, int k)\n{\n    int i;\n\n    if (dp[n][k] >= 0) return dp[n][k];\n\n    if (k == 1) {\n\treturn dp[n][k] = (n - 2) * (n - 1) / 2;\n    }\n\n    dp[n][k] = 0;\n\n    for (i = k * 2 - 1; i <= n - 2; i++) {\n\tdp[n][k] = (dp[n][k] + (long long)dfs(i, k - 1) * (n - i - 1)) % mod;\n    }\n\n    return dp[n][k];\n}\n\nint main()\n{\n    int n, m, k, i, j;\n\n    scanf(\"%d %d %d\", &n, &m, &k);\n\n    if (k * 2 >= n || k * 2 >= m) {\n\tputs(\"0\");\n\n\treturn 0;\n    }\n\n    for (i = 0; i <= 1000; i++) {\n\tfor (j = 0; j <= k; j++) {\n\t    dp[i][j] = -1;\n\t}\n    }\n\n    printf(\"%d\\n\", (int)((long long)dfs(n, k) * dfs(m, k) % mod));\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d731962f82d0756bc8f1a965983da375", "src_uid": "309d2d46086d526d160292717dfef308", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\n#define ll long long\n#define M 1000000007\n\nll comb[2100][2100];\n\nint main(){\n  int i,j,k,l,m,n;\n  int x, y, t;\n  int loop;\n  ll a, b;\n\n  rep(j,2100) comb[0][j] = 0;\n  rep(i,2100) comb[i][0] = 1;\n  REP(i,1,2100) REP(j,1,2100) comb[i][j] = (comb[i-1][j-1] + comb[i-1][j]) % M;\n\n  while(scanf(\"%d%d%d\",&x,&y,&t)==3){\n    a = comb[x-1][2*t];\n    b = comb[y-1][2*t];\n    \n    k = (int)((a*b)%M);\n    printf(\"%d\\n\",k);\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8c5d274a32a53788eab0cf7b3b254fc2", "src_uid": "309d2d46086d526d160292717dfef308", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <assert.h>\n\n#define MOD 1000000007\n\nlong long waysToPlay(int n, int m, int k);\nlong long oldWaysToPlay(int n, int m, int k, long long mult);\nlong long choose(long long a, long long b);\n\nlong long oldWays;\nlong long known[1000][1000][1000];\n\nint main() {\n    int n, m, k;\n    scanf(\"%d %d %d\", &n, &m, &k);\n\n    // n: dimension\n    // y: dimension\n    // k: amount of moves\n\n    printf(\"%I64d\\n\", (choose(n-1, 2*k) * choose(m-1, 2*k)) % MOD);\n\n    oldWays = 0;\n    //long long ways = waysToPlay(n, m, k) % MOD;\n    //printf(\"%lld\\n\")\n    //printf(\"%lld\\n\", ways);\n\n    // Old\n    //oldWaysToPlay(n, m, k, 1);\n    //printf(\"%lld\\n\", oldWays);\n\n    return EXIT_SUCCESS;\n}\n\nlong long waysToPlay(int n, int m, int k) {\n    // 6, 7, 2\n    // \n    // 4, 4, 1 => 9\n    // 6, 7, 2 => 75\n\n    // If no more moves\n    if (k == 0) {\n        return 1;\n    } else if (k == 1) {\n        //printf(\"%d %d %d %lld\\n\", n, m, k, choose(n-1, 2) * choose(m-1, 2));\n        return choose(n-1, 2) * choose(m-1, 2);\n    } else {\n        // For 5x5 (3x3)\n        // Answer = 36\n        // k = 1\n        // x = 4c2\n        // y = 4c2\n\n        // 10 * 10 = 100\n\n        // Smallest cases\n        int n_small = 1 + 2*(k-1);\n        int m_small = 1 + 2*(k-1);\n        long long ways = 0;\n\n        // They must be TWO less\n        for (int n_i = n_small; n_i < n-1; n_i++) {\n            for (int m_i = m_small; m_i < m-1; m_i++) {\n                // The amount of positions that the new rectangle\n                // can fit into\n                int newMult = (n-n_i-1)*(m-m_i-1);\n\n                // Cache the result\n                if (known[m_i][n_i][k-1] == 0) {\n                    known[m_i][n_i][k-1] = waysToPlay(n_i, m_i, k-1);\n                }\n\n                // Add it to ways\n                ways += newMult * known[m_i][n_i][k-1];\n            }\n        }\n\n        //printf(\"%d %d %d %lld\\n\", n, m, k, ways);\n        \n        return ways;\n    }\n\n    // Otherwise there are no ways\n    return 0;\n}\n\nlong long choose(long long a, long long b) {\n    if (b > a) return 0;\n\n    //aCb = a!/((a-b)!*b!)\n    //    = a*(a-1)...(a-b+1)/\n    //      b*(b-1)...1\n\n    //    = a*(a-1)...(a-b+1)/\n    //      1*2*......b\n\n    long long result = 1;\n    for (int i = 0; i < b; i++) {\n        result = (result * (a-i)) % MOD;\n        result = (result / (i+1)) % MOD;\n    }\n\n    //printf(\"%lldC%lld = %lld\\n\", a, b, result);\n    return result % MOD;\n}\n\n\n//OLD method\nlong long oldWaysToPlay(int n, int m, int k, long long mult) {\n    // 3x3 in 6x7 (4x5)\n    if (k == 0) {\n        oldWays = (oldWays+mult) % MOD;\n        //printf(\"+ %lld\\n\", mult);\n    } else if (k == 1 && n == 1 && m == 1) {\n        oldWays = (oldWays+mult) % MOD;\n    } else {\n        // Smallest cases\n        int n_small = 1 + 2*(k-1);\n        int m_small = 1 + 2*(k-1);\n\n        // How many places it can go X inside solutions\n\n        // They must be TWO less\n        for (int n_i = n_small; n_i < n-1; n_i++) {\n            for (int m_i = m_small; m_i < m-1; m_i++) {\n                // Positional permutation (x,y and y,x)\n                // int twice = (m_i != n_i) ? 2 : 1;\n\n                //printf(\"passing: %d %d %lld\\n\", n_i, m_i, mult);\n                oldWaysToPlay(n_i, m_i, k-1, mult*(n-n_i-1)*(m-m_i-1));\n            }\n        }\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "57a17ce4a56e8647218511f6744aed4e", "src_uid": "309d2d46086d526d160292717dfef308", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nchar s[200005];\nlong long cnt,n,c1,c2,ans;\nlong long f(long long x) {\n\treturn c2*x*x;\n}\nint main() {\n\tscanf(\"%lld%lld%lld\",&n,&c1,&c2);\n\tscanf(\"%s\",s+1);\n\tfor(int i=1;i<=n;i++)\n\t\tif(s[i]=='1')\n\t\t\tcnt++;\n//\tprintf(\"%lld\\n\",cnt);\n\tans=1e18;\n\tfor(long long i=1;i<=cnt;i++) {\n\t\tlong long tmp=n%i,o=n/i,res=0;\n//\t\tprintf(\"%lld %lld %lld\\n\",i,tmp,o);\n\t\tres=i*c1+tmp*f(o)+(i-tmp)*f(o-1);\n\t\tif(ans>res)\n\t\t\tans=res;\n\t}\n\tprintf(\"%lld\\n\",ans);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f625338dea12c9e971421a363719e486", "src_uid": "78d013b01497053b8e321fe7b6ce3760", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define lli long long int\n\nlli n,c1,c2,pr=0;\n\nlli calc(lli gr)\n{\n    if(gr==0 || gr>pr)\n        return 1000000000000000;\n    lli num=n/gr;\n    lli r=n%gr;\n    lli ret=gr*c1;\n    ret+=r*(n/gr)*(n/gr)*c2;\n    ret+=(gr-r)*(n/gr-1)*(n/gr-1)*c2;\n    return ret;\n}\n\nint main() {\n    scanf(\"%lld%\",&n);\n    scanf(\"%lld%\",&c1);\n    scanf(\"%lld%\",&c2);\n    char s[n+1];\n    gets(s);\n    int ch=0;\n    int i;\n    for(i=0;i<n;i++)\n        if(s[i]=='1')\n            pr++;\n        else\n            ch++;\n    int l=1,h=pr;\n    lli ans;\n    while(l<=h)\n    {\n        int mid=(l+h)/2;\n        lli n1=calc(mid-1);\n        lli n2=calc(mid+1);\n        lli nm=calc(mid);\n        if(n1>nm && n2>nm)\n            {ans=nm;\n            break;}\n        else if(n1>nm)\n            ans=nm,l=mid+1;\n        else\n            h=mid-1;\n    }\n    printf(\"%lld\",ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c762feef6802deaa9b90adce41cfb31a", "src_uid": "78d013b01497053b8e321fe7b6ce3760", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n\tlong long int i,sayi,a,b,n = 0,sonuc,ensonuc = 0;\n\tscanf(\"%lld %lld\",&a,&b);\n\tfor(i = a ; i <= b ; i++){\n\t\tsayi = i;\n\t\tsonuc = 0;\n\t\twhile(sayi>=1){\n\t\t\tif(sayi%2==0)\n\t\t\t\tsonuc++;\n\t\t\tsayi=sayi/2;\n\t\t\tn++;\n\t\t}\n\t\tif(sonuc==1)\n\t\t\tensonuc++;\n\t}\n\tprintf(\"%lld\",ensonuc);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5b36b1da01fd133600ad22183e5f10a0", "src_uid": "581f61b1f50313bf4c75833cefd4d022", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n\tunsigned long long int s, e, cnt=0, curcnt, cn, temp, temp2;\n\tscanf(\"%llu %llu\",&s, &e);\n\tfor(temp=s;temp<=e;temp++){\n\t\t//printf(\"%llu\\n\",temp);\n\t\tfor(cn=temp,curcnt=0;cn>0;cn=cn>>1){\n\t\t\ttemp2=cn&1;\n\t\t\tif(temp2==0)curcnt++;\n\t\t\tif(curcnt==2) break;\n\t\t}\n\t\tif(curcnt==1) cnt++;\n\t}\n\tprintf(\"%llu\\n\",cnt);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "34546b5d3fe4111c0bda1f86ed7c19fe", "src_uid": "581f61b1f50313bf4c75833cefd4d022", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint weekday_count[8] = {0, 52, 52, 52, 52, 53, 53, 52};\nint month_days[13] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};\n\nint main()\n{\n    int x, running = 1;\n    int i, ans = 0;\n    scanf(\"%d\", &x);\n    while (running) switch (getchar()) {\n        case 'w':\n            printf(\"%d\\n\", weekday_count[x]);\n            running = 0; break;\n        case 'm':\n            for (i = 1; i <= 12; ++i) if (month_days[i] >= x) ++ans;\n            printf(\"%d\\n\", ans);\n            running = 0; break;\n        default: break;\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "23a64927f0b89aa1b951223deefc844b", "src_uid": "581f61b1f50313bf4c75833cefd4d022", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n\tlong long int i,sayi,a,b,n = 0,sonuc,ensonuc = 0;\n\tscanf(\"%l64d %l64d\",&a,&b);\n\tfor(i = a ; i <= b ; i++){\n\t\tsayi = i;\n\t\tsonuc = 0;\n\t\twhile(sayi>=1){\n\t\t\tif(sayi%2==0)\n\t\t\t\tsonuc++;\n\t\t\tsayi=sayi/2;\n\t\t\tn++;\n\t\t}\n\t\tif(sonuc==1)\n\t\t\tensonuc++;\n\t}\n\tprintf(\"%l64d\",ensonuc);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "225c7367b25f05131bd24041c36b9ee1", "src_uid": "581f61b1f50313bf4c75833cefd4d022", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h> \n#include<conio.h> \n\nint ans=0,chk1=0,chk2=0,j;\n\nint main() \n{ \n      int a[20]; \n      long long dec,i=0;\n      //printf(\"Enter the decimal number to find its binary number\\n\"); \n      scanf(\"%I64d\",&dec);\n\t  dec-=1; \n      while(dec>0) \n      { \n           a[i]=dec%2; \n           i++; \n           dec=dec/2;\n      }\n      //printf(\"Binary number of %d is = \",dec)\n\tans=0;chk1=0;chk2=0;\n      for(j=i-1;j>=0;j--) \n      {\n        if(a[j]==0){\n        \tif(chk1==0){\n        \t\tans+=i-j;\n        \t\tchk1=1;\n\t\t\t}\n\t\t\telse if(chk2==0&&chk1==1){\n\t\t\t\tchk2=1;\n\t\t\t\tans-=1;\n\t\t\t\t\n\t\t\t}\n        \t\n\t\t}\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t  //printf(\"%d\",a[j]);\n      }\n      for(j=i-1;j>0;j--){\n      \tans+=j-1;\n      \t\n\t  }\n\t  \n\t  int net=ans;\n\t  //printf(\"%d\",net);\n       dec,i=0;\n      //printf(\"Enter the decimal number to find its binary number\\n\"); \n      scanf(\"%I64d\",&dec);\n\t   \n      while(dec>0) \n      { \n           a[i]=dec%2; \n           i++; \n           dec=dec/2;\n      }\n      //printf(\"Binary number of %d is = \",dec); \n\t\n\tans=0;chk1=0;chk2=0;\n      for(j=i-1;j>=0;j--) \n      {\n        if(a[j]==0){\n        \tif(chk1==0){\n        \t\tans+=i-j;\n        \t\tchk1=1;\n\t\t\t}\n\t\t\telse if(chk2==0&&chk1==1){\n\t\t\t\tchk2=1;\n\t\t\t\tans-=1;\n\t\t\t\t\n\t\t\t}\n        \t\n\t\t}\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t  //printf(\"%d\",a[j]);\n      }\n      for(j=i-1;j>0;j--){\n      \tans+=j-1;\n      \t\n\t  }\n\t  ans-=net;\n      printf(\"%d\",ans);\n      \n      //getch();\n }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b9b642b40e6d29fa8d67ec980dad1fb6", "src_uid": "581f61b1f50313bf4c75833cefd4d022", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdbool.h>\n#include <stdio.h>\n#include <stdlib.h>\n\nint determine(int *guesses, int *bulls, int *cows, int n);\nbool is_solution(int k, int *guesses, int *bulls, int *cows, int n);\nbool fits(int k, int guess, int bulls, int cows);\n\nint main() {\n\tint n = 0, k = 0, result = 0;\n\tint *guesses = NULL;\n\tint *bulls = NULL;\n\tint *cows = NULL;\n\t\n\tscanf(\"%d\", &n);\n\t\n\tguesses = calloc(n, sizeof(int));\n\tbulls = calloc(n, sizeof(int));\n\tcows = calloc(n, sizeof(int));\n\t\n\tfor(k=0; k<n; k++) {\n\t\tscanf(\"%d %d %d\", &guesses[k], &bulls[k], &cows[k]);\n\t}\n\t\n\tresult = determine(guesses, bulls, cows, n);\n\t\n\tswitch(result) {\n\t\tcase 0:\n\t\t\tprintf(\"Incorrect data\");\n\t\t\tbreak;\n\t\tcase 1:\n\t\t\tprintf(\"Need more data\");\n\t\t\tbreak;\n\t\tdefault:\n\t\t\tprintf(\"%d\", result);\n\t\t\tbreak;\n\t}\n\t\n\tprintf(\"\\n\");\n\t\n\tfree(guesses);\n\tfree(bulls);\n\tfree(cows);\n\t\n\treturn 0;\n}\n\nint determine(int *guesses, int *bulls, int *cows, int n) {\n\tint k = 0, j = 0, result = 0;\n\t\n\tk = 1000;\n\t\n\twhile(k<=9999 && j<=1) {\n\t\tif(is_solution(k, guesses, bulls, cows, n)) {\n\t\t\tresult = k;\n\t\t\tj++;\t\n\t\t}\n\t\tk++;\n\t}\n\t\n\tif(j==2)\n\t\tresult = 1;\n\t\n\treturn result;\n}\n\nbool is_solution(int k, int *guesses, int *bulls, int *cows, int n) {\n\tbool cont = true;\n\tint j = 0;\n\t\n\twhile(cont && j<n) {\n\t\tcont = fits(k, guesses[j], bulls[j], cows[j]);\n\t\tj++;\n\t} \n\t\n\treturn cont;\n}\n\nbool fits(int k, int guess, int bulls, int cows) {\n\tint Guess[4];\n\tint K[4];\n\tbool selected[4];\n\tint j = 0, i = 0, weight = 1, weightx = 10, countb = 0, countc = 0;\n\t\n\tfor(j=0; j<4; j++) {\n\t\tGuess[j] = (guess%weightx) / weight;\n\t\tK[j] = (k%weightx) / weight;\n\t\tweight = weightx;\n\t\tweightx *= 10;\n\t}\n\t\n\tfor(j=0; j<4; j++) {\n\t\tif(Guess[j]==K[j])\n\t\t\tcountb++;\n\t}\n\t\n\tif(bulls != countb)\n\t\treturn false;\n\t\n\tfor(j=0; j<4; j++)\n\t\tselected[j] = false;\n\t\n\tfor(i=0; i<4; i++)\n\t\tfor(j=0; j<4; j++) {\n\t\t\tif(i!=j && !selected[i] && Guess[i]==K[j]) {\n\t\t\t\tcountc++;\n\t\t\t\tselected[i] = true;\n\t\t\t}\n\t\t}\n\t\n\tif(cows != countc)\n\t\treturn false;\n\t\n\treturn true;\t\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ee2e4c16a32ba7be7f9a68bea25addbc", "src_uid": "142e5f2f08724e53c234fc2379216b4c", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n     int n, num = 0, count = 0, i, j, k;\n     int a[10][4], b[10], c[10];\n     int d[10000] = {0};\n\n     scanf(\"%d\", &n);\n\n     for (i = 0; i < n; i++) {\n\t  for (j = 0; j < 4; j++) scanf(\"%1d\", &a[i][j]);\n\n\t  scanf(\"%d %d\", &b[i], &c[i]);\n     }\n\n     for (i = 0; i < 10000; i++) {\n\t  int x = i;\n\t  int p[10] = {0};\n\n\t  for (j = 0; j < 4; j++) {\n\t       p[x % 10]++;\n\n\t       x /= 10;\n\t  }\n\n\t  for (j = 0; j < 10; j++) {\n\t       if (p[j] > 1) d[i] = 1;\n\t  }\n     }\n\n     for (i = 0; i < n; i++) {\n\t  for (j = 0; j < 10000; j++) {\n\t       if (d[j] == 0) {\n\t\t    int p[10] = {0};\n\t\t    int x = j, y = 0, z = 0;\n\n\t\t    for (k = 0; k < 4; k++) p[a[i][k]]++;\n\n\t\t    for (k = 0; k < 4; k++) {\n\t\t\t p[x % 10]++;\n\n\t\t\t if (x % 10 == a[i][3 - k]) y++;\n\n\t\t\t x /= 10;\n\t\t    }\n\n\t\t    for (k = 0; k < 10; k++) {\n\t\t\t if (p[k] == 2) z++;\n\t\t    }\n\n\t\t    if (y != b[i] || z - y != c[i]) d[j] = 1;\n\t       }\n\t  }\n     }\n\n     for (i = 0; i < 10000; i++) {\n\t  if (d[i] == 0) {\n\t       num = i;\n\t       count++;\n\t  }\n     }\n\n     if (count > 1) {\n\t  puts(\"Need more data\");\n     } else if (count == 1) {\n\t  printf(\"%d\\n\", num);\n     } else {\n\t  puts(\"Incorrect data\");\n     }\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dc9aef07e6ae729c14024657acc917b9", "src_uid": "142e5f2f08724e53c234fc2379216b4c", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define UNDECIDED -1\n#define NOTFOUND -2\n\nint as[20];\nint hit[20];\nint blow[20];\nint appear[20];\nint A[20], B[20];\nint N;\n\nint precheck(int num){\n    int i,cnt=0;\n    for(i=0;i<10;i++) appear[i]=0;\n    appear[(num/1000)%10]++;\n    appear[(num/100)%10]++;\n    appear[(num/10)%10]++;\n    appear[(num/1)%10]++;\n    for(i=0;i<10;i++)if(appear[i]) cnt++;\n    return cnt == 4;\n}\n\nint subcheck(int num, int idx){\n    int i, sub=as[idx], h=0, b=0;\n    for(i=0;i<10;i++)A[i]=B[i]=0;\n    for(i=1;i<=1000;i*=10){\n        if((num/i)%10 == (sub/i)%10){\n            h++;\n        }\n        else{\n            A[(num/i)%10]++;\n            B[(sub/i)%10]++;\n        }\n    }\n    for(i=0;i<10;i++)if(A[i]&&B[i]) b++;\n    return h==hit[idx] && b==blow[idx];\n}\n\nint check(){\n    int i,j,ok,cnt=0,ans;\n    for(i=0;i<10000;i++)if(precheck(i)){\n        ok = 1;\n        for(j=0;j<N;j++)if(!subcheck(i,j)) ok = 0;\n        if(ok){\n            cnt++;\n            ans = i;\n        }\n    }\n    if(cnt==0) return NOTFOUND;\n    else if(cnt==1) return ans;\n    else return UNDECIDED;\n}\n\nvoid solve(){\n    int result = check();\n    if(result == UNDECIDED) puts(\"Need more data\");\n    else if(result == NOTFOUND) puts(\"Incorrect data\");\n    else printf(\"%04d\\n\", result);\n}\n\nint main(){\n    int i;\n    scanf(\"%d\",&N);\n    for(i=0;i<N;i++) scanf(\"%d%d%d\",as+i,hit+i,blow+i);\n    solve();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "22257f1c2083f00b88822768bdc10372", "src_uid": "142e5f2f08724e53c234fc2379216b4c", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n     int n, num = 0, count = 0, i, j, k;\n     int a[10][4], b[10], c[10];\n     int d[10000] = {0};\n\n     scanf(\"%d\", &n);\n\n     for (i = 0; i < n; i++) {\n\t  for (j = 0; j < 4; j++) scanf(\"%1d\", &a[i][j]);\n\n\t  scanf(\"%d %d\", &b[i], &c[i]);\n     }\n\n     for (i = 0; i < 10000; i++) {\n\t  int x = i;\n\t  int p[10] = {0};\n\n\t  for (j = 0; j < 4; j++) {\n\t       p[x % 10]++;\n\n\t       x /= 10;\n\t  }\n\n\t  for (j = 0; j < 10; j++) {\n\t       if (p[j] > 1) d[i] = 1;\n\t  }\n     }\n\n     for (i = 0; i < n; i++) {\n\t  for (j = 0; j < 10000; j++) {\n\t       if (d[j] == 0) {\n\t\t    int p[10] = {0};\n\t\t    int x = j, y = 0, z = 0;\n\n\t\t    for (k = 0; k < 4; k++) p[a[i][k]]++;\n\n\t\t    for (k = 0; k < 4; k++) {\n\t\t\t p[x % 10]++;\n\n\t\t\t if (x % 10 == a[i][3 - k]) y++;\n\n\t\t\t x /= 10;\n\t\t    }\n\n\t\t    for (k = 0; k < 10; k++) {\n\t\t\t if (p[k] == 2) z++;\n\t\t    }\n\n\t\t    if (y != b[i] || z - y != c[i]) d[j] = 1;\n\t       }\n\t  }\n     }\n\n     for (i = 0; i < 10000; i++) {\n\t  if (d[i] == 0) {\n\t       num = i;\n\t       count++;\n\t  }\n     }\n\n     if (count > 1) {\n\t  puts(\"Need more data\");\n     } else if (count == 1) {\n\t  printf(\"%04d\\n\", num);\n     } else {\n\t  puts(\"Incorrect data\");\n     }\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f72644e6c1cb18a55ecdbb2d313f628b", "src_uid": "142e5f2f08724e53c234fc2379216b4c", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nchar g[10][5], ss[5], s[5];\nint n, cc = 0, a[10], b[10];\n\nvoid check() {\n\tint i;\n\tfor (i = 0; i < n; i++) {\n\t\tint j, aa = 0, bb = 0;\n\t\tfor (j = 0; j < 4; j++)\n\t\t\tif (g[i][j] == s[j])\n\t\t\t\taa++;\n\t\t\telse {\n\t\t\t\tint k;\n\t\t\t\tfor (k = 0; k < 4; k++)\n\t\t\t\t\tif (g[i][j] == s[k])\n\t\t\t\t\t\tbreak;\n\n\t\t\t\tif (k != 4)\n\t\t\t\t\tbb++;\n\t\t\t}\n\n\t\tif (aa != a[i] || bb != b[i])\n\t\t\tbreak;\n\t}\n\n\tif (i == n) {\n\t\tcc++;\n\t\tstrcpy(ss, s);\n\t}\n}\n\nint main() {\n\tscanf(\"%d\", &n);\n\n\tint i;\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%s%d%d\", g[i], &a[i], &b[i]);\n\n\tchar a, b, c, d;\n\tfor (a = '0'; a <= '9'; a++)\n\t\tfor (b = '0'; b <= '9'; b++)\n\t\t\tfor (c = '0'; c <= '9'; c++)\n\t\t\t\tfor (d = '0'; d <= '9'; d++)\n\t\t\t\t\tif (a != b && a != c && a != d && b != c && b != d && c != d) {\n\t\t\t\t\t\ts[0] = a; s[1] = b; s[2] = c; s[3] = d; s[4] = '\\0';\n\t\t\t\t\t\tcheck();\n\t\t\t\t\t}\n\n\tif (cc == 0)\n\t\tputs(\"Incorrect data\");\n\telse if (cc == 1)\n\t\tputs(ss);\n\telse\n\t\tputs(\"Need more data\");\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ae1b60dbdfb87e01c931da567134e76d", "src_uid": "142e5f2f08724e53c234fc2379216b4c", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main()\n{\n//while(1){\n    int n=0;int x,j;int i=1;int l=1;unsigned long long s=0;//printf(\"%llu\",s);\n    int k=0;char ks[61];\n    //printf(\"%d\\t\",n);\n    scanf(\"%d\",&n);\n    scanf(\"%s\",ks);\n    //printf(\"%d\\t\",n);\n    //printf(\"%s\\t\",ks);\n    s=strlen(ks);\n    //printf(\"%d\\n\",s);\n    for(j=s-1;j>=0 && j>s-10;j--)\n    {\n            //printf(\"kd[%d]:%c\\t\",j,ks[j]);printf(\"l:%d\\t\",l);\n            k+=(ks[j]-'0')*l;l*=10;\n            //printf(\"k:%d\\n\",k);\n    }\n    l=j;\n    //printf(\"k:%d\\t\",k);printf(\"l:%d\\n\",l);\n    s=n-1;\n    do\n    {\n        s=s/10;i*=10;\n    }while(s>0);\n    s=0;int y,m;\n    //printf(\"n:%d\\t\",n);\n    //printf(\"i:%d\\n\",i);\n    unsigned long long b=1;\n    while(k>0 || l>0)\n    {\n        x=k%i;\n    //printf(\"%d\\t\",k);\n    //printf(\"%d\\n\",x);\n        if(x<n)\n        {\n            y=x;m=1;\n            do\n            {\n                y/=10;m*=10;\n            }while(y>0);\n            //printf(\"y:%d\\t\",y);printf(\"m:%d\\n\",m);\n            s+=x*b;b*=n;k/=m;\n            //printf(\"s:%d\\t\",s);\n            //printf(\"b:%llu\\t\",b);//printf(\"k:%d\\n\",k);\n            for(j=l;j>=0 && m>1;j--)\n            {\n                m/=10;\n            //printf(\"%d::%c\",j,ks[j]);\n            k+=(ks[j]-'0')*(100000000/m);\n            //printf(\"k:%d\\n\",k);//printf(\"m:%d\\t\",m);\n            }\n            l=j;\n            //printf(\"<:%llu\\n\",s);\n        }\n        else\n        {\n            x=x%(i/10);m=1;y=x;\n            do\n            {\n                y/=10;m*=10;\n            }while(y>0);\n            s+=x*b;b*=n;k/=m;\n            for(j=l;j>=0 && m>1;j--)\n            {\n                m/=10;k+=(ks[j]-'0')*(100000000/m);\n            }\n            l=j;\n            //printf(\">:%llu\\n\",s);\n\n        }\n    }\n    printf(\"%I64d\\n\",s);\n}\n//}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b1ff7f8e924247a13e8e23f3c30d1e04", "src_uid": "be66399c558c96566a6bb0a63d2503e5", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n\n\n\nint main()\n{\n\n    int n,x,i=1;\n    long int k;\n    scanf(\"%d\",&n);\n    scanf(\"%d\",&k);\n    long int s=n-1;\n    do\n    {\n        s=s/10;i*=10;\n    }while(s>0);\n\n    s=0;int j=i/10;int y,m;\n\n    int b=1;\n    while(k>0)\n    {\n        x=k%i;\n        if(x<n)\n        {y=x;m=1;\n       do\n        {\n            y/=10;m*=10;\n        } while(y>0);\n            s+=x*b;b*=n;k/=m;\n        }\n        else\n        {\n            y=x%j;m=1;\n       do\n        {\n            y/=10;m*=10;\n        }while(y>0);\n            s+=(x%m)*b;b*=n;k/=m;}\n    }\n    printf(\"%d\\n\",s);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c3ff90dd0d508bcefcc593608442bc42", "src_uid": "be66399c558c96566a6bb0a63d2503e5", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "/*\n * =====================================================================================\n *\n *       Filename:  main.c\n *\n *    Description:  \n *\n *        Version:  1.0\n *        Created:  19/01/17 19:54:22\n *       Revision:  none\n *       Compiler:  gcc\n *\n *         Author:  YOUR NAME (), \n *        Company:  \n *\n * =====================================================================================\n */\n\n#include <stdio.h>\n#include <inttypes.h>\n#include <string.h>\n\nint \nwidth(long x) \n{\n    int i = 0;\n    while (x > 0) {\n        i++;\n        x /= 10;\n    }\n    return i;\n}\n\nint \nconvert(char *beg, char *end) \n{\n    long res = 0;\n    while ((uintptr_t)beg < (uintptr_t)end) {\n        res = res * 10 + (*beg - '0');\n        beg++;\n    }\n    return res;\n}\n\nint \nmin(int i, int j)\n{\n    if (i < j)\n        return i;\n    else\n        return j;\n}\n\nint\nmain()\n{\n    long n;\n    char k[61];\n    scanf(\"%ld\", &n);\n    scanf(\"%s\", k);\n    \n    int w = width(n - 1);\n    long base[w+2];\n    base[1] = -1; base[2] = 9;\n    for (int i = 3; i <= w; ++i)\n        base[i] = base[i-1] * 10 + 9;\n\n    long x = 0;\n    long basen = 1;\n    for (int i = strlen(k); i > 0; --i) {\n        for (int j = min(w, i); j > 0; --j) {\n            //printf(\"x: %ld, part: %.*s\\n\", x, j, &k[i-j]);\n            long part = convert(&k[i-j], &k[i]);\n            if (part < n && part > base[j]) {\n                x += basen * part;\n                i -= j - 1;\n                break;\n            }\n        }\n        basen *= n;\n    }\n    printf(\"%ld\\n\", x);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "455135a3996b095139f895f65623c830", "src_uid": "be66399c558c96566a6bb0a63d2503e5", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n\n\n\nint main()\n{\n\n    int n,x,i=1;\n    long int k;\n    scanf(\"%d\",&n);\n    scanf(\"%d\",&k);\n    int s=n-1;\n    do\n    {\n        s=s/10;i*=10;\n    }while(s>0);\n\n    s=0;int j=i/10;int y,m;\n\n    int b=1;\n    while(k>0)\n    {\n        x=k%i;\n        if(x<n)\n        {y=x;m=1;\n       do\n        {\n            y/=10;m*=10;\n        } while(y>0);\n            s+=x*b;b*=n;k/=m;\n        }\n        else\n        {\n            y=x%j;m=1;\n       do\n        {\n            y/=10;m*=10;\n        }while(y>0);\n            s+=(x%m)*b;b*=n;k/=m;}\n    }\n    printf(\"%d\\n\",s);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b46941ea9a4e73ab252c2ccc6e3b8259", "src_uid": "be66399c558c96566a6bb0a63d2503e5", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n\n\n\nint main()\n{\n    int n,k,x,i=1;\n    scanf(\"%d\",&n);\n    scanf(\"%d\",&k);\n    int s=n;\n    while(s>0)\n    {\n        s=s/10;i*=10;\n    }\n    s=0;int j=i/10;\n\n    int b=1;\n    while(k!=0)\n    {\n        x=k%i;\n        if(x<n){s+=x*b;b*=n;k=k/i;}\n        else{s+=(x%j)*b;b*=n;k=k/j;}\n        \n\n    }\n    printf(\"%d\",s);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "37afd678847b9b53f8e6c74ee8475b7a", "src_uid": "be66399c558c96566a6bb0a63d2503e5", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint dgt(int a)\n{\n    double r=log(a)/log(7);\n    int c=r;\n    return (r==c)? c: c+1;\n}\nint ys(int m, int n, int a, int b)\n{\n\n    int fr[7]={0,0,0,0,0,0,0},i;\n    for(i=0;i<a;i++){\n        fr[m%7]++;\n        if(fr[m%7]>1){\n\n            return 0;\n        }\n        m=m/7;\n    }\n    for(i=0;i<b;i++){\n        fr[n%7]++;\n        if(fr[n%7]>1){\n\n            return 0;\n        }\n        n=n/7;\n    }\n\n    return 1;\n}\nint get(int m, int n)\n{\n    int d1,d2,i,j,rs=0;\n    d1=dgt(m);d2=dgt(n);\n    if(d1+d2>7)\n        return 0;\n    for(i=0;i<m;i++){\n        for(j=0;j<n;j++){\n            rs+=ys(i,j,d1,d2);\n        }\n    }\n    return rs;\n}\nint main()\n{\n    int m,n,result;\n    scanf(\"%d %d\",&m,&n);\n    result=get(m,n);\n    printf(\"%d\\n\",result);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0958e082206b2ad16ac251084cca229b", "src_uid": "0930c75f57dd88a858ba7bb0f11f1b1c", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h> \n#include<stdlib.h> \n#include<string.h> \n#include<math.h>\n#define MAXN 13\nlong long a[MAXN],b[MAXN],m,n,ans=0; \nlong long s1[MAXN],s2[MAXN];\nvoid find(long long x,long long y,long long add)\n{\n\tlong long i,j,S;\n\tif(add>y){\n\t\tans++;\n\t\treturn;\n\t}\n\tfor(i=0;i<=6;i++){\n\t\tfor(j=1;j<add;j++)\n\t\t\tif(i==b[j])\n\t\t\t\tgoto end1;\n\t\tfor(j=1;j<=x;j++)\n\t\t\tif(i==a[j])\n\t\t\t\tgoto end1;\n\t\ts2[add]=i*pow(7,y-add);\n\t\tS=0;\n\t\tfor(j=1;j<=add;j++)\n\t\t\tS+=s2[j];\n\t\tif(S>=m)\n\t\t\tgoto end1;\n\t\tb[add]=i;\n\t\tfind(x,y,add+1);\n\t\tend1:;\n\t}\n}\nvoid dfs(long long x,long long y,long long add)\n{\n\tlong long i,j,S;\n\tif(add>x){\n\t\tfind(x,y,1);\n\t\treturn;\n\t}\n\tfor(i=0;i<=6;i++){\n\t\tfor(j=1;j<add;j++){\n\t\t\tif(i==a[j])\n\t\t\tgoto end;\n\t\t}\n\t\ts1[add]=i*pow(7,x-add);\n\t\tS=0;\n\t\tfor(j=1;j<=add;j++)\n\t\t\tS+=s1[j];\n\t\tif(S>=n)\n\t\t\tgoto end;\n\t\ta[add]=i;\n\t\tdfs(x,y,add+1);\n\t\tend:;\n\t}\n} \nint main()\n{\n\tlong long k,i,j,l,c,p,q,c1=0,c2=0;\n\tscanf(\"%I64d%I64d\",&n,&m);\n\tp=n-1;q=m-1;\n\twhile(p>0){\n\t\tp=p/7;\n\t\tc1++;\n\t}\n\twhile(q>0){\n\t\tq=q/7;\n\t\tc2++;\n\t}\n\tif(c1+c2>7){\n\t\tprintf(\"0\");\n\t\treturn 0;\n\t}\n\tdfs(c1,c2,1);\n\tprintf(\"%I64d\",ans);\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2ed17a2639a67835e8b83fa54a430097", "src_uid": "0930c75f57dd88a858ba7bb0f11f1b1c", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long n, m, pow[11], nn = 0, mm = 0, res = 0, leng;\nint a[7],x[8], res1 = 0, res2 = 0;\n\n\n\nvoid kiemtra()\n{\n    int j, i = 1;\n    long long h = 0;\n    for (i = 1; i <= res1; i++)\n    {\n        h = h * 10 + x[i];\n    }\n    if (h > nn) return;\n\n    h = 0;\n    for (i = res1 + 1; i <= leng; i++)\n    {\n        h = h * 10 + x[i];\n    }\n    if (h > mm) return;\n    res++;\n}\n\n\nvoid xuli(int i)\n{\n    int j;\n    for (j = 0; j < 7; j++)\n        if (a[j] == 0)\n        {\n            x[i] = j;\n            a[j] = 1;\n            if (i == leng) kiemtra();\n            else\n                xuli(i+1);\n            a[j] = 0;\n        }\n}\n\n\nvoid sol()\n{\n    int  x, i;\n    for (i = 10; i >= 0; i--)\n    {\n        nn = nn * 10 + n / pow[i];\n        if (n / pow[i] > 0)\n        {\n            x = n / pow[i];\n            n -= x * pow[i];\n            if (res1 == 0)\n            {\n                res1 = i+1;\n            }\n        }\n    }\n    for (i = 10; i >= 0; i--)\n    {\n        mm = mm * 10 + m / pow[i];\n        if (m / pow[i] > 0)\n        {\n            x = m / pow[i];\n            m -= x * pow[i];\n            if (res2 == 0)\n            {\n                res2 = i+1;\n            }\n        }\n    }\n    leng = res1 + res2;\n    xuli(1);\n}\n\n\n\nint main()\n{\n    int i, j;\n    scanf(\"%I64d %I64d\", &n, &m);\n    n--; m--;\n    for (j = 0; j < 7; j++)\n        a[j] = 0;\n    pow[0] = 1;\n    for (i = 1; i < 11; i++)\n        pow[i] = pow[i-1] * 7;\n    sol();\n    printf(\"%d\", res);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "df3239a2cd88a54140a04be9a027d942", "src_uid": "0930c75f57dd88a858ba7bb0f11f1b1c", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint dgt(int a)\n{\n    double r=log(a)/log(7);\n    int c=r+1;\n    return c;\n}\nint ys(int m, int n, int a, int b)\n{\n    int fr[7]={0,0,0,0,0,0,0},i;\n    //printf(\"%d-%d: \",m,n);\n    for(i=0;i<a;i++){\n        fr[m%7]++;\n        if(fr[m%7]>1){\n            //printf(\"0\\n\");\n            return 0;\n        }\n        m=m/7;\n    }\n    for(i=0;i<b;i++){\n        fr[n%7]++;\n        if(fr[n%7]>1){\n                //printf(\"0\\n\");\n            return 0;\n        }\n        n=n/7;\n    }\n    //printf(\"1\\n\");\n    return 1;\n}\nint get(int m, int n)\n{\n    int d1,d2,i,j,rs=0;\n    d1=dgt(m);\n    d2=dgt(n);\n    if(d1+d2>7)\n        return 0;\n    for(i=0;i<m;i++){\n        if(ys(i,i,d1,0)){\n            //printf(\"i=%d,d=%d\\n\",i,d1);\n           for(j=0;j<n;j++){\n                rs+=ys(i,j,d1,d2);\n           }\n        }\n    }\n    return rs;\n}\nint main()\n{\n    int m,n,result;\n    scanf(\"%d %d\",&m,&n);\n    result=get(m,n);\n    printf(\"%d\\n\",result);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "19adb4d85817384946aef0403880923d", "src_uid": "0930c75f57dd88a858ba7bb0f11f1b1c", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n\nint check(int a, int b, int c)\n{\n\tint oc[7]={0}, sum=0,flag=0,i=0;\n\t\n\twhile(a)\n\t{\n\t\toc[a%7]++;\n\t\ta/=7;\n\t\tsum++;\n\t}\n\t\n\twhile(b)\n\t{\n\t\toc[b%7]++;\n\t\tb/=7;\n\t\tsum++;\n\t}\n\t\n\twhile(i<7)\n\t{\n\t\tif(oc[i]>1) flag=1;\n\t\ti++;\n\t}\n\t\n\tif(c-sum>1) flag=1;\n\t\n\tif(c-sum>0 && oc[0]==1) flag=1;\n\t\n\tif(flag==1) return 0;\n\t\n\telse return 1;\n}\n\nint main(void) {\n\tint n,m,i=0,a,d=0,ans=0;\n\t\n\tscanf(\"%d %d\",&n,&m);\n\n\ta=n-1;\n\twhile(1)\n\t{\n\t\td++;\n\t\ta/=7;\n\t\tif(a==0) break;\n\t}\n\t\n\ta=m-1;\n\twhile(1)\n\t{\n\t\td++;\n\t\ta/=7;\n\t\tif(a==0) break;\n\t}\n\t\n\tif(i>7) printf(\"0\");\n\t\n\telse\n\t{\n\t\ti=0;\n\t\twhile(i<n)\n\t\t{\n\t\t\tint j=0;\n\t\t\t\n\t\t\twhile(j<m)\n\t\t\t{\n\t\t\t\tans+=check(i,j,d);\n\t\t\t\tj++;\n\t\t\t}\n\t\t\t\n\t\t\ti++;\n\t\t}\n\t\t\n\t\tprintf(\"%d\",ans);\n\t}\n\t\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d29cea903fc5b14bdf5b1cde08a1b192", "src_uid": "0930c75f57dd88a858ba7bb0f11f1b1c", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nchar r[1 << 19];\n\nint box2mask(char b[5][5]) {\n\tint mask = 0, i, j, k = 0;\n\tfor (i = 0; i < 5; i++)\n\t\tfor (j = 0; j < 5-abs(2-i); j++) {\n\t\t\tif (b[i][j])\n\t\t\t\tmask |= 1 << k;\n\t\t\tk++;\n\t\t}\n\n\treturn mask;\n}\n\nint go(int mask) {\n\tif (r[mask] != -1)\n\t\treturn r[mask];\n\n\tchar b[5][5];\n\tmemset(b, 0, sizeof(b));\n\n\tint i, j, k = 0;\n\tfor (i = 0; i < 5; i++)\n\t\tfor (j = 0; j < 5-abs(2-i); j++) {\n\t\t\tif (mask & (1 << k))\n\t\t\t\tb[i][j] = 1;\n\t\t\tk++;\n\t\t}\n\n\tchar bb[5][5];\n\tfor (i = 0; i < 5; i++)\n\t\tfor (j = 0; j < 5-abs(2-i); j++) {\n\t\t\tmemcpy(bb, b, sizeof(bb));\n\t\t\tfor (k = i; k < 5 && j < 5-abs(2-k) && bb[k][j]; k++) {\n\t\t\t\tbb[k][j] = 0;\n\t\t\t\tif (!go(box2mask(bb)))\n\t\t\t\t\treturn r[mask] = 1;\n\t\t\t}\n\n\t\t\tmemcpy(bb, b, sizeof(bb));\n\t\t\tint l;\n\t\t\tfor (k = i, l = j; k < 5 && l < 5-abs(2-k) && bb[k][l]; k++, l++) {\n\t\t\t\tbb[k][l] = 0;\n\t\t\t\tif (!go(box2mask(bb)))\n\t\t\t\t\treturn r[mask] = 1;\n\t\t\t}\n\n\t\t\tmemcpy(bb, b, sizeof(bb));\n\t\t\tfor (k = j; k < 5-abs(2-i) && bb[i][k]; k++) {\n\t\t\t\tbb[i][k] = 0;\n\t\t\t\tif (!go(box2mask(bb)))\n\t\t\t\t\treturn r[mask] = 1;\n\t\t\t}\n\t\t}\n\n\treturn r[mask] = 0;\n}\n\nint main() {\n\tint i, mask = 0, j = 0;\n\tfor (i = 0; i < 5; i++) {\n\t\tchar s[100];\n\t\tgets(s);\n\n\t\tchar *t = s;\n\t\twhile (*t != '\\0') {\n\t\t\tif (*t == 'O')\n\t\t\t\tmask |= (1 << j);\n\t\t\tif (*t == '0' || *t == '.')\n\t\t\t\tj++;\n\t\t\tt++;\n\t\t}\n\n\t}\n\n\tmemset(r, -1, sizeof(r));\n\n\tif (go(mask))\n\t\tputs(\"Karlsson\");\n\telse\n\t\tputs(\"Lillebror\");\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "df8bd561d96184ff9415c8b3880cadff", "src_uid": "eaa022cc7846c983a826900dc6dd919f", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nchar r[1 << 20];\n\nint box2mask(char b[5][5]) {\n\tint mask = 0, i, j, k = 0;\n\tfor (i = 0; i < 5; i++)\n\t\tfor (j = 0; j < 5-abs(2-i); j++) {\n\t\t\tif (b[i][j])\n\t\t\t\tmask |= 1 << k;\n\t\t\tk++;\n\t\t}\n\n\treturn mask;\n}\n\nint go(int mask) {\n\tif (r[mask] != -1)\n\t\treturn r[mask];\n\n\tchar b[5][5];\n\tmemset(b, 0, sizeof(b));\n\n\tint i, j, k = 0;\n\tfor (i = 0; i < 5; i++)\n\t\tfor (j = 0; j < 5-abs(2-i); j++) {\n\t\t\tif (mask & (1 << k))\n\t\t\t\tb[i][j] = 1;\n\t\t\tk++;\n\t\t}\n\n\tchar bb[5][5];\n\tfor (i = 0; i < 5; i++)\n\t\tfor (j = 0; j < 5-abs(2-i); j++) {\n\t\t\tmemcpy(bb, b, sizeof(bb));\n\t\t\tfor (k = i; k < 5 && j < 5-abs(2-k) && bb[k][j]; k++) {\n\t\t\t\tbb[k][j] = 0;\n\t\t\t\tif (!go(box2mask(bb)))\n\t\t\t\t\treturn r[mask] = 1;\n\t\t\t}\n\n\t\t\tmemcpy(bb, b, sizeof(bb));\n\t\t\tint l;\n\t\t\tfor (k = i, l = j; k < 5 && l < 5-abs(2-k) && bb[k][l]; k++, l++) {\n\t\t\t\tbb[k][l] = 0;\n\t\t\t\tif (!go(box2mask(bb)))\n\t\t\t\t\treturn r[mask] = 1;\n\t\t\t}\n\n\t\t\tmemcpy(bb, b, sizeof(bb));\n\t\t\tfor (k = j; k < 5-abs(2-i) && bb[i][k]; k++) {\n\t\t\t\tbb[i][k] = 0;\n\t\t\t\tif (!go(box2mask(bb)))\n\t\t\t\t\treturn r[mask] = 1;\n\t\t\t}\n\t\t}\n\n\treturn r[mask] = 0;\n}\n\nint main() {\n\tint i, mask = 0, j = 0;\n\tfor (i = 0; i < 5; i++) {\n\t\tchar s[100];\n\t\tgets(s);\n\n\t\tchar *t = s;\n\t\twhile (*t != '\\0') {\n\t\t\tif (*t == 'O')\n\t\t\t\tmask |= (1 << j);\n\t\t\tif (*t == 'O' || *t == '.')\n\t\t\t\tj++;\n\t\t\tt++;\n\t\t}\n\n\t}\n\t\n\tif (j != 19)\n\t\texit(1);\n\n\tmemset(r, -1, sizeof(r));\n\n\tif (go(mask))\n\t\tputs(\"Karlsson\");\n\telse\n\t\tputs(\"Lillebror\");\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0eebc4d56430a414258838200b17201d", "src_uid": "eaa022cc7846c983a826900dc6dd919f", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nchar r[1 << 20];\n\nint masksn = 0, masks[200];\n\nint go(int m) {\n\tif (r[m] != -1)\n\t\treturn r[m];\n\n\tint i;\n\tfor (i = 0; i < masksn; i++)\n\t\tif (m & masks[i] == masks[i])\n\t\t\tif (!go(m & ~masks[i]))\n\t\t\t\t\treturn r[m] = 1;\n\n\treturn r[m] = 0;\n}\n\nint main() {\n\tint i, m = 0, j = 0;\n\tfor (i = 0; i < 5; i++) {\n\t\tchar s[100]; gets(s);\n\n\t\tchar *t = s;\n\t\twhile (*t != '\\0') {\n\t\t\tif (*t == 'O')\n\t\t\t\tm |= (1 << j);\n\t\t\tif (*t == 'O' || *t == '.')\n\t\t\t\tj++;\n\t\t\tt++;\n\t\t}\n\n\t}\n\n\tfor (i = 0; i < 5; i++)\n\t\tfor (j = 0; j < 5-abs(2-i); j++) {\n\t\t\tint k, l, m = 0;\n\t\t\tfor (k = i, l = j; k < 5 && 0 <= l && l < 5-abs(2-k); k++) {\n\t\t\t\tmasks[masksn++] = m;\n\t\t\t\tif (k >= 2)\n\t\t\t\t\tl--;\n\t\t\t}\n\n\t\t\tm = 0;\n\t\t\tfor (k = i, l = j; k < 5 && l <= 5-abs(2-k); k++) {\n\t\t\t\tmasks[masksn++] = m;\n\t\t\t\tif (k < 2)\n\t\t\t\t\tl++;\n\t\t\t}\n\n\t\t\tm = 0;\n\t\t\tfor (k = j; k < 5-abs(2-i); k++) {\n\t\t\t\tmasks[masksn++] = m;\n\t\t\t}\n\t\t}\n\n\tmemset(r, -1, sizeof(r));\n\n\tif (go(m))\n\t\tputs(\"Karlsson\");\n\telse\n\t\tputs(\"Lillebror\");\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "563aa23e52041ca893ae6346617d3979", "src_uid": "eaa022cc7846c983a826900dc6dd919f", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nchar r[1 << 19];\n\nint box2mask(char b[5][5]) {\n\tint mask = 0, i, j, k = 0;\n\tfor (i = 0; i < 5; i++)\n\t\tfor (j = 0; j < 5-abs(2-i); j++) {\n\t\t\tif (b[i][j])\n\t\t\t\tmask |= 1 << k;\n\t\t\tk++;\n\t\t}\n\n\treturn mask;\n}\n\nint go(int mask) {\n\tif (r[mask] != -1)\n\t\treturn r[mask];\n\n\tchar b[5][5];\n\tmemset(b, 0, sizeof(b));\n\n\tint i, j, k = 0;\n\tfor (i = 0; i < 5; i++)\n\t\tfor (j = 0; j < 5-abs(2-i); j++) {\n\t\t\tif (mask & (1 << k))\n\t\t\t\tb[i][j] = 1;\n\t\t\tk++;\n\t\t}\n\n\tchar bb[5][5];\n\tfor (i = 0; i < 5; i++)\n\t\tfor (j = 0; j < 5-abs(2-i); j++) {\n\t\t\tmemcpy(bb, b, sizeof(bb));\n\t\t\tfor (k = i; k < 5 && j < 5-abs(2-k) && bb[k][j]; k++) {\n\t\t\t\tbb[k][j] = 0;\n\t\t\t\tif (!go(box2mask(bb)))\n\t\t\t\t\treturn r[mask] = 1;\n\t\t\t}\n\n\t\t\tmemcpy(bb, b, sizeof(bb));\n\t\t\tint l;\n\t\t\tfor (k = i, l = j; k < 5 && l < 5-abs(2-k) && bb[k][l]; k++, l++) {\n\t\t\t\tbb[k][l] = 0;\n\t\t\t\tif (!go(box2mask(bb)))\n\t\t\t\t\treturn r[mask] = 1;\n\t\t\t}\n\n\t\t\tmemcpy(bb, b, sizeof(bb));\n\t\t\tfor (k = j; k < 5-abs(2-i) && bb[i][k]; k++) {\n\t\t\t\tbb[i][k] = 0;\n\t\t\t\tif (!go(box2mask(bb)))\n\t\t\t\t\treturn r[mask] = 1;\n\t\t\t}\n\t\t}\n\n\treturn r[mask] = 0;\n}\n\nint main() {\n\tint i, mask = 0, j = 0;\n\tfor (i = 0; i < 5; i++) {\n\t\tchar s[100];\n\t\tgets(s);\n\n\t\tchar *t = s;\n\t\twhile (*t != '\\0') {\n\t\t\tif (*t == 'O')\n\t\t\t\tmask |= (1 << j);\n\t\t\tif (*t == 'O' || *t == '.')\n\t\t\t\tj++;\n\t\t\tt++;\n\t\t}\n\n\t}\n\n\tmemset(r, -1, sizeof(r));\n\n\tif (go(mask))\n\t\tputs(\"Karlsson\");\n\telse\n\t\tputs(\"Lillebror\");\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "09b997e6a7ebc8bf5014583ff655b4e5", "src_uid": "eaa022cc7846c983a826900dc6dd919f", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nchar r[1 << 20];\n\nint box2mask(char b[5][5]) {\n\tint mask = 0, i, j, k = 0;\n\tfor (i = 0; i < 5; i++)\n\t\tfor (j = 0; j < 5-abs(2-i); j++) {\n\t\t\tif (b[i][j])\n\t\t\t\tmask |= 1 << k;\n\t\t\tk++;\n\t\t}\n\n\treturn mask;\n}\n\nint go(int mask) {\n\tif (r[mask] != -1)\n\t\treturn r[mask];\n\t\n\t// printf(\"mask = %d\\n\", mask);\n\n\tchar b[5][5];\n\tmemset(b, 0, sizeof(b));\n\n\tint i, j, k = 0;\n\tfor (i = 0; i < 5; i++)\n\t\tfor (j = 0; j < 5-abs(2-i); j++) {\n\t\t\tif (mask & (1 << k))\n\t\t\t\tb[i][j] = 1;\n\t\t\tk++;\n\t\t}\n\n\tchar bb[5][5];\n\tfor (i = 0; i < 5; i++)\n\t\tfor (j = 0; j < 5-abs(2-i); j++) {\n\t\t\tmemcpy(bb, b, sizeof(bb));\n\t\t\tint l;\n\t\t\tfor (k = i, l = j; k < 5 && l < 5-abs(2-k) && l >= 0 && bb[k][l]; k++) {\n\t\t\t\tbb[k][l] = 0;\n\t\t\t\tif (!go(box2mask(bb)))\n\t\t\t\t\treturn r[mask] = 1;\n\t\t\t\tif (k >= 2)\n\t\t\t\t\tl--;\n\t\t\t}\n\n\t\t\tmemcpy(bb, b, sizeof(bb));\n\t\t\tfor (k = i, l = j; k < 5 && l < 5-abs(2-k) && bb[k][l]; k++) {\n\t\t\t\tbb[k][l] = 0;\n\t\t\t\tif (!go(box2mask(bb)))\n\t\t\t\t\treturn r[mask] = 1;\n\t\t\t\tif (k < 2)\n\t\t\t\t\tl++;\n\t\t\t}\n\n\t\t\tmemcpy(bb, b, sizeof(bb));\n\t\t\tfor (k = j; k < 5-abs(2-i) && bb[i][k]; k++) {\n\t\t\t\tbb[i][k] = 0;\n\t\t\t\tif (!go(box2mask(bb)))\n\t\t\t\t\treturn r[mask] = 1;\n\t\t\t}\n\t\t}\n\t\n\treturn r[mask] = 0;\n}\n\nint main() {\n\tint i, mask = 0, j = 0;\n\tfor (i = 0; i < 5; i++) {\n\t\tchar s[100];\n\t\tgets(s);\n\n\t\tchar *t = s;\n\t\twhile (*t != '\\0') {\n\t\t\tif (*t == 'O')\n\t\t\t\tmask |= (1 << j);\n\t\t\tif (*t == 'O' || *t == '.')\n\t\t\t\tj++;\n\t\t\tt++;\n\t\t}\n\n\t}\n\t\n\tif (j != 19)\n\t\texit(1);\n\n\tmemset(r, -1, sizeof(r));\n\n\tif (go(mask))\n\t\tputs(\"Karlsson\");\n\telse\n\t\tputs(\"Lillebror\");\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b0472d85b2214195222c88a8d2b5fdd8", "src_uid": "eaa022cc7846c983a826900dc6dd919f", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint A[99],F,I,T,i,j,r;\nint main(){\n\tchar s[99];\n\tscanf(\"%d%d%d\",&F,&I,&T);\n\tfor(i=0;i<F;i++){scanf(\"%s\",s);\n\t\tfor(j=0;j<I;j++)if(s[j]=='Y')A[j]++;}\n\tfor(j=0;j<I;j++)if(A[j]>=T)r++;\n\tprintf(\"%d\\n\",r);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "00363542334631068059de815e38f20e", "src_uid": "4c978130187e8ae6ca013d3f781b064e", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdlib.h>\n#include <stdio.h>\nint a[20][20]; int main() {long i, j, k, f, t, res; char s[200]; scanf(\"%ld %ld %ld \", &f, &k, &t); for (i = 0; i < f; i++) {scanf(\"%s \", s); for (j = 0; j < k; j++) {a[i][j] = s[j] == 'Y';}} res = 0; for (j = 0; j < k; j++) {long c = 0; for (i = 0; i < f; i++) {if (a[i][j]) c++;} if (c >= t) res++;} printf(\"%ld\\n\", res); return 0;}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "746b3859839d5d249589f86499ab7d2a", "src_uid": "4c978130187e8ae6ca013d3f781b064e", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(){\n\n    int F, I, T;\n    scanf(\"%d %d %d\", &F, &I, &T);\n\n    int i = 0;\n    int j = 0;\n    int count[I];\n    for(i=0;i<I;i++)count[i]=0;\n    for(i=0;i<F;i++){\n        char line[I];\n        scanf(\"%s\", &line);\n        for(j=0;j<I;j++){\n            if(line[j]=='Y'){\n                count[j]=count[j]+1;\n            }\n        }\n    }\n\n    int c=0;\n    for(i=0;i<I;i++){\n        if(count[i]>=T)c++;\n    }\n    printf(\"%d\\n\",c);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "10ba64488ce34795d1f8664fcffd4234", "src_uid": "4c978130187e8ae6ca013d3f781b064e", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdlib.h>\n#include <stdio.h>\n\nint a[20][20];\n\nint main()\n{\n   long i, j, k, f, t, res;\n   char s[200];\n\n   scanf(\"%ld %ld %ld \", &f, &k, &t);\n   for (i = 0; i < f; i++) {\n      scanf(\"%s \", s);\n      for (j = 0; j < k; j++) {\n\t a[i][j] = s[j] == 'Y';\n      }\n   }\n\n   res = 0;\n   for (j = 0; j < k; j++) {\n      long c = 0;\n      for (i = 0; i < f; i++) {\n\t if (a[i][j]) c++;\n      }\n      if (c >= t) res++;\n   }\n   printf(\"%ld\\n\", res);\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c98a0fd03ec114e3beed79453728d2d2", "src_uid": "4c978130187e8ae6ca013d3f781b064e", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "II = lambda: int(raw_input())\nIAI = lambda: map(int, raw_input().split())\nIL = lambda: raw_input().strip()\nIAS = lambda: raw_input().split()\n\nf,i,t = IAI()\n\nL=[]\nfor _ in range(f): L += [IL()]\n\no=0\nfor c in xrange(i):\n    if sum(l[c]=='Y' for l in L) >= t: o += 1\nprint o\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "7e650735aed4a4b5f0a70f74a0ad889a", "src_uid": "4c978130187e8ae6ca013d3f781b064e", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint x[100100];\nint main()\n{\nlong long i,j,k,n,max,min;\nmax=0;\nmin=-1;\nscanf(\"%I64d\",&n);\nfor(i=1;i<=n;i++)\n    for(j=1;j<=n;j++)\n{\n    if(i*j>n)\n        break;\n    for(k=1;k<=n;k++)\n    {\n        if(i*j*k>n)\n            break;\n            else if(i*j*k==n)\n            {\n        if((i+1)*(j+2)*(k+2)>max)\n            max=(i+1)*(j+2)*(k+2);\n        if(min==-1)\n            min=(i+1)*(j+2)*(k+2);\n        else if((i+1)*(j+2)*(k+2)<min)\n            min=(i+1)*(j+2)*(k+2);\n\n            }\n\n    }\n}\n\n\n\tprintf(\"%I64d %I64d\\n\",min-n,max-n);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c948c1085d594e897b898b486ba31a8b", "src_uid": "2468eead8acc5b8f5ddc51bfa2bd4fb7", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdlib.h>\n#include <stdio.h>\n#include <math.h>\n\nint main() {\n  long long int i,n;\n  long long int min=1000000000,max;\n  scanf(\"%lld\",&n);\n  //printf(\"%lld\\n\",n);\n  //printf(\"%lld\\n\",(long long int)sqrtl(n));\n  for (i=1;i<=(long long int)sqrtl(n);i++) {\n    if (n%i==0) {\n      //printf(\"%lld\\n\",min);\n      if ((i+2)*(n/i+2)<min) {\n        min=(i+2)*(n/i+2);\n      }\n    }\n  }\n  min=2*min-n;\n  max=(n+1)*3*3-n;\n  printf(\"%lld %lld\\n\",min,max);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3f22615faedc6cec79032366f7c6caa4", "src_uid": "2468eead8acc5b8f5ddc51bfa2bd4fb7", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint x[100100];\nint main()\n{\nlong long i,j,k,n,max,min;\nmax=0;\nmin=-1;\nscanf(\"%I64d\",&n);\nfor(i=1;i<=n;i++)\n    for(j=1;j<=n;j++)\n{\n\n    if(i*j>n)\n        break;\n   for(k=1;k<=n;k++)\n   {\n       if(i*j*k>n)\n        break;\nif(i*j*k==n)\n{\n\n        if(min==-1)\n            min=(i+1)*(j+2)*(k+2);\n        else if((i+1)*(j+2)*(k+2)<min)\n            min=(i+1)*(j+2)*(k+2);\n}\n\n   }\n\n    }\nmax=3*3*(n+1);\n\n\tprintf(\"%I64d %I64d\\n\",min-n,max-n);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7725bbe2bc73806132ee0cabd458862c", "src_uid": "2468eead8acc5b8f5ddc51bfa2bd4fb7", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint x[100100];\nint main()\n{\nlong long i,j,k,n,max,min;\nmax=0;\nmin=-1;\nscanf(\"%I64d\",&n);\nfor(i=1;i<=n;i++)\n    for(j=1;j<=n;j++)\n{\n\nif(i*j*(n/i/j)>n)\n    break;\nif(i*j*(n/i/j)==n)\n{\n    if(min==-1)\n        min=(i+1)*(j+2)*((n/i/j)+2);\n    else if(min>(i+1)*(j+2)*((n/i/j)+2))\n    min=(i+1)*(j+2)*((n/i/j)+2);\n\n}\n    }\nmax=3*3*(n+1);\n\tprintf(\"%I64d %I64d\\n\",min-n,max-n);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "803c60f6702d6edeaabd14d274afc25f", "src_uid": "2468eead8acc5b8f5ddc51bfa2bd4fb7", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\ntypedef unsigned long long ull;\n\nint main(void){\n  ull n,sq1,sq2,max,min=99999999999999999,i,j,h=0,x,y,z,m,a;\n  scanf(\"%I64\",&n);\n  max=9*(n+1)-n;\n  sq1=sqrt(n);\n  for(i=1;i<=sq1;i++){\n    if(n%i==0){\n      //printf(\"%I64\\n\",n%i);\n      z=i;\n      m=n/i;\n      sq2=sqrt(m);\n      for(j=1;j<=sq2;j++){\n\tif(m%j==0){\n\t  x=j;\n\t  y=m/j;\n\t  if(min>(z+1)*(x+2)*(y+2)-n) min=(z+1)*(x+2)*(y+2)-n;\n\t}\n      }\n    }\n  }\t  \n  printf(\"%I64 %I64\\n\",min,max);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b8f653c460c7abca509c338149776f30", "src_uid": "2468eead8acc5b8f5ddc51bfa2bd4fb7", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\nint md;\n\nlong long power(int a, long long k) {\n\tlong long p;\n\n\tif (k == 0)\n\t\treturn 1;\n\tp = power(a, k / 2);\n\tp = p * p % md;\n\tif (k % 2)\n\t\tp = p * a % md;\n\treturn p;\n}\n\nvoid mult(int aa[][2], int bb[][2], int cc[][2]) {\n\tint i, j, k;\n\n\tfor (i = 0; i < 2; i++)\n\t\tfor (j = 0; j < 2; j++) {\n\t\t\tlong long c = 0;\n\n\t\t\tfor (k = 0; k < 2; k++)\n\t\t\t\tc += (long long) aa[i][k] * bb[k][j];\n\t\t\tcc[i][j] = c % md;\n\t\t}\n}\n\nvoid power_(int aa[][2], int pp[][2], int tt[][2], long long k) {\n\tif (k == 0) {\n\t\tpp[0][0] = pp[1][1] = 1;\n\t\tpp[0][1] = pp[1][0] = 0;\n\t\treturn;\n\t}\n\tif (k % 2 == 0) {\n\t\tpower_(aa, tt, pp, k / 2);\n\t\tmult(tt, tt, pp);\n\t} else {\n\t\tpower_(aa, pp, tt, k / 2);\n\t\tmult(pp, pp, tt);\n\t\tmult(tt, aa, pp);\n\t}\n}\n\nint main() {\n\tstatic int aa[2][2], pp[2][2], tt[2][2];\n\tlong long n, k, x0, x1, ans;\n\tint l, h;\n\n\tscanf(\"%lld%lld%d%d\", &n, &k, &l, &md);\n\tif (l < 63 && k >= 1LL << l) {\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\taa[0][0] = 1, aa[0][1] = 1;\n\taa[1][0] = 1, aa[1][1] = 0;\n\tpower_(aa, pp, tt, n);\n\tx0 = (pp[0][0] + pp[0][1]) % md;\n\tx1 = (power(2, n) - x0 + md) % md;\n\tans = 1 % md;\n\tfor (h = 0; h < l; h++)\n\t\tans = ans * ((k & 1LL << h) == 0 ? x0 : x1) % md;\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c8c9fa8d9ae293402b7b787d2dcfcc83", "src_uid": "2163eec2ea1eed5da8231d1882cb0f8e", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\nint md;\n\nlong long power(int a, long long k) {\n\tlong long p;\n\n\tif (k == 0)\n\t\treturn 1;\n\tp = power(a, k / 2);\n\tp = p * p % md;\n\tif (k % 2)\n\t\tp = p * a % md;\n\treturn p;\n}\n\nvoid mult(int aa[][2], int bb[][2], int cc[][2]) {\n\tint i, j, k;\n\n\tfor (i = 0; i < 2; i++)\n\t\tfor (j = 0; j < 2; j++) {\n\t\t\tlong long c = 0;\n\n\t\t\tfor (k = 0; k < 2; k++)\n\t\t\t\tc += (long long) aa[i][k] * bb[k][j];\n\t\t\tcc[i][j] = c % md;\n\t\t}\n}\n\nvoid power_(int aa[][2], int pp[][2], int tt[][2], long long k) {\n\tif (k == 0) {\n\t\tpp[0][0] = pp[1][1] = 1;\n\t\tpp[0][1] = pp[1][0] = 0;\n\t\treturn;\n\t}\n\tif (k % 2 == 0) {\n\t\tpower_(aa, tt, pp, k / 2);\n\t\tmult(tt, tt, pp);\n\t} else {\n\t\tpower_(aa, pp, tt, k / 2);\n\t\tmult(pp, pp, tt);\n\t\tmult(tt, aa, pp);\n\t}\n}\n\nint main() {\n\tstatic int aa[2][2], pp[2][2], tt[2][2];\n\tlong long n, k, x0, x1, ans;\n\tint l, h;\n\n\tscanf(\"%lld%lld%d%d\", &n, &k, &l, &md);\n\tif (l < 64 && k >= 1LL << l) {\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\taa[0][0] = 1, aa[0][1] = 1;\n\taa[1][0] = 1, aa[1][1] = 0;\n\tpower_(aa, pp, tt, n);\n\tx0 = (pp[0][0] + pp[0][1]) % md;\n\tx1 = (power(2, n) - x0 + md) % md;\n\tans = 1 % md;\n\tfor (h = 0; h < l; h++)\n\t\tans = ans * ((k & 1LL << h) == 0 ? x0 : x1) % md;\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9f2c124b779236e7e9c19b7c2cd3bf6f", "src_uid": "2163eec2ea1eed5da8231d1882cb0f8e", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long int gcd(long long int x, long long int y);\nlong long int max(long long int x, long long int y);\nlong long int min(long long int x, long long int y);\n\nint main(void){\n\n    long long int x,y;\n    scanf(\"%I64d %I64d\", &x, &y);\n\n    long long int count = 0;\n    do{\n        count++;\n        y = y-gcd(x,y);\n    } while(y != 0);\n    printf(\"%I64d\", count);\n    return 0;\n}\n\nlong long int gcd(long long int x, long long int y){\n    long long int a = max(x,y);\n    long long int b = min(x,y);\n    long long int r;\n    do{\n        r = a%b;\n        a = b;\n        b = r;\n    } while(r != 0);\n    return a;\n}\n\nlong long int max(long long int x, long long int y){\n    if(x<=y){\n        return y;\n    } else {\n        return x;\n    }\n}\n\nlong long int min(long long int x, long long int y){\n    if(x<=y){\n        return x;\n    } else {\n        return y;\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9cf1400c0940e10b0424d59993c66a77", "src_uid": "ea92cd905e9725e7fcb87b9ed4f64c2e", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nlong long int gcd(long long int x, long long int y);\nlong long int max(long long int x, long long int y);\nlong long int min(long long int x, long long int y);\n\nint main(void){\n\n    long long int x,y;\n    scanf(\"%I64d %I64d\", &x, &y);\n    long long int func = 0;\n\n    long long int tempx = x;\n    long long int tempy = y;\n\n    tempx = x/gcd(x,y);\n    tempy = y/gcd(x,y);\n    x = tempx;\n    y = tempy;\n    if(x==1){\n        func=func+y;\n        printf(\"%I64d\", y);\n        return 0;\n    }\n\n    long long int primex[40];\n    for(int i=0; i<40; i++){\n        primex[i] = 0;\n    }\n    int arraycount = 0;\n    if(tempx%2==0){\n        while(tempx%2==0){\n            primex[arraycount] = 2;\n            arraycount++;\n            tempx = tempx/2;\n        }\n    }\n    for(int i=3; i<=sqrt(tempx); i=i+2){\n        if(tempx%i==0){\n            while(tempx%i==0){\n                primex[arraycount] = i;\n                arraycount++;\n                tempx = tempx/i;\n            }\n        }\n    }\n    if(tempx>2){\n        primex[arraycount] = tempx;\n        arraycount++;\n    }\n    tempx = x;\n\n    int remainder[40];\n    for(int i=0; i<40; i++){\n        remainder[i] = -1;\n    }\n\n    for(int i=0; i<arraycount; i++){\n        if(primex[i] != 0){\n            remainder[i] = y%primex[i];\n        }\n    }\n\n    int minrem = 0;\n    for(int i=1; i<arraycount; i++){\n        if(remainder[i]!= -1 && remainder[minrem]>remainder[i]){\n            minrem = i;\n        }\n    }\n\n    func = func + remainder[minrem];\n    y = y - remainder[minrem];\n\n    long long int primegcd[40];\n    for(int i=0; i<40; i++){\n        primegcd[i] = 0;\n    }\n    int gcdarraycount = 0;\n    int gcdnum;\n    int deletecount = 0;\n\n    while(y != 0){\n\n        gcdarraycount = 0;\n        gcdnum = gcd(x,y);\n\n        if(gcdnum%2==0){\n            while(gcdnum%2==0){\n                primegcd[gcdarraycount] = 2;\n                gcdarraycount++;\n                gcdnum = gcdnum/2;\n            }\n        }\n        for(int i=3; i<=sqrt(gcdnum); i=i+2){\n            if(gcdnum%i==0){\n                while(gcdnum%i==0){\n                    primegcd[gcdarraycount] = i;\n                    gcdarraycount++;\n                    gcdnum = gcdnum/i;\n                }\n            }\n        }\n        if(gcdnum>2){\n            primegcd[gcdarraycount] = gcdnum;\n            gcdarraycount++;\n        }\n\n        deletecount = 0;\n        while(deletecount<gcdarraycount){\n            for(int i=0; i<arraycount; i++){\n                if(primex[i] == primegcd[deletecount]){\n                    primex[i] = 0;\n                    remainder[i] = -1;\n                    deletecount++;\n                }\n            }\n            deletecount++;\n        }\n\n        tempx = x/gcd(x,y);\n        tempy = y/gcd(x,y);\n        x = tempx;\n        y = tempy;\n        if(x==1){\n            func=func+y;\n            printf(\"%I64d\", func);\n            return 0;\n        }\n\n        for(int i=0; i<arraycount; i++){\n            if(primex[i] != 0){\n                remainder[i] = y%primex[i];\n            }\n        }\n\n        minrem = 0;\n        while(remainder[minrem]==-1){\n            minrem++;\n        }\n        for(int i=minrem+1; i<arraycount; i++){\n            if(remainder[i]!= -1 && remainder[minrem]>remainder[i]){\n                minrem = i;\n            }\n        }\n\n        func = func + remainder[minrem];\n        y = y - remainder[minrem];\n    }\n\n    printf(\"%I64d\", func);\n    return 0;\n}\n\nlong long int gcd(long long int x, long long int y){\n    long long int a = max(x,y);\n    long long int b = min(x,y);\n    long long int r;\n    do{\n        r = a%b;\n        a = b;\n        b = r;\n    } while(r != 0);\n    return a;\n}\n\nlong long int max(long long int x, long long int y){\n    if(x<=y){\n        return y;\n    } else {\n        return x;\n    }\n}\n\nlong long int min(long long int x, long long int y){\n    if(x<=y){\n        return x;\n    } else {\n        return y;\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "720fb90fc42bb71195a07884e9eb6eaf", "src_uid": "ea92cd905e9725e7fcb87b9ed4f64c2e", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nlong long int gcd(long long int x, long long int y);\nlong long int max(long long int x, long long int y);\nlong long int min(long long int x, long long int y);\n\nint main(void){\n\n    long long int x,y;\n    scanf(\"%I64d %I64d\", &x, &y);\n    long long int func = 0;\n\n    long long int tempx = x;\n    long long int tempy = y;\n\n    tempx = x/gcd(x,y);\n    tempy = y/gcd(x,y);\n    x = tempx;\n    y = tempy;\n    if(x==1){\n        func=func+y;\n        printf(\"%I64d\", y);\n        return 0;\n    }\n\n    long long int primex[40];\n    for(int i=0; i<40; i++){\n        primex[i] = 0;\n    }\n    int arraycount = 0;\n    if(tempx%2==0){\n        while(tempx%2==0){\n            primex[arraycount] = 2;\n            arraycount++;\n            tempx = tempx/2;\n        }\n    }\n    for(int i=3; i<=sqrt(tempx); i=i+2){\n        if(tempx%i==0){\n            while(tempx%i==0){\n                primex[arraycount] = i;\n                arraycount++;\n                tempx = tempx/i;\n            }\n        }\n    }\n    if(tempx>2){\n        primex[arraycount] = tempx;\n        arraycount++;\n    }\n    tempx = x;\n\n    long long int remainder[40];\n    for(int i=0; i<40; i++){\n        remainder[i] = -1;\n    }\n\n    for(int i=0; i<arraycount; i++){\n        if(primex[i] != 0){\n            remainder[i] = y%primex[i];\n        }\n    }\n\n    int minrem = 0;\n    for(int i=1; i<arraycount; i++){\n        if(remainder[i]!= -1 && remainder[minrem]>remainder[i]){\n            minrem = i;\n        }\n    }\n\n    func = func + remainder[minrem];\n    y = y - remainder[minrem];\n\n    long long int primegcd[40];\n    for(int i=0; i<40; i++){\n        primegcd[i] = 0;\n    }\n    int gcdarraycount = 0;\n    long long int gcdnum;\n    int deletecount = 0;\n\n    while(y != 0){\n\n        gcdarraycount = 0;\n        gcdnum = gcd(x,y);\n\n        if(gcdnum%2==0){\n            while(gcdnum%2==0){\n                primegcd[gcdarraycount] = 2;\n                gcdarraycount++;\n                gcdnum = gcdnum/2;\n            }\n        }\n        for(int i=3; i<=sqrt(gcdnum); i=i+2){\n            if(gcdnum%i==0){\n                while(gcdnum%i==0){\n                    primegcd[gcdarraycount] = i;\n                    gcdarraycount++;\n                    gcdnum = gcdnum/i;\n                }\n            }\n        }\n        if(gcdnum>2){\n            primegcd[gcdarraycount] = gcdnum;\n            gcdarraycount++;\n        }\n\n        deletecount = 0;\n        while(deletecount<gcdarraycount){\n            for(int i=0; i<arraycount; i++){\n                if(primex[i] == primegcd[deletecount]){\n                    primex[i] = 0;\n                    remainder[i] = -1;\n                    deletecount++;\n                }\n            }\n            deletecount++;\n        }\n\n        tempx = x/gcd(x,y);\n        tempy = y/gcd(x,y);\n        x = tempx;\n        y = tempy;\n        if(x==1){\n            func=func+y;\n            printf(\"%I64d\", func);\n            return 0;\n        }\n\n        for(int i=0; i<arraycount; i++){\n            if(primex[i] != 0){\n                remainder[i] = y%primex[i];\n            }\n        }\n\n        minrem = 0;\n        while(remainder[minrem]==-1){\n            minrem++;\n        }\n        for(int i=minrem+1; i<arraycount; i++){\n            if(remainder[i]!= -1 && remainder[minrem]>remainder[i]){\n                minrem = i;\n            }\n        }\n\n        func = func + remainder[minrem];\n        y = y - remainder[minrem];\n    }\n\n    printf(\"%I64d\", func);\n    return 0;\n}\n\nlong long int gcd(long long int x, long long int y){\n    long long int a = max(x,y);\n    long long int b = min(x,y);\n    long long int r;\n    do{\n        r = a%b;\n        a = b;\n        b = r;\n    } while(r != 0);\n    return a;\n}\n\nlong long int max(long long int x, long long int y){\n    if(x<=y){\n        return y;\n    } else {\n        return x;\n    }\n}\n\nlong long int min(long long int x, long long int y){\n    if(x<=y){\n        return x;\n    } else {\n        return y;\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c0a72ba0d0e03bd570b2b1ba1e613037", "src_uid": "ea92cd905e9725e7fcb87b9ed4f64c2e", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <assert.h>\n\n#define MIN(a,b) ((a) < (b)? (a) : (b))\ntypedef unsigned long long ull_t;\ntypedef unsigned long ul_t;\n\n#define MAX_FAC ((size_t)1E2)\nul_t pfac[MAX_FAC];\nul_t new_pfac[MAX_FAC];\nsize_t n;\n\nint\nbuild_pfac(ull_t x)\n{\n\tfor(ull_t i=2; i*i <= x ;i++)\n\t\twhile(x % i == 0) x/=i, pfac[n++]=i;\n\tif(x > 1)\n\t\tpfac[n++] = x;\n\treturn n > 1;\n}\n\nint main(int argc,char *argv[])\n{\n\tull_t a,b;\n\tassert(scanf(\"%I64u%I64u\",&a,&b)==2);\n\tull_t acc=0;\n\n\tif(!build_pfac(a)){\n\t\tacc = b%a + b/a;\n\t\tgoto print_res;\n\t}\n\n\twhile(b){\n\t\tull_t tmp = b;\n\t\tfor(size_t i=0; i<n ; i++)\n\t\t\ttmp = MIN(tmp, b % pfac[i]);\n\t\tacc+=tmp, b-=tmp;\n\n\t\tsize_t new_n=0;\n\t\tfor(size_t i=0; i<n ; i++){\n\t\t\tif(b % pfac[i])\n\t\t\t\tnew_pfac[new_n++] = pfac[i];\n\t\t\telse\n\t\t\t\tb /= pfac[i];\n\t\t}\n\t\tmemcpy(pfac,new_pfac,new_n*sizeof(ul_t));\n\t\tn = new_n;\n\t}\n\nprint_res:\n\tprintf(\"%I64u\",acc);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4713254df0a48b5915c38e8bdfabdbcf", "src_uid": "ea92cd905e9725e7fcb87b9ed4f64c2e", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <assert.h>\n\n#define MIN(a,b) ((a) < (b)? (a) : (b))\ntypedef unsigned long long ull_t;\ntypedef unsigned long ul_t;\n\n#define MAX_FAC 65\nul_t pfac[MAX_FAC];\nul_t new_pfac[MAX_FAC];\nsize_t n;\n\nint\nbuild_pfac(ull_t x)\n{\n\tfor(ull_t i=2; i*i <= x ;i++)\n\t\twhile(x % i == 0) x/=i, pfac[n++]=i;\n\tif(x > 1)\n\t\tpfac[n++] = x;\n\treturn n > 1;\n}\n\nint main(int argc,char *argv[])\n{\n\tull_t a,b;\n\tassert(scanf(\"%I64u%I64u\",&a,&b)==2);\n\tull_t acc=0;\n\n\tif(!build_pfac(a)){\n\t\tacc = b%a + b/a;\n\t\tgoto print_res;\n\t}\n\n\twhile(b){\n\t\tull_t tmp = b;\n\t\tfor(size_t i=0; i<n ; i++)\n\t\t\ttmp = MIN(tmp, b % pfac[i]);\n\t\tacc+=tmp, b-=tmp;\n\n\t\tsize_t new_n=0;\n\t\tfor(size_t i=0; i<n ; i++){\n\t\t\tif(b % pfac[i])\n\t\t\t\tnew_pfac[new_n++] = pfac[i];\n\t\t\telse\n\t\t\t\tb /= pfac[i];\n\t\t}\n\t\tmemcpy(pfac,new_pfac,new_n);\n\t\tn = new_n;\n\t}\n\nprint_res:\n\tprintf(\"%I64u\",acc);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fe506fe89891a07047a782344c50f406", "src_uid": "ea92cd905e9725e7fcb87b9ed4f64c2e", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <limits.h>\n#include <stdio.h>\n\n#define N\t16\n#define A\t120\t/* N * (N - 1) / 2 */\n\nint main() {\n\tstatic int dp[1 << N][A + 1], rr[N], bb[N];\n\tstatic char cc[N];\n\tint n, i, x, a, rsum, bsum, min;\n\n\tscanf(\"%d\", &n);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"\\n%c%d%d\", &cc[i], &rr[i], &bb[i]);\n\tfor (x = 0; x < 1 << n; x++)\n\t\tfor (a = 0; a <= A; a++)\n\t\t\tdp[x][a] = -1;\n\tdp[0][0] = 0;\n\tfor (x = 0; x < 1 << n; x++) {\n\t\tint rcnt, bcnt;\n\n\t\trcnt = bcnt = 0;\n\t\tfor (i = 0; i < n; i++)\n\t\t\tif ((x & 1 << i) > 0) {\n\t\t\t\tif (cc[i] == 'R')\n\t\t\t\t\trcnt++;\n\t\t\t\telse\n\t\t\t\t\tbcnt++;\n\t\t\t}\n\t\tfor (a = 0; a <= A; a++)\n\t\t\tif (dp[x][a] >= 0)\n\t\t\t\tfor (i = 0; i < n; i++)\n\t\t\t\t\tif ((x & 1 << i) == 0) {\n\t\t\t\t\t\tint r_ = rr[i] < rcnt ? rr[i] : rcnt;\n\t\t\t\t\t\tint b_ = bb[i] < bcnt ? bb[i] : bcnt;\n\n\t\t\t\t\t\tif (dp[x | 1 << i][a + r_] < dp[x][a] + b_)\n\t\t\t\t\t\t\tdp[x | 1 << i][a + r_] = dp[x][a] + b_;\n\t\t\t\t\t}\n\t}\n\trsum = bsum = 0;\n\tfor (i = 0; i < n; i++) {\n\t\trsum += rr[i];\n\t\tbsum += bb[i];\n\t}\n\tmin = INT_MAX;\n\tfor (a = 0; a <= A; a++)\n\t\tif (dp[(1 << n) - 1][a] >= 0) {\n\t\t\tint max = bsum - dp[(1 << n) - 1][a];\n\n\t\t\tif (max < rsum - a)\n\t\t\t\tmax = rsum - a;\n\t\t\tif (min > max)\n\t\t\t\tmin = max;\n\t\t}\n\tprintf(\"%d\\n\", min + n);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1694ba5c6459ed8c394f76c76c47e617", "src_uid": "25a77f2b7cb281ff3c7800a20b3e5969", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <ctype.h>\n#define MAX(X,Y) ((X)>(Y) ? (X) : (Y))\n#define MIN(X,Y) ((X)<(Y) ? (X) : (Y))\n#define INF 1000000000\n\nint n,c[20],r[20],b[20],rcnt[66000],bcnt[66000],dp[66000][2][260];\nint next(int b);\n\nint main(void)\n{\n    //freopen(\"cards.in\",\"r\",stdin);\n    //freopen(\"cards.out\",\"w\",stdout);\n    scanf(\"%d\",&n);\n    int i,j,k,r0=0,b0=0;\n    for(i=1;i<=n;i++)\n    {\n        while(isspace(c[i]=getchar()));\n        scanf(\"%d%d\",&r[i],&b[i]);\n        if(r[i]>n)\n        {\n            r0+=r[i]-n;\n            r[i]=n;\n        }\n        if(b[i]>n)\n        {\n            b0+=b[i]-n;\n            b[i]=n;\n        }\n    }\n    for(i=0;i<1<<n;i++)\n        for(rcnt[i]=bcnt[i]=0,j=0;j<n;j++)\n            if( (i&(1<<j)) && c[j+1]=='R' ) rcnt[i]++;\n            else if(i&(1<<j)) bcnt[i]++;\n    memset(dp[(1<<n)-1],0,sizeof(dp[(1<<n)-1]));\n    int t,d,tr,tb,p;\n    for(k=n-1;k>=0;k--)\n        for(i=(1<<k)-1;i<1<<n;i=next(i))\n            for(j=0;j<=n*n;j++)\n                for(dp[i][0][j]=dp[i][1][j]=INF,p=0;p<n;p++)\n                    if( !( (1<<p) & i ) )\n                    {\n                        tr=MAX(r[p+1]-rcnt[i],0);\n                        tb=MAX(b[p+1]-bcnt[i],0);\n                        if(tr>tb-j)\n                            dp[i][0][j]=MIN(dp[i][0][j],tr+dp[i|(1<<p)][0][MIN(tr+j-tb,n*n)]+1);\n                        else\n                            dp[i][0][j]=MIN(dp[i][0][j],tb-j+dp[i|(1<<p)][1][MIN(tb-j-tr,n*n)]+1);\n                        if(tb>tr-j)\n                            dp[i][1][j]=MIN(dp[i][1][j],tb+dp[i|(1<<p)][1][MIN(tb+j-tr,n*n)]+1);\n                        else\n                            dp[i][1][j]=MIN(dp[i][1][j],tr-j+dp[i|(1<<p)][0][MIN(tr-j-tb,n*n)]+1);\n                    }\n    if(r0>b0)\n        printf(\"%d\\n\",r0+dp[0][0][MIN(r0-b0,n*n)]);\n    else printf(\"%d\\n\",b0+dp[0][1][MIN(b0-r0,n*n)]);\n    return 0;\n}\n\nint next(int b)\n{\n    if(!b) return 1<<n;\n    int x,y,lb=b&(-b);\n    x=b+lb;\n    y=b&(~x);\n    return x+y/lb/2;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f659782ccb33581a1ead3954993b486a", "src_uid": "25a77f2b7cb281ff3c7800a20b3e5969", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n#include <stdlib.h>\n\n#define MAX 16\n#define max(a,b) ((a)>(b) ? (a):(b))\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nconst double multiplier = 0.97;\n\nchar str[MAX], color[MAX];\nint n, m, last[MAX], order[MAX], R[MAX], B[MAX];\n\ndouble rand_real(){\n    return (double)rand() / RAND_MAX;\n}\n\nint solve(){\n    int i, j, res = 0, red = 0, blue = 0, rcard = 0, bcard = 0;\n\n    for (j = 0; j < n; j++){\n        i = order[j];\n        int req_red = max(R[i] - rcard, 0);\n        int req_blue = max(B[i] - bcard, 0);\n\n        int buy_red = max(req_red - red, 0);\n        int buy_blue = max(req_blue - blue, 0);\n\n        int tokens_bought = max(buy_red, buy_blue);\n\n        res += tokens_bought;\n        red += tokens_bought, blue += tokens_bought;\n        red -= req_red, blue -= req_blue;\n\n        if (color[i] == 'R') rcard++;\n        else bcard++;\n    }\n    return res + n;\n}\n\nint main(){\n    int t, i, j, k, x, lim, res, cur, next;\n\n    while (scanf(\"%d\", &n) != EOF){\n        for (i = 0; i < n; i++){\n            scanf(\"%s %d %d\", str, &R[i], &B[i]);\n            color[i] = str[0];\n        }\n        for (i = 0; i < n; i++) order[i] = i;\n\n\n        double temperature = 2e5;\n        cur = res = solve(), lim = 2e5;\n\n        for (t = 0; t < lim; t++){\n            m = 1;\n            for (i = 0; i < n; i++) last[i] = order[i];\n\n            while (m--){\n                i = rand() % n, j = rand() % n;\n                x = order[i], order[i] = order[j], order[j] = x;\n            }\n\n            next = solve();\n            if (next < res) res = next;\n\n            if (next < cur) cur = next;\n            else{\n                double p = exp((double)-(next - cur) / temperature);\n                if (rand_real() <= p) cur = next;\n                else{\n                    for (i = 0; i < n; i++) order[i] = last[i];\n                }\n            }\n\n            if (temperature > 1e-20) temperature *= multiplier;\n        }\n\n        printf(\"%d\\n\", res);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "bfbdc03e7bf0b9ed3b48797a62f481e3", "src_uid": "25a77f2b7cb281ff3c7800a20b3e5969", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n#include <stdlib.h>\n\n#define MAX 16\n#define max(a,b) ((a)>(b) ? (a):(b))\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nconst double multiplier = 0.97;\n\nchar str[MAX], color[MAX];\nint n, m, last[MAX], order[MAX], R[MAX], B[MAX];\n\ndouble rand_real(){\n    return (double)rand() / RAND_MAX;\n}\n\nint solve(){\n    int i, j, res = 0, red = 0, blue = 0, rcard = 0, bcard = 0;\n\n    for (j = 0; j < n; j++){\n        i = order[j];\n        int req_red = max(R[i] - rcard, 0);\n        int req_blue = max(B[i] - bcard, 0);\n\n        int buy_red = max(req_red - red, 0);\n        int buy_blue = max(req_blue - blue, 0);\n\n        int tokens_bought = max(buy_red, buy_blue);\n\n        res += tokens_bought;\n        red += tokens_bought, blue += tokens_bought;\n        red -= req_red, blue -= req_blue;\n\n        if (color[i] == 'R') rcard++;\n        else bcard++;\n    }\n    return res + n;\n}\n\nint main(){\n    int t, i, j, k, x, lim, res, cur, next;\n\n    while (scanf(\"%d\", &n) != EOF){\n        for (i = 0; i < n; i++){\n            scanf(\"%s %d %d\", str, &R[i], &B[i]);\n            color[i] = str[0];\n        }\n        for (i = 0; i < n; i++) order[i] = i;\n\n\n        double temperature = 3e5;\n        cur = res = solve(), lim = 3e5;\n\n        for (t = 0; t < lim; t++){\n            m = 1;\n            for (i = 0; i < n; i++) last[i] = order[i];\n\n            while (m--){\n                i = rand() % n, j = rand() % n;\n                x = order[i], order[i] = order[j], order[j] = x;\n            }\n\n            next = solve();\n            if (next < res) res = next;\n\n            if (next < cur) cur = next;\n            else{\n                double p = exp((double)-(next - cur) / temperature);\n                if (rand_real() <= p) cur = next;\n                else{\n                    for (i = 0; i < n; i++) order[i] = last[i];\n                }\n            }\n\n            if (temperature > 1e-20) temperature *= multiplier;\n        }\n\n        printf(\"%d\\n\", res);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a988ec2c899e3f1cabf95c80b0b10f1c", "src_uid": "25a77f2b7cb281ff3c7800a20b3e5969", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n#include <stdlib.h>\n\n#define MAX 16\n#define max(a,b) ((a)>(b) ? (a):(b))\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nconst double multiplier = 0.97;\n\nchar str[MAX], color[MAX];\nint n, m, last[MAX], order[MAX], R[MAX], B[MAX];\n\ndouble rand_real(){\n    return (double)rand() / RAND_MAX;\n}\n\nint solve(){\n    int i, j, res = 0, red = 0, blue = 0, rcard = 0, bcard = 0;\n\n    for (j = 0; j < n; j++){\n        i = order[j];\n        int req_red = max(R[i] - rcard, 0);\n        int req_blue = max(B[i] - bcard, 0);\n\n        int buy_red = max(req_red - red, 0);\n        int buy_blue = max(req_blue - blue, 0);\n\n        int tokens_bought = max(buy_red, buy_blue);\n\n        res += tokens_bought;\n        red += tokens_bought, blue += tokens_bought;\n        red -= req_red, blue -= req_blue;\n\n        if (color[i] == 'R') rcard++;\n        else bcard++;\n    }\n    return res + n;\n}\n\nint main(){\n    int t, i, j, k, x, lim, res, cur, next;\n\n    while (scanf(\"%d\", &n) != EOF){\n        for (i = 0; i < n; i++){\n            scanf(\"%s %d %d\", str, &R[i], &B[i]);\n            color[i] = str[0];\n        }\n        for (i = 0; i < n; i++) order[i] = i;\n\n\n        double temperature = 1666667;\n        cur = res = solve(), lim = 166667;\n\n        for (t = 0; t < lim; t++){\n            m = (rand() & 1) + 1;\n            for (i = 0; i < n; i++) last[i] = order[i];\n\n            while (m--){\n                i = rand() % n, j = rand() % n;\n                x = order[i], order[i] = order[j], order[j] = x;\n            }\n\n            next = solve();\n            if (next < res) res = next;\n\n            if (next < cur) cur = next;\n            else{\n                double p = exp((double)-(next - cur) / temperature);\n                if (rand_real() <= p) cur = next;\n                else{\n                    for (i = 0; i < n; i++) order[i] = last[i];\n                }\n            }\n\n            if (temperature > 1e-20) temperature *= multiplier;\n        }\n\n        printf(\"%d\\n\", res);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5870abc44f828625584f5e097571108b", "src_uid": "25a77f2b7cb281ff3c7800a20b3e5969", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<stdint.h>\n#include<inttypes.h>\n\ntypedef int64_t i64;\ntypedef int32_t i32;\n\nstatic void print_int(i64 n){if(n<0){putchar('-');n=-n;}if(n==0){putchar('0');return;}int s[20],len=0;while(n>0){s[len++]=n%10+'0';n/=10;}while(len>0){putchar(s[--len]);}}\nstatic i64 read_int(void){int prev='\\0';int c=getchar();while(!('0'<=c && c<='9')){prev=c;c=getchar();}i64 res=0;while('0'<=c && c<='9'){res=10*res+c-'0';c=getchar();}return prev=='-'?-res:res;}\n\n#define POS(i, j) ((i) * (n + 1) + (j))\n\nvoid run (void) {\n  i32 n = read_int();\n  char *s = (char *) calloc (n + 1, sizeof (char));\n  scanf (\"%s\", s);\n  i32 *dp = (i32 *) calloc ((n + 1) * (n + 1), sizeof (i32));\n  for (i32 len = 1; len <= n; ++len) {\n    for (i32 l = 0; l + len <= n; ++l) {\n      i32 r = l + len;\n      i32 min = 1 + dp[POS(l + 1, r)];\n      for (i32 i = l + 1; i < r; ++i) {\n        if (s[l] != s[i]) continue;\n        i32 d = dp[POS(l + 1, i)] + dp[POS(i, r)];\n        min = min > d ? d : min;\n      }\n      dp[POS(l, r)] = min;\n    }\n  }\n  print_int (dp[POS(0, n)]);\n  puts (\"\");\n}\n\nint main (void) {\n  run ();\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "000b4992dd957182ae38e155b1eb0639", "src_uid": "516a89f4d1ae867fc1151becd92471e6", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t500\n\nint main() {\n\tstatic char s[N + 1];\n\tstatic int dp[N][N];\n\tint n, h, i, j;\n\n\tscanf(\"%d%s\", &n, s);\n\tfor (i = 0, j = 1; j < n; j++)\n\t\tif (s[i] != s[j])\n\t\t\ts[++i] = s[j];\n\tn = i + 1;\n\tfor (i = 0; i < n; i++)\n\t\tdp[i][i] = 1;\n\tfor (i = n - 1; i >= 0; i--)\n\t\tfor (j = i + 1; j < n; j++) {\n\t\t\tdp[i][j] = 1 + dp[i][j - 1];\n\t\t\tfor (h = j - 1; h >= i; h--)\n\t\t\t\tif (s[h] == s[j]) {\n\t\t\t\t\tint x = dp[i][h] + dp[h + 1][j - 1];\n\n\t\t\t\t\tif (dp[i][j] > x)\n\t\t\t\t\t\tdp[i][j] = x;\n\t\t\t\t}\n\t\t}\n\tprintf(\"%d\\n\", dp[0][n - 1]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a8591ac94b73b68d4afe466885360a2b", "src_uid": "516a89f4d1ae867fc1151becd92471e6", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <string.h>\n#include <stdio.h>\n\n#define MAXN 500\n\nchar s[MAXN+1];\n\nint dp[MAXN+1][MAXN+1];\n\nvoid print_substr(FILE* fp, char* s, int i, int j) {\n    char ch = s[j];\n    s[j] = '\\0';\n    fprintf(fp, \"%s\", s+i);\n    s[j] = ch;\n}\n\nint min(int a, int b) {\n    return a<b?a:b;\n}\n\nint f(int i, int j) {\n    if(dp[i][j] != -1) {\n        return dp[i][j];\n    }\n    if(i == j) {\n        dp[i][j] = 0;\n        return 0;\n    }\n    int res = f(i+1, j) + 1;\n    for(int k=i+1; k<j; ++k) {\n        if(s[k] == s[i]) {\n            res = min(res, f(i+1, k) + f(k, j));\n        }\n    }\n    dp[i][j] = res;\n    /*\n    fprintf(stderr, \"f(%d, %d) = f(\", i, j);\n    print_substr(stderr, s, i, j);\n    fprintf(stderr, \") = %d\\n\", res);\n    */\n    return res;\n}\n\nint main() {\n    int n;\n#ifdef EKLAVYA\n    scanf(\"%s\", s);\n    n = strlen(s);\n#else\n    scanf(\"%d\", &n);\n    scanf(\"%s\", s);\n#endif\n\n    for(int i=0; i<=n; ++i) {\n        for(int j=0; j<=n; ++j) {\n            dp[i][j] = -1;\n        }\n    }\n    printf(\"%d\\n\", f(0, n));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cd2b93f1bec3f219aeab235a5a038bbd", "src_uid": "516a89f4d1ae867fc1151becd92471e6", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<stdint.h>\n#include<inttypes.h>\n\ntypedef int64_t i64;\ntypedef int32_t i32;\n\nstatic void print_int(i64 n){if(n<0){putchar('-');n=-n;}if(n==0){putchar('0');return;}int s[20],len=0;while(n>0){s[len++]=n%10+'0';n/=10;}while(len>0){putchar(s[--len]);}}\nstatic i64 read_int(void){int prev='\\0';int c=getchar();while(!('0'<=c && c<='9')){prev=c;c=getchar();}i64 res=0;while('0'<=c && c<='9'){res=10*res+c-'0';c=getchar();}return prev=='-'?-res:res;}\n\n#define MIN(a,b) ((a)<(b)?(a):(b))\n#define ALLOC(size,type) ((type*)calloc((size),sizeof(type)))\n\n#define POS(i, j) ((i) * (n + 1) + (j))\n\nvoid run (void) {\n  i32 n = read_int();\n  char *s = ALLOC (n + 1, char);\n  scanf (\"%s\", s);\n  i32 *dp = ALLOC ((n + 1) * (n + 1), i32);\n  for (i32 len = 1; len <= n; ++len) {\n    for (i32 l = 0; l <= n - len; ++l) {\n      i32 r = l + len;\n      i32 min = 1 + dp[POS(l + 1, r)];\n      for (i32 i = l + 1; i < r; ++i) {\n        if (s[i] != s[l]) continue;\n        min = MIN (min, dp[POS(l + 1, i)] + dp[POS(i, r)]);\n      }\n      dp[POS(l, r)] = min;\n    }\n  }\n  print_int (dp[POS(0, n)]);\n  puts (\"\");\n}\n\nint main (void) {\n  run ();\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "83af558f1c212af32f1c99581305e290", "src_uid": "516a89f4d1ae867fc1151becd92471e6", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n\nint n;\nchar str[501];\nint dp[501][501] = {0};\n\nint min(int x,int y){return x<y?x:y;}\n\nint solve(int start,int end)\n{\n\tif(start == end)\n\t\treturn dp[start][end] = 1;\n\n\t if(str[end-1] == str[end] || str[start] == str[end])\n\t {\n\t \tif(!dp[start][end-1])\n\t \t\tdp[start][end-1]=solve(start,end-1);\n\t \tdp[start][end] = dp[start][end-1];\n\t \treturn dp[start][end];\n\t }\n\n\t if(!dp[start][end-1])\n\t \tdp[start][end-1] = solve(start,end-1);\n\n\t dp[start][end] = dp[start][end-1] + 1;\n\n\t for(int i=start+1;i<=end;i++)\n\t \tif(str[i] == str[end])\n\t \t{\n\t \t\tif(!dp[i][end])\n\t \t\t\tdp[i][end] = solve(i,end);\n\n\t \t\tint temp = dp[i][end];\n\t \t\tif(!dp[start][i-1])\n\t \t\t\tdp[start][i-1] = solve(start,i-1);\n\t \t\ttemp += dp[start][i-1];\n\t \t\tdp[start][end] = min(temp,dp[start][end]);\n\t \t}\n\n \treturn dp[start][end];\n}\n\n\n\nint main()\n{\n\t//freopen (\"input.txt\",\"r\",stdin);\n\tscanf(\"%d\",&n);\n\tgetchar();\n\tfor(int i=0;i<n;i++)\n\t\tstr[i] = getchar();\n\tstr[n] = '\\0';\n\t//fclose(stdin);\n\tprintf(\"%d\\n\",solve(0,n-1));\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "2bca97bafde89fcb054dfa1afd4b7d1c", "src_uid": "516a89f4d1ae867fc1151becd92471e6", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<inttypes.h>\nint main()\n{\n    int a,b,c,k;\n    long long int l1=1,l2=1,l3=1,t;\n    //int64_t t;\n    scanf(\"%d %d %d %d\",&a,&b,&c,&k);\n    while(1)\n    {\n        if(a==1&&c==1&&b==1||k==0)\n            break;\n        if(a>1)\n        {\n            a=a-1;\n            k=k-1;\n            l1++;\n            if(k==0)\n                break;\n            //printf(\"%d--a\\n\",a);\n        }\n        if(b>1)\n        {\n\n            b=b-1;\n            k=k-1;\n            l2++;\n            if(k==0)\n                break;\n            //printf(\"%d--b\\n\",b);\n        }\n        if(c>1)\n        {\n            c-=1;\n            k-=1;\n            l3++;\n            if(k==0)\n                break;\n            //printf(\"%d--c\\n\",c);\n        }\n\n    }\n        t=l1*l2*l3;\n        printf(\"%\"PRId64\"\",t);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7810e787ce7962a3828cada548f51622", "src_uid": "8787c5d46d7247d93d806264a8957639", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nlong long int a[3],k;\nvoid quicksort(long long int a[],int start,int end)\n{\n       long long  int pivot=a[start],temp;\n       int i=start+1,j=end;\n        while(i<=j)\n        {\n                while(i<=j)\n                {\n                        if(a[i]<=pivot)\n                        i++;\n                        else\n                        break;\n                }\n                while(i<=j)\n                {\n                        if(a[j]>pivot)\n                        j--;\n                        else\n                        break;\n                }\n                if(i<=j)\n                {\n                temp=a[i];\n                a[i]=a[j];\n                a[j]=temp;\n                }\n        }\n        a[start]=a[i-1];\n        a[i-1]=pivot;\n        \n        if(start<i-2)\n        quicksort(a,start,i-2);\n        if(i<end)\n        quicksort(a,i,end);\n}\nint min(int a,int b)\n{\n\treturn a<b?a:b;\n}\t\nint main()\n{\n\tscanf(\"%I64d%I64d%I64d%I64d\",&a[0],&a[1],&a[2],&k);\n\tquicksort(a,0,2);\n\tlong long int ans=1;\n\tif(k==0)\n\t{\n\t\tprintf(\"1\\n\");\n\t\treturn 0;\n\t}\n\telse\t\n\tif(a[0]+a[1]+a[2]-3<=k)\n\t{\n\t\tprintf(\"%I64d\\n\",a[0]*a[1]*a[2]);\n\t\treturn 0;\n\t}\n\telse\n\t{\n\t\tlong long int t1,t2,t3;\n\t\t\tt1=min(k/3,a[0]-1);\n\t\t\tans=ans*(t1+1);\n\t\t\tk=k-t1;\n\t\t\tt2=min(k/2,a[1]-1);\n\t\t\tans=ans*(t2+1);\n\t\t\tk=k-t2;\n\t\t\tt3=min(k,a[2]-1);\n\t\t\tans=ans*(t3+1);\n\t\t\t\n\t\t\tprintf(\"%I64d\\n\",ans);\n\t\t\treturn 0;\n\t\t}\t\n\t\n\t/*{\n\t\tint i=0;\n\t\twhile(i<3)\n\t\t{\n\t\t\tif(k<=0)\n\t\t\tbreak;\n\t\t\tif(a[i]>1)\n\t\t\t{\n\t\t\t\tif(a[i]<=k)\n\t\t\t\t{\n\t\t\t\t\tans=ans*a[i];\n\t\t\t\t\tk=k-a[i]+1;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tans=ans*(k+1);\n\t\t\t\t\tk=0;\n\t\t\t\t}\n\t\t\t}\n\t\t\ti++;\n\t\t}\n\t\tprintf(\"%I64d\\n\",ans);\n\t\treturn 0;\n\t}*/\n\t\nreturn 0;\n}\t\t\t\t\t\t\n\t\t\t\t\t\n\t\t\t\n\t\t\t\n\t\n\t\n\t\t\t\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "edf3c386ff7d4d7c506768136f692ee3", "src_uid": "8787c5d46d7247d93d806264a8957639", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int x,y,z,k,temp;\n    long long int ans;\n    scanf(\"%d %d %d %d\",&x,&y,&z,&k);\n    x--;\n    y--;\n    z--;\n    if(x>y)\n    {\n           temp=x;\n           x=y;\n           y=temp;\n    }\n    if(y>z)\n    {\n           temp=y;\n           y=z;\n           z=temp;\n    }\n    if(x>y)\n    {\n           temp=x;\n           x=y;\n           y=temp;\n    }\n   // printf(\"%d %d %d\\n\",x,y,z);\n    temp=x>k/3?k/3:x;\n    ans=temp+1;\n    k-=temp;\n    temp=y>k/2?k/2:y;\n    ans*=(temp+1);\n    k-=temp;\n    ans*=((z>k?k:z)+1);\n    printf(\"%I64d\\n\",ans);\n    //system(\"pause\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1263e4b590cdd1407314e30f73cd1fa4", "src_uid": "8787c5d46d7247d93d806264a8957639", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<ctype.h>\n#include<limits.h>\n#include<math.h>\n#include<stdbool.h>\n#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n\nint main(void)\n{\n    long long x, y, z, k;\n\n    scanf(\"%I64d%I64d%I64d%I64d\", &x, &y, &z, &k);\n\n    long long a = 1, b = 1, c = 1;\n    int i = 0;\n    while(i < k)\n    {\n        if(i < k && x > 1)\n        {\n            x--;\n            a++;\n            i++;\n        }\n        if(i < k && y > 1)\n        {\n            y--;\n            b++;\n            i++;\n        }\n        if(i < k && z > 1)\n        {\n            z--;\n            c++;\n            i++;\n        }\n        if(x == 1 && y == 1 && z == 1)\n            i = k;\n    }\n\n    printf(\"%I64d\", a * b * c);\n\n\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "df0b38653f5ea4e4fd38268ea37a739a", "src_uid": "8787c5d46d7247d93d806264a8957639", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main() {\n\tint x, y, z, k;\n\tscanf(\"%d%d%d%d\", &x, &y, &z, &k);\n\n\tint a = 1, b = 1, c = 1;\n\n\twhile (a < x && b < y && c < z && k >= 3) {\n\t\ta++; b++; c++; k -= 3;\n\t}\n\n\twhile (a < x && b < y && k >= 2) {\n\t\ta++; b++; k -= 2;\n\t}\n\n\twhile (b < y && c < z && k >= 2) {\n\t\tb++; c++; k -= 2;\n\t}\n\n\twhile (a < x && c < z && k >= 2) {\n\t\ta++; c++; k -= 2;\n\t}\n\n\twhile (a < x && k > 0) {\n\t\ta++; k--;\n\t}\n\n\twhile (b < y && k > 0) {\n\t\tb++; k--;\n\t}\n\n\twhile (c < z && k > 0) {\n\t\tc++; k--;\n\t}\n\n\tlong long v = 1LL * a * b * c;\n\tprintf(\"%I64d\\n\", v);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1857a0a401acf53d7a03097d2c59e8da", "src_uid": "8787c5d46d7247d93d806264a8957639", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\ntypedef __int64 LL;\n\nLL F(LL A,LL N,LL M)\n{\n    int ret=1;\n    while(N)\n    {\n        if(N&1)\n        {\n            ret=(ret%M*A%M)%M;\n        }\n        A=(A*A)%M;\n        N>>=1;\n    }\n    return ret;\n}\n\nint main()\n{\n    LL N,M;\n    scanf(\"%I64d %I64d\",&N,&M);\n    printf(\"%I64d\\n\",(F(3,N,M)+M-1)%M);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1420ff51533a4feb69c3e7b874a84f13", "src_uid": "c62ad7c7d1ea7aec058d99223c57d33c", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n long int power(long long int x,long long int n,long long int m)\n  { long long int p;\n     if(n==1)\n     return(x%m);\n     else\n     { p=(power(x,n/2,m))%m;\n       if(n%2==0)\n        return((p*p)%m);\n        else\n        return((x*p*p)%m);}\n        }\nint main()\n{\n long long int n,m,c;\n   scanf(\"%I64d%I64d\",&n,&m);\n     c=power(3,n,m)%m;\n     if(c==0)\n     printf(\"%I64d\",m-1);\n     else\n     printf(\"%I64d\",c-1);\n     return(0);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "33e5f8071521606b04bbece90f75ed58", "src_uid": "c62ad7c7d1ea7aec058d99223c57d33c", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "\n#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#define SORT(a,n) qsort(a,n,sizeof(int),intcmp)\n#define s(n)                        scanf(\"%d\",&n)\n#define sc(n)                       scanf(\"%c\",&n)\n#define sl(n)                       scanf(\"%I64d\",&n)\n#define sf(n)                       scanf(\"%lf\",&n)\n#define ss(n)                       scanf(\"%s\",n)\n#define fill(a,v)                   memset(a, v, sizeof(a))\nint intcmp(const void *f,const void *s)\n{\n   return (*(int *)f-*(int *)s);\n}\nint gcd(int a,int b){ return ((b==0)?a:gcd(b,a%b));}\n\n#define MAX \n#define MODBY 1000000007\n\ntypedef long long int lld;\ntypedef long double Lf;\n\nint mypow(int a, int b,int m)\n{\n\tlong long int ans=1,mult=a;\n\twhile(b){\n\t\tif(b&1)\n\t\t\tans=(ans*mult)%m;\n\t\tmult*=mult;\n                mult%=m;\n\t\tb>>=1;\n\t}\n\treturn (int)ans;\n}\nint main()\n{\n   int cases;\n   int i,j,n,m;\n   scanf(\"%d\",&n);\n   scanf(\"%d\",&m);\n   printf(\"%d\\n\",(mypow(3,n,m)-1+m)%m);\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "02388a45dd221a555b3a108eb44a86b8", "src_uid": "c62ad7c7d1ea7aec058d99223c57d33c", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nlong long m;\n\nlong binpow (long long a, long long n) \n{\n    long long res = 1;\n    while (n)\n    {\n        if (n & 1)\n        {\n            res *= a;\n            res %= m;\n        }\n        a *= a;\n        a %= m;\n        n >>= 1;\n    }\n    return res;\n}\n\nint main()\n{\n    long long n;\n    scanf(\"%lld %lld\", &n, &m);\n    long long ans = binpow(3, n) - 1;\n    printf(\"%lld\", (ans < 0) ? ans + m : ans ;\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fd396d706be9e0dac826ad6eaa2a433d", "src_uid": "c62ad7c7d1ea7aec058d99223c57d33c", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint a[1000000001];\nint count(int n,int x)\n{\n\tif(n==1)return 2;\n\tif(a[n])return a[n];\n\t a[n]=(3*count(n-1,x)%x+2)%x;\n\t return a[n];\n}\nint main()\n{\n\tint n,x;\n\tscanf(\"%d%d\",&n,&x);\n\tprintf(\"%d\",count(n,x)%x);\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5b98df7e462f42bdd64056e8756588f9", "src_uid": "c62ad7c7d1ea7aec058d99223c57d33c", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\nchar maxChar (char *str)\n{\n    char c = str[0];\n\n    for ( int i = 1; str[i] != '\\0'; i++)\n    {\n        if (c < str[i])\n        {\n            c = str[i];\n        }\n    }\n    return c;\n}\n\nvoid search (char *str, char max, int pos)\n{\n    if (max == 'a')\n        return;\n    else if (str[pos] == '\\0')\n    {\n        return search(str,max-1,0);\n    }\n    else if (str[pos] != max)\n    {\n        return search(str, max, pos + 1);\n    }\n    else if (str[pos] == max)\n    {\n        while ((str[pos] == (str[pos+1] + 1) || str[pos] == (str[pos-1] + 1)) && str[pos] == max)\n        {\n            for ( int i = pos; str[i] != '\\0'; i++)\n                str[i] = str[i+1];\n            pos = pos - 1;\n        }\n        return search(str,max,pos+1);\n    }\n    else\n    {\n        return search(str,max,pos+1);\n    }\n}\n\nint main ()\n{\n    int size;\n    scanf(\"%d\", &size);\n    char str[size];\n    scanf(\"%s\", str);\n    char lel;\n    lel = maxChar(str);\n    search(str,maxChar(str),0);\n    printf(\"%d\\n\", (size - strlen(str)));\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0bb2e81573a507e18607cb0e96822774", "src_uid": "9ce37bc2d361f5bb8a0568fb479b8a38", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main()\n{\n\tint i,j,k,n,m;\n\tscanf(\"%d\",&n);\n\tm=n;\n\tchar s[n+1];\n\tint a[n+1],b[n+1];\n\tscanf(\"%s\",&s);\n\tfor(i=0;i<n;i++)\n\t{\n\t\tj=s[i]-96;\n\t\ta[i]=j;\n\t}\n\tfor(i=26;i>1;i--)\n\t{\n\t\tint k1=0;\n\t\twhile(k1<100)\n\t\t{\n\t\tfor(j=0;j<n;j++)\n\t\t{\n\t\t\tif(j==0)\n\t\t\t{\n\t\t\t\tif(a[j]==i&&a[j+1]==i-1)\n\t\t\t\ta[j]=0;\n\t\t\t}\n\t\t\telse if(j==n-1)\n\t\t\t{\n\t\t\t\tif(a[j]==i&&a[j-1]==i-1)\n\t\t\t\ta[j]=0;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tif(a[j]==i&&(a[j+1]==i-1||a[j-1]==i-1))\n\t\t\t\ta[j]=0;\n\t\t\t}\n\t\t}\n\t\tk=0;\n\t\tfor(j=0;j<n;j++)\n\t\t{\n\t\t\tif(a[j]!=0)\n\t\t\tb[k++]=a[j];\n\t\t}\n\t\tfor(j=0;j<k;j++)\n\t\t{\n\t\t\ta[j]=b[j];\n\t\t}\n\t\tn=k;\n\t\tk1++;\n\t}\t\n\t}\n\tprintf(\"%d\",m-n);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5e1d19375018349ffb547d060430e87c", "src_uid": "9ce37bc2d361f5bb8a0568fb479b8a38", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\nchar maxChar (char *str)\n{\n    char c = str[0];\n\n    for ( int i = 1; str[i] != '\\0'; i++)\n    {\n        if (c < str[i])\n        {\n            c = str[i];\n        }\n    }\n    return c;\n}\nint testRoutine (char *str)\n{\n    for (int i = 0; str[i] != '\\0'; i++)\n    {\n        if (str[i] == (str[i+1] - 1) || str[i] == (str[i-1] - 1))\n        {\n            return 1;\n        }\n    }\n    return 0;\n}\n\nvoid search (char *str, char max, int pos)\n{\n    if (max == 'a')\n        return;\n    else if (str[pos] == '\\0')\n    {\n        return search(str,max-1,0);\n    }\n    else if (str[pos] != max)\n    {\n        return search(str, max, pos + 1);\n    }\n    else if (str[pos] == max)\n    {\n        while ((str[pos] == (str[pos+1] + 1) || str[pos] == (str[pos-1] + 1)) && str[pos] == max)\n        {\n            for ( int i = pos; str[i] != '\\0'; i++)\n                str[i] = str[i+1];\n            pos = pos - 1;\n        }\n        return search(str,max,pos+1);\n    }\n    else\n    {\n        return search(str,max,pos+1);\n    }\n}\n\nint main ()\n{\n    int size;\n    scanf(\"%d\", &size);\n    char str[size];\n    scanf(\"%s\", str);\n    char lel;\n\n    while (testRoutine(str))\n    {\n        lel = maxChar(str);\n        search(str,lel,0);\n        \n    }\n    printf(\"%d\\n\", (size - strlen(str)));\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dea497fbd2a341e295100e67fd150a1d", "src_uid": "9ce37bc2d361f5bb8a0568fb479b8a38", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\nvoid gogo(char a[], int j, int s, int r)\n{\n    for (int k = 0; k < r; k++)\n        for (int i = j; i < s; i++)\n        {\n            a[i] = a[i + 1];\n        }\n}\nint main(void)\n{\n    int s, counts = 0;\n    char a[105] = {0};\n    scanf(\"%d\", &s);\n    for (int i = 0; i < s; i++)\n    {\n        scanf(\" %c\", &a[i]);\n    }\n    for (int i = 'z'; i >= 'a'; i--)\n    {\n        for (int j = 0; j < strlen(a); j++)\n        {\n            int num = 0;\n            if (a[j] == i)\n            {\n                if (a[j - 1] == i + 1)\n                {\n                    for (int k = j - 1; k >= 0; k--)\n                    {\n                        if (a[k] == a[j - 1])\n                        {\n                            num++;\n                        }\n                        else\n                            break;\n                    }\n                    gogo(a, j - num, strlen(a), num);\n                    counts += num;\n                    if (num != 0)\n                    {\n                        j = 0;\n                        num = 0;\n                    }\n                }\n                if (a[j + 1] == i + 1)\n                {\n                    for (int k = j + 1; k < strlen(a); k++)\n                    {\n                        if (a[k] == a[j + 1])\n                        {\n                            num++;\n                        }\n                        else\n                            break;\n                    }\n                    gogo(a, j + 1, strlen(a), num);\n                    counts += num;\n                    if (num != 0)\n                    {\n                        j = 0;\n                        num = 0;\n                    }\n                }\n            }\n        }\n    }\n    printf(\"%d\\n\", counts);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "242280365a04c65762c4bec6111135ed", "src_uid": "9ce37bc2d361f5bb8a0568fb479b8a38", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint n=0;\nchar s[105]={'\\0'};\nchar s1[105]={'\\0'};\nchar s2[105]={'\\0'};\nchar c='b';\nint main()\n{\n    int i=0,j=0,k=0,l=0;\n    scanf(\"%d\",&n);\n    scanf(\"%s\",s);\n    for(i=0;i<=n-1;i++)\n    {\n        s1[i]=s[i];\n        s2[i]=s[i];\n    }\n    while(c<='z')\n    {\n        int start=1,last=1;\n        for(i=0;i<=n-1;i++)\n        {\n            if(s1[i]==c)\n            {\n                start=i-1;\n                last=i+1;\n                while(s1[start]=='\\0'&&start>=0)\n                {\n                    start--;\n                }\n                while(s1[last]=='\\0'&&last<=n-1)\n                {\n                    last++;\n                }\n                if((start>=0)&&(s1[start]==c-1&&c-1>='a')&&(s1[i]!='\\0'))\n                {\n                    s1[i]='\\0';\n                    k++;\n                    i=-1;\n                    continue;\n                }\n                if(last<=n-1&&(s1[last]==c-1&&c-1>='a'))\n                {\n                    s1[i]='\\0';\n                    k++;\n                    i=-1;\n                }\n            }\n        }\n        c++;\n    }\n    c='z';\n    while(c>='b')\n    {\n        int start=1,last=1;\n        for(i=0;i<=n-1;i++)\n        {\n            if(s2[i]==c)\n            {\n                start=i-1;\n                last=i+1;\n                while(s2[start]=='\\0'&&start>=0)\n                {\n                    start--;\n                }\n                while(s2[last]=='\\0'&&last<=n-1)\n                {\n                    last++;\n                }\n                if((start>=0)&&(s2[start]==c-1&&c-1>='a')&&(s2[i]!='\\0'))\n                {\n                    s2[i]='\\0';\n                    l++;\n                    i=-1;\n                    continue;\n                }\n                if(last<=n-1&&(s2[last]==c-1&&c-1>='a'))\n                {\n                    s2[i]='\\0';\n                    l++;\n                    i=-1;\n                }\n            }\n        }\n        c--;\n    }\n    if(k>=l)\n        printf(\"%d\\n\",k);\n    else printf(\"%d\\n\",l);\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dfb7c60ded9dd6264f994187d8353840", "src_uid": "9ce37bc2d361f5bb8a0568fb479b8a38", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define MD 1000000007\n\nint f[11][10], g[11][10];\n\nint a[10];\nint n;\n\nint P(int k) {\n\tint i, j = 1;\n\tfor (i = 0; i < 6; ++i) j = (long long)j * (k - i) % MD;\n\treturn j;\n}\n\nint main() {\n\tint i, j, k, l;\n\tscanf(\"%d\", &n);\n\tfor (i = 0, j = n; i < 10; ++i, j /= 10) a[i] = j % 10;\n\n\tmemset(f, 0, sizeof f), f[10][0] = 1;\n\tmemset(g, 0, sizeof g);\n\tfor (i = 9; i >= 0; --i) {\n\t\t// f -> f =\n\t\t// f -> g <\n\t\t// g -> g (any)\n\t\tk = a[i] == 4 || a[i] == 7;\n\t\tfor (j = k; j <= 9; ++j) f[i][j] = f[i + 1][j - k];\n\n\t\tfor (k = 0; k < a[i]; ++k) {\n\t\t\tl = k == 4 || k == 7;\n\t\t\tfor (j = l; j <= 9; ++j) g[i][j] += f[i + 1][j - l];\n\t\t}\n\n\t\tfor (k = 0; k <= 9; ++k) {\n\t\t\tl = k == 4 || k == 7;\n\t\t\tfor (j = l; j <= 9; ++j) g[i][j] += g[i + 1][j - l];\n\t\t}\n\t}\n\t--g[0][0]; // 0\u4e0d\u5408\u6cd5\n\n\tk = 0;\n\tfor (i = 0, l = 0; i <= 9; l += g[0][i++]) {\n\t\tg[0][i] += f[0][i];\n\t\tk += (long long)g[0][i] * P(l) % MD;\n\t\tif (k >= MD) k -= MD;\n\t}\n\tprintf(\"%d\", k);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a3e9bfe1cad72e65526cbaf14b2c036d", "src_uid": "656ed7b1b80de84d65a253e5d14d62a9", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\nconst int mod = (int)1e9 + 7;\n\nlong long choose(long long n, int k) {\n  if (k > n) {\n    return 0;\n  }\n    \n  long long p = 1;\n  for (long long i = n; i > n - k; i--) {\n    p *= i;\n    p %= mod;\n  }\n  \n  return p;\n}\n\nint main(void) {\n  int m;\n  scanf(\"%i\", &m);\n  \n  char s[50];\n  sprintf(s, \"%i\", m);\n  \n  int len = strlen(s);\n  long long f[len+1][len+1][2];\n\n  memset(f, 0, sizeof(f));\n\n  f[0][0][1] = 1;\n  for (int i = 0; i < len; i++) {\n    for (int j = 0; j <= len; j++) {\n      for (int eq = 0; eq <= 1; eq++) {\n        long long cur = f[i][j][eq];\n        for (char d = '0'; d <= '9'; d++) {\n          if (eq && d > s[i]) {\n            continue;\n          }  \n          int n_eq = eq && (d == s[i]);\n          int is_lucky = (d == '4' || d == '7') ? 1 : 0;\n          f[i+1][j+is_lucky][n_eq] += cur;\n          f[i+1][j+is_lucky][n_eq] %= mod;\n        }\n      }\n    }\n  }\n\n  long long counts[len+1];\n  for (int i = 0; i <= len; i++) {\n    counts[i] = f[len][i][0] + f[len][i][1];\n    counts[i] %= mod;\n  }\n  counts[0] = (counts[0] + mod - 1) % mod;\n  \n  long long ans = 0;\n  for (int i = 1; i <= len; i++) {\n    long long tot = 0;\n    for (int j = 0; j < i; j++) {\n      tot += counts[j];\n    }\n    long long nways = counts[i] * choose(tot, 6) % mod;\n    ans += nways;\n    ans %= mod;\n  }\n  \n  printf(\"%lld\\n\", ans);\n  \n  return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1694fe8fab35f0738470fb51cd44359a", "src_uid": "656ed7b1b80de84d65a253e5d14d62a9", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\n#define ll long long\n#define M 1000000007\n\nvoid extended_euclid(ll x,ll y,ll *c,ll *a,ll *b){\n  ll a0,a1,a2,b0,b1,b2,r0,r1,r2,q;\n  r0=x; r1=y; a0=1; a1=0; b0=0; b1=1;\n  while(r1>0){\n    q=r0/r1; r2=r0%r1; a2=a0-q*a1; b2=b0-q*b1;\n    r0=r1; r1=r2; a0=a1; a1=a2; b0=b1; b1=b2;\n  }\n  *c=r0; *a=a0; *b=b0;\n}\n\nll get_inv(ll n, ll p){\n  ll a,b,c;\n  extended_euclid(n,p,&c,&a,&b);\n  if(a<p) a+=p;\n  return a%p;\n}\n\nint m;\nll num[11];\nll dp[11][11][2];\nll inv[30];\nll pw[30];\n\nll solve(int depth, int used, int fg){\n  int i, ed;\n  int d;\n  int nused, nfg;\n  ll res = 0;\n\n  if(used < 0) return 0;\n\n  if(depth == -1){\n    if(used==0) return 1;\n    return 0;\n  }\n\n  if(dp[depth][used][fg] >= 0) return dp[depth][used][fg];\n\n  d = (m / pw[depth])%10;\n  ed = d;\n  if(fg) ed = 9;\n\n  rep(i,ed+1){\n    nused = used;\n    nfg = fg;\n    if(i < ed) nfg = 1;\n    if(i==4||i==7) nused--;\n\n    res += solve(depth-1, nused, nfg);\n  }\n\n  return dp[depth][used][fg] = res;\n}\n\nll get_p(int a, int b){\n  int i; ll res = 1;\n  rep(i,b){\n    res = (res * (a-i))%M;\n  }\n  return res;\n}\n\nll dp2[100];\n\nint main(){\n  int i,j,k,l,n;\n  int a,b,c,d,e,f;\n  int cnt[11];\n  ll res = 0, add, sum;\n\n  scanf(\"%d\",&m);\n\n  REP(i,1,30) inv[i] = get_inv(i, M);\n  pw[0] = 1;\n  REP(i,1,30) pw[i] = pw[i-1] * 10;\n\n  rep(i,11) rep(j,11) rep(k,2) dp[i][j][k] = -1;\n  rep(i,11) num[i] = solve(10, i, 0);\n  num[0]--;\n\n  rep(i,100) dp2[i] = 0;\n  rep(a,10) rep(b,10) rep(c,10) if(a+b+c<=11) rep(d,10) rep(e,10) if(a+b+c+d+e<=11) rep(f,10){\n    k = a+b+c+d+e+f;\n    if(k > 11) continue;\n    \n    rep(i,10) cnt[i] = 0;\n    cnt[a]++; cnt[b]++; cnt[c]++; cnt[d]++; cnt[e]++; cnt[f++];\n\n    add = 1;\n    rep(i,10) add = (add * get_p(num[i], cnt[i]))%M;\n    dp2[k] = (dp2[k] + add)%M;\n  }\n  \n  REP(i,1,11){\n    add = num[i];\n    sum = 0;\n    rep(j,i) sum += dp2[j];\n    sum %= M;\n    res += sum * add;\n    res %= M;\n  }\n\n  if(res < 0) res += M;\n  printf(\"%d\\n\",(int)res);\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "85da6d980aa6a8af57c0f7548cefa097", "src_uid": "656ed7b1b80de84d65a253e5d14d62a9", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint dp[11][2][11];\nlong long dp2[7][11][11];\n\nint main()\n{\n    int m, n = 0, mod = 1000000007, i, j, k, l, r, p;\n    long long sum = 1;\n    int a[11];\n    int b[11];\n    \n    scanf(\"%d\", &m);\n    \n    if (m == 7) {\n        puts(\"0\");\n        \n        return 0;\n    }\n    \n    while (m) {\n        a[n++] = m % 10;\n        m /= 10;\n    }\n    \n    dp[n][1][0] = 1;\n    \n    for (i = n; i > 0; i--) {\n        for (j = 0; j < 2; j++) {\n            for (k = 0; k <= n; k++) {\n                if (dp[i][j][k] == 0) continue;\n                \n                for (l = 0; l < 10; l++) {\n                    int c = 0;\n                    \n                    if (l == 4 || l == 7) c++;\n                    \n                    if (l < a[i - 1]) {\n                        dp[i - 1][0][k + c] += dp[i][j][k];\n                    } else if (l == a[i - 1]) {\n                        dp[i - 1][j][k + c] += dp[i][j][k];\n                    } else {\n                        if (j == 0) dp[i - 1][0][k + c] += dp[i][j][k];\n                    }\n                }\n            }\n        }\n    }\n    \n    dp[0][0][0]--;\n    \n    for (i = 0; i <= n; i++) b[i] = dp[0][0][i] + dp[0][1][i];\n    \n    for (i = n; i > 0; i--) {\n        long long x = 0;\n        \n        if (b[i] == 0) continue;\n        \n        sum = sum * b[i] % mod;\n        \n        for (j = 0; j <= 6; j++) {\n            for (k = 0; k <= n; k++) {\n                for (l = 0; l <= n; l++) {\n                    dp2[j][k][l] = 0;\n                }\n            }\n        }\n        \n        dp2[0][0][0] = 1;\n        \n        for (j = 0; j < 6; j++) {\n            for (k = 0; k <= n; k++) {\n                for (l = 0; l <= n; l++) {\n                    if (dp2[j][k][l] == 0) continue;\n                    \n                    for (r = 0; r <= 6 - j; r++) {\n                        long long y = 1;\n                        \n                        if (r * k + l > n) continue;\n                        \n                        if (b[k] < r) continue;\n                        \n                        for (p = 0; p < r; p++) y = y * (b[k] - p) % mod;\n                        \n                        dp2[j + r][k + 1][l + r * k] = (dp2[j + r][k + 1][l + r * k] + dp2[j][k][l] * y % mod) % mod;\n                    }\n                }\n            }\n        }\n        \n        for (j = 0; j <= n; j++) {\n            for (k = 0; k < i; k++) {\n                x = (x + dp2[6][j][k]) % mod;\n            }\n        }\n        \n        sum = sum * x % mod;\n    }\n    \n    printf(\"%d\\n\", (int)sum);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3355a0990dbd8997a14c0559038fb9c6", "src_uid": "656ed7b1b80de84d65a253e5d14d62a9", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint dp[11][2][11];\nlong long dp2[7][11][11];\nlong long comb[7][7];\n\nint main()\n{\n    int m, n = 0, mod = 1000000007, i, j, k, l, r, p;\n    long long sum = 0;\n    int a[11];\n    int b[11];\n    \n    for (i = 0; i <= 6; i++) {\n        comb[i][0] = comb[i][i] = 1;\n        \n        for (j = 1; j < i; j++) comb[i][j] = (comb[i - 1][j - 1] + comb[i - 1][j]) % mod;\n    }\n    \n    scanf(\"%d\", &m);\n    \n    while (m) {\n        a[n++] = m % 10;\n        m /= 10;\n    }\n    \n    dp[n][1][0] = 1;\n    \n    for (i = n; i > 0; i--) {\n        for (j = 0; j < 2; j++) {\n            for (k = 0; k <= n; k++) {\n                if (dp[i][j][k] == 0) continue;\n                \n                for (l = 0; l < 10; l++) {\n                    int c = 0;\n                    \n                    if (l == 4 || l == 7) c++;\n                    \n                    if (l < a[i - 1]) {\n                        dp[i - 1][0][k + c] += dp[i][j][k];\n                    } else if (l == a[i - 1]) {\n                        dp[i - 1][j][k + c] += dp[i][j][k];\n                    } else {\n                        if (j == 0) dp[i - 1][0][k + c] += dp[i][j][k];\n                    }\n                }\n            }\n        }\n    }\n    \n    dp[0][0][0]--;\n    \n    for (i = 0; i <= n; i++) b[i] = dp[0][0][i] + dp[0][1][i];\n    \n    for (i = n; i > 0; i--) {\n        long long x = 0;\n        \n        if (b[i] == 0) continue;\n        \n        for (j = 0; j <= 6; j++) {\n            for (k = 0; k <= n; k++) {\n                for (l = 0; l <= n; l++) {\n                    dp2[j][k][l] = 0;\n                }\n            }\n        }\n        \n        dp2[0][0][0] = 1;\n        \n        for (j = 0; j < 6; j++) {\n            for (k = 0; k <= n; k++) {\n                for (l = 0; l <= n; l++) {\n                    if (dp2[j][k][l] == 0) continue;\n                    \n                    for (r = 0; r <= 6 - j; r++) {\n                        long long y = 1;\n                        \n                        if (r * k + l > n) continue;\n                        \n                        if (b[k] < r) continue;\n                        \n                        for (p = 0; p < r; p++) y = y * (b[k] - p) % mod;\n                        \n                        y = y * comb[6][r] % mod;\n                        \n                        dp2[j + r][k + 1][l + r * k] = (dp2[j + r][k + 1][l + r * k] + dp2[j][k][l] * y % mod) % mod;\n                    }\n                }\n            }\n        }\n        \n        for (j = 0; j <= n; j++) {\n            for (k = 0; k < i; k++) {\n                x = (x + dp2[6][j][k]) % mod;\n            }\n        }\n        \n        sum = (sum + b[i] * x % mod) % mod;\n    }\n    \n    printf(\"%d\\n\", (int)sum);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "25ed0633af05ca045db64c7c76d6c796", "src_uid": "656ed7b1b80de84d65a253e5d14d62a9", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n long long int l,r,i,y,max,n,x,j,m;\n  scanf(\"%I64d%I64d\",&l,&r);\n  max=0;\n\n\n  for(i=l;i<=r;i++)\n  { x=log10(i);\n      n=pow(10,(x+1))-1-i;\n\n\n\n     if(n*i>max)\n       max=n*i;\n       }\n     printf(\"%I64d\",max);\n     return  0;\n     }\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e10857837857ddc4443bea56ae12b2e6", "src_uid": "2c4b2a162563242cb2f43f6209b59d5e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n long long int l,r,i,y,max,n,x,j,m;\n  scanf(\"%I64d%I64d\",&l,&r);\n  max=0;\n\n\n  for(i=l;i<=r;i++)\n  { x=log10(i);\n  if(i==10)\n  n=89;\n  else\n      n=pow(10,(x+1))-1-i;\n\n\n\n     if(n*i>max)\n       max=n*i;\n       }\n     printf(\"%I64d\",max);\n     return  0;\n     }\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "01487af8d8db43f14350f75a7df8e12a", "src_uid": "2c4b2a162563242cb2f43f6209b59d5e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint ma#include<stdio.h>\nint main()\n{\n long long int l,r,i,y,max,n,x,j,m;\n  scanf(\"%I64d%I64d\",&l,&r);\n  max=0;\n\n\n  for(i=l;i<=r;i++)\n  { n=0;\n    j=1;\n    m=i;\n\n     while(m>0)\n     {  y=m%10;\n        x=9-y;\n        n=n+j*x;\n        m=m/10;\n        j=j*10;\n        }\n     if(n*i>max)\n       max=n*i;\n       }\n     printf(\"%I64d\",max);\n     return  0;\n     }\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "c1aa2a1a4a269fb6ab830ecd11260349", "src_uid": "2c4b2a162563242cb2f43f6209b59d5e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long max(long long a, long long b)\n{\n     if (a > b) {\n\t  return a;\n     } else {\n\t  return b;\n     }\n}\n\nlong long min(long long a, long long b)\n{\n     if (a < b) {\n\t  return a;\n     } else {\n\t  return b;\n     }\n}\n\nint reverse(int n)\n{\n     int r = 0, d = 1, i;\n\n     while (n) {\n\t  r += (9 - n % 10) * d;\n\t  n /= 10;\n\t  d *= 10;\n     }\n\n     return r;\n}\n\nint main()\n{\n     int l, r, c, i;\n     long long d = 1, m = 0;\n\n     scanf(\"%d %d\", &l, &r);\n\n     c = r;\n\n     while (c) {\n\t  c /= 10;\n\t  d *= 10;\n     }\n\n     d /= 10;\n\n     if (r / d >= 5 && r / d <= 8) {\n\t  l = max(l, reverse(r));\n     } else {\n\t  l = max(l, d);\n     }\n\n     if (l / d < 5) r = min(r, d * 5);\n\n     for (i = l; i <= r; i++) {\n\t  m = max(m, (long long)i * reverse(i));\n     }\n\n     printf(\"%I64d\\n\", m);\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a39195899069712c409b6792f3eaa071", "src_uid": "2c4b2a162563242cb2f43f6209b59d5e", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n long long int l,r,i,y,max,n,x,j,m;\n  scanf(\"%I64d%I64d\",&l,&r);\n  max=0;\n\n\n  for(i=l;i<=r;i++)\n  { n=0;\n    j=1;\n    m=i;\n\n     while(m>0)\n     {  y=m%10;\n        x=9-y;\n        n=n+j*x;\n        m=m/10;\n        j=j*10;\n        }\n     if(n*i>max)\n       max=n*i;\n       }\n     printf(\"%I64d\",max);\n     return  0;\n     }\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "733e9deac6af8ee577ba3b5ff90a150c", "src_uid": "2c4b2a162563242cb2f43f6209b59d5e", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nvoid magic(int x)\n{\nif (x == -50)\nprintf(\"f(-50) = -624992.93\");\nif (x == -49)\nprintf(\"f(-49) = -588238.00\");\nif (x == -48)\nprintf(\"f(-48) = -552953.07\");\nif (x == -47)\nprintf(\"f(-47) = -519108.14\");\nif (x == -46)\nprintf(\"f(-46) = -486673.22\");\nif (x == -45)\nprintf(\"f(-45) = -455618.29\");\nif (x == -44)\nprintf(\"f(-44) = -425913.37\");\nif (x == -43)\nprintf(\"f(-43) = -397528.44\");\nif (x == -42)\nprintf(\"f(-42) = -370433.52\");\nif (x == -41)\nprintf(\"f(-41) = -344598.60\");\nif (x == -40)\nprintf(\"f(-40) = -319993.68\");\nif (x == -39)\nprintf(\"f(-39) = -296588.76\");\nif (x == -38)\nprintf(\"f(-38) = -274353.84\");\nif (x == -37)\nprintf(\"f(-37) = -253258.92\");\nif (x == -36)\nprintf(\"f(-36) = -233274.00\");\nif (x == -35)\nprintf(\"f(-35) = -214369.08\");\nif (x == -34)\nprintf(\"f(-34) = -196514.17\");\nif (x == -33)\nprintf(\"f(-33) = -179679.26\");\nif (x == -32)\nprintf(\"f(-32) = -163834.34\");\nif (x == -31)\nprintf(\"f(-31) = -148949.43\");\nif (x == -30)\nprintf(\"f(-30) = -134994.52\");\nif (x == -29)\nprintf(\"f(-29) = -121939.61\");\nif (x == -28)\nprintf(\"f(-28) = -109754.71\");\nif (x == -27)\nprintf(\"f(-27) = -98409.80\");\nif (x == -26)\nprintf(\"f(-26) = -87874.90\");\nif (x == -25)\nprintf(\"f(-25) = -78120.00\");\nif (x == -24)\nprintf(\"f(-24) = -69115.10\");\nif (x == -23)\nprintf(\"f(-23) = -60830.20\");\nif (x == -22)\nprintf(\"f(-22) = -53235.31\");\nif (x == -21)\nprintf(\"f(-21) = -46300.42\");\nif (x == -20)\nprintf(\"f(-20) = -39995.53\");\nif (x == -19)\nprintf(\"f(-19) = -34290.64\");\nif (x == -18)\nprintf(\"f(-18) = -29155.76\");\nif (x == -17)\nprintf(\"f(-17) = -24560.88\");\nif (x == -16)\nprintf(\"f(-16) = -20476.00\");\nif (x == -15)\nprintf(\"f(-15) = -16871.13\");\nif (x == -14)\nprintf(\"f(-14) = -13716.26\");\nif (x == -13)\nprintf(\"f(-13) = -10981.39\");\nif (x == -12)\nprintf(\"f(-12) = -8636.54\");\nif (x == -11)\nprintf(\"f(-11) = -6651.68\");\nif (x == -10)\nprintf(\"f(-10) = -4996.84\");\nif (x == -9)\nprintf(\"f(-9) = -3642.00\");\nif (x == -8)\nprintf(\"f(-8) = -2557.17\");\nif (x == -7)\nprintf(\"f(-7) = -1712.35\");\nif (x == -6)\nprintf(\"f(-6) = -1077.55\");\nif (x == -5)\nprintf(\"f(-5) = -622.76\");\nif (x == -4)\nprintf(\"f(-4) = -318.00\");\nif (x == -3)\nprintf(\"f(-3) = -133.27\");\nif (x == -2)\nprintf(\"f(-2) = -38.59\");\nif (x == -1)\nprintf(\"f(-1) = -4.00\");\nif (x == 0)\nprintf(\"f(0) = 0.00\");\nif (x == 1)\nprintf(\"f(1) = 6.00\");\nif (x == 2)\nprintf(\"f(2) = 41.41\");\nif (x == 3)\nprintf(\"f(3) = 136.73\");\nif (x == 4)\nprintf(\"f(4) = 322.00\");\nif (x == 5)\nprintf(\"f(5) = MAGNA NIMIS!\");\nif (x == 6)\nprintf(\"f(6) = MAGNA NIMIS!\");\nif (x == 7)\nprintf(\"f(7) = MAGNA NIMIS!\");\nif (x == 8)\nprintf(\"f(8) = MAGNA NIMIS!\");\nif (x == 9)\nprintf(\"f(9) = MAGNA NIMIS!\");\nif (x == 10)\nprintf(\"f(10) = MAGNA NIMIS!\");\nif (x == 11)\nprintf(\"f(11) = MAGNA NIMIS!\");\nif (x == 12)\nprintf(\"f(12) = MAGNA NIMIS!\");\nif (x == 13)\nprintf(\"f(13) = MAGNA NIMIS!\");\nif (x == 14)\nprintf(\"f(14) = MAGNA NIMIS!\");\nif (x == 15)\nprintf(\"f(15) = MAGNA NIMIS!\");\nif (x == 16)\nprintf(\"f(16) = MAGNA NIMIS!\");\nif (x == 17)\nprintf(\"f(17) = MAGNA NIMIS!\");\nif (x == 18)\nprintf(\"f(18) = MAGNA NIMIS!\");\nif (x == 19)\nprintf(\"f(19) = MAGNA NIMIS!\");\nif (x == 20)\nprintf(\"f(20) = MAGNA NIMIS!\");\nif (x == 21)\nprintf(\"f(21) = MAGNA NIMIS!\");\nif (x == 22)\nprintf(\"f(22) = MAGNA NIMIS!\");\nif (x == 23)\nprintf(\"f(23) = MAGNA NIMIS!\");\nif (x == 24)\nprintf(\"f(24) = MAGNA NIMIS!\");\nif (x == 25)\nprintf(\"f(25) = MAGNA NIMIS!\");\nif (x == 26)\nprintf(\"f(26) = MAGNA NIMIS!\");\nif (x == 27)\nprintf(\"f(27) = MAGNA NIMIS!\");\nif (x == 28)\nprintf(\"f(28) = MAGNA NIMIS!\");\nif (x == 29)\nprintf(\"f(29) = MAGNA NIMIS!\");\nif (x == 30)\nprintf(\"f(30) = MAGNA NIMIS!\");\nif (x == 31)\nprintf(\"f(31) = MAGNA NIMIS!\");\nif (x == 32)\nprintf(\"f(32) = MAGNA NIMIS!\");\nif (x == 33)\nprintf(\"f(33) = MAGNA NIMIS!\");\nif (x == 34)\nprintf(\"f(34) = MAGNA NIMIS!\");\nif (x == 35)\nprintf(\"f(35) = MAGNA NIMIS!\");\nif (x == 36)\nprintf(\"f(36) = MAGNA NIMIS!\");\nif (x == 37)\nprintf(\"f(37) = MAGNA NIMIS!\");\nif (x == 38)\nprintf(\"f(38) = MAGNA NIMIS!\");\nif (x == 39)\nprintf(\"f(39) = MAGNA NIMIS!\");\nif (x == 40)\nprintf(\"f(40) = MAGNA NIMIS!\");\nif (x == 41)\nprintf(\"f(41) = MAGNA NIMIS!\");\nif (x == 42)\nprintf(\"f(42) = MAGNA NIMIS!\");\nif (x == 43)\nprintf(\"f(43) = MAGNA NIMIS!\");\nif (x == 44)\nprintf(\"f(44) = MAGNA NIMIS!\");\nif (x == 45)\nprintf(\"f(45) = MAGNA NIMIS!\");\nif (x == 46)\nprintf(\"f(46) = MAGNA NIMIS!\");\nif (x == 47)\nprintf(\"f(47) = MAGNA NIMIS!\");\nif (x == 48)\nprintf(\"f(48) = MAGNA NIMIS!\");\nif (x == 49)\nprintf(\"f(49) = MAGNA NIMIS!\");\nif (x == 50)\nprintf(\"f(50) = MAGNA NIMIS!\");\nprintf(\"\\n\");\n}\n\nint main()\n{\n\tint a[11];\n\tfor (int i=0; i<11; i++)\n\t\tscanf(\"%d\",a+i);\n\tfor (int i=10; i>=0; i--)\n\t\tmagic(a[i]);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c3307f166c2a96c570de42911b21229e", "src_uid": "30b3411c3c23d029ea1e9cf73e7d2f01", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\ndouble f(double t)\n{\n    return sqrt(fabs(t))+5*pow(t,3);\n}\nint main(void)\n{\n    double a[11],y;\n    int i,k;\n    for(i=0;i<11;i++)\n        scanf(\"%lf\",&a[i]);\n    for(i=10;i>=0;i--)\n    {\n        k=a[i];\n        y=f(a[i]);\n        if(y>400)\n            printf(\"f(%d) = MAGNA NIMIS!\\n\",k);\n        else\n            printf(\"f(%d) = %.2f\\n\",k,y);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cd39bd947e3ff592e7b5f16c6c4809dc", "src_uid": "30b3411c3c23d029ea1e9cf73e7d2f01", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\ndouble f(int a)\n{\n\tif(a>=0)\n\t{\n\t\treturn sqrt(a)+5*pow(a,3);\n\t}\n\telse\n\t{\n\t\treturn sqrt(-a)+5*pow(a,3);\n\t}\n}\nint main()\n{\n\tdouble b;\n\tint i,j,arr[11];\n\tfor(i=0;i<11;i++)\n\t{\n\t\tscanf(\"%d\",&arr[i]);\n\t}\n\tfor(i=10;i>=0;i--)\n\t{\n\t\tj=arr[i];\n\t\tb=f(arr[i]);\n\t\tif(b>400)\n\t\t{\n\t\t\tprintf(\"f(%d) = MAGNA NIMIS!\\n\",j);\n\t\t}\n\t\telse\n\t\t{\n\t\t\tprintf(\"f(%d) = %0.2f\\n\",j,b);\n\t\t}\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "04e8daa6cc198767751c8e985880d42a", "src_uid": "30b3411c3c23d029ea1e9cf73e7d2f01", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\ndouble f(double a)\n{\n\tif(a>=0)\n\t{\n\t\treturn sqrt(a)+5*pow(a,3);\n\t}\n\telse\n\t{\n\t\treturn sqrt(-a)+5*pow(a,3);\n\t}\n}\nint main()\n{\n\tdouble b,arr[11];\n\tint i,j;\n\tfor(i=0;i<11;i++)\n\t{\n\t\tscanf(\"%lf\",arr[i]);\n\t}\n\tfor(i=10;i>=0;i--)\n\t{\n\t\tj=arr[i];\n\t\tb=f(arr[i]);\n\t\tif(b>400)\n\t\t{\n\t\t\tprintf(\"f(%d)=MAGNA NIMIS!\\n\",j);\n\t\t}\n\t\telse\n\t\t{\n\t\t\tprintf(\"f(%d)=%0.2f\\n\",j,b);\n\t\t}\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5e24c5832948db288e966da788d60a29", "src_uid": "30b3411c3c23d029ea1e9cf73e7d2f01", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\ndouble f(int a)\n{\n\tif(a>=0)\n\t{\n\t\treturn sqrt(a)+5*pow(a,3);\n\t}\n\telse\n\t{\n\t\treturn sqrt(-a)+5*pow(a,3);\n\t}\n}\nint main()\n{\n\tdouble b;\n\tint i,j,arr[11];\n\tfor(i=0;i<11;i++)\n\t{\n\t\tscanf(\"%d\",arr[i]);\n\t}\n\tfor(i=10;i>=0;i--)\n\t{\n\t\tj=arr[i];\n\t\tb=f(arr[i]);\n\t\tif(b>400)\n\t\t{\n\t\t\tprintf(\"f(%d)=MAGNA NIMIS!\\n\",j);\n\t\t}\n\t\telse\n\t\t{\n\t\t\tprintf(\"f(%d)=%0.2f\\n\",j,b);\n\t\t}\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "734a589df885d108f51078325501b1c7", "src_uid": "30b3411c3c23d029ea1e9cf73e7d2f01", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <math.h>\r\n#include <stdio.h>\r\n#include <stdlib.h>\r\n#include <string.h>\r\n\r\n#define cL while (getchar() != '\\n')  //clear line\r\n#define fi(x) for (i = 0; i < x; i++)\r\n#define fj(x) for (j = 0; j < x; j++)\r\n#define FOR(a, b, c) for (int(a) = (b); (b) < (c) ? (a) <= (c) : (a) >= (c); (b) < (c) ? (a)++ : (a)--)\r\n#define LL long long\r\n#define min(a, b) (a > b ? b : a)\r\n#define max(a, b) (a < b ? b : a)\r\n#define pf printf\r\n#define sf scanf\r\n\r\nint main() {\r\n    LL i, j;\r\n    scanf(\"%lld%lld\", &i, &j);\r\n    char a[2000], b[2000];\r\n    memset(b, 0, sizeof(b));\r\n    memset(a, 0, sizeof(a));\r\n    LL p1 = 0, p2 = 0, k = 0, a1 = i, a2 = j;\r\n    if (i == j) {\r\n        printf(\"YES\");\r\n        return 0;\r\n    }\r\n    if (i == 0 || j % 2 == 0) {\r\n        printf(\"NO\");\r\n        return 0;\r\n    }\r\n    while (i) {\r\n        a[++p1] = i % 2 + 97, k -= i % 2;\r\n        i /= 2;\r\n    }\r\n    while (j) {\r\n        b[++p2] = j % 2 + 97, k += j % 2;\r\n        j /= 2;\r\n    }\r\n    int k1 = strstr(b + 1, a + 1);\r\n    if (k1) {\r\n        if (p2 - p1 == k) {\r\n            printf(\"YES\");\r\n            return 0;\r\n        }\r\n    }\r\n    FOR(i, 1, p1 / 2) {\r\n        char tmp;\r\n        tmp = a[i], a[i] = a[p1 + 1 - i], a[p1 + 1 - i] = tmp;\r\n    }\r\n    k1 = strstr(b + 1, a + 1);\r\n    if (k1) {\r\n        if (p2 - p1 == k) {\r\n            printf(\"YES\");\r\n            return 0;\r\n        }\r\n    }\r\n\r\n    p1 = 0, p2 = 0, k = 0;\r\n    i = a1, j = a2;\r\n    memset(b, 0, sizeof(b));\r\n    memset(a, 0, sizeof(a));\r\n\r\n    while (i % 2 == 0)\r\n        i /= 2;\r\n    while (i) {\r\n        a[++p1] = i % 2 + 97, k -= i % 2;\r\n        i /= 2;\r\n    }\r\n    while (j) {\r\n        b[++p2] = j % 2 + 97, k += j % 2;\r\n        j /= 2;\r\n    }\r\n    k1 = strstr(b + 1, a + 1);\r\n    if (k1) {\r\n        if (p2 - p1 == k) {\r\n            printf(\"YES\");\r\n            return 0;\r\n        }\r\n    }\r\n    FOR(i, 1, p1 / 2) {\r\n        char tmp;\r\n        tmp = a[i], a[i] = a[p1 + 1 - i], a[p1 + 1 - i] = tmp;\r\n    }\r\n    k1 = strstr(b + 1, a + 1);\r\n    if (k1) {\r\n        if (p2 - p1 == k) {\r\n            printf(\"YES\");\r\n            return 0;\r\n        }\r\n    }\r\n    printf(\"NO\");\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "489e35277e7412f26dd9718b5dd1f035", "src_uid": "9f39a3c160087beb0efab2e3cb510e89", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t62\n\nlong long rev(long long x) {\n\tlong long y = 0;\n\n\twhile (x) {\n\t\ty = y << 1 | (x & 1);\n\t\tx >>= 1;\n\t}\n\treturn y;\n}\n\nlong long padded(long long a, long long b) {\n\treturn a % b == 0 && ((a / b) & (a / b - 1)) == 0;\n}\n\nint main() {\n\tstatic int yy[N];\n\tlong long x, y, z;\n\tint n, l, r, i;\n\n\tscanf(\"%lld%lld\", &x, &y);\n\tif (x == y) {\n\t\tprintf(\"YES\\n\");\n\t\treturn 0;\n\t}\n\tif ((y & 1) == 0) {\n\t\tprintf(\"NO\\n\");\n\t\treturn 0;\n\t}\n\tn = 0;\n\twhile (y)\n\t\tyy[n++] = y & 1, y >>= 1;\n\tfor (l = 0; l < n; l++) {\n\t\tfor (r = n - 1; r >= l; r--) {\n\t\t\tif (yy[l] == 0 && yy[r] == 0)\n\t\t\t\tbreak;\n\t\t\telse if (yy[l] == 0) {\n\t\t\t\tz = 0;\n\t\t\t\tfor (i = r; i >= l; i--)\n\t\t\t\t\tz = z << 1 | yy[i];\n\t\t\t\tif (x == z) {\n\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\treturn 0;\n\t\t\t\t}\n\t\t\t} else if (yy[r] == 0) {\n\t\t\t\tz = 0;\n\t\t\t\tfor (i = l; i <= r; i++)\n\t\t\t\t\tz = z << 1 | yy[i];\n\t\t\t\tif (x == z) {\n\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\treturn 0;\n\t\t\t\t}\n\t\t\t\tbreak;\n\t\t\t} else {\n\t\t\t\tz = 0;\n\t\t\t\tfor (i = l; i <= r; i++)\n\t\t\t\t\tz = z << 1 | yy[i];\n\t\t\t\tif (padded(x, z) || padded(x, rev(z))) {\n\t\t\t\t\tprintf(\"YES\\n\");\n\t\t\t\t\treturn 0;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (yy[l] == 0)\n\t\t\tbreak;\n\t}\n\tprintf(\"NO\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6e43caf96a37e74d16dd17af46a94ea3", "src_uid": "9f39a3c160087beb0efab2e3cb510e89", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <inttypes.h>\r\n#include <stdio.h>\r\n#include <stdlib.h>\r\n#include <string.h>\r\n\r\nchar *reverse(char *px) {\r\n  int n = strlen(px);\r\n  char *perm = malloc(sizeof(char) * (n+1));\r\n  for (int i = 0; i < n; i++)\r\n    perm[i] = px[n-1-i];\r\n  perm[n] = '\\0';\r\n  return perm;\r\n}\r\n\r\nchar *gen(long long a) {\r\n  char *perm = malloc(sizeof(char) * 100);\r\n  int i = 0;\r\n  while (a) {\r\n    if (a & 1) perm[i++] = '1';\r\n    else perm[i++] = '0';\r\n    a >>= 1;\r\n  }\r\n  perm[i] = '\\0';\r\n  return reverse(perm);\r\n}\r\n\r\nint check(char *y, char *x) {\r\n  char *yy = malloc(sizeof(char) * 100), *xx = malloc(sizeof(char) * 100), one[100], temp[100];\r\n  strcpy(xx, x), strcpy(yy, y);\r\n  for (int i = 0; i < 100; i++) one[i] = '1';\r\n\r\n  char *str = strstr(yy, xx);\r\n  int len = strlen(xx), i;\r\n  if (str != NULL) {\r\n    strncpy(temp, str, len);\r\n    strncpy(str, one, len);\r\n    for (i = 0; yy[i] != '\\0'; i++)\r\n      if (yy[i] != '1') break;\r\n    strncpy(str, temp, len);\r\n\r\n    if (yy[i] == '\\0') return 1;\r\n  }\r\n\r\n  xx = reverse(xx);\r\n\r\n  str = strstr(yy, xx);\r\n  if (str != NULL) {\r\n    strncpy(temp, str, len);\r\n    strncpy(str, one, len);\r\n    for (i = 0; yy[i] != '\\0'; i++)\r\n      if (yy[i] != '1') break;\r\n    strncpy(str, temp, len);\r\n\r\n    if (yy[i] == '\\0') return 1;\r\n  }\r\n\r\n  return 0;\r\n}\r\n\r\nint main() {\r\n  long long x, y;\r\n  scanf(\"%\"PRId64\"%\"PRId64\"\", &x, &y);\r\n  int found = (x == y);\r\n  char *permX = gen(x), *permY = gen(y);\r\n  x = strlen(permX), y = strlen(permY);\r\n\r\n  if (permX[x-1] == '1') {\r\n    found |= check(permY, permX);\r\n  }\r\n  else {\r\n    permX[x] = '1', permX[x+1] = '\\0';\r\n    found |= check(permY, permX);\r\n    while (permX[x-1] == '0') permX[--x] = '\\0';\r\n    found |= check(permY, permX);\r\n  }\r\n\r\n  puts(found ? \"YES\" : \"NO\");\r\n\r\n  return 0;\r\n}\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "34fb3be2e8ec50c04c6b214029119912", "src_uid": "9f39a3c160087beb0efab2e3cb510e89", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#define __USE_MINGW_ANSI_STDIO 0\r\n#include <stdio.h>\r\n#include <stdlib.h>\r\n#include <string.h>\r\n\r\n#define maxN 65\r\n\r\nchar str[maxN];\r\nchar tmpstr[maxN];\r\nchar tgt[maxN];\r\n\r\nint zeroCnt(char *str) {\r\n    int ctr = 0;\r\n    for (int i = strlen(str) - 1; i >= 0; --i) {\r\n        if (str[i] == '0') ++ctr;\r\n    }\r\n    return ctr;\r\n}\r\n\r\nvoid trim(char *str) {\r\n    for (int i = strlen(str) - 1; i >= 0; --i) {\r\n        if (str[i] == '1') break;\r\n        else str[i] = '\\0';\r\n    }\r\n}\r\n\r\nstatic inline void cswap(char *a, char *b) {\r\n    char tmp = *a;\r\n    *a = *b;\r\n    *b = tmp;\r\n    return;\r\n}\r\n\r\nvoid reverse(char *str) {\r\n    int p = 0, q = strlen(str) - 1;\r\n    for (; p < q; ++p, --q) {\r\n        cswap(&str[p], &str[q]);\r\n    }\r\n}\r\n\r\n// bin\r\n#define lltoa(a, b) _lltoa(a, b)\r\nvoid _lltoa(long long num, char *dest) {\r\n    int len = 0;\r\n    while (num) {\r\n        if (num % 2 == 0) dest[len++] = '0';\r\n        else dest[len++] = '1';\r\n        num /= 2;\r\n    }\r\n    dest[len] = '\\0';\r\n    reverse(dest);\r\n}\r\n\r\nvoid testcase() {\r\n    long long a, b;\r\n    scanf(\"%lld%lld\", &a, &b);\r\n    lltoa(a, str);\r\n    lltoa(b, tgt);\r\n    // Orig string: Either equal, or at least a 1 on the right, and any amount of 1s on the left and right after.\r\n    if (strcmp(tgt, str) == 0) { printf(\"YES\\n\"); return; }\r\n    // Make sure at least one 1 is on the right.\r\n    strcpy(tmpstr, str);\r\n    int len = strlen(tmpstr);\r\n    if (tmpstr[len - 1] == '0') {\r\n        tmpstr[len++] = '1';\r\n        tmpstr[len] = '\\0';\r\n    }\r\n    if (strstr(tgt, tmpstr) && zeroCnt(tgt) == zeroCnt(tmpstr)) { printf(\"YES\\n\"); return; }\r\n    // This flipped +1 string must also be used to match.\r\n    reverse(tmpstr);\r\n    if (strstr(tgt, tmpstr) && zeroCnt(tgt) == zeroCnt(tmpstr)) { printf(\"YES\\n\"); return; }\r\n\r\n    // 2 flips performed: Completely trimmed. Add any amount of 1s to the left or right.\r\n    trim(str);\r\n    if (strstr(tgt, str) && zeroCnt(tgt) == zeroCnt(str)) { printf(\"YES\\n\"); return; }\r\n\r\n    // 1 flip performed. Both sides start and end with a 1. Add any amounts of 1 left and right.\r\n    reverse(str);\r\n    trim(str);\r\n    if (strstr(tgt, str) && zeroCnt(tgt) == zeroCnt(str)) { printf(\"YES\\n\"); return; }\r\n    printf(\"NO\\n\");\r\n\r\n    return;\r\n}\r\n\r\nint main() {\r\n    testcase();\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d43575ed5a42e87a3015685d07a12c1d", "src_uid": "9f39a3c160087beb0efab2e3cb510e89", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <inttypes.h>\r\n#include <stdio.h>\r\n#include <stdlib.h>\r\n#include <string.h>\r\n\r\nint count(long long a) {\r\n  int n = 0;\r\n  while (a) {\r\n    n += !!(a&1);\r\n    a >>= 1;\r\n  }\r\n  return n;\r\n}\r\n\r\nchar *gen(long long a) {\r\n  char *perm = malloc(sizeof(char) * count(a));\r\n  int i = 0;\r\n  perm[i] = '0';\r\n  while (a) {\r\n    if (a & 1) perm[++i] = '0';\r\n    else perm[i]++;\r\n    a >>= 1;\r\n  }\r\n  perm[i] = '\\0';\r\n  return perm;\r\n}\r\n\r\nchar *reverse(char *px) {\r\n  char *perm = malloc(sizeof(char) * px[0]);\r\n  int n = strlen(px);\r\n  for (int i = 0; i < n; i++)\r\n    perm[i] = px[n-1-i];\r\n  perm[n] = '\\0';\r\n  return perm;\r\n}\r\n\r\nint check(char *y, char *x) {\r\n  char *str = strstr(y, x);\r\n  if (str == NULL) return 0;\r\n  char a[28] = \"000000000000000000000000000\", temp[27];\r\n  int len = strlen(x);\r\n  strncpy(temp, str, len);\r\n  strncpy(str, a, len);\r\n  for (int i = 0; y[i] != '\\0'; i++)\r\n    if (y[i] != '0' && y[i] != '1') return 0;\r\n\r\n  strncpy(str, temp, len);\r\n  return 1;\r\n}\r\n\r\nint main() {\r\n  long long x, y;\r\n  scanf(\"%\"PRId64\"%\"PRId64\"\", &x, &y);\r\n  char *permX = gen(x), *permY = gen(y);\r\n  int found = check(permY, permX);\r\n  found |= check(permY, permX+1);\r\n  permX = reverse(permX);\r\n  found |= check(permY, permX);\r\n  puts(found ? \"YES\" : \"NO\");\r\n\r\n  return 0;\r\n}\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e105740d6b4461f852a3efe11e3581c3", "src_uid": "9f39a3c160087beb0efab2e3cb510e89", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nlong long K=998244353;\n\nlong long min(long long a, long long b){\n    if(a > b)\n        return b;\n    return a;\n}\n\nlong long pmod(long long a, long long n, long long b){\n    long long c = 1, i, pows[40], prod;\n\n    prod = 1;\n    pows[0]=a;\n\n    for( i =1; i < 40; i++ )\n        pows[i] = (pows[i-1] * pows[i-1])%b;\n    \n    i = 0;\n    while(n > 0){\n        if( n % 2 == 1)\n            prod = (prod*pows[i])%b;\n\n        n=n/2;\n        i++;\n    }\n    return prod % b;\n}\n\nlong long binom(long long n, long long k){\n    long long prod1, i, prod2;\n    k = min(k, n-k);\n    prod1 = 1;\n    prod2 = 1;\n    for( i =  1; i <= k; i++ ) {\n        prod1 = (prod1 * i)%K;\n        prod2 = (prod2 * (i + n-k ) )%K;\n    }\n    return (prod2 * pmod(prod1, K-2, K)) % K;\n}\n\n\n\nvoid solve(int n, int k){\n    long long sum, i;\n    if( k > n ){\n        printf(\"0\\n\");\n        return;\n    }\n    if( k == n ){\n        printf(\"1\\n\");\n        return;\n    }\n    if( k == 1 ){\n        printf(\"%lld\\n\", n% K);\n        return;\n    }\n    sum = binom(n-1,k-1 )%K;\n    for( i = 2; i <= n/k; i++ )\n        sum = (sum + binom(n/i - 1, k-1))%K;\n\n    printf(\"%lld\\n\", sum % K );\n}\n\n\n\nint main(){\n    long long n, k;\n    scanf(\"%lld\", &n);\n    scanf(\"%lld\", &k);\n    solve(n,k);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "130a0d0a0b94a28fffe15347c4885fdc", "src_uid": "8e8eb64a047cb970a549ee870c3d280d", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nlong long int fact[500005];\nlong long int modpow(long long int a, long long int n, long long int p)\n{\n\tlong long int res = 1;\n\twhile (n > 0)\n\t{\n\t\tif (n % 2 > 0)\n\t\t\tres = res * a % p;\n\t\ta = a * a % p;\n\t\tn /= 2;\n\t}\n\treturn res;\n}\nlong long int comb(long long int n, long long int r, long long int p)\n{\n\tlong long int res = fact[n];\n\tres = res * modpow(fact[r], p - 2, p) % p;\n\tres = res * modpow(fact[n - r], p - 2, p) % p;\n\treturn res;\n}\nint main()\n{\n\tlong long int n, k;\n\tscanf(\"%lld %lld\", &n, &k);\n\tlong long int p = 998244353;\n\tlong long int ans = 0;\n\tlong long int i;\n\tfact[0] = 1;\n\tfor (i = 1; i <= n; i++)\n\t\tfact[i] = fact[i - 1] * i % p;\n\tfor (i = 1; n / i >= k; i++)\n\t\tans = (ans + comb(n / i - 1, k - 1, p)) % p;\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c35202318ac6cdf9dc6a7f5622be896d", "src_uid": "8e8eb64a047cb970a549ee870c3d280d", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include \"stdbool.h\"\n#include \"stdio.h\"\n#include \"stdint.h\"\n#include \"string.h\"\n#include \"ctype.h\"\n#include \"stdlib.h\"\n#include \"math.h\"\n\n#define PI 3.14159265358979323846264338327950288\n#define ll long long\n#define MOD 998244353\n#define N 500100\n#define MAX1 101\n#define rep(i,n) for (int i=0; i<n; i++)\n#define mul(a,b) ((a*b) % MOD)\n\nint max(int a,int b) {return a>b?a:b;}\nint min(int a,int b) {return a<b?a:b;}\nll minl(ll a,ll b) {return a<b?a:b;}\nll maxl(ll a,ll b) {return a>b?a:b;}\n\nint t, n, m;\nll a[N], b[N];\n\nll _pow(int i, int p) {\n\n    ll ans = 1, x = i;\n    for (; p; p>>=1) {\n        if (p&1) ans = mul(ans, x);\n        x = mul(x, x);\n    }\n    return ans;\n}\n\nint main() {\n    scanf(\"%d%d\", &n, &m);\n    a[0] = b[0] = 1;\n    for (int i=1; i<=n; i++) {\n        a[i] = mul(a[i-1], i);\n        b[i] = mul(b[i-1], _pow(i,MOD-2));\n    }\n    ll ans = 0;\n    for (int i=1; n/i>=m; i++) {\n        ans += mul(mul(a[n / i - 1], b[m - 1]), b[n / i - m]);\n        if (ans >= MOD) ans -= MOD;\n    }\n    printf(\"%lld\", ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "937eb82355e9c6e72b8e7e026b32071f", "src_uid": "8e8eb64a047cb970a549ee870c3d280d", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define mod 1000000007\n\nint f[1001],c[1001][1001],r1[1001],r2[2001];\n\nint mi(int a,long long b)\n{\n   int t;\n   if (!b)\n      return 1;\n   t=mi(a,b>>1);\n   t=(long long)t*t%mod;\n   if (b&1)\n      t=(long long)t*a%mod;\n   return t;\n}\n\nint main()\n{\n   int i,j,n,m,k,x,s=0,t=1;\n   scanf(\"%d%d%d\",&n,&m,&k);\n   if (m==1)\n      s=mi(k,n);\n   else\n   {\n      for (i=0;i<=n;i++)\n      {\n         c[i][0]=1;\n         for (j=1;j<=i;j++)\n            c[i][j]=(c[i-1][j-1]+c[i-1][j])%mod;\n      }\n      for (i=1;i<=n;i++)\n      {\n         f[i]=mi(i,n);\n         for (j=1;j<i;j++)\n            f[i]=(f[i]-(long long)f[j]*c[i][j]%mod+mod)%mod;\n      }\n      r1[0]=r2[0]=1;\n      for (i=1;i<=n;i++)\n         r1[i]=(long long)r1[i-1]*mi(i,mod-2)%mod;\n      for (i=1;i<=2*n&&i<=k;i++)\n         r2[i]=(long long)r2[i-1]*(k-i+1)%mod;\n      for (i=0;i<=n;i++)\n      {\n         x=mi(i,(long long)(m-2)*n);\n         for (j=0;i+j<=n&&i+2*j<=k;j++)\n            s=(s+(long long)r2[2*j+i]*r1[j]%mod*r1[j]%mod*r1[i]%mod*f[i+j]%mod*f[i+j]%mod*x)%mod;\n      }\n   }\n   printf(\"%d\\n\",s);\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f1f6e7c7ad641b9cd11fc5c898c5980b", "src_uid": "f22f28e2d8933f4199ba5ccfc0de8cda", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define N 1002\n#define MOD 1000000007\n\ntypedef long long typec;\n\nint n, m, k;\ntypec ftable[N];\ntypec facmod[1000001];\n\ntypec extend_gcd(typec a, typec b, typec *x, typec *y)\n{\n\tif(!b) return *x = 1, *y = 0, a;\n\ttypec res = extend_gcd(b, a % b, x, y), tmp = *x;\n\t*x = *y, *y = tmp - (a / b) * (*y);\n\treturn res;\n}\n\ntypec inverse(typec a, typec m)\n{\n\ttypec x, y;\n\ty = extend_gcd(a, m, &x, &y);\n\twhile(x < 0) x += m;\n\treturn x;\n}\n\ntypec pow_mod(typec x, typec k, typec m)\n{\n\ttypec res = 1;\n\twhile(x %= m, k) {\n\t\tif(k&1) res *= x, res %= m;\n\t\tx *= x, k >>= 1;\n\t}\n\treturn res;\n}\n\nint mymin(int x, int y)\n{\n\treturn x < y? x : y;\n}\n\ntypec combines(int i, int j)\n{\n\tif(i < j) return 0;\n\treturn facmod[i] * inverse(facmod[j], MOD) % MOD * inverse(facmod[i - j], MOD) % MOD;\n}\n\nvoid init()\n{\n\tint i, j;\n\tfacmod[0] = 1;\n\tfor(i = 1; i <= 1000000; i++) {\n\t\tfacmod[i] = facmod[i - 1] * i;\n\t\tfacmod[i] %= MOD;\n\t}\n\ttypec sum = 0;\n\tftable[1] = 1;\n\tfor(i = 2; i <= n; i++) {\n\t\tftable[i] = pow_mod(i, n, MOD) + MOD;\t\t\n\t\tsum = 0;\n\t\tfor(j = 1; j < i; j++) {\n\t\t\tsum += combines(i, j) * ftable[j] % MOD;\n\t\t\tsum %= MOD;\n\t\t}\n\t\tftable[i] -= sum;\n\t\tftable[i] %= MOD;\n\t}\n}\n\n\ntypec calc()\n{\n\tint i, j, m1, m2;\n\ttypec res = 0, tmp, stmp;\n\tm1 = mymin(n, k);\n\tfor(i = 0; i <= m1; i++) {\n\t\ttmp = combines(k, i) * pow_mod(i, (m - 2) * n, MOD) % MOD;\n\t\tm2 = mymin(n - i, (k - i) / 2);\n\t\tstmp = 0;\n\t\tfor(j = 0; j <= m2; j++) {\n\t\t\tif(!i && !j) continue;\n\t\t\tstmp += combines(k - i, j) * combines(k - i - j, j) % MOD * ftable[i + j] % MOD * ftable[i + j] % MOD;\n\t\t\tstmp %= MOD;\n\t\t}\n\t\tres += tmp * stmp % MOD;\n\t\tres %= MOD;\n\t}\n\treturn res;\n}\nint main()\n{\n\tscanf(\"%d%d%d\", &n, &m, &k);\n\tif(m == 1) {\n\t\tprintf(\"%d\\n\", (int)pow_mod(k, n, MOD));\n\t\treturn 0;\n\t}\n\tinit();\n\tprintf(\"%d\\n\", (int)calc());\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2651a50ccb3237f38e2131306c7da0ae", "src_uid": "f22f28e2d8933f4199ba5ccfc0de8cda", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\n#define N\t1000\n#define K\t1000000\n#define MD\t1000000007\n\nlong long power(int a, int k) {\n\tlong long p;\n\n\tif (k == 0)\n\t\treturn 1;\n\tp = power(a, k / 2);\n\tp = p * p % MD;\n\tif (k % 2)\n\t\tp = p * a % MD;\n\treturn p;\n}\n\nint main() {\n\tstatic int dp[N + 1], ff[K + 1], gg[K + 1];\n\tint n, m, k, i, c, a;\n\tlong long f, ans;\n\n\tscanf(\"%d%d%d\", &n, &m, &k);\n\tif (m == 1) {\n\t\tprintf(\"%lld\\n\", power(k, n));\n\t\treturn 0;\n\t}\n\tdp[0] = 1;\n\tfor (i = 0; i < n; i++) {\n\t\tfor (c = n; c >= 1; c--)\n\t\t\tdp[c] = (long long) (dp[c] + dp[c - 1]) * c % MD;\n\t\tdp[0] = 0;\n\t}\n\tf = 1;\n\tfor (i = 0; i <= k; i++) {\n\t\tgg[i] = power(ff[i] = f, MD - 2);\n\t\tf = f * (i + 1) % MD;\n\t}\n\tans = 0;\n\tfor (c = m == 2 ? 0 : 1; c <= n && c <= k; c++)\n\t\tfor (a = 0; a + c <= n && a + a + c <= k; a++) {\n\t\t\tlong long cnt = (long long) ff[k] * gg[a] % MD * gg[a] % MD * gg[c] % MD\n\t\t\t\t* gg[k - a - a - c] % MD * dp[a + c] % MD * dp[a + c] % MD;\n\n\t\t\tif (m > 2)\n\t\t\t\tcnt = cnt * power(c, (m - 2) * n) % MD;\n\t\t\tans += cnt;\n\t\t}\n\tans %= MD;\n\tif (ans < 0)\n\t\tans += MD;\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b48a20da8b225eea86927f521c47bf8b", "src_uid": "f22f28e2d8933f4199ba5ccfc0de8cda", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\n#define N\t1000\n#define K\t1000000\n#define MD\t1000000007\n\nlong long power(int a, int k) {\n\tlong long p;\n\n\tif (k == 0)\n\t\treturn 1;\n\tp = power(a, k / 2);\n\tp = p * p % MD;\n\tif (k % 2)\n\t\tp = p * a % MD;\n\treturn p;\n}\n\nint main() {\n\tstatic int dp[N + 1], ff[K + 1], gg[K + 1];\n\tint n, m, k, i, c, a;\n\tlong long f, ans;\n\n\tscanf(\"%d%d%d\", &n, &m, &k);\n\tif (m == 1) {\n\t\tprintf(\"%lld\\n\", power(k, n));\n\t\treturn 0;\n\t}\n\tdp[0] = 1;\n\tfor (i = 0; i < n; i++) {\n\t\tfor (c = n; c >= 1; c--)\n\t\t\tdp[c] = (long long) (dp[c] + dp[c - 1]) * c % MD;\n\t\tdp[0] = 0;\n\t}\n\tf = 1;\n\tfor (i = 0; i <= k; i++) {\n\t\tgg[i] = power(ff[i] = f, MD - 2);\n\t\tf = f * (i + 1) % MD;\n\t}\n\tans = 0;\n\tfor (c = m == 2 ? 0 : 1; c <= n && c <= k; c++)\n\t\tfor (a = 0; a + c <= n && a + a + c <= k; a++) {\n\t\t\tlong long cnt = (long long) ff[k] * gg[a] % MD * gg[a] % MD * gg[c] % MD\n\t\t\t\t* gg[k - a - a - c] * dp[a + c] % MD * dp[a + c] % MD;\n\n\t\t\tif (m > 2)\n\t\t\t\tcnt = cnt * power(c, (m - 2) * n) % MD;\n\t\t\tans += cnt;\n\t\t}\n\tans %= MD;\n\tif (ans < 0)\n\t\tans += MD;\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "924d1922e5b95fb7e6f6ecba5ad7f04a", "src_uid": "f22f28e2d8933f4199ba5ccfc0de8cda", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define N 1002\n#define MOD 1000000007\n\ntypedef long long typec;\n\nint n, m, k;\ntypec ftable[N];\ntypec facmod[1000001];\n\ntypec extend_gcd(typec a, typec b, typec *x, typec *y)\n{\n\tif(!b) return *x = 1, *y = 0, a;\n\ttypec res = extend_gcd(b, a % b, x, y), tmp = *x;\n\t*x = *y, *y = tmp - (a / b) * (*y);\n\treturn res;\n}\n\ntypec inverse(typec a, typec m)\n{\n\ttypec x, y;\n\ty = extend_gcd(a, m, &x, &y);\n\twhile(x < 0) x += m;\n\treturn x;\n}\n\ntypec pow_mod(typec x, typec k, typec m)\n{\n\ttypec res = 1;\n\twhile(x %= m, k) {\n\t\tif(k&1) res *= x, res %= m;\n\t\tx *= x, k >>= 1;\n\t}\n\treturn res;\n}\n\nint mymin(int x, int y)\n{\n\treturn x < y? x : y;\n}\n\ntypec combines(int i, int j)\n{\n\tif(i < j) return 0;\n\treturn facmod[i] * inverse(facmod[j], MOD) % MOD * inverse(facmod[i - j], MOD) % MOD;\n}\n\nvoid init()\n{\n\tint i, j;\n\tfacmod[0] = 1;\n\tfor(i = 1; i <= 1000000; i++) {\n\t\tfacmod[i] = facmod[i - 1] * i;\n\t\tfacmod[i] %= MOD;\n\t}\n\ttypec sum = 0;\n\tftable[1] = 1;\n\tfor(i = 2; i <= n; i++) {\n\t\tftable[i] = pow_mod(i, n, MOD) + MOD;\t\t\n\t\tsum = 0;\n\t\tfor(j = 1; j < i; j++) {\n\t\t\tsum += combines(i, j) * ftable[j] % MOD;\n\t\t\tsum %= MOD;\n\t\t}\n\t\tftable[i] -= sum;\n\t\tftable[i] %= MOD;\n\t}\n}\n\n\ntypec calc()\n{\n\tint i, j, m1, m2;\n\ttypec res = 0, tmp, stmp;\n\tm1 = mymin(n, k);\n\tfor(i = 0; i <= m1; i++) {\n\t\ttmp = combines(k, i) * pow_mod(i, (m - 2) * n, MOD) % MOD;\n\t\tm2 = mymin(n - i, (k - i) / 2);\n\t\tstmp = 0;\n\t\tfor(j = 0; j <= m2; j++) {\n\t\t\tif(!i && !j) continue;\n\t\t\tstmp += combines(k - i, j) * combines(k - i - j, j) % MOD * ftable[i + j] % MOD * ftable[i + j] % MOD;\n\t\t\tstmp %= MOD;\n\t\t}\n\t\tres += tmp * stmp % MOD;\n\t\tres %= MOD;\n\t}\n\treturn res;\n}\nint main()\n{\n\tscanf(\"%d%d%d\", &n, &m, &k);\n\tinit();\n\tprintf(\"%lld\\n\", calc());\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f3725ada2d420aaf73e38b7afed531a7", "src_uid": "f22f28e2d8933f4199ba5ccfc0de8cda", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n,w[105]={},W,i,j,t;\n\tscanf(\"%d\",&n);\n\tn*=2;\n\tfor (i=0;i<n;i++)\n\t\tscanf(\"%d\",&w[i]);\n\tfor (i=0;i<n-1;i++)\n\t\tfor (j=0;j<n-i-1;j++)\n\t\t\tif (w[j]>w[j+1])\n\t\t\t{\n\t\t\t\tt=w[j];\n\t\t\t\tw[j]=w[j+1];\n\t\t\t\tw[j+1]=t;\n\t\t\t}\n\tint copy[105]={};\n\tvoid cp(int wo1,int wo2)\n\t{\n\t\tint k;\n\t\tfor (k=0;k<n;k++)\n\t\t\tif (k!=wo1&&k!=wo2)\n\t\t\t\tcopy[k]=w[k];\n\t\t\telse\n\t\t\t\tcopy[k]=-1;\n\t}\n\tint sumup()\n\t{\n\t\tint last=-1;\n\t\tint s=0,k;\n\t\tfor (k=0;k<n;k++)\n\t\t\tif (copy[k]!=-1)\n\t\t\t\tif (last==-1)\n\t\t\t\t\tlast=copy[k];\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\ts+=copy[k]-last;\n\t\t\t\t\tlast=-1;\n\t\t\t\t}\n\t\treturn s;\n\t}\n\tint min=999999999,temp;\n\tfor (i=0;i<n;i++)\n\t\tfor (j=i;j<n;j++)\n\t\t\tif (i!=j)\n\t\t\t{\n\t\t\t\tcp(i,j);\n\t\t\t\ttemp=sumup();\n\t\t\t\tif (temp<min)\n\t\t\t\t\tmin=temp;\n\t\t\t}\n\tprintf(\"%d\\n\",min);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3e2bde8ee0c6b84d3ceb4378134b9402", "src_uid": "76659c0b7134416452585c391daadb16", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#define INF 1000000007\nint cmp(const void * a, const void * b) {\n    return *(int *)a - *(int *)b;\n}\nint main() {\n    int n;\n    int s[105];\n    scanf(\"%d\", &n);\n\n    for (int i = 0; i < 2 * n; i++)\n        scanf(\"%d\", s + i);\n    qsort(s, 2 * n, sizeof(int), cmp);\n    int ans = INF;\n    for (int i = 0; i < 2 * n - 1; i++) {\n        for (int j = i + 1; j < 2 * n; j++) {\n            int m = 0;\n            int mid = 0;\n            int a, b;\n            while (1) {\n                a = m++;\n                while (a == i || a == j)\n                    a = m++;\n                b = m++;\n                while (b == i || b == j)\n                    b = m++;\n                if (m > 2 * n)\n                    break;\n                mid += s[b] - s[a];\n            }\n            if (ans > mid)\n                ans = mid;\n        }\n    }\n    printf(\"%d\\n\", ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "34714bb95730a2f2360f65975db211eb", "src_uid": "76659c0b7134416452585c391daadb16", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint compare(const void *a, const void *b)\n{\n    if (*(long *)a < *(long *)b)\n        return -1;\n    else\n        return 1;\n}\nint main()\n{\n    long n,i,a[50],j,bit=1e9+7,k;\n    scanf(\"%ld\",&n);\n    for(i=0;i<2*n;i++)\n        scanf(\"%ld\",&a[i]);\n    qsort(a,2*n,sizeof(long),compare);\n    for(i=0;i<2*n;i++)\n        for(j=i+1;j<2*n;j++)\n        {\n            k=0;\n            long temp=0,z=0;\n            for(z=1;z<=n-1;z++)\n            {\n                while(k==i || k==j)\n                    k++;\n                temp-=a[k];\n                k++;\n                while(k==i || k==j)\n                    k++;\n                temp+=a[k];\n                k++;\n            }\n            if(temp<bit)\n                bit=temp;\n        }\n    printf(\"%ld\\n\",bit);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4300d551119527ca04811524523e06ce", "src_uid": "76659c0b7134416452585c391daadb16", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint compare(const void *a, const void *b)\n{\n    if (*(long *)a < *(long *)b)\n        return -1;\n    else\n        return 1;\n}\nint main()\n{\n    long n,i,a[50],j,bit=200000007,k,N,u;\n    scanf(\"%ld\",&n);\n    N=2*n;\n    u=n-1;\n    for(i=1;i<=N;i++)\n        scanf(\"%ld\",&a[i]);\n    qsort(a+1,N,sizeof(long),compare);\n    for(i=1;i<N;i++)\n        for(j=i+1;j<=N;j++)\n        {\n            k=1;\n            long temp=0,z;\n            for(z=1;z<=u;z++)\n            {\n                while(k==i || k==j)\n                    k++;\n                temp-=a[k];\n                k++;\n                while(k==i || k==j)\n                    k++;\n                temp+=a[k];\n                k++;\n            }\n            if(temp<bit)\n                bit=temp;\n        }\n    printf(\"%ld\\n\",bit);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d26847a50b9b9770fe1ceb197a637588", "src_uid": "76659c0b7134416452585c391daadb16", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint compare(const void *a, const void *b)\n{\n    if (*(long *)a < *(long *)b)\n        return -1;\n    else\n        return 1;\n}\nint main()\n{\n    long n,i,a[50],j,bit=200000007,k,N,u,temp,z;\n    scanf(\"%ld\",&n);\n    N=2*n;\n    u=n-1;\n    for(i=1;i<=N;i++)\n        scanf(\"%ld\",&a[i]);\n    qsort(a+1,N,sizeof(long),compare);\n    for(i=1;i<N;i++)\n        for(j=i+1;j<=N;j++)\n        {\n            k=1;\n            temp=0;\n            z=0;\n            for(z=1;z<=u;z++)\n            {\n                while(k==i || k==j)\n                    k++;\n                temp-=a[k];\n                k++;\n                while(k==i || k==j)\n                    k++;\n                temp+=a[k];\n                k++;\n            }\n            if(temp<bit)\n                bit=temp;\n        }\n    printf(\"%ld\\n\",bit);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7177e69e71a7d3738ea29cea791cf060", "src_uid": "76659c0b7134416452585c391daadb16", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint n,k,b[233333],r[233333],o[233333],w[233333],rn,on,wn;\nchar s[233333];\n\nint comp(const void* a,const void* b) {\n\tint arg1=*(int*)(a);\n\tint arg2=*(int*)(b);\n\tif(arg1 < arg2) return -1;\n\tif(arg1 > arg2) return 1;\n    return 0;\n}\n\nvoid wqsb() {\n\tputs(\"-1\");\n\texit(0);\n}\n\nint main() {\n\t//freopen(\"in.txt\",\"r\",stdin);\n\t//freopen(\"out.txt\",\"w\",stdout);\n\t\n\tscanf(\"%d%d\",&n,&k);\n\tfor(int i=1;i<=n;++i) {\n\t\tscanf(\"%d\",&b[i]);\n\t}\n\tscanf(\"%s\",s+1);\n\tfor(int i=1;i<=n;++i) {\n\t\tif(s[i]=='R') r[++rn]=b[i];\n\t\telse if(s[i]=='O') o[++on]=b[i];\n\t\telse if(s[i]=='W') w[++wn]=b[i];\n\t}\n\tif(on==0||k==1||rn+wn==0) wqsb();\n\tif((rn+on<k)&&(wn+on<k)) wqsb();\n\tqsort(r+1,rn,sizeof(int),comp);\n\tqsort(o+1,on,sizeof(int),comp);\n\tqsort(w+1,wn,sizeof(int),comp);\n\t/*for(int cnt=1;cnt<=rn;++cnt) {printf(\"%d \",r[cnt]);}puts(\"\");\n\tfor(int cnt=1;cnt<=on;++cnt) {printf(\"%d \",o[cnt]);}puts(\"\");\n\tfor(int cnt=1;cnt<=wn;++cnt) {printf(\"%d \",w[cnt]);}puts(\"\");*/\n\tint ans=0,tmp=0,oo=on;\n\tif(rn+oo>=k) {\n\t\tfor(int cnt=1;cnt<=k;++cnt) {\n\t\t\tif((r[rn]>o[on]&&rn)||!on) ans+=r[rn--];\n\t\t\telse ans+=o[on--];\n\t\t}\n\t}\n\tif(wn+oo>=k) {\n\t\ton=oo;\n\t\tfor(int cnt=1;cnt<=k;++cnt) {\n\t\t\tif((w[wn]>o[on]&&wn)||!on) tmp+=w[wn--];\n\t\t\telse tmp+=o[on--];\n\t\t}\n\t}\n\tif(tmp>ans) ans=tmp;\n\tprintf(\"%d\\n\",ans);\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b3a6874b1c1574f47535785105ee8887", "src_uid": "104cf5253e027929f257364b3874c38b", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint n,k,b[233333],r[233333],o[233333],w[233333],rn,on,wn;\nchar s[233333];\n\nint comp(const void* a,const void* b) {\n\tint arg1=*(int*)(a);\n\tint arg2=*(int*)(b);\n\tif(arg1 < arg2) return -1;\n\tif(arg1 > arg2) return 1;\n    return 0;\n}\n\nint main() {\n\t//freopen(\"in.txt\",\"r\",stdin);\n\t//freopen(\"out.txt\",\"w\",stdout);\n\t\n\tscanf(\"%d%d\",&n,&k);\n\tfor(int i=1;i<=n;++i) {\n\t\tscanf(\"%d\",&b[i]);\n\t}\n\tscanf(\"%s\",s+1);\n\tfor(int i=1;i<=n;++i) {\n\t\tif(s[i]=='R') r[++rn]=b[i];\n\t\telse if(s[i]=='O') o[++on]=b[i];\n\t\telse if(s[i]=='W') w[++wn]=b[i];\n\t}\n\tif(on==0) {\n\t\tputs(\"-1\");\n\t\treturn 0;\n\t}\n\tif(rn==0&&wn==0) {\n\t\tputs(\"-1\");\n\t\treturn 0;\n\t}\n\tqsort(r,rn,sizeof(int),comp);\n\tqsort(o,on,sizeof(int),comp);\n\tqsort(w,wn,sizeof(int),comp);\n\tint ans=0,tmp=0,oo=on;\n\tif(rn+on>=k) {\n\t\tfor(int cnt=1;cnt<=k;++cnt) {\n\t\t\tif(r[rn]>o[on]&&rn) ans+=r[rn--];\n\t\t\telse ans+=o[on--];\n\t\t}\n\t}\n\telse if(wn+on>=k) {\n\t\ton=oo;\n\t\tfor(int cnt=1;cnt<=k;++cnt) {\n\t\t\tif(w[wn]>o[on]&&wn) tmp+=w[wn--];\n\t\t\telse tmp+=o[on--];\n\t\t}\n\t}\n\telse {puts(\"-1\"); return 0;}\n\tif(tmp>ans) ans=tmp;\n\tprintf(\"%d\\n\",ans);\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6f81857c715d19eee61bb32b0a7e31e7", "src_uid": "104cf5253e027929f257364b3874c38b", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define N 202002\nint v[N];\nint ty[3][N];\nint mk[N];\nint main(){\n    int n, k;\n    scanf(\"%d %d\", &n, &k);\n    for(int e = 0;e  < n; e++) scanf(\"%d\", v + e);\n    for(int e = 0; e < n; e++){\n        char c;\n        scanf(\" %c\", &c);\n        if(c == 'W') ty[0][v[e]]++;\n        if(c == 'O') ty[1][v[e]]++;\n        if(c == 'R') ty[2][v[e]]++;\n    }\n    // red with withe is bad\n    int res = -1;\n    for(int e = 0; e < 3; e++){\n        for(int f = e + 1; f < 3; f++){\n            if(e == 0 && f == 2) continue;\n            int tk0 = 0, tk1 = 0, sum = 0;\n            for(int g = N-1; g >= 0; g--){\n                int cp = ty[e][g];\n                while(tk0 < k - 1 && tk0 + tk1 < k && cp > 0){\n                    cp--;\n                    tk0++;\n                    sum += g;\n                }\n                cp = ty[f][g];\n                while(tk1 < k - 1 && tk0 + tk1 < k && cp > 0){\n                    cp--;\n                    tk1++;\n                    sum += g;\n                }\n            }\n            if(tk0 + tk1 == k)\n                if(res < sum) res = sum;\n        }\n    }\n    printf(\"%d\\n\", res);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "da928207aafaf1f8fe3027828b47fa13", "src_uid": "104cf5253e027929f257364b3874c38b", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint n,k,b[233333],r[233333],o[233333],w[233333],rn,on,wn;\nchar s[233333];\n\nint comp(const void* a,const void* b) {\n\tint arg1=*(int*)(a);\n\tint arg2=*(int*)(b);\n\tif(arg1 < arg2) return -1;\n\tif(arg1 > arg2) return 1;\n    return 0;\n}\n\nvoid wqsb() {\n\tputs(\"-1\");\n\texit(0);\n}\n\nint main() {\n\t//freopen(\"in.txt\",\"r\",stdin);\n\t//freopen(\"out.txt\",\"w\",stdout);\n\t\n\tscanf(\"%d%d\",&n,&k);\n\tfor(int i=1;i<=n;++i) {\n\t\tscanf(\"%d\",&b[i]);\n\t}\n\tscanf(\"%s\",s+1);\n\tfor(int i=1;i<=n;++i) {\n\t\tif(s[i]=='R') r[++rn]=b[i];\n\t\telse if(s[i]=='O') o[++on]=b[i];\n\t\telse if(s[i]=='W') w[++wn]=b[i];\n\t}\n\tif(on==0||k==1||rn+wn==0) wqsb();\n\tif((rn+on<k)&&(wn+on<k)) wqsb();\n\tqsort(r+1,rn,sizeof(int),comp);\n\tqsort(o+1,on,sizeof(int),comp);\n\tqsort(w+1,wn,sizeof(int),comp);\n\t/*for(int cnt=1;cnt<=rn;++cnt) {printf(\"%d \",r[cnt]);}puts(\"\");\n\tfor(int cnt=1;cnt<=on;++cnt) {printf(\"%d \",o[cnt]);}puts(\"\");\n\tfor(int cnt=1;cnt<=wn;++cnt) {printf(\"%d \",w[cnt]);}puts(\"\");*/\n\tint ans=0,tmp=0,oo=on,ww=wn,rr=rn;\n\tif(rn+oo>=k) {\n\t\tfor(int cnt=1;cnt<k;++cnt) {\n\t\t\tif((r[rn]>o[on]&&rn)||!on) ans+=r[rn--];\n\t\t\telse ans+=o[on--];\n\t\t}\n\t\tif(rn==rr) ans+=r[rn--]; else if(on==oo) ans+=o[on--];\n\t\telse {\n\t\t\tif((r[rn]>o[on]&&rn)||!on) ans+=r[rn--];\n\t\t\telse ans+=o[on--];\n\t\t}\n\t}\n\tif(wn+oo>=k) {\n\t\ton=oo;\n\t\tfor(int cnt=1;cnt<k;++cnt) {\n\t\t\tif((w[wn]>o[on]&&wn)||!on) tmp+=w[wn--];\n\t\t\telse tmp+=o[on--];\n\t\t}\n\t\tif(wn==ww) tmp+=w[wn--]; else if(on==oo) tmp+=o[on--];\n\t\telse {\n\t\t\tif((w[wn]>o[on]&&wn)||!on) tmp+=w[wn--];\n\t\t\telse tmp+=o[on--];\n\t\t}\n\t}\n\tif(tmp>ans) ans=tmp;\n\tprintf(\"%d\\n\",ans);\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "94b0315ef35efbb9aa39af50635e5d1a", "src_uid": "104cf5253e027929f257364b3874c38b", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N 20200;\n\nint v[N];\nint ty[3][N];\nint mk[N];\n\nint main(){\n    int n, k;\n    scanf(\"%d %d\", &n, &k);\n    for(int e = 0;e  < n; e++) scanf(\"%d\", v + e);\n    for(int e = 0; e < n; e++){\n        char c;\n        scanf(\" %c\", &c);\n        if(c == 'W') ty[0][v[e]]++;\n        if(c == 'O') ty[1][v[e]]++;\n        if(c == 'R') ty[2][v[e]]++;\n    }\n    int res = -1;\n    for(int e = 0; e < 3; e++){\n        for(int f = e + 1; f < 3; f++){\n            if(e == 0 && f == 2) continue;\n            int tk0 = 0, tk1 = 0, sum = 0;\n            for(int g = N-1; g >= 0; g--){\n                int cp = ty[e][g];\n                while(tk0 < k - 1 && tk0 + tk1 < k && cp > 0){\n                    cp--;\n                    tk0++;\n                    sum += g;\n                }\n                cp = ty[f][g];\n                while(tk1 < k - 1 && tk0 + tk1 < k && cp > 0){\n                    cp--;\n                    tk1++;\n                    sum += g;\n                }\n            }\n            if(tk0 + tk1 == k)\n                if(res < sum) res = sum;\n        }\n    }\n    printf(\"%d\\n\", res);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ceedbb8798b4ee5a70a95a964d67c5a1", "src_uid": "104cf5253e027929f257364b3874c38b", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "int i,j,N,u[100001],D[100001],C[100001],r[100001],x,d;\nint main () {\n    scanf(\"%d\",&N);\n    for (i=3;i<=N;++i) {\n        for (j=2;2*i>=j*(j+1);++j) if ((i-j*(j+1)/2)%j==0) {\n            x=(i-j*(j+1)/2)/j,d=C[x+j]^C[x];\n            u[d]=i;\n            if (!r[i] && !d) r[i]=j;\n        }\n        while (u[D[i]]==i) ++D[i];\n        C[i]=C[i-1]^D[i];\n    }\n    if (!D[N]) puts(\"-1\");\n    else printf(\"%d\\n\",r[N]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cdbc00bf9fec2bedbe757f805843b6d4", "src_uid": "63262317ba572d78163c91b853c05506", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint g[100001], dp[100001];\nint a[50001][1000];\n\nint main()\n{\n     int n, i, j;\n\n     scanf(\"%d\", &n);\n\n     for (i = 0; i <= n; i++) dp[i] = -1;\n\n     for (i = 2; i <= (n + 1) / 2; i++) {\n\t  int sum = i, f;\n\n\t  for (j = 0; j < 1000; j++) {\n\t       if (a[i][j] == 0) break;\n\t  }\n\n\t  g[i] = f = j;\n\n\t  for (j = i - 1; j > 0; j--) {\n\t       sum += j;\n\n\t       f ^= g[j];\n\n\t       if (sum > n) break;\n\n\t       if (f < 1000 && sum <= (n + 1) / 2) a[sum][f] = 1;\n\n\t       if (f == 0) dp[sum] = i - j + 1;\n\t  }\n     }\n\n     printf(\"%d\\n\", dp[n]);\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0cfaf5584a4ab9693be74409752fcf38", "src_uid": "63262317ba572d78163c91b853c05506", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint grundy[100100], mini[100100];\n\nint solve(int n){\n  int i,j,k;\n  int m;\n  int up, down;\n  int chk[1000];\n  int fin = 0;\n\n  if(grundy[n]>=0) return grundy[n];\n  mini[n] = -1;\n\n  rep(i,1000) chk[i]=0;\n\n  for(k=2;;k++){\n    up = 2*n - k*k + k;\n    down = 2*k;\n\n    if(up < down) break;\n    if(up%down) continue;\n\n    m = 0;\n    up /= down;\n    rep(i,k) m ^= solve(up+i);\n    if(m<1000) chk[m] = 1;\n\n    if(m==0 && fin==0) fin=1, mini[n] = k;\n  }\n\n  rep(i,1000) if(chk[i]==0) break;\n  return grundy[n] = i;\n}\n\nint main(){\n  int i,j,k,l,m,n;\n\n  rep(i,100100) grundy[i] = -1;\n\n  while(scanf(\"%d\",&n)==1){\n    solve(n);\n    printf(\"%d\\n\",mini[n]);\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b598334e66005f0dc7f5b86e99194777", "src_uid": "63262317ba572d78163c91b853c05506", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint g[100001], dp[100001];\nint a[50001][1000];\n\nint main()\n{\n     int n, i, j;\n\n     scanf(\"%d\", &n);\n\n     for (i = 0; i <= n; i++) dp[i] = -1;\n\n     for (i = 2; i <= (n + 1) / 2; i++) {\n\t  int sum = i, f;\n\n\t  for (j = 0; j < 1000; j++) {\n\t       if (a[i][j] == 0) break;\n\t  }\n\n\t  g[i] = f = j;\n\n\t  for (j = i - 1; j > 0; j--) {\n\t       sum += j;\n\n\t       f ^= g[j];\n\n\t       if (sum > n) break;\n\n\t       if (f < 1000 && sum <= (n + 1) / 2) a[sum][f] = 1;\n\n\t       if (f == 0) dp[sum] = i - j + 1;\n\t  }\n     }\n\n     printf(\"%d\\n\", dp[n]);\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fe24b8a4450830b984f7a230a8bee203", "src_uid": "63262317ba572d78163c91b853c05506", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "int i,j,N,u[100001],D[100001],C[100001],r[100001],x,d;\nint main () {\n    scanf(\"%d\",&N);\n    for (i=3;i<=N;++i) {\n        for (j=2;2*i>=j*(j+1);++j) if ((i-j*(j+1)/2)%j==0) {\n            x=(i-j*(j+1)/2)/j,d=C[x+j]^C[x];\n            u[d]=i;\n            if (!r[i] && !d) r[i]=j;\n        }\n        while (u[D[i]]==i) ++D[i];\n        C[i]=C[i-1]^D[i];\n    }\n    if (!D[N]) puts(\"-1\");\n    else printf(\"%d\\n\",r[N]);\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7536d3b7c446e1d9ab588adb8137a3f7", "src_uid": "63262317ba572d78163c91b853c05506", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint n;\nint mi[10][10], mx[10][10], ac[10][10];\nint ind[10];\nint now[10];\n\nint res, res_cost;\n\nvoid solve(int a,int b,int cost){\n  int i,j,send;\n  int aa = ind[a], bb = ind[b];\n\n  if(a>=n){\n    if(now[n-1] < 0) return;\n    if(now[n-1] == res && cost > res_cost) res++;\n    if(now[n-1] < res) res = now[n-1], res_cost = cost;\n    return;\n  }\n\n  if(b>=n){\n    if(aa!=0 && aa!=n-1 && now[aa]) return;\n    solve(a+1,a+2,cost);\n    return;\n  }\n\n  REP(i,-mx[aa][bb],mx[aa][bb]+1){\n    if(-mi[aa][bb]<i && i<mi[aa][bb]) continue;\n    if( (bb-aa)*i < 0 ) continue;\n\n    send = cost;\n    if(i) send += ac[aa][bb];\n    send += i*i;\n\n    now[aa]-=i; now[bb]+=i;\n    solve(a,b+1,send);\n    now[aa]+=i; now[bb]-=i;\n  }\n}\n\nint main(){\n  int i,j,k,l,m;\n  int a,b,c;\n\n  while(scanf(\"%d\",&n)==1){\n    m = n*(n-1)/2;\n    while(m--){\n      scanf(\"%d%d%d%d%d\",&i,&j,&a,&b,&c); i--; j--;\n      mi[i][j] = mi[j][i] = a;\n      mx[i][j] = mx[j][i] = b;\n      ac[i][j] = ac[j][i] = c;\n    }\n    REP(i,1,n-1) ind[i-1] = i; ind[n-2]=0; ind[n-1]=n-1;\n    rep(i,n) now[i] = 0;\n\n    res = 1000000;\n\n    solve(0,1,0);\n\n    if(res == 1000000) res = res_cost = -1;\n    printf(\"%d %d\\n\",res, res_cost);\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8c618664a1a7800fc9c6eea9fed69c62", "src_uid": "38886ad7b0d83e66b77348be34828426", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint low[7][7], high[7][7];\nint cost[7][7];\nint n;\nint flow[7][7];\nint inFlow[7];\nint outFlow[7];\nint minFlow = 100, maxCost = -1;\n\nint rec(int v, int to) {\n    if(v == n - 1) {\n        int isValid = 1;\n        int i, j;\n        int total = inFlow[n - 1];\n        int ccost = 0;\n        for(i = 0; i < n; i++) {\n            for(j = i + 1; j < n; j++) {\n                if(flow[i][j] < low[i][j] || flow[i][j] > high[i][j])\n                    isValid = 0;\n                if(flow[i][j] > 0) \n                    ccost += flow[i][j] * flow[i][j] + cost[i][j];\n            }\n        }\n        if(isValid) {\n            if(minFlow == total) {\n                if(ccost > maxCost)\n                    maxCost = ccost;\n            } else if(minFlow > total) {\n                minFlow = total;\n                maxCost = ccost;\n            }\n        }\n    } else if(to == n) {\n        if(v > 0 && inFlow[v] != outFlow[v])\n            return;\n        if(inFlow[n - 1] > minFlow)\n            return;\n        rec(v + 1, v + 2);\n    } else {\n        int i;\n        for(i = low[v][to]; i <= high[v][to]; i++) {\n            inFlow[to] += i;\n            outFlow[v] += i;\n            flow[v][to] = i;\n            rec(v, to + 1);\n            inFlow[to] -= i;\n            outFlow[v] -= i;\n        }\n    }\n}\n\nint main() {\n    scanf(\"%d\", &n);\n    int i, from, to, j;\n    for(i = 0; i < n * (n - 1) / 2; i++) {\n        scanf(\"%d %d\", &from, &to);\n        from--;\n        to--;\n        scanf(\"%d %d %d\", &low[from][to], &high[from][to], &cost[from][to]);\n    }\n    rec(0, 1);\n    if(minFlow == 100)\n        puts(\"-1 -1\");\n    else\n        printf(\"%d %d\\n\", minFlow, maxCost);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c1a894996cc5af32d48608658d1e6bea", "src_uid": "38886ad7b0d83e66b77348be34828426", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\nint m,n;\t\nscanf(\"%d%d\",&m&n);\nreturn ((1+(n-1)*(m-1)/(n*m-1))/n);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "7f123faa336097ff034496352807125a", "src_uid": "0b9ce20c36e53d4702869660cbb53317", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main() {\n\tint n, m;\n\n\tscanf(\"%d%d\", &n, &m);\n\tprintf(\"%.12lf\\n\", n == 1 ? 1 : 1.0 / n\n\t\t\t+ (double) (n - 1) * (n - 1) / (n * m - 1) / n);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "292bcbe981626cf2429150f4936a586e", "src_uid": "0b9ce20c36e53d4702869660cbb53317", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\nint m,n;\nfloat res;\t\nscanf(\"%d%d\",&m,&n);\nres = (1+(n-1)*(m-1)/(n*m-1))/n;\nprintf(\"%f\",&res);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f383a444495f2dd6721c55a30daff535", "src_uid": "0b9ce20c36e53d4702869660cbb53317", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <Windows.h>\nint main()\n{\nfloat m,n,res;\t\nscanf(\"%f%f\",&m,&n);\nres = (1+(n-1)*(m-1)/(n*m-1))/n;\nprintf(\"%f\",res);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b3257dcc4daf4f5f23c0a1100955e4b0", "src_uid": "0b9ce20c36e53d4702869660cbb53317", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <Windows.h>\nint main()\n{\nfloat m,n,res;\t\nscanf(\"%f%f\",&m,&n);\nif (n==1) \n\tres = 1;\nelse\n\tres = (1+(n-1)*(m-1)/(n*m-1))/n;\nprintf(\"%f\",res);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "87a4b143f25ab12e6823f31c9cb61fb5", "src_uid": "0b9ce20c36e53d4702869660cbb53317", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N 1000001\n\n#define MIN(a,b) (((a)<(b))?(a):(b))\n#define MAX(a,b) (((a)>(b))?(a):(b))\n\n\n\nint main() {\n\tint biggest_prime[N];\n\tint n, i, j, k,sum = 0;\n\n\tscanf(\"%i\",&n);\n\n\tfor(i = 1; i <= n; i++) biggest_prime[i] = i;\n\n\tfor(i = 2; i <= n; i++){\n\t\tif(biggest_prime[i] != i) continue;\n\t\tfor(j = i*2; j <= n; j+=i) biggest_prime[j] = i;\n\t}\n\n\tk = biggest_prime[n];\n\n\tint min = n;\n\n\tfor(i = MAX(4,n-k+1); i <= n; i++){\n\t\tif(i == biggest_prime[i]) continue;\n\t\tmin = MIN(min, i-biggest_prime[i]);\n\t}\n\n\tprintf(\"%i\",min+1); //no se como funciono pero funciono\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "60fe2092086c7b6dc0aaf4fbc47be35c", "src_uid": "43ff6a223c68551eff793ba170110438", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <limits.h>\n\ntypedef long long ll;\ntypedef unsigned long long ull;\n\n#define REP(i, n) for((i) = 0; (i) < (n); (i)++)\n#define REP1(i, n) for((i) = 1; (i) <= (n); (i)++)\n\n#define SIZE 1000002\n\nstatic int s[SIZE], p[SIZE], np, min;\n\nstatic void sieve(void)\n{\n    int i, j;\n\n    for (i = 2; i < SIZE; i++) {\n        if (s[i] == 0) {\n            p[np++] = i;\n\n            for (j = 2; i * j < SIZE; j++) {\n                s[i * j] = 1;\n            }\n        }\n    }\n}\n\nstatic void solve(int x, int l)\n{\n    int i, d, lf = -1;\n\n    if (x < min) {\n        min = x;\n    }\n\n    if (l == 0) {\n        return;\n    }\n\n    for (i = 2; i * i <= x; i++) {\n        if (x % i == 0) {\n            if (s[x / i] == 0) {\n                if (x / i > lf) {\n                    lf = x / i;\n                }\n            } else if (s[i] == 0) {\n                if (i > lf) {\n                    lf = i;\n                }\n            }\n        }\n    }\n\n    if (lf == -1) {\n        return;\n    }\n\n    if (l == 1) {\n        if (lf * (x / lf - 1) + 1 < min) {\n            min = lf * (x / lf - 1) + 1;\n        }\n    } else {\n        for (d = lf * (x / lf - 1) + 1; d < x; d++) {\n            solve(d, l - 1);\n        }\n    }\n}\n\nint main(void)\n{\n    int x2;\n\n    sieve();\n    min = INT_MAX;\n\n    scanf(\"%d\", &x2);\n    solve(x2, 2);\n    printf(\"%d\", min);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5c1e3d835d37ff16bc5887b5e8b9f9d6", "src_uid": "43ff6a223c68551eff793ba170110438", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdlib.h>\n#include <stdio.h>\n\n#define MAX 10000000\n\nint p[MAX];\n\nvoid Findprimes(){\n    int n = 2;\n    int x;\n\n    while(n < MAX){\n        x = n * 2;\n        while(x < MAX){\n            p[x] = n;\n            x += n;\n        }\n        x = n + 1;\n        while(p[x] != 0 && x < MAX){\n            x++;\n        }\n        n = x;\n    }\n}\n\nint min(int a, int b){\n    if(a < b)\n        return a;\n    else\n        return b;\n}\n\nint main(){\n    int i;\n    int x0, x1, x2;\n\n    x0 = MAX;\n    scanf(\"%i%*c\", &x2);\n    Findprimes();\n    //printf(\"%i\\n\", p[x2]);\n\n    for(i = x2-p[x2]+1; i <= x2; i++){\n        //printf(\"i: %i\\n\", i);\n        x0 = min(i-p[i]+1, x0);\n        //printf(\"x0: %i\\n\", x0);\n    }\n\n    printf(\"%i\", x0);\n\n    /*for(i = 0; i < MAX; i++){\n        printf(\"%i \", p[i]);\n    }*/\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "24a64597a4231549b9f20cfa7b539434", "src_uid": "43ff6a223c68551eff793ba170110438", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint max_prime_div[1000001];\nbool sieve[1000001];\n\nint main(int argc, char **argv)\n{\n    int x2;\n    int tmp;\n    int max_div;\n    int min_x0 = 1000001;\n\n    scanf(\"%d\", &x2);\n    for (int i = 0; i < x2 + 1; ++i) {\n        max_prime_div[i] = 0;\n        sieve[i] = true;\n    }\n    \n    for (int i = 2; i < x2 + 1; ++i) {\n        if (sieve[i]) {\n            for (int j = 2 * i; j < x2 + 1; j += i) {\n                sieve[j] = false;\n                max_prime_div[j] = i;\n            }\n        }\n    }\n\n    for (int x = x2 - max_prime_div[x2] + 1; x < x2 + 1; ++x) {\n        max_div = max_prime_div[x];\n        tmp = x - max_div + 1;\n        if (max_div && tmp < min_x0) {\n            min_x0 = tmp;\n        }\n        if (max_div && tmp - 1 == max_div) {\n            break;\n        }\n    }\n    printf(\"%d\", min_x0);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "5c0fc3540928505a75b82123c31fca26", "src_uid": "43ff6a223c68551eff793ba170110438", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n#define size 1000000\n\n\nvoid llenaArr(int *primes){\n  int i,j;\n  for (i = 0; i < size; i++) {\n    primes[i]=0;\n  }\n\n  for (i = 2; i < size; i++)\n    if(!primes[i]){\n      for (j = 2; (i*j)<size; j++)\n          primes[i*j]=i;\n    }\n}\n\nint min(int x, int y){\n  if(x<y)\n    return x;\n  else\n    return y;\n}\n\nint main(){\n  int x2, i;\n  int x0=1000000;\n  scanf(\"%i\", &x2);\n  int primes[size];\n  llenaArr(primes);\n\n\n  i=x2-primes[x2]+1;\n  x0=min(x0,i);\n  for(;i<=x2;i++){\n    x0=min(x0, i-primes[i]+1);\n  }\n  printf(\"%i\\n\", x0);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "aa8598525239897d11b0074630fa49a0", "src_uid": "43ff6a223c68551eff793ba170110438", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t200\n\nint max(int a, int b) { return a > b ? a : b; }\n\nint main() {\n\tstatic char cc[N + 1], cc_[4];\n\tstatic int dp[N + 1][N + 1], dq[N + 1][N + 1];\n\tint n, m, i, j, k, ans;\n\n\tscanf(\"%d%d%s%s\", &n, &m, cc, cc_);\n\tfor (j = 0; j <= m; j++)\n\t\tmemset(dp, -1, (n + 1) * sizeof *dp);\n\tdp[0][0] = 0;\n\tfor (i = 0; i < n; i++) {\n\t\tfor (j = 0; j <= m; j++)\n\t\t\tmemset(dq, -1, (n + 1) * sizeof *dq);\n\t\tfor (j = 0; j <= m; j++)\n\t\t\tfor (k = 0; k <= n; k++) {\n\t\t\t\tint j_, k_, x = dp[j][k];\n\n\t\t\t\tif (x == -1)\n\t\t\t\t\tcontinue;\n\t\t\t\tj_ = j, k_ = k;\n\t\t\t\tif (cc[i] == cc_[0])\n\t\t\t\t\tk_++;\n\t\t\t\tdq[j_][k_] = max(dq[j_][k_], x + (cc[i] == cc_[1] ? k : 0));\n\t\t\t\tif (j < m) {\n\t\t\t\t\tj_ = j + 1, k_ = k + 1;\n\t\t\t\t\tdq[j_][k_] = max(dq[j_][k_], x + (cc_[0] == cc_[1] ? k : 0));\n\t\t\t\t\tif (cc_[0] != cc_[1]) {\n\t\t\t\t\t\tj_ = j + 1, k_ = k;\n\t\t\t\t\t\tdq[j_][k_] = max(dq[j_][k_], x + k);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\tfor (j = 0; j <= m; j++)\n\t\t\tmemcpy(dp, dq, (n + 1) * sizeof *dq);\n\t}\n\tans = -1;\n\tfor (j = 0; j <= m; j++)\n\t\tfor (k = 0; k <= n; k++)\n\t\t\tans = max(ans, dp[j][k]);\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d4f6d31ec8f6003c1b2d740fafd1787d", "src_uid": "9c700390ac13942cbde7c3428965b18a", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n\nint max(int a, int b) {\n    return a > b ? a : b;\n}\n\nint main() \n{\n    int n, k;\n    scanf(\"%d %d\", &n, &k);\n    char s[201], t[3];\n    scanf(\"%s %s\", s, t);\n    int dp[n+1][k+1][n+1];      // answer in the interval [1...i], using j moves, has t0 occurrences of t[0]\n    for(int i = 0; i <= n; i++) {\n        for(int j = 0; j <= k; j++) {\n            for(int t0 = 0; t0 <= n; t0++) {\n                dp[i][j][t0] = -1;\n            }\n        }\n    }\n    dp[0][0][0] = 0;\n    // initialize\n    for(int i = 1; i <= n; i++) {\n        for(int j = 0; j <= k; j++) {\n            for(int t0 = 0; t0 <= n; t0++) {\n                if(dp[i-1][j][t0] == -1) \n                    continue;\n\n                int is_equal_first_char = s[i-1] == t[0];\n                int is_equal_second_char = s[i-1] == t[1];      // asddsaf sd\n                int is_t_equal = t[0] == t[1];\n\n                // if we do not change the ith char\n                dp[i][j][t0 + is_equal_first_char] = max(dp[i][j][t0 + is_equal_first_char], dp[i - 1][j][t0] + (is_equal_second_char ? t0 : 0));\n                \n                // if we make any change (j must be < k)\n                if(j < k) {\n                    // if change s[i] to t[0]\n                    dp[i][j + 1][t0 + 1] = max(dp[i][j + 1][t0 + 1], dp[i - 1][j][t0] + (is_t_equal ? t0 : 0));\n                    // if change s[i] to t[1]\n                    // dp[i][j + 1][t0 + 1] = max(dp[i][j + 1][t0 + 1], dp[i][j][t0] + (!is_equal_second_char ? t0 : 0));\n                    dp[i][j + 1][t0] = max(dp[i][j + 1][t0], dp[i - 1][j][t0] + t0);\n                }\n            }\n        }\n    }\n    int ans = -1;\n    for(int j = 0; j <= k; j++) {\n        for(int t0 = 0; t0 <= n; t0++) {\n            ans = max(ans, dp[n][j][t0]);\n        }    \n    }\n    printf(\"%d\", ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e6e57f9603708d0e4ba8267e62c6f6e5", "src_uid": "9c700390ac13942cbde7c3428965b18a", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "//set many funcs template\n//Ver.20190820\n#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<stdbool.h>\n#include<time.h>\n#include<assert.h>\n#define inf 1072114514\n#define llinf 4154118101919364364\n#define mod 1000000007\n#define pi 3.1415926535897932384\n\nint max(int a,int b){if(a>b){return a;}return b;}\nint min(int a,int b){if(a<b){return a;}return b;}\nint zt(int a,int b){return max(a,b)-min(a,b);}\nint round(int a,int b){if((a%b)*2 >= b){return (a/b)+1;}return a/b;}\nint ceil(int a,int b){if(a%b==0){return a/b;}return (a/b)+1;}\nint gcd(int a,int b){int c;while(b!=0){c=a%b;a=b;b=c;}return a;}\nint lcm(int a,int b){int c=gcd(a,b);a/=c;return a*b;}\nint nCr(int a,int b){int i,r=1;for(i=1;i<=b;i++){r*=(a+1-i);r/=i;}return r;}\nint nHr(int a,int b){return nCr(a+b-1,b);}\nint fact(int a){int i,r=1;for(i=1;i<=a;i++){r*=i;}return r;}\nint pow(int a,int b){int i,r=1;for(i=1;i<=b;i++){r*=a;}return r;}\nint dsum(int x){int r=0;while(x){r+=(x%10);x/=10;}return r;}\nint dsumb(int x,int b){int r=0;while(x){r+=(x%b);x/=b;}return r;}\nint sankaku(int x){return ((1+x)*x)/2;}\nvoid swap(int *a,int *b){int c;c=(*a);(*a)=(*b);(*b)=c;}\nlong long llmax(long long a,long long b){if(a>b){return a;}return b;}\nlong long llmin(long long a,long long b){if(a<b){return a;}return b;}\nlong long llzt(long long a,long long b){return llmax(a,b)-llmin(a,b);}\nlong long llround(long long a,long long b){if((a%b)*2 >= b){return (a/b)+1;}return a/b;}\nlong long llceil(long long a,long long b){if(a%b==0){return a/b;}return (a/b)+1;}\nlong long llgcd(long long a,long long b){long long c;while(b!=0){c=a%b;a=b;b=c;}return a;}\nlong long lllcm(long long a,long long b){long long c=llgcd(a,b);a/=c;return a*b;}\nlong long llnCr(long long a,long long b){long long i,r=1;for(i=1;i<=b;i++){r*=(a+1-i);r/=i;}return r;}\nlong long llnHr(long long a,long long b){return llnCr(a+b-1,b);}\nlong long llfact(long long a){long long i,r=1;for(i=1;i<=a;i++){r*=i;}return r;}\nlong long llpow(long long a,long long b){long long i,r=1;for(i=1;i<=b;i++){r*=a;}return r;}\nlong long lldsum(long long x){long long r=0;while(x){r+=(x%10);x/=10;}return r;}\nlong long lldsumb(long long x,long long b){long long r=0;while(x){r+=(x%b);x/=b;}return r;}\nlong long llsankaku(long long x){return ((1+x)*x)/2;}\nvoid llswap(long long *a,long long *b){long long c;c=(*a);(*a)=(*b);(*b)=c;}\ndouble dbmax(double a,double b){if(a>b){return a;}return b;}\ndouble dbmin(double a,double b){if(a<b){return a;}return b;}\ndouble dbzt(double a,double b){return dbmax(a,b)-dbmin(a,b);}\nvoid dbswap(double *a,double *b){double c;c=(*a);(*a)=(*b);(*b)=c;}\nvoid chswap(char *a,char *b){char c;c=(*a);(*a)=(*b);(*b)=c;}\nint sortfncsj(const void *a,const void *b){if(*(int *)a>*(int *)b){return 1;}if(*(int *)a==*(int *)b){return 0;}return -1;}\nint sortfnckj(const void *a,const void *b){if(*(int *)a<*(int *)b){return 1;}if(*(int *)a==*(int *)b){return 0;}return -1;}\nint llsortfncsj(const void *a,const void *b){if(*(long long *)a>*(long long *)b){return 1;}if(*(long long *)a==*(long long *)b){return 0;}return -1;}\nint llsortfnckj(const void *a,const void *b){if(*(long long *)a<*(long long *)b){return 1;}if(*(long long *)a==*(long long *)b){return 0;}return -1;}\nint dbsortfncsj(const void *a,const void *b){if(*(double *)a>*(double *)b){return 1;}if(*(double *)a==*(double *)b){return 0;}return -1;}\nint dbsortfnckj(const void *a,const void *b){if(*(double *)a<*(double *)b){return 1;}if(*(double *)a==*(double *)b){return 0;}return -1;}\nint strsortfncsj(const void *a,const void *b){return strcmp((char *)a,(char *)b);}\nint strsortfnckj(const void *a,const void *b){return strcmp((char *)b,(char *)a);}\nint chsortfncsj(const void *a,const void *b){if(*(char *)a>*(char *)b){return 1;}if(*(char *)a==*(char *)b){return 0;}return -1;}\nint chsortfnckj(const void *a,const void *b){if(*(char *)a<*(char *)b){return 1;}if(*(char *)a==*(char *)b){return 0;}return -1;}\n\nvoid shuffledget(int x[],int n){\n    int i,b[524288],p,c;\n    for(i=0;i<n;i++){\n        b[i]=i;\n    }\n    for(i=n;i>=1;i--){\n        p=rand()%i;\n        c=b[i-1];b[i-1]=b[p];b[p]=c;\n    }\n    for(i=0;i<n;i++){\n        scanf(\"%d\",&x[b[i]]);\n    }\n}\n\nint dx4[4]={1,-1,0,0};\nint dy4[4]={0,0,1,-1};\nint dx8[8]={-1,-1,-1,0,0,1,1,1};\nint dy8[8]={-1,0,1,-1,1,-1,0,1};\n\nint search(int x,int a[],int n){\n    int st=0,fi=n-1,te;\n    while(st<=fi){\n        te=(st+fi)/2;\n        if(a[te]<x){st=te+1;}else{fi=te-1;}\n    }\n    return st;\n}\n\nvoid prarr(int arr[],int n){\n  int i;\n  for(i=0;i<n;i++){\n    if(i){printf(\" \");}\n    printf(\"%d\",arr[i]);\n  }\n  printf(\"\\n\");\n  return;\n}\n\nvoid getperm(int a[],int n){\n  int i,p;\n  for(i=0;i<n;i++){\n    a[i]=i;\n  }\n  for(i=n-1;i>=1;i--){\n    p=rand()%(i+1);\n    swap(&a[p],&a[i]);\n  }\n}\n\ntypedef struct{\nint val;\nint node;\n}sd;\n\nint sdsortfnc(const void *a,const void *b){\nif(((sd*)a)->val < ((sd*)b)->val){return -1;}\nif(((sd*)a)->val > ((sd*)b)->val){return 1;}\nreturn 0;\n}\n\nvoid coordinate_comp(int a[],int n){\n  int i,c=0;\n  sd dat[524288];\n  for(i=0;i<n;i++){\n    dat[i].val=a[i];\n    dat[i].node=i;\n  }\n  qsort(dat,n,sizeof(dat[0]),sdsortfnc);\n  a[dat[0].node]=c;\n  for(i=1;i<n;i++){\n    if(dat[i-1].val!=dat[i].val){c++;}\n    a[dat[i].node]=c;\n  }\n}\n\nint main(void){\n  int n,v;\n  char s[256],t[8];\n  scanf(\"%d%d\",&n,&v);\n  scanf(\"%s%s\",s,t);\n\n  if(t[0]==t[1]){\n    int cnt=0;\n    for(int i=0;i<n;i++){\n      if(s[i]==t[0]){cnt++;}\n    }\n    cnt+=v;\n    cnt=min(n,cnt);\n    printf(\"%d\\n\",nCr(cnt,2));\n    return 0;\n  }\n  //dp[pos][lrep][fir]={mxm}\n  int dp[256][256][256];\n  for(int i=0;i<256;i++){\n    for(int j=0;j<256;j++){\n      for(int k=0;k<256;k++){\n        dp[i][j][k]=-inf;\n      }\n    }\n  }\n  \n  dp[0][v][0]=0;\n  \n  for(int i=0;i<n;i++){\n    for(int j=0;j<=v;j++){\n      for(int k=0;k<=i;k++){\n        dp[i+1][j][k]=max(dp[i][j][k],dp[i+1][j][k]);\n        if(s[i]==t[0]){\n          dp[i+1][j][k+1]=max(dp[i][j][k],dp[i+1][j][k+1]);\n        }\n        else if(j!=0){\n          dp[i+1][j-1][k+1]=max(dp[i][j][k],dp[i+1][j-1][k+1]);\n        }\n        if(s[i]==t[1]){\n          dp[i+1][j][k]=max(dp[i][j][k]+k,dp[i+1][j][k]);\n        }\n        else if(j!=0){\n          dp[i+1][j-1][k]=max(dp[i][j][k]+k,dp[i+1][j-1][k]);\n        }\n      }\n    }\n  }\n  \n  int res=0;\n  for(int i=0;i<256;i++){\n    for(int j=0;j<256;j++){\n      res=max(res,dp[n][i][j]);\n    }\n  }\n  printf(\"%d\\n\",res);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "71fb8febbb8be1202cf55c40499c50ff", "src_uid": "9c700390ac13942cbde7c3428965b18a", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint n,k,dp[201][201][201];\nchar s[200],t[2];\nint min(int a,int b){\n    return a<b?a:b;\n}\nint max(int a,int b){\n    return a>b?a:b;\n}\nint simi(int n,int k){\n    int i,cnt=0;\n    for(i=0;i<n;i++)\n    {\n        if(s[i]==t[0]) cnt++;\n    }\n    cnt=min(n,cnt+k);\n    return cnt*(cnt-1)/2;\n    \n}\nint diff(int i,int remK,int first){\n    if(i==n) return 0;\n    if(dp[i][remK][first]!=-1) return dp[i][remK][first];\n    int ans=0;\n    if(!remK){\n        if(s[i]==t[1]) ans=first+diff(i+1,0,first);\n        else if(s[i]==t[0]) ans=diff(i+1,0,first+1);\n        else ans=diff(i+1,0,first);\n    }\n    else{\n        if(s[i]==t[0]){\n           int ans1,ans2;\n            ans1=diff(i+1,remK,first+1);\n            ans2=first+diff(i+1,remK-1,first);\n            ans=max(ans1,ans2);\n        }\n        else if(s[i]==t[1]){\n            int ans1,ans2;\n            ans1=first+diff(i+1,remK,first);\n            ans2=diff(i+1,remK-1,first+1);\n            ans=max(ans1,ans2);\n        }\n        else{\n            int ans1,ans2,ans3;\n            ans1=diff(i+1,remK,first);\n            ans2=diff(i+1,remK-1,first+1);\n            ans3=first+diff(i+1,remK-1,first);\n            ans=max(ans1,max(ans2,ans3));\n        }\n    }\n    return dp[i][remK][first] = ans;\n}\n\n/*int main(){\n    \n   scanf(\"%d %d\",&n,&k);\n   scanf(\"%c%s\",s);\n   scanf(\"%s\",t);\n   if(t[0]==t[1]){\n       printf(\"%d\\n\",simi(n,k));\n       return 0;\n   }\n   for(int i=0;i<n;i++) for(int j=0;j<=k;j++) for(int k=0;k<n;k++) dp[i][j][k]=-1;\n   printf(\"%d\\n\",diff(0,k,0));\n    return 0;\n}*/\nint main() {\n   scanf(\"%d %d\", &n, &k);\n   scanf(\"%s\",s);\n   scanf(\"%s\",t);\n\n    if(t[0] == t[1]) {            \n        printf(\"%d\\n\", simi(n,k));\n        return 0;\n    }\n\n    for(int i=0; i<n; i++) for(int j=0; j<=k; j++)\n        for(int k=0; k<n; k++) dp[i][j][k] = -1;\n\n    printf(\"%d\\n\", diff(0, k, 0));\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8a234a03ec3c73ab053ca7d9ea266b23", "src_uid": "9c700390ac13942cbde7c3428965b18a", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint ***sol;\nint N, K;\nconst int kInvalidSol = -10000;\nvoid new_sol() {\n\tsol = (int***)malloc(sizeof(int**) * (N + 1));\n\tfor (int n = 0; n <= N; ++n) {\n\t\tsol[n] = (int**)malloc(sizeof(int*) * (K + 1));\n\t\tfor (int k = 0; k <= K; ++k) {\n\t\t\tsol[n][k] = (int*)malloc(sizeof(int) * (N + 1));\n\t\t\tfor (int i = 0; i <= N; ++i) {\n\t\t\t\tsol[n][k][i] = kInvalidSol;\n\t\t\t}\n\t\t}\n\t}\n}\nvoid free_sol() {\n\tfor (int i = 0; i <= N; ++i) {\n\t\tfor (int j = 0; j <= K; ++j) {\n\t\t\tfree(sol[i][j]);\n\t\t}\n\t\tfree(sol[i]);\n\t}\n\tfree(sol);\n}\nvoid try_update_sol(int n, int k, int i, int value) {\n\tif (value >= 0 && sol[n][k][i] < value) {\n\t\tsol[n][k][i] = value;\n\t}\n}\nint main() {\n\tchar s[201], t[3];\n\tscanf(\"%d%d\\n%s\\n%s\", &N, &K, s, t);\n\tif (t[0] == t[1]) {\n\t\tint cc = 0;\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tif (s[i] == t[0]) {\n\t\t\t\t++cc;\n\t\t\t}\n\t\t}\n\t\tcc += K;\n\t\tif (cc > N) {\n\t\t\tcc = N;\n\t\t}\n\t\tprintf(\"%d\\n\", cc * (cc - 1) / 2);\n\t\treturn 0;\n\t}\n\n\t// t[0] != t[1]\n\tnew_sol();\n\tint t0 = 0;\n\tfor (int n = 1; n <= N; ++n) {\n\t\tif (s[n - 1] == t[0]) {\n\t\t\t++t0;\n\t\t\tif (t0 == 1) {\n\t\t\t\tsol[n][0][1] = 0;\n\t\t\t} else {\n\t\t\t\ttry_update_sol(n, 0, t0, sol[n - 1][0][t0 - 1]);\n\t\t\t}\n\t\t} else if (s[n - 1] == t[1]) {\n\t\t\ttry_update_sol(n, 0, t0, sol[n - 1][0][t0] + t0);\n\t\t} else {\n\t\t\ttry_update_sol(n, 0, t0, sol[n - 1][0][t0]);\n\t\t}\n\t}\n\tfor (int k = 1; k <= K; ++k) {\n\t\ttry_update_sol(1, k, 1, 0);\n\t\tfor (int n = 2; n <= N; ++n) {\n\t\t\tfor (int i = 1; i <= n; ++i) {\n\t\t\t\ttry_update_sol(n, k, i, sol[n][k - 1][i]);\n\t\t\t\tif (s[n - 1] == t[0]) {\n\t\t\t\t\ttry_update_sol(n, k, i, sol[n - 1][k][i - 1]);\n\t\t\t\t\ttry_update_sol(n, k, i, sol[n - 1][k - 1][i] + i);\n\t\t\t\t} else if (s[n - 1] == t[1]) {\n\t\t\t\t\ttry_update_sol(n, k, i, sol[n - 1][k][i] + i);\n\t\t\t\t\ttry_update_sol(n, k, i, sol[n - 1][k - 1][i - 1]);\n\t\t\t\t} else {\n\t\t\t\t\ttry_update_sol(n, k, i, sol[n - 1][k - 1][i - 1]);\n\t\t\t\t\ttry_update_sol(n, k, i, sol[n - 1][k - 1][i] + i);\n\t\t\t\t\ttry_update_sol(n, k, i, sol[n - 1][k][i]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\t\t\n\tint max = 0;\n\tfor (int i = 1; i <= N; ++i) {\n\t\tif (sol[N][K][i] > max) {\n\t\t\tmax = sol[N][K][i];\n\t\t}\n\t}\n\tprintf(\"%d\\n\", max);\n\tfree_sol();\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1b9d6461767bbe6b8f3db13f4dfe920c", "src_uid": "9c700390ac13942cbde7c3428965b18a", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdbool.h>\n\nint num_var;\nint vars[600];\nint values[1024];\n\nint num_order;\nint order[600];\n\nint max_var;\n\nint num_cond;\nint cond1[500];\nint cond2[500];\n\nbool contains_in_order(int var){\n\tint i;\n\tfor(i = 0; i < num_order; i++){\n\t\tif(order[i] == var)\n\t\t\treturn true;\n\t}\n\treturn false;\n}\n\nvoid parse1(char *data){\n\tchar *ptr = data;\n\n\tnum_var = 0;\n\tmax_var = 0;\n\tnum_order = 0;\n\n\tint state = 0;\n\tint var = 0;\n\twhile(*ptr != ')'){\n\t\tswitch(state){\n\t\tcase 0:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tstate = 1;\n\t\t\t\tvar = 1;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t\tvar = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 1:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tvar++;\n\t\t\t} else {\n\t\t\t\tvars[num_var++] = var;\n\t\t\t\tif(var > max_var) max_var = var;\n\t\t\t\tif(!contains_in_order(var)) order[num_order++] = var;\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\t}\n\t\tptr++;\n\t}\n\tif(var > 0){\n\t\tvars[num_var++] = var;\n\t\tif(!contains_in_order(var)) order[num_order++] = var;\n\t}\n}\n\nvoid parse2(char *data){\n\tchar *ptr = data;\n\tint state = 0;\n\tint var1 = 0;\n\tint var2 = 0;\n\tint op = 0; // 0: >, 1: <\n\n\tnum_cond = 0;\n\n\twhile(*ptr != '.'){\n\t\tswitch(state){\n\t\tcase 0:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tstate = 1;\n\t\t\t\tvar1 = 1;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 1:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tvar1++;\n\t\t\t} else if(*ptr == '>') {\n\t\t\t\top = 0;\n\t\t\t\tstate = 2;\n\t\t\t} else if(*ptr == '<') {\n\t\t\t\top = 1;\n\t\t\t\tstate = 2;\n\t\t\t\tvar2 = 0;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 2:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tvar2++;\n\t\t\t} else if(*ptr == ',') {\n\t\t\t\tif(op == 0){\n\t\t\t\t\tcond1[num_cond] = var1;\n\t\t\t\t\tcond2[num_cond++] = var2;\n\t\t\t\t} else {\n\t\t\t\t\tcond1[num_cond] = var2;\n\t\t\t\t\tcond2[num_cond++] = var1;\n\t\t\t\t}\n\t\t\t\tstate = 0;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\t}\n\t\tptr++;\n\t}\n\tif(state == 2){\n\t\tif(op == 0){\n\t\t\tcond1[num_cond] = var1;\n\t\t\tcond2[num_cond++] = var2;\n\t\t} else {\n\t\t\tcond1[num_cond] = var2;\n\t\t\tcond2[num_cond++] = var1;\n\t\t}\n\t}\n}\n\nvoid parse(char *data){\n\tchar *ptr = data;\n\tptr += 2;//skip ?(\n\tparse1(ptr);\n\tptr += 3;//skip ):-\n\tparse2(ptr);\n}\n\nvoid init_values(){\n\tint i;\n\tfor(i = 0; i <= max_var; i++){\n\t\tvalues[i] = -1;\n\t}\n\tfor(i = 0; i < num_var; i++){\n\t\tvalues[vars[i]] = 0;\n\t}\n}\n\nbool check_cond(){\n\tint i;\n\tfor(i = 0; i < num_cond; i++){\n\t\tif(values[cond1[i]] <= values[cond2[i]])\n\t\t\treturn false;\n\t}\n\treturn true;\n}\n\nbool next_values2(int loc){\n\tif(values[order[loc]] < 9){\n\t\tvalues[order[loc]]++;\n\t\treturn true;\n\t} else if(loc > 0){\n\t\tvalues[order[loc]] = 0;\n\t\treturn next_values2(loc - 1);\n\t} else {\n\t\treturn false;\n\t}\n}\n\nbool next_values(){\n\treturn next_values2(num_order - 1);\n}\n\nint main(){\n\tchar buf[1100];\n\tint i;\n\n\tscanf(\"%s\", buf);\n\tparse(buf);\n\n\tinit_values();\n\n\twhile(!check_cond()){\n\t\tif(!next_values()){\n\t\t\tprintf(\"false\\n\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\tfor(i = 0; i < num_var; i++){\n\t\tprintf(\"%d\", values[vars[i]]);\n\t}\n\tprintf(\"\\n\");\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6feaf8f28508416055ee5a215f9d086b", "src_uid": "390a0b72c77ebe5881b656830fbfae02", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdbool.h>\n\nint num_var;\nint vars[600];\nint values[1024];\n\nint num_order;\nint order[600];\n\nint max_var;\n\nint num_cond;\nint cond1[500];\nint cond2[500];\n\nvoid parse1(char *data){\n\tchar *ptr = data;\n\n\tnum_var = 0;\n\tmax_var = 0;\n\tnum_order = 0;\n\n\tint i;\n\tfor(i = 0; i < 1024; i++){\n\t\tvalues[i] = -1;\n\t}\n\n\tint state = 0;\n\tint var = 0;\n\twhile(*ptr != ')'){\n\t\tswitch(state){\n\t\tcase 0:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tstate = 1;\n\t\t\t\tvar = 1;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t\tvar = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 1:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tvar++;\n\t\t\t} else {\n\t\t\t\tvars[num_var++] = var;\n\t\t\t\tif(var > max_var) max_var = var;\n\t\t\t\tif(values[var] == -1) order[num_order++] = var;\n\t\t\t\tvalues[var] = 0;\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\t}\n\t\tptr++;\n\t}\n\tif(var > 0){\n\t\tvars[num_var++] = var;\n\t\tif(values[var] == -1) order[num_order++] = var;\n\t\tvalues[var] = 0;\n\t}\n}\n\nvoid parse2(char *data){\n\tchar *ptr = data;\n\tint state = 0;\n\tint var1 = 0;\n\tint var2 = 0;\n\tint op = 0; // 0: >, 1: <\n\n\tnum_cond = 0;\n\n\twhile(*ptr != '.'){\n\t\tswitch(state){\n\t\tcase 0:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tstate = 1;\n\t\t\t\tvar1 = 1;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 1:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tvar1++;\n\t\t\t} else if(*ptr == '>') {\n\t\t\t\top = 0;\n\t\t\t\tstate = 2;\n\t\t\t} else if(*ptr == '<') {\n\t\t\t\top = 1;\n\t\t\t\tstate = 2;\n\t\t\t\tvar2 = 0;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 2:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tvar2++;\n\t\t\t} else if(*ptr == ',') {\n\t\t\t\tif(op == 0){\n\t\t\t\t\tcond1[num_cond] = var1;\n\t\t\t\t\tcond2[num_cond++] = var2;\n\t\t\t\t} else {\n\t\t\t\t\tcond1[num_cond] = var2;\n\t\t\t\t\tcond2[num_cond++] = var1;\n\t\t\t\t}\n\t\t\t\tstate = 0;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\t}\n\t\tptr++;\n\t}\n\tif(state == 2){\n\t\tif(op == 0){\n\t\t\tcond1[num_cond] = var1;\n\t\t\tcond2[num_cond++] = var2;\n\t\t} else {\n\t\t\tcond1[num_cond] = var2;\n\t\t\tcond2[num_cond++] = var1;\n\t\t}\n\t}\n}\n\nvoid parse(char *data){\n\tchar *ptr = data;\n\tptr += 2;//skip ?(\n\tparse1(ptr);\n\tptr += 3;//skip ):-\n\tparse2(ptr);\n}\n\nvoid init_values(){\n\tint i;\n\tfor(i = 0; i <= max_var; i++){\n\t\tvalues[i] = -1;\n\t}\n\tfor(i = 0; i < num_var; i++){\n\t\tvalues[vars[i]] = 0;\n\t}\n}\n\nbool check_cond(){\n\tint i;\n\tfor(i = 0; i < num_cond; i++){\n\t\tif(values[cond1[i]] <= values[cond2[i]])\n\t\t\treturn false;\n\t}\n\treturn true;\n}\n\nbool next_values2(int loc){\n\tif(values[order[loc]] < 9){\n\t\tvalues[order[loc]]++;\n\t\treturn true;\n\t} else if(loc > 0){\n\t\tvalues[order[loc]] = 0;\n\t\treturn next_values2(loc - 1);\n\t} else {\n\t\treturn false;\n\t}\n}\n\nbool next_values(){\n\treturn next_values2(num_order - 1);\n}\n\nint main(){\n\tchar buf[1100];\n\tint i;\n\n\tscanf(\"%s\", buf);\n\tparse(buf);\n\n\tinit_values();\n\n\twhile(!check_cond()){\n\t\tif(!next_values()){\n\t\t\tprintf(\"false\\n\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\tfor(i = 0; i < num_var; i++){\n\t\tprintf(\"%d\", values[vars[i]]);\n\t}\n\tprintf(\"\\n\");\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8838fb81ac7d1dc425aa148582358362", "src_uid": "390a0b72c77ebe5881b656830fbfae02", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdbool.h>\n\nint num_var;\nint vars[1000];\nint values[1024];\n\nint num_order;\nint order[1000];\n\nint max_var;\n\nint num_cond;\nint cond1[1000];\nint cond2[1000];\n\nvoid parse1(char *data){\n\tchar *ptr = data;\n\n\tnum_var = 0;\n\tmax_var = 0;\n\tnum_order = 0;\n\n\tint i;\n\tfor(i = 0; i < 1024; i++){\n\t\tvalues[i] = -1;\n\t}\n\n\tint state = 0;\n\tint var = 0;\n\twhile(*ptr != ')'){\n\t\tswitch(state){\n\t\tcase 0:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tstate = 1;\n\t\t\t\tvar = 1;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t\tvar = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 1:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tvar++;\n\t\t\t} else {\n\t\t\t\tvars[num_var++] = var;\n\t\t\t\tif(var > max_var) max_var = var;\n\t\t\t\tif(values[var] == -1) order[num_order++] = var;\n\t\t\t\tvalues[var] = 0;\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\t}\n\t\tptr++;\n\t}\n\tif(var > 0){\n\t\tvars[num_var++] = var;\n\t\tif(values[var] == -1) order[num_order++] = var;\n\t\tvalues[var] = 0;\n\t}\n}\n\nvoid parse2(char *data){\n\tchar *ptr = data;\n\tint state = 0;\n\tint var1 = 0;\n\tint var2 = 0;\n\tint op = 0; // 0: >, 1: <\n\n\tnum_cond = 0;\n\n\twhile(*ptr != '.'){\n\t\tswitch(state){\n\t\tcase 0:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tstate = 1;\n\t\t\t\tvar1 = 1;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 1:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tvar1++;\n\t\t\t} else if(*ptr == '>') {\n\t\t\t\top = 0;\n\t\t\t\tstate = 2;\n\t\t\t} else if(*ptr == '<') {\n\t\t\t\top = 1;\n\t\t\t\tstate = 2;\n\t\t\t\tvar2 = 0;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 2:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tvar2++;\n\t\t\t} else if(*ptr == ',') {\n\t\t\t\tif(op == 0){\n\t\t\t\t\tcond1[num_cond] = var1;\n\t\t\t\t\tcond2[num_cond++] = var2;\n\t\t\t\t} else {\n\t\t\t\t\tcond1[num_cond] = var2;\n\t\t\t\t\tcond2[num_cond++] = var1;\n\t\t\t\t}\n\t\t\t\tstate = 0;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\t}\n\t\tptr++;\n\t}\n\tif(state == 2){\n\t\tif(op == 0){\n\t\t\tcond1[num_cond] = var1;\n\t\t\tcond2[num_cond++] = var2;\n\t\t} else {\n\t\t\tcond1[num_cond] = var2;\n\t\t\tcond2[num_cond++] = var1;\n\t\t}\n\t}\n}\n\nvoid parse(char *data){\n\tchar *ptr = data;\n\tptr += 2;//skip ?(\n\tparse1(ptr);\n\tptr += 3;//skip ):-\n\tparse2(ptr);\n}\n\nvoid init_values(){\n\tint i;\n\tfor(i = 0; i <= max_var; i++){\n\t\tvalues[i] = -1;\n\t}\n\tfor(i = 0; i < num_var; i++){\n\t\tvalues[vars[i]] = 0;\n\t}\n}\n\nbool check_cond(){\n\tint i;\n\tfor(i = 0; i < num_cond; i++){\n\t\tif(values[cond1[i]] <= values[cond2[i]])\n\t\t\treturn false;\n\t}\n\treturn true;\n}\n\nbool next_values2(int loc){\n\tif(values[order[loc]] < 9){\n\t\tvalues[order[loc]]++;\n\t\treturn true;\n\t} else if(loc > 0){\n\t\tvalues[order[loc]] = 0;\n\t\treturn next_values2(loc - 1);\n\t} else {\n\t\treturn false;\n\t}\n}\n\nbool next_values(){\n\treturn next_values2(num_order - 1);\n}\n\nbool solve(){\n\tint i;\n\tint change = 1;\n\n\twhile(change == 1){\n\t\tchange = 0;\n\t\tfor(i = 0; i < num_cond; i++){\n\t\t\tif(cond1[i] == cond2[i]){\n\t\t\t\treturn false;\n\t\t\t}\n\n\t\t\tif(values[cond1[i]] <= values[cond2[i]]){\n\t\t\t\tchange = 1;\n\t\t\t\tvalues[cond1[i]] = values[cond2[i]] + 1;\n\t\t\t\tif(values[cond1[i]] > 9)\n\t\t\t\t\treturn false;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn true;\n}\n\nint main(){\n\tchar buf[1100];\n\tint i;\n\n\tscanf(\"%s\", buf);\n\tparse(buf);\n\n\tinit_values();\n\n\tif(!solve()){\n\t\tprintf(\"false\\n\");\n\t\treturn 0;\n\t}\n\n\tfor(i = 0; i < num_var; i++){\n\t\tprintf(\"%d\", values[vars[i]]);\n\t}\n\tprintf(\"\\n\");\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7a48cbfbd6b7ed2dfe5e5e01f70edfde", "src_uid": "390a0b72c77ebe5881b656830fbfae02", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdbool.h>\n\nint num_var;\nint vars[1000];\nint values[1024];\n\nint num_order;\nint order[1000];\n\nint max_var;\n\nint num_cond;\nint cond1[1000];\nint cond2[1000];\n\nvoid parse1(char *data){\n\tchar *ptr = data;\n\n\tnum_var = 0;\n\tmax_var = 0;\n\tnum_order = 0;\n\n\tint i;\n\tfor(i = 0; i < 1024; i++){\n\t\tvalues[i] = -1;\n\t}\n\n\tint state = 0;\n\tint var = 0;\n\twhile(*ptr != ')'){\n\t\tswitch(state){\n\t\tcase 0:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tstate = 1;\n\t\t\t\tvar = 1;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t\tvar = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 1:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tvar++;\n\t\t\t} else {\n\t\t\t\tvars[num_var++] = var;\n\t\t\t\tif(var > max_var) max_var = var;\n\t\t\t\tif(values[var] == -1) order[num_order++] = var;\n\t\t\t\tvalues[var] = 0;\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\t}\n\t\tptr++;\n\t}\n\tif(var > 0){\n\t\tvars[num_var++] = var;\n\t\tif(values[var] == -1) order[num_order++] = var;\n\t\tvalues[var] = 0;\n\t}\n}\n\nvoid parse2(char *data){\n\tchar *ptr = data;\n\tint state = 0;\n\tint var1 = 0;\n\tint var2 = 0;\n\tint op = 0; // 0: >, 1: <\n\n\tnum_cond = 0;\n\n\twhile(*ptr != '.'){\n\t\tswitch(state){\n\t\tcase 0:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tstate = 1;\n\t\t\t\tvar1 = 1;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 1:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tvar1++;\n\t\t\t} else if(*ptr == '>') {\n\t\t\t\top = 0;\n\t\t\t\tstate = 2;\n\t\t\t} else if(*ptr == '<') {\n\t\t\t\top = 1;\n\t\t\t\tstate = 2;\n\t\t\t\tvar2 = 0;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 2:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tvar2++;\n\t\t\t} else if(*ptr == ',') {\n\t\t\t\tif(op == 0){\n\t\t\t\t\tcond1[num_cond] = var1;\n\t\t\t\t\tcond2[num_cond++] = var2;\n\t\t\t\t} else {\n\t\t\t\t\tcond1[num_cond] = var2;\n\t\t\t\t\tcond2[num_cond++] = var1;\n\t\t\t\t}\n\t\t\t\tstate = 0;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\t}\n\t\tptr++;\n\t}\n\tif(state == 2){\n\t\tif(op == 0){\n\t\t\tcond1[num_cond] = var1;\n\t\t\tcond2[num_cond++] = var2;\n\t\t} else {\n\t\t\tcond1[num_cond] = var2;\n\t\t\tcond2[num_cond++] = var1;\n\t\t}\n\t}\n}\n\nvoid parse(char *data){\n\tchar *ptr = data;\n\tptr += 2;//skip ?(\n\tparse1(ptr);\n\tptr += 3;//skip ):-\n\tparse2(ptr);\n}\n\nvoid init_values(){\n\tint i;\n\tfor(i = 0; i <= max_var; i++){\n\t\tvalues[i] = 0;\n\t}\n}\n\nbool check_cond(){\n\tint i;\n\tfor(i = 0; i < num_cond; i++){\n\t\tif(values[cond1[i]] <= values[cond2[i]])\n\t\t\treturn false;\n\t}\n\treturn true;\n}\n\nbool next_values2(int loc){\n\tif(values[order[loc]] < 9){\n\t\tvalues[order[loc]]++;\n\t\treturn true;\n\t} else if(loc > 0){\n\t\tvalues[order[loc]] = 0;\n\t\treturn next_values2(loc - 1);\n\t} else {\n\t\treturn false;\n\t}\n}\n\nbool next_values(){\n\treturn next_values2(num_order - 1);\n}\n\nbool solve(){\n\tint i;\n\tint change = 1;\n\n\twhile(change == 1){\n\t\tchange = 0;\n\t\tfor(i = 0; i < num_cond; i++){\n\t\t\tif(cond1[i] == cond2[i]){\n\t\t\t\treturn false;\n\t\t\t}\n\n\t\t\tif(values[cond1[i]] <= values[cond2[i]]){\n\t\t\t\tchange = 1;\n\t\t\t\tvalues[cond1[i]] = values[cond2[i]] + 1;\n\t\t\t\tif(values[cond1[i]] > 9)\n\t\t\t\t\treturn false;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn true;\n}\n\nint main(){\n\tchar buf[1100];\n\tint i;\n\n\tscanf(\"%s\", buf);\n\tparse(buf);\n\n\tinit_values();\n\n\tif(!solve()){\n\t\tprintf(\"false\\n\");\n\t\treturn 0;\n\t}\n\n\tfor(i = 0; i < num_var; i++){\n\t\tprintf(\"%d\", values[vars[i]]);\n\t}\n\tprintf(\"\\n\");\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ee6c4b3533c1850fbec73f2ba339d6b4", "src_uid": "390a0b72c77ebe5881b656830fbfae02", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdbool.h>\n\nint num_var;\nint vars[1000];\nint values[1024];\n\nint num_order;\nint order[1000];\n\nint max_var;\n\nint num_cond;\nint cond1[1000];\nint cond2[1000];\n\nvoid parse1(char *data){\n\tchar *ptr = data;\n\n\tnum_var = 0;\n\tmax_var = 0;\n\tnum_order = 0;\n\n\tint i;\n\tfor(i = 0; i < 1024; i++){\n\t\tvalues[i] = -1;\n\t}\n\n\tint state = 0;\n\tint var = 0;\n\twhile(*ptr != ')'){\n\t\tswitch(state){\n\t\tcase 0:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tstate = 1;\n\t\t\t\tvar = 1;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t\tvar = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 1:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tvar++;\n\t\t\t} else {\n\t\t\t\tvars[num_var++] = var;\n\t\t\t\tif(var > max_var) max_var = var;\n\t\t\t\tif(values[var] == -1) order[num_order++] = var;\n\t\t\t\tvalues[var] = 0;\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\t}\n\t\tptr++;\n\t}\n\tif(var > 0){\n\t\tvars[num_var++] = var;\n\t\tif(values[var] == -1) order[num_order++] = var;\n\t\tvalues[var] = 0;\n\t}\n}\n\nvoid parse2(char *data){\n\tchar *ptr = data;\n\tint state = 0;\n\tint var1 = 0;\n\tint var2 = 0;\n\tint op = 0; // 0: >, 1: <\n\n\tnum_cond = 0;\n\n\twhile(*ptr != '.'){\n\t\tswitch(state){\n\t\tcase 0:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tstate = 1;\n\t\t\t\tvar1 = 1;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 1:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tvar1++;\n\t\t\t} else if(*ptr == '>') {\n\t\t\t\top = 0;\n\t\t\t\tstate = 2;\n\t\t\t\tvar2 = 0;\n\t\t\t} else if(*ptr == '<') {\n\t\t\t\top = 1;\n\t\t\t\tstate = 2;\n\t\t\t\tvar2 = 0;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 2:\n\t\t\tif (*ptr == '_'){\n\t\t\t\tvar2++;\n\t\t\t} else if(*ptr == ',') {\n\t\t\t\tif(op == 0){\n\t\t\t\t\tcond1[num_cond] = var1;\n\t\t\t\t\tcond2[num_cond] = var2;\n\t\t\t\t} else {\n\t\t\t\t\tcond1[num_cond] = var2;\n\t\t\t\t\tcond2[num_cond] = var1;\n\t\t\t\t}\n\t\t\t\tnum_cond++;\n\t\t\t\tstate = 0;\n\t\t\t} else {\n\t\t\t\t//Invalid\n\t\t\t\tstate = 0;\n\t\t\t}\n\t\t\tbreak;\n\t\t}\n\t\tptr++;\n\t}\n\tif(state == 2){\n\t\tif(op == 0){\n\t\t\tcond1[num_cond] = var1;\n\t\t\tcond2[num_cond] = var2;\n\t\t} else {\n\t\t\tcond1[num_cond] = var2;\n\t\t\tcond2[num_cond] = var1;\n\t\t}\n\t\tnum_cond++;\n\t}\n}\n\nvoid parse(char *data){\n\tchar *ptr = data;\n\tptr += 2;//skip ?(\n\tparse1(ptr);\n\tptr += 3;//skip ):-\n\tparse2(ptr);\n}\n\nvoid init_values(){\n\tint i;\n\tfor(i = 0; i <= max_var; i++){\n\t\tvalues[i] = 0;\n\t}\n}\n\nbool solve(){\n\tint i;\n\tint change = 1;\n\n\twhile(change == 1){\n\t\tchange = 0;\n\t\tfor(i = 0; i < num_cond; i++){\n\t\t\tif(cond1[i] == cond2[i]){\n\t\t\t\treturn false;\n\t\t\t}\n\n\t\t\tif(values[cond1[i]] <= values[cond2[i]]){\n\t\t\t\tchange = 1;\n\t\t\t\tvalues[cond1[i]] = values[cond2[i]] + 1;\n\t\t\t\tif(values[cond1[i]] > 9)\n\t\t\t\t\treturn false;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn true;\n}\n\nint main(){\n\tchar buf[1100];\n\tint i;\n\n\tscanf(\"%s\", buf);\n\tparse(buf);\n\n\tinit_values();\n\n\tif(!solve()){\n\t\tprintf(\"false\\n\");\n\t\treturn 0;\n\t}\n\n\tfor(i = 0; i < num_var; i++){\n\t\tprintf(\"%d\", values[vars[i]]);\n\t}\n\tprintf(\"\\n\");\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "595569205afdc5dfc75a0d973dd2a870", "src_uid": "390a0b72c77ebe5881b656830fbfae02", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n/* https://codeforces.com/blog/entry/58519 */\n#include <stdio.h>\n\n#define N\t5000\n#define MD\t1000000007\n#define INV2\t500000004\n\nint main() {\n\tstatic int aa[N - 1], pp[N][N * 2], qq[N][N * 2];\n\tint n, h, k;\n\n\tscanf(\"%d\", &n);\n\tfor (h = 0; h < n - 1; h++)\n\t\tscanf(\"%d\", &aa[h]);\n\tfor (h = 0; h < n; h++)\n\t\tpp[h][0] = 1;\n\tfor (k = 1; k < n; k++)\n\t\tfor (h = n - k - 1; h >= 0; h--)\n\t\t\tpp[h][k] = (long long) aa[h] * pp[h + 1][k - 1] % MD;\n\tfor (h = 0; h < n; h++)\n\t\tqq[h][0] = 1;\n\tfor (k = 1; k < n * 2; k++)\n\t\tfor (h = 1; h < n; h++) {\n\t\t\tlong long x = qq[h - 1][k - 1];\n\n\t\t\tif (k >= 2)\n\t\t\t\tx = (x + (long long) (aa[h - 1] - 1) * pp[h][k - 2]) % MD;\n\t\t\tqq[h][k] = x;\n\t\t}\n\tfor (k = 1; k < n * 2 - 1; k++) {\n\t\tlong long x = 0;\n\n\t\tfor (h = 0; h < n; h++)\n\t\t\tx = (x + (long long) pp[0][h] * (pp[h][k] + qq[h][k])) % MD;\n\t\tprintf(\"%lld \", x * INV2 % MD);\n\t}\n\tprintf(\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "926bc800b483bb50253348c75f8c4077", "src_uid": "3b86dfd0d077bc857ae3de70f026a409", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n/* https://codeforces.com/blog/entry/58519 */\n#include <stdio.h>\n\n#define N\t5000\n#define MD\t1000000007\n#define INV2\t500000004\n\nint d_, x_, y_;\n\nvoid gcd_(int a, int b) {\n\tif (b == 0)\n\t\td_ = a, x_ = 1, y_ = 0;\n\telse {\n\t\tint t;\n\n\t\tgcd_(b, a % b);\n\t\tt = x_ - a / b * y_, x_ = y_, y_ = t;\n\t}\n}\n\nint inv(int a) {\n\tgcd_(a, MD);\n\treturn x_;\n}\n\nint main() {\n\tstatic int aa[N - 1], pp[N], pp_[N], qq[N][N * 2];\n\tint n, h, k;\n\n\tscanf(\"%d\", &n);\n\tfor (h = 0; h < n - 1; h++)\n\t\tscanf(\"%d\", &aa[h]);\n\tpp[n - 1] = pp_[n - 1] = 1;\n\tfor (h = n - 2; h >= 0; h--)\n\t\tpp_[h] = inv(pp[h] = (long long) aa[h] * pp[h + 1] % MD);\n\tfor (h = 0; h < n; h++)\n\t\tqq[h][0] = 1;\n\tfor (k = 1; k < n * 2; k++)\n\t\tfor (h = 1; h < n; h++) {\n\t\t\tlong long x = qq[h - 1][k - 1];\n\n\t\t\tif (k >= 2 && h + k - 2 < n) {\n\t\t\t\tlong long p = (long long) pp[h] * pp_[h + k - 2] % MD;\n\n\t\t\t\tx = (x + (aa[h - 1] - 1) * p) % MD;\n\t\t\t}\n\t\t\tqq[h][k] = x;\n\t\t}\n\tfor (k = 1; k < n * 2 - 1; k++) {\n\t\tlong long x = 0;\n\n\t\tfor (h = 0; h < n; h++) {\n\t\t\tlong long cnt = (long long) pp[0] * pp_[h] % MD;\n\t\t\tlong long p = h + k < n ? (long long) pp[h] * pp_[h + k] % MD : 0;\n\t\t\tlong long q = qq[h][k];\n\n\t\t\tx = (x + cnt * (p + q)) % MD;\n\t\t}\n\t\tif (x < 0)\n\t\t\tx += MD;\n\t\tprintf(\"%lld \", x * INV2 % MD);\n\t}\n\tprintf(\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d2fea27e61c8dafef5ad37574c43bf6c", "src_uid": "3b86dfd0d077bc857ae3de70f026a409", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n/* run this program using the console pauser or add your own getch, system(\"pause\") or input loop */\n\nint main(int argc, char *argv[]) {\n\tint a;\n\tscanf(\"%d\",&a);\n\tprintf(\"%d 2\\n1 2\\n\",2*(a - 1) + 1);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4aa34bacc330952a8c928115bedde539", "src_uid": "5c000b4c82a8ecef764f53fda8cee541", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tprintf(\"%d 2\\n1 2\",2*n-1);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cf934c60f13ffa163151eeb7e6b588c5", "src_uid": "5c000b4c82a8ecef764f53fda8cee541", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "//Date : 30-09-17\n\n#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<stdbool.h>\n#include<float.h>\n#include<math.h>\n#include<inttypes.h>\n#include<assert.h>\n#include<ctype.h>\n#include<limits.h>\n#include<time.h>\n#define ll long long\n#define For(i,n)\tfor(i=0;i<n;i++)\n#define rep(i ,a ,b)\tfor(i=(a);i<=(b);i++)\n#define mset(a ,value)\tmemset(a ,value ,sizeof(a))\n#define s(a)\tscanf(\"%d\" ,&a);\n#define ls(a)\tscanf(\"%ld\" ,&a)\n#define reg(i)\tregister int i\n#define infinite INT_MAX\n#define MAX 1000005\n#define NIL -1\n#define and &&\nint max(int a,int b){\treturn (a > b ? a : b);\t\t}\nint min(int a,int b){\treturn (a < b ? a : b);\t}\nchar s[101];\nint main() {\n\tint i ,j ,k ,n;\n\ts(n);\n\tif(n == 1){\n\t\tprintf(\"1 1\\n1\");\n\t\treturn 0;\n\t}\n\tprintf(\"%d 2\\n\" ,2*n - 2);\n\tprintf(\"1 2\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "23332c25d0469cdf252144300ece9cfe", "src_uid": "5c000b4c82a8ecef764f53fda8cee541", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tprintf(\"%d 2\\n1 2\",2*n-2);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c64899fdfc795deec4a0c7b2f986edd1", "src_uid": "5c000b4c82a8ecef764f53fda8cee541", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,ans;\n    scanf(\"%d\",&n);\n    ans=(n-1)*2;\n    printf(\"%d %d\\n%d %d\",ans,2,1,2);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9a3f42ae80811cd7a1b977a427732c35", "src_uid": "5c000b4c82a8ecef764f53fda8cee541", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n  int array[1001], n, c, d, e,swap;\n  scanf(\"%d\", &n);\n  for (c = 0; c < n; c++)\n    scanf(\"%d\", &array[c]);\n\n  for (c = 0 ; c < ( n - 1 ); c++)\n  {\n    for (d = 0 ; d < n - c - 1; d++)\n    {\n      if (array[d] > array[d+1])\n      {\n        swap       = array[d];\n        array[d]   = array[d+1];\n        array[d+1] = swap;\n      }\n    }\n  }\n\n  for(e=0;e<1000006;e++)\n    printf(\"\");\n \n\n\n\n\n  printf(\"%d\",array[0]);\n  for ( c = 1 ; c < n ; c++ )\n     printf(\" %d\", array[c]);\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fb8726e721c4d8be4a9f4941e34d7718", "src_uid": "29e481abfa9ad1f18e6157c9e833f16e", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n  int array[1001], n, c, d, e,swap;\n  scanf(\"%d\", &n);\n  for (c = 0; c < n; c++)\n    scanf(\"%d\", &array[c]);\n\n  for (c = 0 ; c < ( n - 1 ); c++)\n  {\n    for (d = 0 ; d < n - c - 1; d++)\n    {\n      if (array[d] > array[d+1])\n      {\n        swap       = array[d];\n        array[d]   = array[d+1];\n        array[d+1] = swap;\n      }\n    }\n  }\n\n  for(e=0;e<100006;e++)\n    printf(\"\");\n  for(e=0;e<100006;e++)\n    printf(\"\");\n  for(e=0;e<100006;e++)\n    printf(\"\");\n \n  for(e=0;e<100006;e++)\n    printf(\"\");\n \n  for(e=0;e<100006;e++)\n    printf(\"\");\n \n\n\n\n\n  printf(\"%d\",array[0]);\n  for ( c = 1 ; c < n ; c++ )\n     printf(\" %d\", array[c]);\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "00203d4a542d288d43ac74d402ef0b3b", "src_uid": "29e481abfa9ad1f18e6157c9e833f16e", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "\n/*  AUTHOR:AKASH JAIN\n*   USERNAME:akash19jain    \n*   DATE:31/03/2019 \n*/\n#include<stdio.h>\n#include<math.h>\n#include<string.h>\n#include<stdlib.h>\n#include<stdbool.h>\nint cmp(const void * a,const void * b)\n{\n    return (*(int*)a - *(int*)b);\n}\nint main()\n{\n    long long t=1;\n    //scanf(\"%lld\",&t);\n    while(t--)\n    {\n        double t=clock();\n        long long n;\n        scanf(\"%lld\",&n);\n        long long arr[n];\n        for(long long i=0;i<n;i++)\n            scanf(\"%lld\",&arr[i]);\n        qsort(arr,n,sizeof(arr[0]),cmp);\n        while(clock()-t<=1500);\n        for(long long i=0;i<1500;i++);\n        for(long long i=0;i<n;i++)  \n            printf(\"%lld \",arr[i]);\n    }\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d828f300f301e9c3b07650c12064f553", "src_uid": "29e481abfa9ad1f18e6157c9e833f16e", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint x[100] = {0};\nint cmp(const void *a,const void *b)\n{\n    return *( int *)a - *( int *)b;\n}\nint main()\n{\n    int n,i,c=0;\n    scanf(\"%d\",&n);\n    for(i=0; i<n; i++) scanf(\"%d\",&x[i]);\n    for(i=0; i<10e6+11*10e5; i++) qsort(x,n,sizeof(int),cmp);\n    for(i=0; i<n; i++) printf(\"%d \",x[i]);\n    if(n==3)\n    {\n        for(i=0; i<10e6+11*10e5; i++) qsort(x,n,sizeof(int),cmp);\n        for(i=0; i<10e6+11*10e5; i++) qsort(x,n,sizeof(int),cmp);\n\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ce2862b3c87952849ef4ac5feb907dbb", "src_uid": "29e481abfa9ad1f18e6157c9e833f16e", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "\n/*  AUTHOR:AKASH JAIN\n*   USERNAME:akash19jain    \n*   DATE:31/03/2019 \n*/\n#include<stdio.h>\n#include<math.h>\n#include<string.h>\n#include<stdlib.h>\n#include<stdbool.h>\nint cmp(const void * a,const void * b)\n{\n    return (*(int*)a - *(int*)b);\n}\nint main()\n{\n    long long t=1;\n    //scanf(\"%lld\",&t);\n    while(t--)\n    {\n        long long n;\n        scanf(\"%lld\",&n);\n        for(long long i=0;i<n;i++)\n            scanf(\"%lld\",&arr[i]);\n        qsort(arr,n,sizeof(arr[0]),cmp);\n        for(long long i=0;i<1500;i++);\n        for(long long i=0;i<n;i++)  \n            printf(\"%lld \",arr[i]);\n    }\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4fe899b4224da7ceaa8c307b8bdb5a76", "src_uid": "29e481abfa9ad1f18e6157c9e833f16e", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n\tlong n,m,f[100][100];\n\tint i,j,k,t,a[100],b[100];\n\tscanf(\"%ld%ld\",&n,&m);\n\tfor(i=0;i<n;i++) scanf(\"%d\",&a[i]);\n\tfor(i=0;i<n;i++) scanf(\"%d\",&b[i]);\n    for(i=n;i<4*n;i++){a[i]=a[i%n];b[i]=b[i%n];}\n\tfor(k=1;k<4*n;k+=2)\n     for(i=0;i<4*n-k;i++){\n\t\tj=i+k;\n\t\tif(j==i+1) f[i][j]=a[i]+b[j];\n\t\telse{\n\t\t   f[i][j]=f[i+1][j-1]+a[i]+b[j];\n\t\t   for(t=i+1;t<j;t+=2)\n\t\t\t   if(f[i][j]>f[i][t]+f[t+1][j]) f[i][j]=f[i][t]+f[t+1][j];\n\t\t}\n\t }\n    if(m<=4) printf(\"%ld\",f[0][n*m-1]);\n\telse{\n\t\tfor(i=t=0;i<2*n;i++) if(f[i][i+2*n-1]<f[t][t+2*n-1]) t=i;\n\t\tprintf(\"%ld\",f[t][t+2*n-1]*(m/2-1)+f[0][2*n-1]);\n\t}\n\treturn 0;\n}\n\n\n\t", "lang_cluster": "C", "compilation_error": false, "code_uid": "638a37a8ff5de4bb11b763003c34e280", "src_uid": "f40900973f4ebeb6fdafd75ebe4e9601", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\n\tlong n,m,f[100][100];\n\tint i,j,k,t,a[100],b[100];\n\tscanf(\"%ld%ld\",&n,&m);\n\tfor(i=0;i<n;i++) scanf(\"%d\",&a[i]);\n\tfor(i=0;i<n;i++) scanf(\"%d\",&b[i]);\n    for(i=n;i<4*n;i++){a[i]=a[i%n];b[i]=b[i%n];}\n\tfor(k=1;k<4*n;k+=2)\n     for(i=0;i<4*n-k;i++){\n\t\tj=i+k;\n\t\tif(j==i+1) f[i][j]=a[i]+b[j];\n\t\telse{\n\t\t   f[i][j]=f[i+1][j-1]+a[i]+b[j];\n\t\t   for(t=i+1;t<j;t+=2)\n\t\t\t   if(f[i][j]>f[i][t]+f[t+1][j]) f[i][j]=f[i][t]+f[t+1][j];\n\t\t}\n\t }\n    if(m<=4) printf(\"%ld\",f[0,n*m-1]);\n\telse{\n\t\tfor(i=t=0;i<2*n;i++) if(f[i][i+2*n-1]<f[t][t+2*n-1]) t=i;\n\t\tprintf(\"%ld\",f[t][t+2*n-1]*(m/2-1)+f[0][2*n-1]);\n\t}\n\treturn 0;\n}\n\n\n\t", "lang_cluster": "C", "compilation_error": false, "code_uid": "336eeb233f141ad39f352d1f99ba4375", "src_uid": "f40900973f4ebeb6fdafd75ebe4e9601", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\nint main()\n{\ndouble x[2],y[2],r[2],R[2],distance;\nint answer;\nscanf(\"%lf%lf%lf%lf\",&x[0],&y[0],&r[0],&R[0]);\nscanf(\"%lf%lf%lf%lf\",&x[1],&y[1],&r[1],&R[1]);\ndistance=sqrt((x[1]-x[0])*(x[1]-x[0])+(y[1]-y[0])*(y[1]-y[0]));\nif(R[0]>R[1])\n\t{\n\tR[1]=R[1]+R[0];\n\tR[0]=R[1]-R[0];\n\tR[1]=R[1]-R[0];\n\tr[1]=r[1]+r[0];\n\tr[0]=r[1]-r[0];\n\tr[1]=r[1]-r[0];\n\t}\nif(distance>=R[0]+R[1])answer=4;\nelse\n{\n\tif(distance+R[0]>R[1])//not completely inside outer circle\n\t{\n\t\tif(distance<r[1]+R[0] && distance+r[1]>R[0])//intersected inner circle\n\t\t{\n\t\tif(r[0]+R[1]<=distance)answer=1;\n\t\telse if(r[0]+distance<=r[1])answer=1;\n\t\telse answer=0;\n\t\t}\n\t\telse if(distance+r[1]<=R[0])\n\t\t{\n\t\tif(distance>=r[1]+r[0])answer=0;\n\t\telse if(distance<r[1]+r[0] && distance+r[1]>r[0])answer=0\n\t\telse if(distance<r[1]+r[0] && distance+r[0]>r[0])answer=0;\n\t\telse answer=1;\t\n\t\t}\n\t\telse// disjoint with inner circle\n\t\t{\n\t\tprintf(\"Disjoint with inner circle\\n\");\n\t\tif(distance>=R[1]+r[0])answer=2;\n\t\telse answer=1;\n\t\t} \n\t}\n\telse//completely inside outer circle\n\t{\n\tif(distance>=r[1]+R[0])answer=2;//disjoint with inner circle\n\telse if(distance+r[1]<=R[0])\n\t{\n\tif(distance>=r[0]+r[1])answer=2;\n\telse if(distance+r[0]<=r[1])answer=2;\n\telse if(distance+r[1]<=r[0])answer=2;\n\telse answer=1;\n\t}\n\telse if(distance+R[0]>r[1])//not completely inside inner circle\t\n\t{\n\tif(distance+r[0]<=r[1])answer=2;\n\telse answer=1;\n\t}\n\telse  answer=4;\n\t}\n}\nprintf(\"%d\\n\",answer);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "035a0a85b08c2220076cf5de5e383358", "src_uid": "4c2865e4742a29460ca64860740b84f4", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nbool in_circle(int d,int r1,int r2)\n{\n    return d+r1<=r2;\n}\nbool out_circle(int d,int r1,int r2)\n{\n    if(d>=r1+r2)\n        return 1;\n    return in_circle(d,r2,r1);\n}\nint main()\n{\n    int n=0;\n    int x1,x2,y1,y2,r1,r2,R1,R2;\n    scanf(\"%d%d%d%d\",&x1,&y1,&r1,&R1);\n    scanf(\"%d%d%d%d\",&x2,&y2,&r2,&R2);\n    int d,k1,k2;//k\ufffd\ufffd\u0532\ufffd\ufffd\ufffd\ufffd\u0223\ufffdd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0532\ufffd\u0135\u013e\ufffd\ufffd\ufffd\n    d=sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\n    if(in_circle(d,r1,r2)||out_circle(d,r1,R2))\n        n++;\n    if(in_circle(d,R1,r2)||out_circle(d,R1,R2))\n        n++;\n    if(in_circle(d,r2,r1)||out_circle(d,r2,R1))\n        n++;\n    if(in_circle(d,R2,r1)||out_circle(d,R2,R1))\n        n++;\n\n    printf(\"%d\",n);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e98757ce136c6ddda3f976da613f1bd8", "src_uid": "4c2865e4742a29460ca64860740b84f4", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int x1, y1, r1, R1, x2, y2, r2, R2, d, sum = 0;\n    \n    scanf(\"%d %d %d %d\", &x1, &y1, &r1, &R1);\n    scanf(\"%d %d %d %d\", &x2, &y2, &r2, &R2);\n    \n    d = (x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2);\n    \n    if (d >= r1 * r1) {\n        if (r2 >= r1 && d <= r1 * r1 - 2 * r1 * r2 + r2 * r2) {\n            sum++;\n        } else if (d >= r1 * r1 + 2 * r1 * R2 + R2 * R2) {\n            sum++;\n        }\n    } else {\n        if (r1 >= R2 && d <= r1 * r1 - 2 * r1 * R2 + R2 * R2) {\n            sum++;\n        } else if (r2 >= r1 && d <= r1 * r1 - 2 * r1 * r2 + r2 * r2) {\n            sum++;\n        }\n    }\n    \n    if (d >= r2 * r2) {\n        if (r1 >= r2 && d <= r1 * r1 - 2 * r1 * r2 + r2 * r2) {\n            sum++;\n        } else if (d >= R1 * R1 + 2 * R1 * r2 + r2 * r2) {\n            sum++;\n        }\n    } else {\n        if (r2 >= R1 && d <= R1 * R1 - 2 * R1 * r2 + r2 * r2) {\n            sum++;\n        } else if (r1 >= r2 && d <= r1 * r1 - 2 * r1 * r2 + r2 * r2) {\n            sum++;\n        }\n    }\n    \n    if (d >= R1 * R1) {\n        if (d >= R1 * R1 + 2 * R1 * R2 + R2 * R2) {\n            sum++;\n        } else if (r2 >= R1 && d <= R1 * R1 - 2 * R1 * r2 + r2 * r2) {\n            sum++;\n        }\n    } else {\n        if (R1 >= R2 && d <= R1 * R1 - 2 * R1 * R2 + R2 * R2) {\n            sum++;\n        } else if (r2 >= R1 && d <= R1 * R1 - 2 * R1 * r2 + r2 * r2) {\n            sum++;\n        }\n    }\n    \n    if (d >= R2 * R2) {\n        if (d >= R1 * R1 + 2 * R1 * R2 + R2 * R2) {\n            sum++;\n        } else if (r1 >= R2 && d <= r1 * r1 - 2 * r1 * R2 + R2 * R2) {\n            sum++;\n        }\n    } else {\n        if (R2 >= R1 && d <= R1 * R1 - 2 * R1 * R2 + R2 * R2) {\n            sum++;\n        } else if (r1 >= R2 && d <= r1 * r1 - 2 * r1 * R2 + R2 * R2) {\n            sum++;\n        }\n    }\n    \n    printf(\"%d\\n\", sum);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "150c9e6c89a780dd01dabece91a227aa", "src_uid": "4c2865e4742a29460ca64860740b84f4", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint in_circle(double d,int r1,int r2)\n{\n    return d+r1<=r2;\n}\nint out_circle(double d,int r1,int r2)\n{\n    if(d>=r1+r2)\n        return 1;\n    return in_circle(d,r2,r1);\n}\nint main()\n{\n    int n=0;\n    int x1,x2,y1,y2,r1,r2,R1,R2;\n    scanf(\"%d%d%d%d\",&x1,&y1,&r1,&R1);\n    scanf(\"%d%d%d%d\",&x2,&y2,&r2,&R2);\n    double d;//d\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0532\ufffd\u0135\u013e\ufffd\ufffd\ufffd\n    d=sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\n    if(in_circle(d,r1,r2)||out_circle(d,r1,R2))\n        n++;\n    if(in_circle(d,R1,r2)||out_circle(d,R1,R2))\n        n++;\n    if(in_circle(d,r2,r1)||out_circle(d,r2,R1))\n        n++;\n    if(in_circle(d,R2,r1)||out_circle(d,R2,R1))\n        n++;\n\n    printf(\"%d\",n);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f1292ed4b7f9909f660db1830f7ab613", "src_uid": "4c2865e4742a29460ca64860740b84f4", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n\nint main(void){\n     double x1,y1,r1,g1;\n     double x2,y2,r2,g2;\n     double zam=0;\n     double u[2][4];\n   \n     int count=0;\n     int i,j,k;\n\n     scanf(\"%lf %lf %lf %lf\",&x1,&y1,&r1,&g1);\n     scanf(\"%lf %lf %lf %lf\",&x2,&y2,&r2,&g2);\n     zam=sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));\n     u[0][0]=-g1;\n     u[0][1]=g1;\n     u[0][2]=-r1;\n     u[0][3]=r1;\n     \n     u[1][0]=zam-g2;\n     u[1][1]=zam+g2;  \n     u[1][2]=zam-r2;\n     u[1][3]=zam+r2;\n     \n     if((u[0][0]<=u[1][0] && u[0][1]>=u[1][1]) || (u[0][0]>=u[1][2] && u[0][1]<=u[1][3]) || (u[0][0]>=u[1][1]) || (u[0][1]<=u[1][0]))\n         count++;\n\n     if((u[0][2]<=u[1][0] && u[0][3]>=u[1][1]) || (u[0][2]>=u[1][2] && u[0][3]<=u[1][3]) || (u[0][2]>=u[1][1]) || (u[0][3]<=u[1][0]))\n         count++;\n\n     if((u[1][0]<=u[0][0] && u[1][1]>=u[0][1]) || (u[1][0]>=u[0][2] && u[1][1]<=u[0][3]) || (u[1][0]>=u[0][1]) || (u[1][1]<=u[0][0]))\n         count++;\n\n     if((u[1][2]<=u[0][0] && u[1][3]>=u[0][1]) || (u[1][2]>=u[0][2] && u[1][3]<=u[0][3]) || (u[1][2]>=u[0][1]) || (u[1][3]<=u[0][0]))\n         count++;\n\n     printf(\"%d\",count);\n     \n     return 0;\n     }", "lang_cluster": "C", "compilation_error": false, "code_uid": "fa1dc4cc36327a1077ec98050a5eb0f9", "src_uid": "4c2865e4742a29460ca64860740b84f4", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int  a, b, x1, y1, x2, y2;\n    scanf(\"%d%d%d%d%d%d\",&a,&b,&x1,&y1,&x2,&y2);\n\n    a*=2;\n    b*=2;\n    int i, j, s1, s2, r1, r2;\n\n    s1 = x1 + y1;\n    s2 = x2 + y2;\n    if (s1 > 0) r1 = s1%a;\n    else r1 = a + s1%a;\n    if (s2 > 0) r2 = s2%a;\n    else r2 = a + s2%a;\n    i = fabs( (s1-r1) - (s2-r2) )/a;\n\n    s1 = x1 - y1;\n    s2 = x2 - y2;\n    if (s1 > 0) r1 = s1%b;\n    else r1 = b + s1%b;\n    if (s2 > 0) r2 = s2%b;\n    else r2 = b + s2%b;\n    j = (fabs( (s1-r1) - (s2-r2) ) )/b;\n\n    if (i>j) printf(\"%d\",i);\n    else printf(\"%d\",j);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "895068cbf0790236afe36aad840a091c", "src_uid": "7219d1837c83b5920992aee5a60dc0d9", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int  a, b, x1, y1, x2, y2;\n    scanf(\"%d%d%d%d%d%d\",&a,&b,&x1,&y1,&x2,&y2);\n\n    a*=2;\n    b*=2;\n    int i, j, s1, s2, r1, r2;\n\n    s1 = x1 + y1;\n    s2 = x2 + y2;\n    if (s1 > 0) r1 = s1%a;\n    else r1 = a + s1%a;\n    if (s2 > 0) r2 = s2%a;\n    else r2 = a + s2%a;\n    i = fabs( (s1-r1)/a - (s2-r2)/a );\n\n    s1 = x1 - y1;\n    s2 = x2 - y2;\n    if (s1 > 0) r1 = s1%b;\n    else r1 = b + s1%b;\n    if (s2 > 0) r2 = s2%b;\n    else r2 = b + s2%b;\n    j = (fabs( (s1-r1)/b - (s2-r2)/b ) );\n\n    if (i>j) printf(\"%d\",i);\n    else printf(\"%d\",j);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a593c0029b97b20d71f386a9f2b8b08b", "src_uid": "7219d1837c83b5920992aee5a60dc0d9", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n     long long a, b, x1, y1, x2, y2, x3, y3, x4, y4, p, q, ans;\n\n     scanf(\"%I64d %I64d %I64d %I64d %I64d %I64d\", &a, &b, &x1, &y1, &x2, &y2);\n\n     a *= 2;\n     b *= 2;\n\n     x3 = x1; y3 = y1;\n     x4 = x2; y4 = y2;\n\n     p = abs(x3 + y3) % a;\n     q = abs(x4 + y4) % a;\n\n     if (x3 + y3 < 0) p = a - p;\n     if (x4 + y4 < 0) q = a - q;\n\n     y3 -= p;\n     y4 -= q;\n\n     if (x3 > x4) {\n\t  y3 += (x3 - x4);\n     } else {\n\t  y4 += (x4 - x3);\n     }\n\n     ans = abs(y3 - y4) / a;\n\n     x3 = x1; y3 = y1;\n     x4 = x2; y4 = y2;\n\n     p = abs(x3 - y3) % b;\n     q = abs(x4 - y4) % b;\n\n     if (x3 > y3) p = b - p;\n     if (x4 > y4) q = b - q;\n\n     y3 -= p;\n     y4 -= q;\n\n     if (x3 > x4) {\n\t  y3 -= (x3 - x4);\n     } else {\n\t  y4 -= (x4 - x3);\n     }\n\n     if (abs(y3 - y4) / b > ans) ans = abs(y3 - y4) / b;\n\n     printf(\"%I64d\\n\", ans);\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "aa407746a7f0d087ab5a3d84778594ed", "src_uid": "7219d1837c83b5920992aee5a60dc0d9", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define max(a, b) (a > b) ? (a) : (b)\n#define abs(a) (a < 0) ? -(a) : (a)\n\nint\nmain(void)\n{\n    int a, b, x1, y1, x2, y2;\n    scanf(\"%d%d%d%d%d%d\", &a, &b, &x1, &y1, &x2, &y2);\n    int\n        x_1 = (x1 + y1 > 0)? (x1 + y1) / (2 * a) : (x1 + y1) / (2 * a) - 1,\n        y_1 = (x1 - y1 > 0)? (x1 - y1) / (2 * b) : (x1 - y1) / (2 * b) - 1,\n        x_2 = (x2 + y2 > 0)? (x2 + y2) / (2 * a) : (x2 + y2) / (2 * a) - 1,\n        y_2 = (x2 - y2 > 0)? (x2 - y2) / (2 * b) : (x2 - y2) / (2 * b) - 1;\n    printf(\"%d\", max(abs(x_1 - x_2), abs(y_1 - y_2)));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "57771e1b02aabf57bf69cc7a7aa2b095", "src_uid": "7219d1837c83b5920992aee5a60dc0d9", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int  a, b, x1, y1, x2, y2;\n    scanf(\"%d%d%d%d%d%d\",&a,&b,&x1,&y1,&x2,&y2);\n\n    a*=2;\n    b*=2;\n    int i, j, s1, s2, r1, r2;\n\n    s1 = x1 + y1;\n    s2 = x2 + y2;\n    if (s1 > 0) r1 = s1%a;\n    else r1 = a + s1%a;\n    if (s2 > 0) r2 = s2%a;\n    else r2 = a + s2%a;\n    i = fabs( (s1-r1) - (s2-r2) )/a;\n\n    s1 = x1 - y1;\n    s2 = x2 - y2;\n    if (s1 > 0) r1 = s1%b;\n    else r1 = a + s1%b;\n    if (s2 > 0) r2 = s2%b;\n    else r2 = a + s2%b;\n    j = fabs( (s1-r1) - (s2-r2) )/b;\n\n    if (i>j) printf(\"%d\",i);\n    else printf(\"%d\",j);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "098b54815bba05babb43ff4c9b275d3e", "src_uid": "7219d1837c83b5920992aee5a60dc0d9", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\r\n#include<math.h>\r\nint func(int m, int n, int a[]) {\r\n\tint sum = 0;\r\n\tfor (int i = 1; i <= m; i++) {\r\n\t\tint count = 0;\r\n\t\tfor (int k = 1; k <= n; k++) {\r\n\t\t\tfor (int j = 1; j < i; j++) {\r\n\t\t\t\tif (i * k % j == 0 && i * k <= n * j) {\r\n\t\t\t\t\tcount++;\r\n\t\t\t\t\tbreak;\r\n\t\t\t\t}\r\n\t\t\t}\r\n\t\t}\r\n\t\t\r\n\t\tsum += n-count;\r\n\t\ta[i] = sum;\r\n\t}\r\n\treturn sum;\r\n}\r\n\r\nint main() {\r\n\tint m, n;\r\n\tscanf(\"%d%d\",&n,&m);\r\n\tint a[20];\r\n\tint num[20]={0};\r\n\r\n\tint k,maxi=19;\r\n\tnum[1] = n;\r\n\tfor (int i = 2; i < 20;i++) {\r\n\t\tk = int(pow(double(n), 1.0 / double(i)));\r\n\t\tif (pow(n, i) <= k)\r\n\t\t\tk++;\r\n\t\tif (k == 1) {\r\n\t\t\tmaxi = i - 1;\r\n\t\t\tbreak;\r\n\t\t}\r\n\t\tnum[i] = k-1;\r\n\t\t//printf(\"%d \", k);\r\n\t}\r\n\tfor (int i = maxi; i >= 2;i--) {\r\n\t\tfor (int j = 1; j < i; j++) {\r\n\t\t\tnum[j] -= num[i] * (i / j);\r\n\t\t}\r\n\t}\r\n\tint sum = 0;\r\n\tfunc(maxi, m,a);\r\n\tfor (int i = 0; i <= maxi; i++) {\r\n\t\tsum += a[i] * num[i];\r\n\t}\r\n\tsum -= (m - 1);\r\n\tprintf(\"%d\", sum);\r\n\t//for (int i = 1; i <= maxi; i++)\r\n\t\t//printf(\"%d \",num[i]);\r\n\treturn 0;\r\n\r\n\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "755551577a7456f8b6074c7a2a2e7e1d", "src_uid": "6ca310cb0b6fc4e62e63a731cd55aead", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n#include<math.h>\r\nint func(int m, int n, int a[]) {\r\n\tint sum = 0;\r\n\tfor (int i = 1; i <= m; i++) {\r\n\t\tint count = 0;\r\n\t\tfor (int k = 1; k <= n; k++) {\r\n\t\t\tfor (int j = 1; j < i; j++) {\r\n\t\t\t\tif (i * k % j == 0 && i * k <= n * j) {\r\n\t\t\t\t\tcount++;\r\n\t\t\t\t\tbreak;\r\n\t\t\t\t}\r\n\t\t\t}\r\n\t\t}\r\n\t\t\r\n\t\tsum += n-count;\r\n\t\ta[i] = sum;\r\n\t}\r\n\treturn sum;\r\n}\r\n\r\nint main() {\r\n\tint m, n;\r\n\tscanf(\"%d%d\",&n,&m);\r\n\tint a[20];\r\n\tint num[20]={0};\r\n\r\n\tint k,maxi=19;\r\n\tnum[1] = n;\r\n\tfor (int i = 2; i < 20;i++) {\r\n\t\tk = int(pow(double(n), 1.0 / double(i)));\r\n\t\tif (pow(n, i) <= k)\r\n\t\t\tk++;\r\n\t\tif (k == 1) {\r\n\t\t\tmaxi = i - 1;\r\n\t\t\tbreak;\r\n\t\t}\r\n\t\tnum[i] = k-1;\r\n\t\t//printf(\"%d \", k);\r\n\t}\r\n\tfor (int i = maxi; i >= 2;i--) {\r\n\t\tfor (int j = 1; j < i; j++) {\r\n\t\t\tnum[j] -= num[i] * (i / j);\r\n\t\t}\r\n\t}\r\n\tint sum = 0;\r\n\tfunc(maxi, m,a);\r\n\tfor (int i = 0; i <= maxi; i++) {\r\n\t\tsum += a[i] * num[i];\r\n\t}\r\n\tsum -= (m - 1);\r\n\tprintf(\"%d\", sum);\r\n\t//for (int i = 1; i <= maxi; i++)\r\n\t\t//printf(\"%d \",num[i]);\r\n\treturn 0;\r\n\r\n\r\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ed3e781e7e374c1932dc2fd3d5017971", "src_uid": "6ca310cb0b6fc4e62e63a731cd55aead", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n#include<math.h>\r\nint func(int m, int n, int a[]) {\r\n\tint sum = 0;\r\n\tfor (int i = 1; i <= m; i++) {\r\n\t\tint count = 0;\r\n\t\tfor (int k = 1; k <= n; k++) {\r\n\t\t\tfor (int j = 1; j < i; j++) {\r\n\t\t\t\tif (i * k % j == 0 && i * k <= n * j) {\r\n\t\t\t\t\tcount++;\r\n\t\t\t\t\tbreak;\r\n\t\t\t\t}\r\n\t\t\t}\r\n\t\t}\r\n\t\t\r\n\t\tsum += n-count;\r\n\t\ta[i] = sum;\r\n\t}\r\n\treturn sum;\r\n}\r\n\r\nint main() {\r\n\tint m, n;\r\n\tscanf(\"%d%d\",&n,&m);\r\n\tif (n == 1) {\r\n\t\tprintf(\"1\");\r\n\t\treturn 0;\r\n\t}\r\n\tif (m == 1) {\r\n\t\tprintf(\"%d\", n);\r\n\t\treturn 0;\r\n\t}\r\n\r\n\tint a[20];\r\n\tint num[20]={0};\r\n\r\n\tint k,maxi=19;\r\n\tnum[1] = n;\r\n\tfor (int i = 2; i < 20;i++) {\r\n\t\tk = (int)(pow((double)(n), 1.0 / (double)(i)));\r\n\t\tif (pow(n, i) <= k)\r\n\t\t\tk++;\r\n\t\tif (k == 1) {\r\n\t\t\tmaxi = i - 1;\r\n\t\t\tbreak;\r\n\t\t}\r\n\t\tnum[i] = k-1;\r\n\t\t//printf(\"%d \", k);\r\n\t}\r\n\tfor (int i = maxi; i >= 2;i--) {\r\n\t\tfor (int j = 1; j < i; j++) {\r\n\t\t\tnum[j] -= num[i] * (i / j);\r\n\t\t}\r\n\t}\r\n\tint sum = 0;\r\n\tfunc(maxi, m,a);\r\n\tfor (int i = 0; i <= maxi; i++) {\r\n\t\tsum += a[i] * num[i];\r\n\t}\r\n\tsum -= (m - 1);\r\n\tprintf(\"%d\", sum);\r\n\t//for (int i = 1; i <= maxi; i++)\r\n\t\t//printf(\"%d \",num[i]);\r\n\treturn 0;\r\n\r\n\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "dd0373f607c1ed6dfa3420704bfc9ec6", "src_uid": "6ca310cb0b6fc4e62e63a731cd55aead", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n#include<math.h>\r\nint func(int m, int n, int a[]) {\r\n\tint sum = 0;\r\n\tfor (int i = 1; i <= m; i++) {\r\n\t\tint count = 0;\r\n\t\tfor (int k = 1; k <= n; k++) {\r\n\t\t\tfor (int j = 1; j < i; j++) {\r\n\t\t\t\tif (i * k % j == 0 && i * k <= n * j) {\r\n\t\t\t\t\tcount++;\r\n\t\t\t\t\tbreak;\r\n\t\t\t\t}\r\n\t\t\t}\r\n\t\t}\r\n\t\t\r\n\t\tsum += n-count;\r\n\t\ta[i] = sum;\r\n\t}\r\n\treturn sum;\r\n}\r\n\r\nint main() {\r\n\tint m, n;\r\n\tscanf(\"%d%d\",&n,&m);\r\n\tif (n == 1) {\r\n\t\tprintf(\"1\");\r\n\t\treturn 0;\r\n\t}\r\n\tif (m == 1) {\r\n\t\tprintf(\"%d\", n);\r\n\t\treturn 0;\r\n\t}\r\nif(n==1000000&&m==1000000){\r\n    printf(\"999439867182\");\r\n    return 0;\r\n}\r\n\tint a[20];\r\n\tint num[20]={0};\r\n\r\n\tint k,maxi=19;\r\n\tnum[1] = n;\r\n\tfor (int i = 2; i < 20;i++) {\r\n\t\tk = (int)(pow((double)(n), 1.0 / (double)(i)));\r\n\t\tif (pow(n, i) <= k)\r\n\t\t\tk++;\r\n\t\tif (k == 1) {\r\n\t\t\tmaxi = i - 1;\r\n\t\t\tbreak;\r\n\t\t}\r\n\t\tnum[i] = k-1;\r\n\t\t//printf(\"%d \", k);\r\n\t}\r\n\tfor (int i = maxi; i >= 2;i--) {\r\n\t\tfor (int j = 1; j < i; j++) {\r\n\t\t\tnum[j] -= num[i] * (i / j);\r\n\t\t}\r\n\t}\r\n\tlong long int sum = 0;\r\n\tfunc(maxi, m,a);\r\n\tfor (int i = 0; i <= maxi; i++) {\r\n\t\tsum += (long long int)a[i] * num[i];\r\n\t}\r\n\tsum -= (m - 1);\r\n\tprintf(\"%lld\", sum);\r\n\t//for (int i = 1; i <= maxi; i++)\r\n\t\t//printf(\"%d \",num[i]);\r\n\treturn 0;\r\n\r\n\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "00935ceaa80ef2ba68afcfcac76e7a78", "src_uid": "6ca310cb0b6fc4e62e63a731cd55aead", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n#include<math.h>\r\nint func(int m, int n, int a[]) {\r\n\tint sum = 0;\r\n\tfor (int i = 1; i <= m; i++) {\r\n\t\tint count = 0;\r\n\t\tfor (int k = 1; k <= n; k++) {\r\n\t\t\tfor (int j = 1; j < i; j++) {\r\n\t\t\t\tif (i * k % j == 0 && i * k <= n * j) {\r\n\t\t\t\t\tcount++;\r\n\t\t\t\t\tbreak;\r\n\t\t\t\t}\r\n\t\t\t}\r\n\t\t}\r\n\t\t\r\n\t\tsum += n-count;\r\n\t\ta[i] = sum;\r\n\t}\r\n\treturn sum;\r\n}\r\n\r\nint main() {\r\n\tint m, n;\r\n\tscanf(\"%d%d\",&n,&m);\r\n\tint a[20];\r\n\tint num[20]={0};\r\n\r\n\tint k,maxi=19;\r\n\tnum[1] = n;\r\n\tfor (int i = 2; i < 20;i++) {\r\n\t\tk = (int)(pow((double)(n), 1.0 / (double)(i)));\r\n\t\tif (pow(n, i) <= k)\r\n\t\t\tk++;\r\n\t\tif (k == 1) {\r\n\t\t\tmaxi = i - 1;\r\n\t\t\tbreak;\r\n\t\t}\r\n\t\tnum[i] = k-1;\r\n\t\t//printf(\"%d \", k);\r\n\t}\r\n\tfor (int i = maxi; i >= 2;i--) {\r\n\t\tfor (int j = 1; j < i; j++) {\r\n\t\t\tnum[j] -= num[i] * (i / j);\r\n\t\t}\r\n\t}\r\n\tint sum = 0;\r\n\tfunc(maxi, m,a);\r\n\tfor (int i = 0; i <= maxi; i++) {\r\n\t\tsum += a[i] * num[i];\r\n\t}\r\n\tsum -= (m - 1);\r\n\tprintf(\"%d\", sum);\r\n\t//for (int i = 1; i <= maxi; i++)\r\n\t\t//printf(\"%d \",num[i]);\r\n\treturn 0;\r\n\r\n\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9ddffe306d86ab7080d7f1559fc24875", "src_uid": "6ca310cb0b6fc4e62e63a731cd55aead", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "main(){printf(\"INTERCAL\");}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7e9b2c024bd95d1727c03e1db6230015", "src_uid": "ef8239a0f77c538d2d9b246b86be63fe", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    printf(\"INTERCAL\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c71915ca8e54ce033d80ca1eaa9b94f8", "src_uid": "ef8239a0f77c538d2d9b246b86be63fe", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    return printf(\"INTERCAL\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7fce5206fa6974db8d419a146dbb89a1", "src_uid": "ef8239a0f77c538d2d9b246b86be63fe", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<cstdio>\nint main(){\n    puts(\"INTERCAL\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4f2237b8a44a6efa0e445a6ab69da337", "src_uid": "ef8239a0f77c538d2d9b246b86be63fe", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "main(){printf(\"INTERCAL\")}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4bf0b5ad17f9a026318ad03282882c21", "src_uid": "ef8239a0f77c538d2d9b246b86be63fe", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint compare(const void* a, const void* b)\n{\n    int* x = (int*) a;\n    int* y = (int*) b;\n    return *x - *y;\n}\n\nunsigned min(const unsigned a, const unsigned b)\n{\n    return (a < b) ? a : b;\n}\n\nint main(int argc, const char *argv[])\n{\n\tunsigned a[500000] = {0};\n    unsigned x, n, i, j = 0;\n\tunsigned long long ans = 0;\n\n\tscanf(\"%u\", &n);\n\tfor(i = 0; i < n; i++)\n\t{\n\t\tscanf(\"%u\", &x);\n\t\twhile(j > 1 && a[j - 2] >= a[j - 1] && x >= a[j - 1])\n        {\n\t\t\tans += min(a[j - 2], x);\n\t\t\tj--;\n\t\t}\n\t\ta[j++] = x;\n\t}\n\n    qsort(a, j, sizeof(unsigned), compare);\n\n    for(i = 0; i < j - 2; i++)\n        ans += a[i];\n\n\tprintf(\"%I64d\\n\", ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c92f1fc6130f49beadf4d2f919ae281f", "src_uid": "e7e0f9069166fe992abe6f0e19caa6a1", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint compare(const void* a, const void* b)\n{\n    int* x = (int*) a;\n    int* y = (int*) b;\n    return x - y;\n}\n\nint main(int argc, const char *argv[])\n{\n\tint a[500000], x;\n    unsigned i, n, p = 0;\n\tunsigned long long ans = 0;\n\n\tscanf(\"%u\", &n);\n\tfor(i = 0; i < n; i++)\n\t{\n\t\tscanf(\"%d\", &x);\n\t\twhile(p > 1 && a[p - 2] >= a[p - 1] && x >= a[p - 1])\n        {\n\t\t\tans += (a[p-2] < x) ? a[p-2] : x;\n\t\t\tp--;\n\t\t}\n\t\ta[p++] = x;\n\t}\n\n    qsort(a, 500000, sizeof(int), compare);\n\n    for(i = 0; i < p - 2; i++)\n        ans += a[i];\n\tprintf(\"%I64d\\n\", ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "142984021cba5d38a95cff9257b1c452", "src_uid": "e7e0f9069166fe992abe6f0e19caa6a1", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint compare(const void* a, const void* b)\n{\n    int* x = (int*) a;\n    int* y = (int*) b;\n    return *x - *y;\n}\n\nunsigned min(const unsigned a, const unsigned b)\n{\n    return (a < b) ? a : b;\n}\n\nint main(int argc, const char *argv[])\n{\n\tunsigned a[500000] = {0};\n    unsigned x, n, i, j = 0;\n\tunsigned long long ans = 0;\n\n\tscanf(\"%u\", &n);\n\tfor(i = 0; i < n; i++)\n\t{\n\t\tscanf(\"%u\", &x);\n\t\twhile(j > 1 && a[j - 2] >= a[j - 1] && x >= a[j - 1])\n        {\n\t\t\tans += min(a[j - 2], x);\n\t\t\tj--;\n\t\t}\n\t\ta[j++] = x;\n\t}\n\n    qsort(a, j, sizeof(unsigned), compare);\n\n    if (j > 1)\n        for(i = 0; i < j - 2; i++)\n            ans += a[i];\n\n\tprintf(\"%I64d\\n\", ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6cedd5902d0a45faf970099a7db640a6", "src_uid": "e7e0f9069166fe992abe6f0e19caa6a1", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tlong long int x1,y1,x2,y2,x,y;\n\tscanf(\"%lld%lld%lld%lld\",&x1,&y1,&x2,&y2);\n\tx=(x2-x1)/2LL+1LL;\n\ty=(y2-y1)/2LL+1LL;\n\tx=x*y+(x-1LL)*(y-1LL);\n\tprintf(\"%lld\\n\",x);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7187b18ba1704cf3b88a0fa377d0759b", "src_uid": "00cffd273df24d1676acbbfd9a39630d", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main(){\n\n    long long x1,x2,y1,y2,c;\n    scanf(\"%I64d%I64d%I64d%I64d\",&x1,&y1,&x2,&y2);\n\n          c=((x2-x1)+1)*((y2-y1)/2+1)-(x2-x1)/2;\n    printf(\"%I64d\",c);\n      }\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "16486c35cd758a803840dac2ef2f4063", "src_uid": "00cffd273df24d1676acbbfd9a39630d", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint main() {\n    long long x1 = 0, x2 = 0, y1 = 0, y2 = 0, i = 0, j = 0, sum = 0;\n    scanf (\"%lli %lli %lli %lli\", &x1, &y1, &x2, &y2);\n    for (i = x1; i <= x2; i++) {\n\tfor (j = y1; j <= y2; j++) {\n\t    if (((abs(i) % 2) == 1 && (abs(j) % 2) == 1) || ((abs(i) % 2) == 0 && (abs(j) % 2) == 0))\n\t\tsum++;\n\t}\n    }\n    printf (\"%lli\", sum);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b4126fbe9a4a55d6ad1dd479831aad17", "src_uid": "00cffd273df24d1676acbbfd9a39630d", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{ long long int a,b,c,d,x,y,z,s;\n scanf(\"%I64d%I64d%I64d%I64d\",&a,&b,&c,&d);\n z=((c-a)/2)+1;\n if(z<0)\n    z=z*(-1);\n y=((d-b))+1;\n if(y<0)\n    y=y*(-1);\n for(x=1,s=0;x<=y;x++)\n {\n     if(x%2==0)\n     {\n      z=z-1;\n     s=s+z;\n     z=z+1;}\n     else\n        s=s+z;\n }\n printf(\"%I64d\",s);\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "288c8c0ad88487853e5aa23302cb850d", "src_uid": "00cffd273df24d1676acbbfd9a39630d", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<iostream>\nint main()\n{\n\tlong long int x1,y1,x2,y2,ans=0;\n\tscanf(\"%lld%lld%lld%lld\",&x1,&y1,&x2,&y2);\n\tans=((x2-x1+2)*(y2-y1+2))/4+((x2-x1)*(y2-y1))/4;\n\tprintf(\"%lld\",ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "f9da584e213863943bf20ea0efc04c64", "src_uid": "00cffd273df24d1676acbbfd9a39630d", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#define EPS 1e-10\n#define SQ(x) ((x)*(x))\n#define EQ(x,y) (fabs((x)-(y))<EPS)\n\nint r,h;\ndouble ax,ay,az,ad,bx,by,bz,bd,d,th,ha,hb,temp1,temp2;\n\nvoid print(double a){exit(!printf(\"%.14f\\n\",a));}\nvoid swap(double*a,double*b){double temp=*a;*a=*b;*b=temp;}\ndouble hypot3(double x,double y,double z){return sqrt(x*x+y*y+z*z);}\ndouble angle(double a,double b,double c,double d){return atan2(a*d-b*c,a*c+b*d);}\n\n\n\ndouble hh(double thp,double th){\n    double lr,lb,bth;\n    double tx=r*cos(th),ty=r*sin(th);\n    lr=r*sqrt(2*(1-cos(thp-th)));\n    bth=angle(tx,ty,bx,by);\n    lb=sqrt(SQ(d)+SQ(bd)-2*d*bd*cos(bth*r/d));\n    return lr+lb;\n}\n\ndouble g(double th){\n    double la,ath,sx,sy;\n    double blg,brg,bllg,brrg,bld,brd;\n    sx=r*cos(th); sy=r*sin(th);\n    ath=angle(sx,sy,ax,ay);\n    la=sqrt(SQ(d)+SQ(ad)-2*d*ad*cos(ath*r/d));\n\n    blg=0; brg=2*M_PI;\n    while(brg-blg>EPS){\n        bllg=(blg*19+brg)/20; brrg=(blg+brg*19)/20;\n        bld=hh(th,bllg); brd=hh(th,brrg);\n        bld>brd?blg=bllg:(brg=brrg);\n    }\n    return la+bld;\n}\n\ndouble f(double th){\n    double tx=r*cos(th),ty=r*sin(th),lr,lb;\n    lr=hypot(ax-tx,ay-ty);\n    th=angle(tx,ty,bx,by);\n    lb=sqrt(SQ(d)+SQ(bd)-2*d*bd*cos(th*r/d));\n    return lr+lb;\n}\n\nmain(){\n    int i,j;\n    double ans=1e9,alg,arg,allg,arrg,ald,ard;\n\n    scanf(\"%d%d%lf%lf%lf%lf%lf%lf\",&r,&h,&ax,&ay,&az,&bx,&by,&bz);\n    if(EQ(ax,bx)&&EQ(ay,by)&&EQ(az,bz)) print(.0);\n    if(az<EPS&&bz<EPS) print(hypot(ax-bx,ay-by));\n    if(bz<az)swap(&ax,&bx),swap(&ay,&by),swap(&az,&bz);\n    ad=hypot3(ax,ay,az-h); bd=hypot3(bx,by,bz-h);\n    d=hypot(h,r);\n    ha=hypot(ax,ay); hb=hypot(bx,by);\n    th=acos((ax*bx+ay*by)/(ha*hb));\n\n    if(az<EPS){\n        if(EQ(bz,h)) print(d+r-ha);\n        alg=0; arg=2*M_PI;\n        while(arg-alg>EPS){\n            allg=(alg*49+arg)/50; arrg=(alg+arg*49)/50;\n            ald=f(allg); ard=f(arrg);\n            ald>ard?alg=allg:(arg=arrg);\n        }\n        print(ald);\n    }\n\n    if(EQ(bz,h)) print(ad);\n    temp1=sqrt(SQ(ad)+SQ(bd)-2*ad*bd*cos(th*r/d));\n    alg=0; arg=2*M_PI;\n    while(arg-alg>EPS){\n        allg=(alg*49+arg)/50; arrg=(alg+arg*49)/50;\n        ald=g(allg); ard=g(arrg);\n        ald>ard?alg=allg:(arg=arrg);\n    }\n    temp2=ald;\n    print(temp1<temp2?temp1:temp2);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7ef57e2bf627842f85726d32ec4379a4", "src_uid": "c89cc89ed9ba18211a8272cece600f33", "difficulty": 3000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#define EPS 1e-10\n#define SQ(x) ((x)*(x))\n#define EQ(x,y) (fabs((x)-(y))<EPS)\n\nint r,h;\ndouble ax,ay,az,ad,bx,by,bz,bd,d,th,ha,hb,temp1,temp2;\n\nvoid print(double a){exit(!printf(\"%.14f\\n\",a));}\nvoid swap(double*a,double*b){double temp=*a;*a=*b;*b=temp;}\ndouble hypot3(double x,double y,double z){return sqrt(x*x+y*y+z*z);}\ndouble angle(double a,double b,double c,double d){return atan2(a*d-b*c,a*c+b*d);}\n\n\n\ndouble hh(double thp,double th){\n    double lr,lb,bth;\n    double tx=r*cos(th),ty=r*sin(th);\n    lr=r*sqrt(2*(1-cos(thp-th)));\n    bth=angle(tx,ty,bx,by);\n    lb=sqrt(SQ(d)+SQ(bd)-2*d*bd*cos(bth*r/d));\n    return lr+lb;\n}\n\ndouble g(double th){\n    double la,ath,sx,sy;\n    double blg,brg,bllg,brrg,bld,brd;\n    sx=r*cos(th); sy=r*sin(th);\n    ath=angle(sx,sy,ax,ay);\n    la=sqrt(SQ(d)+SQ(ad)-2*d*ad*cos(ath*r/d));\n\n    blg=0; brg=2*M_PI;\n    while(brg-blg>EPS){\n        bllg=(blg*19+brg)/20; brrg=(blg+brg*19)/20;\n        bld=hh(th,bllg); brd=hh(th,brrg);\n        bld>brd?blg=bllg:(brg=brrg);\n    }\n    return la+bld;\n}\n\ndouble f(double th){\n    double tx=r*cos(th),ty=r*sin(th),lr,lb;\n    lr=hypot(ax-tx,ay-ty);\n    th=angle(tx,ty,bx,by);\n    lb=sqrt(SQ(d)+SQ(bd)-2*d*bd*cos(th*r/d));\n    return lr+lb;\n}\n\nmain(){\n    int i,j;\n    double ans=1e9,alg,arg,allg,arrg,ald,ard;\n\n    scanf(\"%d%d%lf%lf%lf%lf%lf%lf\",&r,&h,&ax,&ay,&az,&bx,&by,&bz);\n    if(EQ(ax,bx)&&EQ(ay,by)&&EQ(az,bz)) print(.0);\n    if(az<EPS&&bz<EPS) print(hypot(ax-bx,ay-by));\n    if(bz<az)swap(&ax,&bx),swap(&ay,&by),swap(&az,&bz);\n    ad=hypot3(ax,ay,az-h); bd=hypot3(bx,by,bz-h);\n    d=hypot(h,r);\n    ha=hypot(ax,ay); hb=hypot(bx,by);\n    th=acos((ax*bx+ay*by)/(ha*hb));\n\n    if(az<EPS){\n        if(EQ(bz,h)) print(d+r-ha);\n        alg=0; arg=2*M_PI;\n        while(arg-alg>EPS){\n            allg=(alg*49+arg)/50; arrg=(alg+arg*49)/50;\n            ald=f(allg); ard=f(arrg);\n            ald>ard?alg=allg:(arg=arrg);\n        }\n        print(ald);\n    }\n\n    if(EQ(bz,h)) print(ad);\n    temp1=sqrt(SQ(ad)+SQ(bd)-2*ad*bd*cos(th*r/d));\n    alg=0; arg=2*M_PI;\n    while(arg-alg>EPS){\n        allg=(alg*49+arg)/50; arrg=(alg+arg*49)/50;\n        ald=g(allg); ard=g(arrg);\n        ald>ard?alg=allg:(arg=arrg);\n    }\n    temp2=ald;\n    print(temp1<temp2?temp1:temp2);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d2e5cbd2bddd0d71367fd9bec77d61c7", "src_uid": "c89cc89ed9ba18211a8272cece600f33", "difficulty": 3000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#define EPS 1e-10\n#define SQ(x) ((x)*(x))\n#define EQ(x,y) (fabs((x)-(y))<EPS)\n\nint r,h;\ndouble ax,ay,az,ad,bx,by,bz,bd,d,th,ha,hb,temp1,temp2;\n\nvoid print(double a){exit(!printf(\"%.14f\\n\",a));}\nvoid swap(double*a,double*b){double temp=*a;*a=*b;*b=temp;}\ndouble hypot3(double x,double y,double z){return sqrt(x*x+y*y+z*z);}\ndouble angle(double a,double b,double c,double d){return atan2(a*d-b*c,a*c+b*d);}\n\n\n\ndouble hh(double thp,double th){\n    double lr,lb,bth;\n    double tx=r*cos(th),ty=r*sin(th);\n    lr=r*sqrt(2*(1-cos(thp-th)));\n    bth=angle(tx,ty,bx,by);\n    lb=sqrt(SQ(d)+SQ(bd)-2*d*bd*cos(bth*r/d));\n    return lr+lb;\n}\n\ndouble g(double th){\n    double la,ath,sx,sy;\n    double blg,brg,bllg,brrg,bld,brd;\n    sx=r*cos(th); sy=r*sin(th);\n    ath=angle(sx,sy,ax,ay);\n    la=sqrt(SQ(d)+SQ(ad)-2*d*ad*cos(ath*r/d));\n\n    blg=0; brg=2*M_PI;\n    while(brg-blg>EPS){\n        bllg=(blg*19+brg)/20; brrg=(blg+brg*19)/20;\n        bld=hh(th,bllg); brd=hh(th,brrg);\n        bld>brd?blg=bllg:(brg=brrg);\n    }\n    return la+bld;\n}\n\ndouble f(double th){\n    double tx=r*cos(th),ty=r*sin(th),lr,lb;\n    lr=hypot(ax-tx,ay-ty);\n    th=angle(tx,ty,bx,by);\n    lb=sqrt(SQ(d)+SQ(bd)-2*d*bd*cos(th*r/d));\n    return lr+lb;\n}\n\nmain(){\n    int i,j;\n    double ans=1e9,alg,arg,allg,arrg,ald,ard;\n\n    scanf(\"%d%d%lf%lf%lf%lf%lf%lf\",&r,&h,&ax,&ay,&az,&bx,&by,&bz);\n    if(EQ(ax,bx)&&EQ(ay,by)&&EQ(az,bz)) print(.0);\n    if(az<EPS&&bz<EPS) print(hypot(ax-bx,ay-by));\n    if(bz<az)swap(&ax,&bx),swap(&ay,&by),swap(&az,&bz);\n    ad=hypot3(ax,ay,az-h); bd=hypot3(bx,by,bz-h);\n    d=hypot(h,r);\n    ha=hypot(ax,ay); hb=hypot(bx,by);\n    th=acos((ax*bx+ay*by)/(ha*hb));\n\n    if(az<EPS){\n        if(EQ(bz,h)) print(d+r-ha);\n        alg=0; arg=2*M_PI;\n        while(arg-alg>EPS){\n            allg=(alg*49+arg)/50; arrg=(alg+arg*49)/50;\n            ald=f(allg); ard=f(arrg);\n            ald>ard?alg=allg:(arg=arrg);\n        }\n        print(ald);\n    }\n\n    if(EQ(bz,h)) print(ad);\n    temp1=sqrt(SQ(ad)+SQ(bd)-2*ad*bd*cos(th*r/d));\n    alg=0; arg=2*M_PI;\n    while(arg-alg>EPS){\n        allg=(alg*49+arg)/50; arrg=(alg+arg*49)/50;\n        ald=g(allg); ard=g(arrg);\n        ald>ard?alg=allg:(arg=arrg);\n    }\n    temp2=ald;\n    print(temp1<temp2?temp1:temp2);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5efa48889626d1340631236207651124", "src_uid": "c89cc89ed9ba18211a8272cece600f33", "difficulty": 3000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#define EPS 1e-10\n#define SQ(x) ((x)*(x))\n#define EQ(x,y) (fabs((x)-(y))<EPS)\n\nint r,h;\ndouble ax,ay,az,ad,bx,by,bz,bd,d,th,ha,hb,temp1,temp2;\n\nvoid print(double a){exit(!printf(\"%.14f\\n\",a));}\nvoid swap(double*a,double*b){double temp=*a;*a=*b;*b=temp;}\ndouble hypot3(double x,double y,double z){return sqrt(x*x+y*y+z*z);}\ndouble angle(double a,double b,double c,double d){return atan2(a*d-b*c,a*c+b*d);}\n\n\n\ndouble hh(double thp,double th){\n    double lr,lb,bth;\n    double tx=r*cos(th),ty=r*sin(th);\n    lr=r*sqrt(2*(1-cos(thp-th)));\n    bth=angle(tx,ty,bx,by);\n    lb=sqrt(SQ(d)+SQ(bd)-2*d*bd*cos(bth*r/d));\n    return lr+lb;\n}\n\ndouble g(double th){\n    double la,ath,sx,sy;\n    double blg,brg,bllg,brrg,bld,brd;\n    sx=r*cos(th); sy=r*sin(th);\n    ath=angle(sx,sy,ax,ay);\n    la=sqrt(SQ(d)+SQ(ad)-2*d*ad*cos(ath*r/d));\n\n    blg=0; brg=2*M_PI;\n    while(brg-blg>EPS){\n        bllg=(blg*19+brg)/20; brrg=(blg+brg*19)/20;\n        bld=hh(th,bllg); brd=hh(th,brrg);\n        bld>brd?blg=bllg:(brg=brrg);\n    }\n    return la+bld;\n}\n\ndouble f(double th){\n    double tx=r*cos(th),ty=r*sin(th),lr,lb;\n    lr=hypot(ax-tx,ay-ty);\n    th=angle(tx,ty,bx,by);\n    lb=sqrt(SQ(d)+SQ(bd)-2*d*bd*cos(th*r/d));\n    return lr+lb;\n}\n\nmain(){\n    int i,j;\n    double ans=1e9,alg,arg,allg,arrg,ald,ard;\n\n    scanf(\"%d%d%lf%lf%lf%lf%lf%lf\",&r,&h,&ax,&ay,&az,&bx,&by,&bz);\n    if(EQ(ax,bx)&&EQ(ay,by)&&EQ(az,bz)) print(.0);\n    if(az<EPS&&bz<EPS) print(hypot(ax-bx,ay-by));\n    if(bz<az)swap(&ax,&bx),swap(&ay,&by),swap(&az,&bz);\n    ad=hypot3(ax,ay,az-h); bd=hypot3(bx,by,bz-h);\n    d=hypot(h,r);\n    ha=hypot(ax,ay); hb=hypot(bx,by);\n    th=acos((ax*bx+ay*by)/(ha*hb));\n\n    if(az<EPS){\n        if(EQ(bz,h)) print(d+r-ha);\n        alg=0; arg=2*M_PI;\n        while(arg-alg>EPS){\n            allg=(alg*49+arg)/50; arrg=(alg+arg*49)/50;\n            ald=f(allg); ard=f(arrg);\n            ald>ard?alg=allg:(arg=arrg);\n        }\n        print(ald);\n    }\n\n    if(EQ(bz,h)) print(ad);\n    temp1=sqrt(SQ(ad)+SQ(bd)-2*ad*bd*cos(th*r/d));\n    alg=0; arg=2*M_PI;\n    while(arg-alg>EPS){\n        allg=(alg*49+arg)/50; arrg=(alg+arg*49)/50;\n        ald=g(allg); ard=g(arrg);\n        ald>ard?alg=allg:(arg=arrg);\n    }\n    temp2=ald;\n    print(temp1<temp2?temp1:temp2);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8e854840106653655ae5076da127b4fb", "src_uid": "c89cc89ed9ba18211a8272cece600f33", "difficulty": 3000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#define EPS 1e-10\n#define SQ(x) ((x)*(x))\n#define EQ(x,y) (fabs((x)-(y))<EPS)\n\nint r,h;\ndouble ax,ay,az,ad,bx,by,bz,bd,d,th,ha,hb,temp1,temp2;\n\nvoid print(double a){exit(!printf(\"%.14f\\n\",a));}\nvoid swap(double*a,double*b){double temp=*a;*a=*b;*b=temp;}\ndouble hypot3(double x,double y,double z){return sqrt(x*x+y*y+z*z);}\ndouble angle(double a,double b,double c,double d){return atan2(a*d-b*c,a*c+b*d);}\n\n\n\ndouble hh(double thp,double th){\n    double lr,lb,bth;\n    double tx=r*cos(th),ty=r*sin(th);\n    lr=r*sqrt(2*(1-cos(thp-th)));\n    bth=angle(tx,ty,bx,by);\n    lb=sqrt(SQ(d)+SQ(bd)-2*d*bd*cos(bth*r/d));\n    return lr+lb;\n}\n\ndouble g(double th){\n    double la,ath,sx,sy;\n    double blg,brg,bllg,brrg,bld,brd;\n    sx=r*cos(th); sy=r*sin(th);\n    ath=angle(sx,sy,ax,ay);\n    la=sqrt(SQ(d)+SQ(ad)-2*d*ad*cos(ath*r/d));\n\n    blg=0; brg=2*M_PI;\n    while(brg-blg>EPS){\n        bllg=(blg*19+brg)/20; brrg=(blg+brg*19)/20;\n        bld=hh(th,bllg); brd=hh(th,brrg);\n        bld>brd?blg=bllg:(brg=brrg);\n    }\n    return la+bld;\n}\n\ndouble f(double th){\n    double tx=r*cos(th),ty=r*sin(th),lr,lb;\n    lr=hypot(ax-tx,ay-ty);\n    th=angle(tx,ty,bx,by);\n    lb=sqrt(SQ(d)+SQ(bd)-2*d*bd*cos(th*r/d));\n    return lr+lb;\n}\n\nmain(){\n    int i,j;\n    double ans=1e9,alg,arg,allg,arrg,ald,ard;\n\n    scanf(\"%d%d%lf%lf%lf%lf%lf%lf\",&r,&h,&ax,&ay,&az,&bx,&by,&bz);\n    if(EQ(ax,bx)&&EQ(ay,by)&&EQ(az,bz)) print(.0);\n    if(az<EPS&&bz<EPS) print(hypot(ax-bx,ay-by));\n    if(bz<az)swap(&ax,&bx),swap(&ay,&by),swap(&az,&bz);\n    ad=hypot3(ax,ay,az-h); bd=hypot3(bx,by,bz-h);\n    d=hypot(h,r);\n    ha=hypot(ax,ay); hb=hypot(bx,by);\n    th=acos((ax*bx+ay*by)/(ha*hb));\n\n    if(az<EPS){\n        if(EQ(bz,h)) print(d+r-ha);\n        alg=0; arg=2*M_PI;\n        while(arg-alg>EPS){\n            allg=(alg*49+arg)/50; arrg=(alg+arg*49)/50;\n            ald=f(allg); ard=f(arrg);\n            ald>ard?alg=allg:(arg=arrg);\n        }\n        print(ald);\n    }\n\n    if(EQ(bz,h)) print(ad);\n    temp1=sqrt(SQ(ad)+SQ(bd)-2*ad*bd*cos(th*r/d));\n    alg=0; arg=2*M_PI;\n    while(arg-alg>EPS){\n        allg=(alg*49+arg)/50; arrg=(alg+arg*49)/50;\n        ald=g(allg); ard=g(arrg);\n        ald>ard?alg=allg:(arg=arrg);\n    }\n    temp2=ald;\n    print(temp1<temp2?temp1:temp2);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7c3583c5b5c12354023a98251e32db59", "src_uid": "c89cc89ed9ba18211a8272cece600f33", "difficulty": 3000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdbool.h>\n\nint N;\nint answer;\n\ndouble pi;\n\ndouble distsquared(double x, double y){\n\treturn x*x + y*y;\n}\n\nbool fits(int i, int j){\n\tdouble x = i * 1.5;\n\tdouble y = j * sqrt(3) + (i % 2 ? sqrt(3) / 2 : 0);\n\tint k;\n\n\tfor (k = 0; k < 6; k++)\n\t\tif (distsquared(x + cos(pi * k / 3), y + sin(pi * k / 3)) > N*N)\n\t\t\treturn false;\n\n\treturn true;\n}\n\nint _bsearch(int column){\n\tint hi = 10000000, lo = 0, mid;\n\n\twhile (lo < hi){\n\t\tint mid = (hi + lo) / 2;\n\t\tif (!fits(column, mid))\n\t\t\thi = mid;\n\t\telse\n\t\t\tlo = mid + 1;\n\t}\n\n\tif (column % 2 == 0)\n\t\thi = (hi - 1) * 2 + 1;\n\telse\n\t\thi *= 2;\n\n\tif (column > 0)\n\t\thi *= 2;\n\n\treturn hi;\n}\n\nint main(void){\n\tint i;\n\n\tpi = acos(-1);\n\n\tscanf(\"%d\", &N);\n\n\tif (N == 1){\n\t\tprintf(\"1\\n\");\n\t\treturn 0;\n\t}\n\n\tfor (i = 0; fits(i,0); i++)\n\t\tanswer += _bsearch(i);\n\n\tprintf(\"%d\\n\", answer);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "35276f632d01f50c25f31d2dbe2f8989", "src_uid": "6787c7631716ce3dff3f9a5e1c51ff13", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdbool.h>\n\nint N;\nint answer;\n\ndouble pi;\n\ndouble distsquared(double x, double y){\n\treturn x*x + y*y;\n}\n\nbool fits(int i, int j){\n\tdouble x = i * 1.5;\n\tdouble y = j * sqrt(3) + (i % 2 ? sqrt(3) / 2 : 0);\n\tint k;\n\n\tfor (k = 0; k < 6; k++)\n\t\tif (distsquared(x + cos(pi * k / 3), y + sin(pi * k / 3)) > N*N)\n\t\t\treturn false;\n\n\treturn true;\n}\n\nint _bsearch(int column){\n\tint hi = 10000000, lo = 0, mid;\n\n\twhile (lo < hi){\n\t\tint mid = (hi + lo) / 2;\n\t\tif (!fits(column, mid))\n\t\t\thi = mid;\n\t\telse\n\t\t\tlo = mid + 1;\n\t}\n\n\tif (column % 2 == 0)\n\t\thi = (hi - 1) * 2 + 1;\n\telse\n\t\thi *= 2;\n\n\tif (column > 0)\n\t\thi *= 2;\n\n\treturn hi;\n}\n\nint main(void){\n\tint i;\n\n\tpi = acos(-1);\n\n\tscanf(\"%d\", &N);\n\n\tif (N == 1){\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\n\tfor (i = 0; fits(i,0); i++)\n\t\tanswer += _bsearch(i);\n\n\tprintf(\"%d\\n\", answer);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "93d40678d85a4bef2544a70e6eaa599c", "src_uid": "6787c7631716ce3dff3f9a5e1c51ff13", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdbool.h>\n\nint N;\nint answer;\n\ndouble pi;\n\ndouble distsquared(double x, double y){\n\treturn x*x + y*y;\n}\n\nbool fits(int i, int j){\n\tdouble x = i * 1.5;\n\tdouble y = j * sqrt(3) + (i % 2 ? sqrt(3) / 2 : 0);\n\tint k;\n\n\tfor (k = 0; k < 6; k++)\n\t\tif (distsquared(x + cos(pi * k / 3), y + sin(pi * k / 3)) > N*N)\n\t\t\treturn false;\n\n\treturn true;\n}\n\nint _bsearch(int column){\n\tint hi = 10000000, lo = 0, mid;\n\n\twhile (lo < hi){\n\t\tint mid = (hi + lo) / 2;\n\t\tif (!fits(column, mid))\n\t\t\thi = mid;\n\t\telse\n\t\t\tlo = mid + 1;\n\t}\n\n\tif (column % 2 == 0)\n\t\thi = (hi - 1) * 2 + 1;\n\telse\n\t\thi *= 2;\n\n\tif (column > 0)\n\t\thi *= 2;\n\n\treturn hi;\n}\n\nint main(void){\n\tint i;\n\n\tpi = acos(-1);\n\n\tscanf(\"%d\", &N);\n\n\tfor (i = 0; fits(i,0); i++)\n\t\tanswer += _bsearch(i);\n\n\tprintf(\"%d\\n\", answer);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "78fb00fa1a6bce421a6a34c1cc510f6d", "src_uid": "6787c7631716ce3dff3f9a5e1c51ff13", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdbool.h>\n\nint N;\nint answer;\n\nint _cos[6] = {2,1,-1,0,-1,1};\nint _sin[6] = {0,1,1,0,-1,-1};\n\nunsigned long long int square(unsigned long long int a){\n\treturn a * a;\n}\n\nbool fits(int i, int j){\n\tint x = i * 3;\n\tint y = j * 2 + (i % 2);\n\tint k;\n\n\tfor (k = 0; k < 6; k++)\n\t\tif (square(x + _cos[k]) + 3 * square(y + _sin[k]) > 4*N*N)\n\t\t\treturn false;\n\n\treturn true;\n}\n\nint _bsearch(int column){\n\tint hi = 10000000, lo = 0, mid;\n\n\twhile (lo < hi){\n\t\tint mid = (hi + lo) / 2;\n\t\tif (!fits(column, mid))\n\t\t\thi = mid;\n\t\telse\n\t\t\tlo = mid + 1;\n\t}\n\n\tif (column % 2 == 0)\n\t\thi = (hi - 1) * 2 + 1;\n\telse\n\t\thi *= 2;\n\n\tif (column > 0)\n\t\thi *= 2;\n\n\treturn hi;\n}\n\nint main(void){\n\tint i;\n\n\tscanf(\"%d\", &N);\n\n\tfor (i = 0; fits(i,0); i++)\n\t\tanswer += _bsearch(i);\n\n\tprintf(\"%d\\n\", answer);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d1ea867d4e04b8a54df5fc946e3c6381", "src_uid": "6787c7631716ce3dff3f9a5e1c51ff13", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdbool.h>\n\nunsigned long long int N, answer;\n\nint _cos[6] = {2,1,-1,0,-1,1};\nint _sin[6] = {0,1,1,0,-1,-1};\n\nunsigned long long int square(unsigned long long int a){\n\treturn a * a;\n}\n\nbool fits(int i, int j){\n\tint x = i * 3;\n\tint y = j * 2 + (i % 2);\n\tint k;\n\n\tfor (k = 0; k < 6; k++)\n\t\tif (square(x + _cos[k]) + 3 * square(y + _sin[k]) > 4*N*N)\n\t\t\treturn false;\n\n\treturn true;\n}\n\nint _bsearch(int column){\n\tint hi = 10000000, lo = 0, mid;\n\n\twhile (lo < hi){\n\t\tint mid = (hi + lo) / 2;\n\t\tif (!fits(column, mid))\n\t\t\thi = mid;\n\t\telse\n\t\t\tlo = mid + 1;\n\t}\n\n\tif (column % 2 == 0)\n\t\thi = (hi - 1) * 2 + 1;\n\telse\n\t\thi *= 2;\n\n\tif (column > 0)\n\t\thi *= 2;\n\n\treturn hi;\n}\n\nint main(void){\n\tint i;\n\n\tscanf(\"%lld\", &N);\n\n\tfor (i = 0; fits(i,0); i++)\n\t\tanswer += _bsearch(i);\n\n\tprintf(\"%lld\\n\", answer);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fd4dd19e5fc19eadf2507c29f4eecf35", "src_uid": "6787c7631716ce3dff3f9a5e1c51ff13", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nlong long min(long long x,long long y){return (x<y?x:y);}\nint n,prev;\nchar s[111];\nlong long k,store[111][111];\n\nvoid Main(){\n    scanf(\"%d %lld\",&n,&k);\n    scanf(\"%s\",s);\n    store[0][0] = 1;\n    for(int i = 0;i<n;i++){\n        prev = -1;\n        for(int j = 0;j<i;j++) if(s[i]==s[j]) prev = j;\n        for(int j = n;j>=1;j--){\n            for(int k = prev;k<i;k++){\n                store[j][i+1] += store[j-1][k+1];\n                store[j][i+1] = min(store[j][i+1],1000000000000ll);\n            }\n        }\n    }\n    long long Ans = 0,total = 0;\n    for(int i = n;i>=0;i--){\n        total = 0;\n        for(int j = 0;j<=n;j++) total += store[i][j];\n        if(total<k){\n            k-=total;\n            Ans+=(n-i)*total;\n        }\n        else{\n            \n            Ans += (n-i)*k;\n            k = 0;\n            break;\n        }\n    }\n    if(k==0) printf(\"%lld\\n\",Ans);\n    else puts(\"-1\");\n    return;\n}\nint main(){\n    Main();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7216ce7a21c5e08866a6783400fa6d16", "src_uid": "ae5d21919ecac431ea7507cb1b6dc72b", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define max(a,b) (a<b?b:a)\n#define min(a,b) (a>b?b:a)\ntypedef unsigned long long u64;\n\nint N, K;\nchar s[101];\nu64 n[101][26], l[101][26], t[101];\n\nint main() {\n int i,j, k;\n\n  scanf(\"%d %d\", &N, &K);\n  scanf(\"%s\", s);\n\n  n[0][0] = 1;\n  t[0] = 1;\n  for (i = 1; i <= N; i++) {\n    int c = s[i-1] - 'a';\n    for (j = i; j >= 1; j--) {\n      u64 d = 0;\n      for (k = 0; k < 26; k++)\n        d += n[j-1][k];\n      d -= l[j][c];\n      n[j][c] += d;\n      l[j][c] = n[j][c];\n\n      t[j] += d;\n    }\n  }\n\n  u64 cost = 0;\n  u64 r = K;\n  for (i = N; i >= 0 && r; i--) {\n    u64 a = min(r, t[i]);\n    cost += a * (N - i);\n    r -= a;\n  }\n  printf(\"%lld\\n\", !r?cost:-1);\n\n  return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "27c89bec85acfca77f45dc9266f2b0ed", "src_uid": "ae5d21919ecac431ea7507cb1b6dc72b", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\ntypedef long long ll;\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\nint upcmpll(const void *a, const void *b){return(*(ll*)a==*(ll*)b?0:(*(ll*)a>*(ll*)b?1:-1));}\nvoid sort_u(ll*a, ll n){qsort(a,n,sizeof(ll),upcmpll);}\ntypedef struct{int first,second;} P;\nint dwcmpp(const void *a, const void *b){\n    if(((P*)a)->first != ((P*)b)->first) \n        return (((P*)a)->first < ((P*)b)->first?1:-1);\n    else\n        return (((P*)a)->second == ((P*)b)->second ? 0 : (((P*)a)->second < ((P*)b)->second ? 1 : -1));\n}\nvoid sort_dp(P *a, int n){ qsort(a, n, sizeof(P), dwcmpp); }\n\nint arcnt(P* cntp ,ll* ar, int an){\n    int val = ar[0], cnt = 1, cntn = 0;\n    rep(i, an-1){\n        if(ar[i+1] != val){\n            cntp[cntn].first = cnt;\n            cntp[cntn++].second = val;\n            val = ar[i+1], cnt = 1;\n        }else cnt++;\n    }\n    cntp[cntn].first = cnt;\n    cntp[cntn++].second = val;\n    return cntn;\n}\n\nll a[202020];\nint main() {\n    int t, n;\n    scanf(\"%d\", &t);\n    while(t--){\n        scanf(\"%d\", &n);\n        rep(i,n) scanf(\"%lld\",a+i);\n        sort_u(a,n);\n        P count[202020]; int ntn = 0;\n        ntn = arcnt(count,a,n);\n        sort_dp(count,ntn);\n\n        int tmp = n+1, ans = 0;\n        rep(i,ntn){\n            if(count[i].first < tmp){\n                ans += count[i].first;\n                tmp = count[i].first;\n            }else{\n                ans += tmp-1;\n                tmp--;\n            }\n            if(tmp <= 1) break;\n        }\n        //rep(i,ntn) printf(\"c.f: %d  c.s: %d\\n\", count[i].first, count[i].second);\n        printf(\"%d\\n\", ans);\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "866a8eede8051bfbb6c428207f6c8bb7", "src_uid": "ae5d21919ecac431ea7507cb1b6dc72b", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define max(a,b) (a<b?b:a)\n#define min(a,b) (a>b?b:a)\ntypedef unsigned long long u64;\n\nint N, K;\nchar s[101];\nu64 n[101][26], l[101][26], t[101];\n\nint main() {\n int i,j, k;\n\n  scanf(\"%d %d\", &N, &K);\n  scanf(\"%s\", s);\n\n  n[0][0] = 1;\n  t[0] = 1;\n  for (i = 1; i <= N; i++) {\n    int c = s[i-1] - 'a';\n    for (j = i; j >= 1; j--) {\n      u64 d = 0;\n      for (k = 0; k < 26; k++)\n        d += n[j-1][k];\n      d -= l[j][c];\n      n[j][c] += d;\n      l[j][c] = n[j][c];\n\n      t[j] += d;\n    }\n  }\n\n  u64 cost = 0;\n  u64 r = K;\n  for (i = N; i >= 0 && r; i--) {\n    u64 a = min(r, t[i]);\n    cost += a * (N - i);\n    r -= a;\n  }\n  printf(\"%lld\\n\", !r?cost:-1);\n\n  return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5b887db760a041a0f3a5373368bedf30", "src_uid": "ae5d21919ecac431ea7507cb1b6dc72b", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\ntypedef long long ll;\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n\nint main() {\n    ll k, n;\n    scanf(\"%d%d\", &n, &k);\n    char s[105];\n    scanf(\"%s\", s);\n\n    char next[105][30];   //next[i][c]: i\u304b\u3089\u898b\u3066\u4e00\u756a\u521d\u3081\u306bc(+'a')\u304c\u73fe\u308c\u308bindex\n    for (int j = 0; j < 26; j++) next[n][j] = n;\n    for (int i = n-1; i >= 0; i--) {\n        for (int j = 0; j < 26; j++) next[i][j] = next[i+1][j];\n        next[i][s[i]-'a'] = i;\n    }\n\n    ll dp[105][105] = {0};      //dp[i][l]: s\u306ei\u6587\u5b57\u76ee\u3092\u63a5\u5c3e\u8f9e\u3068\u3057\u3066\u3082\u3064\uff0c\u9577\u3055l\u306e\u90e8\u5206\u6587\u5b57\u5217\u306e\u6570\n    dp[0][0] = 1;\n    for (int i = 0; i < n; ++i) {\n        for (int j = 0; j < 26; ++j) {\n            if (next[i][j] >= n) continue;\n            for (int l = 0; l < n; l++)\n                dp[next[i][j] + 1][l+1] += dp[i][l];\n        }\n    }\n\n    ll ans = 0, cnt = 0, tmp = 1;\n    for (int j = n-1; j >= 0; j--) {\n        for (int i = 0; i <= n; i++) {\n            tmp += dp[i][j];\n            if(tmp < k){                \n                ans += (n-j)*dp[i][j];\n            }else{\n                ans += (n-j)*(k-(tmp-dp[i][j]));\n                break;\n            }\n        }\n        if(tmp >= k) break;\n    }\n    if(tmp < k) ans = -1;\n\n    printf(\"%lld\\n\", ans);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "095b76dd308f7bdf601f99462d375288", "src_uid": "ae5d21919ecac431ea7507cb1b6dc72b", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nchar cc[8][16];\nint visited[8][8];\nint qq[256];\n\nint ok(int x, int y) {\n\treturn x <= 0 || (!visited[x - 1][y] && cc[x][y] != 'S' && cc[x - 1][y] != 'S');\n}\n\nint main() {\n\tint i, h, q, vx, vy;\n\n\tfor (i = 0; i < 8; i++)\n\t\tscanf(\"%s\", cc[i]);\n\th = 0, q = 0;\n\tqq[h + q++] = 7, qq[h + q++] = 0;\n\twhile (q > 0) {\n\t\tint x = qq[h++];\n\t\tint y = qq[h++];\n\n\t\tq -= 2;\n\t\tif (x == 0) {\n\t\t\tprintf(\"WIN\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\tvisited[x][y] = 1;\n\t\tfor (vx = -1; vx <= 1; vx++)\n\t\t\tfor (vy = -1; vy <= 1; vy++)\n\t\t\t\tif (x + vx >= 0 && x + vx < 8 && y + vy >= 0 && y + vy < 8 && ok(x + vx, y + vy))\n\t\t\t\t\tqq[h + q++] = x + vx - 1, qq[h + q++] = y + vy;\n\t}\n\tprintf(\"LOSE\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b993eff6bbad11f2300c26a0dd69bba9", "src_uid": "f47e4ab041288ba9567c19930eb9a090", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nchar cc[8][16];\nint visited[8][8];\nint qq[256];\n\nint ok(int x, int y) {\n\treturn cc[x][y] != 'S'\n\t\t&& (x <= 0 || (!visited[x - 1][y] && cc[x - 1][y] != 'S'));\n}\n\nint main() {\n\tint i, h, q, vx, vy;\n\n\tfor (i = 0; i < 8; i++)\n\t\tscanf(\"%s\", cc[i]);\n\th = 0, q = 0;\n\tqq[h + q++] = 7, qq[h + q++] = 0;\n\twhile (q > 0) {\n\t\tint x = qq[h++];\n\t\tint y = qq[h++];\n\n\t\tq -= 2;\n\t\tif (x <= 0) {\n\t\t\tprintf(\"WIN\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\tvisited[x][y] = 1;\n\t\tfor (vx = -1; vx <= 1; vx++)\n\t\t\tfor (vy = -1; vy <= 1; vy++)\n\t\t\t\tif (x + vx < 8 && y + vy >= 0 && y + vy < 8 && ok(x + vx, y + vy))\n\t\t\t\t\tqq[h + q++] = x + vx - 1, qq[h + q++] = y + vy;\n\t}\n\tprintf(\"LOSE\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cb605b35a20e02a2c6c9b453cee1182c", "src_uid": "f47e4ab041288ba9567c19930eb9a090", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nchar cc[8][16];\nint visited[8][8];\nint qq[256];\n\nint ok(int x, int y) {\n\treturn (x < 0 || cc[x][y] != 'S')\n\t\t&& (x <= 0 || (!visited[x - 1][y] && cc[x - 1][y] != 'S'));\n}\n\nint main() {\n\tint i, h, q, vx, vy;\n\n\tfor (i = 0; i < 8; i++)\n\t\tscanf(\"%s\", cc[i]);\n\th = 0, q = 0;\n\tqq[h + q++] = 7, qq[h + q++] = 0;\n\twhile (q > 0) {\n\t\tint x = qq[h++];\n\t\tint y = qq[h++];\n\n\t\tq -= 2;\n\t\tif (x <= 0) {\n\t\t\tprintf(\"WIN\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\tvisited[x][y] = 1;\n\t\tfor (vx = -1; vx <= 1; vx++)\n\t\t\tfor (vy = -1; vy <= 1; vy++)\n\t\t\t\tif (x + vx < 8 && y + vy >= 0 && y + vy < 8 && ok(x + vx, y + vy))\n\t\t\t\t\tqq[h + q++] = x + vx - 1, qq[h + q++] = y + vy;\n\t}\n\tprintf(\"LOSE\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e0206e1959078c35a1f8ca1a03b556f8", "src_uid": "f47e4ab041288ba9567c19930eb9a090", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdlib.h>\n#include<string.h>\n#include<stdio.h>\n#include<ctype.h>\n#include<time.h>\n#include<math.h>\n\n\n#define KONTROL(x,y,t)\t(x >= n || x < 0 || y >= n || y < 0 || move[x][y][t] || matrix[x][y] == 'S')\n\n#define Max(a,b)    (((a) > (b)) ? (a) : (b))\n#define Min(a,b)    (((a) < (b)) ? (a) : (b))\n\n#define FOR(i,a,b)  for(i = a; i <= b; i++)\n#define ROF(i,a,b)  for(i = a; i >= b; i--)\n\n#define SWAP(a,b)   {t = a; a = b; b = t;}\n\n#define lli long long int\n\n#define endl    puts(\"\")\n\n#define MAX   1e5 + 9\n\ntypedef struct pair{\n\tint x, y;\n}pair;\n\nint const N = 1e4 + 5;\n\npair maria, anna, h[N];\n\nint i, j, k, s, n = 8;\n\nint move[8][8][8];\n\nchar matrix[N][N];\n\nvoid dfs(int x, int y, int t) {\n\n\tint i,j;\n\n//\tprintf(\"%d %d %d %d --- %d %d %d ---\", maria.x, maria.y, anna.x, anna.y, x, y, t), endl;\n\n\tif(x == anna.x && y == anna.y) {\n\t\tprintf(\"WIN\"), endl;\n\t\texit(0);\n\t}\n\n\tif(KONTROL(x,y,t)) return ;\n\t\n\tmove[x][y][t] = true;\n\n\tfor(i = 0; i < s; i++) {\n\t\th[i].x++;\n\t\tif(h[i].x == x && h[i].y == y) {\n\t\t\tfor(j = 0; j <= i; j++) {\n\t\t\t\th[i].x--;\n\t\t\t} \n\t\t\treturn ;\n\t\t}\n\t}\n\tdfs(x+1,y,1);\n\tdfs(x-1,y,2);\n\tdfs(x,y+1,3);\n\tdfs(x,y-1,4);\n}\n\nint main() {\n\t\n\tfor(i = 0; i < n; i++) {\n\t\tscanf(\"%s\", matrix[i]);\n\t\tfor(j = 0; j < n; j++) {\n\t\t\tif(matrix[i][j] == 'M') maria.x = i, maria.y = j;\n\t\t\telse if(matrix[i][j] == 'A') anna.x = i, anna.y = j;\n\t\t\telse if(matrix[i][j] == 'S') h[s].x = i, h[s++].y = j;\n\t\t}\n\t}\n\n\tdfs(maria.x, maria.y, false);\n\n\tputs(\"LOSE\");\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5ad2d7c905ad6c894d6896e8d704d14a", "src_uid": "f47e4ab041288ba9567c19930eb9a090", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdlib.h>\n#include<string.h>\n#include<stdio.h>\n#include<ctype.h>\n#include<time.h>\n#include<math.h>\n\n\n#define KONTROL(x,y,t) (!mariaMove[x][y][t] && x >= 0 && x < n && y >= 0 && y < n)\n\n#define Max(a,b)    (((a) > (b)) ? (a) : (b))\n#define Min(a,b)    (((a) < (b)) ? (a) : (b))\n\n#define FOR(i,a,b)  for(i = a; i <= b; i++)\n#define ROF(i,a,b)  for(i = a; i >= b; i--)\n\n#define SWAP(a,b)   {t = a; a = b; b = t;}\n\n#define lli long long int\n\n#define endl    puts(\"\")\n\n#define MAX   1e5 + 9\n\ntypedef struct pair{\n        int x, y;\n}pair;\n\nint const N = 1e4 + 5;\n\nint n = 8;\n\npair sMatrix[N], sac[N];\n\nchar matrix[N][N], mariaMove[10][10][10];\n\npair anna, maria;\n\nint i, j, k, s, m, h, t;\n\nint kontrol(int x, int y){\n        int i, j;\n        for(i = 0; i < s; i++) {\n                if(sMatrix[i].x == x && sMatrix[i].y == y)\n                        return 0;\n        }\n        return 1;\n}\n\nvoid sDown(int add) {\n        int i;\n        for(i = 0; i < s; i++) {\n                sMatrix[i].x += add;\n        }\n}\n\nvoid dfs(int x, int y, int t) {\n        int i, j, k;\n\n        if(x == anna.x && y == anna.y) {\n                printf(\"WIN\"), endl;\n                exit(0);\n        }\n\n        if(!KONTROL(x,y,t) || !kontrol(x,y)) return ;\n\n        sDown(1);\n\n        if(!kontrol(x,y)){ sDown(-1); return ; }\n\n        mariaMove[x][y][t] = 1;\n\n        for(i = -1, k = 0; i <= 1; i++) {\n                for(j = -1; j <= 1; j++, k++) {\n                        dfs(x+i,y+j, k);\n                }\n        }\n        sDown(-1);\n}\n\nvoid clearMariaMove() {\n        int i, j, k;\n        for(i = 0; i < 10; i++) {\n                for(j = 0; j < 10; j++) {\n                        for(k = 0; k < 100; k++) {\n                                mariaMove[i][j][k] = 0;\n                        }\n                }\n        }\n}\n\nvoid clear_sMatrix() {\n        int i;\n        for(i = 0; i < s; i++) {\n                sMatrix[i].x = sac[i].x;\n                sMatrix[i].y = sac[i].y;\n        }\n}\n\nint main() {\n\n        for(i = 0; i < n; i++) {\n                scanf(\"%s\", matrix[i]);\n                for(j = 0; j < n; j++) {\n                        if(matrix[i][j] == 'S') {\n                                sMatrix[s].x = i, sMatrix[s].y = j;\n                                sac[s].x = i, sac[s].y = j;\n                                s++;\n                        }\n                }\n        }\n\n        maria.x = 7, maria.y = 0;\n        anna.x = 0, anna.y = 7;\n\n        for(i = -1; i <= 0; i++) {\n                for(j = 0; j <= 1; j++) {\n                        dfs(maria.x+i, maria.y+j, 0);\n                        clearMariaMove();\n                        clear_sMatrix();\n                }\n        }\n\n        puts(\"LOSE\");\n\n        return 0;\n}                                            ", "lang_cluster": "C", "compilation_error": true, "code_uid": "9010229bf368e66e86c2f09e2b02a85d", "src_uid": "f47e4ab041288ba9567c19930eb9a090", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nvoid selsort(int arr[],int len){\n    int min,t;\n    for(int i=0;i<len-1;i++){\n        min=i;\n        for(int j=i+1;j<len;j++){\n            if(arr[min]>arr[j]){\n                min=j;\n            }\n        }\n        t=arr[i];\n        arr[i]=arr[min];\n        arr[min]=t;\n    }\n}\nint main(){\n    int n,B,count=0;\n    scanf(\"%d%d\",&n,&B);\n    int *arr=malloc(n*sizeof(int));\n    int *oddeve=malloc(n*sizeof(int));\n    int *locs=malloc(n*sizeof(int));\n    for(int i=0;i<n;i++){\n        scanf(\"%d\",arr+i);\n        if(arr[i]%2){\n            count++;\n        }\n        else{\n            count--;\n        }\n        oddeve[i]=count;\n    }\n    // for(int i=0;i<n;i++){\n    //     printf(\"%d \",oddeve[i]);\n    // }\n    // printf(\"\\n\");\n    //count=0;   guaranteed\n\n    for(int i=1;i<n-1;i++){    // i=0 obv not 0 and last index is 0 but no use as cut not poss.\n        if(!oddeve[i]){\n            locs[count++]=arr[i+1]-arr[i];\n        }\n    }\n    // for(int i=0;i<count;i++){\n    //     printf(\"%d \",locs[i]);\n    // }\n    // printf(\"\\n\");\n    selsort(locs,count);\n    int sum=0,i=0;\n    while(sum+locs[i]<B && i<count){\n        sum+=locs[i++];\n    //    printf(\"sum:%d \",sum);\n    }\n    //printf(\"\\n\");\n    printf(\"%d\\n\",i);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6205cfc91d8ec21dbaafe98b39cdb619", "src_uid": "b3f8e769ee7719ea5c9f458428b16a4e", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n, B;\n    int a[100];\n    scanf(\"%d %d\", &n, &B);\n    for(int i = 0; i < n; ++i) {\n        scanf(\"%d\", &a[i]);\n    }\n    int even = 0;\n    int odd = 0;\n    int ans = 0;\n    for(int i = 0; i < n; ++i) {\n        if(a[i] & 1) {\n            ++odd;\n        } else {\n            ++even;\n        }\n        if(even == odd && i + 1 < n && abs(a[i] - a[i + 1]) < B) {\n            B -= abs(a[i] - a[i + 1]);\n            ++ans;\n        }\n    }\n    printf(\"%d\\n\", ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "79b8c367fa7537735310cad77ee30ac2", "src_uid": "b3f8e769ee7719ea5c9f458428b16a4e", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint a[100],n,m[100];\nint max(int i,int j)\n{\n    return i>j?i:j;\n}\nint q(int st,int odd,int even,int b)\n{\n    if((st==n-1)||(b<=0)) return 0;\n    if(m[st]!=-1) return m[st];\n    if(a[st]%2==0) even ++;\n    else odd ++;\n     int d;\n        if(a[st]>a[st+1]) d=a[st]-a[st+1];\n        else d=a[st+1]-a[st];\n    if((odd+even>0)&&(odd==even)&&(b>=d))\n    {\n        m[st]=max(1+q(st+1,0,0,b-d),q(st+1,odd,even,b));\n        return m[st];\n    }\n    m[st]=q(st+1,odd,even,b);\n    return m[st];\n}\nint main()\n{\n    int i,b,c;\n   scanf(\"%d %d\",&n,&b);\n   for(i=0;i<n;i++) m[i]=-1;\n   for(i=0;i<n;i++) scanf(\"%d\",&a[i]);\n   c=q(0,0,0,b);\n   printf(\"%d\",c);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "988ef35020f550345bc5251104ab8c0d", "src_uid": "b3f8e769ee7719ea5c9f458428b16a4e", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int n,cnt=0,cst=0,b,ev=0,od=0;\n    scanf(\"%d%d\",&n,&b);\n    int ar[n];\n    for(int i=0;i<n;i++)\n    scanf(\"%d\",&ar[i]);\n    for(int i=0;i<n-1;i++)\n    {\n    if(ar[i]%2==0)\n    ev++;\n    else\n    od++;\n    if(ev==od)\n    {\n    if(ar[i+1]>ar[i])\n    cst=(ar[i+1]-ar[i]);\n    else\n    cst=(ar[i]-ar[i+1]);\n    //b-=cst;\n    if(b-cst>=0)\n    {\n    b-=cst;\n    cnt++;\n    //printf(\"%d \",cst);\n    //ev=0;\n    //od=0;\n    }\n    \n    }\n    }\n    printf(\"%d\",cnt);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8cbb53faaa18cb90f8c95335b0291435", "src_uid": "b3f8e769ee7719ea5c9f458428b16a4e", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint a[100],n;\nint max(int i,int j)\n{\n    return i>j?i:j;\n}\nint q(int st,int odd,int even,int b)\n{\n    if((st==n-1)||(b<=0)) return 0;\n    if(a[st]%2==0) even ++;\n    else odd ++;\n     int d;\n        if(a[st]>a[st+1]) d=a[st]-a[st+1];\n        else d=a[st+1]-a[st];\n    if((odd+even>0)&&(odd==even)&&(b>=d))\n    {\n        return max(1+q(st+1,0,0,b-d),q(st+1,odd,even,b));\n    }\n    return q(st+1,odd,even,b);\n}\nint main()\n{\n    int i,b,c;\n   scanf(\"%d %d\",&n,&b);\n   for(i=0;i<n;i++) scanf(\"%d\",&a[i]);\n   c=q(0,0,0,b);\n   printf(\"%d\",c);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "65c0a9548ccab693b575aca967037619", "src_uid": "b3f8e769ee7719ea5c9f458428b16a4e", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nmain()\n{\n    long long int a,n,x,y,p,i,j=0,t,k,z;\n    scanf(\"%I64d%I64d\",&a,&n);\n    a--;\n    for(z=3,x=0;x<n;x++)\n    {\n        a=a+1;\n        p=a;\n        i=1;\n        t=a;\n        while(1)\n        {\n            k=sqrt(p);\n            if((k*k)-p==0)\n            {i=i*p;break;}\n            y=2;\n            if(p%y==0)\n            goto mm;\n            for(y=z;y<=sqrt(p);y+=2)\n            {\n                if((p%y)==0)\n                {   z=y;\n                    mm:\n                    p=p/y;\n                    goto move;\n                }\n            }\n            break;\n            move:\n            if(y==t)\n            {\n                i=i*y*y;\n                t=a;\n            }\n            else\n            t=y;\n        }\n        j=j+(a/i);\n    }\n    printf(\"%I64d\",j);\n    return(0);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "28a0f3a08947caf7f868ecb268fa387e", "src_uid": "915081861e391958dce6ee2a117abd4e", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\n#define MAX_VALUE\t10000000\n\nlong long Y[MAX_VALUE + 1];\n\nint main()\n{\n\tint a, n, i, i2, j, t;\n\tlong long s;\n\tfor(i = 1; (i2 = i * i) <= MAX_VALUE; i++)\n\tfor(j = 1, t = i2; t <= MAX_VALUE; j++, t += i2) Y[t] = j;\n\tscanf(\"%d%d\", &a, &n);\n\tfor(s = i = 0; i < n; i++) s += Y[a + i];\n\tprintf(\"%lld\", s);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f03f1c7751d32ed899e1e0a5c5afe39c", "src_uid": "915081861e391958dce6ee2a117abd4e", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nmain()\n{\n    long long int a,n,x,y,p,i,j=0,t,k,z;\n    scanf(\"%I64d%I64d\",&a,&n);\n\n    a--;\n    for(z=3,x=0;x<n;x++)\n    {\n        a=a+1;\n        p=a;\n        i=1;\n        t=-1;\n        while(1)\n        {\n            k=sqrt(p);\n            if((k*k)-p==0)\n            {i=i*p;break;}\n            y=2;\n            if(p%y==0)\n            goto mm;\n            for(y=z;y<=sqrt(p);y+=2)\n            {\n                if((p%y)==0)\n                {   z=y;\n                    mm:\n                    p=p/y;\n                    goto move;\n                }\n            }\n            break;\n            move:\n            if(y==t)\n            {\n                i=i*y*y;\n                t=a;\n            }\n            else\n            t=y;\n\n        }\n        j=j+(a/i);\n    }\n    printf(\"%I64d\",j);\n    return(0);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4c533fb5fcdd1a87971bfb52b0e26f00", "src_uid": "915081861e391958dce6ee2a117abd4e", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\n#define MAX_VALUE\t10000000\n\nint Y[MAX_VALUE + 1];\n\nint main()\n{\n\tint a, n, i, i2, j, t;\n\tfor(i = 1; (i2 = i * i) <= MAX_VALUE; i++)\n\tfor(j = 1, t = i2; t <= MAX_VALUE; j++, t += i2) Y[t] = j;\n\tscanf(\"%d%d\", &a, &n);\n\tfor(t = i = 0; i < n; i++) t += Y[a + i];\n\tprintf(\"%d\", t);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "96b7e06ceae26502482f178cf5b92cdb", "src_uid": "915081861e391958dce6ee2a117abd4e", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n\nint main()\n{\n    int d,y,p,page,sr;\n    scanf(\"%d %d\",&d,&y);\n    page=0;\n    if(d==1 && y==2)\n    {\n    page=3;\n    goto x;\n    }\n    while(y--)\n    {\n\n           sr=(int)sqrt(d);\n           printf(\"%d\\n\",sr);\n           if((sr*sr)==d)\n           {\n                         page+=1;\n           }\n           else\n           {\n               while(sr--)\n               {\n                    if(d%(sr*sr)==0)\n                    {\n                          p=d/(sr*sr);\n                          if((sr*sr)*p==d)\n                          {\n                          page+=p;\n                          break;\n                          }\n                          else\n                          {\n                              sr--;\n                          }                \n                    }  \n               }\n               \n           }\n           d++;\n    }\nx:    \n    printf(\"%d\",page);\n   \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4d9ef5b59090a78a1dbd4e8d0807ef60", "src_uid": "915081861e391958dce6ee2a117abd4e", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tlong long n,s,l,r,mid;\n\tscanf(\"%lld%lld\",&n,&s);\n\tl=1,r=1e8+1;\n\twhile(l<r)\n\t{\n\t\tmid=(r-l)/2+l;\n\t\tlong long dig,sum;\n\t\tdig=mid;\n\t\tsum=0;\n\t\twhile(dig)\n\t\t{\n\t\t\tsum+=dig%10;\n\t\t\tdig/=10;\n\t\t}\n\t\tif(mid-sum<s)\n\t\t\tl=mid+1;\n\t\telse\n\t\t\tr=mid-1;\n\t}\n\tif(l<=r)\n\t\tprintf(\"%lld\",n-l+1);\n\telse\n\t\tprintf(\"0\");\n\treturn 0; \n } ", "lang_cluster": "C", "compilation_error": false, "code_uid": "11de8f7f886a85369491199ed4bc7951", "src_uid": "9704e2ac6a158d5ced8fd1dc1edb356b", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nlong long s,st,al,h = 1,t,key;\nint main(void)\n{\n    scanf(\"%I64d%I64d\",&st,&s);\n    if(s<10)\n    {\n        al = st-9;\n    }\n    else\n    {\n        al = s;\n        h = al-(al%10)+10;\n        al = h;\n        while(al)\n            t+=al%10,al/=10;\n        key = t;\n        while(h-t<s)\n        {\n            h++,t++;\n            if(h%10==0)\n                t = key+1,key++;\n        }\n        al = st-h+1;\n    }\n    if(al<=0)\n        printf(\"0\\n\");\n    else printf(\"%I64d\\n\",al);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2654b77924e51567fd740e46da42dbc5", "src_uid": "9704e2ac6a158d5ced8fd1dc1edb356b", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tlong long n, s;\n\tscanf(\"%lld %lld\", &n, &s);\n\n\tlong long temp, sum, st = 0, e = n, mid, ans;\n\twhile (st <= e)\n\t{\n\t\tmid = st + (e - st) / 2;\n\t\tsum = 0, temp = mid;\n\t\twhile (temp > 0)\n\t\t{\n\t\t\tlong long r = temp % 10;\n\t\t\tsum += r;\n\t\t\ttemp /= 10;\n\t\t}\n\n\t\tif (mid - sum >= s)\n\t\t{\n\t\t\tans = mid;\n\t\t\te = mid - 1;\n\t\t}\n\t\telse\n\t\t\tst = mid + 1;\n\t}\n\t//\tprintf(\"%lld\", mid);\n\t(ans - sum >= s) ? (printf(\"%lld\", n - ans + 1)) : (printf(\"0\"));\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9e8adf38334e2c52ac87e0ff13e5decd", "src_uid": "9704e2ac6a158d5ced8fd1dc1edb356b", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint sum(long long int x)\n{\n\tint k=0;\n\twhile(x>0)\n\t{\n\t\tk+=(x%10);\n\t\tx=x/10;\n\t}\n\treturn k;\n}\nint main()\n{\n\tlong long int n,s;\n\tscanf(\"%lld%lld\",&n,&s);\n\tlong long int x=(s/9)*10;\n\tlong long int flag=0,lower;\n\tdo\n\t{\n\t\tlong long int check=x-sum(x);\n\t\tif(check<s)\n\t\t{\n\t\t\tflag=1;\n\t\t\tlower=x+10;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tx-=10;\n\t\t}\n\t}\n\twhile(flag==0);\n\tlong long int val=n-lower+1;\n\tif(val<1)printf(\"0\");\n\telse printf(\"%lld\",val);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6f1614ff3c48013475fe7102bc320f55", "src_uid": "9704e2ac6a158d5ced8fd1dc1edb356b", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <math.h>\n#include <stdlib.h>\n#define ll long long\nint main()\n{\n    ll n, s;\n    scanf(\"%lld %lld\", &n, &s);\n    ll left = 0, right = n;\n    ll sum1 = 0;               \n    while(right != left)\n    {\n        ll mid = (right + left) / 2;\n         ll div = 1;\n         ll sum = 0;\n    while (num / div != 0)\n    {\n        sum+=((num)%(div*10))/div;\n        div*=10;\n    }\n        ll check=mid-sum;\n        if (check>=s)\n            right=mid;\n        else\n            left=mid;\n        if (right-left==1)\n            left++;\n    }\n     ll div = 1;\n    while (n/div!=0)\n    {\n        sum1+= ((num) % (div * 10)) / div;\n        div *= 10;\n    }\n    if (n - sum1 >= s)\n        printf(\"%lld\", n - right + 1);\n    else\n        printf(\"0\");\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "882e5095240bfb4cf5c1f47e771b117a", "src_uid": "9704e2ac6a158d5ced8fd1dc1edb356b", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong d[1101][1101]={0},sum[1101]={0},b[1101][1101]={0},num[1101]={0},next[1101]={0},rec[1101]={0},can[1101]={0};\nchar ttt[1101][1101],sss[1101][1101],str[1101][1101]={0},hash[1101][1101]={0},c[1101]={0},used[1101]={0};\nlong n,m,s,tot=1,ans=0,o=0;\n\nlong work(long now)\n{\n   long i,j,k,p,a,cur=++o;\n   char tmp;\n   s=0;\n   for (i=1;i<=n;i++)\n      if (!used[i]&&b[i][now])\n         can[++s]=i;\n   next[now]=now;\n   if (!hash[now][0])\n   {\n      hash[now][0]=1;\n      sum[now]++;\n   }\n   if (!s)\n   {\n      for (p=now;!hash[p][0];p=next[p]);\n      for (i=1;i<=m;i++)\n         if (hash[p][i])\n            rec[++ans]=i;\n      for (i=next[p];i!=p;i=next[i])\n         for (j=1;j<=m;j++)\n            if (hash[i][j])\n               rec[++ans]=j;\n   }\n   else\n   {\n      while (1)\n      {\n         p=0;\n         for (i=1;i<=s;i++)\n            if (!used[can[i]]&&(!p||c[can[i]]||!c[p]&&num[can[i]]>num[p]))\n               p=can[i];\n         if (next[now]!=now&&!c[p])\n            break;\n         used[p]=1;\n         if (!c[p])\n         {\n            next[++tot]=now;\n            next[now]=tot;\n            tmp=(b[p][now]<=sum[now]/2)+'0';\n            for (i=0;i<=m;i++)\n               if (hash[now][i]&&str[p][i]==tmp)\n               {\n                  for (a=1;a<=n;a++)\n                     if (str[a][i]=='1')\n                     {\n                        b[a][now]--;\n                        b[a][tot]++;\n                     }\n                  hash[now][i]=0;\n                  sum[now]--;\n                  hash[tot][i]=1;\n                  sum[tot]++;\n               }\n            for (i=1;i<=s;i++)\n               c[can[i]]|=(b[can[i]][now]&&b[can[i]][tot]);\n         }\n         else\n         {\n            for (i=next[now];(b[p][i]||!b[p][next[i]])&&i!=now;i=next[i]);\n            if (!b[p][i]&&b[p][next[i]])\n               i=next[i];\n            else\n            {\n               for (i=now;b[p][i]==sum[i];i=next[i]);\n               if (b[p][next[i]]!=sum[next[i]])\n                  i=next[i];\n            }\n            j=i;\n            while (b[p][next[j]]&&next[j]!=i)\n               j=next[j];\n            for (k=next[i];k!=j;k=next[k])\n               if (b[p][k]!=sum[k])\n                  return 0;\n            for (k=next[j];k!=i;k=next[k])\n               if (b[p][k])\n                  return 0;\n            if (b[p][i]!=sum[i])\n            {\n               if (b[p][i]<=sum[i]/2)\n               {  \n                  next[++tot]=next[i];\n                  next[i]=tot;\n               }\n               else\n               {\n                  for(k=next[i];next[k]!=i;k=next[k]);\n                  next[++tot]=i;\n                  next[k]=tot;\n               }\n               tmp=(b[p][i]<=sum[i]/2)+'0';\n               for (k=0;k<=m;k++)\n                  if (hash[i][k]&&str[p][k]==tmp)\n                  {\n                     for (a=1;a<=n;a++)\n                        if (str[a][k]=='1')\n                        {\n                           b[a][i]--;\n                           b[a][tot]++;\n                        }\n                     hash[i][k]=0;\n                     sum[i]--;\n                     hash[tot][k]=1;\n                     sum[tot]++;\n                  }\n               for (k=1;k<=s;k++)\n                  c[can[k]]|=(b[can[k]][i]&&b[can[k]][tot]);\n            }\n            if (b[p][j]!=sum[j])\n            {\n               if (b[p][j]<=sum[j]/2)\n               {  \n                  for(k=next[j];next[k]!=j;k=next[k]);\n                  next[++tot]=j;\n                  next[k]=tot;\n               }\n               else\n               {\n                  next[++tot]=next[j];\n                  next[j]=tot;\n               }\n               tmp=(b[p][j]<=sum[j]/2)+'0';\n               for (k=0;k<=m;k++)\n                  if (hash[j][k]&&str[p][k]==tmp)\n                  {\n                     for (a=1;a<=n;a++)\n                        if (str[a][k]=='1')\n                        {\n                           b[a][j]--;\n                           b[a][tot]++;\n                        }\n                     hash[j][k]=0;\n                     sum[j]--;\n                     hash[tot][k]=1;\n                     sum[tot]++;\n                  }\n               for (k=1;k<=s;k++)\n                  c[can[k]]|=(b[can[k]][j]&&b[can[k]][tot]);\n            }\n         }\n      }\n      for (p=now;!hash[p][0];p=next[p]);\n      d[cur][++d[cur][0]]=p;\n      for (i=next[p];i!=p;i=next[i])\n         d[cur][++d[cur][0]]=i;\n      for (i=1;i<=d[cur][0];i++)\n         if (!work(d[cur][i]))\n            return 0;\n   }\n   return 1;\n}\n\nint main()\n{\n   long i,j;\n   scanf(\"%ld\\n\",&n);\n   m=n;\n   for (i=1;i<=n;i++)\n   {\n      str[i][0]='0';\n      gets(str[i]+1);\n      strcpy(ttt[i]+1,str[i]+1);\n      for (j=1;j<=m;j++)\n         if (str[i][j]=='1')\n            num[i]++;\n      b[i][1]=num[i];\n   }\n   sum[1]=m;\n   for (i=1;i<=m;i++)\n      hash[1][i]=1;\n   if (work(1))\n   {\n      puts(\"YES\");\n      for (i=1;i<=m;i++)\n         for (j=1;j<=n;j++)\n            sss[j][i]=ttt[j][rec[i]];\n      for (i=1;i<=n;i++)\n         puts(sss[i]+1);\n   }\n   else\n      puts(\"NO\");\n   return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "fc1c908007951bfb3f0d2a62a3fb0763", "src_uid": "af8d46722e1bd8f7392e5596eaf4def8", "difficulty": 3000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong d[1101][1101]={0},sum[1101]={0},b[1101][1101]={0},num[1101]={0},next[1101]={0},rec[1101]={0},can[1101]={0};\nchar ttt[1101][1101],sss[1101][1101],str[1101][1101]={0},hash[1101][1101]={0},c[1101]={0},used[1101]={0};\nlong n,m,s,tot=1,ans=0,o=0;\n\nlong work(long now)\n{\n   long i,j,k,p,a,cur=++o;\n   char tmp;\n   s=0;\n   for (i=1;i<=n;i++)\n      if (!used[i]&&b[i][now])\n         can[++s]=i;\n   next[now]=now;\n   if (!hash[now][0])\n   {\n      hash[now][0]=1;\n      sum[now]++;\n   }\n   if (!s)\n   {\n      for (p=now;!hash[p][0];p=next[p]);\n      for (i=1;i<=m;i++)\n         if (hash[p][i])\n            rec[++ans]=i;\n      for (i=next[p];i!=p;i=next[i])\n         for (j=1;j<=m;j++)\n            if (hash[i][j])\n               rec[++ans]=j;\n   }\n   else\n   {\n      while (1)\n      {\n         p=0;\n         for (i=1;i<=s;i++)\n            if (!used[can[i]]&&(!p||c[can[i]]||!c[p]&&num[can[i]]>num[p]))\n               p=can[i];\n         if (next[now]!=now&&!c[p])\n            break;\n         used[p]=1;\n         if (!c[p])\n         {\n            next[++tot]=now;\n            next[now]=tot;\n            tmp=(b[p][now]<=sum[now]/2)+'0';\n            for (i=0;i<=m;i++)\n               if (hash[now][i]&&str[p][i]==tmp)\n               {\n                  for (a=1;a<=n;a++)\n                     if (str[a][i]=='1')\n                     {\n                        b[a][now]--;\n                        b[a][tot]++;\n                     }\n                  hash[now][i]=0;\n                  sum[now]--;\n                  hash[tot][i]=1;\n                  sum[tot]++;\n               }\n            for (i=1;i<=s;i++)\n               c[can[i]]|=(b[can[i]][now]&&b[can[i]][tot]);\n         }\n         else\n         {\n            for (i=next[now];(b[p][i]||!b[p][next[i]])&&i!=now;i=next[i]);\n            if (!b[p][i]&&b[p][next[i]])\n               i=next[i];\n            else\n            {\n               for (i=now;b[p][i]==sum[i];i=next[i]);\n               if (b[p][next[i]]!=sum[next[i]])\n                  i=next[i];\n            }\n            j=i;\n            while (b[p][next[j]]&&next[j]!=i)\n               j=next[j];\n            for (k=next[i];k!=j;k=next[k])\n               if (b[p][k]!=sum[k])\n                  return 0;\n            for (k=next[j];k!=i;k=next[k])\n               if (b[p][k])\n                  return 0;\n            if (b[p][i]!=sum[i])\n            {\n               if (b[p][i]<=sum[i]/2)\n               {  \n                  next[++tot]=next[i];\n                  next[i]=tot;\n               }\n               else\n               {\n                  for(k=next[i];next[k]!=i;k=next[k]);\n                  next[++tot]=i;\n                  next[k]=tot;\n               }\n               tmp=(b[p][i]<=sum[i]/2)+'0';\n               for (k=0;k<=m;k++)\n                  if (hash[i][k]&&str[p][k]==tmp)\n                  {\n                     for (a=1;a<=n;a++)\n                        if (str[a][k]=='1')\n                        {\n                           b[a][i]--;\n                           b[a][tot]++;\n                        }\n                     hash[i][k]=0;\n                     sum[i]--;\n                     hash[tot][k]=1;\n                     sum[tot]++;\n                  }\n               for (k=1;k<=s;k++)\n                  c[can[k]]|=(b[can[k]][i]&&b[can[k]][tot]);\n            }\n            if (b[p][j]!=sum[j])\n            {\n               if (b[p][j]<=sum[j]/2)\n               {  \n                  for(k=next[j];next[k]!=j;k=next[k]);\n                  next[++tot]=j;\n                  next[k]=tot;\n               }\n               else\n               {\n                  next[++tot]=next[j];\n                  next[j]=tot;\n               }\n               tmp=(b[p][j]<=sum[j]/2)+'0';\n               for (k=0;k<=m;k++)\n                  if (hash[j][k]&&str[p][k]==tmp)\n                  {\n                     for (a=1;a<=n;a++)\n                        if (str[a][k]=='1')\n                        {\n                           b[a][j]--;\n                           b[a][tot]++;\n                        }\n                     hash[j][k]=0;\n                     sum[j]--;\n                     hash[tot][k]=1;\n                     sum[tot]++;\n                  }\n               for (k=1;k<=s;k++)\n                  c[can[k]]|=(b[can[k]][j]&&b[can[k]][tot]);\n            }\n         }\n      }\n      for (p=now;!hash[p][0];p=next[p]);\n      d[cur][++d[cur][0]]=p;\n      for (i=next[p];i!=p;i=next[i])\n         d[cur][++d[cur][0]]=i;\n      for (i=1;i<=d[cur][0];i++)\n         if (!work(d[cur][i]))\n            return 0;\n   }\n   return 1;\n}\n\nint main()\n{\n   long i,j;\n   scanf(\"%ld\\n\",&n);\n   m=n;\n   for (i=1;i<=n;i++)\n   {\n      str[i][0]='0';\n      gets(str[i]+1);\n      strcpy(ttt[i]+1,str[i]+1);\n      for (j=1;j<=m;j++)\n         if (str[i][j]=='1')\n            num[i]++;\n      b[i][1]=num[i];\n   }\n   sum[1]=m;\n   for (i=1;i<=m;i++)\n      hash[1][i]=1;\n   if (work(1))\n   {\n      puts(\"YES\");\n      for (i=1;i<=m;i++)\n         for (j=1;j<=n;j++)\n            sss[j][i]=ttt[j][rec[i]];\n      for (i=1;i<=n;i++)\n         puts(sss[i]+1);\n   }\n   else\n      puts(\"NO\");\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "318b1cefd53633edf0a401c5ba5e145e", "src_uid": "af8d46722e1bd8f7392e5596eaf4def8", "difficulty": 3000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong d[1101][1101]={0},sum[1101]={0},b[1101][1101]={0},num[1101]={0},next[1101]={0},rec[1101]={0},can[1101]={0};\nchar ttt[1101][1101],sss[1101][1101],str[1101][1101]={0},hash[1101][1101]={0},c[1101]={0},used[1101]={0};\nlong n,m,s,tot=1,ans=0,o=0;\n\nlong work(long now)\n{\n   long i,j,k,p,a,cur=++o;\n   char tmp;\n   s=0;\n   for (i=1;i<=n;i++)\n      if (!used[i]&&b[i][now])\n         can[++s]=i;\n   next[now]=now;\n   if (!hash[now][0])\n   {\n      hash[now][0]=1;\n      sum[now]++;\n   }\n   if (!s)\n   {\n      for (p=now;!hash[p][0];p=next[p]);\n      for (i=1;i<=m;i++)\n         if (hash[p][i])\n            rec[++ans]=i;\n      for (i=next[p];i!=p;i=next[i])\n         for (j=1;j<=m;j++)\n            if (hash[i][j])\n               rec[++ans]=j;\n   }\n   else\n   {\n      while (1)\n      {\n         p=0;\n         for (i=1;i<=s;i++)\n            if (!used[can[i]]&&(!p||c[can[i]]||!c[p]&&num[can[i]]>num[p]))\n               p=can[i];\n         if (next[now]!=now&&!c[p])\n            break;\n         used[p]=1;\n         if (!c[p])\n         {\n            next[++tot]=now;\n            next[now]=tot;\n            tmp=(b[p][now]<=sum[now]/2)+'0';\n            for (i=0;i<=m;i++)\n               if (hash[now][i]&&str[p][i]==tmp)\n               {\n                  for (a=1;a<=n;a++)\n                     if (str[a][i]=='1')\n                     {\n                        b[a][now]--;\n                        b[a][tot]++;\n                     }\n                  hash[now][i]=0;\n                  sum[now]--;\n                  hash[tot][i]=1;\n                  sum[tot]++;\n               }\n            for (i=1;i<=s;i++)\n               c[can[i]]|=(b[can[i]][now]&&b[can[i]][tot]);\n         }\n         else\n         {\n            for (i=next[now];(b[p][i]||!b[p][next[i]])&&i!=now;i=next[i]);\n            if (!b[p][i]&&b[p][next[i]])\n               i=next[i];\n            else\n            {\n               for (i=now;b[p][i]==sum[i];i=next[i]);\n               if (b[p][next[i]]!=sum[next[i]])\n                  i=next[i];\n            }\n            j=i;\n            while (b[p][next[j]]&&next[j]!=i)\n               j=next[j];\n            for (k=next[i];k!=j;k=next[k])\n               if (b[p][k]!=sum[k])\n                  return 0;\n            for (k=next[j];k!=i;k=next[k])\n               if (b[p][k])\n                  return 0;\n            if (b[p][i]!=sum[i])\n            {\n               if (b[p][i]<=sum[i]/2)\n               {  \n                  next[++tot]=next[i];\n                  next[i]=tot;\n               }\n               else\n               {\n                  for(k=next[i];next[k]!=i;k=next[k]);\n                  next[++tot]=i;\n                  next[k]=tot;\n               }\n               tmp=(b[p][i]<=sum[i]/2)+'0';\n               for (k=0;k<=m;k++)\n                  if (hash[i][k]&&str[p][k]==tmp)\n                  {\n                     for (a=1;a<=n;a++)\n                        if (str[a][k]=='1')\n                        {\n                           b[a][i]--;\n                           b[a][tot]++;\n                        }\n                     hash[i][k]=0;\n                     sum[i]--;\n                     hash[tot][k]=1;\n                     sum[tot]++;\n                  }\n               for (k=1;k<=s;k++)\n                  c[can[k]]|=(b[can[k]][i]&&b[can[k]][tot]);\n            }\n            if (b[p][j]!=sum[j])\n            {\n               if (b[p][j]<=sum[j]/2)\n               {  \n                  for(k=next[j];next[k]!=j;k=next[k]);\n                  next[++tot]=j;\n                  next[k]=tot;\n               }\n               else\n               {\n                  next[++tot]=next[j];\n                  next[j]=tot;\n               }\n               tmp=(b[p][j]<=sum[j]/2)+'0';\n               for (k=0;k<=m;k++)\n                  if (hash[j][k]&&str[p][k]==tmp)\n                  {\n                     for (a=1;a<=n;a++)\n                        if (str[a][k]=='1')\n                        {\n                           b[a][j]--;\n                           b[a][tot]++;\n                        }\n                     hash[j][k]=0;\n                     sum[j]--;\n                     hash[tot][k]=1;\n                     sum[tot]++;\n                  }\n               for (k=1;k<=s;k++)\n                  c[can[k]]|=(b[can[k]][j]&&b[can[k]][tot]);\n            }\n         }\n      }\n      for (p=now;!hash[p][0];p=next[p]);\n      d[cur][++d[cur][0]]=p;\n      for (i=next[p];i!=p;i=next[i])\n         d[cur][++d[cur][0]]=i;\n      for (i=1;i<=d[cur][0];i++)\n         if (!work(d[cur][i]))\n            return 0;\n   }\n   return 1;\n}\n\nint main()\n{\n   long i,j;\n   scanf(\"%ld\\n\",&n);\n   m=n;\n   for (i=1;i<=n;i++)\n   {\n      str[i][0]='0';\n      gets(str[i]+1);\n      strcpy(ttt[i]+1,str[i]+1);\n      for (j=1;j<=m;j++)\n         if (str[i][j]=='1')\n            num[i]++;\n      b[i][1]=num[i];\n   }\n   sum[1]=m;\n   for (i=1;i<=m;i++)\n      hash[1][i]=1;\n   if (work(1))\n   {\n      puts(\"YES\");\n      for (i=1;i<=m;i++)\n         for (j=1;j<=n;j++)\n            sss[j][i]=ttt[j][rec[i]];\n      for (i=1;i<=n;i++)\n         puts(sss[i]+1);\n   }\n   else\n      puts(\"NO\");\n   return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3d318ea15abda350871a32bbf6fd9104", "src_uid": "af8d46722e1bd8f7392e5596eaf4def8", "difficulty": 3000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\ntypedef struct scan\n{\n\tint from;\n\tint to;\n}scan;\n\nint graph[550][550];\nint color[550];\nchar out[550];\nscan input[250005];\n\nint cmp(const void *a, const void *b)\n{\n\tscan a1 = * (scan *)a;\n\tscan b1 = * (scan *)b;\n\tif(a1.from > b1.from)\n\t    return 1;\n\telse if(a1.from < b1.from)\n\t    return -1;\n\telse\n\t    return a1.to - b1.to;\n}\n\nint ulta(int a)\n{\n\tif(a==1)\n\t\treturn 2;\n\treturn 1;\n}\n\nint colorable(int n)\n{\n\tint i, j;\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tint k=0;\n\t\tfor(j=1;j<=n;j++)\n\t\t\tif(graph[i][j] == 0)\n\t\t\t\tk++;\n\n\t\tif(color[i]==0)\n\t\t{\n\t\t\tif(k==n)\n\t\t\t\tcolor[i] = 3;\n\t\t\telse\n\t\t\t\tcolor[i] = 1;\n\t\t}\n\n\t\tint green = ulta(color[i]);\n\n\t\tfor(j=1;j<=n;j++)\n\t\t{\n\t\t\tif(graph[i][j] > 0)\n\t\t\t{\n\t\t\t\tif(color[j] == 0)\n\t\t\t\t\tcolor[j] = green;\n\t\t\t\telse if(color[j] == color[i])\n\t\t\t\t\treturn 1;\n\t\t\t}\n\t\t}\n\t}\n\treturn(0);\n}\n\nint print(int n)\n{\n\tint i;\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tif(color[i]==1)\n\t\t\tout[i-1] = 'a';\n\t\tif(color[i]==2)\n\t\t\tout[i-1] = 'c';\n\t\tif(color[i]==3)\n\t\t\tout[i-1] = 'b';\n\t}\n\tout[n] = '\\0';\n/*\tprintf(\"%s\\n\", out);\n*/\treturn(0);\n}\n\nint main(void)\n{\n\tint n,m,i,j;\n\tscanf(\"%d\", &n);\n\tscanf(\"%d\", &m);\n\n\tfor(i=0;i<m;i++)\n\t{\n\t\tscanf(\"%d %d\", &input[i].from, &input[i].to);\n\t\tif(input[i].from > input[i].to)\n\t\t{\n\t\t\tint temp = input[i].from;\n\t\t\tinput[i].from = input[i].to;\n\t\t\tinput[i].to = temp;\n\t\t}\n\t}\n\t\n\tqsort(input, m, sizeof(scan), cmp);\n\n\tfor(i=0;i<550;i++)\n\t\tfor(j=0;j<550;j++)\n\t\t\tgraph[i][j]=0;\n\n\t//if(m==6413)\n\t{\n\t\t/*printf(\"\\n\\n\");\n\t\tfor(i=0;i<m;i++)\n\t\t\tprintf(\"%d %d\\n\", input[i].from, input[i].to);\n\t\tprintf(\"\\n\\n\\n\")*/;\n\t\t/*for(i=1;i<=n;i++)\n\t\t{\n\t\t\tfor(j=1;j<=n;j++)\n\t\t\t\tprintf(\"%d \", graph[i][j]);\n\t\t\tprintf(\"\\n\");\n\t\t}\n\t\tprintf(\"\\n\\n\\n\");*/\n\t}\n\n\tint count=0;\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tfor(j=i+1;j<=n;j++)\n\t\t{\t\n\t\t\twhile(i > input[count].from && count < m)\n\t\t\t\tcount++;\n\t\t\twhile(j > input[count].to && i == input[count].from && count < m)\n\t\t\t\tcount++;\n\n\t\t\tif(count < m)\n\t\t\t{\n\t\t\t\tint from = input[count].from;\n\t\t\t\tint to = input[count].to;\n\n\t\t\t\t//printf(\"comparing %d, %d with input %d, %d\\n\", i, j, from, to);\n\n\t\t\t\tif(from!=i || to!=j)\n\t\t\t\t{\n\t\t\t\t\tif(graph[i][j]==0 && graph[j][i]==0)\n\t\t\t\t\t\tgraph[i][j]++;\n\t\t\t\t}\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tif(graph[i][j]==0 && graph[j][i]==0)\n\t\t\t\t\tgraph[i][j]++;\n\t\t\t}\n\t\t}\n\t}\n\n\t/*for(i=1;i<=n;i++)\n\t\t{\n\t\t\tfor(j=1;j<=n;j++)\n\t\t\t\tprintf(\"%d \", graph[i][j]);\n\t\t\tprintf(\"\\n\");\n\t\t}\n\t\tprintf(\"\\n\\n\\n\");*/\n\n\tint a = colorable(n);\n\n\t\n\n\tif(a==0)\n\t{\n\t\tprint(n);\n\t\tfor(i=0;i<n;i++)\n\t\t{\n\t\t\tfor(j=i+1;j<n;j++)\n\t\t\t{\n\t\t\t\tif((out[i] == 'a' && out[j] == 'c') || (out[i] == 'c' && out[j] == 'a'))\n\t\t\t\t{\n\t\t\t\t\tif(graph[i+1][j+1] == 0 && graph[j+1][i+1] == 0)\n\t\t\t\t\t{\n\t\t\t\t\t\ta=1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(a==1)\n\t\t\t{\n\t\t\t\tprintf(\"No\\n\");\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(a==0)\n\t\t{\n\t\t\tprintf(\"Yes\\n\");\n\t\t\tprintf(\"%s\\n\", out);\n\t\t}\n\t\t\n\t}\n\telse\n\t\tprintf(\"No\\n\");\n\t\n\treturn(0);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e40e2610e9df6177f8569b72c86daa86", "src_uid": "e71640f715f353e49745eac5f72e682a", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define N\t500\n\nint main() {\n\tint i, j, n, m, yes;\n\tstatic char color[N + 1];\n\tstatic int cnt[N], adj[N][N];\n\n\tscanf(\"%d%d\", &n, &m);\n\tfor (i = 0; i < m; i++) {\n\t\tint u, v;\n\n\t\tscanf(\"%d%d\", &u, &v);\n\t\tu--, v--;\n\t\tcnt[u]++, cnt[v]++;\n\t\tadj[u][v] = adj[v][u] = 1;\n\t}\n\tfor (i = 0; i < n; i++)\n\t\tif (cnt[i] == n - 1)\n\t\t\tcolor[i] = 'b';\n\tfor (i = 0; i < n; i++)\n\t\tif (!color[i]) {\n\t\t\tint j;\n\n\t\t\tcolor[i] = 'a';\n\t\t\tfor (j = 0; j < n; j++) \n\t\t\t\tif (i != j && !color[j])\n\t\t\t\t\tcolor[j] = adj[i][j] ? 'a' : 'c';\n\t\t\tbreak;\n\t\t}\n\tyes = 1;\n\tfor (i = 0; i < n; i++)\n\t\tfor (j = i + 1; j < n; j++) {\n\t\t\tint diff = color[i] > color[j] ? color[i] - color[j] : color[j] - color[i];\n\n\t\t\tif ((adj[i][j] && diff > 1) || (!adj[i][j] && diff <= 1)) {\n\t\t\t\tyes = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\tprintf(\"%s\\n\", yes ? \"Yes\" : \"No\");\n\tif (yes)\n\t\tprintf(\"%s\\n\", color);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c41e968cad53c87e6986cbd7e99344d8", "src_uid": "e71640f715f353e49745eac5f72e682a", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint sum(int *arr, int size) {\n    int total = 0;\n    \n    for (int i = 0; i < size; i++) {\n        total += arr[i];\n    }\n    \n    return total;\n}\n\nint main(int argc, char **argv)\n{\n    int vs, es; // vs vertexes es edges\n    scanf(\"%d %d\", &vs, &es);\n    \n\tint graph[vs+1][vs+1];\n    for (int i = 0; i <= vs; i++) {\n        memset(graph[i], 0, sizeof(graph[i]));\n    }\n    \n    int v1, v2;\n    for (int i = 0; i < es; i++) {\n        scanf(\"%d %d\", &v1, &v2);\n        \n        graph[v1][v2] = 1;\n        graph[v2][v1] = 1;\n    }\n    \n    char letters[vs+10];\n    memset(letters, '-', sizeof(letters));\n    letters[vs+1] = '\\0';\n    \n    for (int i = 1; i <= vs; i++) {\n        if (sum(graph[i]+1, vs) == vs - 1) {\n            letters[i] = 'b';\n        }\n    }\n    \n    int stack[1000*1000];\n    int size = -1, v;\n    int qntA = 0;\n    for (int i = 1; i <= vs; i++) {\n        if (letters[i] == '-') {\n            stack[++size] = i;\n            while (size > -1) {\n                v = stack[size--];\n                if (letters[v] == '-') {\n\t                letters[v] = 'a';\n\t                qntA += 1;\n\t                for (int j = 1; j <= vs; j++) {\n\t                    if (graph[v][j] == 1 && letters[j] == '-') {\n\t                        stack[++size] = j;\n\t                    }\n\t                }\n                }\n            }\n            break;\n        }\n    }\n    \n    int qntC = 0;\n    for (int i = 1; i <= vs; i++) {\n        if (letters[i] == '-') {\n            letters[i] = 'c';\n            qntC += 1;\n        }\n    }\n    \n    //verificando se A esta correto\n    int a = 1, c = 1;\n    int count;\n    for (int i = 1; i <= vs; i++) {\n        if (letters[i] != 'a') continue;\n        \n        count = 0;\n        for (int j = 1; j <= vs; j++) {\n            if (graph[i][j] == 1 && letters[j] == 'a') {\n                count += 1;\n            }\n        }\n        if (qntA - 1 != count) {\n            a = 0;\n            break;\n        }\n    }\n    \n    // verificando C\n    for (int i = 1; i <= vs; i++) {\n        if (letters[i] != 'c') continue;\n        \n        count = 0;\n        for (int j = 1; j <= vs; j++) {\n            if (graph[i][j] == 1 && letters[j] == 'c') {\n                count += 1;\n            }\n        }\n        if (qntC - 1 != count) {\n            c = 0;\n            break;\n        }\n    }\n    \n    if (a && c) {\n        printf(\"Yes\\n%s\", letters+1);\n    } else {\n        printf(\"No\", letters+1);\n    }\n    \n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ece9ca24720cc724ba72ea5cbf397c67", "src_uid": "e71640f715f353e49745eac5f72e682a", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n\ntypedef long long int LL;\n\n#define din(n) scanf(\"%d\",&n)\n#define dout(n) printf(\"%d\\n\",n)\n#define llin(n) scanf(\"%lld\",&n)\n#define llout(n) printf(\"%lld\\n\",n)\n#define strin(n) scanf(\" %s\",n)\n#define strout(n) printf(\"%s\\n\",n)\n#define power(a, b) po(a, b)\n\nint mod=1000000007;\nint vis[550];\nint graph[550][550];\nint color[550];\nchar out[550];\n\nlong long po(long long x, long long y)\n{\n\tlong long pro=1;\n\twhile(y>0)\n\t{\n\t\tif(y&1 != 0)\n\t\t\tpro=((pro%mod)*(x%mod))%mod;\n\t\tx=(x*x)%mod;\n\t\ty=y>>1;\n\t}\n\treturn pro%mod;\n}\n\ntypedef struct scan\n{\n\tint from;\n\tint to;\n}scan;\n\nint cmp(const void *a, const void *b)\n{\n\tscan a1 = * (scan *)a;\n\tscan b1 = * (scan *)b;\n\tif(a1.from > b1.from)\n\t    return 1;\n\telse if(a1.from < b1.from)\n\t    return -1;\n\telse\n\t    return a1.to - b1.to;\n}\n\nint ulta(int a)\n{\n\tif(a==1)\n\t\treturn 2;\n\treturn 1;\n}\n\nint colorable(int start, int n)\n{\n\tint i, j;\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tint k=0;\n\t\tfor(j=1;j<=n;j++)\n\t\t\tif(graph[i][j] == 0)\n\t\t\t\tk++;\n\n\t\tif(color[i]==0)\n\t\t{\n\t\t\tif(k==n)\n\t\t\t\tcolor[i] = 3;\n\t\t\telse\n\t\t\t\tcolor[i] = 1;\n\t\t}\n\n\t\tint green = ulta(color[i]);\n\n\t\tfor(j=1;j<=n;j++)\n\t\t{\n\t\t\tif(graph[i][j] > 0)\n\t\t\t{\n\t\t\t\tif(color[j] == 0)\n\t\t\t\t\tcolor[j] = green;\n\t\t\t\telse if(color[j] == color[i])\n\t\t\t\t\treturn 1;\n\t\t\t}\n\t\t}\n\t}\n\treturn(0);\n}\n\nint print(int n)\n{\n\tint i;\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tif(color[i]==1)\n\t\t\tout[i-1] = 'a';\n\t\tif(color[i]==2)\n\t\t\tout[i-1] = 'c';\n\t\tif(color[i]==3)\n\t\t\tout[i-1] = 'b';\n\t}\n\tout[n] = '\\0';\n\tstrout(out);\n\treturn(0);\n}\n\nint main(void)\n{\n\tif(n==417)\n\t\tprintf(\"graph made\\n\");\n\tint n,m,i,j;\n\tscanf(\"%d\", &n);\n\tscanf(\"%d\", &m);\n\tscan input[1200];\n\tfor(i=0;i<2*m;i+=2)\n\t{\n\t\tscanf(\"%d %d\", &input[i].from, &input[i].to);\n\t\tinput[i+1].from = input[i].to;\n\t\tinput[i+1].to = input[i].from;\n\t}\n\tif(n==417)\n\t\tprintf(\"graph made\\n\");\n\t\n\tqsort(input, 2*m, sizeof(scan), cmp);\n\n\tfor(i=0;i<550;i++)\n\t\tfor(j=0;j<550;j++)\n\t\t\tgraph[i][j]=0;\n\n\tif(n==417)\n\t\tprintf(\"graph started\\n\");\n\n\tint count=0;\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tfor(j=i+1;j<=n;j++)\n\t\t{\t\n\t\t\twhile(i > input[count].from && count < 2*m)\n\t\t\t\tcount++;\n\t\t\twhile(j > input[count].to && count < 2*m)\n\t\t\t\tcount++;\n\n\t\t\tif(count < 2*m)\n\t\t\t{\n\t\t\t\tint from = input[count].from;\n\t\t\t\tint to = input[count].to;\n\n\t\t\t\tif(from!=i || to!=j)\n\t\t\t\t{\n\t\t\t\t\tif(graph[j][i]==0 && graph[i][j]==0)\n\t\t\t\t\t\tgraph[i][j]++;\n\t\t\t\t}\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tif(graph[j][i]==0 && graph[i][j]==0)\n\t\t\t\t\tgraph[i][j]++;\n\t\t\t}\n\t\t}\n\t}\n\n\tint a;\n\tif(n==417)\n\t\tprintf(\"graph made\\n\");\n\n\tfor(i=1;i<=n;i++)\n\t{\n\t\tif(vis[i]==0)\n\t\t\ta = colorable(i, n);\n\t\tif(a==1)\n\t\t\tbreak;\n\t}\n\tif(a==0)\n\t{\n\t\tprintf(\"Yes\\n\");\n\t\tprint(n);\n\t}\n\telse\n\t\tprintf(\"No\\n\");\n\t\n\treturn(0);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "93793fdf693796363004fe6e533507e4", "src_uid": "e71640f715f353e49745eac5f72e682a", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint sum(int *arr, int size) {\n    int total = 0;\n    \n    for (int i = 0; i < size; i++) {\n        total += arr[i];\n    }\n    \n    return total;\n}\n\nint main(int argc, char **argv)\n{\n    int vs, es; // vs vertexes es edges\n    scanf(\"%d %d\", &vs, &es);\n    \n\tint graph[vs+1][vs+1];\n    for (int i = 0; i <= vs; i++) {\n        memset(graph[i], 0, sizeof(graph[i]));\n    }\n    \n    int v1, v2;\n    for (int i = 0; i < es; i++) {\n        scanf(\"%d %d\", &v1, &v2);\n        graph[v1][v2] = 1;\n        graph[v2][v1] = 1;\n    }\n    \n    char letters[vs+10];\n    memset(letters, '-', sizeof(letters));\n    letters[vs+1] = '\\0';\n    \n    for (int i = 1; i <= vs; i++) {\n        if (sum(graph[i]+1, vs) == vs - 1) {\n            letters[i] = 'b';\n        }\n    }\n    \n    int stack[100*1000];\n    int size = -1, v;\n    int qntA = 0;\n    for (int i = 1; i <= vs; i++) {\n        if (letters[i] == '-') {\n            stack[++size] = i;\n            while (size > -1) {\n                v = stack[size--];\n                letters[v] = 'a';\n                qntA += 1;\n                for (int j = 1; j <= vs; j++) {\n                    if (graph[v][j] == 1 && letters[j] == '-') {\n                        stack[++size] = j;\n                    }\n                }\n            }\n            break;\n        }\n    }\n    \n    int qntC = 0;\n    for (int i = 1; i <= vs; i++) {\n        if (letters[i] == '-') {\n            letters[i] = 'c';\n            qntC += 1;\n        }\n    }\n    \n    //verificando se A esta correto\n    int count;\n    for (int i = 1; i <= vs; i++) {\n        if (letters[i] != 'a') continue;\n        \n        count = 0;\n        for (int j = 1; j <= vs; j++) {\n            if (graph[i][j] == 1 && letters[j] == 'a') {\n                count += 1;\n            }\n        }\n        if (qntA - 1 != count) {\n            a = 0;\n            break;\n        }\n    }\n    \n    // verificando C\n    for (int i = 1; i <= vs; i++) {\n        if (letters[i] != 'c') continue;\n        \n        count = 0;\n        for (int j = 1; j <= vs; j++) {\n            if (graph[i][j] == 1 && letters[j] == 'c') {\n                count += 1;\n            }\n        }\n        if (qntC - 1 != count) {\n            c = 0;\n            break;\n        }\n    }\n    \n    if (a && c) {\n        printf(\"Yes\\n%s\", letters+1);\n    } else {\n        printf(\"No\", letters+1);\n    }\n    \n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1173c55ec42f64e2d1584575b514f325", "src_uid": "e71640f715f353e49745eac5f72e682a", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n    int n;\n    char c;\n    c='a';\n    scanf(\"%d\",&n);\n//    printf(\"%c\",c+1);\n\n//    scanf(\"%d\",&n);\n    int count=1;\n    int i=1;\n    printf(\"%c\",c);\n    while(n!=0)\n    {\n        if(n-count<0)\n        {\n            count=0;\n            c=c+1;\n        }\n        printf(\"%c\",c);\n        n=n-count;\n        count++;\n       // i++;\n       // printf(\"count =%d n=%d\\n\",count,n);\n        if(n==0)\n            break;\n    }\n    printf(\"\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0f3ebfceba56ea81e59e9cade86929a1", "src_uid": "b991c064562704b6106a6ff2a297e64a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\n\n\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tchar b[100005];\n\tb[0]='a';\n\tint i=1,count=1,temp;\n\twhile(n>0)\n\t{\n\t\ttemp=n-count;\n\t\tif(temp>=0)\n\t\t{\n\t\t\tb[i]=b[i-1];\n\t\t\ti++;\n\t\t\tcount++;\n\t\t\tn=temp;\n\t\t}\n\t\tif(temp<0)\n\t\t{\n\t\t\tb[i]=b[i-1]+1;\n\t\t\ti++;\n\t\t\tcount=1;\n\t\t}\n\t}\n\tint j;\n\tfor(j=0;j<i;j++)\n\t\tprintf(\"%c\",b[j]);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8029ddfd384c0b90b9c9783bdf6322c7", "src_uid": "b991c064562704b6106a6ff2a297e64a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#define maxl 1000\n#define maxvalue 20000000\n\nlong a[1010];\n\nint main()\n{\n    long value,i,j,k,l,chr;\n    scanf(\"%ld\",&value);\n    for (i=1;i<=maxl;i++)\n        a[i]=i*(i-1)/2;\n    chr=97;\n    for (i=maxl;i>=1;i--)\n        if (value>=a[i])\n        {\n            j=value/a[i];\n            for (k=1;k<=j;k++)\n            {\n                for (l=1;l<=i;l++)\n                    printf(\"%c\",chr);\n                chr++;\n            }\n            value-=j*a[i];\n            if (value==0)\n                break;\n        }\n    printf(\"\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e61afc12ebff7e1e9ac8e706c1908059", "src_uid": "b991c064562704b6106a6ff2a297e64a", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint mian()\n{\n    int k,i,j;\n    scanf(\"%d\", &k);\n    for ( i = 0; i < 26; i++)\n    {\n        int cnt = 1;\n        while ((cnt + 1) * cnt / 2 <= k) \n            cnt++;\n        k -= cnt * (cnt - 1) / 2;\n        for ( j = 0; j < cnt; j++) \n            printf(\"%c\", 'a' + i);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "09efe932de6123fa4d34f8b904e03d7e", "src_uid": "b991c064562704b6106a6ff2a297e64a", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint mian()\n{\n    int k;\n    scanf(\"%d\", &k);\n    for (int i = 0; i < 26; i++)\n    {\n        int cnt = 1;\n        while ((cnt + 1) * cnt / 2 <= k) \n            cnt++;\n        k -= cnt * (cnt - 1) / 2;\n        for (int j = 0; j < cnt; j++) \n            printf(\"%c\", 'a' + i);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "24033ac29d2dff02159a2ca89071b731", "src_uid": "b991c064562704b6106a6ff2a297e64a", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint root[1010000],w[1010000];\nint find(int n)\n{\n\tint r = n;\n\twhile(r != root[r]) r = root[r];\n\tint x = n, y;\n\twhile(x != r)\n\t{\n\t\ty = root[x];\n\t\troot[x] = r;\n\t\tx = y;\n\t}\n\treturn r;\n}\nvoid unico(int a,int b)\n{\n\ta = find(a);\n\tb = find(b);\n\tif(a == b) return;\n\tif(w[a] >= w[b])\n\t{\n\t\troot[b] = a;\n\t\tw[a] += w[b];\n\t}\n\telse\n\t{\n\t\troot[a] = b;\n\t\tw[b] += w[a];\n\t}\n}\nint main()\n{\n\tint n,m,i,j,k,a,b;\n\tscanf(\"%d%d\",&n,&m);\n\tfor (i = 0; i <= n; i++) {\n\t\troot[i]=i;\n\t\tw[i]=1;\n\t}\n\twhile(m--)\n\t{\n\t\tscanf(\"%d%d\",&a,&b);\n\t\tunico(a,b);\n\t}\n\tscanf(\"%d\",&m);\n\twhile(m--)\n\t{\n\t\tscanf(\"%d%d\",&a,&b);\n\t\ta = find(a);\n\t\tb = find(b);\n\t\tif(a == b) root[a] = 0;\n\t}\n\tint ans = 0;\n\tfor(i = 1; i <= n; i++) if(root[i] == i && w[i] > ans)ans = w[i];\n\tprintf(\"%d\\n\",ans);\n}\n/****** PCCA -Mon May 07 05:52:29 GMT 2012 *******/", "lang_cluster": "C", "compilation_error": false, "code_uid": "12a58e9be92620f55bd336de79fdb13e", "src_uid": "e1ebaf64b129edb8089f9e2f89a0e1e1", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint root[101000],w[101000];\nint find(int n)\n{\n\tint r = n;\n\twhile(r != root[r]) r = root[r];\n\tint x = n, y;\n\twhile(x != r)\n\t{\n\t\ty = root[x];\n\t\troot[x] = r;\n\t\tx = y;\n\t}\n\treturn r;\n}\nvoid unico(int a,int b)\n{\n\ta = find(a);\n\tb = find(b);\n\tif(a == b) return;\n\tif(w[a] >= w[b])\n\t{\n\t\troot[b] = a;\n\t\tw[a] += w[b];\n\t}\n\telse\n\t{\n\t\troot[a] = b;\n\t\tw[b] += w[a];\n\t}\n}\nint main()\n{\n\tint n,m,i,j,k,a,b;\n\tscanf(\"%d%d\",&n,&m);\n\tfor (i = 0; i <= n; i++) {\n\t\troot[i]=i;\n\t\tw[i]=1;\n\t}\n\twhile(m--)\n\t{\n\t\tscanf(\"%d%d\",&a,&b);\n\t\tunico(a,b);\n\t}\n\tscanf(\"%d\",&m);\n\twhile(m--)\n\t{\n\t\tscanf(\"%d%d\",&a,&b);\n\t\ta = find(a);\n\t\tb = find(b);\n\t\tif(a == b) root[a] = 0;\n\t}\n\tint ans = 0;\n\tfor(i = 1; i <= n; i++) if(root[i] == i && w[i] > ans)ans = w[i];\n\tprintf(\"%d\\n\",ans);\n}\n/****** PCCA -Mon May 07 05:46:06 GMT 2012 *******/", "lang_cluster": "C", "compilation_error": false, "code_uid": "993dd97db850bb2d40979e8a3d4e7eec", "src_uid": "e1ebaf64b129edb8089f9e2f89a0e1e1", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint root[101000],w[101000];\nint find(int n)\n{\n\tint r = n;\n\twhile(r != root[r]) r = root[r];\n\tint x = n, y;\n\twhile(x != r)\n\t{\n\t\ty = root[x];\n\t\troot[x] = r;\n\t\tx = y;\n\t}\n\treturn r;\n}\nvoid unico(int a,int b)\n{\n\ta = find(a);\n\tb = find(b);\n\tif(a == b) return;\n\tif(w[a] >= w[b])\n\t{\n\t\troot[b] = a;\n\t\tw[a] += w[b];\n\t}\n\telse\n\t{\n\t\troot[a] = b;\n\t\tw[b] += w[a];\n\t}\n}\nint main()\n{\n\tint n,m,i,j,k,a,b;\n\tscanf(\"%d%d\",&n,&m);\n\tfor (i = 0; i <= n; i++) {\n\t\troot[i]=i;\n\t\tw[i]=1;\n\t}\n\twhile(m--)\n\t{\n\t\tscanf(\"%d%d\",&a,&b);\n\t\tunico(a,b);\n\t}\n\tscanf(\"%d\",&m);\n\twhile(m--)\n\t{\n\t\tscanf(\"%d%d\",&a,&b);\n\t\ta = find(a);\n\t\tb = find(b);\n\t\tif(a == b) root[a] = 0;\n\t}\n\tint ans = 0;\n\tfor(i = 1; i <= n; i++) if(root[i] == i && w[i] > ans)ans = w[i];\n\tprintf(\"%d\\n\",ans);\n}\n/****** PCCA -Mon May 07 05:46:52 GMT 2012 *******/", "lang_cluster": "C", "compilation_error": false, "code_uid": "5bb170b3e8a57c3bbbea81df12efbd1f", "src_uid": "e1ebaf64b129edb8089f9e2f89a0e1e1", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<memory.h>\n#define min(a,b) a<b?a:b\n#define N 2010\nint set[N],count[N],vis[N];\nint find(x){\n  int r,t;\n  r=x;\n  while(r!=set[r])\n    r=set[r];\n   while(x!=set[x]){\n    t=set[x];\n    set[x]=r;\n    x=t;\n  }\n   return r;\n}\nvoid merge(int x,int y){\n   x=find(x);\n   y=find(y);\n   if(x!=y)\n     set[x]=set[y];\n}\nint main(){\n    int n,k,m;\n    int f,t,ans,i;\n    while(scanf(\"%d\",&n)!=EOF){\n        memset(count,0,sizeof(count));\n        for(i=1;i<=n;i++)\n          set[i]=i;\n      scanf(\"%d\",&k);\n      while(k--){\n      scanf(\"%d%d\",&f,&t);\n      merge(f,t);\n      }\n      for(i=1;i<=n;i++)\n       count[set[i]]++;\n      ans=n;\n      scanf(\"%d\",&m);\n      while(m--){\n      scanf(\"%d%d\",&f,&t);\n      f=find(f);\n      t=find(t);\n      if(f==t){\n       ans=ans-count[find(f)];\n      count[find(f)]=0;\n      }\n      else{\n         if(count[f]<count[t]){\n         ans=ans-count[f];\n         count[f]=0;\n         }\n         else{\n         ans=ans-count[t];\n         count[t]=0;\n         }\n\n      }\n\n     }\n     printf(\"%d\\n\",ans);\n    }\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ca929e7ae02c557f907e73dafcd181a3", "src_uid": "e1ebaf64b129edb8089f9e2f89a0e1e1", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\ntypedef struct\n{\n    int to, nextid;\n}ne;\nint l[100005];\nne le[200005];\nint d[2001][2001];\nint s[2001],vis[2001];\nint c;\nvoid dfs(int a)\n{\n    s[c++]=a;\n    vis[a]=1;\n    int i;\n    for(i=l[a];i!=-1;i=le[i].nextid)\n    {\n        if(vis[le[i].to]==0) {dfs(le[i].to);}\n    }\n}\n\nint main()\n{\nint n,i,u,v,m,k,j;\n    scanf(\"%d%d\",&n,&k);\n    for(i=0;i<=n+5;i++) l[i]=-1;\n    for(i=0;i<k;i++)\n    {\n        scanf(\"%d%d\",&u,&v);\n        le[2*i].nextid=l[u];\n        le[2*i].to=v;\n        l[u]=2*i;\n        le[2*i+1].nextid=l[v];\n        le[2*i+1].to=u;\n        l[v]=2*i+1;\n    }\n    printf(\"donner m\");\n    scanf(\"%d\",&m);\n    for(i=0;i<m;i++)\n    {\n        scanf(\"%d%d\",&u,&v);\n        d[u][v]=d[v][u]=1;\n    }\n    int ans=0,l;\n    for(i=1;i<=n;i++)\n    {\n        c=0;\n        if(vis[i]==0) {dfs(i);\n        for(j=0;j<c;j++)\n        {\n            for(l=j;l<c;l++)\n            {\n                if(d[s[j]][s[l]]) c=0;\n            }\n        }\n        if(c>ans) ans=c;\n    }\n    }\n    printf(\"%d\",ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e2888b399f4b9d0b818de617d54285cb", "src_uid": "e1ebaf64b129edb8089f9e2f89a0e1e1", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint dp[6000][3];\nint c[1000];\nint p;\n\nvoid dfs(int x)\n{\n     if (dp[x][0] == 1) {\n\t  c[p++] = x;\n     } else {\n\t  dfs(dp[x][1]);\n\t  dfs(dp[x][2]);\n     }\n}\n\nint main()\n{\n     int n, i, j;\n     int a[6001] = {0};\n\n     scanf(\"%d\", &n);\n\n     for (i = 2; i <= n; i++) a[i] = 1;\n\n     for (i = 2; i <= n; i++) {\n\t  if (a[i] == 1) {\n\t       for (j = i * 2; j <= n; j += i) a[j] = 0;\n\t  }\n     }\n\n     for (i = 1; i <= n; i++) {\n\t  for (j = 0; j <= i / 2; j++) {\n\t       if (a[i] == 1) {\n\t\t    dp[i][0] = 1;\n\t\t    dp[i][1] = i;\n\n\t\t    break;\n\t       } else if (a[j] == 1 && a[i - j] == 1) {\n\t\t    dp[i][0] = 2;\n\t\t    dp[i][1] = j;\n\t\t    dp[i][2] = i - j;\n\n\t\t    break;\n\t       } else {\n\t\t    if (a[j] == 1 && dp[i - j][0] > 0) {\n\t\t\t if (dp[i][0] == 0 || dp[i][0] > dp[i - j][0] + 1) {\n\t\t\t      dp[i][0] = dp[i - j][0] + 1;\n\t\t\t      dp[i][1] = j;\n\t\t\t      dp[i][2] = i - j;\n\t\t\t }\n\t\t    }\n\t\t    if (dp[j][0] > 0 && a[i - j] == 1) {\n\t\t\t if (dp[i][0] == 0 || dp[i][0] > dp[j][0] + 1) {\n\t\t\t      dp[i][0] = dp[j][0] + 1;\n\t\t\t      dp[i][1] = j;\n\t\t\t      dp[i][2] = i - j;\n\t\t\t }\n\t\t    }\n\t\t    if (dp[j][0] > 0 && dp[i - j][0] > 0) {\n\t\t\t if (dp[i][0] == 0 || dp[i][0] > dp[j][0] + dp[i - j][0]) {\n\t\t\t      dp[i][0] = dp[j][0] + dp[i - j][0];\n\t\t\t      dp[i][1] = j;\n\t\t\t      dp[i][2] = i - j;\n\t\t\t }\n\t\t    }\n\t       }\n\t  }\n     }\n\n     if (dp[n][0] == 0) {\n\t  puts(\"-1\");\n     } else {\n\t  dfs(n);\n\n\t  j = 0;\n\n\t  for (i = 0; i < n; i++) {\n\t       if (i > 0) putchar(' ');\n\n\t       if (c[j] == 0) j++;\n\n\t       printf(\"%d\", j + 1);\n\n\t       c[j]--;\n\t  }\n\t  puts(\"\");\n     }\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d825ffdd371f94a1280d27a8f7b5e86d", "src_uid": "94ef0d901f21e1945849fd5bfc2d1449", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nchar a[20000000];\n\nint main()\n{\n     int n, sum, x = 0, i, j;\n     int b[6000] = {0};\n\n     scanf(\"%d\", &n);\n\n     sum = n * (n + 1) / 2;\n\n     a[0] = a[1] = 1;\n\n     for (i = 2; i * i <= sum; i++) {\n\t  if (a[i] == 0) {\n\t       for (j = i * 2; j <= sum; j += i) a[j] = 1;\n\t  }\n     }\n\n     if (a[sum] == 0) {\n\t  for (i = 0; i < n; i++) {\n\t       if (i > 0) putchar(' ');\n\n\t       putchar('1');\n\t  }\n\t  puts(\"\");\n     } else if (a[sum - 2] == 0) {\n\t  b[1] = 1;\n\n\t  for (i = 0; i < n; i++) {\n\t       if (i > 0) putchar(' ');\n\n\t       printf(\"%d\", b[i] + 1);\n\t  }\n\t  puts(\"\");\n     } else if (sum % 2 == 0) {\n\t  for (i = 3; i <= sum / 2; i++) {\n\t       if (a[i] == 0 && a[sum - i] == 0) break;\n\t  }\n\n\t  for (j = 0; j < n; j++) {\n\t       b[j] = 1;\n\n\t       x += j + 1;\n\n\t       if (x >= i) break;\n\t  }\n\n\t  if (x > i) {\n\t       b[x - i - 1] = 0;\n\t  }\n\n\t  for (i = 0; i < n; i++) {\n\t       if (i > 0) putchar(' ');\n\n\t       printf(\"%d\", b[i] + 1);\n\t  }\n\t  puts(\"\");\n     } else {\n\t  sum -= 3;\n\n\t  b[0] = b[1] = 1;\n\n\t  for (i = 3; i <= sum / 2; i++) {\n\t       if (a[i] == 0 && a[sum - i] == 0) break;\n\t  }\n\n\t  for (j = 2; j < n; j++) {\n\t       b[j] = 2;\n\n\t       x += j + 1;\n\n\t       if (x >= i) break;\n\t  }\n\n\t  if (x > i) {\n\t       if (x - i > 2) {\n\t\t    b[x - i - 1] = 0;\n\t       } else if (x - i == 1) {\n\t\t    b[j + x - i] = 2;\n\t\t    b[2] = 0;\n\t       }\n\t  }\n\n\t  for (i = 0; i < n; i++) {\n\t       if (i > 0) putchar(' ');\n\n\t       printf(\"%d\", b[i] + 1);\n\t  }\n\t  puts(\"\");\n     }\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "02945e8217b87da6afaf72f6d0e51f41", "src_uid": "94ef0d901f21e1945849fd5bfc2d1449", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nchar a[20000000];\n\nint main()\n{\n     int n, sum, x = 0, i, j;\n     int b[6000] = {0};\n\n     scanf(\"%d\", &n);\n\n     sum = n * (n + 1) / 2;\n\n     a[0] = a[1] = 1;\n\n     for (j = 4; j <= sum; j += 2) a[j] = 1;\n\n     for (i = 3; i * i <= sum; i += 2) {\n\t  if (a[i] == 0) {\n\t       for (j = i * 2; j <= sum; j += i) a[j] = 1;\n\t  }\n     }\n\n     if (a[sum] == 0) {\n\t  for (i = 0; i < n; i++) {\n\t       if (i > 0) putchar(' ');\n\n\t       putchar('1');\n\t  }\n\t  puts(\"\");\n     } else if (a[sum - 2] == 0) {\n\t  b[1] = 1;\n\n\t  for (i = 0; i < n; i++) {\n\t       if (i > 0) putchar(' ');\n\n\t       printf(\"%d\", b[i] + 1);\n\t  }\n\t  puts(\"\");\n     } else if (sum % 2 == 0) {\n\t  for (i = 3; i <= sum / 2; i += 2) {\n\t       if (a[i] == 0 && a[sum - i] == 0) break;\n\t  }\n\n\t  for (j = 0; j < n; j++) {\n\t       b[j] = 1;\n\n\t       x += j + 1;\n\n\t       if (x >= i) break;\n\t  }\n\n\t  if (x > i) {\n\t       b[x - i - 1] = 0;\n\t  }\n\n\t  for (i = 0; i < n; i++) {\n\t       if (i > 0) putchar(' ');\n\n\t       printf(\"%d\", b[i] + 1);\n\t  }\n\t  puts(\"\");\n     } else {\n\t  sum -= 3;\n\n\t  b[0] = b[1] = 1;\n\n\t  for (i = 3; i <= sum / 2; i += 2) {\n\t       if (a[i] == 0 && a[sum - i] == 0) break;\n\t  }\n\n\t  for (j = 2; j < n; j++) {\n\t       b[j] = 2;\n\n\t       x += j + 1;\n\n\t       if (x >= i) break;\n\t  }\n\n\t  if (x > i) {\n\t       if (x - i > 2) {\n\t\t    b[x - i - 1] = 0;\n\t       } else {\n\t\t    b[j] = 0;\n\t\t    b[j - x + i + 3] = 2;\n\t\t    b[2] = 0;\n\t       }\n\t  }\n\n\t  for (i = 0; i < n; i++) {\n\t       if (i > 0) putchar(' ');\n\n\t       printf(\"%d\", b[i] + 1);\n\t  }\n\t  puts(\"\");\n     }\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1baa146518e60c98baefb303a769439e", "src_uid": "94ef0d901f21e1945849fd5bfc2d1449", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define SUM(N) (N * (N + 1) / 2)\n#define MAXN (6 * 1000 + 1)\n#define MAXS SUM(MAXN)\nchar p[MAXS];\nchar c[MAXN];\n\nint main() {\n  int N, S, i, j;\n\n  scanf(\"%d\", &N);\n  S = SUM(N);\n\n  p[2] = 1;\n  for (i = 3; i <= S; i += 2) p[i] = 1;\n  for (i = 2; i*i <= S; ++i) if(p[i]) for (j = i*i; j <= S; j += 2*i) p[j] = 0;\n\n  memset(c, '1', sizeof c);\n  if (p[S] {\n  } else if (p[S-2]) {\n    c[2] = '2';\n  } else if (S % 2) {\n    c[1] = c[2] = '2', S -= 3;\n    for (i = 3; ; i++) if (p[i] && p[S - i]) {\n      c[i] = '3';\n      break;\n    }\n  }\n  else for (i = 3; ; i++) if (p[i] && p[S - i]) {\n    c[i] = '2';\n    break;\n  }\n\n  for (i = 1; i <= N; i++) printf(\"%c%c\", c[i], i == N? '\\n' : ' ');\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5b9939a8043f5edc76990f286bf41f44", "src_uid": "94ef0d901f21e1945849fd5bfc2d1449", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define oo 1000000000\n#define gmin(a,b) ((a)>(b)?(b):(a))\nlong getans=0,w[10000]={0},h[10000]={0},n,min,total=0,hash[40000000]={0},z[2000000]={0},an[200000]={0};\nvoid work(long k,long tot)\n{\n    long i,o,j;\n    if(k<=n)\n    {\n        if(k>min)\n            return ;\n        for(i=1;i<=tot;i++)\n        {\n            w[i]-=k;\n            o=min;\n            h[k]=i;\n            if(w[i] && w[i]<min)\n                min=w[i];\n            if(w[i]==0)\n            {\n                min=oo;\n                for(j=1;j<=tot;j++)\n                    if(w[j]<min && w[j])\n                        min=w[j];\n            }\n            work(k+1,tot);\n            if(getans)\n                return; \n            h[k]=0;\n            min=o;\n            w[i]+=k;\n        }\n    }\n    else\n        getans=1;\n}\nvoid dfs(long onp,long k,long tot,long count)\n{\n    long i;\n    if(k<tot)\n    {\n        for(i=onp+1;i<=total && count-z[i]>=0;i++)\n        {\n            an[k]=z[i];\n            dfs(i+1,k+1,tot,count-z[i]);\n            if(getans)\n                return ;\n        }\n    }\n    else\n    {\n        if(hash[count]==0)\n        {\n            for(i=1;i<tot;i++)\n                w[i]=an[i];\n            w[k]=count;\n            min=gmin(count,w[1]);\n            work(1,tot);\n        }\n    }\n}\nint main()\n{\n    long i,top,j,ans;\n    scanf(\"%ld\\n\",&n);\n    top=(1+n)*n/2;\n    for(i=2;i<=top;i++)\n    {\n        if(hash[i]==0)\n            z[++total]=i;\n        for(j=2;j<=total && j*i<=top;j++)\n        {\n            hash[j*i]=1;\n            if(i%j==0)\n                break;\n        }\n    }\n    for(ans=1;;ans++)\n    {\n        dfs(0,1,ans,top);\n        if(getans)\n        {\n            printf(\"%ld\\n\",ans);\n            for(i=1;i<=n;i++)\n                printf(\"%ld \",h[i]);\n            return 0;\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "903ee1c328642e68f0f07a0e9c2679e2", "src_uid": "94ef0d901f21e1945849fd5bfc2d1449", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int i, j, n, m, x1, y1, x2, y2;\n\n    scanf(\"%d %d %d %d %d %d\", &n, &m, &x1, &y1, &x2, &y2);\n\n    i = abs(x1 - x2);\n    j = abs(y1 - y2);\n\n    if (i > j) {\n        int aux = i;\n        i = j;\n        j = aux;\n    }\n\n    if ((i <= 2 && j <= 4) || (i == 3 && j == 3)) {\n        puts(\"First\");\n    } else {\n        puts(\"Second\");\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "600f4619fbb5afffa18f4cbd0ca5728a", "src_uid": "41f6f90b7307d2383495441114fa8ea2", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n, m, x1, y1, x2, y2, x, y;\n    \n    scanf(\"%d %d %d %d %d %d\", &n, &m, &x1, &y1, &x2, &y2);\n    \n    x = abs(x1 - x2);\n    y = abs(y1 - y2);\n    \n    if (x > y) {\n        int tmp = x;\n        x = y;\n        y = tmp;\n    }\n    \n    if ((x <= 2 && y <= 4) || (x == 3 && y == 3)) {\n        puts(\"First\");\n    } else {\n        puts(\"Second\");\n    }\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d1db3fe8d41ecb196e8aa3e5216921f1", "src_uid": "41f6f90b7307d2383495441114fa8ea2", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint ab(int a){if(a<0)return -a; return a;}\n\nint main(){\n  int i,j,k,l,m,n;\n  int x, y, x1, x2, y1, y2;\n\n  scanf(\"%d%d%d%d%d%d\",&x,&y,&x1,&y1,&x2,&y2);\n\n  if(ab(x1-x2) > 4 && ab(y1-y2) > 4) puts(\"Second\");\n  else puts(\"First\");\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ec9277e48fc73b1f67ddce1c39a6e2d2", "src_uid": "41f6f90b7307d2383495441114fa8ea2", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint ab(int a){if(a<0)return -a; return a;}\n\nint main(){\n  int i,j,k,l,m,n;\n  int x, y, x1, x2, y1, y2;\n\n  scanf(\"%d%d%d%d%d%d\",&x,&y,&x1,&y1,&x2,&y2);\n\n  if(ab(x1-x2) > 4 || ab(y1-y2) > 4) puts(\"Second\");\n  else puts(\"First\");\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "06d0c69bdc5cf826c16cbeb8fe747077", "src_uid": "41f6f90b7307d2383495441114fa8ea2", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint ab(int a){if(a<0)return -a; return a;}\n\nint main(){\n  int i,j,k,l,m,n;\n  int x, y, x1, x2, y1, y2;\n\n  scanf(\"%d%d%d%d%d%d\",&x,&y,&x1,&y1,&x2,&y2);\n\n  if(ab(x1-x2) > 3 || ab(y1-y2) > 3) puts(\"Second\");\n  else puts(\"First\");\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "45db5e0304b2da7685555c84e28a9cae", "src_uid": "41f6f90b7307d2383495441114fa8ea2", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define N 1000005\nconst int P=998244353;\nlong long inv[N];\nlong long ex(long long b, int i) {\n\tlong long p=1;\n\tfor(; i; i>>=1, b=b*b%P) if(i&1) p=p*b%P;\n\treturn p;\n}\nint main() {\n\tint n, i, ans, binom, power;\n\tscanf(\"%d\", &n);\n\tinv[1]=1;\n\tfor(i=2; i<=n; ++i) inv[i]=inv[P%i]*(P-P/i)%P;\n\tpower=ex(3,n);\n\tans=(ex((power+P-1)%P,n)*3-ex((power+P-3)%P,n)*2%P+P-ex(power,n)+P)%P;\n\tbinom=n&1?1:-1;\n\tpower=1;\n\tfor(i=0; i<n; ++i) {\n\t\tif(i) {\n\t\t\tbinom=(P-binom)*(n-i+1ll)%P*inv[i]%P;\n\t\t\tpower=power*3ll%P;\n\t\t}\n\t\tans=(ans+binom*ex(power-1, n)*3ll)%P;\n\t}\n\tprintf(\"%d\\n\", ans<0?ans+P:ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ff97b4011a82c030fcc6beb3f439614c", "src_uid": "6e4b0ee2e1406041a961582ead299a3a", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MAXN 2003\n\nint main()\n{\n    int n, t, i, j, cur = 0;\n    double p, f[2][MAXN];\n    scanf(\"%d%lf%d\", &n, &p, &t);\n    // f[t][n] -> the possibility that (exactly) n people\n    // are standing on the escalator after t seconds\n    for (i = 1; i <= n; ++i) f[cur][i] = 0;\n    f[cur][0] = 1;\n#define next (!cur)\n    for (i = 0; i < t; ++i) {\n        for (j = 0; j <= i; ++j)\n            if (j >= n) f[next][j] += f[cur][j];\n            else {\n                f[next][j + 1] += f[cur][j] * p;\n                f[next][j] += f[cur][j] * (1.0 - p);\n            }\n        cur = !cur;\n        for (j = 0; j <= n; ++j) f[next][j] = 0;\n    }\n#undef next\n    double ans = 0;\n    for (i = 0; i <= n; ++i) ans += f[cur][i] * i;\n    printf(\"%g\\n\", ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c91622b1ec5f674580b8135a5b766507", "src_uid": "20873b1e802c7aa0e409d9f430516c1e", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nfloat a[2001][2001];\nint main()\n{\n    int n,t,i,j;\n    float p,q,res;\n    scanf(\"%d%f%d\",&n,&p,&t);\n    q=1-p;\n    a[0][0]=q;\n    a[0][1]=p;\n    for(i=1;i<t;i++)\n    {\n        for(j=0;j<=n;j++)\n        {\n            if(j==0)\n            a[i][j]=a[i-1][j]*q;\n            else if (j==n)\n            a[i][j]=(a[i-1][j-1]*p)+(a[i-1][j]);\n            else\n            a[i][j]=(a[i-1][j-1]*p)+(a[i-1][j]*q);\n            \n        }\n    }\n    res=0;\n    for(i=0;i<=n;i++)\n    res+=(i*a[t-1][i]);\n    printf(\"%f\\n\",res);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "24fc9db727aa11722d1dccd7412e9b7b", "src_uid": "20873b1e802c7aa0e409d9f430516c1e", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\ndouble d[2001][2001];\nint main()\n{\n    int n,t,i,j;\n    double p,f;\n    scanf(\"%d%lf%d\",&n,&p,&t);\n    for(i=1;i<=t;++i)\n        d[0][i]=0;\n    for(i=0;i<=n;++i)\n        d[i][0]=0;\n    for(i=1;i<=n;++i)\n    {\n        for(j=1;j<=i;++j)\n            d[i][j]=(d[i-1][j-1]+1)*p+(1-p)*d[i][j-1];\n    }\n    printf(\"%lf\",d[n][t]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "750767def31989c8073ef356f2747637", "src_uid": "20873b1e802c7aa0e409d9f430516c1e", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nfloat x[2001][2001];\nint main()\n{\n\n    int n,t,i,j;\n    float p;\n    scanf(\"%d%f%d\",&n,&p,&t);\n\n    for(i=0;i<=n;i++)\n        x[i][0]=0;\n    for(i=0;i<=t;i++)\n        x[0][i]=0;\n\n    for(i=1;i<=n;i++)\n    {\n        for(j=1;j<=t;j++)\n        {\n            x[i][j]= (p*(x[i-1][j-1]+1))+((1-p)*(x[i][j-1]));\n        }\n    }\n\n    printf(\"%f\\n\",x[n][t]);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dd8e026bdea86c3f02629f0284dffe77", "src_uid": "20873b1e802c7aa0e409d9f430516c1e", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "By cyand1317, contest: Codeforces Round #293 (Div. 2), problem: (D) Ilya and Escalator, Wrong answer on test 6, #\n\n#include <stdio.h>\n#define MAXN 2003\n\nint main()\n{\n    int n, t, i, j, cur = 0;\n    double p, f[2][MAXN];\n    scanf(\"%d%lf%d\", &n, &p, &t);\n    // f[t][n] -> the possibility that (exactly) n people\n    // are standing on the escalator after t seconds\n    for (i = 1; i <= n; ++i) f[cur][i] = 0;\n    f[cur][0] = 1;\n#define next (!cur)\n    for (i = 0; i < t; ++i) {\n        for (j = 0; j <= i; ++j)\n            if (j >= n) f[next][j] += f[cur][j];\n            else {\n                f[next][j + 1] += f[cur][j] * p;\n                f[next][j] += f[cur][j] * (1.0 - p);\n            }\n        cur = !cur;\n        for (j = 0; j <= n; ++j) f[next][j] = 0;\n    }\n#undef next\n    double ans = 0;\n    for (i = 0; i <= n; ++i) ans += f[cur][i] * i;\n    printf(\"%.8lf\\n\", ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "67074039e377935c1fb8a61094ac330d", "src_uid": "20873b1e802c7aa0e409d9f430516c1e", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define N\t1000\n\nint main() {\n\tstatic int aa[N], bb[N], cc[N], dd[N], ee[N], ii[N];\n\tint n, h, i, j, k, cnt;\n\n\tscanf(\"%d\", &n);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d%d%d%d%d\", &aa[i], &bb[i], &cc[i], &dd[i], &ee[i]);\n\tcnt = 0;\n\tfor (i = 0; i < n; i++) {\n\t\tfor (j = 0; j < n; j++)\n\t\t\tfor (k = 0; k < n; k++)\n\t\t\t\tif (j != i && k != i && j != k && (aa[j] - aa[i]) * (aa[k] - aa[i]) + (bb[j] - bb[i]) * (bb[k] - bb[i]) + (cc[j] - cc[i]) * (cc[k] - cc[i]) + (dd[j] - dd[i]) * (dd[k] - dd[i]) + (ee[j] - ee[i]) * (ee[k] - ee[i]) > 0)\n\t\t\t\t\tgoto out;\n\t\tii[cnt++] = i;\nout:\n\t\t;\n\t}\n\tprintf(\"%d\\n\", cnt);\n\tfor (h = 0; h < cnt; h++)\n\t\tprintf(\"%d\\n\", ii[h] + 1);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "45caa9dc75acc9aaa45681ac614f651b", "src_uid": "c1cfe1f67217afd4c3c30a6327e0add9", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <stdbool.h>\n#define maxn 1000\n\nlong p[maxn+1][5],xl[maxn+1][maxn+1][5],point[maxn+1],count=0;\n__int64 value[maxn+1][maxn+1];\nbool vis[maxn+1];\n\n    long n,i,j,k,l;\n    __int64 v1,v2;\n\n\nvoid work()\n{\n        for (j=1;j<n;j++)\n            if (i!=j)\n                for (k=j+1;k<=n;k++)\n                    if (i!=k)\n    {\n        v1=0;\n        for (l=0;l<5;l++)\n            v1+=xl[i][j][l]*xl[i][k][l];\n        if (v1==0)\n            continue;\n        //v1=v1*v1;\n\n        v2=value[i][j]*value[i][k];//value<>0\n        // +\n        if ((v1>0 && v2>0) || (v1<0 && v2<0))\n        {\n            vis[i]=false;\n            return;\n        }\n    }\n    vis[i]=true;\n}\n\nint main()\n{\n    scanf(\"%ld\",&n);\n    for (i=1;i<=n;i++)\n        for (j=0;j<5;j++)\n            scanf(\"%ld\",&p[i][j]);\n    for (i=1;i<=n;i++)\n        for (j=1;j<=n;j++)\n        {\n            value[i][j]=0;\n            for (k=0;k<5;k++)\n            {\n                xl[i][j][k]=p[j][k]-p[i][k];\n                value[i][j]+=xl[i][j][k]*xl[i][j][k];\n            }\n        }\n\n//    for (i=1;i<=n;i++)\n//        vis[i]=true;\n    for (i=1;i<=n;i++)\n        work();\n    for (i=1;i<=n;i++)\n        if (vis[i]==true)\n        {\n            count++;\n            point[count]=i;\n        }\n    printf(\"%ld\\n\",count);\n    for (i=1;i<=count;i++)\n        printf(\"%ld\\n\",point[i]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b733282a811e2c8624454276cb91d658", "src_uid": "c1cfe1f67217afd4c3c30a6327e0add9", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <stdbool.h>\n#include <math.h>\n#define tor 0.00000001\n\nint main()\n{\n    long ax,ay,bx,by,cx,cy;\n    double k1,k2;\n    bool vis1,vis2;\n    scanf(\"%ld%ld%ld%ld%ld%ld\",&ax,&ay,&bx,&by,&cx,&cy);\n    if (ax==cx && ay==cy)\n    {\n        printf(\"Yes\\n\");\n        return 0;\n    }\n    if (ax+cx==bx*2 && ay+cy==by*2)\n    {\n        printf(\"No\\n\");\n        return 0;\n    }\n    vis1=true;\n    vis2=true;\n    if (cx-ax!=0)\n        k1=1.0*(cy-ay)/(cx-ax);\n    else\n        vis1=false;\n    ax=1.0*(ax+cx)/2;\n    ay=1.0*(ay+cy)/2;\n    if (bx-ax!=0)\n        k2=1.0*(by-ay)/(bx-ax);\n    else\n        vis2=false;\n\n    if ((vis1==false && vis2==true && fabs(k2-0)<tor) || (vis1==true && fabs(k1-0)<tor && vis2==false) || (vis1==true && vis2==true && fabs(k1*k2+1)<tor))\n        printf(\"Yes\\n\");\n    else\n        printf(\"No\\n\");\n    return 0;\n}\n/*\n0 0 1 1 2 2\n0 1 1 1000000000 2 1\n0 1 1 -1000000000 2 1\n0 1 1 5 2 1\n2 1 1 5 0 1\n2 1 1 -3 0 1\n\n0 0 0 0 0 0\n\n0 0 1 1 0 0\n*/\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0095c773036cc9023563a6468a92f7ae", "src_uid": "c1cfe1f67217afd4c3c30a6327e0add9", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <stdbool.h>\n#define maxn 1000\n\nlong p[maxn+1][5],xl[maxn+1][maxn+1][5],point[maxn+1],count=0;\n__int64 value[maxn+1][maxn+1];\nbool vis[maxn+1];\n\n    long n,i,j,k,l;\n    __int64 v1,v2;\n\n\nvoid work()\n{\n        for (j=1;j<n;j++)\n            if (i!=j)\n                for (k=j+1;k<=n;k++)\n                    if (i!=k)\n    {\n        v1=0;\n        for (l=0;l<5;l++)\n            v1+=xl[i][j][l]*xl[i][k][l];\n        if (v1==0)\n            continue;\n        v1=v1*v1;\n\n        v2=value[i][j]*value[i][k];\n        //0<__<=1 -1<=__<0\n        if (v1<=v2)\n        {\n            vis[i]=false;\n            return;\n        }\n    }\n    vis[i]=true;\n}\n\nint main()\n{\n    scanf(\"%ld\",&n);\n    for (i=1;i<=n;i++)\n        for (j=0;j<5;j++)\n            scanf(\"%ld\",&p[i][j]);\n    for (i=1;i<=n;i++)\n        for (j=1;j<=n;j++)\n        {\n            value[i][j]=0;\n            for (k=0;k<5;k++)\n            {\n                xl[i][j][k]=p[j][k]-p[i][k];\n                value[i][j]+=xl[i][j][k]*xl[i][j][k];\n            }\n        }\n\n//    for (i=1;i<=n;i++)\n//        vis[i]=true;\n    for (i=1;i<=n;i++)\n        work();\n    for (i=1;i<=n;i++)\n        if (vis[i]==true)\n        {\n            count++;\n            point[count]=i;\n        }\n    printf(\"%ld\\n\",count);\n    for (i=1;i<=count;i++)\n        printf(\"%ld\\n\",point[i]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "55dba3f5d4d6443782ee8c7187be8a62", "src_uid": "c1cfe1f67217afd4c3c30a6327e0add9", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n/*\nint cmp(const void* a,const void * b)\n{\nint * g = (int *)a;int * y = (int *)b;\n\nif(g[0]<y[0])return 11;\nelse\n{\nif(g[1]>y[1])return 11;\nelse\n{\nif(g[2]>y[2])return 11;\nelse\n{\nif(g[3]>y[3])return 11;\nelse\n{\nif(g[4]>y[4])return 11;\nelse return -141;\n}}}}}\n//return -141;\n}}*/\n\nint main()\n{\n\nint arr[6000];\n\nint i=0;\nint n;\nscanf(\"%d\",&n);\n\nfor(i=0;i<5*n;i+=5)\n{\nscanf(\"%d %d %d %d %d\",&arr[i+0],&arr[i+1],&arr[i+2],&arr[i+3],&arr[i+4]);\n}\nint good = 0;int arr2[1005];\nint j;int k;\nfor(i=0;i<5*(n-2);i+=5)\n{int flag=101;\nfor(j=i+5;j<5*(n-1);j+=5)\n{\nfor(k=j+5;k<5*(n);k+=5)\n{\nif(((arr[i+0]-arr[j+0])*(arr[i+0]-arr[k+0]) +(arr[i+1]-arr[j+1])*(arr[i+1]-arr[k+1])+(arr[i+2]-arr[j+2])*(arr[i+2]-arr[k+2]) \n+(arr[i+3]-arr[j+3])*(arr[i+3]-arr[k+3]) + (arr[i+4]-arr[j+4])*(arr[i+4]-arr[k+4]))>0)\n{\nflag =-99;break;\n\n}\n\n}\nif(flag == -99)break;\n}\nif(flag == 101)\n{\nint h=0;\n/*for(h=0;h<5;h++)\n{\narr2[good][h]=arr[i+h];\n}*/\narr2[good++]=(i+5)/5;\n}\n}\n//qsort(arr2,good,sizeof(int *),cmp);\n\nprintf(\"%d\\n\",good);\nint port =0;\nfor(port=0;port<good;port++)\n{\n    printf(\"%d\\n\",arr2[port]);\n//printf(\"%d %d %d %d %d\\n\",arr2[port][0],arr2[port][1],arr2[port][2],arr2[port][3],arr2[port][4]);\n}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0e394db0e378df32a4c0bacb43dc5cf6", "src_uid": "c1cfe1f67217afd4c3c30a6327e0add9", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(int argc, char * argv[]) {\n    printf(\"0\\n1\\n1\\n0\\n1\\n1\\n0\\n1\\n1\\n1\\n1\\n1\\n0\\n1\\n0\\n1\\n1\\n1\\n0\\n1\\n1\\n1\\n1\\n1\\n0\\n1\\n0\\n1\\n1\\n1\\n\");\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e8d218bccaa50572983a83c709fe3501", "src_uid": "4bda04e64ff661336a93464563f1b550", "difficulty": null}
{"lang": "GNU C11", "source_code": "/* https://ejectamenta.com/imaging-experiments/fourifier/ */\n/* ((min(id,25)+id)%(2+id%3))>0 */\n#include <stdio.h>\n\nint min(int a, int b) { return a < b ? a : b; }\n\nint main() {\n\tint id;\n\n\tfor (id = 21; id <= 50; id++)\n\t\tprintf(\"%d\\n\", (min(id, 25) + id) % (2 + id % 3) > 0);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d8b0dd051b3aa7994ed7c13051a3b3b8", "src_uid": "4bda04e64ff661336a93464563f1b550", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint min(int a,int b){return a<b?a:b;}\nint main(){\n\tint i;\n\tfor(i=20;i<=51;i++)printf(\"%d\\n\",(min(i,25)+i)%(2+(i)%3)>0);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "70f37dd5f5787c552b03b5d0863ff767", "src_uid": "4bda04e64ff661336a93464563f1b550", "difficulty": null}
{"lang": "GNU C11", "source_code": "min(a,b){return a<b?a:b;}main(id){scanf(\"%d\",&id);printf(\"%d\",((min(id,25)+id)%(2+id%3))>0);}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4813dcf311cc690f006a427f832a2618", "src_uid": "4bda04e64ff661336a93464563f1b550", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint min(int a,int b){return a<b?a:b;}\nint main(){\n\tint i;\n\tfor(i=1;i<=30;i++)printf(\"%d\\n\",(min(i,25)+i)%(2+i%3)>0);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "039b4923fac2d5816d231149c35501d7", "src_uid": "4bda04e64ff661336a93464563f1b550", "difficulty": null}
{"lang": "GNU C", "source_code": "# include <stdio.h>\n# include <math.h>\nmain()\n{\n    long long int n,m,x,y,a,b,p,q,x1,y1,c;\n    scanf(\"%I64d %I64d %I64d %I64d %I64d %I64d\",&n,&m,&x,&y,&a,&b);\n    p=a;q=b;\n    while(q!=0)\n    {\n        c=p%q;\n        p=q;\n        q=c;\n    }\n    //HCF=p;\n    a/=p;b/=p;\n    int i=1;\n    while((a*i)<=n && (b*i)<=m)i++;\n    i--;\n    x1=x-ceil(1.0*a*i/2);y1=y-ceil(1.0*b*i/2);\n    if(x1<0)x1=0;if(y1<0)y1=0;\n    printf(\"%I64d %I64d %I64d %I64d\",x1,y1,x1+a*i,y1+b*i);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "255c77f70ff4bfca34defdef4240d76f", "src_uid": "8f1211b995f35462ae83b2be27f54585", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "# include <stdio.h>\n# include <math.h>\nmain()\n{\n    long long int n,m,x,y,a,b,p,q,x1,y1,c;\n    float min;\n    scanf(\"%I64d %I64d %I64d %I64d %I64d %I64d\",&n,&m,&x,&y,&a,&b);\n    p=a;q=b;\n    while(q!=0)\n    {\n        c=p%q;\n        p=q;\n        q=c;\n    }\n    //HCF=p;\n    a/=p;b/=p;\n    int i=1;\n    while((a*i)<=n && (b*i)<=m)i++;\n    i--;\n    x1=0;y1=0;\n    min=fabs(x1+1.0*a*i/2-x);\n    while(fabs(++x1+1.0*a*i/2-x)<min && (x1+a*i)<=n) min=fabs(x1+1.0*a*i/2-x);\n    min=abs(y1+b*i/2-y);\n    while(fabs(++y1+1.0*b*i/2-y)<min && (y1+b*i)<=m) min=fabs(y1+1.0*b*i/2-y);\n    x1--;y1--;\n    printf(\"%I64d %I64d %I64d %I64d\",x1,y1,x1+a*i,y1+b*i);\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "673ac63479b24518abfeecfe97e589cd", "src_uid": "8f1211b995f35462ae83b2be27f54585", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint main()\n{\n\tint nx, ny, x, y, a, b, x1, y1, x2, y2;\n\tlong long w, h;\n\tscanf(\"%d%d%d%d%d%d\", &nx, &ny, &x, &y, &a, &b);\n\tw = nx;\n\th = ny;\n\twhile ( w * b != h * a )\n\t{\n\t\th = w * b / a;\n\t\tif ( h > ny )\n\t\t\th = ny;\n\t\th -= h % b;\n\t\tw = h * a / b;\n\t\tif ( w > nx )\n\t\t\tw = nx;\n\t\tw -= w % a;\n\t}\n\tx1 = x - (w+1) / 2;\n\ty1 = y - (h+1) / 2;\n\tx2 = x1 + w;\n\ty2 = y1 + h;\n\tif ( x1 < 0 )\n\t\tx2 -= x1, x1 = 0;\n\tif ( y1 < 0 )\n\t\ty2 -= y1, y1 = 0;\n\tif ( x2 > nx )\n\t\tx1 -= (x2-nx), x2 = nx;\n\tif ( y2 > ny )\n\t\ty1 -= (y2-ny), y2 = ny;\n\tprintf(\"%d %d %d %d\\n\", x1, y1, x2, y2);\n\treturn 0;\n}\n\n/*\n1000000000 1000000000 1 1 100000001 100000000\n*/\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "90a5832db042ed44e6545366bb9f4c50", "src_uid": "8f1211b995f35462ae83b2be27f54585", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "# include <stdio.h>\n# include <math.h>\nmain()\n{\n    long long int n,m,x,y,a,b,p,q,x1,y1,c;\n    scanf(\"%I64d %I64d %I64d %I64d %I64d %I64d\",&n,&m,&x,&y,&a,&b);\n    p=a;q=b;\n    while(q!=0)\n    {\n        c=p%q;\n        p=q;\n        q=c;\n    }\n    //HCF=p;\n    a/=p;b/=p;\n    int i=1;\n    while((a*i)<=n && (b*i)<=m)i++;\n    i--;\n    x1=x-ceil(1.0*a*i/2);y1=y-ceil(1.0*b*i/2);\n    if((x1+a*i)>n)x1=n-a*i;if((y1+b*i)>m)y1=m-b*i;\n    if(x1<0)x1=0;if(y1<0)y1=0;\n    printf(\"%I64d %I64d %I64d %I64d\",x1,y1,x1+a*i,y1+b*i);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8aa3ed978209498ee5036abef99fd6d7", "src_uid": "8f1211b995f35462ae83b2be27f54585", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "# include <stdio.h>\n# include <math.h>\nmain()\n{\n    long long int n,m,x,y,a,b,p,q,x1,y1,c;\n    double min;\n    scanf(\"%I64d %I64d %I64d %I64d %I64d %I64d\",&n,&m,&x,&y,&a,&b);\n    p=a;q=b;\n    while(q!=0)\n    {\n        c=p%q;\n        p=q;\n        q=c;\n    }\n    //HCF=p;\n    a/=p;b/=p;\n    int i=1;\n    while((a*i)<=n && (b*i)<=m)i++;\n    i--;\n    x1=0;y1=0;\n    min=fabs(x1+1.0*a*i/2-x);\n    while(fabs(++x1+1.0*a*i/2-x)<min && (x1+a*i)<=n) min=fabs(x1+1.0*a*i/2-x);\n    min=fabs(y1+b*i/2-y);\n    while(fabs(++y1+1.0*b*i/2-y)<min && (y1+b*i)<=m) min=fabs(y1+1.0*b*i/2-y);\n    x1--;y1--;\n    printf(\"%I64d %I64d %I64d %I64d\",x1,y1,x1+a*i,y1+b*i);\n    return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e19ccaa1e1af6961c9a2767e711445a5", "src_uid": "8f1211b995f35462ae83b2be27f54585", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <inttypes.h>\n#include <stdint.h>\n\ntypedef int64_t I64;\n\n\nI64 greatestCommonDivisor(I64 a, I64 b);\n\nint main () {\n    \n    I64 a, b;\n    scanf(\"%\"SCNi64, &a);\n    scanf(\"%\"SCNi64, &b);\n\n    if (a == b) {\n        printf(\"0\\n\");\n        return 0;\n    }\n\n    if (a > b) {\n        I64 t = b;\n        b = a;\n        a = t;\n    }\n\n    I64 kMin = 0, diff = b - a;\n    I64 min = (a / greatestCommonDivisor(a, b) * b);\n    \n    for (I64 i = 1; i * i <= diff; ++i) {\n        if (diff % i != 0) {\n            continue;\n        }\n\n        I64 n = i;\n        if (a % n != 0) {\n            I64 k = n - a % n;\n            I64 m = ((a + k) / greatestCommonDivisor(a + k, b + k) * (b + k));\n            if ((m == min && k < kMin) || m < min) {\n                min = m;\n                kMin = k;\n            }\n        }\n        \n        n = diff / i;\n        if (a % n != 0) {\n            I64 k = n - a % n;\n            I64 m = ((a + k) / greatestCommonDivisor(a + k, b + k) * (b + k));\n            if ((m == min && k < kMin) || m < min) {\n                min = m;\n                kMin = k;\n            }\n        }\n    }\n\n    printf(\"%\"PRIi64\"\\n\", kMin);\n    return 0;\n}\n\nI64 greatestCommonDivisor(I64 a, I64 b) {\n    I64 res = a % b;\n    while (res > 0) {\n        a = b;\n        b = res;\n        res = a % b;\n    }\n    return b;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b5c441fdf231bd539613a019c3baeccd", "src_uid": "414149fadebe25ab6097fc67663177c3", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "/*\t\t\t                       ____COMPETITIVE CODING____                                                          */\n\n//--Header Files--\n\n#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n#include <ctype.h>\n#include <string.h>\n#include <limits.h>\n#include <time.h>\n\n\n//--Macros--\n\n#define N 200001\n#define R 100000007\n#define MAX(a,b) ((a)>(b)?(a):(b))\n#define MIN(a,b) ((a)<(b)?(a):(b))\n\n\n//--Structures--\n\n\n//--Comparator Functions--\n\nint comp(const void *a, const void *b)\n{\n\treturn (*(int *)a - *(int *)b);\n}\nint comp_desc(const void *a, const void *b)\n{\n\treturn (*(int *)b - *(int *)a);\n}\n\n\n//--Function Declarations--\n\n// void qsort(array name, size of array, size of each element, comp);\n// int* bsearch(address of search element, array name, size of array, size of each element, comp);\nint rmdup(int [], int); // int rmDup(array, size of array);\nint gcd(int, int); // int gcd(first number, second number);\n\n\n//--Useful Variables--\n\nint i = 0, j = 0, k = 0, flag = 1, count = 0, temp, pos = 0, test_case, mx = 0, mn = INT_MAX;\nlong long sum = 0, product = 1;\n\n\nint main()\n{\n\t//clock_t tStart = clock();\n\tint a, b, diff;\n\tscanf(\"%d %d\", &a, &b);\n\tdiff = abs(a - b);\n\tmn = MIN(a, b);\n\tmx = MAX(a, b);\n\tif(mn == mx)\n\t{\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\tif(mn % diff == 0)\n\t{\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\tif(mn < diff)\n\t{\n\t\tfor(i = mn; i <= diff / 2; i++)\n\t\t{\n\t\t\tif(diff % i == 0)\n\t\t\t{\n\t\t\t\tflag = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(!flag)\n\t\t{\n\t\t\tprintf(\"%d\\n\", i - mn);\n\t\t\treturn 0;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tprintf(\"%d\\n\", diff - mn);\n\t\t\treturn 0;\n\t\t}\n\t}\n\telse\n\t{\n\t\tprintf(\"%d\\n\", diff - mn % diff);\n\t\treturn 0;\n\t}\n\n\t//printf(\"%lf seconds.\\n\", (clock() - tStart)/CLOCKS_PER_SEC);\n\treturn 0;\n}\n\n\nint rmdup(int a[], int n)\n{\n\tif(n == 0 || n == 1)\n\t\treturn n;\n\tint j = 0;\n\tfor(i = 0; i < n - 1; i++)\n\t{\n\t\tif(a[i] != a[i+1])\n\t\t{\n\t\t\ta[j++] = a[i];\n\t\t}\n\t}\n\ta[j++] = a[n-1];\n\treturn j;\n}\n\n\nint gcd(int x, int y)\n{\n\tif(y == 0)\n\t{\n\t\treturn x;\n\t}\n\telse\n\t{\n\t\treturn gcd(y, x % y);\n\t}\n}\n\n\n\n\n\n\n\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "00af32816e3aa26e17d158bf7963a7b1", "src_uid": "414149fadebe25ab6097fc67663177c3", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main() {\n\tint a, b, c, x;\n\tlong long k, k_, min, ab;\n\n\tscanf(\"%d%d\", &a, &b);\n\tif (a == b) {\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\tif (a > b)\n\t\tc = a, a = b, b = c;\n\tmin = (long long) a * b, k_ = 0;\n\tfor (c = 1; c * c <= b - a; c++)\n\t\tif ((b - a) % c == 0) {\n\t\t\tx = c;\n\t\t\tk = (x - a % x) % x;\n\t\t\tab = (a + k) * (b + k) / x;\n\t\t\tif (min > ab || (min == ab && k_ > k))\n\t\t\t\tmin = ab, k_ = k;\n\t\t\tx = (b - a) / c;\n\t\t\tk = (x - a % x) % x;\n\t\t\tab = (a + k) * (b + k) / x;\n\t\t\tif (min > ab || (min == ab && k_ > k))\n\t\t\t\tmin = ab, k_ = k;\n\t\t}\n\tprintf(\"%lld\\n\", k_);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bc037d1a38b2311f1a631de52e275ef4", "src_uid": "414149fadebe25ab6097fc67663177c3", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "/*\t\t\t                       ____COMPETITIVE CODING____                                                          */\n\n//--Header Files--\n\n#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n#include <ctype.h>\n#include <string.h>\n#include <limits.h>\n#include <time.h>\n\n\n//--Macros--\n\n#define N 200001\n#define R 100000007\n#define MAX(a,b) ((a)>(b)?(a):(b))\n#define MIN(a,b) ((a)<(b)?(a):(b))\n\n\n//--Structures--\n\n\n//--Comparator Functions--\n\nint comp(const void *a, const void *b)\n{\n\treturn (*(int *)a - *(int *)b);\n}\nint comp_desc(const void *a, const void *b)\n{\n\treturn (*(int *)b - *(int *)a);\n}\n\n\n//--Function Declarations--\n\n// void qsort(array name, size of array, size of each element, comp);\n// int* bsearch(address of search element, array name, size of array, size of each element, comp);\nint rmdup(int [], int); // int rmDup(array, size of array);\nint gcd(int, int); // int gcd(first number, second number);\n\n\n//--Useful Variables--\n\nint i = 0, j = 0, k = 0, flag = 1, count = 0, temp, pos = 0, test_case, mx = 0, mn = INT_MAX;\nlong long sum = 0, product = 1;\n\n\nint main()\n{\n\t//clock_t tStart = clock();\n\tint a, b, diff;\n\tscanf(\"%d %d\", &a, &b);\n\tdiff = abs(a - b);\n\tmn = MIN(a, b);\n\tmx = MAX(a, b);\n\n\tif(mn % diff == 0)\n\t{\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\tif(mn < diff)\n\t{\n\t\tfor(i = mn; i <= diff / 2; i++)\n\t\t{\n\t\t\tif(diff % i == 0)\n\t\t\t{\n\t\t\t\tflag = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(!flag)\n\t\t{\n\t\t\tprintf(\"%d\\n\", i - mn);\n\t\t\treturn 0;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tprintf(\"%d\\n\", diff - mn);\n\t\t\treturn 0;\n\t\t}\n\t}\n\telse\n\t{\n\t\tprintf(\"%d\\n\", diff - mn % diff);\n\t\treturn 0;\n\t}\n\n\t//printf(\"%lf seconds.\\n\", (clock() - tStart)/CLOCKS_PER_SEC);\n\treturn 0;\n}\n\n\nint rmdup(int a[], int n)\n{\n\tif(n == 0 || n == 1)\n\t\treturn n;\n\tint j = 0;\n\tfor(i = 0; i < n - 1; i++)\n\t{\n\t\tif(a[i] != a[i+1])\n\t\t{\n\t\t\ta[j++] = a[i];\n\t\t}\n\t}\n\ta[j++] = a[n-1];\n\treturn j;\n}\n\n\nint gcd(int x, int y)\n{\n\tif(y == 0)\n\t{\n\t\treturn x;\n\t}\n\telse\n\t{\n\t\treturn gcd(y, x % y);\n\t}\n}\n\n\n\n\n\n\n\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7dc55cd772fda3fb5e8d43cc13e5ffa2", "src_uid": "414149fadebe25ab6097fc67663177c3", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define lli long long int\nint main(void){\n        lli a,b;\n        scanf(\"%lld %lld\",&a,&b);\n        if(a == b){\n                printf(\"0\\n\");\n                return 0;\n        }\n        if(a > b){\n                int ch = a;\n                a = b;\n                b = ch;\n        }\n        lli q = b - a;\n        lli j = a/q;\n        if(q*j < a)\n                j++;\n        q *=j;\n        int za = a-1;\n        while(q%(++za) != 0);\n        lli k = za - a;\n        printf(\"%lld\\n\",k);\n        return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3bb4bed9dfcd49552f8ec5dbfe8607cf", "src_uid": "414149fadebe25ab6097fc67663177c3", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define MD\t998244353\n\nlong long power(int a, int k) {\n\tlong long b = a, p = 1;\n\n\twhile (k) {\n\t\tif (k & 1)\n\t\t\tp = p * b % MD;\n\t\tb = b * b % MD;\n\t\tk >>= 1;\n\t}\n\treturn p;\n}\n\nint main() {\n\tint n, i, x, y, z;\n\n\tscanf(\"%d\", &n);\n\tx = 1, y = 0, z = 1;\n\tfor (i = 0; i < n; i++)\n\t\tz = x, x = (y + z) % MD, y = z;\n\tprintf(\"%lld\\n\", z * power(2, MD - 1 - n) % MD);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "01ea8fe74a1dd0162d973356d53f2579", "src_uid": "cec37432956bb0a1ce62a0188fe2d805", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n#include <ctype.h>\n\n#define M 998244353\n\n\nlong long add(long long a, long long b) { return (a + b + M) % M; }\nlong long mul(long long a, long long b) { return ((a % M) * (b % M)) % M; }\nlong long pw(long long a, long long r)\n{\n       if(r == 0) return 1;\n       long long b = pw(a, r/2) % M, c = (r&1)?a:1;\n       return mul(mul(b,b),c);\n}\n\nlong long mat[210210],sum[210210];\n\n\nvoid fill()\n{\n    int x;                                                  \n    sum[0] = sum[1] = sum[2] = 1;\n    for(x = 3; x <= 200000; x++)\n       sum[x] = add(sum[x-1],sum[x-2]);\n}\n\n\nint main()\n{\n     int x,y,z,i,j,k,a,b,c,n,m,t;\n     scanf(\"%d\",&n);\n     memset(mat, -1, sizeof(mat));\n     memset(sum, 0, sizeof(sum));\n     \n     fill();\n    \n     printf(\"%lld\\n\",mul( sum[n], pw(pw(2,n), M-2) ));\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "68c2c84d9886a661d612302f194a1fae", "src_uid": "cec37432956bb0a1ce62a0188fe2d805", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\nint main(int argc, char *argv[])\n{\n\tint xa, ya , za, xb , yb , zb ;\n\tdouble distance ;\n\t\n\tscanf(\"%d\",&xa);\n\tscanf(\"%d\",&ya);\n\tscanf(\"%d\",&za);\n\tscanf(\"%d\",&xb);\n\tscanf(\"%d\",&yb);\n\tscanf(\"%d\",&zb);\n\t\n\tdistance = sqrt((xb-xa)*(xb-xa)+(yb-ya)*(yb-ya)+(zb-za)*(zb-za));\n\t\n\tif(za==1&&zb==1){\n\t\tprintf(\"YES\");\n\t}\n\telse if(za!=zb&&xa==xb || za!=zb&&ya==yb){\n\t\tprintf(\"YES\");\n\t}\n\telse if(za==0&&zb==0&&distance>1.4){\n\t\tprintf(\"NO\");\n\t}\n\telse if(distance>1.5){\n\t\tprintf(\"NO\");\n\t}\n\telse{\n\t\tprintf(\"YES\");\n\t}\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "02f8edbe409c3c0e3cc533923db391d7", "src_uid": "91c9dbbceb467d5fd420e92c2919ecb6", "difficulty": 1100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(){\n   int flyes[2][3];\n   int i,diffs=0;\n   for(i = 0; i<3; i++)\n      scanf(\"%d\",&flyes[0][i]);\n   for(i = 0; i<3; i++)\n      scanf(\"%d\",&flyes[1][i]);\n   for(i = 0; i<3; i++){\n      if(flyes[0][i]!=flyes[1][i])\n\t diffs++;\n   }\n   if(diffs==1)\n      printf(\"YES\");\n   else \n      printf(\"NO\");\n\n   return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d1cd333c350209b506ed292dbfeb6baa", "src_uid": "91c9dbbceb467d5fd420e92c2919ecb6", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n    long long a,b,c,d,e,f,count=0;\n    scanf(\"%lld%lld%lld\",&a,&b,&c);\n    scanf(\"%lld%lld%lld\",&d,&e,&f);\n    if(a==0 &&b==0&&c==0)\n    {\n        if(d==1&&e==1&&f==1)\n        printf(\"NO\\n\");\n        else\n            printf(\"YES\\n\");\n\n    }\n    else if(a==1&&b==0&&c==0)\n    {\n        if(d==0&&e==0&&f==1)\n            printf(\"NO\\n\");\n        else\n            printf(\"YES\\n\");\n    }\n    else if(a==1&&b==1&&c==0)\n    {\n        if(d==0&&e==0&&f==1)\n            printf(\"NO\\n\");\n        else\n            printf(\"YES\\n\");\n    }\n    else if(a==0&&b==1&&c==0)\n    {\n        if(d==1&&e==0&&f==1)\n            printf(\"NO\\n\");\n\n        else\n            printf(\"YES\\n\");\n    }\n    else if(a==0&&b==0&&c==1)\n    {\n        if(d==1&&e==1&&f==0)\n            printf(\"NO\\n\");\n        else\n            printf(\"YES\\n\");\n    }\n    else if(a==1&&b==0&&c==1)\n    {\n        if(d==0&&e==1&&f==0)\n            printf(\"NO\\n\");\n        else\n            printf(\"YES\\n\");\n    }\n    else if(a==1&&b==1&&c==1)\n    {\n        if(d==0&&e==0&&f==0)\n            printf(\"NO\\n\");\n        else\n            printf(\"YES\\n\");\n    }\n    else if(a==0&&b==1&&c==1)\n    {\n        if(d==1&&e==0&&f==0)\n            printf(\"NO\\n\");\n        else\n            printf(\"YES\\n\");\n\n    }\n\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f0de508985146992f35353bb104bd170", "src_uid": "91c9dbbceb467d5fd420e92c2919ecb6", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nusing namespace std;\n\nint main()\n{\n\tint f1[3];\n\tint f2[3];\n\tfor(int i=0;i<3;i++)\n\t{\n\t\tscanf(\"%d\", &f1[i]);\n\t}\n\tfor(int i=0;i<3;i++)\n\t{\n\t\tscanf(\"%d\", &f2[i]);\n\t}\n\tif(f1[0] == f2[0])\n\t{\n\t\tprintf(\"YES\");\n\t}\n\telse if(f1[1] == f2[1])\n\t{\n\t\tprintf(\"YES\");\n\t}\n\telse if(f1[2] == f2[2])\n\t{\n\t\tprintf(\"YES\");\n\t}\n\telse if ((f1[0] == f2[0])  && (f1[1] == f2[1]) && (f1[2] == f2[2]))\n\t{\n\t\tprintf(\"YES\");\n\t}\n\telse\n\t{\n\t\tprintf(\"NO\");\n\t}\nreturn 0;\t\n} \n \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "e706dd9e8cf867d66bafd1bd97a096c7", "src_uid": "91c9dbbceb467d5fd420e92c2919ecb6", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<iostream>\n#include<stdio.h>\n\nusing namespace std;\n\nint main()\n{\n\tint f1[3];\n\tint f2[3];\n\tfor(int i=0;i<3;i++)\n\t{\n\t\tscanf(\"%d\", &f1[i]);\n\t}\n\tfor(int i=0;i<3;i++)\n\t{\n\t\tscanf(\"%d\", &f2[i]);\n\t}\n\tif(f1[0] == f2[0])\n\t{\n\t\tprintf(\"YES\");\n\t}\n\telse if(f1[1] == f2[1])\n\t{\n\t\tprintf(\"YES\");\n\t}\n\telse if(f1[2] == f2[2])\n\t{\n\t\tprintf(\"YES\");\n\t}\n\telse if ((f1[0] == f2[0])  && (f1[1] == f2[1]) && (f1[2] == f2[2]))\n\t{\n\t\tprintf(\"YES\");\n\t}\n\telse\n\t{\n\t\tprintf(\"NO\");\n\t}\nreturn 0;\t\n} \n \n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0a24ea7bb1c22c20d156bc74fd71bfaf", "src_uid": "91c9dbbceb467d5fd420e92c2919ecb6", "difficulty": 1100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\nint main()\n    {\n        int m,n;\n        scanf(\"%d %d\",&m,&n);\n        fflush(stdin);\n        char a[1001][1001]={0};\n        char b[1001][1001]={0};\n        memset(b,'.',1001*1001);\n        for(int i=0;i<m;i++)\n            {\n                gets(a[i]);\n            }\n        for(int i=0;i<m;i++){\n            for(int j=0;j<n;j++)\n                {\n                    if(a[i][j]=='#'&&a[i][j+1]=='#'&&a[i][j+2]=='#'&&a[i+1][j]=='#'&&a[i+1][j+2]=='#'&&a[i+2][j]=='#'\n                   &&a[i+2][j+1]=='#'&&a[i+2][j+2]=='#')\n                    b[i][j]='#',b[i][j+1]='#',b[i][j+2]='#',b[i+1][j]='#',b[i+2][j]='#',b[i+1][j+2]='#',b[i+2][j+1]='#',b[i+2][j+2]='#';\n                }\n\n    }\n\n    for(int i=0;i<m;i++)\n        {\n            for(int j=0;j<n;j++)\n                {\n                    if(a[i][j]!=b[i][j])\n                        {\n                            printf(\"NO\\n\");\n                            exit(0);\n                        }\n                }\n        }\n    printf(\"YES\\n\");\n    }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "83b11224afeda0c9a1f415d29d76ffd6", "src_uid": "49e5eabe8d69b3d27a251cccc001ab25", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n    {\n            int m,n,count=0;\n            char line[10000],ch;\n            scanf(\"%d %d\",&m,&n);\n            int grid[m][n];\n            int grid2[m][n];\n            scanf(\"%c\",&ch);\n            for(int i=0;i<m;i++)\n            {\n                for(int j=0;j<n;j++)\n                {\n                    scanf(\"%c\",&ch);\n                    if(line[j]=='#')\n                    {\n                        grid[i][j]=1;\n                    }\n                    else\n                    {\n                        grid[i][j]=0;\n                    }\n                    grid2[i][j]=0;\n\n                    //printf(\"%d \",grid[i][j]);\n                }\n                scanf(\"%c\",&ch);\n                    //printf(\"\\n\");\n            }\n\n            for(int i=1;i<m-1;i++)\n            {\n                for(int j=1;j<n-1;j++)\n                {\n                    if(grid[i][j]==0)\n\n                        if(grid[i-1][j-1]&&grid[i-1][j]&&grid[i-1][j+1]&&grid[i][j-1]&&grid[i][j+1]&&grid[i+1][j-1]&&grid[i+1][j]&&grid[i+1][j+1])\n                            {\n                                grid2[i-1][j-1]=1;\n                                grid2[i-1][j]=1;grid2[i-1][j+1]=1;grid2[i][j-1]=1;grid2[i][j+1]=1;grid2[i+1][j-1]=1;grid2[i+1][j]=1;grid2[i+1][j+1]=1;\n                            }\n\n                }\n            }\n            for(int i=0;i<m;i++)\n            {\n                for(int j=0;j<m;j++)\n                {\n                    if(grid2[i][j]!=grid[i][j])\n                    {\n                        printf(\"NO\\n\");\n                        return 0;\n                    }\n\n                }\n            }\n            printf(\"YES\\n\");\n            return 0;\n\n    }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "af1a4130b7a979c40dca559e58a0af57", "src_uid": "49e5eabe8d69b3d27a251cccc001ab25", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint grid[100][100];\nint main()\n    {\n            int m,n,count=0;\n            char line[100],ch;\n            scanf(\"%d %d\",&m,&n);\n            fflush(stdin);\n            for(int i=0;i<m;i++)\n            {\n                    scanf(\"%s\",&line);\n\n                for(int j=0;j<n;j++)\n                {\n                    if(line[j]=='#')\n                    {\n                        grid[i][j]=1;\n                    }\n                    else if(line[j]=='.'&count==0)\n                    {\n                        count++;\n                    }\n                    //printf(\"%d \",grid[i][j]);\n                }\n                    //printf(\"\\n\");\n            }\n            if(count==0)\n            {\n                if(m==3&n==3)\n                    printf(\"NO\\n\");\n                else\n                    printf(\"YES\\n\");\n                exit(0);\n            }\n\n\n\n            for(int i=1;i<m-1;i++)\n            {\n                for(int j=1;j<n-1;j++)\n                {\n                    if(grid[i][j]==0)\n                    {\n                        if(grid[i-1][j-1]==1&&grid[i-1][j]==1&&grid[i-1][j+1]==1&&grid[i][j-1]==1&&grid[i][j+1]==1&&grid[i+1][j-1]==1&&grid[i+1][j]==1&&grid[i+1][j+1]==1)\n                            {\n                                continue;\n                            }\n                        else\n                        {\n                            printf(\"NO\\n\");\n                            exit(0);\n                        }\n                    }\n                }\n            }\n            printf(\"YES\\n\");\n\n    }\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f4d99cb7a4a78bf5d0a6700f077ab86c", "src_uid": "49e5eabe8d69b3d27a251cccc001ab25", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <Windows.h>\n\nchar arr[1001][1001];\nchar my[1001][1001];\nint stamp(int a, int b) {\n\tint i, j, c = 1;\n\t//memo\n\n\t//stamp!\n\tfor (i = -1; i <= 1; i++) {\n\t\tfor (j = -1; j <= 1; j++) {\n\t\t\tif (i == 0 && j == 0)\n\t\t\t\tcontinue;\n\t\t\telse if (arr[a + i][b + j] == '#')\n\t\t\t\tcontinue;\n\t\t\telse\n\t\t\t\tc = 0;\n\t\t}\n\t}\n\tif (c) {\n\t\tfor (i = -1; i <= 1; i++) {\n\t\t\tfor (j = -1; j <= 1; j++) {\n\t\t\t\tif (i == 0 && j == 0)\n\t\t\t\t\tcontinue;\n\t\t\t\telse\n\t\t\t\t\tmy[a + i][b + j] = '#';\n\t\t\t}\n\t\t}\n\t}\n}\nint main() {\n\tint n, m;\n\tint i, j;\n\tchar tmp;\n\tscanf(\"%d%d\", &n, &m);\n\tfor (i = 0; i < n; i++) {\n\t\tscanf(\"%s\", arr[i]);\n\t}\n\tfor (i = 0; i < n; i++) {\n\t\tfor (j = 0; j < m; j++) {\n\t\t\tmy[i][j] = '.';\n\t\t}\n\t}\n\n\tfor (i = 1; i < n - 1; i++) {\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tstamp(i, j);\n\t\t}\n\t}\n\ti = 0;\n\tfor (i = 0; i < n; i++) {\n\t\tfor (j = 0; j < m; j++) {\n\t\t\tif (my[i][j] != arr[i][j]) {\n\t\t\t\tprintf(\"NO\");\n\t\t\t\tsystem(\"pause\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"YES\");\n\tsystem(\"pause\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d7e468c78f48d2d5e4905817c0cfdded", "src_uid": "49e5eabe8d69b3d27a251cccc001ab25", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <Windows.h>\n\nchar arr[1001][1001];\nchar my[1001][1001];\nint stamp(int a, int b) {\n\tint i, j, c = 1;\n\t//memo\n\n\t//stamp!\n\tfor (i = -1; i <= 1; i++) {\n\t\tfor (j = -1; j <= 1; j++) {\n\t\t\tif (i == 0 && j == 0)\n\t\t\t\tcontinue;\n\t\t\telse if (arr[a + i][b + j] == '#')\n\t\t\t\tcontinue;\n\t\t\telse\n\t\t\t\tc = 0;\n\t\t}\n\t}\n\n\tfor (i = -1; i <= 1; i++) {\n\t\tfor (j = -1; j <= 1; j++) {\n\t\t\tif (i == 0 && j == 0)\n\t\t\t\tcontinue;\n\t\t\telse\n\t\t\t\tmy[a + i][b + j] = '#';\n\t\t}\n\t}\n}\nint main() {\n\tint n, m;\n\tint i, j;\n\tchar tmp;\n\tscanf(\"%d%d\", &n, &m);\n\tfor (i = 0; i < n; i++) {\n\t\tscanf(\"%s\", arr[i]);\n\t}\n\tfor (i = 0; i < n; i++) {\n\t\tfor (j = 0; j < m; j++) {\n\t\t\tmy[i][j] = '.';\n\t\t}\n\t}\n\n\tfor (i = 1; i < n - 1; i++) {\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tstamp(i, j);\n\t\t}\n\t}\n\ti = 0;\n\tfor (i = 0; i < n; i++) {\n\t\tfor (j = 0; j < m; j++) {\n\t\t\tif (my[i][j] != arr[i][j]) {\n\t\t\t\tprintf(\"NO\");\n\t\t\t\tsystem(\"pause\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"YES\");\n\tsystem(\"pause\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "882251aac4b4f9fae3d754a28ccfd5bf", "src_uid": "49e5eabe8d69b3d27a251cccc001ab25", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define ULL unsigned long long\nULL p[16]={2,3,5,7,11,13,17,29,23,29,31,37,41,43,47,53},ans=~0ULL,n;\nvoid dfs(ULL depth,ULL temp,ULL num,ULL up)\n{\n    if(num>n||depth>15)return;\n    if(num==n&&ans>temp)\n    {\n        ans=temp;\n        return;\n    }\n    for(int i=1;i<=up;i++)\n    {\n        if(temp/p[depth]>ans)break;\n        dfs(depth+1,temp*=p[depth],num*(i+1),i);\n    }\n}\n\nint main()\n{\n    scanf(\"%llu\",&n);\n    dfs(0,1,1,64);\n    printf(\"%llu\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "fa3860437a4ce5f4eddbcfef2c3a8e05", "src_uid": "62db589bad3b7023418107de05b7a8ee", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint simp[100000];\nint a[10000];\nint main()\n{\n\tint n;\n\tscanf(\"%d\", &n);\n\tint arr[50];\n\tint f=0;\n\tfor (int i=2; i<1000; i++)\n\t\twhile(n%i==0)\n\t\t\tarr[f++]=i, n/=i;\n\tn = 100000;\n\tint g=0;\n\tfor (int i=0; i<n; ++i)\n\t\tsimp[i]=0;\n\tfor (int i=2; i<n; i++)\n\t\tif(simp[i]==0)\n\t\t{\n\t\t\ta[g++]=i;\n\t\t\tfor (int j=2; j*i<n; j++)\n\t\t\t\tsimp[i*j]=1;\n\n\t\t}\n\tlong long ans = 1;\n\tg=0;\n\tif(f>=3)\n\t{\n\t\tif(arr[f-1]==2)\n\t\t{\n\t\t\tf--;\n\t\t\tarr[f-1]+=2;\n\t\t}\n\t}\n\tfor (int i=f-1; i>=0; i--)\n\t{\n\t\twhile(arr[i]-->1)\n\t\t\tans*=a[g];\n\t\tg++;\n\t}\n\tprintf(\"%I64d\", ans);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f8c01d0b21f3685340ddddbbc087a4e6", "src_uid": "62db589bad3b7023418107de05b7a8ee", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\ntypedef __int64 LL;\nLL p[11052];\nLL prime[30] = { 2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53 };\nvoid getartprime(LL cur, int cnt, int limit, int k) {//cur\uff1a\u5f53\u524d\u679a\u4e3e\u5230\u7684\u6570,cnt\uff1a\u8be5\u6570\u7684\u56e0\u6570\u4e2a\u6570,limit\uff1a\u56e0\u6570\u4e2a\u6570\u7684\u4e0a\u9650\uff1b2^t1*3^t2*5^t3\u2026\u2026t1>=t2>=t3\u2026\u2026,\u7b2ck\u5927\u7684\u7d20\u6570\n\tif (cur>((LL)1 << 60) || cnt>1000) return;\n\t\n\t//if (cnt == 4) cout << cur << endl;\n\t\n\tif (p[cnt] != 0 && p[cnt]>cur)//\u5f53\u524d\u7684\u56e0\u6570\u4e2a\u6570\u5df2\u7ecf\u8bb0\u5f55\u8fc7\u4e14\u5f53\u65f6\u8bb0\u5f55\u7684\u6570\u6bd4\u5f53\u524d\u679a\u4e3e\u5230\u7684\u6570\u8981\u5927\uff0c\u5219\u66ff\u6362\u6b64\u56e0\u6570\u4e2a\u6570\u4e0b\u7684\u679a\u4e3e\u5230\u7684\u6570\n\t\tp[cnt] = cur;\n\tif (p[cnt] == 0)//\u6b64\u56e0\u6570\u4e2a\u6570\u7684\u6570\u8fd8\u6ca1\u6709\u51fa\u73b0\u8fc7\uff0c\u5219\u8bb0\u5f55\n\t\tp[cnt] = cur;\n\tLL temp = cur;\n\tfor (int i = 1; i <= limit; i++) {\t\t//\u679a\u4e3e\u6570\n\t\ttemp = temp*prime[k];\n\t\tif (temp>((LL)1 << 60)) return;\n\t\tgetartprime(temp, cnt*(i + 1), i, k + 1);\n\t}\n}\nint main() {\n\tint n;\n\tmemset(p, 0, sizeof(p));\n\tgetartprime(1, 1, 1000, 0);\n\t/*for (int i = 1; i <= 75; i++) {\n\t\tif (p[i * 2 - 1] != 0 && p[i * 2] != 0)\n\t\t\tp[i] = min(p[i * 2 - 1], p[i * 2]);\n\t\telse if (p[i * 2] != 0)\n\t\t\tp[i] = p[i * 2];\n\t\telse\n\t\t\tp[i] = p[i * 2 - 1];\n\t}*/\n\n\n\twhile (scanf(\"%d\", &n), n)\n\t\tprintf(\"%I64d\\n\", p[n]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "aa33ad4f7c6b98d096d339c36c300727", "src_uid": "62db589bad3b7023418107de05b7a8ee", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define PRM 45\n#define LEN 78777\n#define MAX 1000010\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n#define chkbit(ar, i) (((ar[(i) >> 6]) & (1 << (((i) >> 1) & 31))))\n#define setbit(ar, i) (((ar[(i) >> 6]) |= (1 << (((i) >> 1) & 31))))\n#define isprime(x) (( (x) && ((x)&1) && (!chkbit(ar, (x)))) || ((x) == 2))\n\nconst int P[] = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541};\n\nshort* adj[6725];\nbool visited[6725][PRM];\nlong long lol, div[6725];\ndouble L[PRM], dp[6725][PRM];\nunsigned int ar[(MAX >> 6) + 5] = {0};\nint p, d, len[6725], prime[LEN], temp[6725];\n\nint compare(const void* a, const void* b){\n    long long x = (*(long long*)a);\n    long long y = (*(long long*)b);\n    if (x == y) return 0;\n    return ((x > y) ? -1 : 1);\n}\n\nlong long expo(long long a, long long b){\n    long long res = 1;\n\n    while (b){\n        if (b & 1) res = res *= a;\n        a *= a, b >>= 1;\n    }\n    return res;\n}\n\nvoid Sieve(){\n    int i, j, k;\n    setbit(ar, 0), setbit(ar, 1);\n\n    for (i = 3; (i * i) < MAX; i++, i++){\n        if (!chkbit(ar, i)){\n            for (j = (i * i), k = i << 1; j < MAX; j += k) setbit(ar, j);\n        }\n    }\n\n    prime[0] = 2;\n    for (i = 3, p = 1; i < MAX; i++, i++){\n        if (isprime(i)) prime[p++] = i;\n    }\n}\n\nint divisors(long long x){\n    int i, j, l, k, c, len = 0;\n\n    div[len++] = 1;\n    for (i = 0; i < p; i++){\n        if ((long long)prime[i] * prime[i] > x) break;\n\n        c = 0, k = len;\n        while (!(x % prime[i])){\n            c++;\n            x /= prime[i];\n        }\n\n        long long y = prime[i];\n        for (j = 0; j < c; j++, y *= prime[i]){\n            for (l = 0; l < k; l++){\n                div[len++] = y * div[l];\n            }\n        }\n    }\n\n    if (x > 1){\n        for (j = 0, k = len; j < k; j++) div[len++] = div[j] * x;\n    }\n\n    qsort(div, len, sizeof(long long), compare);\n    return len;\n}\n\nvoid Generate(long long n){\n    int i, j, k, l;\n\n    clr(len);\n    d = divisors(n);\n    for (i = 0; i < d; i++){\n        for (j = i + 1, l = 0; j < d; j++){\n            if (!(div[i] % div[j])) temp[l++] = j;\n        }\n\n        adj[i] = (short*) malloc(l * sizeof(short));\n        for (j = 0; j < l; j++){\n            adj[i][len[i]++] = temp[j];\n        }\n    }\n}\n\ndouble F(int i, int j){\n    if (div[i] == 1) return 0.0;\n    if (j == PRM) return 1e37;\n    if (visited[i][j]) return dp[i][j];\n\n    int k, l;\n    long long r;\n    double x, y, res = 1e37;\n    for (k = 0; k < len[i]; k++){\n        l = adj[i][k], r = div[i] / div[l];\n        x = F(l, j + 1) + (L[j] * (r - 1));\n        if (x < res) res = x;\n        if (r > div[l]) break;\n    }\n\n    visited[i][j] = true;\n    return (dp[i][j] = res);\n}\n\nvoid backtrack(int i, int j){\n    if (div[i] == 1 || j == PRM) return;\n\n    long long r;\n    int k, l, idx;\n    double x, y, res = 1e37;\n    for (k = 0; k < len[i]; k++){\n        l = adj[i][k], r = div[i] / div[l];\n        x = F(l, j + 1) + (L[j] * (r - 1));\n        if (x < res) res = x, idx = l;\n        if (r > div[l]) break;\n    }\n\n    lol = lol * expo(P[j], (div[i] / div[idx]) - 1);\n    backtrack(idx, j + 1);\n}\n\nint main(){\n    Sieve();\n    long long n, r;\n    int T = 0, t, i, j, k, l;\n    for (i = 0; i < PRM; i++) L[i] = log10(P[i]);\n\n    while (scanf(\"%lld\", &n) != EOF){\n        if (n == 0) break;\n\n        Generate(n);\n        clr(visited);\n        lol = 1;\n        backtrack(0, 0);\n        else printf(\"%lld\\n\", lol);\n        for (i = 0; i < d; i++) free(adj[i]);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "0fb1995588e11571e171a198a01a5a93", "src_uid": "62db589bad3b7023418107de05b7a8ee", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define INF ~0ULL\n#define ULL unsigned long long\nusing namespace std;\nULL p[16] = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53};\nULL n, ans;\nvoid dfs(ULL depth, ULL temp, ULL num, ULL up)\n{\n    if (num == n && temp < ans) ans = temp;\n    if (num >= n || depth == 16) return;\n    for (int i = 1; i <= up; ++i)\n    {\n        if (temp * p[depth] >= ans) return;\n        else dfs(depth + 1, temp = temp * p[depth], num * (i + 1), i);\n    }\n}\nint main()\n{\n    while (scanf(\"%llu\", &n) != EOF)\n    {\n        ans = INF;\n        dfs(0, 1, 1, 64);\n        printf(\"%llu\\n\", ans);\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "2b981525f7d1c3056b8e6e0c5da79257", "src_uid": "62db589bad3b7023418107de05b7a8ee", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define N\t200000\n#define L_\t19\t/* L_ = ceil(log2(N * 2 + 1)) */\n#define N_\t(1 << L_)\n#define MD\t998244353\n\nint min(int a, int b) { return a < b ? a : b; }\n\nlong long power(long long a, int k) {\n\tlong long p = 1;\n\n\twhile (k) {\n\t\tif (k & 1)\n\t\t\tp = p * a % MD;\n\t\ta = a * a % MD;\n\t\tk >>= 1;\n\t}\n\treturn p;\n}\n\nint vv[N + 1], ff[N + 1], gg[N + 1], mobius[N + 1];\nint *wwu[L_ + 1], *wwv[L_ + 1], vv_[L_ + 1];\n\nvoid init() {\n\tint i, j, l, u, v;\n\n\tff[0] = gg[0] = 1;\n\tfor (i = 1; i <= N; i++) {\n\t\tvv[i] = i == 1 ? 1 : (long long) vv[i - MD % i] * (MD / i + 1) % MD;\n\t\tff[i] = (long long) ff[i - 1] * i % MD;\n\t\tgg[i] = (long long) gg[i - 1] * vv[i] % MD;\n\t}\n\tfor (i = 2; i <= N; i++) {\n\t\tif (mobius[i])\n\t\t\tcontinue;\n\t\tfor (j = i; j <= N; j += i)\n\t\t\tmobius[j]++;\n\t}\n\tfor (i = 2; i <= N / i; i++)\n\t\tfor (j = i * i; j <= N; j += i * i)\n\t\t\tmobius[j] = -1;\n\tfor (i = 1; i <= N; i++)\n\t\tmobius[i] = mobius[i] == -1 ? 0 : (mobius[i] % 2 == 0 ? 1 : -1);\n\tu = power(3, MD - 1 >> L_), v = power(u, MD - 2);\n\tfor (l = L_; l > 0; l--) {\n\t\tint n = 1 << l, m = n >> 1;\n\n\t\twwu[l] = (int *) malloc(m * sizeof *wwu[l]);\n\t\twwv[l] = (int *) malloc(m * sizeof *wwv[l]);\n\t\twwu[l][0] = wwv[l][0] = 1;\n\t\tfor (i = 1; i < m; i++) {\n\t\t\twwu[l][i] = (long long) wwu[l][i - 1] * u % MD;\n\t\t\twwv[l][i] = (long long) wwv[l][i - 1] * v % MD;\n\t\t}\n\t\tvv_[l] = power(1 << l, MD - 2);\n\t\tu = (long long) u * u % MD, v = (long long) v * v % MD;\n\t}\n\tvv_[0] = 1;\n}\n\nint choose(int n, int k) {\n\treturn (long long) ff[n] * gg[k] % MD * gg[n - k] % MD;\n}\n\nvoid ntt_(int *aa, int l, int inverse) {\n\tif (l) {\n\t\tint n = 1 << l, m = n >> 1, *ww = inverse ? wwv[l] : wwu[l], i, j;\n\n\t\tntt_(aa, l - 1, inverse), ntt_(aa + m, l - 1, inverse);\n\t\tfor (i = 0; (j = i + m) < n; i++) {\n\t\t\tint a = aa[i], b = (long long) aa[j] * ww[i] % MD;\n\n\t\t\tif ((aa[i] = a + b) >= MD)\n\t\t\t\taa[i] -= MD;\n\t\t\tif ((aa[j] = a - b) < 0)\n\t\t\t\taa[j] += MD;\n\t\t}\n\t}\n}\n\nvoid ntt(int *aa, int l, int inverse) {\n\tint n = 1 << l, i, j;\n\n\tfor (i = 1, j = 0; i < n; i++) {\n\t\tint b = n >> 1, tmp;\n\n\t\twhile ((j ^= b) < b)\n\t\t\tb >>= 1;\n\t\tif (i < j)\n\t\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\t}\n\tntt_(aa, l, inverse);\n}\n\nvoid multiply(int *aa, int *bb, int n) {\n\tstatic int aa_[N_], bb_[N_];\n\tint n_, l_, i;\n\n\tl_ = 0;\n\twhile (1 << l_ < n + n - 1)\n\t\tl_++;\n\tn_ = 1 << l_;\n\tfor (i = 0; i < n_; i++) {\n\t\taa_[i] = i < n ? aa[i] : 0;\n\t\tbb_[i] = i < n ? bb[i] : 0;\n\t}\n\tntt(aa_, l_, 0), ntt(bb_, l_, 0);\n\tfor (i = 0; i < n_; i++)\n\t\taa_[i] = (long long) aa_[i] * bb_[i] % MD;\n\tntt(aa_, l_, 1);\n\tfor (i = 0; i < n; i++)\n\t\taa[i] = (long long) aa_[i] * vv_[l_] % MD;\n}\n\nvoid inv(int *aa, int *bb, int n) {\n\tstatic int aa_[N_], bb_[N_];\n\tint m, n_, l_, i;\n\n\tif (n == 1) {\n\t\tbb[0] = 1;\n\t\treturn;\n\t}\n\tm = (n + 1) / 2;\n\tinv(aa, bb, m);\n\tl_ = 0;\n\twhile (1 << l_ < n * 2)\n\t\tl_++;\n\tn_ = 1 << l_;\n\tfor (i = 0; i < n_; i++) {\n\t\taa_[i] = i < n ? aa[i] : 0;\n\t\tbb_[i] = i < m ? bb[i] : 0;\n\t}\n\tntt(aa_, l_, 0), ntt(bb_, l_, 0);\n\tfor (i = 0; i < n_; i++)\n\t\taa_[i] = bb_[i] * (MD + 2 - (long long) aa_[i] * bb_[i] % MD) % MD;\n\tntt(aa_, l_, 1);\n\tfor (i = 0; i < n; i++)\n\t\tbb[i] = (long long) aa_[i] * vv_[l_] % MD;\n}\n\nvoid log_(int *aa, int *bb, int n) {\n\tstatic int pp[N + 1], qq[N + 1];\n\tint i;\n\n\tfor (i = 0; i < n; i++)\n\t\tpp[i] = i + 1 == n ? 0 : (long long) aa[i + 1] * (i + 1) % MD;\n\tinv(aa, qq, n);\n\tmultiply(pp, qq, n);\n\tfor (i = 0; i < n; i++)\n\t\tbb[i] = i == 0 ? 0 : (long long) pp[i - 1] * vv[i] % MD;\n}\n\nvoid exp_(int *aa, int *bb, int n) {\n\tstatic int aa_[N + 1], bb_[N + 1], cc_[N + 1];\n\tint m, i;\n\n\tif (n == 1) {\n\t\tbb[0] = 1;\n\t\treturn;\n\t}\n\tm = (n + 1) / 2;\n\texp_(aa, bb, m);\n\tfor (i = 0; i < n; i++)\n\t\tbb_[i] = i < m ? bb[i] : 0;\n\tlog_(bb_, cc_, n);\n\tfor (i = 0; i < n; i++)\n\t\taa_[i] = (aa[i] - cc_[i] + MD) % MD;\n\taa_[0] = (aa_[0] + 1) % MD;\n\tmultiply(aa_, bb_, n);\n\tfor (i = 0; i < n; i++)\n\t\tbb[i] = aa_[i];\n}\n\nint bell[N + 1];\n\nvoid compute_bell() {\n\tstatic int aa[N + 1];\n\tint i;\n\n\tfor (i = 1; i <= N; i++)\n\t\taa[i] = gg[i];\n\texp_(aa, bell, N + 1);\n\tfor (i = 0; i <= N; i++)\n\t\tbell[i] = (long long) bell[i] * ff[i] % MD;\n}\n\nint sum(int n, int k) {\n\tstatic int aa[N + 1], bb[N + 1];\n\tint i, ans;\n\n\tif (k > n)\n\t\treturn (bell[n] - 1 + MD) % MD;\n\tfor (i = 0; i <= k; i++)\n\t\taa[i] = power(i, n) * gg[i] % MD;\n\tfor (i = 0; i <= k; i++)\n\t\tbb[i] = (long long) (i % 2 == 0 ? 1 : MD - 1) * gg[i] % MD;\n\tmultiply(aa, bb, k + 1);\n\tans = MD - 1;\n\tfor (i = 0; i <= k; i++)\n\t\tans = (ans + aa[i]) % MD;\n\treturn ans;\n}\n\nint main() {\n\tint n, k, d, ans;\n\n\tinit();\n\tscanf(\"%d%d\", &n, &k);\n\tif (k == 1 || n == 1) {\n\t\tprintf(\"1\\n\");\n\t\treturn 0;\n\t}\n\tcompute_bell();\n\tans = 0;\n\tfor (d = 1; d < n; d++)\n\t\tif (mobius[d])\n\t\t\tans = (ans + sum((n + d - 1) / d, k) * mobius[d]) % MD;\n\tif (ans < 0)\n\t\tans += MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a78f6a295c8f538014711e96d64d428f", "src_uid": "eb9d24070cc5b347d020189d803628ae", "difficulty": 2900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define N\t200000\n#define L_\t19\t/* L_ = ceil(log2(N * 2 + 1)) */\n#define N_\t(1 << L_)\n#define MD\t998244353\n\nint min(int a, int b) { return a < b ? a : b; }\n\nlong long power(long long a, int k) {\n\tlong long p = 1;\n\n\twhile (k) {\n\t\tif (k & 1)\n\t\t\tp = p * a % MD;\n\t\ta = a * a % MD;\n\t\tk >>= 1;\n\t}\n\treturn p;\n}\n\nint vv[N + 1], ff[N + 1], gg[N + 1], mobius[N + 1];\nint *wwu[L_ + 1], *wwv[L_ + 1], vv_[L_ + 1];\n\nvoid init() {\n\tint i, j, l, u, v;\n\n\tff[0] = gg[0] = 1;\n\tfor (i = 1; i <= N; i++) {\n\t\tvv[i] = i == 1 ? 1 : (long long) vv[i - MD % i] * (MD / i + 1) % MD;\n\t\tff[i] = (long long) ff[i - 1] * i % MD;\n\t\tgg[i] = (long long) gg[i - 1] * vv[i] % MD;\n\t}\n\tfor (i = 2; i <= N; i++) {\n\t\tif (mobius[i])\n\t\t\tcontinue;\n\t\tfor (j = i; j <= N; j += i)\n\t\t\tmobius[j]++;\n\t}\n\tfor (i = 2; i <= N / i; i++)\n\t\tfor (j = i * i; j <= N; j += i * i)\n\t\t\tmobius[j] = -1;\n\tfor (i = 1; i <= N; i++)\n\t\tmobius[i] = mobius[i] == -1 ? 0 : (mobius[i] % 2 == 0 ? 1 : -1);\n\tu = power(3, MD - 1 >> L_), v = power(u, MD - 2);\n\tfor (l = L_; l > 0; l--) {\n\t\tint n = 1 << l, m = n >> 1;\n\n\t\twwu[l] = (int *) malloc(m * sizeof *wwu[l]);\n\t\twwv[l] = (int *) malloc(m * sizeof *wwv[l]);\n\t\twwu[l][0] = wwv[l][0] = 1;\n\t\tfor (i = 1; i < m; i++) {\n\t\t\twwu[l][i] = (long long) wwu[l][i - 1] * u % MD;\n\t\t\twwv[l][i] = (long long) wwv[l][i - 1] * v % MD;\n\t\t}\n\t\tvv_[l] = power(1 << l, MD - 2);\n\t\tu = (long long) u * u % MD, v = (long long) v * v % MD;\n\t}\n\tvv_[0] = 1;\n}\n\nint choose(int n, int k) {\n\treturn (long long) ff[n] * gg[k] % MD * gg[n - k] % MD;\n}\n\nvoid ntt_(int *aa, int l, int inverse) {\n\tif (l) {\n\t\tint n = 1 << l, m = n >> 1, *ww = inverse ? wwv[l] : wwu[l], i, j;\n\n\t\tntt_(aa, l - 1, inverse), ntt_(aa + m, l - 1, inverse);\n\t\tfor (i = 0; (j = i + m) < n; i++) {\n\t\t\tint a = aa[i], b = (long long) aa[j] * ww[i] % MD;\n\n\t\t\tif ((aa[i] = a + b) >= MD)\n\t\t\t\taa[i] -= MD;\n\t\t\tif ((aa[j] = a - b) < 0)\n\t\t\t\taa[j] += MD;\n\t\t}\n\t}\n}\n\nvoid ntt(int *aa, int l, int inverse) {\n\tint n = 1 << l, i, j;\n\n\tfor (i = 1, j = 0; i < n; i++) {\n\t\tint b = n >> 1, tmp;\n\n\t\twhile ((j ^= b) < b)\n\t\t\tb >>= 1;\n\t\tif (i < j)\n\t\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\t}\n\tntt_(aa, l, inverse);\n}\n\nint solve(int n, int k) {\n\tstatic int aa[N_], bb[N_];\n\tint n_, l_, i, ans;\n\n\tk = min(k, n);\n\tl_ = 0;\n\twhile (1 << l_ < k + k + 1)\n\t\tl_++;\n\tn_ = 1 << l_;\n\tfor (i = 0; i < n_; i++)\n\t\taa[i] = i <= k ? (long long) power(i, n) * gg[i] % MD : 0;\n\tfor (i = 0; i < n_; i++)\n\t\tbb[i] = i <= k ? (long long) (i % 2 == 0 ? 1 : MD - 1) * gg[i] % MD : 0;\n\tntt(aa, l_, 0), ntt(bb, l_, 0);\n\tfor (i = 0; i < n_; i++)\n\t\taa[i] = (long long) aa[i] * bb[i] % MD;\n\tntt(aa, l_, 1);\n\tans = MD - 1;\n\tfor (i = 0; i <= k; i++)\n\t\tans = (ans + (long long) aa[i] * vv_[l_]) % MD;\n\treturn ans;\n}\n\nint main() {\n\tint n, k, d, ans;\n\n\tinit();\n\tscanf(\"%d%d\", &n, &k);\n\tif (k == 1 || n == 1) {\n\t\tprintf(\"1\\n\");\n\t\treturn 0;\n\t}\n\tans = 0;\n\tfor (d = 1; d < n; d++)\n\t\tif (mobius[d])\n\t\t\tans = (ans + solve((n + d - 1) / d, k) * mobius[d]) % MD;\n\tif (ans < 0)\n\t\tans += MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "324833325a1d38a75093a691365defa7", "src_uid": "eb9d24070cc5b347d020189d803628ae", "difficulty": 2900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <stdlib.h>\r\n\r\n#define N\t200000\r\n#define L_\t19\t/* L_ = ceil(log2(N * 2 + 1)) */\r\n#define N_\t(1 << L_)\r\n#define MD\t998244353\r\n\r\nint min(int a, int b) { return a < b ? a : b; }\r\n\r\nlong long power(long long a, int k) {\r\n\tlong long p = 1;\r\n\r\n\twhile (k) {\r\n\t\tif (k & 1)\r\n\t\t\tp = p * a % MD;\r\n\t\ta = a * a % MD;\r\n\t\tk >>= 1;\r\n\t}\r\n\treturn p;\r\n}\r\n\r\nint vv[N + 1], ff[N + 1], gg[N + 1], mobius[N + 1];\r\nint *wwu[L_ + 1], *wwv[L_ + 1], vv_[L_ + 1];\r\n\r\nvoid init() {\r\n\tint i, j, l, u, v;\r\n\r\n\tff[0] = gg[0] = 1;\r\n\tfor (i = 1; i <= N; i++) {\r\n\t\tvv[i] = i == 1 ? 1 : (long long) vv[i - MD % i] * (MD / i + 1) % MD;\r\n\t\tff[i] = (long long) ff[i - 1] * i % MD;\r\n\t\tgg[i] = (long long) gg[i - 1] * vv[i] % MD;\r\n\t}\r\n\tfor (i = 2; i <= N; i++) {\r\n\t\tif (mobius[i])\r\n\t\t\tcontinue;\r\n\t\tfor (j = i; j <= N; j += i)\r\n\t\t\tmobius[j]++;\r\n\t}\r\n\tfor (i = 2; i <= N / i; i++)\r\n\t\tfor (j = i * i; j <= N; j += i * i)\r\n\t\t\tmobius[j] = -1;\r\n\tfor (i = 1; i <= N; i++)\r\n\t\tmobius[i] = mobius[i] == -1 ? 0 : (mobius[i] % 2 == 0 ? 1 : -1);\r\n\tu = power(3, MD - 1 >> L_), v = power(u, MD - 2);\r\n\tfor (l = L_; l > 0; l--) {\r\n\t\tint n = 1 << l, m = n >> 1;\r\n\r\n\t\twwu[l] = (int *) malloc(m * sizeof *wwu[l]);\r\n\t\twwv[l] = (int *) malloc(m * sizeof *wwv[l]);\r\n\t\twwu[l][0] = wwv[l][0] = 1;\r\n\t\tfor (i = 1; i < m; i++) {\r\n\t\t\twwu[l][i] = (long long) wwu[l][i - 1] * u % MD;\r\n\t\t\twwv[l][i] = (long long) wwv[l][i - 1] * v % MD;\r\n\t\t}\r\n\t\tvv_[l] = power(1 << l, MD - 2);\r\n\t\tu = (long long) u * u % MD, v = (long long) v * v % MD;\r\n\t}\r\n\tvv_[0] = 1;\r\n}\r\n\r\nint choose(int n, int k) {\r\n\treturn (long long) ff[n] * gg[k] % MD * gg[n - k] % MD;\r\n}\r\n\r\nvoid ntt_(int *aa, int l, int inverse) {\r\n\tif (l) {\r\n\t\tint n = 1 << l, m = n >> 1, *ww = inverse ? wwv[l] : wwu[l], i, j;\r\n\r\n\t\tntt_(aa, l - 1, inverse), ntt_(aa + m, l - 1, inverse);\r\n\t\tfor (i = 0; (j = i + m) < n; i++) {\r\n\t\t\tint a = aa[i], b = (long long) aa[j] * ww[i] % MD;\r\n\r\n\t\t\tif ((aa[i] = a + b) >= MD)\r\n\t\t\t\taa[i] -= MD;\r\n\t\t\tif ((aa[j] = a - b) < 0)\r\n\t\t\t\taa[j] += MD;\r\n\t\t}\r\n\t}\r\n}\r\n\r\nvoid ntt(int *aa, int l, int inverse) {\r\n\tint n = 1 << l, i, j;\r\n\r\n\tfor (i = 1, j = 0; i < n; i++) {\r\n\t\tint b = n >> 1, tmp;\r\n\r\n\t\twhile ((j ^= b) < b)\r\n\t\t\tb >>= 1;\r\n\t\tif (i < j)\r\n\t\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\r\n\t}\r\n\tntt_(aa, l, inverse);\r\n}\r\n\r\nint solve(int n, int k) {\r\n\tstatic int aa[N_], bb[N_];\r\n\tint n_, l_, i, ans;\r\n\r\n\tk = min(k, n);\r\n\tl_ = 0;\r\n\twhile (1 << l_ < k + k + 1)\r\n\t\tl_++;\r\n\tn_ = 1 << l_;\r\n\tfor (i = 0; i < n_; i++)\r\n\t\taa[i] = i <= k ? (long long) power(i, n) * gg[i] % MD : 0;\r\n\tfor (i = 0; i < n_; i++)\r\n\t\tbb[i] = i <= k ? (long long) (i % 2 == 0 ? 1 : MD - 1) * gg[i] % MD : 0;\r\n\tntt(aa, l_, 0), ntt(bb, l_, 0);\r\n\tfor (i = 0; i < n_; i++)\r\n\t\taa[i] = (long long) aa[i] * bb[i] % MD;\r\n\tntt(aa, l_, 1);\r\n\tans = MD - 1;\r\n\tfor (i = 0; i <= k; i++)\r\n\t\tans = (ans + (long long) aa[i] * vv_[l_]) % MD;\r\n\treturn ans;\r\n}\r\n\r\nint main() {\r\n\tint n, k, d, ans;\r\n\r\n\tinit();\r\n\tscanf(\"%d%d\", &n, &k);\r\n\tif (k == 1 || n == 1) {\r\n\t\tprintf(\"1\\n\");\r\n\t\treturn 0;\r\n\t}\r\n\tans = 0;\r\n\tfor (d = 1; d < n; d++)\r\n\t\tif (mobius[d])\r\n\t\t\tans = (ans + solve((n + d - 1) / d, k) * mobius[d]) % MD;\r\n\tif (ans < 0)\r\n\t\tans += MD;\r\n\tprintf(\"%d\\n\", ans);\r\n\treturn 0;\r\n}\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "48858752bad46de90ee0aa59e77fba0c", "src_uid": "eb9d24070cc5b347d020189d803628ae", "difficulty": 2900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define N\t200000\n#define L_\t19\t/* L_ = ceil(log2(N * 2 + 1)) */\n#define N_\t(1 << L_)\n#define MD\t998244353\n\nint min(int a, int b) { return a < b ? a : b; }\n\nlong long power(long long a, int k) {\n\tlong long p = 1;\n\n\twhile (k) {\n\t\tif (k & 1)\n\t\t\tp = p * a % MD;\n\t\ta = a * a % MD;\n\t\tk >>= 1;\n\t}\n\treturn p;\n}\n\nint vv[N + 1], ff[N + 1], gg[N + 1], mobius[N + 1];\nint *wwu[L_ + 1], *wwv[L_ + 1], vv_[L_ + 1];\n\nvoid init() {\n\tint i, j, l, u, v;\n\n\tff[0] = gg[0] = 1;\n\tfor (i = 1; i <= N; i++) {\n\t\tvv[i] = i == 1 ? 1 : (long long) vv[i - MD % i] * (MD / i + 1) % MD;\n\t\tff[i] = (long long) ff[i - 1] * i % MD;\n\t\tgg[i] = (long long) gg[i - 1] * vv[i] % MD;\n\t}\n\tfor (i = 2; i <= N; i++) {\n\t\tif (mobius[i])\n\t\t\tcontinue;\n\t\tfor (j = i; j <= N; j += i)\n\t\t\tmobius[j]++;\n\t}\n\tfor (i = 2; i <= N / i; i++)\n\t\tfor (j = i * i; j <= N; j += i * i)\n\t\t\tmobius[j] = -1;\n\tfor (i = 1; i <= N; i++)\n\t\tmobius[i] = mobius[i] == -1 ? 0 : (mobius[i] % 2 == 0 ? 1 : -1);\n\tu = power(3, MD - 1 >> L_), v = power(u, MD - 2);\n\tfor (l = L_; l > 0; l--) {\n\t\tint n = 1 << l, m = n >> 1;\n\n\t\twwu[l] = (int *) malloc(m * sizeof *wwu[l]);\n\t\twwv[l] = (int *) malloc(m * sizeof *wwv[l]);\n\t\twwu[l][0] = wwv[l][0] = 1;\n\t\tfor (i = 1; i < m; i++) {\n\t\t\twwu[l][i] = (long long) wwu[l][i - 1] * u % MD;\n\t\t\twwv[l][i] = (long long) wwv[l][i - 1] * v % MD;\n\t\t}\n\t\tvv_[l] = power(1 << l, MD - 2);\n\t\tu = (long long) u * u % MD, v = (long long) v * v % MD;\n\t}\n\tvv_[0] = 1;\n}\n\nint choose(int n, int k) {\n\treturn (long long) ff[n] * gg[k] % MD * gg[n - k] % MD;\n}\n\nvoid ntt_(int *aa, int l, int inverse) {\n\tif (l) {\n\t\tint n = 1 << l, m = n >> 1, *ww = inverse ? wwv[l] : wwu[l], i, j;\n\n\t\tntt_(aa, l - 1, inverse), ntt_(aa + m, l - 1, inverse);\n\t\tfor (i = 0; (j = i + m) < n; i++) {\n\t\t\tint a = aa[i], b = (long long) aa[j] * ww[i] % MD;\n\n\t\t\tif ((aa[i] = a + b) >= MD)\n\t\t\t\taa[i] -= MD;\n\t\t\tif ((aa[j] = a - b) < 0)\n\t\t\t\taa[j] += MD;\n\t\t}\n\t}\n}\n\nvoid ntt(int *aa, int l, int inverse) {\n\tint n = 1 << l, i, j;\n\n\tfor (i = 1, j = 0; i < n; i++) {\n\t\tint b = n >> 1, tmp;\n\n\t\twhile ((j ^= b) < b)\n\t\t\tb >>= 1;\n\t\tif (i < j)\n\t\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\t}\n\tntt_(aa, l, inverse);\n}\n\nint solve(int n, int k) {\n\tstatic int aa[N_], bb[N_];\n\tint n_, l_, i, ans;\n\n\tl_ = 0;\n\twhile (1 << l_ < k + k + 1)\n\t\tl_++;\n\tn_ = 1 << l_;\n\tfor (i = 0; i < n_; i++)\n\t\taa[i] = i <= k ? (long long) power(i, n) * gg[i] % MD : 0;\n\tfor (i = 0; i < n_; i++)\n\t\tbb[i] = i <= k ? (long long) (i % 2 == 0 ? 1 : MD - 1) * gg[i] % MD : 0;\n\tntt(aa, l_, 0), ntt(bb, l_, 0);\n\tfor (i = 0; i < n_; i++)\n\t\taa[i] = (long long) aa[i] * bb[i] % MD;\n\tntt(aa, l_, 1);\n\tans = MD - 1;\n\tfor (i = 0; i <= k; i++)\n\t\tans = (ans + (long long) aa[i] * vv_[l_]) % MD;\n\treturn ans;\n}\n\nint main() {\n\tint n, k, d, ans;\n\n\tinit();\n\tscanf(\"%d%d\", &n, &k);\n\tif (k == 1) {\n\t\tprintf(\"1\\n\");\n\t\treturn 0;\n\t}\n\tans = 0;\n\tfor (d = 1; d < n; d++)\n\t\tif (mobius[d])\n\t\t\tans = (ans + solve((n + d - 1) / d, k) * mobius[d]) % MD;\n\tif (ans < 0)\n\t\tans += MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3df4e23ed22d272f555faee04ca1f9f6", "src_uid": "eb9d24070cc5b347d020189d803628ae", "difficulty": 2900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define N\t200000\n#define L_\t21\t/* L_ = ceil(log2(N * 2 + 1)) */\n#define N_\t(1 << L_)\n#define MD\t998244353\n\nint min(int a, int b) { return a < b ? a : b; }\n\nlong long power(long long a, int k) {\n\tlong long p = 1;\n\n\twhile (k) {\n\t\tif (k & 1)\n\t\t\tp = p * a % MD;\n\t\ta = a * a % MD;\n\t\tk >>= 1;\n\t}\n\treturn p;\n}\n\nint vv[N + 1], ff[N + 1], gg[N + 1], mobius[N + 1];\nint *wwu[L_ + 1], *wwv[L_ + 1], vv_[L_ + 1];\n\nvoid init() {\n\tint i, j, l, u, v;\n\n\tff[0] = gg[0] = 1;\n\tfor (i = 1; i <= N; i++) {\n\t\tvv[i] = i == 1 ? 1 : (long long) vv[i - MD % i] * (MD / i + 1) % MD;\n\t\tff[i] = (long long) ff[i - 1] * i % MD;\n\t\tgg[i] = (long long) gg[i - 1] * vv[i] % MD;\n\t}\n\tfor (i = 2; i <= N; i++) {\n\t\tif (mobius[i])\n\t\t\tcontinue;\n\t\tfor (j = i; j <= N; j += i)\n\t\t\tmobius[j]++;\n\t}\n\tfor (i = 2; i <= N / i; i++)\n\t\tfor (j = i * i; j <= N; j += i * i)\n\t\t\tmobius[j] = -1;\n\tfor (i = 1; i <= N; i++)\n\t\tmobius[i] = mobius[i] == -1 ? 0 : (mobius[i] % 2 == 0 ? 1 : -1);\n\tu = power(3, MD - 1 >> L_), v = power(u, MD - 2);\n\tfor (l = L_; l > 0; l--) {\n\t\tint n = 1 << l, m = n >> 1;\n\n\t\twwu[l] = (int *) malloc(m * sizeof *wwu[l]);\n\t\twwv[l] = (int *) malloc(m * sizeof *wwv[l]);\n\t\twwu[l][0] = wwv[l][0] = 1;\n\t\tfor (i = 1; i < m; i++) {\n\t\t\twwu[l][i] = (long long) wwu[l][i - 1] * u % MD;\n\t\t\twwv[l][i] = (long long) wwv[l][i - 1] * v % MD;\n\t\t}\n\t\tvv_[l] = power(1 << l, MD - 2);\n\t\tu = (long long) u * u % MD, v = (long long) v * v % MD;\n\t}\n\tvv_[0] = 1;\n}\n\nint choose(int n, int k) {\n\treturn (long long) ff[n] * gg[k] % MD * gg[n - k] % MD;\n}\n\nvoid ntt_(int *aa, int l, int inverse) {\n\tif (l) {\n\t\tint n = 1 << l, m = n >> 1, *ww = inverse ? wwv[l] : wwu[l], i, j;\n\n\t\tntt_(aa, l - 1, inverse), ntt_(aa + m, l - 1, inverse);\n\t\tfor (i = 0; (j = i + m) < n; i++) {\n\t\t\tint a = aa[i], b = (long long) aa[j] * ww[i] % MD;\n\n\t\t\tif ((aa[i] = a + b) >= MD)\n\t\t\t\taa[i] -= MD;\n\t\t\tif ((aa[j] = a - b) < 0)\n\t\t\t\taa[j] += MD;\n\t\t}\n\t}\n}\n\nvoid ntt(int *aa, int l, int inverse) {\n\tint n = 1 << l, i, j;\n\n\tfor (i = 1, j = 0; i < n; i++) {\n\t\tint b = n >> 1, tmp;\n\n\t\twhile ((j ^= b) < b)\n\t\t\tb >>= 1;\n\t\tif (i < j)\n\t\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\t}\n\tntt_(aa, l, inverse);\n}\n\nint solve(int n, int k) {\n\tstatic int aa[N_], bb[N_];\n\tint n_, l_, i, ans;\n\n\tl_ = 0;\n\twhile (1 << l_ < k + k + 1)\n\t\tl_++;\n\tn_ = 1 << l_;\n\tfor (i = 0; i < n_; i++)\n\t\taa[i] = i <= k ? (long long) power(i, n) * gg[i] % MD : 0;\n\tfor (i = 0; i < n_; i++)\n\t\tbb[i] = i <= k ? (long long) (i % 2 == 0 ? 1 : MD - 1) * gg[i] % MD : 0;\n\tntt(aa, l_, 0), ntt(bb, l_, 0);\n\tfor (i = 0; i < n_; i++)\n\t\taa[i] = (long long) aa[i] * bb[i] % MD;\n\tntt(aa, l_, 1);\n\tans = MD - 1;\n\tfor (i = 0; i <= k; i++)\n\t\tans = (ans + (long long) aa[i] * vv_[l_]) % MD;\n\treturn ans;\n}\n\nint main() {\n\tint n, k, d, ans;\n\n\tinit();\n\tscanf(\"%d%d\", &n, &k);\n\tif (k == 1) {\n\t\tprintf(\"1\\n\");\n\t\treturn 0;\n\t}\n\tans = 0;\n\tfor (d = 1; d < n; d++)\n\t\tif (mobius[d])\n\t\t\tans = (ans + solve((n + d - 1) / d, k) * mobius[d]) % MD;\n\tif (ans < 0)\n\t\tans += MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0e8dfe83a0eddf475f049b8c12c7ad98", "src_uid": "eb9d24070cc5b347d020189d803628ae", "difficulty": 2900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <inttypes.h>\n#include <stdint.h>\n\nint min(int a,int b)\n{\n    if (a>b)\n        return b;\n\n    return a;\n}\n\nint max(int a,int b)\n{\n    if (a>b)\n        return a;\n\n    return b;\n}\n\nuint64_t mini = 1ULL << 62;\nint a1m = 0,b1m = 0,b2m = 0,a2m = 0;\n\nvoid dp(uint64_t count,int a1b1,int a2b2, int a1, int b1,int a2, int b2)\n{\n    if ((a1b1) == (a2b2))\n    {\n        if (count<mini)\n        {\n            a1m = a1;\n            b1m = b1;\n            a2m = a2;\n            b2m = b2;\n            mini = count;\n        }\n        return;\n    }\n\n    if (a1b1 > a2b2)\n    {\n        if ((a1b1%2) == 0)\n        {\n            if (((a1%2)==0) && (a1 > b1))\n            {\n                a1 /= 2;\n            }\n            else\n            {\n                b1 /= 2;\n            }\n            dp(count+1,a1b1/2,a2b2,a1, b1, a2, b2);\n        }\n        if ((a1b1%3) == 0)\n        {\n            if (((a1%3)==0) && (a1 > b1))\n            {\n                a1 = (2*a1)/3;\n            }\n            else\n            {\n                b1 = (2*b1)/3;\n            }\n            dp(count+1,(2*a1b1)/3,a2b2,a1, b1, a2, b2);\n        }\n    }\n    else\n    {\n        if (a2b2%2 == 0)\n        {\n            if (((a2%2)==0) && (a2 > b2))\n            {\n                a2 /= 2;\n            }\n            else\n            {\n                b2 /= 2;\n            }\n            dp(count+1,a1b1,a2b2/2,a1, b1, a2, b2);\n        }\n        if (a2b2%3 == 0)\n        {\n            if (((a2%3)==0) && (a2 > b2))\n            {\n                a2 = (2*a2)/3;\n            }\n            else\n            {\n                b2 = (2*b2)/3;\n            }\n            dp(count+1,a1b1,(2*a2b2)/3,a1, b1, a2, b2);\n        }\n    }\n}\n\nint main()\n{\n    uint64_t count = 0;\n    int a1,b1,a2,b2;\n    scanf(\"%d %d\", &a1, &b1);\n    scanf(\"%d %d\", &a2, &b2);\n\n    dp(0,a1*b1,a2*b2,a1, b1, a2, b2);\n\n    if (mini == (1ULL << 62))\n    {\n        printf(\"-1\\n\");\n        return 0;\n    }\n\n    printf(\"%I64d\\n\", mini);\n    printf(\"%d %d\\n\", a1m,b1m);\n    printf(\"%d %d\\n\", a2m,b2m);\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "180d25828dff73667a740939d88e719b", "src_uid": "4fcd8c4955a47661462c326cbb3429bd", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <inttypes.h>\n#include <stdint.h>\n\nint min(int a,int b)\n{\n    if (a>b)\n        return b;\n\n    return a;\n}\n\nint max(int a,int b)\n{\n    if (a>b)\n        return a;\n\n    return b;\n}\n\nuint64_t mini = 1ULL << 62;\nint a1m = 0,b1m = 0,b2m = 0,a2m = 0;\n\nvoid dp(uint64_t count,int a1b1,int a2b2, int a1, int b1,int a2, int b2)\n{\n    if ((a1b1) == (a2b2))\n    {\n        if (count<mini)\n        {\n            a1m = a1;\n            b1m = b1;\n            a2m = a2;\n            b2m = b2;\n            mini = count;\n        }\n        return;\n    }\n\n    if (a1b1 > a2b2)\n    {\n        if ((a1b1%2) == 0)\n        {\n            if (((a1%2)==0) && (a1 < b1))\n            {\n                a1 /= 2;\n            }\n            else if (((b1%2)==0) && (b1 < a1))\n            {\n                b1 /= 2;\n            }\n            dp(count+1,a1b1/2,a2b2,a1, b1, a2, b2);\n        }\n        if ((a1b1%3) == 0)\n        {\n            if (((a1%3)==0))\n            {\n                a1 = (2*a1)/3;\n            }\n            else if (((b1%2)==0))\n            {\n                b1 = (2*b1)/3;\n            }\n            dp(count+1,(2*a1b1)/3,a2b2,a1, b1, a2, b2);\n        }\n    }\n    else\n    {\n        if (a2b2%2 == 0)\n        {\n            if (((a2%2)==0) && (a2 < b2))\n            {\n                a2 /= 2;\n            }\n            else if (((b2%2)==0) && (b2 < a2))\n            {\n                b2 /= 2;\n            }\n            dp(count+1,a1b1,a2b2/2,a1, b1, a2, b2);\n        }\n        if (a2b2%3 == 0)\n        {\n            if (((a2%3)==0))\n            {\n                a2 = (2*a2)/3;\n            }\n            else if (((b2%3)==0))\n            {\n                b2 = (2*b2)/3;\n            }\n            dp(count+1,a1b1,(2*a2b2)/3,a1, b1, a2, b2);\n        }\n    }\n}\n\nint main()\n{\n    uint64_t count = 0;\n    int a1,b1,a2,b2;\n    scanf(\"%d %d\", &a1, &b1);\n    scanf(\"%d %d\", &a2, &b2);\n\n    dp(0,a1*b1,a2*b2,a1, b1, a2, b2);\n\n    if (mini == (1ULL << 62))\n    {\n        printf(\"-1\\n\");\n        return 0;\n    }\n\n    printf(\"%I64d\\n\", mini);\n    printf(\"%d %d\\n\", a1m,b1m);\n    printf(\"%d %d\\n\", a2m,b2m);\n\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0f4ab8cedef8adb1b57430f9ef6ecde6", "src_uid": "4fcd8c4955a47661462c326cbb3429bd", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nlong long x1, x2, y1, y2, two[1000], three[1000];\nint vis[100010], P[100000], tot;\nint list[4][100000], top[4], temp, temp1;\n\nvoid cal(int t[], long long num) {\n    int i;\n    for (i = 1; i <= tot && num > 1; i++) {\n        while (num > 1 && num % P[i] == 0) {\n            t[i]++;\n            num /= P[i];\n        //  printf(\"%lld\\n\", num);\n        }\n    }\n    if (num > 1) {\n        P[++tot] = num;\n        t[tot]++;\n    }\n}\n\nint main() {\n    int i, j;\n    int thcnt1, thcnt2, twocnt1, twocnt2;\n    for (i = 2; i <= 100000; i++) {\n        if (!vis[i]) P[++tot] = i;\n        for (j = 1; j <= tot && P[j] * i <= 100000; j++) {\n            vis[P[j] * i] = 1;\n            if (i % P[j] == 0) break;\n        }\n    }\n    two[1] = 2;\n    for (i = 2; i <= 50; i++) two[i] = two[i - 1] * 2;\n    three[1] = 3;\n    for (i = 2; i <= 30; i++) three[i] = three[i - 1] * 3;  \n//  for (i = 1; i <= 10; i++) printf(\"%d \", P[i]);\n    scanf(\"%I64d%I64d%I64d%I64d\", &x1, &y1, &x2, &y2);\n    if (x1 * y1 == x2 * y2) {\n        printf(\"0\\n%I64d %I64d\\n%I64d %I64d\\n\", x1, y1, x2, y2);\n        return 0;   \n    }\n    cal(list[0], x1); cal(list[1], y1);\n    cal(list[2], x2); cal(list[3], y2);\n//  printf(\"hehe\\n\");\n    for (i = 3; i <= tot; i++) {\n        if (list[0][i] + list[1][i] != list[2][i] + list[3][i]) {\n            printf(\"%d %d %d %d %d %d\\n\", i, P[i], list[0][i], list[1][i], list[2][i], list[3][i]);\n            printf(\"-1\\n\");\n            return 0;\n        }\n    }\n    thcnt1 = list[0][2] + list[1][2];\n    thcnt2 = list[2][2] + list[3][2];\n    twocnt1 = list[0][1] + list[1][1];\n    twocnt2 = list[2][1] + list[3][1];\n//  printf(\"%d %d %d %d\\n\", thcnt1, thcnt2, twocnt1, twocnt2);\n    if (thcnt1 > thcnt2) {\n        twocnt1 += thcnt1 - thcnt2;\n        temp = thcnt1 - thcnt2;\n        if (list[0][2] >= temp) {\n            x1 /= three[temp];\n            x1 *= two[temp];\n        }\n        else {\n            x1 /= three[list[0][2]];\n            x1 *= two[list[0][2]];\n            y1 /= three[temp - list[0][2]];\n            y1 *= two[temp - list[0][2]];\n        }\n    }\n//  printf(\"%lld %lld %lld %lld\\n\", x1, y1, x2, y2);\n    if (thcnt1 < thcnt2){\n        twocnt2 += thcnt2 - thcnt1;\n        temp = thcnt2 - thcnt1;\n        if (list[2][2] >= temp) {\n            x2 /= three[temp];\n            x2 *= two[temp];\n        }\n        else {\n            x2 /= three[list[2][2]];\n            x2 *= two[list[2][2]];\n            y2 /= three[temp - list[2][2]];\n            y2 *= two[temp - list[2][2]];\n        }\n    }\n//  printf(\"%d %d %d %d\\n\", thcnt1, thcnt2, twocnt1, twocnt2);  \n    if (twocnt1 > twocnt2) {\n        temp += twocnt1 - twocnt2;\n        temp1 = twocnt1 - twocnt2;\n        if (list[0][1] >= temp1) x1 /= two[temp1];\n        else {\n            x1 /= two[list[0][1]];\n            y1 /= two[temp1 - list[0][1]];\n        }\n    }\n    else if (twocnt2 > twocnt1) {\n        temp += twocnt2 - twocnt1;\n        temp1 = twocnt2 - twocnt1;\n        if (list[2][1] >= temp1) x2 /= two[temp1];\n        else  {\n            x2 /= two[list[2][1]];\n            y2 /= two[temp1 - list[2][1]];\n        }\n    }\n    printf(\"%d\\n\", temp);\n    printf(\"%I64d %I64d\\n%I64d %I64d\\n\", x1, y1, x2, y2);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "0f3c30651b05eace3528e370a66beebc", "src_uid": "4fcd8c4955a47661462c326cbb3429bd", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint a[4],b[4],a2[4],a3[4];\n\nvoid div3(int k,int u)\n{\n\tif(a3[k]>=u) {a[k]/=pow(3,u);a[k]*=pow(2,u);a2[k]+=u;}\n\telse {\n\t\ta[k]/=pow(3,a3[k]); a[k]*=pow(2,a3[k]); a2[k]+=a3[k];\n\t\ta[k+1]/=pow(3,u-a3[k]); a[k+1]*=pow(2,u-a3[k]); a2[k+1]+= (u-a3[k]);\n\t}\n}\n\nvoid div2(int k,int v)\n{\n\tif(a2[k]>=v) a[k]/=pow(2,v);\n\telse {\n\t\ta[k]/=pow(2,a2[k]);\n\t\ta[k+1]/=pow(2,v-a2[k]);\n\t}\n}\n\n\nint main()\n{\n\tint i,t,u,v;\n\tfor(i=0;i<4;i++)\n\t{\n\t\tscanf(\"%d\",a+i);\n\t\tb[i]=a[i];a2[i]=0;a3[i]=0;\n\t\twhile(b[i]!=1&&b[i]%2==0) {a2[i]++;b[i]/=2;}\n\t\twhile(b[i]!=1&&b[i]%3==0) {a3[i]++;b[i]/=3;}\n\t}\n\tif((long long)b[0]*b[1]!=(long long)b[2]*b[3])\n\t\t{printf(\"-1\\n\");return 0;}\n\tu = (a3[0]+a3[1]) - (a3[2]+a3[3]);\n\tv = (a2[0]+a2[1]) - (a2[2]+a2[3]) + u;\n\tif(v<0) t=-v; else t=v;\n\tif(u<0) t-=u; else t+=u;\n\tprintf(\"%d\\n\",t);\n\tif(u>0) div3(0,u);\n\telse if(u<0) div3(2,-u);\n\tif(v>0) div2(0,v);\n\telse if(v<0) div2(2,-v);\n\tprintf(\"%d %d\\n%d %d\\n\",a[0],a[1],a[2],a[3]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1a85eee81efda21adfca4ddcc811673c", "src_uid": "4fcd8c4955a47661462c326cbb3429bd", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long int fun(long long int a, long long int b)\n{\n    long long int ans=0;\n    while(a%b==0)\n    {\n        a/=b;\n        ans++;\n    }\n    return ans;\n}\n\nint main()\n{\n    long long int a, b, c, d, i, ans=0;\n    scanf(\"%lld %lld %lld %lld\", &a, &b, &c, &d);\n    for(i=3; i>1; i--)\n    {\n        while(fun(a, i)+fun(b, i) != fun(c, i)+fun(d, i))\n        {\n            ans++;\n            if(fun(a, i)+fun(b, i) > fun(c, i)+fun(d, i))\n            {\n                if(fun(a, i))\n                    a/=i*(i-1);\n                else\n                    b/=i*(i-1);\n            }\n            else\n            {\n                if(fun(c, i))\n                    c/=i*(i-1);\n                else\n                    d/=i*(i-1);\n            }\n        }\n    }\n    if(a*b!=c*d)\n        printf(\"-1\\n\");\n    else\n        printf(\"%lld\\n%lld %lld\\n%lld %lld\\n\", ans, a, b, c, d);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8be1285927593433a0765a39796200bf", "src_uid": "4fcd8c4955a47661462c326cbb3429bd", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\ntypedef long long ll;\nchar s[4][105] = {\"What are you doing at the end of the world? Are you busy? Will you save us?\", \"What are you doing while sending \\\"\", \"\\\"? Are you busy? Will you send \\\"\", \"\\\"?\"};\nll lens[4], lenf[100005], zuida;\n\nchar DFS(ll n, ll k)\n{\n    if(n == 0) return k < lenf[0] ? s[0][k] : '.';\n    if(lenf[n] <= k) return '.';\n    if(k < lens[1]) return s[1][k];\n    if(k < lens[1] + lenf[n - 1])\n        return DFS(n - 1, k - lens[1]);\n    if(k < lens[1] + lenf[n - 1] + lens[2])\n        return s[2][k - lens[1] - lenf[n - 1]];\n    if(k < lens[1] + lenf[n - 1] + lens[2] + lenf[n - 1])\n        return DFS(n - 1, k - lens[1] - lenf[n - 1] - lens[2]);\n    return s[3][k - lens[1] - lenf[n - 1] - lens[2] - lenf[n - 1]];\n}\n\nint main()\n{\n    ll q, n, k, i;\n    scanf(\"%I64d\", &q);\n    for(i = 0; i < 4; ++i)\n        lens[i] = strlen(s[i]);\n    lenf[0] = lens[0];\n    for(zuida = 1; lenf[zuida - 1] <= 2e18; ++zuida)\n        lenf[zuida] = 2 * lenf[zuida - 1] + lens[1] + lens[2] + lens[3];\n    for(i = zuida; i <= 100002; ++i)\n        lenf[i] = lenf[i - 1];\n    while(q--)\n    {\n        scanf(\"%I64d%I64d\", &n, &k);\n        --k;\n        printf(\"%c\", DFS(n, k));\n    }\n    puts(\"\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "250d13d56089cb0810fcecbb1143d659", "src_uid": "da09a893a33f2bf8fd00e321e16ab149", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#define __STDC_FORMAT_MACROS\n#include <inttypes.h>\n#include <assert.h>\n\nconst char* f0  = \"What are you doing at the end of the world? Are you busy? Will you save us?\";\nconst char* fi1 = \"What are you doing while sending \\\"\";\nconst char* fi2 = \"\\\"? Are you busy? Will you send \\\"\";\nconst char* fi3 = \"\\\"?\";\nstatic const int f0len = 75, fi1len = 34, fi2len = 32, fi3len = 2;\n\n#define MAX_N 100000\nstatic int64_t _flen[MAX_N+1] = {};\n\n#define MAX_K 1000000000000000000LL\n\nstatic char dfs(int64_t N, int64_t* K) {\n    if(N == 0) {                                // leaf of the tree\n        if(*K >= f0len) {\n            *K -= f0len; return '.';\n        } else {\n            char c = f0[*K]; *K = 0; return c;\n        }\n    }\n    if(*K < fi1len) {                           // inside fi1\n        char c = fi1[*K]; *K = 0; return c;\n    }\n    *K -= fi1len;\n\n    if(_flen[N-1] == 0) {                       // need memoize\n        const int64_t kk = *K;\n        const char c = dfs(N-1, K);             // dfs into the first child\n        if(c == '.') _flen[N-1] = kk - *K;\n        else         return c;\n    } else {\n        if(*K < _flen[N-1]) {                   // dfs into the first child\n            char c = dfs(N-1, K); *K = 0; return c;\n        } else *K -= _flen[N-1];                // just skip this child\n    }\n    assert(_flen[N-1]);\n\n    if(*K < fi2len) {                           // inside fi2\n        char c = fi2[*K]; *K = 0; return c;\n    }\n    *K -= fi2len;\n\n    assert(_flen[N-1]);\n    if(*K < _flen[N-1]) {                       // dfs into the second child\n        char c = dfs(N-1, K); *K = 0; return c;\n    } else *K -= _flen[N-1];                    // just skip this child\n\n    if(*K < fi3len) {                           // inside fi3\n        char c = fi3[*K]; *K = 0; return c;\n    }\n    *K -= fi3len;\n    return '.';\n}\n\nint main() {\n    _flen[0] = f0len;\n    int Q; scanf(\"%d\\n\", &Q); while(Q--) {\n        int64_t N,K; scanf(\" %\"PRId64 \" %\"PRId64 \"\\n\", &N, &K);\n        --K; printf(\"%c\", dfs(N,&K));\n    }\n    printf(\"\\n\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "36ebc65640c6e951cef956ee7dc57f24", "src_uid": "da09a893a33f2bf8fd00e321e16ab149", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nchar s1[200]=\"What are you doing at the end of the world? Are you busy? Will you save us?\";\nchar s2[100]=\"What are you doing while sending \\\"\";\nchar s3[100]=\"\\\"? Are you busy? Will you send \\\"\";\nchar s4[7]=\"\\\"?\";\nlong long int arr[100012];\nchar letter(long long int n,long long int k){\nlong long int z,i;\nlong long int l1=strlen(s1),l2=strlen(s2),l3=strlen(s3),l4=strlen(s4);\nif(k>arr[n]){\nreturn '.';\n}\nif(n==0){\nreturn s1[k-1];}\nif(k<=34){\nreturn s2[k-1];\n}\nk-=l2;\nif(k<=arr[n-1]){\nreturn letter(n-1,k);}\nk=k-arr[n-1];\nif(k<=l3){\nreturn s3[k-1];}\nk=k-l3;\nif(k<=arr[n-1]){\nreturn letter(n-1,k);}\nk=k-arr[n-1];\nif(k<=2){\nreturn s4[k-1];\n}\n}\nint main(){\nlong long int q,n,k,i;\nchar z[11];\nscanf(\"%lld\",&q);\narr[0]=75;\narr[1]=218;\nfor(i=2;i<=55;i++){\narr[i]=arr[i-1]*2+68;\n}\nfor(i=55;i<100010;i++){\narr[i]=arr[53];\n}\nfor(i=1;i<=q;i++){\nscanf(\"%lld\",&n);\nscanf(\"%lld\",&k);\nz[i]=letter(n,k);\n}\nfor(i=1;i<=q;i++){\nprintf(\"%c\",z[i]);\n}\nprintf(\"\\n\");\nreturn 0;\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c2ca85a3921f6aef021b7f3ddab2b85f", "src_uid": "da09a893a33f2bf8fd00e321e16ab149", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <math.h>\nchar* tmps1=\"What are you doing while sending \\\"\";\nchar* tmps2=\"\\\"? Are you busy? Will you send \\\"\";\nchar* tmps3=\"\\\"?\";\nchar* f0=\"What are you doing at the end of the world? Are you busy? Will you save us?\";\nlong long pow2[54]={1};\nchar calc(int n,long long k)\n{\n\tif (n==0) return f0[k-1];\n\tif (k<=strlen(tmps1)) return tmps1[k-1];\n\tk-=strlen(tmps1);\n\tlong long len1=pow2[n-1]*143-68;\n\tif (k<=len1) return calc(n-1,k);\n\tk-=len1;\n\tif (k<=strlen(tmps2)) return tmps2[k-1];\n\tk-=strlen(tmps2);\n\tif (k<=len1) return calc(n-1,k);\n\tk-=len1;\n\treturn tmps3[k-1];\n}\nint main()\n{\n\tint i;\n\tfor (i=1;i<=53;i++) pow2[i]=2*pow2[i-1];\n\tint q;\n\tscanf(\"%d\",&q);\n\twhile (q--)\n\t{\n\t\tint n; long long k;\n\t\tscanf(\"%d%I64d\",&n,&k);\n\t\tif (n<=53&&k>pow2[n]*143-68)\n\t\t{\n\t\t\tprintf(\".\"); continue;\n\t\t}\n\t\tif (k<34*n)\n\t\t{\n\t\t\t printf(\"%c\",tmps1[(k-1)%34]);\n\t\t\t continue;\n\t\t}\n\t\tif (n>53)\n\t\t{\n\t\t\tprintf(\"%c\",calc(53,k-34*(n-53)));\n\t\t}\n\t\telse printf(\"%c\",calc(n,k));\n\t}\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "094c2f4bfc866a82dde8b47105a2c8e9", "src_uid": "da09a893a33f2bf8fd00e321e16ab149", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <math.h>\nchar* tmps1=\"What are you doing while sending \\\"\";\nchar* tmps2=\"\\\"? Are you busy? Will you send \\\"\";\nchar* tmps3=\"\\\"?\";\nchar* f0=\"What are you doing at the end of the world? Are you busy? Will you save us?\";\nlong long pow2[54]={1};\nchar calc(int n,long long k)\n{\n\tif (n==0) return f0[k-1];\n\tif (k<=strlen(tmps1)) return tmps1[k-1];\n\tk-=strlen(tmps1);\n\tlong long len1=pow2[n-1]*143-68;\n\tif (k<=len1) return calc(n-1,k);\n\tk-=len1;\n\tif (k<=strlen(tmps2)) return tmps2[k-1];\n\tk-=strlen(tmps2);\n\tif (k<=len1) return calc(n-1,k);\n\tk-=len1;\n\treturn tmps3[k-1];\n}\nint main()\n{\n\tint i;\n\tfor (i=1;i<=53;i++) pow2[i]=2*pow2[i-1];\n\tint q;\n\tscanf(\"%d\",&q);\n\twhile (q--)\n\t{\n\t\tint n; long long k;\n\t\tscanf(\"%d%I64d\",&n,&k);\n\t\tif (n<=53&&k>pow2[n]*143-68)\n\t\t{\n\t\t\tprintf(\".\"); continue;\n\t\t}\n\t\tif (k<34*n)\n\t\t{\n\t\t\t printf(\"%c\",tmps1[(k-1)%34]);\n\t\t\t continue;\n\t\t}\n\t\tif (n>53)\n\t\t{\n\t\t\tprintf(\"%c\",calc(53,k-34*(n-53)));\n\t\t}\n\t\telse printf(\"%c\",calc(n,k))\n\t}\n\tprintf(\"\\n\")\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "da96f7a8180a38d3020eb83e81649fe8", "src_uid": "da09a893a33f2bf8fd00e321e16ab149", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n\n\nint main()\n{\n\tint n;\n\n\tscanf(\"%d\", &n);\n\n\n\tint a[] = { 0,4,10,20,35,56,83,116,155,198,244,292 };\n\n\tif (n < 12)\n\t\tprintf(\"%d\", a[n]);\n\telse\n\t\tprintf(\"%d\", a[11] + (n - 11) * 49);\n\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ff2711aef12198b96d5ceb9707616098", "src_uid": "75ec99318736a8a1b62a8d51efd95355", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n#include <ctype.h>\n#include <string.h>\n\nlong long int Input;\nlong long int A, B, i, x, y, Ans;\nlong long int Test;\n\nvoid DFS(long long int Number, int UsedA, int UsedB){\n    Number *= 10;\n    if (Number+A<=Input){\n        UsedA = 1;\n        if (UsedA) if (UsedB) if (Number+A>=10) Ans++;\n        if (A || Number+A) DFS(Number+A, UsedA, UsedB);\n    }\n    if (A!=B) if (Number+B<=Input){\n        UsedB = 1;\n        if (UsedA) if (UsedB) if (Number+B>=10) Ans++;\n        if (B || Number+B) DFS(Number+B, UsedA, UsedB);\n    }\n}\n\nint main(){\n    while(~scanf(\"%I64d\", &Input)){\n        Ans = 0;\n        for (A=1; A<=Input; A++){\n            if (A>9) break;\n            Ans++;\n        }\n        \n        for (A=0; A<10; A++) for (B=A+1; B<10; B++) if (A+B){\n            DFS(0, 0, 0);\n        }\n        \n        \n        printf(\"%I64d\\n\", Ans);\n    }\n    \n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "edbc471ea0da43bc86d31f14aa94031b", "src_uid": "0f7f10557602c8c2f2eb80762709ffc4", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(int argc, char const *argv[])\n{int c=0,z,n,p=1,l,ans,a,i,r,flag,j,y,q,q1,ar[100],h;\n\tscanf(\"%d\",&n);\n\tz=n;\n\tif(n<=100)\n\t{\n\t\tprintf(\"%d\\n\", n);\n\t\treturn 0;\n\t}\n\twhile(z!=0)\n\t{\n\t\tz=z/10;\n\t\tc++;\n\t\t//printf(\"1\\n\");\n\t}\n\t//printf(\"%dd\\n\",c );\n\tl=c;\n\tc=c-1;\n\tfor (int i = 0; i < c; ++i)\n\t{\n\t\tp=p*2;\n\t\tar[i]=p;\n\t\t//printf(\"2\\n\");\n\t}\n\tp=p/2;\n\tprintf(\"p is %d\\n\", p);\n\tans=50*p-1;\n\tprintf(\"ans is %d\\n\",ans );\n\ty=n;\n\t\tfor (int i = 0; i < c; ++i)\n\t\t{\n\t\t\ty=y/10;\n\t\t}\n\t\ta=y%10;\n\n\t\tfor(i=1;i<a;i++)\n\t\t{\n\t\t\tans=ans+10*ar[l-1];\n\t\t\t//printf(\"3\\n\");\n\t\t}\n\n\t\tfor(i=1;i<=l-1;i++)\n\t\t{\n\t\t\ta=a*10;\n\t\t}\n\t\tfor(h=a;h<=n;h++)\n\t\t{\n\t\t\ti=h;\n\t\t\tq=i%10;\n\t\t\ti=i/10;r=0;flag=1;\n\t\t\t//printf(\"5\\n\");\n\t\t\tfor(j=1;j<l;j++)\n\t\t\t{//printf(\"4\\n\");\n\t\t\t\tif(r>0)\n\t\t\t\t{\n\t\t\t\t\tif(i%10!=q && i%10!=q1)\n\t\t\t\t\t{\n\t\t\t\t\t\tflag=0;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\t\n\t\t\t\t}\n\t\t\t\tif(i%10!=q)\n\t\t\t\t{\n\t\t\t\t\tr++;\n\t\t\t\t\tq1=i%10;\n\t\t\t\t}\n\t\t\t\ti=i/10;\n\t\t\t}\n\t\t\tif(flag==1)\n\t\t\t{\n\t\t\t\tans++;\n\t\t\t}\n\t\t}\n\tprintf(\"%d\\n\",ans );\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "dc25e04055a73652d5c9a289bc868e6e", "src_uid": "0f7f10557602c8c2f2eb80762709ffc4", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(int argc, char const *argv[])\n{int c=0,z,n,p=1,l,ans,a,i,r,flag,j,y,q,q1,ar[100],h;\n\tscanf(\"%d\",&n);\n\tz=n;\n\tif(n<=100)\n\t{\n\t\tprintf(\"%d\\n\", n);\n\t\treturn 0;\n\t}\n\twhile(z!=0)\n\t{\n\t\tz=z/10;\n\t\tc++;\n\t\t//printf(\"1\\n\");\n\t}\n\t//printf(\"%dd\\n\",c );\n\tl=c;\n\tc=c-1;\n\tfor (int i = 0; i < c; ++i)\n\t{\n\t\tp=p*2;\n\t\tar[i]=p;\n\t\t//printf(\"2\\n\");\n\t}\n\tp=p/2;\n\t//printf(\"p is %d\\n\", p);\n\tans=50*p-1;\n\t//printf(\"ans is %d\\n\",ans );\n\ty=n;\n\t\tfor (int i = 0; i < c; ++i)\n\t\t{\n\t\t\ty=y/10;\n\t\t}\n\t\ta=y%10;\n\n\t\tfor(i=1;i<a;i++)\n\t\t{\n\t\t\tans=ans+10*ar[l-1];\n\t\t\t//printf(\"3\\n\");\n\t\t}\n\n\t\tfor(i=1;i<=l-1;i++)\n\t\t{\n\t\t\ta=a*10;\n\t\t}\n\t\tfor(h=a;h<=n;h++)\n\t\t{\n\t\t\ti=h;\n\t\t\tq=i%10;\n\t\t\ti=i/10;r=0;flag=1;\n\t\t\t//printf(\"5\\n\");\n\t\t\tfor(j=1;j<l;j++)\n\t\t\t{//printf(\"4\\n\");\n\t\t\t\tif(r>0)\n\t\t\t\t{\n\t\t\t\t\tif(i%10!=q && i%10!=q1)\n\t\t\t\t\t{\n\t\t\t\t\t\tflag=0;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\t\n\t\t\t\t}\n\t\t\t\tif(i%10!=q)\n\t\t\t\t{\n\t\t\t\t\tr++;\n\t\t\t\t\tq1=i%10;\n\t\t\t\t}\n\t\t\t\ti=i/10;\n\t\t\t}\n\t\t\tif(flag==1)\n\t\t\t{\n\t\t\t\tans++;\n\t\t\t}\n\t\t}\n\tprintf(\"%d\\n\",ans );\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c654c2a60821f7fdee166ee8a8d90d82", "src_uid": "0f7f10557602c8c2f2eb80762709ffc4", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main(int argc, char const *argv[])\n{int c=0,z,n,p=1,l,ans=0,a,i,r,flag,j,y,q,q1,ar[100],h;\n\tscanf(\"%d\",&n);\n\tz=n;\n\tif(n<=100)\n\t{\n\t\tprintf(\"%d\\n\", n);\n\t\treturn 0;\n\t}\n\twhile(z!=0)\n\t{\n\t\tz=z/10;\n\t\tc++;\n\t\t//printf(\"1\\n\");\n\t}\n\t//printf(\"%dd\\n\",c );\n\tl=c;\n\tc=c-1;\n\tfor (int i = 0; i < c; ++i)\n\t{\n\t\tans=ans+9*(9*(p-1)+1);\n\t\tp=p*2;\n\t\tar[i]=p;\n\t\t//printf(\"2\\n\");\n\t}\n\t//printf(\"ans is %d\\n\",ans );\n\ty=n;\n\t\tfor (int i = 0; i < c; ++i)\n\t\t{\n\t\t\ty=y/10;\n\t\t}\n\t\ta=y%10;\n\n\t\tfor(i=1;i<a;i++)\n\t\t{\n\t\t\tans=ans+10*ar[l-1];\n\t\t\t//printf(\"3\\n\");\n\t\t}\n\n\t\tfor(i=1;i<=l-1;i++)\n\t\t{\n\t\t\ta=a*10;\n\t\t}\n\t\tfor(h=a;h<=n;h++)\n\t\t{\n\t\t\ti=h;\n\t\t\tq=i%10;\n\t\t\ti=i/10;r=0;flag=1;\n\t\t\t//printf(\"5\\n\");\n\t\t\tfor(j=1;j<l;j++)\n\t\t\t{//printf(\"4\\n\");\n\t\t\t\tif(r>0)\n\t\t\t\t{\n\t\t\t\t\tif(i%10!=q && i%10!=q1)\n\t\t\t\t\t{\n\t\t\t\t\t\tflag=0;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\t\n\t\t\t\t}\n\t\t\t\tif(i%10!=q)\n\t\t\t\t{\n\t\t\t\t\tr++;\n\t\t\t\t\tq1=i%10;\n\t\t\t\t}\n\t\t\t\ti=i/10;\n\t\t\t}\n\t\t\tif(flag==1)\n\t\t\t{\n\t\t\t\tans++;\n\t\t\t}\n\t\t}\n\tprintf(\"%d\\n\",ans );\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "aa99e6a0efbab5a4f2ef8a2e8e7fd861", "src_uid": "0f7f10557602c8c2f2eb80762709ffc4", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint main(void)\n{\n    int n,i,j,k,t,count1,count2,flag,num[100],a;\n    while(scanf(\"%d\",&n)!=EOF)\n    {\n        count2=0;\n        for(k=102;k<=n;k++)\n        {\n            memset(num,0,sizeof(num));\n            count1=0;\n            flag=1;\n            t=k;\n            while(t!=0)\n            {\n                a=t%10;\n                num[a]++;\n                t=t/10;\n            }\n            for(j=0;j<=9;j++)\n            {\n                if(num[j]!=0)\n                    count1++;\n                if(count1==3)\n                    flag=0;\n            }\n            if(flag==0)\n            {\n                count2++;\n            }\n        }\n        printf(\"%d\\n\",n-count2);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9f55e7be9c5f55c1fe4b1a8db6fbceac", "src_uid": "0f7f10557602c8c2f2eb80762709ffc4", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nstruct node{\n\tint s,e,d,id;\n}a[105];\nint b[105];\nvoid sort(struct node a[],int m){\n\tstruct node temp;\n\tint i,j;\n\tfor(i=1;i < m;i++){\n\t   for(j = 1;j < m-i;j++){\n\t   \tif(a[j].e > a[j+1].e){\n\t   \t\ttemp = a[j];\n\t   \t\ta[j] = a[j+1];\n\t   \t\ta[j+1] = temp;\n\t\t\t}\n\t\t}\n\t}\n}\nint main(){\n\tint n,m;\n\tint i,j,t;\n\tint flag = 0;\n\twhile(scanf(\"%d%d\",&n,&m) != EOF){\n\t\tmemset(b,0,sizeof(b));\n\t\tfor(i = 1;i <= m;i++){\n\t\t\tscanf(\"%d%d%d\",&a[i].s,&a[i].e,&a[i].d);\n\t\t\ta[i].id = i;\n\t\t\tb[a[i].e] = m + 1;\n\t\t}\n\t\tsort(a,m);\n\t\tfor(i = 1;i <= m;i++){\n\t\t\tint count = 0;\n\t\t\tfor(j = a[i].s;j < a[i].e;j++){\n\t\t\t\tif(b[j] == 0){\n\t\t\t\t\tb[j] = a[i].id;\n\t\t\t\t\tcount++;\n\t\t\t\t}\n\t\t\t\tif(count == a[i].d) break;\n\t\t\t}\n\t\t\tif(count != a[i].d){\n\t\t\t\tflag = 1;\n\t\t\t\tbreak;\n\t\t\t} \n\t\t}\n\t\tif(flag == 1){\n\t\t\tprintf(\"-1\\n\");\n\t\t}\n\t\telse{\n\t\t\tfor(j = 1;j <= n-1;j++){\n\t\t\t\tprintf(\"%d \",b[j]);\n\t\t\t}\n\t\t\tprintf(\"%d\\n\",b[j]);\n\t\t}\n\t\t\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d40e6259f904ee34d7893c48bcc75b75", "src_uid": "02d8d403eb60ae77756ff96f71b662d3", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nstruct exam{\n\tint a;\n\tint b;\n\tint c;\n};\n\nstruct exam x[100];\nint s[100],day[100]={0};\n\nint compare(const void *a,const void *b){\n\treturn x[*(int *)a].b-x[*(int *)b].b;\n}\n\nint main(void){\n\tint n,m,i,j;\n\n\tscanf(\"%d %d\",&n,&m);\n\tfor(i=0;i<m;i++){\n\t\tscanf(\"%d %d %d\",&x[i].a,&x[i].b,&x[i].c);\n\t\ts[i]=i;\n\t\tday[x[i].b-1]=i+1;\n\t}\n\n\tqsort(s,m,sizeof(int),compare);\n\n\tfor(i=0;i<n;i++){\n\t\tif(day[i]!=0){\n\t\t\tif(x[day[i]-1].c>0){\n\t\t\t\tprintf(\"-1\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tday[i]=m+1;\n\t\t\t}\n\t\t}\n\t\telse{\n\t\t\tfor(j=0;j<m;j++){\n\t\t\t\tif(i+1>=x[s[j]].a&&x[s[j]].c>0){\n\t\t\t\t\tx[s[j]].c--;\n\t\t\t\t\tday[i]=s[j]+1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(i=0;i<n-1;i++){\n\t\tprintf(\"%d \",day[i]);\n\t}\n\tprintf(\"%d\\n\",day[n-1]);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7546b9483b548acf0a244091675586ed", "src_uid": "02d8d403eb60ae77756ff96f71b662d3", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h> \n#include <stdlib.h>\nstruct ex {int s; int d; int c; int n;};\nint cm (const void *A, const void *B){\n\treturn\t((struct ex *)A)->d - ((struct ex *)B)->d;\n\t}\nint main (){\nint i, j, n, m;\nint const MAX = 100;\nint ans[100] = {0};\nstruct ex a[MAX];\n\nscanf(\"%d %d\",&n, &m);\nfor (i=0;i < m;i++){\n\tscanf(\"%d %d %d\", &a[i].s, &a[i].d, &a[i].c);\n\ta[i].n = i + 1;\n\tans[a[i].d - 1] = m + 1;\n\t}\n\nqsort(a,m,sizeof a[0], cm);\nj = 0;\nfor (i=0;i<n;i++){\n\tif(ans[i] == m + 1){\n\t\tj++;\n\t\tcontinue;\n\t\t}\n\tint k;\n\tfor(k = j; k < m ; k++){\n\t\tif (a[k].s <= i + 1 && a[k].c > 0 ){\n\t\t\tans[i] = a[k].n;\n\t\t\ta[k].c--;\n\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\n\t}\n//check\nj = 0;\nfor (i=0;i<m;i++)\n\tj += a[i].c;\n\nif (j > 0)\n//if(0)\n\tprintf(\"-1\");\nelse\n\tfor (i = 0; i<n; i++)\n\t\tprintf(\"%i \",ans[i]);\nprintf(\"\\n\");\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "542ef765fbfa1aae1262be0ae2dca118", "src_uid": "02d8d403eb60ae77756ff96f71b662d3", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#include <string.h>\n#include <ctype.h>\n#include <limits.h>\n#include <malloc.h>\n#include <memory.h>\nint g[105][105],n,m,i,j,f[105],ff,ans[105];\nstruct u\n{\n\tint a,b,c,d;\n}k[105];\n\nint cmp(const void *x,const void *y)\n{\n\treturn ((struct u*)x)->b-((struct u*)y)->b;\n}\n\nint main()\n{\n\tmemset(g,0,sizeof(g));\n\tmemset(f,0,sizeof(f));\n\tscanf(\"%d %d\",&n,&m);\n\tfor (i=1;i<=m;i++) \n\t{\n\t\tscanf(\"%d %d %d\",&k[i].a,&k[i].b,&k[i].d);\n\t\tk[i].c=i;\n\t}\n\tqsort(&k[1],m,sizeof(struct u),cmp);\n\tfor (i=1;i<=m;i++)\n\t{\n\t\tfor (j=k[i].a;j<k[i].b;j++) g[i][j]=1;\n\t\tf[k[i].b]=i;\n\t}\n\tfor (i=1;i<=n;i++)\n\t{\n\t\tif (f[i])\n\t\t{\n\t\t\tif (k[f[i]].d<=0) ans[i]=m+1;\n\t\t\telse \n\t\t\t{\n\t\t\t\tprintf(\"-1\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tcontinue;\n\t\t}\n\t\tfor (j=1,ff=0;j<=m;j++)\n\t\tif (g[j][i]&&k[j].d)\n\t\t{\n\t\t\tans[i]=k[j].c;\n\t\t\tk[j].d--;\n\t\t\tff=1;\n\t\t\tbreak;\n\t\t}\n\t\tif (!ff) ans[i]=0;\n\t}\n\tfor (i=1;i<=n;i++) printf(\"%d \",ans[i]);\n\treturn 0;\n} \n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5bff21ace23ce8c40533c297723aca96", "src_uid": "02d8d403eb60ae77756ff96f71b662d3", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\ntypedef struct ExamData_m\n{\n\tint start;\n\tint needed;\n\tint day;\n\tint index;\n} ExamData;\n\nvoid Swap(ExamData *a, ExamData *b)\n{\n\tExamData aux = *a;\n\t*a = *b;\n\t*b = aux;\n}\n\nint Partition(ExamData exams[], int left, int right)\n{\n\tint mid = left + (right - left) / 2;\n\tSwap(exams + left, exams + mid);\n\n\tint pivot = exams[left].start;\n\tint i = left + 1;\n\tint j = right;\n\n\twhile (i <= j) {\n\t\twhile (i <= j && exams[i].start <= pivot) {\n\t\t\ti += 1;\n\t\t}\n\t\twhile (i <= j && exams[j].start > pivot) {\n\t\t\tj -= 1;\n\t\t}\n\t\tif (i <= j) {\n\t\t\tSwap(exams + i, exams + j);\n\t\t\ti += 1;\n\t\t\tj -= 1;\n\t\t}\n\t}\n\n\tSwap(exams + left, exams + i - 1);\n\treturn i - 1;\n}\n\nvoid Sort(ExamData exams[], int left, int right)\n{\n\tif (left >= right) {\n\t\treturn;\n\t}\n\n\tint index = Partition(exams, left, right);\n\tSort(exams, left, index - 1);\n\tSort(exams, index + 1, right);\n}\n\n\ntypedef ExamData HeapNode;\n\nint Father(int node) { return node / 2; }\nint LeftSon(int node) { return node * 2 + 1; }\nint RightSon(int node) { return node * 2 + 2; }\n\nvoid Percolate(HeapNode heap[], int node)\n{\n\tif (node <= 0) {\n\t\treturn;\n\t}\n\n\tint father = Father(node);\n\tif (heap[node].day < heap[father].day) {\n\t\tSwap(heap + node, heap + father);\n\t\tPercolate(heap, father);\n\t}\n}\n\nvoid Sift(HeapNode heap[], int size, int node)\n{\n\tint left = LeftSon(node);\n\tint right = RightSon(node);\n\n\tif (left >= size) {\n\t\treturn;\n\t}\n\n\tint best = left;\n\tif (right < size && heap[right].day < heap[left].day) {\n\t\tbest = right;\n\t}\n\n\tif (heap[best].day < heap[node].day) {\n\t\tSwap(heap + best, heap + node);\n\t\tSift(heap, size, best);\n\t}\n}\n\nvoid AddExam(HeapNode heap[], int *size, ExamData exam)\n{\n\theap[*size] = exam;\n\t*size += 1;\n\tPercolate(heap, *size - 1);\n}\n\nvoid Study(HeapNode heap[], int *size)\n{\n\theap[0].needed -= 1;\n\tif (heap[0].needed <= 0) {\n\t\t*size -= 1;\n\t\tSwap(heap, heap + *size);\n\t\tSift(heap, *size, 0);\n\t}\n}\n\n\n#define MAX_DAYS 100\n\nint days[MAX_DAYS];\nint needed[MAX_DAYS];\nExamData exams[MAX_DAYS];\n\nHeapNode choser[MAX_DAYS];\nint choser_size = 0;\n\nint main()\n{\n\tint ndays, nexams;\n\tscanf(\"%d%d\", &ndays, &nexams);\n\n\tint i;\n\tfor (i = 0; i < ndays; ++i) {\n\t\tdays[i] = -1;\n\t}\n\n\tfor (i = 0; i < nexams; ++i) {\n\t\tscanf(\"%d%d%d\", &exams[i].start, &exams[i].day, &exams[i].needed);\n\t\texams[i].index = i;\n\n\t\texams[i].start -= 1;\n\t\texams[i].day -= 1;\n\t\tdays[exams[i].day] = i;\n\t\tneeded[i] = exams[i].needed;\n\t}\n\n\tSort(exams, 0, nexams - 1);\n\n\tint valid = 1;\n\tint exam_ind = 0;\n\n\tfor (i = 0; i < ndays && valid; ++i) {\n\t\twhile (exam_ind < nexams && exams[exam_ind].start == i) {\n\t\t\tAddExam(choser, &choser_size, exams[exam_ind]);\n\t\t\texam_ind += 1;\n\t\t}\n\n\t\tif (days[i] != -1) {\n\t\t\tif (needed[days[i]] > 0) {\n\t\t\t\tvalid = 0;\n\t\t\t}\n\t\t\tdays[i] = nexams;\n\t\t\tcontinue;\n\t\t} \n\n\t\tif (choser_size > 0) {\n\t\t\tint ind = choser[0].index;\n\t\t\tdays[i] = ind;\n\t\t\tneeded[ind] -= 1;\n\t\t\tStudy(choser, &choser_size);\n\t\t}\n\t}\n\n\tif (!valid) {\n\t\tprintf(\"-1\\n\");\n\t\treturn 0;\n\t}\n\n\tfor (i = 0; i < ndays; ++i) {\n\t\tprintf(\"%d \", days[i] + 1);\n\t}\n\tprintf(\"\\n\");\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "0017859ab1a1d10b3a48225c77a1608b", "src_uid": "02d8d403eb60ae77756ff96f71b662d3", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nconst long long mod = 1e9 + 9;\n\nint main() {\n  long long n, m, i;\n  scanf(\"%I64d %I64d\", &n, &m);\n  long long now = 1;\n  for(i = 1; i <= m; i++) {\n    now *= 2;\n    now %= mod;\n  }\n  long long ans = 1;\n  for(i = 1; i <= n; i++) {\n    now--;\n    if(now < 0) now += mod;\n    ans *= now;\n    ans %= mod;\n  }\n  printf(\"%d\\n\", (int) ans);\n  return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e6777158fb1c957e3f3f4f39b78db011", "src_uid": "fef4d9c94a93fcf6d536f33503b1d4b8", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nint main()\n{\n    int  n,m,i;\n    __int64 s,t;\n    while(scanf(\"%d%d\",&n,&m)!=EOF)\n    {\n        s=t=1;\n        for(i=0;i<m;i++)\n        {\n            t*=2;\n            t%=1000000009;\n        }\n        for(i=1;i<=n;i++)\n        {\n            s*=(t-i);\n            s%=1000000009;\n        }\n        printf(\"%I64d\\n\",s);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8d2d6e984b39a9389e0b80ce7cc9a948", "src_uid": "fef4d9c94a93fcf6d536f33503b1d4b8", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MOD 1000000009\n\nlong long int power(int, int, int);\n\nint main()\n{\n\tint n, m;\n\tscanf(\"%d %d\", &n, &m);\n\n\tlong long int p = power(2, m, MOD);\n\tlong long int sol = 1;\n\tint i;\n\tfor (i=1;i<=n;i++)\n\t{\n\t\tlong long int t = p - i;\n\t\tif (t<0) t+=MOD;\n\t\tsol *= t;\n\t\tsol %= MOD;\n\t}\n\n\tprintf(\"%I64d\\n\", sol);\n\treturn 0;\n}\n\nlong long int power(int base, int exp, int mod)\n{\n\tif (!exp) return 1;\n\tlong long int t = power(base, exp / 2, mod);\n\tlong long int tt = (exp & 1)?base:1;\n\treturn (((t * t) % mod) * tt) % mod;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "898e82f800e1f970485b161465eb7e42", "src_uid": "fef4d9c94a93fcf6d536f33503b1d4b8", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\ntypedef long long ll;\n\nconst ll mod = 1000000009;\n\nvoid solve(int n, int m)\n{\n    ll ans, s, i;\n    s = 1;\n    for (i = 0; i < m; i ++)\n    {\n        s = (s << 1) % mod;\n    }\n    ans = 1;\n    for (i = 0; i < n; i ++)\n    {\n        s --;\n        if (s == 0)\n        {\n            printf(\"0\\n\");\n            return;\n        }\n        ans = (ans * s) % mod;\n    }\n    printf(\"%I64d\\n\", ans);\n}\n\nint main()\n{\n    int n, m;\n    while (scanf(\"%d%d\", &n, &m) == 2)\n    {\n        solve(n, m);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e8567e9f1a293f798b8f10eaac9c265a", "src_uid": "fef4d9c94a93fcf6d536f33503b1d4b8", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "\n#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#define SORT(a,n) qsort(a,n,sizeof(int),intcmp)\n#define s(n)                        scanf(\"%d\",&n)\n#define sc(n)                       scanf(\"%c\",&n)\n#define sl(n)                       scanf(\"%I64d\",&n)\n#define sf(n)                       scanf(\"%lf\",&n)\n#define ss(n)                       scanf(\"%s\",n)\n#define fill(a,v)                   memset(a, v, sizeof(a))\nint intcmp(const void *f,const void *s)\n{\n   return (*(int *)f -*(int *)s);\n}\nint gcd(int a,int b){ return ((b==0)?a:gcd(b,a%b));}\n\n#define MAX\n#define MODBY 1000000009\n\ntypedef long long int lld;\ntypedef long double Lf;\n\nint main()\n{\n   int i,j,n,m;\n   scanf(\"%d\",&n);\n   scanf(\"%d\",&m);\n   lld a=1;\n   for(i=0;i<m;++i)\n      a=(a*2)%MODBY;\n   lld ans=1;\n   for(i=1;i<=n;++i)\n      ans=(ans*(a-i+MODBY))%MODBY;\n   printf(\"%d\\n\",(int)ans);\n\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d3a6479b4b7282a58b2114ccbce95fc2", "src_uid": "fef4d9c94a93fcf6d536f33503b1d4b8", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(int argc, char const *argv[]) {\n\tint u = 0, l = 0;\n\tchar s[51];\n\tfor (int i = 0; i < 51; ++i) {\n\t\ts[i] = 0;\n\t}\n\tscanf(\"%s\", &s);\n\tfor (int i = 0; i < 51; ++i) {\n\t\tif (s[i] <= 90 && s[i] >= 65) {\n\t\t\tu += (s[i] - 64);\n\t\t} else if (s[i] <= 122 && s[i] >= 97) {\n\t\t\tl += (s[i] - 96);\n\t\t}\n\t}\n\tprintf(\"%d\", (u - l));\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d1fe1011607120efa85b6ce0f59c8d0a", "src_uid": "d3fa5a3a008048dc4a9fbce1ebc61d67", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <ctype.h>\n#include <stdio.h>\n#include <string.h>\n\nint main() {\n\tstatic char str[64];\n\tint l, i, res;\n\n\tscanf(\"%s\", str);\n\tl = strlen(str);\n\tres = 0;\n\tfor (i = 0; i < l; i++) {\n\t\tint check1 = str[i] > '@' && str[i] < '[';\n\t\tint check2 = str[i] > '`' && str[i] < '{';\n\t\tint c = tolower(str[i]);\n\n\t\tif (isalpha(c)) {\n\t\t\tc -= ('a' - 1);\n\t\t\tres += check1 * c - check2 * c;\n\t\t}\n\t}\n\tprintf(\"%d\\n\", res);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2c61092084ddf59132de1776f0c118fb", "src_uid": "d3fa5a3a008048dc4a9fbce1ebc61d67", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long n,n1,sum,a[20],value;\n\nlong long findMinOnes(long long n,int i)\n{\n\tint count = 0;\n\tlong long value1,value2;\n\tif(n<0)\n\t\tn *=-1;\n\tif(i==1)\n\t\treturn n;\n\tif(n==1)\n\t\treturn 1;\n\t\twhile(n>a[i])\n\t\t{\n\t\t\tn-= a[i];\n\t\t\tcount+=i;\n\t\t}\n\t\tvalue1 = count + findMinOnes(n,i-1);\n\t\tn-= a[i];\n\t\tcount+=i;\n\t\tvalue2 = count + findMinOnes(n,i-1);\n\t\tif(value1 < value2)\n\t\t\treturn value1;\n\t\telse\n\t\t\treturn value2;\n}\nint main()\n{\n\tint k=1,i=0,count;\n\tint mul = 10;\n\tscanf(\"%I64d\",&n);\n\tn1=n;\n\twhile(n!=0)\n\t{\n\t\tn=n/10;\n\t\ti++;\n\t}\n\ta[k]=1;\n\tfor(k=2;k<=i+1;k++)\n\t{\n\t\ta[k]=a[k-1]+mul;\n\t\tmul*=10;\n\t}\n\tn=n1;\n\tprintf(\"%I64d\",findMinOnes(n,i+1));\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5a0b991ec5e03d0a6be3e08946cf5c0f", "src_uid": "1b17a7b3b41077843ee1d6e0607720d6", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\t\n\tlong long n,i,k=0,min=0,temp=0;\n\tlong long a[1000000] = {0};\n\tscanf(\"%I64d\",&n);\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%I64d\",&a[i]);\n\t\tk+= a[i];\n\t}\n\tk = k/n;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tif(temp < 0)\n\t\tmin+= temp * -1;\n\t\telse\n\t\tmin+= temp;\n\t\ttemp+=a[i]-k;\n\t\t\n\t}\n\tprintf(\"%I64d\",min);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "71d6e1b8e2345f6e379e970e3dd43d01", "src_uid": "1b17a7b3b41077843ee1d6e0607720d6", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define lli long long int\nlli n,i,j,u,k,l,x,y,d,s,t;\nlli gg(lli x){int u=0;  while(x){u++;x/=10;} return u;}\nlli ggg(lli n)\n{\n    while(n/10)n/=10;\n    return n;\n}\nlli g(lli u)\n{\n    lli a=1;\n    while(--u)a=10*a+1;\n    return a;\n}\nlli f(lli n);\nlli fff(lli n)\n{\n    lli u=gg(n);\n    if(u==1) return 2+(11-n);\n    if(ggg(n)<6) return 10000;\n    return u+1+f(g(u+1)-n);\n}\nlli ff(lli n)\n{\n    lli u=gg(n);\n    if(u==1)return n;\n    return ggg(n)*u+(f(n-ggg(n)*g(u)));\n}\nlli f(lli n)\n{\n    if(!n)return 0;\n    if(n<0)n*=-1;\n    lli x,y,u=gg(n);\n    x=ff(n);\n    y=fff(n);\n    return (x>y ? y : x);\n}\nint main()\n{\n    scanf(\"%lld\",&n);\n    x=n;\n    while(x){u++;x/=10;}\n    printf(\"%lld\",f(n));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7a8c8c869c902f1e75b92edc2e935e76", "src_uid": "1b17a7b3b41077843ee1d6e0607720d6", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n#define abs(x) (( (x>0) ? x : -x ))\nint n,y,k,i,t,x,d,u;\nchar a[100];\nint main()\n{\n\tscanf(\"%s\",a);\n\tu=strlen(a);\n\tn=u;\n\tfor(i=0;i<u;i++)\n\t\ta[i]-='0';\n\tt+=a[0]*n;\n\tn--;\n\tk=a[0];\n\tfor(i=1;i<u;i++)\n\t{\n\t\tx=a[i]-k;\n\t\tif(x<0)\n\t\t\tx*=-1;\n\t\tk=a[i];\n\t\tt+=n*x;\n\t\tn--;\n\t}\n\tprintf(\"%d\",t);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8efe64c77f474ea70342d3e2b534e7f1", "src_uid": "1b17a7b3b41077843ee1d6e0607720d6", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long n,n1,sum,a[20],value;\n\nlong long findMinOnes(long long n,int i)\n{\n\tint count = 0;\n\tlong long value1,value2;\n\tif(n<0)\n\t\tn *=-1;\n\tif(i==1)\n\t\treturn n;\n\tif(n==1)\n\t\treturn 1;\n\t\twhile(n>a[i])\n\t\t{\n\t\t\tn-= a[i];\n\t\t\tcount+=i;\n\t\t}\n\t\tvalue1 = count + findMinOnes(n,i-1);\n\t\tn-= a[i];\n\t\tcount+=i;\n\t\tvalue2 = count + findMinOnes(n,i-1);\n\t\tif(value1 < value2)\n\t\t\treturn value1;\n\t\telse\n\t\t\treturn value2;\n}\nvoid main()\n{\n\tint k=1,i=0,count;\n\tint mul = 10;\n\tscanf(\"%I64d\",&n);\n\tn1=n;\n\twhile(n!=0)\n\t{\n\t\tn=n/10;\n\t\ti++;\n\t}\n\ta[k]=1;\n\tfor(k=2;k<=i+1;k++)\n\t{\n\t\ta[k]=a[k-1]+mul;\n\t\tmul*=10;\n\t}\n\tn=n1;\n\tprintf(\"%I64d\",findMinOnes(n,i+1));\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "260f07889cc6a2066a07346ae46c7630", "src_uid": "1b17a7b3b41077843ee1d6e0607720d6", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\nint f(long long int i,long long int tmp,long long int m);\nlong long int min1(long long int a,long long int b);\nint main()\n{\n    long long int m,n,s,i,p,tmp,kase=1,min;\n    scanf(\"%lld%lld\",&m,&n);\n    s=m+n;\n    for(i=1;i<=sqrt(s);i++)\n    {\n        if(s%i!=0)\n            continue;\n        tmp=s/i;\n        m=min1(m,n);\n        if(f(i,tmp,m))\n        {\n            p=2*(i+tmp);\n            if(kase)\n            {\n                min=p;\n                kase=0;\n            }\n            else\n                min=min<p?min:p;\n\n        }\n    }\n    printf(\"%lld\",min);\n    return 0;\n}\nint f(long long int i,long long int tmp,long long int m)\n{\n    int j;\n    for(j=1;j<=sqrt(m);j++)\n    {\n        if(m%j!=0)\n            continue;\n        if(j<=i&&m/j<=tmp||j<=tmp&&m/j<=i)\n            return 1;\n    }\n    return 0;\n}\nlong long int min1(long long int a,long long int b)\n{\n    return a<b?a:b;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "35e90f07f83bfeb8a482dc9f396882a9", "src_uid": "7d0c5f77bca792b6ab4fd4088fe18ff1", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\nint f(long long int i,long long int tmp,long long int m);\nlong long int min1(long long int a,long long int b);\nint main()\n{\n    long long int m,n,s,i,p,tmp,kase=1,min=99999999999;\n    scanf(\"%lld%lld\",&m,&n);\n    s=m+n;\n    for(i=sqrt(s);i>=1;i--)\n    {\n        if(s%i!=0)\n            continue;\n        tmp=s/i;\n\n        if(f(i,tmp,n))\n        {\n            p=2*(i+tmp);\n            min=p<min?p:min;\n            break;\n        }\n\n    }\n    for(i=sqrt(s);i>=1;i--)\n    {\n\n        if(f(i,tmp,m))\n        {\n            p=2*(i+tmp);\n            min=p<min?p:min;\n            break;\n    }\n    printf(\"%lld\",min);\n    return 0;\n}\n}\nint f(long long int i,long long int tmp,long long int m)\n{\n    int j;\n    for(j=sqrt(m);j>=1;j--)\n    {\n        if(m%j!=0)\n            continue;\n        if(j<=i&&m/j<=tmp||j<=tmp&&m/j<=i)\n            return 1;\n    }\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5a73176849166984c328f18bb69a702b", "src_uid": "7d0c5f77bca792b6ab4fd4088fe18ff1", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\nint f(long long int i,long long int tmp,long long int m);\nlong long int min1(long long int a,long long int b);\nint main()\n{\n    long long int m,n,s,i,p,tmp,kase=1,min;\n    scanf(\"%lld%lld\",&m,&n);\n    s=m+n;\n    for(i=sqrt(s);i>=1;i--)\n    {\n        if(s%i!=0)\n            continue;\n        tmp=s/i;\n\n        if(f(i,tmp,n))\n        {\n            p=2*(i+tmp);\n            break;\n        }\n\n    }\n    for(i=sqrt(s);i>=1;i--)\n    {\n\n        if(f(i,tmp,m))\n        {\n            p=2*(i+tmp);\n            break;\n    }\n    printf(\"%lld\",p);\n    return 0;\n}\n}\nint f(long long int i,long long int tmp,long long int m)\n{\n    int j;\n    for(j=sqrt(m);j>=1;j--)\n    {\n        if(m%j!=0)\n            continue;\n        if(j<=i&&m/j<=tmp||j<=tmp&&m/j<=i)\n            return 1;\n    }\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0f7aa7e7a77151e9e0e070d71bbf298d", "src_uid": "7d0c5f77bca792b6ab4fd4088fe18ff1", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\nint f(long long int i,long long int tmp,long long int m);\nlong long int min1(long long int a,long long int b);\nint main()\n{\n    long long int m,n,s,i,p,tmp,kase=1,min;\n    scanf(\"%lld%lld\",&m,&n);\n    s=m+n;\n    for(i=1;i<=s;i++)\n    {\n        if(s%i!=0)\n            continue;\n        tmp=s/i;\n        m=min1(m,n);\n        if(f(i,tmp,m))\n        {\n            p=2*(i+tmp);\n            if(kase)\n            {\n                min=p;\n                kase=0;\n            }\n            else\n                min=min<p?min:p;\n\n        }\n    }\n    printf(\"%lld\",min);\n    return 0;\n}\nint f(long long int i,long long int tmp,long long int m)\n{\n    int j;\n    for(j=1;j<=m;j++)\n    {\n        if(m%j!=0)\n            continue;\n        if(j<=i&&m/j<=tmp||j<=tmp&&m/j<=i)\n            return 1;\n    }\n    return 0;\n}\nlong long int min1(long long int a,long long int b)\n{\n    return a<b?a:b;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a9adf00e2348ff592492a0104c821925", "src_uid": "7d0c5f77bca792b6ab4fd4088fe18ff1", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\nlong long int f(long long int i,long long int tmp,long long int m);\nint min1(int a,int b);\nint main()\n{\n    long long int m,n,s,i,p,tmp,kase=1,min;\n    scanf(\"%lld%lld\",&m,&n);\n    s=m+n;\n    for(i=1;i<=sqrt(s);i++)\n    {\n        if(s%i!=0)\n            continue;\n        tmp=s/i;\n        m=min1(m,n);\n        if(f(i,tmp,m))\n        {\n            p=2*(i+tmp);\n            if(kase)\n            {\n                min=p;\n                kase=0;\n            }\n            else\n                min=min<p?min:p;\n\n        }\n    }\n    printf(\"%lld\",min);\n    return 0;\n}\nlong long int f(long long int i,long long int tmp,long long int m)\n{\n    int j;\n    for(j=1;j<=sqrt(m);j++)\n    {\n        if(m%j!=0)\n            continue;\n        if(j<=i&&m/j<=tmp)\n            return 1;\n    }\n    return 0;\n}\nint min1(int a,int b)\n{\n    return a<b?a:b;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a41c85f09cc42a74de9b2436cc55d7f8", "src_uid": "7d0c5f77bca792b6ab4fd4088fe18ff1", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nlong long int n, k, M, D;\n\nlong long int max(long long int a, long long int b)\n{\n\tif (a > b)\n\t\treturn a;\n\treturn b;\n}\n\nint main()\n{\n\tscanf(\"%I64d %I64d %I64d %I64d\", &n, &k, &M, &D);\n\tlong long int ans = M;\n\tfor (long long int i = D; i >= 2; i--)\n\t{\n\t\tif (n/D < k)\n\t\t\tcontinue;\n\t\tlong long int beg = 1, end = M;\n\t\t\n\t\twhile (beg <= end)\n\t\t{\n\t\t\tlong long int mid = (beg+end)/2;\n\t\t\tlong long int num = n/mid;\n\t\t\t//printf(\"%d, %d, %d\\n\", i, mid, num);\n\t\t\tif (num < k*(i-1)+1)\n\t\t\t{\n\t\t\t\tend = mid-1;\n\t\t\t}\n\t\t\telse if (i == D && num >= k*i+1)\n\t\t\t{\n\t\t\t\tbeg = mid+1;\n\t\t\t}\n\t\t\telse if (num >= k*(i-1)+1)\n\t\t\t{\n\t\t\t\tans = max(ans, (i)*mid);\n\t\t\t\tbeg = mid+1;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tbeg = mid+1;\n\t\t\t\tans = max(ans, (i)*mid);\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"%I64d\\n\", ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "575ccb37b1857dc5cae1b178b0dd0c81", "src_uid": "ac2e795cd44061db8da13e3947ba791b", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(){\n  int D;\n  long n, k, M, ans = 0;\n  scanf(\"%ld%ld%ld%d\", &n, &k, &M, &D);\n  for(int i = 0; i < D; i++){\n    long cur = n / (k * i + 1);\n    if(!cur) break;\n    if(cur > M) cur = M;\n    long lmax = cur * (i + 1);\n    ans = ans > lmax ? ans : lmax;\n  }\n  printf(\"%ld\", ans);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3c4b201c97a4a301d00ddb6430a7fec6", "src_uid": "ac2e795cd44061db8da13e3947ba791b", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(){\n  int D;\n  long n, k, M, ans;\n  scanf(\"%ld%ld%ld%d\", &n, &k, &M, &D);\n  ans = M;\n  for(int i = 1; i <= D; i++){\n    long cur = n / (k * i);\n    long lmax = cur * i;\n    if(!cur) break;\n    if(i < D){\n      if(n / cur > k * i){\n        lmax += cur;\n      } else{\n        while(cur && n / cur-- < k * i);\n        lmax = lmax > cur * (i + 1) ? lmax : cur * (i + 1);\n      }\n    } else if(n / cur > k * i) break;\n    ans = ans > lmax ? ans : lmax;\n  }\n  printf(\"%ld\", ans);\n  return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f7510d32b6eca3848ac868b0cb69717c", "src_uid": "ac2e795cd44061db8da13e3947ba791b", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(){\n  int D;\n  long n, k, M, ans;\n  scanf(\"%ld%ld%ld%d\", &n, &k, &M, &D);\n  ans = M;\n  for(int i = 1; i <= D; i++){\n    long cur = n / (k * i);\n    long lmax = cur * i;\n    if(i < D){\n      if(n / cur > k * i){\n        lmax += cur;\n      } else{\n        while(cur && n / cur-- < k * i);\n        lmax = lmax > cur * (i + 1) ? lmax : cur * (i + 1);\n      }\n    }\n    ans = ans > lmax ? ans : lmax;\n  }\n  printf(\"%ld\", ans);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0c84eb68c1776d46f5c6cba176d2409e", "src_uid": "ac2e795cd44061db8da13e3947ba791b", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nlong long int n, k, M, D;\n\nlong long int max(long long int a, long long int b)\n{\n\tif (a > b)\n\t\treturn a;\n\treturn b;\n}\n\nint main()\n{\n\tscanf(\"%I64d %I64d %I64d %I64d\", &n, &k, &M, &D);\n\tlong long int ans = 0;\n\tfor (long long int i = D; i >= 1; i--)\n\t{\n\t\tif (n/D < k)\n\t\t\tcontinue;\n\t\tlong long int beg = n/(k*(i-1)), end = M;\n\t\twhile (beg <= end)\n\t\t{\n\t\t\tlong long int mid = (beg+end)/2;\n\t\t\tlong long int num = n/mid;\n\t\t\t//printf(\"%d, %d, %d\\n\", i, mid, num);\n\t\t\tif (num < k*(i-1)+1)\n\t\t\t{\n\t\t\t\tend = mid-1;\n\t\t\t}\n\t\t\telse if (i == D && num >= k*i+1)\n\t\t\t{\n\t\t\t\tbeg = mid+1;\n\t\t\t}\n\t\t\telse if (num >= k*(i-1)+1)\n\t\t\t{\n\t\t\t\tans = max(ans, (i)*mid);\n\t\t\t\tbeg = mid+1;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tbeg = mid+1;\n\t\t\t\tans = max(ans, (i)*mid);\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"%I64d\\n\", ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "77c0d062620c0212357087fa53c4cc1f", "src_uid": "ac2e795cd44061db8da13e3947ba791b", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n\n#define N 22\n#define HL 1\n#define HH 4\n#define T 14\n\nint a[N][HH+1][T][2];\nint n, m;\n\nmain()\n{\n  int i, o, p, j, k, l, h, t, s;\n\n  //freopen( \"input.dat\", \"r\", stdin );\n  scanf( \"%d %d\", &n, &m );\n\n  for (i=HL;i<=HH;+++i) a[1][i][0][1] = 1;\n  \n  for (k=1;k<n;++k)\n  {\n    for (h=HL;h<=HH;++h)\n    {\n      for (t=0;t<=m;++t)\n      {\n        for (s=0;s<=1;++s)\n        {\n          if (a[k][h][t][s] != 0)\n          {\n            for (i=HL;i<=HH;++i)\n            {\n              if (i==h) continue;\n              if (k==1 && i<h) continue;\n              if (i<h)\n              {\n                if (s==0) a[k+1][i][t][s] += a[k][h][t][s];\n                else a[k+1][i][t+1][0] += a[k][h][t][s];\n              }\n              else\n              {\n                if (s==0) a[k+1][i][t][1] += a[k][h][t][s];\n                else a[k+1][i][t][s] += a[k][h][t][s];\n              }\n            }\n          }\n        }\n      }\n    }\n  }\n\n  p = 0;\n  for (h = HL;h<=HH;++h)\n    p += a[n][h][m][0];\n\n  printf( \"%d\\n\", p );\n  return 0;\n}\n  \n  \n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d7080e2c40a150c71af2f7a3f289b470", "src_uid": "6d67559744583229455c5eafe68f7952", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n,t;\n    int a[25][10]={14,0,0,0,0,0,0,0,0,0,22,0,0,0,0,0,0,0,0,0,16,70,0,0,0,0,0,0,0,0,6,232,0,0,0,0,0,0,0,0,1,380,353,0,0,0,0,0,0,0,0,396,1786,0,0,0,0,0,0,0,0,284,4500,1782,0,0,0,0,0,0,0,142,7414,12122,0,0,0,0,0,0,0,48,8849,41160,8997,0,0,0,0,0,0,10,8028,92226,76878,0,0,0,0,0,0,1,5658,152140,328222,45425,0,0,0,0,0,0,3112,195420,928494,467292,0,0,0,0,0,0,1322,201744,1947581,2402980,229347,0,0,0,0,0,422,170444,3213988,8205152,2758896,0,0,0,0,0,96,118912,4322956,20852648,16594160,1157954,0,0,0,0,14,68640,4846524,41920210,66357900,15946870,0,0,0,0,1,32632,4594423,69183464,197939352,109824208,5846414,0,0,0,0,12628,3715462,96046590,468541040,503245466,90700276,0};\n    scanf(\"%d%d\",&n,&t);\n    printf(\"%d\",a[n-3][t-1]);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "205f40909ab108831a4345466f46f4db", "src_uid": "6d67559744583229455c5eafe68f7952", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint dp[24][5][24];\nint n, t;\nint main ()\n{\n    int m, k, j, res;\n    dp[1][1][0] = 1;\n    dp[1][2][0] = 1;\n    dp[1][3][0] = 1;\n    dp[1][4][0] = 1;\n    for (n = 2; n <= 20; n++)\n\tfor (m = 1; m <= 4; m++)\n\t    for (k = 0; k <= 19; k++)\n\t\tfor (j = 1; j <= 4; j++) {\n\t\t    if (((n == 2)&&(m < j)) || (j == m)) continue;\n\t\t    dp[n][m][k + ((k%2)&&(m>j)||(!(k%2)&&(m<j)))]\n\t\t\t+= dp[n - 1][j][k];\n\t\t}\n    scanf (\"%d %d\", &n, &t);\n    res = 0;\n    for (j = 1; j <= 4; j++)\n\tres += dp[n][j][2*t - 1];\n    printf (\"%d\\n\", res);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "122271cec6f9f0cf8eba20cb092648a8", "src_uid": "6d67559744583229455c5eafe68f7952", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint dp[24][5][24];\nint n, t;\n\nint main ()\n{\n    int m, i, j, aux;\n    \n    scanf (\"%d %d\", &n, &t);\n\n    dp[1][1][0] = 1;\n    dp[1][2][0] = 1;\n    dp[1][3][0] = 1;\n    dp[1][4][0] = 1;\n    \n    for (n = 2; n <= 20; n++)\n\tfor (m = 1; m <= 4; m++)\n\t    for (i = 0; i <= 19; i++)\n\t\tfor (j = 1; j <= 4; j++) ]\n            {\n\t\t    if (((n == 2)&&(m < j)) || (j == m)) continue;\n\t\t    dp[n][m][i + ((i%2)&&(m>j)||(!(i%2)&&(m<j)))]+= dp[n - 1][j][i];\n            }\n\n    for (j = 1; j <= 4; j++)\n        aux += dp[n][j][2*t - 1];\n        \n    printf (\"%d\\n\", aux);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "c1803f20f76143c7e6c8f8d0d6644c2f", "src_uid": "6d67559744583229455c5eafe68f7952", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint n,t,c;\n\nvoid dfs(int y1,int y2,int x,int l) {\n\t// printf(\"%d %d %d %d\\n\",y1,y2,x,l);\n\tif (x==2&&y1<y2) return;\n\tif (l>t) return;\n\tif (x==n) {\n\t\tif (y1<y2&&t==l) c++;\n\t\treturn;\n\t}\n\tint y;\n\tfor (y=1;y<5;y++)\n\t\tif (y!=y1)\n\t\t\tdfs(y,y1,x+1,l+(y1>y2&&y1>y));\n}\n\nint main() {\n\tscanf(\"%d %d\\n\",&n,&t);\n\tdfs(0,-1,0,0);\n\tprintf(\"%d\\n\",c);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2a111945ab613052eaf871eebebb8a33", "src_uid": "6d67559744583229455c5eafe68f7952", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(){\n  int n = 0;\n  double s = 0, m = 0, l = 31400;\n  scanf(\"%d\", &n);\n  while(n--){\n    double x1, y1, x2, y2;\n    scanf(\"%lf %lf %lf %lf\", &x1, &y1, &x2, &y2);\n    s = (y2-y1)*(x2-x1) + s;\n    if(x1<=l)l = x1;\n    if(y1<=l)l = y1;\n    if(x2>=m)m = x2;\n    if(y2>=m)m = y2;\n  }\n  if(s != (m-l)*(m-l)){\n    printf(\"NO\\n\");\n  }\n  else{\n    printf(\"YES\\n\");\n  }\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "619ec0f26b972b654ed16eb7b2cd0b42", "src_uid": "f63fc2d97fd88273241fce206cc217f2", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    int n,i,max1,max2,j;\n    long min1,min2,ind,tot;\n    tot=0;\n    max1=-1;\n    max2=-1;\n    min1=40000;\n    ind=0;\n    \n    \n    scanf(\"%d\",&n);\n    long arr[n][4];\n    long arr2[n][8];\n    \n    long out[8];\n    for(i=0;i<n;i++)\n    {\n        for(j=0;j<4;j++)\n        {\n            scanf(\"%ld\",&arr[i][j]);\n        }\n        \n    }\n    for(i=0;i<n;i++)\n    {\n    \n    arr2[i][7]=arr[i][1];\n    arr2[i][4]=arr[i][0];\n    arr2[i][6]=arr[i][2];\n    arr2[i][0]=arr[i][0];\n    arr2[i][1]=arr[i][1];\n    arr2[i][2]=arr[i][2];\n    arr2[i][3]=arr[i][3];\n    arr2[i][5]=arr[i][3];\n\n    \n    }\n    \n    \n            for(i=0;i<n;i++)\n            {ind=ind+abs(arr2[i][5]-arr2[i][1])*abs(arr2[i][6]-arr2[i][0])  ;\n                for(j=0;j<8;j+=2)\n                {if(arr2[i][j]>max1)\n                max1=arr2[i][j];\n                if(arr2[i][j]<min1)\n                min1=arr2[i][j];\n                \n                }\n            }\n            for(i=0;i<n;i++)\n            {\n                for(j=1;j<8;j+=2)\n                {if(arr2[i][j]>max2)\n                max2=arr2[i][j];\n                if(arr2[i][j]<min2)\n                min2=arr2[i][j];\n                    \n                }\n            }\n            tot=(max1-min1)*(max1-min1);\n            if(max1-min1==max2-min2&&ind==tot)\n            printf(\"YES\");\n            else\n            printf(\"NO\");\n           \n           \n           \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "24e8953c42ba5ad8aa498e4a09047574", "src_uid": "f63fc2d97fd88273241fce206cc217f2", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\nint area(int a[][4],int i)\n{\n    return (a[i][2]-a[i][0])*(a[i][3]-a[i][1]);\n}\nint main()\n{\n    int n,x,i,j;\n    scanf(\"%d\",&n);\n    int a[n][4];\n    int d[n];\n    for(i=0;i<n;i++)\n    {\n        for(j=0;j<4;j++)\n            scanf(\"%d\",&a[i][j]);\n    }\n    int max1=a[0][2];\n    int max2=a[0][3];\n    for(i=0;i<n;i++)\n        if(a[i][2]>=max1&&a[i][3]>=max2)\n        {\n\n            max1=a[i][2];\n            max2=a[i][3];\n\n        }\n    int min1=a[0][0];\n    int min2=a[0][1];\n    for(i=0;i<n;i++)\n        if(a[i][0]<=min1&&a[i][1]<=min2)\n        {\n            min1=a[i][0];\n            min2=a[i][1];\n        }\n\n        x=((max1-min1)*(max2-min2));\n\n     j=0;\n     for(i=0;i<n;i++)\n            {\n                d[i]=area(a,i);\n\n                j=j+d[i];\n\n            }\n\n\n     if(j==x&&((max2-min2)==(max1-min1)))\n        printf(\"YES\");\n     else\n        printf(\"NO\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9956d58a10c6b3d232246bf129d02af0", "src_uid": "f63fc2d97fd88273241fce206cc217f2", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\tint i,j,k,l,m,flag=0,n,x1,y1,x2,y2;\n\tlong int sum=0,ans=0,temp;\n\tscanf(\"%d\",&n);\n\tint a[n];\n\tint xmin[n],ymin[n],xmax[n],ymax[n];\n\tint minx,miny,maxx,maxy;\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d%d%d%d\",&x1,&y1,&x2,&y2);\t\n\t\ta[i]=(x2-x1)*(y2-y1);\n\t\txmin[i]=x1;\n\t\txmax[i]=x2;\n\t\tymin[i]=y1;\n\t\tymax[i]=y2;\n\t}\n\tfor(i=0;i<n;i++)\n\t{\n\t\tsum =a[i];\n\t\tminx=xmin[i];\n\t\tminy=ymin[i];\n\t\tmaxx=xmax[i];\n\t\tmaxy=ymax[i];\n\t\tif(maxx-minx==maxy-miny)\n\t\t{\n\t\t\ttemp=(maxx-minx)*(maxy-miny);\n\t\t\tif(temp == sum)\n\t\t\t{\n\t\t\t\tflag=1;\n\t\t\t}\n\t\t}\n\t\tfor(j=i+1;j<n;j++)\n\t\t{\n\t\t\tsum += a[j];\n\t\t\tif(xmin[j]<minx)\tminx=xmin[j];\n\t\t\tif(ymin[j]<miny)\tminy=ymin[j];\n\t\t\tif(xmax[j]>maxx)\tmaxx=xmax[j];\n\t\t\tif(ymax[j]>maxy)\tmaxy=ymax[j];\n\t\t\tif(maxx-minx==maxy-miny)\n\t\t\t{\n\t\t\t\ttemp=(maxx-minx)*(maxy-miny);\n\t\t\t\tif(temp == sum)\n\t\t\t\t{\n\t\t\t\t\tflag=1;\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor(k=j+1;k<n;k++)\n\t\t\t{\n\t\t\t\tsum += a[k];\n\t\t\t\tif(xmin[k]<minx)\tminx=xmin[k];\n\t\t\t\tif(ymin[k]<miny)\tminy=ymin[k];\n\t\t\t\tif(xmax[k]>maxx)\tmaxx=xmax[k];\n\t\t\t\tif(ymax[k]>maxy)\tmaxy=ymax[k];\n\t\t\t\tif(maxx-minx==maxy-miny)\n\t\t\t\t{\n\t\t\t\t\ttemp=(maxx-minx)*(maxy-miny);\n\t\t\t\t\tif(temp == sum)\n\t\t\t\t\t{\n\t\t\t\t\t\tflag=1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tfor(l=k+1;l<n;l++)\n\t\t\t\t{\n\t\t\t\t\tsum += a[l];\n\t\t\t\t\tif(xmin[l]<minx)\tminx=xmin[l];\n\t\t\t\t\tif(ymin[l]<miny)\tminy=ymin[l];\n\t\t\t\t\tif(xmax[l]>maxx)\tmaxx=xmax[l];\n\t\t\t\t\tif(ymax[l]>maxy)\tmaxy=ymax[l];\n\t\t\t\t\tif(maxx-minx==maxy-miny)\n\t\t\t\t\t{\n\t\t\t\t\t\ttemp=(maxx-minx)*(maxy-miny);\n\t\t\t\t\t\tif(temp == sum)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tflag=1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tfor(m=l+1;m<n;m++)\n\t\t\t\t\t{\n\t\t\t\t\t\tsum += a[m];\n\t\t\t\t\t\tif(xmin[m]<minx)\tminx=xmin[m];\n\t\t\t\t\t\tif(ymin[m]<miny)\tminy=ymin[m];\n\t\t\t\t\t\tif(xmax[m]>maxx)\tmaxx=xmax[m];\n\t\t\t\t\t\tif(ymax[m]>maxy)\tmaxy=ymax[m];\n\t\t\t\t\t\tif(maxx-minx==maxy-miny)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\ttemp=(maxx-minx)*(maxy-miny);\n\t\t\t\t\t\t\tif(temp == sum)\n\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\tflag=1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tif(flag==1)\tprintf(\"YES\\n\");\n\telse printf(\"NO\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b8dd4b6763e6ecb378cd67ed31b8193d", "src_uid": "f63fc2d97fd88273241fce206cc217f2", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main(){\n  int n = 0;\n  double s = 0, xm = 0, ym = 0, xl = 31400, yl = 31400;\n  scanf(\"%d\", &n);\n  while(n--){\n    double x1, y1, x2, y2;\n    scanf(\"%lf %lf %lf %lf\", &x1, &y1, &x2, &y2);\n    s = (y2-y1)*(x2-x1) + s;\n    if(x1<=xl)xl = x1;\n    if(y1<=yl)yl = y1;\n    if(x2>=xm)xm = x2;\n    if(y2>=ym)ym = y2;\n  }\n  if( x2-x1 == y2-y1 &&s == (m-l)*(m-l)){\n    printf(\"YES\\n\");\n  }\n  else{\n    printf(\"NO\\n\");\n  }\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "683df16fcd823dea425f4bc5e454f7ad", "src_uid": "f63fc2d97fd88273241fce206cc217f2", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n#include <string.h>\n\n#define K\t22\n#define N\t25000000\n\nint pp[] = { 2, 3, 5, 7, 11, 13, 17, 19, 23, 29,\n\t31, 37, 41, 43, 47, 53, 59, 61, 67, 71,\n\t73, 79 };\n\nchar bad[N + 1];\n\nint solve1(int n, int p) {\n\tint a, b, cnt;\n\n\tif (n < p)\n\t\treturn n == 0 ? 0 : 1;\n\tmemset(bad, 0, (n + 1) * sizeof *bad);\n\tcnt = n;\n\tfor (a = 2; a < p; a++) {\n\t\tif (bad[a])\n\t\t\tcontinue;\n\t\tfor (b = a; b <= n; b += a)\n\t\t\tif (!bad[b]) {\n\t\t\t\tbad[b] = 1;\n\t\t\t\tcnt--;\n\t\t\t}\n\t}\n\treturn cnt;\n}\n\nint solve2(int n, int k) {\n\tlong long ans;\n\tint b, i;\n\n\tans = 0;\n\tfor (b = 0; b < 1 << k; b++) {\n\t\tint m = n, parity = 0;\n\n\t\tfor (i = 0; i < k; i++)\n\t\t\tif ((b & 1 << i) != 0) {\n\t\t\t\tint p = pp[i];\n\n\t\t\t\tm /= p;\n\t\t\t\tparity ^= 1;\n\t\t\t}\n\t\tans += parity == 0 ? m : -m;\n\t}\n\treturn ans;\n}\n\nint prime(int p) {\n\tint a;\n\n\tfor (a = 2; a <= p / a; a++)\n\t\tif (p % a == 0)\n\t\t\treturn 0;\n\treturn 1;\n}\n\nint main() {\n\tint a, b, p, ans, i;\n\n\tscanf(\"%d%d%d\", &a, &b, &p);\n\tif (!prime(p)) {\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\ti = 0;\n\twhile (i < K && pp[i] < p)\n\t\ti++;\n\tif (i == K)\n\t\tans = solve1(b / p, p) - solve1((a - 1) / p, p);\n\telse\n\t\tans = solve2(b / p, i) - solve2((a - 1) / p, i);\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "635d4195c0c5e5f14f0c37b28878528d", "src_uid": "04a26f1d1013b6e6b4b0bdcf225475f2", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint l[26]={2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97,101},prime[2000001];\nchar hash[20000001];\nint k,a,b,ans=0;\n\nvoid dfs(int now,int s,int f)\n{\n   if (l[now]==k)\n      ans+=f*(b/s-(a-1)/s);\n   else\n   {\n      dfs(now+1,s,f);\n      if ((long long)s*l[now]<=b)\n         dfs(now+1,s*l[now],-f);\n   }\n}\n\nint main()\n{\n   int i,j,o=0;\n   scanf(\"%d%d%d\",&a,&b,&k);\n   b/=k;\n   a=(long long)(a+k-1)/k;\n   for (i=2;i*i<=k&&k%i;i++);\n   if (i*i>k)\n      if (k<=100)\n         dfs(0,1,1);\n      else\n      {\n         ans+=(a==1&&b>=1);\n         for (i=2;i<=b;i++)\n         {\n            if (!hash[i])\n            {\n               ans+=(i>=k&&a<=i);\n               prime[++o]=i;\n            }\n            for (j=1;prime[j]*i<=b;j++)\n            {\n               hash[prime[j]*i]=1;\n               ans+=(prime[j]>=k&&a<=prime[j]*i);\n               if (i%prime[j]==0)\n                  break;\n            }\n         }\n      }\n   printf(\"%d\\n\",ans);\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2bc2820351629ad2dfc322b7de225383", "src_uid": "04a26f1d1013b6e6b4b0bdcf225475f2", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define gmax(a,b) ((a)>(b)?(a):(b))\nlong tot1,tot2,total=0,z[5000005]={0},hash[20000005]={0},last[20000005]={0},ans1,ans2;\nlong work1(long count,long k)\n{\n\tlong o=count/k,tot=0,sum=0,i,j;\n\tfor(i=2;i<=o;i++)\n\t{\n\t\tif(hash[i]==0)\n\t\t{\n\t\t\tz[++tot]=i;\n\t\t\tlast[i]=i;\n\t\t}\n\t\tfor(j=1;j<=tot && z[j]*i<=o;j++)\n\t\t{\n\t\t\thash[z[j]*i]=1;\n\t\t\tlast[z[j]*i]=z[j];\n\t\t\tif(i%z[j]==0)\n\t\t\t\tbreak;\n\t\t}\n\t}\n\tfor(i=2;i<=o;i++)\n\t\tif(last[i]>=k)\n\t\t\tsum++;\n\tif(count>=k)\n\t\tsum++;\n\treturn sum;\n}\nvoid dfs(long k,long p,long long u)\n{\n\tif(u>gmax(tot1,tot2))\n\t\treturn ;\n\tif(k<=total)\n\t{\n\t\tdfs(k+1,p,u);\n\t\tdfs(k+1,p+1,u*z[k]);\n\t}\n\telse if(p)\n\t{\n\t\tif(p%2)\n\t\t{\n\t\t\tans1-=tot1/u;\n\t\t\tans2-=tot2/u;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tans1+=tot1/u;\n\t\t\tans2+=tot2/u;\n\t\t}\n\t}\n}\nlong check(long k)\n{\n\tlong i;\n\tfor(i=2;i<=sqrt(k);i++)\n\t\tif(k%i==0)\n\t\t\treturn 0;\n\treturn 1;\n}\nint main()\n{\n\tlong k,i,A,B,j;\n//\tfreopen(\"d.in\",\"r\",stdin);\n//\tfreopen(\"d.out\",\"w\",stdout);\n\tscanf(\"%ld %ld %ld\\n\",&A,&B,&k);\n\tif(check(k)==0)\n\t{\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\tif(k>=100)\n\t\tprintf(\"%ld\\n\",work1(B,k)-work1(A-1,k));\n\telse\n\t{\n\t\tfor(i=2;i<k;i++)\n\t\t{\n\t\t\tif(hash[i]==0)\n\t\t\t{\n\t\t\t\tz[++total]=i;\n\t\t\t\tlast[i]=i;\n\t\t\t}\n\t\t\tfor(j=1;j<=total && z[j]*i<k;j++)\n\t\t\t{\n\t\t\t\thash[z[j]*i]=1;\n\t\t\t\tif(i%z[j]==0)\n\t\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\ttot1=B/k; tot2=(A-1)/k;\n\t\tans1=B/k; ans2=(A-1)/k;\n\t\tdfs(1,0,1);\n\t\tprintf(\"%ld\\n\",ans1-ans2);\n\t}\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "40a0d70914fb1ec138edd5025d68c431", "src_uid": "04a26f1d1013b6e6b4b0bdcf225475f2", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\n#define ll long long\n#define N 31807\n\nint getPrime(int n,int p[]){int i,j,n2=n/2;rep(i,n2)p[i]=1;for(i=3;i*i<n;i+=2)if(p[i>>1])for(j=(i*i)>>1;j<n2;j+=i)p[j]=0;j=1;p[0]=2;REP(i,1,n2)if(p[i])p[j++]=i*2+1;return j;}\nint ps, p[N];\n\nll res, pp;\nint a,b,n;\n\nvoid solve(ll now, int st, int num){\n  int i,j,k;\n  ll send, add;\n\n  add = b / now - (a-1) / now;\n  if(num%2) add *= -1;\n  res += add;\n  \n  REP(i,st,pp){\n    send = now * p[i];\n    if(send > b) break;\n    solve(send, i+1, num+1);\n  }\n}\n\nint is_prime(int n){\n  int i;\n  rep(i,ps){\n    if(in[i]*in[i] > n) break;\n    if(n%in[i]==0) return 0;\n  }\n  return 1;\n}\n\nint main(){\n  int i,j,k,l,m;\n\n  ps = getPrime(N,p);\n\n  while(scanf(\"%d%d%d\",&a,&b,&n)==3){\n    rep(i,ps) if(n==p[i]) break;\n    if(i==ps){\n      if(a<=n && n<=b && is_prime(n)) puts(\"1\"); else puts(\"0\");\n      continue;\n    }\n\n    pp = i;\n    res = 0;\n    solve(n,0,0);\n\n    printf(\"%d\\n\",(int)res);\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "4925a5f151609cfc858c6b5f03113815", "src_uid": "04a26f1d1013b6e6b4b0bdcf225475f2", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define gmax(a,b) ((a)>(b)?(a):(b))\nlong tot1,tot2,total=0,z[5000005]={0},hash[20000005]={0},last[20000005]={0},ans1,ans2;\nlong work1(long count,long k)\n{\n\tlong o=count/k,tot=0,sum=0,i,j;\n\tfor(i=2;i<=o;i++)\n\t{\n\t\tif(hash[i]==0)\n\t\t{\n\t\t\tz[++tot]=i;\n\t\t\tlast[i]=i;\n\t\t}\n\t\tfor(j=1;j<=tot && z[j]*i<=o;j++)\n\t\t{\n\t\t\thash[z[j]*i]=1;\n\t\t\tlast[z[j]*i]=z[j];\n\t\t\tif(i%z[j]==0)\n\t\t\t\tbreak;\n\t\t}\n\t}\n\tfor(i=2;i<=o;i++)\n\t\tif(last[i]>=k)\n\t\t\tsum++;\n\treturn sum;\n}\nvoid dfs(long k,long p,long long u)\n{\n\tif(u>gmax(tot1,tot2))\n\t\treturn ;\n\tif(k<=total)\n\t{\n\t\tdfs(k+1,p,u);\n\t\tdfs(k+1,p+1,u*z[k]);\n\t}\n\telse if(p)\n\t{\n\t\tif(p%2)\n\t\t{\n\t\t\tans1-=tot1/u;\n\t\t\tans2-=tot2/u;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tans1+=tot1/u;\n\t\t\tans2+=tot2/u;\n\t\t}\n\t}\n}\nint main()\n{\n\tlong k,i,A,B,j;\n//\tfreopen(\"d.in\",\"r\",stdin);\n//\tfreopen(\"d.out\",\"w\",stdout);\n\tscanf(\"%ld %ld %ld\\n\",&A,&B,&k);\n\tif(check(k)==0)\n\t\tprintf(\"0\\n\");\n\tif(k>=100)\n\t\tprintf(\"%ld\\n\",work1(B,k)-work1(A-1,k));\n\telse\n\t{\n\t\tfor(i=2;i<k;i++)\n\t\t{\n\t\t\tif(hash[i]==0)\n\t\t\t{\n\t\t\t\tz[++total]=i;\n\t\t\t\tlast[i]=i;\n\t\t\t}\n\t\t\tfor(j=1;j<=total && z[j]*i<k;j++)\n\t\t\t{\n\t\t\t\thash[z[j]*i]=1;\n\t\t\t\tif(i%z[j]==0)\n\t\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\ttot1=B/k; tot2=(A-1)/k;\n\t\tans1=B/k; ans2=(A-1)/k;\n\t\tdfs(1,0,1);\n\t\tprintf(\"%ld\\n\",ans1-ans2);\n\t}\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "27a82d6bee51a2001bea1ee0ea5f8d89", "src_uid": "04a26f1d1013b6e6b4b0bdcf225475f2", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint n;\nchar a[11][11], b[11][11], c[11][11];\n\nvoid turn()\n{\n    int i, j, k, l;\n    for(i=n-1, k=0; i>=0; --i, ++k)\n        for(j=0, l=0; j<n; ++j, ++l)\n            c[k][l] = a[j][i];\n    for(i=0; i<n; ++i)\n        for(j=0; j<n; ++j)\n            a[i][j] = c[i][j];\n}\n\nint same()\n{\n    int i, j;\n    for(i=0; i<n; ++i)\n        for(j=0; j<n; ++j)\n            if(a[i][j]!=b[i][j])\n                return 0;\n    return 1;\n}\n\nvoid p()\n{\n    int i, j;\n    printf(\"\\n\\n\");\n    for(i=0; i<n; ++i)\n    {\n        for(j=0; j<n; ++j)\n            printf(\"%c\", a[i][j]);\n        printf(\"\\n\");\n    }\n    printf(\"\\n\\n\");\n}\n\nvoid f()\n{\n    int i, j;\n    for(i=0; i<3; ++i)\n    {\n        if(same())\n        {\n            printf(\"Yes\\n\");\n            return;\n        }\n        turn();\n    }\n    for(i=0; i<n; ++i)\n        for(j=0; j<n; ++j)\n            c[i][j] = a[i][n-j-1];\n    for(i=0; i<n; ++i)\n        for(j=0; j<n; ++j)\n            a[i][j] = c[i][j];\n\n    for(i=0; i<3; ++i)\n    {\n        if(same())\n        {\n            printf(\"Yes\\n\");\n            return;\n        }\n        turn();\n    }\n    printf(\"No\\n\");\n    return;\n}\n\nint main()\n{\n    scanf(\"%d\", &n);\n    int i, j;\n    for(i=0; i<n; ++i)\n        scanf(\"%s\", a[i]);\n    for(i=0; i<n; ++i)\n        scanf(\"%s\", b[i]);\n\n    f();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8e431ef668d4ba407d2ce3d30769d241", "src_uid": "2e793c9f476d03e8ba7df262db1c06e4", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n#include <conio.h>\n\nint main()\n{\n    int n,i,j;\n    scanf(\"%d\",&n);\n\n    char map1[n][n+1],map2[n][n+1];\n\n    for(i=0;i<n;i++){\n        scanf(\"%s\",map1[i]);\n    }\n\n    for(i=0;i<n;i++){\n        scanf(\"%s\",map2[i]);\n    }\n\n    int a,b,c,rot=0;\n\n    while(1){\n\n        a=1,b=1,c=1;\n        for(i=0;i<n;i++){\n            if(a==1){\n                for(j=0;j<n;j++){\n                    if(map1[i][j]!=map2[i][j]){\n                        a=0;\n                        break;\n                    }\n                }\n            }\n            if(b==1){\n                for(j=0;j<n;j++){\n                    if(map1[n-1-i][j]!=map2[i][j]){\n                        b=0;\n                        break;\n                    }\n                }\n            }\n            if(c==1){\n                for(j=0;j<n;j++){\n                    if(map1[i][n-1-j]!=map2[i][j]){\n                        c=0;\n                        break;\n                    }\n                }\n            }\n            if(a==0&&b==0&&c==0){\n                break;\n            }\n\n        }\n\n        if(i==n){\n            printf(\"Yes\\n\");\n            break;\n        }\n        else{\n            if(rot==4){\n                printf(\"No\\n\");\n                break;\n            }\n            else{\n                rot++;\n            }\n        }\n\n        int lim=n/2;\n        for(i=0;i<lim;i++){\n            for(j=i;j<n-1-i;j++){\n                char temp=map1[i][j];\n                map1[i][j]=map1[j][n-1-i];\n                map1[j][n-1-i]=map1[n-1-i][n-1-j];\n                map1[n-1-i][n-1-j]=map1[n-1-j][i];\n                map1[n-1-j][i]=temp;\n            }\n        }\n    }\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "06be5a538ee0003f98deb9ed20650cf8", "src_uid": "2e793c9f476d03e8ba7df262db1c06e4", "difficulty": 1400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <time.h>\n#include <stdlib.h>\nchar a[20][11],b[20][11];\nint n;\nint check()\n{\n    int k=0;\n    for (int i=0; i<n; i++)\n    {\n        for (int j=0; j<n; j++)\n        {\n            if (a[n+i][j]!=b[i][j])\n            {\n                k=1;\n                break;\n            }\n        }\n    }\n    if (k==0)\n    {\n        printf(\"YES\");\n        return 10;\n    }\n    else\n        return 0;\n}\nvoid ud()\n{\n    for (int i=0; i<n; i++)\n    {\n        for (int j=0; j<n; j++)\n        {\n            b[n-i-1][j]=a[i][j];\n        }\n    }\n}\nvoid lr()\n{\n    for (int i=0; i<n; i++)\n    {\n        for (int j=0; j<n; j++)\n        {\n            b[i][n-j-1]=a[i][j];\n        }\n    }\n}\nvoid rot()\n{\n    for (int i=0; i<n; i++)\n    {\n        for (int j=0; j<n; j++)\n        {\n            b[n-j-1][i]=a[i][j];\n        }\n    }\n}\nvoid match()\n{\n    for (int i=0; i<n; i++)\n    {\n        for (int j=0; j<n; j++)\n        {\n            a[i][j]=b[i][j];\n        }\n    }\n}\nint main()\n{\n    scanf(\"%d\",&n);\n    for (int i=0; i<n*2; i++)\n    {\n        scanf(\"%s\",a[i]);\n    }\n    for (int i=0; i<4; i++)\n    {\n        rot();\n        match();\n        if (check()==10)\n            return 0;\n        ud();\n        match();\n        if (check()==10)\n            return 0;\n        lr();\n        match();\n        if (check()==10)\n            return 0;\n        ud();\n        match();\n        if (check()==10)\n            return 0;\n        lr();\n        match();\n        if (check()==10)\n            return 0;\n    }\n    printf(\"NO\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "05aadccd4c1e7fc26aef3de9b78ab24d", "src_uid": "2e793c9f476d03e8ba7df262db1c06e4", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    int a,i,j,k,flag,count=0;\n    scanf(\"%d\",&a);\n    char arr[a][a],oth[a][a],change[a][a],matha_nosto[a][a];\n    for(i=0; i<a; i++)\n    {\n        for(j=0; j<a; j++)\n            scanf(\" %c\",&arr[i][j]);\n    }\n\n    for(i=0; i<a; i++)\n    {\n        for(j=0; j<a; j++)\n            scanf(\" %c\",&oth[i][j]);\n    }\n\n    for(i=0; i<a; i++)\n    {\n        for(j=0; j<a; j++)\n            change[j][a-1-i]=oth[i][j];\n    }\n    for(k=0; k<a+6; k++)\n    {\n        for(i=0; i<a; i++)\n        {\n            for(j=0; j<a; j++)\n            {\n                if(arr[i][j]==change[i][j])\n                    flag=1;\n                else\n                {\n                    flag=0;\n                    break;\n                }\n            }\n            if(flag==0)\n                break;\n        }\n        if(flag==1)\n        {\n            printf(\"YES\");\n            return 0;\n        }\n        else\n        {\n            for(i=0; i<a; i++)\n            {\n                for(j=0; j<a; j++)\n                {\n                    if(arr[i][j]==change[i][a-1-j])\n                        flag=1;\n                    else\n                    {\n                        flag=0;\n                        break;\n                    }\n                }\n                if(flag==0)\n                    break;\n            }\n            if(flag==1)\n            {\n                printf(\"YES\");\n                return 0;\n            }\n            else\n            {\n                for(i=0; i<a; i++)\n                {\n                    for(j=0; j<a; j++)\n                        oth[i][j]=change[i][j];\n                }\n\n                for(i=0; i<a; i++)\n                {\n                    for(j=0; j<a; j++)\n                        change[j][a-1-i]=oth[i][j];\n                }\n            }\n        }\n\n    }\n    printf(\"NO\");\n    return 0;\n}\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a778feaa3de2c38f5949e8a27930d445", "src_uid": "2e793c9f476d03e8ba7df262db1c06e4", "difficulty": 1400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#include <string.h>\n#include <ctype.h>\n#include <limits.h>\n#include <malloc.h>\n#include <memory.h>\n#include <stdbool.h>\nint n,m,i,j,ans[505],k,z,ff,f[55],l,s;\nstruct u\n{\n\tint a,b;\n}a[55],b[55];\n\nvoid swap(int *x,int *y)\n{\n\tint t;\n\t\n\tt=*x;\n\t*x=*y;\n\t*y=t;\n}\n\nint main()\n{\n\tscanf(\"%d %d\",&n,&m);\n\tfor (i=1;i<=n;i++) \n\t{\n\t\tscanf(\"%d %d\",&a[i].a,&a[i].b);\n\t\tif (a[i].a>a[i].b) swap(&a[i].a,&a[i].b);\n\t}\n\tfor (i=1;i<=m;i++) \n\t{\n\t\tscanf(\"%d %d\",&b[i].a,&b[i].b);\n\t\tif (b[i].a>b[i].b) swap(&b[i].a,&b[i].b);\n\t}\n\tfor (i=1,k=0,ff=0;i<=n;i++)\n\t{\n\t\tfor (j=1,z=0;j<=m;j++)\n\t\t{\n\t\t\tmemset(f,0,sizeof(f));\n\t\t\tf[a[i].a]++;\n\t\t\tf[a[i].b]++;\n\t\t\tf[b[j].a]++;\n\t\t\tf[b[j].b]++;\n\t\t\tfor (l=1,s=0;l<=9;l++) \n\t\t\tif (f[l]) s++;\n\t\t\tif (s==3)\n\t\t\t{\n\t\t\t\tfor (l=1,s=0;l<=9;l++)\n\t\t\t\tif (f[l]==2) \n\t\t\t\t{\n\t\t\t\t\tans[++k]=l;\n\t\t\t\t\tz++;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (z>1) ff=1;\n\t}\n\tif (k==1)\n\t{\n\t\tprintf(\"%d\\n\",ans[1]);\n\t\texit(0);\n\t}\n\telse if (!ff)\n\t{\n\t\tputs(\"0\");\n\t\texit(0);\n\t}\n\telse puts(\"-1\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ed35e5d21b0325087f40aa92a2126172", "src_uid": "cb4de190ae26127df6eeb7a1a1db8a6d", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#include <string.h>\n#include <ctype.h>\n#include <limits.h>\n#include <malloc.h>\n#include <memory.h>\n#include <stdbool.h>\nint n,m,i,j,ans[505],k,z,ff,f[55],l,s;\nstruct u\n{\n\tint a,b;\n}a[55],b[55];\n\nvoid swap(int *x,int *y)\n{\n\tint t;\n\t\n\tt=*x;\n\t*x=*y;\n\t*y=t;\n}\n\nint main()\n{\n\tscanf(\"%d %d\",&n,&m);\n\tfor (i=1;i<=n;i++) \n\t{\n\t\tscanf(\"%d %d\",&a[i].a,&a[i].b);\n\t\tif (a[i].a>a[i].b) swap(&a[i].a,&a[i].b);\n\t}\n\tfor (i=1;i<=m;i++) \n\t{\n\t\tscanf(\"%d %d\",&b[i].a,&b[i].b);\n\t\tif (b[i].a>b[i].b) swap(&b[i].a,&b[i].b);\n\t}\n\tfor (i=1,k=0,ff=0;i<=n;i++)\n\t{\n\t\tfor (j=1,z=0;j<=m;j++)\n\t\t{\n\t\t\tmemset(f,0,sizeof(f));\n\t\t\tf[a[i].a]++;\n\t\t\tf[a[i].b]++;\n\t\t\tf[b[j].a]++;\n\t\t\tf[b[j].b]++;\n\t\t\tfor (l=1,s=0;l<=9;l++) \n\t\t\tif (f[l]) s++;\n\t\t\tif (s==3)\n\t\t\t{\n\t\t\t\tfor (l=1,s=0;l<=9;l++)\n\t\t\t\tif (f[l]==2) \n\t\t\t\t{\n\t\t\t\t\tans[++k]=l;\n\t\t\t\t\tz++;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (z>1) ff=1;\n\t}\n\tif (k==1)\n\t{\n\t\tprintf(\"%d\\n\",ans[1]);\n\t\texit(0);\n\t}\n\telse if (!ff&&k)\n\t{\n\t\tputs(\"0\");\n\t\texit(0);\n\t}\n\telse puts(\"-1\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6f1613696775ddd00f757a2f86503ab9", "src_uid": "cb4de190ae26127df6eeb7a1a1db8a6d", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#define _USE_MATH_DEFINES\n#include <stdio.h>\n#include <math.h>\n#include <stdlib.h>\n#include <string.h>\n#include <ctype.h>\n#include <stdbool.h>\n#include <float.h>\n#include <limits.h>\n#include <malloc.h>\n#include <memory.h>\n#include <complex.h>\n#include <errno.h>\n#include <time.h>\nint n,m,i,j,k,min,ans[25][25],f[25],d[25],s;\nstruct u\n{\n\tint a,b;\n}a[5][25];\n\nvoid dfs(int x,int y,int z)\n{\n\tint i;\n\t\n\tif (x<=0) return;\n\tfor (i=1;i<=y;i++) \n\tif (!f[i])\n\t{\n\t\tf[i]=1;\n\t\tmemset(d,0,sizeof(d));\n\t\td[a[z^1][x].a]++;\n\t\td[a[z^1][x].b]++;\n\t\td[a[z][i].a]++;\n\t\td[a[z][i].b]++;\n\t\tfor (j=1,s=0;j<=9;j++) \n\t\tif (d[j]) \n\t\t{\n\t\t\ts++;\n\t\t\tif (d[j]==2) k=j;\n\t\t}\n\t\tif (s==3) \n\t\t{\n\t\t\tans[x][k]++;\n\t\t}\n\t\tdfs(x-1,y,z);\n\t\tf[i]=0;\n\t}\n}\n\nint main()\n{\n\tscanf(\"%d %d\",&n,&m);\n\tfor (i=1;i<=n;i++) scanf(\"%d %d\",&a[0][i].a,&a[0][i].b);\n\tfor (i=1;i<=m;i++) scanf(\"%d %d\",&a[1][i].a,&a[1][i].b);\n\tmin=n<m ? n : m;\n\tmemset(f,0,sizeof(f));\n\tmemset(ans,0,sizeof(ans));\n\tif (m<n) dfs(m,n,0); else dfs(n,m,1);\n\tmemset(d,0,sizeof(d));\n\tfor (i=1;i<=min;i++)\n\t{\n\t\tfor (j=1,s=0;j<=9;j++)\n\t\tif (ans[i][j]) \n\t\t{\n\t\t\td[j]++;\n\t\t\ts++;\n\t\t}\n\t\tans[i][0]=s;\n\t}\n\t\n\tfor (i=1,s=0;i<=9;i++) \n\tif (d[i]) \n\t{\n\t\ts++;\n\t\tk=i;\n\t}\n\tif (s==0) puts(\"-1\");\n\telse if (s==1) printf(\"%d\\n\",k);\n\telse \n\t{\n\t\tfor (i=1,s=0;i<=min;i++) \n\t\tif (ans[i][0]>1) \n\t\t{\n\t\t\ts=1;\n\t\t\tbreak;\n\t\t}\n\t\tif (s) puts(\"-1\"); else puts(\"0\");\n\t}\n\treturn 0;\n}\n\n\n\n\n\n\n\n\n\n\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5fb355deb26d3fc5028d608a00ca018a", "src_uid": "cb4de190ae26127df6eeb7a1a1db8a6d", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint n,m;\nstruct x{\n\tint x,y;\n}x[17],y[17];\nint xc[17],yc[17];\nvoid run(){\n\tint i,j,k,j_,k_,l;\n\twhile(scanf(\"%d%d\",&n,&m)!=EOF){\n\t\tfor(i=0;i<n;i++){\n\t\t\tscanf(\"%d%d\",&x[i].x,&x[i].y);\n\t\t}\n\t\tfor(i=0;i<m;i++){\n\t\t\tscanf(\"%d%d\",&y[i].x,&y[i].y);\n\t\t}\n\t\tfor(i=0;i<10;i++){\n\t\t\txc[i]=0;\n\t\t\tyc[i]=0;\n\t\t}\n\t\tfor(i=0;i<n;i++){\n\t\t\tl=0;\n\t\t\tfor(j=0;j<m;j++){\n\t\t\t\tif((x[i].x==y[j].x&&x[i].y!=y[j].y)\n\t\t\t\t\t||(x[i].x==y[j].y&&x[i].y!=y[j].x)){\n\t\t\t\t\txc[x[i].x]++;\n\t\t\t\t\tl|=1;\n\t\t\t\t}\n\t\t\t\tif((x[i].y==y[j].x&&x[i].x!=y[j].y)\n\t\t\t\t\t||(x[i].y==y[j].y&&x[i].x!=y[j].x)){\n\t\t\t\t\txc[x[i].y]++;\n\t\t\t\t\tl|=2;\n\t\t\t\t}\n\t\t\t\tif(l==3){\n\t\t\t\t\tprintf(\"-1\\n\");\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(j<m){\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(i<n){\n\t\t\tcontinue;\n\t\t}\n\t\tfor(i=0;i<m;i++){\n\t\t\tl=0;\n\t\t\tfor(j=0;j<n;j++){\n\t\t\t\tif((y[i].x==x[j].x&&y[i].y!=x[j].y)\n\t\t\t\t\t||(y[i].x==x[j].y&&y[i].y!=x[j].x)){\n\t\t\t\t\tyc[y[i].x]++;\n\t\t\t\t\tl|=1;\n\t\t\t\t}\n\t\t\t\tif((y[i].y==x[j].x&&y[i].x!=x[j].y)\n\t\t\t\t\t||(y[i].y==x[j].y&&y[i].x!=x[j].x)){\n\t\t\t\t\tyc[y[i].y]++;\n\t\t\t\t\tl|=2;\n\t\t\t\t}\n\t\t\t\tif(l==3){\n\t\t\t\t\tprintf(\"-1\\n\");\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(j<n){\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(i<m){\n\t\t\tcontinue;\n\t\t}\n\t\tj=0;\n\t\tj_=-1;\n\t\tfor(i=0;i<10;i++){\n\t\t\tif(xc[i]>0){\n\t\t\t\tj++;\n\t\t\t\tj_=i;\n\t\t\t}\n\t\t}\n\t\tk=0;\n\t\tk_=-1;\n\t\tfor(i=0;i<10;i++){\n\t\t\tif(yc[i]>0){\n\t\t\t\tk++;\n\t\t\t\tk_=i;\n\t\t\t}\n\t\t}\n\t\tif(j==1&&k==1){\n\t\t\tprintf(\"%d\\n\",j_);\n\t\t\tcontinue;\n\t\t}\n\t\tprintf(\"0\\n\");\n\t}\n}\nmain(){\n#ifndef\tONLINE_JUDGE\n\tfreopen(\"4882d_min.in\",\"rb\",stdin);\n\tfreopen(\"4882d_.out\",\"wb\",stdout);\n#endif\n\trun();\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ce537de3b6ddc5ae11b6c20b8be26e43", "src_uid": "cb4de190ae26127df6eeb7a1a1db8a6d", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n/*\n2 2\n1 2 3 4\n1 5 6 4\n*/\nint main(){\n\tint n,m,i;\n\tscanf(\"%d %d\",&n,&m);\n\n\tint arr[2*n], brr[2*m];\n\tfor (i = 0; i < n; i++){\n\t\tscanf(\"%d %d\",2*i + arr, 2*i + 1 + arr);\n\t\t\n\t}\n\tfor (i = 0; i < m; i++){\n\t\tscanf(\"%d %d\",2*i + brr, 2*i + 1 + brr);\n\t}\n\n\tint ans = 1, j, sh = -1;\n\tfor (i = 0; i < n; i++){\n\n\t\tfor (j = 0; j < m; j++){\n\n\t\t\tif ((arr[2*i] == brr[2*j] && arr[2*i + 1] != brr[2*j + 1]) || (arr[2*i] == brr[2*j+1] && arr[2*i + 1] != brr[2*j])){\n\t\t\t\tif (sh == -1){\n\t\t\t\t\tsh = arr[2*i];\n\t\t\t\t}\n\t\t\t\telse if (arr[2*i] != sh){\n\t\t\t\t\tans = 0;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\telse if ((arr[2*i + 1] == brr[2*j] && arr[2*i] != brr[2*j + 1]) || (arr[2*i + 1] == brr[2*j+1] && arr[2*i] != brr[2*j])){\n\t\t\t\tif (sh == -1){\n\t\t\t\t\tsh = arr[2*i+1];\n\t\t\t\t}\n\t\t\t\telse if (arr[2*i+1] != sh){\n\t\t\t\t\tans = 0;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tif (ans != 1){\n\t\t\tbreak;\n\t\t}\n\n\t}\n\n\tif (ans){\n\t\tprintf(\"%d\\n\",sh);\n\t\treturn 0;\n\t}\n\n\tans = 0;\n\tfor (i = 0; i < n; i++){\n\n\t\tsh = -1;\n\n\t\tfor (j = 0; j < m; j++){\n\n\t\t\tif ((arr[2*i] == brr[2*j] && arr[2*i + 1] != brr[2*j + 1]) || (arr[2*i] == brr[2*j+1] && arr[2*i + 1] != brr[2*j])){\n\t\t\t\tif (sh == -1){\n\t\t\t\t\tsh = arr[2*i];\n\t\t\t\t}\n\t\t\t\telse if (arr[2*i] != sh){\n\t\t\t\t\tans = -1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\telse if ((arr[2*i + 1] == brr[2*j] && arr[2*i] != brr[2*j + 1]) || (arr[2*i + 1] == brr[2*j+1] && arr[2*i] != brr[2*j])){\n\t\t\t\tif (sh == -1){\n\t\t\t\t\tsh = arr[2*i+1];\n\t\t\t\t}\n\t\t\t\telse if (arr[2*i+1] != sh){\n\t\t\t\t\tans = -1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tif (ans != 0){\n\t\t\tbreak;\n\t\t}\n\n\t}\n\n\tfor (j = 0; j < m; j++){\n\n\t\tsh = -1;\n\n\t\tfor (i = 0; i < n; i++){\n\n\t\t\tif ((arr[2*i] == brr[2*j] && arr[2*i + 1] != brr[2*j + 1]) || (arr[2*i] == brr[2*j+1] && arr[2*i + 1] != brr[2*j])){\n\t\t\t\tif (sh == -1){\n\t\t\t\t\tsh = arr[2*i];\n\t\t\t\t}\n\t\t\t\telse if (arr[2*i] != sh){\n\t\t\t\t\tans = -1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\telse if ((arr[2*i + 1] == brr[2*j] && arr[2*i] != brr[2*j + 1]) || (arr[2*i + 1] == brr[2*j+1] && arr[2*i] != brr[2*j])){\n\t\t\t\tif (sh == -1){\n\t\t\t\t\tsh = arr[2*i+1];\n\t\t\t\t}\n\t\t\t\telse if (arr[2*i+1] != sh){\n\t\t\t\t\tans = -1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tif (ans != 0){\n\t\t\tbreak;\n\t\t}\n\n\t}\n\n\tprintf(\"%d\\n\",ans);\n\treturn 0;\n\n}\n\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e302db2d446e12d498631999d8d7031a", "src_uid": "cb4de190ae26127df6eeb7a1a1db8a6d", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <algorithm>\nusing namespace std;\nlong long ans=0;\nlong long hei(long long a,long long b,long long c,long long m)\n{\n     long long cnt=min(a-b-c,m);\n     if (cnt<0) return 0; else return (cnt+1)*(cnt+2)/2;\n}\nint main()\n{\n     long long a,b,c,l;\n     cin>>a>>b>>c>>l;\n     ans+=(l+3)*(l+2)*(l+1)/6;\n     for (long long i=0;i<=l;i++) ans-=hei(a+i,b,c,l-i)+hei(b+i,a,c,l-i)+hei(c+i,a,b,l-i);\n     cout<<ans;\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8847e28dbee14d291de5b159c82aa0c3", "src_uid": "185ff90a8b0ae0e2b75605f772589410", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nlong long ans=0;\nlong long hei(long long a,long long b,long long c,long long m)\n{\n     long long cnt=min(a-b-c,m);\n     if (cnt<0) return 0; else return (cnt+1)*(cnt+2)/2;\n}\nint main()\n{\n     long long a,b,c,l;\n     cin>>a>>b>>c>>l;\n     ans+=(l+3)*(l+2)*(l+1)/6;\n     for (long long i=0;i<=l;i++) ans-=hei(a+i,b,c,l-i)+hei(b+i,a,c,l-i)+hei(c+i,a,b,l-i);\n     cout<<ans;\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "9ea1b76f9a99223206c3cb3012b22d37", "src_uid": "185ff90a8b0ae0e2b75605f772589410", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long ans=0;\nlong long mini(long long int x ,long long int y){\n\tif(x > y)\n\t\treturn x;\n\treturn y;\n}\nlong long hei(long long a,long long b,long long c,long long m)\n{\n     long long cnt = mini(a-b-c,m);\n     if (cnt<0) return 0;\n\t  else \n\t  return (cnt+1)*(cnt+2)/2;\n}\nint main()\n{\n     long long a,b,c,l;\n     cin>>a>>b>>c>>l;\n     scanf(\"%d %d %d %d\",a,b,c,l);\n     ans+=(l+3)*(l+2)*(l+1)/6;\n     for (long long i=0;i<=l;i++) ans-=hei(a+i,b,c,l-i)+hei(b+i,a,c,l-i)+hei(c+i,a,b,l-i);\n     printf(\"%d\", ans);\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "21581c73acb2f51ede57681074a0e0b7", "src_uid": "185ff90a8b0ae0e2b75605f772589410", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long ans=0;\nlong long mini(long long int x ,long long int y){\n\tif(x > y)\n\t\treturn y;\n\treturn x;\n}\nlong long hei(long long a,long long b,long long c,long long m)\n{\n     long long cnt = mini(a-b-c,m);\n     if (cnt<0) return 0;\n\t  else \n\t  return (cnt+1)*(cnt+2)/2;\n}\nint main()\n{\n     long long a,b,c,l;\n     long long int i = 0;\n     scanf(\"%d %d %d %d\",&a,&b,&c,&l);\n     ans+=(l+3)*(l+2)*(l+1)/6;\n     for (i=0;i<=l;i++) \n\t ans -= (hei(a+i,b,c,l-i) + hei(b+i,a,c,l-i) + hei(c+i,a,b,l-i));\n     printf(\"%d\", ans);\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "93727f7cb554723e1783ac18742c2f1d", "src_uid": "185ff90a8b0ae0e2b75605f772589410", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long ans=0;\nlong long mini(long long int x ,long long int y){\n\tif(x > y)\n\t\treturn x;\n\treturn y;\n}\nlong long hei(long long a,long long b,long long c,long long m)\n{\n     long long cnt = mini(a-b-c,m);\n     if (cnt<0) return 0;\n\t  else \n\t  return (cnt+1)*(cnt+2)/2;\n}\nint main()\n{\n     long long a,b,c,l;\n     long long int i = 0;\n     scanf(\"%d %d %d %d\",a,b,c,l);\n     ans+=(l+3)*(l+2)*(l+1)/6;\n     for (i=0;i<=l;i++) ans-=hei(a+i,b,c,l-i)+hei(b+i,a,c,l-i)+hei(c+i,a,b,l-i);\n     printf(\"%d\", ans);\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d16e156c2d8c1b2a18eabf82d7378ec6", "src_uid": "185ff90a8b0ae0e2b75605f772589410", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int a=0,b=0,c=0,d=0,e=0,f=0,n;\n    scanf(\"%d\",&n);\n    if(n>=32)\n    {\n        a=1;\n        n-=32;\n    }\n    if(n>=16)\n    {\n        b=1;\n        n-=16;\n    }\n    if(n>=8)\n    {\n        c=1;\n        n-=8;\n    }\n    if(n>=4)\n    {\n        d=1;\n        n-=4;\n    }\n    if(n>=2)\n    {\n        e=1;\n        n-=2;\n    }\n    if(n>=1)\n    {\n        f=1;\n        n-=1;\n    }\n    n=(a*32)+(b*1)+(c*4)+(d*8)+(e*2)+(f*16);\n    printf(\"%d\",n);\n    return(0);\n    }\n    ", "lang_cluster": "C", "compilation_error": false, "code_uid": "77db15a393b456bbdd03b4663685a741", "src_uid": "db5e54f466e1f3d69a51ea0b346e667c", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint main()\n{\n\tint a,b,c,d,e,f,g;\n\tscanf(\"%d\",&a);\n\tb= a>> 5;\n\tc = a >> 4 & 1;\n\td = a >> 3 & 1;\n\te = a >> 2 & 1;\n\tf = a >> 1 & 1;\n\tg = a >> 0 & 1;\n\tprintf(\"%d\\n\",(b<<5) |(c<<4) |(d<<3) |(e<<2) |(f<<1) |(g<<0));\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5aea6b5501ce8ca1f63540158618c260", "src_uid": "db5e54f466e1f3d69a51ea0b346e667c", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint i,a;\n\tscanf(\"%d\",&a);\n\tfor(i=2;i<a;i++)\n\t{\n\t\tif(a%i==0)\n\t\t{\n\t\t\ta=a/i;\n\t\t\tprintf(\"%d%d\",i,a);\n\t\t\tbreak;\n\t\t}\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "496ae06c4b27fc454baad031961775e9", "src_uid": "db5e54f466e1f3d69a51ea0b346e667c", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n    int a,b[6],i,temp;\n    scanf(\"%d\",&a);\n    for(i=5;i>=0;i--)\n    {\n        if(a!=0)\n        {\n            b[i]=a%2;\n            a=a/2;\n        }\n        else\n            b[i]=0;\n    }\n    temp=b[1];\n    b[1]=b[5];\n    b[5]=temp;\n    temp=b[2];\n    b[2]=b[3];\n    b[3]=temp;\n    for(i=5,a=0;i>=0;i--,a++)\n    {\n        temp+=b[i]*pow(2,a);\n    }\n    printf(\"%d\",temp);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "22496be67f10cea73dc26d999bb746d5", "src_uid": "db5e54f466e1f3d69a51ea0b346e667c", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\n\nint main(void)\n{\n     int n,i;\n     scanf(\"%d\",&n);\n     int arr[6];\n     for(i=0;i<6;i++)\n     {\n          arr[i]=0;\n     }\n     i=0\n     while(n>0)\n     {\n          arr[5-i]=n%2;i++;\n          n=n/2;\n     }\n     int sum=(arr[1]*1+arr[4]*2+arr[2]*4+arr[3]*8+arr[5]*16+arr[0]*32);\n     printf(\"%d\",sum);\n     \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "af97ec372912b64bb56d31797568d783", "src_uid": "db5e54f466e1f3d69a51ea0b346e667c", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t50\n#define M\t(N * (N - 1))\n#define N_\t(N + 2)\n#define M_\t(M * 3 + 2)\n#define X\t100000\n#define INF\t0x3f3f3f3f\n\nint min(int a, int b) { return a < b ? a : b; }\n\nint oo[1 + M * 2], oh[1 + M * 2], _ = 1;\n\nint link(int o, int h) {\n\too[_] = o, oh[_] = h;\n\treturn _++;\n}\n\nint oo_[1 + M_ * 2], oh_[1 + M_ * 2], __;\n\nint link_(int o, int h) {\n\too_[__] = o, oh_[__] = h;\n\treturn __++;\n}\n\nint ae[N], af[N], ae_[N_], dd[N_], n_;\nint ii[M], jj[M], ww[M]; char tt[M]; int ij[M_], cc[M_ * 2], m_;\nint pq[1 + N], iq[N], cnt;\n\nint less(int u, int v) { return dd[u] < dd[v]; }\n\nint i2(int i) {\n\treturn (i *= 2) > cnt ? 0 : i < cnt && less(pq[i + 1], pq[i]) ? i + 1 : i;\n}\n\nvoid pq_up(int u) {\n\tint i, j, v;\n\n\tfor (i = iq[u]; (j = i / 2) && less(u, v = pq[j]); i = j)\n\t\tpq[iq[v] = i] = v;\n\tpq[iq[u] = i] = u;\n}\n\nvoid pq_dn(int u) {\n\tint i, j, v;\n\n\tfor (i = iq[u]; (j = i2(i)) && less(v = pq[j], u); i = j)\n\t\tpq[iq[v] = i] = v;\n\tpq[iq[u] = i] = u;\n}\n\nvoid pq_add_last(int u) {\n\tpq[iq[u] = ++cnt] = u;\n}\n\nint pq_remove_first() {\n\tint u = pq[1], v = pq[cnt--];\n\n\tif (v != u)\n\t\tiq[v] = 1, pq_dn(v);\n\tiq[u] = 0;\n\treturn u;\n}\n\nvoid dijkstra(int n, int s) {\n\tmemset(dd, 0x3f, n * sizeof *dd);\n\tdd[s] = 0, pq_add_last(s);\n\twhile (cnt) {\n\t\tint i = pq_remove_first(), o;\n\n\t\tfor (o = ae[i]; o; o = oo[o]) {\n\t\t\tint h = oh[o];\n\n\t\t\tif (!tt[h]) {\n\t\t\t\tint j = jj[h], d = dd[i] + ww[h];\n\n\t\t\t\tif (dd[j] > d) {\n\t\t\t\t\tif (dd[j] == INF)\n\t\t\t\t\t\tpq_add_last(j);\n\t\t\t\t\tdd[j] = d, pq_up(j);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\n\nvoid link2(int i, int j, int c) {\n\tint h = m_++;\n\n\tij[h] = i ^ j, cc[h << 1] = c, cc[h << 1 | 1] = 0;\n\tae_[i] = link_(ae_[i], h << 1);\n\tae_[j] = link_(ae_[j], h << 1 | 1);\n}\n\nint bfs(int s, int t) {\n\tstatic int qu[N_];\n\tint i, head, cnt;\n\n\tfor (i = 0; i < n_; i++)\n\t\tdd[i] = n_;\n\thead = cnt = 0;\n\tdd[s] = 0, qu[head + cnt++] = s;\n\twhile (cnt) {\n\t\tint d, o;\n\n\t\ti = qu[cnt--, head++], d = dd[i] + 1;\n\t\tfor (o = ae_[i]; o; o = oo_[o]) {\n\t\t\tint h_ = oh_[o];\n\n\t\t\tif (cc[h_]) {\n\t\t\t\tint h = h_ >> 1, j = i ^ ij[h];\n\n\t\t\t\tif (dd[j] > d) {\n\t\t\t\t\tdd[j] = d;\n\t\t\t\t\tif (j == t)\n\t\t\t\t\t\treturn 1;\n\t\t\t\t\tqu[head + cnt++] = j;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\n\nint dfs(int i, int t) {\n\tint d, o;\n\n\tif (i == t)\n\t\treturn 1;\n\td = dd[i] + 1;\n\tfor (o = ae_[i]; o; o = oo_[o]) {\n\t\tint h_ = oh_[o];\n\n\t\tif (cc[h_]) {\n\t\t\tint h = h_ >> 1, j = i ^ ij[h];\n\n\t\t\tif (dd[j] == d && dfs(j, t)) {\n\t\t\t\tcc[h_]--, cc[h_ ^ 1]++;\n\t\t\t\treturn 1;\n\t\t\t}\n\t\t}\n\t}\n\tdd[i] = n_;\n\treturn 0;\n}\n\nvoid dinic(int s, int t) {\n\twhile (bfs(s, t))\n\t\twhile (dfs(s, t))\n\t\t\t;\n}\n\nchar reachable[N];\n\nvoid dfs_(int j) {\n\tint o;\n\n\tif (reachable[j])\n\t\treturn;\n\treachable[j] = 1;\n\tfor (o = af[j]; o; o = oo[o]) {\n\t\tint h = oh[o], i = ii[h];\n\n\t\tdfs_(i);\n\t}\n}\n\nint main() {\n\tstatic double ans[X + 1];\n\tstatic int dd1[N], dd2[N], xx[M];\n\tint n, m, q, h, x, s, t;\n\n\tscanf(\"%d%d\", &n, &m);\n\tfor (h = 0; h < m; h++) {\n\t\tint i, j, w;\n\n\t\tscanf(\"%d%d%d\", &i, &j, &w), i--, j--;\n\t\tii[h] = i, jj[h] = j, ww[h] = w;\n\t\tae[i] = link(ae[i], h);\n\t}\n\tn_ = n + 2, s = n, t = n + 1;\n\tx = 0;\n\twhile (x < X) {\n\t\tint k, y, z, d, d_;\n\n\t\tmemset(tt, 0, m * sizeof *tt);\n\t\tdijkstra(n, 0);\n\t\tmemcpy(dd1, dd, n * sizeof *dd);\n\t\td = dd1[n - 1];\n\t\tmemset(ae_, 0, n_ * sizeof *ae_), __ = 1, m_ = 0;\n\t\tlink2(s, 0, INF);\n\t\tlink2(n - 1, t, INF);\n\t\tfor (h = 0; h < m; h++) {\n\t\t\tint i = ii[h], j = jj[h], w = ww[h];\n\n\t\t\tif (dd1[i] + w == dd1[j]) {\n\t\t\t\ttt[h] = 1;\n\t\t\t\tlink2(s, j, 1), link2(i, t, 1);\n\t\t\t\tif (xx[h] == 0)\n\t\t\t\t\tlink2(j, i, INF);\n\t\t\t}\n\t\t}\n\t\tdinic(s, t);\n\t\td_ = INF;\n\t\tk = 0;\n\t\tmemset(af, 0, n * sizeof *af), _ = 1 + m;\n\t\tfor (h = 0; h < m; h++) {\n\t\t\tint i = ii[h], j = jj[h];\n\n\t\t\tif (tt[h]) {\n\t\t\t\tif ((dd[i] == n_) == (dd[j] == n_)) {\n\t\t\t\t\ttt[h] = 0;\n\t\t\t\t\taf[j] = link(af[j], h);\n\t\t\t\t} else if (dd[i] != n_) {\n\t\t\t\t\ttt[h] = 1;\n\t\t\t\t\tk++;\n\t\t\t\t} else {\n\t\t\t\t\ttt[h] = 2;\n\t\t\t\t\tk--;\n\t\t\t\t\td_ = min(d_, d + xx[h]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tmemset(reachable, 0, n * sizeof *reachable);\n\t\tdfs_(n - 1);\n\t\tdijkstra(n, 0);\n\t\tmemcpy(dd2, dd, n * sizeof *dd);\n\t\td_ = min(d_, dd2[n - 1]);\n\t\tfor (h = 0; h < m; h++)\n\t\t\tif (tt[h] == 2 && dd2[ii[h]] != INF && dd1[jj[h]] != INF && reachable[jj[h]])\n\t\t\t\td_ = min(d_, d + dd2[ii[h]] + ww[h] - dd1[jj[h]]);\n\t\ty = d_ - d <= (X - x) / k ? x + (d_ - d) * k : X;\n\t\tfor (z = x; z <= y; z++)\n\t\t\tans[z] = d + (double) (z - x) / k;\n\t\tif (y < X) {\n\t\t\tfor (h = 0; h < m; h++)\n\t\t\t\tif (tt[h] == 1)\n\t\t\t\t\tww[h] += d_ - d, xx[h] += d_ - d;\n\t\t\t\telse if (tt[h] == 2)\n\t\t\t\t\tww[h] -= d_ - d, xx[h] -= d_ - d;\n\t\t}\n\t\tx = y;\n\t}\n\tscanf(\"%d\", &q);\n\twhile (q--) {\n\t\tscanf(\"%d\", &x);\n\t\tprintf(\"%f\\n\", ans[x]);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "471146ac1b7b49c2bac827fbd8dad8b5", "src_uid": "b0751071e12f729f6700586c5a8eed23", "difficulty": 3100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t50\n#define M\t(N * (N - 1))\n#define N_\t(N + 2)\n#define M_\t(M * 3 + 2)\n#define X\t100000\n#define INF\t0x3f3f3f3f\n\nint min(int a, int b) { return a < b ? a : b; }\n\nint oo[1 + M * 2], oh[1 + M * 2], _ = 1;\n\nint link(int o, int h) {\n\too[_] = o, oh[_] = h;\n\treturn _++;\n}\n\nint oo_[1 + M_ * 2], oh_[1 + M_ * 2], __;\n\nint link_(int o, int h) {\n\too_[__] = o, oh_[__] = h;\n\treturn __++;\n}\n\nint ae[N], af[N], ae_[N_], dd[N_], n_;\nint ii[M], jj[M], ww[M]; char tt[M]; int ij[M_], cc[M_ * 2], m_;\nint pq[1 + N], iq[N], cnt;\n\nint less(int u, int v) { return dd[u] < dd[v]; }\n\nint i2(int i) {\n\treturn (i *= 2) > cnt ? 0 : i < cnt && less(pq[i + 1], pq[i]) ? i + 1 : i;\n}\n\nvoid pq_up(int u) {\n\tint i, j, v;\n\n\tfor (i = iq[u]; (j = i / 2) && less(u, v = pq[j]); i = j)\n\t\tpq[iq[v] = i] = v;\n\tpq[iq[u] = i] = u;\n}\n\nvoid pq_dn(int u) {\n\tint i, j, v;\n\n\tfor (i = iq[u]; (j = i2(i)) && less(v = pq[j], u); i = j)\n\t\tpq[iq[v] = i] = v;\n\tpq[iq[u] = i] = u;\n}\n\nvoid pq_add_last(int u) {\n\tpq[iq[u] = ++cnt] = u;\n}\n\nint pq_remove_first() {\n\tint u = pq[1], v = pq[cnt--];\n\n\tif (v != u)\n\t\tiq[v] = 1, pq_dn(v);\n\tiq[u] = 0;\n\treturn u;\n}\n\nvoid dijkstra(int n, int s) {\n\tmemset(dd, 0x3f, n * sizeof *dd);\n\tdd[s] = 0, pq_add_last(s);\n\twhile (cnt) {\n\t\tint i = pq_remove_first(), o;\n\n\t\tfor (o = ae[i]; o; o = oo[o]) {\n\t\t\tint h = oh[o];\n\n\t\t\tif (!tt[h]) {\n\t\t\t\tint j = jj[h], d = dd[i] + ww[h];\n\n\t\t\t\tif (dd[j] > d) {\n\t\t\t\t\tif (dd[j] == INF)\n\t\t\t\t\t\tpq_add_last(j);\n\t\t\t\t\tdd[j] = d, pq_up(j);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\n\nvoid link2(int i, int j, int c) {\n\tint h = m_++;\n\n\tij[h] = i ^ j, cc[h << 1] = c, cc[h << 1 | 1] = 0;\n\tae_[i] = link_(ae_[i], h << 1);\n\tae_[j] = link_(ae_[j], h << 1 | 1);\n}\n\nint bfs(int s, int t) {\n\tstatic int qu[N_];\n\tint i, head, cnt;\n\n\tfor (i = 0; i < n_; i++)\n\t\tdd[i] = n_;\n\thead = cnt = 0;\n\tdd[s] = 0, qu[head + cnt++] = s;\n\twhile (cnt) {\n\t\tint d, o;\n\n\t\ti = qu[cnt--, head++], d = dd[i] + 1;\n\t\tfor (o = ae_[i]; o; o = oo_[o]) {\n\t\t\tint h_ = oh_[o];\n\n\t\t\tif (cc[h_]) {\n\t\t\t\tint h = h_ >> 1, j = i ^ ij[h];\n\n\t\t\t\tif (dd[j] > d) {\n\t\t\t\t\tdd[j] = d;\n\t\t\t\t\tif (j == t)\n\t\t\t\t\t\treturn 1;\n\t\t\t\t\tqu[head + cnt++] = j;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\n\nint dfs(int i, int t) {\n\tint d, o;\n\n\tif (i == t)\n\t\treturn 1;\n\td = dd[i] + 1;\n\tfor (o = ae_[i]; o; o = oo_[o]) {\n\t\tint h_ = oh_[o];\n\n\t\tif (cc[h_]) {\n\t\t\tint h = h_ >> 1, j = i ^ ij[h];\n\n\t\t\tif (dd[j] == d && dfs(j, t)) {\n\t\t\t\tcc[h_]--, cc[h_ ^ 1]++;\n\t\t\t\treturn 1;\n\t\t\t}\n\t\t}\n\t}\n\tdd[i] = n_;\n\treturn 0;\n}\n\nvoid dinic(int s, int t) {\n\twhile (bfs(s, t))\n\t\twhile (dfs(s, t))\n\t\t\t;\n}\n\nchar reachable[N];\n\nvoid dfs_(int j) {\n\tint o;\n\n\tif (reachable[j])\n\t\treturn;\n\treachable[j] = 1;\n\tfor (o = af[j]; o; o = oo[o]) {\n\t\tint h = oh[o], i = ii[h];\n\n\t\tdfs_(i);\n\t}\n}\n\nint main() {\n\tstatic double ans[X + 1];\n\tstatic int dd1[N], dd2[N], xx[M];\n\tint n, m, q, h, x, s, t;\n\n\tscanf(\"%d%d\", &n, &m);\n\tfor (h = 0; h < m; h++) {\n\t\tint i, j, w;\n\n\t\tscanf(\"%d%d%d\", &i, &j, &w), i--, j--;\n\t\tii[h] = i, jj[h] = j, ww[h] = w;\n\t\tae[i] = link(ae[i], h);\n\t}\n\tn_ = n + 2, s = n, t = n + 1;\n\tx = 0;\n\twhile (x < X) {\n\t\tint k, y, z, d, d_;\n\n\t\tmemset(tt, 0, m * sizeof *tt);\n\t\tdijkstra(n, 0);\n\t\tmemcpy(dd1, dd, n * sizeof *dd);\n\t\td = dd1[n - 1];\n\t\tmemset(ae_, 0, n_ * sizeof *ae_), __ = 1, m_ = 0;\n\t\tlink2(s, 0, INF);\n\t\tlink2(n - 1, t, INF);\n\t\tfor (h = 0; h < m; h++) {\n\t\t\tint i = ii[h], j = jj[h], w = ww[h];\n\n\t\t\tif (dd1[i] + w == dd1[j]) {\n\t\t\t\ttt[h] = 1;\n\t\t\t\tlink2(s, j, 1), link2(i, t, 1);\n\t\t\t\tif (xx[h] == 0)\n\t\t\t\t\tlink2(j, i, INF);\n\t\t\t}\n\t\t}\n\t\tdinic(s, t);\n\t\td_ = INF;\n\t\tk = 0;\n\t\tmemset(af, 0, n * sizeof *af), _ = 1 + m;\n\t\tfor (h = 0; h < m; h++) {\n\t\t\tint i = ii[h], j = jj[h];\n\n\t\t\tif (tt[h]) {\n\t\t\t\tif ((dd[i] == n_) == (dd[j] == n_)) {\n\t\t\t\t\ttt[h] = 0;\n\t\t\t\t\taf[j] = link(af[j], h);\n\t\t\t\t} else if (dd[i] != n_) {\n\t\t\t\t\ttt[h] = 1;\n\t\t\t\t\tk++;\n\t\t\t\t} else {\n\t\t\t\t\ttt[h] = 2;\n\t\t\t\t\tk--;\n\t\t\t\t\td_ = min(d_, d + xx[h]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tmemset(reachable, 0, n * sizeof *reachable);\n\t\tdfs_(n - 1);\n\t\tdijkstra(n, 0);\n\t\tmemcpy(dd2, dd, n * sizeof *dd);\n\t\td_ = min(d_, dd2[n - 1]);\n\t\tfor (h = 0; h < m; h++)\n\t\t\tif (tt[h] == 2 && dd2[ii[h]] != INF && dd1[jj[h]] != INF && reachable[jj[h]])\n\t\t\t\td_ = min(d_, d + dd2[ii[h]] - dd1[jj[h]]);\n\t\ty = d_ - d <= (X - x) / k ? x + (d_ - d) * k : X;\n\t\tfor (z = x; z <= y; z++)\n\t\t\tans[z] = d + (double) (z - x) / k;\n\t\tif (y < X) {\n\t\t\tfor (h = 0; h < m; h++)\n\t\t\t\tif (tt[h] == 1)\n\t\t\t\t\tww[h] += d_ - d, xx[h] += d_ - d;\n\t\t\t\telse if (tt[h] == 2)\n\t\t\t\t\tww[h] -= d_ - d, xx[h] -= d_ - d;\n\t\t}\n\t\tx = y;\n\t}\n\tscanf(\"%d\", &q);\n\twhile (q--) {\n\t\tscanf(\"%d\", &x);\n\t\tprintf(\"%f\\n\", ans[x]);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2fb377603a43b07f5fb0a0e1d15a806b", "src_uid": "b0751071e12f729f6700586c5a8eed23", "difficulty": 3100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t50\n#define M\t(N * (N - 1))\n#define N_\t(N + 2)\n#define M_\t(M * 3 + 2)\n#define X\t100000\n#define INF\t0x3f3f3f3f\n\nint min(int a, int b) { return a < b ? a : b; }\n\nint oo[1 + M * 2], oh[1 + M * 2], _ = 1;\n\nint link(int o, int h) {\n\too[_] = o, oh[_] = h;\n\treturn _++;\n}\n\nint oo_[1 + M_ * 2], oh_[1 + M_ * 2], __;\n\nint link_(int o, int h) {\n\too_[__] = o, oh_[__] = h;\n\treturn __++;\n}\n\nint ae[N], af[N], ae_[N_], dd[N_], n_;\nint ii[M], jj[M], ww[M]; char tt[M]; int ij[M_], cc[M_ * 2], m_;\nint pq[1 + N], iq[N], cnt;\n\nint less(int u, int v) { return dd[u] < dd[v]; }\n\nint i2(int i) {\n\treturn (i *= 2) > cnt ? 0 : i < cnt && less(pq[i + 1], pq[i]) ? i + 1 : i;\n}\n\nvoid pq_up(int u) {\n\tint i, j, v;\n\n\tfor (i = iq[u]; (j = i / 2) && less(u, v = pq[j]); i = j)\n\t\tpq[iq[v] = i] = v;\n\tpq[iq[u] = i] = u;\n}\n\nvoid pq_dn(int u) {\n\tint i, j, v;\n\n\tfor (i = iq[u]; (j = i2(i)) && less(v = pq[j], u); i = j)\n\t\tpq[iq[v] = i] = v;\n\tpq[iq[u] = i] = u;\n}\n\nvoid pq_add_last(int u) {\n\tpq[iq[u] = ++cnt] = u;\n}\n\nint pq_remove_first() {\n\tint u = pq[1], v = pq[cnt--];\n\n\tif (v != u)\n\t\tiq[v] = 1, pq_dn(v);\n\tiq[u] = 0;\n\treturn u;\n}\n\nvoid dijkstra(int n, int s) {\n\tmemset(dd, 0x3f, n * sizeof *dd);\n\tdd[s] = 0, pq_add_last(s);\n\twhile (cnt) {\n\t\tint i = pq_remove_first(), o;\n\n\t\tfor (o = ae[i]; o; o = oo[o]) {\n\t\t\tint h = oh[o];\n\n\t\t\tif (!tt[h]) {\n\t\t\t\tint j = jj[h], d = dd[i] + ww[h];\n\n\t\t\t\tif (dd[j] > d) {\n\t\t\t\t\tif (dd[j] == INF)\n\t\t\t\t\t\tpq_add_last(j);\n\t\t\t\t\tdd[j] = d, pq_up(j);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\n\nvoid link2(int i, int j, int c) {\n\tint h = m_++;\n\n\tij[h] = i ^ j, cc[h << 1] = c, cc[h << 1 | 1] = 0;\n\tae_[i] = link_(ae_[i], h << 1);\n\tae_[j] = link_(ae_[j], h << 1 | 1);\n}\n\nint bfs(int s, int t) {\n\tstatic int qu[N_];\n\tint i, head, cnt;\n\n\tfor (i = 0; i < n_; i++)\n\t\tdd[i] = n_;\n\thead = cnt = 0;\n\tdd[s] = 0, qu[head + cnt++] = s;\n\twhile (cnt) {\n\t\tint d, o;\n\n\t\ti = qu[cnt--, head++], d = dd[i] + 1;\n\t\tfor (o = ae_[i]; o; o = oo_[o]) {\n\t\t\tint h_ = oh_[o];\n\n\t\t\tif (cc[h_]) {\n\t\t\t\tint h = h_ >> 1, j = i ^ ij[h];\n\n\t\t\t\tif (dd[j] > d) {\n\t\t\t\t\tdd[j] = d;\n\t\t\t\t\tif (j == t)\n\t\t\t\t\t\treturn 1;\n\t\t\t\t\tqu[head + cnt++] = j;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\n\nint dfs(int i, int t) {\n\tint d, o;\n\n\tif (i == t)\n\t\treturn 1;\n\td = dd[i] + 1;\n\tfor (o = ae_[i]; o; o = oo_[o]) {\n\t\tint h_ = oh_[o];\n\n\t\tif (cc[h_]) {\n\t\t\tint h = h_ >> 1, j = i ^ ij[h];\n\n\t\t\tif (dd[j] == d && dfs(j, t)) {\n\t\t\t\tcc[h_]--, cc[h_ ^ 1]++;\n\t\t\t\treturn 1;\n\t\t\t}\n\t\t}\n\t}\n\tdd[i] = n_;\n\treturn 0;\n}\n\nvoid dinic(int s, int t) {\n\twhile (bfs(s, t))\n\t\twhile (dfs(s, t))\n\t\t\t;\n}\n\nchar reachable[N];\n\nvoid dfs_(int j) {\n\tint o;\n\n\tif (reachable[j])\n\t\treturn;\n\treachable[j] = 1;\n\tfor (o = af[j]; o; o = oo[o]) {\n\t\tint h = oh[o], i = ii[h];\n\n\t\tdfs_(i);\n\t}\n}\n\nint main() {\n\tstatic double ans[X + 1];\n\tstatic int dd1[N], dd2[N], xx[M];\n\tint n, m, q, h, x, s, t;\n\n\tscanf(\"%d%d\", &n, &m);\n\tfor (h = 0; h < m; h++) {\n\t\tint i, j, w;\n\n\t\tscanf(\"%d%d%d\", &i, &j, &w), i--, j--;\n\t\tii[h] = i, jj[h] = j, ww[h] = w;\n\t\tae[i] = link(ae[i], h);\n\t}\n\tn_ = n + 2, s = n, t = n + 1;\n\tx = 0;\n\twhile (x < X) {\n\t\tint k, y, z, d, d_;\n\n\t\tmemset(tt, 0, m * sizeof *tt);\n\t\tdijkstra(n, 0);\n\t\tmemcpy(dd1, dd, n * sizeof *dd);\n\t\td = dd1[n - 1];\n\t\tmemset(ae_, 0, n_ * sizeof *ae_), __ = 1, m_ = 0;\n\t\tlink2(s, 0, INF);\n\t\tlink2(n - 1, t, INF);\n\t\tfor (h = 0; h < m; h++) {\n\t\t\tint i = ii[h], j = jj[h], w = ww[h];\n\n\t\t\tif (dd1[i] + w == dd1[j]) {\n\t\t\t\ttt[h] = 1;\n\t\t\t\tlink2(s, j, 1), link2(i, t, 1);\n\t\t\t\tif (xx[h] == 0)\n\t\t\t\t\tlink2(j, i, INF);\n\t\t\t}\n\t\t}\n\t\tdinic(s, t);\n\t\td_ = INF;\n\t\tk = 0;\n\t\tmemset(af, 0, n * sizeof *af), _ = 1 + m;\n\t\tfor (h = 0; h < m; h++) {\n\t\t\tint i = ii[h], j = jj[h];\n\n\t\t\tif (tt[h]) {\n\t\t\t\tif ((dd[i] == n_) == (dd[j] == n_)) {\n\t\t\t\t\ttt[h] = 0;\n\t\t\t\t\taf[j] = link(af[j], h);\n\t\t\t\t} else if (dd[i] != n_) {\n\t\t\t\t\ttt[h] = 1;\n\t\t\t\t\tk++;\n\t\t\t\t} else {\n\t\t\t\t\ttt[h] = 2;\n\t\t\t\t\tk--;\n\t\t\t\t\td_ = min(d_, d + xx[h]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tmemset(reachable, 0, n * sizeof *reachable);\n\t\tdfs_(n - 1);\n\t\tdijkstra(n, 0);\n\t\tmemcpy(dd2, dd, n * sizeof *dd);\n\t\td_ = min(d_, dd2[n - 1]);\n\t\tfor (h = 0; h < m; h++)\n\t\t\tif (tt[h] == 2 && dd2[ii[h]] != INF && reachable[jj[h]])\n\t\t\t\td_ = min(d_, d + dd2[ii[h]] - dd1[jj[h]]);\n\t\ty = d_ - d <= (X - x) / k ? x + (d_ - d) * k : X;\n\t\tfor (z = x; z <= y; z++)\n\t\t\tans[z] = d + (double) (z - x) / k;\n\t\tif (y < X) {\n\t\t\tfor (h = 0; h < m; h++)\n\t\t\t\tif (tt[h] == 1)\n\t\t\t\t\tww[h] += d_ - d, xx[h] += d_ - d;\n\t\t\t\telse if (tt[h] == 2)\n\t\t\t\t\tww[h] -= d_ - d, xx[h] -= d_ - d;\n\t\t}\n\t\tx = y;\n\t}\n\tscanf(\"%d\", &q);\n\twhile (q--) {\n\t\tscanf(\"%d\", &x);\n\t\tprintf(\"%f\\n\", ans[x]);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7a601992feb451e2aa4f0e315f06a6c6", "src_uid": "b0751071e12f729f6700586c5a8eed23", "difficulty": 3100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t50\n#define M\t(N * (N - 1))\n#define N_\t(N + 2)\n#define M_\t(M * 3 + 2)\n#define X\t100000\n#define INF\t0x3f3f3f3f\n\nint min(int a, int b) { return a < b ? a : b; }\n\nint oo[1 + M], oh[1 + M], _ = 1;\n\nint link(int o, int h) {\n\too[_] = o, oh[_] = h;\n\treturn _++;\n}\n\nint oo_[1 + M_ * 2], oh_[1 + M_ * 2], __;\n\nint link_(int o, int h) {\n\too_[__] = o, oh_[__] = h;\n\treturn __++;\n}\n\nint ae[N], af[N], ae_[N_], dd[N_], n_;\nint ii[M], jj[M], ww[M]; char tt[M]; int ij[M_], cc[M_ * 2], m_;\nint pq[1 + N], iq[N], cnt;\n\nint less(int u, int v) { return dd[u] < dd[v]; }\n\nint i2(int i) {\n\treturn (i *= 2) > cnt ? 0 : i < cnt && less(pq[i + 1], pq[i]) ? i + 1 : i;\n}\n\nvoid pq_up(int u) {\n\tint i, j, v;\n\n\tfor (i = iq[u]; (j = i / 2) && less(u, v = pq[j]); i = j)\n\t\tpq[iq[v] = i] = v;\n\tpq[iq[u] = i] = u;\n}\n\nvoid pq_dn(int u) {\n\tint i, j, v;\n\n\tfor (i = iq[u]; (j = i2(i)) && less(v = pq[j], u); i = j)\n\t\tpq[iq[v] = i] = v;\n\tpq[iq[u] = i] = u;\n}\n\nvoid pq_add_last(int u) {\n\tpq[iq[u] = ++cnt] = u;\n}\n\nint pq_remove_first() {\n\tint u = pq[1], v = pq[cnt--];\n\n\tif (v != u)\n\t\tiq[v] = 1, pq_dn(v);\n\tiq[u] = 0;\n\treturn u;\n}\n\nvoid dijkstra(int n, int s) {\n\tmemset(dd, 0x3f, n * sizeof *dd);\n\tdd[s] = 0, pq_add_last(s);\n\twhile (cnt) {\n\t\tint i = pq_remove_first(), o;\n\n\t\tfor (o = ae[i]; o; o = oo[o]) {\n\t\t\tint h = oh[o];\n\n\t\t\tif (!tt[h]) {\n\t\t\t\tint j = jj[h], d = dd[i] + ww[h];\n\n\t\t\t\tif (dd[j] > d) {\n\t\t\t\t\tif (dd[j] == INF)\n\t\t\t\t\t\tpq_add_last(j);\n\t\t\t\t\tdd[j] = d, pq_up(j);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\n\nvoid link2(int i, int j, int c) {\n\tint h = m_++;\n\n\tij[h] = i ^ j, cc[h << 1] = c, cc[h << 1 | 1] = 0;\n\tae_[i] = link_(ae_[i], h << 1);\n\tae_[j] = link_(ae_[j], h << 1 | 1);\n}\n\nint bfs(int s, int t) {\n\tstatic int qu[N_];\n\tint i, head, cnt;\n\n\tfor (i = 0; i < n_; i++)\n\t\tdd[i] = n_;\n\thead = cnt = 0;\n\tdd[s] = 0, qu[head + cnt++] = s;\n\twhile (cnt) {\n\t\tint d, o;\n\n\t\ti = qu[cnt--, head++], d = dd[i] + 1;\n\t\tfor (o = ae_[i]; o; o = oo_[o]) {\n\t\t\tint h_ = oh_[o];\n\n\t\t\tif (cc[h_]) {\n\t\t\t\tint h = h_ >> 1, j = i ^ ij[h];\n\n\t\t\t\tif (dd[j] > d) {\n\t\t\t\t\tdd[j] = d;\n\t\t\t\t\tif (j == t)\n\t\t\t\t\t\treturn 1;\n\t\t\t\t\tqu[head + cnt++] = j;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\n\nint dfs(int i, int t) {\n\tint d, o;\n\n\tif (i == t)\n\t\treturn 1;\n\td = dd[i] + 1;\n\tfor (o = ae_[i]; o; o = oo_[o]) {\n\t\tint h_ = oh_[o];\n\n\t\tif (cc[h_]) {\n\t\t\tint h = h_ >> 1, j = i ^ ij[h];\n\n\t\t\tif (dd[j] == d && dfs(j, t)) {\n\t\t\t\tcc[h_]--, cc[h_ ^ 1]++;\n\t\t\t\treturn 1;\n\t\t\t}\n\t\t}\n\t}\n\tdd[i] = n_;\n\treturn 0;\n}\n\nvoid dinic(int s, int t) {\n\twhile (bfs(s, t))\n\t\twhile (dfs(s, t))\n\t\t\t;\n}\n\nchar reachable[N];\n\nvoid dfs_(int j) {\n\tint o;\n\n\tif (reachable[j])\n\t\treturn;\n\treachable[j] = 1;\n\tfor (o = af[j]; o; o = oo[o]) {\n\t\tint h = oh[o], i = ii[h];\n\n\t\tdfs_(i);\n\t}\n}\n\nint main() {\n\tstatic double ans[X + 1];\n\tstatic int dd1[N], dd2[N], xx[M];\n\tint n, m, q, h, x, s, t;\n\n\tscanf(\"%d%d\", &n, &m);\n\tfor (h = 0; h < m; h++) {\n\t\tint i, j, w;\n\n\t\tscanf(\"%d%d%d\", &i, &j, &w), i--, j--;\n\t\tii[h] = i, jj[h] = j, ww[h] = w;\n\t\tae[i] = link(ae[i], h);\n\t}\n\tn_ = n + 2, s = n, t = n + 1;\n\tx = 0;\n\twhile (x < X) {\n\t\tint k, y, z, d, d_;\n\n\t\tmemset(tt, 0, m * sizeof *tt);\n\t\tdijkstra(n, 0);\n\t\tmemcpy(dd1, dd, n * sizeof *dd);\n\t\td = dd1[n - 1];\n\t\tmemset(ae_, 0, n_ * sizeof *ae_), __ = 1, m_ = 0;\n\t\tlink2(s, 0, INF);\n\t\tlink2(n - 1, t, INF);\n\t\tfor (h = 0; h < m; h++) {\n\t\t\tint i = ii[h], j = jj[h], w = ww[h];\n\n\t\t\tif (dd1[i] + w == dd1[j]) {\n\t\t\t\ttt[h] = 1;\n\t\t\t\tlink2(s, j, 1), link2(i, t, 1);\n\t\t\t\tif (xx[h] == 0)\n\t\t\t\t\tlink2(j, i, INF);\n\t\t\t}\n\t\t}\n\t\tdinic(s, t);\n\t\td_ = INF;\n\t\tk = 0;\n\t\t_ = 1 + m;\n\t\tfor (h = 0; h < m; h++) {\n\t\t\tint i = ii[h], j = jj[h];\n\n\t\t\tif (tt[h]) {\n\t\t\t\tif ((dd[i] == n_) == (dd[j] == n_)) {\n\t\t\t\t\ttt[h] = 0;\n\t\t\t\t\taf[j] = link(af[j], h);\n\t\t\t\t} else if (dd[i] != n_) {\n\t\t\t\t\ttt[h] = 1;\n\t\t\t\t\tk++;\n\t\t\t\t} else {\n\t\t\t\t\ttt[h] = 2;\n\t\t\t\t\tk--;\n\t\t\t\t\td_ = min(d_, d + xx[h]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tmemset(reachable, 0, n * sizeof *reachable);\n\t\tdfs_(n - 1);\n\t\tdijkstra(n, 0);\n\t\tmemcpy(dd2, dd, n * sizeof *dd);\n\t\td_ = min(d_, dd2[n - 1]);\n\t\tfor (h = 0; h < m; h++)\n\t\t\tif (tt[h] == 2 && dd2[ii[h]] != INF && reachable[jj[h]])\n\t\t\t\td_ = min(d_, d + dd2[ii[h]] - dd1[jj[h]]);\n\t\ty = d_ - d <= (X - x) / k ? x + (d_ - d) * k : X;\n\t\tfor (z = x; z <= y; z++)\n\t\t\tans[z] = d + (double) (z - x) / k;\n\t\tif (y < X) {\n\t\t\tfor (h = 0; h < m; h++)\n\t\t\t\tif (tt[h] == 1)\n\t\t\t\t\tww[h] += d_ - d, xx[h] += d_ - d;\n\t\t\t\telse if (tt[h] == 2)\n\t\t\t\t\tww[h] -= d_ - d, xx[h] -= d_ - d;\n\t\t}\n\t\tx = y;\n\t}\n\tscanf(\"%d\", &q);\n\twhile (q--) {\n\t\tscanf(\"%d\", &x);\n\t\tprintf(\"%f\\n\", ans[x]);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "90e49b9f5f234cf4c7db6e65d3bdf081", "src_uid": "b0751071e12f729f6700586c5a8eed23", "difficulty": 3100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t50\n#define M\t(N * (N - 1))\n#define N_\t(N + 2)\n#define M_\t(M * 3 + 2)\n#define X\t100000\n#define INF\t0x3f3f3f3f\n\nint min(int a, int b) { return a < b ? a : b; }\n\nint oo[1 + M], oh[1 + M], _ = 1;\n\nint link(int o, int h) {\n\too[_] = o, oh[_] = h;\n\treturn _++;\n}\n\nint oo_[1 + M_ * 2], oh_[1 + M_ * 2], __;\n\nint link_(int o, int h) {\n\too_[__] = o, oh_[__] = h;\n\treturn __++;\n}\n\nint ae[N], af[N], ae_[N_], dd[N_], n_;\nint ii[M], jj[M], ww[M]; char tt[M]; int ij[M_], cc[M_ * 2], m_;\nint pq[1 + N], iq[N], cnt;\n\nint less(int u, int v) { return dd[u] < dd[v]; }\n\nint i2(int i) {\n\treturn (i *= 2) > cnt ? 0 : i < cnt && less(pq[i + 1], pq[i]) ? i + 1 : i;\n}\n\nvoid pq_up(int u) {\n\tint i, j, v;\n\n\tfor (i = iq[u]; (j = i / 2) && less(u, v = pq[j]); i = j)\n\t\tpq[iq[v] = i] = v;\n\tpq[iq[u] = i] = u;\n}\n\nvoid pq_dn(int u) {\n\tint i, j, v;\n\n\tfor (i = iq[u]; (j = i2(i)) && less(v = pq[j], u); i = j)\n\t\tpq[iq[v] = i] = v;\n\tpq[iq[u] = i] = u;\n}\n\nvoid pq_add_last(int u) {\n\tpq[iq[u] = ++cnt] = u;\n}\n\nint pq_remove_first() {\n\tint u = pq[1], v = pq[cnt--];\n\n\tif (v != u)\n\t\tiq[v] = 1, pq_dn(v);\n\tiq[u] = 0;\n\treturn u;\n}\n\nvoid dijkstra(int n, int s) {\n\tmemset(dd, 0x3f, n * sizeof *dd);\n\tdd[s] = 0, pq_add_last(s);\n\twhile (cnt) {\n\t\tint i = pq_remove_first(), o;\n\n\t\tfor (o = ae[i]; o; o = oo[o]) {\n\t\t\tint h = oh[o];\n\n\t\t\tif (!tt[h]) {\n\t\t\t\tint j = jj[h], d = dd[i] + ww[h];\n\n\t\t\t\tif (dd[j] > d) {\n\t\t\t\t\tif (dd[j] == INF)\n\t\t\t\t\t\tpq_add_last(j);\n\t\t\t\t\tdd[j] = d, pq_up(j);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\n\nvoid link2(int i, int j, int c) {\n\tint h = m_++;\n\n\tij[h] = i ^ j, cc[h << 1] = c, cc[h << 1 | 1] = 0;\n\tae_[i] = link_(ae_[i], h << 1);\n\tae_[j] = link_(ae_[j], h << 1 | 1);\n}\n\nint bfs(int s, int t) {\n\tstatic int qu[N_];\n\tint i, head, cnt;\n\n\tfor (i = 0; i < n_; i++)\n\t\tdd[i] = n_;\n\thead = cnt = 0;\n\tdd[s] = 0, qu[head + cnt++] = s;\n\twhile (cnt) {\n\t\tint d, o;\n\n\t\ti = qu[cnt--, head++], d = dd[i] + 1;\n\t\tfor (o = ae_[i]; o; o = oo_[o]) {\n\t\t\tint h_ = oh_[o];\n\n\t\t\tif (cc[h_]) {\n\t\t\t\tint h = h_ >> 1, j = i ^ ij[h];\n\n\t\t\t\tif (dd[j] > d) {\n\t\t\t\t\tdd[j] = d;\n\t\t\t\t\tif (j == t)\n\t\t\t\t\t\treturn 1;\n\t\t\t\t\tqu[head + cnt++] = j;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\n\nint dfs(int i, int t) {\n\tint d, o;\n\n\tif (i == t)\n\t\treturn 1;\n\td = dd[i] + 1;\n\tfor (o = ae_[i]; o; o = oo_[o]) {\n\t\tint h_ = oh_[o];\n\n\t\tif (cc[h_]) {\n\t\t\tint h = h_ >> 1, j = i ^ ij[h];\n\n\t\t\tif (dd[j] == d && dfs(j, t)) {\n\t\t\t\tcc[h_]--, cc[h_ ^ 1]++;\n\t\t\t\treturn 1;\n\t\t\t}\n\t\t}\n\t}\n\tdd[i] = n_;\n\treturn 0;\n}\n\nvoid dinic(int s, int t) {\n\twhile (bfs(s, t))\n\t\twhile (dfs(s, t))\n\t\t\t;\n}\n\nchar reachable[N];\n\nvoid dfs_(int j) {\n\tint o;\n\n\tif (reachable[j])\n\t\treturn;\n\treachable[j] = 1;\n\tfor (o = af[j]; o; o = oo[o]) {\n\t\tint h = oh[o], i = ii[h];\n\n\t\tdfs_(i);\n\t}\n}\n\nint main() {\n\tstatic double ans[X + 1];\n\tstatic int dd1[N], dd2[N], xx[M];\n\tint n, m, q, h, x, s, t;\n\n\tscanf(\"%d%d\", &n, &m);\n\tfor (h = 0; h < m; h++) {\n\t\tint i, j, w;\n\n\t\tscanf(\"%d%d%d\", &i, &j, &w), i--, j--;\n\t\tii[h] = i, jj[h] = j, ww[h] = w;\n\t\tae[i] = link(ae[i], h);\n\t}\n\tn_ = n + 2, s = n, t = n + 1;\n\tx = 0;\n\twhile (x < X) {\n\t\tint k, y, z, d, d_;\n\n\t\tmemset(tt, 0, m * sizeof *tt);\n\t\tdijkstra(n, 0);\n\t\tmemcpy(dd1, dd, n * sizeof *dd);\n\t\td = dd1[n - 1];\n\t\tmemset(ae_, 0, n_ * sizeof *ae_), __ = 1, m_ = 0;\n\t\tlink2(s, 0, INF);\n\t\tlink2(n - 1, t, INF);\n\t\tfor (h = 0; h < m; h++) {\n\t\t\tint i = ii[h], j = jj[h], w = ww[h];\n\n\t\t\tif (dd1[i] + w == dd1[j]) {\n\t\t\t\ttt[h] = 1;\n\t\t\t\tlink2(s, j, 1), link2(i, t, 1);\n\t\t\t\tif (xx[h] == 0)\n\t\t\t\t\tlink2(j, i, INF);\n\t\t\t}\n\t\t}\n\t\tdinic(s, t);\n\t\td_ = INF;\n\t\tk = 0;\n\t\tmemset(af, 0, n * sizeof *af), _ = 1 + m;\n\t\tfor (h = 0; h < m; h++) {\n\t\t\tint i = ii[h], j = jj[h];\n\n\t\t\tif (tt[h]) {\n\t\t\t\tif ((dd[i] == n_) == (dd[j] == n_)) {\n\t\t\t\t\ttt[h] = 0;\n\t\t\t\t\taf[j] = link(af[j], h);\n\t\t\t\t} else if (dd[i] != n_) {\n\t\t\t\t\ttt[h] = 1;\n\t\t\t\t\tk++;\n\t\t\t\t} else {\n\t\t\t\t\ttt[h] = 2;\n\t\t\t\t\tk--;\n\t\t\t\t\td_ = min(d_, d + xx[h]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tmemset(reachable, 0, n * sizeof *reachable);\n\t\tdfs_(n - 1);\n\t\tdijkstra(n, 0);\n\t\tmemcpy(dd2, dd, n * sizeof *dd);\n\t\td_ = min(d_, dd2[n - 1]);\n\t\tfor (h = 0; h < m; h++)\n\t\t\tif (tt[h] == 2 && dd2[ii[h]] != INF && reachable[jj[h]])\n\t\t\t\td_ = min(d_, d + dd2[ii[h]] - dd1[jj[h]]);\n\t\ty = d_ - d <= (X - x) / k ? x + (d_ - d) * k : X;\n\t\tfor (z = x; z <= y; z++)\n\t\t\tans[z] = d + (double) (z - x) / k;\n\t\tif (y < X) {\n\t\t\tfor (h = 0; h < m; h++)\n\t\t\t\tif (tt[h] == 1)\n\t\t\t\t\tww[h] += d_ - d, xx[h] += d_ - d;\n\t\t\t\telse if (tt[h] == 2)\n\t\t\t\t\tww[h] -= d_ - d, xx[h] -= d_ - d;\n\t\t}\n\t\tx = y;\n\t}\n\tscanf(\"%d\", &q);\n\twhile (q--) {\n\t\tscanf(\"%d\", &x);\n\t\tprintf(\"%f\\n\", ans[x]);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "315be5afdf4b0abb2001aed75a2a5da7", "src_uid": "b0751071e12f729f6700586c5a8eed23", "difficulty": 3100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nchar s[11] = \"12345RGBYW\";\nint as(char c) {\n  int i;\n  for (i = 0; i < 10; i++)\n    if (c == s[i])\n      return i;\n}\nint main() {\n  char c[3];\n  int i, j, n, m, a[5] [10], b[10], d[11], k, r, min;\n  while (scanf(\"%d\", &n) != EOF) {\n    for (i = 0; i < 5; i++)\n      for (j = 5; j < 10; j++)\n        a[i][j] = 0;\n\n    getchar();\n    for (i = 0; i < n; i++) {\n      scanf(\"%s\", c);\n      a[as(c[1])][as(c[0])] = 1;\n    }\n    min = 10;\n    for (i = 0; i < 1024; i++) {\n      for (j = 0; j < 11; j++)\n        d[j] = 0;\n      m = 0;\n      for (j = 0; j < 10; j++)\n        if (b[j] = i >> j & 1)\n          m++;\n      for (k = 0; k < 5; k++)\n        for (j = 5; j < 10; j++)\n          if (a[k][j]) {\n            if (!b[k])\n              d[j]++;\n            if (!b[j])\n              d[k]++;\n              if(!b[k]&&!b[j])d[10]++;\n          }\n      r = 1;\n      for (j = 0; j < 11; j++)\n        if (d[j] > 1) {\n          r = 0;\n          break;\n        }\n      if (r)\n        min = min < m ? min : m;\n    }\n    printf(\"%d\\n\", min);\n  }\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fc7b757892dba4c050057537d4ae6965", "src_uid": "3b12863997b377b47bae43566ec1a63b", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <memory.h>\n\nint flag[5][5];\nint flag2[5][5];\nint mark[10];\nint ans ;\n\nint\ndfs(int depth){\n    int i,j,count,index;\n    if(depth ==0){\n        for(i=0;i<5;i++){\n            for(j=0;j<5;j++){\n                flag2[i][j] = flag[i][j];\n            }\n        }\n        \n        for(i=0;i<5;i++){\n            for(j=0;j<5;j++){\n                if(mark[i] && mark[j+5]){\n                    flag2[i][j]=0;\n                }\n            }\n        }\n        for(i=0 ;i<10 ;i++){\n            if(! mark[i] )\n                continue;\n            if ( i < 5){\n                count=0;\n                index=0;\n                for(j=0;j<5;j++){\n                    if(flag2[i][j]){\n                        count ++;\n                        index = j;\n                    }\n                }\n                if( count >1 ){\n                    return 0;\n                }\n                flag2[i][index]=0;\n            }\n            else {\n                count=0;\n                index =0;\n                for(j=0;j<5;j++){\n                    if(flag2[j][i-5]){\n                        count ++;\n                        index =j;\n                    }\n                }\n                if( count >1 ){\n                    return 0;\n                }\n                flag2[index][i-5]=0;\n            }\n        }\n        count =0 ;\n        for(i=0;i<5;i++){\n            for(j=0;j<5;j++){\n                if(flag2[i][j]){\n                    count++;\n                }\n            }\n        }\n        if(count ==1)\n            return 1;\n        else\n            return 0;\n    }\n    for(i=0;i<10;i++){\n        if(mark[i])\n            continue;\n        mark[i] = 1;\n        if(!dfs(depth-1))\n            mark[i] =0;\n        else\n            return 1;\n    }\n    return 0;\n}\n\nint\nmain(int argc,\n     char *argv[]){\n    int n;\n    while( scanf(\"%d\",&n) !=-1 ){\n        char card[2];\n        char color[5] ={'R','G','B','Y','W'};\n        int i,j;\n        memset(flag,0,sizeof(flag));\n        for(i=0;i<n;i++){\n            scanf(\"%s\",card);\n            for(j=0;j<5;j++){\n                if(card[0] == color [j]){\n                    flag[j][card[1]-'1'] ++;\n                }\n            }\n        }\n        /* if(n==4) { */\n        /*     for(i=0;i<5;i++){ */\n        /*         for(j=0;j<5;j++){ */\n        /*             printf(\"%d \", flag[i][j]); */\n        /*         } */\n        /*         printf(\"\\n\"); */\n        /*     } */\n        /* } */\n        for(i=0;i<=10;i++){\n            memset(mark,0,sizeof(mark));\n            if(dfs(i)) {\n                printf(\"%d\\n\",i);\n                break;\n            }\n        }\n    }\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cad6d0b8eaeef7d78c781ee839c99502", "src_uid": "3b12863997b377b47bae43566ec1a63b", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <memory.h>\n\nint flag[5][5];\nint flag2[5][5];\nint mark[10];\nint ans ;\n\nint\ndfs(int depth){\n    int i,j,count,index;\n    if(depth ==0){\n        for(i=0;i<5;i++){\n            for(j=0;j<5;j++){\n                flag2[i][j] = flag[i][j];\n            }\n        }\n        \n        for(i=0;i<5;i++){\n            for(j=0;j<5;j++){\n                if(mark[i] && mark[j+5]){\n                    flag2[i][j]=0;\n                }\n            }\n        }\n        for(i=0 ;i<10 ;i++){\n            if(! mark[i] )\n                continue;\n            if ( i < 5){\n                count=0;\n                index=0;\n                for(j=0;j<5;j++){\n                    if(flag2[i][j]){\n                        count ++;\n                        index = j;\n                    }\n                }\n                if( count >1 ){\n                    return 0;\n                }\n                flag2[i][index]=0;\n            }\n            else {\n                count=0;\n                index =0;\n                for(j=0;j<5;j++){\n                    if(flag2[j][i-5]){\n                        count ++;\n                        index =j;\n                    }\n                }\n                if( count >1 ){\n                    return 0;\n                }\n                flag2[index][i-5]=0;\n            }\n        }\n        count =0 ;\n        for(i=0;i<5;i++){\n            for(j=0;j<5;j++){\n                if(flag2[i][j]){\n                    count++;\n                }\n            }\n        }\n        if(count ==1)\n            return 1;\n        else\n            return 0;\n    }\n    for(i=0;i<10;i++){\n        if(mark[i])\n            continue;\n        mark[i] = 1;\n        if(!dfs(depth-1))\n            mark[i] =0;\n        else\n            return 1;\n    }\n    return 0;\n}\n\nint\nmain(int argc,\n     char *argv[]){\n    int n;\n    int testcase =0;\n    while( scanf(\"%d\",&n) !=-1 ){\n        testcase ++;\n        char card[2];\n        char color[5] ={'R','G','B','Y','W'};\n        int i,j;\n        memset(flag,0,sizeof(flag));\n        for(i=0;i<n;i++){\n            scanf(\"%s\",card);\n            for(j=0;j<5;j++){\n                if(card[0] == color [j]){\n                    flag[j][card[1]-'1'] ++;\n                }\n            }\n        }\n        if(testcase==0){\n            printf(\"0\\n\");\n            continue ;\n        }\n        /* if(n==4) { */\n        /*     for(i=0;i<5;i++){ */\n        /*         for(j=0;j<5;j++){ */\n        /*             printf(\"%d \", flag[i][j]); */\n        /*         } */\n        /*         printf(\"\\n\"); */\n        /*     } */\n        /* } */\n        for(i=0;i<=10;i++){\n            memset(mark,0,sizeof(mark));\n            if(dfs(i)) {\n                printf(\"%d\\n\",i);\n                break;\n            }\n        }\n    }\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "589548d703b6e9f4b855e2a169679c98", "src_uid": "3b12863997b377b47bae43566ec1a63b", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <memory.h>\n\nint flag[5][5];\nint flag2[5][5];\nint mark[10];\nint ans ;\n\nint\ndfs(int depth){\n    int i,j,count,index;\n    if(depth ==0){\n        for(i=0;i<5;i++){\n            for(j=0;j<5;j++){\n                flag2[i][j] = flag[i][j];\n            }\n        }\n        \n        for(i=0;i<5;i++){\n            for(j=0;j<5;j++){\n                if(mark[i] && mark[j+5]){\n                    flag2[i][j]=0;\n                }\n            }\n        }\n        for(i=0 ;i<10 ;i++){\n            if(! mark[i] )\n                continue;\n            if ( i < 5){\n                count=0;\n                index=0;\n                for(j=0;j<5;j++){\n                    if(flag2[i][j]){\n                        count ++;\n                        index = j;\n                    }\n                }\n                if( count >1 ){\n                    return 0;\n                }\n                flag2[i][index]=0;\n            }\n            else {\n                count=0;\n                index =0;\n                for(j=0;j<5;j++){\n                    if(flag2[j][i-5]){\n                        count ++;\n                        index =j;\n                    }\n                }\n                if( count >1 ){\n                    return 0;\n                }\n                flag2[index][i-5]=0;\n            }\n        }\n        count =0 ;\n        for(i=0;i<5;i++){\n            for(j=0;j<5;j++){\n                if(flag2[i][j]){\n                    count++;\n                }\n            }\n        }\n        if(count ==1)\n            return 1;\n        else\n            return 0;\n    }\n    for(i=0;i<10;i++){\n        if(mark[i])\n            continue;\n        mark[i] = 1;\n        if(!dfs(depth-1))\n            mark[i] =0;\n        else\n            return 1;\n    }\n    return 0;\n}\n\nint\nmain(int argc,\n     char *argv[]){\n    int n;\n    int testcase =0;\n    while( scanf(\"%d\",&n) !=EOF ){\n        testcase ++;\n        char card[2];\n        char color[5] ={'R','G','B','Y','W'};\n        int i,j;\n        memset(flag,0,sizeof(flag));\n        for(i=0;i<n;i++){\n            scanf(\"%s\",card);\n            for(j=0;j<5;j++){\n                if(card[0] == color [j]){\n                    flag[j][card[1]-'1'] ++;\n                }\n            }\n        }\n        if(testcase==0){\n            printf(\"0\\n\");\n            continue ;\n        }\n        /* if(n==4) { */\n        /*     for(i=0;i<5;i++){ */\n        /*         for(j=0;j<5;j++){ */\n        /*             printf(\"%d \", flag[i][j]); */\n        /*         } */\n        /*         printf(\"\\n\"); */\n        /*     } */\n        /* } */\n        for(i=0;i<=10;i++){\n            memset(mark,0,sizeof(mark));\n            if(dfs(i)) {\n                printf(\"%d\\n\",i);\n                break;\n            }\n        }\n    }\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "74f9070647d0426522f26257dec178fb", "src_uid": "3b12863997b377b47bae43566ec1a63b", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <memory.h>\n\nint flag[5][5];\nint flag2[5][5];\nint mark[10];\nint ans ;\n\nint\ndfs(int depth){\n    if(depth ==0){\n\n        for(int i=0;i<5;i++){\n            for(int j=0;j<5;j++){\n                flag2[i][j] = flag[i][j];\n            }\n        }\n        \n        for(int i=0;i<5;i++){\n            for(int j=0;j<5;j++){\n                if(mark[i] && mark[j+5]){\n                    flag2[i][j]=0;\n                }\n            }\n        }\n        for(int i=0 ;i<10 ;i++){\n            if(! mark[i] )\n                continue;\n            if ( i < 5){\n                int count=0;\n                int index=0;\n                for(int j=0;j<5;j++){\n                    if(flag2[i][j]){\n                        count ++;\n                        index = j;\n                    }\n                }\n                if( count >1 ){\n                    return 0;\n                }\n                flag2[i][index]=0;\n            }\n            else {\n                int count=0;\n                int index =0;\n                for(int j=0;j<5;j++){\n                    if(flag2[j][i-5]){\n                        count ++;\n                        index =j;\n                    }\n                }\n                if( count >1 ){\n                    return 0;\n                }\n                flag2[index][i-5]=0;\n            }\n        }\n        int count =0 ;\n        for(int i=0;i<5;i++){\n            for(int j=0;j<5;j++){\n                if(flag2[i][j]){\n                    count++;\n                }\n            }\n        }\n        if(count ==1)\n            return 1;\n        else\n            return 0;\n    }\n    for(int i=0;i<10;i++){\n        if(mark[i])\n            continue;\n        mark[i] = 1;\n        if(!dfs(depth-1))\n            mark[i] =0;\n        else\n            return 1;\n    }\n    return 0;\n}\n\nint\nmain(int argc,\n     char *argv[]){\n    int n;\n    scanf(\"%d\",&n);\n    char card[2];\n    char color[5] ={'R','G','B','Y','W'};\n    memset(flag,0,sizeof(flag));\n    for(int i=0;i<n;i++){\n        scanf(\"%s\",card);\n        for(int j=0;j<5;j++){\n            if(card[0] == color [j]){\n                flag[j][card[1]-'1'] ++;\n            }\n        }\n    }\n    for(int i=0;i<=10;i++){\n        memset(mark,0,sizeof(mark));\n        if(dfs(i)) {\n            printf(\"%d\\n\",i);\n            break;\n        }\n    }\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5e76eabe53600ee43eeac9d6a904a595", "src_uid": "3b12863997b377b47bae43566ec1a63b", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define K\t50\n\nint main() {\n\tint q;\n\n\tscanf(\"%d\", &q);\n\twhile (q--) {\n\t\tstatic long long aa[K];\n\t\tlong long a, b, m, lower, upper, x;\n\t\tint i, j, k, good;\n\n\t\tscanf(\"%lld%lld%lld\", &a, &b, &m);\n\t\tif (a == b) {\n\t\t\tprintf(\"1 %lld\\n\", a);\n\t\t\tcontinue;\n\t\t}\n\t\tgood = 0;\n\t\tfor (k = 2; k <= K; k++) {\n\t\t\tlower = (a << (k - 2)) + (1 << (k - 2)) - 1 + 1;\n\t\t\tif (lower > b)\n\t\t\t\tbreak;\n\t\t\tupper = (a << (k - 2)) + m * ((1 << (k - 2)) - 1) + m;\n\t\t\tif (b <= upper) {\n\t\t\t\tgood = 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (!good) {\n\t\t\tprintf(\"-1\\n\");\n\t\t\tcontinue;\n\t\t}\n\t\tb -= lower;\n\t\tprintf(\"%d %lld\", k, aa[0] = a);\n\t\tfor (j = 1; j < k; j++) {\n\t\t\ta = 1 << (j == k - 1 ? 0 : k - 2 - j);\n\t\t\tx = 1 + b / a;\n\t\t\tif (x > m)\n\t\t\t\tx = m;\n\t\t\tb -= (x - 1) * a;\n\t\t\tfor (i = 0; i < j; i++)\n\t\t\t\tx += aa[i];\n\t\t\tprintf(\" %lld\", aa[j] = x);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "06fec672a6a4b56331be5b2acd06af7f", "src_uid": "c9d646762e2e78064bc0670ec7c173c6", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define K\t50\n\nint main() {\n\tint q;\n\n\tscanf(\"%d\", &q);\n\twhile (q--) {\n\t\tstatic long long aa[K];\n\t\tlong long a, b, m, lower, upper, x;\n\t\tint i, j, k, good;\n\n\t\tscanf(\"%lld%lld%lld\", &a, &b, &m);\n\t\tgood = 0;\n\t\tfor (k = 2; k <= K; k++) {\n\t\t\tlower = (a << (k - 2)) + (1 << (k - 2)) - 1 + 1;\n\t\t\tif (lower > b)\n\t\t\t\tbreak;\n\t\t\tupper = (a << (k - 2)) + m * ((1 << (k - 2)) - 1) + m;\n\t\t\tif (b <= upper) {\n\t\t\t\tgood = 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (!good) {\n\t\t\tprintf(\"-1\\n\");\n\t\t\tcontinue;\n\t\t}\n\t\tb -= lower;\n\t\tprintf(\"%d %lld\", k, aa[0] = a);\n\t\tfor (j = 1; j < k; j++) {\n\t\t\ta = 1 << (j == k - 1 ? 0 : k - 2 - j);\n\t\t\tx = 1 + b / a;\n\t\t\tif (x > m)\n\t\t\t\tx = m;\n\t\t\tb -= (x - 1) * a;\n\t\t\tfor (i = 0; i < j; i++)\n\t\t\t\tx += aa[i];\n\t\t\tprintf(\" %lld\", aa[j] = x);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2c7df8ea1d66825ac34b103f24b8f413", "src_uid": "c9d646762e2e78064bc0670ec7c173c6", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main(){\n    int q;\n    scanf(\"%d\",&q);\n    while(q--){\n        long long int a,b,m;\n        scanf(\"%lld %lld %lld\",&a,&b,&m);\n        long long int k=1;\n        if(a==b)\n            printf(\"%lld %lld\\n\",k,a);\n        else{\n            long long int c=a+1;\n            //double n;\n            k = log2((b*1.0)/c) + 1;\n            //printf(\"%lld\\n\", k);\n            long long int d=c*pow(2,k-1);\n            /*if(b!=d){\n                k++;\n                d=d*2;\n            }*/\n            //printf(\"%lld\",k+1);\n            c=a+m;\n            long long int s=c*pow(2,k-1);\n            if((k+1)>=50 || s<b){\n                printf(\"-1\\n\");\n            }\n            else{\n                if(k==1){\n                    printf(\"%lld %lld %lld\\n\",(k+1),a,b);\n                }\n                else{\n                    m--;\n                    long long int r[k+1];\n                    long long int diff = b-d;\n                    //printf(\"%lld\\n\",diff);\n                    long long int j=k;\n                    for(long long int i=1;i<k;i++){\n                        long long int f=diff/pow(2,(j-2));\n                        if(f>m)\n                            f=m;\n                        diff = diff - f*pow(2,(j-2));\n                        r[i] = f + 1;\n                        j--;\n                    }\n                    r[k] = diff + 1;\n                    printf(\"%lld %lld \",(k+1),a);\n                    long long int sum=a;\n                    for(long long int i=1;i<=k;i++){\n                        long long int temp = sum + r[i];\n                        printf(\"%lld \",temp);\n                        //printf(\"%lld \",r[i]);\n                        sum = sum + temp;\n                    }\n                    printf(\"\\n\");\n                }\n            }\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a7f8343a72b9db4662a15b745336927a", "src_uid": "c9d646762e2e78064bc0670ec7c173c6", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint main(){\n    long long int q;\n    scanf(\"%lld\",&q);\n    while(q--){\n        long long int a,b,m;\n        scanf(\"%lld %lld %lld\",&a,&b,&m);\n        long long int k=1;\n        if(a==b)\n            printf(\"%lld %lld\\n\",k,a);\n        else{\n            long long int c=a+1;\n            k = log2((b*1.0)/c) + 1;\n            //printf(\"%lld\\n\",k);\n            long long int s=c*pow(2,k-1);\n            if(k==1){\n                if((b-a)>m)\n                    printf(\"-1\\n\");\n                else\n                    printf(\"%lld %lld %lld\\n\",(k+1),a,b);\n            }\n            else{\n                m--;\n                long long int r[k+2];\n                for(long long int i=0;i<(k+2);i++)\n                    r[i]=0;\n                long long int diff = b-s;\n                //printf(\"%lld\\n\",diff);\n                long long int j=k;\n                for(long long int i=1;i<k;i++){\n                    long long int f=diff/pow(2,(j-2));\n                    if(f>m)\n                        f=m;\n                    diff = diff - f*pow(2,(j-2));\n                    r[i] = f + 1;\n                    j--;\n                }\n                r[k] = diff + 1;\n                if(r[k]>(m+1)){\n                    printf(\"-1\\n\");\n                    continue;\n                }\n                printf(\"%lld %lld \",(k+1),a);\n                long long int sum=a;\n                for(long long int i=1;i<=k;i++){\n                    long long int temp = sum + r[i];\n                    printf(\"%lld \",temp);\n                    //printf(\"%lld \",r[i]);\n                    sum = sum + temp;\n                }\n                printf(\"\\n\");\n            }\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4583699e99686313d2b99f1b30049fab", "src_uid": "c9d646762e2e78064bc0670ec7c173c6", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define K\t50\n\nint main() {\n\tint q;\n\n\tscanf(\"%d\", &q);\n\twhile (q--) {\n\t\tstatic long long aa[K];\n\t\tlong long a, b, m, lower, upper, x;\n\t\tint i, j, k, good;\n\n\t\tscanf(\"%lld%lld%lld\", &a, &b, &m);\n\t\tif (a == b) {\n\t\t\tprintf(\"1 %lld\\n\", a);\n\t\t\tcontinue;\n\t\t}\n\t\tgood = 0;\n\t\tfor (k = 2; k <= K; k++) {\n\t\t\tlower = (a << (k - 2)) + (1LL << (k - 2)) - 1 + 1;\n\t\t\tif (lower > b)\n\t\t\t\tbreak;\n\t\t\tupper = (a << (k - 2)) + m * ((1LL << (k - 2)) - 1) + m;\n\t\t\tif (b <= upper) {\n\t\t\t\tgood = 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (!good) {\n\t\t\tprintf(\"-1\\n\");\n\t\t\tcontinue;\n\t\t}\n\t\tb -= lower;\n\t\tprintf(\"%d %lld\", k, aa[0] = a);\n\t\tfor (j = 1; j < k; j++) {\n\t\t\ta = 1LL << (j == k - 1 ? 0 : k - 2 - j);\n\t\t\tx = 1 + b / a;\n\t\t\tif (x > m)\n\t\t\t\tx = m;\n\t\t\tb -= (x - 1) * a;\n\t\t\tfor (i = 0; i < j; i++)\n\t\t\t\tx += aa[i];\n\t\t\tprintf(\" %lld\", aa[j] = x);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "64986414bd0d352cd5c3b0cebf36c887", "src_uid": "c9d646762e2e78064bc0670ec7c173c6", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\n\n#define N 100000\n#define EPS 1E-6\n\nint sign(double x) { \n  return x < -EPS ? -1 : x > EPS; \n}\n\ndouble sqr(double x) { \n  return x * x; \n}\n\ntypedef struct point {\n  double x, y;\n} point;\n\ndouble dist(point a, point b) {\n  return hypot(a.x - b.x, a.y - b.y);\n}\n\ndouble cross(point a, point b, point c) {\n  return (b.x - a.x) * (c.y - b.y) - (b.y - a.y) * (c.x - b.x);\n}\n\n/* PA * PB */\ndouble dot(point p, point a, point b) {\n  return (a.x - p.x) * (b.x - p.x) + (a.y - p.y) * (b.y - p.y);\n}\n\n/* delta angle of ABC */\ndouble delta_angle(point a, point b, point c) {\n  return acos(dot(b, a, c) / (dist(a, b) * dist(b, c)));\n}\n\npoint *__o;\n\nint angle_cmp(point *p, point *q) {\n  int c;\n  if (c = sign(cross(*__o, *p, *q)))\n    return -c;\n  return sign(dist(*p, *__o) - dist(*q, *__o));\n}\n\npoint stack[N];\n\nint convex_hull(point *ps, int n) {\n  int i, k, top;\n  point q;\n\n  k = 0;\n  for (i = 1; i < n; i++)\n    if (sign(ps[i].y - ps[k].y) < 0 || sign(ps[i].y - ps[k].y) == 0 && ps[i].x < ps[k].x)\n      k = i;\n\n  q = ps[k];\n  ps[k] = ps[0];\n  ps[0] = q;\n\n  __o = &ps[0];\n  qsort(ps + 1, n - 1, sizeof(point), (int (*)(const void *, const void *))angle_cmp);\n\n  top = 0;\n  for (i = 0; i < n; i++) {\n//    printf(\"%lf,%lf\\n\", ps[i].x, ps[i].y);\n    while (top >= 2 && sign(cross(stack[top - 2], stack[top - 1], ps[i])) <= 0) top--;\n    stack[top++] = ps[i];\n  }\n  memcpy(ps, stack, sizeof(point) * top);\n  return top;\n}\n\ndouble cccr(point A, point B, point C) {\n  double a, b, c, cos_B, sin_B, R;\n\n  a = dist(B, C);\n  b = dist(A, C);\n  c = dist(A, B);\n  cos_B = (a * a + c * c - b * b) / (2 * a * c);\n  sin_B = sqrt(1.0 - cos_B * cos_B);\n  return b / sin_B / 2.0;\n}\n\nint too_straight(point A, point B, point C, double r) {\n//  printf(\"R=%lf vs r=%lf\\n\", R, r);\n  return sign(dot(B, A, C)) < 0 && sign(cccr(A, B, C) - r) > 0;\n}\n\ndouble area_bow(double r, double l) {\n  double tri = l * sqrt(sqr(r) - sqr(l / 2)) / 2;\n  double theta = 2 * asin(l / (r + r));\n  double sector = theta * r * r / 2;\n  return sector - tri;\n}\n\ndouble area_polygon(const point a[], int n) {\n  int i, j;\n  double area = 0.0;\n  for (j = 0, i = n - 1; j < n; i = j++)\n    area += a[i].x * a[j].y - a[i].y * a[j].x;\n  return fabs(area) / 2;\n}\n\nvoid die() {\n  *(char *)NULL = 0;\n}\n\nint main() {\n  static point ps[N];\n  int n;\n  double r;\n  double ans, R, Rmin;\n  int i, j, k, z, top, s, ch;\n\n  scanf(\"%d %lf\", &n, &r);\n  for (i = 0; i < n; i++)\n    scanf(\"%lf %lf\", &ps[i].x, &ps[i].y);\n\n  if (n == 1) {\n    puts(\"0\");\n  } else if (n == 2) {\n    ans = area_bow(r, dist(ps[0], ps[1])) * 2.0;\n    printf(\"%.9lf\\n\", ans);\n  } else {\n    n = convex_hull(ps, n);\n//    printf(\"n=%d\\n\", n);\n\n    top = 0;\n    for (i = 0; i < n; i++) {\n      while (top >= 2 && too_straight(stack[top - 2], stack[top - 1], ps[i], r))\n        top--;\n      stack[top++] = ps[i];\n    }\n\n    s = 0;\n    ch = 1;\n    while (ch) {\n      ch = 0;\n      while (top - s >= 3 && too_straight(stack[top - 2], stack[top - 1], stack[s], r))\n        top--, ch = 1;\n      while (top - s >= 3 && too_straight(stack[top - 1], stack[s], stack[s + 1], r))\n        s++, ch = 1;\n    }\n    memcpy(stack, stack + s, sizeof(stack[0]) * (top -= s));\n//    printf(\"top=%d\\n\", top);\n\n    ans = area_polygon(stack, top);\n    for (i = 0, j = 1 % top; i < top; i++, j = (j + 1) % top) {\n//      printf(\"%lf,%lf\\n\", stack[i].x, stack[i].y);\n      ans += area_bow(r, dist(stack[i], stack[j]));\n    }\n    printf(\"%.9lf\\n\", ans);\n\n    if (top >= 3)\n      for (i = 0, j = 1 % top, k = 2 % top; i < top; i++, j = (j + 1) % top, k = (k + 1) % top)\n        if (too_straight(stack[i], stack[j], stack[k], r))\n          die();\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7fbdadef611a38c822761f6fc4c616f9", "src_uid": "5f2a0960bab9bdc91b190ed07d6adcf7", "difficulty": 3000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\n\n#define N 100000\n#define EPS 1E-6\n\nint sign(double x) { \n  return x < -EPS ? -1 : x > EPS; \n}\n\ndouble sqr(double x) { \n  return x * x; \n}\n\ntypedef struct point {\n  double x, y;\n} point;\n\ndouble dist(const point *a, const point *b) {\n  return hypot(a->x - b->x, a->y - b->y);\n}\n\ndouble cross(const point *a, const point *b, const point *c) {\n  return (b->x - a->x) * (c->y - b->y) - (b->y - a->y) * (c->x - b->x);\n}\n\n/* PA * PB */\ndouble dot(const point *p, const point *a, const point *b) {\n  return (a->x - p->x) * (b->x - p->x) + (a->y - p->y) * (b->y - p->y);\n}\n\nconst point *__o;\n\nint angle_cmp(const point *p, const point *q) {\n  int c;\n  if (c = sign(cross(__o, p, q)))\n    return -c;\n  return sign(dist(p, __o) - dist(q, __o));\n}\n\npoint stack[N];\n\nint convex_hull(point ps[], int n) {\n  int i, k, top;\n  point q;\n\n  k = 0;\n  for (i = 1; i < n; i++)\n    if (sign(ps[i].y - ps[k].y) < 0 || sign(ps[i].y - ps[k].y) == 0 && ps[i].x < ps[k].x)\n      k = i;\n\n  q = ps[k];\n  ps[k] = ps[0];\n  ps[0] = q;\n\n  __o = &ps[0];\n  qsort(ps + 1, n - 1, sizeof(point), (int (*)(const void *, const void *))angle_cmp);\n\n  top = 0;\n  for (i = 0; i < n; i++) {\n    while (top >= 2 && sign(cross(&stack[top - 2], &stack[top - 1], &ps[i])) <= 0) top--;\n    stack[top++] = ps[i];\n  }\n  memcpy(ps, stack, sizeof(point) * top);\n  return top;\n}\n\ndouble cccr(const point *A, const point *B, const point *C) {\n  double a, b, c, cos_B, sin_B, R;\n\n  a = dist(B, C);\n  b = dist(A, C);\n  c = dist(A, B);\n  cos_B = (a * a + c * c - b * b) / (2 * a * c);\n  sin_B = sqrt(1.0 - cos_B * cos_B);\n  return b / sin_B / 2.0;\n}\n\nint too_straight(const point *A, const point *B, const point *C, double r) {\n  return sign(dot(B, A, C)) < 0 && sign(cccr(A, B, C) - r) > 0;\n}\n\ndouble area_bow(double r, double l) {\n  double tri = l * sqrt(sqr(r) - sqr(l / 2)) / 2;\n  double theta = 2 * asin(l / (r + r));\n  double sector = theta * r * r / 2;\n  return sector - tri;\n}\n\ndouble area_polygon(const point a[], int n) {\n  int i, j;\n  double area = 0.0;\n  for (j = 0, i = n - 1; j < n; i = j++)\n    area += a[i].x * a[j].y - a[i].y * a[j].x;\n  return fabs(area) / 2;\n}\n\nint main() {\n  static point ps[N];\n  int n;\n  double r;\n  double ans, R, Rmin;\n  int i, j, k, z, top, s, ch;\n\n  scanf(\"%d %lf\", &n, &r);\n  for (i = 0; i < n; i++)\n    scanf(\"%lf %lf\", &ps[i].x, &ps[i].y);\n\n  if (n == 1) {\n    puts(\"0\");\n  } else if (n == 2) {\n    ans = area_bow(r, dist(&ps[0], &ps[1])) * 2.0;\n    printf(\"%.9lf\\n\", ans);\n  } else {\n    n = convex_hull(ps, n);\n\n    top = 0;\n    for (i = 0; i < n; i++) {\n      while (top >= 2 && too_straight(&stack[top - 2], &stack[top - 1], &ps[i], r))\n        top--;\n      stack[top++] = ps[i];\n    }\n\n    s = 0;\n    ch = 1;\n    while (ch) {\n      ch = 0;\n      while (top - s >= 3 && too_straight(&stack[top - 2], &stack[top - 1], &stack[s], r))\n        top--, ch = 1;\n      while (top - s >= 3 && too_straight(&stack[top - 1], &stack[s], &stack[s + 1], r))\n        s++, ch = 1;\n    }\n    memcpy(stack, stack + s, sizeof(stack[0]) * (top -= s));\n\n    ans = area_polygon(stack, top);\n    for (i = 0, j = 1 % top; i < top; i++, j = (j + 1) % top)\n      ans += area_bow(r, dist(&stack[i], &stack[j]));\n    printf(\"%.9lf\\n\", ans);\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f7d37d2ad779a9a7fe20344edd8418d0", "src_uid": "5f2a0960bab9bdc91b190ed07d6adcf7", "difficulty": 3000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\n\n#define N 100000\n#define EPS 1E-6\n\nint sign(double x) { \n  return x < -EPS ? -1 : x > EPS; \n}\n\ndouble sqr(double x) { \n  return x * x; \n}\n\ntypedef struct point {\n  double x, y;\n} point;\n\ndouble dist(point a, point b) {\n  return hypot(a.x - b.x, a.y - b.y);\n}\n\ndouble cross(point a, point b, point c) {\n  return (b.x - a.x) * (c.y - b.y) - (b.y - a.y) * (c.x - b.x);\n}\n\n/* PA * PB */\ndouble dot(point p, point a, point b) {\n  return (a.x - p.x) * (b.x - p.x) + (a.y - p.y) * (b.y - p.y);\n}\n\n/* delta angle of ABC */\ndouble delta_angle(point a, point b, point c) {\n  return acos(dot(b, a, c) / (dist(a, b) * dist(b, c)));\n}\n\npoint *__o;\n\nint angle_cmp(point *p, point *q) {\n  int c;\n  if (c = sign(cross(*__o, *p, *q)))\n    return -c;\n  return sign(dist(*p, *__o) - dist(*q, *__o));\n}\n\npoint stack[N];\n\nint convex_hull(point *ps, int n) {\n  int i, k, top;\n  point q;\n\n  k = 0;\n  for (i = 1; i < n; i++)\n    if (sign(ps[i].y - ps[k].y) < 0 || sign(ps[i].y - ps[k].y) == 0 && ps[i].x < ps[k].x)\n      k = i;\n\n  q = ps[k];\n  ps[k] = ps[0];\n  ps[0] = q;\n\n  __o = &ps[0];\n  qsort(ps + 1, n - 1, sizeof(point), (int (*)(const void *, const void *))angle_cmp);\n\n  top = 0;\n  for (i = 0; i < n; i++) {\n//    printf(\"%lf,%lf\\n\", ps[i].x, ps[i].y);\n    while (top >= 2 && sign(cross(stack[top - 2], stack[top - 1], ps[i])) <= 0) top--;\n    stack[top++] = ps[i];\n  }\n  memcpy(ps, stack, sizeof(point) * top);\n  return top;\n}\n\ndouble cccr(point A, point B, point C) {\n  double a, b, c, cos_B, sin_B, R;\n\n  a = dist(B, C);\n  b = dist(A, C);\n  c = dist(A, B);\n  cos_B = (a * a + c * c - b * b) / (2 * a * c);\n  sin_B = sqrt(1.0 - cos_B * cos_B);\n  return b / sin_B / 2.0;\n}\n\nint too_straight(point A, point B, point C, double r) {\n//  printf(\"R=%lf vs r=%lf\\n\", R, r);\n  return sign(dot(B, A, C)) < 0 && sign(cccr(A, B, C) - r) > 0;\n}\n\ndouble area_bow(double r, double l) {\n  double tri = l * sqrt(sqr(r) - sqr(l / 2)) / 2;\n  double theta = 2 * asin(l / (r + r));\n  double sector = theta * r * r / 2;\n  return sector - tri;\n}\n\ndouble area_polygon(const point a[], int n) {\n  int i, j;\n  double area = 0.0;\n  for (j = 0, i = n - 1; j < n; i = j++)\n    area += a[i].x * a[j].y - a[i].y * a[j].x;\n  return fabs(area) / 2;\n}\n\nvoid die() {\n  *(char *)NULL = 0;\n}\n\nint main() {\n  static point ps[N];\n  int n;\n  double r;\n  double ans, R, Rmin;\n  int i, j, k, z, top, s, ch;\n\n  scanf(\"%d %lf\", &n, &r);\n  for (i = 0; i < n; i++)\n    scanf(\"%lf %lf\", &ps[i].x, &ps[i].y);\n\n  if (n == 1) {\n    puts(\"0\");\n  } else if (n == 2) {\n    ans = area_bow(r, dist(ps[0], ps[1])) * 2.0;\n    printf(\"%.9lf\\n\", ans);\n  } else {\n    n = convex_hull(ps, n);\n//    printf(\"n=%d\\n\", n);\n\n    top = 0;\n    for (i = 0; i < n; i++) {\n      while (top >= 2 && too_straight(stack[top - 2], stack[top - 1], ps[i], r))\n        top--;\n      stack[top++] = ps[i];\n    }\n\n    s = 0;\n    ch = 1;\n    while (ch) {\n      ch = 0;\n      while (top - s >= 3 && too_straight(stack[top - 2], stack[top - 1], stack[s], r))\n        top--, ch = 1;\n      while (top - s >= 3 && too_straight(stack[top - 1], stack[s], stack[s + 1], r))\n        s++, ch = 1;\n    }\n    memcpy(stack, stack + s, sizeof(stack[0]) * (top -= s));\n//    printf(\"top=%d\\n\", top);\n\n    ans = area_polygon(stack, top);\n    for (i = 0, j = 1 % top; i < top; i++, j = (j + 1) % top) {\n//      printf(\"%lf,%lf\\n\", stack[i].x, stack[i].y);\n      ans += area_bow(r, dist(stack[i], stack[j]));\n    }\n    printf(\"%.9lf\\n\", ans);\n\n    if (top >= 3)\n      for (i = 0, j = 1 % top, k = 2 % top; i < top; i++, j = (j + 1) % top, k = (k + 1) % top)\n        if (too_straight(stack[i], stack[j], stack[k], r))\n          die();\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "23eaaac23588719a91455e79ee4b5c00", "src_uid": "5f2a0960bab9bdc91b190ed07d6adcf7", "difficulty": 3000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\n\n#define N 100000\n#define EPS 1E-6\n\nint sign(double x) { \n  return x < -EPS ? -1 : x > EPS; \n}\n\ndouble sqr(double x) { \n  return x * x; \n}\n\ntypedef struct point {\n  double x, y;\n} point;\n\ndouble dist(const point *a, const point *b) {\n  return hypot(a->x - b->x, a->y - b->y);\n}\n\ndouble cross(const point *a, const point *b, const point *c) {\n  return (b->x - a->x) * (c->y - b->y) - (b->y - a->y) * (c->x - b->x);\n}\n\n/* PA * PB */\ndouble dot(const point *p, const point *a, const point *b) {\n  return (a->x - p->x) * (b->x - p->x) + (a->y - p->y) * (b->y - p->y);\n}\n\nconst point *__o;\n\nint angle_cmp(const point *p, const point *q) {\n  int c;\n  if (c = sign(cross(__o, p, q)))\n    return -c;\n  return sign(dist(p, __o) - dist(q, __o));\n}\n\nint convex_hull(point ps[], int n) {\n  static point stack[N];\n  int i, k, top;\n  point q;\n\n  k = 0;\n  for (i = 1; i < n; i++)\n    if (sign(ps[i].y - ps[k].y) < 0 || sign(ps[i].y - ps[k].y) == 0 && ps[i].x < ps[k].x)\n      k = i;\n\n  q = ps[k];\n  ps[k] = ps[0];\n  ps[0] = q;\n\n  __o = &ps[0];\n  qsort(ps + 1, n - 1, sizeof(ps[0]), (int (*)(const void *, const void *))angle_cmp);\n\n  top = 0;\n  for (i = 0; i < n; i++) {\n    while (top >= 2 && sign(cross(&stack[top - 2], &stack[top - 1], &ps[i])) <= 0) top--;\n    stack[top++] = ps[i];\n  }\n  memcpy(ps, stack, sizeof(point) * top);\n  return top;\n}\n\ndouble cccr(const point *A, const point *B, const point *C) {\n  double a, b, c, cos_B, sin_B, R;\n\n  a = dist(B, C);\n  b = dist(A, C);\n  c = dist(A, B);\n  cos_B = (a * a + c * c - b * b) / (2 * a * c);\n  sin_B = sqrt(1.0 - cos_B * cos_B);\n  return b / sin_B / 2.0;\n}\n\nint too_straight(const point *A, const point *B, const point *C, double r) {\n  return sign(dot(B, A, C)) < 0 && sign(cccr(A, B, C) - r) > 0;\n}\n\ndouble area_bow(double r, double l) {\n  double tri = l * sqrt(sqr(r) - sqr(l / 2)) / 2;\n  double theta = 2 * asin(l / (r + r));\n  double sector = theta * r * r / 2;\n  return sector - tri;\n}\n\ndouble area_polygon(point **a, int n) {\n  int i, j;\n  double area = 0.0;\n  for (j = 0, i = n - 1; j < n; i = j++)\n    area += a[i]->x * a[j]->y - a[i]->y * a[j]->x;\n  return fabs(area) / 2;\n}\n\nint main() {\n  static point ps[N];\n  static point *stack[N];\n  int n;\n  double r;\n  double ans, R, Rmin;\n  int i, j, k, z, top, s, ch;\n\n  scanf(\"%d %lf\", &n, &r);\n  for (i = 0; i < n; i++)\n    scanf(\"%lf %lf\", &ps[i].x, &ps[i].y);\n\n  if (n == 1) {\n    puts(\"0\");\n  } else if (n == 2) {\n    ans = area_bow(r, dist(&ps[0], &ps[1])) * 2.0;\n    printf(\"%.9lf\\n\", ans);\n  } else {\n    n = convex_hull(ps, n);\n\n    top = 0;\n    for (i = 0; i < n; i++) {\n      while (top >= 2 && too_straight(stack[top - 2], stack[top - 1], &ps[i], r))\n        top--;\n      stack[top++] = &ps[i];\n    }\n\n    s = 0;\n    ch = 1;\n    while (ch) {\n      ch = 0;\n      while (top - s >= 3 && too_straight(stack[top - 2], stack[top - 1], stack[s], r))\n        top--, ch = 1;\n      while (top - s >= 3 && too_straight(stack[top - 1], stack[s], stack[s + 1], r))\n        s++, ch = 1;\n    }\n    memcpy(stack, stack + s, sizeof(stack[0]) * (top -= s));\n\n    ans = area_polygon(stack, top);\n    for (i = 0, j = 1 % top; i < top; i++, j = (j + 1) % top)\n      ans += area_bow(r, dist(stack[i], stack[j]));\n    printf(\"%.9lf\\n\", ans);\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "856fb38ba6bb572ac4a8c3e5b2b9e384", "src_uid": "5f2a0960bab9bdc91b190ed07d6adcf7", "difficulty": 3000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\n\n#define N 100000\n#define EPS 1E-6\n\nint sign(double x) { \n  return x < -EPS ? -1 : x > EPS; \n}\n\ndouble sqr(double x) { \n  return x * x; \n}\n\ntypedef struct point {\n  double x, y;\n} point;\n\ndouble dist(point a, point b) {\n  return hypot(a.x - b.x, a.y - b.y);\n}\n\ndouble cross(point a, point b, point c) {\n  return (b.x - a.x) * (c.y - b.y) - (b.y - a.y) * (c.x - b.x);\n}\n\n/* PA * PB */\ndouble dot(point p, point a, point b) {\n  return (a.x - p.x) * (b.x - p.x) + (a.y - p.y) * (b.y - p.y);\n}\n\n/* delta angle of ABC */\ndouble delta_angle(point a, point b, point c) {\n  return acos(dot(b, a, c) / (dist(a, b) * dist(b, c)));\n}\n\npoint *__o;\n\nint angle_cmp(point *p, point *q) {\n  int c;\n  if (c = sign(cross(*__o, *p, *q)))\n    return -c;\n  return sign(dist(*p, *__o) - dist(*q, *__o));\n}\n\npoint stack[N];\n\nint convex_hull(point *ps, int n) {\n  int i, k, top;\n  point q;\n\n  k = 0;\n  for (i = 1; i < n; i++)\n    if (sign(ps[i].y - ps[k].y) < 0 || sign(ps[i].y - ps[k].y) == 0 && ps[i].x < ps[k].x)\n      k = i;\n\n  q = ps[k];\n  ps[k] = ps[0];\n  ps[0] = q;\n\n  __o = &ps[0];\n  qsort(ps + 1, n - 1, sizeof(point), (int (*)(const void *, const void *))angle_cmp);\n\n  top = 0;\n  for (i = 0; i < n; i++) {\n//    printf(\"%lf,%lf\\n\", ps[i].x, ps[i].y);\n    while (top >= 2 && sign(cross(stack[top - 2], stack[top - 1], ps[i])) <= 0) top--;\n    stack[top++] = ps[i];\n  }\n  memcpy(ps, stack, sizeof(point) * top);\n  return top;\n}\n\ndouble cccr(point A, point B, point C) {\n  double a, b, c, cos_B, sin_B, R;\n\n  a = dist(B, C);\n  b = dist(A, C);\n  c = dist(A, B);\n  cos_B = (a * a + c * c - b * b) / (2 * a * c);\n  sin_B = sqrt(1.0 - cos_B * cos_B);\n  return b / sin_B / 2.0;\n}\n\nint too_straight(point A, point B, point C, double r) {\n  if (!sign(cross(A, B, C)))\n    return 1;\n  \n//  printf(\"R=%lf vs r=%lf\\n\", R, r);\n  return sign(cccr(A, B, C) - r) > 0;\n}\n\ndouble area_bow(double r, double l) {\n  double tri = l * sqrt(sqr(r) - sqr(l / 2)) / 2;\n  double theta = 2 * asin(l / (r + r));\n  double sector = theta * r * r / 2;\n  return sector - tri;\n}\n\ndouble area_polygon(const point a[], int n) {\n  int i, j;\n  double area = 0.0;\n  for (j = 0, i = n - 1; j < n; i = j++)\n    area += a[i].x * a[j].y - a[i].y * a[j].x;\n  return fabs(area) / 2;\n}\n\nint main() {\n  static point ps[N];\n  int n;\n  double r, ans, R, Rmin;\n  int i, j, k, z, top, s, ch;\n\n  scanf(\"%d %lf\", &n, &r);\n  for (i = 0; i < n; i++)\n    scanf(\"%lf %lf\", &ps[i].x, &ps[i].y);\n\n  if (n == 1) {\n    puts(\"0\");\n  } else if (n == 2) {\n    ans = area_bow(r, dist(ps[0], ps[1])) * 2.0;\n    printf(\"%.9lf\\n\", ans);\n  } else {\n    n = convex_hull(ps, n);\n//    printf(\"n=%d\\n\", n);\n\n    z = -1;\n    for (i = 0, j = 1, k = 2 % n; i < n; i++, j = (j + 1) % n, k = (k + 1) % n) {\n      R = cccr(ps[i], ps[j], ps[k]);\n      if (z == -1 || Rmin > R) {\n        Rmin = R;\n        z = j;\n      }\n    }\n\n    top = 0;\n    for (j = 0, i = z; j < n; j++, i = (i + 1) % n) {\n//      printf(\"%lf,%lf\\n\", ps[i].x, ps[i].y);\n      while (top >= 2 && too_straight(stack[top - 2], stack[top - 1], ps[i], r))\n        top--;\n      stack[top++] = ps[i];\n    }\n    ch = 1;\n    while (ch) {\n      ch = 0;\n      while (top - s >= 2 && too_straight(stack[top - 2], stack[top - 1], stack[s], r))\n        top--, ch = 1;\n      s = 0;\n      while (top - s >= 2 && too_straight(stack[top - 1], stack[s], stack[s + 1], r))\n        s++, ch = 1;\n    }\n//    printf(\"top=%d\\n\", top);\n\n    memcpy(stack, stack + s, sizeof(stack[0]) * (top -= s));\n\n    ans = area_polygon(stack, top);\n    for (i = 0, j = 1 % top; i < top; i++, j = (j + 1) % top) {\n//      printf(\"%lf,%lf\\n\", stack[i].x, stack[i].y);\n      ans += area_bow(r, dist(stack[i], stack[j]));\n    }\n    printf(\"%.9lf\\n\", ans);\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f34c9973b12c57eb0656c09e543a8028", "src_uid": "5f2a0960bab9bdc91b190ed07d6adcf7", "difficulty": 3000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#include<math.h>\n\n#define mset(a) memset(a,0,sizeof(a))\n#define mcpy(a,b) memcpy(a,b,sizeof(a))\n#define mcmp(a,b,n) memcmp(a,b,n)\n#define maxint 2147483647\n#define pi 3.14159265358979323846\n\nlong long n,t,ans=0,k;\nlong long a[111],cnk[111][111];\n\nlong long turn(long long t)\n{\n     long long i=0;\n     \n     if(t&(t-1))\n       return -1;\n     \n     while(t>>=1)\n       i++;\n     return i;\n}\n\nint main()\n{\n    int i,j,l;\n    \n    a[0]=1;\n    for(i=1;i<63;i++)\n      a[i]=a[i-1]<<1;\n    mset(cnk);\n    for(i=0;i<111;i++)\n      {\n        cnk[i][0]=1;\n        for(j=1;j<=i;j++)\n          cnk[i][j]=cnk[i-1][j-1]+cnk[i-1][j];\n      }\n    \n    scanf(\"%I64d%I64d\",&n,&t);\n    \n    k=turn(t);\n    if(k==-1)\n      {\n        printf(\"0\\n\");\n        return 0;\n      }\n    \n    for(i=1;n>a[i];i++)\n      {\n        ans+=cnk[i][k];\n        n-=a[i];\n      }\n    for(i=62;i>=0;i--)\n      if((~k)&&(n>>i&1))\n        {\n          ans+=cnk[i][k];\n          k--;\n        }\n    \n    printf(\"%I64d\\n\",ans);\n    \n    //system(\"pause\");\n    return 0;\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6eb98010107172f7d920ebf744bc571c", "src_uid": "727d5b601694e5e0f0cf3a9ca25323fc", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\nlong long ch(int n, int k) {\n\treturn k == 0 ? 1 : ch(n - 1, k - 1) * n / k;\n}\n\nint main() {\n\tlong long n, m, t, ans;\n\tint k, b, l;\n\n\tscanf(\"%lld%lld\", &n, &t), n += 2;\n\tif (t & t - 1) {\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\tk = 0;\n\twhile (t > 0) {\n\t\tk++;\n\t\tt >>= 1;\n\t}\n\tb = 0;\n\tfor (m = n; m > 1; m >>= 1)\n\t\tb++;\n\tans = 0;\n\tfor (l = 0; b >= 0; b--)\n\t\tif (n & 1LL << b) {\n\t\t\tif (b >= k - l)\n\t\t\t\tans += ch(b, k - l);\n\t\t\tif (++l > k)\n\t\t\t\tbreak;\n\t\t}\n\tif (k == 1)\n\t\tans--;\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a3922fb52f05a5677417c87d4f66357b", "src_uid": "727d5b601694e5e0f0cf3a9ca25323fc", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#include<math.h>\n\n#define mset(a) memset(a,0,sizeof(a))\n#define mcpy(a,b) memcpy(a,b,sizeof(a))\n#define mcmp(a,b,n) memcmp(a,b,n)\n#define maxint 2147483647\n#define pi 3.14159265358979323846\n\nlong long n,t,ans=0,k;\nlong long a[111],cnk[111][111];\n\nlong long turn(long long t)\n{\n     long long i=0;\n     \n     if(t&(t-1))\n       return -1;\n     \n     while(t>>=1)\n       i++;\n     return i;\n}\n\nint main()\n{\n    int i,j,l;\n    \n    a[0]=1;\n    for(i=1;i<63;i++)\n      a[i]=a[i-1]<<1;\n    mset(cnk);\n    for(i=0;i<111;i++)\n      {\n        cnk[i][0]=1;\n        for(j=1;j<=i;j++)\n          cnk[i][j]=cnk[i-1][j-1]+cnk[i-1][j];\n      }\n    \n    scanf(\"%I64d%I64d\",&n,&t);\n    \n    k=turn(t);\n    if(k==-1)\n      {\n        printf(\"0\\n\");\n        return 0;\n      }\n    \n    for(i=1;n>a[i];i++)\n      {\n        ans+=cnk[i][k];\n        n-=a[i];\n      }\n    for(i=62;i>0;i--)\n      if((~k)&&(n>>i&1))\n        {\n          ans+=cnk[i][k];\n          k--;\n        }\n    \n    printf(\"%I64d\\n\",ans);\n    \n    //system(\"pause\");\n    return 0;\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c2d7ef77bd79df8a239549f54207b8af", "src_uid": "727d5b601694e5e0f0cf3a9ca25323fc", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#define modd 1000000007\nlong long fast_expo(long long a,long long b)\n{\n\tlong long res=1;\n\twhile(b>0)\n\t{\n\t\tif(b&1)\n\t\t\tres=(res*a)%modd;\n\t\ta=(a*a)%modd;\n\t\tb=b>>1;\n\t}\n\treturn res;\n}\nint main()\n{\n\tlong long fact[200001];\n\tint i,n;\n\tfact[0]=1;\n\tfor(i=1;i<200001;i++)\n\t\tfact[i]=(fact[i-1]*i)%modd;\n\twhile(scanf(\"%d\",&n)==1)\n\t{\n\t\tlong long ans=(fact[(n<<1)-1]*((fast_expo(fact[n],modd-2)*fast_expo(fact[n-1],modd-2))%modd))%modd;\n\t\tans=(ans<<1)-n;\n\t\tif(ans<0)\n\t\t\tprintf(\"%I64d\\n\",(ans+modd)%modd);\n\t\telse printf(\"%I64d\\n\",ans%modd);\n\t}\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e937f5acb646c77c4963f9fd8b252164", "src_uid": "13a9ffe5acaa79d97df88a069fc520b9", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#define modd 1000000007\nlong long fast_expo(long long a,long long b)\n{\n\tlong long res=1;\n\twhile(b>0)\n\t{\n\t\tif(b&1)\n\t\t\tres=(res*a)%modd;\n\t\ta=(a*a)%modd;\n\t\tb=b>>1;\n\t}\n\treturn res;\n}\nint main()\n{\n\tlong fact[200001];\n\tint i,n;\n\tfact[0]=1;\n\tfor(i=1;i<200001;i++)\n\t\tfact[i]=(fact[i-1]*i)%modd;\n\twhile(scanf(\"%d\",&n)==1)\n\t{\n\t\tlong long ans=(fact[2*n-1]*((fast_expo(fact[n],modd-2)*fast_expo(fact[n-1],modd-2))%modd))%modd;\n\t\tans=(2*ans)-n;\n\t\tif(ans<0)\n\t\t\tprintf(\"%I64d\\n\",(ans+modd)%modd);\n\t\telse printf(\"%I64d\\n\",ans%modd);\n\t}\n\treturn 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6a1851fcb94bda192f737e0432b9bd26", "src_uid": "13a9ffe5acaa79d97df88a069fc520b9", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MAX 1000000007\nlong long int ncr(int n, int k)\n{\n    if(k > n)\n        return 0;\n    if(k == n)\n        return 1;\n    long long int r = n;\n    int i;\n    for(i=2;i<=k;++i)\n    {\n        r *= (n-i+1);\n        r = r/i;\n    }\n    return r;\n}\nint main()\n{\n    int n,i, sum = 0, ans = 0;\n    scanf(\"%d\", &n);\n    sum = n+2;\n    for(i = 1; i <=n; i++){\n        ans = ans + ncr(n+1,i);\n    }\n    ans = (ans+n)%MAX;\n    if(n == 2){\n        ans = 4;\n    }\n    printf(\"%d\", ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "02ec4b1f081548bf04849c2e47ea0916", "src_uid": "13a9ffe5acaa79d97df88a069fc520b9", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define P 1000000007\nint n,i,j;__int64 t=1,s;\nvoid main(){\n\tscanf(\"%d\",&n);\n\tfor(i=1;i<=n;++i)t=t*i%P;\n\tfor(j=P-3,s=t;j;j>>=1,s=s*s%P)\n\t\tif(j&1)t=t*s%P;\n\tfor(i=n;i<n<<1;++i)t=t*i%P;\n\tprintf(\"%I64d\\n\",(t*2-n+P)%P);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "610a90c90b7149576671e9538098d6e9", "src_uid": "13a9ffe5acaa79d97df88a069fc520b9", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define P 1000000007\nint n,i,j;__int64 t=1,s;\nmain(){\n\tscanf(\"%d\",&n);\n\tfor(i=1;i<=n;++i)t=t*i%P;\n\tfor(j=P-3,s=t;j;j>>=1,s=s*s%P)\n\t\tif(j&1)t=t*s%P;\n\tfor(i=n;i<n<<1;++i)t=t*i%P;\n\tprintf(\"%I64d\\n\",(t*2-n+P)%P);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a645b7b5d5fb22ef364e82e09880431c", "src_uid": "13a9ffe5acaa79d97df88a069fc520b9", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int x;\n    scanf(\"%d\",&x);\n    for(long r=1;r<=x;r++)\n    {\n        for(long c=1;c<=r;c++)\n        long mul=r*c;\n        if(mul>=x)\n        {\n            mul=10*(mul/x)+(mul%x);\n        printf(\"%ld\",mul);\n        }\n        puts(\" \");\n        \n        }\n        return 0;\n    }\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "fb1b9abab9e7a914d734104d785fc7e4", "src_uid": "a705144ace798d6b41068aa284d99050", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<cstdio>\nint main()\n{\n    int x;\n    scanf(\"%d\",&x);\n    for(long r=1;r<x;r++)\n    {\n        for(long c=1;c<x;c++)\n        {\n        long mul=r*c;\n        if(mul>=x)\n        {\n            mul=10*(mul/x)+(mul%x);\n        }\n        printf(\"%ld \",mul);\n        }\n        puts(\"\");\n        \n        }\n        return 0;\n    }\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "43a152b0840edda453b6d18f308cf055", "src_uid": "a705144ace798d6b41068aa284d99050", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<cstdio>\nint main()\n{\n    int x;\n    scanf(\"%d\",&x);\n    for(long r=1;r<x;r++)\n    {\n        for(long c=1;c<x;c++)\n        {\n        long mul=r*c;\n        if(mul>=x)\n        {\n            mul=10*(mul/x)+(mul%x);\n        }\n        printf(\"%ld\",mul);\n        }\n        puts(\"\");\n        \n        }\n        return 0;\n    }\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "51aee3feb4bcc67375bd3521f875e1ca", "src_uid": "a705144ace798d6b41068aa284d99050", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int x;\n    scanf(\"%d\",&x);\n    for(long r=1;r<=x;r++)\n    {\n        for(long c=1;c<=r;c++)\n        {\n        long mul=r*c;\n        if(mul>=x)\n        {\n            mul=10*(mul/x)+(mul%x);\n        }\n        printf(\"%ld\",mul);\n        }\n        puts(\"\");\n        \n        }\n        return 0;\n    }\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a31a7e1602ae921fb935bf12c0a9e093", "src_uid": "a705144ace798d6b41068aa284d99050", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int x;\n    scanf(\"%d\",&x);\n    for(long r=1;r<=x;r++)\n    {\n        for(long c=1;c<=r;c++)\n        {\n        long mul=r*c;\n        if(mul>=x)\n        {\n            mul=10*(mul/x)+(mul%x);\n        }\n        printf(\"%ld\",mul);\n        }\n        puts(\" \");\n        \n        }\n        return 0;\n    }\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7a1ed1427cb5d8baa8613be5e8d9f6ce", "src_uid": "a705144ace798d6b41068aa284d99050", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint Cnt[10];\n\nint main()\n{\n    int table[] = {999999999, 99999999, 9999999, 999999, 99999, 9999, 999, 99, 9};\n    int n, reamin = 0, ans = 0;\n    scanf(\"%d\", &n);\n    for(int i = 0; i < 9; ++i) {\n        if(n + n - 1 >= table[i]) {\n            reamin = table[i];\n            break;\n        }\n    }\n    if(reamin == 0) {\n        printf(\"%d\\n\", n * (n - 1) / 2);\n        return 0;\n    }\n    for(int i = 0; i < 9; ++i) {\n        long long expect = (long long)(reamin + 1) * i + reamin;\n        if(n + n - 1 >= expect) {\n            if(expect <= n) {\n                ans += expect / 2;\n            } else {\n                ans += n - expect / 2;\n            }\n        }\n    }\n    printf(\"%d\\n\", ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ca73d91bfb3f100d47cb60a258f28da6", "src_uid": "c20744c44269ae0779c5f549afd2e3f2", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "//Date : 17 - 12 - 17\n\n#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<stdbool.h>\n#include<float.h>\n#include<math.h>\n#include<inttypes.h>\n#include<assert.h>\n#include<ctype.h>\n#include<limits.h>\n#include<time.h>\n#define ll long long\n#define For(i,n)\tfor(i=0;i<n;i++)\n#define rep(i ,a ,b)\tfor(i=(a);i<=(b);i++)\n#define mset(a ,value)\tmemset(a ,value ,sizeof(a))\n#define s(a)\tscanf(\"%d\" ,&a);\n#define ls(a)\tscanf(\"%ld\" ,&a)\n#define reg(i)\tregister int i\n#define infinite INT_MAX\n#define MAX 200005\n#define N 1000005\n#define MM 100001\n#define MOD 1000000007\n#define NIL -1\nll min(ll a,ll b){\treturn (a < b ? a : b)\t;}\t\nint max(int a,int b){\treturn (a > b ? a : b)\t;}\nll gcd(ll a,ll b){\n\tif(a==0)\treturn b;\n\treturn gcd(b%a ,a);\n} \nvoid swap(ll *a,ll *b){\n\tll t = *a;\n\t*a = *b;\n\t*b = t;\n}\nint main(){\n\tint n;\n\ts(n);\n\tll sum = 0LL + n + n - 1;\n\tll ms = sum;\n\tint x = 0 ,_9 = 0;\n\twhile(sum){\n\t\tif(sum % 10 == 9)\t_9++;\n\t\tsum /= 10;\n\t\tx++;\n\t}\n\t//printf(\"%d %d\" ,x ,_9);\n\tif(_9 == x){\tprintf(\"1\");\treturn 0;\t}\n\tif(x == 1){\tprintf(\"%I64d\" ,1LL*n*(n - 1) / 2);\treturn 0;\t}\n\tx--;\n\t_9 = x;\tsum = 0;\n\tll inc = 1;\n\twhile(x){\n\t\tsum = sum * 10LL + 9;\n\t\tinc *= 10;\n\t\tx--;\n\t}\n\t//printf(\"%I64d %I64d\\n\" ,sum ,inc);\n\tll ans = 0 ,lo ,hi ,r ,v;\n\tbool ff = 0;\n\twhile(sum <= ms){\n\t\tlo = 1 ,hi = n ,ff = 0;\n\t\twhile(lo <= hi){\n\t\t\tr =\t(lo + hi) / 2;\n\t\t\tv = sum - r;\n\t\t\tif(v < 0)\thi = r - 1;\n\t\t\telse if(v > n)\tlo = r + 1;\n\t\t\telse {\tff = 1;\tbreak;\t}\n\t\t}\n\t\tif(ff){\n\t\t\tif(r > v)\tswap(&v ,&r);\n\t\t\t//printf(\"%I64d %I64d\\n\" ,r ,v);\n\t\t\tans += min(r ,n - v + 1);\n\t\t\tll diff = v - r - 1;\n\t\t\tans += diff / 2;\n\t\t}\n\t\tsum += inc;\n\t}\n\tprintf(\"%I64d\" ,ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "02b3c5d2f989f951a242cdb2037eed45", "src_uid": "c20744c44269ae0779c5f549afd2e3f2", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n#include <stdbool.h>\n\n#define MIN(a, b) ((a)<(b)?(a):(b))\n#define MAX(a, b) ((a)>(b)?(a):(b))\n\n#define MOD 1e9+7\n#define M 25\n\nint a[5]= {0,0,1,3,6};\n\nint main() {\n    int n;\n//    freopen(\"1.txt\", \"r\", stdin);\n//    freopen(\"2.txt\", \"w\", stdout);\n    while(scanf(\"%d\", &n)!=EOF) {\n        if (n < 5) {\n            printf(\"%d\\n\",a[n]);\n            continue;\n        }\n        long long s = 0LL, t=5LL,i;\n        for(i = 1; i <10; i++) {\n            if (n >=t) {\n                t*=10;\n            } else  {\n                break;\n            }\n        }\n        t/=10;\n        for(i=1; i<=5; i++) {\n            if(n>t*i*2+t-1) {\n                s+=2*t*i;\n                s--;\n            } else {\n                i--;\n                break;\n            }\n        }\n        s+=(n-t*i*2-t+1)*(i+1);\n        if(n>=t+t-1+i*(t*10/5)) {\n            s--;\n        }\n        printf(\"%d\\n\",s);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0ebff0c641dad74759270c85d89cb265", "src_uid": "c20744c44269ae0779c5f549afd2e3f2", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\n\n\n\nlong long int myfunc(long long int n){\n    if(n <= 4)\n        return n * (n - 1) / 2;\n    long double s = 1.0 * n / 5;\n    s = log10l(s);\n    s = floorl(s);\n    long long int m = 5 * (long long int)powl(10, s);\n    long long int result = 0ll;\n    for(int i = 0 ; i < 9 ; i++){\n        long long int min, max;\n        min = (long long int)((i+1) * powl(10, s+1) / 2);\n        max = (long long int)((i+1) * powl(10, s+1) - 2);\n        if (n >= max){\n            result += min - 1;\n        }else if( n < min ){\n            break;\n        }else{\n            result += n - min + 1 ;\n        }\n    }\n    return result;\n}\n\n\nint main(){\n    long long int n;\n    scanf(\"%lld\", &n);\n\n    printf(\"%lld\", myfunc(n));\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e92eb296c93572242d7f1399de6d112f", "src_uid": "c20744c44269ae0779c5f549afd2e3f2", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(){\n\tlong long int i,n;\n\tscanf(\"%lld\",&n);\n\tlong long int temp=n*2;\n\ttemp/=10;\n\tlong long int m=0;\n\tlong long int m10=1;\n\twhile(temp>0){\n\t\ttemp/=10;\n\t\tm++;\n\t\tm10*=10;\n\t}\n\tif(m==0){\n\t\tprintf(\"%lld\\n\",(n*(n-1))/2);\n\t\treturn 0;\n\t}\n\tlong long int ans=0,val=0;\n\tfor(i=1;i<=9;i++){\n\t\tif(i*m10>2*n)break;\n\t\tif(n>=i*m10-1){\n\t\t\tans+=((i*m10/2)-1);\n//\t\t\tval=((i*m10/2)-1);\n//\t\t\tprintf(\"%d=%d\\n\",i,val);\n\t\t}\n\t\telse{\n\t\t\tans+=(n+1-(i*m10/2));\n//\t\t\tval=(n+1-(i*m10/2));\n//\t\t\tprintf(\"%d=%d\\n\",i,val);\n\t\t}\n\t}\n\tprintf(\"%lld\\n\",ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7db8be6334bb5e12f63da1e481b57fb5", "src_uid": "c20744c44269ae0779c5f549afd2e3f2", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define MAX 102\n#define LIM 303\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nbool visited[MAX][MAX][LIM][2];\nint n, t, counter[1010], ar[MAX], dp[MAX][MAX][LIM][2];\n\nint F(int i, int l, int r, int flag){\n    if (i > n){\n        if (r == t || r == LIM){\n            if (!flag) return (counter[ar[l]] * (t - r));\n            else return 0;\n        }\n        else return F(0, l, r + 1, flag);\n    }\n    if (visited[i][l][r][flag]) return dp[i][l][r][flag];\n\n    int x, res = F(i + 1, l, r, flag);\n    if (ar[i] >= ar[l]){\n        x = 1 + F(i + 1, i, r, flag);\n        if (x > res) res = x;\n    }\n    if (!flag && t > LIM){\n        x = F(i, l, r, 1) + (counter[ ar[l] ] * (t - LIM));\n        if (x > res) res = x;\n    }\n\n    visited[i][l][r][flag] = true;\n    return (dp[i][l][r][flag] = res);\n}\n\nint main(){\n    int i, j, k;\n\n    while (scanf(\"%d %d\", &n, &t) != EOF){\n        if (!n) break;\n\n        ar[0] = 0;\n        clr(counter);\n        for (i = 1; i <= n; i++){\n            scanf(\"%d\", &ar[i]);\n            counter[ar[i]]++;\n        }\n\n        clr(visited);\n        int res = F(1, 0, 1, 0);\n        printf(\"%d\\n\", res);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "200552669bfd1b21b1c3f9b78f752cbb", "src_uid": "26cf484fa4cb3dc2ab09adce7a3fc9b2", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#define MAXN 23333\n#define MAXELEM 308\n\nint n, t;\nint a[MAXN];\n\n// Calculate the longest non-decreasing sequence\n// Time complexity: O(n log n)\nint *lnds(int *a, int n)\n{\n    int *ret = (int *)malloc(n * sizeof(int));\n    int a_with_f[MAXN], maxlen = 1;\n    ret[0] = 1;\n    a_with_f[0] = -1;\n    a_with_f[1] = a[0];\n    int lo, hi, mid, i;\n    for (i = 1; i < n; ++i) {\n        if (a[i] >= a_with_f[maxlen]) {\n            a_with_f[++maxlen] = a[i];\n        } else {\n            lo = 0, hi = maxlen;\n            while (lo < hi - 1) {\n                mid = (lo + hi) / 2;\n                if (a[i] >= a_with_f[mid]) lo = mid;\n                else hi = mid;\n            }\n            a_with_f[lo + 1] = a[i];\n        }\n        ret[i] = maxlen;\n    }\n    return ret;\n}\n\nint main()\n{\n    scanf(\"%d%d\", &n, &t);\n    int i;\n    for (i = 0; i < n; ++i) scanf(\"%d\", &a[i]);\n    if (t <= 233) {\n        for (i = n; i < n * t; i += n)\n            memcpy(a + i, a, n * sizeof(int));\n        int *first_part = lnds(a, n * t);\n        printf(\"%d\\n\", first_part[n * t - 1]);\n    } else {\n        for (i = n; i < n * 233; i += n)\n            memcpy(a + i, a, n * sizeof(int));\n        int *first_part = lnds(a, n * 233);\n        int count[MAXELEM] = { 0 }, maxcount = 0;\n        for (i = 0; i < n; ++i) ++count[a[i]];\n        for (i = 0; i < MAXELEM; ++i) if (maxcount < count[i]) maxcount = count[i];\n        for (i = 0; i < n * 233; i += n)\n            if (first_part[i + n] - first_part[i] == maxcount) break;\n        i /= n;\n        // assert(i == 1)?\n        printf(\"%d\\n\", first_part[i * n + n - 1] + (t - i - 1) * maxcount);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0e0ce726b9f65de724259a7f5f309c66", "src_uid": "26cf484fa4cb3dc2ab09adce7a3fc9b2", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define MAX 102\n#define LIM 303\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nbool visited[MAX][MAX][LIM][2];\nint n, t, counter[1010], ar[MAX], dp[MAX][MAX][LIM][2];\n\nint F(int i, int l, int r, int flag){\n    if (i > n){\n        if (r == t || r == LIM){\n            if (!flag) return (counter[ar[l]] * (t - r));\n            else return 0;\n        }\n        else return F(0, l, r + 1, flag);\n    }\n    if (visited[i][l][r][flag]) return dp[i][l][r][flag];\n\n    int x, res = F(i + 1, l, r, flag);\n    if (ar[i] >= ar[l]){\n        x = 1 + F(i + 1, i, r, flag);\n        if (x > res) res = x;\n    }\n    if (!flag && t > LIM){\n        x = F(i, l, r, 1) + (counter[l] * (t - LIM));\n        if (x > res) res = x;\n    }\n\n    visited[i][l][r][flag] = true;\n    return (dp[i][l][r][flag] = res);\n}\n\nint main(){\n    int i, j, k;\n\n    while (scanf(\"%d %d\", &n, &t) != EOF){\n        if (!n) break;\n\n        ar[0] = 0;\n        clr(counter);\n        for (i = 1; i <= n; i++){\n            scanf(\"%d\", &ar[i]);\n            counter[ar[i]]++;\n        }\n\n        clr(visited);\n        int res = F(1, 0, 1, 0);\n        printf(\"%d\\n\", res);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7b564b1a970d723672cdaf59b30f71af", "src_uid": "26cf484fa4cb3dc2ab09adce7a3fc9b2", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define MAX 333\n\nint min(int x, int y) {\n  return x < y ? x :  y;\n}\n\nint a[MAX];\nint dp[MAX];\nint n;\n\nvoid update() {\n  int i, j;\n  for (i = 0; i < n; i++) {\n    int ma = 0;\n    for (j = 0; j <= a[i]; j++) {\n      if (dp[j] > ma) ma = dp[j];\n    }\n    if (ma + 1 > dp[a[i]]) dp[a[i]] = ma + 1;\n  }\n}\n           \nint main() {          \n  int t, i;\n  scanf(\"%d %d\", &n, &t);\n  for (i = 0; i < n; i++) {\n    scanf(\"%d\", &a[i]);\n  }                                   \n  int time1 = min(MAX, t);\n  int time3 = min(MAX, t - time1);\n  int time2 = t - time1 - time2;\n  for (i = 0; i < time1; i++) {\n    update();\n  }\n  int ma = 0;\n  if (time2 != 0) {\n  for (i = 0; i < MAX; i++) {\n    int cnt = 0;\n    int j;\n    for (j = 0; j < n; j++) if (a[j] == i) cnt++;\n    if (dp[i] > ma) ma = dp[i];\n    dp[i] = ma + cnt * time2;                         \n  }\n  }\n  for (i = 0; i < time3; i++) {\n    update();\n  }\n  int res = 0;\n  for (i = 0; i < MAX; i++) if (dp[i] > res) res = dp[i];\n  printf(\"%d\\n\", res);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "53e50c21fb7cc39ea94bdf8a3a2d78ba", "src_uid": "26cf484fa4cb3dc2ab09adce7a3fc9b2", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define MAX 1010\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nint n, ar[MAX];\nbool visited[MAX];\n\nint main(){\n    int i, j, k, l, x, y, pos, counter;\n\n    while (scanf(\"%d\", &n) != EOF){\n        clr(visited);\n        for (i = 0; i < n; i++) scanf(\"%d\", &ar[i]);\n\n        pos = 0, counter = 0;\n        while (counter < n){\n            if (!(pos & 1)){\n                for (i = 0; i < n; i++){\n                    if (!visited[i] && counter >= ar[i]){\n                        counter++;\n                        visited[i] = true;\n                    }\n                }\n            }\n            else{\n                for (i = n - 1; i >= 0; i--){\n                    if (!visited[i] && counter >= ar[i]){\n                        counter++;\n                        visited[i] = true;\n                    }\n                }\n            }\n\n            if (counter == n) break;\n            pos++;\n        }\n\n        printf(\"%d\\n\", pos);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3ee3f0c99cbcd86fd7bf747224fd7f6f", "src_uid": "26cf484fa4cb3dc2ab09adce7a3fc9b2", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    long times,n,value,lvalue,ans,g,maxg=0,v[46],i,j,k;\n    scanf(\"%ld%ld%ld\",&times,&n,&value);\n    for (i=1;i<=n;i++)\n        scanf(\"%ld\",&v[i]);\n    ans=0;\n    for (i=1;i<=n;i++)\n        ans+=v[i];\n    for (i=0;i<=times;i++)\n        if (value-ans*i>=0)\n        {\n            g=(n+1)*i;\n            lvalue=value-ans*i;\n            for (j=1;j<n;j++)//can't solve any problem more\n                for (k=1;k<=times-i;k++)\n                    if (lvalue-v[j]>=0)\n                    {\n                        g++;\n                        lvalue-=v[j];\n                    }\n                    else\n                        break;\n            if (g>maxg)\n                maxg=g;\n        }\n        else\n            break;\n    printf(\"%ld\\n\",maxg);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b8896144868f469f7110f262b3ae83fd", "src_uid": "d659e92a410c1bc836be64fc1c0db160", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    long times,n,value,lvalue,ans,g,maxg=0,v[46],i,j,k;\n    scanf(\"%ld%ld%ld\",&times,&n,&value);\n    for (i=1;i<=n;i++)\n        scanf(\"%ld\",&v[i]);\n    for (i=1;i<n;i++)\n        for (j=i+1;j<=n;j++)\n            if (v[i]>v[j])\n            {\n                k=v[i];\n                v[i]=v[j];\n                v[j]=k;\n            }\n    ans=0;\n    for (i=1;i<=n;i++)\n        ans+=v[i];\n    for (i=0;i<=times;i++)\n        if (value-ans*i>=0)\n        {\n            g=(n+1)*i;\n            lvalue=value-ans*i;\n            for (j=1;j<n;j++)//can't solve any problem more\n                for (k=1;k<=times-i;k++)\n                    if (lvalue-v[j]>=0)\n                    {\n                        g++;\n                        lvalue-=v[j];\n                    }\n                    else\n                        break;\n            if (g>maxg)\n                maxg=g;\n        }\n        else\n            break;\n    printf(\"%ld\\n\",maxg);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "37c1d93c84ee99a2cc0df0c993645388", "src_uid": "d659e92a410c1bc836be64fc1c0db160", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#define me(x) memset(x,0,sizeof(x))\nlong n,a[105],p[16]={2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53};\nlong dp[105][65536],ch[105][65536],va[60];\nlong ab(long x)\n{\n\treturn x>0?x:-x;\n}\nlong an[105];\nint main()\n{\n\tlong i,j,k;\n\tscanf(\"%ld\",&n);\n\tfor (i=1;i<=n;i++) scanf(\"%ld\",&a[i]);\n\tme(dp[0]);\n\tfor (i=1;i<=n;i++) for (j=0;j<65536;j++) dp[i][j]=99999999;\n\tfor (j=1;j<=58;j++)\n\t{\n\t\tva[j]=0;\n\t\tfor (i=0;i<16;i++) if (j%p[i]==0) va[j]+=1<<i;\n\t}\n\tfor (i=0;i<n;i++)\n\t{\n\t\tfor (j=0;j<65536;j++)\n\t\tfor (k=1;k<=58;k++) if (!(j&va[k])&&dp[i+1][j|va[k]]>dp[i][j]+ab(k-a[i+1]))\n\t\t{\n\t\t\tdp[i+1][j|va[k]]=dp[i][j]+ab(k-a[i+1]);\n\t\t\tch[i+1][j|va[k]]=k;\n\t\t}\n\t}\n\tj=65535;\n\tfor (i=n;i>0;i--)\n\t{\n\t\tan[i]=ch[i][j];\n\t\tj^=va[ch[i][j]];\n\t}\n\tfor (i=1;i<=n;i++)\n\t{\n\t\tprintf(\"%ld\",an[i]);\n\t\tif (i!=n) printf(\" \");\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b51ce7165e3a56341c0c873e24adedba", "src_uid": "f26c74f27bbc723efd69c38ad0e523c6", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n#include <stdlib.h>\n\n#define N\t100\n#define INF\t2901\n\nint pp[] = { 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53 };\n\nint max(int a, int b) { return a > b ? a : b; }\n\nint main() {\n\tstatic int aa[N], qq[N], bb[59], dp[N + 1][1 << 16], cc[N + 1][1 << 16];\n\tint n, h, i, a, b, b_, c, cnt;\n\n\tfor (a = 2; a < 59; a++)\n\t\tfor (h = 0; h < 16; h++)\n\t\t\tif (a % pp[h] == 0)\n\t\t\t\tbb[a] |= 1 << h;\n\tscanf(\"%d\", &n);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d\", &aa[i]);\n\tfor (i = 0; i <= n; i++)\n\t\tfor (b = 0; b < 1 << 16; b++)\n\t\t\tdp[i][b] = INF;\n\tdp[0][0] = 0;\n\tfor (i = 0; i < n; i++) {\n\t\ta = max(aa[i] * 2 - 2, 1);\n\t\tfor (b = 0; b < 1 << 16; b++) {\n\t\t\tint x = dp[i][b];\n\n\t\t\tif (x == INF)\n\t\t\t\tcontinue;\n\t\t\tfor (c = 1; c <= a; c++)\n\t\t\t\tif ((bb[c] & b) == 0) {\n\t\t\t\t\tint x_ = x + abs(c - aa[i]);\n\n\t\t\t\t\tb_ = bb[c] | b;\n\t\t\t\t\tif (dp[i + 1][b_] > x_) {\n\t\t\t\t\t\tdp[i + 1][b_] = x_;\n\t\t\t\t\t\tcc[i + 1][b_] = c;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t}\n\t}\n\tb_ = 0;\n\tfor (b = 1; b < 1 << 16; b++)\n\t\tif (dp[n][b_] > dp[n][b])\n\t\t\tb_ = b;\n\tcnt = 0;\n\tfor (i = n; i > 0; i--) {\n\t\tc = cc[i][b_];\n\t\tqq[cnt++] = c;\n\t\tb_ ^= bb[c];\n\t}\n\twhile (cnt--)\n\t\tprintf(\"%d \", qq[cnt]);\n\tprintf(\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "853eda051448987c419e6875b225ba89", "src_uid": "f26c74f27bbc723efd69c38ad0e523c6", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define len 17\n#define inf (1 << 25)\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nint factors[65] = {0};\nbool visited[100][1 << len];\nint n, ar[100], harmony[100], dp[100][1 << len], next[100][1 << len];\nint primes[] = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59};\n\nvoid backtrack(int i, int bitmask){\n    if (i == n) return;\n    harmony[i] = next[i][bitmask];\n    backtrack(i + 1, bitmask | factors[harmony[i]]);\n}\n\nint F(int i, int bitmask){\n    if (i == n) return 0;\n    if (visited[i][bitmask]) return dp[i][bitmask];\n\n    int j, res = inf;\n    for (j = 1; j <= 60; j++){\n        if (!(bitmask & factors[j])){\n            int x = abs(ar[i] - j) + F(i + 1, bitmask | factors[j]);\n            if (x < res){\n                res = x;\n                next[i][bitmask] = j;\n            }\n        }\n    }\n\n    visited[i][bitmask] = true;\n    return (dp[i][bitmask] = res);\n}\n\nint main(){\n    int i, j;\n    for (i = 1; i <= 60; i++){\n        for (j = 0; j < len; j++){\n            if ((i % primes[j]) == 0) factors[i] |= (1 << j);\n        }\n    }\n\n    while (scanf(\"%d\", &n) != EOF){\n        for (i = 0; i < n; i++) scanf(\"%d\", &ar[i]);\n        clr(visited);\n        int res = F(0, 0);\n        backtrack(0, 0);\n        for (i = 0; i < n; i++) printf(\"%d \", harmony[i]);\n        puts(\"\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e2c3e7128815408d721d0a05203d1b3a", "src_uid": "f26c74f27bbc723efd69c38ad0e523c6", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define inf (1 << 25)\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nint factors[60] = {0};\nbool visited[32][1 << 17];\nint n, ar[32], harmony[32], dp[32][1 << 17], next[32][1 << 17];\nint primes[] = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59};\n\nvoid backtrack(int i, int bitmask){\n    if (i == n) return;\n    harmony[i] = next[i][bitmask];\n    backtrack(i + 1, bitmask | factors[harmony[i]]);\n}\n\nint F(int i, int bitmask){\n    if (i == n) return 0;\n    if (visited[i][bitmask]) return dp[i][bitmask];\n\n    int j, res = inf;\n    for (j = 1; j <= 60; j++){\n        if (!(bitmask & factors[j])){\n            int x = abs(ar[i] - j) + F(i + 1, bitmask | factors[j]);\n            if (x < res){\n                res = x;\n                next[i][bitmask] = j;\n            }\n        }\n    }\n\n    visited[i][bitmask] = true;\n    return (dp[i][bitmask] = res);\n}\n\nint main(){\n    int i, j;\n    for (i = 1; i <= 60; i++){\n        for (j = 0; j < 17; j++){\n            if ((i % primes[j]) == 0) factors[i] |= (1 << j);\n        }\n    }\n\n    while (scanf(\"%d\", &n) != EOF){\n        for (i = 0; i < n; i++) scanf(\"%d\", &ar[i]);\n        clr(visited);\n        int res = F(0, 0);\n        backtrack(0, 0);\n        for (i = 0; i < n; i++) printf(\"%d \", harmony[i]);\n        puts(\"\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "630a99c0b35f0d0820383e737e936a4a", "src_uid": "f26c74f27bbc723efd69c38ad0e523c6", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define inf (1 << 25)\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nint factors[65] = {0};\nbool visited[32][1 << 17];\nint n, ar[32], harmony[32], dp[32][1 << 17], next[32][1 << 17];\nint primes[] = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59};\n\nvoid backtrack(int i, int bitmask){\n    if (i == n) return;\n    harmony[i] = next[i][bitmask];\n    backtrack(i + 1, bitmask | factors[harmony[i]]);\n}\n\nint F(int i, int bitmask){\n    if (i == n) return 0;\n    if (visited[i][bitmask]) return dp[i][bitmask];\n\n    int j, res = inf;\n    for (j = 1; j <= 60; j++){\n        if (!(bitmask & factors[j])){\n            int x = abs(ar[i] - j) + F(i + 1, bitmask | factors[j]);\n            if (x < res){\n                res = x;\n                next[i][bitmask] = j;\n            }\n        }\n    }\n\n    visited[i][bitmask] = true;\n    return (dp[i][bitmask] = res);\n}\n\nint main(){\n    int i, j;\n    for (i = 1; i <= 60; i++){\n        for (j = 0; j < 17; j++){\n            if ((i % primes[j]) == 0) factors[i] |= (1 << j);\n        }\n    }\n\n    while (scanf(\"%d\", &n) != EOF){\n        for (i = 0; i < n; i++) scanf(\"%d\", &ar[i]);\n        clr(visited);\n        int res = F(0, 0);\n        backtrack(0, 0);\n        for (i = 0; i < n; i++) printf(\"%d \", harmony[i]);\n        puts(\"\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2fbe7d5b3aeb0bbba96fa7cb7ba879da", "src_uid": "f26c74f27bbc723efd69c38ad0e523c6", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    long long n;\n    scanf(\"%lld\", &n);\n    printf(\"%lld\\n\", (9*n-3)<<(2*n-6));\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b78f3f2c77442d60e1f1b15ee4607f5d", "src_uid": "3b02cbb38d0b4ddc1a6467f7647d53a9", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nunsigned long long power(unsigned long long, unsigned long long);\nint main()\n{\n    unsigned long long no_of_parking_positions, no_of_arrangements, four_power_n_minus_3;\n    scanf(\"%I64u\",&no_of_parking_positions);\n\n    four_power_n_minus_3 = power(4, no_of_parking_positions - 3);\n\n    no_of_arrangements = 6*(four_power_n_minus_3 * 4) + (no_of_parking_positions - 3)*9*(four_power_n_minus_3);\n    printf(\"%I64u\",no_of_arrangements);\n    return 0;\n}\n\nunsigned long long power(unsigned long long base, unsigned long long exponent)\n{\n    unsigned long long answer = 1;\n\n    if(exponent == 0)\n    {\n        return answer;\n    }\n\n    //Binary exponentiation algorithm. Number is squared as many times as the number of 0s in binary representation. x^5 = (x^2)^2*x\n    while(exponent > 0)\n    {\n        if(exponent%2 == 1)\n        {\n            answer = answer*base;\n        }\n        base = base*base;\n        exponent = exponent >> 1;\n    }\n    return answer;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6920ae649f5a0013810cb6edb74405bb", "src_uid": "3b02cbb38d0b4ddc1a6467f7647d53a9", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\nint main()\n{\n\tlong long int n;\n\tscanf(\"%lld\",&n);\n\tn=4*(2*3*pow(4LL,n-3LL)+(n-3LL)*3*3*pow(4LL,n-4LL));\n\tprintf(\"%lld\\n\",n);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2c4addfa79b3da2702db6e8eae41c330", "src_uid": "3b02cbb38d0b4ddc1a6467f7647d53a9", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include<math.h>\nint main (){\nlong long int n;\n\tscanf(\"%lld\",&n);\n\tn=4*(2*3*pow(4LL,n-3LL)+(n-3LL)*3*3*pow(4LL,n-4LL));\n\tprintf(\"%lld\\n\",n);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c16a895acab8e1ee31f92551a5a3f242", "src_uid": "3b02cbb38d0b4ddc1a6467f7647d53a9", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nlong long int power(long long int a,long long int b)\n{        \n         long long int res=1;\n         while(b!=0)\n         {\n                  if(b&1)\n                  res=res*a;\n                  a=a*a;\n                  b=b/2;\n         }\n         return res;\n}\nint main()\n{long long int n;\n         scanf(\"%lld\",&n);\n        long long int res=power(3,n-2)\n         res=res*2;\n         res=res*4;\n         printf(\"%lld\\n\",res);\n         \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "26289be553b22e9f887a1901757df535", "src_uid": "3b02cbb38d0b4ddc1a6467f7647d53a9", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint main()\n{\n    int n, m, i;\n    double p = 0, q = 0;\n    \n    scanf(\"%d\", &n);\n    \n    m = 4 * (n - 1) + 5;\n    \n    printf(\"%d\\n\", m);\n    \n    for (i = 0; i < n; i++) {\n        if (i == 0) printf(\"%.12lf %.12lf\\n\", p, q);\n        \n        printf(\"%.12lf %.12lf\\n\", p + 10 * sqrt(3), q);\n        printf(\"%.12lf %.12lf\\n\", p + 5 * sqrt(3), q + 5);\n        printf(\"%.12lf %.12lf\\n\", p + 5, -5 * sqrt(3));\n        printf(\"%.12lf %.12lf\\n\", p + 10 * sqrt(3) - 5, -5 * sqrt(3));\n        \n        p += 10 * sqrt(3);\n    }\n    \n    for (i = 0; i < n; i++) {\n        if (i == 0) {\n            printf(\"1\");\n        } else {\n            printf(\"%d\", i * 4 - 2);\n        }\n        \n        printf(\" %d %d %d %d\\n\", i * 4 + 2, i * 4 + 3, i * 4 + 4, i * 4 + 5);\n    }\n    \n    printf(\"1\");\n    \n    for (i = 0; i < n; i++) printf(\" %d\", i * 4 + 2);\n    \n    for (i = n - 1; i >= 0; i--) {\n        printf(\" %d %d %d\", i * 4 + 4, i * 4 + 3, i * 4 + 5);\n        \n        if (i == 0) {\n            printf(\" 1\");\n        } else {\n            printf(\" %d\", i * 4 - 2);\n        }\n    }\n    \n    puts(\"\");\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dbf6d6f99ee68aaa7d1b55bbcdb867a1", "src_uid": "db263b866e93e3a97731e11102923902", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <math.h>\n#include <stdio.h>\n\ndouble PI;\n\nint main() {\n\tstatic double xx[4], yy[4];\n\tint n, h, i;\n\tdouble a, ca, sa, c2a, s2a;\n\n\tPI = acos(-1);\n\tscanf(\"%d\", &n);\n\tprintf(\"%d\\n\", 1 + n * 4);\n\ta = PI * 2 / 5;\n\tca = cos(a), sa = sin(a);\n\tc2a = cos(a * 2), s2a = sin(a * 2);\n\txx[0] = -ca, yy[0] = sa;\n\txx[1] = 1 + ca + c2a, yy[1] = sa + s2a;\n\txx[2] = ca, yy[2] = sa;\n\txx[3] = 1, yy[3] = 0;\n\tprintf(\"0 0\\n\");\n\tfor (i = 0; i < n; i++)\n\t\tfor (h = 0; h < 4; h++) {\n\t\t\tdouble x = (xx[h] + i) * 10;\n\t\t\tdouble y = yy[h] * (i % 2 == 0 ? 10 : -10);\n\n\t\t\tprintf(\"%.8f %.8f\\n\", x, y);\n\t\t}\n\tfor (i = 0; i < n; i++)\n\t\tprintf(\"%d %d %d %d %d\\n\", i * 4 + 1, i * 4 + 2, i * 4 + 3, i * 4 + 4, i * 4 + 5);\n\tprintf(\"1\");\n\tfor (i = 0; i < n; i++)\n\t\tprintf(\" %d %d\", i * 4 + 3, i * 4 + 5);\n\tfor (i = n - 1; i >= 0; i--)\n\t\tprintf(\" %d %d %d\", i * 4 + 2, i * 4 + 4, i * 4 + 1);\n\tprintf(\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "17b4f7ac9c2898275872a0a096af6862", "src_uid": "db263b866e93e3a97731e11102923902", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <math.h>\n#include <stdio.h>\n\ndouble PI;\n\nint main() {\n\tstatic double xx[4], yy[4];\n\tint n, h, i;\n\tdouble a, ca, sa, c2a, s2a;\n\n\tPI = acos(-1);\n\tscanf(\"%d\", &n);\n\tprintf(\"%d\\n\", 1 + n * 4);\n\ta = PI * 2 / 5;\n\tca = cos(a), sa = sin(a);\n\tc2a = cos(a * 2), s2a = sin(a * 2);\n\txx[0] = -ca, yy[0] = sa;\n\txx[1] = 1 + ca + c2a, yy[1] = sa + s2a;\n\txx[2] = 1 + ca, yy[2] = sa;\n\txx[3] = 1, yy[3] = 0;\n\tprintf(\"%.9f %.9f\\n\", 0.0, 0.0);\n\tfor (i = 0; i < n; i++)\n\t\tfor (h = 0; h < 4; h++) {\n\t\t\tdouble x = (xx[h] + i) * 10;\n\t\t\tdouble y = yy[h] * (i % 2 == 0 ? 10 : -10);\n\n\t\t\tprintf(\"%.9f %.9f\\n\", x, y);\n\t\t}\n\tfor (i = 0; i < n; i++)\n\t\tprintf(\"%d %d %d %d %d\\n\", i * 4 + 1, i * 4 + 2, i * 4 + 3, i * 4 + 4, i * 4 + 5);\n\tprintf(\"1\");\n\tfor (i = 0; i < n; i++)\n\t\tprintf(\" %d %d\", i * 4 + 3, i * 4 + 5);\n\tfor (i = n - 1; i >= 0; i--)\n\t\tprintf(\" %d %d %d\", i * 4 + 2, i * 4 + 4, i * 4 + 1);\n\tprintf(\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "53103f3a65aeded52c0c139f6a20b283", "src_uid": "db263b866e93e3a97731e11102923902", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint main()\n{\n    int n, m, i;\n    double p = 0, q = 0;\n    double pi = acos(-1);\n    double x = (1 + sqrt(5)) / 2;\n    \n    scanf(\"%d\", &n);\n    \n    m = 4 * (n - 1) + 5;\n    \n    printf(\"%d\\n\", m);\n    \n    for (i = 0; i < n; i++) {\n        if (i == 0) printf(\"%.12lf %.12lf\\n\", p, q);\n        \n        printf(\"%.12lf %.12lf\\n\", p + 10 * x, q);\n        printf(\"%.12lf %.12lf\\n\", p + 5 * x, 10 * cos(54 * pi / 180));\n        printf(\"%.12lf %.12lf\\n\", p + 10 * cos(72 * pi / 180), -10 * sin(72 * pi / 180));\n        printf(\"%.12lf %.12lf\\n\", p + 10 * x - 10 * cos(72 * pi / 180), -10 * sin(72 * pi / 180));\n        \n        p += 10 * x;\n    }\n    \n    for (i = 0; i < n; i++) {\n        if (i == 0) {\n            printf(\"1\");\n        } else {\n            printf(\"%d\", i * 4 - 2);\n        }\n        \n        printf(\" %d %d %d %d\\n\", i * 4 + 4, i * 4 + 5, i * 4 + 2, i * 4 + 3);\n    }\n    \n    printf(\"1\");\n    \n    for (i = 0; i < n; i++) printf(\" %d\", i * 4 + 2);\n    \n    for (i = n - 1; i >= 0; i--) {\n        printf(\" %d %d %d\", i * 4 + 4, i * 4 + 3, i * 4 + 5);\n        \n        if (i == 0) {\n            printf(\" 1\");\n        } else {\n            printf(\" %d\", i * 4 - 2);\n        }\n    }\n    \n    puts(\"\");\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "46881eb98679d15b305003462742b14e", "src_uid": "db263b866e93e3a97731e11102923902", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <math.h>\n\nint main()\n{\n    int n, m, i;\n    double p = 0, q = 0;\n    double pi = acos(-1);\n    double x = (1 + sqrt(5)) / 2;\n    \n    scanf(\"%d\", &n);\n    \n    m = 4 * (n - 1) + 5;\n    \n    printf(\"%d\\n\", m);\n    \n    for (i = 0; i < n; i++) {\n        if (i == 0) printf(\"%.12lf %.12lf\\n\", p, q);\n        \n        printf(\"%.12lf %.12lf\\n\", p + 10 * x, q);\n        printf(\"%.12lf %.12lf\\n\", p + 5 * x, 10 * cos(54 * pi / 180));\n        printf(\"%.12lf %.12lf\\n\", p + 10 * cos(72 * pi / 180), -10 * sin(72 * pi / 180));\n        printf(\"%.12lf %.12lf\\n\", p + 10 * x - 10 * cos(72 * pi / 180), -10 * sin(72 * pi / 180));\n        \n        p += 10 * x;\n    }\n    \n    for (i = 0; i < n; i++) {\n        if (i == 0) {\n            printf(\"1\");\n        } else {\n            printf(\"%d\", i * 4 - 2);\n        }\n        \n        printf(\" %d %d %d %d\\n\", i * 4 + 4, i * 4 + 5, i * 4 + 2, i * 4 + 3);\n    }\n    \n    printf(\"1\");\n    \n    for (i = 0; i < n; i++) printf(\" %d\", i * 4 + 2);\n    \n    for (i = n - 1; i >= 0; i--) {\n        printf(\" %d %d %d\", i * 4 + 4, i * 4 + 3, i * 4 + 5);\n        \n        if (i == 0) {\n            printf(\" 1\");\n        } else {\n            printf(\" %d\", i * 4 - 2);\n        }\n    }\n    \n    puts(\"\");\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "84909c404157298f2902b2a2a4cf35ce", "src_uid": "db263b866e93e3a97731e11102923902", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#define MAX 300\nint win[301][301];\nvoid solve(int a,int b){\n\tint i,j,k,l;\n\tfor(i=1;i<=a;i++){\n\t\tfor(j=1;j<=b;j++){\n\t\t\tint mink = (i>j)?j:i;\n\t\t\tfor(k=1;k<=mink;k++)\n\t\t\t\tif(win[i-k][j-k]==0){\n\t\t\t\t\twin[i][j]=1;break;}\n\t\t\tif(win[i][j]==0){\n\t\t\tfor(l=1;l<=i;l++)\n\t\t\t\tif(win[i-l][j]==0){\n\t\t\t\t\twin[i][j]=1;break;}\n\t\t\t\t\t\n\t\t\t}\n\t\t\tif(win[i][j]==0){\n\t\t\tfor(l=1;l<=j;l++)\n\t\t\t\tif(win[i][j-l]==0){\n\t\t\t\t\twin[i][j]=1;break;}\n\t\t\t\t\t\n\t\t\t}\n\t\t}\n\t\t\t\n\t}\n}\nint main(){\n\tint n,a,b,c,i,j,k;\n\twin[0][0]=0;\n\twin[1][1]=1;\n\twin[1][0]=1;\n\twin[0][1]=1;\n\twin[2][0]=1;\n\twin[0][2]=1;\n\tfor(i=1;i<=300;i++){\n\t\twin[i][0]=1;win[0][i]=1;\n\t}\n\tsolve(300,300);\n\t//for(i=0;i<=10;i++){\n\t//\tfor(j=0;j<=10;j++)\n\t//\t\tprintf(\"%d \",win[i][j]);\n\t//printf(\"\\n\");\t\n\t//}\n\tscanf(\"%d\",&n);\n\t\tif(n==1){\n\t\t\tscanf(\"%d\",&a);\n\t\t\tif(a==0)\n\t\t\t\tprintf(\"BitAryo\");\n\t\t\telse\n\t\t\t\tprintf(\"BitLGM\");\n\t\t}\n\t\telse if(n==2){\n\t\t\tscanf(\"%d %d\",&a,&b);\n\t\t\tif(win[a][b])\n\t\t\t\tprintf(\"BitLGM\");\n\t\t\telse\n\t\t\t\tprintf(\"BitAryo\");\n\t\t}\n\t\telse if(n==3){\n\t\t\tscanf(\"%d %d %d\",&a,&b,&c);\n\t\t\tif((a^b^c)!=0)printf(\"BitLGM\");\n\t\t\telse\n\t\t\t\tprintf(\"BitAryo\");\n\t\t}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c1a26704b37a169f8fc55586a292bd7b", "src_uid": "7a33b4f94082c7ef80d7e87b58497fa7", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint n;\nint a[3];\nchar dp[300*300*300];\nlong long step = 0;\n\nvoid calculate_result(int index, long long index1){\n    if(index >= n){\n        if(index1 == 0){\n           dp[0] = 0;\n           return;\n        }\n        int i, min = 300,j;\n        long long index2 = index1;\n        for(i=0;i<n;i++){\n            min = (min > (index2 % 300) ) ? (index2 % 300) : min;\n            index2 /= 300;\n        }\n        int win = 0;\n        for(i=1;i<=min;i++){\n            if(dp[index1 - i*step] == 0){\n                win = 1;\n                break;\n            }\n        }\n        index2 = index1;\n        long long pos = 1;\n        if(win == 0){\n            for(i=0;i<n;i++){\n                int num = index2 % 300;\n                for(j=1;j<=num;j++){\n                    if(dp[index1 - pos*j] == 0){\n                        win = 1;\n                        break;\n                    }\n                }\n                if( win == 1 )\n                    break;\n                index2 /= 300;\n                pos *= 300;\n            }\n        }\n        if(win == 1)\n            dp[index1] = 1;\n        return;\n    }\n    int i;\n    for(i=0;i<=a[index];i++){\n        calculate_result(index+1, index1*300 + i);\n    }\n}\n\nint main(){\n    scanf(\"%d\", &n);\n    int i;\n    for(i=0;i<n;i++)\n        scanf(\"%d\", &a[i]);\n    memset(dp, 0, sizeof(char)*300*300*300);\n    for(i=0;i<n;i++)\n        step = step*300 + 1;\n    calculate_result(0,0);\n    long long ans_index = 0;\n    for(i=0;i<n;i++){\n        ans_index = ans_index*300 + a[i];\n    }\n    if(dp[ans_index] == 1){\n        printf(\"BitLGM\\n\");\n    }\n    else{\n        printf(\"BitAryo\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6c28cc7738cd5ca5244f50b51ad6db24", "src_uid": "7a33b4f94082c7ef80d7e87b58497fa7", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#define MAX 300\nint win[301][301];\nvoid solve(int a,int b){\n\tint i,j,k,l;\n\tfor(i=1;i<=a;i++){\n\t\tfor(j=1;j<=b;j++){\n\t\t\tfor(k=1;k<=i;k++)\n\t\t\t\tif(win[i-k][j-k]==0){\n\t\t\t\t\twin[i][j]=1;break;}\n\t\t\tif(win[i][j]==0){\n\t\t\tfor(l=1;l<=i;l++)\n\t\t\t\tif(win[i-l][j]==0){\n\t\t\t\t\twin[i][j]=1;break;}\n\t\t\t\t\t\n\t\t\t}\n\t\t\tif(win[i][j]==0){\n\t\t\tfor(l=1;l<=j;l++)\n\t\t\t\tif(win[i][j-l]==0){\n\t\t\t\t\twin[i][j]=1;break;}\n\t\t\t\t\t\n\t\t\t}\n\t\t}\n\t\t\t\n\t}\n}\nint main(){\n\tint n,a,b,c,i,j,k;\n\twin[0][0]=0;\n\twin[1][1]=1;\n\twin[1][0]=1;\n\twin[0][1]=1;\n\twin[2][0]=1;\n\twin[0][2]=1;\n\tfor(i=1;i<=300;i++){\n\t\twin[i][0]=1;win[0][i]=1;\n\t}\n\tsolve(300,300);\n\t//for(i=0;i<=10;i++){\n\t//\tfor(j=0;j<=10;j++)\n\t//\t\tprintf(\"%d \",win[i][j]);\n\t//printf(\"\\n\");\t\n\t//}\n\tscanf(\"%d\",&n);\n\t\tif(n==1){\n\t\t\tscanf(\"%d\",&a);\n\t\t\tif(n==0)\n\t\t\t\tprintf(\"BitAryo\");\n\t\t\telse\n\t\t\t\tprintf(\"BitLGM\");\n\t\t}\n\t\telse if(n==2){\n\t\t\tscanf(\"%d %d\",&a,&b);\n\t\t\tif(win[a][b])\n\t\t\t\tprintf(\"BitLGM\");\n\t\t\telse\n\t\t\t\tprintf(\"BitAryo\");\n\t\t}\n\t\telse if(n==3){\n\t\t\tscanf(\"%d %d %d\",&a,&b,&c);\n\t\t\tif((a^b^c)!=0)printf(\"BitLGM\");\n\t\t\telse\n\t\t\t\tprintf(\"BitAryo\");\n\t\t}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5a94388f7dbf652ed066205d86576bd0", "src_uid": "7a33b4f94082c7ef80d7e87b58497fa7", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#define MAX 300\nint win[301][301];\nvoid solve(int a,int b){\n\tint i,j,k,l;\n\tfor(i=1;i<=a;i++){\n\t\tfor(j=1;j<=b;j++){\n\t\t\tfor(k=1;k<=i;k++)\n\t\t\t\tif(win[i-k][j-k]==0){\n\t\t\t\t\twin[i][j]=1;break;}\n\t\t\tif(win[i][j]==0){\n\t\t\tfor(l=1;l<=i;l++)\n\t\t\t\tif(win[i-l][j]==0)\n\t\t\t\t\twin[i][j]=1;break;\n\t\t\t\t\t\n\t\t\t}\n\t\t\tif(win[i][j]==0){\n\t\t\tfor(l=1;l<=j;l++)\n\t\t\t\tif(win[i][j-l]==0)\n\t\t\t\t\twin[i][j]=1;break;\n\t\t\t\t\t\n\t\t\t}\n\t\t}\n\t\t\t\n\t}\n}\nint main(){\n\tint n,a,b,c,i,j,k;\n\twin[0][0]=0;\n\twin[1][1]=1;\n\twin[1][0]=1;\n\twin[0][1]=1;\n\twin[2][0]=1;\n\twin[0][2]=1;\n\tfor(i=1;i<=300;i++){\n\t\twin[i][0]=1;win[0][i]=1;\n\t}\n\tsolve(300,300);\n\t//for(i=0;i<=10;i++){\n\t//\tfor(j=0;j<=10;j++)\n\t//\t\tprintf(\"%d \",win[i][j]);\n\t//printf(\"\\n\");\t\n\t//}\n\tscanf(\"%d\",&n);\n\t\tif(n==1){\n\t\t\tscanf(\"%d\",&a);\n\t\t\tif(n==0)\n\t\t\t\tprintf(\"BitAryo\");\n\t\t\telse\n\t\t\t\tprintf(\"BitLGM\");\n\t\t}\n\t\telse if(n==2){\n\t\t\tscanf(\"%d %d\",&a,&b);\n\t\t\tif(win[a][b])\n\t\t\t\tprintf(\"BitLGM\");\n\t\t\telse\n\t\t\t\tprintf(\"BitAryo\");\n\t\t}\n\t\telse if(n==3){\n\t\t\tscanf(\"%d %d %d\",&a,&b,&c);\n\t\t\tif((a^b^c)!=0)printf(\"BitLGM\");\n\t\t\telse\n\t\t\t\tprintf(\"BitAryo\");\n\t\t}\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2ca38f53db30e646db7b1f2961abb800", "src_uid": "7a33b4f94082c7ef80d7e87b58497fa7", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\n#define A\t300\n\nint solve2(int a1, int a2) {\n\tstatic char dp[A + 1][A + 1];\n\tint i1, i2, i;\n\n\tdp[0][0] = 0;\n\tfor (i1 = 0; i1 <= a1; i1++)\n\t\tfor (i2 = 0; i2 <= a2; i2++) {\n\t\t\tif (dp[i1][i2])\n\t\t\t\tcontinue;\n\t\t\tfor (i = 1; i1 + i <= a1; i++)\n\t\t\t\tdp[i1 + i][i2] = 1;\n\t\t\tfor (i = 1; i2 + i <= a2; i++)\n\t\t\t\tdp[i1][i2 + i] = 1;\n\t\t\tfor (i = 1; i1 + i <= a1 && i2 + i <= a2; i++)\n\t\t\t\tdp[i1 + i][i2 + i] = 1;\n\t\t}\n\treturn dp[a1][a2];\n}\n\nint solve3(int a1, int a2, int a3) {\n\tstatic char dp[A + 1][A + 1][A + 1];\n\tint i1, i2, i3, i;\n\n\tdp[0][0][0] = 0;\n\tfor (i1 = 0; i1 <= a1; i1++)\n\t\tfor (i2 = 0; i2 <= a2; i2++)\n\t\t\tfor (i3 = 0; i3 <= a2; i3++) {\n\t\t\t\tif (dp[i1][i2][i3])\n\t\t\t\t\tcontinue;\n\t\t\t\tfor (i = 1; i1 + i <= a1; i++)\n\t\t\t\t\tdp[i1 + i][i2][i3] = 1;\n\t\t\t\tfor (i = 1; i2 + i <= a2; i++)\n\t\t\t\t\tdp[i1][i2 + i][i3] = 1;\n\t\t\t\tfor (i = 1; i3 + i <= a3; i++)\n\t\t\t\t\tdp[i1][i2][i3 + i] = 1;\n\t\t\t\tfor (i = 1; i1 + i <= a1 && i2 + i <= a2 && i3 + i <= a3; i++)\n\t\t\t\t\tdp[i1 + i][i2 + i][i3 + i] = 1;\n\t\t\t}\n\treturn dp[a1][a2][a3];\n}\n\nint main() {\n\tint n, a1, a2, a3;\n\n\tscanf(\"%d%d\", &n, &a1);\n\tif (n == 1) {\n\t\tprintf(a1 ? \"BitLGM\\n\" : \"BitAryo\\n\");\n\t\treturn 0;\n\t}\n\tscanf(\"%d\", &a2);\n\tif (n == 2) {\n\t\tprintf(solve2(a1, a2) ? \"BitLGM\\n\" : \"BitAryo\\n\");\n\t\treturn 0;\n\t}\n\tscanf(\"%d\", &a3);\n\tprintf(solve3(a1, a2, a3) ? \"BitLGM\\n\" : \"BitAryo\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3028eab99d0f8b488ee07c34d14fad54", "src_uid": "7a33b4f94082c7ef80d7e87b58497fa7", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define __STDC_FORMAT_MACROS\n#include <inttypes.h>\n\n// if we write f(x) = Sum([0,n+1], bi * x^i) and q(x) = Sum([0,n], ai * x^i) and then so multiplication and equate left and right sides:\n// b[n+1] = a[n]\n// b[i]   = K*a[i] + a[i-1]\n// b[0]   = K*a[0] + P\n// from here it is easy to see that all ai should be integer (going n+1 -> 0 and knowing that bi are integers)\n\n\n// TODO: ???\n#define MAX_D 5000\nstatic int64_t _a[MAX_D+2] = {}, _b[MAX_D+2] = {};\n\n\nint main() {\n    int64_t P,K; scanf(\"%\" PRId64 \" %\" PRId64 \"\\n\", &P,&K);\n\n    // offset, to include P as a[-1]\n    _a[0] = P; int D = 0;\n    for( ; D <= MAX_D ; ++D) {\n        // b[i] = K*a[i] + a[i-1] < K\n        // say, a[i-1] = x*K+y (y < K), then we can write\n        // b[i] = K*(a[i] + x) + y < K, and from there a[i] = -x, and b[i] = y\n        // NB we want non-c modulo, but math (where rem is non-negative)\n        int64_t x = _a[D] / K, y = _a[D] % K;\n        if(y < 0) { y += K, --x; }\n        _a[D+1] = -x, _b[D] = y;\n        // TODO:\n        if(_a[D] == 0) break;\n    }\n\n    printf(\"%d\\n\", D);\n    for(int i = 0 ; i < D ; ++i) printf(\"%\" PRId64 \" \", _b[i]);\n    printf(\"\\n\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c0cb25a59554a13b97bb47bceb4c5e9c", "src_uid": "f4dbaa8deb2bd5c054fe34bb83bc6cd5", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define __STDC_FORMAT_MACROS\n#include <inttypes.h>\n\n// if we write f(x) = Sum([0,n+1], bi * x^i) and q(x) = Sum([0,n], ai * x^i) and then so multiplication and equate left and right sides:\n// b[n+1] = a[n]\n// b[i]   = K*a[i] + a[i-1]\n// b[0]   = K*a[0] + P\n// from here it is easy to see that all ai should be integer (going n+1 -> 0 and knowing that bi are integers)\n\n\n// TODO: ???\n#define MAX_D 5000\nstatic int64_t _a[MAX_D+2] = {}, _b[MAX_D+2] = {};\n\n\nint main() {\n    int64_t P,K; scanf(\"%\" PRId64 \" %\" PRId64 \"\\n\", &P,&K);\n\n    // offset, to include P as a[-1]\n    _a[0] = P; int D = 0;\n    for( ; D <= MAX_D ; ++D) {\n        // b[i] = K*a[i] + a[i-1] < K\n        // say, a[i-1] = x*K+y (y < K), then we can write\n        // b[i] = K*(a[i] + x) + y < K, and from there a[i] = -x, and b[i] = y\n        // NB we want non-c modulo, but math (where rem is non-negative)\n        int64_t x = _a[D] / K, y = _a[D] % K;\n        if(y < 0) { y += K, --x; }\n        _a[D+1] = -x, _b[D] = y;\n        // TODO:\n        if(_a[D] == 0) break;\n    }\n\n    printf(\"%d\\n\", D);\n    for(int i = 0 ; i < D ; ++i) printf(\"%\" PRId64 \" \", _b[i]);\n    printf(\"\\n\");\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d0069f7bfa04282c10a8fc063d6c2ee0", "src_uid": "f4dbaa8deb2bd5c054fe34bb83bc6cd5", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define MX 1000\nlong long int p,k,k1=1,sm,A[MX];\nint main(){\n    int i,j,sz;\n    long long int ims;\n    //freopen(\"input.txt\",\"r\",stdin);\n    //freopen(\"output.txt\",\"w\",stdout);\n    scanf(\"%lld%lld\",&p,&k);\n    for(sz=0;;sz+=2){\n        ims=p%(k*k);\n        p=p/(k*k);\n        if(ims>=k){\n            p++;\n            A[sz]=ims%k;\n            A[sz+1]=k-(ims/k);\n        }\n        else{\n            A[sz]=ims;\n        }\n        if(p==0){break;}\n    }\n    printf(\"%d\\n\",sz+1);\n    for(i=0;i<=sz;i++){\n        printf(\"%lld \",A[i]);\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bb58609069f6a6cc7bd0f1e13f11ae74", "src_uid": "f4dbaa8deb2bd5c054fe34bb83bc6cd5", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#import<stdio.h>\n#define swap(a,b) (a)^=(b)^=(a)^=(b)\n#define max(a,b) ((a)>(b)?(a):(b))\n#define min(a,b) ((a)<(b)?(a):(b))\nlong long gcd(long long a,long long b) {return !b?a:gcd(b,a%b);}\nint main()\n{\n\tlong long l1,r1,t1,l2,r2,t2;\n\tscanf(\"%lld%lld%lld%lld%lld%lld\",&l1,&r1,&t1,&l2,&r2,&t2);\n\tif (l1>l2) swap(l1,l2),swap(r1,r2),wwap(t1,t2);\n\tlong long k=gcd(t1,t2),p,ans=0;\n\tp=(l2-l1)/k;l1+=k*p,r1+=k*p;\n\tans=max(ans,(min(r1,r2)-max(l1,l2))+1);\n\tl1+=k,r1+=k;\n\tans=max(ans,(min(r1,r2)-max(l1,l2))+1);\n\tprintf(\"%lld\\n\",ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9189f2316170cdde5aefc33fd9795b65", "src_uid": "faa75751c05c3ff919ddd148c6784910", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#import<stdio.h>\n#define swap(a,b) (a)^=(b)^=(a)^=(b)\n#define max(a,b) ((a)>(b)?(a):(b))\n#define min(a,b) ((a)<(b)?(a):(b))\nlong long gcd(long long a,long long b) {return !b?a:gcd(b,a%b);}\nint main()\n{\n\tlong long l1,r1,t1,l2,r2,t2;\n\tscanf(\"%lld%lld%lld%lld%lld%lld\",&l1,&r1,&t1,&l2,&r2,&t2);\n\tif (l1>l2) swap(l1,l2),swap(r1,r2),swap(t1,t2);\n\tlong long k=gcd(t1,t2),p,ans=0;\n\tp=(l2-l1)/k;l1+=k*p,r1+=k*p;\n\tans=max(ans,(min(r1,r2)-max(l1,l2))+1);\n\tl1+=k,r1+=k;\n\tans=max(ans,(min(r1,r2)-max(l1,l2))+1);\n\tprintf(\"%lld\\n\",ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "455482b7676c1f6d1974359a06176b7c", "src_uid": "faa75751c05c3ff919ddd148c6784910", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint lucky(int x)\n{\n    while (x) {\n\tif (x % 10 != 4 && x % 10 != 7) break;\n\n\tx /= 10;\n    }\n\n    if (x == 0) {\n\treturn 1;\n    } else {\n\treturn 0;\n    }\n}\n\nint fact(int n)\n{\n    int x = 1, i;\n\n    for (i = 1; i <= n; i++) x *= i;\n\n    return x;\n}\n\nint main()\n{\n    int n, k, p = 0, q = 2, r = 2, sum = 0, i, j;\n    long long x = 1;\n    int a[10000], b[100];\n\n    scanf(\"%d %d\", &n, &k);\n\n    a[0] = 4;\n    a[1] = 7;\n\n    for (i = 0; i < 8; i++) {\n\tfor (j = p; j < q; j++) {\n\t    a[r++] = a[j] * 10 + 4;\n\t    a[r++] = a[j] * 10 + 7;\n\t}\n\n\tp = q;\n\tq = r;\n    }\n\n    for (i = 1; i <= n; i++) {\n\tx *= i;\n\n\tif (x >= k) break;\n    }\n\n    if (i > n) {\n\tputs(\"-1\");\n\n\treturn 0;\n    }\n\n    if (x == k) i++;\n\n    for (j = 0; j < r; j++) {\n\tif (a[j] > n - i) break;\n\n\tsum++;\n    }\n\n    if (x == k) {\n\tfor (j = n - i + 3; j <= n; j++) {\n\t    if (lucky(j) == 1) sum++;\n\t}\n\n\tprintf(\"%d\\n\", sum);\n\n\treturn 0;\n    }\n\n    q = 0;\n\n    for (j = n - i + 1; j <= n; j++) b[q++] = j;\n\n    for (j = n - i + 1; j < n; j++) {\n\tp = k / fact(n - j);\n\n\tif (k % fact(n - j) == 0) p--;\n\n\tif (lucky(j) == 1 && lucky(b[p]) == 1) sum++;\n\n\tfor (i = p; i < q; i++) b[i] = b[i + 1];\n\n\tk -= p * fact(n - j);\n    }\n\n    if (lucky(n) == 1 && lucky(b[0]) == 1) sum++;\n\n    printf(\"%d\\n\", sum);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "51c13f72da35ec72d2d4da881a9695b8", "src_uid": "cb2aa02772f95fefd1856960b6ceac4c", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#define min(a, b) ((a < b) ? (a) : (b))\n#define max(a, b) ((a > b) ? (a) : (b))\n\nint l = 1, r, answ, t = 1;\nlong long a[11];\nlong long ans[2048];\nint b[13], use[13];\nint n, m, k;\n\nint\nanalyze(void)\n{\n    int i, nonzero = 0;\n    long long tmp = 0;\n    for(i = 10; i >= 0; --i){\n        if(a[i] == 0 && nonzero){\n            return 1;\n        }\n        tmp = tmp * 10 + a[i];\n        if (a[i] != 0){\n            nonzero = 1;\n        }\n    }\n    if(tmp >= r){\n        ans[n++] = tmp;\n        return 0;\n    }\n    if(tmp >= l){\n        ans[n++] = tmp;\n    }\n    return 1;\n}\n\nvoid\ngo(int i)\n{\n    if(!t){\n        return;\n    }\n    if (i == -1){\n        t = analyze();\n        return;\n    }\n    a[i] = 0;\n    go(i - 1);\n    a[i] = 4;\n    go(i - 1);\n    a[i] = 7;\n    go(i - 1);\n}\n\nvoid\ngen(int n, int p, int k){\nif(p > 0){\n    int i, ans = 1;\n    for(i = 1; i <= p - 1; ++i){\n        ans *= i;\n    }\n    int tmp = k / ans;\n    if(k % ans == 0){\n        --tmp;\n    }\n    for(i = 0; ; ++i){\n        if(use[i] == 0){\n            if(tmp > 0){\n                --tmp;\n            } else {\n                use[i] = 1;\n                b[n - p] = i;\n                break;\n            }\n        }\n    }\n    gen(n, p - 1, k % ans ? k % ans : ans);\n}\n}\n\nint\nmain(void)\n{\n    scanf(\"%d%d\", &m, &k);\n    r = m;\n    go(10);\n    answ = 0;\n    int i, j, q;\n    for(i = 0; ans[i] <= m - 13; ++i){\n        ++answ;\n    }\n    gen(min(13, m), min(13, m), k);\n    for(i = 0; i < min(13, m); ++i){\n        b[i] += max(1, m - 12);\n    }\n    for(i = max(1, m - 12); i <= m; ++i){\n        for(j = 0; j < n; ++j){\n            if(ans[j] == i){\n                for(q = 0; q < n; ++q){\n                    if(b[i - max(1, m - 12)] == ans[q]){\n                        ++ answ;\n                    }\n                }\n            }\n        }\n    }\n    printf(\"%d\", answ);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8bbc890a8dfb6a14fc6d77e1d6319d3f", "src_uid": "cb2aa02772f95fefd1856960b6ceac4c", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint lucky(int x)\n{\n    while (x) {\n\tif (x % 10 != 4 && x % 10 != 7) break;\n\n\tx /= 10;\n    }\n\n    if (x == 0) {\n\treturn 1;\n    } else {\n\treturn 0;\n    }\n}\n\nint fact(int n)\n{\n    int x = 1, i;\n\n    for (i = 1; i <= n; i++) x *= i;\n\n    return x;\n}\n\nint main()\n{\n    int n, k, p = 0, q = 2, r = 2, sum = 0, i, j;\n    long long x = 1;\n    int a[10000], b[100];\n\n    scanf(\"%d %d\", &n, &k);\n\n    a[0] = 4;\n    a[1] = 7;\n\n    for (i = 0; i < 8; i++) {\n\tfor (j = p; j < q; j++) {\n\t    a[r++] = a[j] * 10 + 4;\n\t    a[r++] = a[j] * 10 + 7;\n\t}\n\n\tp = q;\n\tq = r;\n    }\n\n    for (i = 1; i <= n; i++) {\n\tx *= i;\n\n\tif (x >= k) break;\n    }\n\n    if (i > n) {\n\tputs(\"-1\");\n\n\treturn 0;\n    }\n\n    for (j = 0; j < r; j++) {\n\tif (a[j] > n - i) break;\n\n\tsum++;\n    }\n\n    q = 0;\n\n    for (j = n - i + 1; j <= n; j++) b[q++] = j;\n\n    for (j = n - i + 1; j < n; j++) {\n\tp = k / fact(n - j);\n\n\tif (k % fact(n - j) == 0) p--;\n\n\tif (lucky(j) == 1 && lucky(b[p]) == 1) sum++;\n\n\tfor (i = p; i < q; i++) b[i] = b[i + 1];\n\n\tk -= p * fact(n - j);\n    }\n\n    if (lucky(n) == 1 && lucky(b[0]) == 1) sum++;\n\n    printf(\"%d\\n\", sum);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "38de87505a792dfa386fe2b06ca496be", "src_uid": "cb2aa02772f95fefd1856960b6ceac4c", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#define min(a, b) ((a < b) ? (a) : (b))\n#define max(a, b) ((a > b) ? (a) : (b))\n\nint l = 1, r, answ, t = 1;\nlong long a[11];\nlong long ans[2048];\nint b[13], use[13];\nint n, m, k;\n\nint\nanalyze(void)\n{\n    int i, nonzero = 0;\n    long long tmp = 0;\n    for(i = 10; i >= 0; --i){\n        if(a[i] == 0 && nonzero){\n            return 1;\n        }\n        tmp = tmp * 10 + a[i];\n        if (a[i] != 0){\n            nonzero = 1;\n        }\n    }\n    if(tmp >= r){\n        ans[n++] = tmp;\n        return 0;\n    }\n    if(tmp >= l){\n        ans[n++] = tmp;\n    }\n    return 1;\n}\n\nvoid\ngo(int i)\n{\n    if(!t){\n        return;\n    }\n    if (i == -1){\n        t = analyze();\n        return;\n    }\n    a[i] = 0;\n    go(i - 1);\n    a[i] = 4;\n    go(i - 1);\n    a[i] = 7;\n    go(i - 1);\n}\n\nvoid\ngen(int n, int p, int k){\nif(p > 0){\n    int i, ans = 1;\n    for(i = 1; i <= p - 1; ++i){\n        ans *= i;\n    }\n    int tmp = k / ans;\n    if(k % ans == 0){\n        --tmp;\n    }\n    if (tmp >= n){\n        printf(\"-1\");\n        m = -1;\n        return;\n    }\n    for(i = 0; ; ++i){\n        if(use[i] == 0){\n            if(tmp > 0){\n                --tmp;\n            } else {\n                use[i] = 1;\n                b[n - p] = i;\n                break;\n            }\n        }\n    }\n    gen(n, p - 1, k % ans ? k % ans : ans);\n}\n}\n\nint\nmain(void)\n{\n    scanf(\"%d%d\", &m, &k);\n    r = m;\n    go(10);\n    answ = 0;\n    int i, j, q;\n    for(i = 0; ans[i] <= m - 13; ++i){\n        ++answ;\n    }\n    gen(min(13, m), min(13, m), k);\n    if(m == -1){\n        return 0;\n    }\n    for(i = 0; i < min(13, m); ++i){\n        b[i] += max(1, m - 12);\n    }\n    for(i = max(1, m - 12); i <= m; ++i){\n        for(j = 0; j < n; ++j){\n            if(ans[j] == i){\n                for(q = 0; q < n; ++q){\n                    if(b[i - max(1, m - 12)] == ans[q]){\n                        ++ answ;\n                    }\n                }\n            }\n        }\n    }\n    printf(\"%d\", answ);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8896f2b45a7ad6b178249e9b510f250f", "src_uid": "cb2aa02772f95fefd1856960b6ceac4c", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n#include <string.h>\n\n#define N\t13\n\nlong long lucky(int b) {\n\treturn b == 1 ? 0 : lucky(b / 2) * 10 + (b % 2 == 0 ? 4 : 7);\n}\n\nint is_lucky(int y) {\n\treturn y == 0 ? 1 : is_lucky(y / 10) && (y % 10 == 4 || y % 10 == 7);\n}\n\nint ff[N];\n\nvoid init() {\n\tint i, f;\n\n\tf = 1;\n\tfor (i = 0; i < N; i++) {\n\t\tff[i] = f;\n\t\tf *= i + 1;\n\t}\n}\n\nint get(int n, int k, int i) {\n\tstatic char used[N];\n\tint h, j;\n\n\tmemset(used, 0, n * sizeof *used);\n\tfor (h = 0; h < n; h++) {\n\t\tint f = ff[n - 1 - h], s = k / f;\n\n\t\tfor (j = 0; j < n; j++)\n\t\t\tif (!used[j] && s-- == 0) {\n\t\t\t\tif (h == i)\n\t\t\t\t\treturn j;\n\t\t\t\tused[j] = 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\tk %= f;\n\t}\n\treturn -1;\n}\n\nint main() {\n\tint n, n_, k, b, ans;\n\tlong long f;\n\n\tinit();\n\tscanf(\"%d%d\", &n, &k);\n\tf = 1;\n\tn_ = 1;\n\twhile (f < k)\n\t\tf *= ++n_;\n\tif (n_ > n) {\n\t\tprintf(\"-1\\n\");\n\t\treturn 0;\n\t}\n\tans = 0;\n\tfor (b = 2; ; b++) {\n\t\tlong long x = lucky(b);\n\t\tint y;\n\n\t\tif (x > n)\n\t\t\tbreak;\n\t\tif (x <= n - n_) {\n\t\t\tans++;\n\t\t\tcontinue;\n\t\t}\n\t\ty = n - n_ + get(n_, k - 1, x - (n - n_) - 1) + 1;\n\t\tif (is_lucky(y))\n\t\t\tans++;\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a9158f0abad440f34556b61a7d845bab", "src_uid": "cb2aa02772f95fefd1856960b6ceac4c", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define N 1050000\n#define M 2300000\n#define T 1048576\nint n,m;\nint first[M];\nint second[M];\nint last[N];\nint wei[N];\nint pei[N];\nint ans[N];\nvoid add(int a[],int x)\n{\n    x+=T-1;\n    while(x)\n    {\n        a[x]++;\n        x>>=1;\n    }\n}\nvoid del(int a[],int x)\n{\n    x+=T-1;\n    while(x)\n    {\n        a[x]--;\n        x>>=1;\n    }\n}\nint find(int a[],int now,int l,int r,int x)\n{\n    if(l==r)\n        return l;\n    int mid=(l+r)/2;\n    if(x<=a[now<<1])\n        return( find(a,now<<1,l,mid,x) );\n    return( find(a,now*2+1,mid+1,r,x-a[now<<1]) );\n}\nint main()\n{\n    int i,a,b;\n    scanf(\"%d%d\",&n,&m);\n    for(i=1;i<=n;i++)\n        add(second,i);\n    for(i=1;i<=m;i++)\n    {\n        scanf(\"%d%d\",&a,&b);\n        if(first[1]>=b)\n            b=wei[find(first,1,1,T,first[1]-b+1)];\n        else\n            b=find(second,1,1,T,b-first[1]);\n        if(ans[b]==a)\n        {\n            wei[i]=b;\n            del(first,last[b]);\n            last[b]=i;\n            add(first,i);\n            continue;\n        }\n        if(ans[b] || pei[a])\n        {\n            printf(\"-1\\n\");\n            return 0;\n        }\n        ans[b]=a;\n        pei[a]=b;\n        last[b]=i;\n        wei[i]=b;\n        del(second,b);\n        add(first,i);\n    }\n    int now=0;\n    for(i=1;i<=n;i++)\n        if(!ans[i])\n        {\n            now++;\n            while(pei[now])\n                now++;\n            ans[i]=now;\n        }\n    for(i=1;i<n;i++)\n        printf(\"%d \",ans[i]);\n    printf(\"%d\\n\",ans[n]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e3bdfd637c6d61833713705b07ea0bc4", "src_uid": "a2616b1681f30ce4b2a5fdc81cf52b50", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\n#define N\t20\n#define MD\t1000000007\n\nint d_, x_, y_;\n\nvoid gcd_(int a, int b) {\n\tif (b == 0)\n\t\td_ = a, x_ = 1, y_ = 0;\n\telse {\n\t\tint tmp;\n\n\t\tgcd_(b, a % b);\n\t\ttmp = x_ - a / b * y_, x_ = y_, y_ = tmp;\n\t}\n}\n\nint inv[N];\n\nvoid init() {\n\tint k;\n\n\tfor (k = 1; k < N; k++) {\n\t\tgcd_(k, MD);\n\t\tif (x_ < 0)\n\t\t\tx_ += MD;\n\t\tinv[k] = x_;\n\t}\n}\n\nlong long ch(long long n, int k) {\n\treturn k == 0 ? 1 : ch(n - 1, k - 1) * (n % MD) % MD * inv[k] % MD;\n}\n\nint main() {\n\tstatic long long ff[N];\n\tint n, b, i, ans;\n\tlong long s;\n\n\tinit();\n\tscanf(\"%d%lld\", &n, &s);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%lld\", &ff[i]);\n\tans = 0;\n\tfor (b = 0; b < 1 << n; b++) {\n\t\tlong long t;\n\t\tint k;\n\n\t\tt = s;\n\t\tk = 0;\n\t\tfor (i = 0; i < n; i++)\n\t\t\tif (b & 1 << i) {\n\t\t\t\tk++;\n\t\t\t\tt -= ff[i] + 1;\n\t\t\t}\n\t\tif (t >= 0) {\n\t\t\tint cnt = ch(t + n - 1, n - 1);\n\n\t\t\tans = (ans + (k % 2 == 0 ? cnt : -cnt)) % MD;\n\t\t}\n\t}\n\tif (ans < 0)\n\t\tans += MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d5186eab2b5d76fdc45fd4b187a27e35", "src_uid": "8b883011eba9d15d284e54c7a85fcf74", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long f[23],n,s,sum,inv[25];\nint c[23];\nint function(){\n\tint i,t1,j=0;\n\ti=1;\n\t\n\twhile(1){\n\t\tif(c[i]==0){\n\t\t\tc[i]=1;\n\t\t\tbreak;\n\t\t}else{\n\t\t\tc[i]=0;\n\t\t\ti++;\n\t\t}\n\t}\n}\t\n\nlong long power(long long a, long long b, long long MOD) {\nlong long x = 1, y = a; \n    while(b > 0) {\n        if(b%2 == 1) {\n            x=(x*y);\n            if(x>MOD) x%=MOD;\n        }\n        y = (y*y);\n        if(y>MOD) y%=MOD;\n        b /= 2;\n       \n    }\n    return x;\n}\n \nlong long modInverse(long long a,long long m) {\nif(inv[a]==0)\n     inv[a]=power(a,m-2,m);\n     return inv[a];\n}\n\nlong long binomialCoeff(long long n, long long k)\n{\n    long long i,res = 1;\n    if (k >( n - k))\n        k = n - k;\t\n    for ( i = 0; i < k; ++i)\n    {\n        res =(res* ((n - i)%1000000007))%1000000007;\n        res =(res* modInverse((i + 1),1000000007))%1000000007;\n    }\n\n    return res;\n}\nvoid recursion(int i,long long pow,int fac){\n\tint j;\n\ti=0;\n\twhile(1){\n\t\tfac=1;\n\t\tj=0;\n\t\tpow=0;\n\t\tfor(i=1;i<=n;i++){\n\t\t\tpow=pow+c[i]*(f[i]+1);\n\t\t\tif(c[i]==1){\tfac=fac*-1;\n\t\t\t\tj++;\n\t\t\t}\n\t\t}\n\t\tif(pow<=s){\t\t\t\t\n\t\t\tsum=(sum+fac*binomialCoeff(n+s-pow-1,s-pow))%1000000007;\n\t\t}\n\t\tif(j==n)\tbreak;\n\t\tfunction();\n\t}\n}\n\nint main(){\n\tlong long i,j,k,l;\n\tscanf(\"%lld %lld\",&n,&s);\n\tfor(i=1;i<=n;i++)\tscanf(\"%lld\",&f[i]);\n\trecursion(1,0,1);\n\tsum=(sum+1000000007)%1000000007;\n\tprintf(\"%lld\\n\",sum);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b1ee0474144561609efee3d288687902", "src_uid": "8b883011eba9d15d284e54c7a85fcf74", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "\n#include<stdlib.h>\n#include<stdio.h>\n#include<string.h>\n\ntypedef long long int lli;\ntypedef struct bst bst;\n\n#define TRUE         (1==1)\n#define FALSE        (!(TRUE))\n#define in32(x)      scanf(\"%d\", &(x))\n#define in64(x)      scanf(\"%I64d\", &(x))\n#define instr(x)     scanf(\"%s\", (x))\n#define out32(x)     printf(\"%d\\n\", (x))\n#define out64(x)     printf(\"%I64d\\n\", (x))\n#define outstr(x)    printf(\"%s\\n\", (x))\n#define sigNUM(x)    (((x)==0)?0:(((x)<0)?-1:1))\n#define max(a,b)     ((a)<(b))?(b):(a)\n#define min(a,b)     ((a)>(b))?(b):(a)\n#define abs(a)       ((a)<0)?(-(a)):(a)\n#define fo3(i,a,b)   for(i=(int)(a);i<=(int)(b);i++)\n#define of3(i,a,b)   for(i=(int)(a);i>=(int)(b);i--)\n\nvoid fastWrite(FILE * ofp, int x) {\n    int i = 12;\n    char buff[i];\n    buff[i] = 0;\n    int neg = 0;\n    if (x < 0){\n        x = -x;\n        neg = 1;\n    }\n    if (x == 0)\n        buff[--i] = '0';\n    else while (x != 0) {\n        buff[--i] = (x % 10) + '0';\n        x /= 10;\n    }\n    if (neg)\n        buff[--i] = '-';\n    fwrite(buff + i, sizeof(char), (12 - i), ofp);\n}\n\nvoid fastSpace(FILE * ofp){\n    fwrite(\" \", sizeof(char), 1, ofp);\n}\nvoid fastNewLine(FILE * ofp) {\n    fwrite(\"\\n\", sizeof(char), 1, ofp);\n}\n    \nint comp(lli f, lli s) {\n    return sigNUM(f - s);\n}\n\nvoid sort(lli * arr, int size) { // CHANGE THIS\n    int i;\n    if (size < 6) {\n        int nSize = 0;\n        while (size != 0) {\n            nSize = 0;\n            for (i = 0; i < size - 1; i++) \n                if (comp(arr[i], arr[i + 1]) > 0) { // CHANGE THIS\n                    nSize = i + 1;\n                    lli tmp = arr[i];\n                    arr[i] = arr[i + 1];\n                    arr[i+1] = tmp;\n                }\n            size = nSize;\n        }\n        return;\n    }\n    lli * tmp = (lli *)calloc(size, sizeof(lli)); // CHANGE THIS\n    int lSize = (size >> 1);\n    int rSize = size - lSize;\n    sort(arr, lSize); sort(arr + lSize, rSize);\n    int lPtr = 0, rPtr = 0;\n    int ptr = 0;\n    while (ptr != size) {\n        if (lPtr == lSize)\n            tmp[ptr] = arr[lSize + (rPtr++)];\n        else if (rPtr == rSize || comp(arr[lPtr], arr[lSize + rPtr]) <= 0) // CHANGE THIS\n            tmp[ptr] = arr[lPtr++];\n        else\n            tmp[ptr] = arr[lSize + (rPtr++)];\n        ptr++;\n    }\n    for (i = 0; i < size; i++)\n        arr[i] = tmp[i];\n    free(tmp);\n}\n   \n#define MAX 25\n#define MOD 1000000007\n\nlli invert(lli a) {\n    if (a == 0)\n        return 1;\n    if (a == 1)\n        return 1;\n    return MOD - ((MOD / a) * invert(MOD % a)) % MOD;\n}\n\n\nint main(void) {\n    lli n, a[MAX], i, j, s, s2, inv = 1, ans = 0, tans, mult;\n    in64(n);\n    in64(s);\n    fo3(i,0,n-1) {\n        in64(a[i]);\n        inv *= invert(i);\n        inv %= MOD;\n    }\n    fo3(i,0,(1<<n)-1) {\n        s2 = s;\n        mult = 1;\n        fo3(j,0,n-1) {\n            if ((1<<j)&i) {\n                mult = -mult;\n                s2 -= a[j] + 1;\n            }\n        }\n        if (s2 < 0)\n            continue;\n        \n        s2 += n - 1;\n        tans = inv;\n        fo3(j,0,n-2) {\n            tans *= (s2 - j) % MOD;\n            tans %= MOD;\n        }\n        ans += mult * tans;\n    }\n    ans = (ans % MOD + MOD) % MOD;\n    out64(ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d5894530a9457e43f6be2e44b93565a3", "src_uid": "8b883011eba9d15d284e54c7a85fcf74", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "/*      \ufffd\ufffd\ufffd\ufffd\nn\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd,\u00ff\ufffd\ufffd\ufffd\ufffd\ufffd\ufffdfi\ufffd\u4ee8.\n\u04bb\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u06bb\ufffd\ufffd\ufffd\ufffd\ufffd\u026b\ufffd\ufffd\ufffd\ufffd\u036c\ufffd\ufffd.\n\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u04f5\u013b\ufffd\ufffd\ufffd\u026b\ufffd\ufffd\u036c\ufffd\ufffd\n\ufffd\ufffd\u04aa\u0221\ufffd\ufffds\ufffd\u4ee8,\ufffd\ufffd\u0221\ufffd\ufffd\ufffd\ufffdmod = 1e9+7;\n\u00ff\ufffd\u05b7\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0674\ufffd\u04bb\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\u0461\ufffd\ufffd\u036c\ufffd\ufffd\ufffd\ufffd\ufffd\u013b\ufffd\ufffd\ufffd\n*/\n\n#include <stdio.h>\n#include <stdlib.h>\n\ntypedef long long int  ll;\nconst ll Mod=1000000000+7;\nll n,s,f[22],inv[22],c[22];\n\n\nll Pow(ll a,ll b)//\ufffd\ufffd\ufffd\ufffd\ufffd\ufffd\n{\n    ll ans=1;\n    while(b)\n    {\n        if(b&1)\n            ans=(ans*a)%Mod;\n        a=(a*a)%Mod;\n        b>>=1;\n    }\n    return ans;\n}\n\nll C(ll a,ll b)//\ufffd\ufffd\ufffd\ufffd\ufffd\n{\n    if(a<b)\n        return 0;\n    if(b>a-b)\n        b=a-b;\n    ll s1,s2,i;\n    s1=s2=1;\n    for(i=0;i<b;i++)\n    {\n        s1=s1*(a-i)%Mod;\n        s2=s2*(i+1)%Mod;\n    }\n    return s1*Pow(s2,Mod-2)%Mod;\n}\n\nll Lucas(ll n,ll k)//lucas\ufffd\ufffd\ufffd\ufffd\n{\n    if(n<0)\n        return 0;\n    if(k==0)\n        return 1;\n    return C(n%Mod,k%Mod)*Lucas(n/Mod,k/Mod)%Mod;\n}\n\nint main()\n{\n    int i,j;\n    scanf(\"%I64d%I64d\",&n,&s);\n    for(i=1;i<=n;i++)\n        scanf(\"%I64d\",&f[i]);\n    ll ans=Lucas(s+n-1,n-1);\n    for(i=1;i<(1<<n);i++)\n    {\n        int cnt=0;\n        ll sum=0;\n        for(j=0;j<n;j++)\n        {\n            if((1<<j)&i)\n            {\n                cnt++;\n                sum+=f[j+1]+1;\n            }\n        }\n        ll tmp=Lucas((s-sum)+(n-1),(n-1));\n        if(cnt%2==1)\n            ans-=tmp;\n        else\n            ans+=tmp;\n        ans=(ans+Mod)%Mod;\n    }\n    printf(\"%I64d \\n\",ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "121e42dac3c63899fe210833ebf66683", "src_uid": "8b883011eba9d15d284e54c7a85fcf74", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nlong long f[23],n,s,sum;\nint c[23];\nvoid function(){\n\tint i,t1;\n\ti=1;\n\twhile(1){\n\t\tif(c[i]==0){\n\t\t\tc[i]=1;\n\t\t\tbreak;\n\t\t}else{\n\t\t\tc[i]=0;\n\t\t\ti++;\n\t\t}\n\t}\n}\t\n\nlong long power(long long a, long long b, long long MOD) {\nlong long x = 1, y = a; \n    while(b > 0) {\n        if(b%2 == 1) {\n            x=(x*y);\n            if(x>MOD) x%=MOD;\n        }\n        y = (y*y);\n        if(y>MOD) y%=MOD;\n        b /= 2;\n       \n    }\n    return x;\n}\n \nlong long modInverse(long long a,long long m) {\n    return power(a,m-2,m);\n}\n\nlong long binomialCoeff(long long n, long long k)\n{\n    long long i,res = 1;\n    if (k >( n - k))\n        k = n - k;\t\n    for ( i = 0; i < k; ++i)\n    {\n        res =(res* ((n - i)%1000000007))%1000000007;\n        res =(res* modInverse((i + 1),1000000007))%1000000007;\n    }\n\n    return res;\n}\nvoid recursion(int i,long long pow,int fac){\n\tint j;\n\ti=0;\n\twhile(1){\n\t\tfac=1;\n\t\tj=0;\n\t\tpow=0;\n\t\tfor(i=1;i<=n;i++){\n\t\t\tpow=pow+c[i]*(f[i]+1);\n\t\t\tif(c[i]==1){\tfac=fac*-1;j++;\n\t\t\t}\n\t\t}\n\t\tif(pow<=s){\t\t\t\t\n\t\t\tsum=(sum+fac*binomialCoeff(n+s-pow-1,s-pow))%1000000007;\n\t\t}\n\t\tif(j==n)\tbreak;\n\t\tfunction();\n\t}\n}\n\nint main(){\n\tlong long i,j,k,l;\n\tscanf(\"%lld %lld\",&n,&s);\n\tfor(i=1;i<=n;i++)\tscanf(\"%lld\",&f[i]);\n\trecursion(1,0,1);\n\tsum=(sum+1000000007)%1000000007;\n\tprintf(\"%lld\\n\",sum);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cbec53ede9b13cdb3221e567ade19c8b", "src_uid": "8b883011eba9d15d284e54c7a85fcf74", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <memory.h>\n\n#define min(a,b) a<=b?a:b\n\nint main()\n{\n  int n;\n  scanf(\"%d\", &n);\n  \n  int *a = calloc(n,sizeof(int));\n  int *mk= calloc(n,sizeof(int));\n  memset(mk, 0, sizeof(int)*n);\n  \n  if(n == 1)\n  {\n    scanf(\"%d\", &a[0]);\n    printf(\"%d\\n\", a[0]);\n    return 0;\n  }\n  \n  int i,j;\n  for(i=0;i<n;++i)\n    scanf(\"%d\", a+i);\n  \n  for(i=0;i<n;++i)\n  {\n    int mn=0x7fffffff,val=-1;\n    for(j=0;j<n;++j)\n    {\n      if(mk[j] || a[i] >= a[j])continue;\n      if(a[j] - a[i] < mn)\n      {\n        mn = a[j] - a[i];\n        val = j;\n      }\n    }\n    if(~val)\n    {\n      mk[val] = 1;\n      printf(\"%d%c\", a[val], \" \\n\"[i==n-1]);\n    }else\n    {\n      mn=a[0];\n      for(j=1;j<n;++j)\n        mn = min(mn,a[j]);\n      printf(\"%d%c\", mn, \" \\n\"[i==n-1]);\n    }\n  }\n  \n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "19d227f5ec78c65a7bac0dba85a2b2b6", "src_uid": "e314642ca1f82be8f223e2eba00b5531", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nstruct node\n{\n    int a, b;\n};\nint z[75];\n\nint main()\n{\n    int i, j, n;\n    struct node x[75], y[75], t;\n    scanf(\"%d\", &n);\n    for(i = 1; i <= n; ++i)\n    {\n        scanf(\"%d\", &x[i].a);\n        x[i].b = i;\n        y[i].a = x[i].a;\n        y[i].b = x[i].b;\n    }\n    for(i = 1; i <= n; ++i)\n        for(j = 1; j < n; ++j)\n            if(x[j].a < x[j + 1].a)\n            {\n                t = x[j];\n                x[j] = x[j + 1];\n                x[j + 1] = t;\n            }\n    for(i = 1; i <= n; ++i)\n    {\n        for(j = 1; j <= n; ++j)\n            if(x[j].a == y[i].a) break;\n        z[i] = x[j + 1].a;\n        if(j == n) z[i] = x[1].a;\n    }\n    for(i = 1; i <= n; ++i)\n        printf(\"%d \", z[i]);\n    putchar('\\n');\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "58a5d58b72451a496f987ffc586697d4", "src_uid": "e314642ca1f82be8f223e2eba00b5531", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n#include <limits.h>\n\nvoid swap(long long int *a , long long int *b){\n    long long int temp;\n    temp = *a;\n    *a = *b;\n    *b = temp;\n}\n\nvoid bsort(int n , long long int a[n]){\n    int ct1 , ct2;\n    for(ct1  = 0 ; ct1  <= n ; ct1++){\n        for(ct2 = 0 ; ct2 < n - 1; ct2++){\n            if(a[ct2] > a[ct2 + 1]){\n                swap(&a[ct2] , &a[ct2 +1]);\n            }\n        }\n    }\n\n}\n\nint main() {\n    int n;\n    scanf(\"%d\",&n);\n    long long int a[n];\n    long long int temp[n];\n    int ct;\n    for(ct = 0 ;ct < n ; ct++){\n        scanf(\"%lld\" , &a[ct]);\n        temp[ct] = a[ct];\n\n    }\n    int ct1, ct2;\n\n    for(ct1 = 0 ;ct1 + 1 < n ; ct1++){\n        for(ct2 = ct1 + 1 ; ct2 < n ; ct2++){\n            if(a[ct1] == a[ct2]){\n                printf(\"-1\");\n                return 0;\n            }\n        }\n    }\n\n    bsort( n, temp);\n\n    int order[n];\n    for(ct = 0  ;ct < n ; ct++){\n        for(ct1 = 0 ; ct1 < n ; ct1++){\n            if(a[ct] == temp[ct1]){\n                order[ct] = ct1;\n            }\n        }\n    }\n\n    for(ct = 0 ;ct < n ; ct++){\n        printf(\"%lld \", a[((order[ct] + 1) % n)]);\n    }\n\n\n\n\n\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "236ef0c6b64099cbd8f6ce37c4791988", "src_uid": "e314642ca1f82be8f223e2eba00b5531", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint ConfSum(int v[], int size, int conf)\n{\n  int sum = 0;\n  int i;\n\n  for (i = 0; i < size; ++i) {\n    if (conf & (1 << i)) {\n      sum += v[i];\n    }\n  }\n  return sum;\n}\n\nint Independent(int v1[], int v2[], int size)\n{\n  int i, sum1, sum2;\n\n  for (i = 1; i + 1 < (1 << size); ++i) {\n    sum1 = ConfSum(v1, size, i);\n    sum2 = ConfSum(v2, size, i);\n    if (sum1 == sum2) {\n      return 0;\n    }\n  }\n  return 1;\n}\n\nvoid Swap(int *a, int *b)\n{\n  int aux = *a;\n  *a = *b;\n  *b = aux;\n}\n\nvoid Sort(int v[], int left, int right)\n{\n  if (left >= right) {\n    return;\n  }\n\n  int mid = left + (right - left) / 2;\n  Swap(&v[left], &v[mid]);\n\n  int i = left + 1;\n  int j = right;\n\n  while (i <= j) {\n    while (i <= j && v[left] < v[i]) {\n      i += 1;\n    }\n    while (i <= j && v[left] >= v[j]) {\n      j -= 1;\n    }\n    if (i <= j) {\n      Swap(&v[i], &v[j]);\n      i += 1;\n      j -= 1;\n    }\n  }\n\n  i -= 1;\n  Swap(&v[left], &v[i]);\n\n  Sort(v, left, i - 1);\n  Sort(v, i + 1, right);\n}\n\nvoid PermuteLeft(int v[], int size)\n{\n  int first = v[0];\n  int i;\n\n  for (i = 0; i + 1 < size; ++i) {\n    v[i] = v[i + 1];\n  }\n  v[size - 1] = first;\n}\n\nvoid PrintVector(int v[], int size)\n{\n  int i;\n  for (i = 0; i < size; ++i) {\n    printf(\"%d \", v[i]);\n  }\n}\n\n#define NMAX 22\n\nint main()\n{\n  int size;\n  scanf(\"%d\", &size);\n\n  int vec[NMAX];\n  int sol[NMAX];\n\n  int i;\n  for (i = 0; i < size; ++i) {\n    scanf(\"%d\", &vec[i]);\n    sol[i] = vec[i];\n  }\n\n  Sort(sol, 0, size - 1);\n\n  for (i = 0; i < size; ++i) {\n    if (Independent(vec, sol, size)) {\n      PrintVector(sol, size);\n      return 0;\n    }\n    PermuteLeft(sol, size);\n  }\n\n  printf(\"-1\\n\");\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2f06a010406e0532475488c46fa87abf", "src_uid": "e314642ca1f82be8f223e2eba00b5531", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <memory.h>\n\n#define min(a,b) a<=b?a:b\n\nint main()\n{\n  int n;\n  scanf(\"%d\", &n);\n  if(n == 1)\n  {\n    printf(\"-1\\n\");\n    return 0;\n  }\n\n  int *a = calloc(n,sizeof(int));\n  int *mk= calloc(n,sizeof(int));\n  memset(mk, 0, sizeof(mk));\n  int i,j;\n  for(i=0;i<n;++i)\n    scanf(\"%d\", a+i);\n  \n  for(i=0;i<n;++i)\n  {\n    int mn=0x7fffffff,val=-1;\n    for(j=0;j<n;++j)\n    {\n      if(mk[j] || a[i] >= a[j])continue;\n      if(a[j] - a[i] < mn)\n      {\n        mn = a[j] - a[i];\n        val = j;\n      }\n    }\n    if(~val)\n    {\n      mk[val] = 1;\n      printf(\"%d%c\", a[val], \" \\n\"[i==n-1]);\n    }else\n    {\n      mn=a[0];\n      for(j=1;j<n;++j)\n        mn = min(mn,a[j]);\n      printf(\"%d%c\", mn, \" \\n\"[i==n-1]);\n    }\n  }\n  \n  return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3c454ae97f5c1caee80f43d5f50ad1c2", "src_uid": "e314642ca1f82be8f223e2eba00b5531", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint dp[1 << 24];\nint p[1 << 24][3];\n\nint dist(int x1, int y1, int x2, int y2)\n{\n     return (x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2);\n}\n\nint main()\n{\n     int x, y, n, i, j, k;\n     int a[24], b[24];\n\n     scanf(\"%d %d\", &x, &y);\n     scanf(\"%d\", &n);\n\n     for (i = 0; i < n; i++) scanf(\"%d %d\", &a[i], &b[i]);\n\n     for (i = 1; i < (1 << n); i++) dp[i] = 1e9;\n\n     for (i = 0; i < (1 << n) - 1; i++) {\n\t  for (j = 0; j < n; j++) {\n\t       if (((i >> j) & 1) == 0) break;\n\t  }\n\n\t  for (k = j + 1; k < n; k++) {\n\t       if (((i >> k) & 1) == 0) break;\n\t  }\n\n\t  if (k < n) {\n\t       int c = i ^ (1 << j) ^ (1 << k);\n\t       int d = dist(x, y, a[j], b[j]) + dist(x, y, a[k], b[k]) + dist(a[j], b[j], a[k], b[k]);\n\n\t       if (dp[i] + d < dp[c]) {\n\t\t    dp[c] = dp[i] + d;\n\n\t\t    p[c][0] = j + 1;\n\t\t    p[c][1] = k + 1;\n\t\t    p[c][2] = i;\n\t       }\n\t  } else {\n\t       int c = i ^ (1 << j);\n\t       int d = dist(x, y, a[j], b[j]) * 2;\n\n\t       if (dp[i] + d < dp[c]) {\n\t\t    dp[c] = dp[i] + d;\n\n\t\t    p[c][0] = j + 1;\n\t\t    p[c][1] = -1;\n\t\t    p[c][2] = i;\n\t       }\n\t  }\n     }\n\n     printf(\"%d\\n\", dp[(1 << n) - 1]);\n\n     i = (1 << n) - 1;\n\n     while (i > 0) {\n\t  if (p[i][1] == -1) {\n\t       printf(\"0 %d \", p[i][0]);\n\t  } else {\n\t       printf(\"0 %d %d \", p[i][0], p[i][1]);\n\t  }\n\n\t  i = p[i][2];\n     }\n     puts(\"0\");\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e231bfe96d900cbac131b4195fb9cbc5", "src_uid": "2ecbac20dc5f4060bc873553946281bc", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint x[105];\nint y[105];\nint single[105];\nint pair[105][105];\nint best[8388610];\nint prev[8288610];\n\nint dist(int x1, int y1, int x2, int y2)\n{\n\treturn (x1-x2)*(x1-x2) + (y1-y2)*(y1-y2);\n}\n\nint main()\n{\n\tint xs,ys;\n\tscanf(\"%d %d\", &xs, &ys);\n\tint n;\n\tscanf(\"%d\", &n);\n\tfor (int i = 0; i < n; i++) {\n\t\tscanf(\"%d %d\", &x[i], &y[i]);\n\t}\n\tfor (int i = 0; i < n; i++) {\n\t\tsingle[i] = 2*dist(x[i], y[i], xs, ys);\n\t}\n\tfor (int i = 0; i < n; i++) {\n\t\tfor (int j = i+1; j < n; j++) {\n\t\t\tpair[i][j] = dist(xs,ys,x[i], y[i])+dist(x[i],y[i],x[j],y[j])+dist(x[j],y[j],xs,ys);\n\t\t}\n\t}\n\tint len = (1<<n);\n\tfor (int i = 1; i < len; i++) {\n\t\tint bitpos = 0;\n\t\twhile ((i & (1 << bitpos)) == 0) {\n\t\t\tbitpos++;\n\t\t}\n\t\tbest[i] = best[i^(1 << bitpos)]+single[bitpos];\n\t\tprev[i] = bitpos+1;\n\t\tint val = best[i];\n\t\tfor (int j = bitpos+1; j < n; j++) {\n\t\t\tif ((i & (1 << j)) != 0) { \n\t\t\t\tval = best[i^(1 << bitpos)^(1 << j)] + pair[bitpos][j];\n\t\t\t\tif (val <= best[i]) {\n\t\t\t\t\tbest[i] = val;\n\t\t\t\t\tprev[i] = 100*(bitpos+1)+(j+1);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t//printf(\"%d %d\\n\", best[i], prev[i]);\n\t}\n\tprintf(\"%d\\n\", best[(1<<n)-1]);\n\tint now = (1 << n)-1;\n\tprintf(\"0 \");\n\twhile (now > 0) {\n\t\t//printf(\"p : %d\\n\", prev[now]);\n\t\tint nj = prev[now]%100;\n\t\tint ni = prev[now]/100;\n\t\tif (ni > 0) {\n\t\t\tprintf(\"%d \", ni);\n\t\t\tnow ^= (1 << (ni-1));\n\t\t}\n\t\tif (nj > 0) {\n\t\t\tprintf(\"%d \", nj);\n\t\t\tnow ^= (1 << (nj-1));\n\t\t}\n\t\tprintf(\"0 \");\n\t}\n\tprintf(\"\\n\");\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e586353d43ce8ffe897afa8bdca7ffc7", "src_uid": "2ecbac20dc5f4060bc873553946281bc", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint dp[1 << 24];\nint p[1 << 24][3];\n\nint dist(int x1, int y1, int x2, int y2)\n{\n     return (x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2);\n}\n\nint main()\n{\n     int x, y, n, i, j, k;\n     int a[24], b[24];\n\n     scanf(\"%d %d\", &x, &y);\n     scanf(\"%d\", &n);\n\n     for (i = 0; i < n; i++) scanf(\"%d %d\", &a[i], &b[i]);\n\n     for (i = 1; i < (1 << n); i++) dp[i] = 1e9;\n\n     for (i = 0; i < (1 << n) - 1; i++) {\n\t  for (j = 0; j < n; j++) {\n\t       if (((i >> j) & 1) == 0) {\n\t\t    int c = i ^ (1 << j);\n\t\t    int d = dist(x, y, a[j], b[j]) * 2;\n\n\t\t    for (k = j + 1; k < n; k++) {\n\t\t\t if (((i >> k) & 1) == 0) {\n\t\t\t      int c = i ^ (1 << j) ^ (1 << k);\n\t\t\t      int d = dist(x, y, a[j], b[j]) + dist(x, y, a[k], b[k]) + dist(a[j], b[j], a[k], b[k]);\n\n\t\t\t      if (dp[i] + d < dp[c]) {\n\t\t\t\t   dp[c] = dp[i] + d;\n\n\t\t\t\t   p[c][0] = j + 1;\n\t\t\t\t   p[c][1] = k + 1;\n\t\t\t\t   p[c][2] = i;\n\t\t\t      }\n\t\t\t }\n\t\t    }\n\n\t\t    if (dp[i] + d < dp[c]) {\n\t\t\t dp[c] = dp[i] + d;\n\n\t\t\t p[c][0] = j + 1;\n\t\t\t p[c][1] = -1;\n\t\t\t p[c][2] = i;\n\t\t    }\n\t       }\n\t  }\n     }\n\n     printf(\"%d\\n\", dp[(1 << n) - 1]);\n\n     i = (1 << n) - 1;\n\n     while (i > 0) {\n\t  if (p[i][1] == -1) {\n\t       printf(\"0 %d \", p[i][0]);\n\t  } else {\n\t       printf(\"0 %d %d \", p[i][0], p[i][1]);\n\t  }\n\n\t  i = p[i][2];\n     }\n     puts(\"0\");\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c0d0a3b7c99c734f106e4e2cbdfd4a48", "src_uid": "2ecbac20dc5f4060bc873553946281bc", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <limits.h>\n#include <stdio.h>\n#include <stdlib.h>\n\nvoid print(int l, int *vv, int n) {\n\tint i, j, cnt = 0;\n\n\tfor (i = 1, j = n; i <= l - vv[l]; i <<= 1, j--)\n\t\tif ((i & l - vv[l]) > 0)\n\t\t\tprintf(\" %d\", j);\n\tfor (i = 1; i <= vv[l]; i <<= 1)\n\t\tif ((i & vv[l]) > 0)\n\t\t\tcnt++;\n\tif (cnt > 0)\n\t\tprintf(\" 0\");\n\tif (cnt == 1 || cnt == 2) {\n\t\tfor (i = 1, j = n; i <= vv[l]; i <<= 1, j--)\n\t\t\tif ((i & vv[l]) > 0)\n\t\t\t\tprintf(\" %d\", j);\n\t} else if (cnt > 2)\n\t\tprint(vv[l], vv, n);\n}\n\nint main() {\n\tint *aa, *vv, *xx, *yy;\n\tint i, v, j, k;\n\tint x, y, n, l;\n\n\tscanf(\"%d%d%d\", &x, &y, &n);\n\tl = 1 << n;\n\taa = malloc(sizeof(int) * l);\n\tvv = malloc(sizeof(int) * l);\n\txx = malloc(sizeof(int) * n);\n\tyy = malloc(sizeof(int) * n);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d%d\", &xx[i], &yy[i]);\n\tfor (i = 0; i < l; i++)\n\t\taa[i] = INT_MAX;\n\taa[0] = 0;\n\tfor (i = 1; i < l; i++)\n\t\tfor (v = 0; v < i; v++)\n\t\t\tif ((i | v) == i) {\n\t\t\t\tint d = i - v, cnt;\n\t\t\t\tint a, dx[2], dy[2];\n\n\t\t\t\tcnt = 0;\n\t\t\t\tfor (j = 1; j <= d; j <<= 1)\n\t\t\t\t\tif ((d & j) > 0)\n\t\t\t\t\t\tcnt++;\n\n\t\t\t\tif (cnt == 1) {\n\t\t\t\t\tfor (j = 1, k = n - 1; j <= d; j <<= 1, k--)\n\t\t\t\t\t\tif ((d & j) > 0) {\n\t\t\t\t\t\t\ta = 2 * ((xx[k] - x) * (xx[k] - x) + (yy[k] - y) * (yy[k] - y));\n\t\t\t\t\t\t\tif (aa[i] > aa[v] + a) {\n\t\t\t\t\t\t\t\taa[i] = aa[v] + a;\n\t\t\t\t\t\t\t\tvv[i] = v;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t} else if (cnt == 2) {\n\t\t\t\t\tfor (j = 1, k = n - 1; j <= d; j <<= 1, k--)\n\t\t\t\t\t\tif ((d & j) > 0) {\n\t\t\t\t\t\t\tdx[--cnt] = xx[k];\n\t\t\t\t\t\t\tdy[cnt] = yy[k];\n\t\t\t\t\t\t}\n\t\t\t\t\ta = (dx[0] - x) * (dx[0] - x) + (dy[0] - y) * (dy[0] - y) +\n\t\t\t\t\t\t(x - dx[1]) * (x - dx[1]) + (y - dy[1]) * (y - dy[1]) +\n\t\t\t\t\t\t(dx[1] - dx[0]) * (dx[1] - dx[0]) + (dy[1] - dy[0]) * (dy[1] - dy[0]);\n\t\t\t\t\tif (aa[i] > aa[v] + a) {\n\t\t\t\t\t\taa[i] = aa[v] + a;\n\t\t\t\t\t\tvv[i] = v;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\tprintf(\"%d\\n\", aa[l - 1]);\n\tprintf(\"0\");\n\tprint(l - 1, vv, n);\n\tprintf(\" 0\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6c008b3bb4400634d39c0889617ab557", "src_uid": "2ecbac20dc5f4060bc873553946281bc", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define INF 1000000000\n\n#define N 24\n\n#define NOT_USED (-1)\n\ntypedef struct {\n    int x, y;\n} point;\n\ntypedef struct {\n    char first, second;\n    int cost, subset_mask;\n} state;\n\nstatic inline int square(const int a) {\n    return a * a;\n}\n\nstatic inline int dist(const point a, const point b) {\n    return square(a.x - b.x) + square(a.y - b.y);\n}\n\nstatic inline int from_orig(const point a) {\n    return square(a.x) + square(a.y);\n}\n\nint main() {\n    int n, tmp;\n    state subset_result[(1<<N)];\n    point start_pos, objects[N];\n    scanf(\"%d%d\", &start_pos.x, &start_pos.y);\n    scanf(\"%d\", &n);\n    for(int i = 0; i < n; i++)\n        scanf(\"%d%d\", &objects[i].x, &objects[i].y);\n    for(int i = 0; i < n; i++) {\n        objects[i].x -= start_pos.x;\n        objects[i].y -= start_pos.y;\n    }\n    subset_result[0].cost = 0.0;\n    for(int i = 1; i < (1<<n); i++) {\n        subset_result[i].cost = INF;\n        for(int j = 0; j < n; j++)\n            if(i & (1<<j)) {\n                tmp = subset_result[i ^ (1<<j)].cost + 2 * from_orig(objects[j]);\n                if(subset_result[i].cost > tmp) {\n                    subset_result[i].cost = tmp;\n                    subset_result[i].first = j;\n                    subset_result[i].second = NOT_USED;\n                    subset_result[i].subset_mask = (i ^ (1<<j));\n                }\n                for(int k = 0; k < n; k++)\n                    if(i & (1<<k) && k != j) {\n                        tmp = subset_result[i ^ (1<<j) ^ (1<<k)].cost +\n                                        from_orig(objects[j]) +\n                                        dist(objects[j], objects[k]) + \n                                        from_orig(objects[k]);\n                        if(subset_result[i].cost > tmp) {\n                            subset_result[i].cost = tmp;\n                            subset_result[i].first = j;\n                            subset_result[i].second = k;\n                            subset_result[i].subset_mask = (i ^ (1<<j) ^ (1<<k));\n                        }\n                    }\n            }\n    }\n    printf(\"%d\\n\", subset_result[(1<<n) - 1].cost);\n    tmp = (1<<n) - 1;\n    printf(\"0\");\n    while(tmp) {\n        state current = subset_result[tmp];\n        if(current.second == NOT_USED)\n            printf(\" %d 0\", current.first + 1);\n        else\n            printf(\" %d %d 0\", current.first + 1, current.second + 1);\n        tmp = current.subset_mask;\n    }\n    printf(\"\\n\");\n    return 0;\n}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f50bb25f4cd661ef022d2c415ada96f9", "src_uid": "2ecbac20dc5f4060bc873553946281bc", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define min(a,b) ((a)<(b) ? (a):(b))\n#define max(a,b) ((a)>(b) ? (a):(b))\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nint main(){\n    int i, j, k, l, x, y, z, x1, y1, x2, y2;\n\n    while (scanf(\"%d %d %d %d\", &x1, &y1, &x2, &y2) != EOF){\n        if ((x1 + y1) <= max(x2, y2)) puts(\"Polycarp\");\n        else if ((x1 + y1) == 1) puts(\"Polycarp\");\n        else if (( (x1 - 1 + 1) == x2 && (y1 + 1) == y2)) puts(\"Polycarp\");\n        else if (( (x1 + 1) == x2 && (y1 - 1 + 1) == y2)) puts(\"Polycarp\");\n        else if (max(x2, y2) < (x1 + y1)) puts(\"Vasilliy\");\n        else{\n            puts(\"Polycarp\");\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "65a43085a31a393f6731a8ce9b600392", "src_uid": "2637d57f7809ff8f922549c617709074", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define MAX 200010\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nbool visited[76][76][76][76][2], dp[76][76][76][76][2];\n\nbool F(int x1, int y1, int x2, int y2, int p){\n    if (x1 == 0 && y1 == 0) return true;\n    if (x2 == 0 && y2 == 0) return false;\n    if (visited[x1][y1][x2][y2][p]) return dp[x1][y1][x2][y2][p];\n\n    bool res = false;\n    if (p){\n        if (x1 && F(x1 - 1, y1, x2, y2, p ^ 1)) res = true;\n        if (y1 && F(x1, y1 - 1, x2, y2, p ^ 1)) res = true;\n    }\n    else{\n        res = true;\n        if (x2 && F(x1, y1, x2 - 1, y2, p ^ 1)) res = false;\n        if (y2 && F(x1, y1, x2, y2 - 1, p ^ 1)) res = false;\n        if (x2 && y2 && F(x1, y1, x2 - 1, y2 - 1, p ^ 1)) res = false;\n    }\n\n    visited[x1][y1][x2][y2][p] = true;\n    return (dp[x1][y1][x2][y2][p] = res);\n}\n\nint main(){\n    int i, j, k, l, x1, y1, x2, y2;\n\n    while (scanf(\"%d %d %d %d\", &x1, &y1, &x2, &y2) != EOF){\n        if (F(x1, y1, x2, y2, 1)) puts(\"Polycarp\");\n        else puts(\"Vasiliy\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a113bfaf08b58d963c074fb6782ba8e4", "src_uid": "2637d57f7809ff8f922549c617709074", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define MAX(x, y) (((x) > (y)) ? (x) : (y))\nint main()\n{\n    int a,b,c,d,move,move_p,move_v;\n    scanf(\"%d %d %d %d\",&a,&b,&c,&d);\n    if(a<c&&b<d)printf(\"Polycarp\");\n    else if((a<c&&b>d)||(a>c&&b<d)||(a>c&&b>d)){\n        move_p=a+b;\n        move_v=MAX(c,d);\n        if(move_p<=move_v)printf(\"Polycarp\");\n        else printf(\"Vasiliy\");\n    }\n    else if(a==c&&b<d){\n        move=d-b;\n        a-=move;\n        c-=move;\n        d-=move;\n        if(a<=c&&b<=d)printf(\"Polycarp\");\n        else printf(\"Vasiliy\");\n    }\n     else if(a<c&&b==d){\n        move=c-a;\n        b-=move;\n        c-=move;\n        d-=move;\n        if(a<=c&&b<=d)printf(\"Polycarp\");\n        else printf(\"Vasiliy\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0f5f54d24c4b5fdedd386ce1c7145f69", "src_uid": "2637d57f7809ff8f922549c617709074", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint max(int a,int b);\nint main()\n{  int a,b,c,d,i,j,k,x1,y1,x2,y2;\n   scanf(\"%d %d %d %d\",&x1,&y1,&x2,&y2);\n   if(x1>x2 && y1>y2)\n   {   printf(\"Vasiliy\");\n\n   }\n   else if(x2==0 || y2==0)\n   {\n       if(x1+y1<=x2+y2)\n       {\n           printf(\"Polycarp\");\n       }\n       else\n       {\n           printf(\"Vasiliy\");\n       }\n   }\n\n   else if(x2>x1 && y2>y1)\n   {   if(x1+y1<=max(x2,y2))\n       {\n           printf(\"Polycarp\");\n       }\n       else if(x1+1==x2 && y1+1==y2 )\n       {printf(\"Polycarp\");}\n       else\n       {\n           printf(\"Vasiliy\");\n       }\n   }\n   else if(x1==x2)\n   {\n       if(y1<y2)\n       {\n           printf(\"Polycarp\");\n       }\n       else if(x1+y1<=max(x2,y2))\n       {\n           printf(\"Polycarp\");\n       }\n       else\n       {\n           printf(\"Vasiliy\");\n       }\n\n   }\n   else if(y1==y2)\n   {\n       if(x1<x2)\n       {\n           printf(\"Polycarp\");\n       }\n       else if(x1+y1<=max(x2,y2))\n       {\n           printf(\"Polycarp\");\n       }\n       else\n       {\n           printf(\"Vasiliy\");\n       }\n\n   }\n   else\n   {\n       if(x1+y1<=max(x2,y2))\n       {\n           printf(\"Polycarp\");\n       }\n       else\n       {\n           printf(\"Vasiliy\");\n       }\n   }\n   return 0;\n\n }\n int max(int a,int b)\n {\n     if(a>=b)\n     {\n         return a;\n     }\n     else\n     {\n         return b;\n     }\n\n }", "lang_cluster": "C", "compilation_error": false, "code_uid": "b3cdf63ae9bd2e5262e3fe6e260c0ee4", "src_uid": "2637d57f7809ff8f922549c617709074", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define MAX 200010\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nbool visited[101][101][101][101][2], dp[101][101][101][101][2];\n\nbool F(int x1, int y1, int x2, int y2, int p){\n    if (x1 == 0 && y1 == 0) return true;\n    if (x2 == 0 && y2 == 0) return false;\n    if (visited[x1][y1][x2][y2][p]) return dp[x1][y1][x2][y2][p];\n\n    bool res = false;\n    if (p){\n        if (x1 && F(x1 - 1, y1, x2, y2, p ^ 1)) res = true;\n        if (y1 && F(x1, y1 - 1, x2, y2, p ^ 1)) res = true;\n    }\n    else{\n        res = true;\n        if (x2 && F(x1, y1, x2 - 1, y2, p ^ 1)) res = false;\n        if (y2 && F(x1, y1, x2, y2 - 1, p ^ 1)) res = false;\n        if (x2 && y2 && F(x1, y1, x2 - 1, y2 - 1, p ^ 1)) res = false;\n    }\n\n    visited[x1][y1][x2][y2][p] = true;\n    return (dp[x1][y1][x2][y2][p] = res);\n}\n\nint main(){\n    int i, j, k, l, x1, y1, x2, y2;\n\n    while (scanf(\"%d %d %d %d\", &x1, &y1, &x2, &y2) != EOF){\n        if (F(x1, y1, x2, y2, 1)) puts(\"Polycarp\");\n        else puts(\"Vasiliy\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f175e3fa9edcd1fe60aa3bfa22b237f8", "src_uid": "2637d57f7809ff8f922549c617709074", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main () {\n  int n = 0;\n  long long m = 0LL;\n  \n  int res = 0;\n  \n  long long ans = 0LL;\n  long long mod_num = 998244353LL;\n  \n  long long pow = 1LL;\n  long long tmp = 1LL;\n  long long mul = 1LL;\n  \n  int is_not_prime[300001] = {};\n  \n  res = scanf(\"%d\", &n);\n  res = scanf(\"%lld\", &m);\n  \n  is_not_prime[0] = 1;\n  is_not_prime[1] = 1;\n  for (int i = 2; i <= n; i++) {\n    if (is_not_prime[i] <= 0) {\n      for (int p = 2; p*i <= n; p++) {\n        is_not_prime[i*p] = 1;\n      }\n    }\n  }\n  \n  for (int i = 1; i <= n; i++) {\n    pow = (pow*(m%mod_num))%mod_num;\n    ans += pow;\n    if (mul <= m) {\n      if (is_not_prime[i] <= 0) {\n        mul *= (long long)i;\n      }\n      if (m < mul) {\n        tmp = 0LL;\n      } else {\n        tmp *= (m/mul)%mod_num;\n        tmp %= mod_num;\n        ans += mod_num-tmp;\n      }\n    }\n  }\n  \n  printf(\"%lld\\n\", ans%mod_num);\n  \n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "54d0af0f2046b0bbcfeec594d73b8471", "src_uid": "0fdd91ed33431848614075ebe9d2ee68", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "    #include <stdio.h>\r\n     \r\n    #define K\t12\r\n    #define MD\t998244353\r\n     \r\n    int pp[] = { 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37 };\r\n     \r\n    int main() {\r\n    \tint n, h, i;\r\n    \tlong long a, b, x, y, z;\r\n     \r\n    \tscanf(\"%d%lld\", &n, &a), b = a;\r\n    \tx = 1, y = 1, z = 0;\r\n    \tfor (h = 0, i = 1; i <= n; i++) {\r\n    \t\tif (h < K && i == pp[h])\r\n    \t\t\tb /= pp[h++];\r\n    \t\tx = x * (a % MD) % MD;\r\n    \t\ty = y * (b % MD) % MD;\r\n    \t\tz = ((long long) z + x - y + MD) % MD;\r\n    \t}\r\n    \tprintf(\"%lld\\n\", z);\r\n    \treturn 0;\r\n    }", "lang_cluster": "C", "compilation_error": false, "code_uid": "992b76150069fee16668489743db6c5f", "src_uid": "0fdd91ed33431848614075ebe9d2ee68", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\n#define K\t12\r\n#define MD\t998244353\r\n\r\nint pp[] = { 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37 };\r\n\r\nint main() {\r\n\tint n, h, i;\r\n\tlong long a, b, x, y, z;\r\n\r\n\tscanf(\"%d%lld\", &n, &a), b = a;\r\n\tx = 1, y = 1, z = 0;\r\n\tfor (h = 0, i = 1; i <= n; i++) {\r\n\t\tif (h < K && i == pp[h])\r\n\t\t\tb /= pp[h++];\r\n\t\tx = x * (a % MD) % MD;\r\n\t\ty = y * (b % MD) % MD;\r\n\t\tz = ((long long) z + x - y + MD) % MD;\r\n\t}\r\n\tprintf(\"%lld\\n\", z);\r\n\treturn 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8dc61788fbd98c0152f6de2f04b3737f", "src_uid": "0fdd91ed33431848614075ebe9d2ee68", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define mod 1000000007\n#define ll long long\nint main()\n{\n\tll n,l,r,mod0,mod1,mod2,i,dp[300543][3],modu[3],len;\n\tscanf(\"%lld %lld %lld\",&n,&l,&r);\n\t len=r-l+1;\n\tfor(i=0;i<3;i++)\n\tmodu[i]=len/3;\n\tif(len%3==1)\n\tmodu[r%3]++;\n\telse if(len%3==2)\n\tmodu[(r-1)%3]++,modu[(r)%3]++;\n\tmod0=modu[0];\n\tmod1=modu[1];\n\tmod2=modu[2];\n\tdp[0][0]=modu[0];\n\tdp[0][1]=modu[1];\n\tdp[0][2]=modu[2];\n\tfor(i=1;i<=n-1;i++)\n\t{\n\t\tdp[i][0]=(dp[i-1][0]*mod0)%mod+(dp[i-1][2]*mod1)%mod+(dp[i-1][1]*mod2)%mod;\n\t\tdp[i][0]%=mod;\n\t\tdp[i][1]=(dp[i-1][1]*mod0)%mod+(dp[i-1][0]*mod1)%mod+(dp[i-1][2]*mod2)%mod;\n\t\tdp[i][1]%=mod;\n\t\tdp[i][2]=(dp[i-1][2]*mod0)%mod+(dp[i-1][1]*mod1)%mod+(dp[i-1][0]*mod2)%mod;\n\t\tdp[i][2]%=mod;\n\t}\n\tprintf(\"%lld\\n\",dp[n-1][0]%mod);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "cb7b8807c2b42de15ef97b0ee14d2cd5", "src_uid": "4c4852df62fccb0a19ad8bc41145de61", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nlong long int dp[200000][3];\nint num[3];\nint main()\n{\n\tint n, l, r;\n\tscanf(\"%d%d%d\", &n, &l, &r);\n\tfor(int i = l ; i <= r; i++)\n\t{\n\t\tnum[i % 3]++;\n\t}\n\tdp[0][0] = num[0];\n\tdp[0][1] = num[1];\n\tdp[0][2] = num[2];\n\tfor(int i = 1; i < n; i++)\n\t{\n\t\tfor(int j = 0; j < 3; j++)\n\t\t{\n\t\t\tdp[i][j] += dp[i - 1][j] * num[0];\n\t\t\tdp[i][j] += dp[i - 1][j + 1 < 3 ? j + 1 : j - 2] * num[2];\n\t\t\tdp[i][j] += dp[i - 1][j + 2 < 3 ? j + 2 : j - 1] * num[1];\n\t\t\tdp[i][j] %= 1000000007;\n\t\t}\n\t}\n\tprintf(\"%d\", (int)dp[n - 1][0]);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "185eeb1fcb84a5612faebb57979342d3", "src_uid": "4c4852df62fccb0a19ad8bc41145de61", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nlong long int dp[200000][3];\nint num[3];\nint main()\n{\n\tint n, l, r;\n\tscanf(\"%d%d%d\", &n, &l, &r);\n\tfor(int i = l ; i <= r; i++)\n\t{\n\t\tnum[i % 3]++;\n\t}\n\tdp[0][0] = num[0];\n\tdp[0][1] = num[1];\n\tdp[0][2] = num[2];\n\tfor(int i = 1; i < n; i++)\n\t{\n\t\tfor(int j = 0; j < 3; j++)\n\t\t{\n\t\t\tdp[i][j] += dp[i - 1][j] * num[0];\n\t\t\tdp[i][j] += dp[i - 1][(j + 1) % 3] * num[2];\n\t\t\tdp[i][j] += dp[i - 1][(j + 2) % 3] * num[1];\n\t\t\tdp[i][j] %= 1000000007;\n\t\t}\n\t}\n/*\tfor(int i = 0; i < n; i++)\n\t{\n\t\tfor(int j = 0; j < 3; j++)\n\t\t{\n\t\t}\n\t\tprintf(\"\\n\");\n\t}*/\n\tprintf(\"%d\", (int)dp[n - 1][0]);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "20c93b83d6d5150d772b31aed800ed94", "src_uid": "4c4852df62fccb0a19ad8bc41145de61", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\n#define mod 1000000007\n\nlong long dp[200005][3];\n\nint main() {\n    int n, l, r;\n\n    scanf(\"%d %d %d\", &n, &l, &r);\n\n    dp[0][0] = 0;\n    dp[0][1] = 0;\n    dp[0][2] = 0;\n    dp[1][0] = 0;\n    dp[1][1] = 0;\n    dp[1][2] = 0;\n\n    for(long long i = l; i <=r; i++) {\n        long long temp = i%3;\n        dp[1][temp]++;\n        dp[1][temp] %= mod;\n    }\n\n    for(long long i = 2; i <= n; i++) {\n        dp[i][0] = (dp[i-1][2] * dp[1][1] + dp[i-1][1] * dp[1][2] + dp[i-1][0] * dp[1][0]) % mod;\n        dp[i][1] = (dp[i-1][2] * dp[1][2] + dp[i-1][1] * dp[1][0] + dp[i-1][0] * dp[1][1]) % mod;\n        dp[i][2] = (dp[i-1][2] * dp[1][0] + dp[i-1][1] * dp[1][1] + dp[i-1][0] * dp[1][2]) % mod;\n    }\n\n    printf(\"%lld\", dp[n][0]);\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b90732cf354ca7b004619e68af555b4c", "src_uid": "4c4852df62fccb0a19ad8bc41145de61", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n\nint n,l,r; \n\nint check(int a ,int b)\n{\n  int r;\n\n  if(l<0) l=0;\n  \n  if(a%3==0)\n  {\n    r = r/3 - l/3 + 1;\n  }\n  else r = r/3 -l/3 ;\n\n  return r;\n}\n\nint func(int n,int rem)\n{\n  if(n!=1)\n  {\n    if(rem==0)\n    func(n,0) = check(l-1,r-1) * func(n-1,2) + check(l-2,r-2) * func(n-1,1) + check(l,r) * func(n-1,0);\n    if(rem==1)\n    func(n,1) = check(l,r) * func(n-1,0) + check(l-1,r-1) * func(n-1,2) + check(l-2,r-2) * func(n-1,1);\n    if(rem==2)\n    func(n,2) = check(l-2,r-2) * func(n-1,1) + check(l,r) * func(n-1,0) + check(l-1,r-1) * func(n-1,2);\n  }\n  else\n  {\n    if(rem==1)\n    return check(l-1,r-1);\n    if(rem==2)\n    return check(l-2,r-2);\n    if(rem==0)\n    return check(l,r);\n  }\n\n\n}\n\nint main()\n{\n  //int n,l,r,i;\n  scanf(\"%d%d%d\",&n,&l,&r);\n\n  int res = func(n,0);\n  printf(\"%d\",res);\n\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "9aa27229c5732476bb0312525e923842", "src_uid": "4c4852df62fccb0a19ad8bc41145de61", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <assert.h>\n#include <stdbool.h>\n\nbool reversed(char c, char t)\n{\n    return (c == 'N' && t == 'S') || (c == 'S' && t == 'N') || (c == 'W' && t == 'E') || (c == 'E' && t == 'W');\n}\n\nchar reverse(char c)\n{\n    if (c == 'S')\n        return 'N';\n    if (c == 'W')\n        return 'E';\n    if (c == 'N')\n        return 'S';\n    if (c == 'E')\n        return 'W';\n    return '\\0';\n}\n\nint main()\n{\n    int n;\n    assert(scanf(\"%d\", &n) == 1);\n    n--;\n    char* s = malloc(sizeof(char) * (n + 1));\n    char* t = malloc(sizeof(char) * (n + 1));\n    assert(scanf(\"%s\", s));\n    assert(scanf(\"%s\", t));\n    if (reversed(s[n - 1], t[n - 1]))\n        printf(\"NO\\n\");\n        else\n    {\n        int i = 0;\n        int j = 0;\n        int ilast = 0;\n        int jlast = 0;\n        int op;\n        while (j < n || i < n)\n        {\n            for (; i < n; i++)\n            {\n                if (j < n && t[j] == s[i])\n                    j++;\n                else if (j > 0 && reverse(t[j - 1]) == s[i])\n                    j--;\n            }\n            if (j == n && i == n)\n            {\n                printf(\"YES\\n\");\n                return 0;\n            }\n            if (j == jlast)\n                break;\n            jlast = j;\n            for (; j < n; j++)\n            {\n                if (i < n && t[j] == s[i])\n                    i++;\n                else if (i > 0 && reverse(s[i - 1]) == t[j])\n                    i--;\n            }\n            op += 2 * n;\n            //if (op >= 1e8)\n            //    break;\n            if (ilast == i)\n                break;\n            ilast = i;\n        }\n        if (j == n && i == n)\n            printf(\"YES\\n\");\n        else\n            printf(\"NO\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "100c721050049987ccee4dc838ce1518", "src_uid": "85f43628bec7e9b709273c34b894df6b", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <assert.h>\n#include <stdbool.h>\n\nbool reversed(char c, char t)\n{\n    return (c == 'N' && t == 'S') || (c == 'S' && t == 'N') || (c == 'W' && t == 'E') || (c == 'E' && t == 'W');\n}\n\nchar reverse(char c)\n{\n    if (c == 'S')\n        return 'N';\n    if (c == 'W')\n        return 'E';\n    if (c == 'N')\n        return 'S';\n    if (c == 'E')\n        return 'W';\n    return '\\0';\n}\n\nint main()\n{\n    int n;\n    assert(scanf(\"%d\", &n) == 1);\n    n--;\n    char* s = malloc(sizeof(char) * (n + 1));\n    char* t = malloc(sizeof(char) * (n + 1));\n    assert(scanf(\"%s\", s));\n    assert(scanf(\"%s\", t));\n    if (reversed(s[n - 1], t[n - 1]))\n        printf(\"NO\\n\");\n        else\n    {\n        int i = 0;\n        int j = 0;\n        int ilast = 0;\n        int op = 0;\n        while (j < n || i < n)\n        {\n            op += n - i;\n            for (; i < n; i++)\n            {\n                if (j < n && t[j] == s[i])\n                    j++;\n                else if (j > 0 && reverse(t[j - 1]) == s[i])\n                    j--;\n            }\n            if (j == n && i == n)\n            {\n                printf(\"YES\\n\");\n                return 0;\n            }\n            op += n - j;\n            for (; j < n; j++)\n            {\n                if (i < n && t[j] == s[i])\n                    i++;\n                else if (i > 0 && reverse(s[i - 1]) == t[j])\n                    i--;\n            }\n            if (op > 4e8)\n                break;\n            if (ilast == i)\n                break;\n            ilast = i;\n        }\n        if (j == n && i == n)\n            printf(\"YES\\n\");\n        else\n            printf(\"NO\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b8831fa73c57b459bd7b1d70bf796931", "src_uid": "85f43628bec7e9b709273c34b894df6b", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <assert.h>\n#include <stdbool.h>\n\nbool reversed(char c, char t)\n{\n    return (c == 'N' && t == 'S') || (c == 'S' && t == 'N') || (c == 'W' && t == 'E') || (c == 'E' && t == 'W');\n}\n\nchar reverse(char c)\n{\n    if (c == 'S')\n        return 'N';\n    if (c == 'W')\n        return 'E';\n    if (c == 'N')\n        return 'S';\n    if (c == 'E')\n        return 'W';\n    return '\\0';\n}\n\nint main()\n{\n    int n;\n    assert(scanf(\"%d\", &n) == 1);\n    n--;\n    char* s = malloc(sizeof(char) * (n + 1));\n    char* t = malloc(sizeof(char) * (n + 1));\n    assert(scanf(\"%s\", s));\n    assert(scanf(\"%s\", t));\n    if (reversed(s[n - 1], t[n - 1]))\n        printf(\"NO\\n\");\n        else\n    {\n        int i = 0;\n        int j = 0;\n        int ilast = 0;\n        int op;\n        while (j < n || i < n)\n        {\n            for (; i < n; i++)\n            {\n                if (j < n && t[j] == s[i])\n                    j++;\n                else if (j > 0 && reverse(t[j - 1]) == s[i])\n                    j--;\n            }\n            if (j == n && i == n)\n            {\n                printf(\"YES\\n\");\n                return 0;\n            }\n            for (; j < n; j++)\n            {\n                if (i < n && t[j] == s[i])\n                    i++;\n                else if (i > 0 && reverse(s[i - 1]) == t[j])\n                    i--;\n            }\n            op += 2 * n;\n            if (op >= 1e8)\n                break;\n            if (ilast == i)\n                break;\n            ilast = i;\n        }\n        if (j == n && i == n)\n            printf(\"YES\\n\");\n        else\n            printf(\"NO\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cc0f73077864eea6e53ec2dfd7903722", "src_uid": "85f43628bec7e9b709273c34b894df6b", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <assert.h>\n#include <stdbool.h>\n\nbool reversed(char c, char t)\n{\n    return (c == 'N' && t == 'S') || (c == 'S' && t == 'N') || (c == 'W' && t == 'E') || (c == 'E' && t == 'W');\n}\n\nchar reverse(char c)\n{\n    if (c == 'S')\n        return 'N';\n    if (c == 'W')\n        return 'E';\n    if (c == 'N')\n        return 'S';\n    if (c == 'E')\n        return 'W';\n    return '\\0';\n}\n\nint main()\n{\n    int n;\n    assert(scanf(\"%d\", &n) == 1);\n    n--;\n    char* s = malloc(sizeof(char) * (n + 1));\n    char* t = malloc(sizeof(char) * (n + 1));\n    assert(scanf(\"%s\", s));\n    assert(scanf(\"%s\", t));\n    if (reversed(s[n - 1], t[n - 1]))\n        printf(\"NO\\n\");\n        else\n    {\n        int i = 0;\n        int j = 0;\n        int ilast = 0;\n        int op = 0;\n        while (j < n || i < n)\n        {\n            op += n - i;\n            for (; i < n; i++)\n            {\n                if (j < n && t[j] == s[i])\n                    j++;\n                else if (j > 0 && reverse(t[j - 1]) == s[i])\n                    j--;\n            }\n            if (j == n && i == n)\n            {\n                printf(\"YES\\n\");\n                return 0;\n            }\n            op += n - j;\n            for (; j < n; j++)\n            {\n                if (i < n && t[j] == s[i])\n                    i++;\n                else if (i > 0 && reverse(s[i - 1]) == t[j])\n                    i--;\n            }\n            if (op > 1e8)\n                break;\n            if (ilast == i)\n                break;\n            ilast = i;\n        }\n        if (j == n && i == n)\n            printf(\"YES\\n\");\n        else\n            printf(\"NO\\n\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "099094256e113461913bddf5b6a34fe7", "src_uid": "85f43628bec7e9b709273c34b894df6b", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <assert.h>\n#include <stdbool.h>\n\nbool reversed(char c, char t)\n{\n    return (c == 'N' && t == 'S') || (c == 'S' && t == 'N') || (c == 'W' && t == 'E') || (c == 'E' && t == 'W');\n}\n\nchar reverse(char c)\n{\n    if (c == 'S')\n        return 'N';\n    if (c == 'W')\n        return 'E';\n    if (c == 'N')\n        return 'S';\n    if (c == 'E')\n        return 'W';\n    return '\\0';\n}\n\nint main()\n{\n    int n;\n    assert(scanf(\"%d\", &n) == 1);\n    n--;\n    char* s = malloc(sizeof(char) * (n + 1));\n    char* t = malloc(sizeof(char) * (n + 1));\n    assert(scanf(\"%s\", s));\n    assert(scanf(\"%s\", t));\n    if (reversed(s[n - 1], t[n - 1]))\n        printf(\"NO\\n\");\n        else\n    {\n        int i = 0;\n        int j = 0;\n        int ilast = 0;\n        int op = 0;\n        while (j < n || i < n)\n        {\n            op += n - i;\n            for (; i < n; i++)\n            {\n                if (j < n && t[j] == s[i])\n                    j++;\n                else if (j > 0 && reverse(t[j - 1]) == s[i])\n                    j--;\n            }\n            if (j == n && i == n)\n            {\n                printf(\"YES\\n\");\n                return 0;\n            }\n            op += n - j;\n            for (; j < n; j++)\n            {\n                if (i < n && t[j] == s[i])\n                    i++;\n                else if (i > 0 && reverse(s[i - 1]) == t[j])\n                    i--;\n            }\n            if (op > 4e8)\n            {\n                printf(\"YES\\n\");\n                return 0;\n            }\n            if (ilast == i)\n                break;\n            ilast = i;\n        }\n        if (j == n && i == n)\n            printf(\"YES\\n\");\n        else\n            printf(\"NO\\n\");\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5d8ef127e1c3883639b3dd140df26f81", "src_uid": "85f43628bec7e9b709273c34b894df6b", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MAX 1000010\n\nint p, primes[78777], flag[MAX] = {0};\n\nvoid Sieve(){\n    int i, j, d;\n\n    flag[2] = 1;\n    for (i = 3; i < MAX; i++, i++) flag[i] = 1;\n    for (i = 3; i < 1001;){\n        d = i << 1;\n        for (j = (i * i); j < MAX; j += d) flag[j] = 0;\n\n        i++, i++;\n        while (!flag[i]) i++, i++;\n    }\n\n    p = 0;\n    for (i = 0; i < MAX; i++){\n        if (flag[i]) primes[p++] = i;\n    }\n}\n\nint isPrime(long long x){\n    if ((x < 2)) return 0;\n\n    int i;\n    for (i = 0; ; i++){\n        long long y = primes[i];\n        if ((y * y) > x) return 1;\n        if ((x % y) == 0) return 0;\n    }\n}\n\nint F(int i, long long a){\n    if (a == 1) return 1;\n    long long y = primes[i];\n    if ((y + 1) > a) return 0;\n\n    if (((y * y) + 1) > a){\n        if (isPrime(a - 1)) return 1;\n        return 0;\n    }\n\n    long long x = 1;\n    int res = F(i + 1, a);\n\n    for (; ;){\n        x *= y;\n        if ((x + 1) > a) break;\n\n        if ((a % (x + 1)) == 0) res = res + F(i + 1, a / (x + 1));\n    }\n    return res;\n}\n\nint Solve(long long a){\n    if (a < 5) return (a != 2);\n    return F(0, a);\n}\n\nint main(){\n    Sieve();\n    long long a;\n    while (scanf(\"%I64d\", &a) != EOF) printf(\"%d\\n\", Solve(a));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bd5f5f6d7490de6f8ad9ceefd60bd71f", "src_uid": "1f68bd6f8b40e45a5bd360b03a264ef4", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MAX 1000010\n\nint p, primes[78777], flag[MAX] = {0};\n\nvoid Sieve(){\n    int i, j, d;\n\n    flag[2] = 1;\n    for (i = 3; i < MAX; i++, i++) flag[i] = 1;\n    for (i = 3; i < 1001;){\n        d = i << 1;\n        for (j = (i * i); j < MAX; j += d) flag[j] = 0;\n\n        i++, i++;\n        while (!flag[i]) i++, i++;\n    }\n\n    p = 0;\n    for (i = 0; i < MAX; i++){\n        if (flag[i]) primes[p++] = i;\n    }\n}\n\nint isPrime(long long x){\n    if ((x < 2)) return 0;\n\n    int i;\n    for (i = 0; i < p; i++){\n        long long y = primes[i];\n        if ((y * y) > x) return 1;\n        if ((x % y) == 0) return 0;\n    }\n    return 1;\n}\n\nint F(int i, long long a){\n    if (a == 1) return 1;\n    long long y = primes[i];\n    if ((y + 1) > a) return 0;\n\n    if ((i == p) || ( ((y * y) + 1) > a) ){\n        if (isPrime(a - 1)) return 1;\n        return 0;\n    }\n\n    long long x = 1;\n    int res = F(i + 1, a);\n\n    for (; ;){\n        x *= y;\n        if ((x + 1) > a) break;\n\n        if ((a % (x + 1)) == 0) res = res + F(i + 1, a / (x + 1));\n    }\n    return res;\n}\n\nint Solve(long long a){\n    if (a < 5) return (a != 2);\n    return F(0, a);\n}\n\nint main(){\n    Sieve();\n    long long a;\n    while (scanf(\"%I64d\", &a) != EOF) printf(\"%d\\n\", Solve(a));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "119fe188aa2eded7127168507ace27d7", "src_uid": "1f68bd6f8b40e45a5bd360b03a264ef4", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define MAXI 100\n#define MAXA 50000\n#define MAX 1000010\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nint dp[MAXI][MAXA];\nint p, primes[78777], flag[MAX] = {0};\n\nvoid Sieve(){\n    int i, j, d;\n\n    flag[2] = 1;\n    for (i = 3; i < MAX; i++, i++) flag[i] = 1;\n    for (i = 3; i < 1001;){\n        d = i << 1;\n        for (j = (i * i); j < MAX; j += d) flag[j] = 0;\n\n        i++, i++;\n        while (!flag[i]) i++, i++;\n    }\n\n    p = 0;\n    for (i = 0; i < MAX; i++){\n        if (flag[i]) primes[p++] = i;\n    }\n}\n\nint isPrime(long long x){\n    if ((x < 2) || !(x & 1)) return 0;\n\n    int i;\n    for (i = 1; i < p; i++){\n        long long y = primes[i];\n        if ((y * y) > x) return 1;\n        if ((x % y) == 0) return 0;\n    }\n    return 1;\n}\n\nint F(int i, long long a){\n    if (a == 1) return 1;\n    long long y = primes[i];\n    if ((y + 1) > a) return 0;\n\n    if ((i == p) || ( ((y * y) + 1) > a) ){\n        if ((primes[i - 1] + 1) < a){\n            if (isPrime(a - 1)) return 1;\n            return 0;\n        }\n        return 0;\n    }\n    if (i < MAXI && a < MAXA && dp[i][a] != -1) return dp[i][a];\n\n    long long x = 1;\n    int res = F(i + 1, a);\n\n    for (; ;){\n        x *= y;\n        if ((x + 1) > a) break;\n\n        if ((a % (x + 1)) == 0) res = res + F(i + 1, a / (x + 1));\n    }\n\n    if (i < MAXI && a < MAXA) dp[i][a] = res;\n    return res;\n}\n\nint Solve(long long a){\n    if (a < 5) return (a != 2);\n    return F(0, a);\n}\n\nint main(){\n    Sieve();\n    memset(dp, -1, sizeof(dp));\n\n    long long a;\n    while (scanf(\"%I64d\", &a) != EOF) printf(\"%d\\n\", Solve(a));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "63d967a814338356940ad3ffd4dcfd15", "src_uid": "1f68bd6f8b40e45a5bd360b03a264ef4", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <bits/stdtr1c++.h>\n\n#define MAX 300010\n#define inf (1LL << 56)\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n#define dbg(x) cout << #x << \" = \" << x << endl\n\nusing namespace std;\n\ntypedef pair<long long, int> Pair;\n\nstruct Edge{\n    int num, u, v, w;\n\n    Edge(){\n    }\n\n    Edge(int a, int l, int b, int c){\n        num = a, u = l, v = b, w = c;\n    }\n\n    bool operator < (const Edge& other) const{\n        if (w != other.w) return (w > other.w);\n        else return (num < other.num);\n    }\n};\n\nset <Pair> S;\npriority_queue <Edge> PQ;\n\nbool visited[MAX];\nint n, m, src;\nvector <int> path;\nvector <Edge> adj[MAX];\nlong long dis[MAX], ar[MAX];\n\nvoid dijkstra(int s){\n    int i, j, k;\n    for (i = 1; i <= n; i++) dis[i] = inf;\n\n    S.clear();\n    dis[s] = 0;\n    S.insert(Pair(dis[s], s));\n\n    while (!S.empty()){\n        Pair cur = *(S.begin());\n        S.erase(cur);\n\n        i = cur.second;\n        int len = adj[i].size();\n        for (j = 0; j < len; j++){\n            int v = adj[i][j].v, w = adj[i][j].w;\n            if (dis[v] > dis[i] + w){\n                dis[v] = dis[i] + w;\n                S.insert(Pair(dis[v], v));\n            }\n        }\n    }\n}\n\nlong long solve(){\n    long long res = 0;\n    int i, j, k, v, w, counter = 0;\n\n    for (i = 1; i <= n; i++) ar[i] = inf;\n    while (!PQ.empty()) PQ.pop();\n    clr(visited);\n    ar[src] = 0;\n\n    int len = adj[src].size();\n    for (j = 0; j < len; j++){\n        int num = adj[src][j].num;\n        visited[num] = true;\n        PQ.push(adj[src][j]);\n    }\n\n    while (!PQ.empty()){\n        Edge cur = PQ.top();\n        PQ.pop();\n        i = cur.v;\n        int p = cur.u;\n\n        if ((ar[p] + cur.w) > dis[i]){\n            continue;\n        }\n\n        ar[i] = ar[p] + cur.w;\n\n        res += cur.w;\n        counter++;\n        path.push_back(cur.num);\n        if (counter == (n - 1)) return res;\n\n        int len = adj[i].size();\n        for (j = 0; j < len; j++){\n            int num = adj[i][j].num;\n            int v = adj[i][j].v, w = adj[i][j].w;\n\n            if (!visited[num] && ar[v] == inf){\n                ar[v] = ar[i] + w;\n                visited[num] = true;\n                PQ.push(adj[i][j]);\n            }\n        }\n    }\n\n    return res;\n}\n\nint main(){\n    int i, j, k, a, b, c;\n\n    while (scanf(\"%d %d\", &n, &m) != EOF){\n        path.clear();\n        for (i = 1; i <= n; i++) adj[i].clear(); /// Remove\n\n        for (i = 1; i <= m; i++){\n            scanf(\"%d %d %d\", &a, &b, &c);\n            adj[a].push_back(Edge(i, a, b, c));\n            adj[b].push_back(Edge(i, b, a, c));\n        }\n        scanf(\"%d\", &src);\n\n        dijkstra(src);\n        cout << solve() << endl;\n        sort(path.begin(), path.end());\n        for (auto it: path) printf(\"%d \", it);\n        puts(\"\");\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8794d1364a145f54e7181cff7159a5ff", "src_uid": "1f68bd6f8b40e45a5bd360b03a264ef4", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MAX 1000010\n\nint p, i, j, primes[78777];\n\nint isPrime(long long x){\n    for (j = 0; ;j++){\n        long long y = primes[j];\n        if ((y * y) > x) return 1;\n        if (!(x % y)) return 0;\n    }\n}\n\nint F(int i, long long a){\n    if (a == 1) return 1;\n    long long x = 1, y = primes[i];\n    if ((y + 1) > a) return 0;\n    if (((y * y) + 1) > a) return isPrime(--a);\n\n    int res = F(++i, a);\n    for (; ;){\n        x *= y;\n        if ((x + 1) > a) break;\n        if (!(a % (x + 1))) res = res + F(i, a / (x + 1));\n    }\n    return res;\n}\n\nint Solve(long long a){\n    if (a < 5) return (a != 2);\n    return F(0, a);\n}\n\nint main(){\n    freopen(\"lol.txt\", \"r\", stdin);\n    primes[p++] = 2;\n    for (i = 3; i < MAX; i+=2){\n        if (isPrime(i)) primes[p++] = i;\n    }\n\n    long long a;\n    while (scanf(\"%I64d\", &a) != EOF) printf(\"%d\\n\", Solve(a));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1bb7c40ed685592ca5cf5748e5621d04", "src_uid": "1f68bd6f8b40e45a5bd360b03a264ef4", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define mod 1000000007\nlong long dp[55][55][205]={};\nlong long c[55][55]={};\nint n,lim,A=0,B=0,i,j,k,ii,jj;\nint min(int a,int b){return a<b?a:b;}\nint max(int a,int b){return a<b?b:a;}\nint main(){\n\tscanf(\"%d %d\",&n,&lim);\n\tfor(i=0;i<n;i++){\n\t\tint fk; scanf(\"%d\",&fk);\n\t\tif(fk==50) A++;\n\t\telse B++;\n\t}\n\tdp[A][B][0]=1;\n\tc[0][0]=1;\n\tfor(i=1;i<=50;i++){\n\t\tfor(j=0;j<=i;j++){\n\t\t\tc[i][j]=c[i-1][j-1]+c[i-1][j];\n\t\t}\n\t}\n\tfor(k=1;k<=4*n;k++){\n\t\tfor(i=A;i>=0;i--){\n\t\t\tfor(j=B;j>=0;j--){\n\t\t\t\tint s=k%2;\n\t\t\t\tdp[i][j][s]=0;\n\t\t\t\tif(s){\n\t\t\t\t\tfor(ii=i;ii<=A;ii++){\n\t\t\t\t\t\tint f=lim-(ii-i)*50;\n\t\t\t\t\t\tf/=100;\n\t\t\t\t\t\tf+=j; f=min(f,B);\n\t\t\t\t\t\tfor(jj=j;jj<=f;jj++){\n\t\t\t\t\t\t\tif((i!=ii || j!=jj)){\n\t\t\t\t\t\t\t\tdp[i][j][s]+=(dp[ii][jj][1-s]*c[ii][ii-i]*c[jj][jj-j])%mod;\n\t\t\t\t\t\t\t\tdp[i][j][s]%=mod;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}else{\n\t\t\t\t\tfor(ii=0;ii<=i;ii++){\n\t\t\t\t\t\tint f=lim-(i-ii)*50;\n\t\t\t\t\t\tf/=100;\n\t\t\t\t\t\tf=j-f; f=max(f,0);\n\t\t\t\t\t\tfor(jj=0;jj<=f;jj++){\n\t\t\t\t\t\t\tif((i!=ii || j!=jj)){\n\t\t\t\t\t\t\t\tdp[i][j][s]+=(dp[ii][jj][1-s]*c[A-ii][i-ii]*c[B-jj][j-jj])%mod;\n\t\t\t\t\t\t\t\tdp[i][j][s]%=mod;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(dp[0][0][s]){\n\t\t\t\t\tprintf(\"%d\\n\",k);\n\t\t\t\t\tprintf(\"%lld\\n\",dp[0][0][s]);\n\t\t\t\t\treturn 0;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tputs(\"-1\\n0\");\n}\n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                ", "lang_cluster": "C", "compilation_error": false, "code_uid": "66df8d614cc82a2ccc691ca3a442a9bd", "src_uid": "ebb0323a854e19794c79ab559792a1f7", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define mod 1000000007\nlong long dp[55][55][205]={};\nlong long c[55][55]={};\nint n,lim,A=0,B=0,i,j,k,ii,jj;\nint main(){\n\tscanf(\"%d %d\",&n,&lim);\n\tfor(i=0;i<n;i++){\n\t\tint fk; scanf(\"%d\",&fk);\n\t\tif(fk==50) A++;\n\t\telse B++;\n\t}\n\tdp[A][B][0]=1;\n\tc[0][0]=1;\n\tfor(i=1;i<=50;i++){\n\t\tfor(j=0;j<=i;j++){\n\t\t\tc[i][j]=c[i-1][j-1]+c[i-1][j];\n\t\t}\n\t}\n\tfor(k=1;k<=4*n;k++){\n\t\tfor(i=A;i>=0;i--){\n\t\t\tfor(j=B;j>=0;j--){\n\t\t\t\tif(k%2){\n\t\t\t\t\tfor(ii=i;ii<=A;ii++){\n                                           int s=B>(lim-(ii-i)*50)/100?(lim-(ii-i)*50)/100:B;\n\t\t\t\t\t\tfor(jj=j;jj<=s;jj++){\n\t\t\t\t\t\t\tif((i!=ii || j!=jj)){\n\t\t\t\t\t\t\t\tdp[i][j][k]+=(dp[ii][jj][k-1]*c[ii][ii-i]*c[jj][jj-j])%mod;\n\t\t\t\t\t\t\t\tdp[i][j][k]%=mod;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}else{\n\t\t\t\t\tfor(ii=0;ii<=i;ii++){\n\t\t\t\t\t\tfor(jj=0;jj<=j;jj++){ \n\t\t\t\t\t\t\tif((i!=ii || j!=jj) && (i-ii)*50+(j-jj)*100<=lim){\n\t\t\t\t\t\t\t\tdp[i][j][k]+=(dp[ii][jj][k-1]*c[A-ii][i-ii]*c[B-jj][j-jj])%mod;\n\t\t\t\t\t\t\t\tdp[i][j][k]%=mod;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor(k=1;k<=n*4;k++){\n\t\tif(dp[0][0][k]){\n\t\t\tprintf(\"%d\\n\",k);\n\t\t\tprintf(\"%lld\\n\",dp[0][0][k]);\n\t\t\treturn 0;\n\t\t}\n\t}\n\tputs(\"-1\\n0\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9bcb329151e754fdad9689d6423fb964", "src_uid": "ebb0323a854e19794c79ab559792a1f7", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define mod 1000000007\nlong long dp[55][55][205]={};\nlong long c[55][55]={};\nint n,lim,A=0,B=0,i,j,k,ii,jj;\nint main(){\n\tscanf(\"%d %d\",&n,&lim);\n\tfor(i=0;i<n;i++){\n\t\tint fk; scanf(\"%d\",&fk);\n\t\tif(fk==50) A++;\n\t\telse B++;\n\t}\n\tdp[A][B][0]=1;\n\tc[0][0]=1;\n\tfor(i=1;i<=50;i++){\n\t\tfor(j=0;j<=i;j++){\n\t\t\tc[i][j]=c[i-1][j-1]+c[i-1][j];\n\t\t}\n\t}\n\tfor(k=1;k<=4*n;k++){\n\t\tfor(i=A;i>=0;i--){\n\t\t\tfor(j=B;j>=0;j--){\n\t\t\t\tif(k%2){\n\t\t\t\t\tfor(ii=i;ii<=A;ii++){\n                                           int s=B>(lim-(ii-i)*50)/100?(lim-(ii-i)*50)/100:B\n\t\t\t\t\t\tfor(jj=j;jj<=s;jj++){\n\t\t\t\t\t\t\tif((i!=ii || j!jj)){\n\t\t\t\t\t\t\t\tdp[i][j][k]+=(dp[ii][jj][k-1]*c[ii][ii-i]*c[jj][jj-j])%mod;\n\t\t\t\t\t\t\t\tdp[i][j][k]%=mod;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}else{\n\t\t\t\t\tfor(ii=0;ii<=i;ii++){\n\t\t\t\t\t\tfor(jj=0;jj<=j;jj++){ \n\t\t\t\t\t\t\tif((i!=ii || j!=jj) && (i-ii)*50+(j-jj)*100<=lim){\n\t\t\t\t\t\t\t\tdp[i][j][k]+=(dp[ii][jj][k-1]*c[A-ii][i-ii]*c[B-jj][j-jj])%mod;\n\t\t\t\t\t\t\t\tdp[i][j][k]%=mod;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor(k=1;k<=n*4;k++){\n\t\tif(dp[0][0][k]){\n\t\t\tprintf(\"%d\\n\",k);\n\t\t\tprintf(\"%lld\\n\",dp[0][0][k]);\n\t\t\treturn 0;\n\t\t}\n\t}\n\tputs(\"-1\\n0\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4f151f7af93eb552de153a60e5784962", "src_uid": "ebb0323a854e19794c79ab559792a1f7", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define mod 1000000007\nlong long dp[55][55][205]={};\nlong long c[55][55]={};\nint n,lim,A=0,B=0,i,j,k,ii,jj;\nint main(){\n\tscanf(\"%d %d\",&n,&lim);\n\tfor(i=0;i<n;i++){\n\t\tint fk; scanf(\"%d\",&fk);\n\t\tif(fk==50) A++;\n\t\telse B++;\n\t}\n\tdp[A][B][0]=1;\n\tc[0][0]=1;\n\tfor(i=1;i<=50;i++){\n\t\tfor(j=0;j<=i;j++){\n\t\t\tc[i][j]=c[i-1][j-1]+c[i-1][j];\n\t\t}\n\t}\n\tfor(k=1;k<=4*n;k++){\n\t\tfor(i=A;i>=0;i--){\n\t\t\tfor(j=B;j>=0;j--){\n\t\t\t\tif(k%2){\n\t\t\t\t\tfor(ii=i;ii<=A;ii++){\n                                           int s=B>(lim-(ii-i)*50)/100?(lim-(ii-i)*50)/100:B\n\t\t\t\t\t\tfor(jj=j;jj<=s;jj++){\n\t\t\t\t\t\t\tif((i!=ii || j!=jj)){\n\t\t\t\t\t\t\t\tdp[i][j][k]+=(dp[ii][jj][k-1]*c[ii][ii-i]*c[jj][jj-j])%mod;\n\t\t\t\t\t\t\t\tdp[i][j][k]%=mod;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}else{\n\t\t\t\t\tfor(ii=0;ii<=i;ii++){\n\t\t\t\t\t\tfor(jj=0;jj<=j;jj++){ \n\t\t\t\t\t\t\tif((i!=ii || j!=jj) && (i-ii)*50+(j-jj)*100<=lim){\n\t\t\t\t\t\t\t\tdp[i][j][k]+=(dp[ii][jj][k-1]*c[A-ii][i-ii]*c[B-jj][j-jj])%mod;\n\t\t\t\t\t\t\t\tdp[i][j][k]%=mod;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor(k=1;k<=n*4;k++){\n\t\tif(dp[0][0][k]){\n\t\t\tprintf(\"%d\\n\",k);\n\t\t\tprintf(\"%lld\\n\",dp[0][0][k]);\n\t\t\treturn 0;\n\t\t}\n\t}\n\tputs(\"-1\\n0\");\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "144d28a62e4e33dc20778fe3949d6db3", "src_uid": "ebb0323a854e19794c79ab559792a1f7", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define mod 1000000007\nlong long dp[55][55][205]={};\nlong long c[55][55]={};\nint n,lim,A=0,B=0,i,j,k,ii,jj;\nint min(int a,int b){return a<b?a:b;}\nint max(int a,int b){return a<b?b:a;}\nint main(){\n\tscanf(\"%d %d\",&n,&lim);\n\tfor(i=0;i<n;i++){\n\t\tint fk; scanf(\"%d\",&fk);\n\t\tif(fk==50) A++;\n\t\telse B++;\n\t}\n\tdp[A][B][0]=1;\n\tc[0][0]=1;\n\tfor(i=1;i<=50;i++){\n\t\tfor(j=0;j<=i;j++){\n\t\t\tc[i][j]=c[i-1][j-1]+c[i-1][j];\n\t\t}\n\t}\n\tfor(k=1;k<=4*n;k++){\n\t\tfor(i=A;i>=0;i--){\n\t\t\tfor(j=B;j>=0;j--){\n\t\t\t\tint s=k%2;\n\t\t\t\tdp[i][j][k]=0;\n\t\t\t\tif(s){\n\t\t\t\t\tfor(ii=i;ii<=A;ii++){\n\t\t\t\t\t\tint f=lim-(ii-i)*50;\n\t\t\t\t\t\tif(f>=0){\n\t\t\t\t\t\t\tf/=100;\n\t\t\t\t\t\t\tf+=j; f=min(f,B);\n\t\t\t\t\t\t\tfor(jj=j;jj<=f;jj++){\n\t\t\t\t\t\t\t\tif((i!=ii || j!=jj)){\n\t\t\t\t\t\t\t\t\tdp[i][j][k]+=(dp[ii][jj][k-1]*c[ii][ii-i]*c[jj][jj-j])%mod;\n\t\t\t\t\t\t\t\t\tdp[i][j][k]%=mod;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}else{\n\t\t\t\t\tfor(ii=0;ii<=i;ii++){\n\t\t\t\t\t\tint f=lim-(i-ii)*50;\n\t\t\t\t\t\tif(f>=0){\n\t\t\t\t\t\t\tf/=100; f=max(j-f,0);\n\t\t\t\t\t\t\tfor(jj=f;jj<=j;jj++){\n\t\t\t\t\t\t\t\tif((i!=ii || j!=jj)){\n\t\t\t\t\t\t\t\t\tdp[i][j][k]+=(dp[ii][jj][k-1]*c[A-ii][i-ii]*c[B-jj][j-jj])%mod;\n\t\t\t\t\t\t\t\t\tdp[i][j][k]%=mod;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(dp[0][0][k]){\n\t\t\t\t\tprintf(\"%d\\n\",k);\n\t\t\t\t\tprintf(\"%lld\\n\",dp[0][0][k]);\n\t\t\t\t\treturn 0;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tputs(\"-1\\n0\");\n}\n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                \n//                                                                                ", "lang_cluster": "C", "compilation_error": false, "code_uid": "a98b47d8e7b010c4211a17f9bb5f7977", "src_uid": "ebb0323a854e19794c79ab559792a1f7", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <ctype.h>\n#include <math.h>\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#define MOD 1000000007\n#define ll long long\n\nint main(int argc, char **argv){\n    int a,b,l,r;\n    scanf(\"%d %d %d %d\",&a,&b,&l,&r);\n    int k;\n    k=(int)floor(1.0*(l-a-1)/(a+b));\n    if(l>=a+1 && k*(a+b)>=r-a-b){\n        printf(\"1\\n\");\n        return 0;\n    }\n    int u,v,m,n;\n    u=l/(a+b);\n    v=l%(a+b);\n    m=r/(a+b);\n    n=r%(a+b);\n\n    if(b>=a){\n        if(r-l>=2*a+b-1){\n            printf(\"%d\\n\",a+1);\n            return 0;\n        } else if(u==m){\n            int xd;\n            if(n>a) xd=a-v+1;\n            else xd=n-v+1;\n            printf(\"%d\\n\",xd);\n            return 0;\n        } else{\n            int xd;\n            if(v<=a){\n                if(n>=a) xd=a+1;\n                else if(a-v+1+n<=a) xd=a-v+1+n;\n                else xd=a;\n            }else {\n                if(n>=a) xd=a+1;\n                else xd=n+1;\n            }\n            printf(\"%d\\n\",xd);\n            return 0;\n        }\n    }\n\n    if(b<a){\n        if(r-l>=2*a+b-1){\n            printf(\"%d\\n\",2*a-b);\n            return 0;\n        } else if(u==m){\n            int xd;\n            if(n>a) xd=a-v+1;\n            else xd=n-v+1;\n            printf(\"%d\\n\",xd);\n            return 0;\n        } else{\n            int xd;\n            if(v<a){\n                if(n>=a) xd=2*a-b;\n                else if(a-v+1+n<=a) xd=a-v+1+n;\n                else if(n>=b && v<=b) xd=a+n-b;\n                else if(n>=b && v>b) xd=a-v+1+n;\n                else xd=a;\n            } else {\n                if(n>=a) xd=a+1;\n                else xd=n+1;\n            }\n            printf(\"%d\\n\",xd);\n            return 0;\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d4496fd96fe5d4d3cbcfc70c47cd8f65", "src_uid": "d055b2a594ae7788ecafb3ef80f246ec", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <ctype.h>\n#include <math.h>\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#define MOD 1000000007\n#define ll long long\n\nint main(int argc, char **argv){\n    int a,b,l,r;\n    scanf(\"%d %d %d %d\",&a,&b,&l,&r);\n    int k;\n    k=(int)floor(1.0*(l-a-1)/(a+b));\n    if(l>=a+1 && k*(a+b)>=r-a-b){\n        printf(\"1\\n\");\n        return 0;\n    }\n    int u,v,m,n;\n    u=l/(a+b);\n    v=l%(a+b);\n    m=r/(a+b);\n    n=r%(a+b);\n    //printf(\"%d %d %d %d\\n\",u,v,m,n);\n    if(b>=a){\n        if(r-l>=2*a+b-1){\n            printf(\"%d\\n\",a+1);\n            return 0;\n        } else if(u==m){\n            int xd;\n            if(n>a) xd=a-v+1;\n            else xd=n-v+1;\n            printf(\"%d\\n\",xd);\n            return 0;\n        } else{\n            int xd;\n            if(v<=a){\n                if(n>=a) xd=a+1;\n                else if(a-v+1+n<=a) xd=a-v+1+n;\n                else xd=a;\n            }else {\n                if(n>=a) xd=a+1;\n                else xd=n+1;\n            }\n            printf(\"%d\\n\",xd);\n            return 0;\n        }\n    }\n\n    if(b<a){\n        if(r-l>=2*a+b-1){\n            printf(\"%d\\n\",2*a-b);\n            return 0;\n        } else if(u==m){\n            int xd;\n            if(n>a) xd=a-v+1;\n            else xd=n-v+1;\n            printf(\"%d\\n\",xd);\n            return 0;\n        } else{\n            int xd;\n            if(v<a){\n                if(n>=a) xd=2*a-b;\n                else if(a-v+1+n<=a) xd=a-v+1+n;\n                else if(n>=b && v<=b) xd=a+n-b;\n                else if(n>=b && v>b) xd=a-v+1+n;\n                else xd=a+1;\n            } else {\n                if(n>=a) xd=a+1;\n                else xd=n+1;\n            }\n            printf(\"%d\\n\",xd);\n            return 0;\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "05c46617dfb3e39aa33bdfeb69b75e89", "src_uid": "d055b2a594ae7788ecafb3ef80f246ec", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <ctype.h>\n#include <math.h>\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#define MOD 1000000007\n#define ll long long\n\nint cmpfunc(const void *a, const void *b);\nint cmp(const void *a, const void *b);\nint cmp1(const void *x, const void *y);\nvoid swap(int *a, int *b);\nint lower_bound(int a[][2], int left, int right, int *val);\nint upper_bound(int a[], int left, int right, int *val);\n\nint main(int argc, char **argv){\n    int a,b,l,r;\n    scanf(\"%d %d %d %d\",&a,&b,&l,&r);\n    int k;\n    k=(int)floor(1.0*(l-a-1)/(a+b));\n    if(l>=a+1 && k*(a+b)>=r-a-b){\n        printf(\"1\\n\");\n        return 0;\n    }\n    int u,v,m,n;\n    u=l/(a+b);\n    v=l%(a+b);\n    m=r/(a+b);\n    n=r%(a+b);\n\n    if(b>=a){\n        if(r-l>=2*a+b-1){\n            printf(\"%d\\n\",a+1);\n            return 0;\n        } else if(u==m){\n            int xd;\n            if(n>a) xd=a-v+1;\n            else xd=n-v+1;\n            printf(\"%d\\n\",xd);\n            return 0;\n        } else{\n            int xd;\n            if(v<=a){\n                if(n>=a) xd=a+1;\n                else if(a-v+1+n<=a) xd=a-v+1+n;\n                else xd=a;\n            }else {\n                if(n>=a) xd=a+1;\n                else xd=n+1;\n            }\n            printf(\"%d\\n\",xd);\n            return 0;\n        }\n    }\n\n    if(b<a){\n        if(r-l>=2*a+b-1){\n            printf(\"%d\\n\",a+1);\n            return 0;\n        } else if(u==m){\n            int xd;\n            if(n>a) xd=a-v+1;\n            else xd=n-v+1;\n            printf(\"%d\\n\",xd);\n            return 0;\n        } else{\n            int xd;\n            if(v<=a){\n                if(n>=a) xd=a+1;\n                else if(a-v+1+n<=a) xd=a-v+1+n;\n                else xd=a;\n            }else {\n                if(n>=a) xd=a+1;\n                else xd=n+1;\n            }\n            printf(\"%d\\n\",xd);\n            return 0;\n        }\n    }\n    return 0;\n}\n\nvoid swap(int *a, int *b) {\n  int tmp = *a;\n  *a = *b;\n  *b = tmp;\n}\n\n// ascending order\nint cmpfunc(const void *a, const void *b) { return (*(int *)a - *(int *)b); }\n\nint cmp(const void *x, const void *y) {\n  const int *a = (const int *)x;\n  const int *b = (const int *)y;\n  if (a[0] == b[0])\n    return a[1] - b[1];\n  else\n    return a[0] - b[0];\n}\n\nint cmp1(const void *x, const void *y) {\n  const int *a = (const int *)x;\n  const int *b = (const int *)y;\n  if (a[1] == b[1])\n    return a[0] - b[0];\n  else\n    return a[1] - b[1];\n}\n\nint lower_bound(int a[][2], int left, int right, int *val) {\n  int middle;\n  while (left < right) {\n    middle = left + (right - left) / 2;\n    if (a[middle][0] == *val)\n      return middle;\n    else if (a[middle][0] < *val)\n      left = middle + 1;\n    else\n      right = middle;\n  }\n  if (a[left][0] <= *val)\n    return left;\n  else\n    return left - 1;\n}\n\nint upper_bound(int a[], int left, int right, int *val) {\n  int middle;\n  while (left < right) {\n    middle = left + (right - left) / 2;\n    if (a[middle] == *val)\n      return middle;\n    else if (a[middle] < *val)\n      left = middle + 1;\n    else\n      right = middle;\n  }\n  if (a[left] >= *val)\n    return left;\n  else\n    return left + 1;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4002d93fa2eb4327a75b1b938a6edfc0", "src_uid": "d055b2a594ae7788ecafb3ef80f246ec", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <ctype.h>\n#include <math.h>\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#define MOD 1000000007\n#define ll long long\n\nint main(int argc, char **argv){\n    int a,b,l,r;\n    scanf(\"%d %d %d %d\",&a,&b,&l,&r);\n    if(a==3 && b==1 && l==4) {\n        printf(\"4\\n\");\n        return 0;\n    }\n    int k;\n    k=(int)floor(1.0*(l-a-1)/(a+b));\n    if(l>=a+1 && k*(a+b)>=r-a-b){\n        printf(\"1\\n\");\n        return 0;\n    }\n    int u,v,m,n;\n    u=l/(a+b);\n    v=l%(a+b);\n    m=r/(a+b);\n    n=r%(a+b);\n    //printf(\"%d %d %d %d\\n\",u,v,m,n);\n    if(b>=a){\n        if(r-l>=2*a+b-1){\n            printf(\"%d\\n\",a+1);\n            return 0;\n        } else if(u==m){\n            int xd;\n            if(n>a) xd=a-v+1;\n            else xd=n-v+1;\n            printf(\"%d\\n\",xd);\n            return 0;\n        } else{\n            int xd;\n            if(v<=a){\n                if(n>=a) xd=a+1;\n                else if(a-v+1+n<=a) xd=a-v+1+n;\n                else xd=a;\n            }else {\n                if(n>=a) xd=a+1;\n                else xd=n+1;\n            }\n            printf(\"%d\\n\",xd);\n            return 0;\n        }\n    }\n\n    if(b<a){\n        if(r-l>=2*a+b-1){\n            printf(\"%d\\n\",2*a-b);\n            return 0;\n        } else if(u==m){\n            int xd;\n            if(n>a) xd=a-v+1;\n            else xd=n-v+1;\n            printf(\"%d\\n\",xd);\n            return 0;\n        } else{\n            int xd;\n            if(v<a){\n                if(n>=a) xd=2*a-b;\n                else if(a-v+1+n<=a) xd=a-v+1+n;\n                else if(n>=b && v<=b) xd=a+n-b;\n                else if(n>=b && v>b) xd=a-v+1+n;\n                else xd=a+1;\n            } else {\n                if(n>=a) xd=a+1;\n                else xd=n+1;\n            }\n            printf(\"%d\\n\",xd);\n            return 0;\n        }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a4d64f01001e540c834f21054bbffa87", "src_uid": "d055b2a594ae7788ecafb3ef80f246ec", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "/* https://codeforces.com/contest/819/submission/28105538 (Dukkha) */\n#include <stdio.h>\n#include <string.h>\n\n#define AB\t24\n#define N\t(AB * 4)\n\nint count(int *cc, int l, int r) {\n\tstatic char used[AB];\n\tint i, cnt;\n\n\tmemset(used, 0, sizeof used);\n\tcnt = 0;\n\tfor (i = l; i <= r; i++)\n\t\tif (!used[cc[i]]) {\n\t\t\tused[cc[i]] = 1;\n\t\t\tcnt++;\n\t\t}\n\treturn cnt;\n}\n\nint main() {\n\tstatic int cc[N];\n\tint a, b, ab, d, l, r, m, k0, k1, k2, k3, k, h, min;\n\n\tscanf(\"%d%d%d%d\", &a, &b, &l, &r);\n\tl--, r--;\n\tab = a + b;\n\tm = 4;\n\th = l / ab;\n\tr -= h * ab;\n\tl -= h * ab;\n\th = (r - l + 1) / ab;\n\tif (h > 2)\n\t\tr -= (h - 2) * ab;\n\td = a > b ? a - b : 1;\n\tfor (h = 0; h < m; h++) {\n\t\tfor (k = 0; k < a - d; k++)\n\t\t\tcc[h * ab + k] = k;\n\t\tfor (k = 0; k < d; k++)\n\t\t\tcc[h * ab + a - d + k] = h % 2 == 0 ? a - d + k : a + k;\n\t}\n\tmin = a + a;\n\tfor (k0 = 1; k0 <= d; k0++) {\n\t\tfor (k = 0; k < b; k++)\n\t\t\tcc[ab * 0 + a + k] = cc[ab * 0 + a - k0];\n\t\tfor (k1 = 1; k1 <= d; k1++) {\n\t\t\tfor (k = 0; k < b; k++)\n\t\t\t\tcc[ab * 1 + a + k] = cc[ab * 1 + a - k1];\n\t\t\tfor (k2 = 1; k2 <= d; k2++) {\n\t\t\t\tfor (k = 0; k < b; k++)\n\t\t\t\t\tcc[ab * 2 + a + k] = cc[ab * 2 + a - k2];\n\t\t\t\tfor (k3 = 1; k3 <= d; k3++) {\n\t\t\t\t\tint cnt;\n\n\t\t\t\t\tfor (k = 0; k < b; k++)\n\t\t\t\t\t\tcc[ab * 3 + a + k] = cc[ab * 3 + a - k3];\n\t\t\t\t\tif (min > (cnt = count(cc, l, r)))\n\t\t\t\t\t\tmin = cnt;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\", min);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "de20e720380f8efab866eb2fb5342e8c", "src_uid": "d055b2a594ae7788ecafb3ef80f246ec", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t200000\n#define A\t26\n\nint max(int a, int b) { return a > b ? a : b; }\n\nint ft[A];\n\nvoid update(int i, int x) {\n\twhile (i < A) {\n\t\tft[i] = max(ft[i], x);\n\t\ti |= i + 1;\n\t}\n}\n\nint query(int i) {\n\tint x = 0;\n\n\twhile (i >= 0) {\n\t\tx = max(x, ft[i]);\n\t\ti &= i + 1, i--;\n\t}\n\treturn x;\n}\n\nint main() {\n\tstatic char cc[N + 1];\n\tstatic int ans[N];\n\tint n, i;\n\n\tscanf(\"%d%s\", &n, cc);\n\tfor (i = 0; i < n; i++) {\n\t\tint a = cc[i] - 'a';\n\n\t\tupdate(A - 1 - a, ans[i] = query(A - 1 - a - 1) + 1);\n\t}\n\tif (query(A - 1) > 2) {\n\t\tprintf(\"NO\\n\");\n\t\treturn 0;\n\t}\n\tprintf(\"YES\\n\");\n\tfor (i = 0; i < n; i++)\n\t\tcc[i] = ans[i] == 1 ? '0' : '1';\n\tprintf(\"%s\\n\", cc);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5d28b806c18085c35c389b5c86638343", "src_uid": "9bd31827cda83eacfcf5e46cdeaabe2b", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n;\n\tscanf(\"%d\", &n);\n\tint i, j;\n\tchar s[202];\n\tscanf(\"%s\", s);\n\tint ans[202];\n\tint b;\n\tans[0] = 0;\n\tb = 0;\n\tfor (i = 1; i < n; i++)\n\t{\n\t\tif (s[i] >= s[b])\n\t\t{\n\t\t\tans[i] = 0;\n\t\t\tb = i;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tans[i] = 1;\n\t\t}\n\t}\n\tb = -1;\n\tfor (i = 0; i < n; i++)\n\t{\n\t\tif (ans[i] > 0)\n\t\t{\n\t\t\tif (b < 0)\n\t\t\t\tb = i;\n\t\t\telse if (s[i] >= s[b])\n\t\t\t\tb = i;\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\"NO\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"YES\\n\");\n\tfor (i = 0; i < n; i++)\n\t\tprintf(\"%d\", ans[i]);\n\tprintf(\"\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "802de7882afc67abda7fca53bed3c431", "src_uid": "9bd31827cda83eacfcf5e46cdeaabe2b", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#pragma region kyopuro_templates\n#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#include<stdbool.h>\n#include<assert.h>\n#include<time.h>\n#include<ctype.h>\ntypedef long long ll;\ntypedef long double ld;\n#define rep(i,l,r)for(ll i=(l);i<(r);i++)\n#define repp(i,l,r,k)for(ll i=(l);i<(r);i+=(k))\n#define rrep(i,l,r)for(ll i=(l);i>=(r);i--)\n#define INF (1LL<<62)\n#define MOD1 1000000007\n#define MOD2 998244353\n#define MAX_N (1 << 20)\n#define YES printf(\"Yes\\n\")\n#define NO printf(\"No\\n\")\n#define PN printf(\"\\n\")\n#define charsize 100005 //10^5+5\n#define PI 3.141592653589793238\n\nvoid swap(ll *a, ll *b){ll c;c=*b;*b=*a;*a= c;}\nvoid cin(ll *n){ scanf(\"%lld\",&(*n)); }\nll max2(ll a,ll b){return a>=b?a:b;}\nll min2(ll a,ll b){return a>=b?b:a;}\nll min3(ll a, ll b, ll c){return (a<=b && a<=c) ? a : b<=c ? b : c;}\nll max3(ll a, ll b, ll c){return (a>=b && a>=c) ? a : b>=c ? b : c;}\nll minn(ll n, ll a[]){ll b=INF;rep(i,0,n) b=min2(b,a[i]);return b;}\nll maxn(ll n, ll a[]){ll b=-INF;rep(i,0,n) b=max2(b,a[i]);return b;}\nll POW(ll a, ll b){ll c=1;rep(i,0,b) c*=a;return c;}\ndouble POW_d(double a, double b){double c=1;rep(i,0,b) c*=a;return c;}\nll gcd(ll a,ll b){return b?gcd(b,a%b):a;}\nll lcm(ll a,ll b){return a/gcd(a,b)*b;}\nll mod_MOD1(ll n){n+= n<0?((-n)/MOD1+1)*MOD1:0; return n%=MOD1;}\nll mod_p(ll n ,ll p){n+= n<0?((-n)/p+1)*p:0; return n%=p;}\nll change_into_num(char s[] , ll len, ll p){ return !p ? 0 : POW(10,p-1)*(s[len-p]-'0') + change_into_num(s,len,p-1); }\nll digits(ll a, ll b){return a/b?1+digits(a/b,b):1;}\nll base(ll n, ll a, ll i){return i==1?n%a:base(n/a,a,i-1);}\nll is_inArr1(ll x, ll n){ return ( x<0 || x>=n ) ? 0 : 1 ; }\nll is_inArr2(ll y, ll x, ll h, ll w){ return ( y<0 || y>=h || x<0 || x>=w ) ? 0 : 1 ; }\n\n\nvoid lr_lower( int *l, int *r, ll am, ll val , int type ){ (type<3) ? ( am < val ?  ( *l = (*l+*r)/2 ) : ( *r= (*l+*r)/2 ) ) : ( am <= val ? ( *l = (*l+*r)/2 ) : ( *r= (*l+*r)/2 ) ); }\nvoid lr_upper( int *l, int *r, ll am, ll val , int type ){ (type<3) ? ( am <= val ?  ( *l = (*l+*r)/2 ) : ( *r= (*l+*r)/2 ) ) : ( am < val ? ( *l = (*l+*r)/2 ) : ( *r= (*l+*r)/2 ) ); }\nint cmp_lower( ll a, ll b, int type ){ return (type==1) ? ( a==b ? 1 : 0 ) : (type==2) ? ( a>=b ? 1 : 0 ) : ( a>b ? 1 : 0 ) ; }\nint cmp_upper( ll a, ll b, int type ){ return (type==1) ? ( a==b ? 1 : 0 ) : (type==2) ? ( a<=b ? 1 : 0 ) : ( a<b ? 1 : 0 ) ; }\n// return smallest p  which meets  a[p]==val :1  >=:2   >:3\nll lower_bound( ll a[], int l, int r, ll val , int type ){  while(r-l>1) lr_lower(&l,&r,a[ (l+r)/2 ],val,type);  return cmp_lower(a[l],val,type) ? l : cmp_lower(a[r],val,type) ? r : -1;  }\n// return biggest p  which meets   a[p]==val :1  <=:2   <:3\nll upper_bound( ll a[], int l, int r, ll val , int type ){  while(r-l>1) lr_upper(&l,&r,a[ (l+r)/2 ],val,type); return cmp_upper(a[r],val,type) ? r : cmp_upper(a[l],val,type) ? l : -1; }\n// count i  which meets ai==x\nll count(ll a[], int l, int r, ll x){  int p = lower_bound(a,l,r,x,1);  return p==-1 ? 0 : upper_bound(a,p,r,x,1)-p+1; }\n\nll *factors[2] , fac_cnt=0 , is_factor_prepared=0;\nll factor_pre(){  rep(i,0,1){ if(is_factor_prepared++) return 0; }  ll tmp=(1e6)/2+1, fac_tmp[tmp];  rep(i,0,tmp){fac_tmp[i]=i?2*i+1:2;}  rep(i,1,tmp){if(fac_tmp[i]){  repp(j,3,tmp/(2*i+1)+1,2 ){  if( j*(2*i+1)<tmp ) fac_tmp[ (j*(2*i+1)-1)/2 ]=0;  }  }else continue;}  rep(i,0,tmp){if(fac_tmp[i]){  rep(j,0,2){ factors[j] = realloc( factors[j] , sizeof(ll)*( fac_cnt +1 ) );  factors[j][j?fac_cnt++:fac_cnt]=j?0:fac_tmp[i];  }  } }  return 0;  }\nll factor(ll n, ll new_common_plus){ factor_pre();  rep(i,0,fac_cnt){ ll cnt=0; rep(j,0,1){ while( ( cnt+= n %factors[0][i]==0 ? 1 : 0 )  && (n/=factors[0][i]) %factors[0][i]==0 ) continue; } factors[1][i]= new_common_plus==1 ? cnt :  new_common_plus==2 ? max2(factors[1][i],cnt) : factors[1][i]+cnt ;  if( factors[0][i]> n ) break; } return n; }\nll judge_prime(ll n){ factor_pre(); rep(i,0,fac_cnt){ if(n<factors[0][i]*factors[0][i] || n==factors[0][i]) break; else if(n%factors[0][i]==0) n/=n; }  return n==1?0:1; }\n\nll *mf_arr,*inv_arr,*finv_arr,is_minv_made=0,is_mf_made=0,num_of_inv=2*1e6+10;\nll makeinv(ll n , ll mod){  rep(i,0,1){if(is_minv_made++) return 0;}  inv_arr = realloc(inv_arr, sizeof(ll)*2 );  finv_arr = realloc(finv_arr, sizeof(ll)*2 );  inv_arr[1]=1;finv_arr[0]=finv_arr[1]=1;  rep(i,2,n+1){  inv_arr = realloc(inv_arr, sizeof(ll)*(i+1) );  finv_arr = realloc(finv_arr, sizeof(ll)*(i+1) );  inv_arr[i]= mod - inv_arr[mod%i] * (mod / i) % mod;  finv_arr[i] = finv_arr[i - 1] * inv_arr[i] % mod;  }  return 0; }\nll make_mf(ll n, ll mod){  rep(i,0,1){ if(is_mf_made++) return 0; }  mf_arr = realloc(mf_arr, sizeof(ll)*2 );  ll x=1;  mf_arr[0]=mf_arr[1]=x;  rep(i,2,n+1){   x=x*i%mod;  mf_arr = realloc(mf_arr, sizeof(ll)*(i+1) );  mf_arr[i]=x; }  return 0;  }\nll m_inv(ll x, ll mod, ll is_fac ){ makeinv(num_of_inv,mod);  return is_fac?finv_arr[x]:inv_arr[x]; }\nll m_f(ll x, ll mod){  make_mf(num_of_inv,mod);  return mf_arr[x];  }\nll mod_nck(ll n, ll k, ll mod){ return m_f(n,mod)*m_inv(k,mod,1)%mod*m_inv(n-k,mod,1)%mod; }\nll m_p(ll r,ll n,ll mod){  ll t=1,s=r;  while(n>0){ t = (n&1) ? t*s%mod : t;  s=s*s%mod; n>>=1; }  return r?t:0;  }\nll m_mul2(ll a, ll b, ll mod){ return a*b%mod; }\nll m_mul3(ll a, ll b, ll c, ll mod){ return m_mul2(a*b%mod,c,mod); }\nll m_mul4(ll a, ll b, ll c, ll d, ll mod){ return m_mul3(a*b%mod,c,d,mod); }\nll m_mul5(ll a, ll b, ll c, ll d, ll e, ll mod){ return m_mul4(a*b%mod,c,d,e,mod); }\n\nint upll(const void*a, const void*b){return*(ll*)a<*(ll*)b?-1:*(ll*)a>*(ll*)b?1:0;}\nint downll(const void*a, const void*b){return*(ll*)a<*(ll*)b?1:*(ll*)a>*(ll*)b?-1:0;}\nint cmp_string( const void * a , const void * b ) {  return strcmp( (char *)a , (char *)b ); }  // qsort((void*)s,n,sizeof(s[0]),int_sort );\nint cmp_char(const void * a, const void * b) { return *(char *)a - *(char *)b;}\nvoid sortup(ll*a,int n){qsort(a,n,sizeof(ll),upll);}\nvoid sortdown(ll*a,int n){qsort(a,n,sizeof(ll),downll);}\nvoid sort_string(int n,int size,char s[][size]){ qsort( (void*)s , n , sizeof(s[0]) , cmp_string ); }\nvoid sort_char(char *s){ qsort( (void *)s , strlen(s) , sizeof(char) , cmp_char ); }\nll unique_string(ll n ,ll size, char s[][size]){ ll ans=1; rep(i,1,n) if( strcmp(s[i],s[i-1]) ) ans++; return ans; }\nll unique_num(ll n , ll a[]){ ll ans=1; rep(i,1,n) if( a[i]!=a[i-1] ) ans++; return ans; }\n\n\ntypedef struct{ ll a , b,c;}fr;\nint cmp1( const void *p, const void *q ) { return ((fr*)p) ->b - ((fr*)q)->b;}\nint cmp2( const void *p, const void *q ) { return ((fr*)q) ->a - ((fr*)p)->a;}\nvoid strsortup(fr*a,int n){qsort(a,n,sizeof(fr),cmp1);}\nvoid strsortdown(fr*a,int n){qsort(a,n,sizeof(fr),cmp2);}\nvoid swap_struct( fr* p, fr* q ){\n    fr r;\n    r=*p;\n    *p=*q;\n    *q=r;\n}\n\n#pragma region AVL\n/*---------------------------AVL start--------------------------------*/\n//https://qiita.com/mikecat_mixc/items/e9f8248de2ae7f7a0a29\ntypedef struct node_AVL_set{  \n    ll val;\n    int diff;\n    int cnt;\n    struct node_AVL_set *child[2];\n}AVL_set;\nvoid AVL_set_inside_rotate(AVL_set **node, int is_right){\n    int l = is_right==false , r = is_right==true , sign = is_right ? 1 : -1;\n    if((*node)->child[l] != NULL){\n        AVL_set* left = (*node)->child[l];\n        int a= (*node)->diff * sign , b= left->diff * sign ,na,nb;\n        if(b+1){\n            na=a-1-b;\n            nb= (a-b) ? b-1 : a-2;\n        }else{\n            na=a-1;\n            nb= a ? b-1 : a+b-2;\n        }\n        (*node)->diff = na * sign;\n        left->diff = nb * sign;\n        /* rotate-> */\n        (*node)->child[l] = (*node)->child[l]->child[r];\n        left->child[r] = *node;\n        *node = left;\n    }\n}\nint AVL_set_inside_update(AVL_set **node, ll data, int add){\n    if(*node == NULL){\n        if(add==2){\n            *node = malloc(sizeof(AVL_set));\n            (*node)->val = data;\n            (*node)->cnt = 1;\n            (*node)->diff = 0;\n            (*node)->child[0] = NULL;\n            (*node)->child[1] = NULL;\n        }\n        return add==2 ? *node != NULL : 0; \n    }else{\n        int l, delta, delta_sign; AVL_set *next_node;\n        if(data == (*node)->val){\n            if(add==2){\n                (*node)->cnt++;\n                return 0;\n            }else{\n                if( add && (*node)->cnt > 1 ){\n                    (*node)->cnt--; return 0;\n                }else{\n                    if((*node)->child[1] == NULL){\n                        next_node = (*node)->child[0];\n                        free(*node);\n                        *node = next_node;\n                        return -1;\n                    }else if((*node)->child[0] == NULL){\n                        next_node = (*node)->child[1];\n                        free(*node);\n                        *node = next_node;\n                        return -1;\n                    }else{\n                        for(next_node = (*node)->child[0];\n                        next_node->child[1] != NULL;\n                        next_node = next_node->child[1]);\n                        (*node)->val = next_node->val;\n                        l=0;\n                        delta_sign=1;\n                        delta = AVL_set_inside_update(&(*node)->child[l], next_node->val, add);\n                    }\n                }\n            }\n        }else{\n            l = data >= (*node)->val ? 1 : 0;\n            delta_sign = data < (*node)->val ? 1 : -1;\n            delta = AVL_set_inside_update(&(*node)->child[l], data, add);\n        }\n        if( delta ){\n            int orig_diff = (*node)->diff;\n            int do_rotate = 0, rotate_l , diff_sign , rotate_right;\n            (*node)->diff += delta * delta_sign;\n            if((*node)->diff > 1){\n                do_rotate = 1;\n                rotate_l = 0;\n                diff_sign = 1;\n                rotate_right = 1;\n            }else if((*node)->diff < -1){\n                do_rotate = 1;\n                rotate_l = 1;\n                diff_sign = -1;\n                rotate_right = 0;\n            }\n            if(do_rotate){\n                int child_diff = (*node)->child[rotate_l]->diff;\n                if((*node)->child[rotate_l]->diff * diff_sign < 0){\n                    AVL_set_inside_rotate(&(*node)->child[rotate_l], !rotate_right);\n                }\n                AVL_set_inside_rotate(node, rotate_right);\n                return delta < 0 && child_diff != 0 ? -1 : 0;\n            }\n            if     (delta > 0 && orig_diff == 0) return 1;\n            else if(delta < 0 && orig_diff != 0) return -1;\n            else                                 return 0;\n        }else{ \n            return 0;\n        }\n    }\n}\n\nvoid AVL_set_inside_print(const AVL_set *node, int depth){\n    if(node == NULL) return;\n    AVL_set_inside_print(node->child[1], depth + 1);\n    printf(\"%lld %d\\n\", node->val,node->cnt);\n    AVL_set_inside_print(node->child[0], depth + 1);    \n}\nvoid AVL_set_inside_free(AVL_set *node){\n    if(node == NULL) return;\n    AVL_set_inside_free(node->child[0]);\n    AVL_set_inside_free(node->child[1]);\n    free(node);\n}\nll AVL_set_inside_count(AVL_set *root, ll val){\n    AVL_set *node; node = root;\n    while(node){\n        if     (val < node->val) node = node->child[0];\n        else if(val > node->val) node = node->child[1];\n        else                     return node->cnt;\n    }\n    return 0;\n}\nll AVL_set_inside_minmax(AVL_set *root, int type){\n    while(root->child[type] !=NULL)  root= root->child[type];\n    return root->val;\n}\nvoid AVL_set_inside_swap(AVL_set **node1, AVL_set **node2){  \n    AVL_set *tmp;  tmp=*node1; *node1=*node2; *node2=tmp;\n}\n\n#define set_MAX_SIZE 514511\nll set_main( int command , int set_num , ll val ){\n    static bool set_is_init=false;\n    static AVL_set *set_pointer[set_MAX_SIZE];\n    static ll set_siz[set_MAX_SIZE];\n    if(!set_is_init){ set_is_init=true; rep(i,0,set_MAX_SIZE){ *(set_pointer+i) = NULL; set_siz[i]=0; } }\n    if(command==-1){ AVL_set_inside_print( set_pointer[set_num] ,0); }\n    if(command==1){ AVL_set_inside_count(set_pointer[set_num],val) ? 1 : set_siz[set_num]++;  AVL_set_inside_update( &set_pointer[set_num] , val , 2 ); }\n    if(command==2){ return AVL_set_inside_count(set_pointer[set_num],val); }\n    if(command==3){ ( AVL_set_inside_count(set_pointer[set_num],val) > 1 ) ? 1 : set_siz[set_num]--;  AVL_set_inside_update( &set_pointer[set_num] , val,1); }\n    if(command==4){ set_siz[set_num]--; AVL_set_inside_update( &set_pointer[set_num] , val , 0 ); }\n    if(command==5){ set_siz[set_num]=0; AVL_set_inside_free( set_pointer[set_num] ); set_pointer[set_num] = NULL; }\n    if(command==6){ return set_siz[set_num]; }\n    if(command==7){ return AVL_set_inside_minmax(set_pointer[set_num],1); }\n    if(command==8){ return AVL_set_inside_minmax(set_pointer[set_num],0); }\n    if(command==9){ AVL_set_inside_swap(&set_pointer[set_num],&set_pointer[val]); }\n    return 0;\n}\n\nvoid set_print(int set_num){ set_main(-1,set_num,0); }\nvoid set_insert(int set_num, ll val){ set_main(1,set_num,val); }\nll set_count(int set_num, ll val){ return set_main(2,set_num,val); }\nvoid set_erase(int set_num, ll val, int is_all){ if(is_all) set_main(4,set_num,val); else set_main(3,set_num,val); }\nvoid set_clear(int set_num){ set_main(5,set_num,0); }\nll set_size(int set_num){ return set_main(6,set_num,0); }\nll set_max(int set_num){ return set_main(7,set_num,0); }\nll set_min(int set_num){ return set_main(8,set_num,0); }\nvoid set_swap(ll set_num1, ll set_num2){ set_main(9,set_num1,set_num2); }\n\n/*\ninsert *\nsize *\nclear *\nerase *\ncount *\nmax *\nmin *\nswap *\nbegin\nend\nmerge  source \u306e\u8981\u7d20\u306e\u30ad\u30fc\u3068\u7b49\u4fa1\u306a\u30ad\u30fc\u306e\u8981\u7d20\u304c\u3042\u308b\u5834\u5408\u3001\u305d\u306e\u8981\u7d20\u306f source \u304b\u3089\u62bd\u51fa\u3055\u308c\u306a\u3044\nlower_bound\nupper_bound\n*/\n\n// ll map_main()\n\n/*---------------------------AVL start--------------------------------*/\n\n#pragma endregion AVL\n\n\n\n#pragma endregion kyopuro_templates\n\n\n\n\n\n\n\n\n\n\n\n\n\nchar s[1151154];\n// char t[1151154];\nll ans[115115];\nvoid solve(){\n    // fgets(s,sizeof(s),stdin); \n    ll n;\n    // ll ans=0;\n    cin(&n);\n    scanf(\"%s\",s);\n    fr aa[n];\n    rep(i,0,n){\n        aa[i].a = s[i]-'a';\n        aa[i].b=i;\n        aa[i].c=-1;\n    }\n    ll t[n];\n    rep(i,0,n){t[i]=aa[i].a;}\n    rep(i,0,n){ans[i]=-1;}\n    sortup(t,n);\n    // rep(i,0,n){printf(\"%lld\",t[i]);}PN;\n    rep(i,0,n){\n        // rep(i,0,n){\n        //     printf(\"%lld\",aa[i].a);\n        // }PN;\n        if(t[i]!=aa[i].a){\n            rep(j,i+1,n){\n                if(t[i]==aa[j].a){\n                    // printf(\"%lld %lld\\n\",i,j);\n                    if(aa[i].c==-1){\n                        if(aa[j].c==-1){\n                            aa[i].c=0;\n                            aa[j].c=1;\n                        }else{\n                            aa[i].c=aa[j].c^1;\n                        }\n                    }else{\n                        if(aa[i].c==aa[j].c){\n                            printf(\"NO\\n\"); return;\n                        }\n                        if(aa[j].c==-1){\n                            aa[j].c=aa[i].c^1;\n                        }\n                    }\n                    swap_struct(&aa[i],&aa[j]);\n                    break;\n                    // s[j]=s[i];\n                    // s[i]=t[i];\n                }\n            }\n        }else{\n            if(aa[i].c==-1){\n                aa[i].c=0;            \n            }\n        }\n    }\n    strsortup(aa,n);\n    printf(\"YES\\n\");\n    rep(i,0,n){\n        printf(\"%lld\",aa[i].c);\n    }PN;\n}\n\nint main(void){\n    ll T=1;\n    // cin(&T);\n    rep(i,0,T){ solve(); }\n    return 0;\n}\n\n\n/*\n    while (ng + 1 < ok) {\n        int p = ng + (ok - ng) / 2;\n        int cnt = 0;\n        for (i = 0; i < n; i++) {\n            cnt += (a[i] + p - 1) / p - 1;\n        }\n        if (cnt <= k) ok = p; else ng = p;\n    }\n*/\n// 10^18 2^60 3^38 5^26\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cb56037e282923b36d5b5f20af71d894", "src_uid": "9bd31827cda83eacfcf5e46cdeaabe2b", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tint n;\n\tscanf(\"%d\", &n);\n\tint i, j;\n\tchar s[202];\n\tscanf(\"%s\", s);\n\tint ans[202];\n\tint b;\n\tans[0] = 0;\n\tb = 0;\n\tfor (i = 1; i < n; i++)\n\t{\n\t\tif (s[i] >= s[b])\n\t\t{\n\t\t\tans[i] = 0;\n\t\t\tb = i;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tans[i] = 1;\n\t\t}\n\t}\n\tb = -1;\n\tfor (i = 0; i < n; i++)\n\t{\n\t\tif (ans[i] > 0)\n\t\t{\n\t\t\tif (b < 0)\n\t\t\t\tb = i;\n\t\t\telse if (s[i] >= s[b])\n\t\t\t\tb = i;\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\"NO\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tfor (i = 0; i < n; i++)\n\t\tprintf(\"%d\", ans[i]);\n\tprintf(\"\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6f887d3e4dc20f68167515fdaf047a3a", "src_uid": "9bd31827cda83eacfcf5e46cdeaabe2b", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#pragma region kyopuro_templates\n#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#include<stdbool.h>\n#include<assert.h>\n#include<time.h>\n#include<ctype.h>\ntypedef long long ll;\ntypedef long double ld;\n#define rep(i,l,r)for(ll i=(l);i<(r);i++)\n#define repp(i,l,r,k)for(ll i=(l);i<(r);i+=(k))\n#define rrep(i,l,r)for(ll i=(l);i>=(r);i--)\n#define INF (1LL<<62)\n#define MOD1 1000000007\n#define MOD2 998244353\n#define MAX_N (1 << 20)\n#define YES printf(\"Yes\\n\")\n#define NO printf(\"No\\n\")\n#define PN printf(\"\\n\")\n#define charsize 100005 //10^5+5\n#define PI 3.141592653589793238\n\nvoid swap(ll *a, ll *b){ll c;c=*b;*b=*a;*a= c;}\nvoid cin(ll *n){ scanf(\"%lld\",&(*n)); }\nll max2(ll a,ll b){return a>=b?a:b;}\nll min2(ll a,ll b){return a>=b?b:a;}\nll min3(ll a, ll b, ll c){return (a<=b && a<=c) ? a : b<=c ? b : c;}\nll max3(ll a, ll b, ll c){return (a>=b && a>=c) ? a : b>=c ? b : c;}\nll minn(ll n, ll a[]){ll b=INF;rep(i,0,n) b=min2(b,a[i]);return b;}\nll maxn(ll n, ll a[]){ll b=-INF;rep(i,0,n) b=max2(b,a[i]);return b;}\nll POW(ll a, ll b){ll c=1;rep(i,0,b) c*=a;return c;}\ndouble POW_d(double a, double b){double c=1;rep(i,0,b) c*=a;return c;}\nll gcd(ll a,ll b){return b?gcd(b,a%b):a;}\nll lcm(ll a,ll b){return a/gcd(a,b)*b;}\nll mod_MOD1(ll n){n+= n<0?((-n)/MOD1+1)*MOD1:0; return n%=MOD1;}\nll mod_p(ll n ,ll p){n+= n<0?((-n)/p+1)*p:0; return n%=p;}\nll change_into_num(char s[] , ll len, ll p){ return !p ? 0 : POW(10,p-1)*(s[len-p]-'0') + change_into_num(s,len,p-1); }\nll digits(ll a, ll b){return a/b?1+digits(a/b,b):1;}\nll base(ll n, ll a, ll i){return i==1?n%a:base(n/a,a,i-1);}\nll is_inArr1(ll x, ll n){ return ( x<0 || x>=n ) ? 0 : 1 ; }\nll is_inArr2(ll y, ll x, ll h, ll w){ return ( y<0 || y>=h || x<0 || x>=w ) ? 0 : 1 ; }\n\n\nvoid lr_lower( int *l, int *r, ll am, ll val , int type ){ (type<3) ? ( am < val ?  ( *l = (*l+*r)/2 ) : ( *r= (*l+*r)/2 ) ) : ( am <= val ? ( *l = (*l+*r)/2 ) : ( *r= (*l+*r)/2 ) ); }\nvoid lr_upper( int *l, int *r, ll am, ll val , int type ){ (type<3) ? ( am <= val ?  ( *l = (*l+*r)/2 ) : ( *r= (*l+*r)/2 ) ) : ( am < val ? ( *l = (*l+*r)/2 ) : ( *r= (*l+*r)/2 ) ); }\nint cmp_lower( ll a, ll b, int type ){ return (type==1) ? ( a==b ? 1 : 0 ) : (type==2) ? ( a>=b ? 1 : 0 ) : ( a>b ? 1 : 0 ) ; }\nint cmp_upper( ll a, ll b, int type ){ return (type==1) ? ( a==b ? 1 : 0 ) : (type==2) ? ( a<=b ? 1 : 0 ) : ( a<b ? 1 : 0 ) ; }\n// return smallest p  which meets  a[p]==val :1  >=:2   >:3\nll lower_bound( ll a[], int l, int r, ll val , int type ){  while(r-l>1) lr_lower(&l,&r,a[ (l+r)/2 ],val,type);  return cmp_lower(a[l],val,type) ? l : cmp_lower(a[r],val,type) ? r : -1;  }\n// return biggest p  which meets   a[p]==val :1  <=:2   <:3\nll upper_bound( ll a[], int l, int r, ll val , int type ){  while(r-l>1) lr_upper(&l,&r,a[ (l+r)/2 ],val,type); return cmp_upper(a[r],val,type) ? r : cmp_upper(a[l],val,type) ? l : -1; }\n// count i  which meets ai==x\nll count(ll a[], int l, int r, ll x){  int p = lower_bound(a,l,r,x,1);  return p==-1 ? 0 : upper_bound(a,p,r,x,1)-p+1; }\n\nll *factors[2] , fac_cnt=0 , is_factor_prepared=0;\nll factor_pre(){  rep(i,0,1){ if(is_factor_prepared++) return 0; }  ll tmp=(1e6)/2+1, fac_tmp[tmp];  rep(i,0,tmp){fac_tmp[i]=i?2*i+1:2;}  rep(i,1,tmp){if(fac_tmp[i]){  repp(j,3,tmp/(2*i+1)+1,2 ){  if( j*(2*i+1)<tmp ) fac_tmp[ (j*(2*i+1)-1)/2 ]=0;  }  }else continue;}  rep(i,0,tmp){if(fac_tmp[i]){  rep(j,0,2){ factors[j] = realloc( factors[j] , sizeof(ll)*( fac_cnt +1 ) );  factors[j][j?fac_cnt++:fac_cnt]=j?0:fac_tmp[i];  }  } }  return 0;  }\nll factor(ll n, ll new_common_plus){ factor_pre();  rep(i,0,fac_cnt){ ll cnt=0; rep(j,0,1){ while( ( cnt+= n %factors[0][i]==0 ? 1 : 0 )  && (n/=factors[0][i]) %factors[0][i]==0 ) continue; } factors[1][i]= new_common_plus==1 ? cnt :  new_common_plus==2 ? max2(factors[1][i],cnt) : factors[1][i]+cnt ;  if( factors[0][i]> n ) break; } return n; }\nll judge_prime(ll n){ factor_pre(); rep(i,0,fac_cnt){ if(n<factors[0][i]*factors[0][i] || n==factors[0][i]) break; else if(n%factors[0][i]==0) n/=n; }  return n==1?0:1; }\n\nll *mf_arr,*inv_arr,*finv_arr,is_minv_made=0,is_mf_made=0,num_of_inv=2*1e6+10;\nll makeinv(ll n , ll mod){  rep(i,0,1){if(is_minv_made++) return 0;}  inv_arr = realloc(inv_arr, sizeof(ll)*2 );  finv_arr = realloc(finv_arr, sizeof(ll)*2 );  inv_arr[1]=1;finv_arr[0]=finv_arr[1]=1;  rep(i,2,n+1){  inv_arr = realloc(inv_arr, sizeof(ll)*(i+1) );  finv_arr = realloc(finv_arr, sizeof(ll)*(i+1) );  inv_arr[i]= mod - inv_arr[mod%i] * (mod / i) % mod;  finv_arr[i] = finv_arr[i - 1] * inv_arr[i] % mod;  }  return 0; }\nll make_mf(ll n, ll mod){  rep(i,0,1){ if(is_mf_made++) return 0; }  mf_arr = realloc(mf_arr, sizeof(ll)*2 );  ll x=1;  mf_arr[0]=mf_arr[1]=x;  rep(i,2,n+1){   x=x*i%mod;  mf_arr = realloc(mf_arr, sizeof(ll)*(i+1) );  mf_arr[i]=x; }  return 0;  }\nll m_inv(ll x, ll mod, ll is_fac ){ makeinv(num_of_inv,mod);  return is_fac?finv_arr[x]:inv_arr[x]; }\nll m_f(ll x, ll mod){  make_mf(num_of_inv,mod);  return mf_arr[x];  }\nll mod_nck(ll n, ll k, ll mod){ return m_f(n,mod)*m_inv(k,mod,1)%mod*m_inv(n-k,mod,1)%mod; }\nll m_p(ll r,ll n,ll mod){  ll t=1,s=r;  while(n>0){ t = (n&1) ? t*s%mod : t;  s=s*s%mod; n>>=1; }  return r?t:0;  }\nll m_mul2(ll a, ll b, ll mod){ return a*b%mod; }\nll m_mul3(ll a, ll b, ll c, ll mod){ return m_mul2(a*b%mod,c,mod); }\nll m_mul4(ll a, ll b, ll c, ll d, ll mod){ return m_mul3(a*b%mod,c,d,mod); }\nll m_mul5(ll a, ll b, ll c, ll d, ll e, ll mod){ return m_mul4(a*b%mod,c,d,e,mod); }\n\nint upll(const void*a, const void*b){return*(ll*)a<*(ll*)b?-1:*(ll*)a>*(ll*)b?1:0;}\nint downll(const void*a, const void*b){return*(ll*)a<*(ll*)b?1:*(ll*)a>*(ll*)b?-1:0;}\nint cmp_string( const void * a , const void * b ) {  return strcmp( (char *)a , (char *)b ); }  // qsort((void*)s,n,sizeof(s[0]),int_sort );\nint cmp_char(const void * a, const void * b) { return *(char *)a - *(char *)b;}\nvoid sortup(ll*a,int n){qsort(a,n,sizeof(ll),upll);}\nvoid sortdown(ll*a,int n){qsort(a,n,sizeof(ll),downll);}\nvoid sort_string(int n,int size,char s[][size]){ qsort( (void*)s , n , sizeof(s[0]) , cmp_string ); }\nvoid sort_char(char *s){ qsort( (void *)s , strlen(s) , sizeof(char) , cmp_char ); }\nll unique_string(ll n ,ll size, char s[][size]){ ll ans=1; rep(i,1,n) if( strcmp(s[i],s[i-1]) ) ans++; return ans; }\nll unique_num(ll n , ll a[]){ ll ans=1; rep(i,1,n) if( a[i]!=a[i-1] ) ans++; return ans; }\n\n\ntypedef struct{ ll a , b,c;}fr;\nint cmp1( const void *p, const void *q ) { return ((fr*)p) ->b - ((fr*)q)->b;}\nint cmp2( const void *p, const void *q ) { return ((fr*)q) ->a - ((fr*)p)->a;}\nvoid strsortup(fr*a,int n){qsort(a,n,sizeof(fr),cmp1);}\nvoid strsortdown(fr*a,int n){qsort(a,n,sizeof(fr),cmp2);}\nvoid swap_struct( fr* p, fr* q ){\n    fr r;\n    r=*p;\n    *p=*q;\n    *q=r;\n}\n\n#pragma region AVL\n/*---------------------------AVL start--------------------------------*/\n//https://qiita.com/mikecat_mixc/items/e9f8248de2ae7f7a0a29\ntypedef struct node_AVL_set{  \n    ll val;\n    int diff;\n    int cnt;\n    struct node_AVL_set *child[2];\n}AVL_set;\nvoid AVL_set_inside_rotate(AVL_set **node, int is_right){\n    int l = is_right==false , r = is_right==true , sign = is_right ? 1 : -1;\n    if((*node)->child[l] != NULL){\n        AVL_set* left = (*node)->child[l];\n        int a= (*node)->diff * sign , b= left->diff * sign ,na,nb;\n        if(b+1){\n            na=a-1-b;\n            nb= (a-b) ? b-1 : a-2;\n        }else{\n            na=a-1;\n            nb= a ? b-1 : a+b-2;\n        }\n        (*node)->diff = na * sign;\n        left->diff = nb * sign;\n        /* rotate-> */\n        (*node)->child[l] = (*node)->child[l]->child[r];\n        left->child[r] = *node;\n        *node = left;\n    }\n}\nint AVL_set_inside_update(AVL_set **node, ll data, int add){\n    if(*node == NULL){\n        if(add==2){\n            *node = malloc(sizeof(AVL_set));\n            (*node)->val = data;\n            (*node)->cnt = 1;\n            (*node)->diff = 0;\n            (*node)->child[0] = NULL;\n            (*node)->child[1] = NULL;\n        }\n        return add==2 ? *node != NULL : 0; \n    }else{\n        int l, delta, delta_sign; AVL_set *next_node;\n        if(data == (*node)->val){\n            if(add==2){\n                (*node)->cnt++;\n                return 0;\n            }else{\n                if( add && (*node)->cnt > 1 ){\n                    (*node)->cnt--; return 0;\n                }else{\n                    if((*node)->child[1] == NULL){\n                        next_node = (*node)->child[0];\n                        free(*node);\n                        *node = next_node;\n                        return -1;\n                    }else if((*node)->child[0] == NULL){\n                        next_node = (*node)->child[1];\n                        free(*node);\n                        *node = next_node;\n                        return -1;\n                    }else{\n                        for(next_node = (*node)->child[0];\n                        next_node->child[1] != NULL;\n                        next_node = next_node->child[1]);\n                        (*node)->val = next_node->val;\n                        l=0;\n                        delta_sign=1;\n                        delta = AVL_set_inside_update(&(*node)->child[l], next_node->val, add);\n                    }\n                }\n            }\n        }else{\n            l = data >= (*node)->val ? 1 : 0;\n            delta_sign = data < (*node)->val ? 1 : -1;\n            delta = AVL_set_inside_update(&(*node)->child[l], data, add);\n        }\n        if( delta ){\n            int orig_diff = (*node)->diff;\n            int do_rotate = 0, rotate_l , diff_sign , rotate_right;\n            (*node)->diff += delta * delta_sign;\n            if((*node)->diff > 1){\n                do_rotate = 1;\n                rotate_l = 0;\n                diff_sign = 1;\n                rotate_right = 1;\n            }else if((*node)->diff < -1){\n                do_rotate = 1;\n                rotate_l = 1;\n                diff_sign = -1;\n                rotate_right = 0;\n            }\n            if(do_rotate){\n                int child_diff = (*node)->child[rotate_l]->diff;\n                if((*node)->child[rotate_l]->diff * diff_sign < 0){\n                    AVL_set_inside_rotate(&(*node)->child[rotate_l], !rotate_right);\n                }\n                AVL_set_inside_rotate(node, rotate_right);\n                return delta < 0 && child_diff != 0 ? -1 : 0;\n            }\n            if     (delta > 0 && orig_diff == 0) return 1;\n            else if(delta < 0 && orig_diff != 0) return -1;\n            else                                 return 0;\n        }else{ \n            return 0;\n        }\n    }\n}\n\nvoid AVL_set_inside_print(const AVL_set *node, int depth){\n    if(node == NULL) return;\n    AVL_set_inside_print(node->child[1], depth + 1);\n    printf(\"%lld %d\\n\", node->val,node->cnt);\n    AVL_set_inside_print(node->child[0], depth + 1);    \n}\nvoid AVL_set_inside_free(AVL_set *node){\n    if(node == NULL) return;\n    AVL_set_inside_free(node->child[0]);\n    AVL_set_inside_free(node->child[1]);\n    free(node);\n}\nll AVL_set_inside_count(AVL_set *root, ll val){\n    AVL_set *node; node = root;\n    while(node){\n        if     (val < node->val) node = node->child[0];\n        else if(val > node->val) node = node->child[1];\n        else                     return node->cnt;\n    }\n    return 0;\n}\nll AVL_set_inside_minmax(AVL_set *root, int type){\n    while(root->child[type] !=NULL)  root= root->child[type];\n    return root->val;\n}\nvoid AVL_set_inside_swap(AVL_set **node1, AVL_set **node2){  \n    AVL_set *tmp;  tmp=*node1; *node1=*node2; *node2=tmp;\n}\n\n#define set_MAX_SIZE 514511\nll set_main( int command , int set_num , ll val ){\n    static bool set_is_init=false;\n    static AVL_set *set_pointer[set_MAX_SIZE];\n    static ll set_siz[set_MAX_SIZE];\n    if(!set_is_init){ set_is_init=true; rep(i,0,set_MAX_SIZE){ *(set_pointer+i) = NULL; set_siz[i]=0; } }\n    if(command==-1){ AVL_set_inside_print( set_pointer[set_num] ,0); }\n    if(command==1){ AVL_set_inside_count(set_pointer[set_num],val) ? 1 : set_siz[set_num]++;  AVL_set_inside_update( &set_pointer[set_num] , val , 2 ); }\n    if(command==2){ return AVL_set_inside_count(set_pointer[set_num],val); }\n    if(command==3){ ( AVL_set_inside_count(set_pointer[set_num],val) > 1 ) ? 1 : set_siz[set_num]--;  AVL_set_inside_update( &set_pointer[set_num] , val,1); }\n    if(command==4){ set_siz[set_num]--; AVL_set_inside_update( &set_pointer[set_num] , val , 0 ); }\n    if(command==5){ set_siz[set_num]=0; AVL_set_inside_free( set_pointer[set_num] ); set_pointer[set_num] = NULL; }\n    if(command==6){ return set_siz[set_num]; }\n    if(command==7){ return AVL_set_inside_minmax(set_pointer[set_num],1); }\n    if(command==8){ return AVL_set_inside_minmax(set_pointer[set_num],0); }\n    if(command==9){ AVL_set_inside_swap(&set_pointer[set_num],&set_pointer[val]); }\n    return 0;\n}\n\nvoid set_print(int set_num){ set_main(-1,set_num,0); }\nvoid set_insert(int set_num, ll val){ set_main(1,set_num,val); }\nll set_count(int set_num, ll val){ return set_main(2,set_num,val); }\nvoid set_erase(int set_num, ll val, int is_all){ if(is_all) set_main(4,set_num,val); else set_main(3,set_num,val); }\nvoid set_clear(int set_num){ set_main(5,set_num,0); }\nll set_size(int set_num){ return set_main(6,set_num,0); }\nll set_max(int set_num){ return set_main(7,set_num,0); }\nll set_min(int set_num){ return set_main(8,set_num,0); }\nvoid set_swap(ll set_num1, ll set_num2){ set_main(9,set_num1,set_num2); }\n\n/*\ninsert *\nsize *\nclear *\nerase *\ncount *\nmax *\nmin *\nswap *\nbegin\nend\nmerge  source \u306e\u8981\u7d20\u306e\u30ad\u30fc\u3068\u7b49\u4fa1\u306a\u30ad\u30fc\u306e\u8981\u7d20\u304c\u3042\u308b\u5834\u5408\u3001\u305d\u306e\u8981\u7d20\u306f source \u304b\u3089\u62bd\u51fa\u3055\u308c\u306a\u3044\nlower_bound\nupper_bound\n*/\n\n// ll map_main()\n\n/*---------------------------AVL start--------------------------------*/\n\n#pragma endregion AVL\n\n\n\n#pragma endregion kyopuro_templates\n\n\n\n\n\n\n\n\n\n\n\n\n\nchar s[1151154];\n// char t[1151154];\nll ans[115115];\nvoid solve(){\n    // fgets(s,sizeof(s),stdin); \n    ll n;\n    // ll ans=0;\n    cin(&n);\n    scanf(\"%s\",s);\n    fr aa[n];\n    rep(i,0,n){\n        aa[i].a = s[i]-'a';\n        aa[i].b=i;\n        aa[i].c=-1;\n    }\n    ll t[n];\n    rep(i,0,n){t[i]=aa[i].a;}\n    rep(i,0,n){ans[i]=-1;}\n    sortup(t,n);\n    // rep(i,0,n){printf(\"%lld\",t[i]);}PN;\n    rep(i,0,n){\n        // rep(i,0,n){\n        //     printf(\"%lld\",aa[i].a);\n        // }PN;\n        if(t[i]!=aa[i].a){\n            rep(j,i+1,n){\n                if(t[i]==aa[j].a){\n                    // printf(\"%lld %lld\\n\",i,j);\n                    if(aa[i].c==-1){\n                        if(aa[j].c==-1){\n                            aa[i].c=0;\n                            aa[j].c=1;\n                        }else{\n                            aa[i].c=aa[j].c^1;\n                        }\n                    }else{\n                        if(aa[i].c==aa[j].c){\n                            printf(\"NO\\n\"); return;\n                        }\n                        if(aa[j].c==-1){\n                            aa[j].c=aa[i].c^1;\n                        }\n                    }\n                    swap_struct(&aa[i],&aa[j]);\n                    break;\n                    // s[j]=s[i];\n                    // s[i]=t[i];\n                }\n            }\n        }else{\n            if(aa[i].c==-1){\n                aa[i].c=0;            \n            }\n        }\n    }\n    strsortup(aa,n);\n    printf(\"YES\\n\");\n    rep(i,0,n){\n        printf(\"%lld\",aa[i].c);\n    }\n}\n\nint main(void){\n    ll T=1;\n    // cin(&T);\n    rep(i,0,T){ solve(); }\n    return 0;\n}\n\n\n/*\n    while (ng + 1 < ok) {\n        int p = ng + (ok - ng) / 2;\n        int cnt = 0;\n        for (i = 0; i < n; i++) {\n            cnt += (a[i] + p - 1) / p - 1;\n        }\n        if (cnt <= k) ok = p; else ng = p;\n    }\n*/\n// 10^18 2^60 3^38 5^26\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c9963556d17f70c220846077d61141e7", "src_uid": "9bd31827cda83eacfcf5e46cdeaabe2b", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <stdlib.h>\r\n#include <math.h>\r\n\r\nint main()\r\n{\r\n    int n;\r\n    scanf(\"%d\",&n);\r\n    long a[n];\r\n    a[0]=1;\r\n    a[1]=3;\r\n    a[2]=6;\r\n    long sum=a[0]+a[1]+a[2];\r\n    for(int j=3;j<n;j++){\r\n        int l=0;\r\n        //s1=(s1+a[j-1])%998244353;\r\n        //for(int k=j-2;k>=0;k--)s1=(s1+a[k])%(998244353);\r\n        float m=sqrt(j+1);\r\n        int k;\r\n        for(k=1;k<m;k++){\r\n            if((j+1)%k==0)l=(l+2);\r\n        }\r\n        if(k*k==m)l++;\r\n        //for(int k=1;k<=j;k++)if((j+1)%k==0)s1=(s1+1)%998244353;\r\n        a[j]=(sum+l)%998244353;\r\n        sum=(sum+a[j])%998244353;\r\n    }\r\n    printf(\"%ld\\n\",a[n-1]);\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "376a287e09b97c7ac458fbedeb7654cc", "src_uid": "09be46206a151c237dc9912df7e0f057", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <stdlib.h>\r\n#include <math.h>\r\n\r\nint main()\r\n{\r\n    int n;\r\n    //scanf(\"%d\",&n);\r\n    n=100;\r\n    long a[n];\r\n    a[0]=1;\r\n    a[1]=3;\r\n    a[2]=6;\r\n    long sum=a[0]+a[1]+a[2];\r\n    for(int j=3;j<n;j++){\r\n        long s1=(1+sum);\r\n        int l=0;\r\n        //s1=(s1+a[j-1])%998244353;\r\n        //for(int k=j-2;k>=0;k--)s1=(s1+a[k])%(998244353);\r\n        for(int k=1;k<=sqrt(j+1);k++){\r\n            if(k==sqrt(j+1) || k==1)\r\n                l=(l+1);\r\n            else if((j+1)%k==0)l=(l+2);\r\n        }\r\n        //for(int k=1;k<=j;k++)if((j+1)%k==0)s1=(s1+1)%998244353;\r\n        a[j]=(s1+l)%998244353;\r\n        sum=(sum+a[j])%998244353;\r\n    }\r\n    printf(\"%ld\\n\",a[n-1]);\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "2dbe97b39a2efcaf60865b7d70e4338f", "src_uid": "09be46206a151c237dc9912df7e0f057", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n\r\nint ysgs(int n) {\r\n    if(n==1) return 1;\r\n    else {\r\n        int cnt=0,i;\r\n        for(i=1;i*i<n;i++)\r\n            if(n%i==0) cnt+=2;\r\n        if(i*i==n) cnt++;\r\n        return cnt%998244353;\r\n    }\r\n}\r\n\r\nint main() {\r\n    int R=998244353,n,s=0,rr,m=0;\r\n    scanf(\"%d\",&n);\r\n    \r\n    if(n>100000){\r\n        s=345451881;\r\n        m=1;\r\n    }\r\n    if(n>200000) {\r\n        s=364228341;\r\n        m=2;\r\n    }\r\n    \r\n    \r\n    \r\n    for( int j=m*100000+1;j<n;j++) {\r\n        rr=(s+ysgs(j))%R;\r\n        s=(s+rr)%R;\r\n    }\r\n    printf(\"%d\\n\",(s+ysgs(n))%R);\r\n    printf(\"%d\",ysgs(n));\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7c3fc54ee497f64b9ab32ee6d94f85b9", "src_uid": "09be46206a151c237dc9912df7e0f057", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include<stdlib.h>\r\ntypedef long long lol;\r\n\r\nint main()\r\n{\r\n    lol n, M = 998244353;\r\n    scanf(\"%lld\",&n);\r\n    lol arr[n+1],id=2;\r\n    lol pr[1000000];\r\n    pr[0]=2;\r\n    pr[1]=3;\r\n    lol i,j,k,p,ct,i1;\r\n    arr[1]=1;\r\n    for(i=2;i<=n;i++)\r\n    {\r\n        p=0;\r\n        while((p<id) && (i%(pr[p])!=0) && (pr[p]*pr[p]<i)) p++;\r\n        if(p==id)\r\n        {\r\n            arr[i]=2;\r\n            pr[id]=i;\r\n            id++;\r\n            continue;\r\n        }\r\n        p = pr[p];\r\n        ct = 0;\r\n        i1=i;\r\n        while(i1%p==0)\r\n        {\r\n            ct++;\r\n            i1/=p;\r\n        }\r\n        arr[i] = arr[i1]*(ct+1);\r\n    }\r\n    lol ex = 1;\r\n    lol ans = arr[n]%M, a1;\r\n    for(i=1;i<n;i++)\r\n    {\r\n        a1 = (ex*arr[n-i])%M;\r\n        ans+=a1;\r\n        ans%=M;\r\n        ex*=2;\r\n        ex%=M;\r\n    }\r\n    printf(\"%lld\",ans);\r\n    return 0;\r\n}\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a56537d5f4d094c5a51b886f66e30403", "src_uid": "09be46206a151c237dc9912df7e0f057", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\n\r\nint ysgs(int n) {\r\n    if(n==1) return 1;\r\n    else {\r\n        int cnt=0,i;\r\n        for(i=1;i*i<n;i++)\r\n            if(n%i==0) cnt+=2;\r\n        if(i*i==n) cnt++;\r\n        return cnt%998244353;\r\n    }\r\n}\r\n\r\nint main() {\r\n    int R=998244353,n,s=0,rr,m=0;\r\n    scanf(\"%d\",&n);\r\n    \r\n    if(n>100000){\r\n        s=345451881;\r\n        m=1;\r\n    }\r\n    if(n>200000) {\r\n        s=364228341;\r\n        m=2;\r\n    }\r\n    if(n>300000) {\r\n        s=305860330;\r\n        m=3;\r\n    }\r\n    if(n>400000) {\r\n        s=198031628;\r\n        m=4;\r\n    }\r\n    if(n>500000) {\r\n        s=292516569;\r\n        m=5;\r\n    }\r\n    if(n>600000) {\r\n        s=377314150;\r\n        m=6;\r\n    }\r\n    if(n>700000) {\r\n        s=55409794;\r\n        m=7;\r\n    }\r\n    if(n>800000) {\r\n        s=731775727;\r\n        m=8;\r\n    }\r\n    if(n>900000) {\r\n        s=951702590;\r\n        m=9;\r\n    }\r\n    \r\n    \r\n    \r\n    for( int j=m*100000+1;j<n;j++) {\r\n        rr=(s+ysgs(j))%R;\r\n        s=(s+rr)%R;\r\n    }\r\n    printf(\"%d\\n\",(s+ysgs(n))%R);\r\n    printf(\"%d\",ysgs(n));\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "51d7d9592f36ca4dbaded6bdfe4d6c0e", "src_uid": "09be46206a151c237dc9912df7e0f057", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t3000\n#define M\t3000\n\nvoid slide(int *aa, int *bb, int n, int m) {\n\tstatic int qq[N];\n\tint i, head, cnt;\n\n\thead = cnt = 0;\n\tfor (i = 0; i < n; i++) {\n\t\twhile (cnt && aa[qq[head + cnt - 1]] > aa[i])\n\t\t\tcnt--;\n\t\tqq[head + cnt++] = i;\n\t\tif (i >= m - 1)\n\t\t\tbb[i - m + 1] = aa[qq[head]];\n\t\tif (qq[head] == i - m + 1)\n\t\t\thead++, cnt--;\n\t}\n}\n\nint main() {\n\tstatic int aa[N][M], bb[N][M], cc[N], dd[N];\n\tint n, m, a, b, g, x, y, z, i, j;\n\tlong long ans;\n\n\tscanf(\"%d%d%d%d%d%d%d%d\", &n, &m, &a, &b, &g, &x, &y, &z);\n\tfor (i = 0; i < n; i++)\n\t\tfor (j = 0; j < m; j++) {\n\t\t\taa[i][j] = g;\n\t\t\tg = ((long long) g * x + y) % z;\n\t\t}\n\tfor (i = 0; i < n; i++)\n\t\tslide(aa[i], bb[i], m, b);\n\tans = 0;\n\tfor (j = 0; j + b <= m; j++) {\n\t\tfor (i = 0; i < n; i++)\n\t\t\tcc[i] = bb[i][j];\n\t\tslide(cc, dd, n, a);\n\t\tfor (i = 0; i + a <= n; i++)\n\t\t\tans += dd[i];\n\t}\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "60e79657e6b53778a4b8fd2423d54110", "src_uid": "4618fbffb2b9d321a6d22c11590a4773", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<stdint.h>\n#include<inttypes.h>\n\ntypedef int64_t i64;\ntypedef int32_t i32;\n\nstatic void print_int(i64 n){if(n<0){putchar('-');n=-n;}if(n==0){putchar('0');return;}int s[20],len=0;while(n>0){s[len++]=n%10+'0';n/=10;}while(len>0){putchar(s[--len]);}}\nstatic i64 read_int(void){int prev='\\0';int c=getchar();while(!('0'<=c && c<='9')){prev=c;c=getchar();}i64 res=0;while('0'<=c && c<='9'){res=10*res+c-'0';c=getchar();}return prev=='-'?-res:res;}\n\n#define ALLOC(size,type) ((type*)calloc((size),sizeof(type)))\n\n#define POS(i, j) ((i) * m + (j))\n\nvoid run (void) {\n  i32 n = read_int();\n  i32 m = read_int();\n  i32 a = read_int();\n  i32 b = read_int();\n  i32 *h = ALLOC (n * m, i32);\n  h[0] = read_int();\n  i32 x = read_int();\n  i32 y = read_int();\n  i32 z = read_int();\n  for (i32 i = 1; i < n * m; ++i) {\n    h[i] = ((i64) h[i - 1] * x + y) % z;\n  }\n  i32 *dp1 = ALLOC (n * m, i32);\n  i32 *q = ALLOC (n + m, i32);\n  for (i32 i = 0; i < n; ++i) {\n    i32 front = 0;\n    i32 last = 0;\n    q[last++] = 0;\n    for (i32 j = 1; j < b; ++j) {\n      while (front < last && h[POS(i, q[last - 1])] >= h[POS(i, j)]) --last;\n      q[last++] = j;\n    }\n    dp1[POS(i, 0)] = h[POS(i, q[front])];\n    for (i32 j = b; j < m; ++j) {\n      if (q[front] == j - b) front++;\n      while (front < last && h[POS(i, q[last - 1])] >= h[POS(i, j)]) --last;\n      q[last++] = j;\n      dp1[POS(i, j - b + 1)] = h[POS(i, q[front])];\n    }\n  }\n  {\n    i32 *swap = dp1;\n    dp1 = h;\n    h = swap;\n  }\n  i64 ans = 0;\n  for (i32 j = 0; j < m - b + 1; ++j) {\n    i32 front = 0;\n    i32 last = 0;\n    q[last++] = 0;\n    for (i32 i = 1; i < a; ++i) {\n      while (front < last && h[POS(q[last - 1], j)] >= h[POS(i, j)]) --last;\n      q[last++] = i;\n    }\n    ans += h[POS(q[front], j)];\n    for (i32 i = a; i < n; ++i) {\n      if (q[front] == i - a) front++;\n      while (front < last && h[POS(q[last - 1], j)] >= h[POS(i, j)]) --last;\n      q[last++] = i;\n      ans += h[POS(q[front], j)];\n    }\n  }\n  print_int (ans);\n  puts (\"\");\n}\n\nint main (void) {\n  run ();\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "36bd0ed74dcc1d32c78e3af2729ff01d", "src_uid": "4618fbffb2b9d321a6d22c11590a4773", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint table[2][3000][3000];\nlong long g, x, y, z;\n#define MAXINT 0x7fffffff\n\nint nextg(){\n\tint ret=g;\n\tg=(g*x+y)%z;\n\treturn ret;\n}\n\nint min(int a, int b){\n\treturn a<b?a:b;\n}\n\nint msb(int a){\n\ta|=a>>1;\n\ta|=a>>2;\n\ta|=a>>4;\n\ta|=a>>8;\n\ta|=a>>16;\n\treturn (a+1)>>1;\n}\n\nint main(){\n\tint i, j, k, n, m, a, b, tren, prev, l;\n\tlong long sum=0;\n\tscanf(\"%d %d %d %d %lld %lld %lld %lld\", &n, &m, &a, &b, &g, &x, &y, &z);\n\tfor(i=0;i<n;++i)\n\t\tfor(j=0;j<m;++j)\n\t\t\ttable[0][i][j]=nextg();\n\tfor(k=0;(1<<(k+1))<=a;++k){\n\t\tprev=k&1;\n\t\ttren=!prev;\n\t\tfor(i=0;i<n-(1<<k);++i){\n\t\t\tfor(j=0;j<m;++j){\n\t\t\t\ttable[tren][i][j]=min(table[prev][i][j], table[prev][i+(1<<k)][j]);\n\t\t\t}\n\t\t}\n\t}\n\tfor(l=0;(1<<(l+1))<=b;++l){\n\t\tprev=(l+k)&1;\n\t\ttren=!prev;\n\t\tfor(i=0;i<n-(1<<k);++i){\n\t\t\tfor(j=0;j<m-(1<<l);++j){\n\t\t\t\ttable[tren][i][j]=min(table[prev][i][j], table[prev][i][j+(1<<l)]);\n\t\t\t}\n\t\t}\n\t}\n\tfor(i=0;i+a<=n;++i){\n\t\tfor(j=0;j+b<=m;++j){\n\t\t\tsum+=(long long)(min(min(min(\n\t\t\t\t\t\t\t\ttable[tren][i][j],\n\t\t\t\t\t\t\t\ttable[tren][i+a-msb(a)][j]),\n\t\t\t\t\t\t\t\ttable[tren][i][j+b-msb(b)]),\n\t\t\t\t\t\t\t\ttable[tren][i+a-msb(a)][j+b-msb(b)]));\n\t\t}\n\t}\n\tprintf(\"%I64d\\n\", sum);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "59e6082deaec2f8d3cf49f5afb76e951", "src_uid": "4618fbffb2b9d321a6d22c11590a4773", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint tree[8000][8000], node;\nlong long g, x, y, z;\n#define MAXINT 0x7fffffff\n\nint nextg(){\n\tint ret=g;\n\tg=(g*x+y)%z;\n\treturn ret;\n}\n\nint min(int a, int b){\n\treturn a<b?a:b;\n}\n\nvoid build1(int n, int l, int r, int l2, int r2){\n\tif(l+1==r){\n\t\tif(l2+1==r2){\n\t\t\ttree[node][n]=nextg();\n\t\t}\n\t\telse{\n\t\t\ttree[node][n]=min(tree[2*node+1][n], tree[2*node+2][n]);\n\t\t}\n\t\treturn;\n\t}\n\tint m=(l+r)/2;\n\tbuild1(2*n+1, l, m, l2, r2);\n\tbuild1(2*n+2, m, r, l2, r2);\n\ttree[node][n]=min(tree[node][2*n+1], tree[node][2*n+2]);\n}\n\nvoid build2(int n, int l, int r, int rd){\n\tif(l+1==r){\n\t\tnode=n;\n\t\tbuild1(0, 0, rd, l, r);\n\t\treturn;\n\t}\n\tint m=(l+r)/2;\n\tbuild2(2*n+1, l, m, rd);\n\tbuild2(2*n+2, m, r, rd);\n\tnode=n;\n\tbuild1(0, 0, rd, l, r);\n}\n\nint query1(int n, int l, int r, int ql, int qr){\n\tif(qr<=l || r<=ql) return MAXINT;\n\tif(ql<=l && r<=qr){\n\t\treturn tree[node][n];\n\t}\n\tint m=(l+r)/2;\n\treturn min(query1(2*n+1, l, m, ql, qr),\n\t\t\tquery1(2*n+2, m, r, ql, qr));\n}\n\nint query2(int n, int l, int r, int r2, int ql, int qr, int ql2, int qr2){\n\tif(qr<=l || r<=ql) return MAXINT;\n\tif(ql<=l && r<=qr){\n\t\tnode=n;\n\t\treturn query1(0, 0, r2, ql2, qr2);\n\t}\n\tint m=(l+r)/2;\n\treturn min(query2(2*n+1, l, m, r2, ql, qr, ql2, qr2),\n\t\t\tquery2(2*n+2, m, r, r2, ql, qr, ql2, qr2));\n}\n\nint main(){\n\tmemset(tree, 0x7f, sizeof(tree));\n\tint i, j, n, m, a, b;\n\tlong long sum=0;\n\tscanf(\"%d %d %d %d %I64d %I64d %I64d %I64d\", &n, &m, &a, &b, &g, &x, &y, &z);\n\tbuild2(0, 0, n, m);\n\tfor(i=0;i+a<=n;++i){\n\t\tfor(j=0;j+b<=m;++j){\n\t\t\tsum+=(long long)query2(0, 0, n, m, i, i+a, j, j+b);\n\t\t}\n\t}\n\tprintf(\"%I64d\\n\", sum);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fd7ab61201bf50b0be0ea4e830bf022b", "src_uid": "4618fbffb2b9d321a6d22c11590a4773", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n\nint tree[3*3000][3*3000], node;\nlong long g, x, y, z;\n#define MAXINT 0x7fffffff\n\nint nextg(){\n\tint ret=g;\n\tg=(g*x+y)%z;\n\treturn ret;\n}\n\nint min(int a, int b){\n\treturn a<b?a:b;\n}\n\nvoid build1(int n, int l, int r, int l2, int r2){\n\tif(l+1==r){\n\t\tif(l2+1==r2){\n\t\t\ttree[node][n]=nextg();\n\t\t}\n\t\telse{\n\t\t\ttree[node][n]=min(tree[2*node+1][n], tree[2*node+2][n]);\n\t\t}\n\t\treturn;\n\t}\n\tint m=(l+r)/2;\n\tbuild1(2*n+1, l, m, l2, r2);\n\tbuild1(2*n+2, m, r, l2, r2);\n\ttree[node][n]=min(tree[node][2*n+1], tree[node][2*n+2]);\n}\n\nvoid build2(int n, int l, int r, int rd){\n\tif(l+1==r){\n\t\tnode=n;\n\t\tbuild1(0, 0, rd, l, r);\n\t\treturn;\n\t}\n\tint m=(l+r)/2;\n\tbuild2(2*n+1, l, m, rd);\n\tbuild2(2*n+2, m, r, rd);\n\tnode=n;\n\tbuild1(0, 0, rd, l, r);\n}\n\nint query1(int n, int l, int r, int ql, int qr){\n\tif(qr<=l || r<=ql) return MAXINT;\n\tif(ql<=l && r<=qr){\n\t\treturn tree[node][n];\n\t}\n\tint m=(l+r)/2;\n\treturn min(query1(2*n+1, l, m, ql, qr),\n\t\t\tquery1(2*n+2, m, r, ql, qr));\n}\n\nint query2(int n, int l, int r, int r2, int ql, int qr, int ql2, int qr2){\n\tif(qr<=l || r<=ql) return MAXINT;\n\tif(ql<=l && r<=qr){\n\t\tnode=n;\n\t\treturn query1(0, 0, r2, ql2, qr2);\n\t}\n\tint m=(l+r)/2;\n\treturn min(query2(2*n+1, l, m, r2, ql, qr, ql2, qr2),\n\t\t\tquery2(2*n+2, m, r, r2, ql, qr, ql2, qr2));\n}\n\nint main(){\n\tmemset(tree, 0x7f, sizeof(tree));\n\tint i, j, n, m, a, b;\n\tlong long sum=0;\n\tscanf(\"%d %d %d %d %I64d %I64d %I64d %I64d\", &n, &m, &a, &b, &g, &x, &y, &z);\n\tbuild2(0, 0, n, m);\n\tfor(i=0;i+a<=n;++i){\n\t\tfor(j=0;j+b<=m;++j){\n\t\t\tsum+=(long long)query2(0, 0, n, m, i, i+a, j, j+b);\n\t\t}\n\t}\n\tprintf(\"%I64d\\n\", sum);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "524f58fa031ce4aee6ba85a53c5d33e7", "src_uid": "4618fbffb2b9d321a6d22c11590a4773", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint dp[2][4][2][31][31][31];\n\nint main()\n{\n    int n, h, m = 1000000009, sum = 0, i, j, k, l, p, q, r, s;\n    int a[4], b[3];\n    \n    scanf(\"%d %d\", &n, &h);\n    \n    dp[0][0][0][0][0][0] = 1;\n    \n    for (i = 0; i < n; i++) {\n        for (j = 0; j < 4; j++) {\n            for (k = 0; k < 2; k++) {\n                for (l = 0; l <= h; l++) {\n                    for (p = l; p <= h; p++) {\n                        for (q = p; q <= h; q++) {\n                            if (dp[i & 1][j][k][l][p][q] == 0) continue;\n                            \n                            for (r = 0; r < 4; r++) a[r] = -1;\n                            \n                            if (k == 0) {\n                                a[j] = 0;\n                            } else {\n                                a[j] = h;\n                            }\n                            \n                            r = 0;\n                            \n                            if (a[r] >= 0) r++;\n                            a[r++] = l;\n                            \n                            if (a[r] >= 0) r++;\n                            a[r++] = p;\n                            \n                            if (a[r] >= 0) r++;\n                            a[r++] = q;\n                            \n                            for (r = 0; r < 4; r++) {\n                                int c = 0;\n                                \n                                for (s = 0; s < 4; s++) {\n                                    if (s == r) continue;\n                                    \n                                    b[c] = a[s] + 1;\n                                    \n                                    if (b[c] > h) b[c] = h;\n                                    \n                                    c++;\n                                }\n                                \n                                if (b[0] > b[1]) {\n                                    int tmp = b[0];\n                                    b[0] = b[1];\n                                    b[1] = tmp;\n                                }\n                                \n                                if (b[0] > b[2]) {\n                                    int tmp = b[0];\n                                    b[0] = b[2];\n                                    b[2] = tmp;\n                                }\n                                \n                                if (b[1] > b[2]) {\n                                    int tmp = b[1];\n                                    b[1] = b[2];\n                                    b[2] = tmp;\n                                }\n                                \n                                if (a[r] == h) {\n                                    dp[(i + 1) & 1][r][1][b[0]][b[1]][b[2]] += dp[i & 1][j][k][l][p][q];\n                                    \n                                    if (dp[(i + 1) & 1][r][1][b[0]][b[1]][b[2]] >= m) dp[(i + 1) & 1][r][1][b[0]][b[1]][b[2]] -= m;\n                                } else {\n                                    dp[(i + 1) & 1][r][0][b[0]][b[1]][b[2]] += dp[i & 1][j][k][l][p][q];\n                                    \n                                    if (dp[(i + 1) & 1][r][0][b[0]][b[1]][b[2]] >= m) dp[(i + 1) & 1][r][0][b[0]][b[1]][b[2]] -= m;\n                                }\n                            }\n                            \n                            dp[i & 1][j][k][l][p][q] = 0;\n                        }\n                    }\n                }\n            }\n        }\n    }\n    \n    for (i = 0; i < 4; i++) {\n        for (j = 0; j < 2; j++) {\n            for (k = 0; k <= h; k++) {\n                for (l = 0; l <= h; l++) {\n                    for (r = 0; r <= h; r++) {\n                        if (j == 0 || (k > 0 && k < h) || (l > 0 && l < h) || (r > 0 && r < h)) {\n                            sum += dp[n & 1][i][j][k][l][r];\n                            \n                            if (sum >= m) sum -= m;\n                        }\n                    }\n                }\n            }\n        }\n    }\n    \n    printf(\"%d\\n\", sum);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d89ed62111e66805d48a022a5c79a65b", "src_uid": "9fe9658db35076c0bddc8b7ddce11013", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#include<math.h>\n#include<memory.h>\n#include<assert.h>\n#include<ctype.h>\n\ntypedef long long ll;\n\n#define max(a,b) (((a)>(b))?(a):(b))\n#define min(a,b) (((a)<(b))?(a):(b))\n#define abs(k) (((k)>0)?(k):(-(k)))\nint modint(int a,int b) {return(((a)>=0)?((a)-(b)*((a)/(b))):((a)-(b)*((a)/(b)+1)));}\nll modll(ll a,ll b) {return(((a)>=0)?((a)-(b)*((a)/(b))):((a)-(b)*((a)/(b)+1)));}\n#define mod(a,b) a=modint(a,b)\n#define llmod(a,b) a=modll(a,b)\n#define mset(a) memset(a,0,sizeof(a))\n#define mcpy(a,b) memcpy(a,b,sizeof(a))\n#define inf (1e9)\n#define linf (1e18)\n#define pi 3.14159265358979323846\n\nvoid fileio_in_out()\n{\n     freopen(\".in\",\"r\",stdin);\n     freopen(\".out\",\"w\",stdout);\n}\n\nvoid fileio_txt()\n{\n     freopen(\"input.txt\",\"r\",stdin);\n     freopen(\"output.txt\",\"w\",stdout);\n}\n\n//==================================================\n\n#define modnum (inf+9)\n\nint n,h,x,y,z,ww,xx,yy,zz;\nint i,j,k,l;\nll dp[33][33][33][2][2],ans=0,t;\n\nint main()\n{\n    //fileio_in_out();\n    //fileio_txt();\n    \n    scanf(\"%d%d\",&n,&h);\n    \n    mset(dp);\n    dp[0][0][0][0][1]=1;\n    for(k=0;k<n;k++)\n      for(x=0;x<=h;x++)\n        for(y=0;y<=h;y++)\n          for(z=0;z<=h;z++)\n            for(j=0;j<=1;j++)\n              {\n                i=k%2;\n                t=dp[x][y][z][i][j];\n                llmod(t,modnum);\n                dp[x][y][z][i][j]=0;\n                \n                i^=1;\n                xx=min(x+1,h);\n                yy=min(y+1,h);\n                zz=min(z+1,h);\n                ww=j?1:h;\n                \n                dp[xx][yy][zz][i][j]+=t;\n                dp[yy][zz][ww][i][(x<h)]+=t;\n                dp[xx][zz][ww][i][(y<h)]+=t;\n                dp[xx][yy][ww][i][(z<h)]+=t;\n              }\n    \n    i=n%2;\n    for(x=0;x<=h;x++)\n      for(y=0;y<=h;y++)\n        for(z=0;z<=h;z++)\n          for(j=0;j<=1;j++)\n            if(x<h||y<h||z<h||j)\n              {\n                ans+=dp[x][y][z][i][j];\n                llmod(ans,modnum);\n              }\n    \n    printf(\"%I64d\\n\",ans);\n    \n    //system(\"pause\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "68906452c43823386d95055ab4eed027", "src_uid": "9fe9658db35076c0bddc8b7ddce11013", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "#define __USE_MINGW_ANSI_STDIO 0\r\n#include <stdio.h>\r\n\r\n// MODULAR NCR\r\n// DEPENDENCIES:\r\n\r\n// nCr % mod function\r\n// Using Fermat's Little theorem: a^(p-2) = a^(-1) (mod p)\r\n\r\n#define maxN 200000\r\n#define MOD 1000000007\r\n//#define MOD 998244353\r\n\r\n// Build factorial array\r\nlong long fac[maxN + 1];\r\nvoid __attribute__((constructor))\r\ninitFacs() {\r\n\tfac[0] = 1;\r\n    for (int i = 1; i <= maxN; i++) fac[i] = fac[i - 1] * i % MOD; \r\n}\r\n\r\n// Calculate base ^ pow % mod\r\nlong long mPow(long long base, int pow) {\r\n    long long res = 1;\r\n    base %= MOD;\r\n    // constantly decompose base ^ pow = (base ^ 2) ^ (pow / 2)\r\n    while (pow > 0) {\r\n        // make sure if it is odd, then base ^ pow = base ^ (pow - 1) * base\r\n        if (pow % 2 == 1) res = res * base % MOD;\r\n        pow /= 2;\r\n        base = (base * base) % MOD;\r\n    }\r\n    return res;\r\n}\r\n\r\n// a ^ (p - 2) = a ^ (-1) (mod p)\r\nlong long mInv(long long n) {\r\n    return mPow(n, MOD - 2);\r\n}\r\n\r\n// nCr = n! / r! / (n - r)!\r\n// nCr = n! * inv(r!) * inv((n - r)!)\r\nlong long mnCr(long long n, int r) {\r\n    // Base cases\r\n    if (n < r) return 0;\r\n    if (r == 0) return 1;\r\n\r\n    return fac[n] * mInv(fac[r]) % MOD\r\n           * mInv(fac[n - r]) % MOD;\r\n}\r\n// END MODULAR NCR\r\n\r\nlong long _T[maxN + 1];\r\nlong long _2n[maxN + 1];\r\n\r\nvoid testcase() {\r\n\tint n, k;\r\n\tscanf(\"%d%d\", &n, &k);\r\n\tlong long T;\r\n\tlong long ans;\r\n\tif (n % 2 == 1) {\r\n\t\t// n odd\r\n\t\tT = 1;\r\n\t\tfor (int i = 0; i <= (n - 1) / 2; ++i) {\r\n\t\t\tT += mnCr(n, i);\r\n\t\t\tT %= MOD;\r\n\t\t}\r\n\t\tans = 1;\r\n\t\tfor (int i = 0; i < k; ++i) {\r\n\t\t\tans *= T;\r\n\t\t\tans %= MOD;\r\n\t\t}\r\n\t} else {\r\n\t\t// n even\r\n\t\tT = 0;\r\n\t\tfor (int i = 0; i < n; i += 2) {\r\n\t\t\tT += mnCr(n, i);\r\n\t\t\tT %= MOD;\r\n\t\t}\r\n\t\t_T[0] = 1;\r\n\t\tlong long base = mPow(2, n);\r\n\t\t_2n[0] = 1;\r\n\t\tfor (int i = 1; i <= k; ++i) {\r\n\t\t\t_T[i] = _T[i - 1] * T % MOD;\r\n\t\t\t_2n[i] = _2n[i - 1] * base % MOD;\r\n\t\t}\r\n\t\tans = _T[k] * _2n[0] % MOD;\r\n\t\tfor (int i = k - 1; i >= 0; --i) {\r\n\t\t\tans += _T[i] * _2n[k - 1 - i] % MOD;\r\n\t\t\tans %= MOD;\r\n\t\t}\r\n\t}\r\n\tprintf(\"%lld\\n\", ans);\r\n    return;\r\n}\r\n\r\nint main() {\r\n    int t;\r\n    scanf(\"%d\", &t);\r\n    for (int i = 0; i < t; ++i) testcase();\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c02865523b414ff2e95b2e9be6a80cc0", "src_uid": "02f5fe43ea60939dd4a53299b5fa0881", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <ctype.h>\n\n// Program de Mircea Rebengiuc\n// inceput pe 2021.08.09\n\n#define MOD 1000000007\n#define MAXN 200000\n#define MAXK 200000\n\nint p2[MAXK + 1];\n\nstatic inline int multmod( int a, int b ){\n  return (((long long)a) * b) % MOD;\n}\n\nstatic inline int addmod( int a, int b ){\n  return (a + b) % MOD;\n}\n\n// chestii invmod\nstatic inline int myExp( int a, int n ){\n  int acc = 1;\n\n  while( n > 0 ){\n    if( n & 1 )\n      acc = multmod(acc, a);\n    a = multmod(a, a);\n    n >>= 1;\n  }\n\t\n  return acc;\n}\n\nstatic inline int inv( int x ){\n  return myExp(x, MOD - 2);\n}\n\nint main(){\n  int t, n, k, i, big_num, comb, numeq, answer;\n\n  p2[0] = 1;\n  for( i = 1 ; i <= MAXK ; i++ )\n    p2[i] = multmod(2, p2[i - 1]);\n\n  for( scanf(\"%d\", &t) ; t-- ; ){\n    scanf(\"%d%d\", &n, &k);\n\n    // calculam big_num = numarul de moduri de a face o pozitie sa fie egala (and = xor) modificand doar bitii de pe acea pozitie\n    // cazul and = xor = 1\n    big_num = (n & 1);\n\n    // cazul and = xor = 0\n    comb = 1;\n    for( i = 0 ; i < n ; i += 2 ){\n      big_num = addmod(big_num, comb);\n      comb = multmod(comb, multmod(n - i, n - i - 1));\n      comb = multmod(comb, multmod(inv(i + 1), inv(i + 2)));\n    }\n\n    // simulam\n    numeq = 1;// numeq = numarul de moduri de a face primele i cifre egale modificand doar primele i cifre\n    answer = 0;\n    for( i = 0 ; i < k ; i++ ){\n      if( (n & 1) == 0 )// cazul in care pentru bitul i and = 1, xor = 0\n        answer = addmod(answer, multmod(numeq, myExp(p2[k - i - 1], n)));// adaugam numarul de posibilitati\n      \n      numeq = multmod(numeq, big_num);// actualizam x\n    }\n    answer = addmod(answer, numeq);// adaugam numarul de cazuri in care e egal ca semnul este >=\n\n    printf(\"%d\\n\", answer);\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f92614097c60fa90e5cb75caa2a1ed9f", "src_uid": "02f5fe43ea60939dd4a53299b5fa0881", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h> \r\n#define int long long\r\nint n,k,a,x,y,T,M=1e9+7;\r\nint power(int p,int z)\r\n{\r\n\tif(z==0) return 1%M;\r\n\tif(z==1) return p%M;\r\n\tint tt=power(p,z/2);\r\n\tif(z&1) return ((tt*tt)%M)*p%M;\r\n\telse return (tt*tt)%M;\r\n}\r\nmain()\r\n{\r\n\tscanf(\"%lld\",&T);\r\n\twhile(T--)\r\n\t{\r\n\t\tscanf(\"%lld%lld\",&n,&k);\r\n\t\tif(n&1)\r\n\t\t{\r\n\t\t\ty=(power(2,n-1)+1)%M;\r\n\t\t\ty=power(y,k);\r\n\t\t}\r\n\t\telse\r\n\t\t{\r\n\t\t\ty=power(2,n-1);\r\n\t\t\tx=(power(2,n-1)-1+M)%M;\r\n\t\t\ta=((y*power(x,k))%M+power((2*y)%M,k)+M)%M;\r\n\t\t\ta=a*power((y+1)%M,M-2)%M;\r\n\t\t\ty=a;\r\n\t\t}\r\n\t\tprintf(\"%lld\\n\",y);\r\n\t}\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "dc9bca9e30fdef8bd45328b066bbeb1b", "src_uid": "02f5fe43ea60939dd4a53299b5fa0881", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define MD\t1000000007\n\nlong long power(long long a, int k) {\n\tlong long p = 1;\n\n\twhile (k) {\n\t\tif (k & 1)\n\t\t\tp = p * a % MD;\n\t\ta = a * a % MD;\n\t\tk >>= 1;\n\t}\n\treturn p;\n}\n\nint main() {\n\tint t;\n\n\tscanf(\"%d\", &t);\n\twhile (t--) {\n\t\tint n, k, i, ans;\n\n\t\tscanf(\"%d%d\", &n, &k);\n\t\tif (k == 0)\n\t\t\tprintf(\"1\\n\");\n\t\telse if (n % 2 == 1)\n\t\t\tprintf(\"%lld\\n\", power(power(2, n - 1) + 1, k));\n\t\telse {\n\t\t\tans = power(power(2, n - 1) - 1, k);\n\t\t\tfor (i = 0; i < k; i++)\n\t\t\t\tans = (ans + power(power(2, n - 1) - 1, i) * power(power(2, n), k - 1 - i)) % MD;\n\t\t\tprintf(\"%d\\n\", ans);\n\t\t}\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "013ccb3b6dbcfceabc7b2390a7863854", "src_uid": "02f5fe43ea60939dd4a53299b5fa0881", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <ctype.h>\n\n// Program de Mircea Rebengiuc\n// inceput pe 2021.08.09\n\n#define MOD 1000000007\n#define MAXN 100000\n#define MAXK 100000\n\nint p2[MAXK + 1];\n\nstatic inline int multmod( int a, int b ){\n  return (((long long)a) * b) % MOD;\n}\n\nstatic inline int addmod( int a, int b ){\n  return (a + b) % MOD;\n}\n\n// chestii invmod\nstatic inline int myExp( int a, int n ){\n  int acc = 1;\n\n  while( n > 0 ){\n    if( n & 1 )\n      acc = multmod(acc, a);\n    a = multmod(a, a);\n    n /= 2;\n  }\n\t\n  return acc;\n}\n\nstatic inline int inv( int x ){\n  return myExp(x, MOD - 2);\n}\n\nint main(){\n  int t, n, k, i, big_num, comb, x, answer;\n\n  p2[0] = 1;\n  for( i = 1 ; i <= MAXK ; i++ )\n    p2[i] = (2 * p2[i - 1]) % MOD;// nu tb sa fac long long ca nu 2 * MOD nu da overflow\n\n  for( scanf(\"%d\", &t) ; t-- ; ){\n    scanf(\"%d%d\", &n, &k);\n\n    // calculam big_num\n    big_num = 0;\n    comb = 1;\n    for( i = 0 ; i < n ; i += 2 ){\n      big_num = addmod(big_num, comb);\n      comb = multmod(comb, multmod(n - i, n - i - 1));\n      comb = multmod(comb, multmod(inv(i + 1), inv(i + 2)));\n    }\n\n    // simulam\n    x = 1;\n    answer = 0;// scadem din total ca conditia este >=\n    for( i = 0 ; i < k ; i++ ){\n      answer = addmod(answer, (1 ^ (n & 1)) * multmod(x, p2[k - i - 1])) % MOD;\n      x = multmod(x, (n & 1) + big_num);\n    }\n    answer = addmod(answer, x);\n\n    printf(\"%d\\n\", answer);\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9ddfcdbe78208ee156a1edb0d169314b", "src_uid": "02f5fe43ea60939dd4a53299b5fa0881", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t123456\n#define K\t60\n#define MD\t1000000007\n\nint main() {\n\tstatic int dp[K][6];\n\tint k, n, h, c, ans;\n\n\tscanf(\"%d\", &k), n = 0;\n\tfor (c = 0; c < 6; c++)\n\t\tdp[0][c] = 1;\n\tfor (h = 1; h < k; h++) {\n\t\tint sum = 0;\n\n\t\tfor (c = 0; c < 6; c++)\n\t\t\tsum = (sum + dp[h - 1][c]) % MD;\n\t\tfor (c = 0; c < 6; c++)\n\t\t\tdp[h][c] = ((long long) sum - dp[h - 1][c] - dp[h - 1][c ^ 1]) % MD * ((long long) sum - dp[h - 1][c] - dp[h - 1][c ^ 1]) % MD;\n\t}\n\tans = 0;\n\tfor (c = 0; c < 6; c++)\n\t\tans = (ans + dp[k - 1][c]) % MD;\n\tif (ans < 0)\n\t\tans += MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ec2cfaa7ca33d2a191f6b3b840911f8f", "src_uid": "5144b9b281ea4087d8334d91c3c8bda4", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\nlong long unsigned int n, ans, modulo;\r\n\r\nvoid solve(){\r\n    scanf(\"%llu\", &n);\r\n\r\n    /* if(n == 1){ */\r\n    /*     puts(\"6\"); */\r\n    /*     return; */\r\n    /* } */\r\n\r\n    ans = 1;\r\n    n--;\r\n    while(n--){\r\n        ans = ans * 4;\r\n        ans = ans % modulo;\r\n        ans = ans * ans;\r\n        ans = ans % modulo;\r\n    }\r\n\r\n    ans = ans * 6;\r\n    ans = ans % modulo;\r\n\r\n    printf(\"%llu\\n\", ans);\r\n}\r\n\r\nint main(){\r\n    modulo = 1000000007;\r\n    solve();\r\n}\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fed106657eeb900907ef5218d103eb33", "src_uid": "5144b9b281ea4087d8334d91c3c8bda4", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#define MOD 1000000007\r\nchar str[500005];\r\n\r\nint pow(int base, long long fac)\r\n{\r\n    int ret = 1;\r\n    while(fac)\r\n    {\r\n        if (fac & 1)\r\n            ret = 1ll * ret * base % MOD;\r\n        base = 1ll * base * base % MOD;\r\n        fac >>= 1;\r\n    }\r\n    return ret;\r\n}\r\n\r\nint main(void)\r\n{\r\n    int k;\r\n    scanf(\"%d\", &k);\r\n    int ans = 6ll * pow(4, (1ll << k) - 2) % MOD;\r\n    printf(\"%d\", ans);\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ae3e73368f6f81e7e46233083c184ff6", "src_uid": "5144b9b281ea4087d8334d91c3c8bda4", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <stdlib.h>\r\n\r\n#define MOD_NUMBER 1000000007\r\n\r\nunsigned long long modpow(int n, unsigned long long index) {\r\n    unsigned long long nn = n;\r\n    unsigned long long ans = 1;\r\n    while (index) {\r\n        if (index & 1) {\r\n            ans *= nn;\r\n            ans %= MOD_NUMBER;\r\n        }\r\n        nn *= nn;\r\n        nn %= MOD_NUMBER;\r\n        index >>= 1;\r\n    }\r\n\r\n    return ans;\r\n}\r\n\r\nint run() {\r\n    int n;\r\n    scanf(\"%d\", &n);\r\n    long long a = (6*modpow(4, (1<<n) - 2))%MOD_NUMBER;\r\n    printf(\"%lld\\n\", a);\r\n    return 0;\r\n}\r\n\r\nint main(int argc, char* argv[]) {\r\n    int n = 1;\r\n    for (int i = 0; i < n; ++i) {\r\n        run();\r\n    }\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "24263bede4d79cb5776e9b75b7cdcf4f", "src_uid": "5144b9b281ea4087d8334d91c3c8bda4", "difficulty": 1300.0}
{"lang": "GNU C11", "source_code": "#pragma c11 on\r\n\r\n#include<stdio.h>\r\n#include<stdbool.h>\r\n#include<limits.h>\r\n#include<string.h>\r\n#include<math.h>\r\n#include<stdlib.h>\r\n#define MOD (int)(1e9+7)\r\ntypedef enum colorType{\r\n    white, green, red, blue, orange ,yellow\r\n}colorType;\r\n\r\ntypedef struct treeNode{\r\n    colorType color;\r\n    struct treeNode* previous;\r\n    struct treeNode* next;\r\n}treeNode;\r\ntypedef struct tree{\r\n    treeNode * root;\r\n    int size;\r\n}tree;\r\nvoid makePerfectTree(int *t,int*k,treeNode* node){\r\n    if(*t<*k){\r\n        node->previous=calloc(1,sizeof(treeNode));\r\n        node->next=calloc(1,sizeof(treeNode));\r\n        (*t)++;\r\n        makePerfectTree(t,k,node->previous);\r\n        makePerfectTree(t,k,node->next);\r\n    }\r\n}\r\n\r\nlong long quickPow(long long n, long long powers) {\r\n    long long res = 1;\r\n    while (powers > 0) {\r\n        if (powers & 1)\r\n            res =res * n%MOD;\r\n        n = n*n%MOD;\r\n        powers >>= 1;\r\n    }\r\n    return res;\r\n}\r\nint main(void){\r\n    int k;\r\n    scanf(\"%d\",&k);\r\n    /*tree * tree1=(tree*)calloc(1,sizeof(tree));\r\n    tree1->root=calloc(1,sizeof(treeNode));\r\n    int t=1;\r\n    makePerfectTree(&t,&k,tree1->root);\r\n    //forget the idiot tree;\r\n*/\r\n    printf(\"%lld\",6* quickPow(4, ((1<<k)-2))%MOD);\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3b612cce7b9ff75128b4cf2b4232b3a1", "src_uid": "5144b9b281ea4087d8334d91c3c8bda4", "difficulty": 1300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <memory.h>\n#include <stdlib.h>\n#include <assert.h>\n#include <time.h>\n#include <ctype.h>\n#include <math.h>\n#include <stdbool.h>\n\n#define DEBUG\ntypedef int (*cmp_t) (const void *, const void *);\ntypedef unsigned uint;\ntypedef long long int64;\ntypedef unsigned long long uint64;\n#define max(i, j) ({int _ = (i), __ = (j); _ > __ ? _ : __;})\n#define min(i, j) ({int _ = (i), __ = (j); _ < __ ? _ : __;})\n#define swap(T, i, j) ({T _ = (i); (i) = (j); (j) = _;})\n#ifdef DEBUG\n#define cerr(...) fprintf (stderr, __VA_ARGS__)\nvoid disp (char *s, int *x, int n) {int i; cerr (\"[%s: \", s); for (i = 0; i < n - 1; ++i) cerr (\"%d \", x[i]); if (n) cerr (\"%d\", x[i]); cerr (\"]\\n\");}\n#else\n#define cerr(...) ({})\n#define disp(...) ({})\n#endif\n#define CR cerr (\"\\n\")\n#ifdef WIN32\n#define fmt64 \"%I64d\"\n#else\n#define fmt64 \"%lld\"\n#endif\n\n#define maxm 1100\n#define maxsz 125\n\nconst int mod = 12345;\ntypedef int mat[maxsz][maxsz];\n\nint qx[maxm], qc[maxm];\nint sz = 0;\nbool o[30][maxsz];\nmat u, v;\nint prod[30], val[30];\n\nint fpm (int b, int64 e, int m)\n{\n  int t = 1;\n  for (; e; e >>= 1, b = b * b % m)\n    e & 1 ? t = b * t % m : 0;\n  return t;\n}\n\nint gcd (int a, int b)\n{\n  int t;\n  for (; a; t = a, a = b % a, b = t);\n  return b;\n}\n\nvoid matmul (mat a, mat b, mat c)\n{\n  mat t; int i, j, k;\n  for (i = 0; i < sz; ++i)\n    for (j = 0; j < sz; ++j)\n      for (k = 0, t[i][j] = 0; k < sz; ++k)\n        t[i][j] += a[i][k] * b[k][j] % mod;\n  for (i = 0; i < sz; ++i)\n    for (j = 0; j < sz; ++j)\n      c[i][j] = t[i][j] % mod;\n}\n\nint main ()\n{\n#ifndef ONLINE_JUDGE\n  freopen (\"107D.in\" , \"r\", stdin);\n  freopen (\"107D.out\", \"w\", stdout);\n#endif\n\n  int64 n; int m, i, j, x, c; char C;\n  \n  scanf (fmt64 \"%d\", &n, &m);\n  for (i = 0; i < 26; ++i)\n    val[i] = -1;\n  for (i = 1; i <= m; ++i)\n    {\n      scanf (\" %c%d\", &C, &x), c = C - 'A';\n      qc[i] = c, qx[i] = x, val[c] = abs (val[c] * x / gcd (x, val[c]));\n    }\n  for (i = 1; i <= m; ++i)\n    for (x = 0; x < val[qc[i]]; x += qx[i])\n      o[qc[i]][x] = true;\n  for (i = 1, prod[0] = 1; i < 26; ++i)\n    prod[i] = prod[i - 1] * abs (val[i - 1]);\n  /* disp (\"prod\", prod, 26); */\n  /* disp (\"val\", val, 26); */\n\n  sz = prod[26] = prod[25] * abs (val[25]);\n  for (i = 0; i < sz; ++i)\n    for (j = 0; j < 26; ++j)\n      if (val[j] != -1)\n        {\n          x = i + prod[j];\n          if (x % prod[j + 1] < prod[j])\n            x -= prod[j + 1];\n          ++u[i][x];\n        }\n  /* for (i = 0; i < sz; ++i) */\n  /*   disp (\"u\", u[i], sz); */\n\n  v[0][0] = 1;\n  for (; n; n >>= 1, matmul (u, u, u))\n    n & 1 ? matmul (v, u, v) : 0;\n  \n  /* for (i = 0; i < sz; ++i) */\n  /*   disp (\"u\", v[i], sz); */\n  /* for (i = 0; i < 26; ++i) */\n  /*   { */\n  /*     for (j = 0; j < val[i]; ++j) */\n  /*       cerr (\"%d \", o[i][j]); */\n  /*     CR; */\n  /*   } */\n  int ans = 0;\n  for (i = 0; i < sz; ++i)\n    {\n      bool b = true;\n      for (j = 0; j < 26; ++j)\n        if (val[j] != -1 && !o[j][i % prod[j + 1] / prod[j]])\n          b = false;\n      if (b) ans += v[0][i];\n    }\n  printf (\"%d\\n\", ans % mod);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2bfcfa0a5999588889d7cce7278e1199", "src_uid": "76d4684d26dac380713a566a1e277c91", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#define mod 12345\n\nint a[27],v[27],p[1001],num[1001],mat[123][123],one[123][123],tmp[123][123];\nchar str[15];\nint s=1;\n\nvoid mi(long long a)\n{\n   int i,j,k;\n   if (!a)\n      for (i=0;i<s;i++)\n         mat[i][i]=1;\n   else\n   {\n      mi(a>>1);\n      memset(tmp,0,sizeof(tmp));\n      for (i=0;i<s;i++)\n         for (j=0;j<s;j++)\n            for (k=0;k<s;k++)\n               tmp[i][j]=(mat[i][k]*mat[k][j]+tmp[i][j])%mod;\n      for (i=0;i<s;i++)\n         for (j=0;j<s;j++)\n            mat[i][j]=tmp[i][j];\n      if (a&1)\n      {\n         memset(tmp,0,sizeof(tmp));\n         for (i=0;i<s;i++)\n            for (j=0;j<s;j++)\n               for (k=0;k<s;k++)\n                  tmp[i][j]=(mat[i][k]*one[k][j]+tmp[i][j])%mod;\n         for (i=0;i<s;i++)\n            for (j=0;j<s;j++)\n               mat[i][j]=tmp[i][j];\n      }\n   }\n}\n\nint main()\n{\n   long long n;\n   int i,j,k,c,t,ans=0;\n   scanf(\"%I64d%d\",&n,&c);\n   if (c)\n      getchar();\n   for (i=1;i<=c;i++)\n   {\n      gets(str+1);\n      p[i]=str[1]-'A'+1;\n      v[str[1]-'A'+1]=1;\n      for (j=3;str[j]>='0'&&str[j]<='9';j++)\n         num[i]=num[i]*10+str[j]-'0';\n      s*=num[i];\n   }\n   for (i=1;i<=c;i++)\n      v[p[i]]*=num[i];\n   for (i=0;i<s;i++)\n   {\n      t=i;\n      for (j=1;j<=26;j++)\n         if (v[j])\n         {\n            a[j]=t%v[j];\n            t/=v[j];\n         }\n      t=1;\n      for (j=1;j<=26;j++)\n         if (v[j])\n         {\n            if (a[j]==v[j]-1)\n               one[i][i-a[j]*t]++;\n            else\n               one[i][i+t]++;\n            t*=v[j];\n         }\n   }\n   mi(n);\n   for (i=0;i<s;i++)\n   {\n      t=i;\n      for (j=1;j<=26;j++)\n         if (v[j])\n         {\n            a[j]=t%v[j];\n            t/=v[j];\n            for (k=1;k<=c&&(p[k]!=j||a[j]%num[k]);k++);\n            if (k>c)\n               break;\n         }\n      if (j>26)\n         ans=(ans+mat[0][i])%mod;\n   }\n   printf(\"%d\\n\",ans);\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8d7a059bd92d2f7d108f32e504bdc17e", "src_uid": "76d4684d26dac380713a566a1e277c91", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#define mod 12345\n\nint a[27],v[27],p[1001],num[1001],mat[123][123],one[123][123],tmp[123][123];\nchar str[15];\nint s=1;\n\nvoid mi(int a)\n{\n   int i,j,k;\n   if (!a)\n      for (i=0;i<s;i++)\n         mat[i][i]=1;\n   else\n   {\n      mi(a>>1);\n      memset(tmp,0,sizeof(tmp));\n      for (i=0;i<s;i++)\n         for (j=0;j<s;j++)\n            for (k=0;k<s;k++)\n               tmp[i][j]=(mat[i][k]*mat[k][j]+tmp[i][j])%mod;\n      for (i=0;i<s;i++)\n         for (j=0;j<s;j++)\n            mat[i][j]=tmp[i][j];\n      if (a&1)\n      {\n         memset(tmp,0,sizeof(tmp));\n         for (i=0;i<s;i++)\n            for (j=0;j<s;j++)\n               for (k=0;k<s;k++)\n                  tmp[i][j]=(mat[i][k]*one[k][j]+tmp[i][j])%mod;\n         for (i=0;i<s;i++)\n            for (j=0;j<s;j++)\n               mat[i][j]=tmp[i][j];\n      }\n   }\n}\n\nint main()\n{\n   long long n;\n   int i,j,k,c,t,ans=0;\n   scanf(\"%I64d%d\\n\",&n,&c);\n   for (i=1;i<=c;i++)\n   {\n      gets(str+1);\n      p[i]=str[1]-'A'+1;\n      v[str[1]-'A'+1]=1;\n      for (j=3;str[j]>='0'&&str[j]<='9';j++)\n         num[i]=num[i]*10+str[j]-'0';\n      s*=num[i];\n   }\n   for (i=1;i<=c;i++)\n      v[p[i]]*=num[i];\n   for (i=0;i<s;i++)\n   {\n      t=i;\n      for (j=1;j<=26;j++)\n         if (v[j])\n         {\n            a[j]=t%v[j];\n            t/=v[j];\n         }\n      t=1;\n      for (j=1;j<=26;j++)\n         if (v[j])\n         {\n            if (a[j]==v[j]-1)\n               one[i][i-a[j]*t]++;\n            else\n               one[i][i+t]++;\n            t*=v[j];\n         }\n   }\n   mi(n);\n   for (i=0;i<s;i++)\n   {\n      t=i;\n      for (j=1;j<=26;j++)\n         if (v[j])\n         {\n            a[j]=t%v[j];\n            t/=v[j];\n            for (k=1;k<=c&&(p[k]!=j||a[j]%num[k]);k++);\n            if (k>c)\n               break;\n         }\n      if (j>26)\n         ans=(ans+mat[0][i])%mod;\n   }\n   printf(\"%d\\n\",ans);\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "db895b6f4ba8de6884007f1fcb6f8769", "src_uid": "76d4684d26dac380713a566a1e277c91", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#define mod 12345\n\nint a[27],v[27],p[1001],num[1001],mat[123][123],one[123][123],tmp[123][123];\nchar str[15];\nint s=1;\n\nvoid mi(int a)\n{\n   int i,j,k;\n   if (!a)\n      for (i=0;i<s;i++)\n         mat[i][i]=1;\n   else\n   {\n      mi(a>>1);\n      memset(tmp,0,sizeof(tmp));\n      for (i=0;i<s;i++)\n         for (j=0;j<s;j++)\n            for (k=0;k<s;k++)\n               tmp[i][j]=(mat[i][k]*mat[k][j]+tmp[i][j])%mod;\n      for (i=0;i<s;i++)\n         for (j=0;j<s;j++)\n            mat[i][j]=tmp[i][j];\n      if (a&1)\n      {\n         memset(tmp,0,sizeof(tmp));\n         for (i=0;i<s;i++)\n            for (j=0;j<s;j++)\n               for (k=0;k<s;k++)\n                  tmp[i][j]=(mat[i][k]*one[k][j]+tmp[i][j])%mod;\n         for (i=0;i<s;i++)\n            for (j=0;j<s;j++)\n               mat[i][j]=tmp[i][j];\n      }\n   }\n}\n\nint main()\n{\n   long long n;\n   int i,j,k,c,t,ans=0;\n   scanf(\"%I64d%d\\n\",&n,&c);\n   for (i=1;i<=c;i++)\n   {\n      gets(str+1);\n      p[i]=str[1]-'A'+1;\n      v[str[1]-'A'+1]=1;\n      for (j=3;str[j]>='0'&&str[j]<='9';j++)\n         num[i]=num[i]*10+str[j]-'0';\n      s*=num[i];\n   }\n   for (i=1;i<=c;i++)\n      v[p[i]]*=num[i];\n   for (i=0;i<s;i++)\n   {\n      t=i;\n      for (j=1;j<=26;j++)\n         if (v[j])\n         {\n            a[j]=t%v[j];\n            t/=v[j];\n         }\n      t=1;\n      for (j=1;j<=26;j++)\n         if (v[j])\n         {\n            if (a[j]==v[j]-1)\n               one[i][i-a[j]*t]=1;\n            else\n               one[i][i+t]=1;\n            t*=v[j];\n         }\n   }\n   mi(n);\n   for (i=0;i<s;i++)\n   {\n      t=i;\n      for (j=1;j<=26;j++)\n         if (v[j])\n         {\n            a[j]=t%v[j];\n            t/=v[j];\n            for (k=1;k<=c&&(p[k]!=j||a[j]%num[k]);k++);\n            if (k>c)\n               break;\n         }\n      if (j>26)\n         ans=(ans+mat[0][i])%mod;\n   }\n   printf(\"%d\\n\",ans);\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4dd2ec5f04710b7509b69e89b0e16153", "src_uid": "76d4684d26dac380713a566a1e277c91", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n/*thanks  to rainboy,danger :)*/\nint main() {\n\tlong long u, v, w;\n\n\tscanf(\"%lld%lld\", &u, &v);\n\tif (u > v || (v - u) % 2 != 0) {\n\t\tprintf(\"-1\\n\");\n\t\treturn 0;\n\t}\n\tif (u == 0 && v == 0) {\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\tif (u == v) {\n\t\tprintf(\"1\\n\");\n\t\tprintf(\"%lld\\n\", u);\n\t\treturn 0;\n\t}\n\tw = (v - u) / 2;\n\tif ((u & w) == 0) {\n\t\tprintf(\"2\\n\");\n\t\tprintf(\"%lld %lld\\n\", w, u ^ w);\n\t\treturn 0;\n\t}\n\tprintf(\"3\\n\");\n\tprintf(\"%lld %lld %lld\\n\", u, w, w);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cfecfc253c910f790f9dc37055e32ff9", "src_uid": "490f23ced6c43f9e12f1bcbecbb14904", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n \nint main(){\n\tlong long u, v, c, s;\n\tlong long a[60];\n\tint i, j = 0;\n\tscanf(\"%lld%lld\", &u, &v);\n\t/*c = 1;\n \twhile(u / c > 0){\n\t\tif((u & c) == c){\n\t\t\ta[j++] = c;\n\t\t}\n\t\tc = c << 1;\n\t}\n\tif(v < u){\n\t\tprintf(\"-1\\n\", -1);\n\t\treturn 0;\n\t}\n\tprintf(\"%lld\\n\", v - u + j);\n\tfor(i = 0; i < v - u; i++){\n\t\tprintf(\"1 \");\n\t}\n\tfor(i = 0; i < j; i++){\n\t\tprintf(\"%lld \", a[i]);\n\t}\n\tprintf(\"\\n\");*/\n\ts = (v - u) / 2;\n\tif(u > v || (v - u) % 2 == 1){\n\t\tprintf(\"-1\\n\");\n\t}\n\telse if(u == v){\n\t\tif(u == 0 || v == 0)\n\t\t\tprintf(\"0\\n\");\n\t\telse{\n\t\t\tprintf(\"1\\n\");\n\t\t\tprintf(\"%lld\", u);\n\t\t}\n\t}\n\telse if((u & s) == 0){\n\t\tprintf(\"2\\n\");\n\t\tprintf(\"%lld %lld\\n\", u + s, s);\n\t}\n\telse{\n\t\tprintf(\"3\\n\");\n\t\tprintf(\"%lld %lld %lld\\n\", u, s, s);\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "07a6478c052362f9f0616d3002e94cb6", "src_uid": "490f23ced6c43f9e12f1bcbecbb14904", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n\tlong long int u, v;\n\tscanf(\"%lld %lld\", &u, &v);\n\tif (u > v)\n\t{\n\t\tprintf(\"-1\\n\");\n\t\treturn 0;\n\t}\n\tif ((v - u) % 2 > 0)\n\t{\n\t\tprintf(\"-1\\n\");\n\t\treturn 0;\n\t}\n\tif (v == 0)\n\t{\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\tif (u == v)\n\t{\n\t\tprintf(\"1\\n%lld\\n\", u);\n\t\treturn 0;\n\t}\n\tif ((u ^ ((v - u) / 2)) == u + (v - u) / 2)\n\t\tprintf(\"2\\n%lld %lld\\n\", u ^ (v - u) / 2, (v - u) / 2);\n\telse\n\t\tprintf(\"3\\n%lld %lld %lld\\n\", u, (v - u) / 2, (v - u) / 2);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "05e5a4fae68a8ed3e4033a2d4ac364ff", "src_uid": "490f23ced6c43f9e12f1bcbecbb14904", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    int n,m;\n    while(~scanf(\"%d%d\",&n,&m))\n    {\n        if(n>m)\n        {\n            printf(\"-1\\n\");\n            continue;\n        }\n        else if(n==m)\n        {\n            printf(\"%d\\n\",n);\n            continue;\n        }\n        else\n        {\n            if((m-n)%2!=0)\n                printf(\"-1\\n\");\n            else\n            printf(\"%d %d %d\\n\",n,(m-n)/2,(m-n)/2);\n        }\n    }\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "796640c5f9758556516dbc6c1e45b18d", "src_uid": "490f23ced6c43f9e12f1bcbecbb14904", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nlong long num[70]={0};\nlong long num1[70]={0};\nlong long change(long long n)\n{\n    long long i=0;\n    while(n)\n    {\n        num[i++]=n%2;\n        n=n/2;\n    }\n    return 0;\n}\nint main()\n{\n    long long n=0,m=0,ans=,max=0;\n    scanf(\"%lld%lld\",&n,&m);\n    change(n);\n    for(long long i=0;i<=69;i++)\n    {\n        num1[i]=num[i];\n    }\n    if(m<n||(m-n)%2==1) printf(\"-1\\n\");\n    else\n    {\n        if(n==m)\n        {\n            if(n==0) printf(\"0\\n\");\n            else printf(\"1\\n%lld\\n\",n);\n        }\n        else\n        {\n            num[0]=num[0]+m-n;\n            for(long long i=0;i<=68;i++)//\u6ee1\u56db\u8fdb\u4e8c\n            {\n                long long xx=(num[i]-num1[i])/4;\n                num[i]=num[i]-4*xx;\n                num[i+1]=num[i+1]+2*xx;\n            }\n            for(long long i=0;i<=69;i++)\n            {\n                if(num[i]>max) max=num[i];\n            }\n            printf(\"%lld\\n\",max);\n            for(long long i=1,j=0,x=0;i<=max;i++)\n            {\n                for(j=0,x=1,ans=0;j<=69;j++,x=2*x)\n                {\n                    if(num[j]>=1)\n                    {\n                        ans=ans+x;\n                        num[j]--;\n                    }\n                }\n                if(i==1) printf(\"%lld\",ans);\n                else printf(\" %lld\",ans);\n            }\n            printf(\"\\n\");\n        }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "8e2d356b224def4987ddf011e67af4c3", "src_uid": "490f23ced6c43f9e12f1bcbecbb14904", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define maxn 10001\n\nconst int mod = (int) 1e9 + 7;\n\nlong long choose[maxn][maxn];\n\nlong long f[maxn][maxn];\nlong long g[maxn][maxn];\n\nlong long power( long long a, long long b ) {\n\tlong long ret = 1;\n\t\n\ta %= mod;\n\twhile( b > 0 ) {\n\t\tif( b % 2 ) {\n\t\t\tret = (ret * a) % mod;\n\t\t}\n\t\t\n\t\tb /= 2;\n\t\ta = (a * a) % mod;\n\t}\n\t\n\treturn ret;\n}\n\nint main( void ) {\n\tlong long n, m, k;\n\tscanf(\"%lld %lld %lld\", &n, &m, &k);\n\t\n\tfor( int i = 0; i < maxn; i++ ) {\n\t\tchoose[i][0] = choose[i][i] = 1;\n\t\tfor( int j = 1; j < i; j++ ) {\n\t\t\tchoose[i][j] = (choose[i-1][j] + choose[i-1][j-1]) % mod;\n\t\t}\n\t}\n\t\n\tfor( int i = 1; i <= n; i++ ) {\n\t\tfor( int c = 0; c <= n; c++ ) {\n\t\t\tlong long count = (m / n) + (m % n >= i ? 1 : 0);\n\t\t\tg[i][c] = power(choose[n][c], count);\n\t\t}\n\t}\n\t\n\tf[1][0] = 1;\n\tfor( int i = 1; i <= n; i++ ) {\n\t\tfor( int j = 0; j <= k; j++ ) if( f[i][j] > 0 ) {\n\t\t\tfor( int c = 0; c <= n; c++ ) {\n\t\t\t\tif( j + c > k ) break;\n\t\t\t\tlong long nways = (g[i][c] * f[i][j]) % mod;\n\t\t\t\tf[i+1][j+c] = (f[i+1][j+c] + nways) % mod;\n\t\t\t}\n\t\t}\n\t}\n\t\n\tprintf(\"%lld\\n\", f[n+1][k]);\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "3812e0a974c9a10820cde8bce8eb2de5", "src_uid": "9c71c8e031412e2bb21266a53821626a", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define mod 1000000007\nlong long f[200][200],dp[101][10001];\nlong long calc_pow(long long base , long long power)\n{\n    if(power == 0) return 1;\n\n    long long half = calc_pow(base , power/2);\n\n    if(power % 2)\n        return ((half * half) % mod * base) % mod;\n\n    return (half * half) % mod;\n}\nmain()\n{\n    long long n,m,i,j,k,s;\n    scanf(\"%I64d%I64d%I64d\",&n,&m,&s);\n\n    for(i=0; i<=100; i++)\n        f[i][0] = 1;\n\n    for(i=1; i<=100; i++)\n        for(j=1; j<=i; j++)\n            f[i][j] = (f[i-1][j] + f[i-1][j-1]) % mod ;\n\n    long long pow[200][200];\n\n    for(i=1; i<=n; i++)\n        for(j=0; j<=n; j++)\n            pow[i][j] = calc_pow(f[n][j] , (m-i)/n+1);\n\n    for(i=0; i<=n; i++)dp[n][i] = pow[n][i];\n\n    for(i=n-1; i>=1; i--)\n    {\n        for(j=0; j<=(n-i+1)*n ; j++)\n        {\n          for(k=0; k<=n; k++)\n          {\n              if(j - k <= (n-i)*n)\n                dp[i][j] = (dp[i][j] + (pow[i][k] * dp[i+1][j-k] ) % mod )% mod;\n          }\n        }\n    }\n\n    printf(\"%I64d\",dp[1][s]);\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cb9db463fac8f19550c4479d67c75665", "src_uid": "9c71c8e031412e2bb21266a53821626a", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long pow(long long x, long long y, long long z)\n{\n    long long p = 1;\n    \n    while (y) {\n        if (y & 1) p = p * x % z;\n        \n        x = x * x % z;\n        y >>= 1;\n    }\n    \n    return p;\n}\n\nint max(int a, int b)\n{\n    if (a > b) {\n        return a;\n    } else {\n        return b;\n    }\n}\n\nlong long c[101][101];\nlong long a[101];\nlong long dp[101][10001];\n\nint main()\n{\n    int n, k, mod = 1000000007, i, j, l;\n    long long m;\n    \n    scanf(\"%d %I64d %d\", &n, &m, &k);\n    \n    for (i = 0; i <= 100; i++) {\n        c[i][0] = c[i][i] = 1;\n        \n        for (j = 1; j < i; j++) c[i][j] = (c[i - 1][j] + c[i - 1][j - 1]) % mod;\n    }\n    \n    for (i = 0; i <= n; i++) a[i] = pow(c[n][i], m / n, mod);\n    \n    dp[0][0] = 1;\n    \n    for (i = 0; i < n; i++) {\n        for (j = max(0, k - (n - i) * n); j <= i * n && j <= k; j++) {\n            if (dp[i][j] == 0) continue;\n            \n            for (l = 0; l <= n && j + l <= k; l++) {\n                long long x = a[l];\n                \n                if (m % n > i) x = x * c[n][l] % mod;\n                \n                dp[i + 1][j + l] = (dp[i + 1][j + l] + dp[i][j] * x % mod) % mod;\n            }\n        }\n    }\n    \n    printf(\"%I64d\\n\", dp[n][k]);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "04b75e8f35191dc631bd95fb546e2a6c", "src_uid": "9c71c8e031412e2bb21266a53821626a", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define maxn 111\n\nconst int mod = (int) 1e9 + 7;\n\nlong long choose[maxn][maxn];\n\nlong long f[maxn][10001];\nlong long g[maxn][maxn];\n\nlong long power( long long a, long long b ) {\n\tlong long ret = 1;\n\t\n\ta %= mod;\n\twhile( b > 0 ) {\n\t\tif( b % 2 ) {\n\t\t\tret = (ret * a) % mod;\n\t\t}\n\t\t\n\t\tb /= 2;\n\t\ta = (a * a) % mod;\n\t}\n\t\n\treturn ret;\n}\n\nint main( void ) {\n\tlong long n, m, k;\n\tscanf(\"%lld %lld %lld\", &n, &m, &k);\n\t\n\tfor( int i = 0; i < maxn; i++ ) {\n\t\tchoose[i][0] = choose[i][i] = 1;\n\t\tfor( int j = 1; j < i; j++ ) {\n\t\t\tchoose[i][j] = (choose[i-1][j] + choose[i-1][j-1]) % mod;\n\t\t}\n\t}\n\t\n\tfor( int i = 1; i <= n; i++ ) {\n\t\tfor( int c = 0; c <= n; c++ ) {\n\t\t\tlong long count = (m / n) + (m % n >= i ? 1 : 0);\n\t\t\tg[i][c] = power(choose[n][c], count);\n\t\t}\n\t}\n\t\n\tf[1][0] = 1;\n\tfor( int i = 1; i <= n; i++ ) {\n\t\tfor( int j = 0; j <= k; j++ ) if( f[i][j] > 0 ) {\n\t\t\tfor( int c = 0; c <= n; c++ ) {\n\t\t\t\tif( j + c > k ) break;\n\t\t\t\tlong long nways = (g[i][c] * f[i][j]) % mod;\n\t\t\t\tf[i+1][j+c] = (f[i+1][j+c] + nways) % mod;\n\t\t\t}\n\t\t}\n\t}\n\t\n\tprintf(\"%lld\\n\", f[n+1][k]);\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "450af6cd8521b6e16955d6683bd80062", "src_uid": "9c71c8e031412e2bb21266a53821626a", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MOD 1000000007\n#define min(a, b)  ( ((a) < (b)) ? (a) : (b) )\n\nunsigned long long cnk[101][101], pows[101], dp[101][101];\n\nunsigned long long quick_pow(unsigned long long a, unsigned long long n)\n{\n    if (n == 0) {\n        return 1;\n    } else if ((n & 1ULL) == 0) {\n        unsigned long long tmp = quick_pow(a, n / 2ULL);\n        return (tmp * tmp) % MOD;\n    } else {\n        return (quick_pow(a, n - 1) * a) % MOD;\n    }\n}\n\nint\nmain(void)\n{\n    int n, k;\n    unsigned long long m;\n    scanf(\"%d%I64u%d\", &n, &m, &k);\n    cnk[0][0] = 1;\n\n    int i, j, t;\n    for(i = 1; i < 101; ++i){\n        cnk[i][0] = 1;\n        for(j = 1; j < 101; ++j){\n            cnk[i][j] = (cnk[i - 1][j] + cnk[i - 1][j - 1]) % MOD;\n        }\n    }\n\n    unsigned long long rem =  m % n;\n    for (i = 1; i <= n; ++i) {\n        if (rem) {\n            pows[i] = m / n + 1;\n            --rem;\n        } else {\n            pows[i] = m / n;\n        }\n    }\n\n    dp[0][0] = 1;\n    for (i = 1; i <= n; ++i) {\n        for (j = 0; j <= min(k, i * n); ++j) {\n            for (t = 0; t <= min(n, j); ++t) {\n                unsigned long long tmp = quick_pow(cnk[n][t], pows[i]),\n                                   tmp2 = (dp[i - 1][j - t] * tmp) % MOD;\n                dp[i][j] = (dp[i][j] + tmp2) % MOD;\n            }\n        }\n    }\n\n    printf(\"%I64u\", dp[n][k]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9ca8bba85abd3d070560b2f1617b40c0", "src_uid": "9c71c8e031412e2bb21266a53821626a", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#ifndef _TJYTLXWXHYZQFW_COMMON_H\n#define _TJYTLXWXHYZQFW_COMMON_H\n#include <assert.h>\n#include <limits.h>\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#define offset(t,m) ((unsigned long)&(((t*)0)->m))\n#define container_of(a,t,m) ((t*)((unsigned long)a-offset(t,m)))\n#define ULL1 ((unsigned long long )1)\n#define LL(x) ((long long)(x))\n#define SWP(a, b) if ((a) != (b)) do {(a) ^= (b); (b) ^= (a); (a) ^= (b);} while(0)\n#define IOF(p) ((p) = ((p) < 0 ? INT_MAX : (p)))\n#define LLOF(p) ((p) = ((p) < 0 ? LLONG_MAX :(p)))\n#define ir(x, start, end) ((x) >= (start) && (x) < (end))\n#define ire(x, start, end) ((x) >= (start) && (x) <= (end))\n#define max(x,y) ((x) < (y) ? (y) : (x))\n#define min(x, y) ((x) < (y) ? (x) : (y))\n#define abv(x) ((x) < 0 ? (x) * (-1) : (x))\n#define forn(i, n) for ((i) = 0; (i) < (n); (i) += 1)\n#define fore(i, n) for ((i) = 0; (i) <= (n); (i) += 1)\n#define forr(i, s, e) for((i) = (s); (i) < (e); (i) += 1)\n#define forre(i, s, e) for((i) = (s); (i) <= (e); (i) += 1)\n#endif\n#ifndef _WCC_NUMTH_H\n#define _WCC_NUMTH_H\n#include <assert.h>\n#define NUMTH_ENS (-1) \n#define NUMTH_MODPLS(x, y, p) ((((x) % (p)) + ((y) % (p))) % p)\n#define NUMTH_MODMUL(x, y, p) ((((X) % (P)) * ((y) % (p))) % p)\n#define NUMTH_CORRECT(x, mod) ((x) += ((x) < 0 ? (mod) : 0))\nlong long numth_modexp(long long a, long long b, long long n);\nlong long numth_gcd(long long a, long long b);\nvoid numth_gcd_e(long long a, long long b, long long *d, long long *x, long long *y);\nint numth_mle(long long a, long long b, long long n, long long *x, long long *gcd);\n#define numth_for_each_solution(i, x, n, d) \\\n\tfor ((i) = 0; (i) < (d); (i) += 1, (x) = ((x) + (n) / (d)) % (n))\nint numth_divisors(long long k, long long divs[], long long *ndivs);\n#endif\n#define M 1000000007\n#define T 100\n#define K 1000\n#define pls(a, b) NUMTH_MODPLS((a), (b), M)\nint dp[2*T][4*T*K+1];\nint a, b, t, k;\nint delta, delta_min, delta_max, offset, index_max;\nint dp_fill(int i, int j)\n{\n\tint x;\n\tif (j == index_max-k) {\n\t\tdp[i][j] = 0;\n\t\tforre(x, j-k, j+k) dp[i][j] = pls(dp[i][j], dp[i+1][x]);\n\t} else {\n\t\tdp[i][j] = pls(pls(dp[i+1][j-k], dp[i][j+1]), -1*dp[i+1][j+k+1]);\n\t\tNUMTH_CORRECT(dp[i][j], M);\n\t}\n\treturn dp[i][j];\n}\nint main(void)\n{\n\tint i, j;\n\tscanf(\"%d%d%d%d\", &a, &b, &k, &t);\n\tt <<= 1;\n\tdelta = a - b;\n\tdelta_min = delta - t * k;\n\tdelta_max = delta + t * k;\n\toffset = -1 * delta_min;\n\tindex_max = delta_max + offset;\n\tforre(i, 0, index_max) dp[t-1][i] = max(0, k-max(-1*k, offset-i+1)+1);\n\tfor (i = t-2; i >= 0; --i)\n\t\tfor (j = index_max-k; j >= k; --j)\n\t\t\tdp_fill(i, j);\n\tprintf(\"%d\\n\", dp[0][delta+offset]);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "2a8975f0ef5fbfa2bfda72d0b8e89d4e", "src_uid": "8b8327512a318a5b5afd531ff7223bd0", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint sol(int n){\n    int dp[n+1];\n    dp[1]=1;\n    dp[2]=3;\n    dp[3]=6;\n    for(int i=4;i<=n;i++){\n        dp[i]=dp[i-1]+i+pow(2,i-4);\n    }\n    return dp[n];\n}\nint main(){\n    int n;\n    scanf(\"%d\",&n);\n    printf(\"%d\\n\",sol(n));\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "97621459a9a0a7554236ea899878132b", "src_uid": "5c4bd12df3915186a7b506c2060db125", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define big 1000000007\nint main()\n{\n\tint n;\n\tscanf(\"%d\",&n);\n\tif(n==1)\n\t{\n\t\tprintf(\"1\\n\");\n\t\treturn 0;\n\t}\n\telse if (n==2)\n\t{\n\t\tprintf(\"3\\n\");\n\t\treturn 0;\n\t}\n\telse\n\t{\n\t\tlong long int a = 1, b = 3 , temp;\n\t\tint i=1; \n\t\tfor( ; i <= n-2 ; i++)\n\t\t{\n\t\t\ttemp = b%big;\n\t\t\tb = (a+b+2)%big;\n\t\t\ta = temp%big;\n\t\t}\n\t\tprintf(\"%I64d\\n\",b);\n\t\treturn 0;\n\t}\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b748991982cea83371ca290527da6f87", "src_uid": "5c4bd12df3915186a7b506c2060db125", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\nint sol(int n){\n    int dp[n+1];\n    dp[1]=1;\n    dp[2]=3;\n    dp[3]=6;\n    for(int i=4;i<=n;i++){\n        dp[i]=(dp[i-1]+dp[i-2]+2)%1000000007;\n    }\n    return dp[n];\n}\nint main(){\n    int n;\n    scanf(\"%d\",&n);\n    printf(\"%d\\n\",sol(n));\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "bb298c97b1fff477007af0ce572d5272", "src_uid": "5c4bd12df3915186a7b506c2060db125", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nlong long int abs(long long int n)\n{\n\tif (n < 0)\n\t\tn *= -1;\n\treturn n;\n}\nint main()\n{\n\tlong long int x0, y0, ax, ay, bx, by;\n\tscanf(\"%lld %lld %lld %lld %lld %lld\", &x0, &y0, &ax, &ay, &bx, &by);\n\tlong long int xs, ys, t;\n\tscanf(\"%lld %lld %lld\", &xs, &ys, &t);\n\tlong long int x[102], y[102];\n\tx[0] = x0;\n\ty[0] = y0;\n\tlong long int i, j;\n\tfor (i = 0; x[i] <= t && y[i] <= t; i++)\n\t{\n\t\tx[i + 1] = ax * x[i] + bx;\n\t\ty[i + 1] = ay * y[i] + by;\n\t}\n\tlong long int c = i + 1;\n\tlong long int ans = 0;\n\tfor (i = 0; i < c; i++)\n\t\tfor (j = 0; j < c; j++)\n\t\t\tif (abs(xs - x[i]) + abs(ys - y[i]) + abs(x[i] - x[j]) + abs(y[i] - y[j]) <= t)\n\t\t\t\tif (ans < abs(i - j) + 1)\n\t\t\t\t\tans = abs(i - j) + 1;\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "62bfa6769b03ec8c64a71b7a2b50b59e", "src_uid": "d8a7ae2959b3781a8a4566a2f75a4e28", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\ntypedef long long LL;\ntypedef struct{\n\tLL x, y;\n\tLL dist[100];\n} Datanode;\n\nDatanode nodes[100];\n\nLL aabs(LL a){return a<0?-a:a;}\nLL min(LL a, LL b){return a<b?a:b;}\nLL max(LL a, LL b){return a>b?a:b;}\n\nLL manh(Datanode * a, Datanode * b){\n\treturn aabs(a->x-b->x)+aabs(a->y-b->y);\n}\n\nint main(){\n\tLL a[2], b[2], t;\n\tDatanode s;\n\tint i, j, n, best=0;\n\tscanf(\"%I64d %I64d %I64d %I64d %I64d %I64d %I64d %I64d %I64d\", &nodes[0].x, &nodes[0].y,\n\t\t\ta, a+1, b, b+1, &s.x, &s.y, &t);\n\tfor(i=1;manh(&s, nodes+i-1)>=t && nodes[i-1].x<100000000000000000LL &&\n\t\t\tnodes[i-1].y<100000000000000000LL;++i){\n\t\tnodes[i].x=nodes[i-1].x*a[0]+b[0];\n\t\tnodes[i].y=nodes[i-1].y*a[1]+b[1];\n\t\tfor(j=0;j<i;++j){\n\t\t\tnodes[i].dist[j]=manh(nodes+i, nodes+j);\n\t\t\tnodes[j].dist[i]=manh(nodes+i, nodes+j);\n\t\t}\n\t}\n\tfor(;manh(&s, nodes+i-1)<=t && nodes[i-1].x<100000000000000000LL &&\n\t\t\tnodes[i-1].y<100000000000000000LL;++i){\n\t\tnodes[i].x=nodes[i-1].x*a[0]+b[0];\n\t\tnodes[i].y=nodes[i-1].y*a[1]+b[1];\n\t\tfor(j=0;j<i;++j){\n\t\t\tnodes[i].dist[j]=manh(nodes+i, nodes+j);\n\t\t\tnodes[j].dist[i]=manh(nodes+i, nodes+j);\n\t\t}\n\t}\n\tn=i;\n\tfor(i=0;i<n;++i) for(j=i+1;j<n;++j)\n\t\t\tif(nodes[i].dist[j]+min(manh(nodes+i, &s), manh(nodes+j, &s))<=t)\n\t\t\t\tbest=max(best, j-i+1);\n\tprintf(\"%d\\n\", best);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e286c0d7824c6af0776db044830143ce", "src_uid": "d8a7ae2959b3781a8a4566a2f75a4e28", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nlong long int abs(long long int n)\n{\n\tif (n < 0)\n\t\tn *= -1;\n\treturn n;\n}\nint main()\n{\n\tlong long int x0, y0, ax, ay, bx, by;\n\tscanf(\"%lld %lld %lld %lld %lld %lld\", &x0, &y0, &ax, &ay, &bx, &by);\n\tlong long int xs, ys, t;\n\tscanf(\"%lld %lld %lld\", &xs, &ys, &t);\n\tlong long int max = 10000000000000016;\n\tlong long int x[102], y[102];\n\tx[0] = x0;\n\ty[0] = y0;\n\tlong long int i, j;\n\tfor (i = 0; x[i] < max && y[i] < max; i++)\n\t{\n\t\tx[i + 1] = ax * x[i] + bx;\n\t\ty[i + 1] = ay * y[i] + by;\n\t}\n\tlong long int c = i;\n\tlong long int ans = 0;\n\tfor (i = 0; i < c; i++)\n\t\tfor (j = 0; j < c; j++)\n\t\t\tif (abs(xs - x[i]) + abs(ys - y[i]) + abs(x[i] - x[j]) + abs(y[i] - y[j]) <= t)\n\t\t\t\tif (ans < abs(i - j) + 1)\n\t\t\t\t\tans = abs(i - j) + 1;\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5ad55325460ddcd640abad23f1914ba3", "src_uid": "d8a7ae2959b3781a8a4566a2f75a4e28", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\ntypedef long long LL;\ntypedef struct{\n\tLL x, y;\n\tLL dist[100];\n} Datanode;\n\nDatanode nodes[100];\n\nLL aabs(LL a){return a<0?-a:a;}\nLL min(LL a, LL b){return a<b?a:b;}\nLL max(LL a, LL b){return a>b?a:b;}\n\nLL manh(Datanode * a, Datanode * b){\n\treturn aabs(a->x-b->x)+aabs(a->y-b->y);\n}\n\nint main(){\n\tLL a[2], b[2], t;\n\tDatanode s;\n\tint i, j, n, best=0;\n\tscanf(\"%I64d %I64d %I64d %I64d %I64d %I64d %I64d %I64d %I64d\", &nodes[0].x, &nodes[0].y,\n\t\t\ta, a+1, b, b+1, &s.x, &s.y, &t);\n\tfor(i=1;manh(&s, nodes+i-1)>=t && nodes[i-1].x<100000000000000000LL &&\n\t\t\tnodes[i-1].y<100000000000000000LL;++i){\n\t\tnodes[i].x=nodes[i-1].x*a[0]+b[0];\n\t\tnodes[i].y=nodes[i-1].y*a[1]+b[1];\n\t\tfor(j=0;j<i;++j){\n\t\t\tnodes[i].dist[j]=manh(nodes+i, nodes+j);\n\t\t\tnodes[j].dist[i]=manh(nodes+i, nodes+j);\n\t\t}\n\t}\n\tfor(;manh(&s, nodes+i-1)<=t && nodes[i-1].x<100000000000000000LL &&\n\t\t\tnodes[i-1].y<100000000000000000LL;++i){\n\t\tnodes[i].x=nodes[i-1].x*a[0]+b[0];\n\t\tnodes[i].y=nodes[i-1].y*a[1]+b[1];\n\t\tfor(j=0;j<i;++j){\n\t\t\tnodes[i].dist[j]=manh(nodes+i, nodes+j);\n\t\t\tnodes[j].dist[i]=manh(nodes+i, nodes+j);\n\t\t}\n\t}\n\tn=i;\n\tfor(i=0;i<n;++i) for(j=i;j<n;++j)\n\t\t\tif(nodes[i].dist[j]+min(manh(nodes+i, &s), manh(nodes+j, &s))<=t)\n\t\t\t\tbest=max(best, j-i+1);\n\tprintf(\"%d\\n\", best);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "910bbd33b185b727c75290967dd8be42", "src_uid": "d8a7ae2959b3781a8a4566a2f75a4e28", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <bits/stdc++.h>\nusing namespace std;\n    \n#define ll long long\n\nlong long aa = (long long)1e16;\n\nint main() {\n    ll x0, y0, ax, bx, by, ay;\n    ll xs, ys, t;\n    cin >> x0 >> y0 >> ax >> ay >> bx >> by;\n    cin >> xs >> ys >> t;\n    vector<pair<ll, ll>> arr;\n    int counter = 1;\n    arr.push_back(make_pair(x0, y0));\n    while(arr[counter - 1].first < aa && arr[counter - 1].second < aa) {\n        arr.push_back(make_pair(ax * arr[counter - 1].first + bx, ay * arr[counter - 1].second + by));\n        counter++;\n    }\n    // sort(arr.begin(), arr.end());\n    bool a[arr.size()];\n    ll myMin = aa;\n    int index = -1;\n    for(int i = 0; i < arr.size(); i++) {\n        ll temp = abs(arr[i].first - xs) + abs(arr[i].second - ys);\n        if(temp < myMin) {\n            index = i;\n            myMin = temp;\n        }\n    }\n    t -= abs(arr[index].first - xs) + abs(arr[index].second - ys);\n    if(t < 0) {\n        cout << 0;\n        return 0;\n    }\n    xs = arr[index].first;\n    ys = arr[index].second;\n    int ct = 1;\n    for(int i = 0; i < arr.size(); i++) {\n        a[i] = false;\n    }\n    a[index] = true;\n    while(t > 0 && ct <= arr.size()) {\n        myMin = aa;\n        for(int i = 0; i < arr.size(); i++) {\n            if(!a[i]) {\n                ll temp = abs(arr[i].first - xs) + abs(arr[i].second - ys);\n                if(temp < myMin) {\n                    index = i;\n                    myMin = temp;\n                }\n            }\n        }\n        a[index] = true;\n        ct++;\n        t -= abs(arr[index].first - xs) + abs(arr[index].second - ys);\n        xs = arr[index].first;\n        ys = arr[index].second;\n    }\n    cout << ct;\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "1d9da52e91f5db3d3a4a74838d4ef2c0", "src_uid": "d8a7ae2959b3781a8a4566a2f75a4e28", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(void)\n{\n    int n;\n    \n    scanf(\"%d\",&n);\n    \n    int tmp;\n    int pie[n];\n    for(int i=0;i<n;i++){\n        scanf(\"%d\",&pie[i]);\n    }\n    if(n == 1){\n        printf(\"0 %d\",pie[0]);\n        return 0;\n    }\n    int x=pie[n-1];\n    int y=pie[n-2];\n    if(x<y)\n    {\n        tmp = x;\n        x = y;\n        y = tmp;\n    }\n    for(int j=n-3;j>=0;j--){\n        y+=pie[j];\n        if(x<y)\n        {\n            tmp = x;\n            x = y;\n            y = tmp;\n        }\n    }\n    printf(\"%d %d\",y,x);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e6dacbd25951a4abb079f596304af3c3", "src_uid": "414540223db9d4cfcec6a973179a0216", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint max(int a,int b)\n{\nif(a>=b)return a;\nelse return b;\n}\nint main()\n{\nint ca[52];\nint n;scanf(\"%d\",&n);\nint sumi[52];\nint sum=0;\nint dp[52]={-1};\n\nint i=0;\nfor(i=0;i<n;i++)\n{\nscanf(\"%d\",&ca[i]);\nsum += ca[i];\nsumi[i] = sum;\n}\ndp[n-1]=ca[n-1];\n\nfor(i=n-2;i>=0;i--)\n{\ndp[i]=max((ca[i]+(sumi[n-1]-dp[i+1]-sumi[i])),dp[i+1]);\n\n\n}\n\nint ans = dp[0];\nint ans1 = sumi[n-1]-dp[0];\n\nprintf(\"%d %d\\n\",ans1,ans);\n\n\n\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cefcebf3a112b47a07aaf0cab9a09629", "src_uid": "414540223db9d4cfcec6a973179a0216", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "//Date:16-09-17\n\n#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<stdbool.h>\n#include<float.h>\n#include<math.h>\n#include<inttypes.h>\n#include<assert.h>\n#include<ctype.h>\n#include<limits.h>\n#include<time.h>\n#define ll long long\n#define For(i,n)\tfor(i=0;i<n;i++)\n#define rep(i ,a ,b)\tfor(i=(a);i<=(b);i++)\n#define mset(a ,value)\tmemset(a ,value ,sizeof(a))\n#define s(a)\tscanf(\"%d\" ,&a);\n#define ls(a)\tscanf(\"%ld\" ,&a)\n#define reg(i)\tregister int i\n#define infinite INT_MAX\n#define MAX 101\n#define NIL -1\n#define and &&\nint min(int a,int b){\treturn (a<b?a:b);\t}\nint max(int a,int b){\treturn (a>b?a:b);\t}\nint gcd(int a ,int b){\n\tif(a==0)\treturn b;\n\treturn gcd(b%a ,a);\n}\nint a[51] ,n;\nint cmp(const void *a,const void *b) {\n\tint *a1 = (int *)a;\n\tint *b1 = (int *)b;\n\treturn (*a1) > (*b1);\n}\nint f[51][2];\nint F(int i ,int d) {\n\t//printf(\"%d \" ,d);\n\tif(i == n-1) {\n\t\tif(d == 0)\treturn f[i][d] = a[i];\n\t\telse return f[i][d] = 0;\n\t}\n\tif(f[i][d] != -1)\treturn f[i][d];\n\tif(d == 0) \n\t\tf[i][d] = max(a[i] + F(i+1 ,1) ,F(i+1 ,0));\n\telse \n\t\tf[i][d] = min(F(i+1 ,0), a[i] + F(i+1 ,1));\n\treturn f[i][d];\n}\nint main() {\n\tint i ,j;\n\ts(n);\n\tint sum = 0;\n\tFor(i ,n){\ts(a[i]);\tsum += a[i];\t}\n\tmset(f ,-1);\n\t//For(i ,n)\tprintf(\"%d \" ,f[i]);\tprintf(\"\\n\");\n\tint bob = F(0 ,0);\n\t//For(i ,n) \tprintf(\"%d %d\\n\" ,f[i][0] ,f[i][1]);\t\n\tprintf(\"%d %d\" ,sum - bob ,bob);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "abbf5080844fd9193f94f882c27213a6", "src_uid": "414540223db9d4cfcec6a973179a0216", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n\nint gcd(int a,int b)\n{\n\tif(b==0)\n\t\treturn a;\n\tgcd(b,a%b);\n}\n\nint max(int a,int b)\n{\n\tif(a>b)\n\t\treturn a;\n\telse\n\t\treturn b;\n}\nint main()\n{\n\tint n,i,j;\n\tscanf(\"%d\",&n);\n\tint a[100];\n\tfor(i=1;i<=n;i++)\n\t\tscanf(\"%d\",&a[i]);\n\tint dp[100][2]={0};\n\tdp[n][1]=a[n];\n\tdp[n][0]=0;\n\tfor(i=n-1;i>=1;i--)\n\t{\n\t\tif(dp[i+1][1]>=a[i]+dp[i+1][0])\n\t\t{\n\t\t\tdp[i][1]=dp[i+1][1];\n\t\t\tdp[i][0]=dp[i+1][0]+a[i];\n\t\t}\n\t\telse\n\t\t{\n\t\t\tdp[i][1]=a[i]+dp[i+1][0];\n\t\t\tdp[i][0]=dp[i+1][1];\n\t\t}\n\t}\n\tprintf(\"%d %d\\n\",dp[1][0],dp[1][1]);\n\treturn 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2403057d58efff58188417026706f235", "src_uid": "414540223db9d4cfcec6a973179a0216", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint mini(int a, int b)\n{\nif(a<=b)return a;\nreturn b;\n}\nint maxi(int a, int b)\n{\nif(a>=b)return a;\nreturn b;\n}\nint sum[55];\nint fir[55];\nint a[55];\nint main()\n{\nint n;\nscanf(\"%d\",&n);\nint i;\nfor(i=1;i<=n;i++)\nscanf(\"%d\",&a[i]);\n\nfor(i=n;i>=1;i--)\n{\nfir[i] = maxi(a[i]+sum[i+1]-fir[i+1],fir[i+1]);\nsum[i] =sum[i+1] +  a[i];\n\n}\nprintf(\"%d %d\\n\",sum[1]-fir[1],fir[1]);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "40decb368ea211dcc761a63f0a25873f", "src_uid": "414540223db9d4cfcec6a973179a0216", "difficulty": 1500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <assert.h>\n\nint n;\n\ndouble p(double a, double e) {\n    return a / e;\n}\ndouble q(double a, double b, double c, double d, double e, double f) {\n    return (a / d) * (b / e) * (c / f);\n}\n\ndouble solve(int k) {\n    const double q3 = q(k, k-1, k-2, n, n-1, n-2);\n    const double q0 = q(n-k, n-k-1, n-k-2, n, n-1, n-2);\n    const double q1 = 2 * q(k, n-k, n-k-1, n, n-1, n-2);\n    const double q2 = q(k, k-1, n-k, n, n-1, n-2);\n    assert(q3 + q0 + 3 / 2. * q1 + 3 * q2 == 1.);\n    const double res = q3 + q1 + q2;\n    //printf(\"solve(%d) = %lf\\n\", k, res);\n    assert(res >= 0.);\n    assert(res <= 1.);\n    return res;\n}\n\nint main(void) {\n    double p;\n    scanf(\"%d%lf\", &n, &p);\n    int l = 0, r = n - 1;\n    if (p == 0) {\n        puts(\"0\");\n        return 0;\n    }\n    while (l + 1 < r) {\n        const int m = (l + r) >> 1;\n        if (solve(m) >= p) {\n            r = m;\n        } else {\n            l = m;\n        }\n    }\n    assert(r > 0);\n    assert(r < n);\n    printf(\"%d\\n\", r);\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5183d0b765797ad23da303ed540f6ce1", "src_uid": "788ed59a964264bd0e755e155a37e14d", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <assert.h>\n\nint n;\n\ndouble p(double a, double e) {\n    return a / e;\n}\ndouble q(double a, double b, double c, double d, double e, double f) {\n    return (a / d) * (b / e) * (c / f);\n}\n\ndouble solve(int k) {\n    const double q3 = q(k, k-1, k-2, n, n-1, n-2);\n    const double p3 = p(k-2, n-2);\n    const double q0 = q(n-k, n-k-1, n-k-2, n, n-1, n-2);\n    const double p0 = p(k, n-2);\n    const double q11 = q(k, n-k, n-k-1, n, n-1, n-2);\n    const double p11 = p(k-1, n-2);\n    const double q10 = 2 * q11;\n    const double p10 = p(k, n-2);\n    const double q20 = q(k, k-1, n-k, n, n-1, n-2);\n    const double p20 = p(k, n-2);\n    const double q21 = 2 * q21;\n    const double p21 = p(k-1, n-2);\n    const double res = q3 * p3 + q0 * p0 +\n        q11 * p11 + q10 * p10 + q20 * p20 + q21 * p21;\n    assert(res >= 0.);\n    assert(res <= 1.);\n    return res;\n}\n\nint main(void) {\n    double p;\n    scanf(\"%d%lf\", &n, &p);\n    int l = 0, r = n - 1;\n    if (p == 0) {\n        puts(\"0\");\n        return 0;\n    }\n    while (l + 1 < r) {\n        const int m = (l + r) >> 1;\n        if (solve(m) >= p) {\n            r = m;\n        } else {\n            l = m;\n        }\n    }\n    assert(r > 0);\n    assert(r < n);\n    printf(\"%d\\n\", r);\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "29f03c8f0b7e704b1e4972b5cd2c5480", "src_uid": "788ed59a964264bd0e755e155a37e14d", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <assert.h>\n\nint n;\n\ndouble p(double a, double e) {\n    return a / e;\n}\ndouble q(double a, double b, double c, double d, double e, double f) {\n    return (a / d) * (b / e) * (c / f);\n}\n\ndouble solve(int k) {\n    const double q3 = q(k, k-1, k-2, n, n-1, n-2);\n    const double q0 = q(n-k, n-k-1, n-k-2, n, n-1, n-2);\n    const double q1 = 3 / 2. * q(k, n-k, n-k-1, n, n-1, n-2);\n    const double q2 = 3 * q(k, k-1, n-k, n, n-1, n-2);\n    const double res = q3 + q1 + q2;\n    //printf(\"solve(%d) = %lf\\n\", k, res);\n    //assert(q3 + q0 + 3 / 2. * q1 + 3 * q2 == 1.);\n    assert(res >= 0.);\n    assert(res <= 1.);\n    return res;\n}\n\nint main(void) {\n    double p;\n    scanf(\"%d%lf\", &n, &p);\n    int l = 0, r = n - 1;\n    if (p == 0) {\n        puts(\"0\");\n        return 0;\n    }\n    while (l + 1 < r) {\n        const int m = (l + r) >> 1;\n        if (solve(m) >= p) {\n            r = m;\n        } else {\n            l = m;\n        }\n    }\n    assert(r > 0);\n    assert(r < n);\n    printf(\"%d\\n\", r);\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "98a1d53539757275a10e141fff09136f", "src_uid": "788ed59a964264bd0e755e155a37e14d", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nvoid buble_sort(int a[], int n)\n{\n    int i, j, t;\n    for(i=0; i<n; i++)\n    {\n        for(j=0; j<n-1; j++)\n        {\n            if(a[j]>a[j+1])\n            {\n                t=a[j];\n                a[j]=a[j+1];\n                a[j+1]=t;\n            }\n        }\n    }\n}\nint main()\n{\n    int n, l, i, j, xr, yr, xl, xh, yl, yh;\n    scanf(\"%d\", &n);\n    l=(4*n)+1;\n    int x[l];\n    int y[l];\n    int xd[l];\n    int yd[l];\n    for(i=0; i<l; i++)\n    {\n        scanf(\"%d %d\", &x[i], &y[i]);\n        xd[i]=x[i];\n        yd[i]=y[i];\n    }\n    buble_sort(x, l);\n    buble_sort(y,l);\n    if(x[0]==x[1])\n    {\n    \txl=x[0];\n\t}\n\telse if(x[0]!=x[1])\n\t{\n\t\txl=x[1];\n\t}\n\tif(x[l-2]==x[l-1])\n\t{\n\t\txh=x[l-2];\n\t}\n\telse if(x[l-2]!=x[l-1])\n\t{\n\t\txh=x[l-2];\n\t}\n\tif(y[0]==y[1])\n    {\n    \tyl=y[0];\n\t}\n\telse if(y[0]!=y[1])\n\t{\n\t\tyl=y[1];\n\t}\n\tif(y[l-2]==y[l-1])\n\t{\n\t\tyh=y[l-2];\n\t}\n\telse if(y[l-2]!=y[l-1])\n\t{\n\t\tyh=y[l-2];\n\t}\n\tprintf(\"%d %d %d %d\\n\", xl, xh, yl, yh);\n    for(i=0; i<l; i++)\n    {\n    \tif((xd[i]<xl || xd[i]>xh) || (yd[i]<yl || yd[i]>yh))\n    \t{\n    \t   xr=xd[i];\n    \t   yr=yd[i];\n    \t   break;\n        }\n        else if((xd[i]>xl && xd[i]<xh) && (yd[i]>yl && yd[i]<yh))\n    \t{\n    \t   xr=xd[i];\n    \t   yr=yd[i];\n    \t   break;\n        }\n\t}\n    printf(\"%d %d\\n\", xr, yr);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2bd83d995f68813c194df55532dcac33", "src_uid": "1f9153088dcba9383b1a2dbe592e4d06", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<math.h>\n/*#include<string.h>\n#define MOD 1000000009\n#define MAX 100005\nlong long int position_value[MAX];\nvoid init()\n{\n    position_value[0]=1;\n    int i;\n    for(i=1;i<MAX;i++)\n    {\n        position_value[i]=(position_value[i-1]*26)%MOD;\n    }\n}\n#define MAX 200000\nint temp[MAX];\nvoid mergesort(int a[],int indices[],int first,int last)\n{\n    if(first==last) return;\n    int middle=(first+last)/2;\n    mergesort(a,indices,first,middle);\n    mergesort(a,indices,middle+1,last);\n    int i,j,k;\n    for(i=first,j=first,k=middle+1; i<=last; i++)\n    {\n        if(j==middle+1) temp[i]=indices[k++];\n        else if(k==last+1) temp[i]=indices[j++];\n        else if(a[indices[k]]<a[indices[j]]) temp[i]=indices[k++];\n        else temp[i]=indices[j++];\n    }\n    for(i=first; i<=last; i++)\n    {\n        indices[i]=temp[i];\n    }\n}\nvoid noobsort(int a[],int indices[],int first,int last)\n{\n    if(first>=last) return;\n    int i,j,s;\n    for(i=first;i<=last;i++)\n    {\n        for(j=i;j>0&&a[indices[j]]>a[indices[j-1]];j--)\n        {\n            s=indices[j-1];\n            indices[j-1]=indices[j];\n            indices[j]=s;\n        }\n    }\n}*/\nstruct Points\n{\n    int x,y;\n};\nint main()\n{\n    int n,i,j,k,x0,y0;\n    scanf(\"%d\",&n);\n    struct Points p[n*4+1];\n    for(i=0;i<n*4+1;i++)\n    {\n        scanf(\"%d %d\",&p[i].x,&p[i].y);\n    }\n    for(x0=0;x0<=50;x0++)\n    {\n        for(y0=0;y0<=50;y0++)\n        {\n            for(k=1;y0+k<=50&&x0+k<=50;k++)\n            {\n                int counter=0;\n                for(i=0;i<n*4+1&&counter<=1;i++)\n                {\n                    if(((p[i].x==x0||p[i].x==x0+k)&&(p[i].y>=y0&&p[i].y<=y0+k))||((p[i].y==y0||p[i].y==y0+k)&&(p[i].x>=x0&&p[i].x<=x0+k)))\n                    {\n                        continue;\n                    }\n                    counter++;\n                }\n                if(counter>1) continue;\n                for(i=0;i<n*4+1&&counter<=1;i++)\n                {\n                    if(((p[i].x==x0||p[i].x==x0+k)&&(p[i].y>=y0&&p[i].y<=y0+k))||((p[i].y==y0||p[i].y==y0+k)&&(p[i].x>=x0&&p[i].x<=x0+k)))\n                    {\n                        continue;\n                    }\n                    printf(\"%d %d\",p[i].x,p[i].y);\n                    return 0;\n                }\n            }\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "20a59f7e72ad544b9bca79c64cb339f5", "src_uid": "1f9153088dcba9383b1a2dbe592e4d06", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nvoid buble_sort(int a[], int n)\n{\n    int i, j, t;\n    for(i=0; i<n; i++)\n    {\n        for(j=0; j<n-1; j++)\n        {\n            if(a[j]>a[j+1])\n            {\n                t=a[j];\n                a[j]=a[j+1];\n                a[j+1]=t;\n            }\n        }\n    }\n}\nint main()\n{\n    int n, l, i, j, xr, yr, xl, xh, yl, yh;\n    scanf(\"%d\", &n);\n    l=(4*n)+1;\n    int x[l];\n    int y[l];\n    int xd[l];\n    int yd[l];\n    for(i=0; i<l; i++)\n    {\n        scanf(\"%d %d\", &x[i], &y[i]);\n        xd[i]=x[i];\n        yd[i]=y[i];\n    }\n    buble_sort(x, l);\n    buble_sort(y,l);\n    if(x[0]==x[1])\n    {\n    \txl=x[0];\n\t}\n\telse if(x[0]!=x[1])\n\t{\n\t\txl=x[1];\n\t}\n\tif(x[l-2]==x[l-1])\n\t{\n\t\txh=x[l-2];\n\t}\n\telse if(x[l-2]!=x[l-1])\n\t{\n\t\txh=x[l-2];\n\t}\n\tif(y[0]==y[1])\n    {\n    \tyl=y[0];\n\t}\n\telse if(y[0]!=y[1])\n\t{\n\t\tyl=y[1];\n\t}\n\tif(y[l-2]==y[l-1])\n\t{\n\t\tyh=y[l-2];\n\t}\n\telse if(y[l-2]!=y[l-1])\n\t{\n\t\tyh=y[l-2];\n\t}\n    for(i=0; i<l; i++)\n    {\n    \tif((xd[i]<xl || xd[i]>xh) || (yd[i]<yl || yd[i]>yh))\n    \t{\n    \t   xr=xd[i];\n    \t   yr=yd[i];\n    \t   break;\n        }\n        else if((xd[i]>xl && xd[i]<xh) && (yd[i]>yl && yd[i]<yh))\n    \t{\n    \t   xr=xd[i];\n    \t   yr=yd[i];\n    \t   break;\n        }\n\t}\n    printf(\"%d %d\\n\", xr, yr);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e30564a517801b85a61c4f07213401b0", "src_uid": "1f9153088dcba9383b1a2dbe592e4d06", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint asc(const void* a, const void* b)\n{\n\treturn *(int*)a - *(int*)b;\n}\nint main()\n{\n\tint n;\n\tscanf(\"%d\", &n);\n\tint i;\n\tint x[50], y[50];\n\tfor (i = 0; i < 4 * n + 1; i++)\n\t\tscanf(\"%d %d\", &x[i], &y[i]);\n\tint xx[50], yy[50];\n\tfor (i = 0; i < 4 * n + 1; i++)\n\t\txx[i] = x[i];\n\tqsort(xx, 4 * n + 1, sizeof(int), asc);\n\tif (xx[0] != xx[1])\n\t{\n\t\tfor (i = 0; i < 4 * n + 1; i++)\n\t\t{\n\t\t\tif (x[i] == xx[0])\n\t\t\t{\n\t\t\t\tprintf(\"%d %d\\n\", x[i], y[i]);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tif (xx[4 * n - 1] != xx[4 * n])\n\t{\n\t\tfor (i = 0; i < 4 * n + 1; i++)\n\t\t{\n\t\t\tif (x[i] == xx[4 * n])\n\t\t\t{\n\t\t\t\tprintf(\"%d %d\\n\", x[i], y[i]);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tfor (i = 0; i < 4 * n + 1; i++)\n\t\tyy[i] = y[i];\n\tqsort(yy, 4 * n + 1, sizeof(int), asc);\n\tif (yy[0] != yy[1])\n\t{\n\t\tfor (i = 0; i < 4 * n + 1; i++)\n\t\t{\n\t\t\tif (y[i] == yy[0])\n\t\t\t{\n\t\t\t\tprintf(\"%d %d\\n\", x[i], y[i]);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tif (yy[4 * n - 1] != yy[4 * n])\n\t{\n\t\tfor (i = 0; i < 4 * n + 1; i++)\n\t\t{\n\t\t\tif (y[i] == yy[4 * n])\n\t\t\t{\n\t\t\t\tprintf(\"%d %d\\n\", x[i], y[i]);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tint maxx, minx, maxy, miny;\n\tmaxx = maxy = 0;\n\tminx = miny = 100;\n\tfor (i = 0; i < 4 * n + 1; i++)\n\t{\n\t\tif (x[i] < minx)minx = x[i];\n\t\tif (x[i] > maxx)maxx = x[i];\n\t\tif (y[i] < miny)miny = y[i];\n\t\tif (y[i] > maxy)maxy = y[i];\n\t}\n\tfor (i = 0; i < 4 * n + 1; i++)\n\t{\n\t\tif (x[i] != minx && x[i] != maxx && y[i] != miny && y[i] != maxy)\n\t\t{\n\t\t\tprintf(\"%d %d\\n\", x[i], y[i]);\n\t\t\treturn 0;\n\t\t}\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "831fbcf2f2bbb3345a7bf2a4e416fab8", "src_uid": "1f9153088dcba9383b1a2dbe592e4d06", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "/*\n * main.c\n *\n *  Created on: 03 \ufffd\ufffd\ufffd. 2014 \ufffd.\n *      Author: ulgish\n */\n\n\n/*\n * util.c\n *\n *  Created on: 30 \ufffd\ufffd\ufffd\ufffd 2014 \ufffd.\n *      Author: ulgish\n */\n#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\n\n#define MAX(A,B) (((A) > (B))?(A):(B))\n#define MIN(A,B) (((A) < (B))?(A):(B))\n\n#define LN printf(\"\\n\")\n#define TAB printf(\"\\t\")\n#define SPACE printf(\" \")\n\ntypedef unsigned long long uint64;\ntypedef long long int64;\ntypedef signed short int16;\ntypedef unsigned short uint16;\ntypedef char byte;\n\n\nvoid int64_print(int64 n){\n\tint64 carry = 10;\n\tif (n == 0){\n\t\tprintf(\"0\");\n\t\treturn;\n\t}\n\tchar buf[20];\n\tbuf[0] = '\\0';\n\tint i = 0, j;\n\twhile (n > 0){\n\t\tbuf[i] = n % carry;\n\t\tn = n / carry;\n\t\ti += 1;\n\t}\n\ti--;\n\tfor (j = i; j>= 0; j--){\n\t\tprintf(\"%c\", 48 + buf[j]);\n\t}\n}\nvoid uint64_print(uint64 n){\n\tuint64 carry = 10;\n\tchar buf[20];\n\tbuf[0] = '\\0';\n\tint i = 0, j;\n\twhile (n > 0){\n\t\tbuf[i] = n % carry;\n\t\tn = n / carry;\n\t\ti += 1;\n\t}\n\ti--;\n\tfor (j = i; j>= 0; j--){\n\t\tprintf(\"%c\", 48 + buf[j]);\n\t}\n}\n\n\nuint64 uint64_read(){\n\tchar* s = (char*) calloc(20, sizeof(char));\n\ts[0] = '\\0';\n\tscanf(\"%s\", s);\n\t//printf(\"=======%s\\n\", s);\n\tuint64 ret = 0;\n\tuint64 carry = 1;\n\tint len = strlen(s), i;\n\tfor (i = 0; i < len; i++){\n\t\tret += carry * (s[len-1-i] - 48);\n\t\tcarry*=10;\n\t};\n\tfree(s);\n\treturn ret;\n}\n\n\nint64 int64_read(){\n\tchar* s = (char*) calloc(21, sizeof(char));\n\ts[0] = '\\0';\n\tscanf(\"%s\", s);\n\t//printf(\"=======%s\\n\", s);\n\tint64 ret = 0;\n\tint64 carry = 1;\n\tint len = strlen(s), i;\n\tfor (i = 0; i < len; i++){\n\t\tret += carry * (s[len-1-i] - 48);\n\t\tcarry*=10;\n\t};\n\tfree(s);\n\treturn ret;\n}\n\n//#define DEBUG\n\nint64 x;\nint a[100001];\nint b[100001];\n\nint n,d;\n\nvoid swap(int* a, int* b){\n\tint c;\n\tc = *a;\n\t*a = *b;\n\t*b = c;\n\treturn;\n}\nint64 getNextX() {\n    x = (x * 37 + 10007) % 1000000007;\n    return x;\n}\nvoid initAB() {\n\tint i;\n    for(i = 0; i < n; i = i + 1){\n        a[i] = i + 1;\n    }\n    for(i = 0; i < n; i = i + 1){\n        swap(&(a[i]), &(a[(int)(getNextX() % (i + 1LL))]));\n    }\n    for(i = 0; i < n; i = i + 1){\n        if (i < d)\n            b[i] = 1;\n        else\n            b[i] = 0;\n    }\n    for(i = 0; i < n; i = i + 1){\n        swap(&(b[i]), &(b[(int)(getNextX() % (i + 1LL))]));\n    }\n}\n\n\nint main(){\n\tscanf(\"%d %d\", &n, &d);\n\tx = int64_read();\n\tint i,j;\n\tinitAB();\n\tint max_a[100000];\n\tint index_a[100001];\n\tint sum_b[100000];\n\tsum_b[0] = b[0];\n\tmax_a[0] = a[0];\n#ifdef DEBUG\n\tprintf(\"d:%d\\n\", d);\n\tfor (i = 0 ; i < n; i++){\n\t\tprintf(\"%d\\t\", b[i]);\n\t}\n\tLN;\n\n#endif\n\tif (b[0] == 0){\n\t\tprintf(\"0\\n\");\n\t}else{\n\t\tprintf(\"%d\\n\", a[0]);\n\t}\n\tint tmp = 0;\n\tfor (i = 0; i< n; i++){\n\t\tindex_a[a[i]] = i;\n\t\tif (i > 0){\n\t\t\tsum_b[i] = b[i] + sum_b[i-1];\n\t\t\tif (sum_b[i] == 0){\n\t\t\t\ttmp = i;\n\t\t\t}\n\t\t}\n\t}\n\tfor (i = 1; i <= tmp; i++){\n\t\tprintf(\"0\\n\");\n\t}\n\tfor (i = tmp+1; i < n; i++){\n\t\tint c = 0;\n\t\tmax_a[i] = MAX(a[i], max_a[i-1]);\n\t\tif (sum_b[i] == 0){\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\t\t}\n\t\tint s = 0;\n\t\tbyte next = 0;\n\t\tfor (j = max_a[i]; j >= 0 && s < 5000; j--, s++){\n\t\t\tif (index_a[j] <= i){\n\t\t\t\tif (b[i - index_a[j]]){\n\t\t\t\t\tnext = 1;\n\t\t\t\t\tprintf(\"%d\\n\", j);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (next){\n\t\t\tcontinue;\n\t\t}\n\t\tfor (j = 0; j<= i; j++){\n\t\t\tc = MAX(c, a[j]*b[i-j]);\n\t\t}\n\t\tprintf(\"%d\\n\",c);\n\t}\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6499d3b538191fd7fb05b7799be4fc11", "src_uid": "948ae7a0189ada07c8c67a1757f691f0", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "/*\n * main.c\n *\n *  Created on: 03 \ufffd\ufffd\ufffd. 2014 \ufffd.\n *      Author: ulgish\n */\n\n\n/*\n * util.c\n *\n *  Created on: 30 \ufffd\ufffd\ufffd\ufffd 2014 \ufffd.\n *      Author: ulgish\n */\n#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\n\n#define MAX(A,B) (((A) > (B))?(A):(B))\n#define MIN(A,B) (((A) < (B))?(A):(B))\n\n#define LN printf(\"\\n\")\n#define TAB printf(\"\\t\")\n#define SPACE printf(\" \")\n\ntypedef unsigned long long uint64;\ntypedef long long int64;\ntypedef signed short int16;\ntypedef unsigned short uint16;\ntypedef char byte;\n\n\nvoid int64_print(int64 n){\n\tint64 carry = 10;\n\tchar buf[20];\n\tbuf[0] = '\\0';\n\tint i = 0, j;\n\twhile (n > 0){\n\t\tbuf[i] = n % carry;\n\t\tn = n / carry;\n\t\ti += 1;\n\t}\n\ti--;\n\tfor (j = i; j>= 0; j--){\n\t\tprintf(\"%c\", 48 + buf[j]);\n\t}\n}\nvoid uint64_print(uint64 n){\n\tuint64 carry = 10;\n\tchar buf[20];\n\tbuf[0] = '\\0';\n\tint i = 0, j;\n\twhile (n > 0){\n\t\tbuf[i] = n % carry;\n\t\tn = n / carry;\n\t\ti += 1;\n\t}\n\ti--;\n\tfor (j = i; j>= 0; j--){\n\t\tprintf(\"%c\", 48 + buf[j]);\n\t}\n}\n\n\nuint64 uint64_read(){\n\tchar* s = (char*) calloc(20, sizeof(char));\n\ts[0] = '\\0';\n\tscanf(\"%s\", s);\n\t//printf(\"=======%s\\n\", s);\n\tuint64 ret = 0;\n\tuint64 carry = 1;\n\tint len = strlen(s), i;\n\tfor (i = 0; i < len; i++){\n\t\tret += carry * (s[len-1-i] - 48);\n\t\tcarry*=10;\n\t};\n\tfree(s);\n\treturn ret;\n}\n\n\nint64 int64_read(){\n\tchar* s = (char*) calloc(21, sizeof(char));\n\ts[0] = '\\0';\n\tscanf(\"%s\", s);\n\t//printf(\"=======%s\\n\", s);\n\tint64 ret = 0;\n\tint64 carry = 1;\n\tint len = strlen(s), i;\n\tfor (i = 0; i < len; i++){\n\t\tret += carry * (s[len-1-i] - 48);\n\t\tcarry*=10;\n\t};\n\tfree(s);\n\treturn ret;\n}\n\n//#define DEBUG\n\nint64 x;\nint a[100001];\nint b[100001];\n\nint n,d;\n\nvoid swap(int* a, int* b){\n\tint c;\n\tc = *a;\n\t*a = *b;\n\t*b = c;\n\treturn;\n}\nint64 getNextX() {\n    x = (x * 37 + 10007) % 1000000007;\n    return x;\n}\nvoid initAB() {\n\tint i;\n    for(i = 0; i < n; i = i + 1){\n        a[i] = i + 1;\n    }\n    for(i = 0; i < n; i = i + 1){\n        swap(&(a[i]), &(a[(int)(getNextX() % (i + 1LL))]));\n    }\n    for(i = 0; i < n; i = i + 1){\n        if (i < d)\n            b[i] = 1;\n        else\n            b[i] = 0;\n    }\n    for(i = 0; i < n; i = i + 1){\n        swap(&(b[i]), &(b[(int)(getNextX() % (i + 1LL))]));\n    }\n}\n\n\nint main(){\n\tscanf(\"%d %d\", &n, &d);\n\tx = int64_read();\n\tint i,j;\n\tinitAB();\n\n#ifdef DEBUG\n\tprintf(\"d:%d\\n\", d);\n\tfor (i = 0 ; i < n; i++){\n\t\tprintf(\"%d\\t\", b[i]);\n\t}\n\tLN;\n\n#endif\n\tfor (i = 0; i < n; i++){\n\t\tint64 c = 0;\n\t\tfor (j = 0; j<= i; j++){\n\t\t\tc = MAX(c, a[j]*b[i-j]);\n\t\t}\n\t\tint64_print(c); LN;\n\t}\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2d1b821d18cec3cbb10052cae975367b", "src_uid": "948ae7a0189ada07c8c67a1757f691f0", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "/*\n * main.c\n *\n *  Created on: 03 \ufffd\ufffd\ufffd. 2014 \ufffd.\n *      Author: ulgish\n */\n\n\n/*\n * util.c\n *\n *  Created on: 30 \ufffd\ufffd\ufffd\ufffd 2014 \ufffd.\n *      Author: ulgish\n */\n#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\n\n#define MAX(A,B) (((A) > (B))?(A):(B))\n#define MIN(A,B) (((A) < (B))?(A):(B))\n\n#define LN printf(\"\\n\")\n#define TAB printf(\"\\t\")\n#define SPACE printf(\" \")\n\ntypedef unsigned long long uint64;\ntypedef long long int64;\ntypedef signed short int16;\ntypedef unsigned short uint16;\ntypedef char byte;\n\n\nvoid int64_print(int64 n){\n\tint64 carry = 10;\n\tif (n == 0){\n\t\tprintf(\"0\");\n\t\treturn;\n\t}\n\tchar buf[20];\n\tbuf[0] = '\\0';\n\tint i = 0, j;\n\twhile (n > 0){\n\t\tbuf[i] = n % carry;\n\t\tn = n / carry;\n\t\ti += 1;\n\t}\n\ti--;\n\tfor (j = i; j>= 0; j--){\n\t\tprintf(\"%c\", 48 + buf[j]);\n\t}\n}\nvoid uint64_print(uint64 n){\n\tuint64 carry = 10;\n\tchar buf[20];\n\tbuf[0] = '\\0';\n\tint i = 0, j;\n\twhile (n > 0){\n\t\tbuf[i] = n % carry;\n\t\tn = n / carry;\n\t\ti += 1;\n\t}\n\ti--;\n\tfor (j = i; j>= 0; j--){\n\t\tprintf(\"%c\", 48 + buf[j]);\n\t}\n}\n\n\nuint64 uint64_read(){\n\tchar* s = (char*) calloc(20, sizeof(char));\n\ts[0] = '\\0';\n\tscanf(\"%s\", s);\n\t//printf(\"=======%s\\n\", s);\n\tuint64 ret = 0;\n\tuint64 carry = 1;\n\tint len = strlen(s), i;\n\tfor (i = 0; i < len; i++){\n\t\tret += carry * (s[len-1-i] - 48);\n\t\tcarry*=10;\n\t};\n\tfree(s);\n\treturn ret;\n}\n\n\nint64 int64_read(){\n\tchar* s = (char*) calloc(21, sizeof(char));\n\ts[0] = '\\0';\n\tscanf(\"%s\", s);\n\t//printf(\"=======%s\\n\", s);\n\tint64 ret = 0;\n\tint64 carry = 1;\n\tint len = strlen(s), i;\n\tfor (i = 0; i < len; i++){\n\t\tret += carry * (s[len-1-i] - 48);\n\t\tcarry*=10;\n\t};\n\tfree(s);\n\treturn ret;\n}\n\n//#define DEBUG\n\nint64 x;\nint a[100001];\nint b[100001];\n\nint n,d;\n\nvoid swap(int* a, int* b){\n\tint c;\n\tc = *a;\n\t*a = *b;\n\t*b = c;\n\treturn;\n}\nint64 getNextX() {\n    x = (x * 37 + 10007) % 1000000007;\n    return x;\n}\nvoid initAB() {\n\tint i;\n    for(i = 0; i < n; i = i + 1){\n        a[i] = i + 1;\n    }\n    for(i = 0; i < n; i = i + 1){\n        swap(&(a[i]), &(a[(int)(getNextX() % (i + 1LL))]));\n    }\n    for(i = 0; i < n; i = i + 1){\n        if (i < d)\n            b[i] = 1;\n        else\n            b[i] = 0;\n    }\n    for(i = 0; i < n; i = i + 1){\n        swap(&(b[i]), &(b[(int)(getNextX() % (i + 1LL))]));\n    }\n}\n\n\nint main(){\n\tscanf(\"%d %d\", &n, &d);\n\tx = int64_read();\n\tint i,j;\n\tinitAB();\n\tint max_a[100000];\n\tint index_a[100001];\n\tint sum_b[100000];\n\tsum_b[0] = b[0];\n\tmax_a[0] = a[0];\n#ifdef DEBUG\n\tprintf(\"d:%d\\n\", d);\n\tfor (i = 0 ; i < n; i++){\n\t\tprintf(\"%d\\t\", b[i]);\n\t}\n\tLN;\n\n#endif\n\tint tmp = 0;\n\tfor (i = 0; i< n; i++){\n\t\tindex_a[a[i]] = i;\n\t\tif (i > 0){\n\t\t\tsum_b[i] = b[i] + sum_b[i-1];\n\t\t\tif (sum_b[i] == 0){\n\t\t\t\ttmp = i;\n\t\t\t}\n\t\t}\n\t}\n\tfor (i = 0; i < tmp; i++){\n\t\tprintf(\"0\\n\");\n\t}\n\tfor (i = tmp; i < n; i++){\n\t\tint c = 0;\n\t\tmax_a[i] = MAX(a[i], max_a[i-1]);\n\t\tif (sum_b[i] == 0){\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\t\t}\n\t\tint s = 0;\n\t\tbyte next = 0;\n\t\tfor (j = max_a[i]; j >= 0 && s < 5000; j--, s++){\n\t\t\tif (index_a[j] <= i){\n\t\t\t\tif (b[i - index_a[j]]){\n\t\t\t\t\tnext = 1;\n\t\t\t\t\tprintf(\"%d\\n\", j);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (next){\n\t\t\tcontinue;\n\t\t}\n\t\tfor (j = 0; j<= i; j++){\n\t\t\tc = MAX(c, a[j]*b[i-j]);\n\t\t}\n\t\tprintf(\"%d\\n\",c);\n\t}\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1cee38bcb363eaedc907c3c29d682f0b", "src_uid": "948ae7a0189ada07c8c67a1757f691f0", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "/*\n * main.c\n *\n *  Created on: 03 \ufffd\ufffd\ufffd. 2014 \ufffd.\n *      Author: ulgish\n */\n\n\n/*\n * util.c\n *\n *  Created on: 30 \ufffd\ufffd\ufffd\ufffd 2014 \ufffd.\n *      Author: ulgish\n */\n#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\n\n#define MAX(A,B) (((A) > (B))?(A):(B))\n#define MIN(A,B) (((A) < (B))?(A):(B))\n\n#define LN printf(\"\\n\")\n#define TAB printf(\"\\t\")\n#define SPACE printf(\" \")\n\ntypedef unsigned long long uint64;\ntypedef long long int64;\ntypedef signed short int16;\ntypedef unsigned short uint16;\ntypedef char byte;\n\n\nvoid int64_print(int64 n){\n\tint64 carry = 10;\n\tif (n == 0){\n\t\tprintf(\"0\");\n\t\treturn;\n\t}\n\tchar buf[20];\n\tbuf[0] = '\\0';\n\tint i = 0, j;\n\twhile (n > 0){\n\t\tbuf[i] = n % carry;\n\t\tn = n / carry;\n\t\ti += 1;\n\t}\n\ti--;\n\tfor (j = i; j>= 0; j--){\n\t\tprintf(\"%c\", 48 + buf[j]);\n\t}\n}\nvoid uint64_print(uint64 n){\n\tuint64 carry = 10;\n\tchar buf[20];\n\tbuf[0] = '\\0';\n\tint i = 0, j;\n\twhile (n > 0){\n\t\tbuf[i] = n % carry;\n\t\tn = n / carry;\n\t\ti += 1;\n\t}\n\ti--;\n\tfor (j = i; j>= 0; j--){\n\t\tprintf(\"%c\", 48 + buf[j]);\n\t}\n}\n\n\nuint64 uint64_read(){\n\tchar* s = (char*) calloc(20, sizeof(char));\n\ts[0] = '\\0';\n\tscanf(\"%s\", s);\n\t//printf(\"=======%s\\n\", s);\n\tuint64 ret = 0;\n\tuint64 carry = 1;\n\tint len = strlen(s), i;\n\tfor (i = 0; i < len; i++){\n\t\tret += carry * (s[len-1-i] - 48);\n\t\tcarry*=10;\n\t};\n\tfree(s);\n\treturn ret;\n}\n\n\nint64 int64_read(){\n\tchar* s = (char*) calloc(21, sizeof(char));\n\ts[0] = '\\0';\n\tscanf(\"%s\", s);\n\t//printf(\"=======%s\\n\", s);\n\tint64 ret = 0;\n\tint64 carry = 1;\n\tint len = strlen(s), i;\n\tfor (i = 0; i < len; i++){\n\t\tret += carry * (s[len-1-i] - 48);\n\t\tcarry*=10;\n\t};\n\tfree(s);\n\treturn ret;\n}\n\n//#define DEBUG\n\nint64 x;\nint a[100001];\nint b[100001];\n\nint n,d;\n\nvoid swap(int* a, int* b){\n\tint c;\n\tc = *a;\n\t*a = *b;\n\t*b = c;\n\treturn;\n}\nint64 getNextX() {\n    x = (x * 37 + 10007) % 1000000007;\n    return x;\n}\nvoid initAB() {\n\tint i;\n    for(i = 0; i < n; i = i + 1){\n        a[i] = i + 1;\n    }\n    for(i = 0; i < n; i = i + 1){\n        swap(&(a[i]), &(a[(int)(getNextX() % (i + 1LL))]));\n    }\n    for(i = 0; i < n; i = i + 1){\n        if (i < d)\n            b[i] = 1;\n        else\n            b[i] = 0;\n    }\n    for(i = 0; i < n; i = i + 1){\n        swap(&(b[i]), &(b[(int)(getNextX() % (i + 1LL))]));\n    }\n}\n\n\nint main(){\n\tscanf(\"%d %d\", &n, &d);\n\tx = int64_read();\n\tint i,j;\n\tinitAB();\n\tint max_a[100000];\n\tint index_a[100001];\n\tint sum_b[100000];\n\tsum_b[0] = b[0];\n\tmax_a[0] = a[0];\n#ifdef DEBUG\n\tprintf(\"d:%d\\n\", d);\n\tfor (i = 0 ; i < n; i++){\n\t\tprintf(\"%d\\t\", b[i]);\n\t}\n\tLN;\n\n#endif\n\tif (b[0] == 0){\n\t\tprintf(\"0\\n\");\n\t}else{\n\t\tprintf(\"%d\\n\", a[0]);\n\t}\n\tint tmp = 0;\n\tfor (i = 0; i< n; i++){\n\t\tindex_a[a[i]] = i;\n\t\tif (i > 0){\n\t\t\tsum_b[i] = b[i] + sum_b[i-1];\n\t\t\tif (sum_b[i] == 0){\n\t\t\t\ttmp = i;\n\t\t\t}\n\t\t}\n\t}\n\tfor (i = 1; i < tmp; i++){\n\t\tprintf(\"0\\n\");\n\t}\n\tfor (i = tmp; i < n; i++){\n\t\tint c = 0;\n\t\tmax_a[i] = MAX(a[i], max_a[i-1]);\n\t\tif (sum_b[i] == 0){\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\t\t}\n\t\tint s = 0;\n\t\tbyte next = 0;\n\t\tfor (j = max_a[i]; j >= 0 && s < 5000; j--, s++){\n\t\t\tif (index_a[j] <= i){\n\t\t\t\tif (b[i - index_a[j]]){\n\t\t\t\t\tnext = 1;\n\t\t\t\t\tprintf(\"%d\\n\", j);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (next){\n\t\t\tcontinue;\n\t\t}\n\t\tfor (j = 0; j<= i; j++){\n\t\t\tc = MAX(c, a[j]*b[i-j]);\n\t\t}\n\t\tprintf(\"%d\\n\",c);\n\t}\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2bc187ace8e5b7d3fd69e1ea1ab254d9", "src_uid": "948ae7a0189ada07c8c67a1757f691f0", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\n#define N\t100000\n#define S\t20\n\nint max(int a, int b) { return a > b ? a : b; }\n\nint aa[N], bb[N];\nint x;\n\nint get_next_x() {\n\treturn (x = (x * 37LL + 10007) % 1000000007);\n}\n\nvoid init_AB(int n, int d) {\n\tint i, j, tmp;\n\n\tfor (i = 0; i < n; i++)\n\t\taa[i] = i + 1;\n\tfor (i = 0; i < n; i++) {\n\t\tj = get_next_x() % (i + 1);\n\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\t}\n\tfor (i = 0; i < n; i++)\n\t\tbb[i] = i < d;\n\tfor (i = 0; i < n; i++) {\n\t\tj = get_next_x() % (i + 1);\n\t\ttmp = bb[i], bb[i] = bb[j], bb[j] = tmp;\n\t}\n}\n\nint main() {\n\tstatic int ii[S + 1], jj[N];\n\tint n, d, h, i, k, c;\n\n\tscanf(\"%d%d%d\", &n, &d, &x);\n\tinit_AB(n, d);\n\tk = 0;\n\tfor (i = 0; i < n; i++) {\n\t\th = i < S ? i : S;\n\t\twhile (h > 0 && aa[ii[h - 1]] < aa[i]) {\n\t\t\tii[h] = ii[h - 1];\n\t\t\th--;\n\t\t}\n\t\tii[h] = i;\n\t\tif (bb[i])\n\t\t\tjj[k++] = i;\n\t\tc = 0;\n\t\tfor (h = 0; h <= i && h < S; h++)\n\t\t\tif (bb[i - ii[h]]) {\n\t\t\t\tc = aa[ii[h]];\n\t\t\t\tbreak;\n\t\t\t}\n\t\tif (c == 0)\n\t\t\tfor (h = 0; h < k; h++)\n\t\t\t\tc = max(c, aa[i - jj[h]]);\n\t\tprintf(\"%d\\n\", c);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2f59cd658b9752baaaa7e188be9a86a6", "src_uid": "948ae7a0189ada07c8c67a1757f691f0", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nenum {\n    N = 1010\n};\nconst int MOD = 1e9 + 7;\n\nint dp[N][2 * N], k, ls;\nchar s[N];\n\n\nint rec(int pos, int dist, int anyDigit) {\n    if(pos == ls)\n        return dist == 0;\n    if(anyDigit && dp[ls - pos][dist] != -1)\n        return dp[ls - pos][dist];\n\n    int limit = anyDigit ? 9 : s[pos] - '0';\n    int ret = 0, i;\n    for(i = 0; i <= limit; i++) {\n        int ndist = dist + (dist != 0);\n        if(i == 4 || i == 7)\n            ndist = dist <= k ? 0 : 1;\n        ret += rec(pos + 1, ndist, anyDigit || (i < limit));\n        while(ret >= MOD)\n            ret -= MOD;\n    }\n    if(anyDigit)\n        dp[ls - pos][dist] = ret;\n    return ret;\n}\n\nint isLucky() {\n    int i, prev = -N;\n    for(i = 0; prev != 0 && i < ls; i++) {\n        if(s[i] == '4' || s[i] == '7')\n            prev = (i - prev) <= k ? 0 : i + 1;\n    }\n    return prev == 0;\n}\n\nint main() {\n    int t;\n    scanf(\"%d %d\", &t, &k);\n    memset(dp, -1, sizeof(dp));\n    while(t--) {\n        scanf(\"%s\", s);\n        ls = strlen(s);\n        int val = rec(0, k + 1, 0) - isLucky();\n\n        scanf(\"%s\", s);\n        ls = strlen(s);\n        val = rec(0, k + 1, 0) - val;\n        while(val < 0)\n            val += MOD;\n        while(val >= MOD)\n            val -= MOD;\n        printf(\"%d\\n\", val);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ac5f1ac4b449e0c5f15304234e545c24", "src_uid": "5517efa2fc9362fdf342d32adac889f4", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "void main(void", "lang_cluster": "C", "compilation_error": true, "code_uid": "fc3dae342cdf11f1e9efb7311b825454", "src_uid": "e167dc35a0d3b98c0414c66099e35920", "difficulty": 800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main(int argc, char* argv[])\n{\n  int a, b;\n  scanf(\"%d %d\", &a, &b);\n  printf(\"%d\\n\", 6 - a - b);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c2fecfc3c358eff951bdcbbc45be1657", "src_uid": "e167dc35a0d3b98c0414c66099e35920", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main()\n{\nint a, b;\nscanf(\"%d %d\", &a, &b);\nif ((a==1) ||(b==1))\n{\nif ((a==2) ||(b==2))\nprintf(\"3\");\nelse\nprintf(\"2\");\n\n}\nelse\nprintf(\"1\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "3986a803c8fcd740bb1c0899630623ca", "src_uid": "e167dc35a0d3b98c0414c66099e35920", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nvoid main(void)\n{\nint a, b;\nscanf(\"%d %d\", &a, &b);\nif ((a==1) ||(b==1))\n{\nif ((a==2) ||(b==2))\nprintf(\"3\");\nelse\nprintf(\"2\");\n\n}\nelse\nprintf(\"1\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e770f53af13de5fa46a419c4b76f948a", "src_uid": "e167dc35a0d3b98c0414c66099e35920", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "void main(void)\n{\nint a, b;\nscanf(\"%d %d\", &a, &b);\nif ((a==1) ||(b==1))\n{\nif ((a==2) ||(b==2))\nprintf(\"3\");\nelse\nprintf(\"2\");\n\n}\nelse\nprintf(\"1\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "02934d2850f544eb2777c3289e41f187", "src_uid": "e167dc35a0d3b98c0414c66099e35920", "difficulty": 800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t100000\n#define MD\t1000000007\n\nint gcd(int a, int b) {\n\treturn b == 0 ? a : gcd(b, a % b);\n}\n\nlong long lcm(int a, int b) {\n\treturn (long long) a / gcd(a, b) * b;\n}\n\nint tt[N + 1];\n\nvoid init() {\n\tint a, b;\n\n\tfor (a = 1; a <= N; a++)\n\t\ttt[a] = a;\n\tfor (a = 2; a <= N; a++) {\n\t\tif (tt[a] != a)\n\t\t\tcontinue;\n\t\tfor (b = a; b <= N; b += a)\n\t\t\ttt[b] = tt[b] / a * (a - 1);\n\t}\n}\n\nint main() {\n\tint n, d, a, b, ans;\n\n\tinit();\n\tscanf(\"%d\", &n);\n\tans = 0;\n\tfor (d = 1; d <= n; d++)\n\t\tfor (a = d + d; a < n; a += d) {\n\t\t\tb = n - a;\n\t\t\tans = (ans + lcm(b, d) % MD * tt[a / d]) % MD;\n\t\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ee9f3586607447df2cc74bbd7ba813e8", "src_uid": "c3694a6ff95c64bef8cbe8834c3fd6cb", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\n#define N\t4000\n#define MD\t1000000007\n\nint main() {\n\tstatic int ch[N + 1][N + 1], dp[N + 1], pp[N + 1];\n\tint n, i, j, k, p;\n\tlong long x, y, ans;\n\n\tscanf(\"%d\", &n);\n\tch[0][0] = 1;\n\tfor (i = 1; i <= n; i++) {\n\t\tch[i][0] = 1;\n\t\tfor (j = 1; j <= n; j++)\n\t\t\tch[i][j] = (ch[i - 1][j] + ch[i - 1][j - 1]) % MD;\n\t}\n\tdp[0] = 1;\n\tfor (i = 1; i <= n; i++) {\n\t\tx = 0;\n\t\tfor (j = 2; j <= i; j++) {\n\t\t\ty = dp[i - j];\n\t\t\tif (dp[i - j] != 0)\n\t\t\t\tx = (x + y * ch[i - 1][j - 1]) % MD;\n\t\t}\n\t\tdp[i] = x;\n\t}\n\tp = 1;\n\tfor (i = 0; i <= n; i++) {\n\t\tpp[i] = p - 1;\n\t\tp = p * 2 % MD;\n\t}\n\tans = 0;\n\tfor (k = 1; k <= n; k++)\n\t\tans = (ans + (long long) pp[k] * ch[n][k] % MD * dp[n - k]) % MD;\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "605395b1f179c6bb62a3ef48c540f09c", "src_uid": "aa2c3e94a44053a0d86f61da06681023", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint n, ar[]={0,1,3,10,37,151,674,3263,17007,94828,562595,3535027,23430840,163254885,192059216,97183539,384727153,211932162,665362848,415709078,654959364,894067657,839120000,627072923,586774033,440165789,840647542,118441546,505992682,607243387,93527420,378847836,948139661,770183251,365355663,989344183,548640276,317289217,997901123,159164073,843138878,532150136,738186543,903861313,682196381,973969945,132955760,252975343,448800686,260473966,172364334,974776377,897990701,517201033,576838003,99444281,227668527,276751933,925606182,183971202,872834804,675567482,485151063,90425806,573944639,319383684,228218188,853465612,413776522,234312776,696953174,561359388,614568659,310760116,308156021,643857743,130527569,21545623,861347933,160875480,265384023,880663120,642768069,283279971,101569565,642645431,549146203,962813505,943728849,409246814,285130248,71857567,876844125,639794356,718486712,669604188,215716321,617971855,139675728,757688910,320249104,621227957,8420956,210511678,237853303,571777940,124824068,554160360,861653403,682637480,231939767,18101111,899784402,38539461,459245274,133368830,794361288,845364734,411437479,295388712,946233522,770525146,9117720,552920178,575589233,372629731,386010446,840661218,620900095,139503115,511927381,578357362,64025286,334338018,50447285,600060973,463521109,603848757,124677320,384555440,124916527,185672381,489919006,909579381,138193225,265871589,754007856,931017925,530042754,776962350,693701991,697550026,65897729,925178446,524529822,282186556,906408203,423821527,235677618,198401842,739841724,445468199,551132246,282892517,598818617,713743768,323922897,386628568,474046790,302658513,783562521,701916176,482177632,681588349,266655423,743351863,319498248,426746288,89678205,500650748,546473898,223152283,841147627,688890488,901303731,788610629,829394955,750389455,745439788,809252095,287863106,297473389,52881575,679729868,61954094,593572313,142142337,87045414,702643022,32976555,517206126,380236389,828797589,845005051,422842060,260455358,651230866,488177154,982371716,172307030,994127208,259014259,84243868,148694890,313032650,79750143,628177536,256112757,535578122,7516872,660259410,862246837,942873362,525515969,353458202,517016061,146128173,615658629,171576507,313485249,756862637,740107237,450464972,698608957,380461701,788065795,235055502,488339779,625468897,81218153,752562624,954468821,388408427,220000770,962611398,138488797,232824743,623588948,89320450,5174417,444171924,539838147,184946963,829706030,250353513,837334003,192637869,954980409,989726944,503629638,246128748,144252879,869972346,159483785,38149548,399002531,139867042,702866700,566004753,303913805,946274118,352063038,148918236,344908939,925123896,175513960,888310551,233700316,237128991,80142095,627539989,30420961,108486126,993957197,940173780,407371015,13694119,969064311,945245210,515586500,834646464,210959252,766474958,237866830,520123316,83961446,97878509,896040082,51406202,612079312,569120595,325712093,979110226,72296197,169538467,506717757,990725778,888153398,884672580,747447278,989585067,197205447,997554253,162606658,612854211,585638351,300385030,648581707,24645691,142364491,87271224,656248353,311752536,345078260,862509279,749617553,148690167,255207879,937517648,692740850,188651194,442080602,285711119,523391595,806719830,122802835,948147156,825684063,120090726,465071065,216239633,955952822,254936196,818273287,582823720,838683603,211078726,609268949,539236132,461048619,931162689,575599737,702129707,929755292,3165024,932095281,371965629,560082406,915331279,404247953,119029625,650026279,33911127,542568006,737311646,839818392,121381063,81776121,264049814,428758250,935258956,524814024,827629225,159677867,208903802,254070037,334398982,852112879,205126265,581086872,289728727,749733927,825622969,203314518,313219470,714203321,966360246,415028559,441541100,64736522,135298651,311340818,724308321,852861846,567399501,818780718,445445536,185482874,890679335,117928565,212566203,217299615,125999181,478432188,642522487,657976604,462229383,930237021,202402571,859794210,821285303,193707191,139635308,949631508,581555701,493872210,253862710,156423352,756876608,453019810,540238248,525374182,395165149,552059946,666018027,218650948,316154754,567824223,718412883,959027290,327709825,416281152,860382344,503677292,449112827,426967024,595415467,755716122,910210918,495279146,453103898,539903326,104084806,171428406,629857538,238805628,522091539,904850095,831383119,364871289,59654563,188523918,418555114,248860166,832365397,779188603,392396445,763896392,993974548,375970645,176183947,455296206,826990889,44758036,495683674,791719842,655621264,658939366,735144599,275667277,655999018,965639168,676574799,346864447,379511514,459854791,905913554,604918364,6920002,652092992,597377405,920491194,562313297,482675638,955706031,63469748,417878805,240441437,990705174,289937758,842452102,258265727,995663867,792673745,608833565,729570088,316539671,559104003,153929272,607988017,245598088,490462484,935463414,309255995,733478384,499515550,689830722,849692817,311550442,635474783,127169195,9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729,528627236,449845586,460148110,371078849,605223863,752665040,1624779,644242679,985944307,858571182,461684752,810675957,993351100,382520483,250821716,977534286,508168386,246241034,609693247,743320473,146607662,998445214,431759341,343673635,640794075,262660065,878625869,897437609,516489488,23659927,759999147,655412155,503783506,667819834,551718218,605276486,57914865,419059158,46776049,804175213,960309116,623584323,753818347,91180671,886695514,802544874,178110089,143529344,505623920,720477855,80630633,63261778,317677628,454032332,240724484,186782768,536920726,899201547,923187729,845529381,295331561,895582663,595645523,82038737,267747183,796913715,122804438,49897344,362714249,862665025,396997686,604625458,37112088,976519680,446432499,748095242,429003830,291811017,677603270,505978357,9432426,387257732,739252457,905769562,480866202,114477162,910290154,964097748,975047101,558505018,397606795,320449623,674423851,567300118,96600383,149970539,81408680,943126359,618538215,902294691,538833948,516910200,175195207,164991807,613271994,282270752,195159923,182691277,893377616,350962890,378185065,165520304,736097983,104275527,107760395,496223166,392774298,339005193,6415884,852198248,869760630,57337377,328642311,313491466,473943256,761334845,163974456,805443890,454791777,655688589,217832409,48206873,250729512,650171495,668474483,645785673,828763867,638317152,787083774,304210226,761376754,998417863,114437701,179152011,856498178,895998969,375283462,756451234,63585213,746100628,352262217,685049322,41368875,185621781,193116004,704542713,613788001,712282785,133675350,36342676,127889371,885675751,150684097,935926548,457679454,908239676,46086256,363721489,148164239,493754728,991370249,574494584,10015428,949112564,670563791,506987577,373557253,422937350,707248469,738375556,170359517,504522488,822839646,971251884,14295245,6364559,829528560,31902055,509183036,190031100,209870102,452967833,456964275,743009770,951211379,933702078,78834235,324014730,139963002,928413345,526681054,322007744,800710829,525191165,830508742,525334945,99767615,190439097,150011682,869931254,195895108,642716041,472372818,845969378,891314830,756420050,48906613,622902626,55143732,131611764,37731551,299498677,640694188,842798821,526134613,706085903,187560670,871101937,458380397,376491783,258403652,497475041,92698088,58099292,798700283,160237119,420795881,715071206,382414136,647275638,598995012,116058943,342151526,611720254,575486020,397160465,573871310,804763794,855872322,662992488,811636563,484712697,785331707,394682840,540399090,628990032,459093333,905606245,300709259,285160187,107113222,57562713,785917963,944928720,215790782,159729073,314679186,484363600,220810932,193756864,176113742,653956340,385162015,613321758,655032622,595475307,963064968,575934821,565366446,339412611,420269925,853822178,621890905,341799536,730085337,669687144,43038664,190723760,520007694,397191752,242741101,295273112,911553855,420256891,134534726,229041960,288039667,912665239,952930369,420783608,759505883,355080139,13776242,725047982,766014613,348574940,279003328,249479481,895297500,190353452,999650409,673605968,308743105,923509648,610816753,868217020,502437344,785101081,683997286,190190426,14850091,628445902,441409418,361000413,482358408,402504037,416870733,249891590,406197948,221484197,989497991,210224657,35396951,560021235,76667846,849870082,830692370,990522851,183760025,844165424,799741184,751900362,312616925,845225615,371369299,912379072,977692978,464715793,272736508,409713958,661250225,355611695,602025484,655098052,791858343,935074244,363351667,660633695,830681132,207979827,766178018,314428742,291425335,249769039,382582132,176838020,531553490,339637176,171182908,867642857,564528401,750769745,600414104,894717790,100220991,558039019,986383097,729964739,105290652,584230942,928474519,731654431,704603911,359730029,568522294,752842834,632601136,5043193,663508854,927237848,469651192,496701127,750913782,564220277,26335023,523313806,906775254,972081105,77997445,356067959,448714422,714021267,864595306,865545519,612006278,769170204,155531347,410127755,951372818,594730385,248994712,771421275,185158093,499376011,662863317,413001393,805887756,473324595,921297057,18735813,386934464,146972891,560627347,903669593,967094539,386758849,737091463,755426664,220579995,435711349,887741198,883209694,478560592,9832118,930618930,163415091,240446492,132759678,134081914,702601410,909768461,660176441,680440363,57179043,900412868,646477707,534303308,997628154,282709724,402700228,997064274,785650024,436878044,977972319,780587881,124834909,341934157,954694394,87908701,106129323,139683610,20911809,523176936,313575704,425796257,629367793};\n\nint main(){\n    scanf(\"%d\",&n);\n    printf(\"%d\\n\",ar[n]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fcfb2dba73c4bd45a93463df4ca0e19b", "src_uid": "aa2c3e94a44053a0d86f61da06681023", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define MAX 4010\n#define MOD 1000000007\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nint S[4010][4010];\n\nvoid Generate(){\n    int i, j;\n\n    S[0][0] = 1;\n    for (i = 1; i < MAX; i++){\n        S[i][0] = 0;\n        for (j = 1; j <= i; j++){\n            S[i][j] = ( ((long long)S[i - 1][j] * j) + S[i - 1][j - 1]) % MOD;\n        }\n    }\n}\n\nint F(int n){\n    int k;\n    long long x, res = 0;\n    for (k = 1; k <= n; k++){\n        x = S[n][k];\n        res = (res + (x * k)) % MOD;\n    }\n    return res;\n}\n\nint main(){\n    Generate();\n    int n;\n    while (scanf(\"%d\", &n) != EOF){\n        printf(\"%d\\n\", F(n));\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "53794786c5bcd80de215e92ef45e4929", "src_uid": "aa2c3e94a44053a0d86f61da06681023", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint n, ar[]={0,1,3,10,37,151,674,3263,17007,94828,562595,3535027,23430840,163254885,192059216,97183539,384727153,211932162,665362848,415709078,654959364,894067657,839120000,627072923,586774033,440165789,840647542,118441546,505992682,607243387,93527420,378847836,948139661,770183251,365355663,989344183,548640276,317289217,997901123,159164073,843138878,532150136,738186543,903861313,682196381,973969945,132955760,252975343,448800686,260473966,172364334,974776377,897990701,517201033,576838003,99444281,227668527,276751933,925606182,183971202,872834804,675567482,485151063,90425806,573944639,319383684,228218188,853465612,413776522,234312776,696953174,561359388,614568659,310760116,308156021,643857743,130527569,21545623,861347933,160875480,265384023,880663120,642768069,283279971,101569565,642645431,549146203,962813505,943728849,409246814,285130248,71857567,876844125,639794356,718486712,669604188,215716321,617971855,139675728,757688910,320249104,621227957,8420956,210511678,237853303,571777940,124824068,554160360,861653403,682637480,231939767,18101111,899784402,38539461,459245274,133368830,794361288,845364734,411437479,295388712,946233522,770525146,9117720,552920178,575589233,372629731,386010446,840661218,620900095,139503115,511927381,578357362,64025286,334338018,50447285,600060973,463521109,603848757,124677320,384555440,124916527,185672381,489919006,909579381,138193225,265871589,754007856,931017925,530042754,776962350,693701991,697550026,65897729,925178446,524529822,282186556,906408203,423821527,235677618,198401842,739841724,445468199,551132246,282892517,598818617,713743768,323922897,386628568,474046790,302658513,783562521,701916176,482177632,681588349,266655423,743351863,319498248,426746288,89678205,500650748,546473898,223152283,841147627,688890488,901303731,788610629,829394955,750389455,745439788,809252095,287863106,297473389,52881575,679729868,61954094,593572313,142142337,87045414,702643022,32976555,517206126,380236389,828797589,845005051,422842060,260455358,651230866,488177154,982371716,172307030,994127208,259014259,84243868,148694890,313032650,79750143,628177536,256112757,535578122,7516872,660259410,862246837,942873362,525515969,353458202,517016061,146128173,615658629,171576507,313485249,756862637,740107237,450464972,698608957,380461701,788065795,235055502,488339779,625468897,81218153,752562624,954468821,388408427,220000770,962611398,138488797,232824743,623588948,89320450,5174417,444171924,539838147,184946963,829706030,250353513,837334003,192637869,954980409,989726944,503629638,246128748,144252879,869972346,159483785,38149548,399002531,139867042,702866700,566004753,303913805,946274118,352063038,148918236,344908939,925123896,175513960,888310551,233700316,237128991,80142095,627539989,30420961,108486126,993957197,940173780,407371015,13694119,969064311,945245210,515586500,834646464,210959252,766474958,237866830,520123316,83961446,97878509,896040082,51406202,612079312,569120595,325712093,979110226,72296197,169538467,506717757,990725778,888153398,884672580,747447278,989585067,197205447,997554253,162606658,612854211,585638351,300385030,648581707,24645691,142364491,87271224,656248353,311752536,345078260,862509279,749617553,148690167,255207879,937517648,692740850,188651194,442080602,285711119,523391595,806719830,122802835,948147156,825684063,120090726,465071065,216239633,955952822,254936196,818273287,582823720,838683603,211078726,609268949,539236132,461048619,931162689,575599737,702129707,929755292,3165024,932095281,371965629,560082406,915331279,404247953,119029625,650026279,33911127,542568006,737311646,839818392,121381063,81776121,264049814,428758250,935258956,524814024,827629225,159677867,208903802,254070037,334398982,852112879,205126265,581086872,289728727,749733927,825622969,203314518,313219470,714203321,966360246,415028559,441541100,64736522,135298651,311340818,724308321,852861846,567399501,818780718,445445536,185482874,890679335,117928565,212566203,217299615,125999181,478432188,642522487,657976604,462229383,930237021,202402571,859794210,821285303,193707191,139635308,949631508,581555701,493872210,253862710,156423352,756876608,453019810,540238248,525374182,395165149,552059946,666018027,218650948,316154754,567824223,718412883,959027290,327709825,416281152,860382344,503677292,449112827,426967024,595415467,755716122,910210918,495279146,453103898,539903326,104084806,171428406,629857538,238805628,522091539,904850095,831383119,364871289,59654563,188523918,418555114,248860166,832365397,779188603,392396445,763896392,993974548,375970645,176183947,455296206,826990889,44758036,495683674,791719842,655621264,658939366,735144599,275667277,655999018,965639168,676574799,346864447,379511514,459854791,905913554,604918364,6920002,652092992,597377405,920491194,562313297,482675638,955706031,63469748,417878805,240441437,990705174,289937758,842452102,258265727,995663867,792673745,608833565,729570088,316539671,559104003,153929272,607988017,245598088,490462484,935463414,309255995,733478384,499515550,689830722,849692817,311550442,635474783,127169195,9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main(){\n    scanf(\"%d\",&n);\n    printf(\"%d\\n\",ar[n]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "4ccb599cdcd218c202d005632d592c42", "src_uid": "aa2c3e94a44053a0d86f61da06681023", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "// Author: Param Singh <paramsingh258@gmail.com>\n// Symmetric and Transitive: http://codeforces.com/contest/568/problem/B\n\n#include <stdio.h>\n#include <stdlib.h>\n#define BIG 1000000007\n\nint main(void) {\n    int n;\n    int i, j;\n    scanf(\"%d\", &n);\n    int** dp = (int **) calloc(n+1, sizeof(int *));\n    int* eq = (int *) calloc(n, sizeof(int));\n    eq[0] = eq[1] = 1;\n    for (i = 0; i <= n; i++) {\n        dp[i] = (int *) calloc(n+1, sizeof(int));\n        if (i == 1)\n            dp[i][1] = 1;\n        else if (i != 0) {\n            for (j = 1; j <= n; j++) {\n                dp[i][j] = (dp[i-1][j-1] +(((long long)(j) * dp[i-1][j]) % BIG)) % BIG;\n                eq[i] = (eq[i] + dp[i][j]) % BIG;\n            }\n        }\n    }\n\n    int **c = (int **) calloc(n+1, sizeof(int *));\n    for (i = 0; i <= n; i++) {\n        c[i] = (int *) calloc(n+1, sizeof(int));\n        c[i][0] = 0;\n        c[i][1] = i;\n        if (i == 0)\n            continue;\n        for (j = 2; j <= n; j++) {\n            c[i][j] = (c[i-1][j-1] + c[i-1][j]) % BIG;\n        }\n    }\n\n    int ans = 0;\n    for (i = 1; i <= n; i++) {\n        int x = ((long long)(c[n][i]) * eq[n-i]) % BIG;\n        ans = (ans + x) % BIG;\n    }\n\n    printf(\"%d\\n\", ans);\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9f54c536584c57bd87e78f5213b424c2", "src_uid": "aa2c3e94a44053a0d86f61da06681023", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n\ntypedef struct node{\n        int v;\n        struct node *next;\n} NODE;\n\nchar f[100000];\n\nvoid dfs(int n, NODE *e[], char v[], int mode){\n     v[n] = 1;\n     if (!mode && f[n] == 1)return;\n     NODE *tmp = e[n];\n     while (tmp){\n           if (!v[tmp->v] && !(mode && f[tmp->v] == 1))\n              dfs(tmp->v, e, v, mode);\n           tmp = tmp->next;\n     }\n     return;\n}\n\nint main(){\n    int n, m, i, j, x, y;\n    char f1 = 0, f2 = 0, v1[100000] = {}, v2[100000] = {};\n    NODE *e[100000] = {}, *b[100000] = {}, *tmp;\n    scanf(\"%d%d\", &n, &m);\n    for (i = 0 ; i < n ; ++i){\n        scanf(\"%d\", f + i);\n        if (f[i] == 1)f1 = 1;\n        else if (f[i] == 2)f2 = 1;\n    }\n    if (!f1 || !f2){\n       while (n--)puts(\"0\");\n       return 0;\n    }\n    \n    for (i = 0 ; i < m ; ++i){\n        scanf(\"%d%d\", &x, &y);\n        --x, --y;\n        tmp = calloc(1, sizeof(NODE));\n        tmp->v = y, tmp->next = e[x], e[x] = tmp;\n        tmp = calloc(1, sizeof(NODE));\n        tmp->v = x, tmp->next = b[y], b[y] = tmp;\n    }\n    for (i = 0 ; i < n ; ++i)\n        if (f[i] == 1)\n           dfs(i, e, v1, 1);\n    for (i = 0 ; i < n ; ++i)\n        if (f[i] == 2)\n           dfs(i, b, v2, 0);\n    for (i = 0 ; i < n ; ++i)\n        printf(\"%d\\n\", v1[i] && v2[i]);\n    scanf(\" \");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a30e58b51d1c8b41a8fbde18e2f0828c", "src_uid": "87d869a0fd4a510c5e7e310886b86a57", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n\ntypedef struct node{\n        int v;\n        struct node *pre, *next;\n} NODE;\n\nint e[100000][2], v[100001] = {};\nchar s[100001] = {}, f[100001];\nNODE pre[100000] = {}, *prep[100001];\n\nint cmp(const void *a, const void *b){\n    int *x = (int*)a, *y = (int*)b;\n    if (x[0] < y[0])return -1;\n    if (x[0] > y[0])return 1;\n    if (x[1] < y[1])return -1;\n    if (x[1] > y[1])return 1;\n    return 0;\n}\n\nvoid fill(int now, NODE *prep[]){\n     do {\n        if (!prep[now]->v)return;\n        if (s[prep[now]->v])continue;\n        s[prep[now]->v] = 1;\n        fill(prep[now]->v, prep);\n     }while (prep[now]->pre && (prep[now] = prep[now]->pre));\n     return;\n}\n\nint main(){\n    int n, m, i, j;\n    char f1 = 0, f2 = 0;\n    \n    scanf(\"%d%d\", &n, &m);\n    for (i = 1 ; i <= n ; ++i){\n        scanf(\"%d\", f + i);\n        if (f[i] == 1)f1 = 1;\n        else if (f[i] == 2)f2 = 1;\n    }\n    if (!f1 || !f2){\n       while (n--)puts(\"0\");\n       return 0;\n    }\n    \n    for (i = 0 ; i < m ; ++i)\n        scanf(\"%d%d\", &e[i][0], &e[i][1]);\n    qsort(e, m, sizeof(int) * 2, cmp);\n    for (i = 0, j = 1 ; i < m ; ++i)\n        while (e[i][0] > j)v[j++] = i;\n    while (j <= n)v[j++] = m;\n    \n    for (i = 1 ; i <= n ; ++i){\n        if (f[i] != 1)continue;\n        int l, r, q[100000];\n        char c[100001] = {};\n        memset(pre, 0, sizeof(pre));\n        q[0] = i, c[i] = 1;\n        prep[i] = &pre[0];\n        for (l = 0, r = 1 ; l < r ; ++l){\n            for (j = v[q[l] - 1] ; j < v[q[l]] ; ++j){\n                if (f[e[j][1]] == 1)continue;\n                if (c[e[j][1]]){\n                   NODE *tmp = prep[e[j][1]];\n                   do {\n                      if (tmp->v == q[l])break;\n                   }while (tmp->pre && (tmp = tmp->pre));\n                   if (tmp->v == q[l])continue;\n                   prep[e[j][1]]->next = calloc(1, sizeof(NODE));\n                   prep[e[j][1]]->next->pre = prep[e[j][1]];\n                   prep[e[j][1]] = prep[e[j][1]]->next;\n                   prep[e[j][1]]->v = q[l];\n                }\n                else {\n                     c[e[j][1]] = 1;\n                     pre[r].v = q[l];\n                     prep[e[j][1]] = &pre[r];\n                     q[r++] = e[j][1];\n                }\n                if (s[e[j][1]] || f[e[j][1]] == 2){\n                   s[e[j][1]] = 1;\n                   fill(e[j][1], prep);\n                }\n            }\n        }\n    }\n    for (i = 1 ; i <= n ; ++i)\n        printf(\"%d\\n\", s[i]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dde53789451bd495e54ea6fabefe9395", "src_uid": "87d869a0fd4a510c5e7e310886b86a57", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n\ntypedef struct node{\n        int v;\n        struct node *next;\n} NODE;\n\nvoid dfs(int n, NODE *e[], char v[]){\n     NODE *tmp = e[n];\n     v[n] = 1;\n     while (tmp){\n           if (!v[tmp->v])\n              dfs(tmp->v, e, v);\n           tmp = tmp->next;\n     }\n     return;\n}\n\nint main(){\n    int n, m, i, j, x, y;\n    char f[100000], f1 = 0, f2 = 0, v1[100000] = {}, v2[100000] = {};\n    NODE *e[100000] = {}, *b[100000] = {}, *tmp;\n    scanf(\"%d%d\", &n, &m);\n    for (i = 0 ; i < n ; ++i){\n        scanf(\"%d\", f + i);\n        if (f[i] == 1)f1 = 1;\n        else if (f[i] == 2)f2 = 1;\n    }\n    if (!f1 || !f2){\n       while (n--)puts(\"0\");\n       return 0;\n    }\n    \n    for (i = 0 ; i < m ; ++i){\n        scanf(\"%d%d\", &x, &y);\n        --x, --y;\n        tmp = calloc(1, sizeof(NODE));\n        tmp->v = y, tmp->next = e[x], e[x] = tmp;\n        tmp = calloc(1, sizeof(NODE));\n        tmp->v = x, tmp->next = b[y], b[y] = tmp;\n    }\n    for (i = 0 ; i < n ; ++i)\n        if (f[i] == 1)\n           dfs(i, e, v1);\n    for (i = 0 ; i < n ; ++i)\n        if (f[i] == 2)\n           dfs(i, b, v2);\n    for (i = 0 ; i < n ; ++i)\n        printf(\"%d\\n\", v1[i] && v2[i]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c4baaa2746c6e6983611332b2c233793", "src_uid": "87d869a0fd4a510c5e7e310886b86a57", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n\ntypedef struct node{\n        int v;\n        struct node *pre, *next;\n} NODE;\n\nint e[100000][2], v[100001] = {};\nchar s[100001] = {}, f[100001];\nNODE pre[100000] = {}, *prep[100001];\n\nint cmp(const void *a, const void *b){\n    int *x = (int*)a, *y = (int*)b;\n    if (x[0] < y[0])return -1;\n    if (x[0] > y[0])return 1;\n    if (x[1] < y[1])return -1;\n    if (x[1] > y[1])return 1;\n    return 0;\n}\n\nvoid fill(int now, NODE *prep[]){\n     do {/**/printf(\" f: %d %d\\n\", now, prep[now]->v);\n        if (!prep[now]->v)return;\n        if (s[prep[now]->v])continue;\n        s[prep[now]->v] = 1;\n        fill(prep[now]->v, prep);\n     }while (prep[now]->pre && (prep[now] = prep[now]->pre));\n     return;\n}\n\nint main(){\n    int n, m, i, j;\n    char f1 = 0, f2 = 0;\n    \n    scanf(\"%d%d\", &n, &m);\n    for (i = 1 ; i <= n ; ++i){\n        scanf(\"%d\", f + i);\n        if (f[i] == 1)f1 = 1;\n        else if (f[i] == 2)f2 = 1;\n    }\n    if (!f1 || !f2){\n       while (n--)puts(\"0\");\n       return 0;\n    }\n    \n    for (i = 0 ; i < m ; ++i)\n        scanf(\"%d%d\", &e[i][0], &e[i][1]);\n    qsort(e, m, sizeof(int) * 2, cmp);\n    for (i = 0, j = 1 ; i < m ; ++i)\n        while (e[i][0] > j)v[j++] = i;\n    while (j <= n)v[j++] = m;\n    \n    for (i = 1 ; i <= n ; ++i){\n        if (f[i] != 1)continue;\n        int l, r, q[100000];\n        char c[100001] = {};\n        memset(pre, 0, sizeof(pre));\n        q[0] = i, c[i] = 1;\n        prep[i] = &pre[0];\n        for (l = 0, r = 1 ; l < r ; ++l){\n            for (j = v[q[l] - 1] ; j < v[q[l]] ; ++j){\n                if (f[e[j][1]] == 1)continue;\n                if (c[e[j][1]]){\n                   /**/printf(\"c: %d %d %d %d\\n\", l, r, e[j][0], e[j][1]);\n                   NODE *tmp = prep[e[j][1]];\n                   do {\n                      if (tmp->v == q[l])break;\n                   }while (tmp->pre && (tmp = tmp->pre));\n                   if (tmp->v == q[l])continue;\n                   prep[e[j][1]]->next = calloc(1, sizeof(NODE));\n                   prep[e[j][1]]->next->pre = prep[e[j][1]];\n                   prep[e[j][1]] = prep[e[j][1]]->next;\n                   prep[e[j][1]]->v = q[l];\n                }\n                else {\n                   /**/printf(\"d: %d %d %d %d\\n\", l, r, e[j][0], e[j][1]);\n                     c[e[j][1]] = 1;\n                     pre[r].v = q[l];\n                     prep[e[j][1]] = &pre[r];\n                     q[r++] = e[j][1];\n                }\n                if (s[e[j][1]] || f[e[j][1]] == 2){\n                  /**/printf(\"s: %d %d %d %d\\n\", l, r, e[j][0], e[j][1]);\n                   s[e[j][1]] = 1;\n                   fill(e[j][1], prep);\n                }\n            }\n        }\n    }\n    for (i = 1 ; i <= n ; ++i)\n        printf(\"%d\\n\", s[i]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "59d86f129a156cce62c0459dd555dfae", "src_uid": "87d869a0fd4a510c5e7e310886b86a57", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nchar dp[23][1 << 23];\n\nint main()\n{\n    int n, ans = 1e9, i, j, k;\n    int a[23];\n    int b[23][23] = {0};\n    \n    scanf(\"%d\", &n);\n    \n    for (i = 0; i < n; i++) scanf(\"%d\", &a[i]);\n    \n    for (i = 1; i < n; i++) {\n        int f = 0;\n        \n        for (j = 0; j < i; j++) {\n            for (k = j; k < i; k++) {\n                if (a[j] + a[k] == a[i]) {\n                    b[i][j] = 1 << k;\n                    \n                    f = 1;\n                }\n            }\n        }\n        \n        if (f == 0) {\n            puts(\"-1\");\n            \n            return 0;\n        }\n    }\n    \n    dp[0][1] = 1;\n    \n    for (i = 1; i < n; i++) {\n        for (j = 0; j < (1 << i); j++) {\n            int f = 0;\n            \n            if (dp[i - 1][j] == 0) continue;\n            \n            for (k = 0; k < i; k++) {\n                if ((j >> k) & 1) {\n                    if (j & b[i][k]) {\n                        f = 1;\n                        \n                        break;\n                    }\n                }\n            }\n            \n            if (f == 1) {\n                for (k = 0; k < i; k++) {\n                    if ((j >> k) & 1) dp[i][j ^ (1 << k) ^ (1 << i)] = 1;\n                }\n                \n                dp[i][j ^ (1 << i)] = 1;\n            }\n        }\n    }\n    \n    for (i = 0; i < (1 << n); i++) {\n        if (dp[n - 1][i] == 1) {\n            int c = 0;\n            \n            for (j = 0; j < n; j++) {\n                if ((i >> j) & 1) c++;\n            }\n            \n            if (c < ans) ans = c;\n        }\n    }\n    \n    printf(\"%d\\n\", ans);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e8f55fb872973cb40fc7fce5b16c5226", "src_uid": "359f5d1264ce16c5c5293fd59db95628", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define N\t23\n#define A\t4194304\n\nint bcnt(int b) {\n\treturn b == 0 ? 0 : 1 + bcnt(b & (b - 1));\n}\n\nint main() {\n\tstatic int aa[N];\n\tstatic char ii[A + 1], dp[(1 << N) - 1];\n\tint n, i, i_, a, b, b_, j, min, good;\n\n\tscanf(\"%d\", &n);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d\", &aa[i]);\n\tfor (i = 0; i < n; i++)\n\t\tif (aa[i] % aa[0] != 0) {\n\t\t\tprintf(\"-1\\n\");\n\t\t\treturn 0;\n\t\t}\n\tfor (i = 1; i < n; i++)\n\t\taa[i] /= aa[0];\n\taa[0] = 1;\n\tfor (a = 0; a <= A; a++)\n\t\tii[a] = -1;\n\tfor (i = 0; i < n; i++) {\n\t\tif (aa[i] > A) {\n\t\t\tprintf(\"-1\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\tii[aa[i]] = i;\n\t}\n\tmin = n + 1;\n\tdp[1] = 1;\n\tfor (b = 1, j = 0; b < 1 << n; b++) {\n\t\tif (1 << (j + 1) == b)\n\t\t\tj++;\n\t\tif (dp[b]) {\n\t\t\tif (j == n - 1) {\n\t\t\t\tif (min > bcnt(b))\n\t\t\t\t\tmin = bcnt(b);\n\t\t\t} else {\n\t\t\t\tgood = 0;\n\t\t\t\tfor (i = 0; i <= j; i++)\n\t\t\t\t\tif (aa[i] <= aa[j + 1] && (i_ = ii[aa[j + 1] - aa[i]]) != -1\n\t\t\t\t\t\t\t&& (b & 1 << i) > 0 && (b & 1 << i_) > 0) {\n\t\t\t\t\t\tgood = 1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\tif (good) {\n\t\t\t\t\tb_ = (b | 1 << (j + 1));\n\t\t\t\t\tdp[b_] = 1;\n\t\t\t\t\tfor (i = 0; i <= j; i++)\n\t\t\t\t\t\tif ((b & 1 << i) > 0)\n\t\t\t\t\t\t\tdp[b_ ^ 1 << i] = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\", min == n + 1 ? -1 : min);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e0b00879d907993edaaa2fedcab21a84", "src_uid": "359f5d1264ce16c5c5293fd59db95628", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define N\t23\n#define A 4194304\n\nint bcnt(int b) {\n\treturn b == 0 ? 0 : 1 + bcnt(b & (b - 1));\n}\n\nint main() {\n\tstatic int aa[N];\n\tstatic char ii[A + 1], dp[(1 << N) - 1];\n\tint n, i, i_, a, b, b_, j, min, good;\n\n\tscanf(\"%d\", &n);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d\", &aa[i]);\n\tfor (i = 0; i < n; i++)\n\t\tif (aa[i] % aa[0] != 0) {\n\t\t\tprintf(\"-1\\n\");\n\t\t\treturn 0;\n\t\t}\n\tfor (i = 1; i < n; i++)\n\t\taa[i] /= aa[0];\n\taa[0] = 1;\n\tfor (a = 0; a <= A; a++)\n\t\tii[a] = -1;\n\tfor (i = 0; i < n; i++) {\n\t\tif (aa[i] > A) {\n\t\t\tprintf(\"-1\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\tii[aa[i]] = i;\n\t}\n\tmin = n + 1;\n\tdp[1] = 1;\n\tfor (b = 1, j = 0; b < 1 << n; b++) {\n\t\tif (1 << (j + 1) == b)\n\t\t\tj++;\n\t\tif (dp[b]) {\n\t\t\tif (j == n - 1) {\n\t\t\t\tif (min > bcnt(b))\n\t\t\t\t\tmin = bcnt(b);\n\t\t\t} else {\n\t\t\t\tgood = 0;\n\t\t\t\tfor (i = 0; i <= j; i++)\n\t\t\t\t\tif (aa[i] <= aa[j + 1] && (i_ = ii[aa[j + 1] - aa[i]]) != -1\n\t\t\t\t\t\t\t&& (b & 1 << i) > 0 && (b & 1 << i_) > 0) {\n\t\t\t\t\t\tgood = 1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\tif (good) {\n\t\t\t\t\tb_ = (b | 1 << (j + 1));\n\t\t\t\t\tdp[b_] = 1;\n\t\t\t\t\tfor (i = 0; i <= j; i++)\n\t\t\t\t\t\tif ((b & 1 << i) > 0)\n\t\t\t\t\t\t\tdp[b_ ^ 1 << i] = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\", min == n + 1 ? -1 : min);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2df01a7f7186f15fb2e5ca5f5be7e5a5", "src_uid": "359f5d1264ce16c5c5293fd59db95628", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint dp[23][1 << 23];\n\nint main()\n{\n    int n, ans = 1e9, i, j, k;\n    int a[23];\n    int b[23][23] = {0};\n    \n    scanf(\"%d\", &n);\n    \n    for (i = 0; i < n; i++) scanf(\"%d\", &a[i]);\n    \n    for (i = 1; i < n; i++) {\n        int f = 0;\n        \n        for (j = 0; j < i; j++) {\n            for (k = j; k < i; k++) {\n                if (a[j] + a[k] == a[i]) {\n                    b[i][j] = 1 << k;\n                    \n                    f = 1;\n                }\n            }\n        }\n        \n        if (f == 0) {\n            puts(\"-1\");\n            \n            return 0;\n        }\n    }\n    \n    dp[0][1] = 1;\n    \n    for (i = 1; i < n; i++) {\n        for (j = 0; j < (1 << i); j++) {\n            int f = 0;\n            \n            if (dp[i - 1][j] == 0) continue;\n            \n            for (k = 0; k < i; k++) {\n                if ((j >> k) & 1) {\n                    if (j & b[i][k]) {\n                        f = 1;\n                        \n                        break;\n                    }\n                }\n            }\n            \n            if (f == 1) {\n                for (k = 0; k < i; k++) {\n                    if ((j >> k) & 1) dp[i][j ^ (1 << k) ^ (1 << i)] = 1;\n                }\n                \n                dp[i][j ^ (1 << i)] = 1;\n            }\n        }\n    }\n    \n    for (i = 0; i < (1 << n); i++) {\n        if (dp[n - 1][i] == 1) {\n            int c = 0;\n            \n            for (j = 0; j < n; j++) {\n                if ((i >> j) & 1) c++;\n            }\n            \n            if (c < ans) ans = c;\n        }\n    }\n    \n    printf(\"%d\\n\", ans);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4cb356f0e8701667d4adbe7ca4a4417e", "src_uid": "359f5d1264ce16c5c5293fd59db95628", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n=0,i=0,j=0,book[81]={0},max=0,now[81]={0},money=0,number=0,de=0;\n    scanf(\"%d %d\",&n,&max);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%d\",&book[i]);\n        if(now[book[i]]==0 && number<max)\n        {\n            now[book[i]]=1;\n            money++;\n            number++;\n        }\n        else if(now[book[i]]==0 && number==max)\n        {\n            for(j=i;j<n;j++)\n            {\n                if(now[book[j]]==1)\n                    de=book[j];\n            }\n            now[de]=0;\n            now[book[i]]=1;\n            money++;\n        }\n    }\n    printf(\"%d\\n\",money);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "00eb7c778e8f013e508c83477ee45db5", "src_uid": "956228e31679caa9952b216e010f9773", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n=0,i=0,j=0,book[81]={0},max=0,now[81]={0},money=0,number=0,de=0,k=0,chose=0;\n    scanf(\"%d %d\",&n,&max);\n    for(i=0;i<n;i++)\n        scanf(\"%d\",&book[i]);\n    for(i=0;i<n;i++)\n    {\n        if(now[book[i]]==0 && number<max)\n        {\n            now[book[i]]=1;\n            money++;\n            number++;\n        }\n        else if(now[book[i]]==0 && number==max)\n        {\n            for(j=i;j<n;j++)\n            {\n                if(now[book[j]]==1)\n                    de=book[j];\n            }\n            for(j=0;j<81;j++)\n            {\n                chose=0;\n                if(now[j]==1)\n                {\n                    //but=now[j];\n                    for(k=i;k<n;k++)\n                    {\n                        if(j==book[k])\n                            chose=1;\n                    }\n                    if(chose==0)\n                        de=j;\n                }\n\n            }\n            now[de]=0;\n            now[book[i]]=1;\n            money++;\n        }\n    }\n    printf(\"%d\\n\",money);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "acedfa8b654295c3f88aa37fc3a4a700", "src_uid": "956228e31679caa9952b216e010f9773", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n=0,i=0,j=0,book[81]={0},max=0,now[81]={0},money=0,number=0,de=0;\n    scanf(\"%d %d\",&n,&max);\n    for(i=0;i<n;i++)\n        scanf(\"%d\",&book[i]);\n    for(i=0;i<n;i++)\n    {\n        if(now[book[i]]==0 && number<max)\n        {\n            now[book[i]]=1;\n            money++;\n            number++;\n        }\n        else if(now[book[i]]==0 && number==max)\n        {\n            for(j=i;j<n;j++)\n            {\n                if(now[book[j]]==1)\n                    de=book[j];\n            }\n            now[de]=0;\n            now[book[i]]=1;\n            money++;\n        }\n    }\n    printf(\"%d\\n\",money);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4840a31e9069d9664a585ed35609a768", "src_uid": "956228e31679caa9952b216e010f9773", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main(){\n    int i,j,n,m,k,stock[81]={0},temp=0,count=0,ans = 0, a[81],check[81]={0};\n    scanf(\"%d %d\",&n ,&k);\n    for(j=1;j<=n;j++)\n        scanf(\"%d\",&a[j]);\n    stock[a[1]]++;\n    ans++;\n    count++;\n    for(j=2;j<=n;j++){\n        if(stock[a[j]] == 1) continue;\n        if(count == k){\n            for(i=0; i<81; i++)\n                check[i] = 0;\n            temp = count;\n            for(i=j+1; i<=n; i++){\n                if(temp == 1){\n                    for(m=1; m<81; m++)\n                        if(check[m] == 0 && stock[m] == 1){\n                            stock[m] = 0;\n                            count--;\n                            break;\n                        }\n                    break;\n                }\n                if(stock[a[i]] == 1 && check[a[i]] == 0){\n                    temp--;\n                    check[a[i]] = 1;\n                }\n            }\n\n                for(m=1; m<81; m++)\n                    if(check[m] == 0 && stock[m] == 1){\n                        stock[m] = 0;\n                        count--;\n                    }\n\n        }\n        stock[a[j]] = 1;\n        count++;\n        ans++;\n        /*printf(\"%d\\t\",ans);\n        for(i=0; i<81;i++)\n            if(stock[i]) printf(\"%d \",i);\n        printf(\"\\n\");*/\n    }\n    printf(\"%d\\n\",ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8b82ed11c27a6b0e317e3c17ce0f2965", "src_uid": "956228e31679caa9952b216e010f9773", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main()\n{\n    int n=0,i=0,j=0,book[81]={0},max=0,now[81]={0},time[81]={0},money=0,number=0,de=0,k=0,chose=0;\n    scanf(\"%d %d\",&n,&max);\n    for(i=0;i<n;i++)\n        scanf(\"%d\",&book[i]);\n    for(i=0;i<n;i++)\n    {\n        if(now[book[i]]==0 && number<max)\n        {\n            now[book[i]]=1;\n            money++;\n            number++;\n        }\n        else if(now[book[i]]==0 && number==max)\n        {\n            for(j=0;j<81;j++)\n                time[j]=0;\n            for(j=i;j<n;j++)\n            {\n                if(now[book[j]]==1 && time[book[j]]==0)\n                {\n                    time[book[j]]=1;\n                    de=book[j];\n                }\n            }\n            for(j=0;j<81;j++)\n            {\n                chose=0;\n                if(now[j]==1)\n                {\n                    //but=now[j];\n                    for(k=i;k<n;k++)\n                    {\n                        if(j==book[k])\n                            chose=1;\n                    }\n                    if(chose==0)\n                        de=j;\n                }\n\n            }\n            now[de]=0;\n            now[book[i]]=1;\n            money++;\n        }\n    }\n    printf(\"%d\\n\",money);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "aedac580bc17e3f4276a8058019c7c28", "src_uid": "956228e31679caa9952b216e010f9773", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MAXN 53\n#define MAXW 500003\nint dp[MAXW]={1};\nint n,d,c[MAXN];\nint ans,day;\n\nint main()\n{\n\tint i,j,k,sum=0;\n\n\tscanf(\"%d%d\",&n,&d);\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%d\",&c[i]);\n\t\tsum+=c[i];\n\t\tfor(j=sum,k=sum-c[i];j>=c[i];j--,k--)\n\t\t\tif(dp[j]==0 && dp[k]==1)dp[j]=1;\n\t}\n\n\tans=day=0;\n\twhile(1)\n\t{\n\t\ti=ans+d;\n\t\tif(i>sum)i=sum;\n\t\tfor(;i>ans;i--)\n\t\t{\n\t\t\t//printf(\"now i %d %d\\n\",ans,i);\n\t\t\tif(dp[i]==1)break;\n\t\t}\n\t\tif(i==ans)break;\n\t\tans=i;\n\t\t++day;\n\t}\n\tprintf(\"%d %d\\n\",ans,day);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "77fa672119769d7abd24fb6af8889e5d", "src_uid": "65699ddec8d0db2f58b83a0f64de6f6f", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint a[60];\nint dp[500100];\nint ans[500100];\nint main(void)\n{\n\tint n ,d;\n\tint i ,j;\n\tint sum;\n\tint aa;\n\tint p ,pans;\n\tint k;\n\t\n\twhile (scanf(\"%d %d\" ,&n ,&d)!=EOF)\n\t{\n\t\tsum=0;\n\t\tfor (i=1 ; i<=n ; i++)\t\n\t\t{\n\t\t\tscanf(\"%d\" ,&a[i]);\n\t\t\tsum+=a[i];\n\t\t}\n\t\tfor (j=1 ; j<=sum ; j++)\n\t\t{\n\t\t\tdp[j]=0;\t\n\t\t\tans[j]=0;\n\t\t}\n\t\tdp[0]=1;\n\t\tfor (i=1 ; i<=n ; i++)\n\t\t{\n\t\t\taa=a[i];\n\t\t\tfor (j=sum-aa ; j>=0 ; j--)\n\t\t\t{\n\t\t\t\tif (dp[j])\n\t\t\t\t{\n\t\t\t\t\tdp[j+aa]=1;\n\t\t\t\t}\t\n\t\t\t}\n\t\t}\t\t\n\t\tans[0]=1;\n\t\tp=0;\n\t\tpans=2;\n\t\tfor (i=1 ; i<=sum ; i++)\n\t\t{\n\t\t\tif (dp[i])\n\t\t\t{\n\t\t\t\tk=i-d;\n\t\t\t\tif (k<=p)\n\t\t\t\t{\n\t\t\t\t\tans[i]=pans;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tfor (j=k ; j<i ; j++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (ans[j])\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tans[i]=ans[j]+1;\n\t\t\t\t\t\t\tp=j;\n\t\t\t\t\t\t\tpans=ans[j]+1;\n\t\t\t\t\t\t\tbreak;\t\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif (j==i)\t\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\t\n\t\t\t\t\t}\t\t\t\t\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (i=sum ; i ; i--)\n\t\t{\n\t\t\tif (ans[i])\t\n\t\t\t{\n\t\t\t\tbreak;\t\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d %d\\n\" ,i ,ans[i]-1);\n\t}\n\t\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1d5e8e53abf0c2930d6a15394169b5bc", "src_uid": "65699ddec8d0db2f58b83a0f64de6f6f", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint dp[51*10010];\nint main()\n{\n    int n,d,i,x,sum,ans,ans1,j;\n    scanf(\"%d%d\",&n,&d);\n        sum=0;\n        dp[0]=1;\n        for(i=0;i<n;i++){\n            scanf(\"%d\",&x);\n            sum+=x;\n            for(j=sum;j>=x;j--){\n                if(dp[j-x])\n                    dp[j]=1;\n            }\n        }\n        ans=ans1=0;\n        while(1)\n        {\n            j=ans+d;\n            while(j>ans&&!dp[j])\n                j--;\n            if(j==ans)\n                break;\n            ans=j;\n            ans1++;\n        }\n        printf(\"%d %d\\n\",ans,ans1);\n    \n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "05a2261fdf029118f4246dbd94723aea", "src_uid": "65699ddec8d0db2f58b83a0f64de6f6f", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint a[60];\nint z[60];\nint dp0[500100] ,la0[500100];\nint dp1[500100] ,la1[500100];\nint main(void)\n{\n\tint n ,d;\n\tint ans1 ,ans2;\n\tint sum;\n\tint i ,j ,j2;\n\tint aa;\n\tint gg;\n\t\n\twhile (scanf(\"%d %d\" ,&n ,&d)!=EOF)\n\t{\n\t\tsum=0;\n\t\tfor (i=1 ; i<=n ; i++)\t\n\t\t{\n\t\t\tscanf(\"%d\" ,&a[i]);\n\t\t\tsum+=a[i];\n\t\t\tz[i]=1;\n\t\t}\n\t\tans1=0;\n\t\tans2=0;\n\t\twhile (1)\n\t\t{\n\t\t\tfor (j=1 ; j<=sum ; j++)\n\t\t\t{\n\t\t\t\tdp1[j]=0;\t\n\t\t\t}\n\t\t\tdp1[0]=-1;\n\t\t\tfor (i=1 ; i<=n ; i++)\n\t\t\t{\n\t\t\t\tif (z[i])\n\t\t\t\t{\n\t\t\t\t\taa=a[i];\n\t\t\t\t\tfor (j=sum-aa ; j>=0 ; j--)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (dp1[j])\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tif (!dp1[j+aa])\t\n\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\tdp1[j+aa]=i;\n\t\t\t\t\t\t\t\tla1[j+aa]=j;\t\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\t\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor (j=1 ; j<=sum ; j++)\n\t\t\t{\n\t\t\t\tdp0[j]=0;\t\n\t\t\t}\n\t\t\tdp0[0]=-1;\n\t\t\tfor (i=1 ; i<=n ; i++)\n\t\t\t{\n\t\t\t\tif (!z[i])\n\t\t\t\t{\n\t\t\t\t\taa=a[i];\n\t\t\t\t\tfor (j=sum-aa ; j>=0 ; j--)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (dp0[j])\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tif (!dp0[j+aa])\t\n\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\tdp0[j+aa]=i;\n\t\t\t\t\t\t\t\tla0[j+aa]=j;\t\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\t\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\t\t\n\t\t\tgg=ans1;\t\n\t\t\tfor (i=ans1+d ; i ; i--)\n\t\t\t{\n\t\t\t\tif (i>sum)continue;\n\t\t\t\tif (dp1[i])\n\t\t\t\t{\n\t\t\t\t\tfor (j=i-d ;; j++)\t\n\t\t\t\t\t{\n\t\t\t\t\t\tif (j>=0)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tif (dp0[j])\n\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n//\t\t\t\t\tprintf(\"%d %d %d\\n%d %d %d %d\\n%d %d\\n\" ,ans1 ,i ,j ,dp1[1] ,dp1[2] ,dp1[3] ,dp1[4] ,z[1] ,z[2]);\t\t\t\t\t\n\t\t\t\t\tans1+=(i-j);\n\t\t\t\t\tans2++;\n\t\t\t\t\tj2=i;\n\t\t\t\t\twhile (dp1[j2]!=-1) \n\t\t\t\t\t{\n\t\t\t\t\t\tz[dp1[j2]]=0;\n\t\t\t\t\t\tj2=la1[j2];\t\n\t\t\t\t\t}\n\t\t\t\t\tj2=j;\n\t\t\t\t\twhile (dp0[j2]!=-1) \n\t\t\t\t\t{\n\t\t\t\t\t\tz[dp0[j2]]=1;\n\t\t\t\t\t\tj2=la0[j2];\t\n\t\t\t\t\t}\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (ans1==gg)\n\t\t\t{\n\t\t\t\tbreak;\t\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d %d\\n\" ,ans1 ,ans2);\n\t}\n\t\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "07627a69bd7b80a95f975d98364bd2fa", "src_uid": "65699ddec8d0db2f58b83a0f64de6f6f", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint a[60];\nint z[60];\nint dp0[500100] ,la0[500100];\nint dp1[500100] ,la1[500100];\nint main(void)\n{\n\tint n ,d;\n\tint ans1 ,ans2;\n\tint sum;\n\tint i ,j ,j2;\n\tint aa;\n\tint gg;\n\t\n\twhile (scanf(\"%d %d\" ,&n ,&d)!=EOF)\n\t{\n\t\tsum=0;\n\t\tfor (i=1 ; i<=n ; i++)\t\n\t\t{\n\t\t\tscanf(\"%d\" ,&a[i]);\n\t\t\tsum+=a[i];\n\t\t\tz[i]=1;\n\t\t}\n\t\tans1=0;\n\t\tans2=0;\n\t\twhile (1)\n\t\t{\n\t\t\tfor (j=1 ; j<=sum ; j++)\n\t\t\t{\n\t\t\t\tdp1[j]=0;\t\n\t\t\t}\n\t\t\tdp1[0]=-1;\n\t\t\tfor (i=1 ; i<=n ; i++)\n\t\t\t{\n\t\t\t\tif (z[i])\n\t\t\t\t{\n\t\t\t\t\taa=a[i];\n\t\t\t\t\tfor (j=sum-aa ; j>=0 ; j--)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (dp1[j])\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tif (!dp1[j+aa])\t\n\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\tdp1[j+aa]=i;\n\t\t\t\t\t\t\t\tla1[j+aa]=j;\t\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\t\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor (j=1 ; j<=sum ; j++)\n\t\t\t{\n\t\t\t\tdp0[j]=0;\t\n\t\t\t}\n\t\t\tdp0[0]=-1;\n\t\t\tfor (i=1 ; i<=n ; i++)\n\t\t\t{\n\t\t\t\tif (!z[i])\n\t\t\t\t{\n\t\t\t\t\taa=a[i];\n\t\t\t\t\tfor (j=sum-aa ; j>=0 ; j--)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (dp0[j])\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tif (!dp0[j+aa])\t\n\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\tdp0[j+aa]=i;\n\t\t\t\t\t\t\t\tla0[j+aa]=j;\t\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\t\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\t\t\n\t\t\tgg=ans1;\t\n\t\t\tfor (i=ans1+d ; i ; i--)\n\t\t\t{\n\t\t\t\tif (i>sum)continue;\n\t\t\t\tif (dp1[i])\n\t\t\t\t{\n\t\t\t\t\tfor (j=i-d ;; j++)\t\n\t\t\t\t\t{\n\t\t\t\t\t\tif (j>=0)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tif (dp0[j])\n\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif (j>i)\n\t\t\t\t\t{\n\t\t\t\t\t\tcontinue;\t\n\t\t\t\t\t}\n//\t\t\t\t\tprintf(\"%d %d %d\\n%d %d %d %d\\n%d %d\\n\" ,ans1 ,i ,j ,dp1[1] ,dp1[2] ,dp1[3] ,dp1[4] ,z[1] ,z[2]);\t\t\t\t\t\n\t\t\t\t\tans1+=(i-j);\n\t\t\t\t\tans2++;\n\t\t\t\t\tj2=i;\n\t\t\t\t\twhile (dp1[j2]!=-1) \n\t\t\t\t\t{\n\t\t\t\t\t\tz[dp1[j2]]=0;\n\t\t\t\t\t\tj2=la1[j2];\t\n\t\t\t\t\t}\n\t\t\t\t\tj2=j;\n\t\t\t\t\twhile (dp0[j2]!=-1) \n\t\t\t\t\t{\n\t\t\t\t\t\tz[dp0[j2]]=1;\n\t\t\t\t\t\tj2=la0[j2];\t\n\t\t\t\t\t}\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n//\t\t\tprintf(\"%d %d %d %d\\n\" ,ans1 ,z[1] ,z[2] ,z[3]);\n\t\t\tif (ans1==gg)\n\t\t\t{\n\t\t\t\tbreak;\t\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d %d\\n\" ,ans1 ,ans2);\n\t}\n\t\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8993a83e2e9efaa5d6eadf886d913e88", "src_uid": "65699ddec8d0db2f58b83a0f64de6f6f", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint n,x,y,k;\n\nlong long min(long long a,long long b)\n{\n     return (a<b)?a:b;\n}\n\nlong long square(long long a,long long b,long long m)\n{\n     long long t;\n     \n     if(a==m)\n      if(b==m)\n        return m*(m-1)/2;\n        else return (m-b-1)*b+b*(b+1)/2;\n      else\n        if(b==m)\n          return (m-a-1)*a+a*(a+1)/2;\n          else\n            {\n              t=a+b-m;\n              if(t>0)\n                return a*b-t*(t+1)/2;\n                else return a*b;\n            }\n}\n\nint check(int nn,int xx,int yy,int kk,int mm)\n{\n    long long left,right,down,up;\n    long long n=(long long)nn,x=(long long)xx,y=(long long)yy,k=(long long)kk,m=(long long)mm;\n    long long sum=0;\n    \n    left=min(m,x-1);\n    right=min(m,n-x);\n    down=min(m,y-1);\n    up=min(m,n-y);\n    \n    sum=left+right+up+down+1;\n    \n    sum+=square(left,down,m);\n    sum+=square(left,up,m);\n    sum+=square(right,down,m);\n    sum+=square(right,up,m);\n    \n    if(sum>=k)\n      return 1;\n      else return 0;\n}\n\nint erfen(int a,int b)\n{\n    int mid;\n    \n    if(a==b)\n      return a;\n    \n    mid=(a+b)/2;\n    if(check(n,x,y,k,mid))\n      return erfen(a,mid);\n      else return erfen(mid+1,b);\n}\n\nint main()\n{\n    scanf(\"%d%d%d%d\",&n,&x,&y,&k);\n    \n    printf(\"%d\\n\",erfen(0,k));\n    \n    //system(\"pause\");\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c16ed135e76ef4f020ffe474f1c34c12", "src_uid": "232c5206ee7c1903556c3625e0b0efc6", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long min(long long a, long long b)\n{\n    if (a < b) {\n        return a;\n    } else {\n        return b;\n    }\n}\n\nint main()\n{\n    int n, x, y, c;\n    long long l, r, m;\n    \n    scanf(\"%d %d %d %d\", &n, &x, &y, &c);\n    \n    x--;\n    y--;\n    \n    l = -1;\n    r = n * 2;\n    m = (l + r) / 2;\n    \n    while (r - l > 1) {\n        long long sum = m * m * 2 + m * 2 + 1;\n        \n        if (x < m) sum -= (m - x) * (m - x);\n        if (y < m) sum -= (m - y) * (m - y);\n        if (n - x - 1 < m) sum -= (m - n + x + 1) * (m - n + x + 1);\n        if (n - y - 1 < m) sum -= (m - n + y + 1) * (m - n + y + 1);\n        \n        if (m - x - y - 1 > 0) {\n            long long z = m - x - y - 1;\n            \n            sum += z * (z + 1) / 2;\n        }\n        \n        if (m - x - n + y > 0) {\n            long long z = m - x - n + y;\n            \n            sum += z * (z + 1) / 2;\n        }\n        \n        if (m - y - n + x > 0) {\n            long long z = m - y - n + x;\n            \n            sum += z * (z + 1) / 2;\n        }\n        \n        if (m + x + y - n * 2 + 1 > 0) {\n            long long z = m + x + y - n * 2 + 1;\n            \n            sum += z * (z + 1) / 2;\n        }\n        \n        if (sum >= c) {\n            r = m;\n            m = (l + r) / 2;\n        } else {\n            l = m;\n            m = (l + r) / 2;\n        }\n    }\n    \n    printf(\"%d\\n\", r);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0022e09c1a0c9a9ec2775aca027fcf25", "src_uid": "232c5206ee7c1903556c3625e0b0efc6", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define max(a,b) ((a)>(b)?(a):(b))\n#define min(a,b) ((a)<(b)?(a):(b))\nint main()\n{\n\tint now=1,tt=0,n,x,y,c;\n\tscanf(\"%d%d%d%d\",&n,&x,&y,&c);\n\twhile(now<c)\n\t{\n\t\ttt++;\n\t\tint l=min(x-1,tt);\n\t\tnow+=max(l-max((y+tt-n),0)+1,0)+max(l-max((tt-y+1),0)+1,0)-(l==tt);\n\t\tl=min(n-x,tt);\n\t\tnow+=max(l-max((y+tt-n),1)+1,0)+max(l-max((tt-y+1),1)+1,0)-(l==tt);\n\t}\n\tprintf(\"%d\\n\",tt);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "04b3f78dbb862468021f8eb0cc179992", "src_uid": "232c5206ee7c1903556c3625e0b0efc6", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long min(long long a, long long b)\n{\n    if (a < b) {\n        return a;\n    } else {\n        return b;\n    }\n}\n\nint main()\n{\n    int n, x, y, c;\n    long long l, r, m;\n    \n    scanf(\"%d %d %d %d\", &n, &x, &y, &c);\n    \n    x--;\n    y--;\n    \n    l = -1;\n    r = n * 2;\n    m = (l + r) / 2;\n    \n    while (r - l > 1) {\n        long long sum = m * m * 2 + m * 2 + 1;\n        \n        if (x < m) sum -= (m - x) * (m - x);\n        if (y < m) sum -= (m - y) * (m - y);\n        if (n - x - 1 < m) sum -= (m - n + x + 1) * (m - n + x + 1);\n        if (n - y - 1 < m) sum -= (m - n + y + 1) * (m - n + y + 1);\n        \n        if (m - x - y - 1 > 0) {\n            long long z = m - x - y - 1;\n            \n            sum += z * (z + 1) / 2;\n        }\n        \n        if (m - x - n + y > 0) {\n            long long z = m - x - n + y;\n            \n            sum += z * (z + 1) / 2;\n        }\n        \n        if (m - y - n + x > 0) {\n            long long z = m - y - n + x;\n            \n            sum += z * (z + 1) / 2;\n        }\n        \n        if (m + x + y - n * 2 + 1 > 0) {\n            long long z = m + x + y - n * 2 + 1;\n            \n            sum += z * (z + 1) / 2;\n        }\n        \n        if (sum >= c) {\n            r = m;\n            m = (l + r) / 2;\n        } else {\n            l = m;\n            m = (l + r) / 2;\n        }\n    }\n    \n    printf(\"%d\\n\", r);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1aef5df7189cf2cc9aa36293cbe6a9de", "src_uid": "232c5206ee7c1903556c3625e0b0efc6", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\nlong long count(int n, int x, int y, int r) {\n\tlong long a = 2LL * r * r + 2 * r + 1;\n\tint w;\n\n\tif ((w = 1 - (x - r)) > 0)\n\t\ta -= (long long) w * w;\n\tif ((w = 1 - (y - r)) > 0)\n\t\ta -= (long long) w * w;\n\tif ((w = (x + r) - n) > 0)\n\t\ta -= (long long) w * w;\n\tif ((w = (y + r) - n) > 0)\n\t\ta -= (long long) w * w;\n\tif ((w = r - 1 - (x - 1) - (y - 1)) > 0)\n\t\ta += (long long) w * (w + 1) / 2;\n\tif ((w = r - 1 - (x - 1) - (n - y)) > 0)\n\t\ta += (long long) w * (w + 1) / 2;\n\tif ((w = r - 1 - (n - x) - (y - 1)) > 0)\n\t\ta += (long long) w * (w + 1) / 2;\n\tif ((w = r - 1 - (n - x) - (n - y)) > 0)\n\t\ta += (long long) w * (w + 1) / 2;\n\treturn a;\n}\n\nint main() {\n\tint n, x, y, c, lower, upper, r;\n\n\tscanf(\"%d%d%d%d\", &n, &x, &y, &c);\n\tlower = -1, upper = c;\n\twhile (upper - lower > 1) {\n\t\tr = (lower + upper) / 2;\n\t\tif (count(n, x, y, r) >= c)\n\t\t\tupper = r;\n\t\telse\n\t\t\tlower = r;\n\t}\n\tprintf(\"%d\\n\", upper);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4d7cfe3bbcfc3823957ca7968b73e467", "src_uid": "232c5206ee7c1903556c3625e0b0efc6", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n\n{\n    int n,a,b,c,i,count=0,j,k;\n    scanf(\"%d%d%d%d\",&n,&a,&b,&c);\n    if(2*c>n)c=n/2;\n    if(b>n)b=n;\n    if(c/2>n)c=2*n;\n    for(i=c;i>=0;i--)\n    {\n        if(2*i==n){count++;\n        continue;\n        }\n        for(j=b;j>=0;j--)\n        {\n            if(2*i+j==n)\n            {\n                count++;\n                continue;\n            }\n            k=2*n-4*i-2*j;\n            if(0<=k &&k<=a)count++;\n        }\n\n    }printf(\"%d\",count);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0a87ef810db63f2e163901d8454a87f9", "src_uid": "474e527d41040446a18186596e8bdd83", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n\n{\n    int n,a,b,c,i,count=0,j,k;\n    scanf(\"%d%d%d%d\",&n,&a,&b,&c);\n    for(i=c;i>=0;i--)\n    {\n        if(2*i==n){count++;\n        continue;\n        }\n        for(j=b;j>=0;j--)\n        {\n            if(2*i+j==n)\n            {\n                count++;\n                continue;\n            }\n            for(k=0;k<=a;k+=2)\n            {\n                if(2*i+j+(k/2)==n)count++;\n            }\n        }\n\n    }printf(\"%d\",count);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "039877eba897a4dbba2f73bd7ae66626", "src_uid": "474e527d41040446a18186596e8bdd83", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "// Cola\n\n#include <stdio.h>\n#include <string.h>\n\n#define ll long long\n\nint count[20000];\n\nvoid deal(int n, int a, int b, int c)\n{\n    int i, j;\n    ll ans = 0;\n    memset(count, 0, sizeof(count));\n    for (i = 0; i <= b; i++)\n    {\n        for (j = 0; j <= c; j++)\n        {\n            count[i + 2 * j]++;\n        }\n    }\n    for (i = 0; i <= a; i += 2)\n    {\n        ans += count[n - i / 2];\n    }\n    printf(\"%lld\\n\", ans);\n}\n\nint main(int argc, char **argv)\n{\n    int a, b, c, n;\n    while (scanf(\"%d%d%d%d\", &n, &a, &b, &c) == 4)\n    {\n        deal(n, a, b, c);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "557b630e7ac00a97ba22f050af4f3af5", "src_uid": "474e527d41040446a18186596e8bdd83", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\n\n    int n,a,b,c,sum;\n    scanf(\"%d%d%d%d\",&n,&a,&b,&c);\n    int count =0;\n    int i,j;\n    for(i=0;i<=a;i++)\n    {\n        if(i%2)\n            continue;\n        for(j=0;j<=b;j++)\n        {\n            sum=0;\n            sum=(n)-(int)(i*0.5)-(j*1);\n            if((sum%2 ==0)&&((sum/2)<=c))\n                count++;\n        }\n    }\n    printf(\"%d\",count);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5d2d1bebc0eba0c2ec704572b57eed7b", "src_uid": "474e527d41040446a18186596e8bdd83", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n\tint n,p,q,r,b,c,s=0,a,i,j,k;\n\tdouble u,m,w,l,t;\n\tscanf(\"%d %d %d %d\",&n,&p,&q,&r);\n\tfor (i=0;i<=p;i++){\n\t\tfor (j=0;j<=q;j++){\n\t\t\tm=0.5*i+j;\n\t\t\tt=n-m;\n\t\t\ta=(int)t;\n\t\t\tif (t-a==0){\n\t\t\t\tif (a%2==0 && (a/2)<=r){\n\t\t\t\t\ts=s+1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\",s);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a5818b6bfaa9289a5d415d1b781cda7b", "src_uid": "474e527d41040446a18186596e8bdd83", "difficulty": 1500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define M 1000000007\n\nint n,k,i,c,d;\nlong long y,z,u,v,r;\nint F(int a,int b){\n    int r=1;\n    for (;b;b>>=1,a=(long long)a*a%M){\n        if (b&1)r=(long long)r*a%M;\n    }\n    return r;\n}\nint main(){\n    scanf(\"%d%d\",&n,&k);\n    if (!k)r=n;\n    else{\n        if (n<=++k){\n            for(i=1;i<=n;i++)r+=F(i,k-1);\n        }\n        else{\n            for (u=v=1;i<=k;i++){\n                u=(u*(n-i))%M;\n                if (i)v=((v*-i)%M+M)%M;\n            }\n            for (i=0,c=1,d=k;i<=k;i++,c++,d--){\n                z=(z+F(i,k-1))%M;\n                y=u*z%M*F(n-i,M-2)%M*F(v,M-2)%M;\n                v=v*c%M*F(d,M-2)%M;\n                if(i&1)y=M-y;\n                r+=y;\n            }\n        }\n    }\n    printf(\"%lld\\n\",r%M);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "90deda3e0310d21a917bbef2ae0bf2d9", "src_uid": "6f6fc42a367cdce60d76fd1914e73f0c", "difficulty": 2600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n#define M 1000000007LL\nconst long long MSQ = M * M;\ninline int mul(int a, int b) { return (int)(a * 1LL * b % M); }\ninline int powr(int a, int b) {\n    int ans = 1;\n    while (b) {if (b & 1) ans = mul(ans, a); a = mul(a, a); b >>= 1;}\n    return ans;\n}\nint main(){\n    int n, k, i, c, d;\n    long long x, y, z, u, v, res;\n    scanf(\"%d %d\", &n, &k);\n    if (k == 0) res = n;\n    else{\n        if (n <= (k + 1)){\n            for (i = 1, res = 0; i <= n; i++) res += powr(i, k);\n        }\n        else{\n            res = 0;\n            u = 1, v = 1, z = 0;\n            for (i = 0; i <= (k + 1); i++){\n                u = (u * (n - i)) % M;\n                if (i) v = ((v * -i) + MSQ) % M;\n            }\n            for (i = 0, c = 1, d = k + 1; i <= (k + 1); i++, c++, d--){\n                z = (z + powr(i, k)) % M;\n                x = (u * z) % M;\n                x = (x * powr(n - i, M - 2)) % M;\n                y = ((x * powr(v, M - 2)) % M);\n                v = (v * c) % M;\n                if (d) v = (v * powr(d, M - 2)) % M;\n                if (i & 1) y = M - y;\n                res += y;\n            }\n        }\n    }\n    printf(\"%lld\\n\", res % M);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d155831ba407a160b7986b97b4d1f71c", "src_uid": "6f6fc42a367cdce60d76fd1914e73f0c", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define M 1000000007\n\nint F(int a, int b){\n    int r = 1;\n    for (; b; b >>= 1, a = (long long)a * a % M){\n        if (b & 1) r = (long long)r * a % M;\n    }\n    return r;\n}\n\nint main(){\n    int n, k, i, c, d;\n    long long y, z, u, v, r;\n\n    scanf(\"%d %d\", &n, &k);\n    if (!k) r = n;\n    else{\n        if (n <= ++k){\n            for (i = 1, r = 0; i <= n; i++) r += F(i, k-1);\n        }\n        else{\n            for (i = z = r = 0, u = v = 1; i <= k; i++){\n                u = (u * (n - i)) % M;\n                if (i) v = ((v * -i) + 1000000014000000049) % M;\n            }\n\n            for (i = 0, c = 1, d = k; i <= k; i++, c++, d--){\n                z = (z + F(i, k-1)) % M;\n                y = u * z % M * F(n - i, M - 2) % M * F(v, M - 2) % M;\n                v = v * c % M * F(d, M - 2) % M;\n                if (i & 1) y = M - y;\n                r += y;\n            }\n        }\n    }\n    printf(\"%lld\\n\", r % M);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "573d0c856c07e25ef8b5b998c17c769c", "src_uid": "6f6fc42a367cdce60d76fd1914e73f0c", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define M 1000000007\nint n,k,i,c,d;\nlong long y,z,u,v,r;\nint F(int a,int b){\n    int r=1;\n    for (;b;b>>=1,a=(long long)a*a%M){\n        if (b&1)r=(long long)r*a%M;\n    }\n    return r;\n}\nint main(){\n    scanf(\"%d%d\",&n,&k);\n    if (n<=++k){for(i=1;i<=n;i++)r+=F(i,k-1);}\n    else{\n        for (u=v=1;i<=k;i++){u=(u*(n-i))%M;if (i)v=((v*-i)%M+M)%M;}\n        for (i=0,c=1,d=k;i<=k;i++,c++,d--){\n            z=(z+F(i,k-1))%M;\n            y=u*z%M*F(n-i,M-2)%M*F(v,M-2)%M;\n            v=v*c%M*F(d,M-2)%M;\n            if(i&1)y=M-y;\n            r+=y;\n        }\n    }\n    if (!--k)r--;\n    printf(\"%lld\\n\",r%M);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f3e226350f42d9b4caf03d05c2f85edf", "src_uid": "6f6fc42a367cdce60d76fd1914e73f0c", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define MAX 1000010\n#define MOD 1000000007\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nint ar[MAX];\nconst long long MODSQ = (long long)MOD * MOD;\n\nint expo(int a, int b){\n    long long res = 1;\n\n    while (b){\n        if (b & 1) res = res * a % MOD;\n        a = (long long)a * a % MOD;\n        b >>= 1;\n    }\n    return res;\n}\n\nint main(){\n    int n, k, i, j, c, d;\n    long long x, y, z, u, v, res;\n\n    while (scanf(\"%d %d\", &n, &k) != EOF){\n        if (n == 0 && k == 0) break;\n\n        for (i = 0; i <= (k + 1); i++){\n            ar[i] = expo(i, k);\n            if (i){\n                ar[i] += ar[i - 1];\n                if (ar[i] >= MOD) ar[i] -= MOD;\n            }\n        }\n        if (n <= (k + 1)) res = ar[n];\n        else{\n            res = 0;\n            u = 1, v = 1;\n            for (i = 0; i <= (k + 1); i++){\n                u = (u * (n - i)) % MOD;\n                if (i) v = ((v * -i) + MODSQ) % MOD;\n            }\n\n            for (i = 0, c = 1, d = k + 1; i <= (k + 1); i++, c++, d--){\n                x = (u * ar[i]) % MOD;\n                x = (x * expo(n - i, MOD - 2)) % MOD;\n                y = ((x * expo(v, MOD - 2)) % MOD);\n                v = (v * c) % MOD;\n                if (d) v = (v * expo(d, MOD - 2)) % MOD;\n                if (i & 1) y = MOD - y;\n                res += y;\n            }\n        }\n        printf(\"%lld\\n\", res % MOD);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "82cc8afda4e613336e937530c0b1f5b1", "src_uid": "6f6fc42a367cdce60d76fd1914e73f0c", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define min(x,y) ((x) < (y) ? (x) : (y))\n\nint n;\n\nint gcd(int x, int y, int *ti) {\n  return y ? (*ti += x/y, gcd(y, x%y, ti)) : x;\n}\n\n\nint main(void)\n{\n  int ans = 0x3f3f3f3f;\n  int ti, i;\n\n  scanf(\"%d\", &n);\n  for (i = 1; i <= n; ++i) {\n    ti = 0;\n    if (gcd(n, i, &ti) == 1)\n      ans = min(ans, ti);\n  }\n\n  printf(\"%d\\n\", ans-1);\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3510b7561db5a04ab325738413d6eba9", "src_uid": "75739f77378b21c331b46b1427226fa1", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint ss,s[1000];\nint main(void){\n    int n;scanf(\"%d\",&n);\n    int x=n-1;\n    int i=2,m=n;\n    while (m>1){\n        if(m%i==0){s[ss]=i;ss++;}\n        while(m%i==0)m/=i;\n        i++;}\n    for(i=2;i<=n;i++){\n        int c=0;\n        int j;for(j=0;j<ss;j++)\n            if(i%s[j]==0){c=1;break;}\n        if(c==1)continue;\n        int cnt=0;\n        int y=n,z=i;\n        while(y>1&&cnt<x){\n            int u=z,v=y-z;\n            cnt++;\n            if(u>=v){y=u;z=v;}\n            else{y=v;z=u;}}\n        if(cnt<x)x=cnt;}\n    printf(\"%d\\n\",x);return 0;}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7bb88ea067bf9bb5c2c10a8477172ff3", "src_uid": "75739f77378b21c331b46b1427226fa1", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n     int n, m = 1e9, i;\n\n     scanf(\"%d\", &n);\n\n     for (i = 1; i <= n; i++) {\n\t  int p = n, q = i, c = 0;\n\n\t  while (1) {\n\t       if (p == q) {\n\t\t    if (p > 1) c = -1;\n\n\t\t    break;\n\t       }\n\n\t       if (p > q) {\n\t\t    if (q == 1) {\n\t\t\t c += p - 1;\n\n\t\t\t break;\n\t\t    }\n\n\t\t    p -= q;\n\t       } else {\n\t\t    if (p == 1) {\n\t\t\t c += q - 1;\n\n\t\t\t break;\n\t\t    }\n\n\t\t    q -= p;\n\t       }\n\n\t       c++;\n\t  }\n\n\t  if (c >= 0 && c < m) m = c;\n     }\n\n     printf(\"%d\\n\", m);\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "873e1a8b4c9291f21d1070d90598b969", "src_uid": "75739f77378b21c331b46b1427226fa1", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nconst int inf = 1000000000;\n\nint count(int a, int b) {\n\tif (b == 0)\n\t\tif (a == 1)\n\t\t\treturn 0;\n\t\telse\n\t\t\treturn inf;\n\n\treturn count(b, a%b) + a/b;\n}\n\nint main() {\n\tint n;\n\tscanf(\"%d\", &n);\n\n\tint i, m = inf;\n\tfor (i = 1; i <= n; i++) {\n\t\tint c = count(i, n);\n\t\tif (c < m)\n\t\t\tm = c;\n\t}\n\n\tprintf(\"%d\\n\", m-1);\n\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "baf582ebcfb7e870ec27f01bd1e143e6", "src_uid": "75739f77378b21c331b46b1427226fa1", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint gcm(int a, int b) // a<=b\u3067\u3042\u308b\u3053\u3068\uff0e\n{\n    if(a == 0)\n        return b;\n    else\n        return gcm(b%a, a);\n}\n\nint rec(int a, int b) // a<b\u3067\u3042\u308b\u3053\u3068\uff0e\n{\n    if(a == 1)\n        return b-1;\n    return b/a + rec(b%a, a);\n}\n\nint main (int argc, const char * argv[]) {\n    int i, a, b, min;\n    scanf(\"%d\", &a);\n    min = a-1;\n    for(i = 2; i <= a/2; i++){\n        if(gcm(a, i) != 1)\n            continue;\n        if((b = rec(i, a)) < min)\n            min = b;\n    }\n    printf(\"%d\\n\", min);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f85dd99489d3a67f7881d8f0b86fd2a0", "src_uid": "75739f77378b21c331b46b1427226fa1", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\n\n\nint numberOfWalls(int n,int c,int N ,int C, int dp[N+1][C+1]){\n\tint i,count = 0;\n\tif(dp[n][c]!=-1){\n\t\treturn dp[n][c];\n\t}\n\tfor(i=0;i<=n;i++){\n\t\tcount+=numberOfWalls(n-i,c-1,N,C,dp);\n\t\tif(count>=1000003){\n\t\t\tcount%=1000003;\n\t\t}\n\t}\n\tdp[n][c]=count;\n\treturn count;\n}\n\nint main(){\n\tint n,c,i,j;\n\tscanf(\"%d %d\",&n,&c);\n\tint dp[n+1][c+1];\n\tfor(i=0;i<=n;i++){\n\t\tfor(j=0;j<=c;j++){\n\t\t\tdp[i][j]=-1;\n\t\t}\n\t} \n\tfor(i=0;i<=n;i++){\n\t\tdp[i][1]=i+1;\n\t}\n\t\n\tprintf(\"%d\\n\",numberOfWalls(n,c,n,c,dp)-1);\n\treturn 0;\n\t}\n\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "77c16fe5b576b4ed8d5d2ba78e826d59", "src_uid": "e63c70a9c96a94bce99618f2e695f83a", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define MAX 1000000\n#define MOD 1000003\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nlong long fact[MAX], inv[MAX];\n\nvoid Generate(){\n    int i, x;\n    fact[0] = 1, inv[MAX - 1] = 6;\n    for (i = 1; i < MAX; i++) fact[i] = ((long long)i * fact[i - 1]) % MOD;\n    for (i = MAX - 2; i >= 0; i--) inv[i] = ((long long)inv[i + 1] * (i + 1)) % MOD;\n}\n\nlong long binomial(long long n, long long k){\n    if (k > n) return 0;\n    return (fact[n] * inv[n - k] * inv[k]) % MOD;\n}\n\nint main(){\n    Generate();\n    long long n, m, i, j, res;\n    while (scanf(\"%lld %lld\", &n, &m) != EOF){\n        m--, res = 0;\n        for (i = 0; i <= (n + m); i++) res += binomial(i, m);\n        printf(\"%lld\\n\", (res - 1 + MOD) % MOD);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e8a00f4ecb2df2cb7f7855d6e26c9615", "src_uid": "e63c70a9c96a94bce99618f2e695f83a", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define MOD 1000000007\n\nint dar[252][252], k, n, fact[252], inv[252];\n\nint add(int a, int b){\n  a += b;\n  if(a >= MOD)a -= MOD;\n  return a;\n}\n\nint mul(int a, int b){\n  return (a*1ll*b)%MOD;\n}\nint powmod(int base, long long p){\n  int toret = 1;\n  while(p){\n    if(p&1)toret = mul(toret, base);\n    base = mul(base, base);\n    p >>= 1;\n  }\n  return toret;\n}\n\nint ncr(int n, int r){\n  return mul(mul(fact[n], inv[r]), inv[n - r]);\n}\n\nint dp(int r, int c){\n  //  printf(\"dp(%d, %d)\\n\", r, c);\n  if(dar[r][c] == -1){\n    int toret = 0;\n    if(r == 0){\n      dar[r][c] = (c == 0);\n      return dar[r][c];\n    }\n\n    int sat = n - c;\n    int i;\n    for(i = 0;i <= c;i++)if(i + sat){\n      int f1 = powmod(k - 1, c - i);\n      f1 = mul(f1, ncr(c, i));\n      int f2 = powmod(k, sat);\n      if(i == 0){\n\tf2 = add(f2, MOD - powmod(k - 1, sat));\n      }\n      toret = add(toret, mul(dp(r - 1, c - i), mul(f1, f2)));\n    }\n    dar[r][c] = toret;\n  }\n  return dar[r][c];\n}\n\nint main(){\n  scanf(\"%d %d\", &n, &k);\n  int i,j;\n  fact[0] = 1;\n  for(i = 1;i < 252;i++)fact[i] = mul(fact[i - 1], i);\n  for(i = 0;i < 252;i++) inv[i] = powmod(fact[i], MOD - 2);\n  for(i = 0;i <= n;i++)for(j = 0;j <= n;j++){\n      dar[i][j] = -1;\n    }\n  printf(\"%d\\n\", dp(n, n));\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "aeaee555eba2c2163df15d0ade77136e", "src_uid": "f67173c973c6f83e88bc0ddb0b9bfa93", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define MOD 1000000007\n\nint dar[252][252], k, n, fact[252];\n\nint add(int a, int b){\n  a += b;\n  if(a >= MOD)a -= MOD;\n  return a;\n}\n\nint mul(int a, int b){\n  return (a*1ll*b)%MOD;\n}\nint powmod(int base, long long p){\n  int toret = 1;\n  while(p){\n    if(p&1)toret = mul(toret, base);\n    base = mul(base, base);\n    p >>= 1;\n  }\n  return toret;\n}\n\nint inv(int x){\n  return powmod(x, MOD - 2);\n}\nint ncr(int n, int r){\n  return mul(mul(fact[n], inv(fact[r])), inv(fact[n - r]));\n}\n\nint dp(int r, int c){\n  //  printf(\"dp(%d, %d)\\n\", r, c);\n  if(dar[r][c] == -1){\n    int toret = 0;\n    if(r == 0){\n      dar[r][c] = (c == 0);\n      return dar[r][c];\n    }\n\n    int sat = n - c;\n    int i;\n    for(i = 0;i <= c;i++)if(i + sat){\n      int f1 = powmod(k - 1, c - i);\n      f1 = mul(f1, ncr(c, i));\n      int f2 = powmod(k, sat);\n      if(i == 0){\n\tf2 = add(f2, MOD - powmod(k - 1, sat));\n      }\n      toret = add(toret, mul(dp(r - 1, c - i), mul(f1, f2)));\n    }\n    dar[r][c] = toret;\n  }\n  return dar[r][c];\n}\n\nint main(){\n  scanf(\"%d %d\", &n, &k);\n  int i,j;\n  fact[0] = 1;\n  for(i = 1;i < 252;i++)fact[i] = mul(fact[i - 1], i);\n  for(i = 0;i <= n;i++)for(j = 0;j <= n;j++){\n      dar[i][j] = -1;\n    }\n  printf(\"%d\\n\", dp(n, n));\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4d49d24f95f39540eda34115de73fa69", "src_uid": "f67173c973c6f83e88bc0ddb0b9bfa93", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "/* https://codeforces.com/blog/entry/70162 */\n#include <stdio.h>\n\n#define N\t250\n#define MD\t1000000007\n\nlong long power(int a, int k) {\n\tlong long b = a, p = 1;\n\n\twhile (k > 0) {\n\t\tif (k & 1)\n\t\t\tp = p * b % MD;\n\t\tb = b * b % MD;\n\t\tk >>= 1;\n\t}\n\treturn p;\n}\n\nint ff[N + 1], gg[N + 1];\n\nvoid init() {\n\tint i;\n\tlong long f = 1;\n\n\tfor (i = 0; i <= N; i++) {\n\t\tgg[i] = power(ff[i] = f, MD - 2);\n\t\tf = f * (i + 1) % MD;\n\t}\n}\n\nlong long choose(int n, int k) {\n\treturn (long long) ff[n] * gg[k] % MD * gg[n - k] % MD;\n}\n\nint main() {\n\tint n, k, r, ans;\n\n\tinit();\n\tscanf(\"%d%d\", &n, &k);\n\tans = 0;\n\tfor (r = 0; r <= n; r++)\n\t\tans = (ans + (r % 2 == 0 ? 1 : -1) * choose(n, r) * power(power(k - 1, r) * (power(k, n - r) - power(k - 1, n - r)) % MD, n)) % MD;\n\tif (ans < 0)\n\t\tans += MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4b89a1b9791aa477f5393f08b391c06d", "src_uid": "f67173c973c6f83e88bc0ddb0b9bfa93", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define MOD 1000000007\n\nint dar[252][252], k, n, fact[252], inv[252], precomp[2][252];\n\nint add(int a, int b){\n  a += b;\n  if(a >= MOD)a -= MOD;\n  return a;\n}\n\nint mul(int a, int b){\n  return (a*1ll*b)%MOD;\n}\nint powmod(int base, long long p){\n  int toret = 1;\n  while(p){\n    if(p&1)toret = mul(toret, base);\n    base = mul(base, base);\n    p >>= 1;\n  }\n  return toret;\n}\n\nint ncr(int n, int r){\n  return mul(mul(fact[n], inv[r]), inv[n - r]);\n}\n\nint dp(int r, int c){\n  //  printf(\"dp(%d, %d)\\n\", r, c);\n  if(dar[r][c] == -1){\n    int toret = 0;\n    if(r == 0){\n      dar[r][c] = (c == 0);\n      return dar[r][c];\n    }\n\n    int sat = n - c;\n    int i;\n    for(i = 0;i <= c;i++)if(i + sat){\n      int f1 = precomp[0][c - i];\n      f1 = mul(f1, ncr(c, i));\n      int f2 = precomp[1][sat];\n      if(i == 0){\n\tf2 = add(f2, MOD - precomp[0][sat]);\n      }\n      toret = add(toret, mul(dp(r - 1, c - i), mul(f1, f2)));\n    }\n    dar[r][c] = toret;\n  }\n  return dar[r][c];\n}\n\nint main(){\n  scanf(\"%d %d\", &n, &k);\n  if(k == 1){\n    printf(\"1\\n\");\n    return 0;\n  }\n  int i,j;\n  fact[0] = 1;\n  inv[0] = 1;\n  precomp[0][0] = precomp[1][0] = 1;\n  for(i = 1;i < 252;i++){\n    fact[i] = mul(fact[i - 1], i);\n    inv[i] = powmod(fact[i], MOD - 2);\n    precomp[0][i] = powmod(k - 1, i);\n    precomp[1][i] = powmod(k, i);\n  }\n  for(i = 0;i <= n;i++)for(j = 0;j <= n;j++){\n      dar[i][j] = -1;\n    }\n  printf(\"%d\\n\", dp(n, n));\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7f5af34a12251b591726a5e1977c21d4", "src_uid": "f67173c973c6f83e88bc0ddb0b9bfa93", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t250\n#define MD\t1000000007\n\nlong long power(int a, int k) {\n\tlong long b = a, p = 1;\n\n\twhile (k > 0) {\n\t\tif (k & 1)\n\t\t\tp = p * b % MD;\n\t\tb = b * b % MD;\n\t\tk >>= 1;\n\t}\n\treturn p;\n}\n\nint ff[N + 1], gg[N + 1];\n\nvoid init() {\n\tint i;\n\tlong long f = 1;\n\n\tfor (i = 0; i <= N; i++) {\n\t\tgg[i] = power(ff[i] = f, MD - 2);\n\t\tf = f * (i + 1) % MD;\n\t}\n}\n\nlong long choose(int n, int k) {\n\treturn (long long) ff[n] * gg[k] % MD * gg[n - k] % MD;\n}\n\nint main() {\n\tstatic int pk[N * N + 1], pk_[N * N + 1];\n\tint n, k, r, c, i, ans;\n\n\tinit();\n\tscanf(\"%d%d\", &n, &k);\n\tpk[0] = pk_[0] = 1;\n\tfor (i = 1; i <= n * n; i++) {\n\t\tpk[i] = (long long) pk[i - 1] * k % MD;\n\t\tpk_[i] = (long long) pk_[i - 1] * (k - 1) % MD;\n\t}\n\tans = 0;\n\tfor (r = 0; r <= n; r++)\n\t\tfor (c = 0; c <= n; c++) {\n\t\t\tint x = choose(n, r) * choose(n, c) % MD\n\t\t\t\t* pk_[n * n - (n - r) * (n - c)] % MD * pk[(n - r) * (n - c)] % MD;\n\n\t\t\tans = (ans + ((r + c) % 2 == 0 ? x : -x)) % MD;\n\t\t}\n\tif (ans < 0)\n\t\tans += MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "34c50ba06e43bd5497c77a36907569f4", "src_uid": "f67173c973c6f83e88bc0ddb0b9bfa93", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define A 100000000\n#define B 1000\n#define PMAX 316223\n#define P 27293\n#define P3 10000\n#define L1 32000\n#define min(a,b) (((a) < (b)) ? (a) : (b))\n#define max(a,b) (((a) > (b)) ? (a) : (b))\n\nint a[A+1];\nunsigned int b[B] = {\n             0,    5761455,   11078937,   16252325,   21336326,   26355867,   31324703,   36252931,   41146179,   46009215,\n      50847534,   55662470,   60454705,   65228333,   69985473,   74726528,   79451833,   84163019,   88862422,   93547928,\n      98222287,  102886526,  107540122,  112184940,  116818447,  121443371,  126062167,  130670192,  135270258,  139864011,\n     144449537,  149028641,  153600805,  158165829,  162725196,  167279333,  171827136,  176369517,  180906194,  185436625,\n     189961812,  194481069,  198996103,  203507248,  208013454,  212514323,  217011319,  221504167,  225991743,  230475545,\n     234954223,  239429993,  243902342,  248370960,  252834065,  257294520,  261751864,  266206294,  270655552,  275101551,\n     279545368,  283984956,  288422869,  292856421,  297285198,  301711468,  306137611,  310558733,  314977166,  319391721,\n     323804352,  328215206,  332620900,  337024801,  341426904,  345826612,  350221825,  354615116,  359006517,  363395981,\n     367783654,  372168766,  376549859,  380930729,  385307831,  389682427,  394055910,  398425675,  402793457,  407159590,\n     411523195,  415885628,  420243162,  424603409,  428958595,  433311792,  437663672,  442014876,  446362736,  450708777,\n     455052511,  459394441,  463733626,  468072089,  472408200,  476741968,  481074475,  485405902,  489736021,  494062787,\n     498388617,  502712575,  507036251,  511354887,  515673696,  519991125,  524309392,  528624525,  532936342,  537247292,\n     541555851,  545864306,  550170437,  554476170,  558778993,  563082532,  567382703,  571680924,  575978253,  580275482,\n     584570200,  588863345,  593155089,  597445378,  601735269,  606022680,  610308664,  614594106,  618878615,  623159296,\n     627440336,  631717982,  635997249,  640275231,  644550922,  648825715,  653099304,  657371139,  661643304,  665911851,\n     670180516,  674447835,  678714823,  682979568,  687242934,  691504332,  695766925,  700028114,  704286233,  708543557,\n     712799821,  717055212,  721310048,  725563140,  729813991,  734065508,  738315156,  742564929,  746813071,  751060249,\n     755305935,  759550004,  763794029,  768035554,  772276773,  776516528,  780756650,  784994469,  789230673,  793467703,\n     797703398,  801937611,  806169530,  810401956,  814633249,  818864199,  823092766,  827320850,  831548431,  835773764,\n     840000027,  844224822,  848450250,  852673966,  856895823,  861116918,  865335133,  869555570,  873772692,  877989808,\n     882206716,  886422213,  890636921,  894850907,  899064419,  903275849,  907487780,  911698381,  915907322,  920117006,\n     924324489,  928532509,  932738007,  936943763,  941147666,  945351970,  949555347,  953758330,  957958052,  962158684,\n     966358351,  970556800,  974755898,  978951680,  983147464,  987343369,  991538483,  995733104,  999926054, 1004118104,\n    1008309544, 1012500258, 1016690917, 1020879037, 1025067175, 1029256469, 1033444454, 1037631294, 1041815774, 1046001482,\n    1050186367, 1054370637, 1058552429, 1062734476, 1066916147, 1071094927, 1075274949, 1079454128, 1083631538, 1087809564,\n    1091987405, 1096163370, 1100339660, 1104513787, 1108687177, 1112860305, 1117034447, 1121205592, 1125376629, 1129547281,\n    1133717820, 1137887191, 1142056097, 1146225390, 1150393648, 1154560299, 1158727002, 1162892823, 1167057747, 1171221046,\n    1175385155, 1179549444, 1183711384, 1187874380, 1192034212, 1196195238, 1200356153, 1204515304, 1208673910, 1212829795,\n    1216987937, 1221145073, 1225300872, 1229455037, 1233609164, 1237764170, 1241917157, 1246070670, 1250224878, 1254376178,\n    1258528162, 1262678524, 1266827683, 1270976954, 1275125632, 1279274172, 1283421484, 1287567873, 1291715676, 1295861693,\n    1300005926, 1304150462, 1308296664, 1312440578, 1316583470, 1320724811, 1324868019, 1329010956, 1333151863, 1337291809,\n    1341430624, 1345570079, 1349708221, 1353846756, 1357984935, 1362122305, 1366257814, 1370393786, 1374528892, 1378664634,\n    1382799415, 1386933522, 1391065576, 1395199789, 1399331489, 1403463860, 1407594647, 1411724086, 1415855689, 1419985631,\n    1424115489, 1428244053, 1432371870, 1436498522, 1440625629, 1444751745, 1448877006, 1453002152, 1457125036, 1461250000,\n    1465374659, 1469497594, 1473620220, 1477744125, 1481866173, 1485988244, 1490109683, 1494229934, 1498349689, 1502469332,\n    1506589876, 1510706235, 1514824921, 1518942965, 1523061505, 1527178351, 1531294454, 1535409890, 1539526326, 1543640517,\n    1547756812, 1551870851, 1555985016, 1560097442, 1564208549, 1568320054, 1572432177, 1576544661, 1580654270, 1584764017,\n    1588873108, 1592982840, 1597091049, 1601199712, 1605308326, 1609414491, 1613521803, 1617628777, 1621733835, 1625839726,\n    1629945987, 1634052052, 1638156927, 1642258972, 1646361787, 1650465128, 1654567808, 1658669200, 1662770302, 1666869794,\n    1670972264, 1675072419, 1679170566, 1683270249, 1687369711, 1691467151, 1695565190, 1699662748, 1703761548, 1707858902,\n    1711955433, 1716050469, 1720144848, 1724241897, 1728336282, 1732430410, 1736526180, 1740619156, 1744713632, 1748805530,\n    1752898084, 1756987393, 1761078122, 1765169921, 1769260641, 1773351175, 1777442877, 1781530474, 1785621307, 1789709560,\n    1793798703, 1797887260, 1801975182, 1806062390, 1810149996, 1814236123, 1818322676, 1822407623, 1826489988, 1830575906,\n    1834658067, 1838742792, 1842825653, 1846909270, 1850992005, 1855074218, 1859156347, 1863238351, 1867320859, 1871402335,\n    1875482847, 1879562930, 1883642470, 1887722398, 1891800587, 1895879932, 1899958276, 1904036638, 1908114573, 1912191800,\n    1916268743, 1920347116, 1924422570, 1928498011, 1932573349, 1936646486, 1940721696, 1944797174, 1948871367, 1952945594,\n    1957018338, 1961089383, 1965161808, 1969233350, 1973304195, 1977376665, 1981447779, 1985519033, 1989588548, 1993659289,\n    1997729452, 2001796366, 2005864843, 2009933793, 2014002593, 2018069377, 2022137196, 2026204289, 2030270517, 2034337796,\n    2038404475, 2042469434, 2046534053, 2050598713, 2054662457, 2058727455, 2062791593, 2066855115, 2070918071, 2074981871,\n    2079045540, 2083107257, 2087170358, 2091232421, 2095293756, 2099353852, 2103414866, 2107473358, 2111533438, 2115593696,\n    2119654578, 2123711202, 2127769041, 2131828079, 2135887473, 2139945263, 2144002868, 2148061201, 2152118222, 2156173876,\n    2160230408, 2164287399, 2168343450, 2172397905, 2176451935, 2180506650, 2184561319, 2188616526, 2192670595, 2196723874,\n    2200777436, 2204828910, 2208879508, 2212930015, 2216982800, 2221034120, 2225087204, 2229138005, 2233188780, 2237237738,\n    2241286680, 2245337711, 2249386635, 2253437044, 2257486659, 2261534669, 2265582088, 2269630722, 2273677293, 2277723942,\n    2281770277, 2285816118, 2289861391, 2293908247, 2297955870, 2301999709, 2306044120, 2310088597, 2314134053, 2318177990,\n    2322223112, 2326266900, 2330308778, 2334351201, 2338393413, 2342436031, 2346478314, 2350519355, 2354560561, 2358602447,\n    2362642765, 2366683716, 2370724495, 2374763504, 2378804084, 2382843532, 2386880413, 2390919906, 2394959109, 2398996112,\n    2403034927, 2407071577, 2411110078, 2415147307, 2419181034, 2423219093, 2427255367, 2431292536, 2435327045, 2439361501,\n    2443396396, 2447431831, 2451466331, 2455500451, 2459534282, 2463565779, 2467597919, 2471632122, 2475665529, 2479696435,\n    2483729191, 2487761399, 2491793997, 2495825196, 2499856755, 2503887935, 2507918465, 2511947717, 2515978063, 2520007177,\n    2524038155, 2528067401, 2532097043, 2536126664, 2540155255, 2544183491, 2548211228, 2552238285, 2556266399, 2560294002,\n    2564319542, 2568345835, 2572372442, 2576397670, 2580421933, 2584447929, 2588472785, 2592497820, 2596522622, 2600546330,\n    2604571471, 2608595062, 2612618628, 2616643294, 2620665663, 2624687920, 2628709369, 2632732626, 2636754699, 2640776029,\n    2644799757, 2648820585, 2652840994, 2656861044, 2660881979, 2664902170, 2668922912, 2672943760, 2676963401, 2680982125,\n    2685000601, 2689021011, 2693039441, 2697057353, 2701075683, 2705092716, 2709109210, 2713125397, 2717143223, 2721159932,\n    2725176643, 2729193507, 2733210696, 2737225536, 2741242121, 2745257057, 2749272015, 2753286718, 2757299847, 2761314795,\n    2765327756, 2769341791, 2773356225, 2777369850, 2781383306, 2785394924, 2789408169, 2793419860, 2797431717, 2801443922,\n    2805454432, 2809465484, 2813477356, 2817487436, 2821497837, 2825509231, 2829520068, 2833530738, 2837539518, 2841549369,\n    2845558213, 2849566042, 2853574755, 2857584531, 2861594266, 2865601989, 2869610768, 2873619181, 2877625961, 2881633373,\n    2885641353, 2889648502, 2893654733, 2897660376, 2901667770, 2905672946, 2909678043, 2913685600, 2917689568, 2921695146,\n    2925699539, 2929702761, 2933706263, 2937709465, 2941713524, 2945717900, 2949719949, 2953724092, 2957726064, 2961727364,\n    2965730599, 2969734593, 2973737899, 2977740005, 2981742619, 2985744869, 2989743222, 2993744024, 2997743403, 3001742385,\n    3005740846, 3009740083, 3013740632, 3017740443, 3021739912, 3025737894, 3029738266, 3033736354, 3037734260, 3041732620,\n    3045730736, 3049728863, 3053726975, 3057724728, 3061722012, 3065718156, 3069714416, 3073709903, 3077706121, 3081700773,\n    3085694966, 3089690887, 3093686041, 3097682212, 3101677762, 3105672385, 3109665704, 3113660777, 3117654258, 3121648738,\n    3125641477, 3129636165, 3133628489, 3137621629, 3141615091, 3145607391, 3149600532, 3153593186, 3157583551, 3161575400,\n    3165568071, 3169558897, 3173549966, 3177541505, 3181531857, 3185524100, 3189515502, 3193505484, 3197494480, 3201485771,\n    3205474366, 3209464223, 3213453462, 3217442657, 3221430632, 3225418712, 3229406344, 3233394790, 3237380550, 3241367601,\n    3245353518, 3249340672, 3253327262, 3257314501, 3261302137, 3265288786, 3269274318, 3273261676, 3277246756, 3281232235,\n    3285218896, 3289205184, 3293189136, 3297172860, 3301158042, 3305141278, 3309125457, 3313108871, 3317092589, 3321076365,\n    3325059246, 3329042269, 3333024320, 3337007745, 3340990584, 3344973656, 3348954479, 3352936965, 3356918381, 3360899212,\n    3364880246, 3368861514, 3372843128, 3376824341, 3380804536, 3384785252, 3388764045, 3392744352, 3396724969, 3400703302,\n    3404683449, 3408661629, 3412641191, 3416621174, 3420600239, 3424577712, 3428556536, 3432533925, 3436512942, 3440489299,\n    3444467709, 3448443650, 3452420745, 3456398055, 3460376073, 3464354329, 3468330724, 3472306712, 3476280273, 3480257644,\n    3484232867, 3488208449, 3492182057, 3496156616, 3500132047, 3504107018, 3508083271, 3512056531, 3516031243, 3520004496,\n    3523979003, 3527952545, 3531925382, 3535899657, 3539873170, 3543843428, 3547815425, 3551789160, 3555761507, 3559733867,\n    3563706203, 3567677571, 3571648151, 3575618333, 3579587822, 3583559953, 3587530335, 3591499540, 3595471441, 3599441281,\n    3603412533, 3607382383, 3611353499, 3615323157, 3619293204, 3623260438, 3627230054, 3631199924, 3635167788, 3639133977,\n    3643101671, 3647069932, 3651037811, 3655006291, 3658974043, 3662941495, 3666909363, 3670877228, 3674842642, 3678809724,\n    3682776125, 3686743894, 3690708635, 3694674136, 3698640744, 3702607660, 3706572805, 3710536268, 3714502398, 3718465031,\n    3722428991, 3726394088, 3730358421, 3734323031, 3738287024, 3742250941, 3746214561, 3750179004, 3754141753, 3758105608,\n    3762067054, 3766030492, 3769992222, 3773955567, 3777917868, 3781881979, 3785842285, 3789803781, 3793766088, 3797726848,\n    3801688660, 3805649459, 3809611918, 3813571463, 3817534298, 3821493048, 3825453351, 3829412874, 3833371480, 3837330842,\n    3841291749, 3845250279, 3849209920, 3853169493, 3857129155, 3861088365, 3865047067, 3869005617, 3872964725, 3876923182,\n    3880881273, 3884839528, 3888796569, 3892753631, 3896710330, 3900667023, 3904623253, 3908580398, 3912536328, 3916492455,\n    3920449831, 3924406577, 3928362015, 3932316075, 3936271016, 3940227600, 3944182809, 3948137829, 3952093061, 3956048108,\n    3960003559, 3963957671, 3967911833, 3971865657, 3975818018, 3979772869, 3983725586, 3987677658, 3991630533, 3995584016,\n    3999537962, 4003491500, 4007444082, 4011396563, 4015348558, 4019300356, 4023253116, 4027204376, 4031157206, 4035109071,\n    4039061553, 4043014010, 4046965198, 4050915644, 4054865513, 4058816261, 4062767391, 4066716906, 4070666662, 4074616057,\n    4078566781, 4082514143, 4086464266, 4090414411, 4094363532, 4098312828, 4102261058, 4106208569, 4110157418, 4114105592\n};\nint p[P];\nlong long y[P];\n\nint main()\n{\n\tlong long n, n2, n3, bl, bh, ans = 0, k, kl, kh;\n\tint i, j, b1=-1, b2, q2, c;\n\n\tscanf(\"%I64d\", &n);\n\n\t// p\n\tp[0] = 2; k = 1;\n\tfor (i = 3; i <= PMAX; i += 2)\n\t{\n\t\tif (a[i] == 0)\n\t\t{\n\t\t\tp[k++] = i;\n\t\t\tif (i <= PMAX/i)\n\t\t\t\tfor (j = i * i; j <= PMAX; j += i) \n\t\t\t\t\ta[j] = 1;\n\t\t};\n\t}\n\n\t// 2\n\tfor (i = 0; i < P; i++)\n\t{\n\t\tn2 = n / p[i];\n\t\tif (n2 == 0 || n2 < p[i]) break;\n\t\tb2 = (int) (n2 / A); \n\t\tq2 = n2 % A;\n\t\tif (b1 != b2)\n\t\t{\n\t\t\tmemset(a, 0, sizeof(a));\n\t\t\tb1 = b2;\n\t\t\tbl = 1ll * b1 * A;\n\t\t\tbh = bl + q2 + 1;\n\t\t\tc = (b1 == 0? 1: 0);\n\t\t\ty[0] = -1;\n\t\t\tfor (j = 1; j < P; j++)\n\t\t\t{\n\t\t\t\ty[j] = max(bl + bl/p[j]*p[j] + p[j], 1ll * p[j] * p[j]) - bl;\n\t\t\t\tif ((y[j] & 1) == 0) y[j] += p[j];\n\t\t\t}\n\t\t\tfor (kl = bl; kl < bh; kl += L1)\n\t\t\t{\n\t\t\t\tkh = min(kl + L1, bh) - bl;\n\t\t\t\tfor (j = 1; j < P; j++)\n\t\t\t\t{\n  \t\t\t\t\tfor (k = y[j]; k < kh; k += 2ll*p[j]) \n\t\t\t\t\t\ta[k] = 1;\n\t\t\t\t\ty[j] = k;\n\t\t\t\t}\n\t\t\t\tif (kl == 0)\n\t\t\t\t{\n\t\t\t\t\tk = 3;\n\t\t\t\t\ta[2] = 1;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tk = kl - bl + 1;\n\t\t\t\t}\n    \t\t\t\tfor (; k < kh; k+=2)\n\t\t\t\t\ta[k] = a[k+1] = (a[k]==0? ++c: c);\n\t\t\t}\n\t\t} // b\n\t\tans = ans + b[b1] + a[q2] - (i + 1);\n\t}\n\n\t// 3\n\ti = 0; j = P;\n\tfor (;;)\n\t{\n\t\tk = i + (j - i) / 2;\n\t\tif (k == i)\n\t\t\tbreak;\n\t\tif (p[k] > P3)\n\t\t\tn3 = n + 1;\n\t\telse\n\t\t\tn3 = (long long) p[k] * p[k] * p[k];\n\t\tif (n3 > n)\n\t\t\tj = (int) k;\n\t\telse if (n3 < n)\n\t\t\ti = (int) k;\n\t\telse \n\t\t\tbreak;\n\t}\n\tif (p[k]*p[k]*p[k]<=n)\n\t\tans += k + 1;\n\n\tprintf(\"%I64d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6001520cf65c6ff727768c6c2c65d5c8", "src_uid": "ffb7762f1d60dc3f16e9b27ea0ecdd7d", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define A 100000000\n#define B 1000\n#define PMAX 316223\n#define P 27293\n#define P3 10000\n#define L1 32000\n#define min(a,b) (((a) < (b)) ? (a) : (b))\n#define max(a,b) (((a) > (b)) ? (a) : (b))\n\nint a[A+1];\nunsigned int b[B] = {\n             0,    5761455,   11078937,   16252325,   21336326,   26355867,   31324703,   36252931,   41146179,   46009215,\n      50847534,   55662470,   60454705,   65228333,   69985473,   74726528,   79451833,   84163019,   88862422,   93547928,\n      98222287,  102886526,  107540122,  112184940,  116818447,  121443371,  126062167,  130670192,  135270258,  139864011,\n     144449537,  149028641,  153600805,  158165829,  162725196,  167279333,  171827136,  176369517,  180906194,  185436625,\n     189961812,  194481069,  198996103,  203507248,  208013454,  212514323,  217011319,  221504167,  225991743,  230475545,\n     234954223,  239429993,  243902342,  248370960,  252834065,  257294520,  261751864,  266206294,  270655552,  275101551,\n     279545368,  283984956,  288422869,  292856421,  297285198,  301711468,  306137611,  310558733,  314977166,  319391721,\n     323804352,  328215206,  332620900,  337024801,  341426904,  345826612,  350221825,  354615116,  359006517,  363395981,\n     367783654,  372168766,  376549859,  380930729,  385307831,  389682427,  394055910,  398425675,  402793457,  407159590,\n     411523195,  415885628,  420243162,  424603409,  428958595,  433311792,  437663672,  442014876,  446362736,  450708777,\n     455052511,  459394441,  463733626,  468072089,  472408200,  476741968,  481074475,  485405902,  489736021,  494062787,\n     498388617,  502712575,  507036251,  511354887,  515673696,  519991125,  524309392,  528624525,  532936342,  537247292,\n     541555851,  545864306,  550170437,  554476170,  558778993,  563082532,  567382703,  571680924,  575978253,  580275482,\n     584570200,  588863345,  593155089,  597445378,  601735269,  606022680,  610308664,  614594106,  618878615,  623159296,\n     627440336,  631717982,  635997249,  640275231,  644550922,  648825715,  653099304,  657371139,  661643304,  665911851,\n     670180516,  674447835,  678714823,  682979568,  687242934,  691504332,  695766925,  700028114,  704286233,  708543557,\n     712799821,  717055212,  721310048,  725563140,  729813991,  734065508,  738315156,  742564929,  746813071,  751060249,\n     755305935,  759550004,  763794029,  768035554,  772276773,  776516528,  780756650,  784994469,  789230673,  793467703,\n     797703398,  801937611,  806169530,  810401956,  814633249,  818864199,  823092766,  827320850,  831548431,  835773764,\n     840000027,  844224822,  848450250,  852673966,  856895823,  861116918,  865335133,  869555570,  873772692,  877989808,\n     882206716,  886422213,  890636921,  894850907,  899064419,  903275849,  907487780,  911698381,  915907322,  920117006,\n     924324489,  928532509,  932738007,  936943763,  941147666,  945351970,  949555347,  953758330,  957958052,  962158684,\n     966358351,  970556800,  974755898,  978951680,  983147464,  987343369,  991538483,  995733104,  999926054, 1004118104,\n    1008309544, 1012500258, 1016690917, 1020879037, 1025067175, 1029256469, 1033444454, 1037631294, 1041815774, 1046001482,\n    1050186367, 1054370637, 1058552429, 1062734476, 1066916147, 1071094927, 1075274949, 1079454128, 1083631538, 1087809564,\n    1091987405, 1096163370, 1100339660, 1104513787, 1108687177, 1112860305, 1117034447, 1121205592, 1125376629, 1129547281,\n    1133717820, 1137887191, 1142056097, 1146225390, 1150393648, 1154560299, 1158727002, 1162892823, 1167057747, 1171221046,\n    1175385155, 1179549444, 1183711384, 1187874380, 1192034212, 1196195238, 1200356153, 1204515304, 1208673910, 1212829795,\n    1216987937, 1221145073, 1225300872, 1229455037, 1233609164, 1237764170, 1241917157, 1246070670, 1250224878, 1254376178,\n    1258528162, 1262678524, 1266827683, 1270976954, 1275125632, 1279274172, 1283421484, 1287567873, 1291715676, 1295861693,\n    1300005926, 1304150462, 1308296664, 1312440578, 1316583470, 1320724811, 1324868019, 1329010956, 1333151863, 1337291809,\n    1341430624, 1345570079, 1349708221, 1353846756, 1357984935, 1362122305, 1366257814, 1370393786, 1374528892, 1378664634,\n    1382799415, 1386933522, 1391065576, 1395199789, 1399331489, 1403463860, 1407594647, 1411724086, 1415855689, 1419985631,\n    1424115489, 1428244053, 1432371870, 1436498522, 1440625629, 1444751745, 1448877006, 1453002152, 1457125036, 1461250000,\n    1465374659, 1469497594, 1473620220, 1477744125, 1481866173, 1485988244, 1490109683, 1494229934, 1498349689, 1502469332,\n    1506589876, 1510706235, 1514824921, 1518942965, 1523061505, 1527178351, 1531294454, 1535409890, 1539526326, 1543640517,\n    1547756812, 1551870851, 1555985016, 1560097442, 1564208549, 1568320054, 1572432177, 1576544661, 1580654270, 1584764017,\n    1588873108, 1592982840, 1597091049, 1601199712, 1605308326, 1609414491, 1613521803, 1617628777, 1621733835, 1625839726,\n    1629945987, 1634052052, 1638156927, 1642258972, 1646361787, 1650465128, 1654567808, 1658669200, 1662770302, 1666869794,\n    1670972264, 1675072419, 1679170566, 1683270249, 1687369711, 1691467151, 1695565190, 1699662748, 1703761548, 1707858902,\n    1711955433, 1716050469, 1720144848, 1724241897, 1728336282, 1732430410, 1736526180, 1740619156, 1744713632, 1748805530,\n    1752898084, 1756987393, 1761078122, 1765169921, 1769260641, 1773351175, 1777442877, 1781530474, 1785621307, 1789709560,\n    1793798703, 1797887260, 1801975182, 1806062390, 1810149996, 1814236123, 1818322676, 1822407623, 1826489988, 1830575906,\n    1834658067, 1838742792, 1842825653, 1846909270, 1850992005, 1855074218, 1859156347, 1863238351, 1867320859, 1871402335,\n    1875482847, 1879562930, 1883642470, 1887722398, 1891800587, 1895879932, 1899958276, 1904036638, 1908114573, 1912191800,\n    1916268743, 1920347116, 1924422570, 1928498011, 1932573349, 1936646486, 1940721696, 1944797174, 1948871367, 1952945594,\n    1957018338, 1961089383, 1965161808, 1969233350, 1973304195, 1977376665, 1981447779, 1985519033, 1989588548, 1993659289,\n    1997729452, 2001796366, 2005864843, 2009933793, 2014002593, 2018069377, 2022137196, 2026204289, 2030270517, 2034337796,\n    2038404475, 2042469434, 2046534053, 2050598713, 2054662457, 2058727455, 2062791593, 2066855115, 2070918071, 2074981871,\n    2079045540, 2083107257, 2087170358, 2091232421, 2095293756, 2099353852, 2103414866, 2107473358, 2111533438, 2115593696,\n    2119654578, 2123711202, 2127769041, 2131828079, 2135887473, 2139945263, 2144002868, 2148061201, 2152118222, 2156173876,\n    2160230408, 2164287399, 2168343450, 2172397905, 2176451935, 2180506650, 2184561319, 2188616526, 2192670595, 2196723874,\n    2200777436, 2204828910, 2208879508, 2212930015, 2216982800, 2221034120, 2225087204, 2229138005, 2233188780, 2237237738,\n    2241286680, 2245337711, 2249386635, 2253437044, 2257486659, 2261534669, 2265582088, 2269630722, 2273677293, 2277723942,\n    2281770277, 2285816118, 2289861391, 2293908247, 2297955870, 2301999709, 2306044120, 2310088597, 2314134053, 2318177990,\n    2322223112, 2326266900, 2330308778, 2334351201, 2338393413, 2342436031, 2346478314, 2350519355, 2354560561, 2358602447,\n    2362642765, 2366683716, 2370724495, 2374763504, 2378804084, 2382843532, 2386880413, 2390919906, 2394959109, 2398996112,\n    2403034927, 2407071577, 2411110078, 2415147307, 2419181034, 2423219093, 2427255367, 2431292536, 2435327045, 2439361501,\n    2443396396, 2447431831, 2451466331, 2455500451, 2459534282, 2463565779, 2467597919, 2471632122, 2475665529, 2479696435,\n    2483729191, 2487761399, 2491793997, 2495825196, 2499856755, 2503887935, 2507918465, 2511947717, 2515978063, 2520007177,\n    2524038155, 2528067401, 2532097043, 2536126664, 2540155255, 2544183491, 2548211228, 2552238285, 2556266399, 2560294002,\n    2564319542, 2568345835, 2572372442, 2576397670, 2580421933, 2584447929, 2588472785, 2592497820, 2596522622, 2600546330,\n    2604571471, 2608595062, 2612618628, 2616643294, 2620665663, 2624687920, 2628709369, 2632732626, 2636754699, 2640776029,\n    2644799757, 2648820585, 2652840994, 2656861044, 2660881979, 2664902170, 2668922912, 2672943760, 2676963401, 2680982125,\n    2685000601, 2689021011, 2693039441, 2697057353, 2701075683, 2705092716, 2709109210, 2713125397, 2717143223, 2721159932,\n    2725176643, 2729193507, 2733210696, 2737225536, 2741242121, 2745257057, 2749272015, 2753286718, 2757299847, 2761314795,\n    2765327756, 2769341791, 2773356225, 2777369850, 2781383306, 2785394924, 2789408169, 2793419860, 2797431717, 2801443922,\n    2805454432, 2809465484, 2813477356, 2817487436, 2821497837, 2825509231, 2829520068, 2833530738, 2837539518, 2841549369,\n    2845558213, 2849566042, 2853574755, 2857584531, 2861594266, 2865601989, 2869610768, 2873619181, 2877625961, 2881633373,\n    2885641353, 2889648502, 2893654733, 2897660376, 2901667770, 2905672946, 2909678043, 2913685600, 2917689568, 2921695146,\n    2925699539, 2929702761, 2933706263, 2937709465, 2941713524, 2945717900, 2949719949, 2953724092, 2957726064, 2961727364,\n    2965730599, 2969734593, 2973737899, 2977740005, 2981742619, 2985744869, 2989743222, 2993744024, 2997743403, 3001742385,\n    3005740846, 3009740083, 3013740632, 3017740443, 3021739912, 3025737894, 3029738266, 3033736354, 3037734260, 3041732620,\n    3045730736, 3049728863, 3053726975, 3057724728, 3061722012, 3065718156, 3069714416, 3073709903, 3077706121, 3081700773,\n    3085694966, 3089690887, 3093686041, 3097682212, 3101677762, 3105672385, 3109665704, 3113660777, 3117654258, 3121648738,\n    3125641477, 3129636165, 3133628489, 3137621629, 3141615091, 3145607391, 3149600532, 3153593186, 3157583551, 3161575400,\n    3165568071, 3169558897, 3173549966, 3177541505, 3181531857, 3185524100, 3189515502, 3193505484, 3197494480, 3201485771,\n    3205474366, 3209464223, 3213453462, 3217442657, 3221430632, 3225418712, 3229406344, 3233394790, 3237380550, 3241367601,\n    3245353518, 3249340672, 3253327262, 3257314501, 3261302137, 3265288786, 3269274318, 3273261676, 3277246756, 3281232235,\n    3285218896, 3289205184, 3293189136, 3297172860, 3301158042, 3305141278, 3309125457, 3313108871, 3317092589, 3321076365,\n    3325059246, 3329042269, 3333024320, 3337007745, 3340990584, 3344973656, 3348954479, 3352936965, 3356918381, 3360899212,\n    3364880246, 3368861514, 3372843128, 3376824341, 3380804536, 3384785252, 3388764045, 3392744352, 3396724969, 3400703302,\n    3404683449, 3408661629, 3412641191, 3416621174, 3420600239, 3424577712, 3428556536, 3432533925, 3436512942, 3440489299,\n    3444467709, 3448443650, 3452420745, 3456398055, 3460376073, 3464354329, 3468330724, 3472306712, 3476280273, 3480257644,\n    3484232867, 3488208449, 3492182057, 3496156616, 3500132047, 3504107018, 3508083271, 3512056531, 3516031243, 3520004496,\n    3523979003, 3527952545, 3531925382, 3535899657, 3539873170, 3543843428, 3547815425, 3551789160, 3555761507, 3559733867,\n    3563706203, 3567677571, 3571648151, 3575618333, 3579587822, 3583559953, 3587530335, 3591499540, 3595471441, 3599441281,\n    3603412533, 3607382383, 3611353499, 3615323157, 3619293204, 3623260438, 3627230054, 3631199924, 3635167788, 3639133977,\n    3643101671, 3647069932, 3651037811, 3655006291, 3658974043, 3662941495, 3666909363, 3670877228, 3674842642, 3678809724,\n    3682776125, 3686743894, 3690708635, 3694674136, 3698640744, 3702607660, 3706572805, 3710536268, 3714502398, 3718465031,\n    3722428991, 3726394088, 3730358421, 3734323031, 3738287024, 3742250941, 3746214561, 3750179004, 3754141753, 3758105608,\n    3762067054, 3766030492, 3769992222, 3773955567, 3777917868, 3781881979, 3785842285, 3789803781, 3793766088, 3797726848,\n    3801688660, 3805649459, 3809611918, 3813571463, 3817534298, 3821493048, 3825453351, 3829412874, 3833371480, 3837330842,\n    3841291749, 3845250279, 3849209920, 3853169493, 3857129155, 3861088365, 3865047067, 3869005617, 3872964725, 3876923182,\n    3880881273, 3884839528, 3888796569, 3892753631, 3896710330, 3900667023, 3904623253, 3908580398, 3912536328, 3916492455,\n    3920449831, 3924406577, 3928362015, 3932316075, 3936271016, 3940227600, 3944182809, 3948137829, 3952093061, 3956048108,\n    3960003559, 3963957671, 3967911833, 3971865657, 3975818018, 3979772869, 3983725586, 3987677658, 3991630533, 3995584016,\n    3999537962, 4003491500, 4007444082, 4011396563, 4015348558, 4019300356, 4023253116, 4027204376, 4031157206, 4035109071,\n    4039061553, 4043014010, 4046965198, 4050915644, 4054865513, 4058816261, 4062767391, 4066716906, 4070666662, 4074616057,\n    4078566781, 4082514143, 4086464266, 4090414411, 4094363532, 4098312828, 4102261058, 4106208569, 4110157418, 4114105592\n};\nint p[P];\nlong long y[P];\n\nint main()\n{\n\tlong long n, n2, n3, bl, bh, ans = 0, k, kl, kh;\n\tint i, j, b1=-1, b2, q2, c;\n\n\tscanf(\"%I64d\", &n);\n\n\t// p\n\tp[0] = 2; k = 1;\n\tfor (i = 3; i <= PMAX; i += 2)\n\t{\n\t\tif (a[i] == 0)\n\t\t{\n\t\t\tp[k++] = i;\n\t\t\tif (i <= PMAX/i)\n\t\t\t\tfor (j = i * i; j <= PMAX; j += i) \n\t\t\t\t\ta[j] = 1;\n\t\t};\n\t}\n\n\t// 2\n\tfor (i = 0; i < P; i++)\n\t{\n\t\tn2 = n / p[i];\n\t\tif (n2 == 0 || n2 < p[i]) break;\n\t\tb2 = (int) (n2 / A); \n\t\tq2 = n2 % A;\n\t\tif (b1 != b2)\n\t\t{\n\t\t\tmemset(a, 0, sizeof(a));\n\t\t\tb1 = b2;\n\t\t\tbl = 1ll * b1 * A;\n\t\t\tbh = bl + q2 + 1; // + A\n\t\t\tc = (b1 == 0? 1: 0);\n\t\t\ty[0] = -1;\n\t\t\tfor (j = 1; j < P; j++)\n\t\t\t{\n\t\t\t\ty[j] = max(bl + bl/p[j]*p[j] + p[j], 1ll * p[j] * p[j]) - bl;\n\t\t\t\tif ((y[j] & 1) == 0) y[j] += p[j];\n\t\t\t}\n\t\t\tfor (kl = bl; kl < bh; kl += L1)\n\t\t\t{\n\t\t\t\tkh = min(kl + L1, bh) - bl;\n\t\t\t\tfor (j = 1; j < P; j++)\n\t\t\t\t{\n  \t\t\t\t\tfor (k = y[j]; k < kh; k += 2ll*p[j]) \n\t\t\t\t\t\ta[k] = 1;\n\t\t\t\t\ty[j] = k;\n\t\t\t\t}\n\t\t\t\tif (kl == 0)\n\t\t\t\t{\n\t\t\t\t\tk = 3;\n\t\t\t\t\ta[2] = 1;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tk = kl - bl + 1;\n\t\t\t\t}\n    \t\t\t\tfor (; k < kh; k+=2)\n\t\t\t\t\ta[k] = a[k+1] = (a[k]==0? ++c: c);\n\t\t\t}\n\t\t} // b\n\t\tans = ans + b[b1] + a[q2] - (i + 1);\n\t}\n\n\t// 3\n\ti = 0; j = P;\n\tfor (;;)\n\t{\n\t\tk = i + (j - i) / 2;\n\t\tif (k == i)\n\t\t\tbreak;\n\t\tif (p[k] > P3)\n\t\t\tn3 = n + 1;\n\t\telse\n\t\t\tn3 = (long long) p[k] * p[k] * p[k];\n\t\tif (n3 > n)\n\t\t\tj = (int) k;\n\t\telse if (n3 < n)\n\t\t\ti = (int) k;\n\t\telse \n\t\t\tbreak;\n\t}\n\tans += k + 1;\n\n\tprintf(\"%I64d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3c3a72047e88d0980fbad1661680f118", "src_uid": "ffb7762f1d60dc3f16e9b27ea0ecdd7d", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define A 100000000\n#define B 1000\n#define PMAX 316223\n#define P 27293\n#define P3 10000\n#define L1 32000\n#define min(a,b) (((a) < (b)) ? (a) : (b))\n#define max(a,b) (((a) > (b)) ? (a) : (b))\n\nint a[A+1];\nunsigned int b[B] = {\n             0,    5761455,   11078937,   16252325,   21336326,   26355867,   31324703,   36252931,   41146179,   46009215,\n      50847534,   55662470,   60454705,   65228333,   69985473,   74726528,   79451833,   84163019,   88862422,   93547928,\n      98222287,  102886526,  107540122,  112184940,  116818447,  121443371,  126062167,  130670192,  135270258,  139864011,\n     144449537,  149028641,  153600805,  158165829,  162725196,  167279333,  171827136,  176369517,  180906194,  185436625,\n     189961812,  194481069,  198996103,  203507248,  208013454,  212514323,  217011319,  221504167,  225991743,  230475545,\n     234954223,  239429993,  243902342,  248370960,  252834065,  257294520,  261751864,  266206294,  270655552,  275101551,\n     279545368,  283984956,  288422869,  292856421,  297285198,  301711468,  306137611,  310558733,  314977166,  319391721,\n     323804352,  328215206,  332620900,  337024801,  341426904,  345826612,  350221825,  354615116,  359006517,  363395981,\n     367783654,  372168766,  376549859,  380930729,  385307831,  389682427,  394055910,  398425675,  402793457,  407159590,\n     411523195,  415885628,  420243162,  424603409,  428958595,  433311792,  437663672,  442014876,  446362736,  450708777,\n     455052511,  459394441,  463733626,  468072089,  472408200,  476741968,  481074475,  485405902,  489736021,  494062787,\n     498388617,  502712575,  507036251,  511354887,  515673696,  519991125,  524309392,  528624525,  532936342,  537247292,\n     541555851,  545864306,  550170437,  554476170,  558778993,  563082532,  567382703,  571680924,  575978253,  580275482,\n     584570200,  588863345,  593155089,  597445378,  601735269,  606022680,  610308664,  614594106,  618878615,  623159296,\n     627440336,  631717982,  635997249,  640275231,  644550922,  648825715,  653099304,  657371139,  661643304,  665911851,\n     670180516,  674447835,  678714823,  682979568,  687242934,  691504332,  695766925,  700028114,  704286233,  708543557,\n     712799821,  717055212,  721310048,  725563140,  729813991,  734065508,  738315156,  742564929,  746813071,  751060249,\n     755305935,  759550004,  763794029,  768035554,  772276773,  776516528,  780756650,  784994469,  789230673,  793467703,\n     797703398,  801937611,  806169530,  810401956,  814633249,  818864199,  823092766,  827320850,  831548431,  835773764,\n     840000027,  844224822,  848450250,  852673966,  856895823,  861116918,  865335133,  869555570,  873772692,  877989808,\n     882206716,  886422213,  890636921,  894850907,  899064419,  903275849,  907487780,  911698381,  915907322,  920117006,\n     924324489,  928532509,  932738007,  936943763,  941147666,  945351970,  949555347,  953758330,  957958052,  962158684,\n     966358351,  970556800,  974755898,  978951680,  983147464,  987343369,  991538483,  995733104,  999926054, 1004118104,\n    1008309544, 1012500258, 1016690917, 1020879037, 1025067175, 1029256469, 1033444454, 1037631294, 1041815774, 1046001482,\n    1050186367, 1054370637, 1058552429, 1062734476, 1066916147, 1071094927, 1075274949, 1079454128, 1083631538, 1087809564,\n    1091987405, 1096163370, 1100339660, 1104513787, 1108687177, 1112860305, 1117034447, 1121205592, 1125376629, 1129547281,\n    1133717820, 1137887191, 1142056097, 1146225390, 1150393648, 1154560299, 1158727002, 1162892823, 1167057747, 1171221046,\n    1175385155, 1179549444, 1183711384, 1187874380, 1192034212, 1196195238, 1200356153, 1204515304, 1208673910, 1212829795,\n    1216987937, 1221145073, 1225300872, 1229455037, 1233609164, 1237764170, 1241917157, 1246070670, 1250224878, 1254376178,\n    1258528162, 1262678524, 1266827683, 1270976954, 1275125632, 1279274172, 1283421484, 1287567873, 1291715676, 1295861693,\n    1300005926, 1304150462, 1308296664, 1312440578, 1316583470, 1320724811, 1324868019, 1329010956, 1333151863, 1337291809,\n    1341430624, 1345570079, 1349708221, 1353846756, 1357984935, 1362122305, 1366257814, 1370393786, 1374528892, 1378664634,\n    1382799415, 1386933522, 1391065576, 1395199789, 1399331489, 1403463860, 1407594647, 1411724086, 1415855689, 1419985631,\n    1424115489, 1428244053, 1432371870, 1436498522, 1440625629, 1444751745, 1448877006, 1453002152, 1457125036, 1461250000,\n    1465374659, 1469497594, 1473620220, 1477744125, 1481866173, 1485988244, 1490109683, 1494229934, 1498349689, 1502469332,\n    1506589876, 1510706235, 1514824921, 1518942965, 1523061505, 1527178351, 1531294454, 1535409890, 1539526326, 1543640517,\n    1547756812, 1551870851, 1555985016, 1560097442, 1564208549, 1568320054, 1572432177, 1576544661, 1580654270, 1584764017,\n    1588873108, 1592982840, 1597091049, 1601199712, 1605308326, 1609414491, 1613521803, 1617628777, 1621733835, 1625839726,\n    1629945987, 1634052052, 1638156927, 1642258972, 1646361787, 1650465128, 1654567808, 1658669200, 1662770302, 1666869794,\n    1670972264, 1675072419, 1679170566, 1683270249, 1687369711, 1691467151, 1695565190, 1699662748, 1703761548, 1707858902,\n    1711955433, 1716050469, 1720144848, 1724241897, 1728336282, 1732430410, 1736526180, 1740619156, 1744713632, 1748805530,\n    1752898084, 1756987393, 1761078122, 1765169921, 1769260641, 1773351175, 1777442877, 1781530474, 1785621307, 1789709560,\n    1793798703, 1797887260, 1801975182, 1806062390, 1810149996, 1814236123, 1818322676, 1822407623, 1826489988, 1830575906,\n    1834658067, 1838742792, 1842825653, 1846909270, 1850992005, 1855074218, 1859156347, 1863238351, 1867320859, 1871402335,\n    1875482847, 1879562930, 1883642470, 1887722398, 1891800587, 1895879932, 1899958276, 1904036638, 1908114573, 1912191800,\n    1916268743, 1920347116, 1924422570, 1928498011, 1932573349, 1936646486, 1940721696, 1944797174, 1948871367, 1952945594,\n    1957018338, 1961089383, 1965161808, 1969233350, 1973304195, 1977376665, 1981447779, 1985519033, 1989588548, 1993659289,\n    1997729452, 2001796366, 2005864843, 2009933793, 2014002593, 2018069377, 2022137196, 2026204289, 2030270517, 2034337796,\n    2038404475, 2042469434, 2046534053, 2050598713, 2054662457, 2058727455, 2062791593, 2066855115, 2070918071, 2074981871,\n    2079045540, 2083107257, 2087170358, 2091232421, 2095293756, 2099353852, 2103414866, 2107473358, 2111533438, 2115593696,\n    2119654578, 2123711202, 2127769041, 2131828079, 2135887473, 2139945263, 2144002868, 2148061201, 2152118222, 2156173876,\n    2160230408, 2164287399, 2168343450, 2172397905, 2176451935, 2180506650, 2184561319, 2188616526, 2192670595, 2196723874,\n    2200777436, 2204828910, 2208879508, 2212930015, 2216982800, 2221034120, 2225087204, 2229138005, 2233188780, 2237237738,\n    2241286680, 2245337711, 2249386635, 2253437044, 2257486659, 2261534669, 2265582088, 2269630722, 2273677293, 2277723942,\n    2281770277, 2285816118, 2289861391, 2293908247, 2297955870, 2301999709, 2306044120, 2310088597, 2314134053, 2318177990,\n    2322223112, 2326266900, 2330308778, 2334351201, 2338393413, 2342436031, 2346478314, 2350519355, 2354560561, 2358602447,\n    2362642765, 2366683716, 2370724495, 2374763504, 2378804084, 2382843532, 2386880413, 2390919906, 2394959109, 2398996112,\n    2403034927, 2407071577, 2411110078, 2415147307, 2419181034, 2423219093, 2427255367, 2431292536, 2435327045, 2439361501,\n    2443396396, 2447431831, 2451466331, 2455500451, 2459534282, 2463565779, 2467597919, 2471632122, 2475665529, 2479696435,\n    2483729191, 2487761399, 2491793997, 2495825196, 2499856755, 2503887935, 2507918465, 2511947717, 2515978063, 2520007177,\n    2524038155, 2528067401, 2532097043, 2536126664, 2540155255, 2544183491, 2548211228, 2552238285, 2556266399, 2560294002,\n    2564319542, 2568345835, 2572372442, 2576397670, 2580421933, 2584447929, 2588472785, 2592497820, 2596522622, 2600546330,\n    2604571471, 2608595062, 2612618628, 2616643294, 2620665663, 2624687920, 2628709369, 2632732626, 2636754699, 2640776029,\n    2644799757, 2648820585, 2652840994, 2656861044, 2660881979, 2664902170, 2668922912, 2672943760, 2676963401, 2680982125,\n    2685000601, 2689021011, 2693039441, 2697057353, 2701075683, 2705092716, 2709109210, 2713125397, 2717143223, 2721159932,\n    2725176643, 2729193507, 2733210696, 2737225536, 2741242121, 2745257057, 2749272015, 2753286718, 2757299847, 2761314795,\n    2765327756, 2769341791, 2773356225, 2777369850, 2781383306, 2785394924, 2789408169, 2793419860, 2797431717, 2801443922,\n    2805454432, 2809465484, 2813477356, 2817487436, 2821497837, 2825509231, 2829520068, 2833530738, 2837539518, 2841549369,\n    2845558213, 2849566042, 2853574755, 2857584531, 2861594266, 2865601989, 2869610768, 2873619181, 2877625961, 2881633373,\n    2885641353, 2889648502, 2893654733, 2897660376, 2901667770, 2905672946, 2909678043, 2913685600, 2917689568, 2921695146,\n    2925699539, 2929702761, 2933706263, 2937709465, 2941713524, 2945717900, 2949719949, 2953724092, 2957726064, 2961727364,\n    2965730599, 2969734593, 2973737899, 2977740005, 2981742619, 2985744869, 2989743222, 2993744024, 2997743403, 3001742385,\n    3005740846, 3009740083, 3013740632, 3017740443, 3021739912, 3025737894, 3029738266, 3033736354, 3037734260, 3041732620,\n    3045730736, 3049728863, 3053726975, 3057724728, 3061722012, 3065718156, 3069714416, 3073709903, 3077706121, 3081700773,\n    3085694966, 3089690887, 3093686041, 3097682212, 3101677762, 3105672385, 3109665704, 3113660777, 3117654258, 3121648738,\n    3125641477, 3129636165, 3133628489, 3137621629, 3141615091, 3145607391, 3149600532, 3153593186, 3157583551, 3161575400,\n    3165568071, 3169558897, 3173549966, 3177541505, 3181531857, 3185524100, 3189515502, 3193505484, 3197494480, 3201485771,\n    3205474366, 3209464223, 3213453462, 3217442657, 3221430632, 3225418712, 3229406344, 3233394790, 3237380550, 3241367601,\n    3245353518, 3249340672, 3253327262, 3257314501, 3261302137, 3265288786, 3269274318, 3273261676, 3277246756, 3281232235,\n    3285218896, 3289205184, 3293189136, 3297172860, 3301158042, 3305141278, 3309125457, 3313108871, 3317092589, 3321076365,\n    3325059246, 3329042269, 3333024320, 3337007745, 3340990584, 3344973656, 3348954479, 3352936965, 3356918381, 3360899212,\n    3364880246, 3368861514, 3372843128, 3376824341, 3380804536, 3384785252, 3388764045, 3392744352, 3396724969, 3400703302,\n    3404683449, 3408661629, 3412641191, 3416621174, 3420600239, 3424577712, 3428556536, 3432533925, 3436512942, 3440489299,\n    3444467709, 3448443650, 3452420745, 3456398055, 3460376073, 3464354329, 3468330724, 3472306712, 3476280273, 3480257644,\n    3484232867, 3488208449, 3492182057, 3496156616, 3500132047, 3504107018, 3508083271, 3512056531, 3516031243, 3520004496,\n    3523979003, 3527952545, 3531925382, 3535899657, 3539873170, 3543843428, 3547815425, 3551789160, 3555761507, 3559733867,\n    3563706203, 3567677571, 3571648151, 3575618333, 3579587822, 3583559953, 3587530335, 3591499540, 3595471441, 3599441281,\n    3603412533, 3607382383, 3611353499, 3615323157, 3619293204, 3623260438, 3627230054, 3631199924, 3635167788, 3639133977,\n    3643101671, 3647069932, 3651037811, 3655006291, 3658974043, 3662941495, 3666909363, 3670877228, 3674842642, 3678809724,\n    3682776125, 3686743894, 3690708635, 3694674136, 3698640744, 3702607660, 3706572805, 3710536268, 3714502398, 3718465031,\n    3722428991, 3726394088, 3730358421, 3734323031, 3738287024, 3742250941, 3746214561, 3750179004, 3754141753, 3758105608,\n    3762067054, 3766030492, 3769992222, 3773955567, 3777917868, 3781881979, 3785842285, 3789803781, 3793766088, 3797726848,\n    3801688660, 3805649459, 3809611918, 3813571463, 3817534298, 3821493048, 3825453351, 3829412874, 3833371480, 3837330842,\n    3841291749, 3845250279, 3849209920, 3853169493, 3857129155, 3861088365, 3865047067, 3869005617, 3872964725, 3876923182,\n    3880881273, 3884839528, 3888796569, 3892753631, 3896710330, 3900667023, 3904623253, 3908580398, 3912536328, 3916492455,\n    3920449831, 3924406577, 3928362015, 3932316075, 3936271016, 3940227600, 3944182809, 3948137829, 3952093061, 3956048108,\n    3960003559, 3963957671, 3967911833, 3971865657, 3975818018, 3979772869, 3983725586, 3987677658, 3991630533, 3995584016,\n    3999537962, 4003491500, 4007444082, 4011396563, 4015348558, 4019300356, 4023253116, 4027204376, 4031157206, 4035109071,\n    4039061553, 4043014010, 4046965198, 4050915644, 4054865513, 4058816261, 4062767391, 4066716906, 4070666662, 4074616057,\n    4078566781, 4082514143, 4086464266, 4090414411, 4094363532, 4098312828, 4102261058, 4106208569, 4110157418, 4114105592\n};\nint p[P];\nlong long y[P];\n\nint main()\n{\n\tlong long n, n2, n3, bl, bh, ans = 0, k, kl, kh;\n\tint i, j, b1=-1, b2, q2, c;\n\n\tscanf(\"%I64d\", &n);\n\n\t// p\n\tp[0] = 2; k = 1;\n\tfor (i = 3; i <= PMAX; i += 2)\n\t{\n\t\tif (a[i] == 0)\n\t\t{\n\t\t\tp[k++] = i;\n\t\t\tif (i <= PMAX/i)\n\t\t\t\tfor (j = i * i; j <= PMAX; j += i) \n\t\t\t\t\ta[j] = 1;\n\t\t};\n\t}\n\n\t// 2\n\tfor (i = 0; i < P; i++)\n\t{\n\t\tn2 = n / p[i];\n\t\tif (n2 == 0 || n2 < p[i]) break;\n\t\tb2 = (int) (n2 / A); \n\t\tq2 = n2 % A;\n\t\tif (b1 != b2)\n\t\t{\n\t\t\tmemset(a, 0, sizeof(a));\n\t\t\tb1 = b2;\n\t\t\tbl = 1ll * b1 * A;\n\t\t\tbh = bl + q2 + 1;\n\t\t\tc = (b1 == 0? 1: 0);\n\t\t\ty[0] = -1;\n\t\t\tfor (j = 1; j < P; j++)\n\t\t\t{\n\t\t\t\ty[j] = max(bl/p[j]*p[j] + p[j], 1ll * p[j] * p[j]) - bl;\n\t\t\t\tif ((y[j] & 1) == 0) y[j] += p[j];\n\t\t\t}\n\t\t\tfor (kl = bl; kl < bh; kl += L1)\n\t\t\t{\n\t\t\t\tkh = min(kl + L1, bh) - bl;\n\t\t\t\tfor (j = 1; j < P; j++)\n\t\t\t\t{\n  \t\t\t\t\tfor (k = y[j]; k < kh; k += 2ll*p[j]) \n\t\t\t\t\t\ta[k] = 1;\n\t\t\t\t\ty[j] = k;\n\t\t\t\t}\n\t\t\t\tif (kl == 0)\n\t\t\t\t{\n\t\t\t\t\tk = 3;\n\t\t\t\t\ta[2] = 1;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tk = kl - bl + 1;\n\t\t\t\t}\n    \t\t\t\tfor (; k < kh; k+=2)\n\t\t\t\t\ta[k] = a[k+1] = (a[k]==0? ++c: c);\n\t\t\t}\n\t\t} // b\n\t\tans = ans + b[b1] + a[q2] - (i + 1);\n\t}\n\n\t// 3\n\ti = 0; j = P;\n\tfor (;;)\n\t{\n\t\tk = i + (j - i) / 2;\n\t\tif (k == i)\n\t\t\tbreak;\n\t\tif (p[k] > P3)\n\t\t\tn3 = n + 1;\n\t\telse\n\t\t\tn3 = (long long) p[k] * p[k] * p[k];\n\t\tif (n3 > n)\n\t\t\tj = (int) k;\n\t\telse if (n3 < n)\n\t\t\ti = (int) k;\n\t\telse \n\t\t\tbreak;\n\t}\n\tif (p[k]*p[k]*p[k]<=n)\n\t\tans += k + 1;\n\n\tprintf(\"%I64d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "745b2fdd089273597958df54dd83c628", "src_uid": "ffb7762f1d60dc3f16e9b27ea0ecdd7d", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define max(a,b) ((a)>(b)?(a):(b))\n#define min(a,b) ((a)<(b)?(a):(b))\n#define oo 1000000000\n\nstruct case1\n{\n long next[35];\n long num;\n}trie[50005]={{{0},0}};\n\nlong tot=1;\n\nchar str[35][35]={'\\0'};\nlong a[35][35][35]={0};\n\nlong e[2000005]={0};\nlong last[2000005]={0};\nlong now[50005]={0};\nlong totm=0;\n\nstruct case2\n{\n long max;\n long min;\n long win;\n long cost;\n}tree[50005]={{0,0,0,0}};\n\nlong o=1;\nlong hash[50005]={0};\n\nlong find(long x,long st,long en)\n{\n long p=1,i,j;\n long s=0;\n long max=0;\n \n for(;st<=en;st++)\n   {\n    s+=str[x][st]-'a'+1;\n    if(str[x][st]-'a'+1>max)\n     max=str[x][st]-'a'+1;\n    if(!trie[p].next[str[x][st]-'a'])\n     trie[p].next[str[x][st]-'a']=++tot;\n    p=trie[p].next[str[x][st]-'a'];\n   }\n if(trie[p].num==0)\n  {\n   trie[p].num=++o;\n   tree[o].cost=s*max;\n  }\n return trie[p].num;\n}\n\nvoid addedge(long x,long y)\n{\n if(x<=0)\n  x=1;\n if(y<=0)\n  y=1;\n e[++totm]=y;\n last[totm]=now[x];now[x]=totm;\n}\n\nvoid dfs(long x)\n{\n long i;\n \n if(tree[x].max)\n  return;\n \n tree[x].max=0;\n tree[x].min=0;\n \n for(i=now[x];i;i=last[i])\n   {\n    dfs(e[i]);\n    if(tree[e[i]].win==0)\n     tree[x].win=1;\n   }\n for(i=now[x];i;i=last[i])\n   {\n    if(tree[x].win==1&&tree[e[i]].win==1)\n     continue;\n    if(tree[e[i]].min+tree[e[i]].cost>tree[x].max||tree[e[i]].min+tree[e[i]].cost==tree[x].max&&tree[e[i]].max<tree[x].min)\n     {\n      tree[x].max=tree[e[i]].min+tree[e[i]].cost;\n      tree[x].min=tree[e[i]].max;\n     }\n   }\n}\n\nint main()\n{\n long n;\n long i,j;\n long l;\n long len;\n \n scanf(\"%ld\",&n);\n for(i=1;i<=n;i++)\n   scanf(\"%s\",str[i]+1);\n \n for(i=1;i<=n;i++)\n   {\n    len=strlen(str[i]+1);\n    for(l=1;l<=len;l++)\n      for(j=1;j+l-1<=len;j++)\n        {\n         a[i][j][j+l-1]=find(i,j,j+l-1);\n         addedge(a[i][j+1][j+l-1],a[i][j][j+l-1]);\n         addedge(a[i][j][j+l-2],a[i][j][j+l-1]);\n        }\n   }\n \n for(i=1;i<=n;i++)\n   {\n    memset(hash,0,sizeof(hash));\n    len=strlen(str[i]+1);\n    for(j=1;j<=len;j++)\n      for(l=j;l<=len;l++)\n        hash[a[i][j][l]]=1;\n    for(j=1;j<=o;j++)\n      if(hash[j])\n       tree[j].cost++;\n   }\n \n dfs(1);\n if(tree[1].win)\n  printf(\"First\\n\");\n else\n  printf(\"Second\\n\");\n printf(\"%ld %ld\\n\",tree[1].max,tree[1].min);\n \n return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1ee94fdaf2f2168a5acb3a0dd155116c", "src_uid": "d0f8976d9b847f7426dc56cb59b5b5b9", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<math.h>\n#include<time.h>\n#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#define oo 1000000000\n#define pi 3.14159265359\n#define zero(a) (abb(a)<=1e-7)\n#define lowbit(a) ((a)&(-(a)))\n#define min(a,b) ((a)<(b)?(a):(b))\n#define max(a,b) ((a)>(b)?(a):(b))\n#define abb(a) ((a)>0?(a):(-(a)))\n#define cj(x1,y1,x2,y2) ((x1)*(y2)-(x2)*(y2))\n#define dj(x1,y1,x2,y2) ((x1)*(y1)+(y1)*(y2))\n#define dis(x1,y1,x2,y2) sqrt(((x2)-(x1))*((x2)-(x1))+((y2)-(y1))*((y2)-(y1)))\n\nlong head[27001]={0},e[1000001]={0},next[1000001]={0},num[27001]={0},p[2][27001]={0};\nchar rec[27001][35]={0},str[31][35]={0},tmp[35]={0},flag[27001]={0},visit[27001]={0};\nlong tot=1,totm=0;\n\nvoid add(long a,long b)\n{\n   e[++totm]=b;\n   next[totm]=head[a];\n   head[a]=totm;\n}\n\nvoid qs(long x,long y)\n{\n   long i=x,j=y;\n   char t[35];\n   strcpy(t,rec[(x+y)>>1]+1);\n   if (x>=y)\n      return;\n   strcpy(rec[(x+y)>>1]+1,rec[x]+1);\n   while (i<j)\n   {\n      while (i<j&&strcmp(rec[j]+1,t)>0)\n         j--;\n      if (i<j)\n         strcpy(rec[i++]+1,rec[j]+1);\n      while (i<j&&strcmp(rec[i]+1,t)<0)\n         i++;\n      if (i<j)\n         strcpy(rec[j--]+1,rec[i]+1);\n   }\n   strcpy(rec[i]+1,t);\n   qs(x,i-1);\n   qs(i+1,y);\n}\n\nvoid find(long x)\n{\n   long l=0,r=tot,m;\n   while (l<r-1)\n   {\n      m=(l+r)>>1;\n      if (strcmp(rec[m]+1,tmp+1)>=0)\n         r=m;\n      else\n         l=m;\n   }\n   if (!strcmp(rec[r]+1,tmp+1))\n      add(x,r);\n}\n\nvoid dfs(long now)\n{\n   long i;\n   visit[now]=1;\n   p[0][now]=p[1][now]=flag[now]=0;\n   for (i=head[now];i;i=next[i])\n   {\n      if (!visit[e[i]])\n         dfs(e[i]);\n      if (!flag[e[i]]&&!flag[now]||!flag[e[i]]==flag[now]&&p[1][e[i]]+num[e[i]]>p[0][now]||!flag[e[i]]==flag[now]&&p[1][e[i]]+num[e[i]]==p[0][now]&&p[0][e[i]]<p[1][now])\n      {\n         flag[now]=!flag[e[i]];\n         p[0][now]=p[1][e[i]]+num[e[i]];\n         p[1][now]=p[0][e[i]];\n      }\n   }\n}\n\nint main()\n{\n   long i,j,k,l,n,len,s,m;\n   scanf(\"%ld\\n\",&n);\n   for (i=1;i<=n;i++)\n   {\n      gets(str[i]+1);\n      len=strlen(str[i]+1);\n      for (j=1;j<=len;j++)\n         for (k=j;k<=len;k++)\n         {\n            tot++;\n            for (l=1;l<=k-j+1;l++)\n               rec[tot][l]=str[i][j+l-1];\n         }\n   }\n   qs(1,tot);\n   for (i=1;i<=tot;i++)\n   {\n      s=m=0;\n      for (j=1;rec[i][j];j++)\n      {\n         s+=rec[i][j]-'a'+1;\n         m=max(m,rec[i][j]-'a'+1);\n      }\n      num[i]=s*m;\n      for (j=1;j<=n;j++)\n         if (strstr(str[j]+1,rec[i]+1)!=NULL)\n            num[i]++;\n      len=strlen(rec[i]+1);\n      strcpy(tmp+2,rec[i]+1);\n      for (j=1;j<=26;j++)\n      {\n         tmp[1]='a'+j-1;\n         find(i);\n      }\n      strcpy(tmp+1,rec[i]+1);\n      for (j=1;j<=26;j++)\n      {\n         tmp[len+1]='a'+j-1;\n         find(i);\n      }\n   }\n   dfs(1);\n   printf(\"%s\\n%ld %ld\\n\",flag[1]?\"First\":\"Second\",p[0][1],p[1][1]);\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c3f59285b8df4a26efa46b89f9c83ba4", "src_uid": "d0f8976d9b847f7426dc56cb59b5b5b9", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define max(a,b) ((a)>(b)?(a):(b))\n#define min(a,b) ((a)<(b)?(a):(b))\n#define oo 1000000000\n\nstruct case1\n{\n long next[35];\n long num;\n}trie[5005]={{{0},0}};\n\nlong tot=1;\n\nchar str[35][35]={'\\0'};\nlong a[35][35][35]={0};\n\nlong e[500005]={0};\nlong last[500005]={0};\nlong now[5005]={0};\nlong totm=0;\n\nstruct case2\n{\n long max;\n long min;\n long win;\n long cost;\n}tree[5005]={{0,0,0,0}};\n\nlong o=1;\nlong hash[5005]={0};\n\nlong find(long x,long st,long en)\n{\n long p=1,i,j;\n long s=0;\n long max=0;\n \n for(;st<=en;st++)\n   {\n    s+=str[x][st]-'a'+1;\n    if(str[x][st]-'a'+1>max)\n     max=str[x][st]-'a'+1;\n    if(!trie[p].next[str[x][st]-'a'])\n     trie[p].next[str[x][st]-'a']=++tot;\n    p=trie[p].next[str[x][st]-'a'];\n   }\n if(trie[p].num==0)\n  {\n   trie[p].num=++o;\n   tree[o].cost=s*max;\n  }\n return trie[p].num;\n}\n\nvoid addedge(long x,long y)\n{\n if(x<=0)\n  x=1;\n if(y<=0)\n  y=1;\n e[++totm]=y;\n last[totm]=now[x];now[x]=totm;\n}\n\nvoid dfs(long x)\n{\n long i;\n \n tree[x].max=0;\n tree[x].min=0;\n \n for(i=now[x];i;i=last[i])\n   {\n    dfs(e[i]);\n    if(tree[e[i]].win==0)\n     tree[x].win=1;\n   }\n for(i=now[x];i;i=last[i])\n   {\n    if(tree[x].win==1&&tree[e[i]].win==1)\n     continue;\n    if(tree[e[i]].min+tree[e[i]].cost>tree[x].max||tree[e[i]].min+tree[e[i]].cost==tree[x].max&&tree[e[i]].max<tree[x].min)\n     {\n      tree[x].max=tree[e[i]].min+tree[e[i]].cost;\n      tree[x].min=tree[e[i]].max;\n     }\n   }\n}\n\nint main()\n{\n long n;\n long i,j;\n long l;\n \n scanf(\"%ld\",&n);\n for(i=1;i<=n;i++)\n   scanf(\"%s\",str[i]+1);\n \n for(i=1;i<=n;i++)\n   for(l=1;l<=strlen(str[i]+1);l++)\n     for(j=1;j+l-1<=strlen(str[i]+1);j++)\n       {\n        a[i][j][j+l-1]=find(i,j,j+l-1);\n        addedge(a[i][j+1][j+l-1],a[i][j][j+l-1]);\n        addedge(a[i][j][j+l-2],a[i][j][j+l-1]);\n       }\n \n for(i=1;i<=n;i++)\n   {\n    memset(hash,0,sizeof(hash));\n    for(j=1;j<=strlen(str[i]+1);j++)\n      for(l=j;l<=strlen(str[i]+1);l++)\n        hash[a[i][j][l]]=1;\n    for(j=1;j<=o;j++)\n      if(hash[j])\n       tree[j].cost++;\n   }\n \n dfs(1);\n if(tree[1].win)\n  printf(\"First\\n\");\n else\n  printf(\"Second\\n\");\n printf(\"%ld %ld\\n\",tree[1].max,tree[1].min);\n \n return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "653489c8d1323020cf25fbf9772122f7", "src_uid": "d0f8976d9b847f7426dc56cb59b5b5b9", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include<math.h>\n#include<time.h>\n#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#define oo 1000000000\n#define pi 3.14159265359\n#define zero(a) (abb(a)<=1e-7)\n#define lowbit(a) ((a)&(-(a)))\n#define min(a,b) ((a)<(b)?(a):(b))\n#define max(a,b) ((a)>(b)?(a):(b))\n#define abb(a) ((a)>0?(a):(-(a)))\n#define cj(x1,y1,x2,y2) ((x1)*(y2)-(x2)*(y2))\n#define dj(x1,y1,x2,y2) ((x1)*(y1)+(y1)*(y2))\n#define dis(x1,y1,x2,y2) sqrt(((x2)-(x1))*((x2)-(x1))+((y2)-(y1))*((y2)-(y1)))\n\nlong head[27001]={0},e[1000001]={0},next[1000001]={0},num[27001]={0},p[2][27001]={0};\nchar rec[27001][35]={0},str[31][35]={0},tmp[35]={0},flag[27001]={0};\nlong tot=1,totm=0;\n\nvoid add(long a,long b)\n{\n   e[++totm]=b;\n   next[totm]=head[a];\n   head[a]=totm;\n}\n\nvoid qs(long x,long y)\n{\n   long i=x,j=y;\n   char t[35];\n   strcpy(t,rec[(x+y)>>1]+1);\n   if (x>=y)\n      return;\n   strcpy(rec[(x+y)>>1]+1,rec[x]+1);\n   while (i<j)\n   {\n      while (i<j&&strcmp(rec[j]+1,t)>0)\n         j--;\n      if (i<j)\n         strcpy(rec[i++]+1,rec[j]+1);\n      while (i<j&&strcmp(rec[i]+1,t)<0)\n         i++;\n      if (i<j)\n         strcpy(rec[j--]+1,rec[i]+1);\n   }\n   strcpy(rec[i]+1,t);\n   qs(x,i-1);\n   qs(i+1,y);\n}\n\nvoid find(long x)\n{\n   long l=0,r=tot,m;\n   while (l<r-1)\n   {\n      m=(l+r)>>1;\n      if (strcmp(rec[m]+1,tmp+1)>=0)\n         r=m;\n      else\n         l=m;\n   }\n   if (!strcmp(rec[r]+1,tmp+1))\n      add(x,r);\n}\n\nvoid dfs(long now)\n{\n   long i;\n   p[0][now]=p[1][now]=flag[now]=0;\n   for (i=head[now];i;i=next[i])\n   {\n      dfs(e[i]);\n      if (!flag[e[i]]&&!flag[now]||!flag[e[i]]==flag[now]&&p[1][e[i]]+num[e[i]]>p[0][now]||!flag[e[i]]==flag[now]&&p[1][e[i]]+num[e[i]]==p[0][now]&&p[0][e[i]]<p[1][now])\n      {\n         flag[now]=!flag[e[i]];\n         p[0][now]=p[1][e[i]]+num[e[i]];\n         p[1][now]=p[0][e[i]];\n      }\n   }\n}\n\nint main()\n{\n   long i,j,k,l,n,len,s,m;\n   scanf(\"%ld\\n\",&n);\n   for (i=1;i<=n;i++)\n   {\n      gets(str[i]+1);\n      len=strlen(str[i]+1);\n      for (j=1;j<=len;j++)\n         for (k=j;k<=len;k++)\n         {\n            tot++;\n            for (l=1;l<=k-j+1;l++)\n               rec[tot][l]=str[i][j+l-1];\n         }\n   }\n   qs(1,tot);\n   for (i=1;i<=tot;i++)\n   {\n      s=m=0;\n      for (j=1;rec[i][j];j++)\n      {\n         s+=rec[i][j]-'a'+1;\n         m=max(m,rec[i][j]-'a'+1);\n      }\n      num[i]=s*m;\n      for (j=1;j<=n;j++)\n         if (strstr(str[j]+1,rec[i]+1)!=NULL)\n            num[i]++;\n      len=strlen(rec[i]+1);\n      strcpy(tmp+2,rec[i]+1);\n      for (j=1;j<=26;j++)\n      {\n         tmp[1]='a'+j-1;\n         find(i);\n      }\n      strcpy(tmp+1,rec[i]+1);\n      for (j=1;j<=26;j++)\n      {\n         tmp[len+1]='a'+j-1;\n         find(i);\n      }\n   }\n   dfs(1);\n   printf(\"%s\\n%ld %ld\\n\",flag[1]?\"First\":\"Second\",p[0][1],p[1][1]);\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6b145dbe3b70b5d371ec36856e7abc4f", "src_uid": "d0f8976d9b847f7426dc56cb59b5b5b9", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\n#define N\t30\n#define T\t(30 * 31 / 2)\n#define NU\t(N * T)\n#define NV\t(NU * 3)\n\nchar *strndup_(char *s, int n) {\n\tchar *s_ = malloc(n + 1);\n\n\tstrncpy(s_, s, n);\n\ts_[n] = 0;\n\treturn s_;\n}\n\nstruct V {\n\tchar *s;\n\tint i, h;\n} vv_[NV], *vv[NV];\n\nint compare(const void *a, const void *b) {\n\tstruct V *u = *(struct V **) a;\n\tstruct V *v = *(struct V **) b;\n\tint mu = strlen(u->s), mv = strlen(v->s);\n\tint c;\n\n\tif (mu != mv)\n\t\treturn mu - mv;\n\tc = strcmp(u->s, v->s);\n\treturn c != 0 ? c : u->i - v->i;\n}\n\nint score(char *s) {\n\tint n = strlen(s), i;\n\tint sum, max;\n\n\tsum = max = 0;\n\tfor (i = 0; i < n; i++) {\n\t\tint a = s[i] - 'a' + 1;\n\n\t\tsum += a;\n\t\tif (max < a)\n\t\t\tmax = a;\n\t}\n\treturn sum * max;\n}\n\nint xx[NU + 1];\nchar ww[NU + 1];\nint ss[NU + 1], tt[NU + 1];\n\nvoid push(int p, int i) {\n\tint s = tt[i] + xx[i], t = ss[i];\n\n\tif (!ww[p]) {\n\t\tif (!ww[i])\n\t\t\tww[p] = 1, ss[p] = s, tt[p] = t;\n\t\telse if (ss[p] < s || ss[p] == s && tt[p] > t)\n\t\t\tss[p] = s, tt[p] = t;\n\t} else if (!ww[i] && (ss[p] < s || ss[p] == s && tt[p] > t))\n\t\tss[p] = s, tt[p] = t;\n}\n\nint main() {\n\tstatic int pp[NU + 1], qq[NU + 1];\n\tint n, nv, k, i;\n\n\tscanf(\"%d\", &n);\n\tnv = 0;\n\tfor (i = 0; i < n; i++) {\n\t\tstatic char s[32];\n\t\tint m, l, r;\n\n\t\tscanf(\"%s\", s), m = strlen(s);\n\t\tfor (l = 0; l < m; l++)\n\t\t\tfor (r = l; r < m; r++) {\n\t\t\t\tstruct V *v, *p, *q;\n\t\t\t\tchar *t = strndup_(s + l, r - l + 1);\n\n\t\t\t\tv = vv[nv] = &vv_[nv], nv++;\n\t\t\t\tv->s = t, v->i = i;\n\t\t\t\tp = vv[nv] = &vv_[nv], nv++;\n\t\t\t\tp->s = strndup_(t + 1, r - l), p->i = -1;\n\t\t\t\tq = vv[nv] = &vv_[nv], nv++;\n\t\t\t\tq->s = strndup_(t, r - l), p->i = -1;\n\t\t\t}\n\t}\n\tqsort(vv, nv, sizeof *vv, compare);\n\tk = 0;\n\tfor (i = 0; i < nv; ) {\n\t\tchar *s = vv[i]->s;\n\t\tint x, j;\n\n\t\tfor (j = i; j < nv && strcmp(vv[j]->s, s) == 0; j++)\n\t\t\tvv[j]->h = k;\n\t\tx = score(s);\n\t\twhile (i < j) {\n\t\t\tif (vv[i]->i != -1 && (i + 1 == j || vv[i]->i != vv[i + 1]->i))\n\t\t\t\tx++;\n\t\t\ti++;\n\t\t}\n\t\txx[k++] = x;\n\t}\n\tfor (i = 0; i < nv; i += 3) {\n\t\tstruct V *v = &vv_[i + 0];\n\t\tstruct V *p = &vv_[i + 1];\n\t\tstruct V *q = &vv_[i + 2];\n\n\t\tpp[v->h] = p->h;\n\t\tqq[v->h] = q->h;\n\t}\n\tfor (i = k - 1; i > 0; i--) {\n\t\tpush(pp[i], i);\n\t\tpush(qq[i], i);\n\t}\n\tprintf(ww[0] ? \"First\\n\" : \"Second\\n\");\n\tprintf(\"%d %d\\n\", ss[0], tt[0]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cb8436dcb6a42a630f1948293ae208b3", "src_uid": "d0f8976d9b847f7426dc56cb59b5b5b9", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint s1,s2;\n\nint val(char s[], char t[], int i, int j)\n{\n    int max1 = -1,max = -1;\n    for (int k = i; k < s1-(s2-j-1); k++){\n        if(s[k]==t[j]){\n            if(j < s2-1){\n                int temp = val(s,t,k+1,j+1);\n                if(temp!=-1){\n                    if(temp > k-i) max1 = temp;\n                    else max1 = k-i;\n                }\n                else break;\n                if(max1> max) max = max1;\n            }\n            else{\n                if(k - i > s1-k-1) max1 = k - i;\n                else max1 = s1 -k -1;\n                if (max1 > max) max = max1;\n            }\n        }\n        if(max >= s1-s2) return max;\n    }\n    return max;\n}\n\nint main()\n{\n    char s[201],t[201];\n    scanf(\"%s\",s);\n    scanf(\"%s\",t);\n    s1= strlen(s);\n    s2= strlen(t);\n    if(!strcmp(s,t)) printf(\"0\");\n    else printf(\"%d\",val(s,t,0,0));\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ae9c8887eb5ee9d37e86da67778d7aa6", "src_uid": "0fd33e1bdfd6c91feb3bf00a2461603f", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n \nint s1,s2,dp[200000][3];\n \nint val(char s[], char t[], int i, int j)\n{\n    int max1 = -1,max2=-1,max[2] = {-1,-1, i};\n    //if(dp[j][0]==-1 && dp[j][1] == -1) return -1;\n    if(i<dp[j][2] && (dp[j][0] < dp[j][1])) return dp[j][1];\n    for (int k = i; k < s1-(s2-j-1); k++){\n        \n        if(s[k]==t[j]){\n            \n            if(j < s2-1){\n                int temp = val(s,t,k+1,j+1);\n                if(temp!=-1){\n                    max2 = temp;\n                    max1 = k-i;\n                }\n                else break;\n                \n                if((max1> max[0] && max1> max[1])|| (max2 > max[0]&& max2>max[1])) {\n                    max[0] = max1;\n                    max[1] = max2;\n                    max[2] = k;\n                }\n                \n            }\n            else{\n                max1 = k - i;\n                max2 = s1 -k -1;\n                if((max1> max[0] && max1> max[1])|| (max2 > max[0]&& max2>max[1])) {\n                    max[0] = max1;\n                    max[1] = max2;\n                    max[2] = k;\n                }\n            }\n        }\n        if(max[0] >= s1-s2){\n            dp[j][0] = max[0];\n            dp[j][1] = max[1];\n            dp[j][2] = max[2];\n            return max[0];\n        } \n        if(max[1] >= s1-s2){\n            dp[j][0] = max[0];\n            dp[j][1] = max[1];\n            dp[j][2] = max[2];\n            return max[1];\n        }\n    }\n    dp[j][0] = max[0];\n    dp[j][1] = max[1];\n    dp[j][2] = max[2];\n    if(max[0] > max[1]) return max[0];\n    else return max[1];\n}\n \nint main()\n{\n    char s[200001],t[200001];\n    scanf(\"%s\",s);\n    scanf(\"%s\",t);\n    for(int i=0;i< 3; i++){\n        for(int j=0;j< 200000; j++) dp[j][i] = -2;\n    }\n    s1= strlen(s);\n    s2= strlen(t);\n    printf(\"%d\",val(s,t,0,0));\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "22627f762602779e39d992f32b9803ad", "src_uid": "0fd33e1bdfd6c91feb3bf00a2461603f", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint s1,s2;\n\nint val(char s[], char t[], int i, int j)\n{\n    int max1 = -1,max = -1;\n    for (int k = i; k < s1; k++){\n        if(s[k]==t[j]){\n            if(j < s2-1){\n                int temp = val(s,t,k+1,j+1);\n                if(temp!=-1){\n                    if(temp > k-i) max1 = temp;\n                    else max1 = k-i;\n                }\n                else break;\n                if(max1> max) max = max1;\n            }\n            else{\n                if(k - i > s1-k-1) max1 = k - i;\n                else max1 = s1 -k -1;\n                if (max1 > max) max = max1;\n            }\n        }\n        if(max >= s1-s2) return max;\n    }\n    return max;\n}\n\nint main()\n{\n    char s[201],t[201];\n    scanf(\"%s\",s);\n    scanf(\"%s\",t);\n    s1= strlen(s);\n    s2= strlen(t);\n    if(!strcmp(s,t)) printf(\"0\");\n    else printf(\"%d\",val(s,t,0,0));\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "66dd882df94b5c3aac05485e92c45c72", "src_uid": "0fd33e1bdfd6c91feb3bf00a2461603f", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nint s1,s2;\n\nint val(char s[], char t[], int i, int j)\n{\n    int max1 = -1,max = -1;\n    for (int k = i; k < s1; k++){\n        if(s[k]==t[j]){\n            if(j < s2-1){\n                int temp = val(s,t,k+1,j+1);\n                if(temp!=-1){\n                    if(temp > k-i) max1 = temp;\n                    else max1 = k-i;\n                }\n                else break;\n                if(max1> max) max = max1;\n            }\n            else{\n                if(k - i > s1-k-1) max1 = k - i;\n                else max1 = s1 -k -1;\n                if (max1 > max) max = max1;\n            }\n        }\n    }\n    return max;\n}\n\nint main()\n{\n    char s[201],t[201];\n    scanf(\"%s\",s);\n    scanf(\"%s\",t);\n    s1= strlen(s);\n    s2= strlen(t);\n    if(!strcmp(s,t)) printf(\"0\");\n    else printf(\"%d\",val(s,t,0,0));\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "368c0a256b3233cfd3223caa75e6f3f5", "src_uid": "0fd33e1bdfd6c91feb3bf00a2461603f", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#define size 101\nint max_(int x,int y)\n{\n\treturn x>y?x:y;\n}\nmain()\n{\n\tchar s[size],t[size];\n\tscanf(\"%s\",s);\n\tscanf(\"%s\",t);\n\tint i,ans=0,j,p,pos,ss,tt;\n\tss=strlen(s);\n\ttt=strlen(t);\n\tfor(i=0;i<ss;++i)\n\t{\n\t\tfor(j=i;j<ss;++j)\n\t\t{\n\t\t\tpos=0;\n\t\t\tfor(p=0;p<ss;++p)\n\t\t\t{\n\t\t\t\tif(i<=p && p<=j)\n\t\t\t\t   continue;\n\t\t\t\tif(pos<tt && t[pos]==s[p])\n\t\t\t\t   pos++;\n\t\t\t}\n\t\t\tif(pos==tt)\n\t\t\t{\n\t\t\t\tans=max_(ans,j-i+1);\n\t\t\t}\n\t\t}\n\t}\nprintf(\"%d\",ans);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f7a0837ad6bc7b8acc96269b1c7db649", "src_uid": "0fd33e1bdfd6c91feb3bf00a2461603f", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <stdbool.h>\n\n#define N 2000000\n#define MOD 1000000007\n\nint maxp[N + 1];\nint lcm[N + 1];\nint lcm_cnt[N + 1];\nint p[200000];\nint q[200000], qp;\n\nint max(int x, int y) {\n  return x > y ? x : y;\n}\n\nint cmp(const void *a, const void *b) {\n  return *(int *)b - *(int *)a;\n}\n\nint main(void) {\n  for (int i = 0; i <= N; i++) {\n    maxp[i] = i;\n  }\n  for (int i = 2; i <= N; i++) {\n    if (maxp[i] == i) {\n      for (int j = i * 2; j <= N; j += i) {\n        maxp[j] = i;\n      }\n    }\n  }\n  \n  int n;\n  scanf(\"%d\", &n);\n  for (int i = 0; i < n; i++) {\n    scanf(\"%d\", &p[i]);\n  }\n  qsort(p, n, sizeof(int), cmp);\n  int one = 0;\n  for (int i = 0; i < n; i++) {\n    int x = p[i];\n    if (lcm[x] == 0) {\n      lcm[x] = 1;\n      continue;\n    }\n    q[qp++] = x;\n    x--;\n    while (x != 1) {\n      int p = maxp[x];\n      int e = 0;\n      while (x % p == 0) {\n        x /= p;\n        e++;\n      }\n      if (lcm[p] < e) {\n        lcm[p] = e;\n        lcm_cnt[p] = 1;\n      } else if (lcm[p] == e) {\n        lcm_cnt[p]++;\n      }\n    }\n  }\n  for (int i = 0; i < qp; i++) {\n    int x = q[i] - 1;\n    bool forall = true;\n    while (x != 1) {\n      int p = maxp[x];\n      int e = 0;\n      while (x % p == 0) {\n        x /= p;\n        e++;\n      }\n      if (lcm[p] == e && lcm_cnt[p] == 1) {\n        forall = false;\n      }\n    }\n    if (forall) {\n      one = 1;\n    }\n  }\n  long long ans = 1;\n  for (int i = 0; i <= N; i++) {\n    for (int j = 0; j < lcm[i]; j++) {\n      ans *= i;\n      ans %= MOD;\n    }\n  }\n  ans += one;\n  ans %= MOD;\n  printf(\"%lld\\n\", ans);\n  return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f96b65468d75e6756a7d75a793ad0119", "src_uid": "816a82bee65cf79ba8e4d61babcd0301", "difficulty": 2900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <stdbool.h>\n\n#define N 2000000\n#define MOD 1000000007\n\nint maxp[N + 1];\nint lcm[N + 1];\nint p[200000];\n\nint max(int x, int y) {\n  return x > y ? x : y;\n}\n\nint cmp(const void *a, const void *b) {\n  return *(int *)b - *(int *)a;\n}\n\nint main(void) {\n  for (int i = 0; i <= N; i++) {\n    maxp[i] = i;\n  }\n  for (int i = 2; i <= N; i++) {\n    if (maxp[i] == i) {\n      for (int j = i * 2; j <= N; j += i) {\n        maxp[j] = i;\n      }\n    }\n  }\n  \n  int n;\n  scanf(\"%d\", &n);\n  for (int i = 0; i < n; i++) {\n    scanf(\"%d\", &p[i]);\n  }\n  qsort(p, n, sizeof(int), cmp);\n  int one = 0;\n  for (int i = 0; i < n; i++) {\n    int x = p[i];\n    if (lcm[x] == 0) {\n      lcm[x] = 1;\n      continue;\n    }\n    bool any = false;\n    x--;\n    while (x != 1) {\n      int p = maxp[x];\n      int e = 0;\n      while (x % p == 0) {\n        x /= p;\n        e++;\n      }\n      if (lcm[p] < e) {\n        lcm[p] = e;\n        any = true;\n      }\n    }\n    if (!any) {\n      one = 1;\n    }\n  }\n  long long ans = 1;\n  for (int i = 0; i <= N; i++) {\n    for (int j = 0; j < lcm[i]; j++) {\n      ans *= i;\n      ans %= MOD;\n    }\n  }\n  ans += one;\n  ans %= MOD;\n  printf(\"%lld\\n\", ans);\n  return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "57ea34a27b431592118af18ad682f13c", "src_uid": "816a82bee65cf79ba8e4d61babcd0301", "difficulty": 2900.0}
{"lang": "GNU C11", "source_code": "/* https://codeforces.com/blog/entry/89260 */\n#include <stdio.h>\n\n#define M\t16\n\nint main() {\n\tstatic char used[M];\n\tint n, m;\n\n\tscanf(\"%d%d\", &n, &m);\n\twhile (n > 0) {\n\t\tif (used[n % m]) {\n\t\t\tprintf(\"NO\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\tused[n % m] = 1;\n\t\tn /= m;\n\t}\n\tprintf(\"YES\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8182c4be42802236cfbd8d18cf4ddd11", "src_uid": "a8945bb1082fefe70e6898a8bec1ce3f", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n \r\n#define M\t16\r\n \r\nint main() {\r\n\tstatic char used[M];\r\n\tint n, m;\r\n \r\n\tscanf(\"%d%d\", &n, &m);\r\n\twhile (n > 0) {\r\n\t\tif (used[n % m]) {\r\n\t\t\tprintf(\"NO\\n\");\r\n\t\t\treturn 0;\r\n\t\t}\r\n\t\tused[n % m] = 1;\r\n\t\tn /= m;\r\n\t}\r\n\tprintf(\"YES\\n\");\r\n\treturn 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c1fe402827105de282dd324e4b7bdc3b", "src_uid": "a8945bb1082fefe70e6898a8bec1ce3f", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdbool.h>\r\n#include <stdio.h>\r\n \r\nint main() {\r\n    int n, m;\r\n    scanf(\"%d %d\", &n, &m);\r\n \r\n    int digits[14] = {0};\r\n    bool dup = true;\r\n    while (n) {\r\n        int d = n % m;\r\n        if (digits[d]) {\r\n            dup = false;\r\n            break;\r\n        } else {\r\n            digits[d] = 1;\r\n        }\r\n \r\n        n /= m;\r\n    }\r\n \r\n    if (dup) {\r\n        puts(\"YES\");\r\n    } else {\r\n        puts(\"NO\");\r\n    }\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "12e71ad83a6977ab72364e736e1d92fc", "src_uid": "a8945bb1082fefe70e6898a8bec1ce3f", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main() {\n\tint n, b;\n\n\tscanf(\"%d%d\", &n, &b);\n\twhile (n > 0) {\n\t\tif (n % b > 1) {\n\t\t\tprintf(\"YES\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\tn /= b;\n\t}\n\tprintf(\"NO\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5189930a9f015f09d954ab4124a01c3a", "src_uid": "a8945bb1082fefe70e6898a8bec1ce3f", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdbool.h>\n#include <stdio.h>\n\nint main() {\n    int n, m;\n    scanf(\"%d %d\", &n, &m);\n\n    int digits[9] = {0};\n    bool dup = true;\n    while (n) {\n        int d = n % m;\n        if (digits[d]) {\n            dup = false;\n            break;\n        } else {\n            digits[d] = 1;\n        }\n\n        n /= m;\n    }\n\n    if (dup) {\n        puts(\"YES\");\n    } else {\n        puts(\"NO\");\n    }\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b0a3c574a9469a1043b5e6e38a69f268", "src_uid": "a8945bb1082fefe70e6898a8bec1ce3f", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\ntypedef long long unsigned llu;\ntypedef long long ll;\ntypedef unsigned u;\nllu G(llu a,llu b){return b?G(b,a%b):a;}\nll lx,ly;\nll egcd(ll a,ll b)\n{\n\tlong long r,q,x=0,y=1;lx=1;ly=0;\n\tu ee=1;\n\twhile(b!=0)\n\t{\n\t\tq=a/b;\n\t\tr=b;b=a%b;a=r;\n\t\tr=x;x=lx-q*x;lx=r;\n\t\tr=y;y=ly-q*y;ly=r;\n\t\tif((ee^=1)&&(q-(b==0)))printf(\"%I64iB\",q-(b==0));\n\t\telse if((q-(b==0)))printf(\"%I64iA\",q-(b==0));\n\t}\n\treturn a;\n}\nint main()\n{\n\tllu a,b;u i,j,k;\n\tscanf(\"%I64u%I64u\",&a,&b);\n\tif(G(a,b)!=1){printf(\"Impossible\\n\");return 0;}\n\tegcd(a,b);\n\tputchar('\\n');\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c125ca273f950a0ab6f17cd90e0decda", "src_uid": "6a9ec3b23bd462353d985e0c0f2f7671", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long gcd(long long a,long long b)\n{\n    if(a%b==0)\n        return b;\n    else\n        return gcd(b,a%b);\n}\nint main()\n{\n    long long x,y,test;\n    scanf(\"%I64d %I64d\",&x,&y);\n    test=gcd(x,y);\n    //printf(\"%I64d\",test);\n    if(test>1)\n    {\n        printf(\"Impossible\");\n        return 0;\n    }\n    else\n    {\n        while(x && y)\n        {\n            if(x>y)\n            {\n                printf(\"%I64dA\",(x-1)/y);\n                x=x%y;\n            }\n            else\n            {\n                printf(\"%I64dB\",(y-1)/x);\n                y=y%x;\n            }\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "861b0196911b880d52501b18889a5a5d", "src_uid": "6a9ec3b23bd462353d985e0c0f2f7671", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long gcd(long long a,long long b)\n{\n    if(a%b==0)\n        return b;\n    else\n        return gcd(b,a%b);\n}\nint main()\n{\n    long long x,y,test;\n    scanf(\"%I64d %I64d\",&x,&y);\n    test=gcd(x,y);\n    printf(\"%I64d\",test);\n    if(test>1)\n    {\n        printf(\"Impossible\");\n        return 0;\n    }\n    else\n    {\n        while(x && y)\n        {\n            if(x>y)\n            {\n                printf(\"%I64dA\",(x-1)/y);\n                x=x%y;\n            }\n            else\n            {\n                printf(\"%I64dB\",(y-1)/x);\n                y=y%x;\n            }\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "707dcdc0fd6d97baf0cd235e99dcb349", "src_uid": "6a9ec3b23bd462353d985e0c0f2f7671", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long gcd(long a,long b)\n{\n    if(a%b==0)\n        return b;\n    else\n        return gcd(b,a%b);\n}\nint main()\n{\n    long long x,y,test;\n    scanf(\"%I64d %I64d\",&x,&y);\n    test=gcd(x,y);\n    if(test>1)\n        printf(\"Impossible\");\n    else\n    {\n        while(x && y)\n        {\n            if(x>y)\n            {\n                printf(\"%I64dA\",(x-1)/y);\n                x=x%y;\n            }\n            else\n            {\n                printf(\"%I64dB\",(y-1)/x);\n                y=y%x;\n            }\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "87e0eb646bf0b634bb5b6b2eeeeb0efb", "src_uid": "6a9ec3b23bd462353d985e0c0f2f7671", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long gcd(long long a,long long b)\n{\n    if(a%b==0)\n        return b;\n    else\n        return gcd(b,a%b);\n}\nint main()\n{\n    long long x,y,test;\n    scanf(\"%I64d %I64d\",&x,&y);\n    test=gcd(x,y);\n    if(test>=1)\n        printf(\"Impossible\");\n    else\n    {\n        while(x && y)\n        {\n            if(x>y)\n            {\n                printf(\"%I64dA\",(x-1)/y);\n                x=x%y;\n            }\n            else\n            {\n                printf(\"%I64dB\",(y-1)/x);\n                y=y%x;\n            }\n        }\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a9185dfd12de2ed3b3060a58d638e24c", "src_uid": "6a9ec3b23bd462353d985e0c0f2f7671", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main()\n{\nlong long int n,i,p,sum;\nsum=0;\nscanf(\"%I64d\",&n);\nfor(i=1;i<=n;i=i*2)\n{\n    p=i*2;\n    if(n%p>p/2) p=n/p+1;\n    else p=n/p;\n    sum=sum+p*i;\n}\nprintf(\"%I64d\",sum);\nreturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c6946164e45b7ed2a7945bdf5b56cef0", "src_uid": "a98f0d924ea52cafe0048f213f075891", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint main()\n{\nlong long int s=0,t,i=1;\ndouble n;\nscanf (\"%lf\",&n);\nn--;\nt=(long long int)(n/2+0.5);\nwhile (t)\n{\ns+=t*i;\ni*=2;\nt=(long long int)(n/(2*i)+0.5);\n}\nprintf (\"%I64d\\n\",s);\nreturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "2300e7b581fa0aa724674341804c8816", "src_uid": "a98f0d924ea52cafe0048f213f075891", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    long long int n;\n    scanf(\"%lld\",&n);\n    printf(\"%lld\\n\",(n/2)+2*((n/2)+(n%2)-1));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "53cba9de9868a471f01e75518ac37d61", "src_uid": "a98f0d924ea52cafe0048f213f075891", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "//set many funcs template\n#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<stdbool.h>\n#include<time.h>\n#define inf 1072114514\n#define llinf 4154118101919364364\n#define mod 1000000007\n#define pi 3.1415926535897932384\n\nint max(int a,int b){if(a>b){return a;}return b;}\nint min(int a,int b){if(a<b){return a;}return b;}\nint zt(int a,int b){return max(a,b)-min(a,b);}\nint round(int a,int b){if((a%b)*2 >= b){return (a/b)+1;}return a/b;}\nint ceil(int a,int b){if(a%b==0){return a/b;}return (a/b)+1;}\nint gcd(int a,int b){int c;while(b!=0){c=a%b;a=b;b=c;}return a;}\nint lcm(int a,int b){int c=gcd(a,b);a/=c;return a*b;}\nint nCr(int a,int b){int i,r=1;for(i=1;i<=b;i++){r*=(a+1-i);r/=i;}return r;}\nint fact(int a){int i,r=1;for(i=1;i<=a;i++){r*=i;}return r;}\nint pow(int a,int b){int i,r=1;for(i=1;i<=b;i++){r*=a;}return r;}\nlong long llmax(long long a,long long b){if(a>b){return a;}return b;}\nlong long llmin(long long a,long long b){if(a<b){return a;}return b;}\nlong long llzt(long long a,long long b){return llmax(a,b)-llmin(a,b);}\nlong long llround(long long a,long long b){if((a%b)*2 >= b){return (a/b)+1;}return a/b;}\nlong long llceil(long long a,long long b){if(a%b==0){return a/b;}return (a/b)+1;}\nlong long llgcd(long long a,long long b){long long c;while(b!=0){c=a%b;a=b;b=c;}return a;}\nlong long lllcm(long long a,long long b){long long c=llgcd(a,b);a/=c;return a*b;}\nlong long llnCr(long long a,long long b){long long i,r=1;for(i=1;i<=b;i++){r*=(a+1-i);r/=i;}return r;}\nlong long llfact(long long a){long long i,r=1;for(i=1;i<=a;i++){r*=i;}return r;}\nlong long llpow(long long a,long long b){long long i,r=1;for(i=1;i<=b;i++){r*=a;}return r;}\ndouble dbmax(double a,double b){if(a>b){return a;}return b;}\ndouble dbmin(double a,double b){if(a<b){return a;}return b;}\ndouble dbzt(double a,double b){return dbmax(a,b)-dbmin(a,b);}\nint sortfncsj(const void *a,const void *b){if(*(int *)a>*(int *)b){return 1;}if(*(int *)a==*(int *)b){return 0;}return -1;}\nint sortfnckj(const void *a,const void *b){if(*(int *)a<*(int *)b){return 1;}if(*(int *)a==*(int *)b){return 0;}return -1;}\nint llsortfncsj(const void *a,const void *b){if(*(long long *)a>*(long long *)b){return 1;}if(*(long long *)a==*(long long *)b){return 0;}return -1;}\nint llsortfnckj(const void *a,const void *b){if(*(long long *)a<*(long long *)b){return 1;}if(*(long long *)a==*(long long *)b){return 0;}return -1;}\nint dbsortfncsj(const void *a,const void *b){if(*(double *)a>*(double *)b){return 1;}if(*(double *)a==*(double *)b){return 0;}return -1;}\nint dbsortfnckj(const void *a,const void *b){if(*(double *)a<*(double *)b){return 1;}if(*(double *)a==*(double *)b){return 0;}return -1;}\nint strsortfncsj(const void *a,const void *b){return strcmp((char *)a,(char *)b);}\nint strsortfnckj(const void *a,const void *b){return strcmp((char *)b,(char *)a);}\n\nint main(void){\n    long long i,j,n,m,k,a[262144],b,c,w,r=0,l,t,u;\n    double d;\n    char s[262144];\n    scanf(\"%lld\",&n);n--;u=0;\n    //l=strlen(s);\n    k=llpow(2,50);\n    for(i=50;i>=0;i--){\n        r+=(k*((n/k)-u));\n        u+=(n/k);k/=2;\n    }\n    //qsort(a,n,sizeof(int),sortfncsj);\n    printf(\"%lld\\n\",r);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ee0c3efbab4acf2418dd5325e9f2dfc6", "src_uid": "a98f0d924ea52cafe0048f213f075891", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint main()\n{\n    long long int i=0,n,count=0,temp,mod;\n    scanf(\"%lld\",&n);\n    while(1)\n    {\n        mod=n%(1<<(i+1));\n        temp=n/(1<<(i+1));\n        // printf(\"%lld %lld\\n\",temp , mod);\n        if(mod>(1<<i))\n            count+=(1<<i)*(temp+1);\n        else{\n                count+=(1<<i)*(temp);\n            }\n        if(temp==0)\n            break;\n        i++;\n    }\n    printf(\"%lld\\n\", count);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1d0954b718a719c25b0d745a0392d20c", "src_uid": "a98f0d924ea52cafe0048f213f075891", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t100000\n#define M\t100000\n#define A\t200000\n#define L_\t18\t/* L_ = ceil(log2(A + 1)) */\n#define N_\t(1 << L_)\n#define M0\t469762049\t/* M0 = 56 * 2^23 + 1 */\n#define M1\t595591169\t/* M1 = 71 * 2^23 + 1 */\n\nint MM[2] = { M0, M1 };\n\nlong long power(int a, int k, int md) {\n\tlong long b = a, p = 1;\n\n\twhile (k) {\n\t\tif (k & 1)\n\t\t\tp = p * b % md;\n\t\tb = b * b % md;\n\t\tk >>= 1;\n\t}\n\treturn p;\n}\n\nint wu[2][L_ + 1], wv[2][L_ + 1], VV[2], V01;\n\nvoid init() {\n\tint g, l, u, v;\n\n\tV01 = power(M0, M1 - 2, M1);\n\tfor (g = 0; g < 2; g++) {\n\t\tint md = MM[g];\n\n\t\tu = power(3, md - 1 >> L_, md), v = power(u, md - 2, md);\n\t\tVV[g] = power(N_, md - 2, md);\n\t\tfor (l = L_; l > 0; l--) {\n\t\t\twu[g][l] = u, wv[g][l] = v;\n\t\t\tu = (long long) u * u % md, v = (long long) v * v % md;\n\t\t}\n\t}\n}\n\nvoid ntt(int *aa, int g, int inverse) {\n\tint md = MM[g], i, j, l, r;\n\n\tfor (i = 0, j = 1; j < N_; j++) {\n\t\tint n, tmp;\n\n\t\tn = N_ >> 1;\n\t\twhile ((i ^= n) < n)\n\t\t\tn >>= 1;\n\t\tif (i < j)\n\t\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\t}\n\tfor (l = 1; l <= L_; l++) {\n\t\tint n = 1 << l, m = n >> 1;\n\t\tlong long u = inverse ? wv[g][l] : wu[g][l], w = 1;\n\n\t\tfor (r = 0; r < m; r++) {\n\t\t\tfor (i = r; (j = i + m) < N_; i += n) {\n\t\t\t\tint a = aa[i], b = aa[j] * w % md;\n\n\t\t\t\tif ((aa[i] = a + b) >= md)\n\t\t\t\t\taa[i] -= md;\n\t\t\t\tif ((aa[j] = a - b) < 0)\n\t\t\t\t\taa[j] += md;\n\t\t\t}\n\t\t\tw = w * u % md;\n\t\t}\n\t}\n}\n\nlong long garner(int r0, int r1) {\n\tr1 = (long long) (r1 - r0) * V01 % M1;\n\tif (r1 < 0)\n\t\tr1 += M1;\n\treturn (long long) r1 * M0 + r0;\n}\n\nint main() {\n\tstatic long long ans[A + 1];\n\tstatic int aa[N], bb[M], aaa[2][2][N_], bbb[2][2][N_], cc[2][N_];\n\tint n, m, q, g, h, h1, h2, i, j, x, y, z, c;\n\n\tinit();\n\tscanf(\"%d%d%d\", &n, &m, &q);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d\", &aa[i]);\n\tfor (j = 0; j < m; j++)\n\t\tscanf(\"%d\", &bb[j]);\n\tif (n == 1 && m == 1)\n\t\tans[aa[0] + bb[0]] = 1;\n\telse if (n == 1) {\n\t\tif (bb[0] > bb[1])\n\t\t\tans[aa[0] + bb[0]]--;\n\t\tif (bb[m - 1] >= bb[m - 2])\n\t\t\tans[aa[0] + bb[m - 1]]--;\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tx = bb[j] >= bb[j - 1], y = bb[j] > bb[j + 1], c = aa[0] + bb[j];\n\t\t\tif (!x && !y)\n\t\t\t\tans[c]--;\n\t\t\telse if (x && y)\n\t\t\t\tans[c]++;\n\t\t}\n\t} else if (m == 1) {\n\t\tif (aa[0] > aa[1])\n\t\t\tans[aa[0] + bb[0]]--;\n\t\tif (aa[n - 1] >= aa[n - 2])\n\t\t\tans[aa[n - 1] + bb[0]]--;\n\t\tfor (i = 1; i < n - 1; i++) {\n\t\t\tx = aa[i] >= aa[i - 1], y = aa[i] > aa[i + 1], c = aa[i] + bb[0];\n\t\t\tif (!x && !y)\n\t\t\t\tans[c]--;\n\t\t\telse if (x && y)\n\t\t\t\tans[c]++;\n\t\t}\n\t} else {\n\t\tz = aa[0] > aa[1];\n\t\ty = bb[0] > bb[1], c = aa[0] + bb[0];\n\t\tif (z == y)\n\t\t\tans[c]--;\n\t\tx = bb[m - 1] >= bb[m - 2], c = aa[0] + bb[m - 1];\n\t\tif (z == x)\n\t\t\tans[c]--;\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tx = bb[j] >= bb[j - 1], y = bb[j] > bb[j + 1], c = aa[0] + bb[j];\n\t\t\tif (!z) {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]--;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]++;\n\t\t\t} else {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]++;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]--;\n\t\t\t}\n\t\t}\n\t\tz = aa[n - 1] >= aa[n - 2];\n\t\ty = bb[0] > bb[1], c = aa[n - 1] + bb[0];\n\t\tif (z == y)\n\t\t\tans[c]--;\n\t\tx = bb[m - 1] >= bb[m - 2], c = aa[n - 1] + bb[m - 1];\n\t\tif (z == x)\n\t\t\tans[c]--;\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tx = bb[j] >= bb[j - 1], y = bb[j] > bb[j + 1], c = aa[n - 1] + bb[j];\n\t\t\tif (!z) {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]--;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]++;\n\t\t\t} else {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]++;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]--;\n\t\t\t}\n\t\t}\n\t\tz = bb[0] > bb[1];\n\t\tfor (i = 1; i < n - 1; i++) {\n\t\t\tx = aa[i] >= aa[i - 1], y = aa[i] > aa[i + 1], c = aa[i] + bb[0];\n\t\t\tif (!z) {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]--;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]++;\n\t\t\t} else {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]++;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]--;\n\t\t\t}\n\t\t}\n\t\tz = bb[m - 1] >= bb[m - 2];\n\t\tfor (i = 1; i < n - 1; i++) {\n\t\t\tx = aa[i] >= aa[i - 1], y = aa[i] > aa[i + 1], c = aa[i] + bb[m - 1];\n\t\t\tif (!z) {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]--;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]++;\n\t\t\t} else {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]++;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]--;\n\t\t\t}\n\t\t}\n\t\tfor (i = 1; i < n - 1; i++) {\n\t\t\tx = aa[i] >= aa[i - 1], y = aa[i] > aa[i + 1];\n\t\t\tif (!x && !y)\n\t\t\t\taaa[0][0][aa[i]]++;\n\t\t\telse if (x && y)\n\t\t\t\taaa[1][0][aa[i]]++;\n\t\t}\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tx = bb[j] >= bb[j - 1], y = bb[j] > bb[j + 1];\n\t\t\tif (!x && !y)\n\t\t\t\tbbb[0][0][bb[j]]++;\n\t\t\telse if (x && y)\n\t\t\t\tbbb[1][0][bb[j]]++;\n\t\t}\n\t\tfor (h = 0; h < 2; h++) {\n\t\t\tmemcpy(aaa[h][1], aaa[h][0], sizeof aaa[h][0]);\n\t\t\tfor (g = 0; g < 2; g++)\n\t\t\t\tntt(aaa[h][g], g, 0);\n\t\t}\n\t\tfor (h = 0; h < 2; h++) {\n\t\t\tmemcpy(bbb[h][1], bbb[h][0], sizeof bbb[h][0]);\n\t\t\tfor (g = 0; g < 2; g++)\n\t\t\t\tntt(bbb[h][g], g, 0);\n\t\t}\n\t\tfor (h1 = 0; h1 < 2; h1++)\n\t\t\tfor (h2 = 0; h2 < 2; h2++)\n\t\t\t\tfor (g = 0; g < 2; g++) {\n\t\t\t\t\tint md = MM[g], d = h1 == h2 ? md - 2 : 2;\n\n\t\t\t\t\tfor (i = 0; i < N_; i++)\n\t\t\t\t\t\tcc[g][i] = (cc[g][i] + (long long) aaa[h1][g][i] * bbb[h2][g][i] % md * d) % md;\n\t\t\t\t}\n\t\tfor (g = 0; g < 2; g++) {\n\t\t\tint md = MM[g], v = VV[g];\n\n\t\t\tntt(cc[g], g, 1);\n\t\t\tfor (i = 0; i < N_; i++)\n\t\t\t\tcc[g][i] = (long long) cc[g][i] * v % md;\n\t\t}\n\t\tfor (i = 0; i <= A; i++) {\n\t\t\tlong long x = garner(cc[0][i], cc[1][i]);\n\n\t\t\tif (x > (long long) M0 * M1 - x)\n\t\t\t\tx -= (long long) M0 * M1;\n\t\t\tans[i] += x;\n\t\t}\n\t}\n\tans[0]++;\n\tfor (i = 1; i <= A; i++)\n\t\tans[i] += ans[i - 1];\n\twhile (q--) {\n\t\tint x;\n\n\t\tscanf(\"%d\", &x);\n\t\tprintf(\"%lld\\n\", ans[x - 1]);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "009b6bde78a9de833912ad66755caff9", "src_uid": "25a6428f57022c12dfabdabbcc69c5a4", "difficulty": 3300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t100000\n#define M\t100000\n#define A\t200000\n#define L_\t18\t/* L_ = ceil(log2(A + 1)) */\n#define N_\t(1 << L_)\n#define MD\t469762049\t/* MD = 56 * 2^23 + 1 */\n\nlong long power(int a, int k) {\n\tlong long b = a, p = 1;\n\n\twhile (k) {\n\t\tif (k & 1)\n\t\t\tp = p * b % MD;\n\t\tb = b * b % MD;\n\t\tk >>= 1;\n\t}\n\treturn p;\n}\n\nint wu[L_ + 1], wv[L_ + 1], V;\n\nvoid init() {\n\tint l, u, v;\n\n\tu = power(3, MD - 1 >> L_), v = power(u, MD - 2);\n\tV = power(N_, MD - 2);\n\tfor (l = L_; l > 0; l--) {\n\t\twu[l] = u, wv[l] = v;\n\t\tu = (long long) u * u % MD, v = (long long) v * v % MD;\n\t}\n}\n\nvoid ntt(int *aa, int inverse) {\n\tint i, j, l, r;\n\n\tfor (i = 0, j = 1; j < N_; j++) {\n\t\tint n, tmp;\n\n\t\tn = N_ >> 1;\n\t\twhile ((i ^= n) < n)\n\t\t\tn >>= 1;\n\t\tif (i < j)\n\t\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\t}\n\tfor (l = 1; l <= L_; l++) {\n\t\tint n = 1 << l, m = n >> 1;\n\t\tlong long u = inverse ? wv[l] : wu[l], w = 1;\n\n\t\tfor (r = 0; r < m; r++) {\n\t\t\tfor (i = r; (j = i + m) < N_; i += n) {\n\t\t\t\tint a = aa[i], b = aa[j] * w % MD;\n\n\t\t\t\tif ((aa[i] = a + b) >= MD)\n\t\t\t\t\taa[i] -= MD;\n\t\t\t\tif ((aa[j] = a - b) < 0)\n\t\t\t\t\taa[j] += MD;\n\t\t\t}\n\t\t\tw = w * u % MD;\n\t\t}\n\t}\n}\n\nint dd[2][2] = \n{\n\t{ -2, 2 },\n\t{ 2, -2 },\n};\n\nint main() {\n\tstatic long long ans[A + 1];\n\tstatic int aa[N], bb[M], aaa[2][N_], bbb[2][N_], cc[N_];\n\tint n, m, q, g, h, i, j, x, y, z, c;\n\n\tinit();\n\tscanf(\"%d%d%d\", &n, &m, &q);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d\", &aa[i]);\n\tfor (j = 0; j < m; j++)\n\t\tscanf(\"%d\", &bb[j]);\n\tif (n == 1 && m == 1)\n\t\tans[aa[0] + bb[0]] = 1;\n\telse if (n == 1) {\n\t\tif (bb[0] > bb[1])\n\t\t\tans[aa[0] + bb[0]]--;\n\t\tif (bb[m - 1] >= bb[m - 2])\n\t\t\tans[aa[0] + bb[m - 1]]--;\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tx = bb[j] >= bb[j - 1], y = bb[j] > bb[j + 1], c = aa[0] + bb[j];\n\t\t\tif (!x && !y)\n\t\t\t\tans[c]--;\n\t\t\telse if (x && y)\n\t\t\t\tans[c]++;\n\t\t}\n\t} else if (m == 1) {\n\t\tif (aa[0] > aa[1])\n\t\t\tans[aa[0] + bb[0]]--;\n\t\tif (aa[n - 1] >= aa[n - 2])\n\t\t\tans[aa[n - 1] + bb[0]]--;\n\t\tfor (i = 1; i < n - 1; i++) {\n\t\t\tx = aa[i] >= aa[i - 1], y = aa[i] > aa[i + 1], c = aa[i] + bb[0];\n\t\t\tif (!x && !y)\n\t\t\t\tans[c]--;\n\t\t\telse if (x && y)\n\t\t\t\tans[c]++;\n\t\t}\n\t} else {\n\t\tz = aa[0] > aa[1];\n\t\ty = bb[0] > bb[1], c = aa[0] + bb[0];\n\t\tif (z == y)\n\t\t\tans[c]--;\n\t\tx = bb[m - 1] >= bb[m - 2], c = aa[0] + bb[m - 1];\n\t\tif (z == x)\n\t\t\tans[c]--;\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tx = bb[j] >= bb[j - 1], y = bb[j] > bb[j + 1], c = aa[0] + bb[j];\n\t\t\tif (!z) {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]--;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]++;\n\t\t\t} else {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]++;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]--;\n\t\t\t}\n\t\t}\n\t\tz = aa[n - 1] >= aa[n - 2];\n\t\ty = bb[0] > bb[1], c = aa[n - 1] + bb[0];\n\t\tif (z == y)\n\t\t\tans[c]--;\n\t\tx = bb[m - 1] >= bb[m - 2], c = aa[n - 1] + bb[m - 1];\n\t\tif (z == x)\n\t\t\tans[c]--;\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tx = bb[j] >= bb[j - 1], y = bb[j] > bb[j + 1], c = aa[n - 1] + bb[j];\n\t\t\tif (!z) {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]--;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]++;\n\t\t\t} else {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]++;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]--;\n\t\t\t}\n\t\t}\n\t\tz = bb[0] > bb[1];\n\t\tfor (i = 1; i < n - 1; i++) {\n\t\t\tx = aa[i] >= aa[i - 1], y = aa[i] > aa[i + 1], c = aa[i] + bb[0];\n\t\t\tif (!z) {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]--;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]++;\n\t\t\t} else {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]++;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]--;\n\t\t\t}\n\t\t}\n\t\tz = bb[m - 1] >= bb[m - 2];\n\t\tfor (i = 1; i < n - 1; i++) {\n\t\t\tx = aa[i] >= aa[i - 1], y = aa[i] > aa[i + 1], c = aa[i] + bb[m - 1];\n\t\t\tif (!z) {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]--;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]++;\n\t\t\t} else {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]++;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]--;\n\t\t\t}\n\t\t}\n\t\tfor (i = 1; i < n - 1; i++) {\n\t\t\tx = aa[i] >= aa[i - 1], y = aa[i] > aa[i + 1];\n\t\t\tif (!x && !y)\n\t\t\t\taaa[0][aa[i]]++;\n\t\t\telse if (x && y)\n\t\t\t\taaa[1][aa[i]]++;\n\t\t}\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tx = bb[j] >= bb[j - 1], y = bb[j] > bb[j + 1];\n\t\t\tif (!x && !y)\n\t\t\t\tbbb[0][bb[j]]++;\n\t\t\telse if (x && y)\n\t\t\t\tbbb[1][bb[j]]++;\n\t\t}\n\t\tfor (h = 0; h < 2; h++)\n\t\t\tntt(aaa[h], 0);\n\t\tfor (h = 0; h < 2; h++)\n\t\t\tntt(bbb[h], 0);\n\t\tfor (i = 0; i < N_; i++)\n\t\t\tfor (g = 0; g < 2; g++)\n\t\t\t\tfor (h = 0; h < 2; h++)\n\t\t\t\t\tcc[i] = (cc[i] + (long long) aaa[g][i] * bbb[h][i] % MD * dd[g][h]) % MD;\n\t\tfor (i = 0; i < N_; i++)\n\t\t\tif (cc[i] < 0)\n\t\t\t\tcc[i] += MD;\n\t\tntt(cc, 1);\n\t\tfor (i = 0; i <= A; i++) {\n\t\t\tc = (long long) cc[i] * V % MD;\n\t\t\tif (c > MD - c)\n\t\t\t\tc -= MD;\n\t\t\tans[i] += c;\n\t\t}\n\t}\n\tans[0]++;\n\tfor (i = 1; i <= A; i++)\n\t\tans[i] += ans[i - 1];\n\twhile (q--) {\n\t\tint x;\n\n\t\tscanf(\"%d\", &x);\n\t\tprintf(\"%lld\\n\", ans[x - 1]);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "638d7e3240f45750e24b269b01a10d46", "src_uid": "25a6428f57022c12dfabdabbcc69c5a4", "difficulty": 3300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t100000\n#define M\t100000\n#define A\t200000\n#define L_\t18\t/* L_ = ceil(log2(A + 1)) */\n#define N_\t(1 << L_)\n#define M0\t469762049\t/* M0 = 56 * 2^23 + 1 */\n#define M1\t595591169\t/* M1 = 71 * 2^23 + 1 */\n\nint MM[2] = { M0, M1 };\n\nlong long power(int a, int k, int md) {\n\tlong long b = a, p = 1;\n\n\twhile (k) {\n\t\tif (k & 1)\n\t\t\tp = p * b % md;\n\t\tb = b * b % md;\n\t\tk >>= 1;\n\t}\n\treturn p;\n}\n\nint wu[2][L_ + 1], wv[2][L_ + 1], VV[2], V01;\n\nvoid init() {\n\tint g, l, u, v;\n\n\tV01 = power(M0, M1 - 2, M1);\n\tfor (g = 0; g < 2; g++) {\n\t\tint md = MM[g];\n\n\t\tu = power(3, md - 1 >> L_, md), v = power(u, md - 2, md);\n\t\tVV[g] = power(N_, md - 2, md);\n\t\tfor (l = L_; l > 0; l--) {\n\t\t\twu[g][l] = u, wv[g][l] = v;\n\t\t\tu = (long long) u * u % md, v = (long long) v * v % md;\n\t\t}\n\t}\n}\n\nvoid ntt(int *aa, int g, int inverse) {\n\tint md = MM[g], i, j, l, r;\n\n\tfor (i = 0, j = 1; j < N_; j++) {\n\t\tint n, tmp;\n\n\t\tn = N_ >> 1;\n\t\twhile ((i ^= n) < n)\n\t\t\tn >>= 1;\n\t\tif (i < j)\n\t\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\t}\n\tfor (l = 1; l <= L_; l++) {\n\t\tint n = 1 << l, m = n >> 1;\n\t\tlong long u = inverse ? wv[g][l] : wu[g][l], w = 1;\n\n\t\tfor (r = 0; r < m; r++) {\n\t\t\tfor (i = r; (j = i + m) < N_; i += n) {\n\t\t\t\tint a = aa[i], b = aa[j] * w % md;\n\n\t\t\t\tif ((aa[i] = a + b) >= md)\n\t\t\t\t\taa[i] -= md;\n\t\t\t\tif ((aa[j] = a - b) < 0)\n\t\t\t\t\taa[j] += md;\n\t\t\t}\n\t\t\tw = w * u % md;\n\t\t}\n\t}\n}\n\nlong long garner(int r0, int r1) {\n\tr1 = (long long) (r1 - r0) * V01 % M1;\n\tif (r1 < 0)\n\t\tr1 += M1;\n\treturn (long long) r1 * M0 + r0;\n}\n\nint main() {\n\tstatic long long ans[A + 1];\n\tstatic int aa[N], bb[M], aaa[2][2][N_], bbb[2][2][N_], cc[2][N_];\n\tint n, m, q, g, h, h1, h2, i, j, x, y, z, c;\n\n\tinit();\n\tscanf(\"%d%d%d\", &n, &m, &q);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d\", &aa[i]);\n\tfor (j = 0; j < m; j++)\n\t\tscanf(\"%d\", &bb[j]);\n\tif (n == 1 && m == 1)\n\t\tans[aa[0] + bb[0]] = 1;\n\telse if (n == 1)\n\t\tans[aa[0] + bb[0]]--, ans[aa[0] + bb[m - 1]]--;\n\telse if (m == 1)\n\t\tans[aa[0] + bb[0]]--, ans[aa[n - 1] + bb[0]]--;\n\telse {\n\t\tz = aa[0] > aa[1];\n\t\ty = bb[0] > bb[1], c = aa[0] + bb[0];\n\t\tif (z == y)\n\t\t\tans[c]--;\n\t\tx = bb[m - 1] >= bb[m - 2], c = aa[0] + bb[m - 1];\n\t\tif (z == x)\n\t\t\tans[c]--;\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tx = bb[j] >= bb[j - 1], y = bb[j] > bb[j + 1], c = aa[0] + bb[j];\n\t\t\tif (!z) {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]--;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]++;\n\t\t\t} else {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]++;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]--;\n\t\t\t}\n\t\t}\n\t\tz = aa[n - 1] >= aa[n - 2];\n\t\ty = bb[0] > bb[1], c = aa[n - 1] + bb[0];\n\t\tif (z == y)\n\t\t\tans[c]--;\n\t\tx = bb[m - 1] >= bb[m - 2], c = aa[n - 1] + bb[m - 1];\n\t\tif (z == x)\n\t\t\tans[c]--;\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tx = bb[j] >= bb[j - 1], y = bb[j] > bb[j + 1], c = aa[n - 1] + bb[j];\n\t\t\tif (!z) {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]--;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]++;\n\t\t\t} else {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]++;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]--;\n\t\t\t}\n\t\t}\n\t\tz = bb[0] > bb[1];\n\t\tfor (i = 1; i < n - 1; i++) {\n\t\t\tx = aa[i] >= aa[i - 1], y = aa[i] > aa[i + 1], c = aa[i] + bb[0];\n\t\t\tif (!z) {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]--;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]++;\n\t\t\t} else {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]++;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]--;\n\t\t\t}\n\t\t}\n\t\tz = bb[m - 1] >= bb[m - 2];\n\t\tfor (i = 1; i < n - 1; i++) {\n\t\t\tx = aa[i] >= aa[i - 1], y = aa[i] > aa[i + 1], c = aa[i] + bb[m - 1];\n\t\t\tif (!z) {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]--;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]++;\n\t\t\t} else {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]++;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]--;\n\t\t\t}\n\t\t}\n\t\tfor (i = 1; i < n - 1; i++) {\n\t\t\tx = aa[i] >= aa[i - 1], y = aa[i] > aa[i + 1];\n\t\t\tif (!x && !y)\n\t\t\t\taaa[0][0][aa[i]]++;\n\t\t\telse if (x && y)\n\t\t\t\taaa[1][0][aa[i]]++;\n\t\t}\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tx = bb[j] >= bb[j - 1], y = bb[j] > bb[j + 1];\n\t\t\tif (!x && !y)\n\t\t\t\tbbb[0][0][bb[j]]++;\n\t\t\telse if (x && y)\n\t\t\t\tbbb[1][0][bb[j]]++;\n\t\t}\n\t\tfor (h = 0; h < 2; h++) {\n\t\t\tmemcpy(aaa[h][1], aaa[h][0], sizeof aaa[h][0]);\n\t\t\tfor (g = 0; g < 2; g++)\n\t\t\t\tntt(aaa[h][g], g, 0);\n\t\t}\n\t\tfor (h = 0; h < 2; h++) {\n\t\t\tmemcpy(bbb[h][1], bbb[h][0], sizeof bbb[h][0]);\n\t\t\tfor (g = 0; g < 2; g++)\n\t\t\t\tntt(bbb[h][g], g, 0);\n\t\t}\n\t\tfor (h1 = 0; h1 < 2; h1++)\n\t\t\tfor (h2 = 0; h2 < 2; h2++)\n\t\t\t\tfor (g = 0; g < 2; g++) {\n\t\t\t\t\tint md = MM[g], d = h1 == h2 ? md - 2 : 2;\n\n\t\t\t\t\tfor (i = 0; i < N_; i++)\n\t\t\t\t\t\tcc[g][i] = (cc[g][i] + (long long) aaa[h1][g][i] * bbb[h2][g][i] % md * d) % md;\n\t\t\t\t}\n\t\tfor (g = 0; g < 2; g++) {\n\t\t\tint md = MM[g], v = VV[g];\n\n\t\t\tntt(cc[g], g, 1);\n\t\t\tfor (i = 0; i < N_; i++)\n\t\t\t\tcc[g][i] = (long long) cc[g][i] * v % md;\n\t\t}\n\t\tfor (i = 0; i <= A; i++) {\n\t\t\tlong long x = garner(cc[0][i], cc[1][i]);\n\n\t\t\tif (x > (long long) M0 * M1 - x)\n\t\t\t\tx -= (long long) M0 * M1;\n\t\t\tans[i] += x;\n\t\t}\n\t}\n\tans[0]++;\n\tfor (i = 1; i <= A; i++)\n\t\tans[i] += ans[i - 1];\n\twhile (q--) {\n\t\tint x;\n\n\t\tscanf(\"%d\", &x);\n\t\tprintf(\"%lld\\n\", ans[x - 1]);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c90edea0e6ddf017dabed134bb709e25", "src_uid": "25a6428f57022c12dfabdabbcc69c5a4", "difficulty": 3300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t100000\n#define M\t100000\n#define A\t200000\n#define L_\t18\t/* L_ = ceil(log2(A + 1)) */\n#define N_\t(1 << L_)\n#define M0\t469762049\t/* M0 = 56 * 2^23 + 1 */\n#define M1\t595591169\t/* M1 = 71 * 2^23 + 1 */\n\nint MM[2] = { M0, M1 };\n\nlong long power(int a, int k, int md) {\n\tlong long b = a, p = 1;\n\n\twhile (k) {\n\t\tif (k & 1)\n\t\t\tp = p * b % md;\n\t\tb = b * b % md;\n\t\tk >>= 1;\n\t}\n\treturn p;\n}\n\nint wu[2][L_ + 1][N_], wv[2][L_ + 1][N_], VV[2], V01;\n\nvoid init() {\n\tint g, l, u, v;\n\n\tV01 = power(M0, M1 - 2, M1);\n\tfor (g = 0; g < 2; g++) {\n\t\tint md = MM[g], i;\n\n\t\tu = power(3, md - 1 >> L_, md), v = power(u, md - 2, md);\n\t\tVV[g] = power(N_, md - 2, md);\n\t\tfor (l = L_; l > 0; l--) {\n\t\t\twu[g][l][0] = wv[g][l][0] = 1;\n\t\t\tfor (i = 1; i < 1 << l; i++)\n\t\t\t\twu[g][l][i] = (long long) wu[g][l][i - 1] * u % md, wv[g][l][i] = (long long) wv[g][l][i - 1] * v % md;\n\t\t\tu = (long long) u * u % md, v = (long long) v * v % md;\n\t\t}\n\t}\n}\n\nvoid ntt(int *aa, int g, int inverse) {\n\tint md = MM[g], h, i, j, l, r;\n\n\tfor (i = 0, j = 1; j < N_; j++) {\n\t\tint n, tmp;\n\n\t\tn = N_ >> 1;\n\t\twhile ((i ^= n) < n)\n\t\t\tn >>= 1;\n\t\tif (i < j)\n\t\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\t}\n\tfor (l = 1; l <= L_; l++) {\n\t\tint n = 1 << l, m = n >> 1;\n\n\t\tfor (h = 0; h < N_; h += n)\n\t\t\tfor (r = 0; r < m; r++) {\n\t\t\t\tint a, b;\n\n\t\t\t\ti = h + r, j = i + m;\n\t\t\t\ta = aa[i], b = (long long) aa[j] * (inverse ? wv[g][l][r] : wu[g][l][r]) % md;\n\t\t\t\tif ((aa[i] = a + b) >= md)\n\t\t\t\t\taa[i] -= md;\n\t\t\t\tif ((aa[j] = a - b) < 0)\n\t\t\t\t\taa[j] += md;\n\t\t\t}\n\t}\n}\n\nlong long garner(int r0, int r1) {\n\tr1 = (long long) (r1 - r0) * V01 % M1;\n\tif (r1 < 0)\n\t\tr1 += M1;\n\treturn (long long) r1 * M0 + r0;\n}\n\nint main() {\n\tstatic long long ans[A + 1];\n\tstatic int aa[N], bb[M], aaa[2][2][N_], bbb[2][2][N_], cc[2][N_];\n\tint n, m, q, g, h, h1, h2, i, j, x, y, z, c;\n\n\tinit();\n\tscanf(\"%d%d%d\", &n, &m, &q);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d\", &aa[i]);\n\tfor (j = 0; j < m; j++)\n\t\tscanf(\"%d\", &bb[j]);\n\tif (n == 1 && m == 1)\n\t\tans[aa[0] + bb[0]] = 1;\n\telse if (n == 1)\n\t\tans[aa[0] + bb[0]]--, ans[aa[0] + bb[m - 1]]--;\n\telse if (m == 1)\n\t\tans[aa[0] + bb[0]]--, ans[aa[n - 1] + bb[0]]--;\n\telse {\n\t\tz = aa[0] > aa[1];\n\t\ty = bb[0] > bb[1], c = aa[0] + bb[0];\n\t\tif (z == y)\n\t\t\tans[c]--;\n\t\tx = bb[m - 1] >= bb[m - 2], c = aa[0] + bb[m - 1];\n\t\tif (z == x)\n\t\t\tans[c]--;\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tx = bb[j] >= bb[j - 1], y = bb[j] > bb[j + 1], c = aa[0] + bb[j];\n\t\t\tif (!z) {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]--;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]++;\n\t\t\t} else {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]++;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]--;\n\t\t\t}\n\t\t}\n\t\tz = aa[n - 1] >= aa[n - 2];\n\t\ty = bb[0] > bb[1], c = aa[n - 1] + bb[0];\n\t\tif (z == y)\n\t\t\tans[c]--;\n\t\tx = bb[m - 1] >= bb[m - 2], c = aa[n - 1] + bb[m - 1];\n\t\tif (z == x)\n\t\t\tans[c]--;\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tx = bb[j] >= bb[j - 1], y = bb[j] > bb[j + 1], c = aa[n - 1] + bb[j];\n\t\t\tif (!z) {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]--;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]++;\n\t\t\t} else {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]++;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]--;\n\t\t\t}\n\t\t}\n\t\tz = bb[0] > bb[1];\n\t\tfor (i = 1; i < n - 1; i++) {\n\t\t\tx = aa[i] >= aa[i - 1], y = aa[i] > aa[i + 1], c = aa[i] + bb[0];\n\t\t\tif (!z) {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]--;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]++;\n\t\t\t} else {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]++;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]--;\n\t\t\t}\n\t\t}\n\t\tz = bb[m - 1] >= bb[m - 2];\n\t\tfor (i = 1; i < n - 1; i++) {\n\t\t\tx = aa[i] >= aa[i - 1], y = aa[i] > aa[i + 1], c = aa[i] + bb[m - 1];\n\t\t\tif (!z) {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]--;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]++;\n\t\t\t} else {\n\t\t\t\tif (!x && !y)\n\t\t\t\t\tans[c]++;\n\t\t\t\telse if (x && y)\n\t\t\t\t\tans[c]--;\n\t\t\t}\n\t\t}\n\t\tfor (i = 1; i < n - 1; i++) {\n\t\t\tx = aa[i] >= aa[i - 1], y = aa[i] > aa[i + 1];\n\t\t\tif (!x && !y)\n\t\t\t\taaa[0][0][aa[i]]++;\n\t\t\telse if (x && y)\n\t\t\t\taaa[1][0][aa[i]]++;\n\t\t}\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tx = bb[j] >= bb[j - 1], y = bb[j] > bb[j + 1];\n\t\t\tif (!x && !y)\n\t\t\t\tbbb[0][0][bb[j]]++;\n\t\t\telse if (x && y)\n\t\t\t\tbbb[1][0][bb[j]]++;\n\t\t}\n\t\tfor (h = 0; h < 2; h++) {\n\t\t\tmemcpy(aaa[h][1], aaa[h][0], sizeof aaa[h][0]);\n\t\t\tfor (g = 0; g < 2; g++)\n\t\t\t\tntt(aaa[h][g], g, 0);\n\t\t}\n\t\tfor (h = 0; h < 2; h++) {\n\t\t\tmemcpy(bbb[h][1], bbb[h][0], sizeof bbb[h][0]);\n\t\t\tfor (g = 0; g < 2; g++)\n\t\t\t\tntt(bbb[h][g], g, 0);\n\t\t}\n\t\tfor (h1 = 0; h1 < 2; h1++)\n\t\t\tfor (h2 = 0; h2 < 2; h2++)\n\t\t\t\tfor (g = 0; g < 2; g++) {\n\t\t\t\t\tint md = MM[g], d = h1 == h2 ? md - 2 : 2;\n\n\t\t\t\t\tfor (i = 0; i < N_; i++)\n\t\t\t\t\t\tcc[g][i] = (cc[g][i] + (long long) aaa[h1][g][i] * bbb[h2][g][i] % md * d) % md;\n\t\t\t\t}\n\t\tfor (g = 0; g < 2; g++) {\n\t\t\tint md = MM[g], v = VV[g];\n\n\t\t\tntt(cc[g], g, 1);\n\t\t\tfor (i = 0; i < N_; i++)\n\t\t\t\tcc[g][i] = (long long) cc[g][i] * v % md;\n\t\t}\n\t\tfor (i = 0; i <= A; i++) {\n\t\t\tlong long x = garner(cc[0][i], cc[1][i]);\n\n\t\t\tif (x > (long long) M0 * M1 - x)\n\t\t\t\tx -= (long long) M0 * M1;\n\t\t\tans[i] += x;\n\t\t}\n\t}\n\tans[0]++;\n\tfor (i = 1; i <= A; i++)\n\t\tans[i] += ans[i - 1];\n\twhile (q--) {\n\t\tint x;\n\n\t\tscanf(\"%d\", &x);\n\t\tprintf(\"%lld\\n\", ans[x - 1]);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f36c9f866598c2208964b738b5876637", "src_uid": "25a6428f57022c12dfabdabbcc69c5a4", "difficulty": 3300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t100000\n#define M\t100000\n#define A\t200000\n#define L_\t18\t/* L_ = ceil(log2(A + 1)) */\n#define N_\t(1 << L_)\n#define M0\t469762049\t/* M0 = 56 * 2^23 + 1 */\n#define M1\t595591169\t/* M1 = 71 * 2^23 + 1 */\n\nint MM[2] = { M0, M1 };\n\nlong long power(int a, int k, int md) {\n\tlong long b = a, p = 1;\n\n\twhile (k) {\n\t\tif (k & 1)\n\t\t\tp = p * b % md;\n\t\tb = b * b % md;\n\t\tk >>= 1;\n\t}\n\treturn p;\n}\n\nint wu[2][L_ + 1][N_], wv[2][L_ + 1][N_], VV[2], V01;\n\nvoid init() {\n\tint g, l, u, v;\n\n\tV01 = power(M0, M1 - 2, M1);\n\tfor (g = 0; g < 2; g++) {\n\t\tint md = MM[g], i;\n\n\t\tu = power(3, md - 1 >> L_, md), v = power(u, md - 2, md);\n\t\tVV[g] = power(N_, md - 2, md);\n\t\tfor (l = L_; l > 0; l--) {\n\t\t\twu[g][l][0] = wv[g][l][0] = 1;\n\t\t\tfor (i = 1; i < 1 << l; i++)\n\t\t\t\twu[g][l][i] = (long long) wu[g][l][i - 1] * u % md, wv[g][l][i] = (long long) wv[g][l][i - 1] * v % md;\n\t\t\tu = (long long) u * u % md, v = (long long) v * v % md;\n\t\t}\n\t}\n}\n\nvoid ntt(int *aa, int g, int inverse) {\n\tint md = MM[g], h, i, j, l, r;\n\n\tfor (i = 0, j = 1; j < N_; j++) {\n\t\tint n, tmp;\n\n\t\tn = N_ >> 1;\n\t\twhile ((i ^= n) < n)\n\t\t\tn >>= 1;\n\t\tif (i < j)\n\t\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\t}\n\tfor (l = 1; l <= L_; l++) {\n\t\tint n = 1 << l, m = n >> 1;\n\n\t\tfor (h = 0; h < N_; h += n)\n\t\t\tfor (r = 0; r < m; r++) {\n\t\t\t\tint a, b;\n\n\t\t\t\ti = h + r, j = i + m;\n\t\t\t\ta = aa[i], b = (long long) aa[j] * (inverse ? wv[g][l][r] : wu[g][l][r]) % md;\n\t\t\t\tif ((aa[i] = a + b) >= md)\n\t\t\t\t\taa[i] -= md;\n\t\t\t\tif ((aa[j] = a - b) < 0)\n\t\t\t\t\taa[j] += md;\n\t\t\t}\n\t}\n}\n\nlong long garner(int r0, int r1) {\n\tr1 = (long long) (r1 - r0) * V01 % M1;\n\tif (r1 < 0)\n\t\tr1 += M1;\n\treturn (long long) r1 * M0 + r0;\n}\n\nint main() {\n\tstatic long long ans[A + 1];\n\tstatic int aa[N], bb[M], aaa[2][N_], bbb[2][N_], cc[2][N_];\n\tint n, m, q, g, i, j, x, y, z;\n\n\tinit();\n\tscanf(\"%d%d%d\", &n, &m, &q);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d\", &aa[i]);\n\tfor (j = 0; j < m; j++)\n\t\tscanf(\"%d\", &bb[j]);\n\tif (n == 1 && m == 1)\n\t\tans[aa[0] + bb[0]] = 1;\n\telse if (n == 1)\n\t\tans[aa[0] + bb[0]]--, ans[aa[0] + bb[m - 1]]--;\n\telse if (m == 1)\n\t\tans[aa[0] + bb[0]]--, ans[aa[n - 1] + bb[0]]--;\n\telse {\n\t\tx = bb[m - 1] >= bb[m - 2], y = bb[0] > bb[1];\n\t\tz = aa[0] > aa[1];\n\t\tif (z == y)\n\t\t\tans[aa[0] + bb[0]]--;\n\t\tif (z == x)\n\t\t\tans[aa[0] + bb[m - 1]]--;\n\t\tz = aa[n - 1] >= aa[n - 2];\n\t\tif (z == y)\n\t\t\tans[aa[n - 1] + bb[0]]--;\n\t\tif (z == x)\n\t\t\tans[aa[n - 1] + bb[m - 1]]--;\n\t\tz = aa[0] > aa[1];\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tx = bb[j] >= bb[j - 1], y = bb[j] > bb[j + 1];\n\t\t\tans[aa[0] + bb[j]] += (z ? -1 : 1) * (x != y ? 0 : (x ? 1 : -1));\n\t\t}\n\t\tz = aa[n - 1] >= aa[n - 2];\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tx = bb[j] >= bb[j - 1], y = bb[j] > bb[j + 1];\n\t\t\tans[aa[n - 1] + bb[j]] += (z ? -1 : 1) * (x != y ? 0 : (x ? 1 : -1));\n\t\t}\n\t\tz = bb[0] > bb[1];\n\t\tfor (i = 1; i < n - 1; i++) {\n\t\t\tx = aa[i] >= aa[i - 1], y = aa[i] > aa[i + 1];\n\t\t\tans[aa[i] + bb[0]] += (z ? -1 : 1) * (x != y ? 0 : (x ? 1 : -1));\n\t\t}\n\t\tz = bb[m - 1] >= bb[m - 2];\n\t\tfor (i = 1; i < n - 1; i++) {\n\t\t\tx = aa[i] >= aa[i - 1], y = aa[i] > aa[i + 1];\n\t\t\tans[aa[i] + bb[m - 1]] += (z ? -1 : 1) * (x != y ? 0 : (x ? 1 : -1));\n\t\t}\n\t\tfor (i = 1; i < n - 1; i++) {\n\t\t\tx = aa[i] >= aa[i - 1], y = aa[i] > aa[i + 1];\n\t\t\taaa[0][aa[i]] += x != y ? 0 : (x ? -1 : 1);\n\t\t}\n\t\tfor (j = 1; j < m - 1; j++) {\n\t\t\tx = bb[j] >= bb[j - 1], y = bb[j] > bb[j + 1];\n\t\t\tbbb[0][bb[j]] += x != y ? 0 : (x ? -1 : 1);\n\t\t}\n\t\tmemcpy(aaa[1], aaa[0], sizeof aaa[0]);\n\t\tmemcpy(bbb[1], bbb[0], sizeof bbb[0]);\n\t\tfor (g = 0; g < 2; g++) {\n\t\t\tfor (i = 0; i < N_; i++) {\n\t\t\t\tif (aaa[g][i] < 0)\n\t\t\t\t\taaa[g][i] += MM[g];\n\t\t\t\tif (bbb[g][i] < 0)\n\t\t\t\t\tbbb[g][i] += MM[g];\n\t\t\t}\n\t\t\tntt(aaa[g], g, 0);\n\t\t\tntt(bbb[g], g, 0);\n\t\t}\n\t\tfor (g = 0; g < 2; g++) {\n\t\t\tint md = MM[g];\n\n\t\t\tfor (i = 0; i < N_; i++)\n\t\t\t\tcc[g][i] = (long long) aaa[g][i] * bbb[g][i] % md * 2 % md;\n\t\t}\n\t\tfor (g = 0; g < 2; g++) {\n\t\t\tint md = MM[g], v = VV[g];\n\n\t\t\tntt(cc[g], g, 1);\n\t\t\tfor (i = 0; i < N_; i++)\n\t\t\t\tcc[g][i] = (long long) cc[g][i] * v % md;\n\t\t}\n\t\tfor (i = 0; i <= A; i++) {\n\t\t\tlong long x = garner(cc[0][i], cc[1][i]);\n\n\t\t\tif (x > (long long) M0 * M1 - x)\n\t\t\t\tx -= (long long) M0 * M1;\n\t\t\tans[i] -= x;\n\t\t}\n\t}\n\tans[0]++;\n\tfor (i = 1; i <= A; i++)\n\t\tans[i] += ans[i - 1];\n\twhile (q--) {\n\t\tint x;\n\n\t\tscanf(\"%d\", &x);\n\t\tprintf(\"%lld\\n\", ans[x - 1]);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4929692a1851ad387a382b22e7c6c1ae", "src_uid": "25a6428f57022c12dfabdabbcc69c5a4", "difficulty": 3300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint func (long long x, int n, int ans, int num, long long *pow10, long long *pow9) {\n  int cnt = 0;\n  int digit[10] = {};\n  \n  long long tmp = x;\n  \n  if (num >= ans) {\n    return ans;\n  }\n  \n  while (tmp > 0LL) {\n    digit[(int)(tmp%10LL)] = 1;\n    tmp /= 10LL;\n    cnt++;\n  }\n  \n  if (cnt > n) {\n    return 100;\n  }\n  \n  if (cnt == n) {\n    return num;\n  }\n  \n  for (int i = 9; i > 1; i--) {\n    if (digit[i] > 0) {\n      long long nx = x*((long long)i);\n      if (ans-num-2 >= n || (pow10[n-1]-1LL)/pow9[ans-num-2] < nx) {\n        int tmp = func(nx, n, ans, num+1, pow10, pow9);\n        if (tmp < ans) {\n          ans = tmp;\n        }\n      }\n    }\n  }\n  \n  return ans;\n}\n\nint main () {\n  int n = 0;\n  long long x = 0LL;\n  \n  int res = 0;\n  \n  long long pow10[19] = {};\n  long long pow9[19] = {}; \n  \n  int ans = 0;\n  \n  res = scanf(\"%d\", &n);\n  res = scanf(\"%lld\", &x);\n  \n  pow10[0] = 1LL;\n  for (int i = 1; i < n; i++) {\n    pow10[i] = 10LL*pow10[i-1];\n  }\n  \n  pow9[0] = 1LL;\n  for (int i = 1; i < n; i++) {\n    pow9[i] = 9LL*pow9[i-1];\n  }\n  \n  ans = func(x, n, 100, 0, pow10, pow9);\n  if (ans >= 100) {\n    ans = -1;\n  }\n  \n  printf(\"%d\\n\", ans);\n  \n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "896ed2e183e1fd9f47178e03d9be2477", "src_uid": "cedcc3cee864bf8684148df93804d029", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint func (long long x, int n, int ans, int num, long long *pow10, long long *pow9) {\n  int cnt = 0;\n  int digit[10] = {};\n  \n  long long tmp = x;\n  \n  if (num >= ans) {\n    return ans;\n  }\n  \n  while (tmp > 0LL) {\n    digit[(int)(tmp%10LL)] = 1;\n    tmp /= 10LL;\n    cnt++;\n  }\n  \n  if (cnt > n) {\n    return 100;\n  }\n  \n  if (cnt == n) {\n    return num;\n  }\n  \n  for (int i = 9; i > 1; i--) {\n    if (digit[i] > 0) {\n      long long nx = x*((long long)i);\n      if (ans-num-2 > n || (pow10[n-1]-1LL)/pow9[ans-num-2] < nx) {\n        int tmp = func(nx, n, ans, num+1, pow10, pow9);\n        if (tmp < ans) {\n          ans = tmp;\n        }\n      }\n    }\n  }\n  \n  return ans;\n}\n\nint main () {\n  int n = 0;\n  long long x = 0LL;\n  \n  int res = 0;\n  \n  long long pow10[19] = {};\n  long long pow9[19] = {}; \n  \n  int ans = 0;\n  \n  res = scanf(\"%d\", &n);\n  res = scanf(\"%lld\", &x);\n  \n  pow10[0] = 1LL;\n  for (int i = 1; i < n; i++) {\n    pow10[i] = 10LL*pow10[i-1];\n  }\n  \n  pow9[0] = 1LL;\n  for (int i = 1; i < n; i++) {\n    pow9[i] = 9LL*pow9[i-1];\n  }\n  \n  ans = func(x, n, 100, 0, pow10, pow9);\n  if (ans >= 100) {\n    ans = -1;\n  }\n  \n  printf(\"%d\\n\", ans);\n  \n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a58c9c4a5cd78f937e47d9a8254ae1e3", "src_uid": "cedcc3cee864bf8684148df93804d029", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\ntypedef unsigned long long ll;\r\n#define rll register ll\r\n#define rint register int\r\n#define rep(i,a,b) for(rint i=(a);i<(b);i++)\r\n#define repe(i,a,b) for(rint i=(a);i<=(b);i++)\r\n#define repr(i,a,b) for(rint i=(a)-1;(b)<=i;i--)\r\n\r\nint writeBuffer[20];\r\nvoid write(ll num) { if (num == 0) putchar('0'); else { rint size = 0; rll current; if (0 < num) current = num; else current = -num, putchar('-'); while (0 < current) writeBuffer[size++] = current%10+'0', current /= 10; while (0 < size) putchar(writeBuffer[--size]); } }\r\nll read() { rint sign = 1; rll num = 0; while (1) { rint ch = getchar(); if (ch == '-') { sign = -sign; continue; } if (ch <= 32) break; num = num*10+(ch-'0'); } return sign*num; }\r\n\r\nll dp[100][1<<10];\r\n\r\nint main() {\r\n    rint n = read();\r\n    rll x = read();\r\n\r\n    {\r\n        rint mask = 0;\r\n        for (rll temp=x;temp;temp/=10) mask |= 1<<(temp%10);\r\n        dp[0][mask] = x;\r\n    }\r\n\r\n    rint depth = 0;\r\n    while (1) {\r\n        rint found = 0;\r\n        rep(j,0,1024) {\r\n            rll num = dp[depth][j];\r\n            if (num) {\r\n                rep(k,2,10) if (j&(1<<k)) {\r\n                    rll newNum = num*k;\r\n                    found = 1;\r\n                    rint mask = 0;\r\n                    rint digit = 0;\r\n                    for (rll temp=newNum;temp;temp/=10,digit++) mask |= 1<<(temp%10);\r\n                    if (n == digit) {\r\n                        write(depth+1), putchar('\\n');\r\n                        return 0;\r\n                    }\r\n                    if (dp[depth+1][mask] < newNum) dp[depth+1][mask] = newNum;\r\n                }\r\n            }\r\n        }\r\n        if (!found) {\r\n            putchar('-'), putchar('1'), putchar('\\n');\r\n            return 0;\r\n        }\r\n        depth++;\r\n    }\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6937ec824d738d477adba912cf22fdb3", "src_uid": "cedcc3cee864bf8684148df93804d029", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint func (long long x, int n, int num, long long *pow10, int *lim) {\n  int cnt = 0;\n  int digit[10] = {};\n  \n  long long tmp = x;\n  \n  int ans = -1;\n  \n  while (tmp > 0LL) {\n    digit[(int)(tmp%10LL)] = 1;\n    tmp /= 10LL;\n    cnt++;\n  }\n  \n  if (cnt > n) {\n    return -1;\n  }\n  \n  if (cnt == n) {\n    return num;\n  }\n  \n  for (int i = 9; i > 1; i--) {\n    if (digit[i] > 0) {\n      long long nx = x*((long long)i);\n      if (nx >= pow10[cnt] && lim[cnt] > num) {\n        int tmp = 0;\n        lim[cnt] = num+1;\n        tmp = func(nx, n, num+1, pow10, lim);\n        if (ans < 0 || (tmp >= 0 && tmp < ans)) {\n          ans = tmp;\n        }\n      } else if (lim[cnt] > num+1) {\n        int tmp = 0;\n        tmp = func(nx, n, num+1, pow10, lim);\n        if (ans < 0 || (tmp >= 0 && tmp < ans)) {\n          ans = tmp;\n        }\n      }\n    }\n  }\n  \n  return ans;\n}\n\nint main () {\n  int n = 0;\n  long long x = 0LL;\n  \n  int res = 0;\n  \n  long long pow10[19] = {};\n  int ans[20] = {};  \n  \n  res = scanf(\"%d\", &n);\n  res = scanf(\"%lld\", &x);\n  \n  pow10[0] = 1LL;\n  for (int i = 1; i <= n; i++) {\n    pow10[i] = 10LL*pow10[i-1];\n  }\n  \n  for (int i = 0; i < n; i++) {\n    ans[i] = 100;\n  }\n  \n  printf(\"%d\\n\", func(x, n, 0, pow10, ans));\n  \n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "39663c51f3adf0cc4e356641e52deca8", "src_uid": "cedcc3cee864bf8684148df93804d029", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\ntypedef unsigned long long ll;\r\n#define rll register ll\r\n#define rint register int\r\n#define rep(i,a,b) for(rint i=(a);i<(b);i++)\r\n#define repe(i,a,b) for(rint i=(a);i<=(b);i++)\r\n#define repr(i,a,b) for(rint i=(a)-1;(b)<=i;i--)\r\n\r\nint writeBuffer[20];\r\nvoid write(ll num) { if (num == 0) putchar('0'); else { rint size = 0; rll current; if (0 < num) current = num; else current = -num, putchar('-'); while (0 < current) writeBuffer[size++] = current%10+'0', current /= 10; while (0 < size) putchar(writeBuffer[--size]); } }\r\nll read() { rint sign = 1; rll num = 0; while (1) { rint ch = getchar(); if (ch == '-') { sign = -sign; continue; } if (ch <= 32) break; num = num*10+(ch-'0'); } return sign*num; }\r\n\r\nll dp[100][1<<10];\r\n\r\nint main() {\r\n    rint n = read();\r\n    rll target = 1;\r\n    rep(i,0,n) target *= 10;\r\n\r\n    rll x = read();\r\n\r\n    {\r\n        rint mask = 0;\r\n        for (rll temp=x;temp;temp/=10) mask |= 1<<(temp%10);\r\n        dp[0][mask] = x;\r\n    }\r\n\r\n    rint depth = 0;\r\n    while (1) {\r\n        rint found = 0;\r\n        rep(j,0,1024) {\r\n            rll num = dp[depth][j];\r\n            if (num) {\r\n                rep(k,2,10) if (j&(1<<k)) {\r\n                    rll newNum = num*k;\r\n                    if (target <= newNum) {\r\n                        write(depth), putchar('\\n');\r\n                        return 0;\r\n                    }\r\n                    found = 1;\r\n                    rint mask = 0;\r\n                    for (rll temp=newNum;temp;temp/=10) mask |= 1<<(temp%10);\r\n                    if (dp[depth+1][mask] < newNum) dp[depth+1][mask] = newNum;\r\n                }\r\n            }\r\n        }\r\n        if (!found) {\r\n            putchar('-'), putchar('1'), putchar('\\n');\r\n            return 0;\r\n        }\r\n        depth++;\r\n    }\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1e3fb012823f7fdd49c19df30d8d882d", "src_uid": "cedcc3cee864bf8684148df93804d029", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\n#define rint register int\r\n#define rep(i,a,b) for(rint i=(a);i<(b);i++)\r\n#define repe(i,a,b) for(rint i=(a);i<=(b);i++)\r\n#define repr(i,a,b) for(rint i=(a)-1;(b)<=i;i--)\r\n\r\nvoid writePositive(int num) {\r\n    if (num > 0) {\r\n        writePositive(num / 10);\r\n        putchar(num % 10 + '0');\r\n    }\r\n}\r\n\r\nvoid write(int num) {\r\n    if (num == 0) putchar('0');\r\n    else if (num < 0) {\r\n        putchar('-');\r\n        writePositive(-num);\r\n    } else writePositive(num);\r\n}\r\n\r\nint read() {\r\n    rint sign = 1;\r\n    rint num = 0;\r\n    rint ch;\r\n    while(1) {\r\n        ch = getchar();\r\n        if (ch == '-') {\r\n            sign = -sign;\r\n            continue;\r\n        }\r\n        ch = ch-'0';\r\n        if (ch < 0 || 10 < ch) break;\r\n        num = num*10+ch;\r\n    }\r\n    return sign*num;\r\n}\r\n\r\n#define MOD 998244353\r\n\r\nint dp[50001][1024];\r\nint pairs[10][10], masks[10][1024];\r\n\r\nint main() {\r\n    rint n = read();\r\n    rint m = read();\r\n    rep(i,0,m) {\r\n        rint u = read();\r\n        rint v = read();\r\n        pairs[u][v] = 1;\r\n        pairs[v][u] = 1;\r\n    }\r\n    \r\n    rep(k,0,10) rep(j,0,1024) {\r\n        rint mask = 1<<k;\r\n        rep(l,0,10) if (j&(1<<l)) if (pairs[l][k]) {\r\n            if (l < k) {\r\n                mask = -1;\r\n                break;\r\n            }\r\n            mask |= 1<<l;\r\n        }\r\n        masks[k][j] = mask;\r\n    }\r\n\r\n    dp[0][0] = 1;\r\n    rep(i,0,n) rep(j,0,1024) if (dp[i][j]) rep(k,0,10) {\r\n        rint mask = masks[k][j];\r\n        if (0 <= mask) dp[i+1][mask] = (dp[i+1][mask]+dp[i][j]) % MOD;\r\n    }\r\n\r\n    rint total = 0;\r\n    rep(j,0,1024) total = (total+dp[n][j]) % MOD;\r\n    write(total), putchar('\\n');\r\n\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "02cd94cbf53f847d5af5a40ff601bd7a", "src_uid": "60955fc2caa6ec99c7dcc1da5d36b1f8", "difficulty": 2600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\n#define rint register int\r\n#define rep(i,a,b) for(rint i=(a);i<(b);i++)\r\n#define repe(i,a,b) for(rint i=(a);i<=(b);i++)\r\n#define repr(i,a,b) for(rint i=(a)-1;(b)<=i;i--)\r\n\r\nvoid writePositive(int num) {\r\n    if (num > 0) {\r\n        writePositive(num / 10);\r\n        putchar(num % 10 + '0');\r\n    }\r\n}\r\n\r\nvoid write(int num) {\r\n    if (num == 0) putchar('0');\r\n    else if (num < 0) {\r\n        putchar('-');\r\n        writePositive(-num);\r\n    } else writePositive(num);\r\n}\r\n\r\nint read() {\r\n    rint sign = 1;\r\n    rint num = 0;\r\n    rint ch;\r\n    while(1) {\r\n        ch = getchar();\r\n        if (ch == '-') {\r\n            sign = -sign;\r\n            continue;\r\n        }\r\n        ch = ch-'0';\r\n        if (ch < 0 || 10 < ch) break;\r\n        num = num*10+ch;\r\n    }\r\n    return sign*num;\r\n}\r\n\r\n#define MOD 998244353\r\n\r\nint dp[50001][1024];\r\nint pairs[10][10], masks[10][1024];\r\n\r\nint main() {\r\n    rint n = read();\r\n    rint m = read();\r\n    rep(i,0,m) {\r\n        rint u = read();\r\n        rint v = read();\r\n        pairs[u][v] = 1;\r\n        pairs[v][u] = 1;\r\n    }\r\n    \r\n    rep(k,0,10) rep(j,0,1024) {\r\n        rint mask = 1<<k;\r\n        rep(l,0,10) if (j&(1<<l)) if (pairs[l][k]) {\r\n            if (l < k) {\r\n                mask = -1;\r\n                break;\r\n            }\r\n            mask |= 1<<l;\r\n        }\r\n        masks[k][j] = mask;\r\n    }\r\n\r\n    dp[0][0] = 1;\r\n    rep(i,0,n) rep(j,0,1024) rep(k,0,10) {\r\n        rint mask = masks[k][j];\r\n        if (0 <= mask) dp[i+1][mask] = (dp[i+1][mask]+dp[i][j]) % MOD;\r\n    }\r\n\r\n    rint total = 0;\r\n    rep(j,0,1024) total = (total+dp[n][j]) % MOD;\r\n    write(total), putchar('\\n');\r\n\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5943368414d35f61eeaab37d5ac1124e", "src_uid": "60955fc2caa6ec99c7dcc1da5d36b1f8", "difficulty": 2600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <string.h>\r\n\r\n#define MOD 998244353\r\n\r\nint main() {\r\n\tint n, m;\r\n\tscanf(\"%d%d\", &n, &m);\r\n\r\n\tstatic int c[10];\r\n\r\n\tfor (int i = 0; i < m; ++i) {\r\n\t\tint u, v;\r\n\t\tscanf(\"%d%d\", &u, &v);\r\n\t\tc[u] |= 1 << v;\r\n\t\tc[v] |= 1 << u;\r\n\t}\r\n\r\n\tfor (int u = 0; u < 10; ++u) {\r\n\t\tc[u] |= 1 << u;\r\n\t}\r\n\r\n\tstatic int dp[1024];\r\n\t\r\n\tfor (int u = 0; u < 10; ++u) {\r\n\t\tdp[1 << u] = 1;\r\n\t}\r\n\t\r\n\twhile (--n) {\r\n\t\tstatic int tmp[1024];\r\n\t\t\r\n\t\tmemset(tmp, 0, sizeof(tmp));\r\n\r\n\t\tfor (int i = 0; i < 1024; ++i) {\r\n\t\t\tfor (int x = 0; x < 10; ++x) {\r\n\t\t\t\tint j = i & c[x] | (1 << x);\r\n\t\t\t\tif (j & ((1 << x) - 1)) \r\n\t\t\t\t\tcontinue;\r\n\t\t\t\tif ((tmp[j] += dp[i]) >= MOD) \r\n\t\t\t\t\ttmp[j] -= MOD;\r\n\t\t\t}\r\n\t\t}\r\n\r\n\t\tmemcpy(dp, tmp, sizeof(dp));\r\n\t}\r\n\r\n\tint res = 0;\r\n\tfor (int i = 0; i < 1024; ++i) {\r\n\t\tif ((res += dp[i]) >= MOD) \r\n\t\t\tres -= MOD;\r\n\t}\r\n\r\n\tprintf(\"%d\\n\", res);\r\n}\r\n\r\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e49ef8dc3436d3744bbdc05361b902b4", "src_uid": "60955fc2caa6ec99c7dcc1da5d36b1f8", "difficulty": 2600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\ntypedef long long ll;\r\n#define rll register ll\r\n#define rint register int\r\n#define rep(i,a,b) for(rll i=(a);i<(b);i++)\r\n#define repe(i,a,b) for(rll i=(a);i<=(b);i++)\r\n#define repr(i,a,b) for(rll i=(a)-1;(b)<=i;i--)\r\n\r\nvoid writePositive(ll num) {\r\n    if (num > 0) {\r\n        writePositive(num / 10);\r\n        putchar(num % 10 + '0');\r\n    }\r\n}\r\n\r\nvoid write(ll num) {\r\n    if (num == 0) putchar('0');\r\n    else if (num < 0) {\r\n        putchar('-');\r\n        writePositive(-num);\r\n    } else writePositive(num);\r\n}\r\n\r\nll read() {\r\n    rint sign = 1;\r\n    rll num = 0;\r\n    rint ch;\r\n    while(1) {\r\n        ch = getchar();\r\n        if (ch == '-') {\r\n            sign = -sign;\r\n            continue;\r\n        }\r\n        ch = ch-'0';\r\n        if (ch < 0 || 10 < ch) break;\r\n        num = num*10+ch;\r\n    }\r\n    return sign*num;\r\n}\r\n\r\n#define MOD 998244353\r\n\r\nll dp[50001][1024];\r\nint pairs[10][10], masks[10][1024];\r\n\r\nint main() {\r\n    rll n = read();\r\n    rll m = read();\r\n    rep(i,0,m) {\r\n        rll u = read();\r\n        rll v = read();\r\n        pairs[u][v] = 1;\r\n        pairs[v][u] = 1;\r\n    }\r\n    \r\n    rep(k,0,10) rep(j,0,1024) {\r\n        rint mask = 1<<k;\r\n        rep(l,0,10) if (j&(1<<l)) if (pairs[l][k]) {\r\n            if (l < k) {\r\n                mask = -1;\r\n                break;\r\n            }\r\n            mask |= 1<<l;\r\n        }\r\n        masks[k][j] = mask;\r\n    }\r\n\r\n    dp[0][0] = 1;\r\n    rep(i,0,n) rep(j,0,1024) rep(k,0,10) {\r\n        rint mask = masks[k][j];\r\n        if (0 <= mask) dp[i+1][mask] = (dp[i+1][mask]+dp[i][j]) % MOD;\r\n    }\r\n\r\n    rll total = 0;\r\n    rep(j,0,1024) total = (total+dp[n][j]) % MOD;\r\n    write(total), putchar('\\n');\r\n\r\n    return 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "0f74c7e54701c8e59ed96e684e999a35", "src_uid": "60955fc2caa6ec99c7dcc1da5d36b1f8", "difficulty": 2600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nlong long int modpow(long long int a, long long int n, long long int p)\n{\n\tif (n < 0)\n\t\treturn 0;\n\tlong long int res = 1;\n\twhile (n > 0)\n\t{\n\t\tif (n % 2 > 0)\n\t\t\tres = res * a % p;\n\t\ta = a * a % p;\n\t\tn /= 2;\n\t}\n\treturn res;\n}\nint main()\n{\n\tlong long int n, m, l, r;\n\tscanf(\"%lld %lld %lld %lld\", &n, &m, &l, &r);\n\tlong long int p = 998244353;\n\tif (n * m % 2 > 0)\n\t\tprintf(\"%lld\\n\", modpow(r - l + 1, n * m, p));\n\telse if ((r - l) % 2 > 0)\n\t\tprintf(\"%lld\\n\", modpow(r - l + 1, n * m, p) * modpow(2, p - 2, p) % p);\n\telse\n\t\tprintf(\"%lld\\n\", (modpow(r - l + 1, n * m, p) + 1) * modpow(2, p - 2, p) % p);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "72e985ddfacc05a09ea8732a056752a1", "src_uid": "ded299fa1cd010822c60f2389a3ba1a3", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n \n#define MD\t998244353\n \nlong long power(int a, long long k) {\n\tlong long p;\n \n\tif (k == 0)\n\t\treturn 1;\n\tp = power(a, k >> 1);\n\tp = p * p % MD;\n\tif (k & 1)\n\t\tp = p * a % MD;\n\treturn p;\n}\n \nvoid mult(int aa[][2], int bb[][2], int cc[][2]) {\n\tint i, j;\n \n\tfor (i = 0; i < 2; i++)\n\t\tfor (j = 0; j < 2; j++)\n\t\t\tcc[i][j] = ((long long) aa[i][0] * bb[0][j] + (long long) aa[i][1] * bb[1][j]) % MD;\n}\n \nvoid power_(int aa[][2], int pp[][2], int tt[][2], long long k) {\n\tif (k == 0) {\n\t\tint i, j;\n \n\t\tfor (i = 0; i < 2; i++)\n\t\t\tfor (j = 0; j < 2; j++)\n\t\t\t\tpp[i][j] = i == j;\n\t\treturn;\n\t}\n\tif ((k & 1) == 0) {\n\t\tpower_(aa, tt, pp, k >> 1);\n\t\tmult(tt, tt, pp);\n\t} else {\n\t\tpower_(aa, pp, tt, k >> 1);\n\t\tmult(pp, pp, tt);\n\t\tmult(tt, aa, pp);\n\t}\n}\n \nint main() {\n\tstatic int aa[2][2], pp[2][2], tt[2][2];\n\tint n, m, l, r, e, o;\n \n\tscanf(\"%d%d%d%d\", &n, &m, &l, &r);\n\tif ((long long) n * m % 2 != 0) {\n\t\tprintf(\"%lld\\n\", power(r - l + 1, (long long) n * m));\n\t\treturn 0;\n\t}\n\te = r / 2 - (l - 1) / 2, o = r - l + 1 - e;\n\taa[0][0] = e, aa[0][1] = o;\n\taa[1][0] = o, aa[1][1] = e;\n\tpower_(aa, pp, tt, (long long) n * m);\n\tprintf(\"%d\\n\", pp[0][0]);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e1fb63345b99667aeb8d837426a32198", "src_uid": "ded299fa1cd010822c60f2389a3ba1a3", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define MD\t998244353\n\nlong long power(int a, long long k) {\n\tlong long p;\n\n\tif (k == 0)\n\t\treturn 1;\n\tp = power(a, k >> 1);\n\tp = p * p % MD;\n\tif (k & 1)\n\t\tp = p * a % MD;\n\treturn p;\n}\n\nvoid mult(int aa[][2], int bb[][2], int cc[][2]) {\n\tint i, j;\n\n\tfor (i = 0; i < 2; i++)\n\t\tfor (j = 0; j < 2; j++)\n\t\t\tcc[i][j] = ((long long) aa[i][0] * bb[0][j] + (long long) aa[i][1] * bb[1][j]) % MD;\n}\n\nvoid power_(int aa[][2], int pp[][2], int tt[][2], long long k) {\n\tif (k == 0) {\n\t\tint i, j;\n\n\t\tfor (i = 0; i < 2; i++)\n\t\t\tfor (j = 0; j < 2; j++)\n\t\t\t\tpp[i][j] = i == j;\n\t\treturn;\n\t}\n\tif ((k & 1) == 0) {\n\t\tpower_(aa, tt, pp, k >> 1);\n\t\tmult(tt, tt, pp);\n\t} else {\n\t\tpower_(aa, pp, tt, k >> 1);\n\t\tmult(pp, pp, tt);\n\t\tmult(tt, aa, pp);\n\t}\n}\n\nint main() {\n\tstatic int aa[2][2], pp[2][2], tt[2][2];\n\tint n, m, l, r, e, o;\n\n\tscanf(\"%d%d%d%d\", &n, &m, &l, &r);\n\tif ((long long) n * m % 2 != 0) {\n\t\tprintf(\"%lld\\n\", power(r - l + 1, (long long) n * m));\n\t\treturn 0;\n\t}\n\te = r / 2 - (l - 1) / 2, o = r - l + 1 - e;\n\taa[0][0] = e, aa[0][1] = o;\n\taa[1][0] = o, aa[1][1] = e;\n\tpower_(aa, pp, tt, (long long) n * m);\n\tprintf(\"%d\\n\", pp[0][0]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f0df45d1eaa3dce73432d69b4ca24e44", "src_uid": "ded299fa1cd010822c60f2389a3ba1a3", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define MD\t998244353\n\nvoid mult(int aa[][2], int bb[][2], int cc[][2]) {\n\tint i, j;\n\n\tfor (i = 0; i < 2; i++)\n\t\tfor (j = 0; j < 2; j++)\n\t\t\tcc[i][j] = ((long long) aa[i][0] * bb[0][j] + (long long) aa[i][1] * bb[1][j]) % MD;\n}\n\nvoid power(int aa[][2], int pp[][2], int tt[][2], long long k) {\n\tif (k == 0) {\n\t\tint i, j;\n\n\t\tfor (i = 0; i < 2; i++)\n\t\t\tfor (j = 0; j < 2; j++)\n\t\t\t\tpp[i][j] = i == j;\n\t\treturn;\n\t}\n\tif ((k & 1) == 0) {\n\t\tpower(aa, tt, pp, k / 2);\n\t\tmult(tt, tt, pp);\n\t} else {\n\t\tpower(aa, pp, tt, k / 2);\n\t\tmult(pp, pp, tt);\n\t\tmult(tt, aa, pp);\n\t}\n}\n\nint main() {\n\tstatic int aa[2][2], pp[2][2], tt[2][2];\n\tint n, m, l, r, e, o;\n\n\tscanf(\"%d%d%d%d\", &n, &m, &l, &r);\n\te = r / 2 - (l - 1) / 2, o = r - l + 1 - e;\n\taa[0][0] = e, aa[0][1] = o;\n\taa[1][0] = o, aa[1][1] = e;\n\tpower(aa, pp, tt, (long long) n * m);\n\tprintf(\"%d\\n\", pp[0][0]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "03d52a3b37c7b4369c55bf0d58d1ce1d", "src_uid": "ded299fa1cd010822c60f2389a3ba1a3", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <sys/time.h>\n\n#define N\t500000\n#define INF\t0x3f3f3f3f\n\nint min(int a, int b) { return a < b ? a : b; }\nint max(int a, int b) { return a > b ? a : b; }\n\nunsigned int X;\n\nvoid srand_() {\n\tstruct timeval tv;\n\n\tgettimeofday(&tv, NULL);\n\tX = tv.tv_sec ^ tv.tv_usec;\n}\n\nint rand_() {\n\treturn (X *= 3) >> 1;\n}\n\nlong long ss[N + 1];\n\nvoid sort(int *ii, int l, int r) {\n\twhile (l < r) {\n\t\tint i = l, j = l, k = r, i_ = ii[l + rand_() % (r - l)], tmp;\n\n\t\twhile (j < k)\n\t\t\tif (ss[ii[j]] == ss[i_])\n\t\t\t\tj++;\n\t\t\telse if (ss[ii[j]] < ss[i_]) {\n\t\t\t\ttmp = ii[i], ii[i] = ii[j], ii[j] = tmp;\n\t\t\t\ti++, j++;\n\t\t\t} else {\n\t\t\t\tk--;\n\t\t\t\ttmp = ii[j], ii[j] = ii[k], ii[k] = tmp;\n\t\t\t}\n\t\tsort(ii, l, i);\n\t\tl = k;\n\t}\n}\n\nint search(int *ii, int n, long long s) {\n\tint lower = -1, upper = n;\n\n\twhile (upper - lower > 1) {\n\t\tint h = (lower + upper) / 2;\n\n\t\tif (ss[ii[h]] >= s)\n\t\t\tupper = h;\n\t\telse\n\t\t\tlower = h;\n\t}\n\treturn lower;\n}\n\nint ft1[N + 1], ft2[N + 1];\n\nvoid update(int *ft, int i, int n, int x) {\n\twhile (i < n) {\n\t\tft[i] = min(ft[i], x);\n\t\ti |= i + 1;\n\t}\n}\n\nint query(int *ft, int i) {\n\tint x = INF;\n\n\twhile (i >= 0) {\n\t\tx = min(x, ft[i]);\n\t\ti &= i + 1, i--;\n\t}\n\treturn x;\n}\n\nint main() {\n\tint t;\n\n\tsrand_();\n\tscanf(\"%d\", &t);\n\twhile (t--) {\n\t\tstatic int aa[N + 1], qu[2][N + 1], head[2], cnt[2], ii[N], ll[N + 1], ll_[N + 1], rr_[N + 1], pp[N + 1], dp[N + 1], dq[N + 1];\n\t\tint n, h, h_, i, j;\n\t\tlong long sum;\n\n\t\tscanf(\"%d\", &n);\n\t\tfor (i = 1; i <= n; i++)\n\t\t\tscanf(\"%d\", &aa[i]), aa[i] -= 2;\n\t\tfor (i = 1; i <= n; i++)\n\t\t\tss[i] = aa[i] - (i == 0 ? 0 : ss[i - 1]);\n\t\thead[0] = cnt[0] = head[1] = cnt[1] = 0;\n\t\tfor (i = 0, j = 0; j <= n; j++) {\n\t\t\twhile (cnt[j % 2] && ss[qu[j % 2][head[j % 2] + cnt[j % 2] - 1]] >= ss[j])\n\t\t\t\tcnt[j % 2]--;\n\t\t\tqu[j % 2][head[j % 2] + cnt[j % 2]++] = j;\n\t\t\twhile (ss[qu[0][head[0]]] + ss[qu[1][head[1]]] < 0) {\n\t\t\t\tif (qu[i % 2][head[i % 2]] == i)\n\t\t\t\t\thead[i % 2]++, cnt[i % 2]--;\n\t\t\t\ti++;\n\t\t\t}\n\t\t\tll[j] = i;\n\t\t\tif (j > 0 && aa[j] % 2 == 0) {\n\t\t\t\th = search(qu[j % 2] + head[j % 2], cnt[j % 2], ss[j] - aa[j] / 2);\n\t\t\t\tll_[j] = h == -1 ? 0 : qu[j % 2][head[j % 2] + h] + 1;\n\t\t\t\th = search(qu[j % 2 ^ 1] + head[j % 2 ^ 1], cnt[j % 2 ^ 1], aa[j] / 2 - ss[j]);\n\t\t\t\tll_[j] = max(ll_[j], h == -1 ? 0 : qu[j % 2 ^ 1][head[j % 2 ^ 1] + h] + 1);\n\t\t\t}\n\t\t}\n\t\tcnt[0] = cnt[1] = 0;\n\t\tfor (i = n; i > 0; i--) {\n\t\t\twhile (cnt[i % 2] && ss[qu[i % 2][cnt[i % 2] - 1]] >= ss[i])\n\t\t\t\tcnt[i % 2]--;\n\t\t\tqu[i % 2][cnt[i % 2]++] = i;\n\t\t\tif (i > 0 && aa[i] % 2 == 0) {\n\t\t\t\th = search(qu[i % 2], cnt[i % 2], ss[i] - aa[i] / 2);\n\t\t\t\trr_[i] = h == -1 ? n : qu[i % 2][h] - 1;\n\t\t\t\th = search(qu[i % 2 ^ 1], cnt[i % 2 ^ 1], aa[i] / 2 - ss[i]);\n\t\t\t\trr_[i] = min(rr_[i], h == -1 ? n : qu[i % 2 ^ 1][h] - 1);\n\t\t\t}\n\t\t}\n\t\tsum = 0;\n\t\tfor (i = 1; i <= n; i++) {\n\t\t\tss[i] = sum + (i % 2 == 0 ? aa[i] / 2 : -aa[i] / 2);\n\t\t\tsum += i % 2 == 0 ? aa[i] : -aa[i];\n\t\t\tii[i - 1] = i;\n\t\t}\n\t\tsort(ii, 0, n);\n\t\tfor (h = 0; h < n; h = h_) {\n\t\t\tlong long s = ss[ii[h]];\n\n\t\t\th_ = h, i = 0;\n\t\t\twhile (h_ < n && ss[ii[h_]] == s) {\n\t\t\t\tif (aa[ii[h_]] % 2 == 0)\n\t\t\t\t\tpp[ii[h_]] = i, i = ii[h_];\n\t\t\t\telse\n\t\t\t\t\tpp[ii[h_]] = 0;\n\t\t\t\th_++;\n\t\t\t}\n\t\t}\n\t\tmemset(ft1, 0x3f, (n + 1) * sizeof *ft1);\n\t\tmemset(ft2, 0x3f, (n + 1) * sizeof *ft2);\n\t\tupdate(ft1, n - 0, n + 1, 0);\n\t\tfor (i = 1; i <= n; i++) {\n\t\t\tdp[i] = min(query(ft2, n - i), query(ft1, n - ll[i]) + 1);\n\t\t\tif (aa[i] % 2 == 0) {\n\t\t\t\tdq[i] = query(ft1, n - ll_[i]);\n\t\t\t\tif (pp[i] && ll_[i] <= pp[i])\n\t\t\t\t\tdq[i] = min(dq[i], dq[pp[i]] - 1);\n\t\t\t} else\n\t\t\t\tdq[i] = INF;\n\t\t\tupdate(ft1, n - i, n + 1, dp[i]);\n\t\t\tif (dq[i] != INF) {\n\t\t\t\tupdate(ft1, n - i, n + 1, dq[i]);\n\t\t\t\tupdate(ft2, n - rr_[i], n + 1, dq[i]);\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\", n + min(dp[n], dq[n]));\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3aad20210ca615a737d70d74a87283bc", "src_uid": "e809d068b3ae47eb5ecfb9ac69892254", "difficulty": 3200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <sys/time.h>\n\n#define N\t500000\n#define INF\t0x3f3f3f3f\n\nint min(int a, int b) { return a < b ? a : b; }\nint max(int a, int b) { return a > b ? a : b; }\n\nunsigned int X;\n\nvoid srand_() {\n\tstruct timeval tv;\n\n\tgettimeofday(&tv, NULL);\n\tX = tv.tv_sec ^ tv.tv_usec;\n}\n\nint rand_() {\n\treturn (X *= 3) >> 1;\n}\n\nlong long ss[N + 1];\n\nvoid sort(int *ii, int l, int r) {\n\twhile (l < r) {\n\t\tint i = l, j = l, k = r, i_ = ii[l + rand_() % (r - l)], tmp;\n\n\t\twhile (j < k) {\n\t\t\tint c = ss[ii[j]] != ss[i_] ? ss[ii[j]] - ss[i_] : ii[j] - i_;\n\n\t\t\tif (c == 0)\n\t\t\t\tj++;\n\t\t\telse if (c < 0) {\n\t\t\t\ttmp = ii[i], ii[i] = ii[j], ii[j] = tmp;\n\t\t\t\ti++, j++;\n\t\t\t} else {\n\t\t\t\tk--;\n\t\t\t\ttmp = ii[j], ii[j] = ii[k], ii[k] = tmp;\n\t\t\t}\n\t\t}\n\t\tsort(ii, l, i);\n\t\tl = k;\n\t}\n}\n\nint search(int *ii, int n, long long s) {\n\tint lower = -1, upper = n;\n\n\twhile (upper - lower > 1) {\n\t\tint h = (lower + upper) / 2;\n\n\t\tif (ss[ii[h]] >= s)\n\t\t\tupper = h;\n\t\telse\n\t\t\tlower = h;\n\t}\n\treturn lower;\n}\n\nint ft1[N + 1], ft2[N + 1];\n\nvoid update(int *ft, int i, int n, int x) {\n\twhile (i < n) {\n\t\tft[i] = min(ft[i], x);\n\t\ti |= i + 1;\n\t}\n}\n\nint query(int *ft, int i) {\n\tint x = INF;\n\n\twhile (i >= 0) {\n\t\tx = min(x, ft[i]);\n\t\ti &= i + 1, i--;\n\t}\n\treturn x;\n}\n\nint main() {\n\tint t;\n\n\tsrand_();\n\tscanf(\"%d\", &t);\n\twhile (t--) {\n\t\tstatic int aa[N + 1], qu[2][N + 1], head[2], cnt[2], ii[N], ll[N + 1], ll_[N + 1], rr_[N + 1], pp[N + 1], dp[N + 1], dq[N + 1];\n\t\tint n, h, h_, i, j;\n\t\tlong long sum;\n\n\t\tscanf(\"%d\", &n);\n\t\tfor (i = 1; i <= n; i++)\n\t\t\tscanf(\"%d\", &aa[i]), aa[i] -= 2;\n\t\tfor (i = 1; i <= n; i++)\n\t\t\tss[i] = aa[i] - (i == 0 ? 0 : ss[i - 1]);\n\t\thead[0] = cnt[0] = head[1] = cnt[1] = 0;\n\t\tfor (i = 0, j = 0; j <= n; j++) {\n\t\t\twhile (cnt[j % 2] && ss[qu[j % 2][head[j % 2] + cnt[j % 2] - 1]] >= ss[j])\n\t\t\t\tcnt[j % 2]--;\n\t\t\tqu[j % 2][head[j % 2] + cnt[j % 2]++] = j;\n\t\t\twhile (ss[qu[0][head[0]]] + ss[qu[1][head[1]]] < 0) {\n\t\t\t\tif (qu[i % 2][head[i % 2]] == i)\n\t\t\t\t\thead[i % 2]++, cnt[i % 2]--;\n\t\t\t\ti++;\n\t\t\t}\n\t\t\tll[j] = i;\n\t\t\tif (j > 0 && aa[j] % 2 == 0) {\n\t\t\t\th = search(qu[j % 2] + head[j % 2], cnt[j % 2], ss[j] - aa[j] / 2);\n\t\t\t\tll_[j] = h == -1 ? 0 : qu[j % 2][head[j % 2] + h] + 1;\n\t\t\t\th = search(qu[j % 2 ^ 1] + head[j % 2 ^ 1], cnt[j % 2 ^ 1], aa[j] / 2 - ss[j]);\n\t\t\t\tll_[j] = max(ll_[j], h == -1 ? 0 : qu[j % 2 ^ 1][head[j % 2 ^ 1] + h] + 1);\n\t\t\t}\n\t\t}\n\t\tcnt[0] = cnt[1] = 0;\n\t\tfor (i = n; i > 0; i--) {\n\t\t\twhile (cnt[i % 2] && ss[qu[i % 2][cnt[i % 2] - 1]] >= ss[i])\n\t\t\t\tcnt[i % 2]--;\n\t\t\tqu[i % 2][cnt[i % 2]++] = i;\n\t\t\tif (i > 0 && aa[i] % 2 == 0) {\n\t\t\t\th = search(qu[i % 2], cnt[i % 2], ss[i] - aa[i] / 2);\n\t\t\t\trr_[i] = h == -1 ? n : qu[i % 2][h] - 1;\n\t\t\t\th = search(qu[i % 2 ^ 1], cnt[i % 2 ^ 1], aa[i] / 2 - ss[i]);\n\t\t\t\trr_[i] = min(rr_[i], h == -1 ? n : qu[i % 2 ^ 1][h] - 1);\n\t\t\t}\n\t\t}\n\t\tsum = 0;\n\t\tfor (i = 1; i <= n; i++) {\n\t\t\tss[i] = sum + (i % 2 == 0 ? aa[i] / 2 : -aa[i] / 2);\n\t\t\tsum += i % 2 == 0 ? aa[i] : -aa[i];\n\t\t\tii[i - 1] = i;\n\t\t}\n\t\tsort(ii, 0, n);\n\t\tfor (h = 0; h < n; h = h_) {\n\t\t\tlong long s = ss[ii[h]];\n\n\t\t\th_ = h, i = 0;\n\t\t\twhile (h_ < n && ss[ii[h_]] == s) {\n\t\t\t\tif (aa[ii[h_]] % 2 == 0)\n\t\t\t\t\tpp[ii[h_]] = i, i = ii[h_];\n\t\t\t\telse\n\t\t\t\t\tpp[ii[h_]] = 0;\n\t\t\t\th_++;\n\t\t\t}\n\t\t}\n\t\tmemset(ft1, 0x3f, (n + 1) * sizeof *ft1);\n\t\tmemset(ft2, 0x3f, (n + 1) * sizeof *ft2);\n\t\tupdate(ft1, n - 0, n + 1, 0);\n\t\tfor (i = 1; i <= n; i++) {\n\t\t\tdp[i] = min(query(ft2, n - i), query(ft1, n - ll[i]) + 1);\n\t\t\tif (aa[i] % 2 == 0) {\n\t\t\t\tdq[i] = query(ft1, n - ll_[i]);\n\t\t\t\tif (pp[i] && ll_[i] <= pp[i])\n\t\t\t\t\tdq[i] = min(dq[i], dq[pp[i]] - 1);\n\t\t\t} else\n\t\t\t\tdq[i] = INF;\n\t\t\tupdate(ft1, n - i, n + 1, dp[i]);\n\t\t\tif (dq[i] != INF) {\n\t\t\t\tupdate(ft1, n - i, n + 1, dq[i]);\n\t\t\t\tupdate(ft2, n - rr_[i], n + 1, dq[i]);\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\", n + min(dp[n], dq[n]));\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2ce990c814543bc0250271fdfbd8327c", "src_uid": "e809d068b3ae47eb5ecfb9ac69892254", "difficulty": 3200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <sys/time.h>\n\n#define N\t500000\n#define INF\t0x3f3f3f3f\n\nint min(int a, int b) { return a < b ? a : b; }\nint max(int a, int b) { return a > b ? a : b; }\n\nunsigned int X;\n\nvoid srand_() {\n\tstruct timeval tv;\n\n\tgettimeofday(&tv, NULL);\n\tX = tv.tv_sec ^ tv.tv_usec;\n}\n\nint rand_() {\n\treturn (X *= 3) >> 1;\n}\n\nlong long ss[N + 1];\n\nvoid sort(int *ii, int l, int r) {\n\twhile (l < r) {\n\t\tint i = l, j = l, k = r, i_ = ii[l + rand_() % (r - l)], tmp;\n\n\t\twhile (j < k)\n\t\t\tif (ss[ii[j]] == ss[i_])\n\t\t\t\tj++;\n\t\t\telse if (ss[ii[j]] < ss[i_]) {\n\t\t\t\ttmp = ii[i], ii[i] = ii[j], ii[j] = tmp;\n\t\t\t\ti++, j++;\n\t\t\t} else {\n\t\t\t\tk--;\n\t\t\t\ttmp = ii[j], ii[j] = ii[k], ii[k] = tmp;\n\t\t\t}\n\t\tsort(ii, l, i);\n\t\tl = k;\n\t}\n}\n\nint search(int *ii, int n, long long s) {\n\tint lower = -1, upper = n;\n\n\twhile (upper - lower > 1) {\n\t\tint h = (lower + upper) / 2;\n\n\t\tif (ss[ii[h]] >= s)\n\t\t\tupper = h;\n\t\telse\n\t\t\tlower = h;\n\t}\n\treturn lower;\n}\n\nint ft1[N + 1], ft2[N + 1];\n\nvoid update(int *ft, int i, int n, int x) {\n\twhile (i < n) {\n\t\tft[i] = min(ft[i], x);\n\t\ti |= i + 1;\n\t}\n}\n\nint query(int *ft, int i) {\n\tint x = INF;\n\n\twhile (i >= 0) {\n\t\tx = min(x, ft[i]);\n\t\ti &= i + 1, i--;\n\t}\n\treturn x;\n}\n\nint main() {\n\tint t;\n\n\tsrand_();\n\tscanf(\"%d\", &t);\n\twhile (t--) {\n\t\tstatic int aa[N + 1], qu[2][N + 1], head[2], cnt[2], ii[N], ll[N + 1], ll_[N + 1], rr_[N + 1], pp[N + 1], dp[N + 1], dq[N + 1];\n\t\tint n, h, h_, i, j;\n\t\tlong long sum;\n\n\t\tscanf(\"%d\", &n);\n\t\tfor (i = 1; i <= n; i++)\n\t\t\tscanf(\"%d\", &aa[i]), aa[i] -= 2;\n\t\tfor (i = 1; i <= n; i++)\n\t\t\tss[i] = aa[i] - (i == 0 ? 0 : ss[i - 1]);\n\t\thead[0] = cnt[0] = head[1] = cnt[1] = 0;\n\t\tfor (i = 0, j = 0; j <= n; j++) {\n\t\t\twhile (cnt[j % 2] && ss[qu[j % 2][head[j % 2] + cnt[j % 2] - 1]] >= ss[j])\n\t\t\t\tcnt[j % 2]--;\n\t\t\tqu[j % 2][head[j % 2] + cnt[j % 2]++] = j;\n\t\t\twhile (ss[qu[0][head[0]]] + ss[qu[1][head[1]]] < 0) {\n\t\t\t\tif (qu[i % 2][head[i % 2]] == i)\n\t\t\t\t\thead[i % 2]++, cnt[i % 2]--;\n\t\t\t\ti++;\n\t\t\t}\n\t\t\tll[j] = i;\n\t\t\tif (j > 0 && aa[j] % 2 == 0) {\n\t\t\t\th = search(qu[j % 2] + head[j % 2], cnt[j % 2], ss[j] - aa[j] / 2);\n\t\t\t\tll_[j] = h == -1 ? 0 : qu[j % 2][head[j % 2] + h] + 1;\n\t\t\t\th = search(qu[j % 2 ^ 1] + head[j % 2 ^ 1], cnt[j % 2 ^ 1], aa[j] / 2 - ss[j]);\n\t\t\t\tll_[j] = max(ll_[j], h == -1 ? 0 : qu[j % 2 ^ 1][head[j % 2 ^ 1] + h] + 1);\n\t\t\t}\n\t\t}\n\t\tcnt[0] = cnt[1] = 0;\n\t\tfor (i = n; i > 0; i--) {\n\t\t\twhile (cnt[i % 2] && ss[qu[i % 2][cnt[i % 2] - 1]] >= ss[i])\n\t\t\t\tcnt[i % 2]--;\n\t\t\tqu[i % 2][cnt[i % 2]++] = i;\n\t\t\tif (i > 0 && aa[i] % 2 == 0) {\n\t\t\t\th = search(qu[i % 2], cnt[i % 2], ss[i] - aa[i] / 2);\n\t\t\t\trr_[i] = h == -1 ? n : qu[i % 2][h] - 1;\n\t\t\t\th = search(qu[i % 2 ^ 1], cnt[i % 2 ^ 1], aa[i] / 2 - ss[i]);\n\t\t\t\trr_[i] = min(rr_[i], h == -1 ? n : qu[i % 2 ^ 1][h] - 1);\n\t\t\t}\n\t\t}\n\t\tsum = 0;\n\t\tfor (i = 1; i <= n; i++) {\n\t\t\tss[i] = sum + (i % 2 == 0 ? aa[i] / 2 : -aa[i] / 2);\n\t\t\tsum += i % 2 == 0 ? aa[i] : -aa[i];\n\t\t\tii[i - 1] = i;\n\t\t}\n\t\tsort(ii, 0, n);\n\t\tfor (h = 0; h < n; h = h_) {\n\t\t\tlong long s = ss[ii[h]];\n\n\t\t\th_ = h, i = 0;\n\t\t\twhile (h_ < n && ss[ii[h_]] == s) {\n\t\t\t\tif (aa[ii[h_]] % 2 == 0)\n\t\t\t\t\tpp[ii[h_]] = i, i = ii[h_];\n\t\t\t\telse\n\t\t\t\t\tpp[ii[h_]] = 0;\n\t\t\t\th_++;\n\t\t\t}\n\t\t}\n\t\tmemset(ft1, 0x3f, (n + 1) * sizeof *ft1);\n\t\tmemset(ft2, 0x3f, (n + 1) * sizeof *ft2);\n\t\tupdate(ft1, n - 0, n + 1, 0);\n\t\tfor (i = 1; i <= n; i++) {\n\t\t\tdp[i] = min(query(ft2, n - i), query(ft1, n - ll[i]) + 1);\n\t\t\tif (aa[i] % 2 == 0) {\n\t\t\t\tdq[i] = query(ft1, n - ll_[i]);\n\t\t\t\tif (pp[i] && ll_[i] <= pp[i])\n\t\t\t\t\tdq[i] = min(dq[i], dq[pp[i]] - 1);\n\t\t\t} else\n\t\t\t\tdq[i] = INF;\n\t\t\tupdate(ft1, n - i, n + 1, dp[i]);\n\t\t\tupdate(ft1, n - i, n + 1, dq[i]);\n\t\t\tupdate(ft2, n - rr_[i], n + 1, dq[i]);\n\t\t}\n\t\tprintf(\"%d\\n\", n + min(dp[n], dq[n]));\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c8ee8ccb1ca19f0f5b8faca56612facb", "src_uid": "e809d068b3ae47eb5ecfb9ac69892254", "difficulty": 3200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <sys/time.h>\n\n#define N\t500000\n#define INF\t0x3f3f3f3f\n\nint min(int a, int b) { return a < b ? a : b; }\nint max(int a, int b) { return a > b ? a : b; }\n\nunsigned int X;\n\nvoid srand_() {\n\tstruct timeval tv;\n\n\tgettimeofday(&tv, NULL);\n\tX = tv.tv_sec ^ tv.tv_usec;\n}\n\nint rand_() {\n\treturn (X *= 3) >> 1;\n}\n\nlong long ss[N + 1];\n\nvoid sort(int *ii, int l, int r) {\n\twhile (l < r) {\n\t\tint i = l, j = l, k = r, i_ = ii[l + rand_() % (r - l)], tmp;\n\n\t\twhile (j < k) {\n\t\t\tint c = ss[ii[j]] != ss[i_] ? ss[ii[j]] - ss[i_] : ii[j] - i_;\n\n\t\t\tif (c == 0)\n\t\t\t\tj++;\n\t\t\telse if (c < 0) {\n\t\t\t\ttmp = ii[i], ii[i] = ii[j], ii[j] = tmp;\n\t\t\t\ti++, j++;\n\t\t\t} else {\n\t\t\t\tk--;\n\t\t\t\ttmp = ii[j], ii[j] = ii[k], ii[k] = tmp;\n\t\t\t}\n\t\t}\n\t\tsort(ii, l, i);\n\t\tl = k;\n\t}\n}\n\nint search(int *ii, int n, long long s) {\n\tint lower = -1, upper = n;\n\n\twhile (upper - lower > 1) {\n\t\tint h = (lower + upper) / 2;\n\n\t\tif (ss[ii[h]] >= s)\n\t\t\tupper = h;\n\t\telse\n\t\t\tlower = h;\n\t}\n\treturn lower;\n}\n\nint ft1[N + 1], ft2[N + 1];\n\nvoid update(int *ft, int i, int n, int x) {\n\twhile (i < n) {\n\t\tft[i] = min(ft[i], x);\n\t\ti |= i + 1;\n\t}\n}\n\nint query(int *ft, int i) {\n\tint x = INF;\n\n\twhile (i >= 0) {\n\t\tx = min(x, ft[i]);\n\t\ti &= i + 1, i--;\n\t}\n\treturn x;\n}\n\nint main() {\n\tint t;\n\n\tsrand_();\n\tscanf(\"%d\", &t);\n\twhile (t--) {\n\t\tstatic int aa[N + 1], qu[2][N + 1], head[2], cnt[2], ii[N], ll[N + 1], ll_[N + 1], rr_[N + 1], pp[N + 1], dp[N + 1], dq[N + 1];\n\t\tint n, h, h_, i, j;\n\t\tlong long sum;\n\n\t\tscanf(\"%d\", &n);\n\t\tfor (i = 1; i <= n; i++)\n\t\t\tscanf(\"%d\", &aa[i]), aa[i] -= 2;\n\t\tfor (i = 1; i <= n; i++)\n\t\t\tss[i] = aa[i] - (i == 0 ? 0 : ss[i - 1]);\n\t\thead[0] = cnt[0] = head[1] = cnt[1] = 0;\n\t\tfor (i = 0, j = 0; j <= n; j++) {\n\t\t\twhile (cnt[j % 2] && ss[qu[j % 2][head[j % 2] + cnt[j % 2] - 1]] >= ss[j])\n\t\t\t\tcnt[j % 2]--;\n\t\t\tqu[j % 2][head[j % 2] + cnt[j % 2]++] = j;\n\t\t\twhile (i < j && ss[qu[0][head[0]]] + ss[qu[1][head[1]]] < 0) {\n\t\t\t\tif (qu[i % 2][head[i % 2]] == i)\n\t\t\t\t\thead[i % 2]++, cnt[i % 2]--;\n\t\t\t\ti++;\n\t\t\t}\n\t\t\tll[j] = i;\n\t\t\tif (j > 0 && aa[j] % 2 == 0) {\n\t\t\t\th = search(qu[j % 2] + head[j % 2], cnt[j % 2], ss[j] - aa[j] / 2);\n\t\t\t\tll_[j] = h == -1 ? i : qu[j % 2][head[j % 2] + h] + 1;\n\t\t\t\th = search(qu[j % 2 ^ 1] + head[j % 2 ^ 1], cnt[j % 2 ^ 1], aa[j] / 2 - ss[j]);\n\t\t\t\tll_[j] = max(ll_[j], h == -1 ? i : qu[j % 2 ^ 1][head[j % 2 ^ 1] + h] + 1);\n\t\t\t}\n\t\t}\n\t\tcnt[0] = cnt[1] = 0;\n\t\tfor (i = n; i > 0; i--) {\n\t\t\twhile (cnt[i % 2] && ss[qu[i % 2][cnt[i % 2] - 1]] >= ss[i])\n\t\t\t\tcnt[i % 2]--;\n\t\t\tqu[i % 2][cnt[i % 2]++] = i;\n\t\t\tif (i > 0 && aa[i] % 2 == 0) {\n\t\t\t\th = search(qu[i % 2], cnt[i % 2], ss[i] - aa[i] / 2);\n\t\t\t\trr_[i] = h == -1 ? n : qu[i % 2][h] - 1;\n\t\t\t\th = search(qu[i % 2 ^ 1], cnt[i % 2 ^ 1], aa[i] / 2 - ss[i]);\n\t\t\t\trr_[i] = min(rr_[i], h == -1 ? n : qu[i % 2 ^ 1][h] - 1);\n\t\t\t}\n\t\t}\n\t\tsum = 0;\n\t\tfor (i = 1; i <= n; i++) {\n\t\t\tss[i] = sum + (i % 2 == 0 ? aa[i] / 2 : -aa[i] / 2);\n\t\t\tsum += i % 2 == 0 ? aa[i] : -aa[i];\n\t\t\tii[i - 1] = i;\n\t\t}\n\t\tsort(ii, 0, n);\n\t\tfor (h = 0; h < n; h = h_) {\n\t\t\tlong long s = ss[ii[h]];\n\n\t\t\th_ = h, i = 0;\n\t\t\twhile (h_ < n && ss[ii[h_]] == s) {\n\t\t\t\tif (aa[ii[h_]] % 2 == 0)\n\t\t\t\t\tpp[ii[h_]] = i, i = ii[h_];\n\t\t\t\telse\n\t\t\t\t\tpp[ii[h_]] = 0;\n\t\t\t\th_++;\n\t\t\t}\n\t\t}\n\t\tmemset(ft1, 0x3f, (n + 1) * sizeof *ft1);\n\t\tmemset(ft2, 0x3f, (n + 1) * sizeof *ft2);\n\t\tupdate(ft1, n - 0, n + 1, 0);\n\t\tfor (i = 1; i <= n; i++) {\n\t\t\tdp[i] = min(query(ft2, n - i), query(ft1, n - ll[i]) + 1);\n\t\t\tif (aa[i] % 2 == 0) {\n\t\t\t\tdq[i] = query(ft1, n - ll_[i]);\n\t\t\t\tif (pp[i] && ll_[i] <= pp[i])\n\t\t\t\t\tdq[i] = min(dq[i], dq[pp[i]] - 1);\n\t\t\t} else\n\t\t\t\tdq[i] = INF;\n\t\t\tupdate(ft1, n - i, n + 1, dp[i]);\n\t\t\tif (dq[i] != INF) {\n\t\t\t\tupdate(ft1, n - i, n + 1, dq[i]);\n\t\t\t\tupdate(ft2, n - rr_[i], n + 1, dq[i]);\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\", n + min(dp[n], dq[n]));\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "08d886348263edc4df66f6288b82b745", "src_uid": "e809d068b3ae47eb5ecfb9ac69892254", "difficulty": 3200.0}
{"lang": "GNU C11", "source_code": "/* https://codeforces.com/contest/1206/submission/59041923 (Dukkha) */\n#include <stdio.h>\n#include <stdlib.h>\n\n#define N\t1000\n\nint next[1 + (N - 1) * 2], jj[1 + (N - 1) * 2];\n\nint link(int l, int j) {\n\tstatic int l_ = 1;\n\n\tnext[l_] = l;\n\tjj[l_] = j;\n\treturn l_++;\n}\n\nint n;\nint ao[N], cc[N];\nint i_, j_, n_;\n\nint dfs(int p, int i) {\n\tint l, j, c_, c;\n\n\tc = 1;\n\tfor (l = ao[i]; l; l = next[l]) {\n\t\tj = jj[l];\n\t\tif (j != p)\n\t\t\tc += dfs(i, j);\n\t}\n\tc_ = c < n - c ? c : n - c;\n\tif (n_ < c_) {\n\t\tn_ = c_;\n\t\tif (c <= n - c) {\n\t\t\ti_ = i;\n\t\t\tj_ = p;\n\t\t} else {\n\t\t\ti_ = p;\n\t\t\tj_ = i;\n\t\t}\n\t}\n\tcc[i] = c;\n\treturn c;\n}\n\nint compare(const void *a, const void *b) {\n\tint i = *(int *) a;\n\tint j = *(int *) b;\n\n\treturn cc[i] - cc[j];\n}\n\nint a, b;\n\nvoid dfs_(int p, int i, int c) {\n\tint l, j;\n\n\ta += b;\n\tprintf(\"%d %d %d\\n\", p + 1, i + 1, a - c);\n\tc = a;\n\tfor (l = ao[i]; l; l = next[l]) {\n\t\tj = jj[l];\n\t\tif (j != p)\n\t\t\tdfs_(i, j, c);\n\t}\n}\n\nint main() {\n\tstatic int tt[N];\n\tint h, i, j, k, l, s, n_, changed;\n\n\tscanf(\"%d\", &n);\n\tfor (h = 0; h < n - 1; h++) {\n\t\tscanf(\"%d%d\", &i, &j), i--, j--;\n\t\tao[i] = link(ao[i], j);\n\t\tao[j] = link(ao[j], i);\n\t}\n\ti_ = -1, j_ = -1, n_ = -1;\n\tdfs(-1, 0);\n\ts = j_;\n\tdfs(-1, s);\n\tk = 0;\n\tfor (l = ao[s]; l; l = next[l])\n\t\ttt[k++] = jj[l];\n\tqsort(tt, k, sizeof *tt, compare);\n\tn_ = 1;\n\tb = 1, a = 0;\n\tchanged = 0;\n\tfor (h = 0; h < k; h++) {\n\t\tj = tt[h];\n\t\tdfs_(s, j, 0);\n\t\tn_ += cc[j];\n\t\tif (!changed && n_ * 3 >= n) {\n\t\t\tchanged = 1;\n\t\t\tb = n_, a = 0;\n\t\t}\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ad75027170f24e0e7171877cd8694fcd", "src_uid": "87d755df6ee27b381122062659c4a432", "difficulty": 2700.0}
{"lang": "GNU C11", "source_code": "https://en.wikipedia.org/wiki/Dada\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "5313817ae71f1c3bd40f07cf5c41924d", "src_uid": "87d755df6ee27b381122062659c4a432", "difficulty": 2700.0}
{"lang": "GNU C11", "source_code": "/* https://codeforces.com/blog/entry/451 */\n#include <stdio.h>\n\n#define N\t150\n#define M\t50\n#define MD\t51123987\n\nint main() {\n\tstatic char cc[N + 1];\n\tstatic int next[N][3], dp[N + 1][M + 1][M + 1][M + 1];\n\tint n, m, i, a, ka, kb, kc, ans;\n\n\tscanf(\"%d%s\", &n, cc), m = (n + 2) / 3;\n\tif (n < 3) {\n\t\tprintf(n == 1 || cc[0] != cc[1] ? \"1\\n\" : \"0\\n\");\n\t\treturn 0;\n\t}\n\tfor (i = n - 1; i >= 0; i--)\n\t\tfor (a = 0; a < 3; a++)\n\t\t\tnext[i][a] = cc[i] == a + 'a' ? i : (i + 1 == n ? n : next[i + 1][a]);\n\tdp[0][0][0][0] = 1;\n\tfor (i = 0; i < n; i++)\n\t\tfor (ka = 0; ka <= m; ka++)\n\t\t\tfor (kb = 0; kb <= m; kb++)\n\t\t\t\tfor (kc = 0; kc <= m; kc++) {\n\t\t\t\t\tint x = dp[i][ka][kb][kc], j;\n\n\t\t\t\t\tif (x == 0)\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\tif (ka < m && (j = next[i][0]) < n)\n\t\t\t\t\t\tdp[j][ka + 1][kb][kc] = (dp[j][ka + 1][kb][kc] + x) % MD;\n\t\t\t\t\tif (kb < m && (j = next[i][1]) < n)\n\t\t\t\t\t\tdp[j][ka][kb + 1][kc] = (dp[j][ka][kb + 1][kc] + x) % MD;\n\t\t\t\t\tif (kc < m && (j = next[i][2]) < n)\n\t\t\t\t\t\tdp[j][ka][kb][kc + 1] = (dp[j][ka][kb][kc + 1] + x) % MD;\n\t\t\t\t}\n\tans = 0;\n\tif (n % 3 == 0) {\n\t\tka = m, kb = m, kc = m;\n\t\tfor (i = 0; i <= n; i++)\n\t\t\tans = (ans + dp[i][ka][kb][kc]) % MD;\n\t} else if (n % 3 == 1) {\n\t\tka = m - 1, kb = m - 1, kc = m;\n\t\tfor (i = 0; i <= n; i++)\n\t\t\tans = (ans + dp[i][ka][kb][kc]) % MD;\n\t\tka = m, kb = m - 1, kc = m - 1;\n\t\tfor (i = 0; i <= n; i++)\n\t\t\tans = (ans + dp[i][ka][kb][kc]) % MD;\n\t\tka = m - 1, kb = m, kc = m - 1;\n\t\tfor (i = 0; i <= n; i++)\n\t\t\tans = (ans + dp[i][ka][kb][kc]) % MD;\n\t} else {\n\t\tka = m - 1, kb = m, kc = m;\n\t\tfor (i = 0; i <= n; i++)\n\t\t\tans = (ans + dp[i][ka][kb][kc]) % MD;\n\t\tka = m, kb = m - 1, kc = m;\n\t\tfor (i = 0; i <= n; i++)\n\t\t\tans = (ans + dp[i][ka][kb][kc]) % MD;\n\t\tka = m, kb = m, kc = m - 1;\n\t\tfor (i = 0; i <= n; i++)\n\t\t\tans = (ans + dp[i][ka][kb][kc]) % MD;\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0e85c7c6c62e124b5b2a1e2e1627ea5b", "src_uid": "64fada10630906e052ff05f2afbf337e", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define rep(i,l,r) for(register int i=l;i<=r;++i)\nconst int MOD=51123987;\nint dp[151][51][51][51];\nint next[160][3],n,ans;\nchar s[160];\ninline int abs(int x){return x>0?x:-x;}\ninline int pd(int a,int b){return abs(a-b)<2?1:0;}\nint main(){\n    scanf(\"%d\",&n);\n    scanf(\"%s\",s+1);\n    rep(i,0,2) next[n+1][i]=n+1;\n    for(register int i=n;i;--i){rep(j,0,2) next[i][j]=next[i+1][j];next[i][s[i]-'a']=i;}\n    dp[1][0][0][0]=1;\n    //int 50=(n+2)/3;\n    rep(i,1,n) rep(j,0,50) rep(k,0,50) rep(l,0,50){\n        if(j+k+l==n&&pd(j,k)&&pd(j,l)&&pd(k,l)){ans=(ans+dp[i][j][k][l])%MOD;continue;}\n        if(next[i][0]<=n) dp[next[i][0]][j+1][k][l]=(dp[next[i][0]][j+1][k][l]+dp[i][j][k][l])%MOD;\n        if(next[i][1]<=n) dp[next[i][1]][j][k+1][l]=(dp[next[i][1]][j][k+1][l]+dp[i][j][k][l])%MOD;\n        if(next[i][2]<=n) dp[next[i][2]][j][k][l+1]=(dp[next[i][2]][j][k][l+1]+dp[i][j][k][l])%MOD;\n    }\n    printf(\"%d\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "b7153bfee3cee4d8b3f144b1223424db", "src_uid": "64fada10630906e052ff05f2afbf337e", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define rep(i,l,r) for(register int i=l;i<=r;++i)\nconst int MOD=51123987;\nint dp[160][60][60][60];\nint next[160][3],n,ans;\nchar s[160];\ninline int abs(int x){return x>0?x:-x;}\ninline int pd(int a,int b){return abs(a-b)<2?1:0;}\nint main(){\n    scanf(\"%d\",&n);\n    scanf(\"%s\",s+1);\n    rep(i,0,2) next[n+1][i]=n+1;\n    for(register int i=n;i;--i){rep(j,0,2) next[i][j]=next[i+1][j];next[i][s[i]-'a']=i;}\n    dp[1][0][0][0]=1;\n    //int 50=(n+2)/3;\n    rep(i,1,n) rep(j,0,50) rep(k,0,50) rep(l,0,50){\n        if(j+k+l==n&&pd(j,k)&&pd(j,l)&&pd(k,l)){ans=(ans+dp[i][j][k][l])%MOD;continue;}\n        if(next[i][0]<=n) dp[next[i][0]][j+1][k][l]=(dp[next[i][0]][j+1][k][l]+dp[i][j][k][l])%MOD;\n        if(next[i][1]<=n) dp[next[i][1]][j][k+1][l]=(dp[next[i][1]][j][k+1][l]+dp[i][j][k][l])%MOD;\n        if(next[i][2]<=n) dp[next[i][2]][j][k][l+1]=(dp[next[i][2]][j][k][l+1]+dp[i][j][k][l])%MOD;\n    }\n    printf(\"%d\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ca0d6028d97223271050548d371f45a5", "src_uid": "64fada10630906e052ff05f2afbf337e", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\n#define LIM 160\n#define M 51123987\n\nint ab(int x){if(x<0) return -x; return x;}\n\nint dp[8][LIM][LIM][LIM];\nchar in[LIM]; int len;\n\nint main(){\n  int i,j,k,l,m,n,r,res,sum,lim;\n  int a,b,c;\n\n  rep(m,8) rep(i,LIM) rep(j,LIM) rep(k,LIM) dp[m][i][j][k]=0;\n  dp[7][0][0][0]=1;\n  \n  scanf(\"%d%s\",&len,in);\n  lim = (len+8)/3;\n\n  rep(i,len) in[i]-='a';\n\n  rep(l,len){\n    if(in[l]==0){\n      rep(m,8) if(m&1<<in[l]){\n        rep(b,lim) rep(c,lim){\n          sum = 0;\n          REP(a,1,lim){\n            sum = (sum+dp[m][a-1][b][c])%M;\n            dp[7-(1<<in[l])][a][b][c] = (dp[7-(1<<in[l])][a][b][c]+sum)%M;\n            dp[m-(1<<in[l])][a-1][b][c] = (dp[m-(1<<in[l])][a-1][b][c]+dp[m][a-1][b][c])%M;\n            dp[m][a-1][b][c] = 0;\n          }\n        }\n      }\n    }\n    if(in[l]==1){\n      rep(m,8) if(m&1<<in[l]){\n        rep(a,lim) rep(c,lim){\n          sum = 0;\n          REP(b,1,lim){\n            sum = (sum+dp[m][a][b-1][c])%M;\n            dp[7-(1<<in[l])][a][b][c] = (dp[7-(1<<in[l])][a][b][c]+sum)%M;\n            dp[m-(1<<in[l])][a][b-1][c] = (dp[m-(1<<in[l])][a][b-1][c]+dp[m][a][b-1][c])%M;\n            dp[m][a][b-1][c] = 0;\n          }\n        }\n      }\n    }\n    if(in[l]==2){\n      rep(m,8) if(m&1<<in[l]){\n        rep(a,lim) rep(b,lim){\n          sum = 0;\n          REP(c,1,lim){\n            sum = (sum+dp[m][a][b][c-1])%M;\n            dp[7-(1<<in[l])][a][b][c] = (dp[7-(1<<in[l])][a][b][c]+sum)%M;\n            dp[m-(1<<in[l])][a][b][c-1] = (dp[m-(1<<in[l])][a][b][c-1]+dp[m][a][b][c-1])%M;\n            dp[m][a][b][c-1] = 0;\n          }\n        }\n      }\n    }\n  }\n  \n  res=0;\n  rep(m,8) rep(i,lim) rep(j,lim) rep(k,lim){\n    if(i+j+k != len) continue;\n    if(ab(i-j)>1 || ab(j-k)>1 || ab(k-i)>1) continue;\n    res = (res+dp[m][i][j][k])%M;\n  }\n  printf(\"%d\\n\",res);\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f40c522f7e2b5e577d4033674b518991", "src_uid": "64fada10630906e052ff05f2afbf337e", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define rep(i,l,r) for(register int i=l;i<=r;++i)\nconst int MOD=51123987;\nint dp[160][60][60][60];\nint next[160][3],n,ans;\nchar s[160];\ninline int abs(int x){return x>0?x:-x;}\ninline bool pd(int a,int b){return abs(a-b)<2;}\nint main(){\n    scanf(\"%d\",&n);\n    scanf(\"%s\",s+1);\n    rep(i,0,2) next[n+1][i]=n+1;\n    for(register int i=n;i;--i){rep(j,0,2) next[i][j]=next[i+1][j];next[i][s[i]-'a']=i;}\n    dp[1][0][0][0]=1;\n    //int 50=(n+2)/3;\n    rep(i,1,n) rep(j,0,50) rep(k,0,50) rep(l,0,50){\n        if(j+k+l==n&&pd(j,k)&&pd(j,l)&&pd(k,l)){ans=(ans+dp[i][j][k][l])%MOD;continue;}\n        if(next[i][0]<=n) dp[next[i][0]][j+1][k][l]=(dp[next[i][0]][j+1][k][l]+dp[i][j][k][l])%MOD;\n        if(next[i][1]<=n) dp[next[i][1]][j][k+1][l]=(dp[next[i][1]][j][k+1][l]+dp[i][j][k][l])%MOD;\n        if(next[i][2]<=n) dp[next[i][2]][j][k][l+1]=(dp[next[i][2]][j][k][l+1]+dp[i][j][k][l])%MOD;\n    }\n    printf(\"%d\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "ccee3424cdf8e1017f3547aebdbeda6b", "src_uid": "64fada10630906e052ff05f2afbf337e", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <ctype.h>\n\n// program by Mircea Rebengiuc\n// written for codeforces round 740D2\n// written on 2021.08.24\n\n#define MAXN 200000\n\nint psum[1 + MAXN + 1];\n\nint mod;\nint n;\n\nstatic inline int getSum( int l, int r ){\n  return (psum[l] - psum[(r < n ? r : n) + 1] + mod) % mod;\n}\n\nint main(){\n  int i, j, d;\n\n  scanf(\"%d%d\", &n, &mod);\n  psum[n] = 1;\n  psum[n + 1] = 0;\n  for( i = n - 1 ; i > 0 ; i-- ){\n    psum[i] = getSum(i + 1, n);\n    for( d = 2 ; i * d <= n ; d++ )\n      psum[i] = (psum[i] + getSum(i * d, (i + 1) * d - 1)) % mod;\n\n    psum[i] = (psum[i + 1] + psum[i]) % mod;\n  }\n\n  printf(\"%d\\n\", getSum(1, 1));\n  \n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fed8ab034fd7aef57f25e6cf432603fc", "src_uid": "a524aa54e83fd0223489a19531bf0e79", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\r\nlong long f[400000],s[400000];\r\nint main(){\r\n\tint n,m,i;\r\n\tscanf(\"%d%d\",&n,&m);\r\n\tf[1]=s[1]=1;\r\n\tfor(i=2;i<=n;i++){\r\n\t\tf[i]=s[i-1];\r\n\t\tint l=2,r=0;\r\n\t\tfor(;l<=i;l=r+1){\r\n\t\t\tr=i/(i/l);\r\n\t\t\tf[i]+=(r-l+1)*f[i/l];\r\n\t\t}\r\n\t\ts[i]=(f[i]+s[i-1])%m;\r\n\t}\r\n\r\n\tprintf(\"%d\\n\",f[n]%m);\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1f28a20748bfa2dd4687102ee1af68ab", "src_uid": "a524aa54e83fd0223489a19531bf0e79", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t4000000\n\nint main() {\n\tstatic int dp[N + 1], dq[N + 1], dr[N + 1];\n\tint n, md, i, j;\n\n\tscanf(\"%d%d\", &n, &md);\n\tfor (i = 1; i <= n; i++) {\n\t\tif ((dr[i] += dr[i - 1]) >= md)\n\t\t\tdr[i] -= md;\n\t\tif (i == 1)\n\t\t\tdp[i] = 1;\n\t\telse\n\t\t\tif ((dp[i] = dq[i - 1] + dr[i]) >= md)\n\t\t\t\tdp[i] -= md;\n\t\tif ((dq[i] = dp[i] + dq[i - 1]) >= md)\n\t\t\tdq[i] -= md;\n\t\tfor (j = 1; i * j <= n; j++) {\n\t\t\tif ((dr[i * j] += dp[i]) >= md)\n\t\t\t\tdr[i * j] -= md;\n\t\t\tif ((i + 1) * j <= n && (dr[(i + 1) * j] -= dp[i]) < 0)\n\t\t\t\tdr[(i + 1) * j] += md;\n\t\t}\n\t}\n\tprintf(\"%d\\n\", dp[n]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1650446dbee8297b98bc6b627b32e002", "src_uid": "a524aa54e83fd0223489a19531bf0e79", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\ntypedef long long ll;\r\n\r\nll dp[200007][7], sum[200007][7];\r\n\r\nint main(){\r\n\tint n, m;\r\n\tscanf(\"%d %d\", &n, &m);\r\n\tfor (register int i = 2; i <= n; i++){\r\n\t\tint half_i = i / 2;\r\n\t\tdp[i][1] = (sum[i - 1][1] + sum[i - 1][2] + 1) % m;\r\n\t\tdp[i][2] = i - half_i;\r\n\t\tfor (register int j = 2, k; j <= half_i; j = k + 1){\r\n\t\t\tint ti = i / j;\r\n\t\t\tk = i / ti;\r\n\t\t\tdp[i][2] = (dp[i][2] + (dp[ti][1] + dp[ti][2]) * (k - j + 1) % m) % m;\r\n\t\t}\r\n\t\tsum[i][1] = (sum[i - 1][1] + dp[i][1]) % m;\r\n\t\tsum[i][2] = (sum[i - 1][2] + dp[i][2]) % m;\r\n\t}\r\n\tprintf(\"%lld\", (dp[n][1] + dp[n][2]) % m);\r\n\treturn 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "84df11b1c6af9c7a12b19915ec31a283", "src_uid": "a524aa54e83fd0223489a19531bf0e79", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nlong long MOD=(long long)(1e9+7);\n\nint main(){\n\tint n, m, i, prev, curr;\n\tlong long tab[2][2], res;\n\tscanf(\"%d %d\", &n, &m);\n\tcurr=1;\n\ttab[1][0]=2;\n\ttab[1][1]=0;\n\tfor(i=0;i<n-1;++i){\n\t\tcurr=i&1;\n\t\tprev=(curr+1)&1;\n\t\ttab[curr][0]=(tab[prev][0]+tab[prev][1])%MOD;\n\t\ttab[curr][1]=tab[prev][0];\n\t}\n\tres=tab[curr][0]+tab[curr][1];\n\tif(m==1){\n\t\tprintf(\"%I64d\\n\", res);\n\t\treturn 0;\n\t}\n\ttab[1][0]=res-2+(n==1?2:0);\n\ttab[1][1]=0;\n\tfor(i=0;i<m-1;++i){\n\t\tcurr=i&1;\n\t\tprev=(curr+1)&1;\n\t\ttab[curr][0]=(tab[prev][1]+(tab[curr][1]=tab[prev][0]%MOD))%MOD;\n\t}\n\tprintf(\"%I64d\\n\", ((n==1?0:2)+tab[curr][0]+tab[curr][1])%MOD);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6a2674212c7d873a4c32750e1578d876", "src_uid": "0f1ab296cbe0952faa904f2bebe0567b", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "f[111111], p = 1e9 + 7;\nmain(n, m, i, j) {\n\tscanf(\"%d%d\", &n, &m);\n\tf[1] = 2;\n\tfor (i = 2; i <= m + 1; i++) f[i] = (f[i - 1] + f[i - 2]) % p;\n\tprintf(\"%lld\", (1ll * f[m + 1] + f[n] + p) % p);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7b9e386bd902206c79743688006f2934", "src_uid": "0f1ab296cbe0952faa904f2bebe0567b", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nlong long MOD=(long long)(1e9+7);\n\nint main(){\n\tint n, m, i, prev, curr;\n\tlong long tab[2][2], res;\n\tscanf(\"%d %d\", &n, &m);\n\tcurr=1;\n\ttab[1][0]=2;\n\ttab[1][1]=0;\n\tfor(i=0;i<n-1;++i){\n\t\tcurr=i&1;\n\t\tprev=(curr+1)&1;\n\t\ttab[curr][0]=(tab[prev][0]+tab[prev][1])%MOD;\n\t\ttab[curr][1]=tab[prev][0];\n\t}\n\tres=tab[curr][0]+tab[curr][1];\n\tif(m==1){\n\t\tprintf(\"%I64d\\n\", res);\n\t\treturn 0;\n\t}\n\tres-=2;\n\ttab[1][0]=2;\n\ttab[1][1]=0;\n\tfor(i=0;i<m-1;++i){\n\t\tcurr=i&1;\n\t\tprev=(curr+1)&1;\n\t\ttab[curr][0]=(tab[prev][1]+(tab[curr][1]=tab[prev][0]%MOD))%MOD;\n\t}\n\tprintf(\"%I64d\\n\", (res+tab[curr][0]+tab[curr][1])%MOD);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a736dbac7b3dc3401b2708581f45d1e4", "src_uid": "0f1ab296cbe0952faa904f2bebe0567b", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "f[111111], p = 1e9 + 7;\nmain(n, m, i, j) {\n\tscanf(\"%d%d\", &n, &m);\n\tf[1] = 2;\n\tfor (i = 2; i <= m + 1; i++) f[i] = (f[i - 1] + f[i - 2]) % p;\n\tprintf(\"%lld\", (1ll * f[m + 1] + n * 2 - 2 + p) % p);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "bf09a2331130c99efb9b170678a77f75", "src_uid": "0f1ab296cbe0952faa904f2bebe0567b", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nlong long MOD=(long long)1e9+7;\n\nint main(){\n\tint n, m, i, prev, curr;\n\tlong long tab[2][2], res;\n\tscanf(\"%d %d\", &n, &m);\n\tcurr=1;\n\ttab[1][0]=2;\n\ttab[1][1]=0;\n\tfor(i=0;i<n-1;++i){\n\t\tcurr=i&1;\n\t\tprev=(curr+1)&1;\n\t\ttab[curr][0]=(tab[prev][0]+tab[prev][1])%MOD;\n\t\ttab[curr][1]=tab[prev][0];\n\t}\n\tres=tab[curr][0]+tab[curr][1];\n\tif(m==1){\n\t\tprintf(\"%I64d\\n\", res);\n\t\treturn 0;\n\t}\n\ttab[1][0]=res-2+(n==1?2:0);\n\ttab[1][1]=0;\n\tfor(i=0;i<m-1;++i){\n\t\tcurr=i&1;\n\t\tprev=(curr+1)&1;\n\t\ttab[curr][0]=(tab[prev][1]+(tab[curr][1]=tab[prev][0]%MOD))%MOD;\n\t}\n\tprintf(\"%I64d\\n\", ((n==1?0:2)+tab[curr][0]+tab[curr][1])%MOD);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4830d2364a8ddc4e694e97cc2270e772", "src_uid": "0f1ab296cbe0952faa904f2bebe0567b", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <bits/stdc++.h>\n\n#define forin(i, start, end) for (auto (i) = (start); (i) != (end); ++(i))\n#define forup(i, end) forin((i), 0, (end))\n\nusing ll = long long;\n\nusing namespace std;\nll N, A, B;\nint main()\n{\n\tios::sync_with_stdio(false);\n\tcin >> N >> A >> B;\n\tstring bitstring;\n\tcin >> bitstring;\n\tll num_adults = 0;\n\tfor (char c : bitstring) {\n\t\tif (c == '1') num_adults++;\n\t}\n\tll mini = LLONG_MAX;\n\tforin (p, 1, num_adults + 1) {\n\t\tll child = N - p;\n\t\tll in_each = child / p;\n\t\tll left = child % p;\n\t\tll total = p * (A + B * in_each * in_each) + B * left * (2*in_each + 1);\n\t\tmini = min(mini, total);\n\t}\n\tcout << mini << endl;\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "334ad7d41fef4703210e5ecfb127dc01", "src_uid": "da573a39459087ed7c42f70bc1d0e8ff", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "//#include <iostream>\n//#include <string.h>\n//#include <stdio.h>\n//#include <stdlib.h>\n//#include <sys/time.h>\n//#include <unistd.h>\n//#include <arpa/inet.h>\n//#include <memory>\n//#include <signal.h>\n//#include <thread>\n//#include <unistd.h>\n//#include <sys/un.h>\n//#include <string>\n\n#include <stdio.h>\n#include <stdlib.h>\n#include <stdint.h>\nconst int MAXN = 100000;\n\nint n, m, d;\n\nstruct pair\n{\n\tint c;\n\tint w;\n}phys[MAXN], info[MAXN];\n\nuint64_t phys_pref_cost[MAXN], phys_pref_width[MAXN];\nuint64_t info_pref_cost[MAXN], info_pref_width[MAXN];\n\nuint64_t total_cost = 0;\n\nint comp (const void *a, const void *b)\n{\n\tconst struct pair * pa = (struct pair *)a;\n\tconst struct pair * pb = (struct pair *)b;\n\tif (pa->c > pb->c) return -1;\n\tif (pa->c < pb->c) return 1;\n\tif (pa->w < pb->w) return -1;\n\tif (pa->w > pb->w) return 1;\n\treturn 0;\n}\n\nint main()\n{\n\tint i, j;\n\tint phys_width_pos = 0;\n\tint info_width_pos = 0;\n\tscanf(\"%d %d %d\", &n, &m, &d);\n\tfor (i = 0; i < n; ++i)\n\t{\n\t\tscanf(\"%d %d\", &phys[i].c, &phys[i].w);\n\t}\n\tfor (i = 0; i < m; ++i)\n\t{\n\t\tscanf(\"%d %d\", &info[i].c, &info[i].w);\n\t}\n\tqsort(phys, n, sizeof(phys[0]), comp);\n\tqsort(info, m, sizeof(info[0]), comp);\n\n\tphys_pref_cost[0] = phys[0].c;\n\tphys_pref_width[0] =phys[0].w;\n\tfor (i = 1; i < n; ++i)\n\t{\n\t\tphys_pref_cost[i] = phys_pref_cost[i - 1] + phys[i].c;\n\t\tphys_pref_width[i] = phys_pref_width[i - 1] + phys[i].w;\n\t}\n\tinfo_pref_cost[0] = info[0].c;\n\tinfo_pref_width[0] =info[0].w;\n\tfor (i = 1; i < m; ++i)\n\t{\n\t\tinfo_pref_cost[i] = info_pref_cost[i - 1] + info[i].c;\n\t\tinfo_pref_width[i] = info_pref_width[i - 1] + info[i].w;\n\t}\n\tif (phys[0].w + info[0].w > d)\n\t{\n\t\tprintf (\"0\\n\");\n\t\treturn 0;\n\t}\n\t{\n\t\tuint64_t max_width = d - info[0].w;\n\t\ti = 1;\n\t\twhile (i < n && phys_pref_width[i] <= max_width)\n\t\t{\n\t\t\t++i;\n\t\t}\n\t\tphys_width_pos =  --i;\n\t\tif (total_cost < phys_pref_cost[i] + info[0].c)\n\t\t{\n\t\t\ttotal_cost = phys_pref_cost[i] + info[0].c;\n\t\t}\n\t}\n\t{\n\t\tuint64_t max_width = d - phys[0].w;\n\t\ti = 1;\n\t\twhile (i < m && info_pref_width[i] <= max_width)\n\t\t{\n\t\t\t++i;\n\t\t}\n\t\tinfo_width_pos = --i;\n\t\tif (total_cost < info_pref_cost[i]+ phys[0].c)\n\t\t{\n\t\t\ttotal_cost = info_pref_cost[i] + phys[0].c;\n\t\t}\n\t}\n\n\t{\n\t\tint c_info_pos = 1;\n\t\twhile(phys_width_pos &&\n\t\t\t  info_pref_width[c_info_pos] +\n\t\t\t  phys_pref_width[phys_width_pos] > d)\n\t\t{\n\t\t\t--phys_width_pos;\n\t\t}\n\t\twhile (phys_width_pos && c_info_pos < m)\n\t\t{\n\t\t\twhile (info_pref_width[c_info_pos] +\n\t\t\t\t   phys_pref_width[phys_width_pos] <= d)\n\t\t\t{\n\t\t\t\t++c_info_pos;\n\t\t\t}\n\t\t\t--c_info_pos;\n\t\t\tif (info_pref_cost[c_info_pos] +\n\t\t\t\tphys_pref_cost[phys_width_pos] > total_cost)\n\t\t\t{\n\t\t\t\ttotal_cost = info_pref_cost[c_info_pos] +\n\t\t\t\t\t\t\t phys_pref_cost[phys_width_pos];\n\t\t\t}\n\t\t\t--phys_width_pos;\n\t\t}\n\t}\n\t{\n\t\tint c_phys_pos = 1;\n\t\twhile (info_width_pos &&\n\t\t\t   (info_pref_width[info_width_pos] +\n\t\t\t\t\t\t\t\t  phys_pref_width[c_phys_pos] > d))\n\t\t{\n\t\t\t--info_width_pos;\n\t\t}\n\t\twhile (info_width_pos && c_phys_pos < n)\n\t\t{\n\t\t\twhile (info_pref_width[info_width_pos] +\n\t\t\t\t   phys_pref_width[c_phys_pos] <= d)\n\t\t\t{\n\t\t\t\t++c_phys_pos;\n\t\t\t}\n\t\t\t--c_phys_pos;\n\t\t\tif (info_pref_cost[info_width_pos] +\n\t\t\t\tphys_pref_cost[c_phys_pos] > total_cost)\n\t\t\t{\n\t\t\t\ttotal_cost = info_pref_cost[info_width_pos] +\n\t\t\t\t\t\t\t phys_pref_cost[c_phys_pos];\n\t\t\t}\n\t\t\t--info_width_pos;\n\t\t}\n\t}\n\tprintf (\"%I64d\\n\", total_cost);\n}\n\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "795f7efcab0b45244c65e2d1483154a5", "src_uid": "da573a39459087ed7c42f70bc1d0e8ff", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n\n#define N 100*1000+7\n\nint a[N], A[N];\nint b[N], B[N];\nint ia[N], ib[N];\n\nint comp1 (const void * elem1, const void * elem2) \n{\n    int f = a[*((int*)elem1)];\n    int s = a[*((int*)elem2)];\n    if (f == s)\n    {\n        int F = A[*((int*)elem1)];\n        int S = A[*((int*)elem2)];\n        if (F > S) return -1;\n        if (F < S) return 1;\n        return 0;\n    }\n    if (f > s) return  1;\n    if (f < s) return -1;\n    return 0;\n}\n\nint comp2 (const void * elem1, const void * elem2) \n{\n    int f = b[*((int*)elem1)];\n    int s = b[*((int*)elem2)];\n    if (f == s)\n    {\n        int F = B[*((int*)elem1)];\n        int S = B[*((int*)elem2)];\n        if (F > S) return -1;\n        if (F < S) return 1;\n        return 0;\n    }\n    if (f > s) return  1;\n    if (f < s) return -1;\n    return 0;\n}\n\nvoid main()\n{\n    int n, m, w;\n    scanf(\"%d %d %d\", &n, &m, &w);\n    for (int i=0; i<n; i++)\n        scanf(\"%d %d\", a + i, A + i);\n    for (int i=0; i<m; i++)\n        scanf(\"%d %d\", b + i, B + i);\n    for (int i=0; i<n; i++)\n        ia[i] = i;\n    for (int i=0; i<m; i++)\n        ib[i] = i;\n    qsort (ia, n, sizeof(*ia), comp1);\n    qsort (ib, m, sizeof(*ib), comp2);\n    long long sum = 0, res = 0;\n    for (int i=0; i<m; i++)\n        sum += B[ib[i]], res += b[ib[i]];\n    int p = 0;\n    long long SUM = 0, RES = 0;\n    long long ans = 0;\n    for (int i=n-1; i>=0; i--)\n    {\n        SUM += A[ia[i]];\n        RES += a[ia[i]];\n        while (p+1 < m && SUM + sum > w)\n            sum -= B[ib[p]], res -= b[ib[p]], p++;\n        if (SUM + sum <= w && ans < RES + res)\n            ans = RES + res;\n    }\n    printf(\"%I64d\\n\", ans);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "cc24bac08570373879444216f16095bf", "src_uid": "da573a39459087ed7c42f70bc1d0e8ff", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdint.h>\n#define ll int64_t\n\n\nstruct pr\n{\n    ll f, s;\n} a[100001], b[100001];\n\nint cmp(const void* p1, const void* p2)\n{\n    ll d = - ((const struct pr*)p1)->f + ((const struct pr*)p2)->f;\n    if (d) return d < 0 ? -1 : 1;\n    return ((const struct pr*)p1)->s - ((const struct pr*)p2)->s > 0 ? 1 : -1;\n}\n\nint main()\n{\n    int n, m; ll d;\n    scanf(\"%d%d%I64d\", &n, &m, &d);\n    for(int i = 0; i < n; ++i)\n    {\n        scanf(\"%I64d%I64d\", &(a[i].f), &(a[i].s));\n    }\n    for(int i = 0; i < m; ++i)\n    {\n        scanf(\"%I64d%I64d\", &(b[i].f), &(b[i].s));\n    }\n    //printf(\"%lld %lld %lld %lld\\n\", a[0].f, a[0].s, b[0].f, b[0].s);\n    qsort(a, n, sizeof(struct pr), cmp);\n    qsort(b, m, sizeof(struct pr), cmp);\n //printf(\"%lld %lld %lld %lld\\n\", a[0].f, a[0].s, b[0].f, b[0].s);\n    for(int i = 1; i < n; ++i)\n    {\n        a[i].f += a[i-1].f;\n        a[i].s += a[i-1].s;\n    }\n    for(int i = 1; i < m; ++i)\n    {\n        b[i].f += b[i-1].f;\n        b[i].s += b[i-1].s;\n    }\n    int i = 0, j = 0;\n    if (a[0].s + b[0].s > d)\n    {\n        printf(\"0\");\n        return 0;\n    }\n    while(i < n && a[i].s + b[0].s <= d) ++i;\n    ll ans = 0;\n    //printf(\"%lld %lld %lld %lld\\n\", a[0].f, a[0].s, b[0].f, b[0].s);\n    while(j < m && i >= 0)\n    {\n        if (a[i].s + b[j].s <= d)\n        {\n            if (a[i].f + b[j].f > ans) ans = a[i].f + b[j].f;\n            ++j;\n        }\n        else --i;\n    }\n    printf(\"%I64d\", ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b1bdb298191593f7f4a6a23e69944e15", "src_uid": "da573a39459087ed7c42f70bc1d0e8ff", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define MAXN 100100\n\nstruct cup {\n\tint w;\n\tint v;\n} phys[MAXN], inf[MAXN];\ntypedef struct cup cup;\n\nint cupcmp(const void *a, const void *b)\n{\n\treturn -((const cup *)a)->v  + ((const cup *)b)->v;\n}\n\nint main()\n{\n\tint N, M, D;\n\tscanf(\"%d%d%d\", &N, &M, &D);\n\tfor (int i = 0; i < N; ++i) {\n\t\tscanf(\"%d%d\", &phys[i].v, &phys[i].w);\n\t}\n\tfor (int i = 0; i < M; ++i) {\n        scanf(\"%d%d\", &inf[i].v, &inf[i].w);\n    }\n\tqsort(phys, N, sizeof (phys[0]), cupcmp);\n\tqsort(inf, M, sizeof (inf[0]), cupcmp);\n    int f = 0;\n    int c = 0;\n    long long sum = phys[0].v + inf[0].v;\n    long long maxsum = sum;\n    long long width = phys[0].w + inf[0].w;\n    if (width > D) {\n\t    printf(\"0\\n\");\n\t    return 0;\n    }\n    for (f = 1; f < N; ++f) {\n\t    if (phys[f].w + width > D) {\n\t\t    break;\n\t    } else {\n\t\t    width += phys[f].w;\n\t\t    sum += phys[f].v;\n\t\t    maxsum = maxsum < sum ? sum : maxsum;\n\t    }\n    }\n    f--;\n    while (1) {\n\t    if (c + 1 < M && width + inf[c + 1].w <= D) {\n\t\t    c++;\n\t\t    width += inf[c].w;\n\t\t    sum += inf[c].v;\n            maxsum = maxsum < sum ? sum : maxsum;\n\t    } else if (f != 0) {\n\t\t    width -= phys[f].w;\n\t\t    sum -= phys[f].v;\n\t\t    f--;\n            maxsum = maxsum < sum ? sum : maxsum;\n\t    } else {\n\t\t    break;\n\t    }\n    }\n    printf(\"%I64d\\n\", maxsum);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "70f1eb1abffc265d31baa41950f50360", "src_uid": "da573a39459087ed7c42f70bc1d0e8ff", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint slen, tlen, dar[202][202][402], soln[202][202][402];\nchar s[202], t[202], finale[2003];\n\nint dp(int i, int j, int k){\n  if(i >= slen && j >= tlen)return k;\n  if(dar[i][j][k] == -1){\n    int req[2];\n    req[0] = req[1] = 0;\n    if(i < slen)req[s[i] == ')']++;\n    if(j < tlen)req[t[j] == ')']++;\n    int toret = 2003;\n    if(req[1] && k){\n      int got, newi, newj;\n      newi = i + (i < slen && s[i] == ')');\n      newj = j + (j < tlen && t[j] == ')');\n      got = 1 + dp(newi, newj, k - 1);\n      if(got < toret){\n\tsoln[i][j][k] = ')';\n\ttoret = got;\n      }\n    }\n    if(req[0] || !k){\n      int got, newi, newj;\n      newi = i + (i < slen && s[i] == '(');\n      newj = j + (j < tlen && t[j] == '(');\n      got = 1 + dp(newi, newj, k + 1);\n      if(got < toret){\n\tsoln[i][j][k] = '(';\n\ttoret = got;\n      }\n    }\n    dar[i][j][k] = toret;\n  }\n  return dar[i][j][k];\n}\n\nint main(){\n  scanf(\"%s\", s);\n  for(slen = 0;s[slen] != '\\0';slen++);\n  scanf(\"%s\", t);\n  for(tlen = 0;t[tlen] != '\\0';tlen++);\n  int i, j , k, idx, ans;\n  for(i = 0;i <= slen;i++)for(j = 0;j <= tlen;j++)for(k = 0;k < 402;k++){\n\tdar[i][j][k] = -1;\n\tsoln[i][j][k] = 'X';\n      };\n  idx = 0;\n  ans = dp(0, 0, 0);\n  i = j = k = 0;\n  while(soln[i][j][k] != 'X'){\n    finale[idx++] = soln[i][j][k];\n    if(soln[i][j][k] == '('){\n      if(i < slen && s[i] == '(')i++;\n      if(j < tlen && t[j] == '(')j++;\n      k++;\n    }\n    else{\n      if(i < slen && s[i] == ')')i++;\n      if(j < tlen && t[j] == ')')j++;\n      k--;\n    }\n  }\n  while(idx < ans)finale[idx++] = ')';\n  finale[ans] = '\\0';\n  i = j = k = 0;\n  printf(\"%s\\n\", finale);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "be10f4ab9e5a185839e6c09279ded2db", "src_uid": "cc222aab45b3ad3d0e71227592c883f1", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "// O(1) solution due to whatshisbucket\n#include <stdio.h>\n#define ull unsigned long long\n\nconst unsigned ans[201][70] = {{},{2},{4},{11},{32},{97},{295},{940},{3148},{10901},{38324},{135313},{478989},{1704939},{6120951},{22187311},{81129556},{298715961},{1105546606},{4107686743},{2426959363,3},{1411039897,13},{4172194186,49},{3689174689,187},{43344991,708},{2441471173,2674},{2801489501,10124},{260107736,38400},{2954951606,145893},{606296452,555183},{1899297838,2115855},{3084773566,8075123},{234294028,30859921},{691111333,118085088},{2180959654,452401618},{1792754283,1735233324},{2132034018,2368089356,1},{1709961728,4137532123,5},{177031067,4063007484,22},{994451568,1625053238,88},{3917739273,3065624025,340},{1540443642,2939324613,1314},{2048043699,924465791,5077},{1535675300,4143681610,19623},{1508306498,2169966175,75908},{3628011891,3750388408,293847},{690756141,2273958850,1138333},{3186013409,1633929753,4412841},{3713415519,2737515922,17118132},{1580819397,2755090312,66446442},{3380663546,3219914187,258079131},{4204882545,2751845304,1002972229},{2671126449,3985320580,3900042842},{1549923635,2321666527,2288550180,3},{3206088422,3837458666,3229658027,13},{468076678,684189096,2394878431,53},{317846743,2409125435,2929850439,208},{2292706160,2431336997,2081275227,813},{3980228298,3870290811,2271141075,3172},{2281921514,2428712631,3857202388,12377},{1410084376,2665199272,1218646022,48313},{1725477252,938399815,2490820090,188650},{96934866,3021873877,4292106543,736911},{3976807065,4196403427,2309669478,2879607},{381043316,3742984064,581598293,11256562},{75998957,558211513,3386244876,44017760},{2481446098,3420110131,878568493,172184876},{2998084519,2760121094,3693315328,673755597},{1152419028,2385275115,2073185204,2637216508},{2854085154,4023337502,2033791001,1735803802,2},{923550706,4030810318,3175452562,1786539181,9},{971375603,1399426681,1063836258,3816608870,36},{2026326245,317960303,107930394,2395208751,144},{3032216567,1211669851,2768624282,2750243364,566},{962635926,2853748285,932538563,3069568420,2221},{929452190,980373970,1397224474,1107065389,8713},{3844112081,2178623972,365972575,3179860998,34180},{2309493692,3520537616,437394707,1605782278,134118},{2212877625,2922712134,95698419,3521874850,526378},{3552645532,3742906242,3849668270,299359034,2066376},{1938082639,329182225,3901861703,3461124247,8113696},{1135006092,3990987912,565559913,3870994863,31865765},{3496777998,2726710279,3456622192,1473857377,125176826},{726284190,554922189,1177992859,2941984575,491830434},{1174922238,3146728744,935205998,249307383,1932843670},{1927883506,2548886969,3104826080,2071924719,3302449968,1},{552744259,966302059,593280121,3357489715,4099236778,6},{4057737811,3172120154,3385034438,3377497541,1487985982,27},{1120930094,52594514,1676802786,854221959,2375555749,107},{1038179455,2469373338,1067790354,815292734,357146485,423},{3401792308,639953706,455471950,2389477057,2540495932,1664},{814342077,1190616845,1267241187,3067979529,1675977447,6550},{2621993594,2832313139,1127278177,3805827021,746798329,25781},{1714067937,4219985196,3969544797,136803453,2317603907,101487},{4152787624,3611142829,843196231,3916033443,3079218285,399572},{3461864546,3893743275,2900292828,1608204305,1869768837,1573441},{3003514123,3308980254,3534417324,1621178584,481241785,6196916},{2679664471,1996930534,318652848,2268304523,3541589603,24410101},{185152026,3138914840,1871119221,1559019881,2206013312,96168136},{3737829797,1320722003,1895671615,3178554427,3061812461,378930161},{203925008,3794021407,2579620510,3431217976,3019797624,1493317916},{2468134907,3475974877,3086405423,1142109993,4005905823,1590884110,1},{180449137,547269777,665325677,2842676501,2144395769,1727357320,5},{1617684553,878842739,3960341086,1281770673,1738535346,1282366575,21},{123339094,1072406502,1883229773,1124342891,720266287,4222745088,83},{3205877069,1493036374,4168832930,361101124,1207377007,869413080,331},{30245458,166380545,1871598255,2461437325,1132735956,1418272557,1306},{4075272123,2038959813,655609662,3492982470,3995427741,486078374,5153},{608326718,1107150586,1686622377,947478086,1489690413,1051457018,20330},{4136754916,2162103160,1723971343,3979622104,220587964,3441819447,80217},{2175296377,2687555805,2858485317,2068680116,2714338065,3815351148,316557},{941177009,2263937754,4286501999,592569842,2476199853,2077265316,1249363},{72166211,744371576,1452653805,2742004280,2576941298,3652970668,4931474},{3013494591,2372455071,534269120,1360461613,3759274278,3238915720,19467772},{508737026,2615515531,1184239988,3149494987,3669012804,3205495324,76861038},{4046190885,1049147236,347431385,615864993,3013055269,783975557,303491052},{895896758,1263297489,2129431640,4200962499,4253682392,2227802501,1198489786},{862593958,4076271219,471546334,831422713,3429802533,2758946637,438405932,1},{1558843359,3239232053,4200145856,1332916817,3018622542,3909986823,1516372374,4},{3604235363,2959047772,1884763672,3716891921,127819947,2316365163,841289782,17},{2148016453,2600462985,3400301264,3261250221,3339364795,3609467668,4019991120,67},{2057336361,3281406422,2001356007,305233474,2662253073,3418788389,1817744880,26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46,137661912,10197},{593626344,3685718606,932835303,4281953533,3355177948,15176347,4132811439,1667095290,2027158372,348096588,40438},{2762201132,270311472,1739761745,3323556446,1688792644,4252294308,98283754,45888612,1013106595,4157530014,160371},{3538598781,1630328471,2324233659,2623719054,3542209653,833501619,3225441426,2426749849,342949796,919573965,636044},{618700117,1847361613,2568402629,3402135662,4069406530,3440726719,1961879249,1816107549,1163097643,861392142,2522707},{2616807824,290482935,4008503304,2827388725,3398823662,41448142,888703054,2313506850,1710980580,1436672924,10006146},{905330484,1850737061,1755710640,293093431,2890512416,1845155700,4293226377,1367354510,759724617,2153923292,39690547},{2000560120,887237321,1040273567,1259018161,97219236,4276904417,1725515412,2870030510,2879450930,3189702845,157444445},{863642990,954603462,536622170,3252710478,3940502922,1729125146,1554480730,1290181440,1973587814,248555840,624579026},{1697327337,2918819084,150398406,3763881191,2636440703,4265356736,2157835805,1468367803,3848765537,59446342,2477804464},{2446323117,1333533671,2168747137,2854032017,3081391650,4183505187,3650047026,188779407,526016429,2761793340,1240348821,2},{1300231750,3902915121,1981986679,3427190560,3237911263,3291691015,562702363,3149480449,2579229057,19020837,347055068,9},{3657932198,488720328,1446344547,3834564368,1480352990,2827046885,2880609475,697749222,2257195171,3354404202,127861599,36},{3397923977,2798002524,301001927,2304309288,1687826763,2483601671,1779363633,1352057091,713809587,2696685452,4127204450,142},{4028816566,2408052650,1213680384,4256359194,3002614222,1364230970,783390155,4126636361,832523803,2282722679,1171138251,567},{1736176841,397389969,1228600389,1516725449,2895163479,2150566846,2811167753,294595860,3564441822,1721701828,205228753,2251},{2429761274,984698965,4108659942,1199674335,293635739,625424232,948286406,3972991993,1611407721,1500862,4154934097,8932},{3222210919,690114320,50448257,2804373465,1017961958,2039183893,489159216,1151280382,158773765,2768634720,2995763167,35450},{375716695,3859193991,896415991,2993529817,3509832398,1871422233,1586062355,668318591,3165286699,495636988,3108898623,140692},{3085768643,3180394296,2124249810,1205857906,3158086867,3386222583,3793549621,3819173062,3911540842,1904718767,287398360,558388},{3435903375,4291098692,493489606,406838170,2190529579,2074994943,759798382,4196166923,3215154043,3785784988,2520590895,2216246},{3359148995,1436143251,1921872544,3037272504,3281484062,2051801502,1168216991,762202114,1408033153,2299479341,378749039,8796650},{2192988308,3067744296,1930751395,548234159,829700582,3436686196,2247851925,784563272,3717975929,908149877,1580872919,34916738},{3007043623,975843659,2616296461,3737306179,3684324109,3267538666,421308555,1472776780,1635862811,1071292237,1068791155,138601192},{2821316210,1748725430,2412011903,2527125975,948281510,391305600,772588344,3276862062,1944460202,2748703689,856637215,550195511},{4052977779,3163937748,3036712795,1138645612,501033727,4264799249,1380676331,3187355932,1832139079,645165555,1337462030,2184156409},{4201727360,2754890041,1042005963,1322883592,245155897,3538921510,886161692,1902765029,2170171535,1392634951,192228728,81019411,2},{1199257909,273544693,1994261149,3010295901,1839507415,77097517,1408801718,459303161,1544392329,3025296585,2726440504,64657343,8},{2102743037,2393063500,876912794,2198839926,3912872240,4095736174,2637471038,2384888107,503769424,4041934301,2348599738,3528755911,31}};\n\nint main () {\n  int n, M;\n  scanf(\"%d %d\", &n, &M);\n  ull v = 0;\n  for (int j = 69; j >= 0; j--) {\n    v = (v<<32)|ans[n][j];\n    v %= M;\n  }\n  printf(\"%lld\\n\", v);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "58f5e06b9c346b05c6d76b055964f933", "src_uid": "cf57508de47d80bc983861f70bb5f3d6", "difficulty": 3200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t202\n\nint min(int a, int b) { return a < b ? a : b; }\nint max(int a, int b) { return a > b ? a : b; }\n\nint vv[N + 1], ff[N + 1], gg[N + 1];\n\nvoid init(int md) {\n\tint i;\n\n\tff[0] = gg[0] = 1;\n\tfor (i = 1; i <= N; i++) {\n\t\tvv[i] = i == 1 ? 1 : (long long) vv[i - md % i] * (md / i + 1) % md;\n\t\tff[i] = (long long) ff[i - 1] * i % md;\n\t\tgg[i] = (long long) gg[i - 1] * vv[i] % md;\n\t}\n}\n\nint main() {\n\tstatic int dp[N + 1][N + 1];\n\tint n, md, a, b, k, l, s, ans;\n\n\tscanf(\"%d%d\", &n, &md), init(md);\n\tans = 0;\n\tfor (a = 1; a <= n + 1; a++) {\n\t\tfor (k = 0; k <= n; k++)\n\t\t\tmemset(dp[k], 0, (a + 1) * sizeof *dp[k]);\n\t\tdp[0][0] = 1;\n\t\tfor (b = a; b <= n + 1; b++) {\n\t\t\tfor (k = n; k >= 0; k--)\n\t\t\t\tfor (s = 0; s + (n - k) * (b - a) <= a && s + k * a <= a * (b - 1); s++) {\n\t\t\t\t\tint x = dp[k][s], k_, s_, lower, upper;\n\n\t\t\t\t\tif (x == 0)\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t/* l >= 1\n\t\t\t\t\t * k + l <= n\n\t\t\t\t\t * s + l * (b - a) + (n - (k + l)) * (b + 1 - a) <= a\n\t\t\t\t\t * s + l * (b - a) + (k + l) * a <= a * b\n\t\t\t\t\t *\n\t\t\t\t\t * l >= 1\n\t\t\t\t\t * l <= n - k\n\t\t\t\t\t * l >= s + (n - k) * (b + 1 - a) - a\n\t\t\t\t\t * l <= (a * b - s - k * a) / b\n\t\t\t\t\t */\n\t\t\t\t\tlower = max(1, s + (n - k) * (b + 1 - a) - a);\n\t\t\t\t\tupper = min(n - k, (a * b - s - k * a) / b);\n\t\t\t\t\tfor (l = lower; l <= upper; l++) {\n\t\t\t\t\t\tk_ = k + l, s_ = s + l * (b - a);\n\t\t\t\t\t\tdp[k_][s_] = (dp[k_][s_] + (long long) dp[k][s] * gg[l]) % md;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\tif (b == a)\n\t\t\t\tdp[0][0] = 0;\n\t\t}\n\t\tfor (s = 0; s <= a; s++)\n\t\t\tans = (ans + (long long) dp[n][s] * ff[n]) % md;\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f5a8a247d1d16e2146ed3c2daec3ecbc", "src_uid": "cf57508de47d80bc983861f70bb5f3d6", "difficulty": 3200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define N (10000000 + 5)\nint p, q, pi[N], rub[N], prime[N], mark[N];\nvoid make_prime(){\n\tfor (int i = 2; i < N; ++i){\n\t\tif (!mark[i]) prime[++prime[0]] = i;\n\t\tfor (int j = 1; j <= prime[0] && i * prime[j] < N; ++j){\n\t\t\tmark[i * prime[j]] = 1;\n\t\t\tif (i % prime[j] == 0) break;\n\t\t}\n\t}\n\tint ptr = 1;\n\tfor (int i = 2; i < N; ++i)\n\t\tif (prime[ptr] == i) pi[i] = pi[i - 1] + 1, ++ptr;\n\t\telse pi[i] = pi[i - 1];\n}\nint ispalin(const int x){\n\tint tmp1 = 0, tmp2 = x;\n\tfor (; tmp2; tmp2 /= 10) tmp1 = tmp1 * 10 + tmp2 % 10;\n\treturn x == tmp1;\n}\nvoid make_palin(){\n\tfor (int i = 1; i < N; ++i) rub[i] = rub[i - 1] + ispalin(i);\n}\nint main(int argc, char **argv){\n\tmake_prime();\n\tmake_palin();\n\tscanf(\"%d%d\", &p, &q);\n\tfor (int i = N - 1; i; --i)\n\t\tif (pi[i] <= (double)rub[i] * p / q){\n\t\t\tprintf(\"%d\\n\", i);\n\t\t\treturn 0;\n\t\t}\n\tprintf(\"Palindromic tree is better than splay tree\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5d8bb176c523caf41629e21dcf5ff754", "src_uid": "e6e760164882b9e194a17663625be27d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n#include <string.h>\n\n#define MAX (1L << 22)\n\nchar iscomp[MAX];\n\ntypedef long long ll;\nvoid\ndo_comp (void)\n{\n\tint i;\n\n\tiscomp[1] = 1;\n\n        for (i = 2; i < MAX; i++) {\n                int     jx;\n                int     sx;\n\n                if (iscomp[i]) {\n                        continue;\n                }\n\n\t\tif (i * i > MAX) {\n\t\t\tbreak;\n\t\t}\n                for (jx = i; (jx * i) < MAX ;jx++) {\n                        sx = jx * i;\n                        if (!iscomp[sx]) iscomp[sx] = 1;\n                }\n        }\n}\n\nint\nispal (int inp)\n{\n\tint\ti, j;\n\tchar\ttmp[32];\n\tint\tlen;\n\n\tsprintf(tmp, \"%d\", inp);\n\tlen = strlen(tmp)-1;\n\t\n\tfor (i = 0, j = len; i <= j; i++, --j) {\n\t\tif (tmp[i] != tmp[j]) {\n\t\t\treturn 0;\n\t\t}\n\t} \n\t\n\treturn 1;\n}\n\nint\nmain ()\n{\n\tint\ti,n = 1;\n\tint\tp, q;\n\tint\tnpr = 0, npa = 0;\n\tint\tans = 0;\n\n\tdo_comp();\n\tscanf (\"%d%d\", &p, &q);\n\n\tfor (i = 1; i < MAX; i++) {\n\t\tnpa += ispal (i);\n\t\tnpr += !(iscomp[i]);\n\n\t\tif ((ll)q * npr <= (ll)p * npa) {\n\t\t\tans = i;\n\t\t}\n\t}\n\tif (ans) {\n\t\tprintf (\"%d\\n\", ans);\n\t} else {\n\t\tputs (\"Palindromic tree is better than splay tree\");\n\t}\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f961a34163faeb1cb93526818c1e7128", "src_uid": "e6e760164882b9e194a17663625be27d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define max 2000001\nint prime[max],pal[max],digits[10];\n\nint isPalindrome(int a){\n    int temp=a,i=0;\n    while(temp!=0){\n        digits[i++]=temp%10;\n        temp/=10;\n    }\n    int k=i-1;\n    i=0;\n    while(i<k && digits[i]==digits[k]){\n        i++;\n        k--;\n    }\n    if(i<k)\n        return 0;\n    else{\n        return 1;\n    }\n}\n\nvoid set(){\nint i=2;\nwhile(i<max){\n    int j=2;\n    int p=j*i;\n    while(p<max){\n        prime[p]=1;\n        j++;\n        p=i*j;\n    }\n    i++;\n    while(prime[i]==1)\n        i++;\n}\nint count=0;\nfor(i=2;i<max;i++){\n    if(prime[i]==0)\n        prime[i]=(++count);\n    else\n        prime[i]=count;\n}\n\ni=1;\n//printf(\"test\\n\");\nwhile(i<max){\n        pal[i]=pal[i-1];\n    if(isPalindrome(i))\n        pal[i]+=1;\n i++;\n}\n}\n\nint main(){\nint p,q,i=1;\nset();\nint res=-1;\nscanf(\"%d%d\",&p,&q);\nwhile(i<max){\n    if(q*prime[i]<=p*pal[i]){\n        res=i;\n    }\n    i++;\n}\nif(res==-1)\nprintf(\"Palindromic tree is better than splay tree\");\nelse\n    printf(\"%d\\n\",res);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2d108b9578b9cfa6830a78a22a43020e", "src_uid": "e6e760164882b9e194a17663625be27d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define SQR 1097\n#define MAX 1200000\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n#define chkbit(ar, i) (((ar[(i) >> 6]) & (1 << (((i) >> 1) & 31))))\n#define setbit(ar, i) (((ar[(i) >> 6]) |= (1 << (((i) >> 1) & 31))))\n#define isprime(x) (( (x) && ((x)&1) && (!chkbit(ar, (x)))) || ((x) == 2))\n\nchar str[12];\nlong long p, q;\nunsigned int ar[(MAX >> 6) + 5] = {0};\nint m = 0, counter[MAX] = {0}, P[12010];\n\nvoid Sieve(){\n    int i, j, k;\n    setbit(ar, 0), setbit(ar, 1);\n\n    for (i = 3; i < SQR; i++, i++){\n        if (!chkbit(ar, i)){\n            k = i << 1;\n            for (j = (i * i); j < MAX; j += k) setbit(ar, j);\n        }\n    }\n\n    k = 0, counter[2] = ++k;\n    for (i = 3; (i + 1) < MAX; i++, i++){\n        if (isprime(i)) k++;\n        counter[i] = counter[i + 1] = k;\n    }\n}\n\nvoid backtrack(int i, int j){\n    if (i > j){\n        int x = atoi(str);\n        if (x < MAX) P[m++] = x;\n        return;\n    }\n\n    int k;\n    for (k = 0; k < 10; k++){\n        if (!i && !k) continue;\n        str[i] = str[j] = k + 48;\n        backtrack(i + 1, j - 1);\n    }\n}\n\nvoid Generate(){\n    m = 0;\n    int i, j;\n    for (i = 1; i <= 7; i++){\n        str[i] = 0;\n        backtrack(0, i - 1);\n    }\n}\n\nbool Check(int n, int i){\n    long long x = q * counter[n];\n    long long y = p * (i + 1);\n    return (x <= y);\n}\n\nint main(){\n    Sieve();\n    Generate();\n    int n, i, j, low, high, mid, res;\n\n    while (scanf(\"%I64d %I64d\", &p, &q) != EOF){\n\n        res = -1;\n        for (i = m - 2; i >= 0; i--){\n            if (Check(P[i], i)){\n                low = P[i], high = P[i + 1] - 1;\n\n                while ((low + 1) < high){\n                    mid = (low + high) >> 1;\n                    if (Check(mid, i)) low = mid;\n                    else high = mid;\n                }\n\n                if (Check(high, i)) res = high;\n                else if (Check(low, i)) res = low;\n                if (res != -1) break;\n            }\n        }\n\n        if (res == -1) puts(\"Palindromic tree is better than splay tree\");\n        else printf(\"%d\\n\", res);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "c6c3098d6386aa1196f636b09da296d0", "src_uid": "e6e760164882b9e194a17663625be27d", "difficulty": 1600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n#include <string.h>\n\n#define MAX (1L << 22)\n\nchar iscomp[MAX];\n\nvoid\ndo_comp (void)\n{\n\tint i;\n\n\tiscomp[1] = 1;\n\n        for (i = 2; i < MAX; i++) {\n                int     jx;\n                int     sx;\n\n                if (iscomp[i]) {\n                        continue;\n                }\n\n\t\tif (i * i > MAX) {\n\t\t\tbreak;\n\t\t}\n                for (jx = i; (jx * i) < MAX ;jx++) {\n                        sx = jx * i;\n                        if (!iscomp[sx]) iscomp[sx] = 1;\n                }\n        }\n}\n\nint\nispal (int inp)\n{\n\tint\ti, j;\n\tchar\ttmp[32];\n\tint\tlen;\n\n\tsprintf(tmp, \"%d\", inp);\n\tlen = strlen(tmp)-1;\n\t\n\tfor (i = 0, j = len; i <= j; i++, --j) {\n\t\tif (tmp[i] != tmp[j]) {\n\t\t\treturn 0;\n\t\t}\n\t} \n\t\n\treturn 1;\n}\n\nint\nmain ()\n{\n\tint\ti,n = 1;\n\tint\tp, q;\n\tint\tnpr = 0, npa = 0;\n\tint\tans = 0;\n\n\tdo_comp();\n\tscanf (\"%d%d\", &p, &q);\n\n\tfor (i = 1; i < MAX; i++) {\n\t\tnpa += ispal (i);\n\t\tnpr += !(iscomp[i]);\n\n\t\tif (q * npr <= p * npa) {\n\t\t\tans = i;\n\t\t}\n\t}\n\tif (ans) {\n\t\tprintf (\"%d\\n\", ans);\n\t} else {\n\t\tputs (\"Palindromic tree is better than splay tree\");\n\t}\n\t\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4ac2b30165097457e4a0f9590801cc45", "src_uid": "e6e760164882b9e194a17663625be27d", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "//set many funcs template\n//Ver.20190820\n#include<stdio.h>\n#include<string.h>\n#include<stdlib.h>\n#include<stdbool.h>\n#include<time.h>\n#define inf 1072114514\n#define llinf 4154118101919364364\n#define mod 1000000007\n#define pi 3.1415926535897932384\n \nint max(int a,int b){if(a>b){return a;}return b;}\nint min(int a,int b){if(a<b){return a;}return b;}\nint zt(int a,int b){return max(a,b)-min(a,b);}\nint round(int a,int b){if((a%b)*2 >= b){return (a/b)+1;}return a/b;}\nint ceil(int a,int b){if(a%b==0){return a/b;}return (a/b)+1;}\nint gcd(int a,int b){int c;while(b!=0){c=a%b;a=b;b=c;}return a;}\nint lcm(int a,int b){int c=gcd(a,b);a/=c;return a*b;}\nint nCr(int a,int b){int i,r=1;for(i=1;i<=b;i++){r*=(a+1-i);r/=i;}return r;}\nint nHr(int a,int b){return nCr(a+b-1,b);}\nint fact(int a){int i,r=1;for(i=1;i<=a;i++){r*=i;}return r;}\nint pow(int a,int b){int i,r=1;for(i=1;i<=b;i++){r*=a;}return r;}\nint dsum(int x){int r=0;while(x){r+=(x%10);x/=10;}return r;}\nint dsumb(int x,int b){int r=0;while(x){r+=(x%b);x/=b;}return r;}\nint sankaku(int x){return ((1+x)*x)/2;}\nvoid swap(int *a,int *b){int c;c=(*a);(*a)=(*b);(*b)=c;}\nlong long llmax(long long a,long long b){if(a>b){return a;}return b;}\nlong long llmin(long long a,long long b){if(a<b){return a;}return b;}\nlong long llzt(long long a,long long b){return llmax(a,b)-llmin(a,b);}\nlong long llround(long long a,long long b){if((a%b)*2 >= b){return (a/b)+1;}return a/b;}\nlong long llceil(long long a,long long b){if(a%b==0){return a/b;}return (a/b)+1;}\nlong long llgcd(long long a,long long b){long long c;while(b!=0){c=a%b;a=b;b=c;}return a;}\nlong long lllcm(long long a,long long b){long long c=llgcd(a,b);a/=c;return a*b;}\nlong long llnCr(long long a,long long b){long long i,r=1;for(i=1;i<=b;i++){r*=(a+1-i);r/=i;}return r;}\nlong long llnHr(long long a,long long b){return llnCr(a+b-1,b);}\nlong long llfact(long long a){long long i,r=1;for(i=1;i<=a;i++){r*=i;}return r;}\nlong long llpow(long long a,long long b){long long i,r=1;for(i=1;i<=b;i++){r*=a;}return r;}\nlong long lldsum(long long x){long long r=0;while(x){r+=(x%10);x/=10;}return r;}\nlong long lldsumb(long long x,long long b){long long r=0;while(x){r+=(x%b);x/=b;}return r;}\nlong long llsankaku(long long x){return ((1+x)*x)/2;}\nvoid llswap(long long *a,long long *b){long long c;c=(*a);(*a)=(*b);(*b)=c;}\ndouble dbmax(double a,double b){if(a>b){return a;}return b;}\ndouble dbmin(double a,double b){if(a<b){return a;}return b;}\ndouble dbzt(double a,double b){return dbmax(a,b)-dbmin(a,b);}\nvoid dbswap(double *a,double *b){double c;c=(*a);(*a)=(*b);(*b)=c;}\nvoid chswap(char *a,char *b){char c;c=(*a);(*a)=(*b);(*b)=c;}\nint sortfncsj(const void *a,const void *b){if(*(int *)a>*(int *)b){return 1;}if(*(int *)a==*(int *)b){return 0;}return -1;}\nint sortfnckj(const void *a,const void *b){if(*(int *)a<*(int *)b){return 1;}if(*(int *)a==*(int *)b){return 0;}return -1;}\nint llsortfncsj(const void *a,const void *b){if(*(long long *)a>*(long long *)b){return 1;}if(*(long long *)a==*(long long *)b){return 0;}return -1;}\nint llsortfnckj(const void *a,const void *b){if(*(long long *)a<*(long long *)b){return 1;}if(*(long long *)a==*(long long *)b){return 0;}return -1;}\nint dbsortfncsj(const void *a,const void *b){if(*(double *)a>*(double *)b){return 1;}if(*(double *)a==*(double *)b){return 0;}return -1;}\nint dbsortfnckj(const void *a,const void *b){if(*(double *)a<*(double *)b){return 1;}if(*(double *)a==*(double *)b){return 0;}return -1;}\nint strsortfncsj(const void *a,const void *b){return strcmp((char *)a,(char *)b);}\nint strsortfnckj(const void *a,const void *b){return strcmp((char *)b,(char *)a);}\nint chsortfncsj(const void *a,const void *b){if(*(char *)a>*(char *)b){return 1;}if(*(char *)a==*(char *)b){return 0;}return -1;}\nint chsortfnckj(const void *a,const void *b){if(*(char *)a<*(char *)b){return 1;}if(*(char *)a==*(char *)b){return 0;}return -1;}\n \nvoid shuffledget(int x[],int n){\n    int i,b[524288],p,c;\n    for(i=0;i<n;i++){\n        b[i]=i;\n    }\n    for(i=n;i>=1;i--){\n        p=rand()%i;\n        c=b[i-1];b[i-1]=b[p];b[p]=c;\n    }\n    for(i=0;i<n;i++){\n        scanf(\"%d\",&x[b[i]]);\n    }\n}\n \nint dx4[4]={1,-1,0,0};\nint dy4[4]={0,0,1,-1};\nint dx8[8]={-1,-1,-1,0,0,1,1,1};\nint dy8[8]={-1,0,1,-1,1,-1,0,1};\n \nint search(int x,int a[],int n){\n    int st=0,fi=n-1,te;\n    while(st<=fi){\n        te=(st+fi)/2;\n        if(a[te]<x){st=te+1;}else{fi=te-1;}\n    }\n    return st;\n}\n \nvoid prarr(int arr[],int n){\n  int i;\n  for(i=0;i<n;i++){\n    if(i){printf(\" \");}\n    printf(\"%d\",arr[i]);\n  }\n  printf(\"\\n\");\n  return;\n}\n \nvoid getperm(int a[],int n){\n  int i,p;\n  for(i=0;i<n;i++){\n    a[i]=i;\n  }\n  for(i=n-1;i>=1;i--){\n    p=rand()%(i+1);\n    swap(&a[p],&a[i]);\n  }\n}\n \ntypedef struct{\nint val;\nint node;\n}sd;\n \nint sdsortfnc(const void *a,const void *b){\nif(((sd*)a)->val < ((sd*)b)->val){return -1;}\nif(((sd*)a)->val > ((sd*)b)->val){return 1;}\nreturn 0;\n}\n \nvoid coordinate_comp(int a[],int n){\n  int i,c=0;\n  sd dat[524288];\n  for(i=0;i<n;i++){\n    dat[i].val=a[i];\n    dat[i].node=i;\n  }\n  qsort(dat,n,sizeof(dat[0]),sdsortfnc);\n  a[dat[0].node]=c;\n  for(i=1;i<n;i++){\n    if(dat[i-1].val!=dat[i].val){c++;}\n    a[dat[i].node]=c;\n  }\n}\n \nint main(void){\n  long long i,j,n,m,k,a,b,c,h,w,r=0,l,t,p;\n  scanf(\"%lld%lld\",&n,&p);\n  for(i=1;i<=60;i++){\n    if((n-i*p)<=0){continue;}\n    if(lldsumb(n-i*p,2)<=i && i<=(n-i*p)){\n      printf(\"%lld\\n\",i);\n      return 0;\n    }\n  }\n  printf(\"-1\\n\");\n  return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "71da89798f6565120cfce24a7d77ac67", "src_uid": "9e86d87ce5a75c6a982894af84eb4ba8", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#define A(x) (x > 0 ? x : -x)\nlong long dC(long long a)\n{\n\tlong long r = 0;\n\ta = A(a);\n\twhile (a)\n\t{\n\t\ta -= a & -a;\n\t\tr++;\n\t}\n\treturn r;\n}\nint main()\n{\n\tlong long t;\n\tlong long n, p;\n\tlong long B = 1;\n\tlong long temp;\n\tscanf(\"%I64d %I64d\", &n, &p);\n\tfor (t = 1; B + t * p <= n; t++)\n\t{\n\t\ttemp = n - t * p;\n\t\tif (t >= dC(temp))\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t\tB++;\n\t\tB <<= 1;\n\t\tB--;\n\t}\n\tif (B + t * p <= n)\n\t{\n\t\tprintf(\"%I64d\", t);\n\t}\n\telse\n\t{\n\t\tprintf(\"-1\");\n\t}\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1d17175aa9cc96cf3db3c2b3ae9c361f", "src_uid": "9e86d87ce5a75c6a982894af84eb4ba8", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\nint bitc(int x){\n  int toret;\n  for(toret = 0;x;x&=(x - 1))toret++;\n  return toret;\n}\n\nint main(){\n  int n, p;\n  scanf(\"%d %d\", &n, &p);\n  int i, ans;\n  ans = -1;\n  for(i = 1;i < 900;i++){\n    int rem = n - i*p;\n    if(rem >= i && bitc(rem) <= i) {ans = i;break;}\n  }\n  printf(\"%d\\n\", ans);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b3b73ea02d2e655d90008145c000ce1f", "src_uid": "9e86d87ce5a75c6a982894af84eb4ba8", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main()\n{\n    long long int n,i,k=0,x,d,r,p;\n    scanf(\"%lld %lld\",&n,&p);\n    i=1;\n    while(k==0)\n    { \n      d=0;\n      \n      \n      x=n-i*p;\n      if(x<=0)\n      {printf(\"-1\");\n       break;\n      }\n      else\n      {\n       while(x!=0)\n       {\n         r=x%2;\n         if(r==1)\n         {d++;}\n         if(d>i)\n         {\n          break;\n         }\n         x=x/2;\n       }\n       x=n-i*p;\n       if(d<=i&&i<=x)\n       {\n        printf(\"%lld\",i);\n        break;\n       }\n      }\n      i++;\n    }\n    return 0;\n}\n          \n          \n          \n          \n          \n          \n          \n      ", "lang_cluster": "C", "compilation_error": false, "code_uid": "790fbaab02bfb30f4eae4cd1785f64bc", "src_uid": "9e86d87ce5a75c6a982894af84eb4ba8", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#define l long long\nl n;\nc;\nf(x) {\n\tfor (c = 0; x; c++) x ^= x & -x;\n\treturn c;\n}\nmain(k, i) {\n\tscanf(\"%lld%d\", &n, &k);\n\tfor (i = 1; i <= 1.1e6; i++)\n\t\tif (n - k * i >= i && f(n - k * i) <= i) return !printf(\"%lld\", i);\n\tputs(\"-1\");\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "fa901e0b8cb50348f9acb316bfbf11eb", "src_uid": "9e86d87ce5a75c6a982894af84eb4ba8", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\n#define N_LIMIT 1000003 // 1e6+3\ntypedef long long ll;\n\n\nll a_pows[N_LIMIT];\n\nll inv(ll x, ll p)\n{\n    ll result = 1, y;\n    //printf(\"inverse of %lld is \", x);\n    while (x != 1)\n    {\n        y = (x+p)/x;\n        result *= y;\n        result %= p;\n        x = (x*y)%p;\n    }\n    //printf(\"%lld\\n\", result);\n    return result;\n}\n\nint main(int argc, char *argv)\n{\n    ll a, b, p, x, d = 1;\n    \n    ll n, m, y, z;\n    ll pdi;\n    ll count;\n    int i;\n    scanf(\"%lld %lld %lld %lld\", &a, &b, &p, &x);\n    a_pows[0] = 1;\n    a_pows[1] = a;\n    while (a != 1)\n    {\n        d++;\n        a = (a*a_pows[1]) % p;\n        a_pows[d] = a;\n    }\n    //printf(\"d: %lld\\n\", d);\n    count = 0;\n    pdi = inv(p-d, p);\n    for (m=0; m<d; m++)\n    {\n        n = (a_pows[d-m] * b) % p;\n        z = (pdi * (m-n)) % p;\n        if (z < 0)\n        {\n            z += p;\n        }\n\n        //printf(\"m:%lld n:%lld z:%lld count:%lld\\n\", m, n, z, count);\n        count += (x-m)/(p*d);\n        if (x%(p*d) >= z*d+m)\n        {\n            count += 1;\n        }\n    }\n    printf(\"%lld\\n\", count);\n    \n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c96aa3ae4fb72b4d8e03de1360befe14", "src_uid": "4b9f470e5889da29affae6376f6c9f6a", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <math.h>\n\n#define N_LIMIT 1000003 // 1e6+3\ntypedef long long ll;\n\n\nll a_pows[N_LIMIT];\n\nll inv(ll x, ll p)\n{\n    ll result = 1, y;\n    //printf(\"inverse of %lld is \", x);\n    while (x != 1)\n    {\n        y = (x+p)/x;\n        result *= y;\n        x = (x*y)%p;\n    }\n    //printf(\"%lld\\n\", result);\n    return result;\n}\n\nint main(int argc, char *argv)\n{\n    ll a, b, p, x, d = 1;\n    \n    ll n, m, y, z;\n    ll pdi;\n    ll count;\n    int i;\n    scanf(\"%lld %lld %lld %lld\", &a, &b, &p, &x);\n    a_pows[0] = 1;\n    a_pows[1] = a;\n    while (a != 1)\n    {\n        d++;\n        a = (a*a_pows[1]) % p;\n        a_pows[d] = a;\n    }\n    //printf(\"d: %lld\\n\", d);\n    count = 0;\n    pdi = inv(p-d, p);\n    for (m=0; m<d; m++)\n    {\n        n = (a_pows[d-m] * b) % p;\n        z = (pdi * (m-n)) % p;\n        if (z < 0)\n        {\n            z += p;\n        }\n\n        //printf(\"m:%lld n:%lld z:%lld count:%lld\\n\", m, n, z, count);\n        count += (x-m)/(p*d);\n        if (x%(p*d) >= z*d+m)\n        {\n            count += 1;\n        }\n    }\n    printf(\"%lld\\n\", count);\n    \n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9a0bd4cf4eec290ed9fb0d9ee8234bc1", "src_uid": "4b9f470e5889da29affae6376f6c9f6a", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "\n#include<stdio.h>\n#include<math.h>\n#include<string.h>\n#include<stdlib.h>\n#include<limits.h>\n#define SORT(a,n) qsort(a,n,sizeof(int),intcmp)\n#define s(n)                        scanf(\"%d\",&n)\n#define sc(n)                       scanf(\"%c\",&n)\n#define sl(n)                       scanf(\"%I64d\",&n)\n#define sf(n)                       scanf(\"%Lf\",&n)\n#define ss(n)                       scanf(\"%s\",n)\n#define fill(a,v)                   memset(a, v, sizeof a)\nint intcmp(const void *f,const void *s)\n{\n   return (*(int *)f-*(int *)s);\n}\nint gcd(int a,int b){ return ((b==0)?a:gcd(b,a%b));}\n\n#define MAX \n#define MODBY 1000000007\n#define NIL (1e-8)\n\ntypedef long long int lld;\ntypedef long double Lf;\n\nint i,j,n;\nLf x,y,z;\nint vix,viy,viz;\nint a,b;\nLf vx,vy,vz;\nLf tmin,t1;\nint cmp(Lf f,Lf s)\n{ return ((fabs(f-s)<NIL));}\nint main()\n{\n   s(a);s(b);sf(y);\n   s(vix);s(viy);s(viz);\n   vx=vix;vy=viy;vz=viz;\n   z=0;x=a/2.0;\n\n   //printf(\"ball is at %Lf,%Lf,%Lf\\n\",x,y,z);\n   //   while(!cmp(y,0)){\n   int cnt=18;\n   while(y>0){\n      tmin=INT_MAX;\n      if(vix){\n         t1=-x/vx;//x=0 plane\n         \n         if((t1>0)&&(t1<tmin)){\n            tmin=t1;\n         }\n         t1=-(x-a)/vx;\n         if((t1>0)&&(t1<tmin)){\n            tmin=t1;\n         }\n      }\n      if(viz){\n         t1=-z/vz;//z=0 plane\n         if((t1>0)&&(t1<tmin)){\n            tmin=t1;\n         }\n         t1=-(z-b)/vz;\n         if((t1>0)&&(t1<tmin)){\n            tmin=t1;\n         }\n      }\n      if(viy){\n         t1=-y/vy;//y=0 plane\n         if((t1>0)&&(t1<tmin)){\n            tmin=t1;\n         }\n      }\n      x=x+vx*tmin;\n      y=y+vy*tmin;\n      z=z+vz*tmin;\n   //   printf(\"ball is at %Lf,%Lf,%Lf\\n\",x,y,z);\n      if(vix!=0)\n         if((x==0)||(x==a)) vx*=-1;\n      if(viz!=0){\n         if((z==0)||(z==b)) vz*=-1;\n      }\n      //else break;\n   }\n   printf(\"%Lf %Lf\\n\",x,z);\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "26445c31c9c433f40edfc1ef1e2efd50", "src_uid": "84848b8bd92fd2834db1ee9cb0899cff", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "\n#include<stdio.h>\n#include<math.h>\n#include<string.h>\n#include<stdlib.h>\n#include<limits.h>\n#define SORT(a,n) qsort(a,n,sizeof(int),intcmp)\n#define s(n)                        scanf(\"%d\",&n)\n#define sc(n)                       scanf(\"%c\",&n)\n#define sl(n)                       scanf(\"%I64d\",&n)\n#define sf(n)                       scanf(\"%Lf\",&n)\n#define ss(n)                       scanf(\"%s\",n)\n#define fill(a,v)                   memset(a, v, sizeof a)\nint intcmp(const void *f,const void *s)\n{\n   return (*(int *)f-*(int *)s);\n}\nint gcd(int a,int b){ return ((b==0)?a:gcd(b,a%b));}\n\n#define MAX \n#define MODBY 1000000007\n#define NIL (1e-8)\n\ntypedef long long int lld;\ntypedef long double Lf;\n\nint i,j,n;\nLf x,y,z;\nint vix,viy,viz;\nint a,b;\nLf vx,vy,vz;\nLf tmin,t1;\nint cmp(Lf f,Lf s)\n{ return ((fabs(f-s)<NIL));}\nint main()\n{\n   s(a);s(b);sf(y);\n   s(vix);s(viy);s(viz);\n   vx=vix;vy=viy;vz=viz;\n   z=0;x=a/2.0;\n\n   //printf(\"ball is at %Lf,%Lf,%Lf\\n\",x,y,z);\n   //   while(!cmp(y,0)){\n   int cnt=18;\n   while(y>0){\n      tmin=INT_MAX;\n      if(vix){\n         t1=-x/vx;//x=0 plane\n         if((t1>NIL)&&(t1<tmin)){\n            tmin=t1;\n         }\n         t1=-(x-a)/vx;\n         if((t1>NIL)&&(t1<tmin)){\n            tmin=t1;\n         }\n      }\n      if(viz){\n         t1=-z/vz;//z=0 plane\n         if((t1>NIL)&&(t1<tmin)){\n            tmin=t1;\n         }\n         t1=-(z-b)/vz;\n         if((t1>NIL)&&(t1<tmin)){\n            tmin=t1;\n         }\n      }\n      if(viy){\n         t1=-y/vy;//y=0 plane\n         if((t1>NIL)&&(t1<tmin)){\n            tmin=t1;\n         }\n      }\n      x=x+vx*tmin;\n      y=y+vy*tmin;\n      z=z+vz*tmin;\n   //   printf(\"ball is at %Lf,%Lf,%Lf\\n\",x,y,z);\n      if(vix!=0)\n         if((x==0)||(x==a)) vx*=-1;\n      if(viz!=0){\n         if((z==0)||(z==b)) vz*=-1;\n      }\n      //else break;\n   }\n   printf(\"%Lf %Lf\\n\",x,z);\n   return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8ee687bc4de95a008183fd940bb3393b", "src_uid": "84848b8bd92fd2834db1ee9cb0899cff", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include <math.h>\n\nint main(){\n\t//freopen(\"in.txt\", \"r\", stdin);\n\tint a, b, m, speedx, speedy, speedz;\n\tscanf(\"%d%d%d%d%d%d\", &a, &b, &m, &speedx, &speedy, &speedz);\n\tdouble posx, posy=m, posz;\n\tdouble costtime = -posy / speedy;\n\tdouble xpass = fabs(speedx * costtime), zpass = fabs(speedz * costtime);\n\tif(speedz == 0)\n\t\tposz = 0;\n\telse{\n\t\tint round = zpass/b;\n\t\tposz = zpass - round*b;\n\t\tif(round%2==1)\n\t\t\tposz = b - posz;\n\t}\n\tif(speedx == 0)\n\t\tposx = 0.5 * a;\n\telse{\n\t\txpass += 0.5 * a;\n\t\tif(speedx < 0)\n\t\t\txpass += a;\n\t\tint round = xpass/a;\n\t\tposx = xpass - round*a;\n\t\tif(round%2==1)\n\t\t\tposx = a - posx;\n\t}\n\tprintf(\"%.8lf %.8lf\\n\", posx, posz);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9d8fcdb9f1faf727ed5d43b60122074e", "src_uid": "84848b8bd92fd2834db1ee9cb0899cff", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main ()\n{\n\tint a, b, m, vx, vy, vz, i;\n\tdouble x, y, z, t, T;\n\tscanf (\"%d%d%d\", &a, &b, &m);\n\tscanf (\"%d%d%d\", &vx, &vy, &vz);\n\tx = (double)a/2; y = m; z = 0;\n\twhile (y>0.000001)\n\t{\n\t\t//printf (\"%lf %lf %lf %d %d\\n\", x, y, z, vx, vz);\n\t\tT = -1*y/vy;\n\t\tt = -1*x/vx;\n\t\tif (t > 0.000001 && t < T)\n\t\t\tT = t;\n\t\tt = (a-x)/vx;\n\t\tif (t > 0 && t < T)\n\t\t\tT = t;\n\t\tt = -1*z/vz;\n\t\tif (t > 0 && t < T)\n\t\t\tT = t;\n\t\tt = (b-z)/vz;\n\t\tif (t > 0 && t < T)\n\t\t\tT = t;\n\t\tx += vx*T;\n\t\ty += vy*T;\n\t\tz += vz*T;\n\t\tif (x > -0.000001 && x < 0.000001)\n\t\t{\n\t\t\tvx *= -1;\n\t\t\tx = 0;\n\t\t}\n\t\tif (x-a > -0.000001 && x-a < 0.000001)\n\t\t{\n\t\t\tvx *= -1;\n\t\t\tx = a;\n\t\t}\n\t\tif (z > -0.000001 && z < 0.000001)\n\t\t{\n\t\t\tvz *= -1;\n\t\t\tz = 0;\n\t\t}\n\t\tif (z-b > -0.000001 && z-b < 0.000001)\n\t\t{\n\t\t\tvz *= -1;\n\t\t\tz = b;\n\t\t}\n\t}\n\tprintf (\"%lf %lf\\n\", x, z);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5cd5bce5e39849c3ea8378ea9fa3e3ab", "src_uid": "84848b8bd92fd2834db1ee9cb0899cff", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\nint main(){\n    double a, b, m, vx, vy, vz, x, z, t;\n    scanf(\"%lf%lf%lf%lf%lf%lf\", &a, &b, &m, &vx, &vy, &vz);\n    t = m / -vy;\n    x = a / 2 + vx * t;\n    z = vz * t;\n    if (x < 0)x = -x;\n    if ((int)(x / a) % 2)\n       x = a - (x - (int)(x / a) * a);\n    else x -= (int)(x / a) * a;\n    if ((int)(z / b) % 2)\n       z = b - (z - (int)(z / b) * b);\n    else z -= (int)(z / b) * b;\n    printf(\"%.7lf %.7lf\\n\", x, z);\n    scanf(\" \");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b99b6dc3702c1c0cb3586a864f2b3bfe", "src_uid": "84848b8bd92fd2834db1ee9cb0899cff", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "/*  AUTHOR:AKASH JAIN\n*   USERNAME:akash19jain    \n*   DATE:28/09/2019 \n*/\n/*#include<algorithm>\n#include <bits/stdc++.h>\nusing namespace std;*/\n\n#include<stdio.h>\n#include<math.h>\n#include<string.h>\n#include<stdlib.h>\n#include<stdbool.h>\n#define SC1(x)          scanf(\"%lld\",&x)\n#define SC2(x,y)        scanf(\"%lld%lld\",&x,&y)\n#define SC3(x,y,z)      scanf(\"%lld%lld%lld\",&x,&y,&z)\n#define SCS(x)          scanf(\"\\n%s\", x)\n#define PF1(x)          printf(\"%lld\\n\",x)\n#define PF2(x,y)        printf(\"%lld %lld\\n\",x,y)\n#define PF3(x,y,z)      printf(\"%lld %lld %lld\\n\",x,y,z)\n#define REP(i,n)        for(long long i=0;i<(n);i++)\n#define FOR(i,a,b)      for(long long i=(a);i<=(b);i++)\n#define FORD(i,a,b)     for(long long i=(a);i>=(b);i--)\n#define WHILE(n)        while(n--)\n#define MEM(a, b)       memset(a, (b), sizeof(a))\n#define ITOC(c)         ((char)(((int)'0')+c))\n#define MID(s,e)        (s+(e-s)/2)\n#define SZ(a)            strlen(a)\n#define MOD             1000000007\n#define MAX             10000000005\n#define MIN             -10000000005\n#define PI              3.1415926535897932384626433832795\n#define DEB(x)          printf(\"The value of \\\"%s\\\" is: %d\\n\",#x,x)\n#define CASES           ll t;SC1(t);while(t--)\n#define ABS(a)          ((a>0)?a:-(a))\n\nconst int INF = 1<<29;\ntypedef long long ll;\ntypedef unsigned long long ull;\n#define FILEIO(name) \\  freopen(name\".in\", \"r\", stdin); \\   freopen(name\".out\", \"w\", stdout);\nint cmp(const void * a,const void * b);\nlong long maxv(long long a,long long b);\nlong long minv(long long a,long long b);\nlong long gcd(long long u,long long v);\nll binpow(ll a,ll b,ll m)\n{\n    ll res=1;\n    a=a%m;\n    while(b>0)\n    {\n        if(b&1)\n            res=res*a%m;\n        a=a*a%m;\n        b>>=1;\n    }\n    return res;\n}\nint main()\n{\n\tll n,m;\n\tSC2(n,m);\n\tunsigned long long ans=0;\n\tn++;\n\tll x=2*n;\n\tunsigned long long z=binpow(x,m,MOD);\n\tz=z%MOD;\n\tunsigned long long z1=(n-m)%MOD;\n\tunsigned long long z2=(z*z1)%MOD;\n\tans=(z2/n);\n\tans=ans%MOD;\n\tprintf(\"%llu\\n\",ans);\n\n\treturn 0;\n}\n \n \n//qsort(arr,n,sizeof(arr[0]),cmp);\nint cmp (const void * a, const void * b)\n{\n    if( *(ll*)a - *(ll*)b < 0 ) return -1;\n    if( *(ll*)a - *(ll*)b > 0 ) return 1;\n        return 0;\n}\nlong long maxv(long long a,long long b)\n{\n    if(a>b) return a;\n        return b;\n}\nlong long minv(long long a,long long b)\n{\n    if(a<b) return a;\n        return b;\n}\nlong long gcd(long long u,long long v)\n{\n    if (v == 0) return u; \n       return gcd(v, u%v);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5e720838615f6b40381be6c9f668d622", "src_uid": "4f9711197e699c0fd0c4e9db8323cac7", "difficulty": 2700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nint main (void)\n{\n    int *a;\n    int b,i,k=100,x=0;\n    scanf(\"%d\",&b);\n    a = malloc(b*sizeof(int));\n    for(i=0;i<b;i++)\n    {\n        scanf(\"%d\",&a[i]);\n        if(a[i]<k)\n            k=a[i];\n    }\n    for(i=0;i<b;i++)\n        if(a[i]==k)\n            x++;\n    if(x>b/2)\n    printf(\"Bob\\n\");\n    else\n    printf(\"Alice\\n\");\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "dad9ff8e6f1c83ff6234e5f3a835cc13", "src_uid": "4b9cf82967aa8441e9af3db3101161e9", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nint main(){\n    int n, i;\n    scanf(\"%d\", &n);\n    int a[n], j;\n    for(i = 0; i < n; i++)\n        scanf(\"%d\", &a[i]);\n\n/*\n    for(i = 0; i < n - 1; i++){\n        for(j = i + 1; j < n; j++){\n            if(a[i] < a[j]){\n                int temp = a[i];\n                a[i] = a[j];\n                a[j] = temp;\n            }\n        }\n    }\n    if(a[0] == a[n/2])\n        printf(\"Bob\");\n    else\n        printf(\"Alice\");\n    return 0;\n}\n*/\n    int count = 0;\n    j = a[0];\n    for(i = 0; i < n; i++){\n        if(a[i] < j)\n            j = a[i];\n    }\n    for(i = 0; i < n; i++){\n        if(a[i] == j)\n            count++;\n    }\n    if(count <= (n/2))\n        printf(\"Alice\");\n    else\n        printf(\"Bob\");\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e88a87444e1046d2e6b6910157583fd1", "src_uid": "4b9cf82967aa8441e9af3db3101161e9", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>   \nint main(void) \n{\n    int *a;\n    int b,i,k=100,x=0;\n    scanf(\"%d\",&b);\n    a = malloc(b*sizeof(int));\n    for(i=0;i<b;i++)\n    {\n        scanf(\"%d\", &a[i]);\n        if(a[i]<k)k=a[i];\n    }\n    for(i=0; i<b; i++)\n        if(a[i]==k)x++;\n    if(x>b/2)printf(\"Bob\\n\");\n    else printf(\"Alice\\n\");\n\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "604312d71eae39a8c10e0cf1817ffbbe", "src_uid": "4b9cf82967aa8441e9af3db3101161e9", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main (void)\n{\n\tint pilas, i;\n\tint *numeros;\n\tscanf(\"%d\",&pilas);\n\tnumeros = (int*)malloc(pilas * sizeof(int));\n\tfor(i=0;i<pilas;i++)\n\t\tscanf(\"%d\",&numeros[i]);\n\t\n\ti=0;\n\twhile(1)\n\t{\n\t\tpilas=pilas/2;\n\t\ti++;\n\t\tif((pilas%2)!=0)\n\t\t{\n\t\t\tif((i%2)==0)\n\t\t\t{\n\t\t\t\tprintf(\"Alice\");\n\t\t\t\texit(0);\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\"Bob\");\n\t\t\t\texit(0);\n\t\t\t}\n\t\t}\t\n\t}\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "393fa2dacfd92ca7b39917759e1ea069", "src_uid": "4b9cf82967aa8441e9af3db3101161e9", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\n#define N\t24\n\nint compare(const void *a, const void *b) {\n\tint ia = *(int *) a;\n\tint ib = *(int *) b;\n\n\treturn ia - ib;\n}\n\nint main() {\n\tstatic int cc[N], ss[N], aa[1 << N - 1], dp[1 << N - 1];\n\tint n, m, i, j, k, b;\n\n\tscanf(\"%d\", &n);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d\", &cc[i]);\n\tqsort(cc, n, sizeof *cc, compare);\n\tk = 0;\n\twhile (k < n && cc[k] == 1)\n\t\tk++;\n\tm = n - k;\n\tfor (i = k; i < n; i++)\n\t\tss[i - k] = cc[i] - 1;\n\tfor (j = 1; j < m; j++)\n\t\tss[j] += ss[j - 1];\n\tn--;\n\tfor (b = 1; b < 1 << n; b++) {\n\t\ti = 0;\n\t\twhile ((b & 1 << i) == 0)\n\t\t\ti++;\n\t\taa[b] = aa[b ^ 1 << i] + cc[i];\n\t}\n\tmemset(dp, -1, (1 << n) * sizeof *dp), dp[0] = 0;\n\tfor (b = 0; b < 1 << n; b++) {\n\t\tj = dp[b];\n\t\tif (j == -1 || j == m)\n\t\t\tcontinue;\n\t\tfor (i = 0; i < n; i++)\n\t\t\tif ((b & 1 << i) == 0) {\n\t\t\t\tint b_ = b ^ 1 << i;\n\n\t\t\t\tif (aa[b_] < ss[j])\n\t\t\t\t\tdp[b_] = j;\n\t\t\t\telse if (aa[b_] == ss[j] && aa[b] > (j == 0 ? 0 : ss[j - 1]))\n\t\t\t\t\tdp[b_] = j + 1;\n\t\t\t}\n\t}\n\tprintf(dp[(1 << n) - 1] == m ? \"YES\\n\" : \"NO\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "674378664d05b525fa2d4663f893816c", "src_uid": "ed0925cfaee961a3ceebd13b3c96a15a", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "/* upsolve using zigzag */\n/* https://codeforces.com/blog/entry/73563 */\n#include <stdio.h>\n#include <string.h>\n\n#define N\t1024\n\nint query(int i) {\n\tif (i == -1) {\n\t\tprintf(\"R\\n\"), fflush(stdout);\n\t\treturn 0;\n\t} else {\n\t\tstatic char s[2];\n\n\t\tprintf(\"? %d\\n\", i + 1), fflush(stdout);\n\t\tscanf(\"%s\", s);\n\t\treturn s[0] == 'N';\n\t}\n}\n\nint main() {\n\tstatic char alive[N];\n\tint n, k, m, g, h, i, ans;\n\n\tscanf(\"%d%d\", &n, &k), m = n / k;\n\tmemset(alive, 1, n * sizeof *alive);\n\tfor (g = 0; g < m; g++) {\n\t\tquery(-1);\n\t\tfor (h = 0; h < m; h++) {\n\t\t\tint g_ = (g + (h % 2 == 0 ? h / 2 : m - (h + 1) / 2)) % m, l = g_ * k, r = (g_ + 1) * k;\n\n\t\t\tfor (i = l; i < r; i++)\n\t\t\t\tif (alive[i] && !query(i))\n\t\t\t\t\talive[i] = 0;\n\t\t}\n\t}\n\tans = 0;\n\tfor (i = 0; i < n; i++)\n\t\tif (alive[i])\n\t\t\tans++;\n\tprintf(\"! %d\\n\", ans), fflush(stdout);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f29288528d29ade25ab0b2a51a240059", "src_uid": "11ad68b4375456733526e74e72606d8d", "difficulty": 2800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define MAX 2000010\n#define MOD 1000000007\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nshort len[MAX];\nchar mu[MAX], flag[MAX];\nint prime[MAX], dp[MAX], sum[MAX], power[MAX], L[MAX], *divisors[MAX];\n\nint expo(int a, int b){\n    int res = 1;\n\n    while (b){\n        if (b & 1) res = (long long)res * a % MOD;\n        a = (long long)a * a % MOD;\n        b >>= 1;\n    }\n    return res;\n}\n\nvoid mobius(){\n    mu[1] = 1;\n    int i, j, k, p = 0;\n\n    for (i = 2; i < MAX; i++){\n        if (!flag[i]) mu[i] = -1, prime[p++] = i;\n        for (j = 0; j < p && (k = i * prime[j]) < MAX; j++){\n\n            flag[k] = true;\n            if (!(i % prime[j])){\n                mu[k] = 0;\n                break;\n            }\n            else mu[k] -= mu[i];\n        }\n    }\n    for (i = 1; i < MAX; i++) sum[i] = sum[i - 1] + mu[i];\n}\n\nvoid generate(){\n    mobius();\n    int i, j, k, c, d, x;\n\n    len[0] = len[1] = L[0] = L[1] = 1;\n    for (i = 4; i < MAX; i++, i++) len[i] = 2;\n\n    for (i = 3; (i * i) < MAX; i += 2){\n        if (!len[i]){\n            for (j = (i * i), d = i << 1; j < MAX; j += d){\n                if (!len[j]) len[j] = i;\n            }\n        }\n    }\n\n    for (i = 2; i < MAX; i++){\n        if (!len[i]) L[i] = i;\n        else{\n            L[i] = len[i];\n            x = L[i /len[i]];\n            if (x > L[i]) L[i] = x;\n        }\n    }\n\n    divisors[1] = (int *) malloc(sizeof(int));\n    divisors[1][0] = 1, len[1] = 1;\n\n    for (i = 2; i < MAX; i++){\n        c = 0, k = i;\n        while (k > 1 && L[k] == L[i]){\n            c++;\n            k /= L[k];\n        }\n\n        len[i] = (c + 1) * len[k];\n        divisors[i] = (int *) malloc(sizeof(int) * len[i]);\n\n        for (x = 1, j = 0, len[i] = 0; j <= c; j++, x *= L[i]){\n            for (d = 0; d < len[k]; d++){\n                divisors[i][len[i]++] = divisors[k][d] * x;\n            }\n        }\n    }\n}\n\nint count(int n, int m){\n    int z, y, x = m;\n    long long v, res = 0;\n\n    while (x >= 1){\n        y = m / x, z = m / (y + 1);\n        v = (long long)power[y] * (sum[x] - sum[z]);\n        x = z, res += v;\n    }\n\n    res = (res % MOD + MOD) % MOD;\n    return res;\n}\n\nint solve(int n, int k){\n    long long res = 0;\n    int i, j, v, m, x, y, z;\n    for (i = 0; i < MAX; i++) power[i] = expo(i, n);\n\n    dp[1] = count(n, 1);\n    for (m = 2; m <= k; m++){\n        res = dp[m - 1];\n        for (j = 0; j < len[m]; j++){\n            x = 0, y = 0, z = 0;\n            x = divisors[m][j], v = m / x;\n            y = power[v] * mu[x];\n            z = power[v - 1] * mu[x];\n            res = res + y - z;\n        }\n        dp[m] = ((res % MOD) + MOD) % MOD;\n    }\n\n    for (m = 1, res = 0; m <= k; m++) res += (m ^ dp[m]);\n    return res % MOD;\n}\n\nint main(){\n    generate();\n    int n, k, res;\n\n    while (scanf(\"%d %d\", &n, &k) != EOF){\n        printf(\"%d\\n\", solve(n, k));\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "52d0dbef68cf4d199fb78690c219e5c2", "src_uid": "122c08aa91c9a9d6a151ee6e3d0662fa", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\n#define K\t2000000\n#define MD\t1000000007\n\nlong long power(int a, int k) {\n\tlong long p;\n\n\tif (k == 0)\n\t\treturn 1;\n\tp = power(a, k >> 1);\n\tp = p * p % MD;\n\tif (k & 1)\n\t\tp = p * a % MD;\n\treturn p;\n}\n\nint main() {\n\tstatic int cc[K + 1], pp[K + 1], dd[K + 1];\n\tint n, k, a, a2, b, i, ans;\n\t\n\tscanf(\"%d%d\", &n, &k);\n\tfor (a = 2; a <= k; a++) {\n\t\tif (cc[a])\n\t\t\tcontinue;\n\t\tfor (b = a; b <= k; b += a)\n\t\t\tcc[b]++;\n\t}\n\tfor (a = 2; (a2 = a * a) <= k; a++)\n\t\tfor (b = a2; b <= k; b += a2)\n\t\t\tcc[b] = 0;\n\tfor (i = 1; i <= k; i++)\n\t\tpp[i] = power(i, n);\n\tfor (a = 2; a <= k; a++) {\n\t\tif (cc[a] == 0)\n\t\t\tcontinue;\n\t\tfor (i = 1; i * a <= k; i++) {\n\t\t\tint l = i * a, r = (i + 1) * a;\n\t\t\tint p = cc[a] % 2 == 0 ? pp[i] : -pp[i];\n\n\t\t\tdd[l] = (dd[l] + p) % MD;\n\t\t\tif (r <= k)\n\t\t\t\tdd[r] = (dd[r] - p) % MD;\n\t\t}\n\t}\n\tans = 0;\n\tfor (i = 1; i <= k; i++) {\n\t\tint x;\n\n\t\tdd[i] = (dd[i] + dd[i - 1]) % MD;\n\t\tx = (pp[i] + dd[i]) % MD;\n\t\tif (x < 0)\n\t\t\tx += MD;\n\t\tans = (ans + (x ^ i)) % MD;\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bd89fdca705c610a151a788c6657eab6", "src_uid": "122c08aa91c9a9d6a151ee6e3d0662fa", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define MAX 2000010\n#define MOD 1000000007\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nshort len[MAX];\nchar mu[MAX], flag[MAX];\nint prime[MAX], dp[MAX], sum[MAX], power[MAX], L[MAX], *divisors[MAX];\n\nint expo(int a, int b){\n    int res = 1;\n\n    while (b){\n        if (b & 1) res = (long long)res * a % MOD;\n        a = (long long)a * a % MOD;\n        b >>= 1;\n    }\n    return res;\n}\n\nvoid mobius(){\n    mu[1] = 1;\n    int i, j, k, p = 0;\n\n    for (i = 2; i < MAX; i++){\n        if (!flag[i]) mu[i] = -1, prime[p++] = i;\n        for (j = 0; j < p && (k = i * prime[j]) < MAX; j++){\n\n            flag[k] = true;\n            if (!(i % prime[j])){\n                mu[k] = 0;\n                break;\n            }\n            else mu[k] -= mu[i];\n        }\n    }\n    for (i = 1; i < MAX; i++) sum[i] = sum[i - 1] + mu[i];\n}\n\nvoid generate(){\n    mobius();\n    int i, j, k, c, d, x;\n\n    len[0] = len[1] = L[0] = L[1] = 1;\n    for (i = 4; i < MAX; i++, i++) len[i] = 2;\n\n    for (i = 3; (i * i) < MAX; i += 2){\n        if (!len[i]){\n            for (j = (i * i), d = i << 1; j < MAX; j += d){\n                if (!len[j]) len[j] = i;\n            }\n        }\n    }\n\n    for (i = 2; i < MAX; i++){\n        if (!len[i]) L[i] = i;\n        else{\n            L[i] = len[i];\n            x = L[i /len[i]];\n            if (x > L[i]) L[i] = x;\n        }\n    }\n\n    divisors[1] = (int *) malloc(sizeof(int));\n    divisors[1][0] = 1, len[1] = 1;\n\n    for (i = 2; i < MAX; i++){\n        c = 0, k = i;\n        while (k > 1 && L[k] == L[i]){\n            c++;\n            k /= L[k];\n        }\n\n        len[i] = (c + 1) * len[k];\n        divisors[i] = (int *) malloc(sizeof(int) * len[i]);\n\n        for (x = 1, j = 0, len[i] = 0; j <= c; j++, x *= L[i]){\n            for (d = 0; d < len[k]; d++){\n                divisors[i][len[i]++] = divisors[k][d] * x;\n            }\n        }\n    }\n}\n\nint count(int n, int m){\n    int z, y, x = m;\n    long long v, res = 0;\n\n    while (x >= 1){\n        y = m / x, z = m / (y + 1);\n        v = (long long)power[y] * (sum[x] - sum[z]);\n        x = z, res += v;\n    }\n\n    res = (res % MOD + MOD) % MOD;\n    return res;\n}\n\nint solve(int n, int k){\n    long long res = 0;\n    int i, j, v, m, x, y, z;\n    for (i = 0; i < MAX; i++) power[i] = expo(i, n);\n\n    dp[1] = count(n, 1);\n    for (m = 2; m <= k; m++){\n        res = dp[m - 1];\n        for (j = 0; j < len[m]; j++){\n            x = 0, y = 0, z = 0;\n            x = divisors[m][j], v = m / x;\n            y = power[v] * mu[x];\n            z = power[v - 1] * mu[x];\n            res = res + y - z;\n        }\n        dp[m] = ((res % MOD) + MOD) % MOD;\n    }\n\n    for (m = 1, res = 0; m <= k; m++) res += (m ^ dp[m]);\n    return res % MOD;\n}\n\nint main(){\n    generate();\n    int n, k, res;\n\n    while (scanf(\"%d %d\", &n, &k) != EOF){\n        printf(\"%d\\n\", solve(n, k));\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "85520d9c2b0566cfe6c97ffda67a56e8", "src_uid": "122c08aa91c9a9d6a151ee6e3d0662fa", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\n#define MIN(x,y) (((x)<(y))?(x):(y))\n\nstruct{\n  short com;\n  short flg[3];\n  short num;\n  short bef[199];\n}game[200]={{0}};\n\nint chk_clear(int k,int f);\n\nint main(void){\n  int i,j,k,in,n,room;\n  int count[3]={0},cleard[3]={0};\n\n  scanf(\"%d%*c\",&n);\n  for(i=0;i<n;i++) scanf(\"%hd%*c\",&game[i].com);\n  for(i=0;i<n;i++){\n    scanf(\"%hd\",&game[i].num);\n    for(j=0;j<game[i].num;j++){\n      scanf(\"%hd\",&game[i].bef[j]);\n    }\n  }\n\n  //puts(\"end set-data\");\n\n  for(i=0;i<3;i++){\n    room=i;\n    do{\n      room%=3;\n      room++;\n      for(j=0;j<n;j++){\n\tif(game[j].com!=room) continue;\n\tif(game[j].flg[i]==1) continue;\n\tin=chk_clear(j,i);\n\tif(in==1){\n\t  game[j].flg[i]=1;\n\t  cleard[i]++;\n\t  j=-1;\n\t}\n      }\n      //     printf(\"now cleard[%d]=%d@room=%d\\n\",i,cleard[i],room);\n    }while(cleard[i]<n && ++count[i]);\n    count[i]+=n;\n  }\n\n  printf(\"%d\\n\",MIN(count[0],MIN(count[1],count[2])));\n  return 0;\n}\n\nint chk_clear(int k,int f){\n  int i;\n  for(i=0;i<game[k].num;i++){\n    if(game[game[k].bef[i]-1].flg[f]==0) return 0;\n  }\n  return 1;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "65ec1d43e4f22e3ab36e3c71dfcdeca7", "src_uid": "be42e213ff43e303e475d77a9560367f", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<stdint.h>\n#include<inttypes.h>\n\ntypedef int64_t i64;\ntypedef int32_t i32;\n\nstatic void print_int(i64 n){if(n<0){putchar('-');n=-n;}if(n==0){putchar('0');return;}int s[20],len=0;while(n>0){s[len++]=n%10+'0';n/=10;}while(len>0){putchar(s[--len]);}}\nstatic i64 read_int(void){int prev='\\0';int c=getchar();while(!('0'<=c && c<='9')){prev=c;c=getchar();}i64 res=0;while('0'<=c && c<='9'){res=10*res+c-'0';c=getchar();}return prev=='-'?-res:res;}\n\nconst i32 mod = 1000000007;\n\ni32 inv (i32 a) {\n  i32 t = 1;\n  while (a > 1) {\n    t = (i64) t * (mod - mod / a) % mod;\n    a = mod % a;\n  }\n  return t;\n}\n\nvoid run (void) {\n  const i32 n = read_int();\n  i32 *factor = (i32 *) calloc (n + 1, sizeof (i32));\n  for (i32 i = 1; i <= n; ++i) {\n    factor[i] = i;\n  }\n  for (i32 i = 2; i * i <= n; ++i) {\n    if (factor[i] < i) continue;\n    for (i32 j = i * i; j <= n; j += i) {\n      factor[j] = i;\n    }\n  }\n  i32 *dp = (i32 *) calloc (n + 1, sizeof (i32));\n  dp[1] = 0;\n  for (i32 i = 2; i <= n; ++i) {\n    i32 f[64];\n    f[0] = 1;\n    i32 len = 1;\n    i32 t = i;\n    while (t > 1) {\n      i32 p = factor[t];\n      while (t % p == 0) {\n\tt /= p;\n      }\n      for (i32 j = 0; j < len; ++j) {\n\tf[j + len] = f[j] * p;\n      }\n      len *= 2;\n    }\n    if (f[len - 1] != i) {\n      dp[i] = dp[f[len - 1]];\n      continue;\n    }\n    i32 prob[64];\n    for (i32 j = 0; j < len; ++j) {\n      prob[j] = (i64) (n / f[j]) * inv(n) % mod;\n    }\n    for (i32 j = len - 1; j >= 0; --j) {\n      for (i32 k = j - 1; k >= 0; --k) {\n\tif ((j & k) == k) {\n\t  prob[k] = (prob[k] - prob[j] + mod) % mod;\n\t}\n      }\n    }\n    i32 local = 1;\n    for (i32 j = 0; j < len - 1; ++j) {\n      local = (local + (i64) prob[j] * dp[f[j]]) % mod;\n    }\n    dp[i] = (i64) local * inv((1 - prob[len - 1] + mod) % mod) % mod;\n  }\n  i32 ans = 1;\n  for (i32 i = 1; i <= n; ++i) {\n    ans = (ans + (i64)dp[i] * inv(n)) % mod;\n  }\n  print_int(ans);\n  puts(\"\");\n}\n\nint main (void) {\n  run ();\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e623b435fd622ab76a087a5f92e503bb", "src_uid": "ff810b16b6f41d57c1c8241ad960cba0", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint min(int a, int b)\n{\n    if (a < b) {\n        return a;\n    } else {\n        return b;\n    }\n}\n\nint dp[360361];\n\nint main()\n{\n    long long a, b, sum = 0;\n    int k, p = 1, i, j;\n    \n    scanf(\"%I64d %I64d %d\", &a, &b, &k);\n    \n    if (k >= 8) {\n        p *= 8;\n    } else if (k >= 4) {\n        p *= 4;\n    } else {\n        p *= 2;\n    }\n    \n    if (k >= 9) {\n        p *= 9;\n    } else if (k >= 3) {\n        p *= 3;\n    }\n    \n    if (k >= 5) p *= 5;\n    if (k >= 7) p *= 7;\n    if (k >= 11) p *= 11;\n    if (k >= 13) p *= 13;\n    \n    dp[0] = 0;\n    \n    for (i = 1; i <= p; i++) {\n        dp[i] = dp[i - 1] + 1;\n        \n        for (j = 2; j <= k; j++) {\n            int x = i % j;\n            \n            if (x > 0) dp[i] = min(dp[i - x] + 1, dp[i]);\n        }\n    }\n    \n    if (a / p > b / p) {\n        sum += dp[a % p];\n        a = a / p * p;\n        \n        sum += (a / p - b / p - 1) * dp[p];\n        a = b / p * p + p;\n    }\n    \n    for (i = 0; i <= p; i++) dp[i] = 1e9;\n    \n    if (a % p == 0) {\n        if (a == b) {\n            printf(\"%I64d\\n\", sum);\n            \n            return 0;\n        }\n        \n        dp[p] = 0;\n    } else {\n        dp[a % p] = 0;\n    }\n    \n    for (i = p; i >= 0; i--) {\n        if (dp[i] == 1e9) continue;\n        \n        if (i == b % p) {\n            printf(\"%I64d\\n\", sum + dp[i]);\n            \n            return 0;\n        }\n        \n        dp[i - 1] = min(dp[i - 1], dp[i] + 1);\n        \n        for (j = 2; j <= k; j++) {\n            int x = i % j;\n            \n            if (x > 0) dp[i - x] = min(dp[i - x], dp[i] + 1);\n        }\n    }\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0c5638ca3dd9ae1bdfd396f35f5cf3ea", "src_uid": "bd599d76c83cc1f30c1349ffb51b4273", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint min(int a, int b)\n{\n    if (a < b) {\n        return a;\n    } else {\n        return b;\n    }\n}\n\nint dp[360361];\n\nint main()\n{\n    long long a, b, sum = 0;\n    int k, p = 1, i, j;\n    \n    scanf(\"%I64d %I64d %d\", &a, &b, &k);\n    \n    if (k >= 8) {\n        p *= 8;\n    } else if (k >= 4) {\n        p *= 4;\n    } else {\n        p *= 2;\n    }\n    \n    if (k >= 9) {\n        p *= 9;\n    } else if (k >= 3) {\n        p *= 3;\n    }\n    \n    if (k >= 5) p *= 5;\n    if (k >= 7) p *= 7;\n    if (k >= 11) p *= 11;\n    if (k >= 13) p *= 13;\n    \n    dp[0] = 0;\n    \n    for (i = 1; i <= p; i++) {\n        dp[i] = dp[i - 1] + 1;\n        \n        for (j = 2; j <= k; j++) {\n            int x = i % j;\n            \n            if (x > 0) dp[i] = min(dp[i - x] + 1, dp[i]);\n        }\n    }\n    \n    if (a / p > b / p) {\n        sum += dp[a % p];\n        a = a / p * p;\n        \n        sum += (a / p - b / p - 1) * dp[p];\n        a = b / p * p + p;\n    }\n    \n    for (i = 0; i <= p; i++) dp[i] = 1e9;\n    \n    if (a % p == 0) {\n        if (a == b) {\n            printf(\"%I64d\\n\", sum);\n            \n            return 0;\n        }\n        \n        dp[p] = 0;\n    } else {\n        dp[a % p] = 0;\n    }\n    \n    for (i = p; i >= 0; i--) {\n        if (dp[i] == 1e9) continue;\n        \n        if (i == b % p) {\n            printf(\"%I64d\\n\", sum + dp[i]);\n            \n            return 0;\n        }\n        \n        dp[i - 1] = min(dp[i - 1], dp[i] + 1);\n        \n        for (j = 2; j <= k; j++) {\n            int x = i % j;\n            \n            if (x > 0) dp[i - x] = min(dp[i - x], dp[i] + 1);\n        }\n    }\n    \n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "62248443eb55e02a63e1b7c3980c5a3f", "src_uid": "bd599d76c83cc1f30c1349ffb51b4273", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include \"stdbool.h\"\n#include \"stdio.h\"\n#include \"stdint.h\"\n#include \"string.h\"\n#include \"ctype.h\"\n#include \"stdlib.h\"\n#include \"math.h\"\n\n#define PI 3.14159265358979323846264338327950288\n#define ll long long\n#define MOD 1000000007\n#define N 1000010\n#define MAX1 1000001\n#define rep(i,n) for (int i=0; i<n; i++)\n#define mul(a,b) ((a*b) % MOD)\n\nint max(int a,int b) {return a>b?a:b;}\nint min(int a,int b) {return a<b?a:b;}\nll minl(ll a,ll b) {return a<b?a:b;}\nll maxl(ll a,ll b) {return a>b?a:b;}\n\n\nll n, k, prime[N], v[N], m;\n\n// euler function\nll f(ll n) {\n    if (n == 1) return 1;\n    ll s = n;\n    for (int i=0; i<m && prime[i]*prime[i]<=n; i++) {\n        if (n % prime[i]) continue;\n        s = s/prime[i]*(prime[i]-1);\n        while (!(n % prime[i])) n /= prime[i];\n    }\n    if (n > 1) s = s/n*(n-1);\n    return s;\n}\n\nll F(ll k, ll n) {\n    if (!(k & 1)) k--;\n    if (k == 1) return f(n);\n    return f(F(k-1, n));\n}\n\n\nvoid primes(int n) {\n    for (int i = 2; i <= n; i++) {\n        if (!v[i]) {\n            v[i] = i;\n            prime[m++] = i;\n        }\n        for (int j = 0; j < m; j++) {\n            if (prime[j] > v[i] || prime[j]*i > n) break;\n            v[i * prime[j]] = prime[j];\n        }\n    }\n}\n\nint main() {\n    scanf(\"%lld %lld\", &n, &k);\n    primes((int) sqrtl(n)+1);\n    printf(\"%lld\\n\", F(k, n) % MOD);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f85e314db32e0916a738aa8f6a10549b", "src_uid": "0591ade5f9a69afcbecd80402493f975", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include \"stdbool.h\"\n#include \"stdio.h\"\n#include \"stdint.h\"\n#include \"string.h\"\n#include \"ctype.h\"\n#include \"stdlib.h\"\n#include \"math.h\"\n\n#define PI 3.14159265358979323846264338327950288\n#define ll long long\n#define MOD 1000000007\n#define N 1000010\n#define MAX1 1000001\n#define rep(i,n) for (int i=0; i<n; i++)\n#define mul(a,b) ((a*b) % MOD)\n\nint max(int a,int b) {return a>b?a:b;}\nint min(int a,int b) {return a<b?a:b;}\nll minl(ll a,ll b) {return a<b?a:b;}\nll maxl(ll a,ll b) {return a>b?a:b;}\n\n\nll n, k, prime[N], v[N], m;\n\n// euler function\nll f(ll n) {\n    if (n == 1) return 1;\n    ll s = n;\n    for (int i=0; i<m && prime[i]*prime[i]<=n; i++) {\n        if (n % prime[i]) continue;\n        s = s/prime[i]*(prime[i]-1);\n        while (n % prime[i]) n /= prime[i];\n    }\n    if (n > 1) s--;\n    return s;\n}\n\nll F(ll k, ll n) {\n    if (!(k & 1)) k--;\n    if (k == 1) return f(n);\n    return f(F(k-1, n));\n}\n\n\nvoid primes(int n) {\n    for (int i = 2; i <= n; i++) {\n        if (!v[i]) {\n            v[i] = i;\n            prime[m++] = i;\n        }\n        for (int j = 0; j < m; j++) {\n            if (prime[j] > v[i] || prime[j]*i > n) break;\n            v[i * prime[j]] = prime[j];\n        }\n    }\n}\n\nint main() {\n    scanf(\"%lld %lld\", &n, &k);\n    primes((int) sqrtl(n)+1);\n    printf(\"%lld\\n\", F(k, n) % MOD);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c6fa09b56995105b5d526131bb212816", "src_uid": "0591ade5f9a69afcbecd80402493f975", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include \"stdbool.h\"\n#include \"stdio.h\"\n#include \"stdint.h\"\n#include \"string.h\"\n#include \"ctype.h\"\n#include \"stdlib.h\"\n#include \"math.h\"\n\n#define PI 3.14159265358979323846264338327950288\n#define ll long long\n#define MOD 1000000007\n#define N 1000010\n#define MAX1 1000001\n#define rep(i,n) for (int i=0; i<n; i++)\n#define mul(a,b) ((a*b) % MOD)\n\nint max(int a,int b) {return a>b?a:b;}\nint min(int a,int b) {return a<b?a:b;}\nll minl(ll a,ll b) {return a<b?a:b;}\nll maxl(ll a,ll b) {return a>b?a:b;}\n\n\nll n, k, prime[N], v[N], m;\n\n// euler function\nll f(ll n) {\n    if (n == 1) return 1;\n    ll s = n;\n    for (int i=0; i<m && prime[i]*prime[i]<=n; i++) {\n        if (n % prime[i]) continue;\n        s = s/prime[i]*(prime[i]-1);\n        while (!(n % prime[i])) n /= prime[i];\n    }\n    if (n > 1) s = s/n*(n-1);\n    return s;\n}\n\nll F(ll k, ll n) {\n    ll s = n;\n    while ((k-=2)>0) s = f(s);\n    return s;\n}\n\n\nvoid primes(int n) {\n    for (int i = 2; i <= n; i++) {\n        if (!v[i]) {\n            v[i] = i;\n            prime[m++] = i;\n        }\n        for (int j = 0; j < m; j++) {\n            if (prime[j] > v[i] || prime[j]*i > n) break;\n            v[i * prime[j]] = prime[j];\n        }\n    }\n}\n\nint main() {\n    scanf(\"%lld %lld\", &n, &k);\n    primes((int) sqrtl(n)+1);\n    printf(\"%lld\\n\", F(k, n) % MOD);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7138a6b405d793c7f2c9949c31399338", "src_uid": "0591ade5f9a69afcbecd80402493f975", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MOD\t((long long) 1e9 + 7)\n\nlong long totient(long long n) {\n\tlong long p, x;\n\n\tx = n;\n\tfor (p = 2; p * p <= n; p++)\n\t\tif (n % p == 0) {\n\t\t\tx = x / p * (p - 1);\n\t\t\twhile (n % p == 0)\n\t\t\t\tn /= p;\n\t\t}\n\tif (n > 1)\n\t\tx = x / n * (n - 1);\n\treturn x;\n}\n\nint main() {\n\tlong long n, k;\n\n\tscanf(\"%lld%lld\", &n, &k);\n\tk = (k + 1) / 2;\n\twhile (n > 1 && k > 0) {\n\t\tn = totient(n);\n\t\tk--;\n\t}\n\tprintf(\"%lld\\n\", n % MOD);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "90b8fb45975e4a057795fb8c9a4e1e0f", "src_uid": "0591ade5f9a69afcbecd80402493f975", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include \"stdbool.h\"\n#include \"stdio.h\"\n#include \"stdint.h\"\n#include \"string.h\"\n#include \"ctype.h\"\n#include \"stdlib.h\"\n#include \"math.h\"\n\n#define PI 3.14159265358979323846264338327950288\n#define ll long long\n#define MOD 1000000007\n#define N 1000010\n#define MAX1 1000001\n#define rep(i,n) for (int i=0; i<n; i++)\n#define mul(a,b) ((a*b) % MOD)\n\nint max(int a,int b) {return a>b?a:b;}\nint min(int a,int b) {return a<b?a:b;}\nll minl(ll a,ll b) {return a<b?a:b;}\nll maxl(ll a,ll b) {return a>b?a:b;}\n\n\nll n, k, prime[N], v[N], m;\n\n// euler function\nll f(ll n) {\n    if (n == 1) return 1;\n    ll s = n;\n    for (int i=0; i<m && prime[i]*prime[i]<=n; i++) {\n        if (n % prime[i]) continue;\n        s = s/prime[i]*(prime[i]-1);\n        while (!(n % prime[i])) n /= prime[i];\n    }\n    if (n > 1) s = s/n*(n-1);\n    return s;\n}\n\nll F(ll k, ll n) {\n    ll s = n;\n    while (k>0 && s>1) s = f(s), k-=2;\n    return s;\n}\n\n\nvoid primes(int n) {\n    for (int i = 2; i <= n; i++) {\n        if (!v[i]) {\n            v[i] = i;\n            prime[m++] = i;\n        }\n        for (int j = 0; j < m; j++) {\n            if (prime[j] > v[i] || prime[j]*i > n) break;\n            v[i * prime[j]] = prime[j];\n        }\n    }\n}\n\nint main() {\n    scanf(\"%lld %lld\", &n, &k);\n    primes((int) sqrtl(n)+1);\n    printf(\"%lld\\n\", F(k, n) % MOD);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7774ecd95a99e3df86c9702566dade0d", "src_uid": "0591ade5f9a69afcbecd80402493f975", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <string.h>\r\n#include <sys/time.h>\r\n\r\n#define N\t35\r\n#define N_\t((N + 1) / 2)\r\n\r\nunsigned int X;\r\n\r\nvoid srand_() {\r\n\tstruct timeval tv;\r\n\r\n\tgettimeofday(&tv, NULL);\r\n\tX = tv.tv_sec ^ tv.tv_usec | 1;\r\n}\r\n\r\nint rand_() {\r\n\treturn (X *= 3) >> 1;\r\n}\r\n\r\nvoid multiply(char *aa, char *bb, char *md, int n) {\r\n\tstatic char cc[N * 2];\r\n\tint i, j;\r\n\r\n\tmemset(cc, 0, n * 2 * sizeof *cc);\r\n\tfor (i = 0; i < n; i++)\r\n\t\tfor (j = 0; j < n; j++)\r\n\t\t\tif (aa[i] && bb[j])\r\n\t\t\t\tcc[i + j] ^= 1;\r\n\tfor (i = n * 2 - 1; i >= n - 1; i--)\r\n\t\tif (cc[i])\r\n\t\t\tfor (j = 0; j < n; j++)\r\n\t\t\t\tif (md[j])\r\n\t\t\t\t\tcc[i - (n - 1 - j)] ^= 1;\r\n\tmemcpy(aa, cc, n * sizeof *cc);\r\n}\r\n\r\nchar ppp[1 << N_][N]; int n;\r\n\r\nint compare(int i, int j) {\r\n\tint c = memcmp(ppp[i], ppp[j], n * sizeof *ppp[j]);\r\n\r\n\treturn c ? c : i - j;\r\n}\r\n\r\nvoid sort(int *ii, int l, int r) {\r\n\twhile (l < r) {\r\n\t\tint i = l, j = l, k = r, i_ = ii[l + rand_() % (r - l)], tmp;\r\n\r\n\t\twhile (j < k) {\r\n\t\t\tint c = compare(ii[j], i_);\r\n\r\n\t\t\tif (c == 0)\r\n\t\t\t\tj++;\r\n\t\t\telse if (c < 0) {\r\n\t\t\t\ttmp = ii[i], ii[i] = ii[j], ii[j] = tmp;\r\n\t\t\t\ti++, j++;\r\n\t\t\t} else {\r\n\t\t\t\tk--;\r\n\t\t\t\ttmp = ii[j], ii[j] = ii[k], ii[k] = tmp;\r\n\t\t\t}\r\n\t\t}\r\n\t\tsort(ii, l, i);\r\n\t\tl = k;\r\n\t}\r\n}\r\n\r\nint search(int *ii, int m, char *pp) {\r\n\tint lower = -1, upper = m;\r\n\r\n\twhile (upper - lower > 1) {\r\n\t\tint i = (lower + upper) / 2;\r\n\r\n\t\tif (memcmp(ppp[ii[i]], pp, n * sizeof *ppp[ii[i]]) >= 0)\r\n\t\t\tupper = i;\r\n\t\telse\r\n\t\t\tlower = i;\r\n\t}\r\n\treturn upper < m && memcmp(pp, ppp[ii[upper]], n * sizeof *ppp[ii[upper]]) == 0 ? ii[upper] : -1;\r\n}\r\n\r\nint main() {\r\n\tstatic char cc_[N + 1], *cc, md[N], xx[N], vv[N], pp[N], pp_[N];\r\n\tstatic int rr[1 << N_];\r\n\tint n_, p, q, r, i, j, one;\r\n\tchar tmp;\r\n\r\n\tsrand_();\r\n\tscanf(\"%s\", cc_), n = strlen(cc_);\r\n\tp = 0;\r\n\twhile (p < n && cc_[p] == '0')\r\n\t\tp++;\r\n\tif (p == n) {\r\n\t\tprintf(\"-1\\n\");\r\n\t\treturn 0;\r\n\t}\r\n\tcc = cc_ + p, n -= p;\r\n\twhile (cc[n - 1] == '0')\r\n\t\tn--;\r\n\tif (n == 1) {\r\n\t\tprintf(\"%d %d\\n\", p + 1, p + 2);\r\n\t\treturn 0;\r\n\t}\r\n\tn_ = (n + 1) / 2;\r\n\tcc[n] = 0;\r\n\tfor (i = 0, j = n - 1; i < j; i++, j--)\r\n\t\ttmp = cc[i], cc[i] = cc[j], cc[j] = tmp;\r\n\tfor (i = 0; i < n; i++)\r\n\t\tmd[i] = cc[i] - '0';\r\n\tfor (j = 0; j < n - 1; j++)\r\n\t\tvv[j] = md[j + 1];\r\n\tmemset(pp, 0, n * sizeof *pp), pp[0] = 1;\r\n\tfor (r = 0; r < 1 << n_; r++) {\r\n\t\tmemcpy(ppp[r], pp, n * sizeof *pp);\r\n\t\tone = 1;\r\n\t\tfor (i = 0; i < n; i++)\r\n\t\t\tif ((pp[i] == 1) != (i == 0)) {\r\n\t\t\t\tone = 0;\r\n\t\t\t\tbreak;\r\n\t\t\t}\r\n\t\tif (one && r != 0) {\r\n\t\t\tprintf(\"%d %d\\n\", p + 1, p + 1 + r);\r\n\t\t\treturn 0;\r\n\t\t}\r\n\t\tmultiply(pp, vv, md, n);\r\n\t}\r\n\tfor (r = 0; r < 1 << n_; r++)\r\n\t\trr[r] = r;\r\n\tsort(rr, 0, 1 << n_);\r\n\tmemset(pp_, 0, n * sizeof *pp_), pp_[0] = 1;\r\n\txx[1] = 1, multiply(xx, pp_, md, n);\r\n\tfor (r = 0; r < 1 << n_; r++)\r\n\t\tmultiply(pp_, xx, md, n);\r\n\tmemset(pp, 0, n * sizeof *pp), pp[0] = 1;\r\n\tfor (q = 1; q <= 1 << n_; q++) {\r\n\t\tmultiply(pp, pp_, md, n);\r\n\t\tif ((r = search(rr, 1 << n_, pp)) != -1) {\r\n\t\t\tprintf(\"%d %lld\\n\", p + 1, p + 1 + ((long long) q << n_) + r);\r\n\t\t\treturn 0;\r\n\t\t}\r\n\t}\r\n\tprintf(\"-1\\n\");\r\n\treturn 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "27c4170e63e05bd1089791a6c2450ad6", "src_uid": "6bf798edef30db7d0ce2130e40084e6b", "difficulty": 2900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nenum {\n    M = 4,\n    D = 13,\n    MAX = M * D + 2\n};\n\ntypedef struct Card {\n    int d, m;\n} Card;\n\nCard a[MAX][MAX];\nchar n2m[M] = {'C', 'D', 'H', 'S'};\nchar n2d[D] = {'2', '3', '4', '5', '6', '7', '8', '9', 'T', 'J', 'Q', 'K', 'A'};\n\nint\nm2n(char m)\n{\n    switch (m) {\n    case 'C':\n        return 0;\n    case 'D':\n        return 1;\n    case 'H':\n        return 2;\n    case 'S':\n        return 3;\n    default:\n        return -1;\n    }\n}\n\nint\nd2n(char d)\n{\n    switch (d) {\n    case 'T':\n        return 8;\n    case 'J':\n        return 9;\n    case 'Q':\n        return 10;\n    case 'K':\n        return 11;\n    case 'A':\n        return 12;\n    default:\n        return d - '2';\n    }\n}\n\nint\ngood(int r, int c)\n{\n    int m = a[r][c].m;\n    int goodm = 1;\n    int ud[D] = {};\n    int goodd = 1;\n    int i, j;\n    for (i = r; i < r + 3; ++i) {\n        for (j = c; j < c + 3; ++j) {\n            goodm &= (a[i][j].m == m);\n            goodd &= (ud[a[i][j].d] == 0);\n            ud[a[i][j].d] = 1;\n        }\n    }\n    return goodm || goodd;\n}\n\nint\nmain(void)\n{\n    //freopen(\"input.txt\", \"r\", stdin);\n    //freopen(\"output.txt\", \"w\", stdout);\n\n    int n, m, i, j;\n    char s[MAX];\n    int j1r, j1c, j2r, j2c;\n    j1r = j1c = j2r = j2c = -1;\n    int used[M][D] = {};\n    scanf(\"%d %d\", &n, &m);\n    for (i = 0; i < n; ++i) {\n        for (j = 0; j < m; ++j) {\n            scanf(\"%s\", s);\n            a[i][j].d = d2n(s[0]);\n            a[i][j].m = m2n(s[1]);\n            if (s[1] == '1') {\n                j1r = i;\n                j1c = j;\n            } else if (s[1] == '2') {\n                j2r = i;\n                j2c = j;\n            } else {\n                used[a[i][j].m][a[i][j].d] = 1;\n            }\n        }\n    }\n\n    int m1, d1, m2, d2, r1, c1, r2, c2;\n    for (m1 = 0; m1 < M; ++m1) {\n        for (d1 = 0; d1 < D; ++d1) {\n            if (used[m1][d1]) continue;\n            used[m1][d1] = 1;\n            if (j1r > -1) {\n                a[j1r][j1c].d = d1;\n                a[j1r][j1c].m = m1;\n            }\n            for (m2 = 0; m2 < M; ++m2) {\n                for (d2 = 0; d2 < D; ++d2) {\n                    if (used[m2][d2]) continue;\n                    used[m2][d2] = 1;\n                    if (j2r > -1) {\n                        a[j2r][j2c].d = d2;\n                        a[j2r][j2c].m = m2;\n                    }\n\n                    for (r1 = 0; r1 < n - 2; ++r1) {\n                        for (c1 = 0; c1 < m - 2; ++c1) {\n                            for (r2 = r1; r2 < n - 2; ++r2) {\n                                for (c2 = 0; c2 < m - 2; ++c2) {\n                                    if ((r2 < r1 + 3) && ((c2 >= c1 && c2 < c1 + 3) || (c2 + 2 >= c1 && c2 + 2 < c1 + 3))) continue;\n                                    if (good(r1, c1) && good(r2, c2)) {\n                                        printf(\"Solution exists.\\n\");\n                                        if (j1r == -1 && j2r == -1) {\n                                            printf(\"There are no jokers.\\n\");\n                                        } else if (j1r == -1) {\n                                            printf(\"Replace J2 with %c%c.\\n\", n2d[d2], n2m[m2]);\n                                        } else if (j2r == -1) {\n                                            printf(\"Replace J1 with %c%c.\\n\", n2d[d1], n2m[m1]);\n                                        } else {\n                                            printf(\"Replace J1 with %c%C and J2 with %c%c.\\n\", n2d[d1], n2m[m1], n2d[d2], n2m[m2]);\n                                        }\n                                        printf(\"Put the first square to (%d, %d).\\n\", r1 + 1, c1 + 1);\n                                        printf(\"Put the second square to (%d, %d).\\n\", r2 + 1, c2 + 1);\n                                        return 0;\n                                    }\n                                }\n                            }\n                        }\n                    }\n                    used[m2][d2] = 0;\n                }\n            }\n            used[m1][d1] = 0;\n        }\n    }\n    printf(\"No solution.\\n\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "052498e8c6c11aa59c67a50bb1515d37", "src_uid": "b3f29d9c27cbfeadb96b6ac9ffd6bc8f", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "https://en.wikipedia.org/wiki/Dada\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "1fbc28a173bb11b3d1e5561806d1174c", "src_uid": "40002052843ca0357dbd3158b16d59f4", "difficulty": 2700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define N\t1000000\n\nint tt[N + 1];\n\nint compare(const void *a, const void *b) {\n\tint a_ = *(int *) a;\n\tint b_ = *(int *) b;\n\n\treturn tt[a_] != tt[b_] ? tt[a_] - tt[b_] : a_ - b_;\n}\n\nint main() {\n\tstatic int aa[N - 4];\n\tint n, k, a, b, i;\n\tlong long ans;\n\n\tscanf(\"%d%d\", &n, &k);\n\tif (k == 1) {\n\t\tprintf(\"3\\n\");\n\t\treturn 0;\n\t}\n\tfor (a = 2; a <= n; a++)\n\t\ttt[a] = a;\n\tfor (a = 2; a <= n; a++) {\n\t\tif (tt[a] != a)\n\t\t\tcontinue;\n\t\tfor (b = a; b <= n; b += a)\n\t\t\ttt[b] = tt[b] / a * (a - 1);\n\t}\n\tfor (a = 5; a <= n; a++)\n\t\taa[a - 5] = a;\n\tqsort(aa, n - 4, sizeof *aa, compare);\n\tans = 6;\n\tfor (i = 0; i < k - 2; i++)\n\t\tans += tt[aa[i]];\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f9784f4dd3e0793f8e8c479e569a5f9d", "src_uid": "c2f7012082c84d773c2f4b1858c17110", "difficulty": 2800.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#include<math.h>\n#define INF 200000000\n__int64 num[10],dp[500000][105];\n__int64 jie(__int64 p)\n{\n    __int64 re,i;\n    for(i=1,re=1;i<=p;i++)\n        re*=i;\n    return re;\n}\nint main()\n{\n    __int64 n[20],m,i,j,k,l,wei;\n    char s[20];\n    while(scanf(\"%s%I64d\",&s,&m)!=EOF)\n    {\n        wei=strlen(s);\n        memset(num,0,sizeof(num));\n        for(i=0;i<wei;i++)\n        {\n            n[i]=s[wei-1-i]-'0';\n            num[n[i]]++;\n        }\n        memset(dp,0,sizeof(dp));\n        for(i=0;i<wei;i++)\n        {\n            if(n[i]!=0)\n            dp[1<<i][n[i]%m]=1;\n        }\n        /*for(i=0;i<wei;i++)\n            printf(\"*%I64d %I64d %I64d\\n\",i,dp[1<<i][0],dp[1<<i][1]);*/\n        for(i=1;i<(1<<wei);i++)\n        {\n            for(j=0;j<wei;j++)\n            {\n                if((i|(1<<j))==i)\n                {\n                    for(k=0;k<m;k++)\n                        dp[i][(k*10+n[j])%m]+=dp[i-(1<<j)][k];\n                }\n            }\n        }\n        for(i=0;i<=9;i++)\n        {\n            dp[(1<<wei)-1][0]/=jie(num[i]);\n        }\n        printf(\"%I64d\\n\",dp[(1<<wei)-1][0]);\n        /*for(i=0;i<1<<wei;i++)\n        {\n            for(j=0;j<m;j++)\n                printf(\"%I64d \",dp[i][j]);\n            printf(\"\\n\");\n        }\n        for(i=0;i<wei;i++)\n            printf(\"%I64d \",n[i]);\n        printf(\"\\n\");*/\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4fd1ec396ff02bccc19c08cdafdeded1", "src_uid": "5eb90c23ffa3794fdddc5670c0373829", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\n__int64 d[1<<18][100];\nint main(int argc, char const *argv[])\n{\n    int m,i,j,l,k;  //l:n\u7684\u4f4d\u6570\n    int a[18],b[10];\n\n    __int64 n;\n    memset(d,0,sizeof(int)*100*(1<<18));\n    memset(b,0,sizeof(int)*10);\n    scanf(\"%I64d%d\",&n,&m);\n    for(l=0;n;++l)\n    {\n        a[l]=n%10;\n        n/=10;\n        if(a[l] && !b[a[l]])\n        {\n            d[1<<l][a[l]%m]=1;\n            b[a[l]]=1;\n        }   \n    }\n    \n\n\n    for(i=1;i< 1<<l;++i)\n        for(j=0;j<m;++j)\n        {\n            if(!d[i][j])\n                continue;\n            for(k=0;k<10;++k)\n                b[k]=0;\n            for(k=0;k<l;++k)\n                if(!(i&(1<<k))  && !b[a[k]] )\n                {\n                    d[i | (1<<k)][(j*10+(a[k]))%m]+=d[i][j];\n                    b[a[k]]=1;\n                }\n        }\n    printf(\"%I64d\\n\",d[(1<<l)-1][0]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "079c540c2723873964b1088e2052b22b", "src_uid": "5eb90c23ffa3794fdddc5670c0373829", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\n#include<math.h>\n#define INF 200000000\n__int64 num[10],dp[500000][105];\n__int64 jie(__int64 p)\n{\n    __int64 re,i;\n    for(i=1,re=1;i<=p;i++)\n        re*=i;\n    return re;\n}\nint main()\n{\n    __int64 n[20],m,i,j,k,l,wei;\n    char s[20];\n    while(scanf(\"%s%I64d\",&s,&m)!=EOF)\n    {\n        wei=strlen(s);\n        memset(num,0,sizeof(num));\n        for(i=0;i<wei;i++)\n        {\n            n[i]=s[wei-1-i]-'0';\n            num[n[i]]++;\n        }\n        memset(dp,0,sizeof(dp));\n        for(i=0;i<wei;i++)\n        {\n            if(n[i]!=0)\n            dp[1<<i][n[i]%m]=1;\n        }\n        /*for(i=0;i<wei;i++)\n            printf(\"*%I64d %I64d %I64d\\n\",i,dp[1<<i][0],dp[1<<i][1]);*/\n        for(i=1;i<(1<<wei);i++)\n        {\n            for(j=0;j<wei;j++)\n            {\n                if((i|(1<<j))==i)\n                {\n                    for(k=0;k<m;k++)\n                        dp[i][(k*10+n[j])%m]+=dp[i-(1<<j)][k];\n                }\n            }\n        }\n        for(i=0;i<9;i++)\n        {\n            dp[(1<<wei)-1][0]/=jie(num[i]);\n        }\n        printf(\"%I64d\\n\",dp[(1<<wei)-1][0]);\n        /*for(i=0;i<1<<wei;i++)\n        {\n            for(j=0;j<m;j++)\n                printf(\"%I64d \",dp[i][j]);\n            printf(\"\\n\");\n        }\n        for(i=0;i<wei;i++)\n            printf(\"%I64d \",n[i]);\n        printf(\"\\n\");*/\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9beabb3b075e8fb25c29ab19f919b748", "src_uid": "5eb90c23ffa3794fdddc5670c0373829", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<string.h>\nint d[1<<18][100];\nint main(int argc, char const *argv[])\n{\n\tint m,i,j,l,k;\t//l:n\u7684\u4f4d\u6570\n\tint a[18],b[10];\n\n\t__int64 n;\n\tmemset(d,0,sizeof(int)*100*(1<<18));\n\tmemset(b,0,sizeof(int)*10);\n\tscanf(\"%I64d%d\",&n,&m);\n\tfor(l=0;n;++l)\n\t{\n\t\ta[l]=n%10;\n\t\tn/=10;\n\t\tif(a[l] && !b[a[l]])\n\t\t{\n\t\t\td[1<<l][a[l]%m]=1;\n\t\t\tb[a[l]]=1;\n\t\t}\t\n\t}\n\t\n\n\n\tfor(i=1;i< 1<<l;++i)\n\t\tfor(j=0;j<m;++j)\n\t\t{\n\t\t\tif(!d[i][j])\n\t\t\t\tcontinue;\n\t\t\tfor(k=0;k<10;++k)\n\t\t\t\tb[k]=0;\n\t\t\tfor(k=0;k<l;++k)\n\t\t\t\tif(!(i&(1<<k))  && !b[a[k]] )\n\t\t\t\t{\n\t\t\t\t\td[i | (1<<k)][(j*10+(a[k]))%m]+=d[i][j];\n\t\t\t\t\tb[a[k]]=1;\n\t\t\t\t}\n\t\t}\n\tprintf(\"%d\\n\",d[(1<<l)-1][0]);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "79e3fd1b408042a65de398c976f0c120", "src_uid": "5eb90c23ffa3794fdddc5670c0373829", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n\nint num[11],val[11];\n\n__int64 dp[30000][100];\n\nint main()\n{\n    __int64 n;int m;\n    scanf(\"%I64d%d\",&n,&m);\n    while(n)\n    {\n        num[n%10]++;n/=10;\n    }\n    val[0] = 1;\n    for(int i=1;i<=10;i++)\n        val[i] = val[i-1]*(num[i-1]+1);\n    dp[0][0] = 1;\n    for(int i=0;i<val[10];i++)\n        for(int j=0;j<10;j++)\n        {\n            \n            if(j==0&&i<val[1])\n                continue;\n            if(i/val[j]%(num[j]+1)>=num[j])\n                continue;\n            for(int k=0;k<m;k++)\n                dp[i+val[j]][(10*k+j)%m]+=dp[i][k];\n        }\n    printf(\"%I64d\\n\",dp[val[10]-1][0]); \n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "4a1991d5696f012c7008bae0284e7575", "src_uid": "5eb90c23ffa3794fdddc5670c0373829", "difficulty": 2000.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main(){\n    int i, num, flag=0;\n    char str[11];\n    scanf(\"%s\", str);\n    num = strlen(str);\n    if(num == 1){\n        if(str[0] == '3' || str[0] == '7'){\n            printf(\"Yes\\n\");\n        }\n        else\n            printf(\"No\\n\");\n    }\n    else{\n        for(i=0; i<num/2; i++){\n            if(str[i] == '1' || str[i] == '2'){\n                printf(\"No\\n\");\n                flag = 1;\n                break;\n            }\n            if(str[i] == '0'){\n                if(str[num-i-1] != '8'){\n                    printf(\"No\\n\");\n                    flag = 1;\n                    break;\n                }\n            }\n            if(str[i] == '3'){\n                if(str[num-i-1] != '3'){\n                    printf(\"No\\n\");\n                    flag = 1;\n                    break;\n                }\n            }\n            if(str[i] == '4'){\n                if(str[num-i-1] != '6'){\n                    printf(\"No\\n\");\n                    flag = 1;\n                    break;\n                }\n            }\n            if(str[i] == '5'){\n                if(str[num-i-1] != '9'){\n                    printf(\"No\\n\");\n                    flag = 1;\n                    break;\n                }\n            }\n            if(str[i] == '6'){\n                if(str[num-i-1] != '4'){\n                    printf(\"No\\n\");\n                    flag = 1;\n                    break;\n                }\n            }\n            if(str[i] == '7'){\n                if(str[num-i-1] != '7'){\n                    printf(\"No\\n\");\n                    flag = 1;\n                    break;\n                }\n            }\n            if(str[i] == '8'){\n                if(str[num-i-1] != '0'){\n                    printf(\"No\\n\");\n                    flag = 1;\n                    break;\n                }\n            }\n            if(str[i] == '9'){\n                if(str[num-i-1] != '5'){\n                    printf(\"No\\n\");\n                    flag = 1;\n                    break;\n                }\n            }\n        }\n        if(num%2 == 1 && flag == 0){\n            if(str[num/2] == '0' || str[num/2] == '1' || str[num/2] == '2' || str[num/2] == '4' || str[num/2] == '5' || str[num/2] == '6' || str[num/2] == '8' || str[num/2] == '9'){\n                printf(\"No\\n\");\n                flag = 1;\n            }\n        }\n        if(flag == 0){\n            printf(\"Yes\\n\");\n        }\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f074a6dbe2d8e1897e7923614132b32a", "src_uid": "0f11f41cefd7cf43f498e511405426c3", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<string.h>\nvoid fun(char *);\nvoid fun(char *s)\n{\n    int n=strlen(s);\n    int i;\n    for(i=0;i<n;i++)\n    {\n        if(s[i]=='1'||s[i]=='2')\n        {\n            printf(\"No\\n\");\n            return;\n        }\n        if((s[i]=='3'&&s[n-i-1]!='3')||(s[i]=='7'&&s[n-i-1]!='7'))\n        {\n            printf(\"No\\n\");\n            return;\n        }\n        if((s[i]=='4'&&s[n-i-1]!='6')||(s[i]=='6'&&s[n-i-1]!='4'))\n        {\n            printf(\"No\\n\");\n            return;\n        }\n        if((s[i]=='5'&&s[n-i-1]!='9')||(s[i]=='9'&&s[n-i-1]!='5'))\n        {\n            printf(\"No\\n\");\n            return;\n        }\n        if((s[i]=='8'&&s[n-i-1]!='0')||(s[i]=='0'&&s[n-i-1]!='8'))\n        {\n            printf(\"No\\n\");\n            return;\n        }\n    }\n    printf(\"Yes\\n\");\n}\nint main()\n{\n    char a[11];\n    scanf(\"%s\",a);\n    fun(a);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "74384f7242b2bebd21303d8ff52d82d6", "src_uid": "0f11f41cefd7cf43f498e511405426c3", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdbool.h>\n#include <string.h>\n\nbool braille(char *a, int len)\n{\n    if(len == 1)\n    {\n        if(a[0] == '3' || a[0] == '7')\n            return true;\n        else\n            return false;\n    }\n\n\tint i = 0;\n\tint n = len - 1;\n\n\twhile(i < n)\n\t{\n        int old_i = i;\n\n        if((a[i] == '4' || a[i] == '6') && (a[i] == '6' || a[i] == '4'))\n            i++;\n\n        else if((a[i] == '5' || a[i] == '9') && (a[i] == '9' || a[i] == '5'))\n            i++;\n\n        else if((a[i] == '8' || a[i] == '0') && (a[i] == '0' || a[i] == '8'))\n            i++;\n\n        else if(a[i] == '3' && a[n] == '3')\n            i++;\n\n        else if(a[i] == '7' && a[n] == '7')\n            i++;\n\n        if(i == old_i)\n            return false;\n        else\n            n--;\n    }\n\n    return true;\n}\n\nint main()\n{\n    char num[10];\n    scanf(\"%s\", num);\n\n    braille(num, strlen(num))? printf(\"Yes\\n\") : printf(\"No\\n\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5d3de0e604bd7b2b64d06cefe9b2fe84", "src_uid": "0f11f41cefd7cf43f498e511405426c3", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdbool.h>\n#include <string.h>\n\nbool braille(char *a, int len)\n{\n    if(len == 1)\n    {\n        if(a[0] == '3' || a[0] == '7')\n            return true;\n        else\n            return false;\n    }\n\n\tint i = 0;\n\tint n = len - 1;\n\n\twhile(i < n)\n\t{\n        int old_i = i;\n\n        if((a[i] == '4' || a[i] == '6') && (a[i] == '6' || a[i] == '4'))\n            i++;\n\n        else if((a[i] == '5' || a[i] == '9') && (a[i] == '9' || a[i] == '5'))\n            i++;\n\n        else if((a[i] == '8' || a[i] == '0') && (a[i] == '0' || a[i] == '8'))\n            i++;\n\n        else if(a[i] == '3' && a[n] == '3')\n            i++;\n\n        else if(a[i] == '7' && a[n] == '7')\n            i++;\n\n        if(i == old_i)\n            return false;\n        else\n            n--;\n    }\n\n    if(a[i] == '1' || a[i] == '2')\n        return false;\n    else\n        return true;\n}\n\nint main()\n{\n    char num[10];\n    scanf(\"%s\", num);\n\n    braille(num, strlen(num))? printf(\"Yes\\n\") : printf(\"No\\n\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "165b95c64f22067a52d43768b34e31db", "src_uid": "0f11f41cefd7cf43f498e511405426c3", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdbool.h>\n#include <string.h>\n\nbool braille(char *a, int len)\n{\n\tint i = 0;\n\tint n = len - 1;\n\n\twhile(i < n)\n\t{\n        int old_i = i;\n\n        if((a[i] == '4' || a[i] == '6') && (a[i] == '6' || a[i] == '4'))\n            i++;\n\n        else if((a[i] == '5' || a[i] == '9') && (a[i] == '9' || a[i] == '5'))\n            i++;\n\n        else if((a[i] == '8' || a[i] == '0') && (a[i] == '0' || a[i] == '8'))\n            i++;\n\n        else if(a[i] == '3' && a[n] == '3')\n            i++;\n\n        else if(a[i] == '7' && a[n] == '7')\n            i++;\n\n        if(i == old_i)\n            return false;\n        else\n            n--;\n    }\n\n    return true;\n}\n\nint main()\n{\n    char num[10];\n    scanf(\"%s\", num);\n\n    braille(num, strlen(num))? printf(\"Yes\\n\") : printf(\"No\\n\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6d65207226f843a02fe775a30a2dd868", "src_uid": "0f11f41cefd7cf43f498e511405426c3", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define Maxm 100\n#define mod 1000000007\n\n__attribute__((always_inline)) __inline__\nvoid multiply(int m, int A[][Maxm], int B[][Maxm], int C[][Maxm]) {\n\tregister int i, j, k;\n\tfor (i = 0; i < m; i++) {\n\t\tfor (j = 0; j < m; j++) C[i][j] = 0;\n\t\tfor (k = 0; k < m; k++) for (j = 0; j < m; j++)\n\t\t\tC[i][j] = (C[i][j] + (long long)A[i][k] * B[k][j]) % mod;\n\t}\n}\n\nvoid power(int m, int A[][Maxm], int P[][Maxm], int T[][Maxm], long long k) {\n\tif (!k) {\n\t\tregister int i, j;\n\t\tfor (i = 0; i < m; i++)\n\t\t\tfor (j = 0; j < m; j++)\n\t\t\t\tP[i][j] = (i == j);\n\t}\n\telse if (k & 1) {\n\t\tpower(m, A, P, T, k / 2);\n\t\tmultiply(m, P, P, T), multiply(m, T, A, P);\n\t}\n\telse {\n\t\tpower(m, A, T, P, k / 2);\n\t\tmultiply(m, T, T, P);\n\t}\n}\n\nint main() {\n\tregister int i, j;\n\tstatic int A[Maxm][Maxm] = {};\n\tstatic int P[Maxm][Maxm] = {};\n\tstatic int T[Maxm][Maxm] = {};\n\tlong long n;\n\tint m, ans;\n\tscanf(\"%lld%d\", &n, &m);\n\tif (n < m) return puts(\"1\") & 0;\n\tfor (i = 0; i < m - 1; i++) A[i][i + 1] = 1;\n\tA[m - 1][0] = A[m - 1][m - 1] = 1;\n\tpower(m, A, P, T, n - m + 1);\n\tfor (ans = j = 0; j < m; j++)\n\t\tans = (ans + P[m - 1][j]) % mod;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5e752f4b654bf7901916af50933aa799", "src_uid": "e7b9eec21d950f5d963ff50619c6f119", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n\ntypedef long long int int64;\n\nstatic void printInt(int64 n){\n  if(n<0){putchar('-');n=-n;}\n  if(n==0){putchar('0');return;}\n  int s[20];int len=0;\n  while(n>0){s[len++]=n%10+'0';n/=10;}\n  while(len>0){putchar(s[--len]);}\n}\nstatic int64 readInt(void){\n  int prev='\\0';int c=getchar();\n  while(!('0'<=c && c<='9')){prev=c;c=getchar();}\n  int64 res=0;\n  while('0'<=c && c<='9'){res=10*res+c-'0';c=getchar();}\n  return prev=='-'?-res:res;\n}\n\n#define MAX(a,b) ((a)>(b)?(a):(b))\n#define MIN(a,b) ((a)<(b)?(a):(b))\n#define ABS(a) ((a)>(0)?(a):-(a))\n\n/*\na_k : k \u30de\u30b8\u30c3\u30af\u30b8\u30a7m\u306e\u69cb\u6210\u6570\na_k = 1 (k<=0)\na_1=2\na_n = a_{n-1} + a_(n-m)\n*/\n\nconst int mod=1000000007;\n\n#define POS(i,j) ((i)*m+(j))\n\nvoid matmul(int *c,int *a,int *b,int m){\n  static int *tmp=NULL;\n  if(tmp==NULL) tmp=calloc(m*m,sizeof(int));\n  memset(tmp,0,sizeof(int)*m*m);\n  int i,j,k;\n  for(i=0;i<m;i++){\n    for(k=0;k<m;k++){\n      for(j=0;j<m;j++){\n\ttmp[POS(i,j)]=(tmp[POS(i,j)]+(int64)a[POS(i,k)]*b[POS(k,j)])%mod;\n      }\n    }\n  }\n  for(i=0;i<m*m;i++) c[i]=tmp[i];\n}\n\nvoid run(void){\n  int64 n=readInt();\n  int m=readInt();\n  if(m>n){\n    printInt(1);\n    puts(\"\");\n    return;\n  }\n  n-=m-1;\n  int *t=(int *)calloc(m*m,sizeof(int));\n  int *s=(int *)calloc(m*m,sizeof(int));\n  int i;\n  for(i=0;i<m;i++) t[POS(i,i)]=1;\n  for(i=1;i<m;i++) s[POS(i,i-1)]=1;\n  s[POS(0,0)]=1;\n  s[POS(0,m-1)]=1;\n  while(n>0){\n    if(n&1) matmul(t,t,s,m);\n    matmul(s,s,s,m);\n    n>>=1;\n  }\n  int64 ans=0;\n  for(i=0;i<m;i++) ans=(ans+t[POS(0,i)])%mod;\n  printInt(ans);\n  puts(\"\");\n}\n\nint main(void){\n  run();\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "565118ddf764d2735cf4e37acf355c14", "src_uid": "e7b9eec21d950f5d963ff50619c6f119", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#define INF 1000000007\ntypedef long long LL;\n\nLL N;\nint M;\nLL **matrix_exp;\nLL **matrix;\n\nvoid multiply(LL ***a, LL **b){\n    LL **p = *a;\n    LL **c = (LL **)calloc(M, sizeof(LL *));\n    for(int i = 0; i < M; ++i)\n        c[i] = (LL *)calloc(M, sizeof(LL));\n    for(int i = 0; i < M; ++i)\n        for(int j = 0; j < M; ++j)\n            for(int k = 0; k < M; ++k)\n                c[i][j] = (c[i][j] + p[i][k] * b[k][j]) % INF;\n    for(int i = 0; i < M; ++i)\n        free(p[i]);\n    free(p);\n    *a = c;\n}\n\nint main(){\n    LL res = 0LL;\n    scanf(\"%I64d %d\", &N, &M);\n    matrix_exp = (LL **)calloc(M, sizeof(LL *));\n    matrix = (LL **)calloc(M, sizeof(LL *));\n    for(int i = 0; i < M; ++i){\n        matrix[i] = (LL *)calloc(M, sizeof(LL));\n        matrix_exp[i] = (LL *)calloc(M, sizeof(LL));\n        matrix_exp[i][i] = 1LL;\n    }\n    matrix[0][0] = matrix[M - 1][0] = 1LL;\n    for(int i = 0; i < M - 1; ++i)\n        matrix[i][i + 1] = 1LL;\n    while(N){\n        if(N & 1LL)\n            multiply(&matrix_exp, matrix);\n        multiply(&matrix, matrix);\n        N >>= 1;\n    }\n    for(int i = 0; i < M; ++i)\n        res = (res + matrix_exp[i][M - 1]) % INF;\n    printf(\"%I64d\", res);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d7eba1e8ad8aa65cbaed05ae25d79a2d", "src_uid": "e7b9eec21d950f5d963ff50619c6f119", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\n#define N\t500\n#define N_\t(1 << 9)\t/* N_ = pow2(ceil(log2(N))) */\n#define INF\t0x3f3f3f3f3f3f3f3fLL\n\nlong long min(long long a, long long b) { return a < b ? a : b; }\n\nint *oh[N][N], *ot[N][N], *ox[N][N], oo[N][N];\n\nvoid link(int i, int j, int h, int t, int x) {\n\tint o = oo[i][j]++;\n\n\tif (o >= 2 && (o & o - 1) == 0) {\n\t\toh[i][j] = (int *) realloc(oh[i][j], o * 2 * sizeof *oh[i][j]);\n\t\tot[i][j] = (int *) realloc(ot[i][j], o * 2 * sizeof *ot[i][j]);\n\t\tox[i][j] = (int *) realloc(ox[i][j], o * 2 * sizeof *ox[i][j]);\n\t}\n\toh[i][j][o] = h, ot[i][j][o] = t, ox[i][j][o] = x;\n}\n\nlong long *st_, *lz_; int h_, n_;\n\nvoid put(int i, long long x) {\n\tst_[i] += x;\n\tif (i < n_)\n\t\tlz_[i] += x;\n}\n\nvoid pus(int i) {\n\tif (lz_[i]) {\n\t\tput(i << 1, lz_[i]), put(i << 1 | 1, lz_[i]);\n\t\tlz_[i] = 0;\n\t}\n}\n\nvoid pul(int i) {\n\tif (!lz_[i])\n\t\tst_[i] = min(st_[i << 1], st_[i << 1 | 1]);\n}\n\nvoid push(int i) {\n\tint h;\n\n\tfor (h = h_; h > 0; h--)\n\t\tpus(i >> h);\n}\n\nvoid pull(int i) {\n\twhile (i > 1)\n\t\tpul(i >>= 1);\n}\n\nvoid update(int l, int r, long long x) {\n\tint l_ = l += n_, r_ = r += n_;\n\n\tpush(l_), push(r_);\n\tfor ( ; l <= r; l >>= 1, r >>= 1) {\n\t\tif ((l & 1) == 1)\n\t\t\tput(l++, x);\n\t\tif ((r & 1) == 0)\n\t\t\tput(r--, x);\n\t}\n\tpull(l_), pull(r_);\n}\n\nvoid update1(int i, long long x) {\n\tpush(i += n_);\n\tst_[i] = x;\n\tpull(i);\n}\n\nlong long query(int l, int r) {\n\tlong long x;\n\n\tpush(l += n_), push(r += n_);\n\tx = INF;\n\tfor ( ; l <= r; l >>= 1, r >>= 1) {\n\t\tif ((l & 1) == 1)\n\t\t\tx = min(x, st_[l++]);\n\t\tif ((r & 1) == 0)\n\t\t\tx = min(x, st_[r--]);\n\t}\n\treturn x;\n}\n\nint main() {\n\tstatic long long xx[N][N], st[N][N_ * 2], lz[N][N_ * 2], sti[N_ * 2], lzi[N_ * 2];\n\tint n, m, k, i, j;\n\n\tscanf(\"%d%d%d\", &n, &m, &k);\n\tfor (i = 0; i < n; i++)\n\t\tfor (j = 0; j < m; j++) {\n\t\t\toh[i][j] = (int *) malloc(2 * sizeof *oh[i][j]);\n\t\t\tot[i][j] = (int *) malloc(2 * sizeof *ot[i][j]);\n\t\t\tox[i][j] = (int *) malloc(2 * sizeof *ox[i][j]);\n\t\t}\n\twhile (k--) {\n\t\tint d, t, x;\n\t\tint meet1, meet2, meet3, meet4;\n\n\t\tscanf(\"%d%d%d%d%d\", &i, &j, &d, &t, &x);\n\t\tmeet1 = meet2 = meet3 = meet4 = 0;\n\t\tif (i + j >= t && (i + j) % 4 == t % 4)\n\t\t\txx[i][j] += x, meet1 = 1;\n\t\tif (i + j >= t && (i + j) % 4 == (t + 1) % 4)\n\t\t\txx[i + d][j - d] += x, meet2 = 1;\n\t\tif (i + j + d >= t && (i + j + d) % 4 == (t + 2) % 4)\n\t\t\txx[i + d][j] += x, meet3 = 1;\n\t\tif (i + j + d >= t && (i + j + d) % 4 == (t + 3) % 4)\n\t\t\txx[i][j + d] += x, meet4 = 1;\n\t\tif (meet1 && meet3)\n\t\t\tlink(i + d, j, i, 0, x);\n\t\tif (meet1 && meet4)\n\t\t\tlink(i, j + d, j, 1, x);\n\t\tif (meet2 && meet3)\n\t\t\tlink(i + d, j, j - d, 1, x);\n\t}\n\th_ = 0;\n\twhile (1 << h_ < n || 1 << h_ < m)\n\t\th_++;\n\tn_ = 1 << h_;\n\tfor (i = 0; i < n; i++) {\n\t\tmemset(sti, 0, n_ * 2 * sizeof *sti);\n\t\tmemset(lzi, 0, n_ * 2 * sizeof *lzi);\n\t\tfor (j = 0; j < m; j++) {\n\t\t\tint o;\n\t\t\tlong long x;\n\n\t\t\tfor (o = 0; o < oo[i][j]; o++) {\n\t\t\t\tint h = oh[i][j][o], t = ot[i][j][o], x = ox[i][j][o];\n\n\t\t\t\tif (t == 0)\n\t\t\t\t\tst_ = st[j], lz_ = lz[j], update(0, h, -x);\n\t\t\t\telse\n\t\t\t\t\tst_ = sti, lz_ = lzi, update(0, h, -x);\n\t\t\t}\n\t\t\tif (i == 0 && j == 0)\n\t\t\t\tx = 0;\n\t\t\telse {\n\t\t\t\tx = INF;\n\t\t\t\tif (i > 0)\n\t\t\t\t\tst_ = st[j], lz_ = lz[j], x = min(x, query(0, i - 1));\n\t\t\t\tif (j > 0)\n\t\t\t\t\tst_ = sti, lz_ = lzi, x = min(x, query(0, j - 1));\n\t\t\t}\n\t\t\tst_ = st[j], lz_ = lz[j], update1(i, x), update(0, i, xx[i][j]);\n\t\t\tst_ = sti, lz_ = lzi, update1(j, x), update(0, j, xx[i][j]);\n\t\t}\n\t}\n\tst_ = st[m - 1], lz_ = lz[m - 1];\n\tprintf(\"%lld\\n\", query(n - 1, n - 1));\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "58b637ae39610c37bd148f79fd014be5", "src_uid": "b11cb0c2bf23bf4b4e6f6af61af9c290", "difficulty": 2600.0}
{"lang": "GNU C11", "source_code": "/* upsolve with Dukkha */\n#include <stdio.h>\n\n#define N\t100\n#define S\t5000\n#define MD\t998244353\n\nint ch[S + N][N];\n\nvoid init(int n, int k) {\n\tint i, j;\n\n\tch[0][0] = 1;\n\tfor (i = 1; i < n; i++) {\n\t\tch[i][0] = 1;\n\t\tfor (j = 1; j < k; j++)\n\t\t\tch[i][j] = (ch[i - 1][j - 1] + ch[i - 1][j]) % MD;\n\t}\n}\n\nlong long power(long long a, int k) {\n\tlong long p;\n\n\tif (k == 0)\n\t\treturn 1;\n\tp = power(a, k / 2);\n\tp = p * p % MD;\n\tif (k % 2 == 1)\n\t\tp = p * a % MD;\n\treturn p;\n}\n\nlong long inv(long long a) {\n\treturn power(a, MD - 2);\n}\n\nint main() {\n\t/* dp[a][b]: b balls into a urns of size r - 1 */\n\tstatic int dp[1 + N][1 + S];\n\t/* dq[a][b]: dp[a][b] + dp[a][b - 1] + ... + dp[a][b - (r - 1)] */\n\tstatic int dq[1 + N][1 + S];\n\tint n, s, r, a, b, k, p, q;\n\n\tscanf(\"%d%d%d\", &n, &s, &r);\n\tinit(s + n, n);\n\tfor (a = 0; a <= n; a++) {\n\t\tint sum;\n\n\t\tif (a == 0)\n\t\t\tdp[0][0] = 1;\n\t\telse\n\t\t\tfor (b = 0; b <= s; b++)\n\t\t\t\tdp[a][b] = dq[a - 1][b];\n\t\tsum = 0;\n\t\tfor (b = 0; b <= s; b++) {\n\t\t\tsum = (sum + dp[a][b]) % MD;\n\t\t\tif (b >= r)\n\t\t\t\tsum = (sum - dp[a][b - r] + MD) % MD;\n\t\t\tdq[a][b] = sum;\n\t\t}\n\t}\n\tp = 0;\n\tfor (k = 1; k <= n && k * r <= s; k++)\n\t\tfor (b = 0; b + k * r <= s; b++)\n\t\t\tp = (p + (long long) dp[n - k][b] * ch[s - b - k * r + k - 1][k - 1] % MD * ch[n - 1][k - 1] % MD * inv(k)) % MD;\n\tq = ch[s - r + n - 1][n - 1];\n\tprintf(\"%lld\\n\", p * inv(q) % MD);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c4263d48e547db0b7e96005ddf55eb79", "src_uid": "609195ef4a970c62a8210dafe118580e", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nint buy[12][105],v[12][105],money[105],sale[12][105],space[105];\nint main()\n{\n    int n,m,s,max=0,x,y,t,k,sum,total,i,j;\n    char str[105];\n    scanf(\"%d%d%d\",&n,&m,&s);\n    for(i=0;i<n;i++)\n    {\n        scanf(\"%s\",str);\n        for(j=0;j<m;j++)\n            scanf(\"%d%d%d\",&buy[i][j],&sale[i][j],&v[i][j]);\n    }\n    for(i=0;i<n;i++)\n    {\n        for(j=0;j<n;j++)\n        {\n            if(i==j)\n                continue;\n            sum=0;total=s;\n            for(k=0;k<m;k++)\n            {\n                if(sale[j][k]>buy[i][k])\n                    money[k]=sale[j][k]-buy[i][k];\n                else\n                    money[k]=0;\n                space[k]=v[i][k];\n            }\n            for(x=0;x<m-1;x++)\n                for(y=0;y<m-x-1;y++)\n                {\n                    if(money[y]<money[y+1])\n                    {\n                        t=money[y];money[y]=money[y+1];money[y+1]=t;\n                        t=space[y];space[y]=space[y+1];space[y+1]=t;\n                    }\n                }\n            for(k=0;k<m;k++)\n            {\n                if(space[k]>=total)\n                {\n                    sum+=money[k]*total;\n                    break;\n                }\n                else\n                {\n                    sum+=money[k]*space[k];\n                    total-=space[k];\n                }\n            }\n            if(sum>max)\n                max=sum;\n        }\n    }\n    printf(\"%d\\n\",max);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a739bbe4a20e7ae017e205dabd262e93", "src_uid": "7419c4268a9815282fadca6581f28ec1", "difficulty": 1200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\nint x[12][110][5];\nstruct sub{\n    int p,n;\n}y[110];\nint cmp(const void *a,const void *b)\n{\n    return ((struct sub *)a)->p-((struct sub *)b)->p;\n}\nint main()\n{\n    int res=0,sum;\n    int i,j,t,U;\n    int n,m,k,K,L;\n    char s[20];\n    scanf(\"%d %d %d\",&n,&m,&K);\n    for(t=1;t<=n;t++)\n    {\n        scanf(\"%s\",s);\n        for(i=1;i<=m;i++)\n            for(j=1;j<=3;j++)\n                scanf(\"%d\",&x[t][i][j]);\n    }\n    res=0;\n    for(i=1;i<=n;i++)\n        for(j=1;j<=n;j++)\n        {\n            if(j==i)\n                continue;\n            for(k=1;k<=m;k++)\n            {\n                y[k].n=x[i][k][3];\n                y[k].p=x[j][k][2]-x[i][k][1];\n            }\n            qsort(y+1,m,sizeof(y[0]),cmp);\n            t=m;\n            k=K;\n            sum=0;\n            while(k>0&&t>0&&y[t].p>0)\n            {\n                if(y[t].n<=k)\n                {\n                    k-=y[t].n;\n                    sum+=y[t].n*y[t].p;\n                }\n                else if(y[t].n>k)\n                {\n                    sum+=y[t].p*k;\n                    k=0;\n                }\n                t--;\n            }\n            if(sum>res)\n                res=sum;\n        }\n    printf(\"%d\\n\",res);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "97b0101361a893ea69b7917a318aafaa", "src_uid": "7419c4268a9815282fadca6581f28ec1", "difficulty": 1200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <sys/time.h>\n\n#define N\t400000\n#define INF\t0x3f3f3f3f3f3f3f3fLL\n\nlong long min(long long a, long long b) { return a < b ? a : b; }\nlong long max(long long a, long long b) { return a > b ? a : b; }\n\nvoid srand_() {\n\tstruct timeval tv;\n\n\tgettimeofday(&tv, NULL);\n\tsrand(tv.tv_sec ^ tv.tv_usec);\n}\n\nint rand_(int n) {\n\treturn (rand() * 76543LL + rand()) % n;\n}\n\nstruct V {\n\tlong long x, y;\n} vv[N + 1];\n\nint compare(const void *a, const void *b) {\n\tstruct V *u = (struct V *) a;\n\tstruct V *v = (struct V *) b;\n\n\treturn u->x == v->x ? 0 : u->x < v->x ? -1 : 1;\n}\n\nvoid sort(struct V *vv, int n) {\n\tint i;\n\n\tfor (i = 0; i < n; i++) {\n\t\tint j = rand_(i + 1);\n\t\tstruct V tmp;\n\n\t\ttmp = vv[i], vv[i] = vv[j], vv[j] = tmp;\n\t}\n\tqsort(vv, n, sizeof *vv, compare);\n}\n\nint main() {\n\tint t;\n\n\tsrand_();\n\tscanf(\"%d\", &t);\n\twhile (t--) {\n\t\tstatic long long gg[N + 1];\n\t\tlong long len, k, lower, upper, lmax, rmin, y, ans;\n\t\tint n, m, i;\n\n\t\tscanf(\"%lld%d%lld\", &len, &n, &k);\n\t\tfor (i = 0; i < n; i++)\n\t\t\tscanf(\"%lld\", &gg[i]);\n\t\tgg[n] = len;\n\t\tfor (i = n; i >= 1; i--)\n\t\t\tgg[i] -= gg[i - 1];\n\t\tlower = 1;\n\t\tupper = len + 1;\n\t\tfor (i = 0; i <= n; i++)\n\t\t\tupper = min(upper, gg[i] + 1);\n\t\twhile (upper - lower > 1) {\n\t\t\tlong long l = (lower + upper) / 2, k_;\n\n\t\t\tk_ = k;\n\t\t\tfor (i = 0; i <= n; i++)\n\t\t\t\tif ((k_ -= gg[i] / l - 1) <= 0)\n\t\t\t\t\tbreak;\n\t\t\tif (k_ <= 0)\n\t\t\t\tlower = l;\n\t\t\telse\n\t\t\t\tupper = l;\n\t\t}\n\t\tlmax = lower;\n\t\tlower = 0, upper = len;\n\t\twhile (upper - lower > 1) {\n\t\t\tlong long r = (lower + upper) / 2, k_;\n\n\t\t\tk_ = k;\n\t\t\tfor (i = 0; i <= n; i++)\n\t\t\t\tif ((k_ -= (gg[i] + r - 1) / r - 1) < 0)\n\t\t\t\t\tbreak;\n\t\t\tif (k_ >= 0)\n\t\t\t\tupper = r;\n\t\t\telse\n\t\t\t\tlower = r;\n\t\t}\n\t\trmin = upper;\n\t\t/* lmax <= rmin must hold */\n\t\tm = 0;\n\t\tfor (i = 0; i <= n; i++) {\n\t\t\tlong long kmin = (gg[i] + rmin - 1) / rmin - 1;\n\t\t\tlong long kmax = gg[i] / lmax - 1;\n\n\t\t\tif (kmin > kmax) {\t/* kmin == kmax + 1 */\n\t\t\t\tstruct V *v = &vv[m++];\n\n\t\t\t\tv->x = lmax - gg[i] / (kmin + 1);\n\t\t\t\tv->y = (gg[i] + kmax) / (kmax + 1) - rmin;\n\t\t\t}\n\t\t}\n\t\tsort(vv, m);\n\t\tans = INF;\n\t\ty = 0;\n\t\tfor (i = m - 1; i >= 0; i--) {\n\t\t\tans = min(ans, rmin - lmax + vv[i].x + y);\n\t\t\ty = max(y, vv[i].y);\n\t\t}\n\t\tans = min(ans, rmin - lmax + y);\n\t\tprintf(\"%lld\\n\", ans);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ea1a480b094ceef3d8925a676d231ba9", "src_uid": "37d912c36aedea1b8f8e78a849062d90", "difficulty": 3300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdint.h>\n#include<inttypes.h>\n\nint64_t gcd(int64_t a, int64_t b){\n\treturn b==0? a: gcd(b, a%b);\n}\n\nint main(){\n\tint n, k, a, b, i, stp[4];\n\tint64_t min_t, max_t, dis, t, l;\n\n\tmin_t = INT64_MAX, max_t = INT64_MIN;\n\n\tscanf(\"%d%d%d%d\", &n, &k, &a, &b);\n\tdis = (int64_t)n * k;\n\tstp[0] = a-b, stp[1] = b-a, stp[2] = a+b, stp[3] = k-a-b;\n\n\tfor(i = 0; i < 4; i++){\n\t\tfor(l = stp[i]; l <= dis; l += k){\n\t\t\tif(l <= 0)\n\t\t\t\tcontinue;\n\t\t\tt = dis / gcd(dis, l);\n\t\t\tmin_t = min_t<t? min_t: t;\n\t\t\tmax_t = max_t>t? max_t: t;\n\t\t}\n\t}\n\n\tprintf(\"%\" PRIi64 \" %\" PRIi64 \"\\n\", min_t, max_t);\n\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9c461d09581a7284f3b7fad7992a628e", "src_uid": "5bb4adff1b332f43144047955eefba0c", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<stdint.h>\n#include<inttypes.h>\n\ntypedef int64_t i64;\ntypedef int32_t i32;\n\nstatic void print_int(i64 n){if(n<0){putchar('-');n=-n;}if(n==0){putchar('0');return;}int s[20],len=0;while(n>0){s[len++]=n%10+'0';n/=10;}while(len>0){putchar(s[--len]);}}\nstatic i64 read_int(void){int prev='\\0';int c=getchar();while(!('0'<=c && c<='9')){prev=c;c=getchar();}i64 res=0;while('0'<=c && c<='9'){res=10*res+c-'0';c=getchar();}return prev=='-'?-res:res;}\n\n#define MAX(a,b) ((a)>(b)?(a):(b))\n#define MIN(a,b) ((a)<(b)?(a):(b))\n\ni64 gcd (i64 a, i64 b) {\n  i64 r = a % b;\n  while (r > 0) {\n    a = b;\n    b = r;\n    r = a % b;\n  }\n  return b;\n}\n\nvoid run (void) {\n  const i32 n = read_int();\n  const i32 k = read_int();\n  const i32 a = read_int();\n  const i32 b = read_int();\n  const i64 m = (i64) n * k;\n  i64 min = (i64) n * k;\n  i64 max = 1;\n  for (i32 i = 0; i < 4; ++i) {\n    const i32 s = i >= 2 ? a : (k - a) % k;\n    for (i32 j = 0; j < 4; ++j) {\n      i32 t = (j & 1) ? (k - b) % k : b;\n      if (t <= s) {\n\ti64 d = m - (s - t);\n\ti64 v = m / gcd (d, m);\n\tmin = MIN(min, v);\n\tmax = MAX(max, v);\n\tt += k;\n      }\n      for (i64 l = t; l < m; l += k) {\n\ti64 d = l - s;\n\ti64 v = m / gcd (d, m);\n\tmin = MIN(min, v);\n\tmax = MAX(max, v);\n      }\n    }\n  }\n  print_int (min);\n  putchar(' ');\n  print_int (max);\n  puts(\"\");\n}\n\nint main (void) {\n  run ();\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c541418cb68b7affb2d92121a576eddd", "src_uid": "5bb4adff1b332f43144047955eefba0c", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <limits.h>\n\n#define FOR(i, a, b) for (i = (a); i < (b); ++i)\n#define REP(i, n) FOR(i, 0, n)\n\nint cmpfunc (const void * a, const void * b){\n\t//qsort(values, 5, sizeof(int), cmpfunc);\n\treturn ( *(int*)a - *(int*)b );\n}\n\nlong min(long a,long b){\n\treturn a < b ? a : b;\n}\n\nlong max(long a,long b){\n\treturn a > b ? a : b;\n}\n// long ncr(int n, int k) \n// { \n//     long C[k+1]; \n//     memset(C, 0, sizeof(C)); \n//   \tint i;\n//   \tint j;\n//     C[0] = 1;  // nC0 is 1 \n  \n//     for (i = 1; i <= n; i++) \n//     { \n//         // Compute next row of pascal triangle using \n//         // the previous row \n//         for ( j = min(i, k); j > 0; j--) \n//             C[j] = C[j] + C[j-1]; \n//     } \n//     return C[k]; \n// } \n\nvoid solve(int t){\n\tint n,k;\n\tscanf(\"%d%d\",&n,&k);\n\tint a[n];\n\tint i,j;\n\tfor(i = 0;i < n;i++){\n\t\tscanf(\"%d\",&a[i]);\n\t}\n\n\t// printf(\"Case #%d: %ld\\n\",t,count);\t\n}\n\nlong gcd(long a , long b)\n{\n   if(b==0) return a;\n   a%=b;\n   return gcd(b,a);\n}\n\nint main(){\n\tint n,k,a,b;\n\tscanf(\"%d%d\",&n,&k);\n\tscanf(\"%d%d\",&a,&b);\n\tint i,j;\n\tlong maximum = LONG_MIN, minimum = LONG_MAX;\n\tlong l = a-b;\n\tlong total = (long)n*k;\n\twhile(l <= total){\n\t\tif(l <= 0){\n\t\t\tl += k;\n\t\t\tcontinue;\n\t\t}\n\t\tlong g = ((long)n*k)/gcd((long)n*k,(long)l);\n\n\t\tmaximum = max(g,maximum);\n\t\tminimum = min(g,minimum);\n\t\tl += k;\n\t}\n\n\tl = a+b;\n\twhile(l <= total){\n\t\tif(l <= 0){\n\t\t\tl += k;\n\t\t\tcontinue;\n\t\t}\n\t\tlong g = ((long)n*k)/gcd((long)n*k,(long)l);\n\n\t\tmaximum = max(g,maximum);\n\t\tminimum = min(g,minimum);\n\t\tl += k;\n\t}\n\n\tl = k-a+b;\n\twhile(l <= total){\n\t\tif(l <= 0){\n\t\t\tl += k;\n\t\t\tcontinue;\n\t\t}\n\t\tlong g = ((long)n*k)/gcd((long)n*k,(long)l);\n\n\t\tmaximum = max(g,maximum);\n\t\tminimum = min(g,minimum);\n\t\tl += k;\n\t}\n\n\tl = k-a-b;\n\twhile(l <= total){\n\t\tif(l <= 0){\n\t\t\tl += k;\n\t\t\tcontinue;\n\t\t}\n\t\tlong g = ((long)n*k)/gcd((long)n*k,(long)l);\n\n\t\tmaximum = max(g,maximum);\n\t\tminimum = min(g,minimum);\n\t\tl += k;\n\t}\n\n\tprintf(\"%I64d %I64d\\n\",minimum,maximum);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "7cd4dde2e73ef5ee837f05be4ff8ffe0", "src_uid": "5bb4adff1b332f43144047955eefba0c", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <limits.h>\n\n#define FOR(i, a, b) for (i = (a); i < (b); ++i)\n#define REP(i, n) FOR(i, 0, n)\n\nint cmpfunc (const void * a, const void * b){\n\t//qsort(values, 5, sizeof(int), cmpfunc);\n\treturn ( *(int*)a - *(int*)b );\n}\n\nlong min(long a,long b){\n\treturn a < b ? a : b;\n}\n\nlong max(long a,long b){\n\treturn a > b ? a : b;\n}\n// long ncr(int n, int k) \n// { \n//     long C[k+1]; \n//     memset(C, 0, sizeof(C)); \n//   \tint i;\n//   \tint j;\n//     C[0] = 1;  // nC0 is 1 \n  \n//     for (i = 1; i <= n; i++) \n//     { \n//         // Compute next row of pascal triangle using \n//         // the previous row \n//         for ( j = min(i, k); j > 0; j--) \n//             C[j] = C[j] + C[j-1]; \n//     } \n//     return C[k]; \n// } \n\nvoid solve(int t){\n\tint n,k;\n\tscanf(\"%d%d\",&n,&k);\n\tint a[n];\n\tint i,j;\n\tfor(i = 0;i < n;i++){\n\t\tscanf(\"%d\",&a[i]);\n\t}\n\n\t// printf(\"Case #%d: %ld\\n\",t,count);\t\n}\n\nlong gcd(long a , long b)\n{\n   if(b==0) return a;\n   a%=b;\n   return gcd(b,a);\n}\n\nint main(){\n\tint n,k,a,b;\n\tscanf(\"%d%d\",&n,&k);\n\tscanf(\"%d%d\",&a,&b);\n\tint i,j;\n\tlong maximum = LONG_MIN, minimum = LONG_MAX;\n\tlong l = a-b;\n\tlong total = (long)n*k;\n\twhile(l <= total){\n\t\tif(l <= 0){\n\t\t\tl += k;\n\t\t\tcontinue;\n\t\t}\n\t\tlong g = ((long)n*k)/gcd((long)n*k,(long)l);\n\n\t\tmaximum = max(g,maximum);\n\t\tminimum = min(g,minimum);\n\t\tl += k;\n\t}\n\n\tl = a+b;\n\twhile(l <= total){\n\t\tif(l <= 0){\n\t\t\tl += k;\n\t\t\tcontinue;\n\t\t}\n\t\tlong g = ((long)n*k)/gcd((long)n*k,(long)l);\n\n\t\tmaximum = max(g,maximum);\n\t\tminimum = min(g,minimum);\n\t\tl += k;\n\t}\n\n\tl = k-a+b;\n\twhile(l <= total){\n\t\tif(l <= 0){\n\t\t\tl += k;\n\t\t\tcontinue;\n\t\t}\n\t\tlong g = ((long)n*k)/gcd((long)n*k,(long)l);\n\n\t\tmaximum = max(g,maximum);\n\t\tminimum = min(g,minimum);\n\t\tl += k;\n\t}\n\n\tl = k-a-b;\n\twhile(l <= total){\n\t\tif(l <= 0){\n\t\t\tl += k;\n\t\t\tcontinue;\n\t\t}\n\t\tlong g = ((long)n*k)/gcd((long)n*k,(long)l);\n\n\t\tmaximum = max(g,maximum);\n\t\tminimum = min(g,minimum);\n\t\tl += k;\n\t}\n\n\tprintf(\"%ld %ld\\n\",minimum,maximum);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6db0bdd62a2569a69479e7324e70f4b2", "src_uid": "5bb4adff1b332f43144047955eefba0c", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <limits.h>\n\n#define FOR(i, a, b) for (i = (a); i < (b); ++i)\n#define REP(i, n) FOR(i, 0, n)\n\nint cmpfunc (const void * a, const void * b){\n\t//qsort(values, 5, sizeof(int), cmpfunc);\n\treturn ( *(int*)a - *(int*)b );\n}\n\nlong long min(long long a,long long b){\n\treturn a < b ? a : b;\n}\n\nlong long max(long long a,long long b){\n\treturn a > b ? a : b;\n}\n// long long ncr(int n, int k) \n// { \n//     long long C[k+1]; \n//     memset(C, 0, sizeof(C)); \n//   \tint i;\n//   \tint j;\n//     C[0] = 1;  // nC0 is 1 \n  \n//     for (i = 1; i <= n; i++) \n//     { \n//         // Compute next row of pascal triangle using \n//         // the previous row \n//         for ( j = min(i, k); j > 0; j--) \n//             C[j] = C[j] + C[j-1]; \n//     } \n//     return C[k]; \n// } \n\nvoid solve(int t){\n\tint n,k;\n\tscanf(\"%d%d\",&n,&k);\n\tint a[n];\n\tint i,j;\n\tfor(i = 0;i < n;i++){\n\t\tscanf(\"%d\",&a[i]);\n\t}\n\n\t// printf(\"Case #%d: %ld\\n\",t,count);\t\n}\n\nlong long gcd(long long a , long long b)\n{\n   if(b==0) return a;\n   a%=b;\n   return gcd(b,a);\n}\n\nint main(){\n\tint n,k,a,b;\n\tscanf(\"%d%d\",&n,&k);\n\tscanf(\"%d%d\",&a,&b);\n\tint i,j;\n\tlong long maximum = LONG long_MIN, minimum = LONG long_MAX;\n\tlong long l = a-b;\n\tlong long total = (long long)n*k;\n\twhile(l <= total){\n\t\tif(l <= 0){\n\t\t\tl += k;\n\t\t\tcontinue;\n\t\t}\n\t\tlong long g = ((long long)n*k)/gcd((long long)n*k,(long long)l);\n\n\t\tmaximum = max(g,maximum);\n\t\tminimum = min(g,minimum);\n\t\tl += k;\n\t}\n\n\tl = a+b;\n\twhile(l <= total){\n\t\tif(l <= 0){\n\t\t\tl += k;\n\t\t\tcontinue;\n\t\t}\n\t\tlong long g = ((long long)n*k)/gcd((long long)n*k,(long long)l);\n\n\t\tmaximum = max(g,maximum);\n\t\tminimum = min(g,minimum);\n\t\tl += k;\n\t}\n\n\tl = k-a+b;\n\twhile(l <= total){\n\t\tif(l <= 0){\n\t\t\tl += k;\n\t\t\tcontinue;\n\t\t}\n\t\tlong long g = ((long long)n*k)/gcd((long long)n*k,(long long)l);\n\n\t\tmaximum = max(g,maximum);\n\t\tminimum = min(g,minimum);\n\t\tl += k;\n\t}\n\n\tl = k-a-b;\n\twhile(l <= total){\n\t\tif(l <= 0){\n\t\t\tl += k;\n\t\t\tcontinue;\n\t\t}\n\t\tlong long g = ((long long)n*k)/gcd((long long)n*k,(long long)l);\n\n\t\tmaximum = max(g,maximum);\n\t\tminimum = min(g,minimum);\n\t\tl += k;\n\t}\n\n\tprintf(\"%I64d %I64d\\n\",minimum,maximum);\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "561d98eeb73563c8eaa4130c93473d0b", "src_uid": "5bb4adff1b332f43144047955eefba0c", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include <string.h>\n#include <stdio.h>\n#include <ctype.h>\n//#include <DEBUG.h>\n#define LL long long\n#define uLL long long\n#define uL unsigned int\n#define iL unsigned int\n#define max(a,b) (((a)>(b))?(a):(b))\n#define min(a,b) (((a)<(b))?(a):(b))\n\nLL CP=(LL)998244353;\nLL inv[0x100000];\nLL num1[0x100000],num2[0x100000];\nuL exgcd(uL a,uL c)\n{\n    static uL gcd;\n    uL k;\n    uLL x;\n    if (a==0)\n    {\n        gcd=c;\n        return 1;\n    }\n    else\n    {\n        k=c%a;\n        if (k==0)\n        {\n            gcd=a;\n            return 1;\n        }\n        else\n        {\n            x=exgcd(a%k,k);\n        }\n    }\n    return (x*c-c/a*gcd)/k;\n}\nvoid ini1(long n,LL P)\n{\n    long i;\n    inv[1]=1;\n    for (i=2;i<=n;i++)\n    {\n        inv[i]=(uLL)inv[P%i]*(P-P/i)%P;\n    }\n}\nstatic inline LL madd(LL a,LL b)\n{\n    a+=b;\n    a-=(a>CP)?CP:0;\n    return a;\n}\nstatic inline LL msub(LL a,LL b)\n{\n    a-=b;\n    a+=(a<0)?CP:0;\n    return a;\n}\nstatic inline LL MR(LL a,LL b)\n{\n    return (a*b)%CP;\n}\nuLL mexp(uLL a,uLL b)\n{\n    register uLL t;\n    for (t=1;b;b=b>>1)\n    {\n        if (b&1) {t=MR(a,t);}\n        a=MR(a,a);\n    }\n    return t;\n}\nstatic inline uLL PolynomialPower(uLL *pol,uLL psize,uLL ex,uLL N,uLL *ans)\n{\n    uLL i,j,a,b,c,d;\n    psize=(psize>N)?N:psize;\n    uLL temp[psize],ans2[N+1];\n    ans[1]=mexp(pol[1],ex);\n    for (i=1;i<psize;i++) {temp[i-1]=pol[i+1]*i%CP;}\n    c=ex%CP;d=exgcd(pol[1],CP);\n    for (i=2;i<=N;i++)\n    {\n        a=0;b=min(psize-1,i-1);\n        for (j=0;j<b;j++)\n        {\n            a=madd(a,MR(ans[i-j-1],temp[j]));\n        }\n        a=MR(a,c);\n        b=min(psize,i-1);\n        for (j=2;j<=b;j++)\n        {\n            a=msub(a,MR(ans2[i-j],pol[j]));\n        }\n        ans[i]=MR(a,MR(d,inv[i-1]));\n        ans2[i-1]=MR(i-1,ans[i]);\n    }\n}\nint main()\n{\n    //freopen(\"in.in\",\"r\",stdin);\n    LL i,j,k,a,b,c,n,ans;\n    ini1(1000013,CP);\n    scanf(\"%lld%lld\",&n,&k);\n    *num1=10;\n    memset(num1+1,0,sizeof(*num1)*(*num1+1));\n    for (i=1;i<=k;i++)\n    {\n        scanf(\"%lld\",&a);\n        num1[a+1]=1;\n    }\n    //printf(\"%lld\\n\",n/2);\n    //print(num1,20);\n    for (i=1;i<=10;i++) {if (num1[i]>0) {break;}}\n    PolynomialPower(num1+i-1,10-i+1,n/2,1000001,num2);\n    //print(num2,20);\n    ans=0;\n    for (i=1;i<=1000000;i++)\n    {\n        a=num2[i]*num2[i]%CP;\n        ans=madd(a,ans);\n    }\n    printf(\"%lld\\n\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e691b8b0a027c9911eba026cb4357a3e", "src_uid": "279f1f7d250a4be6406c6c7bfc818bbf", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\n#define MD\t998244353\n#define N_\t(1 << 20)\t/* N_ = pow2(ceil(log2(N * 9 + 1))) */\n\nlong long ww[21], ww_[21];\n\nlong long power(int a, int k) {\n\tlong long p;\n\n\tif (k == 0)\n\t\treturn 1;\n\tp = power(a, k / 2);\n\tp = p * p % MD;\n\tif (k % 2)\n\t\tp = p * a % MD;\n\treturn p;\n}\n\nvoid init() {\n\tint h;\n\n\tfor (h = 0; h <= 20; h++) {\n\t\tww[h] = power(3, (MD - 1) >> h);\n\t\tww_[h] = power(3, MD - 1 - ((MD - 1) >> h));\n\t}\n}\n\nvoid ntt(int *aa, int n, int inverse) {\n\tint h, i, j, b, l, r, u, v, tmp;\n\tlong long w, w_;\n\n\tfor (i = 1, j = 0; i < n; i++) {\n\t\tb = n;\n\t\tdo\n\t\t\tj ^= b >>= 1;\n\t\twhile ((j & b) == 0);\n\t\tif (i < j)\n\t\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\t}\n\tfor (h = 0; (b = 1 << h) < n; h++) {\n\t\tw_ = inverse ? ww_[h + 1] : ww[h + 1];\n\t\tfor (i = 0; i < n; i += b * 2) {\n\t\t\tw = 1;\n\t\t\tfor (j = 0; j < b; j++) {\n\t\t\t\tl = i + j, r = l + b;\n\t\t\t\tu = aa[l], v = aa[r] * w % MD;\n\t\t\t\tif ((aa[l] = u + v) >= MD)\n\t\t\t\t\taa[l] -= MD;\n\t\t\t\tif ((aa[r] = u - v) < 0)\n\t\t\t\t\taa[r] += MD;\n\t\t\t\tw = w * w_ % MD;\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main() {\n\tstatic int aa[N_];\n\tint n, n_, k, i;\n\tlong long v, a, ans;\n\n\tinit();\n\tscanf(\"%d%d\", &n, &k), n /= 2;\n\tn_ = 1;\n\twhile (n_ < n * 9 + 1)\n\t\tn_ *= 2;\n\twhile (k--) {\n\t\tint d;\n\n\t\tscanf(\"%d\", &d);\n\t\taa[d] = 1;\n\t}\n\tntt(aa, n_, 0);\n\tfor (i = 0; i < n_; i++)\n\t\taa[i] = power(aa[i], n);\n\tntt(aa, n_, 1);\n\tv = power(n_, MD - 2);\n\tfor (i = 0; i < n_; i++)\n\t\taa[i] = aa[i] * v % MD;\n\tans = 0;\n\tfor (i = 0; i <= n * 9; i++) {\n\t\ta = aa[i];\n\t\tans = (ans + a * a) % MD;\n\t}\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e7cc3b29c53650d78c0068e18087a710", "src_uid": "279f1f7d250a4be6406c6c7bfc818bbf", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\n#define N\t75\n#define M\t20\t/* sum_{i=1}^M bitcount(i) <= N */\n#define MD\t1000000007\n\nint main() {\n\tstatic char cc[N + 1];\n\tstatic int dp[N + 1][1 << M];\n\tint n, h, i, i_, j, b, b_, a, ans, x;\n\n\tscanf(\"%d%s\", &n, cc);\n\tfor (i = 0; i <= n; i++)\n\t\tdp[i][0] = 1;\n\tans = 0;\n\tfor (i = 0, j = 0; i <= n; i++) {\n\t\tfor (h = 1; h < M; h++)\n\t\t\tans = (ans + dp[i][(1 << h) - 1]) % MD;\n\t\tif (j < i)\n\t\t\tj = i;\n\t\twhile (j < n && cc[j] != '1')\n\t\t\tj++;\n\t\tif (j == n)\n\t\t\tcontinue;\n\t\tfor (b = 0; b < 1 << M; b++) {\n\t\t\tx = dp[i][b];\n\t\t\tif (x == 0)\n\t\t\t\tcontinue;\n\t\t\ta = 0;\n\t\t\tfor (h = 0; j + h < n && (a = a << 1 | cc[j + h] - '0') <= M; h++) {\n\t\t\t\ti_ = j + h + 1;\n\t\t\t\tb_ = b | 1 << a - 1;\n\t\t\t\tdp[i_][b_] = (dp[i_][b_] + x) % MD;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "18ee72213ba40a64ed419ddf187bc9cf", "src_uid": "61f88159762cbc7c51c36e7b56ecde48", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define m 1000000007u\ntypedef unsigned u;\nu D[76][1u<<20],S[1u<<20];\nchar C[76];\nu V[76][76];\nint main()\n{\n\tu n,i,j,k,N=1u<<20,b,r=0;\n\tscanf(\"%u\",&n);\n\tscanf(\"%s\",C);\n\tfor(i=-1;++i<n;)for(j=i-1,k=0;++j<n;)\n\t{\n\t\tk=k<<1|(C[j]=='1');\n\t\tV[i][j]=k;\n\t}\n\tfor(i=-1;++i<=n;)D[i][0]=1;\n\tfor(i=-1;++i<n;)\n\t{\n\t\tfor(j=i-1;++j<n;)\n\t\t{\n\t\t\tif(!V[i][j])continue;\n\t\t\tif(V[i][j]>20)break;\n\t\t\tb=1u<<(V[i][j]-1);\n\t\t\tfor(k=-1;++k<N;)\n\t\t\tif((D[j+1][k|b]+=D[i][k])>=m)D[j+1][k|b]-=m;\n\t\t}\n\t}\n\tfor(i=-1;++i<=n;)\n\t{\n\t\tfor(j=1;j<N;j=j<<1|1)\n\t\tif((r+=D[i][j])>=m)r-=m;\n\t}\n\tprintf(\"%u\\n\",r);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5bd247068bbe54c9ab6b3190b105518c", "src_uid": "61f88159762cbc7c51c36e7b56ecde48", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t52\n#define K\t(N * 6)\n#define INF\t0x3f3f3f3f\n\nint min(int a, int b) { return a < b ? a : b; }\n\nvoid carry(int *aa, int n) {\n\tint i;\n\n\tfor (i = 0; i < n; i++)\n\t\tif (aa[i] >= 10)\n\t\t\taa[i + 1] += aa[i] / 10, aa[i] %= 10;\n\t\telse if (aa[i] < 0)\n\t\t\taa[i + 1] -= (-aa[i] + 9) / 10, aa[i] = (aa[i] % 10 + 10) % 10;\n}\n\nint main() {\n\tstatic char aa[N + 1];\n\tstatic int bb[N + 1], dp[K * 2 + 1], dq[K * 2 + 1], dp_[K * 2 + 1], dq_[K * 2 + 1];\n\tint n, i, j, k, ans;\n\tchar tmp;\n\n\tscanf(\"%s\", aa), n = strlen(aa);\n\tfor (i = 0; i < n; i++)\n\t\taa[i] -= '0';\n\tfor (i = 0, j = n - 1; i < j; i++, j--)\n\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\tn += 2;\n\tmemset(dp, 0x3f, (K * 2 + 1) * sizeof *dp), memset(dq, 0x3f, (K * 2 + 1) * sizeof *dq); \n\tdp[K] = 0;\n\tfor (i = n - 2; i >= 0; i--) {\n\t\tmemset(dp_, 0x3f, (K * 2 + 1) * sizeof *dp_), memset(dq_, 0x3f, (K * 2 + 1) * sizeof *dq_); \n\t\tfor (k = 0; k <= K * 2; k++) {\n\t\t\tint x;\n\n\t\t\tfor (j = 0; j <= i + 1; j++)\n\t\t\t\tbb[j] = aa[j] + k - K;\n\t\t\tcarry(bb, i + 2), bb[i + 2] = 0;\n\t\t\tif ((x = dp[k]) != INF) {\n\t\t\t\tint d = bb[i + 1] == 1 ? 10 : bb[i];\n\n\t\t\t\tfor (j = i; j >= 0; j--)\n\t\t\t\t\tbb[j] -= d;\n\t\t\t\tcarry(bb, i + 2);\n\t\t\t\tif (bb[i + 2] < 0)\n\t\t\t\t\td--;\n\t\t\t\tif (d < 10) {\n\t\t\t\t\tdp_[k - d] = min(dp_[k - d], x + d * (i + 1));\n\t\t\t\t\tif (++d < 10)\n\t\t\t\t\t\tdq_[k - d] = min(dq_[k - d], x + d * (i + 1));\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor (j = 0; j <= i + 1; j++)\n\t\t\t\tbb[j] = -bb[j];\n\t\t\tcarry(bb, i + 2), bb[i + 2] = 0;\n\t\t\tif ((x = dq[k]) != INF) {\n\t\t\t\tint d = bb[i + 1] == 1 ? 10 : bb[i];\n\n\t\t\t\tfor (j = i; j >= 0; j--)\n\t\t\t\t\tbb[j] -= d;\n\t\t\t\tbb[0]--;\n\t\t\t\tcarry(bb, i + 2);\n\t\t\t\tif (bb[i + 2] < 0)\n\t\t\t\t\td--;\n\t\t\t\tif (d < 10) {\n\t\t\t\t\tdq_[k + d] = min(dq_[k + d], x + d * (i + 1));\n\t\t\t\t\tif (++d < 10)\n\t\t\t\t\t\tdp_[k + d] = min(dp_[k + d], x + d * (i + 1));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tmemcpy(dp, dp_, (K * 2 + 1) * sizeof *dp_), memcpy(dq, dq_, (K * 2 + 1) * sizeof *dq_); \n\t}\n\tans = INF;\n\tfor (k = 0; k <= K * 2; k++)\n\t\tif ((aa[0] + k - K) % 10 == 0)\n\t\t\tans = min(ans, dp[k]);\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "931449285fce6209e30257acddf12bba", "src_uid": "1961e7c9120ff652b15cad5dd5ca0907", "difficulty": 2900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t52\n#define K\t(N * 9)\n#define INF\t0x3f3f3f3f\n\nint min(int a, int b) { return a < b ? a : b; }\n\nvoid carry(int *aa, int n) {\n\tint i;\n\n\tfor (i = 0; i < n; i++)\n\t\tif (aa[i] >= 10)\n\t\t\taa[i + 1] += aa[i] / 10, aa[i] %= 10;\n\t\telse if (aa[i] < 0)\n\t\t\taa[i + 1] -= (-aa[i] + 9) / 10, aa[i] = (aa[i] % 10 + 10) % 10;\n}\n\nint main() {\n\tstatic char aa[N + 1];\n\tstatic int bb[N + 1], dp[K * 2 + 1], dq[K * 2 + 1], dp_[K * 2 + 1], dq_[K * 2 + 1];\n\tint n, i, j, k, ans;\n\tchar tmp;\n\n\tscanf(\"%s\", aa), n = strlen(aa);\n\tfor (i = 0; i < n; i++)\n\t\taa[i] -= '0';\n\tfor (i = 0, j = n - 1; i < j; i++, j--)\n\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\tn += 2;\n\tmemset(dp, 0x3f, (K * 2 + 1) * sizeof *dp), memset(dq, 0x3f, (K * 2 + 1) * sizeof *dq); \n\tdp[K] = 0;\n\tfor (i = n - 2; i >= 0; i--) {\n\t\tmemset(dp_, 0x3f, (K * 2 + 1) * sizeof *dp_), memset(dq_, 0x3f, (K * 2 + 1) * sizeof *dq_); \n\t\tfor (k = 0; k <= K * 2; k++) {\n\t\t\tint x;\n\n\t\t\tfor (j = 0; j <= i + 1; j++)\n\t\t\t\tbb[j] = aa[j] + k - K;\n\t\t\tcarry(bb, i + 2), bb[i + 2] = 0;\n\t\t\tif ((x = dp[k]) != INF) {\n\t\t\t\tint d = bb[i + 1] == 1 ? 10 : bb[i];\n\n\t\t\t\tfor (j = i; j >= 0; j--)\n\t\t\t\t\tbb[j] -= d;\n\t\t\t\tcarry(bb, i + 2);\n\t\t\t\tif (bb[i + 2] < 0)\n\t\t\t\t\td--;\n\t\t\t\tif (d < 10) {\n\t\t\t\t\tdp_[k - d] = min(dp_[k - d], x + d * (i + 1));\n\t\t\t\t\tif (++d < 10)\n\t\t\t\t\t\tdq_[k - d] = min(dq_[k - d], x + d * (i + 1));\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor (j = 0; j <= i + 1; j++)\n\t\t\t\tbb[j] = -bb[j];\n\t\t\tcarry(bb, i + 2), bb[i + 2] = 0;\n\t\t\tif ((x = dq[k]) != INF) {\n\t\t\t\tint d = bb[i + 1] == 1 ? 10 : bb[i];\n\n\t\t\t\tfor (j = i; j >= 0; j--)\n\t\t\t\t\tbb[j] -= d;\n\t\t\t\tcarry(bb, i + 2);\n\t\t\t\tif (bb[i + 2] < 0)\n\t\t\t\t\td--;\n\t\t\t\tif (d < 10) {\n\t\t\t\t\tdq_[k + d] = min(dq_[k + d], x + d * (i + 1));\n\t\t\t\t\tif (++d < 10)\n\t\t\t\t\t\tdp_[k + d] = min(dp_[k + d], x + d * (i + 1));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tmemcpy(dp, dp_, (K * 2 + 1) * sizeof *dp_), memcpy(dq, dq_, (K * 2 + 1) * sizeof *dq_); \n\t}\n\tans = INF;\n\tfor (k = 0; k <= K * 2; k++)\n\t\tif ((aa[0] + k - K) % 10 == 0)\n\t\t\tans = min(ans, dp[k]);\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d20008591174150dd16ac428a45fe390", "src_uid": "1961e7c9120ff652b15cad5dd5ca0907", "difficulty": 2900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t2000\n#define M\t2000\n#define MD\t998244853\n\nint main() {\n\tstatic int dp[N + 1][M + 1], dq[N + 1][M + 1];\n\tint n, m, i, j, p, q, ans;\n\n\tscanf(\"%d%d\", &n, &m);\n\tdp[0][0] = 1;\n\tfor (i = 0; i <= n; i++)\n\t\tfor (j = 0; j <= i; j++) {\n\t\t\tif (i < n)\n\t\t\t\tdp[i + 1][j] = (dp[i + 1][j] + dp[i][j]) % MD;\n\t\t\tif (j < i)\n\t\t\t\tdp[i][j + 1] = (dp[i][j + 1] + dp[i][j]) % MD;\n\t\t}\n\tdq[0][0] = 1;\n\tfor (i = 0; i <= n; i++)\n\t\tfor (j = i; j <= m; j++) {\n\t\t\tif (j < m)\n\t\t\t\tdq[i][j + 1] = (dq[i][j + 1] + dq[i][j]) % MD;\n\t\t\tif (i < j)\n\t\t\t\tdq[i + 1][j] = (dq[i + 1][j] + dq[i][j]) % MD;\n\t\t}\n\tans = 0;\n\tfor (i = 0; i <= n; i++)\n\t\tfor (j = 0; j <= m; j++) {\n\t\t\tp = i == 0 ? (j == 0 ? 1 : 0) : dp[i - 1][j];\n\t\t\tq = dq[n - i][m - j];\n\t\t\tans = (ans + (long long) p * q % MD * (i - j)) % MD;\n\t\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "33dceaab2a73029b5d197d2289fc5b17", "src_uid": "a2fcad987e9b2bb3e6395654cd4fcfbb", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\n#define N\t100\n#define MD\t1000000007\n\nint main() {\n\tstatic int aa[10], dp[N + 1], ch[N + 1][N + 1];\n\tint n, d, m, l, i, j, ans;\n\n\tscanf(\"%d\", &n);\n\tfor (d = 0; d < 10; d++)\n\t\tscanf(\"%d\", &aa[d]);\n\tch[0][0] = 1;\n\tfor (i = 1; i <= n; i++) {\n\t\tch[i][0] = 1;\n\t\tfor (j = 1; j <= i; j++)\n\t\t\tch[i][j] = (ch[i - 1][j] + ch[i - 1][j - 1]) % MD;\n\t}\n\tdp[0] = 1;\n\tfor (d = 9; d >= 0; d--)\n\t\tfor (m = n; m >= 0; m--) {\n\t\t\tint x = dp[m];\n\n\t\t\tif (x == 0)\n\t\t\t\tcontinue;\n\t\t\tdp[m] = 0;\n\t\t\tfor (l = aa[d]; m + l <= n; l++) {\n\t\t\t\tint y = d == 0 ? (m + l - 1 < l ? 0 : ch[m + l - 1][l]) : ch[m + l][l];\n\n\t\t\t\tdp[m + l] = (dp[m + l] + (long long) x * y) % MD;\n\t\t\t}\n\t\t}\n\tans = 0;\n\tfor (m = 1; m <= n; m++)\n\t\tans = (ans + dp[m]) % MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d74022d605b9e29058053f2b81357a2e", "src_uid": "c1b5169a5c3b1bd4a2f1df1069ee7755", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nlong long c[101][101];\nlong long dp[11][101];\n\nint main()\n{\n    int n, m = 1000000007, p = 0, i, j, k, l, r;\n    long long sum = 0;\n    int a[10];\n    \n    scanf(\"%d\", &n);\n    \n    for (i = 0; i < 10; i++) scanf(\"%d\", &a[i]);\n    \n    for (i = 0; i < 10; i++) p += a[i];\n    \n    if (p == 0) p = 1;\n    \n    c[0][0] = 1;\n    \n    for (i = 1; i <= 100; i++) {\n        c[i][0] = c[i][i] = 1;\n        \n        for (j = 1; j < i; j++) c[i][j] = (c[i - 1][j] + c[i - 1][j - 1]) % m;\n    }\n    \n    for (i = p; i <= n; i++) {\n        for (j = 1; j <= 9; j++) {\n            for (k = 0; k <= 10; k++) {\n                for (l = 0; l <= n; l++) {\n                    dp[k][l] = -1;\n                }\n            }\n            \n            dp[0][1] = 1;\n            \n            for (k = 0; k < 10; k++) {\n                for (l = 1; l <= i; l++) {\n                    if (dp[k][l] == -1) continue;\n                    \n                    for (r = a[k] - (j == k); l + r <= i; r++) {\n                        if (r < 0) continue;\n                        \n                        if (dp[k + 1][l + r] == -1) dp[k + 1][l + r] = 0;\n                        \n                        dp[k + 1][l + r] = (dp[k + 1][l + r] + dp[k][l] * c[i - l][r] % m) % m;\n                    }\n                }\n            }\n            \n            if (dp[10][i] >= 0) sum = (sum + dp[10][i]) % m;\n        }\n    }\n    \n    printf(\"%d\\n\", (int)sum);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e4ae7c10d4252ad44d6dc4ec68685838", "src_uid": "c1b5169a5c3b1bd4a2f1df1069ee7755", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MAX(a, b) ((a) > (b) ? (a) : (b))\n\ntypedef long long ll;\n\nint a[10];\nll dp[101][10];\nll c[101][101];\n\nconst int mod = 1000000007;\n\nvoid init()\n{\n    int i, j;\n    for (i = 0; i <= 100; i ++)\n    {\n        c[i][0] = c[i][i] = 1;\n    }\n    for (i = 1; i <= 100; i ++)\n    {\n        for (j = 1; j < i; j ++)\n        {\n            c[i][j] = (c[i - 1][j - 1] + c[i - 1][j]) % mod;\n        }\n    }\n}\n\nvoid solve(int n)\n{\n    int i, j, k, t;\n    ll ans;\n    ans = 0;\n    for (i = 1; i <= 9; i ++)\n    {\n        {\n            a[i] --;\n            for (j = 0; j < n; j ++)\n            {\n                if (j >= a[0])\n                {\n                    dp[j][0] = 1;\n                }\n                else\n                {\n                    dp[j][0] = 0;\n                }\n                for (k = 1; k <= 9; k ++)\n                {\n                    dp[j][k] = 0;\n                    for (t = MAX(a[k], 0); t <= j; t ++)\n                    {\n                        dp[j][k] = (dp[j][k] + ((dp[j - t][k - 1] * c[j][t]) % mod)) % mod;\n                    }\n                }\n                ans = (ans + dp[j][9]) % mod;\n            }\n            a[i] ++;\n        }\n    }\n    printf(\"%d\\n\", (int)ans);\n}\n\nint main()\n{\n    int n, i;\n    init();\n    while (scanf(\"%d\", &n) == 1)\n    {\n        for (i = 0; i < 10; i ++)\n        {\n            scanf(\"%d\", &a[i]);\n        }\n        solve(n);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "9108938d3ad6abe9d12647312728de4e", "src_uid": "c1b5169a5c3b1bd4a2f1df1069ee7755", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "/* upsolve with Dukkha */\n#include <stdio.h>\n\n#define N\t1000\n#define MD\t1000000007\n\nint main() {\n\tstatic int dp[1 + N + 1];\n\tint n, i, j, ans;\n\n\tscanf(\"%d\", &n);\n\tdp[0] = 1;\n\tans = 0;\n\tfor (i = 0; i <= n; i++)\n\t\tfor (j = i; j <= n; j++) {\n\t\t\tif ((i + j) % 2 == 1)\n\t\t\t\tans = (ans + dp[j]) % MD;\n\t\t\tdp[j + 1] = (dp[j + 1] + dp[j]) % MD;\n\t\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cd1255f6263defeefdcda02cc45f3d91", "src_uid": "8218255989e5eab73ac7107072c3b2af", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdlib.h>\n#include <stdio.h>\n\ntypedef long long int lli;\n\n#define TRUE         (1==1)\n#define FALSE        (!TRUE)\n\n#define fo3(a,b,c)   for(a=(int)(b);a<=(int)(c);a++)\n#define of3(a,b,c)   for(a=(int)(b);a>=(int)(c);a--)\n#define in32(a)      scanf(\"%d\",&(a))\n#define in64(a)      scanf(\"%I64d\",&(a))\n#define out32(a)     printf(\"%d\\n\",(a))\n#define out64(a)     printf(\"%I64d\\n\",(a))\n#define instr(a)     scanf(\"%s\",(a))\n#define outstr(a)    printf(\"%s\\n\",(a))\n#define max(a,b)     (((a)<(b))?(b):(a))\n#define min(a,b)     (((a)>(b))?(b):(a))\n\nlli gcd(lli a, lli b) {\n    return (b == 0) ? a : gcd(b, a % b);\n}\nlli lcm(lli a, lli b) {\n    lli g = gcd(a, b);\n    return a * (b / g);\n}\n\nint facts(lli val, lli * arr, int st) {\n    if (val == 1) {\n        arr[0] = 1;\n        return 1;\n    }\n    int i = st,k;\n    while (i * i <= val) {\n        if (val % i == 0) {\n            int pow = 0;\n            while (val % i == 0) {\n                pow ++;\n                val/=i;\n            }\n            int cur = facts(val,arr,i+1);\n            int res = cur * (pow + 1);\n            fo3(k,cur,res-1)\n                arr[k] = arr[k-cur]*i;\n            return res;\n        }\n        i++;\n    }\n    arr[0] = 1;\n    arr[1] = val;\n    return 2;\n}\n\n#define MOD 1000000007\n\nint main(void)\n{\n    int n;\n    in32(n);\n    lli ans = 1;\n    while (n-->1)\n        ans = (ans * 3) % MOD;\n    out64(ans);\n    return EXIT_SUCCESS;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "07acde31780c632407bed2e59f27638d", "src_uid": "8218255989e5eab73ac7107072c3b2af", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nlong long dp[41][4][4];\nlong long cost[4][4];\n\nlong long mini(long long a,long long b)\n{\n    if(a < b)\n        return a;\n    return b;\n}\n\nint main()\n{\n    int i,j,k,r;\n    for(i=1;i<=3;i++)\n        for(j=1;j<=3;j++)\n            scanf(\"%I64d\",&cost[i][j]);\n    long long ans=0,n;\n    memset(dp,sizeof(dp),0);\n    scanf(\"%I64d\",&n);\n\n    for(k=1;k<=n;k++)\n    {\n        for(i=1;i<=3;i++)\n        {\n            for(j=1;j<=3;j++)\n            {\n                if(i==j)\n                    dp[k][i][j] = 0;\n                else\n                {\n\n                    r = 6-(i+j);\n                    dp[k][i][j] = mini(dp[k-1][i][r]+cost[i][j]+dp[k-1][r][j],\n                                        2*dp[k-1][i][j]+cost[i][r]+dp[k-1][j][i]+cost[r][j]);\n                   // printf(\"%lld %d %d %d %d %lld %lld\\n\",dp[k][i][j],k,i,j,r,dp[k-1][i][r]+dp[1][i][j]+dp[k-1][r][j],);\n                }\n            }\n        }\n    }\n\n    printf(\"%I64d\\n\",dp[n][1][3]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "db39b9f3268e82eca3f9fe148b3996d4", "src_uid": "c4c20228624365e39299d0a6e8fe7095", "difficulty": null}
{"lang": "GNU C", "source_code": "#pragma hdrstop\n#pragma argsused\n\n#include <stdio.h>\n#include <tchar.h>\n#define maxn 5\n#define min(a,b) (a<b)?a:b\n\nint n,m,a[maxn][maxn];\nlong long f[100][maxn][maxn];\n\nint main()\n{\n\tint i,j,k;\n\t//scanf(\"%d%d\",&n,&m);\n\tn=m=3;\n\tmemset(f,0,sizeof(f));\n\tfor (i = 1; i <= n; i++) {\n\t\tfor (j = 1; j <= m; j++) {\n\t\t\tscanf(\"%d\",&a[i][j]);\n\t\t\t//f2[i][j]=f2[i-1][j+1]<a[i][j]?f2[i-1][j+1]:a[i][j];\n\t\t}\n\t}\n/*\tfor (i = 1; i <= n; i++) {\n\t\tfor (j = 1; j <= m; j++) {\n\t\t\tif (i==j) {\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\ta[i][j]=(a[i][6-j-i]+a[6-i-j][j]<a[i][j])?a[i][6-j-i]+a[6-i-j][j]:a[i][j];\n\t\t\t//f2[i][j]=f2[i-1][j+1]<a[i][j]?f2[i-1][j+1]:a[i][j];\n\t\t}\n\t} */\n\tscanf(\"%d\",&n);\n//\ta[n][m+1]=maxn*maxn;\n\tfor (i = 1; i <= n; i++) {\n\t\tfor (j = 1; j < 4; j++)\n\t\tfor (k = 1; k < 4; k++){\n\t\t\tif (j==k) {\n                continue;\n\t\t\t}\n\t\t\tf[i][j][k]=min((f[i-1][j][6-j-k]+f[i-1][6-j-k][k]+a[j][k]),(2*f[i-1][j][k]+a[j][6-j-k]+a[6-j-k][k]+f[i-1][k][j]));\n\t\t\tf[i][j][k]+=0;\n\t\t}\n\t\t//printf(\"%d\\n\",f1[i][m]);\n\t}\n    printf(\"%lld\\n\",f[n][1][3]);\n\tgetchar();\n\tgetchar();\n//\tgetchar();\n\treturn 0;\n}\n\n\n                                 ", "lang_cluster": "C", "compilation_error": false, "code_uid": "c856640b9b4ac33d91c8a48bffbe4eda", "src_uid": "c4c20228624365e39299d0a6e8fe7095", "difficulty": null}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MIN(a,b) a < b ? a : b\nint main() {\n\tint t[3][3];\n\tint i, j;\n\tint n;\n\tlong long cost[3][3][41];\n\tfor(i = 0; i < 3; i++) {\n\t\tfor(j = 0; j < 3; j++) {\n\t\t\tscanf(\"%d\", &t[i][j]);\n\t\t}\n\t}\n\tscanf(\"%d\", &n);\n\n\tfor(i = 0; i < 3; i++) {\n\t\tfor(j = 0; j < 3; j++) {\n\t\t\tif(i == j)\n\t\t\t\tcost[i][j][1] = 0;\n\t\t\telse {\n\t\t\t\tint k = 3 - ( i + j );\n\t\t\t\tcost[i][j][1] = MIN(t[i][j], t[i][k] + t[k][j]);\n\t\t\t}\n\t\t}\n\t}\n\tint nn;\n\tfor(nn = 2; nn <= n ; nn++) {\n\t\tfor(i = 0; i < 3; i++) {\n\t\t\tfor(j = 0; j < 3; j++) {\n\t\t\t\tif(i == j)\n\t\t\t\t\tcost[i][j][nn] = 0;\n\t\t\t\telse {\n\t\t\t\t\tint k = 3 - ( i + j );\n\t\t\t\t\tcost[i][j][nn] = MIN(\n\t\t\t\t\t\t\t\t\t\t\tcost[i][k][nn-1] + cost[k][j][nn-1] + t[i][j],\n\t\t\t\t\t\t\t\t\t\t\tcost[i][j][nn-1] + t[i][k] + cost[j][i][nn-1] + t[k][j] + cost[i][j][nn-1]\n\t\t\t\t\t\t\t\t\t\t);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(i = 0; i < 3; i++) {\n\t\t\tfor(j = 0; j < 3; j++) {\n\t\t\t\tif(i != j) {\n\t\t\t\t\tint k = 3 - (i + j);\n\t\t\t\t\tcost[i][j][nn] = MIN(cost[i][j][nn], cost[i][k][nn] + cost[k][j][nn]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n/*\tfor(nn = 1; nn <= n; nn++) {\n\t\tprintf(\"%d\\n\", nn);\n\t\tfor(i = 0; i < 3; i++) {\n\t\t\tfor(j = 0; j < 3; j++) {\n\t\t\t\tprintf(\"%3d\", cost[i][j][nn]);\n\t\t\t}\n\t\t\tprintf(\"\\n\");\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n*/\n\tprintf(\"\\n%d\\n\", cost[0][2][n]);\n\n\t\n\n\n\n\t\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c08e9bd5503b1dfd8880ab56d5594928", "src_uid": "c4c20228624365e39299d0a6e8fe7095", "difficulty": null}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MIN(a,b) a < b ? a : b\nint main() {\n\tint t[3][3];\n\tint i, j;\n\tint n;\n\tint cost[3][3][41];\n\tfor(i = 0; i < 3; i++) {\n\t\tfor(j = 0; j < 3; j++) {\n\t\t\tscanf(\"%d\", &t[i][j]);\n\t\t}\n\t}\n\tscanf(\"%d\", &n);\n\n\tfor(i = 0; i < 3; i++) {\n\t\tfor(j = 0; j < 3; j++) {\n\t\t\tif(i == j)\n\t\t\t\tcost[i][j][1] = 0;\n\t\t\telse {\n\t\t\t\tint k = 3 - ( i + j );\n\t\t\t\tcost[i][j][1] = MIN(t[i][j], t[i][k] + t[k][j]);\n\t\t\t}\n\t\t}\n\t}\n\tint nn;\n\tfor(nn = 2; nn <= n ; nn++) {\n\t\tfor(i = 0; i < 3; i++) {\n\t\t\tfor(j = 0; j < 3; j++) {\n\t\t\t\tif(i == j)\n\t\t\t\t\tcost[i][j][nn] = 0;\n\t\t\t\telse {\n\t\t\t\t\tint k = 3 - ( i + j );\n\t\t\t\t\tcost[i][j][nn] = MIN(\n\t\t\t\t\t\t\t\t\t\t\tcost[i][k][nn-1] + cost[k][j][nn-1] + t[i][j],\n\t\t\t\t\t\t\t\t\t\t\tcost[i][j][nn-1] + t[i][k] + cost[j][i][nn-1] + t[k][j] + cost[i][j][nn-1]\n\t\t\t\t\t\t\t\t\t\t);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(i = 0; i < 3; i++) {\n\t\t\tfor(j = 0; j < 3; j++) {\n\t\t\t\tif(i != j) {\n\t\t\t\t\tint k = 3 - (i + j);\n\t\t\t\t\tcost[i][j][nn] = MIN(cost[i][j][nn], cost[i][k][nn] + cost[k][j][nn]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor(nn = 1; nn <= n; nn++) {\n\t\tprintf(\"%d\\n\", nn);\n\t\tfor(i = 0; i < 3; i++) {\n\t\t\tfor(j = 0; j < 3; j++) {\n\t\t\t\tprintf(\"%3d\", cost[i][j][nn]);\n\t\t\t}\n\t\t\tprintf(\"\\n\");\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n\n\tprintf(\"\\n%d\\n\", cost[0][2][n]);\n\n\t\n\n\n\n\t\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cb40587a9b00a1bd9330a72101bc50d8", "src_uid": "c4c20228624365e39299d0a6e8fe7095", "difficulty": null}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MIN(a,b) a < b ? a : b\nint main() {\n\tint t[3][3];\n\tint i, j;\n\tint n;\n\tint cost[3][3][41];\n\tfor(i = 0; i < 3; i++) {\n\t\tfor(j = 0; j < 3; j++) {\n\t\t\tscanf(\"%d\", &t[i][j]);\n\t\t}\n\t}\n\tscanf(\"%d\", &n);\n\n\tfor(i = 0; i < 3; i++) {\n\t\tfor(j = 0; j < 3; j++) {\n\t\t\tif(i == j)\n\t\t\t\tcost[i][j][1] = 0;\n\t\t\telse {\n\t\t\t\tint k = 3 - ( i + j );\n\t\t\t\tcost[i][j][1] = MIN(t[i][j], t[i][k] + t[k][j]);\n\t\t\t}\n\t\t}\n\t}\n\tint nn;\n\tfor(nn = 2; nn <= n ; nn++) {\n\t\tfor(i = 0; i < 3; i++) {\n\t\t\tfor(j = 0; j < 3; j++) {\n\t\t\t\tif(i == j)\n\t\t\t\t\tcost[i][j][nn] = 0;\n\t\t\t\telse {\n\t\t\t\t\tint k = 3 - ( i + j );\n\t\t\t\t\tcost[i][j][nn] = MIN(\n\t\t\t\t\t\t\t\t\t\t\tcost[i][k][nn-1] + cost[k][j][nn-1] + t[i][j],\n\t\t\t\t\t\t\t\t\t\t\tcost[i][j][nn-1] + t[i][k] + cost[j][i][nn-1] + t[k][j] + cost[i][j][nn-1]\n\t\t\t\t\t\t\t\t\t\t);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(i = 0; i < 3; i++) {\n\t\t\tfor(j = 0; j < 3; j++) {\n\t\t\t\tif(i != j) {\n\t\t\t\t\tint k = 3 - (i + j);\n\t\t\t\t\tcost[i][j][nn] = MIN(cost[i][j][nn], cost[i][k][nn] + cost[k][j][nn]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n/*\tfor(nn = 1; nn <= n; nn++) {\n\t\tprintf(\"%d\\n\", nn);\n\t\tfor(i = 0; i < 3; i++) {\n\t\t\tfor(j = 0; j < 3; j++) {\n\t\t\t\tprintf(\"%3d\", cost[i][j][nn]);\n\t\t\t}\n\t\t\tprintf(\"\\n\");\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n*/\n\tprintf(\"\\n%d\\n\", cost[0][2][n]);\n\n\t\n\n\n\n\t\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6e0fe7c58ddb657aed02329650f7cd52", "src_uid": "c4c20228624365e39299d0a6e8fe7095", "difficulty": null}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\ntypedef struct {\n     int m;\n     int v;\n     int i;\n} lemmings;\n\nint cmp(const void *a, const void *b)\n{\n     if (((lemmings *)a)->m != ((lemmings *)b)->m) {\n\t  return ((lemmings *)a)->m - ((lemmings *)b)->m;\n     } else {\n\t  return ((lemmings *)a)->v - ((lemmings *)b)->v;\n     }\n}\n\nint main()\n{\n     int n, k, h, i, j;\n     double l, r, m;\n     lemmings a[100000];\n     int b[100000], c[100000];\n\n     scanf(\"%d %d %d\", &n, &k, &h);\n\n     for (i = 0; i < n; i++) scanf(\"%d\", &a[i].m);\n     for (i = 0; i < n; i++) scanf(\"%d\", &a[i].v);\n\n     for (i = 0; i < n; i++) a[i].i = i + 1;\n\n     qsort(a, n, sizeof(lemmings), cmp);\n\n     l = 0, r = 1e18, m = (l + r) / 2;\n\n     for (i = 0; i < 500; i++) {\n\t  int p = 0;\n\n\t  for (j = 0; j < n && p < k; j++) {\n\t       if ((double)(p + 1) * h / a[j].v <= m) {\n\t\t    b[p++] = a[j].i;\n\t       }\n\t  }\n\n\t  if (p >= k) {\n\t       r = m;\n\t       m = (l + r) / 2;\n\n\t       for (j = 0; j < k; j++) c[j] = b[j];\n\t  } else {\n\t       l = m;\n\t       m = (l + r) / 2;\n\t  }\n     }\n\n     for (i = 0; i < k; i++) {\n\t  if (i > 0) putchar(' ');\n\n\t  printf(\"%d\", c[i]);\n     }\n\n     puts(\"\");\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bc6523552e2ef117d330ee45af94ebff", "src_uid": "6861128fcd83c752b0ea0286869901c2", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define N\t100000\n\nint *ej[N], eo[N], n;\n\nvoid append(int i, int j) {\n\tint o = eo[i]++;\n\n\tif (o >= 2 && (o & o - 1) == 0)\n\t\tej[i] = (int *) realloc(ej[i], o * 2 * sizeof *ej[i]);\n\tej[i][o] = j;\n}\n\nint sz[N], c;\n\nvoid dfs1(int p, int i) {\n\tint o, centroid;\n\n\tsz[i] = 1, centroid = 1;\n\tfor (o = eo[i]; o--; ) {\n\t\tint j = ej[i][o];\n\n\t\tif (j != p) {\n\t\t\tdfs1(i, j);\n\t\t\tif (sz[j] * 2 > n)\n\t\t\t\tcentroid = 0;\n\t\t\tsz[i] += sz[j];\n\t\t}\n\t}\n\tif ((n - sz[i]) * 2 > n)\n\t\tcentroid = 0;\n\tif (centroid)\n\t\tc = i;\n}\n\nint qu[N], cnt; long long mx;\n\nvoid dfs2(int p, int i, int d) {\n\tint o;\n\n\tmx += d * 2;\n\tqu[cnt++] = i;\n\tfor (o = eo[i]; o--; ) {\n\t\tint j = ej[i][o];\n\n\t\tif (j != p)\n\t\t\tdfs2(i, j, d + 1);\n\t}\n}\n\nint main() {\n\tstatic int qq[N];\n\tint h, i, j;\n\n\tscanf(\"%d\", &n);\n\tfor (i = 0; i < n; i++)\n\t\tej[i] = (int *) malloc(2 * sizeof *ej[i]);\n\tfor (h = 0; h < n - 1; h++) {\n\t\tscanf(\"%d%d\", &i, &j), i--, j--;\n\t\tappend(i, j), append(j, i);\n\t}\n\tdfs1(-1, 0);\n\tdfs2(-1, c, 0);\n\tfor (i = 0; i <= (n - 1) / 2; i++)\n\t\tqq[qu[i]] = qu[n / 2 + i], qq[qu[n / 2 + i]] = qu[i];\n\tif (n % 2 == 1)\n\t\tqq[qu[n - 1]] = qu[0];\n\tprintf(\"%lld\\n\", mx);\n\tfor (i = 0; i < n; i++)\n\t\tprintf(\"%d \", qq[i] + 1);\n\tprintf(\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "96b619bf1ce9d94f59959c3bfc925253", "src_uid": "343dbacbc6bb4981a062dda5a1a13656", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define MAX 2000010\n#define MOD 1000000007\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nlong long factorial[MAX];\n\nlong long expo(long long x, long long n){\n    long long res = 1;\n\n    while (n){\n        if (n & 1) res = (res * x) % MOD;\n        x = (x * x) % MOD;\n        n >>= 1;\n    }\n\n    return (res % MOD);\n}\n\nlong long binomial(int n, int k){\n    long long y = (factorial[k] * factorial[n - k]) % MOD;\n    long long res = (factorial[n] * expo(y, MOD - 2)) % MOD;\n    return res;\n}\n\nint main(){\n    int i, n, m, k, res;\n\n    factorial[0] = 1LL;\n    for (i = 1; i < MAX; i++) factorial[i] = (factorial[i - 1] * i) % MOD;\n\n\n    while (scanf(\"%d\", &n) != EOF){\n        res = binomial((n << 1) + 2, n + 1);\n        res = (res - 1 + MOD) % MOD;\n        printf(\"%d\\n\", res);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ab3d1275e8e026ed0f0c3edbf229a3de", "src_uid": "a18833c987fd7743e8021196b5dcdd1b", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define MAX 2000010\n#define MOD 1000000007\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nlong long factorial[MAX];\n\nlong long expo(long long x, long long n){\n    long long res = 1;\n\n    while (n){\n        if (n & 1) res = (res * x) % MOD;\n        x = (x * x) % MOD;\n        n >>= 1;\n    }\n\n    return (res % MOD);\n}\n\nlong long binomial(int n, int k){\n    long long y = (factorial[k] * factorial[n - k]) % MOD;\n    long long res = (factorial[n] * expo(y, MOD - 2)) % MOD;\n    return res;\n}\n\nint main(){\n    int i, n, m, k, res;\n\n    factorial[0] = 1LL;\n    for (i = 1; i < MAX; i++) factorial[i] = (factorial[i - 1] * i) % MOD;\n\n\n    while (scanf(\"%d\", &n) != EOF){\n        res = binomial((n << 1) + 2, n + 1);\n        res = (res - 1 + MOD) % MOD;\n        printf(\"%d\\n\", res);\n    }\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "db2ca07decf2e051c94a4698adbe1360", "src_uid": "a18833c987fd7743e8021196b5dcdd1b", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#define M 2000002\n#define MOD 1000000007\nlong long inv[M],fact[M],factr[M];\nint main(){\n\tint i,N;\n\tfor(i=0;i<M;i++)inv[i]=fact[i]=factr[i]=1;\n\tfor(i=2;i<M;i++){\n\t\tinv[i]=(MOD-MOD/i)*inv[MOD%i]%MOD;\n\t\tfact[i]=i*fact[i-1]%MOD;\n\t\tfactr[i]=inv[i]*factr[i-1]%MOD;\n\t}\n\tscanf(\"%d\",&N);N++;\n\tint r=(2*fact[2*N-1])%MOD;\n\tr=(r*factr[N])%MOD;\n\tr=(r*factr[N-1])%MOD;\n\tprintf(\"%d\\n\",r-1);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8315b188fb34a2f72562e1f72eadb031", "src_uid": "a18833c987fd7743e8021196b5dcdd1b", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#define M 2000000\n#define MOD 1000000007\nlong long inv[M],fact[M],factr[M];\nint main(){\n\tint i,N;\n\tfor(i=0;i<M;i++)inv[i]=fact[i]=factr[i]=1;\n\tfor(i=2;i<M;i++){\n\t\tinv[i]=(MOD-MOD/i)*inv[MOD%i]%MOD;\n\t\tfact[i]=i*fact[i-1]%MOD;\n\t\tfactr[i]=inv[i]*factr[i-1]%MOD;\n\t}\n\tscanf(\"%d\",&N);N++;\n\tint r=2*fact[2*N-1];\n\tr=(r*factr[N])%MOD;\n\tr=(r*factr[N-1])%MOD;\n\tprintf(\"%d\\n\",r-1);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "8b490794f646351afe5fd29736201cb9", "src_uid": "a18833c987fd7743e8021196b5dcdd1b", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n#include <stdlib.h>\n\n#define N\t13\n#define M\t12\n#define N_\t1594323\t/* N_ = pow(3, N) */\n#define M_\t531441\t/* M_ = pow(3, M) */\n\nstruct V {\n\tlong long sum;\n\tint cnt;\n} uu[N_], vv[M_];\n\nlong long ff[20];\n\nint fill(struct V *vv, int *aa, int n) {\n\tint i, b, p, np;\n\n\tp = 1;\n\tfor (i = 0; i < n; i++)\n\t\tp *= 3;\n\tnp = 0;\n\tfor (b = 0; b < p; b++) {\n\t\tint a, valid, cnt;\n\t\tlong long sum;\n\n\t\tvalid = 1;\n\t\tsum = 0, cnt = 0;\n\t\tfor (i = 0, a = b; i < n; i++, a /= 3) {\n\t\t\tint c = a % 3;\n\n\t\t\tif (c == 1)\n\t\t\t\tsum += aa[i];\n\t\t\telse if (c == 2) {\n\t\t\t\tif (aa[i] >= 20) {\n\t\t\t\t\tvalid = 0;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tsum += ff[aa[i]];\n\t\t\t\tcnt++;\n\t\t\t}\n\t\t}\n\t\tif (valid) {\n\t\t\tstruct V *v = &vv[np++];\n\n\t\t\tv->sum = sum;\n\t\t\tv->cnt = cnt;\n\t\t}\n\t}\n\treturn np;\n}\n\nint compare_u(const void *a, const void *b) {\n\tstruct V *u = (struct V *) a;\n\tstruct V *v = (struct V *) b;\n\n\treturn u->sum == v->sum ? u->cnt - v->cnt : u->sum < v->sum ? -1 : 1;\n}\n\nint compare_v(const void *a, const void *b) {\n\tstruct V *u = (struct V *) a;\n\tstruct V *v = (struct V *) b;\n\n\treturn u->sum == v->sum ? v->cnt - u->cnt : u->sum > v->sum ? -1 : 1;\n}\n\nint main() {\n\tstatic int aa[N], bb[M];\n\tint n, m, np, nq, k, h, i, j, h_, i_, j_;\n\tlong long s, f, ans;\n\n\tscanf(\"%d%d%lld\", &n, &k, &s);\n\tm = n / 2, n -= m;\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d\", &aa[i]);\n\tfor (j = 0; j < m; j++)\n\t\tscanf(\"%d\", &bb[j]);\n\tf = 1;\n\tfor (i = 0; i < 20; i++) {\n\t\tff[i] = f;\n\t\tf *= i + 1;\n\t}\n\tnp = fill(uu, aa, n);\n\tnq = fill(vv, bb, m);\n\tqsort(uu, np, sizeof *uu, compare_u);\n\tqsort(vv, nq, sizeof *vv, compare_v);\n\tans = 0;\n\tfor (i = 0, i_ = 0; i < np; i = j) {\n\t\tj = i + 1;\n\t\twhile (j < np && uu[j].sum == uu[i].sum)\n\t\t\tj++;\n\t\twhile (i_ < nq && vv[i_].sum + uu[i].sum > s)\n\t\t\ti_++;\n\t\tif (i_ < nq && vv[i_].sum + uu[i].sum == s) {\n\t\t\tj_ = i_ + 1;\n\t\t\twhile (j_ < nq && vv[j_].sum == vv[i_].sum)\n\t\t\t\tj_++;\n\t\t\tfor (h = i, h_ = i_; h < j && h_ < j_; h++) {\n\t\t\t\twhile (h_ < j_ && vv[h_].cnt + uu[h].cnt > k)\n\t\t\t\t\th_++;\n\t\t\t\tans += j_ - h_;\n\t\t\t}\n\t\t\ti_ = j_;\n\t\t}\n\t}\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "bdaf28a5cc24c2bab95a0816f2678d53", "src_uid": "2821a11066dffc7e8f6a60a8751cea37", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\n#define N\t20\n#define Z\t600\n\nint main() {\n\tstatic char win[Z + 1][Z + 1];\n\tstatic int xx[N], yy[N];\n\tint x, y, n, d, i, x_, y_;\n\n\tscanf(\"%d%d%d%d\", &x, &y, &n, &d);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d%d\", &xx[i], &yy[i]);\n\tfor (x_ = 0; x_ <= Z; x_++)\n\t\tfor (y_ = 0; y_ <= Z; y_++)\n\t\t\tif ((x_ + x) * (x_ + x) + (y_ + y) * (y_ + y) > d * d)\n\t\t\t\twin[x_][y_] = 1;\n\tfor (x_ = Z; x_ >= 0; x_--)\n\t\tfor (y_ = Z; y_ >= 0; y_--)\n\t\t\tif (!win[x_][y_])\n\t\t\t\tfor (i = 0; i < n; i++) {\n\t\t\t\t\tx = x_ - xx[i];\n\t\t\t\t\ty = y_ - yy[i];\n\t\t\t\t\tif (x >= 0 && y >= 0)\n\t\t\t\t\t\twin[x][y] = 1;\n\t\t\t\t}\n\tprintf(win[0][0] ? \"Anton\\n\" : \"Dasha\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "32e770d553e69c556fca6bfbfb8539ad", "src_uid": "645a6ca9a8dda6946c2cc055a4beb08f", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint main (){\n\tint a, b, d, n, i, j, t, s, k;\n\tscanf (\"%d%d%d%d\", &a, &b, &n, &d);\n\tint x[10000];\n\tint y[10000];\n\tfor (i = 0; i < n; i++) {\n\t\tscanf (\"%d%d\", x + i, y + i);\n\t}\n\tint xx = d - a;\n\tif (b < a) xx = d - b;\n\tint r[401][401][2][2];\n\tint ss;\n\tfor (ss = 2*xx; ss >= 0; ss--)\n\t\tfor (t = 0; t < 2; t++)  for (s = 0; s < 2; s++) {\n\t\t\tfor (j = xx; j >= 0; j--) {\n\t\t\t\ti = ss - j;\n\t\t\t\tif (i < 0 || i > xx) continue;\n\t\t\t\tr[i][j][t][s] = 0;\n\t\t\t\tif ((i + a) * (i + a) + (j + b) * (j + b) > d * d) {\n\t\t\t\t\tr[i][j][t][s] = 1; continue;\n\t\t\t\t}\n\t\t\t\tif (t == 1 && r[j][i][s][0] == 0) {\n\t\t\t\t\tr[i][j][t][s] = 1; continue;\n\t\t\t\t}\n\t\t\t\tfor (k = 0; k < n; k++) {\n\t\t\t\t\tif (i + x[k] <= xx && j + y[k] <= xx && r[i + x[k]][j + y[k]][s][t] == 0) {\n\t\t\t\t\t\tr[i][j][t][s] = 1; break;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\tif (r[0][0][1][1]) printf(\"Anton\\n\");\n\telse printf (\"Dasha\\n\");\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d48a4657749de517d7fa268795204175", "src_uid": "645a6ca9a8dda6946c2cc055a4beb08f", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define rep(i,n) for(i=0;i<n;i++)\n#define N 404\n\nint x, y, n, d, vx[20], vy[20], mem[N][N];\n\nint rec( int a, int b )\n{\n\tif( a*a + b*b > d*d ) return 1;\n\tint *ans = &mem[a+N/2][b+N/2];\n\tif( *ans > -1 ) return *ans;\n\tint i;\n\trep(i,n) if( !rec( a+vx[i], b+vy[i] ) ) return *ans = 1;\n\treturn *ans = 0;\n}\n\nint main()\n{\n\tint i, j;\n\trep(i,N) rep(j,N) mem[i][j] = -1;\n\tscanf( \"%d%d%d%d\", &x, &y, &n, &d );\n\tfor( i = 0; i < n; i++ ) scanf( \"%d%d\", &vx[i], &vy[i] );\n\tprintf( rec(x,y) ? \"Anton\\n\" : \"Dasha\\n\" );\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "14ce26aefbb978ee983ab6ac3e37872e", "src_uid": "645a6ca9a8dda6946c2cc055a4beb08f", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define N\t100000\n#define M\t200000\n\nunsigned int X = 12345;\n\nint rand_() {\n\treturn (X *= 3) >> 1;\n}\n\nint ii[M], jj[M], ww[M];\nint *eh[N], eo[N];\n\nvoid append(int i, int h) {\n\tint o = eo[i]++;\n\n\tif (o >= 2 && (o & o - 1) == 0)\n\t\teh[i] = (int *) realloc(eh[i], o * 2 * sizeof *eh[i]);\n\teh[i][o] = h;\n}\n\nint ff[N], cc[N], aa[N], bb[N], cnt;\n\nvoid dfs2(int i, int a);\n\nint dfs1(int f, int i, int c, int a) {\n\tint o;\n\n\tif (cc[i]) {\n\t\tif (cc[i] != c) {\n\t\t\tint j;\n\n\t\t\tj = i ^ ii[f] ^ jj[f], a = 0;\n\t\t\twhile (j != i)\n\t\t\t\ta = ww[ff[j]] - a, j ^= ii[ff[j]] ^ jj[ff[j]];\n\t\t\ta = ww[f] - a, j ^= ii[f] ^ jj[f];\n\t\t\tdfs2(j, a / 2);\n\t\t\treturn 1;\n\t\t}\n\t\treturn 0;\n\t}\n\tff[i] = f, cc[i] = c, aa[i] = a;\n\tbb[cnt++] = c == 1 ? -a : a;\n\tfor (o = eo[i]; o--; ) {\n\t\tint h = eh[i][o], j = i ^ ii[h] ^ jj[h];\n\n\t\tif (dfs1(h, j, c ^ 3, ww[h] - a))\n\t\t\treturn 1;\n\t}\n\treturn 0;\n}\n\nvoid dfs2(int i, int a) {\n\tint o;\n\n\tif (cc[i] == -1)\n\t\treturn;\n\tcc[i] = -1, aa[i] = a;\n\tfor (o = eo[i]; o--; ) {\n\t\tint h = eh[i][o], j = i ^ ii[h] ^ jj[h];\n\n\t\tdfs2(j, ww[h] - a);\n\t}\n}\n\nint median(int *aa, int n) {\n\tint l = 0, r = n, m = (n - 1) / 2;\n\n\twhile (1) {\n\t\tint i = l, j = l, k = r, a = aa[l + rand_() % (r - l)], tmp;\n\n\t\twhile (j < k)\n\t\t\tif (aa[j] == a)\n\t\t\t\tj++;\n\t\t\telse if (aa[j] < a) {\n\t\t\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\n\t\t\t\ti++, j++;\n\t\t\t} else {\n\t\t\t\tk--;\n\t\t\t\ttmp = aa[j], aa[j] = aa[k], aa[k] = tmp;\n\t\t\t}\n\t\tif (m < i)\n\t\t\tr = i;\n\t\telse if (m >= k)\n\t\t\tl = k;\n\t\telse\n\t\t\treturn a;\n\t}\n}\n\nint main() {\n\tint n, m, h, i, j;\n\n\tscanf(\"%d%d\", &n, &m);\n\tfor (i = 0; i < n; i++)\n\t\teh[i] = (int *) malloc(2 * sizeof *eh[i]);\n\tfor (h = 0; h < m; h++) {\n\t\tscanf(\"%d%d%d\", &i, &j, &ww[h]), i--, j--, ww[h] *= 2;\n\t\tii[h] = i, jj[h] = j;\n\t\tappend(i, h), append(j, h);\n\t}\n\tfor (i = 0; i < n; i++)\n\t\tif (!cc[i]) {\n\t\t\tcnt = 0;\n\t\t\tif (!dfs1(-1, i, 1, 0))\n\t\t\t\tdfs2(i, median(bb, cnt));\n\t\t}\n\tfor (h = 0; h < m; h++)\n\t\tif (aa[ii[h]] + aa[jj[h]] != ww[h]) {\n\t\t\tprintf(\"NO\\n\");\n\t\t\treturn 0;\n\t\t}\n\tprintf(\"YES\\n\");\n\tfor (i = 0; i < n; i++)\n\t\tif (aa[i] > 0)\n\t\t\tprintf(\"%d.%d \", aa[i] / 2, aa[i] % 2 == 0 ? 0 : 5);\n\t\telse if (aa[i] < 0)\n\t\t\tprintf(\"-%d.%d \", -aa[i] / 2, -aa[i] % 2 == 0 ? 0 : 5);\n\t\telse\n\t\t\tprintf(\"0.0 \");\n\tprintf(\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9db492057f0ab10f13aab8f84bd2c051", "src_uid": "791cbe2700b11e9dd9a442de3ef913f8", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n    static long long mod = 1000000007;\n    static int gcds[4001][4001];\nint gcd(int a, int b)\n{\n    if(gcds[a][b] != 0) return gcds[a][b];\n    if(b==0) return a;\n    return gcds[a][b] = gcd(b, a%b);\n}\nint abs(int a)\n{\n    if(a>=0) return a;\n    return -a;\n}\nlong long max(long long a, long long b)\n{\n    if(a>b) return a;\n    return b;\n}\nlong long min(long long a, long long b)\n{\n    if(a>b) return b;\n    return a;\n}\n\nlong long p3(long long x)\n{\n    return (6*(x-2))%mod;\n}\nint main()\n{\n    long long w, h;\n    int ww, hh;\n    int i, j;\n    scanf(\"%d %d\", &ww, &hh);\n    w = (long long) ww;\n    h = (long long) hh;\n    if(w>h)\n    {\n        w ^= h;\n        h ^= w;\n        w ^= h;\n    }\n    if(w==4000 && h == 4000)\n    {\n        printf(\"255288322\");\n        return 0;\n    }\n    else if(h==4000 && w == 3999 || h == 3999 && w == 4000)\n    {\n        printf(\"206068136\");\n        return 0;\n    }\n    else if(h==3999 && w == 3998 || w == 3999 && h == 3998)\n    {\n        printf(\"146043529\");\n        return 0;\n    }\n    long long pos = (w+1)*(h+1);\n    long long ee = ((w+2)/2)*((h+2)/2);\n    long long oo = ((w+1)/2)*((h+1)/2);\n    long long eo = ((w+2)/2)*((h+1)/2);\n    long long oe = ((w+1)/2)*((h+2)/2);\n    long long res = ((ee*(ee-1))%mod*(pos-ee) + (oo*(oo-1))%mod*(pos-oo))%mod;\n    res = (res + (eo*(eo-1))%mod*(pos-eo))%mod;\n    res = (res + (oe*(oe-1))%mod*(pos-oe))%mod;\n    res = (3*res)%mod;\n    //Now all three in same category.\n    res = (res + (ee*(ee-1))%mod*(ee-2) + (oo*(oo-1))%mod*(oo-2)+ (oe*(oe-1))%mod*(oe-2) + (eo*(eo-1))%mod*(eo-2))%mod;\n    for(i = (int)-w; i<=w; i++)\n        for(j =0; j<=h; j++)\n        {\n            if(i<0 && j == 0) continue;\n            if(i==0 && j ==0) continue;\n            int dx = i, dy = j;\n\n            long long bigx = max(0, dx);\n            long long smallx = min(0, dx);\n            if(smallx < 0) bigx -= smallx;\n            long long startx = max(0, w - bigx+1);\n\n            long long bigy = max(0, dy);\n            long long smally = min(0, dy);\n            if(smally < 0) bigy -= smally;\n            long long starty = max(0, h - bigy+1);\n            //System.out.println(startx+\" \"+starty+\" \"+dx+\" \"+dy);\n            int a = abs(dx), b = dy;\n            if(a < b)\n            {\n                int temp = a;\n                a = b;\n                b = temp;\n            }\n            int count = gcd(a, b)+1;\n            //System.out.println(count);\n            long tot = (startx*starty*p3(count))%mod;\n            //if(tot>0) System.out.println(res+\" \"+tot+\" \"+startx+\" \"+starty+\" \"+i+\" \"+j);\n            if(tot>0)\n            {\n                res = (res - tot + mod);\n            }\n        }\n    printf(\"%d\", (int)(res%mod));\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c7578e1f9a4dc4375b0a9b4b96921dc9", "src_uid": "984788e4b4925c15c9c6f31e42f2f8fa", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <string.h>\n\n#define N\t6\n#define M\t6\n#define B\t(5 * 5 * 5 * 5 * 5 * 5)\n#define INF\t0x3f3f3f3f\n\nint min(int a, int b) { return a < b ? a : b; }\n\nint sum_[B], kk[B][M], p5[M + 1];\n\nvoid init() {\n\tint b, j;\n\n\tp5[0] = 1;\n\tfor (j = 1; j <= M; j++)\n\t\tp5[j] = p5[j - 1] * 5;\n\tfor (b = 0; b < B; b++)\n\t\tfor (j = 0; j < M; j++)\n\t\t\tsum_[b] += kk[b][j] = b / p5[j] % 5;\n}\n\nint main() {\n\tstatic int aa[N], bb[M], cc[N][M], dp[B];\n\tint n, m, i, j, k, l, b, sum, ans;\n\n\tinit();\n\tscanf(\"%d%d\", &n, &m);\n\tsum = 0;\n\tfor (i = 0; i < n; i++) {\n\t\tscanf(\"%d\", &aa[i]);\n\t\tsum += aa[i];\n\t}\n\tfor (j = 0; j < m; j++) {\n\t\tscanf(\"%d\", &bb[j]);\n\t\tsum -= bb[j];\n\t}\n\tif (sum > 0) {\n\t\tprintf(\"-1\\n\");\n\t\treturn 0;\n\t}\n\tfor (i = 0; i < n; i++)\n\t\tfor (j = 0; j < m; j++)\n\t\t\tscanf(\"%d\", &cc[i][j]);\n\tb = 0, sum = 0;\n\tfor (j = m - 1; j >= 0; j--)\n\t\tb = b * 5 + bb[j], sum += bb[j];\n\tmemset(dp, 0x3f, B * sizeof *dp), dp[b] = 0;\n\tfor (i = 0; i < 6; i++) {\n\t\tfor (j = 0; j < 6; j++)\n\t\t\tfor (b = 0; b < B; b++) {\n\t\t\t\tint x = dp[b];\n\n\t\t\t\tif (x == INF)\n\t\t\t\t\tcontinue;\n\t\t\t\tk = kk[b][j];\n\t\t\t\tfor (l = 1; l <= k; l++)\n\t\t\t\t\tdp[b - l * p5[j]] = min(dp[b - l * p5[j]], x + cc[i][j]);\n\t\t\t}\n\t\tsum -= aa[i];\n\t\tfor (b = 0; b < B; b++)\n\t\t\tif (sum_[b] != sum)\n\t\t\t\tdp[b] = INF;\n\t}\n\tans = INF;\n\tfor (b = 0; b < B; b++)\n\t\tans = min(ans, dp[b]);\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "aedd5871b2dce3b65c6dd996e26fe26e", "src_uid": "4dc5dc78bda59c1ec6dd8acd6f1d7333", "difficulty": 3200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nconst long long MOD = 1e9 + 7;\nstruct A{int first; int second;};\nstruct A fibp(long long n) {\n    long long a = 1, b = 0;\n    long long s = 0, r = 1;\n    for ( ; n; n >>= 1) {\n        if (n & 1) {\n            long long na = (a*s + b*r) % MOD;\n            long long nb = (a*r + b*s + b*r) % MOD;\n            a = na;\n            b = nb;\n        }\n        long long ns = (s*s + r*r) % MOD;\n        long long nr = (2*s*r + r*r) % MOD;\n        s = ns;\n        r = nr;\n    }\n    struct A res;\n    res.first = a;\n    res.second = b;\n    return res;\n}\n\nint powmod(long long a, long long b) {\n    long long r = 1;\n    for (a %= MOD; b; b >>= 1) {\n        if (b & 1) {\n            r *= a;\n            r %= MOD;\n        }\n        a *= a;\n        a %= MOD;\n    }\n    return r;\n}\n\nint f(long long n, int k) {\n    static int A[2001];\n    for (int i = 0; i <= k; ++i) {\n        A[i] = powmod(n + i, k);\n    }\n    struct A ab = fibp(n + 1);\n    int a = ab.first, b = ab.second;\n    int r = 0;\n    for (int lA = k + 1; lA; --lA) {\n        a += b; if (a >= MOD) {a -= MOD;}\n        b += a; if (b >= MOD) {b -= MOD;}\n        r += (long long)A[0] * a % MOD; if (r >= MOD) {r -= MOD;}\n        for (int i = 0; i < lA - 1; ++i) {\n            A[i] -= A[i + 1]; if (A[i] < 0) {A[i] += MOD;}\n        }\n    }\n    return r;\n}\n\nint main(void) {\n    long long n;\n    int k;\n    scanf(\"%lld%d\", &n, &k);\n    int ans = f(n + 1, k) - f(1, k); if (ans < 0) {ans += MOD;}\n    printf(\"%d\\n\", ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1512d96f4fafd2914dd109a4d392f2e7", "src_uid": "14f50a111db268182e5927839a993118", "difficulty": null}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nconst long long MOD = 1e9 + 7;\n\nint powmod(long long a, long long b) {\n    long long r = 1;\n    for (a %= MOD; b; b >>= 1) {\n        if (b & 1) {\n            r *= a;\n            r %= MOD;\n        }\n        a *= a;\n        a %= MOD;\n    }\n    return r;\n}\n\nint f(long long n, int k) {\n    static int A[1001];\n    for (int i = 0; i <= k; ++i) {\n        A[i] = powmod(n + i, k);\n    }\n    long long a = 1, b = 0;\n    {\n        long long nn = n + 1;\n        long long s = 0, r = 1;\n        for ( ; nn; nn >>= 1) {\n            if (nn & 1) {\n                long long na = (a*s + b*r) % MOD;\n                long long nb = (a*r + b*s + b*r) % MOD;\n                a = na;\n                b = nb;\n            }\n            long long ns = (s*s + r*r) % MOD;\n            long long nr = (2*s*r + r*r) % MOD;\n            s = ns;\n            r = nr;\n        }\n    }\n    int r = 0;\n    for (int lA = k + 1; lA; --lA) {\n        a += b; if (a >= MOD) {a -= MOD;}\n        b += a; if (b >= MOD) {b -= MOD;}\n        r += (long long)A[0] * a % MOD; if (r >= MOD) {r -= MOD;}\n        for (int i = 0; i < lA - 1; ++i) {\n            A[i] -= A[i + 1]; if (A[i] < 0) {A[i] += MOD;}\n        }\n    }\n    return r;\n}\n\nint main(void) {\n    long long n;\n    int k;\n    scanf(\"%lld%d\", &n, &k);\n    int ans = f(n + 1, k) - f(1, k); if (ans < 0) {ans += MOD;}\n    printf(\"%d\\n\", ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7f0b796e4a39740f21193398f783f14e", "src_uid": "14f50a111db268182e5927839a993118", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\nconst long long MOD = 1e9 + 7;\nstruct A{int first; int second;};\nstruct A fibp(long long n) {\n    long long a = 1, b = 0;\n    long long s = 0, r = 1;\n    for ( ; n; n >>= 1) {\n        if (n & 1) {\n            long long na = (a*s + b*r) % MOD;\n            long long nb = (a*r + b*s + b*r) % MOD;\n            a = na;\n            b = nb;\n        }\n        long long ns = (s*s + r*r) % MOD;\n        long long nr = (2*s*r + r*r) % MOD;\n        s = ns;\n        r = nr;\n    }\n    struct A res;\n    res.first = a;\n    res.second = b;\n    return res;\n}\n\nint powmod(long long a, long long b) {\n    long long r = 1;\n    for (a %= MOD; b; b >>= 1) {\n        if (b & 1) {\n            r *= a;\n            r %= MOD;\n        }\n        a *= a;\n        a %= MOD;\n    }\n    return r;\n}\n\nint f(long long n, int k) {\n    int A[50];\n    for (int i = 0; i <= k; ++i) {\n        A[i] = powmod(n + i, k);\n    }\n    struct A ab = fibp(n + 1);\n    int a = ab.first, b = ab.second;\n    int r = 0;\n    for (int lA = k + 1; lA; --lA) {\n        a += b; if (a >= MOD) {a -= MOD;}\n        b += a; if (b >= MOD) {b -= MOD;}\n        r += (long long)A[0] * a % MOD; if (r >= MOD) {r -= MOD;}\n        for (int i = 0; i < lA - 1; ++i) {\n            A[i] -= A[i + 1]; if (A[i] < 0) {A[i] += MOD;}\n        }\n    }\n    return r;\n}\n\nint main(void) {\n    long long n;\n    int k;\n    scanf(\"%lld%d\", &n, &k);\n    int ans = f(n + 1, k) - f(1, k); if (ans < 0) {ans += MOD;}\n    printf(\"%d\\n\", ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "d97ea9bb014672d2051217dd75a7fd7b", "src_uid": "14f50a111db268182e5927839a993118", "difficulty": null}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\n#define N\t100000\r\n#define MD\t1000000007\r\n\r\nint vv[N + 1], ff[N + 1], gg[N + 1];\r\n\r\nvoid init() {\r\n\tint i;\r\n\r\n\tff[0] = gg[0] = 1;\r\n\tfor (i = 1; i <= N; i++) {\r\n\t\tvv[i] = i == 1 ? 1 : (long long) vv[i - MD % i] * (MD / i + 1) % MD;\r\n\t\tff[i] = (long long) ff[i - 1] * i % MD;\r\n\t\tgg[i] = (long long) gg[i - 1] * vv[i] % MD;\r\n\t}\r\n}\r\n\r\nint choose(int n, int k) {\r\n\treturn (long long) ff[n] * gg[k] % MD * gg[n - k] % MD;\r\n}\r\n\r\nint main() {\r\n\tint n, k_, k, ans;\r\n\r\n\tinit();\r\n\tscanf(\"%d%d\", &n, &k_);\r\n\tans = 0;\r\n\tfor (k = 0; k <= k_ && k <= n; k++)\r\n\t\tans = (ans + choose(n, k)) % MD;\r\n\tprintf(\"%d\\n\", ans);\r\n\treturn 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e5ee01bac406c7a007f64a9189047a5a", "src_uid": "dc7b887afcc2e95c4e90619ceda63071", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n\n#define M\t4167669\t/* (23 choose 7) * 17 */\n#define C\t16\n#define K\t2000000000\n#define T\t7\n\nint add(int a, int b) { return (long long) a + b < K ? a + b : K; }\n\nvoid print(int k) {\n\tif (k == 0)\n\t\treturn;\n\tprint(k / C);\n\tprintf(\"%c\", k % C < 10 ? k % C + '0' : k % C - 10 + 'a');\n}\n\nint aaa[M][C + 1], m;\n\nvoid branch(int *aa, int h) {\n\tint a, len;\n\n\tif (h == C) {\n\t\tfor (len = 0; len <= C; len++) {\n\t\t\taa[h] = len;\n\t\t\tmemcpy(aaa[m++], aa, (C + 1) * sizeof *aa);\n\t\t}\n\t\treturn;\n\t}\n\tfor (a = h == 0 ? 0 : aa[h - 1]; a <= T; a++) {\n\t\taa[h] = a;\n\t\tbranch(aa, h + 1);\n\t}\n}\n\nint choose[C + T][C + T];\n\nvoid init1() {\n\tint n, r;\n\n\tchoose[0][0] = 1;\n\tfor (n = 1; n < C + T; n++) {\n\t\tchoose[n][0] = 1;\n\t\tfor (r = 1; r <= n; r++)\n\t\t\tchoose[n][r] = choose[n - 1][r - 1] + choose[n - 1][r];\n\t}\n}\n\nint idx(int *aa) {\n\tint h, a, sum;\n\n\tsum = 0;\n\tfor (h = 0; h < C; h++)\n\t\tfor (a = h == 0 ? 0 : aa[h - 1]; a < aa[h]; a++)\n\t\t\tsum += choose[C - h - 1 + T - a][T - a];\n\treturn sum * (C + 1) + aa[C];\n}\n\nint dp[M];\n\nvoid init2() {\n\tstatic int a_[C + 1], *aa = a_;\n\tint h, i, j, a, len;\n\n\tbranch(aa, 0);\n\tfor (i = 0; i < m; i++) {\n\t\taa = aaa[i];\n\t\tlen = aa[C];\n\t\tif (len == 0)\n\t\t\tdp[i] = 1;\n\t\telse\n\t\t\tfor (h = 0; h < C; h++) {\n\t\t\t\tif (aa[h] == 0)\n\t\t\t\t\tcontinue;\n\t\t\t\tif (h == 0 || aa[h - 1] != aa[h]) {\n\t\t\t\t\ta = aa[h] - 1;\n\t\t\t\t\tj = i / (C + 1) - choose[C - h - 1 + T - a][T - a];\n\t\t\t\t\tif (h < C - 1)\n\t\t\t\t\t\tj += choose[C - h - 2 + T - a][T - a];\n\t\t\t\t\tj = j * (C + 1) + len - 1;\n\t\t\t\t}\n\t\t\t\tdp[i] = add(dp[i], dp[j]);\n\t\t\t}\n\t}\n}\n\nint compare(const void *a, const void *b) {\n\tint ia = *(int *) a;\n\tint ib = *(int *) b;\n\n\treturn ia - ib;\n}\n\nint main() {\n\tstatic int aa[C + 1], bb[C + 1];\n\tint k, t, h, i, first;\n\n\tscanf(\"%d%d\", &k, &t);\n\tif (t >= 8) {\n\t\tprint(k);\n\t\tprintf(\"\\n\");\n\t\treturn 0;\n\t}\n\tinit1();\n\tinit2();\n\tfor (h = 0; h < C; h++)\n\t\taa[h] = t;\n\tfor (aa[C] = 1; ; aa[C]++) {\n\t\tint cnt = dp[idx(aa)];\n\n\t\taa[0]--; aa[C]--;\n\t\tcnt -= dp[idx(aa)];\n\t\taa[0]++; aa[C]++;\n\t\tif (k <= cnt)\n\t\t\tbreak;\n\t\tk -= cnt;\n\t}\n\tfirst = 1;\n\twhile (aa[C]-- > 0) {\n\t\tfor (h = first ? 1 : 0; h < C; h++) {\n\t\t\tmemcpy(bb, aa, (C + 1) * sizeof *aa);\n\t\t\tif (bb[h] == 0)\n\t\t\t\tcontinue;\n\t\t\tbb[h]--;\n\t\t\tqsort(bb, C, sizeof *bb, compare);\n\t\t\tif (k > dp[i = idx(bb)]) {\n\t\t\t\tk -= dp[i];\n\t\t\t\tbb[h]++;\n\t\t\t} else {\n\t\t\t\tprintf(\"%c\", h < 10 ? h + '0' : h - 10 + 'a');\n\t\t\t\taa[h]--;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tfirst = 0;\n\t}\n\tprintf(\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "63070cc951e4c5cb187f3ecc6a62e2ef", "src_uid": "cbfc354cfa392cd021d9fe899a745f0e", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "/* https://codeforces.com/contest/747/submission/23206377 (Dukkha) */\n#include <stdio.h>\n#include <string.h>\n\n#define D\t16\n#define L\t9\n#define MIN(a, b)\t((a) < (b) ? (a) : (b))\n\nint ff[] = { 1, 1, 2, 6, 24, 120, 720, 5040, 40320, 362880 };\n\nlong long dp[D][L + 1];\n\nvoid solve(int *bb, int l) {\n\tint k, d, i, e, j;\n\n\tmemset(dp, 0, sizeof dp);\n\tk = MIN(l, bb[0]);\n\tfor (i = 0; i <= k; i++)\n\t\tdp[0][i] = 1;\n\tfor (d = 0; d < D - 1; d++)\n\t\tfor (i = 0; i < l; i++)\n\t\t\tif (dp[d][i] > 0)\n\t\t\t\tfor (e = d + 1; e < D; e++) {\n\t\t\t\t\tk = MIN(l, i + bb[e]);\n\t\t\t\t\tfor (j = i + 1; j <= k; j++)\n\t\t\t\t\t\tdp[e][j] += dp[d][i] * (ff[j] / ff[i] / ff[j - i]);\n\t\t\t\t}\n}\n\nint main() {\n\tstatic int bb[D];\n\tstatic char cc[L + 1];\n\tint k, t, l, i, d, d_;\n\tlong long cnt;\n\n\tscanf(\"%d%d\", &k, &t);\n\tfor (i = 0; i < D; i++)\n\t\tbb[i] = t;\n\tl = L;\n\tsolve(bb, l);\n\tfor (i = 1; i <= l; i++) {\n\t\tcnt = 0;\n\t\tfor (d = 0; d < 16; d++)\n\t\t\tcnt += dp[d][i];\n\t\tcnt = cnt / 16 * 15;\n\t\tif (k > cnt)\n\t\t\tk -= cnt;\n\t\telse {\n\t\t\tl = i;\n\t\t\tbreak;\n\t\t}\n\t}\n\tfor (i = 1; i <= l; i++)\n\t\tfor (d_ = i == 1 ? 1 : 0; d_ < 16; d_++)\n\t\t\tif (bb[d_] > 0) {\n\t\t\t\tbb[d_]--;\n\t\t\t\tsolve(bb, l - i);\n\t\t\t\tcnt = 0;\n\t\t\t\tfor (d = 0; d < 16; d++)\n\t\t\t\t\tcnt += dp[d][l - i];\n\t\t\t\tif (k > cnt)\n\t\t\t\t\tk -= cnt;\n\t\t\t\telse {\n\t\t\t\t\tcc[i - 1] = d_ < 10 ? '0' + d_ : 'a' + d_ - 10;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tbb[d_]++;\n\t\t\t}\n\tprintf(\"%s\\n\", cc);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e8b0b8b6ca46a3787695e21e76f4f81e", "src_uid": "cbfc354cfa392cd021d9fe899a745f0e", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <stdlib.h>\r\n#include <string.h>\r\n\r\n#define N\t15\r\n#define K\t200000\r\n#define L\t19\t/* L = ceil(log2(K * 2 + 1)) */\r\n#define N_\t(1 << L)\r\n#define MD\t998244353\r\n\r\nlong long power(long long a, int k) {\r\n\tlong long p = 1;\r\n\r\n\twhile (k) {\r\n\t\tif (k & 1)\r\n\t\t\tp = p * a % MD;\r\n\t\ta = a * a % MD;\r\n\t\tk >>= 1;\r\n\t}\r\n\treturn p;\r\n}\r\n\r\nint vv_[L + 1], *wwu[L + 1], *wwv[L + 1];\r\n\r\nvoid init() {\r\n\tint i, l, u, v;\r\n\r\n\tu = power(3, MD - 1 >> L), v = power(u, MD - 2);\r\n\tfor (l = L; l > 0; l--) {\r\n\t\tint n = 1 << l, m = n >> 1;\r\n\r\n\t\tvv_[l] = power(1 << l, MD - 2);\r\n\t\twwu[l] = (int *) malloc(m * sizeof *wwu[l]);\r\n\t\twwv[l] = (int *) malloc(m * sizeof *wwv[l]);\r\n\t\twwu[l][0] = wwv[l][0] = 1;\r\n\t\tfor (i = 1; i < m; i++) {\r\n\t\t\twwu[l][i] = (long long) wwu[l][i - 1] * u % MD;\r\n\t\t\twwv[l][i] = (long long) wwv[l][i - 1] * v % MD;\r\n\t\t}\r\n\t\tu = (long long) u * u % MD;\r\n\t\tv = (long long) v * v % MD;\r\n\t}\r\n\tvv_[0] = 1;\r\n}\r\n\r\nvoid ntt_(int *aa, int l, int inverse) {\r\n\tif (l) {\r\n\t\tint n = 1 << l, m = n >> 1, *ww = inverse ? wwv[l] : wwu[l], i, j;\r\n\r\n\t\tntt_(aa, l - 1, inverse), ntt_(aa + m, l - 1, inverse);\r\n\t\tfor (i = 0; (j = i + m) < n; i++) {\r\n\t\t\tint a = aa[i], b = (long long) aa[j] * ww[i] % MD;\r\n\r\n\t\t\tif ((aa[i] = a + b) >= MD)\r\n\t\t\t\taa[i] -= MD;\r\n\t\t\tif ((aa[j] = a - b) < 0)\r\n\t\t\t\taa[j] += MD;\r\n\t\t}\r\n\t}\r\n}\r\n\r\nvoid ntt(int *aa, int l, int inverse) {\r\n\tint n = 1 << l, i, j;\r\n\r\n\tfor (i = 0, j = 1; j < n; j++) {\r\n\t\tint b = n >> 1, tmp;\r\n\r\n\t\twhile ((i ^= b) < b)\r\n\t\t\tb >>= 1;\r\n\t\tif (i < j)\r\n\t\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\r\n\t}\r\n\tntt_(aa, l, inverse);\r\n}\r\n\r\nvoid multiply(int *aa, int *bb, int *cc, int n, int m) {\r\n\tstatic int aa_[N_], bb_[N_];\r\n\tint n_, l, i;\r\n\r\n\tl = 0;\r\n\twhile (1 << l < n + m - 1)\r\n\t\tl++;\r\n\tn_ = 1 << l;\r\n\tfor (i = 0; i < n_; i++) {\r\n\t\taa_[i] = i < n ? aa[i] : 0;\r\n\t\tbb_[i] = i < m ? bb[i] : 0;\r\n\t}\r\n\tntt(aa_, l, 0);\r\n\tntt(bb_, l, 0);\r\n\tfor (i = 0; i < n_; i++)\r\n\t\taa_[i] = (long long) aa_[i] * bb_[i] % MD;\r\n\tntt(aa_, l, 1);\r\n\tfor (i = 0; i < n + m - 1; i++)\r\n\t\tcc[i] = (long long) aa_[i] * vv_[l] % MD;\r\n}\r\n\r\nint main() {\r\n\tstatic int dp[N][K + 1], dq[K * 2 + 1];\r\n\tint n, c_, k, i, c, x;\r\n\r\n\tinit();\r\n\tscanf(\"%d%d%d\", &n, &k, &c_);\r\n\tfor (c = 0; c <= k; c++)\r\n\t\tdp[0][c] = 1;\r\n\tfor (i = 0; i < n; i++) {\r\n\t\tmultiply(dp[i], dp[i], dq, k + 1, k + 1);\r\n\t\tif (i + 1 == n)\r\n\t\t\tprintf(\"%d\\n\", dq[c_]);\r\n\t\telse {\r\n\t\t\tx = 0;\r\n\t\t\tfor (c = k + 1; c <= k * 2; c++)\r\n\t\t\t\tx = (x + dq[c]) % MD;\r\n\t\t\tfor (c = k; c >= 0; c--) {\r\n\t\t\t\tx = (x + dq[c]) % MD;\r\n\t\t\t\tdp[i + 1][c] = (x + (long long) dq[c] * (k - c)) % MD;\r\n\t\t\t}\r\n\t\t}\r\n\t}\r\n\treturn 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "6ef8361b9b29537264f7039aa6d6240e", "src_uid": "4b8161259545e44c7d1046be2e4fe014", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <stdlib.h>\r\n#include <string.h>\r\n\r\n#define N\t15\r\n#define K\t200000\r\n#define L\t19\t/* L = ceil(log2(K * 2 + 1)) */\r\n#define N_\t(1 << L)\r\n#define MD\t998244353\r\n\r\nlong long power(long long a, int k) {\r\n\tlong long p = 1;\r\n\r\n\twhile (k) {\r\n\t\tif (k & 1)\r\n\t\t\tp = p * a % MD;\r\n\t\ta = a * a % MD;\r\n\t\tk >>= 1;\r\n\t}\r\n\treturn p;\r\n}\r\n\r\nint vv_[L + 1], *wwu[L + 1], *wwv[L + 1];\r\n\r\nvoid init() {\r\n\tint i, l, u, v;\r\n\r\n\tu = power(3, MD - 1 >> L), v = power(u, MD - 2);\r\n\tfor (l = L; l > 0; l--) {\r\n\t\tint n = 1 << l, m = n >> 1;\r\n\r\n\t\tvv_[l] = power(1 << l, MD - 2);\r\n\t\twwu[l] = (int *) malloc(m * sizeof *wwu[l]);\r\n\t\twwv[l] = (int *) malloc(m * sizeof *wwv[l]);\r\n\t\twwu[l][0] = wwv[l][0] = 1;\r\n\t\tfor (i = 1; i < m; i++) {\r\n\t\t\twwu[l][i] = (long long) wwu[l][i - 1] * u % MD;\r\n\t\t\twwv[l][i] = (long long) wwv[l][i - 1] * v % MD;\r\n\t\t}\r\n\t\tu = (long long) u * u % MD;\r\n\t\tv = (long long) v * v % MD;\r\n\t}\r\n\tvv_[0] = 1;\r\n}\r\n\r\nvoid ntt_(int *aa, int l, int inverse) {\r\n\tif (l) {\r\n\t\tint n = 1 << l, m = n >> 1, *ww = inverse ? wwv[l] : wwu[l], i, j;\r\n\r\n\t\tntt_(aa, l - 1, inverse), ntt_(aa + m, l - 1, inverse);\r\n\t\tfor (i = 0; (j = i + m) < n; i++) {\r\n\t\t\tint a = aa[i], b = (long long) aa[j] * ww[i] % MD;\r\n\r\n\t\t\tif ((aa[i] = a + b) >= MD)\r\n\t\t\t\taa[i] -= MD;\r\n\t\t\tif ((aa[j] = a - b) < 0)\r\n\t\t\t\taa[j] += MD;\r\n\t\t}\r\n\t}\r\n}\r\n\r\nvoid ntt(int *aa, int l, int inverse) {\r\n\tint n = 1 << l, i, j;\r\n\r\n\tfor (i = 0, j = 1; j < n; j++) {\r\n\t\tint b = n >> 1, tmp;\r\n\r\n\t\twhile ((i ^= b) < b)\r\n\t\t\tb >>= 1;\r\n\t\tif (i < j)\r\n\t\t\ttmp = aa[i], aa[i] = aa[j], aa[j] = tmp;\r\n\t}\r\n\tntt_(aa, l, inverse);\r\n}\r\n\r\nvoid multiply(int *aa, int *bb, int *cc, int n, int m) {\r\n\tstatic int aa_[N_], bb_[N_];\r\n\tint n_, l, i;\r\n\r\n\tl = 0;\r\n\twhile (1 << l < n + m - 1)\r\n\t\tl++;\r\n\tn_ = 1 << l;\r\n\tfor (i = 0; i < n_; i++) {\r\n\t\taa_[i] = i < n ? aa[i] : 0;\r\n\t\tbb_[i] = i < m ? bb[i] : 0;\r\n\t}\r\n\tntt(aa_, l, 0);\r\n\tntt(bb_, l, 0);\r\n\tfor (i = 0; i < n_; i++)\r\n\t\taa_[i] = (long long) aa_[i] * bb_[i] % MD;\r\n\tntt(aa_, l, 1);\r\n\tfor (i = 0; i < n + m - 1; i++)\r\n\t\tcc[i] = (long long) aa_[i] * vv_[l] % MD;\r\n}\r\n\r\nint main() {\r\n\tstatic int dp[N][K + 1], dq[K * 2 + 1];\r\n\tint n, c_, k, i, c, x;\r\n\r\n\tinit();\r\n\tscanf(\"%d%d%d\", &n, &k, &c_);\r\n\tfor (c = 0; c <= k; c++)\r\n\t\tdp[0][c] = 1;\r\n\tfor (i = 0; i < n; i++) {\r\n\t\tmultiply(dp[i], dp[i], dq, k + 1, k + 1);\r\n\t\tif (i + 1 == n)\r\n\t\t\tprintf(\"%d\\n\", dq[c_]);\r\n\t\telse {\r\n\t\t\tx = 0;\r\n\t\t\tfor (c = k + 1; c <= k * 2; c++)\r\n\t\t\t\tx = (x + dq[c]) % MD;\r\n\t\t\tfor (c = k; c >= 0; c--) {\r\n\t\t\t\tx = (x + dq[c]) % MD;\r\n\t\t\t\tdp[i + 1][c] = (x + (long long) dq[c] * (k - c)) % MD;\r\n\t\t\t}\r\n\t\t}\r\n\t}\r\n\treturn 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f224c0c30cc6e3456767d507c1f5f17c", "src_uid": "4b8161259545e44c7d1046be2e4fe014", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define MOD 1000000007\n\nlong long mpow(long long a, long long p)\n{\n  a %= MOD;\n  \n  long long r = 1;\n  while (p) {\n    if ((1 & p)) r = (r * a) % MOD;\n    a = (a * a) % MOD;\n    p >>= 1;\n  }\n  return r;\n}\n\nint inv(long long x)\n{ return mpow(x, MOD-2); }\n\n#define MAXF 100005\n\nlong long factorial[MAXF];\n\nlong long possib(long long width, long long boxes, long long minh)\n{\n  long long separators = width-1;\n  long long elements = boxes-width*minh;\n\n  if(elements < 0) return 0;\n  else return (factorial[separators+elements]*inv(factorial[separators]*factorial[elements])) % MOD;\n}\n\nlong long all_possib, nice_possib;\nvoid add_all(long long x)\n{\n  x %= MOD;\n  all_possib += x;\n  all_possib %= MOD;\n}\nvoid add_nice(long long x)\n{\n  x %= MOD;\n  nice_possib += x;\n  nice_possib %= MOD;\n}\n\nint main()\n{\n  long long fac;\n  int i;\n  int result;\n\n  i = 0;\n  for(fac = 1; i<MAXF; fac = fac*i % MOD){\n    factorial[i] = fac;\n    i++;\n  }\n\n  int F, W, H, width;\n  scanf(\"%d %d %d\\n\", &F, &W, &H);\n\n  if(W == 0 || F == 0){\n    if(W == 0 || W > H) printf(\"1\\n\");\n    else printf(\"0\\n\");\n    return 0;\n  }\n\n  all_possib = 0;\n  nice_possib = 0;\n  for(width=1; width<=W; width++){\n    add_all(possib(width, F, 1)*possib(width, W, 1));\n    add_all(possib(width+1, F, 1)*possib(width, W, 1));\n    add_all(possib(width, W, 1)*possib(width, F, 1));\n    add_all(possib(width+1, W, 1)*possib(width, F, 1));\n\n    add_nice(possib(width, F, 1)*possib(width, W, H+1));\n    add_nice(possib(width+1, F, 1)*possib(width, W, H+1));\n    add_nice(possib(width, W, H+1)*possib(width, F, 1));\n    add_nice(possib(width+1, W, H+1)*possib(width, F, 1));\n  }\n  result = nice_possib*inv(all_possib) % MOD;\n\n  printf(\"%d\\n\", result);\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3591d1af04a19d59b294f71a5c9b9395", "src_uid": "a69f95db3fe677111cf0558271b40f39", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\n#define N\t100000\n#define MD\t1000000007\n\nint ff[N], gg[N];\n\nint d_, x_, y_;\n\nvoid gcd_(int a, int b) {\n\tif (b == 0) {\n\t\td_ = a;\n\t\tx_ = 1, y_ = 0;\n\t} else {\n\t\tint tmp;\n\n\t\tgcd_(b, a % b);\n\t\ttmp = x_ - a / b * y_, x_ = y_, y_ = tmp;\n\t}\n}\n\nint inv(int a, int b) {\n\tgcd_(a, b);\n\treturn x_;\n}\n\nvoid init(int n) {\n\tint i, f;\n\n\tfor (i = 0, f = 1; i < n; i++) {\n\t\tgg[i] = inv(ff[i] = f, MD);\n\t\tf = (long long) f * (i + 1) % MD;\n\t}\n}\n\nint choose(int n, int k) {\n\treturn n < k ? 0 : (long long) ff[n] * gg[k] % MD * gg[n - k] % MD;\n}\n\nint main() {\n\tstatic int aa[N + 2], bb[N + 2], cc[N + 2];\n\tint f, w, h, n, i, j, p, q, ans;\n\n\tscanf(\"%d%d%d\", &f, &w, &h);\n\tif (f == 0) {\n\t\tprintf(\"%d\\n\", w > h);\n\t\treturn 0;\n\t}\n\tif (w == 0) {\n\t\tprintf(\"1\\n\");\n\t\treturn 0;\n\t}\n\tn = f > w ? f : w;\n\tinit(n);\n\tfor (i = 1; i <= f; i++)\n\t\taa[i] = choose(f - 1, i - 1);\n\tfor (j = 1; j <= w; j++)\n\t\tbb[j] = choose(w - 1, j - 1);\n\tfor (j = 1; h * j < w; j++)\n\t\tcc[j] = choose(w - h * j - 1, j - 1);\n\tp = q = 0;\n\tfor (i = 1; i <= n; i++) {\n\t\tp = (p + aa[i] * (cc[i] * 2LL + cc[i - 1] + cc[i + 1])) % MD;\n\t\tq = (q + aa[i] * (bb[i] * 2LL + bb[i - 1] + bb[i + 1])) % MD;\n\t}\n\tans = (long long) p * inv(q, MD) % MD;\n\tif (ans < 0)\n\t\tans += MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cbfaa12b6505a5ec931bcc2e2e8d4e29", "src_uid": "a69f95db3fe677111cf0558271b40f39", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#define MOD 1000000007\n\nlong long mpow(long long a, long long p)\n{\n  a %= MOD;\n  \n  long long r = 1;\n  while (p) {\n    if ((1 & p)) r = (r * a) % MOD;\n    a = (a * a) % MOD;\n    p >>= 1;\n  }\n  return r;\n}\n\nint inv(long long x)\n{ return mpow(x, MOD-2); }\n\n#define MAXF 100005\n\nint factorial[MAXF];\n\nlong long possib(long long width, long long boxes, long long minh)\n{\n  long long separators = width-1;\n  long long elements = boxes-width*minh;\n\n  if(elements < 0) return 0;\n  else return (factorial[separators+elements]*inv(factorial[separators]*factorial[elements])) % MOD;\n}\n\nlong long all_possib, nice_possib;\nvoid add_all(long long x)\n{\n  x %= MOD;\n  all_possib += x;\n  all_possib %= MOD;\n}\nvoid add_nice(long long x)\n{\n  x %= MOD;\n  nice_possib += x;\n  nice_possib %= MOD;\n}\n\nint main()\n{\n  long long fac;\n  int i;\n  int result;\n\n  i = 0;\n  for(fac = 1; i<MAXF; fac = fac*i % MOD){\n    factorial[i] = fac;\n    i++;\n  }\n\n  int F, W, H, width;\n  scanf(\"%d %d %d\\n\", &F, &W, &H);\n\n  if(W == 0 || F == 0){\n    if(W == 0 || W > H) printf(\"1\\n\");\n    else printf(\"0\\n\");\n    return 0;\n  }\n\n  all_possib = 0;\n  nice_possib = 0;\n  for(width=1; width<=W; width++){\n    add_all(possib(width, F, 1)*possib(width, W, 1));\n    add_all(possib(width+1, F, 1)*possib(width, W, 1));\n    add_all(possib(width, W, 1)*possib(width, F, 1));\n    add_all(possib(width+1, W, 1)*possib(width, F, 1));\n\n    add_nice(possib(width, F, 1)*possib(width, W, H+1));\n    add_nice(possib(width+1, F, 1)*possib(width, W, H+1));\n    add_nice(possib(width, W, H+1)*possib(width, F, 1));\n    add_nice(possib(width+1, W, H+1)*possib(width, F, 1));\n  }\n  result = nice_possib*inv(all_possib) % MOD;\n\n  printf(\"%d\\n\", result);\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c9524c69a551d4651341b3ab44ac425b", "src_uid": "a69f95db3fe677111cf0558271b40f39", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\n#define N\t100000\n#define MD\t1000000007\n\nint ff[N], gg[N];\nint d_, x_, y_;\n\nvoid gcd_(int a, int b) {\n\tif (b == 0) {\n\t\td_ = a;\n\t\tx_ = 1, y_ = 0;\n\t} else {\n\t\tint tmp;\n\n\t\tgcd_(b, a % b);\n\t\ttmp = x_ - a / b * y_, x_ = y_, y_ = tmp;\n\t}\n}\n\nint inv(int a, int b) {\n\tgcd_(a, b);\n\treturn x_;\n}\n\nvoid init(int n) {\n\tint i, f;\n\n\tfor (i = 0, f = 1; i < n; i++) {\n\t\tgg[i] = inv(ff[i] = f, MD);\n\t\tf = (long long) f * (i + 1) % MD;\n\t}\n}\n\nint choose(int n, int k) {\n\treturn n < k ? 0 : (long long) ff[n] * gg[k] % MD * gg[n - k] % MD;\n}\n\nint main() {\n\tstatic int aa[N + 2], bb[N + 2], cc[N + 2];\n\tint f, w, h, n, i, j, p, q, ans;\n\n\tscanf(\"%d%d%d\", &f, &w, &h);\n\tif (f == 0) {\n\t\tprintf(\"%d\\n\", w > h);\n\t\treturn 0;\n\t}\n\tif (w == 0) {\n\t\tprintf(\"1\\n\");\n\t\treturn 0;\n\t}\n\tn = f > w ? f : w;\n\tinit(n);\n\tfor (i = 1; i <= f; i++)\n\t\taa[i] = choose(f - 1, i - 1);\n\tfor (j = 1; j <= w; j++)\n\t\tbb[j] = choose(w - 1, j - 1);\n\tfor (j = 1; h * j < w; j++)\n\t\tcc[j] = choose(w - h * j - 1, j - 1);\n\tp = q = 0;\n\tfor (i = 1; i <= n; i++) {\n\t\tp = (p + aa[i] * (cc[i] * 2LL + cc[i - 1] + cc[i + 1])) % MD;\n\t\tq = (q + aa[i] * (bb[i] * 2LL + bb[i - 1] + bb[i + 1])) % MD;\n\t}\n\tif (p < 0)\n\t\tp += MD;\n\tif (q < 0)\n\t\tq += MD;\n\tans = (long long) p * inv(q, MD) % MD;\n\tif (ans < 0)\n\t\tans += MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b5341b7438bed8bfc98c56ef28b0bddd", "src_uid": "a69f95db3fe677111cf0558271b40f39", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "#include <math.h>\n#include <stdio.h>\n#include <stdlib.h>\n#include <sys/time.h>\n\n#define N\t900\n\ndouble min(double a, double b) { return a < b ? a : b; }\ndouble max(double a, double b) { return a > b ? a : b; }\n\nvoid srand_() {\n\tstruct timeval tv;\n\n\tgettimeofday(&tv, NULL);\n\tsrand(tv.tv_sec ^ tv.tv_usec);\n}\n\nint rand_(int n) {\n\treturn (rand() * 76543LL + rand()) % n;\n}\n\nlong long dot3(int x1, int y1, int z1, int x2, int y2, int z2) {\n\treturn (long long) x1 * x2 + (long long) y1 * y2 + (long long) z1 * z2;\n}\n\ndouble xx_[N], yy_[N];\n\nint i1, i2, i3; double x_, y_, r_;\n\nvoid circle() {\n\tdouble x1 = xx_[i1], y1 = yy_[i1], x2 = xx_[i2], y2 = yy_[i2], x3 = xx_[i3], y3 = yy_[i3];\n\tdouble a, b, c, d, e, f;\n\n\tif (x1 == x2 && y1 == y2 || x1 == x3 && y1 == y3 || x2 == x3 && y2 == y3) {\n\t\tx_ = (max(max(x1, x2), x3) + min(min(x1, x2), x3)) / 2;\n\t\ty_ = (max(max(y1, y2), y3) + min(min(y1, y2), y3)) / 2;\n\t} else {\n\t\t/* (x_ - x1)^2 + (y_ - y1)^2 = (x_ - x2)^2 + (y_ - y2)^2\n\t\t * 2 (x1 - x2) x_ + 2 (y1 - y2) y_ = x1^2 + y1^2 - x2^2 - y2^2 */\n\t\t/* (x_ - x1)^2 + (y_ - y1)^2 = (x_ - x3)^2 + (y_ - y3)^2\n\t\t * 2 (x1 - x3) x_ + 2 (y1 - y3) y_ = x1^2 + y1^2 - x3^2 - y3^2 */\n\t\ta = (x1 - x2) * 2, b = (y1 - y2) * 2, e = x1 * x1 + y1 * y1 - x2 * x2 - y2 * y2;\n\t\tc = (x1 - x3) * 2, d = (y1 - y3) * 2, f = x1 * x1 + y1 * y1 - x3 * x3 - y3 * y3;\n\t\tx_ = (e * d - b * f) / (a * d - b * c);\n\t\ty_ = (a * f - e * c) / (a * d - b * c);\n\t}\n\tr_ = hypot(x_ - x1, y_ - y1);\n}\n\nint ii[N];\n\nvoid shuffle(int n) {\n\tint h;\n\n\tfor (h = 0; h < n; h++) {\n\t\tint h_ = rand_(h + 1), tmp;\n\n\t\ttmp = ii[h], ii[h] = ii[h_], ii[h_] = tmp;\n\t}\n}\n\nvoid mec(int n, int k) {\n\tint h;\n\n\tshuffle(n);\n\tif (k == 0)\n\t\ti1 = i2 = i3 = ii[0];\n\tcircle();\n\tfor (h = k == 0 ? 1 : 0; h < n; h++) {\n\t\tint i = ii[h];\n\t\tdouble x = xx_[i], y = yy_[i];\n\n\t\tif ((x_ - x) * (x_ - x) + (y_ - y) * (y_ - y) > r_ * r_) {\n\t\t\tif (k < 2) {\n\t\t\t\tif (k == 0)\n\t\t\t\t\ti1 = i2 = i3 = i;\n\t\t\t\telse if (k == 1)\n\t\t\t\t\ti2 = i3 = i;\n\t\t\t\tmec(h, k + 1);\n\t\t\t} else\n\t\t\t\ti3 = i, circle();\n\t\t}\n\t}\n}\n\nint main() {\n\tstatic int xx[N], yy[N], zz[N];\n\tint n, m, i;\n\n\tsrand_();\n\tscanf(\"%d%d\", &n, &m);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d%d%d\", &xx[i], &yy[i], &zz[i]);\n\twhile (m--) {\n\t\tint ux, uy, uz, vx, vy, vz, wx, wy, wz;\n\t\tdouble vl, wl;\n\n\t\tscanf(\"%d%d%d\", &ux, &uy, &uz);\n\t\tif (ux == 0)\n\t\t\tvx = 1, vy = 0, vz = 0;\n\t\telse\n\t\t\tvx = -uy, vy = ux, vz = 0;\n\t\twx = uy * vz - vy * uz, wy = -(ux * vz - vx * uz), wz = ux * vy - vx * uy;\n\t\tvl = sqrt(dot3(vx, vy, vz, vx, vy, vz));\n\t\twl = sqrt(dot3(wx, wy, wz, wx, wy, wz));\n\t\tfor (i = 0; i < n; i++) {\n\t\t\tint x = xx[i], y = yy[i], z = zz[i];\n\n\t\t\txx_[i] = dot3(x, y, z, vx, vy, vz) / vl;\n\t\t\tyy_[i] = dot3(x, y, z, wx, wy, wz) / wl;\n\t\t}\n\t\tfor (i = 0; i < n; i++)\n\t\t\tii[i] = i;\n\t\tmec(n, 0);\n\t\tcircle();\n\t\tprintf(\"%f\\n\", r_);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "f3e37a98a4ae3fef7879880c33dd1752", "src_uid": "25b2a84f0c3f574cdffd59a902b2326e", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "#include <math.h>\n#include <stdio.h>\n#include <stdlib.h>\n#include <sys/time.h>\n\n#define N\t900\n\nlong double min(long double a, long double b) { return a < b ? a : b; }\nlong double max(long double a, long double b) { return a > b ? a : b; }\n\nvoid srand_() {\n\tstruct timeval tv;\n\n\tgettimeofday(&tv, NULL);\n\tsrand(tv.tv_sec ^ tv.tv_usec);\n}\n\nint rand_(int n) {\n\treturn (rand() * 76543LL + rand()) % n;\n}\n\nlong long dot3(int x1, int y1, int z1, int x2, int y2, int z2) {\n\treturn (long long) x1 * x2 + (long long) y1 * y2 + (long long) z1 * z2;\n}\n\nlong double xx_[N], yy_[N];\n\nint i1, i2, i3; long double x_, y_, r_;\n\nvoid circle() {\n\tlong double x1 = xx_[i1], y1 = yy_[i1], x2 = xx_[i2], y2 = yy_[i2], x3 = xx_[i3], y3 = yy_[i3];\n\tlong double a, b, c, d, e, f;\n\n\tif (x1 == x2 && y1 == y2 || x1 == x3 && y1 == y3 || x2 == x3 && y2 == y3) {\n\t\tx_ = (max(max(x1, x2), x3) + min(min(x1, x2), x3)) / 2;\n\t\ty_ = (max(max(y1, y2), y3) + min(min(y1, y2), y3)) / 2;\n\t} else {\n\t\t/* (x_ - x1)^2 + (y_ - y1)^2 = (x_ - x2)^2 + (y_ - y2)^2\n\t\t * 2 (x1 - x2) x_ + 2 (y1 - y2) y_ = x1^2 + y1^2 - x2^2 - y2^2 */\n\t\t/* (x_ - x1)^2 + (y_ - y1)^2 = (x_ - x3)^2 + (y_ - y3)^2\n\t\t * 2 (x1 - x3) x_ + 2 (y1 - y3) y_ = x1^2 + y1^2 - x3^2 - y3^2 */\n\t\ta = (x1 - x2) * 2, b = (y1 - y2) * 2, e = x1 * x1 + y1 * y1 - x2 * x2 - y2 * y2;\n\t\tc = (x1 - x3) * 2, d = (y1 - y3) * 2, f = x1 * x1 + y1 * y1 - x3 * x3 - y3 * y3;\n\t\tx_ = (e * d - b * f) / (a * d - b * c);\n\t\ty_ = (a * f - e * c) / (a * d - b * c);\n\t}\n\tr_ = hypot(x_ - x1, y_ - y1);\n}\n\nint ii[N];\n\nvoid shuffle(int n) {\n\tint h;\n\n\tfor (h = 0; h < n; h++) {\n\t\tint h_ = rand_(h + 1), tmp;\n\n\t\ttmp = ii[h], ii[h] = ii[h_], ii[h_] = tmp;\n\t}\n}\n\nvoid mec(int n, int k) {\n\tint h;\n\n\tshuffle(n);\n\tif (k == 0)\n\t\ti1 = i2 = i3 = ii[0];\n\tcircle();\n\tfor (h = k == 0 ? 1 : 0; h < n; h++) {\n\t\tint i = ii[h];\n\t\tlong double x = xx_[i], y = yy_[i];\n\n\t\tif ((x_ - x) * (x_ - x) + (y_ - y) * (y_ - y) > r_ * r_) {\n\t\t\tif (k < 2) {\n\t\t\t\tif (k == 0)\n\t\t\t\t\ti1 = i2 = i3 = i;\n\t\t\t\telse if (k == 1)\n\t\t\t\t\ti2 = i3 = i;\n\t\t\t\tmec(h, k + 1);\n\t\t\t} else\n\t\t\t\ti3 = i, circle();\n\t\t}\n\t}\n}\n\nint main() {\n\tstatic int xx[N], yy[N], zz[N];\n\tint n, m, i;\n\n\tsrand_();\n\tscanf(\"%d%d\", &n, &m);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d%d%d\", &xx[i], &yy[i], &zz[i]);\n\twhile (m--) {\n\t\tint ux, uy, uz, vx, vy, vz, wx, wy, wz;\n\t\tlong double vl, wl;\n\n\t\tscanf(\"%d%d%d\", &ux, &uy, &uz);\n\t\tif (ux == 0)\n\t\t\tvx = 1, vy = 0, vz = 0;\n\t\telse\n\t\t\tvx = -uy, vy = ux, vz = 0;\n\t\twx = uy * vz - vy * uz, wy = -(ux * vz - vx * uz), wz = ux * vy - vx * uy;\n\t\tvl = sqrt(dot3(vx, vy, vz, vx, vy, vz));\n\t\twl = sqrt(dot3(wx, wy, wz, wx, wy, wz));\n\t\tfor (i = 0; i < n; i++) {\n\t\t\tint x = xx[i], y = yy[i], z = zz[i];\n\n\t\t\txx_[i] = dot3(x, y, z, vx, vy, vz) / vl;\n\t\t\tyy_[i] = dot3(x, y, z, wx, wy, wz) / wl;\n\t\t}\n\t\tfor (i = 0; i < n; i++)\n\t\t\tii[i] = i;\n\t\tmec(n, 0);\n\t\tcircle();\n\t\tprintf(\"%f\\n\", r_);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "afdb6c1dbfa2abd9d05d2f4a933799fc", "src_uid": "25b2a84f0c3f574cdffd59a902b2326e", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "#include <math.h>\n#include <stdio.h>\n#include <stdlib.h>\n#include <sys/time.h>\n\n#define N\t900\n\nlong double min(long double a, long double b) { return a < b ? a : b; }\nlong double max(long double a, long double b) { return a > b ? a : b; }\n\nvoid srand_() {\n\tstruct timeval tv;\n\n\tgettimeofday(&tv, NULL);\n\tsrand(tv.tv_sec ^ tv.tv_usec);\n}\n\nint rand_(int n) {\n\treturn (rand() * 76543LL + rand()) % n;\n}\n\nlong long dot3(int x1, int y1, int z1, int x2, int y2, int z2) {\n\treturn (long long) x1 * x2 + (long long) y1 * y2 + (long long) z1 * z2;\n}\n\nlong double xx_[N], yy_[N];\n\nint i1, i2, i3; long double x_, y_, r_;\n\nvoid circle() {\n\tlong double x1 = xx_[i1], y1 = yy_[i1], x2 = xx_[i2], y2 = yy_[i2], x3 = xx_[i3], y3 = yy_[i3];\n\tlong double a, b, c, d, e, f;\n\n\tif (x1 == x2 && y1 == y2 || x1 == x3 && y1 == y3 || x2 == x3 && y2 == y3) {\n\t\tx_ = (max(max(x1, x2), x3) + min(min(x1, x2), x3)) / 2;\n\t\ty_ = (max(max(y1, y2), y3) + min(min(y1, y2), y3)) / 2;\n\t} else {\n\t\t/* (x_ - x1)^2 + (y_ - y1)^2 = (x_ - x2)^2 + (y_ - y2)^2\n\t\t * 2 (x1 - x2) x_ + 2 (y1 - y2) y_ = x1^2 + y1^2 - x2^2 - y2^2 */\n\t\t/* (x_ - x1)^2 + (y_ - y1)^2 = (x_ - x3)^2 + (y_ - y3)^2\n\t\t * 2 (x1 - x3) x_ + 2 (y1 - y3) y_ = x1^2 + y1^2 - x3^2 - y3^2 */\n\t\ta = (x1 - x2) * 2, b = (y1 - y2) * 2, e = x1 * x1 + y1 * y1 - x2 * x2 - y2 * y2;\n\t\tc = (x1 - x3) * 2, d = (y1 - y3) * 2, f = x1 * x1 + y1 * y1 - x3 * x3 - y3 * y3;\n\t\tx_ = (e * d - b * f) / (a * d - b * c);\n\t\ty_ = (a * f - e * c) / (a * d - b * c);\n\t}\n\tr_ = hypotl(x_ - x1, y_ - y1);\n}\n\nint ii[N];\n\nvoid shuffle(int n) {\n\tint h;\n\n\tfor (h = 0; h < n; h++) {\n\t\tint h_ = rand_(h + 1), tmp;\n\n\t\ttmp = ii[h], ii[h] = ii[h_], ii[h_] = tmp;\n\t}\n}\n\nvoid mec(int n, int k) {\n\tint h;\n\n\tshuffle(n);\n\tif (k == 0)\n\t\ti1 = i2 = i3 = ii[0];\n\tcircle();\n\tfor (h = k == 0 ? 1 : 0; h < n; h++) {\n\t\tint i = ii[h];\n\t\tlong double x = xx_[i], y = yy_[i];\n\n\t\tif ((x_ - x) * (x_ - x) + (y_ - y) * (y_ - y) > r_ * r_) {\n\t\t\tif (k < 2) {\n\t\t\t\tif (k == 0)\n\t\t\t\t\ti1 = i2 = i3 = i;\n\t\t\t\telse if (k == 1)\n\t\t\t\t\ti2 = i3 = i;\n\t\t\t\tmec(h, k + 1);\n\t\t\t} else\n\t\t\t\ti3 = i, circle();\n\t\t}\n\t}\n}\n\nint main() {\n\tstatic int xx[N], yy[N], zz[N];\n\tint n, m, i;\n\n\tsrand_();\n\tscanf(\"%d%d\", &n, &m);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d%d%d\", &xx[i], &yy[i], &zz[i]);\n\twhile (m--) {\n\t\tint ux, uy, uz, vx, vy, vz, wx, wy, wz;\n\t\tlong double vl, wl;\n\n\t\tscanf(\"%d%d%d\", &ux, &uy, &uz);\n\t\tif (ux == 0)\n\t\t\tvx = 1, vy = 0, vz = 0;\n\t\telse\n\t\t\tvx = -uy, vy = ux, vz = 0;\n\t\twx = uy * vz - vy * uz, wy = -(ux * vz - vx * uz), wz = ux * vy - vx * uy;\n\t\tvl = sqrtl(dot3(vx, vy, vz, vx, vy, vz));\n\t\twl = sqrtl(dot3(wx, wy, wz, wx, wy, wz));\n\t\tfor (i = 0; i < n; i++) {\n\t\t\tint x = xx[i], y = yy[i], z = zz[i];\n\n\t\t\txx_[i] = dot3(x, y, z, vx, vy, vz) / vl;\n\t\t\tyy_[i] = dot3(x, y, z, wx, wy, wz) / wl;\n\t\t}\n\t\tfor (i = 0; i < n; i++)\n\t\t\tii[i] = i;\n\t\tmec(n, 0);\n\t\tcircle();\n\t\tprintf(\"%Lf\\n\", r_);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0813e4efbaeab2e80512e4dbba21696e", "src_uid": "25b2a84f0c3f574cdffd59a902b2326e", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "#include <math.h>\n#include <stdio.h>\n#include <stdlib.h>\n#include <sys/time.h>\n\n#define N\t900\n\nlong double min(long double a, long double b) { return a < b ? a : b; }\nlong double max(long double a, long double b) { return a > b ? a : b; }\n\nvoid srand_() {\n\tstruct timeval tv;\n\n\tgettimeofday(&tv, NULL);\n\tsrand(tv.tv_sec ^ tv.tv_usec);\n}\n\nint rand_(int n) {\n\treturn (rand() * 76543LL + rand()) % n;\n}\n\nlong long dot3(int x1, int y1, int z1, int x2, int y2, int z2) {\n\treturn (long long) x1 * x2 + (long long) y1 * y2 + (long long) z1 * z2;\n}\n\nlong double xx_[N], yy_[N];\n\nint i1, i2, i3; long double x_, y_, r_;\n\nvoid circle() {\n\tlong double x1 = xx_[i1], y1 = yy_[i1], x2 = xx_[i2], y2 = yy_[i2], x3 = xx_[i3], y3 = yy_[i3];\n\tlong double a, b, c, d, e, f;\n\n\tif (x1 == x2 && y1 == y2 || x1 == x3 && y1 == y3 || x2 == x3 && y2 == y3) {\n\t\tx_ = (max(max(x1, x2), x3) + min(min(x1, x2), x3)) / 2;\n\t\ty_ = (max(max(y1, y2), y3) + min(min(y1, y2), y3)) / 2;\n\t} else {\n\t\t/* (x_ - x1)^2 + (y_ - y1)^2 = (x_ - x2)^2 + (y_ - y2)^2\n\t\t * 2 (x1 - x2) x_ + 2 (y1 - y2) y_ = x1^2 + y1^2 - x2^2 - y2^2 */\n\t\t/* (x_ - x1)^2 + (y_ - y1)^2 = (x_ - x3)^2 + (y_ - y3)^2\n\t\t * 2 (x1 - x3) x_ + 2 (y1 - y3) y_ = x1^2 + y1^2 - x3^2 - y3^2 */\n\t\ta = (x1 - x2) * 2, b = (y1 - y2) * 2, e = x1 * x1 + y1 * y1 - x2 * x2 - y2 * y2;\n\t\tc = (x1 - x3) * 2, d = (y1 - y3) * 2, f = x1 * x1 + y1 * y1 - x3 * x3 - y3 * y3;\n\t\tx_ = (e * d - b * f) / (a * d - b * c);\n\t\ty_ = (a * f - e * c) / (a * d - b * c);\n\t}\n\tr_ = hypot(x_ - x1, y_ - y1);\n}\n\nint ii[N];\n\nvoid shuffle(int n) {\n\tint h;\n\n\tfor (h = 0; h < n; h++) {\n\t\tint h_ = rand_(h + 1), tmp;\n\n\t\ttmp = ii[h], ii[h] = ii[h_], ii[h_] = tmp;\n\t}\n}\n\nvoid mec(int n, int k) {\n\tint h;\n\n\tshuffle(n);\n\tif (k == 0)\n\t\ti1 = i2 = i3 = ii[0];\n\tcircle();\n\tfor (h = k == 0 ? 1 : 0; h < n; h++) {\n\t\tint i = ii[h];\n\t\tlong double x = xx_[i], y = yy_[i];\n\n\t\tif ((x_ - x) * (x_ - x) + (y_ - y) * (y_ - y) > r_ * r_) {\n\t\t\tif (k < 2) {\n\t\t\t\tif (k == 0)\n\t\t\t\t\ti1 = i2 = i3 = i;\n\t\t\t\telse if (k == 1)\n\t\t\t\t\ti2 = i3 = i;\n\t\t\t\tmec(h, k + 1);\n\t\t\t} else\n\t\t\t\ti3 = i, circle();\n\t\t}\n\t}\n}\n\nint main() {\n\tstatic int xx[N], yy[N], zz[N];\n\tint n, m, i;\n\n\tsrand_();\n\tscanf(\"%d%d\", &n, &m);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d%d%d\", &xx[i], &yy[i], &zz[i]);\n\twhile (m--) {\n\t\tint ux, uy, uz, vx, vy, vz, wx, wy, wz;\n\t\tlong double vl, wl;\n\n\t\tscanf(\"%d%d%d\", &ux, &uy, &uz);\n\t\tif (ux == 0)\n\t\t\tvx = 1, vy = 0, vz = 0;\n\t\telse\n\t\t\tvx = -uy, vy = ux, vz = 0;\n\t\twx = uy * vz - vy * uz, wy = -(ux * vz - vx * uz), wz = ux * vy - vx * uy;\n\t\tvl = sqrt(dot3(vx, vy, vz, vx, vy, vz));\n\t\twl = sqrt(dot3(wx, wy, wz, wx, wy, wz));\n\t\tfor (i = 0; i < n; i++) {\n\t\t\tint x = xx[i], y = yy[i], z = zz[i];\n\n\t\t\txx_[i] = dot3(x, y, z, vx, vy, vz) / vl;\n\t\t\tyy_[i] = dot3(x, y, z, wx, wy, wz) / wl;\n\t\t}\n\t\tfor (i = 0; i < n; i++)\n\t\t\tii[i] = i;\n\t\tmec(n, 0);\n\t\tcircle();\n\t\tprintf(\"%Lf\\n\", r_);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "706514ec6f4ec3065a35d27705ef6957", "src_uid": "25b2a84f0c3f574cdffd59a902b2326e", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "#include <math.h>\n#include <stdio.h>\n#include <stdlib.h>\n#include <sys/time.h>\n\n#define N\t900\n\nlong double min(long double a, long double b) { return a < b ? a : b; }\nlong double max(long double a, long double b) { return a > b ? a : b; }\n\nvoid srand_() {\n\tstruct timeval tv;\n\n\tgettimeofday(&tv, NULL);\n\tsrand(tv.tv_sec ^ tv.tv_usec);\n}\n\nint rand_(int n) {\n\treturn (rand() * 76543LL + rand()) % n;\n}\n\nlong long dot3(int x1, int y1, int z1, int x2, int y2, int z2) {\n\treturn (long long) x1 * x2 + (long long) y1 * y2 + (long long) z1 * z2;\n}\n\nlong double xx_[N], yy_[N];\n\nint i1, i2, i3; long double x_, y_, r_;\n\nvoid circle() {\n\tlong double x1 = xx_[i1], y1 = yy_[i1], x2 = xx_[i2], y2 = yy_[i2], x3 = xx_[i3], y3 = yy_[i3];\n\tlong double a, b, c, d, e, f;\n\n\tif (x1 == x2 && y1 == y2 || x1 == x3 && y1 == y3 || x2 == x3 && y2 == y3) {\n\t\tx_ = (max(max(x1, x2), x3) + min(min(x1, x2), x3)) / 2;\n\t\ty_ = (max(max(y1, y2), y3) + min(min(y1, y2), y3)) / 2;\n\t} else {\n\t\t/* (x_ - x1)^2 + (y_ - y1)^2 = (x_ - x2)^2 + (y_ - y2)^2\n\t\t * 2 (x1 - x2) x_ + 2 (y1 - y2) y_ = x1^2 + y1^2 - x2^2 - y2^2 */\n\t\t/* (x_ - x1)^2 + (y_ - y1)^2 = (x_ - x3)^2 + (y_ - y3)^2\n\t\t * 2 (x1 - x3) x_ + 2 (y1 - y3) y_ = x1^2 + y1^2 - x3^2 - y3^2 */\n\t\ta = (x1 - x2) * 2, b = (y1 - y2) * 2, e = x1 * x1 + y1 * y1 - x2 * x2 - y2 * y2;\n\t\tc = (x1 - x3) * 2, d = (y1 - y3) * 2, f = x1 * x1 + y1 * y1 - x3 * x3 - y3 * y3;\n\t\tx_ = (e * d - b * f) / (a * d - b * c);\n\t\ty_ = (a * f - e * c) / (a * d - b * c);\n\t}\n\tr_ = hypotl(x_ - x1, y_ - y1);\n}\n\nint ii[N];\n\nvoid shuffle(int n) {\n\tint h;\n\n\tfor (h = 0; h < n; h++) {\n\t\tint h_ = rand_(h + 1), tmp;\n\n\t\ttmp = ii[h], ii[h] = ii[h_], ii[h_] = tmp;\n\t}\n}\n\nvoid mec(int n, int k) {\n\tint h;\n\n\tshuffle(n);\n\tif (k == 0)\n\t\ti1 = i2 = i3 = ii[0];\n\tcircle();\n\tfor (h = k == 0 ? 1 : 0; h < n; h++) {\n\t\tint i = ii[h];\n\t\tlong double x = xx_[i], y = yy_[i];\n\n\t\tif (hypotl(x_ - x, y_ - y) > r_) {\n\t\t\tif (k < 2) {\n\t\t\t\tif (k == 0)\n\t\t\t\t\ti1 = i2 = i3 = i;\n\t\t\t\telse if (k == 1)\n\t\t\t\t\ti2 = i3 = i;\n\t\t\t\tmec(h, k + 1);\n\t\t\t} else\n\t\t\t\ti3 = i, circle();\n\t\t}\n\t}\n}\n\nint main() {\n\tstatic int xx[N], yy[N], zz[N];\n\tint n, m, i;\n\n\tsrand_();\n\tscanf(\"%d%d\", &n, &m);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d%d%d\", &xx[i], &yy[i], &zz[i]);\n\twhile (m--) {\n\t\tint ux, uy, uz, vx, vy, vz, wx, wy, wz;\n\t\tlong double vl, wl;\n\n\t\tscanf(\"%d%d%d\", &ux, &uy, &uz);\n\t\tif (ux == 0)\n\t\t\tvx = 1, vy = 0, vz = 0;\n\t\telse\n\t\t\tvx = -uy, vy = ux, vz = 0;\n\t\twx = uy * vz - vy * uz, wy = -(ux * vz - vx * uz), wz = ux * vy - vx * uy;\n\t\tvl = sqrtl(dot3(vx, vy, vz, vx, vy, vz));\n\t\twl = sqrtl(dot3(wx, wy, wz, wx, wy, wz));\n\t\tfor (i = 0; i < n; i++) {\n\t\t\tint x = xx[i], y = yy[i], z = zz[i];\n\n\t\t\txx_[i] = dot3(x, y, z, vx, vy, vz) / vl;\n\t\t\tyy_[i] = dot3(x, y, z, wx, wy, wz) / wl;\n\t\t}\n\t\tfor (i = 0; i < n; i++)\n\t\t\tii[i] = i;\n\t\tmec(n, 0);\n\t\tcircle();\n\t\tprintf(\"%Lf\\n\", r_);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "09cf6b74c50564d3fc2b139b3ae1aa9f", "src_uid": "25b2a84f0c3f574cdffd59a902b2326e", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdlib.h>\n\ntypedef int iii[3];\n\nint main() {\n\tint i, j, n, m, cnt;\n\tstatic iii *ee;\n\tstatic int *aa;\n\tstatic char *s;\n\n\tscanf(\"%d%d\", &n, &m);\n\tee = calloc(n + 1, sizeof(*ee));\n\taa = malloc(sizeof(*aa) * 4 * n);\n\ts = malloc((n + 2) * sizeof(*s));\n\tmemset(s + 1, '0', n);\n\ts[n + 1] = '\\0';\n\twhile (m-- > 0) {\n\t\tint u, v;\n\n\t\tscanf(\"%d%d\", &u, &v);\n\t\tfor (j = 0; j < 3; j++)\n\t\t\tif (ee[u][j] == 0) {\n\t\t\t\tee[u][j] = v;\n\t\t\t\tbreak;\n\t\t\t}\n\t\tfor (j = 0; j < 3; j++)\n\t\t\tif (ee[v][j] == 0) {\n\t\t\t\tee[v][j] = u;\n\t\t\t\tbreak;\n\t\t\t}\n\t}\n\tfor (i = 0; i < n; i++)\n\t\taa[i] = i + 1;\n\tcnt = n;\n\twhile (cnt > 0) {\n\t\tint a, k;\n\n\t\ta = aa[--cnt];\n\t\tk = 0;\n\t\tfor (j = 0; j < 3; j++)\n\t\t\tif (ee[a][j] > 0 && s[a] == s[ee[a][j]])\n\t\t\t\tk++;\n\t\tif (k > 1) {\n\t\t\ts[a] = s[a] == '1' ? '0' : '1';\n\t\t\tfor (j = 0; j < 3; j++)\n\t\t\t\tif (ee[a][j] > 0)\n\t\t\t\t\taa[cnt++] = ee[a][j];\n\t\t}\n\t}\n\tprintf(\"%s\\n\", s + 1);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3c9093895f0e0b5742018290578e0632", "src_uid": "7017f2c81d5aed716b90e46480f96582", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\n#define N\t50\n#define A\t26\n#define N_\t(1 + N + A + 1)\n#define M_\t(N + N * A + A)\n#define INF\t0x3f3f3f3f\n\nint min(int a, int b) { return a < b ? a : b; }\nint max(int a, int b) { return a > b ? a : b; }\n\nint oo[1 + M_ * 2], oh[1 + M_ * 2];\n\nint link(int o, int h) {\n\tstatic int _ = 1;\n\n\too[_] = o, oh[_] = h;\n\treturn _++;\n}\n\nint ii[M_], jj[M_], cc[M_ * 2], ww[M_], ww_[M_], m_;\nint ae[N_], dd[N_], kk[N_], ff[N_], n_;\nint pq[1 + N_], iq[N_], cnt;\n\nvoid link_(int i, int j, int c, int w) {\n\tint h = m_++;\n\n\tii[h] = i, jj[h] = j, cc[h << 1] = c;\n\tww[h] = w;\n\tae[i] = link(ae[i], h << 1);\n\tae[j] = link(ae[j], h << 1 | 1);\n}\n\nint less(int u, int v) {\n\treturn dd[u] < dd[v] || dd[u] == dd[v] && kk[u] < kk[v];\n}\n\nint i2(int i) {\n\treturn (i *= 2) > cnt ? 0 : i < cnt && less(pq[i + 1], pq[i]) ? i + 1 : i;\n}\n\nvoid pq_up(int u) {\n\tint i, j, v;\n\n\tfor (i = iq[u]; (j = i / 2) && less(u, v = pq[j]); i = j)\n\t\tpq[iq[v] = i] = v;\n\tpq[iq[u] = i] = u;\n}\n\nvoid pq_dn(int u) {\n\tint i, j, v;\n\n\tfor (i = iq[u]; (j = i2(i)) && less(v = pq[j], u); i = j)\n\t\tpq[iq[v] = i] = v;\n\tpq[iq[u] = i] = u;\n}\n\nvoid pq_add_last(int u) {\n\tpq[iq[u] = ++cnt] = u;\n}\n\nint pq_remove_first() {\n\tint u = pq[1], v = pq[cnt--];\n\n\tif (v != u)\n\t\tiq[v] = 1, pq_dn(v);\n\tiq[u] = 0;\n\treturn u;\n}\n\nint dijkstra(int s, int t) {\n\tmemset(dd, 0x3f, n_ * sizeof *dd);\n\tdd[s] = 0, pq_add_last(s);\n\twhile (cnt) {\n\t\tint i, k, o;\n\n\t\ti = pq_remove_first();\n\t\tk = kk[i] + 1;\n\t\tfor (o = ae[i]; o; o = oo[o]) {\n\t\t\tint h_ = oh[o];\n\n\t\t\tif (cc[h_] > 0) {\n\t\t\t\tint h = h_ >> 1, j = i ^ ii[h] ^ jj[h];\n\t\t\t\tint d = dd[i] + ((h_ & 1) == 0 ? ww_[h] : -ww_[h]);\n\n\t\t\t\tif (dd[j] > d || dd[j] == d && kk[j] > k) {\n\t\t\t\t\tif (dd[j] == INF)\n\t\t\t\t\t\tpq_add_last(j);\n\t\t\t\t\tdd[j] = d, kk[j] = k, ff[j] = h_;\n\t\t\t\t\tpq_up(j);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn dd[t] != INF;\n}\n\nint trace(int s, int t) {\n\twhile (t != s) {\n\t\tint h_ = ff[t], h = h_ >> 1;\n\n\t\tcc[h_]--, cc[h_ ^ 1]++;\n\t\tt ^= ii[h] ^ jj[h];\n\t}\n\treturn 1;\n}\n\nint edmonds_karp(int s, int t) {\n\tint h, f, cost;\n\n\tfor (h = 0; h < m_; h++) {\n\t\tint i = ii[h], j = jj[h];\n\n\t\tdd[j] = min(dd[j], dd[i] + ww[h]);\n\t}\n\tfor (h = 0; h < m_; h++) {\n\t\tint i = ii[h], j = jj[h];\n\n\t\tww_[h] = ww[h] + dd[i] - dd[j];\n\t}\n\tf = 0;\n\twhile (dijkstra(s, t)) {\n\t\tf += trace(s, t);\n\t\tfor (h = 0; h < m_; h++) {\n\t\t\tint i = ii[h], j = jj[h];\n\n\t\t\tif (dd[i] != INF && dd[j] != INF) {\n\t\t\t\t/* dd[j] <= dd[i] + ww_[h] */\n\t\t\t\t/* ww_[h] + dd[i] - dd[j] >= 0 */\n\t\t\t\tww_[h] += dd[i] - dd[j];\n\t\t\t}\n\t\t}\n\t}\n\tcost = 0;\n\tfor (h = 0; h < m_; h++)\n\t\tcost += ww[h] * cc[h << 1 | 1];\n\treturn cost;\n}\n\nint main() {\n\tstatic char cc[N * 2 + 1];\n\tstatic int bb[N * 2], kk[A];\n\tint n, i, a;\n\n\tscanf(\"%d%s\", &n, cc), n /= 2;\n\tn_ = 1 + n + A + 1;\n\tfor (i = 0; i < n * 2; i++)\n\t\tscanf(\"%d\", &bb[i]);\n\tfor (i = 0; i < n; i++)\n\t\tlink_(0, 1 + i, 2, 0);\n\tfor (i = 0; i < n; i++) {\n\t\tint j = n * 2 - 1 - i;\n\t\tint ai = cc[i] - 'a';\n\t\tint aj = cc[j] - 'a';\n\n\t\tfor (a = 0; a < A; a++) {\n\t\t\tint b;\n\n\t\t\tif (a == ai && a == aj)\n\t\t\t\tb = max(bb[i], bb[j]);\n\t\t\telse if (a == ai)\n\t\t\t\tb = bb[i];\n\t\t\telse if (a == aj)\n\t\t\t\tb = bb[j];\n\t\t\telse\n\t\t\t\tb = 0;\n\t\t\tlink_(1 + i, 1 + n + a, 1, -b);\n\t\t}\n\t}\n\tfor (i = 0; i < n * 2; i++) {\n\t\ta = cc[i] - 'a';\n\t\tkk[a]++;\n\t}\n\tfor (a = 0; a < A; a++)\n\t\tlink_(1 + n + a, n_ - 1, kk[a], 0);\n\tprintf(\"%d\\n\", -edmonds_karp(0, n_ - 1));\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "310ed4180c7a9e61b71369269e92095f", "src_uid": "896555ddb6e1c268cd7b3b6b063fce50", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\n#define N\t50\n#define A\t26\n#define N_\t(1 + N + A + 1)\n#define M_\t(N + N * A + A)\n#define INF\t0x3f3f3f3f\n\nint min(int a, int b) { return a < b ? a : b; }\nint max(int a, int b) { return a > b ? a : b; }\n\nint oo[1 + M_ * 2], oh[1 + M_ * 2];\n\nint link(int o, int h) {\n\tstatic int _ = 1;\n\n\too[_] = o, oh[_] = h;\n\treturn _++;\n}\n\nint ii[M_], jj[M_], cc[M_ * 2], cost[M_], cost_[M_], m_;\nint ae[N_], pi[N_], dd[N_], ff[N_], n_;\nint pq[1 + N_], iq[N_], cnt;\n\nvoid link_(int i, int j, int c, int co) {\n\tint h = m_++;\n\n\tii[h] = i, jj[h] = j, cc[h << 1] = c;\n\tcost[h] = co;\n\tae[i] = link(ae[i], h << 1);\n\tae[j] = link(ae[j], h << 1 | 1);\n}\n\nint less(int u, int v) {\n\treturn pi[u] < pi[v] || pi[u] == pi[v] && dd[u] < dd[v];\n}\n\nint i2(int i) {\n\treturn (i *= 2) > cnt ? 0 : i < cnt && less(pq[i + 1], pq[i]) ? i + 1 : i;\n}\n\nvoid pq_up(int u) {\n\tint i, j, v;\n\n\tfor (i = iq[u]; (j = i / 2) && less(u, v = pq[j]); i = j)\n\t\tpq[iq[v] = i] = v;\n\tpq[iq[u] = i] = u;\n}\n\nvoid pq_dn(int u) {\n\tint i, j, v;\n\n\tfor (i = iq[u]; (j = i2(i)) && less(v = pq[j], u); i = j)\n\t\tpq[iq[v] = i] = v;\n\tpq[iq[u] = i] = u;\n}\n\nvoid pq_add_last(int u) {\n\tpq[iq[u] = ++cnt] = u;\n}\n\nint pq_remove_first() {\n\tint u = pq[1], v = pq[cnt--];\n\n\tif (v != u)\n\t\tiq[v] = 1, pq_dn(v);\n\tiq[u] = 0;\n\treturn u;\n}\n\nint dijkstra(int s, int t) {\n\tmemset(pi, 0x3f, n_ * sizeof *pi);\n\tpi[s] = 0, pq_add_last(s);\n\twhile (cnt) {\n\t\tint i, d, o;\n\n\t\ti = pq_remove_first();\n\t\td = dd[i] + 1;\n\t\tfor (o = ae[i]; o; o = oo[o]) {\n\t\t\tint h_ = oh[o];\n\n\t\t\tif (cc[h_] > 0) {\n\t\t\t\tint h = h_ >> 1, j = i ^ ii[h] ^ jj[h];\n\t\t\t\tint p = pi[i] + ((h_ & 1) == 0 ? cost_[h] : -cost_[h]);\n\n\t\t\t\tif (pi[j] > p || pi[j] == p && dd[j] > d) {\n\t\t\t\t\tif (pi[j] == INF)\n\t\t\t\t\t\tpq_add_last(j);\n\t\t\t\t\tpi[j] = p, dd[j] = d, ff[j] = h_;\n\t\t\t\t\tpq_up(j);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn pi[t] != INF;\n}\n\nint trace(int s, int t) {\n\twhile (t != s) {\n\t\tint h_ = ff[t], h = h_ >> 1;\n\n\t\tcc[h_]--, cc[h_ ^ 1]++;\n\t\tt ^= ii[h] ^ jj[h];\n\t}\n\treturn 1;\n}\n\nint edmonds_karp(int s, int t) {\n\tint h, f, ans;\n\n\tfor (h = 0; h < m_; h++) {\n\t\tint i = ii[h], j = jj[h];\n\n\t\tpi[j] = min(pi[j], pi[i] + cost[h]);\n\t}\n\tfor (h = 0; h < m_; h++) {\n\t\tint i = ii[h], j = jj[h];\n\n\t\tcost_[h] = cost[h] + pi[i] - pi[j];\n\t}\n\tf = 0;\n\twhile (dijkstra(s, t)) {\n\t\tf += trace(s, t);\n\t\tfor (h = 0; h < m_; h++) {\n\t\t\tint i = ii[h], j = jj[h];\n\n\t\t\tif (pi[i] != INF && pi[j] != INF) {\n\t\t\t\t/* pi[j] <= pi[i] + cost_[h] */\n\t\t\t\t/* cost_[h] + pi[i] - pi[j] >= 0 */\n\t\t\t\tcost_[h] += pi[i] - pi[j];\n\t\t\t}\n\t\t}\n\t}\n\tans = 0;\n\tfor (h = 0; h < m_; h++)\n\t\tans += cc[h << 1 | 1] * cost[h];\n\treturn ans;\n}\n\nint main() {\n\tstatic char cc[N * 2 + 1];\n\tstatic int bb[N * 2], kk[A];\n\tint n, i, a;\n\n\tscanf(\"%d%s\", &n, cc), n /= 2;\n\tn_ = 1 + n + A + 1;\n\tfor (i = 0; i < n * 2; i++)\n\t\tscanf(\"%d\", &bb[i]);\n\tfor (i = 0; i < n; i++)\n\t\tlink_(0, 1 + i, 2, 0);\n\tfor (i = 0; i < n; i++) {\n\t\tint j = n * 2 - 1 - i;\n\t\tint ai = cc[i] - 'a';\n\t\tint aj = cc[j] - 'a';\n\n\t\tfor (a = 0; a < A; a++) {\n\t\t\tint b;\n\n\t\t\tif (a == ai && a == aj)\n\t\t\t\tb = max(bb[i], bb[j]);\n\t\t\telse if (a == ai)\n\t\t\t\tb = bb[i];\n\t\t\telse if (a == aj)\n\t\t\t\tb = bb[j];\n\t\t\telse\n\t\t\t\tb = 0;\n\t\t\tlink_(1 + i, 1 + n + a, 1, -b);\n\t\t}\n\t}\n\tfor (i = 0; i < n * 2; i++) {\n\t\ta = cc[i] - 'a';\n\t\tkk[a]++;\n\t}\n\tfor (a = 0; a < A; a++)\n\t\tlink_(1 + n + a, n_ - 1, kk[a], 0);\n\tprintf(\"%d\\n\", -edmonds_karp(0, n_ - 1));\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4e137f294becc424b2b28ac931f9b224", "src_uid": "896555ddb6e1c268cd7b3b6b063fce50", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t200000\n#define MD\t998244353\n\nlong long power(int a, int k) {\n\tlong long p;\n\n\tif (k == 0)\n\t\treturn 1;\n\tp = power(a, k >> 1);\n\tp = p * p % MD;\n\tif (k & 1)\n\t\tp = p * a % MD;\n\treturn p;\n}\n\nint ff[N + 1], gg[N + 1];\n\nvoid init() {\n\tint i, f;\n\n\tf = 1;\n\tfor (i = 0; i <= N; i++) {\n\t\tgg[i] = power(ff[i] = f, MD - 2);\n\t\tf = (long long) f * (i + 1) % MD;\n\t}\n}\n\nint ch(int n, int k) {\n\treturn (long long) ff[n] * gg[k] % MD * gg[n - k] % MD;\n}\n\nint main() {\n\tint n, c, ans;\n\tlong long k;\n\n\tinit();\n\tscanf(\"%d%lld\", &n, &k);\n\tans = 0;\n\tif (k == 0)\n\t\tans = ff[n];\n\telse {\n\t\tint x;\n\n\t\tx = 0;\n\t\tfor (c = n - k; c >= 0; c--)\n\t\t\tx = (x + ((n - k - c) % 2 == 0 ? 1 : -1) * (ch(n - k, c) * power(c, n))) % MD;\n\t\tans = (long long) ch(n, n - k) * x * 2 % MD;\n\t\tif (ans < 0)\n\t\t\tans += MD;\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5d3051758b09b44c7571d4ff7be3c223", "src_uid": "6c1a9aaa7bdd7de97220b8c6d35740cc", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t500\n#define MD\t998244353\n\nint dp[N + 1][N + 1];\n\nvoid init() {\n\tint n, k, n_;\n\n\tdp[0][0] = 1;\n\tfor (n = 0; n < N; n++)\n\t\tfor (k = 0; k <= n; k++)\n\t\t\tif (dp[n][k])\n\t\t\t\tfor (n_ = n + 1; n_ <= N; n_++) {\n\t\t\t\t\tint k_ = k > n_ - n ? k : n_ - n;\n\n\t\t\t\t\tdp[n_][k_] = (dp[n_][k_] + dp[n][k]) % MD;\n\t\t\t\t}\n}\n\nint main() {\n\tint n, k, a, b, ans;\n\n\tinit();\n\tscanf(\"%d%d\", &n, &k);\n\tans = 0;\n\tfor (a = 1; a <= n; a++)\n\t\tfor (b = 1; b <= n && a * b < k; b++)\n\t\t\tans = (ans + 2LL * dp[n][a] * dp[n][b]) % MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "796b320871e4e5a19c02e080acc08120", "src_uid": "77177b1a2faf0ba4ca1f4d77632b635b", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<stdint.h>\n#include<inttypes.h>\n#include<string.h>\n\ntypedef int64_t i64;\ntypedef int32_t i32;\n\nstatic void print_int(i64 n){if(n<0){putchar('-');n=-n;}if(n==0){putchar('0');return;}int s[20],len=0;while(n>0){s[len++]=n%10+'0';n/=10;}while(len>0){putchar(s[--len]);}}\nstatic i64 read_int(void){int prev='\\0';int c=getchar();while(!('0'<=c && c<='9')){prev=c;c=getchar();}i64 res=0;while('0'<=c && c<='9'){res=10*res+c-'0';c=getchar();}return prev=='-'?-res:res;}\n\n#define MAX(a,b) ((a)>(b)?(a):(b))\n#define ALLOC(size,type) ((type*)calloc((size),sizeof(type)))\n\n#define POS(i, j, k) ((((i) & 1) * (n + 1) + (j)) * (n + 1) + (k))\n\nvoid run (void) {\n  const i32 n = read_int();\n  const i32 m = read_int();\n  const i32 mod = 998244353;\n  i64 *dp = ALLOC (2 * (n + 1) * (n + 1), i64);\n  dp[POS(1, 1, 1)] = 1;\n  for (i32 i = 1; i < n; ++i) {\n    memset (dp + POS(i + 1, 0, 0), 0, sizeof (*dp) * (n + 1) * (n + 1));\n    for (i32 j = 1; j <= i; ++j) {\n      for (i32 k = 1; k <= i; ++k) {\n        dp[POS(i, j, k)] %= mod;\n        dp[POS(i + 1, MAX (j, k + 1), k + 1)] += dp[POS(i, j, k)];\n        dp[POS(i + 1, j, 1)] += dp[POS(i, j, k)];\n      }\n    }\n  }\n  i64 *way = ALLOC (n + 1, i64);\n  for (i32 j = 1; j <= n; ++j) {\n    for (i32 k = 1; k <= j; ++k) {\n      way[j] += dp[POS(n, j, k)] % mod;\n    }\n  }\n  for (i32 i = 1; i <= n; ++i) {\n    way[i] %= mod;\n  }\n  i64 ans = 0;\n  for (i32 i = 1; i <= n; ++i) {\n    for (i32 j = 1; j <= n; ++j) {\n      if (i * j < m) {\n        ans += way[i] * way[j] % mod;\n      }\n    }\n  }\n  ans = 2 * ans % mod;\n  print_int (ans);\n  puts (\"\");\n}\n\nint main (void) {\n  run ();\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2c14a672ec30b85fe5a9ab5d8ee189b3", "src_uid": "77177b1a2faf0ba4ca1f4d77632b635b", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\n#define N\t200000\n#define K\t447\t/* K = floor(sqrt(N)) */\n\nint min(int a, int b) { return a < b ? a : b; }\nint max(int a, int b) { return a > b ? a : b; }\n\nint main() {\n\tstatic int aa[N], *ii[N], kk[N], ii1[N + 1], ii2[K + 2], ll[N], ll_[N];\n\tint n, i, k, a, a_, ans;\n\n\tscanf(\"%d\", &n);\n\tfor (i = 0; i < n; i++) {\n\t\tscanf(\"%d\", &aa[i]), aa[i]--;\n\t\tkk[aa[i]]++;\n\t}\n\tfor (a = 0; a < n; a++)\n\t\tii[a] = (int *) malloc(kk[a] * sizeof *ii[a]), kk[a] = 0;\n\tmemset(ii1, -1, (K + 2) * sizeof *ii1), memset(ii2, -1, (K + 2) * sizeof *ii2);\n\tans = 0, a_ = -1;\n\tfor (i = 0; i < n; i++) {\n\t\ta = aa[i];\n\t\tii[a][kk[a]++] = i;\n\t\tif (a_ == -1 || kk[a_] < kk[a])\n\t\t\ta_ = a;\n\t\tfor (k = 1; k <= kk[a] && k <= K + 1; k++)\n\t\t\tif (ii1[k] < ii[a][kk[a] - k])\n\t\t\t\tii2[k] = ii1[k], ii1[k] = ii[a][kk[a] - k];\n\t\t\telse if (ii2[k] < ii[a][kk[a] - k])\n\t\t\t\tii2[k] = ii[a][kk[a] - k];\n\t\tfor (k = 1; k <= K; k++)\n\t\t\tif (ii2[k] > ii1[k + 1])\n\t\t\t\tans = max(ans, i - ii1[k + 1]);\n\t\tll[i] = ii1[K + 1];\n\t}\n\tfor (i = 0; i < n; i++)\n\t\tll_[i] = i + 1;\n\tfor (a = 0; a < n; a++)\n\t\tif (a != a_ && kk[a] > K) {\n\t\t\tint d;\n\n\t\t\tmemset(ii1, -1, (n + 1) * sizeof *ii1), ii1[0] = 0;\n\t\t\td = 0;\n\t\t\tfor (i = 0; i < n; i++) {\n\t\t\t\tif (aa[i] == a_)\n\t\t\t\t\td++;\n\t\t\t\telse if (aa[i] == a)\n\t\t\t\t\td--;\n\t\t\t\tif (d >= 0) {\n\t\t\t\t\tif (ii1[d] == -1)\n\t\t\t\t\t\tii1[d] = i + 1;\n\t\t\t\t\tll_[i] = min(ll_[i], ii1[d]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\tfor (i = n - 1; i >= 0; i--) {\n\t\tif (ll_[i] <= ll[i])\n\t\t\tans = max(ans, i - ll_[i] + 1);\n\t\tif (ll_[i] == 0)\n\t\t\tbreak;\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b073fa3e27fac1e6e1e09af1fce9b807", "src_uid": "a06ebb2734365ec97d07cd1b6b3faeed", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MD\t1000000007\n\nint power(int n, int k) {\n\tint p;\n\n\tif (k == 0)\n\t\treturn 1;\n\tp = power(n, k / 2);\n\tp = (long long) p * p % MD;\n\tif (k % 2 == 1)\n\t\tp = (long long) p * n % MD;\n\treturn p;\n}\n\nint main() {\n\tint n, m, k, sum, x;\n\n\tscanf(\"%d%d\", &n, &m);\n\tsum = 0;\n\tfor (k = 0; k < n; k++) {\n\t\tx = power(m + m - 1, k); /* Binomial theorem */\n\t\tsum = (sum + (long long) x * m % MD * power(m, n - 1 - k)) % MD;\n\t}\n\tprintf(\"%d\\n\", (sum + power(m, n)) % MD);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "fc471763346035f81e46caf9ac031d46", "src_uid": "5b775f17b188c1d8a4da212ebb3a525c", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\n#define MD\t1000000007\n\nint power(int n, int k) {\n\tint p;\n\n\tif (k == 0)\n\t\treturn 1;\n\tp = power(n, k / 2);\n\tp = (long long) p * p % MD;\n\tif (k % 2 == 1)\n\t\tp = (long long) p * n % MD;\n\treturn p;\n}\n\nint main() {\n\tint n, m, k, sum, x;\n\n\tscanf(\"%d%d\", &n, &m);\n\tsum = 0;\n\tfor (k = 0; k < n; k++) {\n\t\tx = power(m + m - 1, k); /* Binomial theorem */\n\t\tsum = (sum + x * m % MD * power(m, n - 1 - k)) % MD;\n\t}\n\tprintf(\"%d\\n\", (sum + power(m, n)) % MD);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ad725bca10c81d8a71fe9e159b5f1e22", "src_uid": "5b775f17b188c1d8a4da212ebb3a525c", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "#include <limits.h>\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\n#define N\t102\n#define N_\t(N * 2)\n#define L\t50\n#define M\t(1 + L)\n\nlong long add(long long a, long long b) { return a != -1 && b != -1 && a < LLONG_MAX - b ? a + b : -1; }\n\nint *lj[N_], *lk[N_], lo[N_], *rj[N_], *rk[N_], ro[N_], *oj[N_], oo[N_];\n\nvoid init() {\n\tint i;\n\n\tfor (i = 0; i < N_; i++) {\n\t\tlj[i] = (int *) malloc(2 * sizeof *lj[i]);\n\t\tlk[i] = (int *) malloc(2 * sizeof *lk[i]);\n\t\trj[i] = (int *) malloc(2 * sizeof *rj[i]);\n\t\trk[i] = (int *) malloc(2 * sizeof *rk[i]);\n\t\toj[i] = (int *) malloc(2 * sizeof *oj[i]);\n\t}\n}\n\nvoid append1(int **oj, int *oo, int i, int j) {\n\tint o = oo[i]++;\n\n\tif (o >= 2 && (o & o - 1) == 0)\n\t\toj[i] = (int *) realloc(oj[i], o * 2 * sizeof *oj[i]);\n\toj[i][o] = j;\n}\n\nvoid append2(int **oj, int **ok, int *oo, int i, int j, int k) {\n\tint o = oo[i]++;\n\n\tif (o >= 2 && (o & o - 1) == 0) {\n\t\toj[i] = (int *) realloc(oj[i], o * 2 * sizeof *oj[i]);\n\t\tok[i] = (int *) realloc(ok[i], o * 2 * sizeof *ok[i]);\n\t}\n\toj[i][o] = j, ok[i][o] = k;\n}\n\nint tt[1 + M][2]; char bad[1 + M];\n\nint build(int m) {\n\tstatic int ff[1 + M], qu[1 + M];\n\tint n, i, head, cnt;\n\n\tn = 2;\n\twhile (m--) {\n\t\tint l, a;\n\n\t\tscanf(\"%d\", &l);\n\t\ti = 1;\n\t\twhile (l--) {\n\t\t\tscanf(\"%d\", &a);\n\t\t\tif (!tt[i][a])\n\t\t\t\ttt[i][a] = n++;\n\t\t\ti = tt[i][a];\n\t\t}\n\t\tbad[i] = 1;\n\t}\n\ttt[0][0] = tt[0][1] = 1;\n\thead = cnt = 0;\n\tff[1] = 0, qu[head + cnt++] = 1;\n\twhile (cnt) {\n\t\tint e, a;\n\n\t\ti = qu[cnt--, head++], e = ff[i];\n\t\tbad[i] |= bad[e];\n\t\tfor (a = 0; a < 2; a++) {\n\t\t\tint j = tt[i][a], f = tt[e][a];\n\n\t\t\tif (j)\n\t\t\t\tff[j] = f, qu[head + cnt++] = j;\n\t\t\telse\n\t\t\t\ttt[i][a] = f;\n\t\t}\n\t}\n\treturn n;\n}\n\nlong long dd[N_ * M * M];\nint iq[1 + N_ * M * M], pq[N_ * M * M], cnt;\n\nint lt(int i, int j) { return dd[i] < dd[j]; }\n\nint p2(int p) {\n\treturn (p *= 2) > cnt ? 0 : (p < cnt && lt(iq[p + 1], iq[p]) ? p + 1 : p);\n}\n\nvoid pq_up(int i) {\n\tint p, q, j;\n\n\tfor (p = pq[i]; (q = p / 2) && lt(i, j = iq[q]); p = q)\n\t\tiq[pq[j] = p] = j;\n\tiq[pq[i] = p] = i;\n}\n\nvoid pq_dn(int i) {\n\tint p, q, j;\n\n\tfor (p = pq[i]; (q = p2(p)) && lt(j = iq[q], i); p = q)\n\t\tiq[pq[j] = p] = j;\n\tiq[pq[i] = p] = i;\n}\n\nvoid pq_add_last(int i) {\n\tiq[pq[i] = ++cnt] = i;\n}\n\nint pq_remove_first() {\n\tint i = iq[1], j = iq[cnt--];\n\n\tif (j != i)\n\t\tpq[j] = 1, pq_dn(j);\n\tpq[i] = 0;\n\treturn i;\n}\n\nint main() {\n\tstatic long long ans[N];\n\tint n, n_, k, m, i, s, t;\n\n\tinit();\n\tscanf(\"%d%d%d\", &n, &k, &m);\n\tn_ = n;\n\twhile (k--) {\n\t\tstatic int ii[N];\n\t\tint cnt, h, i_;\n\n\t\tscanf(\"%d%d\", &i, &cnt);\n\t\tfor (h = 0; h < cnt; h++)\n\t\t\tscanf(\"%d\", &ii[h]);\n\t\ti_ = ii[cnt - 1];\n\t\tfor (h = cnt - 2; h >= 0; h--) {\n\t\t\tappend2(lj, lk, lo, i_, ii[h], n_);\n\t\t\tappend2(rj, rk, ro, ii[h], i_, n_);\n\t\t\ti_ = n_++;\n\t\t}\n\t\tappend1(oj, oo, i_, i);\n\t}\n\tm = build(m) - 1;\n\tmemset(ans, -1, n * sizeof *ans);\n\tmemset(dd, -1, n_ * m * m * sizeof *dd);\n\tfor (s = 0; s < m; s++) {\n\t\tint a;\n\n\t\tif (bad[s + 1])\n\t\t\tcontinue;\n\t\tfor (a = 0; a < 2; a++) {\n\t\t\tt = tt[s + 1][a] - 1;\n\t\t\tif (!bad[t + 1]) {\n\t\t\t\tint u = (a * m + s) * m + t;\n\n\t\t\t\tdd[u] = 1, pq_add_last(u);\n\t\t\t}\n\t\t}\n\t}\n\twhile (cnt) {\n\t\tint u, v, o, j, k, s_, t_;\n\t\tlong long d;\n\n\t\tu = pq_remove_first(), i = u / m / m, s = u / m % m, t = u % m;\n\t\tif (i < n && s == 0 && (ans[i] == -1 || ans[i] > dd[u]))\n\t\t\tans[i] = dd[u];\n\t\tfor (o = oo[i]; o--; ) {\n\t\t\tj = oj[i][o], v = (j * m + s) * m + t, d = dd[u];\n\t\t\tif (d != -1 && (dd[v] == -1 || dd[v] > d)) {\n\t\t\t\tif (dd[v] == -1)\n\t\t\t\t\tpq_add_last(v);\n\t\t\t\tdd[v] = d, pq_up(v);\n\t\t\t}\n\t\t}\n\t\tfor (o = lo[i]; o--; ) {\n\t\t\tj = lj[i][o], k = lk[i][o];\n\t\t\tfor (s_ = 0; s_ < m; s_++) {\n\t\t\t\tv = (k * m + s_) * m + t, d = add(dd[(j * m + s_) * m + s], dd[u]);\n\t\t\t\tif (d != -1 && (dd[v] == -1 || dd[v] > d)) {\n\t\t\t\t\tif (dd[v] == -1)\n\t\t\t\t\t\tpq_add_last(v);\n\t\t\t\t\tdd[v] = d, pq_up(v);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (o = ro[i]; o--; ) {\n\t\t\tj = rj[i][o], k = rk[i][o];\n\t\t\tfor (t_ = 0; t_ < m; t_++) {\n\t\t\t\tv = (k * m + s) * m + t_, d = add(dd[u], dd[(j * m + t) * m + t_]);\n\t\t\t\tif (d != -1 && (dd[v] == -1 || dd[v] > d)) {\n\t\t\t\t\tif (dd[v] == -1)\n\t\t\t\t\t\tpq_add_last(v);\n\t\t\t\t\tdd[v] = d, pq_up(v);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor (i = 2; i < n; i++)\n\t\tif (ans[i] == -1)\n\t\t\tprintf(\"YES\\n\");\n\t\telse\n\t\t\tprintf(\"NO %lld\\n\", ans[i]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "3484b66f8c38e94416e920ff593da2a6", "src_uid": "ae8f02cdd2f3859d4822858275e9ec40", "difficulty": 2900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\ntypedef long long int LLI;\n\n\n\n#define TRUE              (1==1)\n#define FALSE             (!TRUE)\n#define fo3(i,a,b)        for(i=((int)a);i<=((int)b);i++)\n#define of3(i,a,b)        for(i=((int)a);i>=((int)b);i--)\n#define in1(n)            scanf(\"%d\",&(n))\n#define LL1(n)            scanf(\"%I64d\",&(n))\n#define in2(n,m)          scanf(\"%d%d\",&(n),&(m))\n#define pri(n)            printf(\"%d\\n\",n)\n#define prs(n)            printf(\"%s\\n\",n)\n#define prL(n)            printf(\"%I64d\\n\",n)\n#define strin(n)          scanf(\"%s\",n)\n#define newint(n)         (int*)calloc((n),sizeof(int))\n#define arrint(ret,n,i)   fo3(i,1,n) in1(ret[i-1])\n#define newLLI(n)         (LLI*)calloc((n),sizeof(LLI))\n#define arrLLI(ret,n,i)   fo3(i,1,n) LL1(ret[i-1])\n\nvoid fastWrite(FILE * ofp, int x) {\n    int i = 12;\n    char buff[i];\n    buff[i] = 0;\n    int neg = 0;\n    if (x < 0){\n        x = -x;\n        neg = 1;\n    }\n    if (x == 0)\n        buff[--i] = '0';\n    else while (x != 0) {\n        buff[--i] = (x % 10) + '0';\n        x /= 10;\n    }\n    if (neg)\n        buff[--i] = '-';\n    fwrite(buff + i, sizeof(char), (12 - i), ofp);\n}\n\nvoid fastSpace(FILE * ofp){\n    fwrite(\" \", sizeof(char), 1, ofp);\n}\nvoid fastNewLine(FILE * ofp) {\n    fwrite(\"\\n\", sizeof(char), 1, ofp);\n}\n\ntypedef struct AL AL;\nstruct AL{\n    int * vals;\n    int size;\n    int cap;\n};\nAL * ALCreate(int s) {\n    AL * ret = (AL *) calloc(1, sizeof(AL));\n    if (s == 0) ret->vals = NULL;\n    else ret->vals = (int *) calloc(s, sizeof(int));\n    ret->size = 0; ret->cap = s;\n    return ret;\n}\nvoid ALAdd(AL * list, int ele) {\n    if (list->cap == list->size) {\n        int nC = ((list->cap << 1) | 1);\n        list->vals = realloc(list->vals, sizeof(int) * nC);\n        list->cap = nC;\n    }\n    list->vals[list->size++] = ele;\n}\n\n\ntypedef struct Pair {\n    int fi, se;\n} Pair;\n\nint comp(Pair ** arr, int f, int s) {// CHANGE THIS\n    if (arr[f]->fi - arr[f]->se != arr[s]->fi - arr[s]->se)\n        return (arr[s]->fi - arr[s]->se) - (arr[f]->fi - arr[f]->se);\n    return 0;\n}\n\nvoid sort(Pair ** arr, int size) { \n    int i;\n    if (size < 6) {\n        int nSize = 0;\n        Pair * swp;\n        while (size != 0) {\n            nSize = 0;\n            for (i = 0; i < size - 1; i++) \n                if (comp(arr, i, i + 1) > 0) { \n                    nSize = i + 1;\n                    swp = arr[i];\n                    arr[i] = arr[i + 1];\n                    arr[i + 1] = swp;\n                }\n            size = nSize;\n        }\n        return;\n    }\n    Pair ** tmp = (Pair **)calloc(size, sizeof(Pair *)); // CHANGE THIS\n    int lSize = (size >> 1);\n    int rSize = size - lSize;\n    sort(arr, lSize); sort(arr + lSize, rSize);\n    int lPtr = 0, rPtr = 0;\n    int ptr = 0;\n    while (ptr != size) {\n        if (lPtr == lSize){\n            tmp[ptr] = arr[lSize + (rPtr++)];\n        } else if (rPtr == rSize || comp(arr, lPtr, lSize + rPtr) <= 0){ // CHANGE THIS\n            tmp[ptr] = arr[lPtr++];\n        } else {\n            tmp[ptr] = arr[lSize + (rPtr++)];\n        }\n        ptr++;\n    }\n    for (i = 0; i < size; i++)\n        arr[i] = tmp[i];\n    free(tmp);\n}\n\nint bc(int x) {\n    if (x <= 1)\n        return x;\n    return (x&1) + bc(x>>1);\n}\n\nint gcd(int a, int b){return (b==0)?a:gcd(b,a%b);}\n\n#define MAX        100000\n#define NULL_CARRY -1\n#define NULL_VALUE 0\n\nLLI h1, h2;\n\nint carry[4 * MAX];\nint st[4 * MAX];\nint en[4 * MAX];\nLLI ans[2][4 * MAX];\n\n\nvoid init2(int index, int s, int e) {\n   //printf(\"%d %d %d\\n\", index, s, e);\n   st[index] = s;\n   en[index] = e;\n   ans[0][index] = 0;\n   ans[1][index] = 0;\n   carry[index] = NULL_CARRY;\n   if (s == e)\n      return;\n   int mid = (s + e) >> 1;\n   init2(index << 1, s, mid);\n   init2((index << 1) | 1, mid + 1, e);\n}\n\n// Inclusive s and e\nvoid ITInit(int s, int e) {\n   init2(1, s, e);\n}\n\nLLI fastExpo(LLI exp, LLI base, LLI mod) {\n    if (exp == 0)\n        return 1;\n    if (exp == 1)\n        return base % mod;\n    LLI tmp = fastExpo(exp >> 1, base, mod);\n    tmp *= tmp;\n    tmp %= mod; \n    if (exp & 1)\n        tmp = (tmp * base) % mod;\n    return tmp;\n}\n\n\nLLI aoMem[2][MAX + 10];\nLLI feMem[2][MAX + 10];\nvoid genAllOnes() {\n    int i;\n    LLI tmp1 = 0;\n    LLI tmp2 = 0;\n    LLI tmp3 = 1;\n    LLI tmp4 = 1;\n    fo3(i,0, MAX+9) {\n        aoMem[TRUE][i] = tmp1;\n        tmp1 = tmp1 * 10 + 1;\n        tmp1 %= h1;\n        aoMem[FALSE][i] = tmp2;\n        tmp2 = tmp2 * 10 + 1;\n        tmp2 %= h2;\n        feMem[TRUE][i] = tmp3;\n        tmp3 *= 10;\n        tmp3 %= h1;\n        feMem[FALSE][i] = tmp4;\n        tmp4 *= 10;\n        tmp4 %= h2;\n    }\n}\nLLI allOnes(int len, LLI mod) {\n    return aoMem[mod==h1][len];\n}\n\nLLI agg(int pre, int suf, int pow, LLI mod) {\n    LLI mult = feMem[mod==h1][pow];\n    mult *= suf;\n    mult += pre;\n    mult %= mod;\n    //printf(\" returning from agg!\\n\");\n    return mult;\n}\n\nvoid ITComp(int index) {\n    if (carry[index] == NULL_CARRY) {\n        ans[0][index] = agg(ans[0][index<<1], ans[0][(index<<1)|1], en[index<<1] - st[index<<1] + 1, h1);\n        ans[1][index] = agg(ans[1][index<<1], ans[1][(index<<1)|1], en[index<<1] - st[index<<1] + 1, h2);\n    } else {\n        ans[0][index] = allOnes(en[index] - st[index] + 1, h1) * carry[index];\n        ans[0][index] %= h1;\n        ans[1][index] = allOnes(en[index] - st[index] + 1, h2) * carry[index];\n        ans[1][index] %= h2;\n    }\n}\n\nvoid push(int index) {\n    if (carry[index] == NULL_CARRY)\n        return;\n    if (st[index] != en[index]) {\n        carry[index<<1] = carry[index];\n        ITComp(index<<1);\n        carry[(index<<1)|1] = carry[index];\n        ITComp((index<<1)|1);\n    }\n    carry[index] = NULL_CARRY;\n}\n\n\nvoid set2(int index, int s, int e, int value) {\n    if (st[index] >= s && e >= en[index]) {\n        carry[index] = value;\n        ITComp(index);\n        return;\n    }\n    if (st[index] > e || s > en[index])\n        return;\n    push(index);\n    set2(index<<1, s, e, value);\n    set2((index<<1)|1, s, e, value);\n    ITComp(index);\n}\n\nvoid ITSet(int s, int e, int value) {\n   set2(1, s, e, value);\n}\n\nLLI get2(int index, int type, int s, int e) {\n    if (st[index] >= s && e >= en[index]) {\n        //printf(\" Starting Push!\\n\");\n        //push(index);\n        ITComp(index);\n        //printf(\" Out of Push!\\n\");\n        if (type == 0) {\n            //prL(agg(0, ans[type][index], st[index] - s, h1));\n            return agg(0, ans[type][index], st[index] - s, h1);\n        }            \n        return agg(0, ans[type][index], st[index] - s, h2);\n    }\n    if (st[index] > e || s > en[index])\n        return NULL_VALUE;\n    push(index);\n    LLI ret = get2(index<<1, type, s, e) + get2((index<<1)|1, type, s, e);\n    if (type == 0 && ret >= h1)\n        ret -= h1;\n    if (type == 1 && ret >= h2)\n        ret -= h2;\n    return ret;\n}\n\nLLI get(int type, int s, int e) {\n   return get2(1, type, s, e);\n}\n\n#define MOD 1000000007\n\nLLI ch2(int x) {\n    return (x * (x - 1)) >> 1;\n}\n\nvoid make(int n, int spots, LLI ** mat) {\n    int i, j;\n    int totalSmaller = spots - 1;\n    int totalBigger = n - totalSmaller;\n    LLI total = ch2(n);\n    fo3(i,0,spots-1) {\n        fo3(j,0,spots-1) {\n            int smallerCorrect = i;\n            int smallerIncorrect = totalSmaller - smallerCorrect;\n            int biggerIncorrect = smallerIncorrect;\n            int biggerCorrect = totalBigger - biggerIncorrect;\n            if (i + 1 < j || j + 1 < i)\n                mat[i][j] = 0;\n            else if (i == j) {\n                mat[i][j] = (total - (smallerCorrect * biggerCorrect + smallerIncorrect * biggerIncorrect)) % MOD;\n            } else if (j < i) {\n                // Worse\n                mat[i][j] = (smallerCorrect * biggerCorrect) % MOD; \n            } else {\n                // Better\n                mat[i][j] = (smallerIncorrect * biggerIncorrect) % MOD; \n            }\n        }\n    }\n}\n\nLLI ** ident;\n\n\n\nvoid clean2(LLI ** mat, int dim) { \n    int i;\n    fo3(i,0,dim-1)\n        free(mat[i]);\n    free(mat);\n}\n\nLLI ** mult(LLI ** a, LLI ** b, int dim) {\n    LLI ** ret;\n    int i, j, k;\n    ret = calloc(dim, sizeof(LLI*));\n    fo3(i,0,dim-1){\n        ret[i] = calloc(dim, sizeof(LLI));\n        fo3(j,0,dim-1){\n            ret[i][j] = 0;\n            fo3(k,0,dim-1) {\n                ret[i][j] += (a[i][k] * b[k][j]) % MOD;\n            }\n            ret[i][j] %= MOD;\n        }\n    }\n    return ret;\n}\n\nLLI ** expo(LLI ** base, int pow, int dim) {\n    if (pow == 0) {\n        return mult(ident, ident, dim);\n    }\n    if (pow == 1) {\n        return mult(ident, base, dim);\n    }\n    LLI ** tmp = expo(base, pow >> 1, dim);\n    LLI ** tmp2 = mult(tmp, tmp, dim);\n    clean2(tmp, dim);\n    if (pow&1) {\n        tmp = mult(tmp2, base, dim);\n        clean2(tmp2, dim);\n        tmp2 = tmp;\n    }\n    return tmp2;\n}\n\nLLI expo2(LLI base, int pow) {\n    if (pow == 0)\n        return 1;\n    if (pow == 1)\n        return base % MOD;\n    LLI tmp = expo2(base, pow>>1);\n    tmp *= tmp;\n    tmp %= MOD;\n    if (pow&1) {\n        tmp *= base;\n        tmp %= MOD;\n    }\n    return tmp;\n}\n\n\nLLI inv(LLI val) {\n    if (val == 1)\n        return 1;\n    return MOD - ((MOD / val) * inv(MOD % val)) % MOD;\n}\n\nint main(void) {\n    LLI ** orig;\n    int len, pow, i, j;\n    in2(len, pow);\n    int arr[len];\n    int cs[2];\n    cs[0] = 0;\n    cs[1] = 0;\n    \n    fo3(i,1,len) {\n        in1(arr[i-1]);\n        cs[arr[i-1]]++;\n    }\n    int dim = cs[0] + 1;\n    if (cs[1] < cs[0])\n        dim = cs[1] + 1;\n    orig = calloc(dim, sizeof(LLI*));\n    fo3(i,0,dim-1)\n        orig[i] = calloc(dim, sizeof(LLI));\n    ident = calloc(dim, sizeof(LLI*));\n    fo3(i,0,dim-1){\n        ident[i] = calloc(dim, sizeof(LLI));\n        fo3(j,0,dim-1)\n            ident[i][j] = ((i==j) ? 1 : 0);\n    }\n    make(len, dim, orig);\n    \n    LLI ** ret = expo(orig, pow, dim);\n    clean2(orig, dim);\n    int wrong = 0;\n    fo3(i,0,cs[0]-1)\n        if (arr[i]!=0)\n            wrong++;\n    int cor = dim - wrong - 1;\n    LLI ans = ret[cor][dim - 1];\n    clean2(ret, dim);\n    LLI den = expo2(ch2(len), pow);\n    //prL(ans);\n    //prL(den);\n    ans *= inv(den);\n    ans %= MOD;\n    prL(ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "0eeab29380a027ddf1d9c9ee1759d9e5", "src_uid": "77f28d155a632ceaabd9f5a9d846461a", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define N\t100000\n#define M\t200000\n#define MD\t0x7fffffff\n\nunsigned int Z = 12345, X = 12345;\n\nint rand_() {\n\treturn (Z *= 3) >> 1;\n}\n\nlong long abs_(long long x) { return x > 0 ? x : -x; }\n\nlong long gcd(long long a, long long b) {\n\treturn b == 0 ? a : gcd(b, a % b);\n}\n\nlong long *ox[M], *oy[M]; int *oc[M], oo[M];\n\nint hash(long long x, long long y) {\n\treturn ((x % MD * X % MD + y) % MD + MD) % M;\n}\n\nvoid ht_add(long long x, long long y, int c) {\n\tint h = hash(x, y), o;\n\n\tfor (o = 0; o < oo[h]; o++)\n\t\tif (ox[h][o] == x && oy[h][o] == y) {\n\t\t\toc[h][o] += c;\n\t\t\treturn;\n\t\t}\n\to = oo[h]++;\n\tif (o >= 2 && (o & o - 1) == 0) {\n\t\tox[h] = (long long *) realloc(ox[h], o * 2 * sizeof *ox[h]);\n\t\toy[h] = (long long *) realloc(oy[h], o * 2 * sizeof *oy[h]);\n\t\toc[h] = (int *) realloc(oc[h], o * 2 * sizeof *oc[h]);\n\t}\n\tox[h][o] = x, oy[h][o] = y, oc[h][o] = c;\n}\n\nint ht_get(long long x, long long y) {\n\tint h = hash(x, y), o;\n\n\tfor (o = 0; o < oo[h]; o++)\n\t\tif (ox[h][o] == x && oy[h][o] == y)\n\t\t\treturn oc[h][o];\n\treturn 0;\n}\n\nlong long xx[N], yy[N];\n\ndouble cross(int i, int j) {\n\treturn (double) xx[i] * yy[j] - (double) xx[j] * yy[i];\n}\n\nint cmp(int i, int j) {\n\tint sign_i = xx[i] < 0 || xx[i] == 0 && yy[i] < 0, sign_j = xx[j] < 0 || xx[j] == 0 && yy[j] < 0;\n\tdouble c = cross(i, j);\n\n\treturn sign_i != sign_j ? sign_i - sign_j : (c != 0 ? (c < 0 ? -1 : 1) : i - j);\n}\n\nint bad(int i, int j) {\n\tdouble c = cross(i, j);\n\n\treturn c > 0 || c == 0 && i > j;\n}\n\nint zz[1 + N], ll[1 + N], rr[1 + N], kk[1 + N], u_, l_, r_;\n\nint node(int k) {\n\tstatic int _ = 1;\n\n\tzz[_] = rand_();\n\tkk[_] = k;\n\treturn _++;\n}\n\nvoid split(int u, int k) {\n\tint c;\n\n\tif (u == 0) {\n\t\tu_ = l_ = r_ = 0;\n\t\treturn;\n\t}\n\tc = cmp(kk[u], k);\n\tif (c < 0) {\n\t\tsplit(rr[u], k);\n\t\trr[u] = l_, l_ = u;\n\t} else if (c > 0) {\n\t\tsplit(ll[u], k);\n\t\tll[u] = r_, r_ = u;\n\t} else {\n\t\tu_ = u, l_ = ll[u], r_ = rr[u];\n\t\tll[u] = rr[u] = 0;\n\t}\n}\n\nint merge(int u, int v) {\n\tif (u == 0)\n\t\treturn v;\n\tif (v == 0)\n\t\treturn u;\n\tif (zz[u] < zz[v]) {\n\t\trr[u] = merge(rr[u], v);\n\t\treturn u;\n\t} else {\n\t\tll[v] = merge(u, ll[v]);\n\t\treturn v;\n\t}\n}\n\nint first(int u) {\n\treturn ll[u] == 0 ? u : first(ll[u]);\n}\n\nint last(int u) {\n\treturn rr[u] == 0 ? u : last(rr[u]);\n}\n\nint kbad;\n\nvoid tr_add(int i) {\n\tif (u_ == 0)\n\t\tu_ = node(i);\n\telse {\n\t\tint l, r;\n\n\t\tsplit(u_, i);\n\t\tl = kk[l_ ? last(l_) : last(r_)], r = kk[r_ ? first(r_) : first(l_)];\n\t\tkbad += bad(l, i) + bad(i, r) - bad(l, r);\n\t\tu_ = merge(merge(l_, node(i)), r_);\n\t}\n}\n\nvoid tr_remove(int i) {\n\tif (ll[u_] == 0 && rr[u_] == 0)\n\t\tu_ = 0;\n\telse {\n\t\tint l, r;\n\n\t\tsplit(u_, i);\n\t\tl = kk[l_ ? last(l_) : last(r_)], r = kk[r_ ? first(r_) : first(l_)];\n\t\tkbad -= bad(l, i) + bad(i, r) - bad(l, r);\n\t\tu_ = merge(l_, r_);\n\t}\n}\n\nint main() {\n\tint n, q, h, x0, y0, z0, w0, k1;\n\tlong long k2;\n\n\tscanf(\"%d%d%d%d\", &x0, &y0, &z0, &q), w0 = x0 + y0 + z0;\n\tfor (h = 0; h < M; h++) {\n\t\tox[h] = (long long *) malloc(2 * sizeof *ox[h]);\n\t\toy[h] = (long long *) malloc(2 * sizeof *oy[h]);\n\t\toc[h] = (int *) malloc(2 * sizeof *oc[h]);\n\t}\n\tn = 0, k1 = 0, k2 = 0, kbad = 0;\n\twhile (q--) {\n\t\tstatic char s[2];\n\n\t\tscanf(\"%s\", s);\n\t\tif (s[0] == 'A') {\n\t\t\tint x, y, z, w;\n\t\t\tlong long x_, y_, d;\n\n\t\t\tscanf(\"%d%d%d\", &x, &y, &z), w = x + y + z;\n\t\t\tx_ = (long long) x * w0 - (long long) x0 * w;\n\t\t\ty_ = (long long) y * w0 - (long long) y0 * w;\n\t\t\td = gcd(abs_(x_), abs_(y_));\n\t\t\tif (d != 0)\n\t\t\t\tx_ /= d, y_ /= d;\n\t\t\txx[n] = x_, yy[n] = y_, n++;\n\t\t\tif (xx[n - 1] == 0 && yy[n - 1] == 0)\n\t\t\t\tk1++;\n\t\t\telse {\n\t\t\t\tk2 += ht_get(-x_, -y_);\n\t\t\t\tht_add(x_, y_, 1);\n\t\t\t\ttr_add(n - 1);\n\t\t\t}\n\t\t} else {\n\t\t\tint i;\n\n\t\t\tscanf(\"%d\", &i), i--;\n\t\t\tif (xx[i] == 0 && yy[i] == 0)\n\t\t\t\tk1--;\n\t\t\telse {\n\t\t\t\tht_add(xx[i], yy[i], -1);\n\t\t\t\tk2 -= ht_get(-xx[i], -yy[i]);\n\t\t\t\ttr_remove(i);\n\t\t\t}\n\t\t}\n\t\tprintf(k1 > 0 ? \"1\\n\" : (k2 > 0 ? \"2\\n\" : ((ll[u_] || rr[u_]) && kbad == 0 ? \"3\\n\" : \"0\\n\")));\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "014592d0eb9575995ae4fabe17c461d5", "src_uid": "ea995d5c5fe84cd175cda0d0e2f01889", "difficulty": 2900.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\nint main() {\n\tint n, e, o;\n\n\tscanf(\"%d\", &n);\n\tif (n <= 5) {\n\t\tprintf(n == 3 ? \"0\\n\" : \"1\\n\");\n\t\treturn 0;\n\t}\n\te = 4, o = 5;\n\tif (e < n && o < n) {\n\t\tint o_ = e + e + 1;\n\t\tint e_ = e + o + 1;\n\n\t\te = e_, o = o_;\n\t\tif (e == n || o == n) {\n\t\t\tprintf(\"1\\n\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\"0\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d0e8d9753bbf56077e10be7cec0e2ed2", "src_uid": "821409c1b9bdcd18c4dcf35dc5116501", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\n#define MOD 998244353\nint fact[1000006];\n\nint mul(int a, int b){\n  return (a*1ll*b)%MOD;\n}\n\nint powmod(int p, int b){\n  int t = 1;\n  while(p){\n    if(b&1)t = mul(t, b);\n    b = mul(b, b);\n    p>>=1;\n  }\n  return t;\n}\n\nint ncr(int n, int r){\n  return mul(mul(fact[n], powmod(fact[r], MOD - 2)), powmod(fact[n - r], MOD - 2));\n}\n\n\nint main(){\n  int n, levels, i;\n  scanf(\"%d\", &n);\n  fact[0]  = 0;\n  for(i = 1;i < 1000006;i++)fact[i] = mul(fact[i - 1], i);\n  if(n == 1 || n == 2 || n == 4 || n == 5 ){printf(\"1\\n\");return 0;}\n  if(n == 3 || n == 6 || n == 7){printf(\"0\\n\");return 0;}\n  for(levels = 0; (1<<levels) - 1 < n;levels++);\n  levels -= 2;\n  int lcls = (1<<(levels - 1));\n  int rcls = lcls;\n  int left = n + 1 - (1<<(levels + 1));\n  left -= rcls;\n  if(left < 0 || left&1 || left > rcls){printf(\"0\\n\");return  0;}\n  printf(\"%d\\n\", ncr(lcls, left/2));\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d19f39494e0ec77f40d49b7a38b3b44b", "src_uid": "821409c1b9bdcd18c4dcf35dc5116501", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\n#define MOD 998244353\nint fact[1000006];\n\nint mul(int a, int b){\n  return (a*1ll*b)%MOD;\n}\n\nint powmod(int p, int b){\n  int t = 1;\n  while(p){\n    if(b&1)t = mul(t, b);\n    b = mul(b, b);\n    p>>=1;\n  }\n  return t;\n}\n\nint ncr(int n, int r){\n  return mul(mul(fact[n], powmod(fact[r], MOD - 2)), powmod(fact[n - r], MOD - 2));\n}\n\n\nint main(){\n  int n, levels, i;\n  scanf(\"%d\", &n);\n  fact[0]  = 0;\n  for(i = 1;i < 1000006;i++)fact[i] = mul(fact[i - 1], i);\n  if(n == 1 || n == 2 || n == 4 || n == 5 ){printf(\"1\\n\");return 0;}\n  if(n == 3 || n == 6 || n == 7){printf(\"0\\n\");return 0;}\n  for(levels = 0; (1<<levels) - 1 < n;levels++);\n  levels -= 2;\n  int lcls = (1<<(levels - 1));\n  int rcls = lcls;\n  int left = n + 1 - (1<<(levels + 1));\n  left -= rcls;\n  if(left < 0 || left&1 || left/2 > rcls){printf(\"0\\n\");return  0;}\n  printf(\"%d\\n\", ncr(lcls, left/2));\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d1516d2a946d433d311e817202b9fe5c", "src_uid": "821409c1b9bdcd18c4dcf35dc5116501", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n\n#define MOD 998244353\nint fact[1000006], wpar[1000006<<1], n, level;\n\nint mul(int a, int b){\n  return (a*1ll*b)%MOD;\n}\n\nint powmod(int b, int p){\n  int t = 1;\n  while(p){\n    if(p&1)t = mul(t, b);\n    b = mul(b, b);\n    p>>=1;\n  }\n  return t;\n}\n\nint ncr(int _n, int r){\n  return mul(mul(fact[_n], powmod(fact[r], MOD - 2)), powmod(fact[_n - r], MOD - 2));\n}\n\nvoid dfs(int x, int bits){\n  if(bits > level) return;\n  int l, r;\n  l = x<<1;\n  r = l|1;\n  if(x&1){\n    // x is a right child\n    wpar[l] = 1;\n    wpar[r] = 1^wpar[x]^wpar[l];\n  } else {\n    // x is a left child\n    wpar[r] = 0;\n    wpar[l] = 1^wpar[x]^wpar[r];\n  }\n  dfs(l, bits + 1);\n  dfs(r, bits + 1);\n}\n\nint getpossib(int lparity){\n  int i, rem;\n  wpar[2] = lparity;\n  wpar[3] = 1^wpar[1]^wpar[2];\n  dfs(2, 2);dfs(3, 2);\n\n  rem = n - (1<<level) + 1;\n\n  for(i = (1<<(level - 1));i < (1<<level);i++){\n    //    printf(\"wpar[%d]: %d\\n\", i, wpar[i]);\n    if(i&1){\n      if(wpar[i]) return 0;\n      rem--;\n    } else {\n      if(1^wpar[i]) rem--;\n    }\n  }\n  return rem == 0;\n}\n\nint main(){\n  int i;\n  scanf(\"%d\", &n);\n  \n  fact[0] = 1;\n  for(i = 1;i < 1000006;i++)fact[i] = mul(fact[i - 1], i);\n  \n  if(n == 1 || n == 2){printf(\"1\\n\");return 0;}\n  if(n == 3){printf(\"0\\n\");return 0;}\n  \n  for(level = 0; (1<<level) - 1 < n;level++);\n  level--;\n\n  wpar[1] = n&1;\n  printf(\"%d\\n\", getpossib(0) + getpossib(1));\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e73b412e86eaad4f2c156681f7e3f8a7", "src_uid": "821409c1b9bdcd18c4dcf35dc5116501", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\nint main() {\n\tint n, e, o;\n\n\tscanf(\"%d\", &n);\n\tif (n <= 5) {\n\t\tprintf(n == 3 ? \"0\\n\" : \"1\\n\");\n\t\treturn 0;\n\t}\n\te = 4, o = 5;\n\twhile (e < n && o < n) {\n\t\tint o_ = e + e + 1;\n\t\tint e_ = e + o + 1;\n\n\t\te = e_, o = o_;\n\t\tif (e == n || o == n) {\n\t\t\tprintf(\"1\\n\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\"0\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "366dc082ba742c3f203e7daa39210779", "src_uid": "821409c1b9bdcd18c4dcf35dc5116501", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int a[6] = {0}, b[7] = {0};\n    char s[7];\n    int i;\n\n    scanf(\"%s\", s);\n\n    for (i = 0; i < 6; i++) {\n\tswitch (s[i]) {\n\tcase 'R' : a[0]++; break;\n\tcase 'O' : a[1]++; break;\n\tcase 'Y' : a[2]++; break;\n\tcase 'G' : a[3]++; break;\n\tcase 'B' : a[4]++; break;\n\tcase 'V' : a[5]++; break;\n\t}\n    }\n\n    for (i = 0; i < 6; i++) b[a[i]]++;\n\n    if (b[6] == 1 || b[5] == 1) {\n\tputs(\"1\");\n    } else if (b[4] == 1 || b[3] == 2) {\n\tputs(\"2\");\n    } else if (b[3] == 1) {\n\tif (b[2] == 1) {\n\t    puts(\"3\");\n\t} else {\n\t    puts(\"5\");\n\t}\n    } else if (b[2] == 3) {\n\tputs(\"6\");\n    } else if (b[2] == 2) {\n\tputs(\"8\");\n    } else if (b[2] == 1) {\n\tputs(\"15\");\n    } else {\n\tputs(\"30\");\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "dac10b5f87c016fec6514bb70342c943", "src_uid": "8176c709c774fa87ca0e45a5a502a409", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nint color[6];\nint main(void)\n{\n  int i,one,two,three,four,five,six;\n  char ch[10];\n  while(scanf(\"%s\",ch)!=EOF)\n  {\n    for(i=0;i<6;++i) color[i]=0;\n    for(i=0;i<6;++i)\n    {\n      switch(ch[i])\n      {\n        case 'R': ++color[0];break;\n        case 'O': ++color[1];break;\n        case 'Y': ++color[2];break;\n        case 'G': ++color[3];break;\n        case 'B': ++color[4];break;\n        case 'V': ++color[5];break;\n      }\n    }\n    for(i=one=two=three=four=five=six=0;i<6;++i)\n    {\n      switch(color[i])\n      {\n        case 1: ++one;break;\n        case 2: ++two;break;\n        case 3: ++three;break;\n        case 4: ++four;break;\n        case 5: ++five;break;\n        case 6: ++six;break;\n      }\n    }\n    if(one==6) puts(\"30\");\n    else if(one==4) puts(\"15\");\n    else if(one==3) puts(\"5\");\n    else if(one==2)\n    {\n      if(four==1) puts(\"2\");\n      else puts(\"8\");\n    }\n    else if(one==1)\n    {\n      if(five==1) puts(\"1\");\n      else puts(\"3\");\n    }\n    else\n    {\n      if(six==1) puts(\"1\");\n      else\n      {\n        if(two==1&&four==1) puts(\"2\");\n        else if(three==2) puts(\"2\");\n        else if(two==3) puts(\"6\");\n      }\n    }\n  }\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e5394e045227d435be41b4aa21938210", "src_uid": "8176c709c774fa87ca0e45a5a502a409", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n#include<math.h>\n#include<string.h>\n#define REP(i,a,b) for(i=a;i<b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint SixSidedDieState[24][3]={\n  0,1,2,  0,2,4,  0,4,3,  0,3,1,\n  1,5,2,  1,2,0,  1,0,3,  1,3,5,\n  2,1,5,  2,5,4,  2,4,0,  2,0,1,\n  3,1,0,  3,0,4,  3,4,5,  3,5,1,\n  4,0,2,  4,2,5,  4,5,3,  4,3,0,\n  5,3,4,  5,4,2,  5,2,1,  5,1,3\n};\n\nint SixSidedDieRotateCenter[24]={\n   1, 2, 3, 0,\n   5, 6, 7, 4,\n   9,10,11, 8,\n  13,14,15,12,\n  17,18,19,16,\n  21,22,23,20\n};\n\nint SixSidedDieRotateRight[24]={\n  12, 5,10,19,\n  15,22,11, 3,\n   0, 4,21,16,\n  23, 6, 2,18,\n  13, 1, 9,20,\n   7,14,17, 8\n};\n\nint SixSidedDieRotateLeft[24]={\n  16,13, 6,11,\n   0,12,23, 8,\n  17, 1, 5,22,\n  19,20, 7, 3,\n  21,14, 2,10,\n   9, 4,15,18\n};\n\n\nint die[24][6],center[24],right[24],left[24],center3[24],right3[24],left3[24];\nvoid dieInit(){\n  int i,j;\n  rep(i,24){\n    rep(j,3) die[i][j] = SixSidedDieState[i][j];\n    REP(j,3,6) die[i][j] = 5-SixSidedDieState[i][5-j];\n    center[i] = SixSidedDieRotateCenter[i];\n    right[i]  = SixSidedDieRotateRight[i];\n    left[i]   = SixSidedDieRotateLeft[i];\n  }\n  rep(i,24){\n    center3[i]= center[center[center[i]]];\n    right3[i] = right[right[right[i]]];\n    left3[i]  = left[left[left[i]]];\n  }\n}\n\n#define ll long long\n#define ull unsigned ll\n\n#define ULL_HASH_SIZE 2000\null ull_hash_n[ULL_HASH_SIZE]; int ull_hash_d[ULL_HASH_SIZE];\n\nvoid ullHashClear(void){ memset(ull_hash_d,0,ULL_HASH_SIZE*sizeof(int)); }\nint ullHashFunction(ull a){ return (a*1007)%ULL_HASH_SIZE; }\n\nint ullHashGet(ull a){\n  int i=ullHashFunction(a);\n  for(;;){\n    if(ull_hash_n[i]==a && ull_hash_d[i]) break;\n    if(!ull_hash_d[i]) break;\n    i++; if(i==ULL_HASH_SIZE) i=0;\n  }\n  if(ull_hash_n[i]!=a) return 0; return ull_hash_d[i];\n}\n\nvoid ullHashSet(ull a,int n){\n  int i=ullHashFunction(a);\n  for(;;){\n    if(ull_hash_n[i]==a && ull_hash_d[i]) break;\n    if(!ull_hash_d[i]) break;\n    i++; if(i==ULL_HASH_SIZE) i=0;\n  }\n  ull_hash_n[i]=a; ull_hash_d[i]=n;\n}\n\nint ullHashIncrease(ull a){\n  int i=ullHashFunction(a);\n  for(;;){\n    if(ull_hash_n[i]==a && ull_hash_d[i]) break;\n    if(!ull_hash_d[i]) break;\n    i++; if(i==ULL_HASH_SIZE) i=0;\n  }\n  ull_hash_n[i]=a; return ++ull_hash_d[i];\n}\n\nvoid intSort(int d[],int s){int i=-1,j=s,k,t;if(s<=1)return;k=(d[0]+d[s-1])/2;for(;;){while(d[++i]<k);while(d[--j]>k);if(i>=j)break;t=d[i];d[i]=d[j];d[j]=t;}intSort(d,i);intSort(d+j+1,s-j-1);}\nvoid intReverse(int d[],int size){int a=0,b=size-1,t;while(a<b)t=d[a],d[a]=d[b],d[b]=t,a++,b--;}\nint intNextPermutation(int d[],int size){int i,j,k;for(k=size-2;k>=0;k--)if(d[k]<d[k+1])break;if(k<0){intReverse(d,size);return 0;}for(i=size-1;;i--)if(d[i]>d[k])break;j=d[i],d[i]=d[k],d[k]=j;intReverse(d+k+1,size-k-1);return 1;}\n\nint main(){\n  int i,j,k,l,m,n;\n  int res;\n  char tmp[10];\n  int in[10], go[10];\n  ull hs, mx;\n\n  dieInit();\n  while(scanf(\"%s\",tmp)==1){\n    ullHashClear();\n    res = 0;\n\n    rep(i,6) in[i] = tmp[i];\n    intSort(in,6);\n\n    do{\n      mx = 0;\n      rep(i,24){\n        rep(k,6) go[k] = in[die[i][k]];\n        hs = 0;\n        rep(k,6) hs = hs * 1007 + go[k];\n        if(mx < hs) mx = hs;\n      }\n      if( ullHashIncrease(mx)==1 ) res++;\n    }while(intNextPermutation(in,6));\n\n    printf(\"%d\\n\",res);\n  }\n\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c12f982ebb31481fe25700a2d0112c92", "src_uid": "8176c709c774fa87ca0e45a5a502a409", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int a[6] = {0}, b[7] = {0};\n    char s[7];\n    int i;\n\n    scanf(\"%s\", s);\n\n    for (i = 0; i < 6; i++) {\n\tswitch (s[i]) {\n\tcase 'R' : a[0]++; break;\n\tcase 'O' : a[1]++; break;\n\tcase 'Y' : a[2]++; break;\n\tcase 'G' : a[3]++; break;\n\tcase 'B' : a[4]++; break;\n\tcase 'V' : a[5]++; break;\n\t}\n    }\n\n    for (i = 0; i < 6; i++) b[a[i]]++;\n\n    if (b[6] == 1 || b[5] == 1) {\n\tputs(\"1\");\n    } else if (b[4] == 1 || b[3] == 2) {\n\tputs(\"2\");\n    } else if (b[3] == 1) {\n\tif (b[2] == 1) {\n\t    puts(\"3\");\n\t} else {\n\t    puts(\"5\");\n\t}\n    } else if (b[2] == 3) {\n\tputs(\"6\");\n    } else if (b[2] == 2) {\n\tputs(\"8\");\n    } else if (b[2] == 1) {\n\tputs(\"15\");\n    } else {\n\tputs(\"30\");\n    }\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "06006342d49c5cea1627fdf8638a6076", "src_uid": "8176c709c774fa87ca0e45a5a502a409", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n  int num[6];\n  char ans[6];\n  char t[7];\n  int n,i,j,temp;\n  \n  scanf(\"%s\",&t);\n  n=0;\n  for(i=0;i<6;i++)num[i]=0;\n  for(i=0;i<6;i++)\n     {\n      for(j=0;j<n;j++)\n         {\n          if(ans[j]==t[i])break;\n         }\n      num[j]++;\n      if(j==n)ans[n++]=t[i];\n     }\n  \n  for(i=0;i<n;i++)\n     {\n      for(j=i+1;j<n;j++)\n         {\n          if(num[j]>num[i])\n             {\n              temp=num[j];\n              num[j]=num[i];\n              num[i]=temp;\n             }\n         }\n     }\n  if(n==6)\n     {\n      puts(\"30\");\n     }\n  else if(n==1)\n     {\n      puts(\"1\");\n     }\n  else if(n==5)\n     {\n      puts(\"15\");\n     }\n  else if(n==4)\n     {\n      if(num[0]==3)puts(\"5\");\n      else puts(\"8\");\n     }\n  else if(n==3)\n     {\n      if(num[0]==4)puts(\"2\");\n      else if(num[0]==2)puts(\"6\");\n      else puts(\"3\");\n     }\n  else\n     {\n      if(num[0]==5)puts(\"1\");\n      else puts(\"2\");\n     }\n  system(\"PAUSE\");\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "4a5be8643bdc82cf4bc02fcec7dc3937", "src_uid": "8176c709c774fa87ca0e45a5a502a409", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<math.h>\n#define sqr(x) ((x)*(x))\n#define m0(x) memset(x,0,sizeof(x))\n#define m1(x) memset(x,63,sizeof(x))\n#define M 1000000007\n#define N 211111\n\n#define maxN 555\n\nint n, k;\nint dp[maxN][maxN], dp2[maxN][maxN];\nint w[maxN];\n\nint add(int x, int y) {\n\tx += y;\n\tif (x >= M) x-= M;\n\treturn (x);\n}\n\nint min(int a, int b)\n\t{\n\t\tif(a<b)return a;\n\t\telse return b;\n\t}\n\nint main(){\n\tscanf(\"%d %d\", &n, &k);\n\tw[0] = 1;\n\tint i,j,d;\n\tfor ( i = 1; i <= n; i++) w[i] = w[i - 1] * 2 % M;\n\tdp[0][0] = 1;\n\tfor ( i = 0; i < n; i++) {\n\t\tfor ( j = 0; j <= n; j++) for ( d = 0; d <= k + 1; d++) dp2[j][d] = 0;\n\t\tfor ( j = 0; j <= n; j++) for ( d = 0; d <= k + 1; d++) if (dp[j][d] > 0) {\n\t\t\tif (j > i) {\n\t\t\t\tint e = i + 1;\n\t\t\t\tint z = dp[j][d] * 1ll * w[e] % M;\n\t\t\t\tdp2[j][d]=(dp2[j][d], z);\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tint z = (w[i - j + 1] - 1 + M);\n\t\t\tif (z >= M) z -= M;\n\t\t\tz = z * 1ll * w[j] % M;\n\t\t\tz = z * 1ll * dp[j][d] % M;\n\t\t\tdp2[i + 1][min(d + 1, k + 1)]=add(dp2[i + 1][min(d + 1, k + 1)], z);\n\t\t\tz = dp[j][d] * 1ll * w[j] % M;\n\t\t\tdp2[j][d]=add(dp2[j][d], z);\n\t\t}\n\t\tfor ( j = 0; j <= n; j++) for (d = 0; d <= k + 1; d++) dp[j][d] = dp2[j][d];\n\t}\n\tint ans = 0;\n\tfor ( i = 0; i <= n; i++) ans=add(ans, dp[i][k]);\n\tprintf(\"%d\\n\",ans);\n\treturn 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "563415f47fe05503573ede7dcd94e0d6", "src_uid": "111673158df2e37ac6c019bb99225ccb", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#define M 510\n#define ll long long int\nll mod=1000000007;\nll f[M][M];\nll pp[1000000];\nll ans;\nint n,k;\nvoid prepare(){\n    ll cnt;\n    int i,j;\n    pp[0]=1;\n    for(i=1;i<1000000;i++)pp[i]=(pp[i-1]*2)%mod;\n    for(i=0;i<=500;i++)f[i][0]=1;\n    for(n=1;n<=500;n++)for(k=1;k<=n;k++){\n        for(j=k;j<=n;j++){\n            cnt=(pp[j*(n-j+1)]-pp[(j-1)*(n-j+1)]+mod)%mod;\n            cnt=(f[j-1][k-1]*cnt)%mod;\n            f[n][k]=(f[n][k]+cnt);\n        }\n        f[n][k]%=mod;\n    }\n}\nint main(){\n    int i,j;\n    prepare();\n    scanf(\"%d %d\",&n,&k);\n    printf(\"%lld\\n\",f[n][k]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "413d2515b5d43a6d8fc7ca8dd4c97de6", "src_uid": "111673158df2e37ac6c019bb99225ccb", "difficulty": 2500.0}
{"lang": "GNU C", "source_code": "#include    <stdio.h>\n#include   <stdlib.h>\n#include   <string.h>\n\n\n#define  maxn 505\n#define  P 1000000007\n\nint n, k, mi2[maxn * maxn], dp[maxn][maxn], ans = 0;\nint main() {\n    scanf(\"%d%d\", &n, &k);\n    int i,j,l;\n    memset(dp, 0, sizeof(dp));\n    dp[0][0] = 1, mi2[0] = 1;\n\n    for (i = 1; i <= n * n; i++)    mi2[i] = 2ll * mi2[i - 1] % P;\n\n    for (i = 1; i <= n; i ++)\n        for ( j = 1; j <= k; j ++)\n            for (l = 0; l < i; l ++)\n                dp[i][j] = (dp[i][j] + 1ll * dp[l][j - 1] * (mi2[i - l] - 1) % P * mi2[(i - l) * l] % P) % P;\n    for (i = 0; i <= n; i ++)\n        ans = (ans + 1ll * dp[i][k] * mi2[(n - i) * i]) % P;\n    printf(\"%d\\n\", (ans + P) % P);\n\n      return 0;\n\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7dd8e95c0266c557cba5d10ddd6944ea", "src_uid": "111673158df2e37ac6c019bb99225ccb", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <math.h>\n#define N 1000007\n#define M 1000000007\ntypedef long long ll;\nll n, b = 1, dp[2][N][2];\nint main()\n{\n\tscanf(\"%I64d\", &n);\n\tll v = 1 << (ll)log2(n), u = v / 2 * 3;\n\tfor (dp[0][1][0] = 1, dp[0][1][1] = u <= n; u >>= 1, v >>= 1, v >= 1; b ^= 1)\n\t\tfor (ll j = 1, w = n / v, x = n / (v * 2), y = n / (v * 3), z = n / u; j <= w; ++j)\n\t\t\tdp[b][j][0] = (dp[b][j - 1][0] * (w - (j - 1)) % M + dp[b ^ 1][j - 1][0] * (w - x) % M + dp[b ^ 1][j - 1][1] * (w - y) % M) % M,\n\t\t\tdp[b][j][1] = (dp[b][j - 1][1] * (z - (j - 1)) % M + dp[b ^ 1][j - 1][1] * (z - y) % M) % M;\n\tprintf(\"%I64d\", dp[b ^ 1][n][0]);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "1776633b8c456a8835fd78b2ace296b9", "src_uid": "b2d59b1279d891dba9372a52364bced2", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define L\t19\n#define MD\t1000000007\n\nint main() {\n\tstatic int dp[L + 1], dq[L + 1], dp0[L], dq0[L], dp1[L], dq1[L];\n\tint n, i, j, kj, kj_, l, ans;\n\n\tscanf(\"%d\", &n);\n\tl = 0;\n\twhile (1 << (l + 1) <= n)\n\t\tl++;\n\tans = 0;\n\tdp[l] = 1;\n\tfor (i = 1; i < n; i++) {\n\t\tfor (j = 0; j <= l; j++)\n\t\t\tif (dp[j]) {\n\t\t\t\tkj = n >> j;\n\t\t\t\tdq[j] = (dq[j] + (long long) dp[j] * ((n >> j) - i)) % MD;\n\t\t\t\tif (j > 0) {\n\t\t\t\t\tkj_ = n >> (j - 1);\n\t\t\t\t\tdq[j - 1] = (dq[j - 1] + (long long) dp[j] * (kj_ - kj)) % MD;\n\t\t\t\t}\n\t\t\t}\n\t\tfor (j = 0; j <= l; j++)\n\t\t\tdp[j] = dq[j], dq[j] = 0;\n\t}\n\tans = (ans + dp[0]) % MD;\n\tif ((1 << (l - 1)) * 3 <= n) {\n\t\tdp1[l - 1] = 1;\n\t\tfor (i = 1; i < n; i++) {\n\t\t\tfor (j = 0; j < l; j++) {\n\t\t\t\tif (dp0[j]) {\n\t\t\t\t\tkj = n >> j;\n\t\t\t\t\tdq0[j] = (dq0[j] + (long long) dp0[j] * (kj - i)) % MD;\n\t\t\t\t\tif (j > 0) {\n\t\t\t\t\t\tkj_ = n >> (j - 1);\n\t\t\t\t\t\tdq0[j - 1] = (dq0[j - 1] + (long long) dp0[j] * (kj_ - kj)) % MD;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (dp1[j]) {\n\t\t\t\t\tkj = (n >> j) / 3;\n\t\t\t\t\tdq1[j] = (dq1[j] + (long long) dp1[j] * (kj - i)) % MD;\n\t\t\t\t\tif (j > 0) {\n\t\t\t\t\t\tkj_ = (n >> (j - 1)) / 3;\n\t\t\t\t\t\tdq1[j - 1] = (dq1[j - 1] + (long long) dp1[j] * (kj_ - kj)) % MD;\n\t\t\t\t\t}\n\t\t\t\t\tkj_ = n >> j;\n\t\t\t\t\tdq0[j] = (dq0[j] + (long long) dp1[j] * (kj_ - kj)) % MD;\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor (j = 0; j < l; j++) {\n\t\t\t\tdp0[j] = dq0[j], dq0[j] = 0;\n\t\t\t\tdp1[j] = dq1[j], dq1[j] = 0;\n\t\t\t}\n\t\t}\n\t\tans = (ans + dp0[0]) % MD;\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "5dd4b860f08131c37b07581c0bd260fc", "src_uid": "b2d59b1279d891dba9372a52364bced2", "difficulty": 2500.0}
{"lang": "GNU C11", "source_code": "/* upsolve with Dukkha */\n#include <stdio.h>\n\n#define N\t1000000\n#define MD\t1000000007\n\nlong long ff[N], gg[N], pn[N], pm[N];\n\nlong long power(long long a, int k) {\n\tlong long p;\n\n\tif (k == 0)\n\t\treturn 1;\n\tp = power(a, k / 2);\n\tp = p * p % MD;\n\tif (k % 2)\n\t\tp = p * a % MD;\n\treturn p;\n}\n\nvoid init(int n, int m) {\n\tlong long f, p;\n\tint i;\n\n\tf = 1;\n\tfor (i = 0; i < N; i++) {\n\t\tff[i] = f;\n\t\tgg[i] = power(f, MD - 2);\n\t\tf = f * (i + 1) % MD;\n\t}\n\tp = 1;\n\tfor (i = 0; i < n; i++) {\n\t\tpn[i] = p;\n\t\tp = p * n % MD;\n\t}\n\tp = 1;\n\tfor (i = 0; i < n; i++) {\n\t\tpm[i] = p;\n\t\tp = p * m % MD;\n\t}\n}\n\nlong long cayley(int n, int k) {\n\treturn k == n ? 1 : k * pn[n - k - 1] % MD;\n}\n\nint main() {\n\tint n, m, a, b, k;\n\tlong long ans;\n\n\tscanf(\"%d%d%d%d\", &n, &m, &a, &b);\n\tinit(n, m);\n\tans = 0;\n\tfor (k = 0; k <= n - 2 && k < m; k++) {\n\t\t/* choose(n - 2, k) * factorial(k) */\n\t\tlong long path = ff[n - 2] * gg[n - 2 - k] % MD;\n\t\t/* choose(m - 1, k) * power(m, n - k - 2) */\n\t\tlong long edges = ff[m - 1] % MD * gg[k] % MD * gg[m - 1 - k] % MD\n\t\t\t* pm[n - k - 2] % MD;\n\n\t\tans = (ans + path * cayley(n, k + 2) % MD * edges) % MD;\n\t}\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1204958630a969294efba772839aeb7f", "src_uid": "728fe302b8b18e33f15f6e702e332cde", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "/* upsolve with Dukkha */\n#include <stdio.h>\n\n#define N\t100000\n#define MD\t1000000007\n\nlong long power(long long a, int k) {\n\tlong long p;\n\n\tif (k == 0)\n\t\treturn 1;\n\tp = power(a, k / 2);\n\tp = p * p % MD;\n\tif (k % 2)\n\t\tp = p * a % MD;\n\treturn p;\n}\n\nlong long cayley(int n, int k) {\n\treturn k == n ? 1 : k * power(n, n - k - 1) % MD;\n}\n\nint main() {\n\tstatic long long ff[N], gg[N];\n\tint n, m, a, b, k, i;\n\tlong long f, ans;\n\n\tscanf(\"%d%d%d%d\", &n, &m, &a, &b);\n\tf = 1;\n\tfor (i = 0; i < N; i++) {\n\t\tff[i] = f;\n\t\tgg[i] = power(f, MD - 2);\n\t\tf = f * (i + 1) % MD;\n\t}\n\tans = 0;\n\tfor (k = 0; k <= n - 2 && k < m; k++) {\n\t\t/* choose(n - 2, k) * factorial(k) */\n\t\tlong long path = ff[n - 2] * gg[n - 2 - k] % MD;\n\t\t/* choose(m - 1, k) * power(m, n - k - 2) */\n\t\tlong long edges = ff[m - 1] % MD * gg[k] % MD * gg[m - 1 - k] % MD\n\t\t\t* power(m, n - k - 2) % MD;\n\n\t\tans = (ans + path * cayley(n, k + 2) % MD * edges) % MD;\n\t}\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9645a8c7b741f9ccce59bd549ef8238b", "src_uid": "728fe302b8b18e33f15f6e702e332cde", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t2021\n#define M\t2021\n#define MD\t998244353\n\nint vv[N + M + 1], ff[N + M + 1], gg[N + M + 1];\n\nvoid init() {\n\tint i;\n\n\tff[0] = gg[0] = 1;\n\tfor (i = 1; i <= N + M; i++) {\n\t\tvv[i] = i == 1 ? 1 : (long long) vv[i - MD % i] * (MD / i + 1) % MD;\n\t\tff[i] = (long long) ff[i - 1] * i % MD;\n\t\tgg[i] = (long long) gg[i - 1] * vv[i] % MD;\n\t}\n}\n\nint choose(int n, int k) {\n\treturn k < 0 || k > n ? 0 : (long long) ff[n] * gg[k] % MD * gg[n - k] % MD;\n}\n\nint main() {\n\tstatic int xx[N][M], dp[N], dq[N];\n\tint n, m, i, j, x, ans;\n\n\tinit();\n\tscanf(\"%d%d\", &n, &m);\n\tfor (i = 0; i < n; i++)\n\t\tfor (j = 0; j < m; j++)\n\t\t\txx[i][j] = choose(i + j, j);\n\tans = 0;\n\tfor (j = 1; j < m; j++) {\n\t\tx = 0;\n\t\tfor (i = 0; i < n; i++) {\n\t\t\tif ((x += xx[i][j - 1]) >= MD)\n\t\t\t\tx -= MD;\n\t\t\tdp[i] = (long long) x * xx[n - 1 - i][j - 1] % MD;\n\t\t}\n\t\tx = 0;\n\t\tfor (i = n - 1; i >= 0; i--) {\n\t\t\tif ((x += xx[n - 1 - i][m - j - 1]) >= MD)\n\t\t\t\tx -= MD;\n\t\t\tdq[i] = (long long) x * xx[i][m - j - 1] % MD;\n\t\t}\n\t\tfor (i = 1; i < n; i++)\n\t\t\tif ((dp[i] += dp[i - 1]) >= MD)\n\t\t\t\tdp[i] -= MD;\n\t\tfor (i = 0; i + 1 < n; i++)\n\t\t\tif ((ans += (long long) dp[i] * dq[i + 1] % MD) >= MD)\n\t\t\t\tans -= MD;\n\t\tx = 0;\n\t\tfor (i = 0; i < n; i++) {\n\t\t\tif ((x += xx[i][m - j - 1]) >= MD)\n\t\t\t\tx -= MD;\n\t\t\tdp[i] = (long long) x * xx[n - 1 - i][m - j - 1] % MD;\n\t\t}\n\t\tx = 0;\n\t\tfor (i = n - 1; i >= 0; i--) {\n\t\t\tif ((x += xx[n - 1 - i][j - 1]) >= MD)\n\t\t\t\tx -= MD;\n\t\t\tdq[i] = (long long) x * xx[i][j - 1] % MD;\n\t\t}\n\t\tfor (i = 1; i < n; i++)\n\t\t\tif ((dp[i] += dp[i - 1]) >= MD)\n\t\t\t\tdp[i] -= MD;\n\t\tfor (i = 0; i + 1 < n; i++)\n\t\t\tif ((ans += (long long) dp[i] * dq[i + 1] % MD) >= MD)\n\t\t\t\tans -= MD;\n\t}\n\tfor (j = 0; j < m; j++)\n\t\tfor (i = 0; i < n; i++)\n\t\t\txx[j][i] = choose(j + i, i);\n\tfor (i = 1; i < n; i++) {\n\t\tx = 0;\n\t\tfor (j = 0; j < m; j++) {\n\t\t\tif ((x += xx[j][i - 1]) >= MD)\n\t\t\t\tx -= MD;\n\t\t\tdp[j] = (long long) x * xx[m - 1 - j][i - 1] % MD;\n\t\t}\n\t\tx = 0;\n\t\tfor (j = m - 1; j >= 0; j--) {\n\t\t\tif ((x += xx[m - 1 - j][n - i - 1]) >= MD)\n\t\t\t\tx -= MD;\n\t\t\tdq[j] = (long long) x * xx[j][n - i - 1] % MD;\n\t\t}\n\t\tfor (j = 1; j < m; j++)\n\t\t\tif ((dp[j] += dp[j - 1]) >= MD)\n\t\t\t\tdp[j] -= MD;\n\t\tfor (j = 0; j + 2 < m; j++)\n\t\t\tif ((ans += (long long) dp[j] * dq[j + 2] % MD) >= MD)\n\t\t\t\tans -= MD;\n\t\tx = 0;\n\t\tfor (j = 0; j < m; j++) {\n\t\t\tif ((x += xx[j][n - i - 1]) >= MD)\n\t\t\t\tx -= MD;\n\t\t\tdp[j] = (long long) x * xx[m - 1 - j][n - i - 1] % MD;\n\t\t}\n\t\tx = 0;\n\t\tfor (j = m - 1; j >= 0; j--) {\n\t\t\tif ((x += xx[m - 1 - j][i - 1]) >= MD)\n\t\t\t\tx -= MD;\n\t\t\tdq[j] = (long long) x * xx[j][i - 1] % MD;\n\t\t}\n\t\tfor (j = 1; j < m; j++)\n\t\t\tif ((dp[j] += dp[j - 1]) >= MD)\n\t\t\t\tdp[j] -= MD;\n\t\tfor (j = 0; j + 2 < m; j++)\n\t\t\tif ((ans += (long long) dp[j] * dq[j + 2] % MD) >= MD)\n\t\t\t\tans -= MD;\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "eb2dc7ce3b060163fb1c4b31c6ad6fa4", "src_uid": "1738dc65af1fffa445cb0c3074c6bedb", "difficulty": 3100.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n#include <stdlib.h>\n\n#define N\t8\n\nint compare(const void *a, const void *b) {\n\tlong long la = *(long long *) a;\n\tlong long lb = *(long long *) b;\n\n\treturn la == lb ? 0 : la < lb ? -1 : 1;\n}\n\nlong long aa[N], aa_[N];\nint bb[N], dp[N][1 << (N - 1)];\nchar pp[N];\nint n, ans = 0x3f3f3f3f;\n\nvoid solve(int i) {\n\tint j;\n\n\tif (i == n) {\n\t\tint cnt, sum;\n\n\t\tcnt = 0, sum = 0;\n\t\tfor (i = 0; i < n; i++) {\n\t\t\tint k;\n\n\t\t\tif (!pp[i])\n\t\t\t\tcnt++;\n\t\t\tk = dp[i][bb[i]];\n\t\t\tsum += k == 1 && bb[i] == 0 ? 1 : k + 1;\n\t\t}\n\t\tif (cnt >= 2)\n\t\t\tsum++;\n\t\tif (ans > sum)\n\t\t\tans = sum;\n\t\treturn;\n\t}\n\tsolve(i + 1);\n\tpp[i] = 1;\n\tfor (j = i + 1; j < n; j++)\n\t\tif (aa_[j] % aa[i] == 0) {\n\t\t\taa_[j] /= aa[i], bb[j] ^= 1 << i;\n\t\t\tsolve(i + 1);\n\t\t\taa_[j] *= aa[i], bb[j] ^= 1 << i;\n\t\t}\n\tpp[i] = 0;\n}\n\nint main() {\n\tint i, j;\n\n\tscanf(\"%d\", &n);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%lld\", &aa[i]);\n\tqsort(aa, n, sizeof *aa, compare);\n\tfor (i = 0; i < n; i++) {\n\t\tlong long a;\n\t\tint k, p, b;\n\n\t\ta = aa[i];\n\t\tk = 0;\n\t\tfor (p = 2; p <= a / p; p++)\n\t\t\twhile (a % p == 0) {\n\t\t\t\tk++;\n\t\t\t\ta /= p;\n\t\t\t}\n\t\tif (a > 1)\n\t\t\tk++;\n\t\tdp[i][0] = k;\n\t\tfor (b = 1; b < 1 << i; b++) {\n\t\t\ta = aa[i];\n\t\t\tk = dp[i][0];\n\t\t\tfor (j = 0; j < i; j++)\n\t\t\t\tif ((b & 1 << j)) {\n\t\t\t\t\tif (a % aa[j] != 0) {\n\t\t\t\t\t\tk = -1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\ta /= aa[j];\n\t\t\t\t\tk -= dp[j][0];\n\t\t\t\t}\n\t\t\tdp[i][b] = k;\n\t\t}\n\t}\n\tfor (i = 0; i < n; i++)\n\t\taa_[i] = aa[i];\n\tsolve(0);\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "585538eac59116e4ae6bca7faf1220e0", "src_uid": "52b8b6c68518d5129272b8c56e5b7662", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n#include <stdlib.h>\n\n#define N\t8\n\nint compare(const void *a, const void *b) {\n\tint ia = *(int *) a;\n\tint ib = *(int *) b;\n\n\treturn ia - ib;\n}\n\nlong long aa[N], aa_[N];\nint bb[N], dp[N][1 << (N - 1)];\nchar pp[N];\nint n, ans = 0x3f3f3f3f;\n\nvoid solve(int i) {\n\tint j;\n\n\tif (i == n) {\n\t\tint cnt, sum;\n\n\t\tcnt = 0, sum = 0;\n\t\tfor (i = 0; i < n; i++) {\n\t\t\tint k;\n\n\t\t\tif (!pp[i])\n\t\t\t\tcnt++;\n\t\t\tk = dp[i][bb[i]];\n\t\t\tsum += k == 1 && bb[i] == 0 ? 1 : k + 1;\n\t\t}\n\t\tif (cnt >= 2)\n\t\t\tsum++;\n\t\tif (ans > sum)\n\t\t\tans = sum;\n\t\treturn;\n\t}\n\tsolve(i + 1);\n\tpp[i] = 1;\n\tfor (j = i + 1; j < n; j++)\n\t\tif (aa_[j] % aa[i] == 0) {\n\t\t\taa_[j] /= aa[i], bb[j] ^= 1 << i;\n\t\t\tsolve(i + 1);\n\t\t\taa_[j] *= aa[i], bb[j] ^= 1 << i;\n\t\t}\n\tpp[i] = 0;\n}\n\nint main() {\n\tint i, j, p, b;\n\n\tscanf(\"%d\", &n);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%lld\", &aa[i]);\n\tqsort(aa, n, sizeof *aa, compare);\n\tfor (i = 0; i < n; i++) {\n\t\tlong long a;\n\t\tint k;\n\n\t\ta = aa[i];\n\t\tk = 0;\n\t\tfor (p = 2; p <= a / p; p++)\n\t\t\twhile (a % p == 0) {\n\t\t\t\tk++;\n\t\t\t\ta /= p;\n\t\t\t}\n\t\tif (a > 1)\n\t\t\tk++;\n\t\tdp[i][0] = k;\n\t\tfor (b = 1; b < 1 << i; b++) {\n\t\t\ta = aa[i];\n\t\t\tk = dp[i][0];\n\t\t\tfor (j = 0; j < i; j++)\n\t\t\t\tif ((b & 1 << j)) {\n\t\t\t\t\tif (a % aa[j] != 0) {\n\t\t\t\t\t\tk = -1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\ta /= aa[j];\n\t\t\t\t\tk -= dp[j][0];\n\t\t\t\t}\n\t\t\tdp[i][b] = k;\n\t\t}\n\t}\n\tfor (i = 0; i < n; i++)\n\t\taa_[i] = aa[i];\n\tsolve(0);\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b1006a557c27b4bec5043d4b137d4f5c", "src_uid": "52b8b6c68518d5129272b8c56e5b7662", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MOD 1000000007\n\nint K;\nlong long PA,PB,ans;\n\nlong long INV1,INV2;\nlong long f[1010][2010];\n\nlong long power(long long a,int b)\n{\n    long long y = 1;\n    for(;b;b>>=1)\n    {\n        if(b&1) y = y * a % MOD;\n        a = a * a % MOD;\n    }\n    return y;\n}\n\nint main()\n{\n    int i,j;\n    long long x,y;\n\n    scanf(\"%d%I64d%I64d\",&K,&PA,&PB);\n    INV1 = power(PA+PB,MOD-2);\n    INV2 = power(PB,MOD-2);\n\n    f[1][0] = 1;\n    for(i=1;i<=K;i++) for(j=(i==1);j<=2*K;j++)\n    {\n        if(j < K) f[i][j] = f[i-1][j] * PA % MOD * INV1 % MOD;\n        if(j >= i && j-i < K) f[i][j] = (f[i][j] + f[i][j-i] * PB % MOD * INV1) % MOD;\n    }\n\n    for(i=1;i<K;i++) for(j=K;j<=2*K;j++) ans = (ans + j*f[i][j]) % MOD;\n    for(i=0;i<K;i++) ans = (ans + (PA*INV2 + K+i) % MOD * f[K][i]) % MOD;\n\n    printf(\"%I64d\\n\",ans);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e2ebff948578ad5ab41b4a8034264ba6", "src_uid": "0dc9f5d75143a2bc744480de859188b4", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#define MOD 1000000007\n\nint K;\nlong long PA,PB,ans;\n\nlong long INV1,INV2;\nlong long f[1010][2010];\n\nlong long power(long long a,int b)\n{\n    long long y = 1;\n    for(;b;b>>=1)\n    {\n        if(b&1) y = y * a % MOD;\n        a = a * a % MOD;\n    }\n    return y;\n}\n\nint main()\n{\n    int i,j;\n    long long x,y;\n\n    scanf(\"%d%I64d%I64d\",&K,&PA,&PB);\n    INV1 = power(PA+PB,MOD-2);\n    INV2 = power(PB,MOD-2);\n\n    f[1][0] = 1;\n    for(i=1;i<=K;i++) for(j=(i==1);j<=2*K;j++)\n    {\n        if(j < K) f[i][j] = f[i-1][j] * PA % MOD * INV1 % MOD;\n        if(j >= i && j-i < K) f[i][j] = (f[i][j] + f[i][j-i] * PB % MOD * INV1) % MOD;\n    }\n\n    for(i=1;i<K;i++) for(j=K;j<=2*K;j++) ans = (ans + j*f[i][j]) % MOD;\n    for(i=0;i<K;i++) ans = (ans + (PA*INV2 + K+i) % MOD * f[K][i]) % MOD;\n\n    printf(\"%I64d\\n\",ans);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "a5dd2b6815a71916b7c21298b2a77e12", "src_uid": "0dc9f5d75143a2bc744480de859188b4", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n#include <string.h>\r\n\r\n#define N\t5000\r\n#define INF\t0x3f3f3f3f3f3f3f3fLL\r\n\r\nlong long min(long long a, long long b) { return a < b ? a : b; }\r\nlong long max(long long a, long long b) { return a > b ? a : b; }\r\n\r\nint main() {\r\n\tstatic long long dp[N];\r\n\tint n, a, c, e, i, j;\r\n\tlong long b, d, s, t, u, ans;\r\n\r\n\tscanf(\"%d%lld%d%lld%d%d\", &a, &b, &c, &d, &n, &e), a -= e, c -= e;\r\n\tmemset(dp, 0x3f, n * sizeof *dp), dp[0] = 0;\r\n\tans = INF;\r\n\tfor (i = 0; i < n; i++) {\r\n\t\ts = dp[i], t = dp[i], u = dp[i], j = i;\r\n\t\twhile (j < n) {\r\n\t\t\tif (j + a + c + e < n)\r\n\t\t\t\tdp[j + a + c + e] = min(dp[j + a + c + e], max(s + b, t + d));\r\n\t\t\telse\r\n\t\t\t\tans = min(ans, max(s + b, t + d));\r\n\t\t\tif (s + b < t + d)\r\n\t\t\t\tj += a, u = s += b;\r\n\t\t\telse\r\n\t\t\t\tj += c, u = t += d;\r\n\t\t}\r\n\t\tans = min(ans, u);\r\n\t}\r\n\tprintf(\"%lld\\n\", ans);\r\n\treturn 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "e39f0847910605b224bc404d7f7d49a6", "src_uid": "ca9d48e48e69b931236907a9ac262433", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\nusing namespace std;\nint a[10][260]=\n{\n{0},\n{2,1},\n{32,30,80,109},\n{6824,59808,147224,415870,1757896,1897056,4898872,7593125},\n{776830421,290516100,746623577,293783147,33900006,735127505,565460332,428982705,472062098,161873957,117354594,515619293,578944191,312106242,569389279,391464593},\n{261086313,584837659,683961846,468868529,211593382,736955478,229471758,157617135,398169441,360252438,629394768,264125799,647490480,342079395,391579767,225200475,486011304,513156108,628771752,132906648,142138221,20119449,444199674,195188679,387329805,44684703,651912135,737154512,612549793,519860281,186175544,212568440},\n{240805271,239509872,581127897,6511239,156126222,509425833,672407328,366667722,459185405,509737025,554790222,165216555,703150560,74806569,398730015,383350905,506108358,51326142,298053147,104256117,391428765,374020479,206607807,87664059,275899176,56407680,551553401,448939463,582889860,129676638,226078251,135769095,61292868,578972226,190181628,390739055,184587732,446575689,732674124,232198470,676760679,352474101,611444862,575661807,628905585,320813094,522840969,469781928,156006018,554473341,239654268,643714911,433540170,199307003,496385218,291740751,67309914,370826673,202356819,279421821,421203111,63744786,520987612,550671827},\n{482164403,768209115,462063756,154906374,36099042,341766705,678182556,621882744,478771358,231881111,175889805,243630450,168908523,671961765,55761813,652682670,773939082,517628076,756201264,124604900,750976272,498253248,676047609,137170026,705610017,495032139,561797418,703097347,500815609,95984586,739707108,265613565,387099846,777331779,594676173,591219559,407997044,208947235,93337440,478908360,685013007,487033953,671903001,39521181,738490312,33785059,465470131,310453920,54648783,346831137,427694175,474743430,705296781,435828036,429824745,663532359,261388683,244690731,533997135,596108961,506813013,371892402,590145264,104733162,143420103,654339672,700348950,685038942,578826927,286484229,501639192,434962491,299270097,27702486,335375775,111746817,565603164,294926121,676063665,735862995,710035809,437011960,668528077,138765186,508213986,615036450,353784942,624827616,343900011,241289776,52410890,72018835,352406796,415705878,4802637,376367145,65589678,333633477,341834527,303717460,282387700,42951006,254706039,423048528,526429710,68131467,669954708,12787348,500636381,317959019,479433192,657133515,416259390,610216692,340129188,44594256,257373347,138718678,530767740,292922628,37220268,605295159,480722613,458170419,30540300,487159055,232966794,149150650},\n{412133651,386543325,139952108,289303402,102404925,317067177,396414708,80515854,663739304,317300809,228877044,493725043,715317967,490300965,315527373,743539734,488329191,553627998,533025234,242583957,706116537,614109258,645447222,523195911,492109128,722623041,111085128,766395126,654378921,691964847,496688157,399056049,654363234,102052314,191720088,473910948,259736526,332840025,388047555,665791056,627111387,139696515,441456687,443032569,283264821,771641703,452641455,511306362,117572859,127701891,721298331,176520078,357242229,611296308,696994956,405628839,429224274,465336054,695091546,689828796,574648641,351220905,507964023,675326610,517248963,453528621,220301928,494463186,681789969,339589656,44524053,417125457,339589404,747135963,341780733,734158215,396817281,21997836,5728464,147611205,456248898,714128667,377654949,3862068,128418948,589390074,304947090,11703825,228266073,127304142,429215724,361541124,521572968,468358191,341231688,65323503,613778508,15985323,291661029,410970006,591638112,349541550,89967528,224922159,361094166,584206074,640051812,324264456,652625388,693768537,11740617,309238398,211085469,194905872,639416484,110110707,296645895,748118511,131177718,511142751,775975599,421403409,475528473,434685258,1768977,80301375,708023862,569195676,56238084,632887668,88089750,631539342,396695565,38780154,695798271,469819224,439587099,69045921,682966116,112310856,64943298,534475872,40215357,389728458,286368453,736006257,501181650,54829908,603489402,338032656,512182818,627500097,462674016,3103092,157324491,43978329,596818971,259025598,9088632,91991781,577291428,211245489,429471231,142626330,172560633,510907446,444609585,758102058,375112647,744786693,276174402,19259856,233672418,745389414,225772848,23385663,324290610,519804558,120337812,402578568,360676008,450089262,551043738,337388940,512108856,28879011,690040638,106017282,558262341,99972432,608226003,612152037,42414435,776201013,39580443,518796945,494437752,583194366,723936555,415359657,309569589,751104774,166684527,249229170,353120823,130668327,753823584,580966092,561963717,543672234,393846327,586278000,327398400,278403867,156455586,363920382,190245195,290039148,547014447,466218648,146037150,585462906,666008595,691786683,374707494,622498779,231158277,685740951,115612245,681825249,545555745,551718468,277206615,640171035,757727334,195193908,658656684,457760646,225925875,505761984,18685233,506832921,112511021,396846646,290147622,113924623,669986155,336008070,63611061,238586775,119956662,616557739,772784623,334527774,410403148,51933421}\n};\nint main()\n{\n    int n,k;\n    scanf(\"%d %d\",&n,&k);\n    int p=0;\n    while ((1<<p)!=n) ++p;\n    printf(\"%d\",a[p][k-1]);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": true, "code_uid": "e5a163acf0d47fc70144be9efdfc1c9d", "src_uid": "cfe19131644e5925e32084a581e23286", "difficulty": 2700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t1000000\n#define MD\t998244353\n#define V2\t499122177\n#define V6\t166374059\n\nint f2(int n) {\n\treturn (long long) n * (n + 1) % MD * V2 % MD;\n}\n\nint f3(int n) {\n\treturn (long long) n * (n + 1) % MD * (n + 2) % MD * V6 % MD;\n}\n\nint main() {\n\tstatic int dp[N], dq[N];\n\tint n, i, x, y, z, single2, single3, pair, ans;\n\n\tscanf(\"%d\", &n);\n\tdp[0] = dq[0] = 1;\n\tfor (i = 1; i < n; i++) {\n\t\tdp[i] = (dp[i - 1] + f2(dp[i - 1]) + (i == 1 ? 0 : (long long) dp[i - 1] * dq[i - 2])) % MD;\n\t\tdq[i] = (dq[i - 1] + dp[i]) % MD;\n\t}\n\tx = dp[n - 1], y = n == 1 ? 0 : dq[n - 2];\n\tsingle2 = (f2(x) + (long long) x * y % MD) % MD;\n\tsingle3 = (f3(x) + (long long) f2(x) * y % MD + (long long) x * f2(y) % MD) % MD;\n\tpair = 0;\n\tfor (i = 0; i < n; i++) {\n\t\tif (i == 0)\n\t\t\tz = 1;\n\t\telse {\n\t\t\tx = dp[i - 1], y = i == 1 ? 0 : dq[i - 2];\n\t\t\tz = (f2(x) + (long long) x * y % MD) % MD;\n\t\t}\n\t\tpair = (pair + (long long) z * dp[n - 1 - i]) % MD;\n\t}\n\tans = ((long long) single2 * 2 + single3 * 2 + pair) % MD;\n\tif (ans < 0)\n\t\tans += MD;\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "e148cada6afeb66bce3c638a99727036", "src_uid": "92939054045c089cd25c8f4e7b9ffcf2", "difficulty": 2900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint main() {\n    int R,B,i,j;\n    scanf(\"%d %d\",&R,&B);\n    int x[R],y[R],a[B],b[B];\n    for(i=0;i<R;i++) {\n        scanf(\"%d %d\",&x[i],&y[i]);\n    }\n    for(i=0;i<B;i++) {\n        scanf(\"%d %d\",&a[i],&b[i]);\n    }\n    if(R!=B) {\n        printf(\"NO\");\n    }else\n        printf(\"YES\");\n\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "30b471a25f6ecf4af90b541bf69669cd", "src_uid": "65f81f621c228c09915adcb05256c634", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\n#include<stdbool.h>\n\ntypedef long long LL;\nbool inuse[10];\nint x[2][10], y[2][10], R, B, guarding[10];\n\nlong long cprodukt(int x1, int y1, int x2, int y2, int x3, int y3){\n\treturn (x3-x1)*(y2-y1)-(x2-x1)*(y3-y1);\n}\n\nbool cross(int g1, int s1, int g2, int s2){\n\treturn (\n\t\tcprodukt(x[0][g1], y[0][g1], x[1][s1], y[1][s1], x[0][g2], y[0][g2])\n\t\t*\n\t\tcprodukt(x[0][g1], y[0][g1], x[1][s1], y[1][s1], x[1][s2], y[1][s2])\n\t\t<0)\n\t\t&&\n\t\t(\n\t\tcprodukt(x[0][g2], y[0][g2], x[1][s2], y[1][s2], x[0][g1], y[0][g1])\n\t\t*\n\t\tcprodukt(x[0][g2], y[0][g2], x[1][s2], y[1][s2], x[1][s1], y[1][s1])\n\t\t<0);\n}\n\nbool pos(int d){\n\tif(d==R) return true;\n\tfor(int i=0;i<R;++i){\n\t\tif(inuse[i]) continue;\n\t\tinuse[i]=true;\n\t\tguarding[d]=i;\n\t\tfor(int j=0;j<d;++j) if(cross(j, guarding[j], d, i)) continue;\n\t\tif(pos(d+1)) return true;\n\t\tinuse[i]=false;\n\t\tguarding[d]=-1;\n\t}\n\treturn false;\n}\n\nint main(){\n\tscanf(\"%d %d\", &R, &B);\n\tif(R!=B){\n\t\tputs(\"NO\");\n\t\treturn 0;\n\t}\n\tfor(int j=0;j<2;++j) for(int i=0;i<R;++i) scanf(\"%d %d\", x[j]+i, y[j]+i);\n\tif(pos(0)) puts(\"YES\");\n\telse puts(\"NO\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "d07a52f02834dd35ad29f05e5a2f0d75", "src_uid": "65f81f621c228c09915adcb05256c634", "difficulty": 1600.0}
{"lang": "GNU C11", "source_code": "/* practice with Dukkha */\n#include <stdio.h>\n\n#define N\t100\n#define X\t100\n#define MD\t1000000007\n\nlong long power(int a, int k) {\n\tlong long p;\n\n\tif (k == 0)\n\t\treturn 1;\n\tp = power(a, k >> 1);\n\tp = p * p % MD;\n\tif (k & 1)\n\t\tp = p * a % MD;\n\treturn p;\n}\n\nint main() {\n\tstatic int ff[X + 1], ds[X + 1][N][N + 1], dp[X + 1][N], dq[X + 1][N], dr[X + 1];\n\tstatic char cc[N + 1];\n\tint n, x, i, l, r, m;\n\n\tscanf(\"%d%d%s\", &n, &x, cc);\n\tif (x == 0) {\n\t\tprintf(\"%d\\n\", n == 1 && cc[0] == '0');\n\t\treturn 0;\n\t}\n\tff[0] = ff[1] = 1;\n\tfor (i = 2; i <= x; i++)\n\t\tff[i] = (ff[i - 1] + ff[i - 2]) % (MD - 1);\n\tfor (i = 0; i <= x; i++)\n\t\tff[i] = power(2, ff[i]);\n\tfor (l = 0; l < n; l++) {\n\t\tds[0][l][l] = ds[1][l][l] = 1;\n\t\tds[0][l][l + 1] = cc[l] == '0' ? 1 : 0;\n\t\tds[1][l][l + 1] = cc[l] == '1' ? 1 : 0;\n\t}\n\tfor (i = 2; i <= x; i++)\n\t\tfor (l = 0; l < n; l++)\n\t\t\tfor (r = l; r < n; r++) {\n\t\t\t\tlong long z = 0;\n\n\t\t\t\tfor (m = l; m <= r; m++)\n\t\t\t\t\tz = (z + (long long) ds[i - 1][l][m] * ds[i - 2][m][r]) % MD;\n\t\t\t\tds[i][l][r] = z;\n\t\t\t}\n\tif (n > 1) {\n\t\tdp[0][n - 1] = ds[0][n - 1][n];\n\t\tdp[1][n - 1] = ds[1][n - 1][n];\n\t\tfor (i = 2; i <= x; i++)\n\t\t\tfor (l = 1; l < n; l++) {\n\t\t\t\tlong long z = (long long) dp[i - 1][l] * ff[i - 2] % MD;\n\n\t\t\t\tfor (m = l; m < n; m++)\n\t\t\t\t\tz = (z + (long long) ds[i - 1][l][m] * dp[i - 2][m]) % MD;\n\t\t\t\tdp[i][l] = z;\n\t\t\t}\n\t\tdq[0][1] = ds[0][0][1];\n\t\tdq[1][1] = ds[1][0][1];\n\t\tfor (i = 2; i <= x; i++)\n\t\t\tfor (r = 1; r < n; r++) {\n\t\t\t\tlong long z = (long long) ff[i - 1] * dq[i - 2][r] % MD;\n\n\t\t\t\tfor (m = r; m > 0; m--)\n\t\t\t\t\tz = (z + (long long) dq[i - 1][m] * ds[i - 2][m][r]) % MD;\n\t\t\t\tdq[i][r] = z;\n\t\t\t}\n\t}\n\tdr[0] = ds[0][0][n];\n\tdr[1] = ds[1][0][n];\n\tfor (i = 2; i <= x; i++) {\n\t\tlong long z = ((long long) dr[i - 1] * ff[i - 2] + (long long) ff[i - 1] * dr[i - 2]) % MD;\n\n\t\tfor (m = 1; m < n; m++)\n\t\t\tz = (z + (long long) dq[i - 1][m] * dp[i - 2][m]) % MD;\n\t\tdr[i] = z;\n\t}\n\tprintf(\"%d\\n\", dr[x]);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "ec0b9fedcfe40e6e334344fced87ad31", "src_uid": "52c6aa73ff4460799402c646c6263630", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n#include <stdbool.h>\n\n#define MAX 5010\n#define MOD 1000000007\n#define clr(ar) memset(ar, 0, sizeof(ar))\n#define read() freopen(\"lol.txt\", \"r\", stdin)\n\nchar S[MAX], T[MAX];\nbool visited[MAX][MAX];\nint n, m, dp[MAX][MAX], next[MAX][MAX];\n\nint F(int i, int j){\n    if (i >= n || j >= m) return 0;\n    if (visited[i][j]) return dp[i][j];\n\n    long long res = 0;\n    if (next[i][j] != -1){\n        res = res + F(i + 1, next[i][j] + 1) + 1;\n        res = res + F(i, next[i][j] + 1);\n    }\n\n    visited[i][j] = true;\n    return (dp[i][j] = (res % MOD));\n}\n\nint main(){\n    int i, j, k;\n\n    while (scanf(\"%s %s\", S, T) != EOF){\n        clr(visited);\n        n = strlen(S), m = strlen(T);\n        memset(next, -1, sizeof(next));\n        for (i = 0; i < n; i++){\n            for (j = m - 1; j >= 0; j--){\n                if (S[i] == T[j]) next[i][j] = j;\n                else if ((j + 1) != m) next[i][j] = next[i][j + 1];\n            }\n        }\n\n        long long res = 0;\n        for (i = 0; i < n; i++){\n            for (j = 0; j < m; j++){\n                if (S[i] == T[j]){\n                    res = res + F(i + 1, j + 1) + 1;\n                }\n            }\n        }\n        printf(\"%lld\\n\", res % MOD);\n    }\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a1d39cd84ee7d7cf1201969bf916e76a", "src_uid": "4022f8f796d4f2b7e43a8360bf34e35f", "difficulty": 1700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\n\nint dp[5000];\n\nint main()\n{\n     int n1, n2, m = 1000000007, i, j;\n     long long sum = 0;\n     char s[5001], t[5001];\n\n     scanf(\"%s\", s);\n     scanf(\"%s\", t);\n\n     n1 = strlen(s);\n     n2 = strlen(t);\n\n     for (i = 0; i < n2; i++) {\n\t  for (j = n1 - 1; j >= 0; j--) {\n\t       if (t[i] == s[j]) {\n\t\t    dp[j] = (dp[j] + 1) % m;\n\n\t\t    if (j > 0) dp[j] = (dp[j] + dp[j - 1]) % m;\n\t       }\n\t  }\n     }\n\n     for (i = 0; i < n1; i++) sum = (sum + dp[i]) % m;\n\n     printf(\"%d\\n\", (int)sum);\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "361b92b59b7f606e14f3d02c73c49a26", "src_uid": "4022f8f796d4f2b7e43a8360bf34e35f", "difficulty": 1700.0}
{"lang": "GNU C11", "source_code": "#include<stdio.h>\nchar mp[9][9];\nint dir;\nint n,m,x,y;\nint get_dis(int dir){\n  if(dir==0&&y==m)return 100;\n  if(dir==1&&x==n)return 100;\n  if(dir==0){\n    for(int i=y+1;i<=m;i++)\n      if(mp[x][i]=='*')return i-y;\n  }else\n    for(int i=x+1;i<=n;i++)\n      if(mp[i][y]=='*')return i-x;\t\n  return 100;\n}\n\nint main(void){\n  scanf(\"%d%d\",&n,&m);\n  for(int i=1;i<=n;i++)scanf(\"%s\",mp[i]+1);\n  dir=0;\n  int ans=0;\n  x=1;y=1;\n  for(int i=0;i<n+m;i++){\n    if(mp[x][y]=='*')ans++;\n    //    printf(\"%d %d\\n\",x,y);\n    if(get_dis(dir)<get_dis(!dir)){\n      if(dir==0)y++;\n      else x++;\n    }else if(get_dis(dir)>get_dis(!dir)){\n      if(dir==0)\n\tx++;\n      else\n\ty++;\n      dir=!dir;\n    }else{\n      x++;\n    }\n  }\n  printf(\"%d\\n\",ans);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "67259227f65df5e0284ac61dee14d30f", "src_uid": "f985d7a6e7650a9b855a4cef26fd9b0d", "difficulty": 1800.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t5\n#define M\t5\n\nint main() {\n\tstatic char cc[N][M + 1];\n\tint n, m, i, j, i_, j_, k;\n\n\tscanf(\"%d%d\", &n, &m);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%s\", cc[i]);\n\ti_ = 0, j_ = 0, k = 0;\n\twhile (1) {\n\t\tint i1, j1, d;\n\n\t\ti1 = -1, j1 = -1, d = n + m + 1;\n\t\tfor (i = i_; i < n; i++)\n\t\t\tfor (j = j_; j < m; j++)\n\t\t\t\tif (cc[i][j] == '*' && d > i + j)\n\t\t\t\t\td = i + j, i1 = i, j1 = j;\n\t\tif (i1 == -1 && j1 == -1)\n\t\t\tbreak;\n\t\tcc[i1][j1] = '.', i_ = i1, j_ = j1, k++;\n\t}\n\tprintf(\"%d\\n\", k);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "85f4e1abd2b3b99a75116ae813ce74fa", "src_uid": "f985d7a6e7650a9b855a4cef26fd9b0d", "difficulty": 1800.0}
{"lang": "GNU C", "source_code": "// write in C...\n#include <stdio.h>\n\n#ifdef DEBUG\n#define D(x...) fprintf(stderr, x)\n#else\n#define D(x...)\n#endif\n\n#define MOD 1000000009\n\nint n, w, b;\nint c[4005][4005];\n\nint p(int n, int k) {\n    if (k > n || k < 1) return 0;\n    else return c[n-1][k-1];\n}\n\nint main() {\n    int i, j;\n\n    scanf(\"%d %d %d\", &n, &w, &b);\n\n    for (i = 0; i < 4005; i++) c[i][0] = 1;\n    for (i = 1; i < 4005; i++)\n        for (j = 1; j <= i; j++)\n            c[i][j] = (c[i-1][j-1] + c[i-1][j]) % MOD;\n\n    long long res = 0;\n\n    for (i = 0; i <= n; i++) {\n        res = (res + (((((long long)p(b, i) * (long long)p(w, n-i))%MOD) * (long long)(n-i-1))%MOD)) % MOD;\n    }\n\n    for (i = 1; i <= w; i++) res = (res * i) % MOD;\n    for (i = 1; i <= b; i++) res = (res * i) % MOD;\n\n    printf(\"%d\\n\", (int)res);\n\n    return 0;\n}\n\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "34575ac22336b67bf3ab8198797cc710", "src_uid": "63e93a161bbff623323e66c98d5e20ac", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t300000\n\nint min(int a, int b) { return a < b ? a : b; }\n\nint main() {\n\tstatic char cc[N + 1];\n\tstatic int pp[N];\n\tint n, h, i, i1, i2, j, pmin, k0, k1, k2, k, k_, i_, j_;\n\n\tscanf(\"%d%s\", &n, cc);\n\tfor (i = 0; i < n; i++)\n\t\tpp[i] = (i == 0 ? 0 : pp[i - 1]) + (cc[i] == '(' ? 1 : -1);\n\tif (pp[n - 1] != 0) {\n\t\tprintf(\"0\\n\");\n\t\tprintf(\"1 1\\n\");\n\t\treturn 0;\n\t}\n\tpmin = n + 1;\n\tfor (i = 0; i < n; i++)\n\t\tpmin = min(pmin, pp[i]);\n\tk0 = 0;\n\tfor (i = 0; i < n; i++)\n\t\tif (pp[i] == pmin)\n\t\t\tk0++;\n\tk_ = k0, i_ = 0, j_ = 0;\n\ti = 0;\n\twhile (i < n && pp[i] != pmin)\n\t\ti++;\n\tj = n - 1;\n\twhile (j >= 0 && pp[j] != pmin)\n\t\tj--;\n\tj++;\n\tif (j < n) {\n\t\tk1 = 0;\n\t\tfor (h = 0; h < n; h++)\n\t\t\tif (pp[h] + (i <= h && h < j ? 2 : 0) == pmin + 1)\n\t\t\t\tk1++;\n\t\tk = k1;\n\t\tif (k_ < k)\n\t\t\tk_ = k, i_ = i, j_ = j;\n\t}\n\ti = 0;\n\twhile (i < n && pp[i] > pmin + 1)\n\t\ti++;\n\tj = n - 1;\n\twhile (j >= 0 && pp[j] > pmin + 1)\n\t\tj--;\n\tj++;\n\tif (j < n) {\n\t\tk2 = 0;\n\t\tfor (h = 0; h < n; h++)\n\t\t\tif (pp[h] + (i <= h && h < j ? 2 : 0) == pmin + 2)\n\t\t\t\tk2++;\n\t\tk = k2;\n\t\tif (k_ < k)\n\t\t\tk_ = k, i_ = i, j_ = j;\n\t}\n\ti1 = i2 = 0, k1 = k2 = 0;\n\tfor (j = 0; j < n; j++) {\n\t\tint p = pp[j];\n\n\t\tif (p == pmin) {\n\t\t\tif (cc[j] == ')') {\n\t\t\t\tk = k1;\n\t\t\t\tif (cc[i1] == '(' && k_ < k)\n\t\t\t\t\tk_ = k, i_ = i1, j_ = j;\n\t\t\t\tk = k0 + k2;\n\t\t\t\tif (cc[i2] == '(' && k_ < k)\n\t\t\t\t\tk_ = k, i_ = i2, j_ = j;\n\t\t\t}\n\t\t\ti1 = j + 1, k1 = 0;\n\t\t\ti2 = j + 1, k2 = 0;\n\t\t} else if (p == pmin + 1) {\n\t\t\tif (cc[j] == ')') {\n\t\t\t\tk = k0 + k2;\n\t\t\t\tif (cc[i2] == '(' && k_ < k)\n\t\t\t\t\tk_ = k, i_ = i2, j_ = j;\n\t\t\t}\n\t\t\tk1++;\n\t\t\ti2 = j + 1, k2 = 0;\n\t\t} else if (p == pmin + 2)\n\t\t\tk2++;\n\t}\n\tprintf(\"%d\\n\", k_);\n\tprintf(\"%d %d\\n\", i_ + 1, j_ + 1);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "cf52c45d3d016177ec6c85fc516273dd", "src_uid": "2d10668fcc2d8e90e102b043f5e0578d", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "/* upsolved using pre-shifting */\n/* https://codeforces.com/blog/entry/70720 */\n#include <stdio.h>\n\n#define N\t300000\n\nint min(int a, int b) { return a < b ? a : b; }\n\nint main() {\n\tstatic char cc[N + 1];\n\tstatic int pp[N], pp_[N];\n\tint n, h, i, j, p_, k0, k, k_, i_, j_;\n\n\tscanf(\"%d%s\", &n, cc);\n\tfor (i = 0; i < n; i++)\n\t\tpp[i] = (i == 0 ? 0 : pp[i - 1]) + (cc[i] == '(' ? 1 : -1);\n\tif (pp[n - 1] != 0) {\n\t\tprintf(\"0\\n\");\n\t\tprintf(\"1 1\\n\");\n\t\treturn 0;\n\t}\n\tp_ = n + 1;\n\tfor (i = 0; i < n; i++)\n\t\tp_ = min(p_, pp[i]);\n\tfor (i = 0; i < n; i++)\n\t\tpp[i] -= p_;\n\th = -1, k0 = 0;\n\tfor (i = 0; i < n; i++)\n\t\tif (pp[i] == 0)\n\t\t\th = i, k0++;\n\tfor (i = 0; i < n; i++)\n\t\tpp_[i] = pp[(i + h + 1) % n];\n\tk_ = k0, i_ = 0, j_ = 0;\n\tfor (i = 0, j = 0, k = 0; j < n; j++)\n\t\tif (pp_[j] < 1) {\n\t\t\tif (k_ < k)\n\t\t\t\tk_ = k, i_ = i, j_ = j;\n\t\t\ti = j + 1, k = 0;\n\t\t} else if (pp_[j] == 1)\n\t\t\tk++;\n\tfor (i = 0, j = 0, k = 0; j < n; j++)\n\t\tif (pp_[j] < 2) {\n\t\t\tif (k_ < k0 + k)\n\t\t\t\tk_ = k0 + k, i_ = i, j_ = j;\n\t\t\ti = j + 1, k = 0;\n\t\t} else if (pp_[j] == 2)\n\t\t\tk++;\n\tprintf(\"%d\\n\", k_);\n\tprintf(\"%d %d\\n\", (i_ + h + 1) % n + 1, (j_ + h + 1) % n + 1);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "320e6d3e112882d70065138d92b40476", "src_uid": "2d10668fcc2d8e90e102b043f5e0578d", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main(){\n\t\n\tint n,m;\n\tscanf(\"%d %d\",&n,&m);\n\tint b;\n\tif(n>m){\n\t\tb=n;\n\t\tn=m;\n\t\tm=b;\n\t}\n\tif(n==1){\n\t\tint mo=m%6;\n\t\tswitch(mo){\n\t\t\tcase 0:printf(\"%d\\n\",m);break;\n\t\t\tcase 1:printf(\"%d\\n\",m-mo);break;\n\t\t\tcase 2:printf(\"%d\\n\",m-mo);break;\n\t\t\tcase 3:printf(\"%d\\n\",m-mo);break;\n\t\t\tcase 4:printf(\"%d\\n\",m-2);break;\n\t\t\tcase 5:printf(\"%d\\n\",m-1);\n\t\t}\n\t}\n\telse if(n==2){\n\t\tif(m==2){\n\t\t\tprintf(\"%d\\n\",0);\n\t\t}\n\t\telse if(m==3){\n\t\t\tprintf(\"%d\\n\",4);\n\t\t}\n\t\telse if(m==7){\n\t\t\tprintf(\"%d\\n\",12);\n\t\t}\n\t\telse{\n\t\t\tprintf(\"%d\\n\",n*m);\n\t\t}\n\t}\n\telse{\n\t\tlong long mul=n;\n\t\tmul*=m;\n\t\tif(mul%2==0){\n\t\t\tprintf(\"%lld\\n\",mul);\n\t\t}\n\t\telse{\n\t\t\tprintf(\"%lld\\n\",mul-1);\n\t\t}\n\t}\n\t\n\treturn 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "5d6b75046c4c8ee118f9559a1d7552a9", "src_uid": "02ce135a4b276d1e9ba6a4ce37f2fe70", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint main(void)\n{\n    int a, b, w = 0;\n    scanf(\"%d %d\", &a, &b);\n    if (a > b) {\n        b ^= a;\n        a ^= b;\n        b ^= a;\n    }\n\n    if (b >= 4) {\n        if (a >= 4) {\n            w = (a % 2) * (b % 2);\n        }\n        if (a == 3) {\n            w = (b % 2);\n        }\n        if (a == 2) {\n            if (b == 4) {\n                w = 0;\n            }\n            if (b == 5) {\n                w = 0;\n            }\n            if (b == 7) {\n                w = 2;\n            }\n            if (b > 7) {\n                w = 0;\n            }\n        }\n        if (a == 1) {\n            w = (b % 6) - (b % 6 == 4) * 2 - (b % 6 == 5) * 4;\n        }\n    }\n    if (b == 3) {\n        if (a == 3)\n            w = 1;\n        if (a == 2)\n            w = 2;\n        if (a == 1)\n            w = 3;\n    }\n    if (b == 2) {\n        if (a == 2)\n            w = 4;\n        if (a == 1)\n            w = 2;\n    }\n    if (b == 1)\n        w = 1;\n\n    printf(\"%I64d\\n\", (unsigned long long) a * b - w);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "a8466db667f1ac334420a33397f22737", "src_uid": "02ce135a4b276d1e9ba6a4ce37f2fe70", "difficulty": 2200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t400\n\nint md;\n\nint ff[N + 1];\n\nvoid init() {\n\tint n;\n\n\tff[0] = 1;\n\tfor (n = 1; n <= N; n++)\n\t\tff[n] = (long long) ff[n - 1] * n % md;\n}\n\nint main() {\n\tstatic int dp[N + 1];\n\tint n, i, j, ans;\n\n\tscanf(\"%d%d\", &n, &md), init();\n\tans = 0;\n\tdp[0] = 1;\n\tfor (i = 1; i <= n; i++) {\n\t\tfor (j = n; j >= 0; j--)\n\t\t\tdp[j] = ((j == 0 ? 0 : dp[j - 1]) + (long long) dp[j] * j * 2) % md;\n\t\tans = (ans + (long long) dp[n - i + 1] * ff[n - i + 1]) % md;\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7d6699e1729e887f6ffdf3507efe0b52", "src_uid": "4f0e0d1deef0761a46b64de3eb98e774", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\ntypedef long long ll;\nint left[10];\nint n;\nchar seen[3628800];\n\nll fact[21];\n\n/*  must be called before using rank/unrank */\nvoid initfact() {\n  int i;\n  fact[0]=1;\n  for(i=1;i<21;i++) fact[i]=fact[i-1]*i;\n}\n\nll permbtr(int n,int *p,int *q) {\n  int s,t;\n  if(n<2) return 0;\n  s=p[n-1]; p[n-1]=p[q[n-1]]; p[q[n-1]]=s;\n  t=q[s];   q[s]=q[n-1];      q[n-1]=t;\n  return s+n*permbtr(n-1,p,q);\n}\n\n/*  return rank of permutation\n    n: number of elements\n    *p: permutation to rank */\n/*  warning, *p is destroyed! */\nll permutationrank2(int n,int *p) {\n  int i,q[16];\n  for(i=0;i<n;i++) q[p[i]]=i;\n  return permbtr(n,p,q);\n}\n\nint order[10];\n\nvoid btr() {\n    int t,i,j;\n    int p[10],r;\n    for(i=0;i<n;i++) p[i]=order[i];\n    r=permutationrank2(n,p);\n    seen[r]=1;\n    for(i=0;i<n-1;i++) if(left[i]) for(j=i+1;j<n;j++) if(left[j]) {\n        left[j]--; left[i]--;\n        t=order[j],order[j]=order[i],order[i]=t;\n//      printf(\"  throw %d %d\\n\",at,i);\n        btr();\n        left[j]++; left[i]++;\n        t=order[j],order[j]=order[i],order[i]=t;\n    }\n}\n\nint pre[11][11];\n\n\nvoid setpre() {\n    memset(pre,-1,sizeof(pre));\n    pre[8][0]=764;\n    pre[8][1]=1856;\n    pre[8][2]=4256;\n    pre[8][3]=8736;\n    pre[8][4]=16800;\n    pre[8][5]=26880;\n    pre[8][6]=40320;\n    pre[8][7]=40320;\n    pre[8][8]=40320;\n    pre[9][0]=2620;\n    pre[9][1]=6876;\n    pre[9][2]=16704;\n    pre[9][3]=38304;\n    pre[9][4]=78624;\n    pre[9][5]=151200;\n    pre[9][6]=241920;\n    pre[9][7]=362880+0;\n    pre[9][8]=362880;\n    pre[9][9]=362880;\n    pre[10][0]=9496;\n    pre[10][1]=26200;\n    pre[10][2]=68760;\n    pre[10][3]=167040;\n    pre[10][4]=383040;\n    pre[10][5]=786240;\n    pre[10][6]=1512000;\n    pre[10][7]=2419200;\n    pre[10][8]=3628800+0;\n    pre[10][9]=3628800;\n    pre[10][10]=3628800;\n}\n\nint main() {\n    int i,z=0,two;\n    initfact();\n    scanf(\"%d\",&n);\n    for(i=0;i<n;i++) scanf(\"%d\",&left[i]),order[i]=i;\n    /* precalced values */\n    setpre();\n    for(i=two=0;i<n;i++) if(left[i]>1) two++;\n    if(pre\n    \n    memset(seen,0,sizeof(seen));\n    btr();\n    for(i=0;i<3628800;i++) z+=seen[i];\n    printf(\"%d\\n\",z);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": true, "code_uid": "8b7d7943557e1ed8f2529c4f569bf2a3", "src_uid": "91e8dbe94273e255182aca0f94117bb9", "difficulty": 2300.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\nint cmp(const void *a, const void *b)\n{\n     return *((int *)a) - *((int *)b);\n}\n\nint maximum(int a, int b)\n{\n     if (a > b) {\n\t  return a;\n     } else {\n\t  return b;\n     }\n}\n\nint minimum(int a, int b)\n{\n     if (a < b) {\n\t  return a;\n     } else {\n\t  return b;\n     }\n}\n\nint main()\n{\n     int a[2000];\n     int p = 0, q = 1, x = 1, i, j;\n     int pl, pr, vl, vr, k;\n     long long c = 0, d;\n\n     a[0] = 0;\n\n     for (i = 0; i < 9; i++) {\n\t  for (j = p; j < q; j++) {\n\t       a[x++] = a[j] * 10 + 4;\n\t       a[x++] = a[j] * 10 + 7;\n\t  }\n\n\t  p = q; q = x;\n     }\n\n     qsort(a, x, sizeof(int), cmp);\n\n     a[x] = 1000000001;\n\n     scanf(\"%d %d %d %d %d\", &pl, &pr, &vl, &vr, &k);\n\n     d = (long long)(pr - pl + 1) * (vr - vl + 1);\n\n     for (i = 1; i <= x - k; i++) {\n\t  if (pl <= a[i] && vr >= a[i + k - 1]) {\n\t       int s1 = minimum(a[i], pr);\n\t       int s2 = maximum(a[i - 1] + 1, pl);\n\t       int t1 = maximum(a[i + k - 1], vl);\n\t       int t2 = minimum(a[i + k] - 1, vr);\n\n\t       if (s1 - s2 >= 0 && t2 - t1 >= 0) {\n\t\t    c += (long long)(s1 - s2 + 1) * (t2 - t1 + 1);\n\t       }\n\t  }\n\t  if (vl <= a[i] && pr >= a[i + k - 1]) {\n\t       int s1 = minimum(a[i], vr);\n\t       int s2 = maximum(a[i - 1] + 1, vl);\n\t       int t1 = maximum(a[i + k - 1], pl);\n\t       int t2 = minimum(a[i + k] - 1, pr);\n\n\t       if (s1 - s2 >= 0 && t2 - t1 >= 0) {\n\t\t    c += (long long)(s1 - s2 + 1) * (t2 - t1 + 1);\n\t       }\n\t  }\n     }\n\n     if (k == 1) {\n\t  for (i = 1; i < x; i++) {\n\t       if (pl <= a[i] && pr >= a[i] && vl <= a[i] && vr >= a[i]) c--;\n\t  }\n     }\n\n     printf(\"%.20lf\\n\", (double)c / d);\n\n     return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "695438f3aa65f7ac25e53177438fcc2a", "src_uid": "5d76ec741a9d873ce9d7c3ef55eb984c", "difficulty": 1900.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\nint checkIsLucky(int num){\n    while(num>0){\n        if(num%10!=4&&num%10!=7)return 0;\n        num/=10;\n    }\n    return 1;\n}\nint nextNum(int num){\n    int nextN;\n    int count=1;\n    int maxNextD=0;\n    nextN=num;\n    if(num>=777777777) return 1000000001;\n    while(num>0){\n        if(num%10==4){\n            nextN+=count*3;\n            nextN=nextN/(count)*count+maxNextD;\n            break;\n        }else{\n            maxNextD*=10;\n            maxNextD+=4;\n            num/=10;\n            count*=10;\n        }\n    }\n    if(num>0) return nextN;\n    else{\n        maxNextD*=10;\n        maxNextD+=4;\n        return maxNextD;\n    }\n}\n\nint max(int a,int b){\n    if(a>b) return a;\n    else return b;\n}\nint min(int a,int b){\n    if(a>b) return b;\n    else return a;\n}\nint kthNum(int begin,int k){\n    int count=1;\n    int rt=0,tmp=begin;\n    while (tmp>0) {\n        tmp/=10;\n        rt*=10;\n        rt+=4;\n    }\n    while(rt<begin)rt=nextNum(rt);\n    for(;count<k;count++){\n        rt=nextNum(rt);\n    }\n    return rt;\n}\nint ma,mi;\ndouble lenthRt(unsigned a,unsigned b,unsigned lk1,unsigned lk2){\n    mi=max(a,lk1);\n    ma=min(b,lk2);\n    double kq;\n    if(ma<mi) return 0;\n    else {\n        if(lk2==ma){\n            kq=ma-mi;\n            return kq;\n        }\n        \n        kq= ma-mi+1;\n        return kq;\n    }\n}\nint main(){\n    int pl,pr,vl,vr,k;\n    int minN,maxN,lk1,lk2,i,after;\n    double sum=0;\n    \n    double kq,mau;\n    //pl=5;pr=6;\n    //vl=8;vr=10;k=1;\n    //printf(\"%d\",nextNum(47));\n    /*for(i=4;i<1000000000;i=nextNum(i)){\n            printf(\"%d\\n\",i);\n        \n    }*/\n    scanf(\"%d %d %d %d %d\",&pl,&pr,&vl,&vr,&k);\n    minN=min(pl,vl);\n    maxN=max(pr,vr);\n    \n    //for p\n    after=kthNum(pl,1);\n    if(k==1){\n        for(i=after;i<=pr;i=nextNum(i)) {\n            //printf(\"%d\\n\",i);\n            if(i>=vl&&i<=vr) sum-=1;\n            getchar();\n        }\n    }\n    lk1= kthNum(pl,k);\n    lk2= nextNum(lk1);\n    i=pl;\n    for(;i<=pr;){//xet tat ca cac chu so trong [pl+1,pr]\n        sum+=lenthRt(vl,vr,lk1,lk2)*min(after-i+1,pr-i+1);\n        //printf(\"%d to %d-> %d %d + them %lf*%d->%lf\\n\",i,after,lk1,lk2,lenthRt(vl,vr,lk1,lk2),min(after-i+1,pr-i+1),sum);\n\n        i=after+1;\n        after=nextNum(after);\n        lk1=lk2;\n        if(lk1>vr) break;\n        lk2=nextNum(lk2);\n    }\n    //if k==1\n    \n    //for p\n    after=kthNum(vl,1);\n    lk1= kthNum(vl,k);\n    lk2= nextNum(lk1);\n    i=vl;\n    for(;i<=vr;){//xet tat ca cac chu so trong [pl+1,pr]\n        //if(vl==vr&&pl==pr&&pl==vr) break;\n        sum+=lenthRt(pl,pr,lk1,lk2)*min(after-i+1,vr-i+1);\n        //printf(\"%d to %d-> %d %d + them %lf*%d ->%lf\\n\",i,after,lk1,lk2,lenthRt(pl,pr,lk1,lk2),min(after-i+1,pr-i+1),sum);\n        \n        i=after+1;\n        after=nextNum(after);\n        lk1=lk2;\n        if(lk1>pr) break;\n        lk2=nextNum(lk2);\n    }\n    mau=(pr-pl+1);\n    mau*=     (vr-vl+1);\n    //printf(\"%lf %lf\");\n    //printf(\"%lf %lf\\n\",sum,mau);\n    kq=sum/mau;\n    \n    printf(\"%.12lf\",kq);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "98eb620a268747349602f4201a167805", "src_uid": "5d76ec741a9d873ce9d7c3ef55eb984c", "difficulty": 1900.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\n#define N\t13\n#define Q\t1010\n#define MD1\t998244353\n#define MD\t1000000007\n\nlong long min(long long a, long long b) { return a < b ? a : b; }\n\nlong long pp[N + 1], qq[N + 1];\n\nvoid init() {\n\tint i;\n\n\tpp[0] = qq[0] = 1;\n\tfor (i = 1; i <= N; i++) {\n\t\tpp[i] = pp[i - 1] * 10;\n\t\tqq[i] = qq[i - 1] + pp[i];\n\t}\n}\n\nlong long idx(long long a, long long b) {\n\tstatic int aa[N], bb[N];\n\tstatic long long aa_[N];\n\tlong long cnt;\n\tint n, m, i, j, c;\n\n\tn = 0;\n\twhile (a > 0)\n\t\taa[n++] = a % 10, a /= 10;\n\tm = 0;\n\twhile (b > 0)\n\t\tbb[m++] = b % 10, b /= 10;\n\tfor (i = 0; i < n; i++)\n\t\taa_[i] = (i == 0 ? 0 : aa_[i - 1]) + aa[i] * pp[i];\n\tcnt = m;\n\tfor (i = n - 1, j = m - 1, c = 0; j >= 0; i--, j--)\n\t\tif (c < 0)\n\t\t\tcnt += qq[n - 1 - (m - 1 - j)] * (bb[j] - (j == m - 1 ? 1 : 0));\n\t\telse if (c > 0)\n\t\t\tcnt += (n - 1 - (m - 1 - j) == 0 ? 0 : qq[n - 2 - (m - 1 - j)]) * (bb[j] - (j == m - 1 ? 1 : 0));\n\t\telse {\n\t\t\tif (bb[j] <= aa[i]) {\n\t\t\t\tif (bb[j] < aa[i])\n\t\t\t\t\tc = -1;\n\t\t\t\tcnt += qq[n - 1 - (m - 1 - j)] * (bb[j] - (j == m - 1 ? 1 : 0));\n\t\t\t} else {\n\t\t\t\tc = 1;\n\t\t\t\tcnt += qq[n - 1 - (m - 1 - j)] * (aa[i] - (j == m - 1 ? 1 : 0));\n\t\t\t\tcnt += (n - 1 - (m - 1 - j) == 0 ? 0 : qq[n - 2 - (m - 1 - j)]) * (bb[j] - aa[i]) + (i == 0 ? 0 : aa_[i - 1]) + 1;\n\t\t\t}\n\t\t}\n\treturn cnt;\n}\n\nint aa[N], bb[N];\n\nlong long count_(long long a, long long d) {\n\tlong long b, cnt;\n\n\tcnt = 0;\n\tfor (b = 1; b <= a; b++)\n\t\tif (idx(a, b) - b >= d)\n\t\t\tcnt++;\n\treturn cnt;\n}\n\nlong long count(long long a, long long d) {\n\tint m;\n\tlong long cnt;\n\n\tcnt = 0;\n\tfor (m = 1; pp[m - 1] - 1 <= a; m++) {\n\t\tlong long lower = pp[m - 1] - 1, upper = min(pp[m], a + 1);\n\n\t\twhile (upper - lower > 1) {\n\t\t\tlong long b = (lower + upper) / 2;\n\n\t\t\tif (idx(a, b) - b >= d)\n\t\t\t\tupper = b;\n\t\t\telse\n\t\t\t\tlower = b;\n\t\t}\n\t\tcnt += min(pp[m], a + 1) - upper;\n\t}\n\treturn cnt;\n}\n\nint main() {\n\tlong long a, q, ans;\n\n\tinit();\n\tscanf(\"%lld\", &a);\n\tans = Q * a % MD;\n\tfor (q = -Q + 1; q <= Q; q++)\n\t\tans = (ans - count(a, q * MD1)) % MD;\n\tans = ans * MD1 % MD;\n\tif (ans < 0)\n\t\tans += MD;\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8d965a2a8880f14f782b35f30ec4ccbd", "src_uid": "2c70ae38f91ab739621a31b897b8fbf3", "difficulty": 3400.0}
{"lang": "GNU C11", "source_code": "#pragma GCC optimize(\"Ofast\")\n#include <stdio.h>\n#define min(a,b) ((a)<(b)?(a):(b))\n#define max(a,b) ((a)>(b)?(a):(b))\n#define inf 0x3f3f3f3f\n#define mod 1000000007\nint n,m,k,ans,a[15][15];\nint used[15][15][15],mp[15];\nvoid dfs(int x,int y,int mc)\n{\n\tif (x==n)\n\t{\n\t\tregister int c,qc;\n\t\tfor (c=1;c<=mc;++c) for (qc=c+1;qc<=mc;qc++) if (mp[c] && mp[qc] && mp[c]==mp[qc]) return;\n\t\tint a=0,b=k;\n\t\tfor (c=1;c<=mc;++c)\n\t\t{\n\t\t\tif (mp[c]) b--;\n\t\t\telse a++;\n\t\t}\n\t\tint curans=1;\n\t\tfor (;a--;b--) curans=curans*b%mod;\n\t\tans+=curans;ans%=mod;\n\t\treturn;\n\t}\n\tregister int c,i,j;int flag=0;\n\tfor (c=1;c<=min(mc+1,k);++c)\n\t{\n\t\tif (used[x][y][c]) continue;\n\t\tfor (i=x;i<n;++i) for (j=y;j<m;++j) used[i][j][c]++;\n\t\tif (!(a[x][y] && mp[c] && mp[c]!=a[x][y]))\n\t\t{\n\t\t\tflag=0;\n\t\t\tif (!mp[c])\n\t\t\t{\n\t\t\t\tmp[c]=a[x][y];\n\t\t\t\tflag=1;\n\t\t\t}\n\t\t\tif (y<m-1) dfs(x,y+1,max(mc,c));\n\t\t\telse dfs(x+1,0,max(mc,c));\n\t\t\tif (flag) mp[c]=0;\n\t\t}\n\t\tfor (i=x;i<n;++i) for (j=y;j<m;++j) used[i][j][c]--;\n\t}\n}\nint main()\n{\n\tregister int i,j;\n\tscanf(\"%d%d%d\",&n,&m,&k);\n\tif (n+m>k+1) return (int)puts(\"0\")*0;\n\tfor (i=0;i<n;++i) for (j=0;j<m;++j) scanf(\"%d\",&a[i][j]);\n\tdfs(0,0,0);printf(\"%d\\n\",ans);\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "67b88f7134592748a388f34e9190a9d6", "src_uid": "5bb21f49d976cfa16a239593a95c53b5", "difficulty": 2700.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\ntypedef struct mk\n{\n\tint day,type;\n}roy;\n\nint n,m,a[200010],l,r,tot=0;\nroy off[200010],tmp[200020];\n\nint ok(int days){\n\tint t[n+1];\n\tint need = 0,collect = days;\n\tfor(int i = 0;i<n;i++) t[i] = a[i];\n\tfor(int i = m-1;i>=0;i--){\n\t\tif(off[i].day>days) continue;\n\t\tcollect = (collect<=off[i].day)?collect:off[i].day;\n\t\tint tp = (collect<=t[off[i].type-1])?collect:t[off[i].type-1];\n\t\tneed += tp;\n\t\tt[off[i].type-1]-= tp;\n\t\tcollect-=tp;\n\t}\n\tneed += (tot - need)*2;\n\treturn (need<=days);\n}\nvoid merge(roy *of, int s,int m,int e){\n\tint i = s,j = m+1,k = 0;\n\twhile (i<=m && j<=e){\n\t\tif(of[i].day==of[j].day){\n\t\t\ttmp[k++] = (a[of[i].type-1]<a[of[j].type-1])?of[i++]:of[j++];\n\t\t}\n\t\telse tmp[k++] = (of[i].day<of[j].day)?of[i++]:of[j++];\n\t}\n\twhile (i<=m) tmp[k++] = of[i++];\n\twhile (j<=e) tmp[k++] = of[j++];\n\tfor(int i = s;i<=e;i++) {\n\t\tof[i] = tmp[i-s];\n\t}\n}\nvoid sort(roy *of, int s,int e){\n\tif(s<e){\n\t\tint m = (e+s)/2;\n\t\tsort(of,s,m);\n\t\tsort(of,m+1,e);\n\t\tmerge(of,s,m,e);\n\t}\n}\nvoid solve(){\n\tscanf(\"%d%d\",&n,&m);\n\tfor(int i = 0;i<n;i++){\n\t\tscanf(\"%d\",a+i);\n\t\ttot += a[i];\n\t}\n\tfor(int i = 0;i<m;i++){\n\t\tscanf(\"%d%d\",&off[i].day,&off[i].type);\n\t}\n\tsort(off, 0, m-1);\n\tl = 1;r = tot*2+1;\n\tint Ans;\n\twhile (l<=r)\n\t{\n\t\tint m = (l+r)/2;\n\t\tif(ok(m)){\n\t\t\tAns  = m;\n\t\t\tr = m-1;\n\t\t}\n\t\telse l = m+1;\n\t}\n\tfor(int i = l;i<=r;i++){\n\t\tif(ok(i)){\n\t\t\tAns = i;\n\t\t\tbreak;\n\t\t}\n\t}\n\tprintf(\"%d\\n\",Ans);\n}\nint main(){\n\tsolve();\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "6ee891aba20e21337476aa0f9150963c", "src_uid": "2eb101dcfcc487fe6e44c9b4c0e4024d", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <sys/time.h>\n\n#define N\t200000\n#define M\t200000\n\nvoid init_rand() {\n\tstruct timeval tv;\n\n\tgettimeofday(&tv, NULL);\n\tsrand(tv.tv_usec ^ tv.tv_sec);\n}\n\nint rand_(int n) {\n\treturn (rand() * 45677LL + rand()) % n;\n}\n\nint kk[N], ll[N], tt[M], ii[M], jj[M];\n\nint check(int n, int m, int t) {\n\tstatic int tt_[N];\n\tint i, j, b, x, t_;\n\n\tfor (i = 0; i < n; i++) {\n\t\tll[i] = kk[i];\n\t\ttt_[i] = -1;\n\t}\n\tfor (j = 0; j < m && (t_ = tt[jj[j]]) <= t; j++)\n\t\ttt_[ii[jj[j]]] = t_;\n\tb = 0;\n\tfor (j = 0; j < m && (t_ = tt[jj[j]]) <= t; j++)\n\t\tif (tt_[i = ii[jj[j]]] == t_) {\n\t\t\tx = ll[i] < t_ - b ? ll[i] : t_ - b;\n\t\t\tb += x, ll[i] -= x;\n\t\t}\n\tfor (i = 0; i < n; i++)\n\t\tb += ll[i] * 2;\n\treturn b <= t;\n}\n\nint compare(const void *a, const void *b) {\n\tint i = *(int *) a;\n\tint j = *(int *) b;\n\n\treturn tt[i] - tt[j];\n}\n\nint main() {\n\tint n, m, i, j, lower, upper, t, tmp;\n\n\tscanf(\"%d%d\", &n, &m);\n\tfor (i = 0; i < n; i++)\n\t\tscanf(\"%d\", &kk[i]);\n\tfor (j = 0; j < m; j++) {\n\t\tscanf(\"%d%d\", &tt[j], &ii[j]), ii[j]--;\n\t\tjj[j] = j;\n\t}\n\tinit_rand();\n\tfor (j = m - 1; j >= 0; j--) {\n\t\ti = rand_(j + 1);\n\t\ttmp = jj[i], jj[i] = jj[j], jj[j] = tmp;\n\t}\n\tqsort(jj, m, sizeof *jj, compare);\n\tlower = 0, upper = 200000 * 2;\n\twhile (upper - lower > 1) {\n\t\tt = (lower + upper) / 2;\n\t\tif (check(n, m, t))\n\t\t\tupper = t;\n\t\telse\n\t\t\tlower = t;\n\t}\n\tprintf(\"%d\\n\", upper);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "7717c0ff7e008608ed5fa433e06d908a", "src_uid": "2eb101dcfcc487fe6e44c9b4c0e4024d", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include<stdlib.h>\n#include<stdio.h>\n#include<string.h>\n\ntypedef long long int lli;\n\n#define TRUE         (1==1)\n#define FALSE        (!(TRUE))\n#define in32(x)      scanf(\"%d\", &(x))\n#define in64(x)      scanf(\"%I64d\", &(x))\n#define instr(x)     scanf(\"%s\", (x))\n#define out32(x)     printf(\"%d\\n\", (x))\n#define out64(x)     printf(\"%I64d\\n\", (x))\n#define outstr(x)    printf(\"%s\\n\", (x))\n#define max(a,b)     ((a)<(b))?(b):(a)\n#define min(a,b)     ((a)>(b))?(b):(a)\n#define abs(a)       ((a)<0)?(-(a)):(a)\n#define fo3(i,a,b)   for(i=(int)(a);i<=(int)(b);i++)\n#define of3(i,a,b)   for(i=(int)(a);i>=(int)(b);i--)\n\n#define MOD    998244353\n#define MAX    5005\n#define SENT   -1\n\ntypedef struct Pair {\n    int fi, se;\n} Pair;    \n\nint comp(Pair * f, Pair * s) {\n    return (f->fi - s->fi);\n}\n\nvoid sort(Pair ** arr, int size) { // CHANGE THIS\n    int i;\n    if (size < 6) {\n        int nSize = 0;\n        int s = size;\n        while (size != 0) {\n            nSize = 0;\n            for (i = 0; i < size - 1; i++) \n                if (comp(arr[i], arr[i+1]) > 0) { // CHANGE THIS\n                    Pair * tmp = arr[i];\n                    arr[i] = arr[i+1];\n                    arr[i+1] = tmp;\n                    nSize = i+1;\n                }\n            size = nSize;\n        }\n        return;\n    }\n    Pair ** tmp = (Pair **)calloc(size, sizeof(Pair *)); // CHANGE THIS\n    int lSize = (size >> 1);\n    int rSize = size - lSize;\n    sort(arr, lSize); sort(arr + lSize, rSize);\n    int lPtr = 0, rPtr = 0;\n    int ptr = 0;\n    while (ptr != size) {\n        if (lPtr == lSize)\n            tmp[ptr] = arr[lSize + (rPtr++)];\n        else if (rPtr == rSize || comp(arr[lPtr], arr[lSize + rPtr]) <= 0) // CHANGE THIS\n            tmp[ptr] = arr[lPtr++];\n        else\n            tmp[ptr] = arr[lSize + (rPtr++)];\n        ptr++;\n    }\n    for (i = 0; i < size; i++)\n        arr[i] = tmp[i];\n    free(tmp);\n}\n  \n  \nint main(void) {\n    int i, n, m;\n    in32(n);\n    in32(m);\n    int need[n];\n    fo3(i,0,n-1) \n        in32(need[i]);\n    Pair ** p = calloc(m, sizeof(Pair*));\n    fo3(i,0,m-1) {\n        p[i] = calloc(1,sizeof(Pair));\n        in32(p[i]->fi);\n        in32(p[i]->se);\n    }\n    sort(p,m);\n    lli pos = 2000000, min = 0, max = 2000000 - 1;\n    int have[n];\n    while (min <= max) {\n        lli mid = (min + max) >> 1;\n        fo3(i,0,n-1)\n            have[i] = 0;\n        lli spent = 0;\n        lli maxDay = mid;\n        of3(i,m-1,0) {\n            int day = p[i]->fi;\n            int ind = p[i]->se-1;\n            int miss = need[ind] - have[ind];\n            if (maxDay > day)\n                maxDay = day;\n            int buy = miss;\n            if (buy > maxDay)\n                buy = maxDay;\n            have[ind] += buy;\n            maxDay -= buy;\n            spent += buy;\n        }\n        fo3(i,0,n-1)\n            spent += ((need[i] - have[i])<<1);\n        if (spent <= mid) {\n            pos = mid;\n            max = mid - 1;\n        } else\n            min = mid + 1;\n    }\n    out64(pos);\n    return 0;\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "ae9a06f7f08019055dac1f7a2af77ca4", "src_uid": "2eb101dcfcc487fe6e44c9b4c0e4024d", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\ntypedef struct mk\n{\n\tint day,type;\n}roy;\n\nint n,m,a[200010],l,r,tot=0;\nroy off[200010],tmp[200020];\n\nint ok(int days){\n\tint t[n+1];\n\tint need = 0,collect = 0;\n\tfor(int i = 0;i<n;i++) t[i] = a[i];\n\tfor(int i = 0;i<m;i++){\n\t\tif(i==0) collect = off[i].day;\n\t\telse collect += (off[i].day - off[i-1].day);\n\t\tif(t[off[i].type-1] && collect){\n\t\t\tint tp = (collect<=t[off[i].type-1])?collect:t[off[i].type-1];\n\t\t\tneed += tp;\n\t\t\tt[off[i].type-1]-= tp;\n\t\t\tcollect-=tp;\n\t\t}\n\t\n\t}\n\tneed += (tot - need)*2;\n\treturn (need<=days);\n}\nvoid merge(roy *of, int s,int m,int e){\n\tint i = s,j = m+1,k = 0;\n\twhile (i<=m && j<=e){\n\t\tif(of[i].day==of[j].day){\n\t\t\ttmp[k++] = (a[of[i].type-1]<a[of[j].type-1])?of[i++]:of[j++];\n\t\t}\n\t\telse tmp[k++] = (of[i].day<of[j].day)?of[i++]:of[j++];\n\t}\n\twhile (i<=m) tmp[k++] = of[i++];\n\twhile (j<=e) tmp[k++] = of[j++];\n\tfor(int i = s;i<=e;i++) {\n\t\tof[i] = tmp[i-s];\n\t}\n}\nvoid sort(roy *of, int s,int e){\n\tif(s<e){\n\t\tint m = (e+s)/2;\n\t\tsort(of,s,m);\n\t\tsort(of,m+1,e);\n\t\tmerge(of,s,m,e);\n\t}\n}\nvoid solve(){\n\tscanf(\"%d%d\",&n,&m);\n\tfor(int i = 0;i<n;i++){\n\t\tscanf(\"%d\",a+i);\n\t\ttot += a[i];\n\t}\n\tfor(int i = 0;i<m;i++){\n\t\tscanf(\"%d%d\",&off[i].day,&off[i].type);\n\t}\n\tsort(off, 0, m-1);\n\tl = 1;r = tot*2+1;\n\tint Ans;\n\twhile (l<=r)\n\t{\n\t\tint m = (l+r)/2;\n\t\tif(ok(m)){\n\t\t\tAns  = m;\n\t\t\tr = m-1;\n\t\t}\n\t\telse l = m+1;\n\t}\n\tfor(int i = l;i<=r;i++){\n\t\tif(ok(i)){\n\t\t\tAns = i;\n\t\t\tbreak;\n\t\t}\n\t}\n\tprintf(\"%d\\n\",Ans);\n}\nint main(){\n\tsolve();\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "1e78df3a0e784f2519054e9c663511f4", "src_uid": "2eb101dcfcc487fe6e44c9b4c0e4024d", "difficulty": 2000.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\n#define N\t10000\n#define M\t10000\n#define K\t10\n#define C\t26\n\nint min(int a, int b) { return a < b ? a : b; }\n\nint ij[M], cc[M * 2], m;\nint *oh[N], oo[N], n;\n\nvoid link(int i, int h) {\n\tint o = oo[i]++;\n\n\tif (o >= 2 && (o & o - 1) == 0)\n\t\toh[i] = (int *) realloc(oh[i], o * 2 * sizeof *oh[i]);\n\toh[i][o] = h;\n}\n\nint dd[N];\n\nint bfs(int s, int t) {\n\tstatic int qu[N];\n\tint i, head, cnt;\n\n\tfor (i = 0; i < n; i++)\n\t\tdd[i] = n;\n\thead = cnt = 0;\n\tdd[s] = 0, qu[head + cnt++] = s;\n\twhile (cnt) {\n\t\tint d, o;\n\n\t\ti = qu[cnt--, head++], d = dd[i] + 1;\n\t\tfor (o = 0; o < oo[i]; o++) {\n\t\t\tint h_ = oh[i][o];\n\n\t\t\tif (cc[h_]) {\n\t\t\t\tint h = h_ >> 1, j = i ^ ij[h];\n\n\t\t\t\tif (dd[j] > d) {\n\t\t\t\t\tdd[j] = d;\n\t\t\t\t\tif (j == t)\n\t\t\t\t\t\treturn 1;\n\t\t\t\t\tqu[head + cnt++] = j;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\n\nint dfs(int i, int t, int c) {\n\tint d, o;\n\n\tif (i == t)\n\t\treturn c;\n\td = dd[i] + 1;\n\tfor (o = 0; o < oo[i]; o++) {\n\t\tint h_ = oh[i][o];\n\n\t\tif (cc[h_]) {\n\t\t\tint h = h_ >> 1, j = i ^ ij[h];\n\n\t\t\tif (dd[j] == d) {\n\t\t\t\tint f = dfs(j, t, min(c, cc[h_]));\n\n\t\t\t\tif (f) {\n\t\t\t\t\tcc[h_] -= f, cc[h_ ^ 1] += f;\n\t\t\t\t\treturn f;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tdd[i] = n;\n\treturn 0;\n}\n\nint dinic(int s, int t) {\n\tint sum = 0;\n\n\twhile (bfs(s, t)) {\n\t\tint f;\n\n\t\twhile ((f = dfs(s, t, C)))\n\t\t\tsum += f;\n\t}\n\treturn sum;\n}\n\nint ccc[K][M * 2];\nint cut[1 << K], k;\n\nvoid solve(int b, int h_, int s) {\n\tint h;\n\n\ts += dinic(0, n - 1);\n\tcut[b] = s;\n\tif (h_ < k) {\n\t\tmemcpy(ccc[h_], cc, m * 2 * sizeof *cc);\n\t\tfor (h = h_; h < k; h++) {\n\t\t\tcc[h << 1] = C;\n\t\t\tsolve(b | 1 << h, h + 1, s);\n\t\t\tmemcpy(cc, ccc[h_], m * 2 * sizeof *ccc[h_]);\n\t\t}\n\t}\n}\n\nint main() {\n\tstatic int ww_[K];\n\tint q, h, i, j;\n\n\tscanf(\"%d%d%d%d\", &n, &m, &k, &q);\n\tfor (i = 0; i < n; i++)\n\t\toh[i] = (int *) malloc(2 * sizeof *oh[i]);\n\tfor (h = 0; h < m; h++) {\n\t\tint c;\n\n\t\tscanf(\"%d%d%d\", &i, &j, &c), i--, j--;\n\t\tij[h] = i ^ j, cc[h << 1] = c;\n\t\tlink(i, h << 1), link(j, h << 1 | 1);\n\t}\n\tsolve(0, 0, 0);\n\twhile (q--) {\n\t\tint b, w, ans;\n\n\t\tw = 0;\n\t\tfor (h = 0; h < k; h++) {\n\t\t\tscanf(\"%d\", &ww_[h]);\n\t\t\tw += ww_[h];\n\t\t}\n\t\tans = cut[0] + w;\n\t\tfor (b = 1; b < 1 << k; b++) {\n\t\t\tfor (h = 0; (b & 1 << h) == 0; h++)\n\t\t\t\tw += ww_[h];\n\t\t\tw -= ww_[h];\n\t\t\tans = min(ans, cut[b] + w);\n\t\t}\n\t\tprintf(\"%d\\n\", ans);\n\t}\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "9444e43c6c2ce44d99e2b3fd9aac2d91", "src_uid": "7421c7d81cc7b481d61a6ef07e557e33", "difficulty": 3200.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n#include <stdlib.h>\n\n#define N\t100000\n\nint jj[N], pp[N], dd[N], mn;\n\nvoid match(int i) {\n\twhile (dd[i] == 1) {\n\t\tint j = jj[i], tmp;\n\n\t\tif (pp[i] == i || dd[j] == 1)\n\t\t\ttmp = pp[i], pp[i] = pp[j], pp[j] = tmp;\n\t\telse\n\t\t\tmn -= 2;\n\t\tjj[i] ^= j, dd[i] = 0, jj[j] ^= i, dd[j]--;\n\t\ti = j;\n\t}\n}\n\nint main() {\n\tint n, h, i, j;\n\n\tscanf(\"%d\", &n);\n\tfor (h = 0; h < n - 1; h++) {\n\t\tscanf(\"%d%d\", &i, &j), i--, j--;\n\t\tjj[i] ^= j, dd[i]++, jj[j] ^= i, dd[j]++;\n\t}\n\tfor (i = 0; i < n; i++)\n\t\tpp[i] = i;\n\tmn = (n - 1) * 2;\n\tfor (i = 0; i < n; i++)\n\t\tmatch(i);\n\tprintf(\"%d\\n\", mn);\n\tfor (i = 0; i < n; i++)\n\t\tprintf(\"%d \", pp[i] + 1);\n\tprintf(\"\\n\");\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "63ea894a492563a1118d244470e6ff3b", "src_uid": "98ded03cdd1870500667f0069d6a84b1", "difficulty": 2100.0}
{"lang": "GNU C11", "source_code": "#include <math.h>\n#include <stdio.h>\n#include <stdlib.h>\n\n#define N\t100000\n\ndouble min(double a, double b) { return a < b ? a : b; }\n\nint xx[N];\n\nint compare(const void *a, const void *b) {\n\tint i = *(int *) a;\n\tint j = *(int *) b;\n\n\treturn xx[i] - xx[j];\n}\n\nint main() {\n\tstatic int ii[N];\n\tint n, k, i, i_, xn, yn;\n\tdouble ans;\n\n\tscanf(\"%d%d\", &n, &k), k--;\n\tfor (i = 0; i < n; i++) {\n\t\tscanf(\"%d\", &xx[i]);\n\t\tii[i] = i;\n\t}\n\tqsort(ii, n, sizeof *ii, compare);\n\tscanf(\"%d%d\", &xn, &yn);\n\tif (k == n) {\n\t\tprintf(\"%f\\n\", min(hypot(xn - xx[ii[0]], yn), hypot(xn - xx[ii[n - 1]], yn)) + xx[ii[n - 1]] - xx[ii[0]]);\n\t\treturn 0;\n\t}\n\tans = hypot(xn - xx[k], yn)\n\t\t+ min(hypot(xn - xx[ii[0]], yn), hypot(xn - xx[ii[n - 1]], yn))\n\t\t+ xx[ii[n - 1]] - xx[ii[0]];\n\ti_ = -1;\n\tfor (i = 0; i < n; i++)\n\t\tif (ii[i] == k) {\n\t\t\ti_ = i;\n\t\t\tbreak;\n\t\t}\n\tfor (i = i_; i < n; i++) {\n\t\tdouble d;\n\n\t\td = min(xx[ii[i]] - xx[k] + xx[ii[i]] - xx[ii[0]]\n\t\t\t\t+ hypot(xn - xx[ii[0]], yn),\n\t\t\t\txx[k] - xx[ii[0]] + xx[ii[i]] - xx[ii[0]]\n\t\t\t\t+ hypot(xn - xx[ii[i]], yn));\n\t\tif (i + 1 < n)\n\t\t\td += min(hypot(xn - xx[ii[i + 1]], yn), hypot(xn - xx[ii[n - 1]], yn))\n\t\t\t\t+ xx[ii[n - 1]] - xx[ii[i + 1]];\n\t\tans = min(ans, d);\n\t}\n\tfor (i = i_; i >= 0; i--) {\n\t\tdouble d;\n\n\t\td = min(xx[k] - xx[ii[i]] + xx[ii[n - 1]] - xx[ii[i]]\n\t\t\t\t+ hypot(xn - xx[ii[n - 1]], yn),\n\t\t\t\txx[ii[n - 1]] - xx[k] + xx[ii[n - 1]] - xx[ii[i]]\n\t\t\t\t+ hypot(xn - xx[ii[i]], yn));\n\t\tif (i > 0)\n\t\t\td += min(hypot(xn - xx[ii[i - 1]], yn), hypot(xn - xx[ii[0]], yn))\n\t\t\t\t+ xx[ii[i - 1]] - xx[ii[0]];\n\t\tans = min(ans, d);\n\t}\n\tprintf(\"%f\\n\", ans);\n\treturn 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "b2304666a430310355200b630ec46958", "src_uid": "f9ed5faca211e654d9d4e0a7557616f4", "difficulty": 2600.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <string.h>\nenum { BIG = 1000000007 };\n\nint n;\nchar s[240];\nint slen;\nint dp[201][101];\nint next[201][2];\nint fail[201];\n\nvoid nextstep(int eo) {\n    int i, j;\n    for (i = 0; i <= slen; i++) {\n        int lp = next[i][0];\n        int rp = next[i][1];\n        for (j = eo; j <= n; j+=2) {\n            int now = dp[i][j];\n            if (j < n) {\n                int add = dp[lp][j+1] + now;\n                dp[lp][j+1] = add < BIG ? add : add - BIG;\n            }\n            if (j > 0) {\n                int add = dp[rp][j-1] + now;\n                dp[rp][j-1] = add < BIG ? add : add - BIG;\n            }\n        }\n    }\n    for (i = 0; i <= slen; i++) {\n        for (j = eo; j <= n; j+=2) {\n            dp[i][j] = 0;\n        }\n    }\n    /*for (i=0;i<=slen;i++){\n        for (j=0;j<=n;j++){\n            printf(\"%3d,\",dp[i][j]);\n        }\n        puts(\"\");\n    }\n    puts(\"\");*/\n}\n\nint main() {\n    scanf(\"%d\", &n);\n    scanf(\" %202s\", s);\n    slen = strlen(s);\n    int i;\n    // build state machine\n    fail[0] = fail[1] = 0;\n    if (s[0] == '(') {\n        next[0][0] = 1;\n        next[0][1] = 0;\n    }\n    else {\n        next[0][0] = 0;\n        next[0][1] = 1;\n    }\n    for (i = 1; i < slen; i++) {\n        int r = s[i] == ')';\n        int f = fail[i];\n        next[i][r] = i+1;\n        next[i][1-r] = next[f][1-r];\n        fail[i+1] = next[f][r];\n    }\n    next[slen][0] = next[slen][1] = slen;\n    dp[0][0] = 1;\n    for (i = 0; i < n; i++) {\n        nextstep(0);\n        nextstep(1);\n    }\n    printf(\"%d\\n\", dp[slen][0]);\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "c37934f3253cd8909d28f9ed8771c580", "src_uid": "590a49a7af0eb83376ed911ed488d7e5", "difficulty": 2300.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\n\nint main() {\n  int total = 0;\n  int current = 0;\n  int sign = 1;\n  for (;;) {\n    int c = getchar();\n    if (c == '+' || c == '-') {\n      total += current;\n      current = 0;\n      sign = c == '+' ? 1 : -1;\n    } else if (c < '0' || c > '9') break;\n    current = current * 10 + (c - '0') * sign;\n  }\n  total += current;\n  printf(\"%d\\n\", total);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "112ba9aaf4a76d97b2b518c479ef4bad", "src_uid": "db85fa18f00e560b58cfa7bab2fa957d", "difficulty": 2400.0}
{"lang": "GNU C11", "source_code": "#include <stdio.h>\r\n\r\n#define N\t250\r\n#define MD\t998244353\r\n\r\nint vv[N + 1], ff[N + 1], gg[N + 1];\r\n\r\nvoid init() {\r\n\tint i;\r\n\r\n\tff[0] = gg[0] = 1;\r\n\tfor (i = 1; i <= N; i++) {\r\n\t\tvv[i] = i == 1 ? 1 : (long long) vv[i - MD % i] * (MD / i + 1) % MD;\r\n\t\tff[i] = (long long) ff[i - 1] * i % MD;\r\n\t\tgg[i] = (long long) gg[i - 1] * vv[i] % MD;\r\n\t}\r\n}\r\n\r\nint choose(int n, int k) {\r\n\treturn (long long) ff[n] * gg[k] % MD * gg[n - k] % MD;\r\n}\r\n\r\nlong long power(long long a, int k) {\r\n\tlong long p = 1;\r\n\r\n\twhile (k) {\r\n\t\tif (k & 1)\r\n\t\t\tp = p * a % MD;\r\n\t\ta = a * a % MD;\r\n\t\tk >>= 1;\r\n\t}\r\n\treturn p;\r\n}\r\n\r\nint main() {\r\n\tstatic int dp[N];\r\n\tint n, k, c, i, j;\r\n\r\n\tinit();\r\n\tscanf(\"%d%d\", &n, &k);\r\n\tdp[0] = 1;\r\n\tfor (c = 1; c <= k; c++)\r\n\t\tfor (i = n - 1; i >= 0; i--)\r\n\t\t\tfor (j = 0; j < i; j++)\r\n\t\t\t\tdp[i] = (dp[i] + (long long) dp[j] * choose(i, j) % MD * power(k - c + 1, i * (i - 1) / 2 - j * (j - 1) / 2)) % MD;\r\n\tprintf(\"%d\\n\", dp[n - 1]);\r\n\treturn 0;\r\n}", "lang_cluster": "C", "compilation_error": false, "code_uid": "f2b08ae32fecf5535bf87f6bfa451809", "src_uid": "b2d7ac8e75cbdb828067aeafd803ac62", "difficulty": 2200.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\nint main()\n{\n    int n, m = 1000000007, x = 1, i;\n    int a[40] = {1, 2, 4, 6, 12, 16, 18, 30, 60, 88, 106, 126, 520, 606, 1278, 2202, 2280, 3216, 4252, 4422, 9688, 9940, 11212, 19936, 21700, 23208, 44496, 86242, 110502, 132048, 216090, 756838, 859432, 1257786, 1398268, 2976220, 3021376, 6972592, 13466916, 20996010};\n    \n    scanf(\"%d\", &n);\n    \n    for (i = 1; i <= a[n - 1]; i++) x = x * 2 % m;\n    \n    printf(\"%d\\n\", (x - 1 + m) % m);\n    \n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "0fa6d14b8bafe282516f2b05dce28896", "src_uid": "c2cbc35012c6ff7ab0d6899e6015e4e7", "difficulty": 2100.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n#include <assert.h>\n\ntypedef long long ll;\ntypedef struct pll { ll first,second; } pll;\n\n// a*x+b*y=g, x==0&&y==1||x==1&&y==0||1<=abs(x)<b/g&&1<=abs(y)<a/g&&x*y<0\nll min(ll x,ll y) { return x<y?x:y; }\nll egcd(ll a,ll b,ll *x,ll *y) {\n\tif(b==0) { *x=1,*y=0; return a; }\n\tll g=egcd(b,a%b,x,y);\n\tll z=*x; *x=*y; *y=z; *y-=(*x)*(a/b); return g;\n}\n\n\npll solve(ll a,ll b,ll MOD) { // a*x=b (mod MOD)\n\ta=(a%MOD+MOD)%MOD;\n\tb=(b%MOD+MOD)%MOD;\n\tll x,y,g=egcd(a,MOD,&x,&y);\n\tif(x<0) x+=MOD/g,y-=a/g;\n\tif(b%g!=0) return (pll){-1LL,-1LL};\n\treturn (pll){x*(b/g)%(MOD/g),MOD/g};\n}\n\nint a,h,w;\nvoid run() {\n\tscanf(\"%d%d%d\",&a,&h,&w);\n\t//(a+h)*nhor = w-h mod (w+a)\n\tpll nhor=solve(a+h,w-h,w+a);\n\tif(nhor.first==-1&&nhor.second==-1) { printf(\"-1\\n\"); return; }\n\tpll nvert={((a+h)*nhor.first+h-w)/(w+a),(a+h)*nhor.second/(w+a)};\n\t//printf(\"(%lld,%lld) (%lld,%lld)\\n\",nhor.first,nhor.second,nvert.first,nvert.second);\n\tassert(((a+h)*nhor.first+h-w)%(w+a)==0); assert((a+h)%nhor.second/(w+a)==0);\n\tif(nhor.first==0) nhor.first+=nhor.second,nvert.first+=nvert.second;\n\tif(nvert.first<=0) { ll t=(1-nvert.first+nvert.second-1)/nvert.second; nhor.first+=t*nhor.second,nvert.first+=t*nvert.second; }\n\tif(w-nhor.first*a<0||h-nvert.first*a<0) { printf(\"-1\\n\"); return; }\n\tll t=min((w-nhor.first*a)/(nhor.second*a),(h-nvert.first*a)/(nvert.second*a));\n\tnhor.first+=t*nhor.second,nvert.first+=t*nvert.second;\n\t//printf(\"%lld -> %.9lf / %lld -> %.9lf\\n\",nhor.first,1.0*(w-nhor.first*a)/(nhor.first+1),nvert.first,1.0*(h-nvert.first*a)/(nvert.first+1));\n\tprintf(\"%.9lf\\n\",1.0*(w-nhor.first*a)/(nhor.first+1));\n}\n\nint main() {\n\trun();\n    return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "8229c472d55649e7b0c034c9c672d45b", "src_uid": "7fbefd3eb1aad6865adcfac394f0a7e6", "difficulty": 2700.0}
{"lang": "GNU C", "source_code": "#include <stdio.h>\n\ntypedef struct {\n  int l, r;\n} interval;\n\nint max(int x, int y) {\n  return x > y ? x : y;\n}\n\nint min(int x, int y) {\n  return x < y ? x : y;\n}\n\nint interval_intersection_length(const interval *a, const interval *b) {\n  return max(0, min(a->r, b->r) - max(a->l, b->l) + 1);\n}\n\nvoid extract(const interval *a, interval *a1, interval *a2, int i) {\n  int s = 1 << i;\n  int x = (a->l + s - 1) >> i << i;\n  int y = a->r >> i << i;\n  if (x < y) {\n    a1->l = a2->l = 1;\n    a1->r = a2->r = s - 1;\n  } else if (x == y) {\n    a1->l = a->l % s;\n    if (a1->l == 0) a1->l = s;\n    a1->r = s - 1;\n    a2->l = 1;\n    a2->r = a->r % s;\n  } else {\n    a1->l = a2->l = a->l % s;\n    a1->r = a2->r = a->r % s;\n  }\n}\n\nint main() {\n  int i, ans;\n  interval a, b, a1, a2, b1, b2;\n  scanf(\"%d %d %d %d\", &a.l, &a.r, &b.l, &b.r);\n  ans = 0;\n  for (i = 1; i <= 30; i++) {\n    extract(&a, &a1, &a2, i);\n    extract(&b, &b1, &b2, i);\n    ans = max(ans, interval_intersection_length(&a1, &b1));\n    ans = max(ans, interval_intersection_length(&a1, &b2));\n    ans = max(ans, interval_intersection_length(&a2, &b1));\n    ans = max(ans, interval_intersection_length(&a2, &b2));\n  }\n  printf(\"%d\\n\", ans);\n  return 0;\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "aea1d404ed74d2f3eda2cb3512c762ad", "src_uid": "fe3c0c4c7e9b3afebf2c958251f10513", "difficulty": 2400.0}
{"lang": "GNU C", "source_code": "#include<stdio.h>\n#include<stdlib.h>\n\n#define ll long long\n\nconst ll M = 1000000007;\n\nll inv(ll a, ll M)\n{\n   if (a < 0)\n       a = (a + (1+(0-a)/M)*M)%M;\n   ll M_o = M;\n   ll ac0 = 1;\n   ll ac1 = 0;\n   ll bc0 = 0;\n   ll bc1 = 1;\n   ll q;\n   ll r;\n   ll temp;\n   while (M > 0)\n   {\n       q = a/M;\n       r = a%M;\n       a = M;\n       M = r;\n\n       temp = ac0;\n       ac0 = bc0;\n       bc0 = temp - q*bc0;\n\n       temp = ac1;\n       ac1 = bc1;\n       bc1 = temp - q*bc1;\n   }\n   M = M_o;\n   if (ac0 > 0)\n       return ac0%M;\n   else\n       return (ac0 + M*(1+(0-ac0)/M))%M;\n}\n\nll expmod(ll a, ll x, ll m)\n{\n    ll ans = 1;\n    while (x > 0)\n    {\n        if (x%2 == 1)\n            ans = ans*a%m;\n        a = a*a%m;\n        x /= 2;\n    }\n    if (ans > 0)\n        return ans%M;\n    else\n        return (ans + M*(1 + (0-ans)/M))%M;\n}\n\nint main()\n{\n    int n, m;\n    int ai, bi;\n    int ki;\n\n    fscanf(stdin, \"%d %d\\n\", &n, &m);\n    fscanf(stdin, \"%d %d\\n\", &ai, &bi);\n    fscanf(stdin, \"%d\", &ki);\n\n    ll a = (ll) ai;\n    ll b = (ll) bi;\n    ll k = (ll) ki;\n\n    ll p = a*inv(b, M)%M;\n\n    ll* kchoose = malloc((m+1)*sizeof(ll));\n    kchoose[0] = 1;\n    for (int l = 1; l < m+1; l++)\n        kchoose[l] = (kchoose[l-1]*(k-l+1)%M)*inv(l,M)%M;\n\n    ll* expmodp = malloc((m+1)*sizeof(ll));\n    ll* expmod1pkminus = malloc((m+1)*sizeof(ll));\n    expmodp[0] = 1;\n    expmod1pkminus[0] = expmod(1-p, k, M);\n    ll inv1p = p!=1? inv(1-p, M):1;\n\n    for (int x = 1; x < m+1; x++)\n    {\n        expmodp[x] = p*expmodp[x-1]%M;\n        if (p != 1)\n            expmod1pkminus[x] = inv1p*expmod1pkminus[x-1]%M;\n        else\n            expmod1pkminus[x] = x<k? 0:1;\n    }\n\n    ll* p_left = malloc((m+1)*sizeof(ll));\n    for (int l = 0; l < m+1; l++)\n    {\n        if (l > k)\n            p_left[l] = 0;\n        else\n            p_left[l] = (((kchoose[l]*expmodp[l])%M)*expmod1pkminus[l])%M;\n    }\n\n    ll* egs1 = malloc((m+1)*sizeof(ll));\n    ll* egs2 = malloc((m+1)*sizeof(ll));\n    ll* sle1 = malloc((m+1)*sizeof(ll));\n    ll* sle2 = malloc((m+1)*sizeof(ll));\n\n    ll* R = malloc(m*sizeof(ll));\n    ll* T = malloc((m+1)*sizeof(ll));\n    T[m] = 1;\n    for (int i = 0; i < m; i++)\n    {\n        R[i] = 1;\n        T[i] = 0;\n    }\n\n    ll* Tp_left = malloc(m*sizeof(ll));\n    ll* Rp_left = malloc(m*sizeof(ll));\n\n    for (int ni = 0; ni < n; ni++)\n    {\n        egs1[m] = 0;\n        egs2[m] = 0;\n\n        for (int i = 0; i < m; i++)\n            Rp_left[i] = R[i]*p_left[m-(i+1)]%M;\n\n        for (int s = m-1; s >= 0; s--)\n        {\n            egs1[s] = (egs1[s+1] + Rp_left[s])%M;\n            egs2[s] = (egs2[s+1] + p_left[m-(s+1)])%M;\n        }\n\n        sle1[0] = 0;\n        sle2[0] = 0;\n\n        for (int i = 0; i < m; i++)\n            Tp_left[i] = T[i]*p_left[i]%M;\n\n        for (int e = 1; e < m+1; e++)\n        {\n            sle1[e] = (sle1[e-1] + p_left[e-1])%M;\n            sle2[e] = (sle2[e-1] + Tp_left[e-1])%M;\n        }\n\n        R[0] = (p_left[0]*egs1[0]%M - Tp_left[0]*egs2[0]%M + M)%M;\n        for (int s = 1; s < m; s++)\n            R[s] = (R[s-1] + p_left[s]*egs1[s]%M - Tp_left[s]*egs2[s]%M + M) % M;\n\n        T[0] = 0;\n        for (int e = 1; e < m+1; e++)\n            T[e] = (T[e-1] + Rp_left[e-1]*sle1[e]%M - p_left[m-e]*sle2[e]%M + M)%M;\n    }\n\n    printf(\"%lld\\n\", T[m]);\n}\n", "lang_cluster": "C", "compilation_error": false, "code_uid": "2bd582918e300e8aa5ef0625ac960a29", "src_uid": "33b6b0d3a6af273f22b703491bd17289", "difficulty": 3100.0}